package com.fishercoder.solutions;

/**
 * 53. Maximum Subarray
 *
 * Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
 * For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguous subarray [4,-1,2,1] has the largest sum = 6.
 */

public class _53 {

  public static class Solution1 {
    /**credit: https://discuss.leetcode.com/topic/5000/accepted-o-n-solution-in-java*/
    public int maxSubArray(int[] nums) {
      int maxSoFar = nums[0];
      int maxEndingHere = nums[0];
      for (int i = 1; i < nums.length; i++) {
        maxEndingHere = Math.max(nums[i], maxEndingHere + nums[i]);
        maxSoFar = Math.max(maxEndingHere, maxSoFar);
      }
      return maxSoFar;
    }
  }
}

package com.fishercoder.solutions;

/**
 * 53. Maximum Subarray
 * Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
 *
 * Example:
 * Input: [-2,1,-3,4,-1,2,1,-5,4],
 * Output: 6
 * Explanation: [4,-1,2,1] has the largest sum = 6.
 *
 * Follow up:
 * If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
 */

public class _53 {

  public static class Solution1 {
    /**credit: https://discuss.leetcode.com/topic/5000/accepted-o-n-solution-in-java*/
    public int maxSubArray(int[] nums) {
      int maxSoFar = nums[0];
      int maxEndingHere = nums[0];
      for (int i = 1; i < nums.length; i++) {
        maxEndingHere = Math.max(nums[i], maxEndingHere + nums[i]);
        maxSoFar = Math.max(maxEndingHere, maxSoFar);
      }
      return maxSoFar;
    }
  }
}

refactor 53