static <T1, T2, T3, T4, T5, T6, T7, T8, T9, T10, T11, T12, T13, R> Seq<R> zipAll(Stream<? extends T1> s1, Stream<? extends T2> s2, Stream<? extends T3> s3, Stream<? extends T4> s4, Stream<? extends T5> s5, Stream<? extends T6> s6, Stream<? extends T7> s7, Stream<? extends T8> s8, Stream<? extends T9> s9, Stream<? extends T10> s10, Stream<? extends T11> s11, Stream<? extends T12> s12, Stream<? extends T13> s13, T1 default1, T2 default2, T3 default3, T4 default4, T5 default5, T6 default6, T7 default7, T8 default8, T9 default9, T10 default10, T11 default11, T12 default12, T13 default13, Function13<? super T1, ? super T2, ? super T3, ? super T4, ? super T5, ? super T6, ? super T7, ? super T8, ? super T9, ? super T10, ? super T11, ? super T12, ? super T13, ? extends R> zipper) {
        return zipAll(seq(s1), seq(s2), seq(s3), seq(s4), seq(s5), seq(s6), seq(s7), seq(s8), seq(s9), seq(s10), seq(s11), seq(s12), seq(s13), default1, default2, default3, default4, default5, default6, default7, default8, default9, default10, default11, default12, default13, zipper);
    }
Zip two streams into one - by storing the corresponding elements from them in a tuple,
when one of streams will end - a default value for that stream will be provided instead -
so the resulting stream will be as long as the longest of the two streams.
<p>
<pre><code>
// (tuple(1, "a"), tuple(2, "x"), tuple(3, "x"))
Seq.zipAll(Seq.of(1, 2, 3), Seq.of("a"), 0, "x")
</code></pre>
jOOL-java-8/src/main/java/org/jooq/lambda/Seq.java