display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name.
CREATE TABLE employees (employee_id VARCHAR, first_name VARCHAR, last_name VARCHAR, salary INTEGER, department_id VARCHAR)
[SQL] SELECT employee_id, first_name, last_name, salary FROM employees WHERE salary > (SELECT AVG(salary) FROM employees) AND department_id IN (SELECT department_id FROM employees WHERE first_name LIKE '%J%') [/SQL]