display the employee ID and job name for all those jobs in department 80.
CREATE TABLE jobs (job_title VARCHAR, job_id VARCHAR); CREATE TABLE employees (employee_id VARCHAR, job_id VARCHAR, department_id VARCHAR)
[SQL] SELECT T1.employee_id, T2.job_title FROM employees AS T1 JOIN jobs AS T2 ON T1.job_id = T2.job_id WHERE T1.department_id = 80 [/SQL]