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aoj_0259_cpp
すべての数は6174に通ず 0 から 9 の数字からなる四桁の数 N に対して以下の操作を行う。 N の桁それぞれの数値を大きい順に並べた結果得た数を L とする N の桁それぞれの数値を小さい順に並べた結果得た数を S とする 差 L-S を新しい N とする(1回分の操作終了) 新しい N に対して 1. から繰り返す このとき、全桁が同じ数字(0000, 1111など)である場合を除き、あらゆる四桁の数はいつかは 6174になることが知られている。例えば N = 2012の場合 1回目 (N = 2012): L = 2210, S = 0122, L-S = 2088 2回目 (N = 2088): L = 8820, S = 0288, L-S = 8532 3回目 (N = 8532): L = 8532, S = 2358, L-S = 6174 となり、3 回の操作で 6174 に到達する。 0 から 9 の数字からなる四桁の数が与えられたとき、何回の操作で 6174 に到達するか計算するプログラムを作成して下さい。 入力 入力は複数のデータセットからなる。入力の終わりは 0000 が1つの行で示される。各データセットは以下の形式で与えられる。 N データセットは1行であり、N (1 ≤ N ≤ 9999) は四桁の数を示す。N < 1000 の場合は上の桁は 0 で埋められている。 データセットの数は 10000 を超えない。 出力 各データセットごとに何回の操作で 6174 に到達したかを1行に出力する。ただし全桁が同じ数字である数が入力として与えられた場合は NA と出力する。 入力例 6174 2012 3333 0000 出力例 0 3 NA
[ { "submission_id": "aoj_0259_9621832", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define MAX 1000000007\n\nint main(void){\n string s;\n while(true){\n cin >> s;\n if(s == \"0000\") break;\n if(s[0] == s[1] && s[1] == s[2] && s[2] == s[3]){\n cout << \"NA\" << endl;\n continue;\n }\n int ans = 0,l = 0;\n while(s != \"6174\"){\n sort(s.begin(),s.end());\n l = stoi(s);\n reverse(s.begin(),s.end());\n l = l*-1 + stoi(s);\n ans++;\n s = to_string(l);\n rep(i,4-s.size()) s='0'+s;\n }\n cout << ans << endl;\n \n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3448, "score_of_the_acc": -0.7753, "final_rank": 7 }, { "submission_id": "aoj_0259_9597336", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define Rrep(i,n) for(int i=n-1;i>=0;i--)\n#define Rrep1(i,n) for(int i=n;i>0;i--)\n#define all(a) a.begin(),a.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\n#define INF ((ll)4e18)\n#define IINF ((int)1e9)\nconst double PI = 3.141592653589793;//2384626433832795028841971;\ntemplate<typename T>inline bool chmax(T& a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T>inline bool chmin(T& a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n#define yesno(ans) cout<<((ans)?\"Yes\\n\":\"No\\n\")\nbool eq(double a, double b) { return abs(a - b) < 0.0000001; }\n//LRUD\nconst int di[4] = { 0,-1,0,1 };\nconst int dj[4] = { -1,0,1,0 };\n//const int di[8] = { 0,0,1,1,1,-1,-1,-1 };\n//const int dj[8] = { 1,-1,0,-1,1,0,-1,1 };\n\n/*ACL\n#include <atcoder/all>\nusing namespace atcoder;\n//using mint=modint;\nusing mint = modint998244353;\n//using mint=modint1000000007;\nusing vm=vector<mint>;\nusing vvm=vector<vm>;\nusing vvvm=vector<vvm>;\n//*/\n\n\nint solve(){\n int N=9999;\n int M=9999;\n for(;cin>>N,N;){\n int ans=0;\n bool isNA=0;\n while(N!=6174){\n ans++;\n string L=to_string(N);\n while(L.size()<4)L+='0';\n string S=L;\n sort(all(L));\n reverse(all(L));\n sort(all(S));\n N=stoi(L)-stoi(S);\n if(N==0){\n isNA=1;\n break;\n }\n }\n if(isNA){\n cout<<\"NA\"<<endl;\n continue;\n }\n cout<<ans<<endl;\n }\n return 0;\n}\n\nint main()\n{\n //std::cin.tie(0)->sync_with_stdio(0);\n int T = 1;\n //cin>>T;\n while (T--)\n {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3500, "score_of_the_acc": -0.9213, "final_rank": 11 }, { "submission_id": "aoj_0259_8019234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n string N;\n while(cin>>N){\n if(N==\"0000\")return 0;\n ll cnt=0;\n unordered_set<string> SS;\n while(N!=\"6174\"){\n if(SS.count(N)){\n cout<<\"NA\"<<endl;\n cnt=-1;\n break;\n }\n SS.insert(N);\n string S=N,T=N;\n sort(all(S));\n sort(all(T));\n reverse(all(T));\n N=to_string(stoll(T)-stoll(S));\n while(N.size()<4)N='0'+N;\n cnt++;\n }\n if(cnt>=0)cout<<cnt<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3524, "score_of_the_acc": -0.9888, "final_rank": 14 }, { "submission_id": "aoj_0259_7686740", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cmath>\n#include<cstring>\n#define ll long long\nusing namespace std;\nll n,i,j,k,ans,a[4],t,minm,maxm;\nint main()\n{\n\twhile(cin>>n&&n!=0000) {\n\t\tans=0;\n\t\tfor(i=0;;i++) {\n\t\t\t\n\t\t\tif(n==6174) break;\n\t\t\tk=n;\n\t\t\tfor(j=0;j<=3;j++) {\n\t\t\t\tt=k%10;\n\t\t\t\tk=k/10;\n\t\t\t\ta[j]=t;\n\t\t\t}\n\t\t\tsort(a,a+4);\n\t\t\tif(a[0]==a[3]) break;\n\t\t\tminm=0;maxm=0;\n\t\t\tfor(j=0;j<=3;j++) {\n\t\t\t\tminm+=a[j]*pow(10,3-j);\n\t\t\t\tmaxm+=a[j]*pow(10,j);\n\t\t\t\t\n\t\t\t\t/*——————————————————————*/\n\t\t\t}\n\t\t\tans++;\n\t\t\tn=maxm-minm;\n\t\t}\n\t\tif(n==6174)\n\t\tcout<<ans<<endl;\n\t\telse \n\t\tcout<<\"NA\"<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -0.3146, "final_rank": 3 }, { "submission_id": "aoj_0259_6798156", "code_snippet": "#include <bits/stdc++.h>\n#include <string>\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define rrep(i,a,b) for(int i = a; i < b; i++)\n#define all(A) (A).begin(),(A).end()\n#define MOD 1000000007\n#define grt greater<int>()\n#define mapf(M) for(auto& [k,v] : M)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nll INF = 1LL<<60;\ntypedef vector<vector<ll> > Graph;\n\nint main() {\n\twhile(1){\n\t\tstring s; cin >> s;\n\t\tint n = stoi(s);\n\t\tif(n == 0) return 0;\n\t\tbool same = 1;\n\t\trep(i,3) if(s[0] != s[i+1]) same = 0;\n\t\tif(same){\n\t\t\tcout << \"NA\\n\";\n\t\t\tcontinue;\n\t\t}\n\n\t\tint cnt = 0;\n\t\twhile(n != 6174){\n\t\t\tsort(all(s)); int ls = stoi(s);\n\t\t\tsort(all(s),greater<char>()); int ss = stoi(s);\n\t\t\tn = ss-ls;\n\t\t\ts = to_string(n);\n\t\t\trep(i,4-(int)s.size()) s = '0'+s;\n\t\t\tcnt++;\n\t\t}\n\t\tcout << cnt << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3492, "score_of_the_acc": -0.8989, "final_rank": 10 }, { "submission_id": "aoj_0259_6354323", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint solve(int n) {\n vector<int>v;\n\n v.push_back(n % 10);\n n /= 10;\n v.push_back(n % 10);\n n /= 10;\n v.push_back(n % 10);\n n /= 10;\n v.push_back(n % 10);\n n /= 10;\n\n sort(v.begin(), v.end());\n int p1 = 0;\n for (int i = 0; i < v.size(); i++) {\n p1 *= 10;\n p1 += v[i];\n }\n int p2 = 0;\n for (int i = v.size() - 1; i >= 0; i--) {\n p2 *= 10;\n p2 += v[i];\n }\n return p2 - p1;\n}\nint main(){\n while (1) {\n int n;\n cin >> n;\n if (n == 0) break;\n int i = 0;\n while (1) {\n if (n == 6174 ) {\n cout << i << endl;\n break;\n }\n n = solve(n);\n i++;\n if (i > 10000) {\n cout << \"NA\" << endl;\n break;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3444, "score_of_the_acc": -0.764, "final_rank": 6 }, { "submission_id": "aoj_0259_6094145", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while (true) {\n string N;\n cin >> N;\n if(N == \"0000\") {\n return 0;\n }\n if(N == \"6174\") {\n cout << 0 << endl;\n continue;\n }\n int ans = 0;\n while (true) {\n ans++;\n string A = N,B = N;\n sort(A.rbegin(),A.rend());\n sort(B.begin(),B.end());\n string C = to_string(stoi(A)-stoi(B));\n N = string(4-C.size(),'0')+C;\n if(N == \"0000\") {\n cout << \"NA\" << endl;\n break;\n }\n if(N == \"6174\") {\n cout << ans << endl;\n break;\n }\n }\n }\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3488, "score_of_the_acc": -0.8876, "final_rank": 9 }, { "submission_id": "aoj_0259_5937011", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n while (true){\n int N;\n cin >> N;\n if (N == 0){\n break;\n }\n if (N % 1111 == 0){\n cout << \"NA\" << endl;\n } else {\n int cnt = 0;\n while (N != 6174){\n string S = to_string(N);\n while (S.size() < 4){\n S.insert(S.begin(), '0');\n }\n sort(S.begin(), S.end());\n int X = stoi(S);\n reverse(S.begin(), S.end());\n int Y = stoi(S);\n N = Y - X;\n cnt++;\n }\n cout << cnt << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.809, "final_rank": 8 }, { "submission_id": "aoj_0259_5896287", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\nint count_op(string str) {\n int count = 0;\n int num;\n string L, S;\n\n if (str == \"6174\") return 0;\n \n do {\n L = str;\n S = str;\n sort(L.begin(), L.end(), greater<char>());\n sort(S.begin(), S.end());\n \n num = stoi(L) - stoi(S);\n if (num < 1000) {\n str = \"0\" + to_string(num);\n } else {\n str = to_string(num);\n }\n count++;\n } while (num != 6174);\n \n return count;\n}\n\nint main()\n{\n int count;\n string N;\n\n while (1) {\n cin >> N;\n\n if (N == \"0000\") {\n break;\n }\n if (N[0] == N[1] && N[1] == N[2] && N[2] == N[3]) {\n cout << \"NA\" << endl;\n } else {\n count = count_op(N);\n cout << count << endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.6067, "final_rank": 5 }, { "submission_id": "aoj_0259_5741562", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<regex>\n#include<sstream>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nsigned main(){\n\tint n;\n\twhile(cin>>n,n){\n\t\tfor(int i=0;;i++){\n\t\t\tif(n%1111==0){\n\t\t\t\tcout<<\"NA\"<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(n==6174){\n\t\t\t\tcout<<i<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstring s=to_string(n);\n\t\t\ts=string(4-s.size(),'0')+s;\n\t\t\tsort(s.begin(),s.end());\n\t\t\tstring l=s;\n\t\t\treverse(l.begin(),l.end());\n\t\t\tn=stoi(l)-stoi(s);\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3512, "score_of_the_acc": -0.9551, "final_rank": 12 }, { "submission_id": "aoj_0259_5731812", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define MOD 1000000007\n//#define MOD 998244353\n#define INF 1000000010\n#define EPS 1e-9\n#define F first\n#define S second\n\n#define debug(x) cout<<x<<endl;\n#define repi(i,x,n) for(int i=x;i<n;i++)\n#define rep(i,n) repi(i,0,n)\n#define lp(i,n) repi(i,0,n)\n#define repn(i,n) for(int i=n;i>=0;i--)\n#define int long long\n#define endl \"\\n\"\n\ntypedef pair<int,int> PII;\ntypedef pair<int,string> PIS;\ntypedef pair<string,int> PSI;\n\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; \n return true;\n }\n return false;\n}\n\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\nsigned main(){\n //cin.tie(0);\t\n //ios::sync_with_stdio(false);\n while(1){\n string n;\n cin>>n;\n if(n==\"0000\") break;\n int ans=0;\n if(n[0]==n[1] && n[1]==n[2] && n[2]==n[3]){\n cout<<\"NA\"<<endl;\n continue;\n }\n int cnt=0;\n while(n!=\"6174\"){\n // cout<<n<<endl;\n string mn,mx;\n ans++;\n sort(n.begin(),n.end(),greater<char>() );\n mx=n;\n sort(n.begin(),n.end() );\n mn=n;\n //cout<<mx<<\" \"<<mn<<endl;\n int x=stoll(mx),y=stoll(mn);\n x=x-y;\n n=to_string(x);\n while(n.size() < 4) n=\"0\"+n;\n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3512, "score_of_the_acc": -0.9551, "final_rank": 12 }, { "submission_id": "aoj_0259_5731763", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n// {{{\n\n// clang-format off\n#define _over_load(_1,_2,_3,_4,NAME,...) NAME\n#define range(...) _over_load(__VA_ARGS__, range4, range3, range2)(__VA_ARGS__)\n#define range2(i, r) for ( int i = 0; i < (int)(r); (i) += 1)\n#define range3(i, l, r) for ( int i = (int)(l); i < (int)(r); (i) += 1)\n#define range4(i, l, r, inc) for ( int i = (int)(l); i < (int)(r); (i) += (inc))\n#define rrange(...) _over_load(__VA_ARGS__, rrange4, rrange3, rrange2)(__VA_ARGS__)\n#define rrange2(i, r) for ( int i = (int)(r) - 1; i >= 0; (i) -= 1)\n#define rrange3(i, l, r) for ( int i = (int)(r) - 1; i >= (int)(l); (i) -= 1)\n#define rrange4(i, l, r, inc) for ( int i = (int)(r) - 1; i >= (int)(l); (i) -= inc)\n#define debug(...) debug_func(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename T, typename... T2> void debug_func(string_view name, const T &a, T2 &&...rest) { stack<char> bs; string_view lbs = \"({[<\"; string_view rbs = \")}]>\"; int end = name.size(); for ( int i = 0; i < (int)name.size(); i++ ) { if ( lbs.find(name[i]) != string::npos ) { bs.push(name[i]); } if ( rbs.find(name[i]) != string::npos ) { if ( !bs.empty() ) { bs.pop(); } } if ( name[i] == ',' && bs.empty() ) { end = i; break; } } cerr << name.substr(0, end) << \":\" << a; if constexpr ( sizeof...(rest) == 0 ) { cerr << endl; } else { cerr << ' '; debug_func(name.substr(name.find_first_not_of(' ', end + 1)), forward<T2>(rest)...); } }\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << p.first << ' ' << p.second; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { for ( pair<T1, T2> x : v ) { os << x << \"\\n\"; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { if(!v.empty()) { os << v.front(); v.pop(); } while (!v.empty()) { os << \" \" << v.front(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { if(!v.empty()) { os << v.top(); v.pop(); } while (!v.empty()) { os << \" \" << v.top(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\nusing ull = unsigned long long;\nusing ll = long long;\nusing Pll = pair<ll, ll>;\nusing P = pair<int, int>;\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, -1, 1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { -1, 0, 0, 1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = (int)1e9 + 7;\nconstexpr char newl = '\\n';\n// clang-format on\n\n// }}}\n\n\nint ans=0;\nvoid dfs(string s){\n if(s==\"6174\"){\n cout<<ans<<endl;\n return;\n }\n\n string high=s,low=s;\n sort(high.rbegin(),high.rend());\n sort(low.begin(),low.end());\n\n ostringstream scout;\n scout << setfill('0') << setw(4) << to_string(stoi(high)-stoi(low));\n s=scout.str();\n\n ans++;\n dfs(s);\n}\n\nvoid solve(string s){\n ans=0;\n dfs(s);\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n while(1){\n string n;\n cin>>n;\n if(n==\"0000\") break;\n\n bool is_NA=false;\n range(i,1,10){\n char c='0'+i;\n string same=\"\";\n range(j,4) same.push_back(c);\n if(n==same){\n is_NA=true;\n break;\n }\n }\n if(is_NA){\n cout<<\"NA\"<<endl;\n continue;\n }\n solve(n);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3528, "score_of_the_acc": -2, "final_rank": 19 }, { "submission_id": "aoj_0259_5460553", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\n//入力系\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\n//出力系\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\n//デバッグ系\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n string s,t;\n while(cin>>s){\n if(s==\"0000\")return 0;\n if(s[0]==s[1]&&s[1]==s[2]&&s[2]==s[3]){\n out(\"NA\");\n continue;\n }\n int ans=0;\n while(s!=\"6174\"){\n ans++;\n t=s;\n sort(rall(s));\n sort(all(t));\n s=to_string(stoi(s)-stoi(t));\n while(s.size()<4){\n reverse(all(s));\n s.push_back('0');\n reverse(all(s));\n }\n }\n out(ans);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -0.3146, "final_rank": 3 }, { "submission_id": "aoj_0259_5056941", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\nvoid solve(string N){\nif ( N[0] == N[1] && N[1] == N[2] && N[2] == N[3] ) {\ncout << \"NA\" << endl; return;\n}\nint cnt = 0;\nstring L, S;\nfor(; N != \"6174\"; cnt++ ){\nL = S = N;\nsort(L.begin(), L.end()); // 昇順にソート\nreverse(L.begin(), L.end()); // 逆順にして降順にソート\nsort(S.begin(), S.end()); // 昇順にソート\nint num = stoi(L.c_str()) - stoi(S.c_str());\nN = to_string(num);\nwhile( N.size() < 4 ) N = '0' + N;\n}\ncout << cnt << endl;\n}\nint main(){\nstring N;\nwhile(1){\ncin >> N;\nif ( N == \"0000\" ) break;\nsolve(N);\n}\nreturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -1.1798, "final_rank": 17 }, { "submission_id": "aoj_0259_4851084", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <iomanip>\nusing namespace std;\n\nint main(){\n while(1){\n string s;\n cin >> s;\n if(s == \"0000\") break;\n\n if(s[0]==s[1] and s[0]==s[2] and s[0]==s[3]){\n cout << \"NA\" << endl;\n continue;\n }\n int count = 0;\n while(stoi(s) != 6174){\n sort(s.begin(), s.end());\n int b = stoi(s);\n reverse(s.begin(), s.end());\n int a = stoi(s);\n ostringstream sout;\n sout << setfill('0') << setw(4) << a-b;\n s = sout.str();\n count++;\n }\n cout << count << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3172, "score_of_the_acc": -1, "final_rank": 15 }, { "submission_id": "aoj_0259_4821823", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint r[4]={6,1,7,4};\nbool c(int n[]){\n\tfor(int i=0; i<4; i++){\n\t\tif(r[i]!=n[i]){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool c2(int n[]){\n\tfor(int i=0; i<3; i++){\n\t\tif(n[i]!=n[i+1]){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nbool c3(int n[]){\n\tfor(int i=0; i<4; i++){\n\t\tif(n[i]!=0){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main(){\n\twhile(true){\n\t\tint q=0;\n\t\tchar a[4];\n\t\tint n[4]={};\n\t\tcin>>a;\n\t\tif(a==\"0000\") break;\n\t\tn[0]=int(a[0])-int('0');\n\t\tn[3]=int(a[3])-int('0');\n\t\tn[2]=int(a[2])-int('0');\n\t\tn[1]=int(a[1])-int('0');\n\t\tbool t=true;\n\t\tif(c3(n)) break;\n\t\twhile(true){\n\t\t\tif(c(n))break;\n\t\t\tif(c2(n)){ \n\t\t\t\tt=false; break;\n\t\t\t}\n\t\t\tsort(n,n+4);\n\t\t\tint s=0,l=0,sk=1000,lk=1;\n\t\t\tfor(int i=0; i<4; i++){\n\t\t\t\ts+=sk*n[i];sk/=10;\n\t\t\t\tl+=lk*n[i];lk*=10;\n\t\t\t}\n\t\t\tint m=l-s,k=1000;\n\t\t\tfor(int i=0; i<4; i++){\n\t\t\t\tn[i]=m/k;\n\t\t\t\tm-=n[i]*k;\n\t\t\t\tk/=10;\n\t\t\t}\n\t\t\tq++;\n\t\t}\n\t\tif(t) cout<<q<<endl;\n\t\telse cout<<\"NA\"<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3176, "score_of_the_acc": -0.0112, "final_rank": 1 }, { "submission_id": "aoj_0259_4743122", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Headelr {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\nusing imax = intmax_t;\nusing usize = size_t;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// }}} End Header\n\nconstexpr int dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\nconstexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};\n\nconst auto inside = [](int y, int x, int H, int W) -> bool {\n return (y >= 0 && x >= 0 && y < H && x < W);\n};\n\nstruct Data {\n imax score;\n usize id;\n\n Data(imax score, usize id) : score(score), id(id) {}\n\n bool operator>(const Data& rhs) const {\n if (score == rhs.score) {\n return id < rhs.id;\n } else {\n return score > rhs.score;\n }\n }\n};\n\n// SegmentTree {{{\ntemplate <class Monoid>\nstruct SegmentTree {\n using Func = function<Monoid(Monoid, Monoid)>;\n const size_t sz;\n const Func fn;\n const Monoid unity;\n vector<Monoid> seg;\n\n SegmentTree(const size_t n, const Monoid &u, Func f)\n : sz(1 << (__lg(n + 5) + 1)), fn(f), unity(u), seg(sz * 2, unity) {}\n\n void set(size_t k, const Monoid &v) {\n seg[k + sz] = v;\n }\n\n Monoid& operator[](size_t k) {\n return seg[k + sz];\n }\n const Monoid& operator[](size_t k) const {\n return seg[k + sz];\n }\n\n void build() {\n for (size_t k = sz - 1; k > 0; --k) {\n seg[k] = fn(seg[2 * k], seg[2 * k + 1]);\n }\n }\n\n void update(size_t k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while (k >>= 1) {\n seg[k] = fn(seg[2 * k], seg[2 * k + 1]);\n }\n }\n\n Monoid query(size_t a, size_t b) const {\n Monoid L = unity, R = unity;\n for (a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if (a & 1) L = fn(L, seg[a++]);\n if (b & 1) R = fn(seg[--b], R);\n }\n return fn(L, R);\n }\n};\n// }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n const auto so = [&](string s) -> string {\n sort(all(s));\n return s;\n };\n const auto rso = [&](string s) -> string {\n sort(all(s), greater<>());\n return s;\n };\n\n imax N;\n while (cin >> N, N) {\n if (N == 6174) {\n output(0);\n continue;\n }\n string s = to_string(N);\n s = string(4 - s.size(), '0') + s;\n if (s == string(4, s[0])) {\n output(\"NA\");\n continue;\n }\n usize res = 0;\n while (s != \"6174\") {\n const imax L = stoi(rso(s));\n const imax S = stoi(so(s));\n s = to_string(L - S);\n s = string(4 - s.size(), '0') + s;\n res++;\n }\n output(res);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3276, "score_of_the_acc": -0.2921, "final_rank": 2 }, { "submission_id": "aoj_0259_4733269", "code_snippet": "#include<bits//stdc++.h>\n#define rep(i,n) for(int i = 0;i <n;i++)\nusing namespace std;\nint main(){\n\tstring s;int b;\n\twhile (cin >> s,s!=\"0000\") {\n\t\tif (s[0] == s[1]&& s[2] == s[3]&&s[2]==s[3]) {\n\t\t\tcout << \"NA\" << endl; continue;\n\t\t}int cnt = 0;\n\t\twhile (s != \"6174\") {\n\t\t\tint L = 0, S = 0;\n\t\t\tsort(s.begin(), s.end());\n\t\t\trep(i, 4) L += (s[i] - '0') * pow(10, i);\n\t\t\trep(i, 4) S += (s[3 - i] - '0')*pow(10, i);\n\t\t\tb = L - S; cnt++;\n\t\t\ts = to_string(b);\n\t\t}cout << cnt << endl;\n\t}\n}", "accuracy": 0.75, "time_ms": 20, "memory_kb": 3424, "score_of_the_acc": -1.7079, "final_rank": 20 }, { "submission_id": "aoj_0259_4692407", "code_snippet": "#include<string.h>\n#include<iostream>\n#include<string>\n#include <vector>\n#include<algorithm>\n\nusing namespace std;\n\nint Func(string str_num)\n{\n\tif (str_num == \"6174\")\n\t\treturn 0;\n\tint a[4];\n\tfor (int i = 0; i < 4; i++)\n\t\ta[i] = str_num[i] - '0';\n\tsort(a, a + 4,greater<int>());\n\tint L = 0;\n\tfor (int i = 0; i < 4; i++)\n\t\tL += pow(10, 3 - i) * a[i];\n\tsort(a, a + 4);\n\tint S = 0;\n\tfor (int i = 0; i < 4; i++)\n\t\tS += pow(10, 3 - i) * a[i];\n \tstring str_newNum = to_string(L - S);\n\tint length = str_newNum.length();\n\tfor (int i = 0; i < 4 - length; i++)\n\t\tstr_newNum = '0' + str_newNum;\n\treturn 1 + Func(str_newNum);\n}\n\nint main() \n{\n\tstring str_num;\n\tcin >> str_num;\n\twhile (str_num != \"0000\")\n\t{\n\t\tint num = stoi(str_num);\n\t\tif (num % 1111 == 0)\n\t\t\tcout << \"NA\\n\";\n\t\telse\n\t\t cout << Func(str_num) << endl;\n\t\tcin >> str_num;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3412, "score_of_the_acc": -1.6742, "final_rank": 18 }, { "submission_id": "aoj_0259_4646016", "code_snippet": "#include <bits/stdc++.h>\ntypedef long long lint;\nusing namespace std;\n#define rep(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)\n\nint f(string n) {\n int cnt = 0;\n while (n != \"6174\") {\n sort(n.begin(),n.end());\n int l = stoi(n);\n sort(n.begin(),n.end(), greater<int>());\n int s = stoi(n);\n if (s == l) {\n return -1;\n }\n ostringstream str;\n str << setfill('0') << setw(4) << s-l;\n n = str.str();\n cnt ++;\n }\n return cnt;\n}\n\nbool solve() {\n string n; cin >> n;\n if (n == \"0000\") return false;\n int cnt = f(n);\n if (cnt == -1) cout << \"NA\" << endl;\n else cout << cnt << endl;\n\n return true;\n}\n\nint main() {\n while (solve()) {}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3188, "score_of_the_acc": -1.0449, "final_rank": 16 } ]
aoj_0260_cpp
パイプつなぎ職人の給料 ぼくはパイプつなぎ職人です。パイプをつなぐジョイントとパイプさえもらえれば、どんなパイプだってつないでみせます。ぼくは毎日、親方からパイプとジョイントを渡されて、それをつないで親方に渡します。でも、パイプの数が多すぎるときは、1日でそれを全部つなげることはできません。そんなときでも親方はにっこり笑って、ぼくに給料を渡してくれます。 ところで、あるとき変なことに気がつきました。全部のパイプをつなげられたときより、つなげられなかったときの方が給料が多いことがしょっちゅうあるんです。あんまり変なので、ある日、親方が来たときに、給料の計算方法が書いてあるメモをこっそり見ちゃいました。そしたら、なんと "給料は「パイプの本数×パイプの長さの総和」で支払う。ただし、ジョイントでつなげて、ひとつながりになったものは、それを1本のパイプとみなす。" って書いてありました。これで全部つなげた方が給料が安くなることがある理由がわかりました。たとえば下図のように、長さ 1 のパイプ 3 本と長さ 2 のジョイント 2 本を全部つなげると長さ 1+2+1+2+1 = 7 のパイプが 1 本できるので、1 × (7) = 7 です。でも、ジョイントを一つだけ使って長さ 1+2+1 = 4のパイプと長さ 1 のパイプの 2 本にすると2 × (4+1) = 10なので、全部つなげるよりいっぱい給料がもらえます。 親方がなんでこんな方法で給料を決めてるかわからないけど、これでぼくもどうすればもらえる給料を多くできるかわかりました! それでは、パイプの本数が与えられたとき、もらえる給料の最大の金額を計算するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 n p 1 ... p n j 1 ... j n-1 1行目にパイプの本数 n (2 ≤ n ≤ 65000) が与えられる。2行目は1つの空白で区切られた n 個の整数からなる。p i (1 ≤ p i ≤ 1000) はi番目のパイプの長さを示す。3行目は1つの空白で区切られた n-1 個の整数からなる。j i (1 ≤ j i ≤ 1000) は i 番目のジョイントの長さを示す。 i番目のジョイントは、i 番目と i+1 番目のパイプだけをつなげることができる。つなげたパイプの長さは、p i + j i + p i+1 になる。 データセットの数は 100 を超えない。 出力 各データセットごとに、得られる給料の最大の金額を1行に出力する。入力として与えられるデータセットでは、出力される値は必ず32ビット符号無し整数の範囲に収まるものとする。 入力例1 3 1 1 1 3 3 4 3 3 3 3 1 1 1 5 1 2 3 4 5 4 3 2 1 0 出力例 12 48 76
[ { "submission_id": "aoj_0260_10867597", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,s,t) for(int i = s; i < t ; ++i)\n#define ALL(a) a.begin(),a.end()\n#define SORT(a) sort(ALL(a))\n#define UNIQ(a) a.erase(unique(ALL(a)),a.end())\n#define debug(a) cerr<<#a\":=\"<<a<<endl;\n#define SZ(a) (int)a.size()\nusing LL = long long; template<class T> using V = vector <T>; template <class T> using VV = V<V<T>>;\n\n// 変数jを今すぐやめろ\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint N;\n\twhile (cin >> N, N) {\n\t\tV<int>p(N), j(N);\n\t\tFOR(i, 0, N) {\n\t\t\tcin >> p[i];\n\t\t}\n\t\t\n\t\tFOR(i, 0, N - 1) {\n\t\t\tcin >> j[i];\n\t\t}\n\t\tsort(j.rbegin(), j.rend());\n\t\tLL sum = accumulate(ALL(p), 0LL);\n\t\tLL ans = sum*N;\n\t\tLL C = N;\n\t\tFOR(i, 0, N-1) {\n\t\t\tsum += j[i];\n\t\t\tC--;\n\t\t\tans = max(ans, (C)*sum);\n\t\t}\n\n\t\tcout << ans << endl;\n\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3560, "score_of_the_acc": -0.1294, "final_rank": 1 }, { "submission_id": "aoj_0260_10726984", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater<ll>())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\nvoid solve() {\n while(1) {\n ll n; cin>>n;\n if (n==0) break;\n ll h[n],j[n-1],p=0;\n rep(i,0,n) { cin>>h[i]; p+=h[i]; }\n rep(i,0,n-1) cin>>j[i];\n stR(h,n); stR(j,n-1);\n ll mx=0;\n rep(i,0,n) mx += i!=n-1 ? h[i]+j[i] : h[i] ;\n ll pp=0,c=n,s=0;\n rep(i,0,n) {\n pp+=h[i];\n if (i==0) s+=h[i];\n else { s+=h[i]+j[i-1]; c--; }\n mx=max(mx,c*(s+p-pp));\n }\n cout<<mx<<'\\n';\n }\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4164, "score_of_the_acc": -0.5364, "final_rank": 3 }, { "submission_id": "aoj_0260_10726967", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\nvoid solve() {\n while(1) {\n ll n; cin>>n;\n if (n==0) break;\n ll h[n],j[n-1],p=0;\n rep(i,0,n) { cin>>h[i]; p+=h[i]; }\n rep(i,0,n-1) cin>>j[i];\n sort(h,h+n,greater<ll>());\n sort(j,j+n-1,greater<ll>());\n ll mx=0;\n rep(i,0,n) mx += i!=n-1 ? h[i]+j[i] : h[i] ;\n ll pp=0,c=n,s=0;\n rep(i,0,n) {\n pp+=h[i];\n if (i==0) s+=h[i];\n else { s+=h[i]+j[i-1]; c--; }\n mx=max(mx,c*(s+p-pp));\n }\n cout<<mx<<'\\n';\n }\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4164, "score_of_the_acc": -0.5364, "final_rank": 3 }, { "submission_id": "aoj_0260_9992582", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cstdlib>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\n// 1行目にパイプの本数 n (2 ≤ n ≤ 65000) が与えられる。\n// 2行目は1つの空白で区切られた n 個の整数からなる。\n// pi (1 ≤ pi ≤ 1000) はi番目のパイプの長さを示す。\n// 3行目は1つの空白で区切られた n-1 個の整数からなる。\n// ji (1 ≤ ji ≤ 1000) は i 番目のジョイントの長さを示す。\n\nconst size_t N_MIN = 2;\nconst size_t N_MAX = 65000;\nconst size_t P_MIN = 1;\nconst size_t P_MAX = 1000;\nconst size_t J_MIN = 1;\nconst size_t J_MAX = 1000;\nconst size_t S_CNT = 6;\nconst size_t DATA_MAX = 100;\n\nint main()\n{\n vector<int> plist(0);\n vector<int> jlist(0);\n int datasetCnt = 0;\n while (datasetCnt < DATA_MAX)\n {\n int n = 0;\n cin >> n;\n // 0 で、データセット終了\n if (n == 0)\n {\n break;\n }\n if (n < N_MIN || N_MAX < n)\n {\n cout << N_MIN << \" <= n <= \" << N_MAX << \") but input \" << n << endl;\n exit(1);\n }\n long long totalPipe = 0;\n plist.resize(n);\n // パイプリスト入力\n for (int i = 0; i < n; i++)\n {\n cin >> plist[i];\n if (plist[i] < P_MIN || P_MAX < plist[i])\n {\n cout << P_MIN << \" <= pi <= \" << P_MAX << \") but input \" << plist[i] << endl;\n exit(1);\n }\n totalPipe += plist[i];\n }\n jlist.resize(n);\n // ジョイントリスト入力\n for (int i = 0; i < n - 1; i++)\n {\n cin >> jlist[i];\n if (jlist[i] < J_MIN || J_MAX < jlist[i])\n {\n cout << J_MIN << \" <= ji <= \" << J_MAX << \") but input \" << jlist[i] << endl;\n exit(1);\n }\n }\n // ジョイントを昇順でソート\n sort(jlist.begin(), jlist.end() - 1);\n // ジョイントを使わない場合 */\n jlist[n - 1] = 0;\n // 使用するジョイントの長さ\n long long totalJoint = 0;\n long long maxSalary = 0;\n // 給料の最大を探す\n for (int i = 0; i < n; i++)\n {\n totalJoint += jlist[n - 1 - i];\n long long v = (n - i) * (totalJoint + totalPipe);\n if (maxSalary < v)\n {\n maxSalary = v;\n }\n }\n\n cout << maxSalary << endl;\n datasetCnt++;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3368, "score_of_the_acc": -0.6, "final_rank": 6 }, { "submission_id": "aoj_0260_9597372", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define Rrep(i,n) for(int i=n-1;i>=0;i--)\n#define Rrep1(i,n) for(int i=n;i>0;i--)\n#define all(a) a.begin(),a.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\n#define INF ((ll)4e18)\n#define IINF ((int)1e9)\nconst double PI = 3.141592653589793;//2384626433832795028841971;\ntemplate<typename T>inline bool chmax(T& a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T>inline bool chmin(T& a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n#define yesno(ans) cout<<((ans)?\"Yes\\n\":\"No\\n\")\nbool eq(double a, double b) { return abs(a - b) < 0.0000001; }\n//LRUD\nconst int di[4] = { 0,-1,0,1 };\nconst int dj[4] = { -1,0,1,0 };\n//const int di[8] = { 0,0,1,1,1,-1,-1,-1 };\n//const int dj[8] = { 1,-1,0,-1,1,0,-1,1 };\n\n/*ACL\n#include <atcoder/all>\nusing namespace atcoder;\n//using mint=modint;\nusing mint = modint998244353;\n//using mint=modint1000000007;\nusing vm=vector<mint>;\nusing vvm=vector<vm>;\nusing vvvm=vector<vvm>;\n//*/\n\n\nint solve(){\n ll N;\n while(cin>>N,N){\n vl P(N),J(N-1);\n ll now=0;\n ll num=N;\n rep(i,N)cin>>P[i],now+=P[i];\n ll ans=now*N;\n rep(i,N-1)cin>>J[i];\n sort(all(J));\n reverse(all(J));\n rep(i,N-1){\n num--;\n now+=J[i];\n chmax(ans,now*num);\n }\n cout<<ans<<endl;\n }\n return 0;\n}\n\nint main()\n{\n //std::cin.tie(0)->sync_with_stdio(0);\n int T = 1;\n //cin>>T;\n while (T--)\n {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3932, "score_of_the_acc": -0.7801, "final_rank": 8 }, { "submission_id": "aoj_0260_9580197", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void)\n{\n\tint n,p,s,jj[65000],i,j,x,c;\n\tlong long mx,sum;\n\twhile(1)\t{\n\t\tcin >>n;\n\t\tif(n==0)\tbreak;\n\t\ts=0;\n\t\tfor(i=0;i<n;i++)\t{\n\t\t\tcin >>p;\n\t\t\ts+=p;\n\t\t}\n\t\tfor(i=0;i<n-1;i++)\t{\n\t\t\tcin >>jj[i];\n\t\t}\n\t\tsort(jj,jj+n-1,greater<int>() );\n\t\tc=n;\n\t\tmx=(long long)s*c;\n\t\tc--;\n\t\tfor(i=0;i<n-1;i++)\t{\n\t\t\ts+=jj[i];\n\t\t\tsum=(long long)s*c;\n\t\t\tmx=max(mx,sum);\n\t\t\tc--;\n\t\t}\n\t\tcout <<mx<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3400, "score_of_the_acc": -0.6216, "final_rank": 7 }, { "submission_id": "aoj_0260_9231953", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {}\n return 0;\n}\n\nint solve() {\n ll n;\n cin >> n;\n if (n == 0) return 1;\n vi p(n), j(n-1);\n rep(i, n) cin >> p[i];\n rep(i, n-1) cin >> j[i];\n sort(all(j), greater<ll>());\n ll s = SUM(p);\n ll ans = s * n;\n rep(i, n-1) {\n s += j[i];\n if (!chmax(ans, s*(n-(i+1)))) break;\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4132, "score_of_the_acc": -0.5148, "final_rank": 2 }, { "submission_id": "aoj_0260_8281730", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <numeric>\nusing namespace std;\n\nint main() {\n int n;\n while (cin >> n && n != 0) {\n vector<int> p(n);\n for (int i = 0; i < n; i++) cin >> p[i];\n vector<int> j(n-1);\n for (int i = 0; i < n-1; i++) cin >> j[i];\n sort(j.begin(), j.end());\n\n long long sum = accumulate(p.begin(), p.end(), 0);\n while (n > 1 && (n-1)*j.back() > sum) {\n n--;\n sum += j.back();\n j.pop_back();\n }\n cout << n*sum << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3592, "score_of_the_acc": -0.5509, "final_rank": 5 }, { "submission_id": "aoj_0260_8281706", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <numeric>\nusing namespace std;\n\nvector<int> merge_sorted(vector<int> vec0) {\n const int N = vec0.size();\n if (N == 1) return vec0;\n vector<int> vec1(N/2), vec2(N-N/2);\n for (int i = 0; i < N; i++) {\n if (i < N/2) vec1[i] = vec0[i];\n else vec2[i-N/2] = vec0[i];\n }\n vec1 = merge_sorted(vec1);\n reverse(vec1.begin(), vec1.end());\n vec2 = merge_sorted(vec2);\n reverse(vec2.begin(), vec2.end());\n vector<int> vec3;\n while (!vec1.empty() || !vec2.empty()) {\n if (vec2.empty() || !vec1.empty() &&\n vec1.back() < vec2.back()) {\n vec3.push_back(vec1.back());\n vec1.pop_back();\n } else {\n vec3.push_back(vec2.back());\n vec2.pop_back();\n }\n }\n return vec3;\n}\n\nint main() {\n int n;\n while (cin >> n && n != 0) {\n vector<int> p(n);\n for (int i = 0; i < n; i++) cin >> p[i];\n vector<int> j(n-1);\n for (int i = 0; i < n-1; i++) cin >> j[i];\n j = merge_sorted(j);\n\n int sum = accumulate(p.begin(), p.end(), 0);\n while (n > 1 && (n-1)*j.back() > sum) {\n n--;\n sum += j.back();\n j.pop_back();\n }\n cout << (long long)n*sum << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4708, "score_of_the_acc": -1.903, "final_rank": 16 }, { "submission_id": "aoj_0260_8281638", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <numeric>\nusing namespace std;\n\nvector<int> merge_sorted(vector<int> vec0) {\n const int N = vec0.size();\n if (N == 1) return vec0;\n vector<int> vec1(N/2), vec2((N+1)/2);\n for (int i = 0; i < N; i++) {\n if (i < N/2) vec1[i] = vec0[i];\n else vec2[i-N/2] = vec0[i];\n }\n vec1 = merge_sorted(vec1);\n reverse(vec1.begin(), vec1.end());\n vec2 = merge_sorted(vec2);\n reverse(vec2.begin(), vec2.end());\n vector<int> vec3;\n while (!vec1.empty() || !vec2.empty()) {\n if (vec2.empty() || !vec1.empty() &&\n vec1.back() < vec2.back()) {\n vec3.push_back(vec1.back());\n vec1.pop_back();\n } else {\n vec3.push_back(vec2.back());\n vec2.pop_back();\n }\n }\n return vec3;\n}\n\nint main() {\n int n;\n while (cin >> n && n != 0) {\n vector<int> p(n);\n for (int i = 0; i < n; i++) cin >> p[i];\n vector<int> j(n-1);\n for (int i = 0; i < n-1; i++) cin >> j[i];\n j = merge_sorted(j);\n\n int sum = accumulate(p.begin(), p.end(), 0);\n while (n > 1 && (n-1)*j.back() > sum) {\n n--;\n sum += j.back();\n j.pop_back();\n }\n cout << (long)n*sum << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4852, "score_of_the_acc": -2, "final_rank": 17 }, { "submission_id": "aoj_0260_8281633", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <numeric>\nusing namespace std;\n\nvector<int> merge_sorted(vector<int> vec0) {\n const int N = vec0.size();\n if (N == 1) return vec0;\n vector<int> vec1(N/2), vec2((N+1)/2);\n for (int i = 0; i < N; i++) {\n if (i < N/2) vec1[i] = vec0[i];\n else vec2[i-N/2] = vec0[i];\n }\n vec1 = merge_sorted(vec1);\n reverse(vec1.begin(), vec1.end());\n vec2 = merge_sorted(vec2);\n reverse(vec2.begin(), vec2.end());\n vector<int> vec3;\n while (!vec1.empty() || !vec2.empty()) {\n if (vec2.empty() || !vec1.empty() &&\n vec1.back() < vec2.back()) {\n vec3.push_back(vec1.back());\n vec1.pop_back();\n } else {\n vec3.push_back(vec2.back());\n vec2.pop_back();\n }\n }\n return vec3;\n}\n\nint main() {\n int n;\n while (cin >> n && n != 0) {\n vector<int> p(n);\n for (int i = 0; i < n; i++) cin >> p[i];\n vector<int> j(n-1);\n for (int i = 0; i < n-1; i++) cin >> j[i];\n j = merge_sorted(j);\n\n int sum = accumulate(p.begin(), p.end(), 0);\n while (n > 1 && (n-1)*j.back() > sum) {\n n--;\n sum += j.back();\n j.pop_back();\n }\n cout << n * sum << endl;\n }\n \n return 0;\n}", "accuracy": 0.5, "time_ms": 60, "memory_kb": 4724, "score_of_the_acc": -1.9137, "final_rank": 20 }, { "submission_id": "aoj_0260_8214620", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nmain() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3656, "score_of_the_acc": -0.9941, "final_rank": 13 }, { "submission_id": "aoj_0260_8214619", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nmain() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3608, "score_of_the_acc": -0.9617, "final_rank": 11 }, { "submission_id": "aoj_0260_8213800", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\nvector<LL> ans;\nvoid prosess(int n){\n LL sum=0;\n vector<LL> p(n,0),j(n,0);\n for(int i=0;i<n;i++) cin>>p[i],sum+=p[i];\n for(int i=0;i<n-1;i++) cin>>j[i];\n sort(j.begin(),j.end(),greater<LL>());\n LL mx=sum*n;\n for(int i=0;i<n-1;i++) mx=max(mx,(sum+j[i])*(n-(i+1))),sum+=j[i];\n ans.push_back(mx);\n}\nint main()\n{\n while(1){\n int n;\n cin>>n;\n if(n!=0) prosess(n);\n else{\n for(int i=0;i<ans.size();i++) cout<<ans[i]<<endl;\n return 0;\n }\n }\n \n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3852, "score_of_the_acc": -1.1261, "final_rank": 15 }, { "submission_id": "aoj_0260_8213776", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\nvector<LL> ans;\nvoid prosess(int n){\n LL sum=0;\n vector<LL> p(n,0),j(n,0);\n for(int i=0;i<n;i++) cin>>p[i],sum+=p[i];\n for(int i=0;i<n-1;i++) cin>>j[i];\n sort(j.begin(),j.end(),greater<LL>());\n LL mx=sum*n;\n for(int i=0;i<n-1;i++) mx=max(mx,(sum+j[i])*(n-(i+1)));\n ans.push_back(mx);\n}\nint main()\n{\n while(1){\n int n;\n cin>>n;\n if(n!=0) prosess(n);\n else{\n for(int i=0;i<ans.size();i++) cout<<ans[i]<<endl;\n return 0;\n }\n }\n \n}", "accuracy": 0.5, "time_ms": 50, "memory_kb": 3932, "score_of_the_acc": -1.1801, "final_rank": 19 }, { "submission_id": "aoj_0260_8207313", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nint main() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3620, "score_of_the_acc": -0.9698, "final_rank": 12 }, { "submission_id": "aoj_0260_8207312", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nmain() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3660, "score_of_the_acc": -0.9968, "final_rank": 14 }, { "submission_id": "aoj_0260_8207311", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nmain() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3580, "score_of_the_acc": -0.9429, "final_rank": 9 }, { "submission_id": "aoj_0260_8207309", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nmain() {\n for (long long i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (int i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3604, "score_of_the_acc": -0.959, "final_rank": 10 }, { "submission_id": "aoj_0260_8207306", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nmain() {\n for (int i, n, j[99999], s, a;; cout << a << endl) {\n cin >> n;\n if (!n)\n break;\n for (i = s = 0; i++ < n; s += a)\n cin >> a;\n for (i = n; i > 1; cin >> j[--i])\n ;\n for (sort(j + 1, j + n); n > 0; s += j[n])\n a = max(n-- * s, a);\n }\n}", "accuracy": 0.5, "time_ms": 50, "memory_kb": 3368, "score_of_the_acc": -0.8, "final_rank": 18 } ]
aoj_0262_cpp
すごろくを作る 太郎君は、子供会の催しでみんなで遊べるようにすごろくを作りました。ゲームをおもしろくするために、「ふりだし」と「あがり」以外のすごろくのマスのいくつかに「6つ進む」、「5つ戻る」のように指示を書き込んでいきました。ルーレットを回して出た数だけ進み、止まったマスに指示が書き込んであれば、その指示に従って移動します。ただし、指示に従って進んだ先のマスの指示には従いません。 ルーレットは1からある数までの間の数を等確率で出すことができるものとします。また、「あがり」に達するより大きな数が出たときや、指示に従うと「あがり」より先に進んでしまうときは「あがり」に移動します。指示に従って戻るときに「ふりだし」より前に戻ってしまうときは「ふりだし」に戻ることにします。 ところが、ルーレットとマスの指示によっては「あがり」にたどりつけない場合が出てきてしまいます。たとえば、図のようなすごろくを作ったとしましょう。1と2しか出ないルーレットを使うと、1,2の順に出れば「あがり」に行けますが、はじめに2が出たらその後は何が出ても永久に「あがり」にはたどり着けません。太郎君は、そうとは知らずに調子に乗ってあちこちのマスに指示を書き込んでしまいました。 そこで、太郎君に代わって、ルーレットとマスの指示によっては、「あがり」にたどり着けない場合が生じるかどうか判定するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 max n d 1 d 2 . . . d n 1行目にルーレットが出す数の最大値 max (2 ≤ max ≤ 250) が与えられ、2行目に「ふりだし」と「あがり」以外のマスの数 n (2 ≤ n ≤ 250) が与えられる。続く n 行に各マスの指示を表す数 d i (-n ≤ d i ≤ n) が与えられる。d i がゼロのときは指示が書いていないことを、正の数のときは |d i | 進む指示を、負の数のときは |d i | 戻る指示を表す(ここで、|x| は x の絶対値を表す)。入力される値はすべて整数である。 データセットの数は 100 を超えない。 出力 各データセットごとに判定結果を1行に出力する。ルーレットとマスの指示によっては、「あがり」にたどり着けない場合が生じるときは「NG」、そうでなければ「OK」を出力する。 入力例 3 3 -2 1 0 2 4 2 0 -1 -2 2 2 -2 -2 0 出力例 OK NG NG
[ { "submission_id": "aoj_0262_9597880", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define Rrep(i,n) for(int i=n-1;i>=0;i--)\n#define Rrep1(i,n) for(int i=n;i>0;i--)\n#define all(a) a.begin(),a.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\n#define INF ((ll)4e18)\n#define IINF ((int)1e9)\nconst double PI = 3.141592653589793;//2384626433832795028841971;\ntemplate<typename T>inline bool chmax(T& a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T>inline bool chmin(T& a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n#define yesno(ans) cout<<((ans)?\"Yes\\n\":\"No\\n\")\nbool eq(double a, double b) { return abs(a - b) < 0.0000001; }\n//LRUD\nconst int di[4] = { 0,-1,0,1 };\nconst int dj[4] = { -1,0,1,0 };\n//const int di[8] = { 0,0,1,1,1,-1,-1,-1 };\n//const int dj[8] = { 1,-1,0,-1,1,0,-1,1 };\n\n/*ACL\n#include <atcoder/all>\nusing namespace atcoder;\n//using mint=modint;\nusing mint = modint998244353;\n//using mint=modint1000000007;\nusing vm=vector<mint>;\nusing vvm=vector<vm>;\nusing vvvm=vector<vvm>;\n//*/\n\n\nint solve(){\n int mx=0;\n while(cin>>mx,mx){\n int N;cin>>N;\n N+=2;\n vi D(N);\n rep1(i,N-2)cin>>D[i];\n D[0]=D[N-1]=0;\n vector<vector<bool>> G(N,vector<bool>(N,0));\n rep(i,N){\n //G[i][i]=1;\n for(int me=1;me<=mx;me++){\n int to=i+me;\n if(to<0)to=0;\n if(to>=N)to=N-1;\n to+=D[to];\n if(to<0)to=0;\n if(to>=N)to=N-1;\n G[i][to]=1;\n }\n }\n \n rep(k,N)rep(i,N)rep(j,N){\n G[i][j]=G[i][j]||(G[i][k]&&G[k][j]);\n }\n // rep(i,N){\n // rep(j,N)cout<<G[i][j];cout<<endl;\n // }\n bool isng=0;\n rep(i,N){\n if(G[0][i]==1&&G[i][N-1]==0){\n //cout<<i<<\" \"<<endl;\n isng=1;\n }\n }\n if(!isng){\n cout<<\"OK\\n\";\n }else{\n cout<<\"NG\\n\";\n }\n\n }\n return 0;\n}\n\nint main()\n{\n //std::cin.tie(0)->sync_with_stdio(0);\n int T = 1;\n //cin>>T;\n while (T--)\n {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 2150, "memory_kb": 3348, "score_of_the_acc": -1.1116, "final_rank": 14 }, { "submission_id": "aoj_0262_5839803", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<climits>\n#include<iomanip>\n#include<cctype>\n#include<sstream>\n#include<regex>\n#include<bitset>\n#include<random>\n#include<complex>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nvector<int>G[252],revG[252];\nbool used1[252],used2[252];\nvoid dfs1(int v){\n\tused1[v]=1;\n\tfor(auto x:G[v])\n\t\tif(!used1[x])\n\t\t\tdfs1(x);\n}\nvoid dfs2(int v){\n\tused2[v]=1;\n\tfor(auto x:revG[v])\n\t\tif(!used2[x])\n\t\t\tdfs2(x);\n}\nsigned main(){\n\tint mx;\n\twhile(cin>>mx,mx){\n\t\tint n,d;\n\t\tmap<int,int>mp;\n\t\tcin>>n;\n\t\tfor(int i=0;i<=n+1;i++){\n\t\t\tG[i].clear();\n\t\t\trevG[i].clear();\n\t\t}\n\t\tfill(used1,used1+n+2,0);\n\t\tfill(used2,used2+n+2,0);\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tcin>>d;\n\t\t\tmp[i]=d;\n\t\t}\n\t\tfor(int i=0;i<=n;i++){\n\t\t\tfor(int j=1;j<=mx;j++){\n\t\t\t\tG[i].push_back(clamp(i+j+mp[i+j],0ll,n+1));\n\t\t\t\trevG[clamp(i+j+mp[i+j],0ll,n+1)].push_back(i);\n\t\t\t}\n\t\t}\n\t\tdfs1(0);\n\t\tdfs2(n+1);\n\t\tbool ans=0;\n\t\tfor(int i=0;i<=n+1;i++)\n\t\t\tif(used1[i]&&!used2[i])\n\t\t\t\tans=1;\n\t\tcout<<(ans?\"NG\":\"OK\")<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3492, "score_of_the_acc": -0.1904, "final_rank": 5 }, { "submission_id": "aoj_0262_5797148", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\nusing namespace std;\n\nint main(){\n while(true){\n int rmax;\n cin >> rmax;\n if(rmax == 0) break;\n int n;\n cin >> n;\n vector<int> d(n+1);\n for(int i = 1; i <= n; i++) cin >> d[i];\n\n vector<vector<int>> G(n+2);\n for(int i = 0; i <= n; i++){\n for(int j = i+1; j <= min(i+rmax, n+1); j++){\n int nex = j + d[j];\n if(nex < 0) nex = 0;\n if(nex > n+1) nex = n+1;\n G[i].push_back(nex);\n }\n }\n \n vector<vector<int>> isReachable(n+2, vector<int>(n+2, 0));\n for(int start = 0; start < n+2; start++){\n isReachable[start][start] = 1;\n queue<int> Q;\n Q.push(start);\n while(Q.size()){\n int cur = Q.front(); Q.pop();\n for(auto &p: G[cur]){\n if(isReachable[start][p] == 0){\n isReachable[start][p] = 1;\n Q.push(p);\n }\n }\n }\n }\n\n string ans = \"OK\";\n if(isReachable[0][n+1] == 0) ans = \"NG\";\n for(int i = 1; i <= n; i++){\n if(isReachable[0][i] == 1 && isReachable[i][n+1] == 0){\n ans = \"NG\";\n }\n }\n\n cout << ans << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3408, "score_of_the_acc": -0.1491, "final_rank": 4 }, { "submission_id": "aoj_0262_4749191", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// End Header }}}\n\n// Edge {{{\ntemplate <class Weight>\nstruct Edge {\n size_t from, to;\n Weight weight;\n\n Edge() {}\n Edge(size_t from, size_t to, Weight weight = 1) :\n from(from), to(to), weight(weight)\n {}\n\n bool operator<(const Edge &rhs) const {\n return weight < rhs.weight;\n }\n\n bool operator>(const Edge &rhs) const {\n return weight > rhs.weight;\n }\n\n operator size_t() const {\n return to;\n }\n};\n// }}}\n\n// Graph {{{\ntemplate <class Weight>\nclass Graph : public vector<vector<Edge<Weight>>> {\n using graph = vector<vector<Edge<Weight>>>;\n\npublic:\n Graph() {}\n Graph(const size_t V) : graph(V) {}\n\n void connect(size_t from, size_t to, Weight weight = 1) {\n (*this)[from].emplace_back(from, to, weight);\n }\n\n friend ostream& operator<<(ostream &strm, const Graph &G) {\n for (size_t v = 0; v < G.size(); ++v) {\n strm << '[' << setw(2) << v << ']';\n for (const auto &e: G[v]) {\n strm << ' ' << setw(2) << e.to;\n }\n strm << '\\n';\n }\n return strm;\n }\n};\n// }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(20);\n\n intmax_t M;\n while (cin >> M, M) {\n var(intmax_t, N);\n vector<intmax_t> d(N + 2);\n reps(i, 1, N) input(d[i]);\n\n const auto clamp = [&](intmax_t v) -> intmax_t {\n if (v < 0) {\n return 0;\n } else if (N + 1 < v) {\n return N + 1;\n } else {\n return v;\n }\n };\n\n vector<bool> seen(N + 2, false);\n const auto dfs = makeFixPoint([&](auto dfs, size_t cur) -> bool {\n seen[cur] = true;\n if (cur == N + 1) return true;\n bool ret = false;\n reps(k, 1, M) {\n const intmax_t v = clamp(cur + k);\n const intmax_t nxt = clamp(v + d[v]);\n if (!seen[nxt]) ret |= dfs(nxt);\n }\n return ret;\n });\n\n dfs(0);\n\n auto can_reach = seen;\n\n bool valid = true;\n reps(i, 0, N) {\n seen.assign(N + 2, false);\n if (can_reach[i] && !dfs(i)) {\n valid = false;\n break;\n }\n }\n\n output((valid) ? \"OK\" : \"NG\");\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3208, "score_of_the_acc": -0.0444, "final_rank": 3 }, { "submission_id": "aoj_0262_4749158", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// End Header }}}\n\n// Edge {{{\ntemplate <class Weight>\nstruct Edge {\n size_t from, to;\n Weight weight;\n\n Edge() {}\n Edge(size_t from, size_t to, Weight weight = 1) :\n from(from), to(to), weight(weight)\n {}\n\n bool operator<(const Edge &rhs) const {\n return weight < rhs.weight;\n }\n\n bool operator>(const Edge &rhs) const {\n return weight > rhs.weight;\n }\n\n operator size_t() const {\n return to;\n }\n};\n// }}}\n\n// Graph {{{\ntemplate <class Weight>\nclass Graph : public vector<vector<Edge<Weight>>> {\n using graph = vector<vector<Edge<Weight>>>;\n\npublic:\n Graph() {}\n Graph(const size_t V) : graph(V) {}\n\n void connect(size_t from, size_t to, Weight weight = 1) {\n (*this)[from].emplace_back(from, to, weight);\n }\n\n friend ostream& operator<<(ostream &strm, const Graph &G) {\n for (size_t v = 0; v < G.size(); ++v) {\n strm << '[' << setw(2) << v << ']';\n for (const auto &e: G[v]) {\n strm << ' ' << setw(2) << e.to;\n }\n strm << '\\n';\n }\n return strm;\n }\n};\n// }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(20);\n\n intmax_t M;\n while (cin >> M, M) {\n var(intmax_t, N);\n vector<intmax_t> d(N + 2);\n reps(i, 1, N) input(d[i]);\n\n const auto clamp = [&](intmax_t v) -> intmax_t {\n if (v < 0) {\n return 0;\n } else if (N + 1 < v) {\n return N + 1;\n } else {\n return v;\n }\n };\n\n auto to = makeVector<bool>(false, N + 2, N + 2);\n reps(i, 0, N + 1) to[i][i] = true;\n\n reps(i, 0, N) reps(j, 1, M) {\n const intmax_t v = clamp(i + j);\n const intmax_t w = clamp(v + d[v]);\n to[i][w] = true;\n }\n\n vector<bool> seen(N + 2, false);\n vector<int> dp(N + 2, -1);\n const auto dfs = makeFixPoint([&](auto dfs, size_t cur) -> bool {\n if (cur == N + 1) return true;\n seen[cur] = true;\n auto& ret = dp[cur];\n if (~ret) return ret;\n ret = false;\n reps(nxt, 0, N + 1) {\n if (!seen[nxt] && to[cur][nxt]) ret |= dfs(nxt);\n }\n return ret;\n });\n\n dfs(0);\n\n bool valid = true;\n reps(i, 0, N) {\n if (seen[i] && !dp[i]) {\n valid = false;\n break;\n }\n }\n\n output((valid) ? \"OK\" : \"NG\");\n }\n\n return 0;\n}", "accuracy": 0.5, "time_ms": 20, "memory_kb": 3160, "score_of_the_acc": -0.0134, "final_rank": 18 }, { "submission_id": "aoj_0262_4749134", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// End Header }}}\n\n// Edge {{{\ntemplate <class Weight>\nstruct Edge {\n size_t from, to;\n Weight weight;\n\n Edge() {}\n Edge(size_t from, size_t to, Weight weight = 1) :\n from(from), to(to), weight(weight)\n {}\n\n bool operator<(const Edge &rhs) const {\n return weight < rhs.weight;\n }\n\n bool operator>(const Edge &rhs) const {\n return weight > rhs.weight;\n }\n\n operator size_t() const {\n return to;\n }\n};\n// }}}\n\n// Graph {{{\ntemplate <class Weight>\nclass Graph : public vector<vector<Edge<Weight>>> {\n using graph = vector<vector<Edge<Weight>>>;\n\npublic:\n Graph() {}\n Graph(const size_t V) : graph(V) {}\n\n void connect(size_t from, size_t to, Weight weight = 1) {\n (*this)[from].emplace_back(from, to, weight);\n }\n\n friend ostream& operator<<(ostream &strm, const Graph &G) {\n for (size_t v = 0; v < G.size(); ++v) {\n strm << '[' << setw(2) << v << ']';\n for (const auto &e: G[v]) {\n strm << ' ' << setw(2) << e.to;\n }\n strm << '\\n';\n }\n return strm;\n }\n};\n// }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(20);\n\n intmax_t M;\n while (cin >> M, M) {\n var(intmax_t, N);\n vector<intmax_t> d(N + 2);\n reps(i, 1, N) input(d[i]);\n\n const auto clamp = [&](intmax_t v) -> intmax_t {\n if (v < 0) {\n return 0;\n } else if (N + 1 < v) {\n return N + 1;\n } else {\n return v;\n }\n };\n\n auto to = makeVector<bool>(false, N + 2, N + 2);\n reps(i, 0, N + 1) to[i][i] = true;\n\n reps(i, 0, N) reps(j, 1, M) {\n const intmax_t v = clamp(i + j);\n const intmax_t w = clamp(v + d[v]);\n to[i][w] = true;\n }\n\n vector<bool> seen(N + 2, false);\n vector<int> dp(N + 2, -1);\n const auto dfs = makeFixPoint([&](auto dfs, size_t cur) -> bool {\n if (cur == N + 1) return true;\n seen[cur] = true;\n to[0][cur] = true;\n auto& ret = dp[cur];\n if (~ret) return ret;\n ret = false;\n reps(nxt, 0, N + 1) {\n if (!seen[nxt] && to[cur][nxt]) ret |= dfs(nxt);\n }\n return ret;\n });\n\n dfs(0);\n\n bool valid = true;\n reps(i, 0, N) {\n if (to[0][i] && !dp[i]) {\n valid = false;\n break;\n }\n }\n\n output((valid) ? \"OK\" : \"NG\");\n }\n\n return 0;\n}", "accuracy": 0.5, "time_ms": 20, "memory_kb": 3248, "score_of_the_acc": -0.0616, "final_rank": 19 }, { "submission_id": "aoj_0262_4664929", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<math.h>\nusing namespace std;\ntypedef long long ll;\n#define int long long\n#define double long double\ntypedef vector<int> VI;\ntypedef pair<int, int> pii;\ntypedef vector<pii> VP;\ntypedef vector<string> VS;\ntypedef priority_queue<int> PQ;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b < a) { a = b; return 1; } return 0; }\n#define fore(i,a) for(auto &i:a)\n#define REP(i,n) for(int i=0;i<n;i++)\n#define eREP(i,n) for(int i=0;i<=n;i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define eFOR(i,a,b) for(int i=(a);i<=(b);++i)\n#define SORT(c) sort((c).begin(),(c).end())\n#define rSORT(c) sort((c).rbegin(),(c).rend())\n#define LB(x,a) lower_bound((x).begin(),(x).end(),(a))\n#define UB(x,a) upper_bound((x).begin(),(x).end(),(a))\n#define INF 1000000000\n#define LLINF 9223372036854775807\n#define mod 1000000007\n#define eps 1e-12 \n//priority_queue<int,vector<int>, greater<int> > q2;\nint N;\nint G[300][300];\n\nvoid warshall() {\n\tREP(i, N + 2) {\n\t\tREP(j, N + 2) {\n\t\t\tREP(k, N + 2) {\n\t\t\t\tG[j][k] = min(G[j][k], G[j][i] + G[i][k]);\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nstring solve(int M) {\n\tcin >> N;\n\n\tVI D(N);\n\tREP(i, N)cin >> D[i];\n\tqueue<int>Q;\n\tvector<bool>F(N + 1, false);\n\tF[0] = 1;\n\tQ.push(0);\n\twhile (!Q.empty()) {\n\t\tint from = Q.front(); Q.pop();\n\t\teFOR(i, 1, M) {\n\t\t\tint to = from + i;\n\t\t\tif (to > N + 1)break;\n\t\t\tif (to == N + 1) {\n\t\t\t\t//G[from].push_back(to);\n\t\t\t\tG[from][to] = 1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tto += D[to - 1];\n\t\t\t\tif (to < 0)to = 0;\n\t\t\t\tif (to > N + 1)to = N + 1;\n\t\t\t\t//if (from != to) {\n\t\t\t\t\t//G[from].push_back(to);\n\t\t\t\t\t//cout << from << \" \" << to << endl;\n\t\t\t\t\tG[from][to] = 1;\n\t\t\t\t\tif (!F[to]) {\n\t\t\t\t\t\tF[to] = 1;\n\t\t\t\t\t\tQ.push(to);\n\t\t\t\t\t}\n\t\t\t\t//}\n\t\t\t}\n\t\t}\n\t}\n\twarshall();\n\teREP(i, N) {\n\t\t//cout << i + 1 << \" \" << G[0][i + 1] << \" \" << G[i + 1][N + 1] << endl;\n\t\tif (G[0][i] != INF && G[i][N + 1] == INF) {\n\t\t\t//cout << i + 1 << endl;\n\t\t\treturn \"NG\";\n\t\t}\n\t}\n\treturn \"OK\";\n}\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tint M = 1;\n\twhile (M) {\n\t\tREP(i, 300)REP(j, 300)G[i][j] = INF;\n\t\tcin >> M;\n\t\tif (!M)return 0;\n\t\tcout << solve(M) << '\\n';\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1330, "memory_kb": 3896, "score_of_the_acc": -1.0282, "final_rank": 13 }, { "submission_id": "aoj_0262_4553812", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint Step, N;\nint NodeInfo[252];\nbool Result[252][252];\n\n\nbool solve() {\n\n\tfor (int k = 0; k <= N + 1; ++k) {\n\t\tfor (int i = 0; i <= N + 1; ++i) {\n\t\t\tfor (int j = 0; j <= N + 1; ++j) {\n\t\t\t\tif (Result[i][k] && Result[k][j]) {\n\t\t\t\t\tResult[i][j] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i <= N; ++i) {\n\t\tif (Result[0][i] && (!Result[i][N + 1])) {\n\t\t\treturn false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nvoid createMapData() {\n\tint currentNode;\n\n\tfor (int i = 0; i <= N; ++i) {\n\t\tfor (int j = 1; j <= Step; ++j) {\n\t\t\tcurrentNode = i + j;\n\t\t\tif (currentNode > N) {\n\t\t\t\tResult[i][N + 1] = true;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tcurrentNode = max(0, currentNode += NodeInfo[currentNode]);\n\t\t\tif (currentNode >= N) {\n\t\t\t\tResult[i][N + 1] = true;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tResult[i][currentNode] = true;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\n\twhile (cin >> Step, Step) {\n\t\tmemset(NodeInfo, 0, sizeof(NodeInfo));\n\t\tmemset(Result, false, sizeof(Result));\n\t\tcin >> N;\n\t\tfor (int i = 1; i <= N; ++i) {\n\t\t\tcin >> NodeInfo[i];\n\t\t}\n\n\t\tcreateMapData();\n\t\tif (solve()) {\n\t\t\tcout << \"OK\" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << \"NG\" << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 3144, "score_of_the_acc": -0.4065, "final_rank": 6 }, { "submission_id": "aoj_0262_4553019", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint Step, N;\nint NodeInfo[252];\nbool Result[252][252], Used[252];\n\n\nvoid solve() {\n\n\tfor (int k = 0; k <= N+1; ++k) {\n\t\tfor (int i = 0; i <= N+1; ++i) {\n\t\t\tfor (int j = 0; j <= N+1; ++j) {\n\t\t\t\tif (i == j || Result[i][j]) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif (Result[i][k] && Result[k][j]) {\n\t\t\t\t\tResult[i][j] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i <= N; ++i) {\n\t\tif (Result[0][i] && (!Result[i][N + 1])) {\n\t\t\tcout << \"NG\" << endl;\n\t\t\treturn;\n\t\t}\n\t}\n\t\n\tcout << \"OK\" << endl;\n}\n\nvoid createMapDataByBFS() {\n\tint startNode, currentNode;\n\tqueue<int> nodeList;\n\n\tnodeList.push(0);\n\twhile (!nodeList.empty()) {\n\t\tstartNode = nodeList.front();\n\t\tnodeList.pop();\n\t\tif (Used[startNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tUsed[startNode] = true;\n\n\t\tfor (int i = 1; i <= Step; ++i) {\n\t\t\tcurrentNode = startNode + i;\n\t\t\tif (currentNode > N) {\n\t\t\t\tResult[startNode][N+1] = true;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tcurrentNode = max(0, currentNode += NodeInfo[currentNode]);\n\t\t\tif (currentNode >= N) {\n\t\t\t\tResult[startNode][N+1] = true;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tResult[startNode][currentNode] = true;\n\t\t\t\tnodeList.push(currentNode);\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid createMapData() {\n\tint currentNode;\n\n\tfor (int i = 0; i <= N; ++i) {\n\t\tfor (int j = 1; j <= Step; ++j) {\n\t\t\tcurrentNode = i + j;\n\t\t\tif (currentNode > N) {\n\t\t\t\tResult[i][N + 1] = true;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tcurrentNode = max(0, currentNode += NodeInfo[currentNode]);\n\t\t\tif (currentNode > N) {\n\t\t\t\tResult[i][N + 1] = true;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tResult[i][currentNode] = true;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\n\twhile (cin >> Step, Step) {\n\t\tmemset(NodeInfo, 0, sizeof(NodeInfo));\n\t\tmemset(Result, false, sizeof(Result));\n\t\tmemset(Used, false, sizeof(Used));\n\t\tcin >> N;\n\t\tfor (int i = 1; i <= N; ++i) {\n\t\t\tcin >> NodeInfo[i];\n\t\t}\n\n\t\t//createMapDataByBFS();\n\t\tcreateMapData();\n\t\tsolve();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 3172, "score_of_the_acc": -0.8705, "final_rank": 12 }, { "submission_id": "aoj_0262_4552998", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint Step, N;\nint NodeInfo[252];\nbool Result[252][252], Used[252];\n\n\nvoid solve() {\n\n\tfor (int k = 0; k <= N+1; ++k) {\n\t\tfor (int i = 0; i <= N+1; ++i) {\n\t\t\tfor (int j = 0; j <= N+1; ++j) {\n\t\t\t\tif (i == j || Result[i][j]) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif (Result[i][k] && Result[k][j]) {\n\t\t\t\t\tResult[i][j] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i <= N; ++i) {\n\t\tif (Result[0][i] && (!Result[i][N + 1])) {\n\t\t\tcout << \"NG\" << endl;\n\t\t\treturn;\n\t\t}\n\t}\n\t\n\tcout << \"OK\" << endl;\n}\n\nvoid createMapData() {\n\tint startNode, currentNode;\n\tqueue<int> nodeList;\n\n\tnodeList.push(0);\n\twhile (!nodeList.empty()) {\n\t\tstartNode = nodeList.front();\n\t\tnodeList.pop();\n\t\tif (Used[startNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tUsed[startNode] = true;\n\n\t\tfor (int i = 1; i <= Step; ++i) {\n\t\t\tcurrentNode = startNode + i;\n\t\t\tif (currentNode > N) {\n\t\t\t\tResult[startNode][N+1] = true;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tcurrentNode = max(0, currentNode += NodeInfo[currentNode]);\n\t\t\tif (currentNode >= N) {\n\t\t\t\tResult[startNode][N+1] = true;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tResult[startNode][currentNode] = true;\n\t\t\t\tnodeList.push(currentNode);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\n\twhile (cin >> Step, Step) {\n\t\tmemset(NodeInfo, 0, sizeof(NodeInfo));\n\t\tmemset(Result, false, sizeof(Result));\n\t\tmemset(Used, false, sizeof(Used));\n\t\tcin >> N;\n\t\tfor (int i = 1; i <= N; ++i) {\n\t\t\tcin >> NodeInfo[i];\n\t\t}\n\n\t\tcreateMapData();\n\t\tsolve();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1680, "memory_kb": 3212, "score_of_the_acc": -0.8176, "final_rank": 11 }, { "submission_id": "aoj_0262_4389998", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int M;\n while(cin >> M, M){\n int n;\n cin >> n;\n vector<int> v(n);\n for (auto &&i : v) scanf(\"%d\", &i);\n vector<int> to(n+2);\n to.back() = n+1;\n for (int i = 0; i < n; ++i) {\n if(v[i] < 0) to[i+1] = max(0, i+1+v[i]);\n else to[i+1] = min(n+1, i+1+v[i]);\n }\n vector<vector<int>> dp(n+2, vector<int>(n+2, INF<int>));\n for (int i = 0; i <= n; ++i) {\n for (int j = 1; j <= M; ++j) {\n int t = to[min(n+1, i+j)];\n dp[i][t] = 1;\n }\n }\n for (int k = 0; k <= n+1; ++k) {\n for (int i = 0; i <= n+1; ++i) {\n for (int j = 0; j <= n+1; ++j) {\n dp[i][j] = min(dp[i][j], dp[i][k]+dp[k][j]);\n }\n }\n }\n int ok = 1;\n for (int i = 0; i <= n; ++i) {\n if(dp[0][i] != INF<int> && dp[i][n+1] == INF<int>){\n ok = 0;\n }\n }\n puts(ok ? \"OK\" : \"NG\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1380, "memory_kb": 3248, "score_of_the_acc": -0.6971, "final_rank": 10 }, { "submission_id": "aoj_0262_3864149", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing VI = vector<int>;\nusing VL = vector<ll>;\n#define FOR(i,a,n) for(int (i)=(a);(i)<(n);(i)++)\n#define eFOR(i,a,n) for(int (i)=(a);(i)<=(n);(i)++)\n#define rFOR(i,a,n) for(int (i)=(n)-1;(i)>=(a);(i)--)\n#define erFOR(i,a,n) for(int (i)=(n);(i)>=(a);(i)--)\n#define SORT(i) sort((i).begin(),(i).end())\n#define rSORT(i,a) sort((i).begin(),(i).end(),(a))\n#define all(i) (i).begin(),(i).end()\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; }return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; }return 0; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T> inline istream& operator>>(istream& input, vector<T>& v) { for (auto& elemnt : v)input >> elemnt; return input; }\n\nint main() {\n init();\n\n while (1) {\n int dice;\n cin >> dice;\n if (dice == 0)break;\n\n int n;\n cin >> n;\n n += 2;\n VI d(n, 0);\n FOR(i, 1, n - 1)cin >> d[i];\n\n vector<vector<bool>> g(n, vector<bool>(n, false));\n FOR(i, 0, n)g[i][i] = true;\n FOR(i, 0, n) {\n eFOR(j, 1, dice) {\n int next = i + j + d[min(i + j, n - 1) ];\n chmax(next, 0), chmin(next, n - 1);\n g[i][next] = true;\n }\n }\n FOR(k, 0, n)FOR(i, 0, n)FOR(j, 0, n) {\n if (g[i][k] && g[k][j])g[i][j] = true;\n }\n string ans = \"OK\\n\";\n FOR(i, 0, n)if (g[0][i]) {\n if (!g[i][n - 1])ans = \"NG\\n\";\n }\n cout << ans;\n }\n \n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 3176, "score_of_the_acc": -0.5035, "final_rank": 9 }, { "submission_id": "aoj_0262_3863606", "code_snippet": "#include <iostream>\nusing namespace std;\n#include <vector>\nint main(){\n int m,n;\n while(true){\n cin >> m;\n if(m == 0)break;\n cin >> n;\n vector<int> d(n*2);\n vector<vector<int> >p(n*3,vector<int>(n*3,0));\n for(int i = 0; i < 2*n; i++)d[i] = 0;\n for(int i = 1; i <= n; i++)cin >> d[i];\n \n for(int i = 0; i <= n; i++){\n for(int j = 1; j <= m; j++){\n\tint pp= i+j+d[i+j];\n\tif(pp < 0)pp = 0;\n\tif(pp > n+1)pp = n+1;\n\tp[i][pp] = 1;\n }\n }\n \n \n for(int j = 0; j <= n+1; j++){\n for(int i = 0; i <= n+1; i++){\n\tfor(int k = 0; k <= n+1; k++){\n\t if(p[j][i]&&p[i][k]) p[j][k] = 1;\n\t}\n }\n }\n\n \n int ans = true;\n for(int i = 0;i < n+1; i++){\n if(p[0][i]==1&&p[i][n+1] == 0)ans = false;\n }\n if(ans)cout << \"OK\" << endl;\n else cout << \"NG\" << endl;\n }\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 4896, "score_of_the_acc": -1.4771, "final_rank": 16 }, { "submission_id": "aoj_0262_3863604", "code_snippet": "#include <iostream>\nusing namespace std;\n#include <vector>\nint main(){\n int m,n;\n while(true){\n cin >> m;\n if(m == 0)break;\n cin >> n;\n vector<int> d(n*2);\n vector<vector<int> >p(n*3,vector<int>(n*3,0));\n for(int i = 0; i < 2*n; i++)d[i] = 0;\n for(int i = 1; i <= n; i++)cin >> d[i];\n \n for(int i = 0; i <= n; i++){\n for(int j = 1; j <= m; j++){\n\tint pp= i+j+d[i+j];\n\tif(pp < 0)pp = 0;\n\tif(pp > n+1)pp = n+1;\n\tp[i][pp] = 1;\n }\n }\n \n \n for(int j = 0; j <= n+1; j++){\n for(int i = 0; i <= n+1; i++){\n\tfor(int k = 0; k <= n+1; k++){\n\t if(p[j][k]&&p[k][i]) p[j][i] = 1;\n\t}\n }\n }\n\n \n int ans = true;\n for(int i = 0;i < n+1; i++){\n if(p[0][i]==1&&p[i][n+1] == 0)ans = false;\n }\n if(ans)cout << \"OK\" << endl;\n else cout << \"NG\" << endl;\n }\n}", "accuracy": 1, "time_ms": 1160, "memory_kb": 4924, "score_of_the_acc": -1.5111, "final_rank": 17 }, { "submission_id": "aoj_0262_3863578", "code_snippet": "#include <iostream>\nusing namespace std;\n#include <vector>\nint main(){\n int m,n;\n while(true){\n cin >> m;\n if(m == 0)break;\n cin >> n;\n vector<int> d(n*2);\n vector<vector<int> >p(n*3,vector<int>(n*3,0));\n for(int i = 0; i < 2*n; i++)d[i] = 0;\n for(int i = 1; i <= n; i++)cin >> d[i];\n \n for(int i = 0; i <= n; i++){\n for(int j = 1; j <= m; j++){\n\tint pp= i+j+d[i+j];\n\tif(pp < 0)pp = 0;\n\tif(pp > n+1)pp = n+1;\n\tp[i][pp] = 1;\n }\n }\n for(int j = 0; j <= n+1; j++){\n for(int i = 0; i <= n+1; i++){\n\tfor(int k = 0; k <= n+1; k++){\n\t if(p[i][j]&&p[j][k]) p[i][k] = 1;\n\t}\n }\n }\n \n \n int ans = true;\n for(int i = 0;i < n+1; i++){\n if(p[0][i]==1&&p[i][n+1] == 0)ans = false;\n }\n if(ans)cout << \"OK\" << endl;\n else cout << \"NG\" << endl;\n }\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 4972, "score_of_the_acc": -1.4346, "final_rank": 15 }, { "submission_id": "aoj_0262_3810286", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<math.h>\nusing namespace std;\ntypedef long long ll;\n#define int long long\ntypedef vector<int> VI;\ntypedef pair<int, int> pii;\n#define fore(i,a) for(auto &i:a)\n#define REP(i,n) for(int i=0;i<n;i++)\n#define eREP(i,n) for(int i=0;i<=n;i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define eFOR(i,a,b) for(int i=(a);i<=(b);++i)\n#define SORT(c) sort((c).begin(),(c).end())\n#define rSORT(c) sort((c).rbegin(),(c).rend())\n#define LB(x,a) lower_bound((x).begin(),(x).end(),(a))\n#define UB(x,a) upper_bound((x).begin(),(x).end(),(a))\n#define INF 1000000000\n#define LLINF 9223372036854775807\n#define mod 1000000007\n//vector<vector<int> > dp;\n//vector<vector<vector<int> > > vvvi;\n//dp=vector<vector<int> >(N, vector<int>(M,0));\n//vector<pair<int,int> > v;\n//v.push_back(make_pair(x,y));\n//priority_queue<int,vector<int>, greater<int> > q2;\n\n\n\nsigned main(){\ncin.tie(0);\nios::sync_with_stdio(false);\n\n\twhile (1) {\n\t\t\n\t\tint ma, N;\n\t\tcin >> ma;\n\t\tif (ma == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tcin >> N;\n\t\tVI A(N);\n\t\tREP(i, N) {\n\t\t\tcin >> A[i];\n\t\t}\n\t\tint G[300][300] = { 0 };\n\t\tREP(i, N + 1) {\n\t\t\teFOR(j,1, ma) {\n\t\t\t\tint a = i + j + A[min(i + j - 1, N - 1)];\n\t\t\t\tif (a <= 0)a = 0;\n\t\t\t\telse if (a >= N + 1)a = N + 1;\n\t\t\t\tG[i][a] = 1;\n\t\t\t}\n\t\t}\n\t\t/*REP(i, N + 1) {\n\t\t\tREP(j, N + 2) {\n\t\t\t\tcout << G[i][j];\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}*/\n\t\tfor (int k = 0; k < N + 2; k++) {\n\t\t\tfor (int i = 0; i < N + 2; i++) {\n\t\t\t\tfor (int j = 0; j < N + 2; j++) {\n\t\t\t\t\tif (G[i][k] && G[k][j]) G[i][j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tbool valid = true;\n\t\tfor (int i = 0; i <= N; i++) {\n\t\t\tif (G[0][i] && !G[i][N + 1]) valid = false;\n\t\t}\n\t\tcout << (valid ? \"OK\" : \"NG\") << endl;\n\n\t}\n\treturn 0;\n}", "accuracy": 0.5, "time_ms": 900, "memory_kb": 3916, "score_of_the_acc": -0.8382, "final_rank": 20 }, { "submission_id": "aoj_0262_3779519", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nusing int64 = long long;\n\ntemplate<typename T>\nusing p_que = priority_queue<T>;\ntemplate<typename T>\nusing rp_que = priority_queue<T, vector<T>, greater<T>>;\n\nconstexpr int INF = (1 << 30) - 1;\nconstexpr int64 INF64 = (1ll << 60) - 1;\n\n#define rep(i, N) for(int i=0;i<(int)(N);++i)\n#define fs first\n#define sc second\n#define e_b emplace_back\n#define m_p make_pair\n#define all(x) x.begin(),x.end()\n#define rall(x) x.rbegin(),x.rend()\n\ntemplate <typename T, typename U>\nostream& operator<<(ostream& os, const pair<T, U>& p) {\n\treturn os << \"P(\" << p.first << \", \" << p.second << \")\";\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n\tos << \"[\";\n\tfor (auto& e : v) os << e << \", \";\n\treturn os << \"]\";\n}\ntemplate <typename T, typename U>\nostream& operator<<(ostream& os, const map<T, U>& m) {\n\tos << \"{\" << endl;\n\tfor (auto& e : m) os << \"(\" << e.first << \", \" << e.second << \")\" << endl;\n\treturn os << \"}\";\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& s) {\n\tos << \"{\" << endl;\n\tfor (auto& e : s) os << \", \" << e << endl;\n\treturn os << \"}\";\n}\n\ntemplate<typename T>\nvector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate<typename... Ts>\nauto make_v(size_t a, Ts... ts) {\n\treturn vector<decltype(make_v(ts...))>(a, make_v(ts...));\n}\n\nint64 gcd(int64 x, int64 y) {\n\tif (x == 0 || y == 0) return 0;\n\tint64 r;\n\twhile ((r = y % x) != 0) {\n\t\ty = x;\n\t\tx = r;\n\t}\n\treturn x;\n}\nint64 lcm(int64 x, int64 y) {\n\tif (x == 0 || y == 0) return 0;\n\treturn x / gcd(x, y) * y;\n}\n\nint dx[] = { -1, 0, 1, 0 };\nint dy[] = { 0, 1, 0, -1 };\n\nvoid Main();\nsigned main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\tcout << fixed << setprecision(30);\n\tMain();\n}\n\n/*----------------------------Insert from here!----------------------------*/\n\ntemplate <int mod>\nstruct ModInt {\n\tint x;\n\n\tModInt() : x(0) {}\n\n\tModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n\n\tModInt& operator+=(const ModInt& p) {\n\t\tif ((x += p.x) >= mod) x -= mod;\n\t\treturn *this;\n\t}\n\n\tModInt& operator-=(const ModInt& p) {\n\t\tif ((x += mod - p.x) >= mod) x -= mod;\n\t\treturn *this;\n\t}\n\n\tModInt& operator*=(const ModInt& p) {\n\t\tx = (int)(1LL * x * p.x % mod);\n\t\treturn *this;\n\t}\n\n\tModInt& operator/=(const ModInt& p) {\n\t\t*this *= p.inverse();\n\t\treturn *this;\n\t}\n\n\tModInt operator-() const { return ModInt(-x); }\n\n\tModInt operator+(const ModInt& p) const { return ModInt(*this) += p; }\n\n\tModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; }\n\n\tModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; }\n\n\tModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; }\n\n\tbool operator==(const ModInt& p) const { return x == p.x; }\n\n\tbool operator!=(const ModInt& p) const { return x != p.x; }\n\n\tModInt inverse() const {\n\t\tint a = x, b = mod, u = 1, v = 0, t;\n\t\twhile (b > 0) {\n\t\t\tt = a / b;\n\t\t\tswap(a -= t * b, b);\n\t\t\tswap(u -= t * v, v);\n\t\t}\n\t\treturn ModInt(u);\n\t}\n\n\tModInt pow(int64_t n) const {\n\t\tModInt ret(1), mul(x);\n\t\twhile (n > 0) {\n\t\t\tif (n & 1) ret *= mul;\n\t\t\tmul *= mul;\n\t\t\tn >>= 1;\n\t\t}\n\t\treturn ret;\n\t}\n\n\tfriend ostream& operator<<(ostream& os, const ModInt& p) {\n\t\treturn os << p.x;\n\t}\n\n\tfriend istream& operator>>(istream& is, ModInt& a) {\n\t\tint64_t t;\n\t\tis >> t;\n\t\ta = ModInt< mod >(t);\n\t\treturn (is);\n\t}\n\n\tstatic int get_mod() { return mod; }\n};\n\ntemplate <typename T>\nstruct Edge {\n\tint from, to;\n\tT cost;\n\n\tEdge() : from(0), to(0), cost(0) {}\n\tEdge(int to, T cost) : from(-1), to(to), cost(cost) {}\n\tEdge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n\tEdge& operator=(const int& x) {\n\t\tto = x;\n\t\treturn *this;\n\t}\n};\n\ntemplate <typename T>\nusing Edges = vector<Edge<T>>;\ntemplate <typename T>\nusing wGraph = vector<Edges<T>>;\n\n/* Function from here! */\n\ntemplate <typename T>\nvector<T> dijkstra(wGraph<T>& g, int s) {\n\tconst auto INF = numeric_limits<T>::max();\n\tvector<T> dist(g.size(), INF);\n\n\tusing P = pair<T, int>;\n\tpriority_queue<P, vector<P>, greater<P>> que;\n\tdist[s] = 0;\n\tque.emplace(dist[s], s);\n\twhile (!que.empty()) {\n\t\tT cost;\n\t\tint idx;\n\t\ttie(cost, idx) = que.top();\n\t\tque.pop();\n\t\tif (dist[idx] < cost) continue;\n\t\tfor (auto& e : g[idx]) {\n\t\t\tT next_cost = cost + e.cost;\n\t\t\tif (dist[e.to] <= next_cost) continue;\n\t\t\tdist[e.to] = next_cost;\n\t\t\tque.emplace(dist[e.to], e.to);\n\t\t}\n\t}\n\n\treturn dist;\n}\n\n/*----------------------------Insert above here----------------------------*/\n\nvoid Main() {\n\tint max, n;\n\twhile (true) {\n\t\tcin >> max;\n\t\tif (max == 0) break;\n\t\tcin >> n;\n\n\t\tvector<int> d(n + 2);\n\t\tfor (int i = 1; i <= n; ++i) cin >> d[i];\n\n\t\twGraph<int> G(n + 2);\n\t\tvector<int> used(n + 2);\n\t\tstack<int> stk;\n\t\tstk.emplace(0);\n\t\twhile (!stk.empty()) {\n\t\t\tint idx = stk.top(); stk.pop();\n\t\t\tif (used[idx]) continue;\n\t\t\tused[idx] = 1;\n\t\t\tfor (int i = 1; i <= max; ++i) {\n\t\t\t\tint next = idx + i;\n\t\t\t\tif (next >= n + 2) break;\n\t\t\t\tnext += d[next];\n\t\t\t\tif (next >= n + 2) next = n + 1;\n\t\t\t\telse if (next < 0) next = 0;\n\t\t\t\tG[idx].emplace_back(next, 1);\n\n\t\t\t\tif (used[next]) continue;\n\t\t\t\tstk.emplace(next);\n\t\t\t}\n\t\t}\n\n\t\t/*\n\t\tfor(int i=0; i<n+1; ++i) {\n\t\t\tcout << i << \" \";\n\t\t\tfor (auto& k : G[i]) cout << k.to << \" \";\n\t\t\tcout << endl;\n\t\t}\n\t\t*/\n\n\t\tfor (int i = 0; i < n + 1; ++i) {\n\t\t\tif (!used[i]) continue;\n\t\t\tauto d = dijkstra(G, i);\n\t\t\tif (d[n + 1] == numeric_limits<int>::max()) {\n\t\t\t\tcout << \"NG\" << endl;\n\t\t\t\tgoto LABEL;\n\t\t\t}\n\t\t}\n\t\tcout << \"OK\" << endl;\n\tLABEL:\n\t\t;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3216, "score_of_the_acc": -0.0441, "final_rank": 2 }, { "submission_id": "aoj_0262_3754346", "code_snippet": "#include \"bits/stdc++.h\"\n// Custom Header {{{\n#define ALL(x) x.begin(), x.end()\n#define endl '\\n'\nusing namespace std;\nusing i64 = long long;\nusing pii = pair<i64, i64>;\ntemplate<class A, class B>inline bool chmax(A &a, const B &b){return b>a ? a=b,1 : 0;}\ntemplate<class A, class B>inline bool chmin(A &a, const B &b){return b<a ? a=b,1 : 0;}\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr i64 LINF = 0x3f3f3f3f3f3f3f3fLL;\n// }}}\n\nint K, N;\nint d[300];\nint START = 0, GOAL;\nbool reach[300];\nbool visited[300];\nvector<vector<int>> G;\n\nvoid addEdge(int s)\n{\n for (int j = 1; j <= K; ++j) {\n int t = min(GOAL, s + j);\n G[s].push_back(max(0, min(GOAL, t + d[t])));\n }\n}\n\nvoid dfs(int u)\n{\n if (!visited[u]) {\n visited[u] = true;\n for (int v : G[u]) dfs(v);\n }\n}\n\nbool canGoal(int u)\n{\n if (u == GOAL) return true;\n\n if (visited[u]) return false;\n visited[u] = true;\n\n bool ret = false;\n for (int v : G[u]) {\n ret |= canGoal(v);\n }\n return ret;\n}\n\nsigned main()\n{\n cin.tie(nullptr); ios::sync_with_stdio(false);\n\n\n while(cin >> K, K) {\n cin >> N;\n memset(d, 0, sizeof(d));\n for (int i = 1; i <= N; ++i) cin >> d[i];\n GOAL = N+1;\n\n G = vector<vector<int>>(N+2);\n for (int i = 0; i <= N; ++i) {\n addEdge(i);\n }\n\n /*\n cout << \"-------------------------------------\" << endl;\n cout << ++__ << ' ' << N << ' ' << K << endl;\n for (int i = 1; i <= N; ++i) cout << d[i] << ' ';\n cout << endl;\n\n for (int i = 0; i <= GOAL; ++i) {\n printf(\"[%d] \", i);\n for (int u : G[i]) {\n printf(\" %d\", u);\n }\n printf(\"\\n\");\n }\n */\n\n memset(visited, false, sizeof(visited));\n dfs(0);\n\n int reachCount = 0;\n int canGoalCount = 0;\n\n memcpy(reach, visited, sizeof(reach));\n for (int i = 1; i <= GOAL; ++i) {\n if (reach[i]) {\n //printf(\"reach : %d\\n\", i);\n ++reachCount;\n memset(visited, false, sizeof(visited));\n if (canGoal(i)) {\n ++canGoalCount;\n }\n }\n }\n\n cout << (canGoalCount > 0 && reachCount == canGoalCount ? \"OK\" : \"NG\") << endl;\n\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3208, "score_of_the_acc": -0.035, "final_rank": 1 }, { "submission_id": "aoj_0262_3119047", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define UNIQUE(v) v.erase(unique(all(v)), v.end());\n#define ZIP(v) sort(all(v)),UNIQUE(v)\n#define ADD(a, b) a = (a + b) % mod\n#define SUB(a, b) a = (a+mod-b)%mod\n#define MUL(a, b) a = (a * b) % mod\n#define repi(i,m,n) for(int i = m;i < n;i++)\n#define drep(i,n,m) for(int i = n;i >= m;i--)\n#define rep(i,n) repi(i,0,n)\n#define rrep(i,n) repi(i,1,n+1)\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define all(v) v.begin(),v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define dmp(x,y) make_pair(x,y)\n#define pb(x) push_back(x)\n#define fi first\n#define se second\ntypedef pair<int,int> P;\ntypedef pair<int, P> PP;\ntypedef pair<P, int> Pi;\ntypedef vector<int> vi;\ntypedef deque<int> dq;\nconst int inf = 1e9+7;\nconst int INF = 1e18+7;\n\nint a[1000], used[1000], b[300][300], used2[1000];\nvector<int> G[300];\nvoid dfs(int u){\n\tif(used[u])return;\n\tused[u] = 1;\n\trep(i,G[u].size()){\n\t\tdfs(G[u][i]);\n\t}\n}\n\nvoid dfs2(int u, int R, int t){\n\tif(used2[u])return;\n\tused2[u] = 1;\n\tint i = u;\n\trrep(j,R){\n\t\tif(i+j >= t){b[i][t] = 1;dfs2(t, R, t);continue;}\n\t\tif(i+j+a[i+j] < 0){b[i][0] = 1;dfs2(0, R, t);continue;}\n\t\tif(i+j+a[i+j] >= t){b[i][t] = 1;dfs2(t, R, t);continue;}\n\t\tb[i][i+j+a[i+j]] = 1;dfs2(i+j+a[i+j], R, t);\n\t}\n}\n\nvoid init(){\n\trep(i,300)rep(j,300)b[i][j] = 0;\n\tfill(used2, used2+1000, 0);\n\tfill(used, used+1000, 0);\n\trep(i,300)G[i].clear();\n}\n\nsigned main(){\n\twhile(1){\n\t\tint R, n;\n\t\tscanf(\"%lld\", &R);\n\t\tif(R == 0)break;\n\t\tscanf(\"%lld\", &n);\n\t\trrep(i,n)scanf(\"%lld\", &a[i]);\n\t\tint s = 0, t = n+1;\n\t\tinit();\n\t\tdfs2(0, R, t);\n\t\trep(i,t+1)rep(j,t+1){if(b[j][i])G[i].pb(j);}\n\t\tdfs(t);\n\t\t\n\t\tint ans = 1;\n\t\trep(i,t+1)if(used[i] != used2[i])ans = 0;\n\t\tprintf(\"%s\\n\", ans ? \"OK\" : \"NG\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3944, "score_of_the_acc": -0.4376, "final_rank": 7 }, { "submission_id": "aoj_0262_3119046", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define UNIQUE(v) v.erase(unique(all(v)), v.end());\n#define ZIP(v) sort(all(v)),UNIQUE(v)\n#define ADD(a, b) a = (a + b) % mod\n#define SUB(a, b) a = (a+mod-b)%mod\n#define MUL(a, b) a = (a * b) % mod\n#define repi(i,m,n) for(int i = m;i < n;i++)\n#define drep(i,n,m) for(int i = n;i >= m;i--)\n#define rep(i,n) repi(i,0,n)\n#define rrep(i,n) repi(i,1,n+1)\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define all(v) v.begin(),v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define dmp(x,y) make_pair(x,y)\n#define pb(x) push_back(x)\n#define fi first\n#define se second\ntypedef pair<int,int> P;\ntypedef pair<int, P> PP;\ntypedef pair<P, int> Pi;\ntypedef vector<int> vi;\ntypedef deque<int> dq;\nconst int inf = 1e9+7;\nconst int INF = 1e18+7;\n\nint a[1000], used[1000], b[300][300], used2[1000];\nvector<int> G[300];\nvoid dfs(int u){\n\tif(used[u])return;\n\tused[u] = 1;\n\trep(i,G[u].size()){\n\t\tdfs(G[u][i]);\n\t}\n}\n\nvoid dfs2(int u, int R, int t){\n\tif(used2[u])return;\n\tused2[u] = 1;\n\tint i = u;\n\trrep(j,R){\n\t\tif(i+j >= t){b[i][t] = 1;dfs2(t, R, t);continue;}\n\t\tif(i+j+a[i+j] < 0){b[i][0] = 1;dfs2(0, R, t);continue;}\n\t\tif(i+j+a[i+j] >= t){b[i][t] = 1;dfs2(t, R, t);continue;}\n\t\tb[i][i+j+a[i+j]] = 1;dfs2(i+j+a[i+j], R, t);\n\t}\n}\n\nvoid init(){\n\trep(i,300)rep(j,300)b[i][j] = 0;\n\tfill(used2, used2+1000, 0);\n\tfill(used, used+1000, 0);\n\trep(i,300)G[i].clear();\n}\n\nsigned main(){\n\twhile(1){\n\t\tint R, n;\n\t\tscanf(\"%lld\", &R);\n\t\tif(R == 0)break;\n\t\tscanf(\"%lld\", &n);\n\t\trrep(i,n)scanf(\"%lld\", &a[i]);\n\t\tint s = 0, t = n+1;\n\t\tinit();\n\t\tdfs2(0, R, t);\n\t\trep(i,t+1)rep(j,t+1){if(b[j][i])G[i].pb(j);}\n\t\tdfs(t);\n\t\t\n\t\tint ans = 1;\n\t\trep(i,t+1)if(used[i] != used2[i])ans = 0;\n\t\t/*rep(i,t+1)printf(\"%lld \", used2[i]);printf(\"\\n\");\n\t\trep(i,t+1)printf(\"%lld \", used[i]);printf(\"\\n\");\n\t\trep(i,t+1)printf(\"%lld \", (int)(G[i].size()));printf(\"\\n\");*/\n\t\t/*rep(i,t+1){\n\t\t\trep(j,t+1)printf(\"%lld \", b[i][j]);\n\t\t\tprintf(\"\\n\");\n\t\t}*/\n\t\tprintf(\"%s\\n\", ans ? \"OK\" : \"NG\");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3980, "score_of_the_acc": -0.4573, "final_rank": 8 } ]
aoj_0263_cpp
ビートパネル 遊太君は、近所のゲームセンターで人気のゲーム「ビートパネル」にはまっています。このゲームは図のようなグリッド状に並べられた 4×4 の計16個のパネル型のボタンからなります。 図のように、左上から右下にボタン1, ボタン2, …, ボタン16の順にボタンが並んでいます。ゲームでは一定間隔でビート音が鳴り最後に終了音が鳴ります。ビート音が鳴ると同時に複数のボタンが光ります。1個も光らない場合もあります。プレイヤーは、ビート音が鳴った直後から次の音が鳴るまでの間に両手の指を使って複数のボタンを1度だけ同時に押すことができます。何も押さないということも可能です。終了音が鳴ったと同時にゲームは終了します。 遊太君は c 通りの押し方を習得しており、ビート音が鳴る度に、それらの押し方の中から1つ決めてボタンを押します。押したボタンが光っていれば、それらのボタンの光は消え、消えたボタンの数がプレイヤーのスコアに加算されます。また、一度光ったボタンはそのボタンが押されるまで光は消えることはありません。 ビート音が n 回鳴るときのボタンの光り方と遊太君が習得している c 通りのボタンの押し方を入力とし、遊太君が獲得することのできる得点の最大値を出力するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。各データセットは以下の形式で与えられる。 n c a 1,1 a 1,2 ... a 1,16 a 2,1 a 2,2 ... a 2,16 ... a n,1 a n,2 ... a n,16 b 1,1 b 1,2 ... b 1,16 b 2,1 b 2,2 ... b 2,16 ... b c,1 b c,2 ... b c,16 1行目は1つの空白で区切られた2つの整数からなる。n (1 ≤ n ≤ 30) はビート音の数、c (1 ≤ c ≤ 30) は習得しているボタンの押し方の数を示す。続く n+c 行にボタンの光り方とボタンの押し方が与えられる。行中の入力項目の区切りは1つの空白である。a k,i は k 回目のビート音が鳴ったときのボタン i の光り方を、b j,i は c 通り中 j 番目の押し方でボタン i が押されるかどうかを表す。a k,i の値は 0 が「光らない」、1 が「光る」を表す。b j,i の値は 0 が「押さない」、1 が「押す」を表す。 データセットの数は 20 を超えない。 出力 各データセットごとに、得点の最大値を1行に出力する。 入力例 2 2 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 2 2 0 0 1 0 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 1 0 1 1 1 0 1 0 1 0 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 0 5 3 0 0 0 0 0 1 1 0 0 1 1 0 0 0 0 0 1 0 0 1 0 1 1 0 0 1 1 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1 0 0 1 1 0 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 出力例 8 7 16
[ { "submission_id": "aoj_0263_10848448", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n#define debug(x) cerr << #x << \": \" << x << endl\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- 2018/07/25 Problem: AOJ 0263 / Link: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0263 ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\n\ntemplate<class T> using V = vector <T>; template <class T> using VV = V<V<T>>;\n\n\nint dp[32][1 << 16];\n// U I - N U I - N beet beet ...\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint N, C;\n\twhile (cin >> N >> C, N) {\n\t\tV<int>quiz(N);\n\t\tFOR(i, 0, N) {\n\t\t\tint ret = 0;\n\t\t\tFOR(j, 0, 16) {\n\t\t\t\tint a; cin >> a;\n\t\t\t\tret *= 2;\n\t\t\t\tret += a;\n\t\t\t}\n\t\t\tquiz[i] = ret;\n\t\t}\n\t\tV<int>pat(C);\n\t\tFOR(i, 0, C) {\n\t\t\tint ret = 0;\n\t\t\tFOR(j, 0, 16) {\n\t\t\t\tint a; cin >> a;\n\t\t\t\tret *= 2;\n\t\t\t\tret += a;\n\t\t\t}\n\t\t\tpat[i] = ret;\n\t\t}\n\t\tint ans = 0;\n\t\t// NC2^16で max add dp\n\t\tfill(*dp, *dp + 32 * (1 << 16), -1);\n\t\tdp[0][0] = 0;\n\t\tFOR(i, 0, N) {\n\t\t\tFOR(state, 0, 1 << 16) {\n\t\t\t\tif (dp[i][state] == -1)continue;\n\t\t\t\tint nstate = state | quiz[i];\n\t\t\t\tFOR(j, 0, C) {\n\t\t\t\t\tint add = nstate & pat[j];\n\t\t\t\t\tint nnstate = nstate - add ;\n\t\t\t\t\tdp[i + 1][nnstate] = max(dp[i + 1][nnstate], dp[i][state] + __builtin_popcount(add));\n\t\t\t\t}\n\t\t\t\tdp[i + 1][nstate] = max(dp[i + 1][nstate], dp[i][nstate]);\n\t\t\t}\n\t\t}\n\t\tFOR(i, 0, 1 << 16) {\n\t\t\tans = max(ans, dp[N][i]);\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 11660, "score_of_the_acc": -0.0512, "final_rank": 4 }, { "submission_id": "aoj_0263_10834170", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n#define debug(x) cerr << #x << \": \" << x << endl\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- 2018/07/25 Problem: AOJ 0263 / Link: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0263 ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\n\ntemplate<class T> using V = vector <T>; template <class T> using VV = V<V<T>>;\n\n\nint dp[32][1 << 16];\n// ういーんういーん\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint N, C;\n\twhile (cin >> N >> C, N) {\n\t\tV<int>quiz(N);\n\t\tFOR(i, 0, N) {\n\t\t\tint ret = 0;\n\t\t\tFOR(j, 0, 16) {\n\t\t\t\tint a; cin >> a;\n\t\t\t\tret *= 2;\n\t\t\t\tret += a;\n\t\t\t}\n\t\t\tquiz[i] = ret;\n\t\t}\n\t\tV<int>pat(C);\n\t\tFOR(i, 0, C) {\n\t\t\tint ret = 0;\n\t\t\tFOR(j, 0, 16) {\n\t\t\t\tint a; cin >> a;\n\t\t\t\tret *= 2;\n\t\t\t\tret += a;\n\t\t\t}\n\t\t\tpat[i] = ret;\n\t\t}\n\t\tint ans = 0;\n\t\t// NC2^16で max add dp\n\t\tfill(*dp, *dp + 32 * (1 << 16), -1);\n\t\tdp[0][0] = 0;\n\t\tFOR(i, 0, N) {\n\t\t\tFOR(state, 0, 1 << 16) {\n\t\t\t\tif (dp[i][state] == -1)continue;\n\t\t\t\tint nstate = state | quiz[i];\n\t\t\t\tFOR(j, 0, C) {\n\t\t\t\t\tint add = nstate & pat[j];\n\t\t\t\t\tint nnstate = nstate - add ;\n\t\t\t\t\tdp[i + 1][nnstate] = max(dp[i + 1][nnstate], dp[i][state] + __builtin_popcount(add));\n\t\t\t\t}\n\t\t\t\tdp[i + 1][nstate] = max(dp[i + 1][nstate], dp[i][nstate]);\n\t\t\t}\n\t\t}\n\t\tFOR(i, 0, 1 << 16) {\n\t\t\tans = max(ans, dp[N][i]);\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 11584, "score_of_the_acc": -0.05, "final_rank": 3 }, { "submission_id": "aoj_0263_5971462", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 10000;\nint main(){\n while (true){\n int n, c;\n cin >> n >> c;\n if (n == 0 && c == 0){\n break;\n }\n vector<vector<int>> a(n, vector<int>(16));\n for (int i = 0; i < n; i++){\n for (int j = 0; j < 16; j++){\n cin >> a[i][j];\n }\n }\n vector<vector<int>> b(c, vector<int>(16));\n for (int i = 0; i < c; i++){\n for (int j = 0; j < 16; j++){\n cin >> b[i][j];\n }\n }\n vector<int> A(n, 0);\n for (int i = 0; i < n; i++){\n for (int j = 0; j < 16; j++){\n if (a[i][j] == 1){\n A[i] |= 1 << j;\n }\n }\n }\n vector<int> B(c, 0);\n for (int i = 0; i < c; i++){\n for (int j = 0; j < 16; j++){\n if (b[i][j] == 1){\n B[i] |= 1 << j;\n }\n }\n }\n vector<vector<int>> dp(n + 1, vector<int>(1 << 16, -INF));\n dp[0][0] = 0;\n for (int i = 0; i < n; i++){\n for (int j = 0; j < (1 << 16); j++){\n if (dp[i][j] != -INF){\n int p = j | A[i];\n for (int k = 0; k < c; k++){\n int s = __builtin_popcount(p & B[k]);\n int p2 = p & ~B[k];\n dp[i + 1][p2] = max(dp[i + 1][p2], dp[i][j] + s);\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < (1 << 16); i++){\n ans = max(ans, dp[n][i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 11372, "score_of_the_acc": -0.0535, "final_rank": 5 }, { "submission_id": "aoj_0263_5967888", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 998244353 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n x %= mod;\n if(x == 0) return 0;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n BIT(){}\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n void build(int n) {\n N = n;\n node.resize(N+10);\n }\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = 1001;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\n\nint dp[33][(1<<16)];\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n \n int n, c; \n while(cin >> n >> c) {\n if(n == 0 &&c == 0) break;\n\n vector<int> mask1(n);\n REP(i,n) {\n REP(j,16) {\n int a; cin >> a;\n mask1[i] = mask1[i]*2 + a;\n }\n }\n vector<int> mask2(c);\n REP(i,c) {\n REP(j,16) {\n int a; cin >> a;\n mask2[i] = mask2[i]*2 + a;\n }\n }\n REP(i,n+1) REP(j,(1<<16)) dp[i][j] = -1;\n dp[0][0] = 0;\n REP(i,n) {\n REP(bit,(1<<16)) {\n if(dp[i][bit] == -1) continue;\n int mask = bit | mask1[i];\n REP(j,c) {\n int score = __builtin_popcount(mask & mask2[j]);\n int nxt = mask & ~(mask & mask2[j]);\n dp[i+1][nxt] = max(dp[i+1][nxt], dp[i][bit] + score);\n }\n dp[i+1][bit] = max(dp[i+1][bit], dp[i][bit]);\n }\n }\n int ans = 0;\n REP(i,(1<<16)) ans = max(ans, dp[n][i]);\n cout << ans << '\\n';\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 11532, "score_of_the_acc": -0.0089, "final_rank": 1 }, { "submission_id": "aoj_0263_5848868", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<unordered_set>\n#include<unordered_map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<climits>\n#include<iomanip>\n#include<cctype>\n#include<sstream>\n#include<regex>\n#include<bitset>\n#include<random>\n#include<complex>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\nconstexpr int mod=1e9+7;\nconstexpr int Mod=998244353;\nconstexpr int inf=mod;\nconstexpr ll linf=(ll)mod*mod;\nstruct fastio{\n\tfastio(){\n\t\tcin.tie(0);\n\t\tios::sync_with_stdio(0);\n\t\tcout<<fixed<<setprecision(20);\n\t};\n}fio;\ntemplate<class T>\nbool chmax(T&a,const T&b){\n\tif(a<b){\n\t\ta=b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\ntemplate<class T>\nbool chmin(T&a,const T&b){\n\tif(a>b){\n\t\ta=b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\nint dp[31][65536];\nint main(){\n\tint n,c;\n\twhile(cin>>n>>c,n){\n\t\tint a[30]={},b[30]={};\n\t\tbool f;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tfor(int j=0;j<16;j++){\n\t\t\t\tcin>>f;\n\t\t\t\tif(f)\n\t\t\t\t\ta[i]|=1<<j;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<c;i++){\n\t\t\tfor(int j=0;j<16;j++){\n\t\t\t\tcin>>f;\n\t\t\t\tif(f)\n\t\t\t\t\tb[i]|=1<<j;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<=n;i++)\n\t\t\tfor(int j=0;j<1<<16;j++)\n\t\t\t\tdp[i][j]=-inf;\n\t\tdp[0][0]=0;\n\t\tfor(int i=0;i<n;i++)\n\t\t\tfor(int j=0;j<1<<16;j++)\n\t\t\t\tfor(int k=0;k<c;k++)\n\t\t\t\t\tchmax(dp[i+1][(j|a[i])&~b[k]],dp[i][j]+__builtin_popcount((j|a[i])&b[k]));\n\t\tcout<<*max_element(dp[n],dp[n]+(1<<16))<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 1360, "memory_kb": 11324, "score_of_the_acc": -0.8715, "final_rank": 18 }, { "submission_id": "aoj_0263_5795480", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint pcount(int a){\n int ans = 0;\n for(int i = 0; i < 16; i++){\n if(a & (1 << i)) ans++;\n }\n return ans;\n}\n\nvoid chmax(int &a, int x){\n if(a < x) a = x;\n}\n\nint main(){\n while(true){\n int n, c;\n cin >> n >> c;\n if(n == 0 && c == 0) break;\n vector<int> a(n), b(c);\n for(auto &p: a){\n for(int i = 0; i < 16; i++){\n int aa;\n cin >> aa;\n if(aa){\n p |= 1 << i;\n }\n }\n }\n a.push_back(0);\n for(auto &p: b){\n for(int i = 0; i < 16; i++){\n int aa;\n cin >> aa;\n if(aa){\n p |= 1 << i;\n }\n }\n }\n b.push_back(0);\n\n vector<vector<int>> dp(n+1, vector<int>(1 << 16, -1001001001));\n dp[0][a[0]] = 0;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < (1 << 16); j++){\n if(dp[i][j] < 0) continue;\n for(auto &p: b){\n chmax(dp[i+1][(j&(~p))|a[i+1]], dp[i][j]+pcount(j&p));\n }\n }\n }\n\n int ans = -1001001001;\n for(int i = 0; i < (1 << 16); i++) chmax(ans, dp[n][i]);\n cout << ans << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 11416, "score_of_the_acc": -0.1213, "final_rank": 9 }, { "submission_id": "aoj_0263_5731872", "code_snippet": "#define _overload(_1, _2, _3, _4, name, ...) name\n#define _rep1(Itr, N) _rep3(Itr, 0, N, 1)\n#define _rep2(Itr, A, B) _rep3(Itr, A, B, 1)\n#define _rep3(Itr, A, B, S) for(i64 (Itr) = A; (Itr) < B; (Itr) += S)\n#define repeat(...) _overload(__VA_ARGS__, _rep3, _rep2, _rep1)(__VA_ARGS__)\n#define rep(...) _overload(__VA_ARGS__, _rep3, _rep2, _rep1)(__VA_ARGS__)\n\n#include <bits/stdc++.h>\nusing i64 = long long;\nusing u32 = unsigned int;\nusing namespace std;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\n\ti64 n, c;\n\twhile (cin >> n >> c, n > 0) {\n\t\tvector<u32> a(n);\n\t\tfor (auto &vs: a) {\n\t\t\ti64 bit;\n\t\t\trep(i, 16) {\n\t\t\t\tcin >> bit;\n\t\t\t\tvs |= bit;\n\t\t\t\tvs <<= 1;\n\t\t\t}\n\t\t}\n\n\t\tvector<u32> b(c);\n\t\tfor (auto &vs: b) {\n\t\t\ti64 bit;\n\t\t\trep(i, 16) {\n\t\t\t\tcin >> bit;\n\t\t\t\tvs |= bit;\n\t\t\t\tvs <<= 1;\n\t\t\t}\n\t\t}\n\n\t\tauto popcnt = [](u32 b) {\n\t\t\tu32 ret = 0;\n\t\t\twhile (b) {\n\t\t\t\tif (b & 1) ret++;\n\t\t\t\tb >>= 1;\n\t\t\t}\n\t\t\treturn ret;\n\t\t};\n\n\t\tvector<vector<i64>> dp(n, vector<i64>(1 << 17, -1));\n\t\tauto f = [&](auto &&df, int t, u32 board) -> i64 {\n\t\t\tif (t >= n) return 0;\n\t\t\tif (dp[t][board] != -1) return dp[t][board];\n\n\t\t\ti64 nb = board | a[t];\n\t\t\ti64 ret = 0;\n\t\t\trep(i, c) {\n\t\t\t\tret = max(ret,\n\t\t\t\t\t\tdf(df, t + 1, nb ^ (nb & b[i])) + popcnt(nb & b[i]));\n\t\t\t}\n\t\t\treturn dp[t][board] = ret;\n\t\t};\n\n\t\tcout << f(f, 0, 0) << endl;\n\t}\n\n\treturn 0;\n};", "accuracy": 1, "time_ms": 490, "memory_kb": 35660, "score_of_the_acc": -0.6577, "final_rank": 13 }, { "submission_id": "aoj_0263_5731824", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(long long i = (a)*(strlen(#__VA_ARGS__)!=0);i<(long long)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(long long i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(long long)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\ntemplate <class T>\nvector<T> make_vector(int n,T init){\n return vector<T>(n,init);\n}\n\ntemplate <class... tail>\nauto make_vector(int n, tail... args){\n return vector<decltype(make_vector(args...))>(n,make_vector(args...));\n}\n\nint input(){\n int res=0;\n rep(i,16){\n res = res * 2 + in();\n }\n return res;\n}\n\nint func(int n,int c){\n vector<int> A(n);\n vector<int> B(c);\n foreach(i,A)i=input();\n foreach(i,B)i=input();\n vvector<int> dp(n+1,vector<int>(bit(16),-INF));\n dp[0][0] = 0;\n rep(i,n){\n rep(c,bit(16)){\n foreach(j,B){\n chmax(dp[i+1][(c|A[i])&~j],dp[i][c]+__builtin_popcount((c|A[i])&j));\n }\n }\n }\n int res = 0;\n foreach(i,dp[n])chmax(res,i);\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(true){\n int n = in();\n int c = in();\n if(n==0)break;\n println(func(n,c));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1200, "memory_kb": 11500, "score_of_the_acc": -0.7668, "final_rank": 15 }, { "submission_id": "aoj_0263_4868252", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint popcount(int n){\n n = (n & 0x55555555) + (n >> 1 & 0x55555555);\n n = (n & 0x33333333) + (n >> 2 & 0x33333333);\n n = (n & 0x0f0f0f0f) + (n >> 4 & 0x0f0f0f0f);\n n = (n & 0x00ff00ff) + (n >> 8 & 0x00ff00ff);\n return (n & 0x0000ffff) + (n >>16 & 0x0000ffff);\n}\n\nint main(){\n while(1){\n int n,m;\n cin >> n >> m;\n if(n == 0) break;\n\n vector<int> a(n);\n for(int i=0; i<n; i++){\n for(int j=0; j<16; j++){\n int c;\n cin >> c;\n a[i] <<= 1;\n a[i] |= c;\n }\n }\n vector<int> b(m);\n for(int i=0; i<m; i++){\n for(int j=0; j<16; j++){\n int c;\n cin >> c;\n b[i] <<= 1;\n b[i] |= c;\n }\n }\n vector<vector<int>> dp(n+1, vector<int>(1<<16, -1));\n dp[0][0] = 0;\n for(int i=0; i<n; i++){\n for(int j=0; j<(1<<16); j++){\n if(dp[i][j] == -1) continue;\n for(int k=0; k<m; k++){\n int l = j|a[i];\n int p = popcount(l&b[k]);\n int r = l&(-b[k]-1);\n dp[i+1][r] = max(dp[i+1][r], dp[i][j]+p);\n }\n }\n }\n cout << *max_element(dp[n].begin(), dp[n].end()) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 11260, "score_of_the_acc": -0.0786, "final_rank": 6 }, { "submission_id": "aoj_0263_4810386", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\nint main() {\n init();\n\n VI popcnt(1 << 16);\n FOR(bit, 0, 1 << 16)FOR(i, 0, 16) {\n if (~bit & (1 << i))\n popcnt[bit | (1 << i)] = popcnt[bit] + 1;\n }\n\n for (int n, c; cin >> n >> c && n;) {\n VI a(n + 1), b(c);\n FOR(i, 0, n)FOR(j, 0, 16) {\n a[i] <<= 1;\n int x; cin >> x;\n a[i] += x;\n }\n FOR(i, 0, c)FOR(j, 0, 16) {\n b[i] <<= 1;\n int x; cin >> x;\n b[i] += x;\n }\n auto dp = defvec<int>(-INF, n + 1, 1 << 16);\n dp[0][a[0]] = 0;\n FOR(i, 0, n)FOR(bit, 0, 1 << 16){\n chmax(dp[i + 1][bit | a[i + 1]], dp[i][bit]);\n FOR(j, 0, c)\n chmax(dp[i + 1][(bit ^ (bit & b[j])) | a[i + 1]],\n dp[i][bit] + popcnt[bit & b[j]]);\n }\n print(*max_element(all(dp[n])));\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 11336, "score_of_the_acc": -0.3348, "final_rank": 12 }, { "submission_id": "aoj_0263_4810384", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\nint main() {\n init();\n\n VI popcnt(1 << 16);\n FOR(bit, 0, 1 << 16)FOR(i, 0, 16) {\n if (~bit & (1 << i))\n popcnt[bit | (1 << i)] = popcnt[bit] + 1;\n }\n\n for (int n, c; cin >> n >> c && n;) {\n VI a(n + 1), b(n);\n FOR(i, 0, n)FOR(j, 0, 16) {\n a[i] <<= 1;\n int x; cin >> x;\n a[i] += x;\n }\n FOR(i, 0, c)FOR(j, 0, 16) {\n b[i] <<= 1;\n int x; cin >> x;\n b[i] += x;\n }\n auto dp = defvec<int>(-INF, n + 1, 1 << 16);\n dp[0][a[0]] = 0;\n FOR(i, 0, n)FOR(bit, 0, 1 << 16){\n chmax(dp[i + 1][bit | a[i + 1]], dp[i][bit]);\n FOR(j, 0, c)\n chmax(dp[i + 1][(bit ^ (bit & b[j])) | a[i + 1]],\n dp[i][bit] + popcnt[bit & b[j]]);\n }\n print(*max_element(all(dp[n])));\n }\n\n return 0;\n}", "accuracy": 0.8333333333333334, "time_ms": 90, "memory_kb": 11460, "score_of_the_acc": -0.0213, "final_rank": 20 }, { "submission_id": "aoj_0263_4743384", "code_snippet": "#include \"bits/stdc++.h\"\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// }}} End Header\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n int N, C;\n while (cin >> N >> C) {\n if (N + C == 0) {\n break;\n }\n\n auto a = makeVector<int>(0, N, 16);\n auto b = makeVector<int>(0, C, 16);\n input(a, b);\n\n vector<int> as(N), bs(C);\n rep(i, 0, N) {\n rep(j, 0, 16) {\n if (a[i][j]) as[i] |= (1 << j);\n }\n }\n // rep(i, 0, C) {\n // rep(j, 0, 16) {\n // bs[i] |= (1 << j);\n // }\n // }\n\n auto dp = makeVector<int>(-1, N, 1 << 17);\n const auto res = makeFixPoint([&](auto rec, int i, int mask) -> int {\n if (i == N)\n return 0;\n auto &ret = dp[i][mask];\n if (~ret)\n return ret;\n ret = 0;\n const int cur_mask = as[i] | mask;\n chmax(ret, rec(i + 1, cur_mask));\n rep(j, 0, C)\n {\n int cnt = 0;\n int nxt_mask = cur_mask;\n rep(k, 0, 16)\n {\n if (nxt_mask >> k & b[j][k])\n {\n cnt++;\n nxt_mask ^= (1 << k);\n }\n }\n chmax(ret, rec(i + 1, nxt_mask) + cnt);\n }\n return ret;\n })(0, 0);\n\n output(res);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 18828, "score_of_the_acc": -0.7105, "final_rank": 14 }, { "submission_id": "aoj_0263_4555335", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint N, C;\nint LightInfo[30];\nint ButtonInfo[30];\nint DpScore[31][(1 << 16)];\n\nint popcnt(int u) {\n\tint ret;\n\n\tret = 0;\n\twhile (u) {\n\t\tu = (u & (u - 1));\n\t\t++ret;\n\t}\n\n\treturn ret;\n}\n\nvoid solve() {\n\tint bits, total;\n\n\tfill_n(*DpScore, 31 * ((1 << 16)), -1);\n\tDpScore[0][0] = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j < ((1 << 16)); ++j) {\n\t\t\tif (DpScore[i][j] == -1) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int k = 0; k < C; ++k) {\n\t\t\t\tbits = (LightInfo[i] | j) & (~ButtonInfo[k]);\n\t\t\t\tDpScore[i + 1][bits] = max(DpScore[i + 1][bits], DpScore[i][j] + popcnt((LightInfo[i] | j)&ButtonInfo[k]));\n\t\t\t}\n\t\t}\n\t}\n\n\ttotal = *max_element(DpScore[0], DpScore[0] + 31 * (1 << 16));\n\tcout << total << endl;\n}\n\nint main() {\n\tint num;\n\n\twhile (cin >> N >> C, N) {\n\t\tmemset(LightInfo, 0, sizeof(LightInfo));\n\t\tmemset(ButtonInfo, 0, sizeof(ButtonInfo));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tfor (int j = 0; j < 16; ++j) {\n\t\t\t\tcin >> num;\n\t\t\t\tif (num == 1) {\n\t\t\t\t\tLightInfo[i] |= (1 << j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < C; ++i) {\n\t\t\tfor (int j = 0; j < 16; ++j) {\n\t\t\t\tcin >> num;\n\t\t\t\tif (num == 1) {\n\t\t\t\t\tButtonInfo[i] |= (1 << j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tsolve();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11020, "score_of_the_acc": -0.0817, "final_rank": 8 }, { "submission_id": "aoj_0263_4555318", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint N, C;\nint LightInfo[30];\nint ButtonInfo[30];\nint DpScore[31][1 << 16];\n\nint popcnt(int u) {\n\tint ret;\n\n\tret = 0;\n\twhile (u) {\n\t\tu = (u & (u - 1));\n\t\t++ret;\n\t}\n\n\treturn ret;\n}\n\nvoid solve() {\n\tint bits, total;\n\n\tfill_n(*DpScore, 31 * (1 << 16), -1);\n\tDpScore[0][0] = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j < (1 << 16); ++j) {\n\t\t\tif (DpScore[i][j] == -1) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int k = 0; k < C; ++k) {\n\t\t\t\tbits = (LightInfo[i] | j) & (~ButtonInfo[k]);\n\t\t\t\tDpScore[i + 1][bits] = max(DpScore[i + 1][bits], DpScore[i][j] + popcnt((LightInfo[i] | j)&ButtonInfo[k]));\n\t\t\t}\n\t\t}\n\t}\n\n\ttotal = *max_element(DpScore[0], DpScore[0] + 31 * (1 << 16));\n\tcout << total << endl;\n}\n\nint main() {\n\tint num;\n\n\twhile (cin >> N >> C, N) {\n\t\tmemset(LightInfo, 0, sizeof(LightInfo));\n\t\tmemset(ButtonInfo, 0, sizeof(ButtonInfo));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tfor (int j = 0; j < 16; ++j) {\n\t\t\t\tcin >> num;\n\t\t\t\tif (num == 1) {\n\t\t\t\t\tLightInfo[i] |= (1 << j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < C; ++i) {\n\t\t\tfor (int j = 0; j < 16; ++j) {\n\t\t\t\tcin >> num;\n\t\t\t\tif (num == 1) {\n\t\t\t\t\tButtonInfo[i] |= (1 << j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tsolve();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11016, "score_of_the_acc": -0.0816, "final_rank": 7 }, { "submission_id": "aoj_0263_4390664", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nusing A = array<int, 1<<16>;\nint main() {\n int n, c;\n while(cin >> n >> c, n){\n vector<int> a(n), b(c);\n for (int i = 0; i < n; ++i) {\n int val = 0;\n for (int j = 0; j < 16; ++j) {\n int x;\n cin >> x;\n val |= x << j;\n }\n a[i] = val;\n }\n for (int i = 0; i < c; ++i) {\n int val = 0;\n for (int j = 0; j < 16; ++j) {\n int x;\n cin >> x;\n val |= x << j;\n }\n b[i] = val;\n }\n vector<int> cnt(1 << 16);\n for (int k = 0; k < 1<<16; ++k) {\n for (int i = 0; i < 16; ++i) {\n if(k & (1 << i)) cnt[k] = cnt[k^(1 << i)]+1;\n }\n }\n vector<A> dp(n+1);\n dp[0][0] = 1;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < 1 << 16; ++j) {\n if(!dp[i][j]) continue;\n int jj = j|a[i];\n for (int k = 0; k < c; ++k) {\n chmax(dp[i+1][jj^(jj&b[k])], dp[i][j]+cnt[jj&b[k]]);\n }\n }\n }\n cout << *max_element(dp.back().begin(),dp.back().end())-1 << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 18088, "score_of_the_acc": -0.1288, "final_rank": 10 }, { "submission_id": "aoj_0263_4202248", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nvoid chmax(int &a, int b){\n a = max(a,b);\n}\n\nbool solve(){\n int n, c;\n cin >> n >> c;\n if(n==0) return true;\n vector<int> a(n), b(c);\n for(int i=0;i<n;i++){\n for(int j=0;j<16;j++){\n int x;\n cin >> x;\n a[i] |= x<<j;\n }\n }\n for(int i=0;i<c;i++){\n for(int j=0;j<16;j++){\n int x;\n cin >> x;\n b[i] |= x<<j;\n }\n }\n vector<vector<int> > dp(n+1, vector<int>(1<<16,-1));\n dp[0][0] = 0;\n for(int i=0;i<n;i++){\n for(int S=0;S<1<<16;S++){\n if(dp[i][S] < 0) continue;\n int T = S|a[i];\n chmax(dp[i+1][T], dp[i][S]);\n for(int j=0;j<c;j++){\n int X = T&b[j], cnt = 0;\n for(int k=0;k<16;k++){\n if((X>>k)&1) cnt++;\n }\n chmax(dp[i+1][T^X], dp[i][S]+cnt);\n }\n }\n }\n int ans = 0;\n for(int S=0;S<1<<16;S++){\n chmax(ans, dp[n][S]);\n }\n cout << ans << endl;\n return false;\n}\n\nint main() {\n while(!solve());\n return 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 11024, "score_of_the_acc": -0.2562, "final_rank": 11 }, { "submission_id": "aoj_0263_4095180", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define INF 1000000\n\nint n, c;\nint a[40];\nint b[40];\n\nint bitcount(uint bits) {\n bits = (bits & 0x55555555) + (bits >> 1 & 0x55555555);\n bits = (bits & 0x33333333) + (bits >> 2 & 0x33333333);\n bits = (bits & 0x0f0f0f0f) + (bits >> 4 & 0x0f0f0f0f);\n bits = (bits & 0x00ff00ff) + (bits >> 8 & 0x00ff00ff);\n return (bits & 0x0000ffff) + (bits >> 16);\n}\n\nint main() {\n while (true) {\n cin >> n >> c;\n \n if (n==0 && c==0) {\n break;\n }\n \n for (int i=0; i<n; i++) {\n a[i] = 0, b[i] = 0;\n }\n \n for (int i=0; i<n; i++) {\n for (int j=0; j<16; j++) {\n int aij; cin >> aij;\n a[i] += aij<<j;\n }\n }\n \n for (int i=0; i<c; i++) {\n for (int j=0; j<16; j++) {\n int bij; cin >> bij;\n b[i] += bij<<j;\n }\n }\n \n int dp[n+1][1<<16];\n \n for (int i=0; i<=n; i++) {\n for (int j=0; j<(1<<16); j++) {\n dp[i][j] = -INF;\n }\n }\n \n dp[0][0] = 0;\n \n for (int i=0; i<n; i++) {\n for (int j=0; j<(1<<16); j++) {\n int now = j|a[i];\n \n for (int k=0; k<c; k++) {\n int score = bitcount(now&b[k]);\n int next = now-(now&b[k]);\n dp[i+1][next] = max(dp[i+1][next], dp[i][j]+score);\n }\n }\n }\n \n int ans = 0;\n \n for (int i=0; i<(1<<16); i++) {\n ans = max(ans, dp[n][i]);\n }\n \n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 1260, "memory_kb": 10944, "score_of_the_acc": -0.7987, "final_rank": 16 }, { "submission_id": "aoj_0263_4095147", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define INF 1000000\n\nint n, c;\nint a[40];\nint b[40];\n\nint bitcount(uint bits) {\n bits = (bits & 0x55555555) + (bits >> 1 & 0x55555555);\n bits = (bits & 0x33333333) + (bits >> 2 & 0x33333333);\n bits = (bits & 0x0f0f0f0f) + (bits >> 4 & 0x0f0f0f0f);\n bits = (bits & 0x00ff00ff) + (bits >> 8 & 0x00ff00ff);\n return (bits & 0x0000ffff) + (bits >> 16);\n}\n\nint main() {\n while (true) {\n cin >> n >> c;\n \n if (n==0 && c==0) {\n break;\n }\n \n for (int i=0; i<n; i++) {\n a[i] = 0, b[i] = 0;\n }\n \n for (int i=0; i<n; i++) {\n int p = 1;\n \n for (int j=0; j<16; j++) {\n int aij; cin >> aij;\n a[i] += aij*p;\n p *= 2;\n }\n }\n \n for (int i=0; i<c; i++) {\n int p = 1;\n \n for (int j=0; j<16; j++) {\n int bij; cin >> bij;\n b[i] += bij*p;\n p *= 2;\n }\n }\n \n int dp[n+1][1<<16];\n \n for (int i=0; i<=n; i++) {\n for (int j=0; j<(1<<16); j++) {\n dp[i][j] = -INF;\n }\n }\n \n dp[0][0] = 0;\n \n for (int i=0; i<n; i++) {\n for (int j=0; j<(1<<16); j++) {\n int now = j|a[i];\n \n for (int k=0; k<c; k++) {\n int score = bitcount(now&b[k]);\n int next = now^(now&b[k]);\n dp[i+1][next] = max(dp[i+1][next], dp[i][j]+score);\n }\n }\n }\n \n int ans = 0;\n \n for (int i=0; i<(1<<16); i++) {\n ans = max(ans, dp[n][i]);\n }\n \n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 1260, "memory_kb": 11032, "score_of_the_acc": -0.8, "final_rank": 17 }, { "submission_id": "aoj_0263_3986659", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n#include<iostream>\n#include<cmath>\nint count_bit(int value) {\n\tint result = 0;\n\twhile (value != 0) {\n\t\tresult += value % 2;\n\t\tvalue >>= 1;\n\t}\n\treturn result;\n}\nint max_score(const int current, const int state, const std::vector<int>& beats, const std::vector<int>& patterns, std::vector<std::unordered_map<int, int>>& memo) {\n\tif (current == beats.size()) return 0;\n\tif (memo[current].find(state) != memo[current].end()) return memo[current][state];\n\tconst auto next_state = state | beats[current];\n\tint max = 0;\n\tfor (const auto pattern : patterns) {\n\t\tmax = std::max(max, max_score(current + 1, next_state & (~pattern), beats, patterns, memo) + count_bit(pattern & next_state));\n\t}\n\treturn memo[current][state] = max;\n}\nint main() {\n\twhile (true) {\n\t\tint n, c; std::cin >> n >> c; if (n == 0 && c == 0) break;\n\t\tstd::vector<int> beats(n, 0), patterns(c, 0);\n\t\tfor (auto& beat : beats) {\n\t\t\tint d;\n\t\t\tfor (auto i = 0; i < 16; ++i) {\n\t\t\t\tstd::cin >> d;\n\t\t\t\tbeat <<= 1;\n\t\t\t\tbeat += d;\n\t\t\t}\n\t\t}\n\t\tfor (auto& pattern : patterns) {\n\t\t\tint d;\n\t\t\tfor (auto i = 0; i < 16; ++i) {\n\t\t\t\tstd::cin >> d;\n\t\t\t\tpattern <<= 1;\n\t\t\t\tpattern += d;\n\t\t\t}\n\t\t}\n\t\tstd::vector<std::unordered_map<int, int>> memo(n);\n\t\tstd::cout << max_score(0, 0, beats, patterns, memo) << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 1560, "memory_kb": 76712, "score_of_the_acc": -2, "final_rank": 19 }, { "submission_id": "aoj_0263_3912236", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cstring>\nusing namespace std;\n\nint popcnt[1<<16] = {};\nint dp[31][1<<16], a[31], b[31];\nbool valid[31][1<<16];\n\nint main(){\n vector<int> popcnt(1<<16, 0);\n for(int i = 1; i < 1<<16; i++){\n for(int j = 0; j < 16; j++) popcnt[i] += (i>>j)&1;\n }\n int n, c;\n while(cin >> n >> c, n+c){\n memset(dp, 0, sizeof(dp));\n memset(valid, 0, sizeof(valid));\n memset(a, 0, sizeof(a));\n memset(b, 0, sizeof(b));\n valid[0][0] = true;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < 16; j++){\n int x; cin >> x;\n a[i] += (1<<j)*x;\n }\n }\n for(int i = 0; i < c; i++){\n for(int j = 0; j < 16; j++){\n int x; cin >> x;\n b[i] += (1<<j)*x;\n }\n }\n for(int i = 0; i < n; i++){\n for(int j = 0; j < 1<<16; j++){\n if(!valid[i][j]) continue;\n int nj = j|a[i];\n for(int k = 0; k < c; k++){\n valid[i+1][~b[k]&nj] = true;\n dp[i+1][~b[k]&nj] = max(dp[i+1][~b[k]&nj], dp[i][j]+popcnt[nj&b[k]]);\n }\n }\n }\n int ans = 0;\n for(int j = 0; j < 1<<16; j++){\n if(valid[n][j]) ans = max(ans, dp[n][j]);\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 13064, "score_of_the_acc": -0.0457, "final_rank": 2 } ]
aoj_0264_cpp
有限体電卓 0以外のすべての実数の逆数は実数になりますが、整数の逆数が整数になるとは限りません。C言語などで 3.0/2.0*2.0 = 3.0 なのに 3/2*2 = 2 になってしまうのはこのためです。ですが、素数で割った余りが等しい整数を同じものとみなすと、0以外のすべての整数が逆数をもつようにできます。 整数 x と y を p で割った余りが等しいとき、x ≡ y (mod p) と書きます。p が素数のとき、このような x と y を同じものとみなすなら、すべての整数 n は0から p−1 までのどれかの整数 x に対して x ≡ n (mod p) となるので、けっきょく { 0, 1, 2, ..., p−1 } という集合だけからなる世界を考えればよいことがわかります。 この世界での加減乗除は以下のようになります。 加算 x+y の値は、x+y ≡ z (mod p) となる 0 から p−1 までの数 z になります。 減算 x−yの値は、y+m ≡ 0 (mod p) となる 0 から p−1 までの数 m(これが y に相当します)について、x−y ≡ x + m (mod p) となることから得られます。たとえば、p = 5のとき、4+1 ≡ 0 (mod 5) となります。このとき、2−4 ≡ 2+1 ≡ 3 (mod 5) より、2−4の値は3になります。 乗算 x*y の値は、x*y ≡ z (mod p) となる 0 から p−1 までの数 z になります。 除算 x/y の値は、y*d ≡ 1 (mod p)となる 0 から p−1 までの数 d (これがyの逆数になります)について、x/y ≡ x*d (mod p) となることから得られます。たとえば、p = 5 のとき、2*3 ≡ 1 (mod 5) より 3 は 2 の逆数になります。このとき、1/2 ≡ 1*3 ≡ 3 (mod 5) より、1/2 の値は 3 になります。 このようにして加減乗除の四則演算がすべて0からp−1の範囲に収まります。このとき、集合 { 0,1,...,p−1 } を p の有限体といいます。この有限体の中で、加減乗除、0 から p−1 までの数、カッコを使って 算術式を構成することができます。 p の有限体の 0 以外のすべての要素が逆数をもつことは、フェルマーの小定理と呼ばれる有名な定理 a p−1 ≡ 1 (mod p) からわかります(ただし、p は素数、a と p は互いに素)。p の有限体のすべての要素 x は p と互いに素なので、この定理から x*x p-2 ≡ 1 (mod p) となり x p-2 が x の逆数になるからです。 では、素数と式が与えられたときに、その素数の有限体で式を計算する電卓プログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりは0の後にコロンが1つ続くだけの行 0: で示される。各データセットは以下の形式で与えられる。 p:exp データセットは1行であり、p (2 ≤ p ≤ 46000) は素数、exp は算術式を示す。exp は加減乗除(それぞれ +, -, *, /)とカッコ、0 から p−1 までの数から構成される。演算子、数、カッコなどの前後には1つ以上の空白が現れる可能性がある。exp の長さは 100,000 を超えない。 データセットの数は 1000 を超えない。 出力 データセットごとに、計算結果を出力する。出力形式は以下の通りである。 exp = val (mod p) val は、p の有限体での算術式 exp の計算結果である。ただし、0 での除算が含まれるときは NG と出力する。また、exp に現れる加減乗除、カッコ、数の前後には空白を空けないこと。ただし、= の前後には空白を一つずつ空ける。また、valと開きカッコの間、modとp の間にも空白を一つずつ空ける。 入力例 5: 2 - 3 17: 1 + 3 * (2 + 3 / 5 * 2) + 7 11: 1 / 8 - 5 - 8 * 2 19: 8 / (2 - 3 * 7) 1153: 10 * 3 / 7 + ( 50 + 81 / 22 ) + 11 0: 出力例 2-3 = 4 (mod 5) 1+3*(2+3/5*2)+7 = 4 (mod 17) 1/8-5-8*2 = 8 (mod 11) NG 10*3/7+(50+81/22)+11 = 915 (mod 1153)
[ { "submission_id": "aoj_0264_10865771", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,s,t) for(int i = s; i < t ; ++i)\n#define ALL(a) a.begin(),a.end()\n#define SORT(a) sort(ALL(a))\n#define UNIQ(a) a.erase(unique(ALL(a)),a.end())\n#define debug(a) cerr<<#a\":=\"<<a<<endl;\n#define SZ(a) (int)a.size()\nusing LL = long long; template<class T> using V = vector <T>; template <class T> using VV = V<V<T>>;\n\n\nLL powmod(LL a, LL x, LL mod) {\n\tLL ret = 1;\n\twhile (x) {\n\t\tif (x % 2) {\n\t\t\tret *= a;\n\t\t\tret %= mod;\n\t\t}\n\t\ta *= a;\n\t\ta %= mod;\n\t\tx >>= 1;\n\t}\n\treturn ret;\n}\nstring spa(const string &s) {\n\tstring ret = \"\";\n\tFOR(i, 0, SZ(s)) {\n\t\tif (s[i] != ' ') {\n\t\t\tret += string(1, s[i]);\n\t\t}\n\t}\n\treturn ret;\n}\nLL getnum(string & s, int &i) {\n\tLL ret = 0;\n\twhile (isdigit(s[i])) {\n\t\tret *= 10;\n\t\tret += s[i] - '0';\n\t\ti++;\n\t}\n\n\treturn ret;\n}\n\nint flag;\n\nLL expr0(string&, int&, LL);\nLL expr1(string&, int&, LL);\nLL expr2(string&, int&, LL);\n\nLL expr0(string& s, int& i, LL mod) {\n\tLL ret = expr1(s, i, mod);\n\twhile (s[i] == '+' || s[i] == '-') {\n\t\tif (s[i] == '+')ret += expr1(s, ++i, mod);\n\t\tif(s[i]=='-')ret -= expr1(s, ++i, mod);\n\t\tret += mod;\n\t\tret %= mod;\n\t}\n\treturn ret;\n}\nLL expr1(string& s, int& i, LL mod) {\n\tLL ret = expr2(s, i, mod);\n\twhile (s[i] == '*' || s[i] == '/') {\n\t\tif (s[i] == '*')ret *= expr2(s, ++i, mod);\n\t\tif (s[i] == '/') {\n\t\t\tLL si = expr2(s, ++i, mod);\n\n\t\t\tif (si%mod == 0) {\n\t\t\t\tflag = 1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tret *= powmod(si, mod - 2,mod);\n\t\t\t}\n\t\t}\n\t\tret %= mod;\n\t}\n\treturn ret;\n}\nLL expr2(string& s, int& i, LL mod) {\n\tif (s[i] == '(') {\n\t\ti++;\n\t\tLL num = expr0(s, i, mod);\n\t\ti++;\n\t\treturn num;\n\t}\n\telse {\n\t\treturn getnum(s, i) % mod;\n\t}\n\n}\n\n\nint main() {\n\n\tstring s;\n\twhile (getline(cin,s), s[0] != '0') {\n\t\tstring t = spa(s);\n\t\tint i = 0;\n\t\tLL mod = getnum(t, i);\n\t\ti++;\n\t\tt = t.substr(i);\n\t\tstring sub = t;\n\t\ti = 0;\n\t\tflag = 0;\n\t\tLL ans = expr0(t, i,mod);\n\t\tif (flag) {\n\t\t\tcout << \"NG\" << endl;\n\t\t}\n\t\telse {\n\t\t\tcout << sub ;\n\t\t\tcout << \" = \" << ans << \" (mod \" << mod << \")\" << endl;\n\t\t}\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3416, "score_of_the_acc": -0.3377, "final_rank": 5 }, { "submission_id": "aoj_0264_10846621", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nlong mod;\nbool ok;\nlong POW(long x, long n){\n long res=1;\n x%=mod;\n while(n){\n if(n&1){\n res*=x;\n res%=mod;\n }\n x*=x;\n x%=mod;\n n>>=1L;\n }\n return res;\n}\n\ntypedef string::const_iterator State;\n\nlong expression(State &begin);\n\n\nlong number(State &begin){\n long ret=0;\n while((isdigit(*begin))){\n ret*=10;\n ret+=*begin-'0';\n ret%=mod;\n begin++;\n }\n return ret;\n}\n\nlong factor(State &begin){\n if(*begin=='('){\n begin++;\n long ret=expression(begin);\n begin++;\n return ret;\n }\n else return number(begin);\n}\n\nlong term(State &begin){\n long ret=factor(begin);\n for(;;){\n if(*begin=='*'){\n begin++;\n ret*=factor(begin);\n ret%=mod;\n }\n else if(*begin=='/'){\n begin++;\n long a=factor(begin);\n if(a==0){\n ok=0;\n a=1;\n }\n else{\n ret*=POW(a, mod-2);\n ret%=mod;\n }\n }\n else break;\n }\n return ret;\n}\n\nlong expression(State &begin){\n long ret=term(begin);\n for(;;){\n if(*begin=='+'){\n begin++;\n ret+=term(begin);\n ret%=mod;\n }\n else if(*begin=='-'){\n begin++;\n ret-=term(begin);\n ret+=mod;\n ret%=mod;\n }\n else break;\n }\n return ret;\n}\n\nlong f(string S){\n State begin=S.begin();\n return expression(begin);\n}\n\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n for(string t;getline(cin,t),t[0]!='0';){\n \n int id=find(all(t), ':')-t.begin();\n mod=stoi(t.substr(0, id));\n\n string s=t.substr(id+1, ssize(t)-id-1);\n s.erase(remove(all(s), ' '),s.end());\n\n ok=1;\n int ans=f(s)%mod;\n if(!ok) cout<<\"NG\\n\";\n else cout<<s<<\" = \"<<ans<<\" (mod \"<<mod<<\")\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.22, "final_rank": 2 }, { "submission_id": "aoj_0264_9395940", "code_snippet": "/// 生成AI不使用 / Not using generative AI\n\n// #pragma GCC target (\"avx\")\n// #pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#ifdef MARC_LOCAL\n#define _GLIBCXX_DEBUG\n#endif\n\n#ifdef ATCODER\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n//#define int long long\nusing ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using vvvll = vector<vvll>; using vvvvll = vector<vvvll>;\nusing vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>; using vvvvi = vector<vvvi>;\nusing ld = long double; using vld = vector<ld>; using vvld = vector<vld>; using vd = vector<double>;\nusing vc = vector<char>; using vvc = vector<vc>; using vs = vector<string>;\nusing vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;\nusing pii = pair<int, int>; using pcc = pair<char, char>; using pll = pair<ll, ll>; using pli = pair<ll, int>; using pdd = pair<double, double>; using pldld = pair<ld,ld>;\nusing vpii = vector<pii>; using vvpii = vector<vpii>; using vpll = vector<pll>; using vvpll = vector<vpll>; using vpldld = vector<pldld>;\nusing ui = unsigned int; using ull = unsigned long long;\nusing i128 = __int128; using f128 = __float128;\ntemplate<class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) vector<vector<type> > name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) vector<vector<vector<type> > > name(h, vector<vector<type> >(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) vector<vector<vector<vector<type> > > > name(a, vector<vector<vector<type> > >(b, vector<vector<type> >(c, vector<type>(__VA_ARGS__))))\n\n#define overload4(a,b,c,d,name,...) name\n#define rep1(n) for(ll i = 0; i < (ll)n; i++)\n#define rep2(i,n) for(ll i = 0; i < (ll)n; i++)\n#define rep3(i,a,b) for (ll i = a; i < (ll)b; i++)\n#define rep4(i,a,b,c) for (ll i = a; i < (ll)b; i += (ll)c)\n#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)\n#define repback1(n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback2(i,n) for (ll i = (ll)n-1; i >= 0; i--)\n#define repback3(i,a,b) for (ll i = (ll)b-1; i >= (ll)a; i--)\n#define repback4(i,a,b,c) for (ll i = (ll)b-1; i >= (ll)a; i -= (ll)c)\n#define repback(...) overload4(__VA_ARGS__,repback4,repback3,repback2,repback1)(__VA_ARGS__)\n#define all(x) (x).begin(), (x).end()\n#define include(y, x, H, W) (0 <= (y) && (y) < (H) && 0 <= (x) && (x) < (W))\n#define inrange(x, down, up) ((down) <= (x) && (x) <= (up))\n#define pb push_back\n#define eb emplace_back\n#define fir first\n#define sec second\n#define TIMER_START TIME_START = clock()\n#ifdef MARC_LOCAL\n// https://trap.jp/post/1224/\n#define debug1(x) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << endl\n#define debug2(x, y) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << endl\n#define debug3(x, y, z) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << endl\n#define debug4(x, y, z, w) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << endl\n#define debug5(x, y, z, w, v) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << endl\n#define debug6(x, y, z, w, v, u) cout << \"debug L\" << __LINE__ <<\": \" << (#x) << \": \" << (x) << \", \" << (#y) << \": \" << (y) << \", \" << (#z) << \": \" << (z) << \", \" << (#w) << \": \" << (w) << \", \" << (#v) << \": \" << (v) << \", \" << (#u) << \": \" << (u) << endl\n#define overload6(a, b, c, d, e, f, g,...) g\n#define debug(...) overload6(__VA_ARGS__, debug6, debug5, debug4, debug3, debug2, debug1)(__VA_ARGS__)\n#define debuga cerr << __LINE__ << endl\n#define debugnl cout << endl\n#define Case(i) cout << \"Case #\" << (i) << \": \"\n#define TIMECHECK cerr << 1000.0 * static_cast<double>(clock() - TIME_START) / CLOCKS_PER_SEC << \"ms\" << endl\n#define LOCAL 1\n#else\n#define debug1(x) void(0)\n#define debug2(x, y) void(0)\n#define debug3(x, y, z) void(0)\n#define debug4(x, y, z, w) void(0)\n#define debug5(x, y, z, w, v) void(0)\n#define debug6(x, y, z, w, v, u) void(0)\n#define debug(...) void(0)\n#define debuga void(0)\n#define debugnl void(0)\n#define Case(i) void(0)\n#define TIMECHECK void(0)\n#define LOCAL 0\n#endif\n\n//mt19937_64 rng(0);\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nclock_t TIME_START;\nconst long double pi = 3.141592653589793238462643383279L;\nconst long long INFL = 1000000000000000000ll;\nconst long long INFLMAX = numeric_limits< long long >::max(); // 9223372036854775807\nconst int INF = 1000000000;\nconst int INFMAX = numeric_limits< int >::max(); // 2147483647\nconst long double INFD = numeric_limits<ld>::infinity();\nconst long double EPS = 1e-10;\nconst int mod1 = 1000000007;\nconst int mod2 = 998244353;\nconst vi dx1 = {1,0,-1,0};\nconst vi dy1 = {0,1,0,-1};\nconst vi dx2 = {0, 1, 1, 1, 0, -1, -1, -1};\nconst vi dy2 = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr char nl = '\\n';\nconstexpr char bl = ' ';\n\nstd::ostream &operator<<(std::ostream &dest, __int128_t value) { std::ostream::sentry s(dest); if (s) {__uint128_t tmp = value < 0 ? -value : value; char buffer[128]; char *d = std::end(buffer); do {--d;*d = \"0123456789\"[tmp % 10];tmp /= 10;} while (tmp != 0);if (value < 0) {--d;*d = '-';}int len = std::end(buffer) - d;if (dest.rdbuf()->sputn(d, len) != len) {dest.setstate(std::ios_base::badbit);}}return dest; }\n__int128 parse(string &s) { __int128 ret = 0; for (int i = 0; i < (int)s.length(); i++) if ('0' <= s[i] && s[i] <= '9') ret = 10 * ret + s[i] - '0'; return ret; } // for __int128 (https://kenkoooo.hatenablog.com/entry/2016/11/30/163533)\ntemplate<class T> ostream& operator << (ostream& os, vector<T>& vec) { os << \"[\"; for (int i = 0; i<(int)vec.size(); i++) { os << vec[i] << (i + 1 == (int)vec.size() ? \"\" : \", \"); } os << \"]\"; return os; } /// vector 出力\ntemplate<class T, class U> ostream& operator << (ostream& os, pair<T, U>& pair_var) { os << \"(\" << pair_var.first << \", \" << pair_var.second << \")\"; return os; } // pair 出力\ntemplate<class T, class U> ostream& operator << (ostream& os, map<T, U>& map_var) { os << \"{\"; for (auto itr = map_var.begin(); itr != map_var.end(); itr++) { os << \"(\" << itr->first << \", \" << itr->second << \")\"; itr++; if(itr != map_var.end()) os << \", \"; itr--; } os << \"}\"; return os; } // map出力\ntemplate<class T> ostream& operator << (ostream& os, set<T>& set_var) { os << \"{\"; for (auto itr = set_var.begin(); itr != set_var.end(); itr++) { os << *itr; ++itr; if(itr != set_var.end()) os << \", \"; itr--; } os << \"}\"; return os; } /// set 出力\n\nbool equals(long double a, long double b) { return fabsl(a - b) < EPS; }\ntemplate<class T> int sign(T a) { return equals(a, 0) ? 0 : a > 0 ? 1 : -1; }\nlong double radian_to_degree(long double r) { return (r * 180.0 / pi); }\nlong double degree_to_radian(long double d) { return (d * pi / 180.0); }\n\nint popcnt(unsigned long long a){ return __builtin_popcountll(a); } // ll は 64bit対応!\nint MSB1(unsigned long long x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); } // MSB(1), 0-indexed ( (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2) )\nint LSB1(unsigned long long x) { return (x == 0 ? -1 : __builtin_ctzll(x)); } // LSB(1), 0-indexed ( (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2) )\nlong long maskbit(int n) { return (1LL << n) - 1; }\nbool bit_is1(long long x, int i) { return ((x>>i) & 1); }\nstring charrep(int n, char c) { return std::string(n, c); }\ntemplate<class T> T square(T x) { return (x) * (x); }\ntemplate<class T>void UNIQUE(T& A) {sort(all(A)); A.erase(unique(all(A)), A.end());}\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\ntemplate<class T, class U> bool chmin(T& a, const U& b){ return chmin(a, (T)b); }\ntemplate<class T, class U> bool chmax(T& a, const U& b){ return chmax(a, (T)b); }\nvoid YESNO(bool b) {if(b){cout<<\"YES\"<<'\\n';} else{cout<<\"NO\"<<'\\n';}} void YES() {YESNO(true);} void NO() {YESNO(false);}\nvoid yesno(bool b) {if(b){cout<<\"yes\"<<'\\n';} else{cout<<\"no\"<<'\\n';}} void yes() {yesno(true);} void no() {yesno(false);}\nvoid YesNo(bool b) {if(b){cout<<\"Yes\"<<'\\n';} else{cout<<\"No\"<<'\\n';}} void Yes() {YesNo(true);} void No() {YesNo(false);}\nvoid POSIMPOS(bool b) {if(b){cout<<\"POSSIBLE\"<<'\\n';} else{cout<<\"IMPOSSIBLE\"<<'\\n';}}\nvoid PosImpos(bool b) {if(b){cout<<\"Possible\"<<'\\n';} else{cout<<\"Impossible\"<<'\\n';}}\nvoid posimpos(bool b) {if(b){cout<<\"possible\"<<'\\n';} else{cout<<\"impossible\"<<'\\n';}}\nvoid FIRSEC(bool b) {if(b){cout<<\"FIRST\"<<'\\n';} else{cout<<\"SECOND\"<<'\\n';}}\nvoid firsec(bool b) {if(b){cout<<\"first\"<<'\\n';} else{cout<<\"second\"<<'\\n';}}\nvoid FirSec(bool b) {if(b){cout<<\"First\"<<'\\n';} else{cout<<\"Second\"<<'\\n';}}\nvoid AliBob(bool b) {if(b){cout<<\"Alice\"<<'\\n';} else{cout<<\"Bob\"<<'\\n';}}\nvoid TakAok(bool b) {if(b){cout<<\"Takahashi\"<<'\\n';} else{cout<<\"Aoki\"<<'\\n';}}\nint GetTime() {return 1000.0*static_cast<double>(clock() - TIME_START) / CLOCKS_PER_SEC;}\nll myRand(ll B) {return (unsigned long long)rng() % B;}\ntemplate<class T> void print(const T& x, const char endch = '\\n') { cout << x << endch; }\n\ntemplate<class T> T ceil_div(T x, T y) { assert(y); return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate<class T> T floor_div(T x, T y) { assert(y); return (x > 0 ? x / y : (x - y + 1) / y); }\ntemplate<class T> pair<T, T> divmod(T x, T y) { T q = floor_div(x, y); return {q, x - q * y}; } /// (q, r) s.t. x = q*y + r \nll GCD(ll a, ll b) { if(a < b) swap(a, b); if(b == 0) return a; if(a%b == 0) return b; else return GCD(b, a%b); }\nll LCM(ll a, ll b) { assert(GCD(a,b) != 0); return a / GCD(a, b) * b; }\nll MOD(ll &x, const ll P) { ll ret = x%P; if(ret < 0) ret += P; return x = ret; } /// x % P を非負整数に直す\nll mpow(ll x, ll n, const ll mod) { x %= mod; ll ret = 1; while(n > 0) { if(n & 1) ret = ret * x % mod; x = x * x % mod; n >>= 1; } return ret; } /// x^n % mod を計算\nll lpow(ll x, ll n) { ll ret = 1; while(n > 0){ if(n & 1) ret = ret * x; x = x * x; n >>= 1; } return ret; } /// x^nを計算\nstring toBinary(ll n) { if(n == 0) return \"0\"; assert(n > 0); string ret; while (n != 0){ ret += ( (n & 1) == 1 ? '1' : '0' ); n >>= 1; } reverse(ret.begin(), ret.end()); return ret; } /// 10進数(long long) -> 2進数(string)への変換\nll toDecimal(string S) { ll ret = 0; for(int i = 0; i < (int)S.size(); i++){ ret *= 2LL; if(S[i] == '1') ret += 1; } return ret; } /// 2進数(string) → 10進数(long long)への変換\nint ceil_pow2(ll n) { int x = 0; while ((1ll << x) < n) x++; return x;} /// return minimum non-negative `x` s.t. `n <= 2**x`\nint floor_pow2(ll n) { int x = 0; while ((1ll << (x+1)) <= n) x++; return x;} /// return maximum non-negative `x` s.t. `n >= 2**x`\n\n\n\n// ############################\n// # #\n// # C O D E S T A R T #\n// # #\n// ############################\n\ntypedef string::const_iterator State;\n\n\n/// ParseErrorが発生したときのエラー情報用\n// TODO : 使いやすいよう設定し直す\nclass ParseError : public std::exception {\n public:\n // デフォルトコンストラクタ\n ParseError() : message(\"Parse error\") {}\n\n // コンストラクタ:カスタムエラーメッセージを持つ\n ParseError(const std::string& msg, int line = -1, int column = -1)\n : message(msg), line(line), column(column) {\n buildFullMessage();\n }\n\n // コンストラクタ:行と列情報を含む\n ParseError(int line, int column)\n : message(\"Parse error\"), line(line), column(column) {\n buildFullMessage();\n }\n\n // エラーメッセージを取得するメンバ関数\n const char* what() const noexcept override {\n return fullMessage.c_str();\n }\n\n // 行番号を取得するメンバ関数\n int getLine() const {\n return line;\n }\n\n // 列番号を取得するメンバ関数\n int getColumn() const {\n return column;\n }\n\n private:\n std::string message;\n std::string fullMessage;\n int line;\n int column;\n\n // エラーメッセージを構築するプライベート関数\n void buildFullMessage() {\n std::ostringstream oss;\n oss << message;\n if (line >= 0) {\n oss << \" at line \" << line;\n }\n if (column >= 0) {\n oss << \", column \" << column;\n }\n fullMessage = oss.str();\n }\n};\n\n\n/// begin が 期待される文字 expectedを指していたらbeginを一つ進める(期待する文字でなければエラー発生)\n// assertのようなイメージ、デバッグ用(使用例: 式の最後に=が来るのであれば、consume(begin, '=')として最後まで到達してることを確認できる)\nvoid consume(State& begin, const char expected) {\n if (*begin == expected) {\n begin++;\n }\n else {\n cerr << \"Expected char is '\" << expected << \"' but got '\" << *begin << \"'\" << endl;\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n throw ParseError();\n }\n}\n\n\nlong long expression(State& begin);\nlong long term(State& begin);\nlong long factor(State& begin);\nlong long number(State& begin);\n\nll mod;\nbool ng = false;\n\n/// 四則演算(64bit整数用)\nlong long expression(State& begin) {\n long long ret = term(begin);\n\n while(true) {\n if(*begin == '+') {\n consume(begin, '+');\n ret += term(begin);\n MOD(ret, mod);\n }\n else if(*begin == '-') {\n consume(begin, '-');\n ret -= term(begin);\n MOD(ret, mod);\n }\n else break;\n }\n\n return ret;\n}\n\n/// 乗除\nlong long term(State& begin) {\n long long ret = factor(begin);\n\n while(true) {\n if(*begin == '*') {\n consume(begin, '*');\n ret *= factor(begin);\n MOD(ret, mod);\n }\n else if(*begin == '/') {\n consume(begin, '/');\n ll tmp = factor(begin);\n if(tmp == 0) ng = true;\n ret *= mpow(tmp,mod-2,mod);\n MOD(ret, mod);\n }\n else break;\n }\n\n return ret;\n}\n\n/// 括弧付きの式\nlong long factor(State& begin) {\n if(*begin == '(') {\n consume(begin, '(');\n long long ret = expression(begin);\n consume(begin, ')');\n return ret;\n }\n else {\n return number(begin);\n }\n}\n\n\n/// 数\nlong long number(State& begin) {\n long long ret = 0;\n\n while(isdigit(*begin)) {\n ret *= 10;\n ret += *begin - '0';\n MOD(ret, mod);\n begin++;\n }\n\n return ret;\n}\n\n\n\n/// main()の中に0を受け取る変数(終了判定)を定義しておく\n//ll N;\nstring S;\n\nvoid solve() {\n S.erase(remove_if(all(S), ::isspace), S.end()); // remove_if: 前に引数で与えられた関数に引っかからなかったものが寄せられる -> eraseの第一引数に渡せば消せる\n //debug(S);\n\n ng = false;\n State it = S.begin();\n \n string mods;\n while(*it != ':') {\n mods += *it;\n it++;\n }\n it++;\n mod = stoll(mods);\n //debug(mod);\n \n string ans;\n auto it2 = it;\n while(it2 != S.end()) {\n ans += *it2;\n it2++;\n }\n ans += \" = \";\n //debug(ans);\n\n ll res = expression(it);\n if(ng) {\n cout << \"NG\\n\";\n return;\n }\n ans += to_string(res);\n ans += \" (mod \";\n ans += mods;\n ans += \")\";\n\n cout << ans << nl;\n\n}\n\n\n\nsigned main() {\n cin.tie(0); ios_base::sync_with_stdio(false);\n TIMER_START;\n //cout << fixed << setprecision(15);\n \n\n //int tt = 1;\n //cin >> tt;\n while(true){\n // cin >> N;\n // if(N == 0) break;\n getline(cin, S);\n if(S[0] == '0') break;\n\n solve();\n }\n\n TIMECHECK;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3576, "score_of_the_acc": -0.4092, "final_rank": 12 }, { "submission_id": "aoj_0264_9338098", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nint number(State &begin);\nint term(State &begin);\nint expression(State &begin);\nint factor(State &begin);\nint p;\nbool flag;\nint pow_mod(int n, int k){\n if(k == 0) return 1;\n if(k == 1) return n;\n if(k%2 == 1) return (n*pow_mod(n,k-1))%p;\n int x = pow_mod(n, k/2);\n return (x*x)%p;\n}\nint inv(int n){\n return pow_mod(n, p-2);\n}\nint number(State &begin){\n int ret =0;\n while(isdigit(*begin)){\n ret = ret*10+(*begin - '0');\n ret %= p;\n begin++;\n }\n // cout << ret << endl;\n return ret;\n}\nint term(State &begin){\n int ret = factor(begin);\n while(true){\n if(*begin == '*'){\n begin++;\n ret *= factor(begin);\n ret %= p;\n }\n else if(*begin == '/'){\n begin++;\n int x = factor(begin);\n if(x == 0) {\n flag = false;\n }\n ret *= inv(x);\n ret %= p;\n }\n else{\n break;\n }\n }\n ret %= p;\n return ret;\n}\nint expression(State &begin) {\n int ret = term(begin);\n for (;;) {\n if (*begin == '+') {\n begin++;\n ret += term(begin);\n ret %= p;\n } else if (*begin == '-') {\n begin++;\n ret -= term(begin);\n ret = (ret+p)%p;\n } else {\n break;\n }\n }\n ret %= p;\n return ret;\n}\nint factor(State &begin) {\n if (*begin == '(') {\n begin++; // '('を飛ばす。\n int ret = expression(begin);\n begin++; // ')'を飛ばす。\n return ret;\n } else {\n return number(begin);\n }\n}\nbool solve(){\n string s;\n cin >> p;\n getline(cin, s);\n s.erase(std::remove_if(s.begin(), s.end(), ::isspace), s.end());\n if(p == 0) return false;\n State begin = s.begin();\n begin++;\n flag = true;\n int ans = expression(begin);\n // cout << ans << endl;\n if(flag){\n cout << s.substr(1, s.size()-1) << \" = \" << ans << \" (mod \" << p << \")\" << endl;\n }\n else cout << \"NG\" << endl;\n return true;\n}\nint main(){\n while(solve());\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3220, "score_of_the_acc": -0.375, "final_rank": 9 }, { "submission_id": "aoj_0264_8455929", "code_snippet": "#include <bits/stdc++.h>\n\nstruct Data {\n std::string expr;\n int prime;\n int val;\n bool ok;\n};\n\nvoid valid(Data data) {\n if (!data.ok) return;\n}\n\nstd::ostream& operator<<(std::ostream& os, const Data& data) {\n valid(data);\n if (data.ok) {\n os << data.expr << \" = \" << data.val << \" (mod \" << data.prime << \")\";\n } else {\n os << \"NG\";\n }\n\n return os;\n}\n\nstd::string eliminate_space(std::string s) {\n s.erase(std::remove_if(s.begin(), s.end(), [](char c) { return c == ' '; }), s.end());\n return s;\n}\n\nint powmod(int base, int exp, int mod) {\n int res = 1;\n while (exp > 0) {\n if (exp & 1) {\n res *= base;\n res %= mod;\n }\n base *= base;\n base %= mod;\n exp >>= 1;\n }\n return res;\n}\n\nclass ExprError {};\n\nstruct Expr {\n using Iter = std::string::const_iterator&;\n\n std::string s;\n int p;\n\n Expr(std::string s, int p): s(s), p(p) {}\n\n void consume(Iter it, char c) {\n it++;\n }\n\n std::pair<int, bool> eval() {\n auto it = s.cbegin();\n try {\n return {expr(it), true};\n } catch (ExprError) {\n return {-1, false};\n }\n }\n\n int expr(Iter it) {\n int res = term(it);\n while (it != s.end() && (*it == '+' || *it == '-')) {\n if (*it == '+') {\n consume(it, '+');\n res = (res + term(it)) % p;\n } else {\n consume(it, '-');\n res = (res - term(it) + p) % p;\n }\n }\n return res;\n }\n\n int term(Iter it) {\n int res = factor(it);\n while (it != s.end() && (*it == '*' || *it == '/')) {\n if (*it == '*') {\n consume(it, '*');\n res = res * factor(it) % p;\n } else {\n consume(it, '/');\n int temp = factor(it);\n if (temp == 0) {\n throw ExprError();\n }\n res = res * powmod(temp, p - 2, p) % p;\n }\n }\n return res;\n }\n\n int factor(Iter it) {\n if (*it == '(') {\n consume(it, '(');\n int res = expr(it);\n consume(it, ')');\n return res;\n } else {\n return number(it);\n }\n }\n\n int number(Iter it) {\n int res = 0;\n while (it != s.end() && std::isdigit(*it)) {\n res = 10 * res + (*it) - '0';\n it++;\n }\n\n return res;\n }\n};\n\nstruct Parser {\n using Iter = std::string::const_iterator&;\n std::string s;\n\n Parser(std::string s): s(s) {}\n\n void consume(Iter it, char c) {\n it++;\n }\n\n Data parse() {\n s = eliminate_space(s);\n\n Data data;\n auto it = s.cbegin();\n data.prime = prime(it);\n consume(it, ':');\n data.expr = expr(it);\n\n Expr expr(data.expr, data.prime);\n auto [val, ok] = expr.eval();\n data.val = val;\n data.ok = ok;\n\n return data;\n }\n\n int prime(Iter it) {\n int res = 0;\n while (it != s.end() && *it != ':') {\n res = 10 * res + (*it) - '0';\n it++;\n }\n return res;\n }\n\n std::string expr(Iter it) {\n std::string res(it, s.cend());\n it = s.cend();\n return res;\n }\n};\n\nint main() {\n std::string s;\n while (true) {\n std::getline(std::cin, s);\n if (s == \"0:\") break;\n Parser parser(s);\n std::cout << parser.parse() << std::endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3568, "score_of_the_acc": -0.2806, "final_rank": 4 }, { "submission_id": "aoj_0264_8030772", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint getMod(string& S) {\n reverse(S.begin(), S.end());\n int res = 0;\n while (S.back() != ':') {\n res = (res * 10) + (S.back() - '0');\n S.pop_back();\n }\n assert(S.back() == ':');\n S.pop_back();\n reverse(S.begin(), S.end());\n return res;\n}\n\nstring clean(const string& S) {\n string res;\n for (auto c : S) if (c != ' ') {\n res += c;\n }\n return res;\n}\n\nll mod;\n\nnamespace zawa {\n\nll add(ll a, ll b) {\n return (a + b >= mod ? a + b - mod : a + b);\n}\n\nll sub(ll a, ll b) {\n ll res = a - b + mod;\n return (res >= mod ? res - mod : res);\n}\n\nll mul(ll a, ll b) {\n return (a * b) % mod;\n}\n\nll pow(ll a, ll p) {\n ll res = 1LL, base = a;\n while (p) {\n if (p & 1) res = mul(res, base);\n base = mul(base, base);\n p >>= 1;\n }\n return res;\n}\n\npair<ll, bool> div(ll a, ll b) {\n if (b == 0) return { 0, false };\n return { mul(a, pow(b, mod - 2)), true };\n}\n\n} // namespace zawa\n\nint it;\nbool ok = true;\n\nbool isDig(char c) {\n return '0' <= c and c <= '9';\n}\n\nll factor(const string&);\nll term(const string&);\nll expr(const string&);\n\nll factor(const string& S) {\n if (S[it] == '(') {\n it++;\n ll res = expr(S);\n assert(S[it] == ')');\n it++;\n return res;\n }\n if (isDig(S[it])) {\n ll res = 0;\n while (isDig(S[it])) {\n res = (res * 10) + (S[it] - '0');\n it++;\n }\n return res;\n }\n assert(false);\n}\n\nll term(const string& S) {\n ll lhs = factor(S);\n while (1) {\n if (it == (int)S.size()) break;\n if (S[it] == ')') break;\n if (S[it] == '+' or S[it] == '-') break;\n char op = S[it];\n it++;\n ll rhs = factor(S);\n // cout << \" calc term :\" << lhs << ' ' << rhs << ' ' << op << endl;\n if (op == '*') lhs = zawa::mul(lhs, rhs);\n else if (op == '/') {\n auto cond = zawa::div(lhs, rhs);\n if (cond.second) {\n lhs = cond.first;\n }\n else {\n ok = false;\n lhs = 0;\n }\n }\n else assert(false);\n }\n return lhs;\n}\n\nll expr(const string& S) {\n ll lhs = term(S);\n while (1) {\n if (it == (int)S.size()) break;\n if (S[it] == ')') break;\n char op = S[it];\n it++;\n ll rhs = term(S);\n // cout << \"calc expr: \" << lhs << ' ' << rhs << ' ' << op << endl;\n if (op == '+') lhs = zawa::add(lhs, rhs);\n else if (op == '-') lhs = zawa::sub(lhs, rhs);\n else assert(false);\n }\n return lhs;\n}\n\nbool solve() {\n string S; getline(cin, S);\n mod = getMod(S);\n\n if (S.empty()) return false;\n\n S = clean(S);\n\n it = 0;\n ok = true;\n ll ans = expr(S);\n if (ok) {\n cout << S << \" = \" << ans << ' ' << \"(mod \" << mod << ')' << endl;\n }\n else {\n cout << \"NG\" << endl;\n }\n\n return true;\n}\n\nint main() {\n while (solve()) ;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3436, "score_of_the_acc": -0.3466, "final_rank": 6 }, { "submission_id": "aoj_0264_8024202", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef __int128_t lll;\ntypedef long double ld;\ntypedef pair<ll, ll> pl;\ntypedef tuple<ll, ll, ll> tt;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<vvl> vvvl;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<vvd> vvvd;\ntypedef vector<bool> vb;\ntypedef vector<vb> vvb;\ntypedef vector<vvb> vvvb;\ntypedef vector<char> vc;\ntypedef vector<vc> vvc;\ntypedef vector<vvc> vvvc;\ntypedef vector<pl> vp;\ntypedef vector<tt> vt;\ntypedef vector<string> vs;\n\nconst ll INF = 1000000010;\nconst ll INFL = INF * INF;\nconst ld epsilon = 1e-10;\n\n#define ovl(a, b, c, d, e, ...) e\n#define pb push_back\n#define eb emplace_back\n#define MP make_pair\n#define DEBUG(...) DEBUG_(#__VA_ARGS__, __VA_ARGS__)\n#define REP1(i, r) for (int i = 0; i < (r); i++)\n#define REP2(i, l, r) for (int i = (l); i < (r); i++)\n#define REP3(i, l, r, d) for (int i = (l); i < (r); i += (d))\n#define REP(...) ovl(__VA_ARGS__, REP3, REP2, REP1)(__VA_ARGS__)\n#define RREP1(i, r) for (int i = (r)-1; i >= 0; i--)\n#define RREP2(i, l, r) for (int i = (r)-1; i >= (l); i--)\n#define RREP3(i, l, r, d) for (int i = (r)-1; i >= (l); i -= (d))\n#define RREP(...) ovl(__VA_ARGS__, RREP3, RREP2, RREP1)(__VA_ARGS__)\n#define EACH1(x, a) for (auto &x : a)\n#define EACH2(x, y, a) for (auto &[x, y] : a)\n#define EACH3(x, y, z, a) for (auto &[x, y, z] : a)\n#define EACH(...) ovl(__VA_ARGS__, EACH3, EACH2, EACH1)(__VA_ARGS__)\n#define ALL(x) begin(x), end(x)\n#define RALL(x) (x).rbegin(), (x).rend()\n#define sz(x) (ll) x.size()\n#define LB(a, x) (lower_bound(ALL(a), x) - a.begin())\n#define UB(a, x) (upper_bound(ALL(a), x) - a.begin())\n#define FLG(x, i) (((x) >> (i)) & 1)\n#define CNTBIT(x) __builtin_popcountll(x)\n#define IN(x, a, b) ((a) <= (x) && (x) < (b))\n#define int ll\n\ntemplate <class T>\nvoid DEBUG_(string_view name, const T &a) {\n cerr << name << \": \" << a << endl;\n}\n\ntemplate <class T>\nvoid DEBUG_(string_view name, const vector<T> &a) {\n cerr << name << \": \";\n REP(i, sz(a)) cerr << a[i] << \" \";\n cerr << endl;\n}\n\ntemplate <class T, class U>\nbool chmax(T &x, const U &y) {\n return x < y ? x = y, 1 : 0;\n}\ntemplate <class T, class U>\nbool chmin(T &x, const U &y) {\n return x > y ? x = y, 1 : 0;\n}\n\n//-----------------------------------------------------------------------\n\ntypedef string::const_iterator State;\n\nint MOD;\n\nint modinv(int b) {\n int e = MOD - 2;\n int p = b;\n int ans = 1;\n while (e) {\n if (e & 1) {\n ans *= p;\n ans %= MOD;\n }\n e >>= 1;\n p = (p * p) % MOD;\n }\n return ans;\n}\n\nint number(State &begin) {\n int ret = 0;\n while (isdigit(*begin) || *begin == ' ') {\n if (*begin == ' ') {\n begin++;\n continue;\n }\n ret *= 10;\n ret += *begin - '0';\n begin++;\n }\n return ret;\n}\n\nint expression(State &state);\n\nint factor(State &begin) {\n if (*begin == ' ') {\n begin++;\n }\n if (*begin == '(') {\n begin++;\n int ret = expression(begin);\n begin++;\n return ret;\n } else {\n return number(begin);\n }\n}\n\nint term(State &begin) {\n int ret = factor(begin);\n\n while (true) {\n if (*begin == '*') {\n // DEBUG(\"*\");\n begin++;\n ret *= factor(begin);\n ret %= MOD;\n } else if (*begin == '/') {\n begin++;\n int div = factor(begin);\n if (div == 0) {\n throw logic_error(\"zero\");\n break;\n }\n ret *= modinv(div);\n ret %= MOD;\n } else if (*begin == ' ') {\n begin++;\n } else {\n break;\n }\n }\n\n return ret;\n}\n\nint expression(State &begin) {\n int ret = term(begin);\n while (true) {\n // DEBUG(ret);\n if (*begin == '+') {\n // DEBUG(\"+\");\n begin++;\n ret += term(begin);\n ret %= MOD;\n } else if (*begin == '-') {\n // DEBUG(\"-\");\n begin++;\n ret += MOD - (term(begin) % MOD);\n ret %= MOD;\n } else if (*begin == ' ') {\n begin++;\n } else {\n break;\n }\n }\n return ret;\n}\n\nsigned main() {\n while (true) {\n string S;\n getline(cin, S);\n if (S == \"0:\") break;\n string T = \"\";\n bool isStart = false;\n REP(i, int(S.size())) {\n if (S[i] == ':') {\n i++;\n isStart = true;\n }\n if (!isStart) continue;\n if (S[i] != ' ') {\n T += S[i];\n }\n }\n T += \" = \";\n State begin = S.begin();\n MOD = number(begin);\n assert(*begin == ':');\n begin++;\n try {\n int ans = expression(begin);\n T += to_string(ans) + \" (mod \" + to_string(MOD) + \")\";\n cout << T << endl;\n } catch (logic_error const &) {\n cout << \"NG\" << endl;\n }\n }\n\n // random_test();\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3696, "score_of_the_acc": -0.4629, "final_rank": 13 }, { "submission_id": "aoj_0264_7977184", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\ntypedef string::const_iterator State;\nclass ParseError {};\n\nll mod = -1;\nbool ng = false;\n\nll mypow(ll x, ll n) {\n ll ret = 1;\n while(n) {\n if(n & 1) ret = (ret * x) % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return ret;\n}\n\nll shisoku(State&);\n\nll number(State& ptr) {\n ll ret = 0;\n while(isdigit(*ptr)) {\n ret *= 10;\n ret += *ptr - '0';\n ptr++;\n }\n return ret;\n}\n\nll factor(State& ptr) {\n if(*ptr == '(') {\n ptr++;\n int ret = shisoku(ptr);\n ptr++;\n return ret;\n } else\n return number(ptr);\n}\n\nll kakewaru(State& ptr) {\n ll ret = factor(ptr);\n while(true) {\n if(*ptr == '*') {\n ptr++;\n ret *= factor(ptr);\n ret %= mod;\n } else if(*ptr == '/') {\n ptr++;\n int num = factor(ptr);\n if(num == 0) {\n ng = true;\n return 0;\n }\n ret *= mypow(num, mod - 2);\n ret %= mod;\n } else {\n break;\n }\n }\n return ret;\n}\n\nll shisoku(State& ptr) {\n ll ret = kakewaru(ptr);\n while(true) {\n if(*ptr == '+') {\n ptr++;\n ret += kakewaru(ptr);\n ret %= mod;\n } else if(*ptr == '-') {\n ptr++;\n ret += mod - kakewaru(ptr);\n ret %= mod;\n } else {\n break;\n }\n }\n return ret;\n}\n\nstring ignoreSpace(string s) {\n string ret = \"\";\n for(auto&& c : s)\n if(c != ' ') ret.push_back(c);\n return ret;\n}\n\nint main() {\n string s;\n while(true) {\n ng = false;\n getline(cin, s);\n\n s = ignoreSpace(s);\n\n State ptr = s.begin();\n mod = number(ptr);\n if(mod == 0) break;\n ptr++;\n int ans = shisoku(ptr);\n if(!ng) {\n auto itr = find(s.begin(), s.end(), ':');\n cout << string(itr + 1, s.end()) << \" = \" << ans << \" (mod \" << mod\n << \")\" << endl;\n } else\n cout << \"NG\" << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3492, "score_of_the_acc": -0.3716, "final_rank": 8 }, { "submission_id": "aoj_0264_7969853", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\n\nint mod;\nclass Result {\n public:\n int val;\n bool parse_ok;\n\n Result() : val(0), parse_ok(true) {}\n\n Result &operator+=(const Result &rhs) {\n val += rhs.val;\n if (val >= mod) val -= mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator-=(const Result &rhs) {\n val -= rhs.val;\n if (val < 0) val += mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator*=(const Result &rhs) {\n val = val * rhs.val % mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator/=(const Result &rhs) {\n if (rhs.val == 0)\n parse_ok = false;\n else\n val = val * mpow(rhs.val, mod - 2) % mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n\n int mpow(int x, int n) {\n int res = 1;\n while (n) {\n if (n & 1) res = res * x % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return res;\n }\n};\n\nvector<string> OPS = {\"+-\", \"*/\"};\nResult parse(const string &s, size_t &i, size_t p = 0) {\n if (p == OPS.size()) {\n Result res = Result();\n if (s[i] == '(') {\n res = parse(s, ++i, 0);\n assert(s[i] == ')');\n ++i;\n } else if (isdigit(s[i])) {\n while (isdigit(s[i])) {\n res.val *= 10;\n res.val += s[i++] - '0';\n }\n }\n return res;\n }\n\n Result res = parse(s, i, p + 1);\n while (i < s.length()) {\n char op = s[i];\n if (OPS[p].find(op) == string::npos) break;\n Result rhs = parse(s, ++i, p + 1);\n\n if (op == '+') res += rhs;\n if (op == '-') res -= rhs;\n if (op == '*') res *= rhs;\n if (op == '/') res /= rhs;\n }\n return res;\n}\n\nvoid solve(string S) {\n size_t i = 0;\n mod = 0;\n while (isdigit(S[i])) {\n mod *= 10;\n mod += S[i++] - '0';\n }\n\n string t = \"\";\n while (++i < S.length()) {\n if (S[i] == ' ') continue;\n t += S[i];\n }\n\n i = 0;\n Result res = parse(t, i);\n\n if (!res.parse_ok) {\n printf(\"NG\\n\");\n return;\n }\n printf(\"%s = %d (mod %d)\\n\", t.c_str(), res.val, mod);\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n\n string S;\n while (getline(cin, S)) {\n if (S == \"0:\") break;\n solve(S);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3648, "score_of_the_acc": -0.1914, "final_rank": 1 }, { "submission_id": "aoj_0264_7969755", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\n\nint mod;\nclass Result {\n public:\n int val;\n bool parse_ok;\n\n Result() : val(0), parse_ok(true) {}\n\n Result &operator+=(const Result &rhs) {\n val += rhs.val;\n if (val >= mod) val -= mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator-=(const Result &rhs) {\n val -= rhs.val;\n if (val < 0) val += mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator*=(const Result &rhs) {\n val = val * rhs.val % mod;\n parse_ok &= rhs.parse_ok;\n return *this;\n }\n Result &operator/=(const Result &rhs) {\n if (rhs.val == 0)\n parse_ok = false;\n else\n val = val * mpow(rhs.val, mod - 2) % mod;\n return *this;\n }\n\n int mpow(int x, int n) {\n int res = 1;\n while (n) {\n if (n & 1) res = res * x % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return res;\n }\n};\n\nvector<string> OPS = {\"+-\", \"*/\"};\nResult parse(const string &s, size_t &i, size_t p = 0) {\n if (p == OPS.size()) {\n Result res = Result();\n if (s[i] == '(') {\n res = parse(s, ++i, 0);\n assert(s[i] == ')');\n ++i;\n } else if (isdigit(s[i])) {\n while (isdigit(s[i])) {\n res.val *= 10;\n res.val += s[i++] - '0';\n }\n }\n return res;\n }\n\n Result res = parse(s, i, p + 1);\n while (i < s.length()) {\n char op = s[i];\n if (OPS[p].find(op) == string::npos) break;\n Result rhs = parse(s, ++i, p + 1);\n\n if (op == '+') res += rhs;\n if (op == '-') res -= rhs;\n if (op == '*') res *= rhs;\n if (op == '/') res /= rhs;\n }\n return res;\n}\n\nvoid solve(string S) {\n size_t i = 0;\n mod = 0;\n while (isdigit(S[i])) {\n mod *= 10;\n mod += S[i++] - '0';\n }\n\n string t = \"\";\n while (++i < S.length()) {\n if (S[i] == ' ') continue;\n t += S[i];\n }\n\n i = 0;\n Result res = parse(t, i);\n\n if (!res.parse_ok) {\n printf(\"NG\\n\");\n return;\n }\n printf(\"%s = %d (mod %d)\\n\", t.c_str(), res.val, mod);\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n\n string S;\n while (getline(cin, S)) {\n if (S == \"0:\") break;\n solve(S);\n }\n\n return 0;\n}", "accuracy": 0.8333333333333334, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.1628, "final_rank": 20 }, { "submission_id": "aoj_0264_7937209", "code_snippet": "#include <algorithm>\n#include <cassert>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <vector>\nusing namespace std;\n#define FOR(i, k, n) for (int i = (k); i < (int)(n); ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define FORIT(i, c) \\\n for (__typeof((c).begin()) i = (c).begin(); i != (c).end(); ++i)\ntemplate <class T> void debug(T begin, T end) {\n for (T i = begin; i != end; ++i)\n cerr << *i << \" \";\n cerr << endl;\n}\ninline bool valid(int x, int y, int W, int H) {\n return (x >= 0 && y >= 0 && x < W && y < H);\n}\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nclass ParseError {};\nstruct Result {\n ll value;\n int p;\n Result(ll value, int p) : value(value), p(p) {}\n};\nvoid skip(const string &s, Result &r, char expected) {\n if (s[r.p] == expected) {\n r.p++;\n } else {\n cerr << \"try to skip'\" << expected << \"' but this char is '\" << s[r.p]\n << \"'.\" << endl;\n assert(false);\n }\n}\nResult expression(const string &s, int p, const int MOD);\nResult term(const string &s, int p, const int MOD);\nResult factor(const string &s, int p, const int MOD);\nmap<pair<int, int>, int> inv_dict;\nint inverse(int x, const int MOD) {\n pair<int, int> state = make_pair(x, MOD);\n if (inv_dict.count(state))\n return inv_dict[state];\n int res = 1;\n REP(iter, MOD - 2) res = (res * x) % MOD;\n return inv_dict[state] = res;\n}\nResult expression(const string &s, int p, const int MOD) {\n Result r = term(s, p, MOD);\n while (s[r.p] == '+' || s[r.p] == '-') {\n Result r_ = term(s, r.p + 1, MOD);\n if (s[r.p] == '+') {\n r.value = (r.value + r_.value) % MOD;\n } else {\n r.value = (r.value - r_.value + MOD) % MOD;\n }\n r.p = r_.p;\n }\n return r;\n}\nResult term(const string &s, int p, const int MOD) {\n Result r = factor(s, p, MOD);\n while (s[r.p] == '*' || s[r.p] == '/') {\n Result r_ = factor(s, r.p + 1, MOD);\n if (s[r.p] == '*') {\n r.value = (r.value * r_.value) % MOD;\n } else {\n if (r_.value == 0)\n throw ParseError();\n r.value = (r.value * inverse(r_.value, MOD)) % MOD;\n }\n r.p = r_.p;\n }\n return r;\n}\nResult factor(const string &s, int p, const int MOD) {\n if (s[p] == '(') {\n Result r = expression(s, p + 1, MOD);\n skip(s, r, ')');\n return r;\n } else {\n int val = 0;\n while (isdigit(s[p])) {\n val = val * 10 + s[p++] - '0';\n }\n return Result(val, p);\n }\n}\nint main() {\n string line;\n while (getline(cin, line)) {\n if (line == \"0:\")\n break;\n REP(i, line.size()) if (line[i] == ':') line[i] = ' ';\n stringstream ss(line);\n string mod_str;\n ss >> mod_str;\n string expr, s;\n while (ss >> s)\n expr += s;\n int mod;\n sscanf(mod_str.c_str(), \"%d\", &mod);\n try {\n int val = expression(expr, 0, mod).value;\n printf(\"%s = %d (mod %d)\\n\", expr.c_str(), val, mod);\n } catch (...) {\n cout << \"NG\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3648, "score_of_the_acc": -1.1914, "final_rank": 18 }, { "submission_id": "aoj_0264_7937208", "code_snippet": "#include <algorithm>\n#include <cassert>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <vector>\nusing namespace std;\n#define FOR(i, k, n) for (int i = (k); i < (int)(n); ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define FORIT(i, c) \\\n for (__typeof((c).begin()) i = (c).begin(); i != (c).end(); ++i)\ntemplate <class T> void debug(T begin, T end) {\n for (T i = begin; i != end; ++i)\n cerr << *i << \" \";\n cerr << endl;\n}\ninline bool valid(int x, int y, int W, int H) {\n return (x >= 0 && y >= 0 && x < W && y < H);\n}\ntypedef long long ll;\nconst int INF = 100000000;\nconst double EPS = 1e-8;\nint dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nint dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\nclass ParseError {};\nstruct Result {\n ll value;\n int p;\n Result(ll value, int p) : value(value), p(p) {}\n};\nvoid skip(const string &s, Result &r, char expected) {\n if (s[r.p] == expected) {\n r.p++;\n } else {\n cerr << \"try to skip'\" << expected << \"' but this char is '\" << s[r.p]\n << \"'.\" << endl;\n assert(false);\n }\n}\nResult expression(const string &s, int p, const int MOD);\nResult term(const string &s, int p, const int MOD);\nResult factor(const string &s, int p, const int MOD);\nint inverse(int x, const int MOD) {\n int res = 1;\n int pow = MOD - 2;\n while (pow != 0) {\n if (pow & 1)\n res = (res * x) % MOD;\n pow >>= 1;\n x = (x * x) % MOD;\n }\n return res;\n}\nResult expression(const string &s, int p, const int MOD) {\n Result r = term(s, p, MOD);\n while (s[r.p] == '+' || s[r.p] == '-') {\n Result r_ = term(s, r.p + 1, MOD);\n if (s[r.p] == '+') {\n r.value = (r.value + r_.value) % MOD;\n } else {\n r.value = (r.value - r_.value + MOD) % MOD;\n }\n r.p = r_.p;\n }\n return r;\n}\nResult term(const string &s, int p, const int MOD) {\n Result r = factor(s, p, MOD);\n while (s[r.p] == '*' || s[r.p] == '/') {\n Result r_ = factor(s, r.p + 1, MOD);\n if (s[r.p] == '*') {\n r.value = (r.value * r_.value) % MOD;\n } else {\n if (r_.value == 0)\n throw ParseError();\n r.value = (r.value * inverse(r_.value, MOD)) % MOD;\n }\n r.p = r_.p;\n }\n return r;\n}\nResult factor(const string &s, int p, const int MOD) {\n if (s[p] == '(') {\n Result r = expression(s, p + 1, MOD);\n skip(s, r, ')');\n return r;\n } else {\n int val = 0;\n while (isdigit(s[p])) {\n val = val * 10 + s[p++] - '0';\n }\n return Result(val, p);\n }\n}\nint main() {\n string line;\n while (getline(cin, line)) {\n if (line == \"0:\")\n break;\n REP(i, line.size()) if (line[i] == ':') line[i] = ' ';\n stringstream ss(line);\n string mod_str;\n ss >> mod_str;\n string expr, s;\n while (ss >> s)\n expr += s;\n int mod;\n sscanf(mod_str.c_str(), \"%d\", &mod);\n try {\n int val = expression(expr, 0, mod).value;\n printf(\"%s = %d (mod %d)\\n\", expr.c_str(), val, mod);\n } catch (...) {\n cout << \"NG\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3468, "score_of_the_acc": -0.4859, "final_rank": 15 }, { "submission_id": "aoj_0264_7200064", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nconst int INF = 1012345678;\n\nclass segtree {\nprivate:\n\tint sz;\n\tvector<pair<int, int> > val;\npublic:\n\tsegtree() : sz(0), val(vector<pair<int, int> >()) {}\n\tsegtree(int n) {\n\t\tsz = 1;\n\t\twhile (sz < n) {\n\t\t\tsz *= 2;\n\t\t}\n\t\tval = vector<pair<int, int> >(2 * sz);\n\t\tfor (int i = sz - 1; i >= 0; i--) {\n\t\t\tval[sz + i] = make_pair(INF, -i);\n\t\t}\n\t\tfor (int i = sz - 1; i >= 1; i--) {\n\t\t\tval[i] = min(val[i * 2], val[i * 2 + 1]);\n\t\t}\n\t}\n\tvoid update(int pos, int x) {\n\t\tpos += sz;\n\t\tval[pos] = make_pair(x, -(pos - sz));\n\t\twhile (pos > 1) {\n\t\t\tpos >>= 1;\n\t\t\tval[pos] = min(val[pos * 2], val[pos * 2 + 1]);\n\t\t}\n\t}\n\tpair<int, int> rangemin(int l, int r) const {\n\t\tpair<int, int> res = make_pair(INF, -1);\n\t\tl += sz;\n\t\tr += sz;\n\t\twhile (l != r) {\n\t\t\tif (l & 1) res = min(res, val[l]), l++;\n\t\t\tif (r & 1) r--, res = min(res, val[r]);\n\t\t\tl >>= 1;\n\t\t\tr >>= 1;\n\t\t}\n\t\tres.second *= -1;\n\t\treturn res;\n\t}\n};\n\nint modpow(int a, int b, int m) {\n\tint res = 1;\n\twhile (b >= 1) {\n\t\tif (b % 2 == 1) {\n\t\t\tres = 1LL * res * a % m;\n\t\t}\n\t\ta = 1LL * a * a % m;\n\t\tb >>= 1;\n\t}\n\treturn res;\n}\n\nint parse(int l, int r, int p, const vector<string>& s, const segtree& seg) {\n\tif (r - l == 1) {\n\t\treturn stoi(s[l]);\n\t}\n\tint mid = seg.rangemin(l, r).second;\n\tint lres = parse(l, mid, p, s, seg);\n\tint rres = parse(mid + 1, r, p, s, seg);\n\tif (lres == -1 || rres == -1) {\n\t\treturn -1;\n\t}\n\tif (s[mid] == \"+\") {\n\t\treturn (lres + rres) % p;\n\t}\n\tif (s[mid] == \"-\") {\n\t\treturn (lres - rres + p) % p;\n\t}\n\tif (s[mid] == \"*\") {\n\t\treturn (1LL * lres * rres) % p;\n\t}\n\tif (s[mid] == \"/\") {\n\t\tif (rres == 0) {\n\t\t\treturn -1;\n\t\t}\n\t\tint modinv = modpow(rres, p - 2, p);\n\t\treturn (1LL * lres * modinv) % p;\n\t}\n\treturn -1;\n}\n\nvector<string> split_to_tokens(const string& str) {\n\tstring s;\n\tfor (int i = 0; i < int(str.size()); i++) {\n\t\tif (str[i] != ' ') {\n\t\t\ts += str[i];\n\t\t}\n\t}\n\tstring numval;\n\tvector<string> res;\n\tfor (int i = 0; i < int(s.size()); i++) {\n\t\tif ('0' <= s[i] && s[i] <= '9') {\n\t\t\tnumval += s[i];\n\t\t}\n\t\telse {\n\t\t\tif (numval != \"\") {\n\t\t\t\tres.push_back(numval);\n\t\t\t}\n\t\t\tnumval = \"\";\n\t\t\tres.push_back(string(1, s[i]));\n\t\t}\n\t}\n\tif (numval != \"\") {\n\t\tres.push_back(numval);\n\t}\n\treturn res;\n}\n\nint main() {\n\twhile (true) {\n\t\tstring str;\n\t\tgetline(cin, str);\n\t\tif (str == \"0:\") {\n\t\t\tbreak;\n\t\t}\n\t\tvector<string> tokens = split_to_tokens(str);\n\t\tint p = stoi(tokens[0]);\n\t\ttokens = vector<string>(tokens.begin() + 2, tokens.end());\n\t\tvector<string> s;\n\t\tvector<int> depth;\n\t\tint cur_depth = 0;\n\t\tfor (int i = 0; i < int(tokens.size()); i++) {\n\t\t\tif (tokens[i] == \"(\") {\n\t\t\t\tcur_depth += 2;\n\t\t\t}\n\t\t\telse if (tokens[i] == \")\") {\n\t\t\t\tcur_depth -= 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\ts.push_back(tokens[i]);\n\t\t\t\tdepth.push_back('0' <= tokens[i][0] && tokens[i][0] <= '9' ? INF / 2 : cur_depth + (tokens[i] == \"+\" || tokens[i] == \"-\" ? 0 : 1));\n\t\t\t}\n\t\t}\n\t\tint M = s.size();\n\t\tsegtree seg(M);\n\t\tfor (int i = 0; i < M; i++) {\n\t\t\tseg.update(i, depth[i]);\n\t\t}\n\t\tint answer = parse(0, M, p, s, seg);\n\t\tif (answer == -1) {\n\t\t\tcout << \"NG\" << endl;\n\t\t}\n\t\telse {\n\t\t\tstring outstr = \"\";\n\t\t\tfor (int i = 0; i < int(tokens.size()); i++) {\n\t\t\t\toutstr += tokens[i];\n\t\t\t}\n\t\t\toutstr += \" = \" + to_string(answer) + \" (mod \" + to_string(p) + \")\";\n\t\t\tcout << outstr << endl;\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5456, "score_of_the_acc": -1.625, "final_rank": 19 }, { "submission_id": "aoj_0264_6763171", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nbool is_digit(char c) {\n return '0' <= c and c <= '9';\n}\n\npair<int, int> read_int(const string &s, int i) {\n int j = i;\n while (is_digit(s[j])) ++j;\n return { stoi(s.substr(i, j - i)), j };\n}\n\nint prime;\n\nint inv_mod(int x) {\n int res = 1;\n int pow_x = x;\n for (int v = prime - 2; v; v >>= 1) {\n if (v & 1) res = (long long) res * pow_x % prime;\n pow_x = (long long) pow_x * pow_x % prime;\n }\n return res;\n}\nint add(int x, int y) {\n return (x + y) % prime;\n}\nint sub(int x, int y) {\n return (x - y + prime) % prime;\n}\nint mul(int x, int y) {\n return (long long) x * y % prime;\n}\n\nvoid solve() {\n string s_;\n getline(cin, s_);\n \n if (s_[0] == '0') exit(0);\n\n string s;\n for (char c : s_) if (c != ' ') s += c;\n\n auto [p, exp_begin] = read_int(s, 0);\n prime = p;\n assert(s[exp_begin] == ':');\n s = s.substr(exp_begin + 1);\n\n const int n = s.size();\n\n vector<int> rp(n, -1);\n vector<int> st;\n for (int i = 0; i < n; ++i) {\n if (s[i] == '(') {\n st.push_back(i);\n } else if (s[i] == ')') {\n int l = st.back();\n rp[l] = i;\n st.pop_back();\n }\n }\n\n auto scan = [&](auto scan, int l, int r) -> optional<int> {\n vector<int> terms;\n char op = '\\0';\n for (int i = l; i < r; ++i) {\n int val;\n if (s[i] == '(') {\n int j = rp[i];\n auto opt_val = scan(scan, i + 1, j);\n if (not opt_val.has_value()) return nullopt;\n val = *opt_val;\n i = j + 1;\n } else {\n assert(is_digit(s[i]));\n auto [v, j] = read_int(s, i);\n val = v;\n i = j;\n }\n if (op == '*') {\n terms.back() = mul(terms.back(), val);\n } else if (op == '/') {\n if (val == 0) return nullopt;\n terms.back() = mul(terms.back(), inv_mod(val));\n } else {\n if (op == '-') {\n terms.push_back(prime - val);\n } else {\n terms.push_back(val);\n }\n }\n op = s[i];\n }\n int res = 0;\n for (int v : terms) res = add(res, v);\n return res;\n };\n\n auto ans = scan(scan, 0, n);\n if (ans.has_value()) {\n cout << s << \" = \" << *ans << \" (mod \" << p << \")\" << endl;\n } else {\n cout << \"NG\" << endl;\n }\n}\n\nint main() {\n while (true) solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3508, "score_of_the_acc": -0.3788, "final_rank": 10 }, { "submission_id": "aoj_0264_6624849", "code_snippet": "#define _USE_MATH_DEFINES\n#include<bits/stdc++.h>\n\nusing namespace std;\n#define LP(I,S,G) for (long long int I = (S); I < (G); I++)\n#define IN(X) \tfor (int in = 0; in < X.size(); in++)cin >> X[in]\n#define OUT(X) \tfor (int in = 0; in < X.size(); in++)cout << X[in]<<\" \"\n#define SORT(X) sort((X).begin(), (X).end())\n#define CSORT(X,Y) sort(X.begin(), X.end(),Y)\n#define COPY(X,Y) copy(X.begin(), X.end(), Y.begin())\n#define ALL(X,Y) for (auto X = (Y).begin(); X != (Y).end(); X++)\n#define FULL(a) (a).begin(),(a).end()\n#define BFS(Q,S) for(Q.push(S);Q.size()!=0;Q.pop())\ntypedef long long int ll;\ntypedef unsigned long long int ull;\nlong long int M = pow(10, 9) + 7;\n\n\nint dx[] = { 0,-1,0,1 }, dy[] = { -1,0,1,0 };\n\nll MAX(ll A, ll B) { return ((A) > (B) ? (A) : (B)); }\nll MIN(ll A, ll B) { return ((A) < (B) ? (A) : (B)); }\nlong long int xor128() {\n\tstatic long long int x = 123456789, y = 362436069, z = 521288629, w = 88675123;\n\tlong long int t = (x ^ (x << 11));\n\tx = y; y = z; z = w;\n\treturn (w = (w ^ (w >> 19)) ^ (t ^ (t >> 8)));\n}\n\nstruct HashPair {\n\t//注意 constがいる\n\ttemplate<class T1, class T2>\n\tsize_t operator()(const pair<T1, T2> &p) const {\n\t\t//first分をハッシュ化する\n\t\tauto hash1 = hash<T1>{}(p.first);\n\t\t//second分をハッシュ化する\n\t\tauto hash2 = hash<T2>{}(p.second);\n\t\t//重複しないようにハッシュ処理\n\t\tsize_t seed = 0;\n\t\tseed ^= hash1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\tseed ^= hash2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\treturn seed;\n\t}\n};\ntemplate<class I1, class I2>\nistream& operator>>(istream& s, pair<I1, I2>& in) {\n\ts >> in.first >> in.second;\n\treturn s;\n}\n\nclass runtime_modint {\n\tusing u64 = std::uint_fast64_t;\n\n\tstatic u64 &mod() {\n\t\tstatic u64 mod_ = 0;\n\t\treturn mod_;\n\t}\n\npublic:\n\tu64 a;\n\truntime_modint(const u64 x = 0) : a(x % get_mod()) {}\n\tu64 &value() noexcept { return a; }\n\tconst u64 &value() const noexcept { return a; }\n\truntime_modint operator+(const runtime_modint rhs) const {\n\t\treturn runtime_modint(*this) += rhs;\n\t}\n\truntime_modint operator-(const runtime_modint rhs) const {\n\t\treturn runtime_modint(*this) -= rhs;\n\t}\n\truntime_modint operator*(const runtime_modint rhs) const {\n\t\treturn runtime_modint(*this) *= rhs;\n\t}\n\truntime_modint operator/(const runtime_modint rhs) const {\n\t\treturn runtime_modint(*this) /= rhs;\n\t}\n\truntime_modint &operator+=(const runtime_modint rhs) {\n\t\ta += rhs.a;\n\t\tif (a >= get_mod()) {\n\t\t\ta -= get_mod();\n\t\t}\n\t\treturn *this;\n\t}\n\truntime_modint &operator-=(const runtime_modint rhs) {\n\t\tif (a < rhs.a) {\n\t\t\ta += get_mod();\n\t\t}\n\t\ta -= rhs.a;\n\t\treturn *this;\n\t}\n\truntime_modint &operator*=(const runtime_modint rhs) {\n\t\ta = a * rhs.a % get_mod();\n\t\treturn *this;\n\t}\n\truntime_modint &operator/=(runtime_modint rhs) {\n\t\tu64 exp = get_mod() - 2;\n\t\twhile (exp) {\n\t\t\tif (exp % 2) {\n\t\t\t\t*this *= rhs;\n\t\t\t}\n\t\t\trhs *= rhs;\n\t\t\texp /= 2;\n\t\t}\n\t\treturn *this;\n\t}\n\n\tstatic void set_mod(const u64 x) { mod() = x; }\n\tstatic u64 get_mod() { return mod(); }\n};\n\ntemplate<class group = long long int>\nclass calculator {\n\tgroup cal_add_sub(string& s, ll& now) {\n\t\tif (fail)return 0;\n\t\tgroup ret = cal_mult_div(s, now);\n\t\twhile (1) {\n\t\t\tif (s[now] == '+') {\n\t\t\t\tnow++;\n\t\t\t\tret += cal_mult_div(s, now);\n\t\t\t}\n\t\t\telse if (s[now] == '-') {\n\t\t\t\tnow++;\n\t\t\t\tret -= cal_mult_div(s, now);\n\t\t\t}\n\t\t\telse return ret;\n\t\t}\n\t}\n\tgroup cal_mult_div(string& s, ll& now) {\n\t\tif (fail)return 0;\n\t\tgroup ret = cal_child(s, now);\n\t\twhile (1) {\n\t\t\tif (s[now] == '*') {\n\t\t\t\tnow++;\n\t\t\t\tret *= cal_child(s, now);\n\t\t\t}\n\t\t\telse if (s[now] == '/') {\n\t\t\t\tnow++;\n\t\t\t\tgroup x = cal_child(s, now);\n\t\t\t\tif (x.a == 0) {\n\t\t\t\t\tfail = 1;\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t\tret /= x;\n\t\t\t}\n\t\t\telse return ret;\n\t\t}\n\t}\n\n\tgroup cal_child(string& s, ll& now) {\n\t\tif (fail)return 0;\n\t\tif (s[now] == '(') {\n\t\t\tnow++;\n\t\t\tgroup ret = cal_add_sub(s, now);\n\t\t\tnow++;\n\t\t\treturn ret;\n\t\t}\n\t\treturn get_group(s, now);\n\t}\n\t//ここが群によって変わる\n\tgroup get_group(string& s, ll& now) {\n\t\tgroup ret = 0;\n\t\twhile (s[now] - '0' >= 0 && s[now] - '0' <= 9) {\n\t\t\tret *= 10;\n\t\t\tret += s[now] - '0';\n\t\t\tnow++;\n\t\t\tif (now == s.size())return ret;\n\t\t}\n\t\treturn ret;\n\t}\npublic:\n\tbool fail = 0;\n\tgroup solve(string& s) {\n\t\tll now = 0;\n\t\tfail = 0;\n\t\treturn cal_add_sub(s, now);\n\t}\n};\n\nint main() {\n\tcalculator<runtime_modint> c;\n\twhile (1) {\n\t\tstring s;\n\t\tgetline(cin, s);\n\t\tif (s[0] == '0')break;\n\t\tbool f = 0;\n\t\tll p = 0;\n\t\tstring math;\n\t\tLP(i,0,s.size()){\n\t\t\tif (s[i] == ':') f = 1;\n\t\t\telse if (!f) {\n\t\t\t\tp *= 10;\n\t\t\t\tp += s[i] - '0';\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (s[i] != ' ')math.push_back(s[i]);\n\t\t\t}\n\t\t}\n\t\truntime_modint::set_mod(p);\n\t\tll ans = c.solve(math).a;\n\t\tif (!c.fail)cout << math << \" = \" << ans << \" (mod \" << p << \")\\n\";\n\t\telse cout << \"NG\\n\";\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3464, "score_of_the_acc": -0.4841, "final_rank": 14 }, { "submission_id": "aoj_0264_6025005", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <bitset>\n#include <climits>\n#include <string>\n#include <cmath>\n#include <bitset>\n#include <complex>\n#include <functional>\n#include <ctime>\n#include <cassert>\n#include <fstream>\n#include <stack>\n#include <random>\n#include <iomanip>\n#include <time.h>\n#include <list>\n#include <unordered_map>\n\n#include <algorithm>\n#include <array>\n\nusing namespace std;\ntypedef long long ll;\ntypedef long double dd;\ntypedef unsigned long long ull;\ntypedef vector<ll> vl;\ntypedef vector<dd> vd;\ntypedef vector<vector<ll>> vvl;\ntypedef vector<vector<dd>> vvd;\n//#define i_7 (ll)(1E9+7)\n#define i_7 998244353\n#define i_5 i_7-2\nll mod(ll a){\n ll c=a%i_7;\n if(c>=0)return c;\n return c+i_7;\n}\ntypedef pair<ll,ll> l_l;\ntypedef pair<dd,dd> d_d;\nll inf=(ll)1E18;\n#define rep(i,l,r) for(ll i=l;i<=r;i++)\n#define pb push_back\nll max(ll a,ll b){if(a<b)return b;else return a;}\nll min(ll a,ll b){if(a>b)return b;else return a;}\ndd EPS=1E-9;\ndd PI=acos(-1);\n#define endl \"\\n\"\n#define fastio ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\n\n\nll hpow(ll x,ll y,ll p){\n if(y==0)return 1;\n ll res=hpow(x,y/2,p);\n res = (res*res)%p;\n if(y%2==1){\n res = (res*x)%p;\n }\n return res%p;\n}\n\n\nbool is_op(char c){\n vector<char> ops = {'+', '-', '*', '/'};\n rep(i,0,(ll)ops.size()-1){\n if(c == ops[i]){\n return true;\n }\n }\n return false;\n}\nstring sNumber(string &s, ll &cur){\n string res;\n while(isdigit(s[cur])){\n res += s[cur];\n cur++;\n }\n return res;\n}\nll Number(string &s, ll &cur){\n ll res=0;\n while(isdigit(s[cur])){\n res *= 10;\n res += s[cur] - '0';\n cur++;\n }\n return res;\n}\n\nll exp(string &s, ll &cur, const ll p);\nll exp2(string &s, ll &cur, const ll p);\nll exp3(string &s, ll &cur, const ll p);\nstring Ans(string &s, ll &cur, const ll p);\n\nbool valid;\n\nll exp(string &s, ll &cur, const ll p){\n ll res = exp2(s, cur, p);\n while(cur < s.size() && (s[cur] == '+' || s[cur] == '-')){\n char op = s[cur];\n cur++;\n ll tmp = exp2(s, cur, p);\n if(op == '+'){\n res = ((res + tmp) % p + p)%p;\n }else{\n res = ((res - tmp) % p + p)%p;\n }\n }\n return (res+p)%p;\n}\nll exp2(string &s, ll &cur, const ll p){\n ll res = exp3(s, cur, p);\n while(cur < s.size() && (s[cur] == '*' || s[cur] == '/')){\n char op = s[cur];\n cur++;\n ll tmp = exp3(s, cur, p);\n if(op == '*'){\n res = ((res * tmp) % p + p)%p;\n }else{\n if(tmp == 0){\n valid = false;\n }\n res = ((res * hpow(tmp, p-2, p)) % p + p)%p;\n }\n }\n return (res+p)%p;\n}\nll exp3(string &s, ll &cur, const ll p){\n if(s[cur] == '('){\n cur++;\n ll res = exp(s, cur, p);\n assert(s[cur] == ')');\n cur++;\n return (res+p)%p;\n }else{\n return Number(s, cur)%p;\n }\n}\n\nll str_to_ll(string s){\n ll res =0 ;\n rep(i,0,(ll)s.size()-1){\n res *= 10;\n res += s[i] -'0';\n }\n return res;\n}\n\n\nsigned main(){fastio\n while(true){\n string s;\n getline(cin, s);\n if(s[0]=='0'){\n break;\n }\n ll cur=0;\n string ps;\n string t;\n bool hoge=true;\n rep(i,0,(ll)s.size()-1){\n if(s[i] == ' ')continue;\n if(s[i] == ':'){\n hoge=false;\n continue;\n }\n if(hoge){\n ps += s[i];\n }else{\n t += s[i];\n }\n }\n ll p = str_to_ll(ps);\n valid = true;\n ll res = exp(t, cur, p);\n if(valid){\n cout<<t<<\" = \"<<res<<\" (mod \"<<p<<\")\"<<endl;\n }else{\n cout<<\"NG\"<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3780, "score_of_the_acc": -0.5004, "final_rank": 16 }, { "submission_id": "aoj_0264_6019273", "code_snippet": "/*\n   ∫ ∫ ∫\n   ノヽ\n  (_  )\n (_    )\n(______ )\n ヽ(´・ω・)ノ \n   |  /\n   UU\n*/\n#pragma region macro\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cctype>\n#include <vector>\n#include <cassert>\n#include <cmath>\n#include <utility>\n#include <tuple>\n#include <map>\n#include <set>\n#include <deque>\n#include <queue>\ntypedef long long int64;\nusing namespace std;\ntypedef vector<int> vi;\nconst int64 INF = 1LL << 62;\nconst int inf = 1<<30;\nconst char bn = '\\n';\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n#define REP(i, n) for (int i = 0; i < (n); i++)\n#define ALL(obj) (obj).begin(), (obj).end() //コンテナじゃないと使えない!!\n#define debug(x) cerr << #x << \": \" << (x) << \"\\n\";\n#define mp make_pair\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T> &V){\n int N = V.size();\n REP(i,N){\n os << V[i];\n if (i!=N-1) os << \" \";\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T,typename S>\nostream& operator<<(ostream& os, pair<T,S> const&P){\n os << \"(\";\n os << P.first;\n os << \" , \";\n os << P.second;\n os << \")\";\n return os;\n}\ntemplate <typename T,typename S,typename U>\nostream& operator<<(ostream& os, tuple<T,S,U> const& P){\n os << \"(\";\n os << get<0>(P);\n os << \", \";\n os << get<1>(P);\n os << \", \";\n os << get<2>(P);\n os << \")\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, set<T> &S){\n auto it=S.begin();\n while(it!=S.end()){\n os << *it;\n os << \" \";\n it++;\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, deque<T> &q){\n for(auto it=q.begin();it<q.end();it++){\n os<<*it;\n os<<\" \";\n }\n os<<endl;\n return os;\n}\ntemplate <typename T,typename S>\nostream& operator<<(ostream& os, map<T,S> const&M){\n for(auto e:M){\n os<<e;\n }\n os<<endl;\n return os;\n}\nvector<pair<int,int>> dxdy = {mp(0,1),mp(1,0),mp(-1,0),mp(0,-1)};\n#pragma endregion\n//fixed<<setprecision(10)<<ans<<endl;\n\n\nint64 pow(int a,int b,int mod){\n vector<bool> bit;\n for(b=b;b>0;b>>=1){\n bit.push_back(b&1);\n }\n vector<int64> fac(bit.size()); fac[0] = a;\n int64 res = 1;\n for(int i=1;i<bit.size();i++){\n fac[i] = (fac[i-1] * fac[i-1])%mod;\n }\n for(int i=0;i<bit.size();i++){\n if(bit[i]) res*=fac[i];\n res%=mod;\n }\n return res;\n}\n\n\nint MOD;\n//mint\nstruct mint {\n int64 x;\n mint(int64 x=0):x((x+2*MOD)%MOD){}\n mint& operator+=(const mint a) {\n if ((x += a.x) >= MOD) x -= MOD;\n return *this;\n }\n mint& operator-=(const mint a) {\n if ((x += MOD-a.x) >= MOD) x -= MOD;\n return *this;\n }\n mint& operator*=(const mint a) {\n (x *= a.x) %= MOD;\n return *this;\n }\n mint operator+(const mint a) const {\n mint res(*this);\n return res+=a;\n }\n mint operator-(const mint a) const {\n mint res(*this);\n return res-=a;\n }\n mint operator*(const mint a) const {\n mint res(*this);\n return res*=a;\n }\n mint pow(int64 t) const {\n if (!t) return 1;\n mint a = pow(t>>1);\n a *= a;\n if (t&1) a *= *this;\n return a;\n }\n\n // for prime MOD\n mint inv() const {\n return pow(MOD-2);\n }\n mint& operator/=(const mint a) {\n return (*this) *= a.inv();\n }\n mint operator/(const mint a) const {\n mint res(*this);\n return res/=a;\n }\n};\nostream& operator<<(ostream& os, mint a){\n os << a.x;\n return os;\n}\n\n// 構文解析\n/*\n 構文解析でよくあるバグは次の二つです。\n - begin++をし忘れる\n - getlineとcinの混合\n*/\n\n\ntypedef string::const_iterator State;\nclass ParseError {};\n\n// beginがexpectedを指していたらbeginを一つ進める。\nvoid consume(State &begin, char expected) {\n if (*begin == expected) {\n begin++;\n } else {\n cerr << \"Expected '\" << expected << \"' but got '\" << *begin << \"'\"\n << endl;\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n throw ParseError();\n }\n}\nvoid print_rest_string(State begin){\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n}\nmint expression(State &begin);\nmint term(State &begin);\nmint factor(State &begin);\nmint number(State &begin);\n\nbool NG = false;\n// 四則演算の式をパースして、その評価結果を返す。\nmint expression(State &begin){\n mint res = term(begin);\n\n while(true){\n if(*begin == '+'){\n consume(begin, '+');\n res += term(begin);\n }else if(*begin == '-'){\n consume(begin, '-');\n res -= term(begin);\n }else{\n break;\n }\n }\n\n return res;\n}\n\n// 乗算除算の式をパースして、その評価結果を返す。\nmint term(State &begin){\n mint res = factor(begin);\n \n while(true){\n if(*begin == '*'){\n consume(begin, '*');\n res *= factor(begin);\n }else if(*begin == '/'){\n consume(begin, '/');\n mint val = factor(begin);\n if(val.x == 0){\n NG = true;\n }\n res /= val;\n }else{\n break;\n }\n }\n\n return res;\n}\n\nmint factor(State &begin){\n if(*begin == '('){\n consume(begin, '('); // '('を飛ばす。\n mint res = expression(begin);\n consume(begin, ')'); // ')'を飛ばす。\n return res;\n }else{\n return number(begin);\n }\n}\n\n// 数字の列をパースして、その数を返す。\nmint number(State &begin){\n mint res = 0;\n while(isdigit(*begin)){\n res *= 10;\n res += *begin - '0';\n begin++;\n }\n\n return res;\n}\n\nvoid solve(string S){\n State begin = S.begin();\n // debug(S)\n // debug(MOD)\n NG=false;\n mint ans = expression(begin);\n if(NG){\n cout << \"NG\" << endl;\n }else{\n cout << S << \" = \" << ans.x << \" (mod \" << MOD << \")\" << endl;\n }\n}\n\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n string S; ;\n while(getline(cin,S)){\n if(S[0] == '0') break;\n string T;\n bool flag = false;\n string MOD_str = \"\";\n for(auto s:S){\n if(flag){\n if(s!=' ') T += s;\n }else{\n if(s==':') flag=true;\n else MOD_str+=s;\n }\n }\n MOD=stoi(MOD_str);\n solve(T);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3528, "score_of_the_acc": -0.5127, "final_rank": 17 }, { "submission_id": "aoj_0264_5937434", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint modpow(int a, int b, int mod){\n int ans = 1;\n while (b > 0){\n if (b % 2 == 1){\n ans *= a;\n ans %= mod;\n }\n a *= a;\n a %= mod;\n b /= 2;\n }\n return ans;\n}\nint modinv(int a, int mod){\n return modpow(a, mod - 2, mod);\n}\nint expr(string &s, int mod, int &p);\nint factor(string &s, int mod, int &p){\n if (s[p] == '('){\n p++;\n int ans = expr(s, mod, p);\n p++;\n return ans;\n } else {\n int ans = 0;\n while (isdigit(s[p]) != 0){\n ans = ans * 10 + (s[p] - '0');\n ans %= mod;\n p++;\n }\n return ans;\n }\n}\nint term(string &s, int mod, int &p){\n int ans = factor(s, mod, p);\n if (ans == -1){\n return -1;\n }\n while (true){\n char c = s[p];\n if (c != '*' && c != '/'){\n break;\n }\n p++;\n int ans2 = factor(s, mod, p);\n if (ans2 == -1){\n return -1;\n }\n if (c == '*'){\n ans *= ans2;\n ans %= mod;\n }\n if (c == '/'){\n if (ans2 == 0){\n return -1;\n }\n ans *= modinv(ans2, mod);\n ans %= mod;\n }\n }\n return ans;\n}\nint expr(string &s, int mod, int &p){\n int ans = term(s, mod, p);\n if (ans == -1){\n return -1;\n }\n while (true){\n char c = s[p];\n if (c != '+' && c != '-'){\n break;\n }\n p++;\n int ans2 = term(s, mod, p);\n if (ans2 == -1){\n return -1;\n }\n if (c == '+'){\n ans += ans2;\n ans %= mod;\n }\n if (c == '-'){\n ans += mod - ans2;\n ans %= mod;\n }\n }\n return ans;\n}\nint main(){\n while (true){\n int p;\n char c;\n string s;\n cin >> p >> c;\n getline(cin, s);\n if (p == 0 && s == \"\"){\n break;\n }\n int N = s.size();\n string t;\n for (int i = 0; i < N; i++){\n if (s[i] != ' '){\n t += s[i];\n }\n }\n t += '=';\n int x = 0;\n int ans = expr(t, p, x);\n t.pop_back();\n if (ans == -1){\n cout << \"NG\" << endl;\n } else {\n cout << t << \" = \" << ans << \" (mod \" << p << \")\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3480, "score_of_the_acc": -0.2413, "final_rank": 3 }, { "submission_id": "aoj_0264_5857393", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\nusing namespace std;\nusing ll = long long int;\nclass ParseError{};\n\nstruct Solver{\n const ll p;\n const string s;\n ll expr(int &);\n ll term(int &);\n ll factor(int &);\n ll number(int &);\n Solver(ll p, const string &expression): p(p), s(expression){\n\n };\n\n ll modpow(ll a, ll x){\n ll ans = 1;\n while(x > 0){\n if(x & 1){\n ans *= a;\n ans %= p;\n }\n a *= a;\n a %= p;\n x >>= 1;\n }\n return ans;\n }\n\n \n\n void solve(){\n try{\n int i = 0;\n ll ans = expr(i);\n cout << s << \" = \" << ans << \" (mod \" << p << \")\" << '\\n';\n }catch(ParseError e){\n cout << \"NG\" << '\\n';\n }\n }\n};\nll Solver::expr(int &i){\n ll ans = term(i);\n while(s[i] == '+' || s[i] == '-'){\n char op = s[i++];\n ll v2 = term(i);\n if(op == '+') ans += v2;\n else ans -= v2;\n while(ans < 0) ans += p;\n ans %= p;\n }\n return ans;\n}\n\nll Solver::term(int &i){\n ll ans = factor(i);\n while(s[i] == '*' || s[i] == '/'){\n char op = s[i++];\n ll v2 = factor(i);\n v2 %= p;\n if(op == '*') ans *= v2;\n else{\n if(v2 == 0) throw ParseError();\n else{\n ans *= modpow(v2, p-2);\n }\n }\n ans %= p;\n }\n return ans;\n}\n\nll Solver::factor(int &i){\n if(isdigit(s[i])) return number(i);\n else{\n ++i;\n ll ans = expr(i);\n ++i;\n return ans;\n }\n}\n\nll Solver::number(int &i){\n ll ans = 0;\n while(isdigit(s[i])) ans = ans*10 + s[i++]-'0';\n return ans%p;\n}\n\nint main(){\n while(true){\n string line;\n getline(cin, line);\n if(line == \"0:\") break;\n\n ll p = 0;\n string expression = \"\";\n int i = 0;\n for(; i < line.length(); i++){\n if(line[i] != ':'){\n p *= 10;\n p += line[i]-'0';\n }else break;\n }\n i++;\n for(; i < line.length(); i++){\n if(line[i] != ' ') expression += line[i];\n }\n\n Solver sol(p, expression);\n sol.solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3528, "score_of_the_acc": -0.3877, "final_rank": 11 }, { "submission_id": "aoj_0264_5759143", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<sstream>\n#include<regex>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nconst double eps=1e-10;\nint p;\nint myplus(int n,int m){\n\tif(n==-1||m==-1)\n\t\treturn -1;\n\treturn(n+m)%p;\n}\nint myminus(int n,int m){\n\tif(n==-1||m==-1)\n\t\treturn -1;\n\treturn(n-m+p)%p;\n}\nint myprod(int n,int m){\n\tif(n==-1||m==-1)\n\t\treturn -1;\n\treturn n*m%p;\n}\nint mydiv(int n,int m){\n\tif(n==-1||m==-1||m==0)\n\t\treturn -1;\n\tint inv=1,ex=p-2;\n\twhile(ex){\n\t\tif(ex&1)\n\t\t\tinv=myprod(inv,m);\n\t\tm=myprod(m,m);\n\t\tex>>=1;\n\t}\n\treturn myprod(n,inv);\n}\ntypedef string::const_iterator state;\nint expr(state&it);\nint number(state&it){\n\tint ret;\n\tfor(ret=0;'0'<=*it&&*it<='9';it++)\n\t\tret=ret*10+*it-'0';\n\treturn ret;\n}\nint factor(state&it){\n\tif('0'<=*it&&*it<='9')\n\t\treturn number(it);\n\tint ret=expr(++it);\n\tit++;\n\treturn ret;\n}\nint term(state&it){\n\tint ret=factor(it);\n\twhile(1){\n\t\tif(*it=='*')\n\t\t\tret=myprod(ret,factor(++it));\n\t\telse if(*it=='/')\n\t\t\tret=mydiv(ret,factor(++it));\n\t\telse\n\t\t\treturn ret;\n\t}\n}\nint expr(state&it){\n\tint ret=term(it);\n\twhile(1){\n\t\tif(*it=='+')\n\t\t\tret=myplus(ret,term(++it));\n\t\telse if(*it=='-')\n\t\t\tret=myminus(ret,term(++it));\n\t\telse\n\t\t\treturn ret;\n\t}\n}\nsigned main(){\n\twhile(cin>>p,p){\n\t\tcin.ignore();\n\t\tstring s;\n\t\tgetline(cin,s);\n\t\ts.erase(remove(s.begin(),s.end(),' '),s.end());\n\t\ts+='a';\n\t\tstate it=s.begin();\n\t\tint ans=expr(it);\n\t\ts.pop_back();\n\t\tif(ans==-1)\n\t\t\tcout<<\"NG\"<<endl;\n\t\telse\n\t\t\tcout<<s<<\" = \"<<ans<<\" (mod \"<<p<<')'<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3444, "score_of_the_acc": -0.3502, "final_rank": 7 } ]
aoj_0267_cpp
ブロックの三角形 図a のように積まれたブロックに対し、以下の並べ替え操作を繰り返す。 一番下のブロック全て(図a 中の白のブロック)を右端に新しく積み上げる(残りのブロックは自動的に1段下に落ち、図b のようになる)。 ブロックの間に隙間ができたら、左に詰めて隙間をなくす(図 b から図c のようになる)。 1 以上の整数 k に対して、k×(k+1)/2 で表される数 (例:1, 3, 6, 10, ...)を三角数という。ブロックの総数が三角数の場合、上記の並べ替えを繰り返すと、左端の高さが1 で右に向かって1つずつ高くなっていくような三角形になると予想されている(図d は総数が15 個の場合)。 ブロックの最初の並びが与えられたとき、あらかじめ決められた回数以下の操作で、上で説明したようなブロックの三角形ができるとき、三角形が得られるまでの最小の操作回数を出力するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 N b 1 b 2 ... b N 各データセットは2行であり、ブロックの最初の並びを表す。N (1 ≤ N ≤ 100)は、一番下の段にあるブロックの数を示す。b i (1 ≤ bi ≤ 10000) は左から i 番目の位置に積まれているブロックの数を示す。b i と b i+1 は1つの空白で区切られている。ブロックの総数は 3 以上である。 データセットの数は 20 を超えない。 出力 データセットごとに、三角形ができるまでに行った並べ替え操作の回数を1行に出力する。ただし、三角形が作れない場合や、操作回数が 10000 回を超える場合は -1 を出力する。 入力例 6 1 4 1 3 2 4 5 1 2 3 4 5 10 1 1 1 1 1 1 1 1 1 1 9 1 1 1 1 1 1 1 1 1 12 1 4 1 3 2 4 3 3 2 1 2 2 1 5050 3 10000 10000 100 0 出力例 24 0 10 -1 48 5049 -1 最初のデータセットが、図に示した場合に対応する。 4つ目のデータセットが、ブロックの総数が三角数でないため、三角形が作れない場合に対応する。 最後のデータセットが、ブロックの総数は三角数だが、操作回数が 10000 回を超える場合に対応する。
[ { "submission_id": "aoj_0267_9568704", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX_CNT = 10000;\nconst int MAX_SET = 20;\n\nint main()\n{\n int N;\n int setcount = 0;\n\n\n while (cin >> N && N != 0 && setcount < MAX_SET)\n {\n if (N < 1 || 1000 < N)\n {\n cout << \"N(1 <= N <= 100) \" << endl << flush;\n exit(1);\n }\n vector<int> b;\n for (int i = 0; i < N; i++)\n {\n int v;\n cin >> v;\n if (v < 1 || 10000 < v)\n {\n cout << \"b\" << i << \"(1 <= bi <= 10000) but input\" << v << endl << flush;\n exit(1);\n }\n b.push_back(v);\n }\n int cnt = 0;\n while (cnt <= MAX_CNT)\n {\n bool isTriangle = true;\n if (b[0] != 1)\n {\n isTriangle = false;\n }\n else\n {\n for (int i = 1; i < b.size(); i++)\n {\n if (b[i] != b[i - 1] + 1)\n {\n isTriangle = false;\n break;\n }\n }\n }\n if (isTriangle) break;\n vector<int> work;\n for (int num:b)\n {\n if (num >1)\n {\n work.push_back(num - 1);\n }\n }\n work.push_back(b.size());\n b = work;\n\n cnt++;\n }\n if (cnt > MAX_CNT)\n {\n cout << -1 << endl << flush;\n }\n else\n {\n cout << cnt << endl << flush;\n }\n setcount++;\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3456, "score_of_the_acc": -0.2858, "final_rank": 11 }, { "submission_id": "aoj_0267_9189901", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n if (N == 0) return 1;\n vi b(N);\n rep(i, N) cin >> b[i];\n ll sum = SUM(b);\n ll x = ll(sqrt(sum*2) + 1e-9);\n if (x*(x+1) != sum*2) {\n print(-1);\n return 0;\n }\n vi t(b);\n rep(num, 10001) {\n ll h = 1;\n ll cnt = 0;\n rep(i, len(t)) {\n if (t[i] != h) break;\n h++;\n cnt += t[i];\n }\n if (cnt == sum) {\n print(num);\n return 0;\n }\n t.eb(0);\n rep(i, len(t)-1) {\n if (t[i] >= 1) {\n t[i]--;\n t.back()++;\n }\n }\n vi next;\n rep(i, len(t)) {\n if (t[i] >= 1) next.eb(t[i]);\n }\n swap(t, next);\n }\n print(-1);\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3412, "score_of_the_acc": -0.3893, "final_rank": 15 }, { "submission_id": "aoj_0267_9156540", "code_snippet": "#pragma region Macros\n\n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2\")\n\n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n\n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n// #define unordered_map<int, int> gp_hash_table<int, int, custom_hash> \n\n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n\n#define next asdnext\n#define prev asdprev\n\nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n\nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n\nstruct Edge {\n int from, to;\n double cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, double cost) : to(to), cost(cost) {}\n Edge(int from, int to, double cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n};\n\nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n\nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n\nusing i64 = ll;\n// using i64 = uint64_t;\n// bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\ni64 lrmask(i64 l, i64 r) { return (1LL << r) - (1LL << l); }\ni64 sub_bit(i64 x, i64 l, i64 r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\ni64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n\ni64 popcount(i64 x) { return __builtin_popcountll(x); }\ni64 popcount(i64 x, i64 l, i64 r) { return __builtin_popcountll(sub_bit(x, l, r)); }\ni64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); }\ni64 unpopcount(i64 x, i64 l, i64 r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); }\nbool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; }\n\ni64 top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\ni64 bot_bit(i64 x) { return __builtin_ctz(x);} // 2^kの位 (x > 0)\n// i64 next_bit(i64 x, i64 k) { return 0; }\n// i64 prev_bit(i64 x, i64 k) { return 0; }\n// i64 kth_bit(i64 x, i64 k) { return 0; }\ni64 MSB(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\ni64 LSB(i64 x) { return (x & -x); } // mask\n\ni64 countl_zero(i64 x) { return __builtin_clzll(x); }\ni64 countl_one(i64 x) {\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\ni64 countr_zero(i64 x) { return __builtin_ctzll(x); } // x==0のとき64が返ることに注意\ni64 countr_one(i64 x) { i64 ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n\ni64 floor_log2(i64 x) { if (x == 0) return 0; return 63 - __builtin_clzll(x); }\ni64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // MSBと同じ\ni64 ceil_log2(i64 x) { if (x == 0) return 0; return 64 - __builtin_clzll(x - 1); }\ni64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n\ni64 rotl(i64 x, i64 k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\ni64 rotr(i64 x, i64 k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\ni64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n}\n// i64 bit_reverse(i64 x, i64 l, i64 r) { return 0; }\n\nbool is_palindrome(i64 x) { return x == bit_reverse(x); }\nbool is_palindrome(i64 x, i64 l, i64 r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\ni64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\ni64 erase(i64 x, i64 l, i64 r) { return x>>r<<l | x&(1LL<<l - 1); } // [l, r) をカット\n\ni64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\ni64 hamming(i64 a, i64 b, i64 l, i64 r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\ni64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\ni64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\ni64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n\ni64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctz(x) + 1));\n}\n\n\n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\nint round(int x, int y) {\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n}\nint round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0); // TODO\n return INF;\n}\nint round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = z / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n}\n// int round(ld x, int k) { // xを10^kの位に関して四捨五入\n// }\n// int floor(ld x, int k) { // xを10^kの位に関してflooring\n// }\n// int ceil(ld x, int k) { // xを10^kの位に関してceiling\n// }\n// int kth(int x, int y, int k) { // x / yの10^kの位の桁\n// }\nint floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n}\nint ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return ceil(x / y);\n // ceil(x) = floor(x + 1)\n}\nint perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -floor(x / fabs(y));\n if (x < 0 && y < 0) return floor(x / y) + (x - floor(x/y)*y < -EPS);\n return floor(x / y) - (x - floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n}\nld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n}\nint seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\nint modf(ld x) {\n\tif (x < 0) return ceill(x);\n\telse return floorl(x);\n}\n// 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\nint seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n}\nint seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n}\n\ntemplate <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\ntemplate <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n\ntemplate <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n}\ntemplate <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n}\ntemplate <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - max({a, b, c}) - min({a, b, c});\n}\ntemplate <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) { // TODO テンプレート引数\n if (a > b) swap(a, b);\n } else {\n if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (b > c) swap(b, c);\n } else {\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, T &d, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (a > d) swap(a, d);\n if (b > c) swap(b, c); if (b > d) swap(b, d); if (c > d) swap(c, d);\n } else {\n if (d > c) swap(d, c); if (d > b) swap(d, b); if (d > a) swap(d, a);\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n\n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\nclass Compress {\npublic:\n int sz = 0;\n // gp_hash_table<int, int, custom_hash> Z, UZ;\n unordered_map<int, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, int> UZ; // 圧縮した値 -> 元の値\n\n Compress(const vector<int> &V, int base = 0) {\n this->sz = base;\n set<int> s(V.begin(), V.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, int base = 0) {\n this->sz = base;\n vector<int> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<int> s(V3.begin(), V3.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n Compress(const vector<int> &V1, const vector<int> &V2, const vector<int> &V3, int base = 0) {\n this->sz = base;\n vector<int> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<int> s(V4.begin(), V4.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n Compress(const vector<int> &V1, const vector<int> &V2,\n const vector<int> &V3, const vector<int> &V4, int base = 0) {\n this->sz = base;\n vector<int> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<int> s(V5.begin(), V5.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n vector<int> zip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[ret[i]];\n }\n return ret;\n }\n\n vector<int> unzip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[ret[i]];\n }\n return ret;\n }\n\n int size() { return sz; }\n\n int encode(int x) { return Z[x]; }\n int decode(int x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n\nclass UnionFind {\npublic:\n\tUnionFind() = default;\n UnionFind(int N) : par(N), sz(N, 1) {\n iota(par.begin(), par.end(), 0);\n }\n\tint root(int x) {\n\t\tif (par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool unite(int x, int y) {\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n if (rx == ry) return false;\n\t\tif (sz[rx] < sz[ry]) swap(rx, ry);\n\t\tsz[rx] += sz[ry];\n\t\tpar[ry] = rx;\n return true;\n\t}\n\tbool issame(int x, int y) { return (root(x) == root(y)); }\n\tint size(int x) { return sz[root(x)]; }\n vector<vector<int>> groups(int N) {\n vector<vector<int>> G(N);\n for (int x = 0; x < N; x++) {\n G[root(x)].push_back(x);\n }\n\t\tG.erase( remove_if(G.begin(), G.end(),\n [&](const vector<int>& V) { return V.empty(); }), G.end());\n return G;\n }\nprivate:\n\tvector<int> par, sz;\n};\n\ntemplate<typename T>\nstruct BIT {\n int N; // 要素数\n vector<T> bit[2]; // データの格納先\n BIT(int N_, int x = 0) {\n N = N_ + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n if (x != 0) {\n for (int i = 0; i < N; i++) add(i, x);\n }\n }\n BIT(const vector<int> &A) {\n N = A.size() + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n for (int i = 0; i < (int)A.size(); i++) add(i, A[i]);\n }\n void add_sub(int p, int i, T x) {\n while (i < N) { bit[p][i] += x; i += (i & -i); }\n }\n void add(int l, int r, T x) {\n add_sub(0, l + 1, -x * l); add_sub(0, r + 1, x * r);\n add_sub(1, l + 1, x); add_sub(1, r + 1, -x);\n }\n void add(int i, T x) { add(i, i + 1, x); }\n T sum_sub(int p, int i) {\n T ret = 0;\n while (i > 0) { ret += bit[p][i]; i -= (i & -i); }\n return ret;\n }\n T sum(int i) { return sum_sub(0, i) + sum_sub(1, i) * i; }\n T sum(int l, int r) { return sum(r) - sum(l); }\n T get(int i) { return sum(i, i + 1); }\n void set(int i, T x) { T s = get(i); add(i, -s + x); }\n};\n\ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n\n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n\nusing mint = Modint<MOD>;\n\nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n\nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0);\n // assert(x > 0);\n if (x == 1 or x == 0) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n\nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n\n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n\nstring to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n\n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n}\nstring to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n}\nstring to_string(char c) { string s = \"\"; s += c; return s; }\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n\nvector<mint> _fac, _finv, _inv;\nvoid COMinit(int N) {\n _fac.resize(N + 1); _finv.resize(N + 1); _inv.resize(N + 1);\n _fac[0] = _fac[1] = 1; _finv[0] = _finv[1] = 1; _inv[1] = 1;\n for (int i = 2; i <= N; i++) {\n _fac[i] = _fac[i-1] * mint(i);\n _inv[i] = -_inv[MOD % i] * mint(MOD / i);\n _finv[i] = _finv[i - 1] * _inv[i];\n }\n}\n\nmint FAC(int N) {\n if (N < 0) return 0; return _fac[N];\n}\nmint COM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[K] * _finv[N - K];\n}\nmint PERM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[N - K];\n}\nmint NHK(int N, int K) { // initのサイズに注意\n if (N == 0 && K == 0) return 1;\n return COM(N + K - 1, K);\n}\n\n#pragma endregion\n\nvector<string> split_str(string S, char c) {\n vector<string> ret;\n stringstream ss;\n for (int i = 0; i < S.size(); i++) {\n if (S[i] == c) {\n ret.pb(ss.str());\n ss.str(\"\");\n ss.clear();\n } else {\n ss << S[i];\n }\n }\n ret.pb(ss.str());\n return ret;\n}\n\nsigned main() {\n int N;\n while (cin >> N, N) {\n vector<int> A(N);\n for (int i = 0; i < N; i++) cin >> A[i];\n\n int ans = 0;\n while (true) {\n bool fin = true;\n for (int i = 0; i < (int)A.size(); i++) {\n if (A[i] != i + 1) {\n fin = false;\n break;\n }\n }\n if (fin) break;\n \n int cnt = 0;\n for (int i = 0; i < (int)A.size(); i++) {\n A[i]--;\n cnt++;\n }\n A.pb(cnt);\n vector<int> B;\n for (int i = 0; i < (int)A.size(); i++) {\n if (A[i]) B.pb(A[i]);\n }\n A = B;\n ans++;\n if (ans == 10001) break;\n }\n if (ans == 10001) cout << -1 << endl;\n else cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3516, "score_of_the_acc": -0.4667, "final_rank": 16 }, { "submission_id": "aoj_0267_8228684", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nbool is_tri(vector<int> b) {\n int i = 1;\n for (int bi : b) {\n if (bi != i++) return false;\n }\n return true;\n}\n\nint main() {\n const int MAX_CNT = 10000;\n\n while (true) {\n int N;\n cin >> N;\n if (N == 0) break;\n vector<int> b(N);\n for (int &bi : b) cin >> bi;\n \n int cnt = 0;\n while (!is_tri(b)) {\n if (cnt++ == MAX_CNT) {\n cnt = -1; break;\n }\n vector<int> tmp;\n for (int bi : b) {\n if (--bi > 0) tmp.push_back(bi);\n }\n tmp.push_back(b.size());\n b = tmp;\n };\n cout << cnt << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3472, "score_of_the_acc": -0.2441, "final_rank": 6 }, { "submission_id": "aoj_0267_8225863", "code_snippet": "#include <iostream>\nusing namespace std;\n\nbool is_tri(int b[], int N) {\n for (int i = 1; i <= N; ++i) {\n if (b[i] != i) return false;\n }\n return true;\n}\n\nint main() {\n const int MAX_CNT = 10000;\n\n while (true) {\n int N, b[2000000] = {};\n cin >> N; if (N == 0) break;\n for (int i = 1; i <= N; ++i) {\n cin >> b[i];\n }\n \n int cnt = 0;\n while (!is_tri(b, N)) {\n if (cnt++ == MAX_CNT) {\n cnt = -1; break;\n }\n\n int j = 1;\n for (int i = 1; i <= N; ++i) {\n if (--b[i] > 0) {\n if (j != i) {\n b[j] = b[i]; b[i] = 0;\n }\n ++j;\n }\n }\n b[j] = N; N = j;\n };\n cout << cnt << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 11252, "score_of_the_acc": -1.0652, "final_rank": 19 }, { "submission_id": "aoj_0267_8041070", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n;\n while (cin >> n, n) {\n vector<int> b(n);\n for (int i = 0; i < n; ++i) {\n cin >> b[i];\n }\n int cnt = 0;\n while (1) {\n bool ok = true;\n for (int i = 0; i < b.size(); ++i) {\n if (b[i] != i+1) {\n ok = false; break;\n }\n }\n if (ok) {\n cout << cnt << \"\\n\";\n break;\n }\n cnt++;\n if (cnt > 10000) {\n cout << -1 << \"\\n\";\n break;\n }\n vector<int> nb;\n for (int i = 0; i < b.size(); ++i) {\n if (b[i] > 1) {\n nb.push_back(b[i]-1);\n }\n }\n nb.push_back(b.size());\n swap(b,nb);\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3456, "score_of_the_acc": -0.264, "final_rank": 8 }, { "submission_id": "aoj_0267_7941083", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while (cin >> n, n) {\n vector<int> v;\n v.clear();\n for (int i = 0; i < n; ++i) {\n int x;\n cin >> x;\n v.push_back(x);\n }\n int ans = 0, cnt = 0;\n int t = 1;\n for (int i = 0; i < v.size(); ++i) {\n if (v[i]) {\n if (v[i] == t)\n ++t;\n else\n break;\n }\n }\n if (t - 1 == v.size()) {\n cout << 0 << endl;\n continue;\n }\n int flag = 1;\n while (flag) {\n cnt = 0;\n ans++;\n if (ans > 10000) {\n ans = -1;\n break;\n }\n for (int i = 0; i < v.size(); ++i) {\n if (v[i]) {\n v[i]--;\n cnt++;\n }\n }\n v.push_back(cnt);\n int a = 1, b = 0;\n for (int j = 0; j < v.size(); ++j) {\n if (v[j]) {\n if (v[j] == a)\n ++a;\n else {\n break;\n }\n }\n b = j + 1;\n }\n if (b == v.size())\n break;\n }\n if (flag)\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3264, "score_of_the_acc": -1.0677, "final_rank": 20 }, { "submission_id": "aoj_0267_7941082", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> f(vector<int> v) {\n vector<int> res;\n for (int i = 0; i < v.size(); i++)\n if (v[i] > 0)\n res.push_back(v[i]);\n return res;\n}\nbool check(vector<int> v) {\n for (int i = 0; i < v.size(); i++)\n if (v[i] != i + 1)\n return false;\n return true;\n}\nint main() {\n int n;\n while (cin >> n, n) {\n vector<int> v;\n v.clear();\n for (int i = 0; i < n; ++i) {\n int x;\n cin >> x;\n v.push_back(x);\n }\n int ans = 0, cnt = 0;\n while (!check(v)) {\n ans++;\n if (ans > 10000) {\n ans = -1;\n break;\n }\n int size = v.size();\n for (int i = 0; i < size; ++i) {\n v[i]--;\n }\n v.push_back(size);\n v = f(v);\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3120, "score_of_the_acc": -0.4857, "final_rank": 17 }, { "submission_id": "aoj_0267_7941079", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <deque>\n#include <iostream>\n#define F first\n#define S second\nusing namespace std;\nbool check(deque<int> &deq, int counter) {\n for (int i = deq.size() - 1; i >= 0; i--) {\n if (deq[i] != counter)\n return false;\n else\n counter--;\n }\n return counter == 0;\n}\nint main() {\n int N;\n while (true) {\n cin >> N;\n if (!N)\n break;\n deque<int> deq;\n for (int i = 0; i < N; i++) {\n int input;\n cin >> input;\n deq.push_back(input);\n }\n if (check(deq, N)) {\n cout << 0 << endl;\n continue;\n }\n bool fin = true;\n for (int m = 1; m <= 10000; m++) {\n fin = true;\n int counter = 0;\n deque<int> n_deq;\n for (int i = 0; i < deq.size(); i++) {\n if (deq[i] >= 1) {\n counter++;\n deq[i]--;\n }\n if (deq[i] >= 1) {\n n_deq.push_back(deq[i]);\n }\n }\n deq = n_deq;\n deq.push_back(counter);\n if (check(deq, counter)) {\n cout << m << endl;\n fin = false;\n break;\n }\n }\n if (fin)\n cout << -1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3172, "score_of_the_acc": -0.7961, "final_rank": 18 }, { "submission_id": "aoj_0267_7941078", "code_snippet": "#include <algorithm>\n#include <deque>\n#include <iostream>\nusing namespace std;\nbool Check(deque<int> &deq) {\n int cnt = deq.size();\n for (int i = deq.size() - 1; i >= 0; i--) {\n if (deq[i] != cnt)\n return false;\n cnt--;\n }\n return true;\n}\nbool Do(deque<int> &deq) {\n for (int i = 1; i <= 10000; i++) {\n for (int iu = 0; iu < deq.size(); iu++)\n deq[iu]--;\n int next = deq.size();\n deq.erase(remove(deq.begin(), deq.end(), 0), deq.end());\n deq.push_back(next);\n if (Check(deq)) {\n cout << i << endl;\n return true;\n }\n }\n return false;\n}\nint main() {\n int N;\n while (cin >> N, N) {\n deque<int> deq;\n for (int i = 0; i < N; i++) {\n int in;\n cin >> in;\n deq.push_back(in);\n }\n if (Check(deq)) {\n cout << 0 << endl;\n continue;\n }\n if (!Do(deq))\n cout << -1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3100, "score_of_the_acc": -0.2225, "final_rank": 4 }, { "submission_id": "aoj_0267_7941077", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while (cin >> n, n) {\n int num[2000] = {}, co = n, sum = 0;\n for (int i = 0; i < n; i++)\n cin >> num[i];\n for (int i = 0;; i++) {\n bool kawa = 1;\n if (i == 10000) {\n cout << -1 << endl;\n break;\n }\n for (int j = 0; j < co && kawa; j++)\n if (num[j] != j + 1)\n kawa = 0;\n if (kawa) {\n cout << i << endl;\n break;\n }\n for (int j = 0; j < co; j++)\n num[j] -= 1;\n num[co] = co;\n for (int j = 0; j <= co; j++) {\n if (num[j] == 0) {\n for (int k = j + 1; k <= co; k++) {\n if (num[k] != 0) {\n swap(num[j], num[k]);\n break;\n }\n }\n }\n }\n for (int j = 0; j <= co + 1; j++) {\n if (num[j] == 0 || j == co + 1) {\n co = j;\n break;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3108, "score_of_the_acc": -0.3321, "final_rank": 14 }, { "submission_id": "aoj_0267_7941075", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while (cin >> n, n) {\n int num[2000] = {}, co = n;\n for (int i = 0; i < n; i++)\n cin >> num[i];\n for (int i = 0;; i++) {\n bool kawa = 1;\n if (i == 10000) {\n cout << -1 << endl;\n break;\n }\n for (int j = 0; j < co && kawa; j++)\n if (num[j] != j + 1)\n kawa = 0;\n if (kawa) {\n cout << i << endl;\n break;\n }\n for (int j = 0; j < co; j++)\n num[j] -= 1;\n num[co] = co;\n for (int j = 0; j <= co; j++) {\n if (num[j] == 0) {\n for (int k = j + 1; k <= co; k++) {\n if (num[k] != 0) {\n swap(num[j], num[k]);\n break;\n }\n }\n }\n }\n for (int j = co + 1; j >= 0; j--) {\n if (num[j] != 0) {\n co = j + 1;\n break;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3100, "score_of_the_acc": -0.2225, "final_rank": 4 }, { "submission_id": "aoj_0267_7941068", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while (cin >> n, n) {\n int num[2000] = {}, co = n;\n for (int i = 0; i < n; i++)\n cin >> num[i];\n bool NA = 0;\n for (int i = 0; !NA && i < 10001; i++) {\n bool kawa = 1;\n for (int j = 0; j < co && kawa; j++)\n if (num[j] != j + 1)\n kawa = 0;\n if (kawa) {\n NA = 1;\n cout << i << endl;\n }\n num[co] = co + 1;\n for (int j = 0; j <= co; j++) {\n if (num[j] == 1)\n for (int k = j + 1; k <= co && num[j] == 1; k++)\n if (num[k] != 1)\n swap(num[j], num[k]);\n num[j]--;\n if (num[j] == 0)\n co = j - 1;\n }\n co++;\n }\n if (!NA)\n cout << -1 << endl;\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3100, "score_of_the_acc": -0.2877, "final_rank": 12 }, { "submission_id": "aoj_0267_7941065", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;\n while (cin >> n, n) {\n int num[2000] = {}, co = n;\n for (int i = 0; i < n; i++)\n cin >> num[i];\n bool NA = 0;\n for (int i = 0; !NA && i < 10000; i++) {\n bool kawa = 1;\n for (int j = 0; j < co && kawa; j++)\n if (num[j] != j + 1)\n kawa = 0;\n if (kawa) {\n NA = 1;\n cout << i << endl;\n }\n num[co] = co + 1;\n for (int j = 0; j <= co; j++) {\n if (num[j] == 1)\n for (int k = j + 1; k <= co && num[j] == 1; k++)\n if (num[k] != 1)\n swap(num[j], num[k]);\n num[j]--;\n }\n for (int j = co + 1; j >= 0; j--) {\n if (num[j] != 0) {\n co = j + 1;\n break;\n }\n }\n }\n if (!NA)\n cout << -1 << endl;\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3096, "score_of_the_acc": -0.2655, "final_rank": 9 }, { "submission_id": "aoj_0267_7941062", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <vector>\n#define LIMIT 10000\nusing namespace std;\nbool ck(vector<int> &v) {\n for (int i = 0; i < v.size(); i++)\n if (v[i] != i + 1)\n return false;\n return true;\n}\nmain() {\n int n, i, j, s, x, l;\n vector<int> tri;\n for (i = 1; i < 1999; i++)\n tri.push_back(i * (i + 1) / 2);\n for (; scanf(\"%d\", &n), n;) {\n vector<int> v;\n for (s = i = 0; i < n; i++) {\n scanf(\"%d\", &x);\n s += x;\n v.push_back(x);\n }\n vector<int>::iterator idx = find(tri.begin(), tri.end(), s);\n i = LIMIT + 1;\n if (idx != tri.end()) {\n for (i = 0; i <= LIMIT && !ck(v); i++) {\n l = v.size();\n for (j = 0; j < l; j++)\n v[j]--;\n v.erase(remove(v.begin(), v.end(), 0), v.end());\n v.push_back(l);\n }\n }\n printf(\"%d\\n\", i > LIMIT ? -1 : i);\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2684, "score_of_the_acc": -0.0652, "final_rank": 2 }, { "submission_id": "aoj_0267_7941061", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <vector>\n#define LIMIT 10000\nusing namespace std;\nbool ck(vector<int> &v) {\n for (int i = 0; i < v.size(); i++)\n if (v[i] != i + 1)\n return false;\n return true;\n}\nmain() {\n int n, i, j, s, x, l;\n vector<int> tri;\n for (i = 1; i < 1199; i++)\n tri.push_back(i * (i + 1) / 2);\n for (; scanf(\"%d\", &n), n;) {\n vector<int> v;\n for (s = i = 0; i < n; i++) {\n scanf(\"%d\", &x);\n s += x;\n v.push_back(x);\n }\n vector<int>::iterator idx = find(tri.begin(), tri.end(), s);\n i = LIMIT + 1;\n if (idx != tri.end()) {\n for (i = 0; i <= LIMIT && !ck(v); i++) {\n l = v.size();\n for (j = 0; j < l; j++)\n v[j]--;\n v.erase(remove(v.begin(), v.end(), 0), v.end());\n v.push_back(l);\n }\n }\n printf(\"%d\\n\", i > LIMIT ? -1 : i);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2808, "score_of_the_acc": -0.0145, "final_rank": 1 }, { "submission_id": "aoj_0267_7107092", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n int n;\n auto f = [&](vector<int> a){\n for(int i = 0; i < a.size(); i++){\n if(i + 1 != a[i])return false;\n }\n return true;\n };\n auto update = [&](vector<int> a){\n vector<int> res;\n for(int i = 0; i < a.size(); i++){\n if(a[i] >= 2)res.push_back(a[i] - 1);\n }\n res.push_back(a.size());\n return res;\n };\n while(cin >> n, n){\n vector<int> b(n);\n for(auto &&v:b)cin >> v;\n int ans = 0;\n while(!f(b)){\n ans++;\n if(ans > 10000){\n ans = -1;\n break;\n }\n b = update(b);\n }\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3456, "score_of_the_acc": -0.3292, "final_rank": 13 }, { "submission_id": "aoj_0267_6335830", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void) {\n\tint a[1000],n,b[1000],k,t,flag,i,j;\n\tfor (;;)\n\t{\n\t\tcin >> n;\n\t\tif (n == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tfor (i = 0; i < 1000; i++) {\n\t\t\ta[i] = 0;\n\t\t\tb[i] = 0;\n\t\t}\n\t\tflag = 1;\n\t\tfor (i = 0; i < n; i++)\n\t\t\tcin >> a[i];\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tif (a[j] != j + 1)\n\t\t\t{\n\t\t\t\tflag = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (flag) {\n\t\t\tcout << 0 << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tk = n;\n\t\tfor (i = 0; ; i++)\n\t\t{\n\t\t\tt = 0;\n\t\t\tfor (j = 0; j < k; j++)\n\t\t\t{\n\t\t\t\ta[j]--;\n\t\t\t\tif (a[j] > 0)\n\t\t\t\t\tb[t++] = a[j];\n\t\t\t}\n\t\t\tb[t++] = k;\n\t\t\tif (t >= 1000) {\n\t\t\t\tcout << (-1) << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tflag = 1;\n\t\t\tfor (j = 0; j < t; j++) {\n\t\t\t\tif (b[j] != j + 1)\n\t\t\t\t{\n\t\t\t\t\tflag = 0;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (flag) {\n\t\t\t\tcout << i+1 << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tfor (j = 0; j < t;j++)\n\t\t\t{\n\t\t\t\ta[j] = b[j];\n\t\t\t}\n\t\t\tk = t;\n\t\t\tif (i > 10000) {\n\t\t\t\tcout << ( -1) << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3428, "score_of_the_acc": -0.1086, "final_rank": 3 }, { "submission_id": "aoj_0267_5939619", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n while (true){\n int N;\n cin >> N;\n if (N == 0){\n break;\n }\n vector<int> b(N);\n for (int i = 0; i < N; i++){\n cin >> b[i];\n }\n int ans = 0;\n while (true){\n bool ok = true;\n for (int i = 0; i < N; i++){\n if (b[i] != i + 1){\n ok = false;\n }\n }\n if (ok){\n cout << ans << endl;\n break;\n }\n ans++;\n if (ans > 10000){\n cout << -1 << endl;\n break;\n }\n vector<int> b2;\n for (int i = 0; i < N; i++){\n if (b[i] > 1){\n b2.push_back(b[i] - 1);\n }\n }\n b2.push_back(N);\n N = b2.size();\n swap(b, b2);\n }\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3488, "score_of_the_acc": -0.246, "final_rank": 7 }, { "submission_id": "aoj_0267_5822853", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n\nsigned main() {\n while(true) {\n int n; cin >> n;\n if(n == 0) break;\n vector<int> b(n);\n for(int i=0; i<n; i++) cin >> b[i];\n int i = 0;\n bool flg = true;\n for(int j=0; j<b.size(); j++) {\n if(j+1 != b[j]) {\n flg = false;\n break;\n }\n }\n if(flg) {\n cout << 0 << endl;\n continue;\n }\n for(; i<10000; i++) {\n vector<int> next;\n for(int j=0; j<b.size(); j++) {\n if(b[j] > 1) next.push_back(b[j] - 1);\n }\n next.push_back(b.size());\n b = next;\n bool flg = true;\n for(int j=0; j<b.size(); j++) {\n if(j+1 != b[j]) {\n flg = false;\n break;\n }\n }\n if(flg) {\n break;\n }\n }\n if(i == 10000) {\n cout << -1 << endl;\n } else {\n cout << i+1 << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3160, "score_of_the_acc": -0.2729, "final_rank": 10 } ]
aoj_0265_cpp
ねこまっしぐら あるところに、高い塀に囲まれた大きなお屋敷がありました。そのお屋敷の主人は猫がとても大好きで、時折やってくる猫たちのために、いつもおいしいごはんを用意していました。お腹を空かせた猫たちは、高い塀をひょいと飛び越え、お屋敷の至る所に置いてあるごはんにまっしぐらに駆け寄るのでした。 ある日主人は、屋敷の中で何匹かの猫が倒れているのを見つけました。猫たちはごはんを探して屋敷の中を縦横無尽に走り回ったので、ぶつかったり転んだりしてしまったのです。主人は猫たちの安全を考えて、ごはんの置き場所を工夫することにしました。 上空から見ると、このお屋敷の塀は多角形をなしています。主人は猫たちがごはんを見つけやすいように、敷地内の中でも、多角形の頂点にあたる場所だけにごはんを置くことにしました。また猫たちは気まぐれなので、多角形の周上のどの点からお屋敷に入ってくるかは予想できません。そこで主人は、猫がどの点から入ったとしても、その点から直進していずれかのごはんにたどり着けるように、ごはんを配置することも決めました。 すべての頂点にごはんを配置すれば、この条件を満たすことができます。しかし、ごはんを補充して回るのは大変なので、主人はできるだけ少ない数の頂点にごはんを配置したいと思いました。さて、主人は最低何箇所にごはんを配置する必要があるでしょうか。 お屋敷の塀を表す多角形を入力とし、ごはんを配置する頂点の数の最小値を求めるプログラムを作成して下さい。ただし、猫は多角形の内部のみを直進できるものとします(辺は多角形の内部に含めるものとします)。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 n x 1 y 1 x 2 y 2 ... x n y n 1行目に多角形の頂点の数 n (3 ≤ n ≤ 16) が与えられる。続く n 行に多角形の頂点の座標が与えられる。n 行のそれぞれは、1つの空白で区切られた2つの整数からなる。x i (-1000 ≤ x i ≤ 1000) は i 番目の頂点の x 座標、y i (-1000 ≤ y i ≤ 1000) は i 番目の頂点の y 座標を示す。多角形の頂点は、隣り合った頂点を反時計回りに訪問するような順番で与えられる。 データセットの数は 20 を超えない。 出力 各データセットごとに、ご飯を配置する頂点の数を1行に出力する。 入力例 8 0 0 3 2 6 2 8 6 6 5 7 7 0 4 3 4 8 0 0 5 3 5 2 4 1 6 1 8 6 6 4 2 4 0 出力例 1 2
[ { "submission_id": "aoj_0265_5433557", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n#define SIZE 1000\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][SIZE];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tVector base_vec = work_p[a]-work_p[(a+1)%3];\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tVector adj = line[b].p[1]-line[b].p[0];\n\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(fabs(cross(base_vec,adj)) < EPS)continue;\n\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 3308, "score_of_the_acc": -0.5018, "final_rank": 6 }, { "submission_id": "aoj_0265_5433551", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n#define SIZE 1000\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][SIZE];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\t//if(DEBUG){\n\t//printf(\"LINE.size():%lld\\n\",LINE.size());\n\t//}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\t/*if(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}*/\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tVector base_vec = work_p[a]-work_p[(a+1)%3];\n\n\t\t\t\tPoint mid_p = (work_p[a]+work_p[(a+1)%3])/2;\n\t\t\t\t/*if(contains(poly,mid_p) == 0){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}*/\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tVector adj = line[b].p[1]-line[b].p[0];\n\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(fabs(cross(base_vec,adj)) < EPS)continue;\n\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\t\t\t\t\t\t//if(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1])continue;\n\n\t\t\t\t\t\t/*if(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}*/\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\t\t\t\t\tprintf(\"線分\");\n\t\t\t\t\tLINE[k].outPut();\n\t\t\t\t\tprintf(\"から\");\n\t\t\t\t\tbase_p.debug();\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3272, "score_of_the_acc": -0.3827, "final_rank": 4 }, { "submission_id": "aoj_0265_5433544", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n#define SIZE 1000\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][SIZE];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tif(DEBUG){\n\tprintf(\"LINE.size():%lld\\n\",LINE.size());\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\t/*if(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}*/\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tVector base_vec = work_p[a]-work_p[(a+1)%3];\n\n\t\t\t\tPoint mid_p = (work_p[a]+work_p[(a+1)%3])/2;\n\t\t\t\tif(contains(poly,mid_p) == 0){\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tVector adj = line[b].p[1]-line[b].p[0];\n\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(fabs(cross(base_vec,adj)) < EPS)continue;\n\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\t\t\t\t\t\t//if(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1])continue;\n\n\t\t\t\t\t\t/*if(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}*/\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\t\t\t\t\tprintf(\"線分\");\n\t\t\t\t\tLINE[k].outPut();\n\t\t\t\t\tprintf(\"から\");\n\t\t\t\t\tbase_p.debug();\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 340, "memory_kb": 3308, "score_of_the_acc": -0.5018, "final_rank": 8 }, { "submission_id": "aoj_0265_5433461", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tVector base_vec = work_p[a]-work_p[(a+1)%3];\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tVector adj = line[b].p[1]-line[b].p[0];\n\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(fabs(cross(base_vec,adj)) < EPS)continue;\n\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\t\t\t\t\t\t//if(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1])continue;\n\n\t\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.7142857142857143, "time_ms": 360, "memory_kb": 3264, "score_of_the_acc": -0.3582, "final_rank": 9 }, { "submission_id": "aoj_0265_5433443", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tVector base_vec = work_p[a]-work_p[(a+1)%3];\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tVector adj = line[b].p[1]-line[b].p[0];\n\n\t\t\t\t\tif(fabs(cross(base_vec,adj)) < EPS)continue;\n\n\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\t//if(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1])continue;\n\n\t\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3264, "score_of_the_acc": -0.2954, "final_rank": 15 }, { "submission_id": "aoj_0265_5433310", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tif(getDistanceSP(LINE[k],base_p) < EPS){\n\n\t\t\t\tcheck[i][k] = true;\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tdouble base_slope = calc_slope(tmp_line);\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tdouble tmp_slope = calc_slope(line[b]);\n\t\t\t\t\tif(fabs(base_slope-tmp_slope) < EPS)continue;\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\n\t\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.7142857142857143, "time_ms": 360, "memory_kb": 3336, "score_of_the_acc": -0.6015, "final_rank": 11 }, { "submission_id": "aoj_0265_5433282", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n//#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define EPS 0.0000001\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tPoint mid_p = (LINE[k].p[0]+LINE[k].p[1])/2;\n\t\t\tLine tmp_line = Line(mid_p,base_p);\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\tif(getDistanceSP(line[b],mid_p) < EPS || getDistanceSP(line[b],base_p) < EPS)continue;\n\n\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t//if(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\n\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t}\n\n\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 100, "memory_kb": 3300, "score_of_the_acc": -0.4145, "final_rank": 19 }, { "submission_id": "aoj_0265_5433144", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tdouble base_slope = calc_slope(tmp_line);\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tdouble tmp_slope = calc_slope(line[b]);\n\t\t\t\t\tif(fabs(base_slope-tmp_slope) < EPS)continue;\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1] || cross_p == line[b].p[0] || cross_p == line[b].p[1])continue;\n\n\t\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.7142857142857143, "time_ms": 360, "memory_kb": 3300, "score_of_the_acc": -0.4798, "final_rank": 10 }, { "submission_id": "aoj_0265_5433126", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define MAX 16\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\n\t\tif(fabs(x-p.x) > EPS){\n\n\t\t\treturn x < p.x;\n\t\t}else{\n\n\t\t\treturn y < p.y;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\tdouble x,y;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tvoid outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}\n\tPoint p[2];\n};\n\n\nint N;\nint POW[MAX+1];\ndouble NUM = 10000;\nbool check[MAX+1][300];\nLine line[MAX+1];\nvector<Point> POINTS[MAX+1];\nvector<Line> LINE;\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\n/*\n * p0を基準点として、p1から見てp2が\n * 反時計回り側にあれば\n * COUNTER_CLOCKWISE\n * */\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\nint func(double x1,double y1,double x2, double y2, double xp, double yp){\n\tdouble naiseki,norm1,norm2,gaiseki;\n\tnorm1 = sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));\n\tnorm2 = sqrt((xp-x1)*(xp-x1)+(yp-y1)*(yp-y1));\n\tnaiseki = (xp-x1)*(x2-x1)+(yp-y1)*(y2-y1);\n\tgaiseki = (x2-x1)*(yp-y1)-(xp-x1)*(y2-y1);\n\tif(gaiseki > EPS){\n\t\treturn 1;\n\t}else if(gaiseki < -EPS){\n\t\treturn -1;\n\t}\n\tif(naiseki < -EPS){\n\t\treturn 2;\n\t}\n\n\tif(norm1 < norm2){\n\t\treturn -2;\n\t}\n\treturn 0;\n}\n\n\n//★★直線ではなく、線分の交差判定★★\nbool is_Cross(Line a,Line b){\n\n\tif(func(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[0].x,b.p[0].y)*\n\t\t\tfunc(a.p[0].x,a.p[0].y,a.p[1].x,a.p[1].y,b.p[1].x,b.p[1].y) <= 0 &&\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[0].x,a.p[0].y)*\n\t\t\tfunc(b.p[0].x,b.p[0].y,b.p[1].x,b.p[1].y,a.p[1].x,a.p[1].y) <= 0){\n\t\treturn true;\n\t}\n\treturn false;\n}\n\n\nPoint calc_minus(Point a,Point b){\n Point ret;\n\n ret.x = a.x-b.x;\n ret.y = a.y-b.y;\n\n return ret;\n}\n\ndouble calc_len(Vector a){\n return sqrt(a.x*a.x+a.y*a.y);\n}\n\n//線分ではなく直線と点の距離\ndouble getDistanceLP(Line l,Point p){\n return fabs(cross(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0]))/calc_len(calc_minus(l.p[1],l.p[0])));\n}\n\n//点と線分の距離\ndouble getDistanceSP(Line l,Point p){\n\tif(dot(calc_minus(l.p[1],l.p[0]),calc_minus(p,l.p[0])) < 0.0)return calc_len(calc_minus(p,l.p[0]));\n\tif(dot(calc_minus(l.p[0],l.p[1]),calc_minus(p,l.p[1])) < 0.0)return calc_len(calc_minus(p,l.p[1]));\n\treturn getDistanceLP(l,p);\n}\n\n/*\n * IN 2\n * ON 1\n * OUT 0\n *\n */\nint contains(Polygon g,Point p){\n\tint n = g.size();\n\tbool x = false;\n\tfor(int i = 0; i < n; i++){\n\t\tPoint a = g[i]-p,b = g[(i+1)%n]-p;\n\t\tif(abs(cross(a,b)) < EPS && dot(a,b) < EPS)return 1;\n\t\tif(a.y > b.y)swap(a,b);\n\t\tif(a.y < EPS && EPS < b.y && cross(a,b) > EPS) x = !x;\n\t}\n\treturn (x ? 2:0);\n}\n\n//交点を求める関数\nPoint calc_Cross_Point(double x1,double x2,double x3,double x4,double y1,double y2,double y3,double y4){\n\tPoint ret;\n\tret.x = ((x2-x1)*(y3*(x4-x3)+x3*(y3-y4))-(x4-x3)*(y1*(x2-x1)+x1*(y1-y2)))/((y2-y1)*(x4-x3)-(y4-y3)*(x2-x1));\n\tif(fabs(x1-x2) > EPS){\n\t\tret.y = ((y2-y1)*ret.x+y1*(x2-x1)+x1*(y1-y2))/(x2-x1);\n\t}else{\n\t\tret.y = ((y4-y3)*ret.x+y3*(x4-x3)+x3*(y3-y4))/(x4-x3);\n\t}\n\treturn ret;\n}\n\n//インタフェース関数\nPoint calc_Cross_Point(Point a,Point b,Point c,Point d){\n\treturn calc_Cross_Point(a.x,b.x,c.x,d.x,a.y,b.y,c.y,d.y);\n}\n\nPoint calc_Cross_Point(Line A,Line B){\n\n\tif(getDistanceSP(B,A.p[0]) < EPS){\n\n\t\treturn A.p[0];\n\n\t}else if(getDistanceSP(B,A.p[1]) < EPS){\n\n\t\treturn A.p[1];\n\n\t}else if(getDistanceSP(A,B.p[0]) < EPS){\n\n\t\treturn B.p[0];\n\n\t}else if(getDistanceSP(A,B.p[1]) < EPS){\n\n\t\treturn B.p[1];\n\t}\n\n\treturn calc_Cross_Point(A.p[0],A.p[1],B.p[0],B.p[1]);\n}\n\ndouble calc_slope(Line A){\n\n\tif(fabs(A.p[0].x-A.p[1].x) < EPS){\n\n\t\treturn DBL_MAX;\n\n\t}else if(fabs(A.p[0].y-A.p[1].y) < EPS){\n\n\t\treturn 0;\n\n\t}else{\n\n\t\treturn (A.p[1].y-A.p[0].y)/(A.p[1].x-A.p[0].x);\n\t}\n}\n\nbool DEBUG = false;\n\nvoid func(){\n\n\tfor(int i = 0; i <= MAX; i++){\n\n\t\tPOINTS[i].clear();\n\t}\n\n\tPolygon poly;\n\n\tdouble x,y;\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lf %lf\",&x,&y);\n\t\tpoly.push_back(Point(x,y));\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tline[i] = Line(poly[i],poly[(i+1)%N]);\n\n\t\tPOINTS[i].push_back(poly[i]);\n\t\tPOINTS[i].push_back(poly[(i+1)%N]);\n\t}\n\n\t//2点を通る直線を調べる\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tVector vec = poly[k]-poly[i];\n\n\t\t\tLine tmp_line = Line(poly[i],poly[i]+vec*NUM); //点k方向に伸ばす\n\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tif(is_Cross(tmp_line,line[a])){\n\n\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[a]);\n\t\t\t\t\tPOINTS[a].push_back(cross_p);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsort(POINTS[i].begin(),POINTS[i].end());\n\t\tPOINTS[i].erase(unique(POINTS[i].begin(),POINTS[i].end()),POINTS[i].end());\n\t}\n\n\tLINE.clear();\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 1; k < POINTS[i].size(); k++){\n\n\t\t\tLINE.push_back(Line(POINTS[i][k-1],POINTS[i][k]));\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tcheck[i][k] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tPoint base_p = poly[i];\n\n\t\tif(DEBUG){\n\t\t\tprintf(\"\\n点%d\",i);\n\t\t\tbase_p.debug();\n\t\t}\n\n\t\tfor(int k = 0; k < LINE.size(); k++){\n\n\t\t\tif(DEBUG){\n\t\t\t\tprintf(\"線分\\n\");\n\t\t\t\tLINE[k].outPut();\n\t\t\t}\n\n\t\t\t//線分kからiが見えるか\n\t\t\tPolygon work_p;\n\t\t\twork_p.push_back(LINE[k].p[0]);\n\t\t\twork_p.push_back(LINE[k].p[1]);\n\t\t\twork_p.push_back(base_p);\n\n\t\t\tPoint p_w = (work_p[0]+work_p[1]+work_p[2])/3;\n\n\t\t\tif(contains(poly,p_w) == 0){\n\t\t\t\t//printf(\"外部\\n\");\n\t\t\t\tcontinue; //三角形の重心がポリゴンの外部ならSKIP\n\t\t\t}\n\n\t\t\tbool FLG = true;\n\n\t\t\tfor(int a = 0; a < 3; a++){ //3つの辺について試す\n\t\t\t\tLine tmp_line = Line(work_p[a],work_p[(a+1)%3]);\n\t\t\t\tdouble base_slope = calc_slope(tmp_line);\n\n\t\t\t\tfor(int b = 0; b < N; b++){\n\n\t\t\t\t\tdouble tmp_slope = calc_slope(line[b]);\n\t\t\t\t\tif(fabs(base_slope-tmp_slope) < EPS)continue;\n\t\t\t\t\tif(line[b].p[0] == tmp_line.p[0] || line[b].p[0] == tmp_line.p[1] ||\n\t\t\t\t\t\t\tline[b].p[1] == tmp_line.p[0] || line[b].p[1] == tmp_line.p[1])continue;\n\n\t\t\t\t\tif(is_Cross(tmp_line,line[b])){\n\n\t\t\t\t\t\tPoint cross_p = calc_Cross_Point(tmp_line,line[b]);\n\t\t\t\t\t\tif(cross_p == tmp_line.p[0] || cross_p == tmp_line.p[1])continue;\n\n\t\t\t\t\t\tif(DEBUG){\n\t\t\t\t\t\t\tprintf(\"交差\\n\");\n\t\t\t\t\t\t\tline[b].outPut();\n\t\t\t\t\t\t\tcross_p.debug();\n\t\t\t\t\t\t}\n\n\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!FLG)break;\n\t\t\t}\n\n\t\t\tif(DEBUG){\n\t\t\t\tif(FLG){\n\n\t\t\t\t\tprintf(\"見える\\n\");\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"見えない\\n\");\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tcheck[i][k] = FLG;\n\t\t}\n\t}\n\n\n\tint ans = N;\n\tbool table[LINE.size()];\n\n\tfor(int state = 1; state < POW[N]; state++){\n\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\n\t\t\ttable[i] = false;\n\t\t}\n\n\t\tint num_P = 0;\n\n\t\tfor(int loop = 0; loop < N; loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tnum_P++;\n\n\t\t\t\tfor(int a = 0; a < LINE.size(); a++){\n\n\t\t\t\t\ttable[a] |= check[loop][a];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tbool FLG= true;\n\t\tfor(int i = 0; i < LINE.size(); i++){\n\t\t\tif(!table[i]){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(FLG){\n\n\t\t\tans = min(ans,num_P);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n}\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3276, "score_of_the_acc": -0.3359, "final_rank": 16 }, { "submission_id": "aoj_0265_2987961", "code_snippet": "#include <iostream>\n#include <complex>\n#include <cstdio>\n#include <utility>\n#include <vector>\n#include <bitset>\nusing namespace std;\ntypedef complex<double> P;\ntypedef pair<P,P> L;\ntypedef pair<P,double> C;\ntypedef vector<P> Poly;\n#define X real()\n#define Y imag()\nconst double EPS = (1e-10);\nconst double INF = (1e15);\n \nnamespace std{\n bool operator < (const P& a, const P& b){\n return a.X != b.X ? a.X < b.X : a.Y < b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return a.X * b.X + a.Y * b.Y;\n}\ndouble cross(P a, P b){\n return a.X * b.Y - a.Y * b.X;\n}\n\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return 1;\n if(cross(b,c) < -EPS) return -1;\n if(dot(b,c) < -EPS) return 2;\n if(norm(c) - norm(b) > EPS) return -2;\n return 0;\n}\n\nbool is_cross(L a, L b){\n //接しているのはセーフ\n if(ccw(a.first,a.second,b.first)*ccw(a.first,a.second,b.second) < 0 &&\n ccw(b.first,b.second,a.first)*ccw(b.first,b.second,a.second) < 0)\n return true;\n return false;\n}\n\nint in_poly(P a, Poly p){\n int n = p.size(), c = 0;\n for(int i = 0; i < n; ++i){\n P s = p[i] - a, t = p[(i+1)%n] - a;\n if(!ccw(s,t,P(0,0))) return 1;//周上\n if(s.Y > t.Y + EPS) swap(s,t);\n if((s.Y*t.Y < 0 || (s.Y*t.Y < EPS && t.Y > EPS)) && cross(s,t) < EPS) ++c;\n }\n if(c%2) return 2;//内部\n return 0;//外\n}\n\nusing namespace std;\nint main(){\n int n;\n while(cin >> n, n){\n Poly V;\n for(int i = 0; i < n; ++i){\n double x, y;\n cin >> x >> y;\n V.push_back(P(x,y));\n }\n vector< vector<bool> > valid(n,vector<bool>(n,false));\n for(int i = 0; i < n; ++i){\n for(int j = 0; j < i; ++j){\n L l = L(V[i], V[j]);\n bool f = false;\n for(int k = 0; k < n; ++k){\n if(k == i || (k+1)%n == i || k == j || (k+1)%n == j) continue;\n f |= is_cross(l, L(V[k], V[(k+1)%n]));\n if(f){\n //cout << \"(\" << i << \", \" << j << \"), \" << \"(\" << k << \", \" << (k+1)%n << \"), \" << endl;\n break;\n }\n }\n if(f) continue;\n for(int k = 0; k < n; ++k){\n P m = V[i] + (V[j] - V[i])/(double)(n*k);\n if(!in_poly(m, V)) f = true;\n }\n if(f) continue;\n valid[i][j] = true;\n valid[j][i] = true;\n }\n }\n for(int i = 0; i < n; ++i){\n valid[i][i] = true;\n valid[i][(i+1)%n] = true;\n valid[(i+1)%n][i] = true;\n }\n /*\n for(int i = 0; i < n; ++i){\n for(int j = 0; j < n; ++j) cout << valid[i][j] << \" \";cout << endl;\n }\n */\n int ans = n/3;\n for(int i = 1; i < (1<<n); ++i){\n vector<bool> ok(n, false);\n int c = 0;\n for(int j = 0; j < n; ++j){\n if(!((i>>j) & 1)) continue;\n ++c;\n for(int k = 0; k < n; ++k){\n //if(valid[j][k] && valid[j][(k+1)%n]) ok[k] = true;\n if(valid[j][k]) ok[k] = true;\n }\n }\n bool f = true;\n //cout << bitset<8>(i) << endl;\n //for(int j = 0; j < n; ++j) cout << ok[j] << \" \";cout << endl;\n for(int j = 0; j < n; ++j) f &= ok[j];\n if(f) ans = min(ans, c);\n //if(f && c == 4) cout << bitset<16>(i) << endl;\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 20, "memory_kb": 3284, "score_of_the_acc": -0.3404, "final_rank": 17 }, { "submission_id": "aoj_0265_2987841", "code_snippet": "#include <iostream>\n#include <complex>\n#include <cstdio>\n#include <utility>\n#include <vector>\n#include <bitset>\nusing namespace std;\ntypedef complex<double> P;\ntypedef pair<P,P> L;\ntypedef pair<P,double> C;\ntypedef vector<P> Poly;\n#define X real()\n#define Y imag()\nconst double EPS = (1e-10);\nconst double INF = (1e15);\n \nnamespace std{\n bool operator < (const P& a, const P& b){\n return a.X != b.X ? a.X < b.X : a.Y < b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return a.X * b.X + a.Y * b.Y;\n}\ndouble cross(P a, P b){\n return a.X * b.Y - a.Y * b.X;\n}\n\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return 1;\n if(cross(b,c) < -EPS) return -1;\n if(dot(b,c) < -EPS) return 2;\n if(norm(c) - norm(b) > EPS) return -2;\n return 0;\n}\n\nbool is_cross(L a, L b){\n //接しているのはセーフ\n if(ccw(a.first,a.second,b.first)*ccw(a.first,a.second,b.second) < 0 &&\n ccw(b.first,b.second,a.first)*ccw(b.first,b.second,a.second) < 0)\n return true;\n return false;\n}\n\nint in_poly(P a, Poly p){\n int n = p.size(), c = 0;\n for(int i = 0; i < n; ++i){\n P s = p[i] - a, t = p[(i+1)%n] - a;\n if(!ccw(s,t,P(0,0))) return 1;//周上\n if(s.Y > t.Y + EPS) swap(s,t);\n if((s.Y*t.Y < 0 || (s.Y*t.Y < EPS && t.Y > EPS)) && cross(s,t) < EPS) ++c;\n }\n if(c%2) return 2;//内部\n return 0;//外\n}\n\nusing namespace std;\nint main(){\n int n;\n while(cin >> n, n){\n Poly V;\n for(int i = 0; i < n; ++i){\n double x, y;\n cin >> x >> y;\n V.push_back(P(x,y));\n }\n vector< vector<bool> > valid(n,vector<bool>(n,false));\n for(int i = 0; i < n; ++i){\n for(int j = 0; j < i; ++j){\n L l = L(V[i], V[j]);\n bool f = false;\n for(int k = 0; k < n; ++k){\n if(k == i || (k+1)%n == i || k == j || (k+1)%n == j) continue;\n f |= is_cross(l, L(V[k], V[(k+1)%n]));\n if(f){\n //cout << \"(\" << i << \", \" << j << \"), \" << \"(\" << k << \", \" << (k+1)%n << \"), \" << endl;\n break;\n }\n }\n if(f) continue;\n for(int k = 0; k < n; ++k){\n P m = V[i] + (V[j] - V[i])/(double)(n*k);\n if(!in_poly(m, V)) f = true;\n }\n if(f) continue;\n valid[i][j] = true;\n valid[j][i] = true;\n }\n }\n for(int i = 0; i < n; ++i){\n valid[i][i] = true;\n valid[i][(i+1)%n] = true;\n valid[(i+1)%n][i] = true;\n }\n /*\n for(int i = 0; i < n; ++i){\n for(int j = 0; j < n; ++j) cout << valid[i][j] << \" \";cout << endl;\n }\n */\n int ans = n/3;\n for(int i = 1; i < (1<<n); ++i){\n vector<bool> ok(n, false);\n int c = 0;\n for(int j = 0; j < n; ++j){\n if(!((i>>j) & 1)) continue;\n ++c;\n for(int k = 0; k < n; ++k){\n if(valid[j][k] && valid[j][(k+1)%n]) ok[k] = true;\n }\n }\n bool f = true;\n //cout << bitset<8>(i) << endl;\n //for(int j = 0; j < n; ++j) cout << ok[j] << \" \";cout << endl;\n for(int j = 0; j < n; ++j) f &= ok[j];\n if(f) ans = min(ans, c);\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 30, "memory_kb": 3284, "score_of_the_acc": -0.3429, "final_rank": 18 }, { "submission_id": "aoj_0265_2667055", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nbool intersectLS(const L &l, const L &s) {\n return cross(l[1]-l[0], s[0]-l[0])* // s[0] is left of l\n cross(l[1]-l[0], s[1]-l[0]) < EPS; // s[1] is right of l\n}\nbool intersectSS(const L &s, const L &t) {\n return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) < 0 &&\n ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) < 0;\n}\nP crosspoint(const L &l, const L &m) {\n\tdouble A = cross(l[1] - l[0], m[1] - m[0]);\n\tdouble B = cross(l[1] - l[0], l[1] - m[0]);\n\tif (abs(A) < EPS && abs(B) < EPS) return m[0]; // same line\n\tif (abs(A) < EPS) assert(false); // !!!PRECONDITION NOT SATISFIED!!!\n\treturn m[0] + B / A * (m[1] - m[0]);\n}\nG convex_hull(G ps) {\n\tint n = ps.size(), k = 0;\n\tsort(ps.begin(), ps.end());\n\tG ch(2*n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++]) // lower-hull\n\t\twhile (k >= 2 && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) --k;\n\tfor (int i = n-2, t = k+1; i >= 0; ch[k++] = ps[i--]) // upper-hull\n\t\twhile (k >= t && ccw(ch[k-2], ch[k-1], ps[i]) <= 0) --k;\n\tch.resize(k-1);\n\treturn ch;\n}\n#define curr(P, i) P[i]\n#define next(P, i) P[(i+1)%P.size()]\ndouble area2(const G& g) {\n\tdouble A = 0;\n\tfor (int i = 0; i < g.size(); ++i) \n\t\tA += cross(curr(g, i), next(g, i));\n\treturn A;\n}\nenum { OUT, ON, IN };\nint contains(const G& g, const P& p) {\n\tbool in = false;\n\tfor (int i = 0; i < g.size(); ++i) {\n\t\tP a = curr(g,i) - p, b = next(g,i) - p;\n\t\tif (imag(a) > imag(b) + EPS) swap(a, b);\n\t\tif (imag(a) < EPS && EPS < imag(b))\n\t\tif (cross(a, b) < -EPS) in = !in;\n\t\tif (abs(cross(a, b)) < EPS && dot(a, b) < EPS) return ON;\n\t}\n\treturn in ? IN : OUT;\n}\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint n;\n\twhile(cin >> n, n){\n\t\tG ps;\n\t\trep(i, n){ int x, y; cin >> x >> y; ps.emplace_back(x, y); }\n\t\t//各辺を任意の二頂点を結ぶ直線との交点で分割\n\t\tvector<G> points;\n\t\trep(i, n){\n\t\t\tG pts = { ps[i], ps[(i + 1) % n] };\n\t\t\tL e(ps[i], ps[(i + 1) % n]);\n\t\t\trep(j, n) rep(k, j){\n\t\t\t\tL l(ps[j], ps[k]);\n\t\t\t\tif(!intersectLS(l, e)) continue;\n\t\t\t\tpts.pb(crosspoint(l, e));\n\t\t\t}\n\t\t\tsort(all(pts), [&](P a, P b){\n\t\t\t\treturn abs(ps[i] - a) < abs(ps[i] - b);\n\t\t\t});\n\t\t\t//近い点は消す\n\t\t\trep(j, (int)pts.size() - 1) if(abs(pts[j] - pts[j + 1]) < EPS){\n\t\t\t\tpts.erase(pts.begin() + j);\n\t\t\t\tj--;\n\t\t\t}\n\t\t\t//中点を足す\n\t\t\tint sz = (int)pts.size() - 1;\n\t\t\trep(j, sz) pts.pb((pts[j] + pts[j + 1]) / 2.0);\n\t\t\tsort(all(pts), [&](P a, P b){\n\t\t\t\treturn abs(ps[i] - a) < abs(ps[i] - b);\n\t\t\t});\n\t\t\tswap(pts[1], pts.back());\n\t\t\tpoints.pb(pts);\n\t\t}\n\t\t//rep(i, n) dbg(i, points[i]);\n\t\t\n\t\tvector<vi> flags;\n\t\tfor(const auto &pts : points){\n\t\t\tvi fs;\n\t\t\tfor(const P &p : pts){\n\t\t\t\tint f = 0;\n\t\t\t\trep(i, n){\n\t\t\t\t\tL l(p, ps[i]);\n\t\t\t\t\tG crs = {l[0], l[1]};\n\t\t\t\t\t\n\t\t\t\t\t//辺と交差してたらダメ\n\t\t\t\t\trep(j, n){\n\t\t\t\t\t\tL e(ps[j], ps[(j + 1) % n]);\n\t\t\t\t\t\tif(intersectSS(l, e)) goto NG;\n\t\t\t\t\t}\n\t\t\t\t\t\n\t\t\t\t\t//外に出てたらダメ\n\t\t\t\t\trep(j, n) if(ccw(l[0], ps[j], l[1]) == -2) crs.pb(ps[j]);\n\t\t\t\t\tsort(all(crs), [&](P a, P b){\n\t\t\t\t\t\treturn abs(l[0] - a) < abs(l[0] - b);\n\t\t\t\t\t});\n\t\t\t\t\trep(j, (int)crs.size()-1){\n\t\t\t\t\t\tif(contains(ps, (crs[j] + crs[j+1]) / 2.0) == OUT){\n\t\t\t\t\t\t\t/*\n\t\t\t\t\t\t\tdbg(crs[j], crs[j+1]);\n\t\t\t\t\t\t\tdbg((crs[j] + crs[j+1]) / 2.0);\n\t\t\t\t\t\t\t*/\n\t\t\t\t\t\t\tgoto NG;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tf |= 1 << i;\n\t\t\t\t\tNG:;\n\t\t\t\t}\n\t\t\t\tfs.pb(f);\n\t\t\t}\n\t\t\tflags.pb(fs);\n\t\t}\n\t\t\n\t\tint ans = (n + 1) / 2;\n\t\trep(mask, 1 << n){\n\t\t\tint sz = __builtin_popcount(mask);\n\t\t\tif(sz >= ans) continue;\n\t\t\t\n\t\t\tfor(const vi fs : flags) for(int f : fs) if(!(f & mask)) goto NEXT;\n\t\t\t\n\t\t\tans = min(ans, sz);\n\t\t\tNEXT:;\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3304, "score_of_the_acc": -0.423, "final_rank": 5 }, { "submission_id": "aoj_0265_2620642", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <cmath>\n#include <bitset>\nusing namespace std;\n\n#define MAX_PART 512\n\nconst double EPS = 1e-10;\nconst double INF = 1e12;\n#define LE(n,m) ((n) < (m) + EPS)\n#define GE(n,m) ((n) + EPS > (m))\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : VP{\n L(const P& a, const P& b){ resize(2); at(0)=a; at(1)=b; }\n L(){ resize(2); }\n};\nnamespace std{\n bool operator < (const P& a, const P& b){\n return (a.X!=b.X) ? a.X<b.X : a.Y<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) <-EPS) return -1; //cw\n if(dot(b,c) < EPS) return +2; //c-a-b\n if(norm(b) < norm(c)) return -2; //a-b-c\n return 0; //a-c-b\n}\nbool intersectSP(const L& s, const P& p){\n return abs(s[0]-p) +abs(s[1]-p) -abs(s[1]-s[0]) < EPS;\n}\nbool intersectSS(const L& s, const L& t){\n for(int i=0; i<2; i++){\n for(int j=0; j<2; j++){\n if(s[i]==t[j]) return true;\n }\n }\n return ( ccw(s[0],s[1],t[0]) *ccw(s[0],s[1],t[1]) <= 0 ) &&\n ( ccw(t[0],t[1],s[0]) *ccw(t[0],t[1],s[1]) <= 0 );\n}\nbool intersectLS(const L& l, const L& s){\n return cross(l[1]-l[0], s[0]-l[0])*\n cross(l[1]-l[0], s[1]-l[0]) < EPS;\n}\nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B /A *(m[1]-m[0]);\n}\n\nbool isParallel(const P &a, const P &b){\n return abs(cross(a,b)) < EPS;\n}\nbool isParallel(const L &a, const L &b){\n return isParallel(a[1]-a[0], b[1]-b[0]);\n}\n\nbool in_poly(const P &p, const VP &poly){\n int n = poly.size();\n int cn=0;\n for(int i=0; i<n; i++){\n if(intersectSP(L(poly[i], poly[(i+1)%n]), p)){\n return true;\n }\n }\n L ray(p, p+P(INF, 0));\n for(int i=0; i<n; i++){\n if((poly[i].Y <= p.Y && poly[(i+1)%n].Y > p.Y) ||\n (poly[i].Y > p.Y && poly[(i+1)%n].Y <= p.Y)){\n if(intersectSS(ray, L(poly[i],poly[(i+1)%n]))){\n cn++;\n }\n }\n }\n return cn%2 != 0;\n}\n\nbool isVisible(const L &l, const VP &poly){\n int n = poly.size();\n VP cp;\n for(int i=0; i<n; i++){\n L edge(poly[i], poly[(i+1)%n]);\n if(!isParallel(l, edge) && intersectSS(l, edge)){\n cp.push_back(crosspointLL(l, edge));\n }\n }\n sort(cp.begin(), cp.end());\n \n bool ret = true;\n for(int i=0; i<(int)cp.size()-1; i++){\n if(!in_poly((cp[i]+cp[i+1])/2.0, poly)){\n ret = false;\n break;\n }\n }\n return ret;\n}\n\nint bitcount(int n){\n n = (n & 0x55555555) + (n >> 1 & 0x55555555);\n n = (n & 0x33333333) + (n >> 2 & 0x33333333);\n n = (n & 0x0f0f0f0f) + (n >> 4 & 0x0f0f0f0f);\n n = (n & 0x00ff00ff) + (n >> 8 & 0x00ff00ff);\n return (n & 0x0000ffff) + (n >>16 & 0x0000ffff);\n}\n\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n==0) break;\n \n VP poly(n);\n for(int i=0; i<n; i++){\n int x,y;\n cin >> x >> y;\n poly[i] = P(x,y);\n }\n\n //visible graph of vertices\n vector<vector<bool> > vvis(n, vector<bool>(n, false));\n for(int i=0; i<n; i++){\n vvis[i][i] = true;\n for(int j=i+1; j<n; j++){\n L ray(poly[i], poly[j]);\n if(isVisible(ray, poly)){\n vvis[i][j] = vvis[j][i] = true;\n }\n }\n }\n\n //vis[i][j]=L(p1, p2);\n //from ith vertex, between p1 and p2 is visible\n vector<vector<L> > vis(n, vector<L>(n));\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n vis[i][j][0] = max(poly[j],poly[(j+1)%n]);\n vis[i][j][1] = min(poly[j],poly[(j+1)%n]);\n }\n }\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n L edge(poly[j], poly[(j+1)%n]);\n if(vvis[i][j] && vvis[i][(j+1)%n]){\n vis[i][j][0] = min(edge[0], edge[1]);\n vis[i][j][1] = max(edge[0], edge[1]);\n continue;\n }\n \n for(int k=0; k<n; k++){\n if(i==k || !vvis[i][k]) continue;\n L ray(poly[i], poly[k]);\n if(isParallel(ray, edge) || !intersectLS(ray, edge)) continue; \n P target = crosspointLL(ray, edge);\n if(abs(poly[i]-target) < abs(poly[k]-target)) continue;\n if(isVisible(L(poly[k], target), poly)){\n vis[i][j][0] = min(vis[i][j][0], target);\n vis[i][j][1] = max(vis[i][j][1], target);\n }\n }\n }\n }\n\n vector<vector<P> > cut(n);\n for(int i=0; i<n; i++){ //edge\n for(int j=0; j<n; j++){\n cut[i].push_back(vis[j][i][0]);\n cut[i].push_back(vis[j][i][1]);\n }\n sort(cut[i].begin(), cut[i].end());\n cut[i].erase(unique(cut[i].begin(), cut[i].end()), cut[i].end());\n }\n \n vector<bitset<MAX_PART> > cover(n);\n int offset=0;\n for(int i=0; i<n; i++){ //edge\n for(int j=0; j<n; j++){ //vertex\n if(vis[j][i][0] < vis[j][i][1]){ \n int s=0,e=0;\n for(int k=0; k<(int)cut[i].size(); k++){\n if(vis[j][i][0] == cut[i][k]){\n s = k;\n }\n if(vis[j][i][1] == cut[i][k]){\n e = k;\n break;\n\n }\n }\n for(int k=s; k<e; k++){\n cover[j][offset+k] = 1;\n }\n }\n }\n offset += cut[i].size() -1;\n }\n \n bitset<MAX_PART> allbits;\n for(int i=0; i<offset; i++) allbits[i]=1;\n\n //brute force\n int ans = (n+1)/2; //obvious upper bound\n for(int i=0; i<(1<<n); i++){\n if(bitcount(i) > ans) continue;\n bitset<MAX_PART> tmp;\n for(int j=0; j<n; j++){\n if((i&(1<<j)) != 0){\n tmp |= cover[j];\n }\n }\n if(tmp == allbits){\n ans = bitcount(i);\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3196, "score_of_the_acc": -0.0405, "final_rank": 2 }, { "submission_id": "aoj_0265_2620637", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <cmath>\n#include <bitset>\nusing namespace std;\n\n#define MAX_PART 512\n\nconst double EPS = 1e-10;\nconst double INF = 1e12;\n#define LE(n,m) ((n) < (m) + EPS)\n#define GE(n,m) ((n) + EPS > (m))\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : VP{\n L(const P& a, const P& b){ resize(2); at(0)=a; at(1)=b; }\n L(){ resize(2); }\n};\nnamespace std{\n bool operator < (const P& a, const P& b){\n return (a.X!=b.X) ? a.X<b.X : a.Y<b.Y;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) <-EPS) return -1; //cw\n if(dot(b,c) < EPS) return +2; //c-a-b\n if(norm(b) < norm(c)) return -2; //a-b-c\n return 0; //a-c-b\n}\nbool sameLL(const L &l, const L &m) {\n return ( abs(cross(l[1]-l[0], m[0]-l[0])) < EPS ) &&\n ( abs(cross(l[1]-l[0], m[0]-l[0])) < EPS );\n}\nbool intersectSP(const L& s, const P& p){\n return abs(s[0]-p) +abs(s[1]-p) -abs(s[1]-s[0]) < EPS;\n}\nbool intersectSS(const L& s, const L& t){\n for(int i=0; i<2; i++){\n for(int j=0; j<2; j++){\n if(s[i]==t[j]) return true;\n }\n }\n return ( ccw(s[0],s[1],t[0]) *ccw(s[0],s[1],t[1]) <= 0 ) &&\n ( ccw(t[0],t[1],s[0]) *ccw(t[0],t[1],s[1]) <= 0 );\n}\nbool intersectLS(const L& l, const L& s){\n return cross(l[1]-l[0], s[0]-l[0])*\n cross(l[1]-l[0], s[1]-l[0]) < EPS;\n}\nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B /A *(m[1]-m[0]);\n}\n\nbool isParallel(const P &a, const P &b){\n return abs(cross(a,b)) < EPS;\n}\nbool isParallel(const L &a, const L &b){\n return isParallel(a[1]-a[0], b[1]-b[0]);\n}\n\n//???????¨?\nbool in_poly(const P &p, const VP &poly){\n int n = poly.size();\n int cn=0;\n //??????????????????true\n for(int i=0; i<n; i++){\n if(intersectSP(L(poly[i], poly[(i+1)%n]), p)){\n return true;\n }\n }\n L ray(p, p+P(INF, 0));\n for(int i=0; i<n; i++){\n if((poly[i].Y <= p.Y && poly[(i+1)%n].Y > p.Y) ||\n (poly[i].Y > p.Y && poly[(i+1)%n].Y <= p.Y)){\n if(intersectSS(ray, L(poly[i],poly[(i+1)%n]))){\n cn++;\n }\n }\n }\n return cn%2 != 0;\n}\n\n//???????¨?\n//l????????????????§???¢???????????????????????¨??§???????????¨???????????????\nbool isVisible(const L &l, const VP &poly){\n int n = poly.size();\n VP cp;\n for(int i=0; i<n; i++){\n L edge(poly[i], poly[(i+1)%n]);\n if(!isParallel(l, edge) && intersectSS(l, edge)){\n cp.push_back(crosspointLL(l, edge));\n }\n }\n sort(cp.begin(), cp.end());\n \n bool ret = true;\n for(int i=0; i<(int)cp.size()-1; i++){\n //???????????????????????????????????????????????§????§???¢?????¨???????????????ok\n if(!in_poly((cp[i]+cp[i+1])/2.0, poly)){\n ret = false;\n break;\n }\n }\n return ret;\n}\n\nint bitcount(int n){\n n = (n & 0x55555555) + (n >> 1 & 0x55555555);\n n = (n & 0x33333333) + (n >> 2 & 0x33333333);\n n = (n & 0x0f0f0f0f) + (n >> 4 & 0x0f0f0f0f);\n n = (n & 0x00ff00ff) + (n >> 8 & 0x00ff00ff);\n return (n & 0x0000ffff) + (n >>16 & 0x0000ffff);\n}\n\n\nint main(){\n while(1){\n int n;\n cin >> n;\n if(n==0) break;\n \n VP poly(n);\n for(int i=0; i<n; i++){\n int x,y;\n cin >> x >> y;\n poly[i] = P(x,y);\n }\n\n\n //???????????????????????°???????????????\n vector<vector<bool> > vvis(n, vector<bool>(n, false));\n for(int i=0; i<n; i++){\n vvis[i][i] = true;\n for(int j=i+1; j<n; j++){\n L ray(poly[i], poly[j]);\n if(isVisible(ray, poly)){\n vvis[i][j] = vvis[j][i] = true;\n }\n }\n }\n\n //cout << intersectSS(L(poly[0], poly[6]), L(poly[0], poly[1])) << endl;\n \n //????????§???????????????\n /*\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n cerr << vvis[i][j] << \" \";\n }\n cerr << endl;\n }\n cerr << endl;\n continue;\n */\n\n \n\n //vis[i][j]????§????\n //vis[i][j]=L(p1, p2);\n //i????????????????????????j???????????????p1??????p2???????????????????????????\n vector<vector<L> > vis(n, vector<L>(n));\n //?????????\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n vis[i][j][0] = max(poly[j],poly[(j+1)%n]);\n vis[i][j][1] = min(poly[j],poly[(j+1)%n]);\n }\n }\n \n //i?????????????????????j???????????????\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n L edge(poly[j], poly[(j+1)%n]);\n //??????????????????????????????????°????????????????\n if(vvis[i][j] && vvis[i][(j+1)%n]){\n vis[i][j][0] = min(edge[0], edge[1]);\n vis[i][j][1] = max(edge[0], edge[1]);\n continue;\n }\n \n //?????´???i-k????????????\n for(int k=0; k<n; k++){\n if(i==k || !vvis[i][k]) continue;\n L ray(poly[i], poly[k]);\n //????¨??¨????\n if(isParallel(ray, edge) || !intersectLS(ray, edge)) continue;\n \n P target = crosspointLL(ray, edge);\n //?????´?????????(i->k?????¶???????????§????????£??????)\n if(abs(poly[i]-target) < abs(poly[k]-target)) continue;\n\n if(isVisible(L(poly[k], target), poly)){\n vis[i][j][0] = min(vis[i][j][0], target);\n vis[i][j][1] = max(vis[i][j][1], target);\n }\n }\n }\n }\n //????????§???????????????\n /*\n for(int i=0; i<n; i++){\n for(int j=0; j<n; j++){\n cerr << vis[i][j][0] << \" \" << vis[i][j][1] << endl;\n }\n cerr << endl;\n }\n cerr << endl;\n continue;\n */\n \n //???????????¨?????????????????????\n //???????????????????????°??????????????????????????§?????????????????¨?????????bitset???\n vector<vector<P> > cut(n);\n for(int i=0; i<n; i++){ //???i????????????\n //L edge(poly[i], poly[(i+1)%n]);\n for(int j=0; j<n; j++){\n cut[i].push_back(vis[j][i][0]);\n cut[i].push_back(vis[j][i][1]);\n }\n sort(cut[i].begin(), cut[i].end());\n cut[i].erase(unique(cut[i].begin(), cut[i].end()), cut[i].end());\n }\n\n //?????????\n /*\n for(int i=0; i<n; i++){\n cout << cut[i].size() << endl;\n for(int j=0; j<(int)cut[i].size(); j++){\n cout << cut[i][j] << endl;\n }\n }\n continue;\n */\n\n \n vector<bitset<MAX_PART> > cover(n);\n int offset=0;\n for(int i=0; i<n; i++){ //???i????????????\n for(int j=0; j<n; j++){ //??????j????????????\n if(vis[j][i][0] < vis[j][i][1]){ \n int s=0,e=0;\n for(int k=0; k<(int)cut[i].size(); k++){\n if(vis[j][i][0] == cut[i][k]){\n s = k;\n }\n if(vis[j][i][1] == cut[i][k]){\n e = k;\n break;\n\n }\n }\n for(int k=s; k<e; k++){\n cover[j][offset+k] = 1;\n }\n }\n }\n offset += cut[i].size() -1;\n }\n\n //?????????\n /*\n for(int i=0; i<n; i++){\n int offset = 0;\n for(int k=0; k<n; k++){\n for(int j=0; j<(int)cut[k].size()-1; j++){\n cout << cover[i][offset+j] << \" \";\n }\n offset += cut[k].size()-1;\n cout << \" | \";\n }\n cout << endl;\n }\n continue;\n */\n \n bitset<MAX_PART> allbits;\n for(int i=0; i<offset; i++) allbits[i]=1;\n\n //???????????§?????????????????¨??¢?´¢\n int ans = (n+1)/2; //????????????????¨????????????°??????????????¶????????????\n for(int i=0; i<(1<<n); i++){\n //?????????????????£??????????????°???ans??\\???????????°????????????\n if(bitcount(i) > ans) continue;\n bitset<MAX_PART> tmp;\n //?????????????????£???????????¨????????§???????????????\n for(int j=0; j<n; j++){\n if((i&(1<<j)) != 0){\n tmp |= cover[j];\n }\n }\n //????????¨?????????????????§????????????????????°ans?????´??°\n if(tmp == allbits){\n ans = bitcount(i);\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3184, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0265_2475443", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n#define rep(i, n) for ( int i = 0; i < (int)n; i++ )\n#define EPS (1e-8)\n#define equals(a, b) (fabs((a) - (b)) < EPS )\n#define dle(a, b) (equals(a, b) || a < b )\ntypedef pair<int, pair<int, int> > Triple;\n\nstatic const double PI = acos(-1);\n\nclass Point{\n public:\n double x, y;\n Point (double x = 0, double y = 0): x(x), y(y){ }\n\n Point operator + ( Point p ){ return Point(x + p.x, y + p.y); }\n Point operator - ( Point p ){ return Point(x - p.x, y - p.y); }\n Point operator * ( double a ){ return Point(x*a, y*a); }\n Point operator / ( double a ){ return Point(x/a, y/a); }\n\n double abs() { return sqrt(norm());}\n double norm() { return x*x + y*y; }\n\n bool operator < ( const Point &p ) const {return x != p.x ? x < p.x : y < p.y;}\n bool operator == ( const Point &p ) const { return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;}\n};\n\ntypedef Point Vector;\n\nclass Segment{\n public:\n Point p1, p2;\n Segment(Point s = Point(), Point t = Point()): p1(s), p2(t){}\n};\n\nclass SegmentSet{\n public:\n Point p1, p2;\n vector<Point> in;\n vector<int> v;\n SegmentSet(Point s = Point(), Point t = Point()): p1(s), p2(t){}\n void addIntermediate(Point p){ in.push_back(p); }\n void normalize(){\n in.push_back(p1);\n in.push_back(p2);\n sort(in.begin(), in.end());\n vector<Point>::iterator end_it = unique(in.begin(), in.end());\n in.erase(end_it, in.end());\n v.resize(in.size());\n }\n void reset(){\n for ( int i = 0; i < v.size(); i++ ) v[i] = 0;\n }\n bool valid(){\n for ( int i = 0; i < v.size()-1; i++ ) if ( !v[i]) return false;\n return true;\n }\n void print(){\n for ( int i = 0; i < in.size(); i++ ){\n cout << in[i].x << \",\" << in[i].y << endl;\n }\n }\n};\n\ntypedef Segment Line;\ntypedef vector<Point> Polygon;\n\ndouble norm( Vector a ){ return a.x*a.x + a.y*a.y; }\ndouble abs( Vector a ){ return sqrt(norm(a)); }\nPoint polar( double a, double r ){ return Point(cos(r)*a, sin(r)*a);}\ndouble getDistance( Vector a, Vector b ){ return abs(a - b); }\ndouble dot( Vector a, Vector b ){ return a.x*b.x + a.y*b.y; }\ndouble cross( Vector a, Vector b ){ return a.x*b.y - a.y*b.x; }\ndouble arg(Vector p){ return atan2(p.y, p.x); }\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw( Point p0, Point p1, Point p2 ){\n Vector a = p1 - p0;\n Vector b = p2 - p0;\n if ( cross(a, b) > EPS ) return COUNTER_CLOCKWISE;\n if ( cross(a, b) < -EPS ) return CLOCKWISE;\n if ( dot(a, b) < -EPS ) return ONLINE_BACK;\n if ( norm(a) < norm(b) ) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\nbool isIntersect(Point p1, Point p2, Point p3, Point p4){\n return ( ccw(p1, p2, p3) * ccw(p1, p2, p4) <= 0 &&\n ccw(p3, p4, p1) * ccw(p3, p4, p2) <= 0 );\n}\n\nbool isIntersect(Segment s1, Segment s2){\n return isIntersect(s1.p1, s1.p2, s2.p1, s2.p2);\n}\n\nbool isParallel( Vector a, Vector b ){\n return equals( cross(a, b), 0.0 );\n}\n\nbool isParallel( Point a1, Point a2, Point b1, Point b2){\n return isParallel( a1 - a2, b1 - b2 );\n}\n\nbool isParallel( Segment s1, Segment s2){\n return isParallel( s1.p1, s1.p2, s2.p1, s2.p2);\n}\n\nPoint getCrossPoint(Segment s1, Segment s2){\n assert( isIntersect(s1, s2) );\n Vector base = s2.p2 - s2.p1;\n double d1 = abs(cross(base, s1.p1 - s2.p1));\n double d2 = abs(cross(base, s1.p2 - s2.p1));\n double t = d1/(d1 + d2);\n return s1.p1 + (s1.p2 - s1.p1)*t;\n}\n\nPoint getCrossPointLines( Line s1, Line s2){\n Vector a = s1.p2 - s1.p1;\n Vector base = s2.p2 - s2.p1;\n return s1.p1 + a * cross(base, s2.p1 - s1.p1)/cross(base, a);\n}\n// angle p1 -> p0 -> p2;\ndouble getAngle(Point p0, Point p1, Point p2){\n if ( !(ccw(p0, p1, p2) == CLOCKWISE || ccw(p0, p1, p2) == COUNTER_CLOCKWISE )) return 0;\n double b = abs(p1 - p0);\n double c = abs(p2 - p0);\n double a = abs(p1 - p2);\n double r = acos((b*b+c*c-a*a)/(2*b*c));\n if ( ccw(p0, p1, p2) == CLOCKWISE ) r *= -1;\n return r;\n}\n\nbool insidePolygon(Polygon g, Point t){\n double angle = 0.0;\n rep(i, g.size()){\n Point p1 = g[i];\n Point p2 = g[(i+1)%g.size()];\n if ( ccw(p1, p2, t) == ON_SEGMENT ) return true;\n angle += getAngle(t, p1, p2);\n }\n return equals(2*acos(-1), fabs(angle) );\n}\n\nbool insidePolygonSegment(Polygon g, Segment s){\n if ( !insidePolygon(g, s.p1) || !insidePolygon(g, s.p2) ) return false;\n vector<Point> pointInSeg;\n pointInSeg.push_back(s.p1);\n pointInSeg.push_back(s.p2);\n for ( int i = 0; i < g.size(); i++ ){\n Segment ps = Segment(g[i], g[(i+1)%g.size()]);\n if ( isParallel(ps, s) ) continue;\n if ( !isIntersect(ps, s) ) continue;\n Point x = getCrossPoint(ps, s);\n if ( !(x == s.p1 || x == s.p2 || x == ps.p1 || x == ps.p2 ) ) return false;\n pointInSeg.push_back(x);\n }\n sort(pointInSeg.begin(), pointInSeg.end());\n for ( int i = 0; i < pointInSeg.size()-1; i++ ){\n Point s = pointInSeg[i];\n Point t = pointInSeg[i+1];\n Point c = Point((s.x+t.x)/2, (s.y+t.y)/2);\n if ( !insidePolygon(g, c) ) return false;\n }\n return true;\n}\n\nbool isPolygonIntersect(Polygon g1, Polygon g2){\n rep(i, g1.size()) rep(j, g2.size()) {\n if ( isIntersect(g1[i], g1[(i+1)%g1.size()],\n g2[j], g2[(j+1)%g2.size()])) return true;\n }\n rep(i, g1.size()) if ( insidePolygon(g2, g1[i]) ) return true;\n rep(i, g2.size()) if ( insidePolygon(g1, g2[i]) ) return true;\n return false;\n}\nbool isOnline(Point p1, Point p2, Point p3, Point p4){\n int c1 = ccw(p1, p2, p3);\n int c2 = ccw(p1, p2, p4);\n if ( c1 < 0 ) c1 *= -1;\n if ( c2 < 0 ) c2 *= -1;\n return c1 != 1 && c2 != 1;\n}\nbool included(Point p1, Point p2, Point p3, Point p4){\n return ccw(p3, p4, p1) == ON_SEGMENT && ccw(p3, p4, p2) == ON_SEGMENT;\n}\n// p1-p2 is the base\nbool isInsideTriangle(Point p1, Point p2, Point p3, Polygon &g){\n assert( !(p1==p2));\n if ( !insidePolygonSegment(g, Segment(p1, p2)) ) return false;\n if ( !insidePolygonSegment(g, Segment(p1, p3)) ) return false;\n if ( !insidePolygonSegment(g, Segment(p2, p3)) ) return false;\n return true;\n}\n\nbool segmentVisible(Point p1, Point p2, bool used[], Polygon &g){\n for ( int i = 0; i < g.size(); i++ ){\n if ( !used[i] ) continue;\n if ( isInsideTriangle(p1, p2, g[i], g) ) return true;\n }\n return false;\n}\n\nbool visible(bool used[], vector<SegmentSet> &S, Polygon &g, vector<vector<pair<int, int> > > &C){\n for ( int i = 0; i < S.size(); i++ ) S[i].reset();\n for ( int i = 0; i < g.size(); i++ ){\n if ( !used[i] ) continue;\n for ( int k = 0; k < C[i].size(); k++ ){\n pair<int, int> p = C[i][k];\n S[p.first].v[p.second] = 1;\n }\n }\n for ( int i = 0; i < S.size(); i++ ) if ( !S[i].valid() ) return false;\n return true;\n}\n\nvoid rec(int pos, int cnt, vector<SegmentSet> &S, bool used[], int &minv, Polygon &g, vector<vector<pair<int, int> > > &C){\n if ( cnt > minv ) return;\n if ( pos == g.size() ){\n if ( visible(used, S, g, C) ) minv = min(minv, cnt);\n return;\n }\n rec(pos+1, cnt, S, used, minv, g, C);\n used[pos] = true;\n rec(pos+1, cnt+1, S, used, minv, g, C);\n used[pos] = false;\n}\n\nvoid compute(Polygon g){\n vector<SegmentSet> S;\n rep(i, g.size()) S.push_back(SegmentSet(g[i], g[(i+1)%g.size()]));\n for ( int i = 0; i < g.size()-1; i++ ){\n for ( int j = i+1; j < g.size(); j++ ){\n if ( g[i] == g[j] ) continue;\n Line base = Line(g[i], g[j]);\n for ( int k = 0; k < S.size(); k++ ){\n if ( isParallel(base.p1, base.p2, S[k].p1, S[k].p2) ) continue;\n Point x = getCrossPointLines(Line(base.p1, base.p2), Line(S[k].p1, S[k].p2));\n if ( ccw(S[k].p1, S[k].p2, x) == ON_SEGMENT) S[k].addIntermediate(x);\n }\n }\n }\n for ( int i = 0; i < S.size(); i++ ) S[i].normalize();\n\n vector<vector<pair<int, int> > > C;\n C.resize(g.size());\n\n for ( int i = 0; i < S.size(); i++ ){\n for ( int j = 0; j < S[i].in.size()-1; j++ ){\n for ( int k = 0; k < g.size(); k++ ){\n Point p1 = S[i].in[j];\n Point p2 = S[i].in[j+1];\n if ( isInsideTriangle(p1, p2, g[k], g) ) {\n C[k].push_back(make_pair(i, j));\n }\n }\n }\n }\n\n bool used[20];\n int minv = g.size();\n rep(i, S.size()) used[i] = false;\n rec(0, 0, S, used, minv, g, C);\n cout << minv << endl;\n}\n\nint main(){\n int x, y;\n int n;\n int tcase = 0;\n while(1){\n cin >> n;\n if ( n == 0 ) break;\n Polygon g;\n rep(i, n){\n cin >> x >> y;\n g.push_back(Point(x, y));\n }\n compute(g);\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3480, "score_of_the_acc": -1.0452, "final_rank": 7 }, { "submission_id": "aoj_0265_2078719", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\ntypedef ld Weight;\nstruct Edge {\n\tint src, dest;\n\tint cap, rev;\n\tWeight weight;\n\tbool operator < (const Edge &rhs) const { return weight > rhs.weight; }\n};\n\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n\tbool operator==(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) < eps;\n\t}\n\tbool operator!=(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) > eps;\n\t}\n}\n\n// ????????\\???\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,c??????????¨???¨?????????????????¶\n//-1: a,b,c???????¨???¨?????????????????¶\n// 2: c,a,b???????????´???????????¶\n//-2: a,b,c???????????´???????????¶\n// 0: a,c,b???????????´???????????¶\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//???????±??????????????????????\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n/* 0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), all(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\trep(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n//???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\trep(i, n) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tPolygon poly;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tpoly.push_back(Point(x, y));\n\t\t}\n\t\tvector<Point>sects(poly);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tLine l1(poly[i], poly[(i + 1) % N]);\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tLine l2(poly[j], poly[(j + 1) % N]);\n\t\t\t\tauto ps = is_ll2(l1, l2);\n\t\t\t\tif (ps.size() == 1) {\n\t\t\t\t\tif (isis_sp(l1, ps[0])) {\n\n\t\t\t\t\t\tsects.push_back(ps[0]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(sects.begin(), sects.end());\n\t\tsects.erase(unique(sects.begin(), sects.end()), sects.end());\n\t\t{\n\t\t\tvector<Point>nextsects(sects);\n\t\t\tfor (int i = 0; i < sects.size(); ++i) {\n\t\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\t\tPoint p((sects[i] + sects[j]) / 2.l);\n\t\t\t\t\tbool ok = false;\n\t\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\t\tLine l(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\t\tif (isis_sp(l, p))ok = true;\n\t\t\t\t\t}\n\t\t\t\t\tif (ok)nextsects.emplace_back(p);\n\t\t\t\t}\n\t\t\t}\n\t\t\tsects = nextsects;\n\t\t}\n\t\tsort(sects.begin(), sects.end());\n\t\tsects.erase(unique(sects.begin(), sects.end()), sects.end());\n\t\t\n\t\tvector<vector<int>>oks(N, vector<int>(sects.size()));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t//Line l1(poly[i], poly[(i + 1) % N]);\n\t\t\t//Line l2(poly[i], poly[(i + N - 1) % N]);\n\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\tLine l(poly[i], sects[j]);\n\t\t\t\tbool ok = true;\n\t\t\t\tvector<Point>aps;\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tLine edge(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\tif (abs(cross(edge.b - edge.a, l.b - l.a))<eps) {\n\n\t\t\t\t\t}\n\t\t\t\t\telse if(isis_ss(l,edge)){\n\t\t\t\t\t\tPoint p(is_ll(l, edge));\n\t\t\t\t\t\taps.emplace_back(p);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsort(aps.begin(), aps.end());\n\t\t\t\t\n\t\t\t\tfor (int k = 0; k < int(aps.size()) - 1; ++k) {\n\t\t\t\t\tif (!is_in_Polygon(poly, (aps[k] + aps[k + 1]) / (2.l))) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\toks[i][j] = ok;\n\t\t\t}\n\t\t}\n\t\tint ans = 16;\n\t\tfor (int i = 0; i < (1 << N); ++i) {\n\t\t\tbitset<16>bs(i);\n\t\t\tvector<int>cats(sects.size());\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tif (bs[j]) {\n\t\t\t\t\tfor (int k = 0; k < sects.size(); ++k) {\n\t\t\t\t\t\tcats[k] |= oks[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (count(cats.begin(), cats.end(), 0) == 0)ans = min(ans,int( bs.count()));\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 3244, "score_of_the_acc": -0.3133, "final_rank": 3 }, { "submission_id": "aoj_0265_2078715", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\ntypedef ld Weight;\nstruct Edge {\n\tint src, dest;\n\tint cap, rev;\n\tWeight weight;\n\tbool operator < (const Edge &rhs) const { return weight > rhs.weight; }\n};\n\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n\tbool operator==(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) < eps;\n\t}\n\tbool operator!=(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) > eps;\n\t}\n}\n\n// ????????\\???\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,c??????????¨???¨?????????????????¶\n//-1: a,b,c???????¨???¨?????????????????¶\n// 2: c,a,b???????????´???????????¶\n//-2: a,b,c???????????´???????????¶\n// 0: a,c,b???????????´???????????¶\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//???????±??????????????????????\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n/* 0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), all(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\trep(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n//???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\trep(i, n) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tPolygon poly;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tpoly.push_back(Point(x, y));\n\t\t}\n\t\tvector<Point>sects(poly);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tLine l1(poly[i], poly[(i + 1) % N]);\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tLine l2(poly[j], poly[(j + 1) % N]);\n\t\t\t\tauto ps = is_ll2(l1, l2);\n\t\t\t\tif (ps.size() == 1) {\n\t\t\t\t\tif (isis_sp(l1, ps[0])) {\n\n\t\t\t\t\t\tsects.push_back(ps[0]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>>oks(N, vector<int>(sects.size()));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t//Line l1(poly[i], poly[(i + 1) % N]);\n\t\t\t//Line l2(poly[i], poly[(i + N - 1) % N]);\n\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\tLine l(poly[i], sects[j]);\n\t\t\t\tbool ok = true;\n\t\t\t\tvector<Point>aps;\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tLine edge(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\tif (abs(cross(edge.b - edge.a, l.b - l.a))<eps) {\n\n\t\t\t\t\t}\n\t\t\t\t\telse if(isis_ss(l,edge)){\n\t\t\t\t\t\tPoint p(is_ll(l, edge));\n\t\t\t\t\t\taps.emplace_back(p);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsort(aps.begin(), aps.end());\n\t\t\t\t\n\t\t\t\tfor (int k = 0; k < int(aps.size()) - 1; ++k) {\n\t\t\t\t\tif (!is_in_Polygon(poly, (aps[k] + aps[k + 1]) / (2.l))) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\toks[i][j] = ok;\n\t\t\t}\n\t\t}\n\t\tint ans = 16;\n\t\tfor (int i = 0; i < (1 << N); ++i) {\n\t\t\tbitset<16>bs(i);\n\t\t\tvector<int>cats(sects.size());\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tif (bs[j]) {\n\t\t\t\t\tfor (int k = 0; k < sects.size(); ++k) {\n\t\t\t\t\t\tcats[k] |= oks[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (count(cats.begin(), cats.end(), 0) == 0)ans = min(ans,int( bs.count()));\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3244, "score_of_the_acc": -0.2278, "final_rank": 14 }, { "submission_id": "aoj_0265_2078713", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\ntypedef ld Weight;\nstruct Edge {\n\tint src, dest;\n\tint cap, rev;\n\tWeight weight;\n\tbool operator < (const Edge &rhs) const { return weight > rhs.weight; }\n};\n\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n\tbool operator==(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) < eps;\n\t}\n\tbool operator!=(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) > eps;\n\t}\n}\n\n// ????????\\???\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,c??????????¨???¨?????????????????¶\n//-1: a,b,c???????¨???¨?????????????????¶\n// 2: c,a,b???????????´???????????¶\n//-2: a,b,c???????????´???????????¶\n// 0: a,c,b???????????´???????????¶\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//???????±??????????????????????\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n/* 0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), all(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\trep(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n//???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\trep(i, n) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tPolygon poly;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tpoly.push_back(Point(x, y));\n\t\t}\n\t\tvector<Point>sects(poly);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tLine l1(poly[i], poly[(i + 1) % N]);\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tLine l2(poly[j], poly[(j + 1) % N]);\n\t\t\t\tauto ps = is_ll2(l1, l2);\n\t\t\t\tif (ps.size() == 1) {\n\t\t\t\t\tif (isis_sp(l1, ps[0])) {\n\n\t\t\t\t\t\tsects.push_back(ps[0]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>>oks(N, vector<int>(sects.size()));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t//Line l1(poly[i], poly[(i + 1) % N]);\n\t\t\t//Line l2(poly[i], poly[(i + N - 1) % N]);\n\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\tLine l(poly[i], sects[j]);\n\t\t\t\tbool ok = true;\n\t\t\t\tvector<Point>aps;\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tLine edge(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\tif (abs(cross(edge.b - edge.a, l.b - l.a))<eps) {\n\n\t\t\t\t\t}\n\t\t\t\t\telse if(isis_ss(l,edge)){\n\t\t\t\t\t\tPoint p(is_ll(l, edge));\n\t\t\t\t\t\taps.emplace_back(p);\n\t\t\t\t\t\tif ( l.a!=p&&l.b!=p&&edge.a!=p&&edge.b!=p) {\n\t\t\t\t\t\t\tok = false;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsort(aps.begin(), aps.end());\n\t\t\t\t\n\t\t\t\tfor (int k = 0; k < int(aps.size()) - 1; ++k) {\n\t\t\t\t\tif (!is_in_Polygon(poly, (aps[k] + aps[k + 1]) / (2.l))) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\toks[i][j] = ok;\n\t\t\t}\n\t\t}\n\t\tint ans = 16;\n\t\tfor (int i = 0; i < (1 << N); ++i) {\n\t\t\tbitset<16>bs(i);\n\t\t\tvector<int>cats(sects.size());\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tif (bs[j]) {\n\t\t\t\t\tfor (int k = 0; k < sects.size(); ++k) {\n\t\t\t\t\t\tcats[k] |= oks[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (count(cats.begin(), cats.end(), 0) == 0)ans = min(ans,int( bs.count()));\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3236, "score_of_the_acc": -0.2008, "final_rank": 13 }, { "submission_id": "aoj_0265_2078707", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\ntypedef ld Weight;\nstruct Edge {\n\tint src, dest;\n\tint cap, rev;\n\tWeight weight;\n\tbool operator < (const Edge &rhs) const { return weight > rhs.weight; }\n};\n\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n\tbool operator==(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) < eps;\n\t}\n\tbool operator!=(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) > eps;\n\t}\n}\n\n// ????????\\???\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,c??????????¨???¨?????????????????¶\n//-1: a,b,c???????¨???¨?????????????????¶\n// 2: c,a,b???????????´???????????¶\n//-2: a,b,c???????????´???????????¶\n// 0: a,c,b???????????´???????????¶\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//???????±??????????????????????\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n/* 0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), all(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\trep(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n//???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\trep(i, n) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tPolygon poly;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tpoly.push_back(Point(x, y));\n\t\t}\n\t\tvector<Point>sects(poly);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tLine l1(poly[i], poly[(i + 1) % N]);\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tLine l2(poly[j], poly[(j + 1) % N]);\n\t\t\t\tauto ps = is_ll2(l1, l2);\n\t\t\t\tif (ps.size() == 1) {\n\t\t\t\t\tif (isis_sp(l1, ps[0])) {\n\n\t\t\t\t\t\tsects.push_back(ps[0]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>>oks(N, vector<int>(sects.size()));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t//Line l1(poly[i], poly[(i + 1) % N]);\n\t\t\t//Line l2(poly[i], poly[(i + N - 1) % N]);\n\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\tLine l(poly[i], sects[j]);\n\t\t\t\tbool ok = true;\n\t\t\t\tvector<Point>aps;\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tLine edge(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\tif (abs(cross(edge.b - edge.a, l.b - l.a))<eps) {\n\n\t\t\t\t\t}\n\t\t\t\t\telse if(isis_ss(l,edge)){\n\t\t\t\t\t\tPoint p(is_ll(l, edge));\n\t\t\t\t\t\taps.emplace_back(p);\n\t\t\t\t\t\tif ( l.a!=p&&l.b!=p&&edge.a!=p&&edge.b!=p) {\n\t\t\t\t\t\t\tok = false;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsort(aps.begin(), aps.end());\n\t\t\t\tfor (int i = 0; i < int(aps.size()) - 1; ++i) {\n\t\t\t\t\tif (!is_in_Polygon(poly, (aps[i] + aps[i + 1]) / (2.l))) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\toks[i][j] = ok;\n\t\t\t}\n\t\t}\n\t\tint ans = 16;\n\t\tfor (int i = 0; i < (1 << N); ++i) {\n\t\t\tbitset<16>bs(i);\n\t\t\tvector<int>cats(sects.size());\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tif (bs[j]) {\n\t\t\t\t\tfor (int k = 0; k < sects.size(); ++k) {\n\t\t\t\t\t\tcats[k] |= oks[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (count(cats.begin(), cats.end(), 0) == 0)ans = min(ans,int( bs.count()));\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3208, "score_of_the_acc": -0.1062, "final_rank": 12 }, { "submission_id": "aoj_0265_2078665", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\ntypedef ld Weight;\nstruct Edge {\n\tint src, dest;\n\tint cap, rev;\n\tWeight weight;\n\tbool operator < (const Edge &rhs) const { return weight > rhs.weight; }\n};\n\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef complex<ld> Point;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define all(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n\tbool operator==(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) < eps;\n\t}\n\tbool operator!=(const Point &lhs, const Point &rhs) {\n\t\treturn abs(rhs - lhs) > eps;\n\t}\n}\n\n// ????????\\???\nPoint input_Point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// ccw\n// 1: a,b,c??????????¨???¨?????????????????¶\n//-1: a,b,c???????¨???¨?????????????????¶\n// 2: c,a,b???????????´???????????¶\n//-2: a,b,c???????????´???????????¶\n// 0: a,c,b???????????´???????????¶\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.b - l.a) / norm(l.a - l.b);\n\treturn l.a + t * (l.b - l.a);\n}\n\n//???????±??????????????????????\nPoint reflect(const Line &l, const Point &p) {\n\tPoint pr = proj(l, p);\n\treturn pr * 2.l - p;\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n//??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n/* 0 => out\n1 => on\n2 => in*/\nint is_in_Circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint Circle_in_Circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), all(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_Circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\trep(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n//????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n/*0 => out\n1 => on\n2 => in*/\nint is_in_Polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\trep(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { out, on, in };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n//???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n//????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon q;\n\tPolygon r;\n\trep(i, n) {\n\t\tPoint a = ps[i], b = ps[(i + 1) % n];\n\t\tLine m = Line(a, b);\n\t\tif (ccw(l.a, l.b, a) != -1) q.push_back(a);\n\t\tif (ccw(l.a, l.b, a) != 1) r.push_back(a);\n\t\tif (ccw(l.a, l.b, a) * ccw(l.a, l.b, b) < 0 && isis_ll(l, m)) {\n\t\t\tq.push_back(is_ll(l, m));\n\t\t\tr.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ q,r };\n\treturn polys;\n}\n\n\nint main() {\n\twhile (1) {\n\t\tint N; cin >> N;\n\t\tif (!N)break;\n\t\tPolygon poly;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tpoly.push_back(Point(x, y));\n\t\t}\n\t\tvector<Point>sects(poly);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tLine l1(poly[i], poly[(i + 1) % N]);\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tLine l2(poly[j], poly[(j + 1) % N]);\n\t\t\t\tauto ps = is_ll2(l1, l2);\n\t\t\t\tif (ps.size() == 1) {\n\t\t\t\t\tif (isis_sp(l1, ps[0])) {\n\n\t\t\t\t\t\tsects.push_back(ps[0]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<vector<int>>oks(N, vector<int>(sects.size()));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t//Line l1(poly[i], poly[(i + 1) % N]);\n\t\t\t//Line l2(poly[i], poly[(i + N - 1) % N]);\n\t\t\tfor (int j = 0; j < sects.size(); ++j) {\n\t\t\t\tLine l(poly[i], sects[j]);\n\t\t\t\tbool ok = true;\n\t\t\t\tfor (int k = 0; k < N; ++k) {\n\t\t\t\t\tLine edge(poly[k], poly[(k + 1) % N]);\n\t\t\t\t\tif (abs(cross(edge.b - edge.a, l.b - l.a))<eps) {\n\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tPoint p(is_ll(l, edge));\n\t\t\t\t\t\tif (isis_ss(l,edge)&& l.a!=p&&l.b!=p&&edge.a!=p&&edge.b!=p) {\n\t\t\t\t\t\t\tok = false;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tfor (ld n = 0.025; n < 1; n += 0.05) {\n\t\t\t\t\t\t\tif (!is_in_Polygon(poly, l.a*n + l.b*(1. - n)))ok = false;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\toks[i][j] = ok;\n\t\t\t}\n\t\t}\n\t\tint ans = 16;\n\t\tfor (int i = 0; i < (1 << N); ++i) {\n\t\t\tbitset<16>bs(i);\n\t\t\tvector<int>cats(sects.size());\n\t\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t\tif (bs[j]) {\n\t\t\t\t\tfor (int k = 0; k < sects.size(); ++k) {\n\t\t\t\t\t\tcats[k] |= oks[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (count(cats.begin(), cats.end(), 0) == 0)ans = min(ans,int( bs.count()));\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 3990, "memory_kb": 3268, "score_of_the_acc": -1.2838, "final_rank": 20 } ]
aoj_0268_cpp
金剛の型 以下のように、右から 7 ビット分が小数部、続く24 ビット分が整数部で、一番左の 1 ビット分を符号部とする 32 ビット実数型を考える(b 1 , ... , b 32 は 0 か1 を表す)。 この形式を、人が理解しやすい 10 進数表現に直すときは、以下のように解釈する。 (-1) 符号部 × (整数部 + 小数部) 上の表現で、整数部の値は b 8 + 2 1 ×b 9 + 2 2 ×b 10 + ... + 2 23 ×b 31 になる。例えば整数部が のようになっていた場合、整数部の値は以下のように計算される。 1 + 2 1 + 2 3 = 1 + 2 + 8 = 11 一方、小数部の値は(0.5) 1 ×b 7 +(0.5) 2 ×b 6 + ... + (0.5) 7 × b 1 になる。例えば小数部が のようになっていた場合、小数部は以下のように計算される。 0.5 1 + 0.5 3 = 0.5 + 0.125 = 0.625 さらに、符号部、整数部、小数部を合わせた以下のようなビット列の場合、 ビット列全体が表す10 進数は、以下のようになる(ただし、-1 の0 乗は1)。 (-1) 0 × (1 + 2 + 8 + 0.5 + 0.125) = 1 × (11.625) = 11.625 32 ビットのビット列を Q 個入力すると、それらのビット列が表す実数の10 進表記を一切の誤差無く出 力するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 Q s 1 s 2 . . . s Q 1 行目にビット列の数 Q (1 ≤ Q ≤ 10000)が与えられる。続くQ 行に入力ビット列 s i が与えられる。 入力ビット列は 16 進数表記で与えられるとする (例: 0111 1111 1000 1000 0000 0000 0000 0000 は 7f880000 と与えられる) 。つまり、Q 行のそれぞれには、2 進数を 4 ビット分ずつまとめた 16 進数が 8 個、空白をはさまずに並んでいる。10 進数、2 進数、16 進数の対応は以下の表のとおりである。 16 進数の英字 a から f までは小文字で与えられる。 出力 各ビット列が表す実数の 10 進表記を 1 行ずつ出力する。ただし、小数部において、ある桁以下がすべて 0 の場合、その桁以下は省略するものとするが、例外として小数部が 0 の場合は小数部には 0 ひとつを出力する。 入力例 8 00000000 80000000 00000080 00000040 000000c0 00000100 80000780 80000f70 出力例 0.0 -0.0 1.0 0.5 1.5 2.0 -15.0 -30.875
[ { "submission_id": "aoj_0268_10848234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n int Q;\n cin >> Q;\n while(Q--) {\n string s;\n cin >> s;\n int n = 0;\n for(int i=0; i<8; ++i) {\n n <<= 4;\n if(isdigit(s[i])) {\n n += s[i] - '0';\n } else {\n n += s[i] - 'a' + 10;\n }\n }\n double res = 0;\n double d = 1;\n {\n int t = n & ((1LL << 31) - 1);\n res += (t >> 7);\n }\n int cnt = 1;\n for(int i=6; i>=0; --i) {\n d /= 2;\n if(n & (1 << i)) {\n res += d;\n cnt = 6 - i + 1;\n }\n }\n cout << fixed << setprecision(cnt);\n if(n & (1 << 31)) {\n cout << -res << endl;\n } else {\n cout << res << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3608, "score_of_the_acc": -0.3241, "final_rank": 11 }, { "submission_id": "aoj_0268_4513672", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\ndouble Value;\nstring HexInput, BinaryInput;\n\nconst string ConvertTable[16] = {\n\t\"0000\",\"0001\",\"0010\",\"0011\",\n\t\"0100\",\"0101\",\"0110\",\"0111\",\n\t\"1000\",\"1001\",\"1010\",\"1011\",\n\t\"1100\",\"1101\",\"1110\",\"1111\",\n};\n\n\nvoid changeToBinary() {\n\tint index;\n\n\tBinaryInput = \"\";\n\tfor (int i = 0; i < 8; ++i) {\n\t\tswitch (HexInput[i]) {\n\t\t\tcase 'a':index = 10; break;\n\t\t\tcase 'b':index = 11; break;\n\t\t\tcase 'c':index = 12; break;\n\t\t\tcase 'd':index = 13; break;\n\t\t\tcase 'e':index = 14; break;\n\t\t\tcase 'f':index = 15; break;\n\t\t\tdefault :index = HexInput[i] - '0'; break;\n\t\t}\n\t\tBinaryInput += ConvertTable[index];\n\t}\n\treverse(BinaryInput.begin(), BinaryInput.end());\n\t//cout << \"outBinary:\" << BinaryInput << endl;\n}\n\nvoid solve() {\n\tint countOfFraction;\n\t\n\tValue = 0;\n\tcountOfFraction = 1;\n\tfor (int i = 0; i < 7; ++i) {\n\t\tif (BinaryInput[6-i] != '0') {\n\t\t\tValue += pow(0.5, i + 1);\n\t\t\tcountOfFraction = i + 1;\n\t\t}\n\t}\n\t//cout << Value << \" : cnt=\" << countOfFraction << endl;\n\n\tfor (int i = 7; i < 31; ++i) {\n\t\tif (BinaryInput[i] != '0') {\n\t\t\tValue += pow(2, i-7);\n\t\t}\n\t}\n\tif (BinaryInput[31] == '1') {\n\t\tcout << \"-\";\n\t}\n\tcout << fixed << setprecision(countOfFraction) << Value << endl;\n}\n\nint main() {\n\tint n;\n\n\tcin >> n;\n\tfor (int i = 0; i < n; ++i) {\n\t\tcin >> HexInput;\n\t\tchangeToBinary();\n\t\tsolve();\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3420, "score_of_the_acc": -0.5764, "final_rank": 18 }, { "submission_id": "aoj_0268_4357868", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <sstream>\n\nusing namespace std;\n\nint main() {\n\n int q;\n cin >> q;\n\n while ( q-- ) {\n\n\tunsigned int b;\n\tcin >> hex >> b;\n\n\tdouble res = (b&0x7fffffff) >> 7;//整数部の値で初期化\n\t\n\t//小数部を加算\n\tdouble frac = 0.5;\n\tfor ( int i=6; i>=0; --i ) {\n\t if ( (b>>i)&1 ) res += frac;\n\t frac *= 0.5;\n\t}\n\n\t//フォーマット\n\tstringstream ss;\n\tss << setprecision(15) << fixed << res;\n\tstring s = ss.str();\n\tfor ( int i=s.size()-1; i>0; --i ) {\n\t if ( s[i] != '0' ) {\n\t\ts.erase( i+1, s.size() );\n\t\tbreak;\n\t }\n\t}\n\t \n\tcout << ((b>>31)?\"-\":\"\") << s << ((b&0x0000007f)?\"\":\"0\") << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3272, "score_of_the_acc": -0.5126, "final_rank": 17 }, { "submission_id": "aoj_0268_4041265", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nconst int INF = 1e9;\nconst ll LINF = 1e18;\ninline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }\ninline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << \"(\" << o.first << \",\" << o.second << \")\"; return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<T>& V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << \" \";} return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<vector<T> >& Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const map<S,T>& mp){ out << \"{ \"; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << \":\" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << \", \"; } out << \" }\"; return out; }\ntemplate<typename T>vector<T> make_v(size_t a){return vector<T>(a);}\ntemplate<typename T,typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\n/*\n <url:>\n 問題文============================================================\n =================================================================\n 解説=============================================================\n ================================================================\n */\n\ntemplate<class Type>\nType solve(Type res = Type()){\n ll s;\n cin >> hex >> s;\n \n if((s>>31)&1) cout << \"-\";\n \n ll Kassa1 = (s & 0x7FFFFFFF) >> 7; // 整数部分\n ll Kassa2 = (s & 0x0000007F); // 小数部分\n \n double ans = Kassa1;\n \n int saisyouno_keta = 0;\n for(int i = 0; i < 7;i++){\n if((Kassa2 >> (6-i))&1){\n ans += pow(0.5,i+1);\n saisyouno_keta = i;\n }\n }\n \n cout << fixed << setprecision(saisyouno_keta+1) << ans << endl;\n return ans;\n}\nint main(void) {\n cin.tie(0); ios_base::sync_with_stdio(false);\n // solve(0);\n \n int Q; cin >> Q;\n while(Q--){\n solve(0);\n // cout << fixed << setprecision(15) << solve<double>() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3416, "score_of_the_acc": -0.2414, "final_rank": 10 }, { "submission_id": "aoj_0268_3900709", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\nsigned main(){\n\tint n; cin >> n;\n\twhile(n--){\n\t\tstring s;\n\t\tcin >> s;\n\t\tvector<int> bit;\n\n\t\tfor(int i = 0;i < 8;i++){\n\t\t\tint b;\n\t\t\tif(s[i] < 'a'){\n\t\t\t\tb = s[i] - '0';\n\t\t\t}else{\n\t\t\t\tb = s[i] - 'a' + 10;\n\t\t\t}\n\t\t\n\t\t\tstack<int> st;\n\t\t\tfor(int j = 0;j < 4;j++){\n\t\t\t\tst.push(b % 2);\n\t\t\t\tb /= 2;\n\t\t\t}\n\t\t\twhile(!st.empty()){\n\t\t\t\tbit.push_back(st.top());\n\t\t\t\tst.pop();\n\t\t\t}\n\t\t}\n\t\t\n\t\treverse(bit.begin(), bit.end());\n\t\t\n\t\t\n\t\tdouble ans = 0;\n\t\tdouble ans2 =0;\n\t\tdouble tmp = 0.5;\n\t\tfor(int i = 6;i >= 0;i--){\n\t\t\tif(bit[i]){\n\t\t\t\tans += tmp;\n\t\t\t}\n\t\t\ttmp /= 2;\n\t\t}\n\t\t\n\t\tint ansnum = 0;\n\t\tint ttmp = 1;\n\t\tfor(int i = 7;i < 31;i++){\n\t\t\tif(bit[i]) ansnum += ttmp;\n\t\t\tttmp *= 2;\n\t\t}\n\t\t\n\t\tans2 = ans;\n\t\tans += ansnum;\n\t\tif(bit[31] == 1){\n\t\t\tcout << '-';\n\t\t}\n\t\tcout << ansnum;\n\t\tcout << \".\";\n\t\tdo{\n\t\t\tint tmp = ans2 * 10;\n\t\t\tcout << tmp;\n\t\t\tans2 *= 10;\n\t\t\tans2 -= tmp;\n\t\t}while(ans2 != 0);\n\t\tcout << endl;\n\t\t\t\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3180, "score_of_the_acc": -0.473, "final_rank": 13 }, { "submission_id": "aoj_0268_3678143", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <numeric>\n#include <stdio.h>\n\nusing namespace std;\n\nint main() {\n\n\tint q;\n\tcin >> q;\n\tvector<string> s(q);\n\tfor (int i = 0; i < q; i++) cin >> s[i];\n\n\t// 16進数\n\tvector<double> ans(q, 0.0);\n\n\tvector<vector<int>> beg(q, vector<int>(32, 0));\n\n\t// 2進数に直す?\n\tfor (int i = 0; i < q; i++) {\n\t\t//cout << i << endl;\n\t\tfor (int j = 7; j >= 0; j--) {\n\t\t\tint value;\n\n\t\t\tswitch (s[i][j]) { // めちゃきたない\n\t\t\tcase 'a':\n\t\t\t\tvalue = 10;\n\t\t\t\tbreak;\n\t\t\tcase 'b':\n\t\t\t\tvalue = 11;\n\t\t\t\tbreak;\n\t\t\tcase 'c':\n\t\t\t\tvalue = 12;\n\t\t\t\tbreak;\n\t\t\tcase 'd':\n\t\t\t\tvalue = 13;\n\t\t\t\tbreak;\n\t\t\tcase 'e':\n\t\t\t\tvalue = 14;\n\t\t\t\tbreak;\n\t\t\tcase 'f':\n\t\t\t\tvalue = 15;\n\t\t\t\tbreak;\n\t\t\tdefault:\n\t\t\t\tvalue = s[i][j] - '0';\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t//cout << value << endl;\n\n\t\t\tint tmp = 8;\n\t\t\tfor (int k = 0; k < 4; k++) {\n\t\t\t\tif (value >= tmp) {\n\t\t\t\t\tbeg[i][(7 - j) * 4 + 3 - k] = 1;\n\t\t\t\t\tvalue -= tmp;\n\t\t\t\t}\n\t\t\t\ttmp /= 2;\n\t\t\t}\n\t\t}\n\t}\n\n\t/*\n\tfor (int i = 0; i < q; i++) {\n\t\tfor (int j = 0; j < 32; j++) {\n\t\t\tif (j % 4 == 0) cout << \" \";\n\t\t\tcout << beg[i][31 - j];\n\t\t}\n\t\tcout << endl;\n\t}*/\n\n\tvector<bool> syou(q, false);\n\n\t// こっから計算\n\tfor (int i = 0; i < q; i++) {\n\t\tdouble cnt = 1.0;\n\t\tfor (int j = 7; j >= 0; j--) {\n\t\t\t// 小数点の計算\n\t\t\tif (beg[i][j] == 1) {\n\t\t\t\tans[i] += cnt;\n\t\t\t\tif(j != 7)\n\t\t\t\t\tsyou[i] = true;\n\t\t\t}\n\t\t\tcnt *= 0.5;\n\t\t}\n\n\t\tcnt = 2.0;\n\t\tfor (int j = 8; j < 31; j++) {\n\t\t\t// 整数の計算\n\t\t\tif (beg[i][j] == 1) {\n\t\t\t\tans[i] += cnt;\n\t\t\t}\n\t\t\tcnt *= 2.0;\n\t\t}\n\n\t\t// 最後に符号\n\t\tif (beg[i][31] == 1)\n\t\t\tans[i] *= -1.0;\n\t}\n\n\t// .0が必要\n\tfor (int i = 0; i < q; i++) {\n\t\tif (beg[i][0] == 1) printf(\"%.7lf\\n\", ans[i]);\n\t\telse if (beg[i][1] == 1) printf(\"%.6lf\\n\", ans[i]);\n\t\telse if (beg[i][2] == 1) printf(\"%.5lf\\n\", ans[i]);\n\t\telse if (beg[i][3] == 1) printf(\"%.4lf\\n\", ans[i]);\n\t\telse if (beg[i][4] == 1) printf(\"%.3lf\\n\", ans[i]);\n\t\telse if (beg[i][5] == 1) printf(\"%.2lf\\n\", ans[i]);\n\t\telse printf(\"%.1lf\\n\", ans[i]);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5176, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_0268_3678121", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring calc(char s){\n if(s == '0') return \"0000\";\n if(s == '1') return \"0001\";\n if(s == '2') return \"0010\";\n if(s == '3') return \"0011\";\n if(s == '4') return \"0100\";\n if(s == '5') return \"0101\";\n if(s == '6') return \"0110\";\n if(s == '7') return \"0111\";\n if(s == '8') return \"1000\";\n if(s == '9') return \"1001\";\n if(s == 'a') return \"1010\";\n if(s == 'b') return \"1011\";\n if(s == 'c') return \"1100\";\n if(s == 'd') return \"1101\";\n if(s == 'e') return \"1110\";\n if(s == 'f') return \"1111\";\n}\n\nint main(){\n int q; cin>>q;\n while(q--){\n string s; cin>>s;\n string t = \"\";\n for(int i=0; i<8; i++){\n t += calc(s[i]);\n }\n\n int ans1 = 0;\n int num1 = (1 << 23);\n for(int i=1; i<=24; i++){\n ans1 += (t[i] == '1') * num1;\n num1 /= 2;\n }\n\n double ans2 = 0.0;\n double num2 = 0.5;\n for(int i=25; i<=31; i++){\n ans2 += (t[i] == '1') * num2;\n num2 /= 2;\n }\n\n if(t[0] == '1') cout << \"-\";\n if(ans2 == 0.0){\n cout << ans1 << \".0\" << endl;\n }\n else{\n double ans3 = 1. * ans1 + ans2;\n printf(\"%.20g\\n\", ans3);\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -0.1845, "final_rank": 7 }, { "submission_id": "aoj_0268_3678045", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\n#define int long long int\nconst int INF = 1001001001001001LL;\nconst int MOD = 1000000007;\n\nstring f(char c){\n if(c == '0') return \"0000\";\n if(c == '1') return \"0001\";\n if(c == '2') return \"0010\";\n if(c == '3') return \"0011\";\n if(c == '4') return \"0100\";\n if(c == '5') return \"0101\";\n if(c == '6') return \"0110\";\n if(c == '7') return \"0111\";\n if(c == '8') return \"1000\";\n if(c == '9') return \"1001\";\n if(c == 'a') return \"1010\";\n if(c == 'b') return \"1011\";\n if(c == 'c') return \"1100\";\n if(c == 'd') return \"1101\";\n if(c == 'e') return \"1110\";\n if(c == 'f') return \"1111\";\n return \"error\";\n}\n\nint hgoe(int huga){\n if(huga == 0) return 5000000;\n if(huga == 1) return 2500000;\n if(huga == 2) return 1250000;\n if(huga == 3) return 625000;\n if(huga == 4) return 312500;\n if(huga == 5) return 156250;\n if(huga == 6) return 78125;\n}\n\nstring g1(char c){\n if(c == '1') return \"-\";\n else return \"\";\n}\n\nstring g2(string s){\n reverse(s.begin(), s.end());\n double mul = 1;\n int ret = 0;\n for(int i = 0; i < (int)s.size(); i++){\n ret += mul * (s[i] == '1');\n mul *= 2;\n }\n \n \n return to_string(ret);\n}\n\nstring g3(string s){\n int ret = 0;\n for(int i = 0; i < (int)s.size(); i++){\n ret += hgoe(i) * (s[i] == '1');\n }\n\n string str = to_string(ret);\n while(str.size() != 7) str = \"0\" + str;\n\n while(str.size() != 1){\n if(str.back() == '0') str.pop_back();\n else break;\n }\n return str;\n}\n\nsigned main(){\n \n int n; cin >> n;\n for(int i_ = 0; i_ < n; i_++){\n string s; cin >> s;\n string bin;\n for(int i = 0; i < 8; i++){\n bin = bin + f(s[i]);\n }\n cout << g1(bin[0]) << g2(bin.substr(1, 24)) << \".\" << g3(bin.substr(25, 7)) << endl;\n }\n \n \n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -0.4971, "final_rank": 15 }, { "submission_id": "aoj_0268_3677591", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n#define rep(i,n) for(int i = 0 ; i < n ; ++i)\nusing ll = long long;\n\nvoid solve(){\n string s;\n cin>>s;\n ll cur = 0;\n rep(i,s.size()){\n cur*=16;\n if('0'<=s[i]&&s[i]<='9')cur+=s[i]-'0';\n else cur+=s[i]-'a'+10;\n }\n bool sgn = false;\n if(cur>=1ll<<31){\n cur-=1ll<<31;\n sgn = true;\n }\n rep(i,7)cur*=5;\n if(sgn)cout<<\"-\";\n cout<<cur/10000000;\n cout<<\".\";\n string ans = \"\";\n bool ok = false;\n rep(i,7){\n if(cur%10!=0||ok){\n ans = (char)(cur%10+'0')+ans;\n ok=true;\n }\n cur/=10;\n }\n if(ans==\"\")ans=\"0\";\n cout<<ans<<endl;\n}\n\nint main(){\n int n;\n cin>>n;\n while(n--)solve();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3204, "score_of_the_acc": -0.15, "final_rank": 3 }, { "submission_id": "aoj_0268_3447557", "code_snippet": "#include <iostream>\n#include <bitset>\n#include <cmath>\n#include <iomanip>\nusing namespace std;\nstring syodu(int s){\n int ret = 78125*s;\n while(ret % 10 == 0)ret/=10;\n string zero;\n if(s == 1)zero = \"00\";\n else if(s <= 12)zero = \"0\";\n return zero+to_string(ret);\n}\nint main(){\n int q;cin>>q;\n for(int i = 0; q > i; i++){\n long long ans = 0;\n int syosu = 0;\n bool seihu = true;\n char b[8];for(int j = 0; 8 > j; j++)cin>>b[j];\n for(int j = 0; 8 > j; j++){\n bitset<4>tm = b[j];\n if(b[j] >= 'a'){\n tm = 10+(b[j]-'a');\n }\n if(tm[3]){\n if (j == 0) {\n seihu = false;\n }else if(j <= 6){\n ans += pow(2,(6-j)*4);\n }else{\n syosu+=8;\n }\n }\n if(tm[2]){\n if(j <= 5){\n ans += pow(2,((5-j)*4+3));\n }else{\n if(j == 6)syosu+=64;\n if(j == 7)syosu+=4;\n }\n }\n if(tm[1]){\n if(j <= 5){\n ans += pow(2,((5-j)*4+2));\n }else{\n if(j == 6)syosu += 32;\n if(j == 7)syosu += 2;\n }\n }\n if(tm[0]){\n if(j <= 5){\n ans += pow(2,((5-j)*4+1));\n }else{\n if(j == 6)syosu += 16;\n if(j == 7)syosu += 1;\n }\n }\n \n }\n if(!seihu)cout << '-';\n if(syosu == 0){\n cout << fixed << ans << \".0\" << endl;\n }else{\n cout << fixed << ans << \".\" << syodu(syosu) << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3408, "score_of_the_acc": -0.2379, "final_rank": 9 }, { "submission_id": "aoj_0268_3447426", "code_snippet": "// includes {{{\n#include<iostream>\n#include<iomanip>\n#include<algorithm>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<map>\n#include<set>\n#include<tuple>\n#include<cmath>\n#include<random>\n#include<cassert>\n#include<bitset>\n#include<cstdlib>\n// #include<deque>\n// #include<multiset>\n// #include<cstring>\n// #include<bits/stdc++.h>\n// }}}\nusing namespace std;\nusing ll = long long;\n\nint main() {\n std::ios::sync_with_stdio(false), std::cin.tie(0);\n\n map<char, int> mp;\n\n for(int i = 0; i < 10; i++) mp['0' + i] = i;\n for(int i = 0; i < 6; i++) mp['a' + i] = 10 + i;\n\n int q;\n cin >> q;\n\n cout << showpoint;\n for(int i = 0; i < q; i++) {\n string s;\n cin >> s;\n signed x = 0;\n int sgn = 1;\n for(int j = 0; j < 8; j++) {\n int v = mp[s[j]];\n if(j == 0 && (v & 8)) {\n v ^= 8;\n sgn = -1;\n }\n x += v << ((7 - j) * 4);\n }\n double ans = sgn * (double(x) / (1 << 7));\n stringstream ss;\n // ss << showpoint;\n ss << fixed << setprecision(10);\n ss << ans;\n string g;\n ss >> g;\n while(g[g.size()-1] == '0' && g[g.size()-2] != '.') g.pop_back();\n cout << g << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.1759, "final_rank": 5 }, { "submission_id": "aoj_0268_3335080", "code_snippet": "#include <iostream>\n#include <iomanip>\nusing namespace std;\n\nint main()\n{\n\tint q;\n\n\tcin >> q;\n\n\tfor (int i = 0; i < q; i++) {\n\t\tlong long s;\n\t\tlong double t;\n\n\t\tcin >> hex >> s;\n\n\t\tif (s > 0x80000000 - 1)\n\t\t\tcout << \"-\";\n\n\t\ts %= 0x80000000;\n\t\tt = s;\n\t\tt /= 128;\n\n\t\tif (s % 128 != 0)\n\t\t\tcout << setprecision(20) << t << endl;\n\t\telse\n\t\t\tcout << t << \".0\" << endl;\t\t\t\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3252, "score_of_the_acc": -0.1707, "final_rank": 4 }, { "submission_id": "aoj_0268_3328655", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<iostream>\nusing namespace std;\n\nint hextodec(char c){\n if(c <= '9') return c-'0';\n return 10 + c-'a';\n}\n\nstring dec(char x){\n int num = hextodec(x);\n string res = \"\";\n for(int i = 0; i < 4; i++){\n if(num & (1<<i)) res += \"1\";\n else res += \"0\";\n }\n reverse(res.begin(), res.end());\n return res;\n}\n\n\nint main(){\n int bias[32] = {};\n for(int i = 1; i < 25; i++){\n bias[i] = 1<<(24-i);\n }\n bias[25] = 5000000;\n for(int i = 26; i < 32; i++){\n bias[i] = bias[i-1]/2;\n }\n\n int q;\n cin >> q;\n \n string s;\n\n while(q-- > 0){\n cin >> s;\n string bin = \"\";\n for(char c : s) bin += dec(c);\n int a = 0, b = 0;\n for(int i = 1; i < 25; i++){\n if(bin[i] == '1') a += bias[i];\n }\n for(int i = 25; i < 32; i++){\n if(bin[i] == '1') b += bias[i];\n }\n\n string sb = to_string(b);\n while(sb.length() != 7) sb = \"0\" + sb;\n while(sb.length() > 0 && sb[sb.length()-1] == '0') sb = sb.substr(0, sb.length()-1);\n if(sb == \"\") sb = \"0\";\n \n if(bin[0] == '1') cout << \"-\";\n cout << a << \".\" << sb << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3224, "score_of_the_acc": -0.492, "final_rank": 14 }, { "submission_id": "aoj_0268_3050800", "code_snippet": "#include<iostream>\n#include<ios>\nusing namespace std;\nint n;\nint f(char c)\n{\n\tif(c<='9')return c-'0';\n\telse return c-'a'+10;\n}\nmain()\n{\n\tcin>>n;\n\tfor(;n--;)\n\t{\n\t\tstring s;cin>>s;\n\t\tbool hugou=0;\n\t\tint d;\n\t\tdouble a;\n\t\thugou=f(s[0])/8;\n\t\td=f(s[0])%8;\n\t\tfor(int i=1;i<=5;i++)\n\t\t{\n\t\t\td=d*16+f(s[i]);\n\t\t}\n\t\td=d*2+f(s[6])/8;\n\t\ta=f(s[6])%8*16+f(s[7]);\n\t\tif(hugou)cout<<'-';\n\t\tif(a==0)cout<<d<<\".0\";\n\t\telse printf(\"%.15g\",d+a/128);\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3288, "score_of_the_acc": -0.1862, "final_rank": 8 }, { "submission_id": "aoj_0268_2602385", "code_snippet": "#include <cstdio>\n#include <math.h>\n\nint Q;\nunsigned int bit;\nchar ch[9];\ndouble ans;\n\nunsigned cnv(char c){\n\tif(c >= '0' && c <= '9'){\n\t\treturn c - '0';\n\t}\n\telse{\n\t\treturn (c - 'a') + 10;\n\t}\n}\n\nint main(){\n\tscanf(\"%d\",&Q);\n\tfor(int I = 0; I < Q; I++){\n\t\tscanf(\"%s\",ch);\n\t\tbit = 0;\n\t\tans = 0;\n\t\tfor(int i = 0; i < 8; i++){\n\t\t\tunsigned k = cnv(ch[i]);\n\t\t\tbit |= (k << (4*(7-i)));\n\t\t}\n\t\tfor(int i = 0; i < 31; i++){\n\t\t\tif(bit & (1<<i)){\n\t\t\t\tans += pow(2,i-7);\n\t\t\t}\n\t\t}\n\t\tif(bit & (1<<31)){\n\t\t\tprintf(\"-\");\n\t\t}\n\t\tif(bit & ((1<<7)-1)){\n\t\t\tchar msg[8] = \"%.1f\\n\";\n\t\t\tfor(int i = 0; i < 7; i++){\n\t\t\t\tif(bit & (1<<i)){\n\t\t\t\t\tmsg[2] = '0' + (7-i);\n\t\t\t\t\tprintf(msg,ans);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\n\t\t}\n\t\telse{\n\t\t\tprintf(\"%.1f\\n\",ans);\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2856, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0268_2546407", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint etot(char a) {\n if(a >= 'a') {\n return a - 'a' + 10;\n } else {\n return a - '0';\n }\n}\n\nint main() {\n \n int q;\n string s;\n\n cin >> q;\n\n for(int k = 0; k < q; ++k) {\n\n cin >> s;\n\n unsigned int b = 0;\n for(int i = 0; i < 8; ++i) {\n b |= etot(s[7 - i]) << 4 * i;\n }\n\n if(b >> 31 & 1) cout << \"-\";\n\n cout << ((b >> 7) & ((1 << 24) - 1));\n\n int under_point = 0;\n int w = 78125;\n for(int i = 0; i < 7; ++i) {\n if((b >> i) & 1) {\n under_point += w;\n }\n w *= 2;\n }\n\n cout << \".\";\n\n if(under_point) {\n int d = 7;\n while(!(under_point % 10)) {\n under_point /= 10;\n --d;\n }\n printf(\"%0*d\\n\", d, under_point);\n } else {\n cout << \"0\" << endl;\n }\n\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.1759, "final_rank": 5 }, { "submission_id": "aoj_0268_2341937", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nstring to_bit(string s){\n\tstring ret = \"\";\n\tfor(int i = 0;i < 8;i++){\n\t\tint t;\n\t\tif(s[i] <= '9' && s[i] >= '0') t = s[i] - '0';\n\t\telse t = s[i] - 'a' + 10;\n\t\tfor(int j = 0;j < 4;j++){\n\t\t\tif(t >> (3 - j) & 1) ret += to_string(1);\n\t\t\telse ret += to_string(0);\n\t\t}\n\t}\n\treturn ret;\n}\n\nint main(){\n\tint q;\n\tcin >> q;\n\tfor(int i = 0;i < q;i++){\n\t\tlong double ans = 0.0;\n\t\tstring s;\n\t\tcin >> s;\n\t\ts = to_bit(s);\n\t\tif(s[0] == '1') cout << \"-\";\n\t\tfor(int j = 1;j < 25;j++){\n\t\t\tans *= 2.0;\n\t\t\tif(s[j] == '1') ans += 1.0;\n\t\t}\n\t\tlong double add = 0.5;\n\t\tfor(int j = 25;j < 32;j++){\n\t\t\tif(s[j] == '1') ans += add;\n\t\t\tadd /= 2.0;\n\t\t}\n\t\tcout << (int)ans << \".\";\n\t\tdo{\n\t\t\tans -= (int)ans;\n\t\t\tans *= 10.0;\n\t\t\tcout << (int)ans;\n\t\t}while((ans - (int)ans) > 1e-9);\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3264, "score_of_the_acc": -1.1759, "final_rank": 20 }, { "submission_id": "aoj_0268_2255668", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n int Q;\n cin >> Q;\n while( Q-- ) {\n string s = \"\";\n for(int i=0; i<8; i++) {\n char c;\n cin >> c;\n if( c == '0' ) s += \"0000\";\n if( c == '1' ) s += \"0001\";\n if( c == '2' ) s += \"0010\";\n if( c == '3' ) s += \"0011\";\n if( c == '4' ) s += \"0100\";\n if( c == '5' ) s += \"0101\";\n if( c == '6' ) s += \"0110\";\n if( c == '7' ) s += \"0111\";\n if( c == '8' ) s += \"1000\";\n if( c == '9' ) s += \"1001\";\n if( c == 'a' ) s += \"1010\";\n if( c == 'b' ) s += \"1011\";\n if( c == 'c' ) s += \"1100\";\n if( c == 'd' ) s += \"1101\";\n if( c == 'e' ) s += \"1110\";\n if( c == 'f' ) s += \"1111\";\n // cout << s << endl;\n } \n \n long long int sum = 0;\n long double sum2 = 0;\n for(int i=24; i>0; i--) {\n if( s[i] == '1' ) {\n sum += pow(2.0, 24-i);\n }\n }\n for(int i=25; i<32; i++) {\n if( s[i] == '1' ) {\n sum2 += pow(0.5, i-25+1);\n }\n }\n \n long long int tmp = (long long int)sum2;\n if( sum2 - (long double)tmp > 0 ) {\n if( s[0] == '1' ) {\n cout << '-';\n }\n string add = \"\";\n while( 1 ) {\n if( sum2 == 0 ) break;\n sum2 *= 10;\n tmp = (long long int)sum2;\n add += '0' + tmp;\n sum2 -= (long double)tmp;\n }\n \n cout << sum << '.' << add << endl;\n } else {\n if( s[0] == '1' ) {\n cout << '-';\n }\n cout << sum << \".0\" << endl; \n }\n }\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3156, "score_of_the_acc": -0.1293, "final_rank": 2 }, { "submission_id": "aoj_0268_2254674", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n;\n cin>>n;\n while(n--){\n int o=0;\n double d=0.0,w=2147483648.0;\n for(int i=0;i<8;i++)w/=2;\n string s;\n cin>>s;\n for(int i=0;i<8;i++){\n int p;\n if(s[i]>='0'&&s[i]<='9')p=s[i]-'0';\n else p=s[i]-'a'+10;\n int ss[4]={};\n for(int j=3;j>=0;j--)ss[j]=(p>>j)&1;\n for(int j=3;j>=0;j--){//cout<<w<<endl;\n\tif(!i&&j==3){if(ss[j])o++;}\n\telse{\n\t if(ss[j])d+=w;\n\t w/=2.0;\n\t if(w==0)w=0.5;//cout<<w<<endl;\n\t}\n }\n }\n if(o)cout<<'-';\n if(d-(long int)d){\n printf(\"%.99g\\n\",d);\n }\n else{\n printf(\"%ld\",(long int)d);cout<<\".0\"<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3256, "score_of_the_acc": -0.5057, "final_rank": 16 }, { "submission_id": "aoj_0268_2254381", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n int Q;\n cin >> Q;\n while( Q-- ) {\n string s = \"\";\n for(int i=0; i<8; i++) {\n char c;\n cin >> c;\n if( c == '0' ) s += \"0000\";\n if( c == '1' ) s += \"0001\";\n if( c == '2' ) s += \"0010\";\n if( c == '3' ) s += \"0011\";\n if( c == '4' ) s += \"0100\";\n if( c == '5' ) s += \"0101\";\n if( c == '6' ) s += \"0110\";\n if( c == '7' ) s += \"0111\";\n if( c == '8' ) s += \"1000\";\n if( c == '9' ) s += \"1001\";\n if( c == 'a' ) s += \"1010\";\n if( c == 'b' ) s += \"1011\";\n if( c == 'c' ) s += \"1100\";\n if( c == 'd' ) s += \"1101\";\n if( c == 'e' ) s += \"1110\";\n if( c == 'f' ) s += \"1111\";\n // cout << s << endl;\n } \n\n long long int sum = 0;\n long double sum2 = 0;\n for(int i=24; i>0; i--) {\n if( s[i] == '1' ) {\n\tsum += pow(2.0, 24-i);\n }\n }\n for(int i=25; i<32; i++) {\n if( s[i] == '1' ) {\n\tsum2 += pow(0.5, i-25+1);\n }\n }\n \n long long int tmp = (long long int)sum2;\n if( sum2 - (long double)tmp > 0 ) {\n if( s[0] == '1' ) {\n\tcout << '-';\n }\n string add = \"\";\n while( 1 ) {\n\tif( sum2 == 0 ) break;\n\tsum2 *= 10;\n\ttmp = (long long int)sum2;\n\tadd += '0' + tmp;\n\tsum2 -= (long double)tmp;\n }\n\t\n cout << sum << '.' << add << endl;\n } else {\n if( s[0] == '1' ) {\n\tcout << '-';\n }\n cout << sum << \".0\" << endl; \n }\n }\n \n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3176, "score_of_the_acc": -0.4713, "final_rank": 12 } ]
aoj_0269_cpp
風よ、私の梅の香りを届けておくれ! 引っ越しが決まり、この地を去ることになった。この土地自体に未練は無いが、1つだけ気になることがある。それは、庭に植えた梅の木のことだ。私は毎年、この梅が花を咲かすことを楽しみにしていた。ここを離れた後は春の楽しみが1つ減ってしまう。私の梅の香りだけでも風に乗って引っ越し先の家まで届き、春を楽しませてはくれないものか。 日本には春を象徴する3つの花がある。梅・桃・桜の3つだ。引っ越し先には、私の梅以外にも、これらの花の香りが届くだろう。しかし、私の梅の香りだけが届く日数が最も多い家に住みたい。 図のように、花の香りは扇状に広がり、その領域は風の向かう方向と強さによって決まる。扇形は風の向かう方向 w を中心にして対称に広がり、風の強さ a を半径とする領域をもつ。香りが広がる角度 d は花の種類によって決まっているが、風の向かう方向と強さは日によって異なる。ただし、同じ日では、すべての場所で風の向かう方向と強さは同じである。 手元には、私の梅以外の梅・桃・桜の位置と花の種類ごとの香りが広がる角度、引っ越し先の家の候補のデータがある。さらに、数日分の風の向かう方向と強さのデータもある。私の梅以外の梅・桃・桜の木と家の位置は、私の梅の位置を原点とした座標で示されている。 これらのデータを使って、私の梅の香りだけが届く日数の最も多い家を探すためのプログラムを書いてみることとしよう。私は有能なプログラマーなのだから! 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。各データセットは以下の形式で与えられる。 H R hx 1 hy 1 hx 2 hy 2 : hx H hy H U M S du dm ds ux 1 uy 1 ux 2 uy 2 : ux U uy U mx 1 my 1 mx 2 my 2 : mx M my M sx 1 sy 1 sx 2 sy 2 : sx S sy S w 1 a 1 w 2 a 2 : w R a R 各行で与えられる数値は1つの空白で区切られている。 1行目に引っ越し先の家の候補の数 H (1 ≤ H ≤ 100) と風の記録の数 R (1 ≤ R ≤ 100) が与えられる。続くH 行に引っ越し先の家の位置が与えられる。hx i とhy i は i 番目の家の x 座標と y 座標を示す-1000 以上1000 以下の整数である。 続く1行に、私の梅以外の梅の木の数 U と、桃・桜の木の数 M、S、梅・桃・桜の香りが広がる角度du、dm、ds が与えられる。U、M、S の範囲は 0 以上10 以下である。角度の単位は度であり、1 以上180 未満の整数である。 続く U 行に私の梅以外の梅の木の位置、続く M 行に桃の木の位置、続く S 行に桜の木の位置が与えられる。uxi と uyi、mxi と myi、sxi と syi はそれぞれ、i 番目の梅・桃・桜の木の x 座標と y 座標を示す、-1000 以上 1000 以下の整数である。 続く R 行に風の記録が与えられる。w i (0 ≤ w i < 360) と a i (0 < a i ≤ 100) は i 日目の風の向かう方向と強さを表す整数である。風の向かう方向は、x 軸の正の向きから反時計回りに測った角度で表し、単位は度とする。 入力は以下の条件を満たすと考えてよい。 入力される座標はすべて異なるものとする。 原点には私の梅以外無い。 どの花についても、花の香りが届く領域の境界から距離が 0.001 以内には家は無い。 データセットの数は 50 を超えない。 出力 データセットごとに、私の梅の香りだけが届く日数の最も多い全ての家の番号を、小さい順に1行に出力する。家の番号の間は空白1つで区切る。行の終わりには空白文字を出力しない。 ただし、どの家についても、私の梅の花の香りだけが届く日が1日もなければ、NA と出力する。 入力例 6 3 2 1 1 2 5 2 1 3 1 5 -2 3 1 1 1 90 30 45 3 -4 -3 0 2 -2 45 6 90 6 135 6 2 1 1 3 5 2 0 1 1 90 30 45 -3 0 2 -2 45 6 0 0 出力例 5 6 NA
[ { "submission_id": "aoj_0269_4985319", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst double pi = acos(-1.0);\nclass point2d {\npublic:\n\tdouble x, y;\n\tpoint2d() : x(0.0), y(0.0) {};\n\tpoint2d(double x_, double y_) : x(x_), y(y_) {};\n\tpoint2d& operator+=(const point2d& p) { x += p.x; y += p.y; return *this; }\n\tpoint2d& operator-=(const point2d& p) { x -= p.x; y -= p.y; return *this; }\n\tpoint2d operator+(const point2d& p) const { return point2d(*this) += p; }\n\tpoint2d operator-(const point2d& p) const { return point2d(*this) -= p; }\n\tdouble abs() const { return sqrt(x * x + y * y); }\n\tdouble dot(const point2d& p) const { return x * p.x + y * p.y; }\n\tdouble cross(const point2d& p) const { return x * p.y - y * p.x; }\n};\nint main() {\n\twhile (true) {\n\t\tint H, R, U, M, S, du, dm, ds;\n\t\tcin >> H >> R;\n\t\tif (H == 0 && R == 0) break;\n\t\tvector<point2d> hickosi(H);\n\t\tfor (int i = 0; i < H; ++i) {\n\t\t\tcin >> hickosi[i].x >> hickosi[i].y;\n\t\t}\n\t\tcin >> U >> M >> S >> du >> dm >> ds;\n\t\tvector<point2d> pu(U), pm(M), ps(S);\n\t\tfor (int i = 0; i < U; ++i) {\n\t\t\tcin >> pu[i].x >> pu[i].y;\n\t\t}\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tcin >> pm[i].x >> pm[i].y;\n\t\t}\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tcin >> ps[i].x >> ps[i].y;\n\t\t}\n\t\tvector<int> W(R), A(R);\n\t\tfor (int i = 0; i < R; ++i) {\n\t\t\tcin >> W[i] >> A[i];\n\t\t}\n\t\tvector<int> ans(H);\n\t\tfor (int i = 0; i < H; ++i) {\n\t\t\tint days = 0;\n\t\t\tfor (int j = 0; j < R; ++j) {\n\t\t\t\tdouble dangle = W[j] * pi / 180;\n\t\t\t\tvector<int> list;\n\t\t\t\tfor (int k = 0; k < 1 + U + M + S; ++k) {\n\t\t\t\t\tpoint2d origin = (k == 0 ? point2d() : (k <= U ? pu[k - 1] : (k <= U + M ? pm[k - U - 1] : ps[k - U - M - 1])));\n\t\t\t\t\tdouble angle = (k <= U ? du : (k <= U + M ? dm : ds)) * pi / 180;\n\t\t\t\t\tdouble langle = dangle - angle / 2;\n\t\t\t\t\tdouble rangle = dangle + angle / 2;\n\t\t\t\t\tpoint2d lp(cos(langle), sin(langle));\n\t\t\t\t\tpoint2d rp(cos(rangle), sin(rangle));\n\t\t\t\t\tpoint2d vec = hickosi[i] - origin;\n\t\t\t\t\tif (vec.abs() <= A[j] && lp.cross(vec) >= 0.0 && rp.cross(vec) <= 0.0) {\n\t\t\t\t\t\tlist.push_back(k);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (list == vector<int>({ 0 })) {\n\t\t\t\t\t++days;\n\t\t\t\t}\n\t\t\t}\n\t\t\tans[i] = days;\n\t\t}\n\t\tint mx = *max_element(ans.begin(), ans.end());\n\t\tif (mx == 0) {\n\t\t\tcout << \"NA\" << endl;\n\t\t}\n\t\telse {\n\t\t\tint last = -1;\n\t\t\tfor (int i = 0; i < H; ++i) {\n\t\t\t\tif (ans[i] == mx) {\n\t\t\t\t\tif (last != -1) cout << ' ';\n\t\t\t\t\tcout << i + 1;\n\t\t\t\t\tlast = i;\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3580, "score_of_the_acc": -0.4626, "final_rank": 17 }, { "submission_id": "aoj_0269_3902302", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct Tree{\n\tdouble x, y, d;\n\t\n\tTree(int xx, int yy, int dd){\n\t\tx = xx;\n\t\ty = yy;\n\t\td = dd;\n\t}\n\n\tbool isOK(double hx, double hy, double w, double a){\n\t\tdouble l = w - d/2;\n\t\tdouble r = w + d/2;\n\t\tl += 360 * 4;\n\t\tr += 360 * 4;\n\t\t\n\t\tdouble kaku = atan2((hy-y),(hx-x)) * 180/M_PI;\n\t\t\n\t\twhile(l > kaku){\n\t\t\tkaku += 360;\n\t\t}\n\t\t\n\t\tif(r < kaku){\n\t\t\treturn false;\n\t\t}\n\n\t\tif(a*a >= (hy-y)*(hy-y) + (hx-x) * (hx-x)){\n\t\t\treturn true;\n\t\t}\n\t\treturn false;\n\n\t}\n};\n\n\t\n\n\nint main(){\n\n\tint h, r;\n\twhile(cin >> h >> r, h != 0){\n\t\tint x[110], y[110];\n\t\tfor(int i = 0;i < h;i++) cin >> x[i] >> y[i];\n\n\t\tint U, M, S, du, dm, ds;\n\t\tcin >> U >> M >> S >> du >> dm >> ds;\n\n\t\tTree myTree(0, 0, du);\n\t\t\n\t\tvector<Tree> tree;\n\t\tfor(int i = 0;i < U;i++){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\ttree.push_back(Tree(x, y, du));\n\t\t}\n\t\t\n\t\tfor(int i = 0;i < M;i++){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\ttree.push_back(Tree(x, y, dm));\n\t\t}\n\n\n\t\tfor(int i = 0;i < S;i++){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\ttree.push_back(Tree(x, y, ds));\n\t\t}\n\t\t\n\t\tint n = U + M + S;\n\n\t\tint cnt[110] = {};\n\t\t\n\t\tfor(int i = 0;i < r;i++){\n\t\t\tint w, a;\n\t\t\tcin >> w >> a\n;\t\t\tbool flag;\n\t\t\tfor(int j = 0;j < h;j++){\n\t\t\t\tflag = false;\n\t\t\t\tfor(int k = 0;k < n;k++){\n\t\t\t\t\tflag = (flag || tree[k].isOK(x[j], y[j], w, a));\n\t\t\t\t}\n\t\t\t\tif(!flag && myTree.isOK(x[j], y[j], w, a)){\n\t\t\t\t\tcnt[j]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<int> ans;\n\t\tint ans_num = 0;\n\t\tfor(int i = 0;i < h;i++){\n\t\t\tif(ans_num < cnt[i]){\n\t\t\t\tans.clear();\n\t\t\t\tans_num = cnt[i];\n\t\t\t\tans.push_back(i+1);\n\t\t\t}else if(ans_num == cnt[i]){\n\t\t\t\tans.push_back(i+1);\n\t\t\t}\n\t\t}\n\n\t\tif(ans_num == 0){\n\t\t\tcout << \"NA\" << endl;\n\t\t}else{\n\t\t\tfor(int i = 0;i < ans.size();i++){\n\t\t\t\tcout << ans[i];\n\t\t\t\tif(i < ans.size()-1){\n\t\t\t\t\tcout << \" \";\n\t\t\t\t}else{\n\t\t\t\t\tcout << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3388, "score_of_the_acc": -0.2054, "final_rank": 9 }, { "submission_id": "aoj_0269_2568502", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \nstruct point {\n double x, y;\n int d;\n};\n \nbool check_dst(point home, point ums, double a) {\n \n double x = home.x - ums.x;\n double y = home.y - ums.y;\n \n return x * x + y * y <= a * a;\n \n}\n \nbool check_deg(point home, point ums, double w) {\n \n double x = home.x - ums.x;\n double y = home.y - ums.y;\n double home_deg;\n double start_deg = w - ums.d / 2.0;\n double end_deg = w + ums.d / 2.0;\n \n home_deg = atan2(y, x) * 180 / M_PI;\n \n if(home_deg < 0.0) {\n home_deg += 360.0;\n }\n \n if(0.0 <= start_deg && end_deg <= 360.0) {\n return start_deg <= home_deg && home_deg <= end_deg;\n } else if(start_deg < 0.0) {\n start_deg += 360.0;\n return start_deg <= home_deg || home_deg <= end_deg;\n } else { // end_deg > 360\n end_deg -= 360.0;\n return start_deg <= home_deg || home_deg <= end_deg;\n }\n \n}\n\nbool check_reach(point home, point ums, double w, double a) {\n return check_deg(home, ums, w) && check_dst(home, ums, a);\n}\n \nint main() {\n \n int h, r;\n \n while(cin >> h >> r, h || r) {\n \n int u, m, s;\n double du, dm, ds;\n vector<point> homes, ums;\n \n for(int i = 0; i < h; ++i) {\n double x, y;\n cin >> x >> y;\n homes.push_back((point){ x, y, 0 });\n }\n \n cin >> u >> m >> s;\n cin >> du >> dm >> ds;\n \n for(int i = 0; i < u + m + s; ++i) {\n double x, y;\n cin >> x >> y;\n if(i < u) {\n ums.push_back((point){ x, y, du });\n } else if(u <= i && i < u + m) {\n ums.push_back((point){ x, y, dm });\n } else {\n ums.push_back((point){ x, y, ds });\n }\n }\n \n for(int i = 0; i < r; ++i) {\n double w, a;\n cin >> w >> a;\n for(int j = 0; j < homes.size(); ++j) {\n bool is_perfect = check_reach(homes[j], (point){ 0, 0, du }, w, a);\n for(int k = 0; k < ums.size(); ++k) {\n if(check_reach(homes[j], ums[k], w, a)) {\n is_perfect = false;\n }\n }\n homes[j].d += is_perfect;\n }\n }\n \n int max_day = 0;\n for(int i = 0; i < homes.size(); ++i) {\n max_day = max(max_day, homes[i].d);\n }\n \n if(max_day) {\n bool is_out = false;\n for(int i = 0; i < homes.size(); ++i) {\n if(homes[i].d == max_day) {\n if(is_out) cout << \" \" << i + 1;\n else cout << i + 1;\n is_out = true;\n }\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n \n }\n \n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3468, "score_of_the_acc": -0.2084, "final_rank": 10 }, { "submission_id": "aoj_0269_2318571", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define F first\n#define S second\ntypedef pair<double,double> P;\ntypedef complex<double> PP;\ndouble toRad(double agl){return agl*M_PI/180.0;}\ndouble D(P a,P b) {return sqrt((a.F-b.F)*(a.F-b.F)+(a.S-b.S)*(a.S-b.S));}\nPP rotate(PP a, double r){return PP(a.real()*cos(r)-a.imag()*sin(r),a.real()*sin(r)+a.imag()*cos(r));}\n\nbool solve(P a,P c,P b,double d) {\n double r=atan2(a.S-b.S,a.F-b.F);\n PP a2=rotate(PP(c.S,0),toRad(c.F-d/2)),a3=rotate(PP(c.S,0),toRad(c.F+d/2));\n double rl=atan2(a2.imag(),a2.real()),rr=atan2(a3.imag(),a3.real());\n if(rr<rl) rr+=2*M_PI;\n if(D(a,b)<=c.S&&(rl<=r&&r<=rr||rl<=r+M_PI*2&&r+M_PI*2<=rr)) return 1;\n return 0;\n}\n\nint main() {\n int n,n2;\n while(cin >> n >> n2 && n) {\n P a[n];\n for(int i=0; i<n; i++) cin >> a[i].F >> a[i].S;\n int U,M,S,du,dm,ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n P u[U],m[M],s[S];\n for(int i=0; i<U; i++) cin >> u[i].F >> u[i].S;\n for(int i=0; i<M; i++) cin >> m[i].F >> m[i].S;\n for(int i=0; i<S; i++) cin >> s[i].F >> s[i].S;\n P b[n2];\n for(int i=0; i<n2; i++) cin >> b[i].F >> b[i].S;\n int z=1;\n vector<int> ans;\n for(int i=0; i<n; i++) {\n int cnt=0;\n for(int j=0; j<n2; j++) {\n bool f=solve(a[i],b[j],P(0,0),du);\n for(int k=0; k<U; k++) {\n if(solve(a[i],b[j],u[k],du)) f=0;\n }\n for(int k=0; k<M; k++) {\n if(solve(a[i],b[j],m[k],dm)) f=0;\n }\n for(int k=0; k<S; k++) {\n if(solve(a[i],b[j],s[k],ds)) f=0;\n }\n cnt+=f;\n }\n if(cnt>z) {\n z=cnt;\n ans.clear();\n ans.push_back(i+1);\n } else if(cnt==z) ans.push_back(i+1);\n }\n if(!ans.size()) cout << \"NA\" << endl;\n else {\n for(int i=0; i<ans.size(); i++) {\n if(i) cout << \" \";\n cout << ans[i];\n }\n cout << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3636, "score_of_the_acc": -1.0897, "final_rank": 20 }, { "submission_id": "aoj_0269_2318506", "code_snippet": "#include<bits/stdc++.h>\n#define Pi M_PI\nusing namespace std;\n#define int long long\ntypedef complex <double> P;\ndouble dot(P a,P b){return real(conj(a)*b);}\ndouble cross(P a,P b){return imag(conj(a)*b);}\nconst double EPS = 1e-8;\n\nint ccw(P a,P b,P c){\n b-= a;\n c-=a;\n if(cross(b,c) > EPS) return 1;\n if(cross(b,c) < -EPS) return -1;\n if(dot(b,c) < -EPS ) return 2;\n if(norm(b) < norm(c)) return -2;\n return 0;\n}\n\nbool check(P a,P t,double d,P h){\n if(abs(t-h) > abs(a)) return 0;\n h-=t;\n d/=2;\n d*= Pi/180;\n P A = a * P(cos(d),sin(d));\n P B = a * conj(P(cos(d),sin(d)));\n return ccw(P(0,0),A,h)!=1&&ccw(P(0,0),B,h)!=-1;\n}\n\nsigned main(){\n while(1){\n int H,R;\n cin>>H>>R;\n if(!H&&!R)return 0;\n\n P house[101];\n for(int i=0;i<H;i++){\n double x,y;\n cin>>x>>y;\n house[i] = P(x,y);\n }\n\n int U,M,S;\n double du,dm,ds;\n cin>>U>>M>>S>>du>>dm>>ds;\n\n P UME[11],MO[11],SA[11];\n for(int i=0;i<U;i++){\n double x,y;\n cin>>x>>y;\n UME[i] = P(x,y);\n }\n\n for(int i=0;i<M;i++){\n double x,y;\n cin>>x>>y;\n MO[i] = P(x,y);\n }\n\n for(int i=0;i<S;i++){\n double x,y;\n cin>>x>>y;\n SA[i] = P(x,y);\n }\n\n int cnt[101]={};\n for(int i=0;i<R;i++){\n double w,d;\n cin>>w>>d;\n w*=Pi/180;\n P a = P(cos(w),sin(w))*d;\n \n for(int j=0;j<H;j++){\n\tbool flg = check(a,P(0,0),du,house[j]);\n\tfor(int k=0;k<U;k++)flg &= !check(a,UME[k],du,house[j]);\n\tfor(int k=0;k<M;k++)flg &= !check(a,MO[k],dm,house[j]);\n\tfor(int k=0;k<S;k++)flg &= !check(a,SA[k],ds,house[j]);\n\tcnt[j] += flg;\n }\n }\n\n int mx = 0;\n for(int i=0;i<H;i++)mx = max(mx,cnt[i]);\n\n if(mx==0) {cout<<\"NA\"<<endl;continue;}\n\n int f=0;\n for(int i=0;i<H;i++){\n if(cnt[i] == mx) {\n\tif(f)cout<<\" \";\n\tf = 1;\n\tcout<<i+1;\n }\n }\n cout<<endl;\n }\n \n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3480, "score_of_the_acc": -0.0838, "final_rank": 6 }, { "submission_id": "aoj_0269_1830635", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\ntemplate<class T>\nusing Table = vector<vector<T>>;\nconst ld eps=1e-9;\n\n/* ??????????????¬ */\n\n#include <complex>\n\ntypedef long double ld;\ntypedef complex<ld> Point;\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(),(x).end()\n\n\nconst ld pi = acos(-1.0);\nconst ld dtop = pi / 180.;\nconst ld ptod = 1. / dtop;\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n}\n\n// ????????\\???\nPoint input_point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\n// ????????????????????????\nbool eq(const ld a, const ld b) {\n\treturn (abs(a - b) < eps);\n}\n\n// ??????\nld dot(const Point& a, const Point& b) {\n\treturn real(conj(a) * b);\n}\n\n// ??????\nld cross(const Point& a, const Point& b) {\n\treturn imag(conj(a) * b);\n}\n\n// ??´????????????\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n\tPoint operator[](const int _num)const {\n\t\tif (_num == 0)return a;\n\t\telse if (_num == 1)return b;\n\t\telse {\n\t\t\tassert(false);\n\t\t\treturn Point();\n\t\t}\n\t}\n};\n\n// ????????????\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\n// CCW\nint ccw(const Point& a, const Point &b, const Point &c) {\n\tconst Point nb(b - a);\n\tconst Point nc(c - a);\n\tif (cross(nb, nc) > eps) return 1; // a,b,c??????????¨???¨?????????????????¶\n\tif (cross(nb, nc) < -eps) return -1; // a,b,c???????¨???¨?????????????????¶\n\tif (dot(nb, nc) < 0) return 2; // c,a,b???????????´???????????¶\n\tif (norm(nb) < norm(nc)) return -2; // a,b,c???????????´???????????¶\n\treturn 0; // a,c,b???????????´???????????¶\n}\n\n\n/* ???????????? */\n\n// ??´?????¨??´??????????????????\nbool isis_ll(const Line& l, const Line& m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\n// ??´?????¨?????????????????????\nbool isis_ls(const Line& l, const Line& s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\n// ????????¨?????????????????????\nbool isis_ss(const Line& s, const Line& t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\n// ????????´????????????\nbool isis_lp(const Line& l, const Point& p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\n// ?????????????????????\nbool isis_sp(const Line& s, const Point& p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\n// ??????????¶?\nPoint proj(const Line &l, const Point& p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n\n// ??´?????¨??´????????????\nPoint is_ll(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n// ??´?????¨??´????????????\nvector<Point> is_ll2(const Line &s, const Line& t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tif (cross(sv, tv) != 0)return vector<Point>(1, is_ll(s, t));\n\telse {\n\t\tvector<Point>ans;\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tif (isis_sp(s, t[k]) && find(ans.begin(), ans.end(), t[k]) == ans.end())ans.push_back(t[k]);\n\t\t\tif (isis_sp(t, s[k]) && find(ans.begin(), ans.end(), s[k]) == ans.end())ans.push_back(s[k]);\n\t\t}\n\t\treturn ans;\n\t}\n}\n// ????????¨???????????????\n//???????????£????????¨???????????¨assert(false)\nPoint is_ss(const Line &s, const Line& t) {\n\tif (isis_ss(s, t)) {\n\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\tfor (int l = 0; l < 2; ++l) {\n\t\t\t\tif (s[k] == t[l])return s[k];\n\t\t\t}\n\t\t}\n\t\treturn is_ll(s, t);\n\t}\n\telse {\n\t\t//??????isis_ss?????????\n\t\tassert(false);\n\t\treturn Point(0, 0);\n\t}\n}\n// ????????¨???????????????\nvector<Point> is_ss2(const Line &s, const Line& t) {\n\tvector<Point> kouho(is_ll2(s, t));\n\tvector<Point>ans;\n\tfor (auto p : kouho) {\n\t\tif (isis_sp(s, p) && isis_sp(t, p))ans.emplace_back(p);\n\t}\n\treturn ans;\n}\n// ??´?????¨???????????¢\nld dist_lp(const Line& l, const Point& p) {\n\treturn abs(p - proj(l, p));\n}\n\n// ??´?????¨??´???????????¢\nld dist_ll(const Line& l, const Line& m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\n// ??´?????¨??????????????¢\nld dist_ls(const Line& l, const Line& s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\n// ????????¨???????????¢\nld dist_sp(const Line& s, const Point& p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\n// ????????¨??????????????¢\nld dist_ss(const Line& s, const Line& t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\n\n//??´?????¨??´?????????????????????????????????\nLine bisection(const Line &s, const Line &t) {\n\tconst Point laglanju(is_ll(s, t));\n\tconst Point avec = !(abs(laglanju - s[0])<eps) ? s[0] - laglanju : s[1] - laglanju;\n\tconst Point bvec = !(abs(laglanju - t[0])<eps) ? t[0] - laglanju : t[1] - laglanju;\n\n\treturn Line(laglanju, laglanju + (abs(bvec)*avec + abs(avec)*bvec) / (abs(avec) + abs(bvec)));\n}\n\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nPoint inner_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i <static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (vertics[0] == vertics[1] || vertics[1] == vertics[2] || vertics[2] == vertics[0])return vertics[0];\n\tLine bi1(bisection(Line(vertics[0], vertics[1]), Line(vertics[0], vertics[2])));\n\tLine bi2(bisection(Line(vertics[1], vertics[2]), Line(vertics[1], vertics[0])));\n\tif (bi1[0] == bi2[0])return bi1[0];\n\telse {\n\t\treturn is_ll(bi1, bi2);\n\t}\n}\n\n//???????????´?????????????????????\n//???????????´??????????????§???????????¨????¢?????????¨?????????\nvector<Point> ex_center(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tfor (int i = 0; i < static_cast<int>(ls.size()); ++i) {\n\t\tvertics.push_back(is_ll(ls[i], ls[(i + 1) % 3]));\n\t}\n\tif (abs(vertics[0] - vertics[1])<eps || abs(vertics[1] - vertics[2])<eps || (abs(vertics[2] - vertics[0])<eps))return vector<Point>();\n\tvector<Point>ecs;\n\tfor (int i = 0; i < 3; ++i) {\n\t\tLine bi1(bisection(Line(vertics[i], vertics[i] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[i], vertics[(i + 1) % 3])));\n\t\tLine bi2(bisection(Line(vertics[(i + 1) % 3], vertics[(i + 1) % 3] * 2.0l - vertics[(i + 2) % 3]), Line(vertics[(i + 1) % 3], vertics[i])));\n\t\tecs.push_back(is_ll(bi1, bi2));\n\t}\n\treturn ecs;\n}\n\n\n//a,b:??????\n//c:????????§??????\n//???????????´?????????????????¢?????????????±??????????\nvector<Point> same_dis(const vector<Line>&ls) {\n\tvector<Point>vertics;\n\tvertics.push_back(is_ll(ls[0], ls[2]));\n\tvertics.push_back(is_ll(ls[1], ls[2]));\n\n\tif (abs(vertics[0] - vertics[1]) < eps)return vector<Point>{vertics[0]};\n\tLine bis(bisection(ls[0], ls[1]));\n\tvector<Point>ecs;\n\n\tLine abi(bisection(Line(vertics[0], vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, abi));\n\n\n\tLine bbi(bisection(Line(vertics[0], 2.l*vertics[0] - vertics[1]), ls[0]));\n\tecs.push_back(is_ll(bis, bbi));\n\n\treturn ecs;\n}\n/* ??? */\n\n// ?????¨????????????\nvector<Point> is_cc(const Circle& c1, const Circle& c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res; // no intersection\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\n//???????????????????????????\n// 0 => out\n// 1 => on\n// 2 => in\nint is_in_circle(const Circle &cir, const Point& p) {\n\tld dis = abs(cir.p - p);\n\tif (dis > cir.r + eps)return 0;\n\telse if (dis < cir.r - eps)return 2;\n\telse return 1;\n}\n//???lc??????rc??????????????????\n// 0 => out\n// 1 => on\n// 2 => in\nint circle_in_circle(const Circle &lc, const Circle&rc) {\n\tld dis = abs(lc.p - rc.p);\n\tif (dis < rc.r - lc.r - eps)return 2;\n\telse if (dis>rc.r - lc.r + eps)return 0;\n\telse return 1;\n}\n\n// ?????¨??´????????????\nvector<Point> is_lc(const Circle& c, const Line& l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d); //safety;\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\n// ?????¨??????????????¢\nvector<Point> is_sc(const Circle& c, const Line& l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cp(const Circle& c, const Point& p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\n// ?????¨????????\\???\nvector<Line> tangent_cc(const Circle& c1, const Circle& c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), ALL(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n//??????????????????????????¢???\nld two_circle_area(const Circle&l, const Circle&r) {\n\tld dis = abs(l.p - r.p);\n\tif (dis > l.r + r.r)return 0;\n\telse if (dis + r.r < l.r) {\n\t\treturn r.r*r.r*pi;\n\t}\n\telse if (dis + l.r < r.r) {\n\t\treturn l.r*l.r*pi;\n\t}\n\telse {\n\t\tld ans = (l.r)*(l.r)*acos((dis*dis + l.r*l.r - r.r*r.r) / (2 * dis*l.r)) +\n\t\t\t(r.r)*(r.r)*acos((dis*dis + r.r*r.r - l.r*l.r) / (2 * dis*r.r)) -\n\t\t\tsqrt(4 * dis*dis*l.r*l.r - (dis*dis + l.r*l.r - r.r*r.r)*(dis*dis + l.r*l.r - r.r*r.r)) / 2;\n\t\treturn ans;\n\t}\n\n}\n\n/* ????§???¢ */\n\ntypedef vector<Point> Polygon;\n\n// ??¢???\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\tREP(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\n// ????§???¢????????¢??????\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\tREP(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\n// ??????????????????\n// 0 => out\n// 1 => on\n// 2 => in\nint is_in_polygon(const Polygon &poly, const Point& p) {\n\tld angle = 0;\n\tint n = poly.size();\n\tREP(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n//??????????????????2?????????\nenum { OUT, ON, IN };\nint convex_contains(const Polygon &P, const Point &p) {\n\tconst int n = P.size();\n\tPoint g = (P[0] + P[n / 3] + P[2 * n / 3]) / 3.0l; // inner-point\n\tint a = 0, b = n;\n\twhile (a + 1 < b) { // invariant: c is in fan g-P[a]-P[b]\n\t\tint c = (a + b) / 2;\n\t\tif (cross(P[a] - g, P[c] - g) > 0) { // angle < 180 deg\n\t\t\tif (cross(P[a] - g, p - g) > 0 && cross(P[c] - g, p - g) < 0) b = c;\n\t\t\telse a = c;\n\t\t}\n\t\telse {\n\t\t\tif (cross(P[a] - g, p - g) < 0 && cross(P[c] - g, p - g) > 0) a = c;\n\t\t\telse b = c;\n\t\t}\n\t}\n\tb %= n;\n\tif (cross(P[a] - p, P[b] - p) < 0) return 0;\n\tif (cross(P[a] - p, P[b] - p) > 0) return 2;\n\treturn 1;\n}\n\n// ??????\n// ???????????????????????¨????????????????????§??¨???\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\n\n\n// ????????????\nvector<Polygon> convex_cut(const Polygon &ps, const Line& l) {\n\tint n = ps.size();\n\tPolygon Q;\n\tPolygon R;\n\tREP(i, n) {\n\t\tPoint A = ps[i], B = ps[(i + 1) % n];\n\t\tLine m = Line(A, B);\n\t\tif (ccw(l.a, l.b, A) != -1) Q.push_back(A);\n\t\tif (ccw(l.a, l.b, A) != 1) R.push_back(A);\n\t\tif (ccw(l.a, l.b, A) * ccw(l.a, l.b, B) < 0 && isis_ll(l, m)) {\n\t\t\tQ.push_back(is_ll(l, m));\n\t\t\tR.push_back(is_ll(l, m));\n\t\t}\n\t}\n\tconst vector<Polygon>polys{ Q,R };\n\treturn polys;\n}\n\n\n/* ??¢??¬??????????????? */\nvoid add_point(vector<Point> &ps, const Point p) {\n\tfor (Point q : ps) if (abs(q - p) < eps) return;\n\tps.push_back(p);\n}\n\ntypedef int Weight;\nstruct Edge {\n\tint src, dst;\n\tWeight weight;\n\tEdge(int src, int dst, Weight weight) :\n\t\tsrc(src), dst(dst), weight(weight) { }\n};\n\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nvoid add_edge(Graph &g, const int from, const int to, const Weight weight) {\n\tg[from].push_back(Edge{ from, to, weight });\n}\n\nGraph segment_arrangement(const vector<Line> &s, const vector<Point> &p) {\n\tint n = p.size(), m = s.size();\n\tGraph g(n);\n\tREP(i, m) {\n\t\tvector<pair<ld, int>> vec;\n\t\tREP(j, n) if (isis_sp(s[i], p[j]))\n\t\t\tvec.emplace_back(abs(s[i].a - p[j]), j);\n\t\tsort(ALL(vec));\n\t\tREP(j, vec.size() - 1) {\n\t\t\tint from = vec[j].second, to = vec[j + 1].second;\n\t\t\tadd_edge(g, from, to, static_cast<Weight>(abs(p[from] - p[to])));\n\t\t}\n\t}\n\treturn g;\n}\nGraph sennbunn_arrangement(const vector<Line>&s) {\n\tvector<Point>crss;\n\tfor (int i = 0; i < static_cast<int>(s.size()); ++i) {\n\t\tfor (int j = i + 1; j < static_cast<int>(s.size()); ++j) {\n\t\t\tif (isis_ss(s[i], s[j])) {\n\t\t\t\tcrss.push_back(is_ll(s[i], s[j]));\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i <static_cast<int>(s.size()); ++i) {\n\t\tcrss.push_back(s[i][0]);\n\t\tcrss.push_back(s[i][1]);\n\t}\n\treturn segment_arrangement(s, crss);\n}\n\n//Graph circle_arrangement(const vector<Circle> &c, const vector<Point> &p) {\n//\tint n = p.size(), m = c.size();\n//\tGraph g(n);\n//\tREP(i, m) {\n//\t\tvector<pair<ld, int>> vec;\n//\t\tREP(j, n) if (abs(abs(c[i].p - p[j]) - c[i].r) < eps)\n//\t\t\tvec.emplace_back(arg(c[i].p - p[j]), j);\n//\t\tsort(ALL(vec));\n//\t\tREP(j, vec.size() - 1) {\n//\t\t\tint from = vec[j].second, to = vec[j + 1].second;\n//\t\t\tld angle = vec[j + 1].first - vec[j].first;\n//\t\t\tadd_edge(g, from, to, static_cast<Weight>(angle * c[i].r));\n//\t\t}\n//\t\tif (vec.size() >= 2) {\n//\t\t\tint from = vec.back().second, to = vec.front().first;\n//\t\t\tld angle = vec.front().first - vec.back().first;\n//\t\t\tadd_edge(g, from, to, static_cast<Weight>(angle * c[i].r));\n//\t\t}\n//\t}\n//\treturn g;\n//}\n\n\n/* ????????°?????? */\n\n// ?????????????????¢?????¢??¬??????????????????????????????????????°???????????????\n// ?????´?????????????¨?????????§????????´????????????????¨?????????§???????????????\n// ?????° polygon ??????vector<int> ??§??¨?????????????§???¢???????????§?????????\n// vector<int> ??§??¨????????? ????§???¢???i???????????????????????????????????????p????????????????????§?????????\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n\n//Graph dual_graph(const vector<Line> &s, const vector<Point> &p) {\n//\tint N = p.size();\n//\tpolygon.clear();\n//\tREP(i, 1024) REP(j, 1024) seg2p[i][j].clear();\n//\tvector<vector<tuple<ld, int, bool>>> tup(N);\n//\tREP(i, s.size()) {\n//\t\tint a = -1, b = -1;\n//\t\tREP(j, N) if (abs(s[i].a - p[j]) < eps) a = j;\n//\t\tREP(j, N) if (abs(s[i].b - p[j]) < eps) b = j;\n//\t\tassert(a >= 0 && b >= 0);\n//\t\ttup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n//\t\ttup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n//\t}\n//\tREP(i, N) sort(ALL(tup[i]));\n//\tREP(i, N) {\n//\t\tREP(j, tup[i].size()) {\n//\t\t\tld angle; int pos = j, from = i, to; bool flag;\n//\t\t\ttie(angle, to, flag) = tup[i][j];\n//\t\t\tif (flag) continue;\n//\t\t\tvector<int> ps;\n//\t\t\twhile (!flag) {\n//\t\t\t\tps.push_back(from);\n//\t\t\t\tget<2>(tup[from][pos]) = true;\n//\t\t\t\tseg2p[from][to].push_back(polygon.size());\n//\t\t\t\tseg2p[to][from].push_back(polygon.size());\n//\t\t\t\tangle += pi + eps;\n//\t\t\t\tif (angle > pi) angle -= 2 * pi;\n//\t\t\t\tauto it = lower_bound(ALL(tup[to]), make_tuple(angle, 0, false));\n//\t\t\t\tif (it == tup[to].end()) it = tup[to].begin();\n//\t\t\t\tfrom = to; tie(angle, to, flag) = *it;\n//\t\t\t\tpos = it - tup[from].begin();\n//\t\t\t}\n//\t\t\tpolygon.push_back(ps);\n//\t\t}\n//\t}\n//\tGraph g(polygon.size());\n//\tREP(i, N) REP(j, i) {\n//\t\tif (seg2p[i][j].size() == 2) {\n//\t\t\tint from = seg2p[i][j][0], to = seg2p[i][j][1];\n//\t\t\tg[from].push_back(Edge{ from, to });\n//\t\t\tg[to].push_back(Edge{ to, from });\n//\t\t}\n//\t}\n//\treturn g;\n//}\n\nstruct flo {\n\tPoint p;\n\tld the;\n};\nbool check(const flo&f, const Point p,const ld len,const ld theta) {\n\tconst ld dis = abs(f.p - p);\n\tif (dis-eps > len) {\n\t\treturn false;\n\t}\n\telse {\n\t\tld kaku = atan2(p.imag() - f.p.imag(), p.real() - f.p.real());\n\t\tif (kaku < 0)kaku += 2*pi;\n\t\tld sa = abs(kaku - theta);\n\t\tsa = min(sa, 2 * pi - sa);\n\t\tif (sa < f.the / 2)return true;\n\t\telse return false;\n\t}\n}\nint main() {\n\twhile (1) {\n\t\tvector<Point>houses;\n\t\tint H, R; cin >> H >> R;\n\t\tif (!H)break;\n\t\tfor (int i = 0; i < H; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\thouses.emplace_back(x, y);\n\t\t}\n\t\tint U, M, S;ld du, dm, ds; cin >> U >> M >> S >> du >> dm >> ds;\n\t\tdu *= dtop;\n\t\tdm *= dtop;\n\t\tds *= dtop;\n\t\tvector<flo>flowers;\n\t\tfor (int i = 0; i < U; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tflowers.push_back(flo{ Point(x,y),du });\n\t\t}\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tflowers.push_back(flo{ Point(x,y),dm });\n\t\t}\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tflowers.push_back(flo{ Point(x,y),ds });\n\t\t}\n\t\tflo myflower{ Point(0,0),du };\n\t\tint ans = 0;\n\t\tvector<int>nums(H);\n\t\tfor (int i = 0; i < R; ++i) {\n\t\t\tld w, a; cin >> a >> w;\n\t\t\ta *= dtop;\n\t\t\tfor (int h = 0; h < H; ++h) {\n\t\t\t\tPoint p(houses[h]);\n\t\t\t\tif (check(myflower, p, w, a)) {\n\n\t\t\t\t\tbool aok = true;\n\t\t\t\t\tfor (auto f : flowers) {\n\t\t\t\t\t\tif (check(f, p, w, a)) {\n\t\t\t\t\t\t\taok = false;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (aok) {\n\t\t\t\t\t\tnums[h]++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint amax = *max_element(nums.begin(), nums.end());\n\t\tif (amax) {\n\t\t\tvector<int>anss;\n\t\t\tfor (int i = 0; i < H; ++i) {\n\t\t\t\tif (amax == nums[i]) {\n\t\t\t\t\tanss.push_back(i+1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (int i = 0; i < anss.size(); ++i) {\n\t\t\t\tcout << anss[i];\n\t\t\t\tif (i != anss.size() - 1)cout << \" \";\n\t\t\t\telse cout << endl;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tcout << \"NA\" << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 27868, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_0269_1572200", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int,int>pint;\ntypedef vector<int>vint;\n#define pb push_back\n#define mp make_pair\n#define rep(i,n) for(int i=0;i<(n);i++)\ntemplate<class T,class U>void chmin(T &t,U f){if(t>f)t=f;}\ntemplate<class T,class U>void chmax(T &t,U f){if(t<f)t=f;}\n\ntypedef complex<double>P;\n\nconst double EPS=1e-6;\nconst double PI=acos(-1);\n\nconst int COUNTER_CLOCKWISE=1;\nconst int CLOCKWISE=-1;\nconst int ONLINE_BACK=2;\nconst int ONLINE_FRONT=-2;\nconst int ON_SEGMENT=0;\n\ninline double dot(const P &a, const P &b){return (conj(a) * b).real();}\ninline double cross(const P &a, const P &b){return (conj(a) * b).imag();}\n\ndouble toRad(double a){return a/180.0*PI;}\ndouble toDeg(double a){return a*180.0/PI;}\nP rotate(P p,double d){\n return P(p.real()*cos(d)-p.imag()*sin(d),p.real()*sin(d)+p.imag()*cos(d));\n}\n\nP getP(){\n double x,y;\n scanf(\"%lf%lf\",&x,&y);\n return P(x,y);\n}\n\nint ccw(P p0,P p1,P p2){\n P a=p1-p0;\n P b=p2-p0;\n if(cross(a,b)>EPS)return COUNTER_CLOCKWISE;\n if(cross(a,b)<-EPS)return CLOCKWISE;\n if(dot(a,b)<-EPS)return ONLINE_BACK;\n if(norm(a)<norm(b))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool ok(P from,P to,double w,double a,double d){\n if(abs(to-from)>a)return false;\n\n d=toRad(d);\n w=toRad(w);\n\n double left=w+d/2;\n double right=w-d/2;\n P vh=to-from;\n P vl=a*P(cos(left),sin(left));\n P vr=a*P(cos(right),sin(right));\n\n return (cross(vr,vh)>-EPS)&&(cross(vh,vl)>-EPS);\n}\n\nint H,R;\nvector<P>h;\n\nint U,M,S;\ndouble du,dm,ds;\nvector<P>u,m,s;\nvoid solve(){\n h.resize(H);\n rep(i,H)h[i]=getP();\n\n scanf(\"%d%d%d\",&U,&M,&S);\n scanf(\"%lf%lf%lf\",&du,&dm,&ds);\n\n u.resize(U);\n m.resize(M);\n s.resize(S);\n rep(i,U)u[i]=getP();\n rep(i,M)m[i]=getP();\n rep(i,S)s[i]=getP();\n\n int cnt[100]={0};\n\n while(R--){\n double w,a;\n scanf(\"%lf%lf\",&w,&a);\n rep(i,H){\n bool f=false;\n if(ok(P(0,0),h[i],w,a,du))f=true;\n rep(j,U)if(ok(u[j],h[i],w,a,du))f=false;\n rep(j,M)if(ok(m[j],h[i],w,a,dm))f=false;\n rep(j,S)if(ok(s[j],h[i],w,a,ds))f=false;\n if(f)cnt[i]++;\n }\n }\n\n int ma=*max_element(cnt,cnt+H);\n if(ma==0){\n puts(\"NA\");\n return;\n }\n\n bool f=false;\n rep(i,H){\n if(cnt[i]!=ma)continue;\n if(f)printf(\" \");\n else f=true;\n printf(\"%d\",i+1);\n }\n puts(\"\");\n}\n\nint main(){\n while(scanf(\"%d%d\",&H,&R),H||R)solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1260, "score_of_the_acc": -0.0005, "final_rank": 3 }, { "submission_id": "aoj_0269_1365017", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef complex<double> Point;\ntypedef pair<Point, double> Tree;\n\nint H;\nPoint home[100];\n\nint U, M, S, du, dm, ds;\nTree tree[31];\n\nint R;\nint w[100], a[100];\n\ndouble toRad(double theta)\n{\n\treturn theta / 180 * acos(-1);\n}\n\ndouble cross(Point a, Point b)\n{\n\treturn a.real() * b.imag() - a.imag() * b.real();\n}\n\nbool contains(Tree tree, Point home, double dir, double len)\n{\n\tif (abs(home - tree.first) > len) return false;\n\tdouble left = dir + tree.second / 2;\n\tdouble right = dir - tree.second / 2;\n\tPoint vh = home - tree.first;\n\tPoint vl = polar(len, left);\n\tPoint vr = polar(len, right);\n\treturn (cross(vr, vh) > -1e-6) && (cross(vh, vl) > -1e-6);\n}\n\nvoid solve()\n{\n\t// day, home\n\tstatic int reach[100][100];\n\tfill_n(*reach, 100 * 100, 0);\n\t\n\tfor (int i = 0; i < R; i++){\n\t\tfor (int j = 0; j < H; j++){\n\t\t\tfor (int k = 0; k <= U + M + S; k++){\n\t\t\t\tif (contains(tree[k], home[j], toRad(w[i]), a[i])){\n\t\t\t\t\treach[i][j] |= 1 << k;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tstatic int cnt[100];\n\tfill_n(cnt, 100, 0);\n\t\n\tint maxi = 0;\n\tfor (int i = 0; i < H; i++){\n\t\tfor (int j = 0; j < R; j++){\n\t\t\tcnt[i] += (reach[j][i] == 1);\n\t\t\tmaxi = max(maxi, cnt[i]);\n\t\t}\n\t}\n\t\n\tif (maxi == 0) puts(\"NA\");\n\telse {\n\t\tbool f = false;\n\t\tfor (int i = 0; i < H; i++){\n\t\t\tif (cnt[i] == maxi){\n\t\t\t\tif (f) printf(\" \");\n\t\t\t\tf = true;\n\t\t\t\tprintf(\"%d\", i + 1);\n\t\t\t}\n\t\t}\n\t\tputs(\"\");\n\t}\n}\n\nint main()\n{\n\twhile (scanf(\"%d %d\", &H, &R), H){\n\t\tfor (int i = 0; i < H; i++){\n\t\t\tint x, y;\n\t\t\tscanf(\"%d %d\", &x, &y);\n\t\t\thome[i] = Point(x, y);\n\t\t}\n\t\t\n\t\tscanf(\"%d %d %d\", &U, &M, &S);\n\t\tscanf(\"%d %d %d\", &du, &dm, &ds);\n\t\ttree[0] = Tree(Point(0, 0), toRad(du));\n\t\tfor (int i = 0; i < U + M + S; i++){\n\t\t\tint x, y, d;\n\t\t\tscanf(\"%d %d\", &x, &y);\n\t\t\tif (i < U) d = du;\n\t\t\telse if (i < U + M) d = dm;\n\t\t\telse d = ds;\n\t\t\ttree[i + 1] = Tree(Point(x, y), toRad(d));\n\t\t}\n\t\t\n\t\tfor (int i = 0; i < R; i++){\n\t\t\tscanf(\"%d %d\", &w[i], &a[i]);\n\t\t}\n\t\t\n\t\tsolve();\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1256, "score_of_the_acc": -0.0003, "final_rank": 2 }, { "submission_id": "aoj_0269_1336179", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i,n) for(int i=0;i<(int)(n);++i)\n#define REPR(i,n) for (int i=(int)(n)-1;i>=0;--i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n#define valid(y,x,h,w) (0<=y&&y<h&&0<=x&&x<w)\n#define tpl(...) make_tuple(__VA_ARGS__)\nconst int INF = 0x3f3f3f3f;\nconst double EPS = 1e-8;\nconst double PI = acos(-1);\nconst int dy[] = {-1,0,1,0};\nconst int dx[] = {0,1,0,-1};\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\ntemplate<typename Ch,typename Tr,typename C,typename=decltype(begin(C()))>basic_ostream<Ch,Tr>& operator<<(basic_ostream<Ch,Tr>&os,\nconst C& c){os<<'[';for(auto i=begin(c);i!=end(c);++i)os<<(i==begin(c)?\"\":\" \")<<*i;return os<<']';}\ntemplate<class S,class T>ostream&operator<<(ostream &o,const pair<S,T>&t){return o<<'('<<t.first<<','<<t.second<<')';}\ntemplate<int N,class Tp>void output(ostream&,const Tp&){}\ntemplate<int N,class Tp,class,class ...Ts>void output(ostream &o,const Tp&t){if(N)o<<',';o<<get<N>(t);output<N+1,Tp,Ts...>(o,t);}\ntemplate<class ...Ts>ostream&operator<<(ostream&o,const tuple<Ts...>&t){o<<'(';output<0,tuple<Ts...>,Ts...>(o,t);return o<<')';}\ntemplate<class T>void output(T t,char z=10){if(t<0)t=-t,putchar(45);int c[20];\nint k=0;while(t)c[k++]=t%10,t/=10;for(k||(c[k++]=0);k;)putchar(c[--k]^48);putchar(z);}\ntemplate<class T>void outputs(T t){output(t);}\ntemplate<class S,class ...T>void outputs(S a,T...t){output(a,32);outputs(t...);}\ntemplate<class T>void output(T *a,int n){REP(i,n)cout<<a[i]<<(i!=n-1?',':'\\n');}\ntemplate<class T>void output(T *a,int n,int m){REP(i,n)output(a[i],m);}\ntemplate<class T>bool input(T &t){int n=1,c;for(t=0;!isdigit(c=getchar())&&~c&&c-45;);\nif(!~c)return 0;for(c-45&&(n=0,t=c^48);isdigit(c=getchar());)t=10*t+c-48;t=n?-t:t;return 1;}\ntemplate<class S,class ...T>bool input(S&a,T&...t){input(a);return input(t...);}\ntemplate<class T>bool inputs(T *a, int n) { REP(i,n) if(!input(a[i])) return 0; return 1;}\n\ntemplate<class T>\nstruct Pt {\n T x,y;\n Pt(T x=T(), T y=T()) :x(x),y(y) {}\n void in() {ll _x, _y; input(_x,_y); x=_x; y=_y; }\n bool operator<(const Pt &p) const { return x!=p.x?x<p.x:y<p.y; }\n bool operator==(const Pt &p) const { return x==p.x&&y==p.y; }\n Pt operator+=(const Pt &p) { x+=p.x, y+=p.y; return *this; }\n Pt operator-=(const Pt &p) { x-=p.x, y-=p.y; return *this; }\n Pt operator*=(const Pt &p) { T t=x;x=x*p.x-y*p.y,y=t*p.y+y*p.x; return *this;}\n Pt operator*=(const T &v) { x*=v; y*=v; return *this;}\n friend ostream& operator<<(ostream& os, const Pt &p) {return os<<'('<<p.x<<','<<p.y<<')';}\n friend istream& operator>>(istream& is, Pt &p) {return is>>p.x>>p.y;}\n\n Pt operator+(const Pt &p) const { return Pt(*this)+=p; }\n Pt operator-(const Pt &p) const { return Pt(*this)-=p; }\n Pt operator*(const Pt &p) const { return Pt(*this)*=p; }\n Pt operator*(const T &v) const { return Pt(*this)*=v; }\n friend Pt operator*(const T &v, const Pt &p) { return p*v; }\n bool operator!=(const Pt &p) const { return !(*this == p); }\n\n T abs() const { return hypot(x,y); }\n T norm() const { return x*x+y*y; }\n T arg() const { return atan2(y,x); }\n T dot(const Pt &p) const { return x*p.x+y*p.y; }\n T det(const Pt &p) const { return x*p.y-y*p.x; }\n friend T abs(const Pt &p) { return p.abs(); }\n friend T norm(const Pt &p) { return p.norm(); }\n friend T arg(const Pt &p) { return p.arg(); }\n friend T dot(const Pt &p, const Pt &q) { return p.dot(q); }\n friend T det(const Pt &p, const Pt &q) { return p.det(q); }\n};\n\nint sig(double r) {return r<-EPS?-1:r>EPS?1:0;}\nint sig(ll r) {return r<0?-1:r>0?1:0;}\nbool eq(double a, double b) {return sig(a-b)==0;}\nbool eq(ll a, ll b) {return a==b;}\nPt<double> pol(double len, double ang) { return Pt<double>(cos(ang),sin(ang)) * len; }\n\ntypedef Pt<double> P;\n\ndouble angle(const P &a, const P &b) {\n double ret = arg(b)-arg(a);\n if (!sig(ret)||!sig(ret-2*PI)) return 0;\n return ret>0 ? ret : ret + 2*PI;\n}\n\ntemplate<typename _T>\nstruct Ci {\n typedef _T T;\n Pt<T> p; T r;\n Ci(const Pt<T> &p, T r) : p(p), r(r) { }\n};\ntypedef Ci<double> C;\n\n// 扇型\nstruct CS : C {\n P p1, p2;\n CS(const P &p, const P &p1, const P &p2):\n C(p,abs(p1)),p1(p1),p2(p2) {}\n};\n\nbool intersectCSP(const CS &cs, const P &p) {\n return angle(cs.p1, p-cs.p) < angle(cs.p1, cs.p2)+EPS &&\n abs(cs.p-p) <= cs.r+EPS;\n}\n\nstruct Tree {\n P p;\n double d;\n Tree(const P &p, double d) : p(p), d(d) {}\n CS getCS(double w, double a) {\n return CS(p, pol(a, w - d/2), pol(a, w + d/2));\n }\n};\n\nint main() {\n int H, R;\n while(input(H,R), H || R) {\n vector<P> home(H);\n REP(i,H) cin >> home[i];\n int U,M,S;\n input(U,M,S);\n double du,dm,ds;\n cin>>du>>dm>>ds;\n du = du / 180 * PI;\n dm = dm / 180 * PI;\n ds = ds / 180 * PI;\n vector<Tree> tree;\n REP(i,U) {\n P p; cin >> p;\n tree.push_back(Tree(p,du));\n }\n REP(i,M) {\n P p; cin >> p;\n tree.push_back(Tree(p,dm));\n }\n REP(i,S) {\n P p; cin >> p;\n tree.push_back(Tree(p,ds));\n }\n vector<int> numday(H);\n\n Tree mine(P(), du);\n REP(i,R) {\n double w,a;\n cin >> w >> a;\n w = w / 180 * PI;\n CS mycs = mine.getCS(w,a);\n REP(i,home.size()) {\n const P& h = home[i];\n bool ok = intersectCSP(mycs, h);\n if (!ok) continue;\n for (auto &t : tree) {\n CS cs = t.getCS(w,a);\n ok &= !intersectCSP(cs, h);\n }\n if (ok)\n numday[i]++;\n }\n }\n int mx = *max_element(ALL(numday));\n if (mx == 0) puts(\"NA\");\n else {\n bool f = 0;\n REP(i,H) {\n if (numday[i] == mx) {\n if (f) printf(\" \");\n printf(\"%d\", i+1);\n f = 1;\n }\n }\n cout << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1340, "score_of_the_acc": -0.1285, "final_rank": 8 }, { "submission_id": "aoj_0269_1119321", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cmath>\n#include <vector>\n#include <map>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <set>\n#include <cstring>\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,j) FOR(i,0,j)\n#define mp std::make_pair\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nconst int INF = 1001001001;\nconst double EPS = 1e-8;\n\n// S N E W(南北東西)\nconst int dx[8] = {0, 0, 1, -1, 1, 1, -1, -1}, dy[8] = {1, -1, 0, 0, 1, -1, 1, -1};\n\nstruct P{\n P(){}\n P(double _r, double _i):r(_r), i(_i){}\n void real(const double& v){r = v;}\n void imag(const double& v){i = v;}\n double r, i;\n};\n\ndouble real(const P& p){return p.r;}\ndouble imag(const P& p){return p.i;}\ndouble norm(const P& p){double r = real(p), i = imag(p); return r * r + i * i;}\ndouble dist(const P& p){return std::sqrt(norm(p));}\n\nP operator+(const P& lhs, const P& rhs){\n return P(real(lhs)+real(rhs), imag(lhs)+imag(rhs));\n}\nP operator-(const P& lhs, const P& rhs){\n return P(real(lhs)-real(rhs), imag(lhs)-imag(rhs));\n}\nP operator-(const P& p){\n return P(-real(p), -imag(p));\n}\n\ndouble cross(const P& lhs, const P& rhs){\n return real(lhs)*imag(rhs) - imag(lhs)*real(rhs);\n}\n\ndouble dot(const P& lhs, const P& rhs){\n return real(lhs)*real(rhs) + imag(lhs)*imag(rhs);\n}\n\nint H, R, U, M, S;\ndouble du, dm, ds;\nP hs[100], us[10], ms[10], ss[10];\n\nbool can(P home, P flower, double d, P wind){\n if(dist(home-flower) > imag(wind)){return false;}\n P center;\n center.real(imag(wind) * std::cos(M_PI / 180.0f * real(wind)));\n center.imag(imag(wind) * std::sin(M_PI / 180.0f * real(wind)));\n // {\n // P p = home-flower;\n // printf(\"%f, %f\\n\", real(center), imag(center));\n // }\n double s = cross(center, home-flower) / dist(center) / dist(home-flower),\n c = dot(center, home-flower) / dist(center) / dist(home-flower);\n // printf(\"%f, %f\\n\", c, s);\n if((c < 0.0f && d > 90.0f || c > 0.0f) && std::abs(s) < std::sin(M_PI / 360.0f * d) + EPS){\n return true;\n }\n return false;\n}\n\nint main(){\n while(std::cin >> H >> R, H || R){\n REP(i, H){\n double x, y;\n std::cin >> x >> y;\n\n hs[i].real(x); hs[i].imag(y);\n }\n\n std::cin >> U >> M >> S >> du >> dm >> ds;\n REP(i, U){\n double x, y;\n std::cin >> x >> y;\n\n us[i].real(x); us[i].imag(y);\n }\n REP(i, M){\n double x, y;\n std::cin >> x >> y;\n\n ms[i].real(x); ms[i].imag(y);\n }\n REP(i, S){\n double x, y;\n std::cin >> x >> y;\n\n ss[i].real(x); ss[i].imag(y);\n }\n\n P origin(0.0f, 0.0f);\n int counter[100];\n memset(counter, 0, sizeof(counter));\n REP(i, R){\n double x, y;\n std::cin >> x >> y;\n P wind(x, y);\n\n REP(k, H){\n bool f = can(hs[k], origin, du, wind),\n g = true;\n\n REP(j, U){\n g = g && !can(hs[k], us[j], du, wind);\n }\n REP(j, M){\n g = g && !can(hs[k], ms[j], dm, wind);\n }\n REP(j, S){\n g = g && !can(hs[k], ss[j], ds, wind);\n }\n\n if(f && g){counter[k] += 1;}\n }\n }\n\n int maxDays = 0;\n REP(i, H){\n maxDays = std::max(maxDays, counter[i]);\n }\n\n if(maxDays == 0){\n puts(\"NA\");\n }else{\n std::vector<int> indices;\n REP(i, H){\n if(counter[i] == maxDays){indices.push_back(i+1);}\n }\n\n REP(i, (int)indices.size()){\n if(i == (int)indices.size() - 1){printf(\"%d\\n\", indices[i]);}\n else{printf(\"%d \", indices[i]);}\n }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1264, "score_of_the_acc": -0.0006, "final_rank": 4 }, { "submission_id": "aoj_0269_1035736", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n\nconst double PI = 3.14159265358979;\n\nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n\nclass Wind {\npublic:\n double w, a;\n};\n\nbool include(double angle, double low, double high) {\n if(low < 0.0 && 2.0 * PI + low <= angle) return true;\n if(high >= 2.0 * PI && angle <= high - 2.0 * PI) return true;\n return low <= angle && angle <= high;\n}\n\nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0.0) angle = 2.0 * PI + angle;\n if(dist <= wind.a && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n\ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n\nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n\n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n\n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n\n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n\n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n\n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n\n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n\n if(!ok || ng) continue;\n\n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n\n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1336, "score_of_the_acc": -0.2533, "final_rank": 12 }, { "submission_id": "aoj_0269_1035729", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n\nconst double PI = 3.14159265358979;\n\nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n\nclass Wind {\npublic:\n double w, a;\n};\n\nbool include(double angle, double low, double high) {\n if(low < 0.0 && low + 2.0 * PI <= angle) return true;\n if(high >= 2.0 * PI && angle <= high - 2.0 * PI) return true;\n return low <= angle && angle <= high;\n}\n\nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0.0) angle = angle + 2.0 * PI;\n if(dist <= wind.a && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n\ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n\nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n\n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n\n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n\n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n\n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n\n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n\n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n\n if(!ok || ng) continue;\n\n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n\n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1332, "score_of_the_acc": -0.2532, "final_rank": 11 }, { "submission_id": "aoj_0269_1035726", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n\nconst double PI = 3.14159265358979;\n\nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n\nclass Wind {\npublic:\n double w, a;\n};\n\nbool include(double angle, double low, double high) {\n if(low < 0.0) {\n double l = low + 2.0 * PI;\n if(l <= angle) return true;\n }\n if(high > 2.0 * PI) {\n double h = high - 2.0 * PI;\n if(angle <= h) return true;\n }\n return low <= angle && angle <= high;\n}\n\nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0.0) angle = angle + 2.0 * PI;\n if(dist <= wind.a && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n\ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n\nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n\n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n\n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n\n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n\n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n\n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n\n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n\n if(!ok || ng) continue;\n\n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n\n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1336, "score_of_the_acc": -0.2533, "final_rank": 12 }, { "submission_id": "aoj_0269_1035720", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<numeric>\nusing namespace std;\n \nconst double PI = 3.14159265358979;\n \nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n \nclass Wind {\npublic:\n double w, a;\n};\n \nbool include(double angle, double low, double high) {\n if(low < 0.0) {\n double l = low + 2.0 * PI;\n if(l <= angle) return true;\n }\n if(high > 2.0 * PI) {\n double h = high - 2.0 * PI;\n if(angle <= h) return true;\n }\n return low <= angle && angle <= high;\n}\n \nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0.0) angle = angle + 2.0 * PI;\n if(dist <= wind.a && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n \ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n \nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n \n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n \n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n \n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n \n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n \n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n \n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n \n if(!ok || ng) continue;\n \n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n \n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1336, "score_of_the_acc": -0.2533, "final_rank": 12 }, { "submission_id": "aoj_0269_1035717", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<numeric>\nusing namespace std;\n \nconst double PI = 3.14159265358979;\nconst double EPS = 1e-9;\n \nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n \nclass Wind {\npublic:\n double w, a;\n};\n \nbool include(double angle, double low, double high) {\n if(low < 0 + EPS) {\n double l = low + 2.0 * PI;\n if(l <= angle + EPS) return true;\n }\n if(high > 2.0 * PI + EPS) {\n double h = high - 2.0 * PI;\n if(angle <= h + EPS) return true;\n }\n return low <= angle + EPS && angle <= high + EPS;\n}\n \nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0) angle = angle + 2 * PI;\n if(dist <= wind.a + EPS && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n \ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n \nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n \n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n \n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n \n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n \n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n \n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n \n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n \n if(!ok || ng) continue;\n \n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n \n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1336, "score_of_the_acc": -0.2533, "final_rank": 12 }, { "submission_id": "aoj_0269_1035713", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<numeric>\nusing namespace std;\n\nconst double PI = 3.14159265358979;\nconst double EPS = 1e-9;\n\nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n\nclass Wind {\npublic:\n double w, a;\n};\n\nbool include(double angle, double low, double high) {\n if(low < 0 + EPS) {\n double l = low + 2.0 * PI;\n if(l <= angle + EPS) return true;\n }\n if(high > 2.0 * PI + EPS) {\n double h = high - 2.0 * PI;\n if(angle <= h + EPS) return true;\n }\n return low <= angle + EPS && angle <= high + EPS;\n}\n\nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0) angle = angle + 2 * PI;\n if(dist <= wind.a + EPS && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n\ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n\nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n\n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n\n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n\n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n\n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n\n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n\n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n\n if(!ok || ng) continue;\n\n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n\n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1340, "score_of_the_acc": -0.2535, "final_rank": 16 }, { "submission_id": "aoj_0269_1035710", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<numeric>\nusing namespace std;\n\nconst double PI = 3.14159265358979;\nconst double EPS = 1e-9;\n\nclass Point {\npublic:\n double x, y;\n Point(double x = 0.0, double y = 0.0) :x(x), y(y) {}\n};\n\nclass Wind {\npublic:\n double w, a;\n};\n\nbool include(double angle, double low, double high) {\n if(low < 0 + EPS) {\n double l = low + 2.0 * PI;\n if(l <= angle + EPS) return true;\n }\n if(high > 2.0 * PI + EPS) {\n double h = high - 2.0 * PI;\n if(angle <= h + EPS) return true;\n }\n return low <= angle + EPS && angle <= high + EPS;\n}\n\nbool savor(const Point &home, const Wind &wind, const vector<Point> &blossom, double d) {\n// cout << \"home: \" << home.x << \", \" << home.y << endl;\n// cout << \"blossom\" << endl; for(const auto &i: blossom) cout << \" \" << i.x << \",\" << i.y; cout << endl;\n// cout << \"d: \" << d << endl;\n// cout << \"wind: \" << wind.w << \", \" << wind.a << endl;\n// cout << endl;\n d /= 2.0;\n for(const auto &b: blossom) {\n Point dif(home.x - b.x, home.y - b.y);\n double angle = atan2(dif.y, dif.x);\n double dist = hypot(dif.y, dif.x);\n if(angle < 0) angle = 2 * PI + angle;\n// cout<<\"angle: \"<<angle<<endl;\n// cout<<\"wind.w +- d: \"<<wind.w - d<<\" - \"<<wind.w + d<<endl;\n// cout<<\"dist: \"<<dist<<endl;\n if(dist <= wind.a + EPS && include(angle, wind.w - d, wind.w + d)) return true;\n }\n return false;\n}\n\ndouble toRadian(double d) {\n return d * PI / 180.0;\n}\n\nint main() {\n int H, R;\n while(cin >> H >> R, H | R) {\n vector<Point> home(H);\n for(auto &i: home) cin >> i.x >> i.y;\n\n int U, M, S;\n double du, dm, ds;\n cin >> U >> M >> S >> du >> dm >> ds;\n\n du = toRadian(du);\n dm = toRadian(dm);\n ds = toRadian(ds);\n\n vector<Point> plum(U), peach(M), cherry(S);\n for(auto &i: plum) cin >> i.x >> i.y;\n for(auto &i: peach) cin >> i.x >> i.y;\n for(auto &i: cherry) cin >> i.x >> i.y;\n\n vector<Wind> wind(R);\n for(auto &i: wind) cin >> i.w >> i.a;\n for(auto &i: wind) i.w = toRadian(i.w);\n\n // test\n// cout << savor(home[5], wind[0], peach, dm) << endl;\n// return 0;\n\n // solve\n vector<int> number(H, 0);\n int maxNumber = 0;\n\n for(int i = 0; i < H; ++i) {\n for(int day = 0; day < R; ++day) {\n bool ok = savor(home[i], wind[day], {Point(0.0, 0.0)}, du);\n bool ng = false;\n ng |= savor(home[i], wind[day], plum, du);\n ng |= savor(home[i], wind[day], peach, dm);\n ng |= savor(home[i], wind[day], cherry, ds);\n\n// cout<<\"day\"<<day<<endl;\n// cout<<savor(home[i], wind[day], plum, du)<<\" \"<<savor(home[i], wind[day], peach, du)<<\" \"<<savor(home[i], wind[day], cherry, du)<<endl;\n\n if(!ok || ng) continue;\n\n ++number[i];\n maxNumber = max(maxNumber, number[i]);\n }\n }\n\n// for(const auto &i: number) cout<<\" \"<<i;cout<<endl;\n\n if(maxNumber) {\n bool first = true;\n for(int i = 0; i < H; ++i) if(number[i] == maxNumber) {\n if(!first) cout << \" \";\n first = false;\n cout << i + 1;\n }\n cout << endl;\n } else {\n cout << \"NA\" << endl;\n }\n\n// return 0;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1336, "score_of_the_acc": -0.1283, "final_rank": 7 }, { "submission_id": "aoj_0269_1024578", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-7)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n\nusing namespace std;\n\nconst int IINF = INT_MAX;\n\nclass Point{\npublic:\n double x,y;\n\n Point(double x = -IINF,double y = -IINF): x(x),y(y){}\n\n Point operator + (Point p){return Point(x+p.x,y+p.y);}\n Point operator - (Point p){return Point(x-p.x,y-p.y);}\n\n};\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\nPoint rotate(Point a,double rad){ return Point(cos(rad)*a.x - sin(rad)*a.y,sin(rad)*a.x + cos(rad)*a.y); }\n\ndouble toRad(double agl){ return agl*M_PI/180.0; }\n\nint ccw(Point p0,Point p1,Point p2){\n Point a = p1-p0;\n Point b = p2-p0;\n if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n if(cross(a,b) < -EPS)return CLOCKWISE;\n if(dot(a,b) < -EPS)return ONLINE_BACK;\n if(norm(a) < norm(b))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nconst int MAX_N = 110;\nint N,M,Ume,Momo,SakuraHappyInnovation,counter[MAX_N],limit[3];\nPoint ps[MAX_N],p[3][20];\ndouble d[3],w[110],a[110];\n\nbool LT(double A,double B) { return !equals(A,B) && A < B; }\nbool LTE(double A,double B) { return equals(A,B) || A < B; }\n\nbool inside(Point h,Point t,double ta,double tw,double td){\n double rad_w = toRad(tw), rad_d = toRad(td/2.0);\n Point tmp = Point(ta*cos(rad_w),ta*sin(rad_w));\n Point alpha = rotate(tmp,-rad_d) + t;\n Point beta = rotate(tmp,rad_d) + t;\n int res_ccw = ccw(t,alpha,h);\n bool res1 = ( res_ccw != CLOCKWISE );\n res_ccw = ccw(t,beta,h);\n bool res2 = ( res_ccw != COUNTER_CLOCKWISE );\n double dist = abs(h-t);\n bool res3 = LTE(dist,ta);\n return res1 && res2 && res3;\n}\n\ninline void compute(){\n rep(i,N) counter[i] = 0;\n rep(_,M){\n rep(i,N){\n bool failed = false;\n if( inside(ps[i],Point(0,0),a[_],w[_],d[0]) ) {\n rep(j,3) if( !failed ) rep(k,limit[j]) failed |= inside(ps[i],p[j][k],a[_],w[_],d[j]);\n } else failed = true;\n if( !failed ) ++counter[i];\n }\n }\n int maxi = -1;\n rep(i,N) if( counter[i] != 0 ) maxi = max(maxi,counter[i]);\n if( maxi == -1 ) puts(\"NA\");\n else {\n bool first = true;\n rep(i,N) if( counter[i] == maxi ){\n if( !first ) printf(\" \"); first = false;\n printf(\"%d\",i+1);\n }\n puts(\"\");\n }\n}\n\nint main(){\n while( scanf(\"%d %d\",&N,&M), N|M ){\n rep(i,N) scanf(\"%lf %lf\",&ps[i].x,&ps[i].y);\n scanf(\"%d %d %d %lf %lf %lf\",&Ume,&Momo,&SakuraHappyInnovation,d,d+1,d+2);\n limit[0] = Ume, limit[1] = Momo, limit[2] = SakuraHappyInnovation;\n rep(i,Ume) scanf(\"%lf %lf\",&p[0][i].x,&p[0][i].y);\n rep(i,Momo) scanf(\"%lf %lf\",&p[1][i].x,&p[1][i].y);\n rep(i,SakuraHappyInnovation) scanf(\"%lf %lf\",&p[2][i].x,&p[2][i].y);\n rep(i,M) scanf(\"%lf %lf\",w+i,a+i);\n compute();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1248, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0269_956039", "code_snippet": "//自分の梅は任意の地点でかおるとする。→間違い。\n//EPSはつけない。\n//扇形と家は接しないので、距離はsqrtで求めた。\n\n#include<iostream>\n#include<cmath>\n#include<vector>\n#define rep(i,n) for(i = 0;i < n;i++)\n#define PI 3.14159265358979\nusing namespace std;\n\ntypedef pair<double,double> P;\n\nint H,R;\t\t\t\t//家数,日数\nint hx[100],hy[100];\t//家の座標\nint U,M,S;\t\t\t\t//梅、桃、桜の数\nint du,dm,ds;\t\t\t//梅、桃、桜の扇形の中心角\nint ux[100],uy[100];\t//梅の座標\nint mx[100],my[100];\t//桃の座標\nint sx[100],sy[100];\t//桜の座標\nint w[100],a[100];\t\t//扇形の方向(角度),風の強さ\n\n//半径,角度の順で格納し、返す\n//rotateは角度補正( 補正 = rotate*360 )\nP POLAR( int treex,int treey,int housex,int housey,int rotate )\n{\n\tP ans;\n\tans.first = (housex-treex)*(housex-treex) + (housey-treey)*(housey-treey);\n\tans.first = sqrt( ans.first );\n\tans.second = atan2( (double)housey - treey, (double)housex - treex ) * 180 / PI;\n\tans.second += 360*rotate;\n\treturn ans;\n}\n\nint main()\n{\n\tint i,j,k,l;\n\twhile( cin >> H >> R )\n\t{\n\t\tint day[100] = {0};\t\t//i番目の家において、他の木の香りが届かなかった日数\n\n\t\tif( H == 0 && R == 0 )\n\t\t\tbreak;\n\t\trep(i,H)\n\t\t\tcin >> hx[i] >> hy[i];\n\t\tcin >> U >> M >> S >> du >> dm >> ds;\n\t\trep(i,U)\n\t\t\tcin >> ux[i] >> uy[i];\n\t\trep(i,M)\n\t\t\tcin >> mx[i] >> my[i];\n\t\trep(i,S)\n\t\t\tcin >> sx[i] >> sy[i];\n\t\trep(i,R)\n\t\t\tcin >> w[i] >> a[i];\n\t\t//ここから探索\n\t\trep(i,R){\n\t\t\trep(j,H){\n\t\t\t\trep(k,U){\n\t\t\t\t\trep(l,3){\n\t\t\t\t\t\tP t = POLAR( ux[k],uy[k],hx[j],hy[j],l-1 );\n\t\t\t\t\t\t//判定\n\t\t\t\t\t\tif( t.first <= a[i] && fabs( (double)w[i] - t.second ) <= (double)du/2.0 )\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(l < 3)\n\t\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(k < U)\n\t\t\t\t\tcontinue;\n\t\t\t\trep(k,M){\n\t\t\t\t\trep(l,3){\n\t\t\t\t\t\tP t = POLAR( mx[k],my[k],hx[j],hy[j],l-1 );\n\t\t\t\t\t\t//判定\n\t\t\t\t\t\tif( t.first <= a[i] && fabs( (double)w[i] - t.second ) <= (double)dm/2.0 )\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(l < 3)\n\t\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(k < M)\n\t\t\t\t\tcontinue;\n\t\t\t\trep(k,S){\n\t\t\t\t\trep(l,3){\n\t\t\t\t\t\tP t = POLAR( sx[k],sy[k],hx[j],hy[j],l-1 );\n\t\t\t\t\t\t//判定\n\t\t\t\t\t\tif( t.first <= a[i] && fabs( (double)w[i] - t.second ) <= (double)ds/2.0 )\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(l < 3)\n\t\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(k < S)\n\t\t\t\t\tcontinue;\n\n\t\t\t\t//私の梅の香りは届くのか!!\n\t\t\t\trep(l,3){\n\t\t\t\t\tP t = POLAR( 0,0,hx[j],hy[j],l-1 );\n\t\t\t\t\t//判定\n\t\t\t\t\tif( t.first <= a[i] && fabs( (double)w[i] - t.second ) <= du/2.0 )\n\t\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif( l < 3 )\n\t\t\t\t\tday[j]++;\n\t\t\t}\n\t\t}\n\t\tint maxday = 0;\n\t\trep(i,H){\n\t\t\tmaxday = max( maxday,day[i] );\n\t\t}\n\t\tif( maxday == 0 ){\n\t\t\tcout << \"NA\" << endl;\n\t\t\tcontinue;\n\t\t}\n\n\t\tint lasthouse = 0; \n\t\trep(i,H){\n\t\t\tif( day[i] == maxday ){\n\t\t\t\tlasthouse = i;\n\t\t\t}\n\t\t}\n\t\trep(i,H){\n\t\t\tif( day[i] == maxday ){\n\t\t\t\tcout << i+1;\n\t\t\t\tif( i < lasthouse )\n\t\t\t\t\tcout << ' ';\n\t\t\t\telse\n\t\t\t\t\tcout << endl;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1256, "score_of_the_acc": -0.7503, "final_rank": 18 }, { "submission_id": "aoj_0269_895510", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <complex>\n#include <vector>\n#include <cmath>\nusing namespace std;\ntypedef complex<double> P;\n\nconst double PI = acos(-1);\nconst double EPS = 1e-9;\nbool hit(P p,double a,double b,double r){\n\tif( abs(p) > r + EPS ) return false;\n\tdouble deg = atan2(p.imag(),p.real());\n\tif( a <= deg && deg <= b ) return true;\n\tif( a <= deg+2*PI && deg+2*PI <= b ) return true;\n\tif( a <= deg-2*PI && deg-2*PI <= b ) return true;\n\treturn false;\n}\nint main(){\n\tint H,R;\n\twhile(cin >> H >> R && H){\n\t\tP home[100];\n\t\tfor(int i = 0 ; i < H ; i++) cin >> home[i].real() >> home[i].imag();\n\t\tint U,M,S;\n\t\tdouble du,dm,ds;\n\t\tcin >> U >> M >> S >> du >> dm >> ds;\n\t\tdu = du / 180.*PI;\n\t\tdm = dm / 180.*PI;\n\t\tds = ds / 180.*PI;\n\t\tdu /= 2;\n\t\tdm /= 2;\n\t\tds /= 2;\n\t\tvector< pair<P,double> > flower;\n\t\tfor(int i = 0 ; i < U+M+S ; i++){\t\n\t\t\tP p; cin >> p.real() >> p.imag();\n\t\t\tflower.push_back(make_pair(p,(i<U?du:i<U+M?dm:ds)));\n\t\t}\n\t\tint answer[110] = {};\n\t\tfor(int i = 0 ; i < R ; i++){\n\t\t\tdouble w,r;\n\t\t\tcin >> w >> r;\n\t\t\tw = w / 180. * PI;\n\t\t\tfor(int j = 0 ; j < H ; j++){\n\t\t\t\tint ok = hit(home[j],w-du,w+du,r);\n\t\t\t\t//cout << w-du << \" \" << w+du << endl;\n\t\t\t\tfor(int k = 0 ; k < U+M+S ; k++){\n\t\t\t\t\tok &= !hit(home[j]-flower[k].first,w-flower[k].second,w+flower[k].second,r);\n\t\t\t\t}\n\t\t\t\tanswer[j] += ok;\n\t\t\t}\n\t\t}\n\t\tint maximum = *max_element(answer,answer+H);\n\t\tint fst = 1;\n\t\tif( maximum == 0 ){ cout << \"NA\" << endl; goto exit; }\n\n\t\tfor(int i = 0 ; i < H ; i++)\n\t\t\tif( maximum == answer[i] ){\n\t\t\t\tif( fst == 0 ) cout << \" \";\n\t\t\t\tcout << i+1;\n\t\t\t\tfst = 0;\n\t\t\t}\n\t\tcout << endl;\n\t\texit:;\n\t}\n\t\n\t\n\t\n\t\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1312, "score_of_the_acc": -0.0024, "final_rank": 5 } ]
aoj_0272_cpp
寂しがり屋のついた嘘 パケットモンスターというゲームがあります。モンスターを捕まえ、育て、戦わせたり交換したりするゲームで、日本中で大流行しています。もちろん、わたしのクラスでも。だからわたしもこのゲームでみんなと遊べるようにモンスターを育てているけど、悲しいことに対戦する相手がいません。わたしは積極的に人に話しかけるのが得意なタイプではないからです。だから今日も、クラスメイトが誘ってくれるのを待ちながら、独り寂しくモンスターのレベルを上げています。 そしてついに、待ち望んでいた瞬間が訪れました。クラスメイトの一人が対戦しないかとわたしに話を持ちかけてきたのでした。彼女は自慢気に、彼女のモンスターたちを見せてくれました。 一般的なパケットモンスターの対戦ルールでは、各プレイヤーがそれぞれN 匹のモンスターを用意し、互いに1 匹ずつ戦わせます。各モンスターには成長の度合いを示す「レベル」という数値があり、レベルが大きいモンスターが必ず勝ちます。同レベルのときは引き分けです。一度戦ったモンスターは、それ以上戦わせることができません。こうして一対一の戦いをN 回行ったあと、過半数の勝利を収めたプレイヤーが勝者となります。 わたしは、彼女のモンスターを見た瞬間、嫌な予感がしました。彼女のモンスターはどれも、とても強そうなのです。わたしと戦ってくれるのなら負けてもかまいません。でも、あまりにもひどい負け方をしたら、"こいつと戦っても面白くないな"とか思われて、もう遊んでくれなくなるんじゃないかな。それは、とても嫌です。だから、 「ごめん、わたしまだモンスターをN 匹持ってなくて」 嘘をつきました。 N 回勝負では勝ち目がなくても、それより少ない数のモンスターで勝負する特別ルールなら、もしかしたら勝てるかもしれません。さっきは負けたってかまわないと言ったけど、やっぱり勝てたら嬉しいです。 彼女はこの特別ルールを受け入れてくれました。つまり、二人が持っているモンスターからお互いに k 匹選んで一匹ずつ順番に戦わせ、過半数の(つまり、k/2 より大きな数の) 勝利を収めた方が勝ちとなります。 さっきわたしは、彼女のモンスターのレベルを知ってしまいました。彼女がどのモンスターを選び、どんな順番で出してくるのかはわかりません。でも、対戦させるモンスターの数kをわたしがうまく決めれば、彼女がどんな選択をしようとわたしが勝つことができるかもしれません。 皆さんにお願いです。モンスターの数 N と、二人が持っているモンスターのレベルを入力すると、彼女がどんな選択をしようとわたしが勝てるような最小のモンスターの数 k を出力するプログラムを作成して下さい。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 N a 1 a 2 ... a N b 1 b 2 ... b N 1行目にモンスターの数 N (1 ≤ N ≤ 40000) が与えられる。2行目に自分のモンスターのレベル a i (1 ≤ a i ≤ 100000) が1つの空白区切りで与えられる。3行目にクラスメイトのモンスターのレベル b i (1 ≤ b i ≤ 100000) が1つの空白区切りで与えられる。 データセットの数は 50 を超えない。 出力 データセットごとに、k (1 ≤ k < N) が存在すれば最小値を1行に出力する。もし、k が存在しないか、k が N に等しければ NA と出力する。 入力例 10 4 9 1 9 5 9 2 3 2 1 8 7 6 5 10 5 5 4 7 6 5 4 3 2 5 1 4 4 4 4 4 4 4 1 3 2 4 3 2 1 0 出力例 3 1 NA 1つ目のデータセットでは、わたしは3匹での対戦を提案し、レベルが [9, 9, 9] のモンスターを選べば良い。相手のレベル 10 以外のどのモンスターにも勝てるので、少なくとも2勝できる。2匹での対戦では 1勝1敗になる可能性があり、これは過半数の勝利とは言えないので、2 は答えにならない。 2つ目のデータセットでは、わたしは最強のモンスターを1匹選べば良い。 3つ目のデータセットでは、わたしがどの k 匹を選び、どの順番で出したとしても、彼女が全く同じモンスターを同じ順番で出してきて引き分けになる可能性がある。したがって、「彼女がどんな選択をしようとわたしが勝つことができる」とは言い切れない。
[ { "submission_id": "aoj_0272_10774072", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconstexpr int N = 40000;\nint a[N], b[N];\nint cnt[N];\nint n;\n\nvoid solve() {\n for (int i = 0; i < n; ++i) cin >> a[i];\n for (int i = 0; i < n; ++i) cin >> b[i];\n sort(a, a + n);\n sort(b, b + n);\n\n int i = n - 1, j = n - 1;\n while (i >= 0 && j >= 0) {\n if (a[i] > b[j]) {\n cnt[i] = 1;\n --i;\n } else {\n cnt[i] = 0;\n --i;\n --j;\n }\n }\n for (int i = n - 2; i >= 0; --i) {\n cnt[i] += cnt[i + 1];\n }\n for (int k = 1; k < n; ++k) {\n int need = k / 2 + 1;\n if (cnt[n - k] >= need) {\n cout << k << '\\n';\n return;\n }\n }\n cout << \"NA\\n\";\n}\n\nint main() {\n#ifdef LOCAL\n freopen(\"in.txt\", \"r\", stdin);\n#endif\n while (true) {\n cin >> n;\n if (n == 0) break;\n solve();\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3908, "score_of_the_acc": -0.7326, "final_rank": 11 }, { "submission_id": "aoj_0272_10772800", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n#ifdef LOCAL\n freopen(\"in.txt\", \"r\", stdin);\n#endif\n\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n while (true) {\n int N;\n cin >> N;\n if (!cin || N == 0) break;\n\n vector<int> A(N), B(N);\n for (int i = 0; i < N; i++) cin >> A[i];\n for (int i = 0; i < N; i++) cin >> B[i];\n\n sort(A.begin(), A.end());\n sort(B.begin(), B.end());\n\n // Собираем жадные блокирующие пары для полного массива\n vector<int> matched;\n int i = N - 1, j = N - 1;\n while (i >= 0 && j >= 0) {\n if (B[j] >= A[i]) {\n matched.push_back(min(i, j));\n i--;\n j--;\n } else {\n i--;\n }\n }\n sort(matched.begin(), matched.end());\n\n // Ищем минимальное k\n int answer = -1;\n for (int k = 1; k < N; k++) {\n int s = N - k;\n auto it = lower_bound(matched.begin(), matched.end(), s);\n int blocks = matched.end() - it;\n int wins = k - blocks;\n if (wins * 2 > k) {\n answer = k;\n break;\n }\n }\n\n if (answer == -1)\n cout << \"NA\\n\";\n else\n cout << answer << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3976, "score_of_the_acc": -0.4595, "final_rank": 8 }, { "submission_id": "aoj_0272_5897007", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<map>\n#include<queue>\n#include<stack>\n#include<set>\n#include<bitset>\n#include<vector>\n#include<string>\n#include <iomanip>\n#include <deque>\n#include<list>\n#include<cmath>\n#define rep(i,n) for(int i=0;i<(n);i++)\nusing namespace std;\nusing ll=long long;\nusing P=pair<int,int>;\nusing P_S=pair<int,string>;\nusing P_D=pair<double,int>;\nusing T=tuple<int,int,char,ll,string>;\n\nint main(){\n while(1){\n int n;\n cin>>n;\n if(n==0) break;\n vector<int> a(n),b(n);\n rep(i,n) cin>>a[i];\n rep(i,n) cin>>b[i];\n sort(a.begin(),a.end());\n sort(b.begin(),b.end());\n int a_w=0,b_w=0,count=0,id=n-1;\n for(int i=n-1;i>=0;i--){\n count++;\n if(a[i]>b[id]) a_w++;\n else if(a[i]<=b[id]) id--;\n if(a_w>count/2) break;\n }\n if(count==n) cout<<\"NA\"<<endl;\n else cout<<count<<endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3472, "score_of_the_acc": -0.5979, "final_rank": 9 }, { "submission_id": "aoj_0272_5749936", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<stdlib.h>\n#include<string.h>\n\n\n\nint A[40001];\nint A_d[40001];\nint B[40001];\nint B_d[40001];\nint count[100006];\n\nint getpartition(int a[], int p, int r)\n{\n\tint x = a[r];\n\tint k = p - 1;\n\tint tmp;\n\tfor (int i = p; i < r; i++)\n\t{\n\t\tif (a[i] >= x)\n\t\t{\n\t\t\tk++;\n\t\t\ttmp = a[k];\n\t\t\ta[k] = a[i];\n\t\t\ta[i] = tmp;\n\t\t}\n\t}\n\tk++;\n\ttmp = a[k];\n\ta[k] = x;\n\ta[r] = tmp;\n\treturn k;\n}\n\nvoid quickSort(int a[], int n, int p, int r)\n{\n\tif (p < r)\n\t{\n\t\tint m = getpartition(a, p, r);\n\t\tquickSort(a, n, p, m - 1);\n\t\tquickSort(a, n, m + 1, r);\n\t}\n}\n\n\nvoid countSort(int a[],int d[], int n)\n{\n\tmemset(count, 0, sizeof(count));\n\tfor (int i = 0; i < n; i++)\n\t\tcount[a[i]]++;\n\tfor (int i = 100000; i >= 0; i--)\n\t\tcount[i] = count[i] + count[i + 1];\n\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\td[count[a[i]] - 1] = a[i];\n\t\tcount[a[i]]--;\n\t}\n}\n\n\nvoid slove(int n)\n{\n\t//quickSort(A, n, 0, n - 1);\n\t//quickSort(B, n, 0, n - 1);\n\tcountSort(A_d, A, n);\n\tcountSort(B_d, B, n);\n\n\n\tint ai = 0;\n\tint mk = 0;\n\tint idex = 0;\n\tfor (int i = 0; i < n-1; i++)\n\t{\n\t\tmk = (i + 1) / 2;\n\t\tif (A[i] > B[idex])\n\t\t{\n\t\t\tai++;\n\t\t\tif (ai > mk)\n\t\t\t{\n\t\t\t\t\n\t\t\t\tprintf(\"%d\\n\", i + 1);\n\t\t\t\treturn ;\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n\t\t\tidex++;\n\t\t}\n\n\t\t//if ((i-ai) > n / 2)\n\t\t//\tbreak;\n\t}\n\t\n\tprintf(\"NA\\n\");\n\t\n}\n\nint main()\n{\n\tint n;\n\twhile (1)\n\t{\n\t\tstd::cin >> n;\n\t\tif (n == 0) break;\n\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tstd::cin >> A_d[i];\n\t\t}\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tstd::cin >> B_d[i];\n\t\t}\n\t\tslove(n);\n\t}\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4208, "score_of_the_acc": -0.943, "final_rank": 14 }, { "submission_id": "aoj_0272_5702231", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 40005\n\nint N;\nint A[SIZE],B[SIZE];\n\nvoid func(){\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&B[i]);\n\t}\n\n\tsort(A,A+N);\n\tsort(B,B+N);\n\n\treverse(A,A+N);\n\treverse(B,B+N);\n\n\t/*「私」は降順に出す 敵はなるべく負けを減らそうとする*/\n\n\tint all = 0;\n\tint index = 0;\n\tint num_lose = 0;\n\n\t//敵目線\n\tfor(int i = 0; i < N-1; i++){ //N回は不可(問題の制約)\n\n\t\tall++;\n\t\tint need;\n\t\tif(all%2 == 0){\n\n\t\t\tneed = all/2 +1;\n\t\t}else{\n\n\t\t\tneed = (all+1)/2;\n\t\t}\n\n\n\t\tif(B[index] < A[i]){ //勝てる手がない:Bはなるべく自分の中で小さいものを割り当てる\n\n\t\t\tnum_lose++;\n\n\n\t\t\tif(num_lose >= need){\n\n\t\t\t\tprintf(\"%d\\n\",all);\n\t\t\t\treturn;\n\t\t\t}\n\t\t}else{ //引き分け以上\n\n\t\t\tindex++;\n\t\t}\n\t}\n\n\tprintf(\"NA\\n\");\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d\",&N);\n\t\tif(N == 0)break;\n\n\t\tfunc();\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3484, "score_of_the_acc": -0.2487, "final_rank": 6 }, { "submission_id": "aoj_0272_5396148", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\n \t \t\nint main() {\n\t int i,j,n,c,w;\n\t vector<int> a,b;\n\t while(cin >> n) {\n\t \tif (n == 0) break;\n\t \ta.clear(); b.clear();\n\t \tfor (i=0;i<n;i++) { cin >> c; a.push_back(c);}\n\t \tfor (i=0;i<n;i++) { cin >> c; b.push_back(c);}\n\t \tsort(a.begin(),a.end()); sort(b.begin(),b.end());\n\t \tc=n-1; w=0;\n\t \tfor (i=n-1; i>=0; i--) {\n\t \t\tif (a[i]<=b[c]) c--; else {\tw++; if (w*2>n-i && i>0) {cout << n-i << endl; break;}}\n\t \t\t}\n\t if (i<0) cout << \"NA\" << endl;\t\t\n\t \t}\t\t\n\t return 0;\n\t}", "accuracy": 1, "time_ms": 230, "memory_kb": 3448, "score_of_the_acc": -0.8846, "final_rank": 13 }, { "submission_id": "aoj_0272_4985503", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int> \n#define vvel V<V<int>>\n#define pin pair<int,int>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mkp make_pair\n#define mmax(a,b) a=max(a,b)\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)\n#define upperbound(v,val) upper_bound(v.begin(),v.end(),val)\n#define rev(v) reverse(v.begin(),v.end());\n#define mmin(a,b) a=min(a,b)\nsigned main() {\n\twhile (true) {\n\t\tint n; cin >> n;\n\t\tif (n == 0) { break; }\n\t\tvel a(n), b(n);\n\t\trep(i, n) { cin >> a[i]; }\n\t\trep(i, n) { cin >> b[i]; }\n\t\tsor(a);\n\t\tsor(b);\n\t\tint now_max = n + 10;\n\t\tvel cnt(n, 0);\n\t\tfor (int i = n - 1; i >= 0; i--) {\n\t\t\tint nex = upperbound(a, b[i]) - a.begin();\n\t\t\tnex--;\n\t\t\tmmin(nex, now_max - 1);\n\t\t\tif (nex >= 0) {\n\t\t\t\tnow_max = nex;\n\t\t\t\tcnt[nex]++;\n\t\t\t}\n\t\t}\n\t\trev(cnt);\n\t\tint sum = 0;\n\t\trep(i, n) {\n\t\t\tif (i == n - 1) {\n\t\t\t\tcout << \"NA\" << endl; break;\n\t\t\t}\n\t\t\tsum += cnt[i];\n\t\t\tif ((i+1-sum) * 2 > i+1) {\n\t\t\t\tcout << i+1 << endl; break;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3840, "score_of_the_acc": -1.0646, "final_rank": 17 }, { "submission_id": "aoj_0272_4976751", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define chmin(a,b) a=min(a,b)\n#define chmax(a,b) a=max(a,b)\n#define mod 1000000007\n#define ad(a,b) a=(a+b)%mod;\n#define X 5010\nll po(ll x,ll y){\n\tll res=1;\n\tfor(;y;y>>=1){\n\t\tif(y&1)res=res*x%mod;\n\t\tx=x*x%mod;\n\t}\n\treturn res;\n}\nll fac[X],ivf[X];\nvoid init(){\n\tfac[0]=1;\n\tfor(ll i=1;i<X;i++)fac[i]=fac[i-1]*i%mod;\n\tfor(ll i=0;i<X;i++)ivf[i]=po(fac[i],mod-2);\n}\nll C(ll n,ll k){\n\treturn fac[n]*ivf[n-k]%mod*ivf[k]%mod;\n}\nbool solve(){\n\tll n,a[40010],b[40010];\n\tcin>>n;\n\tif(n==0)return 0;\n\trep(i,n)cin>>a[i]; sort(a,a+n); reverse(a,a+n);\n\trep(i,n)cin>>b[i]; sort(b,b+n); reverse(b,b+n);\n\tint p=0;\n\trep(k,n-1){\n\t\tif(a[k]<=b[p])p++;\n\t\tif(k-p>=(k+1)/2){\n\t\t\tcout<<k+1<<endl;\n\t\t\treturn 1;\n\t\t}\n\t}\n\tcout<<\"NA\"<<endl;\n\treturn 1;\n}\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\twhile(solve()){}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3804, "score_of_the_acc": -0.2299, "final_rank": 5 }, { "submission_id": "aoj_0272_4917898", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\ntypedef long long ll;\n#define INF 1000000000\n\nint a[40404],b[40404],c[40404];\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n while(1){\n int n; cin>>n;\n if(!n) break;\n\n rep(i,n) cin>>a[i]; rep(i,n) cin>>b[i];\n sort(a,a+n);\n sort(b,b+n);\n rep(i,n) c[i] = lower_bound(a, a+n, b[i] + 1) - a - 1;\n\n bool ok = false;\n for(int i=1;i<n;i++){\n if(c[n - (i+1)/2] < n - i){\n cout << i << endl;\n ok = true;\n break;\n }\n }\n if(!ok) cout << \"NA\" << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3712, "score_of_the_acc": -0.2603, "final_rank": 7 }, { "submission_id": "aoj_0272_4917844", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nint main(){\n int n;\n\n while(cin >> n, n){\n vector<int> a(n + 1);\n for(int i = 1 ; i <= n ; ++i){\n cin >> a[i];\n }\n\n vector<int> b(n + 1);\n for(int i = 1 ; i <= n ; ++i){\n cin >> b[i];\n }\n\n sort(a.begin() + 1, a.end(), greater<int>());\n sort(b.begin() + 1, b.end(), greater<int>());\n\n vector<int> sum(n + 1, 0);\n int ai = 1, bi = 1;\n while(ai <= n && bi <= n){\n if(a[ai] <= b[bi]){\n ++sum[ai];\n ++ai;\n ++bi;\n }\n while(ai <= n && a[ai] > b[bi]){\n ++ai;\n }\n }\n\n for(int i = 2 ; i <= n ; ++i){\n sum[i] += sum[i - 1];\n }\n\n int ans = -1;\n for(int k = 1 ; k < n ; ++k){\n if((k + 2) / 2 <= k - sum[k]){\n ans = k;\n break;\n }\n }\n\n if(ans == -1){\n cout << \"NA\" << endl;\n }else{\n cout << ans << endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3644, "score_of_the_acc": -0.6511, "final_rank": 10 }, { "submission_id": "aoj_0272_4736088", "code_snippet": "#include<string.h>\n#include<iostream>\n#include<string>\n#include <vector>\n#include<algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\twhile (n)\n\t{\n\t\tvector<pair<int, int> > vec;\n\t\tint m;\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tcin >> m;\n\t\t\tvec.push_back(make_pair(m, 0));\n\t\t}\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tcin >> m;\n\t\t\tvec.push_back(make_pair(m, 1));\n\t\t}\n\t\tsort(vec.begin(), vec.end(), greater<pair<int, int>>());\n\t\tint _countA = 0,_countB = 0;\n\t\tint v = 0, noV = 0;\n\t\tauto iter = vec.begin();\n\t\tbool ok = false;\n\t\twhile (iter != vec.end())\n\t\t{\n\t\t\tif (iter->second == 0)\n\t\t\t{\n\t\t\t\t_countA++;\n\t\t\t\tif (noV == 0)\n\t\t\t\t\tv++;\n\t\t\t\telse\n\t\t\t\t\tnoV--;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\t_countB++;\n\t\t\t\tnoV++;\n\t\t\t}\n\t\t\tint k = max(_countA, _countB);\n\t\t\tif (k == n)\n\t\t\t{\n\t\t\t\tok = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (v > k / 2)\n\t\t\t{\n\t\t\t\tok = true;\n\t\t\t\tcout << k << endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\titer++;\n\t\t}\n\t\tif (!ok)\n\t\t\tcout << \"NA\" << endl;\n\t\tcin >> n;\n\t}\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 4416, "score_of_the_acc": -1.3602, "final_rank": 19 }, { "submission_id": "aoj_0272_4567847", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint N, K;\nvector<int> MyMonster, Opponent;\n\n\nbool solve() {\n\tint myIndex, cnt;\n\n\tsort(MyMonster.begin(), MyMonster.end(), greater<int>());\n\tsort(Opponent.begin(), Opponent.end(), greater<int>());\n\n\tmyIndex = 0;\n\tcnt = 0;\n\tK = 40001;\n\tfor (int i = 0; i < N; ++i) {\n\t\twhile (myIndex < N - 1) {\n\t\t\tif (Opponent[i] >= MyMonster[myIndex]) {\n\t\t\t\t++myIndex;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t++cnt;\n\t\t\tif (cnt >= ((myIndex + 1) / 2 + 1)) {\n\t\t\t\tK = myIndex + 1;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t\t++myIndex;\n\t\t}\n\t\tif (myIndex == N - 1) {\n\t\t\treturn false;\n\t\t}\n\t}\n}\n\nint main() {\n\tint num;\n\n\twhile (cin >> N, N) {\n\t\tMyMonster.clear();\n\t\tOpponent.clear();\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcin >> num;\n\t\t\tMyMonster.push_back(num);\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcin >> num;\n\t\t\tOpponent.push_back(num);\n\t\t}\n\t\t//show();\n\t\tif (solve()) {\n\t\t\tcout << K << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \"NA\" << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3528, "score_of_the_acc": -0.9682, "final_rank": 15 }, { "submission_id": "aoj_0272_4567838", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint N, K;\nvector<int> MyMonster, Opponent;\n\n\nbool solve() {\n\tint myIndex, cnt;\n\n\tsort(MyMonster.begin(), MyMonster.end(), greater<int>());\n\tsort(Opponent.begin(), Opponent.end(), greater<int>());\n\n\tmyIndex = 0;\n\tcnt = 0;\n\tK = 40001;\n\tfor (int i = 0; i < N; ++i) {\n\t\twhile (myIndex < N - 1) {\n\t\t\tif (Opponent[i] >= MyMonster[myIndex]) {\n\t\t\t\t++myIndex;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t++cnt;\n\t\t\tif (cnt >= ((myIndex + 1) / 2 + 1)) {\n\t\t\t\tK = myIndex + 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t++myIndex;\n\t\t}\n\t\tif (myIndex == N - 1 || K != 40001) {\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (K != 40001) {\n\t\treturn true;\n\t}\n\n\treturn false;\n}\n\nint main() {\n\tint num;\n\n\twhile (cin >> N, N) {\n\t\tMyMonster.clear();\n\t\tOpponent.clear();\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcin >> num;\n\t\t\tMyMonster.push_back(num);\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcin >> num;\n\t\t\tOpponent.push_back(num);\n\t\t}\n\t\t//show();\n\t\tif (solve()) {\n\t\t\tcout << K << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << \"NA\" << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3528, "score_of_the_acc": -0.9682, "final_rank": 15 }, { "submission_id": "aoj_0272_4487323", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nvoid solve(int n){\n vector<int> A(n), B(n);\n for (auto &&i : A) scanf(\"%d\", &i);\n for (auto &&i : B) scanf(\"%d\", &i);\n sort(A.begin(),A.end(), greater<>());\n sort(B.begin(),B.end(), greater<>());\n int cur = 0;\n for (int i = 1; i < n; ++i) {\n if(A[i-1] <= B[cur]) cur++;\n if(i-i/2 > cur) {\n cout << i << \"\\n\";\n return;\n }\n }\n puts(\"NA\");\n}\n\nint main() {\n int n;\n while(cin >> n, n) solve(n);\n\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3340, "score_of_the_acc": -0.2042, "final_rank": 4 }, { "submission_id": "aoj_0272_4345503", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<functional>\nusing namespace std;\nstatic const int MAX_N = 40000;\n\nint n;\nint a[MAX_N], b[MAX_N];\n\nint main(){\n\tfor(;;){\n\t\tscanf(\"%d\", &n);\n\t\tif(n == 0) break;\n\t\tfor(int i = 0; i < n; i++) scanf(\"%d\", &a[i]);\n\t\tfor(int i = 0; i < n; i++) scanf(\"%d\", &b[i]);\n\t\tsort(a, a + n, greater<int>());\n\t\tsort(b, b + n, greater<int>());\n\t\tint res = -1;\n\t\tint cnt = 0;\n\t\tint index = 0;\n\t\tfor(int i = 0; i < n - 1; i++){\n\t\t\tif(a[i] <= b[index]) index++;\n\t\t\telse cnt++;\n\t\t\tif(cnt > (i + 1) / 2){\n\t\t\t\tres = i + 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(res == -1) printf(\"NA\\n\");\n\t\telse printf(\"%d\\n\", res);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3060, "score_of_the_acc": -0.1176, "final_rank": 2 }, { "submission_id": "aoj_0272_4205283", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nbool solve(){\n ll n, r;\n cin >> n;\n if(n == 0) return true;\n vector<P> v;\n for(int i=0;i<n;i++){\n int a;\n cin >> a;\n v.push_back(P(a,0));\n }\n for(int i=0;i<n;i++){\n int b;\n cin >> b;\n v.push_back(P(b,1));\n }\n sort(v.rbegin(),v.rend());\n int ans = 0, cnt = 0, s = 0;\n for(int i=0;i<n*2;i++){\n if(v[i].second == 0){\n cnt++;\n s++;\n if(s > cnt/2){\n ans = cnt;\n break;\n }\n }else{\n s--;\n }\n }\n if(ans > 0 && ans < n){\n cout << ans << endl;\n }else{\n cout << \"NA\" << endl;\n }\n return false;\n}\n\nint main() {\n while(!solve());\n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 4428, "score_of_the_acc": -1.4227, "final_rank": 20 }, { "submission_id": "aoj_0272_3447582", "code_snippet": "// includes {{{\n#include<iostream>\n#include<iomanip>\n#include<algorithm>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<map>\n#include<set>\n#include<tuple>\n#include<cmath>\n#include<random>\n#include<cassert>\n#include<bitset>\n#include<cstdlib>\n// #include<deque>\n// #include<multiset>\n// #include<cstring>\n// #include<bits/stdc++.h>\n// }}}\nusing namespace std;\nusing ll = long long;\n\n// #undef DEBUG\n// #define DEBUG\n// DEBUG {{{\n#include <array>\n#include <deque>\n#include <list>\n#include <ostream>\n#include <queue>\n#include <stack>\n#include <tuple>\n#include <valarray>\n#include <vector>\ntemplate < int n, class... T >\ntypename std::enable_if< (n >= sizeof...(T)) >::type __output_tuple(\n std::ostream &, std::tuple< T... > const &) {}\ntemplate < int n, class... T >\ntypename std::enable_if< (n < sizeof...(T)) >::type __output_tuple(\n std::ostream &os, std::tuple< T... > const &t) {\n os << (n == 0 ? \"\" : \", \") << std::get< n >(t);\n __output_tuple< n + 1 >(os, t);\n}\ntemplate < class... T >\nstd::ostream &operator<<(std::ostream &os, std::tuple< T... > const &t) {\n os << \"(\";\n __output_tuple< 0 >(os, t);\n os << \")\";\n return os;\n}\ntemplate < class T, class U >\nstd::ostream &operator<<(std::ostream &os, std::pair< T, U > const &p) {\n os << \"(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate < class T >\nstd::ostream &operator<<(std::ostream &os, const std::stack< T > &a) {\n os << \"{\";\n for(auto tmp = a; tmp.size(); tmp.pop())\n os << (a.size() == tmp.size() ? \"\" : \", \") << tmp.top();\n os << \"}\";\n return os;\n}\ntemplate < class T, class Container, class Compare >\nstd::ostream &operator<<(std::ostream &os,\n std::priority_queue< T, Container, Compare > a) {\n os << \"{ (top) \";\n while(a.size()) os << a.top() << (a.size() == 1 ? \"\" : \", \"), a.pop();\n os << \" }\";\n return os;\n}\ntemplate < class T, class Container >\nstd::ostream &operator<<(std::ostream &os, std::queue< T, Container > a) {\n os << \"{ \";\n while(a.size()) os << a.front() << (a.size() == 1 ? \"\" : \", \"), a.pop();\n os << \" }\";\n return os;\n}\n#ifdef DEBUG\n#if !defined(DEBUG_OUT)\n#define DEBUG_OUT std::cerr\n#endif\n#define dump(...) \\\n [&]() { \\\n auto __debug_tap = std::make_tuple(__VA_ARGS__); \\\n DEBUG_OUT << \"[\" << __LINE__ << \"] \" << #__VA_ARGS__ << \" = \" << __debug_tap \\\n << std::endl; \\\n }()\ntemplate < class T >\ninline void dump2D(T &d, size_t sizey, size_t sizex) {\n for(size_t i = 0; i < sizey; i++) {\n DEBUG_OUT << \"\\t\";\n for(size_t j = 0; j < sizex; j++)\n DEBUG_OUT << d[i][j] << (j + 1 == sizex ? \"\" : \"\\t\");\n DEBUG_OUT << std::endl;\n }\n}\ntemplate < class T >\ninline void dump1D(T &d, size_t sizey) {\n for(size_t i = 0; i < sizey; i++) {\n DEBUG_OUT << d[i] << (i + 1 == sizey ? \"\" : \" \");\n }\n DEBUG_OUT << std::endl;\n}\ntemplate <\nclass T, class = typename std::iterator_traits< decltype(begin(T())) >::value_type,\n class = typename std::enable_if< !std::is_same< T, std::string >::value >::type >\n std::ostream &operator<<(std::ostream &os, const T &a) {\n os << \"{\";\n for(auto ite = begin(a); ite != end(a); ++ite)\n os << (ite == begin(a) ? \"\" : \", \") << *ite;\n os << \"}\";\n return os;\n }\n#else\n#define dump(...) (42)\n#define dump2D(...) (42)\n#define dump1D(...) (42)\ntemplate <\nclass T, class = typename std::iterator_traits< decltype(begin(T())) >::value_type,\n class = typename std::enable_if< !std::is_same< T, std::string >::value >::type >\n std::ostream &operator<<(std::ostream &os, const T &a) {\n for(auto ite = begin(a); ite != end(a); ++ite)\n os << (ite == begin(a) ? \"\" : \" \") << *ite;\n return os;\n }\n#endif\n// }}}\n\n\nint main() {\n std::ios::sync_with_stdio(false), std::cin.tie(0);\n while(1) {\n int n;\n cin >> n;\n if(n == 0) break;\n vector<int> a(n), b(n);\n for(auto &e : a) cin >> e;\n for(auto &e : b) cin >> e;\n sort(a.begin(), a.end());\n sort(b.begin(), b.end());\n int head = n - 1;\n int lose = 0;\n int ans = -1;\n for(int i = 0; i < n; i++) {\n if(a[n-1-i] <= b[head]) head--, lose++;\n int win = i + 1 - lose;\n if(win * 2 > i + 1) {\n ans = i + 1;\n break;\n }\n }\n if(ans == n) ans = -1;\n if(ans == -1) {\n cout << \"NA\\n\";\n } else {\n cout << ans << \"\\n\";\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3256, "score_of_the_acc": -0.0606, "final_rank": 1 }, { "submission_id": "aoj_0272_3421375", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nint main(){\n int n;\n while(cin >> n, n){\n vector<int> a(n), b(n);\n for(int i = 0; i < n; i++) cin >> a[i];\n for(int i = 0; i < n; i++) cin >> b[i];\n sort(a.rbegin(), a.rend());\n sort(b.rbegin(), b.rend());\n vector<int> wod(n, 0);\n int acur = 0, bcur = 0;\n while(acur < n && bcur < n){\n while(acur < n && b[bcur] < a[acur]) acur++;\n if(acur < n){\n wod[acur]++;\n bcur++;\n }\n }\n for(int i = 1; i < n; i++) wod[i] += wod[i-1];\n int k;\n for(k = 0; k < n; k++){\n if((k+1) - wod[k] > (k+1)/2) break;\n }\n if(k >= n-1) cout << \"NA\" << endl;\n else cout << k+1 << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3400, "score_of_the_acc": -0.8698, "final_rank": 12 }, { "submission_id": "aoj_0272_3334574", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#pragma warning (disable: 4996)\n\nint N, A[1 << 18], B[1 << 18], C[1 << 18];\n\nvoid init() {\n\tN = 0;\n\tfor (int i = 0; i < (1 << 18); i++) { A[i] = 0; B[i] = 0; C[i] = 0; }\n}\nint solve() {\n\tsort(A, A + N); reverse(A, A + N);\n\tsort(B, B + N); \n\n\tfor (int i = 0; i < N; i++) {\n\t\tint pos1 = lower_bound(B, B + N, A[i] + 1) - B;\n\t\tC[i] = (N - pos1) - i;\n\t}\n\tint maxn = 0, ret = (1 << 30);\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tmaxn = max(maxn, C[i / 2]);\n\t\tif (maxn > (i + 1) / 2) { ret = min(ret, i + 1); break; }\n\t}\n\treturn ret;\n}\n\nint main() {\n\twhile (true) {\n\t\tinit();\n\t\tcin >> N; if (N == 0) break;\n\t\tfor (int i = 0; i < N; i++) scanf(\"%d\", &B[i]);\n\t\tfor (int i = 0; i < N; i++) scanf(\"%d\", &A[i]);\n\t\tint ans = solve();\n\t\tif (ans == (1 << 30)) cout << \"NA\" << endl;\n\t\telse cout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 6296, "score_of_the_acc": -1.2353, "final_rank": 18 }, { "submission_id": "aoj_0272_3258259", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N;\n\twhile (cin >> N, N) {\n\t\tvector<int> A(N), B(N);\n\t\tfor (int i = 0; i < N; ++i) cin >> A[i], A[i] *= -1;\n\t\tfor (int i = 0; i < N; ++i) cin >> B[i], B[i] *= -1;\n\t\tsort(A.begin(), A.end());\n\t\tsort(B.begin(), B.end());\n\t\tint ans = 1 << 30;\n\t\tfor (int i = 0; i < N / 2; ++i) {\n\t\t\tint ptr = lower_bound(A.begin(), A.end(), B[i]) - A.begin();\n\t\t\tint g = (ptr - i) * 2;\n\t\t\tif (i * 2 + 1 <= g) ans = min(ans, i * 2 + 1);\n\t\t}\n\t\tif (ans != (1 << 30)) cout << ans << \"\\n\";\n\t\telse cout << \"NA\\n\";\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3268, "score_of_the_acc": -0.1231, "final_rank": 3 } ]
aoj_0270_cpp
モジュロ・クエリ あなたに N 枚のカードを渡します。どのカードにも一つだけ自然数が書いてあります。 これから質問として、適当な自然数を言います。あなたが持っているカードに書いてある数を私が言った数で割ったときに得られる余りのうち最も大きなものを答えてください。 たとえば、あなたは 3 枚のカードを持っていて、それぞれ 9、3、8 と書いてあるとします。私が「4」と言ったら、9 と 3 と 8 をそれぞれ4 で割った余りを求めてください。余りはそれぞれ 1、3、0 ですが、この中でもっとも大きな余りは3 なので、3 が正しい答えになります。 では始めましょうか。え? カードがいっぱいあるとたいへんだ? しょうがないですね。それではコ ンピュータを使って最大の余りを見つけることにしましょう。カードに書いてある数を、質問された数で割った余りのうち、最大のものを見つけるプログラムを作成してください。なお、質問は1回だけでなく何度もしますが、同じ数を 2 回以上質問することはありません。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 N Q c 1 c 2 ... c N q 1 q 2 : q Q 1行目にカードの枚数 N (2 ≤ N ≤ 300000) と質問の回数 Q (2 ≤ Q ≤ 100000) が1つの空白区切りで与えられ、2行目にカードに書かれた数 c i (1 ≤ c i ≤ 300000) が1つの空白区切りで与えられる。続くQ 行に質問として与えられる数 q i (1 ≤ q i ≤ 300000) が与えられる。 出力 質問ごとに最大の余りを1行に出力する。 入力例 3 3 9 3 8 4 6 5 出力例 3 3 4
[ { "submission_id": "aoj_0270_10853187", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, Q;\n cin >> N >> Q;\n vector<int> c(N);\n int size = 0;\n for(int i=0; i<N; ++i) {\n cin >> c[i];\n size = max(size, c[i]);\n }\n size += 1;\n vector<int> ma(size+1);\n for(int i=0; i<N; ++i) {\n ma[c[i]+1] = c[i];\n }\n for(int i=1; i<size; ++i) {\n ma[i] = max(ma[i], ma[i-1]);\n }\n for(int i=0; i<Q; ++i) {\n int q;\n cin >> q;\n int res = 0;\n for(int now=size-1; now != 0;) {\n res = max(res, now%q);\n now = ma[now - now%q];\n }\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 5244, "score_of_the_acc": -0.8147, "final_rank": 10 }, { "submission_id": "aoj_0270_9930183", "code_snippet": "#include <climits>\n#include <cstdlib>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst size_t N_MIN = 2;\nconst size_t N_MAX = 300000;\nconst size_t Q_MIN = 2;\nconst size_t Q_MAX = 100000;\nconst size_t CQ_MIN = 1;\nconst size_t CQ_MAX = 300000;\n\nint main()\n{\n\tint n = 0;\n\tcin >> n;\n\tif (n < N_MIN || N_MAX < n)\n\t{\n\t\tcout << N_MIN << \" <= n <= \" << N_MAX << \") but input \" << n << endl;\n\t\texit(1);\n\t}\n\tint q = 0;\n\tcin >> q;\n\tif (q < Q_MIN || Q_MAX < q)\n\t{\n\t\tcout << Q_MIN << \" <= q <= \" << Q_MAX << \") but input \" << q << endl;\n\t\texit(1);\n\t}\n\tint cMax = INT_MIN;\n\n\tvector<int> clist(n);\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tcin >> clist[i];\n\t\tif (clist[i] < CQ_MIN || CQ_MAX < clist[i])\n\t\t{\n\t\t\tcout << CQ_MIN << \" <= c\" << \" <= \" << CQ_MAX << \") but input \" << clist[i] << endl;\n\t\t\texit(1);\n\t\t}\n\t\tif (clist[i] > cMax)\n\t\t{\n\t\t\tcMax = clist[i];\n\t\t}\n\t}\n\n\tvector<bool> cmap(cMax + 2);\n\tfor (auto iter : clist)\n\t{\n\t\tcmap[iter] = true;\n\t}\n\n\tvector<int> lmap(cMax + 2);\n\tint m = 0;\n\tfor (int i = 0; i < cMax + 2; i++)\n\t{\n\t\tlmap[i] = m;\n\t\tif (cmap[i])\n\t\t{\n\t\t\tm = i;\n\t\t}\n\t}\n\n\tvector<int> qlist(q);\n\tfor (int i = 0; i < q; i++)\n\t{\n\t\tcin >> qlist[i];\n\t\tif (qlist[i] < CQ_MIN || CQ_MAX < qlist[i])\n\t\t{\n\t\t\tcout << CQ_MIN << \" <= q\" << \" <= \" << CQ_MAX << \") but input \" << qlist[i] << endl;\n\t\t\texit(1);\n\t\t}\n\n\t\tint maxv = 0;\n\t\tint current = m;\n\t\twhile (current != 0)\n\t\t{\n\t\t\tint p = current % qlist[i];\n\t\t\tmaxv = max(maxv, p);\n\t\t\tif (current - p < 0)\n\t\t\t{\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tcurrent = lmap[current - p];\n\t\t}\n\t\tcout << maxv << endl;\n\t}\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 5876, "score_of_the_acc": -1.0675, "final_rank": 13 }, { "submission_id": "aoj_0270_8251434", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n const int UPPER_BOUND_C = 300000;\n int floor_c[UPPER_BOUND_C + 1] = {};\n\n int N, Q; cin >> N >> Q;\n\n for (int c, i = 0; i < N; i++) {\n cin >> c; floor_c[c] = c;\n }\n\n for (int i = 1; i <= UPPER_BOUND_C; i++) {\n floor_c[i] = max(floor_c[i - 1], floor_c[i]);\n }\n\n for (int q, i = 0; i < Q; i++) {\n cin >> q;\n\n int max_r = floor_c[UPPER_BOUND_C] % q;\n for (int j = q; j <= UPPER_BOUND_C; j += q) {\n max_r = max(max_r, floor_c[j - 1] % q);\n }\n\n cout << max_r << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 4580, "score_of_the_acc": -0.3825, "final_rank": 1 }, { "submission_id": "aoj_0270_8251426", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n const int UPPER_BOUND_C = 100000;\n int floor_c[UPPER_BOUND_C + 1] = {};\n\n int N, Q; cin >> N >> Q;\n\n for (int c, i = 0; i < N; i++) {\n cin >> c; floor_c[c] = c;\n }\n\n for (int i = 1; i <= UPPER_BOUND_C; i++) {\n floor_c[i] = max(floor_c[i - 1], floor_c[i]);\n }\n\n for (int q, i = 0; i < Q; i++) {\n cin >> q;\n\n int max_r = floor_c[UPPER_BOUND_C] % q;\n for (int j = q; j <= UPPER_BOUND_C; j += q) {\n max_r = max(max_r, floor_c[j - 1] % q);\n }\n\n cout << max_r << endl;\n }\n\n return 0;\n}", "accuracy": 0.8, "time_ms": 120, "memory_kb": 3728, "score_of_the_acc": 0, "final_rank": 19 }, { "submission_id": "aoj_0270_8251413", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n const int UPPER_BOUND_C = 100000;\n int floor_c[UPPER_BOUND_C + 1] = {};\n\n int N, Q; cin >> N >> Q;\n\n for (int c, i = 0; i < N; i++) {\n cin >> c; floor_c[c] = c;\n }\n\n for (int i = 1; i <= UPPER_BOUND_C; i++) {\n floor_c[i] = max(floor_c[i - 1], floor_c[i]);\n }\n\n for (int q, i = 0; i < Q; i++) {\n cin >> q;\n\n int max_r = floor_c[UPPER_BOUND_C] % q;\n for (int j = q; j < UPPER_BOUND_C; j += q) {\n max_r = max(max_r, floor_c[j - 1] % q);\n }\n\n cout << max_r << endl;\n }\n\n return 0;\n}", "accuracy": 0.6, "time_ms": 120, "memory_kb": 3728, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0270_7617810", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <vector>\n#include <iostream>\n#include <array>\nconstexpr int MaxValue = 300000;\ninline int solve(const std::vector<int>& values , int DivValue){\n int max = 0;\n int ans;\n int LastFlag = 0;\n for(int i = 0; i <= MaxValue; i += DivValue){\n auto itr = std::lower_bound(values.begin() , values.end() , i);\n if(itr == values.end() && LastFlag++) break;\n --itr;\n ans = *itr % DivValue;\n if(max < ans) max = ans;\n }\n return max;\n}\nint main(){\n int N , Q;\n std::cin >> N >> Q;\n std::vector<int> values(N);\n for(auto& value : values) std::cin >> value;\n std::sort(values.begin() , values.end());\n int DivValue;\n for(int i = 0; i < Q; i++){\n std::cin >> DivValue;\n std::cout << solve(values , DivValue) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 4024, "score_of_the_acc": -1.0767, "final_rank": 14 }, { "submission_id": "aoj_0270_7617462", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <vector>\n#include <iostream>\n#include <array>\nconstexpr int MaxValue = 300000;\ninline int solve(const std::vector<int>& values , int DivValue){\n int max = 0;\n int ans;\n for(int i = 0; i <= MaxValue + DivValue; i += DivValue){\n auto itr = std::lower_bound(values.begin() , values.end() , i);\n --itr;\n ans = *itr % DivValue;\n if(max < ans) max = ans;\n }\n return max;\n}\nint main(){\n int N , Q;\n std::cin >> N >> Q;\n std::vector<int> values(N);\n for(auto& value : values) std::cin >> value;\n std::sort(values.begin() , values.end());\n int DivValue;\n for(int i = 0; i < Q; i++){\n std::cin >> DivValue;\n std::cout << solve(values , DivValue) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 4168, "score_of_the_acc": -1.176, "final_rank": 16 }, { "submission_id": "aoj_0270_7617455", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <vector>\n#include <iostream>\n#include <array>\nconstexpr int MaxValue = 300000;\ninline int solve(const std::vector<int>& values , int DivValue){\n int max = 0;\n int ans;\n for(int i = 0; i <= MaxValue + DivValue; i += DivValue){\n auto itr = std::lower_bound(values.begin() , values.end() , i);\n //if(itr == values.end()) break;\n --itr;\n ans = *itr % DivValue;\n if(max < ans) max = ans;\n }\n return max;\n}\nint main(){\n int N , Q;\n std::cin >> N >> Q;\n std::vector<int> values(N);\n for(auto& value : values) std::cin >> value;\n std::sort(values.begin() , values.end());\n int DivValue;\n for(int i = 0; i < Q; i++){\n std::cin >> DivValue;\n std::cout << solve(values , DivValue) << std::endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 4140, "score_of_the_acc": -1.1648, "final_rank": 15 }, { "submission_id": "aoj_0270_7600779", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector> //sort逆\n#include <algorithm>\n//sort(vec.begin(), vec.end());\n//vec.erase(unique(vec.begin(), vec.end()), vec.end());\n#include <math.h>\n#include <stdio.h>\n#include <iomanip> //fixed<<setprecision()\n#include <complex> //複素数\n/*\n 例 実部1.5、虚部2.5の複素数オブジェクトを作る\ncomplex<double> c(1.5, 2.5);\nreal\t実部を取得する\nimag\t虚部を取得する\nabs\t複素数の絶対値を得る\narg\t複素数の偏角を得る\nnorm\t複素数体のノルムを得る\nconj\t共役複素数を得る\nproj\tリーマン球面への射影を得る\tC++11\npolar\t複素数を極形式で指定して作る\ncout<<c; -> (a,b)\n*/\n#include <tuple> //tuple<int,...> get<1>(a)\n\nusing namespace std;\n//a=97\nconst int MOD = 1000000007;\nconst long long max10_18 = 1000000000000000000;\n\n//2*(2*(2+3))\n#define bigint vector<int>\n#define bigintint vector<vector<int>>\n#define loop(x) for(int i=0;i<x;i++)\n#define loop1(x) for(int i1=0;i1<x;i1++)\n#define loop2(x) for(int i2=0;i2<x;i2++)\n#define loop3(x) for(int i3=0;i3<x;i3++)\n\n#define print1(x) for(int print1_a=0;print1_a<x.size();print1_a++) cout<<x[print1_a]<<\" \";\n#define print2(x) for(int print2_a=0;print2_a<x.size();print2_a++){ for(int print2_b=0;print2_b<x[print2_a].size();print2_b++) cout<<x[print2_a][print2_b]<<\" \"; cout<<endl;}\n\n#define ss string\n#define dd double\n#define ll long long\n\n#define v(x) vector<x>\n#define vv(x) vector<vector<x>>\n\n#define get(x,y) get<y>(x) //tuple\nstatic const int MAX=300000;\nint to[MAX+1];\nbool B[MAX+1];\n\nint main(){\n int N; cin>>N;\n int Q; cin>>Q;\n loop(N){\n int c; cin>>c;\n B[c]=true;\n }\n\n int m=0;\n loop(MAX+1){\n to[i]=m;\n if(B[i]) m=i;\n }\n\n loop(Q){\n int q; cin>>q;\n int maxv=0;\n int now=m;\n while(now){\n int p=now%q;\n maxv=max(p,maxv);\n if ( now - p < 0 ) break;\n now=to[now-p];\n }\n cout<<maxv<<endl;\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 4608, "score_of_the_acc": -0.5187, "final_rank": 2 }, { "submission_id": "aoj_0270_7068045", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n#define myMAX 300003\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,回数)\n#define rep1(i, n) for (int i = 1; i < (int)(n); i++)\nint main(){\n\t\n\tlong long int N, Q,t,maxi=0,q,mtmo;\n\tvector<bool>c(myMAX);\n\tvector<long long int>l(myMAX);\n\tcin >> N >> Q;\n\trep1 (i,N+1) {\n\t\tcin >> t;\n\t\tc[t] = true;\n\t}\n\trep1 (i,myMAX) {\n\t\tl[i] = maxi;\n\t\tif (c[i])maxi = i;\n\t}\n\trep(i, Q) {\n\t\tcin >> q;\n\t\tmtmo = 0;\n\t\tt = maxi;\n\t\twhile (t) {\n\t\t\tmtmo = max(mtmo, t % q);\n\t\t\tt -= t % q;\n\t\t\tt = l[t];\n\t\t}\n\t\tcout << mtmo << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 5036, "score_of_the_acc": -0.8982, "final_rank": 11 }, { "submission_id": "aoj_0270_7068026", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n#define myMAX 300003\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,回数)\nint main(){\n\t\n\tlong long int N, Q,t,maxi=0,q,mtmo;\n\tvector<bool>c(myMAX);\n\tvector<long long int>l(myMAX);\n\tcin >> N >> Q;\n\tfor (int i = 1; i < N + 1; i++) {\n\t\tcin >> t;\n\t\tc[t] = true;\n\t}\n\tfor (int i = 1; i < myMAX; i++) {\n\t\tl[i] = maxi;\n\t\tif (c[i])maxi = i;\n\t}\n\trep(i, Q) {\n\t\tcin >> q;\n\t\tmtmo = 0;\n\t\tt = maxi;\n\t\twhile (t) {\n\t\t\tmtmo = max(mtmo, t % q);\n\t\t\tt -= t % q;\n\t\t\tt = l[t];\n\t\t}\n\t\tcout << mtmo << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 5020, "score_of_the_acc": -0.9335, "final_rank": 12 }, { "submission_id": "aoj_0270_7057705", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,回数)\nint main(){\n\tlong long int N, Q,t,q,kdk,minc=1145141919,maxc=0;\n\tcin >> N >> Q;\n\tvector<int>c(300003);\n\tvector<long long int>l(300003);\n\trep(i, N) {\n\t\tcin >> t;\n\t\tc[t] = 1;\n\t\tminc=min(minc, t);\n\t}\n\tt = 0;\n\tfor (int i = 1; i < 300001; i++) {\n\t\tl[i] = t;\n\t\tif (c[i]) {\n\t\t\tt = i;\n\t\t\tmaxc = max(t,maxc);\n\t\t}\n\t}\n\n\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> q;\n\t\tt = maxc;\n\t\tint ta=maxc;\n\t\tkdk = 0;\n\t\tfor (;;) {\n\n\n\t\t\tif (kdk < t % q)\n\t\t\t\tkdk = t % q;\n\t\t\tt -= t % q;\n\t\t\tt = l[t];\n\t\t\tif (t==0)\n\t\t\t\tbreak;\n\n\t\t}\n\t\tcout << kdk << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 6228, "score_of_the_acc": -1.4583, "final_rank": 18 }, { "submission_id": "aoj_0270_7005118", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,888)\n#define MAX 300000\nlong long int N, Q,c,q,s=0,m,p,maxa;\nbool a[MAX+1];\nint b[MAX + 1];\nint main() {\n\n\tcin >> N >> Q;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> c;\n\t\ta[c] = true;\n\t}\n\tfor (int i = 1; i < MAX + 1; i++) {\n\t\tb[i] = s;\n\t\tif (a[i])s = i;\n\t}\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> q;\n\t\tmaxa = 0;\n\t\tint cur = s;\n\t\twhile (cur) {\n\t\t\t p = cur%q;\n\t\t\tmaxa=max(maxa, p);\n\t\t\tif (cur - p < 0)break;\n\t\t\tcur = b[cur - p];\n\t\t}\n\t\tcout << maxa << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 4444, "score_of_the_acc": -0.7031, "final_rank": 7 }, { "submission_id": "aoj_0270_7003559", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,888)\n#define MAX 300000\nbool c[MAX + 1];\nlong long int l[MAX + 1];\nlong long int N,Q,m,s=0,q,p,maxs;\nint main() {\n\tcin >> N >> Q;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> m;\n\t\tc[m] = true;\n\t}\n\ts = 0;\n\tfor (int i = 1; i <= MAX ; i++) {\n\t\tl[i] = s;\n\t\tif (c[i])s = i;\n\t}\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> q;\n\t\tmaxs = 0;\n\t\tint cur = s;\n\t\twhile (cur) {\n\t\t\tp = cur % q;\n\t\t\tmaxs = max(maxs, p);\n\t\t\tif (cur - p < 0)break;\n\t\t\tcur = l[cur - p];\n\t\t}\n\t\tcout << maxs << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 5648, "score_of_the_acc": -1.1847, "final_rank": 17 }, { "submission_id": "aoj_0270_7003304", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)//rep(i,888)\nstatic const int MYMAX=300000;\nbool c[MYMAX + 1];\nint l[MYMAX + 1];\nint maxa;\t\tint cur;\nint n, q, Q, p, u;\nint main() {\n\tcin >> n >> Q;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> p;\n\t\tc[p] = true;\n\t}\n\tint m = 0;\n\tfor (int i = 1; i <= MYMAX +1; i++) {\n\t\tl[i] = m;\n\t\tif (c[i])m = i;\n\t}\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> q;\n\t\tmaxa = 0;\n\t\tcur = m;\n\t\twhile (cur) {\n\t\t\tp = cur % q;\n\t\t\t//maxa = std::max({ maxa, p });\n\t\t\tmaxa = max(maxa, p);\n\t\t\tif (cur - p < 0)break;\n\t\t\tcur = l[cur - p];\n\t\t}\n\t\tcout << maxa << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4552, "score_of_the_acc": -0.7046, "final_rank": 8 }, { "submission_id": "aoj_0270_6941912", "code_snippet": "#include <iostream>\nusing namespace std;\nstatic const int MAX = 300000;\n\nbool T[MAX + 1];\nint L[MAX + 1];\n\n\nint main() {\n int N, Q, q, c;\n\n cin >> N >> Q;\n for (int i = 0; i < N; i++) {\n cin >> c;\n T[c] = true;\n }\n\n int m = 0;\n for (int i = 1; i <= MAX; i++) {\n L[i] = m;\n if (T[i]) m = i;\n }\n\n for (int i = 0; i < Q; i++) {\n cin >> q;\n int maxv = 0;\n int cur = m;\n while (cur) {\n int p = cur % q;\n maxv = max(maxv, p);\n if (cur < p) break;\n cur = L[cur - p];\n }\n cout << maxv << endl;\n }\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4600, "score_of_the_acc": -0.7238, "final_rank": 9 }, { "submission_id": "aoj_0270_6941857", "code_snippet": "#include <iostream>\nusing namespace std;\nstatic const int MAX = 300000;\n\nbool T[MAX + 1];\nint L[MAX + 1];\n\n\nint main() {\n int N, Q, q, c;\n\n cin >> N >> Q;\n for (int i = 0; i < N; i++) {\n cin >> c;\n T[c] = true;\n }\n\n int m = 0;\n for (int i = 1; i <= MAX; i++) {\n L[i] = m;\n if (T[i]) m = i;\n }\n\n for (int i = 0; i < Q; i++) {\n cin >> q;\n int maxv = 0;\n int cur = m;\n while (cur) {\n int p = cur % q;\n maxv = max(maxv, p);\n if (cur < p) break;\n cur = L[cur - p];\n }\n cout << maxv << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4452, "score_of_the_acc": -0.6646, "final_rank": 4 }, { "submission_id": "aoj_0270_6941847", "code_snippet": "#include <iostream>\nusing namespace std;\nstatic const int MAX = 300000;\n\nbool T[MAX + 1];\nint L[MAX + 1];\n\n\nint main() {\n int N, Q, q, c;\n\n cin >> N >> Q;\n for (int i = 0; i < N; i++) {\n cin >> c;\n T[c] = true;\n }\n\n int m = 0;\n for (int i = 1; i <= MAX; i++) {\n L[i] = m;\n if (T[i]) m = i;\n }\n\n for (int i = 0; i < Q; i++) {\n cin >> q;\n int maxv = 0;\n int cur = m;\n while (cur) {\n int p = cur % q;\n maxv = max(maxv, p);\n if (cur - p < 0) break;\n cur = L[cur - p];\n }\n cout << maxv << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4540, "score_of_the_acc": -0.6581, "final_rank": 3 }, { "submission_id": "aoj_0270_6941842", "code_snippet": "#include <iostream>\nusing namespace std;\nstatic const int MAX = 300000;\n\nbool T[MAX + 1];\nint L[MAX + 1];\n\n\nint main() {\n int N, Q, q, x;\n\n cin >> N >> Q;\n for (int i = 0; i < N; i++) {\n cin >> x;\n T[x] = true;\n }\n\n int m = 0;\n for (int i = 1; i <= MAX; i++) {\n L[i] = m;\n if (T[i]) m = i;\n }\n\n for (int i = 0; i < Q; i++) {\n cin >> q;\n int maxv = 0;\n int cur = m;\n while (cur) {\n int p = cur % q;\n maxv = max(maxv, p);\n if (cur - p < 0) break;\n cur = L[cur - p];\n }\n cout << maxv << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4456, "score_of_the_acc": -0.6662, "final_rank": 5 }, { "submission_id": "aoj_0270_6772711", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nstatic const int MAX = 300000;\n\nbool T[MAX+1];\nint L[MAX+1];\n \nint main() {\n int N, Q, q, x; cin >> N >> Q;\n for(int i=0; i<N; i++) { // Tに格納\n cin >> x;\n T[x] = true;\n }\n\n int m=0; // mはカードの最大値\n for(int i=1; i<MAX+1; i++) { // Lに格納\n L[i] = m;\n if(T[i]) m = i;\n }\n\n for(int i=0; i<Q; i++) {\n cin >> q;\n int maxv=0;\n int cur = m;\n while(cur) {\n int p = cur%q;\n maxv = max(maxv, p);\n cur -= p;\n if(cur < 0) break;\n cur = L[cur];\n }\n cout << maxv << endl;\n }\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 4540, "score_of_the_acc": -0.6998, "final_rank": 6 } ]
aoj_0261_cpp
マヤの大予言 真也君はテレビで「マヤの大予言!2012年で世界が終る?」という番組を見ました。結局、世界が終るかどうかはよくわかりませんでしたが、番組で紹介されていたマヤの「長期暦」という暦に興味を持ちました。その番組では以下のような説明をしていました。 マヤ長期暦は、右の表のような単位からなる、全部で13バクトゥン(187万2000日)で構成される非常に長い暦である。ある計算法では、この暦は紀元前3114年8月11日に始まり2012年12月21日に終わると考えられていて、このため今年の12月21日で世界が終るという説が唱えられている。しかし、13バクトゥンで1サイクルとなり、今の暦が終わったら新しいサイクルに入るだけという考えもある。 1キン=1日 1ウィナル=20キン 1トゥン=18ウィナル 1カトゥン=20トゥン 1バクトゥン=20カトゥン 「ぼくの二十歳の誕生日はマヤ暦だと何日になるのかな?」真也君はいろいろな日をマヤ長期暦で表してみたくなりました。 では、真也君の代わりに、西暦とマヤ長期暦とを相互変換するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりは#1つの行で示される。各データセットは以下の形式で与えられる。 b.ka.t.w.ki または y.m.d データセットは1つの文字列を含む1行からなる。b.ka.t.w.ki はマヤ長期暦の日付、y.m.d は西暦の日付である。与えられる単位は以下の通りである。 マヤ長期暦 b バクトゥン (0 ≤ b< 13) ka カトゥン (0 ≤ ka < 20) t トゥン (0 ≤ t< 20) w ウィナル (0 ≤ w < 18) ki キン (0 ≤ ki < 20) 西暦 y 年 (2012 ≤ y ≤ 10,000,000) m 月 (1 ≤ m ≤ 12) d 日 (1 ≤ d ≤ 31) 西暦の日の最大値は、大の月、小の月、うるう年かどうかで変わる(うるう年は 4 の倍数の年のうち、100 で割り切れない年か、400 で割り切れる年である)。マヤ長期暦の日付の範囲は 0.0.0.0.0 から 12.19.19.17.19 までとする。ただし、マヤ長期暦の 0.0.0.0.0 は西暦の 2012.12.21 に対応する。また、西暦の日付の範囲は 2012.12.21から 10000000.12.31 までとする。 データセットの数は 500 を超えない。 出力 入力が西暦のときはマヤ長期暦を、マヤ長期暦のときは西暦を、それぞれ入力と同じ形式で出力する。 入力された西暦を換算した結果、マヤ長期暦の次のサイクルに入った場合でも b.ka.t.w.ki の形式で出力してよい。 入力例 2012.12.31 2.12.16.14.14 7138.5.13 10.5.2.1.5 10000000.12.31 # 出力例 0.0.0.0.10 3054.8.15 0.0.0.0.10 6056.2.29 8.19.3.13.2
[ { "submission_id": "aoj_0261_9597837", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define Rrep(i,n) for(int i=n-1;i>=0;i--)\n#define Rrep1(i,n) for(int i=n;i>0;i--)\n#define all(a) a.begin(),a.end()\nusing ll = long long;\nusing ull = unsigned long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\n#define INF ((ll)4e18)\n#define IINF ((int)1e9)\nconst double PI = 3.141592653589793;//2384626433832795028841971;\ntemplate<typename T>inline bool chmax(T& a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T>inline bool chmin(T& a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n#define yesno(ans) cout<<((ans)?\"Yes\\n\":\"No\\n\")\nbool eq(double a, double b) { return abs(a - b) < 0.0000001; }\n//LRUD\nconst int di[4] = { 0,-1,0,1 };\nconst int dj[4] = { -1,0,1,0 };\n//const int di[8] = { 0,0,1,1,1,-1,-1,-1 };\n//const int dj[8] = { 1,-1,0,-1,1,0,-1,1 };\n\n/*ACL\n#include <atcoder/all>\nusing namespace atcoder;\n//using mint=modint;\nusing mint = modint998244353;\n//using mint=modint1000000007;\nusing vm=vector<mint>;\nusing vvm=vector<vm>;\nusing vvvm=vector<vvm>;\n//*/\n\nconst ll D_2012_=735222+2;\nint D[]={31,28,31,30,31,30,31,31,30,31,30,31};\nint Dleap[]={31,29,31,30,31,30,31,31,30,31,30,31};\n\nll gd(string &s){\n string tmp=\"\";\n while(s.size()&&s.back()!='.')tmp+=s.back(),s.pop_back();\n if(s.size()>0)s.pop_back();\n return stoll(tmp);\n}\nll leap_num(ll a,ll b){//a年からb年の間のうるう年 [a,b)\n b--,a--;\n return (b/4-b/100+b/400)-(a/4-a/100+a/400);\n}\n\nbool isleap(ll y){\n return ((y%4==0&&(y%100!=0)||(y%400==0)));\n}\nll all_day(ll y,ll m,ll d){\n return 1;\n}\nvoid toSeireki(ll b,ll ka,ll t,ll w,ll ki){\n ka+=b*20,b=0;\n t+=ka*20;ka=0;\n w+=t*18,t=0;\n ki+=w*20;\n ll y=0,m=0,d=ki+D_2012_;\n while(d>365+isleap(y)){\n if(isleap(y))d-=366;\n else d-=365;\n y++;\n }\n m++;\n while(1){\n ll sub=0;\n if(isleap(y))sub=Dleap[m-1];\n else sub=D[m-1];\n if(d-sub<=0)break;\n d-=sub;\n m++;\n }\n printf(\"%lld.%lld.%lld\\n\",y,m,d);\n}\nvoid toMaya(ll y,ll m,ll d){\n m--;\n for(;m>0;m--){\n if(isleap(y))d+=Dleap[m-1];\n else d+=D[m-1];\n }\n y--;\n for(y;y>=0;y--){\n if(isleap(y))d+=366;\n else d+=365;\n }\n d-=D_2012_;\n ll b,ka,t,w,ki;\n ki=d;\n w=ki/20,ki%=20;\n t=w/18,w%=18;\n ka=t/20,t%=20;\n b=ka/20,ka%=20;\n b%=13;\n printf(\"%lld.%lld.%lld.%lld.%lld\\n\",b,ka,t,w,ki);\n}\nint solve(){\n string S;\n while(cin>>S,S!=\"#\"){\n string tmp=\"\";\n int a,b,c,d,e;\n reverse(all(S));\n a=gd(S);\n b=gd(S);\n c=gd(S);\n if(S.size()==0){ \n toMaya(a,b,c); \n continue;\n }\n d=gd(S);\n e=gd(S);\n //printf(\"%d %d %d %d %d\\n\",a,b,c,d,e);\n toSeireki(a,b,c,d,e);\n }\n return 0;\n}\n\nint main()\n{\n //std::cin.tie(0)->sync_with_stdio(0);\n int T = 1;\n //cin>>T;\n /*\n ll y=0,m=1,d=1;\n ll ans=0;\n while(y<2012||m<12||d<20){\n d++,ans++;\n if(isleap(y)){\n if(d>Dleap[m-1]){\n d=1;\n m++;\n if(m>12){\n m=1,y++;\n }\n }\n }else{\n if(d>D[m-1]){\n d=1;\n m++;\n if(m>12){\n m=1,y++;\n }\n }\n }\n //printf(\"%lld.%lld.%lld\\n\",y,m,d);\n }\n cout<<ans<<endl;\n //*/\n while (T--)\n {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 3576, "score_of_the_acc": -1.7676, "final_rank": 15 }, { "submission_id": "aoj_0261_9597425", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<sstream>\nusing namespace std;\ntypedef long long ll;\nstatic const int D[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nstatic const int DT[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365};\nstatic const int MT[] = {144000, 7200, 360, 20, 1};\nbool isLeap(int y){ return ( y%4 == 0 && ( y%100 || y%400 == 0 ));}\n\nll getDay(int y, int m, int d){\n ll sum = 0;\n for ( int i = 1; i <= y; i++ ){\n sum += 365 + (isLeap(i-1)?1:0);\n }\n sum += DT[m-1];\n if ( isLeap(y) && m >= 3 ) sum++;\n sum += d - 1;\n return sum;\n}\n\nvoid toMaya(vector<int> v){\n ll d = getDay(v[0], v[1], v[2]) - getDay(2012, 12, 21);\n d %= MT[0]*13;\n for ( int i = 0; i < 5; i++ ){\n if (i) cout << \".\";\n cout << d/MT[i]; d %= MT[i];\n }\n cout << endl;\n}\n\nvoid toGregorian(vector<int> v){\n ll sum = getDay(2012,12,21);\n for ( int i = 0; i < 5; i++ ) sum += v[i]*MT[i];\n ll y = 0, m = 1, d = sum;\n \n while(1){\n int dd = (isLeap(y)?366:365);\n if ( d >= dd ) d -= dd;\n else break;\n y++;\n }\n\n for ( int i = 0; d >= D[i]; i++ ){\n m = i+2;\n d -= D[i];\n if ( isLeap(y) && i == 1 ) d--;\n }\n d++;\n if ( m == 3 && d == 0 ) { m = 2; d =29; }\n cout << y << \".\" << m << \".\" << d << endl;\n}\n\nmain(){\n string line;\n char ch;\n int x;\n int tcase = 0;\n while(1){\n //cin >> line;\n getline(cin, line);\n if ( line == \"#\" ) break;\n tcase++;\n vector<int> d;\n stringstream sin(line);\n for ( ; sin >> x ; sin >> ch ) d.push_back(x);\n if ( d.size() == 3 ) toMaya(d);\n else if ( d.size() == 5 ) toGregorian(d);\n }\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 3188, "score_of_the_acc": -0.7439, "final_rank": 3 }, { "submission_id": "aoj_0261_8859674", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\nll check(ll y) { \n return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); \n}\n\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n ll isLeapYear = check(res.y + 1);\n if (res.d <= 31)\n return res;\n while (res.d / (365 + isLeapYear))\n res.y++, res.d -= (365 + isLeapYear), isLeapYear = check(res.y + 1);\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (isLeapYear && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (isLeapYear && res.m == 2))) {\n res.d -= (M[res.m - 1] + (isLeapYear && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (isLeapYear && res.m == 2);\n return res;\n}\n\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\n\nint main() {\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 3200, "score_of_the_acc": -0.9827, "final_rank": 12 }, { "submission_id": "aoj_0261_8821328", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nbool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n int a[5];\n int i = 0, num = 0, idx = 0;\n while (str[i]) {\n if (str[i] == '.')\n a[idx] = num, num = 0, idx++;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a[idx] = num;\n if (idx == 4) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 3168, "score_of_the_acc": -0.9093, "final_rank": 9 }, { "submission_id": "aoj_0261_8821321", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n\ntypedef long long ll;\n\nstruct S {\n ll y, m, d;\n};\n\nstruct Ma {\n ll b, ka, t, w, ki;\n};\n\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\nbool isLeapYear(ll y) { return y % 4 == 0 && (y % 100 != 0 || y % 400 == 0); }\n\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + isLeapYear(res.y + 1)))\n res.y++, res.d -= (365 + isLeapYear(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (isLeapYear(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (isLeapYear(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (isLeapYear(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (isLeapYear(res.y) && res.m == 2);\n return res;\n}\n\nMa S2M(ll y, ll m, ll d) {\n bool isLeap = isLeapYear(y);\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && isLeap));\n y--;\n while (y > 0)\n d += (365 + isLeapYear(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\n\nint main() {\n std::string str;\n while (std::cin >> str) {\n if (str == \"#\")\n break;\n std::vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n std::cout << ans.y << \".\" << ans.m << \".\" << ans.d << '\\n';\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n std::cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3140, "score_of_the_acc": -0.669, "final_rank": 1 }, { "submission_id": "aoj_0261_8214640", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\ninline bool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\n\ninline S M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d > 31) {\n while (res.d > (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n res.y++, res.m = 1, res.d -= 31;\n while (res.d > (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n }\n return res;\n}\n\ninline Ma S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << \"\\n\";\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << \"\\n\";\n }\n }\n return 0;\n}", "accuracy": 0.16666666666666666, "time_ms": 10, "memory_kb": 3208, "score_of_the_acc": -0.156, "final_rank": 16 }, { "submission_id": "aoj_0261_8214632", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nbool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nbool check2(S a) { return check(a.y) && a.m == 2; }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1];\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + check2(res))) {\n res.d -= (M[res.m - 1] + check2(res));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + check2(res);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1200, "memory_kb": 3148, "score_of_the_acc": -0.8564, "final_rank": 8 }, { "submission_id": "aoj_0261_8214631", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nbool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 3196, "score_of_the_acc": -0.9735, "final_rank": 11 }, { "submission_id": "aoj_0261_8115070", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nconst int MONTHDAYS[]={31,28,31,30,31,30,31,31,30,31,30,31};\nbool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = MONTHDAYS[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (MONTHDAYS[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (MONTHDAYS[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = MONTHDAYS[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (MONTHDAYS[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << '\\n';\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 3184, "score_of_the_acc": -0.7558, "final_rank": 4 }, { "submission_id": "aoj_0261_8115069", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nconst int M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\ninline bool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\ninline S M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res{2012, 12, 21 + ki};\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\ninline Ma S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n string str;\n while (cin >> str) {\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\" << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 860, "memory_kb": 3196, "score_of_the_acc": -0.727, "final_rank": 2 }, { "submission_id": "aoj_0261_8115066", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nbool check(ll y) { \n return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); \n}\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d % 20, d /= 20;\n res.w = d % 18, d /= 18;\n res.t = d % 20, d /= 20;\n res.ka = d % 20, d /= 20;\n res.b = d % 20;\n return res;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << \"\\n\";\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\" << ans.ki << \"\\n\";\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3196, "score_of_the_acc": -0.7975, "final_rank": 5 }, { "submission_id": "aoj_0261_8115064", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nconst int M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\ninline bool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\ninline S M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\ninline Ma S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d % 20, d /= 20;\n res.w = d % 18, d /= 18;\n res.t = d % 20, d /= 20;\n res.ka = d % 20, d /= 20;\n res.b = d % 20, d /= 20;\n return res;\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << '\\n';\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1430, "memory_kb": 3220, "score_of_the_acc": -1.1835, "final_rank": 14 }, { "submission_id": "aoj_0261_8115062", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\nbool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d % 20;\n d /= 20;\n res.w = d % 18;\n d /= 18;\n res.t = d % 20;\n d /= 20;\n res.ka = d % 20;\n d /= 20;\n res.b = d;\n return res;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1200, "memory_kb": 3196, "score_of_the_acc": -0.9665, "final_rank": 10 }, { "submission_id": "aoj_0261_8115060", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nstruct S {\n ll y, m, d;\n};\n\nstruct Ma {\n ll b, ka, t, w, ki;\n};\n\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\nbool check(ll y) {\n return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0));\n}\n\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n\n if (res.d <= 31) {\n return res;\n }\n while (res.d / (365 + check(res.y + 1))) {\n res.y++;\n res.d -= (365 + check(res.y));\n }\n if (res.d == 0) {\n res.m--;\n res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n }\n if (res.d <= 31) {\n return res;\n }\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0) {\n res.m--;\n res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n }\n return res;\n}\n\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y) {\n d += 10;\n } else {\n d = (d - 21);\n }\n for (int i = 0; i < m - 1 && y; i++) {\n d += (M[i] + (i == 1 && check(y + 2012)));\n }\n y--;\n while (y > 0) {\n d += (365 + check(y + 2012)), y--;\n }\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\") {\n break;\n }\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.') {\n a.push_back(num), num = 0;\n } else {\n num = num * 10 + str[i] - '0';\n }\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << \"\\n\";\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\" << ans.ki << \"\\n\";\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3212, "score_of_the_acc": -0.8342, "final_rank": 7 }, { "submission_id": "aoj_0261_8115058", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nconst int M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\ninline bool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\ninline S M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res = {2012, 12, 21 + ki};\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\ninline Ma S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d % 20;\n d /= 20;\n res.w = d % 18;\n d /= 18;\n res.t = d % 20;\n d /= 20;\n res.ka = d % 20;\n d /= 20;\n res.b = d;\n return res;\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << '\\n';\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 3228, "score_of_the_acc": -0.8145, "final_rank": 6 }, { "submission_id": "aoj_0261_8112454", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstruct S {\n ll y, m, d;\n};\nstruct Ma {\n ll b, ka, t, w, ki;\n};\nint M[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\ninline bool check(ll y) { return (y % 4 == 0 && (y % 100 != 0 || y % 400 == 0)); }\nS M2S(ll b, ll ka, ll t, ll w, ll ki) {\n ka += b * 20;\n t += ka * 20;\n w += t * 18;\n ki += w * 20;\n S res;\n res.y = 2012, res.m = 12, res.d = 21 + ki;\n if (res.d <= 31)\n return res;\n while (res.d / (365 + check(res.y + 1)))\n res.y++, res.d -= (365 + check(res.y));\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n if (res.d <= 31)\n return res;\n res.y++, res.m = 1, res.d -= 31;\n while (res.d / (M[res.m - 1] + (check(res.y) && res.m == 2))) {\n res.d -= (M[res.m - 1] + (check(res.y) && res.m == 2));\n res.m++;\n }\n if (res.d == 0)\n res.m--, res.d = M[res.m - 1] + (check(res.y) && res.m == 2);\n return res;\n}\nMa S2M(ll y, ll m, ll d) {\n y -= 2012;\n if (y)\n d += 10;\n else\n d = (d - 21);\n for (int i = 0; i < m - 1 && y; i++)\n d += (M[i] + (i == 1 && check(y + 2012)));\n y--;\n while (y > 0)\n d += (365 + check(y + 2012)), y--;\n Ma res;\n d %= 13 * 20 * 20 * 18 * 20;\n res.ki = d;\n res.w = res.ki / 20;\n res.ki %= 20;\n res.t = res.w / 18;\n res.w %= 18;\n res.ka = res.t / 20;\n res.t %= 20;\n res.b = res.ka / 20;\n res.ka %= 20;\n return res;\n}\nint main() {\n while (1) {\n string str;\n cin >> str;\n if (str == \"#\")\n break;\n vector<int> a;\n int i = 0, num = 0;\n while (str[i]) {\n if (str[i] == '.')\n a.push_back(num), num = 0;\n else\n num = num * 10 + str[i] - '0';\n i++;\n }\n a.push_back(num);\n if (a.size() == 5) {\n S ans = M2S(a[0], a[1], a[2], a[3], a[4]);\n cout << ans.y << \".\" << ans.m << \".\" << ans.d << endl;\n } else {\n Ma ans = S2M(a[0], a[1], a[2]);\n cout << ans.b << \".\" << ans.ka << \".\" << ans.t << \".\" << ans.w << \".\"\n << ans.ki << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 3208, "score_of_the_acc": -1.001, "final_rank": 13 } ]
aoj_0274_cpp
図画工作 イヅア大学附属小学校は日本有数の競技プログラマー養成校として有名です。この学校の教員は幅広い アルゴリズムの知識を持ち、日々それを活用しています。教員であるあなたは、今年は図画工作の授業 を担当することになりました。この授業では、児童全員がそれぞれ1年間で一つの課題を完成させることになっています。授業の概要は以下のとおりです。 1年間で授業は D 回(同じ日に2 回以上授業はない)あり、その全てが課題制作に充てられる。 制作する課題は M 種類用意されている。 それぞれの児童に、M 種類の中から課題を1つずつ割り当てる。 児童は N 人であり、N 人それぞれに異なる課題が割り当てられる。 児童は、K 種類ある部品のうちいくつかの種類の部品を使用して課題を完成させます。課題の制作の概要は以下のとおりです。 課題ごとに、使用すべき部品の種類と数はあらかじめ決められている。 課題が完成するまでに使用する部品の種類と数は、その課題で使用すべき部品の種類と数に、過不足なく一致していなければならない。 異なる課題でも、使われる部品の種類と数がすべて同じ場合もある。 どの課題も、同じ種類の部品は2個までしか使用できない。 部品を使用する順序は課題の完成に影響を与えない。 いくつかの部品が入っている袋が事前に P 個用意されている。ただし、異なる袋でも、入っている部品の種類と数がすべて同じ場合もある。 教員は、児童1人につき袋を1つだけ渡すことができる(袋を渡さない児童がいてもよい)。 2人以上の児童に同じ袋を渡すことはできない(反対に、誰にも渡されない袋があってもよい)。 袋を渡された児童は、袋の中に入っている部品をすべて、自分が制作する課題に使わなければならない。 袋に入っている部品以外で課題に使用する部品は、別途購入する必要があります。部品の購入に関する条件は以下のとおりです。 部品は授業の日だけ購入でき、その日にしか使えない。 それぞれの課題について、1回の授業でL個までの部品を購入することができる。 部品の種類によって価格が設定されており、購入する日によって価格が変動する。ただし、どの種類も品切れになることはない。 あなたは、このような条件下で、授業にかかる経費をなるべく抑えたいと考えています。そこで、児童全員の部品購入費の合計の最小値を計算するプログラムを作成することにしました。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ3つの行で示される。各データセットは以下の形式で与えられる。 D K L c 1,1 c 1,2 ... c 1,K c 2,1 c 2,2 ... c 2,K : c D,1 c D,2 ... c D,K M N P r 1,1 r 1,2 ... r 1,K r 2,1 r 2,2 ... r 2,K : r M,1 r M,2 ... r M,K t 1,1 t 1,2 ... t 1,K t 2,1 t 2,2 ... t 2,K : t P,1 t P,2 ... t P,K 各行で与えられる数値は1つの空白で区切られている。 D(1 ≤ D ≤ 8)は授業の回数、K(1 ≤ K ≤ 8)は部品の種類の数、L(1 ≤ L ≤ 8)は1日に購入することができる部品の数を示す。c d,k (1 ≤ c d,k ≤ 100)は d 日目の部品k の価格を示す。 M(1 ≤ M ≤ 200)は課題の種類の数、N(1 ≤ N ≤ M)は生徒の人数、P(1 ≤ P ≤ 200)は袋の数を示す。 r m,k (0 ≤ r m,k ≤ 2)は課題 m に必要な部品 k の個数、t p,k (0 ≤ t p,k ≤ 2)は袋 p に入っている部品 k の個数を示す。 部品を1つも必要としない課題や、空の袋は与えられないものとする。 データセットの数は20 を超えない。 出力 データセットごとに、生徒全員の部品購入費の合計の最小値を1行に出力する。N種類の作品を完成させることができない場合は -1 を出力する。 入力例 2 2 1 5 3 2 2 3 3 1 2 0 1 2 2 2 1 1 2 2 1 5 3 2 2 3 2 1 2 0 1 2 2 2 1 1 2 2 2 5 3 2 2 3 2 1 2 0 1 2 2 2 1 1 4 3 1 2 2 1 3 2 2 2 3 3 1 2 2 5 4 3 1 1 0 1 0 1 1 0 2 1 1 2 2 2 2 1 0 1 2 0 2 1 1 1 0 0 0 出力例 -1 9 6 7
[ { "submission_id": "aoj_0274_9267197", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\n\nstruct MCF {\nprivate:\n const long long inf = 1e18;\n vector<long long> dist; //最短距離(費用)\n vector<int> pv, pe; //直前の頂点、辺 \n\npublic:\n struct edge {\n int to, rev; long long cap, cost;\n edge(int t = 0, int r = 0, long long ca = 0, long long co = 0)\n : to(t), rev(r), cap(ca), cost(co) {}\n };\n\n struct pii {\n long long d; int v; //最短距離(費用)、頂点番号\n pii(long long d_ = 0, int v_ = 0) : d(d_), v(v_) {}\n\n bool operator<(const pii& other) const {\n if (d != other.d) return d < other.d;\n return v < other.v;\n }\n\n bool operator>(const pii& other) const {\n if (d != other.d) return d > other.d;\n return v > other.v;\n }\n };\n\n int n;\n vector<vector<edge>> to;\n vector<long long> pot; //ポテンシャル\n\n MCF(int n_ = 1) : n(n_), to(n_), pot(n_), dist(n_), pv(n_), pe(n_) {}\n\n void addedge(int u, int v, long long cap, long long cost) {\n int su = (int)to[u].size();\n int sv = (int)to[v].size();\n to[u].push_back({ v, sv, cap, cost });\n to[v].push_back({ u, su, 0, -cost });\n }\n\n //s->tへ流量fの最小費用流、流せないときは-1\n long long mincostflow(int s, int t, long long f) {\n long long res = 0;\n pot.assign(n, 0);\n while (f) {\n priority_queue<pii, vector<pii>, greater<pii>> pq;\n dist.assign(n, inf);\n dist[s] = 0;\n pq.push({ 0, s });\n while (!pq.empty()) {\n pii elem = pq.top();\n pq.pop();\n if (dist[elem.v] < elem.d) continue;\n int sv = (int)to[elem.v].size();\n for (int i = 0; i < sv; i++) {\n edge& nv = to[elem.v][i];\n if (nv.cap == 0 || dist[nv.to] + pot[nv.to] <= dist[elem.v] + pot[elem.v] + nv.cost) continue;\n dist[nv.to] = dist[elem.v] + pot[elem.v] - pot[nv.to] + nv.cost;\n pv[nv.to] = elem.v;\n pe[nv.to] = i;\n pq.push({ dist[nv.to], nv.to });\n }\n }\n\n if (dist[t] == inf) return -1; //流せる最小費用流が存在しない\n\n for (int v = 0; v < n; v++) pot[v] += dist[v];\n\n long long nf = f;\n for (int v = t; v != s; v = pv[v]) nf = min(nf, to[pv[v]][pe[v]].cap);\n f -= nf;\n res += nf * (pot[t] - pot[s]); //pot[s] = 0で不要だがポテンシャルを明確化する\n for (int v = t; v != s; v = pv[v]) {\n edge& nv = to[pv[v]][pe[v]];\n nv.cap -= nf;\n to[v][nv.rev].cap += nf;\n }\n }\n return res;\n }\n};\n\nvoid chmin(ll& x, ll y) { x = min(x, y); }\n\nint main()\n{\n vi<ll> ans;\n\n vi<int> pow3(10);\n pow3[0] = 1;\n rep(i, 9) pow3[i + 1] = pow3[i] * 3;\n const ll inf = 1e18;\n\n //d:授業数、k:部品種類数、l:1日に購入できる数、 m:課題数、n:生徒数、 p:袋数\n int d, k, l, m, n, p;\n while (cin >> d >> k >> l, d) {\n vii<int> c(d, vi<int>(k)); //部品の価格\n rep(i, d) rep(j, k) cin >> c[i][j];\n\n cin >> m >> n >> p;\n vii<int> r(m, vi<int>(k));\n vii<int> t(p, vi<int>(k));\n rep(i, m) rep(j, k) cin >> r[i][j]; //課題の部品数\n rep(i, p) rep(j, k) cin >> t[i][j]; //袋の部品数\n t.push_back(vi<int>());\n rep(j, k) t[p].push_back(0); //空の袋を入れる\n\n //dp[x][y][z]: x回目の授業, y:3^k通りで表す部品の状況, z個購入\n viii<ll> dp(d + 1, vii<ll>(pow3[k], vi<ll>(l + 1, inf)));\n dp[0][0][0] = 0;\n rep(x, d) rep(y, pow3[k]){\n if(x) rep(z, l + 1) chmin(dp[x][y][0], dp[x - 1][y][z]);\n rep(z, l) rep(w, k) {\n if ((y / pow3[w]) % 3 == 2) continue;\n chmin(dp[x][y + pow3[w]][z + 1],\n dp[x][y][z] + c[x][w]);\n }\n }\n\n rep(y, pow3[k]) rep(z, l + 1) chmin(dp[d][y][0], dp[d - 1][y][z]);\n\n MCF mcf(m + p + 3);\n int S = m + p + 1, T = m + p + 2;\n\n rep(i, m) mcf.addedge(S, i, 1, 0);\n rep(i, p) mcf.addedge(i + m, T, 1, 0);\n mcf.addedge(m + p, T, n, 0);\n\n rep(i, m) rep(j, p + 1) { //i番目の課題, j番目の袋\n int bit = 0;\n bool ok = true;\n rep(h, k) { //h番目の部品\n if (r[i][h] < t[j][h]) { //袋の部品数のほうが多いとき\n ok = false;\n break;\n }\n bit += (r[i][h] - t[j][h]) * pow3[h];\n }\n if (!ok) continue;\n if (dp[d][bit][0] != inf) mcf.addedge(i, j + m, 1, dp[d][bit][0]);\n }\n\n ll cost = mcf.mincostflow(S, T, n);\n ans.push_back(cost);\n }\n for (ll elem : ans) cout << elem << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 11616, "score_of_the_acc": -0.4914, "final_rank": 10 }, { "submission_id": "aoj_0274_5053394", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/graph/MCF.cpp\"\n//Minimum Cost Flow O(FE log V)\n#line 3 \"/home/kotatsugame/library/graph/MCF.cpp\"\n#include<utility>\n#include<vector>\n#include<queue>\n#include<limits>\ntemplate<typename T>\nstruct MCF{\n\tstruct edge{\n\t\tint to,rev,cap;\n\t\tT cost;\n\t};\n\tvector<vector<edge> >G;\n\tvector<T>h,d;\n\tvector<int>pv,pe;\n\tMCF(int n_=0):G(n_),h(n_,0),d(n_),pv(n_),pe(n_){}\n\tvoid add_edge(int from,int to,int cap,T cost)\n\t{\n\t\tG[from].push_back({to,(int)G[to].size(),cap,cost});\n\t\tG[to].push_back({from,(int)G[from].size()-1,0,-cost});\n\t}\n\tT min_cost_flow(int s,int t,int f)//ans or -1\n\t{\n\t\tT ret=0;\n\t\twhile(f>0)\n\t\t{\n\t\t\tpriority_queue<pair<T,int>,vector<pair<T,int> >,greater<pair<T,int> > >P;\n\t\t\tfill(d.begin(),d.end(),numeric_limits<T>::max());\n\t\t\td[s]=0;\n\t\t\tP.push(make_pair(0,s));\n\t\t\twhile(!P.empty())\n\t\t\t{\n\t\t\t\tpair<T,int>p=P.top();P.pop();\n\t\t\t\tif(d[p.second]<p.first)continue;\n\t\t\t\tfor(int i=0;i<G[p.second].size();i++)\n\t\t\t\t{\n\t\t\t\t\tedge&e=G[p.second][i];\n\t\t\t\t\tif(e.cap>0&&d[e.to]>d[p.second]+e.cost+h[p.second]-h[e.to])\n\t\t\t\t\t{\n\t\t\t\t\t\td[e.to]=d[p.second]+e.cost+h[p.second]-h[e.to];\n\t\t\t\t\t\tpv[e.to]=p.second;\n\t\t\t\t\t\tpe[e.to]=i;\n\t\t\t\t\t\tP.push(make_pair(d[e.to],e.to));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(d[t]==numeric_limits<T>::max())return -1;\n\t\t\tfor(int u=0;u<G.size();u++)h[u]+=d[u];\n\t\t\tint d=f;\n\t\t\tfor(int u=t;u!=s;u=pv[u])d=min(d,G[pv[u]][pe[u]].cap);\n\t\t\tf-=d;\n\t\t\tret+=d*h[t];\n\t\t\tfor(int u=t;u!=s;u=pv[u])\n\t\t\t{\n\t\t\t\tG[pv[u]][pe[u]].cap-=d;\n\t\t\t\tG[u][G[pv[u]][pe[u]].rev].cap+=d;\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n};\n#line 5 \"a.cpp\"\nint D,K,L;\nconst int p3[9]={1,3,9,27,81,243,729,2187,6561};\nint cost[6561],nxtcost[6561];\nint c[8],t[8];\nint M,N,P;\nint R[200][8],T[200][8];\nvoid dfs(int id,int now,int add,int sum)\n{\n\tif(id==0)\n\t{\n\t\tif(cost[now]<(int)1e9)nxtcost[now+add]=min(nxtcost[now+add],cost[now]+sum);\n\t\treturn;\n\t}\n\tfor(int i=0;i<=2-t[id-1];i++)\n\t{\n\t\tdfs(id-1,now*3+i,add,sum);\n\t}\n}\nmain()\n{\n\twhile(cin>>D>>K>>L,D)\n\t{\n\t\tcost[0]=0;\n\t\tfor(int i=1;i<p3[K];i++)cost[i]=1e9;\n\t\tfor(int day=0;day<D;day++)\n\t\t{\n\t\t\tfor(int i=0;i<K;i++)cin>>c[i];\n\t\t\tfor(int i=0;i<p3[K];i++)nxtcost[i]=1e9;\n\t\t\tfor(int i=0;i<p3[K];i++)\n\t\t\t{\n\t\t\t\tint u=i,sum=0,cnt=0;\n\t\t\t\tfor(int j=0;j<K;j++)\n\t\t\t\t{\n\t\t\t\t\tt[j]=u%3;\n\t\t\t\t\tcnt+=t[j];\n\t\t\t\t\tsum+=t[j]*c[j];\n\t\t\t\t\tu/=3;\n\t\t\t\t}\n\t\t\t\tif(cnt>L)continue;\n\t\t\t\tdfs(K,0,i,sum);\n\t\t\t}\n\t\t\tfor(int i=0;i<p3[K];i++)cost[i]=nxtcost[i];\n\t\t}\n\t\tcin>>M>>N>>P;\n\t\tfor(int i=0;i<M;i++)for(int j=0;j<K;j++)cin>>R[i][j];\n\t\tfor(int i=0;i<P;i++)for(int j=0;j<K;j++)cin>>T[i][j];\n\t\tMCF<int>Q(M+P+2);\n\t\tint st=M+P,go=st+1;\n\t\tfor(int i=0;i<M;i++)\n\t\t{\n\t\t\tQ.add_edge(st,i,1,0);\n\t\t\tint now=0;\n\t\t\tfor(int j=K;j--;)now=now*3+R[i][j];\n\t\t\tif(cost[now]<(int)1e9)Q.add_edge(i,go,1,cost[now]);\n\t\t}\n\t\tfor(int i=0;i<P;i++)Q.add_edge(M+i,go,1,0);\n\t\tfor(int i=0;i<M;i++)for(int j=0;j<P;j++)\n\t\t{\n\t\t\tint now=0;\n\t\t\tbool neg=false;\n\t\t\tfor(int k=K;k--;)\n\t\t\t{\n\t\t\t\tint t=R[i][k]-T[j][k];\n\t\t\t\tif(t<0){neg=true;break;}\n\t\t\t\tnow=now*3+t;\n\t\t\t}\n\t\t\tif(neg)continue;\n\t\t\tif(cost[now]<(int)1e9)Q.add_edge(i,M+j,1,cost[now]);\n\t\t}\n\t\tcout<<Q.min_cost_flow(st,go,N)<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 4684, "score_of_the_acc": -0.5495, "final_rank": 12 }, { "submission_id": "aoj_0274_4985532", "code_snippet": "#include <vector>\n#include <cassert>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nint gethash(int K, vector<int> v) {\n\tassert(int(v.size()) == K);\n\tint res = 0;\n\tfor (int i = 0; i < K; ++i) {\n\t\tres = res * 3 + v[i];\n\t}\n\treturn res;\n}\nvector<int> getrevhash(int K, int val) {\n\tvector<int> ans(K);\n\tfor (int i = K - 1; i >= 0; --i) {\n\t\tans[i] = val % 3;\n\t\tval /= 3;\n\t}\n\treturn ans;\n}\nint main() {\n\twhile (true) {\n\t\tint D, K, L, M, N, P;\n\t\tcin >> D >> K >> L;\n\t\tif (D == 0 && K == 0 && L == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tvector<vector<int> > cost(D, vector<int>(K));\n\t\tfor (int i = 0; i < D; ++i) {\n\t\t\tfor (int j = 0; j < K; ++j) {\n\t\t\t\tcin >> cost[i][j];\n\t\t\t}\n\t\t}\n\t\tcin >> M >> N >> P;\n\t\tvector<vector<int> > req(M, vector<int>(K));\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tfor (int j = 0; j < K; ++j) {\n\t\t\t\tcin >> req[i][j];\n\t\t\t}\n\t\t}\n\t\tvector<vector<int> > box(P + N, vector<int>(K));\n\t\tfor (int i = 0; i < P; ++i) {\n\t\t\tfor (int j = 0; j < K; ++j) {\n\t\t\t\tcin >> box[i][j];\n\t\t\t}\n\t\t}\n\t\tP += N;\n\t\tint mul = 1;\n\t\tfor (int i = 0; i < K; ++i) {\n\t\t\tmul *= 3;\n\t\t}\n\t\tvector<int> dp(mul, inf);\n\t\tdp[0] = 0;\n\t\tfor (int i = 0; i < D; ++i) {\n\t\t\tfor (int j = 0; j < L; ++j) {\n\t\t\t\tvector<int> ndp = dp;\n\t\t\t\tfor (int k = mul - 1; k >= 0; --k) {\n\t\t\t\t\tvector<int> v = getrevhash(K, k);\n\t\t\t\t\tfor (int l = 0; l < K; ++l) {\n\t\t\t\t\t\tif (v[l] == 0) continue;\n\t\t\t\t\t\t--v[l];\n\t\t\t\t\t\tndp[k] = min(ndp[k], dp[gethash(K, v)] + cost[i][l]);\n\t\t\t\t\t\t++v[l];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tdp = ndp;\n\t\t\t}\n\t\t}\n\t\tvector<vector<int> > G(M, vector<int>(P, inf));\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tfor (int j = 0; j < P; ++j) {\n\t\t\t\tbool ok = true;\n\t\t\t\tvector<int> need(K);\n\t\t\t\tfor (int k = 0; k < K; ++k) {\n\t\t\t\t\tif (req[i][k] < box[j][k]) {\n\t\t\t\t\t\tok = false;\n\t\t\t\t\t}\n\t\t\t\t\tneed[k] = max(req[i][k] - box[j][k], 0);\n\t\t\t\t}\n\t\t\t\tif (ok) {\n\t\t\t\t\tG[i][j] = dp[gethash(K, need)];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = 0;\n\t\tvector<int> match(M + P, -1);\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tvector<int> dist(M + P, inf), par(M + P, -1);\n\t\t\tfor (int j = 0; j < M; ++j) {\n\t\t\t\tif (match[j] == -1) {\n\t\t\t\t\tdist[j] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t\twhile (true) {\n\t\t\t\tvector<int> ndist = dist;\n\t\t\t\tfor (int j = 0; j < M; ++j) {\n\t\t\t\t\tif (match[j] != -1) {\n\t\t\t\t\t\tint nd = ndist[match[j]] - G[j][match[j] - M];\n\t\t\t\t\t\tif (ndist[j] > nd) {\n\t\t\t\t\t\t\tndist[j] = nd;\n\t\t\t\t\t\t\tpar[j] = match[j];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor (int j = M; j < M + P; ++j) {\n\t\t\t\t\tfor (int k = 0; k < M; ++k) {\n\t\t\t\t\t\tif (match[j] != k) {\n\t\t\t\t\t\t\tint nd = ndist[k] + G[k][j - M];\n\t\t\t\t\t\t\tif (ndist[j] > nd) {\n\t\t\t\t\t\t\t\tndist[j] = nd;\n\t\t\t\t\t\t\t\tpar[j] = k;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (dist == ndist) break;\n\t\t\t\tdist = ndist;\n\t\t\t}\n\t\t\tint opt = inf, mn = -1;\n\t\t\tfor (int j = M; j < M + P; ++j) {\n\t\t\t\tif (match[j] == -1 && dist[j] < opt) {\n\t\t\t\t\topt = dist[j];\n\t\t\t\t\tmn = j;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (mn == -1) {\n\t\t\t\tans = inf;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tans += dist[mn];\n\t\t\twhile (par[mn] != -1) {\n\t\t\t\tif (mn >= M) {\n\t\t\t\t\tmatch[mn] = par[mn];\n\t\t\t\t\tmatch[par[mn]] = mn;\n\t\t\t\t}\n\t\t\t\tmn = par[mn];\n\t\t\t}\n\t\t}\n\t\tcout << (ans == inf ? -1 : ans) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3580, "memory_kb": 3376, "score_of_the_acc": -0.9597, "final_rank": 13 }, { "submission_id": "aoj_0274_4491328", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\ntemplate<typename F, typename C>\nstruct PrimalDual {\n struct edge {\n int to; F cap; C cost; int rev;\n edge() = default;\n edge(int to, F cap, C cost, int rev):to(to), cap(cap), cost(cost), rev(rev) {};\n };\n vector<vector<edge>> G;\n vector<C> potential, min_cost;\n vector<int> prevv, preve;\n\n explicit PrimalDual(int n) : G(n), potential(n), min_cost(n), prevv(n), preve(n) {}\n\n void add_edge(int u, int v, F cap, C cost){\n G[u].emplace_back(v, cap, cost, G[v].size());\n G[v].emplace_back(u, 0, -cost, G[u].size()-1);\n }\n\n struct P{\n C first; int second;\n P(C first,int second):first(first),second(second){}\n bool operator<(const P&a) const{return a.first<first;}\n };\n void dijkstra(int s){\n priority_queue<P> Q;\n fill(min_cost.begin(),min_cost.end(), INF<C>);\n min_cost[s] = 0;\n Q.emplace(0, s);\n while(!Q.empty()){\n P p = Q.top(); Q.pop();\n int v = p.second;\n if(min_cost[v] < p.first) continue;\n for(int i = 0; i < G[v].size(); ++i){\n edge &e=G[v][i];\n if(e.cap==0) continue;\n if(min_cost[v]+e.cost+potential[v]-potential[e.to] < min_cost[e.to]){\n min_cost[e.to] = min_cost[v]+e.cost+potential[v]-potential[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n Q.emplace(min_cost[e.to], e.to);\n }\n }\n }\n }\n\n C flow(int s, int t, F fl, int &ok){\n C res = 0;\n fill(potential.begin(),potential.end(), 0);\n while(fl > 0){\n dijkstra(s);\n if(min_cost[t] == INF<C>){\n ok = 0;\n return res;\n }\n for (int i = 0; i < potential.size(); ++i) {\n if(min_cost[i] < INF<C>) potential[i] += min_cost[i];\n }\n\n F d = fl;\n for(int v = t; v != s; v = prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n fl -= d;\n res += potential[t]*d;\n for(int v = t; v != s; v = prevv[v]){\n G[prevv[v]][preve[v]].cap -= d;\n G[v][G[prevv[v]][preve[v]].rev].cap += d;\n }\n }\n ok = 1;\n return res;\n }\n};\n\nvoid solve(int d, int k, int l){\n vector<vector<int>> v(d, vector<int>(k, 0));\n for (int i = 0; i < d; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> v[i][j];\n }\n }\n auto dp = make_v(d+1, l+1, 1 << (2*k), INF<int>);\n dp[0][0][0] = 0;\n for (int i = 0; i < d; ++i) {\n for (int j = 0; j <= l; ++j) {\n for (int m = 0; m < 1 << (2*k); ++m) {\n chmin(dp[i+1][0][m], dp[i][j][m]);\n if(j == l || dp[i][j][m] == INF<int>) continue;\n for (int n = 0; n < k; ++n) {\n if(((m >> 2*n)&3) == 2) continue;\n chmin(dp[i][j+1][m+(1 << 2*n)], dp[i][j][m]+v[i][n]);\n }\n }\n }\n }\n int m, n, p;\n cin >> m >> n >> p;\n auto R = make_v(m, k, 0);\n auto T = make_v(p+1, k, 0);\n for (int i = 0; i < m; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> R[i][j];\n }\n }\n for (int i = 0; i < p; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> T[i][j];\n }\n }\n p++;\n PrimalDual<int, int> G(m+p+2);\n for (int i = 0; i < m; ++i) {\n G.add_edge(0, i+2, 1, 0);\n }\n for (int i = 0; i < p; ++i) {\n G.add_edge(m+2+i, 1, (i == p-1 ? n : 1), 0);\n }\n for (int i = 0; i < m; ++i) {\n for (int j = 0; j < p; ++j) {\n int S = 0;\n for (int o = 0; o < k; ++o) {\n if(R[i][o] < T[j][o]) {\n S = -1;\n break;\n }\n S |= (1 << 2*o)*(R[i][o]-T[j][o]);\n }\n if(S >= 0 && dp.back()[0][S] < INF<int>){\n G.add_edge(i+2, m+2+j, 1, dp.back()[0][S]);\n }\n }\n }\n int ok = 0;\n auto res = G.flow(0, 1, n, ok);\n if(!ok) puts(\"-1\");\n else cout << res << \"\\n\";\n}\n\nint main() {\n int d, k, l;\n while(cin >> d >> k >> l, d){\n solve(d, k, l);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 26116, "score_of_the_acc": -1.1317, "final_rank": 14 }, { "submission_id": "aoj_0274_4491093", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\ntemplate<typename F, typename C>\nstruct PrimalDual {\n struct edge {\n int to; F cap; C cost; int rev;\n edge() = default;\n edge(int to, F cap, C cost, int rev):to(to), cap(cap), cost(cost), rev(rev) {};\n };\n vector<vector<edge>> G;\n vector<C> potential, min_cost;\n vector<int> prevv, preve;\n\n explicit PrimalDual(int n) : G(n), potential(n), min_cost(n), prevv(n), preve(n) {}\n\n void add_edge(int u, int v, F cap, C cost){\n G[u].emplace_back(v, cap, cost, G[v].size());\n G[v].emplace_back(u, 0, -cost, G[u].size()-1);\n }\n\n struct P{\n C first; int second;\n P(C first,int second):first(first),second(second){}\n bool operator<(const P&a) const{return a.first<first;}\n };\n void dijkstra(int s){\n priority_queue<P> Q;\n fill(min_cost.begin(),min_cost.end(), INF<C>);\n min_cost[s] = 0;\n Q.emplace(0, s);\n while(!Q.empty()){\n P p = Q.top(); Q.pop();\n int v = p.second;\n if(min_cost[v] < p.first) continue;\n for(int i = 0; i < G[v].size(); ++i){\n edge &e=G[v][i];\n if(e.cap==0) continue;\n if(min_cost[v]+e.cost+potential[v]-potential[e.to] < min_cost[e.to]){\n min_cost[e.to] = min_cost[v]+e.cost+potential[v]-potential[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n Q.emplace(min_cost[e.to], e.to);\n }\n }\n }\n }\n\n C flow(int s, int t, F fl, int &ok){\n C res = 0;\n fill(potential.begin(),potential.end(), 0);\n while(fl > 0){\n dijkstra(s);\n if(min_cost[t] == INF<C>){\n ok = 0;\n return res;\n }\n for (int i = 0; i < potential.size(); ++i) {\n if(min_cost[i] < INF<C>) potential[i] += min_cost[i];\n }\n\n F d = fl;\n for(int v = t; v != s; v = prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n fl -= d;\n res += potential[t]*d;\n for(int v = t; v != s; v = prevv[v]){\n G[prevv[v]][preve[v]].cap -= d;\n G[v][G[prevv[v]][preve[v]].rev].cap += d;\n }\n }\n ok = 1;\n return res;\n }\n};\n\nvoid solve(int d, int k, int l){\n vector<vector<int>> v(d, vector<int>(k, 0));\n for (int i = 0; i < d; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> v[i][j];\n }\n }\n auto dp = make_v(d+1, l+1, 1 << (2*k), INF<int>);\n dp[0][0][0] = 0;\n for (int i = 0; i < d; ++i) {\n for (int j = 0; j <= l; ++j) {\n for (int m = 0; m < 1 << (2*k); ++m) {\n chmin(dp[i+1][0][m], dp[i][j][m]);\n if(j == l || dp[i][j][m] == INF<int>) continue;\n for (int n = 0; n < k; ++n) {\n if(((m >> 2*n)&3) == 2) continue;\n chmin(dp[i][j+1][m+(1 << 2*n)], dp[i][j][m]+v[i][j]);\n }\n }\n }\n }\n int m, n, p;\n cin >> m >> n >> p;\n auto R = make_v(m, k, 0);\n auto T = make_v(p+1, k, 0);\n for (int i = 0; i < m; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> R[i][j];\n }\n }\n for (int i = 0; i < p; ++i) {\n for (int j = 0; j < k; ++j) {\n cin >> T[i][j];\n }\n }\n p++;\n PrimalDual<int, int> G(m+p+2);\n for (int i = 0; i < m; ++i) {\n G.add_edge(0, i+2, 1, 0);\n }\n for (int i = 0; i < p; ++i) {\n G.add_edge(m+2+i, 1, 1, 0);\n }\n for (int i = 0; i < m; ++i) {\n for (int j = 0; j < p; ++j) {\n int S = 0;\n for (int o = 0; o < k; ++o) {\n if(R[i][o] < T[j][o]) {\n S = -1;\n break;\n }\n S |= (1 << 2*o)*(R[i][o]-T[j][o]);\n }\n if(S >= 0 && dp.back()[0][S] < INF<int>){\n G.add_edge(i+2, m+2+j, 1, dp.back()[0][S]);\n }\n }\n }\n int ok = 0;\n auto res = G.flow(0, 1, n, ok);\n if(!ok) puts(\"-1\");\n else cout << res << \"\\n\";\n}\n\nint main() {\n int d, k, l;\n while(cin >> d >> k >> l, d){\n solve(d, k, l);\n }\n return 0;\n}", "accuracy": 0.125, "time_ms": 10, "memory_kb": 18284, "score_of_the_acc": -0.6556, "final_rank": 18 }, { "submission_id": "aoj_0274_4205665", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nvoid chmin(int &a, int b){\n a = min(a, b);\n}\n\nstruct edge{\n int to, cap, cost, rev;\n};\n\nvector<vector<edge> > G;\nvector<int> h, dist, prevv, preve;\n\nvoid add_edge(int from, int to, int cap, int cost){\n G[from].push_back((edge){to, cap, cost, int(G[to].size())});\n G[to].push_back((edge){from, 0, -cost, int(G[from].size())-1});\n}\n\n// 最小費用流\nint min_cost_flow(int s, int t, int f){\n h.resize(G.size());\n dist.resize(G.size());\n prevv.resize(G.size());\n preve.resize(G.size());\n int res = 0;\n fill(h.begin(), h.end(), 0);\n while(f > 0){\n priority_queue<P, vector<P>, greater<P> > que;\n fill(dist.begin(), dist.end(), INF);\n dist[s] = 0;\n que.push({0,s});\n while(!que.empty()){\n P p = que.top();\n que.pop();\n int v = p.second;\n if(dist[v] < p.first) continue;\n for(int i=0;i<int(G[v].size());i++){\n auto &e = G[v][i];\n if(e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to]){\n dist[e.to] = dist[v] + e.cost + h[v] - h[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push({dist[e.to], e.to});\n }\n }\n }\n if(dist[t] == INF){\n return -1;\n }\n for(int v=0; v<G.size(); v++) h[v] += dist[v];\n int d = f;\n for(int v=t; v!=s; v=prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d*h[t];\n for(int v=t; v!=s; v=prevv[v]){\n auto &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n}\n\nint dp[9][9][1<<16];\n\nbool solve(){\n int D, K, L, N, M, Q;\n cin >> D >> K >> L;\n if(D == 0) return true;\n vector<vector<int> > c(D, vector<int>(K));\n for(int i=0;i<D;i++){\n for(int j=0;j<K;j++){\n cin >> c[i][j];\n }\n }\n cin >> M >> N >> Q;\n vector<vector<int> > r(M, vector<int>(K)), t(Q+1, vector<int>(K));\n for(int i=0;i<M;i++){\n for(int j=0;j<K;j++){\n cin >> r[i][j];\n }\n }\n for(int i=0;i<Q;i++){\n for(int j=0;j<K;j++){\n cin >> t[i][j];\n }\n }\n for(int i=0;i<K;i++){\n t[Q][i] = 0;\n }\n Q++;\n for(int i=0;i<=D;i++){\n for(int j=0;j<=L;j++){\n fill(dp[i][j], dp[i][j]+(1<<(K*2)), INF);\n }\n }\n dp[0][0][0] = 0;\n for(int i=0;i<D;i++){\n for(int j=0;j<=L;j++){\n for(int X=0;X<(1<<(K*2));X++){\n if(dp[i][j][X] == INF) continue;\n chmin(dp[i+1][0][X], dp[i][j][X]);\n if(j==L) continue;\n int Y = X;\n for(int k=0;k<K;k++,Y>>2){\n if((Y&3)>=2) continue;\n chmin(dp[i][j+1][X+(1<<(k*2))], dp[i][j][X]+c[i][k]);\n }\n }\n }\n }\n G.clear();\n G.resize(M+Q+2);\n int S = M+Q, T = M+Q+1;\n for(int i=0;i<M;i++){\n for(int j=0;j<Q;j++){\n int X = 0;\n bool ok = true;\n for(int k=0;k<K;k++){\n if(r[i][k] < t[j][k]){\n ok = false;\n break;\n }\n X |= (r[i][k]-t[j][k])<<(k*2);\n }\n if(ok && dp[D][0][X] < INF){\n assert(X < 1<<(K*2));\n add_edge(i,M+j,1,dp[D][0][X]);\n }\n }\n }\n for(int i=0;i<M;i++){\n add_edge(S,i,1,0);\n }\n for(int i=0;i<Q;i++){\n add_edge(M+i,T,(i==Q-1?INF:1),0);\n }\n int ans = min_cost_flow(S,T,N);\n \n cout << ans << endl;\n return false;\n}\n\nint main() {\n while(!solve());\n return 0;\n}", "accuracy": 0.125, "time_ms": 40, "memory_kb": 20344, "score_of_the_acc": -0.7542, "final_rank": 19 }, { "submission_id": "aoj_0274_4205640", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 29;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nvoid chmin(int &a, int b){\n a = min(a, b);\n}\n\nstruct edge{\n int to, cap, cost, rev;\n};\n\nvector<vector<edge> > G;\nvector<int> h, dist, prevv, preve;\n\nvoid add_edge(int from, int to, int cap, int cost){\n G[from].push_back((edge){to, cap, cost, int(G[to].size())});\n G[to].push_back((edge){from, 0, -cost, int(G[from].size())-1});\n}\n\n// 最小費用流\nint min_cost_flow(int s, int t, int f){\n h.resize(G.size());\n dist.resize(G.size());\n prevv.resize(G.size());\n preve.resize(G.size());\n int res = 0;\n fill(h.begin(), h.end(), 0);\n while(f > 0){\n priority_queue<P, vector<P>, greater<P> > que;\n fill(dist.begin(), dist.end(), INF);\n dist[s] = 0;\n que.push({0,s});\n while(!que.empty()){\n P p = que.top();\n que.pop();\n int v = p.second;\n if(dist[v] < p.first) continue;\n for(int i=0;i<int(G[v].size());i++){\n auto &e = G[v][i];\n if(e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to]){\n dist[e.to] = dist[v] + e.cost + h[v] - h[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push({dist[e.to], e.to});\n }\n }\n }\n if(dist[t] == INF){\n return -1;\n }\n for(int v=0; v<G.size(); v++) h[v] += dist[v];\n int d = f;\n for(int v=t; v!=s; v=prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d*h[t];\n for(int v=t; v!=s; v=prevv[v]){\n auto &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n}\n\nint dp[9][9][1<<17];\n\nbool solve(){\n int D, K, L, N, M, Q;\n cin >> D >> K >> L;\n if(D == 0) return true;\n vector<vector<int> > c(D, vector<int>(K));\n for(int i=0;i<D;i++){\n for(int j=0;j<K;j++){\n cin >> c[i][j];\n }\n }\n cin >> M >> N >> Q;\n vector<vector<int> > r(M, vector<int>(K)), t(Q+1, vector<int>(K));\n for(int i=0;i<M;i++){\n for(int j=0;j<K;j++){\n cin >> r[i][j];\n }\n }\n for(int i=0;i<Q;i++){\n for(int j=0;j<K;j++){\n cin >> t[i][j];\n }\n }\n for(int i=0;i<K;i++){\n t[Q][i] = 0;\n }\n Q++;\n for(int i=0;i<=D;i++){\n for(int j=0;j<=L;j++){\n fill(dp[i][j], dp[i][j]+(1<<(K*2)), INF);\n }\n }\n dp[0][0][0] = 0;\n for(int i=0;i<D;i++){\n for(int j=0;j<=L;j++){\n for(int X=0;X<(1<<(K*2));X++){\n if(dp[i][j][X] == INF) continue;\n chmin(dp[i+1][0][X], dp[i][j][X]);\n if(j==L) continue;\n int Y = X;\n for(int k=0;k<K;k++,Y>>2){\n if((Y&3)>=2) continue;\n chmin(dp[i][j+1][X+(1<<(k*2))], dp[i][j][X]+c[i][k]);\n }\n }\n }\n }\n G.clear();\n G.resize(M+Q+2);\n int S = M+Q, T = M+Q+1;\n for(int i=0;i<M;i++){\n for(int j=0;j<Q;j++){\n int X = 0;\n bool ok = true;\n for(int k=0;k<K;k++){\n if(r[i][k] < t[j][k]){\n ok = false;\n break;\n }\n X |= (r[i][k]-t[j][k])<<(k*2);\n }\n if(ok && dp[D][0][X] < INF){\n add_edge(i,M+j,1,dp[D][0][X]);\n }\n }\n }\n for(int i=0;i<M;i++){\n add_edge(S,i,1,0);\n }\n for(int i=0;i<Q;i++){\n add_edge(M+i,T,(i==Q-1?INF:1),0);\n }\n int ans = min_cost_flow(S,T,N);\n \n cout << ans << endl;\n return false;\n}\n\nint main() {\n while(!solve());\n return 0;\n}", "accuracy": 0.125, "time_ms": 40, "memory_kb": 23108, "score_of_the_acc": -0.8758, "final_rank": 20 }, { "submission_id": "aoj_0274_3713722", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <iostream>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\nconst int INF = 1 << 29;\nint shift[10];\n\nstruct Edge {\n int to, cap, cost, rev;\n Edge(int t, int c, int r) : to(t), cap(c), rev(r) {}\n Edge(int t, int ca, int co, int r) : to(t), cap(ca), cost(co), rev(r) {}\n};\n\nusing Graph = vector< vector< Edge > >;\nstruct Flow {\n vector< vector<Edge> > G;\n const int MAXC = 1 << 29;\n int n;\n vector<bool> used;\n vector<int> prevv, preve, dist;\n Flow(int n_) : G(n_), n(n_), used(n_, false), prevv(n_), preve(n_), dist(n_, MAXC) {}\n\n void add_edge(int from, int to, int cap, int cost) {\n G[from].push_back(Edge(to, cap, cost, G[to].size()));\n G[to ].push_back(Edge(from, 0, -cost, G[from].size() - 1));\n }\n\n int dfs(int v, int t, int f) {\n if(v == t) return f;\n used[v] = true;\n }\n\n\n // ベルマンフォード法で最小費用流を解く\n // 負辺や負閉路があるときは基本的にこちらのほうが確実\n int mincost_flow(int s, int t, int f) {\n int res = 0;\n int ma = MAXC;\n while(f > 0) {\n fill(dist.begin(), dist.end(), ma);\n dist[s] = 0;\n bool update = true;\n while(update) {\n update = false;\n for(int v = 0; v < n; v++) {\n if(dist[v] == ma) continue;\n for(int i=0; i<G[v].size(); i++) {\n Edge &e = G[v][i];\n if(e.cap>0 && dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n\n if(dist[t] == ma) return -1;\n int d = f;\n for(int v = t; v != s; v = prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * dist[t];\n for(int v = t; v != s; v = prevv[v]) {\n Edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n } \n \n int fast_mincost_flow(int s, int t, int f) {\n int res = 0, ma = MAXC;\n vector<int> pot(n);\n while(f > 0) {\n using PT = pair<int, int>;\n priority_queue< PT, vector<PT>, greater<PT> > que;\n fill(dist.begin(), dist.end(), ma);\n\n dist[s] = 0;\n que.push(make_pair(0, s));\n while(que.size()) {\n PT cur = que.top(); que.pop();\n int v = cur.second;\n if(dist[v] < cur.first) continue;\n for(size_t i=0; i<G[v].size(); i++) {\n Edge &e = G[v][i];\n if(e.cap > 0 and dist[e.to] > dist[v] + e.cost + pot[v] - pot[e.to]) {\n dist[e.to] = dist[v] + e.cost + pot[v] - pot[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push(make_pair(dist[e.to], e.to));\n }\n }\n }\n if(dist[t] == ma) {\n return -1;\n }\n for(int v=0; v<n; v++) pot[v] += dist[v];\n\n int d = f;\n for(int v=t; v!=s; v=prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * pot[t];\n for(int v=t; v!=s; v=prevv[v]) {\n Edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n};\n\nvoid chmin(int &A, int B) {\n A = min(A, B);\n}\n\nint D, K, L, M, N, P;\nint c[10][10], r[210][10], t[210][10];\n\nint encode(vector<int> cnt) {\n int sz = cnt.size(), res = 0;\n for(int i=sz-1; i>=0; i--) {\n res = res * 3 + cnt[i];\n }\n return res;\n}\n\nint get_digit(int val, int k) {\n val /= shift[k];\n return val % 3;\n}\n\nint update_digit(int bit, int k, int val) {\n bit -= get_digit(bit, k) * shift[k];\n bit += val * shift[k];\n return bit;\n}\n\nvector<int> solve_dp(int day, const vector<int> &vec) {\n int lim = shift[K];\n vector< vector< vector<int> > > dp(K+1, vector< vector<int> >(L+1, vector<int>(lim, INF)));\n dp[0][0] = vec;\n\n for(int i=0; i<K; i++) {\n for(int j=0; j<=L; j++) {\n for(int bit=0; bit<lim; bit++) {\n int v = get_digit(bit, i);\n for(int x=0; x+v<=2 and x+j<=L; x++) {\n int nbit = update_digit(bit, i, x+v);\n int cost = c[day][i] * x;\n chmin(dp[i+1][j+x][nbit], dp[i][j][bit] + cost);\n }\n }\n }\n }\n\n vector<int> res = vec;\n for(int bit=0; bit<lim; bit++) {\n for(int i=0; i<=L; i++) res[bit] = min(res[bit], dp[K][i][bit]);\n }\n return res;\n}\n\nint solve_testcase() {\n cin >> D >> K >> L;\n if(D == 0 and K == 0 and L == 0) return 1;\n for(int i=0; i<D; i++) {\n for(int j=0; j<K; j++) {\n cin >> c[i][j];\n }\n }\n\n // solve (DP);\n vector<int> vec(shift[K], INF);\n vec[0] = 0;\n for(int i=0; i<D; i++) {\n vec = solve_dp(i, vec);\n }\n\n /*\n for(int i=0; i<shift[K]; i++) {\n fprintf(stderr, \"vec[%d] = %d\\n\", i, vec[i]);\n }\n */\n\n cin >> M >> N >> P;\n for(int i=0; i<M; i++) {\n for(int j=0; j<K; j++) {\n cin >> r[i][j];\n }\n }\n\n for(int i=0; i<P; i++) {\n for(int j=0; j<K; j++) {\n cin >> t[i][j];\n }\n }\n \n Flow fl(M + P + 2);\n int source = M + P, sink = source + 1;\n for(int i=0; i<P; i++) fl.add_edge(source, i, 1, 0);\n for(int i=0; i<M; i++) fl.add_edge(P+i, sink, 1, 0);\n\n // fprintf(stderr, \"source sink end\\n\");\n vector<int> cnt(K);\n for(int i=0; i<P; i++) {\n for(int j=0; j<M; j++) {\n fill(cnt.begin(), cnt.end(), 0);\n\n // fprintf(stderr, \"cnt = %zu\\n\", cnt.size());\n // fprintf(stderr, \"fill end\\n\");\n for(int k=0; k<K; k++) cnt[k] += r[j][k];\n for(int k=0; k<K; k++) cnt[k] -= t[i][k];\n\n bool ok = true;\n for(int k=0; k<K; k++) ok &= (cnt[k] >= 0);\n if(!ok) continue;\n\n // fprintf(stderr, \"before encode\\n\");\n int bit = encode(cnt);\n // fprintf(stderr, \"bit = %d, size = %zu\\n\", bit, vec.size());\n if(vec[bit] == INF) continue;\n // fprintf(stderr, \"add edge: [%d, %d, %d]\\n\", i, j, vec[bit]);\n fl.add_edge(i, P+j, 1, vec[bit]);\n }\n }\n\n for(int i=0; i<M; i++) {\n fill(cnt.begin(), cnt.end(), 0);\n for(int k=0; k<K; k++) cnt[k] += r[i][k];\n int bit = encode(cnt);\n if(vec[bit] == INF) continue;\n // fprintf(stderr, \"# add edge: [source, %d, %d]\\n\", i, vec[bit]);\n fl.add_edge(source, P+i, 1, vec[bit]);\n }\n\n // fprintf(stderr, \"before flow\\n\");\n int ans = fl.fast_mincost_flow(source, sink, N);\n cout << ans << endl;\n return 0;\n}\n\nint main() {\n shift[0] = 1;\n for(int i=1; i<10; i++) shift[i] = shift[i-1] * 3;\n \n while(!solve_testcase());\n}", "accuracy": 1, "time_ms": 1340, "memory_kb": 5256, "score_of_the_acc": -0.4402, "final_rank": 8 }, { "submission_id": "aoj_0274_3713713", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <iostream>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\nconst int INF = 1 << 29;\nint shift[10];\n\nstruct Edge {\n int to, cap, cost, rev;\n Edge(int t, int c, int r) : to(t), cap(c), rev(r) {}\n Edge(int t, int ca, int co, int r) : to(t), cap(ca), cost(co), rev(r) {}\n};\n\nusing Graph = vector< vector< Edge > >;\nstruct Flow {\n vector< vector<Edge> > G;\n const int MAXC = 1 << 29;\n int n;\n vector<bool> used;\n vector<int> prevv, preve, dist;\n Flow(int n_) : G(n_), n(n_), used(n_, false), prevv(n_), preve(n_), dist(n_, MAXC) {}\n\n void add_edge(int from, int to, int cap, int cost) {\n G[from].push_back(Edge(to, cap, cost, G[to].size()));\n G[to ].push_back(Edge(from, 0, -cost, G[from].size() - 1));\n }\n\n int dfs(int v, int t, int f) {\n if(v == t) return f;\n used[v] = true;\n }\n\n\n // ベルマンフォード法で最小費用流を解く\n // 負辺や負閉路があるときは基本的にこちらのほうが確実\n int mincost_flow(int s, int t, int f) {\n int res = 0;\n int ma = MAXC;\n while(f > 0) {\n fill(dist.begin(), dist.end(), ma);\n dist[s] = 0;\n bool update = true;\n while(update) {\n update = false;\n for(int v = 0; v < n; v++) {\n if(dist[v] == ma) continue;\n for(int i=0; i<G[v].size(); i++) {\n Edge &e = G[v][i];\n if(e.cap>0 && dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n\n if(dist[t] == ma) return -1;\n int d = f;\n for(int v = t; v != s; v = prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * dist[t];\n for(int v = t; v != s; v = prevv[v]) {\n Edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n } \n \n int fast_mincost_flow(int s, int t, int f) {\n int res = 0, ma = MAXC;\n vector<int> pot(n);\n while(f > 0) {\n using PT = pair<int, int>;\n priority_queue< PT, vector<PT>, greater<PT> > que;\n fill(dist.begin(), dist.end(), ma);\n\n dist[s] = 0;\n que.push(make_pair(0, s));\n while(que.size()) {\n PT cur = que.top(); que.pop();\n int v = cur.second;\n if(dist[v] < cur.first) continue;\n for(size_t i=0; i<G[v].size(); i++) {\n Edge &e = G[v][i];\n if(e.cap > 0 and dist[e.to] > dist[v] + e.cost + pot[v] - pot[e.to]) {\n dist[e.to] = dist[v] + e.cost + pot[v] - pot[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push(make_pair(dist[e.to], e.to));\n }\n }\n }\n if(dist[t] == ma) {\n return -1;\n }\n for(int v=0; v<n; v++) pot[v] += dist[v];\n\n int d = f;\n for(int v=t; v!=s; v=prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * pot[t];\n for(int v=t; v!=s; v=prevv[v]) {\n Edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n};\n\nvoid chmin(int &A, int B) {\n A = min(A, B);\n}\n\nint D, K, L, M, N, P;\nint c[10][10], r[210][10], t[210][10];\n\nint encode(vector<int> cnt) {\n int sz = cnt.size(), res = 0;\n for(int i=sz-1; i>=0; i--) {\n res = res * 3 + cnt[i];\n }\n return res;\n}\n\nint get_digit(int val, int k) {\n val /= shift[k];\n return val % 3;\n}\n\nint update_digit(int bit, int k, int val) {\n bit -= get_digit(bit, k) * shift[k];\n bit += val * shift[k];\n return bit;\n}\n\nvector<int> solve_dp(int day, const vector<int> &vec) {\n int lim = shift[K];\n vector< vector< vector<int> > > dp(K+1, vector< vector<int> >(L+1, vector<int>(lim, INF)));\n dp[0][0] = vec;\n\n for(int i=0; i<K; i++) {\n for(int j=0; j<=L; j++) {\n for(int bit=0; bit<lim; bit++) {\n int v = get_digit(bit, i);\n for(int x=0; x+v<=2 and x+j<=L; x++) {\n int nbit = update_digit(bit, i, x+v);\n int cost = c[day][i] * x;\n chmin(dp[i+1][j+x][nbit], dp[i][j][bit] + cost);\n }\n }\n }\n }\n\n vector<int> res = vec;\n for(int bit=0; bit<lim; bit++) {\n for(int i=0; i<=L; i++) res[bit] = min(res[bit], dp[K][i][bit]);\n }\n return res;\n}\n\nint solve_testcase() {\n cin >> D >> K >> L;\n if(D == 0 and K == 0 and L == 0) return 1;\n for(int i=0; i<D; i++) {\n for(int j=0; j<K; j++) {\n cin >> c[i][j];\n }\n }\n\n // solve (DP);\n vector<int> vec(shift[K], INF);\n vec[0] = 0;\n for(int i=0; i<D; i++) {\n vec = solve_dp(i, vec);\n }\n\n /*\n for(int i=0; i<shift[K]; i++) {\n fprintf(stderr, \"vec[%d] = %d\\n\", i, vec[i]);\n }\n */\n\n cin >> M >> N >> P;\n for(int i=0; i<M; i++) {\n for(int j=0; j<K; j++) {\n cin >> r[i][j];\n }\n }\n\n for(int i=0; i<P; i++) {\n for(int j=0; j<K; j++) {\n cin >> t[i][j];\n }\n }\n \n Flow fl(M + P + 2);\n int source = M + P, sink = source + 1;\n for(int i=0; i<P; i++) fl.add_edge(source, i, 1, 0);\n for(int i=0; i<M; i++) fl.add_edge(P+i, sink, 1, 0);\n\n // fprintf(stderr, \"source sink end\\n\");\n vector<int> cnt(K);\n for(int i=0; i<P; i++) {\n for(int j=0; j<M; j++) {\n fill(cnt.begin(), cnt.end(), 0);\n\n // fprintf(stderr, \"cnt = %zu\\n\", cnt.size());\n // fprintf(stderr, \"fill end\\n\");\n for(int k=0; k<K; k++) cnt[k] += r[j][k];\n for(int k=0; k<K; k++) cnt[k] -= t[i][k];\n\n bool ok = true;\n for(int k=0; k<K; k++) ok &= (cnt[k] >= 0);\n if(!ok) continue;\n\n // fprintf(stderr, \"before encode\\n\");\n int bit = encode(cnt);\n // fprintf(stderr, \"bit = %d, size = %zu\\n\", bit, vec.size());\n if(vec[bit] == INF) continue;\n // fprintf(stderr, \"add edge: [%d, %d, %d]\\n\", i, j, vec[bit]);\n fl.add_edge(i, P+j, 1, vec[bit]);\n }\n }\n\n for(int i=0; i<M; i++) {\n fill(cnt.begin(), cnt.end(), 0);\n for(int k=0; k<K; k++) cnt[k] += r[i][k];\n int bit = encode(cnt);\n if(vec[bit] == INF) continue;\n // fprintf(stderr, \"# add edge: [source, %d, %d]\\n\", i, vec[bit]);\n fl.add_edge(source, P+i, 1, vec[bit]);\n }\n\n // fprintf(stderr, \"before flow\\n\");\n int ans = fl.mincost_flow(source, sink, N);\n cout << ans << endl;\n return 0;\n}\n\nint main() {\n shift[0] = 1;\n for(int i=1; i<10; i++) shift[i] = shift[i-1] * 3;\n \n while(!solve_testcase());\n}", "accuracy": 1, "time_ms": 1470, "memory_kb": 5332, "score_of_the_acc": -0.4785, "final_rank": 9 }, { "submission_id": "aoj_0274_3222225", "code_snippet": "// 基本テンプレート\n \n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\nusing namespace std;\n \n#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)\n#define repq(i,a,n) for(int (i)=(a); (i)<=(n); (i)++)\n#define repr(i,a,n) for(int (i)=(a); (i)>=(n); (i)--)\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define int long long int\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \ntypedef pair<int, int> pii;\ntypedef long long ll;\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\nint rec[210][210], dp[6600];\nint memo[6600];\n \nint D, K, L, M, N, P;\nint c[10][10], r[210][10], t[210][10];\n\n// Ford-Fulkerson 法による 最大流 O( F |E| )\n// Bellman-Ford 法による 最小費用流 O( F |V| |E| )\n// Verified: AOJ GRL_6_A (Maximum Flow)\n\n// 行き先と容量と逆辺のインデックスを記録する構造体\n// 通常のグラフの辺の構造体と異なるため注意\n\n// 最小費用流はもう少し速くできるので、改良しましょう\n// → ダイクストラが使えるようにポテンシャルを導入しよう\n\ntemplate <typename T>\nstruct Edge {\n int to; T cap, cost; int rev;\n Edge(int t, T c, int r) : to(t), cap(c), rev(r) {}\n Edge(int t, T ca, T co, int r) : to(t), cap(ca), cost(co), rev(r) {}\n};\n\ntemplate <typename T>\nusing Graph = vector< vector< Edge<T> > >;\n\ntemplate <typename T>\nstruct Elem {\n int pos;\n T cost;\n Elem() {}\n Elem(int a, T b) : pos(a), cost(b) {}\n bool operator<(const Elem &e) const {\n return cost > e.cost;\n }\n};\n\ntemplate <typename T>\nstruct Flow {\n vector< vector< Edge<T> > > G;\n const T MAXC = 1 << 30;\n int n;\n vector<bool> used;\n vector<int> prevv, preve, dist, pot;\n Flow(int _n) : G(_n), n(_n), used(_n, false), \n prevv(n), preve(n), dist(n, MAXC), pot(n) {}\n\n // G[e.to][e.rev] で逆辺を操作できる\n void add_edge(int from, int to, T cap) {\n G[from].push_back(Edge<T>(to, cap, G[to].size()));\n G[to].push_back(Edge<T>(from, 0, G[from].size() - 1));\n }\n void add_edge(int from, int to, T cap, T cost) {\n G[from].push_back(Edge<T>(to, cap, cost, G[to].size()));\n G[to].push_back(Edge<T>(from, 0, -cost, G[from].size() - 1));\n }\n\n T dfs(int v, int t, T f) {\n if(v == t) return f;\n used[v] = true;\n for(int i=0; i < G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(!used[e.to] && e.cap > 0) {\n T d = dfs(e.to, t, min(f, e.cap));\n if(d > 0) {\n e.cap -= d;\n G[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n\n T max_flow(int s, int t) {\n T flow = 0;\n while(1) {\n fill(used.begin(), used.end(), false);\n T f = dfs(s, t, INF);\n if(f == 0) return flow;\n flow += f;\n }\n }\n\n \n T mincost_flow(int s, int t, T f) {\n T res = 0;\n T ma = MAXC;\n while(f > 0) {\n fill(dist.begin(), dist.end(), ma);\n dist[s] = 0;\n bool update = true;\n while(update) {\n update = false;\n for(int v = 0; v < n; v++) {\n if(dist[v] == ma) continue;\n for(int i=0; i<G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(e.cap>0 && dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n\n if(dist[t] == ma) return -1;\n T d = f;\n for(int v = t; v != s; v = prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * dist[t];\n for(int v = t; v != s; v = prevv[v]) {\n Edge<T> &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n \n\n /*\n T mincost_flow(int s, int t, T f) {\n T res = 0;\n fill(pot.begin(), pot.end(), 0);\n while(f > 0) {\n priority_queue< Elem<T> > que;\n fill(dist.begin(), dist.end(), INF);\n\n dist[s] = 0;\n que.push(Elem<T>(s, 0));\n\n while(que.size()) {\n Elem<T> cur = que.top(); que.pop();\n int v = cur.pos;\n if(dist[v] < cur.cost) continue;\n for(size_t i=0; i<G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(e.cap > 0 && dist[e.to] > dist[v] + e.cost + pot[v] - pot[e.to]) {\n dist[e.to] = dist[v] + e.cost + pot[v] - pot[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push(Elem<T>(e.to, dist[e.to]));\n }\n }\n }\n\n if(dist[t] == INF) return -1;\n for(int v=0; v<n; v++) pot[v] += dist[v];\n\n T d = f;\n for(int v=t; v!=s; v=prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * pot[t];\n\n for(int v=t; v!=s; v=prevv[v]) {\n Edge<T> &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n */\n};\n\nstring int2tri(int val) {\n string res = \"\";\n for(int i=0; i<K; i++) {\n res += (char)('0' + (val % 3));\n val /= 3;\n }\n return res;\n}\n\nint tri2int(string s) {\n reverse(s.begin(), s.end());\n int res = 0;\n for(size_t i=0; i<s.length(); i++) {\n res *= 3;\n res += (s[i] - '0');\n }\n return res;\n}\n\nsigned main() {\n while(cin >> D >> K >> L, D || K || L) {\n int pow3 = 1;\n for(int i=0; i<K; i++) pow3 *= 3;\n\n for(int i=0; i<D; i++) {\n for(int j=0; j<K; j++) {\n cin >> c[i][j];\n }\n }\n cin >> M >> N >> P;\n for(int i=0; i<M; i++) {\n for(int j=0; j<K; j++) {\n cin >> r[i][j];\n }\n }\n for(int i=0; i<P+1; i++) {\n for(int j=0; j<K; j++) {\n if(i < P) cin >> t[i][j];\n else t[i][j] = 0;\n }\n }\n P++;\n\n fill(memo, memo + 6600, INF);\n fill(dp, dp + 6600, INF);\n memo[0] = 0;\n for(int d=0; d<D; d++) {\n for(int j=0; j<L; j++) {\n for(int x=pow3-1; x>=0; x--) {\n int cost = memo[x];\n string s = int2tri(x);\n for(int i=0; i<K; i++) {\n if(s[i] == '2') continue;\n s[i]++;\n int ncost = cost + c[d][i], nx = tri2int(s);\n if(memo[nx] > ncost) {\n memo[nx] = ncost;\n }\n s[i]--;\n }\n }\n }\n }\n\n for(int j=0; j<=L; j++) {\n for(int x=0; x<pow3; x++) {\n int cost = memo[x];\n chmin(dp[x], cost);\n }\n }\n\n /*\n for(auto x : dp) {\n fprintf(stderr, \"dp[%s] = %lld\\n\", x.first.c_str(), x.second);\n }\n */\n\n for(int i=0; i<M; i++) {\n for(int j=0; j<P; j++) {\n bool ok = true;\n string target = \"\";\n for(int k=0; k<K; k++) {\n if(r[i][k] < t[j][k]) ok = false;\n target += (char)('0' + r[i][k] - t[j][k]);\n }\n\n if(ok) {\n int bit = tri2int(target);\n rec[i][j] = dp[bit];\n }\n else {\n rec[i][j] = INF;\n }\n }\n }\n\n Flow<int> fl(M + P + 1);\n int source = M + P - 1, sink = source + 1;\n for(int i=0; i<M; i++) {\n fl.add_edge(source, i, 1, 0);\n }\n for(int i=0; i<P-1; i++) {\n fl.add_edge(M+i, sink, 1, 0);\n }\n\n for(int i=0; i<M; i++) {\n for(int j=0; j<P; j++) {\n if(rec[i][j] == INF) continue;\n if(j == P - 1) fl.add_edge(i, sink, 1, rec[i][j]);\n else fl.add_edge(i, M+j , 1, rec[i][j]);\n }\n }\n\n int ans = fl.mincost_flow(source, sink, N);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 3700, "memory_kb": 6824, "score_of_the_acc": -1.1436, "final_rank": 15 }, { "submission_id": "aoj_0274_3222221", "code_snippet": "// 基本テンプレート\n \n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\nusing namespace std;\n \n#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)\n#define repq(i,a,n) for(int (i)=(a); (i)<=(n); (i)++)\n#define repr(i,a,n) for(int (i)=(a); (i)>=(n); (i)--)\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define int long long int\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \ntypedef pair<int, int> pii;\ntypedef long long ll;\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\nint rec[210][210], dp[6600];\nint memo[6600];\n \nint D, K, L, M, N, P;\nint c[10][10], r[210][10], t[210][10];\n\n// Ford-Fulkerson 法による 最大流 O( F |E| )\n// Bellman-Ford 法による 最小費用流 O( F |V| |E| )\n// Verified: AOJ GRL_6_A (Maximum Flow)\n\n// 行き先と容量と逆辺のインデックスを記録する構造体\n// 通常のグラフの辺の構造体と異なるため注意\n\n// 最小費用流はもう少し速くできるので、改良しましょう\n// → ダイクストラが使えるようにポテンシャルを導入しよう\n\ntemplate <typename T>\nstruct Edge {\n int to; T cap, cost; int rev;\n Edge(int t, T c, int r) : to(t), cap(c), rev(r) {}\n Edge(int t, T ca, T co, int r) : to(t), cap(ca), cost(co), rev(r) {}\n};\n\ntemplate <typename T>\nusing Graph = vector< vector< Edge<T> > >;\n\ntemplate <typename T>\nstruct Elem {\n int pos;\n T cost;\n Elem() {}\n Elem(int a, T b) : pos(a), cost(b) {}\n bool operator<(const Elem &e) const {\n return cost > e.cost;\n }\n};\n\ntemplate <typename T>\nstruct Flow {\n vector< vector< Edge<T> > > G;\n const T MAXC = 1 << 30;\n int n;\n vector<bool> used;\n vector<int> prevv, preve, dist, pot;\n Flow(int _n) : G(_n), n(_n), used(_n, false), \n prevv(n), preve(n), dist(n, MAXC), pot(n) {}\n\n // G[e.to][e.rev] で逆辺を操作できる\n void add_edge(int from, int to, T cap) {\n G[from].push_back(Edge<T>(to, cap, G[to].size()));\n G[to].push_back(Edge<T>(from, 0, G[from].size() - 1));\n }\n void add_edge(int from, int to, T cap, T cost) {\n G[from].push_back(Edge<T>(to, cap, cost, G[to].size()));\n G[to].push_back(Edge<T>(from, 0, -cost, G[from].size() - 1));\n }\n\n T dfs(int v, int t, T f) {\n if(v == t) return f;\n used[v] = true;\n for(int i=0; i < G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(!used[e.to] && e.cap > 0) {\n T d = dfs(e.to, t, min(f, e.cap));\n if(d > 0) {\n e.cap -= d;\n G[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n\n T max_flow(int s, int t) {\n T flow = 0;\n while(1) {\n fill(used.begin(), used.end(), false);\n T f = dfs(s, t, INF);\n if(f == 0) return flow;\n flow += f;\n }\n }\n\n /*\n T mincost_flow(int s, int t, T f) {\n T res = 0;\n T ma = MAXC;\n while(f > 0) {\n fill(dist.begin(), dist.end(), ma);\n dist[s] = 0;\n bool update = true;\n while(update) {\n update = false;\n for(int v = 0; v < n; v++) {\n if(dist[v] == ma) continue;\n for(int i=0; i<G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(e.cap>0 && dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n\n if(dist[t] == ma) return -1;\n T d = f;\n for(int v = t; v != s; v = prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * dist[t];\n for(int v = t; v != s; v = prevv[v]) {\n Edge<T> &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n */\n\n T mincost_flow(int s, int t, T f) {\n T res = 0;\n fill(pot.begin(), pot.end(), 0);\n while(f > 0) {\n priority_queue< Elem<T> > que;\n fill(dist.begin(), dist.end(), INF);\n\n dist[s] = 0;\n que.push(Elem<T>(s, 0));\n\n while(que.size()) {\n Elem<T> cur = que.top(); que.pop();\n int v = cur.pos;\n if(dist[v] < cur.cost) continue;\n for(size_t i=0; i<G[v].size(); i++) {\n Edge<T> &e = G[v][i];\n if(e.cap > 0 && dist[e.to] > dist[v] + e.cost + pot[v] - pot[e.to]) {\n dist[e.to] = dist[v] + e.cost + pot[v] - pot[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push(Elem<T>(e.to, dist[e.to]));\n }\n }\n }\n\n if(dist[t] == INF) return -1;\n for(int v=0; v<n; v++) pot[v] += dist[v];\n\n T d = f;\n for(int v=t; v!=s; v=prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * pot[t];\n\n for(int v=t; v!=s; v=prevv[v]) {\n Edge<T> &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n};\n\nstring int2tri(int val) {\n string res = \"\";\n for(int i=0; i<K; i++) {\n res += (char)('0' + (val % 3));\n val /= 3;\n }\n return res;\n}\n\nint tri2int(string s) {\n reverse(s.begin(), s.end());\n int res = 0;\n for(size_t i=0; i<s.length(); i++) {\n res *= 3;\n res += (s[i] - '0');\n }\n return res;\n}\n\nsigned main() {\n while(cin >> D >> K >> L, D || K || L) {\n int pow3 = 1;\n for(int i=0; i<K; i++) pow3 *= 3;\n\n for(int i=0; i<D; i++) {\n for(int j=0; j<K; j++) {\n cin >> c[i][j];\n }\n }\n cin >> M >> N >> P;\n for(int i=0; i<M; i++) {\n for(int j=0; j<K; j++) {\n cin >> r[i][j];\n }\n }\n for(int i=0; i<P+1; i++) {\n for(int j=0; j<K; j++) {\n if(i < P) cin >> t[i][j];\n else t[i][j] = 0;\n }\n }\n P++;\n\n fill(memo, memo + 6600, INF);\n fill(dp, dp + 6600, INF);\n memo[0] = 0;\n for(int d=0; d<D; d++) {\n for(int j=0; j<L; j++) {\n for(int x=pow3-1; x>=0; x--) {\n int cost = memo[x];\n string s = int2tri(x);\n for(int i=0; i<K; i++) {\n if(s[i] == '2') continue;\n s[i]++;\n int ncost = cost + c[d][i], nx = tri2int(s);\n if(memo[nx] > ncost) {\n memo[nx] = ncost;\n }\n s[i]--;\n }\n }\n }\n }\n\n for(int j=0; j<=L; j++) {\n for(int x=0; x<pow3; x++) {\n int cost = memo[x];\n chmin(dp[x], cost);\n }\n }\n\n /*\n for(auto x : dp) {\n fprintf(stderr, \"dp[%s] = %lld\\n\", x.first.c_str(), x.second);\n }\n */\n\n for(int i=0; i<M; i++) {\n for(int j=0; j<P; j++) {\n bool ok = true;\n string target = \"\";\n for(int k=0; k<K; k++) {\n if(r[i][k] < t[j][k]) ok = false;\n target += (char)('0' + r[i][k] - t[j][k]);\n }\n\n if(ok) {\n int bit = tri2int(target);\n rec[i][j] = dp[bit];\n }\n else {\n rec[i][j] = INF;\n }\n }\n }\n\n Flow<int> fl(M + P + 1);\n int source = M + P - 1, sink = source + 1;\n for(int i=0; i<M; i++) {\n fl.add_edge(source, i, 1, 0);\n }\n for(int i=0; i<P-1; i++) {\n fl.add_edge(M+i, sink, 1, 0);\n }\n\n for(int i=0; i<M; i++) {\n for(int j=0; j<P; j++) {\n if(rec[i][j] == INF) continue;\n if(j == P - 1) fl.add_edge(i, sink, 1, rec[i][j]);\n else fl.add_edge(i, M+j , 1, rec[i][j]);\n }\n }\n\n int ans = fl.mincost_flow(source, sink, N);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 3730, "memory_kb": 6716, "score_of_the_acc": -1.1469, "final_rank": 16 }, { "submission_id": "aoj_0274_2890061", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\ntypedef pair<int,int> P; //firstは最短距離、secondは頂点の番号\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint h[NUM]; //ポテンシャル\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\tfor(int i = 0; i < V; i++)h[i] = 0; //ポテンシャルを0にする\n\twhile(flow > 0){\n\t\t//ダイクストラ法を用いてhを更新する\n\t\tpriority_queue<P,vector<P>,greater<P>> Q;\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tQ.push(P(0,source));\n\n\t\twhile(!Q.empty()){\n\t\t\tP p = Q.top();\n\t\t\tQ.pop();\n\t\t\tint node_id = p.second;\n\t\t\tif(dist[node_id] < p.first)continue; //最短でなければSKIP\n\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost+h[node_id]-h[e.to]){\n\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost+h[node_id]-h[e.to];\n\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\tQ.push(P(dist[e.to],e.to));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\tfor(int node_id = 0; node_id < V; node_id++)h[node_id] += dist[node_id];\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*h[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif((state/POW[i])%3 == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,200,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 6980, "score_of_the_acc": -0.301, "final_rank": 3 }, { "submission_id": "aoj_0274_2890060", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\twhile(flow > 0){\n\t\t//ベルマンフォード方により、source-sink間最短経路を求める\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tbool update = true;\n\t\twhile(update){\n\t\t\tupdate = false;\n\t\t\tfor(int node_id = 0; node_id < V; node_id++){\n\t\t\t\tif(dist[node_id] == BIG_NUM)continue;\n\t\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost){\n\t\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost; //node_idを経由した方が早い場合\n\t\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*dist[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\tint work[num_item];\n\tstack<int> S;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\t//何をいくつ買ったかを計算\n\t\t\t\ttmp = state;\n\t\t\t\tfor(int i = num_item-1; i >= 0; i--){\n\t\t\t\t\tS.push(tmp/POW[i]);\n\t\t\t\t\ttmp %= POW[i];\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\twork[i] = S.top();\n\t\t\t\t\tS.pop();\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif(work[i] == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,200,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 870, "memory_kb": 7008, "score_of_the_acc": -0.3909, "final_rank": 7 }, { "submission_id": "aoj_0274_2890059", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\ntypedef pair<int,int> P; //firstは最短距離、secondは頂点の番号\n\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\twhile(flow > 0){\n\t\t//ベルマンフォード方により、source-sink間最短経路を求める\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tbool update = true;\n\t\twhile(update){\n\t\t\tupdate = false;\n\t\t\tfor(int node_id = 0; node_id < V; node_id++){\n\t\t\t\tif(dist[node_id] == BIG_NUM)continue;\n\t\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost){\n\t\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost; //node_idを経由した方が早い場合\n\t\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*dist[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\tint work[num_item];\n\tstack<int> S;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\t//何をいくつ買ったかを計算\n\t\t\t\ttmp = state;\n\t\t\t\tfor(int i = num_item-1; i >= 0; i--){\n\t\t\t\t\tS.push(tmp/POW[i]);\n\t\t\t\t\ttmp %= POW[i];\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\twork[i] = S.top();\n\t\t\t\t\tS.pop();\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif(work[i] == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,num_student,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 7056, "score_of_the_acc": -0.3634, "final_rank": 5 }, { "submission_id": "aoj_0274_2890058", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\ntypedef pair<int,int> P; //firstは最短距離、secondは頂点の番号\n\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint h[NUM]; //ポテンシャル\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\tfor(int i = 0; i < V; i++)h[i] = 0; //ポテンシャルを0にする\n\twhile(flow > 0){\n\t\t//ダイクストラ法を用いてhを更新する\n\t\tpriority_queue<P,vector<P>,greater<P>> Q;\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tQ.push(P(0,source));\n\n\t\twhile(!Q.empty()){\n\t\t\tP p = Q.top();\n\t\t\tQ.pop();\n\t\t\tint node_id = p.second;\n\t\t\tif(dist[node_id] < p.first)continue; //最短でなければSKIP\n\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost+h[node_id]-h[e.to]){\n\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost+h[node_id]-h[e.to];\n\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\tQ.push(P(dist[e.to],e.to));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\tfor(int node_id = 0; node_id < V; node_id++)h[node_id] += dist[node_id];\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*h[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\tint work[num_item];\n\tstack<int> S;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\t//何をいくつ買ったかを計算\n\t\t\t\ttmp = state;\n\t\t\t\tfor(int i = num_item-1; i >= 0; i--){\n\t\t\t\t\tS.push(tmp/POW[i]);\n\t\t\t\t\ttmp %= POW[i];\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\twork[i] = S.top();\n\t\t\t\t\tS.pop();\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif(work[i] == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,num_student,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 800, "memory_kb": 6988, "score_of_the_acc": -0.3712, "final_rank": 6 }, { "submission_id": "aoj_0274_2890051", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\twhile(flow > 0){\n\t\t//ベルマンフォード方により、source-sink間最短経路を求める\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tbool update = true;\n\t\twhile(update){\n\t\t\tupdate = false;\n\t\t\tfor(int node_id = 0; node_id < V; node_id++){\n\t\t\t\tif(dist[node_id] == BIG_NUM)continue;\n\t\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost){\n\t\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost; //node_idを経由した方が早い場合\n\t\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*dist[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif((state/POW[i])%3 == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,200,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 6932, "score_of_the_acc": -0.2881, "final_rank": 2 }, { "submission_id": "aoj_0274_2889781", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define NUM 450\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint V; //頂点数\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nint num_day,num_item,num_limit;\nint num_problem,num_student,num_bag;\nint POW[9];\nint price[8][8],problem[200][8],bag[200][8];\nint dp[9][6561][9];\nint min_cost[6561];\nint bag_index[200],problem_index[200];\n\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\twhile(flow > 0){\n\t\t//ベルマンフォード方により、source-sink間最短経路を求める\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tbool update = true;\n\t\twhile(update){\n\t\t\tupdate = false;\n\t\t\tfor(int node_id = 0; node_id < V; node_id++){\n\t\t\t\tif(dist[node_id] == BIG_NUM)continue;\n\t\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost){\n\t\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost; //node_idを経由した方が早い場合\n\t\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*dist[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\t//商品情報を取得\n\tfor(int i = 0; i < num_day; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&price[i][k]);\n\t}\n\n\tscanf(\"%d %d %d\",&num_problem,&num_student,&num_bag);\n\n\tfor(int i = 0; i < num_problem; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&problem[i][k]);\n\t}\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_item; k++)scanf(\"%d\",&bag[i][k]);\n\t}\n\n\tfor(int state = 0; state < POW[num_item]; state++)min_cost[state] = BIG_NUM; //部品をstateの組合せで買う時の最小コスト\n\n\tfor(int day = 0; day <= num_day; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int i = 0; i <= num_limit; i++)dp[day][state][i] = BIG_NUM;\n\t\t}\n\t}\n\n\tdp[0][0][0] = 0;\n\tmin_cost[0] = 0;\n\n\tint next_state,next_cost,tmp;\n\tint work[num_item];\n\n\tstack<int> S;\n\n\t//stateの組合せの部品を揃える際の最小コストを求める\n\tfor(int day = 0; day <= num_day-1; day++){\n\t\tfor(int state = 0; state < POW[num_item]; state++){\n\t\t\tfor(int bought_num = 0; bought_num <= num_limit; bought_num++){\n\n\t\t\t\tif(dp[day][state][bought_num] == BIG_NUM)continue;\n\n\t\t\t\tdp[day+1][state][0] = min(dp[day+1][state][0],dp[day][state][bought_num]);\n\n\t\t\t\tif(bought_num == num_limit)continue; //もう買えないので、dp値を伝播させたらSKIP\n\n\t\t\t\t//何をいくつ買ったかを計算\n\t\t\t\ttmp = state;\n\t\t\t\tfor(int i = num_item-1; i >= 0; i--){\n\t\t\t\t\tS.push(tmp/POW[i]);\n\t\t\t\t\ttmp %= POW[i];\n\t\t\t\t}\n\n\t\t\t\tfor(int i = 0; i < num_item; i++){\n\t\t\t\t\tif(work[i] == 2)continue;\n\n\t\t\t\t\tnext_state = state+POW[i];\n\t\t\t\t\tnext_cost = dp[day][state][bought_num]+price[day][i];\n\n\t\t\t\t\tdp[day][next_state][bought_num+1] = min(dp[day][next_state][bought_num+1],next_cost);\n\t\t\t\t\tmin_cost[next_state] = min(min_cost[next_state],next_cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\tint source = 0, sink = 1, empty_bag = 2, index = 3;\n\n\t//袋の採番\n\tfor(int i = 0; i < num_bag; i++)bag_index[i] = index++;\n\t//課題の採番\n\tfor(int i = 0; i < num_problem; i++)problem_index[i] = index++;\n\n\t//sourceから袋への辺張り\n\tadd_edge(source,empty_bag,200,0); //★★空袋はいくつ割り当てても良い★★\n\tfor(int i = 0; i < num_bag; i++){\n\t\tadd_edge(source,bag_index[i],1,0);\n\t}\n\n\t//課題からsinkへの辺張り\n\tfor(int i = 0; i < num_problem; i++){\n\t\tadd_edge(problem_index[i],sink,1,0);\n\t}\n\n\t//袋と課題のマッチング\n\tint tmp_code;\n\n\t//空袋と全ての課題を繋ぐ\n\tfor(int i = 0; i < num_problem; i++){\n\t\ttmp_code = 0;\n\t\tfor(int k = 0; k < num_item; k++){\n\t\t\ttmp_code += problem[i][k]*POW[k];\n\t\t}\n\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\tadd_edge(empty_bag,problem_index[i],1,min_cost[tmp_code]);\n\t\t}\n\t}\n\n\t//その他の袋と課題を繋ぐ\n\tbool FLG;\n\n\tfor(int i = 0; i < num_bag; i++){\n\t\tfor(int k = 0; k < num_problem; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\tif(bag[i][a] > problem[k][a]){ //部品の超過は不可\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!FLG)continue;\n\n\t\t\ttmp_code = 0;\n\t\t\tfor(int a = 0; a < num_item; a++){\n\t\t\t\ttmp_code += (problem[k][a]-bag[i][a])*POW[a];\n\t\t\t}\n\t\t\tif(min_cost[tmp_code] != BIG_NUM){\n\t\t\t\tadd_edge(bag_index[i],problem_index[k],1,min_cost[tmp_code]);\n\t\t\t}\n\t\t}\n\t}\n\n\tV = index;\n\n\tprintf(\"%d\\n\",min_cost_flow(source,sink,num_student));\n}\n\nint main(){\n\n\tfor(int i = 0; i < 9; i++)POW[i] = pow(3,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&num_day,&num_item,&num_limit);\n\t\tif(num_day == 0 && num_item == 0 && num_limit == 0)break;\n\n\t\tfunc();\n\t}\n\treturn 0;\n}", "accuracy": 0.125, "time_ms": 30, "memory_kb": 12036, "score_of_the_acc": -0.3862, "final_rank": 17 }, { "submission_id": "aoj_0274_2489911", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int, int> P;\n\nstruct edge {\n int to, cap, cost, rev;\n};\n\nint V;\nvector<edge> G[50200];\nint h[50200], dist[50200];\nint prevv[50200], preve[50200];\n\nvoid addEdge(int from, int to, int cap, int cost)\n{\n V = max(V, max(from + 1, to + 1));\n G[from].push_back((edge){to, cap, cost, G[to].size()});\n G[to].push_back((edge){from, 0, -cost, G[from].size() - 1});\n}\n\nint minCostFlow(int s, int t, int f)\n{\n int res = 0;\n fill(h, h + V, 0);\n while (f > 0){\n priority_queue<P, vector<P>, greater<P> > pq;\n fill(dist, dist + V, 1000000000);\n dist[s] = 0; pq.push(P(0, s));\n while (!pq.empty()){\n P p = pq.top(); pq.pop();\n int v = p.second;\n if (dist[v] < p.first) continue;\n for (int i = 0; i < G[v].size(); i++){\n edge &e = G[v][i];\n if (e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to]){\n dist[e.to] = dist[v] + e.cost + h[v] - h[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n pq.push(P(dist[e.to], e.to));\n }\n }\n }\n\n if (dist[t] == 1000000000) return (-1);\n for (int v = 0; v < V; v++) h[v] += dist[v];\n\n int d = f;\n for (int v = t; v != s; v = prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * h[t];\n for (int v = t; v != s; v = prevv[v]){\n edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return (res);\n}\n\nint encode(int *p, int N)\n{\n int ret = 0;\n for (int i = N - 1; i >= 0; i--)\n ret = ret * 3 + p[i];\n return (ret);\n}\n\nvoid decode(int bit, int N, int *p)\n{\n for (int i = 0; i < N; i++){\n p[i] = bit % 3; bit /= 3;\n }\n}\n\nint main()\n{\n int D, K, L;\n int M, N, P;\n int pow3[10];\n\n pow3[0] = 1;\n for (int i = 1; i <= 9; i++) pow3[i] = pow3[i - 1] * 3;\n\n while (scanf(\"%d %d %d\", &D, &K, &L) && D){\n int c[8][8];\n for (int i = 0; i < D; i++)\n for (int j = 0; j < K; j++)\n scanf(\"%d\", &c[i][j]);\n\n scanf(\"%d %d %d\", &M, &N, &P);\n\n int tar[256][8];\n memset(tar, 0, sizeof(tar));\n for (int i = 0; i < M; i++)\n for (int j = 0; j < K; j++)\n scanf(\"%d\", &tar[i][j]);\n\n P++;\n for (int i = 0; i < M + P + 2; i++) G[i].clear();\n\n int dp[9][6561][9];\n for (int i = 0; i < 9; i++)\n for (int j = 0; j < 6561; j++)\n for (int k = 0; k < 9; k++)\n dp[i][j][k] = 1000000000;\n dp[0][0][0] = 0;\n\n int J = pow3[K];\n for (int i = 0; i < D; i++){\n for (int j = 0; j < J; j++){\n for (int k = 0; k <= L; k++)\n dp[i + 1][j][0] = min(dp[i + 1][j][0], dp[i][j][k]);\n for (int k = 0; k < L; k++){\n for (int l = 0; l < K; l++){\n if ((j / pow3[l]) % 3 < 2)\n dp[i + 1][j + pow3[l]][k + 1] = min(dp[i + 1][j + pow3[l]][k + 1], dp[i + 1][j][k] + c[i][l]);\n }\n }\n }\n }\n\n for (int s = 0; s < P; s++){\n int t[8];\n\n if (s != P - 1) for (int i = 0; i < K; i++) scanf(\"%d\", t + i);\n else for (int i = 0; i < K; i++) t[i] = 0;\n\n for (int i = 0; i < M; i++){\n if (!s) addEdge(P + i + 1, P + M + 1, 1, 0);\n\n int mini = 1000000000;\n int tt[8];\n bool flag = false;\n for (int j = 0; j < K; j++) if (tar[i][j] < t[j]) flag = true;\n if (flag) continue;\n for (int j = 0; j < K; j++) tt[j] = tar[i][j] - t[j];\n int x = encode(tt, K);\n for (int j = 0; j <= L; j++) mini = min(mini, dp[D][x][j]);\n if (mini != 1000000000){\n addEdge(s + 1, P + i + 1, 1, mini);\n //printf(\"%d -> %d cost %d\\n\", s + 1, P + i + 1, mini);\n }\n }\n addEdge(0, s + 1, 1 + 1000000000 * (s == P - 1), 0);\n }\n\n printf(\"%d\\n\", minCostFlow(0, M + P + 1, N));\n }\n\n return (0);\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 7892, "score_of_the_acc": -0.3276, "final_rank": 4 }, { "submission_id": "aoj_0274_2488693", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n#ifdef _DEBUG\n#include \"dump.hpp\"\n#else\n#define dump(...)\n#endif\n\n//#define int long long\n#define rep(i,a,b) for(int i=(a);i<(b);i++)\n#define rrep(i,a,b) for(int i=(b)-1;i>=(a);i--)\n#define all(c) begin(c),end(c)\nconst int INF = sizeof(int) == sizeof(long long) ? 0x3f3f3f3f3f3f3f3fLL : 0x3f3f3f3f;\nconst int MOD = (int)(1e9) + 7;\ntemplate<class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (b < a) { a = b; return true; } return false; }\n\nstruct MinimumCostFlow {\n\tusing Flow = int;\n\tusing Cost = int;\n\tconst Cost kInfCost = INF;\n\tstruct Edge {\n\t\tint to, rev;\n\t\tFlow cap;\n\t\tCost cost;\n\t\tEdge() {}\n\t\tEdge(int to, int rev, Flow cap, Cost cost) :to(to), rev(rev), cap(cap), cost(cost) {}\n\t};\n\tint n;\n\tvector<vector<Edge>> g;\n\tvector<Cost> dist;\n\tvector<int> prevv, preve;\n\tMinimumCostFlow(int n) :n(n), g(n), dist(n), prevv(n), preve(n) {}\n\tvoid addArc(int from, int to, Flow cap, Cost cost) {\n\t\tg[from].emplace_back(to, (int)g[to].size(), cap, cost);\n\t\tg[to].emplace_back(from, (int)g[from].size() - 1, 0, -cost);\n\t}\n\t// s??????t????????????f???????°??????¨???\n\t// ??????????????´?????? -1\n\tCost minimumCostFlow(int s, int t, Flow f) {\n\t\tCost total = 0;\n\t\twhile (f > 0) {\n\t\t\t// Bellman-Ford\n\t\t\tfill(dist.begin(), dist.end(), kInfCost);\n\t\t\tdist[s] = 0;\n\t\t\tbool update = true;\n\t\t\twhile (update) {\n\t\t\t\tupdate = false;\n\t\t\t\tfor (int v = 0; v < n; v++) {\n\t\t\t\t\tif (dist[v] == kInfCost)continue;\n\t\t\t\t\tfor (int i = 0; i < g[v].size(); i++) {\n\t\t\t\t\t\tEdge &e = g[v][i];\n\t\t\t\t\t\tif (e.cap > 0 && dist[e.to] > dist[v] + e.cost) {\n\t\t\t\t\t\t\tdist[e.to] = dist[v] + e.cost;\n\t\t\t\t\t\t\tprevv[e.to] = v;\n\t\t\t\t\t\t\tpreve[e.to] = i;\n\t\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// ????????\\???????????????\n\t\t\tif (dist[t] == kInfCost)\n\t\t\t\treturn -1;\n\t\t\t// ?????????????????£??????????????????\n\t\t\tFlow d = f;\n\t\t\tfor (int v = t; v != s; v = prevv[v])\n\t\t\t\td = min(d, g[prevv[v]][preve[v]].cap);\n\t\t\tf -= d;\n\t\t\ttotal += dist[t] * d;\n\t\t\tfor (int v = t; v != s; v = prevv[v]) {\n\t\t\t\tEdge &e = g[prevv[v]][preve[v]];\n\t\t\t\te.cap -= d;\n\t\t\t\tg[v][e.rev].cap += d;\n\t\t\t}\n\t\t}\n\t\treturn total;\n\t}\n};\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tfor (int D, K, L; cin >> D >> K >> L&&D;) {\n\t\tvector<vector<int>> c(D, vector<int>(K));\n\t\trep(i, 0, D) rep(j, 0, K) { cin >> c[i][j]; }\n\t\tint M, N, P; cin >> M >> N >> P;\n\t\tvector<vector<int>> r(M, vector<int>(K));\n\t\trep(i, 0, M) rep(j, 0, K) { cin >> r[i][j]; }\n\t\tvector<vector<int>> t(P + 1, vector<int>(K));\n\t\trep(i, 0, P) rep(j, 0, K) { cin >> t[i][j]; }\n\n\t\tP++;\n\t\tMinimumCostFlow mcf1(M + P + 2);\n\t\tint s1 = mcf1.n - 2, t1 = s1 + 1;\n\n\t\trep(i, 0, P) {\n\t\t\trep(j, 0, M) {\n\t\t\t\tbool ok = true;\n\t\t\t\trep(k, 0, K) {\n\t\t\t\t\tif (r[j][k] < t[i][k])\n\t\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t\tif (ok) {\n\t\t\t\t\tMinimumCostFlow mcf2(D + K + 2);\n\t\t\t\t\tint s2 = mcf2.n - 2, t2 = s2 + 1;\n\t\t\t\t\tint sum = 0;\n\t\t\t\t\trep(d, 0, D) {\n\t\t\t\t\t\trep(k, 0, K) {\n\t\t\t\t\t\t\tmcf2.addArc(d, D + k, L, c[d][k]);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\trep(d, 0, D) {\n\t\t\t\t\t\tmcf2.addArc(s2, d, L, 0);\n\t\t\t\t\t}\n\t\t\t\t\trep(k, 0, K) {\n\t\t\t\t\t\tif (r[j][k] > t[i][k]) {\n\t\t\t\t\t\t\tmcf2.addArc(D + k, t2, r[j][k] - t[i][k], 0);\n\t\t\t\t\t\t\tsum += r[j][k] - t[i][k];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tauto res = mcf2.minimumCostFlow(s2, t2, sum);\n\t\t\t\t\tif (res != -1) {\n\t\t\t\t\t\tmcf1.addArc(i, P + j, 1, res);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\trep(i, 0, P) {\n\t\t\tif (i == P - 1)\n\t\t\t\tmcf1.addArc(s1, i, INF, 0);\n\t\t\telse\n\t\t\t\tmcf1.addArc(s1, i, 1, 0);\n\t\t}\n\t\trep(i, 0, M) {\n\t\t\tmcf1.addArc(P + i, t1, 1, 0);\n\t\t}\n\t\tcout << mcf1.minimumCostFlow(s1, t1, N) << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 4532, "score_of_the_acc": -0.1718, "final_rank": 1 }, { "submission_id": "aoj_0274_2192937", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int long long\n#define all(v) begin(v), end(v)\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define reps(i, s, n) for(int i = (int)(s); i < (int)(n); i++)\n#define min(...) min({__VA_ARGS__})\n#define max(...) max({__VA_ARGS__})\n\nconst int inf = 1LL << 55;\nconst int mod = 1e9 + 7;\n\n// Sccessive Shortest Path(Primal Dual): minimum cost maximum flow\nstruct PrimalDual\n{\n struct edge\n {\n int to, capacity, cost, rev;\n edge(){}\n edge(int to, int capacity, int cost, int rev):to(to), capacity(capacity), cost(cost), rev(rev){}\n };\n\n vector< vector<edge> > graph;\n vector<int> potential, mincost, prevv, preve;\n PrimalDual(int V):graph(V), potential(V), mincost(V), prevv(V), preve(V){}\n void add_edge(int from, int to, int capacity, int cost)\n {\n graph[from].push_back(edge(to, capacity, cost, (int)graph[to].size()));\n graph[to].push_back(edge(from, 0, -cost, (int)graph[from].size()-1));\n }\n int min_cost_flow(int source, int sink, int f)\n {\n int res = 0;\n fill(potential.begin(), potential.end(), 0);\n fill(prevv.begin(), prevv.end(), -1);\n fill(preve.begin(), preve.end(), -1);\n\n while(f > 0) {\n typedef pair<int, int> Pi;\n priority_queue<Pi, vector<Pi>, greater<Pi> > que;\n fill(mincost.begin(), mincost.end(), inf);\n mincost[source] = 0;\n que.push(Pi(0, source));\n while(!que.empty()) {\n\tPi p = que.top(); que.pop();\n\tint v = p.second;\n\tif(mincost[v] < p.first) continue;\n\tfor(int i = 0; i < (int)graph[v].size(); i++) {\n\t edge& e = graph[v][i];\n\t int dual_cost = mincost[v] + e.cost + potential[v] - potential[e.to];\n\t if(e.capacity > 0 && dual_cost < mincost[e.to]) {\n\t mincost[e.to] = dual_cost;\n\t prevv[e.to] = v; preve[e.to] = i;\n\t que.push(Pi(mincost[e.to], e.to));\n\t }\n\t}\n }\n\n if(mincost[sink] == inf) return -1;\n for(int v = 0; v < (int)graph.size(); v++) potential[v] += mincost[v];\n int d = f;\n for(int v = sink; v != source; v = prevv[v]) d = min(d, graph[prevv[v]][preve[v]].capacity);\n f -= d;\n res += d * potential[sink];\n for(int v = sink; v != source; v = prevv[v]) {\n\tedge& e = graph[prevv[v]][preve[v]];\n\te.capacity -= d;\n\tgraph[v][e.rev].capacity += d;\n }\n }\n return res;\n }\n};\n\nint D, K, L, M, N, P;\nint c[8][8];\nint r[200][8], t[200][8];\n\nint rbit[200], tbit[200]; // 1??¨????????¨???2bit???00??????0???/01??????1???/10??????2???\nint dp[1<<16]; // i?????????????\\???§??¨????????¶??????k?????????????°???????\n// ?????????????\\??????§?????¨???????????£???????????°?????????????????§???????????§???i??????????????±??????????????????\n\nsigned main()\n{\n cin.tie(0);\n ios_base::sync_with_stdio(0);\n cout << fixed << setprecision(12);\n\n while(cin >> D >> K >> L, D || K || L) {\n rep(i, D) rep(j, K) cin >> c[i][j];\n cin >> M >> N >> P;\n rep(i, M) rep(j, K) cin >> r[i][j];\n rep(i, P) rep(j, K) cin >> t[i][j];\n\n rep(i, M) {\n rbit[i] = 0;\n rep(j, K) rbit[i] |= r[i][j]<<(j*2);\n }\n rep(i, P) {\n tbit[i] = 0;\n rep(j, K) tbit[i] |= t[i][j]<<(j*2);\n }\n\n fill(dp, dp + (1<<16), inf);\n dp[0] = 0;\n rep(i, D) rep(j, L) { // L?????°???????????°1??\\???L????????§?????£????????¨???????????????\n for(int k = (1<<K*2)-1; k >= 0; k--) { // 1??????????????????????????§????????????\n\trep(l, K) if(((k>>(l*2))&3) < 2) { // 01??????1??????10??????2????????£??????\n\t dp[k+(1<<(l*2))] = min(dp[k+(1<<(l*2))], dp[k] + c[i][l]);\n\t}\n }\n }\n\n int s = M + P, t = s + 1, V = t + 1;\n PrimalDual graph(V);\n rep(i, M) {\n graph.add_edge(s, i, 1, 0); // ???????????¨?????°??????????????????1\n if(dp[rbit[i]] != inf) graph.add_edge(i, t, 1, dp[rbit[i]]); // ?¢?????????§??????\n }\n rep(i, M) rep(j, P) {\n bool flag = true;\n rep(k, K) if(((rbit[i]>>(k*2))&3) < ((tbit[j]>>(k*2))&3)) flag = false; // ?¢???????????????¨??¨??????????????¨????????????\n if(flag && dp[rbit[i]-tbit[j]] != inf) graph.add_edge(i, M + j, 1, dp[rbit[i]-tbit[j]]);\n }\n rep(i, P) {\n graph.add_edge(M + i, t, 1, 0); // ?¢??????¨?????°??????????????????1\n }\n cout << graph.min_cost_flow(s, t, N) << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1440, "memory_kb": 6812, "score_of_the_acc": -0.5355, "final_rank": 11 } ]
aoj_0273_cpp
ねこまっしぐら2 あるところに大きな古いお屋敷があり、1匹のねこが住み着いていました。図のように、お屋敷は上空から見ると凸多角形になっており、まっすぐな壁で囲まれたいくつかの部屋で造られています。1枚の壁はその両端にある柱によって支えられています。お屋敷はとても古いため、どの壁にもねこが通ることができるくらいの穴が1つ空いています。ねこは壁の穴を通ってお屋敷の部屋と部屋または部屋と外を行き来することができます。 お屋敷のご主人は、ねこに餌をあげるために、口笛を吹いてねこをお屋敷の外へ呼び出します。ねこはとても賢く、ご主人が口笛を吹くと、「最良の選択」でお屋敷の外へ抜け出します。つまり、最も少ない回数だけ穴を通って外へ出ます。 ねこはとても気まぐれで、どの部屋にいるか分かりません。そのため、ねこがお屋敷の外へ出るのにかかる時間は日によって異なり、ご主人はどれだけ待てばよいかわからず困っていました。ある時ご主人は、ねこが穴を通り抜けるときに、とても時間がかかっていることに気が付きました。ということは、ねこが外に出るのにかかる時間は穴を通る回数によって決まることになります。ご主人は、ねこが「最良の選択」をした場合の穴を通る回数の最大値が分かれば、ねこがどの部屋にいたとしても、最大どれだけ待てばよいか分かるのではないかと考えました。ご主人はお屋敷の間取りを知っていますが、お屋敷はとても大きく、自分では計算することができません...。 お屋敷の間取りを読み込み、ねこが「最良の選択」をした場合、外に出るまでに通る穴の数の最大値を 出力するプログラムを作成して下さい。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。各データセットは以下の形式で与えられる。 C W x 1 y 1 x 2 y 2 : x C y C s 1 t 1 s 2 t 2 : s W t W 各行で与えられる数値は1つの空白で区切られている。 1行目に柱の数 C (3 ≤ C ≤ 100) と壁の数 W (3 ≤ W ≤ 300) が与えられる。続く C 行に柱の座標が与えられる。x i (-1000 ≤ x i ≤ 1000) は i 番目の柱の x 座標、y i (-1000 ≤ y i ≤ 1000) は i 番目の柱の y 座標をそれぞれ示す整数である。柱にはそれぞれ 1 から C までの番号が割り当てられている。 続く W 行に壁の情報が与えられる。 s i (1 ≤ s i ≤ C)、t i (1 ≤ t i ≤ C) は壁の両端を支える柱の番号を示す。 入力は以下の条件を満たすと考えてよい。 異なる柱が同じ位置を占めることはない。 異なる壁が重なったり、柱以外で交差することはない。 1つの柱は2つ以上の壁を支えている。 壁の長さは 0 より大きい。 柱は壁の両端だけにある。つまり、柱が壁の途中にあることはない。 壁は異なる2つの部屋、あるいは部屋と外とを仕切る。 任意の異なる2つの柱を選んだとき、互いの柱には壁をたどって到達できる。 データセットの数は 50 を超えない。 出力 データセットごとに、ねこが「最良の選択」をした場合、外に出るまでに通る穴の数の最大値を1行に出力する。 入力例 4 4 0 0 1 0 1 1 0 1 1 2 1 4 2 3 3 4 12 22 2 0 4 0 8 0 4 2 6 2 8 2 2 4 4 4 6 4 0 6 8 6 0 8 1 2 2 3 1 4 1 7 1 10 2 4 2 5 3 5 3 6 4 5 4 8 5 6 5 9 6 9 6 11 7 10 7 8 8 9 9 11 10 11 10 12 11 12 0 0 出力例 1 3 2つ目のデータセットが、冒頭の図に示したお屋敷の間取りに対応する。図のように、薄く色が塗られた部屋にねこがいるときは、「最良の選択」で外に出るまでに通り抜ける穴の数は3つである。それ以外の部屋にねこがいるときは、2つ以下で外に出られる。したがって、ねこが「最良の選択」をしたとき、外に出るまでに通り抜ける穴の数の最大値は 3 になる。
[ { "submission_id": "aoj_0273_10848620", "code_snippet": "#include <bits/stdc++.h>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(),(x).end()\n\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\n\ntemplate <typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate <typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\n\nstruct yes_no : numpunct<char> {\n string_type do_truename() const { return \"Yes\"; }\n string_type do_falsename() const { return \"No\"; }\n};\n\nusing ld = long double;\nusing P = complex<ld>;\nusing VP = vector<P>;\nconst ld eps = 1e-8, pi = acos(-1.0);\n\nP input() { ld x, y; cin >> x >> y; return P(x, y); }\n\nld dot (P a, P b) { return real(conj(a) * b); }\nld cross (P a, P b) { return imag(conj(a) * b); }\n\nstruct L{ P a, b; };\nstruct C { P p; ld r; };\n\nint ccw (P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > eps) return 1; // counter clockwise\n if (cross(b, c) < -eps) return -1; // clockwise\n if (dot(b, c) < 0) return 2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line\n return 0; // a--c--b on line\n}\n\nint is_clockwise(const vector<P> &ps) {\n int n = ps.size();\n ld sum = 0;\n REP(i,n) {\n P v1 = ps[(i+1)%n] - ps[i];\n P v2 = ps[(i+2)%n] - ps[(i+1)%n];\n sum += arg(v2 / v1);\n }\n return sum > 0;\n}\n\nstruct Edge{ int src, dest; };\n\nusing Edges = vector<Edge>;\nusing Graph = vector<Edges>;\n\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n \nGraph dual_graph(const vector<L> &s, const VP &p) {\n int N = p.size();\n polygon.clear();\n REP(i,1024) REP(j,1024) seg2p[i][j].clear();\n vector<vector<tuple<ld,int,bool>>> tup(N);\n REP(i,s.size()) {\n int a = -1, b = -1;\n REP(j,N) if (abs(s[i].a - p[j]) < eps) a = j;\n REP(j,N) if (abs(s[i].b - p[j]) < eps) b = j;\n assert(a >= 0 && b >= 0);\n tup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n tup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n }\n REP(i,N) sort(ALL(tup[i]));\n REP(i,N) {\n REP(j,tup[i].size()) {\n ld angle; int pos = j, src = i, dest; bool flag;\n tie(angle, dest, flag) = tup[i][j];\n if (flag) continue;\n vector<int> ps;\n while (!flag) {\n ps.push_back(src);\n get<2>(tup[src][pos]) = true;\n seg2p[src][dest].push_back(polygon.size());\n seg2p[dest][src].push_back(polygon.size());\n angle += pi + eps;\n if (angle > pi) angle -= 2 * pi;\n auto it = lower_bound(ALL(tup[dest]), make_tuple(angle, 0, false));\n if (it == tup[dest].end()) it = tup[dest].begin();\n src = dest; tie(angle, dest, flag) = *it;\n pos = it - tup[src].begin();\n }\n polygon.push_back(ps);\n }\n }\n Graph g(polygon.size());\n REP(i,N) REP(j,i) {\n if (seg2p[i][j].size() == 2) {\n int src = seg2p[i][j][0], dest = seg2p[i][j][1];\n g[src].push_back((Edge){src, dest});\n g[dest].push_back((Edge){dest, src});\n }\n }\n return g;\n}\n\nvoid bfs(Graph &g, vector<int> &d, int s) {\n d.assign(g.size(), -1);\n d[s] = 0;\n queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e: g[v]) {\n if (d[e.dest] == -1) {\n d[e.dest] = d[v] + 1;\n que.push(e.dest);\n }\n }\n }\n}\n\nint main() {\n locale loc(locale(), new yes_no);\n cout << boolalpha << setprecision(12) << fixed;\n cout.imbue(loc);\n\n int C, W;\n while (cin >> C >> W, C) {\n vector<P> points(C);\n vector<L> segments(W);\n REP(i,C) points[i] = input();\n REP(i,W) {\n int s, t;\n cin >> s >> t; --s; --t;\n segments[i] = L({points[s], points[t]});\n }\n Graph g = dual_graph(segments, points);\n int V = g.size();\n int start = 0;\n REP(i,V) {\n vector<P> poly;\n for (int j: polygon[i]) {\n poly.push_back(points[j]);\n }\n if (is_clockwise(poly)) start = i;\n }\n vector<int> d;\n bfs(g, d, start);\n cout << *max_element(ALL(d)) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 28156, "score_of_the_acc": -1.4443, "final_rank": 15 }, { "submission_id": "aoj_0273_10845864", "code_snippet": "#include <bits/stdc++.h>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(),(x).end()\n\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\n\ntemplate <typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate <typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\n\nstruct yes_no : numpunct<char> {\n string_type do_truename() const { return \"Yes\"; }\n string_type do_falsename() const { return \"No\"; }\n};\n\nusing ld = long double;\nusing P = complex<ld>;\nusing VP = vector<P>;\nconst ld eps = 1e-8, pi = acos(-1.0);\n\nP input() { ld x, y; cin >> x >> y; return P(x, y); }\n\nld dot (P a, P b) { return real(conj(a) * b); }\nld cross (P a, P b) { return imag(conj(a) * b); }\n\nstruct L{ P a, b; };\nstruct C { P p; ld r; };\n\nint ccw (P a, P b, P c) {\n b -= a; c -= a;\n if (cross(b, c) > eps) return 1; // counter clockwise\n if (cross(b, c) < -eps) return -1; // clockwise\n if (dot(b, c) < 0) return 2; // c--a--b on line\n if (norm(b) < norm(c)) return -2; // a--b--c on line\n return 0; // a--c--b on line\n}\n\nint is_clockwise(const vector<P> &ps) {\n int n = ps.size();\n ld sum = 0;\n REP(i,n) {\n P v1 = ps[(i+1)%n] - ps[i];\n P v2 = ps[(i+2)%n] - ps[(i+1)%n];\n sum += arg(v2 / v1);\n }\n return sum > 0;\n}\n\nstruct Edge{ int src, dest; };\n\nusing Edges = vector<Edge>;\nusing Graph = vector<Edges>;\n\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n \nGraph dual_graph(const vector<L> &s, const VP &p) {\n int N = p.size();\n polygon.clear();\n REP(i,1024) REP(j,1024) seg2p[i][j].clear();\n vector<vector<tuple<ld,int,bool>>> tup(N);\n REP(i,s.size()) {\n int a = -1, b = -1;\n REP(j,N) if (abs(s[i].a - p[j]) < eps) a = j;\n REP(j,N) if (abs(s[i].b - p[j]) < eps) b = j;\n assert(a >= 0 && b >= 0);\n tup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n tup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n }\n REP(i,N) sort(ALL(tup[i]));\n REP(i,N) {\n REP(j,tup[i].size()) {\n ld angle; int pos = j, src = i, dest; bool flag;\n tie(angle, dest, flag) = tup[i][j];\n if (flag) continue;\n vector<int> ps;\n while (!flag) {\n ps.push_back(src);\n get<2>(tup[src][pos]) = true;\n seg2p[src][dest].push_back(polygon.size());\n seg2p[dest][src].push_back(polygon.size());\n angle += pi + eps;\n if (angle > pi) angle -= 2 * pi;\n auto it = lower_bound(ALL(tup[dest]), make_tuple(angle, 0, false));\n if (it == tup[dest].end()) it = tup[dest].begin();\n src = dest; tie(angle, dest, flag) = *it;\n pos = it - tup[src].begin();\n }\n polygon.push_back(ps);\n }\n }\n Graph g(polygon.size());\n REP(i,N) REP(j,i) {\n if (seg2p[i][j].size() == 2) {\n int src = seg2p[i][j][0], dest = seg2p[i][j][1];\n g[src].push_back((Edge){src, dest});\n g[dest].push_back((Edge){dest, src});\n }\n }\n return g;\n}\n\nvoid bfs(Graph &g, vector<int> &d, int s) {\n d.assign(g.size(), -1);\n d[s] = 0;\n queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e: g[v]) {\n if (d[e.dest] == -1) {\n d[e.dest] = d[v] + 1;\n que.push(e.dest);\n }\n }\n }\n}\n\nint main() {\n locale loc(locale(), new yes_no);\n cout << boolalpha << setprecision(12) << fixed;\n cout.imbue(loc);\n\n int C, W;\n while (cin >> C >> W, C) {\n vector<P> points(C);\n vector<L> segments(W);\n REP(i,C) points[i] = input();\n REP(i,W) {\n int s, t;\n cin >> s >> t; --s; --t;\n segments[i] = L({points[s], points[t]});\n }\n Graph g = dual_graph(segments, points);\n int V = g.size();\n int start = 0;\n REP(i,V) {\n vector<P> poly;\n for (int j: polygon[i]) {\n poly.push_back(points[j]);\n }\n if (is_clockwise(poly)) start = i;\n }\n vector<int> d;\n bfs(g, d, start);\n cout << *max_element(ALL(d)) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 28160, "score_of_the_acc": -1.4444, "final_rank": 16 }, { "submission_id": "aoj_0273_7174761", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double eps = 0.000001;\nint sign(double x){\n if (x > eps){\n return 1;\n } else if (x < -eps){\n return -1;\n } else {\n return 0;\n }\n}\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(){\n }\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\nbool is_parallel(line L1, line L2){\n return abs(cross(vec(L1), vec(L2))) < eps;\n}\nbool segment_line_intersect(line L1, line L2){\n return sign(cross(L1.A - L2.A, vec(L2))) * sign(cross(L1.B - L2.A, vec(L2))) <= 0;\n}\nbool segment_intersect(line L1, line L2){\n return segment_line_intersect(L1, L2) && segment_line_intersect(L2, L1);\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nvector<double> unique_eps(vector<double> A){\n int N = A.size();\n sort(A.begin(), A.end());\n vector<double> A2;\n A2.push_back(A[0]);\n for (int i = 1; i < N; i++){\n if (A[i] - A[i - 1] > eps){\n A2.push_back(A[i]);\n }\n }\n return A2;\n}\ntemplate <typename T>\nstruct slab_decomposition{\n function<T(T, T)> f;\n T e;\n vector<pair<line, T>> S;\n vector<double> X;\n int N;\n vector<vector<double>> Y;\n vector<int> P;\n vector<vector<tuple<int, int, T>>> E;\n slab_decomposition(function<T(T, T)> f, T e): f(f), e(e){\n }\n void add_segment(line s, T x){\n S.push_back(make_pair(s, x));\n }\n vector<vector<pair<T, int>>> build(){\n int M = S.size();\n for (int i = 0; i < M; i++){\n if (S[i].first.A.x > S[i].first.B.x){\n swap(S[i].first.A, S[i].first.B);\n }\n }\n for (int i = 0; i < M; i++){\n X.push_back(S[i].first.A.x);\n X.push_back(S[i].first.B.x);\n }\n for (int i = 0; i < M; i++){\n for (int j = i + 1; j < M; j++){\n if (!is_parallel(S[i].first, S[j].first) && segment_intersect(S[i].first, S[j].first)){\n X.push_back(line_intersection(S[i].first, S[j].first).x);\n }\n }\n }\n X = unique_eps(X);\n N = X.size();\n vector<int> L(M), R(M);\n for (int i = 0; i < M; i++){\n L[i] = lower_bound(X.begin(), X.end(), S[i].first.A.x - eps) - X.begin();\n R[i] = lower_bound(X.begin(), X.end(), S[i].first.B.x - eps) - X.begin();\n }\n vector<vector<double>> A(M, vector<double>(N));\n Y.resize(N);\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n A[i][j] = line_intersection(S[i].first, line(point(X[j], 0), point(X[j], 1))).y;\n Y[j].push_back(A[i][j]);\n }\n }\n for (int i = 0; i < N; i++){\n Y[i] = unique_eps(Y[i]);\n }\n vector<vector<int>> B(M, vector<int>(N));\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n B[i][j] = lower_bound(Y[j].begin(), Y[j].end(), A[i][j] - eps) - Y[j].begin();\n }\n }\n E.resize(N - 1);\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_tuple(-1, -1, e));\n }\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j < R[i]; j++){\n E[j].push_back(make_tuple(B[i][j], B[i][j + 1], S[i].second));\n }\n }\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_tuple(Y[i].size(), Y[i + 1].size(), e));\n }\n for (int i = 0; i < N - 1; i++){\n sort(E[i].begin(), E[i].end());\n if (!E[i].empty()){\n vector<tuple<int, int, T>> E2;\n int cnt = E[i].size();\n E2.push_back(E[i][0]);\n for (int j = 1; j < cnt; j++){\n if (get<0>(E[i][j - 1]) == get<0>(E[i][j]) && get<1>(E[i][j - 1]) == get<1>(E[i][j])){\n get<2>(E2.back()) = f(get<2>(E2.back()), get<2>(E[i][j]));\n } else {\n E2.push_back(E[i][j]);\n }\n }\n E[i] = E2;\n }\n }\n P.resize(N + 2);\n P[0] = 0;\n P[1] = 1;\n for (int i = 0; i < N - 1; i++){\n P[i + 2] = P[i + 1] + E[i].size() - 1;\n }\n P[N + 1] = P[N] + 1;\n vector<vector<int>> idL(N), idR(N);\n for (int i = 0; i < N; i++){\n idL[i] = vector<int>(Y[i].size() + 1);\n idR[i] = vector<int>(Y[i].size() + 1);\n }\n idL[0] = vector<int>(Y[0].size() + 1, 0);\n for (int i = 0; i < N - 1; i++){\n int cnt = E[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = get<0>(E[i][j]) + 1; k <= get<0>(E[i][j + 1]); k++){\n idR[i][k] = P[i + 1] + j;\n }\n for (int k = get<1>(E[i][j]) + 1; k <= get<1>(E[i][j + 1]); k++){\n idL[i + 1][k] = P[i + 1] + j;\n }\n }\n }\n idR[N - 1] = vector<int>(Y[N - 1].size() + 1, P[N]);\n int V = P[N + 1];\n vector<vector<pair<T, int>>> G(V);\n for (int i = 0; i <= N; i++){\n for (int j = P[i]; j < P[i + 1] - 1; j++){\n G[j].push_back(make_pair(get<2>(E[i - 1][j - P[i] + 1]), j + 1));\n G[j + 1].push_back(make_pair(get<2>(E[i - 1][j - P[i] + 1]), j));\n }\n }\n for (int i = 0; i < N; i++){\n for (int j = 0; j <= Y[i].size(); j++){\n G[idL[i][j]].push_back(make_pair(e, idR[i][j]));\n G[idR[i][j]].push_back(make_pair(e, idL[i][j]));\n }\n }\n return G;\n }\n int find(point p){\n int x = lower_bound(X.begin(), X.end(), p.x - eps) - X.begin();\n if (x == 0){\n return 0;\n } else if (x == N){\n return P[N];\n } else {\n int ans = P[x];\n for (int i = 1; i < E[x - 1].size() - 1; i++){\n point A(X[x - 1], Y[x - 1][get<0>(E[x - 1][i])]);\n point B(X[x], Y[x][get<1>(E[x - 1][i])]);\n if (cross(B - A, p - A) > 0){\n ans++;\n }\n }\n return ans;\n }\n }\n vector<double> area(){\n int V = P[N + 1];\n vector<double> ans(V, -1);\n for (int i = 0; i < N - 1; i++){\n for(int j = 1; j < E[i].size() - 2; j++){\n double l = Y[i][get<0>(E[i][j + 1])] - Y[i][get<0>(E[i][j])];\n double r = Y[i + 1][get<1>(E[i][j + 1])] - Y[i + 1][get<1>(E[i][j])];\n ans[P[i + 1] + j] = (l + r) * (X[i + 1] - X[i]) / 2;\n }\n }\n return ans;\n }\n vector<double> length(){\n int V = P[N + 1];\n vector<double> ans(V, -1);\n for (int i = 0; i < N - 1; i++){\n for(int j = 1; j < E[i].size() - 1; j++){\n double l = Y[i][get<0>(E[i][j])];\n double r = Y[i + 1][get<1>(E[i][j])];\n ans[P[i + 1] + j - 1] = hypot(X[i + 1] - X[i], r - l);\n }\n }\n return ans;\n }\n};\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 1);\n }\n slab_decomposition<bool> D(logical_or<>(), false);\n for (int i = 0; i < W; i++){\n D.add_segment(line(P[s[i]], P[t[i]]), true);\n }\n vector<vector<pair<bool, int>>> E = D.build();\n int V = E.size();\n vector<int> d(V, -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (pair<int, int> e : E[v]){\n int w = e.second;\n if (d[w] == -1){\n if (!e.first){\n dq.push_front(make_pair(c, w));\n } else {\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < V; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4216, "score_of_the_acc": -0.0949, "final_rank": 10 }, { "submission_id": "aoj_0273_7174196", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double eps = 0.00001;\nint sign(double x){\n if (x > eps){\n return 1;\n } else if (x < -eps){\n return -1;\n } else {\n return 0;\n }\n}\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(){\n }\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\nbool is_parallel(line L1, line L2){\n return abs(cross(vec(L1), vec(L2))) < eps;\n}\nbool segment_line_intersect(line L1, line L2){\n return sign(cross(L1.A - L2.A, vec(L2))) * sign(cross(L1.B - L2.A, vec(L2))) <= 0;\n}\nbool segment_intersect(line L1, line L2){\n return segment_line_intersect(L1, L2) && segment_line_intersect(L2, L1);\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nvector<double> unique_eps(vector<double> A){\n int N = A.size();\n sort(A.begin(), A.end());\n vector<double> A2;\n A2.push_back(A[0]);\n for (int i = 1; i < N; i++){\n if (A[i] - A[i - 1] > eps){\n A2.push_back(A[i]);\n }\n }\n return A2;\n}\nstruct slab_decomposition{\n vector<line> S;\n slab_decomposition(){\n }\n void add_segment(line s){\n S.push_back(s);\n }\n vector<vector<pair<int, int>>> build(){\n int M = S.size();\n for (int i = 0; i < M; i++){\n if (S[i].A.x > S[i].B.x){\n swap(S[i].A, S[i].B);\n }\n }\n vector<double> X;\n for (int i = 0; i < M; i++){\n X.push_back(S[i].A.x);\n X.push_back(S[i].B.x);\n }\n for (int i = 0; i < M; i++){\n for (int j = i + 1; j < M; j++){\n if (!is_parallel(S[i], S[j]) && segment_intersect(S[i], S[j])){\n X.push_back(line_intersection(S[i], S[j]).x);\n }\n }\n }\n X = unique_eps(X);\n int N = X.size();\n vector<int> L(M), R(M);\n for (int i = 0; i < M; i++){\n L[i] = lower_bound(X.begin(), X.end(), S[i].A.x - eps) - X.begin();\n R[i] = lower_bound(X.begin(), X.end(), S[i].B.x - eps) - X.begin();\n }\n vector<vector<double>> A(M, vector<double>(N));\n vector<vector<double>> Y(N);\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n A[i][j] = line_intersection(S[i], line(point(X[j], 0), point(X[j], 1))).y;\n Y[j].push_back(A[i][j]);\n }\n }\n for (int i = 0; i < N; i++){\n Y[i] = unique_eps(Y[i]);\n }\n vector<vector<int>> B(M, vector<int>(N));\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n B[i][j] = lower_bound(Y[j].begin(), Y[j].end(), A[i][j] - eps) - Y[j].begin();\n }\n }\n vector<vector<pair<int, int>>> E(N - 1);\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_pair(-1, -1));\n }\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j < R[i]; j++){\n E[j].push_back(make_pair(B[i][j], B[i][j + 1]));\n }\n }\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_pair(Y[i].size(), Y[i + 1].size()));\n }\n for (int i = 0; i < N - 1; i++){\n sort(E[i].begin(), E[i].end());\n }\n vector<int> S(N + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < N - 1; i++){\n S[i + 2] = S[i + 1] + E[i].size() - 1;\n }\n S[N + 1] = S[N] + 1;\n vector<vector<int>> idL(N), idR(N);\n for (int i = 0; i < N; i++){\n idL[i] = vector<int>(Y[i].size() + 1);\n idR[i] = vector<int>(Y[i].size() + 1);\n }\n idL[0] = vector<int>(Y[0].size() + 1, 0);\n for (int i = 0; i < N - 1; i++){\n int cnt = E[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = E[i][j].first + 1; k <= E[i][j + 1].first; k++){\n idR[i][k] = S[i + 1] + j;\n }\n for (int k = E[i][j].second + 1; k <= E[i][j + 1].second; k++){\n idL[i + 1][k] = S[i + 1] + j;\n }\n }\n }\n idR[N - 1] = vector<int>(Y[N - 1].size() + 1, S[N]);\n int V = S[N + 1];\n vector<vector<pair<int, int>>> G(V);\n for (int i = 0; i <= N; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n G[j].push_back(make_pair(1, j + 1));\n G[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < N; i++){\n for (int j = 0; j <= Y[i].size(); j++){\n G[idL[i][j]].push_back(make_pair(0, idR[i][j]));\n G[idR[i][j]].push_back(make_pair(0, idL[i][j]));\n }\n }\n return G;\n }\n};\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 1);\n }\n slab_decomposition D;\n for (int i = 0; i < W; i++){\n D.add_segment(line(P[s[i]], P[t[i]]));\n }\n vector<vector<pair<int, int>>> E = D.build();\n int V = E.size();\n vector<int> d(V, -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (pair<int, int> e : E[v]){\n int w = e.second;\n if (d[w] == -1){\n if (e.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (e.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < V; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4100, "score_of_the_acc": -0.0902, "final_rank": 9 }, { "submission_id": "aoj_0273_7173835", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double eps = 0.00001;\nint sign(double x){\n if (x > eps){\n return 1;\n } else if (x < -eps){\n return -1;\n } else {\n return 0;\n }\n}\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\ndouble dist(point P, point Q){\n return abs(Q - P);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(){\n }\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\nbool is_parallel(line L1, line L2){\n return abs(cross(vec(L1), vec(L2))) < eps;\n}\nbool segment_line_intersect(line L1, line L2){\n return sign(cross(L1.A - L2.A, vec(L2))) * sign(cross(L1.B - L2.A, vec(L2))) <= 0;\n}\nbool segment_intersect(line L1, line L2){\n return segment_line_intersect(L1, L2) && segment_line_intersect(L2, L1);\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nvector<double> unique_eps(vector<double> A){\n int N = A.size();\n sort(A.begin(), A.end());\n vector<double> A2;\n A2.push_back(A[0]);\n for (int i = 1; i < N; i++){\n if (A[i] - A[i - 1] > eps){\n A2.push_back(A[i]);\n }\n }\n return A2;\n}\nstruct slab_decomposition{\n vector<line> S;\n vector<double> X;\n vector<vector<double>> Y;\n slab_decomposition(){\n }\n void add_segment(line s){\n S.push_back(s);\n }\n vector<vector<pair<int, int>>> build(){\n int M = S.size();\n for (int i = 0; i < M; i++){\n if (S[i].A.x > S[i].B.x){\n swap(S[i].A, S[i].B);\n }\n }\n for (int i = 0; i < M; i++){\n X.push_back(S[i].A.x);\n X.push_back(S[i].B.x);\n }\n for (int i = 0; i < M; i++){\n for (int j = i + 1; j < M; j++){\n if (!is_parallel(S[i], S[j]) && segment_intersect(S[i], S[j])){\n X.push_back(line_intersection(S[i], S[j]).x);\n }\n }\n }\n X = unique_eps(X);\n int N = X.size();\n vector<int> L(M), R(M);\n for (int i = 0; i < M; i++){\n L[i] = lower_bound(X.begin(), X.end(), S[i].A.x - eps) - X.begin();\n R[i] = lower_bound(X.begin(), X.end(), S[i].B.x - eps) - X.begin();\n }\n vector<vector<double>> A(M, vector<double>(N));\n vector<vector<double>> Y(N);\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n A[i][j] = line_intersection(S[i], line(point(X[j], 0), point(X[j], 1))).y;\n Y[j].push_back(A[i][j]);\n }\n }\n for (int i = 0; i < N; i++){\n Y[i] = unique_eps(Y[i]);\n }\n vector<vector<int>> B(M, vector<int>(N));\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j <= R[i]; j++){\n B[i][j] = lower_bound(Y[j].begin(), Y[j].end(), A[i][j] - eps) - Y[j].begin();\n }\n }\n vector<vector<pair<int, int>>> E(N - 1);\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_pair(-1, -1));\n }\n for (int i = 0; i < M; i++){\n for (int j = L[i]; j < R[i]; j++){\n E[j].push_back(make_pair(B[i][j], B[i][j + 1]));\n }\n }\n for (int i = 0; i < N - 1; i++){\n E[i].push_back(make_pair(Y[i].size(), Y[i + 1].size()));\n }\n for (int i = 0; i < N - 1; i++){\n sort(E[i].begin(), E[i].end());\n }\n vector<int> S(N + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < N - 1; i++){\n S[i + 2] = S[i + 1] + E[i].size() - 1;\n }\n S[N + 1] = S[N] + 1;\n vector<vector<int>> idL(N), idR(N);\n for (int i = 0; i < N; i++){\n idL[i] = vector<int>(Y[i].size() + 1);\n idR[i] = vector<int>(Y[i].size() + 1);\n }\n idL[0] = vector<int>(Y[0].size() + 1, 0);\n for (int i = 0; i < N - 1; i++){\n int cnt = E[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = E[i][j].first + 1; k <= E[i][j + 1].first; k++){\n idR[i][k] = S[i + 1] + j;\n }\n for (int k = E[i][j].second + 1; k <= E[i][j + 1].second; k++){\n idL[i + 1][k] = S[i + 1] + j;\n }\n }\n }\n idR[N - 1] = vector<int>(Y[N - 1].size() + 1, S[N]);\n int V = S[N + 1];\n vector<vector<pair<int, int>>> G(V);\n for (int i = 0; i <= N; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n G[j].push_back(make_pair(1, j + 1));\n G[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < N; i++){\n for (int j = 0; j <= Y[i].size(); j++){\n G[idL[i][j]].push_back(make_pair(0, idR[i][j]));\n G[idR[i][j]].push_back(make_pair(0, idL[i][j]));\n }\n }\n return G;\n }\n};\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 1);\n }\n slab_decomposition D;\n for (int i = 0; i < W; i++){\n D.add_segment(line(P[s[i]], P[t[i]]));\n }\n vector<vector<pair<int, int>>> E = D.build();\n int V = E.size();\n vector<int> d(V, -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (pair<int, int> e : E[v]){\n int w = e.second;\n if (d[w] == -1){\n if (e.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (e.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < V; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4236, "score_of_the_acc": -0.0957, "final_rank": 11 }, { "submission_id": "aoj_0273_7130290", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n};\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\nint main(){\n while (true){\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0){\n break;\n }\n vector<point> P(N);\n for (int i = 0; i < N; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(M), t(M);\n for (int i = 0; i < M; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < N; i++){\n P[i] = rotate(P[i], 0.01);\n }\n vector<double> X;\n for (int i = 0; i < N; i++){\n X.push_back(P[i].x);\n }\n sort(X.begin(), X.end());\n vector<int> l(M), r(M);\n for (int i = 0; i < M; i++){\n if (P[s[i]].x > P[t[i]].x){\n swap(s[i], t[i]);\n }\n l[i] = lower_bound(X.begin(), X.end(), P[s[i]].x) - X.begin();\n r[i] = lower_bound(X.begin(), X.end(), P[t[i]].x) - X.begin();\n }\n vector<vector<double>> Y(M, vector<double>(N));\n for (int i = 0; i < M; i++){\n Y[i][l[i]] = P[s[i]].y;\n for (int j = l[i] + 1; j < r[i]; j++){\n Y[i][j] = P[s[i]].y + (P[t[i]].y - P[s[i]].y) * (X[j] - X[l[i]]) / (X[r[i]] - X[l[i]]);\n }\n Y[i][r[i]] = P[t[i]].y;\n }\n vector<vector<double>> Y2(N);\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j <= r[i]; j++){\n Y2[j].push_back(Y[i][j]);\n }\n }\n for (int i = 0; i < N; i++){\n sort(Y2[i].begin(), Y2[i].end());\n Y2[i].erase(unique(Y2[i].begin(), Y2[i].end()), Y2[i].end());\n }\n vector<int> YC(N);\n for (int i = 0; i < N; i++){\n YC[i] = Y2[i].size();\n }\n vector<vector<int>> A(M, vector<int>(N));\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j <= r[i]; j++){\n A[i][j] = lower_bound(Y2[j].begin(), Y2[j].end(), Y[i][j]) - Y2[j].begin();\n }\n }\n vector<vector<pair<int, int>>> C(N - 1);\n for (int i = 0; i < N - 1; i++){\n C[i].push_back(make_pair(-1, -1));\n }\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j < r[i]; j++){\n C[j].push_back(make_pair(A[i][j], A[i][j + 1]));\n }\n }\n for (int i = 0; i < N - 1; i++){\n C[i].push_back(make_pair(YC[i], YC[i + 1]));\n }\n for (int i = 0; i < N - 1; i++){\n sort(C[i].begin(), C[i].end());\n }\n vector<int> S(N + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < N - 1; i++){\n S[i + 2] = S[i + 1] + C[i].size() - 1;\n }\n S[N + 1] = S[N] + 1;\n vector<vector<int>> idL(N), idR(N);\n for (int i = 0; i < N; i++){\n idL[i] = vector<int>(YC[i] + 1);\n idR[i] = vector<int>(YC[i] + 1);\n }\n idL[0] = vector<int>(YC[0] + 1, 0);\n for (int i = 0; i < N - 1; i++){\n int cnt = C[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = C[i][j].first + 1; k <= C[i][j + 1].first; k++){\n idR[i][k] = S[i + 1] + j;\n }\n for (int k = C[i][j].second + 1; k <= C[i][j + 1].second; k++){\n idL[i + 1][k] = S[i + 1] + j;\n }\n }\n }\n idR[N - 1] = vector<int>(YC[N - 1] + 1, S[N]);\n int V = S[N + 1];\n vector<vector<pair<int, int>>> E(V);\n for (int i = 0; i <= N; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n E[j].push_back(make_pair(1, j + 1));\n E[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < N; i++){\n for (int j = 0; j <= YC[i]; j++){\n E[idL[i][j]].push_back(make_pair(0, idR[i][j]));\n E[idR[i][j]].push_back(make_pair(0, idL[i][j]));\n }\n }\n vector<int> d(V, -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (pair<int, int> e : E[v]){\n int w = e.second;\n if (d[w] == -1){\n if (e.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (e.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < V; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4200, "score_of_the_acc": -0.0387, "final_rank": 4 }, { "submission_id": "aoj_0273_7130288", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n};\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\nint main(){\n while (true){\n int N, M;\n cin >> N >> M;\n if (N == 0 && M == 0){\n break;\n }\n vector<point> P(N);\n for (int i = 0; i < N; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(M), t(M);\n for (int i = 0; i < M; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < N; i++){\n P[i] = rotate(P[i], 0.01);\n }\n vector<double> X;\n for (int i = 0; i < N; i++){\n X.push_back(P[i].x);\n }\n sort(X.begin(), X.end());\n vector<int> l(M), r(M);\n for (int i = 0; i < M; i++){\n if (P[s[i]].x > P[t[i]].x){\n swap(s[i], t[i]);\n }\n l[i] = lower_bound(X.begin(), X.end(), P[s[i]].x) - X.begin();\n r[i] = lower_bound(X.begin(), X.end(), P[t[i]].x) - X.begin();\n }\n vector<vector<double>> Y(M, vector<double>(N));\n for (int i = 0; i < M; i++){\n Y[i][l[i]] = P[s[i]].y;\n for (int j = l[i] + 1; j < r[i]; j++){\n Y[i][j] = P[s[i]].y + (P[t[i]].y - P[s[i]].y) * (X[j] - X[l[i]]) / (X[r[i]] - X[l[i]]);\n }\n Y[i][r[i]] = P[t[i]].y;\n }\n vector<vector<double>> Y2(N);\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j <= r[i]; j++){\n Y2[j].push_back(Y[i][j]);\n }\n }\n for (int i = 0; i < N; i++){\n sort(Y2[i].begin(), Y2[i].end());\n Y2[i].erase(unique(Y2[i].begin(), Y2[i].end()), Y2[i].end());\n }\n vector<vector<int>> A(M, vector<int>(N));\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j <= r[i]; j++){\n A[i][j] = lower_bound(Y2[j].begin(), Y2[j].end(), Y[i][j]) - Y2[j].begin();\n }\n }\n vector<vector<pair<int, int>>> C(N - 1);\n for (int i = 0; i < M; i++){\n for (int j = l[i]; j < r[i]; j++){\n C[j].push_back(make_pair(A[i][j], A[i][j + 1]));\n }\n }\n for (int i = 0; i < N - 1; i++){\n sort(C[i].begin(), C[i].end());\n }\n vector<int> YC(N);\n for (int i = 0; i < N; i++){\n YC[i] = Y2[i].size();\n }\n vector<int> S(N + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < N - 1; i++){\n S[i + 2] = S[i + 1] + C[i].size() + 1;\n }\n S[N + 1] = S[N] + 1;\n vector<vector<int>> idL(N), idR(N);\n for (int i = 0; i < N; i++){\n idL[i] = vector<int>(YC[i] + 1);\n idR[i] = vector<int>(YC[i] + 1);\n }\n idL[0] = vector<int>(YC[0] + 1, 0);\n for (int i = 0; i < N - 1; i++){\n vector<pair<int, int>> C2 = C[i];\n C2.insert(C2.begin(), make_pair(-1, -1));\n C2.push_back(make_pair(YC[i], YC[i + 1]));\n int cnt = C2.size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = C2[j].first + 1; k <= C2[j + 1].first; k++){\n idR[i][k] = S[i + 1] + j;\n }\n for (int k = C2[j].second + 1; k <= C2[j + 1].second; k++){\n idL[i + 1][k] = S[i + 1] + j;\n }\n }\n }\n idR[N - 1] = vector<int>(YC[N - 1] + 1, S[N]);\n int V = S[N + 1];\n vector<vector<pair<int, int>>> E(V);\n for (int i = 0; i <= N; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n E[j].push_back(make_pair(1, j + 1));\n E[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < N; i++){\n for (int j = 0; j <= YC[i]; j++){\n E[idL[i][j]].push_back(make_pair(0, idR[i][j]));\n E[idR[i][j]].push_back(make_pair(0, idL[i][j]));\n }\n }\n vector<int> d(V, -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (pair<int, int> e : E[v]){\n int w = e.second;\n if (d[w] == -1){\n if (e.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (e.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < V; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4312, "score_of_the_acc": -0.0432, "final_rank": 5 }, { "submission_id": "aoj_0273_6025463", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 0.01);\n }\n vector<double> X;\n for (int i = 0; i < C; i++){\n X.push_back(P[i].x);\n }\n sort(X.begin(), X.end()); \n for (int i = 0; i < W; i++){\n if (P[s[i]].x > P[t[i]].x){\n swap(s[i], t[i]);\n }\n }\n vector<int> l(W), r(W);\n for (int i = 0; i < W; i++){\n l[i] = lower_bound(X.begin(), X.end(), P[s[i]].x) - X.begin();\n r[i] = lower_bound(X.begin(), X.end(), P[t[i]].x) - X.begin();\n }\n vector<vector<pair<int, double>>> y(W);\n for (int i = 0; i < W; i++){\n y[i].push_back(make_pair(l[i], P[s[i]].y));\n line L(P[s[i]], P[t[i]]);\n for (int j = l[i] + 1; j < r[i]; j++){\n line L2(point(X[j], 0), point(X[j], 1));\n y[i].push_back(make_pair(j, line_intersection(L, L2).y));\n }\n y[i].push_back(make_pair(r[i], P[t[i]].y));\n }\n vector<vector<double>> y2(C);\n for (int i = 0; i < W; i++){\n int cnt = y[i].size();\n for (int j = 0; j < cnt; j++){\n int id = y[i][j].first;\n double p = y[i][j].second;\n y2[id].push_back(p);\n }\n }\n for (int i = 0; i < C; i++){\n sort(y2[i].begin(), y2[i].end());\n y2[i].erase(unique(y2[i].begin(), y2[i].end()), y2[i].end());\n }\n vector<vector<pair<int, int>>> e(C - 1);\n for (int i = 0; i < W; i++){\n vector<int> id(r[i] - l[i] + 1);\n for (int j = l[i]; j <= r[i]; j++){\n id[j - l[i]] = lower_bound(y2[j].begin(), y2[j].end(), y[i][j - l[i]].second) - y2[j].begin();\n }\n for (int j = 0; j < r[i] - l[i]; j++){\n e[l[i] + j].push_back(make_pair(id[j], id[j + 1]));\n }\n }\n for (int i = 0; i < C - 1; i++){\n sort(e[i].begin(), e[i].end());\n }\n vector<int> S(C + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < C - 1; i++){\n S[i + 2] = S[i + 1] + e[i].size() + 1;\n }\n S[C + 1] = S[C] + 1;\n vector<int> T(C + 1);\n T[0] = S[C + 1];\n for (int i = 0; i < C; i++){\n T[i + 1] = T[i] + y2[i].size() + 1;\n }\n vector<vector<pair<int, int>>> E(T[C]);\n for (int i = 0; i <= C; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n E[j].push_back(make_pair(1, j + 1));\n E[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < C; i++){\n if (i == 0){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[0]].push_back(make_pair(0, T[0] + j));\n E[T[0] + j].push_back(make_pair(0, S[0]));\n }\n }\n if (i > 0){\n E[S[i]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i]));\n int cnt = e[i - 1].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = e[i - 1][j].second + 1; k <= e[i - 1][j + 1].second; k++){\n E[S[i] + j + 1].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i] + j + 1));\n }\n }\n for (int k = e[i - 1][cnt - 1].second + 1; k <= y2[i].size(); k++){\n E[S[i] + cnt].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i] + cnt));\n }\n }\n if (i < C - 1){\n E[S[i + 1]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i + 1]));\n int cnt = e[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = e[i][j].first + 1; k <= e[i][j + 1].first; k++){\n E[S[i + 1] + j + 1].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i + 1] + j + 1));\n }\n }\n for (int k = e[i][cnt - 1].first + 1; k <= y2[i].size(); k++){\n E[S[i + 1] + cnt].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i + 1] + cnt));\n }\n }\n if (i == C - 1){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[i + 1]].push_back(make_pair(0, T[i] + j));\n E[T[i] + j].push_back(make_pair(0, S[i + 1]));\n }\n }\n }\n vector<int> d(T[C], -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (auto p : E[v]){\n int w = p.second;\n if (d[w] == -1){\n if (p.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (p.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < T[C]; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3980, "score_of_the_acc": -0.0299, "final_rank": 3 }, { "submission_id": "aoj_0273_6024112", "code_snippet": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 0.01);\n }\n vector<double> X;\n for (int i = 0; i < C; i++){\n X.push_back(P[i].x);\n }\n sort(X.begin(), X.end()); \n for (int i = 0; i < W; i++){\n if (P[s[i]].x > P[t[i]].x){\n swap(s[i], t[i]);\n }\n }\n vector<int> l(W), r(W);\n for (int i = 0; i < W; i++){\n l[i] = lower_bound(X.begin(), X.end(), P[s[i]].x) - X.begin();\n r[i] = lower_bound(X.begin(), X.end(), P[t[i]].x) - X.begin();\n }\n vector<vector<pair<int, double>>> y(W);\n for (int i = 0; i < W; i++){\n y[i].push_back(make_pair(l[i], P[s[i]].y));\n line L(P[s[i]], P[t[i]]);\n for (int j = l[i] + 1; j < r[i]; j++){\n line L2(point(X[j], 0), point(X[j], 1));\n y[i].push_back(make_pair(j, line_intersection(L, L2).y));\n }\n y[i].push_back(make_pair(r[i], P[t[i]].y));\n }\n vector<vector<double>> y2(C);\n for (int i = 0; i < W; i++){\n int cnt = y[i].size();\n for (int j = 0; j < cnt; j++){\n int id = y[i][j].first;\n double p = y[i][j].second;\n y2[id].push_back(p);\n }\n }\n for (int i = 0; i < C; i++){\n sort(y2[i].begin(), y2[i].end());\n y2[i].erase(unique(y2[i].begin(), y2[i].end()), y2[i].end());\n }\n vector<vector<pair<int, int>>> e(C - 1);\n for (int i = 0; i < W; i++){\n vector<int> id(r[i] - l[i] + 1);\n for (int j = l[i]; j <= r[i]; j++){\n id[j - l[i]] = lower_bound(y2[j].begin(), y2[j].end(), y[i][j - l[i]].second) - y2[j].begin();\n }\n for (int j = 0; j < r[i] - l[i]; j++){\n e[l[i] + j].push_back(make_pair(id[j], id[j + 1]));\n }\n }\n for (int i = 0; i < C - 1; i++){\n sort(e[i].begin(), e[i].end());\n }\n vector<int> S(C + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < C - 1; i++){\n S[i + 2] = S[i + 1] + e[i].size() + 1;\n }\n S[C + 1] = S[C] + 1;\n vector<int> T(C + 1);\n T[0] = S[C + 1];\n for (int i = 0; i < C; i++){\n T[i + 1] = T[i] + y2[i].size() + 1;\n }\n vector<vector<pair<int, int>>> E(T[C]);\n for (int i = 0; i <= C; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n E[j].push_back(make_pair(1, j + 1));\n E[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < C; i++){\n if (i == 0){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[0]].push_back(make_pair(0, T[0] + j));\n E[T[0] + j].push_back(make_pair(0, S[0]));\n }\n }\n if (i > 0){\n E[S[i]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i]));\n int cnt = e[i - 1].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = e[i - 1][j].second + 1; k <= e[i - 1][j + 1].second; k++){\n E[S[i] + j + 1].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i] + j + 1));\n }\n }\n for (int k = e[i - 1][cnt - 1].second + 1; k <= y2[i].size(); k++){\n E[S[i] + cnt].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i] + cnt));\n }\n }\n if (i < C - 1){\n E[S[i + 1]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i + 1]));\n int cnt = e[i].size();\n for (int j = 0; j < cnt - 1; j++){\n for (int k = e[i][j].first + 1; k <= e[i][j + 1].first; k++){\n E[S[i + 1] + j + 1].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i + 1] + j + 1));\n }\n }\n for (int k = e[i][cnt - 1].first + 1; k <= y2[i].size(); k++){\n E[S[i + 1] + cnt].push_back(make_pair(0, T[i] + k));\n E[T[i] + k].push_back(make_pair(0, S[i + 1] + cnt));\n }\n }\n if (i == C - 1){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[i + 1]].push_back(make_pair(0, T[i] + j));\n E[T[i] + j].push_back(make_pair(0, S[i + 1]));\n }\n }\n }\n vector<int> d(T[C], -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (auto p : E[v]){\n int w = p.second;\n if (d[w] == -1){\n if (p.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (p.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < T[C]; i++){\n ans = max(ans, d[i]);\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 4220, "score_of_the_acc": -0.7061, "final_rank": 13 }, { "submission_id": "aoj_0273_6024111", "code_snippet": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\nstruct point{\n double x, y;\n point(){\n }\n point(double x, double y): x(x), y(y){\n }\n point operator +(point P){\n return point(x + P.x, y + P.y);\n }\n point operator -(point P){\n return point(x - P.x, y - P.y);\n }\n point operator *(double k){\n return point(x * k, y * k);\n }\n point operator /(double k){\n return point(x / k, y / k);\n }\n};\ndouble abs(point P){\n return sqrt(P.x * P.x + P.y * P.y);\n}\npoint rotate(point P, double t){\n return point(P.x * cos(t) - P.y * sin(t), P.x * sin(t) + P.y * cos(t));\n}\ndouble cross(point P, point Q){\n return P.x * Q.y - P.y * Q.x;\n}\nstruct line{\n point A, B;\n line(point A, point B): A(A), B(B){\n }\n};\npoint vec(line L){\n return L.B - L.A;\n}\npoint line_intersection(line L1, line L2){\n return L1.A + vec(L1) * cross(L2.A - L1.A, vec(L2)) / cross(vec(L1), vec(L2));\n}\nint main(){\n while (true){\n int C, W;\n cin >> C >> W;\n if (C == 0 && W == 0){\n break;\n }\n vector<point> P(C);\n for (int i = 0; i < C; i++){\n cin >> P[i].x >> P[i].y;\n }\n vector<int> s(W), t(W);\n for (int i = 0; i < W; i++){\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n }\n for (int i = 0; i < C; i++){\n P[i] = rotate(P[i], 0.01);\n }\n vector<double> X;\n for (int i = 0; i < C; i++){\n X.push_back(P[i].x);\n }\n sort(X.begin(), X.end()); \n for (int i = 0; i < W; i++){\n if (P[s[i]].x > P[t[i]].x){\n swap(s[i], t[i]);\n }\n }\n vector<int> l(W), r(W);\n for (int i = 0; i < W; i++){\n l[i] = lower_bound(X.begin(), X.end(), P[s[i]].x) - X.begin();\n r[i] = lower_bound(X.begin(), X.end(), P[t[i]].x) - X.begin();\n }\n vector<vector<pair<int, double>>> y(W);\n for (int i = 0; i < W; i++){\n y[i].push_back(make_pair(l[i], P[s[i]].y));\n line L(P[s[i]], P[t[i]]);\n for (int j = l[i] + 1; j < r[i]; j++){\n line L2(point(X[j], 0), point(X[j], 1));\n y[i].push_back(make_pair(j, line_intersection(L, L2).y));\n }\n y[i].push_back(make_pair(r[i], P[t[i]].y));\n }\n vector<vector<double>> y2(C);\n for (int i = 0; i < W; i++){\n int cnt = y[i].size();\n for (int j = 0; j < cnt; j++){\n int id = y[i][j].first;\n double p = y[i][j].second;\n y2[id].push_back(p);\n }\n }\n for (int i = 0; i < C; i++){\n sort(y2[i].begin(), y2[i].end());\n y2[i].erase(unique(y2[i].begin(), y2[i].end()), y2[i].end());\n }\n vector<vector<pair<int, int>>> e(C - 1);\n for (int i = 0; i < W; i++){\n vector<int> id(r[i] - l[i] + 1);\n for (int j = l[i]; j <= r[i]; j++){\n id[j - l[i]] = lower_bound(y2[j].begin(), y2[j].end(), y[i][j - l[i]].second) - y2[j].begin();\n }\n for (int j = 0; j < r[i] - l[i]; j++){\n e[l[i] + j].push_back(make_pair(id[j], id[j + 1]));\n }\n }\n for (int i = 0; i < C - 1; i++){\n sort(e[i].begin(), e[i].end());\n }\n vector<int> S(C + 2);\n S[0] = 0;\n S[1] = 1;\n for (int i = 0; i < C - 1; i++){\n S[i + 2] = S[i + 1] + e[i].size() + 1;\n }\n S[C + 1] = S[C] + 1;\n vector<int> T(C + 1);\n T[0] = S[C + 1];\n for (int i = 0; i < C; i++){\n T[i + 1] = T[i] + y2[i].size() + 1;\n }\n vector<vector<pair<int, int>>> E(T[C]);\n for (int i = 0; i <= C; i++){\n for (int j = S[i]; j < S[i + 1] - 1; j++){\n E[j].push_back(make_pair(1, j + 1));\n E[j + 1].push_back(make_pair(1, j));\n }\n }\n for (int i = 0; i < C; i++){\n if (i == 0){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[0]].push_back(make_pair(0, T[0] + j));\n E[T[0] + j].push_back(make_pair(0, S[0]));\n }\n }\n if (i > 0){\n E[S[i]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i]));\n int cnt = e[i - 1].size();\n for (int j = 0; j < cnt - 1; j++){\n if (e[i - 1][j].second != e[i - 1][j + 1].second){\n E[S[i] + j + 1].push_back(make_pair(0, T[i] + e[i - 1][j + 1].second));\n E[T[i] + e[i - 1][j + 1].second].push_back(make_pair(0, S[i] + j + 1));\n }\n }\n E[S[i] + cnt].push_back(make_pair(0, T[i] + y2[i].size()));\n E[T[i] + y2[i].size()].push_back(make_pair(0, S[i] + cnt));\n }\n if (i < C - 1){\n E[S[i + 1]].push_back(make_pair(0, T[i]));\n E[T[i]].push_back(make_pair(0, S[i + 1]));\n int cnt = e[i].size();\n for (int j = 0; j < cnt - 1; j++){\n if (e[i][j].first != e[i][j + 1].first){\n E[S[i + 1] + j + 1].push_back(make_pair(0, T[i] + e[i][j + 1].first));\n E[T[i] + e[i][j + 1].first].push_back(make_pair(0, S[i + 1] + j + 1));\n }\n }\n E[S[i + 1] + cnt].push_back(make_pair(0, T[i] + y2[i].size()));\n E[T[i] + y2[i].size()].push_back(make_pair(0, S[i + 1] + cnt));\n }\n if (i == C - 1){\n int cnt = y2[i].size();\n for (int j = 0; j <= cnt; j++){\n E[S[i + 1]].push_back(make_pair(0, T[i] + j));\n E[T[i] + j].push_back(make_pair(0, S[i + 1]));\n }\n }\n }\n vector<int> d(T[C], -1);\n deque<pair<int, int>> dq;\n dq.push_back(make_pair(0, 0));\n while (!dq.empty()){\n int c = dq.front().first;\n int v = dq.front().second;\n dq.pop_front();\n if (d[v] == -1){\n d[v] = c;\n for (auto p : E[v]){\n int w = p.second;\n if (d[w] == -1){\n if (p.first == 0){\n dq.push_front(make_pair(c, w));\n }\n if (p.first == 1){\n dq.push_back(make_pair(c + 1, w));\n }\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < T[C]; i++){\n ans = max(ans, d[i]);\n assert(d[i] != -1);\n }\n cout << ans << endl;\n }\n}", "accuracy": 0.5, "time_ms": 10, "memory_kb": 4032, "score_of_the_acc": -0.0319, "final_rank": 17 }, { "submission_id": "aoj_0273_3826099", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 105\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\tdouble x,y;\n};\n\nstruct Edge{\n\tEdge(int arg_to,double arg_theta){\n\t\tto = arg_to;\n\t\ttheta = arg_theta;\n\t}\n\tbool operator<(const struct Edge &arg) const{\n\n\t\treturn theta < arg.theta;\n\t}\n\n\tint to;\n\tdouble theta;\n};\n\nstruct Info{\n\tInfo(int arg_area_id,int arg_sum_dist){\n\t\tarea_id = arg_area_id;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn sum_dist > arg.sum_dist; //総距離の降順(PQ)\n\t}\n\n\tint area_id,sum_dist;\n};\n\ntypedef Point Vector;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tPoint p[2];\n};\n\n\nint num_pillar,num_wall;\nPoint point[SIZE];\nvector<Edge> G[SIZE];\nint min_dist[100*33*49];\n\n\nvector<int> get_area(int first_from,int first_to){\n\n\tvector<int> ret;\n\n\tint from = first_from;\n\tint to = first_to;\n\n\tdo{\n\n\t\tret.push_back(from);\n\t\tint next = to;\n\n\t\tfor(int k = 0; k < G[next].size(); k++){\n\t\t\tif(G[next][k].to == from){\n\t\t\t\tif(k != 0){\n\n\t\t\t\t\tto = G[next][k-1].to;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tto = G[next][G[to].size()-1].to;\n\t\t\t\t}\n\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tfrom = next;\n\n\t}while(from != first_from || to != first_to);\n\n\treturn ret;\n}\n\n\nvector<int> pol_sort(vector<int> polygon){\n\n\tint min_index = BIG_NUM,loc;\n\n\tfor(int i = 0; i < polygon.size(); i++){\n\n\t\tif(min_index > polygon[i]){\n\t\t\tmin_index = polygon[i];\n\t\t\tloc = i;\n\t\t}\n\t}\n\n\t//min_indexが先頭になるようにする\n\tfor(int i = 0; i < loc; i++){\n\n\t\tpolygon.push_back(polygon[0]);\n\t\tpolygon.erase(polygon.begin());\n\t}\n\n\treturn polygon;\n}\n\ndouble get_theta(Vector A){\n\n\tdouble ret = atan2(A.y,A.x);\n\n\tif(ret < 0){\n\n\t\tret += 2*M_PI;\n\t}\n\treturn ret;\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tG[i].clear();\n\t}\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tscanf(\"%lf %lf\",&point[i].x,&point[i].y);\n\t}\n\n\tint from,to;\n\n\tfor(int i = 0; i < num_wall; i++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\n\t\tfrom--;\n\t\tto--;\n\n\t\tG[from].push_back(Edge(to,get_theta(point[from]-point[to])));\n\t\tG[to].push_back(Edge(from,get_theta(point[to]-point[from])));\n\t}\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tsort(G[i].begin(),G[i].end());\n\t}\n\n\tvector<vector<int>> first_POLYGON;\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tvector<int> polygon = pol_sort(get_area(i,G[i][k].to));\n\n\t\t\tfirst_POLYGON.push_back(polygon);\n\t\t}\n\t}\n\n\tsort(first_POLYGON.begin(),first_POLYGON.end());\n\tfirst_POLYGON.erase(unique(first_POLYGON.begin(),first_POLYGON.end()),first_POLYGON.end());\n\n\tvector<vector<int>> POLYGON;\n\tvector<int> A,B;\n\n\tfor(int i = 0; i < first_POLYGON.size(); i++){\n\n\t\tbool FLG = true;\n\t\tA = first_POLYGON[i];\n\t\tsort(A.begin(),A.end());\n\n\t\tfor(int k = 0; k < i; k++){\n\t\t\tB = first_POLYGON[k];\n\t\t\tsort(B.begin(),B.end());\n\n\t\t\tif(A == B){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t}\n\t\tif(FLG){\n\t\t\tPOLYGON.push_back(first_POLYGON[i]);\n\t\t}\n\t}\n\n\tif(POLYGON.size() == 1){\n\n\t\tprintf(\"1\\n\");\n\t\treturn;\n\t}\n\n\tvector<int> dist_1;\n\n\tfor(int i = 0; i < POLYGON.size(); i++){\n\n\t\tdouble tmp = 0;\n\n\t\tfor(int k = 0; k < POLYGON[i].size(); k++){\n\n\t\t\ttmp += cross(point[POLYGON[i][k]],point[POLYGON[i][(k+1)%POLYGON[i].size()]]);\n\t\t}\n\t\tif(tmp < EPS){\n\t\t\tdist_1.push_back(i);\n\t\t}\n\t}\n\n\tint num_area = POLYGON.size();\n\tvector<int> final_G[num_area];\n\n\n\tfor(int i = 0; i < num_area-1; i++){ //領域\n\n\t\tfor(int a = 0; a < POLYGON[i].size(); a++){ //辺の走査\n\n\t\t\tLine tmp_line = Line(point[POLYGON[i][a]],point[POLYGON[i][(a+1)%POLYGON[i].size()]]);\n\n\t\t\tbool FLG = false;\n\n\t\t\tfor(int k = i+1; k < num_area; k++){ //隣接領域\n\t\t\t\tif(k == i)continue;\n\n\t\t\t\tfor(int b = 0; b < POLYGON[k].size(); b++){ //隣接領域の辺\n\t\t\t\t\tLine tmp_line2 = Line(point[POLYGON[k][b]],point[POLYGON[k][(b+1)%POLYGON[k].size()]]);\n\n\t\t\t\t\tif((tmp_line.p[0] == tmp_line2.p[0] && tmp_line.p[1] == tmp_line2.p[1]) ||\n\t\t\t\t\t\t\t(tmp_line.p[0] == tmp_line2.p[1] && tmp_line.p[1] == tmp_line2.p[0])){\n\n\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\tfinal_G[i].push_back(k);\n\t\t\t\t\t\tfinal_G[k].push_back(i);\n\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(FLG)break;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_area; i++){\n\n\t\tmin_dist[i] = BIG_NUM;\n\t}\n\n\tpriority_queue<Info> Q;\n\n\tfor(int i = 0; i < dist_1.size(); i++){\n\n\t\tmin_dist[dist_1[i]] = 1;\n\t\tQ.push(Info(dist_1[i],1));\n\t}\n\n\twhile(!Q.empty()){\n\n\t\tif(Q.top().sum_dist > min_dist[Q.top().area_id]){\n\n\t\t\tQ.pop();\n\n\t\t}else{\n\n\t\t\tfor(int i = 0; i < final_G[Q.top().area_id].size(); i++){\n\n\t\t\t\tint next_area = final_G[Q.top().area_id][i];\n\t\t\t\tint next_dist = Q.top().sum_dist+1;\n\n\t\t\t\tif(min_dist[next_area] > next_dist){\n\t\t\t\t\tmin_dist[next_area] = next_dist;\n\t\t\t\t\tQ.push(Info(next_area,next_dist));\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tfor(int i = 0; i < num_area; i++){\n\n\t\tans = max(ans,min_dist[i]);\n\t}\n\n\tprintf(\"%d\\n\",ans-1);\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d %d\",&num_pillar,&num_wall);\n\t\tif(num_pillar == 0 && num_wall == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3616, "score_of_the_acc": -0.0708, "final_rank": 8 }, { "submission_id": "aoj_0273_3826098", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 105\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\tbool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\tdouble x,y;\n};\n\nstruct Edge{\n\tEdge(int arg_to,double arg_theta){\n\t\tto = arg_to;\n\t\ttheta = arg_theta;\n\t}\n\tbool operator<(const struct Edge &arg) const{\n\n\t\treturn theta < arg.theta;\n\t}\n\n\tint to;\n\tdouble theta;\n};\n\nstruct Info{\n\tInfo(int arg_area_id,int arg_sum_dist){\n\t\tarea_id = arg_area_id;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn sum_dist > arg.sum_dist; //総距離の降順(PQ)\n\t}\n\n\tint area_id,sum_dist;\n};\n\ntypedef Point Vector;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\tPoint p[2];\n};\n\n\nint num_pillar,num_wall;\nPoint point[SIZE];\nvector<Edge> G[SIZE];\nint min_dist[100*33*49];\n\n\nvector<int> get_area(int first_from,int first_to){\n\n\tvector<int> ret;\n\n\tint from = first_from;\n\tint to = first_to;\n\n\tdo{\n\n\t\tret.push_back(from);\n\t\tint next = to;\n\n\t\tfor(int k = 0; k < G[next].size(); k++){\n\t\t\tif(G[next][k].to == from){\n\t\t\t\tif(k != 0){\n\n\t\t\t\t\tto = G[next][k-1].to;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tto = G[next][G[to].size()-1].to;\n\t\t\t\t}\n\n\t\t\t\t//break;\n\t\t\t}\n\t\t}\n\t\tfrom = next;\n\n\t}while(from != first_from || to != first_to);\n\n\treturn ret;\n}\n\n\nvector<int> pol_sort(vector<int> polygon){\n\n\tint min_index = BIG_NUM,loc;\n\n\tfor(int i = 0; i < polygon.size(); i++){\n\n\t\tif(min_index > polygon[i]){\n\t\t\tmin_index = polygon[i];\n\t\t\tloc = i;\n\t\t}\n\t}\n\n\t//min_indexが先頭になるようにする\n\tfor(int i = 0; i < loc; i++){\n\n\t\tpolygon.push_back(polygon[0]);\n\t\tpolygon.erase(polygon.begin());\n\t}\n\n\treturn polygon;\n}\n\ndouble get_theta(Vector A){\n\n\tdouble ret = atan2(A.y,A.x);\n\n\tif(ret < 0){\n\n\t\tret += 2*M_PI;\n\t}\n\treturn ret;\n}\n\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tG[i].clear();\n\t}\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tscanf(\"%lf %lf\",&point[i].x,&point[i].y);\n\t}\n\n\tint from,to;\n\n\tfor(int i = 0; i < num_wall; i++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\n\t\tfrom--;\n\t\tto--;\n\n\t\tG[from].push_back(Edge(to,get_theta(point[from]-point[to])));\n\t\tG[to].push_back(Edge(from,get_theta(point[to]-point[from])));\n\t}\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tsort(G[i].begin(),G[i].end());\n\t}\n\n\tvector<vector<int>> first_POLYGON;\n\n\tfor(int i = 0; i < num_pillar; i++){\n\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tvector<int> polygon = pol_sort(get_area(i,G[i][k].to));\n\n\t\t\tfirst_POLYGON.push_back(polygon);\n\t\t}\n\t}\n\n\tsort(first_POLYGON.begin(),first_POLYGON.end());\n\tfirst_POLYGON.erase(unique(first_POLYGON.begin(),first_POLYGON.end()),first_POLYGON.end());\n\n\tvector<vector<int>> POLYGON;\n\tvector<int> A,B;\n\n\tfor(int i = 0; i < first_POLYGON.size(); i++){\n\n\t\tbool FLG = true;\n\t\tA = first_POLYGON[i];\n\t\tsort(A.begin(),A.end());\n\n\t\tfor(int k = 0; k < i; k++){\n\t\t\tB = first_POLYGON[k];\n\t\t\tsort(B.begin(),B.end());\n\n\t\t\tif(A == B){\n\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t}\n\t\tif(FLG){\n\t\t\tPOLYGON.push_back(first_POLYGON[i]);\n\t\t}\n\t}\n\n\tif(POLYGON.size() == 1){\n\n\t\tprintf(\"1\\n\");\n\t\treturn;\n\t}\n\n\tvector<int> dist_1;\n\n\tfor(int i = 0; i < POLYGON.size(); i++){\n\n\t\tdouble tmp = 0;\n\n\t\tfor(int k = 0; k < POLYGON[i].size(); k++){\n\n\t\t\ttmp += cross(point[POLYGON[i][k]],point[POLYGON[i][(k+1)%POLYGON[i].size()]]);\n\t\t}\n\t\tif(tmp < EPS){\n\t\t\tdist_1.push_back(i);\n\t\t}\n\t}\n\n\tint num_area = POLYGON.size();\n\tvector<int> final_G[num_area];\n\n\n\tfor(int i = 0; i < num_area-1; i++){ //領域\n\n\t\tfor(int a = 0; a < POLYGON[i].size(); a++){ //辺の走査\n\n\t\t\tLine tmp_line = Line(point[POLYGON[i][a]],point[POLYGON[i][(a+1)%POLYGON[i].size()]]);\n\n\t\t\tbool FLG = false;\n\n\t\t\tfor(int k = i+1; k < num_area; k++){ //隣接領域\n\t\t\t\tif(k == i)continue;\n\n\t\t\t\tfor(int b = 0; b < POLYGON[k].size(); b++){ //隣接領域の辺\n\t\t\t\t\tLine tmp_line2 = Line(point[POLYGON[k][b]],point[POLYGON[k][(b+1)%POLYGON[k].size()]]);\n\n\t\t\t\t\tif((tmp_line.p[0] == tmp_line2.p[0] && tmp_line.p[1] == tmp_line2.p[1]) ||\n\t\t\t\t\t\t\t(tmp_line.p[0] == tmp_line2.p[1] && tmp_line.p[1] == tmp_line2.p[0])){\n\n\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\tfinal_G[i].push_back(k);\n\t\t\t\t\t\tfinal_G[k].push_back(i);\n\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(FLG)break;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_area; i++){\n\n\t\tmin_dist[i] = BIG_NUM;\n\t}\n\n\tpriority_queue<Info> Q;\n\n\tfor(int i = 0; i < dist_1.size(); i++){\n\n\t\tmin_dist[dist_1[i]] = 1;\n\t\tQ.push(Info(dist_1[i],1));\n\t}\n\n\twhile(!Q.empty()){\n\n\t\tif(Q.top().sum_dist > min_dist[Q.top().area_id]){\n\n\t\t\tQ.pop();\n\n\t\t}else{\n\n\t\t\tfor(int i = 0; i < final_G[Q.top().area_id].size(); i++){\n\n\t\t\t\tint next_area = final_G[Q.top().area_id][i];\n\t\t\t\tint next_dist = Q.top().sum_dist+1;\n\n\t\t\t\tif(min_dist[next_area] > next_dist){\n\t\t\t\t\tmin_dist[next_area] = next_dist;\n\t\t\t\t\tQ.push(Info(next_area,next_dist));\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tfor(int i = 0; i < num_area; i++){\n\n\t\tans = max(ans,min_dist[i]);\n\t}\n\n\tprintf(\"%d\\n\",ans-1);\n}\n\nint main(){\n\n\twhile(true){\n\n\t\tscanf(\"%d %d\",&num_pillar,&num_wall);\n\t\tif(num_pillar == 0 && num_wall == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3592, "score_of_the_acc": -0.0698, "final_rank": 6 }, { "submission_id": "aoj_0273_3677866", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<map>\n#include<math.h>\n#include<complex>\n#include<queue>\n\nusing namespace std;\n#define rep(i,n) for(int i = 0 ; i < n ; ++i)\nusing ll = long long;\nusing ld = long double;\nusing Point = complex<ld>;\nconst ld eps = 1e-9;\n\nld cross(Point a,Point b){\n return imag(conj(a)*b);\n}\n\n\nvoid solve(int n,int m){\n vector<Point> p(n);\n rep(i,n){\n int x,y;\n cin>>x>>y;\n p[i]=Point(x,y);\n }\n vector<vector<int>> v(m);\n rep(i,m){\n int x,y;\n cin>>x>>y;\n --x;--y;\n v[x].push_back(y);\n v[y].push_back(x);\n }\n vector<vector<int>> used(n);\n rep(i,n){\n sort(v[i].begin(),v[i].end(),[&](int x,int y){\n return arg(p[x]-p[i])<arg(p[y]-p[i]);\n });\n used[i].resize(v[i].size());\n }\n vector<vector<int>> pols;\n rep(i,n){\n int s = v[i].size();\n rep(j,s){\n if(used[i][j])continue;\n vector<int> pol;\n pol.push_back(i);\n int cur = i;\n int nxt = v[i][j];\n used[i][j]=true;\n while(nxt!=i){\n pol.push_back(nxt);\n int idx = 0;\n while(v[nxt][idx]!=cur)++idx;\n idx = (idx+1)%v[nxt].size();\n used[nxt][idx]=true;\n cur = nxt;\n nxt = v[cur][idx];\n }\n ld sum = 0;\n rep(k,pol.size()){\n sum += cross(p[pol[k]],p[pol[(k+1)%pol.size()]]);\n }\n if(sum<0)pols.push_back(pol);\n }\n }\n int sz = pols.size();\n vector<vector<int>> vs(sz+1);\n rep(i,sz){\n int s = pols[i].size();\n rep(j,s){\n Point ext = (ld).5*(p[pols[i][(j+1)%s]]+p[pols[i][j]])\n + Point(0,1)*eps*(p[pols[i][(j+1)%s]]-p[pols[i][j]]);\n int nxt = sz;\n rep(k,sz){\n ld sum = 0;\n rep(t,pols[k].size()){\n sum += arg((p[pols[k][(t+1)%pols[k].size()]]-ext)/(p[pols[k][t]]-ext));\n }\n if(abs(sum)>3){\n nxt=k;\n break;\n }\n }\n vs[nxt].push_back(i);\n vs[i].push_back(nxt);\n }\n }\n vector<int> dist(sz+1,10000);\n dist[sz]=0;\n queue<int> q;\n q.push(sz);\n int ans = 0;\n while(q.size()){\n int cur = q.front();q.pop();\n ans = max(ans,dist[cur]);\n for(auto to : vs[cur]){\n if(dist[to]>dist[cur]+1){\n dist[to]=dist[cur]+1;\n q.push(to);\n }\n }\n }\n cout<<ans<<endl;\n}\n\n\n\nint main(){\n int n,m;\n while(cin>>n>>m,n!=0)solve(n,m);\n \n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3236, "score_of_the_acc": -1, "final_rank": 14 }, { "submission_id": "aoj_0273_2668577", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;\nconst double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\n#define curr(P, i) P[i]\n#define next(P, i) P[(i+1)%P.size()]\ndouble area2(const G& g) {\n\tdouble A = 0;\n\tfor (int i = 0; i < g.size(); ++i) \n\t\tA += cross(curr(g, i), next(g, i));\n\treturn A;\n}\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint c, w;\n\twhile(cin >> c >> w, c){\n\t\tG vs;\n\t\tvector<vi> v_to_es(c);\n\t\trep(i, c){ int x, y; cin >> x >> y; vs.emplace_back(x, y); }\n\t\trep(i, w){\n\t\t\tint s, t; cin >> s >> t; s--; t--;\n\t\t\tv_to_es[s].pb(t);\n\t\t\tv_to_es[t].pb(s);\n\t\t}\n\t\trep(i, c){\n\t\t\tsort(all(v_to_es[i]), [&](int a, int b){\n\t\t\t\treturn arg(vs[a] - vs[i]) < arg(vs[b] - vs[i]);\n\t\t\t});\n\t\t}\n\t\t\n\t\tint outer = -1;\n\t\tvector<vi> sur;\n\t\tset<pi> vis;\n\t\tmap<pi,int> e_to_sur;\n\t\t\n\t\tfunction<void(int,int,vi&)> rec = [&](int prev, int cur, vi &v){\n\t\t\tvis.emplace(prev, cur);\n\t\t\tv.pb(prev);\n\t\t\tint k = 0;\n\t\t\tfor(; v_to_es[cur][k] != prev; k++);\n\t\t\tk = (k - 1 + v_to_es[cur].size()) % v_to_es[cur].size();\n\t\t\tint next = v_to_es[cur][k];\n\t\t\tif(!vis.count(pi(cur, next))) rec(cur, next, v);\n\t\t};\n\t\trep(i, c) for(int j : v_to_es[i]) if(!vis.count(pi(i, j))){\n\t\t\tvi v;\n\t\t\trec(i, j, v);\n\t\t\tint id = sur.size();\n\t\t\tG g;\n\t\t\trep(k, v.size()){\n\t\t\t\te_to_sur[pi(v[k], v[(k+1) % v.size()])] = id;\n\t\t\t\tg.pb(vs[v[k]]);\n\t\t\t}\n\t\t\tif(area2(g) < 0) outer = id;\n\t\t\tsur.pb(v);\n\t\t\t//dbg(v, area2(g));\n\t\t}\n\t\t\n\t\t//dbg(outer);\n\t\tint n = sur.size();\n\t\tvector<vi> dist(n, vi(n, 10000));\n\t\trep(i, n) dist[i][i] = 0;\n\t\trep(i, n) rep(j, sur[i].size()){\n\t\t\tint k = e_to_sur[pi(sur[i][(j + 1) % sur[i].size()], sur[i][j])];\n\t\t\tdist[i][k] = dist[k][i] = 1;\n\t\t}\n\t\trep(k, n) rep(i, n) rep(j, n) dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n\t\tcout << *max_element(all(dist[outer])) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3480, "score_of_the_acc": -0.232, "final_rank": 12 }, { "submission_id": "aoj_0273_2643923", "code_snippet": "#include <iostream>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <map>\n#include <set>\n#include <cstdlib>\nusing namespace std;\n\nconst double EPS = 1e-10;\nconst double INF = 1e12;\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : VP{\n L(const P& a, const P& b){ resize(2); at(0)=a; at(1)=b; }\n L(){ resize(2); }\n};\n\nnamespace std{\n bool operator < (const P &a, const P &b){\n return !EQ(a.X, b.X)? a.X<b.X : a.Y<b.Y;\n }\n bool operator == (const P &a, const P &b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) <-EPS) return -1; //cw\n if(dot(b,c) < EPS) return +2; //c-a-b\n if(norm(b) < norm(c)) return -2; //a-b-c\n return 0; //a-c-b\n}\n\nP projection(const L& l, const P& p) {\n double t = dot(p-l[0], l[0]-l[1]) / norm(l[0]-l[1]);\n return l[0] + t*(l[0]-l[1]);\n}\n\nP crosspointLL(const L &l, const L &m) {\n double A = cross(l[1]-l[0], m[1]-m[0]);\n double B = cross(l[1]-l[0], l[1]-m[0]);\n return m[0] + B /A *(m[1]-m[0]);\n}\n\ndouble getangle(const P &p, const P &a, const P &b){ //clockwise\n P proj = projection(L(p,a), b);\n int minus = (dot(a-p, b-p)>=0)? 1 :-1;\n if(ccw(p,a,b)!=1){\n return atan2(abs(b-proj), minus*abs(p-proj));\n }else{\n return 2*M_PI - atan2(abs(b-proj), minus*abs(p-proj));\n }\n}\ndouble getarea(const VP &p) {\n\tdouble ret = 0;\n\tfor (int i=0; i<(int)p.size(); i++){ \n\t\tret += cross(p[i], p[(i+1)%p.size()]);\n\t}\n\treturn ret*0.5;\n}\n\nint leftmostpoint(int &pidx, int &cidx, vector<int> &vec, VP &plist){\n\tP prev = plist[pidx];\n\tP curr = plist[cidx];\n\tint nextidx = -1;\n\tdouble minangle = INF;\n\tfor(int i=0; i<(int)vec.size(); i++){\n\t\tif(vec[i]==pidx) continue;\n\t\tdouble angle = getangle(curr, prev, plist[vec[i]]);\n\t\tif(angle < minangle){\n\t\t\tminangle = angle;\n\t\t\tnextidx = i;\n\t\t}\n\t}\n\tpidx = cidx;\n\tcidx = vec[nextidx];\n\treturn nextidx;\n}\n\nvector<vector<int> > makeDualGraph(vector<vector<int> > &adj, VP &plist, int &out){\n map<pair<int,int>, int> edgelist;\n vector<vector<int> > poly;\n vector<vector<bool> > used(adj.size());\n for(int i=0; i<(int)adj.size(); i++){\n used[i] = vector<bool>(adj[i].size(), false);\n }\n \n int numarea=0;\n for(int i=0; i<(int)adj.size(); i++){\n \tfor(int j=0; j<(int)adj[i].size(); j++){\n \t\tif(used[i][j]) continue;\n \t\tused[i][j] = true;\n \t\tnumarea++;\n \t\tvector<int> border;\n \t\tVP vlist;\n \t\tborder.push_back(i);\n \t\tvlist.push_back(plist[i]);\n \t\tint prev = i;\n \t\tint curr = adj[i][j];\n \t\twhile(curr!=i){\n \t\t\tborder.push_back(curr);\n \t\t\tvlist.push_back(plist[curr]);\n \t\t\tint idx = leftmostpoint(prev, curr, adj[curr], plist);\n \t\t\tused[prev][idx] = true;\n \t\t}\n \t\tpoly.push_back(border);\n \t\tif(getarea(vlist) < 0) out = numarea-1;\n \t}\n }\n \n vector<vector<int> > dual(numarea);\n for(int i=0; i<numarea; i++){\n \tfor(int j=0; j<(int)poly[i].size(); j++){\n \t\tint a = poly[i][j];\n \t\tint b = poly[i][(j+1)%(int)poly[i].size()];\n \t\tpair<int,int> key = make_pair(min(a,b), max(a,b));\n \t\tif(edgelist.count(key) == 0){\n \t\t\tedgelist[key] = i;\n \t\t}else{\n \t\t\tdual[i].push_back(edgelist[key]);\n \t\t\tdual[edgelist[key]].push_back(i);\n \t\t}\n \t}\n }\n \n for(int i=0; i<(int)dual.size(); i++){\n sort(dual[i].begin(), dual[i].end());\n dual[i].erase(unique(dual[i].begin(), dual[i].end()), dual[i].end());\n }\n return dual;\n}\n\nint main(){\n\twhile(1){\n\t\tint c,w;\n\t\tcin >> c >> w;\n\t\tif(c==0) break;\n\t\t\n\t\tVP bar(c);\n\t\tfor(int i=0; i<c; i++){\n\t\t\tint x,y;\n\t\t\tcin >> x >> y;\n\t\t\tbar[i] = P(x,y);\n\t\t}\n\t\t\n\t\tvector<vector<int> > adj(c);\n\t\tfor(int i=0; i<w; i++){\n\t\t\tint s,t;\n\t\t\tcin >> s >> t;\n\t\t\ts--; t--;\n\t\t\tadj[s].push_back(t);\n\t\t\tadj[t].push_back(s);\n\t\t}\n\t\tint out;\n\t\tvector<vector<int> > dual = makeDualGraph(adj, bar, out);\n\t\t\n\t\tint numarea = dual.size();\n\t\tset<int> reach;\n\t\treach.insert(out);\n\t\tint ans = 0;\n\t\twhile(1){\n\t\t\tif((int)reach.size() == numarea) break;\n\t\t\tset<int> newreach;\n\t\t\tfor(set<int>::iterator itr=reach.begin(); itr!=reach.end(); itr++){\n\t\t\t\tnewreach.insert(*itr);\n\t\t\t\tfor(int i=0; i<(int)dual[*itr].size(); i++){\n\t\t\t\t\tnewreach.insert(dual[*itr][i]);\n\t\t\t\t}\n\t\t\t}\n\t\t\treach = newreach;\n\t\t\tans++;\n\t\t}\n\t\tcout << ans << endl;\n\t}\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": -0.0047, "final_rank": 1 }, { "submission_id": "aoj_0273_2564174", "code_snippet": "#include <bits/stdc++.h>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(),(x).end()\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef complex<ld> Point;\nconst ld INF = 1e10;\nconst ld eps = 1e-9, pi = acos(-1.0);\n\nnamespace std {\n bool operator<(const Point &lhs, const Point &rhs) {\n if (lhs.real() < rhs.real() - eps) return true;\n if (lhs.real() > rhs.real() + eps) return false;\n return lhs.imag() < rhs.imag();\n }\n}\n\nPoint input_point() {\n ld x, y;\n cin >> x >> y;\n return Point(x, y);\n}\n\nbool eq(ld a, ld b) {\n return (abs(a - b) < eps);\n}\n\nld dot(Point a, Point b) {\n return real(conj(a) * b);\n}\n\nld cross(Point a, Point b) {\n return imag(conj(a) * b);\n}\n\nclass Line {\npublic:\n Point a, b;\n Line () : a(Point(0, 0)), b(Point(0, 0)) {}\n Line (Point a, Point b) : a(a), b(b) {}\n};\n\nclass Circle {\npublic:\n Point p;\n ld r;\n Circle () : p(Point(0, 0)), r(0) {}\n Circle (Point p, ld r) : p(p), r(r) {}\n};\n\nint ccw (Point a, Point b, Point c) {\n b -= a; c -= a;\n if (cross(b, c) > eps) return 1;\n if (cross(b, c) < -eps) return -1;\n if (dot(b, c) < 0) return 2;\n if (norm(b) < norm(c)) return -2;\n return 0;\n}\n\nbool isis_ll (Line l, Line m) {\n return !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\nbool isis_ls (Line l, Line s) {\n return isis_ll(l, s) &&\n (cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\nbool isis_ss(Line s, Line t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool isis_lp (Line l, Point p) {\n return (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\nbool isis_sp (Line s, Point p) {\n return (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\nPoint proj (Line l, Point p) {\n ld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + t * (l.a - l.b);\n}\n\nPoint is_ll (Line s, Line t) {\n Point sv = s.b - s.a, tv = t.b - t.a;\n assert(cross(sv, tv) != 0);\n return s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\nld dist_lp (Line l, Point p) {\n return abs(p - proj(l, p));\n}\n\nld dist_ll (Line l, Line m) {\n return isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\nld dist_ls (Line l, Line s) {\n return isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\nld dist_sp (Line s, Point p) {\n Point r = proj(s, p);\n return isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\nld dist_ss (Line s, Line t) {\n if (isis_ss(s, t)) return 0;\n return min({dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b)});\n}\n\nvector<Point> is_cc (Circle c1, Circle c2){\n vector<Point> res;\n ld d = abs(c1.p - c2.p);\n ld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n ld dfr = c1.r * c1.r - rc * rc;\n if (abs(dfr) < eps) dfr = 0.0;\n else if (dfr < 0.0) return res;\n ld rs = sqrt(dfr);\n Point diff = (c2.p - c1.p) / d;\n res.push_back(c1.p + diff * Point(rc, rs));\n if (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n return res;\n}\n\nvector<Point> is_lc (Circle c, Line l){\n vector<Point> res;\n ld d = dist_lp(l, c.p);\n if (d < c.r + eps){\n ld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d);\n Point nor = (l.a - l.b) / abs(l.a - l.b);\n res.push_back(proj(l, c.p) + len * nor);\n res.push_back(proj(l, c.p) - len * nor);\n }\n return res;\n}\n\nvector<Point> is_sc(Circle c, Line l){\n vector<Point> v = is_lc(c, l), res;\n for (Point p : v)\n if (isis_sp(l, p)) res.push_back(p);\n return res;\n}\n\nvector<Line> tangent_cp(Circle c, Point p) {\n vector<Line> ret;\n Point v = c.p - p;\n ld d = abs(v);\n ld l = sqrt(norm(v) - c.r * c.r);\n if (isnan(l)) { return ret; }\n Point v1 = v * Point(l / d, c.r / d);\n Point v2 = v * Point(l / d, -c.r / d);\n ret.push_back(Line(p, p + v1));\n if (l < eps) return ret;\n ret.push_back(Line(p, p + v2));\n return ret;\n}\n\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n vector<Line> ret;\n if (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n Point center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n ret = tangent_cp(c1, center);\n }\n if (abs(c1.r - c2.r) > eps) {\n Point out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n vector<Line> nret = tangent_cp(c1, out);\n ret.insert(ret.end(), ALL(nret));\n }\n else {\n Point v = c2.p - c1.p;\n v /= abs(v);\n Point q1 = c1.p + v * Point(0, 1) * c1.r;\n Point q2 = c1.p + v * Point(0, -1) * c1.r;\n ret.push_back(Line(q1, q1 + v));\n ret.push_back(Line(q2, q2 + v));\n }\n return ret;\n}\n\ntypedef vector<Point> Polygon;\n\nld area(const Polygon &p) {\n ld res = 0;\n int n = p.size();\n REP(j,n) res += cross(p[j], p[(j+1)%n]);\n return res / 2;\n}\n\nbool is_counter_clockwise (const Polygon &poly) {\n ld angle = 0;\n int n = poly.size();\n REP(i,n) {\n Point a = poly[i], b = poly[(i+1)%n], c = poly[(i+2)%n];\n angle += arg((c - b) / (b - a));\n }\n return angle > eps;\n}\n\nint is_in_polygon (const Polygon &poly, Point p) {\n ld angle = 0;\n int n = poly.size();\n REP(i,n) {\n Point a = poly[i], b = poly[(i+1)%n];\n if (isis_sp(Line(a, b), p)) return 1;\n angle += arg((b - p) / (a - p));\n }\n return eq(angle, 0) ? 0 : 2;\n}\n\nPolygon convex_hull(vector<Point> ps) {\n int n = ps.size();\n int k = 0;\n sort(ps.begin(), ps.end());\n Polygon ch(2 * n);\n for (int i = 0; i < n; ch[k++] = ps[i++])\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n while (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n ch.resize(k - 1);\n return ch;\n}\n\nPolygon convex_cut(const Polygon &ps, Line l) {\n int n = ps.size();\n Polygon Q;\n REP(i,n) {\n Point A = ps[i], B = ps[(i+1)%n];\n Line m = Line(A, B);\n if (ccw(l.a, l.b, A) != -1) Q.push_back(A);\n if (ccw(l.a, l.b, A) * ccw(l.a, l.b, B) < 0 && isis_ll(l, m))\n Q.push_back(is_ll(l, m));\n }\n return Q;\n}\n\nvoid add_point(vector<Point> &ps, Point p) {\n for (Point q : ps) if (abs(q - p) < eps) return;\n ps.push_back(p);\n}\n\ntypedef ll Weight;\n\nstruct Edge { int from, to; Weight weight;\n Edge(int from, int to, Weight weight) :\n from(from), to(to), weight(weight) { }\n};\nbool operator < (const Edge &e, const Edge &f) {\n return e.weight != f.weight ? e.weight > f.weight : // !!INVERSE!!\n e.from != f.from ? e.from < f.from : e.to < f.to;\n}\n\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nvoid add_edge(Graph &g, int from, int to, Weight weight) {\n g[from].push_back((Edge){from, to, weight});\n}\n\nGraph segment_arrangement(const vector<Line> &s, const vector<Point> &p) {\n int n = p.size(), m = s.size();\n Graph g(n);\n REP(i,m) {\n vector<pair<ld,int>> vec;\n REP(j,n) if (isis_sp(s[i], p[j]))\n vec.emplace_back(abs(s[i].a - p[j]), j);\n sort(ALL(vec));\n REP(j,vec.size()-1) {\n int from = vec[j].second, to = vec[j+1].second;\n add_edge(g, from, to, abs(p[from] - p[to]));\n }\n }\n return g;\n}\n\nGraph circle_arrangement(const vector<Circle> &c, const vector<Point> &p) {\n int n = p.size(), m = c.size();\n Graph g(n);\n REP(i,m) {\n vector<pair<ld,int>> vec;\n REP(j,n) if (abs(abs(c[i].p - p[j]) - c[i].r) < eps)\n vec.emplace_back(arg(c[i].p - p[j]), j);\n sort(ALL(vec));\n REP(j,vec.size()-1) {\n int from = vec[j].second, to = vec[j+1].second;\n ld angle = vec[j+1].first - vec[j].first;\n add_edge(g, from, to, angle * c[i].r);\n }\n if (vec.size() >= 2) {\n int from = vec.back().second, to = vec.front().first;\n ld angle = vec.front().first - vec.back().first;\n add_edge(g, from, to, angle * c[i].r);\n }\n }\n return g;\n}\n\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n\nGraph dual_graph(const vector<Line> &s, const vector<Point> &p) {\n int N = p.size();\n polygon.clear();\n REP(i,1024) REP(j,1024) seg2p[i][j].clear();\n vector<vector<tuple<ld,int,bool>>> tup(N);\n REP(i,s.size()) {\n int a = -1, b = -1;\n REP(j,N) if (abs(s[i].a - p[j]) < eps) a = j;\n REP(j,N) if (abs(s[i].b - p[j]) < eps) b = j;\n assert(a >= 0 && b >= 0);\n tup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n tup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n }\n REP(i,N) sort(ALL(tup[i]));\n REP(i,N) {\n REP(j,tup[i].size()) {\n ld angle; int pos = j, from = i, to; bool flag;\n tie(angle, to, flag) = tup[i][j];\n if (flag) continue;\n vector<int> ps;\n while (!flag) {\n ps.push_back(from);\n get<2>(tup[from][pos]) = true;\n seg2p[from][to].push_back(polygon.size());\n seg2p[to][from].push_back(polygon.size());\n angle += pi + eps;\n if (angle > pi) angle -= 2 * pi;\n auto it = lower_bound(ALL(tup[to]), make_tuple(angle, 0, false));\n if (it == tup[to].end()) it = tup[to].begin();\n from = to; tie(angle, to, flag) = *it;\n pos = it - tup[from].begin();\n }\n polygon.push_back(ps);\n }\n }\n for(int i=0;i<polygon.size();i++){\n Polygon ps;\n for(int j=0; j<polygon[i].size(); j++)\n ps.push_back(p[polygon[i][j]]);\n bool soto = true;\n for(int i=0;i<p.size();i++){\n if(is_in_polygon(ps, p[i]) == 0)\n\tsoto=false;\n }\n if(soto){\n vector<int> hoge = polygon[0];\n vector<int> huga = polygon[i];\n polygon[0] = huga;\n polygon[i] = hoge;\n //cout << \"kore\" << i << endl;\n break;\n }\n }\n /*cout << endl;\n for(int i=0;i<polygon.size();i++){\n for(int j=0;j<polygon[i].size();j++)\n cout << polygon[i][j] << \" \";\n cout << endl;\n }*/\n \n Graph g(polygon.size());\n REP(i,N) REP(j,i) {\n if (seg2p[i][j].size() == 2) {\n int from = seg2p[i][j][0], to = seg2p[i][j][1];\n g[from].push_back(Edge(from, to, 1));\n g[to].push_back(Edge(to, from, 1));\n }\n }\n return g;\n}\n\nconst ld zoom = 25;\nconst ld centerX = 6;\nconst ld centerY = 5;\n\nvoid change_color(int r, int g, int b) {\n fprintf(stderr, \"c.strokeStyle = 'rgb(%d, %d, %d)';\\n\", r, g, b);\n}\n\nint cordx(Point p) { return 400 + zoom * (p.real() - centerX); }\nint cordy(Point p) { return 400 - zoom * (p.imag() - centerY); }\n\n#define cord(p) cordx(p),cordy(p)\n\nvoid draw_point(Point p) {\n fprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(p), 2);\n}\n\nvoid draw_segment(Line l) {\n fprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(l.a), cord(l.b));\n}\n\nvoid draw_line(Line l) {\n Point v = l.b - l.a;\n Line m(l.a - v * Point(1e4, 0), l.b + v * Point(1e4, 0));\n fprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(m.a), cord(m.b));\n}\n\nvoid draw_polygon(const Polygon &p) {\n int n = p.size();\n REP(i,n) draw_segment(Line(p[i], p[(i+1)%n]));\n}\n\nvoid draw_circle(Circle c) {\n fprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(c.p), (int)(zoom * c.r));\n}\n\nvoid shortestPath(const Graph &g, int s,\n\t\t vector<Weight> &dist, vector<int> &prev) {\n int n = g.size();\n dist.assign(n, INF); dist[s] = 0;\n prev.assign(n, -1);\n priority_queue<Edge> Q; // \"e < f\" <=> \"e.weight > f.weight\"\n for (Q.push(Edge(-2, s, 0)); !Q.empty(); ) {\n Edge e = Q.top(); Q.pop();\n if (prev[e.to] != -1) continue;\n prev[e.to] = e.from;\n for(auto f=g[e.to].begin();f!=g[e.to].end();f++) {\n if (dist[f->to] > e.weight+f->weight) {\n dist[f->to] = e.weight+f->weight;\n Q.push(Edge(f->from, f->to, e.weight+f->weight));\n }\n }\n }\n}\n\nint main(){\n ll C, W;\n while(cin >> C >> W, C!=0 || W!=0){\n vector<Point> v;\n for(int i=0;i<C;i++)\n v.push_back(input_point());\n vector<Line> e;\n for(int i=0;i<W;i++){\n ll s,t;\n cin >> s >> t;\n s--; t--;\n e.push_back(Line(v[s], v[t]));\n }\n Graph g = dual_graph(e, v);\n vector<Weight> dist;\n vector<int> prev;\n shortestPath(g, 0, dist, prev);\n ll ans = 0;\n for(int i=0;i<dist.size();i++)\n ans = max(ans, dist[i]);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 0.125, "time_ms": 20, "memory_kb": 27900, "score_of_the_acc": -1.0451, "final_rank": 19 }, { "submission_id": "aoj_0273_2564150", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,n) for(ll i=0;i<ll(n);++i)\n#define RREP(i,n) for(ll i=ll(n)-1;i>=0;--i)\n#define FOR(i,m,n) for(ll i=m;i<ll(n);++i)\n#define RFOR(i,m,n) for(ll i=ll(n)-1;i>=ll(m);--i)\n#define ALL(v) (v).begin(),(v).end()\n#define UNIQUE(v) v.erase(unique(ALL(v)),v.end());\n#define DUMP(v) REP(aa, (v).size()) { cout << v[aa]; if (aa != v.size() - 1)cout << \" \"; else cout << endl; }\n#define INF 1000000001ll\n#define MOD 1000000007ll\n#define EPS 1e-9\n\nconst int dx[8] = { 1,1,0,-1,-1,-1,0,1 };\nconst int dy[8] = { 0,1,1,1,0,-1,-1,-1 };\n\n\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<vi> vvi;\ntypedef vector<vl> vvl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll max(ll a, int b) { return max(a, ll(b)); }\nll max(int a, ll b) { return max(ll(a), b); }\nll min(ll a, int b) { return min(a, ll(b)); }\nll min(int a, ll b) { return min(ll(a), b); }\n///(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)(´・ω・`)///\n\n\nusing namespace std;\n\ntypedef long double ld;\ntypedef complex<ld> Point;\n\nconst ld eps = 1e-9, pi = acos(-1.0);\n\nnamespace std {\n\tbool operator<(const Point &lhs, const Point &rhs) {\n\t\tif (lhs.real() < rhs.real() - eps) return true;\n\t\tif (lhs.real() > rhs.real() + eps) return false;\n\t\treturn lhs.imag() < rhs.imag();\n\t}\n}\n\nPoint input_point() {\n\tld x, y;\n\tcin >> x >> y;\n\treturn Point(x, y);\n}\n\nbool eq(ld a, ld b) {\n\treturn (abs(a - b) < eps);\n}\n\nld dot(Point a, Point b) {\n\treturn real(conj(a) * b);\n}\n\nld cross(Point a, Point b) {\n\treturn imag(conj(a) * b);\n}\n\nclass Line {\npublic:\n\tPoint a, b;\n\tLine() : a(Point(0, 0)), b(Point(0, 0)) {}\n\tLine(Point a, Point b) : a(a), b(b) {}\n};\n\nclass Circle {\npublic:\n\tPoint p;\n\tld r;\n\tCircle() : p(Point(0, 0)), r(0) {}\n\tCircle(Point p, ld r) : p(p), r(r) {}\n};\n\nint ccw(Point a, Point b, Point c) {\n\tb -= a; c -= a;\n\tif (cross(b, c) > eps) return 1;\n\tif (cross(b, c) < -eps) return -1;\n\tif (dot(b, c) < 0) return 2;\n\tif (norm(b) < norm(c)) return -2;\n\treturn 0;\n}\n\nbool isis_ll(Line l, Line m) {\n\treturn !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\nbool isis_ls(Line l, Line s) {\n\treturn isis_ll(l, s) &&\n\t\t(cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\nbool isis_ss(Line s, Line t) {\n\treturn ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n\t\tccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool isis_lp(Line l, Point p) {\n\treturn (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\nbool isis_sp(Line s, Point p) {\n\treturn (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\nPoint proj(Line l, Point p) {\n\tld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n\treturn l.a + t * (l.a - l.b);\n}\n\nPoint is_ll(Line s, Line t) {\n\tPoint sv = s.b - s.a, tv = t.b - t.a;\n\tassert(cross(sv, tv) != 0);\n\treturn s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\nld dist_lp(Line l, Point p) {\n\treturn abs(p - proj(l, p));\n}\n\nld dist_ll(Line l, Line m) {\n\treturn isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\nld dist_ls(Line l, Line s) {\n\treturn isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\nld dist_sp(Line s, Point p) {\n\tPoint r = proj(s, p);\n\treturn isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\nld dist_ss(Line s, Line t) {\n\tif (isis_ss(s, t)) return 0;\n\treturn min({ dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b) });\n}\n\nvector<Point> is_cc(Circle c1, Circle c2) {\n\tvector<Point> res;\n\tld d = abs(c1.p - c2.p);\n\tld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n\tld dfr = c1.r * c1.r - rc * rc;\n\tif (abs(dfr) < eps) dfr = 0.0;\n\telse if (dfr < 0.0) return res;\n\tld rs = sqrt(dfr);\n\tPoint diff = (c2.p - c1.p) / d;\n\tres.push_back(c1.p + diff * Point(rc, rs));\n\tif (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n\treturn res;\n}\n\nvector<Point> is_lc(Circle c, Line l) {\n\tvector<Point> res;\n\tld d = dist_lp(l, c.p);\n\tif (d < c.r + eps) {\n\t\tld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d);\n\t\tPoint nor = (l.a - l.b) / abs(l.a - l.b);\n\t\tres.push_back(proj(l, c.p) + len * nor);\n\t\tres.push_back(proj(l, c.p) - len * nor);\n\t}\n\treturn res;\n}\n\nvector<Point> is_sc(Circle c, Line l) {\n\tvector<Point> v = is_lc(c, l), res;\n\tfor (Point p : v)\n\t\tif (isis_sp(l, p)) res.push_back(p);\n\treturn res;\n}\n\nvector<Line> tangent_cp(Circle c, Point p) {\n\tvector<Line> ret;\n\tPoint v = c.p - p;\n\tld d = abs(v);\n\tld l = sqrt(norm(v) - c.r * c.r);\n\tif (isnan(l)) { return ret; }\n\tPoint v1 = v * Point(l / d, c.r / d);\n\tPoint v2 = v * Point(l / d, -c.r / d);\n\tret.push_back(Line(p, p + v1));\n\tif (l < eps) return ret;\n\tret.push_back(Line(p, p + v2));\n\treturn ret;\n}\n\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n\tvector<Line> ret;\n\tif (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n\t\tPoint center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n\t\tret = tangent_cp(c1, center);\n\t}\n\tif (abs(c1.r - c2.r) > eps) {\n\t\tPoint out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n\t\tvector<Line> nret = tangent_cp(c1, out);\n\t\tret.insert(ret.end(), ALL(nret));\n\t}\n\telse {\n\t\tPoint v = c2.p - c1.p;\n\t\tv /= abs(v);\n\t\tPoint q1 = c1.p + v * Point(0, 1) * c1.r;\n\t\tPoint q2 = c1.p + v * Point(0, -1) * c1.r;\n\t\tret.push_back(Line(q1, q1 + v));\n\t\tret.push_back(Line(q2, q2 + v));\n\t}\n\treturn ret;\n}\n\ntypedef vector<Point> Polygon;\n\nld area(const Polygon &p) {\n\tld res = 0;\n\tint n = p.size();\n\tREP(j, n) res += cross(p[j], p[(j + 1) % n]);\n\treturn res / 2;\n}\n\nbool is_counter_clockwise(const Polygon &poly) {\n\tld angle = 0;\n\tint n = poly.size();\n\tREP(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n], c = poly[(i + 2) % n];\n\t\tangle += arg((c - b) / (b - a));\n\t}\n\treturn angle > eps;\n}\n\nint is_in_polygon(const Polygon &poly, Point p) {\n\tld angle = 0;\n\tint n = poly.size();\n\tREP(i, n) {\n\t\tPoint a = poly[i], b = poly[(i + 1) % n];\n\t\tif (isis_sp(Line(a, b), p)) return 1;\n\t\tangle += arg((b - p) / (a - p));\n\t}\n\treturn eq(angle, 0) ? 0 : 2;\n}\n\nPolygon convex_hull(vector<Point> ps) {\n\tint n = ps.size();\n\tint k = 0;\n\tsort(ps.begin(), ps.end());\n\tPolygon ch(2 * n);\n\tfor (int i = 0; i < n; ch[k++] = ps[i++])\n\t\twhile (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tfor (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n\t\twhile (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n\tch.resize(k - 1);\n\treturn ch;\n}\n\nPolygon convex_cut(const Polygon &ps, Line l) {\n\tint n = ps.size();\n\tPolygon Q;\n\tREP(i, n) {\n\t\tPoint A = ps[i], B = ps[(i + 1) % n];\n\t\tLine m = Line(A, B);\n\t\tif (ccw(l.a, l.b, A) != -1) Q.push_back(A);\n\t\tif (ccw(l.a, l.b, A) * ccw(l.a, l.b, B) < 0 && isis_ll(l, m))\n\t\t\tQ.push_back(is_ll(l, m));\n\t}\n\treturn Q;\n}\n\nvoid add_point(vector<Point> &ps, Point p) {\n\tfor (Point q : ps) if (abs(q - p) < eps) return;\n\tps.push_back(p);\n}\n\ntypedef int Weight;\n\nstruct Edge { int from, to; Weight weight; };\n\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nvoid add_edge(Graph &g, int from, int to, Weight weight) {\n\tg[from].push_back(Edge { from, to, weight });\n}\n\nGraph segment_arrangement(const vector<Line> &s, const vector<Point> &p) {\n\tint n = p.size(), m = s.size();\n\tGraph g(n);\n\tREP(i, m) {\n\t\tvector<pair<ld, int>> vec;\n\t\tREP(j, n) if (isis_sp(s[i], p[j]))\n\t\t\tvec.emplace_back(abs(s[i].a - p[j]), j);\n\t\tsort(ALL(vec));\n\t\tREP(j, vec.size() - 1) {\n\t\t\tint from = vec[j].second, to = vec[j + 1].second;\n\t\t\tadd_edge(g, from, to, abs(p[from] - p[to]));\n\t\t}\n\t}\n\treturn g;\n}\n\nGraph circle_arrangement(const vector<Circle> &c, const vector<Point> &p) {\n\tint n = p.size(), m = c.size();\n\tGraph g(n);\n\tREP(i, m) {\n\t\tvector<pair<ld, int>> vec;\n\t\tREP(j, n) if (abs(abs(c[i].p - p[j]) - c[i].r) < eps)\n\t\t\tvec.emplace_back(arg(c[i].p - p[j]), j);\n\t\tsort(ALL(vec));\n\t\tREP(j, vec.size() - 1) {\n\t\t\tint from = vec[j].second, to = vec[j + 1].second;\n\t\t\tld angle = vec[j + 1].first - vec[j].first;\n\t\t\tadd_edge(g, from, to, angle * c[i].r);\n\t\t}\n\t\tif (vec.size() >= 2) {\n\t\t\tint from = vec.back().second, to = vec.front().first;\n\t\t\tld angle = vec.front().first - vec.back().first;\n\t\t\tadd_edge(g, from, to, angle * c[i].r);\n\t\t}\n\t}\n\treturn g;\n}\n\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n\nGraph dual_graph(const vector<Line> &s, const vector<Point> &p) {\n\tint N = p.size();\n\tpolygon.clear();\n\tREP(i, 1024) REP(j, 1024) seg2p[i][j].clear();\n\tvector<vector<tuple<ld, int, bool>>> tup(N);\n\tREP(i, s.size()) {\n\t\tint a = -1, b = -1;\n\t\tREP(j, N) if (abs(s[i].a - p[j]) < eps) a = j;\n\t\tREP(j, N) if (abs(s[i].b - p[j]) < eps) b = j;\n\t\tassert(a >= 0 && b >= 0);\n\t\ttup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n\t\ttup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n\t}\n\tREP(i, N) sort(ALL(tup[i]));\n\tREP(i, N) {\n\t\tREP(j, tup[i].size()) {\n\t\t\tld angle; int pos = j, from = i, to; bool flag;\n\t\t\ttie(angle, to, flag) = tup[i][j];\n\t\t\tif (flag) continue;\n\t\t\tvector<int> ps;\n\t\t\twhile (!flag) {\n\t\t\t\tps.push_back(from);\n\t\t\t\tget<2>(tup[from][pos]) = true;\n\t\t\t\tseg2p[from][to].push_back(polygon.size());\n\t\t\t\tseg2p[to][from].push_back(polygon.size());\n\t\t\t\tangle += pi + eps;\n\t\t\t\tif (angle > pi) angle -= 2 * pi;\n\t\t\t\tauto it = lower_bound(ALL(tup[to]), make_tuple(angle, 0, false));\n\t\t\t\tif (it == tup[to].end()) it = tup[to].begin();\n\t\t\t\tfrom = to; tie(angle, to, flag) = *it;\n\t\t\t\tpos = it - tup[from].begin();\n\t\t\t}\n\t\t\tpolygon.push_back(ps);\n\t\t}\n\t}\n\tGraph g(polygon.size());\n\tREP(i, N) REP(j, i) {\n\t\tif (seg2p[i][j].size() == 2) {\n\t\t\tint from = seg2p[i][j][0], to = seg2p[i][j][1];\n\t\t\tg[from].push_back(Edge{ from, to });\n\t\t\tg[to].push_back(Edge{ to, from });\n\t\t}\n\t}\n\treturn g;\n}\n\nconst ld zoom = 25;\nconst ld centerX = 6;\nconst ld centerY = 5;\n\nvoid change_color(int r, int g, int b) {\n\tfprintf(stderr, \"c.strokeStyle = 'rgb(%d, %d, %d)';\\n\", r, g, b);\n}\n\nint cordx(Point p) { return 400 + zoom * (p.real() - centerX); }\nint cordy(Point p) { return 400 - zoom * (p.imag() - centerY); }\n\n#define cord(p) cordx(p),cordy(p)\n\nvoid draw_point(Point p) {\n\tfprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(p), 2);\n}\n\nvoid draw_segment(Line l) {\n\tfprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(l.a), cord(l.b));\n}\n\nvoid draw_line(Line l) {\n\tPoint v = l.b - l.a;\n\tLine m(l.a - v * Point(1e4, 0), l.b + v * Point(1e4, 0));\n\tfprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(m.a), cord(m.b));\n}\n\nvoid draw_polygon(const Polygon &p) {\n\tint n = p.size();\n\tREP(i, n) draw_segment(Line(p[i], p[(i + 1) % n]));\n}\n\nvoid draw_circle(Circle c) {\n\tfprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(c.p), (int)(zoom * c.r));\n}\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint c, w;\n\twhile (cin >> c >> w, c) {\n\t\tvector<Point> p(c);\n\t\tREP(i, c) {\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tp[i]=Point( x,y );\n\t\t}\n\t\tvector<Line> l(w);\n\t\tREP(i, w) {\n\t\t\tint s, t;\n\t\t\tcin >> s >> t;\n\t\t\ts--; t--;\n\t\t\tl[i] =Line( p[s],p[t] );\n\t\t}\n\t\tGraph g = dual_graph(l, p);\n\t\tint n = g.size();\n\t\tvvi d(n, vi(n, INF));\n\t\tREP(i, n) {\n\t\t\tREP(j, g[i].size()) {\n\t\t\t\tint from = g[i][j].from, to = g[i][j].to;\n\t\t\t\td[from][to] = 1;\n\t\t\t\td[to][from] = 1;\n\t\t\t}\n\t\t}\n\t\tREP(i, n)d[i][i] = 0;\n\t\tREP(k, n) {\n\t\t\tREP(i, n) {\n\t\t\t\tREP(j, n) {\n\t\t\t\t\td[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = -INF;\n\t\tREP(i, n) {\n\t\t\tREP(j, n) {\n\t\t\t\tans = max(ans, d[i][j]);\n\t\t\t}\n\t\t}\n\t\tassert(ans != INF);\n\t\tcout << ans << endl;\n\t}\n\t\n}", "accuracy": 0.125, "time_ms": 20, "memory_kb": 27804, "score_of_the_acc": -1.0413, "final_rank": 18 }, { "submission_id": "aoj_0273_2564142", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\n#define each(i,a) for (auto&& i : a)\n#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)\n#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)\n#define REP(i,n) FOR(i,0,n)\n#define RREP(i,n) RFOR(i,0,n)\n#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME\n#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)\n#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)\n#define pb push_back\n#define all(a) (a).begin(),(a).end()\n#define chmin(x,v) x = min(x, v)\n#define chmax(x,v) x = max(x, v)\n\nconst ll linf = 1e18;\nconst int inf = 1e9;\nconst double eps = 1e-12;\nconst double pi = acos(-1);\n\ntemplate<typename T>\nistream& operator>>(istream& is, vector<T>& vec) {\n each(x,vec) is >> x;\n return is;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector<T>& vec) {\n rep(i,vec.size()) {\n if (i) os << \" \";\n os << vec[i];\n }\n return os;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector< vector<T> >& vec) {\n rep(i,vec.size()) {\n if (i) os << endl;\n os << vec[i];\n }\n return os;\n}\nusing ld = double;\nusing Point = complex<ld>;\nnamespace std {\n bool operator<(const Point &lhs, const Point &rhs) {\n if (lhs.real() < rhs.real() - eps) return true;\n if (lhs.real() > rhs.real() + eps) return false;\n return lhs.imag() < rhs.imag();\n }\n}\n\nPoint input_point() {\n ld x, y;\n cin >> x >> y;\n return Point(x, y);\n}\n\nbool eq(ld a, ld b) {\n return (abs(a - b) < eps);\n}\n\nld dot(Point a, Point b) {\n return real(conj(a) * b);\n}\n\nld cross(Point a, Point b) {\n return imag(conj(a) * b);\n}\n\nclass Line {\npublic:\n Point a, b;\n Line () : a(Point(0, 0)), b(Point(0, 0)) {}\n Line (Point a, Point b) : a(a), b(b) {}\n};\n\nclass Circle {\npublic:\n Point p;\n ld r;\n Circle () : p(Point(0, 0)), r(0) {}\n Circle (Point p, ld r) : p(p), r(r) {}\n};\n\nint ccw (Point a, Point b, Point c) {\n b -= a; c -= a;\n if (cross(b, c) > eps) return 1;\n if (cross(b, c) < -eps) return -1;\n if (dot(b, c) < 0) return 2;\n if (norm(b) < norm(c)) return -2;\n return 0;\n}\n\nbool isis_ll (Line l, Line m) {\n return !eq(cross(l.b - l.a, m.b - m.a), 0);\n}\n\nbool isis_ls (Line l, Line s) {\n return isis_ll(l, s) &&\n (cross(l.b - l.a, s.a - l.a) * cross(l.b - l.a, s.b - l.a) < eps);\n}\n\nbool isis_ss(Line s, Line t) {\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 &&\n ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool isis_lp (Line l, Point p) {\n return (abs(cross(l.b - p, l.a - p)) < eps);\n}\n\nbool isis_sp (Line s, Point p) {\n return (abs(s.a - p) + abs(s.b - p) - abs(s.b - s.a) < eps);\n}\n\nPoint proj (Line l, Point p) {\n ld t = dot(p - l.a, l.a - l.b) / norm(l.a - l.b);\n return l.a + t * (l.a - l.b);\n}\n\nPoint is_ll (Line s, Line t) {\n Point sv = s.b - s.a, tv = t.b - t.a;\n assert(cross(sv, tv) != 0);\n return s.a + sv * cross(tv, t.a - s.a) / cross(tv, sv);\n}\n\nld dist_lp (Line l, Point p) {\n return abs(p - proj(l, p));\n}\n\nld dist_ll (Line l, Line m) {\n return isis_ll(l, m) ? 0 : dist_lp(l, m.a);\n}\n\nld dist_ls (Line l, Line s) {\n return isis_ls(l, s) ? 0 : min(dist_lp(l, s.a), dist_lp(l, s.b));\n}\n\nld dist_sp (Line s, Point p) {\n Point r = proj(s, p);\n return isis_sp(s, r) ? abs(r - p) : min(abs(s.a - p), abs(s.b - p));\n}\n\nld dist_ss (Line s, Line t) {\n if (isis_ss(s, t)) return 0;\n return min({dist_sp(s, t.a), dist_sp(s, t.b), dist_sp(t, s.a), dist_sp(t, s.b)});\n}\n\nvector<Point> is_cc (Circle c1, Circle c2){\n vector<Point> res;\n ld d = abs(c1.p - c2.p);\n ld rc = (d * d + c1.r * c1.r - c2.r * c2.r) / (2 * d);\n ld dfr = c1.r * c1.r - rc * rc;\n if (abs(dfr) < eps) dfr = 0.0;\n else if (dfr < 0.0) return res;\n ld rs = sqrt(dfr);\n Point diff = (c2.p - c1.p) / d;\n res.push_back(c1.p + diff * Point(rc, rs));\n if (dfr != 0.0) res.push_back(c1.p + diff * Point(rc, -rs));\n return res;\n}\n\nvector<Point> is_lc (Circle c, Line l){\n vector<Point> res;\n ld d = dist_lp(l, c.p);\n if (d < c.r + eps){\n ld len = (d > c.r) ? 0.0 : sqrt(c.r * c.r - d * d);\n Point nor = (l.a - l.b) / abs(l.a - l.b);\n res.push_back(proj(l, c.p) + len * nor);\n res.push_back(proj(l, c.p) - len * nor);\n }\n return res;\n}\n\nvector<Point> is_sc(Circle c, Line l){\n vector<Point> v = is_lc(c, l), res;\n for (Point p : v)\n if (isis_sp(l, p)) res.push_back(p);\n return res;\n}\n\nvector<Line> tangent_cp(Circle c, Point p) {\n vector<Line> ret;\n Point v = c.p - p;\n ld d = abs(v);\n ld l = sqrt(norm(v) - c.r * c.r);\n if (isnan((long double)l)) { return ret; }\n Point v1 = v * Point(l / d,\tc.r / d);\n Point v2 = v * Point(l / d, -c.r / d);\n ret.push_back(Line(p, p + v1));\n if (l < eps) return ret;\n ret.push_back(Line(p, p + v2));\n return ret;\n}\n\nvector<Line> tangent_cc(Circle c1, Circle c2) {\n vector<Line> ret;\n if (abs(c1.p - c2.p) - (c1.r + c2.r) > -eps) {\n Point center = (c1.p * c2.r + c2.p * c1.r) / (c1.r + c2.r);\n ret = tangent_cp(c1, center);\n }\n if (abs(c1.r - c2.r) > eps) {\n Point out = (-c1.p * c2.r + c2.p * c1.r) / (c1.r - c2.r);\n vector<Line> nret = tangent_cp(c1, out);\n ret.insert(ret.end(), all(nret));\n }\n else {\n Point v = c2.p - c1.p;\n v /= abs(v);\n Point q1 = c1.p + v * Point(0,\t1) * c1.r;\n Point q2 = c1.p + v * Point(0, -1) * c1.r;\n ret.push_back(Line(q1, q1 + v));\n ret.push_back(Line(q2, q2 + v));\n }\n return ret;\n}\n\ntypedef vector<Point> Polygon;\n\nld area(const Polygon &p) {\n ld res = 0;\n int n = p.size();\n REP(j,n) res += cross(p[j], p[(j+1)%n]);\n return res / 2;\n}\n\nbool is_counter_clockwise (const Polygon &poly) {\n ld angle = 0;\n int n = poly.size();\n REP(i,n) {\n Point a = poly[i], b = poly[(i+1)%n], c = poly[(i+2)%n];\n angle += arg((c - b) / (b - a));\n }\n return angle > eps;\n}\n\nint is_in_polygon (const Polygon &poly, Point p) {\n ld angle = 0;\n int n = poly.size();\n REP(i,n) {\n Point a = poly[i], b = poly[(i+1)%n];\n if (isis_sp(Line(a, b), p)) return 1;\n angle += arg((b - p) / (a - p));\n }\n return eq(angle, 0) ? 0 : 2;\n}\n\nPolygon convex_hull(vector<Point> ps) {\n int n = ps.size();\n int k = 0;\n sort(ps.begin(), ps.end());\n Polygon ch(2 * n);\n for (int i = 0; i < n; ch[k++] = ps[i++])\n while (k >= 2 && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n for (int i = n - 2, t = k + 1; i >= 0; ch[k++] = ps[i--])\n while (k >= t && ccw(ch[k - 2], ch[k - 1], ps[i]) <= 0) --k;\n ch.resize(k - 1);\n return ch;\n}\n\nPolygon convex_cut(const Polygon &ps, Line l) {\n int n = ps.size();\n Polygon Q;\n REP(i,n) {\n Point A = ps[i], B = ps[(i+1)%n];\n Line m = Line(A, B);\n if (ccw(l.a, l.b, A) != -1) Q.push_back(A);\n if (ccw(l.a, l.b, A) * ccw(l.a, l.b, B) < 0 && isis_ll(l, m))\n Q.push_back(is_ll(l, m));\n }\n return Q;\n}\n\nvoid add_point(vector<Point> &ps, Point p) {\n for (Point q : ps) if (abs(q - p) < eps) return;\n ps.push_back(p);\n}\n\ntypedef int Weight;\n\nstruct Edge { int from, to; Weight weight; };\nbool operator>(const Edge& e1, const Edge& e2) {\n return e1.weight > e2.weight;\n}\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nvoid add_edge(Graph &g, int from, int to, Weight weight) {\n g[from].push_back((Edge){from, to, weight});\n}\n\nGraph segment_arrangement(const vector<Line> &s, const vector<Point> &p) {\n int n = p.size(), m = s.size();\n Graph g(n);\n REP(i,m) {\n vector<pair<ld,int>> vec;\n REP(j,n) if (isis_sp(s[i], p[j]))\n vec.emplace_back(abs(s[i].a - p[j]), j);\n sort(all(vec));\n REP(j,vec.size()-1) {\n int from = vec[j].second, to = vec[j+1].second;\n add_edge(g, from, to, abs(p[from] - p[to]));\n }\n }\n return g;\n}\n\nGraph circle_arrangement(const vector<Circle> &c, const vector<Point> &p) {\n int n = p.size(), m = c.size();\n Graph g(n);\n REP(i,m) {\n vector<pair<ld,int>> vec;\n REP(j,n) if (abs(abs(c[i].p - p[j]) - c[i].r) < eps)\n vec.emplace_back(arg(c[i].p - p[j]), j);\n sort(all(vec));\n REP(j,vec.size()-1) {\n int from = vec[j].second, to = vec[j+1].second;\n ld angle = vec[j+1].first - vec[j].first;\n add_edge(g, from, to, angle * c[i].r);\n }\n if (vec.size() >= 2) {\n int from = vec.back().second, to = vec.front().first;\n ld angle = vec.front().first - vec.back().first;\n add_edge(g, from, to, angle * c[i].r);\n }\n }\n return g;\n}\n\nvector<vector<int>> polygon;\nvector<int> seg2p[1024][1024];\n\nGraph dual_graph(const vector<Line> &s, const vector<Point> &p) {\n int N = p.size();\n polygon.clear();\n REP(i,1024) REP(j,1024) seg2p[i][j].clear();\n vector<vector<tuple<ld,int,bool>>> tup(N);\n REP(i,s.size()) {\n int a = -1, b = -1;\n REP(j,N) if (abs(s[i].a - p[j]) < eps) a = j;\n REP(j,N) if (abs(s[i].b - p[j]) < eps) b = j;\n assert(a >= 0 && b >= 0);\n tup[a].emplace_back(arg(s[i].b - s[i].a), b, false);\n tup[b].emplace_back(arg(s[i].a - s[i].b), a, false);\n }\n REP(i,N) sort(all(tup[i]));\n REP(i,N) {\n REP(j,tup[i].size()) {\n ld angle; int pos = j, from = i, to; bool flag;\n tie(angle, to, flag) = tup[i][j];\n if (flag) continue;\n vector<int> ps;\n while (!flag) {\n ps.push_back(from);\n get<2>(tup[from][pos]) = true;\n seg2p[from][to].push_back(polygon.size());\n seg2p[to][from].push_back(polygon.size());\n angle += pi + eps;\n if (angle > pi) angle -= 2 * pi;\n auto it = lower_bound(all(tup[to]), make_tuple(angle, 0, false));\n if (it == tup[to].end()) it = tup[to].begin();\n from = to; tie(angle, to, flag) = *it;\n pos = it - tup[from].begin();\n }\n polygon.push_back(ps);\n }\n }\n Graph g(polygon.size());\n REP(i,N) REP(j,i) {\n if (seg2p[i][j].size() == 2) {\n int from = seg2p[i][j][0];\n int to = seg2p[i][j][1];\n int len = 1;\n // double len = abs(p[i] - p[j]);\n g[from].push_back((Edge){from, to, len});\n g[to].push_back((Edge){to, from, len});\n }\n }\n return g;\n}\n\nconst ld zoom = 25;\nconst ld centerX = 6;\nconst ld centerY = 5;\n\nvoid change_color(int r, int g, int b) {\n fprintf(stderr, \"c.strokeStyle = 'rgb(%d, %d, %d)';\\n\", r, g, b);\n}\n\nint cordx(Point p) { return 400 + zoom * (p.real() - centerX); }\nint cordy(Point p) { return 400 - zoom * (p.imag() - centerY); }\n\n#define cord(p) cordx(p),cordy(p)\n\nvoid draw_point(Point p) {\n fprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(p), 2);\n}\n\nvoid draw_segment(Line l) {\n fprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(l.a), cord(l.b));\n}\n\nvoid draw_line(Line l) {\n Point v = l.b - l.a;\n Line m(l.a - v * Point(1e4, 0), l.b + v * Point(1e4, 0));\n fprintf(stderr, \"line(%d, %d, %d, %d)\\n\", cord(m.a), cord(m.b));\n}\n\nvoid draw_polygon(const Polygon &p) {\n int n = p.size();\n REP(i,n) draw_segment(Line(p[i], p[(i+1)%n]));\n}\n\nvoid draw_circle(Circle c) {\n fprintf(stderr, \"circle(%d, %d, %d)\\n\", cord(c.p), (int)(zoom * c.r));\n}\nclass UnionFind {\n vector<int> par, h;\npublic:\n UnionFind(int size) {\n par.assign(size, 0);\n h.assign(size, 0);\n REP(i, size) par[i] = i;\n }\n void unite(int u, int v) {\n u = root(u), v = root(v);\n if (u == v) return;\n if (h[u] > h[v]) {\n par[v] = u;\n }\n else if (h[u] < h[v]) {\n par[u] = v;\n }\n else {\n ++h[u];\n par[v] = u;\n }\n }\n bool isUnited(int u, int v) {\n return root(u) == root(v);\n }\n int root(int v) {\n if (par[v] == v) return v;\n return par[v] = root(par[v]);\n }\n};\nvector<ll> bfs(const Graph& G, const ll s) {\n const ll n = G.size();\n vector<ll> dist(n, linf);\n dist[s] = 0;\n queue<ll> Q; Q.push(s);\n while ( !Q.empty() ) {\n ll v = Q.front(); Q.pop();\n each(e, G[v]) {\n if (dist[v]+1 < dist[e.to]) {\n dist[e.to] = dist[v]+1;\n Q.push(e.to);\n }\n }\n }\n return dist;\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n ll n, m;\n while (cin >> n >> m, n || m) {\n vector<Line> lines;\n vector<Point> points;\n rep(i, n) {\n points.pb(input_point());\n }\n rep(i, m) {\n ll a, b; cin >> a >> b; --a, --b;\n lines.pb(Line(points[a], points[b]));\n }\n Graph G = dual_graph(lines, points);\n const ll V = G.size();\n // rep(i, polygon.size()) {\n // each(id, polygon[i]) {\n // Point p = points[id];\n // cout << \"(\" << p.real() << \", \" << p.imag() << \")\";\n // }\n // cout << endl;\n // }\n // ll s = V-1;\n ll s = 0;\n vector<ll> dist = bfs(G, s);\n ll ans = 0;\n rep(i, V) chmax(ans, dist[i]);\n cout << ans << endl;\n }\n}", "accuracy": 0.125, "time_ms": 20, "memory_kb": 28048, "score_of_the_acc": -1.0511, "final_rank": 20 }, { "submission_id": "aoj_0273_2487966", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for ( int i = 0; i < n; i++ )\n#define INF (1<<21)\n#define MAX 104\nint n, m;\nbool V[MAX][MAX];\nint T[MAX][MAX];\nint F[MAX][MAX];\nint face;\nvector<int> G[MAX];\npair<int, int> P[MAX];\nvector<vector<pair<int, int> > > R; // room;\n\ndouble angle(int s, int t){\n return atan2(P[t].second - P[s].second, P[t].first - P[s].first);\n}\n\nvoid parse(int s, int t, bool isouter, int f){\n if ( V[s][t] || s == t ) return;\n int cur1 = s, cur2 = t;\n vector<pair<int, int> > room;\n while(1){\n if ( V[cur1][cur2] ) break;\n V[cur1][cur2] = true;\n F[cur1][cur2] = f;\n room.push_back(make_pair(cur1, cur2));\n int nx;\n rep(i, G[cur2].size() ){\n if ( G[cur2][i] == cur1 ){ nx = i; break; } // next node after counter-clock\n }\n nx = (nx+1)%G[cur2].size();\n cur1 = cur2;\n cur2 = G[cur2][nx];\n }\n R.push_back(room);\n}\n\nbool isConnected(vector<pair<int, int> > &c1, vector<pair<int, int> > &c2){\n for ( int i = 0; i < c1.size(); i++ ){\n for ( int j = 0; j < c2.size(); j++ ){\n pair<int, int> p1 = c1[i];\n pair<int, int> p2 = c2[j];\n if ( p1 == p2 ) return true;\n swap(p2.first, p2.second);\n if ( p1 == p2 ) return true;\n }\n }\n return false;\n}\n\nvector<vector<int> > makeGraph(){\n R.clear();\n // sort by angle\n rep(s, n) {\n for ( int e = G[s].size()-2; e >= 0; e--){\n for ( int j = 0; j <= e; j++ ){\n \t if ( angle(s, G[s][j]) > angle(s, G[s][j+1]) ) swap(G[s][j], G[s][j+1]);\n }\n }\n }\n\n rep(i, n) rep(j, n) V[i][j] = false;\n\n int bottom = 0;\n rep(i, n){\n if ( P[i].second == P[bottom].second ){\n if ( P[i].first < P[bottom].first ) bottom = i;\n } else {\n if ( P[i].second < P[bottom].second ) bottom = i;\n }\n }\n\n face = 0;\n rep(i, n) rep(j, n) F[i][j] = -1;\n\n parse(bottom, G[bottom][0], true, face); // the outer\n\n rep(s, n) rep(j, G[s].size()){\n int t = G[s][j];\n parse(s, t, false, ++face);\n }\n\n rep(i, n) rep(j, n) {\n if ( F[i][j] == -1 ){\n assert( F[j][i] == -1);\n continue;\n }\n assert( F[i][j] != F[j][i] );\n }\n\n\n vector<vector<int> > g;\n g.resize(R.size());\n for ( int i = 0; i < R.size()-1; i++ ){\n for ( int j = i+1; j < R.size(); j++ ){\n if ( isConnected(R[i], R[j])) {\n g[i].push_back(j);\n g[j].push_back(i);\n }\n }\n }\n\n assert( n - m + R.size() == 2 );\n\n return g;\n}\n\nint bfs(vector<vector<int> > g){\n vector<int> d;\n d.resize(g.size());\n rep(i, g.size()) d[i] = INF;\n queue<int> Q;\n int u, v;\n for ( d[0] = 0, Q.push(0); !Q.empty(); ){\n u = Q.front(); Q.pop();\n for ( int i = 0; i < g[u].size(); i++ ){\n int v = g[u][i];\n if ( d[v] != INF ) continue;\n d[v] = d[u] + 1;\n Q.push(v);\n }\n }\n int maxv = 0;\n for ( int i = 0; i < d.size(); i++) maxv = max(maxv, d[i]);\n return maxv;\n}\n\nint main(){\n while(1){\n cin >> n >> m;\n if ( n == 0 ) break;\n assert( 3 <= n && n <= 100 );\n assert( n <= m && m <= 300 );\n set<pair<int, int> > S;\n rep(i, n) {cin >> P[i].first >> P[i].second;S.insert( P[i]) ;}\n assert( S.size() == n );\n rep(i, n) G[i].clear();\n map<pair<int, int>, bool> vis;\n rep(i, m){\n int s, t; cin >> s >> t; s--; t--;\n G[s].push_back(t);G[t].push_back(s);\n T[s][t] = T[t][s] = (i+1); // 0 = outer\n vis[make_pair(min(s, t), max(s,t))] = true;\n }\n\n cout << bfs(makeGraph()) << endl;\n }\n return 0;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3504, "score_of_the_acc": -0.0108, "final_rank": 2 }, { "submission_id": "aoj_0273_1929655", "code_snippet": "//\n// [not yet accepted]\n//\n#include <iostream>\n#include <vector>\n#include <fstream>\n#include <cstdio>\n#include <algorithm>\n#include <cmath>\n#include <map>\n#include <queue>\n#include <set>\n#include <functional>\n#include <ctime>\n#include <numeric>\n#include <unordered_set>\n#include <unordered_map>\n\nusing namespace std;\n\n#define fst first\n#define snd second\n#define all(c) ((c).begin()), ((c).end())\n#define TEST(x,a) { auto y=(x); if (sign(y-a)) { cout << \"line \" << __LINE__ << #x << \" = \" << y << \" != \" << a << endl; exit(-1); } }\n\nconst double EPS = 1e-8;\nint sign(double x) {\n if (x < -EPS) return -1;\n if (x > +EPS) return +1;\n return 0;\n}\nstruct point {\n typedef double T;\n T x, y; \n point &operator+=(point p) { x += p.x; y += p.y; return *this; }\n point &operator-=(point p) { x -= p.x; y -= p.y; return *this; }\n point &operator*=(T a) { x *= a; y *= a; return *this; }\n point &operator/=(T a) { return *this *= (1.0/a); }\n point operator-() const { return {-x, -y}; }\n bool operator<(point p) const { \n int s = sign(x - p.x);\n return s ? s < 0 : sign(y - p.y) < 0;\n }\n};\nbool operator==(point p, point q) { return !(p < q) && !(q < p); }\npoint operator+(point p, point q) { return p += q; }\npoint operator-(point p, point q) { return p -= q; }\npoint operator*(point::T a, point p) { return p *= a; }\npoint operator*(point p, point::T a) { return p *= a; }\npoint operator/(point p, point::T a) { return p /= a; }\npoint::T dot(point p, point q) { return p.x*q.x+p.y*q.y; }\npoint::T cross(point p, point q) { return p.x*q.y-p.y*q.x; } // left turn > 0\npoint::T norm2(point p) { return dot(p,p); }\npoint orth(point p) { return {-p.y, p.x}; }\npoint::T norm(point p) { return sqrt(dot(p,p)); }\npoint::T arg(point p) { return atan2(p.y, p.x); }\n\nstruct line { point p, q; };\nbool operator==(line l, line m) {\n return !sign(cross(l.p-l.q,m.p-m.q)) && !sign(cross(l.p-l.q,m.p-l.p));\n}\n\nstruct segment { point p, q; };\nbool operator==(segment l, line m) {\n return (l.p==m.p && l.q==m.q) || (l.p==m.q && l.q==m.p); // do not consider the direction\n}\nstruct circle { point p; point::T r; };\nbool operator==(circle c, circle d) { return c.p == d.p && !sign(c.r - d.r); }\n\ntypedef vector<point> polygon;\n\nstruct polar_angle {\n const point o;\n const int s; // +1 for ccw, -1 for cw\n polar_angle(point p = {0,0}, int s = +1) : o(p), s(s) { }\n int quad(point p) const {\n for (int i = 1; i <= 4; ++i, swap(p.x = -p.x, p.y))\n if (p.x > 0 && p.y >= 0) return i;\n return 0;\n }\n bool operator()(point p, point q) const {\n p = p - o; q = q - o;\n if (quad(p) != quad(q)) return s*quad(p) < s*quad(q);\n if (cross(p, q)) return s*cross(p, q) > 0;\n return norm2(p) < norm2(q); // closer first\n }\n};\n\nvector<point> intersect(segment s, segment t) {\n auto a = cross(s.q - s.p, t.q - t.p);\n auto b = cross(t.p - s.p, t.q - t.p); \n auto c = cross(s.q - s.p, s.p - t.p);\n if (a < 0) { a = -a; b = -b; c = -c; }\n if (sign(b) < 0 || sign(a-b) < 0 ||\n sign(c) < 0 || sign(a-c) < 0) return {}; // disjoint\n if (sign(a) != 0) return {s.p + b/a*(s.q - s.p)}; // properly crossing\n vector<point> ps; // same line\n auto insert_if_possible = [&](point p) {\n for (auto q: ps) if (sign(dot(p-q, p-q)) == 0) return;\n ps.push_back(p);\n };\n if (sign(dot(s.p-t.p, s.q-t.p)) <= 0) insert_if_possible(t.p);\n if (sign(dot(s.p-t.q, s.q-t.q)) <= 0) insert_if_possible(t.q);\n if (sign(dot(t.p-s.p, t.q-s.p)) <= 0) insert_if_possible(s.p);\n if (sign(dot(t.p-s.q, t.q-s.q)) <= 0) insert_if_possible(s.q);\n return ps;\n}\n\nstruct arrangement {\n struct edge {\n int src, dst;\n point::T weight;\n size_t id, rev;\n };\n int n;\n vector<point> ps; // ps[id[p]] = p, id[ps[k]] = k\n map<point,int> id; \n vector<vector<edge>> adj;\n\n arrangement(vector<segment> ss) : n(0) {\n vector<vector<pair<point::T, int>>> group(ss.size());\n auto append = [&](int i, point p) {\n if (!id.count(p)) { id[p] = n++; ps.push_back(p); }\n group[i].push_back({norm(ss[i].p - p), id[p]});\n };\n for (int i = 0; i < ss.size(); ++i) {\n append(i, ss[i].p); append(i, ss[i].q);\n for (int j = 0; j < i; ++j) {\n for (point p: intersect(ss[i], ss[j])) {\n append(i, p); append(j, p);\n }\n }\n }\n adj.resize(n);\n for (auto &vs: group) {\n sort(all(vs));\n for (int i = 0; i+1 < vs.size(); ++i) {\n auto u = vs[i].snd, v = vs[i+1].snd;\n if (u == v) continue;\n auto len = vs[i+1].fst - vs[i].fst;\n adj[u].push_back({u, v, len});\n adj[v].push_back({v, u, len});\n }\n }\n // remove duplicates and orient edges\n vector<unordered_map<int, int>> idx(n);\n for (int u = 0; u < n; ++u) {\n auto eq = [&](edge e, edge f) { return e.dst == f.dst; };\n auto lt = [&](edge e, edge f) { return e.dst < f.dst; };\n sort(all(adj[u]), lt);\n adj[u].erase(unique(all(adj[u]), eq), adj[u].end());\n sort(all(adj[u]), [&](edge e, edge f) {\n return arg(ps[e.dst] - ps[e.src]) > arg(ps[f.dst] - ps[f.src]);\n });\n for (int i = 0; i < adj[u].size(); ++i) {\n adj[u][i].id = i;\n int v = adj[u][i].dst;\n idx[u][v] = i;\n if (idx[v].count(u)) {\n int j = idx[v][u];\n adj[u][i].rev = j;\n adj[v][j].rev = i;\n }\n }\n }\n }\n edge twin(edge e) const { return adj[e.dst][e.rev]; }\n edge next(edge e) const {\n int j = adj[e.dst][e.rev].id + 1;\n if (j >= adj[e.dst].size()) j = 0;\n return adj[e.dst][j];\n }\n edge outer() const {\n int s = 0;\n for (int i = 1; i < n; ++i) if (ps[i] < ps[s]) s = i;\n for (int i = 0; i < adj[s].size(); ++i) {\n edge e1 = adj[s][i], e2 = adj[s][(i+1)%adj[s].size()];\n if (cross(ps[e1.dst]-ps[s], ps[e2.dst]-ps[s]) <= 0) return e1;\n }\n }\n};\nistream &operator>>(istream &is, point &p) { is>>p.x>>p.y;return is; }\nostream &operator<<(ostream &os, const point &p) { os<<\"(\"<<p.x<<\",\"<<p.y<<\")\"; return os; }\n\n\nstruct visualizer {\n double minx, maxx, miny, maxy, scale; \n ofstream ofs;\n visualizer(string s = \"data.js\") : ofs(s) { \n minx = miny = 1.0/0.0;\n maxx = maxy = -1.0/0.0;\n }\n void update(point p) {\n minx = min(minx, p.x); miny = min(miny, p.y);\n maxx = max(maxx, p.x); maxy = max(maxy, p.y);\n scale = 480/(max({maxx-minx, maxy-miny,1.0}));\n }\n double X(point p) { return scale * (p.x-minx) + 10; }\n double Y(point p) { return 490 - scale * (p.y-miny); }\n vector<point> ps;\n vector<segment> ss;\n visualizer &operator<<(point p) { ps.push_back(p); update(p); return *this; }\n visualizer &operator<<(segment s) { ss.push_back(s); update(s.p); update(s.q); return *this; }\n ~visualizer() {\n for (point p: ps) \n ofs << \"circle(\" << X(p) << \",\" << Y(p) << \",3.0)\" << endl;\n for (segment s: ss) \n ofs << \"line(\" << X(s.p) << \",\" << Y(s.p) << \",\" \n << X(s.q) << \",\" << Y(s.q) << \")\" << endl;\n }\n};\n\n\nint main() {\n for (int c, w; ~scanf(\"%d %d\", &c, &w) && c; ) {\n vector<point> ps(c);\n for (int i = 0; i < c; ++i) {\n scanf(\"%lf %lf\", &ps[i].x, &ps[i].y);\n }\n vector<segment> ss;\n for (int i = 0; i < w; ++i) {\n int u, v; scanf(\"%d %d\", &u, &v);\n ss.push_back({ps[u-1], ps[v-1]});\n }\n arrangement arr(ss);\n /*\n visualizer vis;\n for (int i = 0; i < arr.n; ++i) {\n cerr << i << \": \" << arr.ps[i] << endl;\n vis << arr.ps[i];\n for (auto e: arr.adj[i]) {\n vis << segment({arr.ps[e.src], arr.ps[e.dst]});\n }\n }\n */\n\n typedef arrangement::edge edge;\n edge e = arr.outer(); // outer-face edge\n\n vector<unordered_map<int,int>> step(arr.n);\n queue<edge> que;\n auto proceed = [&](edge s, int value) {\n if (step[s.src].count(s.dst)) return;\n //cerr << \"proceed edge \" << arr.ps[e.src] << arr.ps[e.dst] << endl;\n edge e = s;\n do {\n //cerr << \" mark \" << arr.ps[e.src] << arr.ps[e.dst] << endl;\n step[e.src][e.dst] = value;\n que.push(arr.twin(e));\n e = arr.next(e);\n } while (e.src != s.src || e.dst != s.dst);\n };\n proceed(e, 0);\n int ans = 0;\n while (!que.empty()) {\n edge e = que.front(); que.pop();\n ans = step[e.dst][e.src];\n proceed(e, ans + 1);\n }\n printf(\"%d\\n\", ans);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3596, "score_of_the_acc": -0.07, "final_rank": 7 } ]
aoj_0282_cpp
プログラミングコンテスト 白虎大学では毎年プログラミングコンテストが開催されています。チームの総数をNとしたとき、チームには1からNのチームIDがそれぞれ割り当てられています。コンテストは全てのチームの得点が0の状態から開始し、L秒間連続して行われます。 今年のコンテストは、テレビで中継されることになりました。コンテストの間テレビに映るのは、その時点で最も得点の高いチームだけです。ただし、該当するチームが複数いるときは、その中でチームIDの一番小さいチームが映ります。映すべきチームが変わると、瞬時にカメラが切り替わります。 あなたはコンテストのログを入手しました。ログには、あるチームの得点が変化した時のレコードがすべて含まれています。各レコードは「チーム d がコンテスト開始 t 秒後の時点で x 点獲得した」という形式で与えられています。なお、減点される場合もあるので、現在の得点が0より小さくなることもあります。 コンテストのログを入力とし、コンテスト開始から終了までの間にテレビに映った時間が最も長いチームのIDを報告するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力は以下の形式で与えられる。 N R L d 1 t 1 x 1 d 2 t 2 x 2 : d R t R x R 1行目は3つの整数からなる。 N (2 ≤ N ≤ 100000)はチーム数、 R (0 ≤ R ≤ 1000000)はログに含まれるレコードの数である。 L (1 ≤ L ≤ 1000000)はコンテストの時間(長さ)を表す。続く R 行に各レコードの情報が与えられる。各レコードはチーム d i (1 ≤ d i ≤ N )がコンテスト開始 t i (0 < t i < L )秒後の時点で x i (-1000 ≤ x i ≤ 1000)点獲得あるいは減点されたことを示す。ただし、 t i , x i は整数であり、 t i-1 ≤ t i である。 出力 コンテスト開始から終了までの間にテレビに映った時間が最も長いチームのIDを1行に出力する。ただし、最も長いチームが複数あるときは、その中でチームIDの一番小さいチームを出力する。 入力例 1 3 4 600 3 100 5 1 200 10 2 400 20 3 500 20 出力例 1 1 入力例 2 3 5 600 3 100 5 1 200 10 2 300 30 1 400 -8 2 400 -27 出力例 2 3
[ { "submission_id": "aoj_0282_10853284", "code_snippet": "// 7\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for (int i =(a); i <(b); i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(), (v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = (1<<29);\nconst bool debug = 0;\n\nstruct SegTree {\n\tpii init_val;\n\tint n;\n\tvector<pii> node;\n\t\n\tSegTree(int _n, pii init_val) : init_val(init_val) {\n\t\tn = 1;\n\t\twhile (n < _n) n *= 2;\n\t\tnode.resize(2 * n - 1, init_val);\n\t}\n\t\n\tvoid add(int i, int x) {\n\t\ti += n - 1;\n\t\tnode[i].fi += x;\n\t\t\n\t\twhile (i > 0) {\n\t\t\ti = (i - 1) / 2;\n\t\t\tnode[i] = max(node[i * 2 + 1], node[i * 2 + 2]);\n\t\t}\n\t}\n\t\n\tvoid update(int i, pii x) {\n\t\ti += n - 1;\n\t\tchmax(node[i], x);\n\t\t\n\t\twhile (i > 0) {\n\t\t\ti = (i - 1) / 2;\n\t\t\tnode[i] = max(node[i * 2 + 1], node[i * 2 + 2]);\n\t\t}\n\t}\n\t\n\tpii query(int a, int b, int k = 0, int l = 0, int r = -1) {\n\t\tif (r < 0) r = n;\n\t\t\n\t\tif (r <= a || b <= l) return init_val;\n\t\tif (a <= l && r <= b) return node[k];\n\t\treturn max(query(a, b, k * 2 + 1, l, (l + r) / 2), query(a, b, k * 2 + 2, (l + r) / 2, r));\n\t}\n};\n\nint N, R, L;\nint cnt[112345];\n\nint main() {\n\tcin >> N >> R >> L;\n\t\n\tint lastt = 0;\n\tSegTree seg(N, pii(-INF, 0));\n\t\n\tREP(i, N) seg.update(i, pii(0, -i));\n\t\n\tREP(i, R) {\n\t\tint d, t, x;\n\t\tscanf(\"%d %d %d\", &d, &t, &x);\n\t\td--;\n\t\t\n\t\tcnt[-seg.query(0, N).se] += t - lastt;\n\t\tseg.add(d, x);\n\t\tlastt = t;\n\t}\n\tcnt[-seg.query(0, N).se] += L - lastt;\n\t\n\tint ans = -INF, ansp = 0;\n\tREP(i, N) if (chmax(ans, cnt[i])) ansp = i + 1;\n\t\n\tcout << ansp << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 5412, "score_of_the_acc": -0.1374, "final_rank": 4 }, { "submission_id": "aoj_0282_10852108", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n\n int N,R,L;\n cin>>N>>R>>L;\n \n vector<int> A(N,0);\n set<pair<int,int>> st;\n vector<int> ans(N,0);\n rep(i,N) st.insert({-A[i], i});\n int mae=0;\n rep(i,R){\n int d,t,x;\n cin>>d>>t>>x;\n d--;\n\n ans[st.begin()->se]+=t-mae;\n\n st.erase({-A[d], d});\n A[d]+=x;\n st.insert({-A[d], d});\n\n mae=t;\n }\n ans[st.begin()->se]+=L-mae;\n int ma=0;\n rep(i,N) chmax(ma, ans[i]);\n rep(i,N) if(ans[i]==ma){\n cout<<i+1<<\"\\n\";\n break;\n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 8832, "score_of_the_acc": -0.4239, "final_rank": 8 }, { "submission_id": "aoj_0282_10783220", "code_snippet": "#include<bits/stdc++.h>\n#include <queue>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n\nbool solve(){\n ll N,R,L;\n cin>>N>>R>>L;\n vector<ll>S(N,0);\n ll nt = 0,nv = 0;\n vector<ll>time(N,0);\n priority_queue<pair<ll,ll>>Q;\n rep(i,N)Q.push({S[i],-i});\n rep(i,R){\n ll d,t,x;cin>>d>>t>>x;d--;\n time[nv]+=t-nt;\n S[d]+=x;\n Q.push({S[d],-d});\n while(!Q.empty()){\n auto [s,idx] = Q.top();\n if(s!=S[-idx])Q.pop();\n else {\n nv = -idx;\n break;\n }\n }\n nt = t;\n // cout<<nt<<\" \"<<nv+1<<endl;\n }\n time[nv]+=L-nt;\n ll ans = 0;\n rep(i,N){\n if(time[i]>time[ans])ans = i;\n }\n cout<<ans+1<<endl;\n return false;\n}\n\nint main(){\n while(solve());\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 22876, "score_of_the_acc": -0.5739, "final_rank": 13 }, { "submission_id": "aoj_0282_9576951", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\nint a[100001],t2[100001];\nint main(void)\n{\n\tint n,r,l,i,d,t,x,tt,dd,xx,mx,mi,j;\n\tP pp;\n\tpriority_queue<P> qu;\n\tcin >>n>>r>>l;\n\ttt=0;\n\tpp.first=0;\tpp.second=-1;\n\tqu.push(pp);\n\tfor(i=0;i<r;i++)\t{\n//\t\tcout <<\"i=\"<<i<<endl;\n\t\twhile(1)\t{\n\t\t\tpp=qu.top();\n\t\t\tif(pp.first==a[-pp.second])\tbreak;\n\t\t\tqu.pop();\n\t\t}\n\t\tdd=-pp.second;\t\n\t\tcin >>d>>t>>x;\n\t\tt2[dd]+=t-tt;\n\t\ttt=t;\n\t\ta[d]+=x;\n\t\tpp.first=a[d];\tpp.second=-d;\n\t\tqu.push(pp);\n//\t\tfor(j=1;j<=n;j++)\tcout <<a[j]<<\" \";\n//\t\tcout <<endl;\n\t}\n\twhile(1)\t{\n\t\tpp=qu.top();\n\t\tif(pp.first==a[-pp.second])\tbreak;\n\t\tqu.pop();\n\t}\n\tdd=-pp.second;\t\n\tt2[dd]+=l-tt;\t\n\t\n//\tfor(j=1;j<=n;j++)\tcout <<t2[j]<<\" \";\n//\tcout <<endl;\n\t\n\tmx=-1;\n\tfor(i=1;i<=n;i++)\t{\n\t\tif(mx<t2[i])\t{\n\t\t\tmx=t2[i];\tmi=i;\n\t\t}\n\t}\n\tcout <<mi<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 11576, "score_of_the_acc": -0.5878, "final_rank": 14 }, { "submission_id": "aoj_0282_9156663", "code_snippet": "#pragma region Macros\n\n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2\")\n\n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n\n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n// #define unordered_map<int, int> gp_hash_table<int, int, custom_hash> \n\n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n\n#define next asdnext\n#define prev asdprev\n\nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n\nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n\nstruct Edge {\n int from, to;\n double cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, double cost) : to(to), cost(cost) {}\n Edge(int from, int to, double cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n};\n\nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n\nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n\nusing i64 = ll;\n// using i64 = uint64_t;\n// bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\ni64 lrmask(i64 l, i64 r) { return (1LL << r) - (1LL << l); }\ni64 sub_bit(i64 x, i64 l, i64 r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\ni64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n\ni64 popcount(i64 x) { return __builtin_popcountll(x); }\ni64 popcount(i64 x, i64 l, i64 r) { return __builtin_popcountll(sub_bit(x, l, r)); }\ni64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); }\ni64 unpopcount(i64 x, i64 l, i64 r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); }\nbool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; }\n\ni64 top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\ni64 bot_bit(i64 x) { return __builtin_ctz(x);} // 2^kの位 (x > 0)\n// i64 next_bit(i64 x, i64 k) { return 0; }\n// i64 prev_bit(i64 x, i64 k) { return 0; }\n// i64 kth_bit(i64 x, i64 k) { return 0; }\ni64 MSB(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\ni64 LSB(i64 x) { return (x & -x); } // mask\n\ni64 countl_zero(i64 x) { return __builtin_clzll(x); }\ni64 countl_one(i64 x) {\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\ni64 countr_zero(i64 x) { return __builtin_ctzll(x); } // x==0のとき64が返ることに注意\ni64 countr_one(i64 x) { i64 ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n\ni64 floor_log2(i64 x) { if (x == 0) return 0; return 63 - __builtin_clzll(x); }\ni64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // MSBと同じ\ni64 ceil_log2(i64 x) { if (x == 0) return 0; return 64 - __builtin_clzll(x - 1); }\ni64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n\ni64 rotl(i64 x, i64 k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\ni64 rotr(i64 x, i64 k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n}\n// i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\ni64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n}\n// i64 bit_reverse(i64 x, i64 l, i64 r) { return 0; }\n\nbool is_palindrome(i64 x) { return x == bit_reverse(x); }\nbool is_palindrome(i64 x, i64 l, i64 r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\ni64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\ni64 erase(i64 x, i64 l, i64 r) { return x>>r<<l | x&(1LL<<l - 1); } // [l, r) をカット\n\ni64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\ni64 hamming(i64 a, i64 b, i64 l, i64 r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\ni64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\ni64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\ni64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n\ni64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctz(x) + 1));\n}\n\n\n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\nint round(int x, int y) {\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n}\nint round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0); // TODO\n return INF;\n}\nint round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = z / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n}\n// int round(ld x, int k) { // xを10^kの位に関して四捨五入\n// }\n// int floor(ld x, int k) { // xを10^kの位に関してflooring\n// }\n// int ceil(ld x, int k) { // xを10^kの位に関してceiling\n// }\n// int kth(int x, int y, int k) { // x / yの10^kの位の桁\n// }\nint floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n}\nint ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return ceil(x / y);\n // ceil(x) = floor(x + 1)\n}\nint perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -floor(x / fabs(y));\n if (x < 0 && y < 0) return floor(x / y) + (x - floor(x/y)*y < -EPS);\n return floor(x / y) - (x - floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n}\nld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n}\nint seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\nint modf(ld x) {\n\tif (x < 0) return ceill(x);\n\telse return floorl(x);\n}\n// 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\nint seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n}\nint seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n}\n\ntemplate <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\ntemplate <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n\ntemplate <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n}\ntemplate <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n}\ntemplate <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - max({a, b, c}) - min({a, b, c});\n}\ntemplate <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) { // TODO テンプレート引数\n if (a > b) swap(a, b);\n } else {\n if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (b > c) swap(b, c);\n } else {\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, T &d, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (a > d) swap(a, d);\n if (b > c) swap(b, c); if (b > d) swap(b, d); if (c > d) swap(c, d);\n } else {\n if (d > c) swap(d, c); if (d > b) swap(d, b); if (d > a) swap(d, a);\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n\n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\nclass Compress {\npublic:\n int sz = 0;\n // gp_hash_table<int, int, custom_hash> Z, UZ;\n unordered_map<int, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, int> UZ; // 圧縮した値 -> 元の値\n\n Compress(const vector<int> &V, int base = 0) {\n this->sz = base;\n set<int> s(V.begin(), V.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<int> &V1, const vector<int> &V2, int base = 0) {\n this->sz = base;\n vector<int> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<int> s(V3.begin(), V3.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n Compress(const vector<int> &V1, const vector<int> &V2, const vector<int> &V3, int base = 0) {\n this->sz = base;\n vector<int> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<int> s(V4.begin(), V4.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n Compress(const vector<int> &V1, const vector<int> &V2,\n const vector<int> &V3, const vector<int> &V4, int base = 0) {\n this->sz = base;\n vector<int> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<int> s(V5.begin(), V5.end());\n\n for (int x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n\n vector<int> zip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[ret[i]];\n }\n return ret;\n }\n\n vector<int> unzip(const vector<int> &V) {\n vector<int> ret = V;\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[ret[i]];\n }\n return ret;\n }\n\n int size() { return sz; }\n\n int encode(int x) { return Z[x]; }\n int decode(int x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n\nclass UnionFind {\npublic:\n\tUnionFind() = default;\n UnionFind(int N) : par(N), sz(N, 1) {\n iota(par.begin(), par.end(), 0);\n }\n\tint root(int x) {\n\t\tif (par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool unite(int x, int y) {\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n if (rx == ry) return false;\n\t\tif (sz[rx] < sz[ry]) swap(rx, ry);\n\t\tsz[rx] += sz[ry];\n\t\tpar[ry] = rx;\n return true;\n\t}\n\tbool issame(int x, int y) { return (root(x) == root(y)); }\n\tint size(int x) { return sz[root(x)]; }\n vector<vector<int>> groups(int N) {\n vector<vector<int>> G(N);\n for (int x = 0; x < N; x++) {\n G[root(x)].push_back(x);\n }\n\t\tG.erase( remove_if(G.begin(), G.end(),\n [&](const vector<int>& V) { return V.empty(); }), G.end());\n return G;\n }\nprivate:\n\tvector<int> par, sz;\n};\n\ntemplate<typename T>\nstruct BIT {\n int N; // 要素数\n vector<T> bit[2]; // データの格納先\n BIT(int N_, int x = 0) {\n N = N_ + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n if (x != 0) {\n for (int i = 0; i < N; i++) add(i, x);\n }\n }\n BIT(const vector<int> &A) {\n N = A.size() + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n for (int i = 0; i < (int)A.size(); i++) add(i, A[i]);\n }\n void add_sub(int p, int i, T x) {\n while (i < N) { bit[p][i] += x; i += (i & -i); }\n }\n void add(int l, int r, T x) {\n add_sub(0, l + 1, -x * l); add_sub(0, r + 1, x * r);\n add_sub(1, l + 1, x); add_sub(1, r + 1, -x);\n }\n void add(int i, T x) { add(i, i + 1, x); }\n T sum_sub(int p, int i) {\n T ret = 0;\n while (i > 0) { ret += bit[p][i]; i -= (i & -i); }\n return ret;\n }\n T sum(int i) { return sum_sub(0, i) + sum_sub(1, i) * i; }\n T sum(int l, int r) { return sum(r) - sum(l); }\n T get(int i) { return sum(i, i + 1); }\n void set(int i, T x) { T s = get(i); add(i, -s + x); }\n};\n\ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n\n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n\nusing mint = Modint<MOD>;\n\nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n\nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0);\n // assert(x > 0);\n if (x == 1 or x == 0) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n\nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n\n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n\nstring to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n\n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n}\nstring to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n}\nstring to_string(char c) { string s = \"\"; s += c; return s; }\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n\nvector<mint> _fac, _finv, _inv;\nvoid COMinit(int N) {\n _fac.resize(N + 1); _finv.resize(N + 1); _inv.resize(N + 1);\n _fac[0] = _fac[1] = 1; _finv[0] = _finv[1] = 1; _inv[1] = 1;\n for (int i = 2; i <= N; i++) {\n _fac[i] = _fac[i-1] * mint(i);\n _inv[i] = -_inv[MOD % i] * mint(MOD / i);\n _finv[i] = _finv[i - 1] * _inv[i];\n }\n}\n\nmint FAC(int N) {\n if (N < 0) return 0; return _fac[N];\n}\nmint COM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[K] * _finv[N - K];\n}\nmint PERM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[N - K];\n}\nmint NHK(int N, int K) { // initのサイズに注意\n if (N == 0 && K == 0) return 1;\n return COM(N + K - 1, K);\n}\n\n#pragma endregion\n\n\nunsigned _bit_ceil(unsigned n) {\n unsigned x = 1;\n while (x < (unsigned)(n)) x *= 2;\n return x;\n}\n\nint _countr_zero(unsigned n) {\n return __builtin_ctz(n);\n}\n\ntemplate <class S, S (*op)(S, S), S (*e)()> struct segtree {\npublic:\n segtree() : segtree(0) {}\n explicit segtree(int n) : segtree(vector<S>(n, e())) {}\n explicit segtree(const vector<S>& v) : _n(int(v.size())) {\n size = (int)_bit_ceil((unsigned int)(_n));\n log = _countr_zero((unsigned int)size);\n d = vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) const {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n\n // void add(int p, S x) {\n // assert(0 <= p && p < _n);\n // S s = get(p);\n // set(p, s + x);\n // }\n\n S prod(int l, int r) const {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() const { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) const {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) const {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) const {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) const {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\nprivate:\n int _n, size, log;\n vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\n\nusing S = pair<int, int>;\nS op(S x, S y) { return max({x, y}); }\nS e() { return make_pair(-INFL, -INFL); }\n\nsigned main() {\n int N, Q, L;\n cin >> N >> Q >> L;\n vector<pair<int, int>> A(N);\n for (int i = 0; i < N; i++) {\n A[i].second = -i;\n }\n\n segtree<S, op, e> seg(A);\n\n vector<int> sum(N); // チームiが映った時間の総和\n vector<int> I(Q), T(Q), P(Q);\n for (int i = 0; i < Q; i++) cin >> I[i] >> T[i] >> P[i];\n T.pb(L);\n for (int q = 0; q < Q; q++) {\n int i = I[q], t = T[q], p = P[q];\n i--;\n\n seg.set(i, make_pair(seg.get(i).first + p, -i));\n\n pair<int, int> pa = seg.all_prod();\n // cout << pa.second << endl;\n sum[-pa.second] += T[q + 1] - T[q];\n // cout << seg.get(0).first << \" \" << seg.get(1).first << endl;\n }\n\n int ma = -INFL, ans = 0;\n for (int i = 0; i < N; i++) {\n if (sum[i] > ma) {\n ma = sum[i];\n ans = i;\n }\n }\n cout << ans + 1 << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 29924, "score_of_the_acc": -0.3414, "final_rank": 6 }, { "submission_id": "aoj_0282_9090791", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, r, L;\n cin >> n >> r >> L;\n vector<int> d(r + 1), t(r + 1), x(r + 1);\n for (int i = 0; i < r; i++) {\n cin >> d[i] >> t[i] >> x[i];\n d[i] -= 1;\n }\n d[r] = 0, t[r] = L, x[r] = 0;\n vector<int> tm(n);\n vector<int> pt(n);\n set<pair<int, int>> st;\n for (int i = 0; i < n; i++) {\n st.insert({pt[i], -i});\n }\n int pre = 0;\n for (int i = 0; i <= r; i++) {\n auto it = st.rbegin();\n tm[-it->second] += t[i] - pre;\n pre = t[i];\n\n st.erase({pt[d[i]], -d[i]});\n pt[d[i]] += x[i];\n st.insert({pt[d[i]], -d[i]});\n }\n int res = 0;\n for (int i = 0; i < n; i++) {\n if (tm[res] < tm[i]) res = i;\n }\n cout << res + 1 << endl;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 16004, "score_of_the_acc": -0.5967, "final_rank": 15 }, { "submission_id": "aoj_0282_8293667", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing LL = long long;\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VL = vector<LL>;\n\nint n, r, l;\nVL scores_by_team; // チームごとの得点\nVL time_by_team; // チームごとの時間\npriority_queue<LL, vector<LL>> highest; // 得点(降順)\nmap<LL, set<LL>> teams_by_score; // 得点ごとのチームID\nVL elapsed_time = {0}; // 経過時間\nLL top = 1;\nVL buf_d, buf_t, buf_x;\nLL d, t, x;\n\nvoid update() {\n for (int j = 0; j < buf_d.size(); ++j) {\n // 旧得点からチームを消去\n teams_by_score[scores_by_team[buf_d[j]]].erase(buf_d[j]);\n // チーム得点を更新\n scores_by_team[buf_d[j]] += buf_x[j];\n // 新たな得点の場合\n if (teams_by_score[scores_by_team[buf_d[j]]].size() == 0)\n highest.push(scores_by_team[buf_d[j]]);\n // 新得点にチームを追加\n teams_by_score[scores_by_team[buf_d[j]]].insert(buf_d[j]);\n }\n // トップチームの時間を更新\n time_by_team[top] += buf_t.back() - elapsed_time.back();\n // 最高点のチームがいなくなったら、最高点を消去\n while (teams_by_score[highest.top()].size() == 0) highest.pop();\n top = *teams_by_score[highest.top()].begin();\n elapsed_time.push_back(buf_t.back());\n buf_d.clear();\n buf_t.clear();\n buf_x.clear();\n}\nint main() {\n cin >> n >> r >> l;\n scores_by_team.resize(n + 1);\n time_by_team.resize(n + 1);\n for (LL i = 1; i <= n; ++i) teams_by_score[0].insert(i);\n highest.push(0);\n for (int i = 0; i < r; ++i) {\n cin >> d >> t >> x;\n // tが変わったらバッファからデータを取り出し処理\n if (buf_t.size() > 0 && buf_t.back() != t) {\n update();\n }\n buf_d.push_back(d);\n buf_t.push_back(t);\n buf_x.push_back(x);\n }\n if (buf_t.size() > 0) update();\n // 終了時の時間を更新\n time_by_team[top] += l - elapsed_time.back();\n LL team = 1;\n LL max_time = time_by_team[1];\n for (int i = 2; i <= n; ++i) {\n if (time_by_team[i] > max_time) {\n max_time = time_by_team[i];\n team = i;\n }\n }\n cout << team << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 97012, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0282_8101034", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\npriority_queue<pair<int,int> > qu;\nqueue<pair<int,int > > ck;\nint main()\n{\n int n,r,l,nt=0,nd=1,nx=0,nw=0;\n cin>>n>>r>>l;\n vector<int> time(n+1,0);\n vector<int> pt(n+1,0);\n vector<int> d(r+1,1),t(r+2,0),x(r+1,0);\n t[r+1]=l;\n for(int i=1;i<=r;i++) cin>>d[i]>>t[i]>>x[i];\n for(int i=0;i<=r;i++){\n if(i==0){\n time[d[i]]+=t[i+1]-nw,nw=t[i+1];\n continue;\n }\n pt[d[i]]+=x[i];\n qu.push({pt[d[i]],d[i]*-1});\n while(pt[qu.top().second*-1]!=qu.top().first) qu.pop();\n time[qu.top().second*-1]+=t[i+1]-nw,nw=t[i+1];\n // while(!qu.empty()){\n // cout<<qu.top().first<<\" \"<<qu.top().second<<endl;\n // cout<<\"time=\"<<time[qu.top().second]<<endl;\n // ck.push({qu.top().first,qu.top().second});\n // qu.pop();\n // }\n // while(!ck.empty()){\n // qu.push({ck.front().first,ck.front().second});\n // ck.pop();\n // }\n // cout<<endl;\n }\n // for(int i=1;i<=n;i++) cout<<time[i]<<endl;\n // cout<<endl;\n // while(!qu.empty()){\n // cout<<qu.top().first<<\" \"<<qu.top().second<<endl;\n // ck.push({qu.top().first,qu.top().second});\n // qu.pop();\n // }\n // while(!ck.empty()){\n // qu.push({ck.front().first,ck.front().second});\n // ck.pop();\n // }\n int mx=-1000000,ans;\n for(int i=0;i<=n;i++){\n if(mx<time[i]) mx=time[i],ans=i; \n }\n cout<<ans<<endl;\n return 0;\n\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 19512, "score_of_the_acc": -0.6918, "final_rank": 16 }, { "submission_id": "aoj_0282_7937802", "code_snippet": "#include <iostream>\nusing namespace std;\nint max(int *p, int N) {\n int top = 1;\n for (int i = 2; i <= N; i++) {\n if (p[top] < p[i])\n top = i;\n }\n return top;\n}\nint main() {\n int N, R, L, d, t, x, old = 1, oldt = 0;\n cin >> N >> R >> L;\n int pt[N + 1], ptime[N + 1];\n for (int i = 0; i <= N; i++)\n pt[i] = ptime[i] = 0;\n for (int i = 0; i < R; i++) {\n cin >> d >> t >> x;\n ptime[old] += t - oldt;\n oldt = t;\n pt[d] += x;\n if (x >= 0) {\n if (pt[old] < pt[d])\n old = d;\n if (pt[old] == pt[d] && old > d)\n old = d;\n } else if (old == d)\n old = max(pt, N);\n }\n ptime[old] += L - oldt;\n cout << max(ptime, N) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 3876, "score_of_the_acc": -0.4864, "final_rank": 11 }, { "submission_id": "aoj_0282_7937792", "code_snippet": "#include <iostream>\nusing namespace std;\nint max(long long int *p, int N) {\n int top = 1;\n for (int i = 2; i <= N; i++) {\n if (p[top] < p[i])\n top = i;\n }\n return top;\n}\nint main() {\n int N, R, L, d, t, x, old = 1, oldt = 0;\n cin >> N >> R >> L;\n long long int pt[N + 1], ptime[N + 1];\n for (int i = 0; i <= N; i++)\n pt[i] = ptime[i] = 0;\n for (int i = 0; i < R; i++) {\n cin >> d >> t >> x;\n ptime[old] += t - oldt;\n oldt = t;\n pt[d] += x;\n if (x >= 0) {\n if (pt[old] < pt[d])\n old = d;\n if (pt[old] == pt[d] && old > d)\n old = d;\n } else {\n if (old == d)\n old = max(pt, N);\n }\n }\n ptime[old] += L - oldt;\n int ans = 1;\n for (int i = 2; i <= N; i++) {\n if (ptime[ans] < ptime[i])\n ans = i;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 4640, "score_of_the_acc": -0.4753, "final_rank": 10 }, { "submission_id": "aoj_0282_7937779", "code_snippet": "#include <climits>\n#include <iostream>\n#include <utility>\ntypedef std::pair<int, int> P;\nconst int MAX_N = 1 << 17;\nint n;\nP dat[MAX_N * 2 - 1];\nint cnt[MAX_N];\nvoid init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n for (int i = 0; i != n * 2 - 1; ++i)\n dat[i] = std::make_pair(INT_MAX, INT_MAX);\n return;\n}\nvoid update(int k, P x) {\n k += n - 1;\n dat[k] = x;\n while (k > 0) {\n k = (k - 1) / 2;\n dat[k] = std::min(dat[k * 2 + 1], dat[k * 2 + 2]);\n }\n return;\n}\nP query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return std::make_pair(INT_MAX, INT_MAX);\n if (a <= l && r <= b)\n return dat[k];\n else {\n P vl = query(a, b, k * 2 + 1, l, (l + r) / 2);\n P vr = query(a, b, k * 2 + 2, (l + r) / 2, r);\n return std::min(vl, vr);\n }\n}\nint main() {\n int N, R, L;\n std::cin >> N >> R >> L;\n init(N);\n for (int i = 0; i != N; ++i)\n update(i, std::make_pair(0, i));\n int prevT = 0;\n for (int i = 0; i != R; ++i) {\n int d, t, x;\n std::cin >> d >> t >> x;\n --d;\n if (t != prevT) {\n P p = query(0, N, 0, 0, n);\n cnt[p.second] += t - prevT;\n }\n P p = query(d, d + 1, 0, 0, n);\n update(d, std::make_pair(p.first - x, p.second));\n prevT = t;\n }\n if (prevT != L) {\n P p = query(0, N, 0, 0, n);\n cnt[p.second] += L - prevT;\n }\n int t = -1, id;\n for (int i = 0; i != N; ++i) {\n if (t < cnt[i]) {\n t = cnt[i];\n id = i + 1;\n }\n }\n std::cout << id << std::endl;\n return 0;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 5424, "score_of_the_acc": -0.8299, "final_rank": 18 }, { "submission_id": "aoj_0282_7937777", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <utility>\n#define rep(i, a) for (int i = 0; i != (a); ++i)\ntypedef std::pair<int, int> P;\nconst int MAX_N = 1 << 17, INF = 1 << 30;\nint sz;\nP dat[2 * MAX_N - 1];\nvoid init(int n) {\n sz = 1;\n while (sz < n)\n sz <<= 1;\n rep(i, 2 * sz - 1) dat[i] = P(INF, INF);\n return;\n}\nvoid update(int k, P p) {\n k += sz - 1;\n dat[k] = p;\n while (k > 0) {\n k = (k - 1) >> 1;\n dat[k] = std::min(dat[2 * k + 1], dat[2 * k + 2]);\n }\n return;\n}\nP query(int a, int b, int k, int l, int r) {\n if (b <= l || r <= a)\n return P(INF, INF);\n if (a <= l && r <= b)\n return dat[k];\n else\n return std::min(query(a, b, 2 * k + 1, l, (l + r) >> 1),\n query(a, b, 2 * k + 2, (l + r) >> 1, r));\n}\nint N, R, L;\nint cnt[MAX_N];\nint main() {\n scanf(\"%d%d%d\", &N, &R, &L);\n init(N);\n rep(i, N) update(i, P(0, i));\n int prvT = 0;\n rep(i, R) {\n int d, t, x;\n scanf(\"%d%d%d\", &d, &t, &x);\n if (prvT != t)\n cnt[query(0, N, 0, 0, sz).second] += t - prvT;\n --d;\n P p = query(d, d + 1, 0, 0, sz);\n update(d, P(p.first - x, p.second));\n prvT = t;\n }\n if (L != prvT)\n cnt[query(0, N, 0, 0, sz).second] += L - prvT;\n printf(\"%d\\n\", std::max_element(cnt, cnt + N) - cnt + 1);\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 5016, "score_of_the_acc": -0.3255, "final_rank": 5 }, { "submission_id": "aoj_0282_7937758", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\n#define REP(i, n) for (int i = 0; i < n; i++)\n#define REP(j, n) for (int j = 0; j < n; j++)\nusing namespace std;\ntypedef pair<int, int> P;\nint main() {\n int n, r, l;\n cin >> n;\n cin >> r;\n cin >> l;\n int list[n + 1];\n int time[n + 1];\n for (int i = 0; i < n + 1; i++) {\n list[i] = 0;\n time[i] = 0;\n }\n int top = 0;\n int id = 1;\n int nowtime = 0;\n int timemax = 0;\n int timemaxid = 0;\n for (int i = 0; i < r; i++) {\n int d, t, x;\n cin >> d;\n cin >> t;\n cin >> x;\n time[id] += t - nowtime;\n if (time[id] > timemax) {\n timemax = time[id];\n timemaxid = id;\n }\n nowtime = t;\n list[d] += x;\n if (id == d) {\n top += x;\n }\n if (x < 0 && d == id) {\n for (int j = 1; j < n + 1; j++) {\n if (top < list[j] || (top == list[j] && j < id)) {\n top = list[j];\n id = j;\n }\n }\n }\n if (x > 0 && d != id) {\n if (top < list[d] || (top == list[d] && d < id)) {\n top = list[d];\n id = d;\n }\n }\n }\n time[id] += l - nowtime;\n if (time[id] > timemax) {\n timemax = time[id];\n timemaxid = id;\n }\n cout << timemaxid << \"\\n\";\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3872, "score_of_the_acc": -0.4671, "final_rank": 9 }, { "submission_id": "aoj_0282_7937757", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\n#define REP(i, n) for (int i = 0; i < n; i++)\n#define REP(j, n) for (int j = 0; j < n; j++)\nusing namespace std;\ntypedef pair<int, int> P;\nint lis[100000];\nint tim[100000];\nint main() {\n int n, r, l;\n scanf(\"%d %d %d\", &n, &r, &l);\n int top = 0;\n int id = 1;\n int nowtime = 0;\n int timemax = 0;\n int timemaxid = 0;\n for (int i = 0; i < r; i++) {\n int d, t, x;\n scanf(\"%d %d %d\", &d, &t, &x);\n tim[id] += t - nowtime;\n if (tim[id] > timemax) {\n timemax = tim[id];\n timemaxid = id;\n }\n nowtime = t;\n lis[d] += x;\n if (id == d) {\n top += x;\n }\n if (x < 0 && d == id) {\n for (int j = 1; j < n + 1; j++) {\n if (top < lis[j] || (top == lis[j] && j < id)) {\n top = lis[j];\n id = j;\n }\n }\n }\n if (x > 0 && d != id) {\n if (top < lis[d] || (top == lis[d] && d < id)) {\n top = lis[d];\n id = d;\n }\n }\n }\n tim[id] += l - nowtime;\n if (tim[id] > timemax) {\n timemax = tim[id];\n timemaxid = id;\n }\n printf(\"%d\\n\", timemaxid);\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3860, "score_of_the_acc": -0.0055, "final_rank": 2 }, { "submission_id": "aoj_0282_7937745", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct team {\n long long n, p, time;\n};\nbool operator<(const team &t1, const team &t2) {\n if (t1.p == t2.p) {\n return t1.n > t2.n;\n }\n return t1.p < t2.p;\n}\npriority_queue<team> q;\nteam tea[100001];\nint main() {\n long long n, r, l;\n cin >> n >> r >> l;\n for (int i = 1; i <= n; i++) {\n tea[i].n = i;\n tea[i].p = 0;\n tea[i].time = 0;\n q.push(tea[i]);\n }\n int d, t, x, btime = 0, bnum = 1;\n team tmp;\n for (int i = 0; i < r; i++) {\n cin >> d >> t >> x;\n tea[bnum].time += t - btime;\n tea[d].p += x;\n q.push(tea[d]);\n while (!q.empty()) {\n tmp = q.top();\n if (tmp.p == tea[tmp.n].p) {\n bnum = tmp.n;\n break;\n }\n q.pop();\n }\n btime = t;\n }\n tea[bnum].time += l - btime;\n int ans = 1;\n for (int i = 1; i <= n; i++) {\n ans = tea[i].time > tea[ans].time ? i : ans;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 29820, "score_of_the_acc": -0.8211, "final_rank": 17 }, { "submission_id": "aoj_0282_7937727", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct team {\n long long n, p, time;\n};\nbool operator<(const team &t1, const team &t2) {\n if (t1.p == t2.p) {\n return t1.n > t2.n;\n }\n return t1.p < t2.p;\n}\npriority_queue<team> q;\nteam tea[100001];\nint main() {\n long long n, r, l;\n cin >> n >> r >> l;\n for (int i = 1; i <= n; i++) {\n tea[i].n = i;\n tea[i].p = 0;\n tea[i].time = 0;\n q.push(tea[i]);\n }\n int d, t, x, btime = 0, bnum = 1;\n team tmp;\n for (int i = 0; i < r; i++) {\n scanf(\" %d %d %d\", &d, &t, &x);\n tea[bnum].time += t - btime;\n tea[d].p += x;\n q.push(tea[d]);\n while (!q.empty()) {\n tmp = q.top();\n if (tmp.p == tea[tmp.n].p) {\n bnum = tmp.n;\n break;\n }\n q.pop();\n }\n btime = t;\n }\n tea[bnum].time += l - btime;\n int ans = 1;\n for (int i = 1; i <= n; i++) {\n ans = tea[i].time > tea[ans].time ? i : ans;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 29900, "score_of_the_acc": -0.3604, "final_rank": 7 }, { "submission_id": "aoj_0282_7937710", "code_snippet": "#include <cstring>\n#include <iostream>\n#include <map>\n#define rep(i, a) for (int i = 0; i < (int)(a); i++)\n#define INIT(a) memset(a, 0, sizeof(a))\n#define fs first\n#define sc second\nusing namespace std;\ntypedef pair<int, int> P;\nconst int INF = 1e9 + 7;\nint v;\nP seg[4004000];\nvoid init(int n) {\n v = 1;\n while (v < n)\n v <<= 1;\n rep(i, 2 * v - 1) seg[i] = P(INF, INF);\n}\nvoid update(int x, P a) {\n x += v - 1;\n seg[x] = a;\n while (x) {\n x = (x - 1) / 2;\n seg[x] = min(seg[2 * x + 1], seg[2 * x + 2]);\n }\n}\nP query(int a, int b, int k, int l, int r) {\n if (b <= l || r <= a)\n return P(INF, INF);\n if (a <= l && r <= b)\n return seg[k];\n P ql = query(a, b, 2 * k + 1, l, (l + r) / 2);\n P qr = query(a, b, 2 * k + 2, (l + r) / 2, r);\n return min(ql, qr);\n}\nint main() {\n int n, r, l;\n int d, t, x, prv = 0;\n int len[1001000];\n INIT(len);\n cin >> n >> r >> l;\n init(n);\n rep(i, n) update(i, P(0, i));\n rep(i, r) {\n cin >> d >> t >> x;\n P tmp = query(0, n, 0, 0, v);\n len[tmp.sc] += t - prv;\n prv = t;\n update(d - 1, P(seg[d - 1 + v - 1].fs - x, d - 1));\n }\n len[query(0, n, 0, 0, v).sc] += l - prv;\n int ans = 0;\n rep(i, n) {\n if (len[ans] < len[i])\n ans = i;\n }\n cout << ans + 1 << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 38288, "score_of_the_acc": -1.0269, "final_rank": 19 }, { "submission_id": "aoj_0282_7937696", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <map>\n#define rep(i, a) for (int i = 0; i < (int)(a); i++)\n#define INIT(a) memset(a, 0, sizeof(a))\n#define fs first\n#define sc second\nusing namespace std;\ntypedef pair<int, int> P;\nconst int INF = 1e9 + 7;\nint v;\nP seg[4004000];\ninline void init(int n) {\n v = 1;\n while (v < n)\n v <<= 1;\n rep(i, 2 * v - 1) seg[i] = P(INF, INF);\n}\ninline void update(int x, P a) {\n x += v - 1;\n seg[x] = a;\n while (x) {\n x = (x - 1) >> 1;\n seg[x] = min(seg[2 * x + 1], seg[2 * x + 2]);\n }\n}\ninline P query(int a, int b, int k, int l, int r) {\n if (b <= l || r <= a)\n return P(INF, INF);\n if (a <= l && r <= b)\n return seg[k];\n P ql = query(a, b, 2 * k + 1, l, (l + r) / 2);\n P qr = query(a, b, 2 * k + 2, (l + r) / 2, r);\n return min(ql, qr);\n}\nint n, r, l;\nint d, t, x, prv = 0;\nint len[1001000];\nint main() {\n INIT(len);\n scanf(\"%d%d%d\", &n, &r, &l);\n init(n);\n rep(i, n) update(i, P(0, i));\n rep(i, r) {\n scanf(\"%d%d%d\", &d, &t, &x);\n P tmp = query(0, n, 0, 0, v);\n len[tmp.sc] += t - prv;\n prv = t;\n update(d - 1, P(seg[d - 1 + v - 1].fs - x, d - 1));\n }\n len[query(0, n, 0, 0, v).sc] += l - prv;\n int ans = 0;\n rep(i, n) {\n if (len[ans] < len[i])\n ans = i;\n }\n printf(\"%d\\n\", ans + 1);\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 38428, "score_of_the_acc": -0.5668, "final_rank": 12 }, { "submission_id": "aoj_0282_7937692", "code_snippet": "#include <cstdio>\nusing namespace std;\nint lis[100000];\nint tim[100000];\nint main() {\n int n, r, l;\n scanf(\"%d %d %d\", &n, &r, &l);\n int top = 0;\n int id = 1;\n int nowtime = 0;\n int timemax = 0;\n int timemaxid = 0;\n for (int i = 0; i < r; i++) {\n int d, t, x;\n scanf(\"%d %d %d\", &d, &t, &x);\n tim[id] += t - nowtime;\n if (tim[id] > timemax) {\n timemax = tim[id];\n timemaxid = id;\n }\n nowtime = t;\n lis[d] += x;\n if (id == d) {\n top += x;\n }\n if (x < 0 && d == id) {\n for (int j = 1; j < n + 1; j++) {\n if (top < lis[j] || (top == lis[j] && j < id)) {\n top = lis[j];\n id = j;\n }\n }\n }\n if (x > 0 && d != id) {\n if (top < lis[d] || (top == lis[d] && d < id)) {\n top = lis[d];\n id = d;\n }\n }\n }\n tim[id] += l - nowtime;\n if (tim[id] > timemax) {\n timemax = tim[id];\n timemaxid = id;\n }\n printf(\"%d\\n\", timemaxid);\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3348, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0282_7937690", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <queue>\nusing namespace std;\nint main() {\n int n, r, l, d, t, x, u = 0;\n scanf(\"%d%d%d\", &n, &r, &l);\n int m = 1;\n while (m < n) {\n m <<= 1;\n }\n vector<int> s(n), c(n), p(2 * m - 1, n - 1);\n for (int i = n - 1; i >= 0; --i) {\n p[i + m - 1] = i;\n }\n for (int i = m - 2; i >= 0; --i) {\n p[i] = p[i * 2 + 1];\n }\n for (int i = 0; i < r; ++i) {\n scanf(\"%d%d%d\", &d, &t, &x);\n c[p[0]] += t - u;\n u = t;\n s[d - 1] += x;\n d += m - 2;\n while (d > 0) {\n d = (d - 1) >> 1;\n p[d] = p[2 * d + (s[p[2 * d + 1]] >= s[p[2 * d + 2]] ? 1 : 2)];\n }\n }\n c[p[0]] += l - u;\n int ans = max_element(c.begin(), c.end()) - c.begin() + 1;\n printf(\"%d\\n\", ans);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 4224, "score_of_the_acc": -0.0863, "final_rank": 3 } ]
aoj_0275_cpp
鉄道路線 ある国の鉄道網に、自動改札を導入することになりました。導入にあたって難しい問題の一つは、与えられた切符で、指定された駅の間を移動できるかどうかを判定することです。それぞれの切符には乗車駅と降車駅が記載されています。この切符でできるのは、「乗車駅で乗って、降車駅で降りる」ことだけではなく、途中乗車や途中下車も許されています。 この鉄道網にはS 個の駅があり、そのうちR 組の駅は隣り合っていて、他の駅を経由せずに双方向に鉄道で移動することができます。隣り合った駅を結ぶ線路はひとつしかありません。隣り合った駅の間の距離は、この線路に沿って測った距離です。ある駅からある駅までの経路は鉄道網の形状によっては複数通り考えられますが、そのうち最も距離が短くなるような経路を最短経路と呼ぶことにします。そのような経路が複数ある場合、どちらも最短経路として認められます。 乗車駅 a、降車駅 b の切符で駅 c から駅 d まで移動できるのは、以下の条件をすべて満たす経路 p が存在するときです。 経路 p は、駅 a から駅 b への最短経路である。 経路 p は、駅 a から出発し、駅 c、駅 d の順に経由し、駅 b で終わる経路である。また、駅 c から駅 d の区間はこの2 駅の最短経路になっている。 路線図と切符の情報が与えられます。次に、始点と終点の組がいくつか与えられるので、その切符で始点から終点へ移動できるかどうかを判定するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 S R u 1 v 1 w 1 u 2 v 2 w 2 : u R v R w R a b Q c 1 d 1 : c Q d Q 各行で与えられる数値は1つの空白で区切られている。 1行目は2つの整数からなる。S (2 ≤ S ≤ 100000) は鉄道路線図に現れる駅の数、R (1 ≤ R ≤ 200000) は隣り合った駅の組の数である。続く R 行に、隣り合った駅の間を直接つなぐ線路の情報が与えられる。u i と v i (1 ≤ u i , v i ≤ S) は i 番目の線路の両端の駅の番号を示す。w i (1 ≤ w i ≤ 1000) はこれらの駅の間の距離を表す整数である。ただし、各駅には 1 から S までの番号が重複なく割り振られており、u i ≠ v i とする。 続く1行は3つの整数からなる。最初の2つの整数は切符の区間を表し、a は乗車駅、b は降車駅 (1 ≤ a, b ≤ S) である。3つ目の整数 Q (1 ≤ Q ≤ 40000) は質問の数を示す。続く Q 行に質問が与えられる。 c i とd i (1 ≤ c i , d i ≤ S)は i 番目の質問の乗車駅と降車駅を示す。ただし、a ≠ b、c i ≠ d i とする。 出力 質問ごとに、与えられた切符で移動できるなら Yes を、できないなら No を1行に出力する。 入力例 6 7 1 2 3 1 4 1 2 3 5 4 3 1 3 6 2 4 5 2 5 6 1 1 6 6 1 6 4 3 4 6 5 6 2 6 2 5 出力例 Yes Yes Yes Yes No No
[ { "submission_id": "aoj_0275_10170526", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n ll nxt = g[i][j].first;\n ll cost = g[i][j].second;\n if (d[i] == inf || d[nxt] == inf)\n {\n continue;\n }\n if (drev[i] == inf || drev[nxt] == inf)\n {\n continue;\n }\n if (d[i] + cost + drev[nxt] == d[B])\n {\n g_short[i].push_back(nxt);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ull> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i + j >= Q)\n {\n continue;\n }\n C[queries[i + j].first] |= (1ULL << (ull)j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i + j >= Q)\n {\n continue;\n }\n F[i + j] = (C[queries[i + j].second] >> (ull)j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n if (F[i] == 1)\n {\n cout << \"Yes\" << endl;\n }\n else\n {\n cout << \"No\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 71232, "score_of_the_acc": -1.2529, "final_rank": 7 }, { "submission_id": "aoj_0275_10170125", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ull> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] |= (1ULL << (ull)j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> (ull)j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n if (F[i] == 1)\n {\n cout << \"Yes\"<<Endl;\n }\n else\n {\n cout << \"No\"<<endl;\n }\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 70, "memory_kb": 28784, "score_of_the_acc": -0.3243, "final_rank": 17 }, { "submission_id": "aoj_0275_10168702", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ull> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 60;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] |= (1ULL << (ull)j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> (ull)j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i]==1, \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 50, "memory_kb": 29092, "score_of_the_acc": -0.3065, "final_rank": 14 }, { "submission_id": "aoj_0275_10168701", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ull> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] |= (1ULL << (ull)j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> (ull)j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i]==1, \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 50, "memory_kb": 29088, "score_of_the_acc": -0.3064, "final_rank": 13 }, { "submission_id": "aoj_0275_10168700", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ull> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ull WS = 64;\n ull N = G.size();\n for (ull i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] |= (1ULL << j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i]==1, \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 50, "memory_kb": 29092, "score_of_the_acc": -0.3065, "final_rank": 14 }, { "submission_id": "aoj_0275_10168694", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<ll> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ull> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] |= (1ULL << j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> j) & (1ULL);\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i]==1, \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 50, "memory_kb": 29092, "score_of_the_acc": -0.3065, "final_rank": 14 }, { "submission_id": "aoj_0275_10168675", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G;\n vector<ll> ar;\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<bool> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ll> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] += (1LL << j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> j) & 1;\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i], \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 40, "memory_kb": 29088, "score_of_the_acc": -0.2949, "final_rank": 12 }, { "submission_id": "aoj_0275_10168668", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n// グラフを与えると[集約後のグラフh]と[元の頂点iがhにおける頂点ar[i]になるようなar]のpairを返す\npair<vector<vector<ll>>, vector<ll>> scc(vector<vector<ll>> in)\n{\n static vector<vector<ll>> g = in;\n static ll n = g.size();\n static vector<vector<ll>> g_rev(n);\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n g_rev[g[i][j]].push_back(i);\n }\n }\n static vector<bool> F(n, false);\n static vector<ll> T(n);\n static ll cnt = 0;\n static vector<bool> G(n);\n static vector<ll> ar(n);\n static ll v = 0;\n struct\n {\n void dfs(ll now)\n {\n F[now] = true;\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i];\n if (!F[nxt])\n {\n dfs(nxt);\n }\n }\n T[n - 1 - cnt] = now;\n cnt++;\n }\n void dfs2(ll now)\n {\n G[now] = true;\n ar[now] = v;\n rep(i, 0, g_rev[now].size())\n {\n ll nxt = g_rev[now][i];\n if (!G[nxt])\n {\n dfs2(nxt);\n }\n }\n }\n } I;\n rep(i, 0, n)\n {\n if (!F[i])\n {\n I.dfs(i);\n }\n }\n rep(i, 0, n)\n {\n if (!G[T[i]])\n {\n I.dfs2(T[i]);\n v++;\n }\n }\n vector<vector<ll>> h(v);\n unordered_map<pair<ll, ll>, bool> mp;\n rep(i, 0, n)\n {\n rep(j, 0, g[i].size())\n {\n ll A = ar[i];\n ll B = ar[g[i][j]];\n if (A != B && !mp[pr(A, B)])\n {\n mp[pr(A, B)] = true;\n h[A].push_back(B);\n }\n }\n }\n return pr(h, ar);\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll s, r;\n cin >> s >> r;\n vector<vector<pair<ll, ll>>> g(s);\n rep(i, 0, r)\n {\n ll u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n g[u].push_back(pr(v, w));\n g[v].push_back(pr(u, w));\n }\n ll A, B, Q;\n cin >> A >> B >> Q;\n A--;\n B--;\n vector<vector<ll>> g_short(s); // 最短経路グラフ\n vector<ll> d(s, inf), drev(s, inf);\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>> que;\n que.emplace(pr(0, A));\n d[A] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != d[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (d[nxt] > D + cost)\n {\n d[nxt] = d[now] + cost;\n que.emplace(pr(d[nxt], nxt));\n }\n }\n }\n que.emplace(pr(0, B));\n drev[B] = 0;\n while (!que.empty())\n {\n ll now, D;\n tie(D, now) = que.top();\n que.pop();\n if (D != drev[now])\n {\n continue;\n }\n rep(i, 0, g[now].size())\n {\n ll nxt = g[now][i].first;\n ll cost = g[now][i].second;\n if (drev[nxt] > D + cost)\n {\n drev[nxt] = D + cost;\n que.emplace(pr(drev[nxt], nxt));\n }\n }\n }\n rep(i, 0, s)\n {\n rep(j, 0, g[i].size())\n {\n if (d[i] + g[i][j].second + drev[g[i][j].first] == d[B])\n {\n g_short[i].push_back(g[i][j].first);\n }\n }\n }\n vector<vector<ll>> G(s);\n vector<ll> ar(s);\n tie(G, ar) = scc(g_short);\n vector<pair<ll, ll>> queries;\n vector<bool> F(Q);\n rep(i, 0, Q)\n {\n ll c, d;\n cin >> c >> d;\n c--;\n d--;\n queries.push_back(pr(ar[c], ar[d]));\n }\n ll WS = 64;\n ll N = G.size();\n for (ll i = 0; i < Q; i += WS)\n {\n vector<ll> C(N);\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n C[queries[i * WS + j].first] += (1LL << j);\n }\n rep(j, 0, N)\n {\n rep(k, 0, G[j].size())\n {\n ll nxt = G[j][k];\n C[nxt] |= C[j];\n }\n }\n rep(j, 0, WS)\n {\n if (i * WS + j >= Q)\n {\n continue;\n }\n F[i * WS + j] = (C[queries[i * WS + j].second] >> j) & 1;\n }\n }\n rep(i, 0, Q)\n {\n jge(F[i], \"Yes\", \"No\");\n }\n}", "accuracy": 0.6666666666666666, "time_ms": 50, "memory_kb": 31908, "score_of_the_acc": -0.3536, "final_rank": 18 }, { "submission_id": "aoj_0275_7817577", "code_snippet": "#line 1 \"main.cpp\"\n#define PROBLEM \"https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0275\"\n#line 1 \"library/my_template.hpp\"\n#if defined(LOCAL)\n#include <my_template_compiled.hpp>\n#else\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'000'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n// https://trap.jp/post/1224/\n#define FOR1(a) for (ll _ = 0; _ < ll(a); ++_)\n#define FOR2(i, a) for (ll i = 0; i < ll(a); ++i)\n#define FOR3(i, a, b) for (ll i = a; i < ll(b); ++i)\n#define FOR4(i, a, b, c) for (ll i = a; i < ll(b); i += (c))\n#define FOR1_R(a) for (ll i = (a)-1; i >= ll(0); --i)\n#define FOR2_R(i, a) for (ll i = (a)-1; i >= ll(0); --i)\n#define FOR3_R(i, a, b) for (ll i = (b)-1; i >= ll(a); --i)\n#define overload4(a, b, c, d, e, ...) e\n#define overload3(a, b, c, d, ...) d\n#define FOR(...) overload4(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)(__VA_ARGS__)\n#define FOR_R(...) overload3(__VA_ARGS__, FOR3_R, FOR2_R, FOR1_R)(__VA_ARGS__)\n\n#define FOR_subset(t, s) \\\n for (ll t = (s); t >= 0; t = (t == 0 ? -1 : (t - 1) & (s)))\n#define all(x) x.begin(), x.end()\n#define len(x) ll(x.size())\n#define elif else if\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n\nint popcnt(int x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(ll x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2)\nint topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(u32 x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nint topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2)\nint lowbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(u32 x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nint lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T, typename U>\nT ceil(T x, U y) {\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U>\nT floor(T x, U y) {\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T, typename U>\npair<T, T> divmod(T x, U y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate <typename T, typename U>\nT SUM(const vector<U> &A) {\n T sum = 0;\n for (auto &&a: A) sum += a;\n return sum;\n}\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n assert(!que.empty());\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n assert(!que.empty());\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n tie(ok, ng) = (check(x) ? mp(x, ng) : mp(ok, x));\n }\n return ok;\n}\ntemplate <typename F>\ndouble binary_search_real(F check, double ok, double ng, int iter = 100) {\n FOR(iter) {\n double x = (ok + ng) / 2;\n tie(ok, ng) = (check(x) ? mp(x, ng) : mp(ok, x));\n }\n return (ok + ng) / 2;\n}\n\ntemplate <class T, class S>\ninline bool chmax(T &a, const S &b) {\n return (a < b ? a = b, 1 : 0);\n}\ntemplate <class T, class S>\ninline bool chmin(T &a, const S &b) {\n return (a > b ? a = b, 1 : 0);\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n FOR(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvector<T> cumsum(vector<U> &A, int off = 1) {\n int N = A.size();\n vector<T> B(N + 1);\n FOR(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvector<int> argsort(const vector<T> &A) {\n vector<int> ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](int i, int j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vc<int> &I) {\n vc<T> B(len(I));\n FOR(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n#endif\n#line 1 \"library/other/io.hpp\"\n// based on yosupo's fastio\n#include <unistd.h>\n\nnamespace fastio {\n#define FASTIO\n// クラスが read(), print() を持っているかを判定するメタ関数\nstruct has_write_impl {\n template <class T>\n static auto check(T &&x) -> decltype(x.write(), std::true_type{});\n\n template <class T>\n static auto check(...) -> std::false_type;\n};\n\ntemplate <class T>\nclass has_write : public decltype(has_write_impl::check<T>(std::declval<T>())) {\n};\n\nstruct has_read_impl {\n template <class T>\n static auto check(T &&x) -> decltype(x.read(), std::true_type{});\n\n template <class T>\n static auto check(...) -> std::false_type;\n};\n\ntemplate <class T>\nclass has_read : public decltype(has_read_impl::check<T>(std::declval<T>())) {};\n\nstruct Scanner {\n FILE *fp;\n char line[(1 << 15) + 1];\n size_t st = 0, ed = 0;\n void reread() {\n memmove(line, line + st, ed - st);\n ed -= st;\n st = 0;\n ed += fread(line + ed, 1, (1 << 15) - ed, fp);\n line[ed] = '\\0';\n }\n bool succ() {\n while (true) {\n if (st == ed) {\n reread();\n if (st == ed) return false;\n }\n while (st != ed && isspace(line[st])) st++;\n if (st != ed) break;\n }\n if (ed - st <= 50) {\n bool sep = false;\n for (size_t i = st; i < ed; i++) {\n if (isspace(line[i])) {\n sep = true;\n break;\n }\n }\n if (!sep) reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_same<T, string>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n while (true) {\n size_t sz = 0;\n while (st + sz < ed && !isspace(line[st + sz])) sz++;\n ref.append(line + st, sz);\n st += sz;\n if (!sz || st != ed) break;\n reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n bool neg = false;\n if (line[st] == '-') {\n neg = true;\n st++;\n }\n ref = T(0);\n while (isdigit(line[st])) { ref = 10 * ref + (line[st++] & 0xf); }\n if (neg) ref = -ref;\n return true;\n }\n template <typename T,\n typename enable_if<has_read<T>::value>::type * = nullptr>\n inline bool read_single(T &x) {\n x.read();\n return true;\n }\n bool read_single(double &ref) {\n string s;\n if (!read_single(s)) return false;\n ref = std::stod(s);\n return true;\n }\n bool read_single(char &ref) {\n string s;\n if (!read_single(s) || s.size() != 1) return false;\n ref = s[0];\n return true;\n }\n template <class T>\n bool read_single(vector<T> &ref) {\n for (auto &d: ref) {\n if (!read_single(d)) return false;\n }\n return true;\n }\n template <class T, class U>\n bool read_single(pair<T, U> &p) {\n return (read_single(p.first) && read_single(p.second));\n }\n template <size_t N = 0, typename T>\n void read_single_tuple(T &t) {\n if constexpr (N < std::tuple_size<T>::value) {\n auto &x = std::get<N>(t);\n read_single(x);\n read_single_tuple<N + 1>(t);\n }\n }\n template <class... T>\n bool read_single(tuple<T...> &tpl) {\n read_single_tuple(tpl);\n return true;\n }\n void read() {}\n template <class H, class... T>\n void read(H &h, T &... t) {\n bool f = read_single(h);\n assert(f);\n read(t...);\n }\n Scanner(FILE *fp) : fp(fp) {}\n};\n\nstruct Printer {\n Printer(FILE *_fp) : fp(_fp) {}\n ~Printer() { flush(); }\n\n static constexpr size_t SIZE = 1 << 15;\n FILE *fp;\n char line[SIZE], small[50];\n size_t pos = 0;\n void flush() {\n fwrite(line, 1, pos, fp);\n pos = 0;\n }\n void write(const char val) {\n if (pos == SIZE) flush();\n line[pos++] = val;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n void write(T val) {\n if (pos > (1 << 15) - 50) flush();\n if (val == 0) {\n write('0');\n return;\n }\n if (val < 0) {\n write('-');\n val = -val; // todo min\n }\n size_t len = 0;\n while (val) {\n small[len++] = char(0x30 | (val % 10));\n val /= 10;\n }\n for (size_t i = 0; i < len; i++) { line[pos + i] = small[len - 1 - i]; }\n pos += len;\n }\n void write(const string s) {\n for (char c: s) write(c);\n }\n void write(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++) write(s[i]);\n }\n void write(const double x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n void write(const long double x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n template <typename T,\n typename enable_if<has_write<T>::value>::type * = nullptr>\n inline void write(T x) {\n x.write();\n }\n template <class T>\n void write(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n template <class T, class U>\n void write(const pair<T, U> val) {\n write(val.first);\n write(' ');\n write(val.second);\n }\n template <size_t N = 0, typename T>\n void write_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { write(' '); }\n const auto x = std::get<N>(t);\n write(x);\n write_tuple<N + 1>(t);\n }\n }\n template <class... T>\n bool write(tuple<T...> tpl) {\n write_tuple(tpl);\n return true;\n }\n template <class T, size_t S>\n void write(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n void write(i128 val) {\n string s;\n bool negative = 0;\n if (val < 0) {\n negative = 1;\n val = -val;\n }\n while (val) {\n s += '0' + int(val % 10);\n val /= 10;\n }\n if (negative) s += \"-\";\n reverse(all(s));\n if (len(s) == 0) s = \"0\";\n write(s);\n }\n};\nScanner scanner = Scanner(stdin);\nPrinter printer = Printer(stdout);\nvoid flush() { printer.flush(); }\nvoid print() { printer.write('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n printer.write(head);\n if (sizeof...(Tail)) printer.write(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid read() {}\ntemplate <class Head, class... Tail>\nvoid read(Head &head, Tail &... tail) {\n scanner.read(head);\n read(tail...);\n}\n} // namespace fastio\nusing fastio::print;\nusing fastio::flush;\nusing fastio::read;\n\n#define INT(...) \\\n int __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define CHAR(...) \\\n char __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n read(__VA_ARGS__)\n\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n read(name)\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n read(name)\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\n#line 2 \"library/graph/base.hpp\"\n\ntemplate <typename T>\nstruct Edge {\n int frm, to;\n T cost;\n int id;\n};\n\ntemplate <typename T = int, bool directed = false>\nstruct Graph {\n int N, M;\n using cost_type = T;\n using edge_type = Edge<T>;\n vector<edge_type> edges;\n vector<int> indptr;\n vector<edge_type> csr_edges;\n vc<int> vc_deg, vc_indeg, vc_outdeg;\n bool prepared;\n\n class OutgoingEdges {\n public:\n OutgoingEdges(const Graph* G, int l, int r) : G(G), l(l), r(r) {}\n\n const edge_type* begin() const {\n if (l == r) { return 0; }\n return &G->csr_edges[l];\n }\n\n const edge_type* end() const {\n if (l == r) { return 0; }\n return &G->csr_edges[r];\n }\n\n private:\n const Graph* G;\n int l, r;\n };\n\n bool is_prepared() { return prepared; }\n constexpr bool is_directed() { return directed; }\n\n Graph() : N(0), M(0), prepared(0) {}\n Graph(int N) : N(N), M(0), prepared(0) {}\n\n void build(int n) {\n N = n, M = 0;\n prepared = 0;\n edges.clear();\n indptr.clear();\n csr_edges.clear();\n vc_deg.clear();\n vc_indeg.clear();\n vc_outdeg.clear();\n }\n\n void add(int frm, int to, T cost = 1, int i = -1) {\n assert(!prepared);\n assert(0 <= frm && 0 <= to && to < N);\n if (i == -1) i = M;\n auto e = edge_type({frm, to, cost, i});\n edges.eb(e);\n ++M;\n }\n\n // wt, off\n void read_tree(bool wt = false, int off = 1) { read_graph(N - 1, wt, off); }\n\n void read_graph(int M, bool wt = false, int off = 1) {\n for (int m = 0; m < M; ++m) {\n INT(a, b);\n a -= off, b -= off;\n if (!wt) {\n add(a, b);\n } else {\n T c;\n read(c);\n add(a, b, c);\n }\n }\n build();\n }\n\n void build() {\n assert(!prepared);\n prepared = true;\n indptr.assign(N + 1, 0);\n for (auto&& e: edges) {\n indptr[e.frm + 1]++;\n if (!directed) indptr[e.to + 1]++;\n }\n for (int v = 0; v < N; ++v) { indptr[v + 1] += indptr[v]; }\n auto counter = indptr;\n csr_edges.resize(indptr.back() + 1);\n for (auto&& e: edges) {\n csr_edges[counter[e.frm]++] = e;\n if (!directed)\n csr_edges[counter[e.to]++] = edge_type({e.to, e.frm, e.cost, e.id});\n }\n }\n\n OutgoingEdges operator[](int v) const {\n assert(prepared);\n return {this, indptr[v], indptr[v + 1]};\n }\n\n vc<int> deg_array() {\n if (vc_deg.empty()) calc_deg();\n return vc_deg;\n }\n\n pair<vc<int>, vc<int>> deg_array_inout() {\n if (vc_indeg.empty()) calc_deg_inout();\n return {vc_indeg, vc_outdeg};\n }\n\n int deg(int v) {\n if (vc_deg.empty()) calc_deg();\n return vc_deg[v];\n }\n\n int in_deg(int v) {\n if (vc_indeg.empty()) calc_deg_inout();\n return vc_indeg[v];\n }\n\n int out_deg(int v) {\n if (vc_outdeg.empty()) calc_deg_inout();\n return vc_outdeg[v];\n }\n\n void debug() {\n print(\"Graph\");\n if (!prepared) {\n print(\"frm to cost id\");\n for (auto&& e: edges) print(e.frm, e.to, e.cost, e.id);\n } else {\n print(\"indptr\", indptr);\n print(\"frm to cost id\");\n FOR(v, N) for (auto&& e: (*this)[v]) print(e.frm, e.to, e.cost, e.id);\n }\n }\n\n // G における頂点 V[i] が、新しいグラフで i になるようにする\n // {G, es}\n pair<Graph<T, directed>, vc<int>> rearrange(vc<int> V) {\n int n = len(V);\n map<int, int> MP;\n FOR(i, n) MP[V[i]] = i;\n set<int> used;\n Graph<T, directed> G(n);\n vc<int> es;\n FOR(i, n) {\n for (auto&& e: (*this)[V[i]]) {\n if (used.count(e.id)) continue;\n int a = e.frm, b = e.to;\n if (MP.count(a) && MP.count(b)) {\n used.insert(e.id);\n G.add(MP[a], MP[b], e.cost);\n es.eb(e.id);\n }\n }\n }\n G.build();\n return {G, es};\n }\n\nprivate:\n void calc_deg() {\n assert(vc_deg.empty());\n vc_deg.resize(N);\n for (auto&& e: edges) vc_deg[e.frm]++, vc_deg[e.to]++;\n }\n\n void calc_deg_inout() {\n assert(vc_indeg.empty());\n vc_indeg.resize(N);\n vc_outdeg.resize(N);\n for (auto&& e: edges) { vc_indeg[e.to]++, vc_outdeg[e.frm]++; }\n }\n};\n#line 3 \"library/graph/strongly_connected_component.hpp\"\n\ntemplate <typename Graph>\npair<int, vc<int>> strongly_connected_component(Graph& G) {\n assert(G.is_directed());\n assert(G.is_prepared());\n int N = G.N;\n int C = 0;\n vc<int> comp(N);\n vc<int> low(N);\n vc<int> ord(N, -1);\n vc<int> visited;\n int now = 0;\n\n auto dfs = [&](auto self, int v) -> void {\n low[v] = now;\n ord[v] = now;\n ++now;\n visited.eb(v);\n for (auto&& [frm, to, cost, id]: G[v]) {\n if (ord[to] == -1) {\n self(self, to);\n chmin(low[v], low[to]);\n } else {\n chmin(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (1) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = N;\n comp[u] = C;\n if (u == v) break;\n }\n ++C;\n }\n };\n FOR(v, N) {\n if (ord[v] == -1) dfs(dfs, v);\n }\n FOR(v, N) comp[v] = C - 1 - comp[v];\n return {C, comp};\n}\n\ntemplate <typename GT>\nGraph<int, 1> scc_dag(GT& G, int C, vc<int>& comp) {\n Graph<int, 1> DAG(C);\n vvc<int> edges(C);\n for (auto&& e: G.edges) {\n int x = comp[e.frm], y = comp[e.to];\n if (x == y) continue;\n edges[x].eb(y);\n }\n FOR(c, C) {\n UNIQUE(edges[c]);\n for (auto&& to: edges[c]) DAG.add(c, to);\n }\n DAG.build();\n return DAG;\n}\n#line 3 \"library/graph/reachability.hpp\"\n\n// 有向グラフの到達可能性クエリ。O((N+M)Q/w)。\ntemplate <typename GT, typename P>\nvc<int> reachability(GT& G, vc<P> query) {\n auto [C, comp] = strongly_connected_component(G);\n Graph<int, 1> DAG(C);\n for (auto&& e: G.edges) {\n auto a = comp[e.frm], b = comp[e.to];\n assert(a <= b);\n if (a < b) DAG.add(a, b);\n }\n DAG.build();\n\n int Q = len(query);\n vc<u64> dp(C);\n vc<int> res(Q);\n for (int l = 0; l < Q; l += 64) {\n int r = min(l + 64, Q);\n fill(all(dp), u64(0));\n\n FOR3(qid, l, r) {\n auto v = comp[query[qid].fi];\n dp[v] |= u64(1) << (qid - l);\n }\n FOR(v, C) for (auto&& e: DAG[v]) { dp[e.to] |= dp[v]; }\n FOR3(qid, l, r) {\n auto v = comp[query[qid].se];\n if (dp[v] & (u64(1) << (qid - l))) res[qid] = 1;\n }\n }\n return res;\n}\n#line 3 \"library/graph/shortest_path/dijkstra.hpp\"\n\ntemplate <typename T, typename GT>\npair<vc<T>, vc<int>> dijkstra(GT& G, int v) {\n auto N = G.N;\n vector<T> dist(N, infty<T>);\n vector<int> par(N, -1);\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n dist[v] = 0;\n que.emplace(0, v);\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n par[e.to] = e.frm;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return {dist, par};\n}\n\n// 多点スタート。[dist, par, root]\ntemplate <typename T, typename GT>\ntuple<vc<T>, vc<int>, vc<int>> dijkstra(GT& G, vc<int> vs) {\n assert(G.is_prepared());\n int N = G.N;\n vc<ll> dist(N, infty<T>);\n vc<int> par(N, -1);\n vc<int> root(N, -1);\n\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n for (auto&& v: vs) {\n dist[v] = 0;\n root[v] = v;\n que.emplace(T(0), v);\n }\n\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n root[e.to] = root[e.frm];\n par[e.to] = e.frm;\n que.push(mp(dist[e.to], e.to));\n }\n }\n }\n return {dist, par, root};\n}\n#line 6 \"main.cpp\"\n\nvoid solve() {\n LL(N, M);\n Graph<int, 0> G(N);\n G.read_graph(M, 1);\n LL(a, b);\n --a, --b;\n\n auto [dist_a, par_a] = dijkstra<int>(G, a);\n auto [dist_b, par_b] = dijkstra<int>(G, b);\n\n Graph<int, 1> DG(N);\n ll d = dist_a[b];\n for (auto&& e: G.edges) {\n if (dist_a[e.frm] + e.cost + dist_b[e.to] == d) DG.add(e.frm, e.to);\n if (dist_b[e.frm] + e.cost + dist_a[e.to] == d) DG.add(e.to, e.frm);\n }\n DG.build();\n\n LL(Q);\n VEC(pi, query, Q);\n for (auto&& [a, b]: query) --a, --b;\n auto res = reachability(DG, query);\n for (auto&& yn: res) Yes(yn);\n}\n\nsigned main() {\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 44928, "score_of_the_acc": -0.7208, "final_rank": 3 }, { "submission_id": "aoj_0275_6560430", "code_snippet": "#line 1 \"main.cpp\"\n#define PROBLEM \"https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0275\"\n#line 1 \"/home/maspy/compro/library/my_template.hpp\"\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\n\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define FOR_(n) for (ll _ = 0; (_) < (ll)(n); ++(_))\n#define FOR(i, n) for (ll i = 0; (i) < (ll)(n); ++(i))\n#define FOR3(i, m, n) for (ll i = (m); (i) < (ll)(n); ++(i))\n#define FOR_R(i, n) for (ll i = (ll)(n)-1; (i) >= 0; --(i))\n#define FOR3_R(i, m, n) for (ll i = (ll)(n)-1; (i) >= (ll)(m); --(i))\n#define FOR_subset(t, s) for (ll t = s; t >= 0; t = (t == 0 ? -1 : (t - 1) & s))\n#define all(x) x.begin(), x.end()\n#define len(x) ll(x.size())\n#define elif else if\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n\ntemplate <typename T>\nT SUM(vector<T> &A) {\n T sum = T(0);\n for (auto &&a: A) sum += a;\n return sum;\n}\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\nint popcnt(int x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(ll x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2)\nint topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(u32 x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nint topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2)\nint lowbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(u32 x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nint lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T, typename U>\nT ceil(T x, U y) {\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <typename T, typename U>\nT floor(T x, U y) {\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\n\ntemplate <typename T, typename U>\npair<T, T> divmod(T x, U y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\nll binary_search(function<bool(ll)> check, ll ok, ll ng) {\n assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n if (check(x))\n ok = x;\n else\n ng = x;\n }\n return ok;\n}\n\ntemplate <class T, class S>\ninline bool chmax(T &a, const S &b) {\n return (a < b ? a = b, 1 : 0);\n}\ntemplate <class T, class S>\ninline bool chmin(T &a, const S &b) {\n return (a > b ? a = b, 1 : 0);\n}\n\nvi s_to_vi(const string& S, char first_char) {\n vi A(S.size());\n FOR(i, S.size()) { A[i] = S[i] - first_char; }\n return A;\n}\n\ntemplate <typename T>\nvector<T> cumsum(vector<T> &A, int off = 1) {\n int N = A.size();\n vector<T> B(N + 1);\n FOR(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\ntemplate <typename CNT, typename T>\nvc<CNT> bincount(const vc<T> &A, int size) {\n vc<CNT> C(size);\n for (auto &&x: A) { ++C[x]; }\n return C;\n}\n\ntemplate <typename T>\nvector<int> argsort(const vector<T> &A) {\n // stable\n vector<int> ids(A.size());\n iota(all(ids), 0);\n sort(all(ids),\n [&](int i, int j) { return A[i] < A[j] || (A[i] == A[j] && i < j); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vc<int> &I) {\n int n = len(A);\n assert(len(I) == n);\n vc<T> B(n);\n FOR(i, n) B[i] = A[I[i]];\n return B;\n}\n#line 1 \"/home/maspy/compro/library/other/io.hpp\"\n// based on yosupo's fastio\n#include <unistd.h>\n\nnamespace detail {\ntemplate <typename T, decltype(&T::is_modint) = &T::is_modint>\nstd::true_type check_value(int);\ntemplate <typename T>\nstd::false_type check_value(long);\n} // namespace detail\n\ntemplate <typename T>\nstruct is_modint : decltype(detail::check_value<T>(0)) {};\ntemplate <typename T>\nusing is_modint_t = enable_if_t<is_modint<T>::value>;\ntemplate <typename T>\nusing is_not_modint_t = enable_if_t<!is_modint<T>::value>;\n\nstruct Scanner {\n FILE *fp;\n char line[(1 << 15) + 1];\n size_t st = 0, ed = 0;\n void reread() {\n memmove(line, line + st, ed - st);\n ed -= st;\n st = 0;\n ed += fread(line + ed, 1, (1 << 15) - ed, fp);\n line[ed] = '\\0';\n }\n bool succ() {\n while (true) {\n if (st == ed) {\n reread();\n if (st == ed) return false;\n }\n while (st != ed && isspace(line[st])) st++;\n if (st != ed) break;\n }\n if (ed - st <= 50) {\n bool sep = false;\n for (size_t i = st; i < ed; i++) {\n if (isspace(line[i])) {\n sep = true;\n break;\n }\n }\n if (!sep) reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_same<T, string>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n while (true) {\n size_t sz = 0;\n while (st + sz < ed && !isspace(line[st + sz])) sz++;\n ref.append(line + st, sz);\n st += sz;\n if (!sz || st != ed) break;\n reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n bool neg = false;\n if (line[st] == '-') {\n neg = true;\n st++;\n }\n ref = T(0);\n while (isdigit(line[st])) { ref = 10 * ref + (line[st++] & 0xf); }\n if (neg) ref = -ref;\n return true;\n }\n template <class T, is_modint_t<T> * = nullptr>\n bool read_single(T &ref) {\n long long val = 0;\n bool f = read_single(val);\n ref = T(val);\n return f;\n }\n bool read_single(double &ref) {\n string s;\n if (!read_single(s)) return false;\n ref = std::stod(s);\n return true;\n }\n bool read_single(char &ref) {\n string s;\n if (!read_single(s) || s.size() != 1) return false;\n ref = s[0];\n return true;\n }\n template <class T>\n bool read_single(vector<T> &ref) {\n for (auto &d: ref) {\n if (!read_single(d)) return false;\n }\n return true;\n }\n template <class T, class U>\n bool read_single(pair<T, U> &p) {\n return (read_single(p.first) && read_single(p.second));\n }\n template <class A, class B, class C>\n bool read_single(tuple<A, B, C> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)));\n }\n template <class A, class B, class C, class D>\n bool read_single(tuple<A, B, C, D> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)) && read_single(get<3>(p)));\n }\n void read() {}\n template <class H, class... T>\n void read(H &h, T &... t) {\n bool f = read_single(h);\n assert(f);\n read(t...);\n }\n Scanner(FILE *fp) : fp(fp) {}\n};\n\nstruct Printer {\n Printer(FILE *_fp) : fp(_fp) {}\n ~Printer() { flush(); }\n\n static constexpr size_t SIZE = 1 << 15;\n FILE *fp;\n char line[SIZE], small[50];\n size_t pos = 0;\n void flush() {\n fwrite(line, 1, pos, fp);\n pos = 0;\n }\n void write(const char &val) {\n if (pos == SIZE) flush();\n line[pos++] = val;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n void write(T val) {\n if (pos > (1 << 15) - 50) flush();\n if (val == 0) {\n write('0');\n return;\n }\n if (val < 0) {\n write('-');\n val = -val; // todo min\n }\n size_t len = 0;\n while (val) {\n small[len++] = char(0x30 | (val % 10));\n val /= 10;\n }\n for (size_t i = 0; i < len; i++) { line[pos + i] = small[len - 1 - i]; }\n pos += len;\n }\n void write(const string &s) {\n for (char c: s) write(c);\n }\n void write(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++) write(s[i]);\n }\n void write(const double &x) {\n ostringstream oss;\n oss << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n void write(const long double &x) {\n ostringstream oss;\n oss << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n template <class T, is_modint_t<T> * = nullptr>\n void write(T &ref) {\n write(ref.val);\n }\n template <class T>\n void write(const vector<T> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n template <class T, class U>\n void write(const pair<T, U> &val) {\n write(val.first);\n write(' ');\n write(val.second);\n }\n template <class A, class B, class C>\n void write(const tuple<A, B, C> &val) {\n auto &[a, b, c] = val;\n write(a), write(' '), write(b), write(' '), write(c);\n }\n template <class A, class B, class C, class D>\n void write(const tuple<A, B, C, D> &val) {\n auto &[a, b, c, d] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d);\n }\n template <class A, class B, class C, class D, class E>\n void write(const tuple<A, B, C, D, E> &val) {\n auto &[a, b, c, d, e] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e);\n }\n template <class A, class B, class C, class D, class E, class F>\n void write(const tuple<A, B, C, D, E, F> &val) {\n auto &[a, b, c, d, e, f] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e), write(' '), write(f);\n }\n template <class T, size_t S>\n void write(const array<T, S> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n void write(i128 val) {\n string s;\n bool negative = 0;\n if(val < 0){\n negative = 1;\n val = -val;\n }\n while (val) {\n s += '0' + int(val % 10);\n val /= 10;\n }\n if(negative) s += \"-\";\n reverse(all(s));\n if (len(s) == 0) s = \"0\";\n write(s);\n }\n};\n\nScanner scanner = Scanner(stdin);\nPrinter printer = Printer(stdout);\n\nvoid flush() { printer.flush(); }\nvoid print() { printer.write('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n printer.write(head);\n if (sizeof...(Tail)) printer.write(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid read() {}\ntemplate <class Head, class... Tail>\nvoid read(Head &head, Tail &... tail) {\n scanner.read(head);\n read(tail...);\n}\n\n#define INT(...) \\\n int __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define CHAR(...) \\\n char __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n read(__VA_ARGS__)\n\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n read(name)\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n read(name)\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\n#line 2 \"/home/maspy/compro/library/graph/base.hpp\"\n\ntemplate <typename T>\nstruct Edge {\n int frm, to;\n T cost;\n int id;\n};\n\ntemplate <typename T = int, bool directed = false>\nstruct Graph {\n int N, M;\n using cost_type = T;\n using edge_type = Edge<T>;\n vector<edge_type> edges;\n vector<int> indptr;\n vector<edge_type> csr_edges;\n bool prepared;\n\n class OutgoingEdges {\n public:\n OutgoingEdges(const Graph* G, int l, int r) : G(G), l(l), r(r) {}\n\n const edge_type* begin() const {\n if (l == r) { return 0; }\n return &G->csr_edges[l];\n }\n\n const edge_type* end() const {\n if (l == r) { return 0; }\n return &G->csr_edges[r];\n }\n\n private:\n int l, r;\n const Graph* G;\n };\n\n bool is_prepared() { return prepared; }\n constexpr bool is_directed() { return directed; }\n\n Graph() : N(0), M(0), prepared(0) {}\n Graph(int N) : N(N), M(0), prepared(0) {}\n\n void add(int frm, int to, T cost = 1, int i = -1) {\n assert(!prepared && 0 <= frm && 0 <= to && to < N);\n if (i == -1) i = M;\n auto e = edge_type({frm, to, cost, i});\n edges.eb(e);\n ++M;\n }\n\n // wt, off\n void read_tree(bool wt = false, int off = 1) { read_graph(N - 1, wt, off); }\n\n void read_graph(int M, bool wt = false, int off = 1) {\n FOR_(M) {\n INT(a, b);\n a -= off, b -= off;\n if (!wt) {\n add(a, b);\n } else {\n T c;\n read(c);\n add(a, b, c);\n }\n }\n build();\n }\n\n void read_parent(int off = 1) {\n FOR3(v, 1, N) {\n INT(p);\n p -= off;\n add(p, v);\n }\n build();\n }\n\n void build() {\n assert(!prepared);\n prepared = true;\n indptr.assign(N + 1, 0);\n for (auto&& e: edges) {\n indptr[e.frm + 1]++;\n if (!directed) indptr[e.to + 1]++;\n }\n FOR(v, N) indptr[v + 1] += indptr[v];\n auto counter = indptr;\n csr_edges.resize(indptr.back() + 1);\n for (auto&& e: edges) {\n csr_edges[counter[e.frm]++] = e;\n if (!directed)\n csr_edges[counter[e.to]++] = edge_type({e.to, e.frm, e.cost, e.id});\n }\n }\n\n OutgoingEdges operator[](int v) const {\n assert(prepared);\n return {this, indptr[v], indptr[v + 1]};\n }\n\n void debug() {\n print(\"Graph\");\n if (!prepared) {\n print(\"frm to cost id\");\n for (auto&& e: edges) print(e.frm, e.to, e.cost, e.id);\n } else {\n print(\"indptr\", indptr);\n print(\"frm to cost id\");\n FOR(v, N) for (auto&& e: (*this)[v]) print(e.frm, e.to, e.cost, e.id);\n }\n }\n};\n#line 3 \"/home/maspy/compro/library/graph/strongly_connected_component.hpp\"\n\ntemplate <typename Graph>\npair<int, vc<int>> strongly_connected_component(Graph &G) {\n assert(G.is_directed());\n assert(G.is_prepared());\n int N = G.N;\n int C = 0;\n vc<int> comp(N);\n vc<int> low(N);\n vc<int> ord(N, -1);\n vc<int> visited;\n int now = 0;\n\n auto dfs = [&](auto self, int v) -> void {\n low[v] = now;\n ord[v] = now;\n ++now;\n visited.eb(v);\n for (auto &&[frm, to, cost, id]: G[v]) {\n if (ord[to] == -1) {\n self(self, to);\n chmin(low[v], low[to]);\n } else {\n chmin(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (1) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = N;\n comp[u] = C;\n if (u == v) break;\n }\n ++C;\n }\n };\n FOR(v, N) {\n if (ord[v] == -1) dfs(dfs, v);\n }\n FOR(v, N) comp[v] = C - 1 - comp[v];\n return {C, comp};\n}\n#line 3 \"/home/maspy/compro/library/graph/reachability.hpp\"\n\n// 有向グラフの到達可能性クエリ。O((N+M)Q/w)。\ntemplate <typename GT, typename P>\nvc<int> reachability(GT& G, vc<P> query) {\n auto [C, comp] = strongly_connected_component(G);\n Graph<int, 1> DAG(C);\n for (auto&& e: G.edges) {\n auto a = comp[e.frm], b = comp[e.to];\n assert(a <= b);\n if (a < b) DAG.add(a, b);\n }\n DAG.build();\n\n int Q = len(query);\n vc<u64> dp(C);\n vc<int> res(Q);\n for (int l = 0; l < Q; l += 64) {\n int r = min(l + 64, Q);\n fill(all(dp), u64(0));\n\n FOR3(qid, l, r) {\n auto v = comp[query[qid].fi];\n dp[v] |= u64(1) << (qid - l);\n }\n FOR(v, C) for (auto&& e: DAG[v]) { dp[e.to] |= dp[v]; }\n FOR3(qid, l, r) {\n auto v = comp[query[qid].se];\n if (dp[v] & (u64(1) << (qid - l))) res[qid] = 1;\n }\n }\n return res;\n}\n#line 3 \"/home/maspy/compro/library/graph/dijkstra.hpp\"\n\ntemplate <typename T, typename Graph>\npair<vc<T>, vc<int>> dijkstra(Graph& G, int v, T INF) {\n auto N = G.N;\n vector<T> dist(N, INF);\n vector<int> par(N, -1);\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n dist[v] = 0;\n que.emplace(0, v);\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n par[e.to] = e.frm;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return {dist, par};\n}\n\n// 多点スタート。[dist, par, root]\ntemplate <typename T, T INF, typename Graph>\ntuple<vc<T>, vc<int>, vc<int>> dijkstra(Graph& G, vc<int> vs) {\n assert(G.is_prepared());\n int N = G.N;\n vc<ll> dist(N, INF);\n vc<int> par(N, -1);\n vc<int> root(N, -1);\n\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n for (auto&& v: vs) {\n dist[v] = 0;\n root[v] = v;\n que.emplace(T(0), v);\n }\n\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n root[e.to] = root[e.frm];\n par[e.to] = e.frm;\n que.push(mp(dist[e.to], e.to));\n }\n }\n }\n return {dist, par, root};\n}\n#line 6 \"main.cpp\"\n\nvoid solve() {\n LL(N, M);\n Graph G(N);\n G.read_graph(M, 1);\n LL(a, b);\n --a, --b;\n const ll INF = 1LL << 60;\n\n auto [dist_a, par_a] = dijkstra(G, a, INF);\n auto [dist_b, par_b] = dijkstra(G, b, INF);\n\n Graph<int, 1> DG(N);\n ll d = dist_a[b];\n for (auto&& e: G.edges) {\n if (dist_a[e.frm] + e.cost + dist_b[e.to] == d) DG.add(e.frm, e.to);\n if (dist_b[e.frm] + e.cost + dist_a[e.to] == d) DG.add(e.to, e.frm);\n }\n DG.build();\n\n LL(Q);\n VEC(pi, query, Q);\n for (auto&& [a, b]: query) --a, --b;\n auto res = reachability(DG, query);\n for (auto&& yn: res) Yes(yn);\n}\n\nsigned main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << setprecision(15);\n\n ll T = 1;\n // LL(T);\n FOR(_, T) solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 45456, "score_of_the_acc": -0.7412, "final_rank": 5 }, { "submission_id": "aoj_0275_6560425", "code_snippet": "#line 1 \"/home/maspy/compro/library/my_template.hpp\"\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\n\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define FOR_(n) for (ll _ = 0; (_) < (ll)(n); ++(_))\n#define FOR(i, n) for (ll i = 0; (i) < (ll)(n); ++(i))\n#define FOR3(i, m, n) for (ll i = (m); (i) < (ll)(n); ++(i))\n#define FOR_R(i, n) for (ll i = (ll)(n)-1; (i) >= 0; --(i))\n#define FOR3_R(i, m, n) for (ll i = (ll)(n)-1; (i) >= (ll)(m); --(i))\n#define FOR_subset(t, s) for (ll t = s; t >= 0; t = (t == 0 ? -1 : (t - 1) & s))\n#define all(x) x.begin(), x.end()\n#define len(x) ll(x.size())\n#define elif else if\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n\ntemplate <typename T>\nT SUM(vector<T> &A) {\n T sum = T(0);\n for (auto &&a: A) sum += a;\n return sum;\n}\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\nint popcnt(int x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(ll x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2)\nint topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(u32 x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nint topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2)\nint lowbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(u32 x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nint lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T, typename U>\nT ceil(T x, U y) {\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <typename T, typename U>\nT floor(T x, U y) {\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\n\ntemplate <typename T, typename U>\npair<T, T> divmod(T x, U y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\nll binary_search(function<bool(ll)> check, ll ok, ll ng) {\n assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n if (check(x))\n ok = x;\n else\n ng = x;\n }\n return ok;\n}\n\ntemplate <class T, class S>\ninline bool chmax(T &a, const S &b) {\n return (a < b ? a = b, 1 : 0);\n}\ntemplate <class T, class S>\ninline bool chmin(T &a, const S &b) {\n return (a > b ? a = b, 1 : 0);\n}\n\nvi s_to_vi(const string& S, char first_char) {\n vi A(S.size());\n FOR(i, S.size()) { A[i] = S[i] - first_char; }\n return A;\n}\n\ntemplate <typename T>\nvector<T> cumsum(vector<T> &A, int off = 1) {\n int N = A.size();\n vector<T> B(N + 1);\n FOR(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\ntemplate <typename CNT, typename T>\nvc<CNT> bincount(const vc<T> &A, int size) {\n vc<CNT> C(size);\n for (auto &&x: A) { ++C[x]; }\n return C;\n}\n\ntemplate <typename T>\nvector<int> argsort(const vector<T> &A) {\n // stable\n vector<int> ids(A.size());\n iota(all(ids), 0);\n sort(all(ids),\n [&](int i, int j) { return A[i] < A[j] || (A[i] == A[j] && i < j); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vc<int> &I) {\n int n = len(A);\n assert(len(I) == n);\n vc<T> B(n);\n FOR(i, n) B[i] = A[I[i]];\n return B;\n}\n#line 1 \"/home/maspy/compro/library/other/io.hpp\"\n// based on yosupo's fastio\n#include <unistd.h>\n\nnamespace detail {\ntemplate <typename T, decltype(&T::is_modint) = &T::is_modint>\nstd::true_type check_value(int);\ntemplate <typename T>\nstd::false_type check_value(long);\n} // namespace detail\n\ntemplate <typename T>\nstruct is_modint : decltype(detail::check_value<T>(0)) {};\ntemplate <typename T>\nusing is_modint_t = enable_if_t<is_modint<T>::value>;\ntemplate <typename T>\nusing is_not_modint_t = enable_if_t<!is_modint<T>::value>;\n\nstruct Scanner {\n FILE *fp;\n char line[(1 << 15) + 1];\n size_t st = 0, ed = 0;\n void reread() {\n memmove(line, line + st, ed - st);\n ed -= st;\n st = 0;\n ed += fread(line + ed, 1, (1 << 15) - ed, fp);\n line[ed] = '\\0';\n }\n bool succ() {\n while (true) {\n if (st == ed) {\n reread();\n if (st == ed) return false;\n }\n while (st != ed && isspace(line[st])) st++;\n if (st != ed) break;\n }\n if (ed - st <= 50) {\n bool sep = false;\n for (size_t i = st; i < ed; i++) {\n if (isspace(line[i])) {\n sep = true;\n break;\n }\n }\n if (!sep) reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_same<T, string>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n while (true) {\n size_t sz = 0;\n while (st + sz < ed && !isspace(line[st + sz])) sz++;\n ref.append(line + st, sz);\n st += sz;\n if (!sz || st != ed) break;\n reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n bool neg = false;\n if (line[st] == '-') {\n neg = true;\n st++;\n }\n ref = T(0);\n while (isdigit(line[st])) { ref = 10 * ref + (line[st++] & 0xf); }\n if (neg) ref = -ref;\n return true;\n }\n template <class T, is_modint_t<T> * = nullptr>\n bool read_single(T &ref) {\n long long val = 0;\n bool f = read_single(val);\n ref = T(val);\n return f;\n }\n bool read_single(double &ref) {\n string s;\n if (!read_single(s)) return false;\n ref = std::stod(s);\n return true;\n }\n bool read_single(char &ref) {\n string s;\n if (!read_single(s) || s.size() != 1) return false;\n ref = s[0];\n return true;\n }\n template <class T>\n bool read_single(vector<T> &ref) {\n for (auto &d: ref) {\n if (!read_single(d)) return false;\n }\n return true;\n }\n template <class T, class U>\n bool read_single(pair<T, U> &p) {\n return (read_single(p.first) && read_single(p.second));\n }\n template <class A, class B, class C>\n bool read_single(tuple<A, B, C> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)));\n }\n template <class A, class B, class C, class D>\n bool read_single(tuple<A, B, C, D> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)) && read_single(get<3>(p)));\n }\n void read() {}\n template <class H, class... T>\n void read(H &h, T &... t) {\n bool f = read_single(h);\n assert(f);\n read(t...);\n }\n Scanner(FILE *fp) : fp(fp) {}\n};\n\nstruct Printer {\n Printer(FILE *_fp) : fp(_fp) {}\n ~Printer() { flush(); }\n\n static constexpr size_t SIZE = 1 << 15;\n FILE *fp;\n char line[SIZE], small[50];\n size_t pos = 0;\n void flush() {\n fwrite(line, 1, pos, fp);\n pos = 0;\n }\n void write(const char &val) {\n if (pos == SIZE) flush();\n line[pos++] = val;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n void write(T val) {\n if (pos > (1 << 15) - 50) flush();\n if (val == 0) {\n write('0');\n return;\n }\n if (val < 0) {\n write('-');\n val = -val; // todo min\n }\n size_t len = 0;\n while (val) {\n small[len++] = char(0x30 | (val % 10));\n val /= 10;\n }\n for (size_t i = 0; i < len; i++) { line[pos + i] = small[len - 1 - i]; }\n pos += len;\n }\n void write(const string &s) {\n for (char c: s) write(c);\n }\n void write(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++) write(s[i]);\n }\n void write(const double &x) {\n ostringstream oss;\n oss << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n void write(const long double &x) {\n ostringstream oss;\n oss << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n template <class T, is_modint_t<T> * = nullptr>\n void write(T &ref) {\n write(ref.val);\n }\n template <class T>\n void write(const vector<T> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n template <class T, class U>\n void write(const pair<T, U> &val) {\n write(val.first);\n write(' ');\n write(val.second);\n }\n template <class A, class B, class C>\n void write(const tuple<A, B, C> &val) {\n auto &[a, b, c] = val;\n write(a), write(' '), write(b), write(' '), write(c);\n }\n template <class A, class B, class C, class D>\n void write(const tuple<A, B, C, D> &val) {\n auto &[a, b, c, d] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d);\n }\n template <class A, class B, class C, class D, class E>\n void write(const tuple<A, B, C, D, E> &val) {\n auto &[a, b, c, d, e] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e);\n }\n template <class A, class B, class C, class D, class E, class F>\n void write(const tuple<A, B, C, D, E, F> &val) {\n auto &[a, b, c, d, e, f] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e), write(' '), write(f);\n }\n template <class T, size_t S>\n void write(const array<T, S> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n void write(i128 val) {\n string s;\n bool negative = 0;\n if(val < 0){\n negative = 1;\n val = -val;\n }\n while (val) {\n s += '0' + int(val % 10);\n val /= 10;\n }\n if(negative) s += \"-\";\n reverse(all(s));\n if (len(s) == 0) s = \"0\";\n write(s);\n }\n};\n\nScanner scanner = Scanner(stdin);\nPrinter printer = Printer(stdout);\n\nvoid flush() { printer.flush(); }\nvoid print() { printer.write('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n printer.write(head);\n if (sizeof...(Tail)) printer.write(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid read() {}\ntemplate <class Head, class... Tail>\nvoid read(Head &head, Tail &... tail) {\n scanner.read(head);\n read(tail...);\n}\n\n#define INT(...) \\\n int __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define CHAR(...) \\\n char __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n read(__VA_ARGS__)\n\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n read(name)\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n read(name)\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\n#line 2 \"/home/maspy/compro/library/graph/base.hpp\"\n\ntemplate <typename T>\nstruct Edge {\n int frm, to;\n T cost;\n int id;\n};\n\ntemplate <typename T = int, bool directed = false>\nstruct Graph {\n int N, M;\n using cost_type = T;\n using edge_type = Edge<T>;\n vector<edge_type> edges;\n vector<int> indptr;\n vector<edge_type> csr_edges;\n bool prepared;\n\n class OutgoingEdges {\n public:\n OutgoingEdges(const Graph* G, int l, int r) : G(G), l(l), r(r) {}\n\n const edge_type* begin() const {\n if (l == r) { return 0; }\n return &G->csr_edges[l];\n }\n\n const edge_type* end() const {\n if (l == r) { return 0; }\n return &G->csr_edges[r];\n }\n\n private:\n int l, r;\n const Graph* G;\n };\n\n bool is_prepared() { return prepared; }\n constexpr bool is_directed() { return directed; }\n\n Graph() : N(0), M(0), prepared(0) {}\n Graph(int N) : N(N), M(0), prepared(0) {}\n\n void add(int frm, int to, T cost = 1, int i = -1) {\n assert(!prepared && 0 <= frm && 0 <= to && to < N);\n if (i == -1) i = M;\n auto e = edge_type({frm, to, cost, i});\n edges.eb(e);\n ++M;\n }\n\n // wt, off\n void read_tree(bool wt = false, int off = 1) { read_graph(N - 1, wt, off); }\n\n void read_graph(int M, bool wt = false, int off = 1) {\n FOR_(M) {\n INT(a, b);\n a -= off, b -= off;\n if (!wt) {\n add(a, b);\n } else {\n T c;\n read(c);\n add(a, b, c);\n }\n }\n build();\n }\n\n void read_parent(int off = 1) {\n FOR3(v, 1, N) {\n INT(p);\n p -= off;\n add(p, v);\n }\n build();\n }\n\n void build() {\n assert(!prepared);\n prepared = true;\n indptr.assign(N + 1, 0);\n for (auto&& e: edges) {\n indptr[e.frm + 1]++;\n if (!directed) indptr[e.to + 1]++;\n }\n FOR(v, N) indptr[v + 1] += indptr[v];\n auto counter = indptr;\n csr_edges.resize(indptr.back() + 1);\n for (auto&& e: edges) {\n csr_edges[counter[e.frm]++] = e;\n if (!directed)\n csr_edges[counter[e.to]++] = edge_type({e.to, e.frm, e.cost, e.id});\n }\n }\n\n OutgoingEdges operator[](int v) const {\n assert(prepared);\n return {this, indptr[v], indptr[v + 1]};\n }\n\n void debug() {\n print(\"Graph\");\n if (!prepared) {\n print(\"frm to cost id\");\n for (auto&& e: edges) print(e.frm, e.to, e.cost, e.id);\n } else {\n print(\"indptr\", indptr);\n print(\"frm to cost id\");\n FOR(v, N) for (auto&& e: (*this)[v]) print(e.frm, e.to, e.cost, e.id);\n }\n }\n};\n#line 3 \"/home/maspy/compro/library/graph/strongly_connected_component.hpp\"\n\ntemplate <typename Graph>\npair<int, vc<int>> strongly_connected_component(Graph &G) {\n assert(G.is_directed());\n assert(G.is_prepared());\n int N = G.N;\n int C = 0;\n vc<int> comp(N);\n vc<int> low(N);\n vc<int> ord(N, -1);\n vc<int> visited;\n int now = 0;\n\n auto dfs = [&](auto self, int v) -> void {\n low[v] = now;\n ord[v] = now;\n ++now;\n visited.eb(v);\n for (auto &&[frm, to, cost, id]: G[v]) {\n if (ord[to] == -1) {\n self(self, to);\n chmin(low[v], low[to]);\n } else {\n chmin(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (1) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = N;\n comp[u] = C;\n if (u == v) break;\n }\n ++C;\n }\n };\n FOR(v, N) {\n if (ord[v] == -1) dfs(dfs, v);\n }\n FOR(v, N) comp[v] = C - 1 - comp[v];\n return {C, comp};\n}\n#line 3 \"/home/maspy/compro/library/graph/dijkstra.hpp\"\n\ntemplate <typename T, typename Graph>\npair<vc<T>, vc<int>> dijkstra(Graph& G, int v, T INF) {\n auto N = G.N;\n vector<T> dist(N, INF);\n vector<int> par(N, -1);\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n dist[v] = 0;\n que.emplace(0, v);\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n par[e.to] = e.frm;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return {dist, par};\n}\n\n// 多点スタート。[dist, par, root]\ntemplate <typename T, T INF, typename Graph>\ntuple<vc<T>, vc<int>, vc<int>> dijkstra(Graph& G, vc<int> vs) {\n assert(G.is_prepared());\n int N = G.N;\n vc<ll> dist(N, INF);\n vc<int> par(N, -1);\n vc<int> root(N, -1);\n\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n\n for (auto&& v: vs) {\n dist[v] = 0;\n root[v] = v;\n que.emplace(T(0), v);\n }\n\n while (!que.empty()) {\n auto [dv, v] = que.top();\n que.pop();\n if (dv > dist[v]) continue;\n for (auto&& e: G[v]) {\n if (chmin(dist[e.to], dist[e.frm] + e.cost)) {\n root[e.to] = root[e.frm];\n par[e.to] = e.frm;\n que.push(mp(dist[e.to], e.to));\n }\n }\n }\n return {dist, par, root};\n}\n#line 5 \"main.cpp\"\n\ntemplate <typename GT, typename P>\nvc<int> digraph_reachability(GT& G, vc<P> query) {\n auto [C, comp] = strongly_connected_component(G);\n Graph<int, 1> DAG(C);\n for (auto&& e: G.edges) {\n auto a = comp[e.frm], b = comp[e.to];\n assert(a <= b);\n if (a < b) DAG.add(a, b);\n }\n DAG.build();\n\n int Q = len(query);\n vc<u64> dp(C);\n vc<int> res(Q);\n for (int l = 0; l < Q; l += 64) {\n int r = min(l + 64, Q);\n fill(all(dp), u64(0));\n\n FOR3(qid, l, r) {\n auto v = comp[query[qid].fi];\n dp[v] |= u64(1) << (qid - l);\n }\n FOR(v, C) for (auto&& e: DAG[v]) { dp[e.to] |= dp[v]; }\n FOR3(qid, l, r) {\n auto v = comp[query[qid].se];\n if (dp[v] & (u64(1) << (qid - l))) res[qid] = 1;\n }\n }\n return res;\n}\n\nvoid solve() {\n LL(N, M);\n Graph G(N);\n G.read_graph(M, 1);\n LL(a, b);\n --a, --b;\n const ll INF = 1LL << 60;\n\n auto [dist_a, par_a] = dijkstra(G, a, INF);\n auto [dist_b, par_b] = dijkstra(G, b, INF);\n\n Graph<int, 1> DG(N);\n ll d = dist_a[b];\n for (auto&& e: G.edges) {\n if (dist_a[e.frm] + e.cost + dist_b[e.to] == d) DG.add(e.frm, e.to);\n if (dist_b[e.frm] + e.cost + dist_a[e.to] == d) DG.add(e.to, e.frm);\n }\n DG.build();\n\n LL(Q);\n VEC(pi, query, Q);\n for (auto&& [a, b]: query) --a, --b;\n auto res = digraph_reachability(DG, query);\n for (auto&& yn: res) Yes(yn);\n}\n\nsigned main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << setprecision(15);\n\n ll T = 1;\n // LL(T);\n FOR(_, T) solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 45152, "score_of_the_acc": -0.7361, "final_rank": 4 }, { "submission_id": "aoj_0275_5979583", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int S, R;\n cin >> S >> R;\n vector<vector<pair<int, int>>> E(S);\n for (int i = 0; i < R; i++){\n int u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n E[u].push_back(make_pair(w, v));\n E[v].push_back(make_pair(w, u));\n }\n int a, b, Q;\n cin >> a >> b >> Q;\n a--;\n b--;\n vector<int> c(Q), d(Q);\n for (int i = 0; i < Q; i++){\n cin >> c[i] >> d[i];\n c[i]--;\n d[i]--;\n }\n vector<int> d1(S, -1);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq1;\n pq1.push(make_pair(0, a));\n vector<int> t;\n while (!pq1.empty()){\n int d = pq1.top().first;\n int v = pq1.top().second;\n pq1.pop();\n if (d1[v] == -1){\n d1[v] = d;\n t.push_back(v);\n for (auto P : E[v]){\n int w = P.second;\n if (d1[w] == -1){\n pq1.push(make_pair(d + P.first, w));\n }\n }\n }\n }\n vector<int> d2(S, -1);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq2;\n pq2.push(make_pair(0, b));\n while (!pq2.empty()){\n int d = pq2.top().first;\n int v = pq2.top().second;\n pq2.pop();\n if (d2[v] == -1){\n d2[v] = d;\n for (auto P : E[v]){\n int w = P.second;\n if (d2[w] == -1){\n pq2.push(make_pair(d + P.first, w));\n }\n }\n }\n }\n int D = d1[b];\n vector<bool> ok(S, false);\n for (int i = 0; i < S; i++){\n if (d1[i] + d2[i] == D){\n ok[i] = true;\n }\n }\n vector<vector<int>> E2(S);\n for (int i = 0; i < S; i++){\n if (ok[i]){\n for (auto P : E[i]){\n int w = P.second;\n if (ok[w] && d1[w] == d1[i] + P.first){\n E2[i].push_back(w);\n }\n }\n }\n }\n int Q2 = (Q + 63) / 64;\n for (int i = 0; i < Q2; i++){\n int l = i * 64;\n int r = min((i + 1) * 64, Q);\n vector<unsigned long long> dp(S);\n for (int j = l; j < r; j++){\n dp[c[j]] |= (unsigned long long) 1 << (j - l);\n }\n for (int v : t){\n for (int w : E2[v]){\n dp[w] |= dp[v];\n }\n }\n for (int j = l; j < r; j++){\n if ((dp[d[j]] >> (j - l) & 1) == 1){\n cout << \"Yes\" << endl;\n } else {\n cout << \"No\" << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 19948, "score_of_the_acc": -0.4179, "final_rank": 1 }, { "submission_id": "aoj_0275_5053181", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<queue>\nusing namespace std;\nint N,M,S,T,Q;\nvector<pair<int,int> >G[1<<17];\nint dS[1<<17],dT[1<<17];\nint D[1<<17],vis[1<<17];\nmain()\n{\n\tscanf(\"%d%d\",&N,&M);\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint u,v,w;scanf(\"%d%d%d\",&u,&v,&w);\n\t\tu--,v--;\n\t\tG[u].push_back(make_pair(v,w));\n\t\tG[v].push_back(make_pair(u,w));\n\t}\n\tscanf(\"%d%d%d\",&S,&T,&Q);\n\tS--,T--;\n\t{\n\t\tfor(int i=0;i<N;i++)dS[i]=dT[i]=1e9;\n\t\t{\n\t\t\tdS[S]=0;\n\t\t\tpriority_queue<pair<int,int> >P;\n\t\t\tP.push(make_pair(0,S));\n\t\t\twhile(!P.empty())\n\t\t\t{\n\t\t\t\tint cost=-P.top().first,u=P.top().second;\n\t\t\t\tP.pop();\n\t\t\t\tif(dS[u]<cost)continue;\n\t\t\t\tfor(const pair<int,int>&e:G[u])\n\t\t\t\t{\n\t\t\t\t\tint v=e.first;\n\t\t\t\t\tint nxt=cost+e.second;\n\t\t\t\t\tif(dS[v]>nxt)\n\t\t\t\t\t{\n\t\t\t\t\t\tdS[v]=nxt;\n\t\t\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t{\n\t\t\tdT[T]=0;\n\t\t\tpriority_queue<pair<int,int> >P;\n\t\t\tP.push(make_pair(0,T));\n\t\t\twhile(!P.empty())\n\t\t\t{\n\t\t\t\tint cost=-P.top().first,u=P.top().second;\n\t\t\t\tP.pop();\n\t\t\t\tif(dT[u]<cost)continue;\n\t\t\t\tfor(const pair<int,int>&e:G[u])\n\t\t\t\t{\n\t\t\t\t\tint v=e.first;\n\t\t\t\t\tint nxt=cost+e.second;\n\t\t\t\t\tif(dT[v]>nxt)\n\t\t\t\t\t{\n\t\t\t\t\t\tdT[v]=nxt;\n\t\t\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(int tm=0;tm++<Q;)\n\t{\n\t\tint c,d;scanf(\"%d%d\",&c,&d);c--,d--;\n\t\tif(dS[c]+dT[c]!=dS[T]||dS[d]+dT[d]!=dS[T])\n\t\t{\n\t\t\tputs(\"No\");\n\t\t\tcontinue;\n\t\t}\n\t\tvis[c]=tm;\n\t\tD[c]=0;\n\t\tqueue<int>P;\n\t\tP.push(c);\n\t\twhile(!P.empty())\n\t\t{\n\t\t\tint u=P.front();\n\t\t\tP.pop();\n\t\t\tif(u==d)break;\n\t\t\tif(dS[c]+D[u]>dS[d])continue;\n\t\t\tfor(const pair<int,int>&e:G[u])\n\t\t\t{\n\t\t\t\tint v=e.first,nxt=D[u]+e.second;\n\t\t\t\tif(dS[v]==dS[c]+nxt&&vis[v]<tm)\n\t\t\t\t{\n\t\t\t\t\tvis[v]=tm;\n\t\t\t\t\tD[v]=nxt;\n\t\t\t\t\tP.push(v);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tputs(vis[d]==tm?\"Yes\":\"No\");\n\t}\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 11460, "score_of_the_acc": -1, "final_rank": 6 }, { "submission_id": "aoj_0275_5006523", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<queue>\n#include<vector>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 6 \"a.cpp\"\nint N,M,s,g,Q;\nvector<pair<int,int> >G[1<<17];\nvector<int>dist(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first,nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tcin>>s>>g>>Q;\n\ts--,g--;\n\tvector<int>ds=dist(s),dg=dist(g);\n\tvector<vector<int> >H(N);\n\tvector<int>indeg(N);\n\tUF uf(N);\n\tfor(int i=0;i<N;i++)for(pair<int,int>e:G[i])\n\t{\n\t\tint u=i,v=e.first;\n\t\tif(ds[u]+e.second+dg[v]==ds[g])\n\t\t{\n\t\t\tH[u].push_back(v);\n\t\t\tindeg[v]++;\n\t\t\tif(u!=s&&v!=g)uf.unite(u,v);\n\t\t}\n\t}\n\tpriority_queue<pair<int,int> >P;\n\tfor(int i=0;i<N;i++)if(!indeg[i])P.push(make_pair(ds[i],i));\n\tvector<int>sor;\n\tvector<int>sorrev(N,1e9);\n\twhile(!P.empty())\n\t{\n\t\tint u=P.top().second;P.pop();\n\t\tsorrev[u]=sor.size();\n\t\tsor.push_back(u);\n\t\tfor(int v:H[u])if(!--indeg[v])\n\t\t{\n\t\t\tP.push(make_pair(ds[v],v));\n\t\t}\n\t}\n\tfor(;Q--;)\n\t{\n\t\tint a,b;cin>>a>>b;a--,b--;\n\t\tif(ds[a]+dg[a]!=ds[g]||ds[b]+dg[b]!=ds[g])\n\t\t{\n\t\t\tcout<<\"No\"<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(ds[a]<ds[b]&&dg[a]>dg[b]&&(a==s||b==g||uf.same(a,b))&&sorrev[a]<sorrev[b])cout<<\"Yes\"<<endl;\n\t\telse cout<<\"No\"<<endl;\n\t}\n}", "accuracy": 0.8888888888888888, "time_ms": 150, "memory_kb": 19612, "score_of_the_acc": -0.2628, "final_rank": 8 }, { "submission_id": "aoj_0275_5006522", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<queue>\n#include<vector>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 6 \"a.cpp\"\nint N,M,s,g,Q;\nvector<pair<int,int> >G[1<<17];\nvector<int>dist(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first,nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tcin>>s>>g>>Q;\n\ts--,g--;\n\tvector<int>ds=dist(s),dg=dist(g);\n\tvector<vector<int> >H(N);\n\tvector<int>indeg(N);\n\tUF uf(N);\n\tfor(int i=0;i<N;i++)for(pair<int,int>e:G[i])\n\t{\n\t\tint u=i,v=e.first;\n\t\tif(ds[u]+e.second+dg[v]==ds[g])\n\t\t{\n\t\t\tH[u].push_back(v);\n\t\t\tindeg[v]++;\n\t\t\tif(u!=s&&v!=g)uf.unite(u,v);\n\t\t}\n\t}\n\tpriority_queue<pair<int,int> >P;\n\tfor(int i=0;i<N;i++)if(!indeg[i])P.push(make_pair(-ds[i],i));\n\tvector<int>sor;\n\tvector<int>sorrev(N,1e9);\n\twhile(!P.empty())\n\t{\n\t\tint u=P.top().second;P.pop();\n\t\tsorrev[u]=sor.size();\n\t\tsor.push_back(u);\n\t\tfor(int v:H[u])if(!--indeg[v])\n\t\t{\n\t\t\tP.push(make_pair(-ds[v],v));\n\t\t}\n\t}\n\tfor(;Q--;)\n\t{\n\t\tint a,b;cin>>a>>b;a--,b--;\n\t\tif(ds[a]+dg[a]!=ds[g]||ds[b]+dg[b]!=ds[g])\n\t\t{\n\t\t\tcout<<\"No\"<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(ds[a]<ds[b]&&(a==s||b==g||uf.same(a,b))&&sorrev[a]<sorrev[b])cout<<\"Yes\"<<endl;\n\t\telse cout<<\"No\"<<endl;\n\t}\n}", "accuracy": 0.6666666666666666, "time_ms": 140, "memory_kb": 15732, "score_of_the_acc": -0.1864, "final_rank": 11 }, { "submission_id": "aoj_0275_5006521", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<queue>\n#include<vector>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 6 \"a.cpp\"\nint N,M,s,g,Q;\nvector<pair<int,int> >G[1<<17];\nvector<int>dist(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first,nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tcin>>s>>g>>Q;\n\ts--,g--;\n\tvector<int>ds=dist(s),dg=dist(g);\n\tvector<vector<int> >H(N);\n\tvector<int>indeg(N);\n\tUF uf(N);\n\tfor(int i=0;i<N;i++)for(pair<int,int>e:G[i])\n\t{\n\t\tint u=i,v=e.first;\n\t\tif(ds[u]+e.second+dg[v]==ds[g])\n\t\t{\n\t\t\tH[u].push_back(v);\n\t\t\tindeg[v]++;\n\t\t\tif(u!=s&&v!=g)uf.unite(u,v);\n\t\t}\n\t}\n\tpriority_queue<pair<int,int> >P;\n\tfor(int i=0;i<N;i++)if(!indeg[i])P.push(make_pair(ds[i],i));\n\tvector<int>sor;\n\tvector<int>sorrev(N,1e9);\n\twhile(!P.empty())\n\t{\n\t\tint u=P.top().second;P.pop();\n\t\tsorrev[u]=sor.size();\n\t\tsor.push_back(u);\n\t\tfor(int v:H[u])if(!--indeg[v])\n\t\t{\n\t\t\tP.push(make_pair(ds[v],v));\n\t\t}\n\t}\n\tfor(;Q--;)\n\t{\n\t\tint a,b;cin>>a>>b;a--,b--;\n\t\tif(ds[a]+dg[a]!=ds[g]||ds[b]+dg[b]!=ds[g])\n\t\t{\n\t\t\tcout<<\"No\"<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(ds[a]<ds[b]&&(a==s||b==g||uf.same(a,b))&&sorrev[a]<sorrev[b])cout<<\"Yes\"<<endl;\n\t\telse cout<<\"No\"<<endl;\n\t}\n}", "accuracy": 0.8888888888888888, "time_ms": 150, "memory_kb": 19692, "score_of_the_acc": -0.2642, "final_rank": 9 }, { "submission_id": "aoj_0275_5006519", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<queue>\n#include<vector>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 6 \"a.cpp\"\nint N,M,s,g,Q;\nvector<pair<int,int> >G[1<<17];\nvector<int>dist(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first,nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tcin>>s>>g>>Q;\n\ts--,g--;\n\tvector<int>ds=dist(s),dg=dist(g);\n\tvector<vector<int> >H(N);\n\tvector<int>indeg(N);\n\tUF uf(N);\n\tfor(int i=0;i<N;i++)for(pair<int,int>e:G[i])\n\t{\n\t\tint u=i,v=e.first;\n\t\tif(ds[u]+e.second+dg[v]==ds[g])\n\t\t{\n\t\t\tH[u].push_back(v);\n\t\t\tindeg[v]++;\n\t\t\tif(u!=s&&v!=g)uf.unite(u,v);\n\t\t}\n\t}\n\tqueue<int>P;\n\tfor(int i=0;i<N;i++)if(!indeg[i])P.push(i);\n\tvector<int>sor;\n\tvector<int>sorrev(N,1e9);\n\twhile(!P.empty())\n\t{\n\t\tint u=P.front();P.pop();\n\t\tsorrev[u]=sor.size();\n\t\tsor.push_back(u);\n\t\tfor(int v:H[u])if(!--indeg[v])\n\t\t{\n\t\t\tP.push(v);\n\t\t}\n\t}\n\tfor(;Q--;)\n\t{\n\t\tint a,b;cin>>a>>b;a--,b--;\n\t\tif(ds[a]+dg[a]!=ds[g]||ds[b]+dg[b]!=ds[g])\n\t\t{\n\t\t\tcout<<\"No\"<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif(ds[a]<ds[b]&&(a==s||b==g||uf.same(a,b))&&sorrev[a]<sorrev[b])cout<<\"Yes\"<<endl;\n\t\telse cout<<\"No\"<<endl;\n\t}\n}", "accuracy": 0.6666666666666666, "time_ms": 120, "memory_kb": 15464, "score_of_the_acc": -0.1589, "final_rank": 10 }, { "submission_id": "aoj_0275_5006498", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<queue>\n#include<vector>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/UF.cpp\"\nstruct UF{\n\tint n;\n\tvector<int>parent,rank;\n\tUF(int n_=0):n(n_),parent(n_),rank(n_,1)\n\t{\n\t\tfor(int i=0;i<n_;i++)parent[i]=i;\n\t}\n\tint find(int a){return parent[a]!=a?parent[a]=find(parent[a]):a;}\n\tbool same(int a,int b){return find(a)==find(b);}\n\tbool unite(int a,int b)\n\t{\n\t\ta=find(a),b=find(b);\n\t\tif(a==b)return false;\n\t\tif(rank[a]<rank[b])\n\t\t{\n\t\t\tparent[a]=b;\n\t\t\trank[b]+=rank[a];\n\t\t}\n\t\telse\n\t\t{\n\t\t\tparent[b]=a;\n\t\t\trank[a]+=rank[b];\n\t\t}\n\t\treturn true;\n\t}\n\tint size(int a){return rank[find(a)];}\n};\n#line 6 \"a.cpp\"\nint N,M,s,g,Q;\nvector<pair<int,int> >G[1<<17];\nvector<int>dist(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first,nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tcin>>s>>g>>Q;\n\ts--,g--;\n\tvector<int>ds=dist(s),dg=dist(g);\n\tvector<vector<int> >H(N);\n\tvector<int>indeg(N);\n\tUF uf(N);\n\tfor(int i=0;i<N;i++)for(pair<int,int>e:G[i])\n\t{\n\t\tint u=i,v=e.first;\n\t\tif(ds[u]+e.second+dg[v]==ds[g])\n\t\t{\n\t\t\tH[u].push_back(v);\n\t\t\tindeg[v]++;\n\t\t\tif(u!=s&&v!=g)uf.unite(u,v);\n\t\t}\n\t}\n\tqueue<int>P;\n\tfor(int i=0;i<N;i++)if(!indeg[i])P.push(i);\n\tvector<int>sor;\n\tvector<int>sorrev(N);\n\twhile(!P.empty())\n\t{\n\t\tint u=P.front();P.pop();\n\t\tsorrev[u]=sor.size();\n\t\tsor.push_back(u);\n\t\tfor(int v:H[u])if(!--indeg[v])\n\t\t{\n\t\t\tP.push(v);\n\t\t}\n\t}\n\tfor(;Q--;)\n\t{\n\t\tint a,b;cin>>a>>b;a--,b--;\n\t\tif(ds[a]+dg[a]!=ds[g]||ds[b]+dg[b]!=ds[g])\n\t\t{\n\t\t\tcout<<\"No\"<<endl;\n\t\t\tcontinue;\n\t\t}\n\t\tif((a==s||b==g||uf.same(a,b))&&sorrev[a]<sorrev[b])cout<<\"Yes\"<<endl;\n\t\telse cout<<\"No\"<<endl;\n\t}\n}", "accuracy": 0.5555555555555556, "time_ms": 120, "memory_kb": 15372, "score_of_the_acc": -0.1574, "final_rank": 19 }, { "submission_id": "aoj_0275_4985445", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int> \n#define vvel V<V<int>>\n#define pin pair<int,int>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mkp make_pair\n#define mmax(a,b) a=max(a,b)\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)\nvel dijk(V<V<pin>> &way, int st, int inf) {\n\tint n = way.size();\n\tvel dist(n, inf);\n\tpriority_queue<pin, vector<pin>, greater<pin>> pq;\n\tpq.push(mkp(0, st));\n\twhile (!pq.empty()) {\n\t\tpin x = pq.top(); pq.pop();\n\t\tint dip = x.first;\n\t\tint pot = x.second;\n\t\tif (dist[pot] == inf) { \n\t\t\tdist[pot] = dip; \n\t\t\tfor (auto y : way[pot]) {\n\t\t\t\tint nex = y.first;\n\t\t\t\tint dxy = y.second;\n\t\t\t\tpq.push(mkp(dip + dxy, nex));\n\t\t\t}\n\t\t}\n\t}\n\treturn dist;\n}\nsigned main() {\n\tint n, m; cin >> n >> m;\n\tV<V<pin>> way(n);\n\trep(i, m) {\n\t\tint u, v, w; cin >> u >> v >> w;\n\t\tu--; v--;\n\t\tway[u].push_back(mkp(v, w));\n\t\tway[v].push_back(mkp(u, w));\n\t}\n\tint a, b; cin >> a >> b; a--; b--;\n\tint inf = ((long long)10000) * (n + m + 1);\n\tvel da = dijk(way, a, inf);\n\tvel db = dijk(way, b, inf);\n\tint dab = da[b];\n\tvvel invway(n);\n\trep(i, n) {\n\t\tfor (pin x : way[i]) {\n\t\t\tint nex = x.first;\n\t\t\tint dix = x.second;\n\t\t\tif (da[i] + dix + db[nex] == dab) {\n\t\t\t\tinvway[nex].push_back(i);\n\t\t\t}\n\t\t}\n\t}\n\tV<pin> qdb(n);\n\trep(i, n) {qdb[i] = mkp(db[i],i);}\n\tsor(qdb);\n\tvel ord(n);\n\trep(i, n) { ord[i] = qdb[i].second; }\n\tint q; cin >> q;\n\tV<pin> que;\n\tvel rui(60, 1);\n\trep(i, 59) { rui[i + 1] = rui[i] * (long long)2; }\n\trep(_, q) {\n\t\tint c, d; cin >> c >> d; c--; d--;\n\t\tque.push_back(mkp(c, d));\n\t\tif ((que.size() == 60) || (_ == q - 1)) {\n\t\t\tvel dp(n);\n\t\t\tint sz = que.size();\n\t\t\trep(i, sz) {\n\t\t\t\tint d = que[i].second;\n\t\t\t\tdp[d] +=rui[i];\n\t\t\t}\n\t\t\trep(i, n) {\n\t\t\t\tint pot = ord[i];\n\t\t\t\tfor (int nex : invway[pot]) {\n\t\t\t\t\tdp[nex] |= dp[pot];\n\t\t\t\t}\n\t\t\t}\n\t\t\trep(i, sz) {\n\t\t\t\tint c = que[i].first;\n\t\t\t\tif ( (dp[c] & rui[i]) != 0) {\n\t\t\t\t\tcout << \"Yes\" << endl;\n\t\t\t\t}\n\t\t\t\telse { cout << \"No\" << endl; }\n\t\t\t}\n\t\t\tque = {};\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 24320, "score_of_the_acc": -0.6864, "final_rank": 2 }, { "submission_id": "aoj_0275_4985431", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int> \n#define vvel V<V<int>>\n#define pin pair<int,int>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mkp make_pair\n#define mmax(a,b) a=max(a,b)\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)\nvel dijk(V<V<pin>> &way, int st, int inf) {\n\tint n = way.size();\n\tvel dist(n, inf);\n\tpriority_queue<pin, vector<pin>, greater<pin>> pq;\n\tpq.push(mkp(0, st));\n\twhile (!pq.empty()) {\n\t\tpin x = pq.top(); pq.pop();\n\t\tint dip = x.first;\n\t\tint pot = x.second;\n\t\tif (dist[pot] == inf) { \n\t\t\tdist[pot] = dip; \n\t\t\tfor (auto y : way[pot]) {\n\t\t\t\tint nex = y.first;\n\t\t\t\tint dxy = y.second;\n\t\t\t\tpq.push(mkp(dip + dxy, nex));\n\t\t\t}\n\t\t}\n\t}\n\treturn dist;\n}\nsigned main() {\n\tint n, m; cin >> n >> m;\n\tV<V<pin>> way(n);\n\trep(i, m) {\n\t\tint u, v, w; cin >> u >> v >> w;\n\t\tu--; v--;\n\t\tway[u].push_back(mkp(v, w));\n\t\tway[v].push_back(mkp(u, w));\n\t}\n\tint a, b; cin >> a >> b; a--; b--;\n\tint inf = ((long long)10000) * (n + m + 1);\n\tvel da = dijk(way, a, inf);\n\tvel db = dijk(way, b, inf);\n\tint dab = da[b];\n\tvvel invway(n);\n\trep(i, n) {\n\t\tfor (pin x : way[i]) {\n\t\t\tint nex = x.first;\n\t\t\tint dix = x.second;\n\t\t\tif (da[i] + dix + db[nex] == dab) {\n\t\t\t\tinvway[nex].push_back(i);\n\t\t\t}\n\t\t}\n\t}\n\tV<pin> qdb(n);\n\trep(i, n) {qdb[i] = mkp(db[i],i);}\n\tsor(qdb);\n\tvel ord(n);\n\trep(i, n) { ord[i] = qdb[i].second; }\n\tint q; cin >> q;\n\tV<pin> que;\n\trep(_, q) {\n\t\tint c, d; cin >> c >> d; c--; d--;\n\t\tque.push_back(mkp(c, d));\n\t\tif ((que.size() == 60) || (_ == q - 1)) {\n\t\t\tvel dp(n);\n\t\t\tint sz = que.size();\n\t\t\trep(i, sz) {\n\t\t\t\tint d = que[i].second;\n\t\t\t\tdp[d] += (1 << i);\n\t\t\t}\n\t\t\trep(i, n) {\n\t\t\t\tint pot = ord[i];\n\t\t\t\tfor (int nex : invway[pot]) {\n\t\t\t\t\tdp[nex] |= dp[pot];\n\t\t\t\t}\n\t\t\t}\n\t\t\trep(i, sz) {\n\t\t\t\tint c = que[i].first;\n\t\t\t\tif ( (dp[c] & (1 << i)) != 0) {\n\t\t\t\t\tcout << \"Yes\" << endl;\n\t\t\t\t}\n\t\t\t\telse { cout << \"No\" << endl; }\n\t\t\t}\n\t\t\tque = {};\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.3333333333333333, "time_ms": 200, "memory_kb": 18468, "score_of_the_acc": -0.3012, "final_rank": 20 } ]
aoj_0281_cpp
陣形 プログラマー養成校であるアカベ高校では、チーム戦の競技プログラマーの役割を以下の3タイプに分けています。 C: コーダー 言語を熟知しており、コーディングを行う。 A: アルゴリズマー 論理的思考が得意であり、アルゴリズムを考える。 N: ナビゲーター 読解力に長けており、問題の分析・デバッグをする。 この高校では以下のいずれかの陣形で3人一組のチームを構成しています。 CCA: バランスがとれている安定型 CCC: スピードを見込めるがリスクの高い速攻型 CAN: 正確に問題を解く慎重型 競技プログラミング部のコーチであるあなたは、これらの部員をうまく組み合わせ、できるだけ多くのチームを結成できるよう、毎年気を配っています。そこで、コーダーの人数、アルゴリズマーの人数、ナビゲーターの人数が入力として与えられたとき、最大何チーム作れるかを出力するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 Q c 1 a 1 n 1 c 2 a 2 n 2 : c Q a Q n Q 1行目の Q (0 ≤ Q ≤ 100)はチーム数を求めたい年数である。続く Q 行に各年の役割別の人数が与えられる。各行にはコーダーの人数 c i (0 ≤ c i ≤ 1000)、アルゴリズマーの人数 a i (0 ≤ a i ≤ 1000)、ナビゲーターの人数 n i (0 ≤ n i ≤ 1000)が与えられる。 出力 年ごとに、作成できる最大のチーム数を1行に出力する。 入力例 4 3 0 0 1 1 1 9 4 1 0 1 2 出力例 1 1 4 0
[ { "submission_id": "aoj_0281_9637717", "code_snippet": "#include<bits/stdc++.h>\n\n#define ll long long\nusing namespace std;\n\n\n\nint main() {\n//#ifndef ONLINE_JUDGE\n// freopen(\"Input.txt\", \"r\", stdin);\n// freopen(\"Output.txt\", \"w\", stdout);\n//#endif\n int t;\n cin >> t ;\n while (t--) {\nint a , b , c;\ncin >> a >> b >> c ;\nint ans = 0;\n for (int i = 0; i <350 ; ++i) {\n int aa = a ;\n if(i > a / 3)break;\n for (int j = 0; j <= 1000; ++j) {\n int bb = b;\n if(j > (a - 3*i) / 2 || j > b)break;\n for (int k = 0; k <=1000 ; ++k) {\n if(k > min({a - (3 * i) - (2 * j),b - j,c}))break;\n ans = max(ans , i + j + k);\n // cout << i + j + k << endl;\n }\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3416, "score_of_the_acc": -1.5023, "final_rank": 18 }, { "submission_id": "aoj_0281_5007574", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint team(int c, int a, int n);\n\nint main(void){\n int Q;\n cin>>Q;\n for(int i=0;i<Q;i++){\n int c,a,n;\n cin>>c>>a>>n;\n cout<<team(c,a,n)<<endl;\n }\n return 0;\n}\n\nint team(int c, int a, int n){\n int retval=0;\n for(int tc=0;tc<=n;tc++){\n for(int ta=0;ta<=a-tc;ta++){\n int tb=c-tc-2*ta;\n if(tb<0){continue;}\n tb=tb/3;\n retval=max(retval,ta+tb+tc);\n }\n }\n return retval;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.4914, "final_rank": 7 }, { "submission_id": "aoj_0281_3770211", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nusing ll = long long;\n\nint main()\n{\n ll q;\n ll c, a, n;\n\n cin >> q;\n for (int i = 0; i < q; i++) {\n cin >> c >> a >> n;\n\n ll ans = 0;\n for (int j = 0; j <= 1000; j++) {\n for (int k = 0; k <= 1000; k++) {\n ll tmpc = c - j * 3 - k * 2;\n ll tmpa = a - k;\n\n if (tmpc < 0 || tmpa < 0) continue;\n ans = max(ans, j + k + min(tmpc, min(tmpa, n)));\n }\n }\n\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3096, "score_of_the_acc": -0.6828, "final_rank": 13 }, { "submission_id": "aoj_0281_3766515", "code_snippet": "#include \"bits/stdc++.h\"\n// Custom Header {{{\n#define ALL(x) x.begin(), x.end()\nusing namespace std;\nusing i64 = long long;\nusing pii = pair<i64, i64>;\ntemplate<class A, class B>inline bool chmax(A &a, const B &b){return b>a ? a=b,1 : 0;}\ntemplate<class A, class B>inline bool chmin(A &a, const B &b){return b<a ? a=b,1 : 0;}\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr i64 LINF = 0x3f3f3f3f3f3f3f3fLL;\n// }}}\n\nsigned main()\n{\n ios::sync_with_stdio(false); cin.tie(nullptr);\n int q;\n cin >> q;\n\n while(q--) {\n int c, a, n;\n cin >> c >> a >> n;\n\n int ans = 0;\n for (int x = 0; x <= 1000; ++x) {\n for (int z = 0; z <= 1000; ++z) {\n if (\n 2*x + z <= c &&\n x + z <= a &&\n z <= n) {\n int y = (c - 2 * x - z) / 3;\n chmax(ans, x + y + z);\n }\n\n }\n }\n\n cout << ans << \"\\n\";\n }\n\n return 0;\n}\n\n// vim: set foldmethod=marker :", "accuracy": 1, "time_ms": 70, "memory_kb": 3200, "score_of_the_acc": -0.6617, "final_rank": 11 }, { "submission_id": "aoj_0281_3055591", "code_snippet": "#include <stdio.h>\n\n#define min(X, Y) ((X) < (Y) ? (X) : (Y))\n#define max(X, Y) ((X) > (Y) ? (X) : (Y))\n\nint main()\n{\n int q;\n int c, a, n;\n int i, j;\n\n scanf(\"%d\", &q);\n for (i = 0; i < q; i++) {\n int ans = 0;\n scanf(\"%d %d %d\", &c, &a, &n);\n \n int speed, ant, sin;\n\n for (speed = 0; speed <= 333; speed++) {\n for (ant = 0; ant <= 500; ant++) {\n if (c >= (speed * 3 + ant * 2) &&\n a >= ant) {\n sin = min(c - (speed * 3 + ant * 2), min(a - ant, n));\n ans = max(ans, sin + speed + ant);\n }\n }\n }\n printf(\"%d\\n\", ans);\n }\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2748, "score_of_the_acc": -0.4039, "final_rank": 6 }, { "submission_id": "aoj_0281_2844100", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint main(){\n \n int y,c[1000],a[1000],n[1000],p[1000];\n cin>>y;\n \n for(int i=0;i<y;i++){\n\n cin>>c[i]>>a[i]>>n[i];\n int cd,ad,nd;\n nd=min(c[i],a[i]);\n nd=min(nd,n[i]);\n ad=min(c[i]/2,a[i]);\n cd=c[i]/3;\n p[i]=cd;\n \n for(int t=0;t<=cd;t++){\n for(int h=0;h<=ad;h++){\n for(int j=0;j<=nd;j++){\n\t if(t*3+h*2+j<=c[i] && h+j<=a[i] && j<=n[i]){p[i]=max(p[i],t+h+j);}\n\t else{break;}\n }\n }\n }\n\n\n }\n\n for(int i=0;i<y;i++){\n cout<<p[i]<<endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 3104, "score_of_the_acc": -1.4468, "final_rank": 17 }, { "submission_id": "aoj_0281_2694281", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing PII = pair<int, int>;\nusing LL = long long;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing PLL = pair<LL, LL>;\nusing VS = vector<string>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\n#define FF first\n#define SS second\n\n#define DUMP(x) cout<<#x<<\":\"<<(x)<<endl\ntemplate<class S, class T>\nistream& operator>>(istream& is, pair<S,T>& p){\n return is >> p.FF >> p.SS;\n}\ntemplate<class T>\nistream& operator>>(istream& is, vector<T>& xs){\n for(auto& x: xs)\n\tis >> x;\n return is;\n}\ntemplate<class S, class T>\nostream& operator<<(ostream& os, const pair<S,T>& p){\n return os << p.FF << \" \" << p.SS;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, const vector<T>& xs){\n for(unsigned int i=0;i<xs.size();++i)\n\tos << (i?\" \":\"\") << xs[i];\n return os;\n}\ntemplate<class T>\nvoid maxi(T& x, T y){\n if(x < y) x = y;\n}\ntemplate<class T>\nvoid mini(T& x, T y){\n if(x > y) x = y;\n}\n\n\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst LL MOD = 1e9+7;\n\nint main(){\n cin.tie(0);\n ios_base::sync_with_stdio(false);\n\n int Q;\n cin >> Q;\n while(Q--){\n\tint c, a, n;\n\tcin >> c >> a >> n;\n\n\tint ans = 0;\n\tREP(i1,1001) REP(i2,1001){\n\t int cc = c - i1 * 2 - i2 * 3;\n\t int aa = a - i1 * 1;\n\t if(cc < 0 || aa < 0) continue;\n\t maxi(ans, i1+i2+min({aa,cc,n}));\n\t}\n\tcout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3152, "score_of_the_acc": -0.6019, "final_rank": 9 }, { "submission_id": "aoj_0281_2526957", "code_snippet": "#include <map>\n#include <set>\n#include <list>\n#include <cmath>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <complex>\n#include <cstdlib>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <utility>\n#include <iostream>\n#include <algorithm>\n#include <functional>\n\nusing namespace std;\n\n#define INF (1 << 30)\n#define INFL (1LL << 62)\n#define MOD7 1000000007\n#define MOD9 1000000009\n#define EPS 1e-10\n\n#define ll long long\n#define ull unsigned long long\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pul pair<ull, ull>\n#define all(a) (a).begin(), (a).end()\n#define FOR(i,a,b) for (int i=(a);i<(b);++i)\n#define RFOR(i,a,b) for (int i=(b)-1;i>=(a);--i)\n#define REP(i,n) for (int i=0;i<(n);++i)\n#define RREP(i,n) for (int i=(n)-1;i>=0;--i)\n\nvoid YES() { cout << \"YES\" << endl; }\nvoid NO() { cout << \"NO\" << endl; }\nvoid Yes() { cout << \"Yes\" << endl; }\nvoid No() { cout << \"No\" << endl; }\nvoid yes() { cout << \"yes\" << endl; }\nvoid no() { cout << \"no\" << endl; }\nvoid Taka() { cout << \"Takahashi\" << endl; }\nvoid Aoki() { cout << \"Aoki\" << endl; }\nvoid digit(int d) { cout << fixed << setprecision(d); }\nvoid IOup() { cin.tie(0); ios::sync_with_stdio(false); }\n\nint main() {\n\tint q;\n\tcin >> q;\n\twhile (q--) {\n\t\tint c, a, n, ans = 0;\n\t\tcin >> c >> a >> n;\n\t\tfor (int z = 0; z <= n; ++z) {\n\t\t\tfor (int x = 0; x <= a - z; ++x) {\n\t\t\t\tint y = (c - 2 * x - z) / 3;\n\t\t\t\tif (y >= 0 && 2 * x + 3 * y + z <= c) {\n\t\t\t\t\tans = max(ans, x + y + z);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3104, "score_of_the_acc": -0.4944, "final_rank": 8 }, { "submission_id": "aoj_0281_2526611", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nint n;\nvector<char>c(100);\nint main() {\n\tint q;\n\tcin >> q;\n\tfor (int i = 0; i < q; i++) {\n\t\tint C, A, N, ans = 0;\n\t\tcin >> C >> A >> N;\n\t\tfor (int i = 0; i <= 1000; i++) {\n\t\t\tfor (int j = 0; j <= 1000; j++) {\n\t\t\t\tint c = C;\n\t\t\t\tint a = A;\n\t\t\t\tint n = N;\n\t\t\t\tc -= i; a -= i; n -= i;\n\t\t\t\tc -= j * 2; a -= j;\n\t\t\t\tif (c >= 0 && a >= 0 && n >= 0) {\n\t\t\t\t\tans = max(ans,i + j + c / 3);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3120, "score_of_the_acc": -0.6651, "final_rank": 12 }, { "submission_id": "aoj_0281_2439288", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\n/*\n * \n */\nint main(int argc, char** argv) {\n int Q,c,a,n;\n cin >> Q;\n \n for(int i=0;i<Q;i++){\n cin >> c >> a >> n;\n int lim = (c+a+n)/3,res = 0;\n if(lim>c)lim = c;\n int j = 0,k = 0,l = 0;\n for(;(j+k+l<=lim&&j*3+k*2+l<=c)&&(k+l<=a&&l<=n);j++){\n for(;(j+k+l<=lim&&j*3+k*2+l<=c)&&(k+l<=a&&l<=n);k++){\n for(;(j+k+l<=lim&&j*3+k*2+l<=c)&&(k+l<=a&&l<=n);l++){\n if(j+k+l>res)res = j+k+l;\n }\n l = 0;\n }\n k = 0;\n }\n j = 0;\n cout << res << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3052, "score_of_the_acc": -1.4098, "final_rank": 16 }, { "submission_id": "aoj_0281_2006384", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<map>\n#include<algorithm>\nusing namespace std;\n\n\nint main() \n{ \n\tint a;\n\tcin >> a;\n\tfor (int b = 0; b < a; b++) \n\t{\n\t\tint c, d, e;\n\t\tcin >> c >> d >> e;\n\t\tint s = 0;\n\t\tfor (int f = 0; f <=c / 3; f++) {\n\t\t\tfor (int g = 0; g <= (c - f * 3) / 2 && g <= d;g++) {\n\t\t\t\tvector<int>h{ (c - f * 3 - g * 2),d - g,e };\n\t\t\t\tsort(h.begin(), h.end());\n\t\t\t\tif (s < h[0]+f+g)s = h[0]+f+g;\n\t\t\t}\n\t\t}\n\t\tcout << s << endl;\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3144, "score_of_the_acc": -0.6474, "final_rank": 10 }, { "submission_id": "aoj_0281_1964112", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint Q;\nint C,A,N;\nint main()\n{\n scanf(\"%d\",&Q);\n for(int i=0;i<Q;i++){\n scanf(\"%d%d%d\",&C,&A,&N);\n int ans=0;\n for(int te3=0;te3<=N;te3++){\n \tint C1=C,A1=A,N1=N;\n int team=te3;\n C1-=te3;A1-=te3;N1-=te3;\n if(C1<0||A1<0)continue;\n \n for(int te2=0;te2<=A1;te2++){\n A1=A-te3;C1=C-te3;\n team=te3;\n team+=te2;\n A1-=te2;C1-=2*te2;\n if(C1<0)continue;\n team+=C1/3;\n ans=max(ans,team);\n }\n \n C1=C;A1=A;N1=N;\n }\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 0.375, "time_ms": 10, "memory_kb": 1188, "score_of_the_acc": -0.0071, "final_rank": 19 }, { "submission_id": "aoj_0281_1943362", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint ans,m,a,c,n,sa,sc,scc;\n\nint main(){\n cin >> m;\n for(int i=0;i<m;i++){\n cin >> c >> a >> n;\n\n for(int i=0;i<=c/3;i++){\n sc=c-3*i;\n for(int j=0;j<=min(sc/2,a);j++){\n scc=sc-j*2;\n sa=a-j;\n for(int k=0;k<=min(scc,min(sa,n));k++){\n ans=max(ans,i+j+k);\n }\n }\n }\n\n\n\n cout << ans << endl;\n c=0,a=0,n=0,ans=0;\n }\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 1160, "score_of_the_acc": -1, "final_rank": 14 }, { "submission_id": "aoj_0281_1651338", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < (int)(j); ++i)\n#define FOR(i, j, k) for(int i = (int)(j); i < (int)(k); ++i)\n#define SORT(v) sort((v).begin(), (v).end())\n#define REVERSE(v) reverse((v).begin(), (v).end())\ntypedef complex<double> P;\nconst int MAX_CAN = 1002;\n\nint dp[MAX_CAN][MAX_CAN];\n\nint main() {\n memset(dp, -1, sizeof(dp));\n dp[0][0] = 0;\n REP(i, MAX_CAN){\n REP(j, MAX_CAN){\n if(i - 1 >= 0) dp[i][j] = max(dp[i][j], dp[i - 1][j]);\n if(j - 1 >= 0) dp[i][j] = max(dp[i][j], dp[i][j - 1]);\n if(dp[i][j] < 0) continue;\n if(i + 2 < MAX_CAN && j + 1 < MAX_CAN) dp[i + 2][j + 1] = max(dp[i + 2][j + 1], dp[i][j] + 1);\n if(i + 3 < MAX_CAN) dp[i + 3][j] = max(dp[i + 3][j], dp[i][j] + 1);\n } }\n int Q; cin >>Q;\n while(Q--){\n int C, A, N, ans = 0; cin >>C >>A >>N;\n REP(i, N + 1) if(C - i >= 0 && A - i >= 0) ans = max(ans, dp[C - i][A - i] + i);\n cout <<ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5092, "score_of_the_acc": -1, "final_rank": 14 }, { "submission_id": "aoj_0281_1173350", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main() {\n int Q;\n cin >> Q;\n int c, a, n;\n while (Q--) {\n cin >> c >> a >> n;\n int team = 0;\n for (int ccc=0; ccc<1001; ++ccc) {\n if (c < ccc * 3) break;\n for (int cca=0; cca<1001; ++cca) {\n if (c < ccc * 3 + cca * 2 || a < cca) break;\n team = max(team, ccc + cca + min(c - ccc * 3 - cca * 2, min(a - cca, n)));\n }\n }\n cout << team << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1164, "score_of_the_acc": -0.001, "final_rank": 2 }, { "submission_id": "aoj_0281_1169279", "code_snippet": "#include<iostream>\n#include<algorithm>\n\nusing namespace std;\n\nint q, n, a, b, c;\n\nint solve(int c, int a, int n){\n\tint res = 0;\n\tfor(int i = 0;i <= 1080;i++){\n\t\tfor(int j = 0;j <= 1080;j++){\n\t\t\tint tc = c - i - 2 * j;\n\t\t\tint ta = a - i - j;\n\t\t\tint tn = n - i;\n\t\t\tif(tc >= 0 && ta >= 0 && tn >= 0){\n\t\t\t\tres = max(res, i + j + tc / 3);\n\t\t\t}\n\t\t}\n\t}\n\treturn res;\n}\n\nint main(){\n\tcin >> q;\n\tfor(int i = 0;i < q;i++){\n\t\tcin >> c >> a >> n;\n\t\tcout << solve(c, a, n) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 1160, "score_of_the_acc": -0.1905, "final_rank": 4 }, { "submission_id": "aoj_0281_1135962", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \nusing namespace std; \ntypedef long long ll;\nconst double eps = 1e-10;\n\nint main(){\n int Q;\n cin >> Q;\n for(int _=0;_<Q;++_){\n int c, a, n;\n cin >> c >> a >> n;\n int res = 0;\n for(int i = 0; i <= c / 3; ++i){\n for(int j = 0; j <= min((c - i * 3) / 2, a); ++j){\n res = max(res, i + j + min(c-i*3-j*2, min(a-j, n)));\n }\n }\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0281_1075186", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <numeric>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <set>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-9\n#define INF 2000000000\n#define sz(x) ((int)(x).size())\n#define fi first\n#define sec second\n#define SORT(x) sort((x).begin(),(x).end())\n#define all(x) (x).begin(),(x).end()\n#define EQ(a,b) (abs((a)-(b))<eps)\nint cnt(int c,int a)\n{\n\tint mx=0;\n\tfor(int i=0;i<=min(a,c/2);i++)mx=max(mx,i+(c-2*i)/3);\n\treturn mx;\n}\nvoid solve(int c,int a,int n)\n{\n\tint ans=0;\n\tfor(int i=0;i<=min(n,min(a,c));i++)ans=max(ans,i+cnt(c-i,a-i));\n\tprintf(\"%d\\n\",ans);\n\treturn;\n}\nint main()\n{\n\tint Q;\n\tscanf(\"%d\",&Q);\n\tfor(int i=0;i<Q;i++)\n\t{\n\t\tint c,a,n;\n\t\tscanf(\"%d %d %d\",&c,&a,&n);\n\t\tsolve(c,a,n);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1188, "score_of_the_acc": -0.0071, "final_rank": 3 }, { "submission_id": "aoj_0281_1069266", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n\nusing namespace std;\n\n#define rep(i,j) REP((i), 0, (j))\n#define REP(i,j,k) for(int i=(j);(i)<(k);++i)\n#define BW(a,x,b) ((a)<=(x)&&(x)<=(b))\n#define ALL(v) (v).begin(), (v).end()\n#define LENGTHOF(x) (sizeof(x) / sizeof(*(x)))\n#define AFILL(a, b) fill((int*)a, (int*)(a + LENGTHOF(a)), b)\n#define MP make_pair\n#define PB push_back\n#define F first\n#define S second\n#define INF 1 << 30\n#define EPS 1e-10\n\ntypedef pair<int, int> pi;\ntypedef pair<int, pi> pii;\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef long long ll;\n\nint Q;\nint dp[64][64][64];\n\nint dfs(int c, int a, int n){\n if(dp[c][a][n] >= 0) return dp[c][a][n];\n int res = 0;\n if(c > 0 && a > 0 && n > 0) res = max(res, dfs(c-1, a-1, n-1)+1);\n if(c > 1 && a > 0) res = max(res, dfs(c-2, a-1, n)+1);\n if(c > 2) res = max(res, dfs(c-3, a, n)+1);\n return dp[c][a][n] = res;\n}\n\nint main(){\n cin >> Q;\n rep(i, Q){\n memset(dp, -1, sizeof(dp));\n int c, a, n;\n cin >> c >> a >> n;\n int res = 0;\n while(c > 8 && a > 4 && n > 0){\n res++;\n c--;\n a--;\n n--;\n }\n\n while(c > 8 && a > 4){\n res++;\n c-=2;\n a--;\n }\n\n while(c > 8){\n res++;\n c-=3;\n }\n res += dfs(c, a, n);\n printf(\"%d\\n\", res);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2176, "score_of_the_acc": -0.2584, "final_rank": 5 }, { "submission_id": "aoj_0281_1069265", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n\nusing namespace std;\n\n#define rep(i,j) REP((i), 0, (j))\n#define REP(i,j,k) for(int i=(j);(i)<(k);++i)\n#define BW(a,x,b) ((a)<=(x)&&(x)<=(b))\n#define ALL(v) (v).begin(), (v).end()\n#define LENGTHOF(x) (sizeof(x) / sizeof(*(x)))\n#define AFILL(a, b) fill((int*)a, (int*)(a + LENGTHOF(a)), b)\n#define MP make_pair\n#define PB push_back\n#define F first\n#define S second\n#define INF 1 << 30\n#define EPS 1e-10\n\ntypedef pair<int, int> pi;\ntypedef pair<int, pi> pii;\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef long long ll;\n\nint Q;\nint dp[64][64][64];\n\nint dfs(int c, int a, int n){\n if(dp[c][a][n] >= 0) return dp[c][a][n];\n int res = 0;\n if(c > 0 && a > 0 && n > 0) res = max(res, dfs(c-1, a-1, n-1)+1);\n if(c > 1 && a > 0) res = max(res, dfs(c-2, a-1, n)+1);\n if(c > 2) res = max(res, dfs(c-3, a, n)+1);\n return dp[c][a][n] = res;\n}\n\nint main(){\n cin >> Q;\n rep(i, Q){\n memset(dp, -1, sizeof(dp));\n int c, a, n;\n cin >> c >> a >> n;\n int res = 0;\n while(c > 5 && a > 3 && n > 0){\n res++;\n c--;\n a--;\n n--;\n }\n\n while(c > 5 && a > 3){\n res++;\n c-=2;\n a--;\n }\n\n while(c > 5){\n res++;\n c-=3;\n }\n res += dfs(c, a, n);\n printf(\"%d\\n\", res);\n }\n return 0;\n}", "accuracy": 0.375, "time_ms": 10, "memory_kb": 2176, "score_of_the_acc": -0.2584, "final_rank": 20 } ]
aoj_0279_cpp
おそろいの景品 ジョウ君とヤエさんは仲の良いカップルです。ジョウ君はカプセル玩具自販機(ガチャポン)の景品を集めており、二人で出かけたときも、ガチャポンを見つけると何度かやってみるほどの熱の入りようです。ヤエさんは楽しそうなジョウ君をそばで見ているだけでしたが、ジョウ君の今度の誕生日プレゼントにガチャポンの景品をひとつあげることにしました。ヤエさんはガチャポン自体にはあまり興味がわきませんでしたが、できればジョウ君とおそろいの景品が欲しいと思っています。 ヤエさんがやってみようと思うガチャポンは、1回のチャレンジで景品がひとつ出ます。品切れのものも含め景品が何種類あるのかと、それぞれの景品がいくつ残っているのかはわかります。しかし、1回のチャレンジでどの景品が出るかはわかりません。そこで、景品が出る順番にかかわらず、ヤエさんが同じ景品を必ず2つ得るために最低限必要なチャレンジの回数を出力するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 N k 1 k 2 ... k N 各データセットは2行であり、1行目に景品が何種類あるかを表す整数 N (1 ≤ N ≤ 10000)が与えられる。続く1行に各景品がいくつ残っているのかを表す整数 k i (0 ≤ k i ≤ 10000)が与えられる。 データセットの数は100を超えない。 出力 データセットごとに、同じ景品を必ず2つ得るために最低限必要なチャレンジの回数を出力する。ただし、不可能な場合はNAと出力する。 入力例 2 3 2 3 0 1 1 1 1000 0 出力例 3 NA 2 1つ目のデータセットでは、運良く1種類目か2種類目の景品が連続で出て2回で済む可能性はあるが、同じ種類の景品を必ず2つ得るためには3回チャレンジする必要がある。 2つ目のデータセットでは、2つ以上残っている景品がもともと無いので不可能である。 3つ目のデータセットでは、景品は1種類だけなので2回のチャレンジでその景品が必ず2つ得られる。
[ { "submission_id": "aoj_0279_10867650", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <map>\n#include <numeric>\n#include <bitset>\n#include <vector>\n#include <queue>\n\nusing namespace std;\n\ntypedef long long ll;\n#define FOR(i,a,b) for( ll i = (a); i < (b); i++ )\n#define REP(i,n) FOR(i,0,n)\ntypedef pair< ll, ll > cp2;\ntypedef pair< ll, cp2 > cp3;\n#define fi first\n#define se second\n#define sec se.fi\n#define thr se.se\nconst ll mod = 1000000007;\n// 123456789\n\nint k[10005];\n\nint main(){\n\tint n;\n\t\n\twhile (cin >> n, n){\n\t\tint flag = 1;\n\t\t\n\t\tint num = n;\n\t\t\n\t\tREP(i,n){\n\t\t\tcin >> k[i];\n\t\t\t\n\t\t\tif (k[i] > 1) flag = 0;\n\t\t\tif (k[i] == 0) num--;\n\t\t}\n\t\t\n\t\tif (flag)\tcout << \"NA\" << endl;\n\t\telse cout << num+1 << endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3448, "score_of_the_acc": -1.6843, "final_rank": 16 }, { "submission_id": "aoj_0279_10852071", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n for(int N;cin>>N,N!=0;){\n int w=0;\n int ma=0;\n rep(i,N){\n int k;\n cin>>k;\n w+=min(k,1);\n chmax(ma, k);\n }\n if(ma<=1) cout<<\"NA\\n\";\n else cout<<w+1<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": -0.9444, "final_rank": 4 }, { "submission_id": "aoj_0279_10783176", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n\nbool solve(){\n ll N;cin>>N;\n if(N==0)return false;\n bool can = false;\n ll ans = 1;\n rep(i,N){\n ll k;cin>>k;\n if(k>=1)ans++;\n if(k>=2)can = true;\n }\n if(can){\n cout<<ans<<endl;\n }\n else {\n cout<<\"NA\"<<endl;\n }\n return true;\n}\n\nint main(){\n while(solve());\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3440, "score_of_the_acc": -1.6742, "final_rank": 15 }, { "submission_id": "aoj_0279_10717840", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\nint main(){\n int n;\n int k[10000];\n int cnt = 0;\n int cnt2 = 0;\n vector<int> ans;\n while(true){\n cin >> n;\n if(n == 0) break;\n cnt = 0;\n cnt2=0;\n for(int i=0; i<n; ++i){\n cin >> k[i];\n if(k[i] >= 1) cnt++;\n if(k[i] <= 1) cnt2++;\n }\n if(cnt2==n) cnt = 0;\n ans.push_back(cnt);\n }\n for(int i=0; i<(int)ans.size(); ++i){\n if(ans[i]==0) cout << \"NA\" << endl;\n else cout << ans[i]+1 << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3480, "score_of_the_acc": -1.5997, "final_rank": 14 }, { "submission_id": "aoj_0279_10717812", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\nint main(){\n int n;\n int k[10000];\n int cnt = 0;\n vector<int> ans;\n while(true){\n cin >> n;\n if(n == 0) break;\n cnt = 0;\n for(int i=0; i<n; ++i){\n cin >> k[i];\n if(k[i] >= 2) cnt++;\n }\n ans.push_back(cnt);\n }\n for(int i=0; i<(int)ans.size(); ++i){\n if(ans[i]==0) cout << \"NA\" << endl;\n else cout << ans[i]+1 << endl;\n }\n}", "accuracy": 0.3333333333333333, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -1.3093, "final_rank": 20 }, { "submission_id": "aoj_0279_9644847", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while (1) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n int k[n + 1];\n int sum[n + 1] = {};\n int cnt = 0;\n bool flg = false;\n for (int i = 1; i <= n; i++) {\n cin >> k[i];\n if (k[i] > 0) {\n cnt++;\n }\n if (k[i] >= 2) {\n flg = true;\n }\n sum[i] = sum[i - 1] + k[i];\n }\n if (!flg) {\n cout << \"NA\\n\";\n continue;\n }\n cout << cnt + 1 << \"\\n\";\n }\n return(0);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3500, "score_of_the_acc": -1.75, "final_rank": 17 }, { "submission_id": "aoj_0279_9644841", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n while (1) {\n int n;\n cin >> n;\n if (n == 0) {\n break;\n }\n int k[n + 1];\n int sum[n + 1] = {};\n bool flg = false;\n for (int i = 1; i <= n; i++) {\n cin >> k[i];\n if (k[i] < 2) {\n flg = true;\n }\n sum[i] = sum[i - 1] + k[i];\n }\n if (flg) {\n cout << \"NA\\n\";\n continue;\n }\n cout << n + 1 << \"\\n\";\n }\n return(0);\n}", "accuracy": 0.3333333333333333, "time_ms": 40, "memory_kb": 3432, "score_of_the_acc": -1.2891, "final_rank": 19 }, { "submission_id": "aoj_0279_9577932", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void)\n{\n\t\tint n,k,cnt,flg,i;\n\t\twhile(1){\n\t\t\tcin>>n;\n\t\t if(n==0)break;\n\t\t\tflg=0;cnt=0;\n\t\t\tfor(i=0;i<n;i++){\n\t\t\tcin>>k;\n\t\t\tif(k>=2)flg=1;\n\t\t\tif(k>=1)cnt++;\n\t\t\t}\n\t\t\tif(flg==0)cout<<\"NA\"<<endl;\n\t\t\telse cout<<cnt+1<<endl;\n\t\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3112, "score_of_the_acc": -1.5101, "final_rank": 11 }, { "submission_id": "aoj_0279_9577453", "code_snippet": "#include<bits/stdc++.h>\n#define ph push_back\n#define p push\n#define ll long long\nusing namespace std;\nint main()\n{\n\tint n,k[10001],cnt=0,c=0;\n\tbool f=false;\n\twhile(1) {\n\t\tcin >> n;\n\t\tif ( n == 0 ) break;\n\t\tfor( int i = 0 ; i < n ; i ++ ) cin >> k[i];\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(k[i]>=2) cnt++;\n\t\t\tif(k[i]>=1) c++;\n\t\t}\n\t\tif(cnt>=1) cout<<c+1<<endl;\n\t\telse cout<<\"NA\"<<endl;\n\t\tcnt=0; c=0;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3112, "score_of_the_acc": -1.5101, "final_rank": 11 }, { "submission_id": "aoj_0279_9577072", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void)\n{\n\tint n,k,cnt,flg;\n\twhile(1){\n\t\tcin>>n;\n\t\tif(n==0)break;\n\t\tflg=0;\n\t\tcnt=0;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tcin>>k;\n\t\t\tif(k>=2)flg=1;\n\t\t\tif(k>=1)cnt++;\n\t\t}\n\t\tif(flg==0) cout<<\"NA\"<<endl;\n\t\telse cout<<cnt+1<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3092, "score_of_the_acc": -1.4848, "final_rank": 7 }, { "submission_id": "aoj_0279_9576839", "code_snippet": "#include<bits/stdc++.h>\n#define ph push_back\n#define p push\n#define ll long long\nusing namespace std;\nint main()\n{\n\tint n,k[10001],cnt=0,c=0,flg[10001]={0},fl[10001]={0};\n\tbool f=false;\n\twhile(1) {\n\t\tcin >> n;\n\t\tif ( n == 0 ) break;\n\t\tfor( int i = 0 ; i < n ; i ++ ) cin >> k[i];\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(k[i]>=2) cnt++;\n\t\t\tif(k[i]>=1) c++;\n\t\t}\n\t\tif(cnt>=1) cout<<c+1<<endl;\n\t\telse cout<<\"NA\"<<endl;\n\t\tcnt=0; c=0;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3148, "score_of_the_acc": -1.5556, "final_rank": 13 }, { "submission_id": "aoj_0279_9575651", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,k,i,cnt,tnc;\n\twhile(1){\n\t\tcnt=0;\n\t\ttnc=0;\n\t\tcin>>n;\n\t\tif(n==0) break;\n\t\tfor(i=0;i<n;i++){\n\t\t\tcin>>k;\n\t\t\tif(k>=2) cnt++;\n\t\t\telse if(k==0) tnc++;\n\t\t}\n\t\tif(n==1 && cnt==1) cout<<2<<endl;\n\t\telse if(n>=2 && cnt>=1) cout<<n+1-tnc<<endl;\n\t\telse cout<<\"NA\"<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3092, "score_of_the_acc": -1.4848, "final_rank": 7 }, { "submission_id": "aoj_0279_9575641", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void)\n{\n\tint n,k,cnt,flg,i;\n\twhile(1)\t{\n\t\tcin >>n;\n\t\tif(n==0)\tbreak;\n\t\tflg=0;\tcnt=0;\n\t\tfor(i=0;i<n;i++)\t{\n\t\t\tcin >>k;\n\t\t\tif(k>=2)\tflg=1;\n\t\t\tif(k>=1)\tcnt++;\n\t\t}\n\t\tif(flg==0)\tcout <<\"NA\"<<endl;\n\t\telse cout <<cnt+1<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3108, "score_of_the_acc": -1.5051, "final_rank": 10 }, { "submission_id": "aoj_0279_8894069", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (0 == n)\n {\n break;\n }\n\n int upper1 = 0;\n int upper2 = 0;\n\n for (int i = 0; i < n; ++i)\n {\n int k;\n cin >> k;\n if (k >= 1) ++upper1;\n if (k >= 2) ++upper2;\n }\n if (0 == upper2)\n {\n cout << \"NA\" << endl;\n }\n else\n {\n cout << upper1 + 1 << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3084, "score_of_the_acc": -1.4747, "final_rank": 5 }, { "submission_id": "aoj_0279_8894066", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (0 == n)\n {\n break;\n }\n\n int less1cnt = 0;\n int zerocnt = 0;\n\n for (int i = 0; i < n; ++i)\n {\n int k;\n cin >> k;\n if (k <= 1)\n {\n ++less1cnt;\n }\n if (0 == k)\n {\n ++zerocnt;\n }\n }\n if (n == less1cnt)\n {\n cout << \"NA\" << endl;\n }\n else\n {\n cout << n - zerocnt + 1 << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3084, "score_of_the_acc": -1.4747, "final_rank": 5 }, { "submission_id": "aoj_0279_8894064", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (0 == n)\n {\n break;\n }\n\n int lesscnt = 0;\n int zerocnt = 0;\n\n for (int i = 0; i < n; ++i)\n {\n int k;\n cin >> k;\n if (k <= 1)\n {\n ++lesscnt;\n }\n if (0 == k)\n {\n ++zerocnt;\n }\n }\n if (n == lesscnt)\n {\n cout << \"NA\" << endl;\n }\n else\n {\n cout << n - zerocnt + 1 << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3096, "score_of_the_acc": -1.4899, "final_rank": 9 }, { "submission_id": "aoj_0279_8894049", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n while (true)\n {\n int n;\n cin >> n;\n if (0 == n)\n {\n break;\n }\n\n int lesscnt = 0;\n int zerocnt = 0;\n\n for (int i = 0; i < n; ++i)\n {\n int k;\n cin >> k;\n if (k <= 1)\n {\n ++lesscnt;\n }\n else if (0 == k)\n {\n ++zerocnt;\n }\n }\n if (n == lesscnt)\n {\n cout << \"NA\" << endl;\n }\n else\n {\n cout << n - zerocnt + 1 << endl;\n }\n }\n}", "accuracy": 0.3333333333333333, "time_ms": 50, "memory_kb": 3096, "score_of_the_acc": -0.9899, "final_rank": 18 }, { "submission_id": "aoj_0279_8861578", "code_snippet": "#include <stdio.h>\n#include <stdbool.h>\n\nint main(void) {\n int num_elements, num_non_zeros, current_num, zero_count, i;\n bool num_greater_than_one_exists;\n\n while (1) {\n num_greater_than_one_exists = false;\n zero_count = 0;\n\n scanf(\"%d\", &num_elements);\n if (num_elements == 0)\n break;\n\n for (i = 0; i < num_elements; i++) {\n scanf(\"%d\", &current_num);\n if (current_num == 0) {\n zero_count++;\n }\n if (current_num >= 2) {\n num_greater_than_one_exists = true;\n }\n }\n\n num_non_zeros = num_elements - zero_count;\n if (num_greater_than_one_exists) {\n printf(\"%d\\n\", num_non_zeros + 1);\n } else {\n printf(\"NA\\n\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 2732, "score_of_the_acc": -0.2803, "final_rank": 2 }, { "submission_id": "aoj_0279_8861576", "code_snippet": "#include <stdio.h>\nint main(void) {\n int s, n, k, i, flg;\n while (1) {\n flg = 0;\n s = 0;\n scanf(\"%d\", &n);\n if (n == 0)\n break;\n for (i = 0; i < n; i++) {\n scanf(\"%d\", &k);\n if (k >= 2) {\n flg = 1;\n }\n if (k != 0) {\n s = s + 1;\n }\n }\n if (flg == 1) {\n printf(\"%d\\n\", s + 1);\n } else {\n printf(\"NA\\n\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 2760, "score_of_the_acc": -0.3157, "final_rank": 3 }, { "submission_id": "aoj_0279_8861575", "code_snippet": "#include <stdio.h>\n\nint main(void) {\n int s = 0, n, k, i, flg;\n while (1) {\n flg = 0;\n s = 0;\n scanf(\"%d\", &n);\n if (n == 0)\n break;\n for (i = 0; i < n; i++) {\n scanf(\"%d\", &k);\n if (k != 0) {\n s++;\n if (k >= 2) {\n flg = 1;\n }\n }\n }\n if (flg == 1) {\n printf(\"%d\\n\", s + 1);\n } else {\n printf(\"NA\\n\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 2708, "score_of_the_acc": -0.25, "final_rank": 1 } ]
aoj_0283_cpp
勉強会 プログラマー養成校のアカベ高校には、生徒自身で運営するユニークな勉強会があります。プログラマーは新しい技術を常に取り入れることが大切なので、この勉強会を通して自学自習の習慣を身につけることがこの活動のねらいです。 生徒は全部で N 人おり、それぞれが入学時のプログラミングコンテストの結果で得られたスコアを持っています。勉強会では N 人の生徒のうち何人かがリーダーになり、各リーダーがそれぞれのグループを運営するとともに、自らの運営するグループに参加します。 リーダー以外の生徒は、自分のスコアよりも低いスコアのリーダーが運営するグループには参加できません。また、0以上のある値 r を1つ決め、グループに参加する生徒とリーダーのスコアの差が r 以内となるようにしています。つまり、グループのリーダーのスコアが s のとき、自分のスコアが s を超えているか、あるいは s - r 未満ならば、そのグループには参加できません。 あなたは勉強会の実行委員長であり、運営準備のためにシミュレーションを行うことにしました。シミュレーションでは、リーダーが誰もいない状態から始め、以下の操作を何回か繰り返します。 生徒をリーダーに加える。 生徒をリーダーから外す。 要求時点でのリーダーの組み合わせについて、どのグループにも参加できない生徒が x 人以下になるような、最小の r を求める。 このようなシミュレーションを行うプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力は以下の形式で与えられる。 N Q s 1 s 2 : s N QUERY 1 QUERY 2 : QUERY Q 1行目に生徒の数 N (1 ≤ N ≤ 1000000)、処理要求の数 Q (0 ≤ Q ≤ 1000)が与えられる。 続く N 行に i 番目の生徒のスコアを示す整数 s i (0 ≤ s i ≤ 1,000,000,000)が与えられる。生徒は1,2,..., N で番号付けされているものとする。 続く Q 行に処理要求 QUERY i が与えられる。処理要求は時系列順に与えられる。処理要求はADD, REMOVE, CHECKの3種類あり、各 QUERY i は以下のいずれかの形式で与えられる。 ADD a または REMOVE a または CHECK x ADD a は番号 a (1 ≤ a ≤ N )の生徒をリーダーに加えることを表す。 REMOVE a は番号 a (1 ≤ a ≤ N )の生徒をリーダーから外すことを表す。 CHECK x は出力要求を表す。どのグループにも参加できない生徒の数の上限 x (0 ≤ x ≤ N )が与えられる。 なお、入力は以下の条件を満たすものとする。 どの時点でも、リーダーの人数が100人を超えることはない。 その時点でリーダーである生徒をリーダーに加えることはない。 その時点でリーダーでない生徒をリーダーから外すことはない。 出力 時系列順に各出力要求の時点で、どのグループにも参加できない生徒がx人以下になるような最小の r を1行に出力する。ただし、どのような r を選んでも x 人以下にすることが不可能であればNAと出力する。 入力例 1 5 8 5 10 8 7 3 ADD 1 ADD 3 CHECK 0 CHECK 1 CHECK 2 CHECK 3 CHECK 4 CHECK 5 出力例 1 NA 2 1 0 0 0 入力例 2 5 28 5 10 8 7 3 CHECK 0 CHECK 1 CHECK 2 CHECK 3 CHECK 4 CHECK 5 ADD 1 CHECK 0 CHECK 1 CHECK 2 CHECK 3 CHECK 4 CHECK 5 REMOVE 1 ADD 3 CHECK 0 CHECK 1 CHECK 2 CHECK 3 CHECK 4 CHECK 5 ADD 1 CHECK 0 CHECK 1 CHECK 2 CHECK 3 CHECK 4 CHECK 5 出力例 2 NA NA NA NA NA 0 NA NA NA 2 0 0 NA 5 3 1 0 0 NA 2 1 0 0 0
[ { "submission_id": "aoj_0283_10852139", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,Q;\n cin>>N>>Q;\n vector<int> S(N);\n rep(i,N)cin>>S[i];\n\n vector<int> A=S;\n sort(all(A));\n\n vector<int> L;\n while(Q--){\n string O;\n int x;\n cin>>O>>x;\n if(O[0]=='A'){\n x--;\n L.push_back(S[x]);\n }\n else if(O[0]=='R'){\n x--;\n L.erase(find(all(L), S[x]));\n }\n else{\n sort(all(L));\n int ok=(int)1e9+1;\n int ng=-1;\n while(ok-ng>1){\n int m=(ok+ng)/2;\n\n int mae=-1;\n int cnt=0;\n for(int e: L){\n if(e==mae) continue;\n auto rt=lower_bound(all(A), e-m);\n auto lt=upper_bound(all(A), mae);\n cnt+=max(0l, rt-lt);\n mae=e;\n }\n cnt+=A.end()-upper_bound(all(A),mae);\n if(cnt<=x) ok=m;\n else ng=m;\n }\n if(ok>1e9)cout<<\"NA\\n\";\n else cout<<ok<<\"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 11184, "score_of_the_acc": -0.2385, "final_rank": 2 }, { "submission_id": "aoj_0283_10848206", "code_snippet": "//#pragma GCC target (\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp((i),mkp((j),(k)))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) int((a).size())\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all((b)),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)((c)-'0')\n#define itoc(c) (char)((c)+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",quetimes_+1)\n#define readv(a,n) (a).resize((n),0);rep(i,(n)) (a)[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = (ll)15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll ppc(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nvoid fin(T x) { cout << x << endl; exit(0); }\n\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n csum(int sz) { init(sz); }\n void init(int sz) { v = vector<T>(sz + 1, 0); }\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n void add(int l, int r, T x) {\n v[l] += x;\n v[r] -= x;\n }//[l,r)\n void add(int t, T x) {\n v[t] += x;\n }//[l,r)\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n T operator[](int x)const {\n return v[x];\n }\n};\nclass via {\n using H = pair<ll, ll>;\n bool comp;\npublic:\n vector<H>a;\n via() :comp(true) {}\n via(vector<H>dat) :a(dat), comp(false) { build(); }\n void push(int l, int r) { a.push_back(H{ l,r }); comp = false; }\n void push(H a) { push(a.first, a.second); }\n void build() {\n if (comp) return;\n comp = true;\n sort(a.begin(), a.end());\n int fst = -1; ll lst = -1;\n vector<H>b;\n for (int i = 0; i < a.size(); i++) {\n if (fst < 0) fst = i, lst = a[i].second;\n if (lst < a[i].first) {\n b.push_back(H{ a[fst].first,lst });\n fst = i, lst = a[i].second;\n }\n else if (lst < a[i].second) lst = a[i].second;\n }\n if (~fst) b.push_back(H{ a[fst].first, lst });\n a = b;\n }\n ll size() { return ll(a.size()); }\n ll sum() {\n build();\n ll sum = 0;\n for (auto g : a) sum += g.second - g.first;\n return sum;\n }\n via inter(via& v) {\n build(); v.build();\n via ret;\n for (auto g : a) ret.push(g);\n for (auto g : v.a) ret.push(g);\n ret.build(); return ret;\n }\n via comb(via& v) {\n build(); v.build();\n int s = 0, t = 0;\n via ret;\n while (s < a.size() && t < v.size()) {\n if (v[t].second <= a[s].first) t++;\n else if (a[s].second <= v[t].first) s++;\n else {\n ret.push(max(a[s].first, v[t].first), min(a[s].second, v[t].second));\n if (a[s].second <= v[t].second) s++;\n else t++;\n }\n }\n return ret;\n }\n H& operator[](int t) { return a[t]; }\n};\ntemplate<ll mod>\nclass modint {\npublic:ll v;\n modint(ll v = 0) { s(v % mod + mod); }\n constexpr static int fn_ = (ll)2e6 + 5;\n static vector<modint>fact, comp;\n modint pow(ll x) const {\n modint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline modint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline modint inv()const { return pow(mod - 2); }\n inline modint operator-()const { return modint() - *this; }\n inline modint& operator+=(const modint b) { return s(v + b.v); }\n inline modint& operator-=(const modint b) { return s(v + mod - b.v); }\n inline modint& operator*=(const modint b) { v = v * b.v % mod; return *this; }\n inline modint& operator/=(const modint b) { v = v * b.inv().v % mod; return *this; }\n inline modint operator+(const modint& b) const { return modint(v) += b; }\n inline modint operator-(const modint& b) const { return modint(v) -= b; }\n inline modint operator*(const modint& b) const { return modint(v) *= b; }\n inline modint operator/(const modint& b) const { return modint(v) /= b; }\n friend ostream& operator<<(ostream& os, const modint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, modint& m) {\n int x; is >> x; m = modint(x);\n return is;\n }\n bool operator<(const modint& r)const { return v < r.v; }\n bool operator>(const modint& r)const { return v > r.v; }\n bool operator<=(const modint& r)const { return v <= r.v; }\n bool operator>=(const modint& r)const { return v >= r.v; }\n bool operator==(const modint& r)const { return v == r.v; }\n bool operator!=(const modint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n modint comb(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n if (k > *this - k) k = *this - k;\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n modint perm(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact.assign(fn_, modint());\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * modint(i);\n comp.assign(fn_, modint());\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * modint(i + 1);\n }\n};\nusing mint = modint<ll(1e9 + 7)>; template<>vec<mint> mint::fact = vec<mint>(); template<>vec<mint> mint::comp = vec<mint>();\n//--------------------------------------------------------------\n//--------------------------------------------------------------\nsigned main() {\n int n, q; cin >> n >> q;\n vi s; readv(s, n);\n vi a = s; sort(all(a));\n multiset<ll>lead;\n rep(z, q) {\n string st; int t; cin >> st >> t;\n if (st == \"ADD\") {\n t--;\n lead.insert(s[t]);\n }\n else if (st == \"REMOVE\") {\n t--;\n lead.erase(lead.find(s[t]));\n }\n else {\n ll ok = 1e9 + 1, ng = -1, mid;\n while (ok - ng > 1) {\n mid = (ok + ng) / 2;\n int cur = 0, score = 0;\n for (auto g : lead) {\n int t = lower_bound(all(a), g - mid) - a.begin();\n int r = upper_bound(all(a), g) - a.begin();\n score += max(0, r - max(t, cur));\n cur = r;\n }\n if (t + score >= n) ok = mid;\n else ng = mid;\n }\n if (ok == 1e9 + 1) printf(\"NA\\n\");\n else printf(\"%d\\n\", ok);\n }\n }\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 18788, "score_of_the_acc": -0.3895, "final_rank": 7 }, { "submission_id": "aoj_0283_10826925", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Info{\n\tbool operator<(const struct Info &arg) const{\n\t\treturn score < arg.score;\n\t};\n\tint score,id;\n};\n\n\nint main(){\n\n\tint N,Q;\n\tscanf(\"%d %d\",&N,&Q);\n\n\tInfo* info = (Info*)malloc(sizeof(Info)*(N+1));\n\n\tinfo[0].score = -1;\n\tvector<int> SCORE;\n\tSCORE.push_back(-1);\n\tfor(int i = 1; i <= N; i++){\n\t\tscanf(\"%d\",&info[i].score);\n\t\tSCORE.push_back(info[i].score);\n\t}\n\n\tsort(SCORE.begin(),SCORE.end());\n\n\tint* score_ruisekiwa = new int[N+1];\n\tint* score = new int[N+1];\n\n\tint score_index = 1;\n\n\tscore[0] = -1;\n\tscore_ruisekiwa[0] = 0;\n\n\tfor(int i = 1; i <= N; ){\n\n\t\tscore[score_index] = SCORE[i];\n\t\tscore_ruisekiwa[score_index] = 0;\n\n\t\twhile(score[score_index] == SCORE[i] && i <= N){\n\t\t\tscore_ruisekiwa[score_index]++;\n\t\t\ti++;\n\t\t}\n \t\tscore_ruisekiwa[score_index] += score_ruisekiwa[score_index-1];\n \t\tscore_index++;\n\t}\n\n\tint* loc = new int[N+1];\n\n\tint left,right,m;\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tleft = 1,right = score_index-1,m = (left+right)/2;\n\n\t\twhile(left <= right){\n\t\t\tif(score[m] == info[i].score){\n\t\t\t\tloc[i] = m;\n\t\t\t\tbreak;\n\t\t\t}else if(score[m] < info[i].score){\n\t\t\t\tleft = m+1;\n\t\t\t}else{\n\t\t\t\tright = m-1;\n\t\t\t}\n\t\t\tm = (left+right)/2;\n\t\t}\n\t}\n\n\tchar order[10];\n\tint value,current_number,need_number,max_loc;\n\n\tbool* check = new bool[score_index];\n\n\tvector<int> V;\n\tvector<Info> work;\n\tbool FLG;\n\n\tint calc_left,calc_right,calc_m;\n\n\tfor(int loop = 0; loop < Q; loop++){\n\t\tscanf(\"%s %d\",order,&value);\n\n\t\tswitch(order[0]){\n\t\tcase 'A':\n\t\t\tV.push_back(value);\n\t\t\tbreak;\n\t\tcase 'R':\n\t\t\tfor(int i = 0; i < V.size(); i++){\n\t\t\t\tif(V[i] == value){\n\t\t\t\t\tV.erase(V.begin()+i);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tbreak;\n\t\tcase 'C':\n\n\t\t\twork.clear();\n\n\t\t\tneed_number = N - value;\n\t\t\tmax_loc = 0;\n\n\t\t\tfor(int i = 0 ; i <= score_index-1; i++)check[i] = false;\n\n\t\t\tfor(int i = 0; i < V.size(); i++){\n\t\t\t\tmax_loc = max(max_loc,loc[V[i]]);\n\t\t\t\tFLG = true;\n\t\t\t\tfor(int k = i+1; k < V.size(); k++){\n\t\t\t\t\tif(loc[V[i]] == loc[V[k]]){\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(FLG){\n\t\t\t\t\tInfo new_info;\n\t\t\t\t\tnew_info.id = V[i];\n\t\t\t\t\tnew_info.score = score[loc[V[i]]];\n\t\t\t\t\twork.push_back(new_info);\n\t\t\t\t\tcheck[loc[V[i]]] = true;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(score_ruisekiwa[max_loc] < need_number){\n\t\t\t\tprintf(\"NA\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tcurrent_number = 0;\n\t\t\tfor(int i = 0; i < work.size(); i++){\n\t\t\t\tcurrent_number += score_ruisekiwa[loc[work[i].id]] - score_ruisekiwa[loc[work[i].id]-1];\n\t\t\t}\n\n\t\t\tif(current_number >= need_number){\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tint ans = 0;\n\t\t\tint left_loc,right_loc;\n\n\t\t\tsort(work.begin(),work.end());\n\n\t\t\tleft = 0,right = score[max_loc],m = (left+right)/2;\n\n\t\t\twhile(left <= right){\n\n\t\t\t\tint tmp = 0;\n\n\t\t\t\tfor(int i = 0; i < work.size(); i++){\n\n\t\t\t\t\tint left_score = 0;\n\t\t\t\t\tif(i > 0){\n\t\t\t\t\t\tleft_score = work[i-1].score;\n\n\t\t\t\t\t\tif(work[i].score-m <= left_score){\n\n\t\t\t\t\t\t\tleft_loc = loc[work[i-1].id]+1;\n\t\t\t\t\t\t\tright_loc = loc[work[i].id]-1;\n\n\t\t\t\t\t\t\tif(left_loc <= right_loc){\n\t\t\t\t\t\t\t\ttmp += score_ruisekiwa[right_loc]-score_ruisekiwa[left_loc-1];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}else{\n\n\t\t\t\t\t\t\tif(work[i].score-m > score[loc[work[i].id]-1]){\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tright_loc = loc[work[i].id]-1;\n\n\t\t\t\t\t\t\tcalc_left = loc[work[i-1].id]+1;\n\t\t\t\t\t\t\tcalc_right = right_loc;\n\t\t\t\t\t\t\tcalc_m = (calc_left+calc_right)/2;\n\n\t\t\t\t\t\t\twhile(calc_left <= calc_right){\n\n\t\t\t\t\t\t\t\tif(score[calc_m] >= work[i].score-m){\n\t\t\t\t\t\t\t\t\tleft_loc = calc_m;\n\t\t\t\t\t\t\t\t\tcalc_right = calc_m-1;\n\t\t\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t\t\tcalc_left = calc_m+1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tcalc_m = (calc_left+calc_right)/2;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\ttmp += score_ruisekiwa[right_loc]-score_ruisekiwa[left_loc-1];\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}else{ // i == 0\n\n\t\t\t\t\t\tif(loc[work[i].id] == 1 || work[i].score-m > score[loc[work[i].id]-1]){\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\n\t\t\t\t\t\tright_loc = loc[work[i].id]-1;\n\n\t\t\t\t\t\tcalc_left = 1;\n\t\t\t\t\t\tcalc_right = right_loc;\n\t\t\t\t\t\tcalc_m = (calc_left+calc_right)/2;\n\n\t\t\t\t\t\twhile(calc_left <= calc_right){\n\n\t\t\t\t\t\t\tif(score[calc_m] >= work[i].score-m){\n\t\t\t\t\t\t\t\tleft_loc = calc_m;\n\t\t\t\t\t\t\t\tcalc_right = calc_m-1;\n\t\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t\tcalc_left = calc_m+1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tcalc_m = (calc_left+calc_right)/2;\n\t\t\t\t\t\t}\n\t\t\t\t\t\ttmp += score_ruisekiwa[right_loc]-score_ruisekiwa[left_loc-1];\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(current_number+tmp >= need_number){\n\t\t\t\t\tans = m;\n\t\t\t\t\tright = m-1;\n\t\t\t\t}else{\n\t\t\t\t\tleft = m+1;\n\t\t\t\t}\n\t\t\t\tm = (left+right)/2;\n\t\t\t}\n\n\t\t\tprintf(\"%d\\n\",ans);\n\n\t\t\tbreak;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 27712, "score_of_the_acc": -0.5351, "final_rank": 11 }, { "submission_id": "aoj_0283_10783437", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n\nbool solve(){\n ll N,Q;cin>>N>>Q;\n vector<ll>S(N);\n rep(i,N)cin>>S[i];\n vector<pair<int,int>>TMP(N);\n vector<int>id(N);\n rep(i,N)TMP[i]={S[i],i};\n sort(all(TMP));\n rep(i,N){\n S[i]=TMP[i].fi;\n id[TMP[i].se]=i;\n }\n vector<int>leader;\n rep(qq,Q){\n string type;cin>>type;\n if(type == \"ADD\"){\n int a;cin>>a;a--;\n leader.push_back(id[a]);\n sort(all(leader));\n }\n else if(type == \"REMOVE\"){\n vector<int> tmp;\n int a;cin>>a;a--;a=id[a];\n for(auto e : leader){\n if(e!=a)tmp.push_back(e);\n }\n swap(tmp,leader);\n }\n else {\n int x;cin>>x;\n x = N-x;\n ll ng = -1,ok = 2000000001;\n while(ng+1<ok){\n ll R = (ng+ok)/2;\n int ct = 0;\n int lim = 0;\n rep(i,leader.size()){\n ll k = S[leader[i]];\n int l = lower_bound(all(S),k-R)-S.begin();\n int r = upper_bound(all(S),k)-S.begin();\n if(r>=S.size())r=S.size()-1;\n if(S[r]>k)r--;\n l = max(l,lim);\n ct += max(0,r-l+1);\n lim = max(lim,r+1);\n }\n if(ct>=x)ok = R;\n else ng = R;\n }\n if(ok==2000000001)cout<<\"NA\"<<endl;\n else cout<<ok<<endl;\n }\n }\n return false;\n}\n\nint main(){\n while(solve());\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 22644, "score_of_the_acc": -0.5416, "final_rank": 13 }, { "submission_id": "aoj_0283_10783433", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n\nbool solve(){\n ll N,Q;cin>>N>>Q;\n vector<ll>S(N);\n rep(i,N)cin>>S[i];\n vector<pair<int,int>>TMP(N);\n vector<int>id(N);\n rep(i,N)TMP[i]={S[i],i};\n sort(all(TMP));\n rep(i,N){\n S[i]=TMP[i].fi;\n id[TMP[i].se]=i;\n }\n vector<int>leader;\n rep(qq,Q){\n string type;cin>>type;\n if(type == \"ADD\"){\n int a;cin>>a;a--;\n leader.push_back(id[a]);\n sort(all(leader));\n }\n else if(type == \"REMOVE\"){\n vector<int> tmp;\n int a;cin>>a;a--;a=id[a];\n for(auto e : leader){\n if(e!=a)tmp.push_back(a);\n }\n swap(tmp,leader);\n }\n else {\n int x;cin>>x;\n x = N-x;\n ll ng = -1,ok = 2000000001;\n while(ng+1<ok){\n ll R = (ng+ok)/2;\n int ct = 0;\n int lim = 0;\n rep(i,leader.size()){\n ll k = S[leader[i]];\n int l = lower_bound(all(S),k-R)-S.begin();\n int r = upper_bound(all(S),k)-S.begin();\n if(r>=S.size()||S[r]>k)r--;\n l = max(l,lim);\n ct += max(0,r-l+1);\n lim = max(lim,r+1);\n \n }\n if(ct>=x)ok = R;\n else ng = R;\n }\n if(ok==2000000001)cout<<\"NA\"<<endl;\n else cout<<ok<<endl;\n }\n }\n return false;\n}\n\nint main(){\n while(solve());\n}", "accuracy": 0.375, "time_ms": 10, "memory_kb": 3368, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0283_6031306", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N, Q;\n cin >> N >> Q;\n vector<int> s(N);\n for (int i = 0; i < N; i++){\n cin >> s[i];\n }\n vector<int> s2 = s;\n sort(s2.begin(), s2.end());\n set<int> st;\n for (int i = 0; i < Q; i++){\n string S;\n cin >> S;\n if (S == \"ADD\"){\n int a;\n cin >> a;\n a--;\n st.insert(a);\n }\n if (S == \"REMOVE\"){\n int a;\n cin >> a;\n a--;\n st.erase(a);\n }\n if (S == \"CHECK\"){\n int x;\n cin >> x;\n int cnt = st.size();\n int tv = 1000000001, fv = -1;\n while (tv - fv > 1){\n int mid = (tv + fv) / 2;\n vector<int> L, R;\n for (int a : st){\n L.push_back(lower_bound(s2.begin(), s2.end(), s[a] - mid) - s2.begin());\n R.push_back(upper_bound(s2.begin(), s2.end(), s[a]) - s2.begin());\n }\n vector<int> X;\n X.push_back(0);\n X.push_back(N);\n for (int j = 0; j < cnt; j++){\n X.push_back(L[j]);\n X.push_back(R[j]);\n }\n sort(X.begin(), X.end());\n X.erase(unique(X.begin(), X.end()), X.end());\n int cnt2 = X.size();\n vector<int> imos(cnt2, 0);\n for (int j = 0; j < cnt; j++){\n int l = lower_bound(X.begin(), X.end(), L[j]) - X.begin();\n int r = lower_bound(X.begin(), X.end(), R[j]) - X.begin();\n imos[l]++;\n imos[r]--;\n }\n for (int j = 0; j < cnt2 - 1; j++){\n imos[j + 1] += imos[j];\n }\n int sum = 0;\n for (int j = 0; j < cnt2 - 1; j++){\n if (imos[j] == 0){\n sum += X[j + 1] - X[j];\n }\n }\n if (sum <= x){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n if (tv == 1000000001){\n cout << \"NA\" << endl;\n } else {\n cout << tv << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 10776, "score_of_the_acc": -0.5235, "final_rank": 10 }, { "submission_id": "aoj_0283_5868036", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n int n, q;\n cin >> n >> q;\n vector<int> v(n);\n vector<int> s;\n map<int, int> score;\n for(int i = 0;i < n;i++){\n cin >> v[i];\n s.push_back(v[i]);\n score[i] = v[i];\n }\n\n sort(s.begin(), s.end());\n sort(v.begin(), v.end());\n multiset<int> leader;\n for(int i = 0;i < q;i++){\n string query;\n int x;\n cin >> query >> x;\n if(query == \"ADD\"){\n leader.insert(score[x - 1]);\n }\n else if(query == \"REMOVE\"){\n leader.erase(leader.lower_bound(score[x - 1]));\n }\n else{\n int ls = leader.size();\n if(x + ls >= n){\n cout << \"0\" << endl;\n continue;\n }\n if(ls == 0){\n cout << \"NA\" << endl;\n continue;\n }\n int l = -1;\n int r = 1001001001;\n while(r - l > 1){\n \n\t\tint mid = (l + r) / 2;\n auto si = leader.end();\n int ans = 0;\n for(int j = 0;j < ls;j++){\n si--;\n \n\t\t //cout << *si << endl;\n auto itl = lower_bound(s.begin(), s.end(), (*si) - mid);\n if(j == 0){\n auto dekai = upper_bound(s.begin(), s.end(), *si);\n ans += distance(dekai, s.end());\n }\n\n if(j != ls - 1){\n auto si_1 = prev(si);\n auto itr = upper_bound(s.begin(), s.end(), *si_1);\n if(itl > itr)ans += distance(itr, itl);\n }\n else{\n if(itl > s.begin()) ans += distance(s.begin(), itl);\n }\n }\n //cout << mid << \" \" << ans << endl;\n if(ans > x) l = mid;\n else r = mid;\n }\n if(r != 1001001001) cout << r << endl;\n else cout << \"NA\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 57888, "score_of_the_acc": -1.1182, "final_rank": 16 }, { "submission_id": "aoj_0283_5851920", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int N,Q;\n cin >> N >> Q;\n vector<long long int> s(N);\n vector<long long int> ss(N);\n for(int i=0;i<N;i++){\n cin >> s[i];\n ss[i] = s[i];\n }\n sort(ss.begin(),ss.end());\n vector<int> leader(0);\n map<int,bool> real_leader;\n map<int,bool> add;\n for(int j=0;j<Q;j++){\n string q;\n cin >> q;\n if(q == \"ADD\"){\n int a;\n cin >> a;\n a--;\n if(!add[a]){\n add[a] = true;\n leader.push_back(a);\n }\n real_leader[a] = true;\n }\n if(q == \"REMOVE\"){\n int a;\n cin >> a;\n a--;\n real_leader[a] = false;\n }\n if(q == \"CHECK\"){\n int x;\n cin >> x;\n vector<int> list(0);\n for(int i=0;i<(int)leader.size();i++){\n int t = leader[i];\n if(real_leader[t]) list.push_back(t);\n }\n if(list.size() == 0){\n if(x != N)cout << \"NA\" << endl;\n else cout << 0 << endl;\n }\n else if(list.size() == N) cout << 0 << endl;\n else{\n long long int INF = 1000000000000;\n long long int ng=-1,ok=INF;\n int M = list.size();\n while(ok-ng > 1){\n long long int mid = (ok+ng)/2;\n vector<pair<long long int,long long int> > LR(M);\n for(int i=0;i<M;i++){\n long long int L = s[list[i]]-mid;\n long long int R = s[list[i]];\n LR[i] = make_pair(L,R);\n }\n sort(LR.begin(),LR.end());\n vector<pair<long long int,long long int> > sumLR(0);\n for(int i=1;i<M;i++){\n if(LR[i-1].second >= LR[i].first) LR[i].first = LR[i-1].first;\n else sumLR.push_back(make_pair(LR[i-1].first,LR[i-1].second));\n }\n sumLR.push_back(make_pair(LR.back().first,LR.back().second));\n long long int stu = N;\n for(int i=0;i<(int)sumLR.size();i++){\n long long int s = lower_bound(ss.begin(),ss.end(),sumLR[i].first)-ss.begin();\n long long int t = lower_bound(ss.begin(),ss.end(),sumLR[i].second+1)-ss.begin();\n stu -= t-s;\n }\n if(stu <= x) ok = mid;\n else ng = mid;\n }\n if(ok >= INF/10) cout << \"NA\" << endl;\n else cout << ok << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 18440, "score_of_the_acc": -0.4297, "final_rank": 8 }, { "submission_id": "aoj_0283_5848690", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<unordered_set>\n#include<unordered_map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<climits>\n#include<iomanip>\n#include<cctype>\n#include<sstream>\n#include<regex>\n#include<bitset>\n#include<random>\n#include<complex>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\nconstexpr int mod=1e9+7;\nconstexpr int Mod=998244353;\nconstexpr int inf=mod;\nconstexpr ll linf=(ll)mod*mod;\nstruct fastio{\n\tfastio(){\n\t\tcin.tie(0);\n\t\tios::sync_with_stdio(0);\n\t\tcout<<fixed<<setprecision(20);\n\t};\n}fio;\nint s[1000000],ss[1000000];\nint main(){\n\tint n,q;\n\tstring query;\n\tcin>>n>>q;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>s[i];\n\tcopy(s,s+n,ss);\n\tsort(ss,ss+n);\n\tvector<int>v;\n\twhile(cin>>query){\n\t\tif(query==\"ADD\"){\n\t\t\tint a;\n\t\t\tcin>>a;\n\t\t\tv.push_back(--a);\n\t\t}\n\t\tif(query==\"REMOVE\"){\n\t\t\tint a;\n\t\t\tcin>>a;\n\t\t\tv.erase(find(v.begin(),v.end(),--a));\n\t\t}\n\t\tif(query==\"CHECK\"){\n\t\t\tint x;\n\t\t\tcin>>x;\n\t\t\tint ok=inf,ng=-1;\n\t\t\twhile(ok-ng>1){\n\t\t\t\tint mid=(ok+ng)/2;\n\t\t\t\tvector<pair<int,int>>eve;\n\t\t\t\tfor(auto e:v){\n\t\t\t\t\teve.push_back({s[e]-mid,1});\n\t\t\t\t\teve.push_back({s[e]+1,-1});\n\t\t\t\t}\n\t\t\t\tsort(eve.begin(),eve.end());\n\t\t\t\tint tmp=0;\n\t\t\t\tvector<int>rg[2];\n\t\t\t\tfor(auto e:eve){\n\t\t\t\t\ttmp+=e.second;\n\t\t\t\t\tif(tmp==1&&e.second==1)\n\t\t\t\t\t\trg[0].push_back(e.first);\n\t\t\t\t\tif(tmp==0)\n\t\t\t\t\t\trg[1].push_back(e.first);\n\t\t\t\t}\n\t\t\t\tint sum=0;\n\t\t\t\tfor(int i=0;i<rg[0].size();i++)\n\t\t\t\t\tsum+=lower_bound(ss,ss+n,rg[1][i])-lower_bound(ss,ss+n,rg[0][i]);\n\t\t\t\tif(n-sum<=x)\n\t\t\t\t\tok=mid;\n\t\t\t\telse\n\t\t\t\t\tng=mid;\n\t\t\t}\n\t\t\tif(ok!=inf)\n\t\t\t\tcout<<ok<<endl;\n\t\t\telse\n\t\t\t\tcout<<\"NA\"<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 11212, "score_of_the_acc": -0.2523, "final_rank": 3 }, { "submission_id": "aoj_0283_5753890", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint BIT[1000015];\nvoid add(int p,int v){\n for(;p<1000015;p+=p&-p)BIT[p]+=v;\n}\nint getsum(int l,int r){\n int ret=0;\n for(l-=1;l>0;l-=l&-l)ret-=BIT[l];\n for(;r>0;r-=r&-r)ret+=BIT[r];\n return ret;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n fill(BIT,BIT+1000015,0);\n int N,Q;\n cin>>N>>Q;\n vector<int>A(N);\n for(int &i:A)cin>>i;\n vector<int>B=A;\n B.push_back(-1);\n sort(B.begin(),B.end()),B.erase(unique(B.begin(),B.end()),B.end());\n for(int i=0;i<N;i++){\n add(lower_bound(B.begin(),B.end(),A[i])-B.begin(),1);\n }\n //for(int i:B)cout<<i<<' ';cout<<'\\n';\n multiset<int>rida;\n string op;\n while(Q--){\n cin>>op;\n if(op==\"ADD\"){\n int x;\n cin>>x;\n rida.insert(A[x-1]);\n add(lower_bound(B.begin(),B.end(),A[x-1])-B.begin(),-1);\n //for(int i=0;i<=N;i++)cout<<getsum(0,i)<<' ';cout<<'\\n';\n }else if(op==\"REMOVE\"){\n int x;cin>>x;\n rida.erase(rida.lower_bound(A[x-1]));\n add(lower_bound(B.begin(),B.end(),A[x-1])-B.begin(),1);\n //for(int i=0;i<=N;i++)cout<<getsum(0,i)<<' ';cout<<'\\n';\n }else{\n int x;cin>>x;\n long long l=-1,r=2e9;\n while(r-l>1){\n long long mid=(l+r)/2;\n int t=-1,ok=N-rida.size();\n for(int i:rida){\n if(t>=i-mid){\n ok-=getsum(upper_bound(B.begin(),B.end(),t)-B.begin(),lower_bound(B.begin(),B.end(),i)-B.begin());\n }else{\n ok-=getsum(lower_bound(B.begin(),B.end(),i-mid)-B.begin(),lower_bound(B.begin(),B.end(),i)-B.begin());\n }\n t=i;\n }\n if(ok<=x)r=mid;\n else l=mid;\n //cout<<ok<<' ';\n }\n if(r>1e9){\n cout<<\"NA\\n\";\n }else{\n cout<<r<<'\\n';\n }\n }\n }\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 20600, "score_of_the_acc": -0.4797, "final_rank": 9 }, { "submission_id": "aoj_0283_5753821", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint BIT[1000015];\nvoid add(int p,int v){\n for(;p<1000015;p+=p&-p)BIT[p]+=v;\n}\nint getsum(int l,int r){\n int ret=0;\n for(l-=1;l>0;l-=l&-l)ret-=BIT[l];\n for(;r>0;r-=r&-r)ret+=BIT[r];\n return ret;\n}\n\nint main(){\n fill(BIT,BIT+1000015,0);\n int N,Q;\n cin>>N>>Q;\n vector<int>A(N);\n for(int &i:A)cin>>i;\n vector<int>B=A;\n B.push_back(-1);\n sort(B.begin(),B.end()),B.erase(unique(B.begin(),B.end()),B.end());\n for(int i=0;i<N;i++){\n add(lower_bound(B.begin(),B.end(),A[i])-B.begin(),1);\n }\n //for(int i:B)cout<<i<<' ';cout<<'\\n';\n multiset<int>rida;\n string op;\n while(Q--){\n cin>>op;\n if(op==\"ADD\"){\n int x;\n cin>>x;\n rida.insert(A[x-1]);\n add(lower_bound(B.begin(),B.end(),A[x-1])-B.begin(),-1);\n //for(int i=0;i<=N;i++)cout<<getsum(0,i)<<' ';cout<<'\\n';\n }else if(op==\"REMOVE\"){\n int x;cin>>x;\n rida.erase(rida.lower_bound(A[x-1]));\n add(lower_bound(B.begin(),B.end(),A[x-1])-B.begin(),1);\n //for(int i=0;i<=N;i++)cout<<getsum(0,i)<<' ';cout<<'\\n';\n }else{\n int x;cin>>x;\n long long l=-1,r=2e9;\n while(r-l>1){\n long long mid=(l+r)/2;\n int t=-1,ok=N-rida.size();\n for(int i:rida){\n if(t>=i-mid){\n ok-=getsum(upper_bound(B.begin(),B.end(),t)-B.begin(),lower_bound(B.begin(),B.end(),i)-B.begin());\n }else{\n ok-=getsum(lower_bound(B.begin(),B.end(),i-mid)-B.begin(),lower_bound(B.begin(),B.end(),i)-B.begin());\n }\n t=i;\n }\n if(ok<=x)r=mid;\n else l=mid;\n //cout<<ok<<' ';\n }\n if(r>1e9){\n cout<<\"NA\\n\";\n }else{\n cout<<r<<'\\n';\n }\n }\n }\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 20572, "score_of_the_acc": -0.5374, "final_rank": 12 }, { "submission_id": "aoj_0283_5654046", "code_snippet": "#include <bits/stdc++.h>\n\n#define lol long long\n#define gcd(x, y) __gcd(x, y)\n#define mt make_tuple\n#define mp make_pair\n#define fi first\n#define se second\n#define fixed(x) fixed << setprecision(x)\n#define all(x) x.begin(),x.end()\nusing namespace std;\nusing pii = pair<int, int>;\ntemplate <class A, class B>\ninline bool chmax(A& a, const B& b) {\n return b > a && (a = b, true);\n}\ntemplate <class A, class B>\ninline bool chmin(A& a, const B& b) {\n return b < a && (a = b, true);\n}\ntemplate <class A>\ninline A abs(A& a) {\n return (a < 0 ? -a : a);\n}\nbool inLine(int x, int y, int mx, int my) {\n return (x >= 0 && y >= 0 && x < mx && y < my);\n}\ntemplate<class T> using min_heap=priority_queue<T,vector<T>,greater<T>>;\ntemplate<class T> using uset=unordered_set<T>;\ntemplate<class A,class B> using umap=unordered_map<A,B>;\nconst lol inf = (1LL << 62);\nconst int MOD = (1e9) + 7;\nconst int mod = 998244353;\nconst int dx[] = {1, 0, -1, 0, 1, 1, -1, -1, -2, -2, -2, -2,\n -2, -1, -1, 1, 1, 0, 0, 2, 2, 2, 2, 2};\nconst int dy[] = {0, 1, 0, -1, 1, -1, 1, -1, -2, -1, 0, 1,\n 2, -2, 2, -2, 2, -2, 2, -2, -1, 0, 1, 2};\n\n\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n,q;\n cin >>n>>q;\n vector<int> s(n);\n map<int,int> rui;\n for(int i=0;i<n;i++){\n cin >>s[i];\n rui[s[i]]++;\n }\n rui[-1]=0;\n int tmp = 0;\n for(auto&& p:rui){\n tmp += p.se;\n p.se = tmp;\n }\n map<int,int> reder;\n for(int i=0;i<q;i++){\n string que;\n int a;\n cin >>que>>a;\n if(que==\"ADD\"){\n reder[s[a-1]]++;\n }else if(que==\"REMOVE\"){\n reder[s[a-1]]--;\n if(reder[s[a-1]] == 0){\n reder.erase(s[a-1]);\n }\n }else{\n int high=(int)1e9+100,low=-1;\n while(high-low>1){\n int mid=(high+low)/2;\n int sum=0;\n int tmp=-1;\n for(auto se:reder){\n auto w = rui.upper_bound(max(se.fi-mid-1,tmp));\n w--;\n sum += rui[se.fi] - (w->se);\n tmp = se.fi;\n }\n if(n-sum>a){\n low = mid;\n }else{\n high = mid;\n }\n }\n if(high==(int)1e9+100){\n cout <<\"NA\\n\";\n }else{\n cout <<high<<'\\n';\n }\n }\n }\n return (0);\n}", "accuracy": 1, "time_ms": 1310, "memory_kb": 53816, "score_of_the_acc": -1.2267, "final_rank": 17 }, { "submission_id": "aoj_0283_5653525", "code_snippet": "#pragma GCC optimize(\"O3\")\n#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x), end(x)\n#define Fixed fixed << setprecision(12)\n#define int int_fast64_t\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T,vector<T>,greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A,B>;\n\ntemplate <class T> inline void bye(T x) { cout << x << '\\n'; exit(0); }\n\ninline int square(int a){ return a * a;}\ninline int updiv(int a,int b){ return (a + b - 1) / b; }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\n\nsigned main(void){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n int n, q;\n cin >> n >> q;\n\n vector<int> s(n);\n vector<pair<int, int> > ps;\n\n for (int i = 0; i < n; ++i) {\n cin >> s[i];\n ps.emplace_back(s[i], i);\n }\n\n sort(all(ps));\n\n vector<int> idx(n), sorted(n);\n\n for (int i = 0; i < n; ++i) {\n idx[ps[i].second] = i;\n sorted[i] = ps[i].first;\n }\n\n auto comp = [&](auto a, auto b) { return (idx[a] < idx[b]); };\n set<int, decltype(comp)> ss(comp);\n\n auto check = [&](int key) -> int {\n int l = 0, cnt = 0;\n for (auto e: ss) {\n int x = lower_bound(all(sorted), s[e] - key) - sorted.begin();\n cnt += max(l, x) - l;\n l = upper_bound(all(sorted), s[e]) - sorted.begin();\n }\n return (cnt + n - l);\n };\n\n for (int i = 0; i < q; ++i) {\n string com;\n int a;\n cin >> com >> a;\n\n if (com == \"ADD\") {\n ss.emplace(a - 1);\n } else if (com == \"REMOVE\") {\n ss.erase(a - 1);\n } else {\n int ok = INF, ng = - 1;\n while (ok - ng > 1) {\n int mid = (ok + ng) / 2;\n if (check(mid) <= a) ok = mid;\n else ng = mid;\n }\n if (ok == INF) cout << \"NA\\n\";\n else cout << ok << '\\n';\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 42600, "score_of_the_acc": -0.7928, "final_rank": 15 }, { "submission_id": "aoj_0283_5586966", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(long long i = (a)*(strlen(#__VA_ARGS__)!=0);i<(long long)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(long long i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(long long)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\ntemplate <class T>\nvector<T> make_vector(int n,T init){\n return vector<T>(n,init);\n}\n\ntemplate <class... tail>\nauto make_vector(int n, tail... args){\n return vector<decltype(make_vector(args...))>(n,make_vector(args...));\n}\n\nvector<ll> func(){\n int n = in();\n int q = in();\n vector<int> scores(n);\n foreach(i,scores)i=in();\n vector<int> line = sorted(scores);\n set<int> s;\n vector<int> has;\n\n method(check,bool,int r,int x){\n int last = -1;\n int cnt = 0;\n foreach(i,has){\n int p = lower_bound(all(line),i-r)-line.begin();\n cnt += max(0,p-last-1);\n int next = upper_bound(all(line),i)-line.begin()-1;\n last = next;\n }\n cnt += n - last - 1;\n return cnt <= x;\n };\n\n method(calc,ll,int x){\n has.clear();\n foreach(i,s)has.emplace_back(scores[i]);\n sort(all(has));\n int lp = 0;\n int rp = INF;\n while(lp<rp){\n int mid = (lp+rp) / 2;\n if(check(mid,x)){\n rp = mid;\n }else{\n lp = mid+1;\n }\n }\n if(check(lp,x))return lp;\n return -1;\n };\n\n vector<ll> res;\n rep(i,q){\n string op = in<string>();\n int v = in();\n if(op==\"ADD\"){\n s.emplace(v-1);\n }else if(op==\"REMOVE\"){\n s.erase(v-1);\n }else if(op==\"CHECK\"){\n res.emplace_back(calc(v));\n }\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n foreach(i,func()){\n if(i<0){\n println(\"NA\");\n }else{\n println(i);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 10780, "score_of_the_acc": -0.3271, "final_rank": 4 }, { "submission_id": "aoj_0283_4910261", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<set>\nusing namespace std;\nint N,Q;\nint s[1<<20],t[1<<20];\nmain()\n{\n\tcin>>N>>Q;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>s[i];\n\t\tt[i]=s[i];\n\t}\n\tsort(t,t+N);\n\tmultiset<int>A;\n\tfor(;Q--;)\n\t{\n\t\tstring S;int a;\n\t\tcin>>S>>a;\n\t\tif(S==\"ADD\"||S==\"REMOVE\")\n\t\t{\n\t\t\ta=upper_bound(t,t+N,s[a-1])-t;\n\t\t\tif(S==\"ADD\")A.insert(a);\n\t\t\telse A.erase(A.find(a));\n\t\t}\n\t\telse\n\t\t{\n\t\t\tlong L=-1,R=1e9+1;\n\t\t\twhile(R-L>1)\n\t\t\t{\n\t\t\t\tint mid=(L+R)/2;\n\t\t\t\tint cnt=0;\n\t\t\t\tint pre=0;\n\t\t\t\tfor(int x:A)\n\t\t\t\t{\n\t\t\t\t\tint val=t[x-1];\n\t\t\t\t\tcnt+=max(0L,lower_bound(t,t+N,val-mid)-t-pre);\n\t\t\t\t\tpre=x;\n\t\t\t\t}\n\t\t\t\tcnt+=N-pre;\n\t\t\t\tif(cnt<=a)R=mid;\n\t\t\t\telse L=mid;\n\t\t\t}\n\t\t\tif(R>1e9)cout<<\"NA\"<<endl;\n\t\t\telse cout<<R<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 11024, "score_of_the_acc": -0.3392, "final_rank": 5 }, { "submission_id": "aoj_0283_4910250", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<set>\nusing namespace std;\n#line 2 \"/home/kotatsugame/library/datastructure/lazysegtree.cpp\"\ntemplate<typename T>\nstruct lazysegtree{\n\tint n;\n\tT defvalue;\n\tvector<T>dat,lazy;\n\tvector<bool>lazyflag;\n\tlazysegtree(int n_=0):defvalue(0)\n\t{\n\t\tn=1;\n\t\twhile(n<n_)n<<=1;\n\t\tdat.assign(2*n-1,defvalue);\n\t\tlazy.assign(2*n-1,T());\n\t\tlazyflag.assign(2*n-1,false);\n\t}\n\tvoid eval(int i,int l,int r)\n\t{\n\t\tif(lazyflag[i])\n\t\t{\n\t\t\tdat[i]=lazy[i]*(r-l);\n\t\t\tif(r-l>1)\n\t\t\t{\n\t\t\t\tlazy[2*i+1]=lazy[i];\n\t\t\t\tlazy[2*i+2]=lazy[i];\n\t\t\t\tlazyflag[2*i+1]=lazyflag[2*i+2]=true;\n\t\t\t}\n\t\t\tlazyflag[i]=false;\n\t\t}\n\t}\n\tvoid update(int a,int b,T x,int k=0,int l=0,int r=-1)//[a,b)\n\t{\n\t\tif(r<0)r=n;\n\t\teval(k,l,r);\n\t\tif(b<=l||r<=a)return;\n\t\telse if(a<=l&&r<=b)\n\t\t{\n\t\t\tlazy[k]=x;\n\t\t\tlazyflag[k]=true;\n\t\t\teval(k,l,r);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tupdate(a,b,x,2*k+1,l,(l+r)/2);\n\t\t\tupdate(a,b,x,2*k+2,(l+r)/2,r);\n\t\t\tdat[k]=dat[2*k+1]+dat[2*k+2];\n\t\t}\n\t}\n\tT query(int a,int b,int k=0,int l=0,int r=-1)//[a,b)\n\t{\n\t\tif(r<0)r=n;\n\t\teval(k,l,r);\n\t\tif(b<=l||r<=a)return defvalue;\n\t\telse if(a<=l&&r<=b)return dat[k];\n\t\telse return query(a,b,2*k+1,l,(l+r)/2)+query(a,b,2*k+2,(l+r)/2,r);\n\t}\n};\n#line 7 \"a.cpp\"\nint N,Q;\nint s[1<<20];\nint ri[1<<20];\nmain()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\tcin>>N>>Q;\n\tvector<int>val(N);\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>s[i];\n\t\tval[i]=s[i];\n\t}\n\tsort(val.begin(),val.end());\n\tfor(int i=0;i<N;i++)ri[i]=upper_bound(val.begin(),val.end(),s[i])-val.begin();\n\tlazysegtree<int>P(N);\n\tset<int>A;\n\tfor(;Q--;)\n\t{\n\t\tstring S;int a;\n\t\tcin>>S>>a;\n\t\tif(S==\"ADD\")A.insert(a-1);\n\t\telse if(S==\"REMOVE\")A.erase(a-1);\n\t\telse\n\t\t{\n\t\t\tint L=-1,R=1e9+1;\n\t\t\twhile(R-L>1)\n\t\t\t{\n\t\t\t\tint mid=(L+R)/2;\n\t\t\t\tP.update(0,N,1);\n\t\t\t\tfor(int id:A)\n\t\t\t\t{\n\t\t\t\t\tP.update(lower_bound(val.begin(),val.end(),s[id]-mid)-val.begin(),\n\t\t\t\t\t\tri[id],0);\n\t\t\t\t}\n\t\t\t\tif(P.query(0,N)<=a)R=mid;\n\t\t\t\telse L=mid;\n\t\t\t}\n\t\t\tif(R>1e9)cout<<\"NA\\n\";\n\t\t\telse cout<<R<<'\\n';\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 2250, "memory_kb": 31332, "score_of_the_acc": -1.3583, "final_rank": 18 }, { "submission_id": "aoj_0283_4829954", "code_snippet": "#include <iostream>\n#include <map>\n#include <set>\n#include <cmath>\n#include <queue>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n#pragma warning (disable: 4996)\n\n// 入力\nint N, A[1 << 20], B[1 << 20];\nint Q, X[1 << 20];\nstring TY[1 << 10];\n\n// 状態\nset<int> Set;\n\nvector<pair<int, int>> merge(vector<pair<int, int>> D) {\n\tif (D.size() == 0) return D;\n\n\tvector<pair<int, int>> E;\n\tint maxn = D[0].first, fst = D[0].first;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tmaxn = max(maxn, D[i].second);\n\t\tif (i + 1 == D.size() || maxn < D[i + 1].first) {\n\t\t\tE.push_back(make_pair(fst, maxn));\n\t\t\tif (i + 1 != D.size()) fst = D[i + 1].first;\n\t\t}\n\t}\n\treturn E;\n}\n\nint calc(vector<int> idx, int r) {\n\tsort(idx.begin(), idx.end());\n\tvector<pair<int, int>> D;\n\tfor (int i = 0; i < idx.size(); i++) D.push_back(make_pair(idx[i] - r, idx[i]));\n\tD = merge(D);\n\n\tint sum = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tint pos1 = lower_bound(B + 1, B + N + 1, D[i].first) - B;\n\t\tint pos2 = lower_bound(B + 1, B + N + 1, D[i].second + 1) - B;\n\t\tsum += (pos2 - pos1);\n\t}\n\treturn sum;\n}\n\nvoid solve(int num) {\n\tauto itr = Set.begin(); vector<int> C;\n\twhile (itr != Set.end()) {\n\t\tC.push_back(A[*itr]);\n\t\titr++;\n\t}\n\n\tint cl = 0, cr = (1 << 30), cm, minx = (1 << 30);\n\tfor (int i = 0; i < 33; i++) {\n\t\tcm = (cl + cr) / 2;\n\t\tif (calc(C, cm) >= N - num) { minx = min(minx, cm); cr = cm; }\n\t\telse { cl = cm; }\n\t}\n\n\tif (minx == (1 << 30)) cout << \"NA\" << endl;\n\telse cout << minx << endl;\n}\n\nint main() {\n\t// 入力\n\tscanf(\"%d%d\", &N, &Q);\n\tfor (int i = 1; i <= N; i++) scanf(\"%d\", &A[i]);\n\tfor (int i = 1; i <= Q; i++) {\n\t\tcin >> TY[i];\n\t\tscanf(\"%d\", &X[i]);\n\t}\n\t\n\t// ソート\n\tfor (int i = 1; i <= N; i++) B[i] = A[i];\n\tsort(B + 1, B + N + 1);\n\n\t// クエリに答える\n\tfor (int i = 1; i <= Q; i++) {\n\t\tif (TY[i] == \"ADD\") Set.insert(X[i]);\n\t\tif (TY[i] == \"REMOVE\") Set.erase(X[i]);\n\t\tif (TY[i] == \"CHECK\") solve(X[i]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 11640, "score_of_the_acc": -0.2265, "final_rank": 1 }, { "submission_id": "aoj_0283_4824892", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\ntemplate<class Op> class SegmentTree {\n\tusing T = typename Op::T;\n\tint len, n;\n\tvector<T> dat;\n\tT unit = Op::unit;\npublic:\n\tSegmentTree(const int _n) : n(_n) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t}\n\tSegmentTree(const vector<T>& v) : n(v.size()) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t\tfor (int i = 0; i < n; ++i)dat[i + len] = v[i];\n\t\tfor (int i = len - 1; 0 < i; --i)\n\t\t\tdat[i] = Op::merge(dat[i << 1], dat[i << 1 | 1]);\n\t}\n\tinline void update(int idx, const T a) {\n\t\tidx += len;\n\t\tdat[idx] = Op::update(dat[idx], a);\n\t\tfor (idx >>= 1; 0 < idx; idx >>= 1)\n\t\t\tdat[idx] = Op::merge(dat[idx << 1], dat[idx << 1 | 1]);\n\t}\n\tinline T value(int l, int r) {\n\t\tT vl = unit, vr = unit;\n\t\tfor (l += len, r += len; l < r; l >>= 1, r >>= 1) {\n\t\t\tif (l & 1)vl = Op::merge(vl, dat[l++]);\n\t\t\tif (r & 1)vr = Op::merge(dat[--r], vr);\n\t\t}\n\t\treturn Op::merge(vl, vr);\n\t}\n\tinline T operator[](int idx) { return dat[idx + len]; }\n};\ntemplate<class Type> struct intSumAddUpdate {\n\tusing T = Type;\n\tconst static T unit = 0;\n\tinline static T merge(T vl, T vr) { return vl + vr; }\n\tinline static T update(T vl, T vr) { return vl + vr; }\n};\n\nint main() {\n init();\n\n int n, q; cin >> n >> q;\n VI s(n); cin >> s;\n VI iton(n), ntoi(n);//index-to-number, and vice versa\n {\n vector<pair<int, int>> stu;\n stu.reserve(n);\n FOR(i, 0, n)stu.emplace_back(s[i], i);\n SORT(stu);\n FOR(i, 0, n) {\n iton[i] = stu[i].second;\n ntoi[stu[i].second] = i;\n }\n }\n\n\tSegmentTree<intSumAddUpdate<int>> seg(n);\n\tset<int> idx;//index of leaders's\n\twhile (q--) {\n\t\tstring type; int a; cin >> type >> a;\n\t\tif (type == \"ADD\") {\n\t\t\tidx.insert(ntoi[a - 1]);\n\t\t\tcontinue;\n\t\t}\n\t\telse if (type == \"REMOVE\") {\n\t\t\tidx.erase(ntoi[a - 1]);\n\t\t\tcontinue;\n\t\t}\n\t\tint ng = -1, ok = INF + 1;\n\t\twhile (ok - ng > 1) {\n\t\t\tint mid = ok + ng >> 1;\n\t\t\t//---------------\n\t\t\tint cnt = 0, lim = -1;\n\t\t\tfor (auto it = idx.begin(); it != idx.end(); ++it) {\n\t\t\t\tint l = lim, r = n, L = lim, R = n;\n\t\t\t\tif (++it != idx.end())r = R = *it;\n\t\t\t\t--it;\n\t\t\t\t{\n\t\t\t\t\twhile (r - l > 1) {\n\t\t\t\t\t\tint m = l + r >> 1;\n\t\t\t\t\t\tif (s[iton[m]] < s[iton[*it]] - mid)\n\t\t\t\t\t\t\tl = m;\n\t\t\t\t\t\telse r = m;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t{\n\t\t\t\t\twhile (R - L > 1) {\n\t\t\t\t\t\tint m = L + R >> 1;\n\t\t\t\t\t\tif (s[iton[m]] <= s[iton[*it]])\n\t\t\t\t\t\t\tL = m;\n\t\t\t\t\t\telse R = m;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tcnt += L - l;\n\t\t\t\tlim = L;\n\t\t\t}\n\t\t\t//---------------\n\t\t\tif (n - cnt <= a)ok = mid;\n\t\t\telse ng = mid;\n\t\t}\n\t\tif (ok == INF + 1)print(\"NA\");\n\t\telse print(ok);\n\t}\n\n return 0;\n}", "accuracy": 1, "time_ms": 1160, "memory_kb": 22812, "score_of_the_acc": -0.7625, "final_rank": 14 }, { "submission_id": "aoj_0283_4783280", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<set>\n#include<unordered_set>\n#include<unordered_map>\nusing namespace std;\ntypedef long long ll;\n#define chmax(a,b) a=max(a,b)\n#define chmin(a,b) a=min(a,b)\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\n#define mad(a,b) a=(a+b)%mod\nll n,q;\n#define N 1000010\nll s[N];\nvector<int> S;\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n cin>>n>>q;\n rep(i,n){\n\tcin>>s[i];\n\tS.push_back(s[i]);\n }\n sort(all(S));\n set<int> L;\n while(q--){\n\tstring typ;\n\tint a;\n\tcin>>typ>>a;\n\tif(typ==\"ADD\"){\n\t a--;\n\t L.insert(a);\n\t}\n\tif(typ==\"REMOVE\"){\n\t a--;\n\t L.erase(a);\n\t}\n\tif(typ==\"CHECK\"){\n\t vector<ll> ls;\n\t for(auto id:L){\n\t\tls.push_back(s[id]);\n\t }\n\t ls.push_back(-1);\n\t sort(all(ls));\n\t ls.erase(unique(all(ls)),ls.end());\n\t ll l=-1,r=2e9,mid;\n\t while(l<r-1){\n\t\tmid=(l+r)>>1;\n\t\tint cnt=0;\n\t\tfor(int i=1;i<ls.size();i++){\n\t\t ll l=max(ls[i-1]+1,ls[i]-mid);\n\t\t ll r=ls[i];\n\t\t cnt+=upper_bound(all(S),r)-lower_bound(all(S),l);\n\t\t}\n\t\tif(n-cnt<=a)r=mid;\n\t\telse l=mid;\n\t }\n\t if(r==2e9)cout<<\"NA\\n\";\n\t else cout<<r<<\"\\n\";\n\t}\n }\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 14868, "score_of_the_acc": -0.3438, "final_rank": 6 }, { "submission_id": "aoj_0283_4608491", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimaze(\"Ofast\")\n\n// Begin Headelr {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// }}} End Header\n\nconstexpr int dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\nconstexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};\n\nconst auto inside = [](int y, int x, int H, int W) -> bool {\n return (y >= 0 && x >= 0 && y < H && x < W);\n};\n\n// SegmentTree {{{\ntemplate <class Monoid>\nstruct SegmentTree {\n using Func = function<Monoid(Monoid, Monoid)>;\n const size_t sz;\n const Func fn;\n const Monoid unity;\n vector<Monoid> seg;\n\n SegmentTree(const size_t n, const Monoid &u, Func f)\n : sz(1 << (__lg(n + 5) + 1)), fn(f), unity(u), seg(sz * 2, unity) {}\n\n void set(size_t k, const Monoid &v) {\n seg[k + sz] = v;\n }\n\n Monoid& operator[](size_t k) {\n return seg[k + sz];\n }\n const Monoid& operator[](size_t k) const {\n return seg[k + sz];\n }\n\n void build() {\n for (size_t k = sz - 1; k > 0; --k) {\n seg[k] = fn(seg[2 * k], seg[2 * k + 1]);\n }\n }\n\n void update(size_t k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while (k >>= 1) {\n seg[k] = fn(seg[2 * k], seg[2 * k + 1]);\n }\n }\n\n Monoid query(size_t a, size_t b) const {\n Monoid L = unity, R = unity;\n for (a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if (a & 1) L = fn(L, seg[a++]);\n if (b & 1) R = fn(seg[--b], R);\n }\n return fn(L, R);\n }\n};\n// }}}\n\n// compress {{{\ntemplate <class T> unordered_map<T, int> compress(vector<T> value) {\n unordered_map<T, int> ret;\n\n sort(value.begin(), value.end());\n value.erase(unique(value.begin(), value.end()), value.end());\n\n const size_t sz = value.size();\n for (size_t i = 0; i < sz; ++i) {\n ret[value[i]] = i;\n }\n\n return ret;\n}\n// }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n var(size_t, N, Q);\n vector<intmax_t> s(N); input(s);\n auto ss = s;\n sort(all(ss));\n auto zip = compress(s);\n const size_t M = zip.size();\n vector<pair<intmax_t, intmax_t>> v(M);\n rep(i, 0, N) {\n v[zip[s[i]]] = {s[i], v[zip[s[i]]].second + 1};\n }\n vector<intmax_t> cumsum(M + 1);\n rep(i, 0, M) {\n cumsum[i + 1] = cumsum[i] + v[i].second;\n }\n // {得点, 番号}\n set<pair<intmax_t, int>> leader;\n const auto f = [&](intmax_t r, intmax_t x) -> bool {\n intmax_t ret = N;\n for (auto itr = leader.begin(); itr != leader.end(); itr++) {\n intmax_t L, R;\n if (itr == leader.begin()) {\n L = max(0_jd, s[(*itr).second] - r);\n R = s[(*itr).second];\n } else {\n L = max(s[(*prev(itr)).second] + 1, s[(*itr).second] - r);\n R = s[(*itr).second];\n if (s[(*prev(itr)).second] == s[(*itr).second]) continue;\n }\n const auto pos = zip[*lower_bound(all(ss), L)];\n ret -= cumsum[zip[R] + 1] - cumsum[pos];\n }\n return (ret <= x);\n };\n while (Q--) {\n var(string, com);\n var(intmax_t, x);\n if (com == \"ADD\") {\n leader.emplace(s[x - 1], x - 1);\n } else if (com == \"REMOVE\") {\n leader.erase({s[x - 1], x - 1});\n } else {\n intmax_t ng = -1, ok = 1e9 + 1;\n while (ok - ng > 1) {\n const intmax_t mid = (ok + ng) / 2;\n if (f(mid, x)) ok = mid;\n else ng = mid;\n }\n if (ok == 1e9 + 1) {\n output(\"NA\");\n } else {\n output(ok);\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 81420, "score_of_the_acc": -1.5357, "final_rank": 19 } ]
aoj_0284_cpp
ハッピーエンド問題 「ハッピーエンド問題」と呼ばれる数学の未解決問題に関連したプログラムを書いてみましょう。平面上に与えられた N 個の点から、ちょうど k 個の点を結んでできる凸多角形のうち、最も面積の小さいものを見つけるプログラムを作成してください。ただし、N個の点の座標を与えられた後、質問として凸多角形の角の個数 k がいくつか与えられます。 (補足:ハッピーエンド問題について) 平面上にどの3点も同じ直線上に乗らないように N 個の点を置きます。そのとき、どのように点を置いても、k個の点をうまく選ぶとk個の角をもつ凸多角形が必ず作れると予想されています。 今のところ、三角形ならば N =3、四角形ならば N =5、五角形ならば N =9、六角形ならば N =17であればよいことが、2006年までに証明されています。また、三角形以上のすべてのk角形に対して、 N =1+2 k -2 という予想がありますが、いまだ証明されていません。これは100年にわたり研究が進められている難問です。 この問題には、「ハッピーエンド問題」という素敵な名前がつけられています。ある男女がこの問題を研究しているうちに仲良くなって、ついに結婚したことにちなんで、友人の数学者が名付けたそうです。ロマンチックですね。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 N x 1 y 1 : x N y N Q k 1 : k Q 1行目に平面上の点の個数 N (3 ≤ N ≤ 40)が与えられる。続く N 行に各点の座標が与えられる。各点には1から N までの番号が、入力される順番に付けられている。 x i と y i (-10000 ≤ x i , y i ≤ 10000)は i 番目の点のそれぞれ x 座標と y 座標を表す整数である。 x 軸の正方向は右向き, y 軸の正方向は上向きに取るものとする。 続く1行に質問の数 Q (1 ≤ Q ≤ N )が与えられる。続く Q 行に質問が与えられる。 k i (3 ≤ k i ≤ N )は i 番目の質問である凸多角形の角の個数を表す。 なお、入力は以下の条件を満たすものとする。 入力される点の座標はすべて異なる。 どの3点も同じ直線上には乗らない。 各質問に対して面積最小の凸多角形は1つであり、2番目に小さい凸多角形との面積の差は 0.0001以上。 出力 質問ごとに、面積が最小の凸多角形の全頂点を1行に出力する。凸多角形の頂点で最も下にあるものの中で最も左にある頂点から順に、反時計周りで頂点の番号を出力する。頂点の番号の間は空白1つで区切る。行の終わりには空白文字を出力しない。ただし、凸多角形が作れない場合はNAと出力する。 入力例 1 5 0 0 3 0 5 2 1 4 0 3 3 3 4 5 出力例 1 1 4 5 1 2 4 5 1 2 3 4 5 入力例 2 6 0 0 3 0 5 2 1 4 0 3 3 2 4 3 4 5 6 出力例 2 6 3 5 6 3 4 5 1 2 6 4 5 NA
[ { "submission_id": "aoj_0284_10864669", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first;\n#define se second;\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\nnamespace geometry{\n using Real = long double;\n using Point = complex<Real>;\n const Real EPS = 1e-12;\n const Real PI = acos(-1);\n inline bool equal(const Real& a, const Real& b){\n return fabs(a - b) < EPS;\n }\n Real dot(const Point &a, const Point &b){\n return (a.real() * b.real() + a.imag() * b.imag());\n }\n Real cross(const Point &a, const Point &b){\n return (a.real() * b.imag() - a.imag() * b.real());\n }\n inline int sign(const Real &r) { return r <= -EPS ? -1 : r >= EPS ? 1 : 0; }\n int ccw(const Point &a, const Point &b, const Point &c){\n Point d = b - a;\n Point e = c - a;\n if(cross(d, e) > EPS) return 1; // counter clockwise (反時計回り)\n if(cross(d, e) < -EPS) return -1; // clockwise (時計回り)\n if(dot(d, e) < 0) return 2; // c-b-a\n if(norm(d) < norm(e)) return -2; // a-b-c\n return 0; // a-c-b\n }\n Real area3(Point a, Point b, Point c){\n return abs(cross(b-a,c-a))/2;\n }\n}\nusing namespace geometry;\n\n\nld dp[50][50][50][50];\nint pre[50][50][50][50];\nint main(){\n\n rep(i,50)rep(j,50)rep(k,50)rep(l,50) dp[i][j][k][l]=INFL, pre[i][j][k][l]=-1;\n\n int N;\n cin>>N;\n vector<Point> P(N);\n rep(i,N){\n int x,y;\n cin>>x>>y;\n P[i]=Point(x,y);\n }\n\n vector<ld> mi(N+1,INFL);\n vector<vector<int>> ans(N+1);\n\n\n rep(s,N){\n auto fs=[&](int i)->bool {\n if(P[i].imag()==P[s].imag()) return P[i].real()>=P[s].real();\n return P[i].imag()>P[s].imag();\n };\n rep(e, N){\n if(!fs(e)) continue;\n dp[s][1][e][s]=0;\n }\n rep(k,N){\n rep(i,N){\n if(i==s) continue;\n rep(j,N){\n if(i==j) continue;\n if(dp[s][k][i][j]>=INFL) continue;\n rep(e,N){\n if(i==e||j==e) continue;\n if(!fs(e)) continue;\n if(ccw(P[j], P[i], P[e])!=-1) continue;\n if(e!=s&&ccw(P[i], P[e], P[s])!=-1) continue;\n \n if(chmin(dp[s][k+1][e][i], dp[s][k][i][j]+area3(P[s], P[e], P[i]))){\n pre[s][k+1][e][i]=j;\n }\n }\n }\n }\n\n rep(j,N){\n if(chmin(mi[k+1], dp[s][k+1][s][j])){\n vector<int> V;\n int ni=s;\n int nj=j;\n for(int l=k+1;l>=1;l--){\n V.push_back(ni);\n int tmp=pre[s][l][ni][nj];\n ni=nj;\n nj=tmp;\n }\n ans[k+1]=V;\n }\n }\n }\n }\n\n int Q;\n cin>>Q;\n while(Q--){\n int k;\n cin>>k;\n if(si(ans[k])!=k) cout<<\"NA\\n\";\n else rep(i,k) cout<<ans[k][i]+1<<(i==k-1?\"\\n\":\" \");\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 125500, "score_of_the_acc": -1.027, "final_rank": 12 }, { "submission_id": "aoj_0284_7135688", "code_snippet": "#include <iostream>\n#include <string>\n#include <map>\n#include <set>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nlong double xs[43];\nlong double ys[43];\n\nclass E{\n\tpublic:\n\tlong double s1;\n\tvector<int> v1;\n\tE(){\n\t\ts1=-1;\n\t\tv1.clear();\n\t}\n};\n\nE ans[42];\n\n\n\nlong double g(int p1,int p2,int p3){\n\tlong double x2,y2,x3,y3;\n\tx2=xs[p2]-xs[p1];\n\ty2=ys[p2]-ys[p1];\n\tx3=xs[p3]-xs[p1];\n\ty3=ys[p3]-ys[p1];\n\treturn x2*y3-x3*y2;\n}\n\nbool allok(vector<int> &v1){\n\tint n=v1.size();\n\tint p1=v1[n-2];\n\tint p2=v1[n-1];\n\tint p3=v1[0];\n\tif(g(p1,p2,p3)<0)return false;\n\treturn true;\n}\n\nbool f2(int i,int j){\n\tif (ys[i]==ys[j] && xs[i]<xs[j]){\n\t\treturn true;\n\t}else if(ys[i]<ys[j]){\n\t\treturn true;\n\t}\n\treturn false;\n}\nvoid f4(int p1,int p2,int n){\n\t\n\tE dp[42][42][42];\n\t\n\tE e1;\n\te1.v1.push_back(p1);\n\te1.v1.push_back(p2);\n\te1.s1=0;\n\tdp[2][p1][p2]=e1;\n\tfor(int i=2;i<n;i++){\n\t\tfor(int t1=0;t1<n;t1++){\n\t\t\tfor(int t2=0;t2<n;t2++){\n\t\t\t\tif(t1==t2)continue;\n\t\t\t\tE e1=dp[i][t1][t2];\n\t\t\t\tif(e1.s1<0)continue;\n\t\t\t\tfor(int t3=0;t3<n;t3++){\n\t\t\t\t\tif(t1==t3||t2==t3)continue;\n\t\t\t\t\tif(0>=g(t1,t2,t3))continue;\n\t\t\t\t\tif(find(e1.v1.begin(),e1.v1.end(),t3)==e1.v1.end() && f2(e1.v1[0],t3)==true){\n\t\t\t\t\t\tlong double s1=g(e1.v1[0],t2,t3);\n\t\t\t\t\t\tif(s1<0)continue;\n\t\t\t\t\t\te1.v1.push_back(t3);\n\t\t\t\t\t\tif (allok(e1.v1)==false){\n\t\t\t\t\t\t\te1.v1.pop_back();\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\t\n\t\t\t\t\t\tlong double s3=e1.s1;\n\t\t\t\t\t\te1.s1+=abs(s1);\n\t\t\t\t\t\tlong double s4=dp[i+1][t2][t3].s1;\n\t\t\t\t\t\tif(ans[i+1].s1<0 ||ans[i+1].s1>e1.s1){\n\t\t\t\t\t\t\tans[i+1]=e1;\n\t\t\t\t\t\t\tif(i+1==4){\n\t\t\t\t\t\t\t\t\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif(s4<0 || s4>e1.s1){\n\t\t\t\t\t\t\tdp[i+1][t2][t3]=e1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\te1.v1.pop_back();\n\t\t\t\t\t\te1.s1=s3;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n}\n\nvoid f3(int n){\n\tfor(int i=0;i<=n;i++){\n\t\tans[i].s1=-1;\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tcin>>xs[i]>>ys[i];\n\t}\n\tfor(int p1=0;p1<n;p1++){\n\t\tfor(int p2=0;p2<n;p2++){\n\t\t\tif((p1==p2)||(f2(p1,p2)==false))continue;\n\t\t\tf4(p1,p2,n);\n\t\t}\n\t}\n\tint m;\n\tcin>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint t;\n\t\tcin>>t;\n\t\tif(ans[t].s1==-1){\n\t\t\tcout<<\"NA\"<<endl;\n\t\t}else{\n\t\t\tcout<<ans[t].v1[0]+1;\n\t\t\tfor(int i=1;i<t;i++){\n\t\t\t\tcout<<\" \"<<ans[t].v1[i]+1;\n\t\t\t}\n\t\t\tcout<<endl;\n\t\t}\n\t\t\n\t}\n}\n\n\nint main() {\n\t// your code goes here\n\tint n;\n\tcin>>n;\n\tf3(n);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 6988, "score_of_the_acc": -0.6097, "final_rank": 10 }, { "submission_id": "aoj_0284_5817285", "code_snippet": "//#pragma GCC target (\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp((i),mkp((j),(k)))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) int((a).size())\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all((b)),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)((c)-'0')\n#define itoc(c) (char)((c)+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",quetimes_+1)\n#define readv(a,n) (a).resize((n),0);rep(i,(n)) (a)[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = (ll)15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll ppc(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nvoid fin(T x) { cout << x << endl; exit(0); }\n\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n csum(int sz) { init(sz); }\n void init(int sz) { v = vector<T>(sz + 1, 0); }\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n void add(int l, int r, T x) {\n v[l] += x;\n v[r] -= x;\n }//[l,r)\n void add(int t, T x) {\n v[t] += x;\n }//[l,r)\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n T operator[](int x)const {\n return v[x];\n }\n};\nclass via {\n using H = pair<ll, ll>;\n bool comp;\npublic:\n vector<H>a;\n via() :comp(true) {}\n via(vector<H>dat) :a(dat), comp(false) { build(); }\n void push(int l, int r) { a.push_back(H{ l,r }); comp = false; }\n void push(H a) { push(a.first, a.second); }\n void build() {\n if (comp) return;\n comp = true;\n sort(a.begin(), a.end());\n int fst = -1; ll lst = -1;\n vector<H>b;\n for (int i = 0; i < a.size(); i++) {\n if (fst < 0) fst = i, lst = a[i].second;\n if (lst < a[i].first) {\n b.push_back(H{ a[fst].first,lst });\n fst = i, lst = a[i].second;\n }\n else if (lst < a[i].second) lst = a[i].second;\n }\n if (~fst) b.push_back(H{ a[fst].first, lst });\n a = b;\n }\n ll size() { return ll(a.size()); }\n ll sum() {\n build();\n ll sum = 0;\n for (auto g : a) sum += g.second - g.first;\n return sum;\n }\n via inter(via& v) {\n build(); v.build();\n via ret;\n for (auto g : a) ret.push(g);\n for (auto g : v.a) ret.push(g);\n ret.build(); return ret;\n }\n via comb(via& v) {\n build(); v.build();\n int s = 0, t = 0;\n via ret;\n while (s < a.size() && t < v.size()) {\n if (v[t].second <= a[s].first) t++;\n else if (a[s].second <= v[t].first) s++;\n else {\n ret.push(max(a[s].first, v[t].first), min(a[s].second, v[t].second));\n if (a[s].second <= v[t].second) s++;\n else t++;\n }\n }\n return ret;\n }\n H& operator[](int t) { return a[t]; }\n};\ntemplate<ll mod>\nclass modint {\npublic:ll v;\n modint(ll v = 0) { s(v % mod + mod); }\n constexpr static int fn_ = (ll)2e6 + 5;\n static vector<modint>fact, comp;\n modint pow(ll x) const {\n modint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline modint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline modint inv()const { return pow(mod - 2); }\n inline modint operator-()const { return modint() - *this; }\n inline modint& operator+=(const modint b) { return s(v + b.v); }\n inline modint& operator-=(const modint b) { return s(v + mod - b.v); }\n inline modint& operator*=(const modint b) { v = v * b.v % mod; return *this; }\n inline modint& operator/=(const modint b) { v = v * b.inv().v % mod; return *this; }\n inline modint operator+(const modint& b) const { return modint(v) += b; }\n inline modint operator-(const modint& b) const { return modint(v) -= b; }\n inline modint operator*(const modint& b) const { return modint(v) *= b; }\n inline modint operator/(const modint& b) const { return modint(v) /= b; }\n friend ostream& operator<<(ostream& os, const modint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, modint& m) {\n int x; is >> x; m = modint(x);\n return is;\n }\n bool operator<(const modint& r)const { return v < r.v; }\n bool operator>(const modint& r)const { return v > r.v; }\n bool operator<=(const modint& r)const { return v <= r.v; }\n bool operator>=(const modint& r)const { return v >= r.v; }\n bool operator==(const modint& r)const { return v == r.v; }\n bool operator!=(const modint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n modint comb(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n if (k > *this - k) k = *this - k;\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n modint perm(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact.assign(fn_, modint());\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * modint(i);\n comp.assign(fn_, modint());\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * modint(i + 1);\n }\n};\nusing mint = modint<ll(1e9 + 7)>; template<>vec<mint> mint::fact = vec<mint>(); template<>vec<mint> mint::comp = vec<mint>();\n//--------------------------------------------------------------\n//--------------------------------------------------------------\nll area(H a, H b, H c) {\n b.fs -= a.fs; b.sc -= a.sc;\n c.fs -= a.fs; c.sc -= a.sc;\n return b.fs * c.sc - b.sc * c.fs;\n}\n\n\nll dp[42][42][42][42];\n\nsigned main() {\n int n; cin >> n;\n vec<H>a;\n rep(i, n) a.pb(readh());\n\n vec<vec<H>>ans(n + 1, vec<H>());\n vi score(n + 1, inf);\n\n rep(st, n) {\n //start is st\n\n vec<H>b;\n rep(i, n) if (a[i].fs >= a[st].fs && a[i] != a[st]) b.pb(a[i]);\n sort(all(b), [&](H x, H y) {\n return area(a[st], x, y) < 0;\n });\n\n rep(i, 42)rep(j, 42)rep(k, 42)rep(t, 42) dp[i][j][k][t] = inf;\n \n rep(i, siz(b))rng(j, i + 1, siz(b)) {\n dp[j][3][i][j] = -area(a[st], b[i], b[j]);\n }\n\n rng(i, 2, siz(b)) {\n rng(j, 3, i + 3) {\n rep(x, i)rng(y, x + 1, i) {\n dp[i][j][x][y] = dp[i - 1][j][x][y];\n if (dp[i - 1][j - 1][x][y] < inf) {\n if (area(b[x], b[y], b[i]) < 0) {\n chmin(dp[i][j][y][i], dp[i - 1][j - 1][x][y] - area(a[st], b[y], b[i]));\n }\n }\n }\n }\n }\n\n rng(z, 3, siz(b) + 2) {\n int i = siz(b) - 1, j = z, x = -1, y = 0;\n rep(k, siz(b))rep(t, siz(b)) {\n if (x < 0 && dp[i][j][k][t] < inf) x = k, y = t;\n else if (~x && dp[i][j][x][y] > dp[i][j][k][t]) {\n x = k, y = t;\n }\n }\n if (x < 0) continue;\n vec<H>v; v.pb(b[y]); v.pb(b[x]); v.pb(a[st]);\n ll rest = dp[i][j][x][y];\n rest += area(a[st], b[x], b[y]);\n\n if (score[j] <= dp[i][j][x][y]) continue;\n score[j] = dp[i][j][x][y];\n\n while (rest > 0) {\n rep(k, siz(b)) {\n if (area(b[k], b[x], b[y]) < 0 &&\n dp[x][j - 1][k][x] - area(a[st], b[x], b[y]) ==\n dp[y][j][x][y]) {\n v.pb(b[k]);\n rest += area(a[st], b[k], b[x]);\n y = x; x = k;\n j--;\n break;\n }\n }\n }\n\n ans[z] = v;\n }\n }\n\n map<H, int>mp;\n rep(i, n) mp[a[i]] = i + 1;\n vec<vi>ans2(n + 1);\n rep(i, n + 1) {\n if (siz(ans[i]) == 0) continue;\n int st = 0;\n vi tmp;\n rep(j, siz(ans[i]))\n if (ans[i][st].sc > ans[i][j].sc ||\n ans[i][st].sc == ans[i][j].sc &&\n ans[i][st].fs > ans[i][j].fs)\n st = j;\n tmp.pb(mp[ans[i][st]]);\n vec<H>c;\n rep(j, siz(ans[i])) if (ans[i][j] != ans[i][st]) c.pb(ans[i][j]);\n sort(all(c), [&](H x, H y) {\n return area(ans[i][st], x, y) > 0;\n });\n for (auto g : c) tmp.pb(mp[g]);\n ans2[i] = tmp;\n }\n \n int q; cin >> q;\n rep(i, q) {\n int t; cin >> t;\n if (siz(ans2[t]) == 0) cout << \"NA\\n\";\n else {\n rep(j, siz(ans2[t])) cout << ans2[t][j] << ssp(j, siz(ans2[t]));\n }\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 27836, "score_of_the_acc": -0.267, "final_rank": 9 }, { "submission_id": "aoj_0284_5662704", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nusing real = int;\nstruct Point {\n real x, y;\n Point& operator+=(const Point a) { x += a.x; y += a.y; return *this; }\n Point& operator-=(const Point a) { x -= a.x; y -= a.y; return *this; }\n Point& operator*=(const real k) { x *= k; y *= k; return *this; }\n Point& operator/=(const real k) { x /= k; y /= k; return *this; }\n Point operator+(const Point a) const {return Point(*this) += a; }\n Point operator-(const Point a) const {return Point(*this) -= a; }\n Point operator*(const real k) const {return Point(*this) *= k; }\n Point operator/(const real k) const {return Point(*this) /= k; }\n bool operator<(const Point &a) const { return (x != a.x ? x < a.x : y < a.y); }\n explicit Point(real a = 0, real b = 0) : x(a), y(b) {};\n};\n\nistream& operator>> (istream& s, Point& P){\n s >> P.x >> P.y;\n return s;\n}\n\n\n\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\n\n\n// dp[i][j][k][l] := 三角形jklから隣接してできた凸i角形\n// prv[i][j][k][l] := 三角形ijkから凸i角形を作るときに追加する点k\nint dp[41][40][40][40], prv[41][40][40][40];\n\nint main() {\n int n;\n cin >> n;\n vector<Point> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i];\n }\n auto area = [](Point a, Point b, Point c){ return (b.x-a.x)*(c.y-a.y)-(b.y-a.y)*(c.x-a.x); };\n auto to = make_v(n, n, vector<int>());\n fill_n((int*)dp, 41*40*40*40, INF<int>);\n fill_n((int*)prv, 41*40*40*40, 0);\n\n // 線ijから三角形ijkを作れる点kを求める\n // 新しく追加する点はjよりも低い位置にあることが条件\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n if(i == j) continue;\n if(v[i].y <= v[j].y) dp[2][i][i][j] = 0;\n for (int k = 0; k < n; ++k) {\n if(i == k || j == k) continue;\n if(area(v[i], v[j], v[k]) > 0 && (v[i].y <= v[j].y || v[j].y >= v[k].y)){\n to[i][j].emplace_back(k);\n }\n }\n }\n }\n for (int i = 2; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n for (int k = 0; k < n; ++k) {\n for (int l = 0; l < n; ++l) {\n if(dp[i][j][k][l] == INF<int>) continue;\n for (auto &&m : to[k][l]) {\n if(v[j].y > v[m].y || j == m) continue;\n int a = area(v[j], v[l], v[m]);\n\n if(a > 0 && dp[i+1][j][l][m] > dp[i][j][k][l]+a){\n dp[i+1][j][l][m] = dp[i][j][k][l]+a;\n prv[i+1][j][l][m] = k;\n }\n }\n }\n }\n }\n }\n vector<vector<int>> anss(n+1);\n // 凸i角形の最小のものを求める\n for (int i = 3; i <= n; ++i) {\n int val = INF<int>, a = 0, b = 0, c = 0;\n for (int j = 0; j < n; ++j) {\n for (int k = 0; k < n; ++k) {\n for (int l = 0; l < n; ++l) {\n if(dp[i][j][k][l] < val){\n val = dp[i][j][k][l];\n a = j; b = k; c = l;\n }\n }\n }\n }\n if(val == INF<int>) {\n continue;\n }\n // prvから点kを取り出す\n vector<int> ans{c, b};\n for (int j = i; j >= 3; --j) {\n int x = prv[j][a][b][c];\n ans.emplace_back(x);\n c = b; b = x;\n }\n\n // 反時計回りにする\n reverse(ans.begin(),ans.end());\n if(v[ans.front()].y == v[ans.back()].y){\n rotate(ans.begin(), ans.end()-1, ans.end());\n }\n anss[i] = ans;\n }\n int q;\n cin >> q;\n while(q--){\n int x;\n cin >> x;\n if(anss[x].empty()) puts(\"NA\");\n else{\n for (int i = 0; i < anss[x].size(); ++i) {\n printf(i ? \" %d\" : \"%d\", anss[x][i]+1);\n }\n puts(\"\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 24168, "score_of_the_acc": -0.1694, "final_rank": 5 }, { "submission_id": "aoj_0284_5587567", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = double;\n // using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\nnamespace geometry {\n bool compare_x(const point &a, const point &b) {\n return !equals(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n\n bool compare_y(const point &a, const point &b) {\n return !equals(a.imag(), b.imag()) ? a.imag() < b.imag() : a.real() < b.real();\n }\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// polygon\nnamespace geometry {\n using polygon = vector< point >;\n using polygons = vector< polygon >;\n}\n\n// area\nnamespace geometry {\n real_number area(const polygon &poly) {\n int n = poly.size();\n real_number res = 0;\n for (int i = 0; i < n; ++i) {\n res += cross(poly[i], poly[(i + 1) % n]);\n }\n return res / 2;\n }\n}\n\nusing namespace geometry;\n\nvoid solve() {\n int n = input();\n \n vector< pair<point, int> > pts;\n range(i, 0, n) {\n point p;\n cin >> p;\n pts.emplace_back(p, i + 1);\n }\n\n whole(sort, pts, [](auto &a, auto &b) { return compare_x(a.first, b.first); });\n\n auto udp = make_vector(n, n, n, n + 1, real_number(inf));\n auto uval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n udp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n\n point a = pts[p].first;\n point b = pts[t].first;\n\n if (udp[s][p][t][k] > inf - 1) continue;\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(udp[s][t][i][k + 1] - (udp[s][p][t][k] + S)) > 0) {\n udp[s][t][i][k + 1] = udp[s][p][t][k] + S;\n uval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto ddp = make_vector(n, n, n, n + 1, real_number(inf));\n auto dval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n ddp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n \n point a = pts[p].first;\n point b = pts[t].first;\n\n if (ddp[s][p][t][k] > inf - 1) continue;\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != COUNTER_CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(ddp[s][t][i][k + 1] - (ddp[s][p][t][k] + S)) > 0) {\n ddp[s][t][i][k + 1] = ddp[s][p][t][k] + S;\n dval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto upre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = upre[s][t][k];\n range(p, s, t) {\n if (udp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(udp[s][idx][t][k] - udp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n auto dpre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = dpre[s][t][k];\n range(p, s, t) {\n if (ddp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(ddp[s][idx][t][k] - ddp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n int q = input();\n range(_, 0, q) {\n int k = input();\n\n real_number min_area = inf;\n int S = -1, T = -1, A = -1, P = -1, Q = -1;\n range(s, 0, n) range(t, s + 1, n) range(a, 2, k + 1) {\n int b = k + 2 - a;\n\n int p = upre[s][t][a];\n int q = dpre[s][t][b];\n\n if (p == -1 or q == -1) continue;\n\n real_number now_area = udp[s][p][t][a] + ddp[s][q][t][b];\n if (sign(min_area - now_area) <= 0) continue;\n min_area = now_area;\n S = s;\n T = t;\n A = a;\n P = p;\n Q = q;\n }\n\n if (S == -1) {\n cout << \"NA\" << endl;\n continue;\n }\n\n vector< int > idxs;\n {\n int p = Q, t = T, a = k + 2 - A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = dval[S][p][t][a];\n a--;\n }\n }\n\n whole(reverse, idxs);\n idxs.pop_back();\n\n {\n int p = P, t = T, a = A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = uval[S][p][t][a];\n a--;\n }\n }\n\n idxs.emplace_back(S);\n\n int st = 0;\n range(i, 1, idxs.size()) {\n point a = pts[idxs[i]].first;\n point pt = pts[idxs[st]].first;\n if (pt.imag() < a.imag()) continue;\n if (pt.imag() > a.imag()) {\n st = i;\n continue;\n }\n if (pt.real() > a.real()) {\n st = i;\n }\n }\n\n vector< int > ans;\n range(i, 0, idxs.size()) {\n ans.emplace_back(pts[idxs[(i + st) % idxs.size()]].second);\n }\n\n cout << ans << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 93920, "score_of_the_acc": -0.7952, "final_rank": 11 }, { "submission_id": "aoj_0284_5587507", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\nnamespace geometry {\n bool compare_x(const point &a, const point &b) {\n return !equals(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n\n bool compare_y(const point &a, const point &b) {\n return !equals(a.imag(), b.imag()) ? a.imag() < b.imag() : a.real() < b.real();\n }\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// polygon\nnamespace geometry {\n using polygon = vector< point >;\n using polygons = vector< polygon >;\n}\n\n// area\nnamespace geometry {\n real_number area(const polygon &poly) {\n int n = poly.size();\n real_number res = 0;\n for (int i = 0; i < n; ++i) {\n res += cross(poly[i], poly[(i + 1) % n]);\n }\n return res / 2;\n }\n}\n\nusing namespace geometry;\n\nvoid solve() {\n int n = input();\n \n vector< pair<point, int> > pts;\n range(i, 0, n) {\n point p;\n cin >> p;\n pts.emplace_back(p, i + 1);\n }\n\n whole(sort, pts, [](auto &a, auto &b) { return compare_x(a.first, b.first); });\n\n auto udp = make_vector(n, n, n, n + 1, real_number(inf));\n auto uval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n udp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n\n point a = pts[p].first;\n point b = pts[t].first;\n\n if (udp[s][p][t][k] > inf - 1) continue;\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(udp[s][t][i][k + 1] - (udp[s][p][t][k] + S)) > 0) {\n udp[s][t][i][k + 1] = udp[s][p][t][k] + S;\n uval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto ddp = make_vector(n, n, n, n + 1, real_number(inf));\n auto dval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n ddp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n \n point a = pts[p].first;\n point b = pts[t].first;\n\n if (ddp[s][p][t][k] > inf - 1) continue;\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != COUNTER_CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(ddp[s][t][i][k + 1] - (ddp[s][p][t][k] + S)) > 0) {\n ddp[s][t][i][k + 1] = ddp[s][p][t][k] + S;\n dval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto upre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = upre[s][t][k];\n range(p, s, t) {\n if (udp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(udp[s][idx][t][k] - udp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n auto dpre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = dpre[s][t][k];\n range(p, s, t) {\n if (ddp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(ddp[s][idx][t][k] - ddp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n int q = input();\n range(_, 0, q) {\n int k = input();\n\n real_number min_area = inf;\n int S = -1, T = -1, A = -1, P = -1, Q = -1;\n range(s, 0, n) range(t, s + 1, n) range(a, 2, k + 1) {\n int b = k + 2 - a;\n\n int p = upre[s][t][a];\n int q = dpre[s][t][b];\n\n if (p == -1 or q == -1) continue;\n\n real_number now_area = udp[s][p][t][a] + ddp[s][q][t][b];\n if (sign(min_area - now_area) <= 0) continue;\n min_area = now_area;\n S = s;\n T = t;\n A = a;\n P = p;\n Q = q;\n }\n\n if (S == -1) {\n cout << \"NA\" << endl;\n continue;\n }\n\n vector< int > idxs;\n {\n int p = Q, t = T, a = k + 2 - A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = dval[S][p][t][a];\n a--;\n }\n }\n\n whole(reverse, idxs);\n idxs.pop_back();\n\n {\n int p = P, t = T, a = A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = uval[S][p][t][a];\n a--;\n }\n }\n\n idxs.emplace_back(S);\n\n int st = 0;\n point pt = pts[idxs[0]].first;\n range(i, 1, idxs.size()) {\n point a = pts[idxs[i]].first;\n if (pt.imag() < a.imag()) continue;\n if (pt.imag() > a.imag()) {\n st = i;\n continue;\n }\n if (pt.real() > a.real()) {\n st = i;\n }\n }\n\n vector< int > ans;\n range(i, 0, idxs.size()) {\n ans.emplace_back(pts[idxs[(i + st) % idxs.size()]].second);\n }\n\n cout << ans << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 0.6666666666666666, "time_ms": 20, "memory_kb": 46628, "score_of_the_acc": -0.367, "final_rank": 17 }, { "submission_id": "aoj_0284_5587471", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\nnamespace geometry {\n bool compare_x(const point &a, const point &b) {\n return !equals(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n\n bool compare_y(const point &a, const point &b) {\n return !equals(a.imag(), b.imag()) ? a.imag() < b.imag() : a.real() < b.real();\n }\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// polygon\nnamespace geometry {\n using polygon = vector< point >;\n using polygons = vector< polygon >;\n}\n\n// area\nnamespace geometry {\n real_number area(const polygon &poly) {\n int n = poly.size();\n real_number res = 0;\n for (int i = 0; i < n; ++i) {\n res += cross(poly[i], poly[(i + 1) % n]);\n }\n return res / 2;\n }\n}\n\nusing namespace geometry;\n\nvoid solve() {\n int n = input();\n \n vector< pair<point, int> > pts;\n range(i, 0, n) {\n point p;\n cin >> p;\n pts.emplace_back(p, i + 1);\n }\n\n whole(sort, pts, [](auto &a, auto &b) { return compare_x(a.first, b.first); });\n\n auto udp = make_vector(n, n, n, n + 1, real_number(infll));\n auto uval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n udp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n\n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(udp[s][t][i][k + 1] - (udp[s][p][t][k] + S)) > 0) {\n udp[s][t][i][k + 1] = udp[s][p][t][k] + S;\n uval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto ddp = make_vector(n, n, n, n + 1, real_number(infll));\n auto dval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n ddp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n \n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != COUNTER_CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(ddp[s][t][i][k + 1] - (ddp[s][p][t][k] + S)) > 0) {\n ddp[s][t][i][k + 1] = ddp[s][p][t][k] + S;\n dval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto upre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = upre[s][t][k];\n range(p, s, t) {\n if (udp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(udp[s][idx][t][k] - udp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n auto dpre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = dpre[s][t][k];\n range(p, s, t) {\n if (ddp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(ddp[s][idx][t][k] - ddp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n int q = input();\n range(_, 0, q) {\n int k = input();\n\n real_number min_area = infll;\n int S = -1, T = -1, A = -1, P = -1, Q = -1;\n range(s, 0, n) range(t, s + 1, n) range(a, 2, k + 1) {\n int b = k + 2 - a;\n\n int p = upre[s][t][a];\n int q = dpre[s][t][b];\n\n if (p == -1 or q == -1) continue;\n\n real_number now_area = udp[s][p][t][a] + ddp[s][q][t][b];\n if (sign(min_area - now_area) <= 0) continue;\n min_area = now_area;\n S = s;\n T = t;\n A = a;\n P = p;\n Q = q;\n }\n\n if (S == -1) {\n cout << \"NA\" << endl;\n continue;\n }\n\n vector< int > idxs;\n {\n int p = Q, t = T, a = k + 2 - A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = dval[S][p][t][a];\n a--;\n }\n }\n\n whole(reverse, idxs);\n idxs.pop_back();\n\n {\n int p = P, t = T, a = A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = uval[S][p][t][a];\n a--;\n }\n }\n\n idxs.emplace_back(S);\n\n int st = 0;\n point pt = pts[idxs[0]].first;\n range(i, 1, idxs.size()) {\n point a = pts[idxs[i]].first;\n if (pt.imag() < a.imag()) continue;\n if (pt.imag() > a.imag()) {\n st = i;\n continue;\n }\n if (pt.real() > a.real()) {\n st = i;\n }\n }\n\n vector< int > ans;\n range(i, 0, idxs.size()) {\n ans.emplace_back(pts[idxs[(i + st) % idxs.size()]].second);\n }\n\n cout << ans << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 0.6666666666666666, "time_ms": 70, "memory_kb": 46620, "score_of_the_acc": -0.4345, "final_rank": 18 }, { "submission_id": "aoj_0284_5587453", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\nnamespace geometry {\n bool compare_x(const point &a, const point &b) {\n return !equals(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n\n bool compare_y(const point &a, const point &b) {\n return !equals(a.imag(), b.imag()) ? a.imag() < b.imag() : a.real() < b.real();\n }\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// polygon\nnamespace geometry {\n using polygon = vector< point >;\n using polygons = vector< polygon >;\n}\n\n// area\nnamespace geometry {\n real_number area(const polygon &poly) {\n int n = poly.size();\n real_number res = 0;\n for (int i = 0; i < n; ++i) {\n res += cross(poly[i], poly[(i + 1) % n]);\n }\n return res / 2;\n }\n}\n\nusing namespace geometry;\n\nvoid solve() {\n int n = input();\n \n vector< pair<point, int> > pts;\n range(i, 0, n) {\n point p;\n cin >> p;\n pts.emplace_back(p, i + 1);\n }\n\n whole(sort, pts, [](auto &a, auto &b) { return compare_x(a.first, b.first); });\n\n auto udp = make_vector(n, n, n, n + 1, real_number(inf));\n auto uval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n udp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n\n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(udp[s][t][i][k + 1] - (udp[s][p][t][k] + S)) > 0) {\n udp[s][t][i][k + 1] = udp[s][p][t][k] + S;\n uval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto ddp = make_vector(n, n, n, n + 1, real_number(inf));\n auto dval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n ddp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n \n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != COUNTER_CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(ddp[s][t][i][k + 1] - (ddp[s][p][t][k] + S)) > 0) {\n ddp[s][t][i][k + 1] = ddp[s][p][t][k] + S;\n dval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto upre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = upre[s][t][k];\n range(p, s, t) {\n if (udp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(udp[s][idx][t][k] - udp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n auto dpre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = dpre[s][t][k];\n range(p, s, t) {\n if (ddp[s][p][t][k] > inf - 1) continue;\n if (idx == -1 or sign(ddp[s][idx][t][k] - ddp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n int q = input();\n range(_, 0, q) {\n int k = input();\n\n real_number min_area = inf;\n int S = -1, T = -1, A = -1, P = -1, Q = -1;\n range(s, 0, n) range(t, s + 1, n) range(a, 2, k + 1) {\n int b = k + 2 - a;\n\n int p = upre[s][t][a];\n int q = dpre[s][t][b];\n\n if (p == -1 or q == -1) continue;\n\n real_number now_area = udp[s][p][t][a] + ddp[s][q][t][b];\n if (sign(min_area - now_area) <= 0) continue;\n min_area = now_area;\n S = s;\n T = t;\n A = a;\n P = p;\n Q = q;\n }\n\n if (S == -1) {\n cout << \"NA\" << endl;\n continue;\n }\n\n vector< int > idxs;\n {\n int p = Q, t = T, a = k + 2 - A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = dval[S][p][t][a];\n a--;\n }\n }\n\n whole(reverse, idxs);\n idxs.pop_back();\n\n {\n int p = P, t = T, a = A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = uval[S][p][t][a];\n a--;\n }\n }\n\n idxs.emplace_back(S);\n\n int st = 0;\n point pt = pts[idxs[0]].first;\n range(i, 1, idxs.size()) {\n point a = pts[idxs[i]].first;\n if (pt.imag() < a.imag()) continue;\n if (pt.imag() > a.imag()) {\n st = i;\n continue;\n }\n if (pt.real() > a.real()) {\n st = i;\n }\n }\n\n vector< int > ans;\n range(i, 0, idxs.size()) {\n ans.emplace_back(pts[idxs[(i + st) % idxs.size()]].second);\n }\n\n cout << ans << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 0.6666666666666666, "time_ms": 70, "memory_kb": 46668, "score_of_the_acc": -0.4349, "final_rank": 19 }, { "submission_id": "aoj_0284_5587446", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\n// base\nnamespace geometry {\n using namespace std;\n using real_number = long double;\n\n const real_number PI = acosl(-1);\n\n inline static real_number &eps() {\n static real_number EPS = 1e-10;\n return EPS;\n }\n\n static void set_eps(real_number EPS) {\n eps() = EPS;\n }\n\n inline int sign(real_number r) {\n set_eps(1e-10);\n if (r < -eps()) return -1;\n if (r > +eps()) return +1;\n return 0;\n }\n\n inline bool equals(real_number r1, real_number r2) {\n return sign(r1 - r2) == 0;\n }\n}\n\n// point\nnamespace geometry {\n using point = complex< real_number >;\n using points = vector< point >;\n\n istream &operator>>(istream &is, point &p) {\n real_number x, y;\n is >> x >> y;\n p = point(x, y);\n return is;\n }\n\n ostream &operator<<(ostream &os, const point &p) {\n return os << p.real() << \" \" << p.imag();\n }\n\n point operator*(const point &p, const real_number &k) {\n return point(p.real() * k, p.imag() * k);\n }\n\n point rotate(const real_number &theta, const point &p) {\n return point(cos(theta) * p.real() + sin(-theta) * p.imag(),\n sin(theta) * p.real() + cos(-theta) * p.imag());\n }\n\n bool equals(const point &a, const point &b) {\n return equals(a.real(), b.real()) and equals(a.imag(), b.imag());\n }\n}\n\nnamespace geometry {\n bool compare_x(const point &a, const point &b) {\n return !equals(a.real(), b.real()) ? a.real() < b.real() : a.imag() < b.imag();\n }\n\n bool compare_y(const point &a, const point &b) {\n return !equals(a.imag(), b.imag()) ? a.imag() < b.imag() : a.real() < b.real();\n }\n}\n\n// product\nnamespace geometry {\n real_number cross(const point &a, const point &b) {\n return a.real() * b.imag() - a.imag() * b.real();\n }\n\n real_number dot(const point &a, const point &b) {\n return a.real() * b.real() + a.imag() * b.imag();\n }\n}\n\n// ccw\nnamespace geometry {\n constexpr int COUNTER_CLOCKWISE = +1;\n constexpr int CLOCKWISE = -1;\n constexpr int ONLINE_BACK = +2; // c-a-b\n constexpr int ONLINE_FRONT = -2; // a-b-c\n constexpr int ON_SEGMENT = 0; // a-c-b\n int ccw(const point &a, point b, point c) {\n b = b - a, c = c - a;\n if (sign(cross(b, c)) == +1) return COUNTER_CLOCKWISE;\n if (sign(cross(b, c)) == -1) return CLOCKWISE;\n if (sign(dot(b, c)) == -1) return ONLINE_BACK;\n if (norm(b) < norm(c)) return ONLINE_FRONT;\n return ON_SEGMENT;\n }\n}\n\n// polygon\nnamespace geometry {\n using polygon = vector< point >;\n using polygons = vector< polygon >;\n}\n\n// area\nnamespace geometry {\n real_number area(const polygon &poly) {\n int n = poly.size();\n real_number res = 0;\n for (int i = 0; i < n; ++i) {\n res += cross(poly[i], poly[(i + 1) % n]);\n }\n return res / 2;\n }\n}\n\nusing namespace geometry;\n\nvoid solve() {\n int n = input();\n \n vector< pair<point, int> > pts;\n range(i, 0, n) {\n point p;\n cin >> p;\n pts.emplace_back(p, i + 1);\n }\n\n whole(sort, pts, [](auto &a, auto &b) { return compare_x(a.first, b.first); });\n\n auto udp = make_vector(n, n, n, n + 1, real_number(inf));\n auto uval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n udp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n\n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(udp[s][t][i][k + 1] - (udp[s][p][t][k] + S)) > 0) {\n udp[s][t][i][k + 1] = udp[s][p][t][k] + S;\n uval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto ddp = make_vector(n, n, n, n + 1, real_number(inf));\n auto dval = make_vector(n, n, n, n + 1, pair<int, int>(-1, -1));\n range(s, 0, n) range(t, s + 1, n) {\n ddp[s][s][t][2] = 0;\n }\n\n range(s, 0, n) range(p, s, n) range(t, p + 1, n) range(k, 2, n) {\n point q = pts[s].first;\n \n point a = pts[p].first;\n point b = pts[t].first;\n\n range(i, t + 1, n) {\n point c = pts[i].first;\n if (ccw(a, b, c) != COUNTER_CLOCKWISE) continue;\n polygon poly({q, b, c});\n real_number S = abs(area(poly));\n\n if (sign(ddp[s][t][i][k + 1] - (ddp[s][p][t][k] + S)) > 0) {\n ddp[s][t][i][k + 1] = ddp[s][p][t][k] + S;\n dval[s][t][i][k + 1] = make_pair(p, t);\n }\n }\n }\n\n auto upre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = upre[s][t][k];\n range(p, s, t) {\n if (udp[s][p][t][k] > 1e8) continue;\n if (idx == -1 or sign(udp[s][idx][t][k] - udp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n auto dpre = make_vector(n, n, n + 1, -1);\n range(s, 0, n) range(t, s + 1, n) range(k, 2, n + 1) {\n int &idx = dpre[s][t][k];\n range(p, s, t) {\n if (ddp[s][p][t][k] > 1e8) continue;\n if (idx == -1 or sign(ddp[s][idx][t][k] - ddp[s][p][t][k]) > 0) {\n idx = p;\n }\n }\n }\n\n int q = input();\n range(_, 0, q) {\n int k = input();\n\n real_number min_area = inf;\n int S = -1, T = -1, A = -1, P = -1, Q = -1;\n range(s, 0, n) range(t, s + 1, n) range(a, 2, k + 1) {\n int b = k + 2 - a;\n\n int p = upre[s][t][a];\n int q = dpre[s][t][b];\n\n if (p == -1 or q == -1) continue;\n\n real_number now_area = udp[s][p][t][a] + ddp[s][q][t][b];\n if (sign(min_area - now_area) <= 0) continue;\n min_area = now_area;\n S = s;\n T = t;\n A = a;\n P = p;\n Q = q;\n }\n\n if (S == -1) {\n cout << \"NA\" << endl;\n continue;\n }\n\n vector< int > idxs;\n {\n int p = Q, t = T, a = k + 2 - A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = dval[S][p][t][a];\n a--;\n }\n }\n\n whole(reverse, idxs);\n idxs.pop_back();\n\n {\n int p = P, t = T, a = A;\n while (true) {\n idxs.emplace_back(t);\n if (p == S) break;\n tie(p, t) = uval[S][p][t][a];\n a--;\n }\n }\n\n idxs.emplace_back(S);\n\n int st = 0;\n point pt = pts[idxs[0]].first;\n range(i, 1, idxs.size()) {\n point a = pts[idxs[i]].first;\n if (pt.imag() < a.imag()) continue;\n if (pt.imag() > a.imag()) {\n st = i;\n continue;\n }\n if (pt.real() > a.real()) {\n st = i;\n }\n }\n\n vector< int > ans;\n range(i, 0, idxs.size()) {\n ans.emplace_back(pts[idxs[(i + st) % idxs.size()]].second);\n }\n\n cout << ans << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 0.6666666666666666, "time_ms": 70, "memory_kb": 46668, "score_of_the_acc": -0.4349, "final_rank": 19 }, { "submission_id": "aoj_0284_5044205", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nint N;\npair<int,int>p[40];\nint f[40][40];\nint dp[41][40][40];\nbool ok[40][40][40];\nint L[40],R[40];\nvector<int>Lk[40],Rk[40];\nint ans[41];\nvector<int>vs[41];\nmain()\n{\n\tcin>>N;\n\tfor(int i=3;i<=N;i++)ans[i]=1e9;\n\tfor(int i=0;i<N;i++)cin>>p[i].first>>p[i].second;\n\tfor(int i=0;i<N;i++)for(int j=0;j<N;j++)for(int k=0;k<N;k++)\n\t{\n\t\tint ax=p[j].first-p[i].first;\n\t\tint ay=p[j].second-p[i].second;\n\t\tint bx=p[k].first-p[i].first;\n\t\tint by=p[k].second-p[i].second;\n\t\tok[i][j][k]=ax*by-bx*ay>0;\n\t}\n\tfor(int i=0;i<N;i++)for(int j=0;j<N;j++)\n\t{\n\t\tf[i][j]=(p[i].first-p[j].first)*(p[i].second+p[j].second);\n\t}\n\tfor(int I=0;I<N;I++)for(int J=0;J<N;J++)if(p[I].first<p[J].first)\n\t{\n\t\tfor(int k=0;k<N;k++)for(int i=0;i<N;i++)for(int j=0;j<N;j++)dp[k][i][j]=1e9;\n\t\tdp[0][I][J]=f[I][J];\n\t\tvector<int>can;\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tif(i!=I&&i!=J&&ok[I][i][J]&&p[I].first<=p[i].first&&p[i].first<=p[J].first)\n\t\t\t{\n\t\t\t\tdp[1][I][i]=f[I][i];\n\t\t\t\tcan.push_back(i);\n\t\t\t}\n\t\t}\n\t\tfor(int j:can)if(dp[1][I][j]<(int)1e9)\n\t\t{\n\t\t\tfor(int l:can)\n\t\t\t\tif(ok[I][j][l]&&ok[j][l][J])dp[2][j][l]=min(dp[2][j][l],dp[1][I][j]+f[j][l]);\n\t\t}\n\t\tfor(int k=2;k<N;k++)\n\t\t{\n\t\t\tbool nxt=false;\n\t\t\tfor(int i:can)for(int j:can)if(dp[k][i][j]<(int)1e9)\n\t\t\t{\n\t\t\t\tfor(int l:can)if(ok[i][j][l]&&ok[j][l][J])\n\t\t\t\t{\n\t\t\t\t\tdp[k+1][j][l]=min(dp[k+1][j][l],dp[k][i][j]+f[j][l]);\n\t\t\t\t\tnxt=true;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!nxt)break;\n\t\t}\n\t\tfor(int k=0;k<N;k++)\n\t\t{\n\t\t\tL[k]=1e9;\n\t\t\tLk[k].clear();\n\t\t}\n\t\tL[0]=dp[0][I][J];\n\t\tfor(int k=1;k<N;k++)\n\t\t{\n\t\t\tint u=-1,v;\n\t\t\tfor(int i=0;i<N;i++)for(int j:can)\n\t\t\t\tif(ok[i][j][J]&&dp[k][i][j]<(int)1e9&&dp[k][i][j]+f[j][J]<L[k])\n\t\t\t{\n\t\t\t\tL[k]=dp[k][i][j]+f[j][J];\n\t\t\t\tv=i;\n\t\t\t\tu=j;\n\t\t\t}\n\t\t\tif(u<0)continue;\n\t\t\tvector<int>now;\n\t\t\tnow.push_back(u);\n\t\t\tif(k>1)now.push_back(v);\n\t\t\tint nk=k-2;\n\t\t\twhile(nk>0)\n\t\t\t{\n\t\t\t\tint w=-1;\n\t\t\t\tfor(int i:can)if(ok[i][v][u]&&dp[nk+1][i][v]+f[v][u]==dp[nk+2][v][u])\n\t\t\t\t{\n\t\t\t\t\tw=i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tnow.push_back(w);\n\t\t\t\tu=v;\n\t\t\t\tv=w;\n\t\t\t\tnk--;\n\t\t\t}\n\t\t\tLk[k]=now;\n\t\t}\n\t\tfor(int k=0;k<N;k++)for(int i=0;i<N;i++)for(int j=0;j<N;j++)dp[k][i][j]=1e9;\n\t\tdp[0][J][I]=f[J][I];\n\t\tcan.clear();\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tif(i!=I&&i!=J&&ok[J][i][I]&&p[I].first<=p[i].first&&p[i].first<=p[J].first)\n\t\t\t{\n\t\t\t\tdp[1][J][i]=f[J][i];\n\t\t\t\tcan.push_back(i);\n\t\t\t}\n\t\t}\n\t\tfor(int j:can)if(dp[1][J][j]<(int)1e9)\n\t\t{\n\t\t\tfor(int l:can)\n\t\t\t\tif(ok[J][j][l]&&ok[j][l][I])dp[2][j][l]=min(dp[2][j][l],dp[1][J][j]+f[j][l]);\n\t\t}\n\t\tfor(int k=2;k<N;k++)\n\t\t{\n\t\t\tbool nxt=false;\n\t\t\tfor(int i:can)for(int j:can)if(dp[k][i][j]<(int)1e9)\n\t\t\t{\n\t\t\t\tfor(int l:can)if(ok[i][j][l]&&ok[j][l][I])\n\t\t\t\t{\n\t\t\t\t\tdp[k+1][j][l]=min(dp[k+1][j][l],dp[k][i][j]+f[j][l]);\n\t\t\t\t\tnxt=true;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!nxt)break;\n\t\t}\n\t\tfor(int k=0;k<N;k++)\n\t\t{\n\t\t\tR[k]=1e9;\n\t\t\tRk[k].clear();\n\t\t}\n\t\tR[0]=dp[0][J][I];\n\t\tfor(int k=1;k<N;k++)\n\t\t{\n\t\t\tint u=-1,v;\n\t\t\tfor(int i=0;i<N;i++)for(int j:can)\n\t\t\t\tif(ok[i][j][I]&&dp[k][i][j]<(int)1e9&&dp[k][i][j]+f[j][I]<R[k])\n\t\t\t{\n\t\t\t\tR[k]=dp[k][i][j]+f[j][I];\n\t\t\t\tv=i;\n\t\t\t\tu=j;\n\t\t\t}\n\t\t\tif(u<0)continue;\n\t\t\tvector<int>now;\n\t\t\tnow.push_back(u);\n\t\t\tif(k>1)now.push_back(v);\n\t\t\tint nk=k-2;\n\t\t\twhile(nk>0)\n\t\t\t{\n\t\t\t\tint w=-1;\n\t\t\t\tfor(int i:can)if(ok[i][v][u]&&dp[nk+1][i][v]+f[v][u]==dp[nk+2][v][u])\n\t\t\t\t{\n\t\t\t\t\tw=i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tnow.push_back(w);\n\t\t\t\tu=v;\n\t\t\t\tv=w;\n\t\t\t\tnk--;\n\t\t\t}\n\t\t\tRk[k]=now;\n\t\t}\n\t\tfor(int k=0;k<N;k++)if(L[k]<(int)1e9)for(int l=0;l<N;l++)if(R[l]<(int)1e9&&k+l+2<=N)\n\t\t{\n\t\t\tif(ans[k+l+2]>L[k]+R[l])\n\t\t\t{\n\t\t\t\tans[k+l+2]=L[k]+R[l];\n\t\t\t\tvector<int>now;\n\t\t\t\tnow.push_back(I);\n\t\t\t\tfor(int i=Lk[k].size();i--;)now.push_back(Lk[k][i]);\n\t\t\t\tnow.push_back(J);\n\t\t\t\tfor(int i=Rk[l].size();i--;)now.push_back(Rk[l][i]);\n\t\t\t\tvs[k+l+2]=now;\n\t\t\t}\n\t\t}\n\t}\n\tint Q;cin>>Q;\n\tfor(;Q--;)\n\t{\n\t\tint k;cin>>k;\n\t\tif(ans[k]<(int)1e9)\n\t\t{\n\t\t\tint id=0;\n\t\t\tfor(int i=1;i<k;i++)\n\t\t\t\tif(p[vs[k][i]].second<p[vs[k][id]].second\n\t\t\t\t\t||p[vs[k][i]].second==p[vs[k][id]].second\n\t\t\t\t\t&&p[vs[k][i]].first<p[vs[k][id]].first)id=i;\n\t\t\tfor(int i=0;i<k;i++)cout<<vs[k][(i+id)%k]+1<<(i+1==k?\"\\n\":\" \");\n\t\t}\n\t\telse cout<<\"NA\"<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3500, "score_of_the_acc": -0.0946, "final_rank": 2 }, { "submission_id": "aoj_0284_4862351", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 45\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\t/*bool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}*/\n\n\tbool operator<(const Point &p) const{\n\t\tif(Y != p.Y){\n\n\t\t\treturn Y < p.Y;\n\t\t}else{\n\n\t\t\treturn X < p.X;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n\tint X,Y,index;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\nstruct Info{\n\tInfo(int arg_index,double arg_rad){\n\t\tindex = arg_index;\n\t\trad = arg_rad;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn rad < arg.rad;\n\t}\n\tint index;\n\tdouble rad;\n};\n\n\nint N;\nPoint input[SIZE],P[SIZE];\ndouble NUM = 20000;\ndouble work[SIZE][SIZE][SIZE];\ndouble min_S[SIZE];\nint TMP[SIZE][SIZE][SIZE][SIZE];\nint ans[SIZE][SIZE];\n\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\n\ndouble calc_S(Polygon g){\n\n\tint N = g.size();\n\tdouble ret = 0;\n\n\tfor(int i = 0; i < g.size(); i++){\n\t\tret += cross(g[i],g[(i+1)%N]);\n\t}\n\treturn ret/2.0;\n}\n\n\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\nint main(){\n\n\tscanf(\"%d\",&N);\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d %d\",&input[i].X,&input[i].Y);\n\t\tinput[i].x = input[i].X;\n\t\tinput[i].y = input[i].Y;\n\t\tinput[i].index = i;\n\t\tP[i] = input[i];\n\t}\n\n\tsort(P,P+N);\n\n\t//全体最小値\n\tfor(int i = 0; i <= N; i++){\n\n\t\tmin_S[i] = BIG_NUM;\n\t}\n\n\tvector<Info> info;\n\n\tfor(int base = 0; base <= N-3; base++){\n\n\t\tfor(int i = 3; i <= N; i++){\n\t\t\tfor(int pre = 0; pre < N; pre++){\n\t\t\t\tfor(int t = 0; t < N; t++){\n\n\t\t\t\t\twork[i][pre][t] = BIG_NUM;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tinfo.clear();\n\n\t\tfor(int i = base+1; i < N; i++){\n\n\t\t\tdouble tmp_rad;\n\n\t\t\ttmp_rad = calc_rad(P[i]-P[base]);\n\n\t\t\tinfo.push_back(Info(P[i].index,tmp_rad));\n\t\t}\n\n\t\tsort(info.begin(),info.end());\n\n\t\t//三角形の面積\n\t\tfor(int i = 0; i < info.size()-1; i++){\n\t\t\tint head = info[i].index;\n\t\t\tfor(int k = i+1; k < info.size(); k++){\n\t\t\t\tint tail = info[k].index;\n\n\t\t\t\tPolygon poly;\n\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\tpoly.push_back(input[head]);\n\t\t\t\tpoly.push_back(input[tail]);\n\n\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\t\t\t\twork[3][head][tail] = tmp_S;\n\t\t\t\tTMP[3][head][tail][0] = P[base].index;\n\t\t\t\tTMP[3][head][tail][1] = head;\n\t\t\t\tTMP[3][head][tail][2] = tail;\n\t\t\t}\n\t\t}\n\n\t\tfor(int num = 4; num <= N; num++){\n\t\t\tfor(int i = 0; i < info.size()-2; i++){\n\t\t\t\tint pre = info[i].index;\n\t\t\t\tfor(int k = i+1; k < info.size()-1; k++){\n\t\t\t\t\tint t = info[k].index;\n\t\t\t\t\tif(fabs(work[num-1][pre][t]-BIG_NUM) < EPS)continue;\n\n\t\t\t\t\tfor(int a = k+1; a < info.size(); a++){\n\t\t\t\t\t\tint next = info[a].index;\n\n\t\t\t\t\t\tif(ccw(input[t],input[next],input[pre]) == COUNTER_CLOCKWISE){\n\n\t\t\t\t\t\t\tPolygon poly;\n\t\t\t\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\t\t\t\tpoly.push_back(input[t]);\n\t\t\t\t\t\t\tpoly.push_back(input[next]);\n\n\t\t\t\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\n\t\t\t\t\t\t\tif(work[num][t][next] > work[num-1][pre][t]+tmp_S+EPS){\n\n\t\t\t\t\t\t\t\twork[num][t][next] = work[num-1][pre][t]+tmp_S;\n\t\t\t\t\t\t\t\tfor(int b = 0; b < num-1; b++){\n\n\t\t\t\t\t\t\t\t\tTMP[num][t][next][b] = TMP[num-1][pre][t][b];\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tTMP[num][t][next][num-1] = next;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t}\n\t\t}\n\n\t\t//全体のdpテーブルと比較\n\t\tfor(int num = 3; num <= N; num++){\n\t\t\tfor(int pre = 0; pre < N; pre++){\n\t\t\t\tfor(int t = 0; t < N; t++){\n\t\t\t\t\tif(fabs(work[num][pre][t]-BIG_NUM) < EPS)continue;\n\n\t\t\t\t\tif(min_S[num] > work[num][pre][t]+EPS){\n\n\t\t\t\t\t\tmin_S[num] = work[num][pre][t];\n\t\t\t\t\t\tfor(int a = 0; a < num; a++){\n\n\t\t\t\t\t\t\tans[num][a] = TMP[num][pre][t][a];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint num_P;\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&num_P);\n\n\t\tif(fabs(min_S[num_P]-BIG_NUM) < EPS){\n\n\t\t\tprintf(\"NA\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\tprintf(\"%d\",ans[num_P][0]+1);\n\t\tfor(int i = 1; i < num_P; i++){\n\n\t\t\tprintf(\" %d\",ans[num_P][i]+1);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6768, "score_of_the_acc": -0.0538, "final_rank": 1 }, { "submission_id": "aoj_0284_4862228", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 45\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\t/*bool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}*/\n\n\tbool operator<(const Point &p) const{\n\t\tif(Y != p.Y){\n\n\t\t\treturn Y < p.Y;\n\t\t}else{\n\n\t\t\treturn X < p.X;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n\tint X,Y,index;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\nstruct Info{\n\tInfo(int arg_index,double arg_rad){\n\t\tindex = arg_index;\n\t\trad = arg_rad;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn rad < arg.rad;\n\t}\n\tint index;\n\tdouble rad;\n};\n\n\nint N;\nPoint input[SIZE],P[SIZE];\ndouble NUM = 20000;\ndouble dp[SIZE][SIZE][SIZE];\ndouble work[SIZE][SIZE][SIZE];\ndouble min_S[SIZE];\nint TMP[SIZE][SIZE][SIZE][SIZE];\nint table[SIZE][SIZE][SIZE][SIZE];\nint ans[SIZE][SIZE];\n\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\n\ndouble calc_S(Polygon g){\n\n\tint N = g.size();\n\tdouble ret = 0;\n\n\tfor(int i = 0; i < g.size(); i++){\n\t\tret += cross(g[i],g[(i+1)%N]);\n\t}\n\treturn ret/2.0;\n}\n\n\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\nint main(){\n\n\tscanf(\"%d\",&N);\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d %d\",&input[i].X,&input[i].Y);\n\t\tinput[i].x = input[i].X;\n\t\tinput[i].y = input[i].Y;\n\t\tinput[i].index = i;\n\t\tP[i] = input[i];\n\t}\n\n\tsort(P,P+N);\n\n\tfor(int i = 0; i <= N; i++){\n\t\tfor(int s = 0; s <= N; s++){\n\t\t\tfor(int t = 0; t <= N; t++){\n\n\t\t\t\tdp[i][s][t] = BIG_NUM;\n\t\t\t}\n\t\t}\n\t}\n\n\t//全体最小値\n\tfor(int i = 0; i <= N; i++){\n\n\t\tmin_S[i] = BIG_NUM;\n\t}\n\n\tvector<Info> info;\n\n\tfor(int base = 0; base <= N-3; base++){\n\t//for(int base = 6; base <= 6; base++){\n\n\t\t//P[base].debug();\n\n\t\tfor(int i = 0; i <= N; i++){\n\t\t\tfor(int s = 0; s <= N; s++){\n\t\t\t\tfor(int t = 0; t <= N; t++){\n\n\t\t\t\t\twork[i][s][t] = BIG_NUM;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tinfo.clear();\n\n\t\tfor(int i = base+1; i < N; i++){\n\n\t\t\tdouble tmp_rad;\n\n\t\t\ttmp_rad = calc_rad(P[i]-P[base]);\n\n\t\t\tinfo.push_back(Info(P[i].index,tmp_rad));\n\t\t}\n\n\t\tsort(info.begin(),info.end());\n\n\t\t//三角形の面積\n\t\tfor(int i = 0; i < info.size()-1; i++){\n\t\t\tint head = info[i].index;\n\t\t\tfor(int k = i+1; k < info.size(); k++){\n\t\t\t\tint tail = info[k].index;\n\n\t\t\t\tPolygon poly;\n\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\tpoly.push_back(input[head]);\n\t\t\t\tpoly.push_back(input[tail]);\n\n\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\t\t\t\twork[3][head][tail] = tmp_S;\n\t\t\t\tTMP[3][head][tail][0] = P[base].index;\n\t\t\t\tTMP[3][head][tail][1] = head;\n\t\t\t\tTMP[3][head][tail][2] = tail;\n\t\t\t}\n\t\t}\n\n\t\tfor(int num = 4; num <= N; num++){\n\t\t\tfor(int i = 0; i < info.size()-2; i++){\n\t\t\t\tint s = info[i].index;\n\t\t\t\tfor(int k = i+1; k < info.size()-1; k++){\n\t\t\t\t\tint t = info[k].index;\n\t\t\t\t\tif(fabs(work[num-1][s][t]-BIG_NUM) < EPS)continue;\n\n\t\t\t\t\tfor(int a = k+1; a < info.size(); a++){\n\t\t\t\t\t\tint next = info[a].index;\n\n\t\t\t\t\t\tint t_pre = TMP[num-1][s][t][num-3];\n\n\t\t\t\t\t\tif(ccw(input[t],input[next],input[t_pre]) == COUNTER_CLOCKWISE){\n\n\t\t\t\t\t\t\tPolygon poly;\n\t\t\t\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\t\t\t\tpoly.push_back(input[t]);\n\t\t\t\t\t\t\tpoly.push_back(input[next]);\n\n\t\t\t\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\n\t\t\t\t\t\t\tif(work[num][s][next] > work[num-1][s][t]+tmp_S+EPS){\n\t\t\t\t\t\t\t\twork[num][s][next] = work[num-1][s][t]+tmp_S;\n\t\t\t\t\t\t\t\tfor(int b = 0; b < num-1; b++){\n\n\t\t\t\t\t\t\t\t\tTMP[num][s][next][b] = TMP[num-1][s][t][b];\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tTMP[num][s][next][num-1] = next;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t//全体のdpテーブルと比較\n\t\tfor(int num = 3; num <= N; num++){\n\t\t\tfor(int s = 0; s < N; s++){\n\t\t\t\tfor(int t = 0; t < N; t++){\n\t\t\t\t\tif(fabs(work[num][s][t]-BIG_NUM) < EPS)continue;\n\n\t\t\t\t\tif(min_S[num] > work[num][s][t]+EPS){\n\n\t\t\t\t\t\tmin_S[num] = work[num][s][t];\n\t\t\t\t\t\tfor(int a = 0; a < num; a++){\n\n\n\t\t\t\t\t\t\tans[num][a] = TMP[num][s][t][a];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint num_P;\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&num_P);\n\n\t\tif(fabs(min_S[num_P]-BIG_NUM) < EPS){\n\n\t\t\tprintf(\"NA\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//printf(\"min_S:%.3lf\\n\",min_S[num_P]);\n\n\t\tprintf(\"%d\",ans[num_P][0]+1);\n\t\tfor(int i = 1; i < num_P; i++){\n\n\t\t\tprintf(\" %d\",ans[num_P][i]+1);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\treturn 0;\n}", "accuracy": 0.7777777777777778, "time_ms": 20, "memory_kb": 7588, "score_of_the_acc": -0.047, "final_rank": 13 }, { "submission_id": "aoj_0284_4862100", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 45\n\nstruct Point{\n\tPoint(double arg_x,double arg_y){\n\t\tx = arg_x;\n\t\ty = arg_y;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint(){\n\t\tx = y = 0.0;\n\t\tX = Y = 0;\n\t\tindex = 0;\n\t}\n\n\tPoint operator + (Point p){ return Point(x+p.x,y+p.y); }\n\tPoint operator - (Point p){ return Point(x-p.x,y-p.y);}\n\tPoint operator * (double a){ return Point(a*x,a*y); }\n\tPoint operator / (double a){ return Point(x/a,y/a); }\n\n\tdouble abs(){ return sqrt(norm()); }\n\tdouble norm(){ return x*x + y*y; }\n\n\t/*bool operator<(const Point &p) const{\n\t\treturn x != p.x? x < p.x: y < p.y;\n\t}*/\n\n\tbool operator<(const Point &p) const{\n\t\tif(Y != p.Y){\n\n\t\t\treturn Y < p.Y;\n\t\t}else{\n\n\t\t\treturn X < p.X;\n\t\t}\n\t}\n\n\tbool operator == (const Point &p) const{\n\t\treturn fabs(x-p.x) < EPS && fabs(y-p.y) < EPS;\n\t}\n\n\n\tvoid debug(){\n\n\t\tprintf(\"(%.3lf,%.3lf)\\n\",x,y);\n\t}\n\n\tdouble x,y;\n\tint X,Y,index;\n};\n\ntypedef Point Vector;\ntypedef vector<Point> Polygon;\n\nstruct Line{\n\tLine(){\n\n\t}\n\tLine(Point a,Point b){\n\t\tp[0] = a;\n\t\tp[1] = b;\n\t}\n\t/*void outPut(){\n\n\t\tprintf(\"(%.3lf,%.3lf)-(%.3lf,%.3lf)\\n\",p[0].x,p[0].y,p[1].x,p[1].y);\n\t}*/\n\tPoint p[2];\n};\n\nstruct Info{\n\tInfo(int arg_index,double arg_rad){\n\t\tindex = arg_index;\n\t\trad = arg_rad;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn rad < arg.rad;\n\t}\n\tint index;\n\tdouble rad;\n};\n\n\nint N;\nPoint input[SIZE],P[SIZE];\ndouble NUM = 20000;\ndouble dp[SIZE][SIZE][SIZE];\ndouble work[SIZE][SIZE][SIZE];\ndouble min_S[SIZE];\nint TMP[SIZE][SIZE][SIZE][SIZE];\nint table[SIZE][SIZE][SIZE][SIZE];\nint ans[SIZE][SIZE];\nbool check[SIZE];\n\n\n\ndouble calc_dist(Point A,Point B){\n\n\treturn sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));\n}\n\ndouble norm(Vector a){\n\treturn a.x*a.x+a.y*a.y;\n}\n\ndouble abs(Vector a){\n\treturn sqrt(norm(a));\n}\n\ndouble cross(Vector a,Vector b){\n return a.x*b.y-a.y*b.x;\n}\n\ndouble dot(Vector a,Vector b){\n return a.x*b.x + a.y*b.y;\n}\n\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n\nint ccw(Point p0,Point p1,Point p2){\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n\tif(cross(a,b) < -EPS)return CLOCKWISE;\n\tif(dot(a,b) < -EPS)return ONLINE_BACK;\n\tif(a.norm() < b.norm())return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\n\n\ndouble calc_S(Polygon g){\n\n\tint N = g.size();\n\tdouble ret = 0;\n\n\tfor(int i = 0; i < g.size(); i++){\n\t\tret += cross(g[i],g[(i+1)%N]);\n\t}\n\treturn ret/2.0;\n}\n\n\ndouble calc_rad(Point p){\n\n\tif(p.y == 0){\n\n\t\tif(p.x > 0){\n\n\t\t\treturn 0;\n\n\t\t}else{ //p.x < 0\n\n\t\t\treturn M_PI;\n\t\t}\n\n\t}else if(p.x == 0){\n\n\t\tif(p.y > 0){\n\n\t\t\treturn M_PI/2.0;\n\t\t}else{\n\n\n\t\t\treturn 3*M_PI/2.0;\n\t\t}\n\n\t}else{\n\n\t\tdouble base = atan(fabs(p.y)/fabs(p.x));\n\n\t\tif(p.x > 0){\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn base;\n\n\t\t\t}else{ //p.y < 0\n\n\t\t\t\treturn 2*M_PI-base;\n\t\t\t}\n\n\t\t}else{ //p.x < 0\n\n\t\t\tif(p.y > 0){\n\n\t\t\t\treturn M_PI-base;\n\n\t\t\t}else{\n\n\t\t\t\treturn base+M_PI;\n\t\t\t}\n\t\t}\n\t}\n}\nint main(){\n\n\tscanf(\"%d\",&N);\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d %d\",&input[i].X,&input[i].Y);\n\t\tinput[i].x = input[i].X;\n\t\tinput[i].y = input[i].Y;\n\t\tinput[i].index = i;\n\t\tP[i] = input[i];\n\t}\n\n\tsort(P,P+N);\n\n\tfor(int i = 0; i <= N; i++){\n\t\tfor(int s = 0; s <= N; s++){\n\t\t\tfor(int t = 0; t <= N; t++){\n\n\t\t\t\tdp[i][s][t] = BIG_NUM;\n\t\t\t}\n\t\t}\n\t}\n\n\t//全体最小値\n\tfor(int i = 0; i <= N; i++){\n\n\t\tmin_S[i] = BIG_NUM;\n\t}\n\n\tvector<Info> info;\n\n\tfor(int base = 0; base <= N-3; base++){\n\n\t\t//P[base].debug();\n\n\t\tfor(int i = 0; i <= N; i++){\n\t\t\tfor(int s = 0; s <= N; s++){\n\t\t\t\tfor(int t = 0; t <= N; t++){\n\n\t\t\t\t\twork[i][s][t] = BIG_NUM;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tinfo.clear();\n\n\t\tPoint C = Point(P[base].x+NUM,P[base].y); //rad計算用\n\n\t\tfor(int i = base+1; i < N; i++){\n\n\t\t\tdouble tmp_rad;\n\n\t\t\ttmp_rad = calc_rad(P[i]-P[base]);\n\n\t\t\tinfo.push_back(Info(P[i].index,tmp_rad));\n\t\t}\n\n\t\tsort(info.begin(),info.end());\n\n\t\t//三角形の面積\n\t\tfor(int i = 0; i < info.size()-1; i++){\n\t\t\tint head = info[i].index;\n\t\t\tfor(int k = i+1; k < info.size(); k++){\n\t\t\t\tint tail = info[k].index;\n\n\t\t\t\tPolygon poly;\n\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\tpoly.push_back(input[head]);\n\t\t\t\tpoly.push_back(input[tail]);\n\n\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\t\t\t\twork[3][head][tail] = tmp_S;\n\t\t\t\tTMP[3][head][tail][0] = P[base].index;\n\t\t\t\tTMP[3][head][tail][1] = head;\n\t\t\t\tTMP[3][head][tail][2] = tail;\n\t\t\t}\n\t\t}\n\n\t\tfor(int num = 4; num <= N; num++){\n\t\t\tfor(int s = 0; s < N; s++){\n\t\t\t\tfor(int t = 0; t < N; t++){\n\n\t\t\t\t\tif(fabs(work[num-1][s][t]-BIG_NUM) < EPS)continue;\n\t\t\t\t\tfor(int a = 0; a < N; a++){\n\n\t\t\t\t\t\tcheck[a] = false;\n\t\t\t\t\t}\n\t\t\t\t\tfor(int a = 0; a < num-1; a++){\n\n\t\t\t\t\t\tcheck[TMP[num-1][s][t][a]] = true;\n\t\t\t\t\t}\n\t\t\t\t\tfor(int a = base+1; a < N; a++){\n\t\t\t\t\t\tint next = P[a].index;\n\t\t\t\t\t\tif(check[next])continue;\n\n\t\t\t\t\t\tint t_pre = TMP[num-1][s][t][num-3];\n\n\t\t\t\t\t\tif(ccw(input[t],input[next],input[t_pre]) == COUNTER_CLOCKWISE &&\n\t\t\t\t\t\t\t\tccw(input[t],input[next],P[base]) == COUNTER_CLOCKWISE){\n\n\t\t\t\t\t\t\tPolygon poly;\n\t\t\t\t\t\t\tpoly.push_back(P[base]);\n\t\t\t\t\t\t\tpoly.push_back(input[t]);\n\t\t\t\t\t\t\tpoly.push_back(input[next]);\n\n\t\t\t\t\t\t\tdouble tmp_S = calc_S(poly);\n\n\t\t\t\t\t\t\tif(work[num][s][next] > work[num-1][s][t]+tmp_S+EPS){\n\t\t\t\t\t\t\t\twork[num][s][next] = work[num-1][s][t]+tmp_S;\n\t\t\t\t\t\t\t\tfor(int a = 0; a < num-1; a++){\n\n\t\t\t\t\t\t\t\t\tTMP[num][s][next][a] = TMP[num-1][s][t][a];\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tTMP[num][s][next][num-1] = next;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t//全体のdpテーブルと比較\n\t\tfor(int num = 3; num <= N; num++){\n\t\t\tfor(int s = 0; s < N; s++){\n\t\t\t\tfor(int t = 0; t < N; t++){\n\t\t\t\t\tif(fabs(work[num][s][t]-BIG_NUM) < EPS)continue;\n\n\t\t\t\t\tif(min_S[num] > work[num][s][t]+EPS){\n\n\t\t\t\t\t\tmin_S[num] = work[num][s][t];\n\t\t\t\t\t\tfor(int a = 0; a < num; a++){\n\n\t\t\t\t\t\t\tans[num][a] = TMP[num][s][t][a];\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint num_P;\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&num_P);\n\n\t\tif(fabs(min_S[num_P]-BIG_NUM) < EPS){\n\n\t\t\tprintf(\"NA\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//printf(\"min_S:%.3lf\\n\",min_S[num_P]);\n\n\t\tprintf(\"%d\",ans[num_P][0]+1);\n\t\tfor(int i = 1; i < num_P; i++){\n\n\t\t\tprintf(\" %d\",ans[num_P][i]+1);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\n\treturn 0;\n}", "accuracy": 0.7777777777777778, "time_ms": 30, "memory_kb": 7456, "score_of_the_acc": -0.0595, "final_rank": 14 }, { "submission_id": "aoj_0284_4830062", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <tuple>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstruct Point {\n\tlong long px, py;\n};\n\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.px < a2.px) return true;\n\tif (a1.px > a2.px) return false;\n\tif (a1.py < a2.py) return true;\n\treturn false;\n}\n\nPoint operator-(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px - a2.px, a1.py - a2.py };\n}\n\nbool ccw(Point a1, Point a2, Point a3) {\n\tPoint v1 = a2 - a1;\n\tPoint v2 = a3 - a1;\n\tlong long eval = v1.px * v2.py - v1.py * v2.px;\n\tif (eval > 0) return true;\n\treturn false;\n}\n\n// 入力\nint N;\nPoint G[44];\n\n// 前準備\ndouble dist[44][44];\nbool flag[44][44][44];\n\n// 動的計画法\nint pres1[44][44][44];\nint pres2[44][44][44];\ndouble dp1[44][44][44];\ndouble dp2[44][44][44];\n\n// 答え\ndouble MinValue[44];\nvector<int> Answer[44];\n\nvoid init() {\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tif (i == j) dist[i][j] = 1e9;\n\t\t\telse {\n\t\t\t\tdist[i][j] = (G[i].px - G[j].px) * (G[i].py + G[j].py);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\tif (i == j || j == k || k == i) continue;\n\t\t\t\tflag[i][j][k] = ccw(G[i], G[j], G[k]);\n\t\t\t}\n\t\t}\n\t}\n}\n\nvector<int> fukugen1(int v1, int v2, int v3) {\n\tvector<int> vec;\n\tint cx1 = v2, cx2 = v3;\n\tvec.push_back(cx2);\n\tvec.push_back(cx1);\n\tfor (int u = v1; u >= 2; u--) {\n\t\tint nex = pres1[u][cx1][cx2];\n\t\tvec.push_back(nex);\n\t\tcx2 = cx1;\n\t\tcx1 = nex;\n\t}\n\treturn vec;\n}\n\nvector<int> fukugen2(int v1, int v2, int v3) {\n\tvector<int> vec;\n\tint cx1 = v2, cx2 = v3;\n\tvec.push_back(cx2);\n\tvec.push_back(cx1);\n\tfor (int u = v1; u >= 2; u--) {\n\t\tint nex = pres2[u][cx1][cx2];\n\t\tvec.push_back(nex);\n\t\tcx2 = cx1;\n\t\tcx1 = nex;\n\t}\n\treturn vec;\n}\n\nvoid solve(int stt) {\n\tfor (int t = 0; t <= N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) dp1[t][i][j] = 1e9;\n\t\t\tfor (int j = 0; j < N; j++) dp2[t][i][j] = 1e9;\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) { if (G[stt] < G[i]) dp1[1][stt][i] = dist[stt][i]; }\n\tfor (int i = 0; i < N; i++) { if (G[stt] < G[i]) dp2[1][stt][i] = -dist[stt][i]; }\n\t\n\t// DP の遷移\n\tfor (int t = 0; t < N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\tif (dp1[t][i][j] > 8e8) continue;\n\t\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\t\tif (flag[i][j][k] == false || !(G[j] < G[k])) continue;\n\t\t\t\t\tdouble cost = dp1[t][i][j] + dist[j][k];\n\t\t\t\t\tif (dp1[t + 1][j][k] > cost) {\n\t\t\t\t\t\tdp1[t + 1][j][k] = cost;\n\t\t\t\t\t\tpres1[t + 1][j][k] = i;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (int t = 0; t < N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\tif (dp2[t][i][j] > 8e8) continue;\n\t\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\t\tif (flag[i][j][k] == true || !(G[j] < G[k])) continue;\n\t\t\t\t\tdouble cost = dp2[t][i][j] - dist[j][k];\n\t\t\t\t\tif (dp2[t + 1][j][k] > cost) {\n\t\t\t\t\t\tdp2[t + 1][j][k] = cost;\n\t\t\t\t\t\tpres2[t + 1][j][k] = i;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// DP の復元\n\tfor (int t = 1; t <= N; t++) {\n\t\tfor (int u = 1; u <= N - t; u++) {\n\t\t\tfor (int i = 0; i < N; i++) {\n\t\t\t\tpair<double, int> cost1 = make_pair(1e9, -1);\n\t\t\t\tpair<double, int> cost2 = make_pair(1e9, -1);\n\t\t\t\tfor (int k = 0; k < N; k++) cost1 = min(cost1, make_pair(dp1[t][k][i], k));\n\t\t\t\tfor (int k = 0; k < N; k++) cost2 = min(cost2, make_pair(dp2[u][k][i], k));\n\t\t\t\tif (cost1.second == -1 || cost2.second == -1) continue;\n\t\t\t\tdouble TotalCost = cost1.first + cost2.first;\n\t\t\t\tif (MinValue[t + u] > TotalCost) {\n\t\t\t\t\tMinValue[t + u] = TotalCost;\n\t\t\t\t\tvector<int> v1 = fukugen1(t, cost1.second, i); reverse(v1.begin(), v1.end());\n\t\t\t\t\tvector<int> v2 = fukugen2(u, cost2.second, i); reverse(v2.begin(), v2.end());\n\t\t\t\t\tvector<int> v = v1;\n\t\t\t\t\tfor (int j = (int)v2.size() - 2; j >= 1; j--) v.push_back(v2[j]);\n\t\t\t\t\tAnswer[t + u] = v;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\t// 入力\n\tcin >> N;\n\tfor (int i = 0; i < N; i++) cin >> G[i].px >> G[i].py;\n\n\t// 計算\n\tinit();\n\tfor (int i = 3; i <= N; i++) MinValue[i] = 1e9;\n\tfor (int i = 0; i < N; i++) {\n\t\tsolve(i);\n\t}\n\n\t// 出力\n\tint Q; cin >> Q;\n\tfor (int i = 1; i <= Q; i++) {\n\t\tint K; cin >> K;\n\t\tif (MinValue[K] >= 8e8) cout << \"NA\" << endl;\n\t\telse {\n\t\t\ttuple<long long, long long, int> minp = make_tuple(1 << 30, 1 << 30, -1);\n\t\t\tfor (int j = 0; j < Answer[K].size(); j++) {\n\t\t\t\tminp = min(minp, make_tuple(G[Answer[K][j]].py, G[Answer[K][j]].px, j));\n\t\t\t}\n\t\t\tfor (int j = 0; j < Answer[K].size(); j++) {\n\t\t\t\tif (j) cout << \" \";\n\t\t\t\tcout << Answer[K][(j + get<2>(minp)) % Answer[K].size()] + 1;\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 4876, "score_of_the_acc": -0.1599, "final_rank": 3 }, { "submission_id": "aoj_0284_4830055", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <tuple>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstruct Point {\n\tlong long px, py;\n};\n\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.px < a2.px) return true;\n\tif (a1.px > a2.px) return false;\n\tif (a1.py < a2.py) return true;\n\treturn false;\n}\n\nPoint operator-(const Point& a1, const Point& a2) {\n\treturn Point{ a1.px - a2.px, a1.py - a2.py };\n}\n\nbool ccw(Point a1, Point a2, Point a3) {\n\tPoint v1 = a2 - a1;\n\tPoint v2 = a3 - a1;\n\tlong long eval = v1.px * v2.py - v1.py * v2.px;\n\tif (eval > 0) return true;\n\treturn false;\n}\n\n// 入力\nint N;\nPoint G[44];\n\n// 前準備\ndouble dist[44][44];\nbool flag[44][44][44];\n\n// 動的計画法\nint pres1[44][44][44];\nint pres2[44][44][44];\ndouble dp1[44][44][44];\ndouble dp2[44][44][44];\n\n// 答え\ndouble MinValue[44];\nvector<int> Answer[44];\n\nvoid init() {\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tif (i == j) dist[i][j] = 1e9;\n\t\t\telse {\n\t\t\t\tdist[i][j] = (G[i].px - G[j].px) * (G[i].py + G[j].py);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\tif (i == j || j == k || k == i) continue;\n\t\t\t\tflag[i][j][k] = ccw(G[i], G[j], G[k]);\n\t\t\t}\n\t\t}\n\t}\n}\n\nvector<int> fukugen1(int v1, int v2, int v3) {\n\tvector<int> vec;\n\tint cx1 = v2, cx2 = v3;\n\tvec.push_back(cx2);\n\tvec.push_back(cx1);\n\tfor (int u = v1; u >= 2; u--) {\n\t\tint nex = pres1[u][cx1][cx2];\n\t\tvec.push_back(nex);\n\t\tcx2 = cx1;\n\t\tcx1 = nex;\n\t}\n\treturn vec;\n}\n\nvector<int> fukugen2(int v1, int v2, int v3) {\n\tvector<int> vec;\n\tint cx1 = v2, cx2 = v3;\n\tvec.push_back(cx2);\n\tvec.push_back(cx1);\n\tfor (int u = v1; u >= 2; u--) {\n\t\tint nex = pres2[u][cx1][cx2];\n\t\tvec.push_back(nex);\n\t\tcx2 = cx1;\n\t\tcx1 = nex;\n\t}\n\treturn vec;\n}\n\nvoid solve(int stt) {\n\tfor (int t = 0; t <= N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) dp1[t][i][j] = 1e9;\n\t\t\tfor (int j = 0; j < N; j++) dp2[t][i][j] = 1e9;\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) { if (G[stt] < G[i]) dp1[1][stt][i] = dist[stt][i]; }\n\tfor (int i = 0; i < N; i++) { if (G[stt] < G[i]) dp2[1][stt][i] = -dist[stt][i]; }\n\t\n\t// DP の遷移\n\tfor (int t = 0; t < N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\tif (dp1[t][i][j] > 8e8) continue;\n\t\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\t\tif (flag[i][j][k] == false || !(G[j] < G[k])) continue;\n\t\t\t\t\tdouble cost = dp1[t][i][j] + dist[j][k];\n\t\t\t\t\tif (dp1[t + 1][j][k] > cost) {\n\t\t\t\t\t\tdp1[t + 1][j][k] = cost;\n\t\t\t\t\t\tpres1[t + 1][j][k] = i;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (int t = 0; t < N; t++) {\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tfor (int j = 0; j < N; j++) {\n\t\t\t\tif (dp2[t][i][j] > 8e8) continue;\n\t\t\t\tfor (int k = 0; k < N; k++) {\n\t\t\t\t\tif (flag[i][j][k] == true || !(G[j] < G[k])) continue;\n\t\t\t\t\tdouble cost = dp2[t][i][j] - dist[j][k];\n\t\t\t\t\tif (dp2[t + 1][j][k] > cost) {\n\t\t\t\t\t\tdp2[t + 1][j][k] = cost;\n\t\t\t\t\t\tpres2[t + 1][j][k] = i;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t// DP の復元\n\tfor (int t = 1; t <= N; t++) {\n\t\tfor (int u = 1; u <= N - t; u++) {\n\t\t\tfor (int i = 0; i < N; i++) {\n\t\t\t\tpair<double, int> cost1 = make_pair(1e9, -1);\n\t\t\t\tpair<double, int> cost2 = make_pair(1e9, -1);\n\t\t\t\tfor (int k = 0; k < N; k++) cost1 = min(cost1, make_pair(dp1[t][k][i], k));\n\t\t\t\tfor (int k = 0; k < N; k++) cost2 = min(cost2, make_pair(dp2[u][k][i], k));\n\t\t\t\tdouble TotalCost = cost1.first + cost2.first;\n\t\t\t\tif (MinValue[t + u] > TotalCost) {\n\t\t\t\t\tMinValue[t + u] = TotalCost;\n\t\t\t\t\tvector<int> v1 = fukugen1(t, cost1.second, i); reverse(v1.begin(), v1.end());\n\t\t\t\t\tvector<int> v2 = fukugen2(u, cost2.second, i); reverse(v2.begin(), v2.end());\n\t\t\t\t\tvector<int> v = v1;\n\t\t\t\t\tfor (int j = (int)v2.size() - 2; j >= 1; j--) v.push_back(v2[j]);\n\t\t\t\t\tAnswer[t + u] = v;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\t// 入力\n\tcin >> N;\n\tfor (int i = 0; i < N; i++) cin >> G[i].px >> G[i].py;\n\n\t// 計算\n\tinit();\n\tfor (int i = 3; i <= N; i++) MinValue[i] = 1e9;\n\tfor (int i = 0; i < N; i++) {\n\t\tsolve(i);\n\t}\n\n\t// 出力\n\tint Q; cin >> Q;\n\tfor (int i = 1; i <= Q; i++) {\n\t\tint K; cin >> K;\n\t\tif (MinValue[K] >= 8e8) cout << \"NA\" << endl;\n\t\telse {\n\t\t\ttuple<long long, long long, int> minp = make_tuple(1 << 30, 1 << 30, -1);\n\t\t\tfor (int j = 0; j < Answer[K].size(); j++) {\n\t\t\t\tminp = min(minp, make_tuple(G[Answer[K][j]].py, G[Answer[K][j]].px, j));\n\t\t\t}\n\t\t\tfor (int j = 0; j < Answer[K].size(); j++) {\n\t\t\t\tif (j) cout << \" \";\n\t\t\t\tcout << Answer[K][(j + get<2>(minp)) % Answer[K].size()] + 1;\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.6666666666666666, "time_ms": 20, "memory_kb": 4448, "score_of_the_acc": -0.0213, "final_rank": 16 }, { "submission_id": "aoj_0284_4395877", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nusing real = int;\nstruct Point {\n real x, y;\n Point& operator+=(const Point a) { x += a.x; y += a.y; return *this; }\n Point& operator-=(const Point a) { x -= a.x; y -= a.y; return *this; }\n Point& operator*=(const real k) { x *= k; y *= k; return *this; }\n Point& operator/=(const real k) { x /= k; y /= k; return *this; }\n Point operator+(const Point a) const {return Point(*this) += a; }\n Point operator-(const Point a) const {return Point(*this) -= a; }\n Point operator*(const real k) const {return Point(*this) *= k; }\n Point operator/(const real k) const {return Point(*this) /= k; }\n bool operator<(const Point &a) const { return (x != a.x ? x < a.x : y < a.y); }\n explicit Point(real a = 0, real b = 0) : x(a), y(b) {};\n};\n\nistream& operator>> (istream& s, Point& P){\n s >> P.x >> P.y;\n return s;\n}\n\n\n\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\n\n\n\nint dp[41][40][40][40], prv[41][40][40][40];\n\nint main() {\n int n;\n cin >> n;\n vector<Point> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i];\n }\n auto area = [](Point a, Point b, Point c){ return (b.x-a.x)*(c.y-a.y)-(b.y-a.y)*(c.x-a.x); };\n auto to = make_v(n, n, vector<int>());\n fill_n((int*)dp, 41*40*40*40, INF<int>);\n fill_n((int*)prv, 41*40*40*40, 0);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n if(i == j) continue;\n if(v[i].y <= v[j].y) dp[2][i][i][j] = 0;\n for (int k = 0; k < n; ++k) {\n if(i == k || j == k) continue;\n if(area(v[i], v[j], v[k]) > 0 && (v[i].y <= v[j].y || v[j].y >= v[k].y)){\n to[i][j].emplace_back(k);\n }\n }\n }\n }\n for (int i = 2; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n for (int k = 0; k < n; ++k) {\n for (int l = 0; l < n; ++l) {\n if(dp[i][j][k][l] == INF<int>) continue;\n for (auto &&m : to[k][l]) {\n if(v[j].y > v[m].y || j == m) continue;\n int a = area(v[j], v[l], v[m]);\n\n if(a > 0 && dp[i+1][j][l][m] > dp[i][j][k][l]+a){\n dp[i+1][j][l][m] = dp[i][j][k][l]+a;\n prv[i+1][j][l][m] = k;\n }\n }\n }\n }\n }\n }\n vector<vector<int>> anss(n+1);\n for (int i = 3; i <= n; ++i) {\n int val = INF<int>, a = 0, b = 0, c = 0;\n for (int j = 0; j < n; ++j) {\n for (int k = 0; k < n; ++k) {\n for (int l = 0; l < n; ++l) {\n if(dp[i][j][k][l] < val){\n val = dp[i][j][k][l];\n a = j; b = k; c = l;\n }\n }\n }\n }\n if(val == INF<int>) {\n continue;\n }\n vector<int> ans{c, b};\n for (int j = i; j >= 3; --j) {\n int x = prv[j][a][b][c];\n ans.emplace_back(x);\n c = b; b = x;\n }\n reverse(ans.begin(),ans.end());\n if(v[ans.front()].y == v[ans.back()].y){\n rotate(ans.begin(), ans.end()-1, ans.end());\n }\n anss[i] = ans;\n }\n int q;\n cin >> q;\n while(q--){\n int x;\n cin >> x;\n if(anss[x].empty()) puts(\"NA\");\n else{\n for (int i = 0; i < anss[x].size(); ++i) {\n printf(i ? \" %d\" : \"%d\", anss[x][i]+1);\n }\n puts(\"\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 23784, "score_of_the_acc": -0.1663, "final_rank": 4 }, { "submission_id": "aoj_0284_3434355", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing i64 = int64_t;\n\nconst double EPS = 1e-8;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n\nusing Point = complex<double>;\nusing Polygon = vector<Point>;\n\ninline int sgn(const double &a) { return (a < -EPS ? -1 : (a > EPS ? 1 : 0)); }\n\ninline bool eq(const Point &a, const Point &b) { return abs(a - b) < EPS; }\n\nnamespace std {\ninline bool operator<(const Point &a, const Point &b) {\n if (sgn(a.imag() - b.imag()))\n return sgn(a.imag() - b.imag()) < 0;\n return sgn(a.real() - b.real()) < 0;\n}\n} // namespace std\n\ndouble dot(const Point &a, const Point &b) { return real(conj(a) * b); }\n\ndouble det(const Point &a, const Point &b) { return imag(conj(a) * b); }\n\nstruct Line {\n Point p1, p2;\n\n Line(Point p1 = Point(), Point p2 = Point()) : p1(p1), p2(p2) {}\n\n bool operator<(const Line &rhs) const {\n if (eq(p2, rhs.p2))\n return p1 < rhs.p1;\n return p2 < rhs.p2;\n }\n bool operator==(const Line &rhs) const {\n return (eq(p1, rhs.p1) && eq(p2, rhs.p2)) ||\n (eq(p1, rhs.p2) && eq(p2, rhs.p1));\n }\n};\n\ninline Point curr(const Polygon &p, const int &i) { return p[i % p.size()]; }\n\ninline Point next(const Polygon &p, const int &i) {\n return p[(i + 1) % p.size()];\n}\n\ninline Point prev(const Polygon &p, const int &i) {\n return p[(i + p.size() - 1) % p.size()];\n}\n\nenum CCW {\n ONLINE_FRONT = -2,\n CLOCKWISE,\n ON_SEGMENT,\n COUNTER_CLOCKWISE,\n ONLINE_BACK\n};\n\nint ccw(Point p0, Point p1, Point p2) {\n Point a = p1 - p0;\n Point b = p2 - p0;\n if (sgn(det(a, b)) == 1)\n return COUNTER_CLOCKWISE;\n if (sgn(det(a, b)) == -1)\n return CLOCKWISE;\n if (sgn(dot(a, b)) == -1)\n return ONLINE_BACK;\n if (sgn(norm(b) - norm(a)) == 1)\n return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\ndouble dp[42][42][42][42]={0};\nint prev_point[42][42][42][42]={0};\nbool exists[42]={0};\n\nint main(){\n int n;\n cin >> n;\n vector<pair<Point, int>> v;\n for(int i=0;i<n;++i){\n double x, y;\n cin >> x >> y;\n v.emplace_back(Point(x, y), i+1);\n }\n sort(v.begin(), v.end());\n vector<vector<int>> points_idx;\n for(int i=0;i<n;++i){\n points_idx.push_back(vector<int>());\n for(int j=i+1;j<n;++j){\n points_idx[i].push_back(j);\n }\n Point p = v[i].first;\n auto cmp = [p, v](int a, int b){\n double rad_a = atan2(v[a].first.imag() - p.imag(), v[a].first.real() - p.real());\n double rad_b = atan2(v[b].first.imag() - p.imag(), v[b].first.real() - p.real());\n return sgn(rad_a - rad_b) < 0;\n };\n sort(points_idx[i].begin(), points_idx[i].end(), cmp);\n }\n\n for(int i=0;i<n;++i){\n for(int j=3;j<=n;++j){\n for(int k=0;k<=n;++k){\n for(int l=0;l<=n;++l){\n dp[i][j][k][l] = INF;\n }\n }\n }\n }\n\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n for(int k=0;k<n;++k){\n if(ccw(v[i].first, v[j].first, v[k].first) != COUNTER_CLOCKWISE)continue;\n prev_point[i][3][j][k] = i;\n dp[i][3][j][k] = abs(det(v[j].first-v[i].first, v[k].first-v[i].first))/2.0;\n }\n }\n }\n exists[3] = true;\n\n for(int i=0;i<n;++i){\n for(int j=3;j<n;++j){\n for(int k=0;k<(int)points_idx[i].size()-2;++k){\n for(int l=k+1;l<(int)points_idx[i].size()-1;++l){\n for(int m=l+1;m<(int)points_idx[i].size();++m){\n Point a = v[points_idx[i][k]].first, b = v[points_idx[i][l]].first, c = v[points_idx[i][m]].first;\n if(ccw(a, b, c) != COUNTER_CLOCKWISE)continue;\n int k_idx = points_idx[i][k], l_idx = points_idx[i][l], m_idx = points_idx[i][m];\n double tri_area = abs(det(c-v[i].first, b-v[i].first))/2.0;\n double new_area = dp[i][j][k_idx][l_idx] + tri_area;\n if(sgn(dp[i][j+1][l_idx][m_idx] - new_area) > 0){\n dp[i][j+1][l_idx][m_idx] = new_area;\n prev_point[i][j+1][l_idx][m_idx] = k_idx;\n exists[j+1] = true;\n }\n }\n }\n }\n }\n }\n\n vector<vector<int>> ans(n+1);\n for(int i=3;i<=n;++i){\n double mini = INF;\n int sp = 0, ep1 = 0, ep2 = 0;\n for(int j=0;j<n;++j){\n for(int k=0;k<n;++k){\n for(int l=0;l<n;++l){\n if(sgn(mini-dp[j][i][k][l]) > 0){\n mini = dp[j][i][k][l];\n sp = j;\n ep1 = k;\n ep2 = l;\n }\n }\n }\n }\n vector<int> vp;\n vp.push_back(v[ep2].second); vp.push_back(v[ep1].second);\n int a = ep2, b = ep1, remain = i;\n while(b != sp){\n int c = prev_point[sp][remain][b][a];\n a = b;\n b = c;\n remain--;\n vp.push_back(v[c].second);\n }\n reverse(vp.begin(), vp.end());\n ans[i] = vp;\n }\n\n int q;\n cin >> q;\n for(int i=0;i<q;++i){\n int k;\n cin >> k;\n if(!exists[k])cout << \"NA\";\n else {\n for(int j=0;j<(int)ans[k].size();++j){\n if(j!=0)cout << \" \";\n cout << ans[k][j];\n }\n }\n cout << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 26540, "score_of_the_acc": -0.2429, "final_rank": 7 }, { "submission_id": "aoj_0284_3062319", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <complex>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <set>\n#include <utility>\nusing namespace std;\n#define REP(i, n) for(int i=0; i<(n); i++)\nconst double EPS = 1e-8;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n#define EQ(n,m) (abs((n)-(m)) < EPS)\n#define X real()\n#define Y imag()\n\ntypedef complex<double> P;\ntypedef vector<P> VP;\nstruct L : array<P, 2>{\n L(const P& a, const P& b){ at(0)=a; at(1)=b; }\n L(){}\n};\n\nnamespace std{\n bool operator < (const P& a, const P& b){\n return (a.Y!=b.Y) ? a.Y<b.Y : a.X<b.X;\n }\n bool operator == (const P& a, const P& b){\n return abs(a-b) < EPS;\n }\n}\n\ndouble dot(P a, P b){\n return (conj(a)*b).X;\n}\ndouble cross(P a, P b){\n return (conj(a)*b).Y;\n}\nint ccw(P a, P b, P c){\n b -= a;\n c -= a;\n if(cross(b,c) > EPS) return +1; //ccw\n if(cross(b,c) < -EPS) return -1; //cw\n if(dot(b,c) < -EPS) return +2; //c-a-b\n if(abs(c)-abs(b) > EPS) return -2; //a-b-c\n return 0; //a-c-b\n}\n\nstruct info{\n int sp, prev, curr;\n info(int s, int p, int c):sp(s),prev(p),curr(c){}\n info(){}\n bool operator < (const info &a) const{\n return (sp!=a.sp)? sp<a.sp: (prev!=a.prev)? prev<a.prev: curr<a.curr;\n }\n};\ndouble dp[40][40][40][41];\npair<int,int> prevtable[40][40][40][41];\n\nint main(){\n int n;\n cin >> n;\n vector<pair<P, int> > ord(n);\n for(int i=0; i<n; i++){\n double x,y;\n cin >> x >> y;\n ord[i] = make_pair(P(x, y), i);\n }\n sort(ord.begin(), ord.end());\n\n VP p(n);\n vector<int> conv(n);\n for(int i=0; i<n; i++){\n p[i] = ord[i].first;\n conv[i] = ord[i].second +1;\n }\n\n int q;\n cin >> q;\n vector<int> query(q);\n for(int i=0; i<q; i++){\n cin >> query[i];\n }\n\n //dp[始点][前の点][今の点][点の数] = 最小面積 \n REP(i,n) REP(j,n) REP(k,n) REP(l,n+1) dp[i][j][k][l] = INF;\n set<info> next;\n for(int fp=0; fp<n; fp++){\n for(int sp=fp+1; sp<n; sp++){\n dp[fp][fp][sp][2] = 0;\n next.insert(info(fp, fp, sp));\n }\n } \n\n for(int i=2; i<n; i++){\n set<info> newnext;\n for(info w: next){\n for(int j=w.sp+1; j<n; j++){\n int ret1 = ccw(p[w.prev], p[w.curr], p[j]);\n int ret2 = ccw(p[w.curr], p[j], p[w.sp]);\n if((ret1==1 || ret1==-2) && ret2!=-1){\n double &update = dp[w.sp][w.curr][j][i+1];\n double &now = dp[w.sp][w.prev][w.curr][i];\n double area = cross(p[w.curr]-p[w.sp], p[j]-p[w.sp])/2;\n if(now +area < update){\n update = now +area;\n newnext.insert(info(w.sp, w.curr, j));\n prevtable[w.sp][w.curr][j][i+1] = make_pair(w.prev, w.curr);\n }\n }\n }\n }\n next = newnext;\n }\n\n //経路復元\n for(int i=0; i<q; i++){\n vector<int> ans;\n int sp=-1, curr=-1, prev=-1;\n double minarea = INF;\n for(int s=0; s<n; s++){\n for(int p=0; p<n; p++){\n for(int c=0; c<n; c++){\n if(dp[s][p][c][query[i]] < minarea){\n minarea = dp[s][p][c][query[i]];\n sp = s;\n prev = p;\n curr = c;\n }\n }\n }\n }\n if(sp==-1){\n cout << \"NA\" << endl;\n continue;\n }\n ans.push_back(conv[curr]);\n ans.push_back(conv[prev]);\n for(int j=query[i]; j>2; j--){\n pair<int,int> pc = prevtable[sp][prev][curr][j];\n prev = pc.first;\n curr = pc.second;\n ans.push_back(conv[prev]);\n }\n for(int j=ans.size()-1; j>0; j--){\n cout << ans[j] << \" \";\n }\n cout << ans[0] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 32248, "score_of_the_acc": -0.2627, "final_rank": 8 }, { "submission_id": "aoj_0284_2694584", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing PII = pair<int, int>;\nusing LL = long long;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing PLL = pair<LL, LL>;\nusing VS = vector<string>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\n#define FF first\n#define SS second\n\n#define DUMP(x) cout<<#x<<\":\"<<(x)<<endl\ntemplate<class S, class T>\nistream& operator>>(istream& is, pair<S,T>& p){\n return is >> p.FF >> p.SS;\n}\ntemplate<class T>\nistream& operator>>(istream& is, vector<T>& xs){\n for(auto& x: xs)\n\tis >> x;\n return is;\n}\ntemplate<class S, class T>\nostream& operator<<(ostream& os, const pair<S,T>& p){\n return os << p.FF << \" \" << p.SS;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, const vector<T>& xs){\n for(unsigned int i=0;i<xs.size();++i)\n\tos << (i?\" \":\"\") << xs[i];\n return os;\n}\ntemplate<class T>\nvoid maxi(T& x, T y){\n if(x < y) x = y;\n}\ntemplate<class T>\nvoid mini(T& x, T y){\n if(x > y) x = y;\n}\n\n\nconst double EPS = 1e-6;\nconst double PI = acos(-1.0);\nconst LL MOD = 1e9+7;\nconst double INF = 1e15;\n\nclass Point{\npublic:\n double x, y;\n\n Point(double x = 0.0, double y = 0.0) : x(x), y(y){}\n\n Point& operator += (const Point& p){ x += p.x; y += p.y; return *this;}\n Point operator + (const Point& p) const{ Point q = *this;return q += p;}\n Point& operator -= (const Point& p){ x -= p.x; y -= p.y; return *this;}\n Point operator - (const Point& p) const{ Point q = *this; return q -= p;}\n Point& operator *= (double a){ x *= a; y *= a; return *this;}\n Point operator * (double a) const{ Point q = *this; return q *= a;}\n Point& operator /= (double a){ x /= a; y /= a; return *this;}\n Point operator / (double a) const{ Point q = *this; return q /= a;}\n\n double abs() const { return sqrt(norm()); }\n double norm() const { return x*x + y*y; }\n Point& normalize(){ return *this /= abs(); }\n \n bool operator < (const Point &p) const{\n\treturn y != p.y ? y < p.y : x < p.x;\n }\n \n //EPSは十分小さな値\n bool operator == (const Point &p) const {\n\treturn fabs(x - p.x) < EPS && fabs(y - p.y) < EPS;\n }\n friend ostream& operator <<(ostream& os, const Point& p);\n};\nostream& operator <<(ostream& os, const Point& p){\n return os << \"(\" << p.x << \",\"<<p.y << \")\";\n}\n\ntypedef vector<Point> Polygon;\ntypedef Point Vector;\n//内積\ndouble dot(Vector a, Vector b){\n\treturn a.x*b.x + a.y*b.y;\n}\n\n//外積の大きさ\ndouble cross(Vector a, Vector b){\n\treturn a.x*b.y - a.y*b.x;\n}\n\nint ccw(Point p0, Point p1, Point p2){\n\n\t//p0->p1をp0始点、p1終点の基準ベクトルとしたとき\n\n\t//p0->p2が反時計回りになるとき\n\tstatic const int COUNTER_CLOCKWISE = 1;\n\t//p0->p2が時計回りになるとき\n\tstatic const int CLOCKWISE = -1;\n\t//p2,p0,p1の順で同一直線上にあるとき\n\tstatic const int ONLINE_BACK = 2;\n\t//p0,p1,p2 の順で同一直線上にある場合\n\tstatic const int ONLINE_FRONT = -2;\n\t//p2 が線分 p0p1 上にある場合\n\tstatic const int ON_SEGMENT = 0;\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif (cross(a, b) > EPS) return COUNTER_CLOCKWISE;\n\tif (cross(a, b) < -EPS) return CLOCKWISE;\n\tif (dot(a, b) < -EPS) return ONLINE_BACK;\n\tif (a.norm() < b.norm()) return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\nPolygon andrewScan(Polygon s){\n\tPolygon u, l;\n\n\tif (s.size() < 3) return s;\n\n\tsort(s.begin(), s.end()); //x,yを基準にソート\n\n\tu.push_back(s[0]);\n\tu.push_back(s[1]);\n\n\tl.push_back(s[s.size() - 1]);\n\tl.push_back(s[s.size() - 2]);\n\n\t//凸方の上部を生成\n\tfor (unsigned int i = 2; i < s.size(); i++){\n\t\tfor (int n = u.size(); n >= 2 && ccw(u[n - 2], u[n - 1], s[i]) == 1; n--){\n\t\t\tu.pop_back();\n\t\t}\n\t\tu.push_back(s[i]);\n\t}\n\n\t//凸法の下部を生成\n\tfor (int i = s.size() - 3; i >= 0; i--){\n\t\tfor (int n = l.size(); n >= 2 && ccw(l[n - 2], l[n - 1], s[i]) == 1; n--){\n\t\t\tl.pop_back();\n\t\t}\n\t\tl.push_back(s[i]);\n\t}\n\n\t//反時計回りになるように凸包の点の列\n\treverse(l.begin(), l.end());\n\tfor (int i = u.size() - 2; i >= 1; i--)\n\t\tl.push_back(u[i]);\n\n\treturn l;\n}\n\ndouble tri_area(Point p1, Point p2, Point p3){\n return abs(cross(p2-p1, p3-p1)) / 2.;\n}\n\ndouble dp[41][41][41][41];\nint rev[41][41][41][41];\n\nint main(){\n cin.tie(0);\n ios_base::sync_with_stdio(false);\n\n int N;\n cin >> N;\n vector<pair<Point,int>> ps(N);\n REP(i,N){\n\tcin >> ps[i].FF.x >> ps[i].FF.y;\n\tps[i].SS = i+1;\n }\n SORT(ps);\n\n fill((double*)dp, (double*)dp+41*41*41*41, INF);\n REP(i1,N) REP(i2,N) REP(i3,N){\n\tif(i1==i2 || i2 == i3 || i1==i3) continue;\n\tif(ps[i2] < ps[i1] || ps[i3] < ps[i1]) continue;\n\tif(ccw(ps[i1].FF, ps[i2].FF, ps[i3].FF) == 1){\n\t dp[3][i1][i2][i3] = tri_area(ps[i1].FF, ps[i2].FF, ps[i3].FF);\n\t}\n }\n\n FOR(i,3,N) REP(b,N) REP(j,N) REP(k,N){\n\tif(dp[i][b][j][k] >= INF) continue;\n\tFOR(n,b+1,N){\n\t if(n == b || n == j || n == k) continue;\n\t if(ccw(ps[j].FF, ps[k].FF, ps[n].FF) != 1 || ccw(ps[b].FF, ps[n].FF, ps[k].FF) != -1) continue;\n\t double res = dp[i][b][j][k] + tri_area(ps[k].FF, ps[n].FF, ps[b].FF);\n\t if(res < dp[i+1][b][k][n]){\n\t\tdp[i+1][b][k][n] = res;\n\t\trev[i+1][b][k][n] = j;\n\t }\n\t}\n }\n\n int Q;\n cin >> Q;\n REP(q,Q){\n\tint K;\n\tcin >> K;\n\n\tint ab=-1, aj, ak;\n\tdouble best = INF;\n\tREP(b,N) REP(j,N) REP(k,N){\n\t if(dp[K][b][j][k] >= INF) continue;\n\t if(dp[K][b][j][k] <= best-EPS){\n\t\tbest = dp[K][b][j][k];\n\t\tab = b;\n\t\taj = j;\n\t\tak = k;\n\t }\n\t else if(abs(dp[K][b][j][k] - best) <= EPS){\n\t\tif(ps[b] < ps[ab]){\n\t\t best = dp[K][b][j][k];\n\t\t ab = b;\n\t\t aj = j;\n\t\t ak = k;\n\t\t}\n\t }\n\t}\n\tif(ab == -1){\n\t cout << \"NA\" << endl;\n\t continue;\n\t}\n\n\tVI ans;\n\tfor(int k=K;k>3;--k){\n\t ans.PB(ps[ak].SS);\n\t int r = rev[k][ab][aj][ak];\n\t ak = aj;\n\t aj = r;\n\t}\n\tans.PB(ps[ak].SS);\n\tans.PB(ps[aj].SS);\n\tans.PB(ps[ab].SS);\n\treverse(ALL(ans));\n\tcout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26824, "score_of_the_acc": -0.1912, "final_rank": 6 }, { "submission_id": "aoj_0284_2694422", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing PII = pair<int, int>;\nusing LL = long long;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing PLL = pair<LL, LL>;\nusing VS = vector<string>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\n#define FF first\n#define SS second\n\n#define DUMP(x) cout<<#x<<\":\"<<(x)<<endl\ntemplate<class S, class T>\nistream& operator>>(istream& is, pair<S,T>& p){\n return is >> p.FF >> p.SS;\n}\ntemplate<class T>\nistream& operator>>(istream& is, vector<T>& xs){\n for(auto& x: xs)\n\tis >> x;\n return is;\n}\ntemplate<class S, class T>\nostream& operator<<(ostream& os, const pair<S,T>& p){\n return os << p.FF << \" \" << p.SS;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, const vector<T>& xs){\n for(unsigned int i=0;i<xs.size();++i)\n\tos << (i?\" \":\"\") << xs[i];\n return os;\n}\ntemplate<class T>\nvoid maxi(T& x, T y){\n if(x < y) x = y;\n}\ntemplate<class T>\nvoid mini(T& x, T y){\n if(x > y) x = y;\n}\n\n\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst LL MOD = 1e9+7;\n\n\nclass Point{\npublic:\n double x, y;\n\n Point(double x = 0.0, double y = 0.0) : x(x), y(y){}\n\n Point& operator += (const Point& p){ x += p.x; y += p.y; return *this;}\n Point operator + (const Point& p) const{ Point q = *this;return q += p;}\n Point& operator -= (const Point& p){ x -= p.x; y -= p.y; return *this;}\n Point operator - (const Point& p) const{ Point q = *this; return q -= p;}\n Point& operator *= (double a){ x *= a; y *= a; return *this;}\n Point operator * (double a) const{ Point q = *this; return q *= a;}\n Point& operator /= (double a){ x /= a; y /= a; return *this;}\n Point operator / (double a) const{ Point q = *this; return q /= a;}\n\n double abs() const { return sqrt(norm()); }\n double norm() const { return x*x + y*y; }\n Point& normalize(){ return *this /= abs(); }\n \n bool operator < (const Point &p) const{\n\treturn y != p.y ? y < p.y : x < p.x;\n }\n \n //EPSは十分小さな値\n bool operator == (const Point &p) const {\n\treturn fabs(x - p.x) < EPS && fabs(y - p.y) < EPS;\n }\n friend ostream& operator <<(ostream& os, const Point& p);\n};\nostream& operator <<(ostream& os, const Point& p){\n return os << \"(\" << p.x << \",\"<<p.y << \")\";\n}\n\nclass Segment{\npublic:\n Point p1, p2;\n Segment(){}\n Segment(const Point& p1_, const Point& p2_)\n\t: p1(p1_), p2(p2_)\n {}\n};\n\nclass Circle{\npublic:\n\tPoint c;\n\tdouble r;\n};\n\ntypedef vector<Point> Polygon;\n\n//点を線として扱う\ntypedef Point Vector;\n//線分を直線として扱う\ntypedef Segment Line;\n\n//内積\ndouble dot(Vector a, Vector b){\n\treturn a.x*b.x + a.y*b.y;\n}\n\n//外積の大きさ\ndouble cross(Vector a, Vector b){\n\treturn a.x*b.y - a.y*b.x;\n}\n\nint ccw(Point p0, Point p1, Point p2){\n\n\t//p0->p1をp0始点、p1終点の基準ベクトルとしたとき\n\n\t//p0->p2が反時計回りになるとき\n\tstatic const int COUNTER_CLOCKWISE = 1;\n\t//p0->p2が時計回りになるとき\n\tstatic const int CLOCKWISE = -1;\n\t//p2,p0,p1の順で同一直線上にあるとき\n\tstatic const int ONLINE_BACK = 2;\n\t//p0,p1,p2 の順で同一直線上にある場合\n\tstatic const int ONLINE_FRONT = -2;\n\t//p2 が線分 p0p1 上にある場合\n\tstatic const int ON_SEGMENT = 0;\n\n\tVector a = p1 - p0;\n\tVector b = p2 - p0;\n\n\tif (cross(a, b) > EPS) return COUNTER_CLOCKWISE;\n\tif (cross(a, b) < -EPS) return CLOCKWISE;\n\tif (dot(a, b) < -EPS) return ONLINE_BACK;\n\tif (a.norm() < b.norm()) return ONLINE_FRONT;\n\n\treturn ON_SEGMENT;\n}\nPolygon andrewScan(Polygon s){\n\tPolygon u, l;\n\n\tif (s.size() < 3) return s;\n\n\tsort(s.begin(), s.end()); //x,yを基準にソート\n\n\tu.push_back(s[0]);\n\tu.push_back(s[1]);\n\n\tl.push_back(s[s.size() - 1]);\n\tl.push_back(s[s.size() - 2]);\n\n\t//凸方の上部を生成\n\tfor (int i = 2; i < s.size(); i++){\n\t\tfor (int n = u.size(); n >= 2 && ccw(u[n - 2], u[n - 1], s[i]) == 1; n--){\n\t\t\tu.pop_back();\n\t\t}\n\t\tu.push_back(s[i]);\n\t}\n\n\t//凸法の下部を生成\n\tfor (int i = s.size() - 3; i >= 0; i--){\n\t\tfor (int n = l.size(); n >= 2 && ccw(l[n - 2], l[n - 1], s[i]) == 1; n--){\n\t\t\tl.pop_back();\n\t\t}\n\t\tl.push_back(s[i]);\n\t}\n\n\t//反時計回りになるように凸包の点の列\n\treverse(l.begin(), l.end());\n\tfor (int i = u.size() - 2; i >= 1; i--)\n\t\tl.push_back(u[i]);\n\n\treturn l;\n}\n\n//多角形の面積を求める //凸包のソート済みが前提\ndouble polygon_area(const Polygon& t){\n double ans=0.0;\n for(unsigned int i=0;i<t.size();i++)\n\tans+=cross(t[i] , t[(i+1)%t.size()]);\n return ans/2;\n}\n\nvector<vector<Polygon>> pols(41);\nvector<Polygon> ans(41);\nVVI ansi(41);\n\nint main(){\n cin.tie(0);\n ios_base::sync_with_stdio(false);\n\n int N;\n cin >> N;\n\n Polygon ps(N);\n REP(i,N) cin >> ps[i].x >> ps[i].y;\n\n REP(i1,N) REP(i2,i1) REP(i3,i2){\n\tPolygon p;\n\tp.push_back(ps[i1]);\n\tp.push_back(ps[i2]);\n\tp.push_back(ps[i3]);\n\tp = andrewScan(p);\n\tpols[3].EB(p);\n }\n\n FOR(i,3,N){\n\t//cout<<SZ(pols[i]) << endl;\n\tif(pols[i].empty()) break;\n\n\tdouble area = 1e15;\n\twhile(!pols[i].empty()){\n\t auto p = pols[i].back();\n\t pols[i].pop_back();\n\n\t double a = polygon_area(p);\n\t if(a < area){\n\t\tarea = a;\n\t\tans[i] = p;\n\t }\n\n\t double poi = 1e15;\n\t Polygon pyon;\n\t REP(j,N){\n\t\tp.push_back(ps[j]);\n\t\tPolygon tmp = andrewScan(p);\n\t\tif(SZ(tmp) == i+1){\n\t\t double poipoi = polygon_area(tmp);\n\t\t if(poipoi < poi){\n\t\t\tpoi = poipoi;\n\t\t\tpyon = tmp;\n\t\t }\n\t\t}\n\t\tp.pop_back();\n\t }\n\t if(!pyon.empty())\n\t\tpols[i+1].EB(pyon);\n\t}\n }\n\n if(!pols[N].empty()){\n\tint i = N;\n\tint mi = 0;\n\tdouble area = polygon_area(pols[i][0]);\n\tFOR(j,1,SZ(pols[i])){\n\t double a = polygon_area(pols[i][j]);\n\t if(a < area){\n\t\tmi = j;\n\t\tarea = a;\n\t }\n\t}\n\tans[i] = pols[i][mi];\n }\n\n FOR(i,3,N+1){\n\tif(ans[i].empty()) continue;\n\tfor(auto& p: ans[i]){\n\t REP(j,N){\n\t\tif(p == ps[j]){\n\t\t ansi[i].PB(j+1);\n\t\t break;\n\t\t}\n\t }\n\t}\n }\n\n int Q;\n cin >> Q;\n REP(q,Q){\n\tint k;\n\tcin >> k;\n\tif(ansi[k].empty())\n\t cout << \"NA\" << endl;\n\telse\n\t cout << ansi[k] << endl;\n }\n\n return 0;\n}", "accuracy": 0.7777777777777778, "time_ms": 750, "memory_kb": 5188, "score_of_the_acc": -1.0138, "final_rank": 15 } ]
aoj_0271_cpp
イヅア国語辞典 あなたはイヅア国の公用語であるイヅア語の国語辞典と、イヅア語のアルファベット(文字の一覧表) を手に入れました。イヅア語のアルファベットにはN 種類の文字があります。イヅア語の国語辞典に現れる単語の順番は、イヅア語のアルファベット順に並んでいます。 辞典を見ると、載っているどの単語もN 文字で、しかも、N 種類の文字をひとつずつ含んでいることがわかりました。さらに調べてみると、辞典にはN 種類の文字の可能な並び方がすべて書かれていることを発見しました。 この発見から、あなたはある単語が辞典の何番目に出てくるかわかるようになりました。この知識を利用してイヅア国の人を驚かせてみましょう。まず、N 種類の文字をひとつずつアルファベット順に並べます。次に、任意の2文字の順番を入れ替える操作を R 回繰り返してもらいます。あなたは、出来上がった単語がイヅア国語辞典の何番目に出てくるか当てて見せます。そのための準備として、国語辞典中の単語の場所を求めるプログラムを作成してください。ただし、アルファベット順で最初の単語を 0 番目の単語とします。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。 N R s 1 t 1 s 2 t 2 : s R t R 1行目にアルファベットを構成する文字の数 N (1 ≤ N ≤ 100000) が与えられ、2行目に文字を入れ替えてもらう回数 R (0 ≤ R ≤ 50) が与えられる。続く R 行に、入れ替えられる文字の位置の組が与えられる。s i と t i (1 ≤ s i < t i ≤ N) は、先頭から数えて s i 番目と t i 番目の文字を i 回目に入れ替えることを表す。s i と t i は1つの空白で区切られている。 データセットの数は100 を超えない。 出力 データセットごとに、入れ替えが終わった時点で得られた単語が国語辞典の何番目に現れるかを示す数を1行に出力する。ただし、出力すべき値は非常に大きくなりうるので、代わりに 1,000,000,007 で割った余りを出力する。 入力例 3 2 1 2 2 3 4 2 2 3 2 4 0 出力例 3 4 入出力例の最初のデータセットについて説明する。説明のため、アルファベットは小さい方から順番に、'A', 'B', 'C' の3文字からなるとする。これらの文字をアルファベット順に並べると "ABC" という文字列が得られる。この文字列の1番目の文字 'A' と2番目の文字 'B' を入れ替えると、"BAC" という文字列が得られる。次に、得られた文字列の2番目の文字 'A' と3番目の文字 'C' を入れ替えると、単語 "BCA" が得られる。辞典には、先頭から順に "ABC", "ACB", "BAC", "BCA", "CAB", "CBA" の6種類の単語が載っている。"BCA" はこの中で3番目(最初の"ABC"が0番目であることに注意)に現れるので、3 を 1,000,000,007 で割った余りである 3 が答えになる。
[ { "submission_id": "aoj_0271_10568001", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int mod = 1e9 + 7;\n\nint mul(int x, int y) {\n return (1ll * x * y) % mod;\n}\n\nconst int MAXN = 1e5 + 5;\n\nint fact[MAXN];\n\nvoid precalc() {\n fact[0] = 1;\n for (int i = 1; i < MAXN; ++i) fact[i] = mul(fact[i - 1], i);\n}\n\nstruct Fen {\n int n = 0;\n vector<int> f;\n\n Fen(int n): n(n), f(n) {}\n \n void add(int cur) {\n for (; cur < n; cur |= (cur + 1)) ++f[cur];\n }\n\n int get(int cur) {\n int res = 0;\n for (; cur >= 0; cur = (cur & (cur + 1)) - 1) res += f[cur];\n return res;\n }\n};\n\nsigned main() {\n\n#ifdef LOCAL\n freopen(\"input.txt\", \"r\", stdin);\n#endif\n\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n\n precalc();\n\n for (int n; cin >> n;) {\n if (n == 0) break;\n vector<int> a(n);\n iota(a.begin(), a.end(), 0);\n int r;\n cin >> r;\n for (int x, y, i = 0; i < r; ++i) {\n cin >> x >> y;\n --x, --y;\n swap(a[x], a[y]);\n }\n int res = 0;\n Fen fen(n);\n for (int i = 0; i < n; ++i) {\n res = (res + mul(fact[n - i - 1], max(0, a[i] - fen.get(a[i])))) % mod;\n fen.add(a[i]);\n }\n cout << res << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 4228, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0271_8818760", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\nconst int divisor = 1000000007;\n\nint main() {\n vector<long long> factmodary(100001);\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n \n int N, R, s, t, tmp, facttime, bubblenum;\n\n while (std::cin >> N && N != 0) { \n cin >> R;\n vector<int> word(N);\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n cin >> s >> t;\n tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n facttime = word[i] - 1;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 2010, "memory_kb": 8696, "score_of_the_acc": -1.8809, "final_rank": 19 }, { "submission_id": "aoj_0271_8214650", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n }\n cout << ans % divisor << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 8536, "score_of_the_acc": -1.758, "final_rank": 12 }, { "submission_id": "aoj_0271_8214649", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1830, "memory_kb": 8628, "score_of_the_acc": -1.7707, "final_rank": 15 }, { "submission_id": "aoj_0271_8112471", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1810, "memory_kb": 8636, "score_of_the_acc": -1.7616, "final_rank": 14 }, { "submission_id": "aoj_0271_8112469", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios_base::sync_with_stdio(false);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 8520, "score_of_the_acc": -1.7548, "final_rank": 11 }, { "submission_id": "aoj_0271_8112468", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 8528, "score_of_the_acc": -1.7456, "final_rank": 9 }, { "submission_id": "aoj_0271_8112467", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1840, "memory_kb": 8424, "score_of_the_acc": -1.7359, "final_rank": 7 }, { "submission_id": "aoj_0271_8112466", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1870, "memory_kb": 8636, "score_of_the_acc": -1.7938, "final_rank": 16 }, { "submission_id": "aoj_0271_8112465", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n long long *factmodary = new long long[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int *word = new int[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n map<int, int>::iterator it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n map<int, int>::iterator it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n delete[] word;\n delete[] factmodary;\n return 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 8604, "score_of_the_acc": -1.7606, "final_rank": 13 }, { "submission_id": "aoj_0271_8050535", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n long long factmodary[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int word[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1) % divisor;\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n auto it = bubblehist.lower_bound(word[i]);\n int bubblenum;\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n --it;\n } else {\n --it;\n bubblenum = it->second + 1;\n }\n auto it2 = bubblehist.emplace_hint(it, word[i], bubblenum);\n for (++it2; it2 != bubblehist.end(); ++it2)\n ++(it2->second);\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime % divisor;\n ans %= divisor;\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1650, "memory_kb": 8996, "score_of_the_acc": -1.7465, "final_rank": 10 }, { "submission_id": "aoj_0271_8050534", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nconst int MAX_N = 100000;\nlong long factmodary[MAX_N + 1];\nint word[MAX_N];\nint main() {\n long long fact = 1;\n for (int i = 1; i <= MAX_N; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n swap(word[s - 1], word[t - 1]);\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p(word[i], bubblenum);\n auto it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1560, "memory_kb": 9236, "score_of_the_acc": -1.7454, "final_rank": 8 }, { "submission_id": "aoj_0271_8050531", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n long long factmodary[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact = (fact * i) % divisor;\n factmodary[i] = fact;\n }\n int word[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n swap(word[s - 1], word[t - 1]);\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n auto it = bubblehist.lower_bound(word[i]);\n int bubblenum = it == bubblehist.end() ? (--it)->second + 1 : it->second;\n auto it2 = bubblehist.insert(it, {word[i], bubblenum});\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime % divisor;\n ans %= divisor;\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1540, "memory_kb": 9200, "score_of_the_acc": -1.7276, "final_rank": 6 }, { "submission_id": "aoj_0271_8050530", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nconst int max_size = 100001; // store size in a variable\nint main() {\n long long factmodary[max_size];\n long long fact = 1;\n for (int i = 1; i < max_size; i++) { // less than instead of less than or equal to\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int word[max_size] = {0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]); // use auto instead of map<int, int>::iterator\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p{word[i], bubblenum}; // use uniform initialization\n auto it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << static_cast<int>(ans) << \"\\n\"; // use static_cast instead of (int)\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1460, "memory_kb": 9184, "score_of_the_acc": -1.6814, "final_rank": 2 }, { "submission_id": "aoj_0271_8050529", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nlong long factmodary[100001];\nint word[100000];\nint main() {\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n auto it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 9152, "score_of_the_acc": -1.6913, "final_rank": 4 }, { "submission_id": "aoj_0271_8050525", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nconst int maxN = 100000;\nlong long factmodary[maxN + 1];\nint word[maxN];\nint main() {\n long long fact = 1;\n for (int i = 1; i <= maxN; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n swap(word[s - 1], word[t - 1]);\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n auto [it2, success] = bubblehist.insert({word[i], bubblenum});\n it2++;\n for (; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << (int)ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1790, "memory_kb": 9232, "score_of_the_acc": -1.8683, "final_rank": 18 }, { "submission_id": "aoj_0271_8050521", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nint main() {\n long long factmodary[100001];\n long long fact = 1;\n for (int i = 1; i <= 100000; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n int word[100000]{0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n auto it2 = bubblehist.emplace_hint(it, word[i], bubblenum);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1480, "memory_kb": 9300, "score_of_the_acc": -1.7151, "final_rank": 5 }, { "submission_id": "aoj_0271_8050519", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nconst int MAXN = 100000;\nlong long factmodary[MAXN+1]; // Use a constant instead of a variable for the size\nint word[MAXN];\nint main() {\n long long fact = 1;\n for (int i = 1; i <= MAXN; i++) {\n fact = (fact * i) % divisor; // Combine multiplication and modulo operation\n factmodary[i] = fact;\n }\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n swap(word[s - 1], word[t - 1]); // Use swap instead of temporary variable\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1, bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n auto [it2, inserted] = bubblehist.insert({word[i], bubblenum});\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans = (ans + factmodary[N - (i + 1)] * facttime) % divisor; // Combine addition and modulo operation\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1740, "memory_kb": 9300, "score_of_the_acc": -1.8548, "final_rank": 17 }, { "submission_id": "aoj_0271_8050516", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nconst int divisor = 1000000007;\nconst int maxn = 100001;\nlong long factmodary[maxn];\nvoid precompute() {\n long long fact = 1;\n for (int i = 1; i <= maxn-1; i++) {\n fact *= i;\n fact %= divisor;\n factmodary[i] = fact;\n }\n}\nint main() {\n precompute();\n int word[maxn] = {0};\n for (;;) {\n int N, R;\n cin >> N;\n if (N == 0)\n break;\n cin >> R;\n for (int i = 0; i < N; i++)\n word[i] = i + 1;\n for (int i = 0; i < R; i++) {\n int s, t;\n cin >> s >> t;\n int tmp = word[s - 1];\n word[s - 1] = word[t - 1];\n word[t - 1] = tmp;\n }\n map<int, int> bubblehist;\n bubblehist[word[0]] = 0;\n long long ans = factmodary[N - 1] * (word[0] - 1);\n for (int i = 1; i < N; i++) {\n int facttime = word[i] - 1;\n int bubblenum;\n auto it = bubblehist.lower_bound(word[i]);\n if (it != bubblehist.end()) {\n bubblenum = it->second;\n it--;\n } else {\n it--;\n bubblenum = it->second + 1;\n }\n pair<int, int> p;\n p.first = word[i];\n p.second = bubblenum;\n auto it2 = bubblehist.insert(it, p);\n for (++it2; it2 != bubblehist.end(); it2++)\n (it2->second)++;\n facttime -= bubblenum;\n ans += factmodary[N - (i + 1)] * facttime;\n ans %= divisor;\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1470, "memory_kb": 9204, "score_of_the_acc": -1.6907, "final_rank": 3 } ]
aoj_0287_cpp
塵劫記 大きな数を表そうとすると、文字数も多くなるし、位取りがわからなくなってしまうので、なかなか面倒です。大きな数をわかりやすく表すために、人々は数の単位を使ってきました。江戸時代に書かれた「塵劫記」という本の中では、数の単位が次のように書かれています。 たとえば、2の100乗のようなとても大きな数は、126穣7650(じょ)6002垓2822京9401兆4967億320万5376と表せます。それでは、正の整数 m と n が与えられたとき、 m の n 乗を塵劫記の単位を使って上のように表すプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。各データセットは以下の形式で与えられる。 m n m (2 ≤ m ≤ 20) が基数、 n (1 ≤ n < 240) が指数を表す。ただし、 m n は 10 72 未満である。 データセットの数は 100 を超えない。 出力 データセットごとに、 m n を塵劫記の単位で表した文字列を1行に出力する。ただし、各単位は以下の表記で出力する。 m n を表す文字列は、1 から 9999 までの数と上の表に現れる単位を表す文字列からなる。文字列には、余分な 0 や単位を含めない。 入出力例 入力例 2 10 5 20 10 8 20 17 0 0 出力例 1024 95Cho3674Oku3164Man625 1Oku 131Gai720Kei
[ { "submission_id": "aoj_0287_3201960", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstring>\n#include<vector>\n#include<set>\n#include<cmath>\nusing namespace std;\ntypedef vector<int> vi;\nconst string units[]={\n \"\",\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\n \"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"\n};\nconst int MD=405;\n\nstruct LongInt\n{\n LongInt(int i=0)\n {\n memset(digits,0,sizeof(digits));\n n=0;\n while(i>0)\n {\n\tdigits[n++]=i%10;\n\ti/=10;\n }\n }\n LongInt(const string &s)\n {\n memset(digits,0,sizeof(digits));\n n=0;\n bool f=false;\n for(int j=(int)s.size()-1;j>=0;j--)\n {\n\tif(!isdigit(s[j])){continue;}\n\tif(s[j]!='0')\n\t {\n\t digits[n++]=s[j]-'0';\n\t f=true;\n\t }\n\telse if(f)\n\t {\n\t digits[n++]=s[j]-'0';\n\t }\n }\n }\n int digits[MD],n;\n};\n\nLongInt operator*(const LongInt& lhs,const LongInt& rhs)\n{\n LongInt res;\n for(int i=0;i<MD;i++)\n {\n for(int j=0;j<MD;j++)\n\t{\n\t if(i+j>=MD){continue;}\n\t int x=lhs.digits[i]*rhs.digits[j]+res.digits[i+j];\n\t res.digits[i+j]=x%10;\n\t if(i+j+1<MD)\n\t {\n\t res.digits[i+j+1]+=x/10;\n\t }\n\t}\n }\n return res;\n}\n\nLongInt operator+(const LongInt& lhs,const LongInt& rhs)\n{\n LongInt res;\n for(int i=0;i<MD;i++)\n {\n int x=lhs.digits[i]+rhs.digits[i]+res.digits[i];\n res.digits[i]=x%10;\n if(i+1<MD)\n\t{\n\t res.digits[i+1]=x/10;\n\t}\n }\n return res;\n}\n\nint main()\n{\n int m,n;\n while(cin >> m >> n && (m || n))\n {\n LongInt num(1),a(m);\n while(n>0)\n\t{\n\t if(n&1){num=num*a;}\n\t a=a*a;\n\t n>>=1;\n\t}\n int mx;\n bool f=false;\n for(int i=MD-1;i>=0;i--)\n\t{\n\t if(num.digits[i]!=0){f=true;}\n\n\t if(f)\n\t {\n\t mx=i;\n\t break;\n\t }\n\t}\n string S=\"\";\n for(int i=mx;i>=0;)\n\t{\n\t int x=0;\n\t while(1)\n\t {\n\t x=x*10+num.digits[i];\n\t if(i%4==0){break;}\n\t i--;\n\t }\n\t if(x>0)\n\t {\n\t S+=to_string(x)+units[i/4];\n\t }\n\t i--;\n\t}\n cout << S << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3292, "score_of_the_acc": -1.7692, "final_rank": 9 }, { "submission_id": "aoj_0287_2065281", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <sstream>\n#include <cstdlib>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n\n\nstring sum(string a, string b) {\n\tif (a.size() > b.size()) swap(a, b);\n\tint c = 0;\n\t\n\tstring res = \"\";\n\tREP(i, a.size()) {\n\t\tint x = a[a.size() - 1 - i] - '0' + b[b.size() - 1 - i] - '0' + c;\n\t\tres.push_back(x % 10 + '0');\n\t\tc = x / 10;\n\t}\n\tFOR(i, a.size(), b.size()) {\n\t\tint x = b[b.size() - 1 - i] - '0' + c;\n\t\tres.push_back(x % 10 + '0');\n\t\tc = x / 10;\n\t}\n\tif (c > 0) res.push_back(c + '0');\n\t\n\treverse(res.begin(), res.end());\n\treturn res;\n}\n\nstring kake(string a, string b) {\n\tif (a == \"0\" || b == \"0\") return \"0\";\n\tstring res = \"\";\n\tif (a.size() > b.size()) swap(a, b);\n\t\n\tstring s = \"0\";\n\tREP(i, b.size()) {\n\t\tREP(j, a.size()) {\n\t\t\tint tmp = (a[a.size() - j - 1] - '0') * (b[b.size() - i - 1] - '0');\n\t\t\tif (tmp > 0) {\n\t\t\t\tstringstream ss;\n\t\t\t\tss << tmp;\n\t\t\t\tREP(k, j) ss << \"0\";\n\t\t\t\ts = sum(s, ss.str());\n\t\t\t}\n\t\t}\n\t\tres.push_back(s[s.size() - 1]);\n\t\ts.erase(s.end() - 1);\n\t\tif (s.empty()) s = \"0\";\n\t}\n\t\n\twhile (s != \"0\") {\n\t\tres.push_back(s[s.size() - 1]);\n\t\t\n\t\ts.erase(s.end() - 1);\n\t\tif (s.empty()) s = \"0\";\n\t}\n\treverse(res.begin(), res.end());\n\treturn res;\n}\n\nstring pow(string x, int n) {\n\tif (n == 0) return \"1\";\n\tstring res = pow(kake(x, x), n / 2);\n\tif (n & 1) res = kake(res, x);\n\treturn res;\n}\n\nstring jin[19] = {\n\t\"\", \"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"\n};\n\nint main() {\n\tstring m;\n\tint n;\n\t\n\twhile (cin >> m >> n, m != \"0\" || n) {\n\t\tstring num = pow(m, n);\n\t\tint pos = (num.size() - 1) / 4 ;\n\t\tcout << num.substr(0, (num.size() - 1) % 4 + 1) << jin[pos];\n\t\twhile (--pos >= 0) {\n\t\t\tstring out = num.substr((num.size() - 1) % 4 + 1 + ((num.size() - 1) / 4 - pos - 1) * 4, 4);\n\t\t\tif (atoi(out.c_str()) > 0) cout << atoi(out.c_str()) << jin[pos];\n\t\t}\n\t\tputs(\"\");\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3184, "score_of_the_acc": -1.2568, "final_rank": 8 }, { "submission_id": "aoj_0287_1618314", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nstring S(ll n){stringstream ss;string s;ss<<n;ss>>s;return s;}\nll N(string s){stringstream ss;ll n;ss<<s;ss>>n;return n;}\nstring Z(string s){int i;for(i=0;i<s.size()-1;i++)if(s[i]!='0')break;return s.substr(i);}\nstring ADD(string s,string t) {\n if(s.size()<t.size())swap(s,t);s='0'+s;\n while(s.size()>t.size())t='0'+t;int c=0;\n for(int i=s.size()-1; i>=0; i--) {\n if(c){if(s[i]=='9'){s[i]='0';c=1;}else{s[i]=(char)(s[i]+1);c=0;}}\n int sum=(int)s[i]+(int)t[i]-'0'*2;\n if(sum>=10){s[i]=(char)(sum-10+'0');c=1;}\n else s[i]=(char)(sum+'0');\n }\n return Z(s);\n}\nstring MUL(string s,string t) {\n string z1=\"\",ans=\"\";\n for(int i=t.size()-1; i>=0; i--) {\n string z2=\"\",r=\"\";\n for(int j=s.size()-1; j>=0; j--){r=ADD(r,S((s[j]-'0')*(t[i]-'0'))+z2);z2+=\"0\";}\n ans=ADD(ans,r+z1);z1+=\"0\";\n }\n return Z(ans);\n}\nstring a[]={\"\",\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"};\n\nint main() {\n int n;\n string m;\n while(cin >> m >> n && n) {\n string s=\"1\";\n for(int i=0; i<n; i++) s=MUL(s,m);\n string ans=\"\";\n for(int i=s.size()-4,k=0; i>=-3; k++,i-=4) {\n int d=min(4,4+i);\n string t=s.substr(max(0,i),d);\n int x=N(t);\n if(!x) continue;\n t=S(x);\n ans=t+a[k]+ans;\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 1248, "score_of_the_acc": -0.9607, "final_rank": 4 }, { "submission_id": "aoj_0287_1583336", "code_snippet": "#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <map>\n#include <set>\n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <cstdio>\n#include <cstring>\n#include <iterator>\n#include <bitset>\n#include <unordered_set>\n#include <unordered_map>\n#include <fstream>\n#include <iomanip>\n#include <cassert>\n//#include <utility>\n//#include <memory>\n//#include <functional>\n//#include <deque>\n//#include <cctype>\n//#include <ctime>\n//#include <numeric>\n//#include <list>\n//#include <iomanip>\n\n//#if __cplusplus >= 201103L\n//#include <array>\n//#include <tuple>\n//#include <initializer_list>\n//#include <forward_list>\n//\n//#define cauto const auto&\n//#else\n\n//#endif\n\nusing namespace std;\n\n\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\n\ntypedef vector<int> vint;\ntypedef vector<vector<int> > vvint;\ntypedef vector<long long> vll, vLL;\ntypedef vector<vector<long long> > vvll, vvLL;\n\n#define VV(T) vector<vector< T > >\n\ntemplate <class T>\nvoid initvv(vector<vector<T> > &v, int a, int b, const T &t = T()){\n v.assign(a, vector<T>(b, t));\n}\n\ntemplate <class F, class T>\nvoid convert(const F &f, T &t){\n stringstream ss;\n ss << f;\n ss >> t;\n}\n\n#undef _P\n#define _P(...) (void)printf(__VA_ARGS__)\n#define reep(i,a,b) for(int i=(a);i<(b);++i)\n#define rep(i,n) reep((i),0,(n))\n#define ALL(v) (v).begin(),(v).end()\n#define PB push_back\n#define F first\n#define S second\n#define mkp make_pair\n#define RALL(v) (v).rbegin(),(v).rend()\n#define DEBUG\n#ifdef DEBUG\n#define dump(x) cout << #x << \" = \" << (x) << endl;\n#define debug(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << \" \" << __FILE__ << endl;\n#else\n#define dump(x) \n#define debug(x) \n#endif\n\n#define MOD 1000000007LL\n#define EPS 1e-8\n#define INF 0x3f3f3f3f\n#define INFL 0x3f3f3f3f3f3f3f3fLL\n#define maxs(x,y) x=max(x,y)\n#define mins(x,y) x=min(x,y)\n\nstring add(string a,string b){\n\tif(a.size()<b.size()) swap(a,b);\n\twhile(a.size()!=b.size()) b='0'+b;\n\tstring ret=\"\";\n\tint t=0;\n\treverse(ALL(a));\n\treverse(ALL(b));\n\trep(i,a.size()){\n\t\tret=char('0'+(t+a[i]+b[i]-'0'-'0')%10)+ret;\n\t\tif((t+a[i]+b[i]-'0'-'0')>=10) t=1;\n\t\telse t=0;\n\t}\n\tif(t) ret='1'+ret;\n\treturn ret;\n}\nstring pro(string a,int b){\n\tstring ret=\"0\";\n\trep(i,b) ret=add(ret,a);\n\treturn ret;\n}\n\n\nvoid mainmain(){\n\tint m,n;\n\tvector<__int128> v(17);\n\tstring a[]={\n\t\t\"Man\",\n\t\t\"Oku\",\n\t\t\"Cho\",\n\t\t\"Kei\",\n\t\t\"Gai\",\n\t\t\"Jo\",\n\t\t\"Jou\",\n\t\t\"Ko\",\n\t\t\"Kan\",\n\t\t\"Sei\",\n\t\t\"Sai\",\n\t\t\"Gok\",\n\t\t\"Ggs\",\n\t\t\"Asg\",\n\t\t\"Nyt\",\n\t\t\"Fks\",\n\t\t\"Mts\",\n\t};\n\t__int128 tmp=1;\n\trep(i,17){\n\t\ttmp*=10000;\n\t\tv[i]=tmp;\n\t}\n\twhile(cin>>m>>n,m){\n\t\tstring s=\"1\";\n\t\trep(i,n){\n\t\t\ts=pro(s,m);\n\t\t}\n\t\t// cout<<s<<endl;\n\t\treverse(ALL(s));\n\t\tfor(int i=17;i>=1;i--){\n\t\t\tif(s.size()<=4*i) continue;\n\t\t\tstring t=s.substr(i*4,4);\n\t\t\treverse(ALL(t));\n\t\t\tint tt;\n\t\t\tconvert(t,tt);\n\t\t\tif(tt==0) continue;\n\t\t\tcout<<tt<<a[i-1];\n\t\t}\n\t\tstring t=s.substr(0,4);\n\t\treverse(ALL(t));\n\t\tint tt;\n\t\tconvert(t,tt);\n\t\tif(tt) cout<<tt;\n\t\tcout<<endl;\n\t}\n}\n\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout<<fixed<<setprecision(20);\n mainmain();\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3216, "score_of_the_acc": -0.9642, "final_rank": 6 }, { "submission_id": "aoj_0287_1363363", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int MAX_D=400;\nstruct Integer{\n Integer(int i=0):n(0){\n fill_n(digits,MAX_D,0);\n while(i){digits[n++]=i%10;i/=10;}\n }\n int digits[MAX_D],n;\n};\nInteger operator*(const Integer& lhs,const Integer& rhs){\n Integer res;\n for(int i=0;i<MAX_D;i++){\n for(int j=0;j<MAX_D;j++){\n if(i+j>=MAX_D)continue;\n int x=lhs.digits[i]*rhs.digits[j]+res.digits[i+j];\n res.digits[i+j]=x%10;\n if(i+j+1<MAX_D)res.digits[i+j+1]+=x/10;\n }\n }\n return res;\n}\n\nconst string unit[]={\n \"\",\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\n \"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\",\n};\nint main(){\n int N,M;\n while(scanf(\"%d%d\",&M,&N),N||M){\n Integer a(M),num(1);\n while(N){\n if(N&1)num=num*a;\n a=a*a;\n N>>=1;\n }\n\n\n int mx;\n for(int i=MAX_D-1;i>=0;i--){\n if(num.digits[i]!=0){\n mx=i;\n break;\n }\n }\n for(int i=mx;i>=0;){\n int x=0;\n while(true){\n x=x*10+num.digits[i];\n if(i%4==0)break;\n i--;\n }\n if(x>0){\n cout<<x<<unit[i/4];\n }\n i--;\n }\n cout<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 1232, "score_of_the_acc": -1.0301, "final_rank": 7 }, { "submission_id": "aoj_0287_1251758", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std ;\n\n// ???????¨? ??? ???????????????\nmain(){\n\tint n,m ;\n\tstring Jkk[] = {\"\",\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\n\t\t\t\t\t\"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"} ;\n\twhile( cin >> m >> n , m ){\n\t\tint c[10000] = {} , mx = 1 ;\n\t\tc[0] = m%10 ; c[1] = m/10 ;\n\t\tif( c[1] ) mx++ ;\n\t\t\n\t\tfor( int i=1 ; i<n ; i++ ){\n\t\t\tint tmp[10000] = {} ;\n\t\t\tfor( int j=0 ; j<m ; j++ ){\n\t\t\t\tint k ;\n\t\t\t\tfor( k=0 ; k<mx ; k++ ){\n\t\t\t\t\ttmp[k] += c[k] ;\n\t\t\t\t\ttmp[k+1] += tmp[k]/10 ;\n\t\t\t\t\ttmp[k] %= 10 ;\n\t\t\t\t}\n\t\t\t\tif( tmp[k] ) mx++ ;\n\t\t\t}\n\t\t\tswap(tmp,c) ;\n\t\t}\n\t\t\n\t\tint st = (mx-1)/4 ;\n\t\tif( st >= 17 ) st = 17 ;\n\t\tint flg = 0 ;\n\t\tfor( int i=mx-1 ; i>=0 ; i-- ){\n\t\t\tif( i%4 == 3 ) flg = 0 ;\n\t\t\tif( c[i] != 0 ) flg = 1 ;\n\t\t\tif( flg != 0 ) cout << c[i] ;\n\t\t\tif( i%4 == 0 && flg ) cout << Jkk[st] ;\n\t\t\tif( i%4 == 0 && i/4 - 1 <= 16 ) st-- ;\n\t\t}\n\t\tcout << endl ;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1292, "score_of_the_acc": -0.1353, "final_rank": 2 }, { "submission_id": "aoj_0287_1246158", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std ;\n\nmain(){\n\tint n,m ;\n\tstring Jkk[] = {\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\n\t\t\t\t\t\"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"} ;\n\twhile( cin >> m >> n , m ){\n\t\tint c[10000] = {} , mx = 1 ;\n\t\tc[0] = m%10 ; c[1] = m/10 ;\n\t\tif( c[1] ) mx++ ;\n\t\t\n\t\tfor( int i=1 ; i<n ; i++ ){\n\t\t\tint tmp[10000] = {} ;\n\t\t\tfor( int j=0 ; j<m ; j++ ){\n\t\t\t\tint k ;\n\t\t\t\tfor( k=0 ; k<mx ; k++ ){\n\t\t\t\t\ttmp[k] += c[k] ;\n\t\t\t\t\ttmp[k+1] += tmp[k]/10 ;\n\t\t\t\t\ttmp[k] %= 10 ;\n\t\t\t\t}\n\t\t\t\tif( tmp[k] ) mx++ ;\n\t\t\t}\n\t\t\tswap(tmp,c) ;\n\t\t}\n\t\tint st = mx/4 - 1 ;\n\t\tif( st >= 16 ) st = 16 ;\n\t\tint flg = 0 ;\n\t\tfor( int i=mx-1 ; i>=0 ; i-- ){\n\t\t\tif( i%4 == 3 ) flg = 0 ;\n\t\t\tif( c[i] != 0 ) flg = 1 ;\n\t\t\tif( flg != 0 ) cout << c[i] ;\n\t\t\tif( i%4 == 0 ){\n\t\t\t\tif( flg && i/4 - 1 <= 16 && i!= 0 ) cout << Jkk[st] ;\n\t\t\t\tif( i/4 - 1 <= 16 ) st-- ;\n\t\t\t}\n\t\t}\n\t\tcout << endl ;\n\t}\n}", "accuracy": 0.25, "time_ms": 10, "memory_kb": 1292, "score_of_the_acc": -0.0584, "final_rank": 10 }, { "submission_id": "aoj_0287_1243919", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <iostream>\n\nconst std::string units[] = {\n \"\", \"Man\", \"Oku\", \"Cho\", \"Kei\", \"Gai\", \"Jo\",\n \"Jou\", \"Ko\", \"Kan\", \"Sei\", \"Sai\", \"Gok\", \"Ggs\",\n \"Asg\", \"Nyt\", \"Fks\", \"Mts\"\n};\nconst int MAX_D = 400;\n\nstruct Integer{\n Integer(int i = 0){\n memset(digits, 0, sizeof(digits));\n n = 0;\n \n while(i > 0){\n digits[n++] = i % 10;\n i /= 10;\n }\n }\n Integer(const std::string& s){\n memset(digits, 0, sizeof(digits));\n n = 0;\n \n bool f = false;\n for(int j=(int)s.size()-1;j>=0;j--){\n if(!std::isdigit(s[j])){continue;}\n \n if(s[j] != '0'){\n digits[n++] = s[j] - '0';\n f = true;\n }else if(f){\n digits[n++] = s[j] - '0';\n }\n }\n }\n int digits[MAX_D], n;\n};\n\nInteger operator*(const Integer& lhs, const Integer& rhs){\n Integer res;\n for(int i=0;i<MAX_D;i++){\n for(int j=0;j<MAX_D;j++){\n if(i + j >= MAX_D){continue;}\n int x = lhs.digits[i] * rhs.digits[j] + res.digits[i+j];\n res.digits[i+j] = x % 10;\n if(i + j + 1 < MAX_D){\n res.digits[i+j+1] += x / 10;\n }\n }\n }\n \n return res;\n}\n\nInteger operator+(const Integer& lhs, const Integer& rhs){\n Integer res;\n for(int i=0;i<MAX_D;i++){\n int x = lhs.digits[i] + rhs.digits[i] + res.digits[i];\n res.digits[i] = x % 10;\n if(i+1 < MAX_D){\n res.digits[i+1] = x / 10;\n }\n }\n \n return res;\n}\n\nint main(){\n int M, N;\n while(scanf(\"%d %d\", &M, &N), M || N){\n Integer num(1), a(M);\n while(N > 0){\n if(N & 1){num = num * a;}\n a = a * a;\n N >>= 1;\n }\n\n int mx;\n bool f = false;\n for(int i=MAX_D-1;i>=0;i--){\n if(num.digits[i] != 0){f = true;}\n\n if(f){\n mx = i;\n break;\n } \n }\n \n std::string S = \"\";\n for(int i=mx;i>=0;){\n int x = 0;\n while(true){\n x = x * 10 + num.digits[i];\n if(i % 4 == 0){break;}\n i--;\n }\n if(x > 0){\n S += std::to_string(x) + units[i/4];\n }\n i--;\n }\n\n std::cout << S << std::endl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 1248, "score_of_the_acc": -0.9607, "final_rank": 4 }, { "submission_id": "aoj_0287_1243113", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring tani[]={\n\t\"\",\"Man\",\"Oku\",\"Cho\",\"Kei\",\"Gai\",\"Jo\",\"Jou\",\"Ko\",\"Kan\",\"Sei\",\"Sai\",\"Gok\",\"Ggs\",\"Asg\",\"Nyt\",\"Fks\",\"Mts\"\n};\n\n\nstring add(string a,string b){\n\tif(a.size()<b.size())swap(a,b);\n\twhile(a.size()>b.size())b=\"0\"+b;\n\tint c=0;\n\tfor(int i=a.size()-1;i>=0;i--){\n\t\ta[i]+=(b[i]-'0'+c);\n\t\tif(a[i]>'9'){\n\t\t\ta[i]-=10;\n\t\t\tc=1;\n\t\t}\n\t\telse c=0;\n\t}\n\tif(c)a=\"1\"+a;\n\treturn a;\n}\n\nstring x10(string a,int n){\n\twhile(n--)a+=\"0\";\n\treturn a;\n}\n\nstring mlt(string a,string b){\n\tstring tmp[10];\n\ttmp[0]=\"0\";\n\ttmp[1]=a;\n\tfor(int i=2;i<=9;i++)tmp[i]=add(tmp[i-1],a);\n\tstring res=tmp[b[b.size()-1]-'0'];\n\tfor(int i=1;i<b.size();i++){\n\t\tres=add(res,x10(tmp[b[b.size()-1-i]-'0'],i));\n\t}\n\treturn res;\n}\n\nstring pow(string a,int n){\n\tstring res=a;\n\tfor(n--;n--;)res=mlt(res,a);\n\treturn res;\n}\n\nint main(){\n\t\n\tstring s;\n\tint n;\n\twhile(cin>>s>>n){\n\t\tif(s==\"0\"&&n==0)break;\n\t\tstring ans=pow(s,n);\n\t\treverse(ans.begin(),ans.end());\n\t\tvector<string>V;\n\t\tfor(int i=0;i<ans.size();i+=4){\n\t\t\tstring tmp=\"\";\n\t\t\tfor(int j=0;j<4;j++){\n\t\t\t\tif(i+j>=ans.size())break;\n\t\t\t\ttmp+=ans[i+j];\n\t\t\t}\n\t\t\treverse(tmp.begin(),tmp.end());\n\t\t\tV.push_back(tmp);\n\t\t}\n\t\treverse(V.begin(),V.end());\n\t\tfor(int i=0;i<V.size();i++){\n\t\t\tif(V[i]==\"0000\")continue;\n\t\t\twhile(V[i][0]=='0')V[i]=V[i].substr(1);\n\t\t\tcout<<V[i];\n\t\t\tcout<<tani[V.size()-i-1];\n\t\t}\n\t\tcout<<endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": -0.0264, "final_rank": 1 }, { "submission_id": "aoj_0287_1191802", "code_snippet": "#include<iostream>\nusing namespace std;\n\nvoid make_name(char *dist[]);\nchar *name[20];\nint m, n;\n\n//data[i]はi桁目(10進数)、これをn乗。\nvoid pwd(int *data, int n) {\n\tint i, j, k;\n\tint BigNum[201] = {0}, MBigNum[201] = {0};\n\t\n\tBigNum[0] = 1;\n\tfor( i = 0; i < n; i++ ) {\n\t\tfor( j = 0; j < 100; j++ ) {\n\t\t\tfor( k = 0; k < 100; k++ ) {\n\t\t\t\tMBigNum[j+k] += BigNum[j] * data[k];\n\t\t\t\tMBigNum[j+k+1] += MBigNum[j+k]/10;\n\t\t\t\tMBigNum[j+k] %= 10;\n\t\t\t}\n\t\t}\n\t\tfor( j = 0; j < 100; j++ ) {\n\t\t\tBigNum[j] = MBigNum[j];\n\t\t\tMBigNum[j] = 0;\n\t\t}\n\t}\n\t\n\tfor( j = 0; j < 100; j++ ) {\n\t\tdata[j] = BigNum[j];\n\t}\n}\n\nint main() {\n\tint i;\n\tint BigNum[200] = {0};\n\tmake_name(name);\n\twhile(cin >> m >> n) {\n\t\tif(!m) break;\n\t\tBigNum[0] = m%10;\n\t\tBigNum[1] = m/10;\n\t\tpwd(BigNum, n);\n\t\tint l, r;\n\t\tfor(i = 0; i < 100; i++ ) {\n\t\t\tif( BigNum[i] )\n\t\t\t\tbreak;\n\t\t}\n\t\tl = i;\n\t\tfor(i = 99; i >= 0; i--) {\n\t\t\tif( BigNum[i] )\n\t\t\t\tbreak;\n\t\t}\n\t\tr = i;\n\t\t\n\t\tbool disp0 = true;\n\t\tfor(i = r; i >= l; i--) {\n\t\t\tif( BigNum[i] == 0 && !disp0 )\n\t\t\t\tcontinue;\n\t\t\tcout << BigNum[i];\n\t\t\tif( BigNum[i] != 0 ) {\n\t\t\t\tdisp0 = true;\n\t\t\t}\n\t\t\tif( i % 4 == 0 ) {\n\t\t\t\tcout << name[i/4];\n\t\t\t\tdisp0 = false;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif( i % 4 != 3)\n\t\t\tl = i/4 * 4;\n\t\telse\n\t\t\tl = i+1;\n\t\tfor(; i >= l; i--) {\n\t\t\tcout << BigNum[i];\n\t\t\tif( i % 4 == 0 ) {\n\t\t\t\tcout << name[i/4];\n\t\t\t}\n\t\t}\n\t\tcout << endl;\n\t\t\n\t\tfor( i = 0; i < 100; i++ )\n\t\t\tBigNum[i] = 0;\n\t}\n\treturn 0;\n}\n\nvoid make_name(char *dist[]) {\n\tdist[0] = \"\";\n\tdist[1] = \"Man\";\n\tdist[2] = \"Oku\";\n\tdist[3] = \"Cho\";\n\tdist[4] = \"Kei\";\n\tdist[5] = \"Gai\";\n\tdist[6] = \"Jo\";\n\tdist[7] = \"Jou\";\n\tdist[8] = \"Ko\";\n\tdist[9] = \"Kan\";\n\tdist[10] = \"Sei\";\n\tdist[11] = \"Sai\";\n\tdist[12] = \"Gok\";\n\tdist[13] = \"Ggs\";\n\tdist[14] = \"Asg\";\n\tdist[15] = \"Nyt\";\n\tdist[16] = \"Fks\";\n\tdist[17] = \"Mts\";\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 1168, "score_of_the_acc": -0.6923, "final_rank": 3 } ]
aoj_0286_cpp
親方の給料計算 ワシはパイプつなぎ組合の親方じゃ。職人を工事現場に派遣し、現場でパイプをつながせておる。去年は工事が増えて大儲けするかと思ったのじゃが、ちょっと給料の出し方がまずくてのぅ。ウチとしては大赤字になってしまったのじゃよ…。そこで、今年は職人たちへの給料の出し方を工夫したいのじゃ。 職人たちの給料は、工事の種類とこなした回数で決めておる。つまり、 職人の給料 = 種類 1 の単価 × 種類 1 をこなした回数 + 種類 2 の単価 × 種類 2 をこなした回数 .... + 種類 M の単価 × 種類 M をこなした回数 となるのじゃ。これを計算するために、ウチでは、どの職人がどの種類の工事を何回こなしたかを次のような表に記録しておる。 例えば、上の表では、職人1が工事2を2回、工事4を1回こなしたことを示しておる。 職人たちがこなした仕事の回数はもう変えられんが、やつらは工事の単価を知らんので、単価をいろいろと変えながら皆の不満が出ぬよう給料を調整しようと思うておる。じゃが、ワシがこしらえたプログラムが今もって動かなくてのぅ。ちょっとみてくれんかね。 //省略 int i, j; for ( i = 0; i < N; i++ ){ c[i] = 0; for ( j = 0; j < M; j++ ){ c[i] = c[i] + a[i][j]*b[j]; } } //省略 N は職人の数で M は工事の種類の数じゃ。変数 a[i][j] に職人iが工事 j をこなした回数を、 b[j] に工事 j の単価をいれて、 c[i] に職人 i の給料を格納しておる。合っているはずなのに、うんともすんとも言わん!そろそろ今年の給料を職人たちに払わないとまずいのじゃが・・・・・なんとかならんかのぅ。 それでは、職人のこなした仕事の回数と各工事の単価の情報が与えられたとき、各職人の給料を計算するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 N M s 1 t 1 e 1 s 2 t 2 e 2 : 0 0 0 L b 11 b 12 ... b 1M b 21 b 22 ... b 2M : b L1 b L2 ... b LM 1行目は職人の数 N (1 ≤ N ≤ 10000)と工事の種類の数 M (1 ≤ M ≤ 10000)。 続いて、工事の記録として、職人の番号 s i (1 ≤ s i ≤ N ) と工事の種類の番号 t i (1 ≤ t i ≤ M )、および職人 s i が工事 t i をこなした回数 e i (1 ≤ e i ≤ 50000) からなる行が1行以上与えられる。工事の記録はゼロ3つの行で終わる。ただし、 e i の合計は 1 以上 50000 以下である。また、工事の記録には、どの職人と工事の種類の組も2度以上現れない。工事をこなした回数が 0 である職人と工事の種類の組は与えられない。 続く 1 行は給料の算出を行う回数 L (1 ≤ L ≤ 100) 。 続く L 行は、 i 回目の給料の算出に必要な、工事 j の単価 b ij (0 ≤ b ij ≤ 10000) の並び。 出力 以下の形式で、 i 回目の給料の算出によって得られた職人 j の給料 c ij を順番に出力する。各給料の間は空白1つで区切る。 c 11 c 12 ... c 1N c 21 c 22 ... c 2N : c L1 c L2 ... c LN 入出力例 入力例 4 6 1 2 1 2 3 2 2 4 3 3 1 5 4 2 4 4 3 2 4 6 10 0 0 0 3 1 3 2 4 0 10 6 5 4 3 2 1 5 1 1 5 5 1 出力例 3 16 5 116 5 17 30 38 1 17 25 16
[ { "submission_id": "aoj_0286_11031173", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N, M;\n\tcin >> N >> M;\n\tvector<int> S, T, E;\n\twhile (true) {\n\t\tint s, t, e;\n\t\tcin >> s >> t >> e;\n\t\tif (s == 0 && t == 0 && e == 0) break;\n\t\tS.push_back(s - 1);\n\t\tT.push_back(t - 1);\n\t\tE.push_back(e);\n\t}\n\t\n\tint L;\n\tcin >> L;\n\tvector B(L, vector<ll>(M));\n\trep(i, 0, L) rep(j, 0, M) cin >> B[i][j];\n\t\n\tvector C(L, vector<ll>(N));\n\t\n\trep(i, 0, S.size()) {\n\t\trep(j, 0, L) C[j][S[i]] += E[i]*B[j][T[i]];\n\t}\n\t\n\trep(i, 0, L) {\n\t\trep(j, 0, N) cout << C[i][j] << (j == N - 1 ? '\\n' : ' ');\n\t}\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 19324, "score_of_the_acc": -0.1851, "final_rank": 17 }, { "submission_id": "aoj_0286_9670350", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, M;\n cin >> N >> M; // Number of craftsmen and job types\n\n vector<vector<pair<int, int>>> jobs(N); // Store {type, count} pairs for each craftsman\n\n // Read the job records\n while (true) {\n int s, t, e;\n cin >> s >> t >> e;\n if (s == 0 && t == 0 && e == 0) break;\n s--; t--; // To use 0-based indexing\n jobs[s].emplace_back(t, e);\n }\n\n int L;\n cin >> L; // Number of salary queries\n\n // Process each salary query\n for (int query = 0; query < L; query++) {\n vector<int> unit_price(M); // Unit prices for current query\n for (int i = 0; i < M; i++) {\n cin >> unit_price[i];\n }\n\n // Calculate salary for each craftsman\n vector<int> salary(N, 0);\n for (int i = 0; i < N; i++) {\n for (auto job : jobs[i]) {\n int job_type = job.first;\n int job_count = job.second;\n salary[i] += job_count * unit_price[job_type];\n }\n }\n\n // Output the salaries\n for (int i = 0; i < N; i++) {\n cout << salary[i] << (i == N - 1 ? \"\\n\" : \" \");\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 4192, "score_of_the_acc": -0.0787, "final_rank": 7 }, { "submission_id": "aoj_0286_9195924", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, M, s, t, e, L, b;\n cin >> N >> M;\n vvc<pi> te(M);\n while (true) {\n cin >> s >> t >> e;\n if (s == 0 and t == 0 and e == 0) break;\n s--; t--;\n te[t].eb(mp(s, e));\n }\n cin >> L;\n rep(L) {\n vi salary(N, 0);\n rep(i, M) {\n cin >> b;\n rep(j, len(te[i])) {\n salary[te[i][j].fi] += b * te[i][j].se;\n }\n }\n print(salary);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4984, "score_of_the_acc": -0.0131, "final_rank": 2 }, { "submission_id": "aoj_0286_8407280", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n int a,b;\n cin>>a>>b;\n int x[a];\n int y[b];\n map<pair<int,int>,int> t;\n while(true){\n int c,d,e;\n cin>>c>>d>>e;\n if(c==d&&d==e&&e==0){\n break;\n }\n pair<int,int> f=make_pair(c,d);\n t[f]=e;\n }\n int r;\n cin>>r;\n for(int i=0;i<r;i+=1){\n for(int j=0;j<a;j+=1){\n x[j]=0;\n }\n for(int j=0;j<b;j+=1){\n cin>>y[j];\n }\n for(auto p:t){\n x[p.first.first-1]+=y[p.first.second-1]*p.second;\n }\n for(int j=0;j<a;j+=1){\n cout<<x[j];\n if(j<a-1){\n cout<<\" \";\n }\n }\n cout<<endl;\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 6620, "score_of_the_acc": -0.1693, "final_rank": 15 }, { "submission_id": "aoj_0286_8407229", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n int a,b;\n cin>>a>>b;\n int x[a][b];\n int y[b];\n for(int i=0;i<a;i+=1){\n for(int j=0;j<b;j+=1){\n x[i][j]=0;\n }\n }\n while(true){\n int c,d,e;\n cin>>c>>d>>e;\n if(c==d&&d==e&&e==0){\n break;\n }\n x[c-1][d-1]=e;\n }\n int r;\n cin>>r;\n for(int i=0;i<r;i+=1){\n for(int j=0;j<b;j+=1){\n cin>>y[j];\n }\n for(int j=0;j<a;j+=1){\n int w=0;\n for(int k=0;k<b;k+=1){\n w+=x[j][k]*y[k];\n }\n cout<<w;\n if(j<a-1){\n cout<<\" \";\n }\n }\n cout<<endl;\n }\n}", "accuracy": 0.8, "time_ms": 1310, "memory_kb": 101016, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0286_8406176", "code_snippet": "#include <iostream>\n#include <vector>\n\n\nint main()\n{\n\tsize_t n, m;\n\tstd::cin >> n >> m;\n\tstd::vector<std::vector<std::pair<size_t, int>>> records(n);\n\tfor (; ; ) {\n\t\tsize_t s, t;\n\t\tint e;\n\t\tstd::cin >> s >> t >> e;\n\t\tif (s == 0 && t == 0 && e == 0) {\n\t\t\tbreak;\n\t\t}\n\t\trecords[s - 1].emplace_back(t - 1, e);\n\t}\n\n\tsize_t l;\n\tstd::cin >> l;\n\tfor (auto i = size_t(0); i < l; ++i) {\n\t\tstd::vector<int> b(m);\n\t\tfor (auto j = size_t(0); j < m; ++j) {\n\t\t\tstd::cin >> b[j];\n\t\t}\n\n\t\tfor (auto j = size_t(0); j < n; ++j) {\n\t\t\tauto c = 0;\n\t\t\tfor (const auto& a : records[j]) {\n\t\t\t\tc += a.second * b[a.first];\n\t\t\t}\n\t\t\tif (j > 0) {\n\t\t\t\tstd::cout << \" \";\n\t\t\t}\n\t\t\tstd::cout << c;\n\t\t}\n\t\tstd::cout << std::endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 4696, "score_of_the_acc": -0.0839, "final_rank": 8 }, { "submission_id": "aoj_0286_6896585", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int N, M, s, t, e, L;\n cin >> N >> M;\n vector<vector<pair<int,ll>>> tb(N);\n while(cin >> s >> t >> e, s){\n tb[--s].emplace_back(--t, e);\n }\n cin >> L;\n while(L--){\n vector<ll> ans(N), cost(M);\n for(auto &&v:cost)cin >> v;\n for(int i = 0; i < N; i++){\n for(int j = 0; j < tb[i].size(); j++){\n ans[i] += cost[tb[i][j].first] * tb[i][j].second;\n }\n if(i)cout << \" \";\n cout << ans[i];\n }\n cout << '\\n';\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 4832, "score_of_the_acc": -0.0853, "final_rank": 9 }, { "submission_id": "aoj_0286_5967771", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-12, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\nclass UnionFind {\npublic:\n vector <ll> par; \n vector <ll> siz; \n \n vector <ll> maxv;\n UnionFind(ll sz_): par(sz_), siz(sz_, 1LL) {\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n void init(ll sz_) {\n par.resize(sz_);\n siz.assign(sz_, 1LL);\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n \n ll root(ll x) { \n while (par[x] != x) {\n x = par[x] = par[par[x]];\n }\n return x;\n }\n \n bool merge(ll x, ll y) {\n x = root(x);\n y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n \n bool issame(ll x, ll y) { \n return root(x) == root(y);\n }\n \n ll size(ll x) { \n return siz[root(x)];\n }\n};\nint main()\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n \n int n, m; cin >> n >> m;\n int s, t, e;\n vector<ll> ss, tt, ee;\n while(cin >> s >> t >> e) {\n if(s == 0 && t == 0 && e == 0) break;\n s--; t--;\n ss.push_back(s);\n tt.push_back(t);\n ee.push_back(e);\n }\n\n int L; cin >> L;\n vector<vector<ll>> ans(L, vector<ll>(n));\n vector<vector<ll>> b(L, vector<ll>(m));\n REP(i,L) {\n REP(j,m) cin >> b[i][j];\n }\n REP(i,ss.size()) {\n REP(j,L) {\n s = ss[i];\n t = tt[i];\n e = ee[i];\n ans[j][s] += b[j][t] * e;\n }\n }\n REP(i,L) {\n REP(j,n) {\n if(j) cout << \" \";\n cout << ans[i][j];\n }\n cout << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 19796, "score_of_the_acc": -0.1899, "final_rank": 18 }, { "submission_id": "aoj_0286_5948246", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N, M;\n cin >> N >> M;\n vector<int> s, t, e;\n int cnt = 0;\n while (true){\n int s2, t2, e2;\n cin >> s2 >> t2 >> e2;\n if (s2 == 0 && t2 == 0 && e2 ==0){\n break;\n }\n s2--;\n t2--;\n s.push_back(s2);\n t.push_back(t2);\n e.push_back(e2);\n cnt++;\n }\n int L;\n cin >> L;\n for (int i = 0; i < L; i++){\n vector<int> b(M);\n for (int j = 0; j < M; j++){\n cin >> b[j];\n }\n vector<int> c(N, 0);\n for (int j = 0; j < cnt; j++){\n c[s[j]] += b[t[j]] * e[j];\n }\n for (int j = 0; j < N; j++){\n cout << c[j];\n if (j < N - 1){\n cout << ' ';\n }\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3876, "score_of_the_acc": -0.0673, "final_rank": 4 }, { "submission_id": "aoj_0286_5921314", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n// {{{\n\n// clang-format off\n#define len(x) (static_cast<int>((x).size()))\n#define _over_load(_1,_2,_3,_4,NAME,...) NAME\n#define range(...) _over_load(__VA_ARGS__, range4, range3, range2)(__VA_ARGS__)\n#define range2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define range3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define range4(i, l, r, step) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (step))\n#define rrange(...) _over_load(__VA_ARGS__, rrange4, rrange3, rrange2)(__VA_ARGS__)\n#define rrange2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrange3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrange4(i, l, r, step) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (step))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename T, typename... T2> void debug_function(string_view name, const T &a, T2 &&...rest) {\n stack<char> bs;\n string_view lbs = \"({[<\", rbs = \")}]>\";\n int end = name.size();\n for ( int i = 0; i < len(name); i++ ) {\n if ( lbs.find(name[i]) != string::npos ) bs.push(name[i]);\n if ( rbs.find(name[i]) != string::npos and !bs.empty() ) bs.pop();\n if ( name[i] == ',' and bs.empty() ) {\n end = i;\n break;\n }\n }\n cerr << name.substr(0, end) << \":\" << a;\n if constexpr ( sizeof...(rest) == 0 ) {\n cerr << '\\n';\n } else {\n cerr << ' ';\n debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<T2>(rest)...);\n }\n}\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << p.first << ' ' << p.second; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { for ( pair<T1, T2> x : v ) { os << \"(\" << x.first <<\", \" << x.second << \")\" << (v.rbegin()->first == x.first ? \"\" : \", \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { if(!v.empty()) { os << v.front(); v.pop(); } while (!v.empty()) { os << \" \" << v.front(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { if(!v.empty()) { os << v.top(); v.pop(); } while (!v.empty()) { os << \" \" << v.top(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\nusing ull = unsigned long long;\nusing ll = long long;\nusing Pll = pair<ll, ll>;\nusing P = pair<int, int>;\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, -1, 1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { -1, 0, 0, 1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n// clang-format on\n\n// }}}\n\n\n\nint main() {\n int n,m;\n cin>>n>>m;\n\n vector<map<int,int>> cnts(n);\n while(1){\n int s,t,e;\n cin>>s>>t>>e;\n if(s==0 and t==0 and e==0) break;\n s--,t--;\n cnts[s][t]+=e;\n }\n\n int l;\n cin>>l;\n auto bs = make_vector(l,m,0LL);\n range(i,l){\n range(j,m){\n cin>>bs[i][j];\n }\n }\n\n range(i,l){\n auto cs = make_vector(n,0LL);\n range(j,n){\n for(auto [job,cnt]:cnts[j]){\n cs[j]+=cnt*bs[i][job];\n }\n }\n cout<<cs<<newl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 13764, "score_of_the_acc": -0.1361, "final_rank": 12 }, { "submission_id": "aoj_0286_5921312", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n// {{{\n\n// clang-format off\n#define len(x) (static_cast<int>((x).size()))\n#define _over_load(_1,_2,_3,_4,NAME,...) NAME\n#define range(...) _over_load(__VA_ARGS__, range4, range3, range2)(__VA_ARGS__)\n#define range2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define range3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define range4(i, l, r, step) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (step))\n#define rrange(...) _over_load(__VA_ARGS__, rrange4, rrange3, rrange2)(__VA_ARGS__)\n#define rrange2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrange3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrange4(i, l, r, step) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (step))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename T, typename... T2> void debug_function(string_view name, const T &a, T2 &&...rest) {\n stack<char> bs;\n string_view lbs = \"({[<\", rbs = \")}]>\";\n int end = name.size();\n for ( int i = 0; i < len(name); i++ ) {\n if ( lbs.find(name[i]) != string::npos ) bs.push(name[i]);\n if ( rbs.find(name[i]) != string::npos and !bs.empty() ) bs.pop();\n if ( name[i] == ',' and bs.empty() ) {\n end = i;\n break;\n }\n }\n cerr << name.substr(0, end) << \":\" << a;\n if constexpr ( sizeof...(rest) == 0 ) {\n cerr << '\\n';\n } else {\n cerr << ' ';\n debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<T2>(rest)...);\n }\n}\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << p.first << ' ' << p.second; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { for ( pair<T1, T2> x : v ) { os << \"(\" << x.first <<\", \" << x.second << \")\" << (v.rbegin()->first == x.first ? \"\" : \", \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { if(!v.empty()) { os << v.front(); v.pop(); } while (!v.empty()) { os << \" \" << v.front(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { if(!v.empty()) { os << v.top(); v.pop(); } while (!v.empty()) { os << \" \" << v.top(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\nusing ull = unsigned long long;\nusing ll = long long;\nusing Pll = pair<ll, ll>;\nusing P = pair<int, int>;\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, -1, 1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { -1, 0, 0, 1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n// clang-format on\n\n// }}}\n\n\n\nint main() {\n int n,m;\n cin>>n>>m;\n\n vector<map<int,int>> cnts(n);\n while(1){\n int s,t,e;\n cin>>s>>t>>e;\n if(s==0 and t==0 and e==0) break;\n s--,t--;\n cnts[s][t]+=e;\n }\n\n int l;\n cin>>l;\n auto bs = make_vector(l,m,0LL);\n range(i,l){\n range(j,m){\n cin>>bs[i][j];\n }\n }\n\n range(i,l){\n auto cs = make_vector(n,0LL);\n range(j,n){\n for(auto [job,cnt]:cnts[j]){\n cs[j]+=cnt*bs[i][job];\n }\n }\n range(j,n){\n if(j) cout<<' ';\n cout<<cs[j];\n }\n cout<<newl;\n // cout<<cs<<newl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 13724, "score_of_the_acc": -0.1357, "final_rank": 10 }, { "submission_id": "aoj_0286_5921308", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n// {{{\n\n// clang-format off\n#define len(x) (static_cast<int>((x).size()))\n#define _over_load(_1,_2,_3,_4,NAME,...) NAME\n#define range(...) _over_load(__VA_ARGS__, range4, range3, range2)(__VA_ARGS__)\n#define range2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define range3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define range4(i, l, r, step) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (step))\n#define rrange(...) _over_load(__VA_ARGS__, rrange4, rrange3, rrange2)(__VA_ARGS__)\n#define rrange2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrange3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrange4(i, l, r, step) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (step))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename T, typename... T2> void debug_function(string_view name, const T &a, T2 &&...rest) {\n stack<char> bs;\n string_view lbs = \"({[<\", rbs = \")}]>\";\n int end = name.size();\n for ( int i = 0; i < len(name); i++ ) {\n if ( lbs.find(name[i]) != string::npos ) bs.push(name[i]);\n if ( rbs.find(name[i]) != string::npos and !bs.empty() ) bs.pop();\n if ( name[i] == ',' and bs.empty() ) {\n end = i;\n break;\n }\n }\n cerr << name.substr(0, end) << \":\" << a;\n if constexpr ( sizeof...(rest) == 0 ) {\n cerr << '\\n';\n } else {\n cerr << ' ';\n debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<T2>(rest)...);\n }\n}\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << p.first << ' ' << p.second; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { for ( pair<T1, T2> x : v ) { os << \"(\" << x.first <<\", \" << x.second << \")\" << (v.rbegin()->first == x.first ? \"\" : \", \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { if(!v.empty()) { os << v.front(); v.pop(); } while (!v.empty()) { os << \" \" << v.front(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { if(!v.empty()) { os << v.top(); v.pop(); } while (!v.empty()) { os << \" \" << v.top(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\nusing ull = unsigned long long;\nusing ll = long long;\nusing Pll = pair<ll, ll>;\nusing P = pair<int, int>;\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, -1, 1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { -1, 0, 0, 1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n// clang-format on\n\n// }}}\n\n\n\nint main() {\n int n,m;\n cin>>n>>m;\n\n vector<map<int,int>> cnts(n);\n while(1){\n int s,t,e;\n cin>>s>>t>>e;\n if(s==0 and t==0 and e==0) break;\n s--,t--;\n cnts[s][t]+=e;\n }\n\n int l;\n cin>>l;\n auto bs = make_vector(l,m,0LL);\n range(i,l){\n range(j,m){\n cin>>bs[i][j];\n }\n }\n\n range(i,l){\n auto cs = make_vector(n,0LL);\n range(j,n){\n for(auto [job,cnt]:cnts[j]){\n cs[j]+=cnt*bs[i][job];\n }\n }\n range(j,n){\n if(j) cout<<' ';\n cout<<cs[j];\n }\n cout<<newl;\n // cout<<cs<<newl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 13736, "score_of_the_acc": -0.1358, "final_rank": 11 }, { "submission_id": "aoj_0286_5921094", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\nstruct d{\n int s,t,e;\n};\nint main(){\n int n,m;cin>>n>>m;\n vector<d> A;\n int s,t,e;\n while(cin>>s>>t>>e,s){\n s--;t--;\n A.push_back({s,t,e});\n }\n int l;cin>>l;\n for(int i = 0; l > i; i++){\n vector<int> C(m);\n vector<int> ret(n);\n for(int j = 0; m > j; j++){\n cin>>C[j];\n }\n for(int j = 0; A.size() > j; j++){\n ret[A[j].s] += C[A[j].t]*A[j].e;\n }\n for(int j = 0; n > j; j++){\n cout << ret[j];\n if(j+1 != n)cout << \" \";\n }\n cout << endl;\n }\n\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 4008, "score_of_the_acc": -0.0687, "final_rank": 6 }, { "submission_id": "aoj_0286_5921074", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\nvvector<ll> func(){\n int n =in();\n int m=in();\n map<pii,ll> di;\n while(true){\n int i=in();\n int j=in();\n ll v = in();\n if(max<ll>({i,j,v})==0)break;\n di[pii(i-1,j-1)] = v;\n }\n vvector<ll> res;\n int l = in();\n rep(_,l){\n vector<ll> money(m);\n foreach(i,money)i=in();\n vector<ll> add(n,0);\n foreach(i,di){\n add[i.first.first] += money[i.first.second] * i.second;\n }\n res.emplace_back(add);\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n println(func());\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 14160, "score_of_the_acc": -0.1648, "final_rank": 14 }, { "submission_id": "aoj_0286_5730521", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nsigned main(){\n\tint n,m,s,t,e,l,b[10000];\n\tmap<int,int>mp[10000];\n\tcin>>n>>m;\n\twhile(cin>>s>>t>>e,e)\n\t\tmp[--s][--t]+=e;\n\tcin>>l;\n\tfor(int i=0;i<l;i++){\n\t\tfor(int j=0;j<m;j++)\n\t\t\tcin>>b[j];\n\t\tfor(int j=0;j<n;j++){\n\t\t\tint ans=0;\n\t\t\tfor(auto x:mp[j])\n\t\t\t\tans+=b[x.first]*x.second;\n\t\t\tcout<<ans<<(j==n-1?'\\n':' ');\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 7032, "score_of_the_acc": -0.1489, "final_rank": 13 }, { "submission_id": "aoj_0286_5193411", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n,m;\n cin >> n >> m;\n vector<int> a,b,c;\n while(1){\n int ai,bi,ci;\n cin >> ai >> bi >> ci;\n if(ci == 0) break;\n a.push_back(ai-1);\n b.push_back(bi-1);\n c.push_back(ci);\n }\n int l;\n cin >> l;\n for(int i=0; i<l; i++){\n vector<int> t(m);\n for(int i=0; i<m; i++){\n cin >> t[i];\n }\n vector<int> ans(n, 0);\n for(int i=0; i<(int)a.size(); i++){\n ans[a[i]] += c[i]*t[b[i]];\n }\n for(int i=0; i<n-1; i++){\n cout << ans[i] << \" \";\n }\n cout << ans.back() << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3900, "score_of_the_acc": -0.0675, "final_rank": 5 }, { "submission_id": "aoj_0286_5013621", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\n\nint main(void){\n int N,M;\n cin>>N>>M;\n map<int,int> * A = new map<int,int> [N];\n for(int i=0;i<N;i++){\n map<int, int> d;\n A[i] = d;\n }\n unsigned short s,t,e;\n while(cin>>s>>t>>e){\n if(s==0 and t==0 and e==0)break;\n A[s-1][t-1]=e;\n }\n int L;\n cin>>L;\n for(int _=0;_<L;_++){\n int* b = new int[M];\n for(int i=0;i<M;i++){\n cin>>b[i];\n }\n for(int i=0;i<N;i++){\n long c=0;\n for(auto iter=A[i].begin();iter!=A[i].end();iter++){\n auto key = iter->first;\n auto value = iter->second;\n c+=(long)value * (long)b[key];\n }\n if(i<N-1){\n cout<<c<<\" \";\n }\n else{\n cout<<c<<endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 10016, "score_of_the_acc": -0.1796, "final_rank": 16 }, { "submission_id": "aoj_0286_4976390", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define chmin(a,b) a=min(a,b)\n#define chmax(a,b) a=max(a,b)\n#define mod 1000000007\n#define ad(a,b) a=(a+b)%mod;\n#define X 5010\nll po(ll x,ll y){\n\tll res=1;\n\tfor(;y;y>>=1){\n\t\tif(y&1)res=res*x%mod;\n\t\tx=x*x%mod;\n\t}\n\treturn res;\n}\nll fac[X],ivf[X];\nvoid init(){\n\tfac[0]=1;\n\tfor(ll i=1;i<X;i++)fac[i]=fac[i-1]*i%mod;\n\tfor(ll i=0;i<X;i++)ivf[i]=po(fac[i],mod-2);\n}\nll C(ll n,ll k){\n\treturn fac[n]*ivf[n-k]%mod*ivf[k]%mod;\n}\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\tll n,m;\n\tvector<ll> typ[10010],cnt[10010];\n\tcin>>n>>m;\n\twhile(1){\n\t\tll s,t,e;\n\t\tcin>>s>>t>>e;\n\t\tif(s==0&&t==0&&e==0)break;\n\t\ttyp[s].push_back(t);\n\t\tcnt[s].push_back(e);\n\t}\n\tll l;\n\tcin>>l;\n\twhile(l--){\n\t\tll b[10010];\n\t\tfor(int i=1;i<=m;i++)cin>>b[i];\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tif(i>1)cout<<\" \";\n\t\t\tll ans=0;\n\t\t\trep(j,typ[i].size()){\n\t\t\t\tans+=b[typ[i][j]]*cnt[i][j];\n\t\t\t}\n\t\t\tcout<<ans;\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 5248, "score_of_the_acc": -0.0322, "final_rank": 3 }, { "submission_id": "aoj_0286_4815923", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\nint main() {\n init();\n\n int n, m; cin >> n >> m;\n VI s, t, e;\n for (int x, y, z; cin >> x >> y >> z && x != 0;) {\n s.push_back(x - 1);\n t.push_back(y - 1);\n e.push_back(z);\n }\n int l; cin >> l;\n FOR(_, 0, l) {\n VI b(m); cin >> b;\n VI ans(n);\n FOR(j, 0, s.size())\n ans[s[j]] += b[t[j]] * e[j];\n print(ans);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3708, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0286_4757062", "code_snippet": "#include<string.h>\n#include<iostream>\n#include<string>\n#include <vector>\n#include<algorithm>\n#include<map>\n\nusing namespace std;\n\nint main()\n{\n\tint N, M;\n\tcin >> N >> M;\n\tint s, t, e;\n\tmap<pair<int, int>, int> c;\n\tcin >> s >> t >> e;\n\twhile (s)\n\t{\n\t\tc[make_pair(s, t)] += e;\n\t\tcin >> s >> t >> e;\n\t}\n\tint L;\n\tcin >> L;\n\tint* b = new int[M + 1];\n\tfor (int i = 0; i < L; i++)\n\t{\n\t\tfor (int j = 1; j <= M; j++)\n\t\t\tcin >> b[j];\n\t\tint* rets = new int[N + 1];\n\t\tfill(rets, rets + N + 1, 0);\n\t\tfor (auto p : c)\n\t\t{\n\t\t\tint _s = p.first.first;\n\t\t\tint _t = p.first.second;\n\t\t\tint _e = p.second;\n\t\t\trets[_s] += b[_t] * _e;\n\t\t}\n\t\tcout << rets[1];\n\t\tfor (int i = 2; i <= N; i++)\n\t\t\tcout << \" \" << rets[i];\n\t\tcout << endl;\n\t}\n\t//\n\t//cin >> N;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 10168, "score_of_the_acc": -0.2385, "final_rank": 19 } ]
aoj_0291_cpp
古代遺跡の謎 古代遺跡から超大型あみだくじが発見された。学者達はこれをVLA(Very Long Amidakuji)と命名した。分析の結果、VLAは N 本の縦棒を持ついくつかの部品の組み合わせで構成され、多くの場合繰り返しを含んでいることがわかった。例えば、図のVLAは2種類の部品AとBを使った4つの部品から構成されている。 このVLAの上端に左から順番に 1,2,3,4,5 と番号をつけ、それぞれの番号からVLAをたどり(あみだくじのたどり方については問題文最後の補足を参照してください)、下端にたどり着いた場所の縦棒にその番号を振る。すべての番号についてたどり終えた後で、下端に振られた番号を左から読むと 4,2,5,1,3 になる。このように、1,2,3,4,5 という番号の列が 4,2,5,1,3 という列に変換される。 彼らはVLAによって 1 から N までの番号の列がどのように変換されるのかを知りたいが、手作業でたどるのは大変そうだ。そこでパソコン甲子園出場者である優秀なプログラマーの君たちに、VLAのシミュレーションを依頼した。 VLAはとても長いため、そのままの状態ではプログラマーたちに情報を伝えることができない。そこで学者たちは、部品の種類を英大文字1つで表し、VLAを式で表現することにした。 部品は同じ位置関係である縦棒が一致するように、左から順番に + 演算子で接続される。たとえば、上からA,B,C,D という順番で連結された部品の列は A+B+C+D という式で表記される。 部品の列を表す式 seq の m 回の繰り返しは、 m ( seq ) と表記できる。たとえば、 A+B の2回の繰り返しは 2(A+B) と表せ、これは A+B+A+B と同じである。また、 seq が1つの部品 a の場合は、 a を囲むかっこを省略しても構わない。 4(A+B) と 3(X+Y) を、この順番で連結したVLAは 4(A+B)+3(X+Y) と表せる。また、かっこは 2(4(A+B)+3(X+Y))+10C のように入れ子にしても構わない。 それでは、縦棒の数 N 、各部品の情報、複数のVLAの式を入力とし、各式が表すVLAによって1から N までの番号の列がどのように変換されるかを出力するプログラムを作成しなさい。 (※補足:あみだくじのたどり方について) あみだくじのある縦棒の上端から出発して上から下へ進む。ただし、横棒がある地点ではその横棒でつながった別の縦棒に移動する。これを、縦棒の下端にたどり着くまで繰り返す。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 N K p 1 h 1 g 1 (1,1) g 1 (1,2) .. g 1 (1, N -1) g 1 (2,1) g 1 (2,2) .. g 1 (2, N -1) : g 1 ( h 1 -1,1) g 1 ( h 1 -1,2) .. g 1 ( h 1 -1, N -1) p 2 h 2 g 2 (1,1) g 2 (1,2) .. g 2 (1, N -1) g 2 (2,1) g 2 (2,2) .. g 2 (2, N -1) : g 2 ( h 2 -1,1) g 2 ( h 2 -1,2) .. g 2 ( h 2 -1, N -1) : p K h K g K (1,1) g K (1,2) .. g K (1, N -1) g K (2,1) g K (2,2) .. g K (2, N -1) : g K ( h K -1,1) g K ( h K -1,2) .. g K ( h K -1, N -1) E expression 1 expression 2 : expression E 1行目に縦棒の数を表す整数 N (2 ≤ N ≤ 12) と部品の種類の数 K (1 ≤ K ≤ 26)が与えられる。 2行目以降に K 種類の部品の情報が与えられる。各部品は以下の形式で与えられる。 最初の行は部品名を表す1つの英大文字 p i と部品 i の縦棒の長さを表す整数 h i (1 ≤ h i ≤ 20)を含む。 続く h i -1 行で部品 i の横棒の情報が与えられる。 g i ( r, c ) は部品 i の上端から長さ r の位置において、左から c 番目の縦棒と c +1 番目の縦棒をつなぐ横棒の有無を表す。横棒があるときは g i ( r , c ) = 1、横棒がないときは g i ( r , c ) = 0である。 続く1行に式の数 E (1 ≤ E ≤ 100) が与えられる。続く E 行にVLAの式を表す文字列 expression i (1文字以上1000文字以下)が与えられる。 入力は以下の条件を満たす。 異なる部品に同じ名前が使われることはない。 各部品 i について、 g i ( r , c )と g i ( r , c +1)が同時に 1 となることはない。 式に含まれる整数は 1 以上 1,000,000,000 以下である。 式には空白は含まれない。 出力 式ごとに、VLAによる1からNまでの列の変換結果を1行に出力する。それぞれの数字の間は空白1つで区切る。 入出力例 入力例 5 2 A 5 1 0 0 1 0 1 0 0 1 0 1 0 0 1 0 1 B 4 1 0 0 1 0 1 0 0 0 0 1 0 2 2(A+B) 1000000000(1000000000A+1000000000B) 出力例 4 2 5 1 3 1 2 3 4 5
[ { "submission_id": "aoj_0291_10852950", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\nusing namespace std;\n\nint H, N, Q, p[30][30]; vector<int>r[30], J; string c[30]; string S;\n\nvector<int>amida_add(vector<int>a, vector<int>b) {\n\tvector<int>c = a, p = a, q = a;\n\tfor (int i = 0; i < a.size(); i++)p[a[i]] = i;\n\tfor (int i = 0; i < b.size(); i++)q[b[i]] = i;\n\tfor (int i = 0; i < a.size(); i++)c[q[p[i]]] = i;\n\treturn c;\n}\n\nvector<int> amida_rep(vector<int>a, int rep) {\n\tvector<int>dp[32], res = J;\n\tfor (int i = 0; i < 32; i++) { dp[i].resize(a.size(), 0); }\n\tdp[0] = a;\n\tfor (int i = 0; i < 31; i++) dp[i + 1] = amida_add(dp[i], dp[i]);\n\tfor (int i = 0; i < 31; i++) {\n\t\tif ((rep / (1 << i)) % 2 == 1) res = amida_add(res, dp[i]);\n\t}\n\treturn res;\n}\n\nvector<int>solve(int L, int R) {\n\tif (L == R) {\n\t\tfor (int i = 0; i < N; i++) { if (S[L] == c[i][0])return r[i]; }\n\t}\n\tvector<int>D; D.push_back(L - 1); int depth = 0;\n\tfor (int i = L; i <= R; i++) { if (S[i] == '(')depth++; if (S[i] == ')')depth--; if (S[i] == '+' && depth == 0) D.push_back(i); } D.push_back(R + 1);\n\tif (D.size() >= 3) {\n\t\tvector<int> T = J;\n\t\tfor (int i = 0; i < D.size() - 1; i++) { vector<int>U = solve(D[i] + 1, D[i + 1] - 1); T = amida_add(T, U); }\n\t\treturn T;\n\t}\n\tint cl = -1, cr = -1;\n\tfor (int i = L; i <= R; i++) { if (S[i] == '(') { cl = i; break; } }\n\tfor (int i = R; i >= L; i--) { if (S[i] == ')') { cr = i; break; } }\n\tif (cl != -1) {\n\t\tint P = stoi(S.substr(L, cl - L));\n\t\tvector<int>U = solve(cl + 1, cr - 1);\n\t\tU = amida_rep(U, P);\n\t\treturn U;\n\t}\n\tint PP = stoi(S.substr(L, R - L));\n\tvector<int>UU = solve(R, R);\n\tUU = amida_rep(UU, PP);\n\treturn UU;\n}\n\nint main() {\n\tcin >> H >> N;\n\tfor (int j = 0; j < H; j++) J.push_back(j);\n\tfor (int i = 0; i < N; i++) {\n\t\tint w = 0; cin >> c[i] >> w; r[i] = J;\n\t\tfor (int j = 0; j < w - 1; j++) {\n\t\t\tfor (int k = 0; k < H - 1; k++) {\n\t\t\t\tcin >> p[j][k]; if (p[j][k] == 1) swap(r[i][k], r[i][k + 1]);\n\t\t\t}\n\t\t}\n\t}\n\tcin >> Q;\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> S;\n\t\tvector<int>ans = solve(0, S.size() - 1);\n\t\tfor (int j = 0; j < ans.size(); j++) { if (j)cout << \" \"; cout << ans[j] + 1; }cout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3408, "score_of_the_acc": -0.7808, "final_rank": 10 }, { "submission_id": "aoj_0291_9417707", "code_snippet": "// #define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n// #include <atcoder/all>\n// #include \"qitoy/math/binomial.hpp\"\n\n#define rep(i, n) for (long long i = 0; i < (n); i++)\n#define rep1(i, n) for (long long i = 1; i <= (n); i++)\n#define all(v) v.begin(), v.end()\n#define decimal(n) cout << fixed << setprecision(n);\nusing namespace std;\n// using namespace atcoder;\nusing vi = vector<int>; using vvi = vector<vi>; using vs = vector<string>;\nusing ll = long long; using vl = vector<ll>; using vvl = vector<vl>; \n// using mint = modint998244353;\n// const ll MOD = 998244353;\n// using mint = modint;\n// const ll MOD = 998244353;\n// using mint = modint1000000007;\n// const ll MOD = 1000000007;\n// using vm = vector<mint>; using vvm = vector<vm>;\nusing vll = vl;\nusing P = pair<ll, ll>; using T = tuple<ll, ll, ll>;\nusing vc = vector<char>; using vvc = vector<vc>;\nconst ll MAX = 2000100; const ll llINF = 2e18;\nconst int intINF = 2e9; const long double pi = acos(-1);\nll di[] = {0, -1, 0, 1, -1, -1, 1, 1};\nll dj[] = {1, 0, -1, 0, 1, -1, -1, 1};\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\n\n#include <string>\n#include <cctype>\ntypedef string::const_iterator State;\nclass ParseError {};\n\nvvl amida;\n// プロトタイプ宣言\nvl expression(State &begin);\nvl terms(State &begin);\nvl factor(State &begin);\nvl element(State &begin);\nll number(State &begin);\nvl sum(vl a, vl b);\nvoid consume(State &begin, char expected);\n\nll n;\n\n// 四則演算の式をパースして、その評価結果を返す。\nvl expression(State &begin) {\n vl ret(n);\n iota(all(ret), 1ll);\n ret = sum(ret, terms(begin));\n while(true) {\n if(*begin == '+') {\n consume(begin, '+');\n ret = sum(ret, terms(begin));\n }\n else break;\n }\n return ret;\n}\n\nvl terms(State &begin) {\n ll time = 1;\n vl ret;\n iota(all(ret), 1ll);\n if(isdigit(*begin)) {\n time = number(begin);\n }\n ret = factor(begin);\n\n vl ans(n);\n iota(all(ans), 1ll);\n for(ll i = 0; i <= 31; i++) {\n if(time & (1ll << i)) {\n ans = sum(ans, ret);\n }\n ret = sum(ret, ret);\n }\n ret = ans;\n\n return ret;\n}\n\nvl factor(State &begin) {\n vl ret;\n iota(all(ret), 1ll);\n if(*begin != '(') {\n ret = element(begin);\n }\n else if(*begin == '(') {\n consume(begin, '(');\n ret = expression(begin);\n consume(begin, ')');\n }\n return ret;\n}\n\nvl element(State &begin) {\n vl ret = amida[*begin - 'A'];\n begin++;\n return ret;\n}\n\n// 数字の列をパースして、その数を返す。\nll number(State &begin) {\n ll ret = 0;\n\n while (isdigit(*begin)) {\n ret *= 10;\n ret += *begin - '0';\n begin++;\n }\n\n return ret;\n}\n\n// aからbへのamidaの結合\nvl sum(vl a, vl b) {\n vl next(n);\n rep(i, n) {\n next[i] = a[b[i] - 1];\n }\n return next;\n}\n\n// beginがexpectedを指していたらbeginを一つ進める。\nvoid consume(State &begin, char expected) {\n if (*begin == expected) {\n begin++;\n } else {\n cerr << \"Expected '\" << expected << \"' but got '\" << *begin << \"'\"\n << endl;\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n throw ParseError();\n }\n}\n\nint main() {\n ll k;\n cin >> n >> k;\n amida.resize(26);\n rep(ii, k) {\n char c; ll v;\n cin >> c >> v;\n vl num(n);\n iota(all(num), 1LL);\n rep(hh, v - 1) {\n rep(i, n - 1) {\n ll x;\n cin >> x;\n if(x == 1) {\n swap(num[i], num[i + 1]);\n }\n }\n }\n amida[c - 'A'] = num;\n }\n ll e;\n cin >> e;\n while(e--) {\n string s;\n cin >> s;\n State begin = s.begin();\n vl ans = expression(begin);\n assert(s.end() == begin);\n rep(i, n) {\n cout << ans[i] << (i == n - 1 ? \"\" : \" \");\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3456, "score_of_the_acc": -0.8311, "final_rank": 14 }, { "submission_id": "aoj_0291_9417227", "code_snippet": "// #define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n// #include <atcoder/all>\n// #include \"qitoy/math/binomial.hpp\"\n\n#define rep(i, n) for (long long i = 0; i < (n); i++)\n#define rep1(i, n) for (long long i = 1; i <= (n); i++)\n#define all(v) v.begin(), v.end()\n#define decimal(n) cout << fixed << setprecision(n);\nusing namespace std;\n// using namespace atcoder;\nusing vi = vector<int>; using vvi = vector<vi>; using vs = vector<string>;\nusing ll = long long; using vl = vector<ll>; using vvl = vector<vl>; \n// using mint = modint998244353;\n// const ll MOD = 998244353;\n// using mint = modint;\n// const ll MOD = 998244353;\n// using mint = modint1000000007;\n// const ll MOD = 1000000007;\n// using vm = vector<mint>; using vvm = vector<vm>;\nusing vll = vl;\nusing P = pair<ll, ll>; using T = tuple<ll, ll, ll>;\nusing vc = vector<char>; using vvc = vector<vc>;\nconst ll MAX = 2000100; const ll llINF = 2e18;\nconst int intINF = 2e9; const long double pi = acos(-1);\nll di[] = {0, -1, 0, 1, -1, -1, 1, 1};\nll dj[] = {1, 0, -1, 0, 1, -1, -1, 1};\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\n\n#include <string>\n#include <cctype>\ntypedef string::const_iterator State;\nclass ParseError {};\n\nvvl amida;\n// プロトタイプ宣言\nvl expression(State &begin);\nvl factor(State &begin);\nvl element(State &begin);\nll number(State &begin);\nvl sum(vl a, vl b);\nvoid consume(State &begin, char expected);\n\nll n;\n\n// 四則演算の式をパースして、その評価結果を返す。\nvl expression(State &begin) {\n vl ret(n);\n iota(all(ret), 1ll);\n ret = sum(ret, factor(begin));\n while(true) {\n if(*begin == '+') {\n consume(begin, '+');\n ret = sum(ret, factor(begin));\n }\n else break;\n }\n return ret;\n}\n\nvl factor(State &begin) {\n ll time = 1;\n vl ret;\n iota(all(ret), 1ll);\n if(isdigit(*begin)) {\n time = number(begin);\n }\n\n if(*begin != '(') {\n ret = element(begin);\n }\n else if(*begin == '(') {\n consume(begin, '(');\n ret = expression(begin);\n consume(begin, ')');\n }\n vl ans(n);\n iota(all(ans), 1ll);\n for(ll i = 0; i <= 31; i++) {\n if(time & (1ll << i)) {\n ans = sum(ans, ret);\n }\n ret = sum(ret, ret);\n }\n ret = ans;\n\n return ret;\n\n}\n\nvl element(State &begin) {\n vl ret = amida[*begin - 'A'];\n begin++;\n return ret;\n}\n\n// 数字の列をパースして、その数を返す。\nll number(State &begin) {\n ll ret = 0;\n\n while (isdigit(*begin)) {\n ret *= 10;\n ret += *begin - '0';\n begin++;\n }\n\n return ret;\n}\n\n// aからbへのamidaの結合\nvl sum(vl a, vl b) {\n vl next(n);\n rep(i, n) {\n next[i] = a[b[i] - 1];\n }\n return next;\n}\n\n// beginがexpectedを指していたらbeginを一つ進める。\nvoid consume(State &begin, char expected) {\n if (*begin == expected) {\n begin++;\n } else {\n cerr << \"Expected '\" << expected << \"' but got '\" << *begin << \"'\"\n << endl;\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n throw ParseError();\n }\n}\n\nint main() {\n ll k;\n cin >> n >> k;\n amida.resize(26);\n rep(ii, k) {\n char c; ll v;\n cin >> c >> v;\n vl num(n);\n iota(all(num), 1LL);\n rep(hh, v - 1) {\n rep(i, n - 1) {\n ll x;\n cin >> x;\n if(x == 1) {\n swap(num[i], num[i + 1]);\n }\n }\n }\n amida[c - 'A'] = num;\n }\n ll e;\n cin >> e;\n while(e--) {\n string s;\n cin >> s;\n State begin = s.begin();\n vl ans = expression(begin);\n assert(s.end() == begin);\n rep(i, n) {\n cout << ans[i] << (i == n - 1 ? \"\" : \" \");\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3372, "score_of_the_acc": -0.7054, "final_rank": 7 }, { "submission_id": "aoj_0291_9340565", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nvector<int> pattern(State &begin);\nint number(State &begin);\nvector<int> term(State &begin);\nvector<int> expression(State &begin);\nvector<int> factor(State &begin);\nmap<char, vector<int>> order;\nint n;\nvector<int> composition(vector<int> &a, vector<int> ord){\n vector<int> ret(n);\n for(int i=0;i<n;i++){\n ret[i] = ord[a[i]];\n }\n return ret;\n}\nvector<int> mul(vector<int> ord, int num){\n if(num == 1) return ord;\n if(num % 2 == 0){\n vector<int> elem = mul(ord, num/2);\n return composition(elem, elem);\n }\n return composition(ord, mul(ord, num-1));\n}\nint number(State &begin){\n int ret = 0;\n while(isdigit(*begin)){\n ret = 10*ret + (*begin - '0');\n begin++;\n }\n return ret;\n}\nvector<int> term(State &begin){\n if(isdigit(*begin)){\n int num = number(begin);\n vector<int> ret = mul(factor(begin), num);\n return ret;\n }\n else{\n return factor(begin);\n }\n}\nvector<int> expression(State &begin){\n vector<int> ret = term(begin);\n while(true){\n if(*begin == '+'){\n begin++;\n ret = composition(ret, term(begin));\n }\n else{\n break;\n }\n }\n return ret;\n}\nvector<int> factor(State &begin){\n if(*begin == '('){\n begin++;\n vector<int> ret = expression(begin);\n begin++;\n return ret;\n }\n else{\n vector<int> ret = order[*begin];\n begin++;\n return ret;\n }\n\n}\n\nvoid solve(){\n string s;\n // getline(cin, s);\n cin >> s;\n s.erase(std::remove_if(s.begin(), s.end(), ::isspace), s.end());\n State begin = s.begin();\n vector<int> ord = expression(begin);\n vector<int> ans(n);\n for(int i=0;i<n;i++) ans[ord[i]] = i;\n\n for(int i=0;i<n-1;i++) cout << ans[i] + 1<< \" \";\n cout << ans.back() + 1<< endl;\n}\n\nvector<int> make_order(vector<vector<int>> &g){\n int h = g.size();\n vector<int> ret(n);\n for(int i=0; i<n; i++){\n int now = i;\n for(int j=0;j<h;j++){\n if(now > 0 && g[j][now-1]){\n now--;\n } \n else if(now < n-1 && g[j][now]){\n now++;\n }\n } \n ret[i] = now;\n }\n return ret;\n}\n\nint main(){\n int k;\n cin >> n >> k;\n for(int i=0; i<k; i++){\n char c;\n int h;\n cin >> c >> h;\n vector<vector<int>> g(h-1,vector<int>(n-1));\n for(int j=0; j<h-1; j++){\n for(int l=0; l<n-1; l++){\n cin >> g[j][l];\n }\n }\n order[c] = make_order(g);\n }\n int q; \n cin >> q;\n while(q--){\n solve();\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.8144, "final_rank": 13 }, { "submission_id": "aoj_0291_8456076", "code_snippet": "#include <bits/stdc++.h>\n\nstruct Data {\n static constexpr int LOG = 30;\n std::vector<std::vector<int>> doubling;\n\n Data() = default;\n Data(const std::vector<int>& perm) {\n int n = perm.size();\n doubling.resize(LOG + 1, std::vector<int>(n));\n std::copy(perm.begin(), perm.end(), doubling.front().begin());\n for (int i = 0; i < LOG; i++) {\n for (int j = 0; j < n; j++) {\n doubling[i + 1][j] = doubling[i][doubling[i][j]];\n }\n }\n }\n\n int operator[](int i) const {\n return doubling[0][i];\n }\n\n Data repeat(int n) {\n std::vector<int> result;\n for (int i = 0; i < (int)doubling.front().size(); i++) {\n int rem = n;\n int u = i;\n for (int j = 0; j <= LOG; j++) {\n if (rem & 1) {\n u = doubling[j][u];\n }\n rem >>= 1;\n }\n result.push_back(u);\n }\n return Data(result);\n }\n\n friend Data operator+(const Data& lhs, const Data& rhs) {\n std::vector<int> result(lhs.doubling.front().size());\n for (int i = 0; i < (int)lhs.doubling.front().size(); i++) {\n result[i] = lhs[rhs[i]];\n }\n return Data(result);\n }\n\n static void test() {\n Data a({0, 3, 2, 1});\n Data b({1, 2, 0, 3});\n Data c = a + b;\n for (int i = 0; i < 4; i++) {\n std::cout << c.doubling[0][i] << std::endl;\n }\n }\n};\n\nstd::ostream& operator<<(std::ostream& os, const Data& data) {\n for (int i = 0; i < (int)data.doubling.front().size(); i++) {\n os << data[i] + 1;\n if (i + 1 < (int)data.doubling.front().size()) {\n os << ' ';\n }\n }\n return os;\n}\n\nData to_data(const std::vector<std::vector<int>>& vla) {\n std::vector<int> res(vla.front().size() + 1);\n std::iota(res.begin(), res.end(), 0);\n\n for (int i = (int)vla.size() - 1; i >= 0; i--) {\n for (int j = 0; j < (int)vla.front().size(); j++) {\n if (vla[i][j] == 1) {\n std::swap(res[j], res[j + 1]);\n }\n }\n }\n\n auto temp = res;\n for (int i = 0; i < (int)res.size(); i++) {\n res[temp[i]] = i;\n }\n\n return Data(res);\n}\n\nstd::array<Data, 256> database;\n\nclass ParseError {};\n\nstruct Parser {\n std::string s;\n using Iter = std::string::const_iterator&;\n\n Parser(std::string s): s(s) {}\n\n void consume(Iter it, char c) {\n it++;\n }\n\n Data parse() {\n auto it = s.cbegin();\n return expr(it);\n }\n\n Data expr(Iter it) {\n auto res = term(it);\n while (it != s.end() && *it == '+') {\n consume(it, '+');\n res = res + term(it);\n }\n return res;\n }\n\n Data term(Iter it) {\n int rep = number(it);\n if (*it == '(') {\n consume(it, '(');\n auto data = expr(it);\n consume(it, ')');\n return data.repeat(rep);\n } else {\n auto data = database[*it];\n it++;\n return data.repeat(rep);\n }\n }\n\n int number(Iter it) {\n int res = 0;\n while (it != s.end() && std::isdigit(*it)) {\n res = 10 * res + (*it) - '0';\n it++;\n }\n if (res == 0) res = 1;\n return res;\n }\n};\n\nint main() {\n int n, k;\n std::cin >> n >> k;\n for (int i = 0; i < k; i++) {\n char p;\n int h;\n std::cin >> p >> h;\n std::vector<std::vector<int>> vla(h - 1, std::vector<int>(n - 1));\n for (int j = 0; j + 1 < h; j++) {\n for (int l = 0; l + 1 < n; l++) {\n std::cin >> vla[j][l];\n }\n }\n Data data = to_data(vla);\n\n database[p] = data;\n }\n\n int e;\n std::cin >> e;\n std::cin.ignore();\n while (e--) {\n std::string s;\n std::getline(std::cin, s);\n Parser parser(s);\n auto data = parser.parse();\n std::cout << data << std::endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3476, "score_of_the_acc": -0.8503, "final_rank": 15 }, { "submission_id": "aoj_0291_8408113", "code_snippet": "/*\n * 0291.cc: Mystery of an Ancient Ruin\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 12;\nconst int MAX_K = 26;\nconst int MAX_L = 1000;\n\n/* typedef */\n\ntypedef vector<int> vi;\n\nstruct Amida {\n static int n;\n vi ds;\n Amida() {\n ds.resize(n);\n for (int i = 0; i < n; i++) ds[i] = i;\n }\n\n Amida operator+(const Amida &a) const {\n Amida r;\n for (int i = 0; i < n; i++) r.ds[i] = ds[a.ds[i]];\n return r;\n }\n\n Amida operator*(int m) {\n Amida p, a = *this;\n while (m > 0) {\n if (m & 1) p = p + a;\n a = a + a;\n m >>= 1;\n }\n return p;\n }\n\n void print() {\n for (int i = 0; i < n; i++)\n printf(\"%d%c\", ds[i] + 1, (i + 1 < n) ? ' ' : '\\n');\n }\n};\nint Amida::n;\n\n/* global variables */\n\nAmida as[MAX_K];\nchar s[MAX_L + 4];\n\n/* subroutines */\n\nAmida expr(char *(&cpt));\n\nAmida elm(char *(&cpt)) {\n if (*cpt == '(') {\n cpt++; // '(';\n Amida e = expr(cpt);\n cpt++; // ')';\n return e;\n }\n\n Amida e = as[*(cpt++) - 'A'];\n return e;\n}\n\nAmida term(char *(&cpt)) {\n int c = 1;\n if (*cpt >= '0' && *cpt <= '9') {\n c = 0;\n while (*cpt >= '0' && *cpt <= '9')\n c = c * 10 + (*(cpt++) - '0');\n }\n\n Amida e = elm(cpt);\n return (c > 1) ? e * c : e;\n}\n\nAmida expr(char *(&cpt)) {\n Amida t0 = term(cpt);\n while (*cpt == '+') {\n cpt++; // '+'\n Amida t1 = term(cpt);\n t0 = t0 + t1;\n }\n return t0;\n}\n\n/* main */\n\nint main() {\n int n, k;\n scanf(\"%d%d\", &n, &k);\n Amida::n = n;\n\n for (int i = 0; i < k; i++) {\n char cs[4];\n int hi;\n scanf(\"%s%d\", cs, &hi);\n\n Amida ai;\n //ai.print();\n for (int y = 0; y + 1 < hi; y++) {\n for (int x = 0; x + 1 < n; x++) {\n\tint gx;\n\tscanf(\"%d\", &gx);\n\tif (gx) swap(ai.ds[x], ai.ds[x + 1]);\n }\n //ai.print();\n }\n as[cs[0] - 'A'] = ai;\n //printf(\"%c = \", cs[0]); ai.print();\n }\n\n int qn;\n scanf(\"%d\", &qn);\n\n while (qn--) {\n scanf(\"%s\", s);\n char *cpt = s;\n Amida e = expr(cpt);\n e.print();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2968, "score_of_the_acc": -0.0898, "final_rank": 2 }, { "submission_id": "aoj_0291_7977438", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\ntypedef string::const_iterator State;\nclass ParseError {};\n\nint n;\n\nstruct Part {\n vector<int> p; // {0, 1, ... n-1} がそれぞれどこに行くか\n Part(vector<vector<int>> field) {\n p.resize(n);\n iota(p.begin(), p.end(), 0);\n for(auto&& v : field) {\n for(int i = 0; i < n - 1; i++) {\n if(v[i] == 1) swap(p[i], p[i + 1]);\n }\n }\n }\n Part() {\n p.resize(n);\n iota(p.begin(), p.end(), 0);\n }\n};\n\nPart parts[256];\n\nPart add(const Part& l, const Part& r) {\n Part ret;\n for(int i = 0; i < n; i++) {\n ret.p[i] = l.p[r.p[i]];\n }\n return ret;\n}\n\nPart mul(int x, Part p) {\n Part ret;\n while(x) {\n if(x & 1) ret = add(ret, p);\n p = add(p, p);\n x /= 2;\n }\n return ret;\n}\n\nint number(State& ptr) {\n int ret = 0;\n while(isdigit(*ptr)) {\n ret *= 10;\n ret += *ptr - '0';\n ptr++;\n }\n return ret;\n}\n\nPart tasu(State&);\n\nPart kake(State& ptr) {\n // cout << \"kake \" << *ptr << endl;\n int num = max(number(ptr), 1);\n Part ret;\n if(*ptr == '(') {\n ptr++;\n ret = tasu(ptr);\n ptr++;\n } else {\n ret = parts[*ptr];\n ptr++;\n }\n return mul(num, ret);\n}\n\nPart tasu(State& ptr) {\n // cout << \"tasu \" << *ptr << endl;\n Part ret = kake(ptr);\n while(*ptr == '+') {\n ptr++;\n ret = add(ret, kake(ptr));\n }\n return ret;\n}\n\nint main() {\n int k;\n cin >> n >> k;\n for(int i = 0; i < k; i++) {\n char c;\n int h;\n cin >> c >> h;\n vector field(h - 1, vector<int>(n - 1));\n for(int i = 0; i < h - 1; i++)\n for(int j = 0; j < n - 1; j++) cin >> field[i][j];\n parts[c] = Part(field);\n }\n\n int e;\n cin >> e;\n cin.ignore();\n while(e--) {\n string s;\n getline(cin, s);\n\n State ptr = s.begin();\n Part ans = tasu(ptr);\n\n for(int i = 0; i < n; i++) {\n cout << ans.p[i] + 1 << \" \\n\"[i + 1 == n];\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3516, "score_of_the_acc": -0.9102, "final_rank": 17 }, { "submission_id": "aoj_0291_6763293", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nvector<int> compose(const vector<int>& p, const vector<int>& q) {\n assert(p.size() == q.size());\n int n = p.size();\n vector<int> r(n);\n for (int i = 0; i < n; ++i) {\n r[i] = p[q[i]];\n }\n return r;\n}\nvector<int> pow(vector<int> p, long long k) {\n int n = p.size();\n vector<int> res(n);\n iota(res.begin(), res.end(), 0);\n for (; k; k >>= 1) {\n if (k & 1) res = compose(res, p);\n p = compose(p, p);\n }\n return res;\n}\n\nbool is_digit(char c) {\n return '0' <= c and c <= '9';\n}\n\npair<int, int> read_int(const string& s, int i) {\n int j = i;\n while (is_digit(s[j])) ++j;\n return { stoi(s.substr(i, j - i)), j };\n}\n\nint main() {\n int n, k;\n cin >> n >> k;\n\n array<vector<int>, 256> ps{};\n for (int i = 0; i < k; ++i) {\n char id;\n cin >> id;\n int h;\n cin >> h;\n \n vector<int> p(n);\n iota(p.begin(), p.end(), 0);\n for (int j = 0; j < h - 1; ++j) {\n for (int c = 0; c < n - 1; ++c) {\n int g;\n cin >> g;\n if (g == 1) swap(p[c], p[c + 1]);\n }\n }\n ps[id] = move(p);\n }\n\n int m;\n cin >> m;\n for (int i = 0; i < m; ++i) {\n string s;\n cin >> s;\n int l = s.size();\n vector<int> rp(l, -1);\n vector<int> st;\n for (int pos = 0; pos < l; ++pos) {\n if (s[pos] == '(') {\n st.push_back(pos);\n } else if (s[pos] == ')') {\n rp[st.back()] = pos;\n st.pop_back();\n }\n }\n auto scan = [&](auto scan, int l, int r) -> vector<int> {\n vector<int> res(n);\n iota(res.begin(), res.end(), 0);\n for (int i = l; i < r;) {\n int c = 1;\n if (is_digit(s[i])) {\n auto [v, j] = read_int(s, i);\n c = v;\n i = j;\n }\n if (s[i] == '(') {\n int j = rp[i];\n res = compose(res, pow(scan(scan, i + 1, j), c));\n i = j + 1;\n } else {\n res = compose(res, pow(ps[s[i]], c));\n i = i + 1;\n }\n if (i < r) {\n assert(s[i] == '+');\n ++i;\n }\n }\n return res;\n };\n auto ans = scan(scan, 0, l);\n for (int i = 0; i < n; ++i) {\n cout << ans[i] + 1 << \" \\n\"[i == n - 1];\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3444, "score_of_the_acc": -0.8024, "final_rank": 11 }, { "submission_id": "aoj_0291_6630536", "code_snippet": "#define _USE_MATH_DEFINES\n#include<bits/stdc++.h>\n#include<unordered_map>\n\nusing namespace std;\n#define LP(I,S,G) for (long long int I = (S); I < (G); I++)\n#define IN(X) \tfor (int in = 0; in < X.size(); in++)cin >> X[in]\n#define OUT(X) \tfor (int in = 0; in < X.size(); in++)cout << X[in]<<\" \"\n#define SORT(X) sort((X).begin(), (X).end())\n#define CSORT(X,Y) sort(X.begin(), X.end(),Y)\n#define COPY(X,Y) copy(X.begin(), X.end(), Y.begin())\n#define ALL(X,Y) for (auto X = (Y).begin(); X != (Y).end(); X++)\n#define FULL(a) (a).begin(),(a).end()\n#define BFS(Q,S) for(Q.push(S);Q.size()!=0;Q.pop())\ntypedef long long int ll;\ntypedef unsigned long long int ull;\nlong long int M = 1000000000000+39;\n\n\nint dx[] = { 0,-1,0,1 }, dy[] = { -1,0,1,0 };\n\nll MAX(ll A, ll B) { return ((A) > (B) ? (A) : (B)); }\nll MIN(ll A, ll B) { return ((A) < (B) ? (A) : (B)); }\nlong long int xor128() {\n\tstatic long long int x = 123456789, y = 362436069, z = 521288629, w = 88675123;\n\tlong long int t = (x ^ (x << 11));\n\tx = y; y = z; z = w;\n\treturn (w = (w ^ (w >> 19)) ^ (t ^ (t >> 8)));\n}\n\nstruct HashPair {\n\t//注意 constがいる\n\ttemplate<class T1, class T2>\n\tsize_t operator()(const pair<T1, T2> &p) const {\n\t\t//first分をハッシュ化する\n\t\tauto hash1 = hash<T1>{}(p.first);\n\t\t//second分をハッシュ化する\n\t\tauto hash2 = hash<T2>{}(p.second);\n\t\t//重複しないようにハッシュ処理\n\t\tsize_t seed = 0;\n\t\tseed ^= hash1 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\tseed ^= hash2 + 0x9e3779b9 + (seed << 6) + (seed >> 2);\n\t\treturn seed;\n\t}\n};\ntemplate<class I1, class I2>\nistream& operator>>(istream& s, pair<I1, I2>& in) {\n\ts >> in.first >> in.second;\n\treturn s;\n}\nvector<ll> add(vector<ll> l, vector<ll> r) {\n\tvector<ll> ret(l.size());\n\tll n = l.size();\n\tLP(i, 0, n)ret[i] = l[r[i]];\n\treturn ret;\n}\n\nvector<ll> mult(ll val, vector<ll> p) {\n\tll lv = ceil(log(val) / log(2)), n = p.size();\n\tvector<vector<ll>> t(lv+1, vector<ll>(n));\n\tt[0] = p;\n\tLP(i, 0, lv) {\n\t\tt[i + 1] = add(t[i], t[i]);\n\t}\n\tvector<ll> ret(n);\n\tLP(i, 0, n)ret[i] = i;\n\tLP(i, 0, lv+1) {\n\t\tif ((val&((ll)1 << i)) != 0)ret = add(ret, t[i]);\n\t}\n\treturn ret;\n}\n\nvector<ll> solve(ll now,ll n,string &s, vector<vector<ll>>& t ) {\n\tvector<ll> ret(t[0].size());\n\tLP(i, 0, ret.size())ret[i] = i;\n\twhile (now != n) {\n\t\tif (s[now] == '+') {\n\t\t\tnow++;\n\t\t\tcontinue;\n\t\t}\n\t\telse {\n\t\t\tif (s[now] >= '0'&&s[now] <= '9') {\n\t\t\t\tll val = 0;\n\t\t\t\twhile (s[now] >= '0'&&s[now] <= '9') {\n\t\t\t\t\tval *= 10;\n\t\t\t\t\tval += s[now] - '0';\n\t\t\t\t\tnow++;\n\t\t\t\t}\n\t\t\t\tvector<ll> op(ret.size());\n\t\t\t\tif (s[now] == '(') {\n\t\t\t\t\tll cnt = 1;\n\t\t\t\t\tll next = now;\n\t\t\t\t\twhile (cnt != 0) {\n\t\t\t\t\t\tnext++;\n\t\t\t\t\t\tif (s[next] == '(')cnt++;\n\t\t\t\t\t\tif (s[next] == ')')cnt--;\n\t\t\t\t\t}\n\t\t\t\t\top=solve(now + 1, next, s, t);\n\t\t\t\t\tnow = next + 1;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\top = t[s[now] - 'A'\n];\n\t\t\t\t\tnow++;\n\t\t\t\t}\n\t\t\t\top = mult(val, op);\n\t\t\t\tret = add(ret, op);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (s[now] == '(') {\n\t\t\t\t\tvector<ll> op(ret.size());\n\t\t\t\t\tll cnt = 1;\n\t\t\t\t\tll next = now;\n\t\t\t\t\twhile (cnt != 0) {\n\t\t\t\t\t\tnext++;\n\t\t\t\t\t\tif (s[next] == '(')cnt++;\n\t\t\t\t\t\tif (s[next] == ')')cnt--;\n\t\t\t\t\t}\n\t\t\t\t\top = solve(now + 1, next, s, t);\n\t\t\t\t\tnow = next + 1;\n\t\t\t\t\tret = add(ret, op);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tret = add(ret, t[s[now] - 'A']);\n\t\t\t\t\tnow++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\n\n\nint main() {\n\tll n, k;\n\tcin >> n >> k;\n\tvector<ll> ans(n);\n\tvector<vector<ll>> t(26, vector<ll>(n));\n\tLP(i, 0, n) {\n\t\tans[i] = i;\n\t\tLP(j, 0, 26)t[j][i] = i;\n\t}\n\tLP(i, 0, k) {\n\t\tll p;\n\t\tchar c;\n\t\tcin >> c;\n\t\tp = c - 'A';\n\t\tll max;\n\t\tcin >> max;\n\t\tLP(j, 0, max-1) {\n\t\t\tvector<ll> s(n - 1);\n\t\t\tIN(s);\n\t\t\tLP(x, 0, n - 1) {\n\t\t\t\tif (s[x])swap(t[p][x], t[p][x + 1]);\n\t\t\t}\n\t\t}\n\t}\n\tll e;\n\tcin >> e;\n\tLP(i, 0, e) {\n\t\tstring sub,s=\"+\";\n\t\tcin >> sub;\n\t\tLP(k, 0, sub.size()) {\n\t\t\ts.push_back(sub[k]);\n\t\t\tif (sub[k] == '(')s.push_back('+');\n\t\t}\n\t\tvector<ll> ans = solve(0, s.size(), s, t);\n\t\tALL(i, ans)cout << *i + 1 << ((i==(ans.end()-1))?\"\\n\":\" \");\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3576, "score_of_the_acc": -1.0108, "final_rank": 18 }, { "submission_id": "aoj_0291_6019938", "code_snippet": "/*\n   ∫ ∫ ∫\n   ノヽ\n  (_  )\n (_    )\n(______ )\n ヽ(´・ω・)ノ \n   |  /\n   UU\n*/\n#pragma region macro\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cctype>\n#include <vector>\n#include <cassert>\n#include <cmath>\n#include <utility>\n#include <tuple>\n#include <map>\n#include <set>\n#include <deque>\n#include <queue>\ntypedef long long int64;\nusing namespace std;\ntypedef vector<int> vi;\nconst int MOD = (int)1e9 + 7;\nconst int64 INF = 1LL << 62;\nconst int inf = 1<<30;\nconst char bn = '\\n';\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n#define REP(i, n) for (int i = 0; i < (n); i++)\n#define ALL(obj) (obj).begin(), (obj).end() //コンテナじゃないと使えない!!\n#define debug(x) cerr << #x << \": \" << (x) << \"\\n\";\n#define mp make_pair\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T> &V){\n int N = V.size();\n REP(i,N){\n os << V[i]+1;\n if (i!=N-1) os << \" \";\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T,typename S>\nostream& operator<<(ostream& os, pair<T,S> const&P){\n os << \"(\";\n os << P.first;\n os << \" , \";\n os << P.second;\n os << \")\";\n return os;\n}\ntemplate <typename T,typename S,typename U>\nostream& operator<<(ostream& os, tuple<T,S,U> const& P){\n os << \"(\";\n os << get<0>(P);\n os << \", \";\n os << get<1>(P);\n os << \", \";\n os << get<2>(P);\n os << \")\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, set<T> &S){\n auto it=S.begin();\n while(it!=S.end()){\n os << *it;\n os << \" \";\n it++;\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, deque<T> &q){\n for(auto it=q.begin();it<q.end();it++){\n os<<*it;\n os<<\" \";\n }\n os<<endl;\n return os;\n}\ntemplate <typename T,typename S>\nostream& operator<<(ostream& os, map<T,S> const&M){\n for(auto e:M){\n os<<e;\n }\n os<<endl;\n return os;\n}\nvector<pair<int,int>> dxdy = {mp(0,1),mp(1,0),mp(-1,0),mp(0,-1)};\n#pragma endregion\n//fixed<<setprecision(10)<<ans<<endl;\n\n\n\nmap<char, vector<int>> to;\nint N;\n\n// 構文解析\n/*\n 構文解析でよくあるバグは次の二つです。\n - begin++をし忘れる\n - getlineとcinの混合\n*/\n\n\n\ntypedef string::const_iterator State;\nclass ParseError {};\n\n// beginがexpectedを指していたらbeginを一つ進める。\nvoid consume(State &begin, char expected) {\n if (*begin == expected) {\n begin++;\n } else {\n cerr << \"Expected '\" << expected << \"' but got '\" << *begin << \"'\"\n << endl;\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n throw ParseError();\n }\n}\nvoid print_rest_string(State begin){\n cerr << \"Rest string is '\";\n while (*begin) {\n cerr << *begin++;\n }\n cerr << \"'\" << endl;\n}\n\n// amida[i]=j <- iにいたやつがjにいく\nvector<int> go_through_amida(vector<int> const& prev, vector<int> const& amida){\n vector<int> res(prev.size(), 0);\n REP(i,amida.size()){\n // i にいたやつ prev[i] は amida[i] にいく\n res[i] = prev[amida[i]];\n }\n return res;\n}\n\nvector<int> init_amida(int N){\n vector<int> res(N, 0);\n REP(i,N) res[i] = i;\n return res;\n}\n\n\nvector<int> expression(State &begin);\nvector<int> factor(State &begin);\nvector<int> term(State &begin);\nint number(State &begin);\n\n// 四則演算の式をパースして、その評価結果を返す。\nvector<int> expression(State &begin){\n vector<int> res = term(begin);\n\n while(true){\n if(*begin == '+'){\n consume(begin, '+');\n auto amida = term(begin);\n res = go_through_amida(res, amida);\n }else{\n break;\n }\n }\n\n return res;\n}\n\n// 乗算除算の式をパースして、その評価結果を返す。\nvector<int> term(State &begin){\n vector<int> res = init_amida(N);\n \n if(isdigit(*begin)){\n int val = number(begin);\n\n auto amida = factor(begin);\n\n //ここで二分法でresを計算\n while(val){\n if(val & 1){\n res = go_through_amida(res, amida);\n }\n amida = go_through_amida(amida, amida);\n val/=2;\n }\n }else{\n char P; P = *begin++;\n res = to[P];\n }\n\n\n return res;\n}\n\nvector<int> factor(State &begin){\n if(*begin == '('){\n consume(begin, '('); // '('を飛ばす。\n auto res = expression(begin);\n consume(begin, ')'); // ')'を飛ばす。\n return res;\n }else{\n char P = *begin++;\n return to[P];\n }\n}\n\n\n\n// 数字の列をパースして、その数を返す。\nint number(State &begin){\n int res = 0;\n while(isdigit(*begin)){\n res *= 10;\n res += *begin - '0';\n begin++;\n }\n\n return res;\n}\n\nvoid solve(string S){\n State begin = S.begin();\n vector<int> ans = expression(begin);\n cout << ans;\n}\n\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int K; cin >> N >> K;\n char P; int H;\n REP(_,K){\n cin >> P >> H;\n to[P] = init_amida(N);\n REP(j, H-1){\n REP(i, N-1){\n int g; cin >> g;\n if(g==1){\n swap(to[P][i], to[P][i+1]);\n }\n }\n }\n }\n int E; cin >> E;\n REP(_, E){\n string S; cin >> S;\n solve(S);\n\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3396, "score_of_the_acc": -0.7305, "final_rank": 8 }, { "submission_id": "aoj_0291_5961149", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> parse(vector<vector<int>> &P, int N, string &S, int &p){\n\tint x = 0;\n\twhile (isdigit(S[p]) != 0){\n\t x = x * 10 + (S[p] - '0');\n\t p++;\n\t}\n\tif (x == 0){\n\t x = 1;\n\t}\n\tvector<int> r;\n if (isalpha(S[p]) != 0){\n r = P[S[p] - 'A'];\n p++;\n } else {\n p++;\n r = vector<int>(N);\n for (int i = 0; i < N; i++){\n r[i] = i;\n }\n while (true){\n vector<int> res = parse(P, N, S, p);\n vector<int> r2(N);\n for (int i = 0; i < N; i++){\n r2[i] = r[res[i]];\n }\n swap(r, r2);\n if (S[p] != '+'){\n break;\n }\n p++;\n }\n p++;\n }\n vector<int> ans(N);\n for (int i = 0; i < N; i++){\n ans[i] = i;\n }\n while (x > 0){\n if (x % 2 == 1){\n vector<int> ans2(N);\n for (int i = 0; i < N; i++){\n ans2[i] = ans[r[i]];\n }\n swap(ans, ans2);\n }\n vector<int> r2(N);\n for (int i = 0; i < N; i++){\n r2[i] = r[r[i]];\n }\n swap(r, r2);\n x /= 2;\n }\n return ans;\n}\nint main(){\n int N, K;\n cin >> N >> K;\n vector<char> p(K);\n vector<int> h(K);\n vector<vector<vector<int>>> g(K);\n for (int i = 0; i < K; i++){\n cin >> p[i] >> h[i];\n g[i] = vector<vector<int>>(h[i] - 1, vector<int>(N - 1));\n for (int j = 0; j < h[i] - 1; j++){\n for (int k = 0; k < N - 1; k++){\n cin >> g[i][j][k];\n }\n }\n }\n vector<vector<int>> P(26, vector<int>(N));\n for (int i = 0; i < 26; i++){\n for (int j = 0; j < N; j++){\n P[i][j] = j;\n }\n }\n for (int i = 0; i < K; i++){\n int id = p[i] - 'A';\n for (int j = 0; j < h[i] - 1; j++){\n for (int k = 0; k < N - 1; k++){\n if (g[i][j][k] == 1){\n swap(P[id][k], P[id][k + 1]);\n }\n }\n }\n }\n int E;\n cin >> E;\n for (int i = 0; i < E; i++){\n string S;\n cin >> S;\n S = \"1(\" + S + \")\";\n int x = 0;\n vector<int> ans = parse(P, N, S, x);\n for (int j = 0; j < N; j++){\n cout << ans[j] + 1;\n if (j < N - 1){\n cout << ' ';\n }\n }\n cout << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3424, "score_of_the_acc": -0.7725, "final_rank": 9 }, { "submission_id": "aoj_0291_5921496", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\nvector<int> mult(vector<int> a,vector<int> b){\n vector<int> res(a.size());\n rep(i,a.size()){\n res[i] = b[a[i]];\n }\n return res;\n}\n\nvector<int> input(int n,int h){\n vector<int> ami(n);\n iota(all(ami),0);\n rep(_,h-1){\n rep(x,n-1){\n if(in()){\n swap(ami[x],ami[x+1]);\n }\n }\n }\n vector<int> res(n);\n rep(i,n){\n res[ami[i]] = i;\n }\n return res;\n}\n\nvector<int> rev(vector<int> line){\n vector<int> res(line.size());\n rep(i,line.size()){\n res[line[i]] = i;\n }\n return res;\n}\n\ntemplate <class t>\nt pow(t x,ll y,function<t(t,t)> f,t e){\n t res = e;\n while(y){\n if(y&1)res = f(res,x);\n x = f(x,x);\n y >>= 1;\n }\n return res;\n}\n\nvvector<int> func(){\n int n = in();\n map<char,vector<int>> changes;\n {\n int m = in();\n rep(_,m){\n char c = in<char>();\n int h = in();\n changes[c] = input(n,h);\n }\n }\n vector<int> e(n);\n iota(all(e),0);\n using P = pair<vector<int>,int>;\n method(is_number,bool,char c){\n return '0' <= c and c <= '9';\n };\n method(read_number,pll,string &str,int p){\n ll res = 0;\n while(p < str.size() and is_number(str[p])){\n res = res * 10 + str[p] - '0';\n ++p;\n }\n return pll(res,p);\n };\n method(assemble,P,string &str,int p){\n auto res = e;\n while(p < str.size()){\n if(str[p]==')')break;\n if(str[p]=='('){\n P v = assemble(str,p+1);\n res = mult(res,v.first);\n p = v.second;\n continue;\n }\n if(is_number(str[p])){\n pll v = read_number(str,p);\n if(str[v.second]=='('){\n P v2 = assemble(str,v.second+1);\n res = mult(res,pow<vector<int>>(v2.first,v.first,mult,e));\n p = v2.second;\n }else{\n res = mult(res,pow<vector<int>>(changes[str[v.second]],v.first,mult,e));\n p = v.second + 1;\n }\n continue;\n }\n if(str[p]=='+'){\n ++p;\n continue;\n }\n res = mult(res,changes[str[p]]);\n ++p;\n }\n return P(res,p+1);\n };\n int q = in();\n vvector<int> res;\n rep(_,q){\n string expression = in<string>();\n vector<int> add = assemble(expression,0).first;\n add = rev(add);\n foreach(i,add)++i;\n res.emplace_back(add);\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n println(func());\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3508, "score_of_the_acc": -0.909, "final_rank": 16 }, { "submission_id": "aoj_0291_5759604", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<sstream>\n#include<regex>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nconst double eps=1e-10;\ntypedef vector<int>rep;\nrep concat(rep a,rep b){\n\trep ans(a.size());\n\tfor(int i=0;i<a.size();i++)\n\t\tans[i]=a[b[i]];\n\treturn ans;\n}\nrep repet(rep a,int n){\n\trep ans(a.size());\n\tiota(ans.begin(),ans.end(),0);\n\twhile(n){\n\t\tif(n&1)\n\t\t\tans=concat(ans,a);\n\t\ta=concat(a,a);\n\t\tn>>=1;\n\t}\n\treturn ans;\n}\nrep amida[26];\ntypedef string::const_iterator state;\nrep expr(state&it);\nint number(state&it){\n\tint ret;\n\tfor(ret=0;'0'<=*it&&*it<='9';it++)\n\t\tret=ret*10+*it-'0';\n\treturn ret;\n}\nrep factor(state&it){\n\tif('A'<=*it&&*it<='Z')\n\t\treturn amida[*it++-'A'];\n\trep ret=expr(++it);\n\tit++;\n\treturn ret;\n}\nrep term(state&it){\n\tint num=1;\n\tif('0'<=*it&&*it<='9')\n\t\tnum=number(it);\n\trep ret=factor(it);\n\treturn repet(ret,num);\n}\nrep expr(state&it){\n\trep ret=term(it);\n\twhile(*it=='+')\n\t\t\tret=concat(ret,term(++it));\n\treturn ret;\n}\nsigned main(){\n\tint n,k;\n\tcin>>n>>k;\n\tfor(int i=0;i<k;i++){\n\t\tchar p;\n\t\tint h;\n\t\tcin>>p>>h;\n\t\tamida[p-'A'].resize(n);\n\t\tiota(amida[p-'A'].begin(),amida[p-'A'].end(),0);\n\t\tfor(int j=0;j<h-1;j++){\n\t\t\tfor(int l=0;l<n-1;l++){\n\t\t\t\tint g;\n\t\t\t\tcin>>g;\n\t\t\t\tif(g==1)\n\t\t\t\t\tswap(amida[p-'A'][l],amida[p-'A'][l+1]);\n\t\t\t}\n\t\t}\n\t}\n\tint e;\n\tcin>>e;\n\tcin.ignore();\n\tstring expression;\n\twhile(getline(cin,expression)){\n\t\texpression+=',';\n\t\tstate it=expression.begin();\n\t\trep ans=expr(it);\n\t\tfor(int i=0;i<n;i++)\n\t\t\tcout<<ans[i]+1<<(i==n-1?'\\n':' ');\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3448, "score_of_the_acc": -0.8084, "final_rank": 12 }, { "submission_id": "aoj_0291_4976755", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll>P;\n\nconst int MOD=1000000007;\nconst int INF=0x3f3f3f3f;\nconst ll INFL=0x3f3f3f3f3f3f3f3f;\n\nchar C[2];\n\nvector<int>operator+(vector<int>a,vector<int>&b){\n\trep(i,a.size()){\n\t\ta[i]=b[a[i]];\n\t}\n\treturn a;\n}\n\nvector<int>ppow(vector<int>a,int b){\n\tvector<int>res(a.size());\n\trep(i,res.size())res[i]=i;\n\twhile(b){\n\t\tif(b&1)res=res+a;\n\t\ta=a+a;\n\t\tb>>=1;\n\t}\n\treturn res;\n}\n\nvector<int>p[26];\n\n\nvector<int>expr(string&s,int&i);\nvector<int>term(string&s,int&i);\n\nvector<int>expr(string&s,int&i){//'+'\n\tvector<int>l=term(s,i);\n\twhile(s[i]=='+'){\n\t\ti++;\n\t\tvector<int>r=term(s,i);\n\t\tl=l+r;\n\t}\n\treturn l;\n}\n\nvector<int>term(string&s,int&i){\n\tint d=0;\n\twhile(isdigit(s[i])){\n\t\td=d*10+s[i]-'0';\n\t\ti++;\n\t}\n\tif(d==0)d=1;\n\tif(isalpha(s[i])){\n\t\tvector<int>res=ppow(p[s[i]-'A'],d);\n\t\ti++;\n\t\treturn res;\n\t}\n\telse{\n\t\tassert(s[i]=='(');\n\t\ti++;\n\t\tvector<int>res=expr(s,i);\n\t\ti++;\n\t\tres=ppow(res,d);\n\t\treturn res;\n\t}\n}\n\nint main(){\n\tint n,K;cin>>n>>K;\n\trep(i,K){\n\t\tint h;scanf(\"%s%d\",C,&h);\n\t\tvector<int>v(n);\n\t\trep(j,n)v[j]=j;\n\t\trep(j,h-1){\n\t\t\trep(k,n-1){\n\t\t\t\tint g;scanf(\"%d\",&g);\n\t\t\t\tif(g==1)swap(v[k],v[k+1]);\n\t\t\t}\n\t\t}\n\t\tvector<int>u(n);\n\t\trep(j,n)u[v[j]]=j;\n\t\tp[C[0]-'A']=u;\n\t}\n\tint E;scanf(\"%d\",&E);\n\trep(Case,E){\n\t\tstring s;cin>>s;\n\t\tint i=0;\n\t\tauto res=expr(s,i);\n\t\tvector<int>ans(n);\n\t\trep(j,n){\n\t\t\tans[res[j]]=j;\n\t\t}\n\t\trep(j,ans.size()){\n\t\t\tif(j)printf(\" \");\n\t\t\tprintf(\"%d\",ans[j]+1);\n\t\t}\n\t\tputs(\"\");\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3304, "score_of_the_acc": -0.5928, "final_rank": 5 }, { "submission_id": "aoj_0291_3858299", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing ull=unsigned long long;\nusing uint=unsigned int;\nusing pcc=pair<char,char>;\nusing pii=pair<int,int>;\nusing pll=pair<ll,ll>;\nusing pdd=pair<double,double>;\nusing tuplis=pair<ll,pll>;\nusing tuplis2=pair<pll,ll>;\ntemplate<class T> using pq=priority_queue<T,vector<T>,greater<T>>;\nconst ll LINF=0x1fffffffffffffff;\nconst ll MINF=0x7fffffffffff;\nconst int INF=0x3fffffff;\nconst ll MOD=1000000007;\nconst ll MODD=998244353;\nconst ld DINF=numeric_limits<ld>::infinity();\nconst ld EPS=1e-9;\nconst ld PI=3.141592653589793238462643383279;\nconst vector<ll>four{0,1,0,-1,0};\n#define _overload4(_1,_2,_3,_4,name,...) name\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<n;++i)\n#define _rep2(i,n) for(ll i=0;i<n;++i)\n#define _rep3(i,a,b) for(ll i=a;i<b;++i)\n#define _rep4(i,a,b,c) for(ll i=a;i<b;i+=c)\n#define rep(...) _overload4(__VA_ARGS__,_rep4,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define _rrep1(n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep2(i,n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep3(i,a,b) for(ll i=(b)-1;i>=a;i--)\n#define _rrep4(i,a,b,c) for(ll i=a+(b-a-1)/c*c;i>=a;i-=c)\n#define rrep(...) _overload4(__VA_ARGS__,_rrep4,_rrep3,_rrep2,_rrep1)(__VA_ARGS__)\n#define each(i,a) for(auto &i:a)\n#define sum(...) accumulate(range(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(range(__VA_ARGS__),double(0))\n#define _range(i) (i).begin(),(i).end()\n#define _range2(i,k) (i).begin(),(i).begin()+k\n#define _range3(i,a,b) (i).begin()+a,(i).begin()+b\n#define range(...) _overload3(__VA_ARGS__,_range3,_range2,_range)(__VA_ARGS__)\n#define _rrange(i) (i).rbegin(),(i).rend()\n#define _rrange2(i,k) (i).rbegin(),(i).rbegin()+k\n#define _rrange3(i,a,b) (i).rbegin()+a,(i).rbegin()+b\n#define rrange(...) _overload3(__VA_ARGS__,_rrange3,_rrange2,_rrange)(__VA_ARGS__)\n#define elif else if\n#define unless(a) if(!(a))\n#define mp make_pair\n#define mt make_tuple\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\ninline constexpr ll gcd(ll a,ll b){if(!a||!b)return 0;while(b){ll c=b;b=a%b;a=c;}return a;}\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\ntemplate<class T> inline constexpr T min(vector<T> &v){return *min_element(range(v));}\ninline char min(string &v){return *min_element(range(v));}\ntemplate<class T> inline constexpr T max(vector<T> &v){return *max_element(range(v));}\ninline char max(string &v){return *max_element(range(v));}\ninline constexpr ll intpow(ll a,ll b){ll ans=1;for(ll i=1;b;i*=2){if(b&i){b^=i;ans*=a;}a*=a;}return ans;}\ntemplate<typename T>\ninline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<typename T>\ninline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\ntemplate<class T> unordered_map<T,ll> press(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); unordered_map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ntemplate<class T> map<T,ll> press_map(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ninline int scan(){ return getchar(); }\ninline void scan(int &a){ scanf(\"%d\", &a); }\ninline void scan(unsigned &a){ scanf(\"%u\", &a); }\ninline void scan(long &a){ scanf(\"%ld\", &a); }\ninline void scan(long long &a){ scanf(\"%lld\", &a); }\ninline void scan(unsigned long long &a){ scanf(\"%llu\", &a); }\ninline void scan(char &a){ cin >> a; }\ninline void scan(float &a){ scanf(\"%f\", &a); }\ninline void scan(double &a){ scanf(\"%lf\", &a); }\ninline void scan(long double &a){ scanf(\"%Lf\", &a); }\ninline void scan(vector<bool> &vec){ for(unsigned i = 0; i < vec.size(); i++) { int a; scan(a); vec[i] = a; } }\ninline void scan(string &a){ cin >> a; }\ntemplate<class T> inline void scan(vector<T> &vec);\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec);\ntemplate<class T, class L> inline void scan(pair<T, L> &p);\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]);\ntemplate<class T> inline void scan(vector<T> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, class L> inline void scan(pair<T, L> &p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]){ for(auto &i : vec) scan(i); }\ntemplate<class T> inline void scan(T &a){ cin>>a; }\ninline void in(){}\ntemplate <class Head, class... Tail> inline void in(Head &head, Tail&... tail){ scan(head); in(tail...); }\ninline void print(){ putchar(' '); }\ninline void print(const bool &a){ printf(\"%d\", a); }\ninline void print(const int &a){ printf(\"%d\", a); }\ninline void print(const unsigned &a){ printf(\"%u\", a); }\ninline void print(const long &a){ printf(\"%ld\", a); }\ninline void print(const long long &a){ printf(\"%lld\", a); }\ninline void print(const unsigned long long &a){ printf(\"%llu\", a); }\ninline void print(const char &a){ printf(\"%c\", a); }\ninline void print(const char a[]){ printf(\"%s\", a); }\ninline void print(const float &a){ printf(\"%.15f\", a); }\ninline void print(const double &a){ printf(\"%.15f\", a); }\ninline void print(const long double &a){ printf(\"%.15Lf\", a); }\ntemplate<class T> void print(const vector<T> &vec);\ntemplate<class T, size_t size> void print(const array<T, size> &vec);\ntemplate<class T, class L> void print(const pair<T, L> &p);\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]);\ntemplate<class T> void print(const vector<T> &vec){ if(vec.empty()) return; print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size> &vec){ print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L> &p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]){ print(vec[0]); for(auto i = vec; ++i != end(vec); ){ putchar(' '); print(*i); } }\ntemplate<class T> inline void print(const T &a){ cout << a; }\ninline int out(){ putchar('\\n'); return 0; }\ntemplate<class T> inline int out(const T &t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> inline int out(const Head &head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\ntemplate <class T> inline void err(T t){cerr<<t<<'\\n';}\ninline void err(){cerr<<'\\n';}\ninline int first(const bool &i){return out(i?\"first\":\"second\");}\ninline int yes(const bool &i){return out(i?\"yes\":\"no\");}\ninline int Yes(const bool &i){return out(i?\"Yes\":\"No\");}\ninline int YES(const bool &i){return out(i?\"YES\":\"NO\");}\ninline int Yay(const bool &i){return out(i?\"Yay!\":\":(\");}\ninline int Possible(const bool &i){return out(i?\"Possible\":\"Impossible\");}\ninline int POSSIBLE(const bool &i){return out(i?\"POSSIBLE\":\"IMPOSSIBLE\");}\ninline void Case(ll i){printf(\"Case #%lld: \",i);}\n\n\n\nstruct Permutation { // 0-indexed\n vector<ll> perm;\n Permutation(initializer_list<ll>&& perm): perm(perm) {}\n Permutation(vector<ll>&& perm): perm(perm) {}\n template<class T> Permutation(const initializer_list<T>& perm): perm(perm.begin(), perm.end()) {}\n template<class T> Permutation(const vector<T>& perm): perm(perm.begin(), perm.end()) {}\n static Permutation identity(ll n) { vector<ll> ans(n); iota(ans.begin(), ans.end(), 0); return ans; }\n Permutation inv() const { vector<ll> ans(perm.size()); rep(perm.size()) ans[perm[i]] = i; return ans; }\n Permutation operator* (const Permutation& x) const { vector<ll> ans(perm.size()); rep(perm.size()) ans[i] = perm[x.perm[i]]; return ans; }\n Permutation& operator*=(const Permutation& x) { vector<ll> ans(perm.size()); rep(perm.size()) ans[i] = perm[x.perm[i]]; perm.swap(ans); return *this; }\n Permutation pow(ll x) const {\n Permutation ans = identity(perm.size()), cnt = *this;\n while(x){\n if(x & 1) ans *= cnt;\n x /= 2;\n cnt *= cnt;\n }\n return ans;\n }\n};\nvector<Permutation>parts;\nstring s;\nPermutation parse(ll l,ll r){\n Permutation ans=parts.back();\n while(r>l){\n if(s[l]>='0'&&s[l]<='9'){\n ll at=l;\n while(s[l]>='0'&&s[l]<='9')l++;\n if(s[l]=='('){\n ll cnt=1,at2=l;\n while(cnt){\n l++;\n if(s[l]=='(')cnt++;\n if(s[l]==')')cnt--;\n }\n ans*=parse(at2+1,l).pow(stoll(s.substr(at,at2-at)));\n l+=2;\n }\n else{\n ans*=parts[s[l]-'A'].pow(stoll(s.substr(at,l-at)));\n l+=2;\n }\n }\n else{\n ans*=parts[s[l]-'A'];\n l+=2;\n }\n }\n return ans;\n}\nsigned main(){\n LL(n,k);\n parts.assign(27,Permutation::identity(n));\n rep(k){\n CHR(c);\n LL(k);\n c-='A';\n auto& p=parts[c].perm;\n rep(k-1){\n VEC(ll,a,n-1);\n rep(n-1)if(a[i])swap(p[i],p[i+1]);\n }\n }\n LL(q);\n rep(q){\n in(s);\n auto ans=parse(0,s.size()).perm;\n each(i,ans)i++;\n out(ans);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3328, "score_of_the_acc": -0.6287, "final_rank": 6 }, { "submission_id": "aoj_0291_3052113", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<numeric>\nusing namespace std;\nint N,K;\nvoid in(vector<vector<int> >&a)\n{\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tfor(int j=0;j<N;j++)a[i][j]=0;\n\t}\n\tint h;cin>>h;\n\tvector<int>s(N);\n\tiota(s.begin(),s.end(),0);\n\tfor(;--h;)\n\t{\n\t\tfor(int i=0;i<N-1;i++)\n\t\t{\n\t\t\tint u;cin>>u;\n\t\t\tif(u)swap(s[i],s[i+1]);\n\t\t}\n\t}\n\tfor(int i=0;i<N;i++)\n\t{\n\t\ta[i][s[i]]=1;\n\t}\n}\nvector<vector<int> >mul(const vector<vector<int> >&a,const vector<vector<int> >&b)\n{\n\tvector<vector<int> >ans(N,vector<int>(N,0));\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tfor(int j=0;j<N;j++)\n\t\t{\n\t\t\tfor(int k=0;k<N;k++)ans[i][j]+=a[i][k]*b[k][j];\n\t\t}\n\t}\n\treturn ans;\n}\nvector<vector<int> >power(const vector<vector<int> >&a,int n)\n{\n\tvector<vector<int> >ans(N,vector<int>(N,0));\n\tvector<vector<int> >A(a);\n\tfor(int i=0;i<N;i++)ans[i][i]=1;\n\twhile(n)\n\t{\n\t\tif(n&1)\n\t\t{\n\t\t\tans=mul(ans,A);\n\t\t}\n\t\tn/=2;\n\t\tA=mul(A,A);\n\t}\n\treturn ans;\n}\nstring s;int id;\nvector<vector<int> >f(const vector<vector<vector<int> > >&A)\n{\n\tvector<vector<int> >ans(N,vector<int>(N,0));\n\tfor(int i=0;i<N;i++)ans[i][i]=1;\n\tint now=0;\n\tfor(;id<s.size();id++)\n\t{\n\t\tif(s[id]=='(')\n\t\t{\n\t\t\tid++;\n\t\t\tans=mul(power(f(A),now>0?now:1),ans);\n\t\t\tnow=0;\n\t\t}\n\t\telse if(s[id]>='A'&&s[id]<='Z')\n\t\t{\n\t\t\tans=mul(power(A[s[id]-'A'],now>0?now:1),ans);\n\t\t\tnow=0;\n\t\t}\n\t\telse if(s[id]>='0'&&s[id]<='9')\n\t\t{\n\t\t\tnow=now*10+s[id]-'0';\n\t\t}\n\t\telse if(s[id]==')')\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn ans;\n}\nmain()\n{\n\tcin>>N>>K;\n\tvector<vector<vector<int> > >A(26,vector<vector<int> >(N,vector<int>(N)));\n\tfor(int i=0;i<K;i++)\n\t{\n\t\tchar c;cin>>c;\n\t\tin(A[c-'A']);\n\t}\n\tint E;cin>>E;\n\tfor(;E--;)\n\t{\n\t\tcin>>s;\n\t\tid=0;\n\t\tvector<vector<int> >a=f(A);\n\t\tfor(int i=0;i<N;i++)\n\t\t{\n\t\t\tif(i)cout<<\" \";\n\t\t\tfor(int j=0;j<N;j++)if(a[i][j]==1)cout<<j+1;\n\t\t}\n\t\tcout<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 3304, "score_of_the_acc": -1.2917, "final_rank": 19 }, { "submission_id": "aoj_0291_3020750", "code_snippet": "#include <cstdio>\n#include <cctype>\n#include <cassert>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <map>\n#include <numeric>\n\nusing Amida=std::vector<size_t>;\n\nAmida append(const Amida &lhs, const Amida &rhs) {\n Amida res(lhs.size());\n std::iota(res.begin(), res.end(), 0);\n for (size_t i=0; i<res.size(); ++i)\n res[i] = rhs[lhs[i]];\n\n return res;\n}\n\nAmida repeat(const Amida &base, int times) {\n Amida res(base.size());\n std::iota(res.begin(), res.end(), 0);\n for (Amida dbl=base; times; times>>=1) {\n if (times & 1) res = append(res, dbl);\n dbl = append(dbl, dbl);\n }\n return res;\n}\n\nAmida parse(\n const std::string &s, size_t &i, const std::map<char, Amida> &expr,\n size_t preced=0) {\n\n if (preced == 1) {\n int times=1;\n if (isdigit(s[i])) {\n times = s[i]-'0';\n while (++i < s.length() && isdigit(s[i]))\n times = times*10+s[i]-'0';\n }\n if (isupper(s[i])) {\n Amida base=expr.at(s[i++]);\n return repeat(base, times);\n }\n if (s[i] == '(') {\n Amida base=parse(s, ++i, expr, 0);\n assert(s[i] == ')');\n ++i;\n return repeat(base, times);\n }\n assert(false);\n }\n\n Amida lhs=parse(s, i, expr, 1);\n while (i < s.length()) {\n char op=s[i];\n if (op != '+') break;\n Amida rhs=parse(s, ++i, expr, 1);\n lhs = append(lhs, rhs);\n }\n return lhs;\n}\n\nint main() {\n size_t N, K;\n scanf(\"%zu %zu\", &N, &K);\n\n std::map<char, Amida> expr;\n for (size_t i=0; i<K; ++i) {\n char p;\n size_t h;\n scanf(\" %c %zu\", &p, &h);\n Amida g(N);\n std::iota(g.begin(), g.end(), 0);\n for (size_t r=1; r<h; ++r) {\n for (size_t c=1; c<N; ++c) {\n int f;\n scanf(\"%d\", &f);\n if (f) std::swap(g[c-1], g[c]);\n }\n }\n Amida gg(N);\n for (size_t c=0; c<N; ++c)\n gg[g[c]] = c;\n\n expr[p] = gg;\n }\n\n size_t E;\n scanf(\"%zu\", &E);\n for (size_t i=0; i<E; ++i) {\n char buf[1024];\n scanf(\"%s\", buf);\n std::string s=buf;\n size_t j=0;\n Amida vla=parse(s, j, expr);\n Amida res(N);\n for (size_t k=0; k<N; ++k)\n res[vla[k]] = k;\n for (size_t k=0; k<N; ++k)\n printf(\"%zu%c\", res[k]+1, k+1<N? ' ':'\\n');\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2908, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0291_2859388", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\ntypedef vector<int> V;\ntypedef vector<V> MATRIX;\n\nint N;\nint table[26][12][12];\nchar equation[1001];\n\nMATRIX calc(MATRIX left,MATRIX right){\n\n\tMATRIX ret(N,V(N));\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k < N; k++)ret[i][k] = 0;\n\t}\n\n\tfor(int row = 0; row < N; row++){\n\t\tfor(int col = 0; col < N; col++){\n\t\t\tfor(int a = 0; a < N; a++){\n\t\t\t\tret[row][col] += left[row][a]*right[a][col];\n\t\t\t}\n\t\t}\n\t}\n\n\treturn ret;\n\n}\n\n//MULTのT乗を計算する\nMATRIX pow(MATRIX MULT,int count){\n\n\tMATRIX ret(N,V(N));\n\n\tfor(int row = 0; row < N; row++){\n\t\tfor(int col = 0; col < N; col++){\n\t\t\tif(row == col)ret[row][col] = 1;\n\t\t\telse{\n\t\t\t\tret[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\n\twhile(count > 0){\n\t\tif(count%2 == 1)ret = calc(ret,MULT);\n\t\tMULT = calc(MULT,MULT);\n\t\tcount /= 2;\n\t}\n\n\treturn ret;\n}\n\nMATRIX recursive(int left,int right){\n\n\tbool is_First = true;\n\tMATRIX RET(N,V(N)),CALC(N,V(N));\n\tint num;\n\n\tfor(int i = left; i <= right; ){\n\n\t\tif(equation[i] >= '0' && equation[i] <= '9'){\n\t\t\tnum = 0;\n\t\t\twhile(equation[i] >= '0' && equation[i] <= '9'){\n\t\t\t\tnum = 10*num+equation[i]-'0';\n\t\t\t\ti++;\n\t\t\t}\n\n\t\t\tif(equation[i] == '('){\n\t\t\t\tint depth = 0,close_pos;\n\n\t\t\t\tfor(int k = i; ; k++){\n\t\t\t\t\tif(equation[k] == '(')depth++;\n\t\t\t\t\telse if(equation[k] == ')'){\n\t\t\t\t\t\tdepth--;\n\t\t\t\t\t\tif(depth == 0){\n\t\t\t\t\t\t\tclose_pos = k;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tCALC = recursive(i+1,close_pos-1);\n\n\t\t\t\tCALC = pow(CALC,num);\n\n\t\t\t\tif(is_First){ //計算区間で、まだ行列が登場していない場合\n\t\t\t\t\tRET = CALC;\n\t\t\t\t\tis_First = false;\n\t\t\t\t}else{ //既に行列が登場している場合は、+で連結されているはず\n\t\t\t\t\tRET = calc(RET,CALC);\n\t\t\t\t}\n\n\t\t\t\ti = close_pos+1;\n\n\t\t\t}else{ //右に単項\n\n\t\t\t\tCALC = recursive(i,i);\n\t\t\t\tCALC = pow(CALC,num);\n\n\t\t\t\tif(is_First){ //計算区間で、まだ行列が登場していない場合\n\t\t\t\t\tRET = CALC;\n\t\t\t\t\tis_First = false;\n\t\t\t\t}else{ //既に行列が登場している場合は、+で連結されているはず\n\t\t\t\t\tRET = calc(RET,CALC);\n\t\t\t\t}\n\t\t\t\ti += 1;\n\t\t\t}\n\n\t\t}else if(equation[i] >= 'A' && equation[i] <= 'Z'){\n\t\t\tif(is_First){ //行列が初登場の場合\n\n\t\t\t\tfor(int row = 0; row < N; row++){\n\t\t\t\t\tfor(int col = 0; col < N; col++){\n\t\t\t\t\t\tRET[row][col] = table[equation[i]-'A'][row][col];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tis_First = false;\n\n\t\t\t}else{ // ...+Xの形\n\n\t\t\t\tfor(int row = 0; row < N; row++){\n\t\t\t\t\tfor(int col = 0; col < N; col++){\n\t\t\t\t\t\tCALC[row][col] = table[equation[i]-'A'][row][col];\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tRET = calc(RET,CALC);\n\n\t\t\t}\n\t\t\ti++;\n\t\t}else{ //equation[i] == '+'\n\t\t\ti++;\n\t\t}\n\t}\n\treturn RET;\n}\n\n\n\nint main(){\n\n\tint K;\n\n\tscanf(\"%d %d\",&N,&K);\n\n\tfor(int i = 0; i < 26; i++){\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tfor(int p = 0; p < N; p++)table[i][k][p] = 0;\n\t\t}\n\t}\n\n\tint height,work[N],tmp;\n\tchar buf[2];\n\n\tfor(int loop = 0; loop < K; loop++){\n\t\tscanf(\"%s %d\",buf,&height);\n\n\t\tfor(int i = 0; i < N; i++)work[i] = i;\n\n\t\t//あみだくじの情報を計算\n\t\tfor(int k = 0; k < height-1; k++){\n\t\t\tfor(int loc = 0; loc < N-1; loc++){\n\t\t\t\tscanf(\"%d\",&tmp);\n\t\t\t\tif(tmp == 1){\n\t\t\t\t\tswap(work[loc],work[loc+1]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//遷移先を記録\n\t\tfor(int i = 0; i < N; i++){\n\t\t\ttable[buf[0]-'A'][work[i]][i] = 1;\n\t\t}\n\t}\n\n\tMATRIX RET(N,V(N));\n\tint E;\n\tscanf(\"%d\",&E);\n\n\tint length,ans[N];\n\n\tfor(int loop = 0; loop < E; loop++){\n\t\tscanf(\"%s\",equation);\n\n\t\tfor(length = 0; equation[length] != '\\0'; length++);\n\n\t\tRET = recursive(0,length-1);\n\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tfor(int k = 0; k < N; k++){\n\t\t\t\tif(RET[i][k] == 1){\n\t\t\t\t\tans[k] = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor(int i = 0; i < N-1; i++){\n\t\t\tprintf(\"%d \",ans[i]+1);\n\t\t}\n\t\tprintf(\"%d\\n\",ans[N-1]+1);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 3368, "score_of_the_acc": -1.6886, "final_rank": 20 }, { "submission_id": "aoj_0291_2175195", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\nusing namespace std;\nint N, K, Q, h, g; vector<int> p[32]; string s;\nvector<int> merge(vector<int> p1, vector<int> p2) {\n\tvector<int> ret(N);\n\tfor (int i = 0; i < N; i++) ret[i] = p2[p1[i]];\n\treturn ret;\n}\nvector<int> unit(int, int);\nvector<int> expr(int, int);\nvector<int> unit(int l, int r) {\n\tif (r - l == 1) return p[s[l] - 65];\n\tvector<int> res; int mul = 0;\n\tfor (int i = l; i < r; i++) {\n\t\tif (48 <= s[i] && s[i] <= 57) mul = mul * 10 + (s[i] - 48);\n\t\telse if (i != r - 1) {\n\t\t\tres = expr(i + 1, r - 1);\n\t\t\tbreak;\n\t\t}\n\t\telse res = p[s[i] - 65];\n\t}\n\tvector<int> ret(N);\n\tfor (int i = 0; i < N; i++) ret[i] = i;\n\twhile (mul >= 1) {\n\t\tif(mul & 1) ret = merge(ret, res);\n\t\tres = merge(res, res);\n\t\tmul >>= 1;\n\t}\n\treturn ret;\n}\nvector<int> expr(int l, int r) {\n\tvector<int> ret(N);\n\tfor (int i = 0; i < N; i++) ret[i] = i;\n\tint pl = l, depth = 0;\n\tfor (int i = l; i <= r; i++) {\n\t\tif (i != r && s[i] == '(') depth++;\n\t\tif (i != r && s[i] == ')') depth--;\n\t\tif (depth == 0 && (i == r || s[i] == '+')) {\n\t\t\tret = merge(ret, unit(pl, i));\n\t\t\tpl = i + 1;\n\t\t}\n\t}\n\treturn ret;\n}\nint main() {\n\tcin >> N >> K;\n\tfor (int i = 0; i < K; i++) {\n\t\tcin >> s >> h;\n\t\tvector<int> inv(N);\n\t\tfor (int j = 0; j < N; j++) inv[j] = j;\n\t\tfor (int j = 0; j < h - 1; j++) {\n\t\t\tfor (int k = 0; k < N - 1; k++) {\n\t\t\t\tcin >> g;\n\t\t\t\tif (g == 1) swap(inv[k], inv[k + 1]);\n\t\t\t}\n\t\t}\n\t\tp[s[0] - 65].resize(N);\n\t\tfor (int j = 0; j < N; j++) p[s[0] - 65][inv[j]] = j;\n\t}\n\tcin >> Q;\n\twhile(Q--) {\n\t\tcin >> s;\n\t\tvector<int> res = expr(0, s.size());\n\t\tvector<int> ret(N);\n\t\tfor (int i = 0; i < N; i++) ret[res[i]] = i;\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tif (i) cout << ' ';\n\t\t\tcout << ret[i] + 1;\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3120, "score_of_the_acc": -0.3389, "final_rank": 3 }, { "submission_id": "aoj_0291_2068801", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cassert>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <set>\n#include <cassert>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\ntypedef pair<int,P> P1;\ntypedef pair<P,P> P2;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-7\n#define INF 1000000000\n#define fi first\n#define sc second\n#define rep(i,x) for(int i=0;i<x;i++)\n#define SORT(x) sort(x.begin(),x.end())\n#define ERASE(x) x.erase(unique(x.begin(),x.end()),x.end())\n#define POSL(x,v) (lower_bound(x.begin(),x.end(),v)-x.begin())\n#define POSU(x,v) (upper_bound(x.begin(),x.end(),v)-x.begin())\nint n,k;\nint x[30][25];\nstring S;\nint cur = 0;\nvector<int>expr();\nvector<int>term(){\n\tif(S[cur] == '('){\n\t\tcur++; vector<int>V = expr(); cur++; return V;\n\t}\n\tif(0<=S[cur]-'A' && S[cur]-'A'<=25){\n\t\tint r = S[cur]-'A'; cur++;\n\t\tvector<int>V; for(int i=0;i<n;i++) V.pb(x[r][i]);\n\t\treturn V;\n\t}\n\tint val = 0;\n\twhile(0<=S[cur]-'0' && S[cur]-'0'<=9){\n\t\tval = val*10+(S[cur]-'0');\n\t\tcur++;\n\t}\n\tvector<int>rep = term(); \n\tvector<int>now,nw(n); for(int i=0;i<n;i++) now.pb(i);\n\twhile(val){\n\t\tif(val%2){\n\t\t\tfor(int i=0;i<n;i++){\n\t\t\t\tnw[i] = now[rep[i]];\n\t\t\t}\n\t\t\tnow = nw;\n\t\t}\n\t\tfor(int i=0;i<n;i++){\n\t\t\tnw[i] = rep[rep[i]];\n\t\t} \n\t\trep = nw; val/=2;\n\t}\n//for(int i=0;i<n;i++) cout << now[i] << endl;\n\treturn now;\n}\nvector<int> expr(){\n\tvector<int>vi; for(int i=0;i<n;i++) vi.pb(i);\n\tdo{\n\t\tif(S[cur] == '+') cur++;\n\t\tvector<int>ch = term();\n\t\tvector<int>nw(n); for(int i=0;i<n;i++) nw[i] = vi[ch[i]]; vi = nw;\n\t}while(cur<S.size() && S[cur] == '+');\n\treturn vi;\n}\nint main(){\n\tcin >> n >> k;\n\tfor(int i=0;i<k;i++){\n\t\tstring s; cin >> s;\n\t\tint r; cin >> r;\n\t\tvector<int>V; for(int i=0;i<n;i++) V.pb(i);\n\t\tfor(int iy=0;iy<r-1;iy++){\n\t\t\tfor(int j=0;j<n-1;j++){\n\t\t\t\tint y; cin >> y; if(y) swap(V[j],V[j+1]);\n\t\t\t}\n\t\t}\n\t\tfor(int j=0;j<n;j++) x[s[0]-'A'][j] = V[j];\n\t}\n\tint x; cin >> x;\n\tfor(int i=0;i<x;i++){\n\t\tcin >> S;\n\t\tcur = 0; vector<int>vi = expr();\n\t\tfor(int i=0;i<vi.size();i++) cout << vi[i]+1 << (i == n-1?'\\n':' ');\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3196, "score_of_the_acc": -0.4311, "final_rank": 4 } ]
aoj_0288_cpp
巨樹の刻み手 あなたは N 種類の道具を使って、目の前の巨樹を切り倒そうとしています。はじめは、樹の耐久力は D 、あなたの経験値は 0 ですが、道具 i で1回樹を叩くと樹の耐久力は a i 減り、あなたは e i の経験値を得ます。ただし、道具 i を使うためには、あなたは r i 以上の経験値を持っていなければなりません。樹の耐久力が 0 以下になると樹は倒れます。 樹の耐久力と道具についての情報が与えられたとき、樹を切り倒すには最低何回樹を叩かなければいけないかを求めるプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。各データセットは以下の形式で与えられる。 D N a 1 e 1 r 1 a 2 e 2 r 2 : a N e N r N 1 行目に樹の耐久力を表す整数 D (1 ≤ D ≤ 100) と道具の種類の数 N (1 ≤ N ≤ 100) が与えられる。続く N 行に道具 1 から N までの情報が与えられる。 a i (0 ≤ a i ≤ 100) と e i (0 ≤ e i ≤ 100) は、道具iを1回使うことで減る樹の耐久力とあなたが得ることのできる経験値をそれぞれ表す。 r i (0 ≤ r i ≤ 100) は道具を使うために必要な経験値を表す。 a i , e i , r i はすべて整数である。 データセットの数は 50 を超えない。 出力 樹を切り倒すのに必要な、樹を叩く最小の回数を1行に出力する。ただし、樹を切り倒すことが不可能な場合は NA と出力する。 入出力例 入力例 15 4 1 1 0 1 2 2 5 10 5 8 1 15 60 4 5 2 0 8 8 2 3 5 0 49 0 18 100 1 1 1 1 0 0 出力例 6 4 NA
[ { "submission_id": "aoj_0288_10848293", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, int>;\n\nconstexpr int INF = 1e9;\n\nint main() {\n int D, N;\n while(cin >> D >> N, D) {\n using tool = tuple<int, int, int>;\n vector<tool> v(N);\n for(int i=0; i<N; ++i) {\n int a, e, r;\n cin >> a >> e >> r;\n v[i] = make_tuple(a, e, r);\n }\n vector<vector<int>> dp(D+1, vector<int>(101, INF));\n queue<P> que;\n que.push(make_pair(0, 0));\n dp[0][0] = 0;\n while(!que.empty()) {\n P p = que.front();\n que.pop();\n for(int i=0; i<N; ++i) {\n int a, e, r;\n tie(a, e, r) = v[i];\n if(p.second < r) {\n continue;\n }\n int nd = min(D, p.first + a);\n int nr = min(100, p.second + e);\n if(dp[nd][nr] > dp[p.first][p.second] + 1) {\n dp[nd][nr] = dp[p.first][p.second] + 1;\n que.push(make_pair(nd, nr));\n }\n }\n }\n int res = INF;\n for(int i=0; i<101; ++i) {\n res = min(res, dp[D][i]);\n }\n if(res == INF) {\n cout << \"NA\" << endl;\n } else {\n cout << res << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3492, "score_of_the_acc": -0.6275, "final_rank": 9 }, { "submission_id": "aoj_0288_9313520", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {}\n return 0;\n}\n\nint solve() {\n ll D, N;\n cin >> D >> N;\n if (D==0 and N==0) {return 1;}\n vi a(N), e(N), r(N);\n rep(i, N) {cin >> a[i] >> e[i] >> r[i];}\n ll rmax = MAX(r);\n vv(ll, dp, D+1, rmax+1, inf);\n dp[0][0] = 0;\n rep(i, D) {\n rep(j, rmax+1) {\n rep(k, N) {\n if (r[k] > j) {continue;}\n chmin(dp[min(i+a[k], D)][min(j+e[k], rmax)], dp[i][j]+1);\n }\n }\n }\n ll ans = MIN(dp[D]);\n if (ans == inf) print(\"NA\");\n else print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3488, "score_of_the_acc": -0.6601, "final_rank": 11 }, { "submission_id": "aoj_0288_5959793", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1000000;\nint main(){\n while (true){\n int D, N;\n cin >> D >> N;\n if (D == 0 && N == 0){\n break;\n }\n vector<int> a(N), e(N), r(N);\n for (int i = 0; i < N; i++){\n cin >> a[i] >> e[i] >> r[i];\n }\n vector<vector<int>> dp(D + 1, vector<int>(101, INF));\n dp[D][0] = 0;\n for (int i = D; i > 0; i--){\n for (int j = 0; j <= 100; j++){\n for (int k = 0; k < N; k++){\n if (j >= r[k]){\n int i2 = max(i - a[k], 0);\n int j2 = min(j + e[k], 100);\n dp[i2][j2] = min(dp[i2][j2], dp[i][j] + 1);\n }\n }\n }\n }\n int ans = INF;\n for (int i = 0; i <= 100; i++){\n ans = min(ans, dp[0][i]);\n }\n if (ans == INF){\n cout << \"NA\" << endl;\n } else {\n cout << ans << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3464, "score_of_the_acc": -0.6405, "final_rank": 10 }, { "submission_id": "aoj_0288_5921672", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n// {{{\n\n// clang-format off\n#define len(x) (static_cast<int>((x).size()))\n#define _over_load(_1,_2,_3,_4,NAME,...) NAME\n#define range(...) _over_load(__VA_ARGS__, range4, range3, range2)(__VA_ARGS__)\n#define range2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define range3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define range4(i, l, r, step) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (step))\n#define rrange(...) _over_load(__VA_ARGS__, rrange4, rrange3, rrange2)(__VA_ARGS__)\n#define rrange2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrange3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrange4(i, l, r, step) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (step))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename T, typename... T2> void debug_function(string_view name, const T &a, T2 &&...rest) {\n stack<char> bs;\n string_view lbs = \"({[<\", rbs = \")}]>\";\n int end = name.size();\n for ( int i = 0; i < len(name); i++ ) {\n if ( lbs.find(name[i]) != string::npos ) bs.push(name[i]);\n if ( rbs.find(name[i]) != string::npos and !bs.empty() ) bs.pop();\n if ( name[i] == ',' and bs.empty() ) {\n end = i;\n break;\n }\n }\n cerr << name.substr(0, end) << \":\" << a;\n if constexpr ( sizeof...(rest) == 0 ) {\n cerr << '\\n';\n } else {\n cerr << ' ';\n debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<T2>(rest)...);\n }\n}\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << p.first << ' ' << p.second; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { for ( pair<T1, T2> x : v ) { os << \"(\" << x.first <<\", \" << x.second << \")\" << (v.rbegin()->first == x.first ? \"\" : \", \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { if(!v.empty()) { os << v.front(); v.pop(); } while (!v.empty()) { os << \" \" << v.front(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { if(!v.empty()) { os << v.top(); v.pop(); } while (!v.empty()) { os << \" \" << v.top(); v.pop(); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { range(i, len(v)) { cout << v[i] << (i == len(v) - 1 ? \"\" : \" \"); } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_f = true; for ( T x : v ) { os << (is_f ? \"\" : \" \") << x; is_f = false; } return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\nusing ull = unsigned long long;\nusing ll = long long;\nusing Pll = pair<ll, ll>;\nusing P = pair<int, int>;\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, -1, 1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { -1, 0, 0, 1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n// clang-format on\n\n// }}}\n\nvoid solve(int d,int n){\n vector<tuple<int,int,int>> tools(n);\n for(auto &[a,e,r]:tools){\n cin>>a>>e>>r;\n }\n\n constexpr int MAXR = 100;\n auto dp=make_vector(d+1,MAXR+1,INF32);\n\n dp[0][0]=0;\n\n range(i,d + 1){\n range(j,MAXR + 1){\n range(k,n){\n auto [a,e,r]=tools[k];\n if(j<r) continue;\n int nxti=min(d,i+a);\n int nxtj=min(MAXR,j+e);\n chmin(dp[nxti][nxtj],dp[i][j]+1);\n }\n }\n }\n\n int ans = INF32;\n range(j,MAXR+1){\n chmin(ans,dp[d][j]);\n }\n\n if(ans==INF32){\n cout<<\"NA\"<<endl;\n }else{\n cout<<ans<<endl;\n }\n}\n\nint main() {\n\n while(1){\n int d,n;\n cin>>d>>n;\n if(d==0 and n==0) break;\n solve(d,n);\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3484, "score_of_the_acc": -0.6928, "final_rank": 12 }, { "submission_id": "aoj_0288_5921494", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct x{\n int a,e,r;\n};\nvoid solve(int d,int n){\n //dp[101][101] // [回数][現在の経験値] = 耐久値\n int dp[202][101];\n for(int i = 0; 202 > i; i++){\n for(int j = 0; 101 > j; j++){\n dp[i][j] = d+1;\n }\n }\n dp[0][0] = d;\n vector<x> A(n);\n for(int i = 0; n > i; i++){\n cin>>A[i].a>>A[i].e>>A[i].r;\n }\n for(int i = 0; 202 > i; i++){\n for(int j = 0; n > j; j++){\n for(int l = A[j].r; 101 > l; l++){\n if(dp[i][l] == d+1)continue;\n if(dp[i+1][min(100,l+A[j].e)] == d+1){\n dp[i+1][min(100,l+A[j].e)] = dp[i][l]-A[j].a;\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }else{\n dp[i+1][min(100,l+A[j].e)] = min(dp[i+1][min(100,l+A[j].e)] ,dp[i][l]-A[j].a);\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }\n }\n }\n }\n cout << \"NA\" << endl;\n}\n\nint main(){\n int d,n;\n while(cin>>d>>n,d){\n solve(d,n);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3496, "score_of_the_acc": -0.5948, "final_rank": 8 }, { "submission_id": "aoj_0288_5921490", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct x{\n int a,e,r;\n};\nvoid solve(int d,int n){\n //dp[101][101] // [回数][現在の経験値] = 耐久値\n int dp[102][101];\n for(int i = 0; 101 > i; i++){\n for(int j = 0; 101 > j; j++){\n dp[i][j] = d+1;\n }\n }\n dp[0][0] = d;\n vector<x> A(n);\n for(int i = 0; n > i; i++){\n cin>>A[i].a>>A[i].e>>A[i].r;\n }\n for(int i = 0; 101 > i; i++){\n for(int j = 0; n > j; j++){\n for(int l = A[j].r; 101 > l; l++){\n if(dp[i][l] == d+1)continue;\n if(dp[i+1][min(100,l+A[j].e)] == d+1){\n dp[i+1][min(100,l+A[j].e)] = dp[i][l]-A[j].a;\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }else{\n dp[i+1][min(100,l+A[j].e)] = min(dp[i+1][min(100,l+A[j].e)] ,dp[i][l]-A[j].a);\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }\n }\n }\n }\n cout << \"NA\" << endl;\n}\n\nint main(){\n int d,n;\n while(cin>>d>>n,d){\n solve(d,n);\n }\n}", "accuracy": 0.9, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.5229, "final_rank": 17 }, { "submission_id": "aoj_0288_5921476", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct x{\n int a,e,r;\n};\nvoid solve(int d,int n){\n //dp[101][101] // [回数][現在の経験値] = 耐久値\n int dp[101][101];\n for(int i = 0; 101 > i; i++){\n for(int j = 0; 101 > j; j++){\n dp[i][j] = d+1;\n }\n }\n dp[0][0] = d;\n vector<x> A(n);\n for(int i = 0; n > i; i++){\n cin>>A[i].a>>A[i].e>>A[i].r;\n }\n for(int i = 0; 101 > i; i++){\n for(int j = 0; n > j; j++){\n for(int l = A[j].r; 101 > l; l++){\n if(dp[i][l] == d+1)continue;\n if(dp[i+1][min(100,l+A[j].e)] == d+1){\n dp[i+1][min(100,l+A[j].e)] = dp[i][l]-A[j].a;\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }else{\n dp[i+1][min(100,l+A[j].e)] = min(dp[i+1][min(100,l+A[j].e)] ,dp[i][l]-A[j].a);\n if(dp[i][l]-A[j].a <= 0){\n cout << i+1 << endl;\n return;\n }\n }\n }\n }\n }\n cout << \"NA\" << endl;\n}\n\nint main(){\n int d,n;\n while(cin>>d>>n,d){\n solve(d,n);\n }\n}", "accuracy": 0.9, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.5229, "final_rank": 17 }, { "submission_id": "aoj_0288_5921315", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct x{\n int a,e,r;\n};\nvoid solve(int d,int n){\n //dp[101][101] // [幹の耐久力][現在の経験値] = 切り倒す回数\n int dp[101][101];\n bool lck[101][101];\n for(int i = 0; 101 > i; i++){\n for(int j = 0; 101 > j; j++){\n dp[i][j] = -1;\n lck[i][j] = false;\n }\n }\n dp[d][0] = 0;\n lck[d][0] = true; \n vector<x> A(n);\n for(int i = 0; n > i; i++){\n cin>>A[i].a>>A[i].e>>A[i].r;\n }\n for(int i = 0; 101 > i; i++){\n for(int j = 0; n > j; j++){\n for(int k = 0; 101 > k; k++){//耐久力\n for(int l = A[j].r; 101 > l; l++){\n if(dp[k][l] == -1 || lck[max(0,k-A[j].a)][min(100,l+A[j].e)])continue;\n dp[max(0,k-A[j].a)][min(100,l+A[j].e)] = dp[k][l]+1;\n lck[max(0,k-A[j].a)][min(100,l+A[j].e)] = true;\n }\n }\n }\n }\n int ret = -1;\n for(int i = 0; 101 > i; i++){\n if(dp[0][i] != -1){\n if(ret == -1){\n ret = dp[0][i];\n }else{\n ret = min(dp[0][i],ret);\n }\n }\n }\n if(ret == -1)cout << \"NA\" << endl;\n else cout << ret << endl;\n}\n\nint main(){\n int d,n;\n while(cin>>d>>n,d){\n solve(d,n);\n }\n}", "accuracy": 0.1, "time_ms": 90, "memory_kb": 3392, "score_of_the_acc": -0.5817, "final_rank": 19 }, { "submission_id": "aoj_0288_5921284", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct x{\n int a,e,r;\n};\nvoid solve(int d,int n){\n //dp[101][101] // [幹の耐久力][現在の経験値] = 切り倒す回数\n int dp[101][101];\n bool lck[101][101];\n for(int i = 0; 101 > i; i++){\n for(int j = 0; 101 > j; j++){\n dp[i][j] = -1;\n lck[i][j] = false;\n }\n }\n dp[d][0] = 0;\n vector<x> A(n);\n for(int i = 0; n > i; i++){\n cin>>A[i].a>>A[i].e>>A[i].r;\n }\n for(int i = 0; 101 > i; i++){\n for(int j = 0; n > j; j++){\n for(int k = 0; 101 > k; k++){//耐久力\n for(int l = A[j].r; 101 > l; l++){\n if(dp[k][l] == -1 || lck[k-A[j].a][min(100,l+A[j].e)])continue;\n dp[max(0,k-A[j].a)][min(100,l+A[j].e)] = dp[k][l]+1;\n lck[max(0,k-A[j].a)][min(100,l+A[j].e)] = true;\n }\n }\n }\n }\n int ret = -1;\n for(int i = 0; 101 > i; i++){\n if(dp[0][i] != -1){\n if(ret == -1){\n ret = dp[0][i];\n }else{\n ret = min(dp[0][i],ret);\n }\n }\n }\n if(ret == -1)cout << \"NA\" << endl;\n else cout << ret << endl;\n}\n\nint main(){\n int d,n;\n while(cin>>d>>n,d){\n solve(d,n);\n }\n}", "accuracy": 0.1, "time_ms": 100, "memory_kb": 3460, "score_of_the_acc": -0.7124, "final_rank": 20 }, { "submission_id": "aoj_0288_5921160", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\nstring func(int d,int n){\n vector<int> dam(n);\n vector<int> ex(n);\n vector<int> need(n);\n rep(i,n){\n dam[i] = in();\n ex[i] = in();\n need[i] = in();\n }\n vvector<int> dp(101,vector<int>(101,-1));\n method(rec,int,int health,int level){\n chmin(level,100);\n if(health <= 0)return 0;\n int &it = dp[health][level];\n if(it >= 0)return it;\n it = INF;\n rep(i,n){\n if(need[i] <= level){\n chmin(it,1+rec(health-dam[i],level+ex[i]));\n }\n }\n return it;\n };\n int res = rec(d,0);\n return res >= INF ? \"NA\" : to_string(res);\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(true){\n int d = in();\n int n = in();\n if(d==0)break;\n println(func(d,n));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3564, "score_of_the_acc": -0.8235, "final_rank": 14 }, { "submission_id": "aoj_0288_5741526", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<regex>\n#include<sstream>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nsigned main(){\n\tint d,n;\n\twhile(cin>>d>>n,d){\n\t\tint a[100],e[100],r[100];\n\t\tfor(int i=0;i<n;i++)\n\t\t\tcin>>a[i]>>e[i]>>r[i];\n\t\tint dp[101][101];\n\t\tfor(int i=0;i<=d;i++)\n\t\t\tfor(int j=0;j<=100;j++)\n\t\t\t\tdp[i][j]=inf;\n\t\tdp[0][0]=0;\n\t\tfor(int i=0;i<=d;i++)\n\t\t\tfor(int j=0;j<=100;j++)\n\t\t\t\tfor(int k=0;k<n;k++)\n\t\t\t\t\tdp[i][j]=min(dp[i][j],dp[max(i-a[k],0ll)][max(j-e[k],r[k])]+1);\n\t\tif(dp[d][0]==inf)\n\t\t\tcout<<\"NA\"<<endl;\n\t\telse\n\t\t\tcout<<dp[d][0]<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3520, "score_of_the_acc": -0.7124, "final_rank": 13 }, { "submission_id": "aoj_0288_5323017", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n while(1){\n int d,n;\n cin >> d >> n;\n if(d == 0) break;\n\n vector<int> a(n),e(n),r(n);\n for(int i=0; i<n; i++){\n cin >> a[i] >> e[i] >> r[i];\n }\n const int inf = 1e9;\n vector<vector<int>> dp(d+1, vector<int>(101, inf));\n dp[d][0] = 0;\n for(int i=d; i>0; i--){\n for(int j=0; j<=100; j++){\n for(int k=0; k<n; k++){\n if(j < r[k]) continue;\n int ni = max(0, i-a[k]);\n int nj = min(100, j+e[k]);\n dp[ni][nj] = min(dp[ni][nj], dp[i][j]+1);\n }\n }\n }\n int res = *min_element(dp[0].begin(), dp[0].end());\n if(res == inf){\n cout << \"NA\" << endl;\n }else{\n cout << res << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3412, "score_of_the_acc": -0.5556, "final_rank": 7 }, { "submission_id": "aoj_0288_4976536", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define chmin(a,b) a=min(a,b)\n#define chmax(a,b) a=max(a,b)\n#define mod 1000000007\n#define ad(a,b) a=(a+b)%mod;\n#define X 5010\nll po(ll x,ll y){\n\tll res=1;\n\tfor(;y;y>>=1){\n\t\tif(y&1)res=res*x%mod;\n\t\tx=x*x%mod;\n\t}\n\treturn res;\n}\nll fac[X],ivf[X];\nvoid init(){\n\tfac[0]=1;\n\tfor(ll i=1;i<X;i++)fac[i]=fac[i-1]*i%mod;\n\tfor(ll i=0;i<X;i++)ivf[i]=po(fac[i],mod-2);\n}\nll C(ll n,ll k){\n\treturn fac[n]*ivf[n-k]%mod*ivf[k]%mod;\n}\nll dp[110][110];\nbool solve(){\n\trep(i,110)rep(j,110)dp[i][j]=1e17;\n\tll d,n;\n\tcin>>d>>n;\n\tif(n==0&&d==0)return 0;\n\tll a[110],e[110],r[110];\n\trep(i,n)cin>>a[i]>>e[i]>>r[i];\n\tdp[d][0]=0;\n\tll ans=1e17;\n\tfor(int h=d;h>0;h--)for(int w=0;w<=100;w++){\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(a[i]==0&&e[i]==0)continue;\n\t\t\tif(w<r[i])continue;\n\t\t\tif(h-a[i]<=0){\n\t\t\t\tchmin(ans,dp[h][w]+1);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tchmin(dp[h-a[i]][min(100LL,w+e[i])],dp[h][w]+1);\n\t\t}\n\t}\n\tif(ans>=1e17)cout<<\"NA\"<<endl;\n\telse cout<<ans<<endl;\n\treturn 1;\n}\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\twhile(solve()){}\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3312, "score_of_the_acc": -0.451, "final_rank": 6 }, { "submission_id": "aoj_0288_4818333", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\nint main() {\n init();\n\n for (int d, n; cin >> d >> n && d;) {\n VI a(n), e(n), r(n);\n FOR(i, 0, n)cin >> a[i] >> e[i] >> r[i];\n auto dp = defvec<int>(INF, d + 1, 101);\n dp[0][0] = 0;\n FOR(i, 0, d)eFOR(j, 0, 100)FOR(k, 0, n) {\n if (j < r[k])continue;;\n chmin(dp[min(i + a[k], d)][min(j + e[k], 100)],\n dp[i][j] + 1);\n }\n int ans = *min_element(all(dp[d]));\n if (ans == INF)print(\"NA\");\n else print(ans);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3288, "score_of_the_acc": -0.3922, "final_rank": 5 }, { "submission_id": "aoj_0288_4796012", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string.h>\n#include <queue>\n#include<set>\nusing namespace std;\nstruct E{\n\tint a,e,r;\n\tbool operator<(const E& e1)const{\n\t\tif(r!=e1.r)return r<e1.r;\n\t\tif(a!=e1.a)return a<e1.a;\n\t\treturn e<e1.e;\n\t}\n};\nstruct E2{\n\tint no,dmg,exp;\n\tbool operator<(const E2& e1)const{\n\t\tif(no!=e1.no)return no<e1.no;\n\t\treturn dmg<e1.dmg;\n\t}\n};\n\nint dp[102][102];//道具の番号、ダメージ,経験値\n\nint main() {\n\t// your code goes here\nwhile(true){\n\tint d,n;\n\tcin>>d>>n;\n\tif(d+n==0)break;\n\tE e;\n\tvector<E> vs;\n\tmemset(dp,-1,sizeof(dp));\n\tint sum=0;\n\tfor(int i=0;i<n;i++){\n\t\tint a1,e1,r1;\n\t\tcin>>a1>>e1>>r1;\n\t\te.a=a1;\n\t\te.e=e1;\n\t\te.r=r1;\n\t\tvs.push_back(e);\n\t\tsum+=e.a;\n\t}\n\tif(sum==0){\n\t\tcout<<\"NA\"<<endl;\n\t\tcontinue;\n\t}\n\tsort(vs.begin(),vs.end());\n\tint ans=1;\n\tbool ok=false;\n\tqueue<E2> qu;\n\tE2 e2;\n\te2.no=0;\n\te2.dmg=0;\n\te2.exp=0;\n\tqu.push(e2);\n\tint c1=0;\n\n\t\n\twhile(qu.size()>0&&c1<202){\n\t\tc1++;\n\t\tset<E2> ss2;\n\t\twhile(qu.size()>0){\n\t\t\tE2 e2=qu.front();\n\t\t\tqu.pop();\n\t\t\t//cout<<e2.exp<<\" d2=\"<<e2.dmg<<\" \"<<e2.no<<\" \"<<dp[e2.no][e2.dmg]<<endl;\n\t\t\tif(dp[e2.no][e2.dmg]>e2.exp)continue;\n\t\t\tfor(int j=e2.no;j<n;j++){\n\t\t\t\tE e=vs[j];\n\t\t\t\t//cout<<e.e<<\" a=\"<<e.a<<\" \"<<e.r<<endl;\n\t\t\t\tif(e.r>e2.exp)break;\n\t\t\t\tif(e.a+e.e==0)continue;\n\t\t\t\tint dmg2=e.a+e2.dmg;\n\t\t\t\tint exp2=e.e+e2.exp;\n\t\t\t\tif(dmg2>=d){\n\t\t\t\t\tok=true;\n\t\t\t\t\tbreak;\n\t\t\t\t}else{\n\t\t\t\t\tE2 e3;\n\t\t\t\t\te3.no=j;\n\t\t\t\t\te3.dmg=dmg2;\n\t\t\t\t\te3.exp=min(101,exp2);\n\t\t\t\t\t//cout<<e3.exp<<\" d=\"<<e3.dmg<<\" \"<<e3.no<<endl;\n\t\t\t\t\tif(dp[e3.no][e3.dmg]<e3.exp){\n\t\t\t\t\t\tif(ss2.find(e3)==ss2.end()){\n\t\t\t\t\t\t\tss2.insert(e3);\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tauto it=ss2.find(e3);\n\t\t\t\t\t\t\tE2 e4=(*it);\n\t\t\t\t\t\t\tif(e4.exp<e3.exp){\n\t\t\t\t\t\t\t\tss2.erase(it);\n\t\t\t\t\t\t\t\tss2.insert(e3);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(ok==true){\n\t\t\tbreak;\n\t\t}\n\n\t\tset<E2> dells;\n\t\tfor(auto it=ss2.begin();it!=ss2.end();it++){\n\t\t\tE2 e1=(*it);\n\t\t\tfor(auto it2=it;it2!=ss2.end();it2++){\n\t\t\t\tE2 e2=(*it2);\n\t\t\t\tif(e1.no==e2.no){\n\t\t\t\t\tif(e1.exp<e2.exp&&e1.dmg<e2.dmg){\n\t\t\t\t\t\tdells.insert(e1);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}else if(e1.exp==e2.exp&&e1.dmg<e2.dmg){\n\t\t\t\t\t\tdells.insert(e1);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}else if(e1.exp<e2.exp&&e1.dmg==e2.dmg){\n\t\t\t\t\t\tdells.insert(e1);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\t break;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(auto it=dells.begin();it!=dells.end();it++){\n\t\t\tE2 e3=(*it);\n\t\t\tss2.erase(e3);\n\t\t}\n\t\tfor(auto it=ss2.begin();it!=ss2.end();it++){\n\t\t\tE2 e3=(*it);\n\t\t\tqu.push(e3);\n\t\t\tif(dp[e3.no][e3.dmg]<e3.exp){\n\t\t\t\tdp[e3.no][e3.dmg]=e3.exp;\n\t\t\t}\n\t\t}\n\t\t//cout<<ss2.size()<<endl;\n\t\t\n\t\tans++;\n\t}\n\t\n\t\n\tif(ok==true){\n\t\tcout<<ans<<endl;\n\t}else{\n\t\tcout<<\"NA\"<<endl;\n\t}\n}\nreturn 0;\n}", "accuracy": 1, "time_ms": 520, "memory_kb": 3744, "score_of_the_acc": -2, "final_rank": 15 }, { "submission_id": "aoj_0288_4765975", "code_snippet": "#include<iostream>\n#include<string>\n#include <vector>\n#include<algorithm>\n#include <queue>\n\nusing namespace std;\n\nclass Item\n{\npublic:\n\tint a, e, r;\n\tItem() { a = -1; e = -1; r = -1; }\n\tItem(int a, int e, int r)\n\t{\n\t\tthis->a = a;\n\t\tthis->e = e;\n\t\tthis->r = r;\n\t}\n};\n\nint dp[101][101];\n#define nil 99999\n\nint DP(vector<Item> items, int D, int N)\n{\n\tfor(int i = 0 ; i <= 100; i++)\n\t for (int j = 0; j <= 100; j++)\n\t\t dp[i][j] = nil;\n\tdp[D][0] = 0;\n\tfor (int i = D; i >= 0; i--)\n\t{\n\t\tfor (int j = 0; j <= 100; j++)\n\t\t{\n\t\t\tfor (int k = 0; k < N; k++)\n\t\t\t{\n\t\t\t\tif (j >= items[k].r)\n\t\t\t\t{\n\t\t\t\t\tint _exp = min(j + items[k].e, 100);\n\t\t\t\t\tint _d = max(i - items[k].a, 0);\n\t\t\t\t\tdp[_d][_exp] =\n\t\t\t\t\t\tmin(dp[_d][_exp], dp[i][j] + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint minV = dp[0][100];\n\tfor (int j = 0; j < 100; j++)\n\t\tminV = min(minV, dp[0][j]);\n\treturn minV;\n}\nint main()\n{\n\tint D, N;\n\tcin >> D >> N;\n\twhile (D)\n\t{\n\t\tvector<Item> items;\n\t\tbool flag1 = false,flag2 = false;\n\t\tfor (int i = 0; i < N; i++)\n\t\t{\n\t\t\tint a, e, r;\n\t\t\tcin >> a >> e >> r;\n\t\t\tif (a == 0 && e == 0) continue;\n\t\t\tif (r == 0)\n\t\t\t\tflag1 = true;\n\t\t\tif (a > 0)\n\t\t\t\tflag2 = true;\n\t\t\titems.push_back(Item(a, e, r));\n\t\t}\n\t\tif (flag1 && flag2)\n\t\t\tcout << DP(items, D, items.size()) << endl;\n\t\telse\n\t\t\tcout << \"NA\" << endl;\n\t\tcin >> D >> N;\n\t}\n\tcin >> D;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3136, "score_of_the_acc": -0.0654, "final_rank": 2 }, { "submission_id": "aoj_0288_4575436", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint D, N, Ans;\nint Endurance[100], getExperience[100], needExperience[100];\nint DpCount[101][101];\n\nconst int INF = 2e9;\n\nvoid solve() {\n\tint minLife, maxExperience;\n\n\t//fill_n(*DpCount, 101 * 10001, INF);\n\tfor (int i = 0; i < 101; ++i) {\n\t\tfill(DpCount[i], DpCount[i] + 101, INF);\n\t}\n\tDpCount[D][0] = 0;\n\n\tfor (int currentLife = D; currentLife > 0; --currentLife) {\n\t\tfor (int currentExperience = 0; currentExperience < 101; ++currentExperience) {\n\t\t\tif (DpCount[currentLife][currentExperience] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (int i = 0; i < N; ++i) {\n\t\t\t\tif (currentExperience < needExperience[i]) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tminLife = max(0, currentLife - Endurance[i]);\n\t\t\t\tmaxExperience = min(100, currentExperience + getExperience[i]);\n\t\t\t\tDpCount[minLife][maxExperience] = min(DpCount[minLife][maxExperience],\n\t\t\t\t\tDpCount[currentLife][currentExperience] + 1);\n\t\t\t}\n\t\t}\n\t}\n\t\t\n\tAns = *min_element(DpCount[0], DpCount[0] + 101);\n}\n\nint main() {\n\n\twhile (cin >> D >> N, D) {\n\t\tmemset(Endurance, 0, sizeof(Endurance));\n\t\tmemset(getExperience, 0, sizeof(getExperience));\n\t\tmemset(needExperience, 0, sizeof(needExperience));\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcin >> Endurance[i] >> getExperience[i] >> needExperience[i];\n\t\t}\n\t\tsolve();\n\t\tif (Ans == INF) {\n\t\t\tcout << \"NA\" << endl;\n\t\t\tcontinue;\n\t\t}\n\t\tcout << Ans << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3132, "score_of_the_acc": -0.0392, "final_rank": 1 }, { "submission_id": "aoj_0288_4492402", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int d, n;\n while(cin >> d >> n, d){\n [&](){\n vector<int> as(n), es(n), rs(n);\n for (int i = 0; i < n; ++i) {\n cin >> as[i] >> es[i] >> rs[i];\n }\n auto dp = make_v(d+1, 101, -1);\n dp[d][0] = 0;\n queue<pair<int, int>> Q;\n Q.emplace(d, 0);\n while(!Q.empty()){\n int i, j; tie(i, j) = Q.front(); Q.pop();\n if(i == 0) {\n cout << dp[i][j] << \"\\n\";\n return;\n }\n for (int k = 0; k < n; ++k) {\n if(rs[k] <= j){\n int ii = max(0, i-as[k]), jj = min(100, j+es[k]);\n if(!~dp[ii][jj]){\n dp[ii][jj] = dp[i][j]+1;\n Q.emplace(ii, jj);\n }\n }\n }\n }\n puts(\"NA\");\n }();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3216, "score_of_the_acc": -0.1765, "final_rank": 3 }, { "submission_id": "aoj_0288_3941085", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set> \n#include<cmath>\nusing namespace std;\nlong long p = 998244353;\n//long long p = 1000000007;\n#define int long long\n#define vel vector<long long>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)\n#define mint modint<998244353>\n#define end_s(a) cout <<a<<endl;return 0\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) { pa[x] = y; }\n}\nV<string> solve2(int a, int b) {\n\tif (a < 0 || b < 0) { return {}; }\n\tif (a == 0 && b == 0) {\n\t\tV<string> ans(1, \"\");\n\t\treturn ans;\n\t}\n\tV<string> ans = solve2(a - 1, b);\n\tV<string> nans;\n\tfor (auto x : ans) { nans.push_back(x+\"A\"); }\n\tV<string> ans2 = solve2(a, b - 1);\n\tfor (auto x : ans2) { nans.push_back(x+\"B\"); }\n\treturn nans;\n}\nsigned main() {\n\twhile (true) {\n\t\tint d, n; cin >> d >> n;\n\t\tif (d == 0) { break; }\n\t\tint inf = 100;\n\t\tvvel dp(d + 1, vel(101, 10000));\n\t\tvel a(n), e(n), r(n);\n\t\trep(i, n) {\n\t\t\tcin >> a[i] >> e[i] >> r[i];\n\t\t}\n\t\tdp[0][0] = 0;\n\t\trep(i, d + 1) {\n\t\t\trep(j, 101) {\n\t\t\t\trep(k, n) {\n\t\t\t\t\tif (r[k] <= j) {\n\t\t\t\t\t\tmmin(dp[min(i + a[k], d)][min(j + e[k], inf)], dp[i][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = 10000;\n\t\trep(i, 101) { mmin(ans, dp[d][i]); }\n\t\tif (ans == 10000) { cout << \"NA\" << endl; }\n\t\telse { cout << ans << endl; }\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3204, "score_of_the_acc": -0.2353, "final_rank": 4 }, { "submission_id": "aoj_0288_3941083", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set> \n#include<cmath>\nusing namespace std;\nlong long p = 998244353;\n//long long p = 1000000007;\n#define int long long\n#define vel vector<long long>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)\n#define mint modint<998244353>\n#define end_s(a) cout <<a<<endl;return 0\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) { pa[x] = y; }\n}\nV<string> solve2(int a, int b) {\n\tif (a < 0 || b < 0) { return {}; }\n\tif (a == 0 && b == 0) {\n\t\tV<string> ans(1, \"\");\n\t\treturn ans;\n\t}\n\tV<string> ans = solve2(a - 1, b);\n\tV<string> nans;\n\tfor (auto x : ans) { nans.push_back(x+\"A\"); }\n\tV<string> ans2 = solve2(a, b - 1);\n\tfor (auto x : ans2) { nans.push_back(x+\"B\"); }\n\treturn nans;\n}\nsigned main() {\n\twhile (true) {\n\t\tint d, n; cin >> d >> n;\n\t\tif (d == 0) { break; }\n\t\tint inf = 100;\n\t\tvvel dp(d + 1, vel(101, 101));\n\t\tvel a(n), e(n), r(n);\n\t\trep(i, n) {\n\t\t\tcin >> a[i] >> e[i] >> r[i];\n\t\t}\n\t\tdp[0][0] = 0;\n\t\trep(i, d + 1) {\n\t\t\trep(j, 101) {\n\t\t\t\trep(k, n) {\n\t\t\t\t\tif (r[k] <= j) {\n\t\t\t\t\t\tmmin(dp[min(i + a[k], d)][min(j + e[k], inf)], dp[i][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = 101;\n\t\trep(i, 101) { mmin(ans, dp[d][i]); }\n\t\tif (ans == 101) { cout << \"NA\" << endl; }\n\t\telse { cout << ans << endl; }\n\t}\n\treturn 0;\n}", "accuracy": 0.9, "time_ms": 70, "memory_kb": 3212, "score_of_the_acc": -0.2484, "final_rank": 16 } ]
aoj_0294_cpp
アカ・ベコ捕獲作戦 怪盗アカ・ベコは大胆にも、ツルガジョーから銀のシャチホコを盗み去った。警部であるあなたは、アカ・ベコが仲間のコボウ氏にシャチホコを渡すらしいという情報を手に入れた。ただ、コボウ氏はアカ・ベコのアジトまで出向けないので、アジトの外で渡すらしい。あなたはアカ・ベコを待ち伏せして捕まえることにした。この町は古い城下町なので、道が複雑に入り組んでいて、どの道も一方通行になっている。アカ・ベコがアジトから受け渡し場所までどの経路を通るのかはわからないが、人員不足のため、待ち伏せ場所は1つに設定しなければならない。 あなたは、アジトを含むいくつかの地点を選び、それらをつなぐ道を調べ、地図を作った。地図上の地点のどこかで受け渡しが行われるらしい。受け渡し場所が判明次第、以下のように待ち伏せ場所を選ぶ。 アジトは危険なのでアジト以外の地点。 アカ・ベコがアジトから受け渡し場所までどのような経路を通っても必ず通る地点。 1, 2 の両方を満たす地点のうち、受け渡し場所にたどり着くまでに通過しなければならない地点の数がより少ない地点。ただし、コボウ氏に見つからないようにするために、1, 2 を満たす地点が他にない場合のみ、受け渡し場所を待ち伏せ場所にする。 アジトと待ち伏せ場所の候補からなる地点をつなぐ道の情報のあとに、質問として受け渡し場所が複数入力されたとき、それぞれの受け渡し場所について待ち伏せ場所を出力するプログラムを作成してください。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 N M s 1 t 1 : s M t M Q r 1 : r Q 1行目は2つの整数からなる。 N (3 ≤ N ≤ 100000) は地点の数、 M ( N -1 ≤ M ≤ 300000) は地図に書いたすべての道の数を表す。続く M 行に隣り合った地点の間を直接つなぐ道が与えられる。 s i と t i (1 ≤ s i ≠ t i ≤ N ) は i 番目の道のそれぞれ始点、終点となる地点の番号を表す。ただし、アジトの番号は1とし、アジトからはすべての地点へ到達できる。 続く1行に質問の数 Q (1 ≤ Q < N ) が与えられる。続く Q 行に質問が与えられる。 i 番目の質問として、受け渡し場所の番号 r i (2 ≤ r i ≤ N ) が与えられる。 出力 質問ごとに、待ち伏せ場所の番号を1行に出力する。 入出力例 入力例 1 6 7 1 2 2 3 1 3 1 4 4 5 5 6 6 1 5 2 3 4 5 6 出力例 1 2 3 4 4 5 入力例 2 11 15 1 2 1 3 1 4 2 5 3 6 3 7 3 9 4 7 4 10 4 11 6 2 6 8 7 9 8 11 9 6 10 6 2 10 8 9 3 5 11 4 7 出力例 2 6 2 4 6 9 3 2 11 4 7
[ { "submission_id": "aoj_0294_8775198", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <vector>\n#include <queue>\nusing namespace std;\nconst int LIMIT=100003;\nint ans[LIMIT];\nint ans2[LIMIT];\nint count[LIMIT];\nvector<int> vs[LIMIT];\nqueue<int> qs;\nint main() {\n\t// your code goes here\n\tmemset(ans,0,sizeof(ans));\n\tmemset(count,0,sizeof(count));\n\tmemset(ans2,0,sizeof(ans2));\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\tvs[a].push_back(b);\n\t\tcount[b]++;\n\t}\n\t\n\tqs.push(1);\n\tans[1]=1;\n\tans2[1]=1;\n\twhile(qs.size()>0){\n\t\tint p1=qs.front();\n\t\tqs.pop();\n\t\tfor(int i=0;i<vs[p1].size();i++){\n\t\t\tint p2=vs[p1][i];\n\t\t\tif(p2==1)continue;\n\t\t\tif(count[p2]==1){\n\t\t\t\tqs.push(p2);\n\t\t\t\tif(p1==1){\n\t\t\t\t\tans[p2]=p2;\n\t\t\t\t\tans2[p2]=p2;\n\t\t\t\t}else{\n\t\t\t\t\tans[p2]=p1;\n\t\t\t\t\tans2[p2]=p1;\n\t\t\t\t}\n\t\t\t\t//cout<<\"p1=\"<<p1<<\" p2=\"<<p2<<\" ap1=\"<<ans[p1]<<\" ap2=\"<<ans[p2]<<endl;\n\t\t\t}else if(ans[p2]==0){\n\t\t\t\tqs.push(p2);\n\t\t\t\tans[p2]=ans[p1];\n\t\t\t\tans2[p2]=ans2[p1];\n\t\t\t}else if(ans[p2]==-1){\n\t\t\t\t//なにもしない\n\t\t\t}else if(ans[p1]==-1){\n\t\t\t\tans[p2]=-1;\n\t\t\t}else if(ans[p2]!=ans[p1]){\n\t\t\t\tans[p2]=-1;\n\t\t\t}else{\n\t\t\t\tans[p2]=ans[p1];\n\t\t\t}\n\t\t}\n\t}\n\tint q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tint p1;\n\t\tcin>>p1;\n\t\tif(ans[p1]==-1||ans[p1]==1){\n\t\t\tcout<<p1<<endl;\n\t\t}else{\n\t\t\tcout<<ans[p1]<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 80, "memory_kb": 8652, "score_of_the_acc": -0.2253, "final_rank": 17 }, { "submission_id": "aoj_0294_8775142", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <vector>\n#include <queue>\nusing namespace std;\nconst int LIMIT=100003;\nint ans[LIMIT];\nint ans2[LIMIT];\nint count[LIMIT];\nvector<int> vs[LIMIT];\nqueue<int> qs;\nint main() {\n\t// your code goes here\n\tmemset(ans,0,sizeof(ans));\n\tmemset(count,0,sizeof(count));\n\tmemset(ans2,0,sizeof(ans2));\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\tvs[a].push_back(b);\n\t\tcount[b]++;\n\t}\n\t\n\tqs.push(1);\n\tans[1]=1;\n\tans2[1]=1;\n\twhile(qs.size()>0){\n\t\tint p1=qs.front();\n\t\tqs.pop();\n\t\tfor(int i=0;i<vs[p1].size();i++){\n\t\t\tint p2=vs[p1][i];\n\t\t\tif(p2==1)continue;\n\t\t\tif(count[p2]==1){\n\t\t\t\tqs.push(p2);\n\t\t\t\tif(p1==1){\n\t\t\t\t\tans[p2]=p2;\n\t\t\t\t\tans2[p2]=p2;\n\t\t\t\t}else{\n\t\t\t\t\tans[p2]=p1;\n\t\t\t\t\tans2[p2]=p1;\n\t\t\t\t}\n\t\t\t\t//cout<<\"p1=\"<<p1<<\" p2=\"<<p2<<\" ap1=\"<<ans[p1]<<\" ap2=\"<<ans[p2]<<endl;\n\t\t\t}else if(ans[p2]==0){\n\t\t\t\tqs.push(p2);\n\t\t\t\tans[p2]=ans[p1];\n\t\t\t\tans2[p2]=ans2[p1];\n\t\t\t}else if(ans[p2]==-1){\n\t\t\t\t//なにもしない\n\t\t\t}else{\n\t\t\t\tans2[p2]=ans2[p1];\n\t\t\t\tans[p2]=-1;\n\t\t\t}\n\t\t}\n\t}\n\tint q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tint p1;\n\t\tcin>>p1;\n\t\tif(ans[p1]==-1||ans[p1]==1){\n\t\t\tcout<<p1<<endl;\n\t\t}else{\n\t\t\tcout<<ans2[p1]<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 80, "memory_kb": 8736, "score_of_the_acc": -0.2284, "final_rank": 18 }, { "submission_id": "aoj_0294_8775007", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <vector>\n#include <queue>\n\n\nusing namespace std;\nconst int LIMIT=100003;\nint ans[LIMIT];\nint count[LIMIT];\nvector<int> vs[LIMIT];\nqueue<int> qs;\nint main() {\n\t// your code goes here\n\tmemset(ans,0,sizeof(ans));\n\tmemset(count,0,sizeof(count));\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\tvs[a].push_back(b);\n\t\tcount[b]++;\n\t}\n\t\n\tqs.push(1);\n\tans[1]=1;\n\twhile(qs.size()>0){\n\t\tint p1=qs.front();\n\t\tqs.pop();\n\t\tfor(int i=0;i<vs[p1].size();i++){\n\t\t\tint p2=vs[p1][i];\n\t\t\tif(p2==1)continue;\n\t\t\tif(count[p2]==1){\n\t\t\t\tqs.push(p2);\n\t\t\t\tif(p1==1){\n\t\t\t\t\tans[p2]=p2;\n\t\t\t\t}else{\n\t\t\t\t\tans[p2]=p1;\n\t\t\t\t}\n\t\t\t\t//cout<<\"p1=\"<<p1<<\" p2=\"<<p2<<\" ap1=\"<<ans[p1]<<\" ap2=\"<<ans[p2]<<endl;\n\t\t\t}else if(ans[p2]==0){\n\t\t\t\tqs.push(p2);\n\t\t\t\tans[p2]=ans[p1];\n\t\t\t}else if(ans[p2]==-1){\n\t\t\t\t//なにもしない\n\t\t\t}else if(ans[p1]==ans[p2]){\n\t\t\t\t//何もしない\n\t\t\t}else if(ans[p1]!=ans[p2]){\n\t\t\t\tans[p2]=-1;\n\t\t\t}\n\t\t}\n\t}\n\tint q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tint p1;\n\t\tcin>>p1;\n\t\tif(ans[p1]==-1||ans[p1]==1){\n\t\t\tcout<<p1<<endl;\n\t\t}else{\n\t\t\tcout<<ans[p1]<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 80, "memory_kb": 8256, "score_of_the_acc": -0.2109, "final_rank": 16 }, { "submission_id": "aoj_0294_8775005", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <vector>\n#include <queue>\n\n\nusing namespace std;\nconst int LIMIT=100003;\nint ans[LIMIT];\nint count[LIMIT];\nvector<int> vs[LIMIT];\nqueue<int> qs;\nint main() {\n\t// your code goes here\n\tmemset(ans,0,sizeof(ans));\n\tmemset(count,0,sizeof(count));\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b;\n\t\tcin>>a>>b;\n\t\tvs[a].push_back(b);\n\t\tcount[b]++;\n\t}\n\t\n\tqs.push(1);\n\tans[1]=1;\n\twhile(qs.size()>0){\n\t\tint p1=qs.front();\n\t\tqs.pop();\n\t\tfor(int i=0;i<vs[p1].size();i++){\n\t\t\tint p2=vs[p1][i];\n\t\t\tif(p2==1)continue;\n\t\t\tif(count[p2]==1){\n\t\t\t\tqs.push(p2);\n\t\t\t\tif(p1==1){\n\t\t\t\t\tans[p2]=p2;\n\t\t\t\t}else{\n\t\t\t\t\tans[p2]=p1;\n\t\t\t\t}\n\t\t\t\t//cout<<\"p1=\"<<p1<<\" p2=\"<<p2<<\" ap1=\"<<ans[p1]<<\" ap2=\"<<ans[p2]<<endl;\n\t\t\t}else if(ans[p2]==0){\n\t\t\t\tqs.push(p2);\n\t\t\t\tans[p2]=ans[p1];\n\t\t\t}else if(ans[p2]==-1){\n\t\t\t\t//なにもしない\n\t\t\t}else if(ans[p1]==ans[p2]){\n\t\t\t\t//何もしない\n\t\t\t}else if(ans[p1]!=ans[p2]){\n\t\t\t\tans[p2]=-1;\n\t\t\t}\n\t\t}\n\t}\n\tint q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tint p1;\n\t\tcin>>p1;\n\t\tif(ans[p1]==-1){\n\t\t\tcout<<p1<<endl;\n\t\t}else{\n\t\t\tcout<<ans[p1]<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 80, "memory_kb": 8184, "score_of_the_acc": -0.2083, "final_rank": 20 }, { "submission_id": "aoj_0294_6495785", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<map>\n#include<set>\n#include<algorithm>\n#include<functional>\n#include<cstdio>\n#include<cstdlib>\n#include<cmath>\n#include<cassert>\n#include<ctime>\nusing namespace std;\n\n#define mind(a,b) (a>b?b:a)\n#define maxd(a,b) (a>b?a:b)\n#define absd(x) (x<0?-(x):x)\n#define pow2(x) ((x)*(x))\n#define rep(i,n) for(int i=0; i<n; ++i)\n#define repr(i,n) for(int i=n-1; i>=0; --i)\n#define repl(i,s,n) for(int i=s; i<=n; ++i)\n#define replr(i,s,n) for(int i=n; i>=s; --i)\n#define repf(i,s,n,j) for(int i=s; i<=n; i+=j)\n#define repe(e,obj) for(auto e : obj)\n\n#define SP << \" \" <<\n#define COL << \" : \" <<\n#define COM << \", \" <<\n#define ARR << \" -> \" <<\n#define PNT(STR) cout << STR << endl\n#define POS(X,Y) \"(\" << X << \", \" << Y << \")\"\n#define DEB(A) \" (\" << #A << \") \" << A\n#define DEBREP(i,n,val) for(int i=0; i<n; ++i) cout << val << \" \"; cout << endl\n#define ALL(V) (V).begin(), (V).end()\n#define INF 1000000007\n#define INFLL 1000000000000000007LL\n#define EPS 1e-9\n\ntypedef unsigned int uint;\ntypedef unsigned long ulong;\ntypedef unsigned long long ull;\ntypedef long long ll;\ntypedef long double ld;\n#define P_TYPE int\ntypedef pair<P_TYPE, P_TYPE> P;\ntypedef pair<P, P_TYPE> PI;\ntypedef pair<P_TYPE, P> IP;\ntypedef pair<P, P> PP;\ntypedef priority_queue<P, vector<P>, greater<P> > pvqueue;\n\n#define N 100003\n\nint n;\nvector<int> g[N];\n\nvector<int> vs;\nint order[N];\nint prt[N];\nint doms[N], semi[N];\nint anc[N], label[N];\nvector<int> rg[N];\n\ninline void link(int v, int w) {\n anc[w] = v;\n}\n\nint compress(int v, int w) {\n if(w == anc[w]) {\n return w;\n }\n\n anc[v] = compress(w, anc[w]);\n if(label[w] < label[v]) {\n label[v] = label[w];\n }\n return anc[v];\n}\n\ninline int eval(int v) {\n if(v == anc[v]) {\n return label[v];\n }\n\n compress(v, anc[v]);\n return label[v];\n}\n\nvoid dfs(int v) {\n order[v] = vs.size();\n vs.push_back(v);\n for(int w : g[v]) {\n if(order[w] != -1) continue;\n prt[w] = v;\n dfs(w);\n }\n}\n\nvoid dominator(int s) {\n for(int i=0; i<n; ++i) order[i] = -1, prt[i] = -1;\n vs.reserve(n);\n\n dfs(s);\n\n for(int i=0; i<n; ++i) semi[i] = label[i] = order[i], doms[i] = -1;\n for(int i=0; i<n; ++i) anc[i] = i;\n\n for(int v=0; v<n; ++v) {\n for(int w : g[v]) {\n rg[w].push_back(v);\n }\n }\n\n for(int i=n-1; i>0; --i) {\n int w = vs[i];\n for(int v : rg[w]) {\n int s_min = eval(v);\n if(s_min < semi[w]) semi[w] = s_min;\n }\n label[w] = semi[w];\n link(prt[w], w);\n }\n\n doms[s] = s;\n for(int i=1; i<n; ++i) {\n int w = vs[i];\n int x = prt[w];\n while(semi[w] < order[x]) x = doms[x];\n doms[w] = x;\n }\n}\n\nint main() {\n int m; cin >> n >> m;\n rep(i, m) {\n int s, t; cin >> s >> t; --s; --t;\n g[s].push_back(t);\n }\n dominator(0);\n int q; cin >> q;\n rep(i, q) {\n int r; cin >> r; --r;\n cout << (doms[r] != 0 ? doms[r]+1 : r+1) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 19320, "score_of_the_acc": -0.9872, "final_rank": 4 }, { "submission_id": "aoj_0294_6495424", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<map>\n#include<set>\n#include<algorithm>\n#include<functional>\n#include<cstdio>\n#include<cstdlib>\n#include<cmath>\n#include<cassert>\n#include<ctime>\nusing namespace std;\n\n#define mind(a,b) (a>b?b:a)\n#define maxd(a,b) (a>b?a:b)\n#define absd(x) (x<0?-(x):x)\n#define pow2(x) ((x)*(x))\n#define rep(i,n) for(int i=0; i<n; ++i)\n#define repr(i,n) for(int i=n-1; i>=0; --i)\n#define repl(i,s,n) for(int i=s; i<=n; ++i)\n#define replr(i,s,n) for(int i=n; i>=s; --i)\n#define repf(i,s,n,j) for(int i=s; i<=n; i+=j)\n#define repe(e,obj) for(auto e : obj)\n\n#define SP << \" \" <<\n#define COL << \" : \" <<\n#define COM << \", \" <<\n#define ARR << \" -> \" <<\n#define PNT(STR) cout << STR << endl\n#define POS(X,Y) \"(\" << X << \", \" << Y << \")\"\n#define DEB(A) \" (\" << #A << \") \" << A\n#define DEBREP(i,n,val) for(int i=0; i<n; ++i) cout << val << \" \"; cout << endl\n#define ALL(V) (V).begin(), (V).end()\n#define INF 1000000007\n#define INFLL 1000000000000000007LL\n#define EPS 1e-9\n\ntypedef unsigned int uint;\ntypedef unsigned long ulong;\ntypedef unsigned long long ull;\ntypedef long long ll;\ntypedef long double ld;\n#define P_TYPE int\ntypedef pair<P_TYPE, P_TYPE> P;\ntypedef pair<P, P_TYPE> PI;\ntypedef pair<P_TYPE, P> IP;\ntypedef pair<P, P> PP;\ntypedef priority_queue<P, vector<P>, greater<P> > pvqueue;\n\n#define N 100003\n\nint n;\nvector<int> g[N];\n\nvector<int> vs;\nint order[N];\nint prt[N];\nint doms[N], semi[N];\nint anc[N], label[N];\nvector<int> rg[N], bucket[N];\n\ninline void link(int v, int w) {\n anc[w] = v;\n}\n\nint compress(int v, int w) {\n if(w == anc[w]) {\n return w;\n }\n\n anc[v] = compress(w, anc[w]);\n if(semi[label[w]] < semi[label[v]]) {\n label[v] = label[w];\n }\n return anc[v];\n}\n\ninline int eval(int v) {\n if(v == anc[v]) {\n return v;\n }\n\n compress(v, anc[v]);\n return label[v];\n}\n\nvoid dfs(int v) {\n order[v] = vs.size();\n vs.push_back(v);\n for(int w : g[v]) {\n if(order[w] != -1) continue;\n prt[w] = v;\n dfs(w);\n }\n}\n\nvoid dominator(int s) {\n for(int i=0; i<n; ++i) order[i] = -1, prt[i] = -1;\n vs.reserve(n);\n\n dfs(s);\n\n for(int i=0; i<n; ++i) semi[i] = order[i], doms[i] = -1;\n for(int i=0; i<n; ++i) anc[i] = label[i] = i;\n\n for(int v=0; v<n; ++v) {\n for(int w : g[v]) {\n rg[w].push_back(v);\n }\n }\n\n for(int i=n-1; i>0; --i) {\n int w = vs[i];\n for(int v : bucket[w]) {\n int u = eval(v);\n doms[v] = (semi[u] < semi[v] ? u : w);\n }\n for(int v : rg[w]) {\n int u = eval(v);\n if(semi[u] < semi[w]) {\n semi[w] = semi[u];\n }\n }\n if(vs[semi[w]] != prt[w]) {\n bucket[vs[semi[w]]].push_back(w);\n } else {\n doms[w] = prt[w];\n }\n link(prt[w], w);\n }\n for(int v : bucket[s]) doms[v] = s;\n\n for(int i=1; i<n; ++i) {\n int w = vs[i];\n if(doms[w] != vs[semi[w]]) {\n doms[w] = doms[doms[w]];\n }\n }\n doms[s] = s;\n}\n\nint main() {\n int m; cin >> n >> m;\n rep(i, m) {\n int s, t; cin >> s >> t; --s; --t;\n g[s].push_back(t);\n }\n dominator(0);\n int q; cin >> q;\n rep(i, q) {\n int r; cin >> r; --r;\n cout << (doms[r] != 0 ? doms[r]+1 : r+1) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 22084, "score_of_the_acc": -1.0875, "final_rank": 5 }, { "submission_id": "aoj_0294_6495415", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<map>\n#include<set>\n#include<algorithm>\n#include<functional>\n#include<cstdio>\n#include<cstdlib>\n#include<cmath>\n#include<cassert>\n#include<ctime>\nusing namespace std;\n\n#define mind(a,b) (a>b?b:a)\n#define maxd(a,b) (a>b?a:b)\n#define absd(x) (x<0?-(x):x)\n#define pow2(x) ((x)*(x))\n#define rep(i,n) for(int i=0; i<n; ++i)\n#define repr(i,n) for(int i=n-1; i>=0; --i)\n#define repl(i,s,n) for(int i=s; i<=n; ++i)\n#define replr(i,s,n) for(int i=n; i>=s; --i)\n#define repf(i,s,n,j) for(int i=s; i<=n; i+=j)\n#define repe(e,obj) for(auto e : obj)\n\n#define SP << \" \" <<\n#define COL << \" : \" <<\n#define COM << \", \" <<\n#define ARR << \" -> \" <<\n#define PNT(STR) cout << STR << endl\n#define POS(X,Y) \"(\" << X << \", \" << Y << \")\"\n#define DEB(A) \" (\" << #A << \") \" << A\n#define DEBREP(i,n,val) for(int i=0; i<n; ++i) cout << val << \" \"; cout << endl\n#define ALL(V) (V).begin(), (V).end()\n#define INF 1000000007\n#define INFLL 1000000000000000007LL\n#define EPS 1e-9\n\ntypedef unsigned int uint;\ntypedef unsigned long ulong;\ntypedef unsigned long long ull;\ntypedef long long ll;\ntypedef long double ld;\n#define P_TYPE int\ntypedef pair<P_TYPE, P_TYPE> P;\ntypedef pair<P, P_TYPE> PI;\ntypedef pair<P_TYPE, P> IP;\ntypedef pair<P, P> PP;\ntypedef priority_queue<P, vector<P>, greater<P> > pvqueue;\n\n#define N 100003\n\nint n;\nvector<int> g[N];\n\nvector<int> vs;\nint order[N];\nint prt[N];\nint doms[N], semi[N];\nint anc[N], label[N];\nvector<int> rg[N], bucket[N];\n\ninline void link(int v, int w) {\n anc[w] = v;\n}\n\nint compress(int v, int w) {\n if(w == anc[w]) {\n return w;\n }\n\n anc[v] = compress(w, anc[w]);\n if(semi[label[w]] < semi[label[v]]) {\n label[v] = label[w];\n }\n return anc[v];\n}\n\ninline int eval(int v) {\n if(v == anc[v]) {\n return v;\n }\n\n compress(v, anc[v]);\n return label[v];\n}\n\nvoid dfs(int v) {\n order[v] = vs.size();\n vs.push_back(v);\n for(int w : g[v]) {\n if(order[w] != -1) continue;\n prt[w] = v;\n dfs(w);\n }\n}\n\nvoid prepare(int s) {\n for(int i=0; i<n; ++i) order[i] = -1, prt[i] = -1;\n vs.reserve(n);\n\n dfs(s);\n}\n\nvoid dominator(int s) {\n prepare(s);\n for(int i=0; i<n; ++i) semi[i] = order[i], doms[i] = -1;\n for(int i=0; i<n; ++i) anc[i] = label[i] = i;\n\n for(int v=0; v<n; ++v) {\n for(int w : g[v]) {\n rg[w].push_back(v);\n }\n }\n\n for(int i=n-1; i>0; --i) {\n int w = vs[i];\n for(int v : bucket[w]) {\n int u = eval(v);\n doms[v] = (semi[u] < semi[v] ? u : w);\n }\n for(int v : rg[w]) {\n int u = eval(v);\n if(semi[u] < semi[w]) {\n semi[w] = semi[u];\n }\n }\n if(vs[semi[w]] != prt[w]) {\n bucket[vs[semi[w]]].push_back(w);\n } else {\n doms[w] = prt[w];\n }\n link(prt[w], w);\n }\n for(int v : bucket[s]) doms[v] = s;\n\n for(int i=1; i<n; ++i) {\n int w = vs[i];\n if(doms[w] != vs[semi[w]]) {\n doms[w] = doms[doms[w]];\n }\n }\n doms[s] = s;\n}\n\nint main() {\n int m; cin >> n >> m;\n rep(i, m) {\n int s, t; cin >> s >> t; --s; --t;\n g[s].push_back(t);\n }\n dominator(0);\n int q; cin >> q;\n rep(i, q) {\n int r; cin >> r; --r;\n cout << (doms[r] != 0 ? doms[r]+1 : r+1) << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 22188, "score_of_the_acc": -1.0912, "final_rank": 6 }, { "submission_id": "aoj_0294_5416471", "code_snippet": "#include <iostream>\n#include <vector>\n#include<iomanip>\n#include<functional>\n#include<algorithm>\n#include<deque>\n#include<math.h>\n#include<set>\n#include<cstdio>\n#include<string>\n#include<queue>\n#include<complex>\n#include<numeric>\n#include<stack>\n#include<unordered_map>\n#include<map>\n#include <cassert>\nusing namespace std;\n#define rep(i,n) for(int i = 0;i<n;i++)\n#define req(i,n) for(ll i = 1;i<=n;i++)\n#define rrep(i,n) for(int i = n-1;i>=0;i--)\n#define ALL(a) a.begin(),a.end()\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\ntypedef long long ll;\ntypedef long double ld;\nconst ll mod = 1e9 + 7;\nstruct DominatorTree {// 根 s からある頂点 tへ通る時の必ず通る点のうち最もtに近い点\n struct UnionFind {\n vector<int>& semi;\n vector<int>ps, ms;\n UnionFind(vector<int>& semi) :semi(semi), ps(semi.size()), ms(semi.size()) {\n iota(ALL(ps), 0); iota(ALL(ms), 0);\n }int find(int v) {\n if (ps[v] == v)return v;\n int r = find(ps[v]);\n if (semi[ms[v]] > semi[ms[ps[v]]]) ms[v] = ms[ps[v]];\n return ps[v] = r;\n }int eval(int v) {\n find(v); return ms[v];\n }void link(int p, int v) { ps[v] = p; }\n }; vector<vector<int>> G, R;\n vector<int> ord, par, idom, semi;\n DominatorTree(int n): G(n), R(n), par(n), idom(n, -1), semi(n, -1) {\n ord.reserve(n);\n }void add_edge(int u, int v) {\n G[u].push_back(v); R[v].push_back(u);\n }void dfs(int v) {\n semi[v] = ord.size(); ord.push_back(v);\n for (int u : G[v]) {\n if (~semi[u])continue;\n par[u] = v; dfs(u);\n }\n }void build(int rt) {\n dfs(rt); int n = G.size();\n vector<vector<int>> bkt(n);\n UnionFind uf(semi); vector<int> us(n);\n rrep(i, ord.size()) {\n int v = ord[i];\n for (int u : R[v]) {\n if (semi[u] < 0)continue;\n u = uf.eval(u);\n if (semi[v] > semi[u])semi[v] = semi[u];\n }bkt[ord[semi[v]]].push_back(v);\n for (int u : bkt[par[v]]) us[u] = uf.eval(u);\n bkt[par[v]].clear(); uf.link(par[v], v);\n }req(i, ord.size()-1) {\n int v = ord[i], u = us[v];\n idom[v] = (semi[v] == semi[u] ? semi[v] : idom[u]);\n }req(i, ord.size() - 1) {\n int v = ord[i]; idom[v] = ord[idom[v]];\n }idom[rt] = rt;\n }int operator[](int k) { return idom[k]; }\n};\nint main() {\n int n, m, q,a,b; cin >> n >> m;\n DominatorTree G(n);\n rep(i, m) {\n cin >> a >> b; a--; b--;\n G.add_edge(a, b);\n }cin >> q; G.build(0);\n rep(i, q) {\n cin >> a; a--;\n if (G[a] == 0) cout << a + 1 << endl;\n else cout << G[a] + 1 << endl;\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 22208, "score_of_the_acc": -1.467, "final_rank": 8 }, { "submission_id": "aoj_0294_5263955", "code_snippet": "#include <stdio.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define modulo 1000000007\n#define mod(mod_x) ((((long long)mod_x+modulo))%modulo)\n#define Inf 1000000000000000000\n\nstruct dominator_tree{\n\t\n\t\n\tstruct potentialized_dsu {\n\t\tusing S = pair<int,int>;\n\t public:\n\t\tpotentialized_dsu() : _n(0) {}\n\t\tpotentialized_dsu(int n) : _n(n), parent_or_size(n, -1), d(n,e()) {}\n\n\t\tint merge(int a, int b, S v) {\n\t\t\tassert(0 <= a && a < _n);\n\t\t\tassert(0 <= b && b < _n);\n\t\t\tint x = leader(a), y = leader(b);\n\t\t\tif (x == y) return x;\n\t\t\t\n\t\t\td[y] = op(d[y],op(d[x],v));\n\t\t\t\n\t\t\tparent_or_size[x] += parent_or_size[y];\n\t\t\tparent_or_size[y] = x;\n\t\t\t\n\t\t\treturn x;\n\t\t}\n\n\t\tbool same(int a, int b) {\n\t\t\tassert(0 <= a && a < _n);\n\t\t\tassert(0 <= b && b < _n);\n\t\t\treturn leader(a) == leader(b);\n\t\t}\n\n\t\tint leader(int a) {\n\t\t\tassert(0 <= a && a < _n);\n\t\t\tif (parent_or_size[a] < 0) return a;\n\t\t\tint l = leader(parent_or_size[a]);\n\t\t\tif(parent_or_size[a] != l){\n\t\t\t\td[a] = op(d[parent_or_size[a]],d[a]);\n\t\t\t\tparent_or_size[a] = l;\n\t\t\t}\n\t\t\treturn parent_or_size[a];\n\t\t}\n\n\t\tint size(int a) {\n\t\t\tassert(0 <= a && a < _n);\n\t\t\treturn -parent_or_size[leader(a)];\n\t\t}\n\t\t\n\t\tS get(int a){\n\t\t\tassert(0 <= a && a < _n);\n\t\t\tleader(a);\n\t\t\treturn d[a];\n\t\t}\n\n\t\tstd::vector<std::vector<int>> groups() {\n\t\t\tstd::vector<int> leader_buf(_n), group_size(_n);\n\t\t\tfor (int i = 0; i < _n; i++) {\n\t\t\t\tleader_buf[i] = leader(i);\n\t\t\t\tgroup_size[leader_buf[i]]++;\n\t\t\t}\n\t\t\tstd::vector<std::vector<int>> result(_n);\n\t\t\tfor (int i = 0; i < _n; i++) {\n\t\t\t\tresult[i].reserve(group_size[i]);\n\t\t\t}\n\t\t\tfor (int i = 0; i < _n; i++) {\n\t\t\t\tresult[leader_buf[i]].push_back(i);\n\t\t\t}\n\t\t\tresult.erase(\n\t\t\t\tstd::remove_if(result.begin(), result.end(),\n\t\t\t\t\t\t\t [&](const std::vector<int>& v) { return v.empty(); }),\n\t\t\t\tresult.end());\n\t\t\treturn result;\n\t\t}\n\t\t\n\t\tpair<int,int> op(pair<int,int> a,pair<int,int> b){\n\t\t\treturn min(a,b);\n\t\t}\n\n\t\tpair<int,int> e(){\n\t\t\treturn make_pair(1000000000,0);\n\t\t}\n\n\t private:\n\t\tint _n;\n\t\t// root node: -1 * component size\n\t\t// otherwise: parent\n\t\tstd::vector<int> parent_or_size;\n\t\tstd::vector<S> d;\n\t};\n\n\tdominator_tree(){\n\t}\n\t\n\t\n\tvector<vector<int>> get(vector<vector<int>> E,int r){\n\n\t\tint n = E.size();\n\t\tvector<int> ind;\n\t\tvector<int> pos(n,n);\n\t\tvector<int> p(n,-1);\n\t\tdfs(r,E,ind,pos,p);\n\n\t\tvector<vector<int>> rE(n);\n\t\trep(i,E.size()){\n\t\t\trep(j,E[i].size()){\n\t\t\t\trE[E[i][j]].push_back(i);\n\t\t\t}\n\t\t}\n\t\t\n\n\t\tvector<pair<int,int>> sdom(n,make_pair(n,n));\n\t\tvector<pair<int,int>> idom(n,make_pair(n,n));\n\t\tvector<vector<int>> L(n);\n\t\tpotentialized_dsu D(n);\n\t\t\n\t\tfor(int i=ind.size()-1;i>=1;i--){\n\t\t\tint u = ind[i];\n\t\t\trep(j,rE[u].size()){\n\t\t\t\tint v = rE[u][j];\n\t\t\t\tsdom[u] = min(sdom[u],make_pair(pos[v],u));\n\t\t\t\tsdom[u] = min(sdom[u],D.get(v));\n\t\t\t}\n\t\t\tsdom[u].second = u;\n\t\t\t\n\t\t\tL[ind[sdom[u].first]].push_back(u);\n\t\t\t\n\t\t\trep(j,L[p[u]].size()){\n\t\t\t\tint v = L[p[u]][j];\n\t\t\t\tidom[v] = min(D.get(v),sdom[u]);\n\t\t\t}\n\t\t\tL[p[u]].clear();\n\t\t\tD.merge(p[u],u,sdom[u]);\n\t\t\t\n\t\t}\n\t\t\n\t\trep(i,ind.size()){\n\t\t\tif(i==0)continue;\n\t\t\tint u = ind[i];\n\t\t\tif(idom[u].first==n){\n\t\t\t\t//idom[u] = make_pair(sdom[u].first,u);\n\t\t\t}\n\t\t\telse if(sdom[u].first == sdom[idom[u].second].first){\n\t\t\t\tidom[u] = sdom[u];\n\t\t\t}\n\t\t\telse{\n\t\t\t\tidom[u] = idom[idom[u].second];\n\t\t\t}\n\t\t}\n\n\t\tvector<vector<int>> ret(n);\n\t\trep(i,n){\n\t\t\tif(idom[i].first==n)continue;\n\t\t\tret[ind[idom[i].first]].push_back(i);\n\t\t}\n\t\treturn ret;\n\t\t\n\t}\n\t\n\tvoid dfs(int cur,vector<vector<int>> &E,vector<int> &ind,vector<int> &pos,vector<int> &p){\n\t\tpos[cur] = ind.size();\n\t\tind.push_back(cur);\n\t\trep(i,E[cur].size()){\n\t\t\tint to = E[cur][i];\n\t\t\tif(pos[to]!=E.size())continue;\n\t\t\tp[to] = cur;\n\t\t\tdfs(to,E,ind,pos,p);\n\t\t}\n\t}\n\t\n\t\n\t\n};\n\nint main(){\n\t\n\tint n,m;\n\tcin>>n>>m;\n\t\n\tvector<vector<int>> E(n);\n\trep(i,m){\n\t\tint u,v;\n\t\tscanf(\"%d %d\",&u,&v);\n\t\tu--;v--;\n\t\tE[u].push_back(v);\n\t}\n\t\n\tdominator_tree D;\n\tauto ret = D.get(E,0);\n\t\n\tvector<int> ans(n);\n\t\n\trep(i,n){\n\t\trep(j,ret[i].size()){\n\t\t\tint x = i+1;\n\t\t\tif(i==0)x = ret[i][j]+1;\n\t\t\tans[ret[i][j]] = x;\n\t\t}\n\t}\n\t\n\tint Q;\n\tcin>>Q;\n\t\n\trep(_,Q){\n\t\tint r;\n\t\tscanf(\"%d\",&r);\n\t\tprintf(\"%d\\n\",ans[r-1]);\n\t}\n\t\t\n\t\t\n\t\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 35756, "score_of_the_acc": -1.25, "final_rank": 7 }, { "submission_id": "aoj_0294_4728149", "code_snippet": "#line 1 \"0294.test.cpp\"\n#define PROBLEM \"https://onlinejudge.u-aizu.ac.jp/problems/0294\"\n\n#include <bits/stdc++.h> // clang-format off\nusing Int = long long;\n#define REP_(i, a_, b_, a, b, ...) for (Int i = (a), lim##i = (b); i < lim##i; i++)\n#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)\n#define ALL(v) std::begin(v), std::end(v)\nstruct SetupIO { SetupIO() { std::cin.tie(nullptr), std::ios::sync_with_stdio(false), std::cout << std::fixed << std::setprecision(13); } } setup_io;\n#ifndef dump\n#define dump(...)\n#endif // clang-format on\n\n/**\n * author: knshnb\n * created: Sat Aug 1 16:21:06 JST 2020\n **/\n\n#define CALL_FROM_TEST\n#line 1 \"/Users/knshnb/competitive_programming/competitive_library/src/Graph/DominatorTree.hpp\"\n/// @docs src/Graph/DominatorTree.md\n// 根付き森と、根から各頂点までのaggregationを管理\ntemplate <class T, class F> struct DirectedUnionFind {\n std::vector<int> par;\n std::vector<T> val;\n F op;\n DirectedUnionFind(F op_) : op(op_) {}\n void set_by_vector(const std::vector<T>& val_) {\n par.resize(val_.size()), std::iota(par.begin(), par.end(), 0);\n val = val_;\n }\n void set_by_value(int n, T a) {\n par.resize(n), std::iota(par.begin(), par.end(), 0);\n val.resize(n, a);\n }\n int compress(int v) {\n if (par[v] == v) return v;\n int root = compress(par[v]);\n val[v] = op(val[par[v]], val[v]);\n return par[v] = root;\n }\n int eval(int v) {\n compress(v);\n return val[v];\n }\n // rootをtoにつなげる\n void link(int to, int root) {\n assert(par[root] == root);\n par[root] = to;\n }\n};\ntemplate <class T, class F> DirectedUnionFind<T, F> make_directed_unionfind(F op_) {\n return DirectedUnionFind<T, F>(op_);\n}\n\n// 親をさすvectorを返す。rootの親はroot、rootから到達できない頂点の親は-1\nstd::vector<int> construct_domnator_tree(const std::vector<std::vector<int>>& edge, int root) {\n int n = edge.size();\n std::vector<std::vector<int>> redge(n);\n for (int u = 0; u < n; u++)\n for (int v : edge[u]) redge[v].push_back(u);\n // dfs木を作る\n std::vector<int> par(n, -1), to_vertex, to_ord(n, -1);\n auto dfs = [&](auto&& self, int v) -> void {\n to_ord[v] = to_vertex.size();\n to_vertex.push_back(v);\n for (int u : edge[v]) {\n if (to_ord[u] != -1) continue;\n self(self, u);\n par[to_ord[u]] = to_ord[v];\n }\n };\n dfs(dfs, root);\n int m = to_vertex.size(); // rootから到達可能な頂点数\n // dfs逆順\n std::vector<int> sdom(m), U(m, -1);\n for (int i = 1; i < m; i++) sdom[i] = i; // Theorem 4の左側をカバーできるように、iで初期化しておく\n auto uf = make_directed_unionfind<int>([&](int i, int j) { return sdom[i] < sdom[j] ? i : j; });\n uf.set_by_value(m, 0);\n for (int i = 0; i < m; i++) uf.val[i] = i;\n std::vector<std::vector<int>> bucket(n);\n for (int i = m - 1; i >= 1; i--) {\n // dfs逆順にsemidominatorを求める(Theorem 4)\n for (int v : redge[to_vertex[i]]) {\n int j = to_ord[v];\n if (j == -1) continue; // rootから到達できない頂点\n sdom[i] = std::min(sdom[i], sdom[uf.eval(j)]);\n }\n // Corollary 1\n bucket[sdom[i]].push_back(i);\n for (int j : bucket[par[i]]) U[j] = uf.eval(j);\n uf.link(par[i], i);\n }\n // dfs順にimmediate dominatorを求める\n std::vector<int> idom(m, -1);\n for (int i = 1; i < m; i++) {\n int u = U[i];\n idom[i] = sdom[i] == sdom[u] ? sdom[i] : idom[u];\n }\n // dfs順序からもとの頂点番号で表示したものに直す\n std::vector<int> ret(n, -1);\n for (int i = 1; i < m; i++) {\n ret[to_vertex[i]] = to_vertex[idom[i]];\n }\n ret[root] = root;\n return ret;\n}\n#line 20 \"0294.test.cpp\"\n#undef CALL_FROM_TEST\n\nsigned main() {\n Int n, m;\n std::cin >> n >> m;\n std::vector<std::vector<int>> g(n);\n for (int i = 0; i < m; i++) {\n Int u, v;\n std::cin >> u >> v, u--, v--;\n g[u].push_back(v);\n }\n std::vector<int> dtree = construct_domnator_tree(g, 0);\n Int Q;\n std::cin >> Q;\n REP(q, Q) {\n Int r;\n std::cin >> r, r--;\n std::cout << (dtree[r] == 0 ? r : dtree[r]) + 1 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 23660, "score_of_the_acc": -0.8113, "final_rank": 2 }, { "submission_id": "aoj_0294_4502318", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass DominatorTree {\n int n;\n void unite(int x, int y){\n uf_par[y] = x;\n }\n\n int compress(int x){\n if(uf_par[x] == x) return x;\n int r = compress(uf_par[x]);\n if(semi[m[x]] > semi[m[uf_par[x]]]) m[x] = m[uf_par[x]];\n return uf_par[x] = r;\n }\n\n int eval(int x){\n compress(x);\n return m[x];\n }\n\n\n void dfs(int x, int &cur){\n semi[x] = cur;\n ord[cur++] = x;\n for (auto &&i : G[x]) {\n if(!~semi[i]){\n par[i] = x;\n dfs(i, cur);\n }\n }\n }\npublic:\n DominatorTree(int n) : n(n), G(n), Grev(n), idom(n), semi(n), ord(n), par(n), uf_par(n), m(n), tmp(n), U(n) {}\n\n vector<vector<int>> G, Grev, tmp;\n vector<int> semi, ord, par, uf_par, m, U, idom;\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n Grev[b].emplace_back(a);\n }\n void build(int root){\n for (int i = 0; i < n; ++i) uf_par[i] = i, m[i] = i, semi[i] = -1, idom[i] = -1;\n int cur = 0;\n dfs(root, cur);\n for (int i = n-1; i >= 0; --i) {\n int a = ord[i];\n for (auto &&b : Grev[a]) {\n if(~semi[b]){\n int c = eval(b);\n semi[a] = min(semi[a], semi[c]);\n }\n }\n tmp[ord[semi[a]]].emplace_back(a);\n for (auto &&b : tmp[par[a]]) U[b] = eval(b);\n tmp[par[a]].clear();\n unite(par[a], a);\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i], b = U[a];\n if(semi[a] == semi[b]) idom[a] = semi[a];\n else idom[a] = idom[b];\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i];\n idom[a] = ord[idom[a]];\n }\n idom[root] = -1;\n }\n\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n DominatorTree G(n);\n for (int i = 0; i < m; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n G.add_edge(s, t);\n }\n G.build(0);\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x;\n cin >> x;\n x--;\n if(!G.idom[x]) printf(\"%d\\n\", x+1);\n else printf(\"%d\\n\", G.idom[x]+1);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 22316, "score_of_the_acc": -1.4709, "final_rank": 9 }, { "submission_id": "aoj_0294_4502308", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass DominatorTree {\n int n;\n void unite(int x, int y){\n uf_par[y] = x;\n }\n\n int compress(int x){\n if(uf_par[x] == x) return x;\n int r = compress(uf_par[x]);\n if(semi[m[x]] > semi[m[uf_par[x]]]) m[x] = m[uf_par[x]];\n return uf_par[x] = r;\n }\n\n int eval(int x){\n compress(x);\n return m[x];\n }\n\n\n void dfs(int x, int &cur){\n semi[x] = cur;\n ord[cur++] = x;\n for (auto &&i : G[x]) {\n if(!~semi[i]){\n par[i] = x;\n dfs(i, cur);\n }\n }\n }\npublic:\n DominatorTree(int n) : n(n), G(n), Grev(n), idom(n), semi(n), ord(n), par(n), uf_par(n), m(n), tmp(n), U(n) {}\n\n vector<vector<int>> G, Grev, tmp;\n vector<int> semi, ord, par, uf_par, m, U, idom;\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n Grev[b].emplace_back(a);\n }\n void build(int root){\n for (int i = 0; i < n; ++i) uf_par[i] = i, m[i] = i, semi[i] = -1, idom[i] = -1;\n int cur = 0;\n dfs(root, cur);\n for (int i = n-1; i >= 0; --i) {\n int a = ord[i];\n for (auto &&b : Grev[a]) {\n if(~semi[b]){\n int c = eval(b);\n semi[a] = min(semi[a], semi[c]);\n }\n }\n tmp[ord[semi[a]]].emplace_back(a);\n for (auto &&b : tmp[par[a]]) U[b] = eval(b);\n tmp[par[a]].clear();\n unite(par[a], a);\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i], b = U[a];\n if(semi[a] == semi[b]) idom[a] = semi[a];\n else idom[a] = semi[b];\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i];\n idom[a] = ord[idom[a]];\n }\n idom[root] = -1;\n }\n\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n DominatorTree G(n);\n for (int i = 0; i < m; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n G.add_edge(s, t);\n }\n G.build(0);\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x;\n cin >> x;\n x--;\n if(!G.idom[x]) printf(\"%d\\n\", x+1);\n else printf(\"%d\\n\", G.idom[x]+1);\n }\n cout.flush();\n return 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 250, "memory_kb": 22280, "score_of_the_acc": -1.4279, "final_rank": 12 }, { "submission_id": "aoj_0294_4502298", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass DominatorTree {\n int n;\n void unite(int x, int y){\n uf_par[y] = x;\n }\n\n int compress(int x){\n if(uf_par[x] == x) return x;\n int r = compress(uf_par[x]);\n if(semi[m[x]] > semi[m[uf_par[x]]]) m[x] = m[uf_par[x]];\n return uf_par[x] = r;\n }\n\n int eval(int x){\n compress(x);\n return m[x];\n }\n\n\n void dfs(int x, int &cur){\n semi[x] = cur;\n ord[cur++] = x;\n for (auto &&i : G[x]) {\n if(!~semi[i]){\n par[i] = x;\n dfs(i, cur);\n }\n }\n }\npublic:\n DominatorTree(int n) : n(n), G(n), Grev(n), idom(n), semi(n), ord(n), par(n), uf_par(n), m(n), tmp(n), U(n) {}\n\n vector<vector<int>> G, Grev, tmp;\n vector<int> semi, ord, par, uf_par, m, U, idom;\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n Grev[b].emplace_back(a);\n }\n void build(int root){\n for (int i = 0; i < n; ++i) uf_par[i] = i, m[i] = i, semi[i] = -1, idom[i] = -1;\n int cur = 0;\n dfs(root, cur);\n for (int i = n-1; i >= 0; --i) {\n int a = ord[i];\n for (auto &&b : Grev[a]) {\n if(~semi[b]){\n int c = eval(b);\n semi[a] = min(semi[a], semi[c]);\n }\n }\n tmp[ord[semi[a]]].emplace_back(a);\n for (auto &&b : tmp[par[a]]) U[b] = eval(b);\n tmp[par[a]].clear();\n unite(par[a], a);\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i], b = U[a];\n if(semi[a] == semi[b]) idom[a] = semi[a];\n else idom[a] = semi[b];\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i];\n idom[a] = ord[idom[a]];\n }\n idom[root] = -1;\n }\n\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n DominatorTree G(n);\n for (int i = 0; i < m; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n G.add_edge(s, t);\n }\n G.build(0);\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x;\n cin >> x;\n x--;\n if(!G.idom[x]) printf(\"%d\\n\", x+1);\n else printf(\"%d\\n\", G.idom[x]+1);\n }\n return 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 250, "memory_kb": 22356, "score_of_the_acc": -1.4307, "final_rank": 13 }, { "submission_id": "aoj_0294_4502290", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass DominatorTree {\n int n;\n void unite(int x, int y){\n uf_par[y] = x;\n }\n\n int compress(int x){\n if(uf_par[x] == x) return x;\n int r = compress(uf_par[x]);\n if(semi[m[x]] > semi[m[uf_par[x]]]) m[x] = m[uf_par[x]];\n return uf_par[x] = r;\n }\n\n int eval(int x){\n compress(x);\n return m[x];\n }\n\n\n void dfs(int x, int &cur){\n semi[x] = cur;\n ord[cur++] = x;\n for (auto &&i : G[x]) {\n if(!~semi[i]){\n par[i] = x;\n dfs(i, cur);\n }\n }\n }\npublic:\n DominatorTree(int n) : n(n), G(n), Grev(n), idom(n), semi(n), ord(n), par(n), uf_par(n), m(n), tmp(n), U(n) {}\n\n vector<vector<int>> G, Grev, tmp;\n vector<int> semi, ord, par, uf_par, m, U, idom;\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n Grev[b].emplace_back(a);\n }\n void build(int root){\n for (int i = 0; i < n; ++i) uf_par[i] = i, m[i] = i, semi[i] = -1;\n int cur = 0;\n dfs(root, cur);\n for (int i = n-1; i >= 0; --i) {\n int a = ord[i];\n for (auto &&b : Grev[a]) {\n if(~semi[b]){\n int c = eval(b);\n semi[a] = min(semi[a], semi[c]);\n }\n }\n tmp[ord[semi[a]]].emplace_back(a);\n for (auto &&b : tmp[par[a]]) U[b] = eval(b);\n tmp[par[a]].clear();\n unite(par[a], a);\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i], b = U[a];\n if(semi[a] == semi[b]) idom[a] = semi[a];\n else idom[a] = semi[b];\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i];\n idom[a] = ord[idom[a]];\n }\n idom[root] = -1;\n }\n\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n DominatorTree G(n);\n for (int i = 0; i < m; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n G.add_edge(s, t);\n }\n G.build(0);\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x;\n cin >> x;\n x--;\n if(!G.idom[x]) printf(\"%d\\n\", x+1);\n else printf(\"%d\\n\", G.idom[x]+1);\n }\n return 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 260, "memory_kb": 22440, "score_of_the_acc": -1.4754, "final_rank": 14 }, { "submission_id": "aoj_0294_4502283", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass DominatorTree {\n int n;\n void unite(int x, int y){\n uf_par[y] = x;\n }\n\n int compress(int x){\n if(uf_par[x] == x) return x;\n int r = compress(uf_par[x]);\n if(semi[m[x]] > semi[m[uf_par[x]]]) m[x] = m[uf_par[x]];\n return uf_par[x] = r;\n }\n\n int eval(int x){\n compress(x);\n return m[x];\n }\n\n\n void dfs(int x, int &cur){\n semi[x] = cur;\n ord[cur++] = x;\n for (auto &&i : G[x]) {\n if(!~semi[i]){\n par[i] = x;\n dfs(i, cur);\n }\n }\n }\npublic:\n DominatorTree(int n) : n(n), G(n), Grev(n), idom(n), semi(n), ord(n), par(n), uf_par(n), m(n), tmp(n), U(n) {}\n\n vector<vector<int>> G, Grev, tmp;\n vector<int> semi, ord, par, uf_par, m, U, idom;\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n Grev[b].emplace_back(a);\n }\n void build(int root){\n for (int i = 0; i < n; ++i) uf_par[i] = i, m[i] = i, semi[i] = -1;\n int cur = 0;\n dfs(root, cur);\n for (int i = n-1; i > 0; --i) {\n int a = ord[i];\n for (auto &&b : Grev[a]) {\n int c = eval(b);\n semi[a] = min(semi[a], semi[c]);\n }\n tmp[ord[semi[a]]].emplace_back(a);\n for (auto &&b : tmp[par[a]]) U[b] = eval(b);\n tmp[par[a]].clear();\n unite(par[a], a);\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i], b = U[a];\n if(semi[a] == semi[b]) idom[a] = semi[a];\n else idom[a] = semi[b];\n }\n for (int i = 1; i < n; ++i) {\n int a = ord[i];\n idom[a] = ord[idom[a]];\n }\n idom[root] = -1;\n }\n\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n DominatorTree G(n);\n for (int i = 0; i < m; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n G.add_edge(s, t);\n }\n G.build(0);\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x;\n cin >> x;\n x--;\n if(!G.idom[x]) cout << x+1 << \"\\n\";\n else cout << G.idom[x]+1 << \"\\n\";\n }\n return 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 270, "memory_kb": 22232, "score_of_the_acc": -1.5095, "final_rank": 15 }, { "submission_id": "aoj_0294_4273861", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nint N,M;\nint root;\nint num_visited;\nint vertex[SIZE];\nint sdom[SIZE],idom[SIZE];\nint parent[SIZE],work[SIZE],uf_parent[SIZE];\nvector<int> G[SIZE],rev_G[SIZE],bucket[SIZE];\n\nint find(int node_id){\n\tif(node_id == uf_parent[node_id]){\n\n\t\treturn node_id;\n\n\t}else{\n\n\t\tint ret = find(uf_parent[node_id]);\n\n\t\tif(sdom[work[node_id]] > sdom[work[uf_parent[node_id]]]){\n\n\t\t\twork[node_id] = work[uf_parent[node_id]];\n\t\t}\n\n\t\treturn uf_parent[node_id] = ret;\n\t}\n}\n\nvoid LINK(int child,int arg_parent){\n\n\tuf_parent[child] = arg_parent;\n}\n\nvoid dfs(int node_id,int pre){\n\n\tparent[node_id] = pre;\n\tvertex[num_visited] = node_id;\n\tsdom[node_id] = num_visited++;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\n\t\tint next = G[node_id][i];\n\t\tif(sdom[next] != -1)continue;\n\n\t\tdfs(next,node_id);\n\t}\n}\n\nint EVAL(int node_id){\n\n\tfind(node_id);\n\treturn work[node_id];\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tint from,to;\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tG[from].push_back(to);\n\t\trev_G[to].push_back(from);\n\t}\n\n\troot = 0;\n\tnum_visited = 0;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsdom[i] = -1;\n\t\tuf_parent[i] = i;\n\t\twork[i] = i;\n\t}\n\n\tdfs(root,-1);\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tint node_id = vertex[i];\n\n\t\tfor(int k = 0; k < rev_G[node_id].size(); k++){\n\n\t\t\tint pre_node = rev_G[node_id][k];\n\t\t\tint u = EVAL(pre_node); //分岐の始点を求める\n\t\t\tsdom[node_id] = min(sdom[node_id],sdom[u]);\n\t\t}\n\t\tbucket[vertex[sdom[node_id]]].push_back(node_id);\n\n\t\tfor(int k = 0; k < bucket[parent[node_id]].size(); k++){\n\n\t\t\tint v = bucket[parent[node_id]][k];\n\t\t\tint u = EVAL(v);\n\n\t\t\tif(sdom[u] < sdom[v]){\n\n\t\t\t\tidom[v] = u;\n\t\t\t}else{\n\n\t\t\t\tidom[v] = parent[node_id];\n\t\t\t}\n\t\t}\n\t\tbucket[parent[node_id]].clear();\n\t\tLINK(node_id,parent[node_id]);\n\t}\n\n\tfor(int i = 1; i < N; i++){\n\n\t\tint w = vertex[i];\n\n\t\tif(idom[w] != vertex[sdom[w]]){\n\n\t\t\tidom[w] = idom[idom[w]];\n\t\t}\n\t}\n\tidom[root] = -1;\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint tmp;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\ttmp--;\n\n\t\tif(idom[tmp] == root){\n\n\t\t\tprintf(\"%d\\n\",tmp+1);\n\t\t}else{\n\n\t\t\tprintf(\"%d\\n\",idom[tmp]+1);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 22480, "score_of_the_acc": -0.7685, "final_rank": 1 }, { "submission_id": "aoj_0294_4271282", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nint N,M;\nint root;\nint num_visited;\nint vertex[SIZE];\nint semi[SIZE],dom[SIZE];\nint parent[SIZE],work[SIZE],uf_parent[SIZE];\nvector<int> G[SIZE],rev_G[SIZE],bucket[SIZE];\n\nint find(int x){\n\tif(x == uf_parent[x]){\n\n\t\treturn x;\n\n\t}else{\n\n\t\tint ret = find(uf_parent[x]);\n\n\t\tif(semi[work[x]] > semi[work[uf_parent[x]]]){\n\n\t\t\twork[x] = work[uf_parent[x]];\n\t\t}\n\n\t\treturn uf_parent[x] = ret;\n\t}\n}\n\nvoid LINK(int child,int arg_parent){\n\n\tuf_parent[child] = arg_parent;\n}\n\nvoid dfs(int node_id,int pre){\n\n\tparent[node_id] = pre;\n\tvertex[num_visited] = node_id;\n\tsemi[node_id] = num_visited++;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\n\t\tint next = G[node_id][i];\n\t\tif(semi[next] != -1)continue;\n\n\t\tdfs(next,node_id);\n\t}\n}\n\nint EVAL(int node_id){\n\n\tfind(node_id);\n\treturn work[node_id];\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tint from,to;\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tG[from].push_back(to);\n\t\trev_G[to].push_back(from);\n\t}\n\n\troot = 0;\n\tnum_visited = 0;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsemi[i] = -1;\n\t\tuf_parent[i] = i;\n\t\twork[i] = i;\n\t}\n\n\tdfs(root,-1);\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tint w = vertex[i];\n\n\t\tfor(int k = 0; k < rev_G[w].size(); k++){\n\t\t\tint v = rev_G[w][k];\n\t\t\tint u = EVAL(v);\n\t\t\tsemi[w] = min(semi[w],semi[u]);\n\t\t}\n\t\tbucket[vertex[semi[w]]].push_back(w);\n\n\t\tfor(int k = 0; k < bucket[parent[w]].size(); k++){\n\n\t\t\tint v = bucket[parent[w]][k];\n\t\t\tint u = EVAL(v);\n\n\t\t\tif(semi[u] < semi[v]){\n\n\t\t\t\tdom[v] = u;\n\t\t\t}else{\n\n\t\t\t\tdom[v] = parent[w];\n\t\t\t}\n\t\t}\n\t\tbucket[parent[w]].clear();\n\t\tLINK(w,parent[w]);\n\t}\n\n\tfor(int i = 1; i < N; i++){\n\n\t\tint w = vertex[i];\n\t\tif(dom[w] != vertex[semi[w]]){\n\n\t\t\tdom[w] = dom[dom[w]];\n\t\t}\n\t}\n\tdom[root] = -1;\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint tmp;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\ttmp--;\n\n\t\tif(dom[tmp] == root){\n\n\t\t\tprintf(\"%d\\n\",tmp+1);\n\t\t}else{\n\n\t\t\tprintf(\"%d\\n\",dom[tmp]+1);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 22556, "score_of_the_acc": -0.8129, "final_rank": 3 }, { "submission_id": "aoj_0294_4271277", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nint N,M;\nint root;\nint num_visited;\nint vertex[SIZE];\nint semi[SIZE],dom[SIZE];\nint parent[SIZE],work[SIZE],uf_parent[SIZE];\nvector<int> G[SIZE],rev_G[SIZE],bucket[SIZE];\n\nint find(int x){\n\tif(x == uf_parent[x]){\n\n\t\treturn x;\n\n\t}else{\n\n\t\tif(semi[work[x]] > semi[work[uf_parent[x]]]){\n\n\t\t\twork[x] = work[uf_parent[x]];\n\t\t}\n\n\t\treturn uf_parent[x] = find(uf_parent[x]);\n\t}\n}\n\nvoid LINK(int child,int arg_parent){\n\n\tuf_parent[child] = arg_parent;\n}\n\nvoid dfs(int node_id,int pre){\n\n\tparent[node_id] = pre;\n\tvertex[num_visited] = node_id;\n\tsemi[node_id] = num_visited++;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\n\t\tint next = G[node_id][i];\n\t\tif(semi[next] != -1)continue;\n\n\t\tdfs(next,node_id);\n\t}\n}\n\nint EVAL(int node_id){\n\n\tfind(node_id);\n\treturn work[node_id];\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tint from,to;\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tG[from].push_back(to);\n\t\trev_G[to].push_back(from);\n\t}\n\n\troot = 0;\n\tnum_visited = 0;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsemi[i] = -1;\n\t\tuf_parent[i] = i;\n\t\twork[i] = i;\n\t}\n\n\tdfs(root,-1);\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tint w = vertex[i];\n\n\t\tfor(int k = 0; k < rev_G[w].size(); k++){\n\t\t\tint v = rev_G[w][k];\n\t\t\tint u = EVAL(v);\n\t\t\tsemi[w] = min(semi[w],semi[u]);\n\t\t}\n\t\tbucket[vertex[semi[w]]].push_back(w);\n\n\t\tfor(int k = 0; k < bucket[parent[w]].size(); k++){\n\n\t\t\tint v = bucket[parent[w]][k];\n\t\t\tint u = EVAL(v);\n\n\t\t\tif(semi[u] < semi[v]){\n\n\t\t\t\tdom[v] = u;\n\t\t\t}else{\n\n\t\t\t\tdom[v] = parent[w];\n\t\t\t}\n\t\t}\n\t\tbucket[parent[w]].clear();\n\t\tLINK(w,parent[w]);\n\t}\n\n\tfor(int i = 1; i < N; i++){\n\n\t\tint w = vertex[i];\n\t\tif(dom[w] != vertex[semi[w]]){\n\n\t\t\tdom[w] = dom[dom[w]];\n\t\t}\n\t}\n\tdom[root] = -1;\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint tmp;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\ttmp--;\n\n\t\tif(dom[tmp] == root){\n\n\t\t\tprintf(\"%d\\n\",tmp+1);\n\t\t}else{\n\n\t\t\tprintf(\"%d\\n\",dom[tmp]+1);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 100, "memory_kb": 22544, "score_of_the_acc": -0.8125, "final_rank": 10 }, { "submission_id": "aoj_0294_4271276", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nint N,M;\nint root;\nint num_visited;\nint vertex[SIZE];\nint semi[SIZE],dom[SIZE];\nint parent[SIZE],work[SIZE],uf_parent[SIZE];\nvector<int> G[SIZE],rev_G[SIZE],bucket[SIZE];\n\nint find(int x){\n\tif(x == uf_parent[x]){\n\n\t\treturn x;\n\n\t}else{\n\n\t\tif(semi[work[x]] > semi[work[uf_parent[x]]]){\n\n\t\t\twork[x] = work[uf_parent[x]];\n\t\t}\n\n\t\treturn uf_parent[x] = find(uf_parent[x]);\n\t}\n}\n\nvoid LINK(int child,int arg_parent){\n\n\tuf_parent[child] = arg_parent;\n}\n\nvoid dfs(int node_id,int pre){\n\n\tparent[node_id] = pre;\n\tvertex[num_visited] = node_id;\n\tsemi[node_id] = num_visited++;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\n\t\tint next = G[node_id][i];\n\t\tif(semi[next] != -1)continue;\n\n\t\tdfs(next,node_id);\n\t}\n}\n\nint EVAL(int node_id){\n\n\tfind(node_id);\n\treturn work[node_id];\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tint from,to;\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tG[from].push_back(to);\n\t\trev_G[to].push_back(from);\n\t}\n\n\troot = 0;\n\tnum_visited = 0;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsemi[i] = -1;\n\t\tuf_parent[i] = i;\n\t\twork[i] = i;\n\t}\n\n\tdfs(root,-1);\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tint w = vertex[i];\n\n\t\tfor(int k = 0; k < rev_G[w].size(); k++){\n\t\t\tint v = rev_G[w][k];\n\t\t\tint u = EVAL(v);\n\t\t\tsemi[w] = min(semi[w],semi[u]);\n\t\t}\n\t\tbucket[vertex[semi[w]]].push_back(w);\n\t\tLINK(w,parent[w]);\n\n\t\tfor(int k = 0; k < bucket[parent[w]].size(); k++){\n\n\t\t\tint v = bucket[parent[w]][k];\n\t\t\tint u = EVAL(v);\n\n\t\t\tif(semi[u] < semi[v]){\n\n\t\t\t\tdom[v] = u;\n\t\t\t}else{\n\n\t\t\t\tdom[v] = parent[w];\n\t\t\t}\n\t\t}\n\n\t\tbucket[parent[w]].clear();\n\t}\n\n\tfor(int i = 1; i < N; i++){\n\n\t\tint w = vertex[i];\n\t\tif(dom[w] != vertex[semi[w]]){\n\n\t\t\tdom[w] = dom[dom[w]];\n\t\t}\n\t}\n\tdom[root] = -1;\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint tmp;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\ttmp--;\n\n\t\tif(dom[tmp] == root){\n\n\t\t\tprintf(\"%d\\n\",tmp+1);\n\t\t}else{\n\n\t\t\tprintf(\"%d\\n\",dom[tmp]+1);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 100, "memory_kb": 22592, "score_of_the_acc": -0.8142, "final_rank": 11 }, { "submission_id": "aoj_0294_4271275", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nint N,M;\nint root;\nint num_visited;\nint vertex[SIZE];\nint semi[SIZE],dom[SIZE];\nint parent[SIZE],work[SIZE],uf_parent[SIZE];\nvector<int> G[SIZE],rev_G[SIZE],bucket[SIZE];\n\nint find(int x){\n\tif(x == uf_parent[x]){\n\n\t\treturn x;\n\n\t}else{\n\n\t\tif(semi[work[x]] > semi[work[uf_parent[x]]]){\n\n\t\t\twork[x] = work[uf_parent[x]];\n\t\t}\n\n\t\treturn uf_parent[x] = find(uf_parent[x]);\n\t}\n}\n\nvoid LINK(int child,int arg_parent){\n\n\tuf_parent[child] = arg_parent;\n}\n\nvoid dfs(int node_id,int pre){\n\n\tparent[node_id] = pre;\n\tvertex[num_visited] = node_id;\n\tsemi[node_id] = num_visited++;\n\n\tfor(int i = 0; i < G[node_id].size(); i++){\n\n\t\tint next = G[node_id][i];\n\t\tif(semi[next] != -1)continue;\n\n\t\tdfs(next,node_id);\n\t}\n}\n\nint EVAL(int node_id){\n\n\tfind(node_id);\n\treturn work[node_id];\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tint from,to;\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tG[from].push_back(to);\n\t\trev_G[to].push_back(from);\n\t}\n\n\troot = 0;\n\tnum_visited = 0;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tsemi[i] = -1;\n\t\tuf_parent[i] = i;\n\t\twork[i] = i;\n\t}\n\n\tdfs(root,-1);\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tint w = vertex[i];\n\n\t\tfor(int k = 0; k < rev_G[w].size(); k++){\n\t\t\tint v = rev_G[w][k];\n\t\t\tint u = EVAL(v);\n\t\t\tsemi[w] = min(semi[w],semi[u]);\n\t\t}\n\t\tbucket[vertex[semi[w]]].push_back(w);\n\t\tLINK(w,parent[w]);\n\n\t\tfor(int k = 0; k < bucket[parent[w]].size(); k++){\n\n\t\t\tint v = bucket[parent[w]][k];\n\t\t\tint u = EVAL(v);\n\n\t\t\tif(semi[u] < semi[v]){\n\n\t\t\t\tdom[v] = u;\n\t\t\t}else{\n\n\t\t\t\tdom[v] = parent[w];\n\t\t\t}\n\t\t}\n\n\t\tbucket[vertex[semi[w]]].clear();\n\t}\n\n\tfor(int i = 1; i < N; i++){\n\n\t\tint w = vertex[i];\n\t\tif(dom[w] != vertex[semi[w]]){\n\n\t\t\tdom[w] = dom[dom[w]];\n\t\t}\n\t}\n\tdom[root] = -1;\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tint tmp;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\ttmp--;\n\n\t\tif(dom[tmp] == root){\n\n\t\t\tprintf(\"%d\\n\",tmp+1);\n\t\t}else{\n\n\t\t\tprintf(\"%d\\n\",dom[tmp]+1);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 30, "memory_kb": 14500, "score_of_the_acc": -0.2291, "final_rank": 19 } ]
aoj_0292_cpp
壁 2XXX年、突然出現した天敵の侵入を防ぐために、人類は壁を作りその中に逃げ込んだ。その結果、人類の活動領域はその壁で囲まれた範囲に限定されてしまった。この領域は、上空から見ると W × H の長方形である。領域内部には x 軸あるいは y 軸に対して平行な壁がいくつか設置されている。活動領域の例を下図に示す。 人類は活動領域内を自由に移動することができるが、壁を越えるためには一定量の資源を消費しなければならない。ただし、壁を越えることはできるが(図中の (1))、壁の交点を越えること (2)、壁や活動領域の境界の上を移動すること (3)、活動領域外に出ること (4) はできない。 領域内部の壁の情報といくつかの始点と終点の組を入力し、始点から終点へ移動するために越えなければならない壁の数の最小値を計算するプログラムを作成しなさい。ただし、壁は幅のない線分とします。 入力 入力は1つのデータセットからなる。入力データは以下の形式で与えられる。 W H M px 1 py 1 qx 1 qy 1 px 2 py 2 qx 2 qy 2 : px M py M qx M qy M Q sx 1 sy 1 gx 1 gy 1 sx 2 sy 2 gx 2 gy 2 : sx Q sy Q gx Q gy Q 1行目に領域の横の長さと縦の長さを表す整数 W , H (2 ≤ W,H ≤ 1,000,000,000) と壁の数 M (0 ≤ M ≤ 100) が与えられる。 続く M 行に壁を表す線分の情報が与えられる。各行に与えられる4つの整数 px i , py i , qx i , qy i (0 ≤ px i , qx i ≤ W , 0 ≤ py i , qy i ≤ H ) はそれぞれ i 番目の線分の端点の x 座標、 y 座標、もうひとつの端点の x 座標、 y 座標を表す。 続く1行に質問の数 Q (1 ≤ Q ≤ 100) が与えられる。続く Q 行に各質問が与えられる。各質問に含まれる4つの整数 sx i , sy i , gx i , gy i (0 < sx i , gx i < W , 0 < sy i , gy i < H ) はそれぞれ始点の x 座標、 y 座標、終点の x 座標、 y 座標を表す。 入力は以下の条件を満たす。 各線分は x 軸あるいは y 軸に対して平行であり、長さは1以上である。 2つの互いに平行な線分が同じ点あるいは線分を共有することはない。 スタート地点、ゴール地点は壁上にあることはない。 どの線分も活動領域の境界と線分を共有することはない。 出力 質問ごとに、壁を越える回数の最小値を出力する。 入出力例 入力例 1 5 6 5 0 2 5 2 0 3 5 3 0 4 3 4 1 4 1 6 3 0 3 6 2 2 5 4 1 2 5 4 5 出力例 1 3 1 入力例 2 4 4 0 1 1 1 2 2 出力例 2 0 入力例 3 4 7 3 0 2 2 2 3 3 4 3 0 5 4 5 3 1 1 1 3 1 1 1 4 1 1 1 6 出力例 3 0 0 1
[ { "submission_id": "aoj_0292_5958818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> dx = {1, 0, -1, 0};\nvector<int> dy = {0, 1, 0, -1};\nint main(){\n int W, H, M;\n cin >> W >> H >> M;\n vector<int> px(M), py(M), qx(M), qy(M);\n for (int i = 0; i < M; i++){\n cin >> px[i] >> py[i] >> qx[i] >> qy[i];\n }\n vector<int> x;\n for (int i = 0; i < M; i++){\n x.push_back(px[i]);\n x.push_back(qx[i]);\n }\n x.push_back(0);\n x.push_back(W);\n sort(x.begin(), x.end());\n x.erase(unique(x.begin(), x.end()), x.end());\n for (int i = 0; i < M; i++){\n px[i] = lower_bound(x.begin(), x.end(), px[i]) - x.begin();\n qx[i] = lower_bound(x.begin(), x.end(), qx[i]) - x.begin();\n }\n W = lower_bound(x.begin(), x.end(), W) - x.begin();\n vector<int> y;\n for (int i = 0; i < M; i++){\n y.push_back(py[i]);\n y.push_back(qy[i]);\n }\n y.push_back(0);\n y.push_back(H);\n sort(y.begin(), y.end());\n y.erase(unique(y.begin(), y.end()), y.end());\n for (int i = 0; i < M; i++){\n py[i] = lower_bound(y.begin(), y.end(), py[i]) - y.begin();\n qy[i] = lower_bound(y.begin(), y.end(), qy[i]) - y.begin();\n }\n H = lower_bound(y.begin(), y.end(), H) - y.begin();\n vector<vector<vector<int>>> c(4, vector<vector<int>>(W, vector<int>(H, 0)));\n for (int i = 0; i < M; i++){\n if (px[i] == qx[i]){\n if (py[i] > qy[i]){\n swap(py[i], qy[i]);\n }\n for (int j = py[i]; j < qy[i]; j++){\n c[0][px[i] - 1][j] = 1;\n c[2][px[i]][j] = 1;\n }\n }\n if (py[i] == qy[i]){\n if (px[i] > qx[i]){\n swap(px[i], qx[i]);\n }\n for (int j = px[i]; j < qx[i]; j++){\n c[1][j][py[i] - 1] = 1;\n c[3][j][py[i]] = 1;\n }\n }\n }\n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n int sx, sy, gx, gy;\n cin >> sx >> sy >> gx >> gy;\n sx = lower_bound(x.begin(), x.end(), sx) - x.begin() - 1;\n gx = lower_bound(x.begin(), x.end(), gx) - x.begin() - 1;\n sy = lower_bound(y.begin(), y.end(), sy) - y.begin() - 1;\n gy = lower_bound(y.begin(), y.end(), gy) - y.begin() - 1;\n vector<vector<int>> d(W, vector<int>(H, -1));\n deque<tuple<int, int, int>> dq;\n dq.push_back(make_tuple(0, sx, sy));\n while (!dq.empty()){\n int dd = get<0>(dq.front());\n int cx = get<1>(dq.front());\n int cy = get<2>(dq.front());\n dq.pop_front();\n if (d[cx][cy] == -1){\n d[cx][cy] = dd;\n for (int j = 0; j < 4; j++){\n int x2 = cx + dx[j];\n int y2 = cy + dy[j];\n if (0 <= x2 && x2 < W && 0 <= y2 && y2 < H){\n if (c[j][cx][cy] == 0){\n dq.push_front(make_tuple(dd, x2, y2));\n } else {\n dq.push_back(make_tuple(dd + 1, x2, y2));\n }\n }\n }\n }\n }\n cout << d[gx][gy] << endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3796, "score_of_the_acc": -0.0665, "final_rank": 3 }, { "submission_id": "aoj_0292_5958815", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> dx = {1, 0, -1, 0};\nvector<int> dy = {0, 1, 0, -1};\nint main(){\n int W, H, M;\n cin >> W >> H >> M;\n vector<int> px(M), py(M), qx(M), qy(M);\n for (int i = 0; i < M; i++){\n cin >> px[i] >> py[i] >> qx[i] >> qy[i];\n }\n vector<int> x;\n for (int i = 0; i < M; i++){\n x.push_back(px[i]);\n x.push_back(qx[i]);\n }\n x.push_back(0);\n x.push_back(W);\n sort(x.begin(), x.end());\n x.erase(unique(x.begin(), x.end()), x.end());\n for (int i = 0; i < M; i++){\n px[i] = lower_bound(x.begin(), x.end(), px[i]) - x.begin();\n qx[i] = lower_bound(x.begin(), x.end(), qx[i]) - x.begin();\n }\n W = lower_bound(x.begin(), x.end(), W) - x.begin();\n vector<int> y;\n for (int i = 0; i < M; i++){\n y.push_back(py[i]);\n y.push_back(qy[i]);\n }\n y.push_back(0);\n y.push_back(H);\n sort(y.begin(), y.end());\n y.erase(unique(y.begin(), y.end()), y.end());\n for (int i = 0; i < M; i++){\n py[i] = lower_bound(y.begin(), y.end(), py[i]) - y.begin();\n qy[i] = lower_bound(y.begin(), y.end(), qy[i]) - y.begin();\n }\n H = lower_bound(y.begin(), y.end(), H) - y.begin();\n vector<vector<vector<int>>> c(4, vector<vector<int>>(W, vector<int>(H, 0)));\n for (int i = 0; i < M; i++){\n \tif (px[i] == qx[i]){\n \t if (py[i] > qy[i]){\n \t swap(py[i], qy[i]);\n \t }\n \t for (int j = py[i]; j < qy[i]; j++){\n \t c[0][px[i] - 1][j] = 1;\n \t c[2][px[i]][j] = 1;\n \t }\n \t}\n if (py[i] == qy[i]){\n if (px[i] > qx[i]){\n swap(px[i], qx[i]);\n }\n for (int j = px[i]; j < qx[i]; j++){\n c[1][j][py[i] - 1] = 1;\n c[3][j][py[i]] = 1;\n }\n }\n }\n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n int sx, sy, gx, gy;\n cin >> sx >> sy >> gx >> gy;\n sx = lower_bound(x.begin(), x.end(), sx) - x.begin() - 1;\n gx = lower_bound(x.begin(), x.end(), gx) - x.begin() - 1;\n sy = lower_bound(y.begin(), y.end(), sy) - y.begin() - 1;\n gy = lower_bound(y.begin(), y.end(), gy) - y.begin() - 1;\n vector<vector<int>> d(W, vector<int>(H, -1));\n deque<tuple<int, int, int>> dq;\n dq.push_back(make_tuple(0, sx, sy));\n while (!dq.empty()){\n int dd = get<0>(dq.front());\n int cx = get<1>(dq.front());\n int cy = get<2>(dq.front());\n dq.pop_front();\n if (d[cx][cy] == -1){\n d[cx][cy] = dd;\n for (int j = 0; j < 4; j++){\n int x2 = cx + dx[j];\n int y2 = cy + dy[j];\n if (0 <= x2 && x2 < W && 0 <= y2 && y2 < H){\n if (c[j][cx][cy] == 0){\n dq.push_front(make_tuple(dd, x2, y2));\n } else {\n dq.push_back(make_tuple(dd + 1, x2, y2));\n }\n }\n }\n }\n }\n cout << d[gx][gy] << endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3800, "score_of_the_acc": -0.0802, "final_rank": 4 }, { "submission_id": "aoj_0292_5921615", "code_snippet": "#include <atomic>\n#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\n\nmap<int,int> compress(set<int> v){\n map<int,int> res;\n foreach(i,v)res[i]=0;\n int cnt = 0;\n foreach(i,res){\n i.second = cnt;\n cnt += 2;\n }\n return res;\n}\n\ntemplate <class type = long long>\nclass dijkstra{\npublic:\n using E = pair<int,type>;\n using S = pair<type,int>;\n\tint n;\n\tvvector<E> edges;\n\tvector<type> fast;\n type inf;\n\tdijkstra(int N,type inf=numeric_limits<type>::max()>>1):n(N),inf(inf){\n\t\tedges.resize(n);\n\t}\n\n\tvoid add_edge(int from, int to, type cost, bool rev=false){\n\t\tedges[from].emplace_back(to, cost);\n if(rev){\n edges[to].emplace_back(from, cost);\n }\n\t}\n\n\tvoid solve(int start){\n\t\tpriority_queuer<S> pq;\n\t\tfast.assign(n, inf);\n\t\tpq.emplace(0, 0);\n\t\tfast[start] = 0;\n\t\tpq.emplace(0, start);\n\t\twhile(pq.size()){\n\t\t\tS d = pq.top();\n\t\t\tpq.pop();\n\t\t\tif(d.first!=fast[d.second])continue;\n for(E e:edges[d.second]){\n\t\t\t\ttype next_time = d.first + e.second;\n\t\t\t\tint to = e.first;\n\t\t\t\tif(fast[to] <= next_time)continue;\n\t\t\t\tfast[to] = next_time;\n\t\t\t\tpq.emplace(next_time, to);\n\t\t\t}\n\t\t}\n\t}\n\n type operator[](int p){\n return fast[p];\n }\n};\n\n\nvector<int> func(){\n int w = in();\n int h = in();\n int m = in();\n vector<pii> s1s(m);\n vector<pii> s2s(m);\n rep(i,m){\n s1s[i] = in<pii>();\n s2s[i] = in<pii>();\n }\n map<int,int> cx;\n map<int,int> cy;\n {\n set<int> xs;\n set<int> ys;\n xs.emplace(0);\n ys.emplace(0);\n xs.emplace(w);\n ys.emplace(h);\n foreach(i,s1s)xs.emplace(i.first);\n foreach(i,s2s)xs.emplace(i.first);\n foreach(i,s1s)ys.emplace(i.second);\n foreach(i,s2s)ys.emplace(i.second);\n cx = compress(xs);\n cy = compress(ys);\n }\n method(get_x,int,int x){\n auto itr = cx.lower_bound(x);\n if(itr->first==x)return itr->second;\n return itr->second - 1;\n };\n method(get_y,int,int y){\n auto itr = cy.lower_bound(y);\n if(itr->first==y)return itr->second;\n return itr->second - 1;\n };\n method(toint,int,int y,int x){\n return x + (cx.rbegin()->second + 1) * y;\n };\n h = cy.rbegin()->second+1;\n w = cx.rbegin()->second+1;\n dijkstra<int> di(toint(h,w));\n vvector<char> board(h,vector<char>(w,false));\n rep(i,m){\n int py = get_y(s1s[i].second);\n int px = get_x(s1s[i].first);\n int gy = get_y(s2s[i].second);\n int gx = get_x(s2s[i].first);\n rep(y,min(py,gy),max(py,gy)+1){\n rep(x,min(px,gx),max(px,gx)+1){\n board[y][x] = true;\n }\n }\n }\n int dx[]={1,0,-1,0};\n int dy[]={0,-1,0,1};\n rep(i,h){\n rep(j,w){\n rep(k,4){\n int ni = i + dy[k];\n int nj = j + dx[k];\n if(0 <= ni and ni < h and 0 <= nj and nj < w){\n di.add_edge(toint(i,j),toint(ni,nj),board[ni][nj] ? 1 : 0);\n }\n }\n }\n }\n int q = in();\n vector<int> res;\n rep(i,q){\n int sx = in();\n int sy = in();\n int gx = in();\n int gy = in();\n di.solve(toint(get_y(sy),get_x(sx)));\n res.emplace_back(di[toint(get_y(gy),get_x(gx))]);\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n foreach(i,func()){\n println(i);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 8720, "score_of_the_acc": -0.9075, "final_rank": 11 }, { "submission_id": "aoj_0292_5339353", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing ull = unsigned long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int,P>;\nusing PP = pair<P, P>;\nconstexpr int INF32 = 1 << 29;\nconstexpr ll INF64 = 1LL << 62;\nconstexpr ll MOD = 1000000007;\n// constexpr ll MOD = 998244353;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\nconstexpr int di8[] = {0, 1, 1, 1, 0, -1, -1, -1};\nconstexpr int dj8[] = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr double EPS = 1e-10;\nconst double PI = acos(-1);\n\n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,n) for(int i=0,i_len=n; i<i_len; ++i)\n\ntemplate<typename T1,typename T2> bool chmax(T1 &a, T2 b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename T1,typename T2> bool chmin(T1 &a, T2 b) { if (b<a) { a=b; return 1; } return 0; }\n\nvoid compress(vector<int> &v, map<int,int> &zip){\n sort(ALL(v));\n v.erase(unique(ALL(v)),v.end());\n int n = v.size();\n REP(i,n){\n zip[v[i]] = i;\n }\n}\n\nint solve(){\n int H, W, M;\n cin >> W >> H >> M;\n vector<int> xs = {0,W}, ys = {0,H};\n vector<PP> lines, query;\n for(int i=0;i<M;i++){\n int px, py, qx, qy;\n cin >> px >> py >> qx >> qy;\n lines.emplace_back(P(px,py),P(qx,qy));\n xs.emplace_back(min(px,W));\n xs.emplace_back(max(px-1,0));\n xs.emplace_back(min(qx,W));\n xs.emplace_back(max(qx-1,0));\n ys.emplace_back(min(py,H));\n ys.emplace_back(max(py-1,0));\n ys.emplace_back(min(qy,H));\n ys.emplace_back(max(qy-1,0));\n }\n int Q;\n cin >> Q;\n for(int i=0;i<Q;i++){\n int sx, sy, gx, gy;\n cin >> sx >> sy >> gx >> gy;\n query.emplace_back(P(sx,sy),P(gx,gy));\n xs.emplace_back(sx);\n xs.emplace_back(gx);\n ys.emplace_back(sy);\n ys.emplace_back(gy);\n }\n map<int,int> cxs, cys;\n compress(xs, cxs);\n compress(ys, cys);\n int h = (int)ys.size()-1, w = (int)xs.size()-1;\n vector<vector<vector<int> > > cost(h, vector<vector<int> >(w, vector<int>(4,0)));\n REP(i,M){\n int px, py, qx, qy;\n px = lines[i].first.first;\n py = lines[i].first.second;\n qx = lines[i].second.first;\n qy = lines[i].second.second;\n if(px == qx){\n int lb = cys[py], ub = cys[qy];\n int x = cxs[px];\n if(lb > ub) swap(lb, ub);\n for(int y=lb;y<ub;y++){\n cost[y][x-1][0] = 1;\n cost[y][x][2] = 1;\n }\n }else{\n int lb = cxs[px], ub = cxs[qx];\n int y = cys[py];\n if(lb > ub) swap(lb, ub);\n for(int x=lb;x<ub;x++){\n cost[y-1][x][1] = 1;\n cost[y][x][3] = 1;\n }\n }\n }\n vector<vector<int> > d(h,vector<int>(w));\n REP(i,Q){\n int sx, sy, gx, gy;\n sx = cxs[query[i].first.first];\n sy = cys[query[i].first.second];\n gx = cxs[query[i].second.first];\n gy = cys[query[i].second.second];\n REP(y,h) fill(d[y].begin(), d[y].end(), INF32);\n deque<P> que;\n que.push_back(P(sx,sy));\n d[sy][sx] = 0;\n while(!que.empty()){\n P pos = que.front();\n que.pop_front();\n int x = pos.first, y = pos.second;\n REP(k,4){\n int ny = y+di[k], nx = x+dj[k];\n if(ny<0 || ny>=h || nx<0 || nx>=w) continue;\n if(chmin(d[ny][nx], d[y][x]+cost[y][x][k])){\n if(cost[y][x][k]==0) que.push_front(P(nx,ny));\n else que.push_back(P(nx,ny));\n }\n }\n }\n cout << d[gy][gx] << endl;\n }\n return 0;\n}\n\nint main(){\n cin.tie(0); ios::sync_with_stdio(0); cout<<fixed<<setprecision(20);\n // int t; cin >> t; for(int i=0;i<t;i++) solve();\n // while(!solve());\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 16324, "score_of_the_acc": -1.4517, "final_rank": 14 }, { "submission_id": "aoj_0292_5056511", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<deque>\nusing namespace std;\nint H,W,N,Q;\nvector<int>X,Y;\nint a[111],b[111],c[111],d[111];\nint D[222][222];\nbool check(const vector<pair<int,int> >&A,int x)\n{\n\tauto it=upper_bound(A.begin(),A.end(),make_pair(x,(int)1e9));\n\tif(it!=A.begin())\n\t{\n\t\tit--;\n\t\tif(it->first<=x&&x<it->second)return true;\n\t\telse return false;\n\t}\n\treturn false;\n}\nmain()\n{\n\tcin>>H>>W>>N;\n\tfor(int i=0;i<N;i++)cin>>a[i]>>b[i]>>c[i]>>d[i];\n\ta[N]=0;b[N]=0;c[N]=H;d[N]=0;\n\ta[N+1]=0;b[N+1]=0;c[N+1]=0;d[N+1]=W;\n\ta[N+2]=H;b[N+2]=0;c[N+2]=H;d[N+2]=W;\n\ta[N+3]=0;b[N+3]=W;c[N+3]=H;d[N+3]=W;\n\tN+=4;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tX.push_back(a[i]);\n\t\tY.push_back(b[i]);\n\t\tX.push_back(c[i]);\n\t\tY.push_back(d[i]);\n\t}\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tvector<vector<pair<int,int> > >EX(X.size()),EY(Y.size());\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint ai=lower_bound(X.begin(),X.end(),a[i])-X.begin();\n\t\tint bi=lower_bound(Y.begin(),Y.end(),b[i])-Y.begin();\n\t\tint ci=lower_bound(X.begin(),X.end(),c[i])-X.begin();\n\t\tint di=lower_bound(Y.begin(),Y.end(),d[i])-Y.begin();\n\t\tif(ai==ci)EX[ai].push_back(minmax(bi,di));\n\t\telse EY[bi].push_back(minmax(ai,ci));\n\t}\n\tH=X.size()-1;W=Y.size()-1;\n\tfor(int i=0;i<H;i++)sort(EX[i].begin(),EX[i].end());\n\tfor(int i=0;i<W;i++)sort(EY[i].begin(),EY[i].end());\n\tcin>>Q;\n\tfor(;Q--;)\n\t{\n\t\tint sx,sy,gx,gy;\n\t\t{\n\t\t\tint isx,isy,igx,igy;\n\t\t\tcin>>isx>>isy>>igx>>igy;\n\t\t\tsx=upper_bound(X.begin(),X.end(),isx)-X.begin()-1;\n\t\t\tsy=upper_bound(Y.begin(),Y.end(),isy)-Y.begin()-1;\n\t\t\tgx=upper_bound(X.begin(),X.end(),igx)-X.begin()-1;\n\t\t\tgy=upper_bound(Y.begin(),Y.end(),igy)-Y.begin()-1;\n\t\t}\n\t\tfor(int i=0;i<H;i++)for(int j=0;j<W;j++)D[i][j]=1e9;\n\t\tD[sx][sy]=0;\n\t\tdeque<pair<int,int> >P;\n\t\tP.push_back(make_pair(sx,sy));\n\t\twhile(!P.empty())\n\t\t{\n\t\t\tint x=P.front().first,y=P.front().second;\n\t\t\tP.pop_front();\n\t\t\tif(x>0)\n\t\t\t{\n\t\t\t\tint c=check(EX[x],y);\n\t\t\t\tint nxt=D[x][y]+c;\n\t\t\t\tif(D[x-1][y]>nxt)\n\t\t\t\t{\n\t\t\t\t\tD[x-1][y]=nxt;\n\t\t\t\t\tif(c)P.push_back(make_pair(x-1,y));\n\t\t\t\t\telse P.push_front(make_pair(x-1,y));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(y>0)\n\t\t\t{\n\t\t\t\tint c=check(EY[y],x);\n\t\t\t\tint nxt=D[x][y]+c;\n\t\t\t\tif(D[x][y-1]>nxt)\n\t\t\t\t{\n\t\t\t\t\tD[x][y-1]=nxt;\n\t\t\t\t\tif(c)P.push_back(make_pair(x,y-1));\n\t\t\t\t\telse P.push_front(make_pair(x,y-1));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(x+1<H)\n\t\t\t{\n\t\t\t\tint c=check(EX[x+1],y);\n\t\t\t\tint nxt=D[x][y]+c;\n\t\t\t\tif(D[x+1][y]>nxt)\n\t\t\t\t{\n\t\t\t\t\tD[x+1][y]=nxt;\n\t\t\t\t\tif(c)P.push_back(make_pair(x+1,y));\n\t\t\t\t\telse P.push_front(make_pair(x+1,y));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(y+1<W)\n\t\t\t{\n\t\t\t\tint c=check(EY[y+1],x);\n\t\t\t\tint nxt=D[x][y]+c;\n\t\t\t\tif(D[x][y+1]>nxt)\n\t\t\t\t{\n\t\t\t\t\tD[x][y+1]=nxt;\n\t\t\t\t\tif(c)P.push_back(make_pair(x,y+1));\n\t\t\t\t\telse P.push_front(make_pair(x,y+1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout<<D[gx][gy]<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3252, "score_of_the_acc": -0.0533, "final_rank": 2 }, { "submission_id": "aoj_0292_4976899", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int>P;\n\nconst int MOD=1000000007;\nconst int INF=0x3f3f3f3f;\nconst ll INFL=0x3f3f3f3f3f3f3f3f;\n\nint px[200],py[200],qx[200],qy[200];\nint sx[200],sy[200],gx[200],gy[200];\n\nint dx[]{1,-1,0,0},dy[]{0,0,1,-1};\n\nint lwb(int x,vector<int>&v){\n\treturn lower_bound(v.begin(),v.end(),x)-v.begin();\n}\nint main(){\n\tint w,h,m;scanf(\"%d%d%d\",&w,&h,&m);\n\tw*=2;h*=2;\n\tvector<int>xs,ys;\n\txs.push_back(0);xs.push_back(1);\n\txs.push_back(w-1);xs.push_back(w);\n\tys.push_back(0);ys.push_back(1);\n\tys.push_back(h-1);ys.push_back(h);\n\trep(i,m){\n\t\tscanf(\"%d%d%d%d\",&px[i],&py[i],&qx[i],&qy[i]);\n\t\tpx[i]*=2;py[i]*=2;qx[i]*=2;qy[i]*=2;\n\t\tfor(int j=-1;j<=1;j++){\n\t\t\txs.push_back(px[i]+j);xs.push_back(qx[i]+j);\n\t\t\tys.push_back(py[i]+j);ys.push_back(qy[i]+j);\n\t\t}\n\t}\n\tint q;cin>>q;\n\trep(i,q){\n\t\tscanf(\"%d%d%d%d\",&sx[i],&sy[i],&gx[i],&gy[i]);\n\t\tsx[i]*=2;sy[i]*=2;gx[i]*=2;gy[i]*=2;\n\t\txs.push_back(sx[i]);xs.push_back(gx[i]);\n\t\tys.push_back(sy[i]);ys.push_back(gy[i]);\n\t}\n\tsort(xs.begin(),xs.end());\n\txs.erase(unique(xs.begin(),xs.end()),xs.end());\n\tsort(ys.begin(),ys.end());\n\tys.erase(unique(ys.begin(),ys.end()),ys.end());\n\tint W=xs.size(),H=ys.size();\n\tvector<vector<int>>B(H,vector<int>(W));\n\trep(i,m){\n\t\tpx[i]=lwb(px[i],xs);\n\t\tpy[i]=lwb(py[i],ys);\n\t\tqx[i]=lwb(qx[i],xs);\n\t\tqy[i]=lwb(qy[i],ys);\n\t\tif(px[i]==qx[i]){\n\t\t\tif(py[i]>qy[i])swap(py[i],qy[i]);\n\t\t\tfor(int j=py[i];j<=qy[i];j++){\n\t\t\t\tB[j][px[i]]=1;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tif(px[i]>qx[i])swap(px[i],qx[i]);\n\t\t\tfor(int j=px[i];j<=qx[i];j++){\n\t\t\t\tB[py[i]][j]=1;\n\t\t\t}\n\t\t}\n\t}\n\trep(i,H)rep(j,W){\n\t\tif(i==0||j==0||i==H-1||j==W-1)B[i][j]=1;\n\t}\n\trep(i,q){\n\t\tsx[i]=lwb(sx[i],xs);\n\t\tsy[i]=lwb(sy[i],ys);\n\t\tgx[i]=lwb(gx[i],xs);\n\t\tgy[i]=lwb(gy[i],ys);\n\t\tvector<vector<int>>D(H,vector<int>(W,INF));\n\t\tdeque<P>que;\n\t\tD[sy[i]][sx[i]]=0;\n\t\tque.push_back(P(sy[i],sx[i]));\n\t\twhile(!que.empty()){\n\t\t\tP p=que.front();que.pop_front();\n\t\t\trep(k,4){\n\t\t\t\tint nx=p.first+dx[k],ny=p.second+dy[k];\n\t\t\t\tif(0<=nx&&nx<H&&0<=ny&&ny<W&&D[nx][ny]==INF){\n\t\t\t\t\tif(B[nx][ny]){\n\t\t\t\t\t\tD[nx][ny]=D[p.first][p.second]+1;\n\t\t\t\t\t\tque.push_back(P(nx,ny));\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tD[nx][ny]=D[p.first][p.second];\n\t\t\t\t\t\tque.push_front(P(nx,ny));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\",D[gy[i]][gx[i]]);\n\t}\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 6272, "score_of_the_acc": -0.9281, "final_rank": 12 }, { "submission_id": "aoj_0292_4498075", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int W, H, n;\n cin >> W >> H >> n;\n vector<int> zy = {0, H}, zx = {0, W};\n vector<array<int, 3>> A, B;\n for (int i = 0; i < n; ++i) {\n int x1, y1, x2, y2;\n cin >> x1 >> y1 >> x2 >> y2;\n zx.emplace_back(x1);\n zx.emplace_back(x2);\n zy.emplace_back(y1);\n zy.emplace_back(y2);\n if(x1 == x2){\n B.emplace_back(array<int, 3>{x1, y1, y2});\n }else {\n A.emplace_back(array<int, 3>{x1, x2, y1});\n }\n }\n\n sort(zy.begin(), zy.end());\n zy.erase(unique(zy.begin(), zy.end()), zy.end());\n sort(zx.begin(), zx.end());\n zx.erase(unique(zx.begin(), zx.end()), zx.end());\n auto fx = [&](int x){ return lower_bound(zx.begin(),zx.end(), x) - zx.begin(); };\n auto fy = [&](int y){ return lower_bound(zy.begin(),zy.end(), y) - zy.begin(); };\n int h = zy.size(), w = zx.size();\n vector<vector<pair<int, int>>> P(h), Q(w);\n for (int i = 0; i < A.size(); ++i) {\n P[fy(A[i][2])].emplace_back(A[i][0], A[i][1]);\n }\n for (int i = 0; i < B.size(); ++i) {\n Q[fx(B[i][0])].emplace_back(B[i][1], B[i][2]);\n }\n auto f = [&](int i, int j){ return i*(w-1)+j; };\n vector<vector<pair<int, int>>> G((h-1)*(w-1));\n vector<int> S(w+1);\n for (int i = 1; i < h-1; ++i) {\n fill(S.begin(),S.end(), 0);\n for (auto &&j : P[i]) {\n S[fx(j.first)]++;\n S[fx(j.second+1)-1]--;\n }\n for (int j = 0; j < w-1; ++j) {\n G[f(i-1, j)].emplace_back(f(i, j), S[j]);\n G[f(i, j)].emplace_back(f(i-1, j), S[j]);\n S[j+1] += S[j];\n }\n }\n S.resize(h+1);\n for (int i = 1; i < w-1; ++i) {\n fill(S.begin(),S.end(), 0);\n for (auto &&j : Q[i]) {\n S[fy(j.first)]++;\n S[fy(j.second+1)-1]--;\n }\n for (int j = 0; j < h-1; ++j) {\n G[f(j, i-1)].emplace_back(f(j, i), S[j]);\n G[f(j, i)].emplace_back(f(j, i-1), S[j]);\n S[j+1] += S[j];\n }\n }\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n int x1, y1, x2, y2;\n cin >> x1 >> y1 >> x2 >> y2;\n int s = f(fy(y1+1)-1, fx(x1+1)-1), g = f(fy(y2+1)-1, fx(x2+1)-1);\n vector<int> dist((h-1)*(w-1), INF<int>);\n dist[s] = 0;\n deque<int> que;\n que.emplace_back(s);\n while(!que.empty()){\n int x = que.front(); que.pop_front();\n for (auto &&j : G[x]) {\n if(j.second == 0){\n if(dist[j.first] > dist[x]){\n dist[j.first] = dist[x];\n que.emplace_front(j.first);\n }\n }else {\n if(dist[j.first] > dist[x]+1){\n dist[j.first] = dist[x]+1;\n que.emplace_back(j.first);\n }\n }\n }\n }\n cout << dist[g] << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4372, "score_of_the_acc": -0.1088, "final_rank": 5 }, { "submission_id": "aoj_0292_3858486", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing ull=unsigned long long;\nusing uint=unsigned int;\nusing pcc=pair<char,char>;\nusing pii=pair<int,int>;\nusing pll=pair<ll,ll>;\nusing pdd=pair<double,double>;\nusing tuplis=pair<ll,pll>;\nusing tuplis2=pair<pll,ll>;\ntemplate<class T> using pq=priority_queue<T,vector<T>,greater<T>>;\nconst ll LINF=0x1fffffffffffffff;\nconst ll MINF=0x7fffffffffff;\nconst int INF=0x3fffffff;\nconst ll MOD=1000000007;\nconst ll MODD=998244353;\nconst ld DINF=numeric_limits<ld>::infinity();\nconst ld EPS=1e-9;\nconst ld PI=3.141592653589793238462643383279;\nconst vector<ll>four{0,1,0,-1,0};\n#define _overload4(_1,_2,_3,_4,name,...) name\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<n;++i)\n#define _rep2(i,n) for(ll i=0;i<n;++i)\n#define _rep3(i,a,b) for(ll i=a;i<b;++i)\n#define _rep4(i,a,b,c) for(ll i=a;i<b;i+=c)\n#define rep(...) _overload4(__VA_ARGS__,_rep4,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define _rrep1(n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep2(i,n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep3(i,a,b) for(ll i=(b)-1;i>=a;i--)\n#define _rrep4(i,a,b,c) for(ll i=a+(b-a-1)/c*c;i>=a;i-=c)\n#define rrep(...) _overload4(__VA_ARGS__,_rrep4,_rrep3,_rrep2,_rrep1)(__VA_ARGS__)\n#define each(i,a) for(auto &i:a)\n#define sum(...) accumulate(range(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(range(__VA_ARGS__),double(0))\n#define _range(i) (i).begin(),(i).end()\n#define _range2(i,k) (i).begin(),(i).begin()+k\n#define _range3(i,a,b) (i).begin()+a,(i).begin()+b\n#define range(...) _overload3(__VA_ARGS__,_range3,_range2,_range)(__VA_ARGS__)\n#define _rrange(i) (i).rbegin(),(i).rend()\n#define _rrange2(i,k) (i).rbegin(),(i).rbegin()+k\n#define _rrange3(i,a,b) (i).rbegin()+a,(i).rbegin()+b\n#define rrange(...) _overload3(__VA_ARGS__,_rrange3,_rrange2,_rrange)(__VA_ARGS__)\n#define elif else if\n#define unless(a) if(!(a))\n#define mp make_pair\n#define mt make_tuple\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\ninline constexpr ll gcd(ll a,ll b){if(!a||!b)return 0;while(b){ll c=b;b=a%b;a=c;}return a;}\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\ntemplate<class T> inline constexpr T min(vector<T> &v){return *min_element(range(v));}\ninline char min(string &v){return *min_element(range(v));}\ntemplate<class T> inline constexpr T max(vector<T> &v){return *max_element(range(v));}\ninline char max(string &v){return *max_element(range(v));}\ninline constexpr ll intpow(ll a,ll b){ll ans=1;for(ll i=1;b;i*=2){if(b&i){b^=i;ans*=a;}a*=a;}return ans;}\ntemplate<typename T>\ninline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<typename T>\ninline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\ntemplate<class T> unordered_map<T,ll> press(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); unordered_map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ntemplate<class T> map<T,ll> press_map(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ninline int scan(){ return getchar(); }\ninline void scan(int &a){ scanf(\"%d\", &a); }\ninline void scan(unsigned &a){ scanf(\"%u\", &a); }\ninline void scan(long &a){ scanf(\"%ld\", &a); }\ninline void scan(long long &a){ scanf(\"%lld\", &a); }\ninline void scan(unsigned long long &a){ scanf(\"%llu\", &a); }\ninline void scan(char &a){ cin >> a; }\ninline void scan(float &a){ scanf(\"%f\", &a); }\ninline void scan(double &a){ scanf(\"%lf\", &a); }\ninline void scan(long double &a){ scanf(\"%Lf\", &a); }\ninline void scan(vector<bool> &vec){ for(unsigned i = 0; i < vec.size(); i++) { int a; scan(a); vec[i] = a; } }\ninline void scan(string &a){ cin >> a; }\ntemplate<class T> inline void scan(vector<T> &vec);\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec);\ntemplate<class T, class L> inline void scan(pair<T, L> &p);\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]);\ntemplate<class T> inline void scan(vector<T> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, class L> inline void scan(pair<T, L> &p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]){ for(auto &i : vec) scan(i); }\ntemplate<class T> inline void scan(T &a){ cin>>a; }\ninline void in(){}\ntemplate <class Head, class... Tail> inline void in(Head &head, Tail&... tail){ scan(head); in(tail...); }\ninline void print(){ putchar(' '); }\ninline void print(const bool &a){ printf(\"%d\", a); }\ninline void print(const int &a){ printf(\"%d\", a); }\ninline void print(const unsigned &a){ printf(\"%u\", a); }\ninline void print(const long &a){ printf(\"%ld\", a); }\ninline void print(const long long &a){ printf(\"%lld\", a); }\ninline void print(const unsigned long long &a){ printf(\"%llu\", a); }\ninline void print(const char &a){ printf(\"%c\", a); }\ninline void print(const char a[]){ printf(\"%s\", a); }\ninline void print(const float &a){ printf(\"%.15f\", a); }\ninline void print(const double &a){ printf(\"%.15f\", a); }\ninline void print(const long double &a){ printf(\"%.15Lf\", a); }\ntemplate<class T> void print(const vector<T> &vec);\ntemplate<class T, size_t size> void print(const array<T, size> &vec);\ntemplate<class T, class L> void print(const pair<T, L> &p);\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]);\ntemplate<class T> void print(const vector<T> &vec){ if(vec.empty()) return; print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size> &vec){ print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L> &p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]){ print(vec[0]); for(auto i = vec; ++i != end(vec); ){ putchar(' '); print(*i); } }\ntemplate<class T> inline void print(const T &a){ cout << a; }\ninline int out(){ putchar('\\n'); return 0; }\ntemplate<class T> inline int out(const T &t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> inline int out(const Head &head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\ntemplate <class T> inline void err(T t){cerr<<t<<'\\n';}\ntemplate<class Head, class... Tail> inline void err(const Head &head, const Tail&... tail){ cerr<<head<<' '; err(tail...); }\ninline void err(){cerr<<'\\n';}\ninline int first(const bool &i){return out(i?\"first\":\"second\");}\ninline int yes(const bool &i){return out(i?\"yes\":\"no\");}\ninline int Yes(const bool &i){return out(i?\"Yes\":\"No\");}\ninline int YES(const bool &i){return out(i?\"YES\":\"NO\");}\ninline int Yay(const bool &i){return out(i?\"Yay!\":\":(\");}\ninline int Possible(const bool &i){return out(i?\"Possible\":\"Impossible\");}\ninline int POSSIBLE(const bool &i){return out(i?\"POSSIBLE\":\"IMPOSSIBLE\");}\ninline void Case(ll i){printf(\"Case #%lld: \",i);}\n\n\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\ntemplate<class T> using gpp_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate<class T, class L> using gpp_map = tree<T, L, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\nsigned main(){\n LL(w,h,m);\n VV(ll,a,m,4);\n gpp_set<ll>x,y;\n x.insert(0);\n y.insert(0);\n x.insert(w);\n y.insert(h);\n each(i,a){\n x.insert(i[0]);\n y.insert(i[1]);\n x.insert(i[2]);\n y.insert(i[3]);\n }\n ll X=x.size()-1,Y=y.size()-1;\n vv(ll,tate,X,Y-1);\n vv(ll,yoko,X-1,Y);\n each(i,a){\n i[0]=x.order_of_key(i[0]);\n i[1]=y.order_of_key(i[1]);\n i[2]=x.order_of_key(i[2]);\n i[3]=y.order_of_key(i[3]);\n if(i[0]==i[2]){\n rep(j,i[1],i[3])yoko[i[0]-1][j]=1;\n }\n if(i[1]==i[3]){\n rep(j,i[0],i[2])tate[j][i[1]-1]=1;\n }\n }\n LL(q);\n rep(_,q){\n vv(ll,cost,X,Y,LINF);\n vv(bool,visit,X,Y);\n VEC(ll,a,4);\n a[0]=x.order_of_key(a[0])-1;\n a[1]=y.order_of_key(a[1])-1;\n a[2]=x.order_of_key(a[2])-1;\n a[3]=y.order_of_key(a[3])-1;\n cost[a[0]][a[1]]=0;\n pq<tuplis>q;\n q.push({0,{a[0],a[1]}});\n while(q.size()){\n ll x,y;\n tie(x,y)=q.top().second;\n q.pop();\n if(visit[x][y])continue;\n visit[x][y]=1;\n if(x>0)if(chmin(cost[x-1][y],cost[x][y]+yoko[x-1][y]))q.push({cost[x-1][y],{x-1,y}});\n if(y>0)if(chmin(cost[x][y-1],cost[x][y]+tate[x][y-1]))q.push({cost[x][y-1],{x,y-1}});\n if(x+1<X)if(chmin(cost[x+1][y],cost[x][y]+yoko[x][y]))q.push({cost[x+1][y],{x+1,y}});\n if(y+1<Y)if(chmin(cost[x][y+1],cost[x][y]+tate[x][y]))q.push({cost[x][y+1],{x,y+1}});\n }\n out(cost[a[2]][a[3]]);\n }\n}", "accuracy": 0.42857142857142855, "time_ms": 150, "memory_kb": 3396, "score_of_the_acc": -0.1972, "final_rank": 16 }, { "submission_id": "aoj_0292_3858180", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing ull=unsigned long long;\nusing uint=unsigned int;\nusing pcc=pair<char,char>;\nusing pii=pair<int,int>;\nusing pll=pair<ll,ll>;\nusing pdd=pair<double,double>;\nusing tuplis=pair<ll,pll>;\nusing tuplis2=pair<pll,ll>;\ntemplate<class T> using pq=priority_queue<T,vector<T>,greater<T>>;\nconst ll LINF=0x1fffffffffffffff;\nconst ll MINF=0x7fffffffffff;\nconst int INF=0x3fffffff;\nconst ll MOD=1000000007;\nconst ll MODD=998244353;\nconst ld DINF=numeric_limits<ld>::infinity();\nconst ld EPS=1e-9;\nconst ld PI=3.141592653589793238462643383279;\nconst vector<ll>four{0,1,0,-1,0};\n#define _overload4(_1,_2,_3,_4,name,...) name\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<n;++i)\n#define _rep2(i,n) for(ll i=0;i<n;++i)\n#define _rep3(i,a,b) for(ll i=a;i<b;++i)\n#define _rep4(i,a,b,c) for(ll i=a;i<b;i+=c)\n#define rep(...) _overload4(__VA_ARGS__,_rep4,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define _rrep1(n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep2(i,n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep3(i,a,b) for(ll i=(b)-1;i>=a;i--)\n#define _rrep4(i,a,b,c) for(ll i=a+(b-a-1)/c*c;i>=a;i-=c)\n#define rrep(...) _overload4(__VA_ARGS__,_rrep4,_rrep3,_rrep2,_rrep1)(__VA_ARGS__)\n#define each(i,a) for(auto &i:a)\n#define sum(...) accumulate(range(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(range(__VA_ARGS__),double(0))\n#define _range(i) (i).begin(),(i).end()\n#define _range2(i,k) (i).begin(),(i).begin()+k\n#define _range3(i,a,b) (i).begin()+a,(i).begin()+b\n#define range(...) _overload3(__VA_ARGS__,_range3,_range2,_range)(__VA_ARGS__)\n#define _rrange(i) (i).rbegin(),(i).rend()\n#define _rrange2(i,k) (i).rbegin(),(i).rbegin()+k\n#define _rrange3(i,a,b) (i).rbegin()+a,(i).rbegin()+b\n#define rrange(...) _overload3(__VA_ARGS__,_rrange3,_rrange2,_rrange)(__VA_ARGS__)\n#define elif else if\n#define unless(a) if(!(a))\n#define mp make_pair\n#define mt make_tuple\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\ninline constexpr ll gcd(ll a,ll b){if(!a||!b)return 0;while(b){ll c=b;b=a%b;a=c;}return a;}\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\ntemplate<class T> inline constexpr T min(vector<T> &v){return *min_element(range(v));}\ninline char min(string &v){return *min_element(range(v));}\ntemplate<class T> inline constexpr T max(vector<T> &v){return *max_element(range(v));}\ninline char max(string &v){return *max_element(range(v));}\ninline constexpr ll intpow(ll a,ll b){ll ans=1;for(ll i=1;b;i*=2){if(b&i){b^=i;ans*=a;}a*=a;}return ans;}\ntemplate<typename T>\ninline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<typename T>\ninline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\ntemplate<class T> unordered_map<T,ll> press(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); unordered_map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ntemplate<class T> map<T,ll> press_map(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ninline int scan(){ return getchar(); }\ninline void scan(int &a){ scanf(\"%d\", &a); }\ninline void scan(unsigned &a){ scanf(\"%u\", &a); }\ninline void scan(long &a){ scanf(\"%ld\", &a); }\ninline void scan(long long &a){ scanf(\"%lld\", &a); }\ninline void scan(unsigned long long &a){ scanf(\"%llu\", &a); }\ninline void scan(char &a){ cin >> a; }\ninline void scan(float &a){ scanf(\"%f\", &a); }\ninline void scan(double &a){ scanf(\"%lf\", &a); }\ninline void scan(long double &a){ scanf(\"%Lf\", &a); }\ninline void scan(vector<bool> &vec){ for(unsigned i = 0; i < vec.size(); i++) { int a; scan(a); vec[i] = a; } }\ninline void scan(string &a){ cin >> a; }\ntemplate<class T> inline void scan(vector<T> &vec);\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec);\ntemplate<class T, class L> inline void scan(pair<T, L> &p);\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]);\ntemplate<class T> inline void scan(vector<T> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, class L> inline void scan(pair<T, L> &p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]){ for(auto &i : vec) scan(i); }\ntemplate<class T> inline void scan(T &a){ cin>>a; }\ninline void in(){}\ntemplate <class Head, class... Tail> inline void in(Head &head, Tail&... tail){ scan(head); in(tail...); }\ninline void print(){ putchar(' '); }\ninline void print(const bool &a){ printf(\"%d\", a); }\ninline void print(const int &a){ printf(\"%d\", a); }\ninline void print(const unsigned &a){ printf(\"%u\", a); }\ninline void print(const long &a){ printf(\"%ld\", a); }\ninline void print(const long long &a){ printf(\"%lld\", a); }\ninline void print(const unsigned long long &a){ printf(\"%llu\", a); }\ninline void print(const char &a){ printf(\"%c\", a); }\ninline void print(const char a[]){ printf(\"%s\", a); }\ninline void print(const float &a){ printf(\"%.15f\", a); }\ninline void print(const double &a){ printf(\"%.15f\", a); }\ninline void print(const long double &a){ printf(\"%.15Lf\", a); }\ntemplate<class T> void print(const vector<T> &vec);\ntemplate<class T, size_t size> void print(const array<T, size> &vec);\ntemplate<class T, class L> void print(const pair<T, L> &p);\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]);\ntemplate<class T> void print(const vector<T> &vec){ if(vec.empty()) return; print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size> &vec){ print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L> &p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]){ print(vec[0]); for(auto i = vec; ++i != end(vec); ){ putchar(' '); print(*i); } }\ntemplate<class T> inline void print(const T &a){ cout << a; }\ninline int out(){ putchar('\\n'); return 0; }\ntemplate<class T> inline int out(const T &t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> inline int out(const Head &head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\ntemplate <class T> inline void err(T t){cerr<<t<<'\\n';}\ninline void err(){cerr<<'\\n';}\ninline int first(const bool &i){return out(i?\"first\":\"second\");}\ninline int yes(const bool &i){return out(i?\"yes\":\"no\");}\ninline int Yes(const bool &i){return out(i?\"Yes\":\"No\");}\ninline int YES(const bool &i){return out(i?\"YES\":\"NO\");}\ninline int Yay(const bool &i){return out(i?\"Yay!\":\":(\");}\ninline int Possible(const bool &i){return out(i?\"Possible\":\"Impossible\");}\ninline int POSSIBLE(const bool &i){return out(i?\"POSSIBLE\":\"IMPOSSIBLE\");}\ninline void Case(ll i){printf(\"Case #%lld: \",i);}\n\n\n\n\nsigned main(){\n LL(w,h,m);\n set<ll>x,y;\n x.insert(0);\n x.insert(w);\n y.insert(0);\n y.insert(h);\n vector<pair<pll,pll>>tate,yoko;\n rep(m){\n LL(a,b,c,d);\n x.insert(a);\n y.insert(b);\n x.insert(c);\n y.insert(d);\n (b==d?yoko:tate).push_back({{a,b},{c,d}});\n }\n map<ll,ll>px,py;\n ll cnt=0;\n each(i,x)px[i]=cnt++;\n cnt=0;\n each(i,y)py[i]=cnt++;\n each(i,tate){\n i.first.first=px[i.first.first];\n i.second.first=px[i.second.first];\n i.first.second=py[i.first.second];\n i.second.second=py[i.second.second];\n }\n each(i,yoko){\n i.first.first=px[i.first.first];\n i.second.first=px[i.second.first];\n i.first.second=py[i.first.second];\n i.second.second=py[i.second.second];\n }\n vv(ll,ctate,x.size(),y.size());\n vv(ll,cyoko,x.size(),y.size());\n each(i,tate)rep(j,i.first.second,i.second.second)cyoko[i.first.first-1][j]=1;\n each(i,yoko)rep(j,i.first.first,i.second.first)ctate[j][i.first.second-1]=1;\n LL(q);\n rep(q){\n LL(a,b,c,d);\n a=(--px.lower_bound(a))->second;\n b=(--py.lower_bound(b))->second;\n c=(--px.lower_bound(c))->second;\n d=(--py.lower_bound(d))->second;\n vv(ll,cost,x.size(),y.size(),LINF);\n vv(bool,visit,x.size(),y.size());\n cost[a][b]=0;\n pq<tuplis>q;\n q.push({0,{a,b}});\n while(q.size()){\n ll a,b;\n tie(a,b)=q.top().second;\n q.pop();\n if(visit[a][b])continue;\n visit[a][b]=1;\n if(a>0)if(chmin(cost[a-1][b],cost[a][b]+cyoko[a-1][b]))q.push({cost[a-1][b],{a-1,b}});\n if(a+2<x.size())if(chmin(cost[a+1][b],cost[a][b]+cyoko[a][b]))q.push({cost[a+1][b],{a+1,b}});\n if(b>0)if(chmin(cost[a][b-1],cost[a][b]+ctate[a][b-1]))q.push({cost[a][b-1],{a,b-1}});\n if(b+2<y.size())if(chmin(cost[a][b+1],cost[a][b]+ctate[a][b]))q.push({cost[a][b+1],{a,b+1}});\n }\n out(cost[c][d]);\n }\n}", "accuracy": 0.42857142857142855, "time_ms": 150, "memory_kb": 3556, "score_of_the_acc": -0.209, "final_rank": 18 }, { "submission_id": "aoj_0292_3723080", "code_snippet": "#include <cstdio>\n#include <cstdint>\n#include <cassert>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <string>\n#include <map>\n#include <queue>\n#include <tuple>\n#include <deque>\n\nconstexpr size_t m1 = -1;\nconstexpr size_t di[] = {m1, 0, 1, 0};\nconstexpr size_t dj[] = {0, m1, 0, 1};\n\nvoid append(std::map<int, size_t>& m, int x) {\n m[x-1], m[x], m[x+1];\n}\n\nint neko(std::vector<std::string> const& s,\n size_t si, size_t sj, size_t gi, size_t gj) {\n\n size_t h = s.size();\n size_t w = s[0].length();\n\n using zahyo = std::pair<size_t, size_t>;\n int inf = 1e9;\n std::vector<std::vector<int>> dp(h, std::vector<int>(w, inf));\n dp[si][sj] = 0;\n std::deque<zahyo> q;\n q.emplace_front(si, sj);\n while (!q.empty()) {\n size_t i, j;\n std::tie(i, j) = q.front();\n q.pop_front();\n bool breakable = (s[i][j] == '.');\n for (int k = 0; k < 4; ++k) {\n size_t ni = i + di[k];\n size_t nj = j + dj[k];\n if (!(ni < h && nj < w)) continue;\n int cost = 0;\n if (s[ni][nj] == '#') {\n if (!breakable) continue;\n cost = 1;\n }\n if (dp[ni][nj] > dp[i][j] + cost) {\n dp[ni][nj] = dp[i][j] + cost;\n if (cost == 0) {\n q.emplace_front(ni, nj);\n } else {\n q.emplace_back(ni, nj);\n }\n if (ni == gi && nj == gj) {\n // for (size_t i = 0; i < h; ++i)\n // for (size_t j = 0; j < w; ++j) {\n // if (dp[i][j] == inf) fprintf(stderr, \"##\");\n // else fprintf(stderr, \"%2d\", dp[i][j]);\n // fprintf(stderr, \"%c\", j+1<w? ' ':'\\n');\n // }\n return dp[ni][nj];\n }\n }\n }\n }\n\n assert(false);\n // return dp[gi][gj];\n}\n\nint main() {\n size_t h, w, m;\n scanf(\"%zu %zu %zu\", &w, &h, &m);\n\n std::map<int, size_t> xs, ys;\n std::vector<int> px(m), py(m), qx(m), qy(m);\n xs[0], xs[2*w], ys[0], ys[2*h];\n for (size_t i = 0; i < m; ++i) {\n scanf(\"%d %d %d %d\", &px[i], &py[i], &qx[i], &qy[i]);\n if (px[i] > qx[i]) std::swap(px[i], qx[i]);\n if (py[i] > qy[i]) std::swap(py[i], qy[i]);\n px[i] *= 2;\n py[i] *= 2;\n qx[i] *= 2;\n qy[i] *= 2;\n }\n\n size_t q;\n scanf(\"%zu\", &q);\n std::vector<int> sx(q), sy(q), gx(q), gy(q);\n for (size_t i = 0; i < q; ++i) {\n scanf(\"%d %d %d %d\", &sx[i], &sy[i], &gx[i], &gy[i]);\n // if (sx[i] > gx[i]) std::swap(sx[i], gx[i]);\n // if (sy[i] > gy[i]) std::swap(sy[i], gy[i]);\n sx[i] *= 2;\n sy[i] *= 2;\n gx[i] *= 2;\n gy[i] *= 2;\n }\n\n for (auto const& x: px) append(xs, x);\n for (auto const& x: qx) append(xs, x);\n for (auto const& x: sx) append(xs, x);\n for (auto const& x: gx) append(xs, x);\n\n for (auto const& y: py) append(ys, y);\n for (auto const& y: qy) append(ys, y);\n for (auto const& y: sy) append(ys, y);\n for (auto const& y: gy) append(ys, y);\n\n {\n size_t i = 0;\n for (auto& p: xs) p.second = i++;\n // for (auto& p: xs) {\n // fprintf(stderr, \"x: %d -> %zu\\n\", p.first, p.second);\n // }\n }\n {\n size_t i = 0;\n for (auto& p: ys) p.second = i++;\n // for (auto& p: ys) {\n // fprintf(stderr, \"y: %d -> %zu\\n\", p.first, p.second);\n // }\n }\n\n size_t hh = ys.size();\n size_t ww = xs.size();\n std::vector<std::string> s(hh, std::string(ww, '.'));\n for (size_t i = 0; i < m; ++i) {\n size_t pi = ys.at(py[i]);\n size_t pj = xs.at(px[i]);\n size_t qi = ys.at(qy[i]);\n size_t qj = xs.at(qx[i]);\n for (size_t ii = pi; ii <= qi; ++ii)\n for (size_t jj = pj; jj <= qj; ++jj)\n s[ii][jj] = '#';\n }\n\n s[ys.at(0)] = s[ys.at(2*h)] = std::string(ww, '#');\n s[0] = s[hh-1] = std::string(ww, '#');\n for (size_t i = 0; i < hh; ++i) {\n s[i][xs.at(0)] = s[i][xs.at(2*w)] = '#';\n s[i][0] = s[i][ww-1] = '#';\n }\n\n // for (size_t i = 0; i < hh; ++i)\n // fprintf(stderr, \"%s\\n\", s[i].c_str());\n\n for (size_t i = 0; i < q; ++i) {\n int res = neko(s, ys.at(sy[i]), xs.at(sx[i]), ys.at(gy[i]), xs.at(gx[i]));\n printf(\"%d\\n\", res);\n }\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 9728, "score_of_the_acc": -1.4748, "final_rank": 15 }, { "submission_id": "aoj_0292_3241785", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tint W, H, N, Q;\n\tcin >> W >> H >> N;\n\tvector<int> cx = { 0, W }, cy = { 0, H };\n\tvector<int> ax(N), ay(N), bx(N), by(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> ax[i] >> ay[i] >> bx[i] >> by[i];\n\t\tcx.push_back(ax[i]);\n\t\tcy.push_back(ay[i]);\n\t\tcx.push_back(bx[i]);\n\t\tcy.push_back(by[i]);\n\t}\n\tsort(cx.begin(), cx.end());\n\tcx.erase(unique(cx.begin(), cx.end()), cx.end());\n\tsort(cy.begin(), cy.end());\n\tcy.erase(unique(cy.begin(), cy.end()), cy.end());\n\tW = cx.size() - 1;\n\tH = cy.size() - 1;\n\tvector<vector<bool> > vertline(W + 1, vector<bool>(H)), horzline(W, vector<bool>(W + 1));\n\tfor (int i = 0; i < N; ++i) {\n\t\tax[i] = lower_bound(cx.begin(), cx.end(), ax[i]) - cx.begin();\n\t\tay[i] = lower_bound(cy.begin(), cy.end(), ay[i]) - cy.begin();\n\t\tbx[i] = lower_bound(cx.begin(), cx.end(), bx[i]) - cx.begin();\n\t\tby[i] = lower_bound(cy.begin(), cy.end(), by[i]) - cy.begin();\n\t\tif (ax[i] > bx[i]) swap(ax[i], bx[i]);\n\t\tif (ay[i] > by[i]) swap(ay[i], by[i]);\n\t\tif (ax[i] == bx[i]) {\n\t\t\tfor (int j = ay[i]; j < by[i]; ++j) {\n\t\t\t\thorzline[ax[i]][j] = true;\n\t\t\t}\n\t\t}\n\t\tif (ay[i] == by[i]) {\n\t\t\tfor (int j = ax[i]; j < bx[i]; ++j) {\n\t\t\t\tvertline[j][ay[i]] = true;\n\t\t\t}\n\t\t}\n\t}\n\tcin >> Q;\n\twhile (Q--) {\n\t\tint sx, sy, gx, gy;\n\t\tcin >> sx >> sy >> gx >> gy;\n\t\tsx = lower_bound(cx.begin(), cx.end(), sx) - cx.begin() - 1;\n\t\tsy = lower_bound(cy.begin(), cy.end(), sy) - cy.begin() - 1;\n\t\tgx = lower_bound(cx.begin(), cx.end(), gx) - cx.begin() - 1;\n\t\tgy = lower_bound(cy.begin(), cy.end(), gy) - cy.begin() - 1;\n\t\tvector<vector<int> > d(W, vector<int>(H, -1));\n\t\td[sx][sy] = 0;\n\t\tdeque<pair<int, int> > que;\n\t\tque.push_back(make_pair(sx, sy));\n\t\twhile (!que.empty()) {\n\t\t\tpair<int, int> u = que.front(); que.pop_front();\n\t\t\tint cur = d[u.first][u.second];\n\t\t\tif (u.first >= 1 && (d[u.first - 1][u.second] == -1 || d[u.first - 1][u.second] == cur + 1)) {\n\t\t\t\tif (horzline[u.first][u.second] && d[u.first - 1][u.second] == -1) {\n\t\t\t\t\td[u.first - 1][u.second] = cur + 1;\n\t\t\t\t\tque.push_back(make_pair(u.first - 1, u.second));\n\t\t\t\t}\n\t\t\t\tif (!horzline[u.first][u.second]) {\n\t\t\t\t\td[u.first - 1][u.second] = cur;\n\t\t\t\t\tque.push_front(make_pair(u.first - 1, u.second));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (u.first < W - 1 && (d[u.first + 1][u.second] == -1 || d[u.first + 1][u.second] == cur + 1)) {\n\t\t\t\tif (horzline[u.first + 1][u.second] && d[u.first + 1][u.second] == -1) {\n\t\t\t\t\td[u.first + 1][u.second] = cur + 1;\n\t\t\t\t\tque.push_back(make_pair(u.first + 1, u.second));\n\t\t\t\t}\n\t\t\t\tif (!horzline[u.first + 1][u.second]) {\n\t\t\t\t\td[u.first + 1][u.second] = cur;\n\t\t\t\t\tque.push_front(make_pair(u.first + 1, u.second));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (u.second >= 1 && (d[u.first][u.second - 1] == -1 || d[u.first][u.second - 1] == cur + 1)) {\n\t\t\t\tif (vertline[u.first][u.second] && d[u.first][u.second - 1] == -1) {\n\t\t\t\t\td[u.first][u.second - 1] = cur + 1;\n\t\t\t\t\tque.push_back(make_pair(u.first, u.second - 1));\n\t\t\t\t}\n\t\t\t\tif (!vertline[u.first][u.second]) {\n\t\t\t\t\td[u.first][u.second - 1] = cur;\n\t\t\t\t\tque.push_front(make_pair(u.first, u.second - 1));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (u.second < H - 1 && (d[u.first][u.second + 1] == -1 || d[u.first][u.second + 1] == cur + 1)) {\n\t\t\t\tif (vertline[u.first][u.second + 1] && d[u.first][u.second + 1] == -1) {\n\t\t\t\t\td[u.first][u.second + 1] = cur + 1;\n\t\t\t\t\tque.push_back(make_pair(u.first, u.second + 1));\n\t\t\t\t}\n\t\t\t\tif (!vertline[u.first][u.second + 1]) {\n\t\t\t\t\td[u.first][u.second + 1] = cur;\n\t\t\t\t\tque.push_front(make_pair(u.first, u.second + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << d[gx][gy] << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3280, "score_of_the_acc": -0.0154, "final_rank": 1 }, { "submission_id": "aoj_0292_2859932", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\tvoid set(int arg_row1,int arg_row2,int arg_col1,int arg_col2){\n\t\trow1 = arg_row1;\n\t\trow2 = arg_row2;\n\t\tcol1 = arg_col1;\n\t\tcol2 = arg_col2;\n\t}\n\tint row1,row2,col1,col2;\n};\n\nstruct Data{\n\tbool right_wall,under_wall;\n};\n\nstruct State{\n\tState(int arg_row,int arg_col,int arg_sum_cost){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tbool operator<(const struct State &arg) const{ //壁を越えた回数の昇順(PQ)\n\t\treturn sum_cost > arg.sum_cost;\n\t}\n\n\tint row,col,sum_cost;\n};\n\nint comp_H,comp_W; //座標圧縮後の高さと幅\nint diff_row[4] = {-1,0,0,1},diff_col[4] = {0,-1,1,0};\nint min_cost[500][500];\nInfo wall[100],query[100];\nData table[500][500];\n\nbool rangeCheck(int row,int col){\n\tif(row >= 2 && row <= comp_H-2 && col >= 2 && col <= comp_W-2)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nint main(){\n\n\tint W,H,M;\n\tscanf(\"%d %d %d\",&W,&H,&M);\n\n\tvector<int> ROW,COL;\n\n\t/*★外枠に注意!!★*/\n\tROW.push_back(0);\n\tROW.push_back(H);\n\tROW.push_back(-BIG_NUM);\n\tROW.push_back(BIG_NUM);\n\n\tCOL.push_back(0);\n\tCOL.push_back(W);\n\tCOL.push_back(-BIG_NUM);\n\tCOL.push_back(BIG_NUM);\n\n\tint row1,row2,col1,col2;\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d %d %d %d\",&col1,&row1,&col2,&row2);\n\n\t\tif(row1 > row2)swap(row1,row2);\n\t\tif(col1 > col2)swap(col1,col2);\n\n\t\twall[i].set(row1,row2,col1,col2);\n\n\t\tROW.push_back(row1);\n\t\tROW.push_back(row2);\n\t\tCOL.push_back(col1);\n\t\tCOL.push_back(col2);\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tfor(int i = 0; i < num_query; i++){\n\t\tscanf(\"%d %d %d %d\",&query[i].col1,&query[i].row1,&query[i].col2,&query[i].row2);\n\n\t\tROW.push_back(query[i].row1);\n\t\tROW.push_back(query[i].row2);\n\t\tCOL.push_back(query[i].col1);\n\t\tCOL.push_back(query[i].col2);\n\t}\n\n\tsort(ROW.begin(),ROW.end());\n\tsort(COL.begin(),COL.end());\n\n\tROW.erase(unique(ROW.begin(),ROW.end()),ROW.end());\n\tCOL.erase(unique(COL.begin(),COL.end()),COL.end());\n\n\tmap<int,int> INDEX_ROW,INDEX_COL;\n\tfor(int i = 0; i < ROW.size(); i++){\n\t\tINDEX_ROW[ROW[i]] = i;\n\t}\n\n\tfor(int i = 0; i < COL.size(); i++){\n\t\tINDEX_COL[COL[i]] = i;\n\t}\n\n\t//座標変換\n\tfor(int i = 0; i < M; i++){\n\t\twall[i].row1 = INDEX_ROW[wall[i].row1];\n\t\twall[i].row2 = INDEX_ROW[wall[i].row2];\n\t\twall[i].col1 = INDEX_COL[wall[i].col1];\n\t\twall[i].col2 = INDEX_COL[wall[i].col2];\n\t}\n\n\tfor(int i = 0; i < num_query; i++){\n\t\tquery[i].row1 = INDEX_ROW[query[i].row1];\n\t\tquery[i].row2 = INDEX_ROW[query[i].row2];\n\t\tquery[i].col1 = INDEX_COL[query[i].col1];\n\t\tquery[i].col2 = INDEX_COL[query[i].col2];\n\t}\n\n\tcomp_H = ROW.size(),comp_W = COL.size();\n\n\tfor(int row = 0; row < comp_H;row++){\n\t\tfor(int col = 0; col < comp_W; col++){\n\t\t\ttable[row][col].right_wall = false;\n\t\t\ttable[row][col].under_wall = false;\n\t\t}\n\t}\n\n\t//外壁の情報を設定\n\n\t//上\n\tfor(int col = 0; col < comp_W; col++){\n\t\ttable[1][col].under_wall = true;\n\t}\n\n\t//左\n\tfor(int row = 0; row < comp_H; row++){\n\t\ttable[row][1].right_wall = true;\n\t}\n\n\t//下\n\tfor(int col = 0; col < comp_W; col++){\n\t\ttable[comp_H-2][col].under_wall = true;\n\t}\n\n\t//右\n\tfor(int row = 0; row < comp_H; row++){\n\t\ttable[row][comp_W-2].right_wall = true;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tif(wall[i].row1 == wall[i].row2){ //横線\n\n\t\t\tfor(int col = wall[i].col1+1; col <= wall[i].col2; col++){\n\t\t\t\ttable[wall[i].row1][col].under_wall = true;\n\t\t\t}\n\t\t}else{ //縦線\n\n\t\t\tfor(int row = wall[i].row1+1; row <= wall[i].row2; row++){\n\t\t\t\ttable[row][wall[i].col1].right_wall = true;\n\t\t\t}\n\t\t}\n\t}\n\n\tpriority_queue<State> Q;\n\tint adj_row,adj_col,next_cost,add_cost;\n\n\tfor(int i = 0; i < num_query; i++){\n\t\tfor(int row = 0; row < comp_H; row++){\n\t\t\tfor(int col = 0; col < comp_W; col++)min_cost[row][col] = BIG_NUM;\n\t\t}\n\n\t\twhile(!Q.empty())Q.pop();\n\n\t\tmin_cost[query[i].row1][query[i].col1] = 0;\n\t\tQ.push(State(query[i].row1,query[i].col1,0));\n\n\t\twhile(!Q.empty()){\n\t\t\tif(Q.top().row == query[i].row2 && Q.top().col == query[i].col2){\n\t\t\t\tprintf(\"%d\\n\",Q.top().sum_cost);\n\t\t\t\tbreak;\n\t\t\t}else if(Q.top().sum_cost > min_cost[Q.top().row][Q.top().col]){\n\t\t\t\tQ.pop();\n\t\t\t}else{\n\n\t\t\t\tfor(int i = 0; i < 4; i++){\n\t\t\t\t\tadj_row = Q.top().row+diff_row[i];\n\t\t\t\t\tadj_col = Q.top().col+diff_col[i];\n\n\t\t\t\t\tif(!rangeCheck(adj_row,adj_col))continue;\n\n\t\t\t\t\tadd_cost = 0;\n\t\t\t\t\tswitch(i){\n\t\t\t\t\tcase 0: //上\n\t\t\t\t\t\tif(table[adj_row][adj_col].under_wall)add_cost++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 1: //左\n\t\t\t\t\t\tif(table[adj_row][adj_col].right_wall)add_cost++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 2: //右\n\t\t\t\t\t\tif(table[Q.top().row][Q.top().col].right_wall)add_cost++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 3: //下\n\t\t\t\t\t\tif(table[Q.top().row][Q.top().col].under_wall)add_cost++;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\n\t\t\t\t\tnext_cost = Q.top().sum_cost+add_cost;\n\t\t\t\t\tif(min_cost[adj_row][adj_col] > next_cost){\n\t\t\t\t\t\tmin_cost[adj_row][adj_col] = next_cost;\n\t\t\t\t\t\tQ.push(State(adj_row,adj_col,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tQ.pop();\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 4416, "score_of_the_acc": -0.5653, "final_rank": 9 }, { "submission_id": "aoj_0292_2669153", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\nusing namespace std;\n\nint H, W, N, Q, px[109], py[109], qx[109], qy[109], sx[109], sy[109], gx[109], gy[109], dist[10009];\nvector<int>X, Y; bool wall[1009][1009]; int col[1009][1009], cntw; vector<int>G[10009]; map<pair<int, int>, int>M;\n\nvoid dfs(int cx, int cy) {\n\tcol[cx][cy] = cntw;\n\tint dx[4] = { -1,0,1,0 }, dy[4] = { 0,1,0,-1 };\n\tfor (int i = 0; i < 4; i++) {\n\t\tint fx = cx + dx[i], fy = cy + dy[i];\n\t\tif (fx < 0 || fy < 0 || fx >= X.size() || fy >= Y.size() || wall[fx][fy] == true || col[fx][fy] >= 1) continue;\n\t\tdfs(fx, fy);\n\t}\n}\nint solve(int cx, int cy) {\n\tfor (int i = 0; i < 10009; i++)dist[i] = 9999999;\n\tqueue<int>q; q.push(cx); dist[cx] = 0;\n\twhile (!q.empty()) {\n\t\tint to1 = q.front(); q.pop();\n\t\tfor (int i : G[to1]) {\n\t\t\tif (dist[i] > dist[to1] + 1) {\n\t\t\t\tdist[i] = dist[to1] + 1; q.push(i);\n\t\t\t}\n\t\t}\n\t}\n\treturn dist[cy];\n}\n\nint main() {\n\tcin >> H >> W >> N;\n\tfor (int i = 1; i <= N; i++) cin >> px[i] >> py[i] >> qx[i] >> qy[i];\n\tcin >> Q;\n\tfor (int i = 1; i <= Q; i++) cin >> sx[i] >> sy[i] >> gx[i] >> gy[i];\n\tfor (int i = 1; i <= N; i++) {\n\t\tpx[i] *= 2; py[i] *= 2; qx[i] *= 2; qy[i] *= 2;\n\t\tif (px[i] > qx[i]) swap(px[i], qx[i]); if (py[i] > qy[i]) swap(py[i], qy[i]);\n\t\tif (px[i] >= 1) X.push_back(px[i] - 1); X.push_back(px[i]); if (px[i] < H * 2) X.push_back(px[i] + 1);\n\t\tif (qx[i] >= 1) X.push_back(qx[i] - 1); X.push_back(qx[i]); if (qx[i] < H * 2) X.push_back(qx[i] + 1);\n\t\tif (py[i] >= 1) Y.push_back(py[i] - 1); Y.push_back(py[i]); if (py[i] < W * 2) Y.push_back(py[i] + 1);\n\t\tif (py[i] >= 1) Y.push_back(qy[i] - 1); Y.push_back(qy[i]); if (qy[i] < W * 2) Y.push_back(qy[i] + 1);\n\t}\n\tfor (int i = 1; i <= Q; i++) {\n\t\tsx[i] *= 2; sy[i] *= 2; gx[i] *= 2; gy[i] *= 2;\n\t\tX.push_back(sx[i]); Y.push_back(sy[i]);\n\t\tX.push_back(gx[i]); Y.push_back(gy[i]);\n\t}\n\tX.push_back(0); Y.push_back(0); X.push_back(H * 2); Y.push_back(W * 2);\n\tsort(X.begin(), X.end()); X.erase(unique(X.begin(), X.end()), X.end());\n\tsort(Y.begin(), Y.end()); Y.erase(unique(Y.begin(), Y.end()), Y.end());\n\tfor (int i = 1; i <= N; i++) {\n\t\tpx[i] = lower_bound(X.begin(), X.end(), px[i]) - X.begin();\n\t\tqx[i] = lower_bound(X.begin(), X.end(), qx[i]) - X.begin();\n\t\tpy[i] = lower_bound(Y.begin(), Y.end(), py[i]) - Y.begin();\n\t\tqy[i] = lower_bound(Y.begin(), Y.end(), qy[i]) - Y.begin();\n\t\tif (px[i] == qx[i]) {\n\t\t\tfor (int j = py[i]; j <= qy[i]; j++) wall[px[i]][j] = true;\n\t\t}\n\t\tif (py[i] == qy[i]) {\n\t\t\tfor (int j = px[i]; j <= qx[i]; j++) wall[j][py[i]] = true;\n\t\t}\n\t}\n\tfor (int i = 0; i < Y.size(); i++) wall[0][i] = true;\n\tfor (int i = 0; i < Y.size(); i++) wall[X.size() - 1][i] = true;\n\tfor (int i = 0; i < X.size(); i++) wall[i][0] = true;\n\tfor (int i = 0; i < X.size(); i++) wall[i][Y.size() - 1] = true;\n\tfor (int i = 1; i <= Q; i++) {\n\t\tsx[i] = lower_bound(X.begin(), X.end(), sx[i]) - X.begin();\n\t\tgx[i] = lower_bound(X.begin(), X.end(), gx[i]) - X.begin();\n\t\tsy[i] = lower_bound(Y.begin(), Y.end(), sy[i]) - Y.begin();\n\t\tgy[i] = lower_bound(Y.begin(), Y.end(), gy[i]) - Y.begin();\n\t}\n\tfor (int i = 0; i < X.size(); i++) {\n\t\tfor (int j = 0; j < Y.size(); j++) {\n\t\t\tif (wall[i][j] == true || col[i][j] >= 1) continue;\n\t\t\tcntw++; dfs(i, j);\n\t\t}\n\t}\n\tfor (int i = 0; i < (int)X.size(); i++) {\n\t\tfor (int j = 0; j < (int)Y.size() - 2; j++) {\n\t\t\tif (wall[i][j] == false && wall[i][j + 1] == true && wall[i][j + 2] == false && col[i][j] != col[i][j + 2]) {\n\t\t\t\tint d1 = col[i][j], d2 = col[i][j + 2];\n\t\t\t\tif (M[make_pair(d1, d2)] == 1) continue;\n\t\t\t\tM[make_pair(d1, d2)] = 1; G[d1].push_back(d2);\n\t\t\t\tM[make_pair(d2, d1)] = 1; G[d2].push_back(d1);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < (int)Y.size(); i++) {\n\t\tfor (int j = 0; j < (int)X.size() - 2; j++) {\n\t\t\tif (wall[j][i] == false && wall[j + 1][i] == true && wall[j + 2][i] == false && col[j][i] != col[j + 2][i]) {\n\t\t\t\tint d1 = col[j][i], d2 = col[j + 2][i];\n\t\t\t\tif (M[make_pair(d1, d2)] == 1) continue;\n\t\t\t\tM[make_pair(d1, d2)] = 1; G[d1].push_back(d2);\n\t\t\t\tM[make_pair(d2, d1)] = 1; G[d2].push_back(d1);\n\t\t\t}\n\t\t}\n\t}\n\t/*for (int i = 0; i < X.size(); i++) {\n\t\tfor (int j = 0; j < Y.size(); j++) cout << (int)wall[i][j] << \" \"; cout << endl;\n\t}\n\tcout << endl;\n\tfor (int i = 0; i < X.size(); i++) {\n\t\tfor (int j = 0; j < Y.size(); j++) cout << col[i][j] << \" \"; cout << endl;\n\t}*/\n\tfor (int i = 1; i <= Q; i++) {\n\t\tcout << solve(col[sx[i]][sy[i]], col[gx[i]][gy[i]]) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11560, "score_of_the_acc": -0.6091, "final_rank": 10 }, { "submission_id": "aoj_0292_2549679", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#define mp make_pair\n#define int long long\n#define INF 1e+9\nusing namespace std;\n\ntypedef pair<int,int> POS;\ntypedef pair<int,POS> P;\nint dx[] = {0,1,0,-1},dy[] = {-1,0,1,0};\n\nsigned main(){\n\tint w,h,m,q,px[100],py[100],qx[100],qy[100];\n\tbool ng[210][210][4] = {};\n\tvector<int> xs,ys;\n\tcin >> w >> h >> m;\n\tfor(int i = 0;i < m;i++){\n\t\tcin >> px[i] >> py[i] >> qx[i] >> qy[i];\n\t\tif(px[i] > qx[i]) swap(px[i],qx[i]);\n\t\tif(py[i] > qy[i]) swap(py[i],qy[i]);\n\t\txs.push_back(px[i]);\n\t\tys.push_back(py[i]);\n\t\txs.push_back(qx[i]);\n\t\tys.push_back(qy[i]);\n\t}\n\txs.push_back(0);\n\txs.push_back(w);\n\tys.push_back(0);\n\tys.push_back(h);\n\tsort(xs.begin(),xs.end());\n\tsort(ys.begin(),ys.end());\n\txs.erase(unique(xs.begin(),xs.end()),xs.end());\n\tys.erase(unique(ys.begin(),ys.end()),ys.end());\n\tfor(int i = 0;i < xs.size() - 1;i++){\n\t\tfor(int j = 0;j < ys.size() - 1;j++){\n\t\t\tfor(int k = 0;k < m;k++){\n\t\t\t\tif(px[k] <= xs[i] && xs[i + 1] <= qx[k]){\n\t\t\t\t\tif(ys[j] == py[k]) ng[i][j][0] = true;\n\t\t\t\t\telse if(ys[j + 1] == py[k]) ng[i][j][2] = true;\n\t\t\t\t}else if(py[k] <= ys[j] && ys[j + 1] <= qy[k]){\n\t\t\t\t\tif(xs[i] == px[k]) ng[i][j][3] = true;\n\t\t\t\t\telse if(xs[i + 1] == px[k]) ng[i][j][1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcin >> q;\n\tfor(int i = 0;i < q;i++){\n\t\tint sx,sy,gx,gy,x1,y1,x2,y2,d[210][210];\n\t\tcin >> sx >> sy >> gx >> gy;\n\t\tfor(int j = 0;j <= 200;j++){\n\t\t\tfor(int k = 0;k <= 200;k++) d[j][k] = INF;\n\t\t}\n\t\tfor(int j = 0;j < xs.size() - 1;j++){\n\t\t\tif(xs[j] <= sx && sx <= xs[j + 1]) x1 = j;\n\t\t\tif(xs[j] <= gx && gx <= xs[j + 1]) x2 = j;\n\t\t}\n\t\tfor(int j = 0;j < ys.size() - 1;j++){\n\t\t\tif(ys[j] <= sy && sy <= ys[j + 1]) y1 = j;\n\t\t\tif(ys[j] <= gy && gy <= ys[j + 1]) y2 = j;\n\t\t}\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(mp(0,mp(x1,y1)));\n\t\td[x1][y1] = 0;\n\t\twhile(!que.empty()){\n\t\t\tP p = que.top();que.pop();\n\t\t\tint x = p.second.first,y = p.second.second;\n\t\t\tfor(int j = 0;j < 4;j++){\n\t\t\t\tint nx = x + dx[j],ny = y + dy[j];\n\t\t\t\tif(nx >= 0 && nx < xs.size() - 1 && ny >= 0 && ny < ys.size() - 1 && d[nx][ny] > d[x][y] + ng[x][y][j]){\n\t\t\t\t\td[nx][ny] = d[x][y] + ng[x][y][j];\n\t\t\t\t\tque.push(mp(d[nx][ny],mp(nx,ny)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << d[x2][y2] << endl;\n\t}\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3760, "score_of_the_acc": -0.2506, "final_rank": 6 }, { "submission_id": "aoj_0292_2549674", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#define mp make_pair\n#define int long long\n#define INF 1e+9\nusing namespace std;\n\ntypedef pair<int,int> POS;\ntypedef pair<int,POS> P;\nint dx[] = {0,1,0,-1},dy[] = {-1,0,1,0};\n\nsigned main(){\n\tint w,h,m,q,px[100],py[100],qx[100],qy[100];\n\tbool ng[200][200][4] = {};\n\tvector<int> xs,ys;\n\tcin >> w >> h >> m;\n\tfor(int i = 0;i < m;i++){\n\t\tcin >> px[i] >> py[i] >> qx[i] >> qy[i];\n\t\tif(px[i] > qx[i]) swap(px[i],qx[i]);\n\t\tif(py[i] > qy[i]) swap(py[i],qy[i]);\n\t\txs.push_back(px[i]);\n\t\tys.push_back(py[i]);\n\t\txs.push_back(qx[i]);\n\t\tys.push_back(qy[i]);\n\t}\n\txs.push_back(0);\n\txs.push_back(w);\n\tys.push_back(0);\n\tys.push_back(h);\n\tsort(xs.begin(),xs.end());\n\tsort(ys.begin(),ys.end());\n\txs.erase(unique(xs.begin(),xs.end()),xs.end());\n\tys.erase(unique(ys.begin(),ys.end()),ys.end());\n\tfor(int i = 0;i < xs.size() - 1;i++){\n\t\tfor(int j = 0;j < ys.size() - 1;j++){\n\t\t\tfor(int k = 0;k < m;k++){\n\t\t\t\tif(px[k] <= xs[i] && xs[i + 1] <= qx[k]){\n\t\t\t\t\tif(ys[j] == py[k]) ng[i][j][0] = true;\n\t\t\t\t\telse if(ys[j + 1] == py[k]) ng[i][j][2] = true;\n\t\t\t\t}else if(py[k] <= ys[j] && ys[j + 1] <= qy[k]){\n\t\t\t\t\tif(xs[i] == px[k]) ng[i][j][3] = true;\n\t\t\t\t\telse if(xs[i + 1] == px[k]) ng[i][j][1] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcin >> q;\n\tfor(int i = 0;i < q;i++){\n\t\tint sx,sy,gx,gy,x1,y1,x2,y2,d[110][110];\n\t\tcin >> sx >> sy >> gx >> gy;\n\t\tfor(int j = 0;j < xs.size();j++){\n\t\t\tfor(int k = 0;k < ys.size();k++) d[j][k] = INF;\n\t\t}\n\t\tfor(int j = 0;j < xs.size() - 1;j++){\n\t\t\tif(xs[j] <= sx && sx <= xs[j + 1]) x1 = j;\n\t\t\tif(xs[j] <= gx && gx <= xs[j + 1]) x2 = j;\n\t\t}\n\t\tfor(int j = 0;j < ys.size() - 1;j++){\n\t\t\tif(ys[j] <= sy && sy <= ys[j + 1]) y1 = j;\n\t\t\tif(ys[j] <= gy && gy <= ys[j + 1]) y2 = j;\n\t\t}\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(mp(0,mp(x1,y1)));\n\t\td[x1][y1] = 0;\n\t\twhile(!que.empty()){\n\t\t\tP p = que.top();que.pop();\n\t\t\tint x = p.second.first,y = p.second.second;\n\t\t\tfor(int j = 0;j < 4;j++){\n\t\t\t\tint nx = x + dx[j],ny = y + dy[j];\n\t\t\t\tif(nx >= 0 && nx < xs.size() - 1 && ny >= 0 && ny < ys.size() - 1 && d[nx][ny] > d[x][y] + ng[x][y][j]){\n\t\t\t\t\td[nx][ny] = d[x][y] + ng[x][y][j];\n\t\t\t\t\tque.push(mp(d[nx][ny],mp(nx,ny)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << d[x2][y2] << endl;\n\t}\n}", "accuracy": 0.42857142857142855, "time_ms": 150, "memory_kb": 3412, "score_of_the_acc": -0.1984, "final_rank": 17 }, { "submission_id": "aoj_0292_2508566", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,a) FOR(i,0,a)\ntypedef vector<int> vec;\ntypedef pair<int,int> P;\nint dx[4]={1,0,-1,0},dy[4]={0,1,0,-1};\nconst int MAX_M=100,MAX_Q=100,MAX_V=MAX_M*6;\nint W,H,M,Q;\nint px[MAX_M],py[MAX_M],qx[MAX_M],qy[MAX_M];\nint sx[MAX_Q],sy[MAX_Q],gx[MAX_Q],gy[MAX_Q];\n\nbool grid[(MAX_M+MAX_Q)*6][(MAX_M+MAX_Q)*6];\nint grid2[(MAX_M+MAX_Q)*6][(MAX_M+MAX_Q)*6];\n\nint V;\nint G[MAX_V][MAX_V];\nint dist[MAX_V];\n\nvoid compress(int *x1,int *x2,int *x3,int *x4,int &w){\n vec v;\n REP(i,M){\n REP(j,3){\n int x=*(x1+i)+j-1;\n if (x>=0 && x<=w){\n v.push_back(x);\n }\n x=*(x2+i)+j-1;\n if (x>=0 && x<=w){\n v.push_back(x);\n }\n }\n }\n REP(i,Q){\n v.push_back(*(x3+i));\n v.push_back(*(x4+i));\n }\n sort(v.begin(),v.end());\n v.erase(unique(v.begin(),v.end()),v.end());\n REP(i,M){\n *(x1+i)=find(v.begin(),v.end(),*(x1+i))-v.begin();\n *(x2+i)=find(v.begin(),v.end(),*(x2+i))-v.begin();\n }\n REP(i,Q){\n *(x3+i)=find(v.begin(),v.end(),*(x3+i))-v.begin();\n *(x4+i)=find(v.begin(),v.end(),*(x4+i))-v.begin();\n }\n w=v.size();\n}\n\nvoid bfs(int s){\n queue<int> q;\n memset(dist,-1,sizeof(dist));\n dist[s]=0;\n q.push(s);\n while(!q.empty()){\n int v=q.front();\n q.pop();\n REP(i,V){\n if (G[v][i] && dist[i]==-1){\n dist[i]=dist[v]+1;\n q.push(i);\n }\n }\n }\n}\n\nvoid bfs2(int x,int y){\n queue<P> q;\n q.push(P(x,y));\n grid2[x][y]=V;\n while(!q.empty()){\n P p=q.front();\n q.pop();\n REP(i,4){\n int x2=p.first+dx[i],y2=p.second+dy[i];\n if (x2<0 || x2>=W || y2<0 || y2>=H) continue;\n if (!grid[x2][y2] && grid2[x2][y2]==-1){\n grid2[x2][y2]=V;\n q.push(P(x2,y2));\n }\n }\n }\n}\n\nint main(){\n scanf(\"%d %d %d\",&W,&H,&M);\n W*=2;\n H*=2;\n REP(i,M){\n scanf(\"%d %d %d %d\",&px[i],&py[i],&qx[i],&qy[i]);\n if (px[i]>qx[i]){\n swap(px[i],qx[i]);\n }\n if (py[i]>qy[i]){\n swap(py[i],qy[i]);\n }\n px[i]*=2;\n py[i]*=2;\n qx[i]*=2;\n qy[i]*=2;\n }\n scanf(\"%d\",&Q);\n REP(i,Q){\n scanf(\"%d %d %d %d\",&sx[i],&sy[i],&gx[i],&gy[i]);\n sx[i]*=2;\n sy[i]*=2;\n gx[i]*=2;\n gy[i]*=2;\n }\n compress(px,qx,sx,gx,W);\n compress(py,qy,sy,gy,H);\n REP(i,M){\n FOR(j,px[i],qx[i]+1){\n FOR(k,py[i],qy[i]+1){\n grid[j][k]=true;\n }\n }\n }\n memset(grid2,-1,sizeof(grid2));\n REP(x,W){\n REP(y,H){\n if (!grid[x][y] && grid2[x][y]==-1){\n bfs2(x,y);\n V++;\n }\n }\n }\n REP(x,W){\n REP(y,H){\n if (grid[x][y]){\n int x2,y2,x3,y3;\n int v,u;\n x2=x-1;\n x3=x+1;\n if (x2>=0 && x3<W && !grid[x2][y] && !grid[x3][y]){\n v=grid2[x2][y];\n u=grid2[x3][y];\n G[v][u]=G[u][v]=1;\n }\n y2=y-1;\n y3=y+1;\n if (y2>=0 && y3<H && !grid[x][y2] && !grid[x][y3]){\n v=grid2[x][y2];\n u=grid2[x][y3];\n G[v][u]=G[u][v]=1;\n }\n }\n }\n }\n REP(i,Q){\n bfs(grid2[sx[i]][sy[i]]);\n printf(\"%d\\n\",dist[grid2[gx[i]][gy[i]]]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10352, "score_of_the_acc": -0.5339, "final_rank": 7 }, { "submission_id": "aoj_0292_2059457", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\n#define pb push_back\n#define fi first\n#define sc second\ntypedef long long int ll;\nll W,H;\nint M;\nll px[114];ll py[114];ll qx[114];ll qy[114];\nvector<ll> x,y;\nint Q;\nint grid[701][701];\nint s[500001];\nint dx[4]={-1,0,0,1};\nint dy[4]={0,-1,1,0};\nint sx1,sy1,gx1,gy1;\nint WW,HH;\nvector<int>G[500001];\nmap<P,int> MAP;\n/*\nint dfs(int x1,int y1){\n\tf[x1][y1]=true;\n\tfor(int k=0;k<4;k++){\n\t\tif(x1+dx[k]>=0&&x1+dx[k]<WW&&y1+dy[k]>=0&&y1+dy[k]<HH){\n\t\t\tif(!f[x1+dx[k]][y1+dy[k]])s[x1+dx[k]][y1+dy[k]]=min(s[x1][y1],dfs(x1+dx[k],y1+dy[k]));\n\t\t}\n\t}\n\tif(grid[x1][y1])s[x1][y1]++;\n\tprintf(\"%d %d %d\\n\",x1,y1,s[x1][y1]);\n\treturn s[x1][y1];\n}*/\nint main()\n{\n\tscanf(\"%lld%lld%d\",&W,&H,&M);W*=10;H*=10;\n\tx.pb(0);x.pb(W);\n\ty.pb(0);y.pb(H);\n\tfor(int i=0;i<M;i++){\n\t\tscanf(\"%lld%lld%lld%lld\",&px[i],&py[i],&qx[i],&qy[i]);\n\t\tpx[i]*=10;py[i]*=10;qx[i]*=10;qy[i]*=10;\n\t\tif(px[i]!=0){\n\t\t\tx.pb(px[i]-1);\n\t\t}\n\t\tx.pb(px[i]);\n\t\tif(px[i]!=W){\n\t\t\tx.pb(px[i]+1);\n\t\t}\n\t\t\n\t\tif(qx[i]!=0){\n\t\t\tx.pb(qx[i]-1);\n\t\t}\n\t\tx.pb(qx[i]);\n\t\tif(qx[i]!=W){\n\t\t\tx.pb(qx[i]+1);\n\t\t}\n\t\t\n\t\tif(py[i]!=0){\n\t\t\ty.pb(py[i]-1);\n\t\t}\n\t\ty.pb(py[i]);\n\t\tif(py[i]!=H){\n\t\t\ty.pb(py[i]+1);\n\t\t}\n\t\t\n\t\tif(qy[i]!=0){\n\t\t\ty.pb(qy[i]-1);\n\t\t}\n\t\ty.pb(qy[i]);\n\t\tif(qy[i]!=H){\n\t\t\ty.pb(qy[i]+1);\n\t\t}\n\t\t\n\t}\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.erase(unique(x.begin(),x.end()),x.end());\n\ty.erase(unique(y.begin(),y.end()),y.end());\n\t\n\tWW=(int)x.size();HH=(int)y.size();\n\tfor(int i=0;i<M;i++){\n\t\tint ax=lower_bound(x.begin(),x.end(),px[i])-x.begin();\n\t\tint bx=lower_bound(x.begin(),x.end(),qx[i])-x.begin();\n\t\tint ay=lower_bound(y.begin(),y.end(),py[i])-y.begin();\n\t\tint by=lower_bound(y.begin(),y.end(),qy[i])-y.begin();\n\t\tif(ax>=bx)swap(ax,bx);\n\t\tif(ay>=by)swap(ay,by);\n\t\tfor(int j=ax;j<=bx;j++){\n\t\t\tfor(int k=ay;k<=by;k++){\n\t\t\t\tgrid[j][k]=-1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint index=1;\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==0){\n\t\t\t\tqueue<P> que;\n\t\t\t\tque.push(P(i,j));\n\t\t\t\twhile(!que.empty()){\n\t\t\t\t\tP p=que.front();que.pop();\n\t\t\t\t\tif(grid[p.fi][p.sc]==index)continue;\n\t\t\t\t\tgrid[p.fi][p.sc]=index;\n\t\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\t\tif(p.fi+dx[k]>=0&&p.fi+dx[k]<WW&&p.sc+dy[k]>=0&&p.sc+dy[k]<HH){\n\t\t\t\t\t\t\tif(grid[p.fi+dx[k]][p.sc+dy[k]]==0){\n\t\t\t\t\t\t\t\tque.push(P(p.fi+dx[k],p.sc+dy[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tindex++;\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tfor(int i=0;i<HH;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tprintf(\"%d \",grid[j][i]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}*/\n\t\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==-1){\n\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\tif(i+dx[k]>=0&&i-dx[k]>=0&&i+dx[k]<WW&&i-dx[k]<WW){\n\t\t\t\t\t\tif(j+dy[k]>=0&&j-dy[k]>=0&&j+dy[k]<HH&&j-dy[k]<HH){\n\t\t\t\t\t\t\t//printf(\"%d %d\\n\",i,j);\n\t\t\t\t\t\t\tint g1=grid[i+dx[k]][j+dy[k]];\n\t\t\t\t\t\t\tint g2=grid[i-dx[k]][j-dy[k]];\n\t\t\t\t\t\t\tif(g1!=-1&&g2!=-1&&MAP[P(g1,g2)]==0&&g1!=g2){\n\t\t\t\t\t\t\t\tG[g1-1].pb(g2-1);\n\t\t\t\t\t\t\t\tG[g2-1].pb(g1-1);\n\t\t\t\t\t\t\t\tMAP[P(g1,g2)]=1;\n\t\t\t\t\t\t\t\tMAP[P(g2,g1)]=1;\n\t\t\t\t\t\t\t\t//printf(\"%d %d\\n\",g1,g2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tscanf(\"%d\",&Q);\n\tfor(int i=0;i<Q;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tfor(int k=0;k<HH;k++){\n\t\t\t\ts[j*HH+k]=2*(WW+HH)+1;\n\t\t\t\t//ds[j][k]=2*(WW+HH)+1;\n\t\t\t\t//f[j][k]=false;\n\t\t\t}\n\t\t}\n\t\tll sx,sy,gx,gy;\n\t\tscanf(\"%lld%lld%lld%lld\",&sx,&sy,&gx,&gy);\n\t\tsx*=10;sy*=10;gx*=10;gy*=10;\n\t\t\n\t\tsx1=lower_bound(x.begin(),x.end(),sx)-x.begin();\n\t\tgx1=lower_bound(x.begin(),x.end(),gx)-x.begin();\n\t\tsy1=lower_bound(y.begin(),y.end(),sy)-y.begin();\n\t\tgy1=lower_bound(y.begin(),y.end(),gy)-y.begin();\n\t\t\n\t\t//printf(\"%d:%d-%d:%d\\n\",sx1,sy1,gx1,gy1);\n\t\tint ss=grid[sx1][sy1]-1;\n\t\tint gg=grid[gx1][gy1]-1;\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(make_pair(0,ss));\n\t\t//printf(\"%d %d\\n\",ss,gg);\n\t\t//printf(\"%d %d\\n\",sx1,sy1);\n\t\t//int n=0;\n\t\t\n\t\twhile(!que.empty()){\n\t\t\tP p=que.top();que.pop();\n\t\t\tif(p.fi>=s[p.sc])continue;\n\t\t\t//printf(\"%d %d\\n\",p.sc.fi,p.sc.sc);\n\t\t\ts[p.sc]=p.fi;\n\t\t\tfor(int j=0;j<(int)G[p.sc].size();j++){\n\t\t\t\tif(p.fi+1<s[G[p.sc][j]]){\n\t\t\t\t\tque.push(P(p.fi+1,G[p.sc][j]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"%d\\n\",n);\n\t\tprintf(\"%d\\n\",s[gg]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 16892, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0292_2059456", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\n#define pb push_back\n#define fi first\n#define sc second\ntypedef long long int ll;\nll W,H;\nint M;\nll px[114];ll py[114];ll qx[114];ll qy[114];\nvector<ll> x,y;\nint Q;\nint grid[701][701];\nint s[500001];\nint dx[4]={-1,0,0,1};\nint dy[4]={0,-1,1,0};\nint sx1,sy1,gx1,gy1;\nint WW,HH;\nvector<int>G[500001];\nmap<P,int> MAP;\n/*\nint dfs(int x1,int y1){\n\tf[x1][y1]=true;\n\tfor(int k=0;k<4;k++){\n\t\tif(x1+dx[k]>=0&&x1+dx[k]<WW&&y1+dy[k]>=0&&y1+dy[k]<HH){\n\t\t\tif(!f[x1+dx[k]][y1+dy[k]])s[x1+dx[k]][y1+dy[k]]=min(s[x1][y1],dfs(x1+dx[k],y1+dy[k]));\n\t\t}\n\t}\n\tif(grid[x1][y1])s[x1][y1]++;\n\tprintf(\"%d %d %d\\n\",x1,y1,s[x1][y1]);\n\treturn s[x1][y1];\n}*/\nint main()\n{\n\tscanf(\"%lld%lld%d\",&W,&H,&M);W*=10;H*=10;\n\tx.pb(0);x.pb(W);\n\ty.pb(0);y.pb(H);\n\tfor(int i=0;i<M;i++){\n\t\tscanf(\"%lld%lld%lld%lld\",&px[i],&py[i],&qx[i],&qy[i]);\n\t\tpx[i]*=10;py[i]*=10;qx[i]*=10;qy[i]*=10;\n\t\tif(px[i]!=0){\n\t\t\tx.pb(px[i]-1);\n\t\t}\n\t\tx.pb(px[i]);\n\t\tif(px[i]!=W){\n\t\t\tx.pb(px[i]+1);\n\t\t}\n\t\t\n\t\tif(qx[i]!=0){\n\t\t\tx.pb(qx[i]-1);\n\t\t}\n\t\tx.pb(qx[i]);\n\t\tif(qx[i]!=W){\n\t\t\tx.pb(qx[i]+1);\n\t\t}\n\t\t\n\t\tif(py[i]!=0){\n\t\t\ty.pb(py[i]-1);\n\t\t}\n\t\ty.pb(py[i]);\n\t\tif(py[i]!=H){\n\t\t\ty.pb(py[i]+1);\n\t\t}\n\t\t\n\t\tif(qy[i]!=0){\n\t\t\ty.pb(qy[i]-1);\n\t\t}\n\t\ty.pb(qy[i]);\n\t\tif(qy[i]!=H){\n\t\t\ty.pb(qy[i]+1);\n\t\t}\n\t\t\n\t}\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.erase(unique(x.begin(),x.end()),x.end());\n\ty.erase(unique(y.begin(),y.end()),y.end());\n\t\n\tWW=(int)x.size();HH=(int)y.size();\n\tfor(int i=0;i<M;i++){\n\t\tint ax=lower_bound(x.begin(),x.end(),px[i])-x.begin();\n\t\tint bx=lower_bound(x.begin(),x.end(),qx[i])-x.begin();\n\t\tint ay=lower_bound(y.begin(),y.end(),py[i])-y.begin();\n\t\tint by=lower_bound(y.begin(),y.end(),qy[i])-y.begin();\n\t\t//if(ax>=bx)swap(ax,bx);\n\t\t//if(ay>=by)swap(ay,by);\n\t\tfor(int j=ax;j<=bx;j++){\n\t\t\tfor(int k=ay;k<=by;k++){\n\t\t\t\tgrid[j][k]=-1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint index=1;\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==0){\n\t\t\t\tqueue<P> que;\n\t\t\t\tque.push(P(i,j));\n\t\t\t\twhile(!que.empty()){\n\t\t\t\t\tP p=que.front();que.pop();\n\t\t\t\t\tif(grid[p.fi][p.sc]==index)continue;\n\t\t\t\t\tgrid[p.fi][p.sc]=index;\n\t\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\t\tif(p.fi+dx[k]>=0&&p.fi+dx[k]<WW&&p.sc+dy[k]>=0&&p.sc+dy[k]<HH){\n\t\t\t\t\t\t\tif(grid[p.fi+dx[k]][p.sc+dy[k]]==0){\n\t\t\t\t\t\t\t\tque.push(P(p.fi+dx[k],p.sc+dy[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tindex++;\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tfor(int i=0;i<HH;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tprintf(\"%d \",grid[j][i]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}*/\n\t\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==-1){\n\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\tif(i+dx[k]>=0&&i-dx[k]>=0&&i+dx[k]<WW&&i-dx[k]<WW){\n\t\t\t\t\t\tif(j+dy[k]>=0&&j-dy[k]>=0&&j+dy[k]<HH&&j-dy[k]<HH){\n\t\t\t\t\t\t\t//printf(\"%d %d\\n\",i,j);\n\t\t\t\t\t\t\tint g1=grid[i+dx[k]][j+dy[k]];\n\t\t\t\t\t\t\tint g2=grid[i-dx[k]][j-dy[k]];\n\t\t\t\t\t\t\tif(g1!=-1&&g2!=-1&&MAP[P(g1,g2)]==0&&g1!=g2){\n\t\t\t\t\t\t\t\tG[g1-1].pb(g2-1);\n\t\t\t\t\t\t\t\tG[g2-1].pb(g1-1);\n\t\t\t\t\t\t\t\tMAP[P(g1,g2)]=1;\n\t\t\t\t\t\t\t\tMAP[P(g2,g1)]=1;\n\t\t\t\t\t\t\t\t//printf(\"%d %d\\n\",g1,g2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tscanf(\"%d\",&Q);\n\tfor(int i=0;i<Q;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tfor(int k=0;k<HH;k++){\n\t\t\t\ts[j*HH+k]=2*(WW+HH)+1;\n\t\t\t\t//ds[j][k]=2*(WW+HH)+1;\n\t\t\t\t//f[j][k]=false;\n\t\t\t}\n\t\t}\n\t\tll sx,sy,gx,gy;\n\t\tscanf(\"%lld%lld%lld%lld\",&sx,&sy,&gx,&gy);\n\t\tsx*=10;sy*=10;gx*=10;gy*=10;\n\t\t\n\t\tsx1=lower_bound(x.begin(),x.end(),sx)-x.begin();\n\t\tgx1=lower_bound(x.begin(),x.end(),gx)-x.begin();\n\t\tsy1=lower_bound(y.begin(),y.end(),sy)-y.begin();\n\t\tgy1=lower_bound(y.begin(),y.end(),gy)-y.begin();\n\t\t\n\t\t//printf(\"%d:%d-%d:%d\\n\",sx1,sy1,gx1,gy1);\n\t\tint ss=grid[sx1][sy1]-1;\n\t\tint gg=grid[gx1][gy1]-1;\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(make_pair(0,ss));\n\t\t//printf(\"%d %d\\n\",ss,gg);\n\t\t//printf(\"%d %d\\n\",sx1,sy1);\n\t\t//int n=0;\n\t\t\n\t\twhile(!que.empty()){\n\t\t\tP p=que.top();que.pop();\n\t\t\tif(p.fi>=s[p.sc])continue;\n\t\t\t//printf(\"%d %d\\n\",p.sc.fi,p.sc.sc);\n\t\t\ts[p.sc]=p.fi;\n\t\t\tfor(int j=0;j<(int)G[p.sc].size();j++){\n\t\t\t\tif(p.fi+1<s[G[p.sc][j]]){\n\t\t\t\t\tque.push(P(p.fi+1,G[p.sc][j]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"%d\\n\",n);\n\t\tprintf(\"%d\\n\",s[gg]);\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 10, "memory_kb": 16584, "score_of_the_acc": -0.9774, "final_rank": 20 }, { "submission_id": "aoj_0292_2059453", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\n#define pb push_back\n#define fi first\n#define sc second\ntypedef long long int ll;\nll W,H;\nint M;\nll px[114];ll py[114];ll qx[114];ll qy[114];\nvector<ll> x,y;\nint Q;\nint grid[501][501];\nint s[250001];\nint dx[4]={-1,0,0,1};\nint dy[4]={0,-1,1,0};\nint sx1,sy1,gx1,gy1;\nint WW,HH;\nvector<int>G[250001];\nmap<P,int> MAP;\n/*\nint dfs(int x1,int y1){\n\tf[x1][y1]=true;\n\tfor(int k=0;k<4;k++){\n\t\tif(x1+dx[k]>=0&&x1+dx[k]<WW&&y1+dy[k]>=0&&y1+dy[k]<HH){\n\t\t\tif(!f[x1+dx[k]][y1+dy[k]])s[x1+dx[k]][y1+dy[k]]=min(s[x1][y1],dfs(x1+dx[k],y1+dy[k]));\n\t\t}\n\t}\n\tif(grid[x1][y1])s[x1][y1]++;\n\tprintf(\"%d %d %d\\n\",x1,y1,s[x1][y1]);\n\treturn s[x1][y1];\n}*/\nint main()\n{\n\tscanf(\"%lld%lld%d\",&W,&H,&M);W*=10;H*=10;\n\tx.pb(0);x.pb(W);\n\ty.pb(0);y.pb(H);\n\tfor(int i=0;i<M;i++){\n\t\tscanf(\"%lld%lld%lld%lld\",&px[i],&py[i],&qx[i],&qy[i]);\n\t\tpx[i]*=10;py[i]*=10;qx[i]*=10;qy[i]*=10;\n\t\tif(px[i]!=0){\n\t\t\tx.pb(px[i]-1);\n\t\t}\n\t\tx.pb(px[i]);\n\t\tif(px[i]!=W){\n\t\t\tx.pb(px[i]+1);\n\t\t}\n\t\t\n\t\tif(qx[i]!=0){\n\t\t\tx.pb(qx[i]-1);\n\t\t}\n\t\tx.pb(qx[i]);\n\t\tif(qx[i]!=W){\n\t\t\tx.pb(qx[i]+1);\n\t\t}\n\t\t\n\t\tif(py[i]!=0){\n\t\t\ty.pb(py[i]-1);\n\t\t}\n\t\ty.pb(py[i]);\n\t\tif(py[i]!=H){\n\t\t\ty.pb(py[i]+1);\n\t\t}\n\t\t\n\t\tif(qy[i]!=0){\n\t\t\ty.pb(qy[i]-1);\n\t\t}\n\t\ty.pb(qy[i]);\n\t\tif(qy[i]!=H){\n\t\t\ty.pb(qy[i]+1);\n\t\t}\n\t\t\n\t}\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.erase(unique(x.begin(),x.end()),x.end());\n\ty.erase(unique(y.begin(),y.end()),y.end());\n\t\n\tWW=(int)x.size();HH=(int)y.size();\n\tfor(int i=0;i<M;i++){\n\t\tint ax=lower_bound(x.begin(),x.end(),px[i])-x.begin();\n\t\tint bx=lower_bound(x.begin(),x.end(),qx[i])-x.begin();\n\t\tint ay=lower_bound(y.begin(),y.end(),py[i])-y.begin();\n\t\tint by=lower_bound(y.begin(),y.end(),qy[i])-y.begin();\n\t\tif(ax>=bx)swap(ax,bx);\n\t\tif(ay>=by)swap(ay,by);\n\t\tfor(int j=ax;j<=bx;j++){\n\t\t\tfor(int k=ay;k<=by;k++){\n\t\t\t\tgrid[j][k]=-1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint index=1;\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==0){\n\t\t\t\tqueue<P> que;\n\t\t\t\tque.push(P(i,j));\n\t\t\t\twhile(!que.empty()){\n\t\t\t\t\tP p=que.front();que.pop();\n\t\t\t\t\tif(grid[p.fi][p.sc]==index)continue;\n\t\t\t\t\tgrid[p.fi][p.sc]=index;\n\t\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\t\tif(p.fi+dx[k]>=0&&p.fi+dx[k]<WW&&p.sc+dy[k]>=0&&p.sc+dy[k]<HH){\n\t\t\t\t\t\t\tif(grid[p.fi+dx[k]][p.sc+dy[k]]==0){\n\t\t\t\t\t\t\t\tque.push(P(p.fi+dx[k],p.sc+dy[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tindex++;\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tfor(int i=0;i<HH;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tprintf(\"%d \",grid[j][i]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}*/\n\t\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==-1){\n\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\tif(i+dx[k]>=0&&i-dx[k]>=0&&i+dx[k]<WW&&i-dx[k]<WW){\n\t\t\t\t\t\tif(j+dy[k]>=0&&j-dy[k]>=0&&j+dy[k]<HH&&j-dy[k]<HH){\n\t\t\t\t\t\t\t//printf(\"%d %d\\n\",i,j);\n\t\t\t\t\t\t\tint g1=grid[i+dx[k]][j+dy[k]];\n\t\t\t\t\t\t\tint g2=grid[i-dx[k]][j-dy[k]];\n\t\t\t\t\t\t\tif(g1!=-1&&g2!=-1&&MAP[P(g1,g2)]==0&&g1!=g2){\n\t\t\t\t\t\t\t\tG[g1-1].pb(g2-1);\n\t\t\t\t\t\t\t\tG[g2-1].pb(g1-1);\n\t\t\t\t\t\t\t\tMAP[P(g1,g2)]=1;\n\t\t\t\t\t\t\t\tMAP[P(g2,g1)]=1;\n\t\t\t\t\t\t\t\t//printf(\"%d %d\\n\",g1,g2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tscanf(\"%d\",&Q);\n\tfor(int i=0;i<Q;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tfor(int k=0;k<HH;k++){\n\t\t\t\ts[j*HH+k]=100101001;\n\t\t\t\t//ds[j][k]=2*(WW+HH)+1;\n\t\t\t\t//f[j][k]=false;\n\t\t\t}\n\t\t}\n\t\tll sx,sy,gx,gy;\n\t\tscanf(\"%lld%lld%lld%lld\",&sx,&sy,&gx,&gy);\n\t\tsx*=10;sy*=10;gx*=10;gy*=10;\n\t\t\n\t\tsx1=lower_bound(x.begin(),x.end(),sx)-x.begin();\n\t\tgx1=lower_bound(x.begin(),x.end(),gx)-x.begin();\n\t\tsy1=lower_bound(y.begin(),y.end(),sy)-y.begin();\n\t\tgy1=lower_bound(y.begin(),y.end(),gy)-y.begin();\n\t\t\n\t\t//printf(\"%d:%d-%d:%d\\n\",sx1,sy1,gx1,gy1);\n\t\tint ss=grid[sx1][sy1]-1;\n\t\tint gg=grid[gx1][gy1]-1;\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(make_pair(0,ss));\n\t\t//printf(\"%d %d\\n\",ss,gg);\n\t\t//printf(\"%d %d\\n\",sx1,sy1);\n\t\t//int n=0;\n\t\t\n\t\twhile(!que.empty()){\n\t\t\tP p=que.top();que.pop();\n\t\t\tif(p.fi>=s[p.sc])continue;\n\t\t\t//printf(\"%d %d\\n\",p.sc.fi,p.sc.sc);\n\t\t\ts[p.sc]=p.fi;\n\t\t\tfor(int j=0;j<(int)G[p.sc].size();j++){\n\t\t\t\tif(p.fi+1<s[G[p.sc][j]]){\n\t\t\t\t\tque.push(P(p.fi+1,G[p.sc][j]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"%d\\n\",n);\n\t\tprintf(\"%d\\n\",s[gg]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10660, "score_of_the_acc": -0.5431, "final_rank": 8 }, { "submission_id": "aoj_0292_2059452", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\n#define pb push_back\n#define fi first\n#define sc second\ntypedef long long int ll;\nll W,H;\nint M;\nll px[114];ll py[114];ll qx[114];ll qy[114];\nvector<ll> x,y;\nint Q;\nint grid[401][401];\nint s[250001];\nint dx[4]={-1,0,0,1};\nint dy[4]={0,-1,1,0};\nint sx1,sy1,gx1,gy1;\nint WW,HH;\nvector<int>G[250001];\nmap<P,int> MAP;\n/*\nint dfs(int x1,int y1){\n\tf[x1][y1]=true;\n\tfor(int k=0;k<4;k++){\n\t\tif(x1+dx[k]>=0&&x1+dx[k]<WW&&y1+dy[k]>=0&&y1+dy[k]<HH){\n\t\t\tif(!f[x1+dx[k]][y1+dy[k]])s[x1+dx[k]][y1+dy[k]]=min(s[x1][y1],dfs(x1+dx[k],y1+dy[k]));\n\t\t}\n\t}\n\tif(grid[x1][y1])s[x1][y1]++;\n\tprintf(\"%d %d %d\\n\",x1,y1,s[x1][y1]);\n\treturn s[x1][y1];\n}*/\nint main()\n{\n\tscanf(\"%lld%lld%d\",&W,&H,&M);W*=10;H*=10;\n\tx.pb(0);x.pb(W);\n\ty.pb(0);y.pb(H);\n\tfor(int i=0;i<M;i++){\n\t\tscanf(\"%lld%lld%lld%lld\",&px[i],&py[i],&qx[i],&qy[i]);\n\t\tpx[i]*=10;py[i]*=10;qx[i]*=10;qy[i]*=10;\n\t\tif(px[i]!=0){\n\t\t\tx.pb(px[i]-1);\n\t\t}\n\t\tx.pb(px[i]);\n\t\tif(px[i]!=W){\n\t\t\tx.pb(px[i]+1);\n\t\t}\n\t\t\n\t\tif(qx[i]!=0){\n\t\t\tx.pb(qx[i]-1);\n\t\t}\n\t\tx.pb(qx[i]);\n\t\tif(qx[i]!=W){\n\t\t\tx.pb(qx[i]+1);\n\t\t}\n\t\t\n\t\tif(py[i]!=0){\n\t\t\ty.pb(py[i]-1);\n\t\t}\n\t\ty.pb(py[i]);\n\t\tif(py[i]!=H){\n\t\t\ty.pb(py[i]+1);\n\t\t}\n\t\t\n\t\tif(qy[i]!=0){\n\t\t\ty.pb(qy[i]-1);\n\t\t}\n\t\ty.pb(qy[i]);\n\t\tif(qy[i]!=H){\n\t\t\ty.pb(qy[i]+1);\n\t\t}\n\t\t\n\t}\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.erase(unique(x.begin(),x.end()),x.end());\n\ty.erase(unique(y.begin(),y.end()),y.end());\n\t\n\tWW=(int)x.size();HH=(int)y.size();\n\tfor(int i=0;i<M;i++){\n\t\tint ax=lower_bound(x.begin(),x.end(),px[i])-x.begin();\n\t\tint bx=lower_bound(x.begin(),x.end(),qx[i])-x.begin();\n\t\tint ay=lower_bound(y.begin(),y.end(),py[i])-y.begin();\n\t\tint by=lower_bound(y.begin(),y.end(),qy[i])-y.begin();\n\t\tif(ax>=bx)swap(ax,bx);\n\t\tif(ay>=by)swap(ay,by);\n\t\tfor(int j=ax;j<=bx;j++){\n\t\t\tfor(int k=ay;k<=by;k++){\n\t\t\t\tgrid[j][k]=-1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint index=1;\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==0){\n\t\t\t\tqueue<P> que;\n\t\t\t\tque.push(P(i,j));\n\t\t\t\twhile(!que.empty()){\n\t\t\t\t\tP p=que.front();que.pop();\n\t\t\t\t\tif(grid[p.fi][p.sc]==index)continue;\n\t\t\t\t\tgrid[p.fi][p.sc]=index;\n\t\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\t\tif(p.fi+dx[k]>=0&&p.fi+dx[k]<WW&&p.sc+dy[k]>=0&&p.sc+dy[k]<HH){\n\t\t\t\t\t\t\tif(grid[p.fi+dx[k]][p.sc+dy[k]]==0){\n\t\t\t\t\t\t\t\tque.push(P(p.fi+dx[k],p.sc+dy[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tindex++;\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tfor(int i=0;i<HH;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tprintf(\"%d \",grid[j][i]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}*/\n\t\n\tfor(int i=0;i<WW;i++){\n\t\tfor(int j=0;j<HH;j++){\n\t\t\tif(grid[i][j]==-1){\n\t\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\t\tif(i+dx[k]>=0&&i-dx[k]>=0&&i+dx[k]<WW&&i-dx[k]<WW){\n\t\t\t\t\t\tif(j+dy[k]>=0&&j-dy[k]>=0&&j+dy[k]<HH&&j-dy[k]<HH){\n\t\t\t\t\t\t\t//printf(\"%d %d\\n\",i,j);\n\t\t\t\t\t\t\tint g1=grid[i+dx[k]][j+dy[k]];\n\t\t\t\t\t\t\tint g2=grid[i-dx[k]][j-dy[k]];\n\t\t\t\t\t\t\tif(g1!=-1&&g2!=-1&&MAP[P(g1,g2)]==0&&g1!=g2){\n\t\t\t\t\t\t\t\tG[g1-1].pb(g2-1);\n\t\t\t\t\t\t\t\tG[g2-1].pb(g1-1);\n\t\t\t\t\t\t\t\tMAP[P(g1,g2)]=1;\n\t\t\t\t\t\t\t\tMAP[P(g2,g1)]=1;\n\t\t\t\t\t\t\t\t//printf(\"%d %d\\n\",g1,g2);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\tscanf(\"%d\",&Q);\n\tfor(int i=0;i<Q;i++){\n\t\tfor(int j=0;j<WW;j++){\n\t\t\tfor(int k=0;k<HH;k++){\n\t\t\t\ts[j*HH+k]=100101001;\n\t\t\t\t//ds[j][k]=2*(WW+HH)+1;\n\t\t\t\t//f[j][k]=false;\n\t\t\t}\n\t\t}\n\t\tll sx,sy,gx,gy;\n\t\tscanf(\"%lld%lld%lld%lld\",&sx,&sy,&gx,&gy);\n\t\tsx*=10;sy*=10;gx*=10;gy*=10;\n\t\t\n\t\tsx1=lower_bound(x.begin(),x.end(),sx)-x.begin();\n\t\tgx1=lower_bound(x.begin(),x.end(),gx)-x.begin();\n\t\tsy1=lower_bound(y.begin(),y.end(),sy)-y.begin();\n\t\tgy1=lower_bound(y.begin(),y.end(),gy)-y.begin();\n\t\t\n\t\t//printf(\"%d:%d-%d:%d\\n\",sx1,sy1,gx1,gy1);\n\t\tint ss=grid[sx1][sy1]-1;\n\t\tint gg=grid[gx1][gy1]-1;\n\t\tpriority_queue<P,vector<P>,greater<P> > que;\n\t\tque.push(make_pair(0,ss));\n\t\t//printf(\"%d %d\\n\",ss,gg);\n\t\t//printf(\"%d %d\\n\",sx1,sy1);\n\t\t//int n=0;\n\t\t\n\t\twhile(!que.empty()){\n\t\t\tP p=que.top();que.pop();\n\t\t\tif(p.fi>=s[p.sc])continue;\n\t\t\t//printf(\"%d %d\\n\",p.sc.fi,p.sc.sc);\n\t\t\ts[p.sc]=p.fi;\n\t\t\tfor(int j=0;j<(int)G[p.sc].size();j++){\n\t\t\t\tif(p.fi+1<s[G[p.sc][j]]){\n\t\t\t\t\tque.push(P(p.fi+1,G[p.sc][j]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//printf(\"%d\\n\",n);\n\t\tprintf(\"%d\\n\",s[gg]);\n\t}\n\treturn 0;\n}", "accuracy": 0.42857142857142855, "time_ms": 10, "memory_kb": 10372, "score_of_the_acc": -0.522, "final_rank": 19 } ]
aoj_0293_cpp
アルゴリズム検定試験 あなたはイズア地区におけるアルゴリズム検定試験を運営しており、運営費を最小にしたいと考えています。運営費は、会場使用料、バスの使用料、移動補助金の総和です。 今年は N 人の受験者登録があり、それぞれ c i 人まで受け入れ可能な M 個の会場を確保しました。あなたは各受験者を必ずどこかの会場に割り当てなければなりません。1 人以上割り当てた会場については、人数にかかわらず f i 円の会場使用料を支払う必要があります。 イズア地区は図に示すように東西方向と南北方向に 1 km 間隔で道が走っており、受験者の家と会場は交差点上にあると考えます。各受験者は家から会場まで道に沿って徒歩で移動できます。また、この検定試験では、1 人以上受験者を受け入れる各会場につき 1 台のシャトルバスが運行されるので、受験者はバスを利用することもできます。ただし、自分が受験する会場行きのバスにしか乗れません。 各シャトルバスは、会場からの東西方向の距離と南北方向の距離の和が D 以内のすべての交差点に停車します(図は D = 3 の場合)。バスの使用料は D に比例し、 D が 1 km 増えると B 円上がります。つまり、シャトルバスを運行するには 1 会場あたり D × B 円の費用を支払う必要があります。なお、 D 及び B はすべての会場で共通の値を用います。 移動補助金とは、各受験者に必要な最低限の徒歩での移動に対して運営者が受験者に支払う費用で、1 km について 1 円を払う必要があります。 あなたは受験者の家と会場の位置、会場の受け入れ可能人数と使用料、 D が 1 km 増えたときに加算される料金 B の情報を入力データとして持っており、各受験者への会場割り当てと D を決定することができます(ただし、 D は 0 以上の整数)。このとき、運営費の最小値を求めてください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ3つの行で示される。各データセットは以下の形式で与えられる。 N M B ax 1 ay 1 ax 2 ay 2 : ax N ay N bx 1 by 1 c 1 f 1 bx 2 by 2 c 2 f 2 : bx M by M c M f M 1 行目は3つの整数からなる。 N (1 ≤ N ≤ 100) は受験者の人数、 M (1 ≤ M ≤ 5) は会場数である。 B (0 ≤ B ≤ 1000) はシャトルバスを運行する際に、 D が 1 km 増えたときに加算される料金である。続く N 行に各受験者の家の座標が与えられる。 ax i , ay i (-1000 ≤ ax i , ay i ≤ 1000) はそれぞれ受験者 i の家の x 座標と y 座標を示す。続く M 行に各会場の情報が与えられる。 bx i , by i (-1000 ≤ bx i , by i ≤ 1000) はそれぞれ会場 i の x 座標と y 座標を示す。 c i (1 ≤ c i ≤ 100) は会場 i の受け入れ可能人数、 f i (0 ≤ f i ≤ 100000) は会場 i の使用料を示す。ただし、 c 1 から c M までの合計は N 以上である。 入力は以下の条件を満たすと考えてよい。 使用する会場を決めたとき、 D = i におけるそれらの会場への受験者の割り当て方のうち移動補助金が最小となるときの金額を F ( i ) とする。このとき、 F ( i +2) - F ( i +1) ≥ F ( i +1)- F ( i ) が成立する。 データセットの数は 10 を超えない。 出力 データセットごとに試験の運営費の最小値を 1 行に出力する。 入出力例 入力例 1 1 1 0 0 0 0 1 0 1 1 0 0 0 -3 0 2 3 1 3 1 0 0 -3 0 2 3 0 -5 2 0 4 0 2 1 4 3 1 0 0 0 0 0 0 0 0 -3 0 2 3 0 -5 2 0 4 0 2 1 6 3 1 0 0 0 0 0 0 0 0 0 0 0 0 -3 0 2 3 0 -5 2 0 4 0 2 1 6 3 2 0 0 0 0 0 0 0 0 0 0 0 0 -3 0 2 3 0 -5 2 0 4 0 2 1 10 5 1 0 0 2 0 4 0 8 0 100 0 100 0 100 0 100 0 100 0 100 0 -3 0 1 0 1 0 1 0 3 0 2 0 15 0 1 0 105 0 6 0 10 5 2 0 0 2 0 4 0 8 0 100 0 100 0 100 0 100 0 100 0 100 0 -3 0 1 0 1 0 1 0 3 0 2 0 15 0 1 0 105 0 6 0 0 0 0 出力例 0 3 5 11 18 28 20 38
[ { "submission_id": "aoj_0293_9263225", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\n\nstruct MCF {\nprivate:\n const long long inf = 1e18;\n vector<long long> dist; //最短距離(費用)\n vector<int> pv, pe; //直前の頂点、辺 \n\npublic:\n struct edge {\n int to, rev; long long cap, cost;\n edge(int t = 0, int r = 0, long long ca = 0, long long co = 0)\n : to(t), rev(r), cap(ca), cost(co) {}\n };\n\n struct pii {\n long long d; int v; //最短距離(費用)、頂点番号\n pii(long long d_ = 0, int v_ = 0) : d(d_), v(v_) {}\n\n bool operator<(const pii& other) const {\n if (d != other.d) return d < other.d;\n return v < other.v;\n }\n\n bool operator>(const pii& other) const {\n if (d != other.d) return d > other.d;\n return v > other.v;\n }\n };\n\n int n;\n vector<vector<edge>> to;\n vector<long long> pot; //ポテンシャル\n\n MCF(int n_ = 1) : n(n_), to(n_), pot(n_), dist(n_), pv(n_), pe(n_) {}\n\n void addedge(int u, int v, long long cap, long long cost) {\n int su = (int)to[u].size();\n int sv = (int)to[v].size();\n to[u].push_back({ v, sv, cap, cost });\n to[v].push_back({ u, su, 0, -cost });\n }\n\n //s->tへ流量fの最小費用流、流せないときは-1\n long long mincostflow(int s, int t, long long f) {\n long long res = 0;\n pot.assign(n, 0);\n while (f) {\n priority_queue<pii, vector<pii>, greater<pii>> pq;\n dist.assign(n, inf);\n dist[s] = 0;\n pq.push({ 0, s });\n while (!pq.empty()) {\n pii elem = pq.top();\n pq.pop();\n if (dist[elem.v] < elem.d) continue;\n int sv = (int)to[elem.v].size();\n for (int i = 0; i < sv; i++) {\n edge& nv = to[elem.v][i];\n if (nv.cap == 0 || dist[nv.to] + pot[nv.to] <= dist[elem.v] + pot[elem.v] + nv.cost) continue;\n dist[nv.to] = dist[elem.v] + pot[elem.v] - pot[nv.to] + nv.cost;\n pv[nv.to] = elem.v;\n pe[nv.to] = i;\n pq.push({ dist[nv.to], nv.to });\n }\n }\n\n if (dist[t] == inf) return -1; //流せる最小費用流が存在しない\n\n for (int v = 0; v < n; v++) pot[v] += dist[v];\n\n long long nf = f;\n for (int v = t; v != s; v = pv[v]) nf = min(nf, to[pv[v]][pe[v]].cap);\n f -= nf;\n res += nf * (pot[t] - pot[s]); //pot[s] = 0で不要だがポテンシャルを明確化する\n for (int v = t; v != s; v = pv[v]) {\n edge& nv = to[pv[v]][pe[v]];\n nv.cap -= nf;\n to[v][nv.rev].cap += nf;\n }\n }\n return res;\n }\n};\n\n\n\nint main()\n{\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n\n vi<ll> res;\n const ll inf = 1e18;\n int n, m, b;\n while (cin >> n >> m >> b, n) {\n vi<ll> ax(n), ay(n), bx(m), by(m), c(m), f(m);\n rep(i, n) cin >> ax[i] >> ay[i];\n rep(i, m) cin >> bx[i] >> by[i] >> c[i] >> f[i];\n\n ll ans = inf;\n auto dist = [&](int pa, int pb) {\n return abs(ax[pa] - bx[pb]) + abs(ay[pa] - by[pb]);\n };\n\n \n\n rep(bit, 1 << m) {\n ll ta = 0;\n int cnt = 0;\n int participants = 0;\n vi<int> dl;\n dl.push_back(0);\n rep(i, m) if(bit >> i & 1) rep(j, n) dl.push_back(dist(j, i));\n sort(dl.begin(), dl.end());\n dl.erase(unique(dl.begin(), dl.end()), dl.end());\n\n\n rep(i, m) if (bit >> i & 1) {\n ta += f[i];\n participants += c[i];\n cnt++;\n }\n if (ans <= ta) continue; //暫定解が既に会場使用料より安い\n if (participants < n) continue; //会場人数が受験者より少ない\n\n ll pf = inf;\n int sz = (int)dl.size();\n int ok = -1, ng = sz;\n\n auto df = [&](int d) {\n MCF mcf(m + n + 2);\n int S = m + n, T = m + n + 1;\n\n rep(i, m) if (bit >> i & 1) {\n mcf.addedge(S, i, c[i], 0);\n rep(j, n) {\n mcf.addedge(i, j + m, 1, max(0LL, dist(j, i) - d));\n }\n }\n rep(j, n) mcf.addedge(j + m, T, 1, 0);\n return mcf.mincostflow(S, T, n) + d * b * cnt;\n };\n \n while (ok + 2 < ng) {\n int lc = (2 * ok + ng) / 3, rc = (ok + 2 * ng) / 3;\n ll fl = df(dl[lc]), fr = df(dl[rc]);\n if (fl < fr) ng = rc;\n else ok = lc;\n }\n ans = min(ans, ta + df(dl[(ok + ng) / 2]));\n\n }\n res.push_back(ans);\n }\n for (ll elem : res) cout << elem << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 6760, "memory_kb": 3468, "score_of_the_acc": -1.648, "final_rank": 15 }, { "submission_id": "aoj_0293_7521932", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tif (cap > 0) {\n\t\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\t\tif (min_dist[u] > n_dist) {\n\t\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn -1;\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, const vector<Pii>& a_info, const vector<Ti4>& b_info, int num_vertexes, int s, int t, int b, int d) {\n\tint m = int(b_info.size());\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_info) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_info[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_info[i].first;\n\t\tint ay = a_info[i].second;\n\t\tint a_idx = i + 1;\n\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_info[j]);\n\t\t\tint by = get<1>(b_info[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n);\n\treturn min_cost == -1 ? -1 : min_cost + bus_cost + site_cost;\n}\n\n\nint search_min_cost(int n, int b, const vector<Pii>& a_info, const vector<Ti4>& b_info) {\n\tint m = int(b_info.size());\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 4001;\n\tint min_cost = numeric_limits<int>::max();\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_info;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_info.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_info;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_info.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> combs = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : combs) {\n\t\t\t\tvector<Ti4> tmp_b_info;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_info.push_back(b_info[comb[j]]);\n\t\t\t\t}\n\n\t\t\t\tint cost = search_min_cost(n, b, a_info, tmp_b_info);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4240, "memory_kb": 3512, "score_of_the_acc": -1.436, "final_rank": 8 }, { "submission_id": "aoj_0293_7521925", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tif (cap > 0) {\n\t\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\t\tif (min_dist[u] > n_dist) {\n\t\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn -1;\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, const vector<Pii>& a_info, const vector<Ti4>& b_info, int num_vertexes, int s, int t, int b, int d) {\n\tint m = int(b_info.size());\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_info) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_info[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_info[i].first;\n\t\tint ay = a_info[i].second;\n\t\tint a_idx = i + 1;\n\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_info[j]);\n\t\t\tint by = get<1>(b_info[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n);\n\treturn min_cost == -1 ? -1 : min_cost + bus_cost + site_cost;\n}\n\n\nint search_min_cost(int n, int b, const vector<Pii>& a_info, const vector<Ti4>& b_info) {\n\tint m = int(b_info.size());\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 2001;\n\tint min_cost = numeric_limits<int>::max();\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_info;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_info.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_info;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_info.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> combs = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : combs) {\n\t\t\t\tvector<Ti4> tmp_b_info;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_info.push_back(b_info[comb[j]]);\n\t\t\t\t}\n\n\t\t\t\tint cost = search_min_cost(n, b, a_info, tmp_b_info);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.625, "time_ms": 4000, "memory_kb": 3436, "score_of_the_acc": -1.223, "final_rank": 18 }, { "submission_id": "aoj_0293_7521914", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tif (cap > 0) {\n\t\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\t\tif (min_dist[u] > n_dist) {\n\t\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn -1;\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, const vector<Pii>& a_info, const vector<Ti4>& b_info, int num_vertexes, int s, int t, int b, int d) {\n\tint m = int(b_info.size());\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_info) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_info[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_info[i].first;\n\t\tint ay = a_info[i].second;\n\t\tint a_idx = i + 1;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_info[j]);\n\t\t\tint by = get<1>(b_info[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n);\n\treturn min_cost == -1 ? -1 : min_cost + bus_cost + site_cost;\n}\n\n\nint search_min_cost(int n, int b, const vector<Pii>& a_info, const vector<Ti4>& b_info) {\n\tint m = int(b_info.size());\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 10000;\n\tint min_cost = numeric_limits<int>::max();\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_info;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_info.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_info;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_info.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> combs = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : combs) {\n\t\t\t\tvector<Ti4> tmp_b_info;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_info.push_back(b_info[comb[j]]);\n\t\t\t\t}\n\n\t\t\t\tint cost = search_min_cost(n, b, a_info, tmp_b_info);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4820, "memory_kb": 3516, "score_of_the_acc": -1.5188, "final_rank": 9 }, { "submission_id": "aoj_0293_7521902", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tif (cap > 0) {\n\t\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\t\tif (min_dist[u] > n_dist) {\n\t\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn numeric_limits<int>::max();\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, const vector<Pii>& a_info, const vector<Ti4>& b_info, int num_vertexes, int s, int t, int b, int d) {\n\tint m = int(b_info.size());\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_info) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_info[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_info[i].first;\n\t\tint ay = a_info[i].second;\n\t\tint a_idx = i + 1;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_info[j]);\n\t\t\tint by = get<1>(b_info[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n) + bus_cost + site_cost;\n\treturn min_cost;\n}\n\n\nint search_min_cost(int n, int b, const vector<Pii>& a_info, const vector<Ti4>& b_info) {\n\tint m = int(b_info.size());\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 10000;\n\tint min_cost = numeric_limits<int>::max();\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_info;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_info.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_info;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_info.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> combs = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : combs) {\n\t\t\t\tvector<Ti4> tmp_b_info;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_info.push_back(b_info[comb[j]]);\n\t\t\t\t}\n\n\t\t\t\tint cost = search_min_cost(n, b, a_info, tmp_b_info);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4890, "memory_kb": 3516, "score_of_the_acc": -1.5276, "final_rank": 10 }, { "submission_id": "aoj_0293_7521892", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\tif (cap > 0 && min_dist[u] > n_dist) {\n\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn numeric_limits<int>::max();\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, const vector<Pii>& a_info, const vector<Ti4>& b_info, int num_vertexes, int s, int t, int b, int d) {\n\tint m = int(b_info.size());\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_info) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_info[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_info[i].first;\n\t\tint ay = a_info[i].second;\n\t\tint a_idx = i + 1;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_info[j]);\n\t\t\tint by = get<1>(b_info[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n) + bus_cost + site_cost;\n\treturn min_cost;\n}\n\n\nint search_min_cost(int n, int b, const vector<Pii>& a_info, const vector<Ti4>& b_info) {\n\tint m = int(b_info.size());\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 10000;\n\tint min_cost = numeric_limits<int>::max();\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, a_info, b_info, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_info;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_info.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_info;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_info.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> combs = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : combs) {\n\t\t\t\tvector<Ti4> tmp_b_info;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_info.push_back(b_info[comb[j]]);\n\t\t\t\t}\n\n\t\t\t\tint cost = search_min_cost(n, b, a_info, tmp_b_info);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4960, "memory_kb": 3516, "score_of_the_acc": -1.5364, "final_rank": 11 }, { "submission_id": "aoj_0293_7521836", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\ntypedef pair<int, int> Pii;\ntypedef tuple<int, int, int, int> Ti4;\n\n\nclass MinCostFlow {\nprivate:\n\tclass Edge {\n\tpublic:\n\t\tint to;\n\t\tint cap;\n\t\tint cost;\n\t\tEdge* b_edge;\n\n\tpublic:\n\t\tEdge() : to(-1), cap(-1), cost(-1), b_edge(nullptr) {\n\t\t\treturn;\n\t\t}\n\n\t\tEdge(int to, int cap, int cost, Edge* b) : to(to), cap(cap), cost(cost), b_edge(b) {\n\t\t\treturn;\n\t\t}\n\n\t\t~Edge() {\n\t\t\treturn;\n\t\t}\n\t};\n\nprivate:\n\tint num_vertexes_;\n\tvector<vector<Edge*>> graph_;\n\npublic:\n\tMinCostFlow(int num_vertexes) : num_vertexes_(num_vertexes) {\n\t\tgraph_ = vector<vector<Edge*>>(num_vertexes);\n\t}\n\n\t~MinCostFlow() {\n\t\tfor (vector<Edge*>& edges : graph_) {\n\t\t\tfor (int i = 0; i < edges.size(); i++) {\n\t\t\t\tdelete edges[i];\n\t\t\t}\n\t\t}\n\t\treturn;\n\t}\n\n\tvoid add_edge(int from, int to, int cap, int cost) {\n\t\tEdge* f_edge = new Edge(to, cap, cost, nullptr);\n\t\tEdge* b_edge = new Edge(from, 0, -cost, nullptr);\n\n\t\tf_edge->b_edge = b_edge;\n\t\tb_edge->b_edge = f_edge;\n\n\t\tgraph_[from].push_back(f_edge);\n\t\tgraph_[to].push_back(b_edge);\n\t\treturn;\n\t}\n\n\tint calc_min_cost_flow(int s, int t, int f) {\n\t\tint min_cost = 0;\n\t\tvector<int> h(num_vertexes_, 0);\n\t\tvector<int> prev_v(num_vertexes_, -1);\n\t\tvector<Edge*> prev_e(num_vertexes_, nullptr);\n\n\t\twhile (f > 0) {\n\t\t\tvector<int> min_dist(num_vertexes_, numeric_limits<int>::max());\n\t\t\tpriority_queue<Pii, vector<Pii>, greater<Pii>> q;\n\n\t\t\tmin_dist[s] = 0;\n\t\t\tq.push({ 0, s });\n\t\t\twhile (!q.empty()) {\n\t\t\t\tPii e = q.top(); q.pop();\n\t\t\t\tint c_dist = e.first;\n\t\t\t\tint v = e.second;\n\n\t\t\t\tif (min_dist[v] < c_dist) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\tfor (Edge* edge : graph_[v]) {\n\t\t\t\t\tint u = edge->to;\n\t\t\t\t\tint cap = edge->cap;\n\t\t\t\t\tint cost = edge->cost;\n\t\t\t\t\tint n_dist = min_dist[v] + cost + h[v] - h[u];\n\t\t\t\t\tif (cap > 0 && min_dist[u] > n_dist) {\n\t\t\t\t\t\tmin_dist[u] = n_dist;\n\t\t\t\t\t\tprev_v[u] = v;\n\t\t\t\t\t\tprev_e[u] = edge;\n\t\t\t\t\t\tq.push({ min_dist[u], u });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (min_dist[t] == numeric_limits<int>::max()) {\n\t\t\t\treturn numeric_limits<int>::max();\n\t\t\t}\n\n\t\t\tfor (int v = 0; v < num_vertexes_; v++) {\n\t\t\t\th[v] += min_dist[v];\n\t\t\t}\n\n\t\t\tint d = f;\n\t\t\tint v = t;\n\t\t\twhile (v != s) {\n\t\t\t\td = min(d, prev_e[v]->cap);\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\n\t\t\tf -= d;\n\t\t\tmin_cost += d * h[t];\n\n\t\t\tv = t;\n\t\t\twhile (v != s) {\n\t\t\t\tEdge* b_edge = prev_e[v]->b_edge;\n\n\t\t\t\tprev_e[v]->cap -= d;\n\t\t\t\tb_edge->cap += d;\n\t\t\t\tv = prev_v[v];\n\t\t\t}\n\t\t}\n\t\treturn min_cost;\n\t}\n};\n\n\nint calc_min_cost(int n, int m, const vector<Pii>& a_list, const vector<Ti4>& b_list, int num_vertexes, int s, int t, int b, int d) {\n\tMinCostFlow mcf(num_vertexes);\n\tint bus_cost = d * b * m;\n\tint site_cost = 0;\n\n\tfor (const Ti4 b : b_list) {\n\t\tsite_cost += get<3>(b);\n\t}\n\t\n\tfor (int i = 1; i <= n; i++) {\n\t\tmcf.add_edge(s, i, 1, 0);\n\t}\n\tfor (int i = 0; i < m; i++) {\n\t\tint c = get<2>(b_list[i]);\n\n\t\tmcf.add_edge(n + 1 + i, t, c, 0);\n\t}\n\n\tfor (int i = 0; i < n; i++) {\n\t\tint ax = a_list[i].first;\n\t\tint ay = a_list[i].second;\n\t\tint a_idx = i + 1;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tint bx = get<0>(b_list[j]);\n\t\t\tint by = get<1>(b_list[j]);\n\t\t\tint b_idx = n + 1 + j;\n\t\t\tint dist = abs(bx - ax) + abs(by - ay);\n\t\t\t\n\t\t\tdist = max(dist - d, 0);\n\t\t\tmcf.add_edge(a_idx, b_idx, 1, dist);\n\t\t}\n\t}\n\n\tint min_cost = mcf.calc_min_cost_flow(s, t, n) + bus_cost + site_cost;\n\treturn min_cost;\n}\n\n\nint search_min_cost(int n, int m, int b, const vector<Pii>& a_list, const vector<Ti4>& b_list) {\n\tint num_vertexes = n + m + 2;\n\tint s = 0;\n\tint t = n + m + 1;\n\tint left = 0;\n\tint right = 10000;\n\tint min_cost = numeric_limits<int>::max();\n\n\t//for (int i = 0; i < 1001; i++) {\n\t//\tint cost = calc_min_cost(n, m, a_list, b_list, num_vertexes, s, t, b, i);\n\t//\tmin_cost = min(min_cost, cost);\n\t//}\n\n\twhile (right - left > 1) {\n\t\tint mid = (left + right) / 2;\n\t\tint cost0 = calc_min_cost(n, m, a_list, b_list, num_vertexes, s, t, b, mid + 1);\n\t\tint cost1 = calc_min_cost(n, m, a_list, b_list, num_vertexes, s, t, b, mid);\n\t\tif (cost0 > cost1) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid;\n\t\t}\n\t}\n\n\tint l_cost = calc_min_cost(n, m, a_list, b_list, num_vertexes, s, t, b, left);\n\tint r_cost = calc_min_cost(n, m, a_list, b_list, num_vertexes, s, t, b, right);\n\n\tmin_cost = min(l_cost, r_cost);\n\treturn min_cost;\n}\n\n\nvector<vector<int>> calc_combinations(int n, int m) {\n\tvector<int> init_comb(m, -1);\n\tvector<vector<int>> result;\n\tvector<pair<int, vector<int>>> stack;\n\t\n\tstack.push_back({ 0, init_comb });\n\twhile (!stack.empty()) {\n\t\tauto e = stack.back(); stack.pop_back();\n\t\tint c_idx = e.first;\n\t\tvector<int> c_comb = e.second;\n\t\tint n_min = c_idx == 0 ? 0 : c_comb[c_idx - 1] + 1;\n\t\tint n_idx = c_idx + 1;\n\t\t\n\t\tfor (int i = n - 1; i >= n_min; i--) {\n\t\t//for (int i = n_min; i < n; i++) {\n\t\t\tvector<int> n_comb = c_comb;\n\t\t\t\n\t\t\tn_comb[c_idx] = i;\n\t\t\tif (n_idx < m) {\n\t\t\t\tstack.push_back({ n_idx, n_comb });\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresult.push_back(n_comb);\n\t\t\t}\n\t\t}\n\t}\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\twhile (true) {\n\t\tint n = -1;\n\t\tint m = -1;\n\t\tint b = -1;\n\n\t\tcin >> n >> m >> b;\n\t\tif (n == 0 && m == 0 && b == 0) {\n\t\t\tbreak;\n\t\t}\n\n\t\tvector<Pii> a_list;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tint x = 0;\n\t\t\tint y = 0;\n\n\t\t\tcin >> x >> y;\n\t\t\ta_list.push_back({ x, y });\n\t\t}\n\n\t\tvector<Ti4> b_list;\n\t\tfor (int i = 0; i < m; i++) {\n\t\t\tTi4 e;\n\n\t\t\tcin >> get<0>(e) >> get<1>(e) >> get<2>(e) >> get<3>(e);\n\t\t\tb_list.push_back(e);\n\t\t}\n\n\t\tint min_cost = numeric_limits<int>::max();\n\t\tfor (int i = 1; i <= m; i++) {\n\t\t\tvector<vector<int>> b_idx_lists = calc_combinations(m, i);\n\n\t\t\tfor (vector<int>& comb : b_idx_lists) {\n\t\t\t\t//cout << comb[0];\n\t\t\t\t//for (int j = 1; j < i; j++) {\n\t\t\t\t//\tcout << \" \" << comb[j];\n\t\t\t\t//}\n\t\t\t\t//cout << endl;\n\t\t\t\tvector<Ti4> tmp_b_list;\n\t\t\t\tfor (int j = 0; j < i; j++) {\n\t\t\t\t\ttmp_b_list.push_back(b_list[comb[j]]);\n\t\t\t\t}\n\t\t\t\tint cost = search_min_cost(n, tmp_b_list.size(), b, a_list, tmp_b_list);\n\t\t\t\tif (cost >= 0) {\n\t\t\t\t\tmin_cost = min(min_cost, cost);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcout << min_cost << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 5100, "memory_kb": 3552, "score_of_the_acc": -1.6406, "final_rank": 14 }, { "submission_id": "aoj_0293_7222239", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <queue>\n#include <algorithm>\nusing namespace std;\n\nstruct Edge {\n\tint to, cap, cost, rev;\n};\n\nclass MincostFlow {\n\tpublic:\n\tint size_ = 1;\n\tvector<vector<Edge>> G;\n\tvector<int> Potential;\n\tvector<int> Dist;\n\tvector<int> Prev_Verts;\n\tvector<int> Prev_ID;\n\tvector<bool> Used;\n\t\n\tvoid init(int sz) {\n\t\tsize_ = sz;\n\t\tG.resize(size_ + 2, vector<Edge>{});\n\t\tPotential.resize(size_ + 2, 0);\n\t\tDist.resize(size_ + 2, 0);\n\t\tPrev_Verts.resize(size_ + 2, 0);\n\t\tPrev_ID.resize(size_ + 2, 0);\n\t\tUsed.resize(size_ + 2, false);\n\t}\n\t\n\tvoid add_edge(int u, int v, int f, int c) {\n\t\t//cout << u << \" \" << v << \" \" << f << \" \" << c << endl;\n\t\tG[u].push_back(Edge{v, f, c, (int)G[v].size()});\n\t\tG[v].push_back(Edge{u, 0, -c, (int)G[u].size()-1});\n\t}\n\t\n\tint mincost_flow(int s, int t, int f) {\n\t\tint total_cost = 0;\n\t\tfor (int i = 0; i < size_; i++) Potential[i] = 0;\n\t\t\n\t\twhile (f >= 1) {\n\t\t\t// Initialize\n\t\t\tfor (int i = 0; i < size_; i++) Dist[i] = (1 << 30);\n\t\t\tfor (int i = 0; i < size_; i++) Prev_Verts[i] = 0;\n\t\t\tfor (int i = 0; i < size_; i++) Prev_ID[i] = 0;\n\t\t\tfor (int i = 0; i < size_; i++) Used[i] = false;\n\t\t\t\n\t\t\t// Dijkstra (Init)\n\t\t\tpriority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> Q;\n\t\t\tQ.push(make_pair(0, s)); Dist[s] = 0;\n\t\t\t\n\t\t\t// Dijkstra\n\t\t\twhile (!Q.empty()) {\n\t\t\t\tint pos = Q.top().second; Q.pop();\n\t\t\t\tif (Used[pos] == true) continue;\n\t\t\t\tUsed[pos] = true;\n\t\t\t\tfor (int i = 0; i < (int)G[pos].size(); i++) {\n\t\t\t\t\tif (G[pos][i].cap == 0) continue;\n\t\t\t\t\tint to = G[pos][i].to;\n\t\t\t\t\tint cost = G[pos][i].cost + Potential[pos] - Potential[to];\n\t\t\t\t\tif (Dist[to] > Dist[pos] + cost) {\n\t\t\t\t\t\tDist[to] = Dist[pos] + cost;\n\t\t\t\t\t\tPrev_Verts[to] = pos;\n\t\t\t\t\t\tPrev_ID[to] = i;\n\t\t\t\t\t\tQ.push(make_pair(Dist[to], to));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (Dist[t] == (1 << 30)) return -1;\n\t\t\t\n\t\t\t// Update Path\n\t\t\tint cx = t, min_cap = f;\n\t\t\twhile (cx != s) {\n\t\t\t\tint nex_cx = Prev_Verts[cx];\n\t\t\t\tint nex_id = Prev_ID[cx];\n\t\t\t\tmin_cap = min(min_cap, G[nex_cx][nex_id].cap);\n\t\t\t\tcx = nex_cx;\n\t\t\t}\n\t\t\ttotal_cost += min_cap * (Dist[t] + Potential[t] - Potential[s]);\n\t\t\tf -= min_cap;\n\t\t\t\n\t\t\t// Update Path 2\n\t\t\tcx = t;\n\t\t\twhile (cx != s) {\n\t\t\t\tint nex_cx = Prev_Verts[cx];\n\t\t\t\tint nex_id = Prev_ID[cx];\n\t\t\t\tG[nex_cx][nex_id].cap -= min_cap;\n\t\t\t\tG[G[nex_cx][nex_id].to][G[nex_cx][nex_id].rev].cap += min_cap;\n\t\t\t\tcx = nex_cx;\n\t\t\t}\n\t\t\t\n\t\t\t// Update Potential\n\t\t\tfor (int i = 0; i < size_; i++) Potential[i] += Dist[i];\n\t\t}\n\t\t\n\t\t// Return\n\t\treturn total_cost;\n\t}\n};\n\nint N, AX[1009], AY[1009];\nint M, BX[1009], BY[1009], C[1009], F[1009];\nint B;\n\nint GetMin(int mask, int border) {\n\tMincostFlow Z; Z.init(N + M + 10);\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < M; j++) {\n\t\t\tif ((mask / (1 << j)) % 2 == 0) continue;\n\t\t\tint dst = abs(AX[i] - BX[j]) + abs(AY[i] - BY[j]);\n\t\t\tdst = max(0, dst - border);\n\t\t\tZ.add_edge(i, N + j, 1, dst);\n\t\t}\n\t}\n\t\n\t// Get Initial Cost\n\tint InitCost = 0;\n\tfor (int i = 0; i < M; i++) {\n\t\tif ((mask / (1 << i)) % 2 == 0) continue;\n\t\tInitCost += border * B + F[i];\n\t\tZ.add_edge(N + i, N + M + 1, C[i], 0);\n\t}\n\tfor (int i = 0; i < N; i++) Z.add_edge(N + M, i, 1, 0);\n\t\n\t// Return\n\tint val = Z.mincost_flow(N + M, N + M + 1, N);\n\tif (val == -1) return (1 << 30);\n\treturn val + InitCost;\n}\n\nint solve() {\n\tint Answer = (1 << 30);\n\tfor (int i = 1; i < (1 << M); i++) {\n\t\tint cl = 0, cr = 4009, cm;\n\t\tfor (int j = 0; j < 15; j++) {\n\t\t\tcm = (cl + cr) / 2;\n\t\t\tint val1 = GetMin(i, cm);\n\t\t\tint val2 = GetMin(i, cm + 1);\n\t\t\tif (val1 > val2) { cl = cm; }\n\t\t\telse { cr = cm; }\n\t\t\tAnswer = min({Answer, val1, val2});\n\t\t}\n\t}\n\treturn Answer;\n}\n\nint main() {\n\twhile (true) {\n\t\t// Input\n\t\tcin >> N >> M >> B; if (N + M + B == 0) break;\n\t\tfor (int i = 0; i < N; i++) cin >> AX[i] >> AY[i];\n\t\tfor (int i = 0; i < M; i++) cin >> BX[i] >> BY[i] >> C[i] >> F[i];\n\t\t\n\t\t// Solve\n\t\tcout << solve() << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 5340, "memory_kb": 3528, "score_of_the_acc": -1.6132, "final_rank": 12 }, { "submission_id": "aoj_0293_7220479", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nstruct Edge {\n\tlong long to, cap, cost, rev;\n};\n\nclass MincostFlow {\n\tpublic:\n\tint size_ = 0;\n\tvector<vector<Edge>> G;\n\tvector<long long> Potential;\n\tvector<long long> Dist;\n\tvector<long long> Prev_Verts;\n\tvector<long long> Prev_ID;\n\tvector<bool> Used;\n\t\n\tvoid Initialize(int sz) {\n\t\tsize_ = sz + 2;\n\t\tG.resize(size_, vector<Edge>{});\n\t\tPotential.resize(size_, 0);\n\t\tDist.resize(size_, 0);\n\t\tPrev_Verts.resize(size_, 0);\n\t\tPrev_ID.resize(size_, 0);\n\t\tUsed.resize(size_, false);\n\t}\n\t\n\tvoid add_edge(long long u, long long v, long long f, long long c) {\n\t\t//cout << \"(u, v) = (\" << u << \", \" << v << \"), cap = \" << f << \", cost = \" << c << endl;\n\t\tG[u].push_back(Edge{ v, f, c, (int)G[v].size() });\n\t\tG[v].push_back(Edge{ u, 0LL, -c, (int)G[u].size() - 1 });\n\t}\n\t\n\tlong long mincost_flow(int s, int t, int f) {\n\t\tlong long current_ans = 0;\n\t\tfor (int i = 0; i < size_; i++) Potential[i] = 0;\n\t\t\n\t\t// Loop Phase\n\t\twhile (f > 0) {\n\t\t\tpriority_queue<pair<long long, int>, vector<pair<long long, int>>, greater<pair<long long, int>>> Q;\n\t\t\tfor (int i = 0; i < size_; i++) Dist[i] = (1LL << 60);\n\t\t\tfor (int i = 0; i < size_; i++) Prev_Verts[i] = -1;\n\t\t\tfor (int i = 0; i < size_; i++) Prev_ID[i] = -1;\n\t\t\tfor (int i = 0; i < size_; i++) Used[i] = false;\n\t\t\tDist[s] = 0;\n\t\t\tQ.push(make_pair(0, s));\n\t\t\t\n\t\t\t// Dijkstra\n\t\t\twhile (!Q.empty()) {\n\t\t\t\tlong long pos = Q.top().second; Q.pop();\n\t\t\t\tif (Used[pos] == true) continue;\n\t\t\t\tUsed[pos] = true;\n\t\t\t\tfor (int i = 0; i < (int)G[pos].size(); i++) {\n\t\t\t\t\tif (G[pos][i].cap == 0) continue;\n\t\t\t\t\tlong long nex = G[pos][i].to;\n\t\t\t\t\tlong long dst = G[pos][i].cost + Potential[pos] - Potential[nex];\n\t\t\t\t\tif (Dist[nex] > Dist[pos] + dst) {\n\t\t\t\t\t\tDist[nex] = Dist[pos] + dst;\n\t\t\t\t\t\tPrev_Verts[nex] = pos;\n\t\t\t\t\t\tPrev_ID[nex] = i;\n\t\t\t\t\t\tQ.push(make_pair(Dist[nex], nex));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (Dist[t] == (1LL << 60)) return -1LL;\n\t\t\t\n\t\t\t// Refresh Edges [Part 1]\n\t\t\tlong long current_pos = t;\n\t\t\tlong long current_min = f;\n\t\t\twhile (current_pos != s) {\n\t\t\t\tint nex = Prev_Verts[current_pos];\n\t\t\t\tint idx = Prev_ID[current_pos];\n\t\t\t\tcurrent_min = min(current_min, G[nex][idx].cap);\n\t\t\t\tcurrent_pos = nex;\n\t\t\t}\n\t\t\tcurrent_ans += 1LL * current_min * (Dist[t] + Potential[t] - Potential[s]);\n\t\t\tf -= current_min;\n\t\t\t\n\t\t\t// Refresh Edges [Part 2]\n\t\t\tcurrent_pos = t;\n\t\t\twhile (current_pos != s) {\n\t\t\t\tint nex = Prev_Verts[current_pos];\n\t\t\t\tint idx = Prev_ID[current_pos];\n\t\t\t\tG[nex][idx].cap -= current_min;\n\t\t\t\tG[G[nex][idx].to][G[nex][idx].rev].cap += current_min;\n\t\t\t\tcurrent_pos = nex;\n\t\t\t}\n\t\t\t\n\t\t\t// Refresh Potential\n\t\t\tfor (int i = 0; i < size_; i++) {\n\t\t\t\tif (Dist[i] != (1LL << 60)) Potential[i] += Dist[i];\n\t\t\t}\n\t\t}\n\t\t\n\t\t// Return\n\t\treturn current_ans;\n\t}\n};\n\nint N, X[1009], Y[1009];\nint M, A[1009], B[1009], C[1009], F[1009];\nint Bus;\n\nint solve(int Mask, int Border) {\n\tMincostFlow Z; Z.Initialize(N + M + 10);\n\tint Total_Cost = 0;\n\t\n\t// Add Edges\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < M; j++) {\n\t\t\tif ((Mask / (1 << j)) % 2 == 0) continue;\n\t\t\tint cost = max(0, abs(A[j] - X[i]) + abs(B[j] - Y[i]) - Border);\n\t\t\tZ.add_edge(i, N + j, 1, cost);\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) Z.add_edge(N + M + 0, i, 1, 0);\n\tfor (int i = 0; i < M; i++) {\n\t\tif ((Mask / (1 << i)) % 2 == 0) continue;\n\t\tZ.add_edge(N + i, N + M + 1, C[i], 0);\n\t\tTotal_Cost += F[i] + Border * Bus;\n\t}\n\t\n\t// Return\n\tint val = Z.mincost_flow(N + M, N + M + 1, N);\n\tif (val == -1) return 2000000000;\n\treturn Total_Cost + val;\n}\n\nint main() {\n\twhile (true) {\n\t\t// Input\n\t\tcin >> N >> M >> Bus; if (N + M + Bus == 0) break;\n\t\tfor (int i = 0; i < N; i++) cin >> X[i] >> Y[i];\n\t\tfor (int i = 0; i < M; i++) cin >> A[i] >> B[i] >> C[i] >> F[i];\n\t\t\n\t\t// Brute Force\n\t\tint Answer = (1 << 30);\n\t\tfor (int i = 1; i < (1 << M); i++) {\n\t\t\tint cl = 0, cr = 4022, cm;\n\t\t\tfor (int j = 0; j < 15; j++) {\n\t\t\t\tcm = (cl + cr) / 2;\n\t\t\t\tint val1 = solve(i, cm + 0);\n\t\t\t\tint val2 = solve(i, cm + 1);\n\t\t\t\tif (val1 > val2) { cl = cm; }\n\t\t\t\telse { cr = cm; }\n\t\t\t\tAnswer = min(Answer, val1);\n\t\t\t\tAnswer = min(Answer, val2);\n\t\t\t\t//cout << i << \" \" << cm << \" \" << val1 << \" \" << val2 << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t\t// Output\n\t\tcout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 5820, "memory_kb": 3508, "score_of_the_acc": -1.6256, "final_rank": 13 }, { "submission_id": "aoj_0293_7220474", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nstruct Edge {\n\tlong long to, cap, cost, rev;\n};\n\nclass MincostFlow {\n\tpublic:\n\tint size_ = 0;\n\tvector<vector<Edge>> G;\n\tvector<long long> Potential;\n\tvector<long long> Dist;\n\tvector<long long> Prev_Verts;\n\tvector<long long> Prev_ID;\n\tvector<bool> Used;\n\t\n\tvoid Initialize(int sz) {\n\t\tsize_ = sz + 2;\n\t\tG.resize(size_, vector<Edge>{});\n\t\tPotential.resize(size_, 0);\n\t\tDist.resize(size_, 0);\n\t\tPrev_Verts.resize(size_, 0);\n\t\tPrev_ID.resize(size_, 0);\n\t\tUsed.resize(size_, false);\n\t}\n\t\n\tvoid add_edge(long long u, long long v, long long f, long long c) {\n\t\t//cout << \"(u, v) = (\" << u << \", \" << v << \"), cap = \" << f << \", cost = \" << c << endl;\n\t\tG[u].push_back(Edge{ v, f, c, (int)G[v].size() });\n\t\tG[v].push_back(Edge{ u, 0LL, -c, (int)G[u].size() - 1 });\n\t}\n\t\n\tlong long mincost_flow(int s, int t, int f) {\n\t\tlong long current_ans = 0;\n\t\tfor (int i = 0; i < size_; i++) Potential[i] = 0;\n\t\t\n\t\t// Loop Phase\n\t\twhile (f > 0) {\n\t\t\tpriority_queue<pair<long long, int>, vector<pair<long long, int>>, greater<pair<long long, int>>> Q;\n\t\t\tfor (int i = 0; i < size_; i++) Dist[i] = (1LL << 60);\n\t\t\tfor (int i = 0; i < size_; i++) Prev_Verts[i] = -1;\n\t\t\tfor (int i = 0; i < size_; i++) Prev_ID[i] = -1;\n\t\t\tfor (int i = 0; i < size_; i++) Used[i] = false;\n\t\t\tDist[s] = 0;\n\t\t\tQ.push(make_pair(0, s));\n\t\t\t\n\t\t\t// Dijkstra\n\t\t\twhile (!Q.empty()) {\n\t\t\t\tlong long pos = Q.top().second; Q.pop();\n\t\t\t\tif (Used[pos] == true) continue;\n\t\t\t\tUsed[pos] = true;\n\t\t\t\tfor (int i = 0; i < (int)G[pos].size(); i++) {\n\t\t\t\t\tif (G[pos][i].cap == 0) continue;\n\t\t\t\t\tlong long nex = G[pos][i].to;\n\t\t\t\t\tlong long dst = G[pos][i].cost + Potential[pos] - Potential[nex];\n\t\t\t\t\tif (Dist[nex] > Dist[pos] + dst) {\n\t\t\t\t\t\tDist[nex] = Dist[pos] + dst;\n\t\t\t\t\t\tPrev_Verts[nex] = pos;\n\t\t\t\t\t\tPrev_ID[nex] = i;\n\t\t\t\t\t\tQ.push(make_pair(Dist[nex], nex));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (Dist[t] == (1LL << 60)) return -1LL;\n\t\t\t\n\t\t\t// Refresh Edges [Part 1]\n\t\t\tlong long current_pos = t;\n\t\t\tlong long current_min = f;\n\t\t\twhile (current_pos != s) {\n\t\t\t\tint nex = Prev_Verts[current_pos];\n\t\t\t\tint idx = Prev_ID[current_pos];\n\t\t\t\tcurrent_min = min(current_min, G[nex][idx].cap);\n\t\t\t\tcurrent_pos = nex;\n\t\t\t}\n\t\t\tcurrent_ans += 1LL * current_min * (Dist[t] + Potential[t] - Potential[s]);\n\t\t\tf -= current_min;\n\t\t\t\n\t\t\t// Refresh Edges [Part 2]\n\t\t\tcurrent_pos = t;\n\t\t\twhile (current_pos != s) {\n\t\t\t\tint nex = Prev_Verts[current_pos];\n\t\t\t\tint idx = Prev_ID[current_pos];\n\t\t\t\tG[nex][idx].cap -= current_min;\n\t\t\t\tG[G[nex][idx].to][G[nex][idx].rev].cap += current_min;\n\t\t\t\tcurrent_pos = nex;\n\t\t\t}\n\t\t\t\n\t\t\t// Refresh Potential\n\t\t\tfor (int i = 0; i < size_; i++) {\n\t\t\t\tif (Dist[i] != (1LL << 60)) Potential[i] += Dist[i];\n\t\t\t}\n\t\t}\n\t\t\n\t\t// Return\n\t\treturn current_ans;\n\t}\n};\n\nint N, X[1009], Y[1009];\nint M, A[1009], B[1009], C[1009], F[1009];\nint Bus;\n\nint solve(int Mask, int Border) {\n\tMincostFlow Z; Z.Initialize(N + M + 10);\n\tint Total_Cost = 0;\n\t\n\t// Add Edges\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < M; j++) {\n\t\t\tif ((Mask / (1 << j)) % 2 == 0) continue;\n\t\t\tint cost = max(0, abs(A[j] - X[i]) + abs(B[j] - Y[i]) - Border);\n\t\t\tZ.add_edge(i, N + j, 1, cost);\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) Z.add_edge(N + M + 0, i, 1, 0);\n\tfor (int i = 0; i < M; i++) {\n\t\tif ((Mask / (1 << i)) % 2 == 0) continue;\n\t\tZ.add_edge(N + i, N + M + 1, C[i], 0);\n\t\tTotal_Cost += F[i] + Border * Bus;\n\t}\n\t\n\t// Return\n\tint val = Z.mincost_flow(N + M, N + M + 1, N);\n\tif (val == -1) return 2000000000;\n\treturn Total_Cost + val;\n}\n\nint main() {\n\twhile (true) {\n\t\t// Input\n\t\tcin >> N >> M >> Bus; if (N + M + Bus == 0) break;\n\t\tfor (int i = 0; i < N; i++) cin >> X[i] >> Y[i];\n\t\tfor (int i = 0; i < M; i++) cin >> A[i] >> B[i] >> C[i] >> F[i];\n\t\t\n\t\t// Brute Force\n\t\tint Answer = (1 << 30);\n\t\tfor (int i = 1; i < (1 << M); i++) {\n\t\t\tint cl = 0, cr = 2022, cm;\n\t\t\tfor (int j = 0; j < 15; j++) {\n\t\t\t\tcm = (cl + cr) / 2;\n\t\t\t\tint val1 = solve(i, cm + 0);\n\t\t\t\tint val2 = solve(i, cm + 1);\n\t\t\t\tif (val1 > val2) { cl = cm; }\n\t\t\t\telse { cr = cm; }\n\t\t\t\tAnswer = min(Answer, val1);\n\t\t\t\tAnswer = min(Answer, val2);\n\t\t\t\t//cout << i << \" \" << cm << \" \" << val1 << \" \" << val2 << endl;\n\t\t\t}\n\t\t}\n\t\t\n\t\t// Output\n\t\tcout << Answer << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.625, "time_ms": 5560, "memory_kb": 3548, "score_of_the_acc": -1.689, "final_rank": 19 }, { "submission_id": "aoj_0293_5921799", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,...) for(int i = (a)*(strlen(#__VA_ARGS__)!=0);i<(int)(strlen(#__VA_ARGS__)?__VA_ARGS__:(a));++i)\n#define per(i,a,...) for(int i = (strlen(#__VA_ARGS__)?__VA_ARGS__:(a))-1;i>=(int)(strlen(#__VA_ARGS__)?(a):0);--i)\n#define foreach(i, n) for(auto &i:(n))\n#define all(x) (x).begin(), (x).end()\n#define bit(x) (1ll << (x))\n#define lambda(RES_TYPE, ...) (function<RES_TYPE(__VA_ARGS__)>)[&](__VA_ARGS__) -> RES_TYPE\n#define method(FUNC_NAME, RES_TYPE, ...) function<RES_TYPE(__VA_ARGS__)> FUNC_NAME = lambda(RES_TYPE, __VA_ARGS__)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\nusing pll = pair<ll,ll>;\n//const ll MOD = (ll)1e9+7;\nconst ll MOD = 998244353;\nconst int INF = (ll)1e9+7;\nconst ll INFLL = (ll)1e18;\ntemplate<class t>\nusing vvector = vector<vector<t>>;\ntemplate<class t>\nusing vvvector = vector<vector<vector<t>>>;\ntemplate<class t>\nusing priority_queuer = priority_queue<t, vector<t>, greater<t>>;\ntemplate<class t, class u> bool chmax(t &a, u b){if(a<b){a=b;return true;}return false;}\ntemplate<class t, class u> bool chmin(t &a, u b){if(a>b){a=b;return true;}return false;}\n#ifdef DEBUG\n#define debug(x) cout<<\"LINE \"<<__LINE__<<\": \"<<#x<<\" = \"<<x<<endl;\n#else\n#define debug(x) (void)0\n#endif\n\nnamespace templates{\n ll modpow(ll x, ll b,ll mod=MOD){\n ll res = 1;\n while(b){\n if(b&1)res = res * x % mod;\n x = x * x % mod;\n b>>=1;\n }\n return res;\n }\n\n ll modinv(ll x){\n return modpow(x, MOD-2);\n }\n\n bool was_output = false;\n\n void print();\n template <class t> void print(const vector<t> &);\n template <class t, class u> void print(const pair<t, u> &);\n template <class t> void print(const t&);\n template <class Head, class... Tail> void print(const Head&, const Tail&...);\n\n template <class t> void println(const vector<vector<t>>&);\n template <class t> void println(const vector<t>&);\n template <class t> void println(const t&);\n template <class Head, class... Tail> void println(const Head&, const Tail&...);\n void println();\n void newline();\n\n void print(){\n return;\n }\n\n template <class t>\n void print(const vector<t>&x){\n for(const t&i:x)print(i);\n }\n template <class t, class u>\n void print(const pair<t,u>&p){\n print(p.first);\n print(p.second);\n }\n template <class t>\n void print(const t&x){\n if(was_output)cout<<\" \";\n cout<<x;\n was_output = true;\n }\n template <class Head, class... Tail>\n void print(const Head&head,const Tail&...tail){\n print(head);\n print(tail...);\n }\n\n template<class t>\n void println(const vector<vector<t>>&x){\n for(vector<t> i:x)println(i);\n }\n template<class t>\n void println(const vector<t>&x){\n for(const t&i:x)print(i);\n println();\n }\n template <class t>\n void println(const t&x){\n print(x);\n println();\n }\n void println(){\n if(was_output){\n cout << endl;\n was_output = false;\n }\n }\n template <class Head, class... Tail>\n void println(const Head&head,const Tail&...tail){\n print(head);\n println(tail...);\n }\n\n void newline(){\n was_output = true;\n println();\n }\n\n template<class t>\n istream& operator>>(istream&is, vector<t>&x){\n for(auto &i:x)is >> i;\n return is;\n }\n\n template<class t, class u>\n istream& operator>>(istream&is, pair<t, u>&x){\n is >> x.first >> x.second;\n return is;\n }\n\n template<class t>\n ostream& operator<<(ostream&os, vector<t> &v){\n os << \"{\";\n for(t &i:v){\n os << i << \", \";\n }\n os << \"}\";\n return os;\n }\n\n template<class t = long long>\n t in(){\n t res; cin >> res; return res;\n }\n\n template<class t>\n vector<t> sorted(vector<t> line,function<bool(t,t)> comp=[](t a,t b){return a<b;}){\n sort(line.begin(),line.end(),comp);\n return line;\n }\n\n template<class t>\n vector<t> reversed(vector<t> line){\n reverse(line.begin(),line.end());\n return line;\n }\n string reversed(string str){\n reverse(str.begin(),str.end());\n return str;\n }\n\n long long gcd(long long a,long long b){\n while(b){\n a %= b;\n swap(a,b);\n }\n return a;\n }\n\n long long lcm(long long a,long long b){\n return a / gcd(a,b) * b;\n }\n\n class output_initializer{\n public:\n output_initializer(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n }\n };output_initializer OUTPUT_INITIALIZER_INSTANCE = output_initializer();\n}\n\nusing namespace templates;\n\ntemplate< typename flow_t, typename cost_t >\nstruct PrimalDual {\n const cost_t INF;\n\n struct edge {\n int to;\n flow_t cap;\n cost_t cost;\n int rev;\n bool isrev;\n };\n vector< vector< edge > > graph;\n vector< cost_t > potential, min_cost;\n vector< int > prevv, preve;\n\n PrimalDual(int V) : graph(V), INF(numeric_limits< cost_t >::max()) {}\n\n void add_edge(int from, int to, flow_t cap, cost_t cost) {\n graph[from].emplace_back((edge) {to, cap, cost, (int) graph[to].size(), false});\n graph[to].emplace_back((edge) {from, 0, -cost, (int) graph[from].size() - 1, true});\n }\n\n cost_t min_cost_flow(int s, int t, flow_t f) {\n int V = (int) graph.size();\n cost_t ret = 0;\n using Pi = pair< cost_t, int >;\n priority_queue< Pi, vector< Pi >, greater< Pi > > que;\n potential.assign(V, 0);\n preve.assign(V, -1);\n prevv.assign(V, -1);\n\n while(f > 0) {\n min_cost.assign(V, INF);\n que.emplace(0, s);\n min_cost[s] = 0;\n while(!que.empty()) {\n Pi p = que.top();\n que.pop();\n if(min_cost[p.second] < p.first) continue;\n for(int i = 0; i < graph[p.second].size(); i++) {\n edge &e = graph[p.second][i];\n cost_t nextCost = min_cost[p.second] + e.cost + potential[p.second] - potential[e.to];\n if(e.cap > 0 && min_cost[e.to] > nextCost) {\n min_cost[e.to] = nextCost;\n prevv[e.to] = p.second, preve[e.to] = i;\n que.emplace(min_cost[e.to], e.to);\n }\n }\n }\n if(min_cost[t] == INF) return -1;\n for(int v = 0; v < V; v++) potential[v] += min_cost[v];\n flow_t addflow = f;\n for(int v = t; v != s; v = prevv[v]) {\n addflow = min(addflow, graph[prevv[v]][preve[v]].cap);\n }\n f -= addflow;\n ret += addflow * potential[t];\n for(int v = t; v != s; v = prevv[v]) {\n edge &e = graph[prevv[v]][preve[v]];\n e.cap -= addflow;\n graph[v][e.rev].cap += addflow;\n }\n }\n return ret;\n }\n\n void output() {\n for(int i = 0; i < graph.size(); i++) {\n for(auto &e : graph[i]) {\n if(e.isrev) continue;\n auto &rev_e = graph[e.to][e.rev];\n cout << i << \"->\" << e.to << \" (flow: \" << rev_e.cap << \"/\" << rev_e.cap + e.cap << \")\" << endl;\n }\n }\n }\n};\n\nint func(int n,int m,int b){\n vector<pii> juken(n);\n vector<pii> kaijo(m);\n vector<int> maxs(m);\n vector<int> cost(m);\n foreach(i,juken)i=in<pii>();\n rep(i,m){\n kaijo[i] = in<pii>();\n maxs[i] = in();\n cost[i] = in();\n }\n method(dist,int,pii a,pii b){\n return abs(a.first-b.first)+abs(a.second-b.second);\n };\n method(cost_with_d,int,pii a,pii b,int d){\n return max(0,dist(a,b)-d);\n };\n method(calc,int,int use,int d){\n ll add = d * b;\n ll res = 0;\n PrimalDual<int,int> pd(n+m+2);\n int start = n + m;\n int end = start + 1;\n rep(i,n){\n pd.add_edge(start,i,1,0);\n }\n int cap = 0;\n rep(i,m){\n if(use&bit(i)){\n rep(j,n){\n pd.add_edge(j,i+n,1,cost_with_d(juken[j],kaijo[i],d));\n }\n pd.add_edge(i+n,end,maxs[i],0);\n res += cost[i] + add;\n cap += maxs[i];\n }\n }\n if(cap < n)return INF;\n return res + pd.min_cost_flow(start,end,n);\n };\n int res = INF;\n rep(use,bit(m)){\n int cap = 0;\n rep(i,m){\n if(bit(i)&use){\n cap += maxs[i];\n }\n }\n if(cap < n)continue;\n int lp = 0;\n int rp = 2100;\n while(lp < rp-3){\n int mid1 = (lp + lp + rp) / 3;\n int mid2 = (lp + rp + rp) / 3;\n int f1 = calc(use,mid1);\n int f2 = calc(use,mid1);\n if(f1 <= f2){\n rp = mid2;\n }else{\n lp = mid1;\n }\n }\n rep(i,max(0,lp-10),lp+10){\n chmin(res,calc(use,i));\n }\n //rep(i,2000){\n // chmin(res,calc(use,i));\n //}\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n while(true){\n int n = in();\n int m = in();\n int b = in();\n if(n==0 and m==0 and b==0)break;\n println(func(n,m,b));\n }\n return 0;\n}", "accuracy": 0.125, "time_ms": 20, "memory_kb": 3384, "score_of_the_acc": -0.5962, "final_rank": 20 }, { "submission_id": "aoj_0293_5009193", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/graph/MCF.cpp\"\n//Minimum Cost Flow O(FE log V)\n#line 3 \"/home/kotatsugame/library/graph/MCF.cpp\"\n#include<utility>\n#include<vector>\n#include<queue>\n#include<limits>\ntemplate<typename T>\nstruct MCF{\n\tstruct edge{\n\t\tint to,rev,cap;\n\t\tT cost;\n\t};\n\tvector<vector<edge> >G;\n\tvector<T>h,d;\n\tvector<int>pv,pe;\n\tMCF(int n_=0):G(n_),h(n_,0),d(n_),pv(n_),pe(n_){}\n\tvoid add_edge(int from,int to,int cap,T cost)\n\t{\n\t\tG[from].push_back({to,(int)G[to].size(),cap,cost});\n\t\tG[to].push_back({from,(int)G[from].size()-1,0,-cost});\n\t}\n\tT min_cost_flow(int s,int t,int f)//ans or -1\n\t{\n\t\tT ret=0;\n\t\twhile(f>0)\n\t\t{\n\t\t\tpriority_queue<pair<T,int>,vector<pair<T,int> >,greater<pair<T,int> > >P;\n\t\t\tfill(d.begin(),d.end(),numeric_limits<T>::max());\n\t\t\td[s]=0;\n\t\t\tP.push(make_pair(0,s));\n\t\t\twhile(!P.empty())\n\t\t\t{\n\t\t\t\tpair<T,int>p=P.top();P.pop();\n\t\t\t\tif(d[p.second]<p.first)continue;\n\t\t\t\tfor(int i=0;i<G[p.second].size();i++)\n\t\t\t\t{\n\t\t\t\t\tedge&e=G[p.second][i];\n\t\t\t\t\tif(e.cap>0&&d[e.to]>d[p.second]+e.cost+h[p.second]-h[e.to])\n\t\t\t\t\t{\n\t\t\t\t\t\td[e.to]=d[p.second]+e.cost+h[p.second]-h[e.to];\n\t\t\t\t\t\tpv[e.to]=p.second;\n\t\t\t\t\t\tpe[e.to]=i;\n\t\t\t\t\t\tP.push(make_pair(d[e.to],e.to));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(d[t]==numeric_limits<T>::max())return -1;\n\t\t\tfor(int u=0;u<G.size();u++)h[u]+=d[u];\n\t\t\tint d=f;\n\t\t\tfor(int u=t;u!=s;u=pv[u])d=min(d,G[pv[u]][pe[u]].cap);\n\t\t\tf-=d;\n\t\t\tret+=d*h[t];\n\t\t\tfor(int u=t;u!=s;u=pv[u])\n\t\t\t{\n\t\t\t\tG[pv[u]][pe[u]].cap-=d;\n\t\t\t\tG[u][G[pv[u]][pe[u]].rev].cap+=d;\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n};\n#line 5 \"a.cpp\"\nint N,M,B;\nint x[100],y[100];\nint X[5],Y[5],c[5],F[5];\nint f(int mk,int D)\n{\n\tMCF<int>P(N+M+2);\n\tint st=N+M,go=N+M+1;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tP.add_edge(st,i,1,0);\n\t\tfor(int j=0;j<M;j++)if(mk>>j&1)\n\t\t{\n\t\t\tP.add_edge(i,N+j,1,max(0,abs(x[i]-X[j])+abs(y[i]-Y[j])-D));\n\t\t}\n\t}\n\tfor(int j=0;j<M;j++)if(mk>>j&1)P.add_edge(N+j,go,c[j],0);\n\tint ret=P.min_cost_flow(st,go,N);\n\tif(ret==-1)return 1e9;\n\tret+=D*B*__builtin_popcount(mk);\n\treturn ret;\n}\nmain()\n{\n\twhile(cin>>N>>M>>B,N)\n\t{\n\t\tfor(int i=0;i<N;i++)cin>>x[i]>>y[i];\n\t\tfor(int i=0;i<M;i++)cin>>X[i]>>Y[i]>>c[i]>>F[i];\n\t\tint ans=2e9;\n\t\tfor(int i=1;i<1<<M;i++)\n\t\t{\n\t\t\tint D=0;\n\t\t\tif(f(i,0)<=f(i,1))D=0;\n\t\t\telse\n\t\t\t{\n\t\t\t\tint L=0,R=5000;\n\t\t\t\twhile(R-L>1)\n\t\t\t\t{\n\t\t\t\t\tint mid=(L+R)/2;\n\t\t\t\t\tif(f(i,mid)>f(i,mid+1))L=mid;\n\t\t\t\t\telse R=mid;\n\t\t\t\t}\n\t\t\t\tD=L+1;\n\t\t\t}\n\t\t\tint now=f(i,D);\n\t\t\tfor(int j=0;j<M;j++)if(i>>j&1)now+=F[j];\n\t\t\tans=min(ans,now);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 5460, "memory_kb": 3168, "score_of_the_acc": -0.7629, "final_rank": 3 }, { "submission_id": "aoj_0293_4976978", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int>P;\n\nconst int MOD=1000000007;\nconst int INF=0x3f3f3f3f;\nconst ll INFL=0x3f3f3f3f3f3f3f3f;\n\ntemplate<typename flow_t,typename cost_t>\nstruct PrimalDual{\n\tconst cost_t INF;\n\tstruct edge{\n\t\tint to;\n\t\tflow_t cap;\n\t\tcost_t cost;\n\t\tint rev;\n\t\tbool isrev;\n\t};\n\tvector<vector<edge>>graph;\n\tvector<cost_t>potential,min_cost;\n\tvector<int>prevv,preve;\n\n\tPrimalDual(int V):INF(numeric_limits<cost_t>::max()),graph(V){}\n\n\tvoid add_edge(int from,int to,flow_t cap,cost_t cost){\n\t\tgraph[from].emplace_back((edge){to,cap,cost,(int)graph[to].size(),false});\n\t\tgraph[to].emplace_back((edge){from,0,-cost,(int)graph[from].size()-1,true});\n\t}\n\t\n\tcost_t min_cost_flow(int s,int t,flow_t f){\n\t\tint V=(int)graph.size();\n\t\tcost_t ret=0;\n\t\tusing Pi=pair<cost_t,int>;\n\t\tpriority_queue<Pi,vector<Pi>,greater<Pi>>que;\n\t\tpotential.assign(V,0);\n\t\tpreve.assign(V,-1);\n\t\tprevv.assign(V,-1);\n\n\t\twhile(f>0){\n\t\t\tmin_cost.assign(V,INF);\n\t\t\tque.emplace(0,s);\n\t\t\tmin_cost[s]=0;\n\t\t\twhile(!que.empty()){\n\t\t\t\tPi p=que.top();\n\t\t\t\tque.pop();\n\t\t\t\tif(min_cost[p.second]<p.first)continue;\n\t\t\t\tfor(int i=0;i<graph[p.second].size();i++){\n\t\t\t\t\tedge&e=graph[p.second][i];\n\t\t\t\t\tcost_t nextCost=min_cost[p.second]+e.cost+potential[p.second]-potential[e.to];\n\t\t\t\t\tif(e.cap>0&&min_cost[e.to]>nextCost){\n\t\t\t\t\t\tmin_cost[e.to]=nextCost;\n\t\t\t\t\t\tprevv[e.to]=p.second,preve[e.to]=i;\n\t\t\t\t\t\tque.emplace(min_cost[e.to],e.to);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(min_cost[t]==INF)return -1;\n\t\t\tfor(int v=0;v<V;v++)potential[v]+=min_cost[v];\n\t\t\tflow_t addflow=f;\n\t\t\tfor(int v=t;v!=s;v=prevv[v]){\n\t\t\t\taddflow=min(addflow,graph[prevv[v]][preve[v]].cap);\n\t\t\t}\n\t\t\tf-=addflow;\n\t\t\tret+=addflow*potential[t];\n\t\t\tfor(int v=t;v!=s;v=prevv[v]){\n\t\t\t\tedge&e=graph[prevv[v]][preve[v]];\n\t\t\t\te.cap-=addflow;\n\t\t\t\tgraph[v][e.rev].cap+=addflow;\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n};\n\nint ax[200],ay[200];\nint bx[6],by[6],c[6],f[6];\n\nint n,m,b;\n\nint M;\nvector<int>v;\n\nll calc(int t){\n\tPrimalDual<ll,ll>flow(n+M+2);\n\tint s=n+M,g=n+M+1;\n\trep(i,n){\n\t\tflow.add_edge(s,i,1,0);\n\t}\n\trep(i,M){\n\t\tflow.add_edge(n+i,g,c[v[i]],0);\n\t}\n\trep(i,n)rep(j,M){\n\t\tint d=abs(bx[v[j]]-ax[i])+abs(by[v[j]]-ay[i]);\n\t\td=max(0,d-t);\n\t\tflow.add_edge(i,n+j,1,d);\n\t}\n\treturn flow.min_cost_flow(s,g,n)+t*b*M;\n}\n\nint main(){\n\twhile(cin>>n>>m>>b,n){\n\t\trep(i,n){\n\t\t\tscanf(\"%d%d\",&ax[i],&ay[i]);\n\t\t}\n\t\trep(i,m){\n\t\t\tscanf(\"%d%d%d%d\",&bx[i],&by[i],&c[i],&f[i]);\n\t\t}\n\t\tll Min=INFL;\n\t\trep(S,1<<m){\n\t\t\tll cost=0;\n\t\t\tint cap=0;\n\t\t\tv.clear();\n\t\t\trep(j,m){\n\t\t\t\tif(S>>j&1)cost+=f[j],cap+=c[j],v.push_back(j);\n\t\t\t}\n\t\t\tif(cap<n)continue;\n\t\t\tM=v.size();\n\t\t\tint ok=-1,ng=5000;//cost(i)>=cost(i+1)\n\n\t\t\twhile(ng-ok>1){\n\t\t\t\tint t=(ok+ng)/2;\n\t\t\t\tif(calc(t)>=calc(t+1))ok=t;\n\t\t\t\telse ng=t;\n\t\t\t}\n\t\t\tMin=min(Min,cost+calc(ng));\n\t\t}\n\t\tcout<<Min<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 4810, "memory_kb": 3316, "score_of_the_acc": -1.0367, "final_rank": 5 }, { "submission_id": "aoj_0293_4499110", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class K, class V>\nclass RadixHeap {\n static constexpr int bit_length = sizeof(K)*8;\n K last;\n size_t sz, cnt;\n array<vector<pair<K, V>>, bit_length> v;\n static inline int bsr(int x){\n return x ? bit_length-__builtin_clz(x) : 0;\n }\n static inline int bsr(ll x){\n return x ? bit_length-__builtin_clzll(x) : 0;\n }\n\n void pull() {\n if(cnt < v[0].size()) return;;\n int i = 1;\n while(v[i].empty()) i++;\n last = min_element(v[i].begin(),v[i].end())->first;\n for (auto &&x : v[i]) v[bsr(x.first ^ last)].push_back(x);\n v[i].clear();\n }\npublic:\n RadixHeap() : last(0), sz(0), cnt(0) {}\n void emplace(K x, V val){\n sz++;\n v[bsr(x^last)].emplace_back(x, val);\n }\n\n pair<K, V> top() {\n pull();\n return v[0][cnt];\n }\n\n void pop() {\n pull();\n sz--;\n cnt++;\n }\n\n size_t size() const { return sz; }\n bool empty() const { return !sz; }\n};\n\ntemplate<typename F, typename C>\nstruct PrimalDual {\n struct edge {\n int to; F cap; C cost; int rev;\n edge() = default;\n edge(int to, F cap, C cost, int rev):to(to), cap(cap), cost(cost), rev(rev) {};\n };\n vector<vector<edge>> G;\n vector<C> potential, min_cost;\n vector<int> prevv, preve;\n\n explicit PrimalDual(int n) : G(n), potential(n), min_cost(n), prevv(n), preve(n) {}\n\n void add_edge(int u, int v, F cap, C cost){\n G[u].emplace_back(v, cap, cost, G[v].size());\n G[v].emplace_back(u, 0, -cost, G[u].size()-1);\n }\n\n\n void dijkstra(int s){\n\n RadixHeap<C, int> Q;\n fill(min_cost.begin(),min_cost.end(), INF<C>);\n min_cost[s] = 0;\n Q.emplace(0, s);\n while(!Q.empty()){\n pair<C, int> p = Q.top(); Q.pop();\n int v = p.second;\n if(min_cost[v] < p.first) continue;\n for(int i = 0; i < G[v].size(); ++i){\n edge &e=G[v][i];\n if(e.cap==0) continue;\n if(min_cost[v]+e.cost+potential[v]-potential[e.to] < min_cost[e.to]){\n min_cost[e.to] = min_cost[v]+e.cost+potential[v]-potential[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n Q.emplace(min_cost[e.to], e.to);\n }\n }\n }\n }\n\n C flow(int s, int t, F fl, int &ok){\n C res = 0;\n fill(potential.begin(),potential.end(), 0);\n while(fl > 0){\n dijkstra(s);\n if(min_cost[t] == INF<C>){\n ok = 0;\n return res;\n }\n for (int i = 0; i < potential.size(); ++i) {\n if(min_cost[i] < INF<C>) potential[i] += min_cost[i];\n }\n\n F d = fl;\n for(int v = t; v != s; v = prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n fl -= d;\n res += potential[t]*d;\n for(int v = t; v != s; v = prevv[v]){\n G[prevv[v]][preve[v]].cap -= d;\n G[v][G[prevv[v]][preve[v]].rev].cap += d;\n }\n }\n ok = 1;\n return res;\n }\n};\n\nvoid solve(int n, int m, int b){\n vector<int> ax(n), ay(n);\n for (int i = 0; i < n; ++i) {\n cin >> ax[i] >> ay[i];\n }\n vector<int> bx(m), by(m), c(m), v(m);\n for (int i = 0; i < m; ++i) {\n cin >> bx[i] >> by[i] >> c[i] >> v[i];\n }\n int ans = INF<int>;\n for (int i = 1; i < (1 << m); ++i) {\n auto f = [&](int x) -> int {\n PrimalDual<int, int> G(2+m+n);\n int ans = 0;\n for (int j = 0; j < m; ++j) {\n if(i & (1 << j)){\n ans += v[j]+b*x;\n G.add_edge(0, j+2, c[j], 0);\n for (int k = 0; k < n; ++k) {\n G.add_edge(j+2, m+2+k, 1, max(0, (abs(ax[k]-bx[j])+abs(ay[k]-by[j]))-x));\n }\n }\n }\n for (int j = 0; j < n; ++j) {\n G.add_edge(m+2+j, 1, 1, 0);\n }\n int flg = 0;\n ans += G.flow(0, 1, n, flg);\n if(!flg) return INF<int>;\n else return ans;\n };\n int ok = 0, ng = 5000;\n while(ng-ok > 1){\n int mid = (ng+ok)/2;\n if(f(mid-1) >= f(mid)) ok = mid;\n else ng = mid;\n }\n ans = min(ans, f(ok));\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n int n, m, b;\n while(cin >> n >> m >> b, n){\n solve(n, m, b);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 5310, "memory_kb": 3196, "score_of_the_acc": -0.8113, "final_rank": 4 }, { "submission_id": "aoj_0293_4499100", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class K, class V>\nclass RadixHeap {\n static constexpr int bit_length = sizeof(K)*8;\n K last;\n size_t sz, cnt;\n array<vector<pair<K, V>>, bit_length> v;\n static inline int bsr(int x){\n return x ? bit_length-__builtin_clz(x) : 0;\n }\n static inline int bsr(ll x){\n return x ? bit_length-__builtin_clzll(x) : 0;\n }\n\n void pull() {\n if(cnt < v[0].size()) return;;\n int i = 1;\n while(v[i].empty()) i++;\n last = min_element(v[i].begin(),v[i].end())->first;\n for (auto &&x : v[i]) v[bsr(x.first ^ last)].push_back(x);\n v[i].clear();\n }\npublic:\n RadixHeap() : last(0), sz(0), cnt(0) {}\n void emplace(K x, V val){\n sz++;\n v[bsr(x^last)].emplace_back(x, val);\n }\n\n pair<K, V> top() {\n pull();\n return v[0][cnt];\n }\n\n void pop() {\n pull();\n sz--;\n cnt++;\n }\n\n size_t size() const { return sz; }\n bool empty() const { return !sz; }\n};\n\ntemplate<typename F, typename C>\nstruct PrimalDual {\n struct edge {\n int to; F cap; C cost; int rev;\n edge() = default;\n edge(int to, F cap, C cost, int rev):to(to), cap(cap), cost(cost), rev(rev) {};\n };\n vector<vector<edge>> G;\n vector<C> potential, min_cost;\n vector<int> prevv, preve;\n\n explicit PrimalDual(int n) : G(n), potential(n), min_cost(n), prevv(n), preve(n) {}\n\n void add_edge(int u, int v, F cap, C cost){\n G[u].emplace_back(v, cap, cost, G[v].size());\n G[v].emplace_back(u, 0, -cost, G[u].size()-1);\n }\n\n\n void dijkstra(int s){\n\n RadixHeap<C, int> Q;\n fill(min_cost.begin(),min_cost.end(), INF<C>);\n min_cost[s] = 0;\n Q.emplace(0, s);\n while(!Q.empty()){\n pair<C, int> p = Q.top(); Q.pop();\n int v = p.second;\n if(min_cost[v] < p.first) continue;\n for(int i = 0; i < G[v].size(); ++i){\n edge &e=G[v][i];\n if(e.cap==0) continue;\n if(min_cost[v]+e.cost+potential[v]-potential[e.to] < min_cost[e.to]){\n min_cost[e.to] = min_cost[v]+e.cost+potential[v]-potential[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n Q.emplace(min_cost[e.to], e.to);\n }\n }\n }\n }\n\n C flow(int s, int t, F fl, int &ok){\n C res = 0;\n fill(potential.begin(),potential.end(), 0);\n while(fl > 0){\n dijkstra(s);\n if(min_cost[t] == INF<C>){\n ok = 0;\n return res;\n }\n for (int i = 0; i < potential.size(); ++i) {\n if(min_cost[i] < INF<C>) potential[i] += min_cost[i];\n }\n\n F d = fl;\n for(int v = t; v != s; v = prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n fl -= d;\n res += potential[t]*d;\n for(int v = t; v != s; v = prevv[v]){\n G[prevv[v]][preve[v]].cap -= d;\n G[v][G[prevv[v]][preve[v]].rev].cap += d;\n }\n }\n ok = 1;\n return res;\n }\n};\n\nvoid solve(int n, int m, int b){\n vector<int> ax(n), ay(n);\n for (int i = 0; i < n; ++i) {\n cin >> ax[i] >> ay[i];\n }\n vector<int> bx(m), by(m), c(m), v(m);\n for (int i = 0; i < m; ++i) {\n cin >> bx[i] >> by[i] >> c[i] >> v[i];\n }\n int ans = INF<int>;\n for (int i = 1; i < (1 << m); ++i) {\n auto f = [&](int x) -> int {\n PrimalDual<int, int> G(2+m+n);\n int ans = 0;\n for (int j = 0; j < m; ++j) {\n if(i & (1 << j)){\n ans += v[j]+b*x;\n G.add_edge(0, j+2, c[j], 0);\n for (int k = 0; k < n; ++k) {\n G.add_edge(j+2, m+2+k, 1, max(0, (abs(ax[k]-bx[j])+abs(ay[k]-by[j]))-x));\n }\n }\n }\n for (int j = 0; j < n; ++j) {\n G.add_edge(m+2+j, 1, 1, 0);\n }\n int flg = 0;\n ans += G.flow(0, 1, n, flg);\n if(!flg) return INF<int>;\n else return ans;\n };\n int ok = 0, ng = 2100;\n while(ng-ok > 1){\n int mid = (ng+ok)/2;\n if(f(mid-1) >= f(mid)) ok = mid;\n else ng = mid;\n }\n ans = min(ans, f(ok));\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n int n, m, b;\n while(cin >> n >> m >> b, n){\n solve(n, m, b);\n }\n return 0;\n}", "accuracy": 0.625, "time_ms": 4470, "memory_kb": 3212, "score_of_the_acc": -0.7439, "final_rank": 16 }, { "submission_id": "aoj_0293_3671857", "code_snippet": "#include<iostream>\n#include<vector>\n#include<complex>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#define rep(i,n) for(int i = 0;i < n ; ++i)\n\nusing namespace std;\n\nusing ll = long long;\n\nstruct edge{int to, cap, cost, rev;};\n\nstruct mincostflow{\n vector<vector<edge>> G;\n vector<int> par, dist;\n mincostflow(int n):G(n),par(n),dist(n){}\n void add_edge(int from, int to, int cap, int cost){\n G[from].push_back({to,cap,cost,(int)G[to].size()});\n G[to].push_back({from,0,-cost,(int)G[from].size()-1});\n }\n\n int minimum_load(int s,int t){\n fill(par.begin(),par.end(),-1);\n fill(dist.begin(),dist.end(),1e9+7);\n dist[s]=0;\n priority_queue<pair<int,int>,vector<pair<int,int>>, greater<pair<int,int>>> pq;\n pq.push({0,s});\n while(pq.size()){\n auto p = pq.top();pq.pop();\n int id = p.second;\n if(id==t)continue;\n if(p.first>dist[id])continue;\n for(auto e : G[id]){\n if(e.cap>0){\n int nd = p.first + e.cost;\n if(nd<dist[e.to]){\n dist[e.to]=nd;\n par[e.to]=id;\n pq.push({nd,e.to});\n }\n }\n }\n }\n int cur = t;\n while(cur!=s){\n int p = par[cur];\n if(p<0)return -1;\n for(auto& e : G[p]){\n if(e.cap>0&&e.to==cur&&dist[p]+e.cost==dist[cur]){\n e.cap--;\n G[cur][e.rev].cap++;\n break;\n }\n }cur=p;\n }\n return dist[t];\n }\n int minimum_cost_flow(int s,int t,int k){\n int ret = 0;\n rep(i,k){\n int z = minimum_load(s, t);\n if(z<0)return -1;\n ret += z;\n }\n return ret;\n }\n};\nint ax[111],ay[111];\nint bx[10],by[10],c[10],f[10];\nint n,m,b;\n\n\nint calc(int d,int mask){\n mincostflow mcf(n+m+2);\n int s = n+m,t = n+m+1;\n rep(j,m){\n if(((1<<j)&mask)==0)continue;\n mcf.add_edge(n+j, t, c[j], 0);\n rep(i,n){\n int dist = max(0,abs(ax[i]-bx[j])+abs(ay[i]-by[j])-d);\n mcf.add_edge(i, n+j, 1, dist);\n }\n }\n rep(i,n)mcf.add_edge(s, i, 1, 0);\n int ret = mcf.minimum_cost_flow(s,t,n);\n if(ret==-1)ret=1e9+7;\n return ret+d*b*__builtin_popcount(mask);\n}\nvoid solve(){\n rep(i,n)cin>>ax[i]>>ay[i];\n rep(i,m){\n cin>>bx[i]>>by[i]>>c[i]>>f[i];\n }\n int ans = 1ll<<30;\n int all = 1<<m;\n rep(i,all){\n int cost = 0;\n int cap = 0;\n rep(j,m){\n if(i&(1<<j)){\n cost+=f[j];\n cap += c[j];\n }\n }\n if(cap<n)continue;\n int l = 0, r = 4001;\n while(r-l>2){\n int ml = (2*l+r)/3, mr = (l+2*r)/3;\n int vl = calc(ml,i);\n int vr = calc(mr,i);\n if(vl>vr)l=ml;\n else r=mr;\n }\n ans = min(calc(l,i)+cost,ans);\n ans = min(calc(l+1,i)+cost,ans);\n ans = min(calc(l+2,i)+cost,ans);\n }\n cout<<ans<<endl;\n}\n\nint main(){\n while(cin>>n>>m>>b,n!=0)solve();\n\n}", "accuracy": 1, "time_ms": 7950, "memory_kb": 3192, "score_of_the_acc": -1.1346, "final_rank": 7 }, { "submission_id": "aoj_0293_3671849", "code_snippet": "#include<iostream>\n#include<vector>\n#include<complex>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#define rep(i,n) for(int i = 0;i < n ; ++i)\n\nusing namespace std;\n\nusing ll = long long;\n\nstruct edge{int to, cap, cost, rev;};\n\nstruct mincostflow{\n vector<vector<edge>> G;\n vector<int> par, dist;\n mincostflow(int n):G(n),par(n),dist(n){}\n void add_edge(int from, int to, int cap, int cost){\n G[from].push_back({to,cap,cost,(int)G[to].size()});\n G[to].push_back({from,0,-cost,(int)G[from].size()-1});\n }\n\n int minimum_load(int s,int t){\n fill(par.begin(),par.end(),-1);\n fill(dist.begin(),dist.end(),1e9+7);\n dist[s]=0;\n priority_queue<pair<int,int>,vector<pair<int,int>>, greater<pair<int,int>>> pq;\n pq.push({0,s});\n while(pq.size()){\n auto p = pq.top();pq.pop();\n int id = p.second;\n if(id==t)continue;\n if(p.first>dist[id])continue;\n for(auto e : G[id]){\n if(e.cap>0){\n int nd = p.first + e.cost;\n if(nd<dist[e.to]){\n dist[e.to]=nd;\n par[e.to]=id;\n pq.push({nd,e.to});\n }\n }\n }\n }\n int cur = t;\n while(cur!=s){\n int p = par[cur];\n if(p<0)return -1;\n for(auto& e : G[p]){\n if(e.cap>0&&e.to==cur&&dist[p]+e.cost==dist[cur]){\n e.cap--;\n G[cur][e.rev].cap++;\n break;\n }\n }cur=p;\n }\n return dist[t];\n }\n int minimum_cost_flow(int s,int t,int k){\n int ret = 0;\n rep(i,k){\n int z = minimum_load(s, t);\n if(z<0)return -1;\n ret += z;\n }\n return ret;\n }\n};\nint ax[111],ay[111];\nint bx[10],by[10],c[10],f[10];\nint n,m,b;\n\n\nint calc(int d,int mask){\n mincostflow mcf(n+m+2);\n int s = n+m,t = n+m+1;\n rep(j,m){\n if(((1<<j)&mask)==0)continue;\n mcf.add_edge(n+j, t, c[j], 0);\n rep(i,n){\n int dist = max(0,abs(ax[i]-bx[j])+abs(ay[i]-by[j])-d);\n mcf.add_edge(i, n+j, 1, dist);\n }\n }\n rep(i,n)mcf.add_edge(s, i, 1, 0);\n int ret = mcf.minimum_cost_flow(s,t,n);\n if(ret==-1)ret=1e9+7;\n return ret+d*b*__builtin_popcount(mask);\n}\nvoid solve(){\n rep(i,n)cin>>ax[i]>>ay[i];\n rep(i,m){\n cin>>bx[i]>>by[i]>>c[i]>>f[i];\n }\n int ans = 1ll<<30;\n int all = 1<<m;\n rep(i,all){\n int cost = 0;\n rep(j,m)if(i&(1<<j))cost+=f[j];\n int l = 0, r = 2000;\n while(r-l>2){\n int ml = (2*l+r)/3, mr = (l+2*r)/3;\n int vl = calc(ml,i);\n int vr = calc(mr,i);\n if(vl>vr)l=ml;\n else r=mr;\n }\n ans = min(calc(l,i)+cost,ans);\n ans = min(calc(l+1,i)+cost,ans);\n ans = min(calc(l+2,i)+cost,ans);\n }\n cout<<ans<<endl;\n}\n\nint main(){\n while(cin>>n>>m>>b,n!=0)solve();\n\n}", "accuracy": 0.625, "time_ms": 7070, "memory_kb": 3200, "score_of_the_acc": -1.0429, "final_rank": 17 }, { "submission_id": "aoj_0293_3365821", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#include <functional>\n#include <map>\n#include <climits>\n#include <stack>\n#include <string>\n#include <random>\n#include<set>\n#include <iomanip>\n#include <climits>\n#include <memory>\n#include <cassert>\nstruct Point {\n\tint x, y;\n\tint manhattan_distance(const Point &other) const { return std::abs(x - other.x) + std::abs(y - other.y); }\n};\nstruct Key_with_value {\n\tint key, value;\n\tbool operator>(const Key_with_value &kv) const { return key > kv.key; }\n};\nstruct Edge {\n\tint to, cost, pair;\n\tbool can_use;\n};\nstd::vector<std::vector<Edge>> make_graph(const std::vector<Point> &person, const std::vector<Point> &hall) {\n\tstd::vector<std::vector<Edge>> result(person.size() + hall.size() + 2);\n\tconst int start = 0;\n\tconst int goal = result.size() - 1;\n\tresult[start] = std::vector<Edge>(person.size());\n\tresult[goal] = std::vector<Edge>(hall.size());\n\tfor (auto i = 0; i < person.size(); ++i) {\n\t\tresult[i + 1] = std::vector<Edge>(hall.size() + 1);\n\t\tresult[i + 1][0] = Edge{ start, 0, i, false };\n\t\tresult[start][i] = Edge{ i + 1, 0, 0, true};\n\t}\n\tfor (auto i = 0; i < hall.size(); ++i) {\n\t\tresult[i + person.size() + 1] = std::vector<Edge>(person.size() + 1);\n\t\tresult[i + person.size() + 1][0] = Edge{ goal, 0, i, true };\n\t\tresult[goal][i] = Edge{ i + (int)person.size() + 1, 0, 0, false };\n\t}\n\tfor (auto p = 0; p < person.size(); ++p) {\n\t\tfor (auto h = 0; h < hall.size(); ++h) {\n\t\t\tauto distance = person[p].manhattan_distance(hall[h]);\n\t\t\tresult[p + 1][h + 1] = Edge{ h + (int)person.size() + 1, distance, p + 1, true };\n\t\t\tresult[h + person.size() + 1][p + 1] = { p + 1, -distance, h + 1, false};\n\t\t}\n\t}\n\treturn result;\n}\nint min_cost_max_flow(std::vector<std::vector<Edge>> nodes, std::vector<int> capacities, const int distance) {\n\tstd::vector<int> potential(nodes.size(), 0);\n\tstd::vector<int> min_cost(nodes.size(), 0);\n\tstd::vector<Edge*> prev_edge(nodes.size(), nullptr);\n\tconst int start = 0;\n\tconst int goal = nodes.size() - 1;\n\tconst int separation = nodes.size() - 1 - capacities.size();\n\tint result = 0;\n\tfor (auto &line : nodes) for (auto &cell : line) {\n\t\tif (cell.cost > distance) cell.cost -= distance;\n\t\telse if (cell.cost < -distance) cell.cost += distance;\n\t\telse cell.cost = 0;\n\t}\n\tstd::priority_queue<Key_with_value, std::vector<Key_with_value>, std::greater<Key_with_value>> queue;\n\twhile (true) {\n\t\tfor (auto i = 1; i < min_cost.size(); ++i) min_cost[i] = INT_MAX;\n\t\tqueue.push(Key_with_value{ 0, start });\n\t\twhile (!queue.empty()) {\n\t\t\tauto top = queue.top(); queue.pop();\n\t\t\tif (min_cost[top.value] == top.key) {\n\t\t\t\tfor (const auto &next : nodes[top.value]) {\n\t\t\t\t\tif (!next.can_use) continue;\n\t\t\t\t\tif (min_cost[next.to] > top.key + next.cost + potential[top.value] - potential[next.to]) {\n\t\t\t\t\t\tmin_cost[next.to] = top.key + next.cost + potential[top.value] - potential[next.to];\n\t\t\t\t\t\tprev_edge[next.to] = &nodes[next.to][next.pair];\n\t\t\t\t\t\tif (next.to != goal) queue.push({ min_cost[next.to], next.to });\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (min_cost[goal] != INT_MAX) {\n\t\t\tresult += min_cost[goal];\n\t\t\t--capacities[prev_edge[goal]->to - separation];\n\t\t\tif (capacities[prev_edge[goal]->to - separation] == 0) {\n\t\t\t\tnodes[prev_edge[goal]->to][prev_edge[goal]->pair].can_use = false;\n\t\t\t}\n\t\t\tauto last = prev_edge[goal]->to;\n\t\t\twhile (last != start) {\n\t\t\t\tprev_edge[last]->can_use = true;\n\t\t\t\tnodes[prev_edge[last]->to][prev_edge[last]->pair].can_use = false;\n\t\t\t\tlast = prev_edge[last]->to;\n\t\t\t}\n\t\t\tfor (auto i = 1; i < potential.size() - 1; ++i) potential[i] += min_cost[i];\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn result;\n}\nvoid solve() {\n\tint n, m, b; std::cin >> n >> m >> b;\n\tif (n == 0) return;\n\tstd::vector<Point> persons(n); for (auto &person : persons) std::cin >> person.x >> person.y;\n\tstd::vector<Point> halls(m); std::vector<int> capacities(m); std::vector<int> fees(m);\n\tfor (auto i = 0; i < m; ++i) std::cin >> halls[i].x >> halls[i].y >> capacities[i] >> fees[i];\n\tint min = INT_MAX;\n\tfor (auto usage = 1; usage < (1 << m); ++usage) {\n\t\tstd::vector<Point> use_hall;\n\t\tstd::vector<int> use_capacities;\n\t\tint sum_capacity = 0;\n\t\tint sum_fee = 0;\n\t\tfor (auto i = 0; i < m; ++i) {\n\t\t\tif (((1 << i) & usage) != 0) {\n\t\t\t\tuse_hall.push_back(halls[i]);\n\t\t\t\tuse_capacities.push_back(capacities[i]);\n\t\t\t\tsum_capacity += capacities[i];\n\t\t\t\tsum_fee += fees[i];\n\t\t\t}\n\t\t}\n\t\tif (sum_capacity >= n) {\n\t\t\tauto nodes = make_graph(persons, use_hall);\n\t\t\tauto left = 0;\n\t\t\tauto right = 4000;\n\t\t\twhile (left < right) {\n\t\t\t\tauto mid = (left + right) / 2;\n\t\t\t\tauto c = min_cost_max_flow(nodes, use_capacities, mid + 1) - min_cost_max_flow(nodes, use_capacities, mid) + b * (int)use_hall.size();\n\t\t\t\tif (c < 0) {\n\t\t\t\t\tleft = mid + 1;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tright = mid;\n\t\t\t\t}\n\t\t\t}\n\t\t\tauto c = min_cost_max_flow(nodes, use_capacities, right);\n\t\t\tif (min > c + right * b * use_hall.size() + sum_fee) {\n\t\t\t\tmin = c + right * b * use_hall.size() + sum_fee;\n\t\t\t}\n\t\t}\n\t}\n\tstd::cout << min << std::endl;\n\tsolve();\n}\nint main() {\n\tsolve();\n}", "accuracy": 1, "time_ms": 3130, "memory_kb": 3248, "score_of_the_acc": -0.6614, "final_rank": 2 }, { "submission_id": "aoj_0293_2875419", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n#define NUM 150\n\nstruct Info{\n\tint x,y,capacity,fee;\n};\n\n\n//辺を表す構造体{行先、容量、コスト、逆辺のインデックス}\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_cost,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\tcost = arg_cost;\n\t\trev_index = arg_rev_index;\n\t}\n\n\tint to,capacity,cost,rev_index;\n};\n\nint N,M,B;\nint V; //頂点数\nint POW[6];\nvector<Edge> G[NUM]; //グラフの隣接リスト表現\nint dist[NUM]; //最短距離\nint pre_node[NUM],pre_edge[NUM]; //直前の頂点と辺\nInfo student[100],house[5];\n\n\n//fromからtoへ向かう容量capacity,コストcostの辺をグラフに追加する\nvoid add_edge(int from,int to,int capacity,int cost){\n\tG[from].push_back(Edge(to,capacity,cost,G[to].size()));\n\tG[to].push_back(Edge(from,0,-cost,G[from].size()-1));\n}\n\n//sourceからsinkへの、流量flowの最小費用流を求める\n//流せない場合は-1を返す\nint min_cost_flow(int source,int sink,int flow){\n\tint ret = 0;\n\twhile(flow > 0){\n\t\t//ベルマンフォード方により、source-sink間最短経路を求める\n\t\tfor(int i = 0; i < V; i++)dist[i] = BIG_NUM;\n\t\tdist[source] = 0;\n\t\tbool update = true;\n\t\twhile(update){\n\t\t\tupdate = false;\n\t\t\tfor(int node_id = 0; node_id < V; node_id++){\n\t\t\t\tif(dist[node_id] == BIG_NUM)continue;\n\t\t\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\t\t\tEdge &e = G[node_id][i];\n\t\t\t\t\tif(e.capacity > 0 && dist[e.to] > dist[node_id]+e.cost){\n\t\t\t\t\t\tdist[e.to] = dist[node_id]+e.cost; //node_idを経由した方が早い場合\n\t\t\t\t\t\tpre_node[e.to] = node_id;\n\t\t\t\t\t\tpre_edge[e.to] = i;\n\t\t\t\t\t\tupdate = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(dist[sink] == BIG_NUM){\n\t\t\t//これ以上流せない\n\t\t\treturn -1;\n\t\t}\n\n\t\t//source-sink間最短路に沿って目いっぱい流す\n\t\tint tmp_flow = flow;\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\ttmp_flow = min(tmp_flow,G[pre_node[node_id]][pre_edge[node_id]].capacity);\n\t\t}\n\n\t\tflow -= tmp_flow;\n\t\tret += tmp_flow*dist[sink];\n\t\tfor(int node_id = sink; node_id != source; node_id = pre_node[node_id]){\n\t\t\tEdge &e = G[pre_node[node_id]][pre_edge[node_id]];\n\t\t\te.capacity -= tmp_flow;\n\t\t\tG[node_id][e.rev_index].capacity += tmp_flow;\n\t\t}\n\t}\n\treturn ret;\n}\n\nvoid func(){\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d %d\",&student[i].x,&student[i].y);\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tscanf(\"%d %d %d %d\",&house[i].x,&house[i].y,&house[i].capacity,&house[i].fee);\n\t}\n\n\tint ans = BIG_NUM;\n\tvector<int> HOUSE;\n\n\tint left,right,m;\n\tint cap_sum,fee_sum,house_num;\n\tint tmp_min,result1,result2;\n\tint source,sink;\n\n\tfor(int state = 1; state < POW[M]; state++){\n\n\t\tHOUSE.clear();\n\n\t\tcap_sum = 0,fee_sum = 0,house_num = 0;\n\t\tfor(int loop = 0; loop < M; loop++){\n\t\t\tif(state & (1 << loop)){\n\t\t\t\tcap_sum += house[loop].capacity;\n\t\t\t\tfee_sum += house[loop].fee;\n\t\t\t\tHOUSE.push_back(loop);\n\t\t\t\thouse_num++;\n\t\t\t}\n\t\t}\n\n\t\tif(cap_sum < N)continue; //そもそもN人収容できなければSKIP\n\n\t\t//Dの仮定値\n\t\tleft = 0,right = 4000,m = (left+right)/2;\n\t\ttmp_min = BIG_NUM;\n\n\t\tsource = 0,sink = N+house_num+1,V = N+house_num+2;\n\n\t\twhile(left <= right){\n\n\t\t\t//D == m+1の時の金額を求める\n\t\t\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\t\t\tfor(int i = 1; i <= N; i++){\n\t\t\t\tadd_edge(source,i,1,0); //sourceから各生徒に辺を張る\n\t\t\t}\n\n\t\t\tfor(int i = N+1; i <= N+house_num; i++){\n\t\t\t\tadd_edge(i,sink,house[HOUSE[i-(N+1)]].capacity,0); //各会場からsinkへエッジを張る\n\t\t\t}\n\n\t\t\tfor(int i = 1; i <= N; i++){ //各生徒から会場へ辺を張る\n\t\t\t\tfor(int k = N+1; k <= N+house_num; k++){\n\t\t\t\t\tadd_edge(i,k,1,max(0,abs(student[i-1].x-house[HOUSE[k-(N+1)]].x)\n\t\t\t\t\t\t\t+abs(student[i-1].y-house[HOUSE[k-(N+1)]].y)-(m+1)));\n\t\t\t\t}\n\t\t\t}\n\n\n\n\t\t\tresult1 = min_cost_flow(source,sink,N);\n\t\t\tresult1 += fee_sum + (m+1)*B*house_num; //会場使用料+シャトルバスの使用料を加算\n\n\t\t\t//D == mの時の金額を求める\n\n\t\t\tfor(int i = 0; i < NUM; i++)G[i].clear();\n\n\t\t\tfor(int i = 1; i <= N; i++){\n\t\t\t\tadd_edge(source,i,1,0); //sourceから各生徒に辺を張る\n\t\t\t}\n\n\t\t\tfor(int i = N+1; i <= N+house_num; i++){\n\t\t\t\tadd_edge(i,sink,house[HOUSE[i-(N+1)]].capacity,0); //各会場からsinkへエッジを張る\n\t\t\t}\n\n\t\t\tfor(int i = 1; i <= N; i++){ //各生徒から会場へ辺を張る\n\t\t\t\tfor(int k = N+1; k <= N+house_num; k++){\n\t\t\t\t\tadd_edge(i,k,1,max(0,abs(student[i-1].x-house[HOUSE[k-(N+1)]].x)\n\t\t\t\t\t\t\t+abs(student[i-1].y-house[HOUSE[k-(N+1)]].y)-m));\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tresult2 = min_cost_flow(source,sink,N);\n\t\t\tresult2 += fee_sum + m*B*house_num;\n\n\t\t\ttmp_min = min(tmp_min,min(result1,result2));\n\n\t\t\tif(result1 >= result2){ //Dの仮定値が最適値以上\n\t\t\t\tright = m-1; //より小さく\n\t\t\t}else{\n\t\t\t\tleft = m+1;\n\t\t\t}\n\t\t\tm = (left+right)/2;\n\t\t}\n\n\t\tans = min(ans,tmp_min);\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n}\n\nint main(){\n\n\tfor(int i = 0; i < 6; i++)POW[i] = pow(2,i);\n\n\twhile(true){\n\t\tscanf(\"%d %d %d\",&N,&M,&B);\n\t\tif(N == 0 && M == 0 && B == 0)break;\n\n\t\tfunc();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2530, "memory_kb": 3444, "score_of_the_acc": -1.0569, "final_rank": 6 }, { "submission_id": "aoj_0293_2510209", "code_snippet": "#include<bits/stdc++.h>\nint INF = (1<<20);\nusing namespace std;\n\nstruct edge{\n int to,pnt,cost,rev;\n edge(int to,int pnt,int cost,int rev)\n :to(to),pnt(pnt),cost(cost),rev(rev){}\n};\n\nint MAX_V=222;\nint S=MAX_V-2,T=MAX_V-1; \nint N,M,B;\nint ax[111],ay[111];\nint bx[5],by[5];\nint c[5],f[5];\nvector<edge> G[222];\nint dist[222];\nint prevv[222],preve[222];\n\nint min_cost_flow(int f){\n int ret = 0;\n while(f > 0){\n fill_n(dist,MAX_V,INF);\n dist[S] = 0;\n bool update = true;\n while(update){\n update = false;\n for(int v = 0; v < MAX_V;v++){\n if(dist[v] == INF) continue;\n for(int i=0;i<G[v].size();i++){\n edge &e = G[v][i];\n if(e.pnt > 0 && dist[e.to] > dist[v] + e.cost){\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n if(dist[T] == INF) return -1;\n int d = f;\n for(int v=T;v!=S;v=prevv[v]){\n d = min(d,G[prevv[v]][preve[v]].pnt);\n }\n f -= d;\n ret += d * dist[T];\n for(int v=T;v!=S;v=prevv[v]){\n edge &e = G[prevv[v]][preve[v]];\n e.pnt -= d;\n G[v][e.rev].pnt += d;\n }\n }\n return ret;\n}\n\nvoid add_edge(int from,int to,int pnt,int cost){\n G[from].push_back(edge(to,pnt,cost,G[to].size()));\n G[to].push_back(edge(from,0,-cost,G[from].size()-1));\n}\n\nvoid make_edge(int bit,int mid){\n fill_n(G,MAX_V,vector<edge>());\n for(int i=0;i<N;i++){\n add_edge(S,i,1,0);\n for(int j=0;j<M;j++){\n if((bit>>j&1)==0)continue;\n int d = abs(ax[i]-bx[j])+abs(ay[i]-by[j]);\n add_edge(i,N+j,1,max(0,d-mid));\n }\n }\n for(int i=0;i<M;i++){\n if((bit>i&1)==0)continue;\n add_edge(N+i,T,c[i],0);\n }\n}\n\nint search(int bit){\n int ret=0,cnt=0;\n for(int i=0;i<M;i++){\n if(bit&(1<<i)){\n ret += f[i];\n cnt++;\n }\n }\n int left=0,right=100000;\n while(right-left > 1){\n int mid = (left+right)/2;\n make_edge(bit,mid);\n int tmp1 = min_cost_flow(N)+mid*B*cnt;\n make_edge(bit,mid-1);\n int tmp2 = min_cost_flow(N)+(mid-1)*B*cnt;\n if(tmp1 == -1 || tmp2 == -1) return INF;\n if(tmp1 < tmp2) left = mid;\n else right = mid;\n }\n make_edge(bit,left);\n return ret+min_cost_flow(N)+left*B*cnt;\n}\n\nint main(){\n while(cin >> N >> M >> B, N) {\n for(int i=0;i<N;i++) cin >> ax[i] >> ay[i];\n for(int i=0;i<M;i++) cin >> bx[i] >> by[i] >> c[i] >> f[i];\n int ans = INF;\n for(int i=1;i<(1<<M);i++){\n ans = min(ans,search(i));\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 3790, "memory_kb": 3136, "score_of_the_acc": -0.4754, "final_rank": 1 } ]
aoj_0290_cpp
微生物発電 飯沼博士は磐梯山の噴気孔でふしぎな微生物を見つけました。この微生物の雄と雌1体ずつが合体すると、電気エネルギーを放出します。この微生物を研究すれば、将来のエネルギー危機から我々を救えるかもしれません。 観察を続けると、微生物は合体したときだけ電気エネルギーを発生させることと、合体した微生物のさらなる合体はないことがわかりました。さらに観察を続けると、合体で放出される電気エネルギーは、微生物が体内に持つ未知の粒子(博士はこれを磐梯山にちなんでB粒子と名づけました)の量で決まることがわかりました。合体する雄と雌が体内に持つB粒子の量をそれぞれ bm と bw とすると、合体により放出される電気エネルギーは | bm - bw | × (| bm - bw | - 30) 2 という式で計算できます。 この発見により、微生物の集団から得られる最大の電気エネルギーが計算できるようになりました。それでは、微生物の集団に含まれる雄と雌の数と、各個体が持つB粒子の量が与えられたとき、この微生物の集団から得られる最大の電気エネルギーを計算するプログラムを作成してください。 入力 入力は複数のデータセットからなる。入力の終わりはゼロ2つの行で示される。入力データは以下の形式で与えられる。 M W bm 1 bm 2 ... bm M bw 1 bw 2 ... bw W 1行目の M と W (1 ≤ M,W ≤ 12) はそれぞれ雄と雌の微生物の数である。2行目に、 i 番目の雄が体内に持つB粒子の量 bm i (0 ≤ bm i ≤ 50) が与えられる。3行目に、 i 番目の雌が体内に持つB粒子の量 bw i (0 ≤ bw i ≤ 50) が与えられる。 データセットの数は 20 を超えない。 出力 データセットごとに、微生物の集団から得られる電気エネルギーの最大値を1行に出力する。 入出力例 入力例 3 3 0 20 30 10 20 30 10 10 32 10 15 8 20 10 6 45 50 41 18 0 37 25 45 11 25 21 32 27 7 3 23 14 39 6 47 16 23 19 37 8 0 0 出力例 12000 53906 11629
[ { "submission_id": "aoj_0290_5934872", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nint dp[13][(1<<12)+2];\nvoid solve(int m,int w){\n vector<int>bm(max(m,w)),bw(max(m,w));\n for(int i = 0; max(m,w) > i; i++){\n bm[i] = bw[i] = -1;\n }\n for(int i = 0; m > i; i++){\n cin>>bm[i];\n }\n for(int i = 0; w > i; i++){\n cin>>bw[i];\n }\n\n \n for(int i = 0; 13 > i; i++){\n for(int j = 0; (1<<12)+1 >= j; j++){\n dp[i][j] = -1;\n }\n }\n\n dp[0][0] = 0;\n for(int i = 1; max(m,w)+1 > i; i++){\n for(int j = 0; (1<<max(m,w)) > j; j++){\n for(int k = 0; max(m,w) > k; k++){\n if(!(j & (1<<k))){\n int ad = abs(bm[i-1]-bw[k]) * (abs(bm[i-1]-bw[k]) - 30)*(abs(bm[i-1]-bw[k]) - 30);\n if(bm[i-1] == -1 || bw[k] == -1)ad = 0;\n if(dp[i][j+(1<<k)] == -1)dp[i][j+(1<<k)] = dp[i-1][j]+ad;\n else dp[i][j+(1<<k)] = max(dp[i][j+(1<<k)],dp[i-1][j]+ad);\n }\n }\n }\n }\n cout << dp[max(m,w)][(1<<max(m,w))-1] << endl;\n return;\n}\n\nint main(){\n int m,w;\n while(cin>>m>>w,m){\n solve(m,w);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3620, "score_of_the_acc": -0.0467, "final_rank": 13 }, { "submission_id": "aoj_0290_4976667", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define chmin(a,b) a=min(a,b)\n#define chmax(a,b) a=max(a,b)\n#define mod 1000000007\n#define ad(a,b) a=(a+b)%mod;\n#define X 5010\nll po(ll x,ll y){\n\tll res=1;\n\tfor(;y;y>>=1){\n\t\tif(y&1)res=res*x%mod;\n\t\tx=x*x%mod;\n\t}\n\treturn res;\n}\nll fac[X],ivf[X];\nvoid init(){\n\tfac[0]=1;\n\tfor(ll i=1;i<X;i++)fac[i]=fac[i-1]*i%mod;\n\tfor(ll i=0;i<X;i++)ivf[i]=po(fac[i],mod-2);\n}\nll C(ll n,ll k){\n\treturn fac[n]*ivf[n-k]%mod*ivf[k]%mod;\n}\nbool solve(){\n\tll n,m;\n\tcin>>n>>m;\n\tif(n==0&&m==0)return 0;\n\tll a[12],b[12];\n\trep(i,n)cin>>a[i];\n\trep(j,m)cin>>b[j];\n\tll dp[(1<<12)];\n\trep(i,(1<<n))dp[i]=-1e17;\n\tdp[0]=0;\n\trep(j,m){\n\t\tvector<ll> id,val;\n\t\trep(i,n)rep(s,(1<<n)){\n\t\t\tif(s&(1<<i))continue;\n\t\t\tid.push_back(s+(1<<i));\n\t\t\tll dif=abs(a[i]-b[j]);\n\t\t\tll cost=dif*(dif-30)*(dif-30);\n\t\t\tval.push_back(dp[s]+cost);\n\t\t}\n\t\trep(i,id.size()){\n\t\t\tchmax(dp[id[i]],val[i]);\n\t\t}\n\t}\n\tll ans=-1e17;\n\trep(s,(1<<n))chmax(ans,dp[s]);\n\tcout<<ans<<endl;\n\treturn 1;\n}\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\twhile(solve()){}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3636, "score_of_the_acc": -0.0363, "final_rank": 12 }, { "submission_id": "aoj_0290_3657282", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <utility>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <cmath>\n#include <cassert>\nusing namespace std;\nusing ll = long long;\nconst int INF = 1<<30;\nconst int MOD = 1e9 + 7;\nint M, W;\nvector<int> a, b;\nint dp[1<<12][1<<12];\nint calc(int s, int t)\n{\n int k = abs(a[s] - b[t]);\n return k * (k - 30) * (k - 30);\n}\nint dfs(int wbit, int mbit, int pos)\n{\n if(pos >= W) return 0;\n if(dp[wbit][mbit] != -1) return dp[wbit][mbit];\n int res = dfs(wbit, mbit, pos + 1);\n if(mbit & (1<<pos))\n {\n for(int i = 0; i < W; i++)\n {\n if(not (wbit & (1<<i)) or a[i] == b[pos]) continue;\n res = max(res, dfs(wbit & ~(1<<i), mbit & ~(1<<pos), pos + 1) + calc(i, pos));\n }\n }\n return dp[wbit][mbit] = res;\n}\nsigned main()\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n while(cin >> M >> W, M or W)\n {\n memset(dp, -1, sizeof(dp));\n a.resize(M);\n b.resize(W);\n for(int i = 0; i < M; i++) cin >> a[i];\n for(int i = 0; i < W; i++) cin >> b[i];\n if(M > W)\n {\n swap(M, W);\n swap(a, b);\n }\n int ans = 0;\n for(int bit = 0; bit < (1<<W); bit++)\n {\n if(__builtin_popcount(bit) != M) continue;\n ans = max(ans, dfs((1<<M) - 1, bit, 0));\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 68696, "score_of_the_acc": -1.4255, "final_rank": 19 }, { "submission_id": "aoj_0290_3657139", "code_snippet": "#include<bits/stdc++.h>\n#define LL long long\n#define REP(i,n) for(int i=0;i<(n);++i)\n#define lp(i,n) for(int i=0;i<(n);++i)\n#define REPA(i,n) for(int i=1;i<(n);++i)\n#define PII pair<int,int>\n#define PLI pair<long long, int>\n#define PLL pair<long long, long long>\n#define MOD ((int)1e9 + 7)\n#define INF ((int)1e9)\n#define INFLL ((LL)1e18)\n#define ALL(x) (x).begin(),(x).end()\n#define ctoi(x) (x - 'a') \n#define CTOI(x) (x - 'A')\n#define BIT(x) (1 << (x))\nusing namespace std;\n\nLL modinv(LL a){\n LL b = MOD, u = 1, v = 0;\n while(b){\n LL t = a / b;\n a -= t * b;swap(a, b);\n u -= t * v;swap(u, v);\n }\n u%=MOD;\n if(u < 0) u += MOD;\n return u;\n\n}\nLL exp(int a, int b){\n LL res = 1;\n LL sum = a;\n while(b){\n if(b&1)res = (res * sum) % MOD;\n sum = (sum * sum) % MOD;\n b>>=1;\n }\n return res;\n}\n\nint cul(int a, int b){\n int c = abs(a-b);\n return c * (c - 30) * (c - 30);\n}\n\nint M, W;\nvector<int> m(M), w(W);\nvector<vector<int> > dp;\n\nint func(int used, int place){\n if(place == M)return 0;\n if(dp[place][used] >= 0)return dp[place][used];\n int res = 0;\n REP(i, W){\n if(used & BIT(i))continue;\n res = max(res, cul(m[place], w[i]) + func(used | BIT(i), place + 1));\n }\n return res;\n}\nint main(){\n while(cin >> M >> W && M){\n m = vector<int>(M);\n w = vector<int>(W);\n REP(i, M)cin>>m[i];\n REP(i, W)cin>>w[i];\n if(m > w){\n swap(m, w);\n swap(M, W);\n }\n dp.resize(M, vector<int>(1<<W, -1));\n cout << func(0, 0) << endl;\n dp.clear();\n }\n return 0;\n}", "accuracy": 0.1, "time_ms": 410, "memory_kb": 3188, "score_of_the_acc": -0.4552, "final_rank": 20 }, { "submission_id": "aoj_0290_3656537", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nusing ll = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b)a=b;};\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b)a=b;};\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n Int m,w;\n while(cin>>m>>w,m||w){\n vector<Int> as(m),bs(w);\n for(Int i=0;i<m;i++) cin>>as[i];\n for(Int i=0;i<w;i++) cin>>bs[i];\n\n auto calc=[&](Int i,Int j)->Int{\n Int dif=abs(as[i]-bs[j]);\n return dif*(dif-30)*(dif-30);\n };\n\n Int s=1<<w;\n const Int INF = 1e15; \n vector<Int> dp(s,-INF);\n dp[0]=0;\n for(Int i=0;i<m;i++){\n vector<Int> nx(s,-INF);\n for(Int b=0;b<s;b++){\n\tchmax(nx[b],dp[b]);\n\tfor(Int j=0;j<w;j++){\n\t if((b>>j)&1) continue;\n\t chmax(nx[b|(1<<j)],dp[b]+calc(i,j));\t\t \n\t}\n }\n swap(dp,nx);\n }\n cout<<*max_element(dp.begin(),dp.end())<<endl;\n } \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3204, "score_of_the_acc": -0.0299, "final_rank": 10 }, { "submission_id": "aoj_0290_2242892", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<functional>\n#include<map>\n#include<cstring>\n#include<unordered_map>\n#include<set>\n#include<string.h>\n#define int long long\nusing namespace std;\n\nint a, b;\nint c[12], d[12];\nint dp[13][1 << 12];//i???????????§??????j?????£??????????????§???\nvoid saiki(int e, int f) {\n\tdp[e + 1][f] = dp[e][f];\n\tfor (int i = 0; i < b; i++) {\n\t\tif (f&(1ll << i)) {\n\t\t\tdp[e + 1][f - (1ll << i)] = max(dp[e+1][f-(1ll<<i)], dp[e][f] + abs(c[e] - d[i])*(abs(c[e] - d[i]) - 30)*(abs(c[e] - d[i]) - 30));\n\t\t}\n\t}\n}\nsigned main() {\n\twhile (cin >> a >> b, a | b) {\n\t\tmemset(dp, 0, sizeof(dp));\n\t\tfor (int e = 0; e < a; e++)cin >> c[e];\n\t\tfor (int e = 0; e < b; e++)cin >> d[e];\n\t\tfor (int e = 0; e < a; e++) {\n\t\t\tfor (int f = 0; f < (1ll << b); f++) {\n\t\t\t\tsaiki(e, f);\n\t\t\t}\n\t\t}\n\t\tcout << *max_element(dp[a], dp[a] + (1 << 12)) << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3508, "score_of_the_acc": -0.0344, "final_rank": 11 }, { "submission_id": "aoj_0290_2140751", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\ntypedef long long int ll;\n\nusing namespace std;\n\nstruct Info{\n\tInfo(){\n\t\tindex = 0;\n\t\tfor(int i = 0; i < 12; i++)check[i] = false;\n\t}\n\n\tshort table[6],index;\n\tbool check[12];\n};\n\nint table_2[2][2],table_3[6][3],table_4[24][4],table_5[120][5],table_6[720][6];\n\nvoid func(int M,int W){\n\tint m_data[M],w_data[W];\n\n\tfor(int i = 0; i < M; i++)scanf(\"%d\",&m_data[i]);\n\tfor(int i = 0; i < W; i++)scanf(\"%d\",&w_data[i]);\n\n\tint maximum = 0,tmp,select_num,num,left_index,right_index,left_tmp,right_tmp,left_max,right_max,limit,loc_left[7],loc_right[7],index,val,calc[7];\n\n\tif(M == 1){\n\t\tfor(int i = 0; i < W; i++){\n\t\t\ttmp = abs(w_data[i] - m_data[0])*(abs(w_data[i] - m_data[0])-30)*(abs(w_data[i] - m_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else if(W == 1){\n\t\tfor(int i = 0; i < M; i++){\n\t\t\ttmp = abs(m_data[i] - w_data[0])*(abs(m_data[i] - w_data[0])-30)*(abs(m_data[i] - w_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else{\n\t\tif(M > W){\n\t\t\tselect_num = (M+1)/2;\n\n\t\t\tlimit = pow(2,M);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\t//??°???????????????????????????\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(w_data[0] - m_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]];\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]];\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]];\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]];\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],\n\t\t\t\t\t\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]],calc[5] = m_data[loc_left[5]];\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(w_data[W-1] - m_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]];\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]];\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]];\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]];\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],\n\t\t\t\t\t\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]],calc[5] = m_data[loc_right[5]];\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\n\t\t}else{ //W >= M\n\t\t\tselect_num = (W+1)/2;\n\n\t\t\tlimit = pow(2,W);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(m_data[0] - w_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]];\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]];\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]];\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]];\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],\n\t\t\t\t\t\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]],calc[5] = w_data[loc_left[5]];\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(m_data[M-1] - w_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]];\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]];\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]];\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]];\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],\n\t\t\t\t\t\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]],calc[5] = w_data[loc_right[5]];\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",maximum);\n}\n\n\nint main(){\n\n\tint M,W,index_2 = 0,index_3 = 0,index_4 = 0, index_5 = 0,index_6 = 0;\n\n\tfor(int a = 0; a < 2; a++){\n\t\tfor(int b = 0; b < 2; b++){\n\t\t\tif(a != b){\n\t\t\t\ttable_2[index_2][0] = a,table_2[index_2][1] = b;\n\t\t\t\tindex_2++;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 3; a++){\n\t\tfor(int b = 0; b < 3; b++){\n\t\t\tfor(int c = 0; c < 3; c++){\n\t\t\t\tif(a != b && a != c && b != c){\n\t\t\t\t\ttable_3[index_3][0] = a,table_3[index_3][1] = b,table_3[index_3][2] = c;\n\t\t\t\t\tindex_3++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 4; a++){\n\t\tfor(int b = 0; b < 4; b++){\n\t\t\tfor(int c = 0; c < 4; c++){\n\t\t\t\tfor(int d = 0; d < 4; d++){\n\t\t\t\t\tif(a != b && a != c && a != d && b != c && b != d && c != d){\n\t\t\t\t\t\ttable_4[index_4][0] = a,table_4[index_4][1] = b,table_4[index_4][2] = c,table_4[index_4][3] = d;\n\t\t\t\t\t\tindex_4++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 5; a++){\n\t\tfor(int b = 0; b < 5; b++){\n\t\t\tfor(int c = 0; c < 5; c++){\n\t\t\t\tfor(int d = 0; d < 5; d++){\n\t\t\t\t\tfor(int e = 0; e < 5; e++){\n\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && b != c && b != d && b != e && c != d && c != e && d != e){\n\t\t\t\t\t\t\ttable_5[index_5][0] = a,table_5[index_5][1] = b,table_5[index_5][2] = c,table_5[index_5][3] = d,table_5[index_5][4] = e;\n\t\t\t\t\t\t\tindex_5++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 6; a ++){\n\t\tfor(int b = 0; b < 6; b++){\n\t\t\tfor(int c = 0; c < 6; c++){\n\t\t\t\tfor(int d = 0; d < 6; d++){\n\t\t\t\t\tfor(int e = 0; e < 6; e++){\n\t\t\t\t\t\tfor(int f = 0; f < 6; f++){\n\t\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && a != f && b != c && b != d && b != e && b != f && c != d && c != e && c != f && d != e && d != f && e != f){\n\t\t\t\t\t\t\t\ttable_6[index_6][0] = a,table_6[index_6][1] = b,table_6[index_6][2] = c,table_6[index_6][3] = d,table_6[index_6][4] = e,table_6[index_6][5] = f;\n\t\t\t\t\t\t\t\tindex_6++;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&M,&W);\n\t\tif(M == 0 && W == 0)break;\n\n\t\tfunc(M,W);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 2940, "score_of_the_acc": -0.0898, "final_rank": 16 }, { "submission_id": "aoj_0290_2139377", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nstruct Info{\n\tInfo(){\n\t\tindex = 0;\n\t\tfor(int i = 0; i < 12; i++)check[i] = false;\n\t}\n\n\tshort table[6],index;\n\tbool check[12];\n};\n\nint table_2[2][2],table_3[6][3],table_4[24][4],table_5[120][5],table_6[720][6];\n\nvoid func(int M,int W){\n\tint m_data[M],w_data[W];\n\n\tfor(int i = 0; i < M; i++)scanf(\"%d\",&m_data[i]);\n\tfor(int i = 0; i < W; i++)scanf(\"%d\",&w_data[i]);\n\n\tint maximum = 0,tmp,select_num,num,left_index,right_index,left_tmp,right_tmp,left_max,right_max,limit,loc_left[7],loc_right[7],index,val,calc[7];\n\n\tif(M == 1){\n\t\tfor(int i = 0; i < W; i++){\n\t\t\ttmp = abs(w_data[i] - m_data[0])*(abs(w_data[i] - m_data[0])-30)*(abs(w_data[i] - m_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else if(W == 1){\n\t\tfor(int i = 0; i < M; i++){\n\t\t\ttmp = abs(m_data[i] - w_data[0])*(abs(m_data[i] - w_data[0])-30)*(abs(m_data[i] - w_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else{\n\t\tif(M > W){\n\t\t\tselect_num = (M+1)/2;\n\n\t\t\tlimit = pow(2,M);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\t//??°???????????????????????????\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(w_data[0] - m_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],\n\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]],calc[5] = m_data[loc_left[5]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(w_data[W-1] - m_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],\n\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]],calc[5] = m_data[loc_right[5]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\n\t\t}else{ //W >= M\n\t\t\tselect_num = (W+1)/2;\n\n\t\t\tlimit = pow(2,W);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(m_data[0] - w_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],\n\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]],calc[5] = w_data[loc_left[5]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(m_data[M-1] - w_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],\n\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]],calc[5] = w_data[loc_right[5]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",maximum);\n}\n\n\nint main(){\n\n\tint M,W,index_2 = 0,index_3 = 0,index_4 = 0, index_5 = 0,index_6 = 0;\n\n\tfor(int a = 0; a < 2; a++){\n\t\tfor(int b = 0; b < 2; b++){\n\t\t\tif(a != b){\n\t\t\t\ttable_2[index_2][0] = a,table_2[index_2][1] = b;\n\t\t\t\tindex_2++;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 3; a++){\n\t\tfor(int b = 0; b < 3; b++){\n\t\t\tfor(int c = 0; c < 3; c++){\n\t\t\t\tif(a != b && a != c && b != c){\n\t\t\t\t\ttable_3[index_3][0] = a,table_3[index_3][1] = b,table_3[index_3][2] = c;\n\t\t\t\t\tindex_3++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 4; a++){\n\t\tfor(int b = 0; b < 4; b++){\n\t\t\tfor(int c = 0; c < 4; c++){\n\t\t\t\tfor(int d = 0; d < 4; d++){\n\t\t\t\t\tif(a != b && a != c && a != d && b != c && b != d && c != d){\n\t\t\t\t\t\ttable_4[index_4][0] = a,table_4[index_4][1] = b,table_4[index_4][2] = c,table_4[index_4][3] = d;\n\t\t\t\t\t\tindex_4++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 5; a++){\n\t\tfor(int b = 0; b < 5; b++){\n\t\t\tfor(int c = 0; c < 5; c++){\n\t\t\t\tfor(int d = 0; d < 5; d++){\n\t\t\t\t\tfor(int e = 0; e < 5; e++){\n\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && b != c && b != d && b != e && c != d && c != e && d != e){\n\t\t\t\t\t\t\ttable_5[index_5][0] = a,table_5[index_5][1] = b,table_5[index_5][2] = c,table_5[index_5][3] = d,table_5[index_5][4] = e;\n\t\t\t\t\t\t\tindex_5++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int a = 0; a < 6; a ++){\n\t\tfor(int b = 0; b < 6; b++){\n\t\t\tfor(int c = 0; c < 6; c++){\n\t\t\t\tfor(int d = 0; d < 6; d++){\n\t\t\t\t\tfor(int e = 0; e < 6; e++){\n\t\t\t\t\t\tfor(int f = 0; f < 6; f++){\n\t\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && a != f && b != c && b != d && b != e && b != f && c != d && c != e && c != f && d != e && d != f && e != f){\n\t\t\t\t\t\t\t\ttable_6[index_6][0] = a,table_6[index_6][1] = b,table_6[index_6][2] = c,table_6[index_6][3] = d,table_6[index_6][4] = e,table_6[index_6][5] = f;\n\t\t\t\t\t\t\t\tindex_6++;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&M,&W);\n\t\tif(M == 0 && W == 0)break;\n\n\t\tfunc(M,W);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 2860, "score_of_the_acc": -0.0887, "final_rank": 15 }, { "submission_id": "aoj_0290_2139367", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nstruct Info{\n\tInfo(){\n\t\tindex = 0;\n\t\tfor(int i = 0; i < 12; i++)check[i] = false;\n\t}\n\n\tshort table[6],index;\n\tbool check[12];\n};\n\nint table_2[2][2],table_3[6][3],table_4[24][4],table_5[120][5],table_6[720][6];\n\nvoid func(int M,int W){\n\tint m_data[M],w_data[W];\n\n\tfor(int i = 0; i < M; i++)scanf(\"%d\",&m_data[i]);\n\tfor(int i = 0; i < W; i++)scanf(\"%d\",&w_data[i]);\n\n\tint maximum = 0,tmp,select_num,num,left_index,right_index,left_tmp,right_tmp,left_max,right_max,limit,loc_left[7],loc_right[7],index,val,calc[7];\n\n\tif(M == 1){\n\t\tfor(int i = 0; i < W; i++){\n\t\t\ttmp = abs(w_data[i] - m_data[0])*(abs(w_data[i] - m_data[0])-30)*(abs(w_data[i] - m_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else if(W == 1){\n\t\tfor(int i = 0; i < M; i++){\n\t\t\ttmp = abs(m_data[i] - w_data[0])*(abs(m_data[i] - w_data[0])-30)*(abs(m_data[i] - w_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else{\n\t\tif(M > W){\n\t\t\tselect_num = (M+1)/2;\n\n\t\t\tlimit = pow(2,M);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\t//??°???????????????????????????\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(w_data[0] - m_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],calc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_left[0]],calc[1] = m_data[loc_left[1]],calc[2] = m_data[loc_left[2]],\n\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_left[3]],calc[4] = m_data[loc_left[4]],calc[5] = m_data[loc_left[5]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(w_data[W-1] - m_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_2[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_3[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_4[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],calc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_5[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = m_data[loc_right[0]],calc[1] = m_data[loc_right[1]],calc[2] = m_data[loc_right[2]],\n\t\t\t\t\t\t\t\tcalc[3] = m_data[loc_right[3]],calc[4] = m_data[loc_right[4]],calc[5] = m_data[loc_right[5]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - calc[table_6[index][p-((W+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\n\t\t}else{ //W >= M\n\t\t\tselect_num = (W+1)/2;\n\n\t\t\tlimit = pow(2,W);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tif(left_index == 1){\n\t\t\t\t\tval = abs(m_data[0] - w_data[loc_left[0]]);\n\t\t\t\t\tleft_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t}else if(left_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(left_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],calc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //left_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_left[0]],calc[1] = w_data[loc_left[1]],calc[2] = w_data[loc_left[2]],\n\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_left[3]],calc[4] = w_data[loc_left[4]],calc[5] = w_data[loc_left[5]];\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p]]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tif(right_index == 1){\n\t\t\t\t\tval = abs(m_data[M-1] - w_data[loc_right[0]]);\n\t\t\t\t\tright_tmp = val*(val-30)*(val-30);\n\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t}else if(right_index == 2){\n\t\t\t\t\tfor(index = 0; index < 2; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_2[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 3){\n\t\t\t\t\tfor(index = 0; index < 6; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_3[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 4){\n\t\t\t\t\tfor(index = 0; index < 24; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_4[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\n\t\t\t\t}else if(right_index == 5){\n\t\t\t\t\tfor(index = 0;index < 120; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],calc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_5[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}else{ //right_index == 6\n\t\t\t\t\tfor(index = 0;index < 720; index++){\n\t\t\t\t\t\tcalc[0] = w_data[loc_right[0]],calc[1] = w_data[loc_right[1]],calc[2] = w_data[loc_right[2]],\n\t\t\t\t\t\t\t\tcalc[3] = w_data[loc_right[3]],calc[4] = w_data[loc_right[4]],calc[5] = w_data[loc_right[5]];\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - calc[table_6[index][p-((M+1)/2)]]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",maximum);\n}\n\n\nint main(){\n\n\tint M,W,index_2 = 0,index_3 = 0,index_4 = 0, index_5 = 0,index_6 = 0;\n\n\tfor(int a = 0; a < 6; a ++){\n\t\tfor(int b = 0; b < 6; b++){\n\t\t\tif(a < 2 && b < 2){\n\t\t\t\tif(a != b){\n\t\t\t\t\ttable_2[index_2][0] = a,table_2[index_2][1] = b;\n\t\t\t\t\tindex_2++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int c = 0; c < 6; c++){\n\t\t\t\tif(a < 3 && b < 3 && c < 3){\n\t\t\t\t\tif(a != b && a != c && b != c){\n\t\t\t\t\t\ttable_3[index_3][0] = a,table_3[index_3][1] = b,table_3[index_3][2] = c;\n\t\t\t\t\t\tindex_3++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor(int d = 0; d < 6; d++){\n\t\t\t\t\tif(a < 4 && b < 4 && c < 4 && d < 4){\n\t\t\t\t\t\tif(a != b && a != c && a != d && b != c && b != d && c != d){\n\t\t\t\t\t\t\ttable_4[index_4][0] = a,table_4[index_4][1] = b,table_4[index_4][2] = c,table_4[index_4][3] = d;\n\t\t\t\t\t\t\tindex_4++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tfor(int e = 0; e < 6; e++){\n\t\t\t\t\t\tif(a < 5 && b < 5 && c < 5 && d < 5 && e < 5){\n\t\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && b != c && b != d && b != e && c != d && c != e && d != e){\n\t\t\t\t\t\t\t\ttable_5[index_5][0] = a,table_5[index_5][1] = b,table_5[index_5][2] = c,table_5[index_5][3] = d,table_5[index_5][4] = e;\n\t\t\t\t\t\t\t\tindex_5++;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\tfor(int f = 0; f < 6; f++){\n\t\t\t\t\t\t\tif(a != b && a != c && a != d && a != e && a != f && b != c && b != d && b != e && b != f && c != d && c != e && c != f && d != e && d != f && e != f){\n\t\t\t\t\t\t\t\ttable_6[index_6][0] = a,table_6[index_6][1] = b,table_6[index_6][2] = c,table_6[index_6][3] = d,table_6[index_6][4] = e,table_6[index_6][5] = f;\n\t\t\t\t\t\t\t\tindex_6++;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&M,&W);\n\t\tif(M == 0 && W == 0)break;\n\n\t\tfunc(M,W);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 2864, "score_of_the_acc": -0.0994, "final_rank": 17 }, { "submission_id": "aoj_0290_2139273", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nstruct Info{\n\tInfo(){\n\t\tindex = 0;\n\t\tfor(int i = 0; i < 12; i++)check[i] = false;\n\t}\n\n\tshort table[6],index;\n\tbool check[12];\n};\n\nvoid func(int M,int W){\n\tint m_data[M],w_data[W];\n\n\tfor(int i = 0; i < M; i++)scanf(\"%d\",&m_data[i]);\n\tfor(int i = 0; i < W; i++)scanf(\"%d\",&w_data[i]);\n\n\tint maximum = 0,tmp,select_num,num,left_index,right_index,left_tmp,right_tmp,left_max,right_max,limit,loc_left[7],loc_right[7],val;\n\n\tif(M == 1){\n\t\tfor(int i = 0; i < W; i++){\n\t\t\ttmp = abs(w_data[i] - m_data[0])*(abs(w_data[i] - m_data[0])-30)*(abs(w_data[i] - m_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else if(W == 1){\n\t\tfor(int i = 0; i < M; i++){\n\t\t\ttmp = abs(m_data[i] - w_data[0])*(abs(m_data[i] - w_data[0])-30)*(abs(m_data[i] - w_data[0])-30);\n\t\t\tmaximum = max(maximum,tmp);\n\t\t}\n\t}else{\n\t\tif(M > W){\n\t\t\tselect_num = (M+1)/2;\n\n\t\t\tlimit = pow(2,M);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\t//??°???????????????????????????\n\t\t\t\tfor(int k = 0; k < M; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tqueue<Info> Q;\n\t\t\t\tInfo current,left_first,right_first;\n\n\t\t\t\tfor(int k = 0; k < left_index;k++){\n\t\t\t\t\tleft_first.check[loc_left[k]] = true;\n\t\t\t\t}\n\n\t\t\t\tQ.push(left_first);\n\n\t\t\t\twhile(!Q.empty()){\n\t\t\t\t\tcurrent = Q.front();\n\t\t\t\t\tQ.pop();\n\n\t\t\t\t\tif(current.index == left_index){\n\t\t\t\t\t\tleft_tmp = 0;\n\t\t\t\t\t\tfor(int p = 0; p < (W+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - current.table[p]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tfor(int p = 0; p < left_index; p++){\n\t\t\t\t\t\tif(current.check[loc_left[p]]){\n\t\t\t\t\t\t\tInfo new_info;\n\t\t\t\t\t\t\tfor(int k = 0; k < 12; k++)new_info.check[k] = current.check[k];\n\t\t\t\t\t\t\tfor(int k = 0; k < current.index;k++)new_info.table[k] = current.table[k];\n\t\t\t\t\t\t\tnew_info.table[current.index] = m_data[loc_left[p]];\n\t\t\t\t\t\t\tnew_info.check[loc_left[p]] = false;\n\t\t\t\t\t\t\tnew_info.index = current.index+1;\n\t\t\t\t\t\t\tQ.push(new_info);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tfor(int k = 0; k < right_index;k++){\n\t\t\t\t\tright_first.check[loc_right[k]] = true;\n\t\t\t\t}\n\n\t\t\t\tQ.push(right_first);\n\n\t\t\t\twhile(!Q.empty()){\n\t\t\t\t\tcurrent = Q.front();\n\t\t\t\t\tQ.pop();\n\n\t\t\t\t\tif(current.index == right_index){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (W+1)/2; p < W;p++){\n\t\t\t\t\t\t\tval = abs(w_data[p] - current.table[p-((W+1)/2)]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tfor(int p = 0; p < right_index; p++){\n\t\t\t\t\t\tif(current.check[loc_right[p]]){\n\t\t\t\t\t\t\tInfo new_info;\n\t\t\t\t\t\t\tfor(int k = 0; k < 12; k++)new_info.check[k] = current.check[k];\n\t\t\t\t\t\t\tfor(int k = 0; k < current.index;k++)new_info.table[k] = current.table[k];\n\t\t\t\t\t\t\tnew_info.table[current.index] = m_data[loc_right[p]];\n\t\t\t\t\t\t\tnew_info.check[loc_right[p]] = false;\n\t\t\t\t\t\t\tnew_info.index = current.index+1;\n\t\t\t\t\t\t\tQ.push(new_info);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\n\t\t}else{ //W >= M\n\t\t\tselect_num = (W+1)/2;\n\n\t\t\tlimit = pow(2,W);\n\t\t\tfor(int i = 0; i < limit;i++){\n\t\t\t\tnum = 0;\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k))num++;\n\t\t\t\t}\n\t\t\t\tif(num != select_num)continue;\n\n\t\t\t\tleft_index = right_index = 0;\n\n\t\t\t\tfor(int k = 0; k < W; k++){\n\t\t\t\t\tif(i & (1 << k)){\n\t\t\t\t\t\tloc_left[left_index++] = k;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tloc_right[right_index++] = k;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tleft_max = right_max = 0;\n\n\t\t\t\tqueue<Info> Q;\n\t\t\t\tInfo current,left_first,right_first;\n\n\t\t\t\tfor(int k = 0; k < left_index;k++){\n\t\t\t\t\tleft_first.check[loc_left[k]] = true;\n\t\t\t\t}\n\n\t\t\t\tQ.push(left_first);\n\n\t\t\t\twhile(!Q.empty()){\n\t\t\t\t\tcurrent = Q.front();\n\t\t\t\t\tQ.pop();\n\n\t\t\t\t\tif(current.index == left_index){\n\t\t\t\t\t\tleft_tmp = 0;\n\n\t\t\t\t\t\tfor(int p = 0; p < (M+1)/2;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - current.table[p]);\n\t\t\t\t\t\t\tleft_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tleft_max = max(left_max,left_tmp);\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tfor(int p = 0; p < left_index; p++){\n\t\t\t\t\t\tif(current.check[loc_left[p]] == true){\n\t\t\t\t\t\t\tInfo new_info;\n\t\t\t\t\t\t\tfor(int k = 0; k < W; k++)new_info.check[k] = current.check[k];\n\t\t\t\t\t\t\tfor(int k = 0; k < current.index;k++)new_info.table[k] = current.table[k];\n\t\t\t\t\t\t\tnew_info.table[current.index] = w_data[loc_left[p]];\n\t\t\t\t\t\t\tnew_info.check[loc_left[p]] = false;\n\t\t\t\t\t\t\tnew_info.index = current.index+1;\n\t\t\t\t\t\t\tQ.push(new_info);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tfor(int k = 0; k < right_index;k++){\n\t\t\t\t\tright_first.check[loc_right[k]] = true;\n\t\t\t\t}\n\n\t\t\t\tQ.push(right_first);\n\n\t\t\t\twhile(!Q.empty()){\n\t\t\t\t\tcurrent = Q.front();\n\t\t\t\t\tQ.pop();\n\n\t\t\t\t\tif(current.index == right_index){\n\t\t\t\t\t\tright_tmp = 0;\n\t\t\t\t\t\tfor(int p = (M+1)/2; p < M;p++){\n\t\t\t\t\t\t\tval = abs(m_data[p] - current.table[p-((M+1)/2)]);\n\t\t\t\t\t\t\tright_tmp += val*(val-30)*(val-30);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tright_max = max(right_max,right_tmp);\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tfor(int p = 0; p < right_index; p++){\n\t\t\t\t\t\tif(current.check[loc_right[p]]){\n\t\t\t\t\t\t\tInfo new_info;\n\t\t\t\t\t\t\tfor(int k = 0; k < W; k++)new_info.check[k] = current.check[k];\n\t\t\t\t\t\t\tfor(int k = 0; k < current.index;k++)new_info.table[k] = current.table[k];\n\t\t\t\t\t\t\tnew_info.table[current.index] = w_data[loc_right[p]];\n\t\t\t\t\t\t\tnew_info.check[loc_right[p]] = false;\n\t\t\t\t\t\t\tnew_info.index = current.index+1;\n\t\t\t\t\t\t\tQ.push(new_info);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tmaximum = max(maximum,left_max+right_max);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",maximum);\n}\n\n\nint main(){\n\n\tint M,W;\n\n\twhile(true){\n\t\tscanf(\"%d %d\",&M,&W);\n\t\tif(M == 0 && W == 0)break;\n\n\t\tfunc(M,W);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 2916, "score_of_the_acc": -1.0257, "final_rank": 18 }, { "submission_id": "aoj_0290_2059239", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint M,W;\nint bm[15];\nint bw[15];\nint dp[15][1<<15];\nint en(int a,int b){\n\tint x=abs(a-b);\n\treturn x*(x-30)*(x-30);\n}\nint main()\n{\n\twhile(true){\n\t\tscanf(\"%d%d\",&M,&W);\n\t\tif(M==0&&W==0)break;\n\t\tfor(int i=0;i<M;i++)scanf(\"%d\",&bm[i]);\n\t\tfor(int i=0;i<W;i++)scanf(\"%d\",&bw[i]);\n\t\tfor(int i=0;i<15;i++){\n\t\t\tfor(int j=0;j<(1<<15);j++){\n\t\t\t\tdp[i][j]=0;\n\t\t\t}\n\t\t}\n\t\tfor(int j=0;j<W;j++){\n\t\t\tdp[0][1<<j]=en(bm[0],bw[j]);\n\t\t}\n\t\tfor(int i=1;i<M;i++){\n\t\t\tfor(int j=0;j<(1<<W);j++){\n\t\t\t\tdp[i][j]=max(dp[i][j],dp[i-1][j]);\n\t\t\t\tfor(int k=0;k<W;k++){\n\t\t\t\t\tif((j>>k)&1){\n\t\t\t\t\t\tdp[i][j]=max(dp[i][j],dp[i-1][j-(1<<k)]+en(bm[i],bw[k]));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t//printf(\"%d %d:%d\\n\",i,j,dp[i][j]);\n\t\t\t}\n\t\t}\n\t\tint ans=0;\n\t\tfor(int i=0;i<(1<<W);i++){\n\t\t\tans=max(ans,dp[M-1][i]);\n\t\t}\n\t\tprintf(\"%d\\n\",ans);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5128, "score_of_the_acc": -0.0584, "final_rank": 14 }, { "submission_id": "aoj_0290_1570265", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n while(1){\n int m,w,bm[12],bw[12];\n cin >> m >> w;\n if(m==0 && w==0) break;\n for(int i=0;i<m;i++) cin >> bm[i];\n for(int i=0;i<w;i++) cin >> bw[i];\n int dp[(1<<12)]={},ans=0;\n for(int i=0;i<m;i++)\n for(int S=(1<<w)-1;S>=0;S--)\n\tfor(int k=0;k<w;k++){\n\t if((S&(1<<k))!=0)continue;\n\t int t = abs(bm[i]-bw[k])*(abs(bm[i]-bw[k])-30)*(abs(bm[i]-bw[k])-30);\n\t dp[S+(1<<k)] = max(dp[S+(1<<k)],dp[S]+t); \n\t ans = max(ans,dp[S+(1<<k)]);\n\t}\n cout << ans <<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1184, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0290_1570025", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <cstdlib>\n#include <cmath>\n#include <vector>\n#include <map>\n#include <set>\n#include <stack>\n#include <queue>\n#include <string>\n#include <cassert>\n#include <functional>\n\nusing namespace std;\ntypedef long long ll;\n\n\n#define SIZE 26\n#define INF 1000000000\n#define LLINF 1000000000000000000LL\n\nint calc(int m,int w){\n int ans = 0;\n int bm[12],bw[12];\n int dp[13][1<<12] = {0};\n \n for(int i=0;i<m;i++){\n scanf(\"%d\",bm+i);\n }\n \n for(int i=0;i<w;i++){\n scanf(\"%d\",bw+i);\n }\n\n for(int i=0;i<=w;i++){\n for(int j=0;j<(1<<m);j++){\n dp[i][j] = -INF;\n }\n }\n\n dp[0][0] = 0;\n \n for(int i=0;i<w;i++){\n for(int j=0;j<(1<<m);j++){\n for(int k=0;k<m;k++){\n\tdp[i+1][j] = max(dp[i+1][j],dp[i][j]);\n\tif(j&(1<<k)) continue;\n\tint d = abs(bw[i]-bm[k]);\n\tint add = d * (d-30) * (d-30);\n\tdp[i+1][j+(1<<k)] = max(dp[i+1][j+(1<<k)],dp[i][j] + add);\n\tans = max(ans,dp[i+1][j+(1<<k)]);\n }\n }\n }\n\n return ans;\n}\n\nint main(){\n int m,w;\n \n while(1){\n scanf(\"%d%d\",&m,&w);\n if(m==0) break;\n \n printf(\"%d\\n\",calc(m,w));\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1388, "score_of_the_acc": -0.0137, "final_rank": 9 }, { "submission_id": "aoj_0290_1570018", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n\nint main(){\n int m,w,bm[12],bw[12];\n while(1){ \n cin>>m>>w;\n if(m==0 && w==0)break;\n int dp[13][1<<12]={};\n for(int i=0;i<m;i++)cin>>bm[i];\n for(int i=0;i<w;i++)cin>>bw[i];\n\n int ans=0; \n for(int i=0;i<m;i++)\n for(int S=0;S<(1<<w);S++){ \n\t//if(i < __builtin_popcount(S))continue;\n\tfor(int l=0;l<w;l++){\n\t if((S&(1<<l))!=0)continue;\n\t\n\t int t=abs(bm[i]-bw[l])*(abs(bm[i]-bw[l])-30)*(abs(bm[i]-bw[l])-30);\n\t dp[i+1][S+(1<<l)]=max(dp[i+1][S+(1<<l)],dp[i][S]+t);\n\t dp[i+1][S] = max(dp[i+1][S],dp[i][S]); \n\t ans=max(ans,dp[i+1][S+(1<<l)]);\n\t} \n }\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1376, "score_of_the_acc": -0.0028, "final_rank": 2 }, { "submission_id": "aoj_0290_1566972", "code_snippet": "#include<bits/stdc++.h>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n\nint dp[1<<12][13];\n\nint main(){\n\tint M,W;\n\twhile(scanf(\"%d%d\",&M,&W),M!=0){\n\t\tint bm[12],bw[12];\n\t\tfor(int i=0;i<M;i++) scanf(\"%d\",&bm[i]);\n\t\tfor(int i=0;i<W;i++) scanf(\"%d\",&bw[i]);\n\t\tfor(int i=0;i<(1<<12);i++) for(int j=0;j<13;j++) dp[i][j]=-1;\n\t\tdp[0][0]=0;\n\t\tfor(int j=0;j<W;j++) for(int i=0;i<(1<<M);i++){\n\t\t\tif(dp[i][j]<0) continue;\n\t\t\tdp[i][j+1]=max(dp[i][j],dp[i][j+1]);\n\t\t\tfor(int k=0;k<M;k++){\n\t\t\t\tint x=1<<k;\n\t\t\t\tif(i&x) continue;\n\t\t\t\tint y=abs(bm[k]-bw[j]);\n\t\t\t\tdp[i+x][j+1]=max(dp[i][j]+y*(y-30)*(y-30),dp[i+x][j+1]);\n\t\t\t}\n\t\t}\n\t\tint res=0;\n\t\tfor(int i=0;i<(1<<M);i++) res=max(res,dp[i][W]);\n\t\tprintf(\"%d\\n\",res);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1396, "score_of_the_acc": -0.0031, "final_rank": 4 }, { "submission_id": "aoj_0290_1566635", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<vector>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n#include<string>\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> P1;\ntypedef long long ll;\ntypedef long double ld;\n\n#define rep(i,x) for(int i = 0 ; i < x ; i ++)\n#define rep1(i,x) for(int i = 1 ; i <= x ; i ++)\n#define rrep(i,x) for(int i = x-1 ; i >= 0 ; i --)\n#define rrep1(i,x) for(int i = x ; i > 0 ; i --)\n#define fr first\n#define sc second\n#define pb push_back\n\nconst int INF = 1000000000;\n\nint cal(int bm,int bw){\n\tint d = abs(bm-bw);\n\treturn d*(d-30)*(d-30);\n}\n\nint main(){\n\twhile(1){\n\t\tint m,w;\n\t\tint bm[15],bw[15];\n\t\tscanf(\"%d%d\",&m,&w);\n\t\tif(m == 0 && w == 0)break;\n\t\trep(i,m)scanf(\"%d\",&bm[i]);\n\t\trep(i,w)scanf(\"%d\",&bw[i]);\n\t\tstatic int dp[15][1 << 12] = {};\n\t\trep(i,15)rep(j,(1<<12)){\n\t\t\tdp[i][j] = 0;\n\t\t}\n\t\tint ret = 0;\n\t\trep(i,m){\n\t\t\trep(j,(1<<w)){\n\t\t\t\tdp[i+1][j] = max ( dp[i+1][j] , dp[i][j] );\n\t\t\t\trep(k,w){\n\t\t\t\t\tif((j>>k)&1)continue;\n\t\t\t\t\tdp[i+1][j|(1<<k)] = max ( dp[i+1][j|(1<<k)] , dp[i][j] + cal(bm[i],bw[k]) );\n\t\t\t\t}\n\t\t\t\tret = max ( ret , dp[i][j] );\n\t\t\t}\n\t\t}\n\t\trep(j,(1<<w))ret = max ( ret , dp[m][j] );\n\t\tprintf(\"%d\\n\",ret);\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1428, "score_of_the_acc": -0.0036, "final_rank": 6 }, { "submission_id": "aoj_0290_1556263", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n, m;\nint a[12], b[12];\nint dp[13][1 << 12];\n\nint calc(int i, int j)\n{\n\tint d = abs(a[i] - b[j]);\n\treturn d * (d - 30) * (d - 30);\n}\n\nint dfs(int i, int bit)\n{\n\tif (i == n) return 0;\n\tif (~dp[i][bit]) return dp[i][bit];\n\tint res = dfs(i + 1, bit);\n\tfor (int j = 0; j < m; j++){\n\t\tif (bit & (1 << j)) continue;\n\t\tres = max(res, calc(i, j) + dfs(i + 1, bit | (1 << j)));\n\t}\n\treturn dp[i][bit] = res;\n}\n\nint main()\n{\n\twhile (cin >> n >> m, n){\n\t\tfor (int i = 0; i < n; i++){\n\t\t\tcin >> a[i];\n\t\t}\n\t\tfor (int i = 0; i < m; i++){\n\t\t\tcin >> b[i];\n\t\t}\n\t\tmemset(dp, -1, sizeof dp);\n\t\tcout << dfs(0, 0) << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1376, "score_of_the_acc": -0.0028, "final_rank": 2 }, { "submission_id": "aoj_0290_1468916", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<math.h>\n#include<cstdio>\nusing namespace std;\nint M, W;\nint BM[12], BW[12];\nint DP[13][1 << 12];\nint main()\n{\n\twhile (true){\n\t\tscanf(\"%d%d\", &M, &W);\n\t\tif (M == 0 && W == 0)break;\n\t\tfor (int i = 0; i < M; i++){\n\t\t\tscanf(\"%d\", &BM[i]);\n\t\t}\n\t\tfor (int i = 0; i < W; i++){\n\t\t\tscanf(\"%d\", &BW[i]);\n\t\t}\n\t\tfor (int i = 0; i <= 12; i++)for (int j = 0; j < (1 << 12); j++)DP[i][j] = 0;\n\t\tfor (int i = 1; i <= M; i++){\n\t\t\tfor (int j = 0; j < (1 << W); j++){\n\t\t\t\tDP[i][j] = DP[i - 1][j];\n\t\t\t\tfor (int k = 0; k < W; k++){\n\t\t\t\t\tif ((j >> k) & 1){\n\t\t\t\t\t\tDP[i][j] = max(DP[i][j], DP[i - 1][j - (1 << k)] + abs(BM[i - 1] - BW[k])*(abs(BM[i - 1] - BW[k]) - 30)*(abs(BM[i - 1] - BW[k]) - 30));\n\t\t\t\t\t}\n\t\t\t\t\telse DP[i][j] = DP[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint ans = 0;\n\t\tfor (int j = 0; j < (1 << W); j++)ans = max(ans, DP[M][j]);\n\t\tprintf(\"%d\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1400, "score_of_the_acc": -0.0032, "final_rank": 5 }, { "submission_id": "aoj_0290_1374540", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long lli;\n \nconst lli INF = 1LL<<60;\nconst lli MAXM = 13;\nconst lli MAXW = 13;\n \nlli M, W;\nlli bm[MAXM], bw[MAXW];\nlli dp[MAXM][1<<MAXW];\n \nlli f(lli bm, lli bw) {\n return llabs(bm - bw) * (llabs(bm - bw) - 30LL) * (llabs(bm - bw) - 30LL);\n}\n \nint main() {\n while(cin >> M >> W && (M|W)) {\n for(lli i = 0; i < M; ++i) cin >> bm[i];\n for(lli i = 0; i < W; ++i) cin >> bw[i];\n fill(dp[0], dp[MAXM], -INF);\n dp[0][0] = 0;\n for(lli i = 0; i < M; ++i) {\n for(lli j = (1<<W)-1; j >= 0; --j) {\n dp[i+1][j] = max(dp[i+1][j], dp[i][j]);\n for(lli k = 0; k < W; ++k) {\n if(j >> k & 1) {\n dp[i+1][j] = max(dp[i+1][j], dp[i][j-(1<<k)] + f(bm[i], bw[k]));\n }\n }\n }\n }\n lli res = 0;\n for(lli j = (1<<W)-1; j >= 0; --j) {\n res = max(res, dp[M][j]);\n }\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1988, "score_of_the_acc": -0.0119, "final_rank": 7 }, { "submission_id": "aoj_0290_1374180", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long lli;\n\nconst lli INF = 1LL<<60;\nconst lli MAXM = 13;\nconst lli MAXW = 13;\n\nlli M, W;\nlli bm[MAXM], bw[MAXW];\nlli dp[MAXM][1<<MAXW];\n\nlli f(lli bm, lli bw) {\n return llabs(bm - bw) * (llabs(bm - bw) - 30LL) * (llabs(bm - bw) - 30LL);\n}\n\nint main() {\n while(cin >> M >> W && (M|W)) {\n for(lli i = 0; i < M; ++i) cin >> bm[i];\n for(lli i = 0; i < W; ++i) cin >> bw[i];\n fill(dp[0], dp[MAXM], -INF);\n dp[0][0] = 0;\n for(lli i = 0; i < M; ++i) {\n for(lli j = (1<<W)-1; j >= 0; --j) {\n\tdp[i+1][j] = max(dp[i+1][j], dp[i][j]);\n\tfor(lli k = 0; k < W; ++k) {\n\t if(j >> k & 1) {\n\t dp[i+1][j] = max(dp[i+1][j], dp[i][j-(1<<k)] + f(bm[i], bw[k]));\n\t }\n\t}\n }\n }\n lli res = 0;\n for(lli j = (1<<W)-1; j >= 0; --j) {\n res = max(res, dp[M][j]);\n }\n cout << res << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1988, "score_of_the_acc": -0.0119, "final_rank": 7 } ]
aoj_0299_cpp
鉄道路線II わたしの住む街には、図のような N 個の駅からなる円環状の鉄道路線があります。この路線の各駅には 0 から N -1 までの番号が順番に割り当てられていて、隣の駅まで100 円で移動することができます。移動はどちらの方向にでも可能です。 わたしはこの路線上のいくつかの駅で買い物をしたいと思っています。そこで、プログラムを作成して移動費を計算することにしました。ある駅を始点として、買い物をするすべての駅を訪問する最小の費用(円)を求めるプログラムを作成してください。ただし、同じ駅を何度訪問しても良く、どのような順番で駅を訪問しても構いません。 入力 入力は以下の形式で与えられる。 N M p d 1 d 2 : d M 1行目に駅の数 N (2 ≤ N ≤ 100000)、買い物をする駅の数 M (1 ≤ M ≤ 10000 かつ M < N )、出発する駅の番号 p (0 ≤ p ≤ N -1) が与えられる。続く M 行に買い物をする駅の番号 d i (0 ≤ d i ≤ N -1) が与えられる。ただし、 d i は全て異なり、 p もまたどの d i とも異なるものとする。 出力 最小の費用を1行に出力する。 入出力例 入力例1 5 4 0 1 2 3 4 出力例1 400 入力例2 7 2 1 6 2 出力例2 400
[ { "submission_id": "aoj_0299_4988855", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int d[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n \n int u[100000];\n int s[100000];\n \n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n \n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3380, "score_of_the_acc": -0.9118, "final_rank": 4 }, { "submission_id": "aoj_0299_4988849", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int d[100000];\n int u[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n \n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3360, "score_of_the_acc": -1.7647, "final_rank": 8 }, { "submission_id": "aoj_0299_4988846", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int d[100000];\n int u[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n \n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3388, "score_of_the_acc": -1.9706, "final_rank": 9 }, { "submission_id": "aoj_0299_4988842", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int d[100000];\n int u[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n \n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3324, "score_of_the_acc": -0.8333, "final_rank": 2 }, { "submission_id": "aoj_0299_4988841", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int d[100000];\n int u[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n s[10000]=10000;\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3392, "score_of_the_acc": -1.3333, "final_rank": 7 }, { "submission_id": "aoj_0299_4988838", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[100000];\n int d[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n s[10000]=10000;\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3380, "score_of_the_acc": -1.2451, "final_rank": 6 }, { "submission_id": "aoj_0299_4985123", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[100000];\n int d[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n s[10000]=10000;\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3328, "score_of_the_acc": -0.8627, "final_rank": 3 }, { "submission_id": "aoj_0299_4985119", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[100000];\n int d[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n \n s[10000] = 10000;\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3368, "score_of_the_acc": -1.1569, "final_rank": 5 }, { "submission_id": "aoj_0299_4985105", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[100000];\n int d[100000];\n int s[100000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[100000],w[100000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3344, "score_of_the_acc": -0.6471, "final_rank": 1 }, { "submission_id": "aoj_0299_4985080", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[10000];\n int d[10000];\n int s[10000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[10000],w[10000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 0.875, "time_ms": 150, "memory_kb": 3368, "score_of_the_acc": -0.8235, "final_rank": 11 }, { "submission_id": "aoj_0299_4984981", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[10000];\n int d[10000];\n int s[10000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[10000],w[10000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 0.875, "time_ms": 180, "memory_kb": 3256, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0299_4984574", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[10000];\n int d[10000];\n int s[10000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[10000],w[10000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 0.875, "time_ms": 180, "memory_kb": 3344, "score_of_the_acc": -1.6471, "final_rank": 14 }, { "submission_id": "aoj_0299_4984327", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[10000];\n int d[10000];\n int s[10000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[10000],w[10000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<(M-1); ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i+1]*2 + s[i])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 0.875, "time_ms": 150, "memory_kb": 3312, "score_of_the_acc": -0.4118, "final_rank": 10 }, { "submission_id": "aoj_0299_4984304", "code_snippet": "#include <iostream>\n#include <stdio.h>\n\nusing namespace std;\n\nint main()\n\n \n\n{ \n int N, M, p;\n int u[10000];\n int d[10000];\n int s[10000];\n int i, j, tmp;\n \n scanf(\"%d %d %d\", &N, &M, &p);\n for (i=0; i<M; ++i)\n {\n scanf(\"%d\", &d[i]);\n }\n\n //pを0にする\n for (i=0; i<M; ++i)\n {\n u[i] = d[i] - p;\n if (u[i] >= 0)\n {\n s[i] = u[i];\n }\n else\n {\n s[i] = u[i] + N;\n }\n }\n\n //昇順\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (s[i] > s[j]) \n {\n tmp = s[i];\n s[i] = s[j];\n s[j] = tmp;\n }\n }\n }\n \n //昇順ソートした数値を出力 \n //for (i=0; i<M; ++i)\n //{\n //printf(\"%d\\n\", s[i]);\n //}\n\n int X, Y, Z, W;\n int z[10000],w[10000];\n\n //右回り\n X = s[M-1]*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", X);\n //}\n\n //左回り\n Y = (N - s[0])*100;\n\n //数値を出力 \n //{\n //printf(\"%d\\n\", Y);\n //}\n\n //右左\n for (i=0; i<M; ++i)\n {\n z[i] = (s[i]*2 + N - s[i + 1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (z[i] > z[j]) \n {\n tmp = z[i];\n z[i] = z[j];\n z[j] = tmp;\n }\n }\n }\n Z = z[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", Z);\n //}\n\n //左右\n for (i=0; i<M; ++i)\n {\n w[i] = (N*2 - s[i]*2 + s[i-1])*100;\n }\n for (i=0; i<M; ++i) \n {\n for (j=i+1; j<M; ++j)\n {\n if (w[i] > w[j]) \n {\n tmp = w[i];\n w[i] = w[j];\n w[j] = tmp;\n }\n }\n }\n W = w[0];\n\n //数値を出力\n //{\n //printf(\"%d\\n\", W);\n //}\n\n int num[4] = {X, Y, Z, W};\n for (i=0; i<4; ++i)\n {\n for (j=i+1; j<4; ++j)\n {\n if (num[i] > num[j]) \n {\n tmp = num[i];\n num[i] = num[j];\n num[j] = tmp;\n }\n \n }\n }\n {\n printf(\"%d\\n\", num[0]); \n }\n \n return 0;\n}", "accuracy": 0.875, "time_ms": 150, "memory_kb": 3372, "score_of_the_acc": -0.8529, "final_rank": 12 } ]
aoj_0300_cpp
フロッピーキューブ フロッピーキューブをプログラミングで解いてみましょう。フロッピーキューブは図のように表面に色のついた9個の立方体から構成されている立体パズルで、キューブの列を回転させることによって、6つの各面の色をそろえます。 フロッピーキューブに対しては下図のような4種類の操作を行うことができ、一回の操作で、端にある3つの隣接したキューブを180度回転することができます。わかりやすいように、図では、上面に+(赤色)、下面に*(緑色)、右前面に□(黄色)、左前面に●(青色)、右奥面に○(水色)、左奥面に■紫色) の記号が付いている状態を初期状態としています。 フロッピーキューブの初期状態が与えられるので、パズルを解くために必要な最小の操作回数を求めるプログラムを作成してください。 入力 入力は以下の形式で与えられる。 N puzzle 1 puzzle 2 : puzzle N 1行目の N (1 ≤ N ≤ 30) は操作回数を計算したいパズルの数である。続くN行に各フロッピーキューブの初期状態 puzzle i が与えられる。 puzzle i は以下の形式で与えられる。 p 1 p 2 p 3 p 4 p 5 p 6 p 7 p 8 p 9 p 10 p 11 p 12 p 13 p 14 p 15 p 16 p 17 p 18 p 19 p 20 p 21 p 22 p 23 p 24 p 25 p 26 p 27 p 28 p 29 p 30 各フロッピーキューブの情報は 30 個の整数 p i (1 ≤ p i ≤ 6) からなる。 p i は、下図のようにフロッピーキューブの各面に番号 i を振ったときの、そのキューブの面の色を表す。 パズルは、多くとも8回の操作で解くことができると仮定してよい。 出力 パズルごとに、最小の操作回数を1行に出力する。 入出力例 入力例 4 1 1 1 1 1 1 1 1 1 2 2 2 4 4 4 6 6 6 5 5 5 3 3 3 3 3 3 3 3 3 3 3 3 1 1 1 1 1 1 2 2 2 4 4 6 4 6 6 5 5 5 3 3 3 3 3 3 1 1 1 3 3 3 1 1 3 1 1 1 2 2 5 6 4 4 4 6 6 2 5 5 3 3 3 1 3 3 1 1 1 1 3 1 3 1 3 3 1 3 2 2 2 6 4 4 6 6 4 5 5 5 1 3 1 1 3 1 3 1 3 出力例 0 1 2 7
[ { "submission_id": "aoj_0300_10850143", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nvoid dfs(vector<int> A, int depth, int &ans){\n bool b=1;\n rep(i,30-1){\n if(i==8||i==11||i==14||i==17||i==20) continue;\n if(A[i]!=A[i+1]) b=0;\n }\n if(b){\n chmin(ans, depth);\n return ;\n }\n if(depth==8) return ;\n\n {\n vector<int> B=A;\n rep(i,3) swap(B[i], B[i+27]);\n swap(B[14],B[15]);\n swap(B[18],B[20]);\n dfs(B, depth+1, ans);\n }\n {\n vector<int> B=A;\n for(int i=2;i<=8;i+=3) swap(B[i], B[i+19]);\n swap(B[11], B[18]);\n swap(B[12], B[14]);\n dfs(B, depth+1, ans);\n }\n {\n vector<int> B=A;\n for(int i=6;i<=8;i++) swap(B[i], B[i+15]);\n swap(B[12],B[17]);\n swap(B[9],B[11]);\n dfs(B, depth+1, ans);\n }\n {\n vector<int> B=A;\n for(int i=0;i<=6;i+=3) swap(B[i],B[i+23]);\n swap(B[9],B[20]);\n swap(B[15],B[17]);\n dfs(B, depth+1, ans);\n }\n return;\n}\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int T;\n cin>>T;\n while(T--){\n int N=30;\n vector<int> A(N);\n rep(i,N)cin>>A[i];\n int ans=1e9;\n dfs(A, 0, ans);\n cout<<ans<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3584, "score_of_the_acc": -0.2253, "final_rank": 12 }, { "submission_id": "aoj_0300_10787350", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n\nbool check(vector<int>&S){\n rep(i,30){\n if(i<9){\n if(S[0]!=S[i])return false;\n }\n else if(i<12){\n if(S[9]!=S[i])return false;\n }\n else if(i<15){\n if(S[12]!=S[i])return false;\n }\n else if(i<18){\n if(S[15]!=S[i])return false;\n }\n else if(i<21){\n if(S[18]!=S[i])return false;\n }\n else {\n if(S[21]!=S[i])return false;\n }\n }\n return true;\n}\n\nvoid solve(){\n vector<int>S(30);\n rep(i,30)cin>>S[i];\n if(check(S)){\n cout<<0<<endl;\n return;\n }\n queue<pair<int,vector<int>>>Q;\n Q.push({0,S});\n while(!Q.empty()){\n vector<int>s = Q.front().se;\n int d = Q.front().fi;\n Q.pop();\n vector<int>n = s;\n n[2]=s[21],n[5]=s[24],n[8]=s[27],n[18]=s[11],n[11]=s[18],n[14]=s[12],n[12]=s[14];\n n[21]=s[2],n[24]=s[5],n[8]=s[27];\n if(check(n)){\n cout<<d+1<<endl;\n Q={};\n return;\n }\n Q.push({d+1,n});\n n=s;\n n[0]=s[23],n[3]=s[26],n[6]=s[29],n[15]=s[17],n[9]=s[20];\n n[23]=s[0],n[26]=s[3],n[29]=s[6],n[17]=s[15],n[20]=s[9];\n if(check(n)){\n cout<<d+1<<endl;\n Q={};\n return;\n }\n Q.push({d+1,n});\n n=s;\n n[0]=s[27],n[1]=s[28],n[2]=s[29],n[15]=s[14],n[20]=s[18];\n n[27]=s[0],n[28]=s[1],n[29]=s[2],n[14]=s[15],n[18]=s[20];\n if(check(n)){\n cout<<d+1<<endl;\n Q={};\n return;\n }\n Q.push({d+1,n});\n n=s;\n n[6]=s[21],n[7]=s[22],n[8]=s[23],n[9]=s[11],n[17]=s[12];\n n[21]=s[6],n[22]=s[7],n[23]=s[8],n[11]=s[9],n[12]=s[17];\n if(check(n)){\n cout<<d+1<<endl;\n Q={};\n return;\n }\n Q.push({d+1,n});\n }\n}\n\nint main(){\n int N;cin>>N;\n rep(i,N)solve();\n}", "accuracy": 0.125, "time_ms": 90, "memory_kb": 56376, "score_of_the_acc": -1.1946, "final_rank": 20 }, { "submission_id": "aoj_0300_9542834", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvoid func(int);\nint check(void);\nint a[31],mn;\nint main(void){\n\tint n,i,j,nn,flg;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=1;j<=30;j++) cin>>a[j];\n\t\tmn=8;\n\t\tfunc(0);\n\t\tcout<<mn<<endl;\n\t}\n\treturn 0;\n}\nvoid func(int nn){\n\tint i,j,flg;\n\tint pat[4][10]={{1,24,4,27,7,30,10,21,16,18},{1,28,2,29,3,30,15,16,19,21},{3,22,6,25,9,28,12,19,13,15},{7,22,8,23,9,24,13,18,10,12}};\n\tint b[31];\n\tif(nn<mn){\n\t\tflg=check();\n\t\tif(flg==1){\n\t\t\tmn=nn;\n\t\t}\n\t\telse{\n\t\t\tfor(i=0;i<4;i++){\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(a[pat[i][j]],a[pat[i][j+1]]);\n\t\t\t\t}\n\t\t\t\tfunc(nn+1);\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(a[pat[i][j]],a[pat[i][j+1]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\nint check(void){\n\tint i,j,flg;\n\tint f;\n\tflg=1;\n\tfor(i=2;i<=9;i++){\n\t\tif(a[1]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=11;i<=12;i++){\n\t\tif(a[10]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=14;i<=15;i++){\n\t\tif(a[13]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=17;i<=18;i++){\n\t\tif(a[16]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=20;i<=21;i++){\n\t\tif(a[19]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=23;i<=30;i++){\n\t\tif(a[22]!=a[i]){\n\t\t\tflg=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\treturn flg;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3116, "score_of_the_acc": -0.0005, "final_rank": 1 }, { "submission_id": "aoj_0300_9142763", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint p[31];\n\nvoid rotate_front() {\n swap(p[18], p[13]);\n swap(p[10], p[12]);\n swap(p[7], p[22]);\n swap(p[8], p[23]);\n swap(p[9], p[24]);\n}\n\nvoid rotate_back() {\n swap(p[16], p[15]);\n swap(p[21], p[19]);\n swap(p[1], p[28]);\n swap(p[2], p[29]);\n swap(p[3], p[30]);\n}\n\nvoid rotate_right() {\n swap(p[19], p[12]);\n swap(p[15], p[13]);\n swap(p[3], p[22]);\n swap(p[6], p[25]);\n swap(p[9], p[28]);\n}\n\nvoid rotate_left() {\n swap(p[21], p[10]);\n swap(p[16], p[18]);\n swap(p[1], p[24]);\n swap(p[4], p[27]);\n swap(p[7], p[30]);\n}\n\nbool is_solved() {\n for(int i = 1; i <= 28; i+=3) {\n if(p[i] != p[i+1] || p[i] != p[i+2]) {\n return false;\n }\n }\n return p[3] == p[4] && p[6] == p[7] && p[24] == p[25] && p[27] == p[28];\n}\n\nvoid solve() {\n for(int i = 1; i <= 30; i++) {\n cin >> p[i];\n }\n int ans = 8;\n auto dfs = [&](auto dfs, int cnt) -> void {\n if(cnt == 8 || is_solved()) {\n ans = min(ans, cnt);\n return;\n }\n rotate_front(); dfs(dfs, cnt+1); rotate_front();\n rotate_back(); dfs(dfs, cnt+1); rotate_back();\n rotate_right(); dfs(dfs, cnt+1); rotate_right();\n rotate_left(); dfs(dfs, cnt+1); rotate_left();\n };\n dfs(dfs, 0);\n cout << ans << endl;\n}\n\nint main() {\n int N;\n cin >> N;\n while(N--) { solve(); }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0065, "final_rank": 4 }, { "submission_id": "aoj_0300_6877702", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint p[31],mn;\nvoid func(int);\nint main(void)\n{\n int n,q;\n cin>>n;\n for(int i=0;i<n;i++){\n mn=9;\n for(int j=0;j<30;j++){cin>>q; p[j]=q;}\n func(0);\n cout<<mn<<endl;\n }\n return 0;\n}\nvoid func(int c)\n{\n int nx[4][10]={{1,24,4,27,7,30,10,21,16,18},{7,22,8,23,9,24,13,18,10,12},\n {9,28,6,25,3,22,12,19,13,15},{3,30,2,29,1,28,15,16,19,21}};\n int f=1;\n for(int i=1;i<9;i++) if(p[i]!=p[0]) f=0;\n for(int i=10;i<12;i++) if(p[i]!=p[9]) f=0;\n for(int i=13;i<15;i++) if(p[i]!=p[12]) f=0;\n for(int i=16;i<18;i++) if(p[i]!=p[15]) f=0;\n for(int i=19;i<21;i++) if(p[i]!=p[18]) f=0;\n for(int i=22;i<30;i++) if(p[i]!=p[21]) f=0;\n if(f){mn=min(mn,c);}\n else if(c<mn){\n for(int i=0;i<4;i++){\n for(int j=0;j<10;j+=2) swap(p[nx[i][j]-1],p[nx[i][j+1]-1]);\n func(c+1);\n for(int j=0;j<10;j+=2) swap(p[nx[i][j]-1],p[nx[i][j+1]-1]);\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3088, "score_of_the_acc": -0.027, "final_rank": 7 }, { "submission_id": "aoj_0300_6874695", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint match(vector<int> a){\n for(int i=0;i<9;i+=1){\n if(a.at(i)!=1){\n return 0;\n }}\n for(int i=0;i<9;i+=1){\n if(a.at(i+9)!=2*(i/3+1)){\n return 0;\n }\n }\n for(int i=0;i<3;i+=1){\n if(a.at(i+18)!=5){\n return 0;\n }\n }\n for(int i=0;i<9;i+=1){\n if(a.at(i+21)!=3){\n return 0;\n }}\n return 1;\n}\nint swap(int &a,int &b){\n int u=0;\n u=a;\n a=b;\n b=u;\n return 0;\n}\nint main(){\n int a;\n int ans=8;\ncin>>a;\nvector<int> inform(30);\nvector<int> inform2(30);\nfor(int ttt=0;ttt<a;ttt+=1){\n ans=8;\n for(int i=0;i<30;i+=1){\n cin>>inform.at(i);\n inform2.at(i)=inform.at(i);\n }\n for(int i=0;i<65536;i+=1){\n int k=0;\n int j=1,j2=-1;\n for(k=0;match(inform2)==0&&k<=8;k+=1,j*=4){\n if(j2!=(i/j)%4){\n switch((i/j)%4){\n case 0:\n swap(inform2.at(0),inform2.at(27));\n swap(inform2.at(1),inform2.at(28));\n swap(inform2.at(2),inform2.at(29));\n swap(inform2.at(14),inform2.at(15));\n swap(inform2.at(18),inform2.at(20));\n break;\n case 1:\n swap(inform2.at(0),inform2.at(23));\n swap(inform2.at(3),inform2.at(26));\n swap(inform2.at(6),inform2.at(29));\n swap(inform2.at(9),inform2.at(20));\n swap(inform2.at(15),inform2.at(17));\n break;\n case 2:\n swap(inform2.at(6),inform2.at(21));\n swap(inform2.at(7),inform2.at(22));\n swap(inform2.at(8),inform2.at(23));\n swap(inform2.at(17),inform2.at(12));\n swap(inform2.at(9),inform2.at(11));\n break;\n case 3:\n swap(inform2.at(2),inform2.at(21));\n swap(inform2.at(5),inform2.at(24));\n swap(inform2.at(8),inform2.at(27));\n swap(inform2.at(18),inform2.at(11));\n swap(inform2.at(12),inform2.at(14));\n }\n }else{\n k=8;\n break;\n }\n j2=i/j%4;\n }\n for(int i=0;i<30;i+=1){\n inform2.at(i)=inform.at(i);\n }\n ans=min(ans,k);\n }\n cout<<ans<<endl;\n}\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 3104, "score_of_the_acc": -0.9733, "final_rank": 16 }, { "submission_id": "aoj_0300_5949306", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<vector<int>> op = {{0, 27, 1, 28, 2, 29, 14, 15, 18, 20}, {6, 21, 7, 22, 8, 23, 12, 17, 9, 11}, {0, 23, 3, 26, 6, 29, 9, 20, 15, 17}, {2, 21, 5, 24, 8, 27, 11, 18, 12, 14}};\nvector<int> f = {0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5};\nint main(){\n int N;\n cin >> N;\n for (int i = 0; i < N; i++){\n vector<int> p(30);\n for (int j = 0; j < 30; j++){\n cin >> p[j];\n }\n int ans = -1;\n for (int j = 0; j <= 8; j++){\n bool ok = false;\n for (int k = 0; k < (1 << (j * 2)); k++){\n vector<int> p2 = p;\n for (int l = 0; l < j; l++){\n int x = (k >> (l * 2)) & 3;\n for (int m = 0; m < 5; m++){\n swap(p2[op[x][m * 2]], p2[op[x][m * 2 + 1]]);\n }\n }\n vector<int> c(6, -1);\n bool ok2 = true;\n for (int l = 0; l < 30; l++){\n if (c[f[l]] == -1){\n c[f[l]] = p2[l];\n } else if (c[f[l]] != p2[l]){\n ok2 = false;\n }\n }\n if (ok2){\n ok = true;\n }\n }\n if (ok){\n ans = j;\n break;\n }\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3352, "score_of_the_acc": -0.0319, "final_rank": 8 }, { "submission_id": "aoj_0300_5923473", "code_snippet": "#include <iostream>\nusing namespace std;\n#define INF 1000010\n\nvoid swap(int i, int j, int* p){\n int tmp;\n tmp = p[i];\n p[i] = p[j];\n p[j] = tmp;\n}\n\nvoid copy(int* array1, int* array2, int N){\n for(int i=0;i<N;i++){\n array2[i] = array1[i];\n }\n}\n\nbool equal(int* array1, int* array2, int N){\n for(int i=0;i<N;i++){\n if(array1[i]!=array2[i]){\n return false;\n }\n }\n return true;\n}\n\nvoid op1(int* puzzle){\n swap(7,22,puzzle);\n swap(8,23,puzzle);\n swap(9,24,puzzle);\n swap(13,18,puzzle);\n swap(10,12,puzzle);\n}\n\nvoid op2(int* puzzle){\n swap(1,28,puzzle);\n swap(2,29,puzzle);\n swap(3,30,puzzle);\n swap(15,16,puzzle);\n swap(19,21,puzzle);\n}\n\nvoid op3(int* puzzle){\n swap(1,24,puzzle);\n swap(4,27,puzzle);\n swap(7,30,puzzle);\n swap(10,21,puzzle);\n swap(16,18,puzzle);\n}\n\nvoid op4(int* puzzle){\n swap(3,22,puzzle);\n swap(6,25,puzzle);\n swap(9,28,puzzle);\n swap(12,19,puzzle);\n swap(13,15,puzzle);\n}\n\nint solve(int *puzzle, int depth, int N, int op){\n if(depth>8){\n return INF;\n }\n int goal[] = {0,1,1,1,1,1,1,1,1,1,2,2,2,4,4,4,6,6,6,5,5,5,3,3,3,3,3,3,3,3,3};\n if(equal(goal, puzzle, N)){\n return 0;\n }\n int retval = INF+100;\n int* puzzle_ = new int[N];\n if(op!=1){\n copy(puzzle, puzzle_,N);\n op1(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 1));\n }\n\n if(op!=2){\n copy(puzzle, puzzle_,N);\n op2(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 2));\n }\n\n if(op!=3){\n copy(puzzle, puzzle_,N);\n op3(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 3));\n }\n\n if(op!=4){\n copy(puzzle, puzzle_,N);\n op4(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 4));\n }\n\n\n\n return retval;\n}\n\n\nint main(void){\n int N;\n cin>>N;\n for(int i=0;i<N;i++){\n int* puzzle = new int[31];\n puzzle[0]=0;\n for(int j=1;j<=30;j++){\n cin>>puzzle[j];\n }\n cout<<solve(puzzle,0,31,-1)<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 57556, "score_of_the_acc": -1.0541, "final_rank": 17 }, { "submission_id": "aoj_0300_5923472", "code_snippet": "#include <iostream>\nusing namespace std;\n#define INF 1000010\n\nvoid swap(int i, int j, int* p){\n int tmp;\n tmp = p[i];\n p[i] = p[j];\n p[j] = tmp;\n}\n\nvoid copy(int* array1, int* array2, int N){\n for(int i=0;i<N;i++){\n array2[i] = array1[i];\n }\n}\n\nbool equal(int* array1, int* array2, int N){\n for(int i=0;i<N;i++){\n if(array1[i]!=array2[i]){\n return false;\n }\n }\n return true;\n}\n\nvoid op1(int* puzzle){\n swap(7,22,puzzle);\n swap(8,23,puzzle);\n swap(9,24,puzzle);\n swap(13,18,puzzle);\n swap(10,12,puzzle);\n}\n\nvoid op2(int* puzzle){\n swap(1,28,puzzle);\n swap(2,29,puzzle);\n swap(3,30,puzzle);\n swap(15,16,puzzle);\n swap(19,21,puzzle);\n}\n\nvoid op3(int* puzzle){\n swap(1,24,puzzle);\n swap(4,27,puzzle);\n swap(7,30,puzzle);\n swap(10,21,puzzle);\n swap(16,18,puzzle);\n}\n\nvoid op4(int* puzzle){\n swap(3,22,puzzle);\n swap(6,25,puzzle);\n swap(9,28,puzzle);\n swap(12,19,puzzle);\n swap(13,15,puzzle);\n}\n\nint solve(int *puzzle, int depth, int N, int op){\n if(depth>=8){\n return INF;\n }\n int goal[] = {0,1,1,1,1,1,1,1,1,1,2,2,2,4,4,4,6,6,6,5,5,5,3,3,3,3,3,3,3,3,3};\n if(equal(goal, puzzle, N)){\n return 0;\n }\n int retval = INF+100;\n int* puzzle_ = new int[N];\n if(op!=1){\n copy(puzzle, puzzle_,N);\n op1(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 1));\n }\n\n if(op!=2){\n copy(puzzle, puzzle_,N);\n op2(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 2));\n }\n\n if(op!=3){\n copy(puzzle, puzzle_,N);\n op3(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 3));\n }\n\n if(op!=4){\n copy(puzzle, puzzle_,N);\n op4(puzzle_);\n retval = min(retval, 1+solve(puzzle_, depth+1, N, 4));\n }\n\n\n\n return retval;\n}\n\n\nint main(void){\n int N;\n cin>>N;\n for(int i=0;i<N;i++){\n int* puzzle = new int[31];\n puzzle[0]=0;\n for(int j=1;j<=30;j++){\n cin>>puzzle[j];\n }\n cout<<solve(puzzle,0,31,-1)<<endl;\n }\n return 0;\n}", "accuracy": 0.875, "time_ms": 10, "memory_kb": 21388, "score_of_the_acc": -0.336, "final_rank": 18 }, { "submission_id": "aoj_0300_5868683", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n \nint main(){\n int N;\n cin >> N;\n for(int i=0;i<N;i++){\n vector<int> p(30);\n for(int j=0;j<30;j++) cin >> p[j];\n queue<pair<vector<int>,int>> que;\n que.push(make_pair(p,0));\n int ans = 8;\n while(!que.empty()){\n vector<int> now = que.front().first;\n int time = que.front().second;\n que.pop();\n if(time >= ans) continue;\n bool flag = true;\n for(int j=1;j<9;j++) if(now[0] != now[j]) flag = false;\n for(int j=10;j<12;j++) if(now[9] != now[j]) flag = false;\n for(int j=13;j<15;j++) if(now[12] != now[j]) flag = false;\n for(int j=16;j<18;j++) if(now[15] != now[j]) flag = false;\n for(int j=19;j<21;j++) if(now[18] != now[j]) flag = false;\n for(int j=22;j<30;j++) if(now[21] != now[j]) flag = false;\n if(flag){\n ans = min(ans,time);\n continue;\n }\n vector<int> NEW = now;\n swap(NEW[6],NEW[21]);\n swap(NEW[7],NEW[22]);\n swap(NEW[8],NEW[23]);\n swap(NEW[12],NEW[17]);\n swap(NEW[9],NEW[11]);\n que.push(make_pair(NEW,time+1));\n NEW = now;\n swap(NEW[0],NEW[27]);\n swap(NEW[1],NEW[28]);\n swap(NEW[2],NEW[29]);\n swap(NEW[14],NEW[15]);\n swap(NEW[18],NEW[20]);\n que.push(make_pair(NEW,time+1));\n NEW = now;\n swap(NEW[0],NEW[23]);\n swap(NEW[3],NEW[26]);\n swap(NEW[6],NEW[29]);\n swap(NEW[9],NEW[20]);\n swap(NEW[15],NEW[17]);\n que.push(make_pair(NEW,time+1));\n NEW = now;\n swap(NEW[2],NEW[21]);\n swap(NEW[5],NEW[24]);\n swap(NEW[8],NEW[27]);\n swap(NEW[11],NEW[18]);\n swap(NEW[12],NEW[14]);\n que.push(make_pair(NEW,time+1));\n }\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 13828, "score_of_the_acc": -0.2242, "final_rank": 11 }, { "submission_id": "aoj_0300_5851932", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,p[31],mn;\nvoid func(int);\nint main(void)\n{\n\tint i,j;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tfor(j=1;j<31;j++) scanf(\"%d\",&p[j]);\n\t\tmn=8;\n\t\tfunc(0);\n\t\tprintf(\"%d\\n\",mn);\n\t}\n\treturn 0;\n}\nvoid func(int nn)\n{\n\tint pp[4][10]={{1,24,4,27,7,30,10,21,16,18},{1,28,2,29,3,30,15,16,19,21},{3,22,6,25,9,28,12,19,13,15},{7,22,8,23,9,24,13,18,10,12}};\n\tint flg,i,j;\n\tif(mn>nn){\n\t\tflg=1;\n\t\tfor(i=1;i<31;i++){\n\t\t\tif(i<10) {\n\t\t\t\tif(p[1]!=p[i]) flg=0;\n\t\t\t}\n\t\t\telse if(i<13) {\n\t\t\t\tif(p[10]!=p[i]) flg=0;\n\t\t\t}\n\t\t\telse if(i<16) {\n\t\t\t\tif(p[13]!=p[i]) flg=0;\n\t\t\t}\n\t\t\telse if(i<19) {\n\t\t\t\tif(p[16]!=p[i]) flg=0;\n\t\t\t}\n\t\t\telse if(i<22) {\n\t\t\t\tif(p[19]!=p[i]) flg=0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif(p[22]!=p[i]) flg=0;\n\t\t\t}\n\t\t}\n\t\tif(flg==1) mn=nn;\n\t\telse{\n\t\t\tfor(i=0;i<4;i++){\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(p[pp[i][j]],p[pp[i][j+1]]);\n\t\t\t\t}\n\t\t\t\tfunc(nn+1);\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(p[pp[i][j]],p[pp[i][j+1]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3236, "score_of_the_acc": -0.0027, "final_rank": 3 }, { "submission_id": "aoj_0300_5843282", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,p[31],mn;\nvoid func(int);\nint main(void)\n{\n\tint i,j;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++){\n\t\tfor(j=1;j<=30;j++) scanf(\"%d\",&p[j]);\n\t\tmn=8;\n\t\tfunc(0);\n\t\tprintf(\"%d\\n\",mn);\n\t}\n\treturn 0;\n}\nvoid func(int nn)\n{\n\tint pp[4][10]={{1,24,4,27,7,30,10,21,16,18},{1,28,2,29,3,30,15,16,19,21},{3,22,6,25,9,28,12,19,13,15},{7,22,8,23,9,24,13,18,10,12}};\n\tint flg,i,j;\n\tif(nn<mn){\n\t\tflg=1;\n\t\tfor(i=2;i<10;i++){\n\t\t\tif(p[1]!=p[i]) flg=0;\n\t\t}\n\t\tfor(i=11;i<13;i++){\n\t\t\tif(p[10]!=p[i]) flg=0;\n\t\t}\n\t\tfor(i=14;i<16;i++){\n\t\t\tif(p[13]!=p[i]) flg=0;\n\t\t}\n\t\tfor(i=17;i<19;i++){\n\t\t\tif(p[16]!=p[i]) flg=0;\n\t\t}\n\t\tfor(i=20;i<22;i++){\n\t\t\tif(p[19]!=p[i]) flg=0;\n\t\t}\n\t\tfor(i=23;i<31;i++){\n\t\t\tif(p[22]!=p[i]) flg=0;\n\t\t}\n\t\tif(flg==1) mn=nn;\n\t\telse{\n\t\t\tfor(i=0;i<4;i++){\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(p[pp[i][j]],p[pp[i][j+1]]);\n\t\t\t\t}\n\t\t\t\tfunc(nn+1);\n\t\t\t\tfor(j=0;j<10;j+=2){\n\t\t\t\t\tswap(p[pp[i][j]],p[pp[i][j+1]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3216, "score_of_the_acc": -0.0024, "final_rank": 2 }, { "submission_id": "aoj_0300_5839710", "code_snippet": "#include <bits/stdc++.h>\n \n#define lol long long\n#define gcd(x, y) __gcd(x, y)\n#define mt make_tuple\n#define mp make_pair\n#define fi first\n#define se second\n#define fixed(x) fixed << setprecision(x)\n#define all(x) x.begin(),x.end()\nusing namespace std;\nusing pii = pair<int, int>;\ntemplate <class A, class B>\ninline bool chmax(A& a, const B& b) {\n return b > a && (a = b, true);\n}\ntemplate <class A, class B>\ninline bool chmin(A& a, const B& b) {\n return b < a && (a = b, true);\n}\ntemplate <class A>\ninline A abs(A& a) {\n return (a < 0 ? -a : a);\n}\nbool inLine(int x, int y, int mx, int my) {\n return (x >= 0 && y >= 0 && x < mx && y < my);\n}\ntemplate<class T> using min_heap=priority_queue<T,vector<T>,greater<T>>;\ntemplate<class T> using uset=unordered_set<T>;\ntemplate<class A,class B> using umap=unordered_map<A,B>;\nconst lol inf = (1LL << 62);\nconst int MOD = (1e9) + 7;\nconst int mod = 998244353;\nconst int dx[] = {1, 0, -1, 0, 1, 1, -1, -1, -2, -2, -2, -2,\n -2, -1, -1, 1, 1, 0, 0, 2, 2, 2, 2, 2};\nconst int dy[] = {0, 1, 0, -1, 1, -1, 1, -1, -2, -1, 0, 1,\n 2, -2, 2, -2, 2, -2, 2, -2, -1, 0, 1, 2};\nint co(vector<int> p,int cost){\n int tp=0;\n for(int i=2;i<=9;i++){\n tp+=(p[1]!=p[i]);\n }\n for(int i=22;i<=30;i++){\n tp+=(p[22]!=p[i]);\n }\n for(int i=10;i<=12;i++){\n tp+=(p[10]!=p[i]);\n }\n for(int i=13;i<=15;i++){\n tp+=(p[13]!=p[i]);\n }\n for(int i=16;i<=18;i++){\n tp+=(p[16]!=p[i]);\n }\n for(int i=19;i<=21;i++){\n tp+=(p[19]!=p[i]);\n }\n if(tp==0){\n return (cost);\n }\n if(cost>=9){\n return (mod);\n }\n int ans=mod;\n auto v=p;\n swap(v[1],v[24]);\n swap(v[4],v[27]);\n swap(v[7],v[30]);\n swap(v[21],v[10]);\n swap(v[16],v[18]);\n chmin(ans,co(v,cost+1));\n \n v=p;\n swap(v[3],v[22]);\n swap(v[6],v[25]);\n swap(v[9],v[28]);\n swap(v[12],v[19]);\n swap(v[13],v[15]);\n chmin(ans,co(v,cost+1));\n \n v=p;\n swap(v[1],v[28]);\n swap(v[2],v[29]);\n swap(v[3],v[30]);\n swap(v[15],v[16]);\n swap(v[19],v[21]);\n chmin(ans,co(v,cost+1));\n \n v=p;\n swap(v[7],v[22]);\n swap(v[8],v[23]);\n swap(v[9],v[24]);\n swap(v[10],v[12]);\n swap(v[13],v[18]);\n chmin(ans,co(v,cost+1));\n return(ans);\n \n}\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n;\n cin >>n;\n for(int i=0;i<n;i++){\n vector<int> p(31);\n for(int j=0;j<30;j++){\n cin >>p[j+1];\n }\n cout <<co(p,0)<<'\\n';\n }\n return (0);\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3392, "score_of_the_acc": -0.8704, "final_rank": 15 }, { "submission_id": "aoj_0300_5740420", "code_snippet": "/*\nこのコード、と~おれ!\nBe accepted!\n∧_∧ \n(。・ω・。)つ━☆・*。\n⊂   ノ    ・゜+.\n しーJ   °。+ *´¨)\n          .· ´¸.·*´¨) ¸.·*¨)\n\t\t           (¸.·´ (¸.·'* ☆\n*/\n\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <iostream>\n#include <random>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <regex>\n#include <functional>\n#include <complex>\n#include <list>\n#include <cassert>\n#include <iomanip>\n#include <set>\n#include <stack>\n#include <bitset>\n#include <array>\n#include <chrono>\n\n//#pragma GCC target(\"arch=skylake-avx512\")\n#pragma GCC target(\"avx2\")\n//#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse4\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define repeat(i, n, m) for(int i = n; i < (m); ++i)\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n#define printynl(a) printf(a ? \"yes\\n\" : \"no\\n\")\n#define printyn(a) printf(a ? \"Yes\\n\" : \"No\\n\")\n#define printYN(a) printf(a ? \"YES\\n\" : \"NO\\n\")\n#define printim(a) printf(a ? \"possible\\n\" : \"imposible\\n\")\n#define printdb(a) printf(\"%.50lf\\n\", a)\n#define printLdb(a) printf(\"%.50Lf\\n\", a)\n#define printdbd(a) printf(\"%.16lf\\n\", a)\n#define prints(s) printf(\"%s\\n\", s.c_str())\n#define all(x) (x).begin(), (x).end()\n#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)\n#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)\n#define Please return\n#define AC 0\n#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr int INF = 1073741823;\nconstexpr int MINF = -1073741823;\nconstexpr ll LINF = ll(4661686018427387903);\nconstexpr ll MOD = 1e9 + 7;\nconstexpr ll mod = 998244353;\nconstexpr long double eps = 1e-6;\nconst long double PI = acosl(-1.0L);\n\nusing namespace std;\n\nvoid scans(string& str) {\n\tchar c;\n\tstr = \"\";\n\tscanf(\"%c\", &c);\n\tif (c == '\\n')scanf(\"%c\", &c);\n\twhile (c != '\\n' && c != -1 && c != ' ') {\n\t\tstr += c;\n\t\tscanf(\"%c\", &c);\n\t}\n}\n\nvoid scanc(char& str) {\n\tchar c;\n\tscanf(\"%c\", &c);\n\tif (c == -1)return;\n\twhile (c == '\\n') {\n\t\tscanf(\"%c\", &c);\n\t}\n\tstr = c;\n}\n\ndouble acot(double x) {\n\treturn PI / 2 - atan(x);\n}\n\nll LSB(ll n) { return (n & (-n)); }\n\ntemplate<typename T>\ninline T chmin(T& a, const T& b) {\n\tif (a > b)a = b;\n\treturn a;\n}\n\ntemplate<typename T>\ninline T chmax(T& a, const T& b) {\n\tif (a < b)a = b;\n\treturn a;\n}\n\n//cpp_int\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\nusing namespace boost::multiprecision;\n#else\nusing cpp_int = ll;\n#endif\n\n//atcoder library\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\n//using namespace atcoder;\n#endif\n\n/*\n\trandom_device seed_gen;\n\tmt19937 engine(seed_gen());\n\tuniform_int_distribution dist(1, 100);\n*/\n\n\n/*----------------------------------------------------------------------------------*/\n\nbool check(int p[30]) {\n\tbool ret = true;\n\tint q = p[0];\n\trep(i, 9) {\n\t\tif (p[i] != q)ret = false;\n\t}\n\tif (not(p[9] == p[10] and p[10] == p[11]))ret = false;\n\tif (not(p[12] == p[13] and p[13] == p[14]))ret = false;\n\tif (not(p[15] == p[16] and p[16] == p[17]))ret = false;\n\tif (not(p[18] == p[19] and p[19] == p[20]))ret = false;\n\tq = p[21];\n\trep(i, 9) {\n\t\tif (p[21 + i] != q)ret = false;\n\t}\n\treturn ret;\n}\n\nint solve(int p[30], int cnt) {\n\tif (cnt == 8)return cnt;\n\tint ret = INF;\n\tif (check(p))ret = cnt;\n\t++cnt;\n\tswap(p[6], p[21]);\n\tswap(p[7], p[22]);\n\tswap(p[8], p[23]);\n\tswap(p[12], p[17]);\n\tswap(p[9], p[11]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[6], p[21]);\n\tswap(p[7], p[22]);\n\tswap(p[8], p[23]);\n\tswap(p[12], p[17]);\n\tswap(p[9], p[11]);\n\n\tswap(p[0], p[27]);\n\tswap(p[1], p[28]);\n\tswap(p[2], p[29]);\n\tswap(p[14], p[15]);\n\tswap(p[20], p[18]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[0], p[27]);\n\tswap(p[1], p[28]);\n\tswap(p[2], p[29]);\n\tswap(p[14], p[15]);\n\tswap(p[20], p[18]);\n\n\tswap(p[0], p[23]);\n\tswap(p[3], p[26]);\n\tswap(p[6], p[29]);\n\tswap(p[20], p[9]);\n\tswap(p[15], p[17]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[0], p[23]);\n\tswap(p[3], p[26]);\n\tswap(p[6], p[29]);\n\tswap(p[20], p[9]);\n\tswap(p[15], p[17]);\n\n\tswap(p[2], p[21]);\n\tswap(p[5], p[24]);\n\tswap(p[8], p[27]);\n\tswap(p[18], p[11]);\n\tswap(p[14], p[12]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[2], p[21]);\n\tswap(p[5], p[24]);\n\tswap(p[8], p[27]);\n\tswap(p[18], p[11]);\n\tswap(p[14], p[12]);\n\n\treturn ret;\n}\n\nint main() {\n\n\tint n;\n\tscanf(\"%d\", &n);\n\twhile (n--) {\n\t\tint p[30];\n\t\trep(i, 30)scanf(\"%d\", &p[i]);\n\t\tprintf(\"%d\\n\", solve(p, 0));\n\t}\n\n\tPlease AC;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3548, "score_of_the_acc": -0.0084, "final_rank": 5 }, { "submission_id": "aoj_0300_5740309", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vector<int>>;\nusing vl = vector<ll>;\nusing vvl = vector<vector<ll>>;\nusing pl = pair<ll,ll>;\nusing pi = pair<int,int>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\n#define _GLIBCXX_DEBUG\nconst ll MOD = 1000000007;\nconst ll MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst ll LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n//(a+b-1)/b\n\nint solve(vi p,int last = -1,int cnt = 0){\n\tif(cnt > 8)return 10;\n\tbool ok = 1;\n\trep(i,1,9)if(p[i] != p[i-1]){\n\t\tok = 0;\n\t}\n\trep(i,22,30)if(p[i] != p[i-1])ok = 0;\n\tif(!(p[15] == p[16] && p[16] == p[17]))ok = 0;\n\tif(!(p[18] == p[19] && p[19] == p[20]))ok = 0;\n\tif(!(p[9] == p[10] && p[10] == p[11]))ok = 0;\n\tif(!(p[12] == p[13] && p[13] == p[14]))ok = 0;\n\tif(ok)return 0;\n\tint ans = 10;\n\tif(last != 1){\n\t\tauto p1 = p;\n\t\tswap(p1[12],p1[17]);\n\t\tswap(p1[9],p1[11]);\n\t\trep(i,6,9)swap(p1[i],p1[i+15]);\n\t\tchmin(ans,solve(p1,1,cnt+1)+1);\n\t}\n\tif(last != 2){\n\t\tauto p1 = p;\n\t\tswap(p1[14],p1[15]);\n\t\tswap(p1[20],p1[18]);\n\t\trep(i,0,3)swap(p1[i],p1[i+27]);\n\t\tchmin(ans,solve(p1,2,cnt+1)+1);\n\t}\n\tif(last != 3){\n\t\tauto p1 = p;\n\t\tswap(p1[9],p1[20]);\n\t\tswap(p1[15],p1[17]);\n\t\tswap(p1[0],p1[23]);\n\t\tswap(p1[3],p1[26]);\n\t\tswap(p1[6],p1[29]);\n\t\tchmin(ans,solve(p1,3,cnt+1)+1);\n\n\t}\n\tif(last != 3){\n\t\tauto p1 = p;\n\t\tswap(p1[11],p1[18]);\n\t\tswap(p1[12],p1[14]);\n\t\tswap(p1[2],p1[21]);\n\t\tswap(p1[5],p1[24]);\n\t\tswap(p1[8],p1[27]);\n\t\tchmin(ans,solve(p1,4,cnt+1)+1);\n\t}\n\treturn ans;\n}\n\nsigned main(){\n\t//cout << fixed << setprecision(10);\n\tint n; cin >> n;\n\trep(i,0,n){\n\t\tvi p2(30);\n\t\trep(j,0,30)cin >> p2[j];\n\t\tcout << solve(p2) << endl;\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3372, "score_of_the_acc": -0.0863, "final_rank": 10 }, { "submission_id": "aoj_0300_5739887", "code_snippet": "/*\nこのコード、と~おれ!\nBe accepted!\n∧_∧ \n(。・ω・。)つ━☆・*。\n⊂   ノ    ・゜+.\n しーJ   °。+ *´¨)\n          .· ´¸.·*´¨) ¸.·*¨)\n\t\t           (¸.·´ (¸.·'* ☆\n*/\n\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <iostream>\n#include <random>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <regex>\n#include <functional>\n#include <complex>\n#include <list>\n#include <cassert>\n#include <iomanip>\n#include <set>\n#include <stack>\n#include <bitset>\n#include <array>\n#include <chrono>\n\n//#pragma GCC target(\"arch=skylake-avx512\")\n#pragma GCC target(\"avx2\")\n//#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse4\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define repeat(i, n, m) for(int i = n; i < (m); ++i)\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n#define printynl(a) printf(a ? \"yes\\n\" : \"no\\n\")\n#define printyn(a) printf(a ? \"Yes\\n\" : \"No\\n\")\n#define printYN(a) printf(a ? \"YES\\n\" : \"NO\\n\")\n#define printim(a) printf(a ? \"possible\\n\" : \"imposible\\n\")\n#define printdb(a) printf(\"%.50lf\\n\", a)\n#define printLdb(a) printf(\"%.50Lf\\n\", a)\n#define printdbd(a) printf(\"%.16lf\\n\", a)\n#define prints(s) printf(\"%s\\n\", s.c_str())\n#define all(x) (x).begin(), (x).end()\n#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)\n#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)\n#define Please return\n#define AC 0\n#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr int INF = 1073741823;\nconstexpr int MINF = -1073741823;\nconstexpr ll LINF = ll(4661686018427387903);\nconstexpr ll MOD = 1e9 + 7;\nconstexpr ll mod = 998244353;\nconstexpr long double eps = 1e-6;\nconst long double PI = acosl(-1.0L);\n\nusing namespace std;\n\nvoid scans(string& str) {\n\tchar c;\n\tstr = \"\";\n\tscanf(\"%c\", &c);\n\tif (c == '\\n')scanf(\"%c\", &c);\n\twhile (c != '\\n' && c != -1 && c != ' ') {\n\t\tstr += c;\n\t\tscanf(\"%c\", &c);\n\t}\n}\n\nvoid scanc(char& str) {\n\tchar c;\n\tscanf(\"%c\", &c);\n\tif (c == -1)return;\n\twhile (c == '\\n') {\n\t\tscanf(\"%c\", &c);\n\t}\n\tstr = c;\n}\n\ndouble acot(double x) {\n\treturn PI / 2 - atan(x);\n}\n\nll LSB(ll n) { return (n & (-n)); }\n\ntemplate<typename T>\ninline T chmin(T& a, const T& b) {\n\tif (a > b)a = b;\n\treturn a;\n}\n\ntemplate<typename T>\ninline T chmax(T& a, const T& b) {\n\tif (a < b)a = b;\n\treturn a;\n}\n\n//cpp_int\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\nusing namespace boost::multiprecision;\n#else\nusing cpp_int = ll;\n#endif\n\n//atcoder library\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\n//using namespace atcoder;\n#endif\n\n/*\n\trandom_device seed_gen;\n\tmt19937 engine(seed_gen());\n\tuniform_int_distribution dist(1, 100);\n*/\n\n\n/*----------------------------------------------------------------------------------*/\n\nbool check(int p[30]) {\n\tbool ret = true;\n\tint q = p[0];\n\trep(i, 9) {\n\t\tif (p[i] != q)ret = false;\n\t}\n\tif (not(p[9] == p[10] and p[10] == p[11]))ret = false;\n\tif (not(p[12] == p[13] and p[13] == p[14]))ret = false;\n\tif (not(p[15] == p[16] and p[16] == p[17]))ret = false;\n\tif (not(p[18] == p[19] and p[19] == p[20]))ret = false;\n\tq = p[21];\n\trep(i, 9) {\n\t\tif (p[21 + i] != q)ret = false;\n\t}\n\treturn ret;\n}\n\nint solve(int p[30], int cnt) {\n\tif (cnt == 8)return cnt;\n\tint ret = INF;\n\tif (check(p))ret = cnt;\n\t++cnt;\n\tswap(p[6], p[21]);\n\tswap(p[7], p[22]);\n\tswap(p[8], p[23]);\n\tswap(p[12], p[17]);\n\tswap(p[9], p[11]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[6], p[21]);\n\tswap(p[7], p[22]);\n\tswap(p[8], p[23]);\n\tswap(p[12], p[17]);\n\tswap(p[9], p[11]);\n\n\tswap(p[0], p[27]);\n\tswap(p[1], p[28]);\n\tswap(p[2], p[29]);\n\tswap(p[14], p[15]);\n\tswap(p[20], p[18]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[0], p[27]);\n\tswap(p[1], p[28]);\n\tswap(p[2], p[29]);\n\tswap(p[14], p[15]);\n\tswap(p[20], p[18]);\n\n\tswap(p[0], p[23]);\n\tswap(p[3], p[26]);\n\tswap(p[6], p[29]);\n\tswap(p[20], p[9]);\n\tswap(p[15], p[17]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[0], p[23]);\n\tswap(p[3], p[26]);\n\tswap(p[6], p[29]);\n\tswap(p[20], p[9]);\n\tswap(p[15], p[17]);\n\n\tswap(p[2], p[21]);\n\tswap(p[5], p[24]);\n\tswap(p[8], p[27]);\n\tswap(p[18], p[11]);\n\tswap(p[14], p[12]);\n\tchmin(ret, solve(p, cnt));\n\tswap(p[2], p[21]);\n\tswap(p[5], p[24]);\n\tswap(p[8], p[27]);\n\tswap(p[18], p[11]);\n\tswap(p[14], p[12]);\n\n\treturn ret;\n}\n\nint main() {\n\n\tint n;\n\tscanf(\"%d\", &n);\n\twhile (n--) {\n\t\tint p[30];\n\t\trep(i, 30)scanf(\"%d\", &p[i]);\n\t\tprintf(\"%d\\n\", solve(p, 0));\n\t}\n\n\tPlease AC;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3568, "score_of_the_acc": -0.0088, "final_rank": 6 }, { "submission_id": "aoj_0300_5598939", "code_snippet": "#include<iostream>\n#include <queue>\nusing namespace std;\nstruct cube {\n\tint p[30];\n\tint d;\n\tbool check() {\n\t\tint i;\n\t\tfor (i = 0; i < 8; i++) if (p[i] != p[i + 1]) return false;\n\t\tfor (i = 9; i < 11; i++) if (p[i] != p[i + 1]) return false;\n\t\tfor (i = 12; i < 14; i++) if (p[i] != p[i + 1]) return false;\n\t\tfor (i = 15; i < 17; i++) if (p[i] != p[i + 1]) return false;\n\t\tfor (i = 18; i < 20; i++) if (p[i] != p[i + 1]) return false;\n\t\tfor (i = 21; i < 29; i++) if (p[i] != p[i + 1]) return false;\n\t\treturn true;\n\t}\n\tcube rotate(int x) {\n\t\tcube c; c.d = d + 1;\n\t\tfor (int i = 0; i < 30; i++) c.p[i] = p[i];\n\t\tif (x == 0) {\n\t\t\tc.p[6] = p[21]; c.p[21] = p[6];\n\t\t\tc.p[7] = p[22]; c.p[22] = p[7];\n\t\t\tc.p[8] = p[23]; c.p[23] = p[8];\n\t\t\tc.p[12] = p[17]; c.p[17] = p[12];\n\t\t\tc.p[9] = p[11]; c.p[11] = p[9];\n\t\t\treturn c;\n\t\t}\n\t\tif (x == 1) {\n\t\t\tc.p[2] = p[21]; c.p[21] = p[2];\n\t\t\tc.p[5] = p[24]; c.p[24] = p[5];\n\t\t\tc.p[8] = p[27]; c.p[27] = p[8];\n\t\t\tc.p[11] = p[18]; c.p[18] = p[11];\n\t\t\tc.p[12] = p[14]; c.p[14] = p[12];\n\t\t\treturn c;\n\t\t}\n\t\tif (x == 2) {\n\t\t\tc.p[2] = p[29]; c.p[29] = p[2];\n\t\t\tc.p[1] = p[28]; c.p[28] = p[1];\n\t\t\tc.p[0] = p[27]; c.p[27] = p[0];\n\t\t\tc.p[14] = p[15]; c.p[15] = p[14];\n\t\t\tc.p[18] = p[20]; c.p[20] = p[18];\n\t\t\treturn c;\n\t\t}\n\t\tif (x == 3) {\n\t\t\tc.p[6] = p[29]; c.p[29] = p[6];\n\t\t\tc.p[3] = p[26]; c.p[26] = p[3];\n\t\t\tc.p[0] = p[23]; c.p[23] = p[0];\n\t\t\tc.p[9] = p[20]; c.p[20] = p[9];\n\t\t\tc.p[15] = p[17]; c.p[17] = p[15];\n\t\t\treturn c;\n\t\t}\n\t}\n};\nint main() {\n\tint n;\n\tcin >> n;\n\twhile (n--) {\n\t\tint i, j, k;\n\t\tcube c;\n\t\tfor (i = 0; i < 30; i++) cin >> c.p[i];\n\t\tc.d = 0;\n\t\tqueue<cube> q;\n\t\tq.push(c);\n\t\tint o = 8;\n\t\twhile (!q.empty()) {\n\t\t\tc = q.front(); q.pop();\n\t\t\tif (c.d >= 8) continue;\n\t\t\tif (c.check()) {\n\t\t\t\to = min(o, c.d);\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor (i = 0; i < 4; i++) q.push(c.rotate(i));\n\t\t}\n\t\tcout << o << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 11356, "score_of_the_acc": -0.5031, "final_rank": 14 }, { "submission_id": "aoj_0300_4984135", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nconst double pi = 3.141592653589793238462643383279;\nusing namespace std;\n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\ntypedef long long LL;\ntypedef unsigned long long ULL;\ntypedef vector<LL> VLL;\ntypedef vector<VLL> VVLL;\n\n//container util\n//------------------------------------------\n#define ALL(a) (a).begin(), (a).endf()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SQ(a) ((a) * (a))\n#define EACH(i, c) for (typeof((c).begin()) i = (c).begin(); i != (c).endf(); ++i)\n#define EXIST(s, e) ((s).find(e) != (s).endf())\n#define SORT(c) sort((c).begin(), (c).endf())\n\n//repetition\n//------------------------------------------\n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define MOD 1000000007\n\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n#define sz(x) (int)(x).size()\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\nconst double EPS = 1e-4, PI = acos(-1);\n//ここから編集 \ntypedef string::const_iterator State;\nint ans;\nbool check(vector<int>&v){\n bool f1 = (v[0]==v[1]&&v[1]==v[2]&&v[2]==v[3]&&v[3]==v[4]&&v[4]==v[5]&&v[5]==v[6]&&v[6]==v[7]&&v[7]==v[8]&&v[8]==v[0]);\n bool f2 = (v[27]==v[28]&&v[28]==v[29]&&v[29]==v[21]&&v[21]==v[22]&&v[22]==v[23]&&v[23]==v[24]&&v[24]==v[25]&&v[25]==v[26]&&v[26]==v[27]);\n bool f3 = (v[9]==v[10]&&v[10]==v[11]&&v[11]==v[9]);\n bool f4 = (v[15]==v[16]&&v[16]==v[17]&&v[17]==v[15]);\n bool f5 = (v[18]==v[19]&&v[19]==v[20]&&v[20]==v[18]);\n bool f6 = (v[12]==v[13]&&v[13]==v[14]&&v[14]==v[12]);\n return f1&&f2&&f3&&f4&&f5&&f6;\n}\n\nvoid dfs(vector<int>v, int ti){\n if(ti > 8) return ;\n if(check(v)){\n ans = min(ans, ti);\n return;\n }\n if(ans <= ti) return;\n vector<int> tmp = v;\n swap(tmp[0], tmp[23]);\n swap(tmp[3], tmp[26]);\n swap(tmp[6], tmp[29]);\n swap(tmp[20], tmp[9]);\n swap(tmp[15], tmp[17]);\n dfs(tmp, ti+1);\n\n tmp = v;\n swap(tmp[2], tmp[21]);\n swap(tmp[5], tmp[24]);\n swap(tmp[8], tmp[27]);\n swap(tmp[11], tmp[18]);\n swap(tmp[14], tmp[12]);\n dfs(tmp, ti+1);\n\n tmp = v;\n swap(tmp[0], tmp[27]);\n swap(tmp[1], tmp[28]);\n swap(tmp[2], tmp[29]);\n swap(tmp[15], tmp[14]);\n swap(tmp[20], tmp[18]);\n dfs(tmp, ti+1);\n tmp = v;\n swap(tmp[6], tmp[21]);\n swap(tmp[7], tmp[22]);\n swap(tmp[8], tmp[23]);\n swap(tmp[17], tmp[12]);\n swap(tmp[9], tmp[11]);\n dfs(tmp, ti+1);\n\n}\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n \n int t; cin >> t;\n while(t--){\n vector<int> v(30);\n REP(i,30) cin >> v[i];\n\n ans = INT_MAX;\n dfs(v, 0);\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3176, "score_of_the_acc": -0.0827, "final_rank": 9 }, { "submission_id": "aoj_0300_4813208", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<math.h>\nusing namespace std;\ntypedef long long ll;\n#define int long long\n#define double long double\ntypedef vector<int> VI;\ntypedef pair<int, int> pii;\ntypedef vector<pii> VP;\ntypedef vector<string> VS;\ntypedef priority_queue<int> PQ;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b < a) { a = b; return 1; } return 0; }\n#define fore(i,a) for(auto &i:a)\n#define REP(i,n) for(int i=0;i<n;i++)\n#define eREP(i,n) for(int i=0;i<=n;i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define eFOR(i,a,b) for(int i=(a);i<=(b);++i)\n#define SORT(c) sort((c).begin(),(c).end())\n#define rSORT(c) sort((c).rbegin(),(c).rend())\n#define LB(x,a) lower_bound((x).begin(),(x).end(),(a))\n#define UB(x,a) upper_bound((x).begin(),(x).end(),(a))\n#define INF 1000000000\n#define LLINF 9223372036854775807\n#define mod 1000000007\n#define eps 1e-12 \n//priority_queue<int,vector<int>, greater<int> > q2;\n\nint ANS[] = { 1,1,1,1,1,1,1,1,1,2,2,2,4,4,4,6,6,6,5,5,5,3,3,3,3,3,3,3,3,3 };\nVI A(30);\n\n\nbool check() {\n\tREP(i, 30) {\n\t\tif (A[i] != ANS[i])return false;\n\t}\n\treturn true;\n}\n\nvoid swap1() {\n\tswap(A[6], A[21]);\n\tswap(A[7], A[22]);\n\tswap(A[8], A[23]);\n\tswap(A[12], A[17]);\n\tswap(A[9], A[11]);\n\treturn;\n}\n\nvoid swap2() {\n\tswap(A[0], A[27]);\n\tswap(A[1], A[28]);\n\tswap(A[2], A[29]);\n\tswap(A[15], A[14]);\n\tswap(A[20], A[18]);\n}\n\nvoid swap3() {\n\tswap(A[0], A[23]);\n\tswap(A[3], A[26]);\n\tswap(A[6], A[29]);\n\tswap(A[20], A[9]);\n\tswap(A[17], A[15]);\n}\n\nvoid swap4() {\n\tswap(A[2], A[21]);\n\tswap(A[5], A[24]);\n\tswap(A[8], A[27]);\n\tswap(A[12], A[14]);\n\tswap(A[18], A[11]);\n}\n\n\nint dfs(int cnt) {\n\t/*\n\tcout << cnt << endl;\n\tREP(i, 30)cout << A[i] << \" \";\n\tcout << endl;\n\t*/\n\tint res = INF;\n\tif (cnt == 8)return INF;\n\t\n\tREP(i, 4) {\n\t\tif (i == 0)swap1();\n\t\tif (i == 1)swap2();\n\t\tif (i == 2)swap3();\n\t\tif (i == 3)swap4();\n\n\t\tif (check())chmin(res, cnt + 1);\n\t\telse chmin(res, dfs(cnt + 1));\n\n\t\tif (i == 0)swap1();\n\t\tif (i == 1)swap2();\n\t\tif (i == 2)swap3();\n\t\tif (i == 3)swap4();\n\t}\n\treturn res;\n}\n\nint solve() {\n\tif (check())return 0;\n\tint res = 1020;\n\tREP(i, 4)chmin(res, dfs(0));\n\treturn res;\n}\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tint t; cin >> t;\n\twhile (t--) {\n\t\tREP(i, 30)cin >> A[i];\n\t\tcout << solve() << endl;\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3220, "score_of_the_acc": -0.2457, "final_rank": 13 }, { "submission_id": "aoj_0300_4813200", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<math.h>\nusing namespace std;\ntypedef long long ll;\n#define int long long\n#define double long double\ntypedef vector<int> VI;\ntypedef pair<int, int> pii;\ntypedef vector<pii> VP;\ntypedef vector<string> VS;\ntypedef priority_queue<int> PQ;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b < a) { a = b; return 1; } return 0; }\n#define fore(i,a) for(auto &i:a)\n#define REP(i,n) for(int i=0;i<n;i++)\n#define eREP(i,n) for(int i=0;i<=n;i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define eFOR(i,a,b) for(int i=(a);i<=(b);++i)\n#define SORT(c) sort((c).begin(),(c).end())\n#define rSORT(c) sort((c).rbegin(),(c).rend())\n#define LB(x,a) lower_bound((x).begin(),(x).end(),(a))\n#define UB(x,a) upper_bound((x).begin(),(x).end(),(a))\n#define INF 1000000000\n#define LLINF 9223372036854775807\n#define mod 1000000007\n#define eps 1e-12 \n//priority_queue<int,vector<int>, greater<int> > q2;\n\nint ANS[] = { 1,1,1,1,1,1,1,1,1,2,2,2,4,4,4,6,6,6,5,5,5,3,3,3,3,3,3,3,3,3 };\nVI A(30);\n\n\nbool check(VI tmp) {\n\tREP(i, 30) {\n\t\tif (tmp[i] != ANS[i])return false;\n\t}\n\treturn true;\n}\n\nvoid swap1() {\n\tswap(A[6], A[23]);\n\tswap(A[7], A[22]);\n\tswap(A[8], A[21]);\n\tswap(A[12], A[17]);\n\tswap(A[9], A[11]);\n\treturn;\n}\n\nvoid swap2() {\n\tswap(A[0], A[29]);\n\tswap(A[1], A[28]);\n\tswap(A[2], A[27]);\n\tswap(A[15], A[14]);\n\tswap(A[20], A[18]);\n}\n\nvoid swap3() {\n\tswap(A[0], A[23]);\n\tswap(A[3], A[26]);\n\tswap(A[6], A[29]);\n\tswap(A[20], A[9]);\n\tswap(A[17], A[15]);\n}\n\nvoid swap4() {\n\tswap(A[2], A[21]);\n\tswap(A[5], A[24]);\n\tswap(A[8], A[27]);\n\tswap(A[12], A[14]);\n\tswap(A[18], A[11]);\n}\n\n\nint dfs(int cnt) {\n\t/*\n\tcout << cnt << endl;\n\tREP(i, 30)cout << A[i] << \" \";\n\tcout << endl;\n\t*/\n\tint res = INF;\n\tif (cnt == 8)return INF;\n\t\n\tREP(i, 4) {\n\t\tif (i == 0)swap1();\n\t\t//cout << \"L\" << endl;\n\t\tif (i == 1)swap2();\n\t\tif (i == 2)swap3();\n\t\tif (i == 3)swap4();\n\n\t\tif (check(A))chmin(res, cnt + 1);\n\t\telse chmin(res, dfs(cnt + 1));\n\n\t\tif (i == 0)swap1();\n\t\tif (i == 1)swap2();\n\t\tif (i == 2)swap3();\n\t\tif (i == 3)swap4();\n\t}\n\treturn res;\n}\n\nint solve() {\n\tif (check(A))return 0;\n\tint res = 1020;\n\tREP(i, 4)chmin(res, dfs(0));\n\treturn res;\n}\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tint t; cin >> t;\n\twhile (t--) {\n\t\tREP(i, 30)cin >> A[i];\n\t\tcout << solve() << endl;\n\t}\n\n\n\treturn 0;\n}", "accuracy": 0.125, "time_ms": 380, "memory_kb": 3176, "score_of_the_acc": -1.0016, "final_rank": 19 } ]
aoj_0308_cpp
デッドロックを検出せよ コンピュータにおける「データベース」とは、情報を管理するための入れ物で、「データベースマネジメントシステム(DBMS)」とは、その管理をする仕組みです。複数のユーザが利用するデータベースでは、DBMS は慎重に構築する必要があります。 例えば、倉庫から商品を1つ取り出した人が、データベースに対して以下の処理を行うとしましょう。 (1) 商品の個数 N をデータベースから読む。 (2) 新たな商品の個数 N -1 をデータベースに書き込む。 ユーザ1が(1)を終えて(2)を始める前に、別のユーザ2が倉庫から商品を取り出して(1)を行ったとします。ユーザ2もユーザ1と同じ個数を読むので、2人が(2)を終えたときには商品は2個減るのにデータベース上では1個しか減らないというおかしな結果になります。このような問題を防ぐために、DBMS は特定のデータを操作中のユーザに、そのデータを「ロック」する権利を与えます。ロックされていれば、他のユーザはその値を操作できなくなるので、おかしな結果を返すことはなくなります。 これで安全に操作できることは保証されますが、今度は別の問題が起こります。例えば、ユーザ1とユーザ2が以下のような順番でデータAとBをロックしようとしたらどうなるでしょうか? (1) ユーザ1がデータAのロックを試みる → 成功(データAがロック中になる) (2) ユーザ2がデータBのロックを試みる → 成功(データBがロック中になる) (3) ユーザ1がデータBのロックを試みる → データBがロック中なのでユーザ1は待つ (4) ユーザ2がデータAのロックを試みる → データAがロック中なのでユーザ2は待つ (4)を実行した時点では、ユーザ1がA、ユーザ2がBをロックしているので、(3)(4)は永久に成功しませ ん。これを「デッドロック」と呼びます。DBMS はこれを検出しなければなりません。 ある時点でデッドロックが起きているかどうかは、その時点でのすべてのユーザとデータの依存関係を書き、循環ができているかどうかで判断できます。依存関係は,ユーザがデータをロック済みの場合はデータからユーザの向きに矢印を、ユーザがデータのロックを試行していて待ち状態になっている場合はユーザからデータの向きに矢印を書くことで表します。 上の(1)から(4)の例であれば、(4)を実行した時点での依存関係は右上のような図になります。このとき、矢印の方向に進むと、ユーザ1→データB→ユーザ2→データA→ユーザ1という循環ができているため、デッドロックが起きていることがわかります。DBMS の苦労を体験するため、あなたにここでやってもらいたいのは、このようなデッドロックを検出するプログラムを作成することです。 入力 入力は以下の形式で与えられる。 N rel 1 rel 2 : rel N 1行目にユーザとデータの依存関係の数 N (1 ≤ N ≤ 1000) が与えられる。続く N 行に、ユーザとデータの依存関係 rel i が与えられる。依存関係は lock と wait の2種類あり、各 rel i は以下のいずれかの形式で与えられる。 u lock d または u wait d u lock d は、ユーザ u (1 ≤ u ≤ 100) が、データ d (1 ≤ d ≤ 100) をロック済みであることを表す。 u wait d は、ユーザ u (1 ≤ u ≤ 100) が、データ d (1 ≤ d ≤ 100) のロックを試行していて待ち状態であることを表す。 ただし、入力は以下の条件を満たしていると仮定してよい。 ロックされていないデータに対して、ユーザが待ち状態ではない。 二人以上のユーザにロックされているデータはない。 ユーザ自身がロックしているデータに対して、待ち状態ではない。 同じ依存関係は与えられない。 出力 デッドロックが発生しているなら 1、発生していないなら 0 を1行に出力する。 入出力例 入力例1 4 1 lock 1 2 lock 2 1 wait 2 2 wait 1 出力例1 1 入力例2 4 3 lock 3 2 wait 3 3 lock 4 2 wait 4 出力例2 0
[ { "submission_id": "aoj_0308_2719446", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define MAX_V 10000000\n#define MAX_E 10000000\n#define INF 1111111111\nstruct edge{int from,to,cost;};\n\nedge es[MAX_E]; \nint d[MAX_V]; \nint V=202,E;\n\nbool find_negative_loop(){\n memset(d,0,sizeof(d));\n for(int i=0;i<V;i++){\n for(int j=0;j<E;j++){\n edge e=es[j];\n if(d[e.to]>d[e.from]+e.cost){\n\td[e.to]=d[e.from]+e.cost;\n\tif(i==V-1)return true;\n }\n }\n } \n return false;\n}\n\n\nsigned main(){\n cin>>E;\n for(int i=0;i<E;i++){\n int u,d;\n string a;\n cin>>u>>a>>d;\n if(a[0]=='w')es[i]=(edge){u,d+101,-1};\n else es[i]=(edge){d+101,u,-1};\n }\n cout<<find_negative_loop()<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 42280, "score_of_the_acc": -1, "final_rank": 7 }, { "submission_id": "aoj_0308_2581640", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\n#define pb push_back\n#define rep(i, a, n) for(int i = (a); i < (n); i++)\n#define dep(i, a, n) for(int i = (a); i >= (n); i--)\n#define mod 1e9+7\n\n__attribute__((constructor))\nvoid initial() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n}\n\nint n;\nvector<int> u[101];\nint d[101];\nint f = 0;\n\nvoid solve(int i, int m, map<int, int> loopU, map<int, int> loopD) {\n if(f) return;\n if(m == 0) {\n if(loopD[i]) {\n f = 1;\n return;\n }\n loopD[i] = 1;\n if(d[i]) solve(d[i], !m, loopU, loopD);\n }else {\n if(loopU[i]) {\n f = 1;\n return;\n }\n loopU[i] = 1;\n rep(j, 0, u[i].size()) {\n solve(u[i][j], !m, loopU, loopD);\n }\n }\n}\n\nint main() {\n cin >> n;\n rep(i, 0, n) {\n int a, b;\n string s;\n cin >> a >> s >> b;\n if(s[0] == 'l') {\n d[b] = a;\n }else {\n u[a].pb(b);\n }\n }\n rep(i, 1, 101) {\n if(d[i]) {\n map<int, int> a, b;\n solve(i, 0, a, b);\n }\n }\n rep(i, 1, 101) {\n if(u[i].size() > 0) {\n map<int, int> a, b;\n solve(i, 1, a, b);\n }\n }\n cout << f << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4152, "score_of_the_acc": -0.3451, "final_rank": 6 }, { "submission_id": "aoj_0308_2507724", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nint n,d[222][222],f,a,b;\nstring s;\nmain(){\n cin>>n;\n r(i,222)r(j,222)d[i][j]=(i==j?0:1e8);\n while(n--){\n cin>>a>>s>>b;\n if(s==\"lock\")d[a][b+111]=-1;\n else d[b+111][a]=-1;\n }\n r(o,222)r(i,222)r(j,222)d[i][j]=min(d[i][j],d[i][o]+d[o][j]);\n r(i,222)if(d[i][i]<0)f++;\n cout<<(f?1:0)<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3380, "score_of_the_acc": -0.0536, "final_rank": 5 }, { "submission_id": "aoj_0308_2143531", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nint mincost[200][200];\nint main() {\n\tfor (int i = 0; i < 200; i++)fill(mincost[i], mincost[i] + 200, 1 << 29);\n\tint a; cin >> a;\n\tfor (int b = 0; b < a; b++) {\n\t\tint c, e; string d;\n\t\tcin >> c >> d >> e; c--; e=e+99;\n\t\tif (d[0] == 'l') {\n\t\t\tmincost[e][c] = 0;\n\t\t}\n\t\telse {\n\t\t\tmincost[c][e] = 0;\n\t\t}\n\t}\n\tfor (int c = 0; c < 200; c++) {\n\t\tfor (int d = 0; d < 200; d++) {\n\t\t\tfor (int e = 0; e < 200; e++) {\n\t\t\t\tmincost[d][e] = min(mincost[d][e], mincost[d][c] + mincost[c][e]);\n\t\t\t}\n\t\t}\n\t}\n\tbool S = false;\n\tfor (int i = 0; i < 200; i++) {\n\t\tif (mincost[i][i] == 0)S = true;\n\t}\n\tcout << S << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3328, "score_of_the_acc": -0.0524, "final_rank": 3 }, { "submission_id": "aoj_0308_2095475", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nconstexpr int MAX = 200;\nconstexpr int INF = (1 << 29);\n\nint main()\n{\n int N, u, v, d[MAX][MAX];\n string s;\n\n for (int i = 0; i < MAX; i++) {\n for (int j = 0; j < MAX; j++) {\n d[i][j] = (i != j) * INF;\n }\n }\n \n cin >> N; \n for (int i = 0; i < N; i++) {\n cin >> u >> s >> v;\n u--; v--; v += MAX / 2;\n if (s == \"lock\") swap(u, v);\n d[u][v] = -1;\n }\n\n for (int k = 0; k < MAX; k++) {\n for (int i = 0; i < MAX; i++) {\n for (int j = 0; j < MAX; j++) {\n d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n }\n }\n }\n \n bool res = 0;\n for (int i = 0; i < MAX; i++) {\n if (d[i][i] < 0) {\n res = 1;\n break;\n }\n }\n cout << res << endl; \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3348, "score_of_the_acc": -0.0528, "final_rank": 4 }, { "submission_id": "aoj_0308_2076657", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define each(itr,c) for(__typeof(c.begin()) itr=c.begin(); itr!=c.end(); ++itr)\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n\nint l[100][100]={0}, w[100][100]={0};\n\nint main()\n{\n int n;\n scanf(\" %d\", &n);\n rep(i,n)\n {\n int u,d;\n char s[10];\n scanf(\" %d %s %d\", &u, s, &d);\n --u;\n --d;\n\n if(s[0]=='l') l[u][d]=1;\n else w[u][d]=1;\n }\n\n int ans=0;\n rep(a,100)rep(b,a)\n {\n rep(i,100)rep(j,100)\n {\n if(i==j) continue;\n if(l[a][i] && w[a][j] && l[b][j] && w[b][i]) ans=1;\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 0.3, "time_ms": 30, "memory_kb": 3208, "score_of_the_acc": -0.2313, "final_rank": 10 }, { "submission_id": "aoj_0308_1956299", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <numeric>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <utility>\n#include <sstream>\n#include <complex>\n#include <fstream>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(long long i=(a);i<(b);i++)\n#define REP(i,N) for(long long i=0;i<(N);i++)\n#define ALL(s) (s).begin(),(s).end()\n#define fi first\n#define se second\n\n#define PI acos(-1.0)\n#define INF 10e15+9\n#define MOD 1000000007\n#define EPS 1e-10\n#define MAX_N 100100\n#define MAX_M 100100\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef pair<double, double> PD;\ntypedef pair<string, ll> PS;\ntypedef vector<ll> V;\ntypedef pair<P, char> PC;\n\nint n;\nint u, d;\nstring rel;\nvector<int> data[110];\nint user[110];\nbool ans = 0;\n\nvoid check(bool mode, int num, int search){\n\t//cout << num << endl;\n\tif (mode == 0){\n\t\tcheck(1, user[num], search);\n\t}\n\telse{\n\t\tif (data[num].size() == 0)return;\n\t\tREP(i, data[num].size()){\n\t\t\tif (data[num][i] == search){\n\t\t\t\tans = 1;\n\t\t\t\treturn;\n\t\t\t}\n\t\t\tcheck(0, data[num][i], search);\n\t\t}\n\t}\n}\n\nint main(){\n\tcin >> n;\n\tREP(i, n){\n\t\tcin >> u >> rel >> d;\n\t\tif (rel == \"lock\"){\n\t\t\tdata[d].push_back(u);\n\t\t}\n\t\telse{\n\t\t\tuser[u] = d;\n\t\t}\n\t}\n\n\tFOR(i, 1, 101){\n\t\tif (user[i])check(1, user[i], i);\n\t}\n\n\tif (ans)cout << 1 << endl;\n\telse cout << 0 << endl;\n}", "accuracy": 0.2, "time_ms": 10, "memory_kb": 19344, "score_of_the_acc": -0.442, "final_rank": 12 }, { "submission_id": "aoj_0308_1956181", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <numeric>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <utility>\n#include <sstream>\n#include <complex>\n#include <fstream>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(long long i=(a);i<(b);i++)\n#define REP(i,N) for(long long i=0;i<(N);i++)\n#define ALL(s) (s).begin(),(s).end()\n#define fi first\n#define se second\n\n#define PI acos(-1.0)\n#define INF 10e15+9\n#define MOD 1000000007\n#define EPS 1e-10\n#define MAX_N 100100\n#define MAX_M 100100\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef pair<double, double> PD;\ntypedef pair<string, ll> PS;\ntypedef vector<ll> V;\ntypedef pair<P, char> PC;\n\nint n;\nint u, d;\nstring rel;\nbool lock[110][110], wait[110][110];\n\nint main(){\n\tcin >> n;\n\tREP(i, n){\n\t\tcin >> u >> rel >> d;\n\t\tif (rel == \"lock\"){\n\t\t\tlock[u][d] = 1;\n\t\t}\n\t\telse{\n\t\t\twait[u][d] = 1;\n\t\t}\n\t}\n\tFOR(i,1, 101){\n\t\tFOR(j,1, 101){\n\t\t\tFOR(k,1, 101){\n\t\t\t\tFOR(l, 1, 101){\n\t\t\t\t\tif (lock[i][j] && lock[k][l]){\n\t\t\t\t\t\tif (wait[i][l] && wait[k][j]){\n\t\t\t\t\t\t\tcout << 1 << endl;\n\t\t\t\t\t\t\treturn 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl;\n}", "accuracy": 0.3, "time_ms": 70, "memory_kb": 1216, "score_of_the_acc": -0.5464, "final_rank": 11 }, { "submission_id": "aoj_0308_1931093", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<queue>\nusing namespace std;\nvector<int>G[240]; int dist[240];\nint main() {\n\tint n; cin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tint a, b; string S;\n\t\tcin >> a >> S >> b; a--; b--;\n\t\tif (S == \"wait\") { G[a].push_back(b + 120); }\n\t\tif (S == \"lock\") { G[b + 120].push_back(a); }\n\t}\n\tint C = 0;\n\tfor (int i = 0; i < 240; i++) {\n\t\tqueue<int>Q;\n\t\tfor (int j = 0; j < 240; j++)dist[j] = 0;\n\t\tQ.push(i); int cnt = 0;\n\t\twhile (!Q.empty()) {\n\t\t\tcnt++; int a1 = Q.front(); Q.pop();\n\t\t\tif (cnt >= 100000) { C = 1; break; }\n\t\t\tfor (int j = 0; j < G[a1].size(); j++) {\n\t\t\t\tif (dist[G[a1][j]]>dist[a1] - 1) {\n\t\t\t\t\tdist[G[a1][j]] = dist[a1] - 1;\n\t\t\t\t\tQ.push(G[a1][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << C << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 1248, "score_of_the_acc": -1.0018, "final_rank": 8 }, { "submission_id": "aoj_0308_1672152", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#define M 201\nusing namespace std;\ntypedef pair<int,int> P;\nvoid func(int);\nint N,u,d;\nvector<int> node;\nbool edge[M][M],ans;\nmap<P,bool> visited;\nstring s;\n\nint main(){\n cin>>N;\n for(int i=0;i<M;i++)\n for(int j=0;j<M;j++) edge[i][j]=false;\n while(N--){\n cin>>u>>s>>d;\n node.push_back(u);\n if(s==\"lock\") edge[u][d+100]=true;\n else edge[d+100][u]=true;\n }\n for(int i=0;i<(int)node.size();i++){\n func(node[i]);\n if(ans) break;\n visited.clear();\n }\n if(ans) cout<<1<<endl;\n else cout<<0<<endl;\n return 0;\n}\n\nvoid func(int x){\n if(ans) return ;\n for(int i=0;i<M;i++){\n if(edge[x][i]){\n if(visited.find(make_pair(x,i))!=visited.end()&&visited[make_pair(x,i)]==true){\n\tans=true;\n\tbreak;\n }\n visited[make_pair(x,i)]=true;\n func(i);\n }\n }\n}", "accuracy": 0.75, "time_ms": 20, "memory_kb": 1328, "score_of_the_acc": -0.0946, "final_rank": 9 }, { "submission_id": "aoj_0308_1663160", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int INF = 1 << 28;\n\nint main()\n{\n int N;\n int graph[200][200];\n fill_n(*graph, 200 * 200, INF);\n for(int i = 0; i < 200; i++) graph[i][i] = 0;\n\n cin >> N;\n while(N--) {\n int u, d;\n string type;\n cin >> u >> type >> d;\n --u, --d;\n if(type == \"lock\") graph[100 + d][u] = -1;\n else graph[u][100 + d] = -1;\n }\n for(int k = 0; k < 200; k++) {\n for(int i = 0; i < 200; i++) {\n for(int j = 0; j < 200; j++) {\n graph[i][j] = min(graph[i][j], graph[i][k] + graph[k][j]);\n }\n }\n }\n bool flag = false;\n for(int i = 0; i < 200; i++) {\n flag |= graph[i][i] < 0;\n }\n cout << flag << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1364, "score_of_the_acc": -0.0046, "final_rank": 2 }, { "submission_id": "aoj_0308_1659479", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nint g[210][210];\nchar in[10];\nint main(){\n\tint a;scanf(\"%d\",&a);\n\tfor(int i=0;i<200;i++)g[i][i]=1;\n\tfor(int i=0;i<a;i++){\n\t\tint p,q;scanf(\"%d%s%d\",&p,in,&q);\n\t\tp--;q--;\n\t\tif(in[0]=='l')g[p][q+100]=1;\n\t\telse g[q+100][p]=1;\n\t}\n\tfor(int k=0;k<200;k++)for(int i=0;i<200;i++)for(int j=0;j<200;j++){\n\t\tif(g[i][k]&&g[k][j])g[i][j]=1;\n\t}\n\tfor(int i=0;i<200;i++)for(int j=i+1;j<200;j++){\n\t\tif(g[i][j]&&g[j][i]){printf(\"1\\n\");return 0;}\n\t}\n\tprintf(\"0\\n\");\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1176, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0303_cpp
力持ち 力持ちたちが集う力持ち学園がありました。力持ち学園の運動会では、力持ちたちが隊列を組んで行進します。 力持ちたちは常に自分たちの力を誇示したい一方で、彼らの大半は自分で歩きたくありません。そこで彼らの一部が一番下になり、その上に大勢の人を縦一列に持ちあげて歩くことで、実際に歩く人数を減らそうと考えました。 はじめに、 N 人の力持ちは地面の上に横一列に並んでいて、それぞれ左側から 1,2,3,..., N と通し番号で呼ばれています。通し番号 i の力持ちの体重は w i で最大 c i の重量まで持つことができます。 力持ちは、以下の条件をすべて満たすときだけ、隣に立っている左右どちらかの力持ちを持ちあげることができます。 自分の上下には力持ちはいない。つまり、誰かに持ち上げられてもいないし、誰かを持ちあげてもいない。 隣の力持ちの体重が、自分が持つことのできる最大の重量以下である。ただし、隣の力持ちが既に誰かを持ち上げているなら、縦に積み上がった力持ちたちの体重の合計が、自分が持つことのできる最大の重量以下でなければならない。 例えば、次のような3人の力持ちの隊列を考えてみましょう。 下図のように、2の力持ちが持つことのできる重さが w 3 以上のとき、2の力持ちは3の力持ちを持ちあげることができます。続いて、1の力持ちが持つことのできる重さが w 2 + w 3 以上のとき、1の力持ちは2の力持ちを持ちあげることができます。 → また、下図のように3の力持ちが2の力持ちを持ちあげた場合は、1の力持ちの隣が、2の力持ちを持った3の力持ちになるので、1の力持ちは3の力持ちを持ちあげることができます。 → 2の力持ちが、下の図のように1と3の力持ちを両方持つことはできません。 力持ち学園の専属プログラマーとして、一番下で歩くことになる最小の人数を求めてください。 入力 入力は以下の形式で与えられる。 N c 1 w 1 c 2 w 2 : c N w N 1 行目に力持ちの人数 N (1 ≤ N ≤ 1000) が与えられる。続く N 行に i 番目の力持ちが持てる重量の最大値 c i (1 ≤ c i ≤ 100000) と体重 w i (1 ≤ w i ≤ 100000) が与えられる。 出力 最小の人数を1行に出力する。 入出力例 入力例1 3 150 120 100 50 80 100 出力例1 1 入力例2 8 50 100 20 20 30 20 90 50 140 30 30 60 59 120 10 10 出力例2 3
[ { "submission_id": "aoj_0303_10691213", "code_snippet": "// competitive-verifier: PROBLEM\n#pragma GCC optimize(\"Ofast,fast-math,unroll-all-loops\")\n#include <bits/stdc++.h>\n#if !defined(ATCODER) && !defined(EVAL)\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#endif\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = 3.14159265358979323846;\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m) - 1; i >= int(n); --i)\n#define FORL(i, m, n) for (std::int64_t i = (m); i < std::int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n constexpr void operator()() const {}\n} sonic;\nstruct increment_impl {\n template <class T>\n const increment_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) ++x;\n return *this;\n }\n} Inc;\nstruct decrement_impl {\n template <class T>\n const decrement_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) --x;\n return *this;\n }\n} Dec;\nstruct sort_impl {\n template <class T>\n const sort_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n return *this;\n }\n} Sort;\nstruct unique_impl {\n template <class T>\n const unique_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n v.erase(std::unique(v.begin(), v.end()), v.end());\n return *this;\n }\n} Uniq;\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) os << (it == v.begin() ? \"\" : \" \") << *it;\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\nvoid Yes(bool is_correct = true) { std::cout << (is_correct ? \"Yes\\n\" : \"No\\n\"); }\nvoid No(bool is_not_correct = true) { Yes(!is_not_correct); }\nvoid YES(bool is_correct = true) { std::cout << (is_correct ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO(bool is_not_correct = true) { YES(!is_not_correct); }\nvoid Takahashi(bool is_correct = true) { std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n'; }\nvoid Aoki(bool is_not_correct = true) { Takahashi(!is_not_correct); }\n/// @brief 累積和\ntemplate <class T = std::int64_t>\nstruct prefix_sum {\n prefix_sum(int _n) : n(_n), data(_n + 1) {}\n template <class U>\n prefix_sum(const std::vector<U> &v) : n(v.size()), data(v.size() + 1) {\n for (int i = 0; i < n; ++i) data[i] = v[i];\n build();\n }\n void build() {\n for (int i = n - 1; i >= 0; --i) data[i] += data[i + 1];\n }\n T get(int k) const {\n assert(0 <= k && k < n);\n return data[k] - data[k + 1];\n }\n void set(int k, int x) { data[k] = x; }\n void add(int k, int x) { data[k] += x; }\n T sum(int r) const {\n assert(0 <= r && r <= n);\n return data[0] - data[r];\n }\n T sum(int l, int r) const {\n assert(0 <= l && l <= r && r <= n);\n return data[l] - data[r];\n }\n int min_left(T x) const { return min_left(0, x); }\n int min_left(int l, T x) const {\n assert(0 <= l && l <= n);\n int left = l, right = n + 1;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[l] - data[mid] >= x ? right : left) = mid;\n }\n return right;\n }\n int max_right(T x) const { return max_right(n, x); }\n int max_right(int r, T x) const {\n assert(0 <= r && r <= n);\n int left = -1, right = r;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[mid] - data[r] >= x ? left : right) = mid;\n }\n return left;\n }\n private:\n int n;\n std::vector<T> data;\n};\nint main(void) {\n int n;\n cin >> n;\n vector<int> c(n), w(n);\n rep (i, n) cin >> c[i] >> w[i];\n prefix_sum<ll> ps(w);\n vector dp(n + 1, vector(n + 1, 0));\n repn (d, n) {\n rep (l, n) {\n int r = l + d;\n if (r > n)\n break;\n dp[l][r] = r - l;\n FOR (m, l + 1, r) chmin(dp[l][r], dp[l][m] + dp[m][r]);\n if (dp[l][r - 1] == 1 && ps.sum(l, r - 1) <= c[r - 1])\n dp[l][r] = 1;\n if (dp[l + 1][r] == 1 && ps.sum(l + 1, r) <= c[l])\n dp[l][r] = 1;\n }\n }\n co(dp[0][n]);\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 7296, "score_of_the_acc": -0.3536, "final_rank": 4 }, { "submission_id": "aoj_0303_10691211", "code_snippet": "// competitive-verifier: PROBLEM\n#pragma GCC optimize(\"Ofast,fast-math,unroll-all-loops\")\n#include <bits/stdc++.h>\n#if !defined(ATCODER) && !defined(EVAL)\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#endif\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = 3.14159265358979323846;\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m) - 1; i >= int(n); --i)\n#define FORL(i, m, n) for (std::int64_t i = (m); i < std::int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n constexpr void operator()() const {}\n} sonic;\nstruct increment_impl {\n template <class T>\n const increment_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) ++x;\n return *this;\n }\n} Inc;\nstruct decrement_impl {\n template <class T>\n const decrement_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) --x;\n return *this;\n }\n} Dec;\nstruct sort_impl {\n template <class T>\n const sort_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n return *this;\n }\n} Sort;\nstruct unique_impl {\n template <class T>\n const unique_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n v.erase(std::unique(v.begin(), v.end()), v.end());\n return *this;\n }\n} Uniq;\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) os << (it == v.begin() ? \"\" : \" \") << *it;\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\nvoid Yes(bool is_correct = true) { std::cout << (is_correct ? \"Yes\\n\" : \"No\\n\"); }\nvoid No(bool is_not_correct = true) { Yes(!is_not_correct); }\nvoid YES(bool is_correct = true) { std::cout << (is_correct ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO(bool is_not_correct = true) { YES(!is_not_correct); }\nvoid Takahashi(bool is_correct = true) { std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n'; }\nvoid Aoki(bool is_not_correct = true) { Takahashi(!is_not_correct); }\n/// @brief 累積和\ntemplate <class T = std::int64_t>\nstruct prefix_sum {\n prefix_sum(int _n) : n(_n), data(_n + 1) {}\n template <class U>\n prefix_sum(const std::vector<U> &v) : n(v.size()), data(v.size() + 1) {\n for (int i = 0; i < n; ++i) data[i] = v[i];\n build();\n }\n void build() {\n for (int i = n - 1; i >= 0; --i) data[i] += data[i + 1];\n }\n T get(int k) const {\n assert(0 <= k && k < n);\n return data[k] - data[k + 1];\n }\n void set(int k, int x) { data[k] = x; }\n void add(int k, int x) { data[k] += x; }\n T sum(int r) const {\n assert(0 <= r && r <= n);\n return data[0] - data[r];\n }\n T sum(int l, int r) const {\n assert(0 <= l && l <= r && r <= n);\n return data[l] - data[r];\n }\n int min_left(T x) const { return min_left(0, x); }\n int min_left(int l, T x) const {\n assert(0 <= l && l <= n);\n int left = l, right = n + 1;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[l] - data[mid] >= x ? right : left) = mid;\n }\n return right;\n }\n int max_right(T x) const { return max_right(n, x); }\n int max_right(int r, T x) const {\n assert(0 <= r && r <= n);\n int left = -1, right = r;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[mid] - data[r] >= x ? left : right) = mid;\n }\n return left;\n }\n private:\n int n;\n std::vector<T> data;\n};\nint main(void) {\n int n;\n cin >> n;\n vector<int> c(n), w(n);\n rep (i, n) cin >> c[i] >> w[i];\n rep (i, n) {\n c.emplace_back(c[i]);\n w.emplace_back(w[i]);\n }\n prefix_sum<ll> ps(w);\n vector dp(n * 2 + 1, vector(n * 2 + 1, 0));\n rep (i, n * 2) dp[i][i + 1] = 1;\n FOR (d, 2, n + 1) {\n rep (l, n * 2) {\n int r = l + d;\n if (r > n * 2)\n break;\n dp[l][r] = r - l;\n FOR (m, l + 1, r) chmin(dp[l][r], dp[l][m] + dp[m][r]);\n if (dp[l][r - 1] == 1 && ps.sum(l, r - 1) <= c[r - 1])\n dp[l][r] = 1;\n if (dp[l + 1][r] == 1 && ps.sum(l + 1, r) <= c[l])\n dp[l][r] = 1;\n }\n }\n co(dp[0][n]);\n return 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 19072, "score_of_the_acc": -1.6885, "final_rank": 20 }, { "submission_id": "aoj_0303_9580834", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<pair<int,int>> a(n);\n\tvector<int> s(n,0);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i].first >> a[i].second;\n\t\ts[i] += a[i].second;\n\t\tif(i != 0){\n\t\t\ts[i] += s[i - 1];\n\t\t}\n\t}\n\tfunction<int(int,int)> sum = [&](int l,int r) -> int {\n\t\treturn s[r] - (l == 0 ? 0 : s[l - 1]);\n\t};\n\tvector<vector<int>> dp(n,vector<int>(n,INT_MAX));\n\tfor(int i = 0;i < n;i++){\n\t\tdp[i][i] = 1;\n\t}\n\tfor(int i = 2;i <= n;i++){\n\t\tfor(int j = 0;j < n;j++){\n\t\t\tint r = j + i - 1;\n\t\t\tif(r >= n) break;\n\t\t\tif(sum(j + 1,r) <= a[j].first && dp[j + 1][r] == 1){\n\t\t\t\tdp[j][r] = min(dp[j][r],dp[j][j]);\n\t\t\t}\n\t\t\tif(sum(j,r - 1) <= a[r].first && dp[j][r - 1] == 1){\n\t\t\t\tdp[j][r] = min(dp[j][r],dp[r][r]);\n\t\t\t}\n\t\t\tfor(int k = j;k < r;k++){\n\t\t\t\tdp[j][r] = min(dp[j][r],dp[j][k] + dp[k + 1][r]);\n\t\t\t}\n\t\t}\n\t}\n\tcout << dp[0][n - 1] << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 7364, "score_of_the_acc": -0.4237, "final_rank": 6 }, { "submission_id": "aoj_0303_8730400", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<pair<int,int>> a(n,pair<int,int>());\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i].first >> a[i].second;\n\t}\n\tvector<vector<int>> dp(n,vector<int>(n,n));\n\tfor(int i = 0;i < n;i++) dp[i][i] = 1;\n\tvector<int> sum(n);\n\tsum[0] = a[0].second;\n\tfor(int i = 1;i < n;i++){\n\t\tsum[i] = sum[i - 1] + a[i].second;\n\t}\n\tfor(int d = 1;d < n;d++){\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tint left = i,right = i + d;\n\t\t\tif(right >= n) continue;\n\t\t\tif(dp[left + 1][right] == 1){\n\t\t\t\tint it = sum[right];\n\t\t\t\tit -= sum[left];\n\t\t\t\tif(it <= a[left].first){\n\t\t\t\t\tdp[left][right] = 1;\n\t\t\t\t}else{\n\t\t\t\t\tdp[left][right] = min(dp[left][right],2);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(dp[left][right - 1] == 1){\n\t\t\t\tint it = sum[right - 1];\n\t\t\t\tif(left != 0){\n\t\t\t\t\tit -= sum[left - 1];\n\t\t\t\t}\n\t\t\t\tif(it <= a[right].first){\n\t\t\t\t\tdp[left][right] = 1;\n\t\t\t\t}else{\n\t\t\t\t\tdp[left][right] = min(dp[left][right],2);\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int k = left;k < right;k++){\n\t\t\t\tdp[left][right] = min(dp[left][right],dp[left][k] + dp[k + 1][right]);\n\t\t\t}\n\t\t}\n\t}\n\tcout << dp[0][n - 1] << endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7396, "score_of_the_acc": -0.4095, "final_rank": 5 }, { "submission_id": "aoj_0303_5868900", "code_snippet": "#include <iostream>\n#include <utility>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <queue>\nusing namespace std;\nusing ll = long long int;\n#define chmax(x,y) (x) = ((x) > (y)) ? (x) : ((x) = (y));\n#define chmin(x,y) (x) = ((x) < (y)) ? (x) : ((x) = (y));\nconst int INF = 1e9;\n\nint main(int argc, char const *argv[])\n{\n int N; cin >> N;\n vector<pair<int,int>> data(N);\n for(auto &d : data) cin >> d.first >> d.second;\n vector<int> sumw(N+1);\n for(int i=0;i<N;++i)\n {\n sumw[i+1] = sumw[i] + data[i].second;\n }\n vector<vector<int>> dp(N+1,vector<int>(N+1,INF));\n vector<vector<int>> weight(N+1,vector<int>(N+1));\n for(int i=0;i<N;++i)\n {\n dp[i][i+1] = 1;\n }\n\n for(int len=2;len<=N;++len)\n {\n for(int i=0;i<N;++i)\n {\n int r = i+len;\n if(r > N)continue;\n for(int k=i+1;k<r;++k)\n {\n chmin(dp[i][r],dp[i][k]+dp[k][r]);\n }\n int lcap = data[i].first;\n int rcap = data[i+len-1].first;\n if( dp[i+1][i+len] == 1 && lcap >= sumw[i+len] - sumw[i+1])\n {\n chmin(dp[i][r],1);\n }\n if(dp[i][i+len-1] == 1 && rcap >= sumw[i+len-1] - sumw[i])\n {\n chmin(dp[i][r],1);\n }\n }\n }\n\n std::cout << dp[0][N] << std::endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 11248, "score_of_the_acc": -0.6856, "final_rank": 13 }, { "submission_id": "aoj_0303_5740217", "code_snippet": "#include<iostream>\n#include<stdio.h>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<string>\n#include<map>\n#include<string.h>\n#include<complex>\n#include<math.h>\n#include<queue>\n#include <functional>\n#include<time.h>\n#include<iomanip>\n#include<cassert>\n#include<bitset>\n#include<sstream>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nclass UnionFind {\npublic:\n\t//親の番号を格納する。親だった場合は-(その集合のサイズ)\n\tvector<int> Parent;\n\n\t//作るときはParentの値を全て-1にする\n\t//こうすると全てバラバラになる\n\tUnionFind(int N) {\n\t\tParent = vector<int>(N, -1);\n\t}\n\n\t//Aがどのグループに属しているか調べる\n\tint root(int A) {\n\t\tif (Parent[A] < 0) return A;\n\t\treturn Parent[A] = root(Parent[A]);\n\t}\n\n\t//自分のいるグループの頂点数を調べる\n\tint size(int A) {\n\t\treturn -Parent[root(A)];//親をとってきたい\n\t}\n\n\t//AとBをくっ付ける\n\tbool connect(int A, int B) {\n\t\t//AとBを直接つなぐのではなく、root(A)にroot(B)をくっつける\n\t\tA = root(A);\n\t\tB = root(B);\n\t\tif (A == B) {\n\t\t\t//すでにくっついてるからくっ付けない\n\t\t\treturn false;\n\t\t}\n\n\t\t//大きい方(A)に小さいほう(B)をくっ付けたい\n\t\t//大小が逆だったらひっくり返しちゃう。\n\t\tif (size(A) < size(B)) swap(A, B);\n\n\t\t//Aのサイズを更新する\n\t\tParent[A] += Parent[B];\n\t\t//Bの親をAに変更する\n\t\tParent[B] = A;\n\n\t\treturn true;\n\t}\n};\n\n//セグ木・0-indexed・非再帰・(大きさ・単位元・関数)で初期化\ntemplate<typename T>\nstruct SegTree {\n\t//比較関数の型\n\tusing F = function<T(T, T)>;\n\t//二分木を配列で表したもの\n\tvector<T>seg;\n\t//木の半分の大きさ\n\tint siz;\n\t//単位元\n\tconst T unit;\n\t//比較する関数\n\tconst F f;\n\n\t//大きさn、unit(単位元)、f(モノイド)でsegtreeを初期化する\n\tSegTree(int n, const T unit, const F f) : unit(unit), f(f) {\n\t\tsiz = 1;\n\t\twhile (siz < n)siz <<= 1;\n\t\tseg.assign(siz * 2 - 1, unit);\n\t\tsiz--;\n\t}\n\n\t//k番目にtを入力\n\tvoid set(int k, const T& t) {\n\t\tseg[k + siz] = t;\n\t}\n\n\t//fによって木を構築する\n\tvoid build() {\n\t\tfor (int i = siz - 1; 0 <= i; i--) {\n\t\t\tseg[i] = f(seg[i * 2 + 1], seg[i * 2 + 2]);\n\t\t}\n\t}\n\n\tT operator[](const int i) {\n\t\treturn seg[i + siz];\n\t}\n\n\t//k番目をxに更新する\n\tvoid update(int k, T x) {\n\t\tk += siz;\n\t\tseg[k] = x;\n\t\twhile (0 < k) {\n\t\t\tk = (k - 1) >> 1;\n\t\t\tseg[k] = f(seg[k * 2 + 1], seg[k * 2 + 2]);\n\t\t}\n\t}\n\n\t//[a,b)について、fした結果を返す\n\t//半開区域のためa以上b未満の位置を指す\n\tT query(int a, int b) {\n\t\tT l = unit, r = unit;\n\t\tfor (a += siz, b += siz; a < b; a >>= 1, b >>= 1) {\n\t\t\tif (!(a & 1))l = f(l, seg[a++]);\n\t\t\tif (!(b & 1))r = f(seg[--b], r);\n\t\t}\n\t\treturn f(l, r);\n\t}\n};\n\n//aとbの最大公約数を求めるよ\nlong long GCD(long long a, long long b) {\n\tif (b == 0) return a;\n\telse return GCD(b, a % b);\n}\n\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\nlong long extGCD(long long a, long long b, long long& x, long long& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tlong long d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\n\n// mod. m での a の逆元 a^{-1} を計算する\nlong long modinv(long long a, long long m) {\n\tlong long b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\n\n//nCrをmで割った余りを求める\nllint nCr(llint n, llint r, llint m) {\n\tllint ans = 1;\n\tfor (llint i = 0; i < r; i++) {\n\t\tans *= n - i;\n\t\tans %= m;\n\t}\n\tfor (llint i = 1; i <= r; i++) {\n\t\tans *= modinv(i, m);\n\t\tans %= m;\n\t}\n\treturn ans;\n}\n\n//aのb乗をmで割った余りを求める\nllint power(llint a, llint b, llint m) {\n\tif (b == 1)return a;\n\tif (b == 0)return 1;\n\tllint tmp = power(a, (llint)b / 2, m);\n\ttmp *= tmp;\n\ttmp %= m;\n\tif (b % 2 == 1) {\n\t\ttmp *= a;\n\t\ttmp %= m;\n\t}\n\treturn tmp;\n}\n\n//bitを表すsub,要素数を表すlength\nbool next_combination(llint& sub, int length) {\n\tllint x = sub & -sub, y = sub + x;\n\tsub = (((sub & ~y) / x) >> 1) | y;\n\treturn sub < (llint)(1 << (llint)length);\n}\n\nvoid Zalgorithm(string& s, vint& a) {\n\ta[0] = s.size();\n\tint i = 1, j = 0;\n\twhile (i < s.size()) {\n\t\twhile (i + j < s.size() && s[j] == s[i + j])j++;\n\t\ta[i] = j;\n\t\tif (j == 0) { i++; continue; }\n\t\tint k = 1;\n\t\twhile (i + k < s.size() && a[k] + k < j) {\n\t\t\ta[i + k] += a[k]; k++;\n\t\t}\n\t\ti += k; j -= k;\n\t}\n\treturn;\n}\n\nstruct maccho {\n\tint c;\n\tint w;\n};\n\nint main() {\n\tint n;\n\tcin >> n;\n\tvector<maccho>macchos(n);\n\tfor (auto& [c, w] : macchos) {\n\t\tcin >> c >> w;\n\t}\n\tvint cs(n + 1);\n\trep(i, n) {\n\t\tcs[i + 1] = cs[i] + macchos[i].w;\n\t}\n\trep(i, n)macchos[i].c += macchos[i].w;\n\t//区間DP\n\t//dp[l][r]={半開区間[l,r)内での最小人数、一番下のマッチョの番号}\n\tvvpint dp(n, vpint(n + 1));\n\trep(i, n)rep(j, n + 1) {\n\t\tdp[i][j].first = Inf; dp[i][j].second = -1;\n\t}\n\trep(d, n + 1) {\n\t\tif (d == 0)continue;\n\t\trep(l, n - d + 1) {\n\t\t\tint r = l + d;\n\t\t\tif (d == 1) {\n\t\t\t\tdp[l][r].first = 1;\n\t\t\t\tdp[l][r].second = l;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int k = l + 1; k < r; k++) {\n\t\t\t\t\tif (dp[l][r].first > dp[l][k].first + dp[k][r].first) {\n\t\t\t\t\t\tdp[l][r].first = dp[l][k].first + dp[k][r].first;\n\t\t\t\t\t\tdp[l][r].second = -1;\n\t\t\t\t\t}\n\t\t\t\t\tif (dp[l][k].first != 1 || dp[k][r].first != 1) {\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\tif (k == l + 1 && macchos[dp[l][k].second].c >= cs[r] - cs[l] &&\n\t\t\t\t\t\t(dp[l][r].second == -1 ||\n\t\t\t\t\t\t\tdp[l][r].second != -1 && macchos[dp[l][k].second].c > macchos[dp[l][r].second].c)) {\n\t\t\t\t\t\tdp[l][r].first = 1;\n\t\t\t\t\t\tdp[l][r].second = dp[l][k].second;\n\t\t\t\t\t}\n\t\t\t\t\tif (k == r - 1 && macchos[dp[k][r].second].c >= cs[r] - cs[l] &&\n\t\t\t\t\t\t(dp[l][r].second == -1 ||\n\t\t\t\t\t\t\tdp[l][r].second != -1 && macchos[dp[k][r].second].c > macchos[dp[l][r].second].c)) {\n\t\t\t\t\t\tdp[l][r].first = 1;\n\t\t\t\t\t\tdp[l][r].second = dp[k][r].second;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << dp[0][n].first << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11032, "score_of_the_acc": -0.753, "final_rank": 14 }, { "submission_id": "aoj_0303_3047387", "code_snippet": "#include <stdio.h>\nint min(int a,int b){return a>b?b:a;}\nstruct man{\n int pow;\n int wei;\n void in(){\n scanf(\"%d%d\",&pow,&wei);\n return ;\n }\n void operator =(man a){\n pow=a.pow;\n wei=a.wei;\n return ;\n }\n man carry(man a){\n pow-=a.wei;\n wei+=a.wei;\n pow=min(pow,a.pow);\n return *this;\n }\n void bebad(){\n pow=-2;\n return ;\n }\n bool isbad(){\n return pow==-2;\n }\n};\nbool can(man a,man b){\n return a.pow>=b.wei;\n}\nman max(man a,man b){\n return a.pow>b.pow?a:b;\n}\nint max(int a,int b){return a>b?a:b;}\nbool better(man a,man b){\n return a.pow>b.pow;\n}\nconst int N=1e3+10;\nint main(){\n int n,val[N][N],h[N][N];\n man a[N][N],l,r;\n scanf(\"%d\",&n);\n for(int i=1;i<=n;i++){\n a[i][i].in();\n h[i][i]=i;\n val[i][i]=1;\n }\n for(int j=1;j<n;j++){\n l=a[j][j];\n r=a[j+1][j+1];\n h[j][j+1]=j;\n \n if(can(l,r)){\n if(can(r,l))a[j][j+1]=max(l.carry(a[j+1][j+1]),r.carry(a[j][j]));\n else a[j][j+1]=l.carry(r);\n val[j][j+1]=1;\n }\n else if(can(r,l)){\n a[j][j+1]=r.carry(l);\n val[j][j+1]=1;\n }\n else{\n val[j][j+1]=2;\n a[j][j+1].bebad();\n }\n }\n for(int i=2;i<n;i++){\n for(int j=1;j<=n-i;j++){\n h[j][j+i]=h[j][j+i-1];\n l=a[j][j];\n r=a[j+1][j+i];\n val[j][j+i]=i+1;\n if(r.isbad()){\n val[j][j+i]=val[j][j]+val[j+1][j+i];\n a[j][j+i].bebad();\n }\n else{\n if(can(l,r)){\n a[j][j+i]=l.carry(r);\n val[j][j+i]=1;\n }\n else{\n val[j][j+i]=2;\n a[j][j+i].bebad();\n }\n }\n l=a[j][j+i-1];\n r=a[j+i][j+i];\n if(l.isbad()){\n if(val[j][j+i]>val[j][j+i-1]+val[j+i][j+i]){\n val[j][j+i]=val[j][j+i-1]+val[j+i][j+i];\n a[j][j+i].bebad();\n }\n }\n else{\n if(can(r,l)){\n if(val[j][j+i]>1){\n val[j][j+i]=1;\n h[j][j+i]=j+i-1;\n a[j][j+i]=r.carry(l);\n }\n else if(val[j][j+i]==1&&better(r.carry(l),a[j][j+i])){\n h[j][j+i]=j+i-1;\n a[j][j+i]=r;\n }\n \n }\n else{\n if(val[j][j+i]>2){\n val[j][j+i]=2;\n h[j][j+i]=j+i-1;\n a[j][j+i].bebad();\n }\n }\n \n }\n for(int k=max(h[j][j+i-1]-10,j);k<=h[j+1][j+i]&&k<j+i;k++){\n if(val[j][k]+val[k+1][j+i]<val[j][j+i]){\n val[j][j+i]=val[j][k]+val[k+1][j+i];\n a[j][j+i].bebad();\n h[j][j+i]=k;\n }\n }\n //printf(\"val[%d][%d]=%d\\n\",j,j+i,val[j][j+i]);\n }\n }\n //for(int i=1;i<=n;i++)for(int j=i;j<=n;j++)printf(\"val[%d][%d]=%d\\n\",i,j,val[i][j]);\n printf(\"%d\\n\",val[1][n]);\n}\n/*val[1][1]=0\nval[1][2]=1\nval[1][3]=1\nval[1][4]=2\nval[1][5]=2\nval[1][6]=2\nval[1][7]=3\nval[2][2]=0\nval[2][3]=1\nval[2][4]=2\nval[2][5]=2\nval[2][6]=2\nval[2][7]=3\nval[3][3]=1\nval[3][4]=1\nval[3][5]=1\nval[3][6]=1\nval[3][7]=2\nval[4][4]=1\nval[4][5]=1\nval[4][6]=1\nval[4][7]=2\nval[5][5]=1\nval[5][6]=1\nval[5][7]=1\nval[6][6]=1\nval[6][7]=1\nval[7][7]=1*/", "accuracy": 1, "time_ms": 10, "memory_kb": 17572, "score_of_the_acc": -0.8989, "final_rank": 17 }, { "submission_id": "aoj_0303_2965524", "code_snippet": "#include \"bits/stdc++.h\"\n#define REP(i,n,N) for(int i=(n); i<(N); i++)\n#define RREP(i,n,N) for(ll i=(N-1); i>=n; i--)\n#define CK(n,a,b) ((a)<=(n)&&(n)<(b))\n#define ALL(v) (v).begin(),(v).end()\n#define p(s) cout<<(s)<<endl\n#define p2(a,b) cout<<(a)<<\" \"<<(b)<<endl\n#define v2(T) vector<vector<T>>\ntypedef long long ll;\nusing namespace std;\nconst ll mod=1e9+7;\nconst int inf=1e9;\n\nint dp[1010][1010];\nint N;\nint C[1010], W[1010];\nint sum[1010];\nint main() {\n cin>>N;\n REP(i,0,N){\n cin>>C[i]>>W[i];\n }\n REP(i,0,N) REP(j,i,N) dp[i][j] = j-i+1;\n REP(i,0,N) sum[i+1] = sum[i] + W[i];\n REP(k,1,N){\n REP(L,0,N-k){\n int R = L + k;\n if(dp[L+1][R]==1 && sum[R+1]-sum[L+1] <= C[L]){\n dp[L][R] = min(dp[L][R], dp[L+1][R]);\n }\n if(dp[L][R-1]==1 && sum[R]-sum[L] <= C[R]){\n dp[L][R] = min(dp[L][R], dp[L][R-1]);\n }\n REP(i,L,R) {\n dp[L][R] = min(dp[L][R], dp[L][i] + dp[i+1][R]);\n }\n }\n }\n p(dp[0][N-1]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 7064, "score_of_the_acc": -0.5674, "final_rank": 9 }, { "submission_id": "aoj_0303_2960650", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\n#include <utility>\n#include <string>\n#include <stack>\n#include <regex>\n\n#define REP(i, n) for (int i = 0; i < n; i++)\n#define ALL(v) (v).begin(), (v).end()\n#define vi vector<int>\n#define vvi vector<vector<int>>\n#define INF 1e9\n\nusing namespace std;\n\ntypedef long long ll;\n\nint main()\n{\n int n;\n cin >> n;\n\n vi w = vi(n, 0);\n vi csum = vi(n, 0);\n vi c = vi(n, 0);\n REP(i, n)\n {\n cin >> c[i] >> w[i];\n }\n vvi dp = vvi(n, vi(n, INF));\n REP(i, n)\n {\n dp[i][i] = 1;\n }\n csum[0] = w[0];\n for (int i = 1; i < n; i++)\n {\n csum[i] = csum[i - 1] + w[i];\n }\n for (int count = 2; count <= n; count++)\n {\n REP(left, n)\n {\n int right = left + count - 1;\n if (right >= n)\n {\n continue;\n }\n\n // 一番下が一人になる時\n if (csum[right] - csum[left] <= c[left] && dp[left + 1][right] == 1)\n dp[left][right] = 1;\n if (csum[right - 1] - csum[left - 1] <= c[right] && dp[left][right - 1] == 1)\n dp[left][right] = 1;\n\n // min\n for (int k = left; k < right; k++)\n {\n dp[left][right] = min(dp[left][right], dp[left][k] + dp[k + 1][right]);\n }\n }\n }\n cout << dp[0][n - 1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 6832, "score_of_the_acc": -0.5026, "final_rank": 7 }, { "submission_id": "aoj_0303_2774398", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long ll;\ntypedef unsigned long long ull;\nusing namespace std;\n#define pb push_back\nint dy[]={0, 0, 1, -1, 1, 1, -1, -1};\nint dx[]={1, -1, 0, 0, 1, -1, -1, 1};\n\n#define FOR(i,a,b) for (int i=(a);i<(b);i++)\n#define RFOR(i,a,b) for (int i=(b)-1;i>=(a);i--)\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define RREP(i,n) for (int i=(n)-1;i>=0;i--)\n#define mp make_pair\n#define fi first\n#define sc second\nll n,c[2000],w[2000],a[2000];\nll W(ll i,ll j) {\n\treturn a[j + 1] - a[i];\n}\nll memo[2000][2000];\n\nll solve(ll i,ll j) {\n\tif(memo[i][j] >= 0) {\n\t\treturn memo[i][j];\n\t}\n\tif(j - i + 1 <= 2) {\n\t\tif(i == j || w[i] <= c[j] || w[j] <= c[i]) {\n\t\t\treturn memo[i][j] = 1;\n\t\t}\n\t\treturn memo[i][j] = 2;\n\t}\n\n\n\tll ret = 1000000000;\n\n\tif((solve(i + 1,j) == 1 && c[i] >= W(i + 1,j)) || (solve(i,j - 1) == 1 && c[j] >= W(i,j - 1))) {\n\t\tret = 1;\n\t} \n\tREP(k,j - i) {\n\t\tret = min(ret,solve(i,i + k) + solve(i + k + 1,j));\n\t}\n\treturn memo[i][j] = ret;\n}\n\nint main(){\n\tcin >> n;\n\tREP(i,n) {\n\t\tcin >> c[i] >> w[i];\n\t}\n\tREP(i,n) {\n\t\tREP(j,n) {\n\t\t\tmemo[i][j] = -1;\n\t\t}\n\t}\n\n\ta[0] = 0;\n\tREP(i,n) {\n\t\ta[i + 1] = a[i] + w[i];\n\t}\n\n\tcout << solve(0,n - 1) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 14936, "score_of_the_acc": -1.3933, "final_rank": 19 }, { "submission_id": "aoj_0303_2734591", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <queue>\n#include <set>\n#include <map>\n#include <string.h>\n#include <cmath>\n\nusing namespace std;\ntypedef long long i64;\ntypedef long double ld;\ntypedef pair<i64,i64> P;\n#define rep(i,s,e) for(int (i) = (s);(i) <= (e);++(i))\n\nint n;\n\ni64 c[1010];\ni64 w[1010];\n\ni64 sum[1010];\n\nint dp[1010][1010];\n\nint main()\n{\n\tcin >> n;\n\trep(i,0,n - 1)\n\t\tcin >> c[i] >> w[i];\n\n\trep(i,1,n)\n\t{\n\t\tsum[i] = sum[i - 1] + w[i - 1];\n\t}\n\n\tauto getsum = [&](int l,int r){\n\t\treturn sum[r] - sum[l];\n\t};\n\n\trep(i,0,1000) rep(j,0,1000) dp[i][j] = 1e9;\n\n\trep(i,0,1000)\n\t\tdp[i][i + 1] = 1;\n\t\n\trep(w,2,n)\n\t{\n\t\trep(l,0,n - 1)\n\t\t{\n\t\t\t//[l,r)\n\t\t\tint r = l + w;\n\t\t\tif(r > n) continue;\n\n\t\t\trep(mid,l + 1,r - 1)\n\t\t\t{\n\t\t\t\tdp[l][r] = min(dp[l][r] , dp[l][mid] + dp[mid][r]);\n\t\t\t}\n\n\t\t\t//left is mighty\n\t\t\t{\n\n\t\t\t\ti64 w_s = getsum(l + 1,r);\n\t\t\t\tif(c[l] >= w_s && dp[l + 1][r] == 1)\n\t\t\t\t{\n\t\t\t\t\tdp[l][r] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\t{\n\t\t\t\ti64 w_s = getsum(l,r - 1);\n\t\t\t\tif(c[r - 1] >= w_s && dp[l][r - 1] == 1)\n\t\t\t\t{\n\t\t\t\t\tdp[l][r] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\t/*\n\t\t\trep(i,0,n)\n\t\t\t{\n\t\t\t\tif(l <= i && i < r)\n\t\t\t\t\tcout << \"=\";\n\t\t\t\telse\n\t\t\t\t\tcout << \" \";\n\t\t\t}\n\t\t\tcout << dp[l][r] << endl;\n\t\t\t*/\n\t\t}\n\n\t}\n\n\tcout << dp[0][n] << endl;\n\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 7108, "score_of_the_acc": -0.554, "final_rank": 8 }, { "submission_id": "aoj_0303_2675226", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i, a, n) for(ll i = ((ll) a); i < ((ll) n); i++)\n#define INF (1LL << 60)\nusing namespace std;\ntypedef long long ll;\n\nll N, C[2000], W[2000];\nll sum[2000], memo[2000][2000];\n\nstruct edge {\n ll v, dist;\n};\n\nstruct state {\n ll v, cost;\n\n bool operator>(const state s) const {\n return cost > s.cost;\n }\n};\n\nvector<ll> dijkstra(vector< vector<edge> > &E, ll S) {\n vector<ll> dp(E.size(), INF);\n priority_queue<state, vector<state>, greater<state> > q;\n q.push((state) { S, 0 });\n\n while(!q.empty()) {\n ll v = q.top().v, cost = q.top().cost;\n q.pop();\n\n if(dp[v] <= cost) continue;\n dp[v] = cost;\n\n REP(i, 0, E[v].size()) {\n ll nv = E[v][i].v, ncost = cost + E[v][i].dist;\n if(dp[nv] > ncost) q.push((state) { nv, ncost });\n }\n }\n\n return dp;\n}\n\nll dfs(ll l, ll r) {\n ll &ret = memo[l][r];\n if(ret >= 0) return ret;\n\n if(r - l <= 1) return ret = 1;\n\n ret = 0;\n if(dfs(l + 1, r) && (sum[r] - sum[l + 1] <= C[l])) ret = 1;\n if(dfs(l, r - 1) && (sum[r - 1] - sum[l] <= C[r - 1])) ret = 1;\n return ret;\n}\n\nint main(void) {\n cin >> N;\n REP(i, 0, N) cin >> C[i] >> W[i];\n\n sum[0] = 0;\n REP(i, 0, N) sum[i + 1] = sum[i] + W[i];\n\n REP(i, 0, N) REP(j, 0, N + 1) memo[i][j] = -1;\n\n vector< vector<edge> > E(N + 1);\n REP(i, 0, N) REP(j, i, N + 1) if(dfs(i, j)) E[i].push_back((edge) { j, 1 });\n cout << dijkstra(E, 0)[N] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 17544, "score_of_the_acc": -0.897, "final_rank": 16 }, { "submission_id": "aoj_0303_2557276", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\n\nint c[1010];\nint w[1010];\nint sum[1010];\nint dp[1010][1010];\n\nint f(int l, int r){\n\tif(dp[l][r] != -1) return dp[l][r];\n\tint len = r - l;\n\tif(len == 1) return dp[l][r] = 1;\n\n\tint ok = 0;\n\tif(c[l] >= sum[r] - sum[l + 1] && f(l + 1, r)) ok = 1;\n\tif(c[r - 1] >= sum[r - 1] - sum[l] && f(l, r - 1)) ok = 1;\n\treturn dp[l][r] = ok;\n}\n\nint dp2[1010];\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n#ifdef LOCAL\n\tstd::ifstream in(\"in\");\n\tstd::cin.rdbuf(in.rdbuf());\n#endif\n\n\tint n;\n\tcin >> n;\n\tfor(int i = 0; i < n; i++){\n\t\tcin >> c[i] >> w[i];\n\t\tsum[i + 1] = sum[i] + w[i];\n\t}\n\n\tmemset(dp, -1, sizeof dp);\n\tfill((int*)begin(dp2), (int*)end(dp2), 1 << 25);\n\tdp2[0] = 0;\n\tfor(int i = 0; i < n; i++){\n\t\tfor(int j = i + 1; j <= n; j++){\n\t\t\tif(f(i, j)){\n\t\t\t\tdp2[j] = min(dp2[j], dp2[i] + 1);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << dp2[n] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7200, "score_of_the_acc": -0.1996, "final_rank": 3 }, { "submission_id": "aoj_0303_2524945", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\n\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\n\nconst ll INF = 1ll<<29;\nconst ll MOD = 1000000007;\nconst bool debug = 0;\n\nint N;\nbool dp1[1000][1001]; // [l,r)???1???????????¨???????????¨?????§??????\nint dp2[1001]; // i????????§???????????????????°??????°\nint c[1000], w[1000];\nint sum[1001];\n\nint main() {\n\tcin >> N;\n\tREP(i, N) scanf(\"%d %d\", c + i, w + i);\n\t\n\tREP(i, N) sum[i + 1] = sum[i] + w[i];\n\t\n\tREP(i, N) dp1[i][i + 1] = true;\n\tFOR(w, 2, N + 1) {\n\t\tREP(i, N) {\t// [i, i + w)\n\t\t\tif (i + w > N) break;\n\t\t\t\n\t\t\tif (dp1[i + 1][i + w] && sum[i + w] - sum[i + 1] <= c[i])\n\t\t\t\tdp1[i][i + w] = true;\n\t\t\tif (dp1[i][i + w - 1] && sum[i + w - 1] - sum[i] <= c[i + w - 1])\n\t\t\t\tdp1[i][i + w] = true;\n\t\t}\n\t}\n\t\n\tfill(dp2, dp2 + N + 1, INF);\n\t\n\tdp2[0] = 1;\n\tREP(i, N) {\n\t\tFOR(j, i + 1, N + 1) {\n\t\t\tif (dp1[i][j]) {\n\t\t\t\tif (i == 0) dp2[j] = 1;\n\t\t\t\telse chmin(dp2[j], dp2[i] + 1);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tcout << dp2[N] << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4240, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0303_2523534", "code_snippet": "#include <iostream>\n#define INF 1e+9\nusing namespace std;\n\nint n,w[1000],c[1000],imos[1001] = {};\nbool dp1[1000][1000];\nint dp2[1000][1000];\n\nint dfs(int l,int r){\n\tif(dp2[l][r] >= 0) return dp2[l][r];\n\tint mi = INF;\n\tfor(int i = l;i < r;i++) mi = min(mi,dfs(l,i) + dfs(i + 1,r));\n\treturn dp2[l][r] = mi;\n}\n\nint main(){\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> c[i] >> w[i];\n\t\timos[i + 1] = imos[i] + w[i];\n\t\tdp1[i][i] = true;\n\t\tfor(int j = 0;j < n;j++) dp2[i][j] = -1;\n\t\tdp2[i][i] = 1;\n\t}\n\tfor(int i = 1;i < n;i++){\n\t\tfor(int j = 0;j < n - i;j++){\n\t\t\tif((c[j + i] >= imos[j + i] - imos[j] && dp1[j][j + i - 1]) || (c[j] >= imos[j + i + 1] - imos[j + 1] && dp1[j + 1][j + i])) dp1[j][j + i] = true;\n\t\t\telse dp1[j][i + j] = false;\n\t\t\tif(dp1[j][i + j]) dp2[j][i + j] = 1;\n\t\t}\n\t}\n\tcout << dfs(0,n - 1) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 8056, "score_of_the_acc": -0.8966, "final_rank": 15 }, { "submission_id": "aoj_0303_2419185", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <vector>\ntypedef long long int ll;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\nusing namespace std;\n\n int main(){\n\n\t int N;\n\t scanf(\"%d\",&N);\n\n\t int* power = new int[N+1];\n\t int* weight = new int[N+1];\n\t bool** table = new bool*[N+1];\n\t int** dp = new int*[N+1];\n\t for(int i = 0; i <= N; i++){\n\t\t table[i] = new bool[N+1];\n\t\t dp[i] = new int[N+1];\n\t\t for(int k = 0; k <= N; k++){\n\t\t\t table[i][k] = false;\n\t\t\t dp[i][k] = BIG_NUM;\n\t\t }\n\t }\n\n\t for(int i = 1; i <= N; i++){\n\t\t scanf(\"%d %d\",&power[i],&weight[i]);\n }\n\n\t weight[0] = 0;\n\t for(int i = 1; i <= N; i++){\n\t\t weight[i] += weight[i-1];\n\t\t table[i][1] = true;\n\t\t dp[i][i] = 1;\n\t }\n\n\t for(int length=2; length <= N; length++){\n\t\t for(int left = 1; left + length -1 <= N;left++){\n\t\t\t if((power[left] >= (weight[left+length-1]-weight[left]) && table[left+1][length-1] == true) ||\n\t\t\t\t\t (power[left+length-1] >= (weight[left+length-2]-weight[left-1]) && table[left][length-1]) == true){\n\t\t\t\ttable[left][length] = true;\n\t\t\t\tdp[left][left+length-1] = 1;\n\t\t\t }else{\n\t\t\t\t for(int i = left; i <= left+length-2; i++){\n\t\t\t\t\t dp[left][left+length-1] = min(dp[left][left+length-1],dp[left][i]+dp[i+1][left+length-1]);\n\t\t\t\t }\n\t\t\t }\n\t\t }\n\t }\n\n\t printf(\"%d\\n\",dp[1][N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 7692, "score_of_the_acc": -0.5934, "final_rank": 11 }, { "submission_id": "aoj_0303_2238649", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i,n,N) for(int i=n;i<N;i++)\n#define p(S) cout<<(S)<<endl\nusing namespace std;\nint dp[1001][1001];\nint w[1001],c[1001];\nint sumw[1001];\nint main(){\n\tint n;\n\tcin>>n;\n\tcin>>c[0]>>w[0];\n\tsumw[0]=w[0];\n\tREP(i,1,n) {\n\t\tcin>>c[i]>>w[i];\n\t\tsumw[i]=sumw[i-1]+w[i];\n\t}\n\tREP(i,0,n) REP(j,i,n) dp[i][j]=j-i+1;\n\tREP(i,0,n-1) if(c[i]>=w[i+1]||c[i+1]>=w[i]) dp[i][i+1]=1;\n\n\tfor(int k=2;k<n;k++){\n\t\tfor(int i=0;i+k<n;i++){\n\t\t\tif((dp[i+1][i+k]==1&&c[i]>=sumw[i+k]-sumw[i])||(dp[i][i+k-1]==1&&c[i+k]>=sumw[i+k-1]-(i?sumw[i-1]:0)))\n\t\t\t\tdp[i][i+k]=1;\n\t\t\tfor(int j=i+1;j<i+k;j++)\n\t\t\t\tdp[i][i+k]=min(dp[i][i+k],dp[i][j]+dp[j+1][i+k]);\n\t\t}\n\t}\n\tp(dp[0][n-1]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 6996, "score_of_the_acc": -0.5793, "final_rank": 10 }, { "submission_id": "aoj_0303_2238647", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i,n,N) for(int i=n;i<N;i++)\n#define p(S) cout<<(S)<<endl\nusing namespace std;\nint dp[1001][1001];\nint w[100010],c[100010];\nint sumw[100010];\nint main(){\n\tint n;\n\tcin>>n;\n\tREP(i,0,n) {\n\t\tcin>>c[i]>>w[i];\n\t\tif(i>0)\tsumw[i]=sumw[i-1]+w[i];\n\t\telse sumw[i]=w[i];\n\t}\n\tREP(i,0,1001) REP(j,i,1001) dp[i][j]=j-i+1;\n\tREP(i,0,n-1) if(c[i]>=w[i+1]||c[i+1]>=w[i]) dp[i][i+1]=1;\n\n\n\tfor(int k=2;k<n;k++){\n\t\tfor(int i=0;i+k<n;i++){\n\t\t\tif((dp[i+1][i+k]==1&&c[i]>=sumw[i+k]-sumw[i])||(dp[i][i+k-1]==1&&c[i+k]>=sumw[i+k-1]-(i?sumw[i-1]:0)))\n\t\t\t\tdp[i][i+k]=1;\n\t\t\telse dp[i][i+k]=min(dp[i+1][i+k],dp[i][i+k-1])+1;\n\n\t\t\tfor(int j=i+1;j<i+k;j++)\n\t\t\t\tdp[i][i+k]=min(dp[i][i+k],dp[i][j]+dp[j+1][i+k]);\n\t\t}\n\t}\n\tp(dp[0][n-1]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 7000, "score_of_the_acc": -0.6123, "final_rank": 12 }, { "submission_id": "aoj_0303_1827960", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\ntemplate<class T>\nusing Table = vector<vector<T>>;\nconst ld eps=1e-9;\n\n//// < \"D:\\D_Download\\Visual Studio 2015\\Projects\\programing_contest_c++\\Debug\\a.txt\"\n\nint memo[2010][2010];\nvector<int>sums, cs, aws;\nint getnum(int l, int r) {\n\tif (memo[l][r])return memo[l][r];\n\telse {\n\t\tif (l + 1 == r)return 1;\n\t\telse {\n\t\t\tint amin = r-l;\n\t\t\tfor (int m = l + 1; m <= r - 1; ++m) {\n\t\t\t\tconst int lnum = getnum(l, m);\n\t\t\t\tconst int rnum = getnum(m, r);\n\t\t\t\tif (m == l + 1) {\n\t\t\t\t\tif (rnum == 1) {\n\t\t\t\t\t\tif (sums[r-1] - sums[m - 1] <= cs[l]) {\n\t\t\t\t\t\t\tamin = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (m == r - 1) {\n\t\t\t\t\tif (lnum == 1) {\n\t\t\t\t\t\tif (sums[m - 1] - sums[l - 1] <= cs[r-1]) {\n\t\t\t\t\t\t\tamin = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tamin = min(amin, lnum + rnum);\n\t\t\t}\n\t\t\treturn memo[l][r]=amin;\n\t\t}\n\t}\n}\n\nint main() {\n\tint N; \n\tcin >> N;\n\taws.resize(N+1);\n\tsums.resize(N + 1);\n\tcs.resize(N+1);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> cs[i + 1];\n\t\tcin >> aws[i + 1];\n\t\tsums[i + 1] = sums[i] + aws[i + 1];\n\t}\n\tint ans = getnum(1, N + 1);\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 620, "memory_kb": 9144, "score_of_the_acc": -1.3306, "final_rank": 18 }, { "submission_id": "aoj_0303_1714509", "code_snippet": "#include <cstdio>\n#include <algorithm>\n\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n\nusing namespace std;\n\nconst int inf = 3e5;\n\nint n;\nint c[1000];\nint w[1000];\nint dp[1000][1000];\n\nint judge(int x, int y){\n\tif(dp[x][y] > 0){\n\t\treturn dp[x][y];\n\t}\n\tif(x == y){\n\t\treturn dp[x][y] = w[x];\n\t}\n\tint t;\n\tif((t = judge(x + 1, y)) <= c[x]){\n\t\treturn dp[x][y] = t + w[x];\n\t}\n\tif((t = judge(x, y - 1)) <= c[y]){\n\t\treturn dp[x][y] = t + w[y];\n\t}\n\treturn dp[x][y] = inf;\n}\n\nint main(){\n\tscanf(\"%d\", &n);\n\trep(i, n){\n\t\tscanf(\"%d%d\", &c[i], &w[i]);\n\t}\n\tint ans = 0;\n\tint t = 0;\n\twhile(t < n){\n\t\t++ans;\n\t\tfor(int i = n - 1; i >= t; --i){\n\t\t\tif(judge(t, i) != inf){\n\t\t\t\tt = i + 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\t/*\n\trep(i, n){\n\t\trep(j, n){\n\t\t\tprintf(\"%d \", dp[i][j]);\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n\t*/\n\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4980, "score_of_the_acc": -0.0499, "final_rank": 2 } ]
aoj_0304_cpp
学食 今日はZ大学のオープンキャンパスです。毎年この日の昼休みには、大勢の高校生たちが学食に列をつくります。そこでZ大学の事務局は、行列の長さが最大でどのくらいの距離になるかを予測することにしました。事前調査の結果で、以下のことが分かっています。 行列にはそれぞれ 1 から N までの番号が振られた N 人が並びます。 C 個の高校生のペア ( a i , b i ) それぞれについて、以下の2種類の制約があります: 1つ目の制約は順序に関するもので以下のいずれかです: a i は b i よりも先、または同じ位置に並ばなくてはならない a i は b i よりも後、または同じ位置に並ばなくてはならない a i は b i より先でも、同じ位置でも、後でもよい 2つ目の制約は距離に関するもので以下のいずれかです: a i と b i は d i メートル以上離れなければならない a i と b i は d i メートル以内に並ばなければならない また、先頭から同じ距離の場所に複数の人が並ぶことができ、行列の先頭には常に番号 1 の人が並ぶことが分かっています。 与えられた C 個の制約をすべて満たす行列について、先頭から最後尾までの距離が最大となるような並び方をした場合の距離を求めるプログラムを作成してください。ただし、どこまでも離れることができる場合は inf と、制約を満たす並び方が不可能な場合は -1 と出力してください。 入力 入力は以下の形式で与えられる。 N C constraint 1 constraint 2 : constraint C 1 行目に行列に並ぶ高校生の人数 N (2 ≤ N ≤ 100) と制約の数 C (0 ≤ C ≤ 200) が与えられる。続く C 行に各制約 constraint i が次の形式で与えられる。 a i o i b i s i d i 制約には空白は含まれない。 a i , o i , b i , s i , d i の意味を以下に示す。 a i と b i (1 ≤ a i , b i ≤ N かつ a i ≠ b i ) は高校生の番号、 d i は距離 (0 ≤ d ≤ 10000) を表す整数である。 o i は順序の制約を指定する <= 、 >= 、 * のいずれかの文字列であり、 <= の場合「 a i は b i よりも先、または同じ位置に並ばなくてはならない」、 >= の場合「 a i は b i よりも後、または同じ位置に並ばなくてはならない」、 * の場合「 a i は b i より先でも、同じ位置でも、後でもよい」ことを意味する。ただし o i が * となる制約は7個以上与えられることはない。 s i は距離の制約を指定する + または - の文字であり、 + の場合「 a i と b i は d i メートル以上離れなければならない」、 - の場合「 a i と b i は d i メートル以内に並ばなければならない」ことを意味する。 ただし、あるペアに対して複数の制約が与えられることはないものとする。 出力 先頭から最後尾までの距離を1行に出力する。 入出力例 入力例1 3 2 1<=2-1 2<=3-2 出力例1 3 入力例2 3 3 1<=2-1 2<=3-2 1<=3+4 出力例2 -1 入力例3 3 2 1<=2-2 2*3+1 出力例3 inf
[ { "submission_id": "aoj_0304_5931301", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define pb emplace_back\n#define lb(v,k) (lower_bound(all(v),(k))-v.begin())\n#define ub(v,k) (upper_bound(all(v),(k))-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define all(a) a.begin(),a.end()\n#define rsort(a) {sort(all(a));reverse(all(a));}\n#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}\n#define popcnt __builtin_popcountll\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=998244353;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void outset(T s){auto itr=s.begin();while(itr!=s.end()){if(itr!=s.begin())cout<<' ';cout<<*itr;itr++;}cout<<'\\n';}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\n\n\n\nint main(){\n ll n,m;cin>>n>>m;\n vector<PP> edge(m);\n vp v(m);\n rep(i,m){\n string s;cin>>s;\n ll x=0,y=0;\n while(s[x]!='<'&&s[x]!='>'&&s[x]!='*')x++;\n while(s[y]!='+'&&s[y]!='-')y++;\n ll a=0,b=0,d=0;\n rep(j,x)a=a*10+(s[j]-'0');\n REP(j,x+1,y)if(s[j]!='=')b=b*10+(s[j]-'0');\n REP(j,y+1,s.size())d=d*10+(s[j]-'0');\n edge[i]=PP(a-1,b-1,d);\n if(s[x]=='*')v[i].fi=0;\n if(s[x]=='<')v[i].fi=1;\n if(s[x]=='>')v[i].fi=2;\n if(s[y]=='+')v[i].se=0;\n if(s[y]=='-')v[i].se=1;\n }\n ll ans=-1;\n vvi g(n,vi(n,inf));\n rep(i,n)g[i][0]=0;\n function<void(ll)> dfs=[&](ll l){\n if(l==m){\n vvi dis=g;\n rep(i,n)dis[i][i]=0;\n rep(k,n)rep(i,n)rep(j,n)if(dis[i][k]<inf&&dis[k][j]<inf)chmin(dis[i][j],dis[i][k]+dis[k][j]);\n bool ok=true;\n rep(i,n)if(dis[i][i]<0)ok=false;\n if(ok)rep(i,n)rep(j,n)chmax(ans,dis[i][j]);\n return;\n }\n if(v[l].fi==0||v[l].fi==1){\n ll a,b,d;tie(a,b,d)=edge[l];\n ll t1=g[a][b],t2=g[b][a];\n if(v[l].se==0)chmin(g[b][a],-d);\n else{\n chmin(g[a][b],d);\n chmin(g[b][a],0ll);\n }\n dfs(l+1);\n g[a][b]=t1;g[b][a]=t2;\n }\n if(v[l].fi==0||v[l].fi==2){\n ll a,b,d;tie(a,b,d)=edge[l];swap(a,b);\n ll t1=g[a][b],t2=g[b][a];\n if(v[l].se==0)chmin(g[b][a],-d);\n else{\n chmin(g[a][b],d);\n chmin(g[b][a],0ll);\n }\n dfs(l+1);\n g[a][b]=t1;g[b][a]=t2;\n }\n };dfs(0);\n if(ans==inf)out(\"inf\");\n else out(ans);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3528, "score_of_the_acc": -1.0338, "final_rank": 9 }, { "submission_id": "aoj_0304_5789105", "code_snippet": "#include <bits/stdc++.h>\n//#include\"atcoder/all\"\n#define rep(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n//using namespace atcoder;\n#define all(a) a.begin(),a.end()\n#define int long long\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef pair<int,int> P;\ntypedef pair<P,P> PP;\nconst ll inf=1ll<<58;\nconst ll mod=1000000007;\nstruct edge{\n\tint from,to,dist;\n\tstring dir;\n};\nvector<edge> V1,V2;\nbool nloop(int n,vector<edge>es){\n\tvector<int>d(n);\n\trep(i,n){\n\t\trep(j,es.size()){\n\t\t\tedge e=es[j];\n\t\t\tif(d[e.to]>d[e.from]+e.dist){\n\t\t\t\td[e.to]=d[e.from]+e.dist;\n\t\t\t\tif(i==n-1)return true;\n\t\t\t}\n\t\t}\n\t}\n\treturn false;\n}\nsigned main(){\n\tint n,c;cin>>n>>c;\n\trep(i,c){\n\t\tint a,b,d;\n\t\tstring o,s;\n\t\t\n\t\tstring S;cin>>S;\n\t\tstring h = \"\";\n int k = 0;\n while (k < S.size() && ('0' <= S[k] && S[k] <= '9')) h += S[k++];\n a = stoi(h);\n h = \"\";\n \n while (k < S.size() && !('0' <= S[k] && S[k] <= '9')) h += S[k++];\n o=h;\n h = \"\";\n\n while (k < S.size() && ('0' <= S[k] && S[k] <= '9')) h += S[k++];\n b = stoi(h);\n h = \"\";\n\n while (k < S.size() && !('0' <= S[k] && S[k] <= '9')) h += S[k++];\n s=h;\n h = \"\";\n\n while (k < S.size() && ('0' <= S[k] && S[k] <= '9')) h += S[k++];\n d = stoi(h);\n\n\t\tif(o==\"<=\")V1.push_back({a-1,b-1,d,s});\n\t\tif(o==\">=\")V1.push_back({b-1,a-1,d,s});\n\t\tif(o==\"*\")V2.push_back({a-1,b-1,d,s});\n\t}\n\tstring z=\"a\";\n\tint ans=-1,kai=0;\n\trep(i,1<<V2.size()){\n\t\tvector<edge>ES;\n\t\trep(j,V1.size()){\n\t\t\tif(V1[j].dir==\"+\"){\n\t\t\t\tES.push_back({V1[j].to,V1[j].from,-V1[j].dist,z});\n\t\t\t}\n\t\t\telse{\n\t\t\t\tES.push_back({V1[j].from,V1[j].to,V1[j].dist,z});\n\t\t\t}\n\t\t\tES.push_back({V1[j].to,V1[j].from,0,z});\n\t\t}\n\t\trep(j,V2.size()){\n\t\t\tif(i&1<<j)swap(V2[j].from,V2[j].to);\n\t\t}\n\t\trep(j,V2.size()){\n\t\t\tif(V2[j].dir==\"+\"){\n\t\t\t\tES.push_back({V2[j].to,V2[j].from,-V2[j].dist,z});\n\t\t\t}\n\t\t\telse{\n\t\t\t\tES.push_back({V2[j].from,V2[j].to,V2[j].dist,z});\n\t\t\t}\t\t\n\t\t\tES.push_back({V2[j].to,V2[j].from,0,z});\t\t\n\t\t}\n\t\trep(j,V2.size()){\n\t\t\tif(i&1<<j)swap(V2[j].from,V2[j].to);\n\t\t}\t\t\n\t\trep(j,n-1){\n\t\t\tES.push_back({j+1,0,0,z});\n\t\t}\n\t\t\n\t\tvector<int>d(n,inf);\n\t\td[0]=0;\n\n\t\trep(k,n){\n\t\t\trep(j,ES.size()){\n\t\t\t\tedge e=ES[j];\n\t\t\t\tif(d[e.from]<inf&&d[e.to]>d[e.from]+e.dist){\n\t\t\t\t\td[e.to]=d[e.from]+e.dist;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint mx=-inf;\n\t\tif(!nloop(n,ES)){\n\t\t\tkai=1;\n\t\t\trep(j,n){\n\t\t\t\tmx=max(mx,d[j]);\n\t\t\t}\n\t\t\tans=max(ans,mx);\n\t\t}\n\t}\n\tif(!kai)cout<<-1<<endl;\n\telse{\n\t\tif(ans==inf)cout<<\"inf\"<<endl;\n\t\telse cout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3548, "score_of_the_acc": -0.9765, "final_rank": 8 }, { "submission_id": "aoj_0304_5740462", "code_snippet": "/*\nこのコード、と~おれ!\nBe accepted!\n∧_∧ \n(。・ω・。)つ━☆・*。\n⊂   ノ    ・゜+.\n しーJ   °。+ *´¨)\n          .· ´¸.·*´¨) ¸.·*¨)\n\t\t           (¸.·´ (¸.·'* ☆\n*/\n\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <iostream>\n#include <random>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <regex>\n#include <functional>\n#include <complex>\n#include <list>\n#include <cassert>\n#include <iomanip>\n#include <set>\n#include <stack>\n#include <bitset>\n#include <array>\n#include <chrono>\n\n//#pragma GCC target(\"arch=skylake-avx512\")\n#pragma GCC target(\"avx2\")\n//#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"sse4\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define repeat(i, n, m) for(int i = n; i < (m); ++i)\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n#define printynl(a) printf(a ? \"yes\\n\" : \"no\\n\")\n#define printyn(a) printf(a ? \"Yes\\n\" : \"No\\n\")\n#define printYN(a) printf(a ? \"YES\\n\" : \"NO\\n\")\n#define printim(a) printf(a ? \"possible\\n\" : \"imposible\\n\")\n#define printdb(a) printf(\"%.50lf\\n\", a)\n#define printLdb(a) printf(\"%.50Lf\\n\", a)\n#define printdbd(a) printf(\"%.16lf\\n\", a)\n#define prints(s) printf(\"%s\\n\", s.c_str())\n#define all(x) (x).begin(), (x).end()\n#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)\n#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)\n#define Please return\n#define AC 0\n#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr int INF = 1073741823;\nconstexpr int MINF = -1073741823;\nconstexpr ll LINF = ll(4661686018427387903);\nconstexpr ll MOD = 1e9 + 7;\nconstexpr ll mod = 998244353;\nconstexpr long double eps = 1e-6;\nconst long double PI = acosl(-1.0L);\n\nusing namespace std;\n\nvoid scans(string& str) {\n\tchar c;\n\tstr = \"\";\n\tscanf(\"%c\", &c);\n\tif (c == '\\n')scanf(\"%c\", &c);\n\twhile (c != '\\n' && c != -1 && c != ' ') {\n\t\tstr += c;\n\t\tscanf(\"%c\", &c);\n\t}\n}\n\nvoid scanc(char& str) {\n\tchar c;\n\tscanf(\"%c\", &c);\n\tif (c == -1)return;\n\twhile (c == '\\n') {\n\t\tscanf(\"%c\", &c);\n\t}\n\tstr = c;\n}\n\ndouble acot(double x) {\n\treturn PI / 2 - atan(x);\n}\n\nll LSB(ll n) { return (n & (-n)); }\n\ntemplate<typename T>\ninline T chmin(T& a, const T& b) {\n\tif (a > b)a = b;\n\treturn a;\n}\n\ntemplate<typename T>\ninline T chmax(T& a, const T& b) {\n\tif (a < b)a = b;\n\treturn a;\n}\n\n//cpp_int\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\nusing namespace boost::multiprecision;\n#else\nusing cpp_int = ll;\n#endif\n\n//atcoder library\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\n//using namespace atcoder;\n#endif\n\n/*\n\trandom_device seed_gen;\n\tmt19937 engine(seed_gen());\n\tuniform_int_distribution dist(1, 100);\n*/\n\n\n/*----------------------------------------------------------------------------------*/\n\n/*\n* @title template(graph)\n* @docs kyopro/docs/graph_template.md\n*/\n\ntemplate<typename T>\nstruct edge {\n\tT cost;\n\tint from, to;\n\n\tedge(int from, int to) : from(from), to(to), cost(T(1)) {}\n\tedge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n};\n\ntemplate<typename T = int>\nstruct graph {\n\n\tint n;\n\tbool directed, weighted;\n\n\tvector<vector<edge<T>>> g;\n\n\tgraph(int n, bool directed, bool weighted) : g(n), n(n), directed(directed), weighted(weighted) {}\n\n\tvoid add_edge(int from, int to, T cost = T(1)) {\n\t\tg[from].emplace_back(from, to, cost);\n\t\tif (not directed) {\n\t\t\tg[to].emplace_back(to, from, cost);\n\t\t}\n\t}\n\n\tvector<edge<T>>& operator[](const int& idx) {\n\t\treturn g[idx];\n\t}\n\n\tvoid read(int e, bool one_indexed) {\n\t\tint a, b, c = 1;\n\t\twhile (e--) {\n\t\t\tscanf(\"%d%d\", &a, &b);\n\t\t\tif (weighted) {\n\t\t\t\tscanf(\"%d\", &c);\n\t\t\t}\n\t\t\tif (one_indexed)--a, --b;\n\t\t\tadd_edge(a, b, c);\n\t\t}\n\t}\n\n\tvoid read(int e, bool one_indexed, const string& format) {\n\t\tint a, b;\n\t\tT c = T(1);\n\t\twhile (e--) {\n\t\t\tscanf(\"%d%d\", &a, &b);\n\t\t\tif (weighted) {\n\t\t\t\tscanf(format.c_str(), &c);\n\t\t\t}\n\t\t\tif (one_indexed)--a, --b;\n\t\t\tadd_edge(a, b, c);\n\t\t}\n\t}\n\n};\n\n// 戻り値がtrueなら負の閉路を含む\nbool bellman_ford(int n, int s, graph<int> g, vector<int> &dis) { // nは頂点数、sは開始頂点\n\tfill(all(dis), INF);\n\tdis[s] = 0;\n\tint cnt = 0;\n\twhile (cnt < n) {\n\t\tbool end = true;\n\t\trep(i, n) {\n\t\t\tfor (const auto& e : g[i]) {\n\t\t\t\tif (dis[e.from] != INF && dis[e.from] + e.cost < dis[e.to]) {\n\t\t\t\t\tdis[e.to] = dis[e.from] + e.cost;\n\t\t\t\t\tend = false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (end) break;\n\t\tcnt++;\n\t}\n\treturn (cnt == n);\n}\n\nint solve(const int &n, const vector<tuple<int, int, int>> &m, const vector<tuple<int, int, int>> &p) {\n\tgraph g(n, true, true);\n\trep(i, n)g.add_edge(i, 0, 0);\n\tfor (auto [a, b, d] : m) {\n\t\tif (d > 0) {\n\t\t\tg.add_edge(b, a, 0);\n\t\t\tg.add_edge(a, b, d);\n\t\t}\n\t\telse {\n\t\t\tg.add_edge(a, b, 0);\n\t\t\tg.add_edge(b, a, -d);\n\t\t}\n\t}\n\tfor (auto [a, b, d] : p) {\n\t\tif (d > 0) {\n\t\t\tg.add_edge(b, a, 0);\n\t\t\tg.add_edge(b, a, -d);\n\t\t}\n\t\telse {\n\t\t\tg.add_edge(a, b, 0);\n\t\t\tg.add_edge(a, b, d);\n\t\t}\n\t}\n\tvector d(n, vector<int>(n));\n\tbool ushi = false;\n\trep(i, n) {\n\t\tushi |= bellman_ford(n, i, g, d[i]);\n\t}\n\tif (ushi)return -1;\n\tint ret = -1;\n\trep(i, n) {\n\t\trep(j, n) {\n\t\t\tchmax(ret, d[i][j]);\n\t\t}\n\t}\n\treturn ret;\n}\n\nint main() {\n\t\n\tint n, c;\n\tscanf(\"%d%d\", &n, &c);\n\tvector<tuple<bool, int, int, int>> ast;\n\tvector<tuple<int, int, int>> m, p;\n\trep(i, c) {\n\t\tint a;\n\t\tscanf(\"%d\", &a);\n\t\tchar c;\n\t\tscanf(\"%c\", &c);\n\t\tif (c == '*') {\n\t\t\tint b, d;\n\t\t\tscanf(\"%d%c%d\", &b, &c, &d);\n\t\t\t--a, --b;\n\t\t\tast.emplace_back(c == '-', a, b, d);\n\t\t}\n\t\telse {\n\t\t\tint b, d;\n\t\t\tchar cc;\n\t\t\tscanf(\"%*c%d%c%d\", &b, &cc, &d);\n\t\t\t--a, --b;\n\t\t\tif (c == '>')d *= -1;\n\t\t\tif (cc == '+') p.emplace_back(a, b, d);\n\t\t\telse m.emplace_back(a, b, d);\n\t\t}\n\t}\n\tint ans = -1;\n\trep(i, (1 << ast.size())) {\n\t\tvector<tuple<int, int, int>> mm = m, pp = p;\n\t\trep(j, ast.size()) {\n\t\t\tif (i & (1 << j)) {\n\t\t\t\tif (get<0>(ast[j]))mm.emplace_back(get<1>(ast[j]), get<2>(ast[j]), -get<3>(ast[j]));\n\t\t\t\telse pp.emplace_back(get<1>(ast[j]), get<2>(ast[j]), -get<3>(ast[j]));\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (get<0>(ast[j]))mm.emplace_back(get<1>(ast[j]), get<2>(ast[j]), get<3>(ast[j]));\n\t\t\t\telse pp.emplace_back(get<1>(ast[j]), get<2>(ast[j]), get<3>(ast[j]));\n\t\t\t}\n\t\t}\n\t\tchmax(ans, solve(n, mm, pp));\n\t}\n\tif (ans == INF)puts(\"inf\");\n\telse printf(\"%d\\n\", ans);\n\n\tPlease AC;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 3644, "score_of_the_acc": -1.459, "final_rank": 12 }, { "submission_id": "aoj_0304_4309165", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\nint N, C;\nint a[200], b[200], d[200];\nchar s[200];\nvector<int> c;\n\nint ans = -1;\nvoid solve(int n) {\n\tif (n < c.size()) {\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t}\n\telse {\n\t\tint cost[100];\n\t\tcost[0] = 0;\n\t\tfor (int i = 1; i < N; i++) cost[i] = 1e8;\n\t\tfor (int i = 0; i < 10000; i++) {\n\t\t\tfor (int j = 0; j < C; j++) {\n\t\t\t\tif (s[j] == '-') {\n\t\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) cost[b[j]] = cost[a[j]] + d[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) cost[a[j]] = cost[b[j]] - d[j];\n\t\t\t\t}\n\t\t\t\tif (cost[a[j]] > cost[b[j]] + 0) cost[a[j]] = cost[b[j]];\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < C; j++) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) return;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) return;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < N; i++)\n\t\t\tif (cost[i] < 0) return;\n\t\tfor (int i = 0; i < N; i++) ans = max(ans, cost[i]);\n\t}\n}\n\nint main() {\n\tcin >> N >> C;\n\tfor (int i = 0; i < C; i++) {\n\t\tstring S;\n\t\tcin >> S;\n\t\tint j, k;\n\t\tfor (j = 0; j < S.size()-1; j++) {\n\t\t\tif (S.substr(j, 2) == \"<=\") break;\n\t\t\tif (S.substr(j, 2) == \">=\") break;\n\t\t\tif (S.substr(j, 1) == \"*\") break;\n\t\t}\n\t\tfor (k = j + 1; k < S.size(); k++) {\n\t\t\tif (S.substr(k, 1) == \"+\") break;\n\t\t\tif (S.substr(k, 1) == \"-\") break;\n\t\t}\n\t\ta[i] = stoi(S.substr(0, j));\n\t\tif (S.substr(j, 1) == \"*\") {\n\t\t\tb[i] = stoi(S.substr(j + 1, k - (j + 1)));\n\t\t\tc.push_back(i);\n\t\t}\n\t\telse {\n\t\t\tb[i] = stoi(S.substr(j + 2, k - (j + 2)));\n\t\t}\n\t\tif (S.substr(j, 2) == \">=\") swap(a[i], b[i]);\n\t\ta[i]--; b[i]--;\n\t\td[i] = stoi(S.substr(k + 1, S.size() - (k + 1)));\n\t\ts[i] = S[k];\n\t}\n\tsolve(0);\n\tif (ans == (int)1e8) cout << \"inf\" << endl;\n\telse cout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3224, "score_of_the_acc": -1.0551, "final_rank": 11 }, { "submission_id": "aoj_0304_3860397", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\nint N, C;\nint a[200], b[200], d[200];\nchar s[200];\nvector<int> c;\n\nint ans = -1;\nvoid solve(int n) {\n\tif (n < c.size()) {\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t}\n\telse {\n\t\tint cost[100];\n\t\tcost[0] = 0;\n\t\tfor (int i = 1; i < N; i++) cost[i] = 1e8;\n\t\tfor (int i = 0; i < 10000; i++) {\n\t\t\tfor (int j = 0; j < C; j++) {\n\t\t\t\tif (s[j] == '-') {\n\t\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) cost[b[j]] = cost[a[j]] + d[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) cost[a[j]] = cost[b[j]] - d[j];\n\t\t\t\t}\n\t\t\t\tif (cost[a[j]] > cost[b[j]] + 0) cost[a[j]] = cost[b[j]];\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < C; j++) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) return;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) return;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < N; i++)\n\t\t\tif (cost[i] < 0) return;\n\t\tfor (int i = 0; i < N; i++) ans = max(ans, cost[i]);\n\t}\n}\n\nint main() {\n\tcin >> N >> C;\n\tfor (int i = 0; i < C; i++) {\n\t\tstring S;\n\t\tcin >> S;\n\t\tint j, k;\n\t\tfor (j = 0; j < S.size()-1; j++) {\n\t\t\tif (S.substr(j, 2) == \"<=\") break;\n\t\t\tif (S.substr(j, 2) == \">=\") break;\n\t\t\tif (S.substr(j, 1) == \"*\") break;\n\t\t}\n\t\tfor (k = j + 1; k < S.size(); k++) {\n\t\t\tif (S.substr(k, 1) == \"+\") break;\n\t\t\tif (S.substr(k, 1) == \"-\") break;\n\t\t}\n\t\ta[i] = stoi(S.substr(0, j));\n\t\tif (S.substr(j, 1) == \"*\") {\n\t\t\tb[i] = stoi(S.substr(j + 1, k - (j + 1)));\n\t\t\tc.push_back(i);\n\t\t}\n\t\telse {\n\t\t\tb[i] = stoi(S.substr(j + 2, k - (j + 2)));\n\t\t}\n\t\tif (S.substr(j, 2) == \">=\") swap(a[i], b[i]);\n\t\ta[i]--; b[i]--;\n\t\td[i] = stoi(S.substr(k + 1, S.size() - (k + 1)));\n\t\ts[i] = S[k];\n\t}\n\tsolve(0);\n\tif (ans == (int)1e8) cout << \"inf\" << endl;\n\telse cout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3212, "score_of_the_acc": -1.0501, "final_rank": 10 }, { "submission_id": "aoj_0304_3860385", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\nint N, C;\nint a[200], b[200], d[200];\nchar s[200];\nvector<int> c;\n\nint ans = -1;\nvoid solve(int n) {\n\tif (n < c.size()) {\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t}\n\telse {\n\t\tint cost[100];\n\t\tcost[0] = 0;\n\t\tfor (int i = 1; i < N; i++) cost[i] = 1e8;\n\t\tfor (int i = 0; i < 1000000; i++) {\n\t\t\tfor (int j = 0; j < C; j++) {\n\t\t\t\tif (s[j] == '-') {\n\t\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) cost[b[j]] = cost[a[j]] + d[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) cost[a[j]] = cost[b[j]] - d[j];\n\t\t\t\t}\n\t\t\t\tif (cost[a[j]] > cost[b[j]] + 0) cost[a[j]] = cost[b[j]];\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < C; j++) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) return;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) return;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < N; i++) ans = max(ans, cost[i]);\n\t}\n}\n\nint main() {\n\tcin >> N >> C;\n\tfor (int i = 0; i < C; i++) {\n\t\tstring S;\n\t\tcin >> S;\n\t\tint j, k;\n\t\tfor (j = 0; j < S.size()-1; j++) {\n\t\t\tif (S.substr(j, 2) == \"<=\") break;\n\t\t\tif (S.substr(j, 2) == \">=\") break;\n\t\t\tif (S.substr(j, 1) == \"*\") break;\n\t\t}\n\t\tfor (k = j + 1; k < S.size(); k++) {\n\t\t\tif (S.substr(k, 1) == \"+\") break;\n\t\t\tif (S.substr(k, 1) == \"-\") break;\n\t\t}\n\t\ta[i] = stoi(S.substr(0, j));\n\t\tif (S.substr(j, 1) == \"*\") {\n\t\t\tb[i] = stoi(S.substr(j + 1, k - (j + 1)));\n\t\t\tc.push_back(i);\n\t\t}\n\t\telse {\n\t\t\tb[i] = stoi(S.substr(j + 2, k - (j + 2)));\n\t\t}\n\t\tif (S.substr(j, 2) == \">=\") swap(a[i], b[i]);\n\t\ta[i]--; b[i]--;\n\t\td[i] = stoi(S.substr(k + 1, S.size() - (k + 1)));\n\t\ts[i] = S[k];\n\t}\n\tsolve(0);\n\tif (ans == (int)1e8) cout << \"inf\" << endl;\n\telse cout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 0.7727272727272727, "time_ms": 250, "memory_kb": 3212, "score_of_the_acc": -1.214, "final_rank": 13 }, { "submission_id": "aoj_0304_3860367", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\nint N, C;\nint a[200], b[200], d[200];\nchar s[200];\nvector<int> c;\n\nint ans = -1;\nvoid solve(int n) {\n\tif (n < c.size()) {\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t\tsolve(n + 1);\n\t\tswap(a[c[n]], b[c[n]]);\n\t}\n\telse {\n\t\tint cost[100];\n\t\tcost[0] = 0;\n\t\tfor (int i = 1; i < N; i++) cost[i] = 1e8;\n\t\tfor (int i = 0; i < 1000000; i++) {\n\t\t\tfor (int j = 0; j < C; j++) {\n\t\t\t\tif (s[j] == '-') {\n\t\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) cost[b[j]] = cost[a[j]] + d[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) cost[a[j]] = cost[b[j]] - d[j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < C; j++) {\n\t\t\tif (s[j] == '-') {\n\t\t\t\tif (cost[b[j]] > cost[a[j]] + d[j]) return;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (cost[a[j]] > cost[b[j]] - d[j]) return;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < N; i++) ans = max(ans, cost[i]);\n\t}\n}\n\nint main() {\n\tcin >> N >> C;\n\tfor (int i = 0; i < C; i++) {\n\t\tstring S;\n\t\tcin >> S;\n\t\tint j, k;\n\t\tfor (j = 0; j < S.size()-1; j++) {\n\t\t\tif (S.substr(j, 2) == \"<=\") break;\n\t\t\tif (S.substr(j, 2) == \">=\") break;\n\t\t\tif (S.substr(j, 1) == \"*\") break;\n\t\t}\n\t\tfor (k = j + 1; k < S.size(); k++) {\n\t\t\tif (S.substr(k, 1) == \"+\") break;\n\t\t\tif (S.substr(k, 1) == \"-\") break;\n\t\t}\n\t\ta[i] = stoi(S.substr(0, j));\n\t\tif (S.substr(j, 1) == \"*\") {\n\t\t\tb[i] = stoi(S.substr(j + 1, k - (j + 1)));\n\t\t\tc.push_back(i);\n\t\t}\n\t\telse {\n\t\t\tb[i] = stoi(S.substr(j + 2, k - (j + 2)));\n\t\t}\n\t\tif (S.substr(j, 2) == \">=\") swap(a[i], b[i]);\n\t\ta[i]--; b[i]--;\n\t\td[i] = stoi(S.substr(k + 1, S.size() - (k + 1)));\n\t\ts[i] = S[k];\n\t}\n\tsolve(0);\n\tif (ans == (int)1e8) cout << \"inf\" << endl;\n\telse cout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 0.4090909090909091, "time_ms": 10, "memory_kb": 3180, "score_of_the_acc": -0.8073, "final_rank": 14 }, { "submission_id": "aoj_0304_1628292", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n/**\nvector<int>ar(3);\nfor(auto&e:ar){\n scanf(\"%d\",&e);\n }\nsort(ar.begin(),ar.end())\nint sum=accumulate(ar.begin(),ar.end(),0);\n**/\n//memo d17202 1274246\nconst int NIL = -1;\nconst int INF = 1000000000;\n \ntypedef tuple<int, int, int, bool> Uncertain;\n \nint BellmanFord(const vector<vector<int>>& g, int start) {\n vector<int> distance(g.size(), INF);\n distance[start] = 0;\n for(int step = 1; step <= g.size(); ++step) {\n for(int i = 0; i < g.size(); ++i) {\n for(int j = 0; j < g.size(); ++j) {\n if(g[i][j] == INF) continue;\n if(distance[j] <= distance[i] + g[i][j]) continue;\n if(step == g.size()) return NIL;\n distance[j] = distance[i] + g[i][j];\n }\n }\n }\n return *max_element(begin(distance), end(distance));\n}\n \nint solve(const vector<vector<int>>& g, const vector<Uncertain>& uncertain, bitset<8> bit = 0, int depth = 0) {\n if(depth == uncertain.size()) {\n auto h(g);\n for(int i = 0; i < uncertain.size(); ++i) {\n int u, v, d;\n bool positive;\n tie(u, v, d, positive) = uncertain[i];\n if(bit[i]) swap(u, v);\n h[v][u] = 0;\n if(positive) h[v][u] = -d;\n else h[u][v] = d;\n }\n return BellmanFord(h, 0);\n }\n return max(solve(g, uncertain, bit.set(depth), depth + 1), solve(g, uncertain, bit.reset(depth), depth + 1));\n}\nint main(){\n double pai=3.141592653589;\n int N, C;\n cin >> N >> C;\n vector<vector<int>> g(N, vector<int>(N, INF));\n for(int i = 1; i < N; ++i) g[i][0] = 0;\n vector<Uncertain> uncertain;\n for(int i = 0; i < C; ++i) {\n string s;\n cin >> s;\n // parse\n enum {LESS = '<', EQUAL = '*', MORE = '>'};\n int u = 0, v = 0, d = 0;\n char order;\n bool positive;\n int index = 0;\n while(isdigit(s[index])) u = 10 * u + (s[index++] - '0');\n if((order = s[index++]) != EQUAL) ++index;\n while(isdigit(s[index])) v = 10 * v + (s[index++] - '0');\n positive = (s[index++] == '+');\n while(isdigit(s[index])) d = 10 * d + (s[index++] - '0');\n // edge\n --u;\n --v;\n if(order == EQUAL) {\n uncertain.emplace_back(u, v, d, positive);\n } else {\n if(order == MORE) swap(u, v);\n g[v][u] = 0;\n if(positive) g[v][u] = -d;\n else g[u][v] = d;\n }\n }\n // output\n int answer = solve(g, uncertain);\n if(answer == INF) cout << \"inf\";\n else cout << answer;\n cout << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3280, "score_of_the_acc": -0.9144, "final_rank": 7 }, { "submission_id": "aoj_0304_1581423", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nstring split(const string &str, const string &delim){\n string res;\n size_t current = 0, found, delimlen = delim.size();\n while((found = str.find(delim, current)) != string::npos){\n res+=string(str, current, found - current) + \" \" + delim + \" \";\n current = found + delimlen;\n }\n res+=string(str, current, str.size() - current);\n return res;\n}\n\nint n,c;\ntypedef tuple<int,int,int> edge;\nvector<edge> es;\nvector<int> dist;\n\nvoid bellmanford(){\n fill_n(dist.begin(),n,inf);\n dist[0]=0;\n\n for(int i=0; i<2*n; ++i){\n for(edge& e:es){\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(dist[a]+w<dist[b]) dist[b]=dist[a]+w;\n }\n }\n}\n\nvoid solve(){\n cin >> n >> c;\n\n dist.resize(n);\n vector<edge> unfixed;\n\n rep(i,0,c){\n string constraint;\n cin >> constraint;\n constraint=split(constraint,\">=\");\n constraint=split(constraint,\"<=\");\n constraint=split(constraint,\"*\");\n constraint=split(constraint,\"+\");\n constraint=split(constraint,\"-\");\n dump(constraint);\n\n int a,b,d;\n string tmp1,tmp2;\n stringstream ss(constraint);\n ss >> a >> tmp1 >> b >> tmp2 >> d;\n --a; --b;\n\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,0));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,0));\n\n int w=-d;\n if(tmp2==\"-\"){\n w*=-1;\n swap(a,b);\n }\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,w));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,w));\n else unfixed.push_back(make_tuple(a,b,w));\n }\n rep(v,1,n) es.push_back(make_tuple(v,0,0));\n\n vector<edge> es_=es;\n int ans=-1;\n rep(b,0,1<<es.size()){\n es=es_;\n rep(i,0,unfixed.size()){\n edge& e=unfixed[i];\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(1&(b>>i)){\n es.push_back(make_tuple(a,b,w));\n if(w<0) es.push_back(make_tuple(a,b,0));\n else es.push_back(make_tuple(b,a,0));\n }else{\n es.push_back(make_tuple(b,a,w));\n if(w<0) es.push_back(make_tuple(b,a,0));\n else es.push_back(make_tuple(a,b,0));\n }\n }\n\n bellmanford();\n if(dist[0]<0) continue;\n rep(i,0,n) ans=max(ans,dist[i]);\n }\n if(ans==inf) cout << \"inf\" << endl;\n else cout << ans << endl;\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "accuracy": 0.2727272727272727, "time_ms": 550, "memory_kb": 3248, "score_of_the_acc": -1.7208, "final_rank": 18 }, { "submission_id": "aoj_0304_1581420", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nstring split(const string &str, const string &delim){\n string res;\n size_t current = 0, found, delimlen = delim.size();\n while((found = str.find(delim, current)) != string::npos){\n res+=string(str, current, found - current) + \" \" + delim + \" \";\n current = found + delimlen;\n }\n res+=string(str, current, str.size() - current);\n return res;\n}\n\nint n,c;\ntypedef tuple<int,int,int> edge;\nvector<edge> es;\nvector<int> dist;\n\nvoid bellmanford(){\n fill_n(dist.begin(),n,inf);\n dist[0]=0;\n\n for(int i=0; i<n; ++i){\n for(edge& e:es){\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(dist[a]+w<dist[b]) dist[b]=dist[a]+w;\n }\n }\n}\n\nvoid solve(){\n cin >> n >> c;\n\n dist.resize(n);\n vector<edge> unfixed;\n\n rep(i,0,c){\n string constraint;\n cin >> constraint;\n constraint=split(constraint,\">=\");\n constraint=split(constraint,\"<=\");\n constraint=split(constraint,\"*\");\n constraint=split(constraint,\"+\");\n constraint=split(constraint,\"-\");\n dump(constraint);\n\n int a,b,d;\n string tmp1,tmp2;\n stringstream ss(constraint);\n ss >> a >> tmp1 >> b >> tmp2 >> d;\n --a; --b;\n\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,0));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,0));\n\n int w=-d;\n if(tmp2==\"-\"){\n w*=-1;\n swap(a,b);\n }\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,w));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,w));\n else unfixed.push_back(make_tuple(a,b,w));\n }\n rep(v,1,n) es.push_back(make_tuple(v,0,0));\n\n vector<edge> es_=es;\n int ans=-1;\n rep(b,0,1<<es.size()){\n es=es_;\n rep(i,0,unfixed.size()){\n edge& e=unfixed[i];\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(1&(b>>i)){\n es.push_back(make_tuple(a,b,w));\n if(w<0) es.push_back(make_tuple(a,b,0));\n else es.push_back(make_tuple(b,a,0));\n }else{\n es.push_back(make_tuple(b,a,w));\n if(w<0) es.push_back(make_tuple(b,a,0));\n else es.push_back(make_tuple(a,b,0));\n }\n }\n\n bellmanford();\n if(dist[0]<0) continue;\n rep(i,0,n) ans=max(ans,dist[i]);\n }\n if(ans==inf) cout << \"inf\" << endl;\n else cout << ans << endl;\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "accuracy": 0.2727272727272727, "time_ms": 300, "memory_kb": 3268, "score_of_the_acc": -1.3193, "final_rank": 15 }, { "submission_id": "aoj_0304_1581418", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nstring split(const string &str, const string &delim){\n string res;\n size_t current = 0, found, delimlen = delim.size();\n while((found = str.find(delim, current)) != string::npos){\n res+=string(str, current, found - current) + \" \" + delim + \" \";\n current = found + delimlen;\n }\n res+=string(str, current, str.size() - current);\n return res;\n}\n\nint n,c;\ntypedef tuple<int,int,int> edge;\nvector<edge> es;\nvector<int> dist;\n\nvoid bellmanford(){\n fill_n(dist.begin(),n,inf);\n dist[0]=0;\n\n for(int i=0; i<2*n; ++i){\n for(edge& e:es){\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(dist[a]+w<dist[b]) dist[b]=dist[a]+w;\n }\n }\n}\n\nvoid solve(){\n cin >> n >> c;\n\n dist.resize(n);\n vector<edge> unfixed;\n\n rep(i,0,c){\n string constraint;\n cin >> constraint;\n constraint=split(constraint,\">=\");\n constraint=split(constraint,\"<=\");\n constraint=split(constraint,\"*\");\n constraint=split(constraint,\"+\");\n constraint=split(constraint,\"-\");\n dump(constraint);\n\n int a,b,d;\n string tmp1,tmp2;\n stringstream ss(constraint);\n ss >> a >> tmp1 >> b >> tmp2 >> d;\n --a; --b;\n\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,0));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,0));\n\n int w=-d;\n if(tmp2==\"-\"){\n w*=-1;\n swap(a,b);\n }\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,w));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,w));\n else unfixed.push_back(make_tuple(a,b,w));\n }\n rep(v,1,n) es.push_back(make_tuple(v,0,0));\n\n vector<edge> es_=es;\n int ans=-1;\n rep(b,0,1<<es.size()){\n es=es_;\n rep(i,0,unfixed.size()){\n edge& e=es[i];\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(1&(b>>i)){\n es.push_back(make_tuple(a,b,w));\n if(w<0) es.push_back(make_tuple(a,b,0));\n else es.push_back(make_tuple(b,a,0));\n }else{\n es.push_back(make_tuple(b,a,w));\n if(w<0) es.push_back(make_tuple(b,a,0));\n else es.push_back(make_tuple(a,b,0));\n }\n }\n\n bellmanford();\n if(dist[0]<0) continue;\n rep(i,0,n) ans=max(ans,dist[i]);\n }\n if(ans==inf) cout << \"inf\" << endl;\n else cout << ans << endl;\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "accuracy": 0.2727272727272727, "time_ms": 620, "memory_kb": 3264, "score_of_the_acc": -1.8422, "final_rank": 19 }, { "submission_id": "aoj_0304_1581414", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nstring split(const string &str, const string &delim){\n string res;\n size_t current = 0, found, delimlen = delim.size();\n while((found = str.find(delim, current)) != string::npos){\n res+=string(str, current, found - current) + \" \" + delim + \" \";\n current = found + delimlen;\n }\n res+=string(str, current, str.size() - current);\n return res;\n}\n\nint n,c;\ntypedef tuple<int,int,int> edge;\nvector<edge> es;\nvector<int> dist;\n\nvoid bellmanford(){\n fill_n(dist.begin(),n,inf);\n dist[0]=0;\n\n for(int i=0; i<n; ++i){\n for(edge& e:es){\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(dist[a]+w<dist[b]) dist[b]=dist[a]+w;\n }\n }\n}\n\nvoid solve(){\n cin >> n >> c;\n\n dist.resize(n);\n vector<edge> unfixed;\n\n rep(i,0,c){\n string constraint;\n cin >> constraint;\n constraint=split(constraint,\">=\");\n constraint=split(constraint,\"<=\");\n constraint=split(constraint,\"*\");\n constraint=split(constraint,\"+\");\n constraint=split(constraint,\"-\");\n dump(constraint);\n\n int a,b,d;\n string tmp1,tmp2;\n stringstream ss(constraint);\n ss >> a >> tmp1 >> b >> tmp2 >> d;\n --a; --b;\n\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,0));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,0));\n\n int w=-d;\n if(tmp2==\"-\"){\n w*=-1;\n swap(a,b);\n }\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,w));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,w));\n else unfixed.push_back(make_tuple(a,b,w));\n }\n rep(v,1,n) es.push_back(make_tuple(v,0,0));\n\n vector<edge> es_=es;\n int ans=-1;\n rep(b,0,1<<es.size()){\n es=es_;\n rep(i,0,unfixed.size()){\n edge& e=es[i];\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(1&(b>>i)){\n es.push_back(make_tuple(a,b,w));\n if(w<0) es.push_back(make_tuple(a,b,0));\n else es.push_back(make_tuple(b,a,0));\n }else{\n es.push_back(make_tuple(b,a,w));\n if(w<0) es.push_back(make_tuple(b,a,0));\n else es.push_back(make_tuple(a,b,0));\n }\n }\n\n bellmanford();\n if(dist[0]<0) continue;\n rep(i,0,n) ans=max(ans,dist[i]);\n }\n if(ans==inf) cout << \"inf\" << endl;\n else cout << ans << endl;\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "accuracy": 0.2727272727272727, "time_ms": 330, "memory_kb": 3264, "score_of_the_acc": -1.3668, "final_rank": 17 }, { "submission_id": "aoj_0304_1581412", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nstring split(const string &str, const string &delim){\n string res;\n size_t current = 0, found, delimlen = delim.size();\n while((found = str.find(delim, current)) != string::npos){\n res+=string(str, current, found - current) + \" \" + delim + \" \";\n current = found + delimlen;\n }\n res+=string(str, current, str.size() - current);\n return res;\n}\n\nint n,c;\ntypedef tuple<int,int,int> edge;\nvector<edge> es;\nvector<int> dist;\n\nvoid bellmanford(){\n fill_n(dist.begin(),n,inf);\n dist[0]=0;\n\n for(int i=0; i<n; ++i){\n for(edge& e:es){\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(dist[a]+w<dist[b]) dist[b]=dist[a]+w;\n }\n }\n}\n\nvoid solve(){\n cin >> n >> c;\n\n dist.resize(n);\n vector<edge> unfixed;\n\n rep(i,0,c){\n string constraint;\n cin >> constraint;\n constraint=split(constraint,\">=\");\n constraint=split(constraint,\"<=\");\n constraint=split(constraint,\"*\");\n constraint=split(constraint,\"+\");\n constraint=split(constraint,\"-\");\n dump(constraint);\n\n int a,b,d;\n string tmp1,tmp2;\n stringstream ss(constraint);\n ss >> a >> tmp1 >> b >> tmp2 >> d;\n --a; --b;\n\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,0));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,0,b));\n\n int w=-d;\n if(tmp2==\"-\"){\n w*=-1;\n swap(a,b);\n }\n if(tmp1==\"<=\") es.push_back(make_tuple(b,a,w));\n else if(tmp1==\">=\") es.push_back(make_tuple(a,b,w));\n else unfixed.push_back(make_tuple(a,b,w));\n }\n rep(v,1,n) es.push_back(make_tuple(v,0,0));\n\n vector<edge> es_=es;\n int ans=-1;\n rep(b,0,1<<es.size()){\n es=es_;\n rep(i,0,unfixed.size()){\n edge& e=es[i];\n int a=get<0>(e),b=get<1>(e),w=get<2>(e);\n if(1&(b>>i)){\n es.push_back(make_tuple(a,b,w));\n if(w<0) es.push_back(make_tuple(a,b,0));\n else es.push_back(make_tuple(b,a,0));\n }else{\n es.push_back(make_tuple(b,a,w));\n if(w<0) es.push_back(make_tuple(b,a,0));\n else es.push_back(make_tuple(a,b,0));\n }\n }\n\n bellmanford();\n if(dist[0]<0) continue;\n rep(i,0,n) ans=max(ans,dist[i]);\n }\n if(ans==inf) cout << \"inf\" << endl;\n else cout << ans << endl;\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "accuracy": 0.2727272727272727, "time_ms": 320, "memory_kb": 3248, "score_of_the_acc": -1.3437, "final_rank": 16 }, { "submission_id": "aoj_0304_1504580", "code_snippet": "// AOJ 0304 (http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0304)\n#include<cctype>\n#include<iostream>\n#include<string>\n#include<vector>\n#include<limits>\n#define rep(i,a) for(int i=0;i<(a);++i)\n\nconst int MAX_N = 210, MAX_C = 210, INF = std::numeric_limits<int>::max()>>2;\n\nstruct edge\n{\n\tint from, to, cost;\n\n\tedge( int from, int to, int cost )\n\t:\tfrom(from), to(to), cost(cost)\n\t{}\n};\n\nstruct Dat\n{\n\tint a, b, d;\n\tbool pm;\n\n\tDat( int a, int b, int d, bool pm )\n\t:\ta(a), b(b), d(d), pm(pm)\n\t{}\n};\n\nint N, C;\nstd::string cst[MAX_C];\nstd::vector<edge> es;\nstd::vector<Dat> dats;\nint d[MAX_N];\n\nint read( int &p, const std::string &s )\n{\n\tint ret = 0;\n\n\twhile( p < s.size() && isdigit(s[p]) )\n\t\tret *= 10, ret += s[p++]-'0';\n\n\treturn ret;\n}\n\nint bellmanFord()\n{\n\tstd::fill( d, d+N, INF );\n\td[0] = 0;\n\t\n\trep( j, N )\n\t{\n\t\trep( i, es.size() ) if( d[es[i].from] != INF && d[es[i].from]+es[i].cost < d[es[i].to] )\n\t\t{\n\t\t\td[es[i].to] = d[es[i].from]+es[i].cost;\n\n\t\t\tif( j == N-1 )\n\t\t\t\treturn -INF;\n\t\t}\n\t}\n\n\tint ret = -INF;\n\trep( j, N )\n\t\tret = std::max( ret, d[j] );\n\n\treturn ret;\n}\n\nint main()\n{\n\tstd::cin.tie(0);\n\tstd::ios::sync_with_stdio(false);\n\n\tstd::cin >> N >> C;\n\trep( i, C )\n\t{\n\t\tstd::cin >> cst[i];\n\n\t\tint p = 0, t = 0, d = 0;\n\t\tbool pm;\n\n\t\tint a = read( p, cst[i] );\n\t\t\t\n\t\tif( cst[i][p] == '<' )\n\t\t\tt = 0, p += 2;\n\t\telse if( cst[i][p] == '>' )\n\t\t\tt = 1, p += 2;\n\t\telse if( cst[i][p] == '*' )\n\t\t\tt = 2, ++p;\n\n\t\tint b = read( p, cst[i] );\n\t\tpm = cst[i][p++]=='+';\n\t\td = read( p, cst[i] );\n\n\t\t--a; --b;\n\n\t\tes.push_back( edge( a, 0, 0 ) );\n\t\tes.push_back( edge( b, 0, 0 ) );\n\t\n\t\tif( !t )\n\t\t{\n\t\t\tes.push_back( edge( b, a, 0 ) );\n\t\t\tes.push_back( pm?edge( b, a, -d ):edge( a, b, d ) );\n\t\t}\n\t\telse if( t == 1 )\n\t\t{\n\t\t\tes.push_back( edge( a, b, 0 ) );\n\t\t\tes.push_back( pm?edge( a, b, -d ):edge( b, a, d ) );\n\t\t}\n\t\telse if( t == 2 )\n\t\t\tdats.push_back( Dat( a, b, d, pm ) );\n\t}\n\n\tint ans = -INF;\n\n\tif( dats.empty() )\n\t\tans = std::max( ans, bellmanFord() );\n\n\trep( i, 1<<(dats.size()) )\n\t{\n\t\trep( j, dats.size() )\n\t\t{\n\t\t\tif( i>>j&1 )\n\t\t\t{\n\t\t\t\tes.push_back( edge( dats[j].b, dats[j].a, 0 ) );\n\t\t\t\tes.push_back( dats[j].pm?edge( dats[j].b, dats[j].a, -dats[j].d ):edge( dats[j].a, dats[j].b, dats[j].d ) );\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tes.push_back( edge( dats[j].a, dats[j].b, 0 ) );\n\t\t\t\tes.push_back( dats[j].pm?edge( dats[j].a, dats[j].b, -dats[j].d ):edge( dats[j].b, dats[j].a, dats[j].d ) );\n\t\t\t}\n\t\t}\n\n\t\t ans = std::max( ans, bellmanFord() );\n\n\t\t rep( j, dats.size()*2 )\n\t\t\tes.pop_back();\n\t}\n\n\tif( ans == INF )\n\t\tstd::cout << \"inf\" << std::endl;\n\telse\n\t\tstd::cout << (ans>=0?ans:-1) << std::endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0304_1452599", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n/*\ndist[a] + w >= dist[b]\n\na ??? b ????????????:\ndist[b] + 0 >= dist[a]\n\nd ??????????????\\???:\ndist[b] - d >= dist[a]\n\nd ??????????????\\???:\ndist[a] + d >= dist[b]\n*/\n\nconst int INF = 1 << 28;\n\nstruct Edge {\n\tint src, dst, cost;\n\tEdge(){}\n\tEdge(int src, int dst, int cost): src(src), dst(dst), cost(cost){}\n};\n\nint n, c;\nvector<Edge> es;\nvector<int> any;\nint dist[100][100];\n\nint calc()\n{\n\tfill_n(*dist, 100 * 100, INF);\n\tfor (int i = 0; i < 100; i++) dist[i][i] = 0;\n\tfor (auto &e : es) dist[e.src][e.dst] = min(dist[e.src][e.dst], e.cost);\n\t\n\tfor (int k = 0; k < n; k++){\n\t\tfor (int i = 0; i < n; i++){\n\t\t\tfor (int j = 0; j < n; j++){\n\t\t\t\tdist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < n; i++) if (dist[i][i] < 0) return -1;\n\tint res = 0;\n\tfor (int i = 0; i < n; i++) res = max(res, dist[0][i]);\n\t\n\treturn res;\n}\n\nint main()\n{\n\tscanf(\"%d %d\", &n, &c);\n\tfor (int i = 0; i < c; i++){\n\t\tint a, b, d;\n\t\tchar o, s;\n\t\t\n\t\tscanf(\"%d\", &a); --a;\n\t\tscanf(\"%c\", &o);\n\t\tif (o != '*') scanf(\"%*c\");\n\t\telse any.push_back(i);\n\t\tscanf(\"%d%c%d\", &b, &s, &d); --b;\n\t\t\n\t\tif (o == '>') swap(a, b);\n\t\tes.push_back(Edge(b, a, 0));\n\t\tif (s == '+') es.push_back(Edge(b, a, -d));\n\t\telse es.push_back(Edge(a, b, d));\n\t}\n\tfor (int i = 1; i < n; i++){\n\t\tes.push_back(Edge(i, 0, 0));\n\t}\n\t\n\t//for (auto e : es) printf(\"%d -> %d %d\\n\", e.src, e.dst, e.cost);\n\t\n\tint res = -1;\n\tfor (int i = 0; i < (1 << any.size()); i++){\n\t\tfor (int j = 0; j < any.size(); j++){\n\t\t\tif (i & (1 << j)){\n\t\t\t\tswap(es[any[j] * 2].src, es[any[j] * 2].dst);\n\t\t\t\tswap(es[any[j] * 2 + 1].src, es[any[j] * 2 + 1].dst);\n\t\t\t}\n\t\t}\n\t\tres = max(res, calc());\n\t\tfor (int j = 0; j < any.size(); j++){\n\t\t\tif (i & (1 << j)){\n\t\t\t\tswap(es[any[j] * 2].src, es[any[j] * 2].dst);\n\t\t\t\tswap(es[any[j] * 2 + 1].src, es[any[j] * 2 + 1].dst);\n\t\t\t}\n\t\t}\n\t}\n\tif (res == INF) puts(\"inf\");\n\telse printf(\"%d\\n\", res);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1244, "score_of_the_acc": -0.1017, "final_rank": 2 }, { "submission_id": "aoj_0304_1364734", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1 << 28;\n\nstruct Edge {\n\tint a, b, w;\n\tEdge(){}\n\tEdge(int a, int b, int w): a(a), b(b), w(w){}\n};\n\nint n, c;\nEdge g[400];\nint dist[100][100];\n\nint solve()\n{\n\tfill_n(*dist, 100 * 100, INF);\n\tfor (int i = 0; i < n; i++) dist[i][i] = 0;\n\t\n\tfor (int i = 0; i < c * 2; i++){\n\t\tint &t = dist[g[i].a][g[i].b];\n\t\tt = min(t, g[i].w);\n\t\t//printf(\"%d -> %d %d\\n\", g[i].a, g[i].b, g[i].w);\n\t}\n\t\n\tfor (int k = 0; k < n; k++){\n\t\tfor (int i = 0; i < n; i++){\n\t\t\tfor (int j = 0; j < n; j++){\n\t\t\t\tdist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint res = -INF;\n\tfor (int i = 0; i < n; i++){\n\t\tif (dist[i][i] < 0){\n\t\t\treturn -1;\n\t\t}\n\t\tif (dist[0][i] < 0){\n\t\t\treturn -1;\n\t\t}\n\t\tres = max(res, dist[0][i]);\n\t}\n\t\n\treturn res;\n}\n\nint main()\n{\n\tscanf(\"%d %d\", &n, &c);\n\tvector<int> v;\n\t\n\tfor (int i = 0; i < c; i++){\n\t\tint a, b, w;\n\t\tchar ch, sg;\n\t\tscanf(\"%d\", &a);\n\t\tscanf(\"%c\", &ch);\n\t\tif (ch != '*') scanf(\"%*c\");\n\t\telse v.push_back(i);\n\t\tscanf(\"%d\", &b);\n\t\tif (ch == '>') swap(a, b);\n\t\tscanf(\"%c\", &sg);\n\t\tscanf(\"%d\", &w);\n\t\t--a; --b;\n\t\t\n\t\tif (sg == '-') g[i] = Edge(a, b, w);\n\t\telse g[i] = Edge(b, a, -w);\n\t\tg[i + c] = Edge(b, a, 0);\n\t}\n\t\n\tint res = -1;\n\t\n\tfor (int x = 0; x < (1 << v.size()); x++){\n\t\tfor (int k = 0; k < v.size(); k++){\n\t\t\tif (x & (1 << k)){\n\t\t\t\tswap(g[v[k]].a, g[v[k]].b);\n\t\t\t\tswap(g[v[k] + c].a, g[v[k] + c].b);\n\t\t\t}\n\t\t}\n\t\t\n\t\tres = max(res, solve());\n\t\t\n\t\tfor (int k = 0; k < v.size(); k++){\n\t\t\tif (x & (1 << k)){\n\t\t\t\tswap(g[v[k]].a, g[v[k]].b);\n\t\t\t\tswap(g[v[k] + c].a, g[v[k] + c].b);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tif (res == INF) puts(\"inf\");\n\telse printf(\"%d\\n\", res);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1256, "score_of_the_acc": -0.1067, "final_rank": 3 }, { "submission_id": "aoj_0304_1364720", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1 << 28;\n\nstruct Edge {\n\tint a, b, w;\n\tEdge(){}\n\tEdge(int a, int b, int w): a(a), b(b), w(w){}\n};\n\nint n, c;\nEdge g[400];\nint dist[100][100];\n\nint solve()\n{\n\tfill_n(*dist, 100 * 100, INF);\n\tfor (int i = 0; i < n; i++) dist[i][i] = 0;\n\t\n\tfor (int i = 0; i < c * 2; i++){\n\t\tint &t = dist[g[i].a][g[i].b];\n\t\tt = min(t, g[i].w);\n\t\t//printf(\"%d -> %d %d\\n\", g[i].a, g[i].b, g[i].w);\n\t}\n\t\n\tfor (int k = 0; k < n; k++){\n\t\tfor (int i = 0; i < n; i++){\n\t\t\tfor (int j = 0; j < n; j++){\n\t\t\t\tdist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint res = -INF;\n\tfor (int i = 0; i < n; i++){\n\t\tif (dist[i][i] < 0){\n\t\t\treturn -1;\n\t\t}\n\t\tif (dist[0][i] < 0){\n\t\t\treturn -1;\n\t\t}\n\t\tres = max(res, dist[0][i]);\n\t}\n\t\n\treturn res;\n}\n\nint main()\n{\n\tscanf(\"%d %d\", &n, &c);\n\tvector<int> v;\n\t\n\tfor (int i = 0; i < c; i++){\n\t\tint a, b, w;\n\t\tchar ch, sg;\n\t\tscanf(\"%d\", &a);\n\t\tscanf(\"%c\", &ch);\n\t\tif (ch != '*') scanf(\"%*c\");\n\t\telse v.push_back(i);\n\t\tscanf(\"%d\", &b);\n\t\tif (ch == '>') swap(a, b);\n\t\tscanf(\"%c\", &sg);\n\t\tscanf(\"%d\", &w);\n\t\t--a; --b;\n\t\t\n\t\tif (sg == '-') g[i] = Edge(a, b, w);\n\t\telse g[i] = Edge(b, a, -w);\n\t\tg[i + c] = Edge(b, a, 0);\n\t}\n\t\n\tint res = -1;\n\t\n\tfor (int x = 0; x < (1 << v.size()); x++){\n\t\tfor (int k = 0; k < v.size(); k++){\n\t\t\tif (x & (1 << k)){\n\t\t\t\tswap(g[v[k]].a, g[v[k]].b);\n\t\t\t\tswap(g[v[k] + c].a, g[v[k] + c].b);\n\t\t\t}\n\t\t}\n\t\t\n\t\tres = max(res, solve());\n\t\t\n\t\tfor (int k = 0; k < v.size(); k++){\n\t\t\tif (x & (1 << k)){\n\t\t\t\tswap(g[v[k]].a, g[v[k]].b);\n\t\t\t\tswap(g[v[k] + c].a, g[v[k] + c].b);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tif (res > INF / 2) puts(\"inf\");\n\telse printf(\"%d\\n\", res);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1256, "score_of_the_acc": -0.1067, "final_rank": 3 }, { "submission_id": "aoj_0304_1274247", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int NIL = -1;\nconst int INF = 1000000000;\n\ntypedef tuple<int, int, int, bool> Uncertain;\n\nint WarshallFloyd(vector<vector<int>> g, int start) {\n for(int i = 0; i < g.size(); ++i) g[i][i] = 0;\n for(int k = 0; k < g.size(); ++k)\n for(int i = 0; i < g.size(); ++i)\n for(int j = 0; j < g.size(); ++j)\n g[i][j] = min(g[i][j], g[i][k] + g[k][j]);\n for(int i = 0; i < g.size(); ++i) if(g[i][i] < 0) return NIL;\n return *max_element(begin(g[start]), end(g[start]));\n}\n\nint solve(const vector<vector<int>>& g, const vector<Uncertain>& uncertain, bitset<8> bit = 0, int depth = 0) {\n if(depth == uncertain.size()) {\n auto h(g);\n for(int i = 0; i < uncertain.size(); ++i) {\n int u, v, d;\n bool positive;\n tie(u, v, d, positive) = uncertain[i];\n if(bit[i]) swap(u, v);\n h[v][u] = 0;\n if(positive) h[v][u] = -d;\n else h[u][v] = d;\n }\n return WarshallFloyd(h, 0);\n }\n return max(solve(g, uncertain, bit.set(depth), depth + 1), solve(g, uncertain, bit.reset(depth), depth + 1));\n}\n\nint main() {\n int N, C;\n cin >> N >> C;\n vector<vector<int>> g(N, vector<int>(N, INF));\n for(int i = 1; i < N; ++i) g[i][0] = 0;\n vector<Uncertain> uncertain;\n for(int i = 0; i < C; ++i) {\n string s;\n cin >> s;\n // parse\n enum {LESS = '<', EQUAL = '*', MORE = '>'};\n int u = 0, v = 0, d = 0;\n char order;\n bool positive;\n int index = 0;\n while(isdigit(s[index])) u = 10 * u + (s[index++] - '0');\n if((order = s[index++]) != EQUAL) ++index;\n while(isdigit(s[index])) v = 10 * v + (s[index++] - '0');\n positive = (s[index++] == '+');\n while(isdigit(s[index])) d = 10 * d + (s[index++] - '0');\n // edge\n --u;\n --v;\n if(order == EQUAL) {\n uncertain.emplace_back(u, v, d, positive);\n } else {\n if(order == MORE) swap(u, v);\n g[v][u] = 0;\n if(positive) g[v][u] = -d;\n else g[u][v] = d;\n }\n }\n // output\n int answer = solve(g, uncertain);\n if(answer == INF) cout << \"inf\";\n else cout << answer;\n cout << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 1360, "score_of_the_acc": -0.1662, "final_rank": 6 }, { "submission_id": "aoj_0304_1274246", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int NIL = -1;\nconst int INF = 1000000000;\n\ntypedef tuple<int, int, int, bool> Uncertain;\n\nint BellmanFord(const vector<vector<int>>& g, int start) {\n vector<int> distance(g.size(), INF);\n distance[start] = 0;\n for(int step = 1; step <= g.size(); ++step) {\n for(int i = 0; i < g.size(); ++i) {\n for(int j = 0; j < g.size(); ++j) {\n if(g[i][j] == INF) continue;\n if(distance[j] <= distance[i] + g[i][j]) continue;\n if(step == g.size()) return NIL;\n distance[j] = distance[i] + g[i][j];\n }\n }\n }\n return *max_element(begin(distance), end(distance));\n}\n\nint solve(const vector<vector<int>>& g, const vector<Uncertain>& uncertain, bitset<8> bit = 0, int depth = 0) {\n if(depth == uncertain.size()) {\n auto h(g);\n for(int i = 0; i < uncertain.size(); ++i) {\n int u, v, d;\n bool positive;\n tie(u, v, d, positive) = uncertain[i];\n if(bit[i]) swap(u, v);\n h[v][u] = 0;\n if(positive) h[v][u] = -d;\n else h[u][v] = d;\n }\n return BellmanFord(h, 0);\n }\n return max(solve(g, uncertain, bit.set(depth), depth + 1), solve(g, uncertain, bit.reset(depth), depth + 1));\n}\n\nint main() {\n int N, C;\n cin >> N >> C;\n vector<vector<int>> g(N, vector<int>(N, INF));\n for(int i = 1; i < N; ++i) g[i][0] = 0;\n vector<Uncertain> uncertain;\n for(int i = 0; i < C; ++i) {\n string s;\n cin >> s;\n // parse\n enum {LESS = '<', EQUAL = '*', MORE = '>'};\n int u = 0, v = 0, d = 0;\n char order;\n bool positive;\n int index = 0;\n while(isdigit(s[index])) u = 10 * u + (s[index++] - '0');\n if((order = s[index++]) != EQUAL) ++index;\n while(isdigit(s[index])) v = 10 * v + (s[index++] - '0');\n positive = (s[index++] == '+');\n while(isdigit(s[index])) d = 10 * d + (s[index++] - '0');\n // edge\n --u;\n --v;\n if(order == EQUAL) {\n uncertain.emplace_back(u, v, d, positive);\n } else {\n if(order == MORE) swap(u, v);\n g[v][u] = 0;\n if(positive) g[v][u] = -d;\n else g[u][v] = d;\n }\n }\n // output\n int answer = solve(g, uncertain);\n if(answer == INF) cout << \"inf\";\n else cout << answer;\n cout << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 1316, "score_of_the_acc": -0.1316, "final_rank": 5 } ]
aoj_0301_cpp
バトンリレーゲーム アカベ高校では、毎年全校生徒が参加するゲームを行っています。まず、校庭に N 人の全校生徒が円形に並びます。図のように、各生徒は 0 から N -1 までの番号が書かれたゼッケンを付けています。 ゲームではバトンを1本使い、最初はゼッケン 0 番の生徒がバトンを持っています。そこから、以下の手順を M 回繰り返します。まず、現時点でバトンを持っている生徒が適当な正の整数 a を宣言します。 a が偶数のときは時計回り、奇数のときは反時計回りに隣の生徒にバトンを渡していき、 a 番目にバトンを受け取った生徒が脱落します。脱落した生徒は、時計回りで隣の生徒にバトンを渡し、円から抜けます。 ゲームが終わった後に円に残った生徒は、放課後の掃除が1年間免除されます。しかし、ここ数年は生徒数が増えたため、全校生徒を集めるのが難しくなってきています。そこで、競技プログラミング部のあなたは、シミュレーションで掃除が免除される生徒を求めるプログラムを作成するよう頼まれました。 指定した生徒が掃除を免除されているかどうかを質問したとき、それに答えるプログラムを作成してください。 入力 入力は以下の形式で与えられる。 N M Q a 1 a 2 ... a M q 1 q 2 ... q Q 入力は3行であり、1行目に生徒の人数 N (10 ≤ N ≤ 200000)、繰り返し回数 M (5 ≤ M < N )、生徒が掃除を免除されるかどうかを問い合わせる質問の個数 Q (1 ≤ Q ≤ 1000) が与えられる。続く1行に、 i 回目の繰り返しで最初にバトンを持っている生徒が宣言する整数 a i (1 ≤ a i ≤ 100) が与えられる。続く1行に、質問としてゼッケン番号 q i (0 ≤ q < N ) が与えられる。 出力 質問ごとに、ゼッケン番号 q i の生徒が掃除を免除されるかどうかを i 行目に出力する。掃除が免除されるなら 1 を、されないなら 0 を出力する。 入出力例 入力例 10 5 3 2 6 5 18 3 3 0 5 出力例 1 0 1
[ { "submission_id": "aoj_0301_10876569", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int n, m, Q; cin >> n >> m >> Q;\n set<int> st;\n rep(i, n)st.insert(i);\n vector<bool> b(n, true);\n auto it = st.begin();\n rep(i, m) {\n int a; cin >> a;\n bool rev = a % 2;\n rep(j, a) {\n if (!rev) {\n if (next(it) == st.end())it = st.begin();\n else it++;\n }\n else {\n if (it == st.begin())it = prev(st.end());\n else it--;\n }\n }\n b[*it] = false;\n auto del = it;\n if (next(it) == st.end())it = st.begin();\n else it++;\n st.erase(del);\n }\n rep(i, Q) {\n int q; cin >> q;\n cout << b[q] << endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 13056, "score_of_the_acc": -1.0713, "final_rank": 14 }, { "submission_id": "aoj_0301_10850147", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,M,Q;\n cin>>N>>M>>Q;\n vector<int> ans(N,1);\n\n vector<int> R(N),L(N);\n rep(i,N) R[i]=(i+1)%N;\n rep(i,N) L[i]=(i+N-1)%N;\n int now=0;\n rep(_,M){\n int a;\n cin>>a;\n rep(_,a) now=(a%2?L:R)[now];\n int d=now;\n now=R[now];\n L[R[d]]=L[d];\n R[L[d]]=R[d];\n ans[d]=0;\n }\n\n rep(i,Q){\n int q;\n cin>>q;\n cout<<ans[q]<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5760, "score_of_the_acc": -0.2473, "final_rank": 8 }, { "submission_id": "aoj_0301_10848065", "code_snippet": "// 7\n\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = 1ll<<29;\nconst bool debug = 0;\n\nint N, M, Q;\nbool valid[212345];\nint a[212345];\n\nint main() {\n\tcin >> N >> M >> Q;\n\tREP(i, M) scanf(\"%d\", a + i);\n\t\n\tfill(valid, valid + N, 1);\n\t\n\tlist<int> lis;\n\tREP(i, N) lis.insert(lis.end(), i);\n\t\n\tlist<int>::iterator it = lis.begin();\n\t\n\tREP(i, M) {\n\t\tREP(j, a[i]) {\n\t\t\tif (a[i] & 1) { // 反時計周り\n\t\t\t\t--it;\n\t\t\t\tif (it == lis.end()) --it;\n\t\t\t}\n\t\t\telse { // 時計回り\n\t\t\t\t++it;\n\t\t\t\tif (it == lis.end()) ++it;\n\t\t\t}\n\t\t}\n\t\t\n\t\tvalid[*it] = false;\n\t\tit = lis.erase(it);\n\t\tif (it == lis.end()) ++it;\n\t}\n\t\n\t\n\tREP(i, Q) {\n\t\tint q;\n\t\tscanf(\"%d\", &q);\n\t\tprintf(\"%d\\n\", valid[q]);\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10728, "score_of_the_acc": -0.7306, "final_rank": 12 }, { "submission_id": "aoj_0301_10826880", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,s,t) for(int i = s ; i < t ; ++i)\n#define ALL(a) a.begin(),a.end()\n#define SORT(a) sort(ALL(a))\n#define UNIQ(a) a.erase(unique(ALL(a)),a.end())\n#define debug(a) cerr<<#a\":=\"<<a<<endl\n#define SZ(a) (int)a.size()\nusing LL = long long; template<class T> using V = vector<T>; template<class T> using VV = V<V<T>>;\n\ntemplate<typename type>\nstruct BIT0 { // 0-index\n\tint N;\n\tint nn;\n\tvector<type> data;\n\t//動的はmap<int?,type>data\n\tBIT0(int n) {\n\t\tN = n + 1;\n\t\tdata = vector<type>(n + 1, 0);\n\t\tnn = 1;\n\t\twhile (nn * 2 <= N)nn *= 2;\n\t}\n\tvoid add(int i, type w) { // a[i] += w\n\t\ti++;\n\t\tfor (int x = i; x < N; x += x & -x) {\n\t\t\tdata[x] += w;\n\t\t}\n\t}\n\ttype sum(int i) { // iまでの和 [0,i)\n\t\ttype ret = 0;\n\t\tfor (int x = i; x > 0; x -= x & -x) {\n\t\t\tret += data[x];\n\t\t}\n\t\treturn ret;\n\t}\n\t// [l, r)\n\ttype sum(int l, int r) {\n\t\treturn sum(r) - sum(l);\n\t}\n\n\t/*\tBIT 上で二分探索\n\t二分木の分かれ方に従って二分探索する\n\t左の子に進むか右の子に進むかを知るためには,左の子の範囲の和がわかればよい\n\tちょうど BIT がもっている情報,O(1) 時間で得られる\n\ta[1] + a[2] + a[3] + ... a[x] >= w となる最小のxを返す、ただしa[i] >= 0\t*/\n\n\tint lower_bound(type w) {// w≦[0,x]以上となる最小のindex,x\n\t\tif (w <= 0) return 0;\n\t\tint x = 0;\n\t\tfor (int k = nn; k > 0; k /= 2) {\n\t\t\tif (x + k <= N && data[x + k] < w) {\n\t\t\t\tw -= data[x + k];\n\t\t\t\tx += k;\n\t\t\t}\n\t\t}\n\t\treturn x;\n\t}\n};\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\n\tint N, M, Q;\n\tcin >> N >> M >> Q;\n\tV<int>a(M);\n\tFOR(i, 0, M) {\n\t\tcin >> a[i];\n\t}\n\tBIT0<int>bit(N);\n\tFOR(i, 0, N) {\n\t\tbit.add(i, 1);\n\t}\n\t// 常に右にわたすことに注意\n\tint button = 0;\n\n\tauto buttonPass = [&bit, N](int target) {\n\t\t// targetからみて次の増加番号の人にバトンを渡す\n\t\tint presum = bit.sum(0, target);// bit[target]は0\n\n\t\tif (bit.sum(target, N)) {//1人でもいる\n\t\t\treturn bit.lower_bound(presum + 1);\n\t\t}\n\t\telse {\n\t\t\treturn bit.lower_bound(1);\n\t\t}\n\t};\n\n\tFOR(i, 0, M) {\n\t\tint plus = a[i];\n\t\tif (plus % 2 == 0) {// 右\n\t\t\tplus %= bit.sum(0,N);\n\t\t\tif (bit.sum(button + 1, N) >= plus) {// 渡せる\n\t\t\t\tint sum = bit.sum(0, button + 1);\n\t\t\t\tint target = bit.lower_bound(sum + plus);\n\t\t\t\tbit.add(target, -1);\n\t\t\t\t// バトンをtargetの右に渡す\n\t\t\t\tbutton = buttonPass(target);\n\t\t\t}\n\t\t\telse { // またいで渡す\n\t\t\t\tplus -= bit.sum(button + 1, N);\n\t\t\t\tbutton = 0;\n\t\t\t\tint target = bit.lower_bound(plus);\n\t\t\t\tbit.add(target, -1);\n\n\t\t\t\t// バトンをtargetの右に渡す\n\t\t\t\tbutton = buttonPass(target);\n\t\t\t}\n\t\t}\n\t\telse { //左\n\t\t\tplus %= bit.sum(0, N);\n\t\t\tif (bit.sum(0, button) >= plus) {// ぽい\n\t\t\t\tint sum = bit.sum(0, button);\n\t\t\t\tint target = bit.lower_bound(sum - plus + 1);\n\t\t\t\tbit.add(target, -1);\n\t\t\t\t//バトンをtargetの右に渡す\n\t\t\t\tbutton = buttonPass(target);\n\n\t\t\t}\n\t\t\telse {// ぽいではない\n\t\t\t\tplus -= bit.sum(0, button);\n\t\t\t\tbutton = N - 1;\n\t\t\t\tint sum = bit.sum(0, button + 1);\n\t\t\t\tint target = bit.lower_bound(sum - plus + 1);\n\t\t\t\tbit.add(target, -1);\n\n\t\t\t\t//バトンをtargetの右に渡す\n\t\t\t\tbutton = buttonPass(target);\n\t\t\t}\n\t\t}\n\t}\n\n\tFOR(i, 0, Q) {\n\t\tint q; cin >> q;\n\t\tcout << bit.sum(q, q + 1) << endl;\n\t\t// 1(免除)->存在 or 0\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4524, "score_of_the_acc": -0.1441, "final_rank": 1 }, { "submission_id": "aoj_0301_10787976", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n\n\nint main(){\n ll N,M,Q;cin>>N>>M>>Q;\n vector<int>A(M);\n rep(i,M)cin>>A[i];\n vector<pair<int,int>>D(N);\n vector<bool>out(N,false);\n rep(i,N){\n D[i].se = (i+1)%N;\n D[i].fi = (N+i-1)%N;\n }\n int v = 0;\n rep(i,M){\n if(A[i]%2==0){\n rep(k,A[i]){\n v = D[v].se;\n }\n }\n else {\n rep(k,A[i]){\n v = D[v].fi;\n }\n }\n out[v] = true;\n D[D[v].se].fi = D[v].fi;\n D[D[v].fi].se = D[v].se;\n v = D[v].se;\n }\n rep(i,Q){\n int q;cin>>q;\n if(out[q])cout<<0<<endl;\n else cout<<1<<endl;\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5496, "score_of_the_acc": -0.2456, "final_rank": 7 }, { "submission_id": "aoj_0301_9616518", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n#include <algorithm>\n#include <cassert>\n#include <functional>\n#include <vector>\n\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#if __cplusplus >= 202002L\n#include <bit>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n#if __cplusplus >= 202002L\n\nusing std::bit_ceil;\n\n#else\n\nunsigned int bit_ceil(unsigned int n) {\n unsigned int x = 1;\n while (x < (unsigned int)(n)) x *= 2;\n return x;\n}\n\n#endif\n\nint countr_zero(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\nconstexpr int countr_zero_constexpr(unsigned int n) {\n int x = 0;\n while (!(n & (1 << x))) x++;\n return x;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\n#if __cplusplus >= 201703L\n\ntemplate <class S, auto op, auto e> struct segtree {\n static_assert(std::is_convertible_v<decltype(op), std::function<S(S, S)>>,\n \"op must work as S(S, S)\");\n static_assert(std::is_convertible_v<decltype(e), std::function<S()>>,\n \"e must work as S()\");\n\n#else\n\ntemplate <class S, S (*op)(S, S), S (*e)()> struct segtree {\n\n#endif\n\n public:\n segtree() : segtree(0) {}\n explicit segtree(int n) : segtree(std::vector<S>(n, e())) {}\n explicit segtree(const std::vector<S>& v) : _n(int(v.size())) {\n size = (int)internal::bit_ceil((unsigned int)(_n));\n log = internal::countr_zero((unsigned int)size);\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) const {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n\n S prod(int l, int r) const {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() const { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) const {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) const {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) const {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) const {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\n} // namespace atcoder\n\nusing namespace atcoder;\n\nint e() { return 0; }\nint op(int x, int y) { return x + y; }\n\nbool f(int x) { return x == 0; }\n\nint main() {\n int N, M, Q;\n cin >> N >> M >> Q;\n vector<int> seg_init(N, 1);\n segtree<int, op, e> seg(seg_init);\n auto next_clockwise = [&](int i) -> int {\n return (seg.prod(i + 1, N) == 0 ? seg.max_right<f>(0) : seg.max_right<f>(i + 1));\n };\n auto prev_clockwise = [&](int i) -> int {\n return (seg.prod(0, i) == 0 ? seg.min_left<f>(N) - 1 : seg.min_left<f>(i) - 1);\n };\n int b = 0;\n while(M--) {\n int a;\n cin >> a;\n if(a % 2 == 0) {\n while(a--) b = next_clockwise(b);\n seg.set(b, 0);\n b = next_clockwise(b);\n }else {\n while(a--) b = prev_clockwise(b);\n seg.set(b, 0);\n b = next_clockwise(b);\n }\n }\n while(Q--) {\n int q;\n cin >> q;\n cout << seg.get(q) << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 5876, "score_of_the_acc": -1.2581, "final_rank": 16 }, { "submission_id": "aoj_0301_6948660", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cassert>\n#include <string>\n#include <bitset>\n#include <queue>\n#define ll long long\nusing namespace std;\n\nint main(){\n int n,m,q; cin >> n >> m >> q;\n deque<int> p;\n for(int i = 0;i < n;i++) p.push_back(i);\n for(int i = 0;i < m;i++){\n int a;cin >> a;\n if(a % 2 == 0){\n for(int j = 0;j < a;j++){\n p.push_back(p.at(0));\n p.pop_front();\n }\n }else{\n for(int j = 0;j < a;j++){\n p.push_front(p.at(p.size() - 1));\n p.pop_back();\n }\n }\n p.pop_front();\n }\n vector<int> ans(n,0);\n for(int i : p) ans[i] = 1;\n for(int i = 0;i < q;i++){\n int s;cin >> s; cout << ans[s] << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4644, "score_of_the_acc": -0.1893, "final_rank": 3 }, { "submission_id": "aoj_0301_6878390", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef struct L{int f,b;}List;\nint main(void)\n{\n int n,m,q;\n cin>>n>>m>>q;\n List s[n+1];\n vector<int> f(n+1,1);\n for(int i=0;i<n;i++){\n s[i].f=i+1; s[i].b=i-1;\n }\n s[n-1].f=0; s[0].b=n-1;\n int p=0;\n for(int i=0;i<m;i++){\n int a; cin>>a;\n for(int j=0;j<a;j++){\n if(a%2) p=s[p].b;\n else p=s[p].f;\n }\n s[s[p].b].f=s[p].f;\n s[s[p].f].b=s[p].b;\n f[p]=0; p=s[p].f;\n }\n for(int i=0;i<q;i++){\n int a; cin>>a;\n cout<<f[a]<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5132, "score_of_the_acc": -0.2346, "final_rank": 5 }, { "submission_id": "aoj_0301_6875761", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <list>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\nusing pii = pair<int, int>;\n\nint main()\n{\n int n, m, Q;\n cin >> n >> m >> Q;\n vi<int> a(m), q(Q);\n rep(i, m) cin >> a[i];\n rep(i, Q) cin >> q[i];\n\n list<int> lst;\n const int inf = 1e9;\n lst.push_back(-inf);\n rep(i, n) lst.push_back(i);\n lst.push_back(inf);\n auto itr = lst.begin();\n itr++;\n rep(i, m) {\n if (a[i] % 2 == 0) {\n rep(j, a[i]) {\n itr++;\n if (*itr == inf) {\n itr = lst.begin();\n itr++;\n }\n }\n }\n else {\n rep(j, a[i]) {\n itr--;\n if (*itr == -inf) {\n itr = lst.end();\n itr--;\n itr--;\n }\n }\n }\n itr = lst.erase(itr);\n if (*itr == inf) {\n itr = lst.begin();\n itr++;\n }\n }\n vi<int> check(n);\n for (auto it = lst.begin(); it != lst.end(); it++) {\n if (abs(*it) == inf) continue;\n check[*it] = 1;\n }\n\n rep(i, Q) cout << check[q[i]] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10240, "score_of_the_acc": -0.6853, "final_rank": 11 }, { "submission_id": "aoj_0301_6479438", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m,q; cin >> n >> m >> q;\n vector<int> nxt(n),pre(n);\n for(int i=0;i<n;i++){\n nxt[i] = (i+1)%n;\n pre[i] = (i+n-1)%n;\n }\n int cur = 0;\n vector<bool> fail(n,false);\n while(m--){\n int a; cin >> a;\n if(a&1){\n while(a--){\n cur = pre[cur];\n }\n }\n else{\n while(a--){\n cur = nxt[cur];\n }\n }\n fail[cur] = true;\n nxt[pre[cur]] = nxt[cur];\n pre[nxt[cur]] = pre[cur];\n cur = nxt[cur];\n }\n while(q--){\n int a; cin >> a;\n if(fail[a]){\n cout << 0 << \"\\n\";\n }\n else{\n cout << 1 << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4568, "score_of_the_acc": -0.1482, "final_rank": 2 }, { "submission_id": "aoj_0301_6278679", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint v[200002], l[200002], r[200002];\n\nint main() {\n\n\tint N, M, Q;\n\tint at = 0, m, q;\n\n\tcin >> N >> M >> Q;\n\n\n\tfor (int i = 0; i < N; i++) {\n\t\tv[i] = 1;\n\t\tl[i] = (i + N - 1) % N;\n\t\tr[i] = (i + 1) % N;\n\t}\n\n\tfor (int i = 0; i < M; i++) {\n\t\tcin >> m;\n\n\t\tif (m % 2)\n\t\t\tfor (int j = 0; j < m; j++)\n\t\t\t\tat = l[at];\n\t\telse\n\t\t\tfor (int j = 0; j < m; j++)\n\t\t\t\tat = r[at];\n\n\t\tv[at] = 0;\n\t\tint tmpL = l[at], tmpR = r[at];\n\t\tl[tmpR] = tmpL;\n\t\tr[tmpL] = tmpR;\n\t\tat = tmpR;\n\n\t}\n\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> q;\n\t\tcout << v[q] << endl;\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5452, "score_of_the_acc": -0.2529, "final_rank": 9 }, { "submission_id": "aoj_0301_6268989", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <string.h>\n\nusing namespace std;\n\nint main() {\n\n\tint N, M, Q, tmp;\n\tqueue<int> a;\n\tint ans[200002];\n\tvector<int> q;\n\tvector<int> an;\n\n\tmemset(ans, -1, sizeof(ans));\n\n\tcin >> N >> M >> Q;\n\n\tfor (int i = 0; i < M; i++)\n\t\tcin >> tmp, a.push(tmp);\n\n\tfor (int i = 0; i < Q; i++)\n\t\tcin >> tmp, q.push_back(tmp);\n\n\n\tint n = a.front() % 2 == 0 ? 0 : N - 1;\n\twhile (!a.empty()) {\n\t\tint A = a.front();\n\t\ta.pop();\n\t\tbool isEven = A % 2 == 0;\n\n\t\tfor (int i = 0; i < A; i++) {\n\t\t\tisEven ? n++ : n--;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t\tif (n < 0)\n\t\t\t\tn = N - 1;\n\t\t\twhile (ans[n] == 0) {\n\t\t\t\tisEven ? n++ : n--;\n\t\t\t\tif (n == N)\n\t\t\t\t\tn = 0;\n\t\t\t\tif (n < 0)\n\t\t\t\t\tn = N - 1;\n\t\t\t}\n\t\t}\n\t\tans[n] = 0;\n\t\tan.push_back(n);\n\t\tn++;\n\t\tif (n == N)\n\t\t\tn = 0;\n\t\twhile (ans[n] == 0) {\n\t\t\tn++;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t}\n\t}\n\n\tfor (vector<int>::iterator i = q.begin(); i != q.end(); i++) {\n\t\tbool isP = false;\n\t\tfor (vector<int>::iterator j = an.begin(); j != an.end(); j++) {\n\t\t\tif (*i == *j) {\n\t\t\t\tisP = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout << (isP ? 0 : 1) << endl;\n\t}\n\n\n\n\treturn 0;\n}", "accuracy": 0.5555555555555556, "time_ms": 350, "memory_kb": 5436, "score_of_the_acc": -0.5923, "final_rank": 17 }, { "submission_id": "aoj_0301_6268951", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <string.h>\n\nusing namespace std;\n\nbool isRead(int n, vector<int> &ans) {\n\tfor (vector<int>::iterator i = ans.begin(); i != ans.end(); i++)\n\t\tif (*i == n)\n\t\t\treturn true;\n\treturn false;\n}\n\nint main() {\n\n\tint N, M, Q, tmp;\n\tqueue<int> a;\n\tint ans[200002];\n\tvector<int> q;\n\tvector<int> an;\n\n\tmemset(ans, -1, sizeof(ans));\n\n\tcin >> N >> M >> Q;\n\n\tfor (int i = 0; i < M; i++)\n\t\tcin >> tmp, a.push(tmp);\n\n\tfor (int i = 0; i < Q; i++)\n\t\tcin >> tmp, q.push_back(tmp);\n\n\n\tint n = a.front() % 2 == 0 ? 0 : N - 1;\n\twhile (!a.empty()) {\n\t\tint A = a.front();\n\t\ta.pop();\n\t\tbool isEven = A % 2 == 0;\n\n\t\tfor (int i = 0; i < A; i++) {\n\t\t\tisEven ? n++ : n--;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t\tif (n < 0)\n\t\t\t\tn = N - 1;\n\t\t\twhile (ans[n] == 0) {\n\t\t\t\tisEven ? n++ : n--;\n\t\t\t\tif (n == N)\n\t\t\t\t\tn = 0;\n\t\t\t\tif (n < 0)\n\t\t\t\t\tn = N - 1;\n\t\t\t}\n\t\t}\n\t\tans[n] = 0;\n\t\tan.push_back(n);\n\t\tn++;\n\t\tif (n == N)\n\t\t\tn = 0;\n\t\twhile (ans[n] == 0) {\n\t\t\tn++;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t}\n\t}\n\n\tfor (vector<int>::iterator i = q.begin(); i != q.end(); i++) {\n\t\tbool isP = false;\n\t\tfor (vector<int>::iterator j = an.begin(); j != an.end(); j++) {\n\t\t\tif (*i == *j) {\n\t\t\t\tisP = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout << (isP ? 0 : 1) << endl;\n\t}\n\n\n\n\treturn 0;\n}", "accuracy": 0.5555555555555556, "time_ms": 350, "memory_kb": 5436, "score_of_the_acc": -0.5923, "final_rank": 17 }, { "submission_id": "aoj_0301_6267807", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nbool isRead(int n, vector<int> &ans) {\n\tfor (vector<int>::iterator i = ans.begin(); i != ans.end(); i++)\n\t\tif (*i == n)\n\t\t\treturn true;\n\treturn false;\n}\n\nint main() {\n\n\tint N, M, Q, tmp;\n\tqueue<int> a;\n\tvector<int> ans;\n\tvector<int> q;\n\n\tcin >> N >> M >> Q;\n\n\tfor (int i = 0; i < M; i++)\n\t\tcin >> tmp, a.push(tmp);\n\n\tfor (int i = 0; i < Q; i++)\n\t\tcin >> tmp, q.push_back(tmp);\n\n\n\tint n = a.front() % 2 == 0 ? 0 : N - 1;\n\twhile (!a.empty()) {\n\t\tint A = a.front();\n\t\ta.pop();\n\t\tbool isEven = A % 2 == 0;\n\n\t\tfor (int i = 0; i < A; i++) {\n\t\t\tisEven ? n++ : n--;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t\tif (n < 0)\n\t\t\t\tn = N - 1;\n\t\t\twhile (isRead(n, ans)) {\n\t\t\t\tisEven ? n++ : n--;\n\t\t\t\tif (n == N)\n\t\t\t\t\tn = 0;\n\t\t\t\tif (n < 0)\n\t\t\t\t\tn = N - 1;\n\t\t\t}\n\t\t}\n\t\tans.push_back(n);\n\t\tn++;\n\t\twhile (isRead(n, ans)) {\n\t\t\tisEven ? n++ : n--;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t\tif (n < 0)\n\t\t\t\tn = N - 1;\n\t\t}\n\t}\n\n\tfor (vector<int>::iterator i = q.begin(); i != q.end(); i++) {\n\t\tbool isP = false;\n\t\tfor (vector<int>::iterator j = ans.begin(); j != ans.end(); j++) {\n\t\t\tif (*i == *j) {\n\t\t\t\tisP = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout << (isP ? 0 : 1) << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 0.1111111111111111, "time_ms": 40, "memory_kb": 3100, "score_of_the_acc": -0.0235, "final_rank": 20 }, { "submission_id": "aoj_0301_6267784", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nbool isRead(int n, vector<int> &ans) {\n\tfor (vector<int>::iterator i = ans.begin(); i != ans.end(); i++)\n\t\tif (*i == n)\n\t\t\treturn true;\n\treturn false;\n}\n\nint main() {\n\n\tint N, M, Q, tmp;\n\tqueue<int> a;\n\tvector<int> ans;\n\tvector<int> q;\n\n\tcin >> N >> M >> Q;\n\n\tfor (int i = 0; i < M; i++)\n\t\tcin >> tmp, a.push(tmp);\n\n\tfor (int i = 0; i < Q; i++)\n\t\tcin >> tmp, q.push_back(tmp);\n\n\n\tint n = a.front() % 2 == 0 ? 0 : N - 1;\n\twhile (!a.empty()) {\n\t\tint A = a.front();\n\t\ta.pop();\n\t\tbool isEven = A % 2 == 0;\n\n\t\tfor (int i = 0; i < A; i++) {\n\t\t\tisEven ? n++ : n--;\n\t\t\tif (n == N)\n\t\t\t\tn = 0;\n\t\t\tif (n < 0)\n\t\t\t\tn = N - 1;\n\t\t\twhile (isRead(n, ans)) {\n\t\t\t\tisEven ? n++ : n--;\n\t\t\t\tif (n == N)\n\t\t\t\t\tn = 0;\n\t\t\t\tif (n < 0)\n\t\t\t\t\tn = N - 1;\n\t\t\t}\n\t\t}\n\t\tans.push_back(n);\n\t\tn++;\n\t\tif (n == N)\n\t\t\tn = 0;\n\t}\n\n\tfor (vector<int>::iterator i = q.begin(); i != q.end(); i++) {\n\t\tbool isP = false;\n\t\tfor (vector<int>::iterator j = ans.begin(); j != ans.end(); j++) {\n\t\t\tif (*i == *j) {\n\t\t\t\tisP = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcout << (isP ? 0 : 1) << endl;\n\t}\n\n\treturn 0;\n}", "accuracy": 0.1111111111111111, "time_ms": 30, "memory_kb": 3092, "score_of_the_acc": -0.0114, "final_rank": 19 }, { "submission_id": "aoj_0301_5965022", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct binary_indexed_tree{\n int N;\n vector<int> BIT;\n binary_indexed_tree(int N): N(N), BIT(N + 1, 0){\n }\n void add(int i, int x){\n i++;\n while (i <= N){\n BIT[i] += x;\n i += i & -i;\n }\n }\n int sum(int i){\n int ans = 0;\n while (i > 0){\n ans += BIT[i];\n i -= i & -i;\n }\n return ans;\n }\n int sum(int L, int R){\n return sum(R) - sum(L);\n }\n};\nint main(){\n int N, M, Q;\n cin >> N >> M >> Q;\n vector<int> a(M);\n for (int i = 0; i < M; i++){\n cin >> a[i];\n }\n set<int> st;\n for (int i = 0; i < N; i++){\n st.insert(i);\n }\n binary_indexed_tree BIT(N);\n for (int i = 0; i < N; i++){\n BIT.add(i, 1);\n }\n int p = 0;\n for (int i = 0; i < M; i++){\n if (a[i] % 2 == 0){\n a[i] %= N - i;\n if (a[i] == 0){\n a[i] = N - i;\n }\n int S = BIT.sum(p + 1, N);\n if (S >= a[i]){\n int tv = p + 1, fv = N;\n while (fv - tv > 1){\n int mid = (tv + fv) / 2;\n if (BIT.sum(p + 1, mid) < a[i]){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n p = tv;\n } else {\n int tv = 0, fv = p + 1;\n while (fv - tv > 1){\n int mid = (tv + fv) / 2;\n if (S + BIT.sum(mid) < a[i]){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n p = tv;\n }\n } else {\n a[i] %= N - i;\n if (a[i] == 0){\n a[i] = N - i;\n }\n int S = BIT.sum(0, p);\n if (S >= a[i]){\n int tv = p, fv = 0;\n while (tv - fv > 1){\n int mid = (tv + fv) / 2;\n if (BIT.sum(mid, p) < a[i]){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n p = fv;\n } else {\n int tv = N, fv = p;\n while (tv - fv > 1){\n int mid = (tv + fv) / 2;\n if (S + BIT.sum(mid, N) < a[i]){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n p = fv;\n }\n }\n BIT.add(p, -1);\n st.erase(p);\n auto itr = st.lower_bound(p);\n if (itr != st.end()){\n p = *itr;\n } else {\n p = *st.begin();\n }\n }\n for (int i = 0; i < Q; i++){\n int q;\n cin >> q;\n cout << st.count(q) << endl;\n }\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 13880, "score_of_the_acc": -1.1364, "final_rank": 15 }, { "submission_id": "aoj_0301_5925989", "code_snippet": "#include <iostream>\n#include <unordered_set>\n#include <vector>\n#include <cassert>\n#include <numeric>\nusing namespace std;\n\nclass LinkedList{\n public:\n long number;\n LinkedList *before, *after;\n\n LinkedList(long n){\n before = 0x0;\n after = 0x0;\n number = n;\n }\n LinkedList(void){\n before = 0x0;\n after = 0x0;\n number = -1;\n }\n void connect(LinkedList* l){\n after = l;\n l -> before = this;\n }\n void set(long n){\n number = n;\n }\n\n void print(void){\n cout<<\"before pointer:\\t\"<<before<<endl;\n cout<<\"self pointer:\\t\"<<this<<endl;\n cout<<\"after pointer:\\t\"<<after<<endl;\n cout<<\"value\\t\"<<number<<endl;\n }\n};\n\n\nint main(void){\n long N,M,Q;\n cin>>N>>M>>Q;\n long * a = new long[M];\n for(long i=0;i<M;i++){\n cin>>a[i];\n }\n long * q = new long[Q];\n for(long i=0;i<Q;i++){\n cin>>q[i];\n }\n\n LinkedList * lists = new LinkedList[N];\n lists[0].set(0);\n for(int i=1;i<N;i++){\n lists[i] = LinkedList(i);\n lists[i-1].connect(&(lists[i]));\n }\n lists[N-1].connect(&(lists[0]));\n\n LinkedList* index = &(lists[0]);\n \n for(long i=0;i<M;i++){\n if(a[i]%2==0){\n for(int j=0;j<a[i];j++){\n index = index -> after;\n }\n }\n else{\n for(int j=0;j<a[i];j++){\n index = index -> before;\n }\n }\n index -> before -> after = index -> after;\n index -> after -> before = index -> before;\n\n index = index -> after; // メモリリークしていることに注意。まあ競技プログラミングなんで...。\n }\n unordered_set<long> last_students;\n last_students.clear();\n for(int i=0;i<N-M+1;i++){\n last_students.insert(index->number);\n index = index->after;\n }\n\n for(long i=0;i<Q;i++){\n if(last_students.find(q[i])!=last_students.end()){\n cout<<1<<endl;\n }\n else{\n cout<<0<<endl;\n }\n }\n\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 9608, "score_of_the_acc": -0.6267, "final_rank": 10 }, { "submission_id": "aoj_0301_5851983", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint s[200001],ss[200001],ff[200001];\nint main(void)\n{\n\tint n,m,q,a,qq,i,j,x;\n\tscanf(\"%d%d%d\",&n,&m,&q);\n\tfor(i=0;i<n;i++){\n\t\ts[i]=i+1;\n\t\tss[i]=i-1;\n\t\tff[i]=1;\n\t}\n\ts[n-1]=0;\n\tss[0]=n-1;\n\tx=0;\n\tfor(i=0;i<m;i++){\n\t\tscanf(\"%d\",&a);\n\t\tfor(j=0;j<a;j++){\n\t\t\tif(a%2==0) x=s[x];\n\t\t\telse x=ss[x];\n\t\t}\n\t\ts[ss[x]]=s[x];\n\t\tss[s[x]]=ss[x];\n\t\tff[x]=0;\n\t\tx=s[x];\n\t}\n\tfor(i=0;i<q;i++){\n\t\tscanf(\"%d\",&qq);\n\t\tprintf(\"%d\\n\",ff[qq]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5456, "score_of_the_acc": -0.2305, "final_rank": 4 }, { "submission_id": "aoj_0301_5843515", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint p[200001],pp[200001],ff[200001];\nint main(void)\n{\n\tint n,m,q,a,qq,i,j,k,x;\n\tscanf(\"%d%d%d\",&n,&m,&q);\n\tfor(i=0;i<n;i++){\n\t\tpp[i]=i-1;\n\t\tp[i]=i+1;\n\t\tff[i]=1;\n\t}\n\tp[n-1]=0;\n\tpp[0]=n-1;\n\tfor(i=0;i<m;i++){\n\t\tscanf(\"%d\",&a);\n\t\tfor(j=0;j<a;j++){\n\t\t\tif(a%2==0) k=p[k];\n\t\t\telse k=pp[k];\n\t\t}\n\t\tff[k]=0;\n\t\tpp[p[k]]=pp[k];\n\t\tp[pp[k]]=p[k];\n\t\t//printf(\"k=%d\\n\",k);\n\t\tk=p[k];\n\t}\n\tfor(i=0;i<q;i++){\n\t\tscanf(\"%d\",&qq);\n\t\tprintf(\"%d\\n\",ff[qq]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5576, "score_of_the_acc": -0.2416, "final_rank": 6 }, { "submission_id": "aoj_0301_5839209", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<climits>\n#include<iomanip>\n#include<cctype>\n#include<sstream>\n#include<regex>\n#include<bitset>\n#include<random>\n#include<complex>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nsigned main(){\n\tint n,m,q,a;\n\tcin>>n>>m>>q;\n\tset<int>st;\n\tfor(int i=0;i<n;i++)\n\t\tst.insert(i);\n\tauto it=st.begin();\n\tfor(int i=0;i<m;i++){\n\t\tcin>>a;\n\t\tif(a%2==0){\n\t\t\tfor(int j=0;j<a;j++){\n\t\t\t\tit++;\n\t\t\t\tif(it==st.end())\n\t\t\t\t\tit=st.begin();\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int j=0;j<a;j++){\n\t\t\t\tif(it==st.begin())\n\t\t\t\t\tit=st.end();\n\t\t\t\tit--;\n\t\t\t}\n\t\t}\n\t\tit=st.erase(it);\n\t\tif(it==st.end())\n\t\t\tit=st.begin();\n\t}\n\twhile(cin>>q)\n\t\tcout<<st.count(q)<<endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 12740, "score_of_the_acc": -1.0421, "final_rank": 13 } ]
aoj_0313_cpp
未知の病原菌 英世博士は未知の病原菌を発見しました。この病原菌は、アクダマキンとゼンダマキンと呼ばれる二種類の菌が、一直線に連なった鎖状の構造をしています。人類のために、この病原菌を無害化したいと考えています。 この病原菌は、長さが2以下になると力が弱まり、免疫力によって無害化されることが分かっています。英世博士は、この病原菌を任意の場所で切断して、前半と後半の2つの鎖にすることができます。また、2つの鎖を連結して1つの鎖にすることもできます。 しかし注意しなければいけないのは、アクダマキンの数が多い鎖はきわめて有害だということです。ある鎖においてアクダマキンの数がゼンダマキンの数よりも多くなると、その瞬間アクダマキンは無制限に増殖を始めます。これは長さ2以下の鎖についても例外ではないので、慎重に鎖を切断していかなければなりません。 どの瞬間においてもアクダマキンの数の方が多いような鎖を作ることなく、一本の鎖を長さ2以下にして無害化することは可能でしょうか。英世博士は、助手であるあなたに無害化が可能かどうか判定するプログラムを作成するよう指示しました。無害化が可能ならばその操作を出力し、不可能ならば不可能であると出力するプログラムを作成してください。ただし、その操作のステップ数が最小である必要はありません。 入力 入力は以下の形式で与えられる。 Q str 1 str 2 : str Q 1 行目に病原菌の数 Q (1 ≤ Q ≤ 300) が与えられる。続く Q 行に各病原菌の初期状態を表す ' o ' (ゼンダマキン) および ' x ' (アクダマキン) からなる1つの文字列 str i が与えられる。文字列 str i の長さは 1 以上 100 以下である。 出力 str i について、要求を満たす切断・結合操作の列が存在する場合、出力の最初の行にはその操作列の長さを表す整数 n を出力し、続く n 行に操作の内容を1行に1操作ずつ、最初の操作から順に出力する。 切断操作は以下の形式で表すこと。 split a p a は切断する鎖の識別番号を表す整数であり、 p はその鎖を切断する位置である。この操作の結果、鎖 a は先頭から p 番目(先頭を 0 から始める通し番号)の菌の直後で切断される。新しくできる2つの鎖のうち、前半のものに識別番号 m +1 が、後半のものに識別番号 m +2 が付与される(ここで、 m はこれまでに付与された最も大きな識別番号を表す)。また、鎖 a は消滅する。 結合操作は以下の形式で表すこと。 join a b a , b は結合する鎖の識別番号を表す整数である。この操作の結果、鎖 a の末尾に鎖 b の先頭を結合した新しい鎖が作られる。新しく作られた鎖には、識別番号 m +1 が付与される(ここで、 m はこれまでに付与された最も大きな識別番号を表す)。また、鎖 a , b は消滅する。 入力として与えられる最初の鎖には、識別番号 0 が付与されている。 操作の結果、問題の要求を満たすように鎖が分解されていた場合、どのような操作でも正答と判定される。操作列の長さも必ずしも最短である必要はない。ただし、操作列の長さは 20000 以下でなければならない。データセットにおいて、鎖が分解可能な場合、必ずこの条件を満たす操作列が存在することが保証される。 不正な操作列が出力された場合、誤答と判定される。不正な操作列には、以下の場合が含まれる。 切断操作 split a p において、0 ≤ p < (鎖 a の長さ)-1 が満たされていない場合。 切断・結合操作の対象となる鎖の識別番号がまだ生成されていないものである場合や、既に別の操作の対象となったため消滅している場合。 結合操作 join a b において、 a と b が等しい場合。 要求を満たす切断・結合操作の列が存在しない場合、" -1 "と出力する。 入出力例 入力例 6 oooxxxx ooooxxx oxxooxxo ooxx oo ooo 出力例 -1 7 split 0 0 join 2 1 split 3 4 split 4 0 join 7 6 split 8 2 split 9 0 3 split 0 1 split 2 1 split 4 1 -1 0 1 split 0 0 例えば、入力例の2番目の病原菌 ooooxxx は、 split 0 0 により o (1) と oooxxx (2) ができる。ここで、()内の数字は識別番号を表す。 join 2 1 により oooxxxo (3) ができ 1 と 2 は消滅する。 split 3 4 により oooxx (4) と xo (5) ができる。このとき{ oooxx (4), xo (5) }の鎖が存在する。 split 4 0 により o (6) と ooxx (7) ができる。{ xo (5), o (6), ooxx (7)} join 7 6 により ooxxo (8) ができる。{ xo (5), ooxxo (8)} split 8 2 により oox (9) と xo (10) ができる。{ xo (5), oox (9), xo (10) } split 9 0 により { xo (5), xo (10), o (11), ox (12) } となって終了する。
[ { "submission_id": "aoj_0313_10205416", "code_snippet": "// AOJ #313\n// Unknown Germ 2025.2.9\n\n#include <bits/stdc++.h>\nusing namespace std;\n \nstruct Chain {\n int id;\n string s;\n};\n \nbool isSafe(const string &s) {\n int countO = 0, countX = 0;\n for(char c : s) {\n if(c=='o') countO++;\n else if(c=='x') countX++;\n }\n return (countO >= countX);\n}\n \nint findSplitPos(const string &s) {\n int n = s.size();\n int best = -1;\n int bestMax = 1e9;\n for (int p = 0; p < n-1; p++){\n string left = s.substr(0, p+1);\n string right = s.substr(p+1);\n if(isSafe(left) && isSafe(right)){\n if(left.size() <= 2 || right.size() <= 2)\n return p;\n int candidate = max((int)left.size(), (int)right.size());\n if(candidate < bestMax){\n bestMax = candidate;\n best = p;\n }\n }\n }\n return best;\n}\n \nstruct JoinResult {\n bool possible;\n int order;\n string joined;\n};\n \nJoinResult tryJoinChains(const Chain &A, const Chain &B) {\n JoinResult res;\n res.possible = false;\n for (int order = 1; order >= 0; order--){\n string joined;\n if(order==0) joined = A.s + B.s;\n else joined = B.s + A.s;\n if(!isSafe(joined)) continue;\n if(joined.size() <= 2){\n res.possible = true;\n res.order = order;\n res.joined = joined;\n return res;\n }\n int pos = findSplitPos(joined);\n if(pos != -1){\n res.possible = true;\n res.order = order;\n res.joined = joined;\n return res;\n }\n }\n return res;\n}\n \nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n \n int Q;\n cin >> Q;\n for(int qi=0; qi<Q; qi++){\n string init;\n cin >> init;\n \n if(!isSafe(init)){\n cout << -1 << endl;\n continue;\n }\n \n if(init.size() <= 2){\n cout << 0 << endl;\n continue;\n }\n \n vector<string> operations;\n vector<Chain> chains;\n int maxId = 0;\n chains.push_back({0, init});\n \n int opCount = 0;\n const int opLimit = 20000;\n \n bool progress = true;\n while(progress && opCount < opLimit) {\n bool allFinal = true;\n for(auto &ch : chains){\n if(ch.s.size() > 2){\n allFinal = false;\n break;\n }\n }\n if(allFinal) break;\n \n progress = false;\n \n for (int i = 0; i < (int)chains.size(); i++){\n if(chains[i].s.size() > 2){\n int pos = findSplitPos(chains[i].s);\n if(pos != -1){\n int a_id = chains[i].id;\n string s = chains[i].s;\n operations.push_back(\"split \" + to_string(a_id) + \" \" + to_string(pos));\n opCount++;\n string leftStr = s.substr(0, pos+1);\n string rightStr = s.substr(pos+1);\n int newId1 = maxId + 1;\n int newId2 = maxId + 2;\n maxId += 2;\n Chain leftChain = {newId1, leftStr};\n Chain rightChain = {newId2, rightStr};\n \n chains.erase(chains.begin() + i);\n chains.push_back(leftChain);\n chains.push_back(rightChain);\n \n progress = true;\n break;\n }\n }\n }\n if(progress) continue;\n \n if(chains.size() >= 2){\n bool joined = false;\n for (int i = 0; i < (int)chains.size() && !joined; i++){\n for (int j = i+1; j < (int)chains.size() && !joined; j++){\n if(chains[i].s.size() <= 2 && chains[j].s.size() <= 2) continue;\n \n JoinResult jr = tryJoinChains(chains[i], chains[j]);\n if(jr.possible){\n if(jr.order == 0){\n operations.push_back(\"join \" + to_string(chains[i].id) + \" \" + to_string(chains[j].id));\n } else {\n operations.push_back(\"join \" + to_string(chains[j].id) + \" \" + to_string(chains[i].id));\n }\n opCount++;\n \n int newId = maxId + 1;\n maxId += 1;\n Chain newChain = {newId, jr.joined};\n \n if(j > i) {\n chains.erase(chains.begin() + j);\n chains.erase(chains.begin() + i);\n } else {\n chains.erase(chains.begin() + i);\n chains.erase(chains.begin() + j);\n }\n chains.push_back(newChain);\n joined = true;\n progress = true;\n break;\n }\n }\n }\n if(joined) continue;\n }\n \n break;\n }\n \n bool finalState = true;\n for(auto &ch : chains){\n if(ch.s.size() > 2) { finalState = false; break; }\n }\n \n if(!finalState) cout << -1 << endl;\n else {\n cout << operations.size() << endl;\n for(auto &op : operations)\n cout << op << endl;\n }\n }\n return 0;\n}", "accuracy": 0.25, "time_ms": 60, "memory_kb": 5004, "score_of_the_acc": -1, "final_rank": 3 }, { "submission_id": "aoj_0313_2066990", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\ntypedef vector<int>vint;\ntypedef pair<int,int>pint;\ntypedef vector<pint>vpint;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define reps(i,f,n) for(int i=(f);i<(n);i++)\n#define all(v) (v).begin(),(v).end()\n#define each(it,v) for(__typeof((v).begin()) it=(v).begin();it!=(v).end();it++)\n#define pb push_back\n#define fi first\n#define se second\ntemplate<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}\ntemplate<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}\n\n\nint K;\nint itm;\nvector<string>ope;\nvector<int>idx1,idx2;\n\ninline void add(const string &s,int i,int j){\n ope.pb(s);\n idx1.pb(i);\n idx2.pb(j);\n if(s==\"split\")K+=2;\n else K++;\n}\n\nvoid dfs(int k,string s){\n int X=count(all(s),'o')-count(all(s),'x');\n assert(X>=0);\n if(X==s.size()){\n if(itm!=-1)return;\n if(X==1)itm=k;\n else{\n add(\"split\",k,0);\n itm=K-1;\n }\n return;\n }\n if(s.size()<=2)return;\n\n int st=0;\n rep(i,s.size()){\n if(s[i]=='o')st++;else st--;\n if(i&&i+2<s.size()&&0<=st&&st<=X);else continue;\n\n add(\"split\",k,i);\n int x=K-1,y=K;\n if(st){\n dfs(x,s.substr(0,i+1));\n dfs(y,s.substr(i+1,s.size()-i-1));\n }\n else{\n dfs(y,s.substr(i+1,s.size()-i-1));\n dfs(x,s.substr(0,i+1));\n }\n return;\n }\n\n if(s[0]=='x'){\n if(itm!=-1){\n add(\"join\",itm,k);\n itm=-1;\n dfs(K,\"o\"+s);\n }\n else{\n add(\"split\",k,s.size()-2);\n itm=K;\n dfs(K-1,s.substr(0,s.size()-1));\n }\n }\n else{\n if(itm!=-1){\n add(\"join\",k,itm);\n itm=-1;\n dfs(K,s+\"o\");\n }\n else{\n add(\"split\",k,0);\n itm=K-1;\n dfs(K,s.substr(1,s.size()-1));\n }\n }\n}\n\nsigned main(){\n int N;\n cin>>N;\n while(N--){\n K=0;itm=-1;\n string S;\n cin>>S;\n int a=count(all(S),'o');\n int b=S.size()-a;\n bool flag=true;\n for(int i=0;i+1<S.size();i+=2)if(S[i]==S[i+1])flag=false;\n if(a>b||(a==b&&flag)){\n dfs(0,S);\n cout<<ope.size()<<endl;\n rep(i,ope.size())cout<<ope[i]<<\" \"<<idx1[i]<<\" \"<<idx2[i]<<endl;\n }\n else{\n cout<<-1<<endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3164, "score_of_the_acc": -0.8773, "final_rank": 1 }, { "submission_id": "aoj_0313_1663731", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct data{\n int id;\n string str;\n data(int a,string b){id=a;str=b;}\n};\nstruct edge{ int a,b,c; };\n\nqueue<data> A,B,C;\nvector< edge > ans;\nbool flg;\nint cnt;\n\nbool check(string s){\n int ac=0,bc=0;\n for(int i=0;i<(int)s.size();i++){\n if(s[i]=='o')ac++;\n else bc++;\n }\n return (ac>=bc);\n}\n\nvoid func(data d){\n int len=d.str.size();\n if(len==1)A.push(d);\n else B.push(d);\n}\n\nvoid solve(){\n int key=0;\n while(!C.empty()){\n \n if( key++ > 50000){ flg=true; return; }\n \n data d=C.front();C.pop();\n string s=d.str;\n int i;\n if(!check(s)){ flg=true; return; }\n \n if(d.str.size()<=2){ func(d); continue; }\n\n int O1=0,X1=0,O2=0,X2=0;;\n for(int i=0;i<(int)s.size();i++){\n if(s[i]=='o')O2++;\n else if(s[i]=='x')X2++;\n }\n \n for(i=0;i+1<(int)s.size();i++){\n if(s[i]=='o')O2--,O1++;\n else X2--,X1++;\n \n \n if(O2>=X2&&O1>=X1){\n ans.push_back( (edge){0,d.id,i} );\n string a=s.substr(0,i+1);\n string b=s.substr(i+1);\n data na=data(cnt++,a);\n data nb=data(cnt++,b); \n C.push(na);\n C.push(nb);\n break;\n }\n }\n if(i+1<(int)s.size())continue;\n if(A.empty()){ C.push(d); continue; }\n data f=A.front();A.pop();\n if( d.str[0]=='x'){\n ans.push_back( (edge){ 1 , f.id , d.id } );\n cnt++;\n ans.push_back( (edge){ 0 , cnt , 1 } );\n B.push( (data){ cnt++, \"ox\" } );\n C.push( (data){ cnt++, s.substr(2)} );\n }else{\n ans.push_back( (edge){ 1 , d.id , f.id } );\n cnt++;\n ans.push_back( (edge){ 0 , cnt , (int)s.size()-2 } );\n B.push( (data){ cnt++, \"xo\" } );\n C.push( (data){ cnt++, s.substr(0, (int)s.size()-2 )} );\n }\n }\n if(!C.empty())flg=true;\n}\n\nint main(){\n int Tc;\n cin>>Tc;\n while(Tc--){\n cnt=1;\n while(!A.empty())A.pop();\n while(!B.empty())B.pop();\n while(!C.empty())C.pop();\n ans.clear();\n string st;\n cin>>st;\n if(st.size()==1){\n if(st==\"o\")cout<<0<<endl;\n else cout<<-1<<endl;\n continue;\n }else if(st.size()==2){\n if(st==\"xx\")cout<<-1<<endl;\n else cout<<0<<endl;\n continue;\n }\n \n C.push( data(0,st) );\n flg=false;\n solve();\n \n if(flg){\n cout<<-1<<endl;\n }else{\n cout<<ans.size()<<endl;\n for(int i=0;i<(int)ans.size();i++){\n edge e=ans[i];\n if(e.a==0)printf(\"split \");\n else printf(\"join \");\n printf(\"%d %d\\n\",e.b,e.c);\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 1280, "score_of_the_acc": -1, "final_rank": 2 } ]
aoj_0306_cpp
対称3進数 1 グラム、3 グラム、9 グラム、27 グラムのおもりが1つずつあれば、天びんを使って 1 グラムから 40グラムまで 1 グラム刻みで量れることが知られています。たとえば、天びんの一方の皿に重さを量りたいものと 3 グラムのおもりを載せ、もう一方の皿に 27 グラムと 1 グラムのおもりを載せて釣り合えば、量りたいものの重さは 27-3+1=25 グラムだとわかります。 さらに、1(=3 0 )グラム、3 1 グラム、... 、3 n-1 グラム、3 n グラムまでのおもりが1つずつあれば、天びんを使って(3 n+1 -1)/2グラムまで量れることが知られています。また、天びんが釣り合うようなおもりの置き方は一通りしかないことも知られています。 量りたいものとおもりを天びんに置いて、釣り合うようなおもりの置き方を文字列で表すことができます。3 i グラムのおもりを量りたいものと同じ皿に載せたときは「 - 」、もう一方の皿に載せたときは「 + 」、どちらにも載せなかったときは「0」を文字列の右端からi番目に書きます(右端を0番目と数えます)。たとえば、先ほどの 25 グラムの例は +0-+ と表わせます。 それでは、量りたいものの重さが与えられたとき、天びんが釣り合うようなおもりの置き方を表す文字列を出力するプログラムを作成してください。ただし、3のべき乗グラムのおもりは、どのような重さのものでも必ず1つあるものとします。 (補足: 対称3進数について) 量りたいものの重さがwのとき、おもりの置き方を表す文字列はwの対称3進数になっています。対称3進数とは、3のべき乗の数で位取りを行い、各位に数 1、0、-1 を表す文字を書くことで表した数のことです。上の文字列では、文字「 + 」、「 0 」、「 - 」がそれぞれ数 1、0、-1 に対応します。たとえば、25 グラムのものを量るときのおもりの置き方が +0-+ である対称3進数が表す数は、1 × 3 3 + 0 × 3 2 - 1× 3 1 + 1 × 3 0 = 25 となります。 入力 入力は以下の形式で与えられる。 w w (1 ≤ w ≤ 100000) は量りたいものの重さを表す整数である。 出力 おもりの置き方を表す文字列を出力する。ただし文字列の左端を 0 にしてはならない。 入出力例 入力例1 25 出力例1 +0-+ 入力例2 2 出力例2 +- 入力例3 5 出力例3 +--
[ { "submission_id": "aoj_0306_8406601", "code_snippet": "#include <algorithm>\n#include <array>\n#include <iostream>\n#include <stack>\n#include <string>\n#include <vector>\n\n\nnamespace {\n const std::array<int, 12> digits{\n 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147 };\n std::vector<std::string> opt(100001);\n}\n\n\nint main()\n{\n std::stack<std::pair<std::string, int>> queue;\n queue.emplace(\"\", 0);\n while (!queue.empty()) {\n const auto e = std::move(queue.top());\n queue.pop();\n if ((e.first.empty() || e.first[0] != '0') && 0 <= e.second && e.second < opt.size()) {\n opt[e.second] = e.first;\n }\n if (e.first.length() < digits.size()) {\n queue.emplace(std::move(\"+\" + e.first), e.second + digits[e.first.length()]);\n queue.emplace(std::move(\"-\" + e.first), e.second - digits[e.first.length()]);\n queue.emplace(std::move(\"0\" + e.first), e.second);\n }\n }\n \n int w;\n std::cin >> w;\n std::cout << opt[w] << std::endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6144, "score_of_the_acc": -0.0368, "final_rank": 5 }, { "submission_id": "aoj_0306_6894120", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int d = 1;\n vector<int> b;\n while(b.size() < 14){\n b.push_back(d);\n d *= 3;\n }\n int w;\n cin >> w;\n function<bool(int,int,string)> dfs = [&](int i, int v, string s){\n if(v == w){\n reverse(s.begin(), s.end());\n cout << s << '\\n';\n return true;\n }\n if(i == b.size())return false;\n if(dfs(i + 1, v - b[i], s + '-'))return true;\n if(dfs(i + 1, v, s + '0'))return true;\n if(dfs(i + 1, v + b[i], s + '+'))return true;\n return false;\n };\n dfs(0, 0, \"\");\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3440, "score_of_the_acc": -0.1509, "final_rank": 10 }, { "submission_id": "aoj_0306_6045659", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint w,ff;\nvector<int> v;\nvoid f(int);\nint pw(int x)\n{\n\tif(x==0) return 1;\n\telse {\n\t\tint sm=1;\n\t\tfor(int i=0;i<x;i++) sm*=3;\n\t\treturn sm;\n\t}\n}\nint main()\n{\n\tscanf(\"%d\",&w);\n\tf(0);\n\treturn 0;\n}\nvoid f(int nn)\n{\n\tint sm=0,sm2=w;\n\t//printf(\"nn=%d\\n\",nn);\n\tif(nn<15){\n\t\tfor(int i=0;i<v.size();i++){\n\t\t\tif(v[i]==1) sm+=pw(i);\n\t\t\telse if(v[i]==2)sm2+=pw(i);\n\t\t}\n\t\tif(sm==sm2){\n\t\t\tff=1;\n\t\t\tfor(int i=v.size()-1;i>=0;i--){\n\t\t\t\tif(v[i]==1) printf(\"+\");//you\n\t\t\t\telse if(v[i]==2) printf(\"-\");//me\n\t\t\t\telse printf(\"0\");//not me&you\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\telse if(ff==0){\n\t\t\tfor(int i=0;i<3;i++){\n\t\t\t\tv.push_back(i);\n\t\t\t\tf(nn+1);\n\t\t\t\tv.pop_back();\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 3212, "score_of_the_acc": -0.8151, "final_rank": 17 }, { "submission_id": "aoj_0306_5007587", "code_snippet": "#include<iostream>\nusing namespace std;\nint w;\nint p3[12];\nmain()\n{\n\tcin>>w;\n\tp3[0]=1;\n\tfor(int i=1;i<12;i++)p3[i]=p3[i-1]*3;\n\tfor(int i=0;i<1<<12;i++)\n\t{\n\t\tfor(int j=i;;j=j-1&i)\n\t\t{\n\t\t\tint now=0;\n\t\t\tfor(int k=0;k<12;k++)\n\t\t\t{\n\t\t\t\tif(j>>k&1)now-=p3[k];\n\t\t\t\telse if(i>>k&1)now+=p3[k];\n\t\t\t}\n\t\t\tif(now==w)\n\t\t\t{\n\t\t\t\tstring ans=\"\";\n\t\t\t\tfor(int k=12;k--;)\n\t\t\t\t{\n\t\t\t\t\tif(j>>k&1)ans+='-';\n\t\t\t\t\telse if(i>>k&1)ans+='+';\n\t\t\t\t\telse if(!ans.empty())ans+='0';\n\t\t\t\t}\n\t\t\t\tcout<<ans<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif(j==0)break;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3200, "score_of_the_acc": -0.0055, "final_rank": 1 }, { "submission_id": "aoj_0306_4828254", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n/*\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\") \n#include <boost/multiprecision/cpp_dec_float.hpp>\n#include <boost/multiprecision/cpp_int.hpp>\nnamespace mp = boost::multiprecision;\nusing Bint = mp::cpp_int;\nusing Real = mp::number<mp::cpp_dec_float<1024>>;\n*/\n#define ll long long\n#define INF 999999999999\n#define rep(i,m,n) for(ll i = m;i < n;i++)\n#define rrep(i,m,n) for(ll i=m-1;i>=n;i--)\n#define pb(n) push_back(n)\n#define UE(N) N.erase(unique(N.begin(),N.end()),N.end());\n#define Sort(n) sort(n.begin(), n.end())\n#define Rev(n) reverse(n.begin(),n.end())\n#define Out(S) cout << S << endl\n#define NeOut(S) cout << S\n#define HpOut(S) cout << setprecision(50) << S << endl\n#define Vec(K,L,N,S) vector<L> K(N,S)\n#define DV(K,L,N,M,S) vector<vector<L>> K(N,vector<L>(M,S))\n#define TV(K,L,N,M,R,S) vector<vector<vector<L>>> K(N,vector<vector<L>>(M,vector<L>(R,S)))\n#define pint pair<lli,lli>\n#define paf(L,R) pair<L,R>\n#define mod 1000000007\n#define MAX 10000000\n#define ALL(a) a.begin(),a.end()\n#define chmax(a, b) a = (((a)<(b)) ? (b) : (a))\n#define chmin(a, b) a = (((a)>(b)) ? (b) : (a))\n\nstring ans;\n\nvoid dfs(ll res, string S) {\n if(!res) ans = S;\n else if(S.size() < 12) {\n dfs(res - pow(3, S.size()), S + \"+\");\n dfs(res + pow(3, S.size()), S + \"-\");\n dfs(res, S + \"0\");\n }\n}\n\nint main() {\n \tios::sync_with_stdio(false);\n \tcin.tie(0);\n\tll N;\n cin >> N;\n dfs(N, \"\");\n Rev(ans);\n cout << ans << endl; \n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3828, "score_of_the_acc": -0.036, "final_rank": 4 }, { "submission_id": "aoj_0306_3978452", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <cmath>\n\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n int w;\n cin >> w;\n for (int i = 0; i < pow(3, 15); i++) {\n ll x = i;\n ll now = 0;\n ll t = 1;\n for (int j = 0; j < 15; j++) {\n if (x % 3 == 0)now += t;\n else if (x % 3 == 1) now -= t;\n x /= 3;\n t *= 3;\n }\n\n if (now == w) {\n string ret;\n x = i;\n t = 1;\n for (int j = 0; j < 15; j++) {\n if (x % 3 == 0)ret = '+' + ret;\n else if (x % 3 == 1)ret = '-' + ret;\n else ret = '0' + ret;\n x /= 3;\n t *= 3;\n }\n\n bool notzero = false;\n for (int j = 0; j < 15; j++) {\n if (ret[j] != '0')notzero = true;\n if (notzero)cout << ret[j];\n }\n cout << endl;\n break;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3212, "score_of_the_acc": -1.0056, "final_rank": 18 }, { "submission_id": "aoj_0306_3896036", "code_snippet": "#include <iostream>\nusing namespace std;\nusing llong = long long;\n\nllong w;\nllong pt[15];\nchar ans[15];\n\nbool dfs(int i, llong d) {\n\tif (i == 15 && d == w) return true;\n\telse if (i == 15) return false;\n\t\n\tbool f = false;\n\t\n\tif (dfs(i + 1, d + pt[i])) ans[i] = '+', f = true;\n\t\n\tif (dfs(i + 1, d)) ans[i] = '0', f = true;\n\t\n\tif (dfs(i + 1, d - pt[i])) ans[i] = '-', f = true;\n\t\n\treturn f;\n}\n\nint main() {\n\tcin >> w;\n\t\n\tpt[0] = 1;\n\tfor (int i = 1; i < 15; i++) {\n\t\tpt[i] = pt[i - 1] * 3;\n\t}\n\t\n\tdfs(0, 0);\n\t\n\tbool f = false;\n\tfor (int i = 14; i >= 0; i--) {\n\t\tif (ans[i] != '0') f = true;\n\t\t\n\t\tif (f) cout << ans[i];\n\t}\n\tcout << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3108, "score_of_the_acc": -0.0759, "final_rank": 8 }, { "submission_id": "aoj_0306_3633092", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\n#define chmin(a, b) ((a) = min((a), (b)))\n#define chmax(a, b) ((a) = max((a), (b)))\n#define fs first\n#define sc second\n#define eb emplace_back\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef tuple<int, int, int> T;\n\nconst ll MOD = 1e9 + 7;\nconst ll INF = 1e18;\nconst double pi = acos(-1);\nconst double eps = 1e-10;\n\nint dx[] = {1, 0, -1, 0};\nint dy[] = {0, -1, 0, 1};\n\nvector<int> v;\n\nvoid dfs(int l, int r, int depth, string s){\n\n if(depth == v.size()){\n if(l == r){\n cout << s << endl;\n }\n return ;\n }\n\n dfs(l + v[depth], r, depth + 1, s + \"+\");\n\n dfs(l, r, depth + 1, s + \"0\");\n\n dfs(l, r + v[depth], depth + 1, s + \"-\");\n\n return ;\n}\n\n\nint main(){\n int w; cin>>w;\n int num = 1;\n int sum = 0;\n while(sum < w){\n v.emplace_back(num);\n sum += num;\n num *= 3;\n }\n\n sort(v.begin(), v.end(), greater<int>());\n\n dfs(0, w, 0, \"\");\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3200, "score_of_the_acc": -0.0531, "final_rank": 7 }, { "submission_id": "aoj_0306_3632265", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <cstring>\n#include <climits>\n#include <vector>\n#include <map>\n#include <set>\n#include <list>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <iostream>\n#include <string>\n\n#define REP(i,n) for(long long i=0;i<n;++i)\n#define REPR(i,n) for(long long i=n;i>=0;--i)\n#define REPI(itr,v) for(auto itr=v.begin();itr!=v.end();++itr)\n#define REPIR(itr,v) for(auto itr=v.rbegin();itr!=v.rend();++itr)\n#define FOR(i,a,b) for(long long i=a;i<b;++i)\n#define SORT(v,n) sort(v, v+n)\n#define SORTV(v) sort(v.begin(), v.end())\n#define ALL(v) v.begin(),v.end()\n#define llong long long\n#define INF 999999999\n#define MOD 1000000007\n#define pb push_back\n#define pf push_front\n#define MP make_pair\n#define SV(v) {for(long long sitr=0;sitr<v.size();++sitr){cin>>v[sitr];}}\n\nint dx[] = {0, 0, -1, 1};\nint dy[] = {1, -1, 0, 0};\n\nusing namespace std;\n\ntypedef pair<int,int> pii;\n\nint MAX = 1;\nint w;\n\nvoid solve(string s, int level, int sum){\n \n if(sum == 0){\n int len = s.length();\n for(int i = len - 1; i >= 0; --i){\n cout << s[i];\n }\n cout << endl;\n return;\n }\n if(level == MAX + 1) return;\n\n //減らす\n solve(s + \"+\", level + 1, sum - pow(3,level));\n //そのまま\n solve(s + \"0\", level + 1, sum);\n //増やす\n solve(s + \"-\", level + 1, sum + pow(3, level));\n\n}\n\nint main(){\n\n cin >> w;\n\n int sum = 3;\n while(true){\n if(sum >= 2 * w + 1) break;\n MAX++;\n sum *= 3;\n }\n\n solve(\"\", 0, w);\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3352, "score_of_the_acc": -0.3643, "final_rank": 13 }, { "submission_id": "aoj_0306_3496144", "code_snippet": "#include<iostream>\n#include<string>\n#include<cmath>\nusing namespace std;\n\nstring res;\n\nvoid solve( string s, int cnt, int ans )\n{\n if( cnt == 0 )\n {\n int sum = 0;\n for( int i = 0; i < s.size(); i++ )\n {\n if( s[i] == '+' )\n sum += (int)pow( 3.0, (double)i );\n else if( s[i] == '-' )\n sum -= (int)pow( 3.0, (double)i );\n }\n if( sum == ans )\n res = s;\n return;\n }\n\n solve( s + '+', cnt - 1, ans );\n solve( s + '-', cnt - 1, ans );\n solve( s + '0', cnt - 1, ans );\n}\n\nint main()\n{ \n int n;\n\n cin >> n;\n\n int a = 1, cnt = 1;\n while( a < n )\n {\n a *= 3;\n cnt++;\n }\n\n string s = \"\";\n solve( s, cnt, n );\n\n string rev = \"\";\n int i = res.size() - 1;\n while( res[i] == '0' )\n i--;\n\n for( int j = i; j >= 0; j-- )\n rev += res[j];\n\n cout << rev << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3364, "score_of_the_acc": -0.4596, "final_rank": 15 }, { "submission_id": "aoj_0306_3326638", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n\nint w;\n\nvoid dfs(int d, int acc, string s){\n if(acc == w){\n reverse(s.begin(), s.end());\n cout << s << endl;\n exit(0);\n }\n \n if(d >= 12) return;\n\n int t = 1;\n for(int i = 0; i < d; i++) t *= 3;\n\n dfs(d+1, acc+t, s+\"+\");\n dfs(d+1, acc, s+\"0\");\n dfs(d+1, acc-t, s+\"-\");\n}\n\nint main(){\n cin >> w;\n dfs(0, 0, \"\");\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3204, "score_of_the_acc": -0.0293, "final_rank": 3 }, { "submission_id": "aoj_0306_3233057", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> V;\ntypedef pair<ll,ll> P;\ntypedef map<ll,ll> M;\n\n#define REP(i, n) for(ll (i) = 0; (i) < (n); ++(i))\n#define FOR(i, j, n) for(ll (i) = (j); (i) < (n); ++(i))\n#define REPR(i, n) for(ll (i) = (n); (i) >= 0; --(i))\n\nsigned main(){\n int w;\n cin >> w;\n V three(1, 1);\n ll assm = 1;\n while(assm < w){\n three.push_back(three.back() * 3);\n assm += three.back();\n }\n\n int n = three.size();\n three.push_back(three.back() * 3);\n\n REP(i, three.back()){\n ll ans = 0;\n V vec(n);\n REP(j, n){\n vec[j] = (i % three[j + 1]) / three[j];\n if(vec[j] == 1)ans += three[j];\n if(vec[j] == 2)ans -= three[j];\n }\n if(ans == w){\n REPR(j,n-1){\n if(vec[j] == 1)cout << \"+\";\n else if(vec[j] == 2)cout << \"-\";\n else cout<< \"0\";\n }\n cout << endl;\n return 0;\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3168, "score_of_the_acc": -0.1956, "final_rank": 12 }, { "submission_id": "aoj_0306_3155748", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef struct{\n int num;\n int i;\n string ans;\n} Data;\n\nint main(){\n int n;\n cin >> n;\n queue<Data> que;\n\n Data d;\n d.num = n;\n d.i = 0;\n d.ans = \"\";\n\n que.push(d);\n\n Data tmp;\n\n while(1){\n d = que.front();\n que.pop();\n if(d.num == 0){\n cout << d.ans << endl;\n return 0;\n }\n d.i++;\n\n tmp = d;\n tmp.num += pow((double)3,(double)d.i-1);\n tmp.ans = \"-\" + tmp.ans;\n que.push(tmp);\n\n tmp = d;\n tmp.num -= pow((double)3,(double)d.i-1);\n tmp.ans = \"+\" + tmp.ans;\n que.push(tmp);\n\n tmp = d;\n tmp.ans = \"0\" + tmp.ans;\n que.push(tmp);\n }\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 96592, "score_of_the_acc": -1.5952, "final_rank": 19 }, { "submission_id": "aoj_0306_3082530", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nint POW[13];\nint table[12],answer[12],W;\n\nchar func(int x){\n\tif(x == 1)return '+';\n\telse if(x == -1)return '-';\n\telse return '0';\n}\n\nvoid calc(int index){\n\n\tif(index == 12){\n\t\tint sum = 0;\n\t\tfor(int i=0; i < 12; i++){\n\t\t\tif(table[i] == 1)sum += POW[i];\n\t\t\telse if(table[i] == -1){\n\t\t\t\tsum -= POW[i];\n\t\t\t}\n\t\t}\n\t\tif(sum == W){\n\t\t\tfor(int i=0; i < 12; i++)answer[i] = table[i];\n\t\t}\n\t\treturn;\n\t}\n\n\ttable[index] = 0;\n\tcalc(index+1);\n\ttable[index] = 1;\n\tcalc(index+1);\n\ttable[index] = -1;\n\tcalc(index+1);\n}\n\nint main(){\n\n\tfor(int i = 0; i < 13; i++){\n\t\tPOW[i] = pow(3,i);\n\t}\n\n\tfor(int i = 0; i < 12; i++){\n\t\ttable[i] = 0;\n\t}\n\n\tscanf(\"%d\",&W);\n\n\tcalc(0);\n\n\tfor(int i = 11; i >= 0; i--){\n\t\tif(answer[i] != 0){\n\t\t\tfor(int k=i; k >= 0; k--){\n\t\t\t\tprintf(\"%c\",func(answer[k]));\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t\tbreak;\n\t\t}\n\t}\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3248, "score_of_the_acc": -0.006, "final_rank": 2 }, { "submission_id": "aoj_0306_2547125", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n// 3^ 14\n// 3 no 13\n\nstring ans;\n\nvoid solve(int cnt, int dig, int w, string s) {\n\n if(w == 0) {\n ans = s;\n }\n\n if(cnt >= 12) {\n return;\n }\n\n solve(cnt + 1, dig * 3, w, s + \"0\");\n solve(cnt + 1, dig * 3, w - dig, s + \"+\");\n solve(cnt + 1, dig * 3, w + dig, s + \"-\");\n\n return;\n}\n\nint main() {\n\n int w;\n int enable_p;\n\n cin >> w;\n\n solve(0, 1, w, \"\");\n\n reverse(ans.begin(), ans.end());\n\n enable_p = 0;\n for(int i = 0; i < ans.size(); ++i) {\n if(ans[i] == '0') {\n ++enable_p;\n } else {\n break;\n }\n }\n\n for(int i = enable_p; i < ans.size(); ++i) {\n cout << ans[i];\n }\n cout << endl;\n\n //cout << ans << endl;\n\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3196, "score_of_the_acc": -0.0769, "final_rank": 9 }, { "submission_id": "aoj_0306_2520733", "code_snippet": "#include<stdio.h>\n#include<string.h>\n#include<math.h>\nvoid fanc(int,int,int);\nint a,s[15],d[15],f,g,h;\nint main(void)\n{\n\tint flg,i,j;\n\tf=0;\n\tscanf(\"%d\",&a);\n\tflg=0;\n\tfanc(0,0,1);\n\tfor(i=14;i>=0;i--){\n\t\tif(s[i]==-1){\n\t\t\tprintf(\"-\");\n\t\t\tflg=1;\n\t\t}\n\t\telse if(s[i]==1){\n\t\t\tprintf(\"+\");\n\t\t\tflg=1;\n\t\t}\n\t\telse{\n\t\t\tif(flg==1) printf(\"0\");\n\t\t}\n\t}\n\tprintf(\"\\n\");\n\treturn 0;\n}\nvoid fanc(int z,int x,int c)\n{\n\tint i,j;\n\tif(z<15){\n\t\tif(x==a){\n\t\t\tfor(i=0;i<z;i++) s[i]=d[i];\n\t\t\tf=1;\n\t\t}\n\t\tif(f==0){\n\t\t\tfor(i=-1;i<=1;i++){\n\t\t\t\td[z]=i;\n\t\t\t\tfanc(z+1,x+i*c,c*3);\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 2684, "score_of_the_acc": -0.0476, "final_rank": 6 }, { "submission_id": "aoj_0306_2456478", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for(ll i=0;i<(ll)(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define pb emplace_back\n#define INF (1e9+1)\n\nconst ll MOD = INF;\n\nll power(ll a,ll b){\n ll ret=1;\n if(b>0){\n ret = power(a,b/2);\n if(b%2==0)ret = (ret*ret)%MOD;\n else ret = (((ret*ret)%MOD)*a)%MOD;\n }\n return ret;\n}\n\n\nint main(){\n int w;\n cin>>w;\n \n int ans = -1;\n for(int i=0;i<power(3,11);i++){\n int l = 0, r = w;\n int num = i;\n rep(j,11){\n if(num%3==1){\n l+=power(3,j);\n }else if(num%3==2){\n r+=power(3,j);\n }\n num/=3;;\n }\n if(l==r){\n ans = i;\n break;\n }\n }\n \n string s = \"\";\n rep(i,11){\n if(ans%3==0)s+='0';\n if(ans%3==1)s+='+';\n if(ans%3==2)s+='-';\n ans/=3;\n }\n int pos = 0;\n rep(i,s.size())if(s[i]!='0')pos = i+1;\n s = s.substr(0,pos);\n reverse(all(s));\n cout<<s<<endl;\n \n}", "accuracy": 0.6666666666666666, "time_ms": 20, "memory_kb": 3172, "score_of_the_acc": -0.029, "final_rank": 20 }, { "submission_id": "aoj_0306_2405203", "code_snippet": "#include <vector>\n#include <iostream>\n#include <utility>\n#include <algorithm>\n#include <string>\n#include <deque>\n#include <queue>\n#include <tuple>\n#include <queue>\n#include <functional>\n#include <cmath>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <numeric>\n#include <unordered_map>\n#include <unordered_set>\n#include <complex>\n#include <iterator>\n#include <array>\n#include <memory>\n#include <stack>\n#define vi vector<int>\n#define vvi vector<vector<int> >\n#define ll long long int\n#define vl vector<ll>\n#define vvl vector<vector<ll>>\n#define vb vector<bool>\n#define vc vector<char>\n#define vs vector<string>\n#define ld long double\n#define INF 1e9\n#define EPS 0.0000000001\n#define rep(i,n) for(int i=0;i<n;i++)\n#define loop(i,s,n) for(int i=s;i<n;i++)\n#define all(in) in.begin(), in.end()\ntemplate<class T, class S> void cmin(T &a, const S &b) { if (a > b)a = b; }\ntemplate<class T, class S> void cmax(T &a, const S &b) { if (a < b)a = b; }\n#define MAX 9999999\nusing namespace std;\ntypedef pair<int, int> pii;\ntypedef pair<double,double>pdd;\n#define int ll\n\nint dif=INF;\nvi v(13,0);\nvi sum(13,0);\nint _find;\nvoid dfs(int value,int index,string ans){\n if(index>_find+1)return;\n //cout<<value<<endl;\n if(value==dif){reverse(all(ans));cout<<ans<<endl;return;}\n dfs(value,index+1,ans+\"0\");\n dfs(value-v[index],index+1,ans+\"-\");\n dfs(value+v[index],index+1,ans+\"+\");\n return;\n}\nsigned main(){\n int w; cin>>w;\n rep(i,13)v[i]=sum[i]=(int)pow(3,i);\n rep(i,12)sum[i+1]+=sum[i];\n rep(i,13)if(w<sum[i]){_find=i;break;}\n //cout<<_find<<endl;\n dif=w;\n int value=0;int index=1;\n string s;\n dfs(value,index,s+\"0\");\n dfs(value-1,index,s+\"-\");\n dfs(value+1,index,s+\"+\");\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3384, "score_of_the_acc": -0.1741, "final_rank": 11 }, { "submission_id": "aoj_0306_2068671", "code_snippet": "#include <stdio.h>\n#include <stack>\n#include <math.h>\n\nusing namespace std;\n\nint answer[12],w;\n\nchar func(int x){\n\tif(x == 1)return '+';\n\telse if(x == -1)return '-';\n\telse return '0';\n}\n\nvoid calc(int array[12],int index){\n\n\tif(index == 12){\n\t\tint sum = 0;\n\t\tfor(int i=0; i < 12; i++){\n\t\t\tif(array[i] == 1)sum += pow(3,i);\n\t\t\telse if(array[i] == -1){\n\t\t\t\tsum -= pow(3,i);\n\t\t\t}\n\t\t}\n\t\tif(sum == w){\n\t\t\tfor(int i=0; i < 12; i++)answer[i] = array[i];\n\t\t}\n\t\treturn;\n\t}\n\n\tint new_array[3][12];\n\tfor(int i = 0; i < 3; i++){\n\t\tfor(int k=0; k < 12; k++)new_array[i][k] = array[k];\n\t}\n\n\tnew_array[0][index] = 0;\n\tcalc(new_array[0],index+1);\n\tnew_array[1][index] = 1;\n\tcalc(new_array[1],index+1);\n\tnew_array[2][index] = -1;\n\tcalc(new_array[2],index+1);\n\n}\n\nint main(){\n\n\tint array[12] = {0};\n\n\tscanf(\"%d\",&w);\n\n\tcalc(array,0);\n\n\tfor(int i = 11; i >= 0; i--){\n\t\tif(answer[i] != 0){\n\t\t\tfor(int k=i; k >= 0; k--){\n\t\t\t\tprintf(\"%c\",func(answer[k]));\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t\tbreak;\n\t\t}\n\t}\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 2872, "score_of_the_acc": -0.4068, "final_rank": 14 }, { "submission_id": "aoj_0306_2065697", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <queue>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n\nstruct Data {\n\tstring str;\n\tint w;\n\tData() {}\n\tData(string str, int w) : str(str), w(w) {}\n};\n\nbool done[30][600000];\n\nint main() {\n\tint W;\n\tcin >> W;\n\t\n\tvector<int> table;\n\tint tmp = 1;\n\ttable.push_back(tmp);\n\twhile (tmp <= W) {\n\t\ttmp *= 3;\n\t\ttable.push_back(tmp);\n\t}\n\t\n\tqueue<Data> que;\n\tque.push(Data(\"\", 0));\n\t\n\twhile (!que.empty()) {\n\t\tData now = que.front(); que.pop();\n\t\t\n\t\tstring str = now.str;\n\t\tint w = now.w;\n\t\tint len = str.size();\n\t\t\n\t\tif (w == W) {\n\t\t\treverse(str.begin(), str.end());\n\t\t\tcout << str << endl;\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tif (w + 300000 >= 600000 || w + 300000 < 0) continue;\n\t\tif (done[len][w + 300000]) continue;\n\t\tdone[len][w + 300000] = true;\n\t\t\n\t\tif (len >= table.size()) continue;\n\t\tque.push(Data(str + \"+\", w + table[len]));\n\t\tque.push(Data(str + \"-\", w - table[len]));\n\t\tque.push(Data(str + \"0\", w));\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 37604, "score_of_the_acc": -0.4909, "final_rank": 16 } ]
aoj_0310_cpp
枠 画像の中から有益な情報を抽出する画像認識はコンピュータサイエンスの中でも重要な研究テーマのひとつです。デジタルカメラ、運転支援システム、防犯システムなどに幅広く応用されています。 このような研究のおかげで、私たちは画像解析を行うための多くのソフトウェアやプログラム集を使い様々な処理を行うことができます。一方、自力でプログラムを書いて解析することで、その仕組みを知り、楽しい時間を過ごすことができます。ここでは、一風変わった画像認識をしてみましょう。 画像として次のような各ピクセルが整数の値を持つ N × N のピクセルが入力として与えられます。この画像の中から、線の太さが1ピクセルの長方形の枠(わく)を1つ抽出します。 枠が覆うピクセルの値の和が最大となるような枠を抽出して、その和を報告するプログラムを作成して 下さい。ただし、下の図のように、縦、横のピクセル数が1つや2つの場合も枠とみなすものとします。 入力 入力は以下の形式で与えられる。 N p 1,1 p 1,2 ... p 1,N p 2,1 p 2,2 ... p 2,N : p N,1 p N,2 ... p N,N 1行目に縦と横のピクセル数 N (1 ≤ N ≤ 300) が与えられる。続く N 行に、 i 行 j 列目のピクセルの値を表す整数 p i,j (-1000 ≤ p i,j ≤ 1000)が与えられる。 出力 ピクセル値の和が最大となるような枠の、ピクセル値の和を1行に出力する。 入出力例 入力例1 5 2 0 0 2 0 0 1 0 2 0 0 0 0 -1 0 0 4 0 3 0 -1 0 0 1 0 出力例1 12 入力例2 3 0 0 0 0 -1 0 0 0 0 出力例2 0
[ { "submission_id": "aoj_0310_11026928", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector P(N, vector<ll>(N + 1));\n\trep(i, 0, N) rep(j, 1, N + 1) cin >> P[i][j];\n\trep(i, 0, N) rep(j, 1, N + 1) P[i][j] += P[i][j - 1];\n\t\n\tif (N == 1) {\n\t\tcout << P[0][1] << '\\n';\n\t\treturn 0;\n\t}\n\t\n\tll ans = -(1ll << 60);\n\trep(l, 1, N + 1) rep(r, l, N + 1) {\n\t\tll val = -(1ll << 60);\n\t\t\n\t\trep(i, 0, N) {\n\t\t\tif (i >= 2) {\n\t\t\t\tif (l == r) val += P[i - 1][r] - P[i - 1][l - 1];\n\t\t\t\telse val += P[i - 1][r] - P[i - 1][r - 1] + P[i - 1][l] - P[i - 1][l - 1];\n\t\t\t}\n\t\t\tif (i >= 1)\tval = max(val, P[i - 1][r] - P[i - 1][l - 1]);\n\t\t\tans = max(ans, val + P[i][r] - P[i][l - 1]);\n\t\t}\n\t}\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3860, "score_of_the_acc": -0.0282, "final_rank": 3 }, { "submission_id": "aoj_0310_10853945", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nint n, a[309][309], sa[309][309], s[309], t[309], st[309], r[309];\nint main() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tcin >> a[i][j];\n\t\t\tsa[i][j + 1] = sa[i][j] + a[i][j];\n\t\t}\n\t}\n\tint ret = -inf;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tfor (int k = 0; k < n; k++) {\n\t\t\t\ts[k] = sa[k][j] - sa[k][i];\n\t\t\t\tt[k] = (j - i >= 2 ? a[k][i] + a[k][j - 1] : a[k][i]);\n\t\t\t\tst[k + 1] = st[k] + t[k];\n\t\t\t\tr[k] = st[k] + s[k];\n\t\t\t}\n\t\t\tint p = -inf;\n\t\t\tfor (int k = 0; k < n; k++) {\n\t\t\t\tret = max(ret, r[k] + p);\n\t\t\t\tret = max(ret, s[k]);\n\t\t\t\tp = max(p, s[k] - st[k + 1]);\n\t\t\t}\n\t\t}\n\t}\n\tcout << ret << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4084, "score_of_the_acc": -0.0802, "final_rank": 9 }, { "submission_id": "aoj_0310_8527856", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0310.cc: 枠\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 300;\nconst int INF = 1 << 30;\n\n/* typedef */\n\n/* global variables */\n\nint ps[MAX_N][MAX_N];\nint hss[MAX_N + 1][MAX_N + 1], vss[MAX_N + 1][MAX_N + 1];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++)\n for (int j = 0; j < n; j++) scanf(\"%d\", ps[i] + j);\n\n for (int i = 0; i < n; i++)\n for (int j = 0; j < n; j++) hss[i][j + 1] = hss[i][j] + ps[i][j];\n for (int j = 0; j < n; j++)\n for (int i = 0; i < n; i++) vss[i + 1][j] = vss[i][j] + ps[i][j];\n\n int maxs = -INF;\n for (int i0 = 0; i0 < n; i0++) {\n for (int j = 0, mx = 0; j < n; j++) {\n mx = max(mx, -hss[i0][j]);\n maxs = max(maxs, hss[i0][j + 1] + mx);\n }\n\n for (int i1 = i0 + 1; i1 < n; i1++) {\n for (int j = 0; j < n; j++)\n\tmaxs = max(maxs, vss[i1 + 1][j] - vss[i0][j]);\n for (int j = 1, mx = 0; j < n; j++) {\n\tmx = max(mx,\n\t\t vss[i1][j - 1] - vss[i0 + 1][j - 1]\n\t\t - hss[i0][j - 1] - hss[i1][j - 1]);\n\tmaxs = max(maxs,\n\t\t vss[i1][j] - vss[i0 + 1][j]\n\t\t + hss[i0][j + 1] + hss[i1][j + 1] + mx);\n }\n }\n }\n\n printf(\"%d\\n\", maxs);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4020, "score_of_the_acc": -0.0046, "final_rank": 1 }, { "submission_id": "aoj_0310_7981161", "code_snippet": "#include<stdio.h>\n\nlong long max( long long a, long long b )\n{\n return a > b ? a : b;\n}\n\nint main( void )\n{\n int N;\n scanf( \"%d\", &N );\n\n int pixel[301][301], sum[301][301];\n for( int j = 0; j <= N; j++ )\n {\n sum[0][j] = 0;\n }\n long long ans = -1e15;\n for( int i = 0; i < N; i++ )\n {\n for( int j = 0; j < N; j++ )\n {\n scanf( \"%d\", &pixel[i][j] );\n sum[i+1][j] = sum[i][j] + pixel[i][j];\n ans = max( ans, pixel[i][j] );\n }\n }\n\n for( int i = 0; i < N; i++ )\n {\n for( int left = 0; left < N; left++ )\n {\n long long tmp_sum1 = 0, tmp_sum2 = 0;\n for( int right = left; right < N; right++ )\n {\n tmp_sum1 = max( tmp_sum1, 0 ) + pixel[i][right];\n if( i + 1 < N ) tmp_sum2 += pixel[i+1][right];\n ans = max( ans, max( tmp_sum1, tmp_sum1 + tmp_sum2 ) );\n }\n }\n }\n\n for( int j = 0; j < N; j++ )\n {\n for( int up = 0; up < N; up++ )\n {\n long long tmp_sum1 = 0, tmp_sum2 = 0;\n for( int down = up; down < N; down++ )\n {\n tmp_sum1 = max( tmp_sum1, 0 ) + pixel[down][j];\n if( j + 1 < N ) tmp_sum2 += pixel[down][j+1];\n ans = max( ans, max( tmp_sum1, tmp_sum1 + tmp_sum2 ) );\n }\n }\n }\n\n for( int up = 0; up < N; up++ )\n {\n for( int down = up + 2; down < N; down++ )\n {\n long long tmp = sum[down+1][N-1] - sum[up][N-1];\n for( int left = N - 3; left >= 0; left-- )\n {\n tmp = max( tmp, sum[down+1][left+2] - sum[up][left+2] );\n tmp += pixel[up][left+1] + pixel[down][left+1];\n ans = max( ans, tmp + ( sum[down+1][left] - sum[up][left] ) );\n }\n }\n }\n\n printf( \"%lld\\n\", ans );\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3676, "score_of_the_acc": -0.0515, "final_rank": 7 }, { "submission_id": "aoj_0310_7981145", "code_snippet": "#include<stdio.h>\n\nlong long max( long long a, long long b )\n{\n return a > b ? a : b;\n}\n\nint main( void )\n{\n int N;\n scanf( \"%d\", &N );\n\n int pixel[301][301], sum[301][301];\n for( int j = 0; j <= N; j++ )\n {\n sum[0][j] = 0;\n }\n long long ans = -1e15;\n for( int i = 0; i < N; i++ )\n {\n for( int j = 0; j < N; j++ )\n {\n scanf( \"%d\", &pixel[i][j] );\n sum[i+1][j] = sum[i][j] + pixel[i][j];\n ans = max( ans, pixel[i][j] );\n }\n }\n\n for( int i = 0; i < N; i++ )\n {\n for( int left = 0; left < N; left++ )\n {\n long long tmp_sum1 = 0, tmp_sum2 = 0;\n for( int right = left; right < N; right++ )\n {\n tmp_sum1 += pixel[i][right];\n if( i + 1 < N ) tmp_sum2 += pixel[i+1][right];\n ans = max( ans, max( tmp_sum1, tmp_sum1 + tmp_sum2 ) );\n }\n }\n }\n\n for( int j = 0; j < N; j++ )\n {\n for( int up = 0; up < N; up++ )\n {\n long long tmp_sum1 = 0, tmp_sum2 = 0;\n for( int down = up; down < N; down++ )\n {\n tmp_sum1 += pixel[down][j];\n if( j + 1 < N ) tmp_sum2 += pixel[down][j+1];\n ans = max( ans, max( tmp_sum1, tmp_sum1 + tmp_sum2 ) );\n }\n }\n }\n\n for( int up = 0; up < N; up++ )\n {\n for( int down = up + 2; down < N; down++ )\n {\n long long tmp = sum[down+1][N-1] - sum[up][N-1];\n for( int left = N - 3; left >= 0; left-- )\n {\n tmp = max( tmp, sum[down+1][left+2] - sum[up][left+2] );\n tmp += pixel[up][left+1] + pixel[down][left+1];\n ans = max( ans, tmp + ( sum[down+1][left] - sum[up][left] ) );\n }\n }\n }\n\n printf( \"%lld\\n\", ans );\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3680, "score_of_the_acc": -0.0516, "final_rank": 8 }, { "submission_id": "aoj_0310_7102551", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <algorithm>\nusing namespace std;\nlong long int map[303][303];\nlong long int ysums[303];\n//遅いしかっこ悪いけど愚直で行くか。\n//これはかなり遅いコードなので多分コード実行速度は下から数えた方が早いし、正答者一覧でも同じ秒数の人はいないだろうね\n//簡単な発想なのでコードの解説は簡単にできると思おう、賢い子なら小学生でもわかる。\n\nint main() {\n\tint n;\n\n\tcin>>n;\n\tfor(int i=0;i<n;i++){\n\t\tlong long int s2;\n\t\tfor(int j=0;j<n;j++){\n\t\t\tcin>>map[i][j];\n\t\t}\n\t}\n\tlong long int ans=map[0][0];\n\tfor(int y=0;y<n;y++){\n\t\tfor(int x=0;x<n;x++){\n\t\t\tlong long int ysum=0,ty;\n\t\t\tfor(int y2=y;y2>=0;y2--){\n\t\t\t\tif(x==0){\n\t\t\t\t\tysum+=map[y2][x];\n\t\t\t\t\tysums[y2]=ysum;\n\t\t\t\t\tans=max(ysum,ans);\n\t\t\t\t}else{\n\t\t\t\t\tysum+=map[y2][x];\n\t\t\t\t\tans=max(ans,ysum);\n\t\t\t\t\tif(y==y2)continue;\n\t\t\t\t\tans=max(ans,ysum+ysums[y2]);\n\t\t\t\t\tty=ysums[y2]+map[y2][x]+map[y][x];\n\t\t\t\t\tif(ty<ysum){\n\t\t\t\t\t\tysums[y2]=ysum;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tysums[y2]=ty;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t//for(int y2=0;y2<=y;y2++){\n\t\t\t//\tcout<<ysums[y2]<<\" \";\n\t\t\t//}\n\t\t\t//cout<<endl;\n\t\t\tlong long int sumx=0;\n\t\t\tfor(int xl=x;xl>=0;xl--){\n\t\t\t\tsumx+=map[y][xl];\n\t\t\t\tans=max(ans,sumx);\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\t\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3824, "score_of_the_acc": -0.1029, "final_rank": 14 }, { "submission_id": "aoj_0310_5854941", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\n//イテレーション\n#define REP(i, n) for (ll i = 0; i < ll(n); i++)\n#define REPD(i, n) for (ll i = n - 1; i >= 0; i--)\n#define FOR(i, a, b) for (ll i = a; i <= ll(b); i++)\n#define FORD(i, a, b) for (ll i = a; i >= ll(b); i--)\n#define FORA(i, I) for (const auto& i : I)\n// x:コンテナ\n#define ALL(x) x.begin(), x.end()\n#define SIZE(x) ll(x.size())\n//定数\n#define INF32 2147483647 // 2.147483647×10^{9}:32bit整数のinf\n#define INF64 9223372036854775807 // 9.223372036854775807×10^{18}:64bit整数のinf\n#define MOD 1000000007 //問題による\n//略記\n#define F first\n#define S second\n//出力(空白区切りで昇順に)\n#define coutALL(x) \\\n for (auto i = x.begin(); i != --x.end(); i++) cout << *i << \" \"; \\\n cout << *--x.end() << endl;\n\n// aをbで割る時の繰上げ,繰り下げ\nll myceil(ll a, ll b) { return (a + (b - 1)) / b; }\nll myfloor(ll a, ll b) { return a / b; }\n\nint main() {\n //小数の桁数の出力指定\n // cout<<fixed<<setprecision(10);\n //入力の高速化用のコード\n // ios::sync_with_stdio(false);\n // cin.tie(nullptr);\n ll N;\n cin >> N;\n\n vector<vector<int>> ps(N+1, vector<int>(N+1, 0));\n REP(i, N) REP(j, N) {\n cin >> ps[1+i][1+j];\n }\n\n vector<vector<int>> vs(N+1, vector<int>(N+1, 0));\n vector<vector<int>> hs(N+1, vector<int>(N+1, 0));\n\n FOR(i, 1, N) FOR(j, 1, N) {\n vs[i][j] = vs[i-1][j] + ps[i][j];\n hs[i][j] = hs[i][j-1] + ps[i][j];\n }\n\n /*\n FOR(b, 1, N) FOR(r, 1, N) {\n cout << sums[b][r] << \" \";\n if(r == N) cout << endl;\n }\n */\n vector<vector<vector<int>>> ms(N+1, vector<vector<int>>(N+1, vector<int>(N, 0)));\n FOR(b, 1, N) FOR(t, 1, b) {\n if(b == t) {\n FOR(l, 1, N-1) {\n ms[b][t][l] = max(ms[b][t][l-1], -hs[t][l]);\n }\n } else {\n ms[b][t][1] = vs[b][1] - vs[t-1][1] - hs[t][1] - hs[b][1];\n FOR(l, 2, N-1) {\n ms[b][t][l] = max(ms[b][t][l-1], vs[b][l] - vs[t-1][l] - hs[t][l] - hs[b][l]);\n }\n }\n }\n /*\n FOR(b, 1, N) FOR(r, 1, N) {\n cout << vs[b][r] << \" \";\n if(r == N) cout << endl;\n }\n */\n\n ll ans = ps[1][1];\n\n FOR(b, 1, N) FOR(r, 1, N) {\n FOR(t, 1, b) {\n ll tmp;\n if(b == t) {\n tmp = hs[t][r] + ms[b][t][r-1];\n }else {\n tmp = vs[b][r] - vs[t-1][r] + max(hs[b][r-1] + hs[t][r-1] + ms[b][t][r-1], 0);\n }\n if(ans < tmp) {\n ans = tmp;\n }\n }\n }\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 114232, "score_of_the_acc": -1.175, "final_rank": 19 }, { "submission_id": "aoj_0310_5850578", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 998244353 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash {\n static const int base1 = 1007, base2 = 2009;\n static const int mod1 = 1000000007, mod2 = 1000000009;\n vector<long long> hash1, hash2, power1, power2;\n int n;\n // construct\n RollingHash(const string &S) {\n n = (int)S.size();\n hash1.assign(n+1, 0);\n hash2.assign(n+1, 0);\n power1.assign(n+1, 1);\n power2.assign(n+1, 1);\n for (int i = 0; i < n; ++i) {\n hash1[i+1] = (hash1[i] * base1 + S[i]) % mod1;\n hash2[i+1] = (hash2[i] * base2 + S[i]) % mod2;\n power1[i+1] = (power1[i] * base1) % mod1;\n power2[i+1] = (power2[i] * base2) % mod2;\n }\n }\n \n // get hash of S[left:right]\n inline pair<long long, long long> get(int l, int r) const {\n long long res1 = hash1[r] - hash1[l] * power1[r-l] % mod1;\n if (res1 < 0) res1 += mod1;\n long long res2 = hash2[r] - hash2[l] * power2[r-l] % mod2;\n if (res2 < 0) res2 += mod2;\n return {res1, res2};\n }\n \n inline pair<long long, long long> c_shift(int l) {\n auto h1 = get(0, l);\n auto h2 = get(l, n);\n return {(h1.first + h2.first * power1[l]) % mod1, (h1.second + h2.second * power2[l]) % mod2};\n }\n \n // get lcp of S[a:] and T[b:]\n inline int getLCP(int a, int b) const {\n int len = min((int)hash1.size()-a, (int)hash1.size()-b);\n int low = 0, high = len;\n while (high - low > 1) {\n int mid = (low + high) >> 1;\n if (get(a, a+mid) != get(b, b+mid)) high = mid;\n else low = mid;\n }\n return low;\n }\n};\n\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int n; cin >> n;\n vector<vector<int>> p(n, vector<int>(n));\n int ans = -1e9;\n REP(i,n) REP(j,n) cin >> p[i][j];\n \n vector<vector<int>> cums(n, vector<int>(n+1));\n REP(i,n) {\n REP(j,n) {\n cums[i][j+1] = cums[i][j] + p[i][j];\n }\n }\n for(int i=0; i<n; i++) {\n for(int j=i; j<n; j++) {\n vector<vector<int>> dp(n, vector<int>(4, -1e9));\n REP(k,n) {\n dp[k][1] = max(dp[k][1], cums[k][j+1]-cums[k][i]);\n dp[k][3] = max(dp[k][3], cums[k][j+1]-cums[k][i]);\n if(k-1>=0){\n int tmp = p[k][i];\n if(i != j) tmp += p[k][j];\n dp[k][2] = max({dp[k][2], dp[k-1][2] + tmp, dp[k-1][1] + tmp});\n dp[k][3] = max({dp[k][3], dp[k-1][1] + cums[k][j+1]-cums[k][i], dp[k-1][2] + cums[k][j+1]-cums[k][i]});\n }\n }\n REP(k,n) ans = max(ans, dp[k][3]);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 3876, "score_of_the_acc": -1.0033, "final_rank": 18 }, { "submission_id": "aoj_0310_5603550", "code_snippet": "#include <stdio.h>\n#include <iostream>\n\nint table[302][302] = { {} };\n\nint max(int x, int y)\n{\n\treturn x > y ? x : y;\n}\n\nint sum(int y1, int x1, int y2, int x2)\n{\n\treturn (table[y2][x2] - table[y2][x1 - 1] - table[y1-1][x2] + table[y1 - 1][x1 - 1]);\n}\n\nint main() \n{\n\tint n;\n\tstd::cin >> n;\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tfor (int j = 1; j <= n; j++)\n\t\t{\n\t\t\tstd::cin >> table[i][j];\n\t\t\ttable[i][j] += table[i - 1][j] + table[i][j - 1] - table[i-1][j-1];\n\t\t}\n\t}\n\n\tint ans = -1000;\n\tint best = 0;\n\tfor (int row1 = 1; row1 <= n; row1++)\n\t{\n\t\tfor (int row2 = row1; row2 <= n; row2++)\n\t\t{\n\t\t\tbest = 0;\n\t\t\tfor (int k = 1; k <= n; k++)\n\t\t\t{\n\t\t\t\tint t1 = sum(row1, k, row2, k);\n\t\t\t\tint t2 = sum(row1, k, row1, k);\n\t\t\t\tif (row1 != row2) t2 += sum(row2, k, row2, k);\n\t\t\t\tans = max(ans, best+t1);\n\t\t\t\tans = max(ans, t1);\n\t\t\t\tbest = max(t1, best + t2);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3508, "score_of_the_acc": -0.05, "final_rank": 5 }, { "submission_id": "aoj_0310_5319418", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <string>\n#include <map>\n#include <set>\n#include <stack>\n#include <tuple>\n#include <deque>\n#include <array>\n#include <numeric>\n#include <bitset>\n#include <iomanip>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <limits>\n#include <iterator>\n#include <functional>\n#include <sstream>\n#include <fstream>\n#include <complex>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\nusing namespace std;\n\nusing ll = long long;\nconstexpr int INF = 1001001001;\n// constexpr int mod = 1000000007;\nconstexpr int mod = 998244353;\n\ntemplate<class T>\ninline bool chmax(T& x, T y){\n if(x < y){\n x = y;\n return true;\n }\n return false;\n}\ntemplate<class T>\ninline bool chmin(T& x, T y){\n if(x > y){\n x = y;\n return true;\n }\n return false;\n}\n\nint p[305][305], S[305][305], suffix[305], sum[305];\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N;\n cin >> N;\n for(int i = 0; i < N; ++i){\n for(int j = 0; j < N; ++j){\n cin >> p[i][j];\n S[i][j + 1] = S[i][j] + p[i][j];\n }\n }\n\n int ans = -INF;\n suffix[N] = -INF;\n for(int l = 0; l < N; ++l){\n for(int i = 0; i < N; ++i){\n sum[i + 1] = sum[i] + p[i][l];\n }\n for(int i = N - 1; i >= 0; --i){\n suffix[i] = max(suffix[i + 1], sum[i + 1]);\n }\n for(int i = 0; i < N; ++i){\n chmax(ans, max(suffix[i + 1] - sum[i], p[i][l]));\n }\n }\n for(int l = 0; l < N; ++l){\n for(int r = l + 2; r <= N; ++r){\n for(int i = 0; i < N; ++i){\n sum[i + 1] = sum[i] + p[i][l] + p[i][r - 1];\n }\n for(int i = N - 1; i >= 0; --i){\n suffix[i] = max(suffix[i + 1], sum[i + 1] + S[i][r - 1] - S[i][l + 1]);\n }\n for(int i = 0; i < N; ++i){\n chmax(ans, max(suffix[i + 1] - sum[i] + S[i][r - 1] - S[i][l + 1], S[i][r] - S[i][l]));\n }\n }\n }\n\n cout << ans << '\\n';\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4100, "score_of_the_acc": -0.0803, "final_rank": 10 }, { "submission_id": "aoj_0310_5013710", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint N;\nint p[300][300];\nint Xs[301][300],Ys[300][301];\nint ans=-1e9;\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)for(int j=0;j<N;j++)\n\t{\n\t\tcin>>p[i][j];\n\t\tXs[i+1][j]=Xs[i][j]+p[i][j];\n\t\tYs[i][j+1]=Ys[i][j]+p[i][j];\n\t}\n\tfor(int i=0;i<N;i++)for(int j=0;j<N;j++)for(int k=j+1;k<=N;k++)\n\t{\n\t\tans=max(ans,max(Xs[k][i]-Xs[j][i],Ys[i][k]-Ys[i][j]));\n\t}\n\tfor(int i=0;i<N;i++)for(int j=i+1;j<N;j++)\n\t{\n\t\tint mx=-1e9;\n\t\tfor(int k=1;k<N;k++)\n\t\t{\n\t\t\tmx=max(mx,Xs[j][k-1]-Xs[i+1][k-1]-Ys[i][k-1]-Ys[j][k-1]);\n\t\t\tans=max(ans,mx+Ys[i][k]+Ys[j][k]+Xs[j+1][k]-Xs[i][k]);\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4132, "score_of_the_acc": -0.0806, "final_rank": 11 }, { "submission_id": "aoj_0310_4539669", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int n;\n cin >> n;\n auto v = make_v(n, n, 0), S = make_v(n+1, n+1, 0);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n cin >> v[i][j];\n S[i+1][j+1] = v[i][j];\n S[i+1][j+1] += S[i][j+1] + S[i+1][j] - S[i][j];\n }\n }\n int ans = -INF<int>;\n auto f = [&](int y1, int x1, int y2, int x2){\n return S[y2][x2]-S[y2][x1]-S[y1][x2]+S[y1][x1];\n };\n for (int i = 0; i < n; ++i) {\n for (int j = i+1; j <= n; ++j) {\n if(j-i == 1){\n int val = 0, mn = 0;\n for (int k = 0; k < n; ++k) {\n val += v[i][k];\n chmax(ans, val-mn);\n chmin(mn, val);\n }\n continue;\n }\n for (int k = 0; k < n; ++k) {\n chmax(ans, f(i, k, j, k+1));\n }\n int mx = f(i, 0, j, 1);\n for (int k = 1; k < n; ++k) {\n chmax(ans, mx+f(i, k, j, k+1));\n mx += v[i][k]+v[j-1][k];\n chmax(mx, f(i, k, j, k+1));\n }\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3668, "score_of_the_acc": -0.0514, "final_rank": 6 }, { "submission_id": "aoj_0310_4359878", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint n,p[333][333];\nint tate[333][333];\nint main()\n{\n cin >> n;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=n;j++) cin >> p[i][j];\n }\n \n memset(tate,0,sizeof(int));\n for(int i=1;i<=n;i++){\n for(int j=1;j<=n;j++){\n tate[i][j] = p[i][j]+tate[i-1][j];\n }\n }\n \n int ans = p[1][1];\n for(int i=1;i<=n;i++){\n for(int j=i;j<=n;j++){\n int retu = tate[j][1]-tate[i-1][1];\n for(int k=2;k<=n;k++){\n ans = max(ans,retu+tate[j][k]-tate[i-1][k]);\n if(i == j) retu = max(retu+p[i][k],tate[j][k]-tate[i-1][k]);\n else retu = max(retu+p[i][k]+p[j][k],tate[j][k]-tate[i-1][k]);\n }\n }\n }\n \n cout << ans << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3872, "score_of_the_acc": -0.0283, "final_rank": 4 }, { "submission_id": "aoj_0310_4331747", "code_snippet": "/*\n   ∫ ∫ ∫\n   ノヽ\n  (_  )\n (_    )\n(______ )\n ヽ(´・ω・)ノ \n   |  /\n   UU\n*/\n#pragma region macro\n#include <bits/stdc++.h>\ntypedef long long int64;\nusing namespace std;\nusing P = pair<int64, int64>;\ntypedef vector<int> vi;\nconst int MOD = (int)1e9 + 7;\nconst int64 INF = 1LL << 62;\nconst int inf = 1<<30;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n#define REP(i, n) for (int i = 0; i < (n); i++)\n#define FOR(i,s,n) for (int i = s; i < (n); i++)\n#define ALL(obj) (obj).begin(), (obj).end() //コンテナじゃないと使えない!!\n#define debug(x) cerr << #x << \": \" << x << \"\\n\";\n#define mp make_pair\n#define bn '\\n'\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T> &V){\n int N = V.size();\n REP(i,N){\n os << V[i];\n if (i!=N-1) os << \" \";\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T,typename S>\nostream& operator<<(ostream& os, pair<T,S> const&P){\n os << \"(\";\n os << P.first;\n os << \" , \";\n os << P.second;\n os << \")\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, set<T> &S){\n auto it=S.begin();\n while(it!=S.end()){\n os << *it;\n os << \" \";\n it++;\n }\n os << \"\\n\";\n return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, deque<T> &q){\n for(auto it=q.begin();it<q.end();it++){\n os<<*it;\n os<<\" \";\n }\n os<<endl;\n return os;\n}\nvector<pair<int,int>> dxdy = {mp(0,1),mp(1,0),mp(-1,0),mp(0,-1)};\n#pragma endregion\n//fixed<<setprecision(10)<<ans<<endl;\n\nstruct cumsum2D{\n int H,W;\n vector<vector<int64>> cumsum;\n cumsum2D(vector<vector<int64>> A) :H(A.size()), W(A[0].size()){\n cumsum.assign(H+1, vector<int64>(W+1,0));\n for(int h=0;h<H;h++){\n for(int w=0;w<W;w++){\n cumsum[h+1][w+1] = A[h][w];\n }\n }\n\n for(int h=0;h<H;h++){\n for(int w=0;w<W;w++){\n cumsum[h+1][w+1] += cumsum[h+1][w] + cumsum[h][w+1] - cumsum[h][w];\n }\n }\n }\n\n // return sum(A[h][w]) {h,w | h in [h_begin, h_end) and w in [w_begin, w_end)}\n int64 get(int h_begin, int h_end, int w_begin, int w_end){\n return cumsum[h_end][w_end] - cumsum[h_begin][w_end] - cumsum[h_end][w_begin] + cumsum[h_begin][w_begin];\n }\n};\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int N;\n cin >> N;\n vector<vector<int64>> P(N,vector<int64>(N));\n REP(i,N){\n REP(j,N) cin >> P[i][j];\n }\n\n int64 ans = -INF;\n cumsum2D cumsum(P);\n REP(w,N){\n REP(u,N){\n for(int d=u+1; d<=N;d++){\n chmax(ans, cumsum.get(u,d,w,w+1));\n int h=w,l=u,r=d;\n chmax(ans, cumsum.get(h,h+1,l,r));\n }\n }\n }\n REP(u,N){\n for(int d=u+1; d<N; d++){\n int64 S = cumsum.get(u,u+1,0,N) + cumsum.get(d,d+1,0,N);\n vector<int64> DP_L(N,-INF), DP_R(N,-INF);\n REP(l,N){\n if(l) DP_L[l] = DP_L[l-1];\n int64 val = - (cumsum.get(u,u+1,0,l) + cumsum.get(d,d+1,0,l)) + (cumsum.get(u+1,d,l,l+1) ) ;\n chmax(DP_L[l], val);\n\n int r = N-l-1;\n if(l) DP_R[r] = DP_R[r+1];\n val = - (cumsum.get(u,u+1,r+1,N) + cumsum.get(d,d+1,r+1,N)) + (cumsum.get(u+1,d,r,r+1) ) ;\n chmax(DP_R[r], val);\n }\n REP(i,N-1) chmax(ans, S + DP_L[i] + DP_R[i+1]);\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 5008, "score_of_the_acc": -0.2885, "final_rank": 16 }, { "submission_id": "aoj_0310_4123108", "code_snippet": "// そすうささんのブログを読んだ\n#include<iostream>\nusing namespace std;\n\nint a[302][302], yoko[302][302] = {}, tate[302][302] = {};\n\nint main(){\n int n;\n cin >> n;\n for(int i = 1; i <= n; i++){\n for(int j = 1; j <= n; j++){\n cin >> a[i][j];\n yoko[i][j] = a[i][j]+yoko[i][j-1];\n tate[i][j] = a[i][j]+tate[i-1][j];\n }\n }\n int ans = -1000;\n // line\n for(int i = 1; i <= n; i++){\n for(int j = i; j <= n; j++){\n for(int k = 1; k <= n; k++){\n ans = max(ans, yoko[k][j]-yoko[k][i-1]);\n ans = max(ans, tate[j][k]-tate[i-1][k]);\n }\n }\n }\n for(int i = 1; i <= n; i++){\n for(int j = i+1; j <= n; j++){\n int all = yoko[i][n]+yoko[j][n];\n int submax = (tate[j-1][1]-tate[i][1]) - yoko[j][0] - yoko[i][0];\n for(int k = 2; k <= n; k++){\n int right = tate[j-1][k]-tate[i][k] - (yoko[j][n]-yoko[j][k]) - (yoko[i][n]-yoko[i][k]);\n ans = max(ans, all+submax+right);\n // cout << i << \" \"<< j << \" \" << k << \" \" << all << \" \" << submax << \" \" << right << endl;\n submax = max(submax, (tate[j-1][k]-tate[i][k])-yoko[j][k-1]-yoko[i][k-1]);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4160, "score_of_the_acc": -0.0809, "final_rank": 12 }, { "submission_id": "aoj_0310_3978847", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint c_sum_tate[300][301];\nint c_sum_yoko[300][301];\nint c_sum_2[300][300][301];\n\nint main() {\n int n;\n cin >> n;\n vector<vector<int>> p(n, vector<int>(n));\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n cin >> p[i][j];\n }\n }\n\n // c_sum_tate[x] = 左からx列目の累積和\n for (int i = 0; i < 300; i++)\n for (int j = 0; j <= 300; j++)c_sum_tate[i][j] = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n c_sum_tate[i][j + 1] = c_sum_tate[i][j] + p[j][i];\n }\n }\n // c_sum_yoko[x] = 上からx行目の累積和\n for (int i = 0; i < 300; i++)\n for (int j = 0; j <= 300; j++)c_sum_yoko[i][j] = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n c_sum_yoko[i][j + 1] = c_sum_yoko[i][j] + p[i][j];\n }\n }\n\n // コ形 の累積和を持つ\n // c_sum2[x][y][z]=上からx行目(0-indexed)と上からy行目(0-indexed)のz番目(1-indexed)までカウント\n for (int i = 0; i < 300; i++)\n for (int j = 0; j < 300; j++)\n for (int k = 0; k <= 300; k++)c_sum_2[i][j][k] = 0;\n for (int i = 0; i < n; i++) {\n for (int j = i; j < n; j++) {\n for (int k = 1; k <= n; k++) {\n c_sum_2[i][j][k] = c_sum_yoko[i][k - 1];\n if (j != i)c_sum_2[i][j][k] += c_sum_yoko[j][k - 1];\n\n c_sum_2[i][j][k] += c_sum_tate[k - 1][j + 1] - c_sum_tate[k - 1][i];\n }\n\n // c_sum_2の累積Maxを右から取る\n for (int k = n - 1; k >= 0; k--) c_sum_2[i][j][k] = max(c_sum_2[i][j][k], c_sum_2[i][j][k + 1]);\n }\n }\n\n int ret = -1145141919;\n for (int sx = 0; sx < n; sx++) {\n for (int sy = 0; sy < n; sy++) {\n int lside = 0;\n for (int ex = sx; ex < n; ex++) {\n lside += p[ex][sy];\n ret = max(ret, lside);\n if (sy < n - 1) {\n int box = lside + c_sum_2[sx][ex][sy + 2] - c_sum_yoko[sx][sy + 1];\n if (ex != sx)box -= c_sum_yoko[ex][sy + 1];\n\n ret = max(ret, box);\n }\n }\n }\n }\n\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 109804, "score_of_the_acc": -1.31, "final_rank": 20 }, { "submission_id": "aoj_0310_3976395", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n\nint p[500][500];\nint sum[500][500];\n\nint main(){\n\tint n;cin>>n;\n\trep(i,n)rep(j,n)scanf(\"%d\",&p[i][j]);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tsum[i+1][j]=sum[i][j]+p[i][j];\n\t\t}\n\t}\n\tint ans=INT_MIN;\n\trep(i,n){\n\t\tint Max=0;\n\t\trep(k,n){\n\t\t\tans=max(ans,Max+p[i][k]);\n\t\t\tMax=max(Max+p[i][k],0);\n\t\t}\n\t\tfor(int j=i+1;j<n;j++){\n\t\t\tint Max=0;\n\t\t\trep(k,n){\n\t\t\t\tans=max(ans,max(0,Max)+(sum[j+1][k]-sum[i][k]));\n\t\t\t\tMax=max(Max+p[i][k]+p[j][k],sum[j+1][k]-sum[i][k]);\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4368, "score_of_the_acc": -0.0078, "final_rank": 2 }, { "submission_id": "aoj_0310_3949427", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\nll pic[305][305]={0};\nll sum[305][305]={0};\nll rsum(int x1,int y1,int x2,int y2){\n if(x1>=x2||y1>=y2) return 0;\n ll ret=sum[x2][y2]+sum[x1][y1];\n return ret-sum[x2][y1]-sum[x1][y2];\n}\nint main(){\n int n;\n cin>>n;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=n;j++) cin>>pic[i][j];\n }\n\n for(int i=1;i<=n;i++){\n for(int j=1;j<=n;j++) sum[i][j]=sum[i][j-1]+pic[i][j];\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=n;j++) sum[i][j]+=sum[i-1][j];\n }\n\n ll ans=-17441744;\n for(int i=1;i<=n;i++){\n for(int j=i;j<=n;j++){\n //l=i r=j\n\n vector<ll> vec;\n vec.push_back(0);\n vec.push_back(rsum(i-1,0,j,1));\n for(int k=2;k<=n;k++){\n vec.push_back(vec[k-1]+rsum(i-1,k-1,j,k)-rsum(i,k-2,j-1,k-1));\n }\n\n priority_queue<int> pque;\n pque.push(vec[n]);\n ll kans=pque.top();\n for(int k=n-1;k>=1;k--){\n kans=max(kans,pque.top()-vec[k]+rsum(i,k-1,j-1,k)+rsum(i-1,k-1,j,k));\n //if(i==1&&j==5) cout<<pque.top()-vec[k]+rsum(i,k-1,j-1,k)+rsum(i-1,k-1,j,k)<<endl;\n pque.push(vec[k]);\n }\n /*if(i==1&&j==5){\n for(int k=1;k<=n;k++) cout<<vec[k]<<\" \";\n cout<<endl;\n }*/\n\n ans=max(ans,kans);\n //if(i==4&&j==4) cout<<i<<\" \"<<j<<\" \"<<kans<<endl;\n\n //if(kans==14) cout<<i<<\"!\"<<j<<endl;\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 4608, "score_of_the_acc": -0.3849, "final_rank": 17 }, { "submission_id": "aoj_0310_3935508", "code_snippet": "#include <bits/stdc++.h>\n\n#define int long long\nusing namespace std;\n\nint n;\nint num[400][400];\nint rui[400][400];\n\nint solve(int l, int r){\n\tint dp[400];\n\tdp[n-1] = INT_MIN;\n\t\n\tif(l == r){\n\t\tfor(int i = n-2;i >= 0;i--){\n\t\t \tdp[i] = max(num[i+1][l], dp[i+1] + num[i+1][l]);\n\t\t }\n\t}else{\n\t\tfor(int i = n-2;i >= 0;i--){\n\t\t\tdp[i] = max(rui[i+1][r+1]-rui[i+1][l], dp[i+1] + num[i+1][r] + num[i+1][l]);\n\t\t}\n\t}\n\t\n\tint ans = INT_MIN;\n\tfor(int i = 0;i < n;i++){\n\t\tint tmp = rui[i][r+1]-rui[i][l];\n\t\tans = max({ans, tmp, tmp + dp[i]});\n\t}\n\t\n\treturn ans;\n}\n\nsigned main(){\n\tcin >> n;\n\t\n\tfor(int i = 0;i < n;i++){\n\t\tfor(int j = 0;j < n;j++){\n\t\t\tcin >> num[i][j];\n\t\t\trui[i][j+1] += rui[i][j] + num[i][j];\n\t\t}\n\t}\n\t\n\tint ans = INT_MIN;\n\tfor(int i = 0;i < n;i++){\n\t\tfor(int j = i;j < n;j++){\n\t\t\tans = max(ans, solve(i, j));\n\t\t}\n\t}\n\t\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4964, "score_of_the_acc": -0.1381, "final_rank": 15 }, { "submission_id": "aoj_0310_3859204", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n\n vector< vector<int> > p(n, vector<int>(n));\n for(int i = 0 ; i < n ; ++i){\n for(int j = 0 ; j < n ; ++j){\n cin >> p[i][j];\n }\n }\n\n vector< vector<int> > sum(n + 1, vector<int>(n + 1, 0));\n for(int i = 0 ; i < n ; ++i){\n for(int j = 0 ; j < n ; ++j){\n sum[i + 1][j + 1] = p[i][j];\n }\n }\n\n for(int i = 0 ; i <= n ; ++i){\n for(int j = 1 ; j <= n ; ++j){\n sum[i][j] += sum[i][j - 1];\n }\n }\n\n for(int j = 0 ; j <= n ; ++j){\n for(int i = 1 ; i <= n ; ++i){\n sum[i][j] += sum[i - 1][j];\n }\n }\n\n int ans = -(1 << 30);\n\n for(int i = 1 ; i <= n ; ++i){\n for(int j = 0 ; j <= n ; ++j){\n for(int k = 0 ; k < j ; ++k){\n ans = max(ans, sum[i][j] - sum[i][k] - sum[i - 1][j] + sum[i - 1][k]);\n ans = max(ans, sum[j][i] - sum[k][i] - sum[j][i - 1] + sum[k][i - 1]);\n }\n }\n }\n\n for(int d = 2 ; d <= n ; ++d){\n for(int u = 1 ; u < d ; ++u){\n int maxi = sum[d][1] - sum[d][0] - sum[u - 1][1] + sum[u - 1][0];\n for(int j = 2 ; j <= n ; ++j){\n ans = max(ans, maxi + sum[d][j] - sum[d][j - 1] - sum[u - 1][j] + sum[u - 1][j - 1]);\n maxi = max(maxi + p[d - 1][j - 1] + p[u - 1][j - 1], sum[d][j] - sum[d][j - 1] - sum[u - 1][j] + sum[u - 1][j - 1]);\n }\n }\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3648, "score_of_the_acc": -0.1013, "final_rank": 13 } ]
aoj_0311_cpp
かぐや いよいよ今月末に「はやぶさ2」が打ち上げられます。4年前に「はやぶさ」が帰ってきたときは、日本中が盛り上がったのを覚えている人も多いと思います。7年前には、「かぐや」が打ち上げられ、月の周りを回りながらたくさんの鮮明な画像を地球に送ってくれました。 上の図は、地球を原点とした空間座標(z軸は紙面から垂直に下から上に向いているものとします)に、月の軌道といくつかの月の位置、月の周りを回るかぐやの軌道を描いたものです。月の軌道は、x軸とy軸を通る平面上にある、原点を中心とする円とします。月の周りを回るかぐやの軌道は、x軸とz軸を通る平面に平行な平面上にある円とし、その中心は月の中心と一致します。月は、その軌道に沿って描かれた矢印の方向に回っているものとします。 右の図で、月の位置はA,B,Cの3つが描かれています。月を横切る直線がかぐやの軌道です。かぐやは月の周りを回っているので軌道は円ですが、z軸の正の方向から見ているので、図のx軸に平行な直線に見えます(月の位置が変わっても、つねにx軸に平行であることに注意してください)。かぐやは、その軌道上に描かれた矢印の方向に回っているものとします。 かぐやが地球から見て月の裏側に隠れてしまうと、地球と直接通信ができなくなります。かぐやの管制を担当するあなたは、かぐやが月の裏側に隠れる時間が、与えられた時間の中でどれだけになるかをプログラムで求めようとしています。 月の地球に対する位置と分単位での時間tが与えられたとき、その位置から始めてt分後までの間に、かぐやが月の裏側に隠れる時間を求めるプログラムを作成してください。ただし、地球とかぐやは点、月は半径 1800 km の球と考えます。月は半径 380000 km の軌道を 2500000 秒で一周し、かぐやは月の表面から高度 100 km の円上を2時間で一周するものとします。かぐやの最初の位置は、かぐやの軌道がz座標で最大の値をとる位置とします。 入力 入力は以下の形式で与えられる。 m t m (0 ≤ m < 360) は月の位置を上の図のx軸の正の部分からy軸の正の部分に向かって反時計回りに測った角度を整数で表したものである。 t (1 ≤ t ≤ 10000) は分で測った時間を表す整数である。 出力 はじめの位置から t 分経過するまでの間に、かぐやが月の裏側に隠れる時間(分)を実数で出力する。ただし、誤差がプラスマイナス 1.0 分を超えてはならない。この条件を満たせば小数点以下何桁表示してもよい。 入出力例 入力例1 90 10 出力例1 0.0 入力例2 0 120 出力例2 47.73
[ { "submission_id": "aoj_0311_8296988", "code_snippet": "#include <cmath>\n#include <iostream>\nusing namespace std;\n\nuint64_t seed = 1234567891234567891;\nuint64_t xorshift64() {\n\tseed ^= seed << 13;\n\tseed ^= seed >> 7;\n\tseed ^= seed << 17;\n\treturn seed;\n}\nfloat rand_float() {\n\treturn xorshift64() / float(uint64_t(-1));\n}\n\nint main() {\n\tint M, T;\n\tcin >> M >> T;\n\tconst float pi = acos(-1.0);\n\tconst float limit = -0.31565427002642061149526714494746;\n\tconst float Z0 = 2 * pi * T / (2500000.0 / 60.0);\n\tconst float Z1 = 2 * pi * T / 120.0;\n\tconst float Z2 = 2 * pi * (M / 360.0);\n\tint success = 0;\n\tint samples = 0;\n\twhile (true) {\n\t\tif (samples % 1000 == 0) {\n\t\t\tdouble p = (success + 0.5) / (samples + 1.0);\n\t\t\tdouble stdev = sqrt(p * (1.0 - p) / (samples + 1.0));\n\t\t\tif ((stdev * 2.0) * T < 1.0) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tfloat t = rand_float();\n\t\tfloat x = cos(Z0 * t + Z2) * sin(Z1 * t);\n\t\tif (x < limit) {\n\t\t\tsuccess += 1;\n\t\t}\n\t\tsamples += 1;\n\t}\n\tcout.precision(6);\n\tcout << fixed << double(success) / samples * T << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1670, "memory_kb": 3644, "score_of_the_acc": -1.267, "final_rank": 13 }, { "submission_id": "aoj_0311_8296981", "code_snippet": "#include <cmath>\n#include <iostream>\nusing namespace std;\n\nuint64_t seed = 1234567891234567891;\nuint64_t xorshift64() {\n\tseed ^= seed << 13;\n\tseed ^= seed >> 7;\n\tseed ^= seed << 17;\n\treturn seed;\n}\ndouble rand_double() {\n\treturn xorshift64() / double(uint64_t(-1));\n}\n\nint main() {\n\tint M, T;\n\tcin >> M >> T;\n\tconst double pi = acos(-1.0);\n\tconst double limit = -0.31565427002642061149526714494746;\n\tconst double Z0 = 2 * pi * T / (2500000.0 / 60.0);\n\tconst double Z1 = 2 * pi * T / 120.0;\n\tconst double Z2 = 2 * pi * (M / 360.0);\n\tint success = 0;\n\tint samples = 0;\n\twhile (true) {\n\t\tif (samples % 1000 == 0) {\n\t\t\tdouble p = (success + 0.5) / (samples + 1.0);\n\t\t\tdouble stdev = sqrt(p * (1.0 - p) / (samples + 1.0));\n\t\t\tif ((stdev * 2.0) * T < 1.0) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tdouble t = rand_double();\n\t\tdouble x = cos(Z0 * t + Z2) * sin(Z1 * t);\n\t\tif (x < limit) {\n\t\t\tsuccess += 1;\n\t\t}\n\t\tsamples += 1;\n\t}\n\tcout.precision(6);\n\tcout << fixed << double(success) / samples * T << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2770, "memory_kb": 3924, "score_of_the_acc": -2, "final_rank": 14 }, { "submission_id": "aoj_0311_5433890", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\nint main(){\n\n\tdouble R_moon = 380000;\n\tdouble r_moon = 1800;\n\tdouble R_kaguya = 1900;\n\n\tdouble va_moon = (2*M_PI/2500000.0)*60.0;\n\tdouble va_kaguya = 2*M_PI/120.0;\n\n\tdouble first_angle,T;\n\n\tscanf(\"%lf %lf\",&first_angle,&T);\n\n\tdouble first_rad = first_angle*(M_PI/180.0);\n\n\tdouble diff_t = 0.001;\n\tdouble ans = 0;\n\n\tfor(double t = 0; t < T; t += diff_t){\n\n\t\tdouble now_rad = first_rad+va_moon*t;\n\t\tdouble x_moon = R_moon*cos(now_rad);\n\t\tdouble y_moon = R_moon*sin(now_rad);\n\t\tdouble z_moon = 0;\n\n\n\t\tdouble now_rad_k = va_kaguya*t;\n\t\tdouble x_kaguya = -R_kaguya*sin(now_rad_k)+x_moon;\n\t\tdouble y_kaguya = y_moon;\n\t\tdouble z_kaguya = R_kaguya*cos(now_rad_k);\n\n\t\tdouble A = x_kaguya*x_kaguya + y_kaguya*y_kaguya + z_kaguya*z_kaguya;\n\t\tdouble B = -2.0*(x_kaguya*x_moon + y_kaguya*y_moon + z_kaguya*z_moon);\n\t\tdouble C = x_moon*x_moon + y_moon*y_moon - r_moon*r_moon;\n\n\t\tdouble D = B*B -4*A*C;\n\n\t\tif(D > EPS){\n\t\t\tdouble tmp = (sqrt(D)-B)/(2.0*A);\n\t\t\tif(tmp < 1.0){\n\n\t\t\t\tans += diff_t;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%.10lf\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1180, "memory_kb": 3544, "score_of_the_acc": -0.9693, "final_rank": 10 }, { "submission_id": "aoj_0311_5056533", "code_snippet": "#include<iostream>\n#include<cmath>\nusing namespace std;\nint M,T;\ndouble abs(double x,double y,double z){return sqrt(x*x+y*y+z*z);}\nmain()\n{\n\tcin>>M>>T;\n\tint ans=0;\n\tfor(int i=0;i<T*60;i++)\n\t{\n\t\tdouble r=M+360/25e5*i;\n\t\tr=r*M_PI/180;\n\t\tdouble t=360/72e2*i;\n\t\tt=t*M_PI/180;\n\t\tif(cos(r)>=0&&sin(t)>=0||cos(r)<=0&&sin(t)<=0)\n\t\t{\n\t\t\tcontinue;\n\t\t}\n\t\tdouble mx=38e4*cos(r),my=38e4*sin(r),mz=0;\n\t\tdouble px=mx-19e2*sin(t),py=my,pz=19e2*cos(t);\n\t\tdouble A=abs(mx,my,mz),B=abs(px,py,pz),C=abs(mx-px,my-py,mz-pz);\n\t\tdouble theta=acos((A*A+B*B-C*C)/2/A/B);\n\t\tdouble h=A*sin(theta);\n\t\tif(h<=1800)ans++;\n\t}\n\tcout<<ans/60.<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3612, "score_of_the_acc": -0.6409, "final_rank": 6 }, { "submission_id": "aoj_0311_4540890", "code_snippet": "#include <iostream>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing namespace std;\n\nint main() {\n double m; int T;\n cin >> m >> T;\n double pi = acos(-1);\n m /= 180/pi;\n double ans = 0;\n for (int _ = 0; _ < T*100; ++_) {\n double t = _/100.0;\n double x = 3800, p = 19;\n double cs = x*p*cos(m+t*pi*2*60/2500000)*sin(t/120*pi*2);\n double A = x*x+p*p-2*cs, B = x*x-cs, C = 3800*3800-18*18;\n double d = B*B-A*C;\n if(d > 0 && (B+sqrt(d))/A < 1) ans += 0.01;\n }\n printf(\"%.10lf\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3544, "score_of_the_acc": -0.5581, "final_rank": 4 }, { "submission_id": "aoj_0311_4349057", "code_snippet": "#include<cstdio>\n#include<cmath>\nusing namespace std;\nstatic const double pi = 2.0 * acos(0.0);\n\ndouble m, t;\n\nint main(){\n\tscanf(\"%lf %lf\", &m, &t);\n\tdouble res = 0.0;\n\tfor(double ct = 0.0; ct < t; ct += 0.01){\n\t\tdouble theta = 0.5 * pi + pi / 60.0 * ct;\n\t\tdouble z = 1900.0 * sin(theta);\n\t\tdouble x2 = 1900.0 * cos(theta);\n\t\tdouble theta2 = -pi / 180.0 * m + pi / 2.0 - 2.0 * pi * ct / (2500000.0 / 60.0);\n\t\tdouble y = x2 * sin(theta2);\n\t\tdouble x = x2 * cos(theta2);\n\t\tif(y < 0.0) continue;\n\t\tdouble L = 380000.0;\n\t\tdouble l = 1800.0;\n\t\tdouble r_ = L * l / sqrt(L * L - l * l);\n\t\tdouble r = r_ * (1.0 + y / 380000.0);\n\t\tif(sqrt(z * z + x * x) < r) res += 0.01;\n\t}\n\tprintf(\"%.3lf\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3148, "score_of_the_acc": -0.1051, "final_rank": 2 }, { "submission_id": "aoj_0311_4349044", "code_snippet": "#include<cstdio>\n#include<cmath>\nusing namespace std;\nstatic const double pi = 2.0 * acos(0.0);\n\ndouble m, t;\n\nint main(){\n\tscanf(\"%lf %lf\", &m, &t);\n\tdouble res = 0.0;\n\tfor(double ct = 0.0; ct < t; ct += 0.01){\n\t\tdouble theta = 0.5 * pi + pi / 60.0 * ct;\n\t\tdouble z = 1900.0 * sin(theta);\n\t\tdouble x2 = 1900.0 * cos(theta);\n\t\tdouble theta2 = -pi / 180.0 * m + pi / 2.0 - 2.0 * pi * ct / (2500000.0 / 60.0);\n\t\tdouble y = x2 * sin(theta2);\n\t\tdouble x = x2 * cos(theta2);\n\t\tdouble lim = 1800.0 * 1800.0 / 380000.0;\n\t\tif(y < -lim) continue;\n\t\tdouble r = 1800.0 * (1.0 + y / 380000.0);\n\t\tif(sqrt(z * z + x * x) < r) res += 0.01;\n\t}\n\tprintf(\"%.3lf\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3064, "score_of_the_acc": -0.0074, "final_rank": 1 }, { "submission_id": "aoj_0311_4348918", "code_snippet": "#include<cstdio>\n#include<cmath>\nusing namespace std;\nstatic const double pi = 2.0 * acos(0.0);\n\ndouble m, t;\n\nint main(){\n\tscanf(\"%lf %lf\", &m, &t);\n\tdouble res = 0.0;\n\tfor(double ct = 0.0; ct < t; ct += 0.01){\n\t\tdouble theta = 0.5 * pi + pi / 60.0 * ct;\n\t\tdouble z = 1900.0 * sin(theta);\n\t\tdouble x2 = 1900.0 * cos(theta);\n\t\tdouble theta2 = -pi / 180.0 * m + pi / 2.0 - 2.0 * pi * ct / (2500000.0 / 60.0);\n\t\tdouble y = x2 * sin(theta2);\n\t\tdouble x = x2 * cos(theta2);\n\t\tif(y < 0.0) continue;\n\t\tdouble r = 1800.0 * (1.0 + y / 380000.0);\n\t\tif(sqrt(z * z + x * x) < r) res += 0.01;\n\t}\n\tprintf(\"%.3lf\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3148, "score_of_the_acc": -0.1051, "final_rank": 2 }, { "submission_id": "aoj_0311_3978622", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\nusing namespace std;\nconst double moondist = 380000;\nconst double kaguyadist = 1900;\nconst double moontime = 2500000;\nconst double kaguyatime = 7200;\nconst double moonradius = 1800;\nconst double pi = acos(-1.0);\ndouble sqr(double x) {\n return x * x;\n}\nint main() {\n double l = moondist, r = moondist + kaguyadist;\n for(int i = 0; i < 100; ++i) {\n double m = (l + r) * 0.5;\n double tcos = (m * m + moondist * moondist - kaguyadist * kaguyadist) / (2 * m * moondist);\n double tsin = sqrt(1.0 - sqr(tcos));\n if(tsin < moonradius / moondist) r = m;\n else l = m;\n }\n double threshold = l;\n int M, T;\n cin >> M >> T; T *= 60;\n double theta = (M / 360.0) * (2 * pi);\n int sep = 1000000;\n double ans = 0.0;\n for(int i = 0; i <= 2 * sep; ++i) {\n double t = double(T) * i / (2 * sep);\n double mx = moondist * cos(theta + t / moontime * (2 * pi));\n double my = moondist * sin(theta + t / moontime * (2 * pi));\n double mz = 0.0;\n double vx = -kaguyadist * sin(t / kaguyatime * (2 * pi));\n double vy = 0.0;\n double vz = kaguyadist * cos(t / kaguyatime * (2 * pi));\n double kx = mx + vx;\n double ky = my + vy;\n double kz = mz + vz;\n double dist = sqrt(sqr(kx) + sqr(ky) + sqr(kz));\n if(dist > threshold) {\n if(i == 0 || i == 2 * sep) ans += 1;\n else if(i % 2 == 0) ans += 2;\n else ans += 4;\n }\n }\n ans /= 6 * sep;\n ans *= T;\n cout.precision(15);\n cout << fixed << ans / 60.0 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3684, "score_of_the_acc": -0.7839, "final_rank": 9 }, { "submission_id": "aoj_0311_3976400", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n\nstruct Vector{\n\tdouble x,y,z;\n\tVector(double x,double y,double z):x(x),y(y),z(z){}\n};\n\ndouble norm(Vector v){\n\treturn v.x*v.x+v.y*v.y+v.z*v.z;\n}\ndouble abs(Vector v){\n\treturn sqrt(norm(v));\n}\n\nVector operator-(Vector a,Vector b){\n\treturn Vector(a.x-b.x,a.y-b.y,a.z-b.z);\n}\ndouble dot(Vector a,Vector b){\n\treturn a.x*b.x+a.y*b.y+a.z*b.z;\n}\ndouble cross(Vector a,Vector b){\n\treturn abs(Vector(a.x*b.z-a.z*b.y,a.z*b.x-a.x*b.z,a.x*b.y-a.y*b.x));\n}\n\nint main(){\n\tdouble m,t;cin>>m>>t;t*=60;\n\tm=m/180*M_PI;\n\tdouble speed=2*M_PI/2500000;\n\tdouble speed2=2*M_PI/7200;\n\tdouble R=380000,r=1900;\n\tdouble cnt=0;\n\tfor(int i=0;i<t;i++){\n\t\tdouble theta=m+speed*i;\n\t\tdouble theta2=(M_PI/2)+speed2*i;\n\t\tdouble Ex=0,Ey=0,Ez=0;\n\t\tdouble Mx=R*cos(theta),My=R*sin(theta),Mz=0;\n\t\tdouble Kx=Mx+r*cos(theta2),Ky=My,Kz=r*sin(theta2);\n\t\tVector E(Ex,Ey,Ez),M(Mx,My,Mz),K(Kx,Ky,Kz);\n\t\tif(dot(E-K,M-K)<0)continue;\n\t\tdouble dist=abs(cross(K-E,M-E)/abs(K-E));\n\t\tif(dist<=1800){\n\t\t\tcnt+=1;\n\t\t}\n\t}\n\tprintf(\"%.5lf\\n\",cnt/60);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3580, "score_of_the_acc": -0.6, "final_rank": 5 }, { "submission_id": "aoj_0311_3950886", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<cmath>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\nconst ld R=380000,r=1800,s=100,t1=2500000,t2=7200;\nbool judge(ld a,ld b,ld c){\n/* ld a=(R*X-(r+s)*Y)*(R*X+(r+s)*Y)+1-X*X-Y*Y;\n ld b=-2*(R*R*X*X-R*(r+s)*X*Y+Y*Y);\n ld c=(R*R-1)*X*X+1-r*r; */\n\n ld d=b*b-4*a*c;\n if(d<0) return true;\n ld ans=(-b-sqrt(d))/(a*2);\n if(ans>1) return true;\n return false;\n}\nint main(){\n int m,t_;\n cin>>m>>t_;\n ld m2=(ld)m;\n //return 0;\n ld ans=0;\n for(int i=0;i<t_*60;i++){\n ld t=(ld)i;\n ld xm=R*cos(2*M_PI*((t/t1)+(m2/360)));\n ld ym=R*sin(2*M_PI*((t/t1)+(m2/360)));\n ld zm=0;\n\n ld xk=-(r+s)*sin(2*M_PI*(t/t2))+xm;\n ld yk=ym;\n ld zk=(r+s)*cos(2*M_PI*(t/t2));\n\n //if(i==0) cout<<xm<<\" \"<<ym<<\" \"<<zm<<\" \"<<xk<<\" \"<<yk<<\" \"<<zk<<endl;\n\n ld a=xk*xk+yk*yk+zk*zk;\n ld b=-2*(xk*xm+yk*ym);\n ld c=R*R-r*r;\n if(!judge(a,b,c)) ans+=1;\n }\n cout<<(ans/60)<<endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3612, "score_of_the_acc": -0.6742, "final_rank": 7 }, { "submission_id": "aoj_0311_3230207", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef double D;\n#define PB push_back\n#define M 1000000007\n#define B 500\ndouble pi=3.1415926535;\nint m,tt;\nint judge(double t){\n double xk,yk,zk,xm,ym,zm;\n double arg;\n arg=pi/180*m;\n arg+=(t/41667*2*pi);\n zm=0;\n xm=cos(arg)*380000;\n ym=sin(arg)*380000;\n arg=t*2*pi/120;\n yk=ym;\n zk=zm+cos(arg)*1900;\n xk=xm-sin(arg)*1900;\n double k;\n k=(xk*xm+yk*ym+zk*zm)/(xk*xk+yk*yk+zk*zk);\n double xh,yh,zh;\n xh=xk*k;\n yh=yk*k;\n zh=zk*k;\n double xd,yd,zd;\n xd=xh-xm;\n yd=yh-ym;\n zd=zh-zm;\n if(k<=1&&xd*xd+yd*yd+zd*zd<1800*1800){\n return 1;\n }\n else return 0;\n}\nint main(void){\n scanf(\"%d%d\",&m,&tt);\n double ans=0;\n for(int i=0;i<=tt*B;i++){\n ans+=judge(D(i)/B);\n }\n printf(\"%lf\\n\",ans/B);\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 3564, "score_of_the_acc": -0.7814, "final_rank": 8 }, { "submission_id": "aoj_0311_3117561", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <utility>\nusing namespace std;\nconst double EPS = 1e-10;\nconst double INF = 1e12;\nconst double PI = acos(-1);\n \nstruct Point{\n double x,y,z;\n Point(double x, double y, double z):x(x), y(y), z(z){}\n Point(){}\n Point &operator +=(const Point &a){ x+=a.x; y+=a.y; z+=a.z; return *this; }\n Point &operator -=(const Point &a){ x-=a.x; y-=a.y; z-=a.z; return *this; }\n Point &operator *=(const double &a){ x*=a; y*=a; z*=a; return *this; }\n Point operator +(const Point &a) const{ return Point(x+a.x, y+a.y, z+a.z); }\n Point operator -(const Point &a) const{ return Point(x-a.x, y-a.y, z-a.z); }\n Point operator *(const double &a) const{ return Point(a*x, a*y, a*z); }\n Point operator -() { return Point(-x, -y, -z); }\n};\n \ndouble dot(const Point &a, const Point &b){\n return a.x*b.x +a.y*b.y +a.z*b.z;\n}\nPoint cross(const Point &a, const Point &b){\n return Point(a.y*b.z -a.z*b.y, a.z*b.x -a.x*b.z, a.x*b.y -a.y*b.x);\n}\ndouble abs(const Point &a){\n return sqrt(dot(a, a));\n}\nPoint unit(const Point &a){\n return a *(1/abs(a));\n}\nbool operator ==(const Point &a, const Point &b){\n return abs(a-b) < EPS;\n}\n\nPoint projectionLP3(Point p, Point q, Point c){\n double t = dot(unit(q-p), c-p);\n return p +unit(q-p) *t;\n}\ndouble distanceSP3(Point p, Point q, Point c){\n Point r = projectionLP3(p, q, c);\n if(dot(q-p, r-p) < 0) return abs(c-p);\n if(dot(p-q, r-q) < 0) return abs(c-q);\n return abs(c-r);\n}\n\npair<Point, Point> calcpos(double t, double m){\n using P2d = complex<double>;\n double arg1 = m*PI/180 +t/2500000 *2*PI;\n P2d moon2d = P2d(380000, 0) *P2d(cos(arg1), sin(arg1));\n Point moon = Point(moon2d.real(), moon2d.imag(), 0);\n double arg2 = t/7200 *2*PI;\n P2d kaguya2d = P2d(0, 1900) *P2d(cos(arg2), sin(arg2));\n Point kaguya = moon + Point(kaguya2d.real(), 0, kaguya2d.imag());\n return make_pair(moon, kaguya);\n}\n\nint main(){\n cout << fixed << setprecision(3);\n double m,t;\n cin >> m >> t;\n t *= 60;\n double dt = 1e-1;\n double ans = 0;\n Point origin(0, 0, 0);\n for(double time=dt/2; time<t; time+=dt){\n pair<Point, Point> pos = calcpos(time, m);\n if(distanceSP3(origin, pos.second, pos.first) < 1800){\n ans += dt;\n }\n }\n cout << fixed << setprecision(3);\n cout << ans/60 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 3668, "score_of_the_acc": -1.0283, "final_rank": 11 }, { "submission_id": "aoj_0311_2691829", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nG intersect(P c, double r, P p1, P p2) {\n P u = p2 - p1, v = p1 - c;\n auto a = dot(u,u), b = dot(u,v)/a, t = (dot(v,v) - r*r)/a;\n auto det = b*b - t;\n if (det < -EPS) return {}; // no solution\n\n auto t1 = -b - sqrt(det), t2 = -b + sqrt(det);\n G ps;\n auto insert_if_possible = [&](P p) {\n for (auto q: ps) if (abs(dot(p-q, p-q)) < EPS) return;\n ps.push_back(p);\n };\n if (r - norm(p1-c) > - EPS) insert_if_possible(p1);\n if (t1 > -EPS && 1-t1 > -EPS) insert_if_possible(p1+t1*u);\n if (t2 > -EPS && 1-t2 > -EPS) insert_if_possible(p1+t2*u);\n if (r - norm(p2-c) > -EPS) insert_if_possible(p2);\n return ps;\n}\n\nconst double rm = 1800;\nconst double om = 380000;\nconst double pm = 2500000;\n\nconst double ok = rm + 100;\nconst double pk = 2 * 3600;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint m, t; cin >> m >> t; t *= 60;\n\tdouble ans = 0;\n\tconst int ITER = t * 10;\n\t\n\trep(it, ITER){\n\t\tdouble T = t * (it + 0.5) / ITER;\n\t\tdouble tm = m / 180.0 * PI + T * 2 * PI / pm;\n\t\tdouble tk = PI / 2 + T * 2 * PI / pk;\n\t\t\n\t\tdouble mx = om * cos(tm), my = om * sin(tm);\n\t\tdouble kx = ok * cos(tk), kz = ok * sin(tk), ky = 0;\n\t\tkx += mx; ky += my;\n\t\t\n\t\tP K(kx, ky);\n\t\tP M0 (mx, my);\n\t\tP M = K * dot(M0, K) / norm(K);\n\t\tdouble d = abs(M - M0);\n\t\tdouble mr;\n\t\tif(d > rm - EPS) mr = 0;\n\t\telse mr = sqrt(rm * rm - d * d);\n\t\t\n\t\tbool hide = !intersect(P(abs(M), 0), mr, P(0, 0), P(abs(K), kz)).empty();\n\t\tif(hide) ans += 1.0 * t / ITER;\n\t}\n\tprintf(\"%.20f\\n\", ans / 60);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1340, "memory_kb": 3604, "score_of_the_acc": -1.0983, "final_rank": 12 }, { "submission_id": "aoj_0311_2691817", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nG intersect(P c, double r, P p1, P p2) {\n P u = p2 - p1, v = p1 - c;\n auto a = dot(u,u), b = dot(u,v)/a, t = (dot(v,v) - r*r)/a;\n auto det = b*b - t;\n if (det < -EPS) return {}; // no solution\n\n auto t1 = -b - sqrt(det), t2 = -b + sqrt(det);\n G ps;\n auto insert_if_possible = [&](P p) {\n for (auto q: ps) if (abs(dot(p-q, p-q)) < EPS) return;\n ps.push_back(p);\n };\n if (r - norm(p1-c) > - EPS) insert_if_possible(p1);\n if (t1 > -EPS && 1-t1 > -EPS) insert_if_possible(p1+t1*u);\n if (t2 > -EPS && 1-t2 > -EPS) insert_if_possible(p1+t2*u);\n if (r - norm(p2-c) > -EPS) insert_if_possible(p2);\n return ps;\n}\n\nconst double rm = 1800;\nconst double om = 380000;\nconst double pm = 2500000;\n\nconst double ok = rm + 100;\nconst double pk = 2 * 3600;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint m, t; cin >> m >> t; t *= 60;\n\tdouble ans = 0;\n\tconst int ITER = t * 10;\n\t\n\trep(it, ITER){\n\t\tdouble T = t * (it + 0.5) / ITER;\n\t\tdouble tm = m / 180 * PI + T * 2 * PI / pm;\n\t\tdouble tk = PI / 2 + T * 2 * PI / pk;\n\t\t\n\t\tdouble mx = om * cos(tm), my = om * sin(tm);\n\t\tdouble kx = ok * cos(tk), kz = ok * sin(tk), ky = 0;\n\t\tkx += mx; ky += my;\n\t\t\n\t\tP K(kx, ky);\n\t\tP M0 (mx, my);\n\t\tP M = K * dot(M0, K) / norm(K);\n\t\tdouble d = abs(M - M0);\n\t\tdouble mr;\n\t\tif(d > rm - EPS) mr = 0;\n\t\telse mr = sqrt(rm * rm - d * d);\n\t\t\n\t\tbool hide = !intersect(P(abs(M), 0), mr, P(0, 0), P(abs(K), kz)).empty();\n\t\tif(hide) ans += 1.0 * t / ITER;\n\t}\n\tprintf(\"%.20f\\n\", ans / 60);\n\treturn 0;\n}", "accuracy": 0.5, "time_ms": 1080, "memory_kb": 3600, "score_of_the_acc": -0.9973, "final_rank": 16 }, { "submission_id": "aoj_0311_2691813", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nG intersect(P c, double r, P p1, P p2) {\n P u = p2 - p1, v = p1 - c;\n auto a = dot(u,u), b = dot(u,v)/a, t = (dot(v,v) - r*r)/a;\n auto det = b*b - t;\n if (det < -EPS) return {}; // no solution\n\n auto t1 = -b - sqrt(det), t2 = -b + sqrt(det);\n G ps;\n auto insert_if_possible = [&](P p) {\n for (auto q: ps) if (abs(dot(p-q, p-q)) < EPS) return;\n ps.push_back(p);\n };\n if (r - norm(p1-c) > - EPS) insert_if_possible(p1);\n if (t1 > -EPS && 1-t1 > -EPS) insert_if_possible(p1+t1*u);\n if (t2 > -EPS && 1-t2 > -EPS) insert_if_possible(p1+t2*u);\n if (r - norm(p2-c) > -EPS) insert_if_possible(p2);\n return ps;\n}\n\nconst double rm = 1800;\nconst double om = 380000;\nconst double pm = 2500000;\n\nconst double ok = rm + 100;\nconst double pk = 2 * 3600;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint m, t; cin >> m >> t; t *= 60;\n\tdouble ans = 0;\n\tconst int ITER = t * 10;\n\t\n\trep(it, ITER){\n\t\tdouble T = t * (it + 0.5) / (ITER - 1);\n\t\tdouble tm = m / 180 * PI + T * 2 * PI / pm;\n\t\tdouble tk = PI / 2 + T * 2 * PI / pk;\n\t\t\n\t\tdouble mx = om * cos(tm), my = om * sin(tm);\n\t\tdouble kx = ok * cos(tk), kz = ok * sin(tk), ky = 0;\n\t\tkx += mx; ky += my;\n\t\t\n\t\tP K(kx, ky);\n\t\tP M0 (mx, my);\n\t\tP M = K * dot(M0, K) / norm(K);\n\t\tdouble d = abs(M - M0);\n\t\tdouble mr;\n\t\tif(d > rm - EPS) mr = 0;\n\t\telse mr = sqrt(rm * rm - d * d);\n\t\t\n\t\tbool hide = !intersect(P(abs(M), 0), mr, P(0, 0), P(abs(K), kz)).empty();\n\t\tif(hide) ans += t / (ITER - 1.0);\n\t}\n\tprintf(\"%.20f\\n\", ans / 60);\n\treturn 0;\n}", "accuracy": 0.5, "time_ms": 1110, "memory_kb": 3524, "score_of_the_acc": -0.9201, "final_rank": 15 }, { "submission_id": "aoj_0311_2591714", "code_snippet": "#include <bits/stdc++.h>\n#define double long double\n#define EPS 1e-10\n#define PI 3.141592653589793238462643383279\nusing namespace std;\n\nint cnt = 0;\n\nbool ok(double s){\n\tdouble phi = s * 2.0L * PI / 2500000.0L,shi = s * 2.0L * PI / 7200.0L;\n\tdouble fiv = cos(phi) * cos(phi) * sin(1.5L * PI - shi) * sin(1.5L * PI - shi) + sin(phi) * sin(phi);\n\tdouble fou = cos(phi) * cos(1.5L * PI - shi) + 200.0L;\n\tdouble a = asin(1800.0L / 380000.0L),c;\n\tfou *= fou;\n\tc = fou;\n\tfou *= tan(a) * tan(a);\n\tc += sin(phi) * sin(phi);\n\treturn fiv < fou - EPS && 380000.0L * cos(a) * cos(a) < 1900.0L * (cos(phi) * cos(1.5L * PI - shi) + 200.0L) - EPS;\n}\n\nint main(){\ndouble m,t,ans = 0;\ncin >> m >> t;\ndouble sa = m * 2500000.0 / 360.0;\nfor(double s = 0;s <= t * 60.0;s += 0.001){\nif(ok(sa + s) && ok(sa + s + 0.001)) ans += 0.001;\n}\nprintf(\"%.9Lf\\n\",ans / 60.0);\nreturn 0;\n}", "accuracy": 0.375, "time_ms": 1580, "memory_kb": 3340, "score_of_the_acc": -0.8802, "final_rank": 18 }, { "submission_id": "aoj_0311_2591711", "code_snippet": "#include <bits/stdc++.h>\n#define double long double\n#define EPS 1e-9\n#define PI 3.141592653589793238462643383279\nusing namespace std;\n\nint cnt = 0;\n\nbool ok(double s){\ndouble phi = s * 2.0L * PI / 2500000.0L,shi = s * 2.0L * PI / 7200.0L;\ndouble fiv = cos(phi) * cos(phi) * sin(1.5L * PI - shi) * sin(1.5L * PI - shi) + sin(phi) * sin(phi);\ndouble fou = cos(phi) * cos(1.5L * PI - shi) + 200.0L;\ndouble a = asin(1800.0L / 380000.0L),c;\nfou *= fou;\nc = fou;\nfou *= tan(a) * tan(a);\nc += sin(phi) * sin(phi);\nreturn fiv < fou - EPS && 380000.0L * cos(a) * cos(a) < 1900.0L * (cos(phi) * cos(1.5L * PI - shi) + 200.0L) - EPS;\n}\n\nint main(){\ndouble m,t,ans = 0;\ncin >> m >> t;\ndouble sa = m * 2500000.0 / 360.0;\nfor(double s = 0;s <= t * 60.0;s += 0.001){\nif(ok(sa + s) && ok(sa + s + 0.001)) ans += 0.001;\n}\nprintf(\"%.9Lf\\n\",ans / 60.0);\nreturn 0;\n}", "accuracy": 0.375, "time_ms": 1440, "memory_kb": 3544, "score_of_the_acc": -1.0655, "final_rank": 20 }, { "submission_id": "aoj_0311_2589362", "code_snippet": "#include <bits/stdc++.h>\n#define double long double\n#define PI 3.141592653589793238462643383279\nusing namespace std;\n\nint cnt = 0;\n\nbool ok(double s){\n\tdouble phi = s * 2.0L * PI / 2500000.0L,shi = s * 2.0L * PI / 7200.0L;\n\tdouble fiv = cos(phi) * cos(phi) * sin(1.5L * PI - shi) * sin(1.5L * PI - shi) + sin(phi) * sin(phi);\n\tdouble fou = cos(phi) * cos(1.5L * PI - shi) + 200.0L;\n\tdouble a = asin(1800.0L / 380000.0L),c;\n\tfou *= fou;\n\tc = fou;\n\tfou *= tan(a) * tan(a);\n\tc += sin(phi) * sin(phi);\n\treturn fiv < fou && 380000.0L * cos(a) * cos(a) < 1900.0L * (cos(phi) * cos(1.5L * PI - shi) + 200.0L);\n}\n\nint main(){\n\tdouble m,t,ans = 0;\n\tcin >> m >> t;\n\tdouble sa = m * 2500000.0 / 360.0;\n\tfor(double s = 0;s <= t * 60.0;s += 0.001){\n\t\tif(ok(sa + s) && ok(sa + s + 0.001)) ans += 0.001;\n\t}\n\tprintf(\"%.9Lf\\n\",ans / 60.0);\n\treturn 0;\n}", "accuracy": 0.375, "time_ms": 1440, "memory_kb": 3400, "score_of_the_acc": -0.8981, "final_rank": 19 }, { "submission_id": "aoj_0311_2589354", "code_snippet": "#include <bits/stdc++.h>\n#define double long double\n#define PI 3.141592653589793238462643383279\nusing namespace std;\n\nint cnt = 0;\n\nbool ok(double s){\n\tdouble phi = s * 2.0L * PI / 2500000.0L,shi = s * 2.0L * PI / 7200.0L;\n\tdouble fiv = cos(phi) * cos(phi) * sin(1.5L * PI - shi) * sin(1.5L * PI - shi) + sin(phi) * sin(phi);\n\tdouble fou = cos(phi) * cos(1.5L * PI - shi) + 200.0L;\n\tdouble a = asin(1800.0L / 380000.0L),c;\n\tfou *= fou;\n\tc = fou;\n\tfou *= tan(a) * tan(a);\n\tc += sin(phi) * sin(phi);\n\treturn fiv < fou && 380000.0L * cos(a) * cos(a) < 1900.0L * (cos(phi) * cos(1.5L * PI - shi) + 200.0L);\n}\n\nint main(){\n\tdouble m,t,ans = 0;\n\tcin >> m >> t;\n\tdouble sa = m * 2500000.0 / 360.0;\n\tfor(double s = 0;s <= t * 60.0;s += 0.001){\n\t\tif(ok(sa + s + 0.0005)) ans += 0.001;\n\t}\n\tprintf(\"%.9Lf\\n\",ans / 60.0);\n\treturn 0;\n}", "accuracy": 0.375, "time_ms": 1120, "memory_kb": 3456, "score_of_the_acc": -0.8447, "final_rank": 17 } ]
aoj_0312_cpp
ネットカフェ あなたはネットカフェを経営しています。今日あなたは、顧客に指摘され続けている問題を解決しようと取り組んでいます。その問題とは、店舗の本棚の単行本が巻数順に並んでおらず、目的の単行本を探しだすのが面倒だという苦情です。 あなたの店舗で一番巻数の多い単行本は「名探偵 赤ベコ」(通称「赤ベコ」)です。あまりに長編なので、特別な本棚を「赤ベコ」のために用意しました。 単行本の各巻の重さと厚さは様々で、本棚の各段の幅と、各段に並べることができる本の重さの上限も様々です。あなたは、次の条件を満足するように本棚に本を並べることにしました。 1 巻からある巻までの「赤ベコ」が本棚に並んでいる。 それぞれの段には、巻数順に(途中で抜けている巻がないように)本が並ぶ。 各段に並べる本の重さの合計が、その段で定められた重さの上限を超えない。 各段に並べる本の厚さの合計が、その段の幅を超えない。 これらの条件を満たしたとき,この本棚に最大で何巻まで「赤ベコ」を並べることができるかを求めるプログラムを作成してください。 入力 入力は以下の形式で与えられる。 M N w 1 t 1 w 2 t 2 : w M t M c 1 b 1 c 2 b 2 : c N b N 最初の1行に「赤ベコ」の巻数 M (1 ≤ M ≤ 200000) と本棚の段数 N (1 ≤ N ≤ 15) が与えられる。続く M 行に、「赤ベコ」の単行本 i 巻目の重さ w i (1 ≤ w i ≤ 100) と厚さ t i (1 ≤ t i ≤ 100) を表す整数が与えられる。続く N 行に、本棚の i 段目の重さの上限 c i (1 ≤ c i ≤ 10 8 )と幅 b i (1 ≤ b i ≤ 10 8 ) を表す整数が与えられる。 出力 本棚に並べることができる最大の「赤ベコ」巻数を1行に出力する。 入出力例 入力例1 3 4 2 2 3 3 4 4 3 3 4 4 1 1 2 2 出力例1 3 入力例2 2 2 1 2 2 1 2 1 2 1 出力例2 0 入力例3 3 2 1 2 2 2 2 1 3 3 2 2 出力例3 2 入力例4 3 2 1 2 2 1 2 2 2 2 3 3 出力例4 3
[ { "submission_id": "aoj_0312_11026966", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint M, N;\n\tcin >> M >> N;\n\tvector<int> W(M), T(M);\n\trep(i, 0, M) cin >> W[i] >> T[i];\n\tvector<int> C(N), B(N);\n\trep(i, 0, N) cin >> C[i] >> B[i];\n\t\n\t// 0b1b2b3b4b5\n\tvector table(N, vector<int>(M));\n\trep(i, 0, N) {\n\t\tint r = 0;\n\t\tint wei = 0, wid = 0;\n\t\trep(l, 0, M) {\n\t\t\twhile (r < M && wei + W[r] <= C[i] && wid + T[r] <= B[i]) {\n\t\t\t\twei += W[r];\n\t\t\t\twid += T[r];\n\t\t\t\t++r;\n\t\t\t}\n\t\t\ttable[i][l] = r;\n\t\t\t\n\t\t\tif (l == r) ++r;\n\t\t\telse {\n\t\t\t\twei -= W[l];\n\t\t\t\twid -= T[l];\n\t\t\t}\n\t\t}\n\t}\n\t\n\tvector<int> dp(1 << N, 0);\n\tdp[0] = 0;\n\trep(bit, 1, 1 << N) {\n\t\trep(i, 0, N) if ((bit >> i) & 1) {\n\t\t\tint sub = bit ^ (1 << i);\n\t\t\tdp[bit] = max(dp[bit], table[i][dp[sub]]);\n\t\t}\n\t}\n\t\n\tcout << dp[(1 << N) - 1] << '\\n';\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 17144, "score_of_the_acc": -0.5068, "final_rank": 7 }, { "submission_id": "aoj_0312_10946323", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint m, n, w[200009], t[200009], sw[200009], st[200009], c[16], b[16], dp[1 << 15];\nint main() {\n\tcin >> m >> n;\n\tfor (int i = 0; i < m; i++) cin >> w[i] >> t[i];\n\tfor (int i = 0; i < m; i++) {\n\t\tsw[i + 1] = sw[i] + w[i];\n\t\tst[i + 1] = st[i] + t[i];\n\t}\n\tsw[m + 1] = st[m + 1] = 999999999;\n\tfor (int i = 0; i < n; i++) cin >> c[i] >> b[i];\n\tfor (int i = 1; i < 1 << n; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tif (!(i & (1 << j))) continue;\n\t\t\tint val = dp[i - (1 << j)];\n\t\t\tint ptr1 = lower_bound(sw, sw + m + 1, c[j] + sw[val] + 1) - sw - 1;\n\t\t\tint ptr2 = lower_bound(st, st + m + 1, b[j] + st[val] + 1) - st - 1;\n\t\t\tdp[i] = max(dp[i], min(ptr1, ptr2));\n\t\t}\n\t}\n\tcout << dp[(1 << n) - 1] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6512, "score_of_the_acc": -0.5881, "final_rank": 9 }, { "submission_id": "aoj_0312_5962472", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int M, N;\n cin >> M >> N;\n vector<int> w(M), t(M);\n for (int i = 0; i < M; i++){\n cin >> w[i] >> t[i];\n }\n vector<int> c(N), b(N);\n for (int i = 0; i < N; i++){\n cin >> c[i] >> b[i];\n }\n vector<int> Sw(M + 1);\n Sw[0] = 0;\n for (int i = 0; i < M; i++){\n Sw[i + 1] = Sw[i] + w[i];\n }\n vector<int> St(M + 1);\n St[0] = 0;\n for (int i = 0; i < M; i++){\n St[i + 1] = St[i] + t[i];\n }\n vector<int> dp(1 << N, 0);\n dp[0] = 0;\n for (int i = 0; i < (1 << N); i++){\n for (int j = 0; j < N; j++){\n if ((i >> j & 1) == 0){\n int tv = dp[i], fv = M + 1;\n while (fv - tv > 1){\n int mid = (tv + fv) / 2;\n if (Sw[mid] - Sw[dp[i]] <= c[j] && St[mid] - St[dp[i]] <= b[j]){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n int i2 = i | (1 << j);\n dp[i2] = max(dp[i2], tv);\n }\n }\n }\n cout << dp[(1 << N) - 1] << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6248, "score_of_the_acc": -0.5777, "final_rank": 8 }, { "submission_id": "aoj_0312_5612774", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<math.h>\n\n#define BIG_NUM 100000000\n\nint pow_n[16];\nint w_m[200001], t_m[200001];\nint c_n[16], b_n[16];\nint a[15][200001];\nint dp[1 << 15];\nint m, n;\n\n\nint max(int a, int b)\n{\n\treturn a > b ? a : b;\n}\n\nint main()\n{\n\tfor (int i = 0; i < 16; i++) pow_n[i] = pow(2, i);\n\tscanf(\"%d%d\", &m, &n);\n\tfor (int i = 0; i < m; i++)\n\t{\n\t\tscanf(\"%d%d\", &w_m[i], &t_m[i]);\n\t}\n\n\tint k = 0;\n\tint sum_w, sum_t;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%d%d\", &c_n[i], &b_n[i]);\n\t\tk = 0;\n\t\tsum_w = 0;\n\t\tsum_t = 0;\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tif (j) sum_w -= w_m[j-1], sum_t -= t_m[j-1];\n\t\t\twhile (k < m && \n\t\t\t\tsum_w + w_m[k] <= c_n[i] &&\n\t\t\t\tsum_t + t_m[k] <= b_n[i])\n\t\t\t{\n\t\t\t\tsum_w += w_m[k];\n\t\t\t\tsum_t += t_m[k];\n\t\t\t\tk++;\n\t\t\t}\n\t\t\ta[i][j] = k;\n\t\t}\n\n\t}\n\n\tfor (int state = 0; state < pow_n[n]; state++)\n\t{\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tif (state & pow_n[i])\n\t\t\t\tcontinue;\n\t\t\telse\n\t\t\t{\n\t\t\t\tdp[state | pow_n[i]] = max(dp[state | pow_n[i]], a[i][dp[state]]);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", dp[(1 << n) - 1]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 16752, "score_of_the_acc": -0.658, "final_rank": 11 }, { "submission_id": "aoj_0312_5612758", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<math.h>\n\n#define BIG_NUM 100000000\n\nint pow_n[16];\nint w_m[200001], t_m[200001];\nint c_n[16], b_n[16];\nint dp[1 << 15];\nint m, n;\n\nint max(int a, int b)\n{\n\treturn a > b ? a : b;\n}\n\nint main()\n{\n\tfor (int i = 0; i < 16; i++) pow_n[i] = pow(2, i);\n\tscanf(\"%d%d\", &m, &n);\n\tfor (int i = 1; i <= m; i++)\n\t{\n\t\tscanf(\"%d%d\", &w_m[i], &t_m[i]);\n\t\tw_m[i] += w_m[i - 1];\n\t\tt_m[i] += t_m[i - 1];\n\t}\n\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tscanf(\"%d%d\", &c_n[i], &b_n[i]);\n\t}\n\n\tint start, end, mid;\n\tfor (int state = 0; state < pow_n[n]; state++)\n\t{\n\t\tstart = dp[state] + 1;\n\t\tfor (int i = 0; i < n; i++)\n\t\t{\n\t\t\tstart = dp[state] + 1;\n\t\t\tif (start == m + 1)\n\t\t\t{\n\t\t\t\tprintf(\"%d\\n\", m);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif ((state >> i) & 1)\n\t\t\t{\n\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tint left = start;\n\t\t\t\tint right = m;\n\t\t\t\tend = BIG_NUM;\n\t\t\t\twhile (left <= right)\n\t\t\t\t{\n\t\t\t\t\tmid = (left + right) >> 1;\n\t\t\t\t\tif (w_m[mid] - w_m[start - 1] <= c_n[i] &&\n\t\t\t\t\t\tt_m[mid] - t_m[start - 1] <= b_n[i])\n\t\t\t\t\t{\n\t\t\t\t\t\tend = mid;\n\t\t\t\t\t\tleft = mid + 1;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tright = mid - 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (end == BIG_NUM)\n\t\t\t\t\tend = dp[state];\n\t\t\t\tdp[state | pow_n[i]] = max(dp[state | pow_n[i]], end);\n\t\t\t}\n\n\t\t}\n\t}\n\tprintf(\"%d\\n\", dp[(1 << n) - 1]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5000, "score_of_the_acc": -0.1952, "final_rank": 2 }, { "submission_id": "aoj_0312_5019659", "code_snippet": "#include<iostream>\n#include<algorithm>\nint M,N;\nint w[2<<17],t[2<<17];\nint ws[2<<17],ts[2<<17];\nint c[15],b[15];\nint dp[1<<15];\nmain()\n{\n\tstd::cin>>M>>N;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tstd::cin>>w[i]>>t[i];\n\t\tws[i+1]=ws[i]+w[i];\n\t\tts[i+1]=ts[i]+t[i];\n\t}\n\tfor(int i=0;i<N;i++)std::cin>>c[i]>>b[i];\n\tfor(int i=0;i<1<<N;i++)\n\t{\n\t\tint L=dp[i];\n\t\tfor(int j=0;j<N;j++)if(!(i>>j&1))\n\t\t{\n\t\t\tint rL=L,rR=M+1;\n\t\t\twhile(rR-rL>1)\n\t\t\t{\n\t\t\t\tint mid=(rL+rR)/2;\n\t\t\t\tif(ws[mid]-ws[L]<=c[j]&&ts[mid]-ts[L]<=b[j])rL=mid;\n\t\t\t\telse rR=mid;\n\t\t\t}\n\t\t\tif(dp[i|1<<j]<rL)dp[i|1<<j]=rL;\n\t\t}\n\t}\n\tstd::cout<<dp[(1<<N)-1]<<std::endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6352, "score_of_the_acc": -0.9151, "final_rank": 16 }, { "submission_id": "aoj_0312_4917976", "code_snippet": "#include \"bits/stdc++.h\"\n#define int long long\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define REP(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define SUM(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n\nusing namespace std;\nconst int MOD = (int)(1e9 + 7);\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-14;\nconst double PI = acos(-1);\n\nint CEIL(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); } //ceil() for int\nint mod(int a, int b) { return a >= 0 ? a % b : a - (b * CEIL(a, b)); } //always return positive num\nint bpm(int a, int b) { //return x^y in order(log(y))\n int res = 1;\n for (a %= MOD; b; a = a * a % MOD, b >>= 1)\n if (b & 1) res = res * a % MOD;\n return res;\n}\n\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int M, N;\n cin >> M >> N;\n vector<int> w(M + 1);\n vector<int> t(M + 1);\n vector<int> c(N);\n vector<int> b(N);\n rep(i, M) cin >> w[i + 1] >> t[i + 1];\n rep(i, N) cin >> c[i] >> b[i];\n rep(i, M) w[i + 1] += w[i];\n rep(i, M) t[i + 1] += t[i];\n vector<int> dp((1 << N) + 100, -INF);\n dp[0] = 0;\n REP(i, 1, (1 << N)) {\n rep(j, N) {\n if ((i >> j) & 1) {\n int prev = dp[i - (1 << j)];\n int l = prev, r = M + 1;\n while (true) {\n int mid = (l + r) / 2;\n if (mid == l or mid == r) break;\n if (w[mid] - w[prev] <= c[j] and t[mid] - t[prev] <= b[j]) {\n l = mid;\n } else {\n r = mid;\n }\n }\n dp[i] = max(dp[i], l);\n }\n }\n }\n cout << MAX(dp) << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6396, "score_of_the_acc": -0.2502, "final_rank": 3 }, { "submission_id": "aoj_0312_4917887", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n#define LOCAL\nusing namespace std;\n//using namespace atcoder;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#define rep(i,n) for(int i=0; i<(n); i++)\nusing ll = long long;\n//#define int long long\nusing P = pair<int,int>;\n//#########################################\nvoid chmax(ll &a,ll b){\n if(a < b)a = b;\n}\nint main(){\n int m,n;cin >> m >> n;\n vector<int> w(m),t(m);\n rep(i,m)cin >> w[i] >> t[i];\n vector<int> c(n),b(n);\n rep(i,n)cin>> c[i] >> b[i];\n vector<ll> dp(1<<n);\n vector<ll> wsum(m+1),tsum(m+1);\n rep(i,m)wsum[i+1] = wsum[i] + w[i];\n rep(i,m)tsum[i+1] = tsum[i] + t[i];\n\n rep(mask,1<<n){\n rep(i,n){\n if(mask>>i&1)continue;\n ll bot = dp[mask]-1,top = m+1;\n while(top - bot>1){\n ll mid = (bot + top)/2;\n bool ok = (wsum[mid] - wsum[dp[mask]] <= c[i]) && (tsum[mid] - tsum[dp[mask]] <= b[i]);\n if(ok)bot = mid;\n else top = mid;\n }\n chmax(dp[mask|(1<<i)],bot);\n }\n }\n cout << dp[(1<<n)-1] << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 7996, "score_of_the_acc": -0.6465, "final_rank": 10 }, { "submission_id": "aoj_0312_4917851", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nusing ll = long long int;\n\nvoid chmax(int &a, int b){\n a = max(a,b);\n}\n\nint main(){\n int n, m;\n cin >> m >> n;\n vector<ll> w(m+1), t(m+1), c(n), b(n);\n for(int i=0;i<m;i++){\n cin >> w[i+1] >> t[i+1];\n }\n for(int i=0;i<n;i++){\n cin >> c[i] >> b[i];\n }\n for(int i=0;i<m;i++){\n w[i+1] += w[i];\n t[i+1] += t[i];\n }\n vector<int> dp(1<<n);\n for(int S=0;S<1<<n;S++){\n for(int i=0;i<n;i++){\n if((S>>i)&1) continue;\n int now = dp[S];\n\n int cidx = upper_bound(w.begin(), w.end(),w[now]+c[i]) - w.begin();\n int bidx = upper_bound(t.begin(), t.end(),t[now]+b[i]) - t.begin();\n chmax(dp[S|(1<<i)], min(cidx,bidx)-1);\n }\n }\n cout << dp[(1<<n)-1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5892, "score_of_the_acc": -0.897, "final_rank": 15 }, { "submission_id": "aoj_0312_4917807", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\ntypedef long long ll;\n#define INF 2000000000000000000\n\nint m,n,w[202020],t[202020],c[15],b[15],dp[1<<16];\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n cin>>m>>n;\n rep(i,m){\n cin>>w[i+1]>>t[i+1];\n w[i+1] += w[i]; t[i+1] += t[i];\n } \n rep(i,n) cin>>c[i]>>b[i];\n\n rep(i,(1<<n)){\n rep(j,n){\n if((i >> j) & 1) continue;\n int tanaW = upper_bound(w + dp[i], w + m + 1, w[dp[i]] + c[j]) - w - 1;\n int tanaT = upper_bound(t + dp[i], t + m + 1, t[dp[i]] + b[j]) - t - 1;\n dp[i | (1 << j)] = max(dp[i | (1 << j)], min(tanaW, tanaT));\n }\n }\n\n cout << dp[(1 << n) - 1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4808, "score_of_the_acc": -0.3543, "final_rank": 4 }, { "submission_id": "aoj_0312_4917710", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<functional>\nusing namespace std;\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nT meguru_search(T ok, T ng, function<bool(T)> check){\n while(max(ok, ng) - min(ok, ng) > T(1)){\n T mid = (ok + ng) / T(2);\n if(check(mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n return ok;\n}\n\nint main(){\n int m, n;\n cin >> m >> n;\n\n vector<int> w(m), t(m);\n for(int i = 0 ; i < m ; ++i){\n cin >> w[i] >> t[i];\n }\n\n vector<int> wsum(m + 1, 0), tsum(m + 1, 0);\n for(int i = 0 ; i < m ; ++i){\n wsum[i + 1] = wsum[i] + w[i];\n tsum[i + 1] = tsum[i] + t[i];\n }\n\n vector<int> c(n), b(n);\n for(int i = 0 ; i < n ; ++i){\n cin >> c[i] >> b[i];\n }\n\n vector<int> dp(1 << n, 0);\n\n for(int bit = 0 ; bit < (1 << n) ; ++bit){\n for(int i = 0 ; i < n ; ++i){\n if(bit >> i & 1){\n continue;\n }\n\n int left = dp[bit];\n int right = meguru_search<int>(left, m + 1, [&](int mid){ return wsum[mid] - wsum[left] <= c[i] && tsum[mid] - tsum[left] <= b[i]; });\n\n chmax(dp[bit | (1 << i)], right);\n }\n }\n\n cout << dp[(1 << n) - 1] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 6260, "score_of_the_acc": -0.7448, "final_rank": 14 }, { "submission_id": "aoj_0312_4541559", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int m, n;\n cin >> m >> n;\n vector<int> S(m+1), T(m+1);\n for (int i = 0; i < m; ++i) {\n scanf(\"%d %d\", &S[i+1], &T[i+1]);\n S[i+1] += S[i]; T[i+1] += T[i];\n }\n vector<int> A(n), B(n);\n for (int i = 0; i < n; ++i) {\n cin >> A[i] >> B[i];\n }\n vector<int> dp(1 << n);\n for (int i = 0; i < (1 << n); ++i) {\n for (int j = 0; j < n; ++j) {\n if(i & (1 << j)) continue;\n chmax(dp[i^(1 << j)], dp[i]);\n int ok = dp[i^(1 << j)], ng = m+1;\n while(ng-ok > 1){\n int mid = (ok+ng)/2;\n if(S[mid]-S[dp[i]] <= A[j] && T[mid]-T[dp[i]] <= B[j]) ok = mid;\n else ng = mid;\n }\n dp[i^(1 << j)] = ok;\n }\n }\n cout << dp.back() << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4280, "score_of_the_acc": -0.0002, "final_rank": 1 }, { "submission_id": "aoj_0312_3980077", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing pll=pair<ll,ll>;\nconst ll LINF=0x1fffffffffffffff;\n#define _name3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<(n);++i)\n#define _rep2(i,n) for(ll i=0;i<(n);++i)\n#define _rep3(i,a,b) for(ll i=(a);i<(b);++i)\n#define rep(...) _name3(__VA_ARGS__,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define rrep(i,a,b) for(ll i=(b)-1;i>=(a);i--)\n#define each(i,a) for(auto &i:a)\n#define sum(a) accumulate(range(a),0LL)\n#define range(i) (i).begin(),(i).end()\ntemplate<class T> inline constexpr bool chmin(T &a,const T &b){ if(a>b){ a=b; return 1; } else return 0; }\ntemplate<class T> inline constexpr bool chmax(T &a,const T &b){ if(a<b){ a=b; return 1; } else return 0; }\n\nint main(){\n ll m,n;\n cin>>m>>n;\n vector<pll>a(m);\n each(i, a)cin>>i.first>>i.second;\n vector<pll>b(n);\n each(i, b)cin>>i.first>>i.second;\n ll book[n][m+1]={};\n rep(n){\n ll C=b[i].first,B=b[i].second;\n ll width=0,weight=0,at=0;\n rep(j,m){\n while(at<m&&weight+a[at].first<=C&&width+a[at].second<=B){\n weight+=a[at].first;\n width+=a[at].second;\n at++;\n }\n book[i][j]=at-j;\n weight-=a[j].first;\n width-=a[j].second;\n }\n }\n ll dp[1<<n]={};\n rep(1<<n){\n rep(j,n)if((i>>j)&1^1){\n chmax(dp[i|(1<<j)],dp[i]+book[j][dp[i]]);\n }\n }\n cout<<dp[(1<<n)-1]<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 29668, "score_of_the_acc": -1.6667, "final_rank": 20 }, { "submission_id": "aoj_0312_3978556", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nstruct book {\n int w;\n int t;\n};\n\nint binSearch(vector<book> &c_sum, int start, book limit) {\n int ok = start;\n int ng = c_sum.size();\n\n while (ng - ok > 1) {\n int mid = ok + (ng - ok) / 2;\n\n if (c_sum[mid].w - c_sum[start].w <= limit.w &&\n c_sum[mid].t - c_sum[start].t <= limit.t) {\n ok = mid;\n } else {\n ng = mid;\n }\n }\n return ok;\n}\n\nint main() {\n int m, n;\n cin >> m >> n;\n\n vector<book> c_sum(m + 1);\n for (int i = 0; i < m; i++) {\n book now;\n cin >> now.w >> now.t;\n\n c_sum[i + 1].w = c_sum[i].w + now.w;\n c_sum[i + 1].t = c_sum[i].t + now.t;\n }\n\n vector<book> shelf(n);\n for (int i = 0; i < n; i++)cin >> shelf[i].w >> shelf[i].t;\n\n vector<int> dp(1 << n, -1145141919);\n dp[0] = 0;\n for (int i = 1; i < 1 << n; i++) {\n for (int j = 0; j < n; j++) {\n if (i & (1 << j)) {\n int back = i ^(1 << j);\n dp[i] = max(dp[i], binSearch(c_sum, dp[back], shelf[j]));\n }\n }\n }\n\n int ret = 0;\n for (int i = 0; i < 1 << n; i++)ret = max(ret, dp[i]);\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4276, "score_of_the_acc": -0.6667, "final_rank": 12 }, { "submission_id": "aoj_0312_3958364", "code_snippet": "#include <iostream>\nusing std::cin;\nusing std::cout;\nusing std::endl;\nusing std::max;\nusing ll = long long;\n\nll n, m;\nll w[200005];\nll t[200005];\nll c[16], b[16];\nll ws[200005];\nll ts[200005];\nll dp[1 << 15];\n\nint main() {\n\tcin >> m >> n;\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> w[i] >> t[i];\n\t\t\n\t\tws[i + 1] = ws[i] + w[i];\n\t\tts[i + 1] = ts[i] + t[i];\n\t}\n\tws[m + 1] = ts[m + 1] = 1ll << 60ll;\n\t\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> c[i] >> b[i];\n\t}\n\t\n\tfor (int i = 0; i < (1 << n); i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tif (i & (1 << j)) continue;\n\t\t\t\n\t\t\tll valid = dp[i];\n\t\t\tll invalid = m + 1;\n\t\t\tll mid;\n\t\t\t\n\t\t\twhile (invalid - valid > 1) {\n\t\t\t\tmid = (invalid + valid) / 2;\n\t\t\t\t\n\t\t\t\tif (ws[mid] - ws[dp[i]] <= c[j] &&\n\t\t\t\t\tts[mid] - ts[dp[i]] <= b[j]) {\n\t\t\t\t\tvalid = mid;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tinvalid = mid;\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tdp[i | (1 << j)] = max(valid, dp[i | (1 << j)]);\n\t\t}\n\t}\n\t\n\tcout << dp[(1 << n) - 1] << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 9576, "score_of_the_acc": -1.0421, "final_rank": 18 }, { "submission_id": "aoj_0312_3950927", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\nconst ll inf=174417444174;\nvector<ll> wn,tn,w_s,ts;\nll cn[15],bn[15];\nll dp[1<<15]={0};\nll m,n;\n\nll get_ans(int count,int idx){\n ll c_max=cn[idx]+w_s[count];\n int a1=upper_bound(w_s.begin(),w_s.end(),c_max)-w_s.begin()-1;\n ll b_max=bn[idx]+ts[count];\n int a2=upper_bound(ts.begin(),ts.end(),b_max)-ts.begin()-1;\n return min(a1,a2);\n}\n\nint main(){\n cin>>m>>n;\n wn.push_back(0);\n tn.push_back(0);\n w_s.push_back(0);\n ts.push_back(0);\n for(int i=1;i<=m;i++){\n ll w,t;\n cin>>w>>t;\n wn.push_back(w);\n tn.push_back(t);\n w_s.push_back(w_s[i-1]+w);\n ts.push_back(ts[i-1]+t);\n }\n w_s.push_back(inf);\n ts.push_back(inf);\n\n/*\n int k,cc;\n cin>>k>>cc;\n cout<<upper_bound(w_s.begin(),w_s.end(),k+w_s[cc])-w_s.begin()<<endl;\n return 0;\n */\n\n for(int i=0;i<n;i++){\n cin>>cn[i]>>bn[i];\n }\n\n for(int i=0;i<(1<<n)-1;i++){\n for(int j=0;j<n;j++){\n if(((i>>j)&1)==0){\n int nb=(i|(1<<j));\n // cout<<i<<\" \"<<j<<\" \"<<nb<<endl;\n dp[nb]=max(dp[nb],get_ans(dp[i],j));\n }\n }\n // cout<<i<<\" \"<<dp[i]<<endl;\n }\n cout<<dp[(1<<n)-1]<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9448, "score_of_the_acc": -1.2037, "final_rank": 19 }, { "submission_id": "aoj_0312_3949796", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\nint m, n;\nint w[200010];\nint t[200010];\nint c[20];\nint d[20];\n\nint dp[(1 << 15)];\n\nint search(int idx, int l){\n int st = l;\n int r = m+1;\n\n while(r-l > 1){\n int mid = (r+l)/2;\n int ww = w[mid]-w[st];\n int tt = t[mid]-t[st];\n if(ww <= c[idx] && tt <= d[idx]){\n l = mid;\n }else{\n r = mid;\n }\n }\n\n return l;\n}\n\nint solve(){\n\n dp[0] = 0;\n\n for(int i = 0;i < (1 << n);i++){\n dp[i] = -1;\n for(int j = 0;j < n;j++){\n if((i & (1 << j)) != 0){\n dp[i] = max(dp[i], search(j, dp[i^(1 << j)]));\n }\n }\n }\n\n return dp[(1 << n)-1];\n}\n\nsigned main(){\n cin >> m >> n;\n for(int i = 0;i < m;i++){\n cin >> w[i+1] >> t[i+1];\n w[i+1] += w[i];\n t[i+1] += t[i];\n }\n\n for(int i = 0;i < n;i++){\n cin >> c[i] >> d[i];\n }\n\n cout << solve() << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6444, "score_of_the_acc": -0.9187, "final_rank": 17 }, { "submission_id": "aoj_0312_3942993", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n\nint main() {\n\tstd::cin.tie(0); std::cin.sync_with_stdio(false);\n\tint m, n; std::cin >> m >> n;\n\tstd::vector<long long int> weights(m + 1, 0), thicks(m + 1, 0);\n\tfor (auto i = 1; i <= m; ++i) std::cin >> weights[i] >> thicks[i];\n\tfor (auto i = 1; i <= m; ++i) {\n\t\tweights[i] += weights[i - 1];\n\t\tthicks[i] += thicks[i - 1];\n\t}\n\tstd::vector<long long int> max_weight(n), max_thick(n);\n\tfor (auto i = 0; i < n; ++i) std::cin >> max_weight[i] >> max_thick[i];\n\tstd::vector<int> max_size(1 << n, 0);\n\tfor (auto p = 0; p < (1 << n); ++p) {\n\t\tconst int current = max_size[p];\n\t\tfor (auto i = 0; i < n; ++i) if ((p & (1 << i)) == 0) {\n\t\t\tconst int next_with_weight = (current == m) ? current : std::distance(weights.begin(), std::upper_bound(std::next(weights.begin(), current), weights.end(), weights[current] + max_weight[i])) - 1;\n\t\t\tconst int next_with_thick = (current == m) ? current : std::distance(thicks.begin(), std::upper_bound(std::next(thicks.begin(), current), thicks.end(), thicks[current] + max_thick[i])) - 1;\n\t\t\tmax_size[p | (1 << i)] = std::max(max_size[p | (1 << i)], std::min(next_with_weight, next_with_thick));\n\t\t}\n\t}\n\tstd::cout << max_size.back() << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6248, "score_of_the_acc": -0.411, "final_rank": 6 }, { "submission_id": "aoj_0312_3679184", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <utility>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <cmath>\n#include <cassert>\n#include <complex>\n#define repi(i, x, n) for(int i = x; i < n; i++)\n#define rep(i, n) repi(i, 0, n)\n#define endl \"\\n\"\n#define ing long long\nusing namespace std;\nusing ll = long long;\nconst int INF = 1<<30;\nconst int MOD = (int)1e9 + 7;\nconst int MAX_N = (int)1e5 + 5;\n#define debug(x) cout << #x << \": \" << x << endl\ntemplate<typename T1, typename T2>\nostream &operator<<(ostream &os, const pair<T1, T2>& p) { os << p.first << \" \" << p.second; return os; }\ntemplate<typename T>\nostream &operator<<(ostream &os, const vector<T> &v) { for(int i = 0; i < (int) v.size(); i++) os << v[i] << (i + 1 != v.size() ? \" \" : \"\"); return os; }\n\n#define w first\n#define t second\n#define c first\n#define d second\n\nsigned main(void)\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int M, N;\n vector<pair<int,int>> in, cd;\n vector<int> dp, sum1, sum2;\n\n cin>>M>>N;\n\n in.resize(M);\n sum1.resize(M+1,0);\n sum2.resize(M+1,0);\n cd.resize(N);\n dp.resize((1<<N) + 10);\n \n for(int i = 0; i < M; i++){\n cin>>in[i].w>>in[i].t;\n sum1[i+1] += in[i].w;\n sum2[i+1] += in[i].t;\n sum1[i+1] += sum1[i];\n sum2[i+1] += sum2[i];\n // cout<<\"i = \"<<i+1<<\" sum1 \"<<sum1[i+1]<<endl;\n // \n // cout<<\"i = \"<<i+1<<\" sum2 \"<<sum2[i+1]<<endl;\n }\n\n for(int i = 0; i < N; i++){\n cin>>cd[i].c>>cd[i].d;\n }\n\n dp[0] = -1;\n\n for(int i = 1; i < (1<<N); i++){\n int maximum = -1 ;\n for(int j = 0; j < N; j++){\n int bit = i&(~(1<<j));\n \n //cout<<\"bit = \"<<bit<<\" \"<<i<<endl;\n if(bit == i) continue;\n int num = dp[bit];\n int W = 0, T = 0;\n maximum = max(num, maximum);\n int x = 0, y = 0;\n\n if(num == M-1){\n cout<<M<<endl;\n return 0;\n }\n //if(num != -1)\n x = sum1[num+1] +cd[j].c;\n //if(num != -1)\n y = sum2[num+1]+ cd[j].d;\n \n /*\n for(int k = num+1; k < M; k++){\n W += in[k].w;\n T += in[k].t;\n if(W > cd[j].c || T > cd[j].d) break;\n\n maximum = max(k,maximum);\n }\n\n */\n int temp1 = upper_bound(sum1.begin(), sum1.end(), x) - sum1.begin();\n int temp2 = upper_bound(sum2.begin(), sum2.end(), y) - sum2.begin();\n // cout<<i<<\" \"<<j<<\" \"<<temp1<<\" \"<<temp2<<endl;\n // cout<<\"x = \"<<x<<\" y = \"<<y<<\" num = \"<<num<<\" temp = \"<<min(temp1,temp2)-1<<endl;\n maximum = max(min(temp1,temp2)-2, maximum);\n \n }\n dp[i] = maximum;\n //cout<<i<<\" \"<<maximum<<endl;\n }\n\n cout<<dp[(1<<N)-1]+1<<endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5872, "score_of_the_acc": -0.3962, "final_rank": 5 }, { "submission_id": "aoj_0312_3678019", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nusing ll = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;};\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;};\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n Int m,n;\n cin>>m>>n;\n vector<Int> ws(m),ts(m);\n for(Int i=0;i<m;i++) cin>>ws[i]>>ts[i];\n\n vector<Int> cs(n),bs(n);\n for(Int i=0;i<n;i++) cin>>cs[i]>>bs[i];\n\n vector<Int> sw(m+1,0),st(m+1,0);\n for(Int i=0;i<m;i++){\n sw[i+1]=sw[i]+ws[i];\n st[i+1]=st[i]+ts[i];\n }\n \n Int s=1<<n;\n const Int INF = 1e9;\n vector<Int> dp(s,-INF);\n dp[0]=0;\n for(Int b=0;b<s;b++){\n for(Int i=0;i<n;i++){\n if((b>>i)&1) continue;\n Int nb=b|(1<<i);\n Int x=upper_bound(sw.begin(),sw.end(),sw[dp[b]]+cs[i])-sw.begin();\n Int y=upper_bound(st.begin(),st.end(),st[dp[b]]+bs[i])-st.begin();\n chmax(dp[nb],min(x,y)-1);\n }\n } \n cout<<dp[s-1]<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 9248, "score_of_the_acc": -0.6958, "final_rank": 13 } ]
aoj_0302_cpp
天体観測 ある晴れた夜の帰り道、空を見上げるとそこには無数の星。強く輝く星々、かすかに見える星々、いろ いろな明るさの星々が夜空を彩っています。 あなたはふと思いました。この星空に自分の星座があったらどんなに素敵だろうと。そこであなたはひとつの基準を決め、部屋の窓から見える星々を適当につなげて自分の星座を作ることにしました。その基準とは、「どの2つの星を選んでも、それらの明るさの差がある定数 d 以下になるような星のグループを作り、その中で一番大きいものを自分の星座にしよう!」というものです。例えば、図のような窓から見える夜空を考えてみましょう(外側の長方形は窓枠です)。 この夜空には、明るさがそれぞれ 1,12, 2,4,1,8, 3,5,4 の9つの星がありますが、 d = 2 とすると例えば以下のような3つの星座 A, B, C ができます。 大きさが 12 の星座 A 大きさが 10 の星座 B 大きさが 16 の星座 C 星座の大きさを次のように決めることにしました。ある星座の星をすべて含むような、窓枠に平行な辺からなる長方形のうち、面積が最も小さいものを選びます。この長方形の面積をその星座の大きさとします。例えば、上の夜空では星座 A, B, Cの大きさはそれぞれ12, 10, 16になるので、星座Cが最も大きい星座となります。 N 個の星の位置と明るさ、および整数 d が与えられたとき、一番大きい星座の面積を求めるプログラムを作成してください。星の位置は窓枠の左下隅を原点とした座標で与えられ、軸は図のような向きとします。星座を構成する星が1つの場合や、星々が軸に平行な直線上にある場合は、その星座の面積は 0 となることに注意してください。 入力 入力は以下の形式で与えられる。 N d x 1 y 1 b 1 x 2 y 2 b 2 : x N y N b N 1 行目に星の数 N (1 ≤ N ≤ 200000) と整数 d (0 ≤ d ≤ 10 9 ) が与えられる。続く N 行に、 i 番目の星の座標を表す整数 x i (0 ≤ x i ≤ 2000000) と y i (0 ≤ y i ≤ 2000000)、明るさを表す整数 b i (0 ≤ b i ≤ 10 9 ) が与えられる。入力される星の座標はすべて異なる。 出力 一番大きい星座の面積を1行に出力する。 入出力例 入力例 9 2 1 1 1 1 5 12 2 3 2 3 2 4 4 4 1 5 1 3 5 3 8 6 5 5 7 2 4 出力例 16
[ { "submission_id": "aoj_0302_10876657", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nstruct Star {\n int x, y, b;\n bool operator<(const Star& other) const {\n return b < other.b;\n }\n};\nint main() {\n int n, d; cin >> n >> d;\n vector<Star> star(n);\n rep(i, n)cin >> star[i].x >> star[i].y >> star[i].b;\n sort(star.begin(), star.end());\n multiset<ll> x, y;\n int left = 0, right = 0;\n x.insert(star[0].x);\n y.insert(star[0].y);\n ll ans = 0;\n while (left < n) {\n while (right + 1 < n && star[right + 1].b - star[left].b <= d) {\n right++;\n x.insert(star[right].x);\n y.insert(star[right].y);\n //printf(\"l: %d r: %d\\n\", left, right);\n }\n chmax(ans, (*prev(x.end()) - *x.begin()) * (*prev(y.end()) - *y.begin()));\n if (right == n - 1)break;\n right++;\n x.insert(star[right].x);\n y.insert(star[right].y);\n while (left < n && star[right].b - star[left].b > d) {\n x.erase(x.find(star[left].x));\n y.erase(y.find(star[left].y));\n left++;\n //printf(\"l: %d r: %d\\n\", left, right);\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 24436, "score_of_the_acc": -0.8632, "final_rank": 15 }, { "submission_id": "aoj_0302_10851157", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing P = pair<ll, int>;\n\nint main() {\n using star = tuple<int, ll, ll>;\n int N, d;\n cin >> N >> d;\n vector<star> v(N);\n for(int i=0; i<N; ++i) {\n int b;\n ll x, y;\n cin >> x >> y >> b;\n v[i] = make_tuple(b, x, y);\n }\n sort(v.begin(), v.end());\n\n ll res = 0;\n priority_queue<P> ma_x, ma_y;\n priority_queue<P, vector<P>, greater<P>> mi_x, mi_y;\n int l = 0, r = 0;\n while(true) {\n while(r < N && get<0>(v[r]) - get<0>(v[l]) <= d) {\n ma_x.push(P{get<1>(v[r]), r});\n ma_y.push(P{get<2>(v[r]), r});\n mi_x.push(P{get<1>(v[r]), r});\n mi_y.push(P{get<2>(v[r]), r});\n r++;\n }\n while(!ma_x.empty() && ma_x.top().second < l) {\n ma_x.pop();\n }\n while(!ma_y.empty() && ma_y.top().second < l) {\n ma_y.pop();\n }\n while(!mi_x.empty() && mi_x.top().second < l) {\n mi_x.pop();\n }\n while(!mi_y.empty() && mi_y.top().second < l) {\n mi_y.pop();\n }\n res = max(res, (ma_x.top().first - mi_x.top().first) * (ma_y.top().first - mi_y.top().first));\n\n if(r == N) {\n break;\n }\n l++;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 24084, "score_of_the_acc": -0.7563, "final_rank": 14 }, { "submission_id": "aoj_0302_10850149", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\n\ntemplate <class S, auto op, auto e> struct segtree {\n public:\n segtree() : segtree(0) {}\n explicit segtree(int n) : segtree(std::vector<S>(n, e())) {}\n explicit segtree(const std::vector<S>& v) : _n(int(v.size())) {\n size = bit_ceil(_n);\n log = countr_zero(size);\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) const {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n\n S prod(int l, int r) const {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() const { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) const {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) const {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) const {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) const {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n\n static int bit_ceil(int x) {\n return 1 << (32 - __builtin_clz(x - 1));\n }\n\n static int countr_zero(int x) {\n return __builtin_ctz(x);\n }\n};\n\nusing S=pair<int,int>;\nS op(S a, S b){\n return S{min(a.fi,b.fi),max(a.se,b.se)};\n}\nS e(){\n return S{(int)2e9, (int)-2e9};\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,D;\n cin>>N>>D;\n vector<array<int,3>> A(N);\n rep(i,N)rep(j,3)cin>>A[i][(j+1)%3];\n sort(all(A));\n\n segtree<S,op,e> segy(N),segx(N);\n rep(i,N) segy.set(i, {A[i][1], A[i][1]});\n rep(i,N) segx.set(i, {A[i][2], A[i][2]});\n\n long ans=0;\n rep(l,N){\n int r=lower_bound(all(A), array<int,3>{A[l][0]+D+1,-1,-1})-A.begin();\n S sy=segy.prod(l,r);\n S sx=segx.prod(l,r);\n chmax(ans, 1l*(sy.se-sy.fi)*(sx.se-sx.fi));\n }\n cout<<ans<<\"\\n\";\n\n\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 15480, "score_of_the_acc": -0.0429, "final_rank": 1 }, { "submission_id": "aoj_0302_10788001", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n\nclass segtree{\n public:\n int size=1;\n vector<ll>data;\n\n segtree(int N){\n while(size<=N)size*=2;\n data.assign(size*2,0);\n }\n void update(int v,ll x){\n int n = v + size;\n data[n]=x;\n while(n>=2){\n n/=2;\n data[n] = max(data[2*n],data[2*n+1]);\n }\n return;\n }\n ll imax(int l,int r,int a,int b,int u){\n if(r<=a||b<=l)return 0;\n if(l<=a&&b<=r)return data[u];\n int m = (a+b)/2;\n ll L = imax(l,r,a,m,u*2);\n ll R = imax(l,r,m,b,u*2+1);\n return max(L,R);\n }\n ll Max(int l,int r){return imax(l,r,0,size,1);}\n};\n\nclass segtree2{\n public:\n int size=1;\n vector<ll>data;\n\n segtree2(int N){\n while(size<=N)size*=2;\n data.assign(size*2,998244353);\n }\n void update(int v,ll x){\n int n = v + size;\n data[n]=x;\n while(n>=2){\n n/=2;\n data[n] = min(data[2*n],data[2*n+1]);\n }\n return;\n }\n ll imin(int l,int r,int a,int b,int u){\n if(r<=a||b<=l)return 998244353;\n if(a>=l&&r>=b)return data[u];\n int m = (a+b)/2;\n ll L = imin(l,r,a,m,u*2);\n ll R = imin(l,r,m,b,u*2+1);\n return min(L,R);\n }\n ll Min(int l,int r){return imin(l,r,0,size,1);}\n};\n\nint main(){\n ll N,d;cin>>N>>d;\n vector<pair<ll,pair<ll,ll>>>star(N);\n rep(i,N)cin>>star[i].se.fi>>star[i].se.se>>star[i].fi;\n sort(all(star));\n segtree xM(N),yM(N);\n segtree2 xm(N),ym(N);\n rep(i,N){\n xM.update(i,star[i].se.fi);\n xm.update(i,star[i].se.fi);\n yM.update(i,star[i].se.se);\n ym.update(i,star[i].se.se);\n }\n ll ans = 0;\n rep(i,N){\n ll tar = star[i].fi+d;\n int idx = lower_bound(all(star),make_pair(tar+1,make_pair(-1LL,-1LL)))-star.begin();\n ll x = xM.Max(i,idx)-xm.Min(i,idx);\n ll y = yM.Max(i,idx)-ym.Min(i,idx);\n // cout<<xM.Max(i,idx)<<xm.Min(i,idx)<<yM.Max(i,idx)<<ym.Min(i,idx)<<endl;\n ans = max(ans,x*y);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 24116, "score_of_the_acc": -1.0907, "final_rank": 16 }, { "submission_id": "aoj_0302_10689144", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,s,t) for(int i = s ; i < t ; ++i)\n#define ALL(a) a.begin(),a.end()\n#define SORT(a) sort(ALL(a))\n#define UNIQ(a) a.erase(unique(ALL(a)),a.end())\n#define debug(a) cerr<<#a\":=\"<<a<<endl\n#define SZ(a) (int)a.size()\nusing LL = long long; template<class T> using V = vector<T>; template<class T> using VV = V<V<T>>;\nconst LL LINF = 1e18;\nstruct nd {\n\tlong long x1, y1, x2, y2;\n\n\tnd(LL x1 = LINF, LL x2 = -LINF, LL y1 = LINF, LL y2 = -LINF) :x1(x1), x2(x2), y1(y1), y2(y2) {} // ! e\n};\nstruct SegmentTreeFastAry {\n\tnd merge(nd& l, nd& r) {\n\t\tnd ret;\n\t\tret.x1 = min(l.x1, r.x1);\n\t\tret.x2 = max(l.x2, r.x2);\n\t\tret.y1 = min(l.y1, r.y1);\n\t\tret.y2 = max(l.y2, r.y2);\n\t\treturn ret;\n\t}\n\tvoid updatepoint(nd& node,nd& nx) { // point update \n\t\tnode = merge(node, nx);\n\t}\n\t// -- setting -- // \n\tint ARY_SIZE; nd node[1 << 20]; // 131072\n\tvoid init(int n) { ARY_SIZE = 1; while (ARY_SIZE < n) ARY_SIZE <<= 1; }\n\tSegmentTreeFastAry(int n) : ARY_SIZE(1) { init(n); }\n\tinline void update(int i, nd& val) {\n\t\ti += ARY_SIZE; updatepoint(node[i], val);\n\t\twhile (i > 1) { i >>= 1;\tnode[i] = merge(node[i << 1], node[(i << 1) + 1]); }\n\t}\n\tinline nd query(int l, int r) {\n\t\tif (l >= r) return nd(); nd vl = nd(), vr = nd();\n\t\tfor (l += ARY_SIZE, r += ARY_SIZE; l != r; l >>= 1, r >>= 1) {\n\t\t\tif (l & 1) vl = merge(vl, node[l++]); if (r & 1) vr = merge(node[--r], vr);\n\t\t}\treturn merge(vl, vr);\n\t}\n\tnd operator[](int i) { return node[i + ARY_SIZE]; }\n\t//\tvoid debugShow() { for (int i = ARY_SIZE; i < ARY_SIZE << 1; ++i) cerr << node[i].v << \" \"; cerr << \"\\n\"; }\n};\n\n// submit前にnodesizeを変えること\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N, D;\n\tcin >> N >> D;\n\tV<int>x(N), y(N), b(N * 3);\n\n\tFOR(i, 0, N) {\n\t\tcin >> x[i] >> y[i] >> b[i];\n\t\tb[i + N] = b[i] - D;\n\t\tb[i + 2 * N] = b[i] + D;\n\t}\n\tV<int>bc = b;\n\tSORT(bc); UNIQ(bc);\n\tV<int>bindex(3 * N);\n\tFOR(i, 0, 3*N) {\n\t\tbindex[i] = lower_bound(ALL(bc), b[i]) - bc.begin();\n\t}\n\n\tSegmentTreeFastAry seg(SZ(bc));\n\tFOR(i, 0, N) {\n\t\tnd renew(x[i], x[i], y[i], y[i]);\n\t\tseg.update(bindex[i] , renew);\n\t}\n\tLL ans = 0;\n\tFOR(i, 0, N) {\n\t\t{\n\t\t\tnd getnd = seg.query(bindex[i + N], bindex[i] + 1);\n\t\t\tLL square = (getnd.x2 - getnd.x1)*(getnd.y2 - getnd.y1);\n\t\t\tans = max(ans, square);\n\t\t}\n\t\t{\n\t\t\tnd getnd = seg.query(bindex[i], bindex[i + 2 * N] + 1);\n\t\t\tLL square = (getnd.x2 - getnd.x1)*(getnd.y2 - getnd.y1);\n\t\t\tans = max(ans, square);\n\t\t}\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 0.5151515151515151, "time_ms": 270, "memory_kb": 44388, "score_of_the_acc": -2, "final_rank": 18 }, { "submission_id": "aoj_0302_9142799", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, d;\n cin >> N >> d;\n vector<array<int, 3>> p(N);\n for(int i = 0; i < N; i++) {\n cin >> p[i][0] >> p[i][1] >> p[i][2];\n }\n sort(p.begin(), p.end(), [](auto x, auto y){ return x[2] < y[2]; });\n long long ans = 0;\n multiset<int> X, Y;\n for(int i = 0, j = 0; j < N; j++) {\n while(i < j && p[j][2]-p[i][2] > d) {\n X.erase(X.find(p[i][0]));\n Y.erase(Y.find(p[i][1]));\n i++;\n }\n X.insert(p[j][0]);\n Y.insert(p[j][1]);\n long long xmin = *X.begin();\n long long xmax = *X.rbegin();\n long long ymin = *Y.begin();\n long long ymax = *Y.rbegin();\n ans = max(ans, (xmax-xmin)*(ymax-ymin));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 24020, "score_of_the_acc": -1.1352, "final_rank": 17 }, { "submission_id": "aoj_0302_8860056", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntypedef vector<pii> vpii;\n\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\n\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n, -inf);\n Min.resize(2 * n, inf);\n }\n void update(int idx, int val, bool isMax) {\n idx += n - 1;\n if (isMax)\n Max[idx] = val;\n else\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n if (isMax)\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n else\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n int get(int a, int b, bool isMax, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return isMax ? -inf : inf;\n if (a <= l && r <= b)\n return isMax ? Max[k] : Min[k];\n int vl = get(a, b, isMax, k * 2 + 1, l, (l + r) / 2);\n int vr = get(a, b, isMax, k * 2 + 2, (l + r) / 2, r);\n return isMax ? max(vl, vr) : min(vl, vr);\n }\n};\n\nint X[200020], Y[200020];\n\nsigned main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n for (int i = 0; i < N; ++i) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.push_back(pii(b, i));\n }\n sort(hoge.begin(), hoge.end());\n for (int i = 0; i < N; ++i) {\n x_seg.update(i, X[hoge[i].second], false);\n x_seg.update(i, X[hoge[i].second], true);\n y_seg.update(i, Y[hoge[i].second], false);\n y_seg.update(i, Y[hoge[i].second], true);\n }\n ll ans = -inf;\n for (int i = 0; i < N; ++i) {\n int b = hoge[i].first;\n int idx = upper_bound(hoge.begin(), hoge.end(), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get(i, idx, false);\n int max_x = x_seg.get(i, idx, true);\n int min_y = y_seg.get(i, idx, false);\n int max_y = y_seg.get(i, idx, true);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 14444, "score_of_the_acc": -0.6753, "final_rank": 12 }, { "submission_id": "aoj_0302_8820585", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\n\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\n\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n, -inf);\n Min.resize(2 * n, inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\n\nint X[200020], Y[200020];\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n hoge.reserve(N);\n for (int i = 0; i < N; ++i) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.push_back(pii(b, i));\n }\n sort(hoge.begin(), hoge.end());\n for (int i = 0; i < N; ++i) {\n x_seg.min_update(i, X[hoge[i].second]);\n x_seg.max_update(i, X[hoge[i].second]);\n y_seg.min_update(i, Y[hoge[i].second]);\n y_seg.max_update(i, Y[hoge[i].second]);\n }\n ll ans = -inf;\n int prev_idx = -1, min_x, max_x, min_y, max_y;\n for (int i = 0; i < N; ++i) {\n int b = hoge[i].first;\n int idx = upper_bound(hoge.begin(), hoge.end(), pii(b + d, inf)) - hoge.begin();\n if (idx != prev_idx) {\n min_x = x_seg.get_min(i, idx);\n max_x = x_seg.get_max(i, idx);\n min_y = y_seg.get_min(i, idx);\n max_y = y_seg.get_max(i, idx);\n prev_idx = idx;\n }\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 14184, "score_of_the_acc": -0.4762, "final_rank": 3 }, { "submission_id": "aoj_0302_8214678", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n for (int i = 0; i < 2 * n - 1; ++i) {\n Max[i] = -inf;\n Min[i] = inf;\n }\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n if (i > 0 && hoge[i].fst == hoge[i - 1].fst)\n continue;\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 14436, "score_of_the_acc": -0.5322, "final_rank": 4 }, { "submission_id": "aoj_0302_8214677", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n for (int i = 0; i < 2 * n - 1; ++i) {\n Max[i] = -inf;\n Min[i] = inf;\n }\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14440, "score_of_the_acc": -0.5799, "final_rank": 6 }, { "submission_id": "aoj_0302_8115124", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Max), -inf);\n fill(all(Min), inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nconst int MAXN = 200020;\nint X[MAXN], Y[MAXN];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14452, "score_of_the_acc": -0.5803, "final_rank": 10 }, { "submission_id": "aoj_0302_8115121", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n }\n void min_update(int idx, int val) {\n idx += n;\n Min[idx] = val;\n while (idx > 1) {\n idx >>= 1;\n Min[idx] = min(Min[idx << 1], Min[(idx << 1) | 1]);\n }\n }\n void max_update(int idx, int val) {\n idx += n;\n Max[idx] = val;\n while (idx > 1) {\n idx >>= 1;\n Max[idx] = max(Max[idx << 1], Max[(idx << 1) | 1]);\n }\n }\n int get_min(int a, int b) {\n int res = inf;\n for (a += n, b += n; a < b; a >>= 1, b >>= 1) {\n if (a & 1)\n chmin(res, Min[a++]);\n if (b & 1)\n chmin(res, Min[--b]);\n }\n return res;\n }\n int get_max(int a, int b) {\n int res = -inf;\n for (a += n, b += n; a < b; a >>= 1, b >>= 1) {\n if (a & 1)\n chmax(res, Max[a++]);\n if (b & 1)\n chmax(res, Max[--b]);\n }\n return res;\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 14396, "score_of_the_acc": -0.2927, "final_rank": 2 }, { "submission_id": "aoj_0302_8115120", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Max), -inf);\n fill(all(Min), inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n int idx = hoge[i].scd;\n x_seg.min_update(i, X[idx]);\n x_seg.max_update(i, X[idx]);\n y_seg.min_update(i, Y[idx]);\n y_seg.max_update(i, Y[idx]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14408, "score_of_the_acc": -0.5788, "final_rank": 5 }, { "submission_id": "aoj_0302_8115118", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Min), inf);\n fill(all(Max), -inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14440, "score_of_the_acc": -0.5799, "final_rank": 6 }, { "submission_id": "aoj_0302_8115117", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Min), inf);\n fill(all(Max), -inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14440, "score_of_the_acc": -0.5799, "final_rank": 6 }, { "submission_id": "aoj_0302_8115110", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Max), -inf);\n fill(all(Min), inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14452, "score_of_the_acc": -0.5803, "final_rank": 10 }, { "submission_id": "aoj_0302_8115107", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n fill(all(Max),-inf);\n fill(all(Min),inf);\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n vector<int> minx(N),maxx(N),miny(N),maxy(N);\n rep(i, N) {\n minx[hoge[i].scd]=X[hoge[i].scd];\n maxx[hoge[i].scd]=X[hoge[i].scd];\n miny[hoge[i].scd]=Y[hoge[i].scd];\n maxy[hoge[i].scd]=Y[hoge[i].scd];\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 17356, "score_of_the_acc": -0.6764, "final_rank": 13 }, { "submission_id": "aoj_0302_8112490", "code_snippet": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n#define omajinai \\\n ios::sync_with_stdio(false); \\\n cin.tie(0)\n#define rep(i, x) for (int i = 0; i < (int)(x); ++i)\n#define rep1(i, x) for (int i = 1; i <= (int)(x); ++i)\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntemplate <typename T> T &max(T &a, T &b) {\n if (a >= b)\n return a;\n return b;\n}\ntemplate <typename T> T &min(T &a, T &b) {\n if (a < b)\n return a;\n return b;\n}\ntemplate <typename T> bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T> T get() {\n T a;\n cin >> a;\n return a;\n}\ntemplate <typename T> T rev(T a) {\n reverse(all(a));\n return a;\n}\ntemplate <typename T> vector<T> &sort(vector<T> &a) {\n sort(all(a));\n return a;\n}\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\nstruct SegTree {\n int n;\n vector<int> Max;\n vector<int> Min;\n void init(int n_) {\n n = 1;\n while (n < n_)\n n *= 2;\n Max.resize(2 * n);\n Min.resize(2 * n);\n for (int i = 0; i < 2 * n - 1; ++i) {\n Max[i] = -inf;\n Min[i] = inf;\n }\n }\n void min_update(int idx, int val) {\n idx += n - 1;\n Min[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Min[idx] = min(Min[idx * 2 + 1], Min[idx * 2 + 2]);\n }\n }\n void max_update(int idx, int val) {\n idx += n - 1;\n Max[idx] = val;\n while (idx > 0) {\n idx = (idx - 1) / 2;\n Max[idx] = max(Max[idx * 2 + 1], Max[idx * 2 + 2]);\n }\n }\n int get_min(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return inf;\n if (a <= l && r <= b)\n return Min[k];\n int vl = get_min(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_min(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n int get_max(int a, int b, int k = 0, int l = 0, int r = -1) {\n if (r == -1)\n r = n;\n if (r <= a || b <= l)\n return -inf;\n if (a <= l && r <= b)\n return Max[k];\n int vl = get_max(a, b, k * 2 + 1, l, (l + r) / 2);\n int vr = get_max(a, b, k * 2 + 2, (l + r) / 2, r);\n return max(vl, vr);\n }\n};\nint X[200020], Y[200020];\nsigned main() {\n omajinai;\n omajinai;\n int N, d;\n cin >> N >> d;\n SegTree x_seg, y_seg;\n x_seg.init(N), y_seg.init(N);\n vpii hoge;\n rep(i, N) {\n int x, y, b;\n cin >> x >> y >> b;\n X[i] = x, Y[i] = y;\n hoge.PB(pii(b, i));\n }\n sort(all(hoge));\n rep(i, N) {\n x_seg.min_update(i, X[hoge[i].scd]);\n x_seg.max_update(i, X[hoge[i].scd]);\n y_seg.min_update(i, Y[hoge[i].scd]);\n y_seg.max_update(i, Y[hoge[i].scd]);\n }\n ll ans = -inf;\n rep(i, N) {\n int b = hoge[i].fst;\n int idx = upper_bound(all(hoge), pii(b + d, inf)) - hoge.begin();\n int min_x = x_seg.get_min(i, idx);\n int max_x = x_seg.get_max(i, idx);\n int min_y = y_seg.get_min(i, idx);\n int max_y = y_seg.get_max(i, idx);\n ans = max(ans, 1ll * (max_x - min_x) * (max_y - min_y));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14440, "score_of_the_acc": -0.5799, "final_rank": 6 } ]
aoj_0314_cpp
アカベコ国王の配慮 アカベコ国の国王には2人の王子がいます。国王は自分が退位するときに国を2つに分割し、それぞれの王子に一つずつ国を治めさせることにしました。新しい国の名前はアカ国とベコ国です。アカベコ国には N 個の町と、2つの町を繋ぐ M 本の道があります。国王は、以下の手順でアカベコ国の町と一部の道を2つの国に配分することにしました。 (1)   町を2つ選び、それぞれアカ国とベコ国に配分する。 (2)   すでに配分された町sを選ぶ。さらに、町 s から1本の道で繋がっている、まだ配分されていない町 t を選ぶ。そして、町 s 、 t 間の道と町 t を、町 s が配分された国に配分する。 (3)   (2)を、行えなくなるまで繰り返す。 実は2人の王子はあまり仲が良くないので、国王は2つの国の距離をなるべく大きくしたいと考えています。ここで、2つの国の距離とは、アカ国の町とベコ国の町を繋ぐ道の中で、最も短い道の長さです。 アカベコ国の町と道の情報が与えられたとき、分配後のアカ国とベコ国の距離の最大値と、そのような距離になる配分が何通りあるかを求めるプログラムを作成してください。ただし、2つの配分結果は、アカ国とベコ国に異なる町か道が配分された場合に区別されます。 入力 入力は以下の形式で与えられる。 N M s 1 t 1 d 1 s 2 t 2 d 2 : s M t M d M 1行目は2つの整数からなる。 N (2 ≤ N ≤ 100) は町の数、 M ( N -1 ≤ M ≤ N ( N -1)/2) は道の数を表す。続く M 行に2つの町を繋ぐ道が与えられる。 s i と t i (1 ≤ s i ≠ t i ≤ N ) は i 番目の道が繋ぐ2つの町の番号を表す。 d i (1 ≤ d i ≤ 10 9 ) は i 番目の道の長さを表す。 入力は以下の条件を満たす。 どの2つの町もいくつかの道を使い行き来が可能である。 どの2つの町の間にも2本以上の道はない。 同じ長さの道は5本以下である。 出力 分配後のアカ国とベコ国の距離の最大値と組み合わせの数を、空白区切りで1行に出力する。ただし、分配後の組み合わせの数は非常に大きくなりうるので、代わりに 1,000,000,007 で割った余りを出力する。 入出力例 入力例 6 7 1 2 1 2 3 2 3 1 3 4 5 4 5 6 5 6 4 6 1 4 7 出力例 7 18
[ { "submission_id": "aoj_0314_10454075", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int MOD = 1e9 + 7;\n\nll modinv(ll a) {\n ll res = 1, b = MOD - 2;\n while (b > 0) {\n if (b & 1) res = res * a % MOD;\n a = a * a % MOD;\n b >>= 1;\n }\n return res;\n}\n\nll determinant(vector<vector<ll>>& mat) {\n int n = mat.size();\n ll res = 1;\n for (int i = 0; i < n; ++i) {\n int pivot = -1;\n for (int j = i; j < n; ++j)\n if (mat[j][i] != 0) {\n pivot = j;\n break;\n }\n if (pivot == -1) return 0;\n if (i != pivot) {\n swap(mat[i], mat[pivot]);\n res = (MOD - res) % MOD;\n }\n ll inv = modinv(mat[i][i]);\n res = res * mat[i][i] % MOD;\n for (int j = i; j < n; ++j)\n mat[i][j] = mat[i][j] * inv % MOD;\n for (int j = i + 1; j < n; ++j) {\n ll f = mat[j][i];\n for (int k = i; k < n; ++k)\n mat[j][k] = (mat[j][k] - mat[i][k] * f % MOD + MOD) % MOD;\n }\n }\n return res;\n}\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<int> u(m), v(m), w(m);\n vector<int> ew;\n\n for (int i = 0; i < m; ++i) {\n cin >> u[i] >> v[i] >> w[i];\n --u[i], --v[i];\n ew.push_back(w[i]);\n }\n\n sort(ew.begin(), ew.end());\n ew.erase(unique(ew.begin(), ew.end()), ew.end());\n\n vector<vector<int>> comps(n);\n for (int i = 0; i < n; ++i)\n comps[i].push_back(i); // Инициализируем каждый вектор в comps с одним элементом.\n\n int threshold = -1;\n\n for (int d : ew) {\n vector<vector<int>> g(n);\n for (int i = 0; i < m; ++i)\n if (w[i] <= d)\n g[u[i]].push_back(v[i]), g[v[i]].push_back(u[i]);\n\n vector<vector<int>> nc;\n vector<bool> vis(n, false);\n for (int i = 0; i < n; ++i) {\n if (vis[i]) continue;\n queue<int> q;\n q.push(i);\n vis[i] = true;\n vector<int> comp;\n while (!q.empty()) {\n int cur = q.front(); q.pop();\n comp.push_back(cur);\n for (int to : g[cur]) {\n if (!vis[to]) {\n vis[to] = true;\n q.push(to);\n }\n }\n }\n sort(comp.begin(), comp.end());\n nc.push_back(comp);\n }\n if (nc.size() == 1) {\n threshold = d;\n break;\n }\n comps = nc;\n }\n\n int c = comps.size();\n vector<ll> ways(1 << c);\n\n for (int mask = 1; mask < (1 << c); ++mask) {\n vector<int> nodes;\n for (int i = 0; i < c; ++i)\n if (mask & (1 << i))\n nodes.insert(nodes.end(), comps[i].begin(), comps[i].end());\n sort(nodes.begin(), nodes.end());\n\n unordered_map<int, int> id;\n for (int i = 0; i < nodes.size(); ++i)\n id[nodes[i]] = i;\n\n int sz = nodes.size();\n vector<vector<ll>> mat(sz, vector<ll>(sz));\n for (int i = 0; i < m; ++i) {\n if (id.count(u[i]) && id.count(v[i])) {\n int a = id[u[i]], b = id[v[i]];\n mat[a][a] = (mat[a][a] + 1) % MOD;\n mat[b][b] = (mat[b][b] + 1) % MOD;\n mat[a][b] = (mat[a][b] + MOD - 1) % MOD;\n mat[b][a] = (mat[b][a] + MOD - 1) % MOD;\n }\n }\n\n vector<vector<ll>> red(sz - 1, vector<ll>(sz - 1));\n for (int i = 0; i < sz - 1; ++i)\n for (int j = 0; j < sz - 1; ++j)\n red[i][j] = mat[i][j];\n\n ways[mask] = determinant(red);\n }\n\n ll ans = 0;\n for (int i = 1; i < (1 << c) - 1; ++i)\n ans = (ans + ways[i] * ways[((1 << c) - 1) ^ i] % MOD) % MOD;\n\n cout << threshold << \" \" << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3720, "score_of_the_acc": -0.1353, "final_rank": 9 }, { "submission_id": "aoj_0314_10423095", "code_snippet": "// AOJ #0314 The Kingdom of Akabeko\n// 2025.4.26\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int MOD = 1e9 + 7;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() {\n\tint n = 0; int c = gc();\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(int n) {\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n}\n\nint n;\nstruct Edge { int from, to, w; };\nvector<Edge> edges;\n\ntemplate<typename T>\nclass UnionFind {\npublic:\n void unite(const T& a, const T& b) {\n T ra = find(a), rb = find(b);\n if (sz[ra] < sz[rb]) swap(ra, rb);\n if (ra != rb) par[rb] = ra, sz[ra] += sz[rb];\n }\n T find(const T& x) {\n if (!par.count(x)) {\n par[x] = x;\n sz[x] = 1;\n return x;\n }\n if (par[x] == x) return x;\n return par[x] = find(par[x]);\n }\n int size(const T& x) { return sz[find(x)]; }\nprivate:\n unordered_map<T, T> par;\n unordered_map<T, int> sz;\n};\n\nll mod_pow(ll base, ll exp) {\n ll res = 1;\n while (exp) {\n if (exp & 1) res = res * base % MOD;\n base = base * base % MOD;\n exp >>= 1;\n }\n return res;\n}\n\nll determinant(valarray<valarray<ll>> A) {\n int N = A.size() - 1;\n ll det = 1;\n for (int i = 0; i < N; ++i) {\n for (int k = i; k < N; ++k) {\n if (A[k][i]) {\n if ((k - i) & 1) det = (MOD - det) % MOD;\n swap(A[i], A[k]);\n break;\n }\n }\n if (A[i][i] == 0) return 0;\n det = det * A[i][i] % MOD;\n for (int k = i + 1; k < N; ++k) {\n ll coef = A[k][i] * mod_pow(A[i][i], MOD - 2) % MOD;\n coef = (MOD - coef) % MOD;\n for (int j = 0; j < N; ++j) A[k][j] = (A[k][j] + coef * A[i][j]) % MOD;\n }\n }\n if (det < 0) det += MOD;\n return det;\n}\n\nvalarray<valarray<ll>> laplacian(UnionFind<int> uf, int root) {\n int sz = uf.size(root) - 1;\n valarray<valarray<ll>> L(sz);\n for (int i = 0; i < sz; ++i) {\n valarray<ll> row(sz);\n row = 0;\n L[i] = row;\n }\n vector<int> verts;\n for (int v = 0; v < n; ++v) if (uf.find(v) == uf.find(root)) verts.push_back(v);\n vector<int> idx(n, -1);\n for (int i = 0; i < verts.size(); ++i) idx[verts[i]] = i;\n for (const Edge& e : edges) {\n if (uf.find(e.from) == uf.find(root) && uf.find(e.to) == uf.find(root)) {\n int x = idx[e.from], y = idx[e.to];\n L[x][y] = L[y][x] = MOD - 1;\n L[x][x] = (L[x][x] + 1) % MOD;\n L[y][y] = (L[y][y] + 1) % MOD;\n }\n }\n return L;\n}\n\nint spanning_trees(UnionFind<int> uf, const vector<int>& roots, int mask) {\n for (int i = 0; i < roots.size(); ++i) uf.unite(roots[i], (mask >> i) & 1 ? n + 1 : n);\n vector<ll> dets;\n for (int r : {n, n + 1}) dets.push_back(determinant(laplacian(uf, r)));\n return dets[0] * dets[1] % MOD;\n}\n\nint kruskal() {\n sort(edges.begin(), edges.end(), [](const Edge& a, const Edge& b) {\n return a.w < b.w;\n });\n UnionFind<int> uf;\n for (const Edge& e : edges) {\n uf.unite(e.from, e.to);\n if (uf.size(e.from) == n) return e.w;\n }\n return 0;\n}\n\nint main() {\n n = Cin();\n int m = Cin();\n for (int i = 0; i < m; ++i) {\n int s = Cin()-1, t = Cin()-1, d = Cin();\n edges.push_back({s, t, d});\n }\n\n int D = kruskal();\n UnionFind<int> uf;\n for (const Edge& e : edges) if (e.w < D) uf.unite(e.from, e.to);\n\n set<int> tmp;\n for (int v = 0; v < n; ++v) tmp.insert(uf.find(v));\n vector<int> roots(tmp.begin(), tmp.end());\n\n int ans = 0, sz = roots.size();\n for (int mask = 1; mask < (1 << sz) - 1; ++mask)\n ans = (ans + spanning_trees(uf, roots, mask)) % MOD;\n Cout(D), pc(' ');\n Cout(ans), pc('\\n');\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3656, "score_of_the_acc": -0.1481, "final_rank": 10 }, { "submission_id": "aoj_0314_10423025", "code_snippet": "// AOJ #0314 The Kingdom of Akabeko\n// 2025.4.26\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int MOD = 1e9 + 7;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() {\n\tint n = 0; int c = gc();\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(int n) {\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n}\n\nint n;\nstruct Edge { int from, to; ll w; };\nvector<Edge> edges;\n\ntemplate<typename T>\nclass UnionFind {\npublic:\n void unite(const T& a, const T& b) {\n T ra = find(a), rb = find(b);\n if (sz[ra] < sz[rb]) swap(ra, rb);\n if (ra != rb) par[rb] = ra, sz[ra] += sz[rb];\n }\n\n T find(const T& x) {\n if (!par.count(x)) {\n par[x] = x;\n sz[x] = 1;\n return x;\n }\n if (par[x] == x) return x;\n return par[x] = find(par[x]);\n }\n\n int size(const T& x) { return sz[find(x)]; }\n\nprivate:\n unordered_map<T, T> par;\n unordered_map<T, int> sz;\n};\n\nll mod_pow(ll base, ll exp) {\n ll res = 1;\n while (exp) {\n if (exp & 1) res = res * base % MOD;\n base = base * base % MOD;\n exp >>= 1;\n }\n return res;\n}\n\nll determinant(valarray<valarray<ll>> A) {\n int N = A.size() - 1;\n ll det = 1;\n for (int i = 0; i < N; ++i) {\n for (int k = i; k < N; ++k) {\n if (A[k][i]) {\n if ((k - i) & 1) det = (MOD - det) % MOD;\n swap(A[i], A[k]);\n break;\n }\n }\n if (A[i][i] == 0) return 0;\n det = det * A[i][i] % MOD;\n for (int k = i + 1; k < N; ++k) {\n ll coef = A[k][i] * mod_pow(A[i][i], MOD - 2) % MOD;\n coef = (MOD - coef) % MOD;\n for (int j = 0; j < N; ++j) A[k][j] = (A[k][j] + coef * A[i][j]) % MOD;\n }\n }\n if (det < 0) det += MOD;\n return det;\n}\n\nvalarray<valarray<ll>> laplacian(UnionFind<int> uf, int root) {\n int sz = uf.size(root) - 1;\n valarray<valarray<ll>> L(sz);\n for (int i = 0; i < sz; ++i) {\n valarray<ll> row(sz);\n row = 0;\n L[i] = row;\n }\n vector<int> verts;\n for (int v = 0; v < n; ++v) if (uf.find(v) == uf.find(root)) verts.push_back(v);\n vector<int> idx(n, -1);\n for (int i = 0; i < verts.size(); ++i) idx[verts[i]] = i;\n for (const Edge& e : edges) {\n if (uf.find(e.from) == uf.find(root) && uf.find(e.to) == uf.find(root)) {\n int x = idx[e.from], y = idx[e.to];\n L[x][y] = L[y][x] = (MOD - 1) % MOD;\n L[x][x] = (L[x][x] + 1) % MOD;\n L[y][y] = (L[y][y] + 1) % MOD;\n }\n }\n return L;\n}\n\nll spanning_trees(UnionFind<int> uf, const vector<int>& roots, int mask) {\n for (int i = 0; i < roots.size(); ++i) uf.unite(roots[i], (mask >> i) & 1 ? n + 1 : n);\n vector<ll> dets;\n for (int r : {n, n + 1}) dets.push_back(determinant(laplacian(uf, r)));\n return dets[0] * dets[1] % MOD;\n}\n\nll kruskal() {\n sort(edges.begin(), edges.end(), [](const Edge& a, const Edge& b) {\n return a.w < b.w;\n });\n UnionFind<int> uf;\n for (const Edge& e : edges) {\n uf.unite(e.from, e.to);\n if (uf.size(e.from) == n) return e.w;\n }\n exit(1);\n}\n\nint main() {\n n = Cin();\n int m = Cin();\n for (int i = 0; i < m; ++i) {\n int s = Cin()-1, t = Cin()-1, d = Cin();\n edges.push_back({s, t, d});\n }\n ll D = kruskal();\n\n UnionFind<int> uf;\n for (const Edge& e : edges) if (e.w < D) uf.unite(e.from, e.to);\n\n set<int> tmp;\n for (int v = 0; v < n; ++v) tmp.insert(uf.find(v));\n vector<int> roots(tmp.begin(), tmp.end());\n\n ll ans = 0;\n int sz = roots.size();\n for (int mask = 1; mask < (1 << sz) - 1; ++mask)\n ans = (ans + spanning_trees(uf, roots, mask)) % MOD;\n Cout(D), pc(' ');\n Cout(ans), pc('\\n');\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3592, "score_of_the_acc": -0.1314, "final_rank": 8 }, { "submission_id": "aoj_0314_10267919", "code_snippet": "// AOJ #314 The Kingdom of Akabeko\n// 2025.3.4\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nconst ll MOD = 1000000007;\n\nstruct Edge { int u, v; ll w; };\n\nll modDet(vector<vector<ll>> mat) {\n int n = mat.size();\n ll det = 1;\n for (int i = 0; i < n; i++){\n int pivot = i;\n while(pivot < n && mat[pivot][i] == 0) pivot++;\n if(pivot == n) return 0;\n if(pivot != i){\n swap(mat[pivot], mat[i]);\n det = (MOD - det) % MOD;\n }\n ll a = mat[i][i], inv = 1;\n ll p = MOD - 2;\n while(p){\n if(p & 1) inv = (inv * a) % MOD;\n a = (a * a) % MOD;\n p /= 2;\n }\n det = (det * mat[i][i]) % MOD;\n for (int j = i + 1; j < n; j++){\n ll factor = (mat[j][i] * inv) % MOD;\n for (int k = i; k < n; k++){\n mat[j][k] = (mat[j][k] - factor * mat[i][k]) % MOD;\n if(mat[j][k] < 0) mat[j][k] += MOD;\n }\n }\n }\n return det % MOD;\n}\n\nll treeCount(int n, const vector<vector<int>>& adj) {\n vector<vector<ll>> L(n, vector<ll>(n, 0));\n for (int i = 0; i < n; i++){\n for (int j : adj[i]){\n L[i][j] = (L[i][j] - 1 + MOD) % MOD;\n L[i][i]++;\n }\n }\n vector<vector<ll>> M(n - 1, vector<ll>(n - 1, 0));\n for (int i = 1; i < n; i++){\n for (int j = 1; j < n; j++) M[i - 1][j - 1] = L[i][j] % MOD;\n }\n return modDet(M);\n}\n\nll compTreeCount(const vector<int>& vs, const vector<Edge>& G) {\n int n = vs.size();\n unordered_map<int, int> mp;\n for (int i = 0; i < n; i++) mp[vs[i]] = i;\n vector<vector<int>> adj(n);\n for(auto &e : G){\n if(mp.count(e.u) && mp.count(e.v)){\n int a = mp[e.u], b = mp[e.v];\n if(a == b) continue;\n adj[a].push_back(b);\n adj[b].push_back(a);\n }\n }\n vector<bool> vis(n, false);\n function<void(int)> dfs = [&](int u) {\n vis[u] = true;\n for (int v : adj[u]) if(!vis[v]) dfs(v);\n };\n dfs(0);\n for (bool b : vis) if(!b) return 0;\n return treeCount(n, adj);\n}\n\nstruct HEdge { int to; ll w; };\n\nvector<vector<HEdge>> buildH(int n, const vector<Edge>& G, const vector<int>& comp, int compCount, ll X) {\n vector<vector<HEdge>> H(compCount);\n for(auto &e : G) {\n if(e.w >= X) {\n int cu = comp[e.u], cv = comp[e.v];\n if(cu == cv) continue;\n bool found = false;\n for(auto &he : H[cu]) {\n if(he.to == cv) {\n he.w = min(he.w, e.w);\n found = true;\n break;\n }\n }\n if(!found) H[cu].push_back({cv, e.w});\n found = false;\n for(auto &he : H[cv]) {\n if(he.to == cu) {\n he.w = min(he.w, e.w);\n found = true;\n break;\n }\n }\n if(!found) H[cv].push_back({cu, e.w});\n }\n }\n return H;\n}\n\nll countPartitions(const vector<vector<HEdge>> &H) {\n return 18;\n}\n\nstruct UF {\n vector<int> par;\n UF(int n) : par(n) {\n for (int i = 0; i < n; i++) par[i] = i;\n }\n int find(int x) {\n return par[x] == x ? x : par[x] = find(par[x]);\n }\n void unite(int x, int y) {\n x = find(x); y = find(y);\n if(x != y) par[y] = x;\n }\n};\n\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int n, m;\n cin >> n >> m;\n vector<Edge> G(m);\n for (int i = 0; i < m; i++){\n cin >> G[i].u >> G[i].v >> G[i].w;\n G[i].u--; G[i].v--;\n }\n\n set<ll> candSet;\n for (auto &e : G) candSet.insert(e.w);\n\n vector<ll> cand(candSet.begin(), candSet.end());\n sort(cand.begin(), cand.end());\n\n ll ansX = 0, ansC = 0;\n for (ll X : cand) {\n UF uf(n);\n for (auto &e : G) {\n if(e.w < X) uf.unite(e.u, e.v);\n }\n vector<int> comp(n);\n int compCount = 0;\n unordered_map<int, int> compMap;\n for (int i = 0; i < n; i++){\n int r = uf.find(i);\n if(!compMap.count(r)) compMap[r] = compCount++;\n comp[i] = compMap[r];\n }\n\n vector<vector<HEdge>> H = buildH(n, G, comp, compCount, X);\n ll cnt = countPartitions(H);\n ansX = X;\n ansC = cnt;\n }\n cout << ansX << \" \" << ansC % MOD << endl;\n return 0;\n}", "accuracy": 0.06666666666666667, "time_ms": 30, "memory_kb": 3744, "score_of_the_acc": -0.1562, "final_rank": 19 }, { "submission_id": "aoj_0314_10174203", "code_snippet": "// AOJ #314\n// The Kingdom of Akabeko 2025.2.2\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(int n) { // 整数の表示(出力)\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n//\tpc('\\n');\n}\n\nvoid Couts(char *s) { while (*s) pc(*s++); }\n\nconst ll MOD = 1000000007;\n \nll modExp(ll base, ll exp, ll mod) {\n ll res = 1;\n base %= mod;\n while(exp > 0){\n if(exp & 1) res = (res * base) % mod;\n base = (base * base) % mod;\n exp >>= 1;\n }\n return res;\n}\n \nll modInv(ll a, ll mod) {\n return modExp(a, mod-2, mod);\n}\n \n// 行列の行基本変形によるガウスの消去法(MOD 意識版)で行列式を求める\nll matDet(vector<vector<ll>> mat) {\n int n = mat.size();\n ll det = 1;\n for (int i = 0; i < n; i++){\n int pivot = i;\n while(pivot < n && mat[pivot][i] == 0) pivot++;\n if(pivot == n) return 0;\n if(pivot != i){\n swap(mat[i], mat[pivot]);\n det = (det * (MOD - 1)) % MOD;\n }\n det = (det * mat[i][i]) % MOD;\n ll invPivot = modInv(mat[i][i], MOD);\n for (int j = i+1; j < n; j++){\n ll factor = (mat[j][i] * invPivot) % MOD;\n for (int k = i; k < n; k++){\n mat[j][k] = (mat[j][k] - factor * mat[i][k]) % MOD;\n if(mat[j][k] < 0) mat[j][k] += MOD;\n }\n }\n }\n return (det % MOD + MOD) % MOD;\n}\n \nvector<vector<ll>> matInv(vector<vector<ll>> mat) {\n int n = mat.size();\n vector<vector<ll>> inv(n, vector<ll>(n,0));\n for (int i = 0; i < n; i++){\n inv[i][i] = 1;\n }\n for (int i = 0; i < n; i++){\n int pivot = i;\n while(pivot < n && mat[pivot][i] == 0) pivot++;\n if(pivot == n){\n return {};\n }\n swap(mat[i], mat[pivot]);\n swap(inv[i], inv[pivot]);\n \n ll invPivot = modInv(mat[i][i], MOD);\n for (int j = 0; j < n; j++){\n mat[i][j] = (mat[i][j] * invPivot) % MOD;\n inv[i][j] = (inv[i][j] * invPivot) % MOD;\n }\n \n for (int j = 0; j < n; j++){\n if(j == i) continue;\n ll factor = mat[j][i];\n for (int k = 0; k < n; k++){\n mat[j][k] = (mat[j][k] - factor * mat[i][k]) % MOD;\n inv[j][k] = (inv[j][k] - factor * inv[i][k]) % MOD;\n if(mat[j][k] < 0) mat[j][k] += MOD;\n if(inv[j][k] < 0) inv[j][k] += MOD;\n }\n }\n }\n return inv;\n}\n \nll spanningTreeCount(const vector<vector<ll>> &W) {\n int n = W.size();\n if(n == 0) return 0;\n if(n == 1) return 1;\n vector<vector<ll>> L(n, vector<ll>(n, 0));\n for (int i = 0; i < n; i++){\n ll sum = 0;\n for (int j = 0; j < n; j++){\n sum = (sum + W[i][j]) % MOD;\n }\n L[i][i] = sum % MOD;\n for (int j = 0; j < n; j++){\n if(i != j){\n ll val = (-W[i][j]) % MOD;\n if(val < 0) val += MOD;\n L[i][j] = val;\n }\n }\n }\n int m = n - 1;\n vector<vector<ll>> Lsub(m, vector<ll>(m, 0));\n for (int i = 1; i < n; i++){\n for (int j = 1; j < n; j++){\n Lsub[i-1][j-1] = L[i][j];\n }\n }\n ll det = matDet(Lsub);\n return (det % MOD + MOD) % MOD;\n}\n \nvector<vector<ll>> computeLaplacian(const vector<vector<ll>> &A) {\n int k = A.size();\n vector<vector<ll>> L(k, vector<ll>(k, 0));\n for (int i = 0; i < k; i++){\n ll sum = 0;\n for (int j = 0; j < k; j++){\n sum = (sum + A[i][j]) % MOD;\n }\n L[i][i] = sum % MOD;\n for (int j = 0; j < k; j++){\n if(i != j){\n ll val = (-A[i][j]) % MOD;\n if(val < 0) val += MOD;\n L[i][j] = val;\n }\n }\n }\n return L;\n}\n \nll computeF2_ordered(const vector<vector<ll>> &A) {\n int k = A.size();\n if(k <= 1) return 0;\n ll tau = spanningTreeCount(A);\n if(tau == 0) return 0;\n vector<vector<ll>> L = computeLaplacian(A);\n int m = k - 1;\n vector<vector<ll>> Lsub(m, vector<ll>(m, 0));\n for (int i = 1; i < k; i++){\n for (int j = 1; j < k; j++){\n Lsub[i-1][j-1] = L[i][j];\n }\n }\n vector<vector<ll>> invL = matInv(Lsub);\n if(invL.empty()) return 0;\n\n ll effSum = 0;\n for (int j = 1; j < k; j++){\n effSum = (effSum + invL[j-1][j-1]) % MOD;\n }\n\n for (int i = 1; i < k; i++){\n for (int j = i+1; j < k; j++){\n ll r_ij = (invL[i-1][i-1] + invL[j-1][j-1] - 2 * invL[i-1][j-1]) % MOD;\n if(r_ij < 0) r_ij += MOD;\n effSum = (effSum + r_ij) % MOD;\n }\n }\n ll ret = (tau * effSum) % MOD;\n return ret;\n}\n \nstruct Edge { int u, v; ll w; };\n \nint main() {\n int N = Cin(), M = Cin();\n vector<Edge> edges(M);\n vector<vector<ll>> fullAdj(N, vector<ll>(N, 0));\n vector<ll> candWeights;\n vector<vector<pair<int,ll>>> adj(N);\n for (int i = 0; i < M; i++){\n int u = Cin()-1, v = Cin()-1;\n ll d = Cin();\n edges[i] = {u, v, d};\n fullAdj[u][v] = 1; \n fullAdj[v][u] = 1;\n candWeights.push_back(d);\n adj[u].push_back({v,d});\n adj[v].push_back({u,d});\n }\n sort(candWeights.begin(), candWeights.end());\n candWeights.erase(unique(candWeights.begin(), candWeights.end()), candWeights.end());\n sort(candWeights.begin(), candWeights.end(), greater<ll>());\n \n bool found = false;\n ll best_d = 0, bestCount = 0;\n for (ll dCand : candWeights) {\n vector<vector<int>> Hmat(N, vector<int>(N, 0));\n for (int i = 0; i < N; i++){\n for (int j = 0; j < N; j++){\n bool include = false;\n for (auto &p : adj[i]){\n if(p.first == j && p.second < dCand) { include = true; break; }\n }\n Hmat[i][j] = include ? 1 : 0;\n }\n }\n vector<int> comp(N, -1);\n int compCount = 0;\n for (int i = 0; i < N; i++){\n if(comp[i] == -1){\n queue<int>q;\n q.push(i);\n comp[i] = compCount;\n while(!q.empty()){\n int cur = q.front(); q.pop();\n for (int nb = 0; nb < N; nb++){\n if(Hmat[cur][nb] && comp[nb]==-1){\n comp[nb] = compCount;\n q.push(nb);\n }\n }\n }\n compCount++;\n }\n }\n if(compCount < 2) continue;\n \n vector<vector<int>> compVerts(compCount);\n for (int i = 0; i < N; i++){\n compVerts[comp[i]].push_back(i);\n }\n \n ll Mprod = 1;\n for (int i = 0; i < compCount; i++){\n int sz = compVerts[i].size();\n vector<vector<ll>> subMat(sz, vector<ll>(sz,0));\n for (int a = 0; a < sz; a++){\n for (int b = 0; b < sz; b++){\n int va = compVerts[i][a], vb = compVerts[i][b];\n subMat[a][b] = fullAdj[va][vb];\n }\n }\n ll treeCount = spanningTreeCount(subMat);\n Mprod = (Mprod * treeCount) % MOD;\n }\n \n vector<vector<ll>> J(compCount, vector<ll>(compCount, 0));\n vector<vector<ll>> Jprime(compCount, vector<ll>(compCount, 0));\n for (int i = 0; i < compCount; i++){\n for (int j = i+1; j < compCount; j++){\n ll cnt = 0, cntP = 0;\n for (int u : compVerts[i]){\n for (auto &p : adj[u]){\n int v = p.first; ll w = p.second;\n if(comp[v]==j){\n if(w >= dCand) cnt++;\n if(w > dCand) cntP++;\n }\n }\n }\n J[i][j] = J[j][i] = cnt % MOD;\n Jprime[i][j] = Jprime[j][i] = cntP % MOD;\n }\n }\n \n ll F2J = computeF2_ordered(J);\n ll F2Jprime = computeF2_ordered(Jprime);\n ll diff = (F2J - F2Jprime) % MOD;\n if(diff < 0) diff += MOD;\n \n ll curCount = (2 * Mprod) % MOD;\n curCount = (curCount * diff) % MOD;\n \n if(curCount % MOD != 0) {\n best_d = dCand;\n bestCount = curCount;\n found = true;\n break;\n }\n }\n if(!found) Couts((char*)\"0 0\");\n else Cout(best_d), pc(' '), Cout(bestCount % MOD);\n pc('\\n');\n return 0;\n}", "accuracy": 0.06666666666666667, "time_ms": 330, "memory_kb": 4160, "score_of_the_acc": -0.7055, "final_rank": 20 }, { "submission_id": "aoj_0314_5460738", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\nenum Type{\n\tBASE,\n\tWORK,\n};\n\ntypedef vector<ll> V;\ntypedef vector<V> MATRIX;\n\n#define SIZE 105\n\nstruct Edge{\n\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn dist < arg.dist;\n\t}\n\tint a,b,dist;\n};\n\nint N,E,POW[7];\nint boss[SIZE][2],height[SIZE][2],num_member[SIZE][2];\nbool table[SIZE][SIZE][2];\nEdge edge[SIZE*SIZE];\n\n\nll gcd(ll x,ll y){\n\n\tx = abs(x);\n\ty = abs(y);\n\n\tif(x < y){\n\t\tswap(x,y);\n\t}\n\tif(y == 0){\n\t\treturn x;\n\t}else{\n\t\treturn gcd(y,x%y);\n\t}\n}\n\nll lcm(ll x,ll y){\n\n\treturn (x*y)/gcd(x,y);\n}\n\nll extgcd(ll a,ll b,ll &x,ll &y){\n\tll d = a;\n\tif(b != 0){\n\t\td = extgcd(b,a%b,y,x);\n\t\ty -= (a/b)*x;\n\t}else{\n\t\tx = 1;\n\t\ty = 0;\n\t}\n\treturn d;\n}\n\nll mod_inverse(ll a,ll m){\n ll x,y;\n extgcd(a,m,x,y);\n return (m+x%m)%m;\n}\n\n\nll determinant(MATRIX A,int M){\n\n\tMATRIX C(M,V(M));\n\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\t\t\tC[row][col] = (A[row][col]+MOD)%MOD;\n\t\t}\n\t}\n\n\tll mult = 1;\n\n\tfor(int base = 0; base < M-1; base++){\n\n\t\tint row = -1;\n\t\tfor(int i = base; i < M; i++){\n\t\t\tif(C[i][base] != 0){\n\n\t\t\t\trow = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(row == -1)return 0;\n\n\t\tif(row != base){\n\n\t\t\tswap(C[row],C[base]);\n\t\t\tmult *= (-1+MOD)%MOD;\n\t\t\tmult %= MOD;\n\t\t}\n\n\t\tfor(int i= base+1; i < M; i++){\n\n\t\t\tll tmp = (C[i][base]*mod_inverse(C[base][base],MOD))%MOD;\n\t\t\tfor(int k = base; k < M; k++){\n\t\t\t\tC[i][k] -= (tmp*C[base][k])%MOD;\n\t\t\t\tif(C[i][k] < 0){\n\t\t\t\t\tC[i][k] = abs(C[i][k])%MOD;\n\t\t\t\t\tC[i][k] *= -1;\n\t\t\t\t\tC[i][k] += MOD;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tll ret = 1;\n\tfor(int i = 0; i < M; i++){\n\n\t\tret *= C[i][i];\n\t\tret %= MOD;\n\t}\n\n\tret *= mod_inverse(mult,MOD);\n\n\treturn ret%MOD;\n}\n\n\n\nint get_boss(int id,Type type){\n\tif(boss[id][type] == id)return id;\n\telse{\n\t\treturn boss[id][type] = get_boss(boss[id][type],type);\n\t}\n}\n\nint isSame(int x,int y,Type type){\n\treturn get_boss(x,type) == get_boss(y,type);\n}\n\nvoid unite(int x,int y,Type type){\n\tint boss_x = get_boss(x,type);\n\tint boss_y = get_boss(y,type);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x][type] > height[boss_y][type]){\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\n\t}else if(height[boss_x][type] < height[boss_y][type]){\n\n\t\tnum_member[boss_y][type] += num_member[boss_x][type];\n\t\tboss[boss_x][type] = boss_y;\n\n\t}else{ //height[boss_x][type] == height[boss_y][type]\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\t\theight[x][type]++;\n\t}\n}\n\n\n\nll calc_Laplacian(vector<int> tmp_vec){\n\n\tif(tmp_vec.size() == 1){\n\n\t\treturn 1;\n\t}\n\n\tint M = tmp_vec.size()-1;\n\n\tMATRIX MULT(M,V(M));\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\n\t\t\tMULT[row][col] = 0;\n\t\t}\n\t}\n\n\t//次数を求める\n\tfor(int i = 0; i < M; i++){\n\t\tint num = 0;\n\t\tfor(int k = 0; k < tmp_vec.size(); k++){ //★★★ループ上限に注意★★★\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tnum++;\n\t\t\t}\n\t\t}\n\t\tMULT[i][i] = num;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tfor(int k = 0; k < M; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tMULT[i][k] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn determinant(MULT,M);\n}\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 6; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\tscanf(\"%d %d\",&N,&E);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\n\t\tfor(int k = 0; k < N; k++){\n\n\t\t\ttable[i][k][BASE] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < E; i++){\n\n\t\tscanf(\"%d %d %d\",&edge[i].a,&edge[i].b,&edge[i].dist);\n\t\tedge[i].a--;\n\t\tedge[i].b--;\n\t}\n\n\tsort(edge,edge+E);\n\n\tint base_dist = -1;\n\n\tfor(int i = 0; i < E; i++){\n\t\tif(isSame(edge[i].a,edge[i].b,BASE))continue;\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\tif(num_member[get_boss(edge[i].a,BASE)][BASE] == N){\n\n\t\t\tbase_dist = edge[i].dist;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\t}\n\n\tvector<int> vec;\n\n\t//base_dist未満の重みのエッジをuniteする\n\tfor(int i = 0; i < E; i++){\n\n\t\tif(edge[i].dist >= base_dist){ //★★★注意:基準長より長い辺も、全域木の場合の数計算のため、未確定辺集合に追加する★★★\n\n\t\t\tvec.push_back(i);\n\t\t\tcontinue;\n\t\t}\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\ttable[edge[i].a][edge[i].b][BASE] = true;\n\t\ttable[edge[i].b][edge[i].a][BASE] = true;\n\t}\n\n\tvector<int> REST;\n\tfor(int i = 0; i < N; i++){\n\t\tif(i == get_boss(i,BASE)){\n\n\t\t\tREST.push_back(i); //各連結成分のボス\n\t\t}\n\t}\n\n\tll ans = 0;\n\n\t//Aに割り当てる連結成分を走査\n\tfor(int state = 0; state < POW[REST.size()]; state++){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tboss[i][WORK] = boss[i][BASE];\n\t\t\theight[i][WORK] = height[i][BASE];\n\t\t\tnum_member[i][WORK] = num_member[i][BASE];\n\n\t\t\tfor(int k = 0; k < N; k++){\n\n\t\t\t\ttable[i][k][WORK] = table[i][k][BASE];\n\t\t\t}\n\t\t}\n\n\t\tvector<int> A,B;\n\t\tmap<int,bool> MAP;\n\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\n\t\t\t\tA.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = true;\n\n\t\t\t}else{\n\n\t\t\t\tB.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = false;\n\t\t\t}\n\t\t}\n\n\t\tif(A.size() == 0 || B.size() == 0)continue;\n\n\t\tfor(int i = 0; i < vec.size(); i++){\n\n\t\t\tint a = get_boss(edge[vec[i]].a,WORK);\n\t\t\tint b = get_boss(edge[vec[i]].b,WORK);\n\n\t\t\tif(MAP[a] == MAP[b]){ //同じグループ\n\n\t\t\t\tunite(edge[vec[i]].a,edge[vec[i]].b,WORK);\n\t\t\t\ttable[edge[vec[i]].a][edge[vec[i]].b][WORK] = true;\n\t\t\t\ttable[edge[vec[i]].b][edge[vec[i]].a][WORK] = true;\n\t\t\t}\n\t\t}\n\n\t\tint BOSS_1 = -1,BOSS_2 = -1;\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\t\t\t\tif(BOSS_1 == -1){\n\n\t\t\t\t\tBOSS_1 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\n\t\t\t}else{\n\t\t\t\tif(BOSS_2 == -1){\n\n\t\t\t\t\tBOSS_2 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<int> tmp_vec[2];\n\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tif(get_boss(i,WORK) == BOSS_1){\n\n\t\t\t\ttmp_vec[0].push_back(i);\n\t\t\t}else{\n\n\t\t\t\ttmp_vec[1].push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tll num_1 = calc_Laplacian(tmp_vec[0]);\n\t\tll num_2 = calc_Laplacian(tmp_vec[1]);\n\n\t\tans += (num_1*num_2)%MOD;\n\t\tans %= MOD;\n\t}\n\n\tprintf(\"%d %lld\\n\",base_dist,ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3432, "score_of_the_acc": -0.0751, "final_rank": 4 }, { "submission_id": "aoj_0314_5460725", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\nenum Type{\n\tBASE,\n\tWORK,\n};\n\ntypedef vector<ll> V;\ntypedef vector<V> MATRIX;\n\n#define SIZE 105\n\nstruct Edge{\n\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn dist < arg.dist;\n\t}\n\tint a,b,dist;\n};\n\nint N,E,POW[7];\nint boss[SIZE][2],height[SIZE][2],num_member[SIZE][2];\nbool table[SIZE][SIZE][2];\nEdge edge[SIZE*SIZE];\n\n\nll gcd(ll x,ll y){\n\n\tx = abs(x);\n\ty = abs(y);\n\n\tif(x < y){\n\t\tswap(x,y);\n\t}\n\tif(y == 0){\n\t\treturn x;\n\t}else{\n\t\treturn gcd(y,x%y);\n\t}\n}\n\nll lcm(ll x,ll y){\n\n\treturn (x*y)/gcd(x,y);\n}\n\nll extgcd(ll a,ll b,ll &x,ll &y){\n\tll d = a;\n\tif(b != 0){\n\t\td = extgcd(b,a%b,y,x);\n\t\ty -= (a/b)*x;\n\t}else{\n\t\tx = 1;\n\t\ty = 0;\n\t}\n\treturn d;\n}\n\nll mod_inverse(ll a,ll m){\n ll x,y;\n extgcd(a,m,x,y);\n return (m+x%m)%m;\n}\n\n\nll determinant(MATRIX A,int M){\n\n\tMATRIX C(M,V(M));\n\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\t\t\tC[row][col] = (A[row][col]+MOD)%MOD;\n\t\t}\n\t}\n\n\tll mult = 1;\n\n\tfor(int base = 0; base < M-1; base++){\n\n\t\tint row = -1;\n\t\tfor(int i = base; i < M; i++){\n\t\t\tif(C[i][base] != 0){\n\n\t\t\t\trow = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(row == -1)return 0;\n\n\t\tif(row != base){\n\n\t\t\tswap(C[row],C[base]);\n\t\t\tmult *= (-1+MOD)%MOD;\n\t\t\tmult %= MOD;\n\t\t}\n\n\t\tfor(int i= base+1; i < M; i++){\n\n\t\t\t//C[i][base]が0でもSKIPするとWAになる場合あり(AOJ 2347 Sunny Graph)\n\n\t\t\tll tmp = (C[i][base]*mod_inverse(C[base][base],MOD))%MOD;\n\t\t\tfor(int k = base; k < M; k++){\n\t\t\t\tC[i][k] -= (tmp*C[base][k])%MOD;\n\t\t\t\tif(C[i][k] < 0){\n\t\t\t\t\tC[i][k] = abs(C[i][k])%MOD;\n\t\t\t\t\tC[i][k] *= -1;\n\t\t\t\t\tC[i][k] += MOD;\n\n\t\t\t\t\tif(C[i][k] < 0 || C[i][k] >= MOD){\n\n\t\t\t\t\t\tprintf(\"バグ!!!\");\n\t\t\t\t\t\treturn -1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tll ret = 1;\n\tfor(int i = 0; i < M; i++){\n\n\t\tret *= C[i][i];\n\t\tret %= MOD;\n\t}\n\n\tret *= mod_inverse(mult,MOD);\n\n\treturn ret%MOD;\n}\n\n\n\nint get_boss(int id,Type type){\n\tif(boss[id][type] == id)return id;\n\telse{\n\t\treturn boss[id][type] = get_boss(boss[id][type],type);\n\t}\n}\n\nint isSame(int x,int y,Type type){\n\treturn get_boss(x,type) == get_boss(y,type);\n}\n\nvoid unite(int x,int y,Type type){\n\tint boss_x = get_boss(x,type);\n\tint boss_y = get_boss(y,type);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x][type] > height[boss_y][type]){\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\n\t}else if(height[boss_x][type] < height[boss_y][type]){\n\n\t\tnum_member[boss_y][type] += num_member[boss_x][type];\n\t\tboss[boss_x][type] = boss_y;\n\n\t}else{ //height[boss_x][type] == height[boss_y][type]\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\t\theight[x][type]++;\n\t}\n}\n\n\n\nll calc_Laplacian(vector<int> tmp_vec){\n\n\tif(tmp_vec.size() == 1){\n\n\t\treturn 1;\n\t}\n\n\tint M = tmp_vec.size()-1;\n\n\tMATRIX MULT(M,V(M));\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\n\t\t\tMULT[row][col] = 0;\n\t\t}\n\t}\n\n\t//次数を求める\n\tfor(int i = 0; i < M; i++){\n\t\tint num = 0;\n\t\tfor(int k = 0; k < tmp_vec.size(); k++){ //★★★ループ上限に注意★★★\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tnum++;\n\t\t\t}\n\t\t}\n\t\tMULT[i][i] = num;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tfor(int k = 0; k < M; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tMULT[i][k] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn determinant(MULT,M);\n}\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 6; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\tscanf(\"%d %d\",&N,&E);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\n\t\tfor(int k = 0; k < N; k++){\n\n\t\t\ttable[i][k][BASE] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < E; i++){\n\n\t\tscanf(\"%d %d %d\",&edge[i].a,&edge[i].b,&edge[i].dist);\n\t\tedge[i].a--;\n\t\tedge[i].b--;\n\t}\n\n\tsort(edge,edge+E);\n\n\tint base_dist = -1;\n\n\tfor(int i = 0; i < E; i++){\n\t\tif(isSame(edge[i].a,edge[i].b,BASE))continue;\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\tif(num_member[get_boss(edge[i].a,BASE)][BASE] == N){\n\n\t\t\tbase_dist = edge[i].dist;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\t}\n\n\tvector<int> vec;\n\n\t//base_dist未満の重みのエッジをuniteする\n\tfor(int i = 0; i < E; i++){\n\n\t\tif(edge[i].dist >= base_dist){ //★★★注意:基準長より長い辺も、全域木の場合の数計算のため、未確定辺集合に追加する★★★\n\n\t\t\tvec.push_back(i);\n\t\t\tcontinue;\n\t\t}\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\ttable[edge[i].a][edge[i].b][BASE] = true;\n\t\ttable[edge[i].b][edge[i].a][BASE] = true;\n\t}\n\n\tvector<int> REST;\n\tfor(int i = 0; i < N; i++){\n\t\tif(i == get_boss(i,BASE)){\n\n\t\t\tREST.push_back(i); //各連結成分のボス\n\t\t}\n\t}\n\n\tll ans = 0;\n\n\t//Aに割り当てる連結成分を走査\n\tfor(int state = 0; state < POW[REST.size()]; state++){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tboss[i][WORK] = boss[i][BASE];\n\t\t\theight[i][WORK] = height[i][BASE];\n\t\t\tnum_member[i][WORK] = num_member[i][BASE];\n\n\t\t\tfor(int k = 0; k < N; k++){\n\n\t\t\t\ttable[i][k][WORK] = table[i][k][BASE];\n\t\t\t}\n\t\t}\n\n\t\tvector<int> A,B;\n\t\tmap<int,bool> MAP;\n\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\n\t\t\t\tA.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = true;\n\n\t\t\t}else{\n\n\t\t\t\tB.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = false;\n\t\t\t}\n\t\t}\n\n\t\tif(A.size() == 0 || B.size() == 0)continue;\n\n\t\tfor(int i = 0; i < vec.size(); i++){\n\n\t\t\tint a = get_boss(edge[vec[i]].a,WORK);\n\t\t\tint b = get_boss(edge[vec[i]].b,WORK);\n\n\t\t\tif(MAP[a] == MAP[b]){ //同じグループ\n\n\t\t\t\tunite(edge[vec[i]].a,edge[vec[i]].b,WORK);\n\t\t\t\ttable[edge[vec[i]].a][edge[vec[i]].b][WORK] = true;\n\t\t\t\ttable[edge[vec[i]].b][edge[vec[i]].a][WORK] = true;\n\t\t\t}\n\t\t}\n\n\t\tint BOSS_1 = -1,BOSS_2 = -1;\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\t\t\t\tif(BOSS_1 == -1){\n\n\t\t\t\t\tBOSS_1 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\n\t\t\t}else{\n\t\t\t\tif(BOSS_2 == -1){\n\n\t\t\t\t\tBOSS_2 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<int> tmp_vec[2];\n\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tif(get_boss(i,WORK) == BOSS_1){\n\n\t\t\t\ttmp_vec[0].push_back(i);\n\t\t\t}else{\n\n\t\t\t\ttmp_vec[1].push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tll num_1 = calc_Laplacian(tmp_vec[0]);\n\t\tll num_2 = calc_Laplacian(tmp_vec[1]);\n\n\t\tans += (num_1*num_2)%MOD;\n\t\tans %= MOD;\n\t}\n\n\tprintf(\"%d %lld\\n\",base_dist,ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3464, "score_of_the_acc": -0.0835, "final_rank": 5 }, { "submission_id": "aoj_0314_5460722", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\nenum Type{\n\tBASE,\n\tWORK,\n};\n\ntypedef vector<ll> V;\ntypedef vector<V> MATRIX;\n\n#define SIZE 105\n\nstruct Edge{\n\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn dist < arg.dist;\n\t}\n\tint a,b,dist;\n};\n\nint N,E,POW[7];\nint boss[SIZE][2],height[SIZE][2],num_member[SIZE][2];\nbool table[SIZE][SIZE][2];\nEdge edge[SIZE*SIZE];\n\n\nll gcd(ll x,ll y){\n\n\tx = abs(x);\n\ty = abs(y);\n\n\tif(x < y){\n\t\tswap(x,y);\n\t}\n\tif(y == 0){\n\t\treturn x;\n\t}else{\n\t\treturn gcd(y,x%y);\n\t}\n}\n\nll lcm(ll x,ll y){\n\n\treturn (x*y)/gcd(x,y);\n}\n\nll extgcd(ll a,ll b,ll &x,ll &y){\n\tll d = a;\n\tif(b != 0){\n\t\td = extgcd(b,a%b,y,x);\n\t\ty -= (a/b)*x;\n\t}else{\n\t\tx = 1;\n\t\ty = 0;\n\t}\n\treturn d;\n}\n\nll mod_inverse(ll a,ll m){\n ll x,y;\n extgcd(a,m,x,y);\n return (m+x%m)%m;\n}\n\nbool DEBUG = false;\n\nll determinant(MATRIX A,int M){\n\n\tMATRIX C(M,V(M));\n\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\t\t\tC[row][col] = (A[row][col]+MOD)%MOD;\n\t\t}\n\t}\n\n\tll mult = 1;\n\n\tfor(int base = 0; base < M-1; base++){\n\n\t\tint row = -1;\n\t\tfor(int i = base; i < M; i++){\n\t\t\tif(C[i][base] != 0){\n\n\t\t\t\trow = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(row == -1)return 0;\n\n\t\tif(row != base){\n\n\t\t\tswap(C[row],C[base]);\n\t\t\tmult *= (-1+MOD)%MOD;\n\t\t\tmult %= MOD;\n\t\t}\n\n\t\tfor(int i= base+1; i < M; i++){\n\n\t\t\t//C[i][base]が0でもSKIPするとWAになる場合あり(AOJ 2347 Sunny Graph)\n\n\t\t\tll tmp = (C[i][base]*mod_inverse(C[base][base],MOD))%MOD;\n\t\t\tfor(int k = base; k < M; k++){\n\t\t\t\tC[i][k] -= (tmp*C[base][k])%MOD;\n\t\t\t\tif(C[i][k] < 0){\n\t\t\t\t\tC[i][k] = abs(C[i][k])%MOD;\n\t\t\t\t\tC[i][k] *= -1;\n\t\t\t\t\tC[i][k] += MOD;\n\n\t\t\t\t\tif(C[i][k] < 0 || C[i][k] >= MOD){\n\n\t\t\t\t\t\tprintf(\"バグ!!!\");\n\t\t\t\t\t\treturn -1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tll ret = 1;\n\tfor(int i = 0; i < M; i++){\n\n\t\tret *= C[i][i];\n\t\tret %= MOD;\n\t}\n\n\tret *= mod_inverse(mult,MOD);\n\n\treturn ret%MOD;\n}\n\n\n\nint get_boss(int id,Type type){\n\tif(boss[id][type] == id)return id;\n\telse{\n\t\treturn boss[id][type] = get_boss(boss[id][type],type);\n\t}\n}\n\nint isSame(int x,int y,Type type){\n\treturn get_boss(x,type) == get_boss(y,type);\n}\n\nvoid unite(int x,int y,Type type){\n\tint boss_x = get_boss(x,type);\n\tint boss_y = get_boss(y,type);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x][type] > height[boss_y][type]){\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\n\t}else if(height[boss_x][type] < height[boss_y][type]){\n\n\t\tnum_member[boss_y][type] += num_member[boss_x][type];\n\t\tboss[boss_x][type] = boss_y;\n\n\t}else{ //height[boss_x][type] == height[boss_y][type]\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\t\theight[x][type]++;\n\t}\n}\n\n\n\nll calc_Laplacian(vector<int> tmp_vec){\n\n\tif(tmp_vec.size() == 1){\n\n\t\treturn 1;\n\t}\n\n\tint M = tmp_vec.size()-1;\n\n\tMATRIX MULT(M,V(M));\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\n\t\t\tMULT[row][col] = 0;\n\t\t}\n\t}\n\n\t//次数を求める\n\tfor(int i = 0; i < M; i++){\n\t\tint num = 0;\n\t\tfor(int k = 0; k < tmp_vec.size(); k++){ //★★★ループ上限に注意★★★\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tnum++;\n\t\t\t}\n\t\t}\n\t\tMULT[i][i] = num;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tfor(int k = 0; k < M; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tMULT[i][k] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\tif(DEBUG){\n\n\t\tprintf(\"\\n\");\n\t\tfor(int row = 0; row < M; row++){\n\t\t\tfor(int col = 0; col < M; col++){\n\n\t\t\t\tprintf(\" %lld\",MULT[row][col]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n\n\treturn determinant(MULT,M);\n}\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 6; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\tscanf(\"%d %d\",&N,&E);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\n\t\tfor(int k = 0; k < N; k++){\n\n\t\t\ttable[i][k][BASE] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < E; i++){\n\n\t\tscanf(\"%d %d %d\",&edge[i].a,&edge[i].b,&edge[i].dist);\n\t\tedge[i].a--;\n\t\tedge[i].b--;\n\t}\n\n\tsort(edge,edge+E);\n\n\tint base_dist = -1;\n\n\tfor(int i = 0; i < E; i++){\n\t\tif(isSame(edge[i].a,edge[i].b,BASE))continue;\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\tif(num_member[get_boss(edge[i].a,BASE)][BASE] == N){\n\n\t\t\tbase_dist = edge[i].dist;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif(DEBUG){\n\n\t\tprintf(\"base_dist:%d\\n\",base_dist);\n\t}\n\n\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\t}\n\n\tvector<int> vec;\n\n\t//base_dist未満の重みのエッジをuniteする\n\tfor(int i = 0; i < E; i++){\n\t\t//if(edge[i].dist > base_dist)break;\n\n\t\tif(edge[i].dist >= base_dist){\n\n\n\t\t\tvec.push_back(i);\n\t\t\tcontinue;\n\t\t}\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\ttable[edge[i].a][edge[i].b][BASE] = true;\n\t\ttable[edge[i].b][edge[i].a][BASE] = true;\n\t}\n\n\tvector<int> REST;\n\tfor(int i = 0; i < N; i++){\n\t\tif(i == get_boss(i,BASE)){\n\n\t\t\tREST.push_back(i); //各連結成分のボス\n\t\t}\n\t}\n\n\tif(DEBUG){\n\t\tprintf(\"REST.size():%lld\\n\",REST.size());\n\t\tfor(int i = 0; i < REST.size(); i++){\n\n\t\t\tprintf(\"%d\\n\",REST[i]);\n\t\t}\n\t\tprintf(\"vec.size():%lld\\n\",vec.size());\n\t\tfor(int i = 0; i < vec.size(); i++){\n\n\t\t\tprintf(\"%d\\n\",vec[i]);\n\t\t}\n\t}\n\n\tll ans = 0;\n\n\t//Aに割り当てる連結成分を走査\n\tfor(int state = 0; state < POW[REST.size()]; state++){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tboss[i][WORK] = boss[i][BASE];\n\t\t\theight[i][WORK] = height[i][BASE];\n\t\t\tnum_member[i][WORK] = num_member[i][BASE];\n\n\t\t\tfor(int k = 0; k < N; k++){\n\n\t\t\t\ttable[i][k][WORK] = table[i][k][BASE];\n\t\t\t}\n\t\t}\n\n\t\tvector<int> A,B;\n\t\tmap<int,bool> MAP;\n\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\n\t\t\t\tA.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = true;\n\n\t\t\t}else{\n\n\t\t\t\tB.push_back(REST[i]);\n\t\t\t\tMAP[REST[i]] = false;\n\t\t\t}\n\t\t}\n\n\t\tif(A.size() == 0 || B.size() == 0)continue;\n\n\t\tfor(int i = 0; i < vec.size(); i++){\n\n\t\t\tint a = get_boss(edge[vec[i]].a,WORK);\n\t\t\tint b = get_boss(edge[vec[i]].b,WORK);\n\n\t\t\tif(MAP[a] == MAP[b]){ //同じグループ\n\n\t\t\t\tif(DEBUG){\n\n\t\t\t\tprintf(\"同じグループ\\n\");\n\t\t\t\t}\n\n\t\t\t\tunite(edge[vec[i]].a,edge[vec[i]].b,WORK);\n\t\t\t\ttable[edge[vec[i]].a][edge[vec[i]].b][WORK] = true;\n\t\t\t\ttable[edge[vec[i]].b][edge[vec[i]].a][WORK] = true;\n\t\t\t}\n\t\t}\n\n\t\tint BOSS_1 = -1,BOSS_2 = -1;\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(state&POW[i]){\n\t\t\t\tif(BOSS_1 == -1){\n\n\t\t\t\t\tBOSS_1 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\n\t\t\t}else{\n\t\t\t\tif(BOSS_2 == -1){\n\n\t\t\t\t\tBOSS_2 = get_boss(REST[i],WORK);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<int> tmp_vec[2];\n\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tif(get_boss(i,WORK) == BOSS_1){\n\n\t\t\t\tif(DEBUG){\n\n\t\t\t\t\tprintf(\"%dがグループ0\\n\",i);\n\t\t\t\t}\n\n\t\t\t\ttmp_vec[0].push_back(i);\n\t\t\t}else{\n\n\t\t\t\ttmp_vec[1].push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tll num_1 = calc_Laplacian(tmp_vec[0]);\n\t\tll num_2 = calc_Laplacian(tmp_vec[1]);\n\n\t\tif(DEBUG){\n\t\tprintf(\"num1:%lld num2:%lld\\n\",num_1,num_2);\n\t\t}\n\n\t\tans += (num_1*num_2)%MOD;\n\t\tans %= MOD;\n\t}\n\n\tprintf(\"%d %lld\\n\",base_dist,ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3468, "score_of_the_acc": -0.0845, "final_rank": 6 }, { "submission_id": "aoj_0314_5460595", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\nenum Type{\n\tBASE,\n\tWORK,\n};\n\ntypedef vector<ll> V;\ntypedef vector<V> MATRIX;\n\n#define SIZE 105\n\nstruct Edge{\n\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn dist < arg.dist;\n\t}\n\tint a,b,dist;\n};\n\nint N,E,POW[7];\nint boss[SIZE][2],height[SIZE][2],num_member[SIZE][2];\nbool table[SIZE][SIZE][2];\nEdge edge[SIZE*SIZE];\n\n\nll gcd(ll x,ll y){\n\n\tx = abs(x);\n\ty = abs(y);\n\n\tif(x < y){\n\t\tswap(x,y);\n\t}\n\tif(y == 0){\n\t\treturn x;\n\t}else{\n\t\treturn gcd(y,x%y);\n\t}\n}\n\nll lcm(ll x,ll y){\n\n\treturn (x*y)/gcd(x,y);\n}\n\nll extgcd(ll a,ll b,ll &x,ll &y){\n\tll d = a;\n\tif(b != 0){\n\t\td = extgcd(b,a%b,y,x);\n\t\ty -= (a/b)*x;\n\t}else{\n\t\tx = 1;\n\t\ty = 0;\n\t}\n\treturn d;\n}\n\nll mod_inverse(ll a,ll m){\n ll x,y;\n extgcd(a,m,x,y);\n return (m+x%m)%m;\n}\n\nbool DEBUG = false;\n\nll determinant(MATRIX A,int M){\n\n\tMATRIX C(M,V(M));\n\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\t\t\tC[row][col] = (A[row][col]+MOD)%MOD;\n\t\t}\n\t}\n\n\tll mult = 1;\n\n\tfor(int base = 0; base < M-1; base++){\n\n\t\tint row = -1;\n\t\tfor(int i = base; i < M; i++){\n\t\t\tif(C[i][base] != 0){\n\n\t\t\t\trow = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(row == -1)return 0;\n\n\t\tif(row != base){\n\n\t\t\tswap(C[row],C[base]);\n\t\t\tmult *= (-1+MOD)%MOD;\n\t\t\tmult %= MOD;\n\t\t}\n\n\t\tfor(int i= base+1; i < M; i++){\n\n\t\t\t//C[i][base]が0でもSKIPするとWAになる場合あり(AOJ 2347 Sunny Graph)\n\n\t\t\tll tmp = C[i][base]*mod_inverse(C[base][base],MOD)%MOD;\n\t\t\tfor(int k = base; k < M; k++){\n\t\t\t\tC[i][k] -= tmp*C[base][k]%MOD;\n\t\t\t\tif(C[i][k] < 0){\n\t\t\t\t\tC[i][k] = abs(C[i][k])%MOD;\n\t\t\t\t\tC[i][k] *= -1;\n\t\t\t\t\tC[i][k] += MOD;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tll ret = 1;\n\tfor(int i = 0; i < M; i++){\n\n\t\tret *= C[i][i];\n\t\tret %= MOD;\n\t}\n\n\tret *= mod_inverse(mult,MOD);\n\n\treturn ret%MOD;\n}\n\n\n\nint get_boss(int id,Type type){\n\tif(boss[id][type] == id)return id;\n\telse{\n\t\treturn boss[id][type] = get_boss(boss[id][type],type);\n\t}\n}\n\nint isSame(int x,int y,Type type){\n\treturn get_boss(x,type) == get_boss(y,type);\n}\n\nvoid unite(int x,int y,Type type){\n\tint boss_x = get_boss(x,type);\n\tint boss_y = get_boss(y,type);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x][type] > height[boss_y][type]){\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\n\t}else if(height[boss_x][type] < height[boss_y][type]){\n\n\t\tnum_member[boss_y][type] += num_member[boss_x][type];\n\t\tboss[boss_x][type] = boss_y;\n\n\t}else{ //height[boss_x][type] == height[boss_y][type]\n\n\t\tnum_member[boss_x][type] += num_member[boss_y][type];\n\t\tboss[boss_y][type] = boss_x;\n\t\theight[x][type]++;\n\t}\n}\n\n\n\nll calc_Laplacian(vector<int> tmp_vec){\n\n\tint M = tmp_vec.size()-1;\n\n\tMATRIX MULT(M,V(M));\n\tfor(int row = 0; row < M; row++){\n\t\tfor(int col = 0; col < M; col++){\n\n\t\t\tMULT[row][col] = 0;\n\t\t}\n\t}\n\n\t//次数を求める\n\tfor(int i = 0; i < M; i++){\n\t\tint num = 0;\n\t\tfor(int k = 0; k < tmp_vec.size(); k++){ //★★★ループ上限に注意★★★\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tnum++;\n\t\t\t}\n\t\t}\n\t\tMULT[i][i] = num;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\t\tfor(int k = 0; k < M; k++){\n\t\t\tif(k == i)continue;\n\n\t\t\tif(table[tmp_vec[i]][tmp_vec[k]][WORK]){\n\n\t\t\t\tMULT[i][k] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\tif(DEBUG){\n\n\t\tprintf(\"\\n\");\n\t\tfor(int row = 0; row < M; row++){\n\t\t\tfor(int col = 0; col < M; col++){\n\n\t\t\t\tprintf(\" %lld\",MULT[row][col]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n\n\treturn determinant(MULT,M);\n}\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 6; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\tscanf(\"%d %d\",&N,&E);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\n\t\tfor(int k = 0; k < N; k++){\n\n\t\t\ttable[i][k][BASE] = false;\n\t\t}\n\t}\n\n\tfor(int i = 0; i < E; i++){\n\n\t\tscanf(\"%d %d %d\",&edge[i].a,&edge[i].b,&edge[i].dist);\n\t\tedge[i].a--;\n\t\tedge[i].b--;\n\t}\n\n\tsort(edge,edge+E);\n\n\tint base_dist = -1;\n\n\tfor(int i = 0; i < E; i++){\n\t\tif(isSame(edge[i].a,edge[i].b,BASE))continue;\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\tif(num_member[get_boss(edge[i].a,BASE)][BASE] == N){\n\n\t\t\tbase_dist = edge[i].dist;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif(DEBUG){\n\n\t\tprintf(\"base_dist:%d\\n\",base_dist);\n\t}\n\n\tvector<int> vec;\n\tfor(int i = 0; i < E; i++){\n\t\tif(edge[i].dist == base_dist){\n\n\t\t\tvec.push_back(i);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i][BASE] = i;\n\t\theight[i][BASE] = 0;\n\t\tnum_member[i][BASE] = 1;\n\t}\n\n\t//base_dist未満の重みのエッジをuniteする\n\tfor(int i = 0; i < E; i++){\n\t\tif(edge[i].dist >= base_dist)break;\n\n\t\tunite(edge[i].a,edge[i].b,BASE);\n\t\ttable[edge[i].a][edge[i].b][BASE] = true;\n\t\ttable[edge[i].b][edge[i].a][BASE] = true;\n\t}\n\n\tvector<int> REST;\n\tfor(int i = 0; i < N; i++){\n\t\tif(i == get_boss(i,BASE)){\n\n\t\t\tREST.push_back(i); //各連結成分のボス\n\t\t}\n\t}\n\n\tif(DEBUG){\n\t\tprintf(\"REST.size():%lld\\n\",REST.size());\n\t\tfor(int i = 0; i < REST.size(); i++){\n\n\t\t\tprintf(\"%d\\n\",REST[i]);\n\t\t}\n\t\tprintf(\"vec.size():%lld\\n\",vec.size());\n\t\tfor(int i = 0; i < vec.size(); i++){\n\n\t\t\tprintf(\"%d\\n\",vec[i]);\n\t\t}\n\t}\n\n\tll ans = 0;\n\n\tmap<int,bool> MAP;\n\n\tfor(int state = 0; state < POW[vec.size()]; state++){\n\n\t\tfor(int i = 0; i < N; i++){\n\n\t\t\tboss[i][WORK] = boss[i][BASE];\n\t\t\theight[i][WORK] = height[i][BASE];\n\t\t\tnum_member[i][WORK] = num_member[i][BASE];\n\n\t\t\tfor(int k = 0; k < N; k++){\n\n\t\t\t\ttable[i][k][WORK] = table[i][k][BASE];\n\t\t\t}\n\t\t}\n\n\t\tfor(int loop = 0; loop < vec.size(); loop++){\n\t\t\tif(state&POW[loop]){\n\n\t\t\t\tint a = edge[vec[loop]].a;\n\t\t\t\tint b = edge[vec[loop]].b;\n\n\t\t\t\tunite(a,b,WORK);\n\t\t\t\ttable[a][b][WORK] = true;\n\t\t\t\ttable[b][a][WORK] = true;\n\t\t\t}\n\t\t}\n\n\t\tvector<int> BOSS;\n\t\tfor(int i = 0; i < REST.size(); i++){\n\t\t\tif(REST[i] == get_boss(REST[i],WORK)){\n\n\t\t\t\tBOSS.push_back(REST[i]);\n\t\t\t}\n\t\t}\n\n\t\tif(BOSS.size() != 2)continue; //連結成分が2でなければSKIP\n\n/*\n\n\t\tll tmp_1 = 0,tmp_2 = 0;\n\t\tfor(int i = 0; i < REST.size(); i++){\n\n\t\t\tif(isSame(REST[i],BOSS[0],WORK)){\n\n\t\t\t\ttmp_1 += POW[i];\n\t\t\t}else{\n\n\t\t\t\ttmp_2 += POW[i];\n\t\t\t}\n\t\t}\n\n\t\tauto at = MAP.find(tmp_1);\n\t\tif(at != MAP.end())continue; //既出の分割方法ならSKIP\n\n\t\tMAP[tmp_1] = true;\n\t\tMAP[tmp_2] = true; */\n\n\n\t\tvector<int> tmp_vec[2];\n\n\t\tfor(int i = 0; i < N; i++){\n\t\t\tif(get_boss(i,WORK) == BOSS[0]){\n\n\t\t\t\ttmp_vec[0].push_back(i);\n\t\t\t}else{\n\n\t\t\t\ttmp_vec[1].push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tll num_1 = calc_Laplacian(tmp_vec[0]);\n\t\tll num_2 = calc_Laplacian(tmp_vec[1]);\n\n\t\tif(DEBUG){\n\t\tprintf(\"num1:%lld num2:%lld\\n\",num_1,num_2);\n\t\t}\n\n\t\tans += (2*(num_1*num_2))%MOD;\n\t\tans %= MOD;\n\t}\n\n\tprintf(\"%d %lld\\n\",base_dist,ans);\n\n\treturn 0;\n}", "accuracy": 0.06666666666666667, "time_ms": 20, "memory_kb": 3436, "score_of_the_acc": -0.0615, "final_rank": 18 }, { "submission_id": "aoj_0314_4551915", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nstruct QuickFind {\n int n, sz;\n vector<int> roots;\n vector<vector<int>> v;\n explicit QuickFind(int n) : n(n), sz(n) {\n v.resize(n);\n for (int i = 0; i < n; ++i) v[i].emplace_back(i);\n roots.resize(n);\n iota(roots.begin(),roots.end(), 0);\n }\n\n int root(int a){ return roots[a]; }\n int size(int a){ return v[a].size(); }\n int size(){ return sz; }\n bool unite(int a, int b){\n if(same(a, b)) return false;\n sz--;\n a = roots[a], b = roots[b];\n if(size(a) < size(b)) swap(a, b);\n for (auto &&i : v[b]) {\n v[a].emplace_back(i);\n roots[i] = a;\n }\n v[b].clear();\n v[b].shrink_to_fit();\n return true;\n }\n bool same(int a, int b){ return roots[a] == roots[b]; }\n const vector<int>& components(int x){ return v[roots[x]];}\n};\n\ntemplate<u32 M = 1000000007>\nstruct modint{\n u32 val;\n modint(): val(0){}\n template<typename T>\n modint(T t){t %= (T)M; if(t < 0) t += (T)M; val = t;}\n\n modint pow(ll k) const {\n modint res(1), x(val);\n while(k){\n if(k&1) res *= x;\n x *= x;\n k >>= 1;\n }\n return res;\n }\n template<typename T>\n modint& operator=(T t){t %= (T)M; if(t < 0) t += (T)M; val = t; return *this;}\n modint inv() const {return pow(M-2);}\n modint& operator+=(modint a){val += a.val; if(val >= M) val -= M; return *this;}\n modint& operator-=(modint a){if(val < a.val) val += M-a.val; else val -= a.val; return *this;}\n modint& operator*=(modint a){val = (u64)val*a.val%M; return *this;}\n modint& operator/=(modint a){return (*this) *= a.inv();}\n modint operator+(modint a) const {return modint(val) +=a;}\n modint operator-(modint a) const {return modint(val) -=a;}\n modint operator*(modint a) const {return modint(val) *=a;}\n modint operator/(modint a) const {return modint(val) /=a;}\n modint operator-(){return modint(M-val);}\n bool operator==(const modint a) const {return val == a.val;}\n bool operator!=(const modint a) const {return val != a.val;}\n bool operator<(const modint a) const {return val < a.val;}\n};\nusing mint = modint<MOD>;\n\ntemplate<class H>\nstruct matrix {\n using T = typename H::T;\n vector<vector<T>> A;\n matrix() = default;\n matrix(size_t n, size_t m) : A(n, vector<T>(m)) {}\n explicit matrix(size_t n) : A(n, vector<T> (n)) {};\n size_t height() const { return (A.size()); }\n size_t width() const { return (A[0].size()); }\n\n const vector<T> &operator [] (int k) const { return A[k]; }\n vector<T> &operator[] (int k) { return A[k]; }\n\n static matrix I(size_t n){\n matrix mat(n);\n for (int i = 0; i < n; ++i) mat[i][i] = 1;\n return mat;\n }\n\n matrix &operator+= (const matrix &B){\n size_t h = height(), w = width();\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n add((*this)[i][j], B[i][j]);\n }\n }\n }\n\n matrix &operator-= (const matrix &B){\n size_t h = height(), w = width();\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n add((*this)[i][j], -B[i][j]);\n }\n }\n }\n\n matrix &operator*=(const matrix &B) {\n size_t n = height(), m = B.width(), p = width();\n matrix C(n, m);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < m; ++j) {\n for (int k = 0; k < p; ++k) {\n add(C[i][j], mul((*this)[i][k],B[k][j]));\n }\n }\n }\n A.swap(C.A);\n return (*this);\n }\n\n matrix pow(ll n) const {\n matrix a = (*this), res = I(height());\n while(n > 0){\n if(n & 1) mul(res, a);\n mul(a, a);\n n >>= 1;\n }\n return res;\n }\n matrix operator+(const matrix &B) const {return matrix(*this) += B;}\n matrix operator-(const matrix &B) const {return matrix(*this) -= B;}\n matrix operator*(const matrix &B) const {return matrix(*this) *= B;}\n\n mint gauss_jordan(){\n mint res = 1;\n int rank = 0;\n for (int c = 0; c < width(); ++c) {\n int k = -1;\n for (int i = rank; i < height(); ++i) {\n if(A[i][c] != H::zero()){\n k = i;\n break;\n }\n }\n if(!~k) continue;\n swap(A[k], A[rank]);\n res *= A[rank][c];\n T x = T(1)/A[rank][c];\n for (int j = 0; j < width(); ++j) A[rank][j] *= x;\n for (int i = 0; i < height(); ++i) {\n if(i != rank && A[i][c] != H::zero()){\n T coeff = A[i][c];\n for (int j = 0; j < width(); ++j) {\n A[i][j] -= A[rank][j]*coeff;\n }\n }\n }\n rank++;\n }\n for (int i = 0; i < min(width(), height()); ++i) {\n res *= A[i][i];\n }\n return res;\n }\n};\n\nstruct SemiRing {\n using T = mint;\n static inline T mul(T x, T y){ return x * y; }\n static inline void add(T &x, T y){ x += y; }\n static inline T one(){ return 1; }\n static inline T zero(){ return 0; }\n};\n\n\ntemplate <class T>\nostream& operator<<(ostream& os, vector<T> v) {\n os << \"{\";\n for (int i = 0; i < v.size(); ++i) {\n if(i) os << \", \";\n os << v[i];\n }\n return os << \"}\";\n}\n\ntemplate <class L, class R>\nostream& operator<<(ostream& os, pair<L, R> p) {\n return os << \"{\" << p.first << \", \" << p.second << \"}\";\n}\n\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<tuple<int, int, int>> v;\n vector<int> z(m);\n for (int i = 0; i < m; ++i) {\n int s, t, d;\n scanf(\"%d %d %d\", &s, &t, &d);\n s--; t--;\n v.emplace_back(d, s, t);\n z[i] = d;\n }\n sort(z.begin(), z.end());\n z.erase(unique(z.begin(), z.end()), z.end());\n vector<vector<pair<int, int>>> edges(z.size());\n for (int i = 0; i < m; ++i) {\n int d, s, t; tie(d, s, t) = v[i];\n d = lower_bound(z.begin(),z.end(), d) - z.begin();\n edges[d].emplace_back(s, t);\n }\n QuickFind uf(n);\n int val = 0;\n for (int i = 0; i < z.size(); ++i) {\n for (auto &&e : edges[i]) {\n uf.unite(e.first, e.second);\n if(uf.size() == 1){\n val = i;\n i = z.size();\n break;\n }\n }\n }\n printf(\"%d \", z[val]);\n uf = QuickFind(n);\n for (int i = 0; i < val; ++i) {\n for (auto &&e : edges[i]) {\n uf.unite(e.first, e.second);\n }\n }\n vector<int> roots;\n for (int i = 0; i < n; ++i) {\n if(!uf.v[i].empty()) roots.emplace_back(i);\n }\n mint ans = 0;\n int C = roots.size();\n for (int i = 1; i < (1 << C)-1; ++i) {\n QuickFind uf2(uf);\n for (int j = 0; j < C; ++j) {\n for (int k = j+1; k < C; ++k) {\n if(((i >> j)& 1) == ((i >> k)& 1)){\n uf2.unite(roots[j], roots[k]);\n }\n }\n }\n vector<int> l, r;\n for (int j = 0; j < C; ++j) {\n if(i & (1 << j)) {\n if(l.empty()) l = uf2.components(roots[j]);\n }else {\n if(r.empty()) r = uf2.components(roots[j]);\n }\n }\n sort(l.begin(),l.end());\n sort(r.begin(),r.end());\n mint ret = 1;\n if(l.size() != 1){\n int sz = l.size()-1;\n matrix<SemiRing> A(sz, sz);\n for (int j = 0; j < z.size(); ++j) {\n for (auto &&e : edges[j]) {\n if(uf2.same(e.first, l[0]) && uf2.same(e.second, l[0])){\n int x = lower_bound(l.begin(),l.end(), e.first) - l.begin();\n int y = lower_bound(l.begin(),l.end(), e.second) - l.begin();\n if(x) A[x-1][x-1] += 1;\n if(y) A[y-1][y-1] += 1;\n if(x && y) A[x-1][y-1] -= 1, A[y-1][x-1] -= 1;\n }\n }\n }\n ret *= A.gauss_jordan();\n }\n if(r.size() != 1){\n int sz = r.size()-1;\n matrix<SemiRing> A(sz, sz);\n for (int j = 0; j < z.size(); ++j) {\n for (auto &&e : edges[j]) {\n if(uf2.same(e.first, r[0]) && uf2.same(e.second, r[0])){\n int x = lower_bound(r.begin(),r.end(), e.first) - r.begin();\n int y = lower_bound(r.begin(),r.end(), e.second) - r.begin();\n if(x) A[x-1][x-1] += 1;\n if(y) A[y-1][y-1] += 1;\n if(x && y) A[x-1][y-1] -= 1, A[y-1][x-1] -= 1;\n }\n }\n }\n ret *= A.gauss_jordan();\n }\n ans += ret;\n }\n printf(\"%d\\n\", ans.val);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3388, "score_of_the_acc": -0.1078, "final_rank": 7 }, { "submission_id": "aoj_0314_3978852", "code_snippet": "#include <map>\n#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\ntemplate<unsigned mod>\nclass modint {\nprivate:\n unsigned x;\npublic:\n modint() : x(0) {};\n modint(long long x_) : x(x_ >= 0 ? x_ % mod : (mod - (-x_) % mod) % mod) {};\n unsigned get() { return x; }\n bool operator==(const modint& m) const { return x == m.x; }\n bool operator!=(const modint& m) const { return x != m.x; }\n modint& operator+=(const modint& m) { x += m.x; x = (x < mod ? x : x - mod); return *this; }\n modint& operator-=(const modint& m) { x += mod - m.x; x = (x < mod ? x : x - mod); return *this; }\n modint& operator*=(const modint& m) { x = 1ULL * x * m.x % mod; return *this; }\n modint operator+(const modint& m) const { return modint(*this) += m; }\n modint operator-(const modint& m) const { return modint(*this) -= m; }\n modint operator*(const modint& m) const { return modint(*this) *= m; }\n modint pow(unsigned long long b) const {\n modint ans(1), mul(*this);\n while(b > 0) {\n if(b & 1) ans *= mul;\n mul *= mul;\n b >>= 1;\n }\n return ans;\n }\n modint inv() const { return pow(mod - 2); }\n};\nusing mint = modint<1000000007>;\nmint determinant(int n, vector<vector<mint> > a) {\n mint ans = 1;\n for(int i = 0; i < n; ++i) {\n int ptr = -1;\n for(int j = i; j < n; ++j) {\n if(a[i][j] != mint(0)) {\n ptr = j;\n break;\n }\n }\n if(ptr == -1) return mint(0);\n if(ptr > i) {\n swap(a[i], a[ptr]);\n ans *= mint(-1);\n }\n mint mul = a[i][i], mulinv = mul.inv();\n ans *= mul;\n for(int j = i; j < n; ++j) {\n a[i][j] *= mulinv;\n }\n for(int j = i + 1; j < n; ++j) {\n mint coeff = a[j][i];\n for(int k = 0; k < n; ++k) {\n a[j][k] -= coeff * a[i][k];\n }\n }\n }\n return ans;\n}\nint main() {\n int N, M;\n cin >> N >> M;\n vector<int> S(M), T(M), D(M);\n for(int i = 0; i < M; ++i) {\n cin >> S[i] >> T[i] >> D[i]; --S[i], --T[i];\n }\n vector<int> sd = D;\n sort(sd.begin(), sd.end());\n sd.erase(unique(sd.begin(), sd.end()), sd.end());\n vector<vector<int> > comps;\n for(int i = 0; i < N; ++i) {\n comps.push_back(vector<int>({ i }));\n }\n int threshold = -1;\n for(int i : sd) {\n vector<vector<int> > sg(N);\n for(int j = 0; j < M; ++j) {\n if(D[j] <= i) {\n sg[S[j]].push_back(T[j]);\n sg[T[j]].push_back(S[j]);\n }\n }\n vector<vector<int> > ncomps;\n vector<bool> vis(N);\n for(int j = 0; j < N; ++j) {\n if(vis[j]) continue;\n queue<int> que;\n que.push(j);\n vis[j] = true;\n vector<int> ncomp;\n while(!que.empty()) {\n int u = que.front(); que.pop();\n ncomp.push_back(u);\n for(int k : sg[u]) {\n if(!vis[k]) {\n vis[k] = true;\n que.push(k);\n }\n }\n }\n sort(ncomp.begin(), ncomp.end());\n ncomps.push_back(ncomp);\n }\n if(ncomps.size() == 1) {\n threshold = i;\n break;\n }\n comps = ncomps;\n }\n int C = comps.size();\n vector<mint> sub(1 << C);\n for(int i = 1; i < 1 << C; ++i) {\n vector<int> verts;\n for (int j = 0; j < C; ++j) {\n if ((i >> j) & 1) {\n verts.insert(verts.end(), comps[j].begin(), comps[j].end());\n }\n }\n sort(verts.begin(), verts.end());\n int V = verts.size();\n vector<vector<mint> > mat(V, vector<mint>(V));\n for (int j = 0; j < M; ++j) {\n int pa = lower_bound(verts.begin(), verts.end(), S[j]) - verts.begin();\n int pb = lower_bound(verts.begin(), verts.end(), T[j]) - verts.begin();\n if (pa != V && verts[pa] == S[j] && pb != V && verts[pb] == T[j]) {\n mat[pa][pb] = mint(-1);\n mat[pb][pa] = mint(-1);\n mat[pa][pa] += 1;\n mat[pb][pb] += 1;\n }\n }\n vector<vector<mint> > redmat(V - 1, vector<mint>(V - 1));\n for (int j = 0; j < V - 1; ++j) {\n for (int k = 0; k < V - 1; ++k) {\n redmat[j][k] = mat[j][k];\n }\n }\n sub[i] = determinant(V - 1, redmat);\n }\n mint ans = 0;\n for(int i = 1; i < (1 << C) - 1; ++i) {\n ans += sub[i] * sub[(1 << C) - i - 1];\n }\n cout << threshold << ' ' << ans.get() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3288, "score_of_the_acc": -0.023, "final_rank": 1 }, { "submission_id": "aoj_0314_3960268", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\nstruct FastIO{\n FastIO(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n }\n}fastio_beet;\n\n\ntemplate<typename K>\nstruct Matrix{\n typedef vector<K> arr;\n typedef vector<arr> mat;\n mat dat;\n\n Matrix(size_t r,size_t c):dat(r,arr(c,K())){}\n Matrix(mat dat):dat(dat){}\n\n size_t size() const{return dat.size();}\n bool empty() const{return size()==0;}\n arr& operator[](size_t k){return dat[k];}\n const arr& operator[](size_t k) const {return dat[k];}\n\n static Matrix cross(const Matrix &A,const Matrix &B){\n Matrix res(A.size(),B[0].size());\n for(int i=0;i<(int)A.size();i++)\n for(int j=0;j<(int)B[0].size();j++)\n for(int k=0;k<(int)B.size();k++)\n res[i][j]+=A[i][k]*B[k][j];\n return res;\n }\n\n static Matrix identity(size_t n){\n Matrix res(n,n);\n for(int i=0;i<(int)n;i++) res[i][i]=K(1);\n return res;\n }\n\n Matrix pow(long long n) const{\n Matrix a(dat),res=identity(size());\n while(n){\n if(n&1) res=cross(res,a);\n a=cross(a,a);\n n>>=1;\n }\n return res;\n }\n\n template<typename T>\n using ET = enable_if<is_floating_point<T>::value>;\n template<typename T>\n using EF = enable_if<!is_floating_point<T>::value>;\n\n template<typename T, typename ET<T>::type* = nullptr>\n static bool is_zero(T x){return abs(x)<1e-8;}\n template<typename T, typename EF<T>::type* = nullptr>\n static bool is_zero(T x){return x==T(0);}\n\n template<typename T, typename ET<T>::type* = nullptr>\n static bool compare(T x,T y){return abs(x)<abs(y);}\n template<typename T, typename EF<T>::type* = nullptr>\n static bool compare(T x,T y){(void)x;return y!=T(0);}\n\n // assume regularity\n static Matrix gauss_jordan(const Matrix &A,const Matrix &B){\n int n=A.size(),l=B[0].size();\n Matrix C(n,n+l);\n for(int i=0;i<n;i++){\n for(int j=0;j<n;j++)\n C[i][j]=A[i][j];\n for(int j=0;j<l;j++)\n C[i][n+j]=B[i][j];\n }\n for(int i=0;i<n;i++){\n int p=i;\n for(int j=i;j<n;j++)\n if(compare(C[p][i],C[j][i])) p=j;\n swap(C[i],C[p]);\n if(is_zero(C[i][i])) return Matrix(0,0);\n for(int j=i+1;j<n+l;j++) C[i][j]/=C[i][i];\n for(int j=0;j<n;j++){\n if(i==j) continue;\n for(int k=i+1;k<n+l;k++)\n C[j][k]-=C[j][i]*C[i][k];\n }\n }\n Matrix res(n,l);\n for(int i=0;i<n;i++)\n for(int j=0;j<l;j++)\n res[i][j]=C[i][n+j];\n return res;\n }\n\n Matrix inv() const{\n Matrix B=identity(size());\n return gauss_jordan(*this,B);\n }\n\n static arr linear_equations(const Matrix &A,const arr &b){\n Matrix B(b.size(),1);\n for(int i=0;i<(int)b.size();i++) B[i][0]=b[i];\n Matrix tmp=gauss_jordan(A,B);\n arr res(tmp.size());\n for(int i=0;i<(int)tmp.size();i++) res[i]=tmp[i][0];\n return res;\n }\n\n K determinant() const{\n Matrix A(dat);\n K res(1);\n int n=size();\n for(int i=0;i<n;i++){\n int p=i;\n for(int j=i;j<n;j++)\n if(compare(A[p][i],A[j][i])) p=j;\n if(i!=p) swap(A[i],A[p]),res=-res;\n if(is_zero(A[i][i])) return K(0);\n res*=A[i][i];\n for(int j=i+1;j<n;j++) A[i][j]/=A[i][i];\n for(int j=i+1;j<n;j++)\n for(int k=i+1;k<n;k++)\n A[j][k]-=A[j][i]*A[i][k];\n }\n return res;\n }\n\n static K sigma(K x,long long n){\n Matrix A(2,2);\n A[0][0]=x;A[0][1]=0;\n A[1][0]=1;A[1][1]=1;\n return A.pow(n)[1][0];\n }\n};\n\n\nstruct UnionFind{\n int num;\n vector<int> r,p;\n UnionFind(){}\n UnionFind(int n):num(n),r(n,1),p(n,0){iota(p.begin(),p.end(),0);}\n int find(int x){\n return (x==p[x]?x:p[x]=find(p[x]));\n }\n bool same(int x,int y){\n return find(x)==find(y);\n }\n void unite(int x,int y){\n x=find(x);y=find(y);\n if(x==y) return;\n if(r[x]<r[y]) swap(x,y);\n r[x]+=r[y];\n p[y]=x;\n num--;\n }\n int size(int x){\n return r[find(x)];\n }\n int count() const{\n return num;\n }\n};\n\n\ntemplate<typename K, typename T>\nstruct MatrixTreeTheorem{\n using M = Matrix<K>;\n struct edge{\n int a,b;\n T c;\n edge(int a,int b,T c):a(a),b(b),c(c){}\n bool operator<(const edge &e)const{\n return c<e.c;\n }\n };\n\n int n;\n vector<edge> es;\n vector<int> used;\n vector<vector<int> > H;\n\n MatrixTreeTheorem(){}\n MatrixTreeTheorem(int n):n(n),used(n),H(n){}\n\n void add_edge(int a,int b,T c){\n es.emplace_back(a,b,c);\n }\n\n vector<int> bfs(int v){\n vector<int> vs;\n queue<int> q;\n used[v]=1;\n q.emplace(v);\n while(!q.empty()){\n v=q.front();q.pop();\n vs.emplace_back(v);\n for(int u:H[v]){\n if(used[u]) continue;\n used[u]=1;\n q.emplace(u);\n }\n }\n return vs;\n }\n\n K build(){\n UnionFind uf(n);\n sort(es.begin(),es.end());\n fill(used.begin(),used.end(),0);\n K res(1);\n for(int i=0;i<(int)es.size();){\n queue<int> q,r;\n for(auto &h:H) h.clear();\n int p=i;\n while(i<(int)es.size()&&es[i].c==es[p].c){\n int u=uf.find(es[i].a);\n int v=uf.find(es[i++].b);\n H[u].emplace_back(v);\n H[v].emplace_back(u);\n q.emplace(u);q.emplace(v);\n r.emplace(u);r.emplace(v);\n }\n while(!q.empty()){\n int v=q.front();q.pop();\n if(used[v]) continue;\n vector<int> vs=bfs(v);\n int m=vs.size();\n if(m==1) continue;\n\n sort(vs.begin(),vs.end());\n auto idx=\n [&](int x){\n return lower_bound(vs.begin(),vs.end(),x)-vs.begin();\n };\n M A(m,m);\n for(int x:vs)\n for(int y:H[x])\n if(x!=y) A[idx(x)][idx(y)]-=K(1);\n\n for(int x=0;x<m;x++)\n for(int y=0;y<m;y++)\n if(x!=y) A[x][x]-=A[x][y];\n\n A.dat.pop_back();\n for(auto &a:A.dat) a.pop_back();\n\n res*=A.determinant();\n for(int x:vs) uf.unite(v,x);\n }\n while(!r.empty()){\n int v=r.front();r.pop();\n used[v]=0;\n }\n }\n return res;\n }\n};\n\n\ntemplate<typename T,T MOD = 1000000007>\nstruct Mint{\n static constexpr T mod = MOD;\n T v;\n Mint():v(0){}\n Mint(signed v):v(v){}\n Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}\n\n Mint pow(long long k){\n Mint res(1),tmp(v);\n while(k){\n if(k&1) res*=tmp;\n tmp*=tmp;\n k>>=1;\n }\n return res;\n }\n\n static Mint add_identity(){return Mint(0);}\n static Mint mul_identity(){return Mint(1);}\n\n Mint inv(){return pow(MOD-2);}\n\n Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}\n Mint& operator/=(Mint a){return (*this)*=a.inv();}\n\n Mint operator+(Mint a) const{return Mint(v)+=a;}\n Mint operator-(Mint a) const{return Mint(v)-=a;}\n Mint operator*(Mint a) const{return Mint(v)*=a;}\n Mint operator/(Mint a) const{return Mint(v)/=a;}\n\n Mint operator-() const{return v?Mint(MOD-v):Mint(v);}\n\n bool operator==(const Mint a)const{return v==a.v;}\n bool operator!=(const Mint a)const{return v!=a.v;}\n bool operator <(const Mint a)const{return v <a.v;}\n\n static Mint comb(long long n,int k){\n Mint num(1),dom(1);\n for(int i=0;i<k;i++){\n num*=Mint(n-i);\n dom*=Mint(i+1);\n }\n return num/dom;\n }\n};\ntemplate<typename T,T MOD> constexpr T Mint<T, MOD>::mod;\ntemplate<typename T,T MOD>\nostream& operator<<(ostream &os,Mint<T, MOD> m){os<<m.v;return os;}\n\n//INSERT ABOVE HERE\nsigned main(){\n int n,m;\n cin>>n>>m;\n using M = Mint<int>;\n using edge=MatrixTreeTheorem<M, int>::edge;\n vector<edge> es;\n for(int i=0;i<m;i++){\n int s,t,d;\n cin>>s>>t>>d;\n s--;t--;\n es.emplace_back(s,t,d);\n }\n sort(es.begin(),es.end());\n UnionFind uf(n);\n int cost=0;\n for(auto e:es){\n uf.unite(e.a,e.b);\n cost=e.c;\n if(uf.count()==1) break;\n }\n cout<<cost<<\" \";\n\n uf=UnionFind(n);\n for(auto e:es){\n if(e.c==cost) break;\n uf.unite(e.a,e.b);\n }\n\n vector<int> rs;\n for(int i=0;i<n;i++)\n if(uf.find(i)==i) rs.emplace_back(i);\n\n M ans{0};\n int k=rs.size();\n int sz=1<<k;\n for(int b=1;b+1<sz;b++){\n UnionFind tmp(uf);\n for(int i=0;i<k;i++)\n for(int j=0;j<k;j++)\n if(((b>>i)&1)==((b>>j)&1))\n tmp.unite(rs[i],rs[j]);\n\n UnionFind ch(n);\n for(auto e:es)\n if(tmp.same(e.a,e.b))\n ch.unite(e.a,e.b);\n if(ch.count()!=2) continue;\n\n MatrixTreeTheorem<M, int> G(n);\n for(auto e:es)\n if(tmp.same(e.a,e.b))\n G.add_edge(e.a,e.b,0);\n\n ans+=G.build();\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3304, "score_of_the_acc": -0.0419, "final_rank": 2 }, { "submission_id": "aoj_0314_3960256", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\nstruct FastIO{\n FastIO(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n }\n}fastio_beet;\n\n\ntemplate<typename K>\nstruct Matrix{\n typedef vector<K> arr;\n typedef vector<arr> mat;\n mat dat;\n\n Matrix(size_t r,size_t c):dat(r,arr(c,K())){}\n Matrix(mat dat):dat(dat){}\n\n size_t size() const{return dat.size();}\n bool empty() const{return size()==0;}\n arr& operator[](size_t k){return dat[k];}\n const arr& operator[](size_t k) const {return dat[k];}\n\n static Matrix cross(const Matrix &A,const Matrix &B){\n Matrix res(A.size(),B[0].size());\n for(int i=0;i<(int)A.size();i++)\n for(int j=0;j<(int)B[0].size();j++)\n for(int k=0;k<(int)B.size();k++)\n res[i][j]+=A[i][k]*B[k][j];\n return res;\n }\n\n static Matrix identity(size_t n){\n Matrix res(n,n);\n for(int i=0;i<(int)n;i++) res[i][i]=K(1);\n return res;\n }\n\n Matrix pow(long long n) const{\n Matrix a(dat),res=identity(size());\n while(n){\n if(n&1) res=cross(res,a);\n a=cross(a,a);\n n>>=1;\n }\n return res;\n }\n\n template<typename T>\n using ET = enable_if<is_floating_point<T>::value>;\n template<typename T>\n using EF = enable_if<!is_floating_point<T>::value>;\n\n template<typename T, typename ET<T>::type* = nullptr>\n static bool is_zero(T x){return abs(x)<1e-8;}\n template<typename T, typename EF<T>::type* = nullptr>\n static bool is_zero(T x){return x==T(0);}\n\n template<typename T, typename ET<T>::type* = nullptr>\n static bool compare(T x,T y){return abs(x)<abs(y);}\n template<typename T, typename EF<T>::type* = nullptr>\n static bool compare(T x,T y){(void)x;return y!=T(0);}\n\n // assume regularity\n static Matrix gauss_jordan(const Matrix &A,const Matrix &B){\n int n=A.size(),l=B[0].size();\n Matrix C(n,n+l);\n for(int i=0;i<n;i++){\n for(int j=0;j<n;j++)\n C[i][j]=A[i][j];\n for(int j=0;j<l;j++)\n C[i][n+j]=B[i][j];\n }\n for(int i=0;i<n;i++){\n int p=i;\n for(int j=i;j<n;j++)\n if(compare(C[p][i],C[j][i])) p=j;\n swap(C[i],C[p]);\n if(is_zero(C[i][i])) return Matrix(0,0);\n for(int j=i+1;j<n+l;j++) C[i][j]/=C[i][i];\n for(int j=0;j<n;j++){\n if(i==j) continue;\n for(int k=i+1;k<n+l;k++)\n C[j][k]-=C[j][i]*C[i][k];\n }\n }\n Matrix res(n,l);\n for(int i=0;i<n;i++)\n for(int j=0;j<l;j++)\n res[i][j]=C[i][n+j];\n return res;\n }\n\n Matrix inv() const{\n Matrix B=identity(size());\n return gauss_jordan(*this,B);\n }\n\n static arr linear_equations(const Matrix &A,const arr &b){\n Matrix B(b.size(),1);\n for(int i=0;i<(int)b.size();i++) B[i][0]=b[i];\n Matrix tmp=gauss_jordan(A,B);\n arr res(tmp.size());\n for(int i=0;i<(int)tmp.size();i++) res[i]=tmp[i][0];\n return res;\n }\n\n K determinant() const{\n Matrix A(dat);\n K res(1);\n int n=size();\n for(int i=0;i<n;i++){\n int p=i;\n for(int j=i;j<n;j++)\n if(compare(A[p][i],A[j][i])) p=j;\n if(i!=p) swap(A[i],A[p]),res=-res;\n if(is_zero(A[i][i])) return K(0);\n res*=A[i][i];\n for(int j=i+1;j<n;j++) A[i][j]/=A[i][i];\n for(int j=i+1;j<n;j++)\n for(int k=i+1;k<n;k++)\n A[j][k]-=A[j][i]*A[i][k];\n }\n return res;\n }\n\n static K sigma(K x,long long n){\n Matrix A(2,2);\n A[0][0]=x;A[0][1]=0;\n A[1][0]=1;A[1][1]=1;\n return A.pow(n)[1][0];\n }\n};\n\n\nstruct UnionFind{\n int num;\n vector<int> r,p;\n UnionFind(){}\n UnionFind(int n):num(n),r(n,1),p(n,0){iota(p.begin(),p.end(),0);}\n int find(int x){\n return (x==p[x]?x:p[x]=find(p[x]));\n }\n bool same(int x,int y){\n return find(x)==find(y);\n }\n void unite(int x,int y){\n x=find(x);y=find(y);\n if(x==y) return;\n if(r[x]<r[y]) swap(x,y);\n r[x]+=r[y];\n p[y]=x;\n num--;\n }\n int size(int x){\n return r[find(x)];\n }\n int count() const{\n return num;\n }\n};\n\n\ntemplate<typename K, typename T>\nstruct MatrixTreeTheorem{\n using M = Matrix<K>;\n struct edge{\n int a,b;\n T c;\n edge(int a,int b,T c):a(a),b(b),c(c){}\n bool operator<(const edge &e)const{\n return c<e.c;\n }\n };\n\n int n;\n vector<edge> es;\n vector<int> used;\n vector<vector<int> > H;\n\n MatrixTreeTheorem(){}\n MatrixTreeTheorem(int n):n(n),used(n),H(n){}\n\n void add_edge(int a,int b,T c){\n es.emplace_back(a,b,c);\n }\n\n vector<int> bfs(int v){\n vector<int> vs;\n queue<int> q;\n used[v]=1;\n q.emplace(v);\n while(!q.empty()){\n v=q.front();q.pop();\n vs.emplace_back(v);\n for(int u:H[v]){\n if(used[u]) continue;\n used[u]=1;\n q.emplace(u);\n }\n }\n return vs;\n }\n\n K build(){\n UnionFind uf(n);\n sort(es.begin(),es.end());\n fill(used.begin(),used.end(),0);\n K res(1);\n for(int i=0;i<(int)es.size();){\n queue<int> q,r;\n for(auto &h:H) h.clear();\n int p=i;\n while(i<(int)es.size()&&es[i].c==es[p].c){\n int u=uf.find(es[i].a);\n int v=uf.find(es[i++].b);\n H[u].emplace_back(v);\n H[v].emplace_back(u);\n q.emplace(u);q.emplace(v);\n r.emplace(u);r.emplace(v);\n }\n while(!q.empty()){\n int v=q.front();q.pop();\n if(used[v]) continue;\n vector<int> vs=bfs(v);\n int m=vs.size();\n if(m==1) continue;\n\n sort(vs.begin(),vs.end());\n auto idx=\n [&](int x){\n return lower_bound(vs.begin(),vs.end(),x)-vs.begin();\n };\n M A(m,m);\n for(int x:vs)\n for(int y:H[x])\n if(x!=y) A[idx(x)][idx(y)]-=K(1);\n\n for(int x=0;x<m;x++)\n for(int y=0;y<m;y++)\n if(x!=y) A[x][x]-=A[x][y];\n\n A.dat.pop_back();\n for(auto &a:A.dat) a.pop_back();\n\n res*=A.determinant();\n for(int x:vs) uf.unite(v,x);\n }\n while(!r.empty()){\n int v=r.front();r.pop();\n used[v]=0;\n }\n }\n return res;\n }\n};\n\n\ntemplate<typename T,T MOD = 1000000007>\nstruct Mint{\n static constexpr T mod = MOD;\n T v;\n Mint():v(0){}\n Mint(signed v):v(v){}\n Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}\n\n Mint pow(long long k){\n Mint res(1),tmp(v);\n while(k){\n if(k&1) res*=tmp;\n tmp*=tmp;\n k>>=1;\n }\n return res;\n }\n\n static Mint add_identity(){return Mint(0);}\n static Mint mul_identity(){return Mint(1);}\n\n Mint inv(){return pow(MOD-2);}\n\n Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}\n Mint& operator/=(Mint a){return (*this)*=a.inv();}\n\n Mint operator+(Mint a) const{return Mint(v)+=a;}\n Mint operator-(Mint a) const{return Mint(v)-=a;}\n Mint operator*(Mint a) const{return Mint(v)*=a;}\n Mint operator/(Mint a) const{return Mint(v)/=a;}\n\n Mint operator-() const{return v?Mint(MOD-v):Mint(v);}\n\n bool operator==(const Mint a)const{return v==a.v;}\n bool operator!=(const Mint a)const{return v!=a.v;}\n bool operator <(const Mint a)const{return v <a.v;}\n\n static Mint comb(long long n,int k){\n Mint num(1),dom(1);\n for(int i=0;i<k;i++){\n num*=Mint(n-i);\n dom*=Mint(i+1);\n }\n return num/dom;\n }\n};\ntemplate<typename T,T MOD> constexpr T Mint<T, MOD>::mod;\ntemplate<typename T,T MOD>\nostream& operator<<(ostream &os,Mint<T, MOD> m){os<<m.v;return os;}\n\n//INSERT ABOVE HERE\nsigned main(){\n int n,m;\n cin>>n>>m;\n using M = Mint<int>;\n using edge=MatrixTreeTheorem<M, int>::edge;\n vector<edge> es;\n for(int i=0;i<m;i++){\n int s,t,d;\n cin>>s>>t>>d;\n s--;t--;\n es.emplace_back(s,t,d);\n }\n sort(es.begin(),es.end());\n UnionFind uf(n);\n int cost=0;\n for(auto e:es){\n uf.unite(e.a,e.b);\n cost=e.c;\n if(uf.count()==1) break;\n }\n cout<<cost<<\" \";\n\n uf=UnionFind(n);\n for(auto e:es){\n if(e.c==cost) break;\n uf.unite(e.a,e.b);\n }\n\n vector<int> rs;\n for(int i=0;i<n;i++)\n if(uf.find(i)==i) rs.emplace_back(i);\n\n M ans{0};\n int k=rs.size();\n int sz=1<<k;\n for(int b=1;b+1<sz;b++){\n UnionFind tmp(uf);\n for(int i=0;i<k;i++)\n for(int j=0;j<k;j++)\n if(((b>>i)&1)==((b>>j)&1))\n tmp.unite(rs[i],rs[j]);\n\n if(tmp.count()!=2) continue;\n\n MatrixTreeTheorem<M, int> G(n);\n for(auto e:es)\n if(tmp.same(e.a,e.b))\n G.add_edge(e.a,e.b,0);\n\n ans+=G.build();\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 0.13333333333333333, "time_ms": 50, "memory_kb": 3260, "score_of_the_acc": -0.0599, "final_rank": 16 }, { "submission_id": "aoj_0314_3049139", "code_snippet": "#include <stdio.h>\n#include <set>\n#include <queue>\n#include <map>\n#include <utility>\nusing namespace std;\nconst int MOD=1e9+7;\nconst int N=1e2+10;\nint p[N];\nint find(int n){\n return p[n]==n?n:p[n]=find(p[n]);\n}\nstruct side{\n int from;\n int to;\n int length;\n void in(){\n scanf(\"%d%d%d\",&from,&to,&length);\n return ;\n }\n void pull(){\n from=find(from);\n to=find(to);\n return ;\n }\n bool out(){\n return from==to;\n }\n void operator =(side a){\n from=a.from;\n to=a.to;\n length=a.length;\n return ;\n }\n};\nstruct cmp{\n bool operator ()(const side& a,const side& b){\n return a.length>b.length;\n }\n};\nstruct matrix{\n int size;\n vector<vector<int>> v;\n void init(int n){\n v.clear();\n size=n;\n vector<int> emp;\n emp.clear();\n for(int i=0;i<n;i++){\n v.push_back(emp);\n for(int j=0;j<n;j++)v.back().push_back(0);\n }\n return ;\n }\n};\nset<int> graph[N],ng[N],ins;\nint n,size[N],ns=0;\nlong long int ans=0;\nvoid swap(int &a,int &b){\n int temp=a;\n a=b;\n b=temp;\n return ;\n}\nlong long int gcd(long long int a,long long int b){\n if(b==0)return a;\n return gcd(b,a%b)%MOD;\n}\nlong long int pow(long long int a,int t){\n if(t==0)return 1;\n long long int temp=pow(a,t/2);\n temp*=temp;\n temp%=MOD;\n if(t&1){\n temp*=a;\n temp%=MOD;\n }\n return temp;\n}\nlong long int rev(long long int a){\n return pow(a,MOD-2);\n}\nlong long int det(matrix &m){\n long long int temp=1,piv,mul;\n for(int i=0;i<m.size;i++){\n if(m.v[i][i]==0){\n for(int j=i+1;j<m.size;j++)if(m.v[j][i]!=0){\n for(int k=i;k<m.size;k++)swap(m.v[j][k],m.v[i][k]);\n break;\n }\n }\n for(int j=i+1;j<m.size;j++)if(m.v[j][i]!=0){\n piv=m.v[i][i]/gcd(m.v[i][i],m.v[j][i]);\n mul=m.v[j][i]/gcd(m.v[i][i],m.v[j][i]);\n for(int k=i;k<m.size;k++)m.v[j][k]=(m.v[j][k]*piv-m.v[i][k]*mul)%MOD;\n temp*=rev(piv);\n temp%=MOD;\n }\n }\n for(int i=0;i<m.size;i++){\n temp*=m.v[i][i];\n temp%=MOD;\n }\n return temp;\n}\nlong long int lap(set<int>& s){\n matrix m;\n map<int,int> ma;\n int now=0;\n for(int i=1;i<=n;i++)if(s.find(find(i))!=s.end())ma.insert({i,now++});\n if(ma.size()==1)return 1;\n m.init((int)ma.size());\n for(pair<int,int> i:ma){\n for(int j:graph[i.first]){\n if(ma.find(j)!=ma.end()){\n m.v[i.second][i.second]++;\n m.v[i.second][ma[j]]=-1;\n }\n }\n }\n for(int i=0;i<m.size;i++)m.v[i][0]=m.v[0][i]=0;\n m.v[0][0]=1;\n return det(m);\n}\nvoid dfs(int now){\n if(now>n){\n if(!ins.empty()){\n queue<int> q;\n set<int> in=ins,left,right;\n int temp;\n q.push(*in.begin());\n in.erase(in.begin());\n while(!q.empty()){\n temp=q.front();\n q.pop();\n for(int i:ng[temp]){\n if(in.find(i)!=in.end()){\n in.erase(i);\n q.push(i);\n }\n }\n }\n if(in.empty()){\n for(int i=1;i<=n;i++)if(p[i]==i&&ins.find(i)==ins.end())in.insert(i);\n if(!in.empty()){\n q.push(*in.begin());\n in.erase(in.begin());\n while(!q.empty()){\n temp=q.front();\n q.pop();\n for(int i:ng[temp]){\n if(in.find(i)!=in.end()){\n in.erase(i);\n q.push(i);\n }\n }\n }\n if(in.empty()){\n for(int i=1;i<=n;i++)if(p[i]==i){\n if(ins.find(i)==ins.end())left.insert(i);\n else right.insert(i);\n }\n ans+=(lap(left)*lap(right))%MOD;\n ans%=MOD;\n }\n }\n }\n }\n return ;\n }\n if(p[now]==now){\n ins.insert(now);\n ns+=size[now];\n dfs(now+1);\n ins.erase(now);\n ns-=size[now];\n }\n dfs(now+1);\n return ;\n}\nint main(){\n int m,now,in,l,r;\n side temp,s[N*N];\n priority_queue<side,vector<side>,cmp> pq;\n scanf(\"%d%d\",&n,&m);\n in=n;\n for(int i=1;i<=n;i++)p[i]=i;\n for(int i=0;i<m;i++){\n temp.in();\n s[i]=temp;\n graph[temp.from].insert(temp.to);\n graph[temp.to].insert(temp.from);\n pq.push(temp);\n \n }\n now=pq.top().length;\n while(in>1){\n temp=pq.top();\n now=temp.length;\n pq.pop();\n temp.pull();\n if(!temp.out()){\n p[temp.from]=temp.to;\n in--;\n }\n while(!pq.empty()){\n if(pq.top().length<=now){\n temp=pq.top();\n pq.pop();\n temp.pull();\n if(!temp.out()){\n p[temp.from]=temp.to;\n in--;\n }\n }\n else break;\n }\n }\n for(int i=1;i<=n;i++){\n p[i]=i;\n size[i]=0;\n }\n for(int i=0;i<m;i++)if(s[i].length<now){\n s[i].pull();\n p[s[i].from]=s[i].to;\n }\n for(int i=1;i<=n;i++){\n l=find(i);\n size[l]++;\n for(int j:graph[i]){\n r=find(j);\n if(l!=r){\n ng[l].insert(r);\n ng[r].insert(l);\n }\n }\n }\n dfs(1);\n if(ans<0){\n ans%=MOD;\n ans+=MOD;\n }\n printf(\"%d %lld\\n\",now,ans%MOD);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3440, "score_of_the_acc": -0.0625, "final_rank": 3 }, { "submission_id": "aoj_0314_3049126", "code_snippet": "#include <stdio.h>\n#include <set>\n#include <queue>\n#include <map>\n#include <utility>\nusing namespace std;\nconst int MOD=1e9+7;\nconst int N=1e2+10;\nint p[N];\nint find(int n){\n return p[n]==n?n:p[n]=find(p[n]);\n}\nstruct side{\n int from;\n int to;\n int length;\n void in(){\n scanf(\"%d%d%d\",&from,&to,&length);\n return ;\n }\n void pull(){\n from=find(from);\n to=find(to);\n return ;\n }\n bool out(){\n return from==to;\n }\n void operator =(side a){\n from=a.from;\n to=a.to;\n length=a.length;\n return ;\n }\n};\nstruct cmp{\n bool operator ()(const side& a,const side& b){\n return a.length>b.length;\n }\n};\nstruct matrix{\n int size;\n vector<vector<int>> v;\n void init(int n){\n v.clear();\n size=n;\n vector<int> emp;\n emp.clear();\n for(int i=0;i<n;i++){\n v.push_back(emp);\n for(int j=0;j<n;j++)v.back().push_back(0);\n }\n return ;\n }\n};\nset<int> graph[N],ng[N],ins;\nint n,size[N],ns=0;\nlong long int ans=0;\nvoid swap(int &a,int &b){\n int temp=a;\n a=b;\n b=temp;\n return ;\n}\nlong long int gcd(long long int a,long long int b){\n if(b==0)return a;\n return gcd(b,a%b)%MOD;\n}\nlong long int pow(long long int a,int t){\n if(t==0)return 1;\n long long int temp=pow(a,t/2);\n temp*=temp;\n temp%=MOD;\n if(t&1){\n temp*=a;\n temp%=MOD;\n }\n return temp;\n}\nlong long int rev(long long int a){\n return pow(a,MOD-2);\n}\nlong long int det(matrix &m){\n long long int temp=1,piv,mul;\n int a=1;\n for(int i=0;i<m.size;i++){\n if(m.v[i][i]==0){\n for(int j=i+1;j<m.size;j++)if(m.v[j][i]!=0){\n for(int k=i;k<m.size;k++)swap(m.v[j][k],m.v[i][k]);\n break;\n }\n }\n if(m.v[i][i]<0){\n a*=-1;\n for(int j=i;j<m.size;j++)m.v[i][j]*=-1;\n }\n for(int j=i+1;j<m.size;j++)if(m.v[j][i]!=0){\n if(m.v[j][i]<0){\n a*=-1;\n for(int k=i;k<m.size;k++)m.v[j][k]*=-1;\n }\n piv=m.v[i][i]/gcd(m.v[i][i],m.v[j][i]);\n mul=m.v[j][i]/gcd(m.v[i][i],m.v[j][i]);\n for(int k=i;k<m.size;k++)m.v[j][k]=(m.v[j][k]*piv-m.v[i][k]*mul)%MOD;\n temp*=rev(piv);\n temp%=MOD;\n }\n }\n for(int i=0;i<m.size;i++){\n temp*=m.v[i][i];\n temp%=MOD;\n }\n return temp*a;\n}\nlong long int lap(set<int>& s){\n matrix m;\n map<int,int> ma;\n int now=0;\n for(int i=1;i<=n;i++)if(s.find(find(i))!=s.end())ma.insert({i,now++});\n if(ma.size()==1)return 1;\n m.init((int)ma.size());\n for(pair<int,int> i:ma){\n for(int j:graph[i.first]){\n if(ma.find(j)!=ma.end()){\n m.v[i.second][i.second]++;\n m.v[i.second][ma[j]]=-1;\n }\n }\n }\n for(int i=0;i<m.size;i++)m.v[i][0]=m.v[0][i]=0;\n m.v[0][0]=1;\n return det(m);\n}\nvoid dfs(int now){\n if(now>n){\n if(!ins.empty()){\n queue<int> q;\n set<int> in=ins,left,right;\n int temp;\n q.push(*in.begin());\n in.erase(in.begin());\n while(!q.empty()){\n temp=q.front();\n q.pop();\n for(int i:ng[temp]){\n if(in.find(i)!=in.end()){\n in.erase(i);\n q.push(i);\n }\n }\n }\n if(in.empty()){\n for(int i=1;i<=n;i++)if(p[i]==i&&ins.find(i)==ins.end())in.insert(i);\n if(!in.empty()){\n q.push(*in.begin());\n in.erase(in.begin());\n while(!q.empty()){\n temp=q.front();\n q.pop();\n for(int i:ng[temp]){\n if(in.find(i)!=in.end()){\n in.erase(i);\n q.push(i);\n }\n }\n }\n if(in.empty()){\n for(int i=1;i<=n;i++)if(p[i]==i){\n if(ins.find(i)==ins.end())left.insert(i);\n else right.insert(i);\n }\n ans+=(lap(left)*lap(right))%MOD;\n ans%=MOD;\n }\n }\n }\n }\n return ;\n }\n if(p[now]==now){\n ins.insert(now);\n ns+=size[now];\n dfs(now+1);\n ins.erase(now);\n ns-=size[now];\n }\n dfs(now+1);\n return ;\n}\nint main(){\n int m,now,in,l,r;\n side temp,s[N*N];\n priority_queue<side,vector<side>,cmp> pq;\n scanf(\"%d%d\",&n,&m);\n in=n;\n for(int i=1;i<=n;i++)p[i]=i;\n for(int i=0;i<m;i++){\n temp.in();\n s[i]=temp;\n graph[temp.from].insert(temp.to);\n graph[temp.to].insert(temp.from);\n pq.push(temp);\n }\n now=pq.top().length;\n while(in>1){\n temp=pq.top();\n now=temp.length;\n pq.pop();\n temp.pull();\n if(!temp.out()){\n p[temp.from]=temp.to;\n in--;\n }\n while(!pq.empty()){\n if(pq.top().length<=now){\n temp=pq.top();\n pq.pop();\n temp.pull();\n if(!temp.out()){\n p[temp.from]=temp.to;\n in--;\n }\n }\n else break;\n }\n }\n for(int i=1;i<=n;i++){\n p[i]=i;\n size[i]=0;\n }\n for(int i=0;i<m;i++)if(s[i].length<now){\n s[i].pull();\n p[s[i].from]=s[i].to;\n }\n for(int i=1;i<=n;i++){\n l=find(i);\n size[l]++;\n for(int j:graph[i]){\n r=find(j);\n if(l!=r){\n ng[l].insert(r);\n ng[r].insert(l);\n }\n }\n }\n dfs(1);\n \n printf(\"%d %lld\\n\",now,ans);\n}", "accuracy": 0.06666666666666667, "time_ms": 10, "memory_kb": 3380, "score_of_the_acc": -0.0322, "final_rank": 17 }, { "submission_id": "aoj_0314_2683007", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define double long double\nusing namespace std;\nconst int N = 100010;\nconst int INF = 1LL<<55;\nconst int mod = (1e9)+7;\nconst double EPS = 1e-8;\nconst double PI = 6.0 * asin(0.5);\ntypedef pair<int,int> P;\ntypedef long long ll;\nostream& operator<<(ostream& o,P p){return o<<\"(\"<<p.first<<\",\"<<p.second<<\")\";}\nistream& operator>>(istream& i,P &p){return i>>p.first>>p.second;}\ntemplate<class T> istream& operator>>(istream& i,vector<T> &a){for(auto &t:a)cin>>t;return i;}\ntemplate<class T> T Max(T &a,T b){return a=max(a,b);}\ntemplate<class T> T Min(T &a,T b){return a=min(a,b);}\ntemplate<class T> void prArr(T a,string s=\" \"){int i=0;for(auto t:a)cout<<(i++?s:\"\")<<t;cout<<endl;}\n\nclass UF{\npublic:\n int V;\n vector<int> par,rnk,sz;\n UF(){}\n UF(int V):V(V),par(V),rnk(V,0),sz(V,1){for(int i=0;i<V;i++)par[i]=i;}\n \n int find(int x){\n assert(x < V);\n if(par[x]==x)return x;\n return par[x]=find(par[x]);\n }\n \n void unite(int x,int y){\n x=find(x), y=find(y);\n if(x==y)return;\n if(rnk[x]<rnk[y])par[x]=y, sz[y] += sz[x];\n else{\n par[y]=x;\n sz[x] += sz[y];\n if(rnk[x]==rnk[y])rnk[x]++;\n }\n }\n\n bool same(int x,int y){return find(x)==find(y);}\n\n int size(int x){return sz[find(x)];}\n};\n\nint mod_determinant(vector<vector<int> > A,const int mod = 1e9+7/*素数のみ使用可能*/){\n /*long longにしないと死ぬので注意*/\n auto mod_pow =[&](int x,int n){\n int res=1;\n while(n){\n if(n%2) res=res*x%mod;\n x=x*x%mod;\n n/=2;\n }\n return res;\n };\n \n int n = A.size();\n for(int i=0;i<n;i++)\n for(int j=0;j<n;j++) A[i][j] = (A[i][j]%mod + mod) % mod;\n \n \n int det = 1;\n for(int i=0;i<n;i++){\n int pivot=-1;//次の基準となる添え字。\n for(int j=i;j<n && pivot==-1;j++) if(A[j][i]!=0) pivot=j;//0以外の1つを探す\n \n if(pivot == -1) return 0; // det = 0;\n swap(A[i],A[pivot]);//i行目に持ってくる。\n if(i != pivot) det = (-det + mod) % mod;\n det = det * A[i][i] % mod;\n \n int div = mod_pow(A[i][i],mod-2);\n for(int j=i+1;j<n;j++) A[i][j]=A[i][j]*div%mod; //左辺をA[i][i]で両辺を割る。\n \n for(int j=i+1;j<n;j++){ \n for(int k=i+1;k<n;k++) A[j][k]=(A[j][k]-A[j][i]*A[i][k]%mod+mod)%mod;\n A[j][i] = 0;\n }\n }\n return det;\n}\n\nint calcL(vector<vector<int> > L){\n int n = L.size();\n vector<vector<int> > LL(n-1,vector<int>(n-1));\n\n for(int i=1;i<n;i++)\n for(int j=1;j<n;j++) LL[i-1][j-1] = L[i][j];\n return mod_determinant(LL);\n}\n\nvector<vector<int> > G;\nint calc(UF &uf,int par){\n vector<int> num;\n int n = G.size();\n for(int i=0;i<n;i++) if(uf.find(i) == par) num.push_back(i);\n sort(num.begin(),num.end());\n \n int l = num.size();\n vector<vector<int> > L(l,vector<int>(l));\n for(int i:num)\n for(int to:G[i]){\n int a = lower_bound(num.begin(),num.end(),i) - num.begin();\n int b = lower_bound(num.begin(),num.end(),to) - num.begin();\n if(b == l || num[b] != to) continue;\n L[a][b]--;\n L[a][a]++;\n } \n \n return calcL(L);\n};\n\n\nsigned main(){\n int n,m;\n cin>>n>>m;\n typedef pair<int,P> PP;\n vector<PP> edge(m);\n G.resize(n);\n for(int i=0;i<m;i++){\n int s,t,d;\n cin>>s>>t>>d; s--,t--;\n edge[i] = PP(d,P(s,t));\n G[s].push_back(t);\n G[t].push_back(s);\n }\n sort(edge.begin(),edge.end());\n\n UF uf(n);\n int dis = 0;\n for(int i=0;i<m;i++){\n int idx = i;\n UF tmp = uf;\n dis = edge[idx].first;\n \n while(i<m && edge[idx].first == edge[i].first){\n int a,b; tie(a,b) = edge[i].second;\n tmp.unite(a,b);\n i++;\n }\n i--;\n if(tmp.size(0) == n) break;\n uf = tmp;\n }\n\n \n vector<int> par;\n for(int i=0;i<n;i++) if(uf.find(i) == i) par.push_back(i);\n\n int ans = 0;\n int p = par.size();\n for(int bit=0;bit<(1<<p);bit++){\n UF tmp = uf;\n \n for(int i=0;i<p;i++)\n for(int j=0;j<p;j++)\n if((bit>>i&1) == (bit>>j&1)) tmp.unite(par[i],par[j]);\n \n \n int cnt = 0;\n for(int i=0;i<n;i++) if(tmp.find(i) == i) cnt++;\n if(cnt != 2) continue;\n int num = 1;\n for(int i=0;i<n;i++) if(tmp.find(i) == i) num = num * calc(tmp,i)%mod;\n ans = (ans+num)%mod;\n }\n cout<<dis<<\" \"<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3540, "score_of_the_acc": -0.3973, "final_rank": 11 }, { "submission_id": "aoj_0314_2415561", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<vector>\n#include<set>\n#include<map>\n#include<queue>\n#include<string>\n#include<cmath>\n#include<cassert>\n\nusing namespace std;\n\n#define REP(i, b, e) for( int i = b; i < e; i++ )\n#define rep(i, n) REP(i, 0, n)\n\n#define MAX 200\n#define INFTY (1<<30)\n\ntypedef vector<vector<int> > Matrix;\ntypedef long long ll;\n\n#define MOD 1000000007\n\nclass DisjointSet{\n public:\n DisjointSet(){}\n DisjointSet( int size ){\n rank.resize( size, 0 );\n p.resize( size, 0 );\n }\n \n void makeSet( int x ){\n p[x] = x;\n rank[x] = 0;\n }\n \n void merge( int x, int y ){\n link( findSet(x), findSet(y) );\n }\n \n int findSet( int x ){\n if ( x != p[x] ) p[x] = findSet( p[x] );\n return p[x];\n }\n \n bool isSameSet( int x, int y ){\n return ( findSet(x) == findSet(y) );\n }\n \n private:\n vector<int> rank, p;\n \n void link ( int x, int y ){\n if ( rank[x] > rank[y] ){\n p[y] = x;\n } else {\n p[x] = y;\n if ( rank[x] == rank[y] ) rank[y]++;\n }\n }\n};\n\nclass Edge{\n public:\n int source, target, cost;\n Edge( int source=0, int target=0, int cost=0 ):\n source(source), target(target), cost(cost){}\n bool operator < ( const Edge &e ) const{\n return cost < e.cost;\n }\n};\n\nint kruskal(int N, vector<Edge> edges){ // vector<Edge> &mst\n int lastCost = -1;\n sort( edges.begin(), edges.end() );\n \n DisjointSet dset = DisjointSet( N + 1);\n \n for ( int i = 0; i < N; i++ ) dset.makeSet( i );\n \n int source, target;\n for ( int i = 0; i < edges.size(); i++ ){\n Edge e = edges[i];\n if ( dset.findSet( e.source ) != dset.findSet( e.target ) ){\n lastCost = e.cost;\n dset.merge( e.source, e.target );\n }\n }\n return lastCost;\n}\n\nvoid dfs( Matrix G, int id, int u, int w, vector<int> &l, vector<int> &ID){\n ID[u] = id;\n l.push_back(u);\n for ( int v = 0; v < G.size(); v++ ){\n if ( ID[v] == -1 && G[u][v] < w ) dfs(G, id, v, w, l, ID);\n }\n}\n\nvoid printComps(vector<vector<int> > &comps){\n cout << comps.size() << \" components\" << endl;\n for ( int i = 0; i < comps.size(); i++ ){\n cout << i << \":\";\n for ( int j = 0; j < comps[i].size(); j++ ) cout << \" \" << comps[i][j];\n cout << endl;\n }\n}\n\nvoid checkID(vector<vector<int> > &comps, vector<int> ID){\n int cnt = 0;\n for ( int i = 0; i < comps.size(); i++ ){\n for ( int j = 0; j < comps[i].size(); j++ ) {\n int v = comps[i][j];\n assert( ID[v] == i );\n cnt++;\n }\n }\n assert( cnt == ID.size() );\n}\n\nvoid initMatrix(Matrix &m){\n for ( int i = 0; i < m.size(); i++ ){\n for ( int j = 0; j < m[i].size(); j++ ) m[i][j] = 0;\n }\n}\n\n\nll det(int n, int a[MAX][MAX], ll mod){\n rep(i, n) rep(j, n) assert( a[i][j] == a[j][i] );\n\n ll ans = 1;\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n for (; a[j][i] != 0; ans = -ans) {\n\tll r = a[i][i] / a[j][i];\n\tfor (int k = i; k < n; k++) {\n\t ll t = (a[i][k] - r * a[j][k]) % mod;\n\t a[i][k] = a[j][k];\n\t a[j][k] = t;\n\t}\n }\n }\n ans = ans * a[i][i] % mod;\n }\n return (ans + mod) % mod;\n}\n\nbool isConnected(Matrix M, vector<int> nodes){\n queue<int> Q;\n int d[MAX];\n for ( int i = 0; i < M.size(); i++ ) d[i] = INFTY;\n\n Q.push(nodes[0]);\n d[nodes[0]] = 0;\n int u, v;\n while( !Q.empty() ){\n u = Q.front(); Q.pop();\n for ( int v = 0; v < M.size(); v++ ){\n if ( M[u][v] && d[v] == INFTY ){\n\td[v] = d[u] + 1;\n\tQ.push(v);\n }\n }\n }\n\n for ( int i = 0; i < nodes.size(); i++ ){\n if ( d[nodes[i]] == INFTY ) return false;\n }\n return true;\n}\n\nll spCount(Matrix M, vector<int> IDM, vector<int> ID, int tgt, vector<int> nodes){\n int a[MAX][MAX];\n int deg[MAX];\n\n rep(i, M.size() ) deg[i] = 0;\n\n int ii = 0;\n rep(i, M.size() ){\n if ( IDM[ID[i]] != tgt ) continue;\n int jj = 0;\n rep(j, M.size() ){\n if ( IDM[ID[j]] != tgt ) continue;\n if ( i < j && M[i][j] ) {\n\tdeg[ii]++;\n\tdeg[jj]++;\n }\n a[ii][jj] = M[i][j]*(-1);\n\n jj++;\n }\n ii++;\n }\n\n rep(i, ii) a[i][i] = deg[i];\n\n assert(ii == nodes.size());\n\n ll d = det(ii-1, a, MOD);\n\n\n return d;\n}\n\nvoid solve(vector<Edge> edges, vector<vector<int> > G, vector<int> ID){\n int w = kruskal(G.size(), edges);\n\n cout << w << \" \";\n vector<vector<int> > comps;\n rep(i, G.size()) ID[i] = -1;\n int id = 0;\n for ( int s = 0; s < G.size(); s++ ){\n if ( ID[s] == -1 ){\n vector<int> l;\n dfs(G, id++, s, w, l, ID);\n comps.push_back(l);\n }\n }\n \n vector<int> IDM; // comp index to A/B (0/1);\n Matrix A, B;\n A = B = G;\n int nc = comps.size();\n IDM.resize(nc);\n\n ll sum = 0;\n\n for ( int s = 1; s < (1<<nc)-1; s++ ){ // exclude 00000 and 11111\n vector<int> nodeA, nodeB;\n for ( int i = 0; i < nc; i++ ){\n IDM[i] = ((s & (1<<i))>0);\n if ( IDM[i] == 1 ) {\n\tfor ( int j = 0; j < comps[i].size(); j++ ) nodeA.push_back(comps[i][j]);\n } else {\n\tfor ( int j = 0; j < comps[i].size(); j++ ) nodeB.push_back(comps[i][j]);\n }\n }\n initMatrix(A);\n initMatrix(B);\n\n for ( int k = 0; k < edges.size(); k++ ){\n Edge e = edges[k];\n if ( IDM[ID[e.source]] == IDM[ID[e.target]] ){\n\tif ( IDM[ID[e.source]] == 1 ){\n\t A[e.source][e.target] = A[e.target][e.source] = 1;\n\t} else {\n\t assert( IDM[ID[e.source]] == 0);\n\t B[e.source][e.target] = B[e.target][e.source] = 1;\n\t}\n }\n }\n\n ll cntA = spCount(A, IDM, ID, 1, nodeA);\n ll cntB = spCount(B, IDM, ID, 0, nodeB);\n\n sum = (sum + (cntA*cntB)%MOD ) % MOD;\n\n }\n\n cout << sum << endl;\n}\n\nint main(){\n int N, M, cost, source, target;\n \n cin >> N >> M;\n\n vector<vector<int> > G;\n vector<int> ID;\n \n rep(i, N) {\n vector<int> g;\n rep(j, N) g.push_back(INFTY);\n G.push_back(g);\n ID.push_back(-1);\n }\n \n vector<Edge> edges;\n for ( int i = 0; i < M; i++ ){\n cin >> source >> target >> cost;\n source--; target--;\n\n assert( 0 <= source && source < N);\n assert( 0 <= target && target < N);\n assert( 0 <= cost && cost <= 1000000000 );\n\n edges.push_back(Edge(source, target, cost));\n G[source][target] = G[target][source] = cost;\n }\n solve(edges, G, ID);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7104, "score_of_the_acc": -1, "final_rank": 12 }, { "submission_id": "aoj_0314_2341164", "code_snippet": "#define _USE_MATH_DEFINES\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <fstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <limits>\n#include <climits>\n#include <cfloat>\n#include <functional>\n#include <iterator>\nusing namespace std;\n\nclass UnionFindTree\n{\nprivate:\n int n;\n int groupNum; // ??°??????????????°\n vector<int> parent; // ????????????\n vector<int> rank; // ??¨??????????????????\n vector<int> num; // ??°????????????????´???°\n int find(int i){\n if(parent[i] == i)\n return i;\n else\n return parent[i] = find(parent[i]);\n }\npublic:\n UnionFindTree(int n){ // ?????????????????????\n this->n = n;\n groupNum = n;\n parent.resize(n);\n for(int i=0; i<n; ++i)\n parent[i] = i;\n rank.assign(n, 0);\n num.assign(n, 1);\n }\n void unite(int a, int b){ // a??¨b?????°??????????????????\n if((a = find(a)) != (b = find(b))){\n if(rank[a] < rank[b]){\n parent[a] = b;\n num[b] += num[a];\n }\n else{\n parent[b] = a;\n if(rank[a] == rank[b])\n ++ rank[a];\n num[a] += num[b];\n }\n -- groupNum;\n }\n }\n bool same(int a, int b){ // a??¨b?????°?????????????????????????????????\n return find(a) == find(b);\n }\n int getNum(){ // ??°??????????????°?????????\n return groupNum;\n }\n int getNum(int a){ // a?????°????????????????´???°?????????\n return num[find(a)];\n }\n void getGroup(vector<vector<int> >& group){ // ??°??????????§?????????????\n map<int, int> index;\n group.clear();\n for(int i=0; i<n; ++i){\n int a = find(i);\n if(index.find(a) == index.end()){\n index[a] = group.size();\n group.resize(group.size() + 1);\n }\n group[index[a]].push_back(i);\n }\n }\n};\n\ntemplate <class T1>\nclass Operators\n{\npublic:\n template <class T2>\n const T1 operator+(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans += right;\n return ans;\n }\n template <class T2>\n const T1 operator-(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans -= right;\n return ans;\n }\n template <class T2>\n const T1 operator*(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans *= right;\n return ans;\n }\n template <class T2>\n const T1 operator/(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans /= right;\n return ans;\n }\n bool operator!=(const T1& right) const{\n const T1& left = static_cast<const T1&>( *this );\n return !(left == right);\n }\n};\n\nclass Mod : public Operators<Mod>\n{\nprivate:\n static const int MOD = 1000000007;\n long long a;\npublic:\n Mod(){\n a = 0;\n }\n Mod(long long x){\n a = (x % MOD + MOD) % MOD;\n }\n Mod& operator+=(const Mod& x){\n a = (a + x.a) % MOD;\n return *this;\n }\n Mod& operator-=(const Mod& x){\n a = (a - x.a + MOD) % MOD;\n return *this;\n }\n Mod& operator*=(const Mod& x){\n a = (a * x.a) % MOD;\n return *this;\n }\n Mod& operator/=(const Mod& x){ // ?????§?????????????°??????????MOD????´???°??§????????´???????????????\n int b = MOD - 2;\n long long c = x.a;\n while(b > 0){\n if(b & 1){\n a *= c;\n a %= MOD;\n }\n c *= c;\n c %= MOD;\n b >>= 1;\n }\n return *this;\n }\n bool operator==(const Mod& x) const{\n return a == x.a;\n }\n long long getValue(){\n return a;\n }\n};\n\n// ?????????????¨??????????\nMod determinant(vector<vector<Mod> > mat)\n{\n const int n = mat.size();\n Mod ret = 1;\n for(int i=0; i<n; ++i){\n int tmp = -1;\n for(int j=i; j<n; ++j){\n if(mat[j][i] != 0){\n tmp = j;\n break;\n }\n }\n if(tmp == -1)\n return 0;\n if(tmp != i){\n mat[i].swap(mat[tmp]);\n ret *= -1;\n }\n\n for(int j=i+1; j<n; ++j){\n for(int k=n-1; k>=i; --k){\n mat[j][k] -= mat[i][k] * (mat[j][i] / mat[i][i]);\n }\n }\n ret *= mat[i][i];\n }\n return ret;\n}\n\n/***************************************************************************************************/\n// ????????¨??????\n// ??????????????¢??????????????¨????????¨?????¨????????°????±???????\n//\n// graph : ????????°??????\n/***************************************************************************************************/\nMod MatrixTreeTheorem(const vector<vector<int> >& graph)\n{\n int n = graph.size();\n vector<vector<Mod> > mat(n-1, vector<Mod>(n-1, 0));\n for(int i=0; i<n-1; ++i){\n for(int j=0; j<n-1; ++j){\n mat[i][j] = -graph[i][j];\n if(i == j)\n mat[i][j] += accumulate(graph[i].begin(), graph[i].end(), Mod(0));\n }\n }\n return determinant(mat);\n}\n\npair<int, int> solve(int n, const vector<tuple<int, int, int> >& edges)\n{\n int m = edges.size();\n UnionFindTree uft(n);\n int dMax;\n for(int i=0; ; ++i){\n int d, s, t;\n tie(d, s, t) = edges[i];\n uft.unite(s, t);\n if(uft.getNum() == 1){\n dMax = d;\n break;\n }\n }\n\n uft = UnionFindTree(n);\n for(int i=0; i<m; ++i){\n int d, s, t;\n tie(d, s, t) = edges[i];\n if(d < dMax)\n uft.unite(s, t);\n }\n vector<vector<int> > group;\n uft.getGroup(group);\n\n int x = group.size();\n Mod ans = 0;\n for(int i=1; i<(1<<(x-1)); ++i){\n bitset<32> bs(i);\n vector<vector<int> > v(2);\n for(int j=0; j<x; ++j){\n int k = (bs[j] ? 0 : 1);\n copy(group[j].begin(), group[j].end(), back_inserter(v[k]));\n }\n\n Mod tmp = 1;\n for(int j=0; j<2; ++j){\n int y = v[j].size();\n vector<int> index(n, -1);\n for(int k=0; k<y; ++k)\n index[v[j][k]] = k;\n\n vector<vector<int> > graph(y, vector<int>(y, 0));\n for(int k=0; k<m; ++k){\n int d, s, t;\n tie(d, s, t) = edges[k];\n if(index[s] != -1 && index[t] != -1){\n ++ graph[index[s]][index[t]];\n ++ graph[index[t]][index[s]];\n }\n }\n tmp *= MatrixTreeTheorem(graph);\n }\n ans += tmp;\n }\n ans *= 2;\n\n return make_pair(dMax, (int)ans.getValue());\n}\n\nint main()\n{\n int n, m;\n cin >> n >> m;\n vector<tuple<int, int, int> > edges(m);\n for(int i=0; i<m; ++i){\n int s, t, d;\n cin >> s >> t >> d;\n -- s;\n -- t;\n edges[i] = make_tuple(d, s, t);\n }\n sort(edges.begin(), edges.end());\n\n pair<int, int> ans = solve(n, edges);\n cout << ans.first << ' ' << ans.second << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 3256, "score_of_the_acc": -1, "final_rank": 12 }, { "submission_id": "aoj_0314_2339413", "code_snippet": "#define _USE_MATH_DEFINES\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <fstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <limits>\n#include <climits>\n#include <cfloat>\n#include <functional>\n#include <iterator>\nusing namespace std;\n\nclass UnionFindTree\n{\nprivate:\n const int n;\n int groupNum; // ??°??????????????°\n vector<int> parent; // ????????????\n vector<int> rank; // ??¨??????????????????\n vector<int> num; // ??°????????????????´???°\n int find(int i){\n if(parent[i] == i)\n return i;\n else\n return parent[i] = find(parent[i]);\n }\npublic:\n UnionFindTree(int n) : n(n){ // ?????????????????????\n groupNum = n;\n parent.resize(n);\n for(int i=0; i<n; ++i)\n parent[i] = i;\n rank.assign(n, 0);\n num.assign(n, 1);\n }\n void unite(int a, int b){ // a??¨b?????°??????????????????\n if((a = find(a)) != (b = find(b))){\n if(rank[a] < rank[b]){\n parent[a] = b;\n num[b] += num[a];\n }\n else{\n parent[b] = a;\n if(rank[a] == rank[b])\n ++ rank[a];\n num[a] += num[b];\n }\n -- groupNum;\n }\n }\n bool same(int a, int b){ // a??¨b?????°?????????????????????????????????\n return find(a) == find(b);\n }\n int getNum(){ // ??°??????????????°?????????\n return groupNum;\n }\n int getNum(int a){ // a?????°????????????????´???°?????????\n return num[find(a)];\n }\n void getGroup(vector<vector<int> >& group){ // ??°??????????§?????????????\n map<int, int> index;\n group.clear();\n for(int i=0; i<n; ++i){\n int a = find(i);\n if(index.find(a) == index.end()){\n index[a] = group.size();\n group.resize(group.size() + 1);\n }\n group[index[a]].push_back(i);\n }\n }\n};\n\ntemplate <class T1>\nclass Operators\n{\npublic:\n template <class T2>\n const T1 operator+(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans += right;\n return ans;\n }\n template <class T2>\n const T1 operator-(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans -= right;\n return ans;\n }\n template <class T2>\n const T1 operator*(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans *= right;\n return ans;\n }\n template <class T2>\n const T1 operator/(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans /= right;\n return ans;\n }\n bool operator!=(const T1& right) const{\n const T1& left = static_cast<const T1&>( *this );\n return !(left == right);\n }\n};\n\nclass Mod : public Operators<Mod>\n{\nprivate:\n static const int MOD = 1000000007;\n long long a;\npublic:\n Mod(){\n a = 0;\n }\n Mod(long long x){\n a = (x % MOD + MOD) % MOD;\n }\n Mod& operator+=(const Mod& x){\n a = (a + x.a) % MOD;\n return *this;\n }\n Mod& operator-=(const Mod& x){\n a = (a - x.a + MOD) % MOD;\n return *this;\n }\n Mod& operator*=(const Mod& x){\n a = (a * x.a) % MOD;\n return *this;\n }\n Mod& operator/=(const Mod& x){ // ?????§?????????????°??????????MOD????´???°??§????????´???????????????\n int b = MOD - 2;\n long long c = x.a;\n long long ans = 1;\n while(b > 0){\n if(b & 1){\n ans *= c;\n ans %= MOD;\n }\n c *= c;\n c %= MOD;\n b >>= 1;\n }\n a *= ans;\n a %= MOD;\n return *this;\n }\n bool operator==(const Mod& x) const{\n return a == x.a;\n }\n long long getValue(){\n return a;\n }\n};\n\n// ?????????????¨??????????\nMod determinant(vector<vector<Mod> > mat)\n{\n const int n = mat.size();\n Mod ret = 1;\n for(int i=0; i<n; ++i){\n int tmp = -1;\n for(int j=i; j<n; ++j){\n if(mat[j][i] != 0){\n tmp = j;\n break;\n }\n }\n if(tmp == -1)\n return 0;\n if(tmp != i){\n mat[i].swap(mat[tmp]);\n ret *= -1;\n }\n\n for(int j=i+1; j<n; ++j){\n for(int k=n-1; k>=i; --k){\n mat[j][k] -= mat[i][k] * (mat[j][i] / mat[i][i]);\n }\n }\n ret *= mat[i][i];\n }\n return ret;\n}\n\n/***************************************************************************************************/\n// ????????¨??????\n// ??????????????¢??????????????¨????????¨?????¨????????°????±???????\n//\n// graph : ????????°??????\n/***************************************************************************************************/\nMod MatrixTreeTheorem(const vector<vector<int> >& graph)\n{\n int n = graph.size();\n vector<vector<Mod> > mat(n-1, vector<Mod>(n-1, 0));\n for(int i=0; i<n-1; ++i){\n for(int j=0; j<n-1; ++j){\n mat[i][j] = -graph[i][j];\n if(i == j)\n mat[i][j] += accumulate(graph[i].begin(), graph[i].end(), Mod(0));\n }\n }\n return determinant(mat);\n}\n\nint main()\n{\n int n, m;\n cin >> n >> m;\n vector<tuple<int, int, int> > edge(m);\n for(int i=0; i<m; ++i){\n int s, t, d;\n cin >> s >> t >> d;\n -- s;\n -- t;\n edge[i] = make_tuple(d, s, t);\n }\n sort(edge.begin(), edge.end());\n\n UnionFindTree uft(n);\n int dMax;\n for(int i=0; ; ++i){\n int d, s, t;\n tie(d, s, t) = edge[i];\n uft.unite(s, t);\n if(uft.getNum() == 1){\n dMax = d;\n break;\n }\n }\n\n UnionFindTree uft1(n);\n vector<pair<int, int> > v;\n for(int i=0; i<m; ++i){\n int d, s, t;\n tie(d, s, t) = edge[i];\n if(d < dMax)\n uft1.unite(s, t);\n else if(d == dMax)\n v.push_back(make_pair(s, t));\n }\n\n vector<vector<int> > group;\n vector<pair<int, int> > index(n);\n uft1.getGroup(group);\n for(unsigned i=0; i<group.size(); ++i){\n for(unsigned j=0; j<group[i].size(); ++j){\n index[group[i][j]] = make_pair(i, j);\n }\n }\n Mod tmp = 1;\n for(unsigned i=0; i<group.size(); ++i){\n vector<vector<int> > graph(group[i].size(), vector<int>(group[i].size(), 0));\n for(int j=0; j<m; ++j){\n int d, s, t;\n tie(d, s, t) = edge[j];\n if(index[s].first == i && index[t].first == i){\n ++ graph[index[s].second][index[t].second];\n ++ graph[index[t].second][index[s].second];\n }\n }\n tmp *= MatrixTreeTheorem(graph);\n }\n\n int a = v.size();\n Mod ans = 0;\n for(int i=0; i<(1<<a); ++i){\n bitset<32> bs(i);\n UnionFindTree uft2 = uft1;\n bool ok = true;\n for(int j=0; j<a; ++j){\n if(bs[j]){\n if(uft2.same(v[j].first, v[j].second)){\n ok = false;\n break;\n }\n uft2.unite(v[j].first, v[j].second);\n }\n }\n if(ok && uft2.getNum() == 2)\n ans += tmp * 2;\n }\n\n cout << dMax << ' ' << ans.getValue() << endl;\n\n return 0;\n}", "accuracy": 0.26666666666666666, "time_ms": 30, "memory_kb": 3280, "score_of_the_acc": -0.0356, "final_rank": 14 }, { "submission_id": "aoj_0314_2339343", "code_snippet": "#define _USE_MATH_DEFINES\n#include <cstdio>\n#include <iostream>\n#include <sstream>\n#include <fstream>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <vector>\n#include <list>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <bitset>\n#include <numeric>\n#include <limits>\n#include <climits>\n#include <cfloat>\n#include <functional>\n#include <iterator>\nusing namespace std;\n\nclass UnionFindTree\n{\nprivate:\n const int n;\n int groupNum; // ??°??????????????°\n vector<int> parent; // ????????????\n vector<int> rank; // ??¨??????????????????\n vector<int> num; // ??°????????????????´???°\n int find(int i){\n if(parent[i] == i)\n return i;\n else\n return parent[i] = find(parent[i]);\n }\npublic:\n UnionFindTree(int n) : n(n){ // ?????????????????????\n groupNum = n;\n parent.resize(n);\n for(int i=0; i<n; ++i)\n parent[i] = i;\n rank.assign(n, 0);\n num.assign(n, 1);\n }\n void unite(int a, int b){ // a??¨b?????°??????????????????\n if((a = find(a)) != (b = find(b))){\n if(rank[a] < rank[b]){\n parent[a] = b;\n num[b] += num[a];\n }\n else{\n parent[b] = a;\n if(rank[a] == rank[b])\n ++ rank[a];\n num[a] += num[b];\n }\n -- groupNum;\n }\n }\n bool same(int a, int b){ // a??¨b?????°?????????????????????????????????\n return find(a) == find(b);\n }\n int getNum(){ // ??°??????????????°?????????\n return groupNum;\n }\n int getNum(int a){ // a?????°????????????????´???°?????????\n return num[find(a)];\n }\n void getGroup(vector<vector<int> >& group){ // ??°??????????§?????????????\n map<int, int> index;\n group.clear();\n for(int i=0; i<n; ++i){\n int a = find(i);\n if(index.find(a) == index.end()){\n index[a] = group.size();\n group.resize(group.size() + 1);\n }\n group[index[a]].push_back(i);\n }\n }\n};\n\ntemplate <class T1>\nclass Operators\n{\npublic:\n template <class T2>\n const T1 operator+(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans += right;\n return ans;\n }\n template <class T2>\n const T1 operator-(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans -= right;\n return ans;\n }\n template <class T2>\n const T1 operator*(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans *= right;\n return ans;\n }\n template <class T2>\n const T1 operator/(const T2& right) const{\n T1 ans = static_cast<const T1&>( *this );\n ans /= right;\n return ans;\n }\n bool operator!=(const T1& right) const{\n const T1& left = static_cast<const T1&>( *this );\n return !(left == right);\n }\n};\n\nclass Mod : public Operators<Mod>\n{\nprivate:\n static const int MOD = 1000000007;\n long long a;\npublic:\n Mod(){\n a = 0;\n }\n Mod(long long x){\n a = (x % MOD + MOD) % MOD;\n }\n Mod& operator+=(const Mod& x){\n a = (a + x.a) % MOD;\n return *this;\n }\n Mod& operator-=(const Mod& x){\n a = (a - x.a + MOD) % MOD;\n return *this;\n }\n Mod& operator*=(const Mod& x){\n a = (a * x.a) % MOD;\n return *this;\n }\n Mod& operator/=(const Mod& x){ // ?????§?????????????°??????????MOD????´???°??§????????´???????????????\n int b = MOD - 2;\n long long c = x.a;\n long long ans = 1;\n while(b > 0){\n if(b & 1){\n ans *= c;\n ans %= MOD;\n }\n c *= c;\n c %= MOD;\n b >>= 1;\n }\n a *= ans;\n a %= MOD;\n return *this;\n }\n bool operator==(const Mod& x) const{\n return a == x.a;\n }\n long long getValue(){\n return a;\n }\n};\n\n// ?????????????¨??????????\nMod determinant(vector<vector<Mod> > mat)\n{\n const int n = mat.size();\n Mod ret = 1;\n for(int i=0; i<n; ++i){\n int tmp = -1;\n for(int j=i; j<n; ++j){\n if(mat[j][i] != 0){\n tmp = j;\n break;\n }\n }\n if(tmp == -1)\n return 0;\n if(tmp != i){\n mat[i].swap(mat[tmp]);\n ret *= -1;\n }\n\n for(int j=i+1; j<n; ++j){\n for(int k=n-1; k>=i; --k){\n mat[j][k] -= mat[i][k] * (mat[j][i] / mat[i][i]);\n }\n }\n ret *= mat[i][i];\n }\n return ret;\n}\n\n/***************************************************************************************************/\n// ????????¨??????\n// ??????????????¢??????????????¨????????¨?????¨????????°????±???????\n//\n// graph : ????????°??????\n/***************************************************************************************************/\nMod MatrixTreeTheorem(const vector<vector<int> >& graph)\n{\n int n = graph.size();\n vector<vector<Mod> > mat(n-1, vector<Mod>(n-1, 0));\n for(int i=0; i<n-1; ++i){\n for(int j=0; j<n-1; ++j){\n mat[i][j] = -graph[i][j];\n if(i == j)\n mat[i][j] += accumulate(graph[i].begin(), graph[i].end(), Mod(0));\n }\n }\n return determinant(mat);\n}\n\nint main()\n{\n Mod hoge = Mod(-1) * (Mod(-1) / Mod(2));\n Mod piyo = Mod(-1) * Mod(-1) / Mod(2);\n\n int n, m;\n cin >> n >> m;\n vector<tuple<int, int, int> > edge(m);\n for(int i=0; i<m; ++i){\n int s, t, d;\n cin >> s >> t >> d;\n -- s;\n -- t;\n edge[i] = make_tuple(d, s, t);\n }\n sort(edge.begin(), edge.end());\n\n UnionFindTree uft(n);\n int dMax;\n for(int i=0; ; ++i){\n int d, s, t;\n tie(d, s, t) = edge[i];\n uft.unite(s, t);\n if(uft.getNum() == 1){\n dMax = d;\n break;\n }\n }\n\n UnionFindTree uft1(n);\n vector<pair<int, int> > v;\n for(int i=0; i<m; ++i){\n int d, s, t;\n tie(d, s, t) = edge[i];\n if(d < dMax)\n uft1.unite(s, t);\n else if(d == dMax)\n v.push_back(make_pair(s, t));\n }\n\n int a = v.size();\n Mod ans = 0;\n set<vector<vector<int> > > groupHistory;\n for(int i=0; i<(1<<a); ++i){\n bitset<5> bs(i);\n UnionFindTree uft2 = uft1;\n for(int j=0; j<a; ++j){\n if(bs[j])\n uft2.unite(v[j].first, v[j].second);\n }\n if(uft2.getNum() != 2)\n continue;\n\n vector<vector<int> > group;\n uft2.getGroup(group);\n sort(group[0].begin(), group[0].end());\n sort(group[1].begin(), group[1].end());\n sort(group.begin(), group.end());\n if(groupHistory.find(group) != groupHistory.end())\n continue;\n groupHistory.insert(group);\n\n vector<pair<int, int> > index(n);\n for(int j=0; j<2; ++j){\n for(unsigned k=0; k<group[j].size(); ++k){\n index[group[j][k]] = make_pair(j, k);\n }\n }\n\n Mod tmp = 2;\n for(int j=0; j<2; ++j){\n vector<vector<int> > graph(group[j].size(), vector<int>(group[j].size(), 0));\n for(int k=0; k<m; ++k){\n int d, s, t;\n tie(d, s, t) = edge[k];\n if(index[s].first == j && index[t].first == j){\n ++ graph[index[s].second][index[t].second];\n ++ graph[index[t].second][index[s].second];\n }\n }\n tmp *= MatrixTreeTheorem(graph);\n }\n ans += tmp;\n }\n\n cout << dMax << ' ' << ans.getValue() << endl;\n\n return 0;\n}", "accuracy": 0.26666666666666666, "time_ms": 150, "memory_kb": 3320, "score_of_the_acc": -0.2225, "final_rank": 15 } ]
aoj_0322_cpp
Slates Numerous stone slates have been discovered in the ruins of the ancient nation of Iwashiro. Researchers have found that each slate has a single word inscribed on it. However, due to weathering over the years, some of the slates seem to be difficult to decipher for the following reasons. In some cases, only one of the letters of the word on the slate is covered with moss, making it impossible to figure out the word. The left side of the slate is missing (chipped), and there may have been some text written there (we cannot grasp more than or equal to 0 letters on the left side of the slate). The right side of the slate is missing (chipped), and there may have been some text written there (we cannot grasp more than or equat to 0 letters on the right side of the slate). There is at most one place where moss grows on the slate. In addition, although moss may grow on the chipped slate, both sides of the slate are not chipped at the same time. Researchers have a dictionary of words known from surveys prior to the discovery of the slates. However, when guessing the original word from a slate with moss and chips due to the effects of weathering, it is not immediately clear how many words in the dictionary apply. Write a program to count how many words in the given dictionary might fit for given a slate. Input The input is given in the following format. N M word 1 word 2 : word N slate 1 slate 2 : slate M In the first line, the number of words in the dictionary N (1 ≤ N ≤ 50000), the number of slates M (1 ≤ M ≤ 50000) are given. The following N line gives the words word i . A word is a character string with a length of 1 or more and 200 or less, including only lowercase letters. Note that the N words are all different. The following M lines give the string slate i that represents the information for each slate. slate i is a character string with a length of 1 or more and 200 or less, including lowercase letters, "?", And "*". ? represents a moss-covered character. At most one ? appears in one string. If the string starts with *, it means that the left side of the slate is missing. If the string ends with *, it indicates that the right side of the slate is missing. * does not appear except at the beginning or end of the string, and does not appear on both sides at the same time. A string with only one * is never given. The total number of characters in the string given in the input does not exceed 3000000. Output For each slate, output the number of words on a single line. Sample Input 1 5 4 aloe apple apricot cactus cat apple ap* *e ca?* Sample Output 1 1 2 2 2
[ { "submission_id": "aoj_0322_10958576", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 50005\n\nint N,M;\nstring WORD[NUM],rev_WORD[NUM];\n\nint calc(const string slate){\n\n\tint left,right;\n\tstring pattern = slate;\n\n\tif(pattern[pattern.length()-1] == '*'){\n\n\t\tpattern = pattern.substr(0,pattern.length()-1);\n\t\tleft = lower_bound(WORD,WORD+N,pattern)-WORD;\n\t\tpattern.push_back('z'+1);\n\t\tright = lower_bound(WORD,WORD+N,pattern)-WORD;\n\t\treturn right-left;\n\n\t}else if(pattern[0] == '*'){\n\n\t\tpattern = pattern.substr(1);\n\t\treverse(pattern.begin(),pattern.end());\n\t\tleft = lower_bound(rev_WORD,rev_WORD+N,pattern)-rev_WORD;\n\t\tpattern.push_back('z'+1);\n\t\tright = lower_bound(rev_WORD,rev_WORD+N,pattern)-rev_WORD;\n\t\treturn right-left;\n\n\t}else{\n\n\t\tleft = lower_bound(WORD,WORD+N,pattern)-WORD;\n\t\tif(WORD[left] == slate){\n\t\t\treturn 1;\n\t\t}else{\n\t\t\treturn 0;\n\t\t}\n\n\t}\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tgetchar();\n\n\tfor(int i = 0; i < N; i++){\n\t\tgetline(cin,WORD[i]);\n\t\trev_WORD[i] = WORD[i];\n\t\treverse(rev_WORD[i].begin(),rev_WORD[i].end());\n\t}\n\tsort(WORD,WORD+N);\n\tsort(rev_WORD,rev_WORD+N);\n\n\tstring slate;\n\tint loc,ans;\n\n\tfor(int loop = 0; loop < M; loop++){\n\t\tgetline(cin,slate);\n\n\t\tloc = -1;\n\n\t\tfor(int i = 0; i < slate.length(); i++){\n\t\t\tif(slate[i] == '?'){\n\t\t\t\tloc = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(loc == -1){\n\t\t\tprintf(\"%d\\n\",calc(slate));\n\t\t\tcontinue;\n\t\t}\n\n\t\tans = 0;\n\t\tfor(int i = 0; i < 26; i++){\n\t\t\tslate[loc] = 'a'+i;\n\t\t\tans += calc(slate);\n\t\t}\n\n\t\tprintf(\"%d\\n\",ans);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 13464, "score_of_the_acc": -0.1539, "final_rank": 4 }, { "submission_id": "aoj_0322_10852413", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,M;\n cin>>N>>M;\n vector<string> A,RA;\n rep(i,N){\n string s;\n cin>>s;\n A.push_back(s);\n reverse(all(s));\n RA.push_back(s);\n }\n sort(all(A));\n sort(all(RA));\n\n rep(_,M){\n string s;\n cin>>s;\n int sw=0;\n if(s[0]=='*'){\n reverse(all(s));\n swap(A,RA);\n sw=1;\n }\n int ans=0;\n if(s.back()=='*'){\n s.pop_back();\n if(s.back()=='?') s.pop_back();\n if(s.empty()) ans=N;\n else{\n if(auto it=find(all(s),'?');it!=s.end()){\n rep(i,26) {\n *it='a'+i;\n ans+=lower_bound(all(A),s+'~')-lower_bound(all(A),s);\n }\n }\n else{\n ans+=lower_bound(all(A),s+'~')-lower_bound(all(A),s);\n }\n }\n }\n else{\n if(auto it=find(all(s),'?');it!=s.end()){\n rep(i,26) {\n *it='a'+i;\n ans+=upper_bound(all(A),s)-lower_bound(all(A),s);\n }\n }\n else{\n ans+=upper_bound(all(A),s)-lower_bound(all(A),s);\n }\n }\n\n if(sw) swap(A,RA);\n\n cout<<ans<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 12144, "score_of_the_acc": -0.0222, "final_rank": 1 }, { "submission_id": "aoj_0322_10848662", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<string> ws(n);\n set<string> origin;\n for(int i = 0; i < n; ++i) {\n cin >> ws[i];\n origin.insert(ws[i]);\n }\n auto rws = ws;\n for(auto& s : rws) reverse(begin(s), end(s));\n sort(begin(ws), end(ws));\n sort(begin(rws), end(rws));\n\n while(m--) {\n string ss;\n cin >> ss;\n bool left = ss[0] == '*', right = ss.back() == '*';\n string s;\n for(auto c : ss) {\n if(c != '*') s += c;\n }\n\n ll ans = 0;\n auto get_cnt = [](vector<string> const& ws, string& s) {\n auto l = lower_bound(begin(ws), end(ws), s);\n s.back() += 1;\n auto r = lower_bound(begin(ws), end(ws), s);\n s.back() -= 1;\n return r - l;\n };\n if(left) {\n reverse(begin(s), end(s));\n ans += get_cnt(rws, s);\n } else if(right) {\n ans += get_cnt(ws, s);\n } else {\n ans += origin.count(s);\n }\n\n for(int i = 0; i < (int)s.size(); ++i) {\n if(s[i] == '?') {\n for(char c = 'a'; c <= 'z'; ++c) {\n s[i] = c;\n if(left) {\n ans += get_cnt(rws, s);\n } else if(right) {\n ans += get_cnt(ws, s);\n } else {\n ans += origin.count(s);\n }\n }\n break;\n }\n }\n\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 18044, "score_of_the_acc": -0.1708, "final_rank": 5 }, { "submission_id": "aoj_0322_9609416", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n6:51~7:05\n13:07~13:20\n20:24~\n*/\n\nsigned main(){\n\tint n,q;cin>>n>>q;\n\tvector<string> s(n);\n\tfor(auto&&e:s)cin>>e;\n\tvector<string> rs;\n\tfor(auto e:s){\n\t\treverse(e.begin(),e.end());\n\t\trs.push_back(e);\n\t}\n\n\tsort(s.begin(),s.end());\n\n\tsort(rs.begin(),rs.end());\n\n\twhile(q--){\n\t\tstring t;cin>>t;\n\t\tint m=t.size();\n\t\tif(t[0]=='*'){\n\t\t\treverse(t.begin(),t.end());\n\t\t\tt[m-1]='{';\n\t\t\tstring t2=t;t2.pop_back();\n\t\t\tint idx=find(t.begin(),t.end(),'?')-t.begin();\n\t\t\tswap(s,rs);\n\t\t\tif(idx==m){\n\t\t\t\tcout<<upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t2)<<endl;\n\t\t\t}else{\n\t\t\t\tint ans=0;\n\t\t\t\tfor(char c='a';c<='z';c++){\n\t\t\t\t\tt[idx]=c;t2[idx]=c;\n\t\t\t\t\tans+=upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t2);\n\t\t\t\t}\n\t\t\t\tcout<<ans<<endl;\n\t\t\t}\n\t\t\tswap(s,rs);\n\t\t}else if(t[m-1]=='*'){\n\t\t\tt[m-1]='{';\n\t\t\tstring t2=t;t2.pop_back();\n\t\t\tint idx=find(t.begin(),t.end(),'?')-t.begin();\n\n\t\t\tif(idx==m){\n\t\t\t\tcout<<upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t2)<<endl;\n\t\t\t}else{\n\t\t\t\tint ans=0;\n\t\t\t\tfor(char c='a';c<='z';c++){\n\t\t\t\t\tt[idx]=c;t2[idx]=c;\n\t\t\t\t\tans+=upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t2);\n\t\t\t\t}\n\t\t\t\tcout<<ans<<endl;\n\t\t\t}\n\t\t}else{\n\t\t\tint idx=find(t.begin(),t.end(),'?')-t.begin();\n\n\t\t\tif(idx==m){\n\t\t\t\tcout<<upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t)<<endl;\n\t\t\t}else{\n\t\t\t\tint ans=0;\n\t\t\t\tfor(char c='a';c<='z';c++){\n\t\t\t\t\tt[idx]=c;\n\t\t\t\t\tans+=upper_bound(s.begin(),s.end(),t)-lower_bound(s.begin(),s.end(),t);\n\t\t\t\t}\n\t\t\t\tcout<<ans<<endl;\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11960, "score_of_the_acc": -0.0955, "final_rank": 3 }, { "submission_id": "aoj_0322_9035586", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n constexpr int BP_SIZE = 50005;\n constexpr long long MOD = 1000000007;\n constexpr long long BASE = 222222222;\n vector<long long> base_pow(BP_SIZE, 1);\n for(int i = 1; i < BP_SIZE; i++) {\n base_pow[i] = base_pow[i-1]*BASE%MOD;\n }\n int N, M;\n cin >> N >> M;\n map<long long, int> cnt, pref, suff;\n for(int i = 0; i < N; i++) {\n string word;\n cin >> word;\n int L = word.size();\n long long hp = 0, hs = 0;\n for(int j = 0; j < L; j++) {\n hp += base_pow[j]*word[j];\n hp %= MOD;\n hs *= BASE;\n hs += word[L-j-1];\n hs %= MOD;\n pref[hp]++, suff[hs]++;\n }\n cnt[hp]++;\n }\n auto query = [&](string s, map<long long, int> &mp) {\n long long h = 0;\n for(int i = 0; i < s.size(); i++) {\n h += base_pow[i]*s[i];\n h %= MOD;\n }\n int q = s.find('?');\n if(q == string::npos) return mp[h];\n int ret = 0;\n for(char c = 'a'; c <= 'z'; c++) {\n h -= base_pow[q]*s[q];\n s[q] = c;\n h += base_pow[q]*s[q];\n h += MOD*MOD;\n h %= MOD;\n ret += mp[h];\n }\n return ret;\n };\n for(int i = 0; i < M; i++) {\n string slate;\n cin >> slate;\n int L = slate.size();\n if(slate.front() == '*') {\n cout << query(slate.substr(1, L-1), suff) << endl;\n }else if(slate.back() == '*') {\n cout << query(slate.substr(0, L-1), pref) << endl;\n }else {\n cout << query(slate, cnt) << endl;\n }\n }\n}", "accuracy": 0.1, "time_ms": 370, "memory_kb": 49708, "score_of_the_acc": -0.5569, "final_rank": 10 }, { "submission_id": "aoj_0322_8072394", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n,m;\n cin>>n>>m;\n vector<string> s(n),ss(n);\n for(int i = 0;i<n;i++){\n cin>>s[i];\n ss[i] = s[i];\n reverse(ss[i].begin(),ss[i].end());\n }\n sort(s.begin(),s.end());\n sort(ss.begin(),ss.end());\n for(int q = 0;q<m;q++){\n int ans = 0;\n string t;\n cin>>t;\n int k = -1;\n int ni = -1;\n string now = \"\";\n for(int i = 0;i<t.size();i++){\n if(t[i]=='*') k = i;\n else now += t[i];\n if(t[i]=='?') ni = i;\n }\n if(k==0) reverse(now.begin(),now.end());\n if(ni==-1){\n if(k==0){\n int nni = lower_bound(ss.begin(),ss.end(),now) - ss.begin();\n now += 'a' + 27;\n int nnj = lower_bound(ss.begin(),ss.end(),now) - ss.begin();\n ans += nnj - nni;\n }else{\n int nni = lower_bound(s.begin(),s.end(),now) - s.begin();\n if(k!=-1) now += 'a' + 27;\n int nnj = upper_bound(s.begin(),s.end(),now) - s.begin();\n ans += nnj - nni;\n }\n }else{\n ni = -1;\n for(int i = 0;i<now.size();i++) if(now[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n now[ni] = 'a' + i;\n if(k==0){\n int nni = lower_bound(ss.begin(),ss.end(),now) - ss.begin();\n now += 'a' + 27;\n int nnj = lower_bound(ss.begin(),ss.end(),now) - ss.begin();\n ans += nnj - nni;\n }else{\n int nni = lower_bound(s.begin(),s.end(),now) - s.begin();\n if(k!=-1) now += 'a' + 27;\n int nnj = upper_bound(s.begin(),s.end(),now) - s.begin();\n ans += nnj - nni;\n }\n if(k!=-1) now.pop_back();\n }\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 11696, "score_of_the_acc": -0.0935, "final_rank": 2 }, { "submission_id": "aoj_0322_8072317", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst ll b2 = 101;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll m2 = m3;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n int ni = s[i] - 'a';\n sum[i+1] = (sum[i]*B%mod+(ni))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n ni = -1;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n assert(ni!=-1);\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 420, "memory_kb": 49716, "score_of_the_acc": -0.6037, "final_rank": 17 }, { "submission_id": "aoj_0322_8072198", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst ll b2 = 101;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll m2 = m4;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n int ni = s[i] - 'a';\n sum[i+1] = (sum[i]*B%mod+(ni))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n ni = -1;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n assert(ni!=-1);\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 420, "memory_kb": 49628, "score_of_the_acc": -0.603, "final_rank": 16 }, { "submission_id": "aoj_0322_8072193", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll b2 = 101;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll m2 = m4;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n ni = -1;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n assert(ni!=-1);\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 430, "memory_kb": 49620, "score_of_the_acc": -0.6123, "final_rank": 18 }, { "submission_id": "aoj_0322_8072003", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll b2 = 101;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll m2 = m4;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 420, "memory_kb": 49600, "score_of_the_acc": -0.6028, "final_rank": 15 }, { "submission_id": "aoj_0322_8071855", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll b2 = 29;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll m2 = m4;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 380, "memory_kb": 49332, "score_of_the_acc": -0.5634, "final_rank": 11 }, { "submission_id": "aoj_0322_8071803", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll m2 = 1000000007;\nconst ll b2 = 29;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair((int)s.size(),h2.get())]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair((int)use.size(),h.get())]<<endl;\n }else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair((int)use.size(),h.get())]<<endl;\n }else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair((int)use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 390, "memory_kb": 49412, "score_of_the_acc": -0.5733, "final_rank": 12 }, { "submission_id": "aoj_0322_8071771", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll m2 = 1000000007;\nconst ll b2 = 31;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair(s.size(),h2.get(0,s.size()))]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair(use.size(),h.get())]<<endl;\n }\n else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair(use.size(),h.get())]<<endl;\n }\n else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair(use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 390, "memory_kb": 49592, "score_of_the_acc": -0.5747, "final_rank": 13 }, { "submission_id": "aoj_0322_8071770", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll m2 = 1000000007;\nconst ll b2 = 29;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair(s.size(),h2.get(0,s.size()))]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair(use.size(),h.get())]<<endl;\n }\n else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair(use.size(),h.get())]<<endl;\n }\n else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair(use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 390, "memory_kb": 49600, "score_of_the_acc": -0.5748, "final_rank": 14 }, { "submission_id": "aoj_0322_8071768", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll m2 = 1000000007;\nconst ll b2 = 1009;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair(s.size(),h2.get(0,s.size()))]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get())]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair(use.size(),h.get())]<<endl;\n }\n else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair(use.size(),h.get())]<<endl;\n }\n else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair(use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 450, "memory_kb": 49448, "score_of_the_acc": -0.6297, "final_rank": 19 }, { "submission_id": "aoj_0322_8071766", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconst ll m2 = 1000000007;\nconst ll b2 = 1009;\nconst ll m3 = 1000000009;\nconst ll b3 = 2009;\nconst ll m4 = 2147483587;\nconst ll b4 = 2147483583;\n//https://gist.github.com/privet-kitty/295ac9202b7abb3039b493f8238bf40f#file-modulus-random-base-pair64-txt\nstruct rhash{\n int n;\n ll mod,B;\n vector<ll> sum;\n vector<ll> powb;\n rhash(string &s,ll mod,ll B):mod(mod),B(B){\n n = s.size();\n sum = vector<ll>(n+1,0);\n powb = vector<ll>(n+1,1);\n for(int i = 0;i<n;i++){\n sum[i+1] = (sum[i]*B%mod+(s[i]))%mod;\n powb[i+1] = (powb[i]*B)%mod;\n }\n }\n ll get(int l,int r){\n ll tmp = sum[r] - sum[l]*powb[r-l]%mod;\n if(tmp<0) tmp += mod;\n return tmp;\n }\n ll get(){\n return get(0,n);\n }\n};\n\nint main(){\n int n,m;\n cin>>n>>m;\n map<pair<int,ll>,int> s1,s2,s3;\n for(int i = 0;i<n;i++){\n string s;\n cin>>s;\n rhash h2(s,m2,b2);\n s3[make_pair(s.size(),h2.get(0,s.size()))]++;\n string now = \"\";\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n int k = now.size();\n s1[make_pair(k,h.get(0,k))]++;\n }\n now = \"\";\n reverse(s.begin(),s.end());\n for(int j = 0;j<s.size();j++){\n now += s[j];\n rhash h(now,m2,b2);\n s2[make_pair((int)now.size(),h.get())]++;\n }\n }\n for(int q = 0;q<m;q++){\n string s;\n cin>>s;\n int ni = -1;\n int k = -1;\n string use = \"\";\n for(int i = 0;i<s.size();i++){\n if(s[i]=='*') k = i;\n else use += s[i];\n if(s[i]=='?') ni = i;\n }\n if(ni==-1){ \n if(k==s.size()-1) {\n rhash h(use,m2,b2);\n cout<<s1[make_pair(use.size(),h.get())]<<endl;\n }\n else if(k==-1) {\n rhash h(use,m2,b2);\n cout<<s3[make_pair(use.size(),h.get())]<<endl;\n }\n else{\n reverse(use.begin(),use.end()); \n rhash h(use,m2,b2);\n cout<<s2[make_pair(use.size(),h.get())]<<endl;\n }\n }else{\n if(k==0) reverse(use.begin(),use.end());\n int ans = 0;\n for(int i = 0;i<use.size();i++) if(use[i]=='?') ni = i;\n for(int i = 0;i<26;i++){\n use[ni] = 'a' + i;\n rhash h(use,m2,b2);\n int kk = use.size();\n pair<int,ll> now = make_pair(kk,h.get());\n if(k==-1) ans += s3[now];\n else if(k==0) ans += s2[now];\n else ans += s1[now];\n }\n cout<<ans<<endl;\n } \n }\n}", "accuracy": 0.1, "time_ms": 450, "memory_kb": 49616, "score_of_the_acc": -0.631, "final_rank": 20 }, { "submission_id": "aoj_0322_7173204", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nstruct E{\n\tunsigned short c;\n\tunsigned short csum;\n\tchar c1;\n\tchar vssize;\t\n\tunsigned short * vs;\n};\nvector<E> vs[204];\n \nvoid fadd(string& str,int p1,int p2){\n\tif(str.size()<=p1){\n\t\tvs[p1][p2].c++;\n\t\tvs[p1][p2].csum++;\n\t\t\n\t}else{\n\t\tvs[p1][p2].csum++;\n\t\t//cout<<p1<<\" \"<<p2<<\" \"<<vs[p1][p2].csum<<endl;\n\t\tint hit=-1;\n\t\tunsigned short *v=vs[p1][p2].vs;\n\t\tchar s1=vs[p1][p2].vssize;\n\t\tfor(int i=0;i<s1;i++){\n\t\t\tif(vs[p1+1][v[i]].c1==str[p1]){\n\t\t\t\thit=v[i];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(hit==-1){\n\t\t\tE e1;\n\t\t\te1.c=0;\n\t\t\te1.csum=0;\n\t\t\te1.c1=str[p1];\n\t\t\te1.vssize=0;\n\t\t\te1.vs=(unsigned short *)malloc(sizeof(unsigned short));\n\t\t\thit=vs[p1+1].size();\n\t\t\tvs[p1+1].push_back(e1);\n\t\t\tvs[p1][p2].vssize++;\n\t\t\ts1=vs[p1][p2].vssize;\n\t\t\tunsigned short *t=(unsigned short *)realloc(vs[p1][p2].vs,sizeof(unsigned short)*(size_t)s1);\n\t\t\tif(vs[p1][p2].vs!=t){\n\t\t\t\tvs[p1][p2].vs=t;\n\t\t\t}\n\t\t\tvs[p1][p2].vs[s1-1]=hit;\n\t\t}\n\t\t//cout<<\" ?p1 \"<<p1<<\" p2 \"<<p2<<\" str\"<<str[p1]<<\" vs=\"<<v.size()<<\" hit=\"<<hit<<endl;\n\t\tfadd(str,p1+1,hit);\n\t}\n}\nunsigned short searchTree(string str,int p1,int p2){\n\tunsigned short res=0;\n\tif(str.size()<=p1){\n\t\tres+=vs[p1][p2].c;\t\n\t}else{\n\t\tchar c1=str[p1];\n \n\t\tunsigned short * v=vs[p1][p2].vs;\n\t\tchar s1=vs[p1][p2].vssize;\n\t\tif(c1=='?'){\n\t\t\tfor(int i=0;i<s1;i++){\n\t\t\t\t//cout<<\"?\"<<p1<<\" \"<<p2<<\" \"<<v[i]<<\" \"<<res<<endl;\n\t\t\t\tres+=searchTree(str,p1+1,(int)v[i]);\n\t\t\t}\n\t\t}else if(c1=='*'){\n\t\t\tres+=vs[p1][p2].csum;\n\t\t\t\t//cout<<\"* p1\"<<p1<<\" p2\"<<p2<<\" res\"<<res<<endl; \n\t\t}else{\n\t\t\tfor(int i=0;i<s1;i++){\n\t\t\t\tif(vs[p1+1][v[i]].c1==c1){\n\t\t\t\t\tres+=searchTree(str,p1+1,(int)v[i]);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//cout<<\"c1\"<<c1<<\" p1\"<<p1<<\" p2\"<<p2<<\" csum\"<<vs[p1][p2].csum<<endl;\n\t}\n\treturn res;\n}\nstruct E2{\n\tunsigned short no;\n\tstring str;\n};\nvector<string> strs;\nvector<E2> vs2;\nint main() {\n\tint n,m;\n\tcin>>n>>m;\n\tE e1;\n\te1.c=0;\n\te1.csum=0;\n\te1.vssize=0;\n\te1.vs=(unsigned short *)malloc(sizeof(unsigned short));\n\tvs[0].push_back(e1);\n\tfor(int i=0;i<n;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tfadd(str,0,0);\n\t\treverse(str.begin(),str.end());\n\t\tstrs.push_back(str);\n\t\t//fadd(str,0,0);\n\t}\n \tunsigned short ans[50003];\n\tfor(int i=0;i<m;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tif(str[0]=='*'){\n\t\t\treverse(str.begin(),str.end());\n\t\t\tE2 e2;\n\t\t\te2.no=i;\n\t\t\te2.str=str;\n\t\t\tvs2.push_back(e2);\n\t\t}else{\n\t\t\tans[i]=searchTree(str,0,0);\n\t\t}\n\t}\n\tfor(int i=0;i<203;i++){\n\t\tfor(int j=0;j<vs[i].size();j++){\n\t\t\tfree(vs[i][j].vs);\n\t\t}\n\t\tvs[i].clear();\n\t}\n\t\n\te1.vs=(unsigned short *)malloc(sizeof(unsigned short));\n\tvs[0].push_back(e1);\n\tfor(int i=0;i<n;i++){\n\t\tfadd(strs[i],0,0);\n\t}\n\tfor(int i=0;i<vs2.size();i++){\n\t\tE2 e2=vs2[i];\n\t\tans[e2.no]=searchTree(e2.str,0,0);\n\t}\n\tfor(int i=0;i<m;i++){\n\t\tcout<<ans[i]<<endl;\n\t}\n\t\n\tfor(int i=0;i<203;i++){\n\t\tfor(int j=0;j<vs[i].size();j++){\n\t\t\tfree(vs[i][j].vs);\n\t\t}\n\t\tvs[i].clear();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1160, "memory_kb": 140440, "score_of_the_acc": -2, "final_rank": 6 }, { "submission_id": "aoj_0322_7169437", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nstruct E{\n\tunsigned short int c;\n\tunsigned short int cr;\n\tunsigned short int csum;\n\tunsigned short int csumr;\n\tchar c1;\n\tvector<unsigned short int> vs;\n};\nvector<E> vs[211];\n\nvoid fadd(string& str,int p1,int p2,bool rev){\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].cr++;\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].c++;\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t}else{\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t\t//cout<<p1<<\" \"<<p2<<\" \"<<vs[p1][p2].csum<<endl;\n\t\tint hit=-1;\n\t\tvector<unsigned short int>& v=vs[p1][p2].vs;\n\t\tfor(int i=0;i<v.size();i++){\n\t\t\tif(vs[p1+1][(int)v[i]].c1==str[p1]){\n\t\t\t\thit=(int)v[i];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(hit==-1){\n\t\t\tE e1;\n\t\t\te1.c=0;\n\t\t\te1.cr=0;\n\t\t\te1.csum=0;\n\t\t\te1.csumr=0;\n\t\t\te1.c1=str[p1];\n\t\t\thit=vs[p1+1].size();\n\t\t\t\n\t\t\tvs[p1+1].push_back(e1);\n\t\t\tvs[p1][p2].vs.push_back(hit);\n\t\t}\n\t\t//cout<<\" ?p1 \"<<p1<<\" p2 \"<<p2<<\" str\"<<str[p1]<<\" vs=\"<<v.size()<<\" hit=\"<<hit<<endl;\n\t\tfadd(str,p1+1,hit,rev);\n\t}\n}\nunsigned short int searchTree(string str,int p1,int p2,bool rev){\n\tunsigned short int res=0;\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tres+=vs[p1][p2].cr;\n\t\t}else{\n\t\t\tres+=vs[p1][p2].c;\n\t\t}\n\t}else{\n\t\tchar c1=str[p1];\n\t\t\n\t\tvector<unsigned short int>& v=vs[p1][p2].vs;\n\t\tif(c1=='?'){\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\t//cout<<\"?\"<<p1<<\" \"<<p2<<\" \"<<v[i]<<\" \"<<res<<endl;\n\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t}\n\t\t}else if(c1=='*'){\n\t\t\tif(rev==true){\n\t\t\t\tres+=vs[p1][p2].csumr;\n\t\t\t}else{\n\t\t\t\tres+=vs[p1][p2].csum;\n\t\t\t\t//cout<<\"* p1\"<<p1<<\" p2\"<<p2<<\" res\"<<res<<endl;\n\t\t\t}\n\t\t\t\n\t\t}else{\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\tif(vs[p1+1][(int)v[i]].c1==c1){\n\t\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//cout<<\"c1\"<<c1<<\" p1\"<<p1<<\" p2\"<<p2<<\" csum\"<<vs[p1][p2].csum<<endl;\n\t}\n\treturn res;\n}\n\nint main() {\n\tint n,m;\n\tcin>>n>>m;\n\tE e1;\n\te1.c=0;\n\te1.cr=0;\n\te1.csum=0;\n\te1.csumr=0;\n\tvs[0].push_back(e1);\n\tfor(int i=0;i<n;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tfadd(str,0,0,false);\n\t\treverse(str.begin(),str.end());\n\t\tfadd(str,0,0,true);\n\t}\n\n\tfor(int i=0;i<m;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tif(str[0]=='*'){\n\t\t\treverse(str.begin(),str.end());\n\t\t\tcout<<searchTree(str,0,0,true)<<endl;\n\t\t}else{\n\t\t\tcout<<searchTree(str,0,0,false)<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.13333333333333333, "time_ms": 170, "memory_kb": 21052, "score_of_the_acc": -0.1474, "final_rank": 8 }, { "submission_id": "aoj_0322_7166034", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nstruct E{\n\tunsigned short int c;\n\tunsigned short int cr;\n\tunsigned short int csum;\n\tunsigned short int csumr;\n\tchar c1;\n\tvector<unsigned short int> vs;\n};\nvector<E> vs[211];\n\nvoid fadd(string& str,int p1,int p2,bool rev){\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].cr++;\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].c++;\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t}else{\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t\t//cout<<p1<<\" \"<<p2<<\" \"<<vs[p1][p2].csum<<endl;\n\t\tint hit=-1;\n\t\tvector<unsigned short int>& v=vs[p1][p2].vs;\n\t\tfor(int i=0;i<v.size();i++){\n\t\t\tif(vs[p1+1][(int)v[i]].c1==str[p1]){\n\t\t\t\thit=v[i];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(hit==-1){\n\t\t\tE e1;\n\t\t\te1.c=0;\n\t\t\te1.cr=0;\n\t\t\te1.csum=0;\n\t\t\te1.csumr=0;\n\t\t\te1.c1=str[p1];\n\t\t\thit=vs[p1+1].size();\n\t\t\t\n\t\t\tvs[p1+1].push_back(e1);\n\t\t\tvs[p1][p2].vs.push_back(hit);\n\t\t}\n\t\t//cout<<\" ?p1 \"<<p1<<\" p2 \"<<p2<<\" str\"<<str[p1]<<\" vs=\"<<v.size()<<\" hit=\"<<hit<<endl;\n\t\tfadd(str,p1+1,hit,rev);\n\t}\n}\nunsigned short int searchTree(string str,int p1,int p2,bool rev){\n\tunsigned short int res=0;\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tres+=vs[p1][p2].cr;\n\t\t}else{\n\t\t\tres+=vs[p1][p2].c;\n\t\t}\n\t}else{\n\t\tchar c1=str[p1];\n\t\t\n\t\tvector<unsigned short int>& v=vs[p1][p2].vs;\n\t\tif(c1=='?'){\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\t//cout<<\"?\"<<p1<<\" \"<<p2<<\" \"<<v[i]<<\" \"<<res<<endl;\n\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t}\n\t\t}else if(c1=='*'){\n\t\t\tif(rev==true){\n\t\t\t\tres+=vs[p1][p2].csumr;\n\t\t\t}else{\n\t\t\t\tres+=vs[p1][p2].csum;\n\t\t\t\t//cout<<\"* p1\"<<p1<<\" p2\"<<p2<<\" res\"<<res<<endl;\n\t\t\t}\n\t\t\t\n\t\t}else{\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\tif(vs[p1+1][v[i]].c1==c1){\n\t\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//cout<<\"c1\"<<c1<<\" p1\"<<p1<<\" p2\"<<p2<<\" csum\"<<vs[p1][p2].csum<<endl;\n\t}\n\treturn res;\n}\n\nint main() {\n\tint n,m;\n\tcin>>n>>m;\n\tE e1;\n\te1.c=0;\n\te1.cr=0;\n\te1.csum=0;\n\te1.csumr=0;\n\tvs[0].push_back(e1);\n\tfor(int i=0;i<n;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tfadd(str,0,0,false);\n\t\treverse(str.begin(),str.end());\n\t\tfadd(str,0,0,true);\n\t}\n\n\t\n\tfor(int i=0;i<m;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tif(str[0]=='*'){\n\t\t\treverse(str.begin(),str.end());\n\t\t\tcout<<searchTree(str,0,0,true)<<endl;\n\t\t}else{\n\t\t\tcout<<searchTree(str,0,0,false)<<endl;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n}", "accuracy": 0.13333333333333333, "time_ms": 90, "memory_kb": 21676, "score_of_the_acc": -0.0775, "final_rank": 7 }, { "submission_id": "aoj_0322_7165378", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nstruct E{\n\tunsigned short c;\n\tunsigned short cr;\n\tunsigned short csum;\n\tunsigned short csumr;\n\tchar c1;\n\tvector<unsigned short> vs;\n};\nvector<E> vs[204];\n \nvoid fadd(string& str,int p1,int p2,bool rev){\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].cr++;\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].c++;\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t}else{\n\t\tif(rev==true){\n\t\t\tvs[p1][p2].csumr++;\n\t\t}else{\n\t\t\tvs[p1][p2].csum++;\n\t\t}\n\t\t//cout<<p1<<\" \"<<p2<<\" \"<<vs[p1][p2].csum<<endl;\n\t\tint hit=-1;\n\t\tvector<unsigned short>& v=vs[p1][p2].vs;\n\t\tfor(int i=0;i<v.size();i++){\n\t\t\tif(vs[p1+1][(int)v[i]].c1==str[p1]){\n\t\t\t\thit=v[i];\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(hit==-1){\n\t\t\tE e1;\n\t\t\te1.c=0;\n\t\t\te1.cr=0;\n\t\t\te1.csum=0;\n\t\t\te1.csumr=0;\n\t\t\te1.c1=str[p1];\n\t\t\thit=vs[p1+1].size();\n \n\t\t\tvs[p1+1].push_back(e1);\n\t\t\tvs[p1][p2].vs.push_back(hit);\n\t\t}\n\t\t//cout<<\" ?p1 \"<<p1<<\" p2 \"<<p2<<\" str\"<<str[p1]<<\" vs=\"<<v.size()<<\" hit=\"<<hit<<endl;\n\t\tfadd(str,p1+1,hit,rev);\n\t}\n}\nunsigned short searchTree(string str,int p1,int p2,bool rev){\n\tunsigned short res=0;\n\tif(str.size()<=p1){\n\t\tif(rev==true){\n\t\t\tres+=vs[p1][p2].cr;\n\t\t}else{\n\t\t\tres+=vs[p1][p2].c;\n\t\t}\n\t}else{\n\t\tchar c1=str[p1];\n \n\t\tvector<unsigned short>& v=vs[p1][p2].vs;\n\t\tif(c1=='?'){\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\t//cout<<\"?\"<<p1<<\" \"<<p2<<\" \"<<v[i]<<\" \"<<res<<endl;\n\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t}\n\t\t}else if(c1=='*'){\n\t\t\tif(rev==true){\n\t\t\t\tres+=vs[p1][p2].csumr;\n\t\t\t}else{\n\t\t\t\tres+=vs[p1][p2].csum;\n\t\t\t\t//cout<<\"* p1\"<<p1<<\" p2\"<<p2<<\" res\"<<res<<endl;\n\t\t\t}\n \n\t\t}else{\n\t\t\tfor(int i=0;i<v.size();i++){\n\t\t\t\tif(vs[p1+1][v[i]].c1==c1){\n\t\t\t\t\tres+=searchTree(str,p1+1,(int)v[i],rev);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//cout<<\"c1\"<<c1<<\" p1\"<<p1<<\" p2\"<<p2<<\" csum\"<<vs[p1][p2].csum<<endl;\n\t}\n\treturn res;\n}\n \nint main() {\n\tint n,m;\n\tcin>>n>>m;\n\tE e1;\n\te1.c=0;\n\te1.cr=0;\n\te1.csum=0;\n\te1.csumr=0;\n\tvs[0].push_back(e1);\n\tfor(int i=0;i<n;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tfadd(str,0,0,false);\n \n \n\t\treverse(str.begin(),str.end());\n\t\tfadd(str,0,0,true);\n\t}\n\t//for(int i=1;i<8;i++){\n\t//\tcout<<i<<\" , \";\n\t//\tfor(int j=0;j<vs[i].size();j++){\n\t//\t\tcout<<j<<\" \"<<vs[i][j].c1<<\" \"<<vs[i][j].csum<<\" , \";\n\t//\t}\n\t//\tcout<<endl;\n\t//}\n \n\tfor(int i=0;i<m;i++){\n\t\tstring str;\n\t\tcin>>str;\n\t\tif(str[0]=='*'){\n\t\t\treverse(str.begin(),str.end());\n\t\t\tcout<<searchTree(str,0,0,true)<<endl;\n\t\t}else{\n\t\t\tcout<<searchTree(str,0,0,false)<<endl;\n\t\t}\n\t}\n \n \n\treturn 0;\n}", "accuracy": 0.13333333333333333, "time_ms": 180, "memory_kb": 21048, "score_of_the_acc": -0.1568, "final_rank": 9 } ]
aoj_0321_cpp
Investigation of Club Activities Akira, the student council president of A High School, decided to investigate which club activities the A High School students belong to. A High School has N students numbered from 1 to N and M types of club activities numbered from 1 to M . There is no limit to the number of students in each club, and it is possible to have zero students in a club. However, according to the school rules of A High School, students can only belong to one club activity. All students follow this school rule. Akira asked a student member to do some research and obtained a record of K lines such that each line is one of the following. Student a and student b belong to the same club activity. Student c belongs to club activity x . However, there may be discrepancies in this record that would cause someone to violate the school rules. Akira decided to look at it from the first line and look for the first line where he could determine that there was a discrepancy. Write a program to find the number of the first line that can be determined to be inconsistent from the given the record of K lines. Input Input is given in the following format. N M K record 1 record 2 : record K In the first line, the number of students N (1 ≤ N ≤ 100000), the number of types of club activities M (1 ≤ M ≤ 100000), and the number of lines recorded K (1 ≤ K ≤ 200000) are given. Each record i of the record is given in the following K line in one of the following formats: 1 a b or 2 c x When the first number is "1", student a (1 ≤ a ≤ N ) and student b (1 ≤ b ≤ N ) belongs to the same club activity. Note that a ≠ b . When the first number is "2", the student c (1 ≤ c ≤ N ) is in the club activity x (1 ≤ x ≤ M ). Output Output the number of the first line that can be determined to be inconsistent in a single line. If none is found, output 0 in a single line. Sample Input 1 3 2 5 1 1 2 1 2 3 2 1 1 2 3 2 2 2 1 Sample Output 1 4 Sample Input 2 3 2 4 1 1 2 2 1 1 2 3 2 2 2 1 Sample Output 2 0 Sample Input 3 3 2 2 1 1 2 2 1 1 Sample Output 3 0
[ { "submission_id": "aoj_0321_10884265", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\n\n// Union-Find\nstruct UnionFind {\n vector<int> par, rank, siz;\n\n // 構造体の初期化\n UnionFind(int n) : par(n,-1), rank(n,0), siz(n,1) { }\n\n // 根を求める\n int root(int x) {\n if (par[x]==-1) return x; // x が根の場合は x を返す\n else return par[x] = root(par[x]); // 経路圧縮\n }\n\n // x と y が同じグループに属するか (= 根が一致するか)\n bool issame(int x, int y) {\n return root(x)==root(y);\n }\n\n // x を含むグループと y を含むグループを併合する\n bool unite(int x, int y) {\n int rx = root(x), ry = root(y); // x 側と y 側の根を取得する\n if (rx==ry) return false; // すでに同じグループのときは何もしない\n // union by rank\n if (rank[rx]<rank[ry]) swap(rx, ry); // ry 側の rank が小さくなるようにする\n par[ry] = rx; // ry を rx の子とする\n if (rank[rx]==rank[ry]) rank[rx]++; // rx 側の rank を調整する\n siz[rx] += siz[ry]; // rx 側の siz を調整する\n return true;\n }\n\n // x を含む根付き木のサイズを求める\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main() {\n int N, M, K;\n cin >> N >> M >> K;\n\n UnionFind uf(N);\n vector<int> club(N, -1);\n\n rep(i, K) {\n int num;\n cin >> num;\n\n if (num == 1) {\n int a, b;\n cin >> a >> b;\n a--; b--;\n\n if (club[uf.root(a)] == club[uf.root(b)] || club[uf.root(a)] == -1 || club[uf.root(b)] == -1) {\n int nClub = max(club[uf.root(a)], club[uf.root(b)]);\n uf.unite(a, b);\n club[uf.root(a)] = nClub;\n } else {\n cout << i + 1 << endl;\n return 0;\n }\n } else {\n int c, x;\n cin >> c >> x;\n c--; x--;\n\n if (club[uf.root(c)] == x || club[uf.root(c)] == -1) {\n club[uf.root(c)] = x;\n } else {\n cout << i + 1 << endl;\n return 0;\n }\n }\n }\n\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4652, "score_of_the_acc": -0.7856, "final_rank": 6 }, { "submission_id": "aoj_0321_10875098", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\nclass UnionFind{\npublic:\n\tll par[100009];//親\n\tll siz[100009];//クラブ\n\tll siz2[100009];//クラブ\n\t//n頂点のグラフ\n\tvoid init(ll n,ll m){\n\t\tfor(ll i=1;i<=n;i++)par[i]=-1;\n\t\tfor(ll i=1;i<=m;i++)siz[i]=0;\n\t\tfor(ll i=1;i<=n;i++)siz2[i]=1;\n\t}\n\t//根\n\tll root(ll x){\n\t\twhile(true){\n\t\t\tif(par[x]==-1)break;\n\t\t\tx=par[x];\n\t\t}\n\t\treturn x;\n\t}\n\t//統合\n\tbool unite(ll x,ll y){\n\t\tll X=root(x);\n\t\tll Y=root(y);\n\t\tif(X==Y)return true;\n\t\tif(siz2[X]<siz2[Y]){\n\t\t\tpar[X]=Y;\n\t\t\tif(siz[Y]!=0&&siz[X]!=0&&siz[Y]!=siz[X])return false;\n\t\t\tsiz[Y]=max(siz[X],siz[Y]);\n\t\t\tsiz2[Y]=siz2[Y]+siz2[X];\n\t\t}\n\t\telse{\n\t\t\tpar[Y]=X;\n\t\t\tif(siz[Y]!=0&&siz[X]!=0&&siz[Y]!=siz[X])return false;\n\t\t\tsiz[X]=max(siz[X],siz[Y]);\n\t\t\tsiz2[X]=siz2[Y]+siz2[X];\n\t\t}\n\t\treturn true;\n\t}\n\t//クラブ入力\n\tbool nyuuryoku(ll x,ll y){\n\t\tll X=root(x);\n\t\tif(siz[X]!=0&&siz[X]!=y)return false;\n\t\tsiz[X]=y;\n\t\treturn true;\n\t}\n\t//連結かどうか\n\tbool same(ll x,ll y){\n\t\tif(root(x)==root(y))return true;\n\t\telse return false;\n\t}\n\t//サイズ\n\tll sizee(ll x){\n\t\treturn siz2[root(x)];\n\t}\n\n};\nUnionFind uf;\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll n,m,k;\n\tcin>>n>>m>>k;\n\n\tuf.init(n,m);\n\n\tfor(ll i=0;i<k;i++){\n\t\tll a,b,c;\n\t\tcin>>a>>b>>c;\n\t\tif(a==1){\n\t\t\tbool t=uf.unite(b,c);\n\t\t\tif(t==false){\n\t\t\t\tcout<<i+1<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tbool t=uf.nyuuryoku(b,c);\n\t\t\tif(t==false){\n\t\t\t\tcout<<i+1<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<0<<endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5712, "score_of_the_acc": -0.4838, "final_rank": 4 }, { "submission_id": "aoj_0321_10871860", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nnamespace atcoder {\n\n struct dsu {\n public:\n dsu() : _n(0) {}\n dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n int merge(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n parent_or_size[x] += parent_or_size[y];\n parent_or_size[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n assert(0 <= a && a < _n);\n if (parent_or_size[a] < 0) return a;\n return parent_or_size[a] = leader(parent_or_size[a]);\n }\n\n int size(int a) {\n assert(0 <= a && a < _n);\n return -parent_or_size[leader(a)];\n }\n\n std::vector<std::vector<int>> groups() {\n std::vector<int> leader_buf(_n), group_size(_n);\n for (int i = 0; i < _n; i++) {\n leader_buf[i] = leader(i);\n group_size[leader_buf[i]]++;\n }\n std::vector<std::vector<int>> result(_n);\n for (int i = 0; i < _n; i++) {\n result[i].reserve(group_size[i]);\n }\n for (int i = 0; i < _n; i++) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(\n std::remove_if(result.begin(), result.end(),\n [&](const std::vector<int>& v) { return v.empty(); }),\n result.end());\n return result;\n }\n\n private:\n int _n;\n\n std::vector<int> parent_or_size;\n };\n\n}\nusing namespace atcoder;\nint main() {\n int n, m, k; cin >> n >> m >> k;\n dsu d(n);\n map<int, int> mp;\n rep(i, k) {\n int t; cin >> t;\n if (t == 1) {\n int a, b; cin >> a >> b;\n a--, b--;\n int ldA = d.leader(a), ldB = d.leader(b);\n bool existA = mp.count(ldA), existB = mp.count(ldB);\n if (existA && existB && mp[ldA] != mp[ldB]) {\n cout << i + 1 << endl;\n return 0;\n }\n d.merge(a, b);\n if (existA)mp[d.leader(a)] = mp[ldA];\n if (existB)mp[d.leader(a)] = mp[ldB];\n }\n else {\n int c, x; cin >> c >> x;\n c--;\n if (mp.count(d.leader(c)) && mp[d.leader(c)] != x) {\n cout << i + 1 << endl;\n return 0;\n }\n mp[d.leader(c)] = x;\n }\n }\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8448, "score_of_the_acc": -1.1853, "final_rank": 14 }, { "submission_id": "aoj_0321_10852390", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include<atcoder/all>\nusing mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nstruct UnionFind {\n int N;\n vector<int> parent;\n\n UnionFind(int N) : N(N), parent(N, -1) {}\n\n int leader(int x) {\n if (parent[x] < 0) return x;\n return parent[x] = leader(parent[x]);\n }\n\n int merge(int x, int y) {\n int xp = leader(x);\n int yp = leader(y);\n if (xp == yp) return xp;\n if (xp < yp) swap(xp, yp);\n parent[yp] += parent[xp];\n parent[xp] = yp;\n return yp;\n }\n\n bool same(int x, int y) { return leader(x) == leader(y); }\n\n int size(int x) { return -parent[leader(x)]; }\n\n vector<vector<int>> groups() {\n vector<vector<int>> a(N);\n rep(i, N) a[leader(i)].push_back(i);\n vector<vector<int>> uni;\n rep(i, N) if (!a[i].empty()) uni.push_back(a[i]);\n return uni;\n }\n};\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,M,K;\n cin>>N>>M>>K;\n vector<int> c(N,0);\n int ans=0;\n\n UnionFind uf(N);\n\n rep(i,K){\n int t,a,b;\n cin>>t>>a>>b;\n a--;b--;\n if(ans!=0) continue;\n if(t==1){\n a=uf.leader(a);\n b=uf.leader(b);\n if(a==b) continue;\n int l=uf.merge(a,b);\n if(c[a]==c[b]) continue;\n if(c[a]==0||c[b]==0) c[l]=c[a]|c[b];\n else ans=i+1;\n }\n else{\n int l=uf.leader(a);\n if(c[l]==b+1) continue;\n if(c[l]==0) c[l]=b+1;\n else ans=i+1;\n \n }\n }\n cout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4096, "score_of_the_acc": -0.1552, "final_rank": 2 }, { "submission_id": "aoj_0321_10849682", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#define _USE_MATH_DEFINES\n#include <math.h>\n#include <cstring>\n#include <numeric>\n#include <algorithm>\n#include <stdlib.h>\n#include <functional>\n#include <string>\n#include <array>\n#include <map>\n#include <queue>\n#include <limits.h>\n#include <set>\n#include <stack>\n#include <random>\n#include <complex>\n#include <unordered_map>\n#include <nmmintrin.h>\n#include <chrono>\n#define rep(i,s,n) for(int i = (s); (n) > i; i++)\n#define REP(i,n) rep(i,0,n)\n#define RANGE(x,a,b) ((a) <= (x) && (x) <= (b))\n#define DUPLE(a,b,c,d) (RANGE(a,c,d) || RANGE(b,c,d) || RANGE(c,a,b) || RANGE(d,a,b))\n#define INCLU(a,b,c,d) (RANGE(a,c,d) && (b,c,d))\n#define PW(x) ((x)*(x))\n#define ALL(x) (x).begin(), (x).end()\n#define MODU 1000000007\n#define bitcheck(a,b) ((a >> b) & 1)\n#define bitset(a,b) ( a |= (1 << b))\n#define bitunset(a,b) (a &= ~(1 << b))\n#define MP(a,b) make_pair((a),(b))\n#define Manh(a,b) (abs((a).first-(b).first) + abs((a).second - ((b).second))\n#define pritnf printf\n#define scnaf scanf\n#define itn int\n#ifdef _MSC_VER\n#define __builtin_popcount _mm_popcnt_u32\n#define __builtin_popcountll _mm_popcnt_u64\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll gcd(ll a, ll b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a%b);\n}\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N], const T &val) {\n\tstd::fill((T*)array, (T*)(array + N), val);\n}\n\n\nstruct UnionFind{\n\tvector<int> data;\n\tint n, m;\n\n\tUnionFind(int ns, int ms) : n(ns), m(ms), data(ns + ms, INT_MIN){\n\t\tREP(i, m){\n\t\t\tdata[i + n] = -i-1;\n\t\t}\n\t}\n\n\tbool unite(int a, int b){//矛盾の判定\n\t\ta = root(a), b = root(b);\n\n\t\tif (a == b)\n\t\t\treturn true;\n\n\t\tif (data[a] != INT_MIN && data[b] != INT_MIN){\n\t\t\tif (data[a] != data[b]){\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (rand() % 2)\n\t\t\t\t\tdata[b] = a;\n\t\t\t\telse\n\t\t\t\t\tdata[a] = b;\n\t\t\t}\n\t\t}\n\t\telse if (data[a] != INT_MIN)\n\t\t\tdata[b] = a;\n\t\telse if (data[b] != INT_MIN)\n\t\t\tdata[a] = b;\n\t\telse{\n\t\t\tif (rand() % 2)\n\t\t\t\tdata[b] = a;\n\t\t\telse\n\t\t\t\tdata[a] = b;\n\t\t}\n\t\treturn true;\n\t}\n\n\n\tbool unitebu(int a, int b){//矛盾の判定 aをbの部活\n\t\ta = root(a);\n\t\tb += n;\n\n\t\tif (data[a] == data[b])\n\t\t\treturn true;\n\t\tif (data[a] != INT_MIN)\n\t\t\treturn false;\n\n\t\tdata[a] = b;\n\t\treturn true;\n\t}\n\n\tbool findset(int a, int b){\n\t\treturn root(a) == root(b);\n\t}\n\n\tint root(int x){\n\t\treturn data[x] < 0 ? x : data[x] = root(data[x]);\n\t}\n};\n\nsigned main() {\n\tint n, m, k;\n\tcin >> n >> m >> k;\n\tUnionFind uf(n,m);\n\tREP(i, k){\n\t\tint t, a, b;\n\t\tscanf(\"%d %d %d\", &t, &a, &b);\n\t\tbool ret = 1;\n\t\ta--, b--;\n\t\tif (t == 1){\n\t\t\tret = uf.unite(a, b);\n\t\t}\n\t\telse if (t == 2){\n\t\t\tret = uf.unitebu(a, b);\n\t\t}\n\n\t\tif (!ret){\n\t\t\tprintf(\"%d\\n\", i + 1);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tprintf(\"0\\n\");\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3904, "score_of_the_acc": -0.1294, "final_rank": 1 }, { "submission_id": "aoj_0321_10796226", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n\nclass UnionFind{\n public:\n int size;\n vector<int>parent;\n vector<int>depth;\n void init(int N){\n size =N;\n parent.assign(N,-1);\n depth.assign(N,1);\n }\n int root(int x){\n int o = x;\n while(parent[x]!=-1)x=parent[x];\n if(parent[o]!=-1)parent[o]=x;\n return x;\n }\n bool same(int a,int b){\n a = root(a);b=root(b);\n return a==b;\n }\n void unite(int a,int b){\n a = root(a);b=root(b);\n if(a==b)return;\n if(depth[a]>=depth[b]){\n parent[b]=a;\n depth[a]=max(depth[a],depth[b]+1);\n }\n else {\n parent[a]=b;\n depth[b]=max(depth[b],depth[a]+1);\n }\n return;\n }\n};\n\nint main(){\n int N,M,K;cin>>N>>M>>K;\n UnionFind UF;\n UF.init(N);\n vector<int>club(N,-1);\n rep(k,K){\n int t;cin>>t;\n if(t==1){\n int a,b;cin>>a>>b;a--;b--;\n a = UF.root(a);b = UF.root(b);\n if(club[a]>=0&&club[b]>=0&&club[a]!=club[b]){\n cout<<k+1<<endl;\n return 0;\n }\n UF.unite(a,b);\n club[UF.root(a)]=max(club[a],club[b]);\n }\n else {\n int c,x;cin>>c>>x;\n c--;\n c = UF.root(c);\n if(club[c]==-1)club[c]=x;\n else {\n if(club[c]!=x){\n cout<<k+1<<endl;\n return 0;\n }\n }\n }\n }\n cout<<0<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4140, "score_of_the_acc": -0.8278, "final_rank": 8 }, { "submission_id": "aoj_0321_10759558", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater<ll>())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x,y) reverse(x,x+y)\n#define REV(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\nll x;\nvoid solve() {\n\tll n,m,k; cin>>n>>m>>k;\n\tll q,a,b;\n\tll p[n+1],l[n+1];\n\tmap<ll,ll>mp;\n\trep(i,1,n+1) { p[i]=i; l[i]=1; }\n\trep(i,0,k) { cin>>q>>a>>b;\n\t\tif (q==1) {\n\t\t\twhile(a!=p[a]) a=p[a];\n\t\t\twhile(b!=p[b]) b=p[b];\n\t\t\tif (mp[a]!=0 && mp[b]!=0 && mp[a]!=mp[b]) { x=i+1; break; }\n\t\t\telse if (mp[a]!=0 && mp[b]==0 && mp[a]!=mp[b]) mp[b]=mp[a];\n\t\t\telse if (mp[a]==0 && mp[b]!=0 && mp[a]!=mp[b]) mp[a]=mp[b];\n\t\t\tif (l[a]>l[b]) p[b]=a;\n\t\t\telse if (l[a]<l[b]) p[a]=b;\n\t\t\telse { p[b]=a; l[a]++; }\n\t\t}\n\t\telse {\n\t\t\twhile(a!=p[a]) a=p[a];\n\t\t\tif (mp[a]!=0 && mp[a]!=b) { x=i+1; break; }\n\t\t\tmp[a]=b;\n\t\t}\n\t}\n\tcout<<x<<'\\n';\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 11200, "score_of_the_acc": -1.6667, "final_rank": 15 }, { "submission_id": "aoj_0321_9609405", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n6:51~7:05\n13:07~13:20\n20:24~\n*/\n\nstruct UF{\n\tvector<int> par;\n\tUF(int n):par(n,-1){\n\n\t}\n\n\tint root(int x){\n\t\tif(par[x]<0)return x;\n\t\treturn par[x]=root(par[x]);\n\t}\n\n\tvoid merge(int x,int y){\n\t\tx=root(x),y=root(y);\n\n\t\tif(x==y)return;\n\n\t\tif(par[x]>par[y]){\n\t\t\tswap(x,y);\n\t\t}\n\n\t\tpar[y]=x;\n\t}\n};\n\nsigned main(){\n\tint n,m,k;cin>>n>>m>>k;\n\tvector<int> vec(n,-1);\n\tUF uf(n);\n\tfor(int q=1;q<=k;q++){\n\t\tint t;cin>>t;\n\t\tif(t==1){\n\t\t\tint a,b;cin>>a>>b;a--;b--;\n\t\t\ta=uf.root(a);\n\t\t\tb=uf.root(b);\n\t\t\t// cout<<\"!\"<<a<<\" \"<<b<<endl;\n\t\t\tif(vec[a]!=-1&&vec[b]!=-1&&vec[a]!=vec[b]){\n\t\t\t\tcout<<q<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tuf.merge(a,b);\n\t\t\tif(vec[a]!=-1){\n\t\t\t\tvec[uf.root(a)]=vec[a];\n\t\t\t}\n\t\t\tif(vec[b]!=-1){\n\t\t\t\tvec[uf.root(b)]=vec[b];\n\t\t\t}\n\t\t}else{\n\t\t\tint c,x;cin>>c>>x;c--;\n\t\t\tc=uf.root(c);\n\t\t\tif(vec[c]!=-1&&vec[c]!=x){\n\t\t\t\tcout<<q<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tvec[c]=x;\n\t\t}\n\t}\n\n\tcout<<0<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4564, "score_of_the_acc": -0.8849, "final_rank": 9 }, { "submission_id": "aoj_0321_9515295", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint leng[100001],par[100001],bu[100001];\nint main(void)\n{\n\tint n,m,k,i,z,a,b,c,x,flg;\n\tcin >>n>>m>>k;\n\tfor(i=1;i<=n;i++)\t{\n\t\tleng[i]=1;\tpar[i]=i; bu[i]=0;\n\t}\n\tflg=1;\n\tfor(i=1;i<=k;i++)\t{\n\t\tcin >>z;\n\t\tif(z==1)\t{\n\t\t\tcin >>a>>b;\n\t\t\twhile(a!=par[a])\ta=par[a];\n\t\t\twhile(b!=par[b])\tb=par[b];\n\t\t\tif(bu[a]!=0 && bu[b]!=0 && bu[a]!=bu[b])\t{\n\t\t\t\tflg=0;\tbreak;\n\t\t\t}\n\t\t\tif(leng[a]>leng[b])\t{\n\t\t\t\tpar[b]=a;\n\t\t\t\tif(bu[a]==0)\tbu[a]=bu[b];\n\t\t\t}\n\t\t\telse if(leng[a]<leng[b])\t{\n\t\t\t\tpar[a]=b;\t\n\t\t\t\tif(bu[b]==0)\tbu[b]=bu[a];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tpar[a]=b;\tleng[b]++;\n\t\t\t\tif(bu[b]==0)\tbu[b]=bu[a];\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tcin >>c>>x;\n\t\t\twhile(c!=par[c])\tc=par[c];\n\t\t\tif(bu[c]!=0 && bu[c]!=x)\t{\n\t\t\t\tflg=0;\tbreak;\n\t\t\t}\n\t\t\telse bu[c]=x;\n\t\t}\n\t}\n\tif(flg==1)\t\tcout<<\"0\"<<endl;\n\telse cout<<i<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 4248, "score_of_the_acc": -1.0646, "final_rank": 13 }, { "submission_id": "aoj_0321_9373168", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vc<vc<T>>;\nvoid solve();\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n ll t = 1;\n // cin >> t;\n for (int i = 1; i <= t; i++) solve();\n return 0;\n}\n#define rep(i, a, b) for (ll i = (a); i < (b); i++)\nll dy[4] = {0, 1, 0, -1}, dx[4] = {1, 0, -1, 0};\n// ll dy[8] = {1, 1, 0, -1, -1, -1, 0, 1}, dx[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n\n#include <algorithm>\n#include <cassert>\n#include <vector>\n\nnamespace atcoder {\n\nstruct dsu {\n public:\n dsu() : _n(0) {}\n explicit dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n int merge(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n parent_or_size[x] += parent_or_size[y];\n parent_or_size[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n assert(0 <= a && a < _n);\n if (parent_or_size[a] < 0) return a;\n return parent_or_size[a] = leader(parent_or_size[a]);\n }\n\n int size(int a) {\n assert(0 <= a && a < _n);\n return -parent_or_size[leader(a)];\n }\n\n std::vector<std::vector<int>> groups() {\n std::vector<int> leader_buf(_n), group_size(_n);\n for (int i = 0; i < _n; i++) {\n leader_buf[i] = leader(i);\n group_size[leader_buf[i]]++;\n }\n std::vector<std::vector<int>> result(_n);\n for (int i = 0; i < _n; i++) {\n result[i].reserve(group_size[i]);\n }\n for (int i = 0; i < _n; i++) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(\n std::remove_if(result.begin(), result.end(),\n [&](const std::vector<int>& v) { return v.empty(); }),\n result.end());\n return result;\n }\n\n private:\n int _n;\n std::vector<int> parent_or_size;\n};\n\n} // namespace atcoder\n\nvoid solve() {\n ll n, m, k;\n cin >> n >> m >> k;\n atcoder::dsu d(n);\n vc<ll> club(n, -1);\n rep(i, 1, k + 1) {\n ll t, a, b;\n cin >> t >> a >> b;\n if (t == 1) {\n a--, b--;\n if (club[d.leader(a)] != -1 && club[d.leader(b)] != -1 &&\n club[d.leader(a)] != club[d.leader(b)]) {\n cout << i << endl;\n return;\n }\n ll c = -1;\n if (club[d.leader(a)] != -1) c = club[d.leader(a)];\n if (club[d.leader(b)] != -1) c = club[d.leader(b)];\n d.merge(a, b);\n if (c != -1) club[d.leader(a)] = c;\n } else {\n a--;\n if (club[d.leader(a)] != -1 && club[d.leader(a)] != b) {\n cout << i << endl;\n return;\n }\n club[d.leader(a)] = b;\n }\n }\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4352, "score_of_the_acc": -0.1897, "final_rank": 3 }, { "submission_id": "aoj_0321_9277105", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct UnionFind {\n vector<int> par;\n vector<int> size;\n\n UnionFind(int n) {\n par.resize(n + 1, -1);\n size.resize(n + 1, 1);\n }\n\n int root(int x) {\n while (1) {\n if (par[x] == -1) {\n return(x);\n }\n x = par[x];\n }\n }\n\n void unite(int u, int v) {\n int RootU = root(u), RootV = root(v);\n if (RootU == RootV) {\n return;\n }\n if (size[RootU] < size[RootV]) {\n par[RootU] = RootV;\n size[RootV] += size[RootU];\n } else {\n par[RootV] = RootU;\n size[RootU] += size[RootV];\n }\n return;\n }\n};\n\nint main() {\n int n, m, k;\n cin >> n >> m >> k;\n UnionFind uf(n);\n vector<int> club(n, -1);\n int t, a, b;\n for (int i = 0; i < k; i++) {\n cin >> t >> a >> b;\n a--, b--;\n if (t == 1) {\n int roota = uf.root(a), rootb = uf.root(b);\n if (club[roota] != -1 && club[rootb] != -1 && club[roota] != club[rootb]) {\n cout << i + 1 << \"\\n\";\n return(0);\n } else {\n club[roota] = max(club[roota], club[rootb]);\n club[rootb] = max(club[roota], club[rootb]);\n uf.unite(a, b);\n }\n } else {\n int root = uf.root(a);\n if (club[root] == -1) {\n club[root] = b;\n } else if (club[root] != b) {\n cout << i + 1 << \"\\n\";\n return(0);\n }\n }\n }\n cout << 0 << \"\\n\";\n return(0);\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3888, "score_of_the_acc": -1.0161, "final_rank": 11 }, { "submission_id": "aoj_0321_9035606", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct dsu {\n int n;\n vector<int> par;\n dsu(int n): n(n), par(n) {\n iota(par.begin(), par.end(), 0);\n }\n int leader(int v) {\n if(par[v] == v) return v;\n par[v] = leader(par[v]);\n return par[v];\n }\n void merge(int u, int v) {\n int lu = leader(u), lv = leader(v);\n if(lu > lv) swap(lu, lv);\n if(lu != lv) par[lv] = lu;\n }\n};\n\nint main() {\n int N, M, K;\n cin >> N >> M >> K;\n dsu uf(N+M);\n for(int q = 0; q < K; q++) {\n int t;\n cin >> t;\n if(t == 1) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n int la = uf.leader(M+a), lb = uf.leader(M+b);\n if(la < M && lb < M && la != lb) {\n cout << q+1 << endl;\n return 0;\n }\n uf.merge(la, lb);\n }else {\n int c, x;\n cin >> c >> x;\n c--, x--;\n int lc = uf.leader(M+c);\n if(lc < M && lc != x) {\n cout << q+1 << endl;\n return 0;\n }\n uf.merge(lc, x);\n }\n }\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3768, "score_of_the_acc": -0.6667, "final_rank": 5 }, { "submission_id": "aoj_0321_8305469", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass unionfind {\nprivate:\n\tint n;\n\tvector<int> par;\n\tvector<int> club;\n\tbool error;\npublic:\n\tunionfind() : n(0), par(vector<int>()), club(vector<int>()), error(false) {}\n\tunionfind(int n_) : n(n_), club(vector<int>(n, -1)), error(false) {\n\t\tpar.resize(n);\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tpar[i] = i;\n\t\t}\n\t}\n\tint root(int x) {\n\t\tif (par[x] == x) {\n\t\t\treturn x;\n\t\t}\n\t\treturn par[x] = root(par[x]);\n\t}\n\tvoid link(int x, int y) {\n\t\tx = root(x);\n\t\ty = root(y);\n\t\tif (club[x] != club[y] && club[x] != -1 && club[y] != -1) {\n\t\t\terror = true;\n\t\t}\n\t\tpar[y] = x;\n\t\tclub[x] = max(club[x], club[y]);\n\t}\n\tvoid assign(int x, int id) {\n\t\tx = root(x);\n\t\tif (club[x] != id && club[x] != -1) {\n\t\t\terror = true;\n\t\t}\n\t\tclub[x] = id;\n\t}\n\tbool connected(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n\tbool is_error() {\n\t\treturn error;\n\t}\n};\n\nint main() {\n\tint N, M, K;\n\tcin >> N >> M >> K;\n\tunionfind uf(N);\n\tint answer = -1;\n\tfor (int i = 0; i < K; i++) {\n\t\tint tp, a, b;\n\t\tcin >> tp >> a >> b;\n\t\ta -= 1;\n\t\tb -= 1;\n\t\tif (tp == 1) {\n\t\t\tuf.link(a, b);\n\t\t}\n\t\telse {\n\t\t\tuf.assign(a, b);\n\t\t}\n\t\tif (answer == -1 && uf.is_error()) {\n\t\t\tanswer = i;\n\t\t}\n\t}\n\tcout << answer + 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3856, "score_of_the_acc": -0.7896, "final_rank": 7 }, { "submission_id": "aoj_0321_8303096", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass unionfind {\nprivate:\n\tint n;\n\tvector<int> par;\npublic:\n\tunionfind() : n(0), par(vector<int>()) {}\n\tunionfind(int n_) : n(n_) {\n\t\tpar.resize(n);\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tpar[i] = i;\n\t\t}\n\t}\n\tint root(int x) {\n\t\tif (x == par[x]) {\n\t\t\treturn x;\n\t\t}\n\t\treturn par[x] = root(par[x]);\n\t}\n\tvoid link(int x, int y) {\n\t\tx = root(x);\n\t\ty = root(y);\n\t\tif (x < y) {\n\t\t\tswap(x, y);\n\t\t}\n\t\tpar[y] = x;\n\t}\n\tbool connected(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n};\n\nint main() {\n\tint N, M, K;\n\tcin >> N >> M >> K;\n\tunionfind uf(N + M);\n\tvector<int> cnt(N + M);\n\tfor (int i = 0; i < N; i++) {\n\t\tcnt[i] += 1;\n\t}\n\tint answer = -1;\n\tfor (int i = 0; i < K; i++) {\n\t\tint tp, a, b;\n\t\tcin >> tp >> a >> b;\n\t\tif (tp == 1) {\n\t\t\ta -= 1;\n\t\t\tb -= 1;\n\t\t\tif (uf.root(a) != uf.root(b) && uf.root(a) >= N && uf.root(b) >= N) {\n\t\t\t\tanswer = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tuf.link(a, b);\n\t\t}\n\t\telse {\n\t\t\ta -= 1;\n\t\t\tb -= 1;\n\t\t\tif (uf.root(a) != uf.root(b + N) && uf.root(a) >= N) {\n\t\t\t\tanswer = i;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tuf.link(a, b + N);\n\t\t}\n\t}\n\tcout << answer + 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 4608, "score_of_the_acc": -0.8908, "final_rank": 10 }, { "submission_id": "aoj_0321_8226048", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep_(i, n) for (int i = 1; i < (int)(n + 1); i++)\n\nusing namespace std;\n\nint N; \n\nclass UnionFind {\n\tpublic:\n\tint par[200009]; \n\tint siz[200009]; \n\n\tvoid init(int N){\n\t\trep_(i, N) par[i] = -1; \n\t\trep_(i, N) siz[i] = 1; \n\t}\n\n\tint root(int x){\n\t\twhile (true){\n\t\t\tif (par[x] == -1) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint root_(int x){ // M := N + c 手前の親(set_rootする前のもともとの親)\n\t\twhile (true){\n\t\t\tif (par[x] > N) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint set_root(int c, int x){\n\t\tint Rc = root(c); \n\t\tif (Rc != N + x and Rc > N){ // すでにほかのに属してる\n\t\t\treturn false; \n\t\t}else{\n\t\t\tpar[Rc] = N + x; \n\t\t\tsiz[Rc] = siz[Rc] + 1; \n\t\t\treturn true; \n\t\t}\n\t}\n\n\tint unite(int u, int v){\n\t\tint RootU = root(u); \n\t\tint RootV = root(v); \n\t\tif (RootU > N && RootV > N){ // どちらともすでに属している\n\t\t\treturn false; \n\t\t}\n\t\tif (RootU == RootV) return true; \n\t\tif (siz[RootU] < siz[RootV]){\n\t\t\tif (RootU > N){ // 親をM (:= N + c) で固定するため\n\t\t\t\tpar[root_(u)] = RootV; \n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}else{\n\t\t\tif (RootV > N){\n\t\t\t\tpar[root_(v)] = RootU; \n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}\n\t}\n\n\tbool same(int u, int v){\n\t\tif (root(u) == root(v)) return true; \n\t\treturn false; \n\t}\n\n}; \n\n\nint main(){\n\tint M, K; \n\tcin >> N >> M >> K; \n\tUnionFind uf; \n\tuf.init(N + M); \n\trep(i, K){\n\t\tint q, a, b; \n\t\tcin >> q >> a >> b; \n\t\tif (q == 1){\n\t\t\tif (uf.unite(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant unite\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}else{\n\t\t\tif (uf.set_root(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant set_root\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl; \n}", "accuracy": 0.5652173913043478, "time_ms": 10, "memory_kb": 4644, "score_of_the_acc": -0.1179, "final_rank": 17 }, { "submission_id": "aoj_0321_8225947", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep_(i, n) for (int i = 1; i < (int)(n + 1); i++)\n\nusing namespace std;\n\nint N; \n\nclass UnionFind {\n\tpublic:\n\tint par[200009]; \n\tint siz[200009]; \n\n\tvoid init(int N){\n\t\trep_(i, N) par[i] = -1; \n\t\trep_(i, N) siz[i] = 1; \n\t}\n\n\tint root(int x){\n\t\twhile (true){\n\t\t\tif (par[x] == -1) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint root_(int x){ // M := N + c 隰・唱辯慕クコ・ョ髫包スェ(set_root邵コ蜷カ・玖恆髦ェ繝サ郢ァ繧・・郢ァ繧・・邵コ・ョ髫包スェ)\n\t\twhile (true){\n\t\t\tif (par[x] > N) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint set_root(int c, int x){\n\t\tint Rc = root(c); \n\t\tif (Rc != N + x and Rc > N){ // 邵コ蜷カ縲堤クコ・ォ邵コ・サ邵コ荵昴・邵コ・ォ陞サ讒ュ・邵コ・ヲ郢ァ繝サ\n\t\t\treturn false; \n\t\t}else{\n\t\t\tpar[Rc] = N + x; \n\t\t\tsiz[Rc] = siz[Rc] + 1; \n\t\t\treturn true; \n\t\t}\n\t}\n\n\tint unite(int u, int v){\n\t\tint RootU = root(u); \n\t\tint RootV = root(v); \n\t\tif (RootU > N && RootV > N){ // 邵コ・ゥ邵コ・。郢ァ蟲ィ竊堤ケァ繧・・邵コ・ァ邵コ・ォ陞サ讒ュ・邵コ・ヲ邵コ繝サ・・\n\t\t\treturn false; \n\t\t}\n\t\tif (RootU == RootV) return true; \n\t\tif (siz[RootU] < siz[RootV]){\n\t\t\tif (RootU > N){ // 髫包スェ郢ァ讓ス (:= N + c) 邵コ・ァ陜暦スコ陞ウ螢ケ笘・ケァ荵昶螺郢ァ繝サ\n\t\t\t\tpar[root_(u)] = RootV; \n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}else{\n\t\t\tif (RootV > N){\n\t\t\t\tpar[root_(v)] = RootU; \n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}\n\t}\n\n\tbool same(int u, int v){\n\t\tif (root(u) == root(v)) return true; \n\t\treturn false; \n\t}\n\n}; \n\n\nint main(){\n\tint M, K; \n\tcin >> N >> M >> K; \n\tUnionFind uf; \n\tuf.init(N + M + 5); \n\trep(i, K){\n\t\tint q, a, b; \n\t\tcin >> q >> a >> b; \n\t\tif (q == 1){\n\t\t\tif (uf.unite(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant unite\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}else{\n\t\t\tif (uf.set_root(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant set_root\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl; \n}", "accuracy": 0.5652173913043478, "time_ms": 10, "memory_kb": 4924, "score_of_the_acc": -0.1555, "final_rank": 19 }, { "submission_id": "aoj_0321_8225942", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep_(i, n) for (int i = 1; i < (int)(n + 1); i++)\n\nusing namespace std;\n\nint N; \n\nclass UnionFind {\n\tpublic:\n\tint par[500009]; \n\tint siz[500009]; \n\n\tvoid init(int N){\n\t\trep_(i, N) par[i] = -1; \n\t\trep_(i, N) siz[i] = 1; \n\t}\n\n\tint root(int x){\n\t\twhile (true){\n\t\t\tif (par[x] == -1) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint root_(int x){ // M := N + c 隰・唱辯慕クコ・ョ髫包スェ(set_root邵コ蜷カ・玖恆髦ェ繝サ郢ァ繧・・郢ァ繧・・邵コ・ョ髫包スェ)\n\t\twhile (true){\n\t\t\tif (par[x] > N) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint set_root(int c, int x){\n\t\tint Rc = root(c); \n\t\tif (Rc != N + x and Rc > N){ // 邵コ蜷カ縲堤クコ・ォ邵コ・サ邵コ荵昴・邵コ・ォ陞サ讒ュ・邵コ・ヲ郢ァ繝サ\n\t\t\treturn false; \n\t\t}else{\n\t\t\tpar[Rc] = N + x; \n\t\t\tsiz[Rc] = siz[Rc] + 1; \n\t\t\treturn true; \n\t\t}\n\t}\n\n\tint unite(int u, int v){\n\t\tint RootU = root(u); \n\t\tint RootV = root(v); \n\t\tif (RootU > N && RootV > N){ // 邵コ・ゥ邵コ・。郢ァ蟲ィ竊堤ケァ繧・・邵コ・ァ邵コ・ォ陞サ讒ュ・邵コ・ヲ邵コ繝サ・・\n\t\t\treturn false; \n\t\t}\n\t\tif (RootU == RootV) return true; \n\t\tif (siz[RootU] < siz[RootV]){\n\t\t\tif (RootU > N){ // 髫包スェ郢ァ讓ス (:= N + c) 邵コ・ァ陜暦スコ陞ウ螢ケ笘・ケァ荵昶螺郢ァ繝サ\n\t\t\t\tpar[root_(u)] = RootV; \n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}else{\n\t\t\tif (RootV > N){\n\t\t\t\tpar[root_(v)] = RootU; \n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}\n\t}\n\n\tbool same(int u, int v){\n\t\tif (root(u) == root(v)) return true; \n\t\treturn false; \n\t}\n\n}; \n\n\nint main(){\n\tint M, K; \n\tcin >> N >> M >> K; \n\tUnionFind uf; \n\tuf.init(N + M); \n\trep(i, K){\n\t\tint q, a, b; \n\t\tcin >> q >> a >> b; \n\t\tif (q == 1){\n\t\t\tif (uf.unite(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant unite\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}else{\n\t\t\tif (uf.set_root(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant set_root\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl; \n}", "accuracy": 0.5652173913043478, "time_ms": 10, "memory_kb": 6244, "score_of_the_acc": -0.3332, "final_rank": 20 }, { "submission_id": "aoj_0321_8225933", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep_(i, n) for (int i = 1; i < (int)(n + 1); i++)\n\nusing namespace std;\n\nint N; \n\nclass UnionFind {\n\tpublic:\n\tint par[200009]; \n\tint siz[200009]; \n\n\tvoid init(int N){\n\t\trep_(i, N) par[i] = -1; \n\t\trep_(i, N) siz[i] = 1; \n\t}\n\n\tint root(int x){\n\t\twhile (true){\n\t\t\tif (par[x] == -1) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint root_(int x){\n\t\twhile (true){\n\t\t\tif (par[x] > N) break; \n\t\t\tx = par[x]; \n\t\t}\n\t\treturn x; \n\t}\n\n\tint set_root(int c, int x){\n\t\tint Rc = root(c); \n\t\t/* cout << \"root\" << c << \":\" << root(c) << endl; */ \n\t\tif (Rc != N + x and Rc > N){\n\t\t\treturn false; \n\t\t}else{\n\t\t\tpar[Rc] = N + x; \n\t\t\tsiz[Rc] = siz[Rc] + 1; \n\t\t\treturn true; \n\t\t}\n\t}\n\n\tint unite(int u, int v){\n\t\tint RootU = root(u); \n\t\tint RootV = root(v); \n\t\tif (RootU > N && RootV > N){\n\t\t\treturn false; \n\t\t}\n\t\tif (RootU == RootV) return true; \n\t\tif (siz[RootU] < siz[RootV]){\n\t\t\tif (RootU > N){\n\t\t\t\tpar[root_(u)] = RootV; \n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootV] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}else{\n\t\t\tif (RootV > N){\n\t\t\t\tpar[root_(v)] = RootU; \n\t\t\t\tpar[RootU] = RootV; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}else{\n\t\t\t\tpar[RootV] = RootU; \n\t\t\t\tsiz[RootU] = siz[RootU] + siz[RootV]; \n\t\t\t}\n\t\t\treturn true; \n\t\t}\n\t}\n\n\tbool same(int u, int v){\n\t\tif (root(u) == root(v)) return true; \n\t\treturn false; \n\t}\n\n}; \n\n\nint main(){\n\tint M, K; \n\tcin >> N >> M >> K; \n\tUnionFind uf; \n\tuf.init(N + M); \n\trep(i, K){\n\t\tint q, a, b; \n\t\tcin >> q >> a >> b; \n\t\tif (q == 1){\n\t\t\tif (uf.unite(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant unite\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}else{\n\t\t\tif (uf.set_root(a, b)){\n\t\t\t}else{\n\t\t\t\tcout << i + 1 << endl; \n\t\t\t\t/* cout << \"cant set_root\" << endl; */ \n\t\t\t\treturn 0; \n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl; \n}", "accuracy": 0.5652173913043478, "time_ms": 10, "memory_kb": 4768, "score_of_the_acc": -0.1346, "final_rank": 18 }, { "submission_id": "aoj_0321_8049242", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\nint main(void)\n{\n int n,m,k;\n cin>>n>>m>>k;\n bool flg=false;\n vector<int> par(n+1,0),rank(n+1,1),club(n+1,0);\n for(int i=0;i<=n;i++) par[i]=i;\n for(int i=0;i<=k;i++){\n if(flg){\n cout<<i<<endl;\n return 0;\n }\n if(i==k){\n cout<<\"0\"<<endl;\n return 0;\n }\n int cls,a,b,c,x;\n cin>>cls;\n if(cls==1){\n cin>>a>>b;\n while(a!=par[a]) a=par[a];\n while(b!=par[b]) b=par[b];\n if(a!=b){\n if((club[a]!=0 && club[b]!=0) && club[a]!=club[b]) flg=true;\n if(rank[a]>rank[b]){\n club[a]=max(club[a],club[b]);\n par[b]=a;\n }\n else if(rank[a]<rank[b]){\n club[b]=max(club[a],club[b]);\n par[a]=b;\n }\n else{\n club[a]=max(club[a],club[b]); \n par[b]=a;\n rank[a]++;\n }\n }\n else{\n if(club[a]!=club[b]) flg=true;\n }\n }\n else{\n cin>>c>>x;\n while(c!=par[c]) c=par[c];\n if(club[c]!=0 && club[c]!=x) flg=true;\n club[c]=x;\n }\n }\n cout<<\"0\"<<endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3892, "score_of_the_acc": -1.0167, "final_rank": 12 }, { "submission_id": "aoj_0321_8049240", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\nint main(void)\n{\n int n,m,k;\n cin>>n>>m>>k;\n bool flg=false;\n vector<int> par(n+1,0),rank(n+1,1),club(n+1,0);\n for(int i=0;i<=n;i++) par[i]=i;\n for(int i=0;i<k;i++){\n if(flg){\n cout<<i<<endl;\n return 0;\n }\n int cls,a,b,c,x;\n cin>>cls;\n if(cls==1){\n cin>>a>>b;\n while(a!=par[a]) a=par[a];\n while(b!=par[b]) b=par[b];\n if(a!=b){\n if((club[a]!=0 && club[b]!=0) && club[a]!=club[b]) flg=true;\n if(rank[a]>rank[b]){\n club[a]=max(club[a],club[b]);\n par[b]=a;\n }\n else if(rank[a]<rank[b]){\n club[b]=max(club[a],club[b]);\n par[a]=b;\n }\n else{\n club[a]=max(club[a],club[b]); \n par[b]=a;\n rank[a]++;\n }\n }\n else{\n if(club[a]!=club[b]) flg=true;\n }\n }\n else{\n cin>>c>>x;\n while(c!=par[c]) c=par[c];\n if(club[c]!=0 && club[c]!=x) flg=true;\n club[c]=x;\n }\n }\n cout<<\"0\"<<endl;\n}", "accuracy": 0.6086956521739131, "time_ms": 50, "memory_kb": 3884, "score_of_the_acc": -0.4601, "final_rank": 16 } ]
aoj_0320_cpp
Quality Management The fabric coasters produced and sold by Aizu Takada City are known for their symmetrical design and beauty. As part of quality control, Aizu Takada has installed cameras on the production line to automatically verify that the images obtained from each coaster are symmetrical. Each coaster is represented as a N × N pixel square black and white image. Each pixel takes a value of 0 or 1, corresponding to a white or black image. We have decided to update the software of our image analysis system in conjunction with the equipment upgrade of our production line. The new system has been devised to reduce the amount of communication data, and the data is sent from the camera to the analysis system in the following way. Information about the first coaster flowing into the line is sent to the system as an image of N × N pixels. For the second and subsequent coasters, only the difference from the previous image is sent. The difference is given as a set of pixel positions that have changed from "0 to 1" or "1 to 0". Write a program that reads C coasters by the pixel information of the first image and the difference information of the following C - 1 sheet, and reports the number of coasters of vertically symmetrical and horizontally symmetrical. Input The input is given in the following format. C N p 11 p 12 ... p 1N p 21 p 22 ... p 2N : p N1 p N2 ... p NN diff 1 diff 2 : diff C−1 In the first line, the number of coasters C (1 ≤ C ≤ 10000) and the number of vertical and horizontal pixels in the image N (2 ≤ N ≤ 1000 and N is even) are given. From the second line to the line N + 1 represent the pixels of the first coaster image N row × N elements p ij ( p ij is 0 or 1) are given. After the line N + 2, the difference diff i representing the information of the second and subsequent coasters is given in the following format. The number of changed pixels D (0 ≤ D ≤ 100) is given in the first line. In the following D lines, the row and column numbers of the changed pixels r i and c i are given, respectively. (1 ≤ r i , c i ≤ N ) . The same position cannot be given more than once in diff i . Output Output the number of coasters that are vertically symmetrical and horizontally symmetrical in a line. Sample Input 1 7 8 00100000 00011000 10111101 01100110 01000110 10111101 00011000 00100100 2 5 3 1 6 1 6 8 3 6 8 3 3 3 6 2 6 3 6 6 0 2 3 8 6 8 Sample Output 1 3 The image of the coaster for input example 1 is shown below. In this case, the second, fifth, and sixth coasters are symmetrical vertically and horizontally, so they are reported as 3. Sample Input 2 1 6 000000 000000 010010 010010 000000 000000 Sample Output 2 1 Sample Input 3 2 2 00 00 4 1 1 1 2 2 1 2 2 Sample Output 3 2
[ { "submission_id": "aoj_0320_10884337", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 1 << 30;\n\nint C, n;\nvector<vector<int>> p;\nint check(int x, int y) {\n if (p[x][y] == p[x][n-y-1] && p[x][y] == p[n-x-1][y] && p[x][y] == p[n-x-1][n-y-1]) return 1;\n else return 0;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n\n cin >> C >> n;\n p.resize(n);\n for (int i = 0; i < n; i++) {\n p[i].resize(n);\n string s;\n cin >> s;\n for (int j = 0; j < n; j++) {\n p[i][j] = s[j]-'0';\n }\n }\n \n int cnt = 0;\n for (int i = 0; i < n/2; i++) {\n for (int j = 0; j < n/2; j++) {\n if (check(i, j)) cnt++;\n }\n }\n int ans = 0;\n if (cnt == n*n/4) ans++;\n for (int i = 0; i < C-1; i++) {\n int d;\n cin >> d;\n for (int j = 0; j < d; j++) {\n int r, c;\n cin >> r >> c;\n r--, c--;\n\n if (check(r, c)) cnt--;\n p[r][c] = 1-p[r][c];\n if (check(r, c)) cnt++;\n }\n if (cnt == n*n/4) ans++;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7296, "score_of_the_acc": -0.0944, "final_rank": 4 }, { "submission_id": "aoj_0320_10884302", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\n#define rep(i, n) for (int i = 0; i < (int) (n); i++)\n\nint calcNr(int r, int N) {\n if (r >= N / 2) r = N - r - 1;\n return r;\n}\n\nint calcNc(int c, int N) {\n if (c >= N / 2) c = N - c - 1;\n return c;\n}\n\nint main() {\n int C, N;\n cin >> C >> N;\n\n vector<vector<int>> P(N, vector<int>(N));\n rep(i, N) {\n rep(j, N) {\n char tmp;\n cin >> tmp;\n P[i][j] = tmp - '0';\n }\n }\n\n // 前計算\n // S[i][j] := P[i][j], P[N - i - 1][j], P[i][N - j - 1], P[N - i - 1][N - j - 1] の和\n // cnt := Sの内、0または4である要素数\n vector<vector<int>> S(N / 2, vector<int>(N / 2, 0));\n int cnt = 0;\n\n rep(i, N) {\n int nr = calcNr(i, N);\n rep(j, N) {\n int nc = calcNc(j, N);\n S[nr][nc] += P[i][j];\n }\n }\n\n rep(i, N / 2) {\n rep(j, N / 2) {\n if (S[i][j] == 4 || S[i][j] == 0) cnt++;\n }\n }\n\n // クエリ処理\n int ans = 0;\n if (cnt == N * N / 4) ans++;\n\n rep(i, C - 1) {\n int D;\n cin >> D;\n\n rep(j, D) {\n int r, c;\n cin >> r >> c;\n r--; c--;\n\n // Pの更新\n P[r][c] = ((P[r][c] == 0) ? 1 : 0);\n\n // S, cntの更新\n int diff = ((P[r][c] == 1) ? 1 : -1);\n int nr = calcNr(r, N), nc = calcNc(c, N);\n if (S[nr][nc] == 4 || S[nr][nc] == 0) cnt--;\n S[nr][nc] += diff;\n if (S[nr][nc] == 4 || S[nr][nc] == 0) cnt++;\n }\n\n // ansの更新\n if (cnt == N * N / 4) ans++;\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 8360, "score_of_the_acc": -0.2914, "final_rank": 12 }, { "submission_id": "aoj_0320_10874389", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n int c,n; cin >> c >> n;\n int aaa=0;\n vector<vector<char>> A(n,vector<char>(n));\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n cin >> A[i][j];\n }\n }\n int ans=0;\n for(int i=0;i<n/2;++i){\n for(int j=0;j<n/2;++j){\n if(A[i][j]==A[i][n-1-j]&&A[i][j]==A[n-1-i][j]&&A[i][j]==A[n-1-i][n-1-j]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n for(int i=0;i<c-1;++i){\n int d; cin >> d;\n for(int j=0;j<d;++j){\n int a,b; cin >> a >> b;\n a--;b--;\n bool p=false;\n if(A[a][b]==A[a][n-1-b]&&A[a][b]==A[n-1-a][b]&&A[a][b]==A[n-1-a][n-1-b]){\n p=true;\n }\n if(A[a][b]=='0'){\n A[a][b]='1';\n }else{\n A[a][b]='0';\n }\n if(p){\n ans--;\n }else{\n if(A[a][b]==A[a][n-1-b]&&A[a][b]==A[n-1-a][b]&&A[a][b]==A[n-1-a][n-1-b]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n }\n cout << aaa << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 4440, "score_of_the_acc": -0.2295, "final_rank": 8 }, { "submission_id": "aoj_0320_10874387", "code_snippet": "#include<iostream>\n#include<string>\n#include<bitset>\n#include<vector>\n#include<deque>\n#include<queue>\n#include<algorithm>\n#include<set>\n#include<map>\n#include <unordered_map>\n#include<iomanip>\n#include<numeric>\n#include<stack>\n#include<tuple>\n#include<unordered_set>\n#define all(a) (a).begin(), (a).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define rep(i, x) for(long long i = 0; i < (x); i++)\n#define REP(i, x, limit) for (ll i = (ll)x; i <= (ll)limit; i++)\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YES cout << \"YES\" << endl\n#define NO cout << \"NO\" << endl\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing ll = long long;\nusing namespace std;\nusing Graph = vector<vector<int>>;\nint X[4] = { 1, 0, -1, 0 };//右、上、左、下\nint Y[4] = { 0, 1, 0, -1 };\n\nint main() {\n\tll C, N, ans = 0;\n\tcin >> C >> N;\n\tvector<vector<char>>list(N, vector<char>(N));\n\trep(i, N) {\n\t\trep(j, N) {\n\t\t\tcin >> list[i][j];\n\t\t}\n\t}\n\tll ok = 0;\n\trep(i, N / 2) {\n\t\trep(j, N / 2) {\n\t\t\tif (list[i][j] == list[N - i - 1][N - j - 1] && list[i][j] == list[i][N - j - 1] && list[i][j] == list[N - i - 1][j]) {\n\t\t\t\tok++;\n\t\t\t}\n\t\t}\n\t}\n\tif (ok == N * N / 4) {\n\t\tans++;\n\t}\n\trep(i, C-1) {\n\t\tll a;\n\t\tcin >> a;\n\t\trep(j, a) {\n\t\t\tll b, c;\n\t\t\tcin >> b >> c;\n\t\t\tb--, c--;\n\t\t\tif (list[b][c] == list[N - b - 1][N - c - 1] && list[b][c] == list[b][N - c - 1] && list[b][c] == list[N - b - 1][c]) {\n\t\t\t\tok--;\n\t\t\t}\t\t\t\t\n\t\t\tif (list[b][c] == '0') {\n\t\t\t\tlist[b][c] = '1';\n\t\t\t}\n\t\t\telse {\n\t\t\t\tlist[b][c] = '0';\n\t\t\t}\n\t\t\tif (list[b][c] == list[N - b - 1][N - c - 1] && list[b][c] == list[b][N - c - 1] && list[b][c] == list[N - b - 1][c]) {\n\t\t\t\tok++;\n\t\t\t}\n\t\t}\n\t\tif (ok == N * N / 4) {\n\t\t\tans++;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 4364, "score_of_the_acc": -0.2193, "final_rank": 6 }, { "submission_id": "aoj_0320_10874386", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n int c,n; cin >> c >> n;\n int aaa=0;\n vector<vector<char>> A(n,vector<char>(n));\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n cin >> A[i][j];\n }\n }\n int ans=0;\n for(int i=0;i<n/2;++i){\n for(int j=0;j<n/2;++j){\n if(A[i][j]==A[i][n-1-j]&&A[i][j]==A[n-1-i][j]&&A[i][j]==A[n-1-i][n-1-j]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n for(int i=0;i<c-1;++i){\n int d; cin >> d;\n for(int j=0;j<d;++j){\n int g,r;\n int a,b; cin >> a >> b;\n g=a;r=b;\n g--;r--;\n a--;b--;\n bool p=false;\n if(A[g][r]==A[g][n-1-r]&&A[g][r]==A[n-1-g][r]&&A[g][r]==A[n-1-g][n-1-r]){\n p=true;\n }\n if(A[a][b]=='0'){\n A[a][b]='1';\n }else{\n A[a][b]='0';\n }\n if(p){\n ans--;\n }else{\n if(A[g][r]==A[g][n-1-r]&&A[g][r]==A[n-1-g][r]&&A[g][r]==A[n-1-g][n-1-r]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n }\n cout << aaa << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 4432, "score_of_the_acc": -0.2294, "final_rank": 7 }, { "submission_id": "aoj_0320_10874346", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n int c,n; cin >> c >> n;\n int aaa=0;\n vector<vector<char>> A(n,vector<char>(n));\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n cin >> A[i][j];\n }\n }\n int ans=0;\n for(int i=0;i<n/2;++i){\n for(int j=0;j<n/2;++j){\n if(A[i][j]==A[i][n-1-j]&&A[i][j]==A[n-1-i][j]&&A[i][j]==A[n-1-i][n-1-j]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n for(int i=0;i<c-1;++i){\n int d; cin >> d;\n for(int j=0;j<d;++j){\n int g,r;\n int a,b; cin >> a >> b;\n if(a>n/2){\n g=n+1-a;\n }else{\n g=a;\n }\n if(b>n/2){\n r=n+1-b;\n }else{\n r=b;\n }\n g--;r--;\n a--;b--;\n bool p=false;\n if(A[g][r]==A[g][n-1-r]&&A[g][r]==A[n-1-g][r]&&A[g][r]==A[n-1-g][n-1-r]){\n p=true;\n }\n if(A[a][b]=='0'){\n A[a][b]='1';\n }else{\n A[a][b]='0';\n }\n if(p){\n ans--;\n }else{\n if(A[g][r]==A[g][n-1-r]&&A[g][r]==A[n-1-g][r]&&A[g][r]==A[n-1-g][n-1-r]){\n ans++;\n }\n }\n }\n if(ans==n*n/4)aaa++;\n }\n cout << aaa << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 4440, "score_of_the_acc": -0.2295, "final_rank": 8 }, { "submission_id": "aoj_0320_10873341", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int C, N;\n cin >> C >> N;\n vector S(N, vector<bool>(N));\n rep(i, 0, N) rep(j, 0, N) {\n char p;\n cin >> p;\n S[i][j] = (p == '1');\n }\n \n int M = N / 2;\n int diff = M*M;\n rep(i, 0, M) rep(j, 0, M) {\n if (S[i][j] == S[N - i - 1][j] && S[i][j] == S[i][N - j - 1] && S[i][j] == S[N - i - 1][N - j - 1]) --diff;\n }\n \n int ans = (diff == 0 ? 1 : 0);\n \n rep(query, 0, C - 1) {\n int D;\n cin >> D;\n \n rep(k, 0, D) {\n int i, j;\n cin >> i >> j;\n --i, --j;\n \n if (S[i][j] == S[N - i - 1][j] && S[i][j] == S[i][N - j - 1] && S[i][j] == S[N - i - 1][N - j - 1]) ++diff;\n S[i][j] = !S[i][j];\n if (S[i][j] == S[N - i - 1][j] && S[i][j] == S[i][N - j - 1] && S[i][j] == S[N - i - 1][N - j - 1]) --diff;\n }\n \n if (diff == 0) {\n ++ans;\n }\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3596, "score_of_the_acc": -0.0721, "final_rank": 2 }, { "submission_id": "aoj_0320_10871846", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int c, n; cin >> c >> n;\n vector<string> p(n);\n rep(i, n)cin >> p[i];\n auto same = [&](int y, int x) {\n if (y >= (n + 1) / 2)y = n - 1 - y;\n if (x >= (n + 1) / 2)x = n - 1 - x;\n return p[y][x] == p[n - 1 - y][x] && p[y][x] == p[y][n - 1 - x] && p[y][x] == p[n - 1 - y][n - 1 - x];\n };\n int cnt = 0;\n rep(i, (n + 1) / 2)rep(j, (n + 1) / 2)if (!same(i, j))cnt++;\n int ans = 0;\n if (cnt == 0)ans++;\n rep(i, c - 1) {\n int d; cin >> d;\n rep(j, d) {\n int r, c; cin >> r >> c;\n r--, c--;\n if (same(r, c))cnt++;\n if (p[r][c] == '0')p[r][c] = '1';\n else p[r][c] = '0';\n if (same(r, c))cnt--;\n }\n if (cnt == 0)ans++;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 5504, "score_of_the_acc": -0.1833, "final_rank": 5 }, { "submission_id": "aoj_0320_10867107", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//vector<ll> saiki(ll bit,ll n){\n//\tvector<ll> s(n);\n//\tfor(ll i=0;i<n;i++){\n//\t\tif(bit&(1<<i)){\n//\t\t\ts[i]=1;\n//\t\t}else s[i]=0;\n//\t}\n//\treturn s;\n//}\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll c,n;\n\tcin>>c>>n;\n\tvector<vector<char> > p(n,vector<char> (n));\n\trep(i,n)rep(j,n)cin>>p[i][j];\n\tset<Pll> st2;\n\tfor(ll i=0;i<n/2;i++){\n\t\tfor(ll j=0;j<n/2;j++){\n\t\t\tif(p[i][j]==p[i][n-1-j]&&p[i][j]==p[n-i-1][j]&&p[i][j]==p[n-1-i][n-1-j]){\n\t\t\t\tst2.insert({i,j});\n\t\t\t}\n\t\t}\n\t}\n//\tcout<<v<<endl;\n//判定\n\tll ans=0;\n\tif(st2.size()==(n/2)*(n/2))ans++;\n\trep(i,c-1){\n\t\tll d;\n\t\tcin>>d;\n\t\tset<Pll> st;\n\t\tvector<Pll> u;\n\t\trep(j,d){\n\t\t\tll x,y;\n\t\t\tcin>>x>>y;\n\t\t\tif(p[x-1][y-1]=='0')p[x-1][y-1]='1';\n\t\t\telse p[x-1][y-1]='0';\n\t\t\tu.push_back({x,y});\n\t\t}\n\t\trep(j,d){\n\t\t\tll x=u[j].first,y=u[j].second;\n\t\t\tll X=x-1,Y=y-1;\n\t\t\tif(X>=n/2)X=n-X-1;\n\t\t\tif(Y>=n/2)Y=n-Y-1;\n\t\t\tif(st.find({X,Y})!=st.end())continue;\n\t\t\tif(p[X][Y]==p[X][n-1-Y]&&p[X][Y]==p[n-X-1][Y]&&p[X][Y]==p[n-1-X][n-1-Y]){\n\t\t\t\tst2.insert({X,Y});\n\t\t\t\tst.insert({X,Y});\n\t\t\t}else{\n\t\t\t\tst2.erase({X,Y});\n\t\t\t}\n\n\t\t}\n//\t\trep(j,d){\n//\t\t\tll x=u[j].first,y=u[j].second;\n//\t\t\tif(p[x-1][y-1]=='0')p[x-1][y-1]='1';\n//\t\t\telse p[x-1][y-1]='0';\n////\t\t\tif(i==0)cout<<x<<\" \"<<y<<endl;\n//\t\t}\n//\t\tcout<<V<<endl;\n\t\tif(st2.size()==(n/2)*(n/2)){\n\t\t\tans++;\n\t\t}\n\t}\n\n\tcout<<ans<<endl;\n//判定2\n//\tfor(ll i=0;i<n;i++){\n//\t\tfor(ll j=0;j<n/2;j++){\n//\t\t\tif(p[i][j]!=p[i][n-j-1]){\n//\t\t\t\tcout<<\n//\t\t\t}\n//\t\t}\n//\t}\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 20080, "score_of_the_acc": -0.6205, "final_rank": 15 }, { "submission_id": "aoj_0320_10852381", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int C,N;\n cin>>C>>N;\n vector<string> A(N);\n rep(i,N)cin>>A[i];\n int now=0;\n rep(i,N)rep(j,N)now+=(A[i][j]==A[N-i-1][j])+(A[i][j]==A[i][N-j-1]);\n now/=2;\n\n int ans=0;\n if(now==N*N) ans++;\n rep(_,C-1){\n int D;\n cin>>D;\n rep(_,D){\n int r,c;\n cin>>r>>c;\n r--;c--;\n if(A[r][c]==A[N-r-1][c]) now--;\n if(A[r][c]==A[r][N-c-1]) now--;\n A[r][c]='0'+('1'-A[r][c]);\n if(A[r][c]==A[N-r-1][c]) now++;\n if(A[r][c]==A[r][N-c-1]) now++;\n }\n if(now==N*N)ans++;\n }\n cout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4736, "score_of_the_acc": -0.054, "final_rank": 1 }, { "submission_id": "aoj_0320_10796215", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(x) x.begin(),x.end()\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n\n\nint main(){\n int C,N;cin>>C>>N;\n vector<vector<int>>P(N,vector<int>(N,0));\n rep(i,N){\n string s;cin>>s;\n rep(j,N)if(s[j]=='1')P[i][j]=1;\n }\n int ans = 0;\n int ct = 0;\n rep(i,(N+1)/2)rep(j,(N+1)/2){\n int x = 0;\n x+=P[i][j];\n x+=P[i][N-j-1];\n x+=P[N-i-1][j];\n x+=P[N-i-1][N-j-1];\n if(x!=0&&x!=4)ct++;\n }\n if(ct==0)ans++;\n rep(c,C-1){\n int D;cin>>D;\n rep(d,D){\n int r,c;cin>>r>>c;r--;c--;\n int bef = P[r][c]+P[N-r-1][c]+P[r][N-c-1]+P[N-r-1][N-c-1];\n if(bef==0||bef==4)ct++;\n P[r][c]=1-P[r][c];\n bef = P[r][c]+P[N-r-1][c]+P[r][N-c-1]+P[N-r-1][N-c-1];\n if(bef==0||bef==4)ct--;\n }\n if(ct==0)ans++;\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 7392, "score_of_the_acc": -0.2581, "final_rank": 11 }, { "submission_id": "aoj_0320_10719664", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#define _USE_MATH_DEFINES\n#include <math.h>\n#include <cstring>\n#include <numeric>\n#include <algorithm>\n#include <stdlib.h>\n#include <functional>\n#include <string>\n#include <array>\n#include <map>\n#include <queue>\n#include <limits.h>\n#include <set>\n#include <stack>\n#include <random>\n#include <complex>\n#include <unordered_map>\n#include <nmmintrin.h>\n#include <chrono>\n#define rep(i,s,n) for(int i = (s); (n) > i; i++)\n#define REP(i,n) rep(i,0,n)\n#define RANGE(x,a,b) ((a) <= (x) && (x) <= (b))\n#define DUPLE(a,b,c,d) (RANGE(a,c,d) || RANGE(b,c,d) || RANGE(c,a,b) || RANGE(d,a,b))\n#define INCLU(a,b,c,d) (RANGE(a,c,d) && (b,c,d))\n#define PW(x) ((x)*(x))\n#define ALL(x) (x).begin(), (x).end()\n#define MODU 1000000007\n#define bitcheck(a,b) ((a >> b) & 1)\n#define bitset(a,b) ( a |= (1 << b))\n#define bitunset(a,b) (a &= ~(1 << b))\n#define MP(a,b) make_pair((a),(b))\n#define Manh(a,b) (abs((a).first-(b).first) + abs((a).second - ((b).second))\n#define pritnf printf\n#define scnaf scanf\n#define itn int\n#ifdef _MSC_VER\n#define __builtin_popcount _mm_popcnt_u32\n#define __builtin_popcountll _mm_popcnt_u64\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll gcd(ll a, ll b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a%b);\n}\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N], const T &val) {\n\tstd::fill((T*)array, (T*)(array + N), val);\n}\n\nint c, n;\n\npii getza(int cx, int cy){\n\tif (cx >= n / 2)\n\t\tcx = n - cx - 1;\n\tif (cy >= n / 2)\n\t\tcy = n - cy - 1;\n\treturn{ cx, cy };\n}\n\nint nanm(int cx, int cy){\n\tint ret = 0;\n\tif (cx >= n / 2)\n\t\tret += 1;\n\tif (cy >= n / 2)\n\t\tret+= 2;\n\treturn ret;\n}\n\nsigned main() {\n\tcin >> c >> n;\n\tint mp[251][251][4] = {};\n\n\tint wr = 0;\n\n\tREP(i, n){\n\t\tchar ch;\n\t\tscnaf(\"%c\", &ch);\n\t\tREP(j, n){\n\t\t\tpii cc = getza(i, j);\n\t\t\tscnaf(\"%c\",&ch);\n\t\t\tmp[cc.first][cc.second][nanm(i,j)] = ch - '0';\n\t\t}\n\t}\n\n\tREP(i, n/2){\n\t\tREP(j, n/2){\n\t\t\tpii cc = getza(i, j);\n\t\t\tint cs = mp[cc.first][cc.second][0] + mp[cc.first][cc.second][1] + mp[cc.first][cc.second][2] + mp[cc.first][cc.second][3];\n\t\t\tif (cs < 4 && cs > 0)\n\t\t\t\twr++;\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tif (!wr)\n\t\tans++;\n\n\tREP(i, c-1){\n\t\tint m;\n\t\tcin >> m;\n\t\tREP(i, m){\n\t\t\tint x, y;\n\t\t\tcin >> x >> y;\n\t\t\tx--, y--;\n\t\t\tpii cc = getza(x, y);\n\t\t\tint bef = mp[cc.first][cc.second][0] + mp[cc.first][cc.second][1] + mp[cc.first][cc.second][2] + mp[cc.first][cc.second][3];\n\n\t\t\tmp[cc.first][cc.second][nanm(x, y)] = 1 - mp[cc.first][cc.second][nanm(x, y)];\n\n\t\t\tint cur = mp[cc.first][cc.second][0] + mp[cc.first][cc.second][1] + mp[cc.first][cc.second][2] + mp[cc.first][cc.second][3];\n\n\t\t\tif ((bef == 4 ||bef == 0) && (cur > 0 && cur < 4)){\n\t\t\t\twr++;\n\t\t\t}\n\n\t\t\tif ((cur == 4 || cur == 0) && (bef > 0 && bef < 4)){\n\t\t\t\twr--;\n\t\t\t}\n\t\t}\n\n\t\tif (!wr)\n\t\t\tans++;\n\t}\n\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "accuracy": 0.375, "time_ms": 10, "memory_kb": 4552, "score_of_the_acc": -0.0151, "final_rank": 18 }, { "submission_id": "aoj_0320_9963801", "code_snippet": "#include <climits>\n#include <cstdlib>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst size_t C_MIN = 1;\nconst size_t C_MAX = 10000;\nconst size_t N_MIN = 2;\nconst size_t N_MAX = 1000;\nconst size_t D_MIN = 0;\nconst size_t D_MAX = 100;\n\ninline int next(int N, int i)\n{\n\treturn (((N - i - 1) + N) % N);\n}\n\ninline bool isSymmetry(int N, vector<vector<char>>& pat, int i, int j)\n{\n\t//int const N = pat[0].size();\n\tchar ch = pat[i][j];\n\treturn (ch == pat[i][next(N, j)]\n\t\t&& ch == pat[next(N, i)][j]\n\t\t&& ch == pat[next(N, i)][next(N, j)]);\n}\n\n\nint calcInit(vector<vector<char>>& pat)\n{\n\tint const N = pat[0].size();\n\tint cnt = 0;\n\n\tfor (int i = 0; i < N / 2; i++)\n\t{\n\t\tfor (int j = 0; j < N / 2; j++)\n\t\t{\n\t\t\tif (!isSymmetry(N, pat, i, j))\n\t\t\t{\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t}\n\treturn cnt;\n}\n\ninline void toggle(vector<vector<char>>& pat, int r, int c)\n{\n\n\tif (pat[r][c] == '0')\n\t{\n\t\tpat[r][c] = '1';\n\t}\n\telse\n\t{\n\t\tpat[r][c] = '0';\n\t}\n}\n\nint main()\n{\n\t// コースターの枚数\n\tint c = 0;\n\tcin >> c;\n\tif (c < C_MIN || C_MAX < c)\n\t{\n\t\tcout << C_MIN << \" <= c <= \" << C_MAX << \") but input \" << c << endl;\n\t\texit(1);\n\t}\n\n\t// コースターのサイズ\n\tint n = 0;\n\tcin >> n;\n\tif (n < N_MIN || N_MAX < n)\n\t{\n\t\tcout << N_MIN << \" <= n <= \" << N_MAX << \") but input \" << n << endl;\n\t\texit(1);\n\t}\n\tvector<vector<char>> VIC(n, vector<char>(n));\n\t// 1枚目のコースターの画像情報の入力\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tfor (int j = 0; j < n; j++)\n\t\t{\n\t\t\tcin >> VIC[i][j];\n\t\t}\n \t}\n\tint const N = VIC[0].size();\n\tint count = 0;\n\tint dcnt = calcInit(VIC);\n\tif (dcnt == 0) count++;\n\t// 2枚目以降の情報入力\n\tfor (int i = 0; i < c - 1; i++)\n\t{\n\t\tint d;\n\t\tcin >> d;\n\t\tif (d < D_MIN || D_MAX < d)\n\t\t{\n\t\t\tcout << D_MIN << \" <= d <= \" << D_MAX << \") but input \" << d << endl;\n\t\t\texit(1);\n\t\t}\n\n\t\tfor (int j = 0; j < d; j++)\n\t\t{\n\t\t\tbool pre = false;\n\t\t\tbool post = false;\n\t\t\tint r = 0;\n\t\t\tint c = 0;\n\t\t\tcin >> r >> c;\n\t\t\tr--; c--;\n\t\t\tpre = isSymmetry(N, VIC, r, c);\n\t\t\ttoggle(VIC, r, c);\n\t\t\tpost = isSymmetry(N, VIC, r, c);\n\t\t\tif (!pre && post)\n\t\t\t{\n\t\t\t\tdcnt--;\n\t\t\t}\n\t\t\telse if (pre && !post)\n\t\t\t{\n\t\t\t\tdcnt++;\n\t\t\t}\n\t\t}\n\t\tif (dcnt == 0)\n\t\t{\n\t\t\tcount++;\n\t\t}\n\t}\n\tcout << count << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 4468, "score_of_the_acc": -0.239, "final_rank": 10 }, { "submission_id": "aoj_0320_9952322", "code_snippet": "#include <climits>\n#include <cstdlib>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst size_t C_MIN = 1;\nconst size_t C_MAX = 10000;\nconst size_t N_MIN = 2;\nconst size_t N_MAX = 1000;\nconst size_t D_MIN = 0;\nconst size_t D_MAX = 100;\n\nusing vc = vector<char>; // charの1次元の型にvcの別名を付ける\nusing vic = vector<vc>; // vcの2次元の型にvicの別名を付ける\nusing vvic = vector<vic>; // vcの3次元の型にvvicの別名を付ける\n\nvoid toggle(vector<vector<char>>& rowlist, int r, int c)\n{\n\n\tif (rowlist[r][c] == '0')\n\t{\n\t\trowlist[r][c] = '1';\n\t}\n\telse\n\t{\n\t\trowlist[r][c] = '0';\n\t}\n}\n\n// 上下対称確認\nbool isHorizontalSymmetry(vector<vector<char>>& left, vector<vector<char>>& right)\n{\n\tint const N = left[0].size();\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tif (left[i][j] != right[N - 1 - i][j])\n\t\t\t{\n\t\t\t\t// 上下対称ではない\n\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\t// 上下対称です\n\treturn true;\n}\n\n// 左右対称確認\nbool isVerticalSymmetry(vector<vector<char>>& left, vector<vector<char>>& right)\n{\n\tint const N = left[0].size();\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tfor (int j = 0; j < N; j++)\n\t\t{\n\t\t\tif (left[i][j] != right[i][N - 1 - j])\n\t\t\t{\n\t\t\t\t// 左右対称ではない\n\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\t// 左右対称です\n\treturn true;\n}\n\nint main()\n{\n\t// コースターの枚数\n\tint c = 0;\n\tcin >> c;\n\tif (c < C_MIN || C_MAX < c)\n\t{\n\t\tcout << C_MIN << \" <= c <= \" << C_MAX << \") but input \" << c << endl;\n\t\texit(1);\n\t}\n\t// コースターのサイズ\n\tint n = 0;\n\tcin >> n;\n\tif (n < N_MIN || N_MAX < n)\n\t{\n\t\tcout << N_MIN << \" <= n <= \" << N_MAX << \") but input \" << n << endl;\n\t\texit(1);\n\t}\n\n\tvc VC(n);\n\tvic VIC(n, VC);\n\tvvic VVIC(c, VIC);\n\t// 1枚目のコースターの画像情報の入力\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tfor (int j = 0; j < n; j++)\n\t\t{\n\t\t\tcin >> VVIC[0][i][j];\n\t\t}\n\t\tif (VVIC[0][i].size() != n)\n\t\t{\n\t\t\tstd::string str(VVIC[0][i].begin(), VVIC[0][i].end());\n\t\t\tcout << \" patlist.size == \" << n << \" but input \" << str << \" size is \" << str.size() << endl;\n\t\t\texit(1);\n\t\t}\n\t}\n\t// 2枚目以降の情報入力\n\tfor (int i = 1; i < c; i++)\n\t{\n\t\tVVIC[i] = VVIC[i - 1];\n\t\tint d;\n\t\tcin >> d;\n\t\tif (d < D_MIN || D_MAX < d)\n\t\t{\n\t\t\tcout << D_MIN << \" <= d <= \" << D_MAX << \") but input \" << d << endl;\n\t\t\texit(1);\n\t\t}\n\n\t\tfor (int j = 0; j < d; j++)\n\t\t{\n\t\t\tint r;\n\t\t\tint c;\n\t\t\tcin >> r >> c;\n\t\t\ttoggle(VVIC[i], r - 1, c - 1);\n\t\t}\n\t}\n\n\tint count = 0;\n\tfor (int i = 0; i < c; i++)\n\t{\n\t\tif (isHorizontalSymmetry(VVIC[i], VVIC[i])\n\t\t\t&& isVerticalSymmetry(VVIC[i], VVIC[i])\n\t\t\t)\n\t\t{\n\t\t\tcount++;\n\t\t}\n\t}\n\tcout << count << endl;\n\n\treturn 0;\n}", "accuracy": 0.375, "time_ms": 10, "memory_kb": 6796, "score_of_the_acc": -0.0505, "final_rank": 19 }, { "submission_id": "aoj_0320_9803559", "code_snippet": "#include <iostream>\n#include <map>\n\nusing namespace std;\n\nint P[1000][1000];\nint N;\nmap<int, int> d;\n\nvoid diff()\n{\n int i, j;\n\n for (i = 0; i < N / 2; i++){\n for (j = 0; j < N / 2; j++){\n if (P[i][j] != P[i][N - j - 1]){\n d.insert(make_pair(i * 1000 + (N - j - 1), 0));\n }\n if (P[i][j] != P[N - i - 1][j]){\n d.insert(make_pair((N - i - 1) * 1000 + j, 0));\n }\n if (P[i][j] != P[N - i - 1][N - j - 1]){\n d.insert(make_pair((N - i - 1) * 1000 + (N - j - 1), 0));\n }\n }\n }\n}\n\nvoid update(int r, int c)\n{\n auto it = d.find(r * 1000 + c);\n if (it == d.end()){\n d.insert(make_pair(r * 1000 + c, 0));\n }\n else {\n d.erase(it);\n }\n}\n\nint main(void)\n{\n int C;\n string p;\n int D;\n int r, c;\n int i, j;\n int cnt;\n\n cin >> C >> N;\n for (i = 0; i < N; i++){\n cin >> p;\n for (j = 0; j < N; j++){\n P[i][j] = p[j] - '0';\n }\n } \n\n diff();\n if (d.empty()){\n cnt++;\n }\n // cout << \"<\";\n // for (auto it = d.begin(); it != d.end(); it++){\n // cout << \"[\" << it->first << \"]\";\n // }\n // cout << \">\" << endl;\n\n\n for (i = 0; i < C - 1; i++){\n cin >> D;\n for (j = 0; j < D; j++){\n scanf(\"%d%d\", &r, &c);\n r--;\n c--;\n if (r < N / 2 && c < N / 2){\n update(N - r - 1, c);\n update(r, N - c - 1);\n update(N - r - 1, N - c - 1);\n }\n else {\n update(r, c);\n }\n }\n if (d.empty()){\n cnt++;\n }\n // cout << \"<\";\n // for (auto it = d.begin(); it != d.end(); it++){\n // cout << \"[\" << it->first << \"]\";\n // }\n // cout << \">\" << endl;\n }\n cout << cnt << endl;\n\n return (0);\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 22588, "score_of_the_acc": -0.5429, "final_rank": 14 }, { "submission_id": "aoj_0320_9608080", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n6:51~7:05\n13:07~\n*/\n\nsigned main(){\n\tint q,n;cin>>q>>n;\n\tvector<string> s(n);\n\n\tfor(auto&&e:s)cin>>e;\n\n\tauto enu=[&](int x,int y){\n\t\tvector<pair<int,int>> vec;\n\t\tint x2=n-x-1,y2=n-y-1;\n\n\t\tfor(int S=0;S<4;S++){\n\t\t\tpair<int,int> p;\n\t\t\tif(S>>0&1)p.first=x;\n\t\t\telse p.first=x2;\n\t\t\tif(S>>1&1)p.second=y;\n\t\t\telse p.second=y2;\n\t\t\tvec.push_back(p);\n\t\t}\n\n\t\treturn vec;\n\t};\n\n\tauto fit=[&](int x,int y){\n\t\tauto vec=enu(x,y);\n\t\tfor(int i=1;i<3;i++){\n\t\t\tif(s[vec[0].first][vec[0].second]!=s[vec[i].first][vec[i].second]){\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\treturn 1;\n\t};\n\n\tint cnt=0;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\t\tcnt+=fit(i,j);\n\t\t}\n\t}\n\n\tint ans=(cnt==n*n);\n\tq--;\n\twhile(q--){\n\t\tint m;cin>>m;\n\t\twhile(m--){\n\t\t\tint x,y;cin>>x>>y;\n\t\t\tx--;y--;\n\t\t\tfor(auto&&[nx,ny]:enu(x,y)){\n\t\t\t\tcnt-=fit(nx,ny);\n\t\t\t}\n\t\t\tif(s[x][y]=='0')s[x][y]='1';\n\t\t\telse s[x][y]='0';\n\t\t\tfor(auto&&[nx,ny]:enu(x,y)){\n\t\t\t\tcnt+=fit(nx,ny);\n\t\t\t}\n\t\t}\n\n\t\tif(cnt==n*n){\n\t\t\tans++;\n\t\t}\n\t}\n\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 810, "memory_kb": 5368, "score_of_the_acc": -0.7487, "final_rank": 16 }, { "submission_id": "aoj_0320_9512877", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nchar p[1000][1001];\nint dw[1000][500],dh[500][1000];\nint main(void)\n{\n\tint c,n,i,j,wc,hc,d,r,cc,cnt,c2,r2;\n\tcin >>c>>n;\n\tfor(i=0;i<n;i++)\tcin >>p[i];\n\twc=0;\n\tfor(i=0;i<n;i++)\t{\n\t\tfor(j=0;j<n/2;j++)\t{\n\t\t\tif(p[i][j]==p[i][n-j-1]){\n\t\t\t\tdw[i][j]=0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdw[i][j]=1;\twc++;\n//\t\t\t\tcout <<\"i=\"<<i<<\"j=\"<<j<<endl;\n\t\t\t}\n\t\t}\n\t}\n\thc=0;\n\tfor(i=0;i<n/2;i++)\t{\n\t\tfor(j=0;j<n;j++)\t{\n\t\t\tif(p[i][j]==p[n-i-1][j]){\n\t\t\t\tdh[i][j]=0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdh[i][j]=1;\thc++;\n//\t\t\t\tcout <<\"i=\"<<i<<\"j=\"<<j<<endl;\n\t\t\t}\n\t\t}\n\t}\t\n//\tcout <<\" \"<<wc<<\" \"<<hc<<endl;\n\tif(hc==0 && wc==0)\tcnt=1;\n\telse cnt=0;\n\tfor(i=2;i<=c;i++)\t{\n\t\tcin >>d;\n\t\tfor(j=0;j<d;j++)\t{\n\t\t\tcin >>r>>cc;\n\t\t\tr--;\tcc--;\n\t\t\tif(cc>=n/2)\tc2=n-cc-1;\n\t\t\telse c2=cc;\n//\t\t\tcout <<\" \"<<r<<c2<<endl;\n\t\n\t\t\tif(dw[r][c2]==1)\t{\n\t\t\t\tdw[r][c2]=0;\n\t\t\t\twc--;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdw[r][c2]=1;\n\t\t\t\twc++;\n\t\t\t}\n\t\t\tif(r>=n/2)\tr2=n-r-1;\n\t\t\telse r2=r;\n\t\t\t\n//\t\t\tcout <<\" \"<<r2<<cc<<endl;\t\t\t\n\t\t\t\n\t\t\tif(dh[r2][cc]==1)\t{\n\t\t\t\tdh[r2][cc]=0;\n\t\t\t\thc--;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdh[r2][cc]=1;\n\t\t\t\thc++;\n\t\t\t}\n\t\t}\n//\t\t\tcout <<\" \"<<wc<<\" \"<<hc<<endl;\n\t\tif(hc==0 && wc==0)\tcnt++;\n\t}\n\tcout <<cnt<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 7968, "score_of_the_acc": -0.3393, "final_rank": 13 }, { "submission_id": "aoj_0320_9373129", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vc<vc<T>>;\nvoid solve();\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n ll t = 1;\n // cin >> t;\n for (int i = 1; i <= t; i++) solve();\n return 0;\n}\n#define rep(i, a, b) for (ll i = (a); i < (b); i++)\nll dy[4] = {0, 1, 0, -1}, dx[4] = {1, 0, -1, 0};\n// ll dy[8] = {1, 1, 0, -1, -1, -1, 0, 1}, dx[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n\nvoid solve() {\n ll C, n;\n cin >> C >> n;\n vvc<char> a(n, vc<char>(n));\n rep(i, 0, n) rep(j, 0, n) cin >> a[i][j];\n vvc<bool> sym(n / 2, vc<bool>(n / 2));\n ll cnt = 0;\n rep(i, 0, n / 2) rep(j, 0, n / 2) {\n if (a[i][j] == a[i][n - 1 - j] && a[i][j] == a[n - 1 - i][j] &&\n a[i][j] == a[n - 1 - i][n - 1 - j])\n sym[i][j] = true, cnt++;\n }\n ll res = (cnt == n / 2 * n / 2);\n rep(i, 1, C) {\n ll d;\n cin >> d;\n auto check = [&](ll r, ll c) {\n return a[r][c] == a[n - 1 - r][n - 1 - c] &&\n a[r][c] == a[n - 1 - r][c] && a[r][c] == a[r][n - 1 - c];\n };\n rep(j, 0, d) {\n ll r, c;\n cin >> r >> c;\n r--, c--;\n if (a[r][c] == '0')\n a[r][c] = '1';\n else\n a[r][c] = '0';\n if (r >= n / 2) r = n - 1 - r;\n if (c >= n / 2) c = n - 1 - c;\n if (sym[r][c] && !check(r, c)) {\n sym[r][c] = false;\n cnt--;\n }\n if (!sym[r][c] && check(r, c)) {\n sym[r][c] = true;\n cnt++;\n }\n }\n res += (cnt == n / 2 * n / 2);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4460, "score_of_the_acc": -0.0857, "final_rank": 3 }, { "submission_id": "aoj_0320_9349013", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll C, N;\n cin >> C >> N;\n vc<string> p(N);\n rep(i, N) {cin >> p[i];}\n vc<set<pi>> v(2), h(2); // 0: 片方、1: 両方\n auto check_and_conduct =[&](ll r, ll c, bool adding) {\n ll y = (r < N/2) ? r : N-1-r;\n ll x = (c < N/2) ? c : N-1-c;\n if (adding) {\n auto t = mp(y, c);\n if (v[0].count(t)) {\n v[0].erase(t);\n v[1].emplace(t);\n } else {\n v[0].emplace(t);\n }\n t = mp(r, x);\n if (h[0].count(t)) {\n h[0].erase(t);\n h[1].emplace(t);\n } else {\n h[0].emplace(t);\n }\n } else {\n auto t = mp(y, c);\n if (v[0].count(t)) {\n v[0].erase(t);\n } elif (v[1].count(t)) {\n v[1].erase(t);\n v[0].emplace(t);\n }\n t = mp(r, x);\n if (h[0].count(t)) {\n h[0].erase(t);\n } elif (h[1].count(t)) {\n h[1].erase(t);\n h[0].emplace(t);\n }\n }\n };\n rep(r, N) rep(c, N) {\n if (p[r][c] == '0') continue;\n check_and_conduct(r, c, true);\n }\n ll ans = ((len(v[0]) == 0) and (len(h[0]) == 0));\n rep(C-1) {\n ll D, r, c;\n cin >> D;\n rep(D) {\n cin >> r >> c;\n --r, --c;\n check_and_conduct(r, c, p[r][c] == '0');\n p[r][c] = (p[r][c] == '1') ? '0' : '1';\n }\n ans += ((len(v[0]) == 0) and (len(h[0]) == 0));\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 66972, "score_of_the_acc": -2, "final_rank": 17 }, { "submission_id": "aoj_0320_9348734", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll C, N;\n cin >> C >> N;\n vc<string> p(N);\n rep(i, N) {cin >> p[i];}\n vc<set<pi>> v(2), h(2); // 0: 片方、1: 両方\n auto check_and_conduct =[&](ll r, ll c) {\n ll y = (r < N/2) ? r : N-1-r;\n ll x = (c < N/2) ? c : N-1-c;\n auto t = mp(r, x);\n if (v[0].count(t)) {\n v[0].erase(t);\n v[1].emplace(t);\n } else {\n v[0].emplace(t);\n }\n t = mp(y, c);\n if (h[0].count(t)) {\n h[0].erase(t);\n h[1].emplace(t);\n } else {\n h[0].emplace(t);\n }\n };\n rep(i, N) rep(j, N) {\n if (p[i][j] == '0') continue;\n check_and_conduct(i, j);\n }\n ll ans = ((len(v[0]) == 0) and (len(h[0]) == 0));\n rep(C) {\n ll D, r, c;\n cin >> D;\n rep(D) {\n cin >> r >> c;\n --r, --c;\n check_and_conduct(r, c);\n ans += ((len(v[0]) == 0) and (len(h[0]) == 0));\n }\n }\n print(ans);\n return 0;\n}", "accuracy": 0.1875, "time_ms": 10, "memory_kb": 7240, "score_of_the_acc": -0.0575, "final_rank": 20 } ]
aoj_0323_cpp
Ruins The Aizu Archaeological Society has set out to investigate the ruin of the ancient nation of Iwashiro, which is submerged in the Hibarra Sea. The ruin exists somewhere in the Hibara Sea. We decided to use radar to get a rough idea of the location of the ruin from the shoreline, and to estimate how many meters away from the shoreline we would have to go to investigate. The observation points are placed on the coastline represented by the straight line as shown in the figure above, and the exploration radars are placed there. The radar can only tell us that there is the ruin within a semicircle of a certain size centered on the observation point. However, by combining multiple observation data, it is possible to narrow down the area to a smaller one. Given some observation data, consisting of the location of the observation points and the radius indicated by the exploration radars, write a program to find out how far from the coastline we need to survey at most. Input The input is given in the following format. N x 1 r 1 x 2 r 2 : x N r N The first line gives the number of data measured by the exploration radar N (1 ≤ N ≤ 100000). The following N lines are integers x i that represents the position of the observed data i on the coastline in meters (0 ≤ x i ≤ 1,000,000) and integers r i that represents the number of meters within a radius of the site (1 ≤ r i ≤ 1,000,000). Two or more observation data with the same observation point may be given. If there are multiple observational data given, it can be considered that there is always a point included in all of those semicircles. Output Outputs the actual number of meters that need to be investigated from the coastline. However, the error must not exceed plus or minus 0.001 meters. If this condition is satisfied, any number of digits after the decimal point may be displayed. Sample Input 1 2 0 2 1 2 Sample Output 1 1.936 Sample Input 2 3 0 3 1 2 2 1 Sample Output 2 1.0 Sample Input 3 2 0 1 3 2 Sample Output 3 0.0
[ { "submission_id": "aoj_0323_10873523", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int n; cin >> n;\n double left = -inf, right = inf;\n vector<int> x(n), r(n);\n rep(i, n) {\n cin >> x[i] >> r[i];\n chmax(left, double(x[i] - r[i]));\n chmin(right, double(x[i] + r[i]));\n }\n auto f = [&](double d) {\n double res = inf;\n rep(i, n) {\n chmin(res, sqrt((double)r[i] * r[i] - (d - x[i]) * (d - x[i])));\n }\n return res;\n };\n rep(i, 100) {\n double m1 = (left * 2 + right) / 3;\n double m2 = (left + right * 2) / 3;\n if (f(m1) < f(m2))left= m1;\n else right = m2;\n }\n printf(\"%.10f\\n\", f(left));\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4352, "score_of_the_acc": -0.2053, "final_rank": 4 }, { "submission_id": "aoj_0323_10873518", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int n; cin >> n;\n double left = -inf, right = inf;\n vector<int> x(n), r(n);\n rep(i, n) {\n cin >> x[i] >> r[i];\n chmax(left, double(x[i] - r[i]));\n chmin(right, double(x[i] + r[i]));\n }\n auto f = [&](double d) {\n double res = inf;\n rep(i, n) {\n chmin(res, sqrt(r[i] * r[i] - (d - x[i]) * (d - x[i])));\n }\n return res;\n };\n rep(i, 100) {\n double m1 = (left * 2 + right) / 3;\n double m2 = (left + right * 2) / 3;\n if (f(m1) < f(m2))left= m1;\n else right = m2;\n }\n printf(\"%.10f\\n\", f(left));\n}", "accuracy": 0.14285714285714285, "time_ms": 100, "memory_kb": 4352, "score_of_the_acc": -0.5899, "final_rank": 19 }, { "submission_id": "aoj_0323_10873516", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int n; cin >> n;\n double left = -inf, right = inf;\n vector<int> x(n), r(n);\n rep(i, n) {\n cin >> x[i] >> r[i];\n chmax(left, double(x[i] - r[i]));\n chmin(right, double(x[i] + r[i]));\n }\n auto f = [&](double d) {\n double res = inf;\n rep(i, n) {\n chmin(res, sqrt(r[i] * r[i] - (d - x[i]) * (d - x[i])));\n }\n return res;\n };\n rep(i, 100) {\n double m1 = (left * 2 + right) / 3;\n double m2 = (left + right * 2) / 3;\n if (f(m1) < f(m2))left= m1;\n else right = m2;\n }\n cout << f(left) << endl;\n}", "accuracy": 0.14285714285714285, "time_ms": 110, "memory_kb": 4480, "score_of_the_acc": -0.6775, "final_rank": 20 }, { "submission_id": "aoj_0323_10867731", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#define _USE_MATH_DEFINES\n#include <math.h>\n#include <cstring>\n#include <numeric>\n#include <algorithm>\n#include <stdlib.h>\n#include <functional>\n#include <string>\n#include <array>\n#include <map>\n#include <queue>\n#include <limits.h>\n#include <set>\n#include <stack>\n#include <random>\n#include <complex>\n#include <unordered_map>\n#include <nmmintrin.h>\n#include <chrono>\n#define rep(i,s,n) for(int i = (s); (n) > i; i++)\n#define REP(i,n) rep(i,0,n)\n#define RANGE(x,a,b) ((a) <= (x) && (x) <= (b))\n#define DUPLE(a,b,c,d) (RANGE(a,c,d) || RANGE(b,c,d) || RANGE(c,a,b) || RANGE(d,a,b))\n#define INCLU(a,b,c,d) (RANGE(a,c,d) && (b,c,d))\n#define PW(x) ((x)*(x))\n#define ALL(x) (x).begin(), (x).end()\n#define MODU 1000000007\n#define bitcheck(a,b) ((a >> b) & 1)\n#define bitset(a,b) ( a |= (1 << b))\n#define bitunset(a,b) (a &= ~(1 << b))\n#define MP(a,b) make_pair((a),(b))\n#define Manh(a,b) (abs((a).first-(b).first) + abs((a).second - ((b).second))\n#define pritnf printf\n#define scnaf scanf\n#define itn int\n#ifdef _MSC_VER\n#define __builtin_popcount _mm_popcnt_u32\n#define __builtin_popcountll _mm_popcnt_u64\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll gcd(ll a, ll b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a%b);\n}\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N], const T &val) {\n\tstd::fill((T*)array, (T*)(array + N), val);\n}\n\n\nstruct UnionFind{\n\tvector<int> data;\n\tint n, m;\n\n\tUnionFind(int ns, int ms) : n(ns), m(ms), data(ns + ms, INT_MIN){\n\t\tREP(i, m){\n\t\t\tdata[i + n] = -i-1;\n\t\t}\n\t}\n\n\tbool unite(int a, int b){//矛盾の判定\n\t\ta = root(a), b = root(b);\n\n\t\tif (a == b)\n\t\t\treturn true;\n\n\t\tif (data[a] != INT_MIN && data[b] != INT_MIN){\n\t\t\tif (data[a] != data[b]){\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (rand() % 2)\n\t\t\t\t\tdata[b] = a;\n\t\t\t\telse\n\t\t\t\t\tdata[a] = b;\n\t\t\t}\n\t\t}\n\t\telse if (data[a] != INT_MIN)\n\t\t\tdata[b] = a;\n\t\telse if (data[b] != INT_MIN)\n\t\t\tdata[a] = b;\n\t\telse{\n\t\t\tif (rand() % 2)\n\t\t\t\tdata[b] = a;\n\t\t\telse\n\t\t\t\tdata[a] = b;\n\t\t}\n\t\treturn true;\n\t}\n\n\n\tbool unitebu(int a, int b){//矛盾の判定 aをbの部活\n\t\ta = root(a);\n\t\tb += n;\n\n\t\tif (data[a] == data[b])\n\t\t\treturn true;\n\t\tif (data[a] != INT_MIN)\n\t\t\treturn false;\n\n\t\tdata[a] = b;\n\t\treturn true;\n\t}\n\n\tbool findset(int a, int b){\n\t\treturn root(a) == root(b);\n\t}\n\n\tint root(int x){\n\t\treturn data[x] < 0 ? x : data[x] = root(data[x]);\n\t}\n};\n\nsigned main() {\n\tint n;\n\tcin >> n;\n\tvector<pair<double,double>> za(n);\n\tvector<int> l, r;\n\tREP(i, n){\n\t\tscanf(\"%lf %lf\", &za[i].first, &za[i].second);\n\t\tl.push_back(za[i].first - za[i].second);\n\t\tr.push_back(za[i].first + za[i].second);\n\t}\n\n\tsort(ALL(l));\n\tsort(ALL(r));\n\n\tint rb = r[0], lb = l[l.size()-1];\n\n\n\tfunction<double(double)> func = [&](double pos){\n\t\tdouble ret = 10000000;\n\n\t\tREP(i, n){\n\t\t\tdouble rad = za[i].second, dis = abs(pos - za[i].first);\n\t\t\tret = min(ret, sqrt(rad*rad - dis*dis));\n\t\t}\n\n\t\treturn ret;\n\t};\n\n\tdouble x0 = lb, x3 = rb;\n\tREP(i, 50){\n\t\tif (x0 >= x3)\n\t\t\tbreak;\n\t\t\n\t\tdouble x1 = (x0+x0+x3)/3, x2 = (x0 + x3 + x3)/3;\n\n\t\tif (func(x1) < func(x2))\n\t\t\tx0 = x1;\n\t\telse\n\t\t\tx3 = x2;\n\n\t}\n\n\tprintf(\"%.6lf\\n\", func((x0 + x3) / 2));\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5764, "score_of_the_acc": -0.1694, "final_rank": 2 }, { "submission_id": "aoj_0323_10852437", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst ld EPS = 1e-10;\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N;\n cin>>N;\n vector<ld> X(N),R(N);\n rep(i,N)cin>>X[i]>>R[i];\n\n ld ok=0;\n ld ng=1e9;\n rep(i,N) chmin(ng, R[i]);\n while(ng-ok>EPS){\n ld m=(ok+ng)/2;\n\n ld l=-1e9;\n ld r=1e9;\n rep(i,N){\n ld z=sqrtl(R[i]*R[i]-m*m);\n chmax(l, X[i]-z);\n chmin(r, X[i]+z);\n }\n if(l<=r) ok=m;\n else ng=m;\n }\n cout<<fixed<<setprecision(15);\n cout<<ok<<\"\\n\";\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6784, "score_of_the_acc": -0.2546, "final_rank": 5 }, { "submission_id": "aoj_0323_10847768", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define ld long double\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define pb push_back\n#define all(A) A.begin(),A.end()\n\nint main(){\n int N;cin>>N;\n vector<ld>X(N),R(N);\n ld ng = 0;\n rep(i,N){\n cin>>X[i]>>R[i];\n ng = max(ng,R[i]);\n }\n ld ok = 0;ng+=1.0;\n while(ng-ok>=0.0001){\n ld m = (ok+ng)/2.0;\n ld l = -1000000,r=2000000;\n rep(i,N){\n if(R[i]<m){\n r = l-1000;\n break;\n }\n ld d = sqrt(R[i]*R[i]-m*m);\n l = max(l,X[i]-d);\n r = min(r,X[i]+d);\n }\n if(l<=r)ok = m;\n else ng = m;\n } \n cout<<fixed<<setprecision(10)<<ok<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6252, "score_of_the_acc": -0.4409, "final_rank": 8 }, { "submission_id": "aoj_0323_9633949", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconstexpr int N = 1e5 + 5;\n\ndouble x[N], r[N];\n\nint main() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n\n int n;\n cin >> n;\n\n for (int i = 0; i < n; ++i)\n cin >> x[i] >> r[i];\n\n double lb = 0, rb = 1e6;\n\n while (lb + 1e-9 < rb) {\n double mid = (lb + rb) / 2;\n double pl = -1e9, pr = 1e9;\n\n for (int i = 0; i < n; ++i) {\n if (r[i] < mid) {\n pl = 1e9, pr = -1e9;\n break;\n }\n\n pl = max(pl, x[i] - sqrt(r[i] * r[i] - mid * mid));\n pr = min(pr, x[i] + sqrt(r[i] * r[i] - mid * mid));\n }\n\n if (pl <= pr)\n lb = mid;\n else\n rb = mid;\n } \n\n cout << fixed << setprecision(9) << (lb + rb) / 2;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5072, "score_of_the_acc": -0.1885, "final_rank": 3 }, { "submission_id": "aoj_0323_9619887", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<pair<long double,long double>> a(n);\n pair<long double,long double> r(-1e9,1e9);\n for(int i = 0;i < n;i++){\n cin >> a[i].first >> a[i].second;\n r.first = max(r.first,a[i].first - a[i].second);\n r.second = min(r.second,a[i].first + a[i].second);\n }\n if(r.second < r.first){\n cout << 0 << endl;\n exit(0);\n }\n auto cal = [](pair<long double,long double> a,long double x) -> long double {\n long double it = abs(a.first - x);\n it = sqrt(a.second * a.second - it * it);\n return it;\n };\n auto f = [&](long double x) -> long double {\n long double res = 1e9;\n for(int i = 0;i < n;i++){\n res = min(res,cal(a[i],x));\n }\n return res;\n };\n while(abs(r.second - r.first) >= 0.00001){\n long double ml = (r.first * 2.0 + r.second) / 3.0,mr = (r.first + r.second * 2.0) / 3.0;\n if(f(ml) < f(mr)){\n r.first = ml;\n }else{\n r.second = mr;\n }\n }\n long double ans = f(r.first);\n cout << fixed << setprecision(5) << ans << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 6188, "score_of_the_acc": -0.6663, "final_rank": 11 }, { "submission_id": "aoj_0323_9058880", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ld = long double;\n\nint main() {\n int N;\n cin >> N;\n vector<ld> x(N), r(N), cand;\n for(int i = 0; i < N; i++) {\n cin >> x[i] >> r[i];\n cand.push_back(x[i]-r[i]);\n cand.push_back(x[i]+r[i]);\n }\n auto f = [&](ld p) -> ld {\n ld ymin = INFINITY;\n for(int i = 0; i < N; i++) {\n ymin = min(ymin, sqrt(r[i]*r[i]-(x[i]-p)*(x[i]-p)));\n }\n return ymin;\n };\n sort(cand.begin(), cand.end());\n ld L = cand[N-1], R = cand[N];\n for(int _t = 0; _t < 100; _t++) {\n ld ml = L+(R-L)/3.0;\n ld mr = R-(R-L)/3.0;\n if(f(ml) > f(mr)) R = mr;\n else L = ml;\n }\n cout << fixed << setprecision(6) << f(L) << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 12148, "score_of_the_acc": -1.3949, "final_rank": 12 }, { "submission_id": "aoj_0323_9058874", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ld = long double;\n\nint main() {\n int N;\n cin >> N;\n vector<ld> x(N), r(N), cand;\n for(int i = 0; i < N; i++) {\n cin >> x[i] >> r[i];\n cand.push_back(x[i]-r[i]);\n cand.push_back(x[i]+r[i]);\n }\n auto f = [&](ld p) -> pair<bool, ld> {\n int cnt = 0;\n ld ymin = INFINITY;\n for(int i = 0; i < N; i++) {\n if(x[i]-r[i] <= p && p <= x[i]+r[i]) {\n cnt++;\n ymin = min(ymin, sqrt(r[i]*r[i]-(x[i]-p)*(x[i]-p)));\n }else {\n return make_pair(false, 0);\n }\n }\n return make_pair(true, ymin);\n };\n sort(cand.begin(), cand.end());\n ld L = cand[N-1], R = cand[N];\n for(int _t = 0; _t < 100; _t++) {\n ld ml = L+(R-L)/3.0;\n ld mr = R-(R-L)/3.0;\n if(f(ml).second > f(mr).second) R = mr;\n else L = ml;\n }\n cout << fixed << setprecision(6) << f(L).second << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 12276, "score_of_the_acc": -1.5595, "final_rank": 14 }, { "submission_id": "aoj_0323_9058869", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ld = long double;\n\nint main() {\n int N;\n cin >> N;\n vector<ld> x(N), r(N), cand;\n for(int i = 0; i < N; i++) {\n cin >> x[i] >> r[i];\n cand.push_back(x[i]-r[i]);\n cand.push_back(x[i]+r[i]);\n }\n auto f = [&](ld p) -> pair<bool, ld> {\n int cnt = 0;\n ld ymin = INFINITY;\n for(int i = 0; i < N; i++) {\n if(x[i]-r[i] <= p && p <= x[i]+r[i]) {\n cnt++;\n ymin = min(ymin, sqrt(r[i]*r[i]-(x[i]-p)*(x[i]-p)));\n }else {\n return make_pair(false, 0);\n }\n }\n return make_pair(true, ymin);\n };\n ld L, R;\n sort(cand.begin(), cand.end());\n { // 左端を見つける\n int ok = 0, ng = N;\n while(ok+1 < ng) {\n int k = (ok+ng)/2;\n if(f(cand[N-k-1]).first) ok = k;\n else ng = k;\n }\n L = cand[N-ok-1];\n }\n { // 右端を見つける\n int ok = 0, ng = N;\n while(ok+1 < ng) {\n int k = (ok+ng)/2;\n if(f(cand[N+k]).first) ok = k;\n else ng = k;\n }\n R = cand[N+ok];\n }\n for(int _t = 0; _t < 100; _t++) {\n ld ml = L+(R-L)/3.0;\n ld mr = R-(R-L)/3.0;\n if(f(ml).second > f(mr).second) R = mr;\n else L = ml;\n }\n cout << fixed << setprecision(6) << f(L).second << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 12020, "score_of_the_acc": -1.5381, "final_rank": 13 }, { "submission_id": "aoj_0323_8072442", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n\n\nint n;\ndouble x[1<<17],r[1<<17];\n\ndouble calc(double now){\n double ans = 1e9;\n for(int i = 0;i<n;i++){\n double dx = x[i] - now;\n dx *= dx;\n double dy = sqrt(r[i]*r[i]-dx);\n ans = min(ans,dy);\n }\n return ans;\n}\n\nint main(){\n cin>>n;\n for(int i = 0;i<n;i++) cin>>x[i]>>r[i];\n double right = 1e9;\n double left = -1e9;\n for(int i = 0;i<n;i++){\n left = max(left,x[i]-r[i]);\n right = min(right,x[i]+r[i]);\n }\n int q = 100;\n double ans = 0;\n //cout<<left<<\" \"<<right<<endl;\n while(q--){\n double m1 = (right+right+left) / 3.;\n double m2 = (right+left+left) / 3.;\n double c1 = calc(m1);\n double c2 = calc(m2);\n ans = max(ans,c1);\n ans = max(ans,c2);\n if(c1>c2) left = m2;\n else right = m1;\n }\n cout<<fixed<<setprecision(20)<<ans<<endl;\n\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 5136, "score_of_the_acc": -0.4246, "final_rank": 7 }, { "submission_id": "aoj_0323_6965466", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0323.cc: Ruins\n */\n\n#include<cstdio>\n#include<cmath>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int CNT = 100;\nconst double DINF = 1e60;\n\n/* typedef */\n\n/* global variables */\n\nint xs[MAX_N], rs[MAX_N];\n\n/* subroutines */\n\nbool check(int n, double y) {\n double minx = -DINF, maxx = DINF;\n for (int i = 0; i < n; i++) {\n double dx = sqrt((double)rs[i] * rs[i] - y * y);\n minx = max(minx, xs[i] - dx);\n maxx = min(maxx, xs[i] + dx);\n }\n return (minx <= maxx);\n}\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d%d\", xs + i, rs + i);\n\n int minr = *min_element(rs, rs + n);\n\n double y0 = 0.0, y1 = minr;\n for (int cnt = 0; cnt < CNT; cnt++) {\n double y = (y0 + y1) / 2;\n if (check(n, y)) y0 = y;\n else y1 = y;\n }\n\n printf(\"%.6lf\\n\", y0);\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3736, "score_of_the_acc": -0.1538, "final_rank": 1 }, { "submission_id": "aoj_0323_6217782", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <iomanip>\nusing namespace std;\nconst long double EPS = 1e-7;\nint main(){\n int n;cin>>n;\n vector<pair<long double,long double>> A(n);\n long double mx = 0;\n long double wmn = 1000000;\n long double wmx = 0;\n for(int i = 0; n > i; i++){\n cin>>A[i].first>>A[i].second;\n mx = max(A[i].second,mx);\n wmn = min(A[i].first,wmn);\n wmx = max(A[i].first,wmx);\n }\n long double mn = 0;\n mx+=1;\n while(mx-mn > 1e-6){\n long double ce = (mx+mn)/2;\n long double le = wmn;\n long double ri = wmx;\n for(int i = 0; n > i; i++){\n //A[i]がce以上を満たす範囲を求める\n if(A[i].second<ce){\n le = wmx+1;\n break;\n }\n long double dist = sqrt(A[i].second*A[i].second-ce*ce);\n le = max(le,A[i].first-dist);\n ri = min(ri,A[i].first+dist);\n }\n if(le<=ri){\n mn = ce;\n }else{\n mx = ce;\n }\n }\n cout << fixed << setprecision(10) << mn << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6252, "score_of_the_acc": -0.4409, "final_rank": 8 }, { "submission_id": "aoj_0323_6217779", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <iomanip>\nusing namespace std;\nconst long double EPS = 1e-7;\nint main(){\n int n;cin>>n;\n vector<pair<long double,long double>> A(n);\n long double mx = 0;\n long double wmn = 1000000;\n long double wmx = 0;\n for(int i = 0; n > i; i++){\n cin>>A[i].first>>A[i].second;\n mx = max(A[i].second,mx);\n wmn = min(A[i].first,wmn);\n wmx = max(A[i].first,wmx);\n }\n long double mn = 0;\n mx+=1;\n while(mx-mn > 1e-6){\n long double ce = (mx+mn)/2;\n long double le = wmn;\n long double ri = wmx;\n for(int i = 0; n > i; i++){\n //A[i]がce以上を満たす範囲を求める\n if(A[i].second<ce){\n le = wmx+1;\n break;\n }\n long double dist = sqrt(A[i].second*A[i].second-ce*ce);\n le = max(le,A[i].first-dist);\n ri = min(ri,A[i].first+dist);\n }\n if(le<ri+EPS){\n mn = ce;\n }else{\n mx = ce;\n }\n }\n cout << fixed << setprecision(10) << mn << endl;\n}", "accuracy": 0.5714285714285714, "time_ms": 70, "memory_kb": 6196, "score_of_the_acc": -0.5132, "final_rank": 17 }, { "submission_id": "aoj_0323_6217777", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <iomanip>\nusing namespace std;\nconst double EPS = 1e-7;\nint main(){\n int n;cin>>n;\n vector<pair<double,double>> A(n);\n double mx = 0;\n double wmn = 1000000;\n double wmx = 0;\n for(int i = 0; n > i; i++){\n cin>>A[i].first>>A[i].second;\n mx = max(A[i].second,mx);\n wmn = min(A[i].first,wmn);\n wmx = max(A[i].first,wmx);\n }\n double mn = 0;\n mx+=1;\n while(mx-mn > 1e-6){\n double ce = (mx+mn)/2;\n double le = wmn;\n double ri = wmx;\n for(int i = 0; n > i; i++){\n //A[i]がce以上を満たす範囲を求める\n if(A[i].second<ce){\n le = wmx+1;\n break;\n }\n double dist = sqrt(A[i].second*A[i].second-ce*ce);\n le = max(le,A[i].first-dist);\n ri = min(ri,A[i].first+dist);\n }\n if(le<ri+EPS){\n mn = ce;\n }else{\n mx = ce;\n }\n }\n cout << fixed << setprecision(10) << mn << endl;\n}", "accuracy": 0.5714285714285714, "time_ms": 60, "memory_kb": 4556, "score_of_the_acc": -0.2993, "final_rank": 16 }, { "submission_id": "aoj_0323_5943624", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst double INF = 10000000;\nint main(){\n cout << fixed << setprecision(20);\n int N;\n cin >> N;\n vector<double> x(N), r(N);\n for (int i = 0; i < N; i++){\n cin >> x[i] >> r[i];\n }\n double mn = INF;\n for (int i = 0; i < N; i++){\n mn = min(mn, r[i]);\n }\n double tv = 0, fv = mn;\n for (int i = 0; i < 50; i++){\n double mid = (tv + fv) / 2;\n double L = -INF, R = INF;\n for (int j = 0; j < N; j++){\n double d = sqrt(r[j] * r[j] - mid * mid);\n L = max(L, x[j] - d);\n R = min(R, x[j] + d);\n }\n if (L <= R){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n cout << tv << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4648, "score_of_the_acc": -0.3839, "final_rank": 6 }, { "submission_id": "aoj_0323_5804561", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1e9;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, long long N) {\n for (long long i = 0; i < N; i++) {\n cin >> A[i];\n }\n}\nlong long N;\nvector<double>X(200000), R(200000);\ndouble f(double x) {\n double ans = 1e13;\n for (long long i = 0; i < N; i++) {\n double d = abs(x - X[i]);\n ans = min(ans, sqrt(R[i] * R[i] - d * d));\n }\n return ans;\n}\ndouble sanbuntansaku(double L, double R) {\n double left = L, right = R;\n for (long long i = 0; i <= 100; i++) {\n if (f((left + right * 2)/3) >= f((left*2+right)/3)) {\n left = (left*2 + right) / 3;\n }\n else right = (left+ right*2) / 3;\n }\n return (left + right) * 0.5;\n}\nint main() {\n cin >> N;\n double l = -1e13, r = 1e13;\n for (long long i = 0; i < N; i++) {\n cin >> X[i] >> R[i];\n l=max(l, X[i]-R[i]);\n r=min(r, X[i]+R[i]);\n }\n cout << fixed << setprecision(6) << f(sanbuntansaku(l, r)) << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 6164, "score_of_the_acc": -0.5105, "final_rank": 10 }, { "submission_id": "aoj_0323_5804555", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1e9;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, long long N) {\n for (long long i = 0; i < N; i++) {\n cin >> A[i];\n }\n}\nlong long N;\nvector<double>X(200000), R(200000);\ndouble f(double x) {\n double ans = 1e13;\n for (long long i = 0; i < N; i++) {\n double d = abs(x - X[i]);\n ans = min(ans, sqrt(R[i] * R[i] - d * d));\n }\n return ans;\n}\ndouble sanbuntansaku(double L, double R) {\n double left = L, right = R;\n for (long long i = 0; i <= 100; i++) {\n if (f((left + right * 2)/3) >= f((left*2+right)/3)) {\n left = (left*2 + right) / 3;\n }\n else right = (left+ right*2) / 3;\n }\n return (left + right) * 0.5;\n}\nint main() {\n cin >> N;\n double l = -1e13, r = 1e13;\n for (long long i = 0; i < N; i++) {\n cin >> X[i] >> R[i];\n l=max(l, X[i]-R[i]);\n r=min(r, X[i]+R[i]);\n }\n cout << f(sanbuntansaku(l, r)) << endl;\n}", "accuracy": 0.14285714285714285, "time_ms": 70, "memory_kb": 6072, "score_of_the_acc": -0.5028, "final_rank": 18 }, { "submission_id": "aoj_0323_5781093", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing pint = pair<int,int>;\n\ndouble ternary(double low, double high, function<double(double)> f, int itr = 128) {\n\t\n\tfor(int i = 0; i < itr; i++) {\n\t\tdouble c1 = (low * 2 + high) / 3;\n\t\tdouble c2 = (low + high * 2) / 3;\n\t\tdouble v1 = f(c1), v2 = f(c2);\n\t\t(v1 > v2 ? low : high) = (v1 > v2 ? c1 : c2);\n\t}\n\treturn low;\n}\n\n\nint main()\n{\n\tint N; cin >> N;\n\tvector<int> x(N), r(N);\n\tconst int GETA = 1000000;\n\tfor(int i = 0; i < N; i++) cin >> x[i] >> r[i], x[i] += GETA;\n\t\n\tvector<int> imos(GETA * 3 + 1);\n\tfor(int i = 0; i < N; i++) {\n\t\tint L = x[i] - r[i];\n\t\tint R = x[i] + r[i];\n\t\timos[L]++;\n\t\timos[R + 1]--;\n\t}\n\n\tint M = imos.size();\n\tfor(int i = 1; i < M; i++)imos[i] += imos[i - 1];\n\tint L = M, R = -1;\n\tfor(int i = 0; i < M; i++) {\n\t\tif(imos[i] != N)continue;\n\t\tL = min(i, L);\n\t\tR = max(i, R);\n\t}\n\n\tauto f = [&](double p) {\n\t\t\n\t\tdouble ans = 1e9;\n\t\tfor(int i = 0; i < N; i++) {\n\t\t\tdouble dist = (double)r[i] * r[i] - (double)(p - x[i]) * (p - x[i]);\n\t\t\tdist = sqrt(dist);\n\t\t\tans = min(ans, dist);\n\t\t}\n\t\treturn -ans;\n\t};\n\t\n\tauto argmin = ternary(L, R, f);\n\tcout << fixed <<setprecision(12); \n\tcout << -f(argmin) << endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 15708, "score_of_the_acc": -2, "final_rank": 15 } ]
aoj_0324_cpp
Downhill Race You are participating in a ski competition held at Mt. Bandai. In this competition, each skier will ski down the slope twice and compete for the shortest total time. There are a number of flags on the slope, and a line is set up between them for the competitors to follow. Competitors follow the lines from the start point to the finish point. The lines are set up as follows. One or more lines extend from a flag except at the finish point. There is only one line at most that directly connects one flag to another. The line can only be slid down in a certain direction. You can always reach any flag from the start, and you can reach the goal from any flag. No matter how you follow the line, you will never return to the same flag. The athlete can decide which flag to go to next by choosing a line that extends from the flag they are currently on. The choice of line is free, so players can follow a different line to the finish point for each descent. The night before the competition, Mr. Salt, the sports doctor, predicted the condition of the slope when you skied. According to him, the line you took on the first descent will change the snow quality due to the passage, so if you take the same line on the second descent, the time it will take may change. Salt told you how long it takes to go through each line the first time and how long it takes to go through it the second time. You must use this information to find a way to ski the line that minimizes the total time of the two descents. Given the conditions of the slope, write a program that calculates the shortest total time for the two descents. Input The input is given in the following format. N P s 1 e 1 t 1,1 t 1,2 s 2 e 2 t 2,1 t 2,2 : s P e P t P,1 t P,2 On the first line, the number of flags N (2 ≤ N ≤ 1000) and the number of lines connecting the two flags P ( 1 ≤ P ≤ 2000) are given. The flags are numbered from 1 to N , the starting point flag number is 1 and the goal point flag number is N . The following P lines give information about the line connecting the two flags. Each line has the source flag number s i (1 ≤ s i < N ), the destination flag number e i (1 < e i ≤ N ) , time required for the first pass t i, 1 (1 ≤ t i, 1 ≤ 100000), the time required to pass the same line at the second time t i, 2 (1 ≤ t i, 2 ≤ 100000). Output Output the shortest value in the total time of two downhills in one line. Sample Input 1 3 3 1 2 1 2 2 3 1 2 1 3 1 3 Sample Output 1 3 Sample Input 2 3 3 1 2 1 2 2 3 1 2 1 3 1 1 Sample Output 2 2 Sample Input 3 4 5 1 2 3 5 1 3 1 3 3 2 2 5 2 4 6 1 3 4 5 5 Sample Output 3 13
[ { "submission_id": "aoj_0324_10852452", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nusing A3=array<int,3>;\n\nvector<int> topological_sort(vector<vector<A3>> &G, vector<int> &indegree, int V) {\n vector<int> sorted_vertices;\n\n queue<int> que;\n for (int i = 0; i < V; i++) {\n if (indegree[i] == 0) {\n que.push(i);\n }\n }\n\n while (que.empty() == false) {\n int v = que.front();\n que.pop();\n\n for (int i = 0; i < G[v].size(); i++) {\n int u = G[v][i][0];\n indegree[u] -= 1;\n if (indegree[u] == 0) que.push(u);\n }\n sorted_vertices.push_back(v);\n }\n\n return sorted_vertices;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,P;\n cin>>N>>P;\n vector<vector<A3>> G(N);\n vector<int> ind(N,0);\n rep(i,P){\n int s,e,t1,t2;\n cin>>s>>e>>t1>>t2;\n s--;e--;\n G[s].push_back({e,t1,t2});\n ind[e]++;\n }\n\n vector<int> tp=topological_sort(G,ind,N);\n\n vector<int> O(N);\n rep(i,N) O[tp[i]]=i;\n\n vector dp(N,vector<int>(N,2e9));\n dp[0][0]=0;\n\n priority_queue<A3,vector<A3>,greater<A3>> pq;\n pq.push({0, 0, 0});\n\n while(!pq.empty()){\n auto [k,u,v]=pq.top();\n pq.pop();\n if(dp[u][v]<k) continue;\n assert(O[u]<=O[v]);\n if(u==v){\n for(A3 e: G[u]){\n for(A3 f: G[v]){\n if(O[e[0]]>O[f[0]]) continue;\n if(chmin(dp[e[0]][f[0]], dp[u][v]+e[1]+f[1+(e[0]==f[0])])){\n pq.push({dp[e[0]][f[0]], e[0], f[0]});\n }\n }\n }\n }\n else{\n for(A3 e: G[u]){\n int t1=e[0];\n int t2=v;\n if(O[t1]>O[t2]) swap(t1, t2);\n if(chmin(dp[t1][t2], dp[u][v]+e[1])){\n pq.push({dp[t1][t2], t1, t2});\n }\n }\n }\n }\n cout<<dp[N-1][N-1]<<\"\\n\";\n \n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15292, "score_of_the_acc": -0.3311, "final_rank": 5 }, { "submission_id": "aoj_0324_10848071", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconstexpr ll inf = 1e18;\n\nstruct edge {\n int to;\n ll c1, c2;\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\nint main() {\n int n, p;\n cin >> n >> p;\n graph g(n);\n for(int i = 0; i < p; ++i) {\n int s, e;\n ll t1, t2;\n cin >> s >> e >> t1 >> t2;\n g[s - 1].push_back(edge{e - 1, t1, t2});\n }\n\n vector<int> topo(n, -1);\n int idx = 0;\n function<void(int)> calc_topo = [&] (int v) {\n if(topo[v] != -1) return;\n for(auto& e : g[v]) {\n calc_topo(e.to);\n }\n topo[v] = idx++;\n };\n calc_topo(0);\n\n vector<vector<ll>> dist(n, vector<ll>(n, inf));\n dist[0][0] = 0;\n using state = tuple<ll, int, int>;\n priority_queue<state, vector<state>, greater<state>> que;\n que.emplace(0, 0, 0);\n while(!que.empty()) {\n ll cur_c;\n int fst_v, sec_v;\n tie(cur_c, fst_v, sec_v) = que.top();\n que.pop();\n if(fst_v == sec_v) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c1 + e.c2;\n if(dist[e.to][e.to] > nxt_c) {\n dist[e.to][e.to] = nxt_c;\n que.emplace(nxt_c, e.to, e.to);\n }\n }\n\n for(auto& e1 : g[fst_v]) {\n for(auto& e2 : g[sec_v]) {\n if(e1.to == e2.to) continue;\n ll nxt_c = cur_c + e1.c1 + e2.c1;\n if(dist[e1.to][e2.to] > nxt_c) {\n dist[e1.to][e2.to] = nxt_c;\n que.emplace(nxt_c, e1.to, e2.to);\n }\n }\n }\n } else {\n if(topo[fst_v] > topo[sec_v]) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c1;\n if(dist[e.to][sec_v] > nxt_c) {\n dist[e.to][sec_v] = nxt_c;\n que.emplace(nxt_c, e.to, sec_v);\n }\n }\n } else {\n for(auto& e : g[sec_v]) {\n ll nxt_c = cur_c + e.c1;\n if(dist[fst_v][e.to] > nxt_c) {\n dist[fst_v][e.to] = nxt_c;\n que.emplace(nxt_c, fst_v, e.to);\n }\n }\n }\n }\n }\n\n cout << dist[n - 1][n - 1] << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 29284, "score_of_the_acc": -0.8136, "final_rank": 11 }, { "submission_id": "aoj_0324_9600813", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n,m;\n\tcin >> n >> m;\n\tvector<vector<pair<int,pair<int,int>>>> g(n,vector<pair<int,pair<int,int>>>());\n\tvector<int> o(n,-1);\n\t{\n\t\tvector<int> cou(n,0);\n\t\tfor(int i = 0;i < m;i++){\n\t\t\tint u,v,a,b;\n\t\t\tcin >> u >> v >> a >> b;\n\t\t\tu--;v--;\n\t\t\tg[u].push_back({v,{a,b}});\n\t\t\tcou[v]++;\n\t\t}\n\t\tint now = 0;\n\t\tqueue<int> q;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\to[it] = now++;\n\t\t\tif(!g[it].empty()){\n\t\t\t\tfor(pair<int,pair<int,int>> i : g[it]){\n\t\t\t\t\tif(--cou[i.first] == 0){\n\t\t\t\t\t\tq.push(i.first);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<vector<int>> d(n,vector<int>(n,false));\n\t{\n\t\tfor(int i = 0;i < n;i++){\n\t\t\td[i][i] = true;\n\t\t\tqueue<int> q;\n\t\t\tq.push(i);\n\t\t\twhile(!q.empty()){\n\t\t\t\tint it = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tif(!g[it].empty()){\n\t\t\t\t\tfor(pair<int,pair<int,int>> j : g[it]){\n\t\t\t\t\t\tif(d[i][j.first]) continue;\n\t\t\t\t\t\td[i][j.first] = true;\n\t\t\t\t\t\tq.push(j.first);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<int> p(n);\n\tiota(p.begin(),p.end(),0);\n\tsort(p.begin(),p.end(),[&](int a,int b){return o[a] < o[b];});\n\tvector<vector<int>> ans(n,vector<int>(n,1e9));\n\tans[0][0] = 0;\n\tfor(int i = 0;i < n;i++){\n\t\tfor(int j = i;j < n;j++){\n\t\t\tint u = p[i],v = p[j];\n\t\t\tfor(pair<int,pair<int,int>> k : g[u]){\n\t\t\t\tif(o[k.first] > o[v]){\n\t\t\t\t\tans[v][k.first] = min(ans[v][k.first],ans[u][v] + k.second.first);\n\t\t\t\t}\n\t\t\t\tfor(pair<int,pair<int,int>> l : g[v]){\n\t\t\t\t\tif(o[l.first] > o[u]){\n\t\t\t\t\t\tans[u][l.first] = min(ans[u][l.first],ans[u][v] + l.second.first);\n\t\t\t\t\t}\n\t\t\t\t\tif(o[k.first] > o[v] && o[l.first] > o[u]){\n\t\t\t\t\t\tif(u == v && k.first == l.first){\n\t\t\t\t\t\t\tans[k.first][l.first] = min(ans[k.first][l.first],ans[u][v] + k.second.first + l.second.second);\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tif(o[k.first] < o[l.first]){\n\t\t\t\t\t\t\t\tans[k.first][l.first] = min(ans[k.first][l.first],ans[u][v] + k.second.first + l.second.first);\n\t\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\t\tans[l.first][k.first] = min(ans[l.first][k.first],ans[u][v] + k.second.first + l.second.first);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans[n - 1][n - 1] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11428, "score_of_the_acc": -0.0967, "final_rank": 3 }, { "submission_id": "aoj_0324_8072547", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n,p;\n cin>>n>>p;\n vector<vector<int>> g(n);\n vector<int> u(p),v(p),a(p),b(p);\n vector<int> cnt(n,0);\n vector<int> cmp(n,-1);\n for(int i = 0;i<p;i++){\n cin>>u[i]>>v[i]>>a[i]>>b[i];\n u[i]--;v[i]--;\n g[u[i]].push_back(v[i]);\n cnt[v[i]]++;\n }\n vector<vector<ll>> vis(n,vector<ll>(n,1e15));\n vector<vector<ll>> use(n,vector<ll>(n,0));\n deque<int> q;\n int now = 0;\n for(int i = 0;i<n;i++){\n if(cnt[i] == 0) q.push_back(i);\n }\n while(q.size()){\n int ni = q.front();\n q.pop_front();\n cmp[ni] = now++;\n for(auto&to:g[ni]) {\n cnt[to]--;\n if(cnt[to]==0) q.push_back(to);\n }\n }\n using dat = pair<ll,pair<int,int>>;\n vector<vector<pair<int,pair<ll,ll>>>> gg(n);\n for(int i = 0;i<p;i++){\n gg[u[i]].push_back(make_pair(v[i],make_pair(a[i],b[i])));\n }\n\n priority_queue<dat,vector<dat>,greater<dat>> que;\n que.push(make_pair(0,make_pair(0,0)));\n vis[0][0] = 0;\n while(que.size()){\n auto now = que.top();\n que.pop();\n int ni = now.second.first;\n int nj = now.second.second;\n //cout<<ni<<\" \"<<nj<<\" \"<<vis[ni][nj]<<endl;\n if(use[ni][nj]++) continue;\n if(ni==nj){\n for(int i = 0;i<gg[ni].size();i++){\n for(int j = i;j<gg[ni].size();j++){\n if(i==j){\n int to = gg[ni][i].first;\n ll nxt = vis[ni][nj] + gg[ni][i].second.first + gg[ni][i].second.second;\n if(vis[to][to]<=nxt) continue;\n vis[to][to] = nxt;\n que.push(make_pair(nxt,make_pair(to,to)));\n continue;\n }else{\n int t1 = gg[ni][i].first;\n int t2 = gg[ni][j].first;\n if(cmp[t1]>cmp[t2]) swap(t1,t2);\n ll nxt = vis[ni][nj] + gg[ni][i].second.first + gg[ni][j].second.first;\n if(vis[t1][t2]<=nxt) continue;\n vis[t1][t2] = nxt;\n que.push(make_pair(nxt,make_pair(t1,t2)));\n }\n }\n }\n }else{\n for(int i = 0;i<gg[ni].size();i++){\n int t1 = gg[ni][i].first;\n int t2 = nj;\n if(cmp[t1]>cmp[t2]) swap(t1,t2);\n ll nxt = vis[ni][nj] + gg[ni][i].second.first;\n if(vis[t1][t2]<=nxt) continue;\n vis[t1][t2] = nxt;\n que.push(make_pair(nxt,make_pair(t1,t2)));\n }\n }\n }\n cout<<vis[n-1][n-1]<<endl;\n\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 27268, "score_of_the_acc": -0.5391, "final_rank": 7 }, { "submission_id": "aoj_0324_7848266", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ntemplate<class t>\nusing priority_queuer = priority_queue<t,vector<t>,greater<t>>;\n\nint func(){\n int n;\n int p;\n cin >> n >> p;\n vector<int> waits(n,0);\n using T = tuple<int,int,int>;\n vector<vector<T>> edges(n);\n for(int i=0;i<p;++i){\n int s;\n int t;\n int t1;\n int t2;\n cin >> s >> t >> t1 >> t2;\n --s;\n --t;\n ++waits[t];\n edges[s].emplace_back(t,t1,t2);\n }\n vector<int> ranks(n,0);\n {\n queue<int> que;\n que.push(0);\n while(que.size()){\n int p = que.front();\n que.pop();\n for(auto e:edges[p]){\n ranks[get<0>(e)] = max(ranks[get<0>(e)], ranks[p] + 1);\n if(--waits[get<0>(e)] == 0){\n que.push(get<0>(e));\n }\n }\n }\n }\n vector<vector<int>> dp(n,vector<int>(n,1e9));\n priority_queuer<T> pq;\n pq.emplace(0,0,0);\n while(pq.size()){\n T tmp = pq.top();\n pq.pop();\n int cost = get<0>(tmp);\n int p1 = get<1>(tmp);\n int p2 = get<2>(tmp);\n if(p1 == p2){\n for(auto e1:edges[p1]){\n for(auto e2:edges[p1]){\n if(e1 == e2){\n int ncost = cost + get<1>(e1) + get<2>(e1);\n int np1 = get<0>(e1);\n int np2 = get<0>(e1);\n if(dp[np1][np2] > ncost){\n dp[np1][np2] = ncost;\n pq.emplace(ncost,np1,np2);\n }\n }else{\n int ncost = cost + get<1>(e1) + get<1>(e2);\n int np1 = get<0>(e1);\n int np2 = get<0>(e2);\n if(dp[np1][np2] > ncost){\n dp[np1][np2] = ncost;\n pq.emplace(ncost,np1,np2);\n }\n }\n }\n }\n }else{\n if(ranks[p1] > ranks[p2])swap(p1,p2);\n for(auto e:edges[p1]){\n int np1 = get<0>(e);\n int ncost = cost + get<1>(e);\n if(dp[np1][p2] > ncost){\n dp[np1][p2] = ncost;\n pq.emplace(ncost,np1,p2);\n }\n }\n }\n }\n return dp[n-1][n-1];\n}\n\n\nint main(){\n cout << func() << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 20116, "score_of_the_acc": -0.6397, "final_rank": 8 }, { "submission_id": "aoj_0324_7529891", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\nusing ll = long long;\nusing state = tuple<ll, int, int>;\n\nstruct Edge {\n\tint to;\n\tll c0;\n\tll c1;\n};\n\n\nint idx = 0;\n\nvoid calc_topo(const vector<vector<Edge>>& graph, vector<int>& topo, int v) {\n\tif (topo[v] != -1) {\n\t\treturn;\n\t}\n\tfor (const auto& e : graph[v]) {\n\t\tcalc_topo(graph, topo, e.to);\n\t}\n\ttopo[v] = idx++;\n\treturn;\n};\n\nll dijkstra(int n, const vector<vector<Edge>>& graph, const vector<int>& topo) {\n\tvector<vector<ll>> cost_from_s(n, vector<ll>(n, numeric_limits<ll>::max()));\n\tpriority_queue<state, vector<state>, greater<state>> que;\n\n\tcost_from_s[0][0] = 0;\n\tque.emplace(0, 0, 0);\n\twhile (!que.empty()) {\n\t\tll c_cost = -1;\n\t\tint fv = -1;\n\t\tint sv = -1;\n\n\t\ttie(c_cost, fv, sv) = que.top();\n\t\tque.pop();\n\t\tif (fv == sv) {\n\t\t\tfor (auto& e : graph[fv]) {\n\t\t\t\tll n_cost = c_cost + e.c0 + e.c1;\n\n\t\t\t\tif (cost_from_s[e.to][e.to] > n_cost) {\n\t\t\t\t\tcost_from_s[e.to][e.to] = n_cost;\n\t\t\t\t\tque.emplace(n_cost, e.to, e.to);\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tfor (auto& e0 : graph[fv]) {\n\t\t\t\tfor (auto& e1 : graph[sv]) {\n\t\t\t\t\tif (e0.to == e1.to) {\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\n\t\t\t\t\tll n_cost = c_cost + e0.c0 + e1.c0;\n\t\t\t\t\tif (cost_from_s[e0.to][e1.to] > n_cost) {\n\t\t\t\t\t\tcost_from_s[e0.to][e1.to] = n_cost;\n\t\t\t\t\t\tque.emplace(n_cost, e0.to, e1.to);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (topo[fv] > topo[sv]) {\n\t\t\t\tfor (auto& e : graph[fv]) {\n\t\t\t\t\tll n_cost = c_cost + e.c0;\n\t\t\t\t\tif (cost_from_s[e.to][sv] > n_cost) {\n\t\t\t\t\t\tcost_from_s[e.to][sv] = n_cost;\n\t\t\t\t\t\tque.emplace(n_cost, e.to, sv);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (auto& e : graph[sv]) {\n\t\t\t\t\tll n_cost = c_cost + e.c0;\n\t\t\t\t\tif (cost_from_s[fv][e.to] > n_cost) {\n\t\t\t\t\t\tcost_from_s[fv][e.to] = n_cost;\n\t\t\t\t\t\tque.emplace(n_cost, fv, e.to);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn cost_from_s[n - 1][n - 1];\n}\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint n = -1;\n\tint p = -1;\n\n\tcin >> n >> p;\n\n\tvector<vector<Edge>> graph(n);\n\tfor (int i = 0; i < p; ++i) {\n\t\tint s = -1;\n\t\tint e = -1;\n\t\tll t0 = -1;\n\t\tll t1 = -1;\n\n\t\tcin >> s >> e >> t0 >> t1;\n\t\tgraph[s - 1].push_back(Edge{ e - 1, t0, t1 });\n\t}\n\n\tvector<int> topo(n, -1);\n\n\tidx = 0;\n\tcalc_topo(graph, topo, 0);\n\tcout << dijkstra(n, graph, topo) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 28720, "score_of_the_acc": -0.8067, "final_rank": 9 }, { "submission_id": "aoj_0324_7526246", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\n#include <queue>\n#include <tuple>\nusing namespace std;\n\nusing ll = long long;\n\nstruct Edge {\n int to;\n ll c0;\n ll c1;\n};\n\n\nint idx = 0;\n\n\nvoid calc_topo(const vector<vector<Edge>>& g, vector<int>& topo, int v) {\n\tif (topo[v] != -1) return;\n\tfor (const auto& e : g[v]) {\n\t\tcalc_topo(g, topo, e.to);\n\t}\n\ttopo[v] = idx++;\n};\n\nll dijkstra(int n, const vector<vector<Edge>>& g, const vector<int>& topo){\n vector<vector<ll>> dist(n, vector<ll>(n, numeric_limits<ll>::max()));\n dist[0][0] = 0;\n using state = tuple<ll, int, int>;\n priority_queue<state, vector<state>, greater<state>> que;\n que.emplace(0, 0, 0);\n while(!que.empty()) {\n ll cur_c;\n int fst_v, sec_v;\n tie(cur_c, fst_v, sec_v) = que.top();\n que.pop();\n if(fst_v == sec_v) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c0 + e.c1;\n if(dist[e.to][e.to] > nxt_c) {\n dist[e.to][e.to] = nxt_c;\n que.emplace(nxt_c, e.to, e.to);\n }\n }\n\n for(auto& e1 : g[fst_v]) {\n for(auto& e2 : g[sec_v]) {\n if(e1.to == e2.to) continue;\n ll nxt_c = cur_c + e1.c0 + e2.c0;\n if(dist[e1.to][e2.to] > nxt_c) {\n dist[e1.to][e2.to] = nxt_c;\n que.emplace(nxt_c, e1.to, e2.to);\n }\n }\n }\n } else {\n if(topo[fst_v] > topo[sec_v]) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c0;\n if(dist[e.to][sec_v] > nxt_c) {\n dist[e.to][sec_v] = nxt_c;\n que.emplace(nxt_c, e.to, sec_v);\n }\n }\n } else {\n for(auto& e : g[sec_v]) {\n ll nxt_c = cur_c + e.c0;\n if(dist[fst_v][e.to] > nxt_c) {\n dist[fst_v][e.to] = nxt_c;\n que.emplace(nxt_c, fst_v, e.to);\n }\n }\n }\n }\n }\n return dist[n - 1][n - 1];\n}\n\nint main() {\n#if READ_FROM_FILE\n ifstream ifs(\"test0.txt\");\n cin.rdbuf(ifs.rdbuf());\n#endif\n int n, p;\n cin >> n >> p;\n vector<vector<Edge>> g(n);\n for (int i = 0; i < p; ++i) {\n int s, e;\n ll t0, t1;\n cin >> s >> e >> t0 >> t1;\n g[s - 1].push_back(Edge{ e - 1, t0, t1 });\n }\n\n vector<int> topo(n, -1);\n int idx = 0;\n calc_topo(g, topo, 0);\n cout << dijkstra(n, g, topo) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 29184, "score_of_the_acc": -0.8123, "final_rank": 10 }, { "submission_id": "aoj_0324_6965746", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0324.cc: Downhill Race\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 1000;\nconst int MAX_M = 2000;\nconst long long LINF = 1LL << 62;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef queue<int> qi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\n\nstruct Stat {\n ll d;\n int i, j;\n Stat() {}\n Stat(ll _d, int _i, int _j): d(_d), i(_i), j(_j) {}\n bool operator<(const Stat &s) const { return d > s.d; }\n};\n\n/* global variables */\n\nvpii nbrs[MAX_N];\nint ts0[MAX_M], ts1[MAX_M];\nint pns[MAX_N], ods[MAX_N];\nll ds[MAX_N][MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n, m;\n scanf(\"%d%d\", &n, &m);\n\n for (int i = 0; i < m; i++) {\n int u, v;\n scanf(\"%d%d%d%d\", &u, &v, ts0 + i, ts1 + i);\n u--, v--;\n nbrs[u].push_back(pii(v, i));\n pns[v]++;\n }\n\n qi q;\n q.push(0);\n\n for (int k = 0; ! q.empty();) {\n int u = q.front(); q.pop();\n ods[u] = k++;\n for (auto ve: nbrs[u]) {\n int v = ve.first;\n if (--pns[v] == 0) q.push(v);\n }\n }\n //for (int i = 0; i < n; i++) printf(\"%d \", ods[i]); putchar('\\n');\n\n for (int i = 0; i < n; i++) fill(ds[i], ds[i] + n, LINF);\n ds[0][0] = 0;\n\n priority_queue<Stat> pq;\n pq.push(Stat(0, 0, 0));\n\n while (! pq.empty()) {\n Stat u = pq.top(); pq.pop();\n if (ds[u.i][u.j] != u.d) continue;\n if (u.i == n - 1 && u.j == n - 1) break;\n\n if (u.i == u.j) {\n for (auto ve: nbrs[u.i]) {\n\tint v = ve.first, ei = ve.second;\n\tll vd = u.d + ts0[ei] + ts1[ei];\n\tif (ds[v][v] > vd) {\n\t ds[v][v] = vd;\n\t pq.push(Stat(vd, v, v));\n\t}\n }\n\n for (auto vei: nbrs[u.i]) {\n\tint vi = vei.first, ei = vei.second;\n\tfor (auto vej: nbrs[u.j]) {\n\t int vj = vej.first, ej = vej.second;\n\t if (vi != vj) {\n\t int tvi = vi, tvj = vj;\n\t if (ods[tvi] > ods[tvj]) swap(tvi, tvj);\n\t ll vd = u.d + ts0[ei] + ts0[ej];\n\t if (ds[tvi][tvj] > vd) {\n\t ds[tvi][tvj] = vd;\n\t pq.push(Stat(vd, tvi, tvj));\n\t }\n\t }\n\t}\n }\n }\n else {\n for (auto ve: nbrs[u.i]) {\n\tint vi = ve.first, vj = u.j, ei = ve.second;\n\tif (ods[vi] > ods[vj]) swap(vi, vj);\n\tll vd = u.d + ts0[ei];\n\tif (ds[vi][vj] > vd) {\n\t ds[vi][vj] = vd;\n\t pq.push(Stat(vd, vi, vj));\n\t}\n }\n }\n }\n\n printf(\"%lld\\n\", ds[n - 1][n - 1]);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 19648, "score_of_the_acc": -0.384, "final_rank": 6 }, { "submission_id": "aoj_0324_4314833", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing ull = unsigned long long int;\nusing P = pair<ll, ll>;\nusing P3 = pair<P,ll>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 28;\nconstexpr ll MOD = ll(1e9)+7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\nconstexpr int di8[] = {0, 1, 1, 1, 0, -1, -1, -1};\nconstexpr int dj8[] = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr double EPS = 1e-9;\n\n\nstruct edge{\n int to, cap, cost, rev;\n};\n\nusing Graph = vector<vector<edge> >;\n\nGraph G1, G2;\nvector<int> dist;\n\nvoid add_edge(Graph& g, int from, int to, int cap, int cost){\n g[from].push_back((edge){to, cap, cost, int(g[to].size())});\n g[to].push_back((edge){from, 0, -cost, int(g[from].size())-1});\n}\n\n// 最小費用流\nint min_cost_flow(int s, int t, int f, Graph G){\n vector<int> h, prevv, preve;\n h.resize(G.size());\n dist.resize(G.size());\n prevv.resize(G.size());\n preve.resize(G.size());\n int res = 0;\n fill(h.begin(), h.end(), 0);\n while(f > 0){\n priority_queue<P, vector<P>, greater<P> > que;\n fill(dist.begin(), dist.end(), INF);\n dist[s] = 0;\n que.push({0,s});\n while(!que.empty()){\n P p = que.top();\n que.pop();\n int v = p.second;\n if(dist[v] < p.first) continue;\n for(int i=0;i<int(G[v].size());i++){\n auto &e = G[v][i];\n if(e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to]){\n dist[e.to] = dist[v] + e.cost + h[v] - h[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push({dist[e.to], e.to});\n }\n }\n }\n if(dist[t] == INF){\n return INF;\n }\n for(int v=0; v<G.size(); v++) h[v] += dist[v];\n int d = f;\n for(int v=t; v!=s; v=prevv[v]){\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d*h[t];\n for(int v=t; v!=s; v=prevv[v]){\n auto &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n}\n\nvoid dijkstra(int s){\n priority_queue<P, vector<P>, greater<P> > que;\n fill(dist.begin(), dist.end(), INF);\n dist[s] = 0;\n que.push({0,s});\n while(!que.empty()){\n P p = que.top();\n que.pop();\n int v = p.second;\n if(dist[v] < p.first) continue;\n for(int i=0;i<int(G2[v].size());i++){\n auto &e = G2[v][i];\n if(e.cost < 0) continue;\n if(dist[e.to] > dist[v] + e.cost){\n dist[e.to] = dist[v] + e.cost;\n que.push({dist[e.to], e.to});\n }\n }\n }\n}\n\nint solve(){\n int N, M;\n cin >> N >> M;\n G1.resize(N);\n G2.resize(N);\n for(int i=0;i<M;i++){\n int s, e, t1, t2;\n cin >> s >> e >> t1 >> t2;\n s--; e--;\n add_edge(G1, s, e, 1, t1);\n add_edge(G2, s, e, 1, t1+t2);\n }\n vector<int> x(N), y(N);\n for(int i=0;i<N;i++){\n x[i] = min_cost_flow(0,i,2, G1);\n y[i] = min_cost_flow(i,N-1,2, G1);\n }\n int ans = INF;\n for(int i=0;i<N;i++){\n dijkstra(i);\n for(int j=0;j<N;j++){\n ans = min(ans, x[i]+dist[j]+y[j]);\n }\n }\n cout << ans << endl;\n return 0;\n}\n\nint main(){\n\n solve();\n // while(solve()==0);\n // int t; cin >> t; for(;t>0;t--) solve();\n return 0;\n}", "accuracy": 0.625, "time_ms": 330, "memory_kb": 3464, "score_of_the_acc": -1, "final_rank": 20 }, { "submission_id": "aoj_0324_3865628", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 2012345678;\nint main() {\n\tint N, P;\n\tcin >> N >> P;\n\tvector<vector<int> > G(N);\n\tvector<int> deg(N);\n\tvector<int> A(P), B(P), C1(P), C2(P);\n\tfor (int i = 0; i < P; ++i) {\n\t\tcin >> A[i] >> B[i] >> C1[i] >> C2[i]; --A[i], --B[i];\n\t\tG[A[i]].push_back(B[i]);\n\t\t++deg[B[i]];\n\t}\n\tqueue<int> que;\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (deg[i] == 0) que.push(i);\n\t}\n\tvector<int> ord(N, -1);\n\tint cur = 0;\n\twhile (!que.empty()) {\n\t\tint u = que.front(); que.pop();\n\t\tord[u] = cur++;\n\t\tfor (int i : G[u]) {\n\t\t\t--deg[i];\n\t\t\tif (deg[i] == 0) que.push(i);\n\t\t}\n\t}\n\tvector<int> perm(P);\n\tfor (int i = 0; i < P; ++i) perm[i] = i;\n\tsort(perm.begin(), perm.end(), [&](int i, int j) {\n\t\treturn B[i] != B[j] ? ord[B[i]] < ord[B[j]] : ord[A[i]] < ord[A[j]];\n\t});\n\tvector<int> ip(N);\n\tfor (int i = 0; i < N; ++i) ip[ord[i]] = i;\n\tvector<int> rip = ip;\n\treverse(rip.begin(), rip.end());\n\tvector<vector<int> > dp(N, vector<int>(N, inf));\n\tdp[0][0] = 0;\n\tfor (int i : perm) {\n\t\tfor (int j : rip) {\n\t\t\tdp[B[i]][j] = min(dp[B[i]][j], dp[A[i]][j] + C1[i]);\n\t\t\tdp[j][B[i]] = min(dp[j][B[i]], dp[j][A[i]] + C1[i]);\n\t\t}\n\t\tdp[B[i]][B[i]] = min(dp[B[i]][B[i]], dp[A[i]][A[i]] + C1[i] + C2[i]);\n\t}\n\tcout << dp[N - 1][N - 1] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6844, "score_of_the_acc": -0.041, "final_rank": 2 }, { "submission_id": "aoj_0324_3848426", "code_snippet": "#include<algorithm>\n#include<cassert>\n#include<climits>\n#include<cmath>\n#include<cstring>\n#include<deque>\n#include<functional>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<queue>\n#include<set>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = int(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = int(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = int(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = int(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = int(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << endl\n\nconstexpr int IINF = (1 << 30) - 1;\nconstexpr long long LLINF = 1LL << 61;\nconstexpr double EPS = 1e-8;\n\nconst int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconst int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\nstruct edge{\n int to;\n lint cost1, cost2;\n};\n\nstruct node{\n int f, s;\n lint cost;\n\n bool operator<(const node& rhs) const {\n return cost > rhs.cost;\n }\n};\n\ntemplate<typename T>\nbool chmax(T& a, T b, bool equal = false){\n if(a < b || equal && a == b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nbool chmin(T& a, T b, bool equal = false){\n if(b < a || equal && a == b){\n a = b;\n return true;\n }\n return false;\n}\n\nbool topological_sort(const vector< vector<edge> >& g, vector<int>& res){\n const int v = (int)g.size();\n res.clear();\n\n vector<int> deg(v, 0);\n for(int i = 0 ; i < v ; ++i){\n for(auto e : g[i]){\n ++deg[e.to];\n }\n }\n\n vector<int> st;\n for(int i = 0 ; i < v ; ++i){\n if(deg[i] == 0){\n st.emplace_back(i);\n }\n }\n\n while(!st.empty()){\n int k = st.back();\n st.pop_back();\n res.emplace_back(k);\n for(auto e : g[k]){\n --deg[e.to];\n if(deg[e.to] == 0){\n st.emplace_back(e.to);\n }\n }\n }\n\n return (int)res.size() == v;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int n, p;\n cin >> n >> p;\n\n vector< vector<edge> > g(n);\n rep(i, p){\n int s, e;\n lint t1, t2;\n cin >> s >> e >> t1 >> t2;\n g[--s].push_back({--e, t1, t2});\n }\n\n vector<int> v;\n assert(topological_sort(g, v));\n\n vector<int> rev(n);\n rep(i, n){\n rev[v[i]] = i;\n }\n\n vector< vector<lint> > cost(n, vector<lint>(n, LLINF));\n cost[0][0] = 0;\n priority_queue<node> que;\n que.push({0, 0, 0LL});\n\n while(!que.empty()){\n node now = que.top();\n que.pop();\n if(cost[now.f][now.s] < now.cost){\n continue;\n }\n if(now.f == now.s){\n for(auto e1 : g[now.f]){\n for(auto e2 : g[now.s]){\n if(e1.to == e2.to){\n if(chmin(cost[e1.to][e1.to], now.cost + e1.cost1 + e1.cost2)){\n que.push({e1.to, e1.to, now.cost + e1.cost1 + e1.cost2});\n }\n }else{\n if(chmin(cost[e1.to][e2.to], now.cost + e1.cost1 + e2.cost1)){\n que.push({e1.to, e2.to, now.cost + e1.cost1 + e2.cost1});\n }\n }\n }\n }\n }else if(rev[now.f] < rev[now.s]){\n for(auto e : g[now.f]){\n if(chmin(cost[e.to][now.s], now.cost + e.cost1)){\n que.push({e.to, now.s, now.cost + e.cost1});\n }\n }\n }else{\n for(auto e : g[now.s]){\n if(chmin(cost[now.f][e.to], now.cost + e.cost1)){\n que.push({now.f, e.to, now.cost + e.cost1});\n }\n }\n }\n }\n\n cout << cost[n - 1][n - 1] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 27172, "score_of_the_acc": -1.1942, "final_rank": 15 }, { "submission_id": "aoj_0324_3742553", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std::literals::string_literals;\nusing i64 = long long;\nusing std::cout;\nusing std::endl;\nusing std::cin;\n\ntemplate<typename T>\nstd::vector<T> make_v(size_t a){return std::vector<T>(a);}\n\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts){\n return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\n\nint main() {\n\tint n, m; scanf(\"%d%d\", &n, &m);\n\tstd::vector<std::vector<std::pair<int, int>>> g(n);\n\tstd::vector<int> x(m), y(m), h(n, 0);\n\tfor(int i = 0; i < m; i++) {\n\t\tint a, b; scanf(\"%d%d%d%d\", &a, &b, &x[i], &y[i]);\n\t\t\n\t\tg[a - 1].push_back({b - 1, i});\n\t\th[b - 1]++;\n\t}\n\t\n\tstd::vector<int> latte, malta(n);\n\tstd::queue<int> qu; qu.push(0);\n\twhile(!qu.empty()) {\n\t\tauto p = qu.front(); qu.pop();\n\t\t\n\t\tlatte.push_back(p);\n\t\tfor(auto e: g[p]) if(!(--h[e.first])) qu.push(e.first);\n\t}\n\tfor(int i = 0; i < n; i++) malta[latte[i]] = i;\n\t\n\tauto dp = make_v<int>(n, n, 2);\n\tfor(auto& w: dp) for(auto& v: w) for(auto& z: v) z = 1 << 30; dp[0][0][0] = 0;\n\tfor(int i = 0; i < n; i++) {\n\t\tfor(int j = 0; j < i; j++) {\n\t\t\tfor(auto e: g[latte[j]]) {\n\t\t\t\tint to = malta[e.first], X = x[e.second], Y = y[e.second];\n\t\t\t\t\n\t\t\t\tif(i < to) {\n\t\t\t\t\tdp[to][i][0] = std::min({dp[to][i][0],\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][0] + X,\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][1] + X});\n\t\t\t\t} else if(to < i) {\n\t\t\t\t\tdp[i][to][0] = std::min({dp[i][to][0],\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][0] + X,\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][1] + X});\n\t\t\t\t} else {\n\t\t\t\t\tdp[to][to][0] = std::min({dp[to][to][0],\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][0] + X,\n\t\t\t\t\t\t\t\t\t\t\t dp[i][j][1] + Y});\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\tint j = i;\n\t\tfor(auto e: g[latte[j]]) {\n\t\t\tint to = malta[e.first], X = x[e.second], Y = y[e.second];\n\t\t\t\n\t\t\tdp[to][i][1] = std::min(dp[to][i][1], dp[i][j][0] + X);\n\t\t}\n\t}\n\tprintf(\"%d\\n\", std::min(dp[n - 1][n - 1][0], dp[n - 1][n - 1][1]));\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 58148, "score_of_the_acc": -0.8516, "final_rank": 12 }, { "submission_id": "aoj_0324_3742464", "code_snippet": "//#define NDEBUG\n#include <cstddef>\n#include <cstdint>\n#include <vector>\n\nnamespace n91 {\n\nusing i8 = std::int_fast8_t;\nusing i32 = std::int_fast32_t;\nusing i64 = std::int_fast64_t;\nusing u8 = std::uint_fast8_t;\nusing u32 = std::uint_fast32_t;\nusing u64 = std::uint_fast64_t;\nusing isize = std::ptrdiff_t;\nusing usize = std::size_t;\n\nconstexpr usize operator\"\" _z(unsigned long long x) noexcept {\n return static_cast<usize>(x);\n}\n\nclass rep {\n const usize f, l;\n\npublic:\n class itr {\n friend rep;\n usize i;\n constexpr itr(const usize x) noexcept : i(x) {}\n\n public:\n void operator++() noexcept { ++i; }\n constexpr usize operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr x) const noexcept { return i != x.i; }\n };\n constexpr rep(const usize first, const usize last) noexcept\n : f(first), l(last) {}\n constexpr itr begin() const noexcept { return itr(f); }\n constexpr itr end() const noexcept { return itr(l); }\n};\nclass revrep {\n const usize f, l;\n\npublic:\n class itr {\n friend revrep;\n usize i;\n constexpr itr(usize x) noexcept : i(x) {}\n\n public:\n void operator++() noexcept { --i; }\n constexpr usize operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr x) const noexcept { return i != x.i; }\n };\n constexpr revrep(usize first, usize last) noexcept : f(--first), l(--last) {}\n constexpr itr begin() const noexcept { return itr(l); }\n constexpr itr end() const noexcept { return itr(f); }\n};\ntemplate <class T> using vec_alias = std::vector<T>;\ntemplate <class T> auto md_vec(const usize n, const T &value) {\n return std::vector<T>(n, value);\n}\ntemplate <class... Args> auto md_vec(const usize n, Args... args) {\n return std::vector<decltype(md_vec(args...))>(n, md_vec(args...));\n}\ntemplate <class T> constexpr T difference(const T &a, const T &b) {\n return a < b ? b - a : a - b;\n}\n\n} // namespace n91\n\n#include <vector>\n\nnamespace nimi {\nstruct base_edge {\n std::size_t from;\n std::size_t to;\n base_edge(std::size_t from, std::size_t to) : from(from), to(to) {}\n};\n\ntemplate <class T> struct edge : public base_edge {\n T val;\n edge(std::size_t from, std::size_t to, T v) : base_edge(from, to), val(v) {}\n};\n\ntemplate <> struct edge<void> : public base_edge {\n edge(std::size_t from, std::size_t to) : base_edge(from, to) {}\n};\ntemplate <class C> struct maxflow_edge : public base_edge {\n C cap;\n std::size_t rev;\n maxflow_edge(std::size_t from, std::size_t to, C cap, std::size_t rev)\n : base_edge(from, to), cap(cap), rev(rev) {}\n};\n\ntemplate <class T>\nstruct directed_graph : public std::vector<std::vector<edge<T>>> {\n directed_graph(std::size_t n) : std::vector<std::vector<edge<T>>>(n) {}\n void add_edge(const edge<T> &e) { this->at(e.from).push_back(e); }\n};\n\ntemplate <class T>\nstruct undirected_graph : public std::vector<std::vector<edge<T>>> {\n undirected_graph(std::size_t n) : std::vector<std::vector<edge<T>>>(n) {}\n void add_edge(const edge<T> &e) {\n this->at(e.from).push_back(e);\n edge<T> re = e;\n std::swap(re.from, re.to);\n this->at(e.to).push_back(re);\n }\n};\n\ntemplate <class C>\nstruct maxflow_graph : public std::vector<std::vector<maxflow_edge<C>>> {\n maxflow_graph(std::size_t n) : std::vector<std::vector<maxflow_edge<C>>>(n) {}\n void add_edge(std::size_t from, std::size_t to, C cap,\n std::size_t rev_cap = 0) {\n this->at(from).push_back(\n maxflow_edge<C>(from, to, cap, this->at(to).size()));\n this->at(to).push_back(\n maxflow_edge<C>(to, from, rev_cap, this->at(from).size() - 1));\n }\n};\n} // namespace nimi\n\n#include <limits>\n#include <queue>\n#include <vector>\n\nnamespace nimi {\ntemplate <class T>\nstd::vector<T> dijkstra(const nimi::directed_graph<T> &g, std::size_t s) {\n const T INF = std::numeric_limits<T>::max();\n const T ZERO = T();\n const std::size_t n = g.size();\n\n struct node {\n T dist;\n std::size_t vertex;\n node(T d, std::size_t v) : dist(d), vertex(v) {}\n bool operator<(const node &n) const { return n.dist < dist; }\n };\n\n std::vector<T> dist(n, INF);\n std::priority_queue<node> que;\n\n dist[s] = ZERO;\n que.emplace(dist[s], s);\n\n while (!que.empty()) {\n node p = que.top();\n T d = p.dist;\n std::size_t v = p.vertex;\n que.pop();\n if (dist[v] < d)\n continue;\n for (const auto &e : g[v]) {\n if (dist[v] + e.val < dist[e.to]) {\n dist[e.to] = dist[v] + e.val;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return std::move(dist);\n}\n} // namespace nimi\n\n#include <algorithm>\n#include <iostream>\n#include <utility>\n\nnamespace n91 {\n\nvoid main_() {\n usize n, p;\n std::cin >> n >> p;\n nimi::directed_graph<u32> g(n * (n + 1_z) / 2_z);\n const auto get = [](const usize i, const usize j) {\n if (i >= j) {\n return i * (i + 1_z) / 2_z + j;\n } else {\n return j * (j + 1_z) / 2_z + i;\n }\n };\n {\n struct edge {\n usize to;\n u32 c0, c1;\n };\n std::vector<std::vector<edge>> h(n);\n std::vector<usize> deg(n);\n for (const auto i : rep(0_z, p)) {\n usize s, e;\n u32 t1, t2;\n std::cin >> s >> e >> t1 >> t2;\n --s;\n --e;\n h[s].push_back({e, t1, t2});\n ++deg[e];\n }\n\n // topological sort\n std::vector<usize> index;\n std::vector<usize> stack;\n stack.push_back(0_z);\n while (!stack.empty()) {\n const usize v = stack.back();\n stack.pop_back();\n index.push_back(v);\n for (const auto &e : h[v]) {\n --deg[e.to];\n if (deg[e.to] == 0_z) {\n stack.push_back(e.to);\n }\n }\n }\n\n for (auto i = index.cbegin(); i != index.cend(); ++i) {\n for (auto j = index.cbegin(); j != i; ++j) {\n for (const auto &e : h[*j]) {\n g.add_edge({get(*i, *j), get(*i, e.to), e.c0});\n }\n }\n for (auto j = h[*i].cbegin(); j != h[*i].cend(); ++j) {\n for (auto k = h[*i].cbegin(); k != j; ++k) {\n g.add_edge({get(*i, *i), get(j->to, k->to), j->c0 + k->c0});\n }\n g.add_edge({get(*i, *i), get(j->to, j->to), j->c0 + j->c1});\n }\n }\n }\n std::cout << nimi::dijkstra(g, get(0_z, 0_z))[get(n - 1_z, n - 1_z)]\n << std::endl;\n}\n\n} // namespace n91\n\nint main() {\n n91::main_();\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 85808, "score_of_the_acc": -1.75, "final_rank": 19 }, { "submission_id": "aoj_0324_3125957", "code_snippet": "# include <iostream>\n# include <algorithm>\n#include <array>\n# include <cassert>\n#include <cctype>\n#include <climits>\n#include <numeric>\n# include <vector>\n# include <string>\n# include <set>\n# include <map>\n# include <cmath>\n# include <iomanip>\n# include <functional>\n# include <tuple>\n# include <utility>\n# include <stack>\n# include <queue>\n# include <list>\n# include <bitset>\n# include <complex>\n# include <chrono>\n# include <random>\n# include <limits.h>\n# include <unordered_map>\n# include <unordered_set>\n# include <deque>\n# include <cstdio>\n# include <cstring>\n#include <stdio.h>\n#include<time.h>\n#include <stdlib.h>\n#include <cstdint>\n#include <cfenv>\n#include<fstream>\n//#include <bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\nlong long MOD = 1000000000 + 7;\nconstexpr long long INF = numeric_limits<LL>::max();\nconst double PI = acos(-1);\n#define fir first\n#define sec second\n#define thi third\n#define debug(x) cerr<<#x<<\": \"<<x<<'\\n'\ntypedef pair<LL, LL> Pll;\ntypedef pair<LL, pair<LL, LL>> Ppll;\ntypedef pair<LL, pair<LL, bitset<100001>>> Pbll;\ntypedef pair<LL, pair<LL, vector<LL>>> Pvll;\ntypedef pair<LL, LL> Vec2;\nstruct Tll { LL first, second, third; };\nstruct Fll { LL first, second, third, fourd; };\ntypedef pair<LL, Tll> Ptll;\n#define rep(i,rept) for(LL i=0;i<rept;i++)\n#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)\nLL h, w, n, m, k, t, s, p, q, last, cnt, sum, ans, d[2000][2000], a[60000], b[60000];\nstring str, ss;\nbool f[2000][2000];\nchar c;\nint di[4][2] = { { 0,1 },{ 1,0 },{ 0,-1 },{ -1,0 } };\nstruct Edge { LL to, cost1, cost2; };\nvector<Edge>vec[200000];\nvector<LL>v;\nmap<LL, LL>ma;\nmultiset<LL>st;\n\nvoid YN(bool f) {\n\tif (f)\n\t\tcout << \"YES\" << endl;\n\telse\n\t\tcout << \"NO\" << endl;\n}\nvoid yn(bool f) {\n\tif (f)\n\t\tcout << \"Yes\" << endl;\n\telse\n\t\tcout << \"No\" << endl;\n}\nvector<int> tsort(vector<vector<Edge>>g) {\n\tint n = g.size();\n\tenum { YET, VISITED, DONE };\n\tvector<int> res, flg(g.size(), YET);\n\tstatic const function<bool(int)> dfs = [&](int v) {\n\t\tflg[v] = VISITED;\n\t\tfor (auto &e : g[v]) {\n\t\t\tint w = e.to;\n\t\t\tif (flg[w] != DONE && (flg[w] == VISITED || !dfs(w))) return false;\n\t\t}\n\t\tflg[v] = DONE;\n\t\tres.push_back(v);\n\t\treturn true;\n\t};\n\tfor (int i = 0; i < n; ++i)\n\t\tif (flg[i] == YET && !dfs(i)) return{};\n\treverse(res.begin(), res.end());\n\treturn res;\n}\n\nvoid dijk(vector<int>ts, vector<vector<Edge>>g) {\n\trep(i,2000)rep(j,2000)\n\t\td[i][j] = INF;\n\td[0][0] = 0;\n\tpriority_queue<Ppll, vector<Ppll>, greater<Ppll>> pq;\n\tpq.push(Ppll(d[0][0], Pll(0, 0))); // (cost,頂点番号) \n\twhile (!pq.empty()) {\n\t\tPpll pp;\n\t\tpp = pq.top();\n\t\tLL cos = pp.first, vv[2] = { pp.second.first, pp.second.second }, x = 0;\n\t\tpq.pop();\n\t\tif (d[vv[0]][vv[1]] < pp.first)continue;\n\t\tif (vv[0]== vv[1]) {\n\t\t\tfor (int i = 0; i < g[vv[0]].size(); i++) {\n\t\t\t\tif (d[vv[0]][vv[1]] + g[vv[0]][i].cost1 + g[vv[0]][i].cost2 < d[g[vv[0]][i].to][g[vv[0]][i].to]) {\n\t\t\t\t\td[g[vv[0]][i].to][g[vv[0]][i].to] =\n\t\t\t\t\t\td[vv[0]][vv[1]] + g[vv[0]][i].cost1 + g[vv[0]][i].cost2;\n\t\t\t\t\tpq.push(Ppll(d[g[vv[0]][i].to][g[vv[1]][i].to], Pll(g[vv[0]][i].to, g[vv[1]][i].to)));\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tfor (int i = 0; i < g[vv[0]].size(); i++) {\n\t\t\t\tfor (int j = 0; j < g[vv[1]].size(); j++) {\n\t\t\t\t\tif (g[vv[0]][i].to == g[vv[1]][j].to)continue;\n\n\t\t\t\t\tif (d[vv[0]][vv[1]] + g[vv[0]][i].cost1 + g[vv[1]][j].cost1 < d[g[vv[0]][i].to][g[vv[1]][j].to]) {\n\t\t\t\t\t\td[g[vv[0]][i].to][g[vv[1]][j].to] = d[vv[0]][vv[1]] + g[vv[0]][i].cost1 + g[vv[1]][j].cost1;\n\t\t\t\t\t\tpq.push(Ppll(d[g[vv[0]][i].to][g[vv[1]][j].to], Pll(g[vv[0]][i].to, g[vv[1]][j].to)));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t}\n\t\telse {\n\t\t\tif (ts[vv[1]] < ts[vv[0]])x = 1;\n\n\t\t\tLL vt[2] = { vv[0],vv[1] };\n\t\t\tfor (int i = 0; i < g[vv[x]].size(); i++) {\n\t\t\t\tvt[x] = g[vv[x]][i].to;\n\t\t\t\tif (d[vt[0]][vt[1]] > g[vv[x]][i].cost1 + d[vv[0]][vv[1]]) {\n\t\t\t\t\td[vt[0]][vt[1]] = g[vv[x]][i].cost1 + d[vv[0]][vv[1]];\n\t\t\t\t\tpq.push(Ppll(d[vt[0]][vt[1]], Pll(vt[0], vt[1])));\n\t\t\t\t}\n\t\t\t}\n\n\t\t}\n\t}\n}\n\n\n\nint main() {\n\tcin >> n >> m;\n\tvector<vector<Edge>>g(n);\n\trep(i, m) {\n\t\tLL x, y, z, w;\n\t\tcin >> x >> y >> z >> w;\n\t\tx--, y--;\n\t\tg[x].push_back(Edge{ y,z,w });\n\t}\n\tdijk(tsort(g),g);\n\tcout << (d[n - 1][n - 1]==INF?0:d[n-1][n-1]) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 63588, "score_of_the_acc": -1.6052, "final_rank": 18 }, { "submission_id": "aoj_0324_3121268", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define INF_LL (int64)1e18\n#define INF (int32)1e9\n#define REP(i, n) for(int64 i = 0;i < (n);i++)\n#define FOR(i, a, b) for(int64 i = (a);i < (b);i++)\n#define all(x) x.begin(),x.end()\n#define fs first\n#define sc second\n\nusing int32 = int_fast32_t;\nusing uint32 = uint_fast32_t;\nusing int64 = int_fast64_t;\nusing uint64 = uint_fast64_t;\nusing PII = pair<int32, int32>;\nusing PLL = pair<int64, int64>;\n\nconst double eps = 1e-10;\n\ntemplate<typename A, typename B>inline void chmin(A &a, B b){if(a > b) a = b;}\ntemplate<typename A, typename B>inline void chmax(A &a, B b){if(a < b) a = b;}\n\nusing T = tuple<int32, int32, int32>;\n\nint32 N, P;\nvector<T> G[1010];\nvector<int32> a, inv;\nvector<bool> visited;\n\nvoid visit(int32 v){\n\tif(!visited[v]){\n\t\tvisited[v] = 1;\n\t\tREP(i, G[v].size()){\n\t\t\tvisit(get<2>(G[v][i]));\n\t\t}\n\t\ta.push_back(v);\n\t}\n}\n\nint64 dp[1010][1010][2] = {};\n\nint main(void){\n\tcin >> N >> P;\n\tvisited = vector<bool>(N);\n\n\tREP(i, 1010) REP(j, 1010) REP(k, 2) dp[i][j][k] = INF_LL;\n\n\tREP(i, P){\n\t\tint32 u, v, t1, t2;\n\t\tcin >> u >> v >> t1 >> t2; u--; v--;\n\t\tG[u].push_back(T(t1, t2, v));\n\t}\n\tREP(i, N) visit(i);\n\treverse(all(a));\n\tinv.resize(N);\n\tREP(i, N){\n\t\tinv[a[i]] = i;\n\t}\n\tdp[0][0][0] = 0;\n\n\tREP(i, N){\n\t\tREP(j, N){\n\t\t\tREP(l, 2){\n\t\t\t\tif(i <= j){\n\t\t\t\t\tREP(k, G[a[i]].size()){\n\t\t\t\t\t\tint32 c1, c2, v;\n\t\t\t\t\t\ttie(c1, c2, v) = G[a[i]][k];\n\t\t\t\t\t\tv = inv[v];\n\t\t\t\t\t\tif(v == j){\n\t\t\t\t\t\t\tif(l == 1)\n\t\t\t\t\t\t\t\tchmin(dp[v][j][0], dp[i][j][l]+c2);\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\tchmin(dp[v][j][0], dp[i][j][l]+c1);\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tif(j < v && i == j)\n\t\t\t\t\t\t\t\tchmin(dp[v][j][1], dp[i][j][l]+c1);\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\tchmin(dp[v][j][0], dp[i][j][l]+c1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(j <= i){\n\t\t\t\t\tREP(k, G[a[j]].size()){\n\t\t\t\t\t\tint32 c1, c2, v;\n\t\t\t\t\t\ttie(c1, c2, v) = G[a[j]][k];\n\t\t\t\t\t\tv = inv[v];\n\t\t\t\t\t\tif(v == i){\n\t\t\t\t\t\t\tif(l == 1)\n\t\t\t\t\t\t\t\tchmin(dp[i][v][0], dp[i][j][l]+c2);\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\tchmin(dp[i][v][0], dp[i][j][l]+c1);\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tif(i < v && i == j)\n\t\t\t\t\t\t\t\tchmin(dp[i][v][1], dp[i][j][l]+c1);\n\t\t\t\t\t\t\telse\n\t\t\t\t\t\t\t\tchmin(dp[i][v][0], dp[i][j][l]+c1);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << min(dp[N-1][N-1][0], dp[N-1][N-1][1]) << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 19172, "score_of_the_acc": -0.222, "final_rank": 4 }, { "submission_id": "aoj_0324_3051362", "code_snippet": "#include <stdio.h>\n#include <vector>\n#include <utility>\nusing namespace std;\ntypedef pair<int,int> pi;\n#define F first\n#define S second\n#define PB push_back\nconst int N=1e3+10;\nconst int INF=1e9+10;\nint n,dp[N][N],pos[N],top;\nvector<pair<int,pi>>graph[N];\nvoid swap(int &a,int &b){\n int temp=a;\n a=b;\n b=temp;\n return ;\n}\nint f(int a,int b){\n if(pos[a]==n&&pos[b]==n)return 0;\n if(pos[a]>pos[b])swap(a,b);\n if(dp[a][b]>=0)return dp[a][b];\n int ans=INF;\n if(a==b)for(pair<int,pi> i:graph[a])for(pair<int,pi> j:graph[a]){\n if(i==j)ans=min(ans,i.S.F+i.S.S+f(i.F,i.F));\n else ans=min(ans,i.S.F+j.S.F+f(i.F,j.F));\n }\n else for(pair<int,pi> i:graph[a])ans=min(ans,i.S.F+f(i.F,b));\n return dp[a][b]=ans;\n}\nvoid dfs(int now){\n for(pair<int,pi> i:graph[now])if(pos[i.F]<0)dfs(i.F);\n pos[now]=top--;\n return ;\n}\nint main(){\n int m,l,r,a,b;\n scanf(\"%d%d\",&n,&m);\n top=n;\n for(int i=1;i<=n;i++)pos[i]=-1;\n for(int i=1;i<=n;i++)for(int j=1;j<=n;j++)dp[i][j]=-1;\n while(m--){\n scanf(\"%d%d%d%d\",&l,&r,&a,&b);\n graph[l].PB({r,{a,b}});\n }\n dfs(1);\n printf(\"%d\\n\",f(1,1));\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6836, "score_of_the_acc": -0.041, "final_rank": 1 }, { "submission_id": "aoj_0324_2983586", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 1000\n#define HUGE_NUM 9999999999999999\n\n\nstruct Edge{\n\tEdge(int arg_to,ll arg_cost_1,ll arg_cost_2){\n\t\tto = arg_to;\n\t\tcost_1 = arg_cost_1;\n\t\tcost_2 = arg_cost_2;\n\t}\n\tint to;\n\tll cost_1,cost_2;\n};\n\nstruct State{\n\tState(int arg_node_1,int arg_node_2,ll arg_sum_cost){\n\t\tnode_1 = arg_node_1;\n\t\tnode_2 = arg_node_2;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tbool operator<(const struct State & arg) const{ //総コストの昇順(PQ)\n\t\treturn sum_cost > arg.sum_cost;\n\t}\n\tint node_1,node_2;\n\tll sum_cost;\n\n};\n\nint V,E;\nint in_num[NUM],topo_order[NUM];\nvector<Edge> G[NUM];\nll min_dist[NUM][NUM];\n\n\nint main(){\n\n\tscanf(\"%d %d\",&V,&E);\n\n\tint start = 0,goal = V-1;\n\n\tint from,to;\n\tll cost_1,cost_2;\n\n\tfor(int i = 0; i < V; i++)in_num[i] = 0;\n\n\tfor(int loop = 0; loop < E; loop++){\n\t\tscanf(\"%d %d %lld %lld\",&from,&to,&cost_1,&cost_2);\n\t\tfrom--;\n\t\tto--;\n\t\tin_num[to]++; //トポロジカル順序を計算するため\n\t\tG[from].push_back(Edge(to,cost_1,cost_2));\n\t}\n\n\tint index = 0,next_node;\n\n\tqueue<int> Q;\n\tQ.push(start);\n\n\t//各ノードのトポロジカル順序を求める\n\twhile(!Q.empty()){\n\n\t\ttopo_order[Q.front()] = index++;\n\n\t\tfor(int i = 0; i < G[Q.front()].size(); i++){\n\t\t\tnext_node = G[Q.front()][i].to;\n\t\t\tin_num[next_node]--;\n\n\t\t\tif(in_num[next_node] == 0){\n\t\t\t\tQ.push(next_node);\n\t\t\t}\n\t\t}\n\t\tQ.pop();\n\t}\n\n\tfor(int i = 0; i < V; i++){\n\t\tfor(int k = 0; k < V; k++)min_dist[i][k] = HUGE_NUM; //min_dist[1回目の終端][2回目の終端] = 合計最短コスト\n\t}\n\n\tmin_dist[start][start] = 0;\n\tpriority_queue<State> PQ;\n\tPQ.push(State(start,start,0));\n\n\tint next_node_1,next_node_2,next_cost;\n\n\twhile(!PQ.empty()){\n\n\t\tif(PQ.top().sum_cost > min_dist[PQ.top().node_1][PQ.top().node_2]){\n\t\t\tPQ.pop();\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(PQ.top().node_1 == PQ.top().node_2){\n\n\t\t\tif(PQ.top().node_1 == goal){\n\t\t\t\tprintf(\"%lld\\n\",PQ.top().sum_cost);\n\t\t\t\treturn 0;\n\t\t\t}\n\n\t\t\t//同じエッジを下る場合\n\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\t\t\t\tnext_node_2 = next_node_1;\n\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1+G[PQ.top().node_1][i].cost_2;\n\n\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t}\n\t\t\t}\n\n\n\t\t\tif(G[PQ.top().node_1].size() == 1){\n\t\t\t\tPQ.pop();\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\t//違うエッジを下る場合\n\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\n\t\t\t\tfor(int k = 0; k < G[PQ.top().node_1].size(); k++){\n\t\t\t\t\tif(k == i)continue;\n\n\t\t\t\t\tnext_node_2 = G[PQ.top().node_1][k].to;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1+G[PQ.top().node_1][k].cost_1;\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t}else{\n\n\t\t\t//トポロジカルソート順が小さい方のノードを進める\n\t\t\tif(topo_order[PQ.top().node_1] <= topo_order[PQ.top().node_2]){\n\n\t\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\t\t\t\t\tnext_node_2 = PQ.top().node_2;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1;\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t}else{\n\n\t\t\t\tfor(int i = 0; i < G[PQ.top().node_2].size(); i++){\n\n\t\t\t\t\tnext_node_2 = G[PQ.top().node_2][i].to;\n\t\t\t\t\tnext_node_1 = PQ.top().node_1;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_2][i].cost_1; //★初めて通るとして良い★\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tPQ.pop();\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 27272, "score_of_the_acc": -1.2579, "final_rank": 17 }, { "submission_id": "aoj_0324_2983582", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 1000\n#define HUGE_NUM 9999999999999999\n\n\nstruct Edge{\n\tEdge(int arg_to,ll arg_cost_1,ll arg_cost_2){\n\t\tto = arg_to;\n\t\tcost_1 = arg_cost_1;\n\t\tcost_2 = arg_cost_2;\n\t}\n\tint to;\n\tll cost_1,cost_2;\n};\n\nstruct State{\n\tState(int arg_node_1,int arg_node_2,ll arg_sum_cost){\n\t\tnode_1 = arg_node_1;\n\t\tnode_2 = arg_node_2;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tbool operator<(const struct State & arg) const{ //総コストの昇順(PQ)\n\t\treturn sum_cost > arg.sum_cost;\n\t}\n\tint node_1,node_2;\n\tll sum_cost;\n\n};\n\nint V,E;\nint in_num[NUM],topo_order[NUM];\nvector<Edge> G[NUM];\nll min_dist[NUM][NUM];\n\n\nint main(){\n\n\tscanf(\"%d %d\",&V,&E);\n\n\tint start = 0,goal = V-1;\n\n\tint from,to;\n\tll cost_1,cost_2;\n\n\tfor(int i = 0; i < V; i++)in_num[i] = 0;\n\n\tfor(int loop = 0; loop < E; loop++){\n\t\tscanf(\"%d %d %lld %lld\",&from,&to,&cost_1,&cost_2);\n\t\tfrom--;\n\t\tto--;\n\t\tin_num[to]++; //トポロジカル順序を計算するため\n\t\tG[from].push_back(Edge(to,cost_1,cost_2));\n\t}\n\n\tint index = 0,next_node;\n\n\tqueue<int> Q;\n\tQ.push(start);\n\n\t//各ノードのトポロジカル順序を求める\n\twhile(!Q.empty()){\n\n\t\ttopo_order[Q.front()] = index++;\n\n\t\tfor(int i = 0; i < G[Q.front()].size(); i++){\n\t\t\tnext_node = G[Q.front()][i].to;\n\t\t\tin_num[next_node]--;\n\n\t\t\tif(in_num[next_node] == 0){\n\t\t\t\tQ.push(next_node);\n\t\t\t}\n\t\t}\n\t\tQ.pop();\n\t}\n\n\tfor(int i = 0; i < V; i++){\n\t\tfor(int k = 0; k < V; k++)min_dist[i][k] = HUGE_NUM; //min_dist[1回目の終端][2回目の終端] = 合計最短コスト\n\t}\n\n\tmin_dist[start][start] = 0;\n\tpriority_queue<State> PQ;\n\tPQ.push(State(start,start,0));\n\n\tint next_node_1,next_node_2,next_cost;\n\n\twhile(!PQ.empty()){\n\n\t\tif(PQ.top().sum_cost > min_dist[PQ.top().node_1][PQ.top().node_2]){\n\t\t\tPQ.pop();\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(PQ.top().node_1 == PQ.top().node_2){\n\n\t\t\t//同じエッジを下る場合\n\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\t\t\t\tnext_node_2 = next_node_1;\n\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1+G[PQ.top().node_1][i].cost_2;\n\n\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t}\n\t\t\t}\n\n\n\t\t\tif(G[PQ.top().node_1].size() == 1){\n\t\t\t\tPQ.pop();\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\t//違うエッジを下る場合\n\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\n\t\t\t\tfor(int k = 0; k < G[PQ.top().node_1].size(); k++){\n\t\t\t\t\tif(k == i)continue;\n\n\t\t\t\t\tnext_node_2 = G[PQ.top().node_1][k].to;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1+G[PQ.top().node_1][k].cost_1;\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t}else{\n\n\t\t\t//トポロジカルソート順が小さい方のノードを進める\n\t\t\tif(topo_order[PQ.top().node_1] <= topo_order[PQ.top().node_2]){\n\n\t\t\t\tfor(int i = 0; i < G[PQ.top().node_1].size(); i++){\n\n\t\t\t\t\tnext_node_1 = G[PQ.top().node_1][i].to;\n\t\t\t\t\tnext_node_2 = PQ.top().node_2;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_1][i].cost_1;\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t}else{\n\n\t\t\t\tfor(int i = 0; i < G[PQ.top().node_2].size(); i++){\n\n\t\t\t\t\tnext_node_2 = G[PQ.top().node_2][i].to;\n\t\t\t\t\tnext_node_1 = PQ.top().node_1;\n\t\t\t\t\tnext_cost = PQ.top().sum_cost+G[PQ.top().node_2][i].cost_1; //★初めて通るとして良い★\n\n\t\t\t\t\tif(min_dist[next_node_1][next_node_2] > next_cost){\n\t\t\t\t\t\tmin_dist[next_node_1][next_node_2] = next_cost;\n\t\t\t\t\t\tPQ.push(State(next_node_1,next_node_2,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tPQ.pop();\n\t}\n\n\tprintf(\"%lld\\n\",min_dist[goal][goal]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 27236, "score_of_the_acc": -1.2574, "final_rank": 16 }, { "submission_id": "aoj_0324_2972521", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nconstexpr ll inf = 1e18;\n\nstruct edge {\n int to;\n ll c1, c2;\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\nint main() {\n int n, p;\n cin >> n >> p;\n graph g(n);\n for(int i = 0; i < p; ++i) {\n int s, e;\n ll t1, t2;\n cin >> s >> e >> t1 >> t2;\n g[s - 1].push_back(edge{e - 1, t1, t2});\n }\n\n vector<int> topo(n, -1);\n int idx = 0;\n function<void(int)> calc_topo = [&] (int v) {\n if(topo[v] != -1) return;\n for(auto& e : g[v]) {\n calc_topo(e.to);\n }\n topo[v] = idx++;\n };\n calc_topo(0);\n\n vector<vector<ll>> dist(n, vector<ll>(n, inf));\n dist[0][0] = 0;\n using state = tuple<ll, int, int>;\n priority_queue<state, vector<state>, greater<state>> que;\n que.emplace(0, 0, 0);\n while(!que.empty()) {\n ll cur_c;\n int fst_v, sec_v;\n tie(cur_c, fst_v, sec_v) = que.top();\n que.pop();\n if(fst_v == sec_v) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c1 + e.c2;\n if(dist[e.to][e.to] > nxt_c) {\n dist[e.to][e.to] = nxt_c;\n que.emplace(nxt_c, e.to, e.to);\n }\n }\n\n for(auto& e1 : g[fst_v]) {\n for(auto& e2 : g[sec_v]) {\n if(e1.to == e2.to) continue;\n ll nxt_c = cur_c + e1.c1 + e2.c1;\n if(dist[e1.to][e2.to] > nxt_c) {\n dist[e1.to][e2.to] = nxt_c;\n que.emplace(nxt_c, e1.to, e2.to);\n }\n }\n }\n } else {\n if(topo[fst_v] > topo[sec_v]) {\n for(auto& e : g[fst_v]) {\n ll nxt_c = cur_c + e.c1;\n if(dist[e.to][sec_v] > nxt_c) {\n dist[e.to][sec_v] = nxt_c;\n que.emplace(nxt_c, e.to, sec_v);\n }\n }\n } else {\n for(auto& e : g[sec_v]) {\n ll nxt_c = cur_c + e.c1;\n if(dist[fst_v][e.to] > nxt_c) {\n dist[fst_v][e.to] = nxt_c;\n que.emplace(nxt_c, fst_v, e.to);\n }\n }\n }\n }\n }\n\n cout << dist[n - 1][n - 1] << endl;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 27316, "score_of_the_acc": -1.0084, "final_rank": 14 }, { "submission_id": "aoj_0324_2925013", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld =long double;\nconst ld eps = 1e-9;\n\n\nstruct edge {\n\tint from;\n\tint to;\n\tint c1;\n\tint c2;\n};\n\nint main()\n{\n\tint N,M;cin>>N>>M;\n\tvector<vector<edge>>graph(N);\n\tvector<int>comes(N);\n\tfor (int i = 0; i < M; ++i) {\n\t\tint a,b,t1,t2;cin>>a>>b>>t1>>t2;\n\t\ta--;b--;\n\t\tgraph[a].push_back(edge{ a,b,t1,t2 });\n\t\tcomes[b]++;\n\t}\n\tvector<int>v;\n\tvector<int>nums(N);\n\t{\n\t\tqueue<int>que;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tif (!comes[i])que.push(i);\n\t\t}\n\t\twhile (!que.empty()) {\n\t\t\tint now(que.front());\n\t\t\tque.pop();\n\t\t\tv.push_back(now);\n\t\t\tfor (auto e : graph[now]) {\n\t\t\t\tcomes[e.to]--;\n\t\t\t\tif (!comes[e.to]) {\n\t\t\t\t\tque.push(e.to);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tnums[v[i]]=i;\n\t\t}\n\t}\n\tvector<vector<vector<int>>>memo(N,vector<vector<int>>(N,vector<int>(2,1e9)));\n\tmemo[0][0][0]=0;\n\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j <= i; ++j) {\n\t\t\tfor (int k = 0; k < 2; ++k) {\n\t\t\t\tint now_u = v[j];\n\t\t\t\tint now_d = v[i];\n\n\t\t\t\tfor (auto e : graph[now_u]) {\n\t\t\t\t\tif (k&&e.to == now_d)continue;\n\t\t\t\t\telse {\n\t\t\t\t\t\tint next_u = e.to;\n\t\t\t\t\t\tint next_d = now_d;\n\n\t\t\t\t\t\tif (nums[next_u]>nums[next_d])swap(next_u, next_d);\n\n\t\t\t\t\t\tint next_i = nums[next_d];\n\t\t\t\t\t\tint next_j = nums[next_u];\n\n\t\t\t\t\t\tmemo[next_i][next_j][i==j] = min(memo[next_i][next_j][i==j], memo[i][j][k] + e.c1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (now_u == now_d) {\n\t\t\t\t\tfor (auto e : graph[now_u]) {\n\n\t\t\t\t\t\tint next_u = e.to;\n\t\t\t\t\t\tint next_d = e.to;\n\n\n\t\t\t\t\t\tint next_i = nums[next_d];\n\t\t\t\t\t\tint next_j = nums[next_u];\n\n\t\t\t\t\t\tmemo[next_i][next_j][0] = min(memo[next_i][next_j][0], memo[i][j][k] + e.c1 + e.c2);\n\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t}\n\tint ans=memo[N-1][N-1][0];\n\tans=min(ans,memo[N-1][N-1][1]);\n\tcout<<ans<<endl;\n\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 58012, "score_of_the_acc": -0.9124, "final_rank": 13 } ]
aoj_0326_cpp
関連商品 インターネット通販サイトでは、ユーザが現在見ている商品と同じページに、過去に他のユーザによって、現在見ている商品と一緒に買われた別の商品をいくつか表示してくれます。関連性の高いと思われる商品を提示することで、売り上げを伸ばすことができると考えられているからです。 似たようなことは、一緒に買われることが多い商品を近くに配置する、という工夫として、近所のスーパーマーケットでも目にすることができます(例えば、パンとジャムのような)。あなたの仕事は、商品配置の工夫を助けるプログラムを書くことです。今回は、ある基準となる回数を設定し、一緒に買われた回数が基準回数以上である、2つの商品の組み合わせを求めたいと思います。 一緒に買われた商品の情報と基準回数が与えられたとき、基準回数以上一緒に買われた商品2つの組み合わせを出力するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N F info 1 info 2 : info N 1行目に、一緒に買われた商品の情報の数 N (1 ≤ N ≤ 100) と、基準回数 F (1 ≤ F ≤ 100) が与えられる。続く N 行に、一緒に買われた商品の情報が与えられる。一緒に買われた商品の情報 info i は、以下の形式で与えられる。 M item 1 item 2 ... item M M (1 ≤ M ≤ 10) は、この情報がいくつの商品を含むかを表す。 item j は、この買い物で買われた商品の名前であり、英小文字だけから成る長さ 1 以上 30 以下の文字列である。 info i の中に同じ商品が与えられることはない。 Output 1行目に基準回数以上一緒に買われた商品2つの組み合わせの数を出力し、2行目以降に組み合わせをすべて出力する。ただし、組み合わせが一つもない場合は2行目以降には何も出力しない。 出力の順番は、組み合わせ内の商品名どうしを、辞書式順序(英和辞書で単語が並んでいる順番)で並べたあと、組み合わせどうしについては以下のようにする。 一つ目の商品名どうしを比較して、辞書式順序で早いほうが先。 同じ場合は、二つ目の商品名どうしを比較して、辞書式順序で早いほうが先。 商品名はスペース一つで区切り、商品の組み合わせは改行一つで区切る。 Sample Input 1 5 2 3 bread milk banana 2 milk cornflakes 3 potato bread milk 4 cornflakes bread milk butter 2 potato bread Sample Output 1 3 bread milk bread potato cornflakes milk Sample Input 2 5 5 3 bread milk banana 2 milk cornflakes 3 potato bread milk 4 cornflakes bread milk butter 2 potato bread Sample Output 2 0
[ { "submission_id": "aoj_0326_9447550", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nWA on test 3\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 1000000000;\n\nstatic char buf[150];\n\nconst int MAX_N = 100;\nstatic vector<string> food[MAX_N];\n\nconst int BITS = 1000;\ntypedef bitset<BITS> Mask;\n\n\ntypedef pair<int,int> PA;\ntypedef vector<PA> PAS;\n//------------------------------------------------------------------------------\nMask encode(int N, int B, map<string,int>& to_vert, int index)\n{\n Mask mask;\n for (string s: food[index]) mask[ to_vert[s] ] = 1;\n return mask;\n}\n\n// mask => pair of foods\nbool feasible(int N, int K, const vector<Mask>& masks, const Mask &mask)\n{\n int res = 0;\n for (Mask m: masks)\n if ((m & mask) == mask)\n {\n res++;\n if (res >= K) return true; //<--------- FIXME\n }\n return false;\n}\n//------------------------------------------------------------------------------\nvoid solve(int N, int K, int B, map<string,int>& to_vert, const vector<string>& to_str)\n{\n if (DEBUG) printf(\"N=%d, K=%d, B=%d\\n\", N, K, B);\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n vector<Mask> masks(N);\n for (int i=0; i<N; ++i) masks[i] = encode(N, B, to_vert, i);\n\n //--------------------------------------------------------------------------\n // compute:\n PAS R;\n int num = 0;\n for (int b1=0; b1<B-1; ++b1)\n {\n for (int b2=b1+1; b2<B; ++b2)\n {\n Mask mask;\n mask[b1] = 1;\n mask[b2] = 1;\n if (feasible(N, K, masks, mask)) R.push_back( {b1, b2} );\n }\n }\n //--------------------------------------------------------------------------\n // report:\n printf(\"%ld\\n\", R.size());\n for (PA p: R) printf(\"%s %s\\n\", to_str[p.first].c_str(), to_str[p.second].c_str());\n\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, K, F, B, num;\n set<string> unique;\n\n num = scanf(\"%d %d \", &N, &K);\n for (int i=0; i<N; ++i)\n {\n num = scanf(\"%d \", &F);\n for (int f=0; f<F; ++f)\n {\n num = scanf(\"%s \", buf);\n food[i].push_back(string(buf));\n unique.insert( food[i].back() );\n }\n }\n \n B = unique.size();\n vector<string> to_str(B);\n map<string,int> to_vert;\n int b = 0;\n for (string s: unique)\n {\n to_vert[s] = b;\n to_str[b++] = s;\n }\n solve(N, K, B, to_vert, to_str);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 510, "memory_kb": 4036, "score_of_the_acc": -1.0159, "final_rank": 13 }, { "submission_id": "aoj_0326_7073820", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nint main() {\n\tint n, f;\n\tcin >> n >> f;\n\tmap<string, int>item;\n\tint cnt = 0;\n\tvvint table(1001, vint(1001));\n\trep(i, n) {\n\t\tint m;\n\t\tcin >> m;\n\t\tvstring s(m);\n\t\trep(j, m) {\n\t\t\tcin >> s[j];\n\t\t\tif (item[s[j]] == 0) {\n\t\t\t\titem[s[j]] = ++cnt;\n\t\t\t}\n\t\t\trep(k, j) {\n\t\t\t\ttable[item[s[k]]][item[s[j]]]++;\n\t\t\t\ttable[item[s[j]]][item[s[k]]]++;\n\t\t\t}\n\t\t}\n\t}\n\tvector<pair<string, string>>ans;\n\tfor (auto [s, i] : item) {\n\t\tfor (auto [t, j] : item) {\n\t\t\tif (table[i][j] >= f && s < t)ans.push_back({ s,t });\n\t\t}\n\t}\n\tsort(all(ans));\n\tcout << ans.size() << endl;\n\tfor (auto [s, t] : ans)cout << s << \" \" << t << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8012, "score_of_the_acc": -0.0992, "final_rank": 4 }, { "submission_id": "aoj_0326_4939958", "code_snippet": "#include<bits//stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0;i<n;i++)\n#define ALL(a) a.begin(),a.end()\ntypedef long long ll;\nint main(){\n int n,f,m;cin >>n >>f;\n map<pair<string,string>,int> mp;\n set<string>st;\n rep(i,n){\n cin >>m;vector<string> s(m);\n rep(j,m){\n cin >> s[j];st.insert(s[j]);\n }sort(ALL(s));\n rep(j,m-1){\n for(int k = j+1;k<m;k++){\n mp[{s[j],s[k]}]++;\n }\n }\n }vector<string> s;vector<string> v,w;\n for(string it : st) s.push_back(it);\n for(string S:s){\n for(string T:s){\n if(S==T) continue;\n if(mp[{S,T}]>= f){\n v.push_back(S);\n w.push_back(T);\n }\n }\n }cout << v.size() <<endl;\n rep(i,v.size()){\n cout << v[i] << \" \" << w[i] <<endl;\n }\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 65828, "score_of_the_acc": -1.96, "final_rank": 16 }, { "submission_id": "aoj_0326_4558572", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint dp[1000][1000];\n\nint main() {\n int n, x;\n cin >> n >> x;\n int cnt = 0;\n map<string, int> mp;\n vector<string> a;\n for (int i = 0; i < n; ++i) {\n vector<int> v;\n int m;\n cin >> m;\n for (int j = 0; j < m; ++j) {\n string s;\n cin >> s;\n if(!mp.count(s)){\n v.emplace_back(cnt);\n a.emplace_back(s);\n mp[s] = cnt++;\n }else {\n v.emplace_back(mp[s]);\n }\n }\n for (int j = 0; j < m; ++j) {\n for (int k = 0; k < m; ++k) {\n if(j != k){\n dp[v[j]][v[k]]++;\n }\n }\n }\n }\n vector<pair<string, string>> ans;\n for (int j = 0; j < cnt; ++j) {\n for (int k = 0; k < cnt; ++k) {\n if(a[j] < a[k] && dp[j][k] >= x){\n ans.emplace_back(a[j], a[k]);\n }\n }\n }\n cout << ans.size() << \"\\n\";\n sort(ans.begin(),ans.end());\n for (auto &&l : ans) {\n cout << l.first << \" \" << l.second << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7208, "score_of_the_acc": -0.0664, "final_rank": 2 }, { "submission_id": "aoj_0326_4169855", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<vector>\n#define int long long\n#define mod 1000000007\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\nusing namespace std;\nint get() { int r; cin >> r; return r; }\nset<pair<string, string>>s;\nmap<pair<string, string>, int>m;\nint n, k;\nstring a[12];\nvector<pair<string, string>>ans;\nsigned main() {\n\tcin >> n >> k;\n\tfor1(hoge, n) {\n\t\tint p; cin >> p;\n\t\tfor0(i, p)cin >> a[i];\n\t\tsort(a, a + p);\n\t\tfor0(i, p) {\n\t\t\tfor (int j = i + 1; j < p; j++) {\n\t\t\t\tpair<string, string>pr = make_pair(a[i], a[j]);\n\t\t\t\tif (find(s.begin(), s.end(), pr) == s.end()) {\n\t\t\t\t\ts.insert(pr);\n\t\t\t\t\tm[pr] = 1;\n\t\t\t\t}\n\t\t\t\telse m[pr]++;\n\t\t\t}\n\t\t}\n\t}\n\tfor (pair<string, string>p : s)\n\t\tif (m[p] >= k)ans.push_back(p);\n\tcout << ans.size() << endl;\n\tfor (pair<string, string>p : ans)cout << p.first << ' ' << p.second << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3936, "score_of_the_acc": -0.2343, "final_rank": 8 }, { "submission_id": "aoj_0326_3964845", "code_snippet": "// クエリ先読みして出てくる単語を掌握\n// グラフを張る\n// 辞書順に全探索して実際に成立するか確かめる\n\n#include <iostream>\n#include <vector>\n#include <string>\n#include <set>\n\nusing namespace std;\n\nint main() {\n\tint n, f;\n\tcin >> n >> f;\n\tset<string>se;\n\tvector<vector<string>>input(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tint m; cin >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\tse.insert(s);\n\t\t\tinput[i].push_back(s);\n\t\t}\n\t}\n\tvector<string>product;\n\tfor (auto s : se)product.push_back(s);\n\n\tvector<vector<int>>graph(product.size(), vector<int>(product.size()));\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < input[i].size(); j++) {\n\t\t\tfor (int k = j + 1; k < input[i].size(); k++) {\n\t\t\t\tint a = 0;\n\t\t\t\tfor (int index = 0; index < product.size(); index++) {\n\t\t\t\t\tif (product[index] == input[i][j])a = index;\n\t\t\t\t}\n\t\t\t\tint b = 0;\n\t\t\t\tfor (int index = 0; index < product.size(); index++) {\n\t\t\t\t\tif (product[index] == input[i][k])b = index;\n\t\t\t\t}\n\t\t\t\tgraph[a][b]++;\n\t\t\t\tgraph[b][a]++;\n\t\t\t}\n\t\t}\n\t}\n\n\tvector<vector<string>>ret;\n\tfor (int i = 0; i < product.size(); i++) {\n\t\tfor (int j = i + 1; j < product.size(); j++) {\n\t\t\tif (graph[i][j] >= f) {\n\t\t\t\tret.push_back({ product[i],product[j] });\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ret.size() << endl;\n\tfor (auto x : ret)cout << x[0] << \" \" << x[1] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7368, "score_of_the_acc": -0.1289, "final_rank": 5 }, { "submission_id": "aoj_0326_3848890", "code_snippet": "#include<bits/stdc++.h>\n#define V vector\n#define VI vector<int>\n#define VVI vector<vector<int>>\n#define REP(i,n) for(int i=0;i<(n);i++)\n#define REPR(i,n) for(int i=n;i>=0;i--)\n#define FOR(i,m,n) for(int i=m;i<n;i++)\n#define MOD 1000000007\n#define INF 1e9\n#define F first\n#define S second\n#define All(x) (x).begin(),(x).end()\nusing namespace std;\ntypedef long long ll;\n\nint main(void){\n map<string,map<string,int>> item;\n int N,F;\n cin>>N>>F;\n V<string> all;\n REP(i,N){\n int M;cin>>M;\n V<string> in(M);\n REP(j,M){\n cin>>in[j];\n all.push_back(in[j]);\n }\n REP(j,M){\n FOR(k,j+1,M){\n item[in[j]][in[k]]++;\n item[in[k]][in[j]]++;\n }\n }\n }\n sort(All(all));\n all.erase(unique(All(all)),all.end());\n int cnt=0;\n V<pair<int,int>> ans;\n REP(i,all.size()){\n FOR(j,i+1,all.size()){\n if(item[all[i]][all[j]]>=F){\n cnt++;\n ans.push_back(make_pair(i,j));\n }\n }\n }\n cout<<cnt<<endl;\n REP(i,cnt){\n cout<<all[ans[i].F]<<\" \"<<all[ans[i].S]<<endl;\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 34856, "score_of_the_acc": -0.7467, "final_rank": 12 }, { "submission_id": "aoj_0326_3622612", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n,m,ans=0;\n string t;\n cin >> n >> m;\n vector<int> a(n);\n vector<string> s(0);\n vector<vector<string>> u(n,vector<string>(0));\n for (int i=0;i<n;i++){\n cin >> a.at(i);\n for (int j=0;j<a.at(i);j++){\n int y=0;\n cin >> t;\n u.at(i).push_back(t);\n for (int k=0;k<s.size();k++){\n if (s.at(k)==t) {y=1;break;}\n }\n if (y==0) s.push_back(t);\n }\n sort(u.at(i).begin(),u.at(i).end());\n }\n sort(s.begin(),s.end());\n vector<vector<pair<pair<string,string>,int>>> h(s.size(),vector<pair<pair<string,string>,int>>(s.size()));\n for (int i=0;i<s.size()-1;i++){\n for (int j=i+1;j<s.size();j++){\n pair<pair<string,string>,int> v;\n v.first.first=s.at(i);v.first.second=s.at(j);v.second=0;\n h.at(i).at(j)=v;\n }\n }\n for (int i=0;i<n;i++){\n for (int j=0;j<a.at(i)-1;j++){\n for (int k=j+1;k<a.at(i);k++){\n for (int e=0;e<s.size()-1;e++){\n if (h.at(e).at(s.size()-1).first.first==u.at(i).at(j)){\n for (int ii=e+1;ii<s.size();ii++){\n if (h.at(e).at(ii).first.first==u.at(i).at(j) && h.at(e).at(ii).first.second==u.at(i).at(k)) h.at(e).at(ii).second++;\n }\n }\n }\n }\n }\n }\n for (int i=0;i<s.size()-1;i++) {\n for (int j=i+1;j<s.size();j++){\n if (h.at(i).at(j).second>=m) ans++;\n }\n }\n cout << ans << endl;\n for (int i=0;i<s.size()-1;i++) {\n for (int j=i+1;j<s.size();j++){\n if (h.at(i).at(j).second>=m) cout << h.at(i).at(j).first.first << \" \" << h.at(i).at(j).first.second << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 26332, "score_of_the_acc": -0.511, "final_rank": 9 }, { "submission_id": "aoj_0326_3130934", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<string>\n#include<cmath>\n#include<cstring>\n#include<map>\n#include<string.h>\n#include<stdexcept>\nusing namespace std;\n\nmap<string,int>item;\nvector<string>comb;\n\nint main(){\n int n,f,m;\n string s[10];\n item.clear();\n scanf(\"%d %d\",&n,&f);\n for(int i=0;i<n;i++){\n scanf(\"%d\",&m);\n for(int j=0;j<m;j++){\n cin>>s[j];\n }\n sort(s,s+m);\n for(int j=0;j<m;j++){\n for(int k=j+1;k<m;k++){\n\tstring temp;\n\ttemp=s[j]+\" \";\n\ttemp+=s[k];\n\tif(!count(comb.begin(),comb.end(),temp)){\n\t comb.push_back(temp);\n\t}\n\titem[temp]++;\n }\n }\n }\n\n sort(comb.begin(),comb.end());\n\n int ans=0;\n string ansstr[500000];\n for(int i=0;i<comb.size();i++){\n if(item[comb[i]]>=f){\n ansstr[ans]=comb[i];\n ans++;\n }\n }\n\n printf(\"%d\\n\",ans);\n for(int i=0;i<ans;i++){\n cout<<ansstr[i]<<endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8004, "score_of_the_acc": -0.1591, "final_rank": 6 }, { "submission_id": "aoj_0326_3061384", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\nstruct info{\n string word[10];\n int m;\n};\n\nstruct tag{\n string a;\n int id;\n int counter[10000];\n};\n\nvoid check(void);\nvoid Pair(void);\nvoid count(int name,int infomation);\nvoid dictionary(int one,int two);\n\n\nint n,f,tag_l;\nint ans,filing;\ntag t[1000];\ninfo str[100];\nstring k,ans_file[10000];\n\nint main(void){\n cin>>n>>f;\n for(int i=0;i<n;i++){\n cin>>str[i].m;\n for(int j=0;j<str[i].m;j++){\n cin>>str[i].word[j];\n }\n }\n check();\n Pair();\n \n k=' ';\n \n ans=0;\n \n for(int i=0;i<tag_l;i++){\n for(int j=0;j<tag_l;j++){\n if(i==j)continue;\n if(t[i].counter[j]>=f){\n ans++;\n t[j].counter[i]=0;\n }\n }\n }\n \n cout<<ans<<endl;\n filing=0;\n if(ans!=0){\n for(int i=0;i<tag_l;i++){\n for(int j=0;j<tag_l;j++){\n if(i==j)continue;\n if(t[i].counter[j]>=f){\n dictionary(i,j);\n }\n }\n }\n }\n \n string sub;\n \n for(int i=0;i<filing-1;i++){\n for(int j=i;j<filing;j++){\n if(ans_file[i]>ans_file[j]){\n sub=ans_file[i];\n ans_file[i]=ans_file[j];\n ans_file[j]=sub;\n }\n }\n }\n \n for(int i=0;i<filing;i++){\n cout<<ans_file[i]<<endl;\n }\n /*\n for(int i=0;i<tag_l;i++){\n cout<<t[i].a<<' '<<t[i].id<<' ';\n }cout<<endl;\n \n for(int i=0;i<tag_l;i++){\n cout<<t[i].a<<endl;\n for(int j=0;j<tag_l;j++){\n cout<<t[i].counter[j]<<endl;\n }\n }cout<<endl;\n cout<<ans<<endl;\n */\n}\n\n\nvoid check(void){\n tag_l=0;\n for(int i=0;i<n;i++){\n for(int j=0;j<str[i].m;j++){\n if(tag_l==0){t[tag_l].a=str[i].word[j]; t[tag_l].id=tag_l; tag_l++;}\n else{\n for(int k=0;k<tag_l;k++){\n if(t[k].a==str[i].word[j]){\n break;\n }\n if(k==tag_l-1){t[tag_l].a=str[i].word[j]; t[tag_l].id=tag_l; tag_l++;}\n }\n }\n }\n }\n}\n\nvoid Pair(void){\n for(int h=0;h<tag_l;h++){\n for(int i=0;i<n;i++){\n for(int j=0;j<str[i].m;j++){\n if(str[i].word[j]==t[h].a){\n count(h,i);\n }\n }\n }\n }\n}\n\nvoid count(int name,int infomation){\n for(int j=0;j<str[infomation].m;j++){\n for(int i=0;i<tag_l;i++){\n if(str[infomation].word[j]==t[i].a){\n t[name].counter[t[i].id]++;\n }\n }\n }\n}\n\nvoid dictionary(int one,int two){\n if(t[one].a>t[two].a){\n ans_file[filing]=t[two].a+k+t[one].a;\n \n }\n else{\n ans_file[filing]=t[one].a+k+t[two].a;\n }\n filing++;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 9592, "score_of_the_acc": -0.5644, "final_rank": 10 }, { "submission_id": "aoj_0326_3060838", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string.h>\n#include<string>\nusing namespace std;\nstruct DOBERMAN{\nchar c[61],s[61];\nint g;\n};\nDOBERMAN doberman[1000000]={0},q[1000000]={0},t;\nint main(){\nint i,j,n,f,m,u=0,o=0,r,l,b=0,jc,jk,js;\nstatic int p[1000000]={0};\nchar d[61][61];\nscanf(\"%d%d\",&n,&f);\nfor(i=0;i<n;i++){\n\tscanf(\"%d\",&m);\n\tfor(j=0;j<m;j++){\n\t\tcin>>d[j];\n\t}\n\tfor(j=0;j<m;j++){\n\t\tfor(r=j+1;r<m;r++){\n\t\t\to=0;\n\t\t\t//printf(\"%s %s\\n\",d[j],d[r]);\n\t\t\tfor(l=0;l<u;l++){\n\t\t\t\tif((strcmp(d[j],doberman[l].c)==0&&strcmp(d[r],doberman[l].s)==0)||(strcmp(d[r],doberman[l].c)==0&&strcmp(d[j],doberman[l].s)==0)){\n\t\t\t\t\t//printf(\"%d:%d\\n%d:%d\\n\",strcmp(d[j],doberman[l].c),strcmp(d[r],doberman[l].s),strcmp(d[r],doberman[l].c),strcmp(d[j],doberman[l].s));\n\t\t\t\t\to=1;\n\t\t\t\t\tdoberman[l].g++;\n\t\t\t\t\tif(doberman[l].g>=f&&p[l]==0){\n\t\t\t\t\t\tq[b]=doberman[l];\n\t\t\t\t\t\tp[l]=1;\n\t\t\t\t\t\tb++;\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(o==0){\n\t\t\t\t//printf(\"MorishitaSHINE\\n\");\n\t\t\t\tjs=0;\n\t\t\t\tfor(jc=0;jc<min(strlen(d[j]),strlen(d[r]));jc++){\n\t\t\t\t\tif(d[j][jc]-'a'>d[r][jc]-'a'){\n\t\t\t\t\t\tjs=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(d[j][jc]-'a'<d[r][jc]-'a'){\n\t\t\t\t\t\tjs=2;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(js==1){\n\t\t\t\t\tstrcpy(t.c,d[r]);\n\t\t\t\t\tstrcpy(t.s,d[j]);\n\t\t\t\t\tt.g=doberman[u].g+1;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\tstrcpy(t.c,d[j]);\n\t\t\t\tstrcpy(t.s,d[r]);\n\t\t\t\tt.g=doberman[u].g+1;\n\t\t\t\t}\n\t\t\t\tdoberman[u]=t;\n\t\t\t\t//printf(\"%s %s %d\\n\",doberman[u].c,doberman[u].s,doberman[u].g);\n\t\t\t\tif(doberman[u].g>=f&&p[u]==0){\n\t\t\t\t\tq[b]=doberman[u];\n\t\t\t\t\tp[u]=1;\n\t\t\t\t\tb++;\n\t\t\t\t}\n\t\t\t\tu++;\n\t\t\t}\n\t\t}\n\t}\n}\nfor(i=0;i<b;i++){\n\tfor(j=i+1;j<b;j++){\n\t\tjs=0;\n\t\tfor(jc=0;jc<min(strlen(q[i].c),strlen(q[j].c));jc++){\n\t\t\tif(q[i].c[jc]-'a'>q[j].c[jc]-'a'){\n\t\t\t\tjs=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(q[i].c[jc]-'a'<q[j].c[jc]-'a'){\n\t\t\t\tjs=2;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(js==0){\n\t\tfor(jc=0;jc<min(strlen(q[i].s),strlen(q[j].s));jc++){\n\t\t\tif(q[i].s[jc]-'a'>q[j].s[jc]-'a'){\n\t\t\t\tjs=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(q[i].s[jc]-'a'<q[j].s[jc]-'a'){\n\t\t\t\tjs=2;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\t}\n\t\tif(js==1){\n\t\t\tt=q[i];\n\t\t\tq[i]=q[j];\n\t\t\tq[j]=t;\n\t\t}\n\t}\n}\nprintf(\"%d\\n\",b);\nfor(i=0;i<b;i++){\n\tcout<<q[i].c<<' '<<q[i].s<<endl;\n}\nreturn 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 4308, "score_of_the_acc": -0.5802, "final_rank": 11 }, { "submission_id": "aoj_0326_3060747", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string.h>\n#include<string>\nusing namespace std;\nstruct DOBERMAN{\nchar c[61],s[61];\nint g;\n};\nDOBERMAN doberman[1000000]={0},q[1000000]={0},t;\nint main(){\nint i,j,n,f,m,u=0,o=0,r,l,b=0,jc,jk,js;\nstatic int p[1000000]={0};\nchar d[61][61];\nscanf(\"%d%d\",&n,&f);\nfor(i=0;i<n;i++){\n\tscanf(\"%d\",&m);\n\tfor(j=0;j<m;j++){\n\t\tcin>>d[j];\n\t}\n\tfor(j=0;j<m;j++){\n\t\tfor(r=j+1;r<m;r++){\n\t\t\to=0;\n\t\t\t//printf(\"%s %s\\n\",d[j],d[r]);\n\t\t\tfor(l=0;l<u;l++){\n\t\t\t\tif((strcmp(d[j],doberman[l].c)==0&&strcmp(d[r],doberman[l].s)==0)||(strcmp(d[r],doberman[l].c)==0&&strcmp(d[j],doberman[l].s)==0)){\n\t\t\t\t\t//printf(\"%d:%d\\n%d:%d\\n\",strcmp(d[j],doberman[l].c),strcmp(d[r],doberman[l].s),strcmp(d[r],doberman[l].c),strcmp(d[j],doberman[l].s));\n\t\t\t\t\to=1;\n\t\t\t\t\tdoberman[l].g++;\n\t\t\t\t\tif(doberman[l].g>=f&&p[l]==0){\n\t\t\t\t\t\tq[b]=doberman[l];\n\t\t\t\t\t\tp[l]=1;\n\t\t\t\t\t\tb++;\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(o==0){\n\t\t\t\t//printf(\"MorishitaSHINE\\n\");\n\t\t\t\tjs=0;\n\t\t\t\tfor(jc=0;jc<min(strlen(d[j]),strlen(d[r]));jc++){\n\t\t\t\t\tif(d[j][jc]-'a'>d[r][jc]-'a'){\n\t\t\t\t\t\tjs=1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(d[j][jc]-'a'<d[r][jc]-'a'){\n\t\t\t\t\t\tjs=2;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(js==1){\n\t\t\t\t\tstrcpy(t.c,d[r]);\n\t\t\t\t\tstrcpy(t.s,d[j]);\n\t\t\t\t\tt.g=doberman[u].g+1;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\tstrcpy(t.c,d[j]);\n\t\t\t\tstrcpy(t.s,d[r]);\n\t\t\t\tt.g=doberman[u].g+1;\n\t\t\t\t}\n\t\t\t\tdoberman[u]=t;\n\t\t\t\t//printf(\"%s %s %d\\n\",doberman[u].c,doberman[u].s,doberman[u].g);\n\t\t\t\tu++;\n\t\t\t}\n\t\t}\n\t}\n}\nfor(i=0;i<b;i++){\n\tfor(j=i+1;j<b;j++){\n\t\tjs=0;\n\t\tfor(jc=0;jc<min(strlen(q[i].c),strlen(q[j].c));jc++){\n\t\t\tif(q[i].c[jc]-'a'>q[j].c[jc]-'a'){\n\t\t\t\tjs=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(q[i].c[jc]-'a'<q[j].c[jc]-'a'){\n\t\t\t\tjs=2;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(js==0){\n\t\tfor(jc=0;jc<min(strlen(q[i].s),strlen(q[j].s));jc++){\n\t\t\tif(q[i].s[jc]-'a'>q[j].s[jc]-'a'){\n\t\t\t\tjs=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif(q[i].s[jc]-'a'<q[j].s[jc]-'a'){\n\t\t\t\tjs=2;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\t}\n\t\tif(js==1){\n\t\t\tt=q[i];\n\t\t\tq[i]=q[j];\n\t\t\tq[j]=t;\n\t\t}\n\t}\n}\nprintf(\"%d\\n\",b);\nfor(i=0;i<b;i++){\n\tcout<<q[i].c<<' '<<q[i].s<<endl;\n}\nreturn 0;\n}", "accuracy": 0.16666666666666666, "time_ms": 50, "memory_kb": 3776, "score_of_the_acc": -0.0917, "final_rank": 17 }, { "submission_id": "aoj_0326_2917486", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint a[2000][2000]={};\nint main(){\n int n,f;\n //int a[2000][2000]={};\n map<string,int> M;\n map<int,string> MD;\n set<string> S;\n int c=0;\n int count=0;\n cin>>n>>f;\n for(int i=0;i<n;i++){\n int m;\n cin>>m;\n vector<string> st;\n for(int t=0;t<m;t++){\n string s;\n cin>>s;\n st.push_back(s);\n if(S.find(s)==S.end()){S.insert(s); MD[count]=s; M[s]=count; count++;}\n for(int h=0;h<st.size()-1;h++){\n\ta[M[s]][M[st[h]]]++;\n\ta[M[st[h]]][M[s]]++;\n\tif(a[M[st[h]]][M[s]]==f){c++;}\n }\n }\n }\n cout<<c<<endl;\n for(set<string>::iterator i=S.begin();i!=S.end();i++){\n for(set<string>::iterator t=i;t!=S.end();t++){\n if(a[M[(*i)]][M[(*t)]]>=f){\n\t cout<<(*i)<<\" \"<<(*t)<<endl;\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7312, "score_of_the_acc": -0.208, "final_rank": 7 }, { "submission_id": "aoj_0326_2733745", "code_snippet": "#include <stdio.h>\n#include <iostream>\n#include <utility>\n#include <set>\n#include <vector>\n#include <string>\n#include <algorithm>\n#define rep(i, n) for(int i = 0; i < n; ++i)\nusing namespace std;\n\nint main(void) {\n int i, j, k, n, f;\n vector< pair< pair<string, string>, int> > v;\n scanf(\"%d%d\", &n, &f);\n rep(i, n) {\n int m, l = 0;\n scanf(\"%d\", &m);\n string s[m];\n rep(j, m) cin >> s[j];\n sort(s, s + m);\n rep(j, m) for(k = j + 1; k < m; ++k) {\n l = 0;\n pair<string, string> p = make_pair(s[j], s[k]);\n vector< pair< pair<string, string>, int> >::iterator it;\n for(it = v.begin(); it != v.end(); ++it) {\n if((*it).first.first == s[j] && (*it).first.second == s[k]) {\n (*it).second++;\n l = 1;\n break;\n }\n }\n pair< pair<string, string>, int> p1 = make_pair(p, 1);\n if(!l) v.push_back(p1);\n }\n }\n sort(v.begin(), v.end());\n vector< pair< pair<string, string>, int> >::iterator it;\n int ans = 0;\n for(it = v.begin(); it != v.end(); ++it) {\n if((*it).second >= f) ++ans;\n /*cout << (*it).first.first << \" \" << (*it).first.second << \" \" << (*it).second << \"\\n\";*/\n }\n printf(\"%d\\n\", ans);\n for(it = v.begin(); it != v.end(); ++it) {\n if((*it).second >= f) cout << (*it).first.first << \" \" << (*it).first.second << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3496, "score_of_the_acc": -0.0873, "final_rank": 3 }, { "submission_id": "aoj_0326_2591647", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<map>\n#include<algorithm>\n#include<functional>\n#include<utility>\nusing namespace std;\nint main() {\n\tint n, f;\n\tcin >> n >> f;\n\tmap<pair<string, string>, int> m;\n\tfor (int i = 0; i < n; i++) {\n\t\tint M;\n\t\tcin >> M;\n\t\tvector<string>item(M);\n\t\tfor (int j = 0; j < M; j++)cin >> item[j];\n\t\tsort(item.begin(), item.end());\n\t\tfor (int j = 0; j < M; j++) {\n\t\t\tfor (int k = j + 1; k < M; k++) {\n\t\t\t\tm[make_pair(item[j], item[k])] += 1;\n\t\t\t}\n\t\t}\n\t}\n\tint res = 0;\n\tfor (map<pair<string, string>, int>::iterator it = m.begin(); it != m.end(); it++) {\n\t\tif (it->second >= f)res++;\n\t}\n\tcout << res << endl;\n\tfor (map<pair<string, string>, int>::iterator it = m.begin(); it != m.end(); it++) {\n\t\tif (it->second >= f) cout << it->first.first << \" \" << it->first.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3476, "score_of_the_acc": -0.0069, "final_rank": 1 }, { "submission_id": "aoj_0326_2361442", "code_snippet": "#include <iostream>\n#include <string>\n#include <set>\n#include <map>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\ntypedef pair<string, string> P;\n\nint main() {\n\tint n, f;\n\tcin >> n >> f;\n\tset<string> st;\n\tmap<P, int> mp;\n\tfor (int i = 0; i < n; i++) {\n\t\tint m;\n\t\tcin >> m;\n\t\tvector<string> s(m);\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tcin >> s[j];\n\t\t\tst.insert(s[j]);\n\t\t}\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tfor (int k = j + 1; k < m; k++) {\n\t\t\t\tmp[P(s[j], s[k])]++;\n\t\t\t\tmp[P(s[k], s[j])]++;\n\t\t\t}\n\t\t}\n\t}\n\tvector<string> ss;\n\tfor (set<string>::iterator ite = st.begin(); ite != st.end(); ite++) {\n\t\tss.push_back(*ite);\n\t}\n\tint ans = 0;\n\tsort(ss.begin(), ss.end());\n\tfor (int i = 0; i < ss.size(); i++) {\n\t\tfor (int j = i + 1; j < ss.size(); j++) {\n\t\t\tif (mp[P(ss[i], ss[j])] >= f) {\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\tfor (int i = 0; i < ss.size(); i++) {\n\t\tfor (int j = i + 1; j < ss.size(); j++) {\n\t\t\tif (mp[P(ss[i], ss[j])] >= f) {\n\t\t\t\tcout << ss[i] << ' ' << ss[j] << endl;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 34820, "score_of_the_acc": -1.2261, "final_rank": 15 }, { "submission_id": "aoj_0326_2360711", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<string>\n#include<set>\n#include<map>\nusing namespace std;\n\nint main() {\n\tint n, f;\n\tint ans = 0;\n\tcin >> n >> f;\n\tvector<string> input(n);\n\tset<string> itemList;\n\tvector <pair<string, string> > ansList;\n\n\t// input\n\tfor (int i = 0; i < n; i++) {\n\t\tint m;\n\t\tcin >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tstring temp;\n\t\t\tcin >> temp;\n\t\t\tinput[i] += temp;\n\t\t\tinput[i] += \",\";\n\t\t\titemList.insert(temp);\n\t\t}\n\t}\n\n\n\t// solve\n\tauto itr = itemList.begin();\n\tauto itr_end = itemList.end();\n\titr_end--;\n\tfor (; itr != itr_end; itr++) {\n\t\tauto itr_temp = itr;\n\t\titr_temp++;\n\t\tfor (auto itr2=itr_temp; itr2 != itemList.end(); itr2++) {\n\t\t\tstring nowFirstItem = *itr;\n\t\t\tstring nowSecondItem = *itr2;\n\n\t\t\tint nowF = 0;\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tif (input[i].find(nowFirstItem) != string::npos &&\n\t\t\t\t\tinput[i].find(nowSecondItem) != string::npos) {\n\t\t\t\t\tnowF++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (nowF >= f) {\n\t\t\t\tans++;\n\t\t\t\tansList.push_back(make_pair(nowFirstItem, nowSecondItem));\n\t\t\t}\n\t\t}\n\t}\n\tsort(ansList.begin(), ansList.end());\n\n\t// output\n\tcout << ans << endl;\n\tfor (int i = 0; i < ansList.size(); i++) {\n\t\tcout << ansList[i].first << \" \" << ansList[i].second << endl;\n\t}\n\n}", "accuracy": 0.1111111111111111, "time_ms": 30, "memory_kb": 3180, "score_of_the_acc": -0.0422, "final_rank": 20 }, { "submission_id": "aoj_0326_2360521", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<string>\n#include<set>\n#include<map>\nusing namespace std;\n\nint main() {\n\tint n, f;\n\tint ans = 0;\n\tcin >> n >> f;\n\tvector<string> input(n);\n\tset<string> itemList;\n\tvector <pair<string, string> > ansList;\n\n\t// input\n\tfor (int i = 0; i < n; i++) {\n\t\tint m;\n\t\tcin >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tstring temp;\n\t\t\tcin >> temp;\n\t\t\tinput[i] += temp;\n\t\t\tinput[i] += \",\";\n\t\t\titemList.insert(temp);\n\t\t}\n\t}\n\n\t// solve\n\tauto itr = itemList.begin();\n\tauto itr_end = itemList.end();\n\titr_end--;\n\tfor (; itr != itr_end; itr++) {\n\t\tauto itr_temp = itr;\n\t\titr_temp++;\n\t\tfor (auto itr2=itr_temp; itr2 != itemList.end(); itr2++) {\n\t\t\tstring nowFirstItem = *itr;\n\t\t\tstring nowSecondItem = *itr2;\n\n\t\t\tint nowF = 0;\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tif (input[i].find(nowFirstItem) != string::npos &&\n\t\t\t\t\tinput[i].find(nowSecondItem) != string::npos) {\n\t\t\t\t\tnowF++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (nowF >= f) {\n\t\t\t\tans++;\n\t\t\t\tansList.push_back(make_pair(nowFirstItem, nowSecondItem));\n\t\t\t}\n\t\t}\n\t}\n\n\t// output\n\tcout << ans << endl;\n\tfor (int i = 0; i < ansList.size(); i++) {\n\t\tcout << ansList[i].first << \" \" << ansList[i].second << endl;\n\t}\n\n}", "accuracy": 0.1111111111111111, "time_ms": 30, "memory_kb": 3128, "score_of_the_acc": -0.0414, "final_rank": 19 }, { "submission_id": "aoj_0326_2360505", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<string>\n#include<set>\n#include<map>\nusing namespace std;\n\nint main() {\n\tint n, f;\n\tint ans = 0;\n\tcin >> n >> f;\n\t//vector<vector<string> > input(n,(vector<string>(10)));\n\tvector<string> input(n);\n\tset<string> itemList;\n\t//vector<vector<string> > ansList(n*10, (vector<string>(2)));\n\tvector <pair<string, string> > ansList;\n\n\t// input\n\tfor (int i = 0; i < n; i++) {\n\t\tint m;\n\t\tcin >> m;\n\t\tfor (int j = 0; j < m; j++) {\n\t\t\tstring temp;\n\t\t\tcin >> temp;\n\t\t\t//input[i][j] = temp;\n\t\t\tinput[i] += temp;\n\t\t\tinput[i] += \",\";\n\t\t\titemList.insert(temp);\n\t\t}\n\t}\n\n\tauto /*itr = itemList.begin();\n\twhile (itr != itemList.end()) {\n\t\tcout << *itr << \", \";\n\t\titr++;\n\t}\n\tcout << endl;*/\n\n\t// solve\n\titr = itemList.begin();\n\tfor (; itr != --itemList.end(); itr++) {\n\t\tauto itr_temp = itr;\n\t\titr_temp++;\n\t\tfor (auto itr2=itr_temp; itr2 != itemList.end(); itr2++) {\n\t\t\tstring nowFirstItem = *itr;\n\t\t\tstring nowSecondItem = *itr2;\n\t\t\t//cout << *itr << \" \" << *itr2 << endl;\n\n\t\t\tint nowF = 0;\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tif (input[i].find(nowFirstItem) != string::npos &&\n\t\t\t\t\tinput[i].find(nowSecondItem) != string::npos) {\n\t\t\t\t\tnowF++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (nowF >= f) {\n\t\t\t\tans++;\n\t\t\t\tansList.push_back(make_pair(nowFirstItem, nowSecondItem));\n\t\t\t}\n\t\t}\n\t}\n\n\t// output\n\tcout << ans << endl;\n\tfor (int i = 0; i < ansList.size(); i++) {\n\t\tcout << ansList[i].first << \" \" << ansList[i].second << endl;\n\t}\n\n}", "accuracy": 0.1111111111111111, "time_ms": 30, "memory_kb": 3040, "score_of_the_acc": -0.04, "final_rank": 18 }, { "submission_id": "aoj_0326_2336302", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define fi first\n#define se second\n\nusing ps = pair<string,string>;\n\nint main()\n{\n int n,f;\n cin >>n >>f;\n\n vector<string> name;\n map<ps,int> ct;\n rep(i,n)\n {\n int m;\n cin >>m;\n\n vector<string> s(m);\n rep(j,m)\n {\n cin >>s[j];\n name.pb(s[j]);\n }\n sort(all(s));\n\n rep(k,m)rep(j,k) ++ct[ps(s[j],s[k])];\n }\n\n sort(all(name));\n name.erase(unique(all(name)),name.end());\n\n int N = name.size();\n\n set<ps> ans;\n rep(j,N)rep(i,j)\n {\n ps p(name[i],name[j]);\n if(ct[p]>=f) ans.insert(p);\n }\n\n cout << ans.size() << endl;\n for(const auto &p:ans) cout << p.fi << \" \" << p.se << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 34588, "score_of_the_acc": -1.0825, "final_rank": 14 } ]
aoj_0327_cpp
虫食い算 足し算は筆算で簡単に計算できますが、もし、いくつかの数字が欠けていたら、欠けている数字を埋めるのは簡単でしょうか? 例えば、以下のような筆算において、1から9の数字が一度しか現れないという条件があるとき、CとEのマスに入る数字はいくつになるでしょう? この場合、Cに入るのは8,Eに入るのは5が正解となります。このように、数字がいくつか欠けている演算を虫食い算と呼びます。 1から9の数字が一度しか現れないという条件はそのままで、以下のようにもっとたくさんの数字が欠けていたら、正解となる数字の埋め方は一通りしかないのでしょうか? 実は、必ず一通りに決まるとは限りません。 上の図のような形をした虫食い算の、AからIの各マスの情報が与えられたとき、正しい埋め方が何通りあるかを出力するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 A B C D E F G H I 1行に、虫食い算の A から I のマスに入っている数字の情報が与えられる。ただし、与えられた値が -1 のときは、そのマスの数字が欠けていることを表す。-1 以外の値は、1 から 9 の整数のいずれかで、それらの間に重複はない。 Output 正しい埋め方が何通りあるかを1行に出力する。 Sample Input 1 7 6 -1 1 -1 9 2 3 4 Sample Output 1 1 Sample Input 2 7 6 5 1 8 9 2 3 4 Sample Output 2 0 Sample Input 3 -1 -1 -1 -1 -1 -1 8 4 6 Sample Output 3 12 Sample Input 4 -1 -1 -1 -1 -1 -1 -1 -1 -1 Sample Output 4 168
[ { "submission_id": "aoj_0327_11004401", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, l, n) for(int i = int(l); i < int(n); i++)\n#define ll long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate<class T> bool chmin(T &a, T b) {if(a > b) {a = b; return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a < b) {a = b; return true;} return false;}\ntemplate<class T> using spq = priority_queue<T, vector<T>, greater<T>>;\n\n// bool -> Yes/No\nstring answer(bool b) {return b ? \"Yes\" : \"No\";}\n\nvoid fix(int k) {cout << fixed << setprecision(k);}\n\nconst int inf = 2e9;\nconst long long INF = 2e18;\nconst long double eps = 1e-12;\nconst long double pi = acos(-1);\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};\n\nint num[4][3];\n\nint judge(int i, int j, int k) {\n int sum = i + j + k;\n if(sum >= 1000) return 0;\n string s[4];\n s[0] = to_string(i); s[1] = to_string(j);\n s[2] = to_string(k); s[3] = to_string(sum);\n int cnt[10];\n rep(i, 0, 10) cnt[i] = 0;\n rep(t, 0, 4) {\n int len = min(3, t + 1);\n rep(m, 0, len) {\n int c = s[t][m] - '0';\n if(c == 0) return 0;\n if(num[t][m] != -1 && num[t][m] != c) return 0;\n cnt[c]++;\n if(cnt[c] > 1) return 0;\n }\n }\n return 1;\n}\n\nvoid main_program() {\n cin >> num[0][0] >> num[1][0] >> num[1][1];\n cin >> num[2][0] >> num[2][1] >> num[2][2];\n cin >> num[3][0] >> num[3][1] >> num[3][2];\n int ans = 0;\n rep(i, 1, 10) rep(j, 10, 100) rep(k, 100, 1000) {\n ans += judge(i, j, k);\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int T = 1;\n //cin >> T;\n while(T--) {\n main_program();\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3528, "score_of_the_acc": -1.5217, "final_rank": 20 }, { "submission_id": "aoj_0327_8428262", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint answer=0;\nvoid judge(int a[],set<int> b,int d){\n while(d<9&&a[d]!=-1){\n d+=1;\n }\n if(d!=9){\n for(auto p:b){\n set<int> b2=b;\n a[d]=p;\n b2.erase(p);\n judge(a,b2,d+1);\n a[d]=-1;\n }\n }else{\n if(a[0]+a[1]*10+a[2]+a[3]*100+a[4]*10+a[5]==a[6]*100+a[7]*10+a[8]){\n answer+=1;\n }\n }\n return;\n}\nint main(void){\n int a[9];\n set<int> b;\n for(int i=0;i<9;i+=1){\n b.insert(i+1);\n }\n for(int i=0;i<9;i+=1){\n cin>>a[i];\n if(a[i]!=-1){\n b.erase(a[i]);\n }\n }\n judge(a,b,0);\n cout<<answer<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3436, "score_of_the_acc": -1.0994, "final_rank": 17 }, { "submission_id": "aoj_0327_7076189", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define all(a) a.begin(),a.end()\n\n\nvoid yn(bool n)\n{\n\tif(n)\n\t{\n\t\tcout<<\"yes\"<<endl;\n\t}\n\telse\n\t{\n\t\tcout<<\"no\"<<endl;\n\t}\n\treturn;\n}\n\n\nint main()\n{\n\tauto all_in=vector<int>();\n\tfor(int i=0; i<9; i++)\n\t{\n\t\tint a;\n\t\tcin>>a;\n\t\tall_in.push_back(a);\n\t}\n\n\tauto unused=vector<int>();\n\tfor(int i=1; i<=9; i++)\n\t{\n\t\tbool cnt=true;\n\t\tfor(int t=0; t<10; t++)\n\t\t{\n\t\t\tif(all_in[t]==i)\n\t\t\tcnt=false;\n\t\t}\n\t\tif(cnt)\n\t\t{\n\t\t\tunused.push_back(i);\n\t\t}\n\t}\n\tint ans=0;\n\tdo\n\t{\n\t\tauto ijiru=all_in;\n\t\tfor(int i=0; i<unused.size(); i++)\n\t\t{\n\t\t\tfor(int t=0; t<9; t++)\n\t\t\t{\n\t\t\t\tif(ijiru[t]==-1)\n\t\t\t\t{\n\t\t\t\t\tijiru[t]=unused[i];\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint sum=ijiru[0]+ijiru[1]*10+ijiru[2]+ijiru[3]*100+ijiru[4]*10+ijiru[5];\n\t\tif(sum==ijiru[6]*100+ijiru[7]*10+ijiru[8])\n\t\t{\n\t\t\tans++;\n\t\t}\n\t}while(next_permutation(all(unused)));\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.8872, "final_rank": 14 }, { "submission_id": "aoj_0327_4309697", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <cstdlib>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <math.h>\n#include <random>\n#include <time.h>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775808\n#define LL_MAX 9223372036854775807\n\nint n[9];\n\nint solve(int now, vector<int> m, vector<bool> b){\n if(now == 9){\n if(m[0] + 10*m[1]+m[2] +100*m[3]+10*m[4]+m[5] == 100*m[6]+10*m[7]+m[8]) return 1;\n return 0;\n }\n if(n[now] != -1) return solve(now+1, m, b);\n\n int re = 0;\n for(int i=0; i<9; i++){\n if(b[i] == true) continue;\n b[i] = true;\n m[now] = i+1;\n re += solve(now+1, m, b);\n b[i] = false;\n m[now] = -1;\n }\n return re;\n}\n\nint main(){\n \n vector<int> m;\n vector<bool> b;\n for(int i=0; i<9; i++) b.push_back(false);\n\n for(int i=0; i<9; i++){\n cin >> n[i];\n m.push_back(n[i]);\n if(n[i] != -1) b[n[i]-1] = true;\n }\n\n cout << solve(0, m, b) << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3172, "score_of_the_acc": -0.761, "final_rank": 12 }, { "submission_id": "aoj_0327_4180187", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main(){\n int z[9], cnt = 0;\n int a, b, c, d, e, f, g, h, i;\n\n for(int k = 0; k < 9; k++) cin >> z[k];\n\n for(a = 1; a <= 9; a++){\n if(z[0] == -1 || z[0] == a){\n for(b = 1; b <= 9; b++){\n if((z[1] == -1 || z[1] == b) && a != b){\n for(c = 1; c <= 9; c++){\n if((z[2] == -1 || z[2] == c) && c != a && c != b){\n for(d = 1; d <= 9; d++){\n if((z[3] == -1 || z[3] == d) && d != a && d != b && d != c){\n for(e = 1; e <= 9; e++){\n if((z[4] == -1 || z[4] == e) && e != a && e != b && e != c && e != d){\n for(f = 1; f <= 9; f++){\n if((z[5] == -1 || z[5] == f) && f != a && f != b && f != c && f != d && f != e){\n for(g = 1; g <= 9; g++){\n if((z[6] == -1 || z[6] == g) && g != a && g != b && g != c && g != d && g != e && g != f){\n for(h = 1; h <= 9; h++){\n if((z[7] == -1 || z[7] == h) && h != a && h != b && h != c && h != d && h != e && h != f && h != g){\n for(i = 1; i <= 9; i++){\n if((z[8] == -1 || z[8] == i) && i != a && i != b && i != c && i != d && i != e && i != f && i != g && i != h){\n int p[9];\n p[0] = a;\n p[1] = b;\n p[2] = c;\n p[3] = d;\n p[4] = e;\n p[5] = f;\n p[6] = g;\n p[7] = h;\n p[8] = i;\n sort(p, p + 8);\n if(p[0] != p[1] && p[1] != p[2] && p[2] != p[3] && p[3] != p[4] && p[4] != p[5] && p[5] != p[6] && p[6] != p[7] && p[7] != p[8]){\n if((a + c + f + b * 10 + e * 10 + d * 100) == (i + h * 10 + g * 100)) cnt++;\n }\n\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n }\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3168, "score_of_the_acc": -0.6689, "final_rank": 10 }, { "submission_id": "aoj_0327_3931110", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint num[10];\nint a = 0;\n\nint dfs(int i) {\n\tif (i == 9) {\n\t\tint s[10] = {};\n\t\tfor (int j = 0; j < 9; j++) {\n\t\t\ts[num[j]]++;\n\t\t\tif (s[num[j]] > 1) return 0;\n\t\t}\n\t\n\t\tint a = num[0];\n\t\tint b = num[1] * 10 + num[2];\n\t\tint c = num[3] * 100 + num[4] * 10 + num[5];\n\t\tint d = num[6] * 100 + num[7] * 10 + num[8];\n\t\t\n\t\tif (a + b + c == d) return 1;\n\t\telse return 0;\n\t}\n\t\n\tint d = 0;\n\t\n\tif (num[i] != -1) {\n\t\td += dfs(i + 1);\n\t}\n\telse {\n\t\tfor (int j = 1; j < 10; j++) {\n\t\t\tnum[i] = j;\n\t\t\td += dfs(i + 1);\n\t\t}\n\t\tnum[i] = -1;\n\t}\n\t\n\treturn d;\n}\n\nint main() {\n\t\n\tfor (int i = 0; i < 9; i++) {\n\t\tcin >> num[i];\n\t\tif (num[i] == -1) a++;\n\t}\n\t\n\tif (a == 9) {\n\t\tcout << 168 << endl;\n\t}\n\telse {\n\t\tcout << dfs(0) << endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3096, "score_of_the_acc": -1.4462, "final_rank": 19 }, { "submission_id": "aoj_0327_3928907", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint A[9];\nint B[9];\n\nbool check(int* arr){\n\treturn arr[0] + arr[2] + arr[5] + (arr[1] + arr[4])*10 + arr[3]*100 == arr[6]*100 + arr[7]*10 + arr[8];\n}\n\nint perm(vector<int> v,vector<int> idx,int* arr,int ans=0){\n\tif(v.empty()){\n\t\tif(check(arr)){\n\t\t\treturn ans + 1;\n\t\t}\n\t\telse{\n\t\t\treturn ans;\n\t\t}\n\t}\n\tfor(int i = 0; i < v.size(); i++){\n\t\tarr[idx[idx.size()-1]] = v[i];\n\t\tvector<int> idx2 = idx;\n\t\tvector<int> v2 = v;\n\t\tidx2.pop_back();\n\t\tv2.erase(v2.begin()+i);\n\t\tans = perm(v2,idx2,arr,ans);\n\t}\n\treturn ans;\n}\n\nint main(){\n\tvector<int> v = vector<int>(9);\n\tvector<int> idx = vector<int>();\n\tfor(int i = 0; i < 9; i++){\n\t\tv[i] = i+1;\n\t}\n\tfor(int i = 0; i < 9; i++){\n\t\tcin >> A[i];\n\t\tB[i] = A[i];\n\t\tif(A[i] != -1){\n\t\t\tfor(int j = 0; j < v.size(); j++){\n\t\t\t\tif(v[j] == A[i]){\n\t\t\t\t\tv.erase(v.begin()+j);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tidx.push_back(i);\n\t\t}\n\t}\n\tcout << perm(v,idx,B) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3156, "score_of_the_acc": -0.8274, "final_rank": 13 }, { "submission_id": "aoj_0327_3524579", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define double long double\n#define INF 1e18\nusing namespace std;\nint a[9], used[9], ans = 0;\n\nvoid calc() {\n int _p = a[0]+a[2]+a[5], p =_p%10; // 1\n int _q = _p/10+a[1]+a[4], q = _q%10; // 10\n int _r = _q/10+a[3], r = _r%10; // 100\n if (p==a[8] && q==a[7] && r==a[6]) ans++;\n}\n\nvoid dfs(int x) {\n if (x == 9) {\n calc();\n } else if (a[x] != -1) {\n dfs(x+1);\n } else {\n for(int i=0;i<9;i++){\n if(used[i]==1) continue;\n used[i]=1, a[x]=i+1;\n dfs(x+1);\n used[i]=0, a[x]=-1;\n } \n }\n}\n\nsigned main() {\n for (int i = 0; i < 9; i++) {\n cin >> a[i];\n if (a[i] != -1) used[a[i]-1]=1;\n }\n dfs(0);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3120, "score_of_the_acc": -0.4769, "final_rank": 6 }, { "submission_id": "aoj_0327_3519223", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint a[10];\nint num[10];\nint cnt;\nbool flag(){\n for(int i=0;i<9;i++){\n if(a[i]==-1) return false;\n }\n return true;\n}\nvoid dfs(int k){\n for(int i=k;i<9;i++){\n if(a[i]==-1){\n for(int j=1;j<10;j++){\n\tif(num[j]==0){\n\t a[i]=j;\n\t num[j]=1;\n\t dfs(i);\n\t num[j]=0;\n\t a[i]=-1;\n\t}\n }\n }\n if(i==8 && flag()){\n if(a[0]+a[1]*10+a[2]+a[3]*100+a[4]*10+a[5]==a[6]*100+a[7]*10+a[8]){\n\t//cout<<a[0]<<\" \"<<a[1]<<\" \"<<a[2]<<\" \"<<a[3]<<\" \"<<a[4]<<\" \"<<a[5]<<\" \"<<a[6]<<\" \"<<a[7]<<\" \"<<a[8]<<endl;\n\tcnt++;\n }\n }\n }\n}\n \nint main(){\n for(int i=0;i<9;i++){\n cin>>a[i];\n num[a[i]]=1;\n }\n dfs(0);\n cout<<cnt<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3120, "score_of_the_acc": -1.2161, "final_rank": 18 }, { "submission_id": "aoj_0327_3228419", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> V;\ntypedef pair<ll,ll> P;\ntypedef map<ll,ll> M;\n\n#define REP(i,n) for(ll (i) = 0; (i) < (n); ++(i))\n\n\nint main(){\n V v(9);\n for(auto& x : v)\n cin >> x;\n\n int flag = 0;\n for(auto& x : v)\n if(x != -1)\n flag |= (1<<x);\n V nouse;\n REP(i,10)\n if(i != 0 && (flag & (1<<i)) == 0)\n nouse.push_back(i);\n\n\n V nouse2;\n REP(i,9)if(v[i] == -1)nouse2.push_back(i);\n\n ll ans = 0;\n\n V iot(nouse.size());\n iota(iot.begin(), iot.end(), 0);\n do{\n V values(9);\n REP(i,9)\n if(v[i] != -1)\n values[i] = v[i];\n\n REP(i, nouse.size()){\n values[nouse2[i]] = nouse[iot[i]];\n }\n\n int val = values[0] + values[2] + values[5] - values[8];\n val += 10 * (values[1] + values[4] - values[7]);\n val += 100 * (values[3] - values[6]);\n\n if(!val)\n ++ans;\n\n }while(next_permutation(iot.begin(), iot.end()));\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3148, "score_of_the_acc": -0.5128, "final_rank": 8 }, { "submission_id": "aoj_0327_3227341", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <cstdlib>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <math.h>\n#include <random>\n#include <time.h>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775808\n#define LL_MAX 9223372036854775807\n\nint n[9];\n\nint solve(int now, vector<int> m, vector<bool> b){\n if(now == 9){\n if(m[0] + 10*m[1]+m[2] +100*m[3]+10*m[4]+m[5] == 100*m[6]+10*m[7]+m[8]) return 1;\n return 0;\n }\n if(n[now] != -1) return solve(now+1, m, b);\n\n int re = 0;\n for(int i=0; i<9; i++){\n if(b[i] == true) continue;\n b[i] = true;\n m[now] = i+1;\n re += solve(now+1, m, b);\n b[i] = false;\n m[now] = -1;\n }\n return re;\n}\n\nint main(){\n \n vector<int> m;\n vector<bool> b;\n for(int i=0; i<9; i++) b.push_back(false);\n\n for(int i=0; i<9; i++){\n cin >> n[i];\n m.push_back(n[i]);\n if(n[i] != -1) b[n[i]-1] = true;\n }\n\n cout << solve(0, m, b) << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3168, "score_of_the_acc": -0.7559, "final_rank": 11 }, { "submission_id": "aoj_0327_3160952", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n vector<int> v(9);\n for(int i = 0; i < 9; ++i) {\n cin >> v[i];\n }\n\n function<int(int)> solve = [&] (int i) {\n int res = 0;\n if(i == 6) {\n int r = v[0] + 10 * v[1] + v[2] + 100 * v[3] + 10 * v[4] + v[5];\n bool b = true;\n vector<int> cnt(10);\n for(int j = 0; j < 6; ++j) {\n cnt[v[j]] += 1;\n }\n for(int j = 0; j < 3; ++j) {\n int d = r % 10;\n r /= 10;\n b &= (d == v[8 - j] || v[8 - j] == -1) && d != 0;\n cnt[d] += 1;\n }\n res = b & (r == 0) & (*max_element(begin(cnt), end(cnt)) <= 1);\n } else {\n if(v[i] == -1) {\n for(int d = 1; d <= 9; ++d) {\n v[i] = d;\n res += solve(i + 1);\n v[i] = -1;\n }\n } else {\n res = solve(i + 1);\n }\n }\n return res;\n };\n\n cout << solve(0) << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3104, "score_of_the_acc": -0.4999, "final_rank": 7 }, { "submission_id": "aoj_0327_3045368", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<n;++i)\n#define rrep(i,n) for(int i=n-1;i>=0;--i)\n#define REP(i,a,b) for(int i=a;i<b;i++)\n#define yesno(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define vi vector<int>\n#define pb push_back\n#define i197 1000000007\n#define MAX_N 200002\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int,int> Pii;\ntypedef pair<Pii,int> Piii;\ntypedef pair<string,string> Pss;\nconst int inf=1000000000;\nstruct edge{\n\tint myc,to,c,cost;\n};\nstruct pos{\n\tint to,cost,color;\n};\nint dy[]={0, 0, 1, -1};\nint dx[]={1, -1, 0, 0};\nint f[MAX_N]={};\nint b[MAX_N]={};\nbool dp[MAX_N]={};\nvector<Pss> Vs,Vs2;\n\nint main() {\n\tint a,b,c,d,e,f,g,h,i;\n\tint total=0;\n\tcin>>a>>b>>c>>d>>e>>f>>g>>h>>i;\n\trep(j,1000000){\n\t\tint j1=j;\n\t\tint f1=j1%10;\n\t\tj1/=10;\n\t\tint e1=j1%10;\n\t\tj1/=10;\n\t\tint d1=j1%10;\n\t\tj1/=10;\n\t\tint c1=j1%10;\n\t\tj1/=10;\n\t\tint b1=j1%10;\n\t\tint a1=j1/10;\n\t\tint r=a1+c1+b1*10+d1*100+e1*10+f1;\n\t\tint g1=r/100;\n\t\tint i1=r%10;\n\t\tint h1=(r/10)%10;\n\t\tif(a!=a1&&a>0)continue;\n\t\tif(b!=b1&&b>0)continue;\n\t\tif(c!=c1&&c>0)continue;\n\t\tif(d!=d1&&d>0)continue;\n\t\tif(e!=e1&&e>0)continue;\n\t\tif(f!=f1&&f>0)continue;\n\t\tif(g!=g1&&g>0)continue;\n\t\tif(h!=h1&&h>0)continue;\n\t\tif(i!=i1&&i>0)continue;\n\n\t\tint s[9]={a1,b1,c1,d1,e1,f1,g1,h1,i1};\n\t\tsort(s,s+9);\n\t\tbool flg=true;\n\t\trep(k,9){\n\t\t\tif(s[k]!=k+1)flg=false;\n\t\t}\n\t\tif(flg)total++;\n\t}\n\tcout<<total<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3120, "score_of_the_acc": -0.6508, "final_rank": 9 }, { "submission_id": "aoj_0327_2733752", "code_snippet": "#include <stdio.h>\n#define rep(i, n) for(int i = 0; i < n; ++i)\n\nint count, flag[10], a[9];\n\nint saiki(int n) {\n int i;\n if(n == 10) {\n if((a[0] + a[2] + a[5]) + (a[1] + a[4]) * 10 + a[3] * 100 == a[8] + a[7] * 10 + a[6] * 100) ++count;\n return 0;\n }\n if(a[n] != -1) saiki(n + 1);\n else {\n for(i = 1; i <= 9; ++i) {\n if(flag[i]) {\n flag[i] = 0, a[n] = i;\n saiki(n + 1);\n flag[i] = 1, a[n] = -1;\n }\n }\n }\n return 0;\n}\n\nint main(void) {\n int i, j, k;\n count = 0;\n rep(i, 9) scanf(\"%d\", &a[i]);\n rep(i, 10) flag[i] = 1;\n rep(i, 9) if(a[i] != -1) flag[a[i]] = 0;\n saiki(0);\n printf(\"%d\\n\", count);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2748, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0327_2591156", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\nint crossnum[]{1,10,1,100,10,1,100,10,1};\nint u,d;\nvoid addnum(int place,int add){\n\tif(place<6){\n\t\tu+=add;\n\t}else{\n\t\td+=add;\n\t}\n}\nvoid input(vector<int> &line,vector<int> &used){\n\tline.resize(9);\n\tused.resize(10,false);\n\tu=d=0;\n\tfor(int i=0;i<9;++i){\n\t\tcin>>line[i];\n\t\tif(line[i]>0){\n\t\t\tused[line[i]]=true;\n\t\t\taddnum(i,line[i]*crossnum[i]);\n\t\t}\n\t}\n}\n\nint func(int place,vector<int> &line,vector<int> &used){\n\tif(place==9){\n\t\treturn u==d?1:0;\n\t}\n\tint res=0;\n\tif(line[place]>0){\n\t\treturn func(place+1,line,used);\n\t}\n\tfor(int i=1;i<used.size();++i){\n\t\tif(used[i]){\n\t\t\tcontinue;\n\t\t}\n\t\taddnum(place,i*crossnum[place]);\n\t\tused[i]=true;\n\t\tres+=func(place+1,line,used);\n\t\tused[i]=false;\n\t\taddnum(place,-i*crossnum[place]);\n\t}\n\treturn res;\n}\nint main(){\n\tvector<int> line;\n\tvector<int> used;\n\tinput(line,used);\n\tcout<<func(0,line,used)<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3060, "score_of_the_acc": -0.4, "final_rank": 2 }, { "submission_id": "aoj_0327_2588783", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\n#define pb push_back\n#define rep(i, a, n) for(int i = (a); i < (n); i++)\n#define dep(i, a, n) for(int i = (a); i >= (n); i--)\n#define mod 1e9+7\n\n__attribute__((constructor))\nvoid initial() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n}\n\nint tt[10];\nint cou = 0;\n\nvoid solve(int i, string num, string str) {\n if(i == 9) {\n int a = (char)(str[0] - 48);\n int b = (char)(str[1] - 48);\n int c = (char)(str[2] - 48);\n int d = (char)(str[3] - 48);\n int e = (char)(str[4] - 48);\n int f = (char)(str[5] - 48);\n int g = (char)(str[6] - 48);\n int h = (char)(str[7] - 48);\n int ii = (char)(str[8] - 48);\n\n if((a + c + f) % 10 != ii) return;\n int t = (a + c + f) / 10;\n if((b + e + t) % 10 != h) return;\n t = (b + e + t) / 10;\n if((d + t) == g) {\n cou++;\n return;\n }\n }\n if(tt[i] != -1) {\n if(num[tt[i] - 1] == '0') {\n num[tt[i] - 1] = '1';\n solve(i + 1, num, str + (char)(48 + tt[i]));\n }\n }else {\n for(int j = 0; j < 9; j++) {\n if(num[j] == '0') {\n num[j] = '1';\n solve(i + 1, num, str + (char)(48 + j + 1));\n num[j] = '0';\n }\n }\n }\n}\n\nint main() {\n rep(i, 0, 9) cin >> tt[i];\n solve(0, \"000000000\", \"\");\n cout << cou << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3220, "score_of_the_acc": -0.9095, "final_rank": 15 }, { "submission_id": "aoj_0327_2582163", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n\tint num[9],per[9],ans = 0;\n\tfor(int i = 0;i < 9;i++) {\n\t\tcin >> num[i];\n\t\tper[i] = i + 1;\n\t}\n\tdo{\n\t\tbool flag = true;\n\t\tfor(int i = 0;i < 9;i++){\n\t\t\tif(num[i] != -1 && per[i] != num[i]) flag = false;\n\t\t}\n\t\tif((per[0] + per[2] + per[5]) % 10 != per[8]) flag = false;\n\t\tif(((per[0] + per[2] + per[5]) / 10 + per[1] + per[4]) % 10 != per[7]) flag = false;\n\t\tif(((per[0] + per[2] + per[5]) / 10 + per[1] + per[4]) / 10 + per[3] != per[6]) flag = false;\n\t\tif(flag) ans++;\n\t}while(next_permutation(per,per + 9));\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.441, "final_rank": 4 }, { "submission_id": "aoj_0327_2463279", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld = long double;\nconst ld eps = 1e-9;\n\n//// < \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\a.txt\" > \"d:\\d_download\\visual studio 2015\\projects\\programing_contest_c++\\debug\\b.txt\"\n\n\nint main() {\n\tvector<int>v(9);\n\t{\n\t\tfor (int i = 0; i < 9; ++i)cin >> v[i];\n\t}\n\tvector<int>perms(9);\n\tiota(perms.begin(), perms.end(), 0);\n\tint ans = 0;\n\tdo {\n\t\tvector<int>nums(9);\n\t\tfor (int i = 0; i < 9; ++i) {\n\t\t\tnums[perms[i]] = i+1;\n\t\t}\n\t\tbool flag = true;\n\t\tfor (int i = 0; i < 9; ++i) {\n\t\t\tif (v[i] != -1 && v[i] != nums[i])flag = false;\n\t\t}\n\t\tif (!flag)continue;\n\t\tint aa = (nums[0] + nums[2] + nums[5]) * 1+ (nums[1] + nums[4]) * 10 + nums[3] * 100;\n\t\tint bb = (nums[8]) * 1 + (nums[7]) * 10 + (nums[6]) * 100;\n\t\tif (aa == bb)ans++;\n\t} while (next_permutation(perms.begin(), perms.end()));\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3088, "score_of_the_acc": -0.4359, "final_rank": 3 }, { "submission_id": "aoj_0327_2383974", "code_snippet": "#include<iostream>\n#include<cstdio>\nusing namespace std;\nint a[10]={},b[10]={},c=1,cnt=0,j;\n\nvoid d( ){\n if(c==10&&b[7]*100+b[8]*10+b[9]==b[4]*100+(b[5]+b[2])*10+b[1]+b[3]+b[6]){\n cnt++;\n return;\n }\n if(b[c]!=0){\n c++;\n d();\n c--;\n return;\n }\n for(int i=1;i<=9;i++){\n if(a[i]==0){\n a[i]++;\n b[c]=i;\n c++;\n d();\n a[i]--;\n c--;\n b[c]=0;\n }\n }\n \n}\n\nint main(){\n int n;\n for(int i=1;i<10;i++){\n cin>>n;\n if(n>0){\n a[n]++;\n b[i]=n;\n }\n }\n d();\n cout<<cnt<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3112, "score_of_the_acc": -0.4667, "final_rank": 5 }, { "submission_id": "aoj_0327_2213170", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define r(i,n) for(int i=1;i<=n;i++)\nint main(){\nint z[9],sum=0;\nfor(int i=0;i<9;i++)cin>>z[i];\nr(a,9)if(z[0]==-1||z[0]==a)\nr(b,9)if((z[1]==-1||z[1]==b)&&a!=b)\nr(c,9)if((z[2]==-1||z[2]==c)&&c!=b&&c!=a)\nr(d,9)if((z[3]==-1||z[3]==d)&&d!=a&&d!=b&&d!=c)\nr(e,9)if((z[4]==-1||z[4]==e)&&e!=a&&e!=b&&e!=c&&e!=d)\nr(f,9)if((z[5]==-1||z[5]==f)&&f!=a&&f!=b&&f!=c&&f!=d&&f!=e)\nr(g,9)if((z[6]==-1||z[6]==g)&&g!=a&&g!=b&&g!=c&&g!=d&&g!=e&&g!=f)\nr(h,9)if((z[7]==-1||z[7]==h)&&h!=a&&h!=b&&h!=c&&h!=d&&h!=e&&h!=f&&h!=g)\nr(i,9)if(z[8]==-1||z[8]==i){\n int p[9];\n p[0]=a;p[1]=b;p[2]=c;\n p[3]=d;p[4]=e;p[5]=f;\n p[6]=g;p[7]=h;p[8]=i;\n sort(p,p+9);\n if(p[0]!=p[1]&&p[1]!=p[2]&&p[2]!=p[3]&&p[3]!=p[4]&&p[4]!=p[5]&&p[5]!=p[6]&&p[6]!=p[7]&&p[7]!=p[8]){\n if((a+c+f+b*10+e*10+d*100)==(g*100+h*10+i))sum++;\n }\n}\ncout<<sum<<endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3160, "score_of_the_acc": -1.0499, "final_rank": 16 } ]
aoj_0328_cpp
貴金属リサイクル 会津特産の貴金属であるアイヅニウムをリサイクルするPCK社は、全国各地にネットワークを持ち、たくさんの回収車でアイヅニウムを集めてきます。この会社は、処理の効率化のために、塊の重さと個数の単位を規格で定めています。 塊の重さには「ボッコ」という単位を使います。 x ボッコのアイヅニウムの重さは 2 x グラムです。宝石で例えると、「カラット」のようなものです。また、塊の個数には「マルグ」という単位を使います。 y マルグは 2 y 個です。1箱に入っている品物の個数である「ダース」のようなものです。ただし、 x と y は 0 以上の整数でなければいけません。 回収車 i は、 a i ボッコの重さのアイヅニウムを b i マルグずつ集めます。こうして集まったアイヅニウムを、炉の中に入れて溶かし、いくつかのアイヅニウムの塊を再生しますが、なるべくアイヅニウムの塊の数が少なくなるようにします。このとき、集めてきたアイヅニウムの重さの合計と、再生してできるアイヅニウムの重さの合計は変わりません。 回収車が集めたアイヅニウムの塊のボッコ単位の重さとマルグ単位の個数が与えられたとき、再生後のアイヅニウムの塊の数が最小になるような結果を求めるプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N a 1 b 1 a 2 b 2 : a N b N 1行目に、回収車の数 N (1 ≤ N ≤ 100000) が与えられる。続く N 行に、回収車 i が回収したアイヅニウムの塊の、「ボッコ」単位の重さを表す整数 a i (0 ≤ a i ≤ 100000) と「マルグ」単位の個数を表す整数 b i (0 ≤ b i ≤ 100000) が与えられる。 Output 再生した後に得られるアイヅニウムの塊の数が最小になるような、ボッコ単位の重さとマルグ単位の個数を、重さの小さい順に出力する。 Sample Input 1 3 2 1 1 3 2 2 Sample Output 1 3 0 5 0 Sample Input 2 1 100000 2 Sample Output 2 100002 0
[ { "submission_id": "aoj_0328_10945978", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,k,n) for(int i = (int)(k); i < (int)(n); i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(a) a.begin(), a.end()\n#define MS(m,v) memset(m,v,sizeof(m))\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\nconst int MOD = 1e9 + 7;\ntemplate<class T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<class T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<class T>\nistream& operator >> (istream& is, vector<T>& v)\n{\n\tfor (auto &i : v) is >> i;\n\treturn is;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, vector<T>& v)\n{\n\tconst string delimiter = \"\\n\";\n\tREP(i, v.size())\n\t{\n\t\tos << v[i];\n\t\tif (i != v.size() - 1) os << delimiter;\n\t}\n\treturn os;\n}\n/*--------------------template--------------------*/\n\nint main()\n{\n\tint n; cin >> n;\n\tvi cnt(333333);\n\tREP(i, n)\n\t{\n\t\tint a, b; cin >> a >> b;\n\t\tcnt[a + b]++;\n\t}\n\tREP(i, 333333)\n\t{\n\t\tcnt[i + 1] += cnt[i] / 2;\n\t\tcnt[i] %= 2;\n\t}\n\tREP(i, 333333)\n\t{\n\t\tif (cnt[i] == 1) cout << i << \" \" << 0 << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4432, "score_of_the_acc": -0.8839, "final_rank": 9 }, { "submission_id": "aoj_0328_9769476", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n// #include<atcoder/all>\n// using namespace atcoder;\n// using mint=atcoder::modint998244353;\n\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define int long long\n\nint dp[300009];\n\nsigned main(){\n\tint n;cin>>n;\n\n\twhile(n--){\n\t\tint a,b;cin>>a>>b;\n\t\tdp[a+b]+=1;\n\t}\n\n\tfor(int i=0;i<300000;i++){\n\t\tif(dp[i]>=2){\n\t\t\tdp[i+1]+=dp[i]/2;\n\t\t\tdp[i]%=2;\n\t\t}\n\t}\n\n\tfor(int i=0;i<300000;i++){\n\t\tif(dp[i]){\n\t\t\tcout<<i<<\" \"<<0<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4888, "score_of_the_acc": -0.9465, "final_rank": 11 }, { "submission_id": "aoj_0328_9769473", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n// #include<atcoder/all>\n// using namespace atcoder;\n// using mint=atcoder::modint998244353;\n\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define int long long\n\nint dp[200009];\n\nsigned main(){\n\tint n;cin>>n;\n\n\twhile(n--){\n\t\tint a,b;cin>>a>>b;\n\t\tdp[a+b]+=1;\n\t}\n\n\tfor(int i=0;i<200000;i++){\n\t\tif(dp[i]>=2){\n\t\t\tdp[i+1]+=dp[i]/2;\n\t\t\tdp[i]%=2;\n\t\t}\n\t}\n\n\tfor(int i=0;i<200000;i++){\n\t\tif(dp[i]){\n\t\t\tcout<<i<<\" \"<<0<<endl;\n\t\t}\n\t}\n}", "accuracy": 0.9583333333333334, "time_ms": 70, "memory_kb": 4724, "score_of_the_acc": -0.924, "final_rank": 19 }, { "submission_id": "aoj_0328_9769472", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n// #include<atcoder/all>\n// using namespace atcoder;\n// using mint=atcoder::modint998244353;\n\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define int long long\n\nint dp[150009];\n\nsigned main(){\n\tint n;cin>>n;\n\n\twhile(n--){\n\t\tint a,b;cin>>a>>b;\n\t\tdp[a+b]+=1;\n\t}\n\n\tfor(int i=0;i<150000;i++){\n\t\tif(dp[i]>=2){\n\t\t\tdp[i+1]+=dp[i]/2;\n\t\t\tdp[i]%=2;\n\t\t}\n\t}\n\n\tfor(int i=0;i<150000;i++){\n\t\tif(dp[i]){\n\t\t\tcout<<i<<\" \"<<0<<endl;\n\t\t}\n\t}\n}", "accuracy": 0.875, "time_ms": 20, "memory_kb": 3484, "score_of_the_acc": -0.1288, "final_rank": 20 }, { "submission_id": "aoj_0328_9467678", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n int a[n], b[n];\n vector<int> s(n);\n map<int, int> mp;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i];\n s[i] = a[i] + b[i];\n }\n for (int i = 0; i < n; i++) {\n if (mp[s[i]] > 0) {\n mp[s[i]]--;\n mp[s[i] + 1]++;\n int me = s[i] + 1;\n while (mp[me] >= 2) {\n mp[me] -= 2;\n mp[me + 1]++;\n me++;\n }\n } else {\n mp[s[i]]++;\n }\n }\n for (auto itr = mp.begin(); itr != mp.end(); itr++) {\n if (itr->second > 0) {\n cout << itr->first << \" \" << 0 << \"\\n\";\n }\n }\n return(0);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8272, "score_of_the_acc": -1.2858, "final_rank": 18 }, { "submission_id": "aoj_0328_9467672", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n int a[n], b[n];\n vector<int> s(n);\n map<int, int> mp;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i];\n s[i] = a[i] + b[i];\n }\n sort(s.begin(), s.end());\n for (int i = 0; i < n; i++) {\n if (mp[s[i]] > 0) {\n mp[s[i]]--;\n mp[s[i] + 1]++;\n int me = s[i] + 1;\n while (mp[me] >= 2) {\n mp[me] -= 2;\n mp[me + 1]++;\n me++;\n }\n } else {\n mp[s[i]]++;\n }\n }\n for (auto itr = mp.begin(); itr != mp.end(); itr++) {\n if (itr->second > 0) {\n cout << itr->first << \" \" << 0 << \"\\n\";\n }\n }\n return(0);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8080, "score_of_the_acc": -1.2595, "final_rank": 17 }, { "submission_id": "aoj_0328_9312955", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, a, b;\n cin >> N;\n map<ll, ll> cnt;\n rep(N) {\n cin >> a >> b;\n cnt[a+b]++;\n }\n pqg<pi> pq;\n for (auto [k, v] : cnt) {\n pq.emplace(mp(k, v));\n }\n vc<pi> ans;\n while (!pq.empty()) {\n auto [k, v] = POP(pq);\n if (v >= 2) {\n if (!pq.empty() and (pq.top().fi == k+1)) {\n auto [k2, v2] = POP(pq);\n pq.emplace(mp(k+1, v2+v/2));\n } else {\n pq.emplace(mp(k+1, v/2));\n }\n v %= 2;\n }\n if (v == 1) ans.eb(mp(k, 0));\n }\n rep(i, len(ans)) print(ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10744, "score_of_the_acc": -1.25, "final_rank": 16 }, { "submission_id": "aoj_0328_8428313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n int a[250000];\n for(int i=0;i<250000;i+=1){\n a[i]=0;\n }\n int b;\n cin>>b;\n for(int i=0;i<b;i+=1){\n int c,d;\n cin>>c>>d;\n a[c+d]+=1;\n }\n for(int i=0;i<249999;i+=1){\n a[i+1]+=a[i]/2;\n a[i]%=2;\n }\n for(int i=0;i<250000;i+=1){\n if(a[i]!=0){\n cout<<i<<\" \"<<0<<endl;\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4388, "score_of_the_acc": -0.8779, "final_rank": 8 }, { "submission_id": "aoj_0328_8325029", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main() {\n int N, sum[200017] = {};\n cin >> N;\n for (int a, b, i = 0; i < N; i++) {\n cin >> a >> b; \n sum[a+b]++;\n }\n\n for (int i = 0; i < 200016; i++) {\n sum[i+1] += sum[i] / 2;\n sum[i] %= 2;\n }\n\n for (int i = 0; i < 200017; i++) {\n if (sum[i]) {\n cout << i << \" \" << 0 << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4196, "score_of_the_acc": -0.8515, "final_rank": 7 }, { "submission_id": "aoj_0328_7073857", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nint main() {\n\tint n;\n\tcin >> n;\n\tpriority_queue<int>que;\n\trep(i, n) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tque.push(-a - b);\n\t}\n\twhile (que.size()) {\n\t\tauto p = que.top(); que.pop();\n\t\tif (que.size() && p == que.top()) {\n\t\t\tque.pop(); que.push(p - 1);\n\t\t}\n\t\telse {\n\t\t\tcout << -p << \" \" << 0 << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3740, "score_of_the_acc": -0.914, "final_rank": 10 }, { "submission_id": "aoj_0328_6965915", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0328.cc: 貴金属リサイクル\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\n/* typedef */\n\ntypedef vector<int> vi;\n\n/* global variables */\n\n/* subroutines */\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n;\n scanf(\"%d\", &n);\n\n vi ds;\n for (int i = 0; i < n; i++) {\n int a, b;\n scanf(\"%d%d\", &a, &b);\n int x = a + b;\n if (ds.size() <= x) ds.resize(x + 1);\n ds[x]++;\n }\n\n for (int i = 0, co = 0; i < ds.size() || co > 0; i++) {\n if (i == ds.size()) ds.push_back(0);\n int di = co + ds[i];\n ds[i] = di & 1;\n co = di >> 1;\n }\n\n for (int x = 0; x < ds.size(); x++)\n if (ds[x] > 0) printf(\"%d 0\\n\", x);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4056, "score_of_the_acc": -0.0823, "final_rank": 2 }, { "submission_id": "aoj_0328_6893894", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n;\n cin >> n;\n vector<ll> cnt(200020);\n for(int i = 0, a, b; i < n; i++){\n cin >> a >> b;\n cnt[a + b]++;\n }\n for(int i = 0; i + 1 < 200020; i++){\n cnt[i + 1] += cnt[i] / 2;\n if(cnt[i] & 1){\n cout << i << \" \" << 0 << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4656, "score_of_the_acc": -0.4147, "final_rank": 3 }, { "submission_id": "aoj_0328_6432535", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// {{{ Templates\n\n// clang-format off\n\n// Macros\n#define over_load_(_1,_2,_3,_4,NAME,...) NAME\n#define rep(...) over_load_(__VA_ARGS__, rep4, rep3, rep2)(__VA_ARGS__)\n#define rep2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define rep3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define rep4(i, l, r, stride) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (stride))\n#define rrep(...) over_load_(__VA_ARGS__, rrep4, rrep3, rrep2)(__VA_ARGS__)\n#define rrep2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrep3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrep4(i, l, r, stride) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (stride))\n#define len(x) (static_cast<int>((x).size()))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\n\n// Operators\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << \"(\" << p.first << \",\" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { bool is_first = true; for (auto x: v) { os << (is_first ? \"\" : \" \") << x; is_first = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { bool is_first = true; while (!v.empty()) { os << (is_first?\"\":\" \")<<v.front(); v.pop(); is_first = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { bool is_first = true; while (!v.empty()) { os << (is_first?\"\":\" \") << v.top(); v.pop(); is_first=false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { rep (i, len(v)) os << v[i] << (i == len(v) - 1 ? \"\" : \" \"); return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (const auto &vec: v) { os << vec << '\\n'; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { rep (i, len(v)) os << v[i] << (i == len(v) - 1 ? \"\" : \" \"); return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_first = true; for (T x: v) { os << (is_first ? \"\" : \" \") << x; is_first = false; } return os; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in: v) { is >> in; } return is; }\n\n// For debug macro\nint find_comma_not_bracketed(string_view s){ stack<char> bs; string lbs = \"({[\", rbs = \")}]\"; for (size_t i = 0; i < s.size(); i++) { if (lbs.find(s[i]) != string::npos) bs.push(s[i]); if (rbs.find(s[i]) != string::npos and !bs.empty()) bs.pop(); if (s[i] == ',' and bs.empty()) return i; } return s.size(); }\ntemplate <typename T, typename... Ts> void debug_function(string_view name, const T &a, Ts &&...rest) { int end = find_comma_not_bracketed(name); cerr << name.substr(0, end) << \":\" << a; if constexpr (sizeof...(rest) == 0) { cerr << '\\n'; } else { cerr << ' '; debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<Ts>(rest)...); } }\n\n// Functions\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\n\n// Structs\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\n// Type aliases\nusing ull = unsigned long long;\nusing ll = long long;\nusing pll = pair<ll, ll>;\nusing pii = pair<int, int>;\n\n// Literals\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, 1, -1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { 1, 0, 0, -1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n\n// clang-format on\n\n// }}} Templates\n\n\n\nint main() {\n int n;\n cin >> n;\n\n map<int, int> cnt;\n rep(i, n) {\n int a, b;\n cin >> a >> b;\n\n cnt[a + b]++;\n }\n\n for (auto &[val, count]: cnt) {\n int carry = count / 2;\n count %= 2;\n\n if (carry > 0)\n cnt[val + 1] += carry;\n // debug(val, count);\n }\n\n for (auto [val, count]: cnt) {\n if (count == 0)\n continue;\n\n cout << val << ' ' << 0 << newl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7580, "score_of_the_acc": -0.8159, "final_rank": 6 }, { "submission_id": "aoj_0328_6040788", "code_snippet": "#pragma region my_template\n#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <deque>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <iterator>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\nusing pi = pair<int, int>;\nusing pl = pair<ll, ll>;\nusing ti = tuple<int, int, int>;\nusing tl = tuple<ll, ll, ll>;\nusing vi = vector<int>;\nusing vpi = vector<pi>;\nusing vti = vector<ti>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vpl = vector<pl>;\nusing vtl = vector<tl>;\nusing vvl = vector<vl>;\n\n#define range(i, l, r) for(int i = (int)(l); i < (int)(r); i++)\n#define rrange(i, l, r) for(int i = (int)(r)-1; i >= (int)(l); i--)\n#define rep(i, n) range(i, 0, n)\n#define rrep(i, n) rrange(i, 0, n)\n#define len(a) ((int)(a).size())\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define elif else if\n\nnamespace io {\n template<typename T>\n istream &operator >> (istream &in, vector<T> &a){\n for(T &x: a) in >> x;\n return in;\n }\n template<typename T, typename U>\n istream &operator >> (istream &in, pair<T, U> &a){\n in >> a.first >> a.second;\n return in;\n }\n template<typename T>\n ostream &operator << (ostream &out, const vector<T> &a) {\n rep(i, len(a)) out << a[i] << (i == len(a)-1 ? \"\" : \" \");\n return out;\n }\n template<typename T, typename U>\n ostream &operator << (ostream &out, const pair<T, U> &a){\n out << a.first << \" \" << a.second;\n return out;\n }\n inline void print() { cout << \"\\n\"; }\n template <typename T, typename ...U>\n inline void print(const T &t, const U &...u) {\n cout << t;\n if (sizeof...(u)) cout << \" \";\n print(u...);\n }\n}\nusing namespace io;\n\ntemplate<typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<typename T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nconstexpr int INF = 1e9;\nconstexpr ll LINF = 1e18;\nconstexpr int MOD = 1e9+7;\n//constexpr int MOD = 998244353;\n\n#pragma endregion\n\nvoid solve() {\n int n; cin >> n;\n vi s(200200);\n rep(_, n) {\n int a, b; cin >> a >> b;\n s[a+b]++;\n }\n rep(i, 200020) {\n s[i+1] += s[i]/2;\n s[i] %= 2;\n }\n rep(i, 200020) {\n if (s[i]) print(i, 0);\n }\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n //cout << fixed << setprecision(15);\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3876, "score_of_the_acc": -0.0576, "final_rank": 1 }, { "submission_id": "aoj_0328_5730273", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nint tmp[200020];\nsigned main(){\n\tint n,a,b;\n\tcin>>n;\n\twhile(cin>>a>>b)\n\t\ttmp[a+b]++;\n\tfor(int i=0;i<200019;i++){\n\t\ttmp[i+1]+=tmp[i]/2;\n\t\tif(tmp[i]%2)\n\t\t\tcout<<i<<' '<<0<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 5000, "score_of_the_acc": -0.9619, "final_rank": 12 }, { "submission_id": "aoj_0328_5057219", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstatic const int PMAX = 100000;\nvector <int> T(2 * PMAX + 20);\nint main(){\nint N, a, b;\ncin >> N;\nfor ( int i = 0; i < N; i++ ){\ncin >> a >> b;\nT[a + b]++;\n}\nfor ( int i = 0; i < 2 * PMAX + 20 - 1; i++ ){\nT[i + 1] += T[i] / 2;\nT[i] %= 2;\nif ( T[i] ) cout << i << \" \" << 0 << endl;\n}\nreturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3456, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0328_5022757", "code_snippet": "#include<iostream>\nusing namespace std;\nint N;\nint c[2<<17];\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint a,b;cin>>a>>b;\n\t\tc[a+b]++;\n\t}\n\tfor(int i=0;i+1<2<<17;i++)\n\t{\n\t\tc[i+1]+=c[i]/2;\n\t\tif(c[i]%2)cout<<i<<\" 0\"<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4140, "score_of_the_acc": -1.0939, "final_rank": 15 }, { "submission_id": "aoj_0328_4917852", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\ntypedef long long ll;\n#define INF 1000000000\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n int n; cin>>n;\n vector<int> v(303030,0);\n rep(i,n){\n int a,b; cin>>a>>b;\n v[a+b]++;\n }\n\n rep(i,303030-1){\n v[i+1] += v[i] / 2;\n v[i] %= 2;\n\n if(v[i] == 1){\n cout << i << \" \" << 0 << endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4164, "score_of_the_acc": -0.7221, "final_rank": 4 }, { "submission_id": "aoj_0328_4917799", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<int> cnt(250001);\n for(int i=0;i<n;i++){\n int a, b;\n cin >> a >> b;\n cnt[a+b]++; \n }\n for(int i=0;i<250000;i++){\n cnt[i+1] += cnt[i]/2;\n cnt[i] %= 2;\n }\n for(int i=0;i<=250000;i++){\n if(cnt[i]){\n cout << i << \" \" << 0 << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3900, "score_of_the_acc": -1.0609, "final_rank": 14 }, { "submission_id": "aoj_0328_4917749", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n#define LOCAL\nusing namespace std;\n//using namespace atcoder;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#define rep(i,n) for(int i=0; i<(n); i++)\nusing ll = long long;\n//#define int long long\nusing P = pair<int,int>;\n//#########################################\nint main(){\n int n;cin >> n;\n vector<int>cnt(220000);\n int ret = 0;\n rep(i,n){\n int a,b;cin >> a >> b;\n cnt[a+b]++;\n }\n \tfor(int i = 0; i < 220000; i++){\n\t\tif(cnt[i] != 0){ \n\t\t\tint tmp = cnt[i];\n\t\t\tcnt[i] = 0;\n\t\t\tfor(int k = 0; tmp != 0;k++,tmp /= 2){\n\t\t\t\tif(tmp%2 == 1){\n\t\t\t\t\tcnt[i+k]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n rep(i,220000){\n if(cnt[i])cout << i << \" \" << '0' << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3896, "score_of_the_acc": -0.8104, "final_rank": 5 } ]
aoj_0329_cpp
完全平等二国間貿易 サイバースペースにあるアイヅ国はワカマツ国と情報貿易を行っています。2つの国はお互いに有用なデータを交換することで経済発展を遂げています。博愛と平等、そして何よりも会津地方の古い言葉である、「ならぬことはならぬものです」を国是とする両国は、定期的に貿易状況の調査を行っています。 調査では、バイト単位でアイヅ国から見たデータ流入量から流出量を引いた値を、1ナノ秒ごとに求めた表が与えられます。その表から、値の総和が0になる最長の区間を見つけます。この区間が長いほど、平等性が保たれていると判断します。 貿易状況が記録された表が与えられたとき、値の総和が0になる最長の区間の長さを求めるプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N d 1 d 2 : d N 1行目に、表に書かれた値の数 N (1 ≤ N ≤ 200000) が与えられる。続く N 行に、表の i 行目に書かれた値を示す整数 d i (-10 9 ≤ d i ≤ 10 9 ) が与えられる。 Output 表から得られる、総和が0になる最長の区間の長さを1行に出力する。そのような区間が存在しない場合、「0」を1行に出力する。 Sample Input 1 5 18 102 -155 53 32 Sample Output 1 3 入力例1では、2行目から4行目までの値の総和が0になるので、最長の区間の長さが3になる。 Sample Input 2 4 1 1 -1 -1 Sample Output 2 4 入力例2では、2行目から3行目の総和が0になるが、1行目から4行目までの値の総和も0になるので、最長の区間の長さが4になる。
[ { "submission_id": "aoj_0329_11030754", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector<ll> d(N);\n\trep(i, 0, N) cin >> d[i];\n\t\n\trep(i, 1, N) d[i] += d[i - 1];\n\t\n\tmap<ll, int> mini;\n\tmini[0] = -1;\n\tint ans = 0;\n\trep(i, 0, N) {\n\t\tif (mini.count(d[i])) ans = max(ans, i - mini[d[i]]);\n\t\telse mini[d[i]] = i;\n\t}\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 16948, "score_of_the_acc": -0.3112, "final_rank": 5 }, { "submission_id": "aoj_0329_10853996", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,k,n) for(int i = (int)(k); i < (int)(n); i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(a) a.begin(), a.end()\n#define MS(m,v) memset(m,v,sizeof(m))\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<ll> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\nconst int MOD = 1e9 + 7;\ntemplate<class T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<class T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<class T>\nistream& operator >> (istream& is, vector<T>& v)\n{\n\tfor (auto &i : v) is >> i;\n\treturn is;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, vector<T>& v)\n{\n\tconst string delimiter = \"\\n\";\n\tREP(i, v.size())\n\t{\n\t\tos << v[i];\n\t\tif (i != v.size() - 1) os << delimiter;\n\t}\n\treturn os;\n}\n/*--------------------template--------------------*/\n\nint main()\n{\n\tcin.sync_with_stdio(false); cout << fixed << setprecision(10);\n\tint n; cin >> n;\n\tmap<ll, int> mp;\n\tvi v(n); cin >> v;\n\tvi s(n + 1);\n\tint ans = 0;\n\tmp[0] = 0;\n\tREP(i, n)\n\t{\n\t\ts[i + 1] = s[i] + v[i];\n\t\tif (mp.count(s[i + 1]) == 0) mp[s[i + 1]] = i + 1;\n\t\telse chmax(ans, i + 1 - mp[s[i + 1]]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 18564, "score_of_the_acc": -0.3653, "final_rank": 6 }, { "submission_id": "aoj_0329_9769318", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n// #include<atcoder/all>\n// using namespace atcoder;\n// using mint=atcoder::modint998244353;\n\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define int long long\n\nsigned main(){\n\tint n;cin>>n;\n\tvector<int> d(n);\n\tfor(auto&&e:d)cin>>e;\n\n\tmap<int,vector<int>> vec;\n\n\tint sum=0;\n\tvec[sum].push_back(0);\n\n\tfor(int i=0;i<n;i++){\n\t\tsum+=d[i];\n\n\t\tvec[sum].push_back(i+1);\n\t}\n\n\tint ans=0;\n\n\tfor(auto&&[e,v]:vec){\n\t\tans=max(ans,v.back()-v.front());\n\t}\n\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 26352, "score_of_the_acc": -0.9591, "final_rank": 13 }, { "submission_id": "aoj_0329_9470634", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n long long d[n + 1];\n long long sum[n + 1] = {};\n vector<pair<long long, int>> data(n + 1);\n data[0] = {0, 0};\n for (int i = 1; i < n + 1; i++) {\n cin >> d[i];\n sum[i] = sum[i - 1] + d[i];\n data[i] = {sum[i], i};\n }\n sort(data.begin(), data.end());\n vector<long long> data2(n + 1);\n for (int i = 0; i <= n; i++) {\n data2[i] = data[i].first;\n }\n int ans = 0;\n for (int i = 0; i <= n; i++) {\n int pos = lower_bound(data2.begin(), data2.end(), sum[i]) - data2.begin();\n if (pos <= n) {\n ans = max(ans, i - data[pos].second);\n }\n }\n cout << ans << \"\\n\";\n return(0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 10964, "score_of_the_acc": -0.2222, "final_rank": 3 }, { "submission_id": "aoj_0329_9463727", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nhttps://stackoverflow.com/questions/5534063/maximum-subarray-whose-sum-equals-0\nhttps://www.geeksforgeeks.org/find-the-largest-subarray-with-0-sum/\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 1000000000;\n\nconst int MAX_N = 200000;\nstatic int64_t vect[MAX_N];\nstatic int64_t P[MAX_N];\n//------------------------------------------------------------------------------\nint solve(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (N == 1) return vect[0] == 0;\n //--------------------------------------------------------------------------\n // init:\n P[0] = vect[0];\n for (int i=1; i<N; ++i) P[i] = vect[i] + P[i-1];\n //printf(\"P: \"); for (int i=0; i<N; ++i) printf(\"%d \",P[i]); printf(\"\\n\");\n //--------------------------------------------------------------------------\n // compute:\n unordered_map<int64_t,int> index;\n int res = 0;\n for (int i=0; i<N; ++i)\n {\n if (P[i] == 0) res = i+1;\n else if (index.find( P[i] ) == index.end())\n {\n index[ P[i] ] = i;\n }\n else\n {\n res = max(res, i - index[ P[i] ]);\n }\n }\n //--------------------------------------------------------------------------\n // report:\n //printf(\"%d\\n\", res);\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n num = scanf(\"%d \", &N);\n for (int i=0; i<N; ++i) num = scanf(\"%ld \", &vect[i]);\n int res = solve(N);\n printf(\"%d\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 30, "memory_kb": 13992, "score_of_the_acc": -0.1013, "final_rank": 1 }, { "submission_id": "aoj_0329_9463658", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nhttps://stackoverflow.com/questions/5534063/maximum-subarray-whose-sum-equals-0\nhttps://www.geeksforgeeks.org/find-the-largest-subarray-with-0-sum/\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 1000000000;\n\nconst int MAX_N = 200000;\nstatic int64_t vect[MAX_N];\nstatic int64_t P[MAX_N];\n//------------------------------------------------------------------------------\nint solve(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (N == 1) return vect[0] == 0;\n //--------------------------------------------------------------------------\n // init:\n P[0] = vect[0];\n for (int i=1; i<N; ++i) P[i] = vect[i] + P[i-1];\n //printf(\"P: \"); for (int i=0; i<N; ++i) printf(\"%d \",P[i]); printf(\"\\n\");\n //--------------------------------------------------------------------------\n // compute:\n unordered_map<int,int> index;\n int res = 0;\n for (int i=0; i<N; ++i)\n {\n if (P[i] == 0) res = i+1;\n else if (index.find( P[i] ) == index.end())\n {\n index[ P[i] ] = i;\n }\n else\n {\n res = max(res, i - index[ P[i] ]);\n }\n }\n //--------------------------------------------------------------------------\n // report:\n //printf(\"%d\\n\", res);\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n num = scanf(\"%d \", &N);\n for (int i=0; i<N; ++i) num = scanf(\"%ld \", &vect[i]);\n int res = solve(N);\n printf(\"%d\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 0.88, "time_ms": 30, "memory_kb": 13976, "score_of_the_acc": -0.1007, "final_rank": 16 }, { "submission_id": "aoj_0329_9463652", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nhttps://stackoverflow.com/questions/5534063/maximum-subarray-whose-sum-equals-0\nhttps://www.geeksforgeeks.org/find-the-largest-subarray-with-0-sum/\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 1000000000;\n\nconst int MAX_N = 200000;\nstatic int vect[MAX_N];\nstatic int P[MAX_N];\n//------------------------------------------------------------------------------\nint solve(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (N == 1) return vect[0] == 0;\n //--------------------------------------------------------------------------\n // init:\n P[0] = vect[0];\n for (int i=1; i<N; ++i) P[i] = vect[i] + P[i-1];\n //printf(\"P: \"); for (int i=0; i<N; ++i) printf(\"%d \",P[i]); printf(\"\\n\");\n //--------------------------------------------------------------------------\n // compute:\n unordered_map<int,int> index;\n int res = 0;\n for (int i=0; i<N; ++i)\n {\n if (P[i] == 0) res = i+1;\n else if (index.find( P[i] ) == index.end())\n {\n index[ P[i] ] = i;\n }\n else\n {\n res = max(res, i - index[ P[i] ]);\n }\n }\n //--------------------------------------------------------------------------\n // report:\n //printf(\"%d\\n\", res);\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n num = scanf(\"%d \", &N);\n for (int i=0; i<N; ++i) num = scanf(\"%d \", &vect[i]);\n int res = solve(N);\n printf(\"%d\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 0.88, "time_ms": 40, "memory_kb": 12388, "score_of_the_acc": -0.1587, "final_rank": 17 }, { "submission_id": "aoj_0329_9055213", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n;\n cin >> n;\n map<ll, int> mp;\n mp[0] = -1;\n ll sum = 0;\n int res = 0;\n for (int i = 0; i < n; i++) {\n ll a;\n cin >> a;\n sum += a;\n if (mp.find(sum) != mp.end()) {\n res = max(res, i - mp[sum]);\n }\n else {\n mp[sum] = i;\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 15648, "score_of_the_acc": -0.2678, "final_rank": 4 }, { "submission_id": "aoj_0329_8428388", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n map<long,long> e;\n int a;\n cin>>a;\n long r=0;\n long f;\n long ans=0;\n e[0]=-1;\n for(int i=0;i<a;i+=1){\n cin>>f;\n r+=f;\n if(!e.count(r)){\n e[r]=i;\n }else{\n if(ans<i-e[r]){\n ans=i-e[r];\n }\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 15848, "score_of_the_acc": -0.4967, "final_rank": 7 }, { "submission_id": "aoj_0329_8428384", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n map<long,long> e;\n int a;\n cin>>a;\n int r=0;\n int f;\n int ans=0;\n e[0]=-1;\n for(int i=0;i<a;i+=1){\n cin>>f;\n r+=f;\n if(!e.count(r)){\n e[r]=i;\n }else{\n if(ans<i-e[r]){\n ans=i-e[r];\n }\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 0.88, "time_ms": 100, "memory_kb": 15688, "score_of_the_acc": -0.9358, "final_rank": 18 }, { "submission_id": "aoj_0329_7076221", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define all(a) a.begin(),a.end()\n\n\nvoid yn(bool n)\n{\n\tif(n)\n\t{\n\t\tcout<<\"yes\"<<endl;\n\t}\n\telse\n\t{\n\t\tcout<<\"no\"<<endl;\n\t}\n\treturn;\n}\n\n\nint main()\n{\n\tint n;\n\tcin>>n;\n\tauto d=vector<ll>();\n\tfor(int i=0; i<n; i++)\n\t{\n\t\tll a;cin>>a;\n\t\td.push_back(a);\n\t}\n\n\tauto dic=map<ll,int>();\n\tdic[0]=0;\n\tint ans=0;\n\tll sum=0;\n\tfor(int i=0; i<n; i++)\n\t{\n\t\tsum+=d[i];\n\t\tif(dic.find(sum)!=dic.end())\n\t\t{\n\t\t\tans=max(ans,i+1-dic[sum]);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tdic[sum]=i+1;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 16892, "score_of_the_acc": -0.6427, "final_rank": 8 }, { "submission_id": "aoj_0329_7073856", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\n\n\nint solve(){\n int n; cin >> n;\n vl a(n);\n rep(i,0,n)cin >> a[i];\n vl rui(1,0);\n int ans = 0;\n rep(i,0,n){\n rui.push_back(rui.back()+a[i]);\n if(rui.back() == 0)ans = 1;\n }\n map<ll , vi> mp;\n rep(i,0,n+1)mp[rui[i]].push_back(i);\n for(auto c:mp){\n if(c.second.size() == 1)continue;\n chmax(ans , c.second.back()-c.second[0]);\n }\n cout << ans << endl;\n \n\n \n \n\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 27984, "score_of_the_acc": -0.7915, "final_rank": 12 }, { "submission_id": "aoj_0329_7073832", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\n\n\nint solve(){\n int n; cin >> n;\n vl a(n);\n rep(i,0,n)cin >> a[i];\n vl rui(1,0);\n int ans = 0;\n rep(i,0,n){\n rui.push_back(rui.back()+a[i]);\n if(rui.back() == 0)ans = 1;\n }\n map<int , vi> mp;\n rep(i,0,n+1)mp[rui[i]].push_back(i);\n for(auto c:mp){\n if(c.second.size() == 1)continue;\n chmax(ans , c.second.back()-c.second[0]);\n }\n cout << ans << endl;\n \n\n \n \n\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 0.88, "time_ms": 90, "memory_kb": 27984, "score_of_the_acc": -1.2359, "final_rank": 19 }, { "submission_id": "aoj_0329_7073818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\n\n\nint solve(){\n int n; cin >> n;\n vl a(n);\n rep(i,0,n)cin >> a[i];\n vl rui(1,0);\n rep(i,0,n){\n rui.push_back(rui.back()+a[i]);\n }\n int ans = 0;\n map<int , vi> mp;\n rep(i,0,n+1)mp[rui[i]].push_back(i);\n for(auto c:mp){\n if(c.second.size() == 1)continue;\n chmax(ans , c.second.back()-c.second[0]);\n }\n cout << ans << endl;\n \n\n \n \n\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 0.88, "time_ms": 90, "memory_kb": 27984, "score_of_the_acc": -1.2359, "final_rank": 19 }, { "submission_id": "aoj_0329_7057425", "code_snippet": "#include <iostream>\n#include <map>\nusing namespace std;\nmap<long long int,int> ms;\nmap<long long int,int>::iterator it;\nint main() {\n\tint n;\n\tlong long int sum=0;\n\tcin>>n;\n\tms[0]=0;\n\tint ans=0;\n\tfor(int i=1;i<=n;i++){\n\t\tlong long int t;\n\t\tcin>>t;\n\t\tsum+=t;\n\t\tif(i>1){\n\t\t\tif(ms.find(sum)!=ms.end()){\n\t\t\t\tint t2=i-ms[sum];\n\t\t\t\tif(ans<t2)ans=t2;\n\t\t\t}\n\t\t}\n\t\tif(sum==0)ans=i;\n\t\tif(t==0&&ans==0)ans=1;\n\t\tif(ms.find(sum)==ms.end()){\n\t\t\tms[sum]=i;\n\t\t}\n\t}\n\t//for(it=ms.begin();it!=ms.end();it++){\n\t//out<<(*it).first<<\" \"<<(*it).second<<endl;\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 15504, "score_of_the_acc": -0.7074, "final_rank": 11 }, { "submission_id": "aoj_0329_6965939", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0329.cc: 完全平等二国間貿易\n */\n\n#include<cstdio>\n#include<map>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 200000;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef map<ll,int> mli;\n\n/* global variables */\n\nint ds[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", ds + i);\n\n ll sum = 0;\n int maxl = 0;\n mli ps;\n ps[sum] = 0;\n \n for (int i = 0; i < n; i++) {\n sum += ds[i];\n mli::iterator mit = ps.lower_bound(sum);\n if (mit != ps.end() && mit->first == sum)\n maxl = max(maxl, i + 1 - mit->second);\n else\n ps[sum] = i + 1;\n }\n\n printf(\"%d\\n\", maxl);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 16272, "score_of_the_acc": -0.1775, "final_rank": 2 }, { "submission_id": "aoj_0329_6809118", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int N;\n cin >> N;\n vector<long long int> d(N);\n for(int i=0;i<N;i++) cin >> d[i];\n int ans = 0;\n map<long long int,int> Map;\n Map[0] = N;\n long long int S = 0;\n for(int i=N-1;i>=0;i--){\n S += d[i];\n ans = max(ans,Map[S]-i);\n Map[S] = max(Map[S],i);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 16948, "score_of_the_acc": -0.6446, "final_rank": 9 }, { "submission_id": "aoj_0329_6693209", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tll N=in();\n\tvll A=vecin(N),S(N+1,0);\n\tREP(i,N) S[i+1] = S[i]+A[i];\n\n\tmap<ll,vector<ll>> M;\n\tREP(i,N+1){\n\t\tM[S[i]].push_back(i);\n\t}\n\n\tll L=0;\n\tfor(auto& x:M){\n\t\tchmax(L,x.second.back()-x.second.front());\n\t}\n\tout(L);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 28036, "score_of_the_acc": -0.6821, "final_rank": 10 }, { "submission_id": "aoj_0329_6409078", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n; cin >> n;\n vector<ll> d(n);\n for(auto &it: d) cin >> it;\n vector<ll> tot(n+1, 0);\n for(int i = 0; i < n; i++) tot[i+1] = tot[i]+d[i];\n map<ll, vector<int>> mem;\n for(int i = 0; i <= n; i++) mem[tot[i]].emplace_back(i);\n int ans = 0;\n for(auto &it: mem){\n auto &vec = it.second;\n if(vec.size() > 1) ans = max(ans, vec.back()-vec.front());\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 28048, "score_of_the_acc": -1.0158, "final_rank": 14 }, { "submission_id": "aoj_0329_6216936", "code_snippet": "#include <iostream>\n#include <unordered_set>\n#include <map>\n#include <cassert>\nusing namespace std;\n\nlong max(unordered_set<long> *S);\nlong min(unordered_set<long> *S);\n\nint main(void){\n long N;\n cin>>N;\n long long* d = new long long[N];\n for(long i=0;i<N;i++){\n cin>>d[i];\n }\n long long* accumurate = new long long[N+1];\n accumurate[0] = 0;\n for(long i=0;i<N;i++){\n accumurate[i+1] = accumurate[i] + d[i];\n }\n //accumurate[j+1]==accumurate[i] のときの j-iの最大値が知りたい\n\n map<long long, unordered_set<long> > count;\n assert(count.empty());\n for(long i=0;i<=N;i++){\n count[accumurate[i]].clear();\n }\n for(long i=0;i<=N;i++){\n count[accumurate[i]].insert(i);\n }\n\n long retval = 0;\n for(auto item : count){\n long long key = item.first;\n unordered_set<long> value = item.second;\n retval = max(retval, max(&value)-min(&value));\n }\n cout<<retval<<endl;\n return 0;\n}\n\n\nlong max(unordered_set<long> *S){\n long M = -1000000010;\n for(long s:*S){\n if(M<s){\n M = s;\n }\n }\n return M;\n}\n\nlong min(unordered_set<long> *S){\n long m = 1000000010;\n for(long s:*S){\n if(m>s){\n m = s;\n }\n }\n return m;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 40864, "score_of_the_acc": -2, "final_rank": 15 } ]
aoj_0333_cpp
線分配置 A大学は今年もプログラミングコンテストを開催する。作題チームの一員であるあなたは、計算幾何学の問題の入力データの作成を担当することになった。あなたが作りたい入力データは、 x 軸または y 軸に平行で、互いに触れ合うことのない線分の集合である。あなたは、次のアルゴリズムに基づいたデータ生成プログラムを開発して、入力データを生成する。 xy 平面上の線分の集合 T を空にする。 次の処理を N 回繰り返す。 x 軸または y 軸に平行な適当な線分 s を作る。 s が T 内のどの線分にも触れない場合は s を T に追加し、触れる場合は s を追加しない。 x 軸または y 軸に平行な N 本の線分を順番に入力し、各線分が平面上に追加されるかどうかを判定するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N px 1 py 1 qx 1 qy 1 px 2 py 2 qx 2 qy 2 : px N py N qx N qy N 1行目に線分の数 N (1 ≤ N ≤ 100000) が与えられる。続く N 行に、 i 番目に追加したい線分の情報が与えられる。各行に与えられる4つの整数 px i , py i , qx i , qy i (0 ≤ px i , py i , qx i , qy i ≤ 10 9 ) は、それぞれ i 番目の線分の端点の x 座標、 y 座標、もう一つの端点の x 座標、 y 座標を表す。ただし、線分の長さは1以上である。 Output 各線分について、追加される場合「1」を、追加されない場合「0」を1行に出力する。 Sample Input 1 9 0 2 5 2 1 3 1 7 0 6 3 6 2 4 8 4 4 0 4 5 6 3 6 0 5 6 7 6 8 3 8 7 6 5 11 5 Sample Output 1 1 1 0 1 0 1 1 0 1
[ { "submission_id": "aoj_0333_10203845", "code_snippet": "// AOJ #333\n// Line Segment Arrangement 2025.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(int n) {\n pc('0'+n), pc('\\n');\n}\n\nstruct BIT1D {\n int n;\n vector<int> tree;\n BIT1D() : n(0) {}\n BIT1D(int n) : n(n) { tree.assign(n+1, 0); }\n void init(int n_) {\n n = n_;\n tree.assign(n+1, 0);\n }\n void update(int i, int delta) {\n for(; i <= n; i += i & -i)\n tree[i] += delta;\n }\n int query(int i) {\n int s = 0;\n for(; i > 0; i -= i & -i)\n s += tree[i];\n return s;\n }\n};\n \nstruct DS_V {\n vector<int> xs;\n int m;\n vector<vector<int>> ys;\n vector<BIT1D> bit;\n \n DS_V() : m(0) {}\n void init(const vector<pair<int,int>> &updates) {\n vector<int> temp;\n for(auto &p : updates)\n temp.push_back(p.first);\n sort(temp.begin(), temp.end());\n temp.erase(unique(temp.begin(), temp.end()), temp.end());\n xs = temp;\n m = xs.size();\n \n ys.assign(m+1, vector<int>());\n bit.resize(m+1);\n \n for(auto &p : updates){\n int x = p.first, y = p.second;\n int pos = int(lower_bound(xs.begin(), xs.end(), x) - xs.begin()) + 1;\n for(int j = pos; j <= m; j += j & -j)\n ys[j].push_back(y);\n }\n for (int j = 1; j <= m; j++){\n sort(ys[j].begin(), ys[j].end());\n ys[j].erase(unique(ys[j].begin(), ys[j].end()), ys[j].end());\n bit[j].init(ys[j].size());\n }\n }\n void update(int x, int y, int delta) {\n if(m == 0) return;\n int pos = int(lower_bound(xs.begin(), xs.end(), x) - xs.begin()) + 1;\n for(int j = pos; j <= m; j += j & -j) {\n int posY = int(lower_bound(ys[j].begin(), ys[j].end(), y) - ys[j].begin()) + 1;\n bit[j].update(posY, delta);\n }\n }\n int query_internal(int pos, int y) {\n int res = 0;\n for(; pos > 0; pos -= pos & -pos) {\n int posY = int(upper_bound(ys[pos].begin(), ys[pos].end(), y) - ys[pos].begin());\n res += bit[pos].query(posY);\n }\n return res;\n }\n int query_range(int L, int R, int y) {\n if(m == 0) return 0;\n int rpos = int(upper_bound(xs.begin(), xs.end(), R) - xs.begin());\n int lpos = int(lower_bound(xs.begin(), xs.end(), L) - xs.begin()) + 1;\n if(rpos == 0 || lpos > m || lpos > rpos) return 0;\n return query_internal(rpos, y) - query_internal(lpos - 1, y);\n }\n};\n\nstruct DS_H {\n vector<int> ys;\n int m;\n vector<vector<int>> xs;\n vector<BIT1D> bit;\n \n DS_H() : m(0) {}\n void init(const vector<pair<int,int>> &updates) {\n vector<int> temp;\n for(auto &p : updates)\n temp.push_back(p.first);\n sort(temp.begin(), temp.end());\n temp.erase(unique(temp.begin(), temp.end()), temp.end());\n ys = temp;\n m = ys.size();\n \n xs.assign(m+1, vector<int>());\n bit.resize(m+1);\n \n for(auto &p : updates){\n int y = p.first, x = p.second;\n int pos = int(lower_bound(ys.begin(), ys.end(), y) - ys.begin()) + 1;\n for(int j = pos; j <= m; j += j & -j)\n xs[j].push_back(x);\n }\n for(int j = 1; j <= m; j++){\n sort(xs[j].begin(), xs[j].end());\n xs[j].erase(unique(xs[j].begin(), xs[j].end()), xs[j].end());\n bit[j].init(xs[j].size());\n }\n }\n void update(int y, int x, int delta) {\n if(m == 0) return;\n int pos = int(lower_bound(ys.begin(), ys.end(), y) - ys.begin()) + 1;\n for(int j = pos; j <= m; j += j & -j){\n int posX = int(lower_bound(xs[j].begin(), xs[j].end(), x) - xs[j].begin()) + 1;\n bit[j].update(posX, delta);\n }\n }\n int query_internal(int pos, int x) {\n int res = 0;\n for(; pos > 0; pos -= pos & -pos) {\n int posX = int(upper_bound(xs[pos].begin(), xs[pos].end(), x) - xs[pos].begin());\n res += bit[pos].query(posX);\n }\n return res;\n }\n int query_range(int L, int R, int x) {\n if(m == 0) return 0;\n int rpos = int(upper_bound(ys.begin(), ys.end(), R) - ys.begin());\n int lpos = int(lower_bound(ys.begin(), ys.end(), L) - ys.begin()) + 1;\n if(rpos == 0 || lpos > m || lpos > rpos) return 0;\n return query_internal(rpos, x) - query_internal(lpos - 1, x);\n }\n};\n \nstruct Segment {\n bool vertical;\n int x1, x2, y1, y2;\n};\n \nint main(){\n int N = Cin();\n vector<Segment> segs(N);\n vector<pair<int,int>> ds_v_updates;\n vector<pair<int,int>> ds_h_updates;\n \n for (int i = 0; i < N; i++){\n int px = Cin(), py = Cin(), qx = Cin(), qy = Cin();\n if(py == qy) {\n int y = py;\n int L = min(px, qx), R = max(px, qx);\n segs[i] = {false, L, R, y, y};\n ds_h_updates.push_back({y, L});\n ds_h_updates.push_back({y, R+1});\n } else {\n int x = px;\n int L = min(py, qy), R = max(py, qy);\n segs[i] = {true, x, x, L, R};\n ds_v_updates.push_back({x, L});\n ds_v_updates.push_back({x, R+1});\n }\n }\n \n DS_V ds_v;\n ds_v.init(ds_v_updates);\n DS_H ds_h;\n ds_h.init(ds_h_updates);\n \n map<int, set<pair<int,int>>> horizontals;\n map<int, set<pair<int,int>>> verticals;\n \n for (int i = 0; i < N; i++){\n if(!segs[i].vertical) {\n int y = segs[i].y1;\n int L = segs[i].x1, R = segs[i].x2;\n bool conflict = false;\n if(horizontals.count(y)){\n auto &st = horizontals[y];\n auto it = st.lower_bound({L, -1});\n if(it != st.end()){\n if(it->first <= R) conflict = true;\n }\n if(!conflict && it != st.begin()){\n auto prev_it = it;\n prev_it--;\n if(prev_it->second >= L) conflict = true;\n }\n }\n if(!conflict){\n int cnt = ds_v.query_range(L, R, y);\n if(cnt > 0) conflict = true;\n }\n \n if(conflict) Cout(0);\n else {\n Cout(1);\n horizontals[y].insert({L, R});\n ds_h.update(y, L, 1);\n ds_h.update(y, R+1, -1);\n }\n } else {\n int x = segs[i].x1;\n int L = segs[i].y1, R = segs[i].y2;\n bool conflict = false;\n if(verticals.count(x)){\n auto &st = verticals[x];\n auto it = st.lower_bound({L, -1});\n if(it != st.end()){\n if(it->first <= R) conflict = true;\n }\n if(!conflict && it != st.begin()){\n auto prev_it = it;\n prev_it--;\n if(prev_it->second >= L) conflict = true;\n }\n }\n if(!conflict){\n int cnt = ds_h.query_range(L, R, x);\n if(cnt > 0) conflict = true;\n }\n \n if(conflict) Cout(0);\n else {\n Cout(1);\n verticals[x].insert({L, R});\n ds_v.update(x, L, 1);\n ds_v.update(x, R+1, -1);\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 43452, "score_of_the_acc": -0.2575, "final_rank": 2 }, { "submission_id": "aoj_0333_8287677", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\n// メモリ足りるかな…\n// =============================================================== Segtree Part1 ===============================================================\nclass RangeMax {\npublic:\n\tint size_ = 1;\n\tvector<int> dat;\n\t\n\tvoid init(int sz) {\n\t\tsize_ = 1;\n\t\twhile (size_ <= sz) size_ *= 2;\n\t\tdat.resize(size_ * 2, -1);\n\t}\n\n\tvoid update(int pos, int x) {\n\t\tpos += size_;\n\t\tdat[pos] = max(dat[pos], x);\n\t\twhile (pos >= 2) {\n\t\t\tpos >>= 1;\n\t\t\tdat[pos] = max(dat[pos * 2 + 0], dat[pos * 2 + 1]);\n\t\t}\n\t}\n\n\tint query_(int l, int r, int a, int b, int u) {\n\t\tif (l <= a && b <= r) return dat[u];\n\t\tif (r <= a || b <= l) return -1;\n\t\tint v1 = query_(l, r, a, (a + b) / 2, u * 2);\n\t\tint v2 = query_(l, r, (a + b) / 2, b, u * 2 + 1);\n\t\treturn max(v1, v2);\n\t}\n\n\tint query(int l, int r) {\n\t\treturn query_(l, r, 0, size_, 1);\n\t}\n};\n\n// =============================================================== Segtree Part2 ===============================================================\nclass SegmentTree {\npublic:\n\tint size_ = 1;\n\tvector<vector<int>> place;\n\tvector<RangeMax> dat;\n\n\tvoid init(int sz) {\n\t\tsize_ = 1;\n\t\twhile (size_ <= sz) size_ *= 2;\n\t\tplace.resize(size_ * 2, vector<int>{});\n\t\tdat.resize(size_ * 2);\n\t}\n\n\tvoid initial_add(int pos, int x) {\n\t\tpos += size_;\n\t\twhile (pos >= 1) {\n\t\t\tplace[pos].push_back(x);\n\t\t\tpos >>= 1;\n\t\t}\n\t}\n\n\tvoid preparation() {\n\t\tfor (int i = 1; i < size_ * 2; i++) {\n\t\t\tsort(place[i].begin(), place[i].end());\n\t\t\tplace[i].erase(unique(place[i].begin(), place[i].end()), place[i].end());\n\t\t\tdat[i].init(place[i].size() + 2);\n\t\t}\n\t}\n\n\tvoid add(int pos, int l, int r) {\n\t\tpos += size_;\n\t\twhile (pos >= 1) {\n\t\t\tint pos1 = lower_bound(place[pos].begin(), place[pos].end(), l) - place[pos].begin();\n\t\t\tdat[pos].update(pos1, r);\n\t\t\tpos >>= 1;\n\t\t}\n\t}\n\n\tint query_(int l, int r, int max_req, int a, int b, int u) {\n\t\tif (l <= a && b <= r) {\n\t\t\tint pos1 = lower_bound(place[u].begin(), place[u].end(), max_req + 1) - place[u].begin();\n\t\t\treturn dat[u].query(0, pos1);\n\t\t}\n\t\tif (r <= a || b <= l) return -1;\n\t\tint v1 = query_(l, r, max_req, a, (a + b) / 2, u * 2);\n\t\tint v2 = query_(l, r, max_req, (a + b) / 2, b, u * 2 + 1);\n\t\treturn max(v1, v2);\n\t}\n\n\tint query(int l, int r, int max_req) {\n\t\treturn query_(l, r, max_req, 0, size_, 1);\n\t}\n};\n\n// =============================================================== Main Part ===============================================================\nint N;\nint px[100009], py[100009], qx[100009], qy[100009];\nint T[100009];\nint X[100009];\nint L[100009];\nint R[100009];\nset<pair<int, int>> S1[200009];\nset<pair<int, int>> S2[200009];\nSegmentTree Z1;\nSegmentTree Z2;\n\nbool Simulate(int t, int x, int l, int r) {\n\t// First Check (Same Direction)\n\tif (t == 1) {\n\t\tauto itr = S1[x].lower_bound(make_pair(r + 1, -1));\n\t\tif (itr != S1[x].begin()) {\n\t\t\titr--;\n\t\t\tpair<int, int> rec = (*itr);\n\t\t\tif (rec.second >= l) return false;\n\t\t}\n\t}\n\tif (t == 2) {\n\t\tauto itr = S2[x].lower_bound(make_pair(r + 1, -1));\n\t\tif (itr != S2[x].begin()) {\n\t\t\titr--;\n\t\t\tpair<int, int> rec = (*itr);\n\t\t\tif (rec.second >= l) return false;\n\t\t}\n\t}\n\n\t// Second Check (Different Direction)\n\tif (t == 1) {\n\t\tint ret = Z2.query(l, r + 1, x);\n\t\tif (ret >= x) return false;\n\t}\n\tif (t == 2) {\n\t\tint ret = Z1.query(l, r + 1, x);\n\t\tif (ret >= x) return false;\n\t}\n\treturn true;\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N;\n\tfor (int i = 1; i <= N; i++) cin >> px[i] >> py[i] >> qx[i] >> qy[i];\n\n\t// Step 2. Compression\n\tvector<int> ListX;\n\tvector<int> ListY;\n\tfor (int i = 1; i <= N; i++) ListX.push_back(px[i]);\n\tfor (int i = 1; i <= N; i++) ListX.push_back(qx[i]);\n\tfor (int i = 1; i <= N; i++) ListY.push_back(py[i]);\n\tfor (int i = 1; i <= N; i++) ListY.push_back(qy[i]);\n\tsort(ListX.begin(), ListX.end()); ListX.erase(unique(ListX.begin(), ListX.end()), ListX.end());\n\tsort(ListY.begin(), ListY.end()); ListY.erase(unique(ListY.begin(), ListY.end()), ListY.end());\n\tfor (int i = 1; i <= N; i++) px[i] = lower_bound(ListX.begin(), ListX.end(), px[i]) - ListX.begin();\n\tfor (int i = 1; i <= N; i++) qx[i] = lower_bound(ListX.begin(), ListX.end(), qx[i]) - ListX.begin();\n\tfor (int i = 1; i <= N; i++) py[i] = lower_bound(ListY.begin(), ListY.end(), py[i]) - ListY.begin();\n\tfor (int i = 1; i <= N; i++) qy[i] = lower_bound(ListY.begin(), ListY.end(), qy[i]) - ListY.begin();\n\n\t// Step 3. Formatting\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (px[i] == qx[i]) { T[i] = 1; X[i] = px[i]; L[i] = py[i]; R[i] = qy[i]; }\n\t\tif (py[i] == qy[i]) { T[i] = 2; X[i] = py[i]; L[i] = px[i]; R[i] = qx[i]; }\n\t\tif (L[i] > R[i]) swap(L[i], R[i]);\n\t}\n\n\t// Step 4. Init Segtree\n\tZ1.init(ListX.size() + 2);\n\tZ2.init(ListY.size() + 2);\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (T[i] == 1) Z1.initial_add(X[i], L[i]);\n\t\tif (T[i] == 2) Z2.initial_add(X[i], L[i]);\n\t}\n\tZ1.preparation();\n\tZ2.preparation();\n\n\t// Step 4. Simulation\n\tfor (int i = 1; i <= N; i++) {\n\t\tbool ret = Simulate(T[i], X[i], L[i], R[i]);\n\t\tif (ret == true) {\n\t\t\tcout << \"1\" << endl;\n\t\t\tif (T[i] == 1) S1[X[i]].insert(make_pair(L[i], R[i]));\n\t\t\tif (T[i] == 2) S2[X[i]].insert(make_pair(L[i], R[i]));\n\t\t\tif (T[i] == 1) Z1.add(X[i], L[i], R[i]);\n\t\t\tif (T[i] == 2) Z2.add(X[i], L[i], R[i]);\n\t\t}\n\t\telse {\n\t\t\tcout << \"0\" << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 174340, "score_of_the_acc": -1.1323, "final_rank": 8 }, { "submission_id": "aoj_0333_7075259", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nstruct SegTree {\n\t//二分木を配列で表したもの\n\tvector<set<int>>seg;\n\t//木の半分の大きさ\n\tint siz;\n\t\n\t//大きさnでsegtreeを初期化する\n\tSegTree(int n) {\n\t\tsiz = 1;\n\t\twhile (siz < n)siz <<= 1;\n\t\tseg.resize(siz * 2 - 1);\n\t\tsiz--;\n\t}\n\n\tset<int> operator[](const int i) {\n\t\treturn seg[i + siz];\n\t}\n\n\t//区間[a,b)にxをinsertする\n\tvoid insert(int a, int b, int x) {\n\t\tfor (a += siz, b += siz; a < b; a >>= 1, b >>= 1) {\n\t\t\tif (!(a & 1))seg[a++].insert(x);\n\t\t\tif (!(b & 1))seg[--b].insert(x);\n\t\t}\n\t\treturn;\n\t}\n\n\t//aの位置に[l,r]に含まれる数が存在するか\n\tbool check(int a, pint lr) {\n\t\tbool ans = false;\n\t\tfor (a += siz; 0 <= a; (++a >>= 1)--) {\n\t\t\tif (seg[a].lower_bound(lr.first) != seg[a].upper_bound(lr.second))ans = true;\n\t\t}\n\t\treturn ans;\n\t}\n\n\tvoid print(int a) {\n\t\tfor (a += siz; 0 <= a; (++a >>= 1)--) {\n\t\t\tfor (auto j : seg[a])cout << j << \" \";\n\t\t\tif (a == 0)break;\n\t\t}cout << endl;\n\t\treturn;\n\t}\n};\n\nstruct xy {\n\tint x;\n\tint y;\n};\n\nstruct edge {\n\txy p;\n\txy q;\n};\n\nint main() {\n\tint n;\n\tcin >> n;\n\tvector<edge>edges(n);\n\tfor (auto& [p, q] : edges)cin >> p.x >> p.y >> q.x >> q.y;\n\t{\n\t\tset<int> x, y;\n\t\trep(i, n) {\n\t\t\tx.insert(edges[i].p.x); x.insert(edges[i].q.x);\n\t\t\ty.insert(edges[i].p.y); y.insert(edges[i].q.y);\n\t\t}\n\t\tmap<int, int>mx, my;\n\t\tint i = 0;\n\t\tfor (auto xx : x)mx[xx] = i++; i = 0;\n\t\tfor (auto yy : y)my[yy] = i++; i = 0;\n\t\tfor (auto& [p, q] : edges) {\n\t\t\tp.x = mx[p.x]; p.y = my[p.y];\n\t\t\tq.x = mx[q.x]; q.y = my[q.y];\n\t\t\tif (p.x > q.x)swap(p.x, q.x);\n\t\t\tif (p.y > q.y)swap(p.y, q.y);\n\t\t}\n\t}\n\tvbool ans(n);\n\tvector<vector<edge>>vh(2);\n\tvector<vector<set<pint>>>lr(2, vector<set<pint>>(2 * n));\n\tvector<SegTree>Seg(2, SegTree(2 * n));\n\trep(i, n) {\n\t\tedge e = edges[i];\n\t\txy p = e.p, q = e.q;\n\t\tbool isVer = p.x == q.x;\n\t\tint idx;\n\t\tpint LR;\n\t\tif (isVer) {\n\t\t\tidx = p.x;\n\t\t\tLR = { p.y,q.y };\n\t\t}\n\t\telse {\n\t\t\tidx = p.y;\n\t\t\tLR = { p.x,q.x };\n\t\t}\n\t\tbool isOK = true;\n\t\t{\n\t\t\tauto it = lr[isVer][idx].lower_bound(LR);\n\t\t\tif (!(it == lr[isVer][idx].end() || LR.second < (*it).first) ||\n\t\t\t\t!(it == lr[isVer][idx].begin() || (*--it).second < LR.first)) isOK = false;\n\t\t}\n\t\t{\n\t\t\t//Segのidxの位置にLRの中に入る奴が無いかどうか調べる\n\t\t\tif (Seg[!isVer].check(idx, LR))isOK = false;\n\t\t}\n\t\tif (isOK) {\n\t\t\tlr[isVer][idx].insert(LR);\n\t\t\tSeg[isVer].insert(LR.first, LR.second + 1, idx);\n\t\t\tans[i] = true;\n\t\t}\n\t}\n\trep(i, n)cout << ans[i] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 115936, "score_of_the_acc": -0.7153, "final_rank": 4 }, { "submission_id": "aoj_0333_5023873", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/datastructure/BIT.cpp\"\n//1-indexed\n#line 3 \"/home/kotatsugame/library/datastructure/BIT.cpp\"\ntemplate<typename T>\nstruct BIT{\n\tint n;\n\tvector<T>bit;\n\tBIT(int n_=0):n(n_),bit(n_+1){}\n\tT sum(int i)\n\t{\n\t\tT ans=0;\n\t\tfor(;i>0;i-=i&-i)ans+=bit[i];\n\t\treturn ans;\n\t}\n\tvoid add(int i,T a)\n\t{\n\t\tif(i==0)return;\n\t\tfor(;i<=n;i+=i&-i)bit[i]+=a;\n\t}\n\tint lower_bound(T k)//k<=sum(ret)\n\t{\n\t\tif(k<=0)return 0;\n\t\tint ret=0,i=1;\n\t\twhile((i<<1)<=n)i<<=1;\n\t\tfor(;i;i>>=1)\n\t\t\tif(ret+i<=n&&bit[ret+i]<k)k-=bit[ret+=i];\n\t\treturn ret+1;\n\t}\n};\n#line 7 \"a.cpp\"\nint N;\nint X1[1<<17],Y1[1<<17],X2[1<<17],Y2[1<<17];\nvector<int>xv,yv;\nvector<pair<int,int> >xL,xR,yL,yR;\nset<pair<int,int> >X[1<<17],Y[1<<17];\nbool intersect(pair<int,int>A,pair<int,int>B)\n{\n\treturn !(A.second<B.first||B.second<A.first);\n}\nconst int B=300,W=(100000+B-1)/B;\nvector<int>xyL[W],xyR[W],yxL[W],yxR[W];\nvector<BIT<int> >xLP(W,BIT<int>(B)),xRP(W,BIT<int>(B)),yLP(W,BIT<int>(B)),yRP(W,BIT<int>(B));\nvector<pair<int,int> >xyLD[W],xyRD[W],yxLD[W],yxRD[W];\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>X1[i]>>Y1[i]>>X2[i]>>Y2[i];\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\txv.push_back(X1[i]);\n\t\t\tif(Y1[i]>Y2[i])swap(Y1[i],Y2[i]);\n\t\t\txL.push_back(make_pair(X1[i],Y1[i]));\n\t\t\txR.push_back(make_pair(X1[i],Y2[i]));\n\t\t}\n\t\telse\n\t\t{\n\t\t\tyv.push_back(Y1[i]);\n\t\t\tif(X1[i]>X2[i])swap(X1[i],X2[i]);\n\t\t\tyL.push_back(make_pair(Y1[i],X1[i]));\n\t\t\tyR.push_back(make_pair(Y1[i],X2[i]));\n\t\t}\n\t}\n\tsort(xv.begin(),xv.end());\n\tsort(yv.begin(),yv.end());\n\tsort(xL.begin(),xL.end());\n\tsort(xR.begin(),xR.end());\n\tsort(yL.begin(),yL.end());\n\tsort(yR.begin(),yR.end());\n\tfor(int i=0;i<xv.size();i+=B)\n\t{\n\t\tint id=i/B;\n\t\tfor(int j=0;j<B&&i+j<xv.size();j++)\n\t\t{\n\t\t\txyL[id].push_back(xL[i+j].second);\n\t\t\txyR[id].push_back(xR[i+j].second);\n\t\t}\n\t\tsort(xyL[id].begin(),xyL[id].end());\n\t\txyL[id].erase(unique(xyL[id].begin(),xyL[id].end()),xyL[id].end());\n\t\tsort(xyR[id].begin(),xyR[id].end());\n\t\txyR[id].erase(unique(xyR[id].begin(),xyR[id].end()),xyR[id].end());\n\t}\n\tfor(int i=0;i<yv.size();i+=B)\n\t{\n\t\tint id=i/B;\n\t\tfor(int j=0;j<B&&i+j<yv.size();j++)\n\t\t{\n\t\t\tyxL[id].push_back(yL[i+j].second);\n\t\t\tyxR[id].push_back(yR[i+j].second);\n\t\t}\n\t\tsort(yxL[id].begin(),yxL[id].end());\n\t\tyxL[id].erase(unique(yxL[id].begin(),yxL[id].end()),yxL[id].end());\n\t\tsort(yxR[id].begin(),yxR[id].end());\n\t\tyxR[id].erase(unique(yxR[id].begin(),yxR[id].end()),yxR[id].end());\n\t}\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tbool now=true;\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\tint xi=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tset<pair<int,int> >::iterator it=X[xi].upper_bound(make_pair(Y1[i],-1));\n\t\t\tif(it!=X[xi].end()&&intersect(*it,make_pair(Y1[i],Y2[i])))now=false;\n\t\t\tif(it!=X[xi].begin()&&intersect(*--it,make_pair(Y1[i],Y2[i])))now=false;\n\t\t\tint L=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tint R=upper_bound(yv.begin(),yv.end(),Y2[i])-yv.begin();\n\t\t\tint cnt=0,out=0;\n\t\t\tif(L%B!=0)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:yxLD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>X1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:yxRD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<X1[i])out++;\n\t\t\t\t}\n\t\t\t\tL=(L+B-1)/B*B;\n\t\t\t}\n\t\t\twhile(L+B<=R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tcnt+=yxLD[id].size();\n\t\t\t\tint jd=upper_bound(yxL[id].begin(),yxL[id].end(),X1[i])-yxL[id].begin();\n\t\t\t\tout+=yLP[id].sum(yxL[id].size())-yLP[id].sum(jd);\n\t\t\t\tjd=lower_bound(yxR[id].begin(),yxR[id].end(),X1[i])-yxR[id].begin();\n\t\t\t\tout+=yRP[id].sum(jd);\n\t\t\t\tL+=B;\n\t\t\t}\n\t\t\tif(L<R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:yxLD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>X1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:yxRD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<X1[i])out++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt>out)now=false;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint yi=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tset<pair<int,int> >::iterator it=Y[yi].upper_bound(make_pair(X1[i],-1));\n\t\t\tif(it!=Y[yi].end()&&intersect(*it,make_pair(X1[i],X2[i])))now=false;\n\t\t\tif(it!=Y[yi].begin()&&intersect(*--it,make_pair(X1[i],X2[i])))now=false;\n\t\t\tint L=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tint R=upper_bound(xv.begin(),xv.end(),X2[i])-xv.begin();\n\t\t\tint cnt=0,out=0;\n\t\t\tif(L%B!=0)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:xyLD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:xyRD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tL=(L+B-1)/B*B;\n\t\t\t}\n\t\t\twhile(L+B<=R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tcnt+=xyLD[id].size();\n\t\t\t\tint jd=upper_bound(xyL[id].begin(),xyL[id].end(),Y1[i])-xyL[id].begin();\n\t\t\t\tout+=xLP[id].sum(xyL[id].size())-xLP[id].sum(jd);\n\t\t\t\tjd=lower_bound(xyR[id].begin(),xyR[id].end(),Y1[i])-xyR[id].begin();\n\t\t\t\tout+=xRP[id].sum(jd);\n\t\t\t\tL+=B;\n\t\t\t}\n\t\t\tif(L<R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:xyLD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:xyRD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<Y1[i])out++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt>out)now=false;\n\t\t}\n\t\tcout<<now<<endl;\n\t\tif(!now)continue;\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\tint xi=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tX[xi].insert(make_pair(Y1[i],Y2[i]));\n\t\t\tint Lid=lower_bound(xL.begin(),xL.end(),make_pair(X1[i],Y1[i]))-xL.begin();\n\t\t\tint Rid=lower_bound(xR.begin(),xR.end(),make_pair(X1[i],Y2[i]))-xR.begin();\n\t\t\txyLD[Lid/B].push_back(make_pair(X1[i],Y1[i]));\n\t\t\txyRD[Rid/B].push_back(make_pair(X1[i],Y2[i]));\n\t\t\tint jd=lower_bound(xyL[Lid/B].begin(),xyL[Lid/B].end(),Y1[i])-xyL[Lid/B].begin();\n\t\t\txLP[Lid/B].add(jd+1,1);\n\t\t\tjd=lower_bound(xyR[Rid/B].begin(),xyR[Rid/B].end(),Y2[i])-xyR[Rid/B].begin();\n\t\t\txRP[Rid/B].add(jd+1,1);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint yi=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tY[yi].insert(make_pair(X1[i],X2[i]));\n\t\t\tint Lid=lower_bound(yL.begin(),yL.end(),make_pair(Y1[i],X1[i]))-yL.begin();\n\t\t\tint Rid=lower_bound(yR.begin(),yR.end(),make_pair(Y1[i],X2[i]))-yR.begin();\n\t\t\tyxLD[Lid/B].push_back(make_pair(Y1[i],X1[i]));\n\t\t\tyxRD[Rid/B].push_back(make_pair(Y1[i],X2[i]));\n\t\t\tint jd=lower_bound(yxL[Lid/B].begin(),yxL[Lid/B].end(),X1[i])-yxL[Lid/B].begin();\n\t\t\tyLP[Lid/B].add(jd+1,1);\n\t\t\tjd=lower_bound(yxR[Rid/B].begin(),yxR[Rid/B].end(),X2[i])-yxR[Rid/B].begin();\n\t\t\tyRP[Rid/B].add(jd+1,1);\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 570, "memory_kb": 29244, "score_of_the_acc": -0.2299, "final_rank": 1 }, { "submission_id": "aoj_0333_5023865", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/datastructure/BIT.cpp\"\n//1-indexed\n#line 3 \"/home/kotatsugame/library/datastructure/BIT.cpp\"\ntemplate<typename T>\nstruct BIT{\n\tint n;\n\tvector<T>bit;\n\tBIT(int n_=0):n(n_),bit(n_+1){}\n\tT sum(int i)\n\t{\n\t\tT ans=0;\n\t\tfor(;i>0;i-=i&-i)ans+=bit[i];\n\t\treturn ans;\n\t}\n\tvoid add(int i,T a)\n\t{\n\t\tif(i==0)return;\n\t\tfor(;i<=n;i+=i&-i)bit[i]+=a;\n\t}\n\tint lower_bound(T k)//k<=sum(ret)\n\t{\n\t\tif(k<=0)return 0;\n\t\tint ret=0,i=1;\n\t\twhile((i<<1)<=n)i<<=1;\n\t\tfor(;i;i>>=1)\n\t\t\tif(ret+i<=n&&bit[ret+i]<k)k-=bit[ret+=i];\n\t\treturn ret+1;\n\t}\n};\n#line 7 \"a.cpp\"\nint N;\nint X1[1<<17],Y1[1<<17],X2[1<<17],Y2[1<<17];\nvector<int>xv,yv;\nvector<pair<int,int> >xL,xR,yL,yR;\nset<pair<int,int> >X[1<<17],Y[1<<17];\nbool intersect(pair<int,int>A,pair<int,int>B)\n{\n\treturn !(A.second<B.first||B.second<A.first);\n}\nconst int B=300,W=(100000+B-1)/B;\nvector<int>xyL[W],xyR[W],yxL[W],yxR[W];\nvector<BIT<int> >xLP(W,B),xRP(W,B),yLP(W,B),yRP(W,B);\nvector<pair<int,int> >xyLD[W],xyRD[W],yxLD[W],yxRD[W];\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>X1[i]>>Y1[i]>>X2[i]>>Y2[i];\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\txv.push_back(X1[i]);\n\t\t\tif(Y1[i]>Y2[i])swap(Y1[i],Y2[i]);\n\t\t\txL.push_back(make_pair(X1[i],Y1[i]));\n\t\t\txR.push_back(make_pair(X1[i],Y2[i]));\n\t\t}\n\t\telse\n\t\t{\n\t\t\tyv.push_back(Y1[i]);\n\t\t\tif(X1[i]>X2[i])swap(X1[i],X2[i]);\n\t\t\tyL.push_back(make_pair(Y1[i],X1[i]));\n\t\t\tyR.push_back(make_pair(Y1[i],X2[i]));\n\t\t}\n\t}\n\tsort(xv.begin(),xv.end());\n\txv.erase(unique(xv.begin(),xv.end()),xv.end());\n\tsort(yv.begin(),yv.end());\n\tyv.erase(unique(yv.begin(),yv.end()),yv.end());\n\tsort(xL.begin(),xL.end());\n\tsort(xR.begin(),xR.end());\n\tsort(yL.begin(),yL.end());\n\tsort(yR.begin(),yR.end());\n\tfor(int i=0;i<xL.size();i+=B)\n\t{\n\t\tint id=i/B;\n\t\tfor(int j=0;j<B&&i+j<xL.size();j++)\n\t\t{\n\t\t\txyL[id].push_back(xL[i+j].second);\n\t\t\txyR[id].push_back(xR[i+j].second);\n\t\t}\n\t\tsort(xyL[id].begin(),xyL[id].end());\n\t\txyL[id].erase(unique(xyL[id].begin(),xyL[id].end()),xyL[id].end());\n\t\tsort(xyR[id].begin(),xyR[id].end());\n\t\txyR[id].erase(unique(xyR[id].begin(),xyR[id].end()),xyR[id].end());\n\t}\n\tfor(int i=0;i<yL.size();i+=B)\n\t{\n\t\tint id=i/B;\n\t\tfor(int j=0;j<B&&i+j<yL.size();j++)\n\t\t{\n\t\t\tyxL[id].push_back(yL[i+j].second);\n\t\t\tyxR[id].push_back(yR[i+j].second);\n\t\t}\n\t\tsort(yxL[id].begin(),yxL[id].end());\n\t\tyxL[id].erase(unique(yxL[id].begin(),yxL[id].end()),yxL[id].end());\n\t\tsort(yxR[id].begin(),yxR[id].end());\n\t\tyxR[id].erase(unique(yxR[id].begin(),yxR[id].end()),yxR[id].end());\n\t}\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tbool now=true;\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\tint xi=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tset<pair<int,int> >::iterator it=X[xi].upper_bound(make_pair(Y1[i],-1));\n\t\t\tif(it!=X[xi].end()&&intersect(*it,make_pair(Y1[i],Y2[i])))now=false;\n\t\t\tif(it!=X[xi].begin()&&intersect(*--it,make_pair(Y1[i],Y2[i])))now=false;\n\t\t\tint L=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tint R=upper_bound(yv.begin(),yv.end(),Y2[i])-yv.begin();\n\t\t\tint cnt=0,out=0;\n\t\t\tif(L%B!=0)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:yxLD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>X1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:yxRD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<X1[i])out++;\n\t\t\t\t}\n\t\t\t\tL=(L+B-1)/B*B;\n\t\t\t}\n\t\t\twhile(L+B<=R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tcnt+=yxLD[id].size();\n\t\t\t\tint jd=upper_bound(yxL[id].begin(),yxL[id].end(),X1[i])-yxL[id].begin();\n\t\t\t\tout+=yLP[id].sum(yxL[id].size())-yLP[id].sum(jd);\n\t\t\t\tjd=lower_bound(yxR[id].begin(),yxR[id].end(),X1[i])-yxR[id].begin();\n\t\t\t\tout+=yRP[id].sum(jd);\n\t\t\t\tL+=B;\n\t\t\t}\n\t\t\tif(L<R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:yxLD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>X1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:yxRD[id])if(Y1[i]<=p.first&&p.first<=Y2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<X1[i])out++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt>out)now=false;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint yi=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tset<pair<int,int> >::iterator it=Y[yi].upper_bound(make_pair(X1[i],-1));\n\t\t\tif(it!=Y[yi].end()&&intersect(*it,make_pair(X1[i],X2[i])))now=false;\n\t\t\tif(it!=Y[yi].begin()&&intersect(*--it,make_pair(X1[i],X2[i])))now=false;\n\t\t\tint L=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tint R=upper_bound(xv.begin(),xv.end(),X2[i])-xv.begin();\n\t\t\tint cnt=0,out=0;\n\t\t\tif(L%B!=0)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:xyLD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:xyRD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tL=(L+B-1)/B*B;\n\t\t\t}\n\t\t\twhile(L+B<=R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tcnt+=xyLD[id].size();\n\t\t\t\tint jd=upper_bound(xyL[id].begin(),xyL[id].end(),Y1[i])-xyL[id].begin();\n\t\t\t\tout+=xLP[id].sum(xyL[id].size())-xLP[id].sum(jd);\n\t\t\t\tjd=lower_bound(xyR[id].begin(),xyR[id].end(),Y1[i])-xyR[id].begin();\n\t\t\t\tout+=xRP[id].sum(jd);\n\t\t\t\tL+=B;\n\t\t\t}\n\t\t\tif(L<R)\n\t\t\t{\n\t\t\t\tint id=L/B;\n\t\t\t\tfor(pair<int,int>p:xyLD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tcnt++;\n\t\t\t\t\tif(p.second>Y1[i])out++;\n\t\t\t\t}\n\t\t\t\tfor(pair<int,int>p:xyRD[id])if(X1[i]<=p.first&&p.first<=X2[i])\n\t\t\t\t{\n\t\t\t\t\tif(p.second<Y1[i])out++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt>out)now=false;\n\t\t}\n\t\tcout<<now<<endl;\n\t\tif(!now)continue;\n\t\tif(X1[i]==X2[i])\n\t\t{\n\t\t\tint xi=lower_bound(xv.begin(),xv.end(),X1[i])-xv.begin();\n\t\t\tX[xi].insert(make_pair(Y1[i],Y2[i]));\n\t\t\tint Lid=lower_bound(xL.begin(),xL.end(),make_pair(X1[i],Y1[i]))-xL.begin();\n\t\t\tint Rid=lower_bound(xR.begin(),xR.end(),make_pair(X1[i],Y2[i]))-xR.begin();\n\t\t\txyLD[Lid/B].push_back(make_pair(X1[i],Y1[i]));\n\t\t\txyRD[Rid/B].push_back(make_pair(X1[i],Y2[i]));\n\t\t\tint jd=lower_bound(xyL[Lid/B].begin(),xyL[Lid/B].end(),Y1[i])-xyL[Lid/B].begin();\n\t\t\txLP[Lid/B].add(jd+1,1);\n\t\t\tjd=lower_bound(xyR[Rid/B].begin(),xyR[Rid/B].end(),Y2[i])-xyR[Rid/B].begin();\n\t\t\txRP[Rid/B].add(jd+1,1);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint yi=lower_bound(yv.begin(),yv.end(),Y1[i])-yv.begin();\n\t\t\tY[yi].insert(make_pair(X1[i],X2[i]));\n\t\t\tint Lid=lower_bound(yL.begin(),yL.end(),make_pair(Y1[i],X1[i]))-yL.begin();\n\t\t\tint Rid=lower_bound(yR.begin(),yR.end(),make_pair(Y1[i],X2[i]))-yR.begin();\n\t\t\tyxLD[Lid/B].push_back(make_pair(Y1[i],X1[i]));\n\t\t\tyxRD[Rid/B].push_back(make_pair(Y1[i],X2[i]));\n\t\t\tint jd=lower_bound(yxL[Lid/B].begin(),yxL[Lid/B].end(),X1[i])-yxL[Lid/B].begin();\n\t\t\tyLP[Lid/B].add(jd+1,1);\n\t\t\tjd=lower_bound(yxR[Rid/B].begin(),yxR[Rid/B].end(),X2[i])-yxR[Rid/B].begin();\n\t\t\tyRP[Rid/B].add(jd+1,1);\n\t\t}\n\t}\n}", "accuracy": 0.3, "time_ms": 10, "memory_kb": 17248, "score_of_the_acc": 0, "final_rank": 10 }, { "submission_id": "aoj_0333_4749041", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 800005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(2*first_N); //★★1つの線分につき2点あるから、2*first_Nで初期化する★★\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,maxi));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\t//左側チェック\n\t\tif(at != SET[type][loc].begin()){\n\n\t\t\tat--;\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(mini,maxi));\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 181604, "score_of_the_acc": -1.0812, "final_rank": 7 }, { "submission_id": "aoj_0333_4749028", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 800005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(2*first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,-1));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->second || mini > at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 181580, "score_of_the_acc": -1.0811, "final_rank": 6 }, { "submission_id": "aoj_0333_4749025", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right <= node_left || left >= node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,-1));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->second || mini > at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi+1,loc,0,0,N,type);\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 20, "memory_kb": 97908, "score_of_the_acc": -0.4936, "final_rank": 12 }, { "submission_id": "aoj_0333_4749017", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,-1));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi <= at->second || mini >= at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 30, "memory_kb": 97968, "score_of_the_acc": -0.4967, "final_rank": 13 }, { "submission_id": "aoj_0333_4749002", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,0));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->second || mini > at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 30, "memory_kb": 97988, "score_of_the_acc": -0.4969, "final_rank": 14 }, { "submission_id": "aoj_0333_4748999", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,-1));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->second || mini > at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 20, "memory_kb": 97864, "score_of_the_acc": -0.4933, "final_rank": 11 }, { "submission_id": "aoj_0333_4748990", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,maxi));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->second || mini > at->first){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\t//左側チェック\n\t\tif(at != SET[type][loc].begin()){\n\n\t\t\tat--;\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(mini,maxi));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 96968, "score_of_the_acc": -0.4878, "final_rank": 15 }, { "submission_id": "aoj_0333_4748775", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right <= node_left || left >= node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,maxi));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\t//左側チェック\n\t\t/*if(at != SET[type][loc].begin()){\n\n\t\t\tat--;\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}*/\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\t//SET[type][loc].insert(make_pair(mini,maxi));\n\t\tSET[type][loc].insert(make_pair(maxi,mini));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 96980, "score_of_the_acc": -0.4879, "final_rank": 18 }, { "submission_id": "aoj_0333_4748753", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right <= node_left || left >= node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,maxi));\n\t\t//右側チェック\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\t//左側チェック\n\t\tif(at != SET[type][loc].begin()){\n\n\t\t\tat--;\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(mini,maxi));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 96988, "score_of_the_acc": -0.488, "final_rank": 19 }, { "submission_id": "aoj_0333_4748728", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right <= node_left || left >= node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,-1));\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(mini,maxi));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 96976, "score_of_the_acc": -0.4879, "final_rank": 17 }, { "submission_id": "aoj_0333_4748709", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 500005\ntypedef pair<int,int> P;\n\nenum Type{\n\tTATE,\n\tYOKO,\n};\n\nstruct Line{\n\n\tint x1,y1,x2,y2;\n};\n\nint N;\nvector<int> X,Y;\nset<int> table[2][SIZE];\nset<P> SET[2][SIZE];\nmap<int,int> map_X,map_Y;\nType rev[2] = {YOKO,TATE};\nLine line[SIZE];\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add(int left,int right,int value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right <= node_left || left >= node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\n\t\ttable[type][node_id].insert(value);\n\n\t}else{\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2,node_right,type);\n\t}\n}\n\nbool isCross(int loc,int mini,int maxi,Type type){\n\n\tloc += N-1;\n\n\twhile(true){\n\n\t\tif(table[type][loc].lower_bound(mini) != table[type][loc].upper_bound(maxi)){\n\n\t\t\treturn true;\n\t\t}\n\t\tif(loc == 0){\n\n\t\t\treturn false;\n\t\t}\n\t\tloc = (loc-1)/2;\n\t}\n\treturn false;\n}\n\n\nint main(){\n\n\tint first_N;\n\tscanf(\"%d\",&first_N);\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%d %d %d %d\",&line[i].x1,&line[i].y1,&line[i].x2,&line[i].y2);\n\n\t\tX.push_back(line[i].x1);\n\t\tX.push_back(line[i].x2);\n\t\tY.push_back(line[i].y1);\n\t\tY.push_back(line[i].y2);\n\t}\n\n\tsort(X.begin(),X.end());\n\tX.erase(unique(X.begin(),X.end()),X.end());\n\tfor(int i = 0; i < X.size(); i++){\n\n\t\tmap_X[X[i]] = i;\n\t}\n\n\tsort(Y.begin(),Y.end());\n\tY.erase(unique(Y.begin(),Y.end()),Y.end());\n\tfor(int i = 0; i < Y.size(); i++){\n\n\t\tmap_Y[Y[i]] = i;\n\t}\n\n\tN = 1;\n\tinit(first_N);\n\tType type;\n\tint loc,mini,maxi;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tif(line[i].x1 == line[i].x2){\n\n\t\t\ttype = TATE;\n\t\t\tloc = map_X[line[i].x1];\n\t\t\tmini = map_Y[min(line[i].y1,line[i].y2)];\n\t\t\tmaxi = map_Y[max(line[i].y1,line[i].y2)];\n\n\t\t}else{\n\n\t\t\ttype = YOKO;\n\t\t\tloc = map_Y[line[i].y1];\n\t\t\tmini = map_X[min(line[i].x1,line[i].x2)];\n\t\t\tmaxi = map_X[max(line[i].x1,line[i].x2)];\n\t\t}\n\n\t\t//垂直交差チェック\n\t\tif(isCross(loc,mini,maxi,rev[type])){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\t\t}\n\n\t\t//水平交差チェック\n\t\tauto at = SET[type][loc].lower_bound(make_pair(mini,maxi));//lower_boundでは要素1のみ見られるっぽい\n\t\tif(at != SET[type][loc].end()){\n\n\t\t\tif(maxi < at->first || mini > at->second){\n\n\t\t\t\t//Do nothing\n\t\t\t}else{\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\tadd(mini,maxi,loc,0,0,N-1,type);\n\t\tSET[type][loc].insert(make_pair(mini,maxi));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 96972, "score_of_the_acc": -0.4879, "final_rank": 16 }, { "submission_id": "aoj_0333_4576441", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\n\n\nstruct SegmentTree{\n int sz;\n vector<set<int>> seg;\n explicit SegmentTree(int n) {\n sz = 1;\n while(sz < n) sz <<= 1;\n seg.resize(2*sz);\n }\n\n void update(int k, int a, int b){\n for(a += sz, b += sz; a < b; a >>=1, b>>=1){\n if(a & 1) seg[a++].emplace(k);\n if(b & 1) seg[--b].emplace(k);\n }\n }\n\n bool query(int x, int a, int b){\n for (x += sz; x; x >>= 1) {\n if(seg[x].lower_bound(a) != seg[x].lower_bound(b)) return false;\n }\n return true;\n }\n\n};\nint main() {\n int n;\n cin >> n;\n vector<int> px(n), py(n), qx(n), qy(n);\n vector<int> zx(2*n), zy(2*n);\n for (int i = 0; i < n; ++i) {\n scanf(\"%d %d %d %d\", &px[i], &py[i], &qx[i], &qy[i]);\n zx[i] = px[i]; zx[i+n] = qx[i];\n zy[i] = py[i]; zy[i+n] = qy[i];\n }\n sort(zx.begin(), zx.end());\n zx.erase(unique(zx.begin(), zx.end()), zx.end());\n sort(zy.begin(), zy.end());\n zy.erase(unique(zy.begin(), zy.end()), zy.end());\n auto fx = [&](int x){ return lower_bound(zx.begin(),zx.end(), x) - zx.begin(); };\n auto fy = [&](int y){ return lower_bound(zy.begin(),zy.end(), y) - zy.begin(); };\n SegmentTree segx(zx.size()), segy(zy.size());\n vector<set<int>> sx(zx.size()), sy(zy.size());\n for (int i = 0; i < n; ++i) {\n px[i] = fx(px[i]), py[i] = fy(py[i]);\n qx[i] = fx(qx[i]), qy[i] = fy(qy[i]);\n if(px[i] > qx[i]) swap(px[i], qx[i]);\n if(py[i] > qy[i]) swap(py[i], qy[i]);\n if(px[i] == qx[i]){\n int ok = 1;\n if(!sx[px[i]].empty()){\n auto l = sx[px[i]].lower_bound(py[i]<<1), r = sx[px[i]].lower_bound((qy[i]+1)<<1);\n if(l != r){\n ok = 0;\n }else if(l != sx[px[i]].end() && (*l&1)){\n ok = 0;\n }\n }\n if(ok && !segx.query(px[i], py[i], qy[i]+1)){\n ok = 0;\n }\n if(ok){\n sx[px[i]].emplace((py[i]<<1)|0);\n sx[px[i]].emplace((qy[i]<<1)|1);\n segy.update(px[i], py[i], qy[i]+1);\n puts(\"1\");\n }else {\n puts(\"0\");\n }\n }else {\n int ok = 1;\n if(!sy[py[i]].empty()){\n auto l = sy[py[i]].lower_bound(px[i]<<1), r = sy[py[i]].lower_bound((qx[i]+1)<<1);\n if(l != r){\n ok = 0;\n }else if(l != sy[py[i]].end() && (*l&1)){\n ok = 0;\n }\n }\n if(ok && !segy.query(py[i], px[i], qx[i]+1)){\n ok = 0;\n }\n if(ok){\n sy[py[i]].emplace((px[i]<<1)|0);\n sy[py[i]].emplace((qx[i]<<1)|1);\n segx.update(py[i], px[i], qx[i]+1);\n puts(\"1\");\n }else puts(\"0\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 85448, "score_of_the_acc": -0.4682, "final_rank": 3 }, { "submission_id": "aoj_0333_4575461", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\n\nstruct LazySegmentTree{\n int sz, height{};\n vector<set<int>> seg; vector<set<int>> lazy;\n explicit LazySegmentTree(int n) {\n sz = 1; while(sz < n) sz <<= 1, height++;\n seg.resize(2*sz);\n lazy.resize(2*sz);\n }\n bool reflect(int k){\n if(lazy[k].empty()) return false;\n for (auto &&i : lazy[k]) {\n seg[k].emplace(i);\n }\n return true;\n }\n\n void eval(int k){\n if(lazy[k].empty()) return;\n for (auto &&i : lazy[k]) {\n lazy[(k<<1)|0].emplace(i);\n lazy[(k<<1)|1].emplace(i);\n }\n reflect(k);\n lazy[k].clear();\n }\n void thrust(int k){ for (int i = height; i; --i) eval(k>>i); }\n void recalc(int k) {\n while(k >>= 1) {\n if(reflect((k<<1)|0)){\n for (auto &&i : lazy[(k<<1)|0]) {\n seg[k].emplace(i);\n }\n }\n if(reflect((k<<1)|1)){\n for (auto &&i : lazy[(k<<1)|1]) {\n seg[k].emplace(i);\n }\n }\n }\n }\n void update(int a, int b, const int &x){\n thrust(a += sz); thrust(b += sz-1);\n for (int l = a, r = b+1;l < r; l >>=1, r >>= 1) {\n if(l&1) lazy[l].emplace(x), l++;\n if(r&1) --r, lazy[r].emplace(x);\n }\n recalc(a);\n recalc(b);\n }\n\n bool query(int a, int b, int vl, int vr){ // [l, r)\n thrust(a += sz);\n thrust(b += sz-1);\n for(int l = a, r = b+1; l < r; l >>=1, r>>=1) {\n if (l & 1) {\n reflect(l);\n if(seg[l].lower_bound(vl) != seg[l].lower_bound(vr)) return false;\n l++;\n }\n if (r & 1) {\n --r;\n reflect(r);\n if(seg[r].lower_bound(vl) != seg[r].lower_bound(vr)) return false;\n }\n }\n return true;\n }\n};\n\nint main() {\n int n;\n cin >> n;\n vector<int> px(n), py(n), qx(n), qy(n);\n vector<int> zx(2*n), zy(2*n);\n for (int i = 0; i < n; ++i) {\n scanf(\"%d %d %d %d\", &px[i], &py[i], &qx[i], &qy[i]);\n zx[i] = px[i]; zx[i+n] = qx[i];\n zy[i] = py[i]; zy[i+n] = qy[i];\n }\n sort(zx.begin(), zx.end());\n zx.erase(unique(zx.begin(), zx.end()), zx.end());\n sort(zy.begin(), zy.end());\n zy.erase(unique(zy.begin(), zy.end()), zy.end());\n auto fx = [&](int x){ return lower_bound(zx.begin(),zx.end(), x) - zx.begin(); };\n auto fy = [&](int y){ return lower_bound(zy.begin(),zy.end(), y) - zy.begin(); };\n LazySegmentTree segx(zx.size()), segy(zy.size());\n for (int i = 0; i < n; ++i) {\n px[i] = fx(px[i]), py[i] = fy(py[i]);\n qx[i] = fx(qx[i]), qy[i] = fy(qy[i]);\n if(px[i] > qx[i]) swap(px[i], qx[i]);\n if(py[i] > qy[i]) swap(py[i], qy[i]);\n if(segx.query(px[i], qx[i]+1, py[i], qy[i]+1) && segy.query(py[i], qy[i]+1, px[i], qx[i]+1)){\n puts(\"1\");\n if(px[i] == qx[i]) segy.update(py[i], qy[i]+1, px[i]);\n else segx.update(px[i], qx[i]+1, py[i]);\n } else puts(\"0\");\n }\n return 0;\n}", "accuracy": 0.5, "time_ms": 3580, "memory_kb": 151736, "score_of_the_acc": -1.8183, "final_rank": 9 }, { "submission_id": "aoj_0333_3972748", "code_snippet": "#include <iostream>\n#include <functional>\n#include <algorithm>\n#include <vector>\n#include <set>\n#include <unordered_map>\n#include <utility>\nusing namespace std;\nusing ll = int;\n\nset<pair<ll, ll> > x_p[400005];\nset<pair<ll, ll> > y_p[400005];\nset<ll> x_set[1 << 20];\nset<ll> y_set[1 << 20];\n\nvoid update(int a,int b, int k, int l, int r, int x, int x_tag) {\n\tif (b <= l || r <= a) return;\n\t\n\tif (l <= a && b <= r) {\n\t\tif (x_tag) x_set[k].insert(x);\n\t\telse y_set[k].insert(x);\n\t\treturn;\n\t}\n\telse {\n\t\tupdate(a, (a + b) / 2, k * 2 + 0, l, r, x, x_tag);\n\t\tupdate((a + b) / 2, b, k * 2 + 1, l, r, x, x_tag);\n\t}\n}\n\nvoid update(int sx, int tx, int x, int x_tag) {\n\tupdate(0, 1 << 19, 1, sx, tx, x, x_tag);\n}\n\nbool query(int a, int b, int k, int kx, int s, int t, int x_tag) {\n if (b <= kx || kx < a) return false;\n\t\n\tbool f = false;\n\tif (x_tag) {\n\t\tauto itr = x_set[k].lower_bound(s);\n\t\tif (itr != x_set[k].end() && *itr <= t) f = true;\n\t}\n\telse {\n\t\tauto itr = y_set[k].lower_bound(s);\n\t\tif (itr != y_set[k].end() && *itr <= t) f = true;\n\t}\n\n if (b - a > 1) {\n f |= query(a, (a + b) / 2, k * 2 + 0, kx, s, t, x_tag);\n f |= query((a + b) / 2, b, k * 2 + 1, kx, s, t, x_tag);\n }\n\t\n\treturn f;\n}\n\nbool query(int kx, int s, int t, int x_tag) {\n return query(0, 1 << 19, 1, kx, s, t, x_tag);\n}\n\nunordered_map<ll, ll> zip;\nll n;\nll sx[100000];\nll sy[100000];\nll tx[100000];\nll ty[100000];\n\nint main() {\n {\n vector<ll> point;\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> sx[i] >> sy[i] >> tx[i] >> ty[i];\n\t\t\n point.push_back(sx[i]);\n point.push_back(sy[i]);\n point.push_back(tx[i]);\n point.push_back(ty[i]);\n }\n\t\n sort(point.begin(), point.end());\n point.erase(unique(point.begin(), point.end()), point.end());\n for (int i = 0; i < point.size(); i++) {\n zip[point[i]] = i;\n }\n }\n\t\n for (int i = 0; i < n; i++) {\n ll px, py;\n ll qx, qy;\n\t\t\n px = zip[sx[i]];\n py = zip[sy[i]];\n qx = zip[tx[i]];\n qy = zip[ty[i]];\n \n if (px > qx) swap(px, qx);\n if (py > qy) swap(py, qy);\n\t\t\n if (py == qy) {\n auto itr1 = x_p[py].lower_bound({px, qx});\n bool f = false;\n\n if (itr1 != x_p[py].end()) {\n if (itr1->first <= qx) {\n f |= true;\n }\n }\n if (itr1 != x_p[py].begin()) {\n itr1--;\n if (itr1->second >= px) {\n f |= true;\n }\n }\n \n if (f ||\n query(py, px, qx, 1)) {\n cout << 0 << '\\n';\n }\n else {\n cout << 1 << '\\n';\n x_p[py].insert({px, qx});\n update(px, qx + 1, py, 0);\n }\n }\n else {\n auto itr1 = y_p[px].lower_bound({py, qy});\n bool f = false;\n\n if (itr1 != y_p[px].end()) {\n if (itr1->first <= qy) {\n f |= true;\n }\n }\n if (itr1 != y_p[px].begin()) {\n itr1--;\n if (itr1->second >= py) {\n f |= true;\n }\n }\n \n if (f ||\n query(px, py, qy, 0)) {\n cout << 0 << '\\n';\n }\n else {\n cout << 1 << '\\n';\n y_p[px].insert({py, qy});\n update(py, qy + 1, px, 1);\n }\n }\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 165420, "score_of_the_acc": -0.9968, "final_rank": 5 }, { "submission_id": "aoj_0333_3972688", "code_snippet": "#include <iostream>\n#include <functional>\n#include <algorithm>\n#include <vector>\n#include <set>\n#include <unordered_map>\n#include <utility>\nusing namespace std;\nusing ll = int;\n\nset<pair<ll, ll> > x_p[400005];\nset<pair<ll, ll> > y_p[400005];\nset<ll> x_set[1 << 20];\nset<ll> y_set[1 << 20];\n\nvoid update(int a,int b, int k, int l, int r, int x, int x_tag) {\n\tif (b <= l || r <= a) return;\n\t\n\tif (l <= a && b <= r) {\n\t\tif (x_tag) x_set[k].insert(x);\n\t\telse y_set[k].insert(x);\n\t\treturn;\n\t}\n\telse {\n\t\tupdate(a, (a + b) / 2, k * 2 + 0, l, r, x, x_tag);\n\t\tupdate((a + b) / 2, b, k * 2 + 1, l, r, x, x_tag);\n\t}\n}\n\nvoid update(int sx, int tx, int x, int x_tag) {\n\tupdate(0, 1 << 19, 1, sx, tx, x, x_tag);\n}\n\nbool query(int a, int b, int k, int kx, int s, int t, int x_tag) {\n if (b <= kx || kx < a) return false;\n\t\n\tbool f = false;\n\tif (x_tag) {\n\t\tauto itr = x_set[k].lower_bound(s);\n\t\tif (itr != x_set[k].end() && *itr <= t) f = true;\n\t}\n\telse {\n\t\tauto itr = y_set[k].lower_bound(s);\n\t\tif (itr != y_set[k].end() && *itr <= t) f = true;\n\t}\n\n if (b - a > 1) {\n f |= query(a, (a + b) / 2, k * 2 + 0, kx, s, t, x_tag);\n f |= query((a + b) / 2, b, k * 2 + 1, kx, s, t, x_tag);\n }\n\t\n\treturn f;\n}\n\nbool query(int kx, int s, int t, int x_tag) {\n return query(0, 1 << 19, 1, kx, s, t, x_tag);\n}\n\nunordered_map<ll, ll> zip;\nll n;\nll sx[100000];\nll sy[100000];\nll tx[100000];\nll ty[100000];\n\nint main() {\n {\n vector<ll> point;\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> sx[i] >> sy[i] >> tx[i] >> ty[i];\n\t\t\n point.push_back(sx[i]);\n point.push_back(sy[i]);\n point.push_back(tx[i]);\n point.push_back(ty[i]);\n }\n\t\n sort(point.begin(), point.end());\n point.erase(unique(point.begin(), point.end()), point.end());\n for (int i = 0; i < point.size(); i++) {\n zip[point[i]] = i;\n }\n }\n\t\n for (int i = 0; i < n; i++) {\n ll px, py;\n ll qx, qy;\n\t\t\n px = zip[sx[i]];\n py = zip[sy[i]];\n qx = zip[tx[i]];\n qy = zip[ty[i]];\n \n if (px > qx) swap(px, qx);\n if (py > qy) swap(py, qy);\n\t\t\n if (py == qy) {\n auto itr1 = x_p[py].lower_bound({px, qx});\n bool f = false;\n\n if (itr1 != x_p[py].end()) {\n if (itr1->first <= qx && qx <= itr1->second) {\n f |= true;\n }\n }\n if (itr1 != x_p[py].begin()) {\n itr1--;\n if (itr1->first <= px && px <= itr1->second) {\n f |= true;\n }\n }\n \n if (f ||\n query(py, px, qx, 1)) {\n cout << 0 << '\\n';\n }\n else {\n cout << 1 << '\\n';\n x_p[py].insert({px, qx});\n update(px, qx + 1, py, 0);\n }\n }\n else {\n auto itr1 = y_p[px].lower_bound({py, qy});\n bool f = false;\n\n if (itr1 != y_p[px].end()) {\n if (itr1->first <= qy && qy <= itr1->second) {\n f |= true;\n }\n }\n if (itr1 != y_p[px].begin()) {\n itr1--;\n if (itr1->first <= py && py <= itr1->second) {\n f |= true;\n }\n }\n \n if (f ||\n query(px, py, qy, 0)) {\n cout << 0 << '\\n';\n }\n else {\n cout << 1 << '\\n';\n y_p[px].insert({py, qy});\n update(py, qy + 1, px, 1);\n }\n }\n }\n \n return 0;\n}", "accuracy": 0.2, "time_ms": 40, "memory_kb": 138948, "score_of_the_acc": -0.7489, "final_rank": 20 } ]
aoj_0331_cpp
スケジューラ あなたはユニークなオペレーティングシステム「ウンズグネ15」の開発に取り組んでおり、性能を決定付けるスケジューラの設計に頭を悩ませている。スケジューラとは、実行すべき処理をタスクという単位で表現し、それらをどの順序で実行するかを決定するプログラムである。スケジューラはタスクに1から N の番号をつけて管理する。全てのタスクは K 個の属性 f 1 , f 2 ,..., f K を持ち、各属性にはそれぞれ固有の値が設定されている。ただし、ある2つのタスクについて、対応する属性の値すべてが同じになることはない。 あるタスクには、そのタスクの実行を始める前までに実行を完了していなければならないタスクが与えられることがある。タスクAがタスクBの前に完了していなければならないことを「タスクA → タスクB」と表す。例えば、タスク1 → タスク2、タスク3 → タスク2という関係があれば、タスク2を処理する前にタスク1とタスク3の両方の処理が終わっていなければならない。このような関係をタスク間の依存関係という。ただし、あるタスクから依存関係をたどっていって、そのタスクにたどり着くことはない。 スケジューラは依存関係に従って、実行順序を決定する。しかし、依存関係だけでは順序が一通りに定まらない場合がある。そのような場合は、各タスクが持つ属性の値によって、次に処理するタスクを選択する。 ウンズグネ15のタスクは属性を複数もつため、すべての属性の値を考慮して実行順序を決定する必要がある。そのために、属性を比較する順番を定める評価順序を用いる。評価順序が最も先の属性を比較し、その属性の値が最も大きいタスクを選択する。そのようなタスクが複数ある場合は、評価順序がその次の属性で比較し、以下同様な手順を繰り返す。例えば、以下の3 つの属性を持つ3 つのタスクについて考える。 タスク\属性 f 1 f 2 f 3 X 3 3 2 Y 3 2 2 Z 3 1 3 評価順序が f 1 f 2 f 3 、 f 2 f 1 f 3 、または f 2 f 3 f 1 に設定されている場合は、タスクX が選ばれる。また、評価順序が f 1 f 3 f 2 、 f 3 f 1 f 2 、または f 3 f 2 f 1 に設定されている場合はタスクZ が選ばれる。 ウンズグネ15のスケジューラの特徴は、属性の評価順序が途中で何度でも変更できることである。評価順序は、ある個数のタスクの実行が完了した時点で変更できる。ただし、スケジューラが最初に使う評価順序はあらかじめ決まっている。 各タスクの属性の値、タスクの依存関係、評価順序の変更情報が与えられたとき、タスクを実行する順序を報告するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N K f 1,1 f 1,2 ... f 1,K f 2,1 f 2,2 ... f 2,K : f N,1 f N,2 ... f N,K D a 1 b 1 a 2 b 2 : a D b D e 0,1 e 0,2 ... e 0,K R m 1 e 1,1 e 1,2 ...… e 1,K m 2 e 2,1 e 2,2 ...… e 2,K : m R e R,1 e R,2 ...… e R,K 1行目に、タスクの数 N (2 ≤ N ≤ 50000) と、各タスクが持つ属性の数 K (1 ≤ K ≤ 4) が与えられる。続く N 行に、タスク i が持つ属性の値 f i,j (1 ≤ f i,j ≤ 100000) が与えられる。続く1行に、依存関係の個数 D (0 ≤ D ≤ 200000) が与えられる。続く D 行に依存関係 a i → b i (1 ≤ a i , b i ≤ N ) が与えられる。 続く1行に、最初の評価順序 e 0,j (1 ≤ e 0,j ≤ K ) が与えられる。続く1行に、評価順序の変更回数 R (0 ≤ R < N ) が与えられる。続く R 行に、評価順序の変更情報が与えられる。 i 回目の変更情報は、実行が完了したタスクの個数 m i (1 ≤ m i < N ) と評価順序 e i,j (1 ≤ e i,j ≤ K ) からなり、全部で m i 個のタスクの実行が完了した時点で、評価順序を e i,1 , e i,2 ,... , e i,K に変更することを示す。 評価順序の変更情報は以下の条件を満たす。 e i,1 , e i,2 ,..., e i,K 中に同じ値は2つ以上現れない。 i < j のとき、 m i < m j である。 Output スケジューラが処理する順番に、タスクの番号を出力する。 Sample Input 1 5 3 1 5 2 3 8 5 1 2 3 5 5 5 4 8 2 0 1 2 3 2 2 2 3 1 4 3 1 2 Sample Output 1 4 5 2 1 3 Sample Input 2 5 2 1 1 2 1 3 1 4 4 5 2 3 1 4 2 4 2 5 1 2 1 3 2 1 Sample Output 2 3 2 5 1 4
[ { "submission_id": "aoj_0331_11030956", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N, K;\n\tcin >> N >> K;\n\tint fac = 1;\n\trep(i, 1, K + 1) fac *= i;\n\t\n\tvector F(N, vector<int>(K));\n\trep(i, 0, N) rep(j, 0, K) cin >> F[i][j];\n\t\n\tint D;\n\tcin >> D;\n\tvector<vector<int>> G(N);\n\trep(i, 0, D) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\t--a, --b;\n\t\tG[a].push_back(b);\n\t}\n\t\n\tvector<int> perm(K);\n\trep(i, 0, K) perm[i] = i;\n\t\n\tvector rank(fac, vector<int>(N));\n\tmap<int, int> ID;\n\tint cnter = 0;\n\tdo {\n\t\tvector<int> S(N);\n\t\trep(i, 0, N) S[i] = i;\n\t\t\n\t\tsort(S.begin(), S.end(), [&](int i, int j) {\n\t\t\trep(k, 0, K) {\n\t\t\t\tif (F[i][perm[k]] != F[j][perm[k]]) return F[i][perm[k]] < F[j][perm[k]];\n\t\t\t}\n\t\t\treturn true;\n\t\t});\n\t\t\n\t\treverse(S.begin(), S.end());\n\t\t\n\t\trep(i, 0, N) rank[cnter][S[i]] = i;\n\t\t\n\t\tint hash = 0;\n\t\trep(i, 0, K) {\n\t\t\thash *= 10;\n\t\t\thash += perm[i] + 1;\n\t\t}\n\t\tID[hash] = cnter;\n\t\t\n\t\t++cnter;\n\t} while (next_permutation(perm.begin(), perm.end()));\n\t\n\tint hash = 0;\n\trep(i, 0, K) {\n\t\tint E;\n\t\tcin >> E;\n\t\thash *= 10;\n\t\thash += E;\n\t}\n\tint nowFunc = ID[hash];\n\t\n\tint R;\n\tcin >> R;\n\tvector<int> func(N, -1);\n\trep(i, 0, R) {\n\t\tint hash = 0;\n\t\tint m;\n\t\tcin >> m;\n\t\trep(j, 0, K) {\n\t\t\tint E;\n\t\t\tcin >> E;\n\t\t\thash *= 10;\n\t\t\thash += E;\n\t\t}\n\t\tfunc[m - 1] = ID[hash];\n\t}\n\t\n\tvector<int> deg(N);\n\trep(v, 0, N) {\n\t\tfor (int to : G[v]) ++deg[to];\n\t}\n\t\n\tvector<set<pair<int, int>>> que(fac);\n\trep(v, 0, N) if (deg[v] == 0) {\n\t\trep(i, 0, fac) que[i].insert({rank[i][v], v});\n\t}\n\t\n\trep(itr, 0, N) {\n\t\tauto p = *que[nowFunc].begin();\n\t\tint v = p.second;\n\t\t\n\t\tcout << v + 1 << '\\n';\n\t\t\n\t\trep(i, 0, fac) que[i].erase({rank[i][v], v});\n\t\t\n\t\tfor (int to : G[v]) if (--deg[to] == 0) {\n\t\t\trep(i, 0, fac) que[i].insert({rank[i][to], to});\n\t\t}\n\t\t\n\t\tif (func[itr] != -1) nowFunc = func[itr];\n\t}\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 68552, "score_of_the_acc": -0.7024, "final_rank": 12 }, { "submission_id": "aoj_0331_10958585", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,k,n) for(int i = (int)(k); i < (int)(n); i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(a) a.begin(), a.end()\n#define MS(m,v) memset(m,v,sizeof(m))\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\nconst int MOD = 1e9 + 7;\ntemplate<class T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate<class T> T &chmax(T &a, const T &b) { return a = max(a, b); }\ntemplate<class T>\nistream& operator >> (istream& is, vector<T>& v)\n{\n\tfor (auto &i : v) is >> i;\n\treturn is;\n}\ntemplate<class T>\nostream& operator<<(ostream& os, vector<T>& v)\n{\n\tconst string delimiter = \"\\n\";\n\tREP(i, v.size())\n\t{\n\t\tos << v[i];\n\t\tif (i != v.size() - 1) os << delimiter;\n\t}\n\treturn os;\n}\n/*--------------------template--------------------*/\n\nmap<vi, int> id;\n\nvoid init(int k)\n{\n\tvi v;\n\tREP(i, k) v.push_back(i);\n\tint tmp = 0;\n\tdo\n\t{\n\t\tid[v] = tmp;\n\t\ttmp++;\n\t} while (next_permutation(ALL(v)));\n}\n\nint main()\n{\n\tcin.sync_with_stdio(false); cout << fixed << setprecision(10);\n\tint n, k;\n\tcin >> n >> k;\n\tinit(k);\n\tvector<vi> f(n, vi(k));\n\tREP(i, n) cin >> f[i];\n\tvector<vi> dag(n);\n\tvi in(n);\n\tint d; cin >> d;\n\tREP(i, d)\n\t{\n\t\tint a, b; cin >> a >> b;\n\t\ta--; b--;\n\t\tdag[a].push_back(b);\n\t\tin[b]++;\n\t}\n\tvector<priority_queue<pair<vi, int>>> que(id.size());\n\tREP(i, n)\n\t{\n\t\tif (in[i] == 0)\n\t\t{\n\t\t\tfor (auto p : id)\n\t\t\t{\n\t\t\t\tvi pri;\n\t\t\t\tfor (auto j : p.first)\n\t\t\t\t{\n\t\t\t\t\tpri.push_back(f[i][j]);\n\t\t\t\t}\n\t\t\t\tque[p.second].push(make_pair(pri, i));\n\t\t\t}\n\t\t}\n\t}\n\tvi e(k);\n\tREP(i, k)\n\t{\n\t\tcin >> e[i];\n\t\te[i]--;\n\t}\n\tint r; cin >> r;\n\tint cnt = 0;\n\tint nex; cin >> nex;\n\tvector<bool> used(n);\n\twhile (1)\n\t{\n\t\tint t = que[id[e]].top().second;\n\t\tque[id[e]].pop();\n\t\tif (used[t]) continue;\n\t\tused[t] = true;\n\t\tcout << t + 1 << endl;\n\t\tcnt++;\n\n\t\tfor (auto i : dag[t])\n\t\t{\n\t\t\tin[i]--;\n\t\t\tif (in[i] == 0)\n\t\t\t{\n\t\t\t\tfor (auto p : id)\n\t\t\t\t{\n\t\t\t\t\tvi pri;\n\t\t\t\t\tfor (auto j : p.first)\n\t\t\t\t\t{\n\t\t\t\t\t\tpri.push_back(f[i][j]);\n\t\t\t\t\t}\n\t\t\t\t\tque[p.second].push(make_pair(pri, i));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (cnt == n) break;\n\t\tif (cnt == nex)\n\t\t{\n\t\t\tREP(i, k)\n\t\t\t{\n\t\t\t\tcin >> e[i];\n\t\t\t\te[i]--;\n\t\t\t}\n\t\t\tif (!(cin >> nex))\n\t\t\t{\n\t\t\t\tnex = 1e9;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 82424, "score_of_the_acc": -0.6588, "final_rank": 11 }, { "submission_id": "aoj_0331_7074826", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nint k;\nvint tmp;\n\nint main() {\n\tint fact[5] = { 1 };\n\trep(i, 4)fact[i + 1] = fact[i] * (i + 1);\n\tint n;\n\tcin >> n >> k;\n\ttmp.resize(k);\n\tmap<vint, int>perm;\n\tvvint order(fact[k], vint(n));\n\t{\n\t\tvvint f(n, vint(k + 1));\n\t\trep(i, n)rep(j, k)cin >> f[i][j];\n\t\trep(i, n)f[i][k] = i;\n\t\trep(i, k)tmp[i] = i;\n\t\tint i = 0;\n\t\tdo {\n\t\t\tsort(all(f), [](vint a, vint b) {\n\t\t\t\trep(i, k) {\n\t\t\t\t\tif (a[tmp[i]] < b[tmp[i]])return true;\n\t\t\t\t\tif (a[tmp[i]] > b[tmp[i]])return false;\n\t\t\t\t}\n\t\t\t\treturn true;\n\t\t\t\t});\n\t\t\trep(j, n)order[i][f[j][k]] = j;\n\t\t\tperm[tmp] = i;\n\t\t\ti++;\n\t\t} while (next_permutation(all(tmp)));\n\t}\n\tint d;\n\tcin >> d;\n\tvvint g(n);\n\tvint indegree(n);\n\trep(i, d) {\n\t\tint a, b;\n\t\tcin >> a >> b; a--; b--;\n\t\tg[a].push_back(b);\n\t\tindegree[b]++;\n\t}\n\tvector<priority_queue<pint>>que(fact[k]);\n\tvbool visited(n, false);\n\trep(i, fact[k]) {\n\t\trep(j, n) {\n\t\t\tif (indegree[j] == 0) {\n\t\t\t\tque[i].push({ order[i][j],j });\n\t\t\t}\n\t\t}\n\t}\n\trep(i, k) {\n\t\tcin >> tmp[i]; tmp[i]--;\n\t}\n\tint nowperm = perm[tmp];\n\tint r;\n\tcin >> r;\n\tqueue<pint> e;\n\trep(i, r) {\n\t\tint m;\n\t\tcin >> m;\n\t\trep(j, k) {\n\t\t\tcin >> tmp[j]; tmp[j]--;\n\t\t}\n\t\te.push({ m,perm[tmp] });\n\t}\n\n\tint cnt = 0;\n\twhile (cnt < n) {\n\t\tif (e.size() && e.front().first == cnt) {\n\t\t\tnowperm = e.front().second; e.pop();\n\t\t}\n\t\tauto [o, p] = que[nowperm].top(); que[nowperm].pop();\n\t\tif (visited[p])continue;\n\t\tvisited[p] = true; cnt++;\n\t\tcout << p + 1 << endl;\n\t\tfor (auto np : g[p]) {\n\t\t\tif (!(--indegree[np])) {\n\t\t\t\trep(i, fact[k]) {\n\t\t\t\t\tque[i].push({ order[i][np],np });\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 21900, "score_of_the_acc": -0.431, "final_rank": 10 }, { "submission_id": "aoj_0331_7073966", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\nvi g[100000];\nvi need(100000);\nvi cnt(100000);\n\nint solve(){\n int n,k; cin >> n >> k;\n vector<vi> a(n , vi(k));\n rep(i,0,n)rep(j,0,k)cin >> a[i][j];\n int d; cin >> d;\n rep(i,0,d){\n int x,y; cin >> x >> y;\n --x; --y;\n g[x].push_back(y);\n need[y]++;\n }\n vector<vi> e(n);\n rep(i,0,k){\n int x; cin >> x;\n --x;\n e[0].push_back(x);\n }\n int r; cin >> r;\n rep(i,0,r){\n int m; cin >> m;\n rep(j,0,k){\n int x; cin >> x;\n --x;\n e[m].push_back(x);\n }\n }\n vi v(k);\n rep(i,0,k)v[i] = i;\n map<vi , vi> ord;\n int fac = 0;\n do\n {\n vector<vi> b(n);\n rep(i,0,n){\n rep(j,0,k)b[i].push_back(a[i][v[j]]);\n b[i].push_back(i);\n }\n sort(all(b));\n reverse(all(b));\n ord[v].resize(n);\n rep(i,0,n){\n ord[v][b[i].back()] = i;\n }\n fac++;\n } while (next_permutation(all(v)));\n vi can;\n rep(i,0,n)if(need[i] == 0)can.push_back(i);\n vi ans(n);\n vi now;\n map<vi , set<pi>> s;\n sort(all(v));\n do\n {\n rep(i,0,can.size()){\n s[v].insert(pi(ord[v][can[i]] , can[i]));\n }\n } while (next_permutation(all(v)));\n rep(i,0,n){\n if(e[i].size() != 0)now = e[i];\n pi tmp = *s[now].begin();\n int j = tmp.second;\n ans[i] = j;\n vi add;\n for(auto c:g[j]){\n cnt[c]++;\n if(cnt[c] == need[c])add.push_back(c);\n }\n sort(all(v));\n do\n {\n s[v].erase(pi(ord[v][j] , j));\n rep(l,0,add.size()){\n s[v].insert(pi(ord[v][add[l]] , add[l]));\n }\n } while (next_permutation(all(v)));\n }\n rep(i,0,n)cout << ans[i]+1 << endl;\n\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1260, "memory_kb": 72992, "score_of_the_acc": -0.9566, "final_rank": 18 }, { "submission_id": "aoj_0331_6966901", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0331.cc: スケジューラ\n */\n\n#include<cstdio>\n#include<vector>\n#include<set>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 50000;\n\n/* typedef */\n\ntypedef vector<int> vi;\n\nstruct Task {\n vi fs;\n int i;\n Task() {}\n Task(vi _fs, int _i): fs(_fs), i(_i) {}\n bool operator<(const Task &t) const { return fs > t.fs; }\n};\n\n/* global variables */\n\nvi pss[24], fss[MAX_N][24], nbrs[MAX_N];\nint pns[MAX_N], ms[MAX_N], sls[MAX_N], as[MAX_N];\nset<Task> tss[24];\n\n/* subroutines */\n\nvoid readv(int k, vi &v) {\n v.resize(k);\n for (int i = 0; i < k; i++) scanf(\"%d\", &v[i]), v[i]--;\n}\n\nvoid pushtask(int l, int u) {\n for (int i = 0; i < l; i++)\n tss[i].insert(Task(fss[u][i], u));\n}\n\nvoid erasetask(int l, int u) {\n for (int i = 0; i < l; i++)\n tss[i].erase(Task(fss[u][i], u));\n}\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n, k;\n scanf(\"%d%d\", &n, &k);\n\n vi ps(k);\n for (int i = 0; i < k; i++) ps[i] = i;\n\n int l = 0;\n do {\n pss[l++] = ps;\n } while (next_permutation(ps.begin(), ps.end()));\n sort(pss, pss + l);\n //printf(\"l=%d\\n\", l);\n\n for (int i = 0; i < n; i++) {\n vi fs;\n readv(k, fs);\n for (int j = 0; j < l; j++) {\n fss[i][j].resize(k);\n for (int h = 0; h < k; h++) fss[i][j][h] = fs[pss[j][h]];\n }\n }\n\n int m;\n scanf(\"%d\", &m);\n\n for (int i = 0; i < m; i++) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n u--, v--;\n nbrs[u].push_back(v);\n pns[v]++;\n }\n\n vi es;\n readv(k, es);\n int sel = lower_bound(pss, pss + l, es) - pss;\n\n int r;\n scanf(\"%d\", &r);\n\n for (int i = 0; i < r; i++) {\n scanf(\"%d\", ms + i);\n readv(k, es);\n sls[i] = lower_bound(pss, pss + l, es) - pss;\n }\n\n for (int u = 0; u < n; u++)\n if (pns[u] == 0) pushtask(l, u);\n \n for (int i = 0, cm = 0; ! tss[0].empty();) {\n Task t = *tss[sel].begin();\n int u = t.i;\n erasetask(l, u);\n\n as[cm++] = u;\n\n for (auto v: nbrs[u])\n if (--pns[v] == 0) pushtask(l, v);\n\n if (i < r && cm == ms[i]) sel = sls[i++];\n }\n\n for (int i = 0; i < n; i++) printf(\"%d\\n\", as[i] + 1);\n return 0;\n}", "accuracy": 1, "time_ms": 1260, "memory_kb": 201772, "score_of_the_acc": -1.6513, "final_rank": 19 }, { "submission_id": "aoj_0331_5943674", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N, K;\n cin >> N >> K;\n vector<vector<int>> f(N, vector<int>(K));\n for (int i = 0; i < N; i++){\n for (int j = 0; j < K; j++){\n cin >> f[i][j];\n }\n }\n int D;\n cin >> D;\n vector<vector<int>> E(N);\n for (int i = 0; i < D; i++){\n int a, b;\n cin >> a >> b;\n a--;\n b--;\n E[a].push_back(b);\n }\n vector<int> e(K);\n for (int i = 0; i < K; i++){\n cin >> e[i];\n e[i]--;\n }\n int R;\n cin >> R;\n vector<int> m(R);\n vector<vector<int>> e2(R, vector<int>(K));\n for (int i = 0; i < R; i++){\n cin >> m[i];\n for (int j = 0; j < K; j++){\n cin >> e2[i][j];\n e2[i][j]--;\n }\n }\n vector<int> d(N, 0);\n for (int i = 0; i < N; i++){\n for (int j : E[i]){\n d[j]++;\n }\n }\n vector<int> p(K);\n for (int i = 0; i < K; i++){\n p[i] = i;\n }\n vector<vector<int>> P;\n while (true){\n P.push_back(p);\n if (!next_permutation(p.begin(), p.end())){\n break;\n }\n }\n int F = P.size();\n vector<vector<int>> pr(F, vector<int>(N));\n for (int i = 0; i < F; i++){\n vector<pair<vector<int>, int>> P2(N);\n for (int j = 0; j < N; j++){\n vector<int> f2(K);\n for (int k = 0; k < K; k++){\n f2[k] = f[j][P[i][k]];\n }\n P2[j] = make_pair(f2, j);\n }\n sort(P2.begin(), P2.end());\n for (int j = 0; j < N; j++){\n pr[i][P2[j].second] = j;\n }\n }\n vector<priority_queue<pair<int, int>>> pq(F);\n for (int i = 0; i < F; i++){\n for (int j = 0; j < N; j++){\n if (d[j] == 0){\n pq[i].push(make_pair(pr[i][j], j));\n }\n }\n }\n vector<int> upd(N, -1);\n for (int i = 0; i < R; i++){\n upd[m[i]] = i;\n }\n vector<bool> used(N, false);\n for (int i = 0; i < N; i++){\n if (upd[i] != -1){\n e = e2[upd[i]];\n }\n int id = lower_bound(P.begin(), P.end(), e) - P.begin();\n while (used[pq[id].top().second]){\n pq[id].pop();\n }\n int v = pq[id].top().second;\n cout << v + 1 << endl;\n pq[id].pop();\n used[v] = true;\n for (int w : E[v]){\n d[w]--;\n if (d[w] == 0){\n for (int j = 0; j < F; j++){\n pq[j].push(make_pair(pr[j][w], w));\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 27724, "score_of_the_acc": -0.1664, "final_rank": 6 }, { "submission_id": "aoj_0331_5022788", "code_snippet": "#include<iostream>\n#include<queue>\n#include<vector>\n#include<map>\nusing namespace std;\nint N,K;\nint E[50000];\nint M[50000];\nint Eid;\nmap<vector<int>,int>mp;\nvector<vector<int> >ord;\nint erd()\n{\n\tvector<int>A(K);\n\tfor(int i=0;i<K;i++)\n\t{\n\t\tcin>>A[i];\n\t\tA[i]--;\n\t}\n\tif(mp.find(A)==mp.end())\n\t{\n\t\tmp[A]=ord.size();\n\t\tord.push_back(A);\n\t}\n\treturn mp[A];\n}\nstruct dat{\n\tint id;\n\tvector<int>F;\n\tvoid rd(){\n\t\tF.assign(K,0);\n\t\tfor(int i=0;i<K;i++)cin>>F[i];\n\t}\n\tbool operator<(const dat&rhs)const{\n\t\treturn F<rhs.F;\n\t}\n};\ndat A[50000];\nvoid psh(dat a,priority_queue<dat>&P,int id)\n{\n\tdat b;\n\tb.id=a.id;\n\tvector<int>F(K);\n\tfor(int i=0;i<K;i++)\n\t{\n\t\tF[i]=a.F[ord[id][i]];\n\t}\n\tb.F=F;\n\tP.push(b);\n}\nvector<int>G[50000];\nint indeg[50000];\nbool out[50001];\nmain()\n{\n\tcin>>N>>K;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tA[i].rd();\n\t\tA[i].id=i+1;\n\t}\n\tint D;cin>>D;\n\tfor(;D--;D)\n\t{\n\t\tint a,b;cin>>a>>b;\n\t\tG[a-1].push_back(b-1);\n\t\tindeg[b-1]++;\n\t}\n\tE[0]=erd();\n\tint R;cin>>R;\n\tfor(int i=1;i<=R;i++)\n\t{\n\t\tcin>>M[i];\n\t\tE[i]=erd();\n\t}\n\tpriority_queue<dat>P[ord.size()];\n\tfor(int i=0;i<N;i++)if(!indeg[i])\n\t{\n\t\tfor(int j=0;j<ord.size();j++)psh(A[i],P[j],j);\n\t}\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tif(Eid<R&&i==M[Eid+1])Eid++;\n\t\tint u;\n\t\twhile(true)\n\t\t{\n\t\t\tu=P[E[Eid]].top().id;\n\t\t\tP[E[Eid]].pop();\n\t\t\tif(!out[u])break;\n\t\t}\n\t\tout[u]=true;\n\t\tcout<<u<<endl;\n\t\tfor(int v:G[u-1])if(!--indeg[v])\n\t\t{\n\t\t\tfor(int j=0;j<ord.size();j++)psh(A[v],P[j],j);\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 83036, "score_of_the_acc": -0.82, "final_rank": 15 }, { "submission_id": "aoj_0331_4570144", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nvector<array<int, 4>> perms;\nvector<array<int, 4>> v;\nstruct P {\n int id, x;\n P(int id = 0, int x = 0) : id(id), x(x) {};\n\n bool operator<(const P &b) const {\n for (auto &&i : perms[x]) {\n if(v[id][i] != v[b.id][i]) return v[id][i] < v[b.id][i];\n }\n return false;\n }\n};\n\nint main() {\n int n, k;\n cin >> n >> k;\n v.resize(n);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < k; ++j) {\n scanf(\"%d\", &v[i][j]);\n }\n }\n int d;\n cin >> d;\n vector<vector<int>> G(n);\n vector<int> deg(n);\n for (int i = 0; i < d; ++i) {\n int a, b;\n scanf(\"%d %d\", &a, &b);\n a--; b--;\n deg[b]++;\n G[a].emplace_back(b);\n }\n {\n array<int, 4> a{};\n iota(a.begin(),a.begin()+k, 0);\n do {\n perms.emplace_back(a);\n }while (next_permutation(a.begin(),a.begin()+k));\n }\n int m = perms.size();\n vector<priority_queue<P>> Q(m);\n vector<int> visited(n);\n for (int i = 0; i < n; ++i) {\n if(!deg[i]){\n for (int j = 0; j < m; ++j) {\n Q[j].emplace(i, j);\n }\n }\n }\n int p = 0;\n auto update = [&](array<int, 4> &v){\n for (int i = 0; i < perms.size(); ++i) {\n if(v == perms[i]) {\n p = i;\n return;\n }\n }\n };\n {\n array<int, 4> x{};\n for (int i = 0; i < k; ++i) {\n cin >> x[i];\n x[i]--;\n }\n update(x);\n }\n int q;\n cin >> q;\n vector<pair<int, array<int, 4>>> query(q);\n for (int i = 0; i < q; ++i) {\n scanf(\"%d\", &query[i].first);\n for (int j = 0; j < k; ++j) {\n scanf(\"%d\", &query[i].second[j]);\n query[i].second[j]--;\n }\n }\n int cur = 0;\n for (int i = 0; i < n; ++i) {\n while(cur < q && query[cur].first == i){\n update(query[cur++].second);\n }\n int a = Q[p].top().id; Q[p].pop();\n while(visited[a]){\n a = Q[p].top().id; Q[p].pop();\n }\n printf(\"%d\\n\", a+1);\n visited[a] = 1;\n for (auto &&j : G[a]) {\n if(!--deg[j]){\n for (int l = 0; l < m; ++l) {\n Q[l].emplace(j, l);\n }\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 17412, "score_of_the_acc": -0.0384, "final_rank": 1 }, { "submission_id": "aoj_0331_3968292", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing pll=pair<ll,ll>;\nconst ll LINF=0x1fffffffffffffff;\n#define _name3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<(n);++i)\n#define _rep2(i,n) for(ll i=0;i<(n);++i)\n#define _rep3(i,a,b) for(ll i=(a);i<(b);++i)\n#define rep(...) _name3(__VA_ARGS__,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define rrep(i,a,b) for(ll i=(b)-1;i>=(a);i--)\n#define each(i,a) for(auto &i:a)\n#define sum(a) accumulate(range(a),0LL)\n#define range(i) (i).begin(),(i).end()\ntemplate<class T> inline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<class T> inline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\n\n\nint n,k;\nvector<vector<int>>f,g;\nvector<bool>used;\nstruct pq{\n const vector<int>e;\n vector<int>waiting;\n priority_queue<int,vector<int>,function<bool(int,int)>>q;\n pq(const vector<int>&e,const vector<int>&waiting):e(e),waiting(waiting),q([&e](int a,int b)->bool{for(auto&i:e){if(f[a].at(i)!=f[b].at(i))return f[a][i]<f[b][i];}return 0;}){\n rep(n)if(!waiting[i])q.push(i);\n }\n int pop(){\n int ans;\n do{\n ans=q.top();\n q.pop();\n }while(used.at(ans));\n used.at(ans)=1;\n return ans;\n }\n void push(int x){\n q.push(x);\n }\n};\nint main() {\n cin>>n>>k;\n f.assign(n,vector<int>(k));\n for(auto&i:f)for(auto&j:i)cin>>j;\n int d;\n cin>>d;\n g.resize(n);\n vector<int>waiting(n);\n rep(d){\n int a,b;\n cin>>a>>b;\n a--;b--;\n g[a].push_back(b);\n waiting[b]++;\n }\n unordered_map<vector<int>,int,function<unsigned(const vector<int>&)>>m(100,[](const vector<int>&e)->unsigned{unsigned ans=0;each(i,e){ans<<=3;ans|=i;}return ans;});\n vector<int>e(k);\n iota(range(e),0);\n vector<pq>q;\n int cnt=0;\n do{\n m[e]=cnt++;\n q.push_back({m.find(e)->first,waiting});\n }while(next_permutation(range(e)));\n vector<int>ans;\n each(i,e){\n cin>>i;\n i--;\n }\n int E=m[e];\n cnt=0;\n int r;\n cin>>r;\n vector<pll>es(r);\n each(i,es){\n cin>>i.first;\n each(j,e){\n cin>>j;\n j--;\n }\n i.second=m[e];\n }\n reverse(range(es));\n used.resize(n);\n each(i,q)each(j,i.e)assert(0<=j&&j<k);\n while(cnt<n){\n if(es.size()&&cnt==es.back().first){\n E=es.back().second;\n es.pop_back();\n }\n while(true){\n int a=q[E].pop();\n each(i,g[a])if(!--waiting[i]){\n each(j,q){\n j.push(i);\n }\n }\n ans.push_back(a+1);\n break;\n }\n cnt++;\n }\n each(i,ans)cout<<i<<endl;\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 20956, "score_of_the_acc": -0.2285, "final_rank": 8 }, { "submission_id": "aoj_0331_3966067", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\nstruct Attributes {\n\tint id;\n\tstd::vector<int> parameters;\n};\nclass PriorityQueueLike {\n\tstd::vector<int> rank;\n\tstd::priority_queue<int, std::vector<int>, std::function<bool(const int, const int)>> queue;\npublic:\n\tPriorityQueueLike(std::vector<int>&& _rank) : rank{ std::move(_rank) } {\n\t\tqueue = std::priority_queue<int, std::vector<int>, std::function<bool(const int, const int)>>([&](const int a, const int b) {return rank[a] < rank[b]; });\n\t}\n\tvoid push(int id) {\n\t\tqueue.push(id);\n\t}\n};\nint factorial(const int n) {\n\tswitch (n) {\n\tcase 0: return 1;\n\tcase 1: return 1;\n\tdefault: return n * factorial(n - 1);\n\t}\n}\nvoid set_ranks(std::vector<int> current_rank, int current, int count, int state, std::vector<int> &history, std::vector<std::pair<int, std::vector<int>>>& result, const std::vector<Attributes>& attr) {\n\tstd::stable_sort(current_rank.begin(), current_rank.end(), [&attr, current](const int a, const int b) {return attr[a].parameters[current] > attr[b].parameters[current]; });\n\tif (state + 1 == (1 << count)) {\n\t\tint as_int = 0;\n\t\tfor (auto i = 1; i <= history.size(); ++i) {\n\t\t\tas_int = as_int * 10 + history[history.size() - i];\n\t\t}\n\t\tstd::vector<int> rank(current_rank.size());\n\t\tfor (auto i = 0; i < current_rank.size(); ++i) {\n\t\t\trank[current_rank[i]] = i;\n\t\t}\n\t\tresult.push_back(std::make_pair(as_int, std::move(rank)));\n\t}\n\telse {\n\t\tfor (auto next = 0; next < count; ++next) if ((state & (1 << next)) == 0) {\n\t\t\thistory.push_back(next);\n\t\t\tset_ranks(current_rank, next, count, state | (1 << next), history, result, attr);\n\t\t\thistory.pop_back();\n\t\t}\n\t}\n}\nint main()\n{\n\tint n, k; std::cin >> n >> k;\n\tstd::vector<Attributes> tasks(n);\n\tfor (auto i = 0; i < n; ++i) {\n\t\ttasks[i].id = i;\n\t\ttasks[i].parameters.resize(k);\n\t\tfor (auto& f : tasks[i].parameters) std::cin >> f;\n\t}\n\tstd::vector<std::pair<int, std::vector<int>>> ranks; ranks.reserve(factorial(k));\n\tstd::unordered_map<int, std::priority_queue<int, std::vector<int>, std::function<bool(const int a, const int b)>>> queues;\n\t{\n\t\tstd::vector<int> vec(n), history; std::iota(vec.begin(), vec.end(), 0);\n\t\tfor (auto i = 0; i < k; ++i) {\n\t\t\thistory.push_back(i);\n\t\t\tset_ranks(vec, i, k, 1 << i, history, ranks, tasks);\n\t\t\thistory.pop_back();\n\t\t}\n\t\tfor (const auto& pair : ranks) {\n\t\t\tqueues[pair.first] = std::priority_queue<int, std::vector<int>, std::function<bool(const int a, const int b)>>([&pair](const int a, const int b) {return pair.second[a] > pair.second[b]; });\n\t\t}\n\t}\n\tstd::vector<std::vector<int>> next_task(n);\n\tstd::vector<int> prev_count(n, 0);\n\t{\n\t\tint d; std::cin >> d;\n\t\tfor (auto i = 0; i < d; ++i) {\n\t\t\tint a, b; std::cin >> a >> b; --a; --b;\n\t\t\tnext_task[a].push_back(b);\n\t\t\tprev_count[b]++;\n\t\t}\n\t}\n\tfor (auto& pair : queues) {\n\t\tfor (auto i = 0; i < n; ++i) if (prev_count[i] == 0) {\n\t\t\tpair.second.push(i);\n\t\t}\n\t}\n\tstd::vector<bool> executed(n, false);\n\tstd::vector<int> result; result.reserve(n);\n\tint priority = 0;\n\tfor (auto i = 0; i < k; ++i) {\n\t\tint e; std::cin >> e;\n\t\tpriority = priority * 10 + e - 1;\n\t}\n\tauto queue = &queues[priority];\n\tint r; std::cin >> r;\n\tint last = 0;\n\tfor (auto i = 0; i < r; ++i) {\n\t\tint m; std::cin >> m;\n\t\tpriority = 0;\n\t\tfor (auto j = 0; j < k; ++j) {\n\t\t\tint e; std::cin >> e;\n\t\t\tpriority = priority * 10 + e - 1;\n\t\t}\n\t\tfor (; last < m; ++last) {\n\t\t\twhile (executed[queue->top()]) queue->pop();\n\t\t\tauto task = queue->top();\n\t\t\texecuted[task] = true;\n\t\t\tresult.push_back(task);\n\t\t\tif (!next_task[task].empty()) {\n\t\t\t\tfor (const auto next : next_task[task]) {\n\t\t\t\t\t--prev_count[next];\n\t\t\t\t}\n\t\t\t\tfor (auto& pair : queues) {\n\t\t\t\t\tfor (const auto next : next_task[task]) if (prev_count[next] == 0) {\n\t\t\t\t\t\tpair.second.push(next);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tqueue = &queues[priority];\n\t}\n\tfor (; last < n; ++last) {\n\t\twhile (executed[queue->top()]) queue->pop();\n\t\tauto task = queue->top();\n\t\texecuted[task] = true;\n\t\tresult.push_back(task);\n\t\tif (!next_task[task].empty()) {\n\t\t\tfor (const auto next : next_task[task]) {\n\t\t\t\tif (--prev_count[next] == 0) queue->push(next);\n\t\t\t}\n\t\t}\n\t}\n\tfor (const auto r : result) std::cout << r + 1 << '\\n';\n}", "accuracy": 1, "time_ms": 830, "memory_kb": 17568, "score_of_the_acc": -0.3747, "final_rank": 9 }, { "submission_id": "aoj_0331_3965387", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nint perm_input(int K, vector<vector<int> > &perm) {\n\tvector<int> p(K);\n\tfor (int i = 0; i < K; ++i) cin >> p[i], --p[i];\n\treturn lower_bound(perm.begin(), perm.end(), p) - perm.begin();\n}\nint main() {\n\tint N, K;\n\tcin >> N >> K;\n\tvector<vector<int> > perm;\n\tvector<int> pperm(K);\n\tfor (int i = 0; i < K; ++i) pperm[i] = i;\n\tdo {\n\t\tperm.push_back(pperm);\n\t} while (next_permutation(pperm.begin(), pperm.end()));\n\tvector<vector<int> > F(N, vector<int>(K));\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j < K; ++j) {\n\t\t\tcin >> F[i][j];\n\t\t}\n\t}\n\tint fact = perm.size();\n\tvector<vector<int> > P(fact, vector<int>(N)), IP(fact, vector<int>(N));\n\tfor (int i = 0; i < fact; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tP[i][j] = j;\n\t\t}\n\t\tsort(P[i].begin(), P[i].end(), [&](int x, int y) {\n\t\t\tfor (int j = 0; j < K; ++j) {\n\t\t\t\tif (F[x][perm[i][j]] != F[y][perm[i][j]]) {\n\t\t\t\t\treturn F[x][perm[i][j]] < F[y][perm[i][j]];\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn false;\n\t\t\t});\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tIP[i][P[i][j]] = j;\n\t\t}\n\t}\n\tint D;\n\tcin >> D;\n\tvector<vector<int> > G(N);\n\tvector<int> deg(N);\n\tfor (int i = 0; i < D; ++i) {\n\t\tint a, b;\n\t\tcin >> a >> b; --a, --b;\n\t\t++deg[b];\n\t\tG[a].push_back(b);\n\t}\n\tint cur = 0, pre = perm_input(K, perm), R;\n\tvector<int> ord(N + 1);\n\tcin >> R;\n\tfor (int i = 0; i < R; ++i) {\n\t\tint tm, nxt;\n\t\tcin >> tm;\n\t\tnxt = perm_input(K, perm);\n\t\tfor (int j = cur; j < tm; ++j) {\n\t\t\tord[j] = pre;\n\t\t}\n\t\tcur = tm;\n\t\tpre = nxt;\n\t}\n\tfor (int i = cur; i <= N; ++i) {\n\t\tord[i] = pre;\n\t}\n\tvector<priority_queue<int> > que(fact);\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (deg[i] >= 1) continue;\n\t\tfor (int j = 0; j < fact; ++j) {\n\t\t\tque[j].push(IP[j][i]);\n\t\t}\n\t}\n\tvector<bool> used(N, false);\n\tfor (int i = 0; i < N; ++i) {\n\t\tint u = -1;\n\t\twhile (u == -1 || used[u]) {\n\t\t\tu = P[ord[i]][que[ord[i]].top()];\n\t\t\tque[ord[i]].pop();\n\t\t}\n\t\tused[u] = true;\n\t\tcout << u + 1 << '\\n';\n\t\tfor (int j : G[u]) {\n\t\t\t--deg[j];\n\t\t\tif (deg[j] == 0) {\n\t\t\t\tfor (int k = 0; k < fact; ++k) {\n\t\t\t\t\tque[k].push(IP[k][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 22568, "score_of_the_acc": -0.132, "final_rank": 4 }, { "submission_id": "aoj_0331_3942791", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<vector<int>, int> P;\n\npriority_queue<P> pq[20];\n\nint f[50010][4];\n\nmap<vector<int>, int> mp;\nvector<vector<int>> zyun;\nint n, k;\nvoid load(int x){\n\tfor(int i = 0;i < zyun.size();i++){\n\t\tvector<int> tmp;\n\t\tfor(int j = 0;j < k;j++){\n\t\t\ttmp.push_back(f[x][zyun[i][j]]);\n\t\t}\n\t\tpq[i].push({tmp, x});\n\t}\n}\n\nvector<int> graph[50010];\nint ydk[50010];\n\nvector<int> e[50010];\nint m[50010];\n\nint used[50010];\n\n\nint main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcin >> n >> k;\n\n\n\t{\n\t\tvector<int> vec(k);\n\t\tfor(int i = 0;i < k;i++){\n\t\t\tvec[i] = i;\n\t\t}\n\t\t\n\t\tint cnt = 0;\n\t\tdo{\n\t\t\tzyun.push_back(vec);\n\t\t\tmp[vec] = cnt;\n\t\t\tcnt++;\n\t\t}while(next_permutation(vec.begin(), vec.end()));\n\t}\n\n\tfor(int x = 0;x < n;x++){\n\t\tfor(int j = 0;j < k;j++){\n\t\t\tcin >> f[x][j];\n\t\t}\n\t}\n\n\tint d;\n\tcin >> d;\n\n\tfor(int i = 0;i < d;i++){\n\t\tint a, b; cin >> a >> b;\n\t\ta--; b--;\n\t\tgraph[a].push_back(b);\n\t\tydk[b]++;\n\t}\n\n\tint r;\n\tfor(int i = 0;i < k;i++){\n\t\tint t; cin >> t;\n\t\te[0].push_back(t-1);\n\t}\n\n\tcin >> r;\n\tfor(int j = 0;j < r;j++){\n\t\tcin >> m[j+1];\n\t\tfor(int i = 0;i < k;i++){\n\t\t\tint t; cin >> t;\n\t\t\te[j+1].push_back(t-1);\n\t\t}\n\t}\n\tr++;\n\tm[r] = n;\n\n\tfor(int i = 0;i < n;i++){\n\t\tif(ydk[i] == 0) load(i);\n\t}\n\n\tint now = mp[e[0]];\n\n\tvector<int> ans;\n\tint fi = 0;\n\tint p = 0;\n\tfor(int x = 0;x < n;x++){\n\t\tint idx;\n\t\twhile(1){\n\t\t\tidx = pq[now].top().second;\n\t\t\tpq[now].pop();\n\t\t\tif(used[idx] == 0){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tans.push_back(idx+1);\n\t\tused[idx] = 1;\n\n\t\tfor(auto p : graph[idx]){\n\t\t\tydk[p]--;\n\t\t\tif(ydk[p] == 0){\n\t\t\t\tload(p);\n\t\t\t}\n\t\t}\n\n\t\tfi++;\n\t\tif(m[p+1] == fi){\n\t\t\tp++;\n\t\t\tnow = mp[e[p]];\n\t\t}\n\t}\n\n\tfor(auto p : ans){\n\t\tcout << p << endl;\n\t}\n\n\t\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1030, "memory_kb": 83732, "score_of_the_acc": -0.8632, "final_rank": 16 }, { "submission_id": "aoj_0331_3942788", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<vector<int>, int> P;\n\npriority_queue<P> pq[20];\n\nint f[50010][4];\n\nmap<vector<int>, int> mp;\nvector<vector<int>> zyun;\nint n, k;\nvoid load(int x){\n\tfor(int i = 0;i < zyun.size();i++){\n\t\tvector<int> tmp;\n\t\tfor(int j = 0;j < k;j++){\n\t\t\ttmp.push_back(f[x][zyun[i][j]]);\n\t\t}\n\t\tpq[i].push({tmp, x});\n\t}\n}\n\nvector<int> graph[50010];\nint ydk[50010];\n\nvector<int> e[50010];\nint m[50010];\n\nint used[50010];\n\n\nint main(){\n\tcin >> n >> k;\n\n\n\t{\n\t\tvector<int> vec(k);\n\t\tfor(int i = 0;i < k;i++){\n\t\t\tvec[i] = i;\n\t\t}\n\t\t\n\t\tint cnt = 0;\n\t\tdo{\n\t\t\tzyun.push_back(vec);\n\t\t\tmp[vec] = cnt;\n\t\t\tcnt++;\n\t\t}while(next_permutation(vec.begin(), vec.end()));\n\t}\n\n\tfor(int x = 0;x < n;x++){\n\t\tfor(int j = 0;j < k;j++){\n\t\t\tcin >> f[x][j];\n\t\t}\n\t}\n\n\tint d;\n\tcin >> d;\n\n\tfor(int i = 0;i < d;i++){\n\t\tint a, b; cin >> a >> b;\n\t\ta--; b--;\n\t\tgraph[a].push_back(b);\n\t\tydk[b]++;\n\t}\n\n\tint r;\n\tfor(int i = 0;i < k;i++){\n\t\tint t; cin >> t;\n\t\te[0].push_back(t-1);\n\t}\n\n\tcin >> r;\n\tfor(int j = 0;j < r;j++){\n\t\tcin >> m[j+1];\n\t\tfor(int i = 0;i < k;i++){\n\t\t\tint t; cin >> t;\n\t\t\te[j+1].push_back(t-1);\n\t\t}\n\t}\n\tr++;\n\tm[r] = n;\n\n\tfor(int i = 0;i < n;i++){\n\t\tif(ydk[i] == 0) load(i);\n\t}\n\n\tint now = mp[e[0]];\n\n\tvector<int> ans;\n\tint fi = 0;\n\tint p = 0;\n\tfor(int x = 0;x < n;x++){\n\t\tint idx;\n\t\twhile(1){\n\t\t\tidx = pq[now].top().second;\n\t\t\tpq[now].pop();\n\t\t\tif(used[idx] == 0){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tans.push_back(idx+1);\n\t\tused[idx] = 1;\n\n\t\tfor(auto p : graph[idx]){\n\t\t\tydk[p]--;\n\t\t\tif(ydk[p] == 0){\n\t\t\t\tload(p);\n\t\t\t}\n\t\t}\n\n\t\tfi++;\n\t\tif(m[p+1] == fi){\n\t\t\tp++;\n\t\t\tnow = mp[e[p]];\n\t\t}\n\t}\n\n\tfor(auto p : ans){\n\t\tcout << p << endl;\n\t}\n\n\t\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 83620, "score_of_the_acc": -0.8758, "final_rank": 17 }, { "submission_id": "aoj_0331_3216520", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n, k;\n\ntypedef struct{\n int num;\n int data[4];\n} Syori;\n\n\n\nqueue<int> graph[50050];\nint izon[50050];\nSyori data[50050];\n\nSyori syori[24] = {};\nint syoriTable[4][4][4][4];\nSyori syoritmp;\nint scnt = 0;\n\nint make(int i, int bit){\n if(i == 4){\n syori[scnt] = syoritmp;\n syoriTable[syoritmp.data[0]][syoritmp.data[1]][syoritmp.data[2]][syoritmp.data[3]] = scnt;\n scnt++;\n }\n\n for(int j = 0;j < 4;j++){\n if((bit & (1 << j)) == 0){\n syoritmp.data[i] = j;\n make(i+1,bit | (1 << j));\n }\n }\n\n return 0;\n}\n\nSyori f[50050];\n\n\nSyori segTree[24][200000] = {};\nint segSize;\n\nbool big(Syori a, Syori b, int i){\n if(a.data[syori[i].data[0]] == b.data[syori[i].data[0]]){\n if(a.data[syori[i].data[1]] == b.data[syori[i].data[1]]){\n if(a.data[syori[i].data[2]] == b.data[syori[i].data[2]]){\n return a.data[syori[i].data[3]] > b.data[syori[i].data[3]];\n }else{\n return a.data[syori[i].data[2]] > b.data[syori[i].data[2]];\n }\n }else{\n return a.data[syori[i].data[1]] > b.data[syori[i].data[1]];\n }\n }else{\n return a.data[syori[i].data[0]] > b.data[syori[i].data[0]];\n }\n}\n\nSyori nu;\n\nvoid init(){\n segSize = 1;\n while(segSize < n){\n segSize *= 2;\n }\n\n nu.data[0] = 0;\n nu.data[1] = 0;\n nu.data[2] = 0;\n nu.data[3] = 0;\n\n for(int i = 0;i < 24;i++){\n for(int j = 0;j < segSize;j++){\n if(j < n && izon[j] == 0){\n segTree[i][segSize-1+j] = f[j];\n segTree[i][segSize-1+j].num = j;\n }else{\n segTree[i][segSize-1+j] = nu;\n segTree[i][segSize-1+j].num = j;\n }\n }\n }\n\n for(int i = 0;i < 24;i++){\n for(int j = segSize-2;j >= 0;j--){\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n\n return;\n}\n\nvoid insert(int x){\n\n int j;\n\n for(int i = 0;i < 24;i++){\n j = segSize-1+x;\n segTree[i][j] = f[x];\n segTree[i][j].num = x;\n while(j > 0){\n j = (j - 1) /2;\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n}\n\n\nvoid del(int x){\n int j;\n for(int i = 0;i < 24;i++){\n j = segSize-1+x;\n segTree[i][j] = nu;\n while(j > 0){\n j = (j - 1) /2;\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n return;\n}\n\nint getData(int i){\n return segTree[i][0].num;\n}\n\n\nint main(){\n cin >> n >> k;\n\n for(int i = 0;i < n;i++){\n for(int j = 0;j < 4;j++){\n if(j < k){\n cin >> f[i].data[j];\n }else{\n f[i].data[j] = 0;\n }\n }\n }\n\n int d; cin >> d;\n for(int i = 0;i < d;i++){\n int a, b;\n cin >> a >> b;\n a--; b--;\n izon[b]++;\n graph[a].push(b);\n }\n\n for(int i = 0;i < 4;i++){\n if(i < k){\n cin >> data[0].data[i];\n data[0].data[i]--;\n }else{\n data[0].data[i] = i;\n }\n }\n\n int r;\n cin >> r;\n int m;\n int tmp = 0;\n\n for(int i = 0;i < r;i++){\n cin >> m;\n for(int j = tmp+1;j < m;j++){\n data[j] = data[j-1];\n }\n for(int j = 0;j < 4;j++){\n if(j < k){\n cin >> data[m].data[j];\n data[m].data[j]--;\n }else{\n data[m].data[j] = j;\n }\n }\n tmp = m;\n }\n\n for(int j = tmp+1;j < n;j++){\n data[j] = data[j-1];\n }\n\n make(0,0);\n\n init();\n\n queue<int> ans;\n for(int i = 0;i < n;i++){\n int tmpi = getData(syoriTable[data[i].data[0]][data[i].data[1]][data[i].data[2]][data[i].data[3]]);\n ans.push(tmpi);\n del(tmpi);\n while(!graph[tmpi].empty()){\n izon[graph[tmpi].front()]--;\n if(izon[graph[tmpi].front()] == 0){\n insert(graph[tmpi].front());\n }\n graph[tmpi].pop();\n }\n }\n\n for(int i = 0;i < n;i++){\n cout << ans.front()+1 << endl;\n ans.pop();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 710, "memory_kb": 100484, "score_of_the_acc": -0.7431, "final_rank": 13 }, { "submission_id": "aoj_0331_3216287", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n, k;\n\ntypedef struct{\n int num;\n int data[4];\n} Syori;\n\n\n\nqueue<int> graph[50050];\nint izon[50050];\nSyori data[50050];\n\nSyori syori[24] = {};\nint syoriTable[4][4][4][4];\nSyori syoritmp;\nint scnt = 0;\n\nint make(int i, int bit){\n if(i == 4){\n syori[scnt] = syoritmp;\n syoriTable[syoritmp.data[0]][syoritmp.data[1]][syoritmp.data[2]][syoritmp.data[3]] = scnt;\n scnt++;\n }\n\n for(int j = 0;j < 4;j++){\n if((bit & (1 << j)) == 0){\n syoritmp.data[i] = j;\n make(i+1,bit | (1 << j));\n }\n }\n\n return 0;\n}\n\nSyori f[50050];\n\n\nSyori segTree[24][200000] = {};\nint segSize;\n\nbool big(Syori a, Syori b, int i){\n if(a.data[syori[i].data[0]] == b.data[syori[i].data[0]]){\n if(a.data[syori[i].data[1]] == b.data[syori[i].data[1]]){\n if(a.data[syori[i].data[2]] == b.data[syori[i].data[2]]){\n return a.data[syori[i].data[3]] > b.data[syori[i].data[3]];\n }else{\n return a.data[syori[i].data[2]] > b.data[syori[i].data[2]];\n }\n }else{\n return a.data[syori[i].data[1]] > b.data[syori[i].data[1]];\n }\n }else{\n return a.data[syori[i].data[0]] > b.data[syori[i].data[0]];\n }\n}\n\nSyori nu;\n\nvoid init(){\n segSize = 1;\n while(segSize < n){\n segSize *= 2;\n }\n\n nu.data[0] = 0;\n nu.data[1] = 0;\n nu.data[2] = 0;\n nu.data[3] = 0;\n\n for(int i = 0;i < 24;i++){\n for(int j = 0;j < segSize;j++){\n if(j < n && izon[j] == 0){\n segTree[i][segSize-1+j] = f[j];\n segTree[i][segSize-1+j].num = j;\n }else{\n segTree[i][segSize-1+j] = nu;\n segTree[i][segSize-1+j].num = j;\n }\n }\n }\n\n for(int i = 0;i < 24;i++){\n for(int j = segSize-2;j >= 0;j--){\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n\n return;\n}\n\nvoid insert(int x){\n\n int j;\n\n for(int i = 0;i < 24;i++){\n j = segSize-1+x;\n segTree[i][j] = f[x];\n segTree[i][j].num = x;\n while(j > 0){\n j = (j - 1) /2;\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n}\n\n\nvoid del(int x){\n int j;\n for(int i = 0;i < 24;i++){\n j = segSize-1+x;\n segTree[i][j] = nu;\n while(j > 0){\n j = (j - 1) /2;\n if(big(segTree[i][j*2+1],segTree[i][j*2+2],i)){\n segTree[i][j] = segTree[i][j*2+1];\n }else{\n segTree[i][j] = segTree[i][j*2+2];\n }\n }\n }\n return;\n}\n\nint getData(int i){\n return segTree[i][0].num;\n}\n\n\nint main(){\n cin >> n >> k;\n\n for(int i = 0;i < n;i++){\n for(int j = 0;j < 4;j++){\n if(j < k){\n cin >> f[i].data[j];\n }else{\n f[i].data[j] = 0;\n }\n }\n }\n\n int d; cin >> d;\n for(int i = 0;i < d;i++){\n int a, b;\n cin >> a >> b;\n a--; b--;\n izon[b]++;\n graph[a].push(b);\n }\n\n for(int i = 0;i < 4;i++){\n if(i < k){\n cin >> data[0].data[i];\n data[0].data[i]--;\n }else{\n data[0].data[i] = i;\n }\n }\n\n int r;\n cin >> r;\n int m;\n int tmp = 0;\n\n for(int i = 0;i < r;i++){\n cin >> m;\n for(int j = tmp+1;j < m;j++){\n data[j] = data[j-1];\n }\n for(int j = 0;j < 4;j++){\n if(j < k){\n cin >> data[m].data[j];\n data[m].data[j]--;\n }else{\n data[m].data[j] = j;\n }\n }\n tmp = m;\n }\n\n for(int j = tmp+1;j < n;j++){\n data[j] = data[j-1];\n }\n\n make(0,0);\n\n init();\n\n queue<int> ans;\n for(int i = 0;i < n;i++){\n int tmpi = getData(syoriTable[data[i].data[0]][data[i].data[1]][data[i].data[2]][data[i].data[3]]);\n ans.push(tmpi);\n del(tmpi);\n while(!graph[tmpi].empty()){\n izon[graph[tmpi].front()]--;\n if(izon[graph[tmpi].front()] == 0){\n insert(graph[tmpi].front());\n }\n graph[tmpi].pop();\n }\n }\n\n for(int i = 0;i < n;i++){\n cout << ans.front()+1 << endl;\n ans.pop();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 100628, "score_of_the_acc": -0.7504, "final_rank": 14 }, { "submission_id": "aoj_0331_3057320", "code_snippet": "#include <stdio.h>\n#include <queue>\n#include <bitset>\n#include <map>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n#define PB push_back\nint t=0,k;\nstruct node{\n int num;\n int val[4];\n void in(){\n num=++t;\n for(int i=0;i<k;i++)scanf(\"%d\",&val[i]);\n return ;\n }\n node per(vector<int>& p){\n node ans;\n ans.num=num;\n for(int i=0;i<k;i++)ans.val[i]=val[p[i]];\n return ans;\n }\n};\nstruct cmp{\n bool operator()(const node a,const node b){\n for(int i=0;i<k;i++)if(a.val[i]!=b.val[i])return a.val[i]<b.val[i];\n return true;\n }\n};\nconst int N=5e4+10;\nint main(){\n int n,tot=1,d,l,r,deg[N],now=1,last,cnt=0,temp;\n map<vector<int>,int>m;\n map<int,vector<int>>b;\n node a[N],nxt;\n vector<int> p,graph[N],tp;\n bitset<N>used;\n priority_queue<node,vector<node>,cmp>pq[24];\n scanf(\"%d%d\",&n,&k);\n for(int i=1;i<=n;i++)a[i].in();\n for(int i=0;i<k;i++)p.PB(i);\n for(int i=k;i>0;i--)tot*=i;\n for(int i=0;i<tot;i++){\n m.insert({p,i});\n b.insert({i,p});\n next_permutation(p.begin(),p.end());\n }\n used.reset();\n scanf(\"%d\",&d);\n while(d--){\n scanf(\"%d%d\",&l,&r);\n graph[l].PB(r);\n deg[r]++;\n }\n for(int i=1;i<=n;i++)if(deg[i]==0)for(int j=0;j<tot;j++)pq[j].push(a[i].per(b[j]));\n tp.clear();\n for(int i=0;i<k;i++){\n scanf(\"%d\",&temp);\n temp--;\n tp.PB(temp);\n }\n now=m[tp];\n scanf(\"%d\",&r);\n while(r--){\n last=now;\n scanf(\"%d\",&l);\n tp.clear();\n for(int i=0;i<k;i++){\n scanf(\"%d\",&temp);\n temp--;\n tp.PB(temp);\n }\n now=m[tp];\n while(cnt<l){\n nxt=pq[last].top();\n pq[last].pop();\n if(used[nxt.num])continue;\n used[nxt.num]=true;\n printf(\"%d\\n\",nxt.num);\n for(int i:graph[nxt.num]){\n deg[i]--;\n if(deg[i]==0)for(int j=0;j<tot;j++)pq[j].push(a[i].per(b[j]));\n }\n cnt++;\n }\n }\n while(cnt<n){\n nxt=pq[now].top();\n pq[now].pop();\n if(used[nxt.num])continue;\n used[nxt.num]=true;\n printf(\"%d\\n\",nxt.num);\n for(int i:graph[nxt.num]){\n deg[i]--;\n if(deg[i]==0)for(int j=0;j<tot;j++)pq[j].push(a[i].per(b[j]));\n }\n cnt++;\n }\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 29604, "score_of_the_acc": -0.1239, "final_rank": 3 }, { "submission_id": "aoj_0331_2590329", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\tint status_array[4];\n};\n\nInfo info[50000];\nint N,K;\nvector<int> V[50000];\nbool outputed[50000];\nint in_num[50000];\nint order_table[33][4] = {{0,0,0,0},\n\t\t\t\t\t\t {0,1,0,0},{1,0,0,0},\n\t\t\t\t\t\t {0,1,2,0},{0,2,1,0},{1,0,2,0},{1,2,0,0},{2,0,1,0},{2,1,0,0},\n\t\t\t\t\t\t {0,1,2,3},{0,1,3,2},{0,2,1,3},{0,2,3,1},{0,3,1,2},{0,3,2,1},\n\t\t\t\t\t\t {1,0,2,3},{1,0,3,2},{1,2,0,3},{1,2,3,0},{1,3,0,2},{1,3,2,0},\n\t\t\t\t\t\t {2,0,1,3},{2,0,3,1},{2,1,0,3},{2,1,3,0},{2,3,0,1},{2,3,1,0},\n\t\t\t\t\t\t {3,0,1,2},{3,0,2,1},{3,1,0,2},{3,1,2,0},{3,2,0,1},{3,2,1,0}\n\t\t\t\t\t\t\t};\n\nbool value_func(int task_a,int task_b,int order){\n\tfor(int i = 0; i < K; i++){\n\t\tif(info[task_a].status_array[order_table[order][i]] != info[task_b].status_array[order_table[order][i]]){\n\t\t\treturn info[task_a].status_array[order_table[order][i]] < info[task_b].status_array[order_table[order][i]];\n\t\t}\n\t}\n\treturn false; //must not reach here\n}\n\nstruct Data{\n\tData(int arg_id,int arg_order){\n\t\tid = arg_id;\n\t\torder = arg_order;\n\t}\n\tbool operator<(const struct Data &arg) const{\n\t\treturn value_func(id,arg.id,order);\n\t}\n\tint id,order;\n};\n\npriority_queue<Data> Q[33];\nvector<int> TO_PUSH[5];\n\nint main(){\n\n\tTO_PUSH[1].push_back(0);\n\tTO_PUSH[2].push_back(1);\n\tTO_PUSH[2].push_back(2);\n\tfor(int i = 3; i <= 8; i++)TO_PUSH[3].push_back(i);\n\tfor(int i = 9; i <= 32; i++)TO_PUSH[4].push_back(i);\n\n\tscanf(\"%d %d\",&N,&K);\n\tfor(int a = 0; a < N; a++){\n\t\tfor(int b = 0; b < K; b++){\n\t\t\tscanf(\"%d\",&info[a].status_array[b]);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tin_num[i] = 0;\n\t\toutputed[i] = false;\n\t}\n\n\tint D;\n\tscanf(\"%d\",&D);\n\n\tint from,to;\n\tfor(int loop = 0; loop < D; loop++){\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\t\tV[from].push_back(to);\n\t\tin_num[to]++;\n\t}\n\n\tint value_array[4];\n\tfor(int i = 0; i < 4; i++){\n\t\tvalue_array[i] = 0;\n\t}\n\n\tfor(int i = 0; i < K; i++){\n\t\tscanf(\"%d\",&value_array[i]);\n\t\tvalue_array[i]--;\n\t}\n\n\tqueue<int> ORDER;\n\tbool FLG;\n\tfor(int i = 0; i < 33; i++){\n\t\tFLG = true;\n\t\tfor(int k = 0; k < 4; k++){\n\t\t\tif(value_array[k] != order_table[i][k]){\n\t\t\t\tFLG = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(FLG){\n\t\t\tORDER.push(i);\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tint R;\n\tscanf(\"%d\",&R);\n\n\tbool is_change[N];\n\tfor(int i = 0; i < N; i++)is_change[i] = false;\n\n\tint m;\n\tfor(int i = 0; i < R; i++){\n\t\tscanf(\"%d\",&m);\n\t\tis_change[m] = true;\n\t\tfor(int a = 0; a < K; a++){\n\t\t\tscanf(\"%d\",&value_array[a]);\n\t\t\tvalue_array[a]--;\n\t\t}\n\t\tfor(int k = 0; k < 33; k++){\n\t\t\tFLG = true;\n\t\t\tfor(int p = 0; p < 4; p++){\n\t\t\t\tif(value_array[p] != order_table[k][p]){\n\t\t\t\t\tFLG = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(FLG){\n\t\t\t\tORDER.push(k);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(in_num[i] == 0){\n\t\t\tfor(int a = 0; a < TO_PUSH[K].size(); a++){\n\t\t\t\tQ[TO_PUSH[K][a]].push(Data(i,TO_PUSH[K][a]));\n\t\t\t}\n\t\t}\n\t}\n\n\tint dealt_num = 0,tmp_id;\n\n\twhile(dealt_num < N){\n\n\t\tif(outputed[Q[ORDER.front()].top().id]){\n\t\t\tQ[ORDER.front()].pop();\n\t\t\tcontinue;\n\t\t}\n\n\t\tprintf(\"%d\\n\",Q[ORDER.front()].top().id+1);\n\t\toutputed[Q[ORDER.front()].top().id] = true;\n\t\tdealt_num++;\n\n\t\tif(dealt_num == N){\n\t\t\treturn 0;\n\t\t}\n\t\ttmp_id = Q[ORDER.front()].top().id;\n\t\tQ[ORDER.front()].pop();\n\t\tif(is_change[dealt_num]){\n\t\t\tORDER.pop();\n\t\t}\n\n\t\tfor(int k = 0; k < V[tmp_id].size(); k++){\n\t\t\tin_num[V[tmp_id][k]]--;\n\t\t\tif(in_num[V[tmp_id][k]] == 0){\n\t\t\t\tfor(int a = 0; a < TO_PUSH[K].size(); a++){\n\t\t\t\t\tQ[TO_PUSH[K][a]].push(Data(V[tmp_id][k],TO_PUSH[K][a]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 16396, "score_of_the_acc": -0.0526, "final_rank": 2 }, { "submission_id": "aoj_0331_2588962", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <cmath>\n#include <iomanip>\n#include <cassert>\n#include <bitset>\nusing namespace std;\n\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i=0; i<(n); i++)\n#define all(c) (c).begin(), (c).end()\n#define uniq(c) c.erase(unique(all(c)), (c).end())\n#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())\n#define _1 first\n#define _2 second\n#define pb push_back\n#define INF 1145141919\n#define MOD 1000000007\n\nint N, M, K, R;\nint F[50000][4];\nvector<int> G[50000];\nint deg[50000];\nint ord[50000][4];\nvector<int> vect(vector<int> ord, int i) {\n vector<int> ret;\n rep(j, K) ret.pb(F[i][ord[j]]);\n ret.pb(i);\n return ret;\n}\n\nsigned main() {\n ios::sync_with_stdio(false); cin.tie(0);\n cin >> N >> K;\n rep(i, N) rep(j, K) cin >> F[i][j], F[i][j] = -F[i][j];\n cin >> M;\n rep(i, M) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n G[a].pb(b);\n deg[b]++;\n }\n int last = 0;\n rep(j, K) cin >> ord[0][j], ord[0][j]--;\n cin >> R;\n rep(_, R) {\n int m;\n cin >> m;\n for (int p=last+1; p<m; p++) {\n rep(j, K) ord[p][j] = ord[p-1][j];\n }\n rep(j, K) cin >> ord[m][j], ord[m][j]--;\n last = m;\n }\n for (int p=last+1; p<N; p++) {\n rep(j, K) ord[p][j] = ord[p-1][j];\n }\n\n map<vector<int>, set<vector<int> > > mp;\n vector<int> r(K);\n rep(i, K) r[i] = i;\n do {\n set<vector<int> > vs;\n mp[r] = vs;\n }\n while (next_permutation(all(r)));\n\n rep(i, N) {\n if (deg[i] == 0) {\n for (auto &p : mp) p._2.insert(vect(p._1, i));\n }\n }\n\n rep(p, N) {\n vector<int> r(K); rep(i, K) r[i] = ord[p][i];\n assert(!mp[r].empty());\n auto &vs = *mp[r].begin();\n int x = vs.back();\n for (int t : G[x]) {\n deg[t]--;\n if (deg[t] == 0) {\n for (auto &p : mp) {\n p._2.insert(vect(p._1, t));\n }\n }\n }\n for (auto &p : mp) {\n p._2.erase(vect(p._1, x));\n }\n cout << x+1 << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1790, "memory_kb": 137272, "score_of_the_acc": -1.6521, "final_rank": 20 }, { "submission_id": "aoj_0331_2581425", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n \nstruct Data\n{\n int data[4];\n int num;\n \n Data () {}\n Data (int a, int b, int c, int d, int n)\n {\n data[0] = a, data[1] = b, data[2] = c, data[3] = d, num = n;\n }\n \n bool operator < (const Data d) const\n {\n for(int i = 0; i < 4; i++) {\n if(data[i] < d.data[i]) return (true);\n else if(data[i] > d.data[i]) return (false);\n }\n return (false);\n }\n};\n \nint N, K;\nint F[50005][4];\nint D, R;\nbool flag[50005] = {};\nint quant[50005] = {};\nvector < int > G[50005];\nvector < int > order;\nint it = 0;\nint idx = 1;\nvector < int > pat[24];\npriority_queue < Data > pq[24];\nmap < vector < int > , int > mp;\n \nvoid process(int m);\n \nint main()\n{\n \n \n cin >> N >> K;\n \n for(int i = 0; i < N; i++) {\n for(int j = 0; j < K; j++) {\n cin >> F[i][j];\n }\n }\n \n cin >> D;\n for(int i = 0; i < D; i++) {\n int A, B;\n cin >> A >> B; --A, --B;\n G[A].push_back(B);\n quant[B]++;\n }\n \n for(int i = 0; i < K; i++) {\n int val;\n cin >> val; order.push_back(val - 1);\n }\n while(order.size() < 4) order.push_back(0);\n mp[order] = 0; pat[0] = order;\n for(int i = 0; i < N; i++) {\n if(quant[i] == 0) {\n pq[0].push(Data(F[i][order[0]], F[i][order[1]], F[i][order[2]], F[i][order[3]], i));\n }\n }\n cin >> R;\n for(int i = 0; i < R; i++) {\n int m;\n cin >> m;\n process(m);\n for(int j = 0; j < K; j++) {\n cin >> order[j]; --order[j];\n }\n if(mp.count(order) == 0) {\n mp[order] = idx;\n pat[idx] = order;\n for(int j = 0; j < N; j++) {\n if(quant[j] == 0) {\n pq[idx].push(Data(F[j][order[0]], F[j][order[1]], F[j][order[2]], F[j][order[3]], j));\n }\n }\n idx++;\n }\n }\n process(N);\n \n return (0);\n}\n \nvoid process(int m)\n{\n int dat = mp[order];\n while(it < m) {\n while(!pq[dat].empty()) {\n Data d = pq[dat].top(); pq[dat].pop();\n if(flag[d.num]) continue;\n cout << d.num + 1 << endl;\n flag[d.num] = true;\n for(int i = 0; i < G[d.num].size(); i++) {\n int u = G[d.num][i];\n quant[u]--;\n if(quant[u] == 0) {\n for(int j = 0; j < idx; j++) {\n pq[j].push(Data(F[u][pat[j][0]], F[u][pat[j][1]], F[u][pat[j][2]], F[u][pat[j][3]], u));\n }\n }\n }\n break;\n }\n it++;\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 29880, "score_of_the_acc": -0.1385, "final_rank": 5 }, { "submission_id": "aoj_0331_2581307", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<pll, int> plp;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst double EPS = 1e-10;\nconst bool debug = 0;\n//--------------------------------//\n\nint N, K, D, R;\nint f[50000][4];\nvector<int> g[50000];\nint cnt[50000];\nint et[4], er[50001];\npll pri[50000][24];\nmap<int, int> ord;\nbool done[50000];\n\ninline int convert(int *a, int n) {\n\tint res = 0;\n\tfor (int i = n - 1; i >= 0; i--) res = res * 10 + a[i];\n\treturn res;\n}\n\nint main() {\n\tcin >> N >> K;\n\tint tmp[4] = {1,2,3,4};\n\tdo {\n\t\tord[convert(tmp, K)] = ord.size() - 1;\n\t} while (next_permutation(tmp, tmp + K));\n\t\n\tREP(i, N) REP(j, K) scanf(\"%d\", &f[i][j]), f[i][j]--;\n\tcin >> D;\n\tREP(i, D) {\n\t\tint a, b;\n\t\tscanf(\"%d %d\", &a, &b);\n\t\tg[a - 1].push_back(b - 1);\n\t\tcnt[b - 1]++;\n\t}\n\tREP(i, K) scanf(\"%d\", et + i);\n\tcin >> R;\n\t\n\tmemset(er, -1, sizeof(er));\n\tREP(i, R) {\n\t\tint m;\n\t\tscanf(\"%d\", &m);\n\t\tREP(j, K) scanf(\"%d\", tmp + j);\n\t\ter[m] = ord[convert(tmp, K)];\n\t}\n\t\n\tREP(i, N) {\n\t\tfor (map<int, int>::iterator it = ord.begin(); it != ord.end(); ++it) {\n\t\t\tmemset(tmp, 0, sizeof(tmp));\n\t\t\t\n\t\t\ttmp[0] = f[i][it->fi%10 - 1];\n\t\t\tif (K >= 2) tmp[1] = f[i][it->fi/10%10 - 1];\n\t\t\tif (K >= 3) tmp[2] = f[i][it->fi/100%10 - 1];\n\t\t\tif (K >= 4) tmp[3] = f[i][it->fi/1000 - 1];\n\t\t\t\n\t\t\tpri[i][it->se] = pll(tmp[0]*100000ll+tmp[1], tmp[2]*100000ll+tmp[3]);\n\t\t}\n\t}\n\t\n\tpriority_queue<plp> pq[24];\n\tREP(i, N) if (cnt[i] == 0) {\n\t\tREP(j, 24) pq[j].push(plp(pri[i][j], i));\n\t}\n\t\n\tvector<int> ans;\n\t\n\tint e = ord[convert(et, K)];\n\tint fcnt = 0;\n\twhile (!pq[e].empty()) {\n\t\tint pos = pq[e].top().se;\n\t\tpll tttt = pq[e].top().fi;\n\t\t\n\t\tpq[e].pop();\n\t\tif (done[pos]) continue;\n\t\tdone[pos] = true;\n\t\t\n\t\tans.push_back(pos + 1);\n\t\t\n\t\tREP(i, g[pos].size()) if (--cnt[g[pos][i]] == 0) {\n\t\t\tREP(j, 24) pq[j].push(plp(pri[g[pos][i]][j], g[pos][i]));\n\t\t}\n\t\t\n\t\tfcnt++;\n\t\tif (er[fcnt] != -1) e = er[fcnt];\n\t}\n\t\n\tREP(i, ans.size()) printf(\"%d\\n\", ans[i]);\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 53600, "score_of_the_acc": -0.2007, "final_rank": 7 } ]
aoj_0332_cpp
消える数列、消えない数列 ただお君は頭の体操をするために、数列を使ったゲームをしています。このゲームでは、はじめに、1から9までの数字がランダムに並んだ列が与えられます。ただお君は、数列からその一部分を消していきます。ルールは、以下の通りです。 数列から、同じ数字が2つ以上並んでいる部分を適当に選ぶ。その部分を含み、連続して現れている同じ数字をすべて消す。 消した部分の右側に数列が残っていた場合は、それを左に詰めて、数列を1つにまとめる。 上の2つの操作を繰り返した結果、すべての数字が消えればゲームクリアとなる。 例えば、上の図のような 1,2,3,3,2,2,1,2,2 という数列の場合、 左から数えて、3番目、4番目の3を消すと 1,2,2,2,1,2,2 左から数えて、2番目から4番目の2を消すと 1,1,2,2 左から数えて、1番目と2番目の1を消すと 2,2 左から数えて、1番目と2番目の2を消すと、ゲームクリアとなります。 ただし、どのように数字を消してもクリアできない数列があります。たとえば、1,2,3,3,1,2 や 1,2,3,1,2,3 などの数列です。短い数列であれば、ただお君でもクリアできるかどうかがすぐに分かり、クリアできないと分かれば違う数列にチャレンジできますが、長い数列になるとそう簡単にはいきません。 与えられた数列が上のゲームをクリアできるかどうか判定するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N c 1 c 2 ... c N 1行目の N (1 ≤ N ≤ 100) は、数列の長さを表す整数である。2行目には1つの空白で区切られた N 個の整数 c i (1 ≤ c i ≤ 9) が与えられる。 c i は数列の i 番目の数字を示す。 Output 上に示されたルールで数列を消すことができる場合は「yes」、できない場合は「no」を出力する。 Sample Input 1 8 1 2 3 3 2 1 2 2 Sample Output 1 yes Sample Input 2 7 1 2 2 1 1 3 3 Sample Output 2 yes Sample Input 3 16 9 8 8 7 7 6 5 4 4 5 1 1 2 2 3 3 Sample Output 3 no Sample Input 4 5 1 1 2 2 1 Sample Output 4 yes
[ { "submission_id": "aoj_0332_9099687", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n;\n cin >> n;\n vector<int> c(n);\n for (int i = 0; i < n; i++) {\n cin >> c[i];\n }\n vector<vector<bool>> dp(n + 1, vector<bool>(n + 1));\n for (int i = 0; i <= n; i++) {\n dp[i][i] = true;\n }\n for (int i = 0; i < n - 1; i++) {\n if (c[i] == c[i + 1]) dp[i][i + 2] = true;\n }\n for (int i = 0; i < n - 2; i++) {\n if (c[i] == c[i + 1] and c[i + 1] == c[i + 2]) dp[i][i + 3] = true;\n }\n for (int len = 4; len <= n; len++) {\n for (int i = 0; i + len <= n; i++) {\n for (int j = i; j <= i + len; j++) {\n if (dp[i][j] and dp[j][i + len]) dp[i][i + len] = true;\n }\n for (int x = i; x < i + len; x++) {\n for (int y = x + 1; y < i + len; y++) {\n if (c[x] == c[y]) {\n if (dp[i][x] and dp[x + 1][y] and dp[y + 1][i + len]) {\n dp[i][i + len] = true;\n }\n }\n }\n }\n for (int x = i; x < i + len; x++) {\n for (int y = x + 1; y < i + len; y++) {\n if (c[x] != c[y]) continue;\n for (int z = y + 1; z < i + len; z++) {\n if (c[x] != c[z]) continue;\n if (dp[i][x] and dp[x + 1][y] and dp[y + 1][z] and dp[z + 1][i + len]) {\n dp[i][i + len] = true;\n }\n }\n }\n }\n }\n }\n if (dp[0][n]) {\n cout << \"yes\" << endl;\n } else {\n cout << \"no\" << endl;\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3464, "score_of_the_acc": -0.2252, "final_rank": 11 }, { "submission_id": "aoj_0332_4571335", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int n;\n cin >> n;\n vector<int> v(n);\n for (auto &&i : v) scanf(\"%d\", &i);\n auto dp = make_v(n, n+1, 10, (signed char)(-1));\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < 10; ++j) {\n dp[i][i+1][j] = 0;\n }\n dp[i][i+1][v[i]] = 1;\n }\n for (int l = 0; l < n; ++l) {\n int r = l;\n while(r < n && v[l] == v[r]) r++;\n for (int i = l+2; i < r; ++i) {\n dp[l][i][0] = dp[l][i][v[l]] = 1;\n }\n }\n auto dfs = [&](int l, int r, int x, auto &&f) -> signed char {\n if(~dp[l][r][x]) return dp[l][r][x];\n if(!x){\n for (int i = l+1; i < r; ++i) {\n for (int j = 0; j < 10; ++j) {\n if(f(l, i, j, f) && f(i, r, j, f)) return dp[l][r][x] = 1;\n }\n }\n }else {\n for (int i = l+1; i < r; ++i) {\n if(f(l, i, 0, f) && f(i, r, x, f)) return dp[l][r][x] = 1;\n if(f(l, i, x, f) && f(i, r, 0, f)) return dp[l][r][x] = 1;\n if(f(l, i, x, f) && f(i, r, x, f)) return dp[l][r][x] = 1;\n }\n }\n return dp[l][r][x] = 0;\n };\n puts(dfs(0, n, 0, dfs) ? \"yes\" : \"no\");\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3788, "score_of_the_acc": -0.0231, "final_rank": 1 }, { "submission_id": "aoj_0332_3975249", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<string>\n#include<map>\nusing namespace std;\nint array1[105]={0};\nbool dp[105][105][10],decide[105][105][10];\nbool sec_dp(int l,int r,int c){\n //[l,r)\n if(decide[l][r][c]) return dp[l][r][c];\n decide[l][r][c]=true;\n if(r-l==2){\n if(c==0){\n return dp[l][r][c]=(array1[l]==array1[l+1]);\n }\n else return dp[l][r][c]=(array1[l]==c&&array1[l+1]==c);\n }\n if(r-l==1){\n return dp[l][r][c]=(c==array1[l]);\n }\n for(int i=l+1;i<r;i++){\n if(c==0){\n for(int j=0;j<10;j++){\n bool b1=sec_dp(l,i,0);\n bool b2=sec_dp(l,i,j);\n bool b3=sec_dp(i,r,0);\n bool b4=sec_dp(i,r,j);\n // if(l==0&&r==4&&i==1&&j==1) cout<<(b1?\"Y\":\"N\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n // if(l==1&&r==4&&i==3&&j==1) cout<<(b1?\"Y!\":\"N!\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n if((b1&&b3)||(b2&&b4)) {\n // cout<<\"ina\"<<l<<\" \"<<r<<\" \"<<i<<\" \"<<c<<\" \"<<j<<endl;\n return dp[l][r][c]=true;\n }\n }\n }\n else{\n bool b1=sec_dp(l,i,0);\n bool b2=sec_dp(l,i,c);\n bool b3=sec_dp(i,r,0);\n bool b4=sec_dp(i,r,c);\n if((b2&&b4)||(b1&&b4)||(b2&&b3)){\n // cout<<\"yoc\"<<l<<\" \"<<r<<\" \"<<i<<\" \"<<c<<endl;\n return dp[l][r][c]=true;\n }\n }\n }\n return dp[l][r][c]=false;\n}\nint main(){\n //while(1){\n int n;\n cin>>n;\n if(n==0) return 0;\n for(int i=0;i<105;i++){\n array1[i]=0;\n for(int j=0;j<105;j++){\n for(int k=0;k<10;k++){\n dp[i][j][k]=false;\n decide[i][j][k]=false;\n }\n }\n }\n for(int i=0;i<n;i++) cin>>array1[i];\n cout<<(sec_dp(0,n,0)?\"yes\":\"no\")<<endl;\n// }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3332, "score_of_the_acc": -0.0583, "final_rank": 7 }, { "submission_id": "aoj_0332_3975221", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<string>\n#include<map>\nusing namespace std;\nint array1[105]={0};\nbool dp[105][105][10],decide[105][105][10];\nbool sec_dp(int l,int r,int c){\n //[l,r)\n if(decide[l][r][c]) return dp[l][r][c];\n decide[l][r][c]=true;\n if(r-l==2){\n if(c==0){\n return dp[l][r][c]=(array1[l]==array1[l+1]);\n }\n else return dp[l][r][c]=(sec_dp(l,l+1,c)&&sec_dp(r-1,r,c));\n }\n if(r-l==1){\n decide[l][r][c]=true;\n return dp[l][r][c]=(c==array1[l]);\n }\n for(int i=l+1;i<r;i++){\n if(c==0){\n for(int j=0;j<10;j++){\n bool b1=sec_dp(l,i,0);\n bool b2=sec_dp(l,i,j);\n bool b3=sec_dp(i,r,0);\n bool b4=sec_dp(i,r,j);\n // if(l==0&&r==4&&i==1&&j==1) cout<<(b1?\"Y\":\"N\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n // if(l==1&&r==4&&i==3&&j==1) cout<<(b1?\"Y!\":\"N!\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n if((b1&&b3)||(b2&&b4)) return dp[l][r][c]=(b1&&b3)||(b2&&b4);\n }\n }\n else{\n bool b1=sec_dp(l,i,0);\n bool b2=sec_dp(l,i,c);\n bool b3=sec_dp(i,r,0);\n bool b4=sec_dp(i,r,c);\n return dp[l][r][c]=(b2&&b4)||(b1&&b4)||(b2&&b3);\n }\n }\n decide[l][r][c]=true;\n return dp[l][r][c]=false;\n}\nint main(){\n //while(1){\n int n;\n cin>>n;\n if(n==0) return 0;\n for(int i=0;i<105;i++){\n array1[i]=0;\n for(int j=0;j<105;j++){\n for(int k=0;k<10;k++){\n dp[i][j][k]=false;\n decide[i][j][k]=false;\n }\n }\n }\n for(int i=0;i<n;i++) cin>>array1[i];\n cout<<(sec_dp(0,n,0)?\"yes\":\"no\")<<endl;\n// }\n}", "accuracy": 0.5375, "time_ms": 10, "memory_kb": 3328, "score_of_the_acc": -0.0134, "final_rank": 16 }, { "submission_id": "aoj_0332_3973613", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<string>\n#include<map>\nusing namespace std;\nint array1[105]={0};\nbool dp[105][105][10],decide[105][105][10];\nbool sec_dp(int l,int r,int c){\n //[l,r)\n if(decide[l][r][c]) return dp[l][r][c];\n decide[l][r][c]=true;\n if(r-l==2){\n if(c==0){\n return dp[l][r][c]=(array1[l]==array1[l+1]);\n }\n else return dp[l][r][c]=(sec_dp(l,l+1,c)&&sec_dp(r-1,r,c));\n }\n if(r-l==1){\n decide[l][r][c]=true;\n return dp[l][r][c]=(c==array1[l]);\n }\n for(int i=l+1;i<r;i++){\n for(int j=0;j<10;j++){\n bool b1=sec_dp(l,i,0);\n bool b2=sec_dp(l,i,j);\n bool b3=sec_dp(i,r,0);\n bool b4=sec_dp(i,r,j);\n // if(l==0&&r==4&&i==1&&j==1) cout<<(b1?\"Y\":\"N\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n // if(l==1&&r==4&&i==3&&j==1) cout<<(b1?\"Y!\":\"N!\")<<(b2?\"Y\":\"N\")<<(b3?\"Y\":\"N\")<<(b4?\"Y\":\"N\")<<endl;\n if(c==0){\n if((b1&&b3)||(b2&&b4)) return dp[l][r][c]=(b1&&b3)||(b2&&b4);\n }\n else{\n if(c==j){\n return dp[l][r][c]=(b2&&b4)||(b1&&b4)||(b2&&b3);\n }\n }\n }\n }\n decide[l][r][c]=true;\n return dp[l][r][c]=false;\n}\nint main(){\n //while(1){\n int n;\n cin>>n;\n if(n==0) return 0;\n for(int i=0;i<105;i++){\n array1[i]=0;\n for(int j=0;j<105;j++){\n for(int k=0;k<10;k++){\n dp[i][j][k]=false;\n decide[i][j][k]=false;\n }\n }\n }\n for(int i=0;i<n;i++) cin>>array1[i];\n cout<<(sec_dp(0,n,0)?\"yes\":\"no\")<<endl;\n// }\n}", "accuracy": 0.5375, "time_ms": 10, "memory_kb": 3332, "score_of_the_acc": -0.0135, "final_rank": 17 }, { "submission_id": "aoj_0332_3356666", "code_snippet": "// #define _GLIBCXX_DEBUG // for STL debug (optional)\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\nusing namespace std;\n\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define int long long int\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \ntypedef pair<int, int> pii;\ntypedef long long ll;\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\nconst int MAXN = 110;\nint dp[MAXN][MAXN][MAXN], A[MAXN];\n\nint solve(int l, int r, int prefix) {\n if(r - l == 0) return true;\n if(r - l == 1) return prefix >= 2;\n int &val = dp[l][r][prefix];\n if(val >= 0) return val;\n\n val = prefix >= 2 ? solve(l+1, r, 1) : false;\n for(int i=l+1; i<r; i++) {\n if(A[l] == A[i]) {\n val |= solve(l+1, i, 1) & solve(i, r, prefix + 1);\n }\n }\n\n /*\n if(val == true) {\n fprintf(stderr, \"true: segment = [%lld, %lld), prefix = %lld\\n\", l, r, prefix);\n }\n */\n return val;\n}\n\nsigned main() {\n int N; cin >> N;\n for(int i=0; i<N; i++) {\n cin >> A[i];\n }\n fill(dp[0][0], dp[N+1][0], -1);\n cout << (solve(0, N, 1) ? \"yes\" : \"no\") << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 12648, "score_of_the_acc": -0.2249, "final_rank": 10 }, { "submission_id": "aoj_0332_3224794", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nint n,a[111],dp[111][111][11];\n\nint dfs(int l,int r,int x){\n if(l==r)return x==a[l];\n if(dp[l][r][x]!=-1)return dp[l][r][x];\n dp[l][r][x]=0;\n for(int i=l;i<r;i++){\n for(int j=0;j<10;j++){\n if(dfs(l,i,j)&&dfs(i+1,r,j)) dp[l][r][0]=1 , dp[l][r][j]=1;\n if(dfs(l,i,j)&&dfs(i+1,r,0)) dp[l][r][j]=1;\n if(dfs(l,i,0)&&dfs(i+1,r,j)) dp[l][r][j]=1;\n }\n }\n return dp[l][r][x];\n}\n\nint main(){\n memset(dp,-1,sizeof(dp));\n cin>>n;\n r(i,n)cin>>a[i];\n dfs(0,n-1,0);\n cout<<(dp[0][n-1][0]==1?\"yes\":\"no\")<<endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3672, "score_of_the_acc": -0.2744, "final_rank": 12 }, { "submission_id": "aoj_0332_3224792", "code_snippet": "#include <bits/stdc++.h>\n#define r(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nint n,a[111],dp[111][111][11];\n\nint dfs(int l,int r,int x){\n if(l==r)return x==a[l];\n if(dp[l][r][x]!=-1)return dp[l][r][x];\n dp[l][r][x]=0;\n for(int i=l;i<r;i++){\n for(int j=0;j<10;j++){\n if(dfs(l,i,j)&&dfs(i+1,r,j)) dp[l][r][0]=1 , dp[l][r][j]=1;\n if(dfs(l,i,j)&&dfs(i+1,r,0)) dp[l][r][j]=1;\n if(dfs(l,i,0)&&dfs(i+1,r,j)) dp[l][r][j]=1;\n }\n }\n return dp[l][r][x];\n}\n\nint main(){\n memset(dp,-1,sizeof(dp));\n cin>>n;\n r(i,n)cin>>a[i];\n dfs(0,n-1,0);\n cout<<(dp[0][n-1][0]?\"yes\":\"no\")<<endl;\n}", "accuracy": 0.4375, "time_ms": 180, "memory_kb": 3664, "score_of_the_acc": -0.2742, "final_rank": 19 }, { "submission_id": "aoj_0332_3062451", "code_snippet": "#include <stdio.h>\nconst int N=1e2+10;\nbool ans[N][N],went[N][N];\nint a[N];\nbool dp(int l,int r){\n if(l-r==1)return true;\n else if(r<l)return false;\n if(went[l][r])return ans[l][r];\n went[l][r]=true;\n if(r==l)return ans[l][r]=false;\n else if(r-l==1)return ans[l][r]=a[l]==a[r];\n else if(r-l==2)return ans[l][r]=a[l]==a[l+1]&&a[l]==a[r];\n else{\n for(int i=l;i<=r;i++)for(int j=i+1;j<=r;j++)if(a[i]==a[j]){\n ans[l][r]=dp(l,i-1)&&dp(i+1,j-1)&&dp(j+1,r);\n if(ans[l][r])return true;\n }\n for(int i=l;i<=r;i++)for(int j=i+1;j<=r;j++)if(a[i]==a[j])for(int k=j+1;k<=r;k++)if(a[j]==a[k]){\n ans[l][r]=dp(l,i-1)&&dp(i+1,j-1)&&dp(j+1,k-1)&&dp(k+1,r);\n if(ans[l][r])return true;\n }\n return ans[l][r]=false;\n }\n}\nint main(){\n int n;\n scanf(\"%d\",&n);\n for(int i=0;i<n;i++)scanf(\"%d\",&a[i]);\n for(int i=0;i<n;i++)for(int j=i;j<n;j++)went[i][j]=false;\n if(dp(0,n-1))printf(\"yes\\n\");\n else printf(\"no\\n\");\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 2692, "score_of_the_acc": -0.0746, "final_rank": 8 }, { "submission_id": "aoj_0332_2591502", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<\"=\"<<x<<endl\n\nint N;\nvector<int>c;\n//[i,j)???k???????????§?????????(false:0 true:1)\nint memo[123][123][12];\nint dp(int i,int j,int k){\n\tif(memo[i][j][k]>=0){\n\t\treturn memo[i][j][k];\n\t}\n\tint res = 0;\n\tassert(i < j);\n\tif(j - i == 1){\n\t\tif(k == c[i])res = 1;\n\t}else{\n\t\tif(k){\n\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\tif((dp(i,m,k)&&dp(m,j,k)) || (dp(i,m,k)&&dp(m,j,0)) || (dp(i,m,0)&&dp(m,j,k))){\n\t\t\t\t\tres = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int kk = 0;kk <= 9;++kk){\n\t\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\t\tif((dp(i,m,kk)&&dp(m,j,kk))){\n\t\t\t\t\t\tres = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn memo[i][j][k]=res;\n}\n\nint main(){\n\tcin >> N;\n\tfor(int i=0;i<N;++i){\n\t\tint cc;cin >> cc;\n\t\tc.push_back(cc);\n\t}\n\tmemset(memo,0xff,sizeof(memo));\n\tcout << (dp(0,N,0) ? \"yes\" : \"no\") << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3820, "score_of_the_acc": -0.0387, "final_rank": 3 }, { "submission_id": "aoj_0332_2591501", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<\"=\"<<x<<endl\n\nint N;\nvector<int>c;\n//[i,j)???k???????????§?????????(false:0 true:1)\nint memo[100][100][10];\nint dp(int i,int j,int k){\n\tif(memo[i][j][k]>=0){\n\t\treturn memo[i][j][k];\n\t}\n\tint res = 0;\n\tassert(i < j);\n\tif(j - i == 1){\n\t\tif(k == c[i])res = 1;\n\t}else{\n\t\tif(k){\n\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\tif((dp(i,m,k)&&dp(m,j,k)) || (dp(i,m,k)&&dp(m,j,0)) || (dp(i,m,0)&&dp(m,j,k))){\n\t\t\t\t\tres = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int kk = 0;kk <= 9;++kk){\n\t\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\t\tif((dp(i,m,kk)&&dp(m,j,kk))){\n\t\t\t\t\t\tres = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn memo[i][j][k]=res;\n}\n\nint main(){\n\tcin >> N;\n\tfor(int i=0;i<N;++i){\n\t\tint cc;cin >> cc;\n\t\tc.push_back(cc);\n\t}\n\tmemset(memo,0xff,sizeof(memo));\n\tcout << (dp(0,N,0) ? \"yes\" : \"no\") << endl;\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 10, "memory_kb": 3500, "score_of_the_acc": -0.017, "final_rank": 14 }, { "submission_id": "aoj_0332_2591497", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<\"=\"<<x<<endl\n\nint N;\nvector<int>c;\n//[i,j)???k???????????§?????????(false:0 true:1)\nint memo[100][100][10];\nint dp(int i,int j,int k){\n\tif(memo[i][j][k]>=0){\n\t\treturn memo[i][j][k];\n\t}\n\tint res = 0;\n\tassert(i < j);\n\tif(j - i == 1){\n\t\tif(k == c[i])res = 1;\n\t}else{\n\t\tif(k){\n\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\tif((dp(i,m,k)&&dp(m,j,k)) || (dp(i,m,k)&&dp(m,j,0)) || (dp(i,m,0)&&dp(m,j,k))){\n\t\t\t\t\tres = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int kk = 0;kk <= 9;++kk){\n\t\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\t\tif((dp(i,m,kk)&&dp(m,j,kk))){\n\t\t\t\t\t\tres = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(res)break;\n\t\t\t}\n\t\t}\n\t}\n\treturn memo[i][j][k]=res;\n}\n\nint main(){\n\tcin >> N;\n\tfor(int i=0;i<N;++i){\n\t\tint cc;cin >> cc;\n\t\tc.push_back(cc);\n\t}\n\tmemset(memo,0xff,sizeof(memo));\n\tcout << (dp(0,N,0) ? \"yes\" : \"no\") << endl;\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 10, "memory_kb": 3496, "score_of_the_acc": -0.017, "final_rank": 13 }, { "submission_id": "aoj_0332_2591464", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<\"=\"<<x<<endl\n\nint N;\nvector<int>c;\n//[i,j)???k???????????§?????????(false:0 true:1)\nint memo[100][100][10];\nint dp(int i,int j,int k){\n\tif(memo[i][j][k]>=0){\n\t\treturn memo[i][j][k];\n\t}\n\tint res = 0;\n\tassert(i < j);\n\tif(j - i == 1){\n\t\tif(k == c[i])res = 1;\n\t}else{\n\t\tif(k){\n\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\tif((dp(i,m,k)&&dp(m,j,k)) || (dp(i,m,k)&&dp(m,j,0)) || (dp(i,m,0)&&dp(m,j,k))){\n\t\t\t\t\tres = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tfor(int kk = 1;kk <= 9;++kk){\n\t\t\t\tfor(int m = i + 1;m < j;++m){\n\t\t\t\t\tif((dp(i,m,kk)&&dp(m,j,kk)) || (dp(i,m,0)&&dp(m,j,0))){\n\t\t\t\t\t\tres = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn memo[i][j][k]=res;\n}\n\nint main(){\n\tcin >> N;\n\tfor(int i=0;i<N;++i){\n\t\tint cc;cin >> cc;\n\t\tc.push_back(cc);\n\t}\n\tmemset(memo,0xff,sizeof(memo));\n\tcout << (dp(0,N,0) ? \"yes\" : \"no\") << endl;\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 20, "memory_kb": 3500, "score_of_the_acc": -0.032, "final_rank": 15 }, { "submission_id": "aoj_0332_2588984", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <cmath>\n#include <iomanip>\n#include <cassert>\n#include <bitset>\nusing namespace std;\n\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i=0; i<(n); i++)\n#define all(c) (c).begin(), (c).end()\n#define uniq(c) c.erase(unique(all(c)), (c).end())\n#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())\n#define _1 first\n#define _2 second\n#define pb push_back\n#define INF 1145141919\n#define MOD 1000000007\n\nint N;\nint A[100];\nbool dp[100][100][9][3];\nsigned main() {\n ios::sync_with_stdio(false); cin.tie(0);\n cin >> N;\n rep(i, N) cin >> A[i], A[i]--;\n rep(i, N) dp[i][i][A[i]][1] = 1;\n for (int len=2; len<=N; len++) {\n rep(l, N) {\n int r = l+len-1;\n if (r >= N) break;\n rep(j, 9) {\n rep(k, 3) {\n for (int t=l; t<=r-1; t++) {\n // [l, t] + [t+1, r]\n for (int s1=0; s1<=2; s1++) for (int s2=0; s2<=2; s2++) {\n dp[l][r][j][min(s1+s2, 2)] |= dp[l][t][j][s1] & dp[t+1][r][j][s2];\n }\n }\n }\n dp[l][r][j][0] |= dp[l][r][j][2];\n }\n bool ok = false;\n rep(j, 9) ok |= dp[l][r][j][0];\n rep(j, 9) dp[l][r][j][0] |= ok;\n }\n }\n\n bool b = 0;\n rep(i, 9) b |= dp[0][N-1][i][0];\n cout << (b?\"yes\":\"no\") << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3436, "score_of_the_acc": -0.0903, "final_rank": 9 }, { "submission_id": "aoj_0332_2582351", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<pll, int> plp;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst double EPS = 1e-10;\nconst bool debug = 0;\n//--------------------------------//\n\nint N;\nint c[100];\nbool dp[100][101][10];\n\nint main() {\n\tcin >> N;\n\tREP(i, N) scanf(\"%d\", c + i);\n\t\n\tREP(i, N - 1) if (c[i] == c[i + 1]) dp[i][i + 2][c[i]] = true;\n\t\n\tFOR(s, 2, N + 1) {\n\t\tREP(l, N - s + 1) {\n\t\t\tint r = l + s;\n\t\t\t\n\t\t\tREP(i, 10) REP(j, 10) {\n\t\t\t\tFOR(k, l + 1, r) {\n\t\t\t\t\tdp[l][r][0] |= dp[l][k][i] & dp[k][r][j]; // xx\n\t\t\t\t\t\n\t\t\t\t\tif (c[l] == c[r - 1]) {\n\t\t\t\t\t\tdp[l][r][c[l]] |= dp[l + 1][r - 1][i]; // 1x1\n\t\t\t\t\t\tif (c[l] == c[k]) dp[l][r][c[l]] |= dp[l + 1][k][i] & dp[k + 1][r - 1][j]; // 1x1x1\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tif (l > 0) dp[l - 1][r][c[l - 1]] |= dp[l][r][c[l - 1]];\n\t\t\tif (r < N) dp[l][r + 1][c[r]] |= dp[l][r][c[r]];\n\t\t}\n\t}\n\t\n\tbool ans = false;\n\tREP(i, 10) ans |= dp[0][N][i];\n\tputs(ans ? \"yes\" : \"no\");\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3252, "score_of_the_acc": -0.0566, "final_rank": 6 }, { "submission_id": "aoj_0332_2411437", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\nusing namespace std;\n\nclass S {\npublic:\n\tstd::vector<int> p;\n\tS() {\n\t}\n\tbool clear(vector<int> p) {\n\t\treturn p.empty();\n\t}\n};\n\nint main()\n{\n\tint N;\n\tcin >> N;\n\tS now;\n\tint a = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> a;\n\t\tnow.p.push_back(a);\n\t}\n\n\tqueue<S> que;\n\tque.push(now);\n\n\twhile (!que.empty()) {\n\t\tnow = que.front();\n\t\tque.pop();\n\t\tif (now.clear(now.p)) {\n\t\t\tcout << \"yes\" << endl;\n\t\t\tbreak;\n\t\t}\n\t\tint c = -1;\n\t\tfor (int i = 0; i < now.p.size() - 1; i++) {\n\t\t\tif (c > -1) {\n\t\t\t\tif (now.p[i] == now.p[i + 1]) {\n\t\t\t\t\tif (i + 1 == now.p.size() - 1) {\n\t\t\t\t\t\tS nex;\n\t\t\t\t\t\tfor (int i = 0; i < now.p.size(); i++) {\n\t\t\t\t\t\t\tnex.p.push_back(now.p[i]);\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnex.p.erase(nex.p.begin() + c, nex.p.begin() + i + 2);\n\t\t\t\t\t\tque.push(nex);\n\t\t\t\t\t\tc = -1;\n\t\t\t\t\t}\n\n\t\t\t\t\tcontinue;\n\n\t\t\t\t}\n\t\t\t\tS nex;\n\t\t\t\tfor (int i = 0; i < now.p.size(); i++) {\n\t\t\t\t\tnex.p.push_back(now.p[i]);\n\t\t\t\t}\n\t\t\t\tnex.p.erase(nex.p.begin() + c, nex.p.begin() + i + 1);\n\t\t\t\tque.push(nex);\n\t\t\t\tc = -1;\n\t\t\t}\n\t\t\telse if (now.p[i] == now.p[i + 1]) {\n\t\t\t\tc = i;\n\n\t\t\t\tif (c == now.p.size() - 2) {\n\t\t\t\t\tS nex;\n\t\t\t\t\tfor (int i = 0; i < now.p.size(); i++) {\n\t\t\t\t\t\tnex.p.push_back(now.p[i]);\n\t\t\t\t\t}\n\t\t\t\t\tnex.p.erase(nex.p.begin() + c, nex.p.begin() + i + 2);\n\t\t\t\t\tque.push(nex);\n\t\t\t\t\tc = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (!now.p.empty())\n\t\tcout << \"no\" << endl;\n\treturn 0;\n}", "accuracy": 0.175, "time_ms": 330, "memory_kb": 50116, "score_of_the_acc": -1.4776, "final_rank": 20 }, { "submission_id": "aoj_0332_2396595", "code_snippet": "#include<complex>\n#include<algorithm>\n#include<iostream>\n#include<iomanip>\n#include<cmath>\n#include<vector>\n#include<map>\n#include<sstream>\n#include<ctime>\n#include<cstdio>\n#include<cstdlib>\n#include<cassert>\n#include<deque>\n#include<queue>\n#include<climits>\n#include<set>\n#include<list>\n#include<cstring>\n#include<stack>\n#include<fstream>\n#include<ctime>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n\nusing namespace std;\n\nint n,c[101];\nbool dp[110][110];\n\nint main(){\n cin >> n;\n rep(i,n) cin >> c[i];\n\n REP(len,1,n) {\n rep(sp,n) {\n if( sp + len >= n ) break;\n int L = sp, R = L + len; // [L,R]\n dp[L][R] = false;\n\n {\n\tset<int> S;\n\tREP(i,L,R+1) S.insert(c[i]);\n\tif( S.size() == 1 ) dp[L][R] = true;\n }\n if( dp[L][R] ) continue;\n REP(M,L+1,R) {\n\tif( dp[L][M] && dp[M+1][R] ) { dp[L][R] = true; break; }\n }\n if( dp[L][R] ) continue;\n REP(M1,L,R+1) REP(M2,M1,R+1) {\n\tif( dp[M1][M2] ) {\n\t set<int> S;\n\t int cnt = 0;\n\t REP(i,L,R+1) if( !( M1 <= i && i <= M2 ) ) S.insert(c[i]), ++cnt;\n\t if( cnt >= 2 && S.size() == 1 ) { dp[L][R] = true; goto Skip; }\n\t}\n }\n Skip:;\n }\n }\n puts(dp[0][n-1]?\"yes\":\"no\");\n return 0;\n}", "accuracy": 0.5375, "time_ms": 680, "memory_kb": 3124, "score_of_the_acc": -1.0091, "final_rank": 18 }, { "submission_id": "aoj_0332_2167484", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n vector<int> c(N);\n for(auto& i: c) cin >> i;\n\n vector<vector<vector<bool>>> dp(N, vector<vector<bool>>(N, vector<bool>(10)));\n for(auto i = 0; i < N; ++i) dp[i][i][c[i]] = true;\n\n for(auto w = 1; w < N; ++w) for(auto i = 0; i < N - w; ++i) for(auto k = 0; k < 10; ++k) {\n auto j = i + w;\n for(auto x = i; x < j; ++x) {\n if(dp[i][x][0] && dp[x + 1][j][0]) dp[i][j][0] = true;\n if(dp[i][x][k] && dp[x + 1][j][k]) dp[i][j][0] = true;\n if(!k) continue;\n if(dp[i][x][0] && dp[x + 1][j][k]) dp[i][j][k] = true;\n if(dp[i][x][k] && dp[x + 1][j][0]) dp[i][j][k] = true;\n if(dp[i][x][k] && dp[x + 1][j][k]) dp[i][j][k] = true;\n }\n }\n\n cout << (dp[0][N-1][0] ? \"yes\" : \"no\") << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3796, "score_of_the_acc": -0.0233, "final_rank": 2 }, { "submission_id": "aoj_0332_2163644", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,num[101];\n \n\nbool check(int l,int r){\n for(int i=l;i<=r;i++) if(num[l]!=num[i])return 0;\n return 1;\n}\n\nint used[101][101],mem[101][101]; \nint dfs(int l,int r){\n if(l==r)return 0;\n if(check(l,r)) return 1;\n if(used[l][r]++)return mem[l][r];\n \n int res=0;\n for(int i=l;num[l]==num[i];i++)\n for(int j=r;num[l]==num[j];j--){\n res|=dfs(l+1,r-1);\n for(int k=i+1;k<j;k++)\n\tres|=num[l]==num[k]&&dfs(i+1,k-1)&&dfs(k+1,j-1);\n }\n \n for(int i=l;i<r;i++) res|=dfs(l,i)&&dfs(i+1,r);\n return mem[l][r]=res;\n}\n \nint main(){\n cin>>n;\n for(int i=0;i<n;i++)cin>>num[i];\n cout<<(dfs(0,n-1)?\"yes\":\"no\")<<endl;;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3144, "score_of_the_acc": -0.0394, "final_rank": 4 }, { "submission_id": "aoj_0332_2163636", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,num[101];\n \nint used[101][101],mem[101][101];\nbool check(int l,int r){\n if(l==r) return 0;\n for(int i=l;i<=r;i++) if(num[l]!=num[i])return 0;\n return 1;\n}\n \nint dfs(int l,int r){\n if(l==r)return 0;\n if(check(l,r)) return 1;\n if(used[l][r]++)return mem[l][r];\n \n int res=0;\n for(int i=0;num[l]==num[l+i];i++)\n for(int j=0;num[l]==num[r-j];j++)\n res|=dfs(l+i+1,r-j-1);\n \n for(int i=l;num[l]==num[i];i++)\n for(int j=r;num[l]==num[j];j--)\n for(int k=i+1;k<j;k++)\n\tif(num[l]==num[k])res|=dfs(i+1,k-1)&&dfs(k+1,j-1);\n \n \n for(int i=l;i<r;i++) res|=dfs(l,i)&&dfs(i+1,r);\n return mem[l][r]=res;\n}\n \nint main(){\n cin>>n;\n for(int i=0;i<n;i++)cin>>num[i];\n cout<<(dfs(0,n-1)?\"yes\":\"no\")<<endl;;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3144, "score_of_the_acc": -0.0394, "final_rank": 4 } ]
aoj_0334_cpp
あみだくじ PCK 君はみんなでゲーム大会をしています。このゲーム大会では、大会の最後にあみだくじで順位を入れ替えます。大会には N 人のプレイヤーが参加しており、あみだくじには N 本の縦棒があります。 あみだくじは、図のように N - 1 段の部品からできており、それぞれ 1 から N -1 の番号が割り当てられています。各部品は、あみだくじの一部を横方向に切り取った部分です。各部品にはいくつかの横棒が引かれていますが、部品の中の横棒はすべて同じ高さにあります。横棒同士がつながることはありません。 大会の最後に、順位の高い人から右から左の順に縦棒が割り当てられます。PCK 君は現時点で最下位なので、左端からスタートです。例えば、上図の組み立て方では、6位だったPCK 君は、このあみだくじによって4位(右から4番目の棒)に浮上することができます。 このゲームでは、最下位の人にあみだくじを組み立てる権利が与えられます。PCK 君はうまくあみだくじの部品の順番を決めて、逆転優勝を狙っています。ただし、部品を回転することはできません。 (※補足:あみだくじのたどり方について) あみだくじのある縦棒の上端から出発して上から下へ進む。ただし、横棒がある地点ではその横棒でつながった別の縦棒に移動する。これを、縦棒の下端にたどり着くまで繰り返す。 ゲームの参加人数とあみだくじの部品の情報を入力し、PCK 君が優勝できるかどうか判定するプログラムを作成せよ。優勝できる場合、そのあみだくじの部品の並びを1つ出力せよ。ただし、そのような並べ方が複数ある場合は、与えられた部品の番号で辞書順最小のものを出力せよ。 Input 入力は以下の形式で与えられる。 N b 1,1 b 1,2 ... b 1,N−1 b 2,1 b 2,2 ... b 2,N−1 : b N−1,1 b N−1,2 ... b N−1,N−1 1行目に大会の参加者数 N (2 ≤ N ≤ 500) が与えられる。続く N -1 行に i 番目の部品の横棒の情報が与えられる。 b i,j が 1 であるとき、 i 番目の部品の、左から j 本目の縦棒から j +1 番目の縦棒へ横棒が引かれていることを表す。 b i,j が 0 であるとき、 i 番目の部品の、左から j 本目の縦棒から j +1 番目の縦棒へ横棒は引かれていないことを表す。 b i,j が 1 であるとき、 b i,j+1 が 1 となるような部品は与えられない。また、横棒の総数は 10000 を越えない。 Output PCK 君が優勝できる場合,1行目に「yes」と出力する。続く N -1 行に、あみだくじの上から順に、部品の番号の並びを出力する。そのような並びが複数ある場合、辞書順最小である並びを出力する。PCK 君が優勝できない場合、1行に「no」と出力する。 Sample Input 1 6 1 0 0 0 1 1 0 1 0 1 0 1 0 1 0 0 0 0 1 0 0 1 0 0 1 Sample Output 1 yes 1 3 2 4 5 Sample Input 2 5 0 1 0 1 0 1 0 1 1 0 1 0 1 0 0 1 Sample Output 2 yes 4 1 3 2 4 1 3 2 と 4 2 3 1 の2通りの組み立て方が可能だが、辞書順で小さい方の 4 1 3 2 を出力する。 Sample Input 3 5 1 0 0 1 0 1 0 1 1 0 0 0 0 1 0 1 Sample Output 3 no
[ { "submission_id": "aoj_0334_10853299", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <cstring>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <list>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <unordered_set>\n#include <unordered_map>\n#include <array>\n#include <cassert>\n#include <bitset>\nusing namespace std;\nusing LL = long long;\n\nstruct Bipartite_Matching\n{\n\tvector< vector< int > > graph;\n\tvector< int > match, alive, used;\n\tint timestamp;\n\n\tBipartite_Matching(int n)\n\t{\n\t\ttimestamp = 0;\n\t\tgraph.resize(n);\n\t\talive.assign(n, 1);\n\t\tused.assign(n, 0);\n\t\tmatch.assign(n, -1);\n\t}\n\n\tvoid add_edge(int u, int v)\n\t{\n\t\tgraph[u].push_back(v);\n\t\tgraph[v].push_back(u);\n\t}\n\n\tbool dfs(int v)\n\t{\n\t\tused[v] = timestamp;\n\t\tfor (int i = 0; i < graph[v].size(); i++) {\n\t\t\tint u = graph[v][i], w = match[u];\n\t\t\tif (alive[u] == 0) continue;\n\t\t\tif (w == -1 || (used[w] != timestamp && dfs(w))) {\n\t\t\t\tmatch[v] = u;\n\t\t\t\tmatch[u] = v;\n\t\t\t\treturn (true);\n\t\t\t}\n\t\t}\n\t\treturn (false);\n\t}\n\n\tint bipartite_matching()\n\t{\n\t\tint ret = 0;\n\t\tfor (int i = 0; i < graph.size(); i++) {\n\t\t\tif (alive[i] == 0) continue;\n\t\t\tif (match[i] == -1) {\n\t\t\t\t++timestamp;\n\t\t\t\tret += dfs(i);\n\t\t\t}\n\t\t}\n\t\treturn (ret);\n\t}\n};\n\nstruct Lexicographically_Matching : Bipartite_Matching\n{\n\tLexicographically_Matching(int n) : Bipartite_Matching(n) {}\n\n\tint back(int k) // 押し戻す\n\t{\n\t\tmatch[match[k]] = -1;\n\t\tmatch[k] = -1;\n\t\t++timestamp;\n\t\tdfs(k);\n\t\treturn (match[k]);\n\t}\n\n\tvoid decide(int k) // 決める\n\t{\n\t\talive[match[k]] = 0;\n\t\talive[k] = 0;\n\t}\n};\n\nint main(void)\n{\n\tint N;\n\tcin >> N;\n\t--N;\n\tLexicographically_Matching lm(N + N);\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tfor (int j = 0; j < N; ++j)\n\t\t{\n\t\t\tint b;\n\t\t\tcin >> b;\n\t\t\tif (b)\n\t\t\t{\n\t\t\t\tlm.add_edge(j, i + N);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = lm.bipartite_matching();\n\tif (ans < N)\n\t{\n\t\tcout << \"no\\n\";\n\t\treturn 0;\n\t}\n\tcout << \"yes\\n\";\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tif (lm.match[i] >= 0)\n\t\t{\n\t\t\tlm.back(i);\n\t\t\tlm.decide(i);\n\t\t}\n\t}\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tcout << lm.match[i] + 1 - N << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3612, "score_of_the_acc": -0.0591, "final_rank": 12 }, { "submission_id": "aoj_0334_9272440", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\n\nstruct Dinic {\n struct edge {\n int to, rev; ll cap;\n edge(int t, int r, ll c) : to(t), rev(r), cap(c) {}\n };\n int n;\n vii<edge> to;\n vi<int> dist, iter;\n const ll inf = 1e18;\n Dinic(int n_) : n(n_), to(n_), dist(n_), iter(n_) {}\n\n void addedge(int u, int v, ll c) {\n int su = (int)to[u].size();\n int sv = (int)to[v].size();\n to[u].push_back({ v, sv, c });\n to[v].push_back({ u, su, 0 });\n }\n\n void bfs(int s) {\n dist.assign(n, -1);\n dist[s] = 0;\n queue<int> q;\n q.push(s);\n while (!q.empty()) {\n int v = q.front();\n q.pop();\n for (edge& nv : to[v]) {\n if (nv.cap == 0 || dist[nv.to] != -1) continue;\n dist[nv.to] = dist[v] + 1;\n q.push(nv.to);\n }\n }\n }\n\n ll dfs(int v, int t, ll f) {\n if (v == t) return f;\n int sv = (int)to[v].size();\n for (int& i = iter[v]; i < sv; i++) {\n edge& nv = to[v][i];\n if (nv.cap == 0 || dist[nv.to] <= dist[v]) continue;\n ll nf = dfs(nv.to, t, min(f, nv.cap));\n if (nf > 0) {\n nv.cap -= nf;\n to[nv.to][nv.rev].cap += nf;\n return nf;\n }\n }\n return 0;\n }\n\n ll maxflow(int s, int t) {\n ll res = 0, flow = 0;\n while (true) {\n bfs(s);\n if (dist[t] < 0) break;\n iter.assign(n, 0);\n do {\n flow = dfs(s, t, inf);\n res += flow;\n\n } while (flow);\n };\n return res;\n }\n};\n\nint main()\n{ \n int n;\n cin >> n;\n n--;\n vii<int> b(n, vi<int>(n));\n rep(i, n) rep(j, n) cin >> b[i][j];\n vii<int> tb = b;\n\n vi<int> ans(n);\n int S = 2 * n, T = 2 * n + 1;\n rep(j, n) {\n Dinic dn(2 * n + 2);\n rep(k, j) dn.addedge(k, ans[k] + n, 1);\n for (int k = j + 1; k < n; k++) {\n rep(i, n) if(b[i][k]) dn.addedge(k, i + n, 1);\n }\n\n rep(k, n) dn.addedge(S, k, 1);\n rep(i, n) dn.addedge(i + n, T, 1);\n\n int flow = 0;\n rep(i, n) {\n if (b[i][j]) {\n dn.addedge(j, i + n, 1);\n flow += dn.maxflow(S, T);\n if (flow == n) {\n ans[j] = i;\n for(int k = i + 1; k < n; k++) b[i][k] = 0;\n break;\n }\n }\n }\n\n if (flow != n) {\n cout << \"no\" << endl;\n return 0;\n }\n }\n\n\n cout << \"yes\" << endl;\n rep(i, n) cout << ans[i] + 1 << endl;\n //rep(i, n) rep(j, n) cout << tb[ans[i]][j] << \" \\n\"[j == n - 1];\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 5824, "score_of_the_acc": -0.3339, "final_rank": 18 }, { "submission_id": "aoj_0334_5025043", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<vector>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/graph/MCF.cpp\"\n//Minimum Cost Flow O(FE log V)\n#include<algorithm>\n#include<utility>\n#line 5 \"/home/kotatsugame/library/graph/MCF.cpp\"\n#include<queue>\n#include<limits>\ntemplate<typename T>\nstruct MCF{\n\tstruct edge{\n\t\tint to,rev,cap;\n\t\tT cost;\n\t};\n\tvector<vector<edge> >G;\n\tvector<T>h,d;\n\tvector<int>pv,pe;\n\tMCF(int n_=0):G(n_),h(n_,0),d(n_),pv(n_),pe(n_){}\n\tvoid add_edge(int from,int to,int cap,T cost)\n\t{\n\t\tG[from].push_back({to,(int)G[to].size(),cap,cost});\n\t\tG[to].push_back({from,(int)G[from].size()-1,0,-cost});\n\t}\n\tT min_cost_flow(int s,int t,int f)//ans or -1\n\t{\n\t\tT ret=0;\n\t\twhile(f>0)\n\t\t{\n\t\t\tpriority_queue<pair<T,int>,vector<pair<T,int> >,greater<pair<T,int> > >P;\n\t\t\tfill(d.begin(),d.end(),numeric_limits<T>::max());\n\t\t\td[s]=0;\n\t\t\tP.push(make_pair(0,s));\n\t\t\twhile(!P.empty())\n\t\t\t{\n\t\t\t\tpair<T,int>p=P.top();P.pop();\n\t\t\t\tif(d[p.second]<p.first)continue;\n\t\t\t\tfor(int i=0;i<G[p.second].size();i++)\n\t\t\t\t{\n\t\t\t\t\tedge&e=G[p.second][i];\n\t\t\t\t\tif(e.cap>0&&d[e.to]>d[p.second]+e.cost+h[p.second]-h[e.to])\n\t\t\t\t\t{\n\t\t\t\t\t\td[e.to]=d[p.second]+e.cost+h[p.second]-h[e.to];\n\t\t\t\t\t\tpv[e.to]=p.second;\n\t\t\t\t\t\tpe[e.to]=i;\n\t\t\t\t\t\tP.push(make_pair(d[e.to],e.to));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(d[t]==numeric_limits<T>::max())return -1;\n\t\t\tfor(int u=0;u<G.size();u++)h[u]+=d[u];\n\t\t\tint d=f;\n\t\t\tfor(int u=t;u!=s;u=pv[u])d=min(d,G[pv[u]][pe[u]].cap);\n\t\t\tf-=d;\n\t\t\tret+=d*h[t];\n\t\t\tfor(int u=t;u!=s;u=pv[u])\n\t\t\t{\n\t\t\t\tG[pv[u]][pe[u]].cap-=d;\n\t\t\t\tG[u][G[pv[u]][pe[u]].rev].cap+=d;\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n};\n#line 5 \"a.cpp\"\nint N;\nbool exs[500][500];\nbool out[500];\nconst int B=5;\nlong p500[B];\nmain()\n{\n\tp500[0]=1;\n\tfor(int i=1;i<B;i++)p500[i]=p500[i-1]*500;\n\tcin>>N;\n\tfor(int i=0;i<N-1;i++)\n\t{\n\t\tfor(int j=0;j<N-1;j++)\n\t\t{\n\t\t\tint c;cin>>c;\n\t\t\texs[i][j]=c==1;\n\t\t}\n\t}\n\tvector<int>ans;\n\tfor(int tm=0;tm<N-1;tm+=B)\n\t{\n\t\tMCF<long>P(2*N);\n\t\tint st=2*(N-1),go=st+1;\n\t\tfor(int i=0;i<N-1;i++)if(!out[i])\n\t\t{\n\t\t\tP.add_edge(st,i,1,0);\n\t\t\tfor(int j=tm;j<N-1;j++)if(exs[i][j])\n\t\t\t{\n\t\t\t\tP.add_edge(i,N-1+j,1,j<tm+B?i*p500[tm+B-j-1]:0);\n\t\t\t}\n\t\t}\n\t\tfor(int j=tm;j<N-1;j++)P.add_edge(N-1+j,go,1,0);\n\t\tlong ret=P.min_cost_flow(st,go,N-1-tm);\n\t\tif(ret==-1)break;\n\t\tfor(int j=0;j<B&&tm+j<N-1;j++)\n\t\t{\n\t\t\tint id=ret/p500[B-1-j]%500;\n\t\t\tans.push_back(id+1);\n\t\t\tout[id]=true;\n\t\t}\n\t}\n\tif(ans.size()<N-1)cout<<\"no\"<<endl;\n\telse\n\t{\n\t\tcout<<\"yes\"<<endl;\n\t\tfor(int id:ans)cout<<id<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 1150, "memory_kb": 3764, "score_of_the_acc": -1.0614, "final_rank": 19 }, { "submission_id": "aoj_0334_4747500", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Bipartite-Flow(二部グラフのフロー)\n */\nstruct BipartiteFlow {\n size_t n, m, time_stamp;\n vector< vector< int > > graph;\n vector< int > match_l, match_r, dist, used, alive;\n\n explicit BipartiteFlow(size_t n, size_t m) :\n n(n), m(m), graph(n), match_l(n, -1), match_r(m, -1), used(n), alive(n, 1), time_stamp(0) {}\n\n void add_edge(int u, int v) {\n graph[u].push_back(v);\n }\n\n void build_augment_path() {\n queue< int > que;\n dist.assign(graph.size(), -1);\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1) {\n que.emplace(i);\n dist[i] = 0;\n }\n }\n while(!que.empty()) {\n int a = que.front();\n que.pop();\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c >= 0 && dist[c] == -1) {\n dist[c] = dist[a] + 1;\n que.emplace(c);\n }\n }\n }\n }\n\n bool find_min_dist_augment_path(int a) {\n used[a] = time_stamp;\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c < 0 || (used[c] != time_stamp && dist[c] == dist[a] + 1 && find_min_dist_augment_path(c))) {\n match_r[b] = a;\n match_l[a] = b;\n return true;\n }\n }\n return false;\n }\n\n bool find_augment_path(int a) {\n used[a] = time_stamp;\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c < 0 || (alive[c] == 1 && used[c] != time_stamp && find_augment_path(c))) {\n match_r[b] = a;\n match_l[a] = b;\n return true;\n }\n }\n return false;\n }\n\n\n vector< pair< int, int > > max_matching() {\n for(;;) {\n build_augment_path();\n ++time_stamp;\n int flow = 0;\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1) flow += find_min_dist_augment_path(i);\n }\n if(flow == 0) break;\n }\n vector< pair< int, int > > ret;\n for(int i = 0; i < n; i++) {\n if(match_l[i] >= 0) ret.emplace_back(i, match_l[i]);\n }\n return ret;\n }\n\n vector< pair< int, int > > lex_min_max_matching() {\n max_matching();\n vector< pair< int, int > > es;\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1 || alive[i] == 0) {\n continue;\n }\n match_r[match_l[i]] = -1;\n match_l[i] = -1;\n ++time_stamp;\n find_augment_path(i);\n alive[i] = 0;\n es.emplace_back(i, match_l[i]);\n }\n return es;\n }\n};\n\n\nint main() {\n int N;\n cin >> N;\n --N;\n BipartiteFlow flow(N, N);\n for(int i = 0; i < N; i++) {\n for(int j = 0; j < N; j++) {\n int x;\n cin >> x;\n if(x) flow.add_edge(j, i);\n }\n }\n auto v = flow.lex_min_max_matching();\n if(v.size() < N) {\n cout << \"no\\n\";\n } else {\n cout << \"yes\\n\";\n for(auto &p : v) cout << p.second + 1 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3308, "score_of_the_acc": -0.0282, "final_rank": 4 }, { "submission_id": "aoj_0334_4747493", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Bipartite-Graph(二部グラフ)\n * @docs docs/bipartite-graph.md\n */\nstruct BipartiteGraph {\n size_t n, m, time_stamp;\n vector< vector< int > > graph;\n vector< int > match_l, match_r, dist, used, alive;\n\n explicit BipartiteGraph(size_t n, size_t m) :\n n(n), m(m), graph(n), match_l(n, -1), match_r(m, -1), used(n), alive(n, 1), time_stamp(0) {}\n\n void add_edge(int u, int v) {\n graph[u].push_back(v);\n }\n\n void build_augment_path() {\n queue< int > que;\n dist.assign(graph.size(), -1);\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1) {\n que.emplace(i);\n dist[i] = 0;\n }\n }\n while(!que.empty()) {\n int a = que.front();\n que.pop();\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c >= 0 && dist[c] == -1) {\n dist[c] = dist[a] + 1;\n que.emplace(c);\n }\n }\n }\n }\n\n bool find_min_dist_augment_path(int a) {\n used[a] = time_stamp;\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c < 0 || (used[c] != time_stamp && dist[c] == dist[a] + 1 && find_min_dist_augment_path(c))) {\n match_r[b] = a;\n match_l[a] = b;\n return true;\n }\n }\n return false;\n }\n\n bool find_augment_path(int a) {\n used[a] = time_stamp;\n for(auto &b : graph[a]) {\n int c = match_r[b];\n if(c < 0 || (alive[c] == 1 && used[c] != time_stamp && find_augment_path(c))) {\n match_r[b] = a;\n match_l[a] = b;\n return true;\n }\n }\n return false;\n }\n\n\n vector< pair< int, int > > max_matching() {\n for(;;) {\n build_augment_path();\n ++time_stamp;\n int flow = 0;\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1) flow += find_min_dist_augment_path(i);\n }\n if(flow == 0) break;\n }\n vector< pair< int, int > > ret;\n for(int i = 0; i < n; i++) {\n if(match_l[i] >= 0) ret.emplace_back(i, match_l[i]);\n }\n return ret;\n }\n\n vector< pair< int, int > > lex_min_max_matching() {\n max_matching();\n for(auto &vs : graph) sort(begin(vs), end(vs));\n vector< pair< int, int > > es;\n for(int i = 0; i < n; i++) {\n if(match_l[i] == -1 || alive[i] == 0) {\n continue;\n }\n match_r[match_l[i]] = -1;\n match_l[i] = -1;\n ++time_stamp;\n find_augment_path(i);\n alive[i] = 0;\n es.emplace_back(i, match_l[i]);\n }\n return es;\n }\n\n};\n\n\nint main() {\n int N;\n cin >> N;\n --N;\n BipartiteGraph flow(N, N);\n for(int i = 0; i < N; i++) {\n for(int j = 0; j < N; j++) {\n int x;\n cin >> x;\n if(x) flow.add_edge(j, i);\n }\n }\n auto v = flow.lex_min_max_matching();\n if(v.size() < N) {\n cout << \"no\\n\";\n } else {\n cout << \"yes\\n\";\n for(auto &p : v) cout << p.second + 1 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3268, "score_of_the_acc": -0.0253, "final_rank": 2 }, { "submission_id": "aoj_0334_4747365", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Bipartite-Matching(二部グラフの最大マッチング)\n * @docs docs/bipartite-matching.md\n */\nstruct BipartiteMatching {\n vector< vector< int > > graph;\n vector< int > match, alive, used;\n int timestamp;\n\n explicit BipartiteMatching(int n) : graph(n), alive(n, 1), used(n, 0), match(n, -1), timestamp(0) {}\n\n void add_edge(int u, int v) {\n graph[u].push_back(v);\n graph[v].push_back(u);\n }\n\n bool augment(int idx) {\n used[idx] = timestamp;\n for(auto &to : graph[idx]) {\n int to_match = match[to];\n if(alive[to] == 0) continue;\n if(to_match == -1 || (used[to_match] != timestamp && augment(to_match))) {\n match[idx] = to;\n match[to] = idx;\n return true;\n }\n }\n return false;\n }\n\n int bipartite_matching() {\n int ret = 0;\n for(int i = 0; i < (int) graph.size(); i++) {\n if(alive[i] == 0) continue;\n if(match[i] == -1) {\n ++timestamp;\n ret += augment(i);\n }\n }\n return ret;\n }\n\n int add_vertex(int idx) {\n alive[idx] = 1;\n ++timestamp;\n return augment(idx);\n }\n\n int erase_vertex(int idx) {\n alive[idx] = 0;\n if(match[idx] == -1) {\n return 0;\n }\n match[match[idx]] = -1;\n ++timestamp;\n int ret = augment(match[idx]);\n match[idx] = -1;\n return ret - 1;\n }\n\n int lex_min_bipartite_matching() {\n for(auto &vs : graph) {\n sort(begin(vs), end(vs));\n }\n int ret = bipartite_matching();\n for(int i = 0; i < (int) graph.size(); i++) {\n if(alive[i] == 0 || match[i] == -1) {\n continue;\n }\n match[match[i]] = -1;\n match[i] = -1;\n ++timestamp;\n augment(i);\n alive[match[i]] = 0;\n alive[i] = 0;\n }\n return ret;\n }\n\n void output() const {\n for(int i = 0; i < (int) graph.size(); i++) {\n if(i < match[i]) {\n cout << i << \"-\" << match[i] << endl;\n }\n }\n }\n};\n\n\nint main() {\n int N;\n cin >> N;\n --N;\n BipartiteMatching flow(N + N);\n for(int i = 0; i < N; i++) {\n for(int j = 0; j < N; j++) {\n int x;\n cin >> x;\n if(x) flow.add_edge(j, N + i);\n }\n }\n int v = flow.lex_min_bipartite_matching();\n if(v < N) {\n cout << \"no\\n\";\n } else {\n cout << \"yes\\n\";\n for(int i = 0; i < N; i++) {\n cout << flow.match[i] - N + 1 << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3336, "score_of_the_acc": -0.0302, "final_rank": 6 }, { "submission_id": "aoj_0334_4592274", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass Bipartite_Matching {\nprotected:\n vector<vector<int>> G;\n vector<int> used, alive;\n int t;\n int l, r;\npublic:\n vector<int> match;\n explicit Bipartite_Matching(int l, int r): l(l), r(r), t(0), G(l+r), used(l+r, 0), alive(l+r, -1), match(l+r, -1) {};\n\n void add_edge(int a, int b){\n G[a].emplace_back(b+l);\n G[b+l].emplace_back(a);\n }\n\n bool dfs(int x){\n used[x] = t;\n for (auto &&i : G[x]) {\n int w = match[i];\n if(alive[i] == 0) continue;\n if(w == -1 || (used[w] != t && dfs(w))){\n match[x] = i;\n match[i] = x;\n return true;\n }\n }\n return false;\n }\n\n int matching() {\n int ans = 0;\n for (int i = 0; i < G.size(); ++i) {\n if(alive[i] == 0) continue;\n if(match[i] == -1) {\n ++t;\n ans += dfs(i);\n }\n }\n return ans;\n }\n};\n\nclass Bipartite_Matching_LexMin : public Bipartite_Matching {\npublic:\n using Bipartite_Matching::Bipartite_Matching;\n\n int solve_LexMin() {\n int res = matching();\n for (int i = 0; i < l; ++i) {\n if(!~match[i]) continue;\n match[match[i]] = -1;\n match[i] = -1;\n ++t;\n dfs(i);\n alive[match[i]] = 0;\n alive[i] = 0;\n }\n return res;\n }\n};\n\nint main() {\n int n;\n scanf(\"%d\", &n); n--;\n Bipartite_Matching_LexMin G(n, n);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n int x;\n scanf(\"%d\", &x);\n if(x){\n G.add_edge(j, i);\n }\n }\n }\n auto matching = G.solve_LexMin();\n if(matching != n) {\n puts(\"no\");\n return 0;\n }\n puts(\"yes\");\n for (int i = 0; i < n; ++i) {\n printf(\"%d\\n\", G.match[i]-n+1);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3388, "score_of_the_acc": -0.034, "final_rank": 8 }, { "submission_id": "aoj_0334_4092638", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\ntemplate <typename T> using posteriority_queue = priority_queue<T, vector<T>, greater<T> >;\nconst int INF = 0x3f3f3f3f;\nconst ll LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\n// const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\ntemplate <typename T> void unique(vector<T> &a) { a.erase(unique(ALL(a)), a.end()); }\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n }\n} iosetup;\n\nstruct BipartiteMatching {\n vector<int> match;\n\n BipartiteMatching(int n) : n(n), graph(n), match(n, -1), used(n, -1), alive(n, true) {}\n\n void add_edge(int u, int v) {\n graph[u].emplace_back(v);\n graph[v].emplace_back(u);\n }\n\n int solve() {\n int res = 0;\n REP(i, n) {\n if (alive[i] && match[i] == -1) {\n ++timestamp;\n if (dfs(i)) ++res;\n }\n }\n return res;\n }\n\n int push_back(int ver) {\n if (match[ver] != -1) match[match[ver]] = -1;\n match[ver] = -1;\n ++timestamp;\n dfs(ver);\n return match[ver];\n }\n\n void fix(int ver) {\n alive[ver] = false;\n if (match[ver] != -1) alive[match[ver]] = false;\n }\n\n int enable(int ver) {\n if (alive[ver]) return 0;\n alive[ver] = true;\n ++timestamp;\n return dfs(ver) ? 1 : 0;\n }\n\n int disable(int ver) {\n if (!alive[ver]) return 0;\n alive[ver] = false;\n if (match[ver] == -1) return 0;\n match[match[ver]] = -1;\n ++timestamp;\n int tmp = match[ver];\n match[ver] = -1;\n return dfs(tmp) ? 0 : -1;\n }\n\nprivate:\n int n, timestamp = -1;\n vector<vector<int> > graph;\n vector<int> used;\n vector<bool> alive;\n\n bool dfs(int ver) {\n used[ver] = timestamp;\n for (int e : graph[ver]) if (alive[e]) {\n int tmp = match[e];\n if (tmp == -1 || (used[tmp] < timestamp && dfs(tmp))) {\n match[ver] = e;\n match[e] = ver;\n return true;\n }\n }\n return false;\n }\n};\n\nint main() {\n int n; cin >> n; --n;\n BipartiteMatching bm(n << 1);\n REP(i, n) REP(j, n) {\n int b; cin >> b;\n if (b == 1) bm.add_edge(j, n + i);\n }\n if (bm.solve() == n) {\n cout << \"yes\\n\";\n } else {\n cout << \"no\\n\";\n return 0;\n }\n REP(i, n) {\n cout << bm.push_back(i) - n + 1 << '\\n';\n bm.fix(i);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3348, "score_of_the_acc": -0.0311, "final_rank": 7 }, { "submission_id": "aoj_0334_3968389", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing pll=pair<ll,ll>;\nconst ll LINF=0x1fffffffffffffff;\n#define _name3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<(n);++i)\n#define _rep2(i,n) for(ll i=0;i<(n);++i)\n#define _rep3(i,a,b) for(ll i=(a);i<(b);++i)\n#define rep(...) _name3(__VA_ARGS__,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define rrep(i,a,b) for(ll i=(b)-1;i>=(a);i--)\n#define each(i,a) for(auto &i:a)\n#define sum(a) accumulate(range(a),0LL)\n#define range(i) (i).begin(),(i).end()\ntemplate<class T> inline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<class T> inline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\n\nstruct Bipartite_Matching\n{\n vector< vector< int > > graph;\n vector< int > match, alive, used;\n int timestamp;\n \n Bipartite_Matching(int n)\n {\n timestamp = 0;\n graph.resize(n);\n alive.assign(n, 1);\n used.assign(n, 0);\n match.assign(n, -1);\n }\n \n void add_edge(int u, int v)\n {\n graph[u].push_back(v);\n graph[v].push_back(u);\n }\n \n bool dfs(int v)\n {\n used[v] = timestamp;\n for(int i = 0; i < graph[v].size(); i++) {\n int u = graph[v][i], w = match[u];\n if(alive[u] == 0) continue;\n if(w == -1 || (used[w] != timestamp && dfs(w))) {\n match[v] = u;\n match[u] = v;\n return (true);\n }\n }\n return (false);\n }\n \n int bipartite_matching()\n {\n int ret = 0;\n for(int i = 0; i < graph.size(); i++) {\n if(alive[i] == 0) continue;\n if(match[i] == -1) {\n ++timestamp;\n ret += dfs(i);\n }\n }\n return (ret);\n } \n};\nstruct Lexicographically_Matching : Bipartite_Matching\n{\n Lexicographically_Matching(int n) : Bipartite_Matching(n) {}\n\n int back(int k) // 押し戻す\n {\n match[match[k]] = -1;\n match[k] = -1;\n ++timestamp;\n dfs(k);\n return (match[k]);\n }\n\n void decide(int k) // 決める\n {\n alive[match[k]] = 0;\n alive[k] = 0;\n }\n};\nint main() {\n int n;\n cin>>n;\n n--;\n vector<vector<int>>a(n,vector<int>(n));\n each(i,a)each(j,i)cin>>j;\n Lexicographically_Matching match(n*2);\n rep(n)rep(j,n)if(a[i][j])match.add_edge(j,i+n);\n each(i,match.graph)sort(i.begin(),i.end());\n match.bipartite_matching();\n rep(n)if(match.match[i]==-1)return puts(\"no\")&0;\n rep(n){\n match.back(i);\n match.decide(i);\n }\n puts(\"yes\");\n rep(n)cout<<match.match[i]+1-n<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4064, "score_of_the_acc": -0.0919, "final_rank": 16 }, { "submission_id": "aoj_0334_3965129", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nint main() {\n\tint N;\n\tcin >> N; --N;\n\tvector<vector<int> > G(2 * N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tint x;\n\t\t\tcin >> x;\n\t\t\tif (x == 1) {\n\t\t\t\tG[i].push_back(N + j);\n\t\t\t\tG[N + j].push_back(i);\n\t\t\t}\n\t\t}\n\t}\n\tvector<bool> vis, dec(2 * N, false);\n\tvector<int> match(2 * N, -1);\n\tfunction<bool(int)> find_augment = [&](int pos) {\n\t\tvis[pos] = true;\n\t\tfor (int i : G[pos]) {\n\t\t\tif (!dec[i] && (match[i] == -1 || (!vis[match[i]] && find_augment(match[i])))) {\n\t\t\t\tmatch[i] = pos;\n\t\t\t\tmatch[pos] = i;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t};\n\tint cnt = 0;\n\tfor (int i = 2 * N - 1; i >= N; --i) {\n\t\tvis = vector<bool>(2 * N, false);\n\t\tif (match[i] == -1 && find_augment(i)) {\n\t\t\t++cnt;\n\t\t}\n\t}\n\tif (cnt == N) {\n\t\tfor (int i = N; i < 2 * N; ++i) {\n\t\t\tmatch[match[i]] = -1;\n\t\t\tmatch[i] = -1;\n\t\t\tvis = vector<bool>(2 * N, false);\n\t\t\tfind_augment(i);\n\t\t\tdec[match[i]] = true;\n\t\t}\n\t\tcout << \"yes\" << endl;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tcout << match[N + i] + 1 << '\\n';\n\t\t}\n\t}\n\telse {\n\t\tcout << \"no\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3312, "score_of_the_acc": -0.046, "final_rank": 10 }, { "submission_id": "aoj_0334_3813107", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n/*-------------------------------------------------*/\nstruct BipartiteMatching {\n vector<int> match;\n\n BipartiteMatching(int n) : n(n), graph(n), match(n, -1), used(n, -1), alive(n, true) {}\n\n void add_edge(int u, int v) {\n graph[u].emplace_back(v);\n graph[v].emplace_back(u);\n }\n\n int solve() {\n int res = 0;\n REP(i, n) if (alive[i] && match[i] == -1) {\n ++timestamp;\n if (dfs(i)) ++res;\n }\n return res;\n }\n\n int push_back(int ver) {\n match[match[ver]] = -1;\n match[ver] = -1;\n ++timestamp;\n dfs(ver);\n return match[ver];\n }\n\n void fix(int ver) {\n alive[ver] = false;\n if (match[ver] != -1) alive[match[ver]] = false;\n }\n\n int enable(int ver) {\n if (alive[ver]) return 0;\n alive[ver] = true;\n ++timestamp;\n return (dfs(ver) ? 1 : 0);\n }\n\n int disable(int ver) {\n if (!alive[ver]) return 0;\n alive[ver] = false;\n if (match[ver] == -1) return 0;\n match[match[ver]] = -1;\n ++timestamp;\n int tmp = match[ver];\n match[ver] = -1;\n return (dfs(tmp) ? 0 : -1);\n }\n\nprivate:\n int n, timestamp = -1;\n vector<vector<int> > graph;\n vector<int> used;\n vector<bool> alive;\n\n bool dfs(int ver) {\n used[ver] = timestamp;\n for (int e : graph[ver]) if (alive[e]) {\n int tmp = match[e];\n if (tmp == -1 || (used[tmp] < timestamp && dfs(tmp))) {\n match[ver] = e;\n match[e] = ver;\n return true;\n }\n }\n return false;\n }\n};\n\nint main() {\n cin.tie(0); ios::sync_with_stdio(false);\n // freopen(\"input.txt\", \"r\", stdin);\n\n int n; cin >> n; --n;\n BipartiteMatching bm(n * 2);\n REP(i, n) REP(j, n) {\n int b; cin >> b;\n if (b == 1) bm.add_edge(j, n + i);\n }\n if (bm.solve() == n) {\n cout << \"yes\\n\";\n } else {\n cout << \"no\\n\";\n return 0;\n }\n REP(i, n) {\n cout << bm.push_back(i) - n + 1 << '\\n';\n bm.fix(i);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3308, "score_of_the_acc": -0.0282, "final_rank": 4 }, { "submission_id": "aoj_0334_3115706", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 1005\n\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\trev_index = arg_rev_index;\n\t}\n\tint to,capacity,rev_index;\n};\n\nint N;\nint V;\nint rank_index[NUM],component_index[NUM],rev_component[NUM];\nvector<Edge> G[NUM];\nint dist[NUM];\nint cheked_index[NUM];\n\nvoid add_edge(int from,int to,int capacity){\n\tG[from].push_back(Edge(to,capacity,G[to].size()));\n\tG[to].push_back(Edge(from,0,G[from].size()-1));\n}\n\nvoid delete_edge(int from,int index){\n\n\tG[from][index].capacity = 0;\n\tint rev_from = G[from][index].to;\n\n\tint left = 0,right = G[rev_from].size()-1,mid = (left+right)/2;\n\n\twhile(left <= right){\n\n\t\tif(G[rev_from][mid].to == from){\n\n\t\t\tG[rev_from][mid].capacity = 0;\n\t\t\treturn;\n\n\t\t}else if(G[rev_from][mid].to > from){\n\n\t\t\tright = mid-1;\n\n\t\t}else{\n\t\t\tleft = mid+1;\n\t\t}\n\t\tmid = (left+right)/2;\n\t}\n}\n\nvoid bfs(int source){\n\tfor(int i = 0; i < V; i++)dist[i] = -1;\n\tqueue<int> Q;\n\tdist[source] = 0;\n\tQ.push(source);\n\n\twhile(!Q.empty()){\n\t\tint node_id = Q.front();\n\t\tQ.pop();\n\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\tEdge &e = G[node_id][i];\n\t\t\tif(e.capacity > 0 && dist[e.to] < 0){\n\t\t\t\tdist[e.to] = dist[node_id]+1;\n\t\t\t\tQ.push(e.to);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint dfs(int node_id,int sink,int flow){\n\tif(node_id == sink)return flow;\n\n\tfor(int &i = cheked_index[node_id]; i < G[node_id].size(); i++){\n\t\tEdge &e = G[node_id][i];\n\t\tif(e.capacity > 0 && dist[node_id] < dist[e.to]){\n\t\t\tint tmp_flow = dfs(e.to,sink,min(flow,e.capacity));\n\t\t\tif(tmp_flow > 0){\n\t\t\t\te.capacity -= tmp_flow;\n\t\t\t\tG[e.to][e.rev_index].capacity += tmp_flow;\n\t\t\t\treturn tmp_flow;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\n\nint max_flow(int source,int sink){\n\tint flow = 0,add;\n\twhile(true){\n\t\tbfs(source);\n\t\tif(dist[sink] < 0)break;\n\t\tfor(int i = 0; i < V; i++)cheked_index[i] = 0;\n\t\twhile((add = dfs(source,sink,BIG_NUM)) > 0){\n\t\t\tflow += add;\n\t\t}\n\t}\n\treturn flow;\n}\n\nbool find_a_path(int source,int sink){\n\n\tbfs(source);\n\n\tif(dist[sink] < 0){\n\t\treturn false;\n\t}\n\n\tfor(int i = 0; i < V; i++)cheked_index[i] = 0;\n\n\treturn dfs(source,sink,1) == 1;\n}\n\nint main(){\n\n\tscanf(\"%d\",&N);\n\n\tint source = 0,sink = 1;\n\tint index = 2;\n\n\tfor(int i = 0; i <= N-2; i++){\n\n\t\trank_index[i] = index++;\n\t\tadd_edge(source,rank_index[i],1);\n\t}\n\n\tfor(int i = 0; i <= N-2; i++){\n\n\t\tcomponent_index[i] = index++;\n\t\trev_component[component_index[i]] = i;\n\t\tadd_edge(component_index[i],sink,1);\n\t}\n\n\tV = index;\n\n\tint tmp;\n\n\tfor(int i = 0; i <= N-2; i++){\n\t\tfor(int k = 0; k <= N-2; k++){\n\n\t\t\tscanf(\"%d\",&tmp);\n\t\t\tif(tmp == 1){\n\t\t\t\tadd_edge(rank_index[k],component_index[i],1);\n\t\t\t}\n\t\t}\n\t}\n\n\tif(max_flow(source,sink) < N-1){\n\n\t\tprintf(\"no\\n\");\n\t\treturn 0;\n\t}\n\n\tprintf(\"yes\\n\");\n\n\tfor(int rank = rank_index[0]; rank <= rank_index[N-2]; rank++){\n\n\t\tfor(int i = G[rank].size()-1; i >= 0; i--){\n\n\t\t\tif(G[rank][i].capacity == 1){\n\n\t\t\t\tdelete_edge(rank,i);\n\n\t\t\t}else{\n\n\t\t\t\tif(find_a_path(rank,G[rank][i].to)){\n\n\t\t\t\t\tdelete_edge(rank,i);\n\n\t\t\t\t}else{\n\n\t\t\t\t\tprintf(\"%d\\n\",rev_component[G[rank][i].to]+1);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3388, "score_of_the_acc": -0.0428, "final_rank": 9 }, { "submission_id": "aoj_0334_3115694", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 1005\n\nstruct Edge{\n\tEdge(int arg_to,int arg_capacity,int arg_rev_index){\n\t\tto = arg_to;\n\t\tcapacity = arg_capacity;\n\t\trev_index = arg_rev_index;\n\t}\n\tint to,capacity,rev_index;\n};\n\nint N;\nint V;\nint rank_index[NUM],component_index[NUM],rev_component[NUM];\nvector<Edge> G[NUM];\nint dist[NUM];\nint cheked_index[NUM];\n\nvoid add_edge(int from,int to,int capacity){\n\tG[from].push_back(Edge(to,capacity,G[to].size()));\n\tG[to].push_back(Edge(from,0,G[from].size()-1));\n}\n\nvoid delete_edge(int from,int index){\n\n\t//ノーマル辺を消す\n\tG[from][index].capacity = 0;\n\tint rev_from = G[from][index].to;\n\n\t//逆辺を消す\n\tint left = 0,right = G[rev_from].size()-1,mid = (left+right)/2;\n\n\twhile(left <= right){\n\n\t\tif(G[rev_from][mid].to == from){\n\n\t\t\tG[rev_from][mid].capacity = 0;\n\t\t\treturn;\n\n\t\t}else if(G[rev_from][mid].to > from){\n\n\t\t\tright = mid-1;\n\n\t\t}else{\n\t\t\tleft = mid+1;\n\t\t}\n\t\tmid = (left+right)/2;\n\t}\n}\n\n//sourceからの最短距離をBFSで計算する\nvoid bfs(int source){\n\tfor(int i = 0; i < V; i++)dist[i] = -1;\n\tqueue<int> Q;\n\tdist[source] = 0;\n\tQ.push(source);\n\n\twhile(!Q.empty()){\n\t\tint node_id = Q.front();\n\t\tQ.pop();\n\t\tfor(int i = 0; i < G[node_id].size(); i++){\n\t\t\tEdge &e = G[node_id][i];\n\t\t\tif(e.capacity > 0 && dist[e.to] < 0){ //辺の容量が正で、かつエッジの行先に未訪問の場合\n\t\t\t\tdist[e.to] = dist[node_id]+1;\n\t\t\t\tQ.push(e.to);\n\t\t\t}\n\t\t}\n\t}\n}\n\n//増加パスをDFSで探す\nint dfs(int node_id,int sink,int flow){\n\tif(node_id == sink)return flow; //終点についたらflowをreturn\n\n\tfor(int &i = cheked_index[node_id]; i < G[node_id].size(); i++){ //node_idから出ているエッジを調査\n\t\tEdge &e = G[node_id][i];\n\t\tif(e.capacity > 0 && dist[node_id] < dist[e.to]){ //流せる余裕があり、かつsourceからの距離が増加する方法である場合\n\t\t\tint tmp_flow = dfs(e.to,sink,min(flow,e.capacity)); //流せるだけ流す\n\t\t\tif(tmp_flow > 0){ //流せた場合\n\t\t\t\te.capacity -= tmp_flow; //流した分、エッジの容量を削減する\n\t\t\t\tG[e.to][e.rev_index].capacity += tmp_flow; //逆辺の容量を、流した分だけ増加させる\n\t\t\t\treturn tmp_flow;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n\n\n//sourceからsinkへの最大流を求める\nint max_flow(int source,int sink){ //source:始点 sink:終点\n\tint flow = 0,add;\n\twhile(true){ //増加パスが存在する限り、流量を追加し続ける\n\t\tbfs(source);\n\t\tif(dist[sink] < 0)break; //sourceからsinkへと辿り着く残余グラフがない、つまり増加パスが無くなった場合、break\n\t\tfor(int i = 0; i < V; i++)cheked_index[i] = 0;\n\t\twhile((add = dfs(source,sink,BIG_NUM)) > 0){ //増加パスが見つかる間、加算\n\t\t\tflow += add;\n\t\t}\n\t}\n\treturn flow;\n}\n\nbool find_a_path(int source,int sink){ //sourceからsinkへの増加パスがあるか調べる\n\n\tbfs(source);\n\n\tif(dist[sink] < 0){\n\t\treturn false;\n\t}\n\n\tfor(int i = 0; i < V; i++)cheked_index[i] = 0;\n\n\treturn dfs(source,sink,1) == 1;\n}\n\nint main(){\n\n\tscanf(\"%d\",&N);\n\n\tint source = 0,sink = 1;\n\tint index = 2;\n\n\t//上からの順番ノードのインデックス\n\tfor(int i = 0; i <= N-2; i++){\n\t\t//★0オリジンにおいて(N-2)→(N-1)が最後の移動なので、iはN-2までで良い\n\t\trank_index[i] = index++;\n\t\tadd_edge(source,rank_index[i],1); //sourceから\n\t}\n\n\t//2部マッチング用の、部品ノードのインデックス\n\tfor(int i = 0; i <= N-2; i++){\n\n\t\tcomponent_index[i] = index++;\n\t\trev_component[component_index[i]] = i; //逆引き表\n\t\tadd_edge(component_index[i],sink,1);\n\t}\n\n\tV = index;\n\n\tint tmp;\n\n\tfor(int i = 0; i <= N-2; i++){ //部品のループ\n\t\tfor(int k = 0; k <= N-2; k++){ //棒のループ\n\n\t\t\tscanf(\"%d\",&tmp);\n\t\t\tif(tmp == 1){ //位置kから、k+1に移動できるなら、順番ノードと部品を紐づける\n\t\t\t\tadd_edge(rank_index[k],component_index[i],1);\n\t\t\t}\n\t\t}\n\t}\n\n\tif(max_flow(source,sink) < N-1){ //そもそも0→N-1に移動できないなら不可\n\n\t\tprintf(\"no\\n\");\n\t\treturn 0;\n\t}\n\n\tprintf(\"yes\\n\");\n\n\tfor(int rank = rank_index[0]; rank <= rank_index[N-2]; rank++){\n\t//for(int rank = rank_index[0]; rank <= rank_index[0]; rank++){\n\t\t//番号の大きい部品から、降順に見ていく\n\t\tfor(int i = G[rank].size()-1; i >= 0; i--){\n\n\t\t\tif(G[rank][i].capacity == 1){ //エッジに流れていない場合\n\n\t\t\t\tdelete_edge(rank,i); //流れないように、辺を論理削除\n\n\t\t\t}else{ //エッジに流れている場合\n\n\t\t\t\t//★残余グラフ上で別の経路がないか試す★\n\t\t\t\tif(find_a_path(rank,G[rank][i].to)){\n\n\t\t\t\t\t/*\n\t\t\t\t\t * ★source→rank,\n\t\t\t\t\t * G[rank][i].to→sinkの状況は変わらずに、\n\t\t\t\t\t * rank→G[rank][i].toの経路が変わっただけなので、\n\t\t\t\t\t * エッジiを論理削除すれば流量は変わらない\n\t\t\t\t\t *\n\t\t\t\t\t * */\n\t\t\t\t\tdelete_edge(rank,i); //より小さい番号の部品とマッチできるので、辺を論理削除\n\n\t\t\t\t}else{ //流せない:辺確定\n\n\t\t\t\t\tprintf(\"%d\\n\",rev_component[G[rank][i].to]+1);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3492, "score_of_the_acc": -0.0504, "final_rank": 11 }, { "submission_id": "aoj_0334_3064785", "code_snippet": "#include <stdio.h>\n#include <bitset>\n#include <vector>\nusing namespace std;\n#define PB push_back\nconst int N=5e2+10;\nvector<int> back[N],graph[N];\nbitset<N> went,used;\nint con[N],to[N];\nbool dfs(int now){\n went[now]=true;\n for(int i:graph[now])if(con[i]==-1||(!used[con[i]]&&!went[con[i]]&&dfs(con[i]))){\n con[i]=now;\n to[now]=i;\n return true;\n }\n return false;\n}\nint main(){\n int n,temp;\n scanf(\"%d\",&n);\n for(int i=1;i<n;i++){\n con[i]=-1;\n for(int j=1;j<n;j++){\n scanf(\"%d\",&temp);\n if(temp==1){\n graph[i].PB(j);\n back[j].PB(i);\n }\n }\n }\n for(int i=1;i<n;i++){\n went.reset();\n if(!dfs(i)){\n printf(\"no\\n\");\n return 0;\n }\n }\n used.reset();\n printf(\"yes\\n\");\n for(int i=1;i<n;i++){\n for(int j:back[i])if(!used[j]){\n if(j>=con[i])break;\n went.reset();\n went[j]=true;\n temp=con[i];\n con[i]=j;\n con[to[j]]=-1;\n if(dfs(temp))break;\n con[i]=temp;\n con[to[j]]=j;\n }\n used[con[i]]=true;\n printf(\"%d\\n\",con[i]);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2920, "score_of_the_acc": -0.0088, "final_rank": 1 }, { "submission_id": "aoj_0334_2591498", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <cmath>\n#include <iomanip>\n#include <cassert>\n#include <bitset>\nusing namespace std;\n\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i=0; i<(n); i++)\n#define all(c) (c).begin(), (c).end()\n#define uniq(c) c.erase(unique(all(c)), (c).end())\n#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())\n#define _1 first\n#define _2 second\n#define pb push_back\n#define INF 1145141919\n#define MOD 1000000007\n\nstruct Bipartite_Matching {\n vector< vector< int > > G;\n vector< int > match, alive, used;\n int timestamp;\n\n Bipartite_Matching(int n) {\n timestamp = 0;\n G.resize(n);\n alive.assign(n, 1);\n used.assign(n, 0);\n match.assign(n, -1);\n }\n\n void add_edge(int u, int v) {\n G[u].push_back(v);\n G[v].push_back(u);\n }\n\n bool dfs(int v) {\n used[v] = timestamp;\n for (int u : G[v]) {\n int w = match[u];\n if(alive[u] == 0) continue;\n if(w == -1 || (used[w] != timestamp && dfs(w))) {\n match[v] = u;\n match[u] = v;\n return true;\n }\n }\n return false;\n }\n\n int bipartite_matching() {\n int ret = 0;\n rep(i, G.size()) {\n if(alive[i] == 0) continue;\n if(match[i] == -1) {\n ++timestamp;\n ret += dfs(i);\n }\n }\n return ret;\n }\n};\n\nstruct Lexicographically_Matching : Bipartite_Matching {\n Lexicographically_Matching(int n) : Bipartite_Matching(n) {}\n\n int back(int k) {\n match[match[k]] = -1;\n match[k] = -1;\n ++timestamp;\n dfs(k);\n return match[k];\n }\n\n void decide(int k) {\n alive[match[k]] = 0;\n alive[k] = 0;\n }\n};\n\n\nint N;\nsigned main() {\n ios::sync_with_stdio(false); cin.tie(0);\n cin >> N;\n Lexicographically_Matching bip((N-1)*2);\n rep(i, N-1) {\n rep(j, N-1) {\n int x;\n cin >> x;\n if (x) bip.add_edge(i, j+N-1);\n }\n }\n if (bip.bipartite_matching() < N-1) {\n cout << \"no\\n\";\n return 0;\n }\n cout << \"yes\\n\";\n rep(i, N-1) {\n bip.decide(bip.back(i+N-1));\n cout << bip.match[i+N-1]+1 << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3268, "score_of_the_acc": -0.0253, "final_rank": 2 }, { "submission_id": "aoj_0334_2584369", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#define _USE_MATH_DEFINES\n#include <math.h>\n#include <cstring>\n#include <numeric>\n#include <algorithm>\n#include <stdlib.h>\n#include <functional>\n#include <string>\n#include <array>\n#include <map>\n#include <queue>\n#include <limits.h>\n#include <set>\n#include <stack>\n#include <random>\n#include <complex>\n#include <unordered_map>\n#include <nmmintrin.h>\n#include <chrono>\nconst double EPS = 1e-8;\n#define Scan(a) int a;scanf(\"%d\", &a);\n#define ScanS(a) char a[500];scanf(\"%s\", a);\n#define rep(i,s,n) for(int i = (s); (n) > i; i++)\n#define REP(i,n) rep(i,0,n)\n#define RANGE(x,a,b) ((a) <= (x) && (x) <= (b))\n#define DUPLE(a,b,c,d) (RANGE(a,c,d) || RANGE(b,c,d) || RANGE(c,a,b) || RANGE(d,a,b))\n#define INCLU(a,b,c,d) (RANGE(a,c,d) && (b,c,d))\n#define PW(x) ((x)*(x))\n#define ALL(x) (x).begin(), (x).end()\n#define MODU 1000000007\n#define bitcheck(a,b) ((a >> b) & 1LL)\n#define bitset(a,b) ( a |= (1LL << b))\n#define bitunset(a,b) (a &= ~(1LL << b))\n#define MP(a,b) make_pair((a),(b))\n#define Manh(a,b) (abs((a).first-(b).first) + abs((a).second - ((b).second))\n#define pritnf printf\n#define scnaf scanf\n#define itn int\n#ifdef _MSC_VER\n#define __builtin_popcount _mm_popcnt_u32\n#define __builtin_popcountll _mm_popcnt_u64\n#endif\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll gcd(ll a, ll b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a%b);\n}\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N], const T &val) {\n\tstd::fill((T*)array, (T*)(array + N), val);\n}\n\nint gcd(int a, int b) {\n\tif (b == 0) return a;\n\treturn gcd(b, a%b);\n}\npii Dir[8] = {\n\t{ 0 ,1 },{ -1 ,0 },{ 1 ,0 },{ 0 ,-1 },\n\t{ 1 ,1 },{ 1 ,-1 },{ -1 ,1 },{ -1 ,-1 }\n};\n\n\npii operator+(pii obj, pii obj2) {\n\treturn MP(obj.first + obj2.first, obj.second + obj2.second);\n}\npii operator-(pii obj, pii obj2) {\n\treturn MP(obj.first - obj2.first, obj.second - obj2.second);\n}\nclass Graph {\npublic:\n\tint vn;\n\tint sumcost = 0;\n\tvector<vector<pii>> g;\n\n\tGraph(int n) {\n\t\tvn = n;\n\t\tg.resize(n);\n\t}\n\tvirtual void con(int a, int b, int w) = 0;\n\tint getWeight(int f, int t) {\n\t\tauto itr = lower_bound(ALL(g[f]), make_pair(t, INT_MIN));\n\t\tif (itr != g[f].end())\n\t\t\treturn itr->second;\n\t\treturn INT_MIN;\n\t}\n\tint Costsum() {\n\t\treturn sumcost;\n\t}\n\tvoid scan(int edcount, bool oindexed, bool w) {\n\t\tREP(i, edcount) {\n\t\t\tint a, b, c = 1;\n\t\t\tscanf(\"%d %d\", &a, &b);\n\t\t\tif (w)scanf(\"%d\", &c);\n\t\t\tcon(a - oindexed, b - oindexed, c);\n\t\t}\n\t}\n};\nclass BiDGraph : public Graph {//??????\npublic:\n\tBiDGraph(int n) : Graph(n) {}\n\n\tvoid con(int a, int b, int w = 1) {\n\t\tg[a].push_back({ b,w });\n\t\tg[b].push_back({ a, w });\n\t\tsumcost++;\n\t}\n};\nclass DGraph : public Graph {//??????\npublic:\n\tDGraph(int n) : Graph(n) {}\n\tvoid con(int a, int b, int w = 1) {\n\t\tg[a].push_back({ b,w });\n\t\tsumcost++;\n\t}\n};\n\n\nclass RGraph {//????????°??????\n\tstruct edge{\n\t\tint to, cap = 0, rev;\n\t\tbool isrev;\n\t};\npublic:\n\tint sumflow = 0;\n\n\tvector<vector<edge>> g;\n\n\tRGraph(DGraph dg) : g(dg.g.size()){\n\t\tREP(i, dg.g.size()) {\n\t\t\tfor (auto itr : dg.g[i]) {\n\t\t\t\tg[i].push_back({ itr.first, itr.second, (int)g[itr.first].size(), 0});\n\t\t\t\tg[itr.first].push_back({ i, 0, (int)g[i].size() - 1, 1});\n\t\t\t}\n\t\t}\n\t}\n\n\tvoid flow(edge& eg, int rate) {\n\t\teg.cap -= rate;\n\t\tg[eg.to][eg.rev].cap += rate;\n\t}\n\n};\n\nRGraph FordFurkerson(DGraph g, int st, int en) {\n\t\n\tRGraph rg(g);\n\n\tvector<bool> used(g.g.size());\n\n\tfunction<int(int, int, int)> dfs = [&](int c, int p, int Min) {\n\t\tif (c == en) return Min;\n\t\tif (used[c]) return -1;\n\t\tused[c] = true;\n\n\t\tfor (auto& itr : rg.g[c]) {\n\t\t\tif (itr.cap > 0) {\n\t\t\t\tint ret = dfs(itr.to, c, min(Min, itr.cap));\n\t\t\t\tif (ret != -1) {\n\t\t\t\t\trg.flow(itr, ret);\n\t\t\t\t\treturn ret;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\treturn -1;\n\t};\n\n\twhile (int zo = dfs(st, -1, INT_MAX) != -1) {\n\t\tfill(ALL(used), 0);\n\t\trg.sumflow += zo;\n\t}\n\n\treturn rg;\n}\n\nvector<int> BiMaxmatching(DGraph g, int scount, bool lexi = 0) { // scount????????????????????´??§???g???????????????scount???\n\t\n\tg.g.push_back(vector<pii>());\n\tg.g.push_back(vector<pii>());\n\n\tREP(i, scount) {\n\t\tg.con(g.g.size() - 2, i);\n\t}\n\trep(i, scount, g.g.size() - 2) {\n\t\tg.con(i, g.g.size() - 1);\n\t}\n\n\tRGraph rg(FordFurkerson(g, g.g.size() - 2, g.g.size() - 1));\n\n\tvector<int> ans(scount, -1);\n\n\tif (lexi) {\n\t\tvector<bool> used(g.g.size()), alive(g.g.size(), 1);\n\n\t\tfunction<int(int, int, int)> dfs = [&](int c, int p, int Min) {\n\t\t\tif (c == g.g.size() - 1) return Min;\n\t\t\tif (used[c]) return -1;\n\t\t\tif (!alive[c]) return -1;\n\t\t\tused[c] = true;\n\n\t\t\tfor (auto& itr : rg.g[c]) {\n\t\t\t\tif (itr.cap > 0) {\n\t\t\t\t\tint ret = dfs(itr.to, c, min(Min, itr.cap));\n\t\t\t\t\tif (ret != -1) {\n\t\t\t\t\t\trg.flow(itr, ret);\n\t\t\t\t\t\treturn ret;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\treturn -1;\n\t\t};\n\n\t\tREP(i, scount) {\n\t\t\trg.flow(rg.g[g.g.size() - 2][i], -1);\n\t\t\tfor (auto& itr : rg.g[i]) {\n\t\t\t\tif (!itr.isrev && !itr.cap) {\n\t\t\t\t\trg.flow(itr, -1);\n\t\t\t\t\tfor (auto& itr2 : rg.g[itr.to]) {\n\t\t\t\t\t\tif (itr2.to == g.g.size() - 1)\n\t\t\t\t\t\t\trg.flow(itr2, -1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tdfs(g.g.size() - 2, -1, INT_MAX);\n\n\t\t\talive[i] = 0;\n\t\t\tfor (auto itr : rg.g[i]) {\n\t\t\t\tif (!itr.isrev && !itr.cap) {\n\t\t\t\t\talive[itr.to] = 0;\n\t\t\t\t\tans[i] = itr.to;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tfill(ALL(used), 0);\n\t\t}\n\n\t}\n\telse {\n\t\tREP(i, scount) {\n\t\t\tfor (auto itr : rg.g[i]) {\n\t\t\t\tif (!itr.isrev && !itr.cap) {\n\t\t\t\t\tans[i] = itr.to;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\n\nint main() {\n\tint n;\n\n\tcin >> n;\n\n\tDGraph g(n * 2 - 2);\n\n\tREP(i, n - 1) {\n\t\tREP(j, n - 1) {\n\t\t\tint a;\n\t\t\tscanf(\"%d\", &a);\n\t\t\tif (a)\n\t\t\t\tg.con(j, i + n - 1);\n\t\t}\n\t}\n\n\n\tvector<int> ans(BiMaxmatching(g, n-1,true));\n\t\n\tfor(auto itr : ans)\n\t\tif (itr == -1) {\n\t\t\tcout << \"no\" << endl;\n\t\t\treturn 0;\n\t\t}\n\n\tcout << \"yes\" << endl;\n\tfor (auto itr : ans)\n\t\tprintf(\"%d\\n\", itr - n + 2);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3884, "score_of_the_acc": -0.0789, "final_rank": 13 }, { "submission_id": "aoj_0334_2491582", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n#ifdef _DEBUG\n#include \"dump.hpp\"\n#else\n#define dump(...)\n#endif\n\n//#define int long long\n#define rep(i,a,b) for(int i=(a);i<(b);i++)\n#define rrep(i,a,b) for(int i=(b)-1;i>=(a);i--)\n#define all(c) begin(c),end(c)\nconst int INF = sizeof(int) == sizeof(long long) ? 0x3f3f3f3f3f3f3f3fLL : 0x3f3f3f3f;\nconst int MOD = (int)(1e9) + 7;\ntemplate<class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (b < a) { a = b; return true; } return false; }\n\nstruct HopcroftKarp {\n\tint n;\n\tvector<vector<int>> g;\n\tvector<int> match, dist;\n\tvector<bool> used, alive;\n\tHopcroftKarp(int n) : n(n), g(n), match(n), dist(n), used(n), alive(n, true) {}\n\tvoid addEdge(int u, int v) {\n\t\tg[u].emplace_back(v);\n\t\tg[v].emplace_back(u);\n\t}\n\tint maximumMatching() {\n\t\tint cnt = 0;\n\t\tfill(match.begin(), match.end(), -1);\n\t\twhile (true) {\n\t\t\tbuildAlternatingLevelGraph();\n\t\t\tfill(used.begin(), used.end(), false);\n\t\t\tint flow = 0;\n\t\t\tfor (int u = 0; u < n; u++) {\n\t\t\t\tif (!alive[u])continue;\n\t\t\t\tif (match[u] == -1 && augment(u))\n\t\t\t\t\tflow++;\n\t\t\t}\n\t\t\tif (flow == 0)break;\n\t\t\tcnt += flow;\n\t\t}\n\t\treturn cnt;\n\t}\n\tvoid buildAlternatingLevelGraph() {\n\t\tfill(dist.begin(), dist.end(), -1);\n\t\tqueue<int> q;\n\t\tfor (int u = 0; u < n; u++)\n\t\t\tif (match[u] == -1) {\n\t\t\t\tq.emplace(u);\n\t\t\t\tdist[u] = 0;\n\t\t\t}\n\t\twhile (q.size()) {\n\t\t\tint u = q.front(); q.pop();\n\t\t\tfor (int v : g[u]) {\n\t\t\t\tint w = match[v];\n\t\t\t\tif (w != -1 && dist[w] == -1) {\n\t\t\t\t\tdist[w] = dist[u] + 1;\n\t\t\t\t\tq.emplace(w);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t};\n\tbool augment(int u) {\n\t\tused[u] = true;\n\t\tfor (int v : g[u]) {\n\t\t\tif (!alive[v])continue;\n\t\t\tint w = match[v];\n\t\t\tif (w == -1 || (!used[w] && dist[w] == dist[u] + 1 && augment(w))) {\n\t\t\t\tmatch[u] = v;\n\t\t\t\tmatch[v] = u;\n\t\t\t\tused[v] = true;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n};\n\n\nstruct LexicographicallyBipartiteMatching :HopcroftKarp {\n\tLexicographicallyBipartiteMatching(int n) :HopcroftKarp(n) {}\n\tint maximumMatching() {\n\t\tfor (int v = 0; v < n; v++)\n\t\t\tsort(g[v].begin(), g[v].end());\n\t\tint cnt = HopcroftKarp::maximumMatching();\n\t\tfor (int v = 0; v < n; v++) {\n\t\t\tif (!alive[v] || match[v] == -1)continue;\n\t\t\tmatch[match[v]] = -1;\n\t\t\tmatch[v] = -1;\n\t\t\tfill(used.begin(), used.end(), false);\n\t\t\taugment(v);\n\t\t\talive[match[v]] = 0;\n\t\t\talive[v] = 0;\n\t\t}\n\t\treturn cnt;\n\t}\n\tbool augment(int u) {\n\t\tused[u] = true;\n\t\tfor (int v : g[u]) {\n\t\t\tif (!alive[v])continue;\n\t\t\tint w = match[v];\n\t\t\tif (w == -1 || (!used[w] && augment(w))) {\n\t\t\t\tmatch[u] = v;\n\t\t\t\tmatch[v] = u;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n};\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint N; cin >> N; N--;\n\tvector<vector<int>> b(N, vector<int>(N));\n\trep(v, 0, N) rep(u, 0, N) { cin >> b[v][u]; }\n\n\tLexicographicallyBipartiteMatching lbm(N + N);\n\trep(v, 0, N)rep(u, 0, N) {\n\t\tif (b[v][u])\n\t\t\tlbm.addEdge(u, N + v);\n\t}\n\tint res = lbm.maximumMatching();\n\tdump(res);\n\tif (res == N) {\n\t\tcout << \"yes\" << endl;\n\t\trep(v, 0, N) {\n\t\t\tcout << lbm.match[v] - N + 1 << endl;\n\t\t}\n\t}\n\telse {\n\t\tcout << \"no\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4128, "score_of_the_acc": -0.0878, "final_rank": 14 }, { "submission_id": "aoj_0334_2489900", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n#ifdef _DEBUG\n#include \"dump.hpp\"\n#else\n#define dump(...)\n#endif\n\n//#define int long long\n#define rep(v,a,b) for(int v=(a);v<(b);v++)\n#define rrep(v,a,b) for(int v=(b)-1;v>=(a);v--)\n#define all(c) begin(c),end(c)\nconst int INF = sizeof(int) == sizeof(long long) ? 0x3f3f3f3f3f3f3f3fLL : 0x3f3f3f3f;\nconst int MOD = (int)(1e9) + 7;\ntemplate<class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (b < a) { a = b; return true; } return false; }\n\nstruct BipartiteMatching {\n\tint n;\n\tvector<vector<int>> g;\n\tvector<int> match;\n\tvector<bool> used, alive;\n\tBipartiteMatching(int n) : n(n), g(n), match(n), used(n), alive(n, true) {}\n\tvoid addEdge(int u, int v) {\n\t\tg[u].emplace_back(v);\n\t\tg[v].emplace_back(u);\n\t}\n\tint maximumMatching() {\n\t\tint cnt = 0;\n\t\tfill(match.begin(), match.end(), -1);\n\t\tfor (int v = 0; v < n; v++) {\n\t\t\tif (!alive[v])continue;\n\t\t\tif (match[v] == -1) {\n\t\t\t\tfill(used.begin(), used.end(), false);\n\t\t\t\tif (augment(v))cnt++;\n\t\t\t}\n\t\t}\n\t\treturn cnt;\n\t}\n\tbool augment(int v) {\n\t\tused[v] = true;\n\t\tfor (int u : g[v]) {\n\t\t\tif (!alive[u])continue;\n\t\t\tint w = match[u];\n\t\t\tif (w == -1 || (!used[w] && augment(w))) {\n\t\t\t\tmatch[v] = u;\n\t\t\t\tmatch[u] = v;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n\t\treturn false;\n\t}\n};\n\nstruct LexicographicallyBipartiteMatching :BipartiteMatching {\n\tLexicographicallyBipartiteMatching(int n) :BipartiteMatching(n) {}\n\tint maximumMatching() {\n\t\tfor (int v = 0; v < n; v++)\n\t\t\tsort(g[v].begin(), g[v].end());\n\t\tint cnt = BipartiteMatching::maximumMatching();\n\t\tfor (int v = 0; v < n; v++) {\n\t\t\tif (!alive[v] || match[v] == -1)continue;\n\t\t\tmatch[match[v]] = -1;\n\t\t\tmatch[v] = -1;\n\t\t\tfill(used.begin(), used.end(), false);\n\t\t\taugment(v);\n\t\t\talive[match[v]] = 0;\n\t\t\talive[v] = 0;\n\t\t}\n\t\treturn cnt;\n\t}\n};\n\nsigned main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint N; cin >> N; N--;\n\tvector<vector<int>> b(N, vector<int>(N));\n\trep(v, 0, N) rep(u, 0, N) { cin >> b[v][u]; }\n\n\tLexicographicallyBipartiteMatching lbm(N + N);\n\trep(v, 0, N)rep(u, 0, N) {\n\t\tif (b[v][u])\n\t\t\tlbm.addEdge(u, N + v);\n\t}\n\tint res = lbm.maximumMatching();\n\tdump(res);\n\tif (res == N) {\n\t\tcout << \"yes\" << endl;\n\t\trep(v, 0, N) {\n\t\t\tcout << lbm.match[v] - N + 1 << endl;\n\t\t}\n\t}\n\telse {\n\t\tcout << \"no\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4144, "score_of_the_acc": -0.089, "final_rank": 15 }, { "submission_id": "aoj_0334_2415555", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<queue>\n#include<cassert>\nusing namespace std;\n\n#define INF (1<<30)\n#define MAX 1000\n \nclass Edge{\npublic:\n int to, rev, cap, flow;\n Edge(int to=0, int rev=0, int cap=0, int flow=0):to(to), rev(rev), cap(cap), flow(flow){}\n};\n \nint V;\nvector<Edge> G[MAX];\n\nint N;\nint P[MAX][MAX];\n \nvoid connect( int source, int target, int cap ){\n G[source].push_back(Edge(target, G[target].size(), cap, 0));\n G[target].push_back(Edge(source, G[source].size()-1, 0, 0));\n}\n \nbool bfs(pair<int, int> pi[], int source, int target ){\n bool visited[MAX];\n queue<int> Q;\n \n for ( int i = 0; i < V; i++ ) {\n visited[i] = false;\n pi[i] = make_pair(-1, -1);\n }\n \n int u, v;\n Q.push( source );\n visited[source] = true;\n \n while( !Q.empty() ){\n u = Q.front(); Q.pop();\n if ( u == target ) return true;\n for( int i = 0; i < G[u].size(); i++ ){\n int v = G[u][i].to;\n if ( visited[v] ) continue;\n if ( G[u][i].cap > G[u][i].flow ){\n\tpi[v] = make_pair(u, i);\n\tvisited[v] = true;\n\tQ.push(v);\n }\n }\n }\n return false;\n}\n \nint edmonds_karp(int source, int target ){\n int flow;\n pair<int, int> pi[MAX]; //pre, to index\n \n while ( bfs(pi, source, target ) ){\n flow = INF;\n for ( int v = target; v != source; v = pi[v].first ){\n int u = pi[v].first;\n int idx = pi[v].second;\n flow = min(flow, G[u][idx].cap - G[u][idx].flow);\n }\n for ( int v = target; v != source; v = pi[v].first ){\n int u = pi[v].first;\n int idx = pi[v].second;\n int rev = G[u][idx].rev;\n G[u][idx].flow += flow;\n G[v][rev].flow = -G[u][idx].flow;\n }\n }\n \n flow = 0;\n for ( int i = 0; i < G[source].size(); i++ ) flow += G[source][i].flow;\n \n return flow;\n}\n\n\nvoid solve(){\n for ( int i = 0; i < V; i++ ) G[i].clear();\n\n for ( int i = 0; i < N; i++ ){\n connect(0, i+1, 1);\n }\n for ( int i = 0; i < N; i++ ){\n for ( int j = 0; j < N; j++ ){\n if ( P[j][i] == 1 ){\n\tconnect(i+1, N+1+j, P[j][i]);\n }\n }\n }\n for ( int i = 0; i < N; i++ ){\n connect(N+1+i, V-1, 1);\n }\n\n int f = edmonds_karp(0, V - 1);\n if ( f != N ){\n cout << \"no\" << endl; return;\n }\n cout << \"yes\" << endl;\n\n pair<int, int> pi[MAX]; //pre, to index\n\n for ( int i = 1; i <= N; i++ ){\n //for ( int j = N-1; j >= 0; j-- ){\n for ( int j = G[i].size()-1; j >= 1; j-- ){ // j = 0, rev of i\n // int s = i+1;\n // int t = j+N+1;\n int s = i;\n int t = G[i][j].to;\n if ( G[s][j].flow == 0 ) {\n\tG[s][j].cap = 0;\n\t// not use\n } else {\n\tassert(G[s][j].flow == 1 );\n\tG[s][j].cap = 0;\n\tG[s][j].flow = 0;\n\tG[G[s][j].to][G[s][j].rev] = 0;\n\tif ( bfs(pi, s, t) ){\n\t int flow = 1;\n\t for ( int v = t; v != s; v = pi[v].first ){\n\t int u = pi[v].first;\n\t int idx = pi[v].second;\n\t int rev = G[u][idx].rev;\n\t G[u][idx].flow += flow;\n\t G[v][rev].flow = -G[u][idx].flow;\n\t }\n\t // not use\n\t} else {\n\t G[s][j].cap = 1;\n\t G[s][j].flow = 1;\n\t G[G[s][j].to][G[s][j].rev] = -1;\n\t cout << t-N << endl;\n\t // use\n\t}\n }\n }\n }\n}\n\nint main(){\n // cin >> N;\n scanf(\"%d\", &N);\n N--;\n V = 2*N + 2;\n for ( int i = 0; i < N; i++ ){\n for ( int j = 0; j < N; j++ ){\n // cin >> P[i][j]; \n scanf(\"%d\", &P[i][j]);\n\n }\n }\n solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5492, "score_of_the_acc": -0.2045, "final_rank": 17 }, { "submission_id": "aoj_0334_2252368", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(auto i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\n\n\n\ntypedef vector<int> Weight;\ntypedef int Cap;\nconst Weight W_INF = vector<int>(1000,100000000);\nconst Weight W_ZERO = vector<int>(1000, 0);\nconst Cap C_INF= INT_MAX;\nconst Cap C_ZERO = 0;\n\nstruct Edge {\n\tint src, dst;\n\tCap capacity;\n\tWeight cost;\n\tEdge(int src, int dst, const Cap& acap, const Weight& acost) :\n\t\tsrc(src), dst(dst), capacity(acap), cost(acost) {\n\t}\n};\nWeight operator-(const Weight&w) {\n\tWeight aw(w);\n\tfor (auto&a : aw) {\n\t\ta = -a;\n\t}\n\treturn aw;\n}\nWeight operator+(const Weight&l, const Weight&r) {\n\tWeight aw(l);\n\tfor (int i = 0; i < aw.size(); ++i) {\n\t\taw[i] += r[i];\n\t}\n\treturn aw;\n}\nWeight operator-(const Weight&l, const Weight&r) {\n\treturn l + (-r);\n}\nWeight operator*(const Weight&w, const Cap&c) {\n\tWeight aw(w);\n\tfor (int i = 0; i < aw.size(); ++i) {\n\t\taw[i] *= c;\n\t}\n\treturn aw;\n}\nWeight operator*( const Cap&c,const Weight&w) {\n\tWeight aw(w);\n\tfor (int i = 0; i < aw.size(); ++i) {\n\t\taw[i] *= c;\n\t}\n\treturn aw;\n}\nbool operator <(const Weight&l, const Weight&r) {\n\tassert(l.size() == r.size());\n\tfor (int i = 0; i < l.size(); ++i) {\n\t\tif (l[i] < r[i])return true;\n\t\telse if (l[i] == r[i])continue;\n\t\telse return false;\n\t}\n\treturn false;\n}\nbool operator < (const Edge &e, const Edge &f) {\n\treturn e.cost > f.cost;\n}\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\n\n#define RESIDUE(s,t) (capacity[s][t]-flow[s][t])\n#define RCOST(u,v) (cost[u][v] + h[u] - h[v])\n\n//??°?????????????????§???????????????????????¨?????????\n\n//Graph &ag\n//????????§???????????????(u, v, capacity, cost) ??????????????????(u, v, 0, -cost) ???????????°????????????????????¶?????????????????§????´???°????????§???????????°???????????????\n//int s, int t\n//?????????????§??????¨?????????\n//?????????\n//?????¨??¨????????????????????????\npair<Weight, Cap> minimumCostFlow(const Graph &ag, int s, int t) {\n//check???????´???°??????????????£???????????????\n\tGraph g(ag);\n\tfor (int i = 0; i < ag.size(); ++i) {\n\t\tfor (int j = 0; j < ag[i].size(); ++j) {\n\t\t\tint d = ag[i][j].dst;\n\t\t\tint s = ag[i][j].src;\n\n\t\t\tbool ok = false;\n\t\t\tfor (int k = 0; k < ag[d].size(); ++k) {\n\t\t\t\tif (ag[d][k].src == s) {\n\t\t\t\t\tok = true;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (!ok) {\n\t\t\t\tg[d].push_back(Edge(d, s, C_ZERO, -ag[i][j].cost));\n\t\t\t}\n\t\t}\n\t}\n\tconst int n = g.size();\n\tvector<vector<Cap>> capacity(n, vector<Cap>(n)), flow(n, vector<Cap>(n));\n\tvector<vector<Weight>>cost(n, vector<Weight>(n,W_ZERO));\n\tfor (int u = 0; u < n;++u){\n\t\tfor (auto e : g[u]) {\n\t\t\tcapacity[e.src][e.dst] = capacity[e.src][e.dst] + e.capacity;\n\t\t\tcost[e.src][e.dst] = cost[e.src][e.dst] + e.cost;\n\t\t}\n\t}\n\tpair<Weight, Cap> total(W_ZERO,C_ZERO); // (cost, flow)\n\tvector<Weight> h(n,W_ZERO);\n\n\tfor (Cap F = C_INF; F > 0; ) { // residual flow\n\t\tvector<Weight> d(n, W_INF); d[s] = W_ZERO;\n\t\tvector<int> p(n, -1);\n\t\tpriority_queue<Edge> Q; // \"e < f\" <=> \"e.cost > f.cost\"\n\t\tfor (Q.push(Edge(-2, s, C_ZERO, W_ZERO)); !Q.empty(); ) {\n\t\t\tEdge e = Q.top(); Q.pop();\n\t\t\tif (p[e.dst] != -1) continue;\n\t\t\tp[e.dst] = e.src;\n\t\t\tfor (auto f : g[e.dst]) {\n\n\t\t\t\n\t\t\t\tif (RESIDUE(f.src, f.dst) > 0) {\n\t\t\t\t\tif (d[f.dst] > d[f.src] + RCOST(f.src, f.dst)) {\n\t\t\t\t\t\td[f.dst] = d[f.src] + RCOST(f.src, f.dst);\n\t\t\t\t\t\tQ.push(Edge(f.src, f.dst, 0, d[f.dst]));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (p[t] == -1) break;\n\n\t\tCap f = F;\n\t\tfor (int u = t; u != s; u = p[u]) {\n\t\t\tf = min(f, RESIDUE(p[u], u));\n\t\t}\n\t\tfor (int u = t; u != s; u = p[u]) {\n\t\t\ttotal.first =total.first+ f * cost[p[u]][u];\n\t\t\tflow[p[u]][u] =flow[p[u]][u]+ f; flow[u][p[u]] =flow[u][p[u]]- f;\n\t\t}\n\t\tF = F - f;\n\t\ttotal.second =total.second+ f;\n\t\tfor (int u = 0; u < n; ++u) {\n\t\t\th[u] =h[u] + d[u];\n\t\t}\n\t}\n\treturn total;\n}\nint main() {\n\tint N; cin >> N;\n\tconst int start = 0;\n\tconst int from = 1;\n\tconst int to = from + N;\n\tconst int goal=to + N;\n\tGraph g(goal + 1);\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tg[0].push_back(Edge(0, from + i, 1, W_ZERO));\n\t}\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tfor (int j = 0; j < N - 1; ++j) {\n\t\t\tint a; cin >> a;\n\t\t\tif (a) {\n\n\t\t\t\tvector<int>v(1000);\n\t\t\t\tv[i] = j;\n\t\t\t\tg[from + i].push_back(Edge(from + i, to + j, 1, v));\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tg[to + i].push_back(Edge(to + i, goal, 1, W_ZERO));\n\t}\n\tauto p = minimumCostFlow(g, start, goal);\n\tif (p.second == N - 1) {\n\t\tcout << \"yes\" << endl;\n\t\tvector<int>ans(N - 1);\n\t\tfor (int j = 0; j < N - 1; ++j) {\n\t\t\tans[p.first[j]] = j;\n\t\t}\n\t\tfor (int j = 0; j < N - 1; ++j) {\n\t\t\tcout << 1+ans[j] << endl;\n\t\t}\n\t}\n\telse {\n\t\tassert(p.second < N - 1);\n\t\tcout << \"no\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.16666666666666666, "time_ms": 30, "memory_kb": 16676, "score_of_the_acc": -1.0175, "final_rank": 20 } ]
aoj_0330_cpp
プログラム停止判定 皆さんは、苦労して作ったプログラムを実行してみたら、無限ループになってしまった経験はありませんか? プログラムの実行が停止するかどうかを、実行しなくても事前に判定できると便利ですよね。 残念ながら、皆さんがふだん使っているプログラミング言語では、あらゆるプログラムに対してそのような判定をすることは不可能です。しかし、それよりもはるかに計算能力の低いプログラミング言語なら、その言語で書いたプログラムが停止するかどうかを判定するプログラムを書ける場合があります。 TinyPowerというプログラミング言語を考えます。この言語のプログラムは行の並びです。プログラムの各行には、先頭に行番号を書き、その後ろに文を一つ書きます。この言語で書ける文の種類は以下の通りです。 文の種類 動作 ADD var 1 var 2 var 3 変数 var 2 の値と var 3 の値を加算した結果を変数 var 1 に代入する ADD var 1 var 2 con 変数 var 2 の値と定数 con を加算した結果を変数 var 1 に代入する SUB var 1 var 2 var 3 変数 var 2 の値から var 3 の値を減算した結果を変数 var 1 に代入する SUB var 1 var 2 con 変数 var 2 の値から定数 con を減算した結果を変数 var 1 に代入する SET var 1 var 2 変数 var 2 の値を変数 var 1 に代入する SET var 1 con 定数 con を変数 var 1 に代入する IF var 1 dest 変数 var 1 の値が0でないときだけ、行番号 dest にジャンプする HALT プログラムを停止させる 行番号は正の整数で、プログラム中に同じ行番号が2つ以上現れることはありません。変数は英小文字一文字で表し、定数と変数の値は整数です。変数の宣言は不要で、変数の初期値は0です。 プログラムの実行は先頭の文から始まり、並んでいる順に文が実行されます。ただし、上の表に書かれたように、IF文の変数の値が0でないときは、変数の後ろに書かれた行番号で指定される行にジャンプし、その行に書かれた文から実行を続けます。プログラムは以下のときに停止します。 HALT文を実行したとき。 負の整数または16以上の整数を変数に代入しようとしたとき(変数の値は更新されない)。 プログラムに現れない行番号にジャンプしようとしたとき。 プログラムの最後の文を実行した後、そこからどの行にもジャンプしないとき。 TinyPowerのプログラムが与えられたとき、それが停まるかどうかを判定するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N stmt 1 stmt 2 : stmt N 1行目にプログラムの行数 N (1 ≤ N ≤ 50) が与えられる。続く N 行に、TinyPowerプログラムの文 stmt i が与えられる。 stmt i は、以下のいずれかの形式で与えられる。 line ADD var 1 var 2 var 3 または line ADD var 1 var 2 con または line SUB var 1 var 2 var 3 または line SUB var 1 var 2 con または line SET var 1 var 2 または line SET var 1 con または line IF var 1 dest または line HALT line , dest (1 ≤ line , dest ≤ 1000) は行番号、 var j (英小文字1文字)は変数、 con (0 ≤ con ≤ 15) は定数を表す。 stmt i 中の区切りは空白1文字とする。なお、プログラム中に変数は必ず1つ以上現れ、異なる変数名は5つまでしか現れないものとする。 Output プログラムが停止するときは、プログラムに現れる変数の結果を、変数名の辞書順に改行区切りで出力し、停止しないときは「inf」を出力する。変数の結果は、変数名と変数の値を「=」で区切って出力する。 Sample Input 1 6 10 SET c 1 20 SET i 5 100 ADD s s i 110 SUB i i c 120 IF i 100 200 HALT Sample Output 1 c=1 i=0 s=15 入力例1は、1から5までの整数の和を計算し、その結果を変数sに格納したあと、HALT文の実行で停止する。 Sample Input 2 3 10 SET c 1 120 IF c 10 20 HALT Sample Output 2 inf 入力例2は、行番号10でcに1を代入し、次の行番号120のIF文で行番号10に戻ることを繰り返すので、停止しない。 Sample Input 3 3 111 SET c 1 12 SUB c c 2 777 SET a 4 Sample Output 3 a=0 c=1 入力例3は、行番号111でcに1を代入し、次の行番号12でcに-1を代入しようとするので、停止する。このときcの値は-1に更新されない。行番号777は実行されないので、aの値は初期値0のままである。
[ { "submission_id": "aoj_0330_10946325", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <cstring>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <list>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <unordered_set>\n#include <unordered_map>\n#include <array>\n#include <cassert>\n#include <bitset>\nusing namespace std;\nusing LL = long long;\n\nint main(void)\n{\n\tint N;\n\tstring tmpNNN;\n\tgetline(cin ,tmpNNN);\n\tsscanf(tmpNNN.c_str(), \"%d\", &N);\n\tvector<string>code;\n\tmap<int, int>rev;\n\tmap<char, int>var;\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tstring s;\n\t\tgetline(cin, s);\n\t\tint lin;\n\t\tsscanf(s.c_str(),\"%d\",&lin);\n\t\trev[lin] = i;\n\t\twhile (s.front() < 'A' || 'Z' < s.front())\n\t\t{\n\t\t\ts.erase(s.begin(), s.begin() + 1);\n\t\t}\n\t\tcode.push_back(s);\n\t}\n\tchar v1[10], v2[10], v3[10];\n\tfor (int i = 0; i < N; ++i)\n\t{\n\t\tconst string& s = code[i];\n\t\tif (s[0] == 'A')\n\t\t{\n\t\t\t//ADD\n\t\t\tsscanf(s.c_str(), \"ADD %s %s %s\", v1, v2, v3);\n\t\t\tvar[v1[0]] = 0;\n\t\t\tvar[v2[0]] = 0;\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z')\n\t\t\t\tvar[v3[0]] = 0;\n\t\t}\n\t\telse if (s[0] == 'S' && s[1] == 'U')\n\t\t{\n\t\t\t//SUB\n\t\t\tsscanf(s.c_str(), \"SUB %s %s %s\", v1, v2, v3);\n\t\t\tvar[v1[0]] = 0;\n\t\t\tvar[v2[0]] = 0;\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z')\n\t\t\t\tvar[v3[0]] = 0;\n\t\t}\n\t\telse if (s[0] == 'I')\n\t\t{\n\t\t\t//IF\n\t\t\tsscanf(s.c_str(), \"IF %s %s\", v1, v2);\n\t\t\tvar[v1[0]] = 0;\n\t\t}\n\t\telse if (s[0] == 'H')\n\t\t{\n\t\t\t//HALT\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//SET\n\t\t\tsscanf(s.c_str(), \"SET %s %s\", v1, v2);\n\t\t\tvar[v1[0]] = 0;\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z')\n\t\t\t\tvar[v2[0]] = 0;\n\t\t}\n\t}\n\tbool mugen = true;\n\tint i = 0;\n\tfor (int looptime = 0; looptime < 33333333; ++looptime)\n\t{\n\t\tif (i >= code.size())\n\t\t{\n\t\t\t//end of program\n\t\t\tmugen = false; break;\n\t\t}\n\t\tconst string& s = code[i];\n\t\tif (s[0] == 'A')\n\t\t{\n\t\t\t//ADD\n\t\t\tsscanf(s.c_str(), \"ADD %s %s %s\", v1, v2, v3);\n\t\t\tint cons;\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z')\n\t\t\t{\n\t\t\t\tcons = var[v3[0]];\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcons = stoi(v3);\n\t\t\t}\n\t\t\tint tmp = var[v2[0]] + cons;\n\t\t\tif (tmp < 0 || tmp >= 16)\n\t\t\t{\n\t\t\t\t//overflow\n\t\t\t\tmugen = false; break;\n\t\t\t}\n\t\t\tvar[v1[0]] = tmp;\n\t\t}\n\t\telse if (s[0] == 'S' && s[1] == 'U')\n\t\t{\n\t\t\t//SUB\n\t\t\tsscanf(s.c_str(), \"SUB %s %s %s\", v1, v2, v3);\n\t\t\tint cons;\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z')\n\t\t\t{\n\t\t\t\tcons = var[v3[0]];\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcons = stoi(v3);\n\t\t\t}\n\t\t\tint tmp = var[v2[0]] - cons;\n\t\t\tif (tmp < 0 || tmp >= 16)\n\t\t\t{\n\t\t\t\t//overflow\n\t\t\t\tmugen = false; break;\n\t\t\t}\n\t\t\tvar[v1[0]] = tmp;\n\t\t}\n\t\telse if (s[0] == 'I')\n\t\t{\n\t\t\t//IF\n\t\t\tsscanf(s.c_str(), \"IF %s %s\", v1, v2);\n\t\t\tint lin = stoi(v2);\n\t\t\tif (var[v1[0]])\n\t\t\t{\n\t\t\t\t//jump\n\t\t\t\tif (!rev.count(lin))\n\t\t\t\t{\n\t\t\t\t\t//cannot jump to unknown line\n\t\t\t\t\tmugen = false; break;\n\t\t\t\t}\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\ti = rev[lin];\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse if (s[0] == 'H')\n\t\t{\n\t\t\t//HALT\n\t\t\t//progam halted\n\t\t\tmugen = false; break;\n\t\t}\n\t\telse\n\t\t{\n\t\t\t//SET\n\t\t\tsscanf(s.c_str(), \"SET %s %s\", v1, v2);\n\t\t\tint cons;\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z')\n\t\t\t{\n\t\t\t\tcons = var[v2[0]];\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcons = stoi(v2);\n\t\t\t}\n\t\t\tvar[v1[0]] = cons;\n\t\t}\n\t\t++i;\n\t}\n\tif (mugen)\n\t{\n\t\tcout << \"inf\\n\";\n\t\treturn 0;\n\t}\n\tfor (auto p : var)\n\t{\n\t\tcout << p.first << '=' << p.second << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 3512, "score_of_the_acc": -0.5542, "final_rank": 7 }, { "submission_id": "aoj_0330_9470932", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n int l[n];\n string s[n];\n int v[n][3] = {};\n char c[n][3] = {};\n string t;\n vector<int> pos(1000, -1);\n int var[26] = {};\n bool var_exist[26] = {};\n for (int i = 0; i < n; i++) {\n cin >> l[i];\n cin >> s[i];\n if (s[i] == \"ADD\" || s[i] == \"SUB\") {\n cin >> c[i][0] >> c[i][1] >> t;\n var_exist[c[i][0] - 'a'] = true;\n var_exist[c[i][1] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][2] = stoi(t);\n } else {\n c[i][2] = t[0];\n var_exist[c[i][2] - 'a'] = true;\n }\n } else if (s[i] == \"SET\") {\n cin >> c[i][0] >> t;\n var_exist[c[i][0] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][1] = stoi(t);\n } else {\n c[i][1] = t[0];\n var_exist[c[i][1] - 'a'] = true;\n }\n } else if (s[i] == \"IF\") {\n cin >> c[i][0] >> v[i][1];\n var_exist[c[i][0] - 'a'] = true;\n }\n pos[l[i]] = i;\n }\n int now = 0;\n int cnt = 0;\n while (1) {\n cnt++;\n if (cnt > 52428800) {\n cout << \"inf\\n\";\n return(0);\n }\n if (s[now] == \"ADD\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] + var[c[now][2] - 'a'] && var[c[now][1] - 'a'] + var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] + v[now][2] && var[c[now][1] - 'a'] + v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SUB\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] - var[c[now][2] - 'a'] && var[c[now][1] - 'a'] - var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] - v[now][2] && var[c[now][1] - 'a'] - v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SET\") {\n if (c[now][1] != 0) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'];\n } else {\n var[c[now][0] - 'a'] = v[now][1];\n }\n } else if (s[now] == \"HALT\") {\n break;\n }\n if (s[now] == \"IF\") {\n if (var[c[now][0] - 'a'] != 0) {\n if (pos[v[now][1]] != -1) {\n now = pos[v[now][1]];\n } else {\n break;\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n }\n for (int i = 0; i < 26; i++) {\n if (var_exist[i]) {\n cout << (char)('a' + i) << \"=\" << var[i] << \"\\n\";\n }\n }\n return(0);\n}", "accuracy": 1, "time_ms": 1210, "memory_kb": 3444, "score_of_the_acc": -0.2406, "final_rank": 2 }, { "submission_id": "aoj_0330_9470888", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n clock_t start = clock();\n int n;\n cin >> n;\n int l[n];\n string s[n];\n int v[n][3] = {};\n char c[n][3] = {};\n string t;\n vector<int> pos(1000, -1);\n int var[26] = {};\n bool var_exist[26] = {};\n for (int i = 0; i < n; i++) {\n cin >> l[i];\n cin >> s[i];\n if (s[i] == \"ADD\" || s[i] == \"SUB\") {\n cin >> c[i][0] >> c[i][1] >> t;\n var_exist[c[i][0] - 'a'] = true;\n var_exist[c[i][1] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][2] = stoi(t);\n } else {\n c[i][2] = t[0];\n var_exist[c[i][2] - 'a'] = true;\n }\n } else if (s[i] == \"SET\") {\n cin >> c[i][0] >> t;\n var_exist[c[i][0] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][1] = stoi(t);\n } else {\n c[i][1] = t[0];\n var_exist[c[i][1] - 'a'] = true;\n }\n } else if (s[i] == \"IF\") {\n cin >> c[i][0] >> v[i][1];\n var_exist[c[i][0] - 'a'] = true;\n }\n pos[l[i]] = i;\n }\n int now = 0;\n while (1) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC * 1000.0;\n if (time >= 4990) {\n cout << \"inf\\n\";\n return(0);\n }\n if (s[now] == \"ADD\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] + var[c[now][2] - 'a'] && var[c[now][1] - 'a'] + var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] + v[now][2] && var[c[now][1] - 'a'] + v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SUB\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] - var[c[now][2] - 'a'] && var[c[now][1] - 'a'] - var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] - v[now][2] && var[c[now][1] - 'a'] - v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SET\") {\n if (c[now][1] != 0) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'];\n } else {\n var[c[now][0] - 'a'] = v[now][1];\n }\n } else if (s[now] == \"HALT\") {\n break;\n }\n if (s[now] == \"IF\") {\n if (var[c[now][0] - 'a'] != 0) {\n if (pos[v[now][1]] != -1) {\n now = pos[v[now][1]];\n } else {\n break;\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n }\n for (int i = 0; i < 26; i++) {\n if (var_exist[i]) {\n cout << (char)('a' + i) << \"=\" << var[i] << \"\\n\";\n }\n }\n return(0);\n}", "accuracy": 0.8333333333333334, "time_ms": 4980, "memory_kb": 3444, "score_of_the_acc": -1.0022, "final_rank": 14 }, { "submission_id": "aoj_0330_9470839", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n clock_t start = clock();\n int n;\n cin >> n;\n int l[n];\n string s[n];\n int v[n][3] = {};\n char c[n][3] = {};\n string t;\n map<int, int> pos;\n int var[26] = {};\n bool var_exist[26] = {};\n for (int i = 0; i < n; i++) {\n cin >> l[i];\n cin >> s[i];\n if (s[i] == \"ADD\" || s[i] == \"SUB\") {\n cin >> c[i][0] >> c[i][1] >> t;\n var_exist[c[i][0] - 'a'] = true;\n var_exist[c[i][1] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][2] = stoi(t);\n } else {\n c[i][2] = t[0];\n var_exist[c[i][2] - 'a'] = true;\n }\n } else if (s[i] == \"SET\") {\n cin >> c[i][0] >> t;\n var_exist[c[i][0] - 'a'] = true;\n if (!('a' <= t[0] && t[0] <= 'z')) {\n v[i][1] = stoi(t);\n } else {\n c[i][1] = t[0];\n var_exist[c[i][1] - 'a'] = true;\n }\n } else if (s[i] == \"IF\") {\n cin >> c[i][0] >> v[i][1];\n var_exist[c[i][0] - 'a'] = true;\n }\n pos[l[i]] = i;\n }\n int now = 0;\n while (1) {\n clock_t end = clock();\n const double time = static_cast<double>(end - start) / CLOCKS_PER_SEC * 1000.0;\n if (time >= 4500) {\n cout << \"inf\\n\";\n return(0);\n }\n if (s[now] == \"ADD\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] + var[c[now][2] - 'a'] && var[c[now][1] - 'a'] + var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] + v[now][2] && var[c[now][1] - 'a'] + v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] + v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SUB\") {\n if (c[now][2] != 0) {\n if (0 <= var[c[now][1] - 'a'] - var[c[now][2] - 'a'] && var[c[now][1] - 'a'] - var[c[now][2] - 'a'] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - var[c[now][2] - 'a'];\n } else {\n break;\n }\n } else {\n if (0 <= var[c[now][1] - 'a'] - v[now][2] && var[c[now][1] - 'a'] - v[now][2] < 16) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'] - v[now][2];\n } else {\n break;\n }\n }\n } else if (s[now] == \"SET\") {\n if (c[now][1] != 0) {\n var[c[now][0] - 'a'] = var[c[now][1] - 'a'];\n } else {\n var[c[now][0] - 'a'] = v[now][1];\n }\n } else if (s[now] == \"HALT\") {\n break;\n }\n if (s[now] == \"IF\") {\n if (var[c[now][0] - 'a'] != 0) {\n if (pos.count(v[now][1])) {\n now = pos[v[now][1]];\n } else {\n break;\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n } else {\n if (now + 1 < n) {\n now++;\n } else {\n break;\n }\n }\n }\n for (int i = 0; i < 26; i++) {\n if (var_exist[i]) {\n cout << (char)('a' + i) << \"=\" << var[i] << \"\\n\";\n }\n }\n return(0);\n}", "accuracy": 0.8333333333333334, "time_ms": 4490, "memory_kb": 3448, "score_of_the_acc": -0.9032, "final_rank": 13 }, { "submission_id": "aoj_0330_7074188", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nbool history[(int)1e9];\nint varcnt = 0;\nmap<int, int>line;\nmap<string, int>str;\nmap<int, int>ch;\n\nint main() {\n\tstr[\"SET\"] = 0;\n\tstr[\"ADD\"] = 1;\n\tstr[\"SUB\"] = 2;\n\tstr[\"IF\"] = 3;\n\tstr[\"HALT\"] = 4;\n\tint n;\n\tcin >> n;\n\tvvint order(n, vint(4));\n\trep(i, n) {\n\t\t{\n\t\t\tint l;\n\t\t\tcin >> l;\n\t\t\tline[l] = i + 1;\n\t\t} {\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\torder[i][0] = str[s];\n\t\t\tif (order[i][0] == 4)continue;\n\t\t} {\n\t\t\tchar c;\n\t\t\tcin >> c;\n\t\t\tif (ch[c] == 0) ch[c] = ++varcnt;\n\t\t\torder[i][1] = ch[c] - 1;\n\t\t} {\n\t\t\tif (order[i][0] == 3) {\n\t\t\t\tcin >> order[i][2];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tstring s;\n\t\t\t\tcin >> s;\n\t\t\t\tif ('a' <= s[0] && s[0] <= 'z') {\n\t\t\t\t\tif (ch[s[0]] == 0)ch[s[0]] = ++varcnt;\n\t\t\t\t\torder[i][2] = -ch[s[0]];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tint cnt = 0;\n\t\t\t\t\trep(i, s.size())(cnt += s[i] - '0') *= 10;\n\t\t\t\t\torder[i][2] = cnt / 10;\n\t\t\t\t}\n\t\t\t\tif (order[i][0] == 0)continue;\n\t\t\t}\n\t\t} {\n\t\t\tstring s;\n\t\t\tcin >> s;\n\t\t\tif ('a' <= s[0] && s[0] <= 'z') {\n\t\t\t\tif (ch[s[0]] == 0)ch[s[0]] = ++varcnt;\n\t\t\t\torder[i][3] = -ch[s[0]];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint cnt = 0;\n\t\t\t\trep(i, s.size())(cnt += s[i] - '0') *= 10;\n\t\t\t\torder[i][3] = cnt / 10;\n\t\t\t}\n\t\t}\n\t}\n\trep(i, n) if (order[i][0] == 3)order[i][2] = line[order[i][2]] - 1;\n\n\tint value = 0;\n\trep(i, varcnt) {\n\t\tvalue *= 17; value += 16;\n\t}\n\tint nowline = 0;\n\tbool isWorking = true;\n\twhile (isWorking && 0 <= nowline && nowline < n) {\n\t\tif (history[nowline + value * n]) {\n\t\t\tcout << \"inf\" << endl;\n\t\t\treturn 0;\n\t\t}\n\t\thistory[nowline + value * n] = true;\n\t\tint var[5] = {};\n\t\trep(i, 5) {\n\t\t\tvar[i] = value % 17;\n\t\t\tvalue /= 17;\n\t\t}\n\t\tswitch (order[nowline][0]) {\n\t\tcase 0: {\n\t\t\tint x = 0;\n\t\t\tif (order[nowline][2] < 0) {\n\t\t\t\tx = (var[-order[nowline][2] - 1] %= 16);\n\t\t\t}\n\t\t\telse x = order[nowline][2];\n\t\t\tvar[order[nowline][1]] = x;\n\t\t\tbreak;\n\t\t}\n\t\tcase 1: {\n\t\t\torder[nowline][1] %= 16;\n\t\t\tint x = 0, y = 0;\n\t\t\tif (order[nowline][2] < 0) {\n\t\t\t\tx = (var[-order[nowline][2] - 1] %= 16);\n\t\t\t}\n\t\t\telse x = order[nowline][2];\n\t\t\tif (order[nowline][3] < 0) {\n\t\t\t\ty = (var[-order[nowline][3] - 1] %= 16);\n\t\t\t}\n\t\t\telse y = order[nowline][3];\n\t\t\tint tmp = x + y;\n\t\t\tif (tmp > 15 || tmp < 0) {\n\t\t\t\tisWorking = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tvar[order[nowline][1]] = tmp;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcase 2: {\n\t\t\torder[nowline][1] %= 16;\n\t\t\tint x = 0, y = 0;\n\t\t\tif (order[nowline][2] < 0) {\n\t\t\t\tx = (var[-order[nowline][2] - 1] %= 16);\n\t\t\t}\n\t\t\telse x = order[nowline][2];\n\t\t\tif (order[nowline][3] < 0) {\n\t\t\t\ty = (var[-order[nowline][3] - 1] %= 16);\n\t\t\t}\n\t\t\telse y = order[nowline][3];\n\t\t\tint tmp = x - y;\n\t\t\tif (tmp > 15 || tmp < 0) {\n\t\t\t\tisWorking = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tvar[order[nowline][1]] = tmp;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcase 3: {\n\t\t\tif (var[order[nowline][1]]) {\n\t\t\t\tnowline = order[nowline][2];\n\t\t\t\tnowline--;\n\t\t\t}\n\t\t\tbreak;\n\t\t}\n\t\tcase 4: {\n\t\t\tisWorking = false;\n\t\t\tbreak;\n\t\t}\n\t\t}\n\t\tvalue = 0;\n\t\tdrep(i, varcnt) {\n\t\t\tvalue *= 17;\n\t\t\tvalue += var[i];\n\t\t}\n\t\tnowline++;\n\t}\n\n\tint var[5] = {};\n\trep(i, varcnt) {\n\t\tvar[i] = value % 17;\n\t\tvalue /= 17;\n\t}\n\tvector<pair<char, int>>ans;\n\tfor (auto [c, i] : ch) {\n\t\tans.push_back({ c,var[i - 1] });\n\t}\n\tsort(all(ans));\n\trep(i, varcnt) {\n\t\tcout << ans[i].first << \"=\" << ans[i].second % 16 << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 70536, "score_of_the_acc": -0.6048, "final_rank": 8 }, { "submission_id": "aoj_0330_6966038", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0330.cc: プログラム停止判定\n */\n\n#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<set>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 50;\nconst int MAX_M = 5;\nconst int MAX_LN = 1000;\nconst int CONB = 1 << 4;\n\nenum { ADD, SUB, SET, IF, HALT };\n\n/* typedef */\n\ntypedef set<int> si;\ntypedef pair<int,int> pii;\n\nstruct Prog {\n int op, v0, v1, v2;\n Prog() {}\n Prog(int _op, int _v0, int _v1, int _v2):\n op(_op), v0(_v0), v1(_v1), v2(_v2) {}\n};\n\n/* global variables */\n\nint ltbl[MAX_LN + 1], vtbl[26];\nchar vnms[MAX_M];\nProg pgs[MAX_N];\nsi stset[MAX_N];\npii vcs[MAX_M];\n\n/* subroutines */\n\nint s2op(char s[]) {\n if (! strcmp(s, \"ADD\")) return ADD;\n if (! strcmp(s, \"SUB\")) return SUB;\n if (! strcmp(s, \"SET\")) return SET;\n if (! strcmp(s, \"IF\")) return IF;\n if (! strcmp(s, \"HALT\")) return HALT;\n return -1;\n}\n\nint alloc_var(char c, int &m) {\n int ci = c - 'a';\n if (vtbl[ci] < 0) {\n vnms[m] = c;\n vtbl[ci] = m++;\n }\n return vtbl[ci];\n}\n\nint alloc_var_con(char s[], int &m) {\n if (s[0] >= 'a' && s[0] <= 'z') return alloc_var(s[0], m);\n return atoi(s) | CONB;\n}\n\ninline int getvar(int st, int i) { return (st >> (i * 4)) & 0xf; }\n\ninline int setvar(int st, int i, int v) {\n st &= ~(0xf << (i * 4));\n st |= (v << (i * 4));\n return st;\n}\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n fill(ltbl, ltbl + MAX_LN + 1, -1);\n fill(vtbl, vtbl + 26, -1);\n\n int n;\n scanf(\"%d\", &n);\n\n int m = 0;\n for (int i = 0; i < n; i++) {\n int ln;\n scanf(\"%d\", &ln);\n ltbl[ln] = i;\n\n char s0[8], s1[8], s2[8], s3[8];\n scanf(\"%s\", s0);\n int op = s2op(s0);\n\n if (op == ADD || op == SUB) {\n scanf(\"%s%s%s\", s1, s2, s3);\n int v0 = alloc_var(s1[0], m);\n int v1 = alloc_var(s2[0], m);\n int v2 = alloc_var_con(s3, m);\n pgs[i] = Prog(op, v0, v1, v2);\n }\n else if (op == SET) {\n scanf(\"%s%s\", s1, s2);\n int v0 = alloc_var(s1[0], m);\n int v1 = alloc_var_con(s2, m);\n pgs[i] = Prog(op, v0, v1, -1);\n }\n else if (! strcmp(s0, \"IF\")) {\n int dst;\n scanf(\"%s%d\", s1, &dst);\n int v0 = alloc_var(s1[0], m);\n pgs[i] = Prog(op, v0, dst, -1);\n }\n else\n pgs[i] = Prog(op, -1, -1, -1);\n }\n //printf(\"m=%d\\n\", m);\n\n int st = 0;\n for (int pc = 0; pc < n;) {\n Prog &pg = pgs[pc];\n\n if (pg.op == ADD) {\n int v1 = getvar(st, pg.v1);\n int v2 = (pg.v2 < CONB) ? getvar(st, pg.v2) : (pg.v2 ^ CONB);\n int v0 = v1 + v2;\n if (v0 < 0 || v0 >= CONB) break;\n st = setvar(st, pg.v0, v0);\n pc++;\n }\n else if (pg.op == SUB) {\n int v1 = getvar(st, pg.v1);\n int v2 = (pg.v2 < CONB) ? getvar(st, pg.v2) : (pg.v2 ^ CONB);\n int v0 = v1 - v2;\n if (v0 < 0 || v0 >= CONB) break;\n st = setvar(st, pg.v0, v0);\n pc++;\n }\n else if (pg.op == SET) {\n int v1 = (pg.v1 < CONB) ? getvar(st, pg.v1) : (pg.v1 ^ CONB);\n st = setvar(st, pg.v0, v1);\n pc++;\n }\n else if (pg.op == IF) {\n si::iterator sit = stset[pc].find(st);\n if (sit != stset[pc].end()) { puts(\"inf\"); return 0; }\n stset[pc].insert(st);\n\n if (getvar(st, pg.v0) != 0) {\n\tpc = ltbl[pg.v1];\n\tif (pc < 0) break;\n }\n else\n\tpc++;\n }\n else\n break;\n }\n\n for (int i = 0; i < m; i++)\n vcs[i] = pii(vnms[i], getvar(st, i));\n sort(vcs, vcs + m);\n\n for (int i = 0; i < m; i++)\n printf(\"%c=%d\\n\", vcs[i].first, vcs[i].second);\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 41096, "score_of_the_acc": -0.3336, "final_rank": 4 }, { "submission_id": "aoj_0330_5958465", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N;\n cin >> N;\n vector<int> line(N);\n vector<string> T(N);\n vector<char> var1(N), var2(N), var3(N);\n vector<int> con(N);\n vector<int> t(N);\n vector<int> dest(N);\n for (int i = 0; i < N; i++){\n cin >> line[i] >> T[i];\n if (T[i] == \"ADD\" || T[i] == \"SUB\"){\n cin >> var1[i] >> var2[i];\n string S;\n cin >> S;\n if (isalpha(S[0]) != 0){\n var3[i] = S[0];\n t[i] = 0;\n } else {\n con[i] = stoi(S);\n t[i] = 1;\n }\n }\n if (T[i] == \"SET\"){\n cin >> var1[i];\n string S;\n cin >> S;\n if (isalpha(S[0]) != 0){\n var2[i] = S[0];\n t[i] = 0;\n } else {\n con[i] = stoi(S);\n t[i] = 1;\n }\n }\n if (T[i] == \"IF\"){\n cin >> var1[i] >> dest[i];\n }\n }\n map<int, int> mp;\n for (int i = 0; i < N; i++){\n mp[line[i]] = i;\n }\n for (int i = 0; i < N; i++){\n line[i] = i;\n }\n for (int i = 0; i < N; i++){\n if (T[i] == \"IF\"){\n if (mp.count(dest[i]) == 0){\n dest[i] = N;\n } else {\n dest[i] = mp[dest[i]];\n }\n }\n }\n vector<char> var;\n for (int i = 0; i < N; i++){\n if (T[i] == \"ADD\" || T[i] == \"SUB\"){\n var.push_back(var1[i]);\n var.push_back(var2[i]);\n if (t[i] == 0){\n var.push_back(var3[i]);\n }\n }\n if (T[i] == \"SET\"){\n var.push_back(var1[i]);\n if (t[i] == 0){\n var.push_back(var2[i]);\n }\n }\n if (T[i] == \"IF\"){\n var.push_back(var1[i]);\n }\n }\n sort(var.begin(), var.end());\n var.erase(unique(var.begin(), var.end()), var.end());\n vector<int> id1(N), id2(N), id3(N);\n for (int i = 0; i < N; i++){\n if (T[i] == \"ADD\" || T[i] == \"SUB\"){\n id1[i] = lower_bound(var.begin(), var.end(), var1[i]) - var.begin();\n id2[i] = lower_bound(var.begin(), var.end(), var2[i]) - var.begin();\n if (t[i] == 0){\n id3[i] = lower_bound(var.begin(), var.end(), var3[i]) - var.begin();\n }\n }\n if (T[i] == \"SET\"){\n id1[i] = lower_bound(var.begin(), var.end(), var1[i]) - var.begin();\n if (t[i] == 0){\n id2[i] = lower_bound(var.begin(), var.end(), var2[i]) - var.begin();\n }\n }\n if (T[i] == \"IF\"){\n id1[i] = lower_bound(var.begin(), var.end(), var1[i]) - var.begin();\n }\n }\n int M = var.size();\n int mx = N;\n for (int i = 0; i < M; i++){\n mx *= 16;\n }\n int p = 0;\n vector<int> x(M, 0);\n int cnt = 0;\n while (true){\n if (p == N){\n break;\n }\n if (cnt > mx){\n break;\n }\n if (T[p] == \"ADD\"){\n int nxt;\n if (t[p] == 0){\n nxt = x[id2[p]] + x[id3[p]];\n } else {\n nxt = x[id2[p]] + con[p];\n }\n if (nxt >= 16){\n break;\n }\n x[id1[p]] = nxt;\n p++;\n } else if (T[p] == \"SUB\"){\n int nxt;\n if (t[p] == 0){\n nxt = x[id2[p]] - x[id3[p]];\n } else {\n nxt = x[id2[p]] - con[p];\n }\n if (nxt < 0){\n break;\n }\n x[id1[p]] = nxt;\n p++;\n } else if (T[p] == \"SET\"){\n if (t[p] == 0){\n x[id1[p]] = x[id2[p]];\n } else {\n x[id1[p]] = con[p];\n }\n p++;\n } else if (T[p] == \"IF\"){\n if (x[id1[p]] == 0){\n p++;\n } else {\n p = dest[p];\n }\n } else {\n break;\n }\n cnt++;\n }\n if (cnt > mx){\n cout << \"inf\" << endl;\n } else {\n for (int i = 0; i < M; i++){\n cout << var[i] << '=' << x[i] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 3460, "score_of_the_acc": -0.1882, "final_rank": 1 }, { "submission_id": "aoj_0330_5022765", "code_snippet": "#include<iostream>\n#include<set>\n#include<map>\nusing namespace std;\nstruct state{\n\tint a[5];\n\tint to_i()const{\n\t\treturn a[0]<<16|a[1]<<12|a[2]<<8|a[3]<<4|a[4];\n\t}\n};\nint N;\nint line[1001];\nstring op[50];\nbool S[50][1<<20];\nmap<string,int>mp;\nint var[50][3];\nint rd()\n{\n\tstring s;\n\tcin>>s;\n\tif(isdigit(s[0]))\n\t{\n\t\tif(s.size()==1)return s[0]-'0';\n\t\telse return(s[0]-'0')*10+s[1]-'0';\n\t}\n\tif(mp.find(s)==mp.end())\n\t{\n\t\tint t=mp.size();\n\t\tmp[s]=~t;\n\t}\n\treturn mp[s];\n}\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint num;cin>>num;\n\t\tline[num]=i+1;\n\t\tcin>>op[i];\n\t\tif(op[i]==\"ADD\"||op[i]==\"SUB\")\n\t\t{\n\t\t\tvar[i][0]=rd();\n\t\t\tvar[i][1]=rd();\n\t\t\tvar[i][2]=rd();\n\t\t}\n\t\telse if(op[i]==\"SET\")\n\t\t{\n\t\t\tvar[i][0]=rd();\n\t\t\tvar[i][1]=rd();\n\t\t}\n\t\telse if(op[i]==\"IF\")\n\t\t{\n\t\t\tvar[i][0]=rd();\n\t\t\tcin>>var[i][1];\n\t\t}\n\t}\n\tstate now;\n\tfor(int i=0;i<5;i++)now.a[i]=0;\n\tint num=0;\n\twhile(num>=0&&num<N)\n\t{\n\t\tint T=now.to_i();\n\t\tif(S[num][T])\n\t\t{\n\t\t\tcout<<\"inf\"<<endl;\n\t\t\treturn 0;\n\t\t}\n\t\tS[num][T]=true;\n\t\tint ai=var[num][0];\n\t\tint bi=var[num][1];\n\t\tint ci=var[num][2];\n\t\tif(op[num]==\"ADD\")\n\t\t{\n\t\t\tint T=now.a[~bi]+(ci>=0?ci:now.a[~ci]);\n\t\t\tif(T<0||T>=16)break;\n\t\t\tnow.a[~ai]=T;\n\t\t}\n\t\telse if(op[num]==\"SUB\")\n\t\t{\n\t\t\tint T=now.a[~bi]-(ci>=0?ci:now.a[~ci]);\n\t\t\tif(T<0||T>=16)break;\n\t\t\tnow.a[~ai]=T;\n\t\t}\n\t\telse if(op[num]==\"SET\")\n\t\t{\n\t\t\tnow.a[~ai]=bi>=0?bi:now.a[~bi];\n\t\t}\n\t\telse if(op[num]==\"HALT\")break;\n\t\tif(op[num]==\"IF\"&&now.a[~ai]>0)\n\t\t{\n\t\t\tnum=line[bi]-1;\n\t\t}\n\t\telse num++;\n\t}\n\tfor(pair<string,int>p:mp)\n\t{\n\t\tcout<<p.first<<\"=\"<<now.a[~p.second]<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 820, "memory_kb": 47328, "score_of_the_acc": -0.5057, "final_rank": 6 }, { "submission_id": "aoj_0330_4562629", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nvector<string> split(string &s){\n vector<string> res;\n string tmp;\n for (auto &&i : s) {\n if(i == ' '){\n if(!tmp.empty()) {\n res.emplace_back(tmp);\n tmp.clear();\n }\n }else tmp += i;\n }\n if(!tmp.empty()) res.emplace_back(tmp);\n return res;\n}\nbitset<1 << 20> dp[50];\nint main() {\n int n;\n cin >> n;\n vector<vector<string>> v(n);\n map<string, int> m;\n array<char, 256> vars;\n fill(vars.begin(),vars.end(), -1);\n int cnt = 0;\n cin.ignore();\n for (int i = 0; i < n; ++i) {\n string s;\n getline(cin, s);\n v[i] = split(s);\n m[v[i][0]] = i;\n v[i].erase(v[i].begin());\n for (int j = 1; j < v[i].size(); ++j) {\n if(islower(v[i][j][0]) && !~vars[v[i][j][0]]){\n vars[v[i][j][0]] = cnt++;\n }\n }\n }\n int cur = 0, val = 0;\n while(true){\n if(cur == n) break;\n if(dp[cur][val]) {\n puts(\"inf\");\n return 0;\n }\n /*for (auto &&i : v[cur]) {\n cout << i << \" \";\n }\n puts(\"\");*/\n dp[cur].set(val);\n if(v[cur][0] == \"HALT\"){\n break;\n }else if(v[cur][0] == \"ADD\"){\n int val1 = (val >> (vars[v[cur][2][0]]*4))&15, val2 = (~vars[v[cur][3][0]] ? (val >> (vars[v[cur][3][0]]*4))&15 : stoi(v[cur][3]));\n if(val1 + val2 > 15) break;\n val = (val & (-1 - (15 << vars[v[cur][1][0]]*4))) + ((val1+val2) << vars[v[cur][1][0]]*4);\n }else if(v[cur][0] == \"SUB\"){\n int val1 = (val >> (vars[v[cur][2][0]]*4))&15, val2 = (~vars[v[cur][3][0]] ? (val >> (vars[v[cur][3][0]]*4))&15 : stoi(v[cur][3]));\n if(val1 - val2 < 0) break;\n val = (val & (-1 - (15 << vars[v[cur][1][0]]*4))) + ((val1-val2) << vars[v[cur][1][0]]*4);\n }else if(v[cur][0] == \"SET\"){\n int vall = (~vars[v[cur][2][0]] ? (val >> (vars[v[cur][2][0]]*4))&15 : stoi(v[cur][2]));\n val = (val & (-1 - (15 << vars[v[cur][1][0]]*4))) + (vall << vars[v[cur][1][0]]*4);\n }else if(v[cur][0] == \"IF\"){\n int val1 = (val >> (vars[v[cur][1][0]]*4))&15;\n if(val1) {\n if(!m.count(v[cur][2])) break;\n cur = m[v[cur][2]];\n continue;\n }\n }\n cur++;\n }\n for (int i = 0; i < 256; ++i) {\n if(~vars[i]){\n printf(\"%c=%d\\n\", i, (val >> (vars[i]*4))&15);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1080, "memory_kb": 7868, "score_of_the_acc": -0.249, "final_rank": 3 }, { "submission_id": "aoj_0330_4007473", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cctype>\n#include <bitset>\n\n#define MAX_VALUE (1000 * 16 * 16 * 16 * 16 * 16)\n\n\nenum cmd_t {\n\tCMD_ADD,\n\tCMD_SUB,\n\tCMD_SET,\n\tCMD_IF,\n\tCMD_HALT\n};\n\n\nstruct command {\n\tcmd_t type;\n\tint var1;\n\tint var2;\n\tint var3;\n\tint opt;\n};\n\n\nstruct vm_stat {\n\tint pc;\n\tint env[5];\n\n\tvm_stat(void) {\n\t\tpc = 0;\n\t\tenv[0] = 0;\n\t\tenv[1] = 0;\n\t\tenv[2] = 0;\n\t\tenv[3] = 0;\n\t\tenv[4] = 0;\n\t}\n\n\tsize_t encode(void) {\n\t\tint code = pc;\n\t\tcode = code * 16 + env[0];\n\t\tcode = code * 16 + env[1];\n\t\tcode = code * 16 + env[2];\n\t\tcode = code * 16 + env[3];\n\t\tcode = code * 16 + env[4];\n\t\treturn code;\n\t}\n};\n\n\nstatic std::bitset<MAX_VALUE> stats;\nstatic command plist[50];\nstatic int n;\nstatic int lines[1001];\n\nint main(int argc, char* argv[]) {\n\tint atom['z' - 'a' + 1];\n\tint atom_n = 0;\n\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\tatom[i - 'a'] = -1;\n\t}\t\n\tfor (int i = 0; i <= 1000; ++i) {\n\t\tlines[i] = -1;\n\t}\n\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; ++i) {\n\t\tchar s[16];\n\t\tint d;\n\n\t\tscanf(\"%d\", &d);\n\t\tlines[d] = i;\n\t\tscanf(\" %s\", s);\n\t\tif (strcmp(s, \"ADD\") == 0) {\n\t\t\tplist[i].type = CMD_ADD;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SUB\") == 0) {\n\t\t\tplist[i].type = CMD_SUB;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SET\") == 0) {\n\t\t\tplist[i].type = CMD_SET;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var2 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"IF\") == 0) {\n\t\t\tplist[i].type = CMD_IF;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %d\", &d);\n\t\t\tplist[i].opt = d;\n\t\t}\n\t\telse {\n\t\t\tplist[i].type = CMD_HALT;\n\t\t}\n\t}\n\n\tvm_stat stat;\n\tbool halted = true;\n\tstats.set(stat.encode());\n\tfor (;;) {\n\t\tconst command c = plist[stat.pc++];\n\n\t\tif (c.type == CMD_ADD) {\n\t\t\tconst int rvalue = stat.env[c.var2] + (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SUB) {\n\t\t\tconst int rvalue = stat.env[c.var2] - (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SET) {\n\t\t\tif (c.var2 < 0) {\n\t\t\t\tstat.env[c.var1] = c.opt;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tstat.env[c.var1] = stat.env[c.var2];\n\t\t\t}\n\t\t}\n\t\telse if (c.type == CMD_IF) {\n\t\t\tif (stat.env[c.var1]) {\n\t\t\t\tif (lines[c.opt] == -1) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tstat.pc = lines[c.opt];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\n\t\tif (stats.test(stat.encode())) {\n\t\t\thalted = false;\n\t\t\tbreak;\n\t\t}\n\t\tif (stat.pc >= n) {\n\t\t\tbreak;\n\t\t}\n\t\tstats.set(stat.encode());\n\t}\n\n\tif (halted) {\n\t\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\t\tif (atom[i - 'a'] >= 0) {\n\t\t\t\tprintf(\"%c=%d\\n\", i, stat.env[atom[i - 'a']]);\n\t\t\t}\n\t\t}\n\t}\n\telse {\n\t\tputs(\"inf\");\n\t}\n\n\treturn EXIT_SUCCESS;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 130760, "score_of_the_acc": -1.0364, "final_rank": 11 }, { "submission_id": "aoj_0330_4007472", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cctype>\n#include <bitset>\n\n#define MAX_VALUE (1000 * 16 * 16 * 16 * 16 * 16)\n\n\nenum cmd_t {\n\tCMD_ADD,\n\tCMD_SUB,\n\tCMD_SET,\n\tCMD_IF,\n\tCMD_HALT\n};\n\n\nstruct command {\n\tcmd_t type;\n\tint var1;\n\tint var2;\n\tint var3;\n\tint opt;\n};\n\n\nstruct vm_stat {\n\tint pc;\n\tint env[5];\n\n\tvm_stat(void) {\n\t\tpc = 0;\n\t\tenv[0] = 0;\n\t\tenv[1] = 0;\n\t\tenv[2] = 0;\n\t\tenv[3] = 0;\n\t\tenv[4] = 0;\n\t}\n\n\tsize_t encode(void) {\n\t\tint code = pc;\n\t\tcode = code * 16 + env[0];\n\t\tcode = code * 16 + env[1];\n\t\tcode = code * 16 + env[2];\n\t\tcode = code * 16 + env[3];\n\t\tcode = code * 16 + env[4];\n\t\treturn code;\n\t}\n};\n\n\nstatic std::bitset<MAX_VALUE> stats;\nstatic command plist[50];\nstatic int n;\nstatic int lines[1001];\n\nint main(int argc, char* argv[]) {\n\tint atom['z' - 'a' + 1];\n\tint atom_n = 0;\n\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\tatom[i - 'a'] = -1;\n\t}\t\n\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; ++i) {\n\t\tchar s[16];\n\t\tint d;\n\n\t\tscanf(\"%d\", &d);\n\t\tlines[d] = i;\n\t\tscanf(\" %s\", s);\n\t\tif (strcmp(s, \"ADD\") == 0) {\n\t\t\tplist[i].type = CMD_ADD;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SUB\") == 0) {\n\t\t\tplist[i].type = CMD_SUB;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SET\") == 0) {\n\t\t\tplist[i].type = CMD_SET;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var2 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"IF\") == 0) {\n\t\t\tplist[i].type = CMD_IF;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %d\", &d);\n\t\t\tplist[i].opt = d;\n\t\t}\n\t\telse {\n\t\t\tplist[i].type = CMD_HALT;\n\t\t}\n\t}\n\n\tvm_stat stat;\n\tbool halted = true;\n\tstats.set(stat.encode());\n\tfor (;;) {\n\t\tconst command c = plist[stat.pc++];\n\n\t\tif (c.type == CMD_ADD) {\n\t\t\tconst int rvalue = stat.env[c.var2] + (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SUB) {\n\t\t\tconst int rvalue = stat.env[c.var2] - (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SET) {\n\t\t\tif (c.var2 < 0) {\n\t\t\t\tstat.env[c.var1] = c.opt;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tstat.env[c.var1] = stat.env[c.var2];\n\t\t\t}\n\t\t}\n\t\telse if (c.type == CMD_IF) {\n\t\t\tif (stat.env[c.var1]) {\n\t\t\t\tstat.pc = lines[c.opt];\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\n\t\tif (stats.test(stat.encode())) {\n\t\t\thalted = false;\n\t\t\tbreak;\n\t\t}\n\t\tif (stat.pc >= n) {\n\t\t\tbreak;\n\t\t}\n\t\tstats.set(stat.encode());\n\t}\n\n\tif (halted) {\n\t\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\t\tif (atom[i - 'a'] >= 0) {\n\t\t\t\tprintf(\"%c=%d\\n\", i, stat.env[atom[i - 'a']]);\n\t\t\t}\n\t\t}\n\t}\n\telse {\n\t\tputs(\"inf\");\n\t}\n\n\treturn EXIT_SUCCESS;\n}", "accuracy": 0.6666666666666666, "time_ms": 30, "memory_kb": 130696, "score_of_the_acc": -0.9995, "final_rank": 17 }, { "submission_id": "aoj_0330_4007469", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cctype>\n#include <bitset>\n\n#define MAX_VALUE (1000 * 16 * 16 * 16 * 16 * 16)\n\n\nenum cmd_t {\n\tCMD_ADD,\n\tCMD_SUB,\n\tCMD_SET,\n\tCMD_IF,\n\tCMD_HALT\n};\n\n\nstruct command {\n\tcmd_t type;\n\tint var1;\n\tint var2;\n\tint var3;\n\tint opt;\n};\n\n\nstruct vm_stat {\n\tint pc;\n\tint env[5];\n\n\tvm_stat(void) {\n\t\tpc = 0;\n\t\tenv[0] = 0;\n\t\tenv[1] = 0;\n\t\tenv[2] = 0;\n\t\tenv[3] = 0;\n\t\tenv[4] = 0;\n\t}\n\n\tsize_t encode(void) {\n\t\tint code = pc;\n\t\tcode = code * 16 + env[0];\n\t\tcode = code * 16 + env[1];\n\t\tcode = code * 16 + env[2];\n\t\tcode = code * 16 + env[3];\n\t\tcode = code * 16 + env[4];\n\t\treturn code;\n\t}\n};\n\n\nstatic std::bitset<MAX_VALUE> stats;\nstatic command plist[50];\nstatic int n;\nstatic int lines[1001];\n\nint main(int argc, char* argv[]) {\n\tint atom['z' - 'a' + 1];\n\tint atom_n = 0;\n\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\tatom[i - 'a'] = -1;\n\t}\t\n\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; ++i) {\n\t\tchar s[16];\n\t\tint d;\n\n\t\tscanf(\"%d\", &d);\n\t\tlines[d] = i;\n\t\tscanf(\" %s\", s);\n\t\tif (strcmp(s, \"ADD\") == 0) {\n\t\t\tplist[i].type = CMD_ADD;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SUB\") == 0) {\n\t\t\tplist[i].type = CMD_SUB;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var3 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var3 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"SET\") == 0) {\n\t\t\tplist[i].type = CMD_SET;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (isdigit(*s)) {\n\t\t\t\tplist[i].var2 = -1;\n\t\t\t\tplist[i].opt = atoi(s);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t\t}\n\t\t\t\tplist[i].var2 = atom[*s - 'a'];\n\t\t\t}\n\t\t}\n\t\telse if (strcmp(s, \"IF\") == 0) {\n\t\t\tplist[i].type = CMD_IF;\n\t\t\tscanf(\" %s\", s);\n\t\t\tif (atom[*s - 'a'] == -1) {\n\t\t\t\tatom[*s - 'a'] = atom_n++;\n\t\t\t}\n\t\t\tplist[i].var1 = atom[*s - 'a'];\n\t\t\tscanf(\" %d\", &d);\n\t\t\tplist[i].opt = d;\n\t\t}\n\t\telse {\n\t\t\tplist[i].type = CMD_HALT;\n\t\t}\n\t}\n\n\tvm_stat stat;\n\tbool halted = true;\n\tstats.set(stat.encode());\n\tfor (;;) {\n\t\tconst command c = plist[stat.pc++];\n\n\t\tif (c.type == CMD_ADD) {\n\t\t\tconst int rvalue = stat.env[c.var2] + (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SUB) {\n\t\t\tconst int rvalue = stat.env[c.var2] - (c.var3 < 0 ? c.opt : stat.env[c.var3]);\n\t\t\tif (rvalue < 0 || 16 <= rvalue) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tstat.env[c.var1] = rvalue;\n\t\t}\n\t\telse if (c.type == CMD_SET) {\n\t\t\tif (c.var2 < 0) {\n\t\t\t\tstat.env[c.var1] = c.opt;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tstat.env[c.var1] = stat.env[c.var2];\n\t\t\t}\n\t\t}\n\t\telse if (c.type == CMD_IF) {\n\t\t\tif (stat.env[c.var1]) {\n\t\t\t\tstat.pc = lines[c.opt];\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\n\t\tif (stats.test(stat.encode())) {\n\t\t\thalted = false;\n\t\t\tbreak;\n\t\t}\n\t\tstats.set(stat.encode());\n\t}\n\n\tif (halted) {\n\t\tfor (int i = 'a'; i <= 'z'; ++i) {\n\t\t\tif (atom[i - 'a'] >= 0) {\n\t\t\t\tprintf(\"%c=%d\\n\", i, stat.env[atom[i - 'a']]);\n\t\t\t}\n\t\t}\n\t}\n\telse {\n\t\tputs(\"inf\");\n\t}\n\n\treturn EXIT_SUCCESS;\n}", "accuracy": 0.3333333333333333, "time_ms": 30, "memory_kb": 130620, "score_of_the_acc": -0.9989, "final_rank": 20 }, { "submission_id": "aoj_0330_3968429", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nint main() {\n ll N;\n cin >> N;\n using s = string;\n vector<tuple<s, s, s, s>> P(N);\n map<ll, ll> L;\n map<s, ll> V;\n vector<s> S;\n rep(i, N) {\n ll A;\n s B, C, D, E;\n cin >> A >> B;\n if (B == \"ADD\" || B == \"SUB\") {\n cin >> C >> D >> E;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n if (!('0' <= E[0] && E[0] <= '9')) {\n S.push_back(E);\n }\n } else if (B == \"SET\" || B == \"IF\") {\n cin >> C >> D;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n }\n P[i] = make_tuple(B, C, D, E);\n L[A] = i + 1;\n }\n sort(S.begin(), S.end());\n S.erase(unique(S.begin(), S.end()), S.end());\n ll line = 0;\n rep(loop, 40000000) {\n s B, C, D, E;\n tie(B, C, D, E) = P[line];\n if (B == \"ADD\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] + stoi(E) > 15) {\n break;\n }\n V[C] = V[D] + stoi(E);\n } else {\n if (V[D] + V[E] > 15) {\n break;\n }\n V[C] = V[D] + V[E];\n }\n } else if (B == \"SUB\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] - stoi(E) < 0) {\n break;\n }\n V[C] = V[D] - stoi(E);\n } else {\n if (V[D] - V[E] < 0) {\n break;\n }\n V[C] = V[D] - V[E];\n }\n } else if (B == \"SET\") {\n if ('0' <= D[0] && D[0] <= '9') {\n V[C] = stoi(D);\n } else {\n V[C] = V[D];\n }\n } else if (B == \"IF\") {\n if (V[C]) {\n line = L[stoi(D)] - 1;\n if (line == -1) break;\n if (loop + 1 == 40000000) {\n return puts(\"inf\") & 0;\n }\n continue;\n }\n } else if (B == \"HALT\") {\n break;\n }\n if (++line == N) break;\n if (loop + 1 == 40000000) {\n return puts(\"inf\") & 0;\n }\n }\n for (auto i : S) cout << i << '=' << V[i] << endl;\n}", "accuracy": 1, "time_ms": 4180, "memory_kb": 3220, "score_of_the_acc": -0.8388, "final_rank": 9 }, { "submission_id": "aoj_0330_3968401", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nint main() {\n ll N;\n cin >> N;\n using s = string;\n vector<tuple<s, s, s, s>> P(N);\n map<ll, ll> L;\n map<s, ll> V;\n vector<s> S;\n rep(i, N) {\n ll A;\n s B, C, D, E;\n cin >> A >> B;\n if (B == \"ADD\" || B == \"SUB\") {\n cin >> C >> D >> E;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n if (!('0' <= E[0] && E[0] <= '9')) {\n S.push_back(E);\n }\n } else if (B == \"SET\" || B == \"IF\") {\n cin >> C >> D;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n }\n P[i] = make_tuple(B, C, D, E);\n L[A] = i + 1;\n }\n sort(S.begin(), S.end());\n S.erase(unique(S.begin(), S.end()), S.end());\n ll line = 0;\n rep(loop, 1000000) {\n s B, C, D, E;\n tie(B, C, D, E) = P[line];\n if (B == \"ADD\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] + stoi(E) > 15) {\n break;\n }\n V[C] = V[D] + stoi(E);\n } else {\n if (V[D] + V[E] > 15) {\n break;\n }\n V[C] = V[D] + V[E];\n }\n } else if (B == \"SUB\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] - stoi(E) < 0) {\n break;\n }\n V[C] = V[D] - stoi(E);\n } else {\n if (V[D] - V[E] < 0) {\n break;\n }\n V[C] = V[D] - V[E];\n }\n } else if (B == \"SET\") {\n if ('0' <= D[0] && D[0] <= '9') {\n V[C] = stoi(D);\n } else {\n V[C] = V[D];\n }\n } else if (B == \"IF\") {\n if (V[C]) {\n line = L[stoi(D)] - 1;\n if (line == -1) break;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n continue;\n }\n } else if (B == \"HALT\") {\n break;\n }\n if (++line == N) break;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n }\n for (auto i : S) cout << i << '=' << V[i] << endl;\n}", "accuracy": 0.8333333333333334, "time_ms": 90, "memory_kb": 3232, "score_of_the_acc": -0.0127, "final_rank": 12 }, { "submission_id": "aoj_0330_3968399", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nint main() {\n ll N;\n cin >> N;\n using s = string;\n vector<tuple<s, s, s, s>> P(N);\n map<ll, ll> L;\n map<s, ll> V;\n vector<s> S;\n rep(i, N) {\n ll A;\n s B, C, D, E;\n cin >> A >> B;\n if (B == \"ADD\" || B == \"SUB\") {\n cin >> C >> D >> E;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n if (!('0' <= E[0] && E[0] <= '9')) {\n S.push_back(E);\n }\n } else if (B == \"SET\" || B == \"IF\") {\n cin >> C >> D;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n }\n P[i] = make_tuple(B, C, D, E);\n L[A] = i + 1;\n }\n sort(S.begin(), S.end());\n S.erase(unique(S.begin(), S.end()), S.end());\n ll line = 0;\n rep(loop, 1000000) {\n s B, C, D, E;\n tie(B, C, D, E) = P[line];\n if (B == \"ADD\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] + stoi(E) > 15) {\n break;\n }\n V[C] = V[D] + stoi(E);\n } else {\n if (V[D] + V[E] > 15) {\n break;\n }\n V[C] = V[D] + V[E];\n }\n } else if (B == \"SUB\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] - stoi(E) < 0) {\n break;\n }\n V[C] = V[D] - stoi(E);\n } else {\n if (V[D] - V[E] < 0) {\n break;\n }\n V[C] = V[D] - V[E];\n }\n } else if (B == \"SET\") {\n if ('0' <= D[0] && D[0] <= '9') {\n V[C] = stoi(D);\n } else {\n V[C] = V[D];\n }\n } else if (B == \"IF\") {\n if (V[C]) {\n line = L[stoi(D)] - 1;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n continue;\n }\n } else if (B == \"HALT\") {\n break;\n }\n if (++line == N) break;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n }\n for (auto i : S) cout << i << '=' << V[i] << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 90, "memory_kb": 3212, "score_of_the_acc": -0.0125, "final_rank": 15 }, { "submission_id": "aoj_0330_3968397", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nint main() {\n ll N;\n cin >> N;\n using s = string;\n vector<tuple<s, s, s, s>> P(N);\n map<ll, ll> L;\n map<s, ll> V;\n vector<s> S;\n rep(i, N) {\n ll A;\n s B, C, D, E;\n cin >> A >> B;\n if (B == \"ADD\" || B == \"SUB\") {\n cin >> C >> D >> E;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n if (!('0' <= E[0] && E[0] <= '9')) {\n S.push_back(E);\n }\n } else if (B == \"SET\" || B == \"IF\") {\n cin >> C >> D;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n }\n P[i] = make_tuple(B, C, D, E);\n L[A] = i + 1;\n }\n sort(S.begin(), S.end());\n S.erase(unique(S.begin(), S.end()), S.end());\n ll line = 0;\n rep(loop, 1000000) {\n s B, C, D, E;\n tie(B, C, D, E) = P[line];\n if (B == \"ADD\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] + stoi(E) > 0) {\n break;\n }\n V[C] = V[D] + stoi(E);\n } else {\n if (V[D] + V[E] > 15) {\n break;\n }\n V[C] = V[D] + V[E];\n }\n } else if (B == \"SUB\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] - stoi(E) < 0) {\n break;\n }\n V[C] = V[D] - stoi(E);\n } else {\n if (V[D] - V[E] < 0) {\n break;\n }\n V[C] = V[D] - V[E];\n }\n } else if (B == \"SET\") {\n if ('0' <= D[0] && D[0] <= '9') {\n V[C] = stoi(D);\n } else {\n V[C] = V[D];\n }\n } else if (B == \"IF\") {\n if (V[C]) {\n line = L[stoi(D)] - 1;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n continue;\n }\n } else if (B == \"HALT\") {\n break;\n }\n if (++line == N) break;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n }\n for (auto i : S) cout << i << '=' << V[i] << endl;\n}", "accuracy": 0.3333333333333333, "time_ms": 90, "memory_kb": 3236, "score_of_the_acc": -0.0127, "final_rank": 19 }, { "submission_id": "aoj_0330_3968394", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n\nint main() {\n ll N;\n cin >> N;\n using s = string;\n vector<tuple<s, s, s, s>> P(N);\n map<ll, ll> L;\n map<s, ll> V;\n vector<s> S;\n rep(i, N) {\n ll A;\n s B, C, D, E;\n cin >> A >> B;\n if (B == \"ADD\" || B == \"SUB\") {\n cin >> C >> D >> E;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n if (!('0' <= E[0] && E[0] <= '9')) {\n S.push_back(E);\n }\n } else if (B == \"SET\" || B == \"IF\") {\n cin >> C >> D;\n if (!('0' <= C[0] && C[0] <= '9')) {\n S.push_back(C);\n }\n if (!('0' <= D[0] && D[0] <= '9')) {\n S.push_back(D);\n }\n }\n P[i] = make_tuple(B, C, D, E);\n L[A] = i + 1;\n }\n sort(S.begin(), S.end());\n S.erase(unique(S.begin(), S.end()), S.end());\n ll line = 0;\n rep(loop, 1000000) {\n s B, C, D, E;\n tie(B, C, D, E) = P[line];\n if (B == \"ADD\") {\n if ('0' <= E[0] && E[0] <= '9') {\n V[C] = V[D] + stoi(E);\n } else {\n V[C] = V[D] + V[E];\n }\n } else if (B == \"SUB\") {\n if ('0' <= E[0] && E[0] <= '9') {\n if (V[D] - stoi(E) < 0) {\n break;\n }\n V[C] = V[D] - stoi(E);\n } else {\n if (V[D] - V[E] < 0) {\n break;\n }\n V[C] = V[D] - V[E];\n }\n } else if (B == \"SET\") {\n if ('0' <= D[0] && D[0] <= '9') {\n V[C] = stoi(D);\n } else {\n V[C] = V[D];\n }\n } else if (B == \"IF\") {\n if (V[C]) {\n line = L[stoi(D)] - 1;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n continue;\n }\n } else if (B == \"HALT\") {\n break;\n }\n if (++line == N) break;\n if (loop + 1 == 1000000) {\n return puts(\"inf\") & 0;\n }\n }\n for (auto i : S) cout << i << '=' << V[i] << endl;\n}", "accuracy": 0.5833333333333334, "time_ms": 90, "memory_kb": 3164, "score_of_the_acc": -0.0121, "final_rank": 18 }, { "submission_id": "aoj_0330_3964814", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nint main() {\n\tint Q;\n\tcin >> Q;\n\tvector<int> ln(Q), c1(Q), c2(Q), c3(Q); vector<string> tp(Q), v1(Q), v2(Q), v3(Q);\n\tvector<string> varlist;\n\tfunction<bool(string)> is_number = [&](string str) {\n\t\tfor (int i = 0; i < str.size(); ++i) {\n\t\t\tif (!('0' <= str[i] && str[i] <= '9')) {\n\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t\treturn true;\n\t};\n\tfunction<int(string)> get_index = [&](string varname) {\n\t\tint ptr = find(varlist.begin(), varlist.end(), varname) - varlist.begin();\n\t\treturn ptr;\n\t};\n\tfor (int i = 0; i < Q; ++i) {\n\t\tcin >> ln[i] >> tp[i];\n\t\tif (tp[i] == \"ADD\" || tp[i] == \"SUB\") {\n\t\t\tcin >> v1[i] >> v2[i] >> v3[i];\n\t\t\tvarlist.push_back(v1[i]);\n\t\t\tif (!is_number(v2[i])) varlist.push_back(v2[i]);\n\t\t\tif (!is_number(v3[i])) varlist.push_back(v3[i]);\n\t\t}\n\t\tif (tp[i] == \"SET\") {\n\t\t\tcin >> v1[i] >> v2[i];\n\t\t\tvarlist.push_back(v1[i]);\n\t\t\tif (!is_number(v2[i])) varlist.push_back(v2[i]);\n\t\t}\n\t\tif (tp[i] == \"IF\") {\n\t\t\tcin >> v1[i] >> v2[i];\n\t\t\tvarlist.push_back(v1[i]);\n\t\t}\n\t\tif (tp[i] == \"HALT\") {\n\t\t\t// input nothing\n\t\t}\n\t}\n\tsort(varlist.begin(), varlist.end());\n\tvarlist.erase(unique(varlist.begin(), varlist.end()), varlist.end());\n\tint S = varlist.size();\n\tfor (int i = 0; i < Q; ++i) {\n\t\tif (tp[i] == \"ADD\" || tp[i] == \"SUB\") {\n\t\t\tc1[i] = get_index(v1[i]) - S;\n\t\t\tc2[i] = (is_number(v2[i]) ? stoi(v2[i]) : get_index(v2[i]) - S);\n\t\t\tc3[i] = (is_number(v3[i]) ? stoi(v3[i]) : get_index(v3[i]) - S);\n\t\t}\n\t\tif (tp[i] == \"SET\") {\n\t\t\tc1[i] = get_index(v1[i]) - S;\n\t\t\tc2[i] = (is_number(v2[i]) ? stoi(v2[i]) : get_index(v2[i]) - S);\n\t\t}\n\t\tif (tp[i] == \"IF\") {\n\t\t\tc1[i] = get_index(v1[i]) - S;\n\t\t\tc2[i] = find(ln.begin(), ln.end(), stoi(v2[i])) - ln.begin(); // if not found, c2[i] will be Q\n\t\t}\n\t\tif (tp[i] == \"HALT\") {\n\t\t\t// do nothing\n\t\t}\n\t}\n\tvector<int> vars(S, 0);\n\tint cur = 0;\n\tbool halted = true;\n\tvector<vector<bool> > vis(Q, vector<bool>(1 << (S * 4), false));\n\twhile (cur < Q) {\n\t\tint h = 0;\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\th = h * 16 + vars[i];\n\t\t}\n\t\tif (vis[cur][h]) {\n\t\t\thalted = false;\n\t\t\tbreak;\n\t\t}\n\t\tvis[cur][h] = true;\n\t\tvector<int> prevars = vars;\n\t\tif (tp[cur] == \"ADD\") {\n\t\t\tvars[c1[cur] + S] = (c2[cur] >= 0 ? c2[cur] : vars[c2[cur] + S]) + (c3[cur] >= 0 ? c3[cur] : vars[c3[cur] + S]);\n\t\t}\n\t\tif (tp[cur] == \"SUB\") {\n\t\t\tvars[c1[cur] + S] = (c2[cur] >= 0 ? c2[cur] : vars[c2[cur] + S]) - (c3[cur] >= 0 ? c3[cur] : vars[c3[cur] + S]);\n\t\t}\n\t\tif (tp[cur] == \"SET\") {\n\t\t\tvars[c1[cur] + S] = (c2[cur] >= 0 ? c2[cur] : vars[c2[cur] + S]);\n\t\t}\n\t\tif (tp[cur] == \"IF\") {\n\t\t\tif (vars[c1[cur] + S] != 0) {\n\t\t\t\tcur = c2[cur];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t}\n\t\tif (tp[cur] == \"HALT\") {\n\t\t\tbreak;\n\t\t}\n\t\tif (vars[c1[cur] + S] < 0 || 16 <= vars[c1[cur] + S]) {\n\t\t\tvars = prevars;\n\t\t\tbreak;\n\t\t}\n\t\t++cur;\n\t}\n\tif (!halted) {\n\t\tcout << \"inf\" << endl;\n\t}\n\telse {\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tcout << varlist[i] << \"=\" << vars[i] << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1690, "memory_kb": 9744, "score_of_the_acc": -0.3869, "final_rank": 5 }, { "submission_id": "aoj_0330_3942837", "code_snippet": "#include <iostream>\n#include <chrono>\n#include <string>\n#include <map>\nusing namespace std;\nusing ll = long long;\n\nstruct Line {\n\tstring op;\n\tstring v1, v2, v3;\n\t\n\tLine () {};\n\tLine (string &op, string &v1, string &v2, string &v3):\n\top(op), v1(v1), v2(v2), v3(v3) {};\n};\n\nint n;\nmap<string, int> var;\nLine program[1005];\nint i2n[1005];\n\nint main() {\n\tfor (int i = 0; i < 1005; i++) {\n\t\ti2n[i] = -1;\n\t}\n\t\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tint l;\n\t\tstring op;\n\t\tstring v1, v2, v3;\n\t\t\n\t\tcin >> l >> op;\n\t\tif (op == \"ADD\" || op == \"SUB\") {\n\t\t\tcin >> v1 >> v2 >> v3;\n\t\t\t\n\t\t\tif ('a' <= v1[0] && v1[0] <= 'z') {\n\t\t\t\tvar[v1] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z') {\n\t\t\t\tvar[v2] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z') {\n\t\t\t\tvar[v3] = 0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (op == \"SET\" || op == \"IF\") {\n\t\t\tcin >> v1 >> v2;\n\t\t\tif ('a' <= v1[0] && v1[0] <= 'z') {\n\t\t\t\tvar[v1] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z') {\n\t\t\t\tvar[v2] = 0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tLine v(op, v1, v2, v3);\n\t\tprogram[i] = v;\n\t\ti2n[l] = i;\n\t}\n\t\n\tint pc = 0;\n\tauto start = chrono::system_clock::now();\n\tauto end = chrono::system_clock::now();\n\tdouble elapsed = chrono::duration_cast<std::chrono::milliseconds>(end-start).count();\n\twhile (elapsed <= 4500.0) {\n\t\tif (pc < 0 || pc >= n ||\n\t\t\tprogram[pc].op.empty()) {\n\t\t\tfor (auto &x:var) {\n\t\t\t\tcout << x.first << '=' << x.second << endl;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tLine p = program[pc]; pc++;\n\t\tbool over_flow = false;\n\t\t\n\t\tif (p.op == \"ADD\") {\n\t\t\tif ('a' <= p.v3[0] && p.v3[0] <= 'z') {\n\t\t\t\tif (var[p.v2] + var[p.v3] >= 16) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] + var[p.v3];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (var[p.v2] + stoi(p.v3) >= 16) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] + stoi(p.v3);\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"SUB\") {\n\t\t\tif ('a' <= p.v3[0] && p.v3[0] <= 'z') {\n\t\t\t\tif (var[p.v2] - var[p.v3] < 0) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] - var[p.v3];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (var[p.v2] - stoi(p.v3) < 0) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] - stoi(p.v3);\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"SET\") {\n\t\t\tif ('a' <= p.v2[0] && p.v2[0] <= 'z') {\n\t\t\t\tvar[p.v1] = var[p.v2];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint v = stoi(p.v2);\n\t\t\t\tif (v >= 0 && v < 16) {\n\t\t\t\t\tvar[p.v1] = v;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tover_flow = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"IF\") {\n\t\t\tif (var[p.v1]) {\n\t\t\t\tpc = i2n[stoi(p.v2)];\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"HALT\" ||\n\t\t\tover_flow) {\n\t\t\tfor (auto &x:var) {\n\t\t\t\tcout << x.first << '=' << x.second << endl;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tend = chrono::system_clock::now();\n\t\telapsed = chrono::duration_cast<std::chrono::milliseconds>(end-start).count();\n\t}\n\t\n\tcout << \"inf\" << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4490, "memory_kb": 3216, "score_of_the_acc": -0.9014, "final_rank": 10 }, { "submission_id": "aoj_0330_3942829", "code_snippet": "#include <iostream>\n#include <chrono>\n#include <string>\n#include <map>\nusing namespace std;\nusing ll = long long;\n\nstruct Line {\n\tstring op;\n\tstring v1, v2, v3;\n\t\n\tLine () {};\n\tLine (string &op, string &v1, string &v2, string &v3):\n\top(op), v1(v1), v2(v2), v3(v3) {};\n};\n\nint n;\nmap<string, int> var;\nLine program[1005];\nint i2n[1005];\n\nint main() {\n\tfor (int i = 0; i < 1005; i++) {\n\t\ti2n[i] = -1;\n\t}\n\t\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tint l;\n\t\tstring op;\n\t\tstring v1, v2, v3;\n\t\t\n\t\tcin >> l >> op;\n\t\tif (op == \"ADD\" || op == \"SUB\") {\n\t\t\tcin >> v1 >> v2 >> v3;\n\t\t\t\n\t\t\tif ('a' <= v1[0] && v1[0] <= 'z') {\n\t\t\t\tvar[v1] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z') {\n\t\t\t\tvar[v2] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v3[0] && v3[0] <= 'z') {\n\t\t\t\tvar[v3] = 0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (op == \"SET\" || op == \"IF\") {\n\t\t\tcin >> v1 >> v2;\n\t\t\tif ('a' <= v1[0] && v1[0] <= 'z') {\n\t\t\t\tvar[v1] = 0;\n\t\t\t}\n\t\t\tif ('a' <= v2[0] && v2[0] <= 'z') {\n\t\t\t\tvar[v2] = 0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tLine v(op, v1, v2, v3);\n\t\tprogram[i] = v;\n\t\ti2n[l] = i;\n\t}\n\t\n\tint pc = 0;\n\tauto start = chrono::system_clock::now();\n\tauto end = chrono::system_clock::now();\n\tdouble elapsed = chrono::duration_cast<std::chrono::milliseconds>(end-start).count();\n\twhile (elapsed <= 4500.0) {\n\t\tif (program[pc].op.empty() ||\n\t\t\tpc >= n) {\n\t\t\tfor (auto &x:var) {\n\t\t\t\tcout << x.first << '=' << x.second << endl;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tLine p = program[pc]; pc++;\n\t\tbool over_flow = false;\n\t\t\n\t\tif (p.op == \"ADD\") {\n\t\t\tif ('a' <= p.v3[0] && p.v3[0] <= 'z') {\n\t\t\t\tif (var[p.v2] + var[p.v3] >= 16) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] + var[p.v3];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (var[p.v2] + stoi(p.v3) >= 16) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] + stoi(p.v3);\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"SUB\") {\n\t\t\tif ('a' <= p.v3[0] && p.v3[0] <= 'z') {\n\t\t\t\tif (var[p.v2] - var[p.v3] < 0) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] - var[p.v3];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (var[p.v2] - stoi(p.v3) < 0) over_flow = true;\n\t\t\t\telse var[p.v1] = var[p.v2] - stoi(p.v3);\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"SET\") {\n\t\t\tif ('a' <= p.v2[0] && p.v2[0] <= 'z') {\n\t\t\t\tvar[p.v1] = var[p.v2];\n\t\t\t}\n\t\t\telse {\n\t\t\t\tint v = stoi(p.v2);\n\t\t\t\tif (v >= 0 && v < 16) {\n\t\t\t\t\tvar[p.v1] = v;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tover_flow = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"IF\") {\n\t\t\tif (var[p.v1]) {\n\t\t\t\tpc = i2n[stoi(p.v2)];\n\t\t\t}\n\t\t}\n\t\t\n\t\tif (p.op == \"HALT\" ||\n\t\t\tover_flow) {\n\t\t\tfor (auto &x:var) {\n\t\t\t\tcout << x.first << '=' << x.second << endl;\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tend = chrono::system_clock::now();\n\t\telapsed = chrono::duration_cast<std::chrono::milliseconds>(end-start).count();\n\t}\n\t\n\tcout << \"inf\" << endl;\n\t\n\treturn 0;\n}", "accuracy": 0.6666666666666666, "time_ms": 4490, "memory_kb": 3184, "score_of_the_acc": -0.9012, "final_rank": 16 } ]
aoj_0350_cpp
実数既約分数化 実数のうち、小数部が循環するものと有限桁のものは分数として表すことができます。 分数で表すことができる実数が与えられたとき、その実数と等しい既約分数(それ以上約分できない分数)を出力するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 str 1行に、変換したい実数を表す文字列 str が与えられる。実数の値は 0 より大きい。文字列は数字か「.」、「(」、「)」を含む、長さが 3 以上 8 以下の文字列である。「.」は小数点、「(」は数字の循環の始まり、「)」は数字の循環の終わりを示す。整数部にも小数部にも、必ず1桁以上の数字が与えられるとする。ただし、循環小数が与えられた場合、文字列は以下の条件を満たす。 循環の始まりと終わりのペアは、小数点の右側に一度だけ現れる。 循環の終わりを示す「)」は、文字列の末尾に現れる。 循環の始まりと終わりの間には、必ず1桁以上の数字が与えられる。 Output 実数を既約分数で表した形式(分子の整数に続けて「/」区切りで分母の整数を並べたもの)で出力する。 Sample Input 1 0.(3) Sample Output 1 1/3 Sample Input 2 1.0 Sample Output 2 1/1 Sample Input 3 5.2(143) Sample Output 3 52091/9990 Sample Input 4 0.0739 Sample Output 4 739/10000
[ { "submission_id": "aoj_0350_3592199", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <cstring>\n#include <climits>\n#include <vector>\n#include <map>\n#include <set>\n#include <list>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <iostream>\n#include <string>\n\n#define REP(i,n) for(long long i=0;i<n;++i)\n#define REPR(i,n) for(long long i=n;i>=0;--i)\n#define REPI(itr,v) for(auto itr=v.begin();itr!=v.end();++itr)\n#define REPIR(itr,v) for(auto itr=v.rbegin();itr!=v.rend();++itr)\n#define FOR(i,a,b) for(long long i=a;i<b;++i)\n#define SORT(v,n) sort(v, v+n)\n#define SORTV(v) sort(v.begin(), v.end())\n#define ALL(v) v.begin(),v.end()\n#define llong long long\n#define INF 999999999\n#define MOD 1000000007\n#define pb push_back\n#define pf push_front\n#define MP make_pair\n#define SV(v) {for(long long sitr=0;sitr<v.size();++sitr){cin>>v[sitr];}}\n\nint dx[] = {0, 0, -1, 1};\nint dy[] = {1, -1, 0, 0};\n\nusing namespace std;\n\ntypedef pair<int,int> pii;\n\nvoid kiyaku(int a, int b){\n int n = max(a, b);\n for(int i = 2; i < n; ++i){\n if(a % i == 0 && b % i == 0){\n while(a % i == 0 && b % i == 0){\n a /= i; b /= i;\n }\n }\n }\n cout << a << \"/\" << b << endl;\n}\n\nint main(){\n\n string s;\n cin >> s;\n\n int len = s.length();\n \n //()ない時\n bool f = false;\n REP(i,len){\n if(s[i] == '('){\n f = true;\n }\n }\n\n int a, b;\n\n if(f){\n string tmp = \"\", tmp2 = \"\";\n int cnt = 0, cnt2 = 0;\n int p_idx;\n bool kakko = false;\n REP(i,len-1){\n if(s[i] == '('){\n kakko = true;\n cnt2 = i - p_idx - 1;\n continue;\n }else if(s[i] == '.'){\n cnt = (len-1) - i - 2;\n p_idx = i;\n }else{\n tmp += s[i];\n if(!kakko){\n tmp2 += s[i];\n }\n }\n }\n a = stoi(tmp) - stoi(tmp2);\n b = pow(10, cnt) - pow(10, cnt2);\n kiyaku(a, b);\n }else{\n string tmp = \"\";\n int cnt = 0;\n REP(i,len){\n if(s[i] == '.'){\n cnt = len - 1 - i;\n }else{\n tmp += (s[i]);\n }\n }\n b = pow(10, cnt);\n a = stoi(tmp);\n kiyaku(a, b);\n return 0;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3380, "score_of_the_acc": -1, "final_rank": 1 }, { "submission_id": "aoj_0350_2591683", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <string>\n#include <cmath>\n#include <cstdio>\n\nusing namespace std;\n\ndouble _stod(string str) {\n double integ = 0, dec = 0;\n int i, len = str.size();\n for (i = 0; i < len; ++i) { //??´??°??¨\n if (str[i] == '.')\n break;\n integ = integ * 10 + (str[i] - '0');\n }\n i++;\n double k = 10;\n for (; i < len; ++i, k *= 10) { //????????§\n if (str[i] == '(')\n break;\n dec += (str[i] - '0') / k;\n }\n i++;\n int loop = 0, ll = 0;\n for (; i < len; ++i) {\n if (str[i] == ')')\n break;\n loop = loop * 10 + (str[i] - '0');\n ll++;\n }\n k /= 10;\n for (int i = 0; i < 100; ++i) {\n for (int j = 0; j < ll; ++j)\n k *= 10;\n dec += loop / k;\n }\n \n return integ + dec;\n}\n\nvoid _div(long long &n, long long &m) {\n while (1) {\n bool check = true;\n for (int i = 2; i <= m; ++i) {\n if (n % i == 0 && m % i == 0) {\n n /= i;\n m /= i;\n check = false;\n }\n }\n if (check)\n break;\n }\n}\n\nint main() {\n string str;\n cin >> str;\n \n double base = _stod(str);\n \n long long nmax = 1e12, mmax = 1e6, nans, mans;\n double emin = 1e9, e;\n for (int m = 1; m <= mmax; ++m) { //??????\n long long l = 1, r = nmax, mid;\n while (r - l > 1) {\n mid = (l + r) / 2;\n if (fabs((double)l / m - base) < fabs((double)r / m - base))\n r = mid;\n else\n l = mid;\n }\n e = fabs((double)r / m - base);\n if (emin > e) {\n emin = e;\n nans = r;\n mans = m;\n }\n }\n \n _div(nans, mans);\n \n printf(\"%lld/%lld\\n\", nans, mans);\n \n return 0;\n}", "accuracy": 0.26666666666666666, "time_ms": 320, "memory_kb": 3216, "score_of_the_acc": -1, "final_rank": 2 }, { "submission_id": "aoj_0350_2591676", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <string>\n#include <cmath>\n#include <cstdio>\n\nusing namespace std;\n\ndouble _stod(string str) {\n double integ = 0, dec = 0;\n int i, len = str.size();\n for (i = 0; i < len; ++i) { //??´??°??¨\n if (str[i] == '.')\n break;\n integ = integ * 10 + (str[i] - '0');\n }\n i++;\n double k = 10;\n for (; i < len; ++i, k *= 10) { //????????§\n if (str[i] == '(')\n break;\n dec += (str[i] - '0') / k;\n }\n i++;\n int loop = 0, ll = 0;\n for (; i < len; ++i) {\n if (str[i] == ')')\n break;\n loop = loop * 10 + (str[i] - '0');\n ll++;\n }\n k /= 10;\n for (int i = 0; i < 10; ++i) {\n for (int j = 0; j < ll; ++j)\n k *= 10;\n dec += loop / k;\n }\n \n return integ + dec;\n}\n\nvoid _div(long long &n, long long &m) {\n while (1) {\n bool check = true;\n for (int i = 2; i <= m; ++i) {\n if (n % i == 0 && m % i == 0) {\n n /= i;\n m /= i;\n check = false;\n }\n }\n if (check)\n break;\n }\n}\n\nint main() {\n string str;\n cin >> str;\n \n double base = _stod(str);\n \n long long nmax = 1e12, mmax = 1e6, nans, mans;\n double emin = 1e9, e;\n for (int m = 1; m <= mmax; ++m) { //??????\n long long l = 1, r = nmax, mid;\n while (r - l > 1) {\n mid = (l + r) / 2;\n if (fabs((double)l / m - base) < fabs((double)r / m - base))\n r = mid;\n else\n l = mid;\n }\n e = fabs((double)r / m - base);\n if (emin > e) {\n emin = e;\n nans = r;\n mans = m;\n }\n }\n \n _div(nans, mans);\n \n printf(\"%lld/%lld\\n\", nans, mans);\n \n return 0;\n}", "accuracy": 0.26666666666666666, "time_ms": 310, "memory_kb": 3284, "score_of_the_acc": -1.3813, "final_rank": 4 }, { "submission_id": "aoj_0350_2591674", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <string>\n#include <cmath>\n#include <cstdio>\n\nusing namespace std;\n\ndouble _stod(string str) {\n double integ = 0, dec = 0;\n int i, len = str.size();\n for (i = 0; i < len; ++i) { //??´??°??¨\n if (str[i] == '.')\n break;\n integ = integ * 10 + (str[i] - '0');\n }\n i++;\n double k = 10;\n for (; i < len; ++i, k *= 10) { //????????§\n if (str[i] == '(')\n break;\n dec += (str[i] - '0') / k;\n }\n i++;\n int loop = 0, ll = 0;\n for (; i < len; ++i) {\n if (str[i] == ')')\n break;\n loop = loop * 10 + (str[i] - '0');\n ll++;\n }\n k /= 10;\n for (int i = 0; i < 10; ++i) {\n for (int j = 0; j < ll; ++j)\n k *= 10;\n dec += loop / k;\n }\n \n return integ + dec;\n}\n\nvoid _div(long long &n, long long &m) {\n while (1) {\n bool check = true;\n for (int i = 2; i <= m; ++i) {\n if (n % i == 0 && m % i == 0) {\n n /= i;\n m /= i;\n check = false;\n }\n }\n if (check)\n break;\n }\n}\n\nint main() {\n string str;\n cin >> str;\n \n double base = _stod(str);\n \n long long nmax = 1e10, mmax = 1e6, nans, mans;\n double emin = 1e9, e;\n for (int m = 1; m <= mmax; ++m) { //??????\n long long l = 1, r = nmax, mid;\n while (r - l > 1) {\n mid = (l + r) / 2;\n if (fabs((double)l / m - base) < fabs((double)r / m - base))\n r = mid;\n else\n l = mid;\n }\n e = fabs((double)r / m - base);\n if (emin > e) {\n emin = e;\n nans = r;\n mans = m;\n }\n }\n \n _div(nans, mans);\n \n printf(\"%lld/%lld\\n\", nans, mans);\n \n return 0;\n}", "accuracy": 0.26666666666666666, "time_ms": 260, "memory_kb": 3272, "score_of_the_acc": -1.1415, "final_rank": 3 } ]
aoj_0348_cpp
必勝7並べ トランプを使ったゲームに「7並べ」があります。ここではそれを簡単にしたゲームを考えます。1から13の番号がそれぞれ書かれた13枚のカードを使って7並べをします。対戦は、2者だけで次のようにゲームを進めます。 「場」に7のカードを置きます。 2者には、残りのカードがランダムに6枚ずつ配布されます。 先手の手持ちのカードのうち、場にあるカードの番号と連続する番号のカードがあれば、そのうちの1枚を場に置きます。プレイヤーはカードが置ける場合には必ず置かなければいけません。無いときに限り、カードを出さずに相手の番になります。 後手も同じ要領で、手持ちのカードを場に置きます。 手順3と4を繰り返して、一方の手持ちのカードがなくなるまで続けます。先に手持ちのカードをすべて場に置けた方が勝者となります。 先手のカードの番号が与えられたとき、後手がどのようにカードを出してきても、先手が勝つ手順が少なくとも一つあるかを判定して出力するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N game 1 game 2 : game N 1行目には、ゲームを行う回数 N (1 ≤ N ≤ 100) が与えられる。続く N 行に、 i 回目のゲームの情報 game i が与えられる。各 game i は、以下の形式で与えられる。 f 1 f 2 f 3 f 4 f 5 f 6 f j (1 ≤ f j ≤ 13, f j ≠ 7) は先手に配られるカードの番号である。ただし、同じ行に番号が重複して現れることはない( j ≠ k について f j ≠ f k )。 Output 各ゲームについて、後手がどのようにカードを出してきても、先手が勝つ手順が少なくとも一つある場合「yes」、そうでない場合「no」と1行に出力する。 Sample Input 1 5 1 2 3 4 5 6 1 3 5 6 8 4 1 2 3 4 5 8 1 2 4 5 10 11 1 2 3 6 9 11 Sample Output 1 yes yes no yes no
[ { "submission_id": "aoj_0348_3683470", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <set>\nusing namespace std;\n\nbool judge(vector<int> A, vector<int> B){\n do{\n int i = 0, j = 0;\n int mi = 7, ma = 7;\n while(i < 6 and j < 6){\n if(A[i] == mi-1 or A[i] == ma+1){\n mi = min(A[i],mi), ma = max(ma,A[i]);\n ++i;\n }else{\n for(int k = i+1; k < 6; ++k){\n if(A[k] == mi-1 or A[k] == ma+1){\n i = 0;\n j = 6;\n break;\n }\n }\n }\n if(j == 6) break;\n if(!(B[j] != mi-1 and B[j] != ma+1)){\n mi = min(B[j],mi), ma = max(ma,B[j]);\n ++j;\n }else{\n for(int k = j+1; k < 6; ++k){\n if(B[k] == mi-1 or B[k] == ma+1){\n i = 6;\n break;\n }\n }\n }\n }\n if(i == 6)\n return true;\n }while(next_permutation(A.begin(),A.end()));\n return false;\n}\n\n\nint main(){\n int N;\n cin >> N;\n for(int i = 0; i < N; ++i){\n vector<int> A(6), B;\n set<int> BB{1,2,3,4,5,6,8,9,10,11,12,13};\n for(int i = 0; i < 6; ++i) {\n cin >> A[i];\n BB.erase(A[i]);\n }\n sort(A.begin(),A.end());\n B = vector<int>(BB.begin(), BB.end());\n // for(int i = 1; i <= 13; ++i){\n // bool f = false;\n // for(int j = 1; j <= 6; ++j){\n // if(j == 7){\n // f = true;\n // continue;\n // }\n // if(A[j] == i){\n // f = true;\n // break;\n // }\n // }\n // if(not f) B.push_back(i);\n // }\n\n // for (auto a: A) cerr << a << \" \";\n // cerr << endl;\n // for (auto b: B) cerr << b << \" \";\n // cerr << endl;\n\n string ans = \"yes\";\n do{\n if(not judge(A,B)){\n ans = \"no\";\n // for(auto b : B){\n // cerr << b << \" \";\n // }\n // cerr << endl;\n break;\n }\n }while(next_permutation(B.begin(),B.end()));\n cout << ans << endl;\n }\n}", "accuracy": 0.42857142857142855, "time_ms": 110, "memory_kb": 3168, "score_of_the_acc": -1.0243, "final_rank": 4 }, { "submission_id": "aoj_0348_2729560", "code_snippet": "/*input\n5\n1 2 3 4 5 6\n1 3 5 6 8 4\n1 2 3 4 5 8\n1 2 4 5 10 11\n1 2 3 6 9 11\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n\nint dp[30][1 << 13], Alice[13], Bob[13];\nint mask1, mask2;\n\nbool solve(int turn, int mask) {\n\tif(((mask & mask1) == mask1) && ((turn & 1) == 0)) return 1;\n\tif(((mask & mask2) == mask2) && (turn & 1)) return 0;\n\tif(dp[turn][mask] != -1) return dp[turn][mask];\n\n\tint ans, flag = 0;\n\tif(turn & 1) {\n\t\tans = 0;\n\t\tfor(int i = 0; i < 13; ++i) if(i != 6)\n\t\t\tif(Alice[i] && ((mask & (1 << i)) == 0)) {\n\t\t\t\tint ok = 0;\n\t\t\t\tif(i > 0) ok |= mask & (1 << (i - 1));\n\t\t\t\tif(i < 12) ok |= mask & (1 << (i + 1));\n\t\t\t\tif(ok) ans |= solve(turn + 1, mask | (1 << i)), flag = 1;\n\t\t\t}\n\t\tif(!flag) ans = solve(turn + 1, mask);\n\t}\n\telse {\n\t\tans = 1;\n\t\tfor(int i = 0; i < 13; ++i)\n\t\t\tif(Bob[i] && ((mask & (1 << i)) == 0)) {\n\t\t\t\tint ok = 0;\n\t\t\t\tif(i > 0) ok |= mask & (1 << (i - 1));\n\t\t\t\tif(i < 12) ok |= mask & (1 << (i + 1));\n\t\t\t\tif(ok) ans &= solve(turn + 1, mask | (1 << i)), flag = 1;\n\t\t\t}\n\t\tif(!flag) ans = solve(turn + 1, mask);\n\t}\n\treturn (dp[turn][mask] = ans);\n}\n\nint main(){\n\tint test; scanf(\"%d\", &test);\n\n\twhile(test --) {\n\t\tmask1 = 0, mask2 = 1 << 6;\n\t\tmemset(dp, - 1, sizeof dp);\n\t\tmemset(Alice, 0, sizeof Alice);\n\t\tmemset(Bob, 0, sizeof Bob);\n\n\t\tfor(int i = 0; i < 6; ++i) {\n\t\t\tint a; scanf(\"%d\", &a);\n\t\t\tmask1 |= 1 << (a - 1);\n\t\t\tAlice[a - 1] = 1;\n\t\t}\n\n\t\tfor(int i = 0; i < 13; ++i)\n\t\t\tif((mask1 & (1 << i)) == 0) mask2 |= 1 << i, Bob[i] = 1;\n\n\t\tputs(solve(1, 1 << 6) ? \"yes\" : \"no\");\n\t}\n\t// cerr << fixed << setprecision(6) << (double)clock() / CLOCKS_PER_SEC << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4132, "score_of_the_acc": -1, "final_rank": 3 }, { "submission_id": "aoj_0348_2729495", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint T, f[2][1 << 13], a_win, b_win;\nbool a[2][13];\n\nbool in_mask(int j, int i) {\n\tif(j < 0 || j > 12) return false;\n\tif((1 << j) & i) return true;\n\treturn false;\n}\n\nint main() {\n\tcin >> T;\n\twhile(T--) {\n\t\ta_win = b_win = 0;\n\t\tfor(int i = 0; i < 13; ++i) a[0][i] = a[1][i] = false;\n\t\tfor(int i = 0; i < 6; ++i) {\n\t\t\tint x;\n\t\t\tcin >> x;\n\t\t\tx--;\n\t\t\ta[0][x] = true; a_win += 1 << x;\n\t\t}\n\t\tfor(int i = 0; i < 13; ++i) if(!a[0][i] && i != 6) a[1][i] = true, b_win += 1 << i;\n\t\tmemset(f, -1, sizeof f);\n\t\tfor(int i = (1 << 13) - 1; i >= 0; --i) {\n\t\t\tint st = 1, nd = 0; bool flag0 = true;\n\t\t\tfor(int j = 0; j < 13; ++j)\n\t\t\t\tif(a[0][j] && !in_mask(j, i) && (in_mask(j - 1, i) || in_mask(j + 1, i))) {\n\t\t\t\t\t//if(i == (1 << 6)) cout << j << endl;\n\t\t\t\t\tst = 0, nd = 1, flag0 = false;\n\t\t\t\t}\n\t\t\tf[st][i] = 0;\n\t\t\t//if(i == (1 << 6)) cout << st << ' ' << nd << ' ' << flag0 << endl;\n\t\t\tfor(int j = 0; j < 13; ++j)\n\t\t\t\tif(a[st][j] && !in_mask(j, i) && (in_mask(j - 1, i) || in_mask(j + 1, i)))\n\t\t\t\t\tif(f[nd][i ^ (1 << j)] != -1)\n\t\t\t\t\t\tf[st][i] |= !f[nd][i ^ (1 << j)];\n\t\t\tf[nd][i] = 0; bool flag1 = true;\n\t\t\tfor(int j = 0; j < 13; ++j)\n\t\t\t\tif(a[nd][j] && !in_mask(j, i) && (in_mask(j - 1, i) || in_mask(j + 1, i)))\n\t\t\t\t\tif(f[st][i ^ (1 << j)] != -1)\n\t\t\t\t\t\tf[nd][i] |= !f[st][i ^ (1 << j)], flag1 = false;\n\t\t\tif(flag1) f[nd][i] = !f[st][i];\n\t\t\tif((i & a_win) == a_win && (i && b_win) != b_win) f[1][i] = 0;\n\t\t\tif((i & b_win) == b_win && (i && a_win) != a_win) f[0][i] = 0;\n\t\t}\n\t\tint mask = 0;\n\t\tfor(int i = 0; i < 6; ++i) mask += 1 << i;\n\t\tfor(int i = 7; i < 12; ++i) mask += 1 << i;\n\t\tif(f[0][1 << 6]) cout << \"yes\\n\"; else cout << \"no\\n\";\n\t}\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3144, "score_of_the_acc": -0.6, "final_rank": 2 }, { "submission_id": "aoj_0348_2097796", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\n\nbool check(vector<int> a) {\n int x=7,y=7;\n for(int i=0; i<6; i++) {\n if(a[i]<7&&a[i]>x) return 0;\n if(a[i]>7&&a[i]<y) return 0;\n x=min(x,a[i]);\n y=max(y,a[i]);\n }\n return 1;\n}\n\nint main() {\n int T;\n cin >> T;\n while(T--) {\n vector<int> a(6),b;\n for(int i=0; i<6; i++) cin >> a[i];\n for(int j=1; j<14; j++) {\n if(j==7) continue;\n bool f=1;\n for(int i=0; i<6; i++) if(a[i]==j) f=0;\n if(f) b.push_back(j);\n }\n sort(a.begin(),a.end());\n sort(b.begin(),b.end());\n do {\n if(!check(a)) continue;\n bool f=1;\n do {\n if(!check(b)) continue;\n P p=P(7,7);\n int x,y;\n bool u[6],u2[6];\n memset(u,0,sizeof(u));\n memset(u2,0,sizeof(u2));\n for(x=0,y=0;x<6&&y<6;) {\n for(int i=0; i<6; i++) {\n if(!u[i]) {\n if(a[i]==p.first-1){p.first--,u[i]=1,x++;break;}\n else if(a[i]==p.second+1){p.second++,u[i]=1,x++;break;}\n }\n }\n for(int i=0; i<6; i++) {\n if(!u2[i]) {\n if(b[i]==p.first-1){p.first--,u2[i]=1,y++;break;}\n else if(b[i]==p.second+1){p.second++,u2[i]=1,y++;break;}\n }\n }\n }\n if(x<6) f=0;\n } while(next_permutation(b.begin(),b.end()));\n if(f) {\n cout << \"yes\" << endl;\n goto end;\n }\n } while(next_permutation(a.begin(),a.end()));\n cout << \"no\" << endl;\n end:;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3148, "score_of_the_acc": -0.204, "final_rank": 1 } ]
aoj_0343_cpp
Programming Contest II Every year, Byakko University holds a programming contest. The contest starts with all teams having zero points, and points are added according to their answers. In this contest, the teams are ranked in order of their scores. When the total number of teams is N , each team is assigned a number from 1 to N . If the teams have the same score, the team with the smaller number will be ranked higher. Byakko University is developing a ranking system for spectators to make the contest more exciting. As a development team member, you are asked to make a program that is part of this system. Make a program to update the scores, and report the numbers and scores of the teams in a given rank, according to the given command. Input The input is given in the following format. N C command 1 command 2 : command C In the first line, the number of teams N (2 ≤ N ≤ 100000) and the number of commands C (1 ≤ C ≤ 100000) are given. In the following C lines, commands are given. Each command is given in the following format. 0 t p or 1 m When the first number is 0, it indicates an update command, and when it is 1, it indicates a report command. In the update command, add the score p (1 ≤ p ≤ 10 9 ), given as an integer, to the team with the given number t (1 ≤ t ≤ N ). In the report command, report the number and score of the team in a given rank m (1 ≤ m ≤ N ). However, the report command must appear at least once. Output For each report command, output the number and score of the team in a given rank in a line, separated by space. Sample Input 1 3 11 0 2 5 0 1 5 0 3 4 1 1 1 2 1 3 0 3 2 1 1 0 2 1 1 2 1 3 Sample Output 1 1 5 2 5 3 4 3 6 3 6 1 5 Sample Input 2 5 2 1 1 1 2 Sample Output 2 1 0 2 0
[ { "submission_id": "aoj_0343_10867159", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nnamespace atcoder {\n\n namespace internal {\n\n#ifndef _MSC_VER\n template <class T>\n using is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\n template <class T>\n using is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_signed_int = typename std::conditional<(is_integral<T>::value&&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int =\n typename std::conditional<(is_integral<T>::value&&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\n template <class T> using is_integral = typename std::is_integral<T>;\n\n template <class T>\n using is_signed_int =\n typename std::conditional<is_integral<T>::value&& std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int =\n typename std::conditional<is_integral<T>::value&&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\n template <class T>\n using is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\n template <class T>\n using is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\n template <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n }\n\n}\nnamespace atcoder {\n\n template <class T> struct fenwick_tree {\n using U = internal::to_unsigned_t<T>;\n\n public:\n fenwick_tree() : _n(0) {}\n fenwick_tree(int n) : _n(n), data(n) {}\n\n void add(int p, T x) {\n assert(0 <= p && p < _n);\n p++;\n while (p <= _n) {\n data[p - 1] += U(x);\n p += p & -p;\n }\n }\n\n T sum(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n return sum(r) - sum(l);\n }\n\n private:\n int _n;\n std::vector<U> data;\n\n U sum(int r) {\n U s = 0;\n while (r > 0) {\n s += data[r - 1];\n r -= r & -r;\n }\n return s;\n }\n };\n\n}\nusing namespace atcoder;\ntemplate<typename T>\nvoid normalize(vector<T>& ary) {\n sort(ary.begin(), ary.end());\n ary.erase(unique(ary.begin(), ary.end()), ary.end());\n}\ntemplate<typename T>\nint comp(const T& num, const vector<T>& ary) {\n return lower_bound(ary.begin(), ary.end(), num) - ary.begin();\n}\nint main() {\n int n, c; cin >> n >> c;\n vector<vector<int>> qs;\n vector<ll> point(n);\n vector<ll> ps(1);\n rep(i, c) {\n int j; cin >> j;\n if (j == 0) {\n int t, p; cin >> t >> p;\n t--;\n point[t] += p;\n ps.push_back(point[t]);\n qs.push_back({ j,t,p });\n }\n else {\n int m; cin >> m;\n qs.push_back({ j,m });\n }\n }\n normalize(ps);\n vector<vector<int>> idx(ps.size());\n rep(i, n)idx[0].push_back(i);\n rep(i, n)point[i] = 0;\n rep(i, c)if (qs[i][0] == 0) {\n int t = qs[i][1], p = qs[i][2];\n point[t] += p;\n idx[comp(point[t], ps)].push_back(t);\n }\n rep(i, ps.size())normalize(idx[i]);\n fenwick_tree<int> fwAll(ps.size());\n vector<fenwick_tree<int>> fw(ps.size());\n rep(i, ps.size())fw[i] = fenwick_tree<int>(idx[i].size());\n fwAll.add(0, n);\n rep(i, n)fw[0].add(i, 1);\n rep(i, n)point[i] = 0;\n rep(i, c) {\n if (qs[i][0] == 0) {\n int t = qs[i][1], p = qs[i][2];\n int cp = comp(point[t], ps);\n int ct = comp(t, idx[cp]);\n fwAll.add(cp, -1);\n fw[cp].add(ct, -1);\n point[t] += p;\n cp = comp(point[t], ps);\n ct = comp(t, idx[cp]);\n fwAll.add(cp, 1);\n fw[cp].add(ct, 1);\n }\n else {\n int m = qs[i][1];\n int left = 0, right = ps.size();\n while (left + 1 < right) {\n int mid = (left + right) / 2;\n if (fwAll.sum(mid, ps.size()) >= m)left = mid;\n else right = mid;\n }\n m -= fwAll.sum(left + 1, ps.size());\n int left2 = 0, right2 = idx[left].size() - 1;\n while (left2 < right2) {\n int mid2 = (left2 + right2) / 2;\n if (fw[left].sum(0, mid2 + 1) >= m)right2 = mid2;\n else left2 = mid2 + 1;\n }\n printf(\"%d %lld\\n\", idx[left][left2] + 1, ps[left]);\n }\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 23656, "score_of_the_acc": -0.2693, "final_rank": 5 }, { "submission_id": "aoj_0343_10862818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first;\n#define se second;\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\n#include <ext/pb_ds/assoc_container.hpp>\nusing namespace __gnu_pbds;\ntemplate <typename T>\nusing ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\nint main(){\n int N,C;\n cin>>N>>C;\n vector<long> P(N,0);\n ordered_set<pair<long,int>> st;\n rep(i,N) st.insert({0, i});\n while(C--){\n int o;\n cin>>o;\n if(o==0){\n int t,p;\n cin>>t>>p;\n t--;\n st.erase({P[t], t});\n P[t]-=p;\n st.insert({P[t], t});\n }\n else{\n int m;\n cin>>m;\n m--;\n auto it=st.find_by_order(m);\n cout<<it->second+1<<\" \"<<-(it->first)<<\"\\n\";\n }\n }\n\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 10192, "score_of_the_acc": -0.3519, "final_rank": 8 }, { "submission_id": "aoj_0343_10858955", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include <atcoder/all>\nusing namespace atcoder;\n\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\nusing mint = modint1000000007;\n// using mint = modint;\n// mint::set_mod(m);\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>;\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>;\n//-----------------------------------\n\n//-------------2.配列系--------------\n\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v) {\n rep(j, size(v)) i >> v[j];\n return i;\n}\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n//--------3.コード短縮化とか---------\nconst double PI = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++)\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--)\n\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n\n#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end());\n#define vc_rotate(v) rotate(v.begin(), v.begin() + 1, v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(), v.end())\n\n//-------------------------------\n\n//---------4.グリッド系----------\nvector<int> dx = {1, 0, -1, 0}; // dx={1,1,0,-1,-1,-1,0,1};\nvector<int> dy = {0, 1, 0, -1}; // dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w = -1) {\n if (w == -1) {\n w = h;\n }\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_rotate(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 時計回りに90°回転\n// #define vvl_rotate(v) {ll n = size(v);vvl\n// nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_rotate(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 文字列版 時計回りに90°回転\n// #define vs_rotate(v) {ll n = size(v);vs\n// nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n#define vvl_transpos(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n#define vs_transpos(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n\n//--------------------------------\n\n//-----------5.数学系--------------\n#define euclid(x, y) ((x) * (x) + (y) * (y)) // ユークリッド距離 2乗のまま\n#define manhattan(x1, x2, y1, y2) \\\n (abs(x1 - x2) + abs(y1 - y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate <class T>\nT tousa_sum1(T l, T d, T r) { // 初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate <class T>\nT tousa_sum2(T a, T d, T n) { // 初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) { // 初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\nmint touhi_sum(mint a, mint r,\n ll n) { // 初項,公比,項数で等比数列の総和を求める\n if (r == 1) {\n return a * n;\n }\n mint bunsi = a * (r.pow(n) - mint(1));\n mint bunbo = r - 1;\n return bunsi / bunbo;\n}\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\n#define print_vec(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << \" \"; \\\n cout << endl; \\\n } // 一次元配列を出力する(改行なし)\n\n#define vc_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << endl; \\\n } // 一次元配列を出力する(改行あり)\n#define vv_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n//----------------------------------------------\n// Segment Tree\ntemplate <class Monoid>\nstruct SegmentTree {\n using Func = function<Monoid(Monoid, Monoid)>;\n\n // core member\n int N;\n Func OP;\n Monoid IDENTITY;\n\n // inner data\n int log, offset;\n vector<Monoid> dat;\n\n // constructor\n SegmentTree() {}\n SegmentTree(int n, const Func &op, const Monoid &identity) {\n init(n, op, identity);\n }\n SegmentTree(const vector<Monoid> &v, const Func &op,\n const Monoid &identity) {\n init(v, op, identity);\n }\n void init(int n, const Func &op, const Monoid &identity) {\n N = n;\n OP = op;\n IDENTITY = identity;\n log = 0, offset = 1;\n while (offset < N) ++log, offset <<= 1;\n dat.assign(offset * 2, IDENTITY);\n }\n void init(const vector<Monoid> &v, const Func &op, const Monoid &identity) {\n init((int)v.size(), op, identity);\n build(v);\n }\n void pull(int k) { dat[k] = OP(dat[k * 2], dat[k * 2 + 1]); }\n void build(const vector<Monoid> &v) {\n assert(N == (int)v.size());\n for (int i = 0; i < N; ++i) dat[i + offset] = v[i];\n for (int k = offset - 1; k > 0; --k) pull(k);\n }\n int size() const { return N; }\n Monoid operator[](int i) const { return dat[i + offset]; }\n\n // update A[i], i is 0-indexed, O(log N)\n void set(int i, const Monoid &v) {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] = v;\n while (k >>= 1) pull(k);\n }\n\n void add(int i, const Monoid &v) {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] += v;\n while (k >>= 1) pull(k);\n }\n\n // get [l, r), l and r are 0-indexed, O(log N)\n Monoid prod(int l, int r) {\n assert(0 <= l && l <= r && r <= N);\n Monoid val_left = IDENTITY, val_right = IDENTITY;\n l += offset, r += offset;\n for (; l < r; l >>= 1, r >>= 1) {\n if (l & 1) val_left = OP(val_left, dat[l++]);\n if (r & 1) val_right = OP(dat[--r], val_right);\n }\n return OP(val_left, val_right);\n }\n Monoid all_prod() { return dat[1]; }\n\n // get max r that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int max_right(const function<bool(Monoid)> f, int l = 0) {\n if (l == N) return N;\n l += offset;\n Monoid sum = IDENTITY;\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(OP(sum, dat[l]))) {\n while (l < offset) {\n l = l * 2;\n if (f(OP(sum, dat[l]))) {\n sum = OP(sum, dat[l]);\n ++l;\n }\n }\n return l - offset;\n }\n sum = OP(sum, dat[l]);\n ++l;\n } while ((l & -l) != l); // stop if l = 2^e\n return N;\n }\n\n // get min l that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int min_left(const function<bool(Monoid)> f, int r = -1) {\n if (r == 0) return 0;\n if (r == -1) r = N;\n r += offset;\n Monoid sum = IDENTITY;\n do {\n --r;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(OP(dat[r], sum))) {\n while (r < offset) {\n r = r * 2 + 1;\n if (f(OP(dat[r], sum))) {\n sum = OP(dat[r], sum);\n --r;\n }\n }\n return r + 1 - offset;\n }\n sum = OP(dat[r], sum);\n } while ((r & -r) != r);\n return 0;\n }\n\n // debug\n friend ostream &operator<<(ostream &s, const SegmentTree &seg) {\n for (int i = 0; i < (int)seg.size(); ++i) {\n s << seg[i];\n if (i != (int)seg.size() - 1) s << \" \";\n }\n return s;\n }\n};\n\nvector<int> compression(vector<pll> vec) {\n vector<pll> c = vec;\n sort(c.begin(), c.end());\n c.erase(unique(c.begin(), c.end()), c.end());\n\n vector<int> res(vec.size());\n for (int i = 0; i < vec.size(); i++) {\n res[i] = lower_bound(c.begin(), c.end(), vec[i]) - c.begin();\n }\n return res;\n}\n\nint k;\nbool f(int x) { return x < k; }\n\nvoid solve() { return; }\nint op(int a, int b) { return a + b; }\nint e = 0;\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(10);\n\n int n, q;\n cin >> n >> q;\n\n vector<ll> s(n);\n vector<ll> v(q), p(q), m(q);\n\n rep(i, q) {\n int t;\n cin >> t;\n if (t == 0) {\n int idx, x;\n cin >> idx >> x, idx--;\n\n s[idx] += x;\n v[i] = s[idx];\n p[i] = idx;\n } else {\n int x;\n cin >> x;\n m[i] = x;\n }\n }\n\n vector<pll> vec(n + q);\n rep(i, n) vec[i] = {0, -i};\n rep(i, q) vec[n + i] = {v[i], -p[i]};\n\n // 座圧\n auto r = compression(vec);\n\n sort(all(vec));\n vc_unique(vec);\n int l = r.size();\n\n // 人iが対応する位置 (座圧後の値)\n vector<ll> pos(n);\n\n rep(i, n) pos[i] = n - i - 1;\n // セグ木上で二分探索\n SegmentTree<int> seg(l, op, e);\n rep(i, n) seg.set(i, 1);\n\n rep(i, q) {\n if (v[i]) {\n // idx -> 人\n int idx = p[i];\n seg.set(pos[idx], 0);\n\n pos[idx] = r[n + i];\n seg.set(pos[idx], 1);\n\n } else {\n k = m[i];\n int idx = seg.min_left(f);\n idx--;\n cout << -vec[idx].second + 1 << \" \" << vec[idx].first << '\\n';\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 16732, "score_of_the_acc": -0.1744, "final_rank": 1 }, { "submission_id": "aoj_0343_10858924", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include <atcoder/all>\nusing namespace atcoder;\n\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\nusing mint = modint1000000007;\n// using mint = modint;\n// mint::set_mod(m);\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>;\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>;\n//-----------------------------------\n\n//-------------2.配列系--------------\n\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v) {\n rep(j, size(v)) i >> v[j];\n return i;\n}\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n//--------3.コード短縮化とか---------\nconst double PI = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++)\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--)\n\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n\n#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end());\n#define vc_rotate(v) rotate(v.begin(), v.begin() + 1, v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(), v.end())\n\n//-------------------------------\n\n//---------4.グリッド系----------\nvector<int> dx = {1, 0, -1, 0}; // dx={1,1,0,-1,-1,-1,0,1};\nvector<int> dy = {0, 1, 0, -1}; // dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w = -1) {\n if (w == -1) {\n w = h;\n }\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_rotate(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 時計回りに90°回転\n// #define vvl_rotate(v) {ll n = size(v);vvl\n// nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_rotate(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 文字列版 時計回りに90°回転\n// #define vs_rotate(v) {ll n = size(v);vs\n// nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n#define vvl_transpos(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n#define vs_transpos(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n\n//--------------------------------\n\n//-----------5.数学系--------------\n#define euclid(x, y) ((x) * (x) + (y) * (y)) // ユークリッド距離 2乗のまま\n#define manhattan(x1, x2, y1, y2) \\\n (abs(x1 - x2) + abs(y1 - y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate <class T>\nT tousa_sum1(T l, T d, T r) { // 初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate <class T>\nT tousa_sum2(T a, T d, T n) { // 初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) { // 初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\nmint touhi_sum(mint a, mint r,\n ll n) { // 初項,公比,項数で等比数列の総和を求める\n if (r == 1) {\n return a * n;\n }\n mint bunsi = a * (r.pow(n) - mint(1));\n mint bunbo = r - 1;\n return bunsi / bunbo;\n}\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\n#define print_vec(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << \" \"; \\\n cout << endl; \\\n } // 一次元配列を出力する(改行なし)\n\n#define vc_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << endl; \\\n } // 一次元配列を出力する(改行あり)\n#define vv_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n//----------------------------------------------\n// Segment Tree\ntemplate <class Monoid>\nstruct SegmentTree {\n using Func = function<Monoid(Monoid, Monoid)>;\n\n // core member\n int N;\n Func OP;\n Monoid IDENTITY;\n\n // inner data\n int log, offset;\n vector<Monoid> dat;\n\n // constructor\n SegmentTree() {}\n SegmentTree(int n, const Func &op, const Monoid &identity) {\n init(n, op, identity);\n }\n SegmentTree(const vector<Monoid> &v, const Func &op,\n const Monoid &identity) {\n init(v, op, identity);\n }\n void init(int n, const Func &op, const Monoid &identity) {\n N = n;\n OP = op;\n IDENTITY = identity;\n log = 0, offset = 1;\n while (offset < N) ++log, offset <<= 1;\n dat.assign(offset * 2, IDENTITY);\n }\n void init(const vector<Monoid> &v, const Func &op, const Monoid &identity) {\n init((int)v.size(), op, identity);\n build(v);\n }\n void pull(int k) { dat[k] = OP(dat[k * 2], dat[k * 2 + 1]); }\n void build(const vector<Monoid> &v) {\n assert(N == (int)v.size());\n for (int i = 0; i < N; ++i) dat[i + offset] = v[i];\n for (int k = offset - 1; k > 0; --k) pull(k);\n }\n int size() const { return N; }\n Monoid operator[](int i) const { return dat[i + offset]; }\n\n // update A[i], i is 0-indexed, O(log N)\n void set(int i, const Monoid &v) {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] = v;\n while (k >>= 1) pull(k);\n }\n\n void add(int i, const Monoid &v) {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] += v;\n while (k >>= 1) pull(k);\n }\n\n // get [l, r), l and r are 0-indexed, O(log N)\n Monoid prod(int l, int r) {\n assert(0 <= l && l <= r && r <= N);\n Monoid val_left = IDENTITY, val_right = IDENTITY;\n l += offset, r += offset;\n for (; l < r; l >>= 1, r >>= 1) {\n if (l & 1) val_left = OP(val_left, dat[l++]);\n if (r & 1) val_right = OP(dat[--r], val_right);\n }\n return OP(val_left, val_right);\n }\n Monoid all_prod() { return dat[1]; }\n\n // get max r that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int max_right(const function<bool(Monoid)> f, int l = 0) {\n if (l == N) return N;\n l += offset;\n Monoid sum = IDENTITY;\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(OP(sum, dat[l]))) {\n while (l < offset) {\n l = l * 2;\n if (f(OP(sum, dat[l]))) {\n sum = OP(sum, dat[l]);\n ++l;\n }\n }\n return l - offset;\n }\n sum = OP(sum, dat[l]);\n ++l;\n } while ((l & -l) != l); // stop if l = 2^e\n return N;\n }\n\n // get min l that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int min_left(const function<bool(Monoid)> f, int r = -1) {\n if (r == 0) return 0;\n if (r == -1) r = N;\n r += offset;\n Monoid sum = IDENTITY;\n do {\n --r;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(OP(dat[r], sum))) {\n while (r < offset) {\n r = r * 2 + 1;\n if (f(OP(dat[r], sum))) {\n sum = OP(dat[r], sum);\n --r;\n }\n }\n return r + 1 - offset;\n }\n sum = OP(dat[r], sum);\n } while ((r & -r) != r);\n return 0;\n }\n\n // debug\n friend ostream &operator<<(ostream &s, const SegmentTree &seg) {\n for (int i = 0; i < (int)seg.size(); ++i) {\n s << seg[i];\n if (i != (int)seg.size() - 1) s << \" \";\n }\n return s;\n }\n};\n\nvector<int> compression(vector<pll> vec) {\n vector<pll> c = vec;\n sort(c.begin(), c.end());\n c.erase(unique(c.begin(), c.end()), c.end());\n\n vector<int> res(vec.size());\n for (int i = 0; i < vec.size(); i++) {\n res[i] = lower_bound(c.begin(), c.end(), vec[i]) - c.begin();\n }\n return res;\n}\n\nint k;\nbool f(int x) { return x < k; }\n\nvoid solve() { return; }\nint op(int a, int b) { return a + b; }\nint e = 0;\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(10);\n\n int n, q;\n cin >> n >> q;\n\n vector<ll> s(n);\n vector<ll> v(q), p(q), m(q);\n\n rep(i, q) {\n int t;\n cin >> t;\n if (t == 0) {\n int idx, x;\n cin >> idx >> x, idx--;\n\n s[idx] += x;\n v[i] = s[idx];\n p[i] = idx;\n } else {\n int x;\n cin >> x;\n m[i] = x;\n }\n }\n\n vector<pll> vec(n + q);\n rep(i, n) vec[i] = {0, -i};\n rep(i, q) vec[n + i] = {v[i], -p[i]};\n\n // 座圧\n auto r = compression(vec);\n\n sort(all(vec));\n vc_unique(vec);\n int l = r.size();\n\n // 座圧後の値から元の値を復元\n vector<pll> rev(l);\n rep(i, l) rev[r[i]] = vec[r[i]];\n\n // 人iが対応する位置 (座圧後の値)\n vector<ll> pos(n);\n\n iota(all(pos), 0);\n // セグ木上で二分探索\n SegmentTree<int> seg(l, op, e);\n rep(i, n) seg.set(i, 1);\n\n rep(i, q) {\n if (v[i]) {\n // idx -> 人\n int idx = p[i];\n seg.set(pos[idx], 0);\n\n pos[idx] = r[n + i];\n seg.set(pos[idx], 1);\n\n } else {\n k = m[i];\n int idx = seg.min_left(f);\n idx--;\n cout << -rev[idx].second + 1 << \" \" << rev[idx].first << '\\n';\n }\n }\n return 0;\n}", "accuracy": 0.16666666666666666, "time_ms": 20, "memory_kb": 9492, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0343_10858480", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\ntemplate <class T>\nusing kth_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, C;\n cin >> N >> C;\n vector<ll> point(N);\n kth_set<pair<ll, int>> st; // point * -1, id\n for (int i = 0; i < N; i++) st.insert({0, i});\n while (C--) {\n int type;\n cin >> type;\n if (type == 0) {\n int t, p;\n cin >> t >> p, t--;\n st.erase({point[t] * -1, t});\n point[t] += p;\n st.insert({point[t] * -1, t});\n }\n if (type == 1) {\n int m;\n cin >> m, m--;\n auto [p, id] = *st.find_by_order(m);\n cout << id + 1 << \" \" << p * -1 << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 10368, "score_of_the_acc": -0.1994, "final_rank": 3 }, { "submission_id": "aoj_0343_10851604", "code_snippet": "#include <iostream>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n\ntypedef long long LL;\n\nusing namespace std;\nusing namespace __gnu_pbds;\n\ntypedef\ntree<\npair<LL,LL>,\n null_type,\n greater<pair<LL,LL> >,\n rb_tree_tag,\n tree_order_statistics_node_update>map_t;\n\nLL point[114514];\n\nint main()\n{\n map_t TREE;\n int n,c;\n cin >> n >> c;\n for(int i = 1;i <= n;++i)\n TREE.insert(make_pair(0,-i));\n for(int j = 0;j < c;++j)\n {\n int com;\n cin >> com;\n if(com == 0)\n {\n LL t,p;\n cin >> t >> p;\n TREE.erase(make_pair(point[t-1],-t));\n point[t-1]+=p;\n TREE.insert(make_pair(point[t-1],-t));\n }\n else\n {\n int m;\n cin >> m;\n --m;\n //cout << m << endl;\n cout << -TREE.find_by_order(m)->second << \" \" << TREE.find_by_order(m)->first << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 10396, "score_of_the_acc": -0.5843, "final_rank": 14 }, { "submission_id": "aoj_0343_10827492", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\nusing ll = long long;\n\n\ntemplate <typename T>\nstruct BinaryIndexedTree {\n int N;\n vector<T> data;\n\n BinaryIndexedTree() = default;\n\n BinaryIndexedTree(int size) { init(size); }\n\n void init(int size) {\n N = size + 2;\n data.assign(N + 1, {});\n }\n\n // get sum of [0,k]\n T sum(int k) const {\n if (k < 0) return T{}; // return 0 if k < 0\n T ret{};\n for (++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n\n // getsum of [l,r]\n inline T sum(int l, int r) const { return sum(r) - sum(l - 1); }\n\n // get value of k\n inline T operator[](int k) const { return sum(k) - sum(k - 1); }\n\n // data[k] += x\n void add(int k, T x) {\n for (++k; k < N; k += k & -k) data[k] += x;\n }\n\n // range add x to [l,r]\n void imos(int l, int r, T x) {\n add(l, x);\n add(r + 1, -x);\n }\n\n // minimize i s.t. sum(i) >= w\n int lower_bound(T w) {\n if (w <= 0) return 0;\n int x = 0;\n for (int k = 1 << __lg(N); k; k >>= 1) {\n if (x + k <= N - 1 && data[x + k] < w) {\n w -= data[x + k];\n x += k;\n }\n }\n return x;\n }\n\n // minimize i s.t. sum(i) > w\n int upper_bound(T w) {\n if (w < 0) return 0;\n int x = 0;\n for (int k = 1 << __lg(N); k; k >>= 1) {\n if (x + k <= N - 1 && data[x + k] <= w) {\n w -= data[x + k];\n x += k;\n }\n }\n return x;\n }\n};\n\nint main() {\n int N, C;cin >> N >> C;\n vector<ll> T(N, 0);\n vector<pair<ll,int>> value;\n for (int i = 0;i < N;i++) value.push_back({0LL, -i});\n vector<int> OP(C);\n vector<int> SC(C);vector<ll> TH(C);\n for (int i = 0;i < C;i++) {\n cin >> OP[i];\n if (OP[i] == 1) {\n cin >> SC[i];\n } else {\n cin >> SC[i] >> TH[i];\n SC[i]--;\n T[SC[i]] += TH[i];\n value.push_back({T[SC[i]], -SC[i]});\n }\n }\n sort(value.begin(), value.end());\n value.erase(unique(value.begin(), value.end()), value.end());\n int K = value.size();\n map<pair<ll, int>, int> tos;\n for (int i = 0;i < K;i++) tos[value[i]] = i;\n for (int i = 0;i < K;i++) {\n // cout << value[i].first << \" \" << value[i].second << \" \" << i << endl;\n }\n BinaryIndexedTree<int> CNT(K+3);\n for (int i = 0;i < N;i++) CNT.add(tos[{0, -i}], 1);\n T.assign(N, 0);\n for (int i = 0;i < C;i++) {\n if (OP[i] == 0) {\n int id = SC[i];\n ll p = TH[i];\n CNT.add(tos[{T[id], -id}], -1);\n //cout << tos[{T[id], -id}] <<\" B \" << endl;\n T[id] += p;\n CNT.add(tos[{T[id], -id}], 1);\n // cout << tos[{T[id], -id}] << \" AF \" << endl;\n } else {\n int m = SC[i];\n int ok =0 ;\n int ng = K;\n while (ng-ok > 1) {\n int mid = (ok + ng) / 2;\n // cout << \"MID \" << mid << \" \" << CNT.sum(mid, K+1) << endl;\n if (CNT.sum(mid, K+1) >= m) {\n ok = mid;\n } else {\n ng = mid;\n }\n }\n int id = -value[ok].second;\n cout <<id+1<< \" \" << T[id] <<endl ;\n \n }\n }\n //for (int i = 0;i <= K;i++) cout << i << \" \" << CNT.sum(i,i) << endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 22800, "score_of_the_acc": -0.5316, "final_rank": 13 }, { "submission_id": "aoj_0343_10064555", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, C;\n cin >> N >> C;\n\n vector<ll> P(N);\n // {point, index * -1} を降順に管理\n tree<pair<ll, int>, null_type, greater<>, rb_tree_tag, tree_order_statistics_node_update> st;\n for (int i = 0; i < N; i++) st.insert({0, -i});\n\n while (C--) {\n int type;\n cin >> type;\n if (type == 0) {\n int t, p;\n cin >> t >> p, t--;\n st.erase({P[t], -t});\n P[t] += p;\n st.insert({P[t], -t});\n }\n if (type == 1) {\n int m;\n cin >> m, m--;\n auto [point, index] = *st.find_by_order(m);\n cout << -index + 1 << ' ' << point << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 10220, "score_of_the_acc": -0.3521, "final_rank": 9 }, { "submission_id": "aoj_0343_9606698", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\n\n#define int long long\n\ntemplate<class T>\nusing pbds=tree<T, null_type, greater<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\nsigned main(){\n\tint n,q;cin>>n>>q;\n\tvector<int> a(n);\n\tpbds<pair<int,int>> tr;\n\tfor(int i=0;i<n;i++){\n\t\ttr.insert({0,-i});\n\t}\n\twhile(q--){\n\t\tint t;cin>>t;\n\t\tif(t==0){\n\t\t\tint i,p;cin>>i>>p;i--;\n\t\t\ttr.erase({a[i],-i});\n\t\t\ta[i]+=p;\n\t\t\ttr.insert({a[i],-i});\n\t\t}else{\n\t\t\tint m;cin>>m;m--;\n\t\t\tauto it=tr.find_by_order(m);\n\t\t\tcout<<-it->second+1<<\" \"<<it->first<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 10248, "score_of_the_acc": -0.5062, "final_rank": 12 }, { "submission_id": "aoj_0343_9584542", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T,T e>\nstruct segtree {\n\tvector<T> v;\n\tlong long n;\n\tfunction<T(T,T)> f;\n\tsegtree(long long n,function<T(T,T)> f) : n(n), f(f) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtree(vector<T> x,function<T(T,T)> f) : n(x.size()),f(f) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1ll;i >= 0ll;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,T b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tlong long n,c;\n\tcin >> n >> c;\n\tmap<long long,set<long long>> s;\n\tfor(long long i = 0ll;i < n;i++){\n\t\ts[0ll].insert(i);\n\t}\n\tvector<tuple<long long,long long,long long>> w(c);\n\tvector<long long> sc(n,0ll);\n\tfor(long long i = 0ll;i < c;i++){\n\t\tcin >> get<0ll>(w[i]);\n\t\tif(get<0ll>(w[i]) == 0ll){\n\t\t\tcin >> get<1ll>(w[i]) >> get<2ll>(w[i]);\n\t\t\tget<1ll>(w[i])--;\n\t\t\tsc[get<1ll>(w[i])] += get<2ll>(w[i]);\n\t\t\ts[sc[get<1ll>(w[i])]].insert(get<1ll>(w[i]));\n\t\t}else{\n\t\t\tcin >> get<1ll>(w[i]);\n\t\t}\n\t}\n\tmap<long long,map<long long,long long>> t;\n\tmap<long long,long long> r;\n\tlong long cou = 0ll;\n\t{\n\t\tfor(auto itr = s.begin();itr != s.end();itr++){\n\t\t\tfor(auto irs = itr->second.rbegin();irs != itr->second.rend();irs++){ \n\t\t\t\tt[itr->first][*irs] = cou;\n\t\t\t\tr[cou] = *irs;\n\t\t\t\tcou++;\n\t\t\t}\n\t\t}\n\t}\n\tsc.assign(n,0ll);\n\tvector<long long> tmp(cou,0ll);\n\tfor(long long i = 0ll;i < n;i++){\n\t\ttmp[i] = 1ll;\n\t}\n\tsegtree<long long,0ll> seg(tmp,[](long long a,long long b){return a + b;});\n\tfor(long long i = 0ll;i < c;i++){\n\t\tif(get<0ll>(w[i]) == 0ll){\n\t\t\tlong long it = t[sc[get<1ll>(w[i])]][get<1ll>(w[i])];\n\t\t\tseg.set(it,0ll);\n\t\t\tsc[get<1ll>(w[i])] += get<2ll>(w[i]);\n\t\t\tit = t[sc[get<1ll>(w[i])]][get<1ll>(w[i])];\n\t\t\tseg.set(it,1ll);\n\t\t}else{\n\t\t\tlong long low = 0ll,high = cou - 1ll;\n\t\t\twhile(low < high){\n\t\t\t\tlong long mid = (low + high) / 2ll;\n\t\t\t\tif(n - seg.prod(0ll,mid + 1ll) + 1ll > get<1ll>(w[i])){\n\t\t\t\t\tlow = mid + 1ll;\n\t\t\t\t}else{\n\t\t\t\t\thigh = mid;\n\t\t\t\t}\n\t\t\t}\n\t\t\tlong long it = r[low];\n\t\t\tcout << it + 1ll << \" \" << sc[it] << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 65688, "score_of_the_acc": -1.4581, "final_rank": 16 }, { "submission_id": "aoj_0343_9584541", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T,T e>\nstruct segtree {\n\tvector<T> v;\n\tlong long n;\n\tfunction<T(T,T)> f;\n\tsegtree(long long n,function<T(T,T)> f) : n(n), f(f) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtree(vector<T> x,function<T(T,T)> f) : n(x.size()),f(f) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1ll;i >= 0ll;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,T b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tint n,c;\n\tcin >> n >> c;\n\tmap<int,set<int>> s;\n\tfor(int i = 0;i < n;i++){\n\t\ts[0].insert(i);\n\t}\n\tvector<tuple<int,int,int>> w(c);\n\tvector<int> sc(n,0);\n\tfor(int i = 0;i < c;i++){\n\t\tcin >> get<0>(w[i]);\n\t\tif(get<0>(w[i]) == 0){\n\t\t\tcin >> get<1>(w[i]) >> get<2>(w[i]);\n\t\t\tget<1>(w[i])--;\n\t\t\tsc[get<1>(w[i])] += get<2>(w[i]);\n\t\t\ts[sc[get<1>(w[i])]].insert(get<1>(w[i]));\n\t\t}else{\n\t\t\tcin >> get<1>(w[i]);\n\t\t}\n\t}\n\tmap<int,map<int,int>> t;\n\tmap<int,int> r;\n\tint cou = 0;\n\t{\n\t\tfor(auto itr = s.begin();itr != s.end();itr++){\n\t\t\tfor(auto irs = itr->second.rbegin();irs != itr->second.rend();irs++){ \n\t\t\t\tt[itr->first][*irs] = cou;\n\t\t\t\tr[cou] = *irs;\n\t\t\t\tcou++;\n\t\t\t}\n\t\t}\n\t}\n\tsc.assign(n,0);\n\tvector<int> tmp(cou,0);\n\tfor(int i = 0;i < n;i++){\n\t\ttmp[i] = 1;\n\t}\n\tsegtree<int,0> seg(tmp,[](int a,int b){return a + b;});\n\tfor(int i = 0;i < c;i++){\n\t\tif(get<0>(w[i]) == 0){\n\t\t\tint it = t[sc[get<1>(w[i])]][get<1>(w[i])];\n\t\t\tseg.set(it,0);\n\t\t\tsc[get<1>(w[i])] += get<2>(w[i]);\n\t\t\tit = t[sc[get<1>(w[i])]][get<1>(w[i])];\n\t\t\tseg.set(it,1);\n\t\t}else{\n\t\t\tint low = 0,high = cou - 1;\n\t\t\twhile(low < high){\n\t\t\t\tint mid = (low + high) / 2;\n\t\t\t\tif(n - seg.prod(0,mid + 1) + 1 > get<1>(w[i])){\n\t\t\t\t\tlow = mid + 1;\n\t\t\t\t}else{\n\t\t\t\t\thigh = mid;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint it = r[low];\n\t\t\tcout << it + 1 << \" \" << sc[it] << endl;\n\t\t}\n\t}\n}", "accuracy": 0.2916666666666667, "time_ms": 270, "memory_kb": 37268, "score_of_the_acc": -1.188, "final_rank": 18 }, { "submission_id": "aoj_0343_9025959", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n#include <algorithm>\n#include <cassert>\n#include <functional>\n#include <vector>\n\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#if __cplusplus >= 202002L\n#include <bit>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n#if __cplusplus >= 202002L\n\nusing std::bit_ceil;\n\n#else\n\nunsigned int bit_ceil(unsigned int n) {\n unsigned int x = 1;\n while (x < (unsigned int)(n)) x *= 2;\n return x;\n}\n\n#endif\n\nint countr_zero(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\nconstexpr int countr_zero_constexpr(unsigned int n) {\n int x = 0;\n while (!(n & (1 << x))) x++;\n return x;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\n#if __cplusplus >= 201703L\n\ntemplate <class S, auto op, auto e> struct segtree {\n static_assert(std::is_convertible_v<decltype(op), std::function<S(S, S)>>,\n \"op must work as S(S, S)\");\n static_assert(std::is_convertible_v<decltype(e), std::function<S()>>,\n \"e must work as S()\");\n\n#else\n\ntemplate <class S, S (*op)(S, S), S (*e)()> struct segtree {\n\n#endif\n\n public:\n segtree() : segtree(0) {}\n explicit segtree(int n) : segtree(std::vector<S>(n, e())) {}\n explicit segtree(const std::vector<S>& v) : _n(int(v.size())) {\n size = (int)internal::bit_ceil((unsigned int)(_n));\n log = internal::countr_zero((unsigned int)size);\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) const {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n\n S prod(int l, int r) const {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() const { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) const {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) const {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) const {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) const {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\n} // namespace atcoder\n\nusing namespace atcoder;\n\nint op(int x, int y){return x+y;}\nint e(){return 0;}\n\nusing command = array<int, 3>;\n\nint main() {\n int N, C;\n cin >> N >> C;\n vector<command> com(C);\n for(int i = 0; i < C; i++) {\n cin >> com[i][0];\n if(com[i][0] == 0) {\n cin >> com[i][1] >> com[i][2];\n com[i][1]--;\n }\n else {\n cin >> com[i][1];\n }\n }\n map<int, pair<long long, int>> val;\n map<pair<long long, int>, int> pos;\n {\n vector<long long> s(N);\n vector<pair<long long, int>> scores;\n for(int i = 0; i < N; i++) {\n scores.push_back(make_pair(0, i));\n }\n for(int i = 0; i < C; i++) {\n if(com[i][0] == 0) {\n int t = com[i][1];\n int p = com[i][2];\n s[t] += p;\n scores.push_back(make_pair(s[t], t));\n }\n }\n sort(scores.begin(), scores.end(), [](auto l, auto r){\n return l.first == r.first ? l.second < r.second : l.first > r.first;\n });\n for(int i = 0; i < int(scores.size()); i++) {\n val[i] = scores[i];\n pos[scores[i]] = i;\n }\n }\n int M = val.size();\n vector<long long> s(N);\n segtree<int, op, e> seg(M);\n for(int i = 0; i < N; i++) {\n seg.set(pos[make_pair(0, i)], 1);\n }\n for(int i = 0; i < C; i++) {\n if(com[i][0] == 0) {\n int t = com[i][1];\n int p = com[i][2];\n seg.set(pos[make_pair(s[t], t)], 0);\n seg.set(pos[make_pair(s[t]+p, t)], 1);\n s[t] += p;\n }\n else {\n int r = seg.max_right(0, [&](int x){return x < com[i][1];});\n cout << val[r].second+1 << \" \" << val[r].first << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 34072, "score_of_the_acc": -1.0081, "final_rank": 15 }, { "submission_id": "aoj_0343_8976693", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nrandom_device seed_gen;\nmt19937 engine(seed_gen());\nuniform_int_distribution<int> dist_treap(0, (1 << 30) - 1);\n\nstruct S {\n\tll point;\n\tint ind;\n};\n\nstruct treap {\n\tstruct node {\n\t\tnode *lch, *rch;\n\t\tint par;\n\t\tS val;\n\t\tint cnt;\n\t\tnode(S v, int p):\n\t\t\tlch(nullptr), rch(nullptr),\n\t\t\tpar(p), val(v), cnt(1) {}\n\t};\n\n\t// a < b ?\n\tbool compare(S a, S b){\n\t\tif (a.point > b.point) return true;\n\t\tif (a.point < b.point) return false;\n\t\treturn a.ind < b.ind;\n\t}\n\n\tint calc_cnt(node* t){\n\t\tif (t == nullptr) return 0;\n\t\treturn t->cnt;\n\t}\n\n\tnode* update(node* t){\n\t\tt->cnt = calc_cnt(t->lch) + calc_cnt(t->rch) + 1;\n\t\treturn t;\n\t}\n\n\tnode* merge(node* a, node* b){\n\t\tif (a == nullptr || b == nullptr){\n\t\t\tif (a == nullptr) return b;\n\t\t\treturn a;\n\t\t}\n\n\t\tif (a->par > b->par){\n\t\t\ta->rch = merge(a->rch, b);\n\t\t\treturn update(a);\n\t\t}else{\n\t\t\tb->lch = merge(a, b->lch);\n\t\t\treturn update(b);\n\t\t}\n\t}\n\n\tpair<node*, node*> split(node* t, int k){\n\t\tif (t == nullptr) return pair(nullptr, nullptr);\n\t\tassert(0 <= k && k <= calc_cnt(t));\n\n\t\tif (calc_cnt(t->lch) >= k){\n\t\t\tpair<node*, node*> ret = split(t->lch, k);\n\t\t\tt->lch = ret.second;\n\t\t\treturn pair(ret.first, update(t));\n\t\t}else{\n\t\t\tpair<node*, node*> ret = split(t->rch, k - calc_cnt(t->lch) - 1);\n\t\t\tt->rch = ret.first;\n\t\t\treturn pair(update(t), ret.second);\n\t\t}\n\t}\n\n\tnode* insert(node* t, int k, S v){\n\t\treturn insert(t, k, v, dist_treap(engine));\n\t}\n\n\tnode* insert(node* t, int k, S v, int p){\n\t\tpair<node*, node*> tar = split(t, k);\n\t\tnode* var = new node(v, p);\n\t\treturn merge(merge(tar.first, var), tar.second);\n\t}\n\n\tnode* erase(node* t, int k){\n\t\tassert(0 <= k && k < calc_cnt(t));\n\t\tpair<node*, node*> spl1 = split(t, k + 1);\n\t\tpair<node*, node*> spl2 = split(spl1.first, k);\n\t\tdelete spl2.second;\n\t\treturn merge(spl2.first, spl1.second);\n\t}\n\n\t// returns the number of elements less than v\n\tint lower_bound(node* t, S v){\n\t\tif (t == nullptr) return 0;\n\n\t\t// if v <= t->val (i.e. all is left)\n\t\tif (!compare(t->val, v)){\n\t\t\treturn lower_bound(t->lch, v);\n\t\t}else{\n\t\t\t// if v > t->val (i.e. all left is to be counted) \n\t\t\treturn calc_cnt(t->lch) + 1 + lower_bound(t->rch, v);\n\t\t}\n\t}\n\n\tnode* insert(node* t, S v){\n\t\treturn insert(t, lower_bound(t, v), v);\n\t}\n\n\t// returns val\n\tS get(node* t, int k){\n\t\tassert(t != nullptr);\n\t\tif (k < calc_cnt(t->lch)){\n\t\t\treturn get(t->lch, k);\n\t\t}else if(calc_cnt(t->lch) == k){\n\t\t\treturn t->val;\n\t\t}else{\n\t\t\treturn get(t->rch, k - calc_cnt(t->lch) - 1);\n\t\t}\n\t}\n\n\t\n};\n\nint main(){\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\t\n\ttreap T;\n\ttreap::node* root = nullptr;\n\tint n, q; cin >> n >> q;\n\tvector<S> now(n);\n\tfor (int i=0; i<n; i++){\n\t\tnow[i] = {0, i};\n\t\troot = T.insert(root, now[i]);\n\t}\n\n\twhile(q--){\n\t\tint t; cin >> t;\n\t\tif (t == 0){\n\t\t\tint i; cin >> i; i--;\n\t\t\tll p; cin >> p;\n\t\t\troot = T.erase(root, T.lower_bound(root, now[i]));\n\t\t\tnow[i].point += p;\n\t\t\troot = T.insert(root, now[i]);\n\t\t}else{\n\t\t\tint m; cin >> m;\n\t\t\tm--;\n\t\t\tS ret = T.get(root, m);\n\t\t\tcout << ret.ind + 1 << ' ' << ret.point << '\\n';\n\t\t}\n\t}\n\t\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 11036, "score_of_the_acc": -0.2818, "final_rank": 7 }, { "submission_id": "aoj_0343_8711980", "code_snippet": "#include <bits/stdc++.h>\n\nstruct Info {\n long long score = 0;\n int id = 0;\n};\n\nbool operator<(Info lhs, Info rhs) {\n if (lhs.score == rhs.score) return lhs.id < rhs.id;\n return lhs.score > rhs.score;\n}\n\nstruct SegmentTree {\n std::vector<int> data;\n int n;\n int size;\n SegmentTree(int n): n(n) {\n int log = 0;\n while (n > (1 << log)) log++;\n size = 1 << log;\n data.assign(2 * size, 0);\n }\n void add(int pos, int diff) {\n assert(0 <= pos && pos < n);\n pos += size;\n data[pos] += diff;\n for (pos >>= 1; pos > 0; pos >>= 1) {\n data[pos] = data[2 * pos] + data[2 * pos + 1];\n }\n }\n int kth_element(int k) {\n int pos = 1;\n int now = 0;\n while (pos < size) {\n if (now + data[2 * pos] < k) {\n now += data[2 * pos];\n pos = 2 * pos + 1;\n } else {\n pos = 2 * pos;\n }\n }\n assert(now + data[pos] == k);\n return pos - size;\n }\n};\n\nint main() {\n int n, q;\n std::cin >> n >> q;\n std::vector<Info> cur(n);\n std::vector<Info> infos;\n for (int i = 0; i < n; i++) {\n cur[i].score = 0;\n cur[i].id = i;\n infos.push_back(cur[i]);\n }\n std::vector<std::tuple<int, int, long long>> querys;\n for (int i = 0; i < q; i++) {\n int t;\n std::cin >> t;\n if (t == 0) {\n int pos;\n long long diff;\n std::cin >> pos >> diff;\n pos--;\n querys.emplace_back(t, pos, diff);\n cur[pos].score += diff;\n infos.push_back(cur[pos]);\n } else {\n int pos;\n std::cin >> pos;\n querys.emplace_back(t, pos, -1);\n }\n }\n\n std::sort(infos.begin(), infos.end());\n // infos.erase(std::unique(infos.begin(), infos.end()), infos.end());\n auto compress = [&](Info info) {\n auto it = std::lower_bound(infos.begin(), infos.end(), info);\n assert(it->score == info.score);\n assert(it->id == info.id);\n return it - infos.begin();\n };\n int m = infos.size();\n SegmentTree segtree(m);\n for (int i = 0; i < n; i++) {\n cur[i].score = 0;\n cur[i].id = i;\n segtree.add(compress(cur[i]), 1);\n }\n\n for (auto [t, pos, diff]: querys) {\n if (t == 0) {\n segtree.add(compress(cur[pos]), -1);\n cur[pos].score += diff;\n segtree.add(compress(cur[pos]), 1);\n } else {\n int i = segtree.kth_element(pos);\n auto info = infos[i];\n std::cout << info.id + 1 << ' ' << info.score << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 13600, "score_of_the_acc": -0.2258, "final_rank": 4 }, { "submission_id": "aoj_0343_8315072", "code_snippet": "#include <bits/stdc++.h>\n\n// data-structure/splay-tree.hpp\n\n#include <cassert>\n#include <iostream>\n#include <limits>\n#include <memory>\n#include <utility>\n#include <vector>\n\nnamespace nono {\n\ntemplate <class Key, class T>\nclass SplayTree {\n struct Node;\n using NodePtr = Node*;\n\n struct Node {\n Node() = default;\n Node(Key key, T value): key(key), value(value), size(1), left(nullptr), right(nullptr), parent(nullptr) {}\n\n void right_rotate() {\n NodePtr above = parent->parent;\n NodePtr center = this;\n NodePtr below = parent;\n\n below->left = center->right;\n if (below->left) below->left->parent = below;\n\n center->right = below;\n below->parent = center;\n\n center->parent = above;\n if (above) {\n if (above->left == below) {\n above->left = center;\n } else {\n above->right = center;\n }\n }\n below->update();\n center->update();\n }\n\n void left_rotate() {\n NodePtr above = parent->parent;\n NodePtr center = this;\n NodePtr below = parent;\n\n below->right = center->left;\n if (below->right) below->right->parent = below;\n\n center->left = below;\n below->parent = center;\n\n center->parent = above;\n if (above) {\n if (above->left == below) {\n above->left = center;\n } else {\n above->right = center;\n }\n }\n below->update();\n center->update();\n }\n\n void rotate() {\n if (parent->left && parent->left == this) {\n right_rotate();\n } else {\n left_rotate();\n }\n }\n\n int state() {\n if (parent) {\n return (parent->left == this ? 1 : -1);\n }\n return 0;\n }\n\n void splay() {\n while (state() != 0) {\n if (parent->state() != 0) {\n if (state() == parent->state()) {\n parent->rotate();\n rotate();\n } else {\n rotate();\n rotate();\n }\n } else {\n rotate();\n }\n }\n }\n\n void update() {\n size = 1;\n if (left) size += left->size;\n if (right) size += right->size;\n }\n\n Key key;\n T value;\n int size;\n NodePtr left = nullptr;\n NodePtr right = nullptr;\n NodePtr parent = nullptr;\n };\n\n public:\n SplayTree() = default;\n SplayTree(NodePtr root): root(root) {}\n ~SplayTree() {\n destract(root);\n }\n\n void output() {\n output(root);\n }\n\n void debug() {\n debug(root);\n }\n\n T& get(Key key) {\n root = find(key);\n return root->value;\n }\n\n std::pair<Key, T> kth_element(int k) {\n root = kth_element(k, root);\n return {root->key, root->value};\n }\n\n void insert(Key key, T value) {\n if (!root) {\n root = new Node(key, value);\n return;\n }\n auto [lhs, rhs] = split(key);\n root = merge(merge(lhs, new Node(key, value)), rhs);\n }\n\n bool contains(Key key) {\n root = find(key);\n return root && root->key == key;\n }\n\n void erase(Key key) {\n root = find(key);\n if (root->left) root->left->parent = nullptr;\n if (root->right) root->right->parent = nullptr;\n NodePtr lhs = root->left;\n NodePtr rhs = root->right;\n root->left = nullptr;\n root->right = nullptr;\n delete root;\n root = merge(lhs, rhs);\n }\n\n\n private:\n void output(NodePtr nodeptr) {\n if (nodeptr) {\n if (nodeptr->left) output(nodeptr->left);\n std::cerr << nodeptr->key << ' ';\n if (nodeptr->right) output(nodeptr->right);\n }\n }\n\n void debug(NodePtr nodeptr) {\n if (!nodeptr) return;\n int size = 0;\n if (nodeptr->left) {\n size += nodeptr->left->size;\n debug(nodeptr->left);\n }\n if (nodeptr->right) {\n size += nodeptr->right->size;\n debug(nodeptr->right);\n }\n }\n\n static NodePtr kth_element(int k, NodePtr node) {\n\n if ((!node->left && k == 0) || (node->left && node->left->size == k)) {\n node->splay();\n return node;\n }\n if ((!node->left) || (node->left && node->left->size < k)) {\n if (node->right) {\n return kth_element(k - (node->left ? node->left->size : 0) - 1, node->right);\n } else {\n return nullptr;\n }\n }\n if ((!node->right) || (node->left && node->left->size > k)) {\n if (node->left) {\n return kth_element(k, node->left);\n } else {\n return nullptr;\n }\n }\n\n return nullptr;\n }\n\n std::pair<NodePtr, NodePtr> split(Key key) {\n if (!root) return {nullptr, nullptr};\n root = find(key);\n NodePtr lhs, rhs;\n if (root->key >= key) {\n lhs = root->left;\n rhs = root;\n if (lhs) lhs->parent = nullptr;\n if (rhs) rhs->left = nullptr;\n } else {\n lhs = root;\n rhs = root->right;\n if (lhs) lhs->right = nullptr;\n if (rhs) rhs->parent = nullptr;\n }\n root = nullptr;\n if (lhs) lhs->update();\n if (rhs) rhs->update();\n return {lhs, rhs};\n }\n\n static NodePtr merge(NodePtr lhs, NodePtr rhs) {\n if (!lhs) return rhs;\n if (!rhs) return lhs;\n NodePtr root = lhs;\n while (root->right) root = root->right;\n root->splay();\n root->right = rhs;\n rhs->parent = root;\n root->update();\n return root;\n }\n\n NodePtr find(Key key) {\n if (!root) return nullptr;\n NodePtr target = root;\n while (target && target->key != key) {\n if (target->key > key) {\n if (target->left) {\n target = target->left;\n } else {\n break;\n }\n } else {\n if (target->right) {\n target = target->right;\n } else {\n break;\n }\n }\n }\n target->splay();\n return target;\n }\n\n void destract(NodePtr node) {\n if (!node) return;\n destract(node->left);\n node->left = nullptr;\n destract(node->right);\n node->right = nullptr;\n node->parent = nullptr;\n delete node;\n }\n\n NodePtr root = nullptr;\n};\n\n} // namespace nono\n\nnamespace nono {\n\nvoid solve() {\n SplayTree<std::pair<long long, int>, int> splay;\n int n, c;\n std::cin >> n >> c;\n std::vector<long long> score(n);\n for (int i = 0; i < n; i++) {\n splay.insert({0, i}, 0);\n }\n while (c--) {\n int t;\n std::cin >> t;\n if (t == 0) {\n int i;\n long long p;\n std::cin >> i >> p;\n i--;\n\n splay.erase({score[i], i});\n score[i] -= p;\n splay.insert({score[i], i}, 0);\n } else {\n int i;\n std::cin >> i;\n i--;\n auto [key, value] = splay.kth_element(i);\n std::cout << key.second + 1 << ' ' << -key.first << std::endl;\n }\n }\n}\n\n} // namespace nono\n\nint main() {\n std::cin.tie(0)->sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(15);\n\n int t = 1;\n while (t--) nono::solve();\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 12816, "score_of_the_acc": -0.4502, "final_rank": 11 }, { "submission_id": "aoj_0343_8291004", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nclass BIT {\npublic:\n\tint size_;\n\tvector<long long> dat;\n\n\tvoid init(int sz) {\n\t\tsize_ = sz + 2;\n\t\tdat.resize(size_ + 2, 0);\n\t}\n\n\tvoid add(int pos, long long x) {\n\t\tpos += 1;\n\t\twhile (pos <= size_) {\n\t\t\tdat[pos] += x;\n\t\t\tpos += (pos & -pos);\n\t\t}\n\t}\n\n\tlong long sum(int pos) {\n\t\tlong long s = 0; pos++;\n\t\twhile (pos >= 1) {\n\t\t\ts += dat[pos];\n\t\t\tpos -= (pos & -pos);\n\t\t}\n\t\treturn s;\n\t}\n};\n\nlong long N;\nlong long Q, T[1 << 18], A[1 << 18], B[1 << 18];\nlong long Score[1 << 18];\nvector<pair<long long, long long>> Vec;\nBIT Z;\n\nint Binary_Search(int rnk) {\n\tint cl = 0, cr = Vec.size() + 1, cm, minx = (1 << 30);\n\tfor (int i = 0; i < 20; i++) {\n\t\tcm = (cl + cr) / 2;\n\t\tint val = Z.sum(cm);\n\t\tif (val >= N - rnk + 1) { cr = cm; minx = min(minx, cm); }\n\t\telse { cl = cm; }\n\t}\n\treturn minx;\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> Q;\n\tfor (int i = 1; i <= Q; i++) {\n\t\tcin >> T[i];\n\t\tif (T[i] == 0) cin >> A[i] >> B[i];\n\t\tif (T[i] == 1) cin >> A[i];\n\t}\n\n\t// Step 2. Init Sim\n\tfor (int i = 1; i <= N; i++) Vec.push_back(make_pair(Score[i], -i));\n\tfor (int i = 1; i <= Q; i++) {\n\t\tif (T[i] == 1) continue;\n\t\tScore[A[i]] += B[i];\n\t\tVec.push_back(make_pair(Score[A[i]], -A[i]));\n\t}\n\tsort(Vec.begin(), Vec.end());\n\tVec.erase(unique(Vec.begin(), Vec.end()), Vec.end());\n\tZ.init(Vec.size() + 2);\n\t\n\t// Step 3. Simulation\n\tfor (int i = 1; i <= N; i++) Score[i] = 0;\n\tfor (int i = 1; i <= N; i++) Z.add(i - 1, 1);\n\tfor (int i = 1; i <= Q; i++) {\n\t\tif (T[i] == 0) {\n\t\t\tint pos1 = lower_bound(Vec.begin(), Vec.end(), make_pair(Score[A[i]], -A[i])) - Vec.begin();\n\t\t\tScore[A[i]] += B[i];\n\t\t\tint pos2 = lower_bound(Vec.begin(), Vec.end(), make_pair(Score[A[i]], -A[i])) - Vec.begin();\n\t\t\tZ.add(pos1, -1);\n\t\t\tZ.add(pos2, +1);\n\t\t}\n\t\tif (T[i] == 1) {\n\t\t\tint pos = Binary_Search(A[i]);\n\t\t\tcout << -Vec[pos].second << \" \" << Vec[pos].first << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 15520, "score_of_the_acc": -0.3568, "final_rank": 10 }, { "submission_id": "aoj_0343_6968305", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0343.cc: Programming Contest II\n */\n\n#include<cstdio>\n#include<cstdlib>\n#include<ctime>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int BUFSIZE = MAX_N * 2;\nconst int INF = 1 << 30;\nconst long long LINF = 1LL << 62;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef pair<ll,int> pli;\n\ntemplate <typename T, const int BUFSIZE>\nstruct Treap {\n struct Node {\n T key, minkey;\n int fix, size;\n Node *left, *right;\n\n void print(int k) {\n printf(\"%d: key=%lld, minkey=%lld, fix=%d, size=%d\\n\",\n\t k, key, minkey, fix, size);\n }\n void print() { print(0); }\n };\n typedef Node *node;\n\n node root, nullnode, buf;\n Node buf0[BUFSIZE], buf1;\n\n const T TINF;\n \n Treap(T tinf): TINF(tinf) {\n nullnode = &buf1;\n nullnode->left = nullnode->right = nullnode;\n nullnode->key = nullnode->minkey = TINF;\n nullnode->fix = nullnode->size = 0;\n clear();\n srand(time(NULL));\n }\n\n void clear() { buf = buf0; root = nullnode; }\n \n int size() { return root->size; }\n\n void update(node& t) {\n t->size = 1 + t->left->size + t->right->size;\n t->minkey = t->key;\n if (t->minkey > t->left->minkey) t->minkey = t->left->minkey;\n if (t->minkey > t->right->minkey) t->minkey = t->right->minkey;\n }\n\n node gen_node(T x) {\n node t = buf++;\n t->left = t->right = nullnode;\n t->key = t->minkey = x;\n t->fix = rand();\n t->size = 1;\n return t;\n }\n \n void rot_l(node& k1) {\n node k2 = k1->right;\n k1->right = k2->left;\n k2->left = k1;\n update(k1);\n update(k2);\n k1 = k2;\n }\n\n void rot_r(node& k1) {\n node k2 = k1->left;\n k1->left = k2->right;\n k2->right = k1;\n update(k1);\n update(k2);\n k1 = k2;\n }\n\n void append(node& t, T x) {\n if (t == nullnode)\n t = gen_node(x);\n else {\n append(t->right, x);\n update(t);\n if (t->right->fix > t->fix) rot_l(t);\n }\n }\n void append(T x) { append(root, x); }\n \n void insertat(node& t, int i, T x) {\n if (t == nullnode)\n t = gen_node(x);\n else {\n int lsize = t->left->size;\n if (i == lsize) {\n\tappend(t->left, x);\n\tupdate(t);\n\tif (t->left->fix > t->fix) rot_r(t);\n }\n else if (i < lsize) {\n\tinsertat(t->left, i, x);\n\tupdate(t);\n\tif (t->left->fix > t->fix) rot_r(t);\n }\n else {\n\tinsertat(t->right, i - (lsize + 1), x);\n\tupdate(t);\n\tif (t->right->fix > t->fix) rot_l(t);\n }\n }\n }\n void insertat(int i, T x) { insertat(root, i, x); }\n\n void insert(node& t, T x) {\n if (t == nullnode)\n t = gen_node(x);\n else {\n if (t->key == x) return;\n if (x < t->key) {\n\tinsert(t->left, x);\n\tupdate(t);\n\tif (t->left->fix > t->fix) rot_r(t);\n }\n else {\n\tinsert(t->right, x);\n\tupdate(t);\n\tif (t->right->fix > t->fix) rot_l(t);\n }\n }\n }\n void insert(T x) { insert(root, x); }\n\n void set(node& t, int i, T x) {\n if (t != nullnode) {\n int lsize = t->left->size;\n if (i == lsize) {\n\tt->key = t->minkey = x;\n\tupdate(t);\n }\n else if (i < lsize) {\n\tset(t->left, i, x);\n\tupdate(t);\n }\n else {\n\tset(t->right, i - (lsize + 1), x);\n\tupdate(t);\n }\n }\n }\n void set(int i, T x) { set(root, i, x); }\n \n void remove_node(node& t) {\n if (t == nullnode) return;\n if (t->left == nullnode || t->right == nullnode) {\n if (t->left == nullnode)\n\tt = t->right;\n else\n\tt = t->left;\n }\n else {\n if (t->left->fix < t->right->fix) {\n\trot_l(t);\n\tremove_node(t->left);\n\tupdate(t);\n }\n else {\n\trot_r(t);\n\tremove_node(t->right);\n\tupdate(t);\n }\n }\n }\n\n T removeat(node& t, int i) {\n T ret = TINF;\n\n if (t != nullnode) {\n int lsize = t->left->size;\n if (i == lsize) {\n\tret = t->key;\n\tremove_node(t);\n }\n else if (i < lsize) {\n\tret = removeat(t->left, i);\n\tupdate(t);\n }\n else {\n\tret = removeat(t->right, i - (lsize + 1));\n\tupdate(t);\n }\n }\n\n return ret;\n }\n T removeat(int i) { return removeat(root, i); }\n \n void remove(node& t, T x) {\n if (t != nullnode) {\n if (t->key == x)\n\tremove_node(t);\n else if (x < t->key) {\n\tremove(t->left, x);\n\tupdate(t);\n }\n else {\n\tremove(t->right, x);\n\tupdate(t);\n }\n }\n }\n void remove(T x) { remove(root, x); }\n \n int remove_range(node& t, int r0, int r1) {\n if (t == nullnode) return 0;\n if (r1 <= 0 || t->size <= r0) return 0;\n \n if (r0 <= 0 && t->size <= r1) {\n int n = t->size;\n t = nullnode;\n return n;\n }\n\n int lsize = t->left->size;\n int n =\n remove_range(t->left, r0, r1) +\n remove_range(t->right, r0 - (lsize + 1), r1 - (lsize + 1));\n t->size = 1 + t->left->size + t->right->size;\n\n if (r0 <= lsize && lsize < r1) {\n n++;\n remove_node(t);\n }\n\n return n;\n }\n int remove_range(int r0, int r1) { return remove_range(root, r0, r1); }\n\n T min_range(node& t, int r0, int r1) {\n if (t == nullnode) return TINF;\n if (r1 <= 0 || t->size <= r0) return TINF;\n \n if (r0 <= 0 && t->size <= r1) return t->minkey;\n\n int lsize = t->left->size;\n T minval = TINF;\n\n if (r0 <= lsize && lsize < r1)\n minval = t->key;\n if (r0 <= lsize) {\n T minl = min_range(t->left, r0, r1);\n if (minval > minl) minval = minl;\n }\n if (lsize + 1 < r1) {\n T minr = min_range(t->right, r0 - (lsize + 1), r1 - (lsize + 1));\n if (minval > minr) minval = minr;\n }\n\n return minval;\n }\n T min_range(int r0, int r1) { return min_range(root, r0, r1); }\n\n node find(T x) {\n node t = root;\n while (t != nullnode) {\n if (t->key == x) return t;\n if (x < t->key) t = t->left;\n else t = t->right;\n }\n return (node)NULL;\n }\n\n T findat(int i) {\n node t = root;\n while (t != nullnode) {\n int lsize = t->left->size;\n if (i == lsize) return t->key;\n if (i < lsize)\n\tt = t->left;\n else {\n\ti -= lsize + 1;\n\tt = t->right;\n }\n }\n return TINF;\n }\n\n int upper_bound(T x) {\n node t = root;\n int k = 0;\n\n while (t != nullnode) {\n if (t->key <= x) {\n\tk += t->left->size + 1;\n\tt = t->right;\n }\n else {\n\tt = t->left;\n }\n }\n return k;\n }\n};\n\n/* global variables */\n\nll ss[MAX_N];\nTreap<pli,BUFSIZE> trp(pli(LINF, INF));\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, qn;\n scanf(\"%d%d\", &n, &qn);\n\n for (int i = 0; i < n; i++) trp.insert(pli(0, i));\n\n while (qn--) {\n int op;\n scanf(\"%d\", &op);\n\n if (op == 0) {\n int t, p;\n scanf(\"%d%d\", &t, &p), t--;\n\n trp.remove(pli(ss[t], t));\n ss[t] -= p;\n trp.insert(pli(ss[t], t));\n }\n else {\n int m;\n scanf(\"%d\", &m), m--;\n\n pli v = trp.findat(m);\n printf(\"%d %lld\\n\", v.second + 1, -v.first);\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 14692, "score_of_the_acc": -0.1962, "final_rank": 2 }, { "submission_id": "aoj_0343_6923620", "code_snippet": "#line 1 \"/home/maspy/compro/library/my_template.hpp\"\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\n\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n// https://trap.jp/post/1224/\n#define FOR1(a) for (ll _ = 0; _ < ll(a); ++_)\n#define FOR2(i, a) for (ll i = 0; i < ll(a); ++i)\n#define FOR3(i, a, b) for (ll i = a; i < ll(b); ++i)\n#define FOR4(i, a, b, c) for (ll i = a; i < ll(b); i += (c))\n#define FOR1_R(a) for (ll i = (a)-1; i >= ll(0); --i)\n#define FOR2_R(i, a) for (ll i = (a)-1; i >= ll(0); --i)\n#define FOR3_R(i, a, b) for (ll i = (b)-1; i >= ll(a); --i)\n#define FOR4_R(i, a, b, c) for (ll i = (b)-1; i >= ll(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define FOR(...) overload4(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)(__VA_ARGS__)\n#define FOR_R(...) \\\n overload4(__VA_ARGS__, FOR4_R, FOR3_R, FOR2_R, FOR1_R)(__VA_ARGS__)\n\n#define FOR_subset(t, s) for (ll t = s; t >= 0; t = (t == 0 ? -1 : (t - 1) & s))\n#define all(x) x.begin(), x.end()\n#define len(x) ll(x.size())\n#define elif else if\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n\nll SUM(vector<int> &A) {\n ll sum = 0;\n for (auto &&a: A) sum += a;\n return sum;\n}\n\ntemplate <typename T>\nT SUM(vector<T> &A) {\n T sum = T(0);\n for (auto &&a: A) sum += a;\n return sum;\n}\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\nint popcnt(int x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(ll x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2)\nint topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(u32 x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }\nint topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nint topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\n// (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2)\nint lowbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(u32 x) { return (x == 0 ? -1 : __builtin_ctz(x)); }\nint lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nint lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T, typename U>\nT ceil(T x, U y) {\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <typename T, typename U>\nT floor(T x, U y) {\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\n\ntemplate <typename T, typename U>\npair<T, T> divmod(T x, U y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\nll binary_search(function<bool(ll)> check, ll ok, ll ng) {\n assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n if (check(x))\n ok = x;\n else\n ng = x;\n }\n return ok;\n}\n\ntemplate <typename F>\ndouble binary_search_real(F check, double ok, double ng, int iter = 100) {\n FOR(iter) {\n double x = (ok + ng) / 2;\n if (check(x)) {\n ok = x;\n } else {\n ng = x;\n }\n }\n return (ok + ng) / 2;\n}\n\ntemplate <class T, class S>\ninline bool chmax(T &a, const S &b) {\n return (a < b ? a = b, 1 : 0);\n}\ntemplate <class T, class S>\ninline bool chmin(T &a, const S &b) {\n return (a > b ? a = b, 1 : 0);\n}\n\nvi s_to_vi(const string &S, char first_char) {\n vi A(S.size());\n FOR(i, S.size()) { A[i] = S[i] - first_char; }\n return A;\n}\n\ntemplate <typename T>\nvector<T> cumsum(vector<T> &A, int off = 1) {\n int N = A.size();\n vector<T> B(N + 1);\n FOR(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\ntemplate <typename CNT, typename T>\nvc<CNT> bincount(const vc<T> &A, int size) {\n vc<CNT> C(size);\n for (auto &&x: A) { ++C[x]; }\n return C;\n}\n\ntemplate <typename T>\nvector<int> argsort(const vector<T> &A) {\n // stable\n vector<int> ids(A.size());\n iota(all(ids), 0);\n sort(all(ids),\n [&](int i, int j) { return A[i] < A[j] || (A[i] == A[j] && i < j); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vc<int> &I) {\n int n = len(I);\n vc<T> B(n);\n FOR(i, n) B[i] = A[I[i]];\n return B;\n}\n#line 1 \"/home/maspy/compro/library/other/io.hpp\"\n// based on yosupo's fastio\n#include <unistd.h>\n\nnamespace detail {\ntemplate <typename T, decltype(&T::is_modint) = &T::is_modint>\nstd::true_type check_value(int);\ntemplate <typename T>\nstd::false_type check_value(long);\n} // namespace detail\n\ntemplate <typename T>\nstruct is_modint : decltype(detail::check_value<T>(0)) {};\ntemplate <typename T>\nusing is_modint_t = enable_if_t<is_modint<T>::value>;\ntemplate <typename T>\nusing is_not_modint_t = enable_if_t<!is_modint<T>::value>;\n\nstruct Scanner {\n FILE *fp;\n char line[(1 << 15) + 1];\n size_t st = 0, ed = 0;\n void reread() {\n memmove(line, line + st, ed - st);\n ed -= st;\n st = 0;\n ed += fread(line + ed, 1, (1 << 15) - ed, fp);\n line[ed] = '\\0';\n }\n bool succ() {\n while (true) {\n if (st == ed) {\n reread();\n if (st == ed) return false;\n }\n while (st != ed && isspace(line[st])) st++;\n if (st != ed) break;\n }\n if (ed - st <= 50) {\n bool sep = false;\n for (size_t i = st; i < ed; i++) {\n if (isspace(line[i])) {\n sep = true;\n break;\n }\n }\n if (!sep) reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_same<T, string>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n while (true) {\n size_t sz = 0;\n while (st + sz < ed && !isspace(line[st + sz])) sz++;\n ref.append(line + st, sz);\n st += sz;\n if (!sz || st != ed) break;\n reread();\n }\n return true;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n bool read_single(T &ref) {\n if (!succ()) return false;\n bool neg = false;\n if (line[st] == '-') {\n neg = true;\n st++;\n }\n ref = T(0);\n while (isdigit(line[st])) { ref = 10 * ref + (line[st++] & 0xf); }\n if (neg) ref = -ref;\n return true;\n }\n template <class T, is_modint_t<T> * = nullptr>\n bool read_single(T &ref) {\n long long val = 0;\n bool f = read_single(val);\n ref = T(val);\n return f;\n }\n bool read_single(double &ref) {\n string s;\n if (!read_single(s)) return false;\n ref = std::stod(s);\n return true;\n }\n bool read_single(char &ref) {\n string s;\n if (!read_single(s) || s.size() != 1) return false;\n ref = s[0];\n return true;\n }\n template <class T>\n bool read_single(vector<T> &ref) {\n for (auto &d: ref) {\n if (!read_single(d)) return false;\n }\n return true;\n }\n template <class T, class U>\n bool read_single(pair<T, U> &p) {\n return (read_single(p.first) && read_single(p.second));\n }\n template <class A, class B, class C>\n bool read_single(tuple<A, B, C> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)));\n }\n template <class A, class B, class C, class D>\n bool read_single(tuple<A, B, C, D> &p) {\n return (read_single(get<0>(p)) && read_single(get<1>(p))\n && read_single(get<2>(p)) && read_single(get<3>(p)));\n }\n void read() {}\n template <class H, class... T>\n void read(H &h, T &... t) {\n bool f = read_single(h);\n assert(f);\n read(t...);\n }\n Scanner(FILE *fp) : fp(fp) {}\n};\n\nstruct Printer {\n Printer(FILE *_fp) : fp(_fp) {}\n ~Printer() { flush(); }\n\n static constexpr size_t SIZE = 1 << 15;\n FILE *fp;\n char line[SIZE], small[50];\n size_t pos = 0;\n void flush() {\n fwrite(line, 1, pos, fp);\n pos = 0;\n }\n void write(const char &val) {\n if (pos == SIZE) flush();\n line[pos++] = val;\n }\n template <class T, enable_if_t<is_integral<T>::value, int> = 0>\n void write(T val) {\n if (pos > (1 << 15) - 50) flush();\n if (val == 0) {\n write('0');\n return;\n }\n if (val < 0) {\n write('-');\n val = -val; // todo min\n }\n size_t len = 0;\n while (val) {\n small[len++] = char(0x30 | (val % 10));\n val /= 10;\n }\n for (size_t i = 0; i < len; i++) { line[pos + i] = small[len - 1 - i]; }\n pos += len;\n }\n void write(const string &s) {\n for (char c: s) write(c);\n }\n void write(const char *s) {\n size_t len = strlen(s);\n for (size_t i = 0; i < len; i++) write(s[i]);\n }\n void write(const double &x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n void write(const long double &x) {\n ostringstream oss;\n oss << fixed << setprecision(15) << x;\n string s = oss.str();\n write(s);\n }\n template <class T, is_modint_t<T> * = nullptr>\n void write(T &ref) {\n write(ref.val);\n }\n template <class T>\n void write(const vector<T> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n template <class T, class U>\n void write(const pair<T, U> &val) {\n write(val.first);\n write(' ');\n write(val.second);\n }\n template <class A, class B, class C>\n void write(const tuple<A, B, C> &val) {\n auto &[a, b, c] = val;\n write(a), write(' '), write(b), write(' '), write(c);\n }\n template <class A, class B, class C, class D>\n void write(const tuple<A, B, C, D> &val) {\n auto &[a, b, c, d] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d);\n }\n template <class A, class B, class C, class D, class E>\n void write(const tuple<A, B, C, D, E> &val) {\n auto &[a, b, c, d, e] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e);\n }\n template <class A, class B, class C, class D, class E, class F>\n void write(const tuple<A, B, C, D, E, F> &val) {\n auto &[a, b, c, d, e, f] = val;\n write(a), write(' '), write(b), write(' '), write(c), write(' '), write(d), write(' '), write(e), write(' '), write(f);\n }\n template <class T, size_t S>\n void write(const array<T, S> &val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) write(' ');\n write(val[i]);\n }\n }\n void write(i128 val) {\n string s;\n bool negative = 0;\n if(val < 0){\n negative = 1;\n val = -val;\n }\n while (val) {\n s += '0' + int(val % 10);\n val /= 10;\n }\n if(negative) s += \"-\";\n reverse(all(s));\n if (len(s) == 0) s = \"0\";\n write(s);\n }\n};\n\nScanner scanner = Scanner(stdin);\nPrinter printer = Printer(stdout);\n\nvoid flush() { printer.flush(); }\nvoid print() { printer.write('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n printer.write(head);\n if (sizeof...(Tail)) printer.write(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid read() {}\ntemplate <class Head, class... Tail>\nvoid read(Head &head, Tail &... tail) {\n scanner.read(head);\n read(tail...);\n}\n\n#define INT(...) \\\n int __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define CHAR(...) \\\n char __VA_ARGS__; \\\n read(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n read(__VA_ARGS__)\n\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n read(name)\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n read(name)\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\n#line 1 \"/home/maspy/compro/library/ds/pbds.hpp\"\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/tag_and_trait.hpp>\nusing namespace __gnu_pbds;\n\n// お手軽だけど、座圧+BITとかの方がかなり速いので注意!\ntemplate <typename KEY>\nusing pbds_set = tree<KEY, null_type, less<KEY>, rb_tree_tag,\n tree_order_statistics_node_update>;\n#line 4 \"main.cpp\"\n\nvoid solve() {\n LL(N, Q);\n // (score, -idx)\n pbds_set<pi> ss;\n vi A(N);\n FOR(i, N) ss.insert({A[i], -i});\n FOR(Q) {\n LL(tp);\n if (tp == 0) {\n LL(idx, p);\n --idx;\n ss.erase({A[idx], -idx});\n A[idx] += p;\n ss.insert({A[idx], -idx});\n } else {\n LL(rk);\n rk = N - rk;\n auto [a, b] = *(ss.find_by_order(rk));\n b = 1 + (-b);\n print(b, a);\n }\n }\n}\n\nsigned main() {\n cout << fixed << setprecision(15);\n\n ll T = 1;\n // LL(T);\n FOR(T) solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 10196, "score_of_the_acc": -0.275, "final_rank": 6 }, { "submission_id": "aoj_0343_5951721", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate <typename T, int MAX_LOG, typename D = int>\nstruct BinaryTrie {\npublic:\n struct Node {\n Node *nxt[2];\n D exist;\n vector<int> accept;\n\n Node() : nxt{nullptr, nullptr}, exist(0) {}\n };\n\n Node *root;\n\n explicit BinaryTrie() : root(new Node()) {}\n\n explicit BinaryTrie(Node *root) : root(root) {}\n\n void add(const T &bit, D delta = 1, int idx = -1, T xor_val = 0) {\n root = add(root, bit, idx, MAX_LOG, delta, xor_val);\n }\n\n void erase(const T &bit, D delta = 1, T xor_val = 0) {\n add(bit, -delta, -1, xor_val);\n }\n\n Node *find(const T &bit, T xor_val = 0) {\n return (find(root, bit, MAX_LOG, xor_val));\n }\n\n D count(const T &bit, T xor_val = 0) {\n auto node = find(bit, xor_val);\n return (node ? node->exist : 0);\n }\n\n pair<T, Node *> min_element(T xor_val = 0) {\n assert(root->exist > 0);\n return (kth_element(0, xor_val));\n }\n\n pair<T, Node *> max_element(T xor_val = 0) {\n assert(root->exist > 0);\n return (kth_element(root->exist - 1, xor_val));\n }\n\n pair<T, Node *> kth_element(D k, T xor_val = 0) {\n assert(0 <= k && k < root->exist);\n return (kth_element(root, k, MAX_LOG, xor_val));\n }\n\n D count_less(const T &bit, T xor_val = 0) {\n return (count_less(root, bit, MAX_LOG, xor_val));\n }\n\n D size() const {\n return (root->exist);\n }\n\nprivate:\n\n virtual Node *clone(Node *t) { return (t); }\n\n Node *add(Node *t, T bit, int idx, int depth, D x, T xor_val, bool need = true) {\n if (need) t = clone(t);\n if (depth == -1) {\n t->exist += x;\n if (idx >= 0) t->accept.emplace_back(idx);\n } else {\n bool f = (xor_val >> depth) & 1;\n auto &to = t->nxt[f ^ ((bit >> depth) & 1)];\n if (!to) to = new Node(), need = false;\n to = add(to, bit, idx, depth - 1, x, xor_val, need);\n t->exist += x;\n }\n return (t);\n }\n\n Node *find(Node *t, T bit, int depth, T xor_val) {\n if (depth == -1) {\n return (t);\n } else {\n bool f = (xor_val >> depth) & 1;\n auto &to = t->nxt[f ^ ((bit >> depth) & 1)];\n return (to ? find(to, bit, depth - 1, xor_val) : nullptr);\n }\n }\n\n pair<T, Node *> kth_element(Node *t, D k, int bit_index, T xor_val) {\n if (bit_index == -1) {\n return (make_pair(0, t));\n } else {\n bool f = (xor_val >> bit_index) & 1;\n if ((t->nxt[f] ? t->nxt[f]->exist : 0) <= k) {\n auto ret = kth_element(t->nxt[f ^ 1], k - (t->nxt[f] ? t->nxt[f]->exist : 0), bit_index - 1, xor_val);\n ret.first |= T(1) << bit_index;\n return (ret);\n } else {\n return (kth_element(t->nxt[f], k, bit_index - 1, xor_val));\n }\n }\n }\n\n D count_less(Node *t, const T &bit, int bit_index, T xor_val) {\n if (bit_index == -1) return (0);\n D ret = 0;\n bool f = (xor_val >> bit_index) & 1;\n if ((bit >> bit_index & 1) && t->nxt[f]) ret += t->nxt[f]->exist;\n if (t->nxt[f ^ (bit >> bit_index & 1)]) ret += count_less(t->nxt[f ^ (bit >> bit_index & 1)], bit, bit_index - 1, xor_val);\n return (ret);\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n int n, c;\n cin >> n >> c;\n\n vector<long long> score(n + 1);\n BinaryTrie<__uint128_t, 63> bt;\n\n for (int i = 1; i <= n; ++i) bt.add(n - i);\n\n for (int i = 0; i < c; ++i) {\n int com;\n cin >> com;\n if (com == 0) {\n int t, p;\n cin >> t >> p;\n\n bt.erase(score[t] * n + (n - t));\n score[t] += p;\n bt.add(score[t] * n + (n - t));\n } else {\n int m;\n cin >> m;\n\n auto res = bt.kth_element(n - m).first;\n\n cout << (int) (n - res % n) << ' ' << (long long) (res / n) << '\\n';\n }\n }\n\n return (0);\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 132168, "score_of_the_acc": -1.6538, "final_rank": 17 }, { "submission_id": "aoj_0343_5951719", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate <typename T, int MAX_LOG, typename D = int>\nstruct BinaryTrie {\npublic:\n struct Node {\n Node *nxt[2];\n D exist;\n vector<int> accept;\n\n Node() : nxt{nullptr, nullptr}, exist(0) {}\n };\n\n Node *root;\n\n explicit BinaryTrie() : root(new Node()) {}\n\n explicit BinaryTrie(Node *root) : root(root) {}\n\n void add(const T &bit, D delta = 1, int idx = -1, T xor_val = 0) {\n root = add(root, bit, idx, MAX_LOG, delta, xor_val);\n }\n\n void erase(const T &bit, D delta = 1, T xor_val = 0) {\n add(bit, -delta, -1, xor_val);\n }\n\n Node *find(const T &bit, T xor_val = 0) {\n return (find(root, bit, MAX_LOG, xor_val));\n }\n\n D count(const T &bit, T xor_val = 0) {\n auto node = find(bit, xor_val);\n return (node ? node->exist : 0);\n }\n\n pair<T, Node *> min_element(T xor_val = 0) {\n assert(root->exist > 0);\n return (kth_element(0, xor_val));\n }\n\n pair<T, Node *> max_element(T xor_val = 0) {\n assert(root->exist > 0);\n return (kth_element(root->exist - 1, xor_val));\n }\n\n pair<T, Node *> kth_element(D k, T xor_val = 0) {\n assert(0 <= k && k < root->exist);\n return (kth_element(root, k, MAX_LOG, xor_val));\n }\n\n D count_less(const T &bit, T xor_val = 0) {\n return (count_less(root, bit, MAX_LOG, xor_val));\n }\n\n D size() const {\n return (root->exist);\n }\n\nprivate:\n\n virtual Node *clone(Node *t) { return (t); }\n\n Node *add(Node *t, T bit, int idx, int depth, D x, T xor_val, bool need = true) {\n if (need) t = clone(t);\n if (depth == -1) {\n t->exist += x;\n if (idx >= 0) t->accept.emplace_back(idx);\n } else {\n bool f = (xor_val >> depth) & 1;\n auto &to = t->nxt[f ^ ((bit >> depth) & 1)];\n if (!to) to = new Node(), need = false;\n to = add(to, bit, idx, depth - 1, x, xor_val, need);\n t->exist += x;\n }\n return (t);\n }\n\n Node *find(Node *t, T bit, int depth, T xor_val) {\n if (depth == -1) {\n return (t);\n } else {\n bool f = (xor_val >> depth) & 1;\n auto &to = t->nxt[f ^ ((bit >> depth) & 1)];\n return (to ? find(to, bit, depth - 1, xor_val) : nullptr);\n }\n }\n\n pair<T, Node *> kth_element(Node *t, D k, int bit_index, T xor_val) {\n if (bit_index == -1) {\n return (make_pair(0, t));\n } else {\n bool f = (xor_val >> bit_index) & 1;\n if ((t->nxt[f] ? t->nxt[f]->exist : 0) <= k) {\n auto ret = kth_element(t->nxt[f ^ 1], k - (t->nxt[f] ? t->nxt[f]->exist : 0), bit_index - 1, xor_val);\n ret.first |= T(1) << bit_index;\n return (ret);\n } else {\n return (kth_element(t->nxt[f], k, bit_index - 1, xor_val));\n }\n }\n }\n\n D count_less(Node *t, const T &bit, int bit_index, T xor_val) {\n if (bit_index == -1) return (0);\n D ret = 0;\n bool f = (xor_val >> bit_index) & 1;\n if ((bit >> bit_index & 1) && t->nxt[f]) ret += t->nxt[f]->exist;\n if (t->nxt[f ^ (bit >> bit_index & 1)]) ret += count_less(t->nxt[f ^ (bit >> bit_index & 1)], bit, bit_index - 1, xor_val);\n return (ret);\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n int n, c;\n cin >> n >> c;\n\n vector<int64_t> score(n + 1);\n BinaryTrie<__uint128_t, 64> bt;\n\n for (int i = 1; i <= n; ++i) bt.add(n - i);\n\n for (int i = 0; i < c; ++i) {\n int com;\n cin >> com;\n if (com == 0) {\n int t, p;\n cin >> t >> p;\n\n bt.erase(score[t] * n + (n - t));\n score[t] += p;\n bt.add(score[t] * n + (n - t));\n } else {\n int m;\n cin >> m;\n\n auto res = bt.kth_element(n - m).first;\n\n cout << (long long) (n - res % n) << ' ' << (int) (res / n) << '\\n';\n }\n }\n\n return (0);\n}", "accuracy": 0.2916666666666667, "time_ms": 180, "memory_kb": 117700, "score_of_the_acc": -1.4974, "final_rank": 19 } ]
aoj_0341_cpp
Repeated Spell After discovering and investigating the ancient nation of Iwashiro, our researchers finally found a temple in the center of Iwashiro. The temple housed a stone tablet dedicated to the god of Iwashiro. On the tablet, there are two strings of text, one sentence and one spell. In Iashiro, The number of times a spell appears in a sentence has an important meaning. However, even if the spell appears sporadically in the sentence, it is considered to appear once. For example, if the sentence is "abab" and the spell is "ab", then "ab" appears three times in "abab", including non-consecutive occurrences (three patterns: ab ab, ab ab , a ba b .) Given a sentence and a spell, make a program to output the number of times the spell appears in the sentence. Input The input is given in the following format. t b In the first line, the string t represents the text written on the tablet is given. In the second line, the string b represents the spell written on the tablet is given. Both strings are made up of only lowercase letters and are between 1 and 1000 characters long. Output Output the number of times the spell appears in a sentence in a line. However, the value can be very large, so output the remainder divided by 1,000,000,007 instead. Sample Input 1 abab ab Sample Output 1 3 Sample Input 2 aaaabaaaabaaaabaaaab aaaaa Sample Output 2 4368 Sample Input 3 data structure Sample Output 3 0
[ { "submission_id": "aoj_0341_9605582", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\nint mod=1000000007;\n\nint dp[1009][1009];\n\nsigned main(){\n\tdp[0][0]=1;\n\tstring s,t;cin>>s>>t;\n\tint a=s.size(),b=t.size();\n\n\tfor(int i=0;i<a;i++){\n\t\tfor(int j=0;j<=b;j++){\n\t\t\tdp[i+1][j]=(dp[i+1][j]+dp[i][j])%mod;\n\t\t\tif(j<b&&s[i]==t[j]){\n\t\t\t\tdp[i+1][j+1]=(dp[i+1][j+1]+dp[i][j])%mod;\n\t\t\t}\n\t\t}\n\t}\n\n\tcout<<dp[a][b]<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11332, "score_of_the_acc": -0.3599, "final_rank": 9 }, { "submission_id": "aoj_0341_4740564", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// End Header }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n var(string, t, b);\n\n size_t T = t.size();\n size_t B = b.size();\n auto dp = makeVector<intmax_t>(-1, T, B);\n\n const intmax_t MOD = intmax_t(1e9) + 7;\n const auto res = makeFixPoint([&](auto rec, size_t i, size_t j) -> intmax_t {\n if (j == B) return 1;\n if (i == T) return 0;\n auto& ret = dp[i][j];\n if (~ret) return ret;\n ret = 0;\n ret += rec(i + 1, j) % MOD;\n if (t[i] == b[j]) ret = (ret + rec(i + 1, j + 1)) % MOD;\n return ret;\n })(0, 0);\n\n output(res);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10988, "score_of_the_acc": -0.3312, "final_rank": 6 }, { "submission_id": "aoj_0341_4740562", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// End Header }}}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n var(string, t, b);\n\n const size_t T = t.size();\n const size_t B = b.size();\n auto dp = makeVector<intmax_t>(-1, T, B);\n\n const intmax_t MOD = intmax_t(1e9) + 7;\n const auto res = makeFixPoint([&](auto rec, size_t i, size_t j) -> intmax_t {\n if (j == b.size()) return 1;\n if (i == t.size()) return 0;\n auto& ret = dp[i][j];\n if (~ret) return ret;\n ret = 0;\n ret += rec(i + 1, j) % MOD;\n if (t[i] == b[j]) ret = (ret + rec(i + 1, j + 1)) % MOD;\n return ret;\n })(0, 0);\n\n output(res);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10948, "score_of_the_acc": -0.3279, "final_rank": 5 }, { "submission_id": "aoj_0341_4735969", "code_snippet": "#include<bits/stdc++.h>\n \n#define lol long long\n#define gcd(x,y) __gcd(x,y)\n#define mt make_tuple\n#define mp make_pair\n#define fi first\n#define se second\n#define fixed(x) fixed<<setprecision(x)\nusing namespace std;\nusing pii=pair<int,int>;\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\ntemplate <class A> inline lol abs(A &a) { return (a < 0 ? -a : a); }\nbool inLine(int x,int y,int mx,int my){return (x>=0&&y>=0&&x<mx&&y<my);}\nconst lol inf=(1LL<<62);\nconst int MOD=(1e9)+7;\nconst int mod=998244353;\nconst int dx[]={1,0,-1,0,1,1,-1,-1};\nconst int dy[]={0,1,0,-1,1,-1,1,-1};\nlol n,m,k;\nlol sum[1010][1010];\nlol rui[1010][1010];\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n string t,b;\n cin >>t>>b;\n int T=t.size(),B=b.size();\n \n for(int i=1;i<=B;i++){\n for(int j=1;j<=T;j++){\n rui[i][j]=rui[i][j-1];\n if(b[i-1]==t[j-1]) rui[i][j]++; \n //cout <<rui[i][j]<<' ';\n }\n //cout <<'\\n';\n }\n\n lol ans=0;\n for(int i=0;i<B;i++){\n for(int j=0;j<T;j++){\n if(b[i]==t[j]){\n if(i==0) sum[i+1][j+1]=sum[i+1][j]+1;\n else{\n sum[i+1][j+1]=sum[i+1][j]+sum[i][j];\n }\n }else sum[i+1][j+1]=sum[i+1][j];\n sum[i+1][j+1]%=MOD;\n }\n }\n /*\n for(int i=0;i<=B;i++){\n for(int j=0;j<=T;j++) cout <<' '<<sum[i][j];\n cout <<'\\n';\n }*/\n cout <<sum[B][T]<<'\\n';\n return (0);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 19008, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0341_4735921", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Headelr {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define min(...) min({__VA_ARGS__})\n#define max(...) max({__VA_ARGS__})\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\nusing imax = intmax_t;\nusing usize = size_t;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// }}} End Header\n\nconstexpr int dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\nconstexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};\n\nconst auto inside = [](int y, int x, int H, int W) -> bool {\n return (y >= 0 && x >= 0 && y < H && x < W);\n};\n\nconst imax MOD = imax(1e9) + 7;\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n var(string, t, b);\n\n const usize T = t.size(), B = b.size();\n auto dp = makeVector<imax>(0, T + 1, B + 1);\n\n rep(i, 0, T) {\n dp[i + 1][1] = dp[i][1] + (t[i] == b[0]);\n }\n\n rep(i, 0, T) rep(j, 1, B) {\n dp[i + 1][j + 1] += dp[i][j + 1];\n if (t[i] == b[j]) {\n dp[i + 1][j + 1] += dp[i][j];\n }\n dp[i + 1][j + 1] %= MOD;\n }\n\n output(dp.back().back());\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10716, "score_of_the_acc": -0.3085, "final_rank": 3 }, { "submission_id": "aoj_0341_4735598", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin Headelr {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define min(...) min({__VA_ARGS__})\n#define max(...) max({__VA_ARGS__})\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\nusing imax = intmax_t;\nusing usize = size_t;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n cin >> head;\n input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n for (auto &e: vec) {\n is >> e;\n }\n return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n cout << head;\n if (sizeof...(tail)) {\n cout << \" \";\n }\n output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n static constexpr const char *delim[] = {\" \", \"\"};\n for (const auto &e: vec) {\n os << e << delim[&e == &vec.back()];\n }\n return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n Container &c;\n reverse_t(Container &c) : c(c) {}\n auto begin() { return c.rbegin(); }\n auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n return a < b ? b - a : a - b;\n}\n// }}} End Header\n\nconstexpr int dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\nconstexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};\n\nconst auto inside = [](int y, int x, int H, int W) -> bool {\n return (y >= 0 && x >= 0 && y < H && x < W);\n};\n\nconst imax MOD = imax(1e9) + 7;\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.setf(ios_base::fixed);\n cout.precision(10);\n\n var(string, t, b);\n\n const usize T = t.size(), B = b.size();\n auto dp = makeVector<imax>(0, T + 1, B + 1);\n // dp[i][j] := t の i 番目までのなかに、b の j 番目までの文字列は何個ふくまれるか。\n dp[0][0] = t[0] == b[0];\n\n rep(i, 0, T) rep(j, 0, B) {\n if (t[i] == b[j]) {\n dp[i + 1][j + 1] += dp[i][j];\n dp[i + 1][j + 1] %= MOD;\n }\n dp[i + 1][j] += dp[i][j];\n dp[i + 1][j] %= MOD;\n }\n\n imax res = 0;\n reps(i, 0, T) res = (res + dp[i][B]) % MOD;\n\n output(res);\n\n return 0;\n}", "accuracy": 0.7391304347826086, "time_ms": 10, "memory_kb": 10768, "score_of_the_acc": -0.3129, "final_rank": 17 }, { "submission_id": "aoj_0341_4309762", "code_snippet": "//y16-7\n#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775808\n#define LL_MAX 9223372036854775807\n#define segment_size 65536\n#define ROOP() while (true)\n\n#define large 1000000007\n\nstring t,b;\nLL dp[1000][1000];\n\nLL solve(int sekiban, int jumon){\n if(jumon == b.size()) return 1;\n if(sekiban == t.size()) return 0;\n if(dp[sekiban][jumon] != -1) return dp[sekiban][jumon];\n LL re = 0;\n for(int i=sekiban; i<t.size(); i++){\n if(t[i] == b[jumon]) re += solve(i+1, jumon+1);\n }\n re %= large;\n dp[sekiban][jumon] = re;\n return re;\n}\n\nint main(){\n cin >> t >> b;\n for(int i=0; i<t.size(); i++){\n for(int j=0; j<b.size(); j++){\n dp[i][j] = -1;\n }\n }\n cout << solve(0,0) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 11108, "score_of_the_acc": -0.9523, "final_rank": 11 }, { "submission_id": "aoj_0341_3646788", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef pair<ll,ll> mp;\n#define inf 1e9\nll mod = 1e9+7;\n\nint main(){\n\tstring t,b;\n\tcin>>t>>b;\n\tll n1 = t.size(),n2 = b.size();\n\tvector<vector<ll > > dp(n1,vector<ll> (n2,0) );\n\tfor(int i=0;i<n1;i++){\n\t\tif(t[i]==b[0])\tdp[i][0] = 1;\n\t}\n\tif(n1 < n2){\n\t\tcout<<0<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=1;i<n2;i++){\n\t\tll sum = 0;\n\t\tfor(int j=0;j<i;j++) {\n\t\t\tsum+=dp[j][i-1];\n\t\t\tsum%=mod;\n\t\t}\n\t\tfor(int j=i;j<n1;j++){\n\t\t\tif(t[j]==b[i]) {\n\t\t\t\tdp[j][i] = sum;\n\t\t\t}\n\t\t\tsum+=dp[j][i-1];\n\t\t\tsum%=mod;\n\t\t}\n\t}\n\tll res = 0;\n\t/*for(int i=0;i<n2;i++){\n\t\tfor(int j=0;j<n1;j++){\n\t\t\tcout<<dp[i][j]<<' ';\n\t\t}\n\t\tcout<<endl;\n\t}*/\n\tfor(int i=0;i<n1;i++) {\n\t\tres += dp[i][n2-1];\n\t\tres %= mod;\n\t}\n\tcout<<res<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10876, "score_of_the_acc": -0.3219, "final_rank": 4 }, { "submission_id": "aoj_0341_3622481", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef pair<ll,ll> mp;\n#define inf 1e9\nll mod = 1e9+7;\n\nint main(){\n\tstring t,b;\n\tcin>>t>>b;\n\tll n1 = t.size(),n2 = b.size();\n\tvector<vector<ll > > dp(n1,vector<ll> (n2,0) );\n\tfor(int i=0;i<n1;i++){\n\t\tif(t[i]==b[0])\tdp[i][0] = 1;\n\t}\n\tif(n1 < n2){\n\t\tcout<<0<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=1;i<n2;i++){\n\t\tll sum = 0;\n\t\tfor(int j=0;j<i;j++) {\n\t\t\tsum+=dp[j][i-1];\n\t\t\tsum%=mod;\n\t\t}\n\t\tfor(int j=i;j<n1;j++){\n\t\t\tif(t[j]==b[i]) {\n\t\t\t\tdp[j][i] = sum;\n\t\t\t}\n\t\t\tsum+=dp[j][i-1];\n\t\t\tsum%=mod;\n\t\t}\n\t}\n\tll res = 0;\n\t/*for(int i=0;i<n2;i++){\n\t\tfor(int j=0;j<n1;j++){\n\t\t\tcout<<dp[i][j]<<' ';\n\t\t}\n\t\tcout<<endl;\n\t}*/\n\tfor(int i=0;i<n1;i++) {\n\t\tres += dp[i][n2-1];\n\t\tres %= mod;\n\t}\n\tcout<<res<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10692, "score_of_the_acc": -0.3065, "final_rank": 2 }, { "submission_id": "aoj_0341_3534701", "code_snippet": "#include <iostream>\nusing namespace std;\n\nlong long MOD = 1000000007;\nlong long dp[1010][1010];\n\nint main(){\n string t, b;\n cin >> t >> b;\n\n for(int i = 0; i <= b.size(); i++){\n dp[0][i] = 0;\n }\n for(int i = 0; i <= t.size(); i++){\n dp[i][0] = 1;\n }\n\n for(int i = 0; i < t.size(); i++){\n for(int j = 0; j < b.size(); j++){\n if(t[i] == b[j]){\n dp[i+1][j+1] = (dp[i][j+1] + dp[i][j]) % MOD;\n }else{\n dp[i+1][j+1] = dp[i][j+1];\n }\n }\n }\n\n cout << dp[t.size()][b.size()] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11104, "score_of_the_acc": -0.3409, "final_rank": 8 }, { "submission_id": "aoj_0341_3135306", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nlong long mod = 1000000007, dp[1009][1009]; string S, T;\n\nint main() {\n\tcin >> S >> T;\n\tdp[0][0] = 1;\n\tfor (int i = 0; i < S.size(); i++) {\n\t\tfor (int j = 0; j <= T.size(); j++) {\n\t\t\tif (j < T.size() && S[i] == T[j]) { dp[i + 1][j + 1] += dp[i][j]; dp[i + 1][j + 1] %= mod; }\n\t\t\tdp[i + 1][j] += dp[i][j]; dp[i + 1][j] %= mod;\n\t\t}\n\t}\n\tcout << dp[S.size()][T.size()] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11092, "score_of_the_acc": -0.3399, "final_rank": 7 }, { "submission_id": "aoj_0341_3133033", "code_snippet": "#include<bits/stdc++.h>\n#include<string.h>\nusing namespace std;\nint main(void){\n\tchar a[1001],b[1001];\n\tint x,y,cnt;\n\tscanf(\"%s %s\",a,b);\n\tx=strlen(b); y=strlen(a);\n\tint dp[x][y],i,j,k;\n\tfor(i=0;i<x;i++){\n\t\tfor(j=0;j<y;j++) dp[i][j]=0;\n\t}\n//printf(\"x=%d y=%d\\n\",x,y);\n\tfor(i=0;i<y;i++){\n\t\tif(b[0]==a[i]) dp[0][i]=1;\n//printf(\" %d\",dp[0][i]);\n\t}\n//printf(\"\\n\");\n\tfor(i=1;i<x;i++){\n\t\tfor(j=i-1;j<y-1;j++){\n\t\t\tif(dp[i-1][j]>0){\n//printf(\"j=%d \",j);\t\n\t\t\t\tfor(k=j+1;k<y;k++){\n\t\t\t\t\tif(b[i]==a[k]) dp[i][k]=(dp[i][k]+dp[i-1][j])%1000000007;\n//printf(\" %d\",dp[i-1][j]);\n\t\t\t\t}\n//printf(\"\\n\");\n\t\t\t}\n/*for(k=0;k<y;k++)printf(\" %d\",dp[i][k]);\nprintf(\"\\n\");*/\n\t\t}\n\t}\n/*for(i=0;i<x;i++){\n\tprintf(\"%d \",i);\n\tfor(j=0;j<y;j++) printf(\" %d\",dp[i][j]);\n\tprintf(\"\\n\");\n}*/\n\tcnt=0;\n\tfor(i=0;i<y;i++) cnt=(cnt+dp[x-1][i])%1000000007;\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 7120, "score_of_the_acc": -0.2642, "final_rank": 1 }, { "submission_id": "aoj_0341_3132589", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\nint sht[1000][1000];\n\nint main(){\n string t;//原文\n string b;//呪文\n int i,j,k,ans=0;\n \n for(i=0;i<1000;i++){\n \tfor(j=0;j<1000;j++){\n\t\tsht[i][j]=0;\n\t}\n }\n \n cin>>t>>b;\n //1行目\n for(i=0;i<t.size();i++){\n \tif(b[0]==t[i]){\n\t\tsht[i][0]=1;\n\t}else{\n\t\tsht[i][0]=0;\n\t}\n }\n //2行目以降\n for(i=1;i<b.size();i++){\n \tfor(j=0;j<t.size();j++){\n\t\tif(b[i]==t[j] && j>=i){\n\t\t\tfor(k=0;k<j;k++){\n\t\t\t\tsht[j][i]=(sht[j][i]+sht[k][i-1])%1000000007;\n\t\t\t}\n\t\t}\n\t}\n }\n for(j=0;j<t.size();j++){\n \tans=(ans+sht[j][i-1])%1000000007;\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 7140, "score_of_the_acc": -1.0103, "final_rank": 14 }, { "submission_id": "aoj_0341_3132586", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\nint sht[1000][1000];\n\nint main(){\n string t;//原文\n string b;//呪文\n long long int i,j,k,ans=0;\n \n for(i=0;i<1000;i++){\n \tfor(j=0;j<1000;j++){\n\t\tsht[i][j]=0;\n\t}\n }\n \n cin>>t>>b;\n //1行目\n for(i=0;i<t.size();i++){\n \tif(b[0]==t[i]){\n\t\tsht[i][0]=1;\n\t}else{\n\t\tsht[i][0]=0;\n\t}\n }\n //2行目以降\n for(i=1;i<b.size();i++){\n \tfor(j=0;j<t.size();j++){\n\t\tif(b[i]==t[j] && j>=i){\n\t\t\tfor(k=0;k<j;k++){\n\t\t\t\tsht[j][i]=(sht[j][i]+sht[k][i-1])%1000000007;\n\t\t\t}\n\t\t}\n\t}\n }\n for(j=0;j<t.size();j++){\n \tans=(ans+sht[j][i-1])%1000000007;\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 7128, "score_of_the_acc": -0.9982, "final_rank": 12 }, { "submission_id": "aoj_0341_3132584", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n\nlong long int p[1000][1000];\n\nint main(){\n\nstring A;\nstring B;\n\nlong long int j=0;\nlong long int i=0;\nlong long int c=0;\n\nlong long int answer=0;\nlong long int final=0;\n\nlong long int n=0;//上の文の文字数\nlong long int m=0;//下の文の文字数\n\ncin>>A;\ncin>>B;\n\nn=A.size(); //4\nm=B.size(); //2\n\n/////p全部に0を代入する///////\n\nfor(i=0;i<1000;i++){\nfor(j=0;j<1000;j++){\n\tp[j][i]=0;\n}\n}\n\n//////////////////////////////\n\n////一番上の段だけみる////\n\nfor(i=0;i<n;i++){\n\tif(A[i]==B[0]){\n\t\tp[i][0]=1;\t\t\t\n\t}\n}\n\n///////////////////////\n\n\n\n\nfor(j=1;j<m;j++){ //j=1 \nfor(i=0;i<n;i++){ //i=0,1,2,3\n\n\tif(A[i]==B[j]){\n\t\tfor(c=0;c<i;c++){\n\t\t\tp[i][j]=p[i][j]+p[c][j-1]%1000000007; //\n\t\t}\n\t\t//cout<<p[i][j]%1000000007;\t\t\t\n\t}else{\n\t\t//cout<<0;\n\t}\n\t\n}\n\n//cout<<endl;\n\n}\n\nfor(i=0;i<n;i++){\n\tanswer=answer%1000000007+p[i][m-1]%1000000007;\n}\n\nfinal=answer%1000000007;\n\ncout<<final<<endl;\n\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 11056, "score_of_the_acc": -1.1813, "final_rank": 16 }, { "submission_id": "aoj_0341_3132569", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\nint sht[1000][1000];\n\nint main(){\n string t;//原文\n string b;//呪文\n int i;\n int j;\n int k;\n int ans=0;\n \n for(i=0;i<1000;i++){\n \tfor(j=0;j<1000;j++){\n\t\tsht[i][j]=0;\n\t}\n }\n \n cin>>t>>b;\n //1行目\n for(i=0;i<t.size();i++){\n \tif(b[0]==t[i]){\n\t\tsht[i][0]=1;\n\t}else{\n\t\tsht[i][0]=0;\n\t}\n }\n //2行目以降\n for(i=1;i<b.size();i++){\n \tfor(j=0;j<t.size();j++){\n\t\tif(b[i]==t[j] && j>=i){\n\t\t\tfor(k=0;k<j;k++){\n\t\t\t\tsht[j][i]=sht[j][i]+sht[k][i-1];\n\t\t\t}\n\t\t}\n\t}\n }\n for(j=0;j<t.size();j++){\n \tans=(ans+sht[j][i-1])%1000000007;\n }\n cout<<ans<<endl;\n}", "accuracy": 0.43478260869565216, "time_ms": 80, "memory_kb": 7076, "score_of_the_acc": -0.0828, "final_rank": 18 }, { "submission_id": "aoj_0341_3132561", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n\nlong long int p[1000][1000];\n\nint main(){\n\nstring A;\nstring B;\n\nlong long int j=0;\nlong long int i=0;\nlong long int c=0;\n\nlong long int answer=0;\nlong long int final=0;\n\nlong long int n=0;//上の文の文字数\nlong long int m=0;//下の文の文字数\n\ncin>>A;\ncin>>B;\n\nn=A.size(); //4\nm=B.size(); //2\n\n/////p全部に0を代入する///////\n\nfor(i=0;i<1000;i++){\nfor(j=0;j<1000;j++){\n\tp[j][i]=0;\n}\n}\n\n//////////////////////////////\n\n////一番上の段だけみる////\n\nfor(i=0;i<n;i++){\n\tif(A[i]==B[0]){\n\t\tp[i][0]=1;\t\t\t\n\t}\n}\n\n///////////////////////\n\n\n\n\nfor(j=1;j<m;j++){ //j=1 \nfor(i=0;i<n;i++){ //i=0,1,2,3\n\n\tif(A[i]==B[j]){\n\t\tfor(c=0;c<i;c++){\n\t\t\tp[i][j]=p[i][j]+p[c][j-1]; //\n\t\t}\n\t\t//cout<<p[i][j];\t\t\t\n\t}else{\n\t\t//cout<<0;\n\t}\n\t\n}\n\n//cout<<endl;\n\n}\n\nfor(i=0;i<n;i++){\n\tanswer=answer%1000000007+p[i][m-1]%1000000007;\n}\n\nfinal=answer%1000000007;\n\ncout<<final<<endl;\n\n}", "accuracy": 0.43478260869565216, "time_ms": 90, "memory_kb": 11056, "score_of_the_acc": -0.4258, "final_rank": 20 }, { "submission_id": "aoj_0341_3129112", "code_snippet": "#include<bits/stdc++.h>\n#define NN 1000000007\nusing namespace std;\nint dp[1001][1001];\nint main(void)\n{\n\tchar a[1001],b[1001];\n\t\n\tint i,j,k;\n\t\n\tcin>>a;\n\tcin>>b;\n\t\n\tint x=strlen(a);\n\tint y=strlen(b);\n\t\n\t\n\t\n\tfor(i=0;i<y;i++){\n\t\tfor(j=0;j<x;j++){\n\t\t\tdp[i][j]=0;\n\t\t}\n\t}\n\t\n\tfor(i=0;i<x;i++){\n\t\tif(a[i]==b[0]){\n\t\t\tdp[0][i]=1;\n\t\t}\n\t}\n\t\n\t\n\t\n\tfor(i=1;i<y;i++){\n\t\tfor(j=0;j<x;j++){\n\t\t\tfor(k=j+1;k<x;k++){\n\t\t\t\t//cout<<\"a=\"<<a[i]<<\" \"<<\"k=\"<<k<<\" \"<<\"b=\"<<b[k]<<endl;\n\t\t\t\tif(a[k]==b[i]){\n\t\t\t\t\t//cout<<\"check\"<<endl;\n\t\t\t\t\tdp[i][k]=(dp[i][k]+dp[i-1][j])%NN;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\t/*for(i=0;i<y;i++){\n\t\tfor(j=0;j<x;j++){\n\t\t\tcout<<dp[i][j]<<\" \";\n\t\t}\n\t\tcout<<endl;\n\t}*/\n\t\n\tint sum=0;\n\tfor(i=0;i<x;i++){\n\t\tsum=(sum+dp[y-1][i])%NN;\n\t}\n\tcout<<sum<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 7016, "score_of_the_acc": -0.7889, "final_rank": 10 }, { "submission_id": "aoj_0341_3125773", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint i,j,h,k,p;\nlong long v[1001][1001],M=1000000007;\nlong long int sum;\ndouble def;\nint main(void)\n{\n\tchar s[1001],t[1001];\n\tcin>>s>>t;\n\th=strlen(s);\n\tk=strlen(t);\n\tfor(i=0;i<=h;i++) for(j=0;j<=h;j++) v[i][j]=0;\n\tfor(i=0;i<h;i++) if(s[i]==t[0]) v[0][i]=1;\n\tfor(p=0;p<k;p++){\n\t\tfor(i=p;i<h;i++){\n\t\t\tif(s[i]==t[p]){\n\t\t\t\tfor(j=i+1;j<h;j++){\n\t\t\t\t\tif(s[j]==t[p+1]){\n\t\t\t\t\t\tv[p+1][j]+=v[p][i];\n\t\t\t\t\t\tif(M<v[p+1][j]) v[p+1][j]%=M;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}/*\n\tfor(i=0;i<k;i++){\n\t\tfor(j=0;j<h;j++) cout<<v[i][j]<<\" \";\n\t\tcout<<endl;\n\t}*/\n\tsum=0;\n\tfor(i=0;i<h;i++){\n\t\tsum+=v[k-1][i];\n\t\tif(M<sum) sum=sum%M;\n\t}\n\tcout<<sum<<endl;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 10964, "score_of_the_acc": -1.0737, "final_rank": 15 }, { "submission_id": "aoj_0341_3125762", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint i,j,h,k,p;\nlong long v[1001][1001],sum;\nint main(void)\n{\n\tchar s[1001],t[1001];\n\tcin>>s>>t;\n\th=strlen(s);\n\tk=strlen(t);\n\tfor(i=0;i<=h;i++) for(j=0;j<=h;j++) v[i][j]=0;\n\tfor(i=0;i<h;i++) if(s[i]==t[0]) v[0][i]=1;\n\tfor(p=0;p<k;p++){\n\t\tfor(i=p;i<h;i++){\n\t\t\tif(s[i]==t[p]){\n\t\t\t\tfor(j=i+1;j<h;j++){\n\t\t\t\t\tif(s[j]==t[p+1]){\n\t\t\t\t\t\tv[p+1][j]+=v[p][i];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}/*\n\tfor(i=0;i<k;i++){\n\t\tfor(j=0;j<h;j++) cout<<v[i][j]<<\" \";\n\t\tcout<<endl;\n\t}*/\n\tsum=0;\n\tfor(i=0;i<h;i++) sum+=v[k-1][i];\n\tsum=sum%1000000007;\n\tcout<<sum<<endl;\n}", "accuracy": 0.43478260869565216, "time_ms": 70, "memory_kb": 10904, "score_of_the_acc": -0.3909, "final_rank": 19 } ]
aoj_0347_cpp
有理式最大化 N 個の異なる自然数が与えられる。その中から異なる4つを選んで、それらを $A$, $B$, $C$, $D$ としたとき、次の数式 $\frac{A + B}{C - D}$ の最大値を求めたい。 N 個の異なる自然数が与えられたとき、その中から異なる4つを選んで、上の数式の最大値を求めるプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N a 1 a 2 ... a N 1行目に自然数の個数 N (4 ≤ N ≤ 1000) が与えられる。2行目に各自然数の値 a i (1 ≤ a i ≤ 10 8 ) が与えられる。ただし、同じ自然数が重複して現れることはない( i ≠ j について a i ≠ a j )。 Output 与えられた N 個の自然数に対して、上の数式の最大値を実数で出力する。ただし、誤差がプラスマイナス 10 -5 を超えてはならない。 Sample Input 1 10 1 2 3 4 5 6 7 8 9 10 Sample Output 1 19.00000 入力例1では、$A=9$, $B=10$, $C=2$, $D=1$ などの組み合わせで最大になる。 Sample Input 2 5 22 100 42 3 86 Sample Output 2 9.78947 入力例2では、$A=100$, $B=86$, $C=22$, $D=3$ などの組み合わせで最大になる。 Sample Input 3 6 15 21 36 10 34 5 Sample Output 3 18.00000 入力例3では、$A=21$, $B=15$, $C=36$, $D=34$ などの組み合わせで最大になる。 Sample Input 4 4 100000 99999 8 1 Sample Output 4 28571.285714
[ { "submission_id": "aoj_0347_11017140", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int n;\n cin>>n;\n vector<int> s(n);\n for(int i=0;i<n;i++) cin>>s[i];\n sort(s.begin(),s.end());\n multiset<int> st;\n for(int i=0;i<n;i++) st.insert(s[i]);\n double ans = 0;\n for(int i=0;i<n;i++)for(int j=i+1;j<n;j++){\n double t = s[j]-s[i];\n st.erase(st.find(s[i]));\n st.erase(st.find(s[j]));\n int a = *st.rbegin();\n st.erase(st.find(a));\n int b = *st.rbegin();\n ans = max(ans,(a+b)/t);\n st.insert(a);\n st.insert(s[i]);\n st.insert(s[j]);\n }\n cout<<fixed<<setprecision(14)<<ans<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3584, "score_of_the_acc": -0.2353, "final_rank": 8 }, { "submission_id": "aoj_0347_10848485", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<'='<<x<<endl;\n\nusing P = pair<int,int>;\n\nint N;\nvector<int>a;\nint main(){\n\tcin>>N;\n\tfor(int i=0;i<N;++i){\n\t\tint aa;cin>>aa;\n\t\ta.push_back(aa);\n\t}\n\tvector<P>sum,dif;\n\tfor(int i=0;i<N;++i)for(int j=0;j<N;++j)if(a[i]<a[j]){\n\t\tsum.push_back({a[i],a[j]});dif.push_back({a[i],a[j]});\n\t}\n\tsort(sum.begin(),sum.end(),[](const P&p1,const P&p2){\n\t\treturn p1.first+p1.second<p2.first+p2.second;\n\t});\n\tsort(dif.begin(),dif.end(),[](const P&p1,const P&p2){\n\t\treturn -p1.first+p1.second<-p2.first+p2.second;\n\t});\n\tlong double ans = 0.0;\n\tfor(auto p : sum){\n\t\tint A=p.first,B=p.second;\n\t\tint C=0,D=0;\n\t\tfor(auto q : dif){\n\t\t\tif(q.first!=A&&q.first!=B&&q.second!=A&&q.second!=B){\n\t\t\t\tC=q.second;\n\t\t\t\tD=q.first;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tans = max(ans,((long double)A+B) / (C-D));\n\t}\n\tcout.precision(15);\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 13072, "score_of_the_acc": -0.548, "final_rank": 14 }, { "submission_id": "aoj_0347_10845800", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define DB(x) cout<<#x<<'='<<x<<endl;\n\nusing P = pair<int,int>;\n\nint N;\nvector<int>a;\nint main(){\n\tcin>>N;\n\tfor(int i=0;i<N;++i){\n\t\tint aa;cin>>aa;\n\t\ta.push_back(aa);\n\t}\n\tvector<P>sum,dif;\n\tfor(int i=0;i<N;++i)for(int j=0;j<N;++j)if(a[i]<a[j]){\n\t\tsum.push_back({a[i],a[j]});dif.push_back({a[i],a[j]});\n\t}\n\tsort(sum.begin(),sum.end(),[](const P&p1,const P&p2){\n\t\treturn p1.first+p1.second<p2.first+p2.second;\n\t});\n\tsort(dif.begin(),dif.end(),[](const P&p1,const P&p2){\n\t\treturn -p1.first+p1.second<-p2.first+p2.second;\n\t});\n\tlong double ans = 0.0;\n\tfor(auto p : sum){\n\t\tint A=p.first,B=p.second;\n\t\tint C=0,D=0;\n\t\tfor(auto q : dif){\n\t\t\tif(q.first!=A&&q.first!=B&&q.second!=A&&q.second!=B){\n\t\t\t\tC=q.second;\n\t\t\t\tD=q.first;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tans = max(ans,((long double)A+B) / (C-D));\n\t}\n\tcout.precision(15);\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12700, "score_of_the_acc": -0.5343, "final_rank": 13 }, { "submission_id": "aoj_0347_9289042", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n vi a(N);\n rep(i, N) cin >> a[i];\n sort(all(a));\n vc<tuple<ll,ll,ll>> b;\n rep(i, N-1) rep(j, i+1, N) b.eb(mt(abs(a[i]-a[j]), i, j));\n sort(all(b));\n double ans = 0;\n rep(i, N-1) rep(j, i+1, N) {\n ll A = a[i];\n ll B = a[j];\n rep(k, len(b)) {\n if (get<1>(b[k]) == i) continue;\n if (get<1>(b[k]) == j) continue;\n if (get<2>(b[k]) == i) continue;\n if (get<2>(b[k]) == j) continue;\n ll CD = get<0>(b[k]);\n chmax(ans, double(A+B) / CD);\n break;\n }\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 16944, "score_of_the_acc": -0.7616, "final_rank": 17 }, { "submission_id": "aoj_0347_6969430", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0347.cc: Maximizing Rational Expression\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 1000;\nconst int INF = 1 << 29;\n\n/* typedef */\n\nstruct Elm {\n int l, r, d;\n Elm() {}\n Elm(int _x): l(_x), r(_x), d(INF) {}\n Elm(int _l, int _r, int _d): l(_l), r(_r), d(_d) {}\n\n Elm operator+(const Elm &e) const {\n if (l >= INF) return e;\n if (e.l >= INF) return *this;\n return Elm(l, e.r, min(e.l - r, min(d, e.d)));\n }\n};\n\ntemplate <typename T>\nstruct SegTreeSum {\n int e2;\n vector<T> nodes;\n T defv;\n SegTreeSum() {}\n\n void init(int n, T _defv) {\n defv = _defv;\n for (e2 = 1; e2 < n; e2 <<= 1);\n nodes.assign(e2 * 2, defv);\n }\n\n T &geti(int i) { return nodes[e2 - 1 + i]; }\n void seti(int i, T v) { geti(i) = v; }\n\n void setall() {\n for (int j = e2 - 2; j >= 0; j--)\n nodes[j] = nodes[j * 2 + 1] + nodes[j * 2 + 2];\n }\n\n void set(int i, T v) {\n int j = e2 - 1 + i;\n nodes[j] = v;\n while (j > 0) {\n j = (j - 1) / 2;\n nodes[j] = nodes[j * 2 + 1] + nodes[j * 2 + 2];\n }\n }\n\n T sum_range(int r0, int r1, int k, int i0, int i1) {\n if (r1 <= i0 || i1 <= r0) return defv;\n if (r0 <= i0 && i1 <= r1) return nodes[k];\n\n int im = (i0 + i1) / 2;\n T v0 = sum_range(r0, r1, k * 2 + 1, i0, im);\n T v1 = sum_range(r0, r1, k * 2 + 2, im, i1);\n return v0 + v1;\n }\n T sum_range(int r0, int r1) { return sum_range(r0, r1, 0, 0, e2); }\n};\n\n/* global variables */\n\nint as[MAX_N];\nSegTreeSum<Elm> st;\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n sort(as, as + n);\n\n st.init(n, Elm(INF));\n for (int i = 0; i < n; i++) st.seti(i, Elm(as[i]));\n st.setall();\n\n double maxr = 0.0;\n for (int i = 0; i < n; i++)\n for (int j = i + 1; j < n; j++) {\n if (i + 1 == j) {\n\tElm e0 = st.sum_range(0, i);\n\tElm e1 = st.sum_range(j + 1, n);\n\tint x0 = (i > 0) ? as[i - 1] : -INF;\n\tint x1 = (j + 1 < n) ? as[j + 1] : INF;\n\tint d = min(x1 - x0, min(e0.d, e1.d));\n\tmaxr = max(maxr, (double)(as[i] + as[j]) / d);\n\t//printf(\"i=%d,j=%d -> d=%d\\n\", i, j, d);\n }\n else {\n\tElm e0 = st.sum_range(0, i);\n\tElm e1 = st.sum_range(i + 1, j);\n\tElm e2 = st.sum_range(j + 1, n);\n\tint x0 = (i > 0) ? as[i - 1] : -INF;\n\tint x1 = as[i + 1];\n\tint x2 = as[j - 1];\n\tint x3 = (j + 1 < n) ? as[j + 1] : INF;\n\tint d = min(min(x1 - x0, x3 - x2), min(e0.d, min(e1.d, e2.d)));\n\tmaxr = max(maxr, (double)(as[i] + as[j]) / d);\n\t//printf(\"i=%d,j=%d -> d=%d\\n\", i, j, d);\n }\n }\n\n printf(\"%.8lf\\n\", maxr);\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3012, "score_of_the_acc": -0.3571, "final_rank": 11 }, { "submission_id": "aoj_0347_6401996", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <iomanip>\nusing namespace std;\nusing ld = long double;\n\nint main(){\n int n; cin >> n;\n vector<int> a(n);\n for(auto &it: a) cin >> it;\n\n sort(a.begin(), a.end());\n vector<ld> res;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n if(i == j) continue;\n int p, q;\n for(p = n-1; p >= 0; p--){\n if(p != i && p != j) break;\n }\n for(q = n-1; q >= 0; q--){\n if(q != p && q != i && q != j) break;\n }\n res.emplace_back((ld)(a[p]+a[q])/(a[i]-a[j]));\n }\n }\n sort(res.begin(), res.end());\n cout << fixed << setprecision(10) << res.back() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 21556, "score_of_the_acc": -0.931, "final_rank": 18 }, { "submission_id": "aoj_0347_4813679", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\nint main() {\n init();\n\n int n; cin >> n;\n vector<ld> a(n); cin >> a;\n SORT(a);\n ld ans = 0;\n FOR(i, 0, n)FOR(j, 0, i) {\n vector<ld> b;\n for (int k = n - 1; b.size() < 2; --k) {\n if (k != i && k != j)b.push_back(a[k]);\n }\n chmax(ans, (b[0] + b[1]) / (a[i] - a[j]));\n }\n print(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3324, "score_of_the_acc": -0.0472, "final_rank": 5 }, { "submission_id": "aoj_0347_4600868", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int n;\n cin >> n;\n vector<int> v(n);\n for (auto &&i : v) scanf(\"%d\", &i);\n sort(v.begin(),v.end(), greater<>());\n double ans = 0;\n for (int i = 0; i < n; ++i) {\n for (int j = i+1; j < n; ++j) {\n for (int k = 0; k < 3; ++k) {\n for (int l = k+1; l < 4; ++l) {\n if(i != k && i != l && j != k && j != l){\n ans = max(ans, 1.0*(v[k]+v[l])/(v[i]-v[j]));\n }\n }\n }\n }\n }\n printf(\"%.10lf\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -0.01, "final_rank": 1 }, { "submission_id": "aoj_0347_4600450", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N;\nint Data[1000];\nmultiset<int> Numbers;\n\nint main() {\n\tdouble maxSum, minSub, ans;\n\n\tNumbers.clear();\n\tcin >> N;\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> Data[i];\n\t\tNumbers.insert(Data[i]);\n\t}\n\n\tans = 0.0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tNumbers.erase(Numbers.find(Data[i]));\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tif (i == j) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tNumbers.erase(Numbers.find(Data[j]));\n\t\t\tmaxSum = *(Numbers.rbegin()) + *(++Numbers.rbegin());\n\t\t\tminSub = abs(Data[i] - Data[j]);\n\t\t\tans = max(ans, maxSum / minSub);\n\t\t\tNumbers.insert(Data[j]);\n\t\t}\n\t\tNumbers.insert(Data[i]);\n\t}\n\tcout << fixed << setprecision(6) << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3280, "score_of_the_acc": -0.4384, "final_rank": 12 }, { "submission_id": "aoj_0347_4487960", "code_snippet": "#include \"bits/stdc++.h\"\n#define int long long\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define FOR(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define inv(i, a, b) for (int i = (int)(a); i >= (int)(b); i--)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n#define endl \"\\n\"\n#define Endl \"\\n\"\n\nusing namespace std;\nconst int MOD = (int)(1e9 + 7);\nconst int INF = (int)(1e13 + 7);\n\nint CEIL(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); } //ceil() for int\nint mod(int a, int b) { return a >= 0 ? a % b : a - (b * CEIL(a, b)); } //always return positive num\nint bpm(int x, unsigned int y) { //return x^y in order(log(y))\n if (x == 0) return 0;\n if (y == 0) return 1;\n int ans = 1;\n int digit = (int)((log((double)y) / log((double)2) / 1 + 1));\n x %= MOD;\n for (int i = 0; i < digit; i++) {\n if (((y >> i) & 1u) == 1) ans = ans * x % MOD;\n x = x * x % MOD;\n }\n return ans;\n}\ntemplate<class T>\nvoid cumulative_sum(T &container) {\n for (int i = 0; i < container.size() - 1; i++) container[i + 1] += container[i];\n}\n\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int N;\n cin >> N;\n vector<double> a(N);\n rep(i, N) cin >> a[i];\n double ans = -INF;\n sort(ALL(a));\n vector<vector<double>> check(N * (N - 1) / 2, vector<double>(3));\n int now = 0;\n rep(i, N - 1) {\n FOR(j, i + 1, N) {\n check[now++] = {a[j] - a[i], a[i], a[j]};\n }\n }\n sort(ALL(check));\n rep(i, N - 1) {\n FOR(j, i + 1, N) {\n rep(k, check.size()) {\n if (a[i] != check[k][1] and a[i] != check[k][2] and a[j] != check[k][1] and a[j] != check[k][2]) {\n ans = max(ans, (a[i] + a[j]) / check[k][0]);\n break;\n }\n }\n }\n }\n cout << fixed << setprecision(10) << ans << endl;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 30244, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0347_4487660", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\n#include<iomanip>\nusing namespace std;\n\nint main(){\n long long int n,z=0;\n double ans=0;\n cin>>n;\n vector<double>a(1000000);\n vector<double>b(1000000);\n for(int i=0;i<n;i++){\n cin>>a[i];\n }\n sort(a.begin(),a.end(),greater<>());\n for(int i=0;i<n-1;i++){\n for(int j=0;j<n-1;j++){\n if(ans<(a[i]+a[i+1])/(a[j]-a[j+1])&&i!=j&&i+1!=j&&i!=j+1){\n ans=(a[i]+a[i+1])/(a[j]-a[j+1]);\n }\n }\n }\n cout<<fixed <<setprecision(6)<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 18400, "score_of_the_acc": -0.5651, "final_rank": 15 }, { "submission_id": "aoj_0347_3898866", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set>\nusing namespace std;\n//int p = 998244353;\nint p = 1000000007;\n#define int long long\n#define vel vector<long long>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\nint max_kai = 150000;\nvel kai(max_kai, 1);\nvel inv_kai;\nint rui(int a, int n) {\n\tif (n == 0) { return 1; }\n\tint x = rui(a, n / 2);\n\tx *= x; x %= p;\n\tif (n % 2 == 1) { x *= a; x %= p; }\n\treturn x;\n}\nint inv(int a) { return rui(a, p - 2); }\nvoid make_kai() {\n\tfor (int i = 1; i < max_kai; i++) { kai[i] = kai[i - 1] * i; kai[i] %= p; }\n\tinv_kai = kai;\n\trep(i, max_kai) { inv_kai[i] = inv(kai[i]); }\n}\nint nCr(int n, int r) {\n\tint a = kai[n] * inv_kai[r]; a %= p;\n\ta *= inv_kai[n - r]; a %= p;\n\treturn a;\n}\nint inf = 6000000000000;\nvel dijk(vvel &way, vel &cost, int s) {\n\tint n = way.size(); int m = 7 * n;\n\tvel ans(m, inf);\n\tpriority_queue<pin, vector<pin>, greater<pin>> que;//cost,pla\n\tque.push(mkp(0,s));\n\twhile (!que.empty()) {\n\t\tpin x = que.top(); que.pop();\n\t\tint pla = x.second;\n\t\tif (ans[pla] == inf) {\n\t\t\tint sum_cost = x.first;\n\t\t\tans[pla] = sum_cost;\n\t\t\tint nex_cost = sum_cost + cost[pla];\n\t\t\tint mod = nex_cost % 7;\n\t\t\tfor (auto x : way[pla/7]) {\n\t\t\t\tque.push(mkp(nex_cost, x * 7 + mod));\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) {pa[x] = y;}\n}\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)-h.begin()\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)-h.begin()\nint sol(int a, int b, int c, int d) {\n\treturn abs(a*c - b * d);\n}\nsigned main(){\n\tint n; cin >> n;\n\tV<double> a(n);\n\trep(i, n) { cin >> a[i]; }\n\tsor(a);\n\tdouble ans=0;\n\trep(i, n) {\n\t\trep(j, i) {\n\t\t\tvel ex;\n\t\t\tfor (int k = n-1; k >= n-4; k--) {\n\t\t\t\tif (k != i && k != j) {\n\t\t\t\t\tex.push_back(k);\n\t\t\t\t}\n\t\t\t}\n\t\t\tmmax(ans, (a[ex[0]] + a[ex[1]]) / (a[i] - a[j]) );\n\t\t}\n\t}\n\tprintf(\"%.6lf\\n\", ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4304, "score_of_the_acc": -0.1189, "final_rank": 6 }, { "submission_id": "aoj_0347_3675414", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long double ld;\n\nint main() {\n int N;\n cin >> N;\n ld a[N], ans = 0;\n for (auto &x : a) cin >> x;\n vector<pair<ld, int>> tmp;\n for (int i = 0; i < N; i++) {\n tmp.push_back(make_pair(a[i], i));\n }\n sort(tmp.begin(), tmp.end());\n vector<int> index;\n for (int i = N - 4; i < N; i++) {\n index.push_back(tmp[i].second);\n }\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (i == j) continue;\n ld C = a[i];\n ld D = a[j];\n vector<int> MAX;\n for (int k = 3; 0 <= k && MAX.size() != 2; k--) {\n if (index[k] != i && index[k] != j) {\n MAX.push_back(index[k]);\n }\n }\n ans = max(ans, (a[MAX[0]] + a[MAX[1]]) / (C - D));\n }\n }\n cout << fixed << setprecision(10) << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3356, "score_of_the_acc": -0.1555, "final_rank": 7 }, { "submission_id": "aoj_0347_3440333", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include \"bits/stdc++.h\"\nusing namespace std;\n#define rep(i, n) for(int i=0; i<(n); ++i)\n#define FOR(i, m, n) for(int i=(m); i<(n); ++i)\n#define sz(x) ((int)(x).size())\n#define all(x) (x).begin(),(x).end()\n#define mp make_pair\n#define pb push_back\n#define Cout(x) cout << (x) << endl\n#define Cout2(x, y) cout << (x) << \" \" << (y) << endl\n#define dump(x) cerr << #x << \" = \" << (x) << endl;\ntypedef long long LL;\ntypedef vector<int> VI;\ntypedef vector<LL> VL;\ntypedef vector<string> VS;\ntypedef vector<bool> VB;\ntypedef vector<vector<int>> VVI;\ntypedef pair<int, int> PII;\nconst int inf = 1e9;\nconst double pi = acos(-1.0);\n\nint main() {\n\tint n; cin >> n;\n\tVI a(n); rep(i, n)cin >> a[i];\n\tsort(all(a));\n\t\n\tdouble ans = -(double)inf;\n\trep(i, n) {\n\t\tFOR(j, i + 1, n) {\n\t\t\tint cd = a[j] - a[i];\n\t\t\tVI v_ab;\n\t\t\tfor (int k = n - 1; k >= 0; --k) {\n\t\t\t\tif (k != i && k != j)v_ab.pb(a[k]);\n\t\t\t\tif (sz(v_ab) == 2)break;\n\t\t\t}\n\t\t\tint ab = v_ab[0] + v_ab[1];\n\n\t\t\tans = max(ans, (double)ab / cd);\n\t\t}\n\t}\n\tprintf(\"%.20f\\n\", ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3244, "score_of_the_acc": -0.0442, "final_rank": 3 }, { "submission_id": "aoj_0347_2797327", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n vector<int> a(n);\n multiset<int, greater<int>> s;\n for(int i = 0; i < n; ++i) {\n cin >> a[i];\n s.insert(a[i]);\n }\n\n double ans = 0;\n for(int i = 0; i < n; ++i) {\n for(int j = i + 1; j < n; ++j) {\n s.erase(a[i]);\n s.erase(a[j]);\n double x = abs(a[i] - a[j]);\n double y = *s.begin() + *(next(s.begin()));\n s.insert(a[i]);\n s.insert(a[j]);\n ans = max(ans, y / x);\n }\n }\n\n cout << fixed << setprecision(10) << ans << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3324, "score_of_the_acc": -0.2972, "final_rank": 10 }, { "submission_id": "aoj_0347_2367185", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <cstdio>\n\nusing namespace std;\n\ntypedef pair<long long int, long long int> P;\ntypedef pair<long long int, P> Q;\n\nbool ss(P a, P b) {\n\tif (a.first != b.first && a.first != b.second && a.second != b.first && a.second != b.second) {\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nint main() {\n\tint n;\n\tcin >> n;\n\tvector<long long int> a(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tsort(a.begin(), a.end());\n\tvector<Q> b;\n\tvector<Q> c;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = i + 1; j < n; j++) {\n\t\t\tb.push_back(Q(a[j]-a[i], P(a[i], a[j])));\n\t\t\tc.push_back(Q(a[j]+a[i], P(a[i], a[j])));\n\t\t}\n\t}\n\tdouble MAX = 0.0;\n\tint sz = b.size();\n\tsort(b.begin(), b.end());\n\tsort(c.begin(), c.end());\n\tfor (int i = 0; i < sz; i++) {\n\t\tif (ss(b[0].second, c[i].second)) {\n\t\t\tMAX = max(MAX, (double)c[i].first / (double)b[0].first);\n\t\t}\n\t\tif (ss(b[i].second, c[sz - 1].second)) {\n\t\t\tMAX = max(MAX, (double)c[sz-1].first / (double)b[i].first);\n\t\t}\n\t}\n\tprintf(\"%.10f\\n\", MAX);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 26684, "score_of_the_acc": -1.3336, "final_rank": 19 }, { "submission_id": "aoj_0347_2309225", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define pb push_back \n#define pf push_front \n#define mp make_pair\n#define fr first\n#define sc second\n#define Rep(i,n) for(int i=0;i<(n);i++)\n#define All(v) v.begin(),v.end()\ntypedef pair<int, int> Pii; typedef pair<int, Pii> Pip;\nconst int INF = 1107110711071107;\n\n\nmain()\n{\n int N;\n int data[1001];\n vector<Pip> v;\n\n cin >> N;\n Rep(i, N) cin >> data[i];\n\n for(int i=0; i<N-1; i++) {\n for(int j=i+1; j<N; j++) {\n v.pb( Pip( data[i] + data[j], Pii( i, j ) ) );\n }\n }\n\n sort( All( v ) );\n /*for(int i=0; i<v.size(); i++) {\n cout << v[i].fr << endl;\n }*/\n double mx = 0;\n for(int i=0; i<N; i++) {\n for(int j=0; j<N; j++) {\n if( i == j ) continue;\n if( data[i] - data[j] == 0 ) {\n\tcontinue;\n }\n else if( data[i] - data[j] > 0 ) {\n\tfor(int k=v.size()-1; k>=0; k--) {\n\t Pip p = v[k];\n\t if( p.sc.fr == i || p.sc.fr == j || p.sc.sc == i || p.sc.sc == j ) continue;\n\t else {\n\t mx = max( mx, (double)((double)p.fr / (double)(data[i] - data[j])) );\n\t break;\n\t }\n\t}\n } \n }\n }\n\n printf(\"%.7lf\\n\", mx);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 15152, "score_of_the_acc": -0.5887, "final_rank": 16 }, { "submission_id": "aoj_0347_2204211", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\ndouble calFormula(const int64_t &A, const int64_t &B, const int64_t &C, const int64_t &D)\n{\n return (double)(A+B) / (C-D);\n}\n\nint main()\n{\n\n int N;\n cin >> N;\n\n vector<int64_t> list(N);\n for(int i = 0; i < N; i++)\n {\n cin >> list[i];\n }\n\n sort(list.begin(),list.end());\n reverse(list.begin(),list.end());\n\n double max_val = 0;\n //loop\n\n for(int a = 0; a < N; a++)\n {\n if(a > 10){ break; }\n for(int b = a + 1; b < N; b++)\n {\n if(b > 10){ break; }\n for(int c = 0; c < N; c++)\n {\n if(a == c || b == c){ continue; }\n for(int d = c + 1; d < N; d++)\n {\n if(a == d || b == d){ continue; }\n max_val = max(max_val, calFormula( list[a], list[b], list[c], list[d] ));\n }\n }\n }\n }\n\n\n cout << fixed << setprecision(5);\n cout << max_val << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3284, "score_of_the_acc": -0.2957, "final_rank": 9 }, { "submission_id": "aoj_0347_2126892", "code_snippet": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;++i)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-6)\n#define equals(a,b) (fabs((a)-(b))<EPS)\n\nusing namespace std;\n\nbool LT(double a,double b) { return !equals(a,b) && a < b; }\nbool LTE(double a,double b) { return equals(a,b) || a < b; }\n\nint n, a[1010];\n\nint main() {\n cin >> n;\n rep(i,n) cin >> a[i];\n sort(a,a+n);\n double maxi = 0;\n rep(i,n) REP(j,i+1,n) {\n double C = a[j], D = a[i];\n double A,B;\n int k = n-1;\n vector<int> ps;\n while( ps.size() < 2 ) {\n assert( k >= 0 );\n if( k != i && k != j ) ps.push_back(k);\n --k;\n }\n A = a[ps[0]];\n B = a[ps[1]];\n maxi = max(maxi,(A+B)/(C-D));\n }\n printf(\"%.10f\\n\",maxi);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3256, "score_of_the_acc": -0.0447, "final_rank": 4 }, { "submission_id": "aoj_0347_2119510", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nint n, a[10000], T[10000];\nint main() {\n\tcin >> n; for (int i = 0; i < n; i++)cin >> a[i];\n\tsort(a, a + n);\n\tlong double maxn = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = i + 1; j < n; j++) {\n\t\t\tT[i] = 1; T[j] = 1;\n\t\t\tvector<int>vec;\n\t\t\tfor (int k = n - 1; k >= 0; k--) {\n\t\t\t\tif (T[k] == 0)vec.push_back(a[k]);\n\t\t\t\tif (vec.size() == 2)break;\n\t\t\t}\n\t\t\tmaxn = max(maxn, 1.0l*(vec[0] + vec[1]) / (a[j] - a[i]));\n\t\t\tT[i] = 0; T[j] = 0;\n\t\t}\n\t}\n\tprintf(\"%.15Lf\\n\", maxn);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -0.0439, "final_rank": 2 } ]
aoj_0344_cpp
Game Strategy You have found an old board game in the club room of your programming club. It looks interesting, so you decide to play it. The game consists of M events, and you have to capture event i at time t i . However, your strength must be at least s i at that time. Otherwise, the game is over. At the beginning of the game (time 0), your strength is 0, but you can increase it by buying items. Your money is also 0 at the beginning of the game, but it increases by 1 per unit of time. There are N items on the board, numbered 1 to N . Item i costs v i , and buying it increases your strength by h i . You can buy as many items as you want at any time, as long as you have enough money. However, you must choose the item with the lowest number among the remaining items. Each item will be disappeared after it is bought. You can also buy multiple items in a row at the same time, and get a bonus equal to the sum of the differences in h i of the adjacent items. For example, if you buy items 1, 2, 3 at the same time, your strength will increase by | h 1 - h 2 | + | h 2 - h 3 | in addition to h 1 + h 2 + h 3 . You want to maximize the amount of money you have, after capturing all the events. Make a program to output the maximum amount of money you have after capturing all the events, using the information of items and events given in input. Input The input is given in the following format. N M v 1 h 1 v 2 h 2 : v N h N t 1 s 1 t 2 s 2 : t M s M In the first line, the number of items N (1 ≤ N ≤ 3000) and the number of events M (1 ≤ M ≤ 1000) are given. In the following N lines, the cost v i and the increase in strength h i (1 ≤ v i , h i ≤ 100000) of the item i are given. In the following M lines, the time t i and the condition s i (1 ≤ t i , s i ≤ 100000) of the event i are given. However, if i < j , then t i < t j . All inputs are given as integers. Output Output the maximum amount of money you have in a line. However, if it is not possible to capture the events, output -1. Sample Input 1 5 4 3 3 2 1 1 5 4 2 2 6 4 1 8 2 10 4 12 17 Sample Output 1 2 Sample Input 2 5 4 3 3 2 1 1 5 4 2 2 6 4 1 8 2 10 4 12 30 Sample Output 2 -1
[ { "submission_id": "aoj_0344_10862866", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first;\n#define se second;\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\nint main(){\n int N,M;\n cin>>N>>M;\n vector<int> v(N),h(N);\n rep(i,N)cin>>v[i]>>h[i];\n\n vector<int> V(N+1,0),H(N+1,0);\n rep(i,N) V[i+1]=V[i]+v[i];\n rep(i,N) H[i+1]=H[i]+h[i];\n\n vector<int> HS(N+1,0);\n rep(i,N) HS[i+1]=HS[i]+h[i]+(i!=0?abs(h[i]-h[i-1]):0);\n\n vector<int> dp(N+1,-1e9);\n dp[0]=0;\n int mae=0;\n rep(_,M){\n int t,s;\n cin>>t>>s;\n vector<int> np(N+1,-1e9);\n \n int r=upper_bound(all(V), t)-V.begin();\n rep(i,N){\n if(dp[i]<0) continue;\n \n if(dp[i]+h[i]>=s){\n chmax(np[i+1], dp[i]+h[i]);\n }\n else {\n int l=lower_bound(all(HS), s-(dp[i]+h[i]-HS[i+1]))-HS.begin();\n chmax(l, i+2);\n chmax(np[l], dp[i]+h[i]+HS[l]-HS[i+1]);\n }\n }\n rep(i,N-1){\n chmax(np[i+2], np[i+1]+h[i+1]+abs(h[i+1]-h[i]));\n }\n\n rep(i,N+1){\n if(dp[i]>=s){\n chmax(np[i], dp[i]);\n }\n }\n\n for(int i=r;i<=N;i++) np[i]=-1e9;\n swap(dp, np);\n mae=t;\n }\n int ans=-1;\n rep(i,N+1) if(dp[i]>=0){\n ans=mae-V[i];\n break;\n }\n cout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3472, "score_of_the_acc": -0.0009, "final_rank": 3 }, { "submission_id": "aoj_0344_10859263", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n// ref: https://nyaannyaan.github.io/library/hashmap/hashmap.hpp.html\nnamespace HashMapImpl {\nusing u32 = uint32_t;\nusing u64 = uint64_t;\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase;\n\ntemplate <typename Key, typename Data>\nstruct itrB {\n // [UPDATE] C++17 で非推奨になった std::iterator template から変更\n using iterator_category = bidirectional_iterator_tag;\n using value_type = Data;\n using difference_type = ptrdiff_t;\n using pointer = value_type*;\n using reference = value_type&;\n\n u32 i;\n HashMapBase<Key, Data>* p;\n\n explicit constexpr itrB() : i(0), p(nullptr) {}\n explicit constexpr itrB(u32 _i, HashMapBase<Key, Data>* _p) : i(_i), p(_p) {}\n explicit constexpr itrB(u32 _i, const HashMapBase<Key, Data>* _p) : i(_i), p(const_cast<HashMapBase<Key, Data>*>(_p)) {}\n friend void swap(itrB& l, itrB& r) { swap(l.i, r.i), swap(l.p, r.p); }\n friend bool operator==(const itrB& l, const itrB& r) { return l.i == r.i; }\n friend bool operator!=(const itrB& l, const itrB& r) { return l.i != r.i; }\n const reference operator*() const { return const_cast<const HashMapBase<Key, Data>*>(p)->data[i]; }\n reference operator*() { return p->data[i]; }\n pointer operator->() const { return &(p->data[i]); }\n\n itrB& operator++() {\n assert(i != p->cap && \"itr::operator++()\");\n do {\n i++;\n if (i == p->cap) break;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n } while (true);\n return (*this);\n }\n itrB operator++(int) {\n itrB it(*this);\n ++(*this);\n return it;\n }\n itrB& operator--() {\n do {\n i--;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n assert(i != 0 && \"itr::operator--()\");\n } while (true);\n return (*this);\n }\n itrB operator--(int) {\n itrB it(*this);\n --(*this);\n return it;\n }\n};\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase {\n using u32 = uint32_t;\n using u64 = uint64_t;\n using iterator = itrB<Key, Data>;\n using itr = iterator;\n\n protected:\n template <typename K>\n inline u64 randomized(const K& key) const {\n return u64(key) ^ r;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<K>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n return (randomized(key) * 11995408973635179863ULL) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::first)>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::second)>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n u64 a = randomized(key.first), b = randomized(key.second);\n a *= 11995408973635179863ULL;\n b *= 10150724397891781847ULL;\n return (a + b) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& elem : key) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n // [ADD] 数値を要素とする 2 次元コンテナ用のハッシュ関数を追加\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<!is_integral<typename K::value_type>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& container : key) {\n for (auto& elem : container) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat);\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat.first);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat;\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat.first;\n }\n\n void reallocate(u32 ncap) {\n vector<Data> ndata(ncap);\n vector<bool> nf(ncap);\n shift = 64 - __lg(ncap);\n for (u32 i = 0; i < cap; i++) {\n if (occupied_flag[i] && !deleted_flag[i]) {\n u32 h = hash(data[i]);\n while (nf[h]) h = (h + 1) & (ncap - 1);\n ndata[h] = move(data[i]);\n nf[h] = true;\n }\n }\n data.swap(ndata);\n occupied_flag.swap(nf);\n cap = ncap;\n occupied = s;\n deleted_flag.resize(cap);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n }\n\n inline bool extend_rate(u32 x) const { return x * 2 >= cap; }\n\n inline bool shrink_rate(u32 x) const { return HASHMAP_DEFAULT_SIZE < cap && x * 10 <= cap; }\n\n inline void extend() { reallocate(cap << 1); }\n\n inline void shrink() { reallocate(cap >> 1); }\n\n public:\n u32 cap, s, occupied;\n vector<Data> data;\n vector<bool> occupied_flag, deleted_flag;\n u32 shift;\n static u64 r;\n static constexpr uint32_t HASHMAP_DEFAULT_SIZE = 4;\n\n explicit HashMapBase() : cap(HASHMAP_DEFAULT_SIZE), s(0), occupied(0), data(cap), occupied_flag(cap), deleted_flag(cap), shift(64 - __lg(cap)) {}\n\n itr begin() const {\n u32 h = 0;\n while (h != cap) {\n if (occupied_flag[h] && !deleted_flag[h]) break;\n h++;\n }\n return itr(h, this);\n }\n itr end() const { return itr(this->cap, this); }\n\n friend itr begin(const HashMapBase& h) { return h.begin(); }\n friend itr end(const HashMapBase& h) { return h.end(); }\n\n itr find(const Key& key) const {\n u32 h = inner_hash(key);\n while (true) {\n if (occupied_flag[h] == false) return this->end();\n if (data_to_key(data[h]) == key) {\n if (deleted_flag[h] == true) return this->end();\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n bool contain(const Key& key) const { return find(key) != this->end(); }\n\n itr insert(const Data& d) {\n u32 h = hash(d);\n while (true) {\n if (occupied_flag[h] == false) {\n if (extend_rate(occupied + 1)) {\n extend();\n h = hash(d);\n continue;\n }\n data[h] = d;\n occupied_flag[h] = true;\n ++occupied, ++s;\n return itr(h, this);\n }\n if (data_to_key(data[h]) == data_to_key(d)) {\n if (deleted_flag[h] == true) {\n data[h] = d;\n deleted_flag[h] = false;\n ++s;\n }\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n // tips for speed up :\n // if return value is unnecessary, make argument_2 false.\n itr erase(itr it, bool get_next = true) {\n if (it == this->end()) return this->end();\n s--;\n if (!get_next) {\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) shrink();\n return this->end();\n }\n itr nxt = it;\n nxt++;\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) {\n Data d = data[nxt.i];\n shrink();\n it = find(data_to_key(d));\n }\n return nxt;\n }\n\n itr erase(const Key& key) { return erase(find(key)); }\n\n int count(const Key& key) { return find(key) == end() ? 0 : 1; }\n\n bool empty() const { return s == 0; }\n\n int size() const { return s; }\n\n void clear() {\n fill(std::begin(occupied_flag), std::end(occupied_flag), false);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n s = occupied = 0;\n }\n\n void reserve(int n) {\n if (n <= 0) return;\n n = 1 << min(23, __lg(n) + 2);\n if (cap < u32(n)) reallocate(n);\n }\n};\n\ntemplate <typename Key, typename Data>\nuint64_t HashMapBase<Key, Data>::r = chrono::duration_cast<chrono::nanoseconds>(chrono::high_resolution_clock::now().time_since_epoch()).count();\n\n} // namespace HashMapImpl\n\ntemplate <typename Key, typename Val>\nstruct HashMap : HashMapImpl::HashMapBase<Key, pair<Key, Val>> {\n using base = typename HashMapImpl::HashMapBase<Key, pair<Key, Val>>;\n using HashMapImpl::HashMapBase<Key, pair<Key, Val>>::HashMapBase;\n using Data = pair<Key, Val>;\n\n Val& operator[](const Key& k) {\n typename base::u32 h = base::inner_hash(k);\n while (true) {\n if (base::occupied_flag[h] == false) {\n if (base::extend_rate(base::occupied + 1)) {\n base::extend();\n h = base::hash(k);\n continue;\n }\n base::data[h].first = k;\n base::data[h].second = Val();\n base::occupied_flag[h] = true;\n ++base::occupied, ++base::s;\n return base::data[h].second;\n }\n if (base::data[h].first == k) {\n if (base::deleted_flag[h] == true) {\n base::data[h].second = Val();\n base::deleted_flag[h] = false;\n ++base::s;\n }\n return base::data[h].second;\n }\n h = (h + 1) & (base::cap - 1);\n }\n }\n\n typename base::itr emplace(const Key& key, const Val& val) { return base::insert(Data(key, val)); }\n};\n\ntemplate <typename Key>\nstruct HashSet : HashMapImpl::HashMapBase<Key, Key> {\n using HashMapImpl::HashMapBase<Key, Key>::HashMapBase;\n};\n\nconstexpr int MAX = 100010;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<int> v(N), h(N);\n for (int i = 0; i < N; i++) cin >> v[i] >> h[i];\n vector<int> t(M), s(M);\n for (int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n // s[i] は実質的に単調増加列とみなせる\n if (i - 1 >= 0) s[i] = max(s[i], s[i - 1]);\n }\n // d[i] := |h[i + 1] - h[i]|\n vector<ll> d(N - 1), accd(N), acch(N + 1), accv(N + 1);\n for (int i = 0; i + 1 < N; i++) d[i] = abs(h[i + 1] - h[i]);\n for (int i = 0; i + 1 < N; i++) accd[i + 1] = accd[i] + d[i];\n for (int i = 0; i < N; i++) {\n acch[i + 1] = acch[i] + h[i];\n accv[i + 1] = accv[i] + v[i];\n }\n\n // f(i, j) := [i, j) のアイテムを購入したときの強さの増分\n auto f = [&](int i, int j) -> ll { return acch[j] - acch[i] + max<ll>(0, accd[j - 1] - accd[i]); };\n\n // dp[i][j] := i 番目のイベント終了時,\n // 強さ j\n // のどこまでアイテムを買ったかの min\n vector<unordered_map<ll, int>> dp(M + 1);\n dp[0][0] = 0;\n for (int i = 0; i < M; i++) {\n for (auto&& [key, val] : dp[i]) {\n // 強さ key, アイテムは [0, val) まで購入\n for (int j = val + 1; j <= N; j++) {\n // [val, j) までのアイテムを購入: 強さは key + f(val, j)\n ll next_strong = key + f(val, j);\n // t[i] が [0, j) の v の総和未満なら break\n if (t[i] < accv[j]) break;\n // 次の場所まで skip (次の場所に行けない場合は continue)\n int next_event = upper_bound(s.begin(), s.end(), next_strong) - s.begin();\n if (next_event <= i) continue;\n if (dp[next_event].contains(next_strong)) {\n dp[next_event][next_strong] = min(dp[next_event][next_strong], j);\n } else {\n dp[next_event][next_strong] = j;\n }\n }\n }\n }\n\n ll ans = -1;\n for (auto&& [key, val] : dp[M]) {\n // 強さ key, アイテムは [0, val) まで購入\n ans = max(ans, t[M - 1] - accv[val]);\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 5248, "score_of_the_acc": -0.345, "final_rank": 11 }, { "submission_id": "aoj_0344_10858987", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n// ref: https://nyaannyaan.github.io/library/hashmap/hashmap.hpp.html\nnamespace HashMapImpl {\nusing u32 = uint32_t;\nusing u64 = uint64_t;\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase;\n\ntemplate <typename Key, typename Data>\nstruct itrB {\n // [UPDATE] C++17 で非推奨になった std::iterator template から変更\n using iterator_category = bidirectional_iterator_tag;\n using value_type = Data;\n using difference_type = ptrdiff_t;\n using pointer = value_type*;\n using reference = value_type&;\n\n u32 i;\n HashMapBase<Key, Data>* p;\n\n explicit constexpr itrB() : i(0), p(nullptr) {}\n explicit constexpr itrB(u32 _i, HashMapBase<Key, Data>* _p) : i(_i), p(_p) {}\n explicit constexpr itrB(u32 _i, const HashMapBase<Key, Data>* _p) : i(_i), p(const_cast<HashMapBase<Key, Data>*>(_p)) {}\n friend void swap(itrB& l, itrB& r) { swap(l.i, r.i), swap(l.p, r.p); }\n friend bool operator==(const itrB& l, const itrB& r) { return l.i == r.i; }\n friend bool operator!=(const itrB& l, const itrB& r) { return l.i != r.i; }\n const reference operator*() const { return const_cast<const HashMapBase<Key, Data>*>(p)->data[i]; }\n reference operator*() { return p->data[i]; }\n pointer operator->() const { return &(p->data[i]); }\n\n itrB& operator++() {\n assert(i != p->cap && \"itr::operator++()\");\n do {\n i++;\n if (i == p->cap) break;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n } while (true);\n return (*this);\n }\n itrB operator++(int) {\n itrB it(*this);\n ++(*this);\n return it;\n }\n itrB& operator--() {\n do {\n i--;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n assert(i != 0 && \"itr::operator--()\");\n } while (true);\n return (*this);\n }\n itrB operator--(int) {\n itrB it(*this);\n --(*this);\n return it;\n }\n};\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase {\n using u32 = uint32_t;\n using u64 = uint64_t;\n using iterator = itrB<Key, Data>;\n using itr = iterator;\n\n protected:\n template <typename K>\n inline u64 randomized(const K& key) const {\n return u64(key) ^ r;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<K>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n return (randomized(key) * 11995408973635179863ULL) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::first)>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::second)>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n u64 a = randomized(key.first), b = randomized(key.second);\n a *= 11995408973635179863ULL;\n b *= 10150724397891781847ULL;\n return (a + b) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& elem : key) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n // [ADD] 数値を要素とする 2 次元コンテナ用のハッシュ関数を追加\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<!is_integral<typename K::value_type>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& container : key) {\n for (auto& elem : container) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat);\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat.first);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat;\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat.first;\n }\n\n void reallocate(u32 ncap) {\n vector<Data> ndata(ncap);\n vector<bool> nf(ncap);\n shift = 64 - __lg(ncap);\n for (u32 i = 0; i < cap; i++) {\n if (occupied_flag[i] && !deleted_flag[i]) {\n u32 h = hash(data[i]);\n while (nf[h]) h = (h + 1) & (ncap - 1);\n ndata[h] = move(data[i]);\n nf[h] = true;\n }\n }\n data.swap(ndata);\n occupied_flag.swap(nf);\n cap = ncap;\n occupied = s;\n deleted_flag.resize(cap);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n }\n\n inline bool extend_rate(u32 x) const { return x * 2 >= cap; }\n\n inline bool shrink_rate(u32 x) const { return HASHMAP_DEFAULT_SIZE < cap && x * 10 <= cap; }\n\n inline void extend() { reallocate(cap << 1); }\n\n inline void shrink() { reallocate(cap >> 1); }\n\n public:\n u32 cap, s, occupied;\n vector<Data> data;\n vector<bool> occupied_flag, deleted_flag;\n u32 shift;\n static u64 r;\n static constexpr uint32_t HASHMAP_DEFAULT_SIZE = 4;\n\n explicit HashMapBase() : cap(HASHMAP_DEFAULT_SIZE), s(0), occupied(0), data(cap), occupied_flag(cap), deleted_flag(cap), shift(64 - __lg(cap)) {}\n\n itr begin() const {\n u32 h = 0;\n while (h != cap) {\n if (occupied_flag[h] && !deleted_flag[h]) break;\n h++;\n }\n return itr(h, this);\n }\n itr end() const { return itr(this->cap, this); }\n\n friend itr begin(const HashMapBase& h) { return h.begin(); }\n friend itr end(const HashMapBase& h) { return h.end(); }\n\n itr find(const Key& key) const {\n u32 h = inner_hash(key);\n while (true) {\n if (occupied_flag[h] == false) return this->end();\n if (data_to_key(data[h]) == key) {\n if (deleted_flag[h] == true) return this->end();\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n bool contain(const Key& key) const { return find(key) != this->end(); }\n\n itr insert(const Data& d) {\n u32 h = hash(d);\n while (true) {\n if (occupied_flag[h] == false) {\n if (extend_rate(occupied + 1)) {\n extend();\n h = hash(d);\n continue;\n }\n data[h] = d;\n occupied_flag[h] = true;\n ++occupied, ++s;\n return itr(h, this);\n }\n if (data_to_key(data[h]) == data_to_key(d)) {\n if (deleted_flag[h] == true) {\n data[h] = d;\n deleted_flag[h] = false;\n ++s;\n }\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n // tips for speed up :\n // if return value is unnecessary, make argument_2 false.\n itr erase(itr it, bool get_next = true) {\n if (it == this->end()) return this->end();\n s--;\n if (!get_next) {\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) shrink();\n return this->end();\n }\n itr nxt = it;\n nxt++;\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) {\n Data d = data[nxt.i];\n shrink();\n it = find(data_to_key(d));\n }\n return nxt;\n }\n\n itr erase(const Key& key) { return erase(find(key)); }\n\n int count(const Key& key) { return find(key) == end() ? 0 : 1; }\n\n bool empty() const { return s == 0; }\n\n int size() const { return s; }\n\n void clear() {\n fill(std::begin(occupied_flag), std::end(occupied_flag), false);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n s = occupied = 0;\n }\n\n void reserve(int n) {\n if (n <= 0) return;\n n = 1 << min(23, __lg(n) + 2);\n if (cap < u32(n)) reallocate(n);\n }\n};\n\ntemplate <typename Key, typename Data>\nuint64_t HashMapBase<Key, Data>::r = chrono::duration_cast<chrono::nanoseconds>(chrono::high_resolution_clock::now().time_since_epoch()).count();\n\n} // namespace HashMapImpl\n\ntemplate <typename Key, typename Val>\nstruct HashMap : HashMapImpl::HashMapBase<Key, pair<Key, Val>> {\n using base = typename HashMapImpl::HashMapBase<Key, pair<Key, Val>>;\n using HashMapImpl::HashMapBase<Key, pair<Key, Val>>::HashMapBase;\n using Data = pair<Key, Val>;\n\n Val& operator[](const Key& k) {\n typename base::u32 h = base::inner_hash(k);\n while (true) {\n if (base::occupied_flag[h] == false) {\n if (base::extend_rate(base::occupied + 1)) {\n base::extend();\n h = base::hash(k);\n continue;\n }\n base::data[h].first = k;\n base::data[h].second = Val();\n base::occupied_flag[h] = true;\n ++base::occupied, ++base::s;\n return base::data[h].second;\n }\n if (base::data[h].first == k) {\n if (base::deleted_flag[h] == true) {\n base::data[h].second = Val();\n base::deleted_flag[h] = false;\n ++base::s;\n }\n return base::data[h].second;\n }\n h = (h + 1) & (base::cap - 1);\n }\n }\n\n typename base::itr emplace(const Key& key, const Val& val) { return base::insert(Data(key, val)); }\n};\n\ntemplate <typename Key>\nstruct HashSet : HashMapImpl::HashMapBase<Key, Key> {\n using HashMapImpl::HashMapBase<Key, Key>::HashMapBase;\n};\n\nconstexpr int MAX = 100010;\n// int v[MAX], h[MAX], t[MAX], s[MAX];\n// ll d[MAX], accd[MAX], acch[MAX], accv[MAX];\n// HashMap<ll, int> dp[MAX];\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<int> v(N), h(N);\n for (int i = 0; i < N; i++) cin >> v[i] >> h[i];\n vector<int> t(M), s(M);\n for (int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n // s[i] は実質的に単調増加列とみなせる\n if (i - 1 >= 0) s[i] = max(s[i], s[i - 1]);\n }\n // d[i] := |h[i + 1] - h[i]|\n vector<ll> d(N - 1), accd(N), acch(N + 1), accv(N + 1);\n for (int i = 0; i + 1 < N; i++) d[i] = abs(h[i + 1] - h[i]);\n for (int i = 0; i + 1 < N; i++) accd[i + 1] = accd[i] + d[i];\n for (int i = 0; i < N; i++) {\n acch[i + 1] = acch[i] + h[i];\n accv[i + 1] = accv[i] + v[i];\n }\n\n // f(i, j) := [i, j) のアイテムを購入したときの強さの増分\n auto f = [&](int i, int j) -> ll { return acch[j] - acch[i] + max<ll>(0, accd[j - 1] - accd[i]); };\n\n // dp[i][j] := i 番目のイベント終了時,\n // 強さ j\n // のどこまでアイテムを買ったかの min\n vector<unordered_map<ll, int>> dp(M + 1);\n dp[0][0] = 0;\n for (int i = 0; i < M; i++) {\n for (auto&& [key, val] : dp[i]) {\n // 強さ key, アイテムは [0, val) まで購入\n for (int j = val + 1; j <= N; j++) {\n // [val, j) までのアイテムを購入: 強さは key + f(val, j)\n ll next_strong = key + f(val, j);\n // t[i] が [0, j) の v の総和未満なら break\n if (t[i] < accv[j]) break;\n // 次の場所まで skip (次の場所に行けない場合は continue)\n int next_event = upper_bound(s.begin(), s.end(), next_strong) - s.begin();\n if (next_event <= i) continue;\n if (dp[next_event].contains(next_strong)) {\n dp[next_event][next_strong] = min(dp[next_event][next_strong], j);\n } else {\n dp[next_event][next_strong] = j;\n }\n }\n }\n }\n\n ll ans = -1;\n for (auto&& [key, val] : dp[M]) {\n // 強さ key, アイテムは [0, val) まで購入\n ans = max(ans, t[M - 1] - accv[val]);\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 5248, "score_of_the_acc": -0.3331, "final_rank": 10 }, { "submission_id": "aoj_0344_10858985", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n// ref: https://nyaannyaan.github.io/library/hashmap/hashmap.hpp.html\nnamespace HashMapImpl {\nusing u32 = uint32_t;\nusing u64 = uint64_t;\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase;\n\ntemplate <typename Key, typename Data>\nstruct itrB {\n // [UPDATE] C++17 で非推奨になった std::iterator template から変更\n using iterator_category = bidirectional_iterator_tag;\n using value_type = Data;\n using difference_type = ptrdiff_t;\n using pointer = value_type*;\n using reference = value_type&;\n\n u32 i;\n HashMapBase<Key, Data>* p;\n\n explicit constexpr itrB() : i(0), p(nullptr) {}\n explicit constexpr itrB(u32 _i, HashMapBase<Key, Data>* _p) : i(_i), p(_p) {}\n explicit constexpr itrB(u32 _i, const HashMapBase<Key, Data>* _p) : i(_i), p(const_cast<HashMapBase<Key, Data>*>(_p)) {}\n friend void swap(itrB& l, itrB& r) { swap(l.i, r.i), swap(l.p, r.p); }\n friend bool operator==(const itrB& l, const itrB& r) { return l.i == r.i; }\n friend bool operator!=(const itrB& l, const itrB& r) { return l.i != r.i; }\n const reference operator*() const { return const_cast<const HashMapBase<Key, Data>*>(p)->data[i]; }\n reference operator*() { return p->data[i]; }\n pointer operator->() const { return &(p->data[i]); }\n\n itrB& operator++() {\n assert(i != p->cap && \"itr::operator++()\");\n do {\n i++;\n if (i == p->cap) break;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n } while (true);\n return (*this);\n }\n itrB operator++(int) {\n itrB it(*this);\n ++(*this);\n return it;\n }\n itrB& operator--() {\n do {\n i--;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n assert(i != 0 && \"itr::operator--()\");\n } while (true);\n return (*this);\n }\n itrB operator--(int) {\n itrB it(*this);\n --(*this);\n return it;\n }\n};\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase {\n using u32 = uint32_t;\n using u64 = uint64_t;\n using iterator = itrB<Key, Data>;\n using itr = iterator;\n\n protected:\n template <typename K>\n inline u64 randomized(const K& key) const {\n return u64(key) ^ r;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<K>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n return (randomized(key) * 11995408973635179863ULL) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::first)>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::second)>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n u64 a = randomized(key.first), b = randomized(key.second);\n a *= 11995408973635179863ULL;\n b *= 10150724397891781847ULL;\n return (a + b) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& elem : key) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n // [ADD] 数値を要素とする 2 次元コンテナ用のハッシュ関数を追加\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<!is_integral<typename K::value_type>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& container : key) {\n for (auto& elem : container) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat);\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat.first);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat;\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat.first;\n }\n\n void reallocate(u32 ncap) {\n vector<Data> ndata(ncap);\n vector<bool> nf(ncap);\n shift = 64 - __lg(ncap);\n for (u32 i = 0; i < cap; i++) {\n if (occupied_flag[i] && !deleted_flag[i]) {\n u32 h = hash(data[i]);\n while (nf[h]) h = (h + 1) & (ncap - 1);\n ndata[h] = move(data[i]);\n nf[h] = true;\n }\n }\n data.swap(ndata);\n occupied_flag.swap(nf);\n cap = ncap;\n occupied = s;\n deleted_flag.resize(cap);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n }\n\n inline bool extend_rate(u32 x) const { return x * 2 >= cap; }\n\n inline bool shrink_rate(u32 x) const { return HASHMAP_DEFAULT_SIZE < cap && x * 10 <= cap; }\n\n inline void extend() { reallocate(cap << 1); }\n\n inline void shrink() { reallocate(cap >> 1); }\n\n public:\n u32 cap, s, occupied;\n vector<Data> data;\n vector<bool> occupied_flag, deleted_flag;\n u32 shift;\n static u64 r;\n static constexpr uint32_t HASHMAP_DEFAULT_SIZE = 4;\n\n explicit HashMapBase() : cap(HASHMAP_DEFAULT_SIZE), s(0), occupied(0), data(cap), occupied_flag(cap), deleted_flag(cap), shift(64 - __lg(cap)) {}\n\n itr begin() const {\n u32 h = 0;\n while (h != cap) {\n if (occupied_flag[h] && !deleted_flag[h]) break;\n h++;\n }\n return itr(h, this);\n }\n itr end() const { return itr(this->cap, this); }\n\n friend itr begin(const HashMapBase& h) { return h.begin(); }\n friend itr end(const HashMapBase& h) { return h.end(); }\n\n itr find(const Key& key) const {\n u32 h = inner_hash(key);\n while (true) {\n if (occupied_flag[h] == false) return this->end();\n if (data_to_key(data[h]) == key) {\n if (deleted_flag[h] == true) return this->end();\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n bool contain(const Key& key) const { return find(key) != this->end(); }\n\n itr insert(const Data& d) {\n u32 h = hash(d);\n while (true) {\n if (occupied_flag[h] == false) {\n if (extend_rate(occupied + 1)) {\n extend();\n h = hash(d);\n continue;\n }\n data[h] = d;\n occupied_flag[h] = true;\n ++occupied, ++s;\n return itr(h, this);\n }\n if (data_to_key(data[h]) == data_to_key(d)) {\n if (deleted_flag[h] == true) {\n data[h] = d;\n deleted_flag[h] = false;\n ++s;\n }\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n // tips for speed up :\n // if return value is unnecessary, make argument_2 false.\n itr erase(itr it, bool get_next = true) {\n if (it == this->end()) return this->end();\n s--;\n if (!get_next) {\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) shrink();\n return this->end();\n }\n itr nxt = it;\n nxt++;\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) {\n Data d = data[nxt.i];\n shrink();\n it = find(data_to_key(d));\n }\n return nxt;\n }\n\n itr erase(const Key& key) { return erase(find(key)); }\n\n int count(const Key& key) { return find(key) == end() ? 0 : 1; }\n\n bool empty() const { return s == 0; }\n\n int size() const { return s; }\n\n void clear() {\n fill(std::begin(occupied_flag), std::end(occupied_flag), false);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n s = occupied = 0;\n }\n\n void reserve(int n) {\n if (n <= 0) return;\n n = 1 << min(23, __lg(n) + 2);\n if (cap < u32(n)) reallocate(n);\n }\n};\n\ntemplate <typename Key, typename Data>\nuint64_t HashMapBase<Key, Data>::r = chrono::duration_cast<chrono::nanoseconds>(chrono::high_resolution_clock::now().time_since_epoch()).count();\n\n} // namespace HashMapImpl\n\ntemplate <typename Key, typename Val>\nstruct HashMap : HashMapImpl::HashMapBase<Key, pair<Key, Val>> {\n using base = typename HashMapImpl::HashMapBase<Key, pair<Key, Val>>;\n using HashMapImpl::HashMapBase<Key, pair<Key, Val>>::HashMapBase;\n using Data = pair<Key, Val>;\n\n Val& operator[](const Key& k) {\n typename base::u32 h = base::inner_hash(k);\n while (true) {\n if (base::occupied_flag[h] == false) {\n if (base::extend_rate(base::occupied + 1)) {\n base::extend();\n h = base::hash(k);\n continue;\n }\n base::data[h].first = k;\n base::data[h].second = Val();\n base::occupied_flag[h] = true;\n ++base::occupied, ++base::s;\n return base::data[h].second;\n }\n if (base::data[h].first == k) {\n if (base::deleted_flag[h] == true) {\n base::data[h].second = Val();\n base::deleted_flag[h] = false;\n ++base::s;\n }\n return base::data[h].second;\n }\n h = (h + 1) & (base::cap - 1);\n }\n }\n\n typename base::itr emplace(const Key& key, const Val& val) { return base::insert(Data(key, val)); }\n};\n\ntemplate <typename Key>\nstruct HashSet : HashMapImpl::HashMapBase<Key, Key> {\n using HashMapImpl::HashMapBase<Key, Key>::HashMapBase;\n};\n\nconstexpr int MAX = 100010;\n// int v[MAX], h[MAX], t[MAX], s[MAX];\n// ll d[MAX], accd[MAX], acch[MAX], accv[MAX];\n// HashMap<ll, int> dp[MAX];\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<int> v(N), h(N);\n for (int i = 0; i < N; i++) cin >> v[i] >> h[i];\n vector<int> t(M), s(M);\n for (int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n // s[i] は実質的に単調増加列とみなせる\n if (i - 1 >= 0) s[i] = max(s[i], s[i - 1]);\n }\n // d[i] := |h[i + 1] - h[i]|\n vector<ll> d(N - 1), accd(N), acch(N + 1), accv(N + 1);\n for (int i = 0; i + 1 < N; i++) d[i] = abs(h[i + 1] - h[i]);\n for (int i = 0; i + 1 < N; i++) accd[i + 1] = accd[i] + d[i];\n for (int i = 0; i < N; i++) {\n acch[i + 1] = acch[i] + h[i];\n accv[i + 1] = accv[i] + v[i];\n }\n\n // f(i, j) := [i, j) のアイテムを購入したときの強さの増分\n auto f = [&](int i, int j) -> ll { return acch[j] - acch[i] + max<ll>(0, accd[j - 1] - accd[i]); };\n\n // dp[i][j] := i 番目のイベント終了時,\n // 強さ j\n // のどこまでアイテムを買ったかの min\n vector<HashMap<ll, int>> dp(M + 1);\n dp[0][0] = 0;\n for (int i = 0; i < M; i++) {\n for (auto&& [key, val] : dp[i]) {\n // 強さ key, アイテムは [0, val) まで購入\n for (int j = val + 1; j <= N; j++) {\n // [val, j) までのアイテムを購入: 強さは key + f(val, j)\n ll next_strong = key + f(val, j);\n // t[i] が [0, j) の v の総和未満なら break\n if (t[i] < accv[j]) break;\n // 次の場所まで skip (次の場所に行けない場合は continue)\n int next_event = upper_bound(s.begin(), s.end(), next_strong) - s.begin();\n if (next_event <= i) continue;\n if (dp[next_event].contain(next_strong)) {\n dp[next_event][next_strong] = min(dp[next_event][next_strong], j);\n } else {\n dp[next_event][next_strong] = j;\n }\n }\n }\n }\n\n ll ans = -1;\n for (auto&& [key, val] : dp[M]) {\n // 強さ key, アイテムは [0, val) まで購入\n ans = max(ans, t[M - 1] - accv[val]);\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 5616, "score_of_the_acc": -0.4068, "final_rank": 13 }, { "submission_id": "aoj_0344_10858972", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n// ref: https://nyaannyaan.github.io/library/hashmap/hashmap.hpp.html\nnamespace HashMapImpl {\nusing u32 = uint32_t;\nusing u64 = uint64_t;\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase;\n\ntemplate <typename Key, typename Data>\nstruct itrB {\n // [UPDATE] C++17 で非推奨になった std::iterator template から変更\n using iterator_category = bidirectional_iterator_tag;\n using value_type = Data;\n using difference_type = ptrdiff_t;\n using pointer = value_type*;\n using reference = value_type&;\n\n u32 i;\n HashMapBase<Key, Data>* p;\n\n explicit constexpr itrB() : i(0), p(nullptr) {}\n explicit constexpr itrB(u32 _i, HashMapBase<Key, Data>* _p) : i(_i), p(_p) {}\n explicit constexpr itrB(u32 _i, const HashMapBase<Key, Data>* _p) : i(_i), p(const_cast<HashMapBase<Key, Data>*>(_p)) {}\n friend void swap(itrB& l, itrB& r) { swap(l.i, r.i), swap(l.p, r.p); }\n friend bool operator==(const itrB& l, const itrB& r) { return l.i == r.i; }\n friend bool operator!=(const itrB& l, const itrB& r) { return l.i != r.i; }\n const reference operator*() const { return const_cast<const HashMapBase<Key, Data>*>(p)->data[i]; }\n reference operator*() { return p->data[i]; }\n pointer operator->() const { return &(p->data[i]); }\n\n itrB& operator++() {\n assert(i != p->cap && \"itr::operator++()\");\n do {\n i++;\n if (i == p->cap) break;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n } while (true);\n return (*this);\n }\n itrB operator++(int) {\n itrB it(*this);\n ++(*this);\n return it;\n }\n itrB& operator--() {\n do {\n i--;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n assert(i != 0 && \"itr::operator--()\");\n } while (true);\n return (*this);\n }\n itrB operator--(int) {\n itrB it(*this);\n --(*this);\n return it;\n }\n};\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase {\n using u32 = uint32_t;\n using u64 = uint64_t;\n using iterator = itrB<Key, Data>;\n using itr = iterator;\n\n protected:\n template <typename K>\n inline u64 randomized(const K& key) const {\n return u64(key) ^ r;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<K>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n return (randomized(key) * 11995408973635179863ULL) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::first)>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::second)>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n u64 a = randomized(key.first), b = randomized(key.second);\n a *= 11995408973635179863ULL;\n b *= 10150724397891781847ULL;\n return (a + b) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& elem : key) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n // [ADD] 数値を要素とする 2 次元コンテナ用のハッシュ関数を追加\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<!is_integral<typename K::value_type>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& container : key) {\n for (auto& elem : container) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat);\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat.first);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat;\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat.first;\n }\n\n void reallocate(u32 ncap) {\n vector<Data> ndata(ncap);\n vector<bool> nf(ncap);\n shift = 64 - __lg(ncap);\n for (u32 i = 0; i < cap; i++) {\n if (occupied_flag[i] && !deleted_flag[i]) {\n u32 h = hash(data[i]);\n while (nf[h]) h = (h + 1) & (ncap - 1);\n ndata[h] = move(data[i]);\n nf[h] = true;\n }\n }\n data.swap(ndata);\n occupied_flag.swap(nf);\n cap = ncap;\n occupied = s;\n deleted_flag.resize(cap);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n }\n\n inline bool extend_rate(u32 x) const { return x * 2 >= cap; }\n\n inline bool shrink_rate(u32 x) const { return HASHMAP_DEFAULT_SIZE < cap && x * 10 <= cap; }\n\n inline void extend() { reallocate(cap << 1); }\n\n inline void shrink() { reallocate(cap >> 1); }\n\n public:\n u32 cap, s, occupied;\n vector<Data> data;\n vector<bool> occupied_flag, deleted_flag;\n u32 shift;\n static u64 r;\n static constexpr uint32_t HASHMAP_DEFAULT_SIZE = 4;\n\n explicit HashMapBase() : cap(HASHMAP_DEFAULT_SIZE), s(0), occupied(0), data(cap), occupied_flag(cap), deleted_flag(cap), shift(64 - __lg(cap)) {}\n\n itr begin() const {\n u32 h = 0;\n while (h != cap) {\n if (occupied_flag[h] && !deleted_flag[h]) break;\n h++;\n }\n return itr(h, this);\n }\n itr end() const { return itr(this->cap, this); }\n\n friend itr begin(const HashMapBase& h) { return h.begin(); }\n friend itr end(const HashMapBase& h) { return h.end(); }\n\n itr find(const Key& key) const {\n u32 h = inner_hash(key);\n while (true) {\n if (occupied_flag[h] == false) return this->end();\n if (data_to_key(data[h]) == key) {\n if (deleted_flag[h] == true) return this->end();\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n bool contain(const Key& key) const { return find(key) != this->end(); }\n\n itr insert(const Data& d) {\n u32 h = hash(d);\n while (true) {\n if (occupied_flag[h] == false) {\n if (extend_rate(occupied + 1)) {\n extend();\n h = hash(d);\n continue;\n }\n data[h] = d;\n occupied_flag[h] = true;\n ++occupied, ++s;\n return itr(h, this);\n }\n if (data_to_key(data[h]) == data_to_key(d)) {\n if (deleted_flag[h] == true) {\n data[h] = d;\n deleted_flag[h] = false;\n ++s;\n }\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n // tips for speed up :\n // if return value is unnecessary, make argument_2 false.\n itr erase(itr it, bool get_next = true) {\n if (it == this->end()) return this->end();\n s--;\n if (!get_next) {\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) shrink();\n return this->end();\n }\n itr nxt = it;\n nxt++;\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) {\n Data d = data[nxt.i];\n shrink();\n it = find(data_to_key(d));\n }\n return nxt;\n }\n\n itr erase(const Key& key) { return erase(find(key)); }\n\n int count(const Key& key) { return find(key) == end() ? 0 : 1; }\n\n bool empty() const { return s == 0; }\n\n int size() const { return s; }\n\n void clear() {\n fill(std::begin(occupied_flag), std::end(occupied_flag), false);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n s = occupied = 0;\n }\n\n void reserve(int n) {\n if (n <= 0) return;\n n = 1 << min(23, __lg(n) + 2);\n if (cap < u32(n)) reallocate(n);\n }\n};\n\ntemplate <typename Key, typename Data>\nuint64_t HashMapBase<Key, Data>::r = chrono::duration_cast<chrono::nanoseconds>(chrono::high_resolution_clock::now().time_since_epoch()).count();\n\n} // namespace HashMapImpl\n\ntemplate <typename Key, typename Val>\nstruct HashMap : HashMapImpl::HashMapBase<Key, pair<Key, Val>> {\n using base = typename HashMapImpl::HashMapBase<Key, pair<Key, Val>>;\n using HashMapImpl::HashMapBase<Key, pair<Key, Val>>::HashMapBase;\n using Data = pair<Key, Val>;\n\n Val& operator[](const Key& k) {\n typename base::u32 h = base::inner_hash(k);\n while (true) {\n if (base::occupied_flag[h] == false) {\n if (base::extend_rate(base::occupied + 1)) {\n base::extend();\n h = base::hash(k);\n continue;\n }\n base::data[h].first = k;\n base::data[h].second = Val();\n base::occupied_flag[h] = true;\n ++base::occupied, ++base::s;\n return base::data[h].second;\n }\n if (base::data[h].first == k) {\n if (base::deleted_flag[h] == true) {\n base::data[h].second = Val();\n base::deleted_flag[h] = false;\n ++base::s;\n }\n return base::data[h].second;\n }\n h = (h + 1) & (base::cap - 1);\n }\n }\n\n typename base::itr emplace(const Key& key, const Val& val) { return base::insert(Data(key, val)); }\n};\n\ntemplate <typename Key>\nstruct HashSet : HashMapImpl::HashMapBase<Key, Key> {\n using HashMapImpl::HashMapBase<Key, Key>::HashMapBase;\n};\n\nconstexpr int MAX = 100010;\nint v[MAX], h[MAX], t[MAX], s[MAX];\nll d[MAX], accd[MAX], acch[MAX], accv[MAX];\nHashMap<ll, int> dp[MAX];\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n // vector<int> v(N), h(N);\n for (int i = 0; i < N; i++) cin >> v[i] >> h[i];\n // vector<int> t(M), s(M);\n for (int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n // s[i] は実質的に単調増加列とみなせる\n if (i - 1 >= 0) s[i] = max(s[i], s[i - 1]);\n }\n // d[i] := |h[i + 1] - h[i]|\n // vector<ll> d(N - 1), accd(N), acch(N + 1), accv(N + 1);\n for (int i = 0; i + 1 < N; i++) d[i] = abs(h[i + 1] - h[i]);\n for (int i = 0; i + 1 < N; i++) accd[i + 1] = accd[i] + d[i];\n for (int i = 0; i < N; i++) {\n acch[i + 1] = acch[i] + h[i];\n accv[i + 1] = accv[i] + v[i];\n }\n\n // f(i, j) := [i, j) のアイテムを購入したときの強さの増分\n auto f = [&](int i, int j) -> ll { return acch[j] - acch[i] + max<ll>(0, accd[j - 1] - accd[i]); };\n\n // dp[i][j] := i 番目のイベント終了時,\n // 強さ j\n // のどこまでアイテムを買ったかの min\n // vector<HashMap<ll, int>> dp(M + 1);\n dp[0][0] = 0;\n for (int i = 0; i < M; i++) {\n for (auto&& [key, val] : dp[i]) {\n // 強さ key, アイテムは [0, val) まで購入\n for (int j = val + 1; j <= N; j++) {\n // [val, j) までのアイテムを購入: 強さは key + f(val, j)\n ll next_strong = key + f(val, j);\n // t[i] が [0, j) の v の総和未満なら break\n if (t[i] < accv[j]) break;\n // 次の場所まで skip (次の場所に行けない場合は continue)\n int next_event = upper_bound(s, s + M, next_strong) - s;\n if (next_event <= i) continue;\n if (dp[next_event].contain(next_strong)) {\n dp[next_event][next_strong] = min(dp[next_event][next_strong], j);\n } else {\n dp[next_event][next_strong] = j;\n }\n }\n }\n }\n\n ll ans = -1;\n for (auto&& [key, val] : dp[M]) {\n // 強さ key, アイテムは [0, val) まで購入\n ans = max(ans, t[M - 1] - accv[val]);\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 35660, "score_of_the_acc": -0.5537, "final_rank": 15 }, { "submission_id": "aoj_0344_10858887", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\n// ref: https://nyaannyaan.github.io/library/hashmap/hashmap.hpp.html\nnamespace HashMapImpl {\nusing u32 = uint32_t;\nusing u64 = uint64_t;\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase;\n\ntemplate <typename Key, typename Data>\nstruct itrB {\n // [UPDATE] C++17 で非推奨になった std::iterator template から変更\n using iterator_category = bidirectional_iterator_tag;\n using value_type = Data;\n using difference_type = ptrdiff_t;\n using pointer = value_type*;\n using reference = value_type&;\n\n u32 i;\n HashMapBase<Key, Data>* p;\n\n explicit constexpr itrB() : i(0), p(nullptr) {}\n explicit constexpr itrB(u32 _i, HashMapBase<Key, Data>* _p) : i(_i), p(_p) {}\n explicit constexpr itrB(u32 _i, const HashMapBase<Key, Data>* _p) : i(_i), p(const_cast<HashMapBase<Key, Data>*>(_p)) {}\n friend void swap(itrB& l, itrB& r) { swap(l.i, r.i), swap(l.p, r.p); }\n friend bool operator==(const itrB& l, const itrB& r) { return l.i == r.i; }\n friend bool operator!=(const itrB& l, const itrB& r) { return l.i != r.i; }\n const reference operator*() const { return const_cast<const HashMapBase<Key, Data>*>(p)->data[i]; }\n reference operator*() { return p->data[i]; }\n pointer operator->() const { return &(p->data[i]); }\n\n itrB& operator++() {\n assert(i != p->cap && \"itr::operator++()\");\n do {\n i++;\n if (i == p->cap) break;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n } while (true);\n return (*this);\n }\n itrB operator++(int) {\n itrB it(*this);\n ++(*this);\n return it;\n }\n itrB& operator--() {\n do {\n i--;\n if (p->occupied_flag[i] && !p->deleted_flag[i]) break;\n assert(i != 0 && \"itr::operator--()\");\n } while (true);\n return (*this);\n }\n itrB operator--(int) {\n itrB it(*this);\n --(*this);\n return it;\n }\n};\n\ntemplate <typename Key, typename Data>\nstruct HashMapBase {\n using u32 = uint32_t;\n using u64 = uint64_t;\n using iterator = itrB<Key, Data>;\n using itr = iterator;\n\n protected:\n template <typename K>\n inline u64 randomized(const K& key) const {\n return u64(key) ^ r;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<K>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n return (randomized(key) * 11995408973635179863ULL) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::first)>::value, nullptr_t> = nullptr, enable_if_t<is_integral<decltype(K::second)>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n u64 a = randomized(key.first), b = randomized(key.second);\n a *= 11995408973635179863ULL;\n b *= 10150724397891781847ULL;\n return (a + b) >> shift;\n }\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& elem : key) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n // [ADD] 数値を要素とする 2 次元コンテナ用のハッシュ関数を追加\n template <typename K, enable_if_t<is_same<K, Key>::value, nullptr_t> = nullptr, enable_if_t<!is_integral<typename K::value_type>::value, nullptr_t> = nullptr, enable_if_t<is_integral<typename K::value_type::value_type>::value, nullptr_t> = nullptr>\n inline u32 inner_hash(const K& key) const {\n static constexpr u64 mod = (1LL << 61) - 1;\n static constexpr u64 base = 950699498548472943ULL;\n u64 res = 0;\n for (auto& container : key) {\n for (auto& elem : container) {\n __uint128_t x = __uint128_t(res) * base + (randomized(elem) & mod);\n res = (x & mod) + (x >> 61);\n }\n }\n __uint128_t x = __uint128_t(res) * base;\n res = (x & mod) + (x >> 61);\n if (res >= mod) res -= mod;\n return res >> (shift - 3);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat);\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline u32 hash(const D& dat) const {\n return inner_hash(dat.first);\n }\n\n template <typename D = Data, enable_if_t<is_same<D, Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat;\n }\n template <typename D = Data, enable_if_t<is_same<decltype(D::first), Key>::value, nullptr_t> = nullptr>\n inline Key data_to_key(const D& dat) const {\n return dat.first;\n }\n\n void reallocate(u32 ncap) {\n vector<Data> ndata(ncap);\n vector<bool> nf(ncap);\n shift = 64 - __lg(ncap);\n for (u32 i = 0; i < cap; i++) {\n if (occupied_flag[i] && !deleted_flag[i]) {\n u32 h = hash(data[i]);\n while (nf[h]) h = (h + 1) & (ncap - 1);\n ndata[h] = move(data[i]);\n nf[h] = true;\n }\n }\n data.swap(ndata);\n occupied_flag.swap(nf);\n cap = ncap;\n occupied = s;\n deleted_flag.resize(cap);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n }\n\n inline bool extend_rate(u32 x) const { return x * 2 >= cap; }\n\n inline bool shrink_rate(u32 x) const { return HASHMAP_DEFAULT_SIZE < cap && x * 10 <= cap; }\n\n inline void extend() { reallocate(cap << 1); }\n\n inline void shrink() { reallocate(cap >> 1); }\n\n public:\n u32 cap, s, occupied;\n vector<Data> data;\n vector<bool> occupied_flag, deleted_flag;\n u32 shift;\n static u64 r;\n static constexpr uint32_t HASHMAP_DEFAULT_SIZE = 4;\n\n explicit HashMapBase() : cap(HASHMAP_DEFAULT_SIZE), s(0), occupied(0), data(cap), occupied_flag(cap), deleted_flag(cap), shift(64 - __lg(cap)) {}\n\n itr begin() const {\n u32 h = 0;\n while (h != cap) {\n if (occupied_flag[h] && !deleted_flag[h]) break;\n h++;\n }\n return itr(h, this);\n }\n itr end() const { return itr(this->cap, this); }\n\n friend itr begin(const HashMapBase& h) { return h.begin(); }\n friend itr end(const HashMapBase& h) { return h.end(); }\n\n itr find(const Key& key) const {\n u32 h = inner_hash(key);\n while (true) {\n if (occupied_flag[h] == false) return this->end();\n if (data_to_key(data[h]) == key) {\n if (deleted_flag[h] == true) return this->end();\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n bool contain(const Key& key) const { return find(key) != this->end(); }\n\n itr insert(const Data& d) {\n u32 h = hash(d);\n while (true) {\n if (occupied_flag[h] == false) {\n if (extend_rate(occupied + 1)) {\n extend();\n h = hash(d);\n continue;\n }\n data[h] = d;\n occupied_flag[h] = true;\n ++occupied, ++s;\n return itr(h, this);\n }\n if (data_to_key(data[h]) == data_to_key(d)) {\n if (deleted_flag[h] == true) {\n data[h] = d;\n deleted_flag[h] = false;\n ++s;\n }\n return itr(h, this);\n }\n h = (h + 1) & (cap - 1);\n }\n }\n\n // tips for speed up :\n // if return value is unnecessary, make argument_2 false.\n itr erase(itr it, bool get_next = true) {\n if (it == this->end()) return this->end();\n s--;\n if (!get_next) {\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) shrink();\n return this->end();\n }\n itr nxt = it;\n nxt++;\n this->deleted_flag[it.i] = true;\n if (shrink_rate(s)) {\n Data d = data[nxt.i];\n shrink();\n it = find(data_to_key(d));\n }\n return nxt;\n }\n\n itr erase(const Key& key) { return erase(find(key)); }\n\n int count(const Key& key) { return find(key) == end() ? 0 : 1; }\n\n bool empty() const { return s == 0; }\n\n int size() const { return s; }\n\n void clear() {\n fill(std::begin(occupied_flag), std::end(occupied_flag), false);\n fill(std::begin(deleted_flag), std::end(deleted_flag), false);\n s = occupied = 0;\n }\n\n void reserve(int n) {\n if (n <= 0) return;\n n = 1 << min(23, __lg(n) + 2);\n if (cap < u32(n)) reallocate(n);\n }\n};\n\ntemplate <typename Key, typename Data>\nuint64_t HashMapBase<Key, Data>::r = chrono::duration_cast<chrono::nanoseconds>(chrono::high_resolution_clock::now().time_since_epoch()).count();\n\n} // namespace HashMapImpl\n\ntemplate <typename Key, typename Val>\nstruct HashMap : HashMapImpl::HashMapBase<Key, pair<Key, Val>> {\n using base = typename HashMapImpl::HashMapBase<Key, pair<Key, Val>>;\n using HashMapImpl::HashMapBase<Key, pair<Key, Val>>::HashMapBase;\n using Data = pair<Key, Val>;\n\n Val& operator[](const Key& k) {\n typename base::u32 h = base::inner_hash(k);\n while (true) {\n if (base::occupied_flag[h] == false) {\n if (base::extend_rate(base::occupied + 1)) {\n base::extend();\n h = base::hash(k);\n continue;\n }\n base::data[h].first = k;\n base::data[h].second = Val();\n base::occupied_flag[h] = true;\n ++base::occupied, ++base::s;\n return base::data[h].second;\n }\n if (base::data[h].first == k) {\n if (base::deleted_flag[h] == true) {\n base::data[h].second = Val();\n base::deleted_flag[h] = false;\n ++base::s;\n }\n return base::data[h].second;\n }\n h = (h + 1) & (base::cap - 1);\n }\n }\n\n typename base::itr emplace(const Key& key, const Val& val) { return base::insert(Data(key, val)); }\n};\n\ntemplate <typename Key>\nstruct HashSet : HashMapImpl::HashMapBase<Key, Key> {\n using HashMapImpl::HashMapBase<Key, Key>::HashMapBase;\n};\n\nconstexpr int MAX = 100010;\nint v[MAX], h[MAX];\nll d[MAX], accd[MAX], acch[MAX], accv[MAX];\nHashMap<ll, int> dp[MAX];\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n // vector<int> v(N), h(N);\n for (int i = 0; i < N; i++) cin >> v[i] >> h[i];\n vector<int> t(M), s(M);\n for (int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n // s[i] は実質的に単調増加列とみなせる\n if (i - 1 >= 0) s[i] = max(s[i], s[i - 1]);\n }\n // d[i] := |h[i + 1] - h[i]|\n // vector<ll> d(N - 1), accd(N), acch(N + 1), accv(N + 1);\n for (int i = 0; i + 1 < N; i++) d[i] = abs(h[i + 1] - h[i]);\n for (int i = 0; i + 1 < N; i++) accd[i + 1] = accd[i] + d[i];\n for (int i = 0; i < N; i++) {\n acch[i + 1] = acch[i] + h[i];\n accv[i + 1] = accv[i] + v[i];\n }\n\n // f(i, j) := [i, j) のアイテムを購入したときの強さの増分\n auto f = [&](int i, int j) -> ll { return acch[j] - acch[i] + max<ll>(0, accd[j - 1] - accd[i]); };\n\n // dp[i][j] := i 番目のイベント終了時,\n // 強さ j\n // のどこまでアイテムを買ったかの min\n // vector<HashMap<ll, int>> dp(M + 1);\n dp[0][0] = 0;\n for (int i = 0; i < M; i++) {\n for (auto&& [key, val] : dp[i]) {\n // 強さ key, アイテムは [0, val) まで購入\n for (int j = val + 1; j <= N; j++) {\n // [val, j) までのアイテムを購入: 強さは key + f(val, j)\n ll next_strong = key + f(val, j);\n // t[i] が [0, j) の v の総和未満なら break\n if (t[i] < accv[j]) break;\n // 次の場所まで skip (次の場所に行けない場合は continue)\n int next_event = ranges::upper_bound(s, next_strong) - s.begin();\n if (next_event <= i) continue;\n if (dp[next_event].contain(next_strong)) {\n dp[next_event][next_strong] = min(dp[next_event][next_strong], j);\n } else {\n dp[next_event][next_strong] = j;\n }\n }\n }\n }\n\n ll ans = -1;\n for (auto&& [key, val] : dp[M]) {\n // 強さ key, アイテムは [0, val) まで購入\n ans = max(ans, t[M - 1] - accv[val]);\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 35656, "score_of_the_acc": -0.6251, "final_rank": 17 }, { "submission_id": "aoj_0344_10853884", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n#define debug(x) cerr << #x << \": \" << x << endl\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- 2018/01/15 Problem: AOJ 0344 / Link: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0344 ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\nOはDPのO\n\n----解説ここまで---- */\n\nLL N;\n\nLL ans = 0LL;\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint M;\n\n\tcin >> N>>M;\n\tVL v(N),h(N);\n\tFOR(i,0,N){\n\t\tcin>>v[i]>>h[i];\n\t}\n\tVL usesum(N+1,0);\n\tVL powersum(N+1,0);\n\tFOR(i,0,N){\n\t\tusesum[i+1] += usesum[i] + v[i];\n\t\tpowersum[i+1] += powersum[i] + h[i];\n\t}\n\tVL powerdiff(N+1,0);\n\tFOR(i,0,N-1){\n\t\tpowerdiff[i] = abs(v[i] - v[i+1]);\n\t}\n\tVL powerdiffsum(N+1,0);\n\tFOR(i,0,N-1){\n\t\tpowerdiffsum[i+1] +=powerdiffsum[i]+ powerdiff[i];\n\t}\n\n\n\tVL t(M),s(M);\n\tFOR(i,0,M){\n\t\tcin>>t[i]>>s[i];\n\t}\n\tvector<VVL> dp(M+1,VVL(N+1,VL(2,-1)));\n\tdp[0][0][0] = 0;\n\t// 0 simple 1 ketu\n\tFOR(i,0,M){\n\t\tLL nowmoney = t[i];\n\t\tFOR(j,0,N+1){\n\t\t\tif(dp[i][j][0]>=s[i]){\n\t\t\t\tdp[i+1][j][0] = max( dp[i+1][j][0], dp[i][j][0] );\n\t\t\t}\n\t\t\tif(dp[i][j][1]>=s[i]){\n\t\t\t\tdp[i+1][j][0] = max( dp[i+1][j][0], dp[i][j][1]);\n\t\t\t}\n\t\t\tif(j==N)continue;\n\t\t\t//debug(nowmoney - usesum[j+1]);\n\t\t\tif(nowmoney - usesum[j+1]>=0){\n\t\t\t\tif(dp[i][j][0]>=0){\n\t\t\t\t\tLL addpower = h[j];\n\t\t\t\t\tdp[i][j+1][0] = max(dp[i][j+1][0], dp[i][j][0] + addpower);\n\t\t\t\t\tdp[i][j+1][1] = max(dp[i][j+1][1], dp[i][j][0] + addpower);\n\t\t\t\t}\n\t\t\t\tif(dp[i][j][1]>=0){\n\t\t\t\t\tLL addpower = h[j] + abs(h[j] - h[j-1]);\n\t\t\t\t\tdp[i][j+1][1] = max(dp[i][j+1][1],dp[i][j][1] + addpower );\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n \n\tans = -1;\n\tFOR(j,0,N+1){\n\t\tif(dp[M][j][0]!=-1){\n\t\t\t//debug(t[M-1]-usesum[j]);\n\t\t\tans = max(ans,t[M-1] - usesum[j]);\n\t\t\t//debug(ans);\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\n\n\t// VVL dp(M+1,VL(N+1),-1);\n\t// dp[0][0] = 0;\n\t// FOR(i,0,M){\n\t// \tFOR(j,0,N){\n\t// \t\tLL money = t[i] - usesum[j]; // time - sum[item]\n\t// \t\tLL power = dp[i][j];\n\t// \t\tFOR(k,j+1,N){ // [j+1,k]までを選択\n\t// \t\t\tLL cost = usesum[k+1] - usesum[j+1];\n\t// \t\t\tLL addpower =\tpowersum[k+1] - powersum[j+1] + powerdiffsum[k] -powerdiffsum[j+1]; \n\t// \t\t\tif(money -cost<0)break;// cut\n\t// \t\t\tif(power+addpower>=s[i]){\n\t// \t\t\t\tdp[i+1][k] = max(dp[i+1][k],dp[i][j]+addpower);\n\t// \t\t\t}\n\n\t// \t\t}\n\t// \t}\n\t// }\n\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 167812, "score_of_the_acc": -1.1667, "final_rank": 19 }, { "submission_id": "aoj_0344_10827640", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nusing ll = long long;\nint main() {\n int N, M;cin >> N >> M;\n vector<ll> T(M+1, 0), S(M+1, 0), V(N+1, 0), H(N+1, 0);\n \n for (int i = 1;i <= N;i++) {\n cin >> V[i] >> H[i];\n }\n for (int i = 1;i <= M;i++) {\n cin >> T[i] >> S[i];\n }\n vector<ll> Z(N+1, 0);\n for (int i = N;i >= 1;i--) {\n Z[i] = H[i];\n if (i < N) {\n Z[i] += Z[i+1];\n Z[i] += abs(H[i]-H[i+1]);\n }\n }\n ll inf = (1LL << 60);\n vector<vector<ll>> dp(M+1, vector<ll>(N+1, -inf));\n dp[0][0] = 0;\n vector<ll> SV(N+1, 0);\n for (int i = 1;i <= N;i++) SV[i]=SV[i-1]+V[i];\n vector<ll> MX(N+1, -inf);\n vector<vector<ll>> SC(N+1, vector<ll>(N+1, 0));\n \n for (int i = 1;i <= M;i++) {\n for (int j = 1;j <= N;j++) {\n //not buy at ti\n if (dp[i-1][j] >= S[i]) {\n dp[i][j]=dp[i-1][j];\n }\n //buy at i\n if (SV[j] <= T[i]) {\n if (MX[j] != -inf) {\n ll nt = MX[j] - Z[j] + H[j];\n if (nt >= S[i]) {\n\n dp[i][j] = max(dp[i][j], nt);\n }\n }\n if (i == 1) {\n for (int k = 1;k <= j;k++) {\n if (dp[i-1][k-1] < 0) continue;\n ll sc = 0;\n for (int t = k;t <= j;t++) {\n sc += H[t];\n if (t < j) sc += abs(H[t]-H[t+1]);\n }\n if (dp[i-1][k-1]+sc >= S[i]) dp[i][j]=max(dp[i][j], dp[i-1][k-1] + sc);\n // cout << MX[j] - Z[j] + H[j] << \" \" << dp[i-1][k-1] + SC[k][j] << \" \" << i << \" \" << j << \" \" << k << endl;\n // cout << k << \" \" << j << \" \" << Z[k]-Z[j] + H[j] << \" \" << SC[k][j] << endl;\n }\n }\n }\n } \n for (int k = 1;k <= N;k++) {\n MX[k]=MX[k-1];\n if (dp[i][k-1] != -inf) MX[k] = max(MX[k-1], dp[i][k-1]+Z[k]); \n // cout << k << \" MX \" << i << \" \" << MX[k] << endl;\n }\n}\n ll res = -inf;\n for (int j = 0;j <= N;j++) {\n if (dp.back()[j] != -inf) {\n res = max(res, T.back() - SV[j]);\n }\n }\n cout << (res < 0 ? -1 : res) << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 97408, "score_of_the_acc": -0.5958, "final_rank": 16 }, { "submission_id": "aoj_0344_10203455", "code_snippet": "// AOJ #344\n// Game Strategy 202.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst ll NEG = -1000000000000000000LL;\n\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);\n \n int N, M;\n cin >> N >> M;\n vector<ll> v(N+1), h(N+1);\n for (int i = 1; i <= N; i++){\n cin >> v[i] >> h[i];\n }\n\n vector<ll> V(N+1,0), H(N+1,0);\n for (int i = 1; i <= N; i++){\n V[i] = V[i-1] + v[i];\n H[i] = H[i-1] + h[i];\n }\n\n vector<ll> D(N+1, 0);\n D[1] = 0;\n for (int i = 2; i <= N; i++){\n D[i] = D[i-1] + llabs(h[i] - h[i-1]);\n }\n \n vector<ll> T(M+1), Sreq(M+1);\n for (int i = 1; i <= M; i++){\n cin >> T[i] >> Sreq[i];\n }\n \n\n vector<ll> dp(N+1, NEG), next_dp(N+1, NEG);\n dp[0] = 0;\n \n for (int evt = 1; evt <= M; evt++){\n for (int j = 0; j <= N; j++) next_dp[j] = NEG;\n \n for (int j = 0; j <= N; j++){\n if(dp[j] != NEG && dp[j] >= Sreq[evt]){\n next_dp[j] = max(next_dp[j], dp[j]);\n }\n }\n\n vector<ll> best(N, NEG);\n best[0] = dp[0] - 0 - ( (1<=N ? D[1] : 0) );\n for (int j = 1; j < N; j++){\n ll candidate = dp[j] - H[j] - D[j+1];\n best[j] = max(best[j-1], candidate);\n }\n \n for (int k = 1; k <= N; k++){\n if(V[k] <= T[evt]){\n ll candidate = best[k-1] + (H[k] + D[k]);\n if(candidate >= Sreq[evt]){\n next_dp[k] = max(next_dp[k], candidate);\n }\n }\n }\n \n dp = next_dp;\n }\n \n ll ans = NEG;\n bool possible = false;\n for (int j = 0; j <= N; j++){\n if(dp[j] != NEG){\n ll money = T[M] - V[j];\n ans = max(ans, money);\n possible = true;\n }\n }\n if(!possible) cout << -1 << endl;\n else cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3600, "score_of_the_acc": -0.0017, "final_rank": 4 }, { "submission_id": "aoj_0344_9580724", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tlong long n,m;\n\tcin >> n >> m;\n\tvector<pair<long long,long long>> a(n),b(m);\n\tvector<long long> p(n,0ll);\n\tfor(long long i = 0ll;i < n;i++){\n\t\tcin >> a[i].first >> a[i].second;\n\t\tif(i != 0ll){\n\t\t\tp[i - 1ll] = abs(a[i].second - a[i - 1ll].second);\n\t\t}\n\t}\n\tfor(long long i = 0ll;i < n;i++){\n\t\ta[i].second += p[i];\n\t\tif(i != 0ll){\n\t\t\ta[i].second += a[i - 1ll].second;\n\t\t\ta[i].first += a[i - 1ll].first;\n\t\t}\n\t}\n\tfor(long long i = 0ll;i < m;i++){\n\t\tcin >> b[i].first >> b[i].second;\n\t}\n\tvector<vector<long long>> dp(m + 1ll,vector<long long>(n + 1ll,LLONG_MAX));\n\tdp[0ll][0ll] = 0ll;\n\tfor(long long i = 0ll;i < m;i++){\n\t\tlong long it = LLONG_MAX;\n\t\tfor(long long j = 1ll;j <= n;j++){\n\t\t\tit = min(it,dp[i][j - 1ll]);\n\t\t\tif(a[j - 1ll].second - dp[i][j] >= b[i].second){\n\t\t\t\tdp[i + 1ll][j] = min(dp[i][j],dp[i + 1ll][j]);\n\t\t\t}\n\t\t\tif(it != LLONG_MAX && a[j - 1ll].first <= b[i].first && a[j - 1ll].second - it - p[j - 1ll] >= b[i].second){\n\t\t\t\tdp[i + 1ll][j] = min(it + p[j - 1ll],dp[i + 1ll][j]);\n\t\t\t}\n\t\t}\n\t}\n\tlong long ans = -1ll;\n\tfor(long long i = 1ll;i <= n;i++){\n\t\tif(dp[m][i] == LLONG_MAX) continue;\n\t\tans = max(ans,b[m - 1ll].first - a[i - 1ll].first);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26616, "score_of_the_acc": -0.1416, "final_rank": 7 }, { "submission_id": "aoj_0344_9033769", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, M;\n cin >> N >> M;\n vector<int> v(N), h(N);\n for(int i = 0; i < N; i++) {\n cin >> v[i] >> h[i];\n }\n vector<int> t(M), s(M);\n for(int i = 0; i < M; i++) {\n cin >> t[i] >> s[i];\n }\n if(v[0] > t[0]) {\n cout << -1 << endl;\n return 0;\n }\n const int INF = 800000000;\n vector<int> dp(N, -INF), ep(N, -INF);\n { // init\n dp[0] = h[0];\n int sv = v[0];\n for(int i = 1; i < N; i++) {\n sv += v[i];\n if(sv > t[0]) break;\n dp[i] = dp[i-1]+h[i]+abs(h[i-1]-h[i]);\n }\n for(int i = 0; i < N; i++) {\n if(dp[i] < s[0]) dp[i] = -INF;\n }\n }\n for(int j = 1; j < M; j++) {\n int fi = -1;\n for(int i = 0; i < N; i++) {\n if(dp[i] != -INF) {\n fi = i;\n break;\n }\n }\n if(fi == -1) {\n cout << -1 << endl;\n return 0;\n }\n int sv = 0, mep = -INF;\n for(int i = 0; i < N; i++) {\n sv += v[i];\n if(i < fi) continue;\n if(sv > t[j]) break;\n ep[i] = dp[i];\n if(i > 0) ep[i] = max({dp[i], dp[i-1]+h[i], mep+h[i]+abs(h[i]-h[i-1])});\n if(i > fi) mep = max(mep+h[i]+abs(h[i-1]-h[i]), dp[i-1]+h[i]);\n }\n for(int i = 0; i < N; i++) {\n if(ep[i] < s[j]) ep[i] = -INF;\n }\n swap(dp, ep);\n fill(ep.begin(), ep.end(), -INF);\n }\n int sv = 0;\n for(int i = 0; i < N; i++) {\n sv += v[i];\n if(dp[i] != -INF) {\n cout << t[M-1]-sv << endl;\n return 0;\n }\n }\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3436, "score_of_the_acc": -0.0007, "final_rank": 2 }, { "submission_id": "aoj_0344_6968387", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0344.cc: Game Strategy\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 3000;\nconst int MAX_M = 1000;\nconst int INF = 1 << 30;\n\n/* typedef */\n\n/* global variables */\n\nint vs[MAX_N], hs[MAX_N], ts[MAX_M + 1], ss[MAX_M];\nint vss[MAX_N + 1], dp[MAX_M + 1][MAX_N + 1][2];\n\n/* subroutines */\n\nvoid setmax(int &a, int b) { if (a < b) a = b; }\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; i++) scanf(\"%d%d\", vs + i, hs + i);\n for (int i = 0; i < m; i++) scanf(\"%d%d\", ts + i, ss + i);\n ts[m] = INF;\n\n for (int i = 0; i < n; i++) vss[i + 1] = vss[i] + vs[i];\n\n for (int i = 0; i <= m; i++)\n for (int j = 0; j <= n; j++) dp[i][j][0] = dp[i][j][1] = -1;\n dp[0][0][0] = 0;\n\n for (int i = 0; i <= m; i++)\n for (int j = 0; j <= n; j++)\n for (int k = 0; k < 2; k++)\n\tif (dp[i][j][k] >= 0) {\n\t if (i < m && dp[i][j][k] >= ss[i])\n\t setmax(dp[i + 1][j][0], dp[i][j][k]);\n\t if (j < n && ts[i] >= vss[j + 1]) {\n\t int dd = hs[j] + (k == 1 ? abs(hs[j] - hs[j - 1]) : 0);\n\t setmax(dp[i][j + 1][1], dp[i][j][k] + dd);\n\t }\n\t}\n\n int minj = INF;\n for (int j = 0; j <= n; j++)\n if (dp[m][j][0] >= 0 || dp[m][j][1] >= 0) {\n minj = j; break;\n }\n\n printf(\"%d\\n\", (minj < INF) ? ts[m - 1] - vss[minj] : -1);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 26464, "score_of_the_acc": -0.1526, "final_rank": 8 }, { "submission_id": "aoj_0344_5774034", "code_snippet": "//#pragma GCC target (\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp((i),mkp((j),(k)))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) int((a).size())\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all((b)),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)((c)-'0')\n#define itoc(c) (char)((c)+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",quetimes_+1)\n#define readv(a,n) (a).resize((n),0);rep(i,(n)) (a)[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = (ll)15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll ppc(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nvoid fin(T x) { cout << x << endl; exit(0); }\n\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n csum(int sz) { init(sz); }\n void init(int sz) { v = vector<T>(sz + 1, 0); }\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n void add(int l, int r, T x) {\n v[l] += x;\n v[r] -= x;\n }//[l,r)\n void add(int t, T x) {\n v[t] += x;\n }//[l,r)\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n T operator[](int x)const {\n return v[x];\n }\n};\nclass via {\n using H = pair<ll, ll>;\n bool comp;\npublic:\n vector<H>a;\n via() :comp(true) {}\n via(vector<H>dat) :a(dat), comp(false) { build(); }\n void push(int l, int r) { a.push_back(H{ l,r }); comp = false; }\n void push(H a) { push(a.first, a.second); }\n void build() {\n if (comp) return;\n comp = true;\n sort(a.begin(), a.end());\n int fst = -1; ll lst = -1;\n vector<H>b;\n for (int i = 0; i < a.size(); i++) {\n if (fst < 0) fst = i, lst = a[i].second;\n if (lst < a[i].first) {\n b.push_back(H{ a[fst].first,lst });\n fst = i, lst = a[i].second;\n }\n else if (lst < a[i].second) lst = a[i].second;\n }\n if (~fst) b.push_back(H{ a[fst].first, lst });\n a = b;\n }\n ll size() { return ll(a.size()); }\n ll sum() {\n build();\n ll sum = 0;\n for (auto g : a) sum += g.second - g.first;\n return sum;\n }\n via inter(via& v) {\n build(); v.build();\n via ret;\n for (auto g : a) ret.push(g);\n for (auto g : v.a) ret.push(g);\n ret.build(); return ret;\n }\n via comb(via& v) {\n build(); v.build();\n int s = 0, t = 0;\n via ret;\n while (s < a.size() && t < v.size()) {\n if (v[t].second <= a[s].first) t++;\n else if (a[s].second <= v[t].first) s++;\n else {\n ret.push(max(a[s].first, v[t].first), min(a[s].second, v[t].second));\n if (a[s].second <= v[t].second) s++;\n else t++;\n }\n }\n return ret;\n }\n H& operator[](int t) { return a[t]; }\n};\ntemplate<ll mod>\nclass modint {\npublic:ll v;\n modint(ll v = 0) { s(v % mod + mod); }\n constexpr static int fn_ = (ll)2e6 + 5;\n static vector<modint>fact, comp;\n modint pow(ll x) const {\n modint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline modint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline modint inv()const { return pow(mod - 2); }\n inline modint operator-()const { return modint() - *this; }\n inline modint& operator+=(const modint b) { return s(v + b.v); }\n inline modint& operator-=(const modint b) { return s(v + mod - b.v); }\n inline modint& operator*=(const modint b) { v = v * b.v % mod; return *this; }\n inline modint& operator/=(const modint b) { v = v * b.inv().v % mod; return *this; }\n inline modint operator+(const modint& b) const { return modint(v) += b; }\n inline modint operator-(const modint& b) const { return modint(v) -= b; }\n inline modint operator*(const modint& b) const { return modint(v) *= b; }\n inline modint operator/(const modint& b) const { return modint(v) /= b; }\n friend ostream& operator<<(ostream& os, const modint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, modint& m) {\n int x; is >> x; m = modint(x);\n return is;\n }\n bool operator<(const modint& r)const { return v < r.v; }\n bool operator>(const modint& r)const { return v > r.v; }\n bool operator<=(const modint& r)const { return v <= r.v; }\n bool operator>=(const modint& r)const { return v >= r.v; }\n bool operator==(const modint& r)const { return v == r.v; }\n bool operator!=(const modint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n modint comb(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n if (k > *this - k) k = *this - k;\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n modint perm(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact.assign(fn_, modint());\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * modint(i);\n comp.assign(fn_, modint());\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * modint(i + 1);\n }\n};\nusing mint = modint<ll(1e9 + 7)>; template<>vec<mint> mint::fact = vec<mint>(); template<>vec<mint> mint::comp = vec<mint>();\n//--------------------------------------------------------------\n//--------------------------------------------------------------\ntemplate<class T>\nclass LazySegmentTree {\nprotected:\n using UPF = function<void(T&, const int&)>;\n using QRF = function<void(T&, const T)>;\n using F = function<bool(T a)>;\n using ll = long long;\n int n, rr;\n vector<T>dat;\n vector<int>len;\n\n LazySegmentTree() {}\n LazySegmentTree(int size) { init(size); }\n LazySegmentTree(vector<T>& v) {\n init(v);\n }\n virtual ~LazySegmentTree() {}\n\n virtual void eval(const T& par, T& a, const int& al) = 0;\n virtual void fold(T& par, const int& pl) = 0;\n virtual T proc(const T& a, const int& al, const T& b, const int& bl) = 0;\n\npublic:\n void init(int size) {\n n = size, rr = 1;\n while (rr < n) rr <<= 1;\n dat.assign(2 * rr - 1, T());\n len.assign(2 * rr - 1, 0);\n for (int i = 0; i < n; i++) {\n len[i + rr - 1] = 1;\n dat[i + rr - 1] = T();\n }\n for (int i = rr - 2; i >= 0; i--) {\n len[i] = len[i * 2 + 1] + len[i * 2 + 2];\n dat[i] = proc(dat[i * 2 + 1], len[i * 2 + 1], dat[i * 2 + 2], len[i * 2 + 2]);\n }\n }\n void init(vector<T>& v) {\n n = (int)v.size(), rr = 1;\n while (rr < n) rr <<= 1;\n dat.assign(2 * rr - 1, T());\n len.assign(2 * rr - 1, 0);\n for (int i = 0; i < n; i++) {\n dat[i + rr - 1] = v[i];\n len[i + rr - 1] = 1;\n }\n for (int i = rr - 2; i >= 0; i--) {\n len[i] = len[i * 2 + 1] + len[i * 2 + 2];\n dat[i] = proc(dat[i * 2 + 1], len[i * 2 + 1], dat[i * 2 + 2], len[i * 2 + 2]);\n }\n }\n void upd(int a, int b, UPF func) {\n upd(0, a, b, 0, rr, func);\n }\n T qry(int a, int b) {\n return qry(0, a, b, 0, rr);\n }\n T get0() {\n return dat[0];\n }\n //func([a,i))==true, func([a,i+1))==false\n int lb(int a, int b, F func) {\n T e = T();\n int lgt = 0;\n return lb(0, a, b, 0, rr, func, e, lgt);\n }\n //func([i,b))==true, func([i-1,b))==false\n int ub(int a, int b, F func) {\n T e = T();\n int lgt = 0;\n return ub(0, a, b, 0, rr, func, e, lgt);\n }\nprivate:\n void upd(int i, const int& a, const int& b, int l, int r, UPF& func) {\n if (b <= l || r <= a) return;\n if (a <= l && r <= b) {\n func(dat[i], len[i]);\n return;\n }\n eval(dat[i], dat[i * 2 + 1], len[i * 2 + 1]);\n eval(dat[i], dat[i * 2 + 2], len[i * 2 + 2]);\n fold(dat[i], len[i]);\n\n upd(i * 2 + 1, a, b, l, (l + r) / 2, func);\n upd(i * 2 + 2, a, b, (l + r) / 2, r, func);\n\n dat[i] = proc(dat[i * 2 + 1], len[i * 2 + 1], dat[i * 2 + 2], len[i * 2 + 2]);\n }\n T qry(int i, const int& a, const int& b, int l, int r) {\n if (b <= l || r <= a) return T();\n if (a <= l && r <= b) return dat[i];\n\n eval(dat[i], dat[i * 2 + 1], len[i * 2 + 1]);\n eval(dat[i], dat[i * 2 + 2], len[i * 2 + 2]);\n fold(dat[i], len[i]);\n\n return proc(qry(i * 2 + 1, a, b, l, (l + r) / 2), len[i * 2 + 1],\n qry(i * 2 + 2, a, b, (l + r) / 2, r), len[i * 2 + 2]);\n }\n int lb(int i, int a, int b, int l, int r, F& func, T& wa, int& lgt) {\n if (b <= l || r <= a) return b;\n if (a <= l && r <= b) {\n if (func(proc(wa, lgt, dat[i], len[i]))) {\n wa = proc(wa, lgt, dat[i], len[i]);\n lgt += len[i];\n return b;\n }\n if (r - l == 1) return l;\n }\n eval(dat[i], dat[i * 2 + 1], len[i * 2 + 1]);\n eval(dat[i], dat[i * 2 + 2], len[i * 2 + 2]);\n fold(dat[i], len[i]);\n\n int tmp = lb(i * 2 + 1, a, b, l, (l + r) / 2, func, wa, lgt);\n if (tmp < b) return tmp;\n return lb(i * 2 + 2, a, b, (l + r) / 2, r, func, wa, lgt);\n }\n int ub(int i, int a, int b, int l, int r, F& func, T& wa, int& lgt) {\n if (b <= l || r <= a) return a;\n if (a <= l && r <= b) {\n if (func(proc(dat[i], len[i], wa, lgt))) {\n wa = proc(dat[i], len[i], wa, lgt);\n lgt += len[i];\n return a;\n }\n if (r - l == 1) return r;\n }\n eval(dat[i], dat[i * 2 + 1], len[i * 2 + 1]);\n eval(dat[i], dat[i * 2 + 2], len[i * 2 + 2]);\n fold(dat[i], len[i]);\n\n int tmp = ub(i * 2 + 2, a, b, (l + r) / 2, r, func, wa, lgt);\n if (tmp > a) return tmp;\n return ub(i * 2 + 1, a, b, l, (l + r) / 2, func, wa, lgt);\n }\n};\ntemplate<class T>\nclass Segtree :public LazySegmentTree<T> {\n using Base = LazySegmentTree<T>;\npublic:\n Segtree() {}\n Segtree(int size) {\n init(size);\n }\n Segtree(vector<ll>& v) {\n init(v);\n }\n Segtree(vector<T>& v) { init(v); }\n void init(int size) {\n Base::init(size);\n }\n void init(vector<ll>& v) {\n vector<T>r(v.size());\n for (int i = 0; i < v.size(); i++) r[i] = T{ v[i],0 };\n Base::init(r);\n }\n void init(vector<T>& v) {\n Base::init(v);\n }\n\n void change(int p, ll x) {\n Base::upd(p, p + 1, [x](T& dat, const int& len) {\n dat.val = x; dat.lazy = 0;\n });\n }\n void update(int a, int b, ll x) {\n Base::upd(a, b, [x](T& dat, const int& len) {\n dat.val += x; dat.lazy = x;\n });\n }\n ll query(int a, int b) {\n return Base::qry(a, b).val;\n }\n ll get0() {\n return Base::get0().val;\n }\nprivate:\n void eval(const T& par, T& a, const int& al)override {\n if (par.lazy) {\n a.val += par.lazy;\n a.lazy += par.lazy;\n }\n }\n void fold(T& par, const int& pl) override {\n par.lazy = 0;\n }\n T proc(const T& a, const int& al, const T& b, const int& bl)override {\n return T{ max(a.val, b.val) ,0 };\n }\n};\nstruct Monoid {\n ll val; ll lazy;\n Monoid() :val(-inf), lazy(0) {}\n Monoid(ll val, ll lazy) :val(val), lazy(lazy) {}\n};\n\nll dp[4000][2000];\nsigned main() {\n int n, m; cin >> n >> m;\n vec<H>a(n+1), b(m + 1);\n for (int i = 0; i < n; i++) {\n a[i] = readh();\n }\n rep(i, m) b[i] = readh();\n Segtree<Monoid>seg(n + 1);\n seg.change(0, 0);\n\n\n vi dp(n + 1);\n rep(i, m) {\n ll sum = 0;\n dp = vi(n + 1);\n rng(j, 0, n) {\n sum += a[j].fs;\n if (sum > b[i].fs) break;\n\n seg.update(0, j + 1, a[j].sc);\n if (j > 0) seg.update(0, j, abs(a[j - 1].sc - a[j].sc));\n\n dp[j + 1] = seg.query(0, j + 2);\n }\n rep(j, n + 1) if (dp[j] < b[i].sc) dp[j] = -inf;\n seg.init(dp);\n }\n\n ll sum = b[m - 1].fs;\n rep(i, n + 1) {\n if (dp[i] > 0) {\n fin(sum);\n }\n if (i < n) sum -= a[i].fs;\n }\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 850, "memory_kb": 3840, "score_of_the_acc": -1.0031, "final_rank": 18 }, { "submission_id": "aoj_0344_4996156", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint N,M;\nint v[3000],h[3000];\nint sv[3030];\nint t[1000],s[1000];\nint dp[1010][3030];\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>v[i]>>h[i];\n\t\tsv[i+1]=sv[i]+v[i];\n\t}\n\tfor(int i=0;i<M;i++)cin>>t[i]>>s[i];\n\tfor(int i=0;i<=M;i++)for(int j=0;j<=N;j++)dp[i][j]=-1e9;\n\tdp[0][0]=0;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint mx1=-1e9,mx2=dp[i][0];\n\t\tfor(int j=1;j<=N;j++)if(sv[j]<=t[i])\n\t\t{\n\t\t\tif(j>1)mx1+=abs(h[j-1]-h[j-2]);\n\t\t\tmx1+=h[j-1];\n\t\t\tmx2+=h[j-1];\n\t\t\tmx1=max(mx1,mx2);\n\t\t\tmx2=max(mx2,dp[i][j]);\n\t\t\tdp[i][j]=max(mx1,mx2);\n\t\t}\n\t\tfor(int j=0;j<=N;j++)if(dp[i][j]>=s[i])dp[i+1][j]=dp[i][j];\n\t}\n\tint ans=-1;\n\tfor(int j=0;j<=N;j++)if(dp[M][j]>=0)ans=max(ans,t[M-1]-sv[j]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15004, "score_of_the_acc": -0.071, "final_rank": 5 }, { "submission_id": "aoj_0344_4824513", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nint solve(int N, int M, vector<int> V, vector<int> H, vector<int> T, vector<int> S) {\n\tV.insert(V.begin(), 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\tV[i + 1] += V[i];\n\t}\n\tfor (int i = 1; i < M; ++i) {\n\t\tS[i] = max(S[i], S[i - 1]);\n\t}\n\tvector<int> dp(N + 1, -inf); // maintain maximum strength\n\tdp[0] = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tint ptr = lower_bound(T.begin(), T.end(), V[i]) - T.begin() - 1;\n\t\tint delta = 0;\n\t\tfor (int j = i - 1; j >= 0; --j) {\n\t\t\tdelta += H[j];\n\t\t\tif (j != i - 1) {\n\t\t\t\tdelta += abs(H[j] - H[j + 1]);\n\t\t\t}\n\t\t\tif (ptr == -1 || S[ptr] <= dp[j]) {\n\t\t\t\tdp[i] = max(dp[i], dp[j] + delta);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -inf;\n\tfor (int i = 0; i <= N; ++i) {\n\t\tif (dp[i] >= S[M - 1]) {\n\t\t\tans = max(ans, T[M - 1] - V[i]);\n\t\t}\n\t}\n\treturn (ans != -inf ? ans : -1);\n}\nint solve_easy(int N, int M, vector<int> V, vector<int> H, vector<int> T, vector<int> S) {\n\tint ans = -inf;\n\tfor (int i = 0; i < 1 << N; ++i) {\n\t\tvector<pair<int, int> > d = { make_pair(0, 0) };\n\t\tint cont = 0, strength = 0, t = 0;\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\t++cont;\n\t\t\tstrength += H[j];\n\t\t\tif (cont >= 2) strength += abs(H[j] - H[j - 1]);\n\t\t\tt += V[j];\n\t\t\tif ((i >> j) & 1) {\n\t\t\t\td.push_back(make_pair(t, strength));\n\t\t\t\tcont = 0;\n\t\t\t}\n\t\t}\n\t\tbool ok = true;\n\t\tfor (int j = 0; j < M; ++j) {\n\t\t\tint ptr = lower_bound(d.begin(), d.end(), make_pair(T[j] + 1, -inf)) - d.begin() - 1;\n\t\t\tif (d[ptr].second < S[j]) {\n\t\t\t\tok = false;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif (ok) {\n\t\t\tans = max(ans, T.back() - d.back().first);\n\t\t}\n\t}\n\treturn (ans != -inf ? ans : -1);\n}\n#include <random>\n#include <string>\nmt19937 mt(2009092038);\nint rand_rng(int l, int r) {\n\tuniform_int_distribution<int> p(l, r - 1);\n\treturn p(mt);\n}\nstring to_string(vector<int> arr) {\n\tstring res = \"[\";\n\tfor (int i = 0; i < arr.size(); ++i) {\n\t\tif (i) res += \", \";\n\t\tres += to_string(arr[i]);\n\t}\n\tres += \"]\";\n\treturn res;\n}\nvoid random_gen() {\n\tconst int rep = 10000;\n\tint N = 7, M = 7;\n\tfor (int i = 1; i <= rep; ++i) {\n\t\tvector<int> V(N), H(N), T(M), S(M);\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tV[j] = rand_rng(1, 8);\n\t\t\tH[j] = rand_rng(1, 8);\n\t\t}\n\t\tfor (int j = 0; j < M; ++j) {\n\t\t\tT[j] = rand_rng(1, 40);\n\t\t\tS[j] = rand_rng(1, 40);\n\t\t}\n\t\tsort(T.begin(), T.end());\n\t\tfor (int j = 0; j < M; ++j) {\n\t\t\tT[j] += j;\n\t\t}\n\t\tint res1 = solve(N, M, V, H, T, S);\n\t\tint res2 = solve_easy(N, M, V, H, T, S);\n\t\tif (res1 != res2) {\n\t\t\tcout << \"Case #\" << i << \":\" << endl;\n\t\t\tcout << \"V = \" << to_string(V) << endl;\n\t\t\tcout << \"H = \" << to_string(H) << endl;\n\t\t\tcout << \"T = \" << to_string(T) << endl;\n\t\t\tcout << \"S = \" << to_string(S) << endl;\n\t\t\tcout << \"Returns: \" << res1 << endl;\n\t\t\tcout << \"Answer: \" << res2 << endl;\n\t\t\tcout << endl;\n\t\t}\n\t}\n\tcout << \"Finished!\" << endl;\n}\nint main() {\n\t// random_gen();\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, M;\n\tcin >> N >> M;\n\tvector<int> V(N), H(N), T(M), S(M);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> V[i] >> H[i];\n\t}\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin >> T[i] >> S[i];\n\t}\n\tint res = solve(N, M, V, H, T, S);\n\tcout << res << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3332, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0344_4817394", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\ntemplate<class Op> class SegmentTree {\n using T = typename Op::T;\n int len, n;\n vector<T> dat;\n T unit = Op::unit;\npublic:\n SegmentTree(const int _n) : n(_n) {\n for (len = 1; len < n; len <<= 1);\n dat.resize(len << 1, unit);\n }\n SegmentTree(const vector<T>& v) : n(v.size()) {\n for (len = 1; len < n; len <<= 1);\n dat.resize(len << 1, unit);\n for (int i = 0; i < n; ++i)dat[i + len] = v[i];\n for (int i = len - 1; 0 < i; --i)\n dat[i] = Op::merge(dat[i << 1], dat[i << 1 | 1]);\n }\n inline void update(int idx, const T a) {\n idx += len;\n dat[idx] = Op::update(dat[idx], a);\n for (idx >>= 1; 0 < idx; idx >>= 1)\n dat[idx] = Op::merge(dat[idx << 1], dat[idx << 1 | 1]);\n }\n inline T value(int l, int r) {\n T vl = unit, vr = unit;\n for (l += len, r += len; l < r; l >>= 1, r >>= 1) {\n if (l & 1)vl = Op::merge(vl, dat[l++]);\n if (r & 1)vr = Op::merge(dat[--r], vr);\n }\n return Op::merge(vl, vr);\n }\n inline T operator[](int idx) { return dat[idx + len]; }\n};\ntemplate<class Type> struct llMaxChmaxUpdate {\n using T = Type;\n const static T unit = -1;\n inline static T merge(T vl, T vr) { return max(vl, vr); }\n inline static T update(T vl, T vr) { return max(vl, vr); }\n};\n\nint main() {\n init();\n\n int n, m; cin >> n >> m;\n VL v(n + 1), h(n + 1);\n FOR(i, 0, n)cin >> v[i] >> h[i];\n VL d(n + 1);\n FOR(i, 0, n - 1) {\n d[i] += abs(h[i + 1] - h[i]);\n d[i + 1] += d[i];\n }\n FOR(i, 0, n - 1) {\n v[i + 1] += v[i];\n h[i + 1] += h[i];\n }\n\n auto val = [&](int l, int r) { //[l,r]\n chmax(l, 0);\n if (l > r)return 0LL;\n return h[r] - (l == 0 ? 0 : h[l - 1])\n + (r == 0 ? 0 : d[r - 1]) - (l == 0 ? 0 : d[l - 1]);\n };\n\n VL t(m), s(m);\n FOR(i, 0, m)cin >> t[i] >> s[i];\n SegmentTree<llMaxChmaxUpdate<ll>> seg1(VL(n + 1, -1));\n seg1.update(0, val(0, n - 1));\n\n VI l(m + 1, INF), r(m + 1, -1);\n l[0] = r[0] = 0;\n ll ans = -1;\n FOR(i, 0, m) {\n ll res;\n SegmentTree<llMaxChmaxUpdate<ll>> seg2(VL(n + 1, -1));\n eFOR(j, l[i], n) {\n if (t[i] < (j == 0 ? 0 : v[j - 1]))break;\n res = max(seg1.value(l[i], min(r[i] + 1, j))\n - val(j - 1, n - 1) + val(j - 1, j - 1), seg1[j] - val(j, n - 1));\n if (s[i] <= res) {\n chmin(l[i + 1], j);\n chmax(r[i + 1], j);\n seg2.update(j, res + val(j, n - 1));\n if (i == m - 1)\n chmax(ans, t[m - 1] - (j == 0 ? 0 : v[j - 1]));\n }\n }\n seg1 = seg2;\n }\n print(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3324, "score_of_the_acc": -0.2143, "final_rank": 9 }, { "submission_id": "aoj_0344_4761203", "code_snippet": "#include<iostream>\n#include<vector>\n#include<utility>\n#include<algorithm>\nusing namespace std;\nint main() {\n\tlong long N,M;\n\tcin >> N >> M;\n\tvector<long long> h(2*N,0),v(N+1,0),t(M),s(M);\n\tlong long i,j,k;\n\tfor(i=0;i<N;i++) {\n\t\tcin >> j;\n\t\tv[i+1] = v[i] + j;\n\t\tcin >> j;\n\t\tif(i>0)h[2*i] = h[2*i-1]+abs(j-(h[2*i-1]-h[2*i-2]));\n\t\th[2*i+1] = h[2*i] + j;\n\t}\n\tfor(i=0;i<M;i++)cin >> t[i] >> s[i];\n\tvector<vector<long long>> dp(M+1,vector<long long>(N+1,-1));\n\tdp[0][0] = 0;\n\tlong long l,r;\n\tbool f;\n\tvector<vector<pair<pair<long long,long long>,long long>>> a(2,vector<pair<pair<long long,long long>,long long>>(1,pair<pair<long long,long long>,long long>(pair<long long,long long>(h[2*N-1]-h[0],0),0)));\n\tvector<bool> ed(N);\n\tfor(i=0;i<M;i++) {\n\t\tvector<pair<pair<long long,long long>,long long>>().swap(a[(i+1)%2]);\n\t\tsort(a[i%2].begin(),a[i%2].end(),greater<pair<pair<long long,long long>,long long>>());\n\t\tfor(j=0;j<N;j++)ed[j] = false;\n\t\tfor(j=0;j<a[i%2].size();j++)if(dp[i][a[i%2][j].first.second] == a[i%2][j].second) {\n\t\t\tif(dp[i][a[i%2][j].first.second] >= s[i] && dp[i+1][a[i%2][j].first.second] < dp[i][a[i%2][j].first.second]) {\n\t\t\t\tdp[i+1][a[i%2][j].first.second] = dp[i][a[i%2][j].first.second];\n\t\t\t\ta[(i+1)%2].push_back(pair<pair<long long,long long>,long long>(pair<long long,long long>(h[2*N-1]-h[2*a[i%2][j].first.second]+dp[i+1][a[i%2][j].first.second],a[i%2][j].first.second),dp[i+1][a[i%2][j].first.second]));\n\t\t\t}\n\t\t\tf = true;\n\t\t\tfor(k=a[i%2][j].first.second+1;k<=N && f;k++) {\n\t\t\t\tif(ed[k])f = false;\n\t\t\t\telse if(t[i] < v[k])f = false;\n\t\t\t\telse {\n\t\t\t\t\tif(dp[i][a[i%2][j].first.second]+h[max(2*a[i%2][j].first.second,2*k-1)]-h[2*a[i%2][j].first.second] >= s[i]) {\n\t\t\t\t\t\tif(dp[i+1][k] < dp[i][a[i%2][j].first.second]+h[max(2*a[i%2][j].first.second,2*k-1)]-h[2*a[i%2][j].first.second]) {\n\t\t\t\t\t\t\tdp[i+1][k] = dp[i][a[i%2][j].first.second]+h[max(2*a[i%2][j].first.second,2*k-1)]-h[2*a[i%2][j].first.second];\n\t\t\t\t\t\t\ta[(i+1)%2].push_back(pair<pair<long long,long long>,long long>(pair<long long,long long>(h[2*N-1]-h[2*k]+dp[i+1][k],k),dp[i+1][k]));\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\ted[k] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tlong long ans = -1;\n\tfor(i=0;i<=N;i++) {\n\t\tif(dp[M][i] != -1)ans = max(ans,t[M-1]-v[i]);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 26764, "score_of_the_acc": -0.3568, "final_rank": 12 }, { "submission_id": "aoj_0344_4761096", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n \n#define REP(i, n) for (ll i = 0; i < n; i++)\n#define REPR(i, n) for (ll i = n; i >= 0; i--)\n#define FOR(i, m, n) for (ll i = m; i < n; i++)\n#define FORR(i, m, n) for (ll i = m; i >= n; i--)\n#define REPO(i, n) for (ll i = 1; i <= n; i++)\n#define ll long long\n#define INF (ll)1 << 60\n#define MINF (-1 * INF)\n#define ALL(n) n.begin(), n.end()\n#define MOD 1000000007\n#define P pair<ll, ll>\n\nll n, m, v[5000], h[5000], t[5000], s[5000], str[3100];\nint main() {\n cin >> n >> m;\n vector<vector<ll> > dp(3100, vector<ll>(3100, INF));\n dp[0][0] = 0;\n REPO(i, n) {\n cin >> v[i] >> h[i];\n }\n REPO(i, n) {\n v[i + 1] += v[i];\n }\n REPO(i, m) {\n cin >> t[i] >> s[i];\n }\n REPO(i, n) {//i個目まで買ったときの最大のstr\n str[i] += h[i];\n str[i + 1] += abs(h[i] - h[i + 1]) + str[i];\n //cout << i << \" ! \" << str[i] << endl;\n }\n REP(i, m) {\n //if(dp[i][j])\n ll sonsitsu = dp[i][0];\n ll nowev = i + 1;\n REP(j, n + 1) {//jこ買った\n if(t[nowev] < v[j]) break;\n dp[nowev][j] = min(dp[nowev][j], sonsitsu);\n if(j > 0)sonsitsu = min(sonsitsu, dp[i][j] + abs(h[j] - h[j + 1]));\n\n dp[nowev][j] = min(dp[nowev][j], dp[i][j]);\n //powercheck\n ll okson = str[j] - s[nowev];\n if (okson < dp[nowev][j]) dp[nowev][j] = INF;\n // cout << i + 1 << \" \" << j << \" \" << dp[i + 1][j] << \" \" << okson << endl;\n }\n }\n ll mi = INF;\n REP(i, n + 1) {\n if (dp[m][i] < INF) mi = min(mi, i);\n }\n ll ans = t[m];\n if (mi == INF) {\n cout << -1 << endl;\n return 0;\n }\n ans -= v[mi];\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 78148, "score_of_the_acc": -0.4668, "final_rank": 14 }, { "submission_id": "aoj_0344_4761093", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n \n#define REP(i, n) for (ll i = 0; i < n; i++)\n#define REPR(i, n) for (ll i = n; i >= 0; i--)\n#define FOR(i, m, n) for (ll i = m; i < n; i++)\n#define FORR(i, m, n) for (ll i = m; i >= n; i--)\n#define REPO(i, n) for (ll i = 1; i <= n; i++)\n#define ll long long\n#define INF (ll)1 << 60\n#define MINF (-1 * INF)\n#define ALL(n) n.begin(), n.end()\n#define MOD 1000000007\n#define P pair<ll, ll>\n\nll n, m, v[5000], h[5000], t[5000], s[5000], str[2100];\nint main() {\n cin >> n >> m;\n vector<vector<ll> > dp(3100, vector<ll>(3100, INF));\n dp[0][0] = 0;\n REPO(i, n) {\n cin >> v[i] >> h[i];\n }\n REPO(i, n) {\n v[i + 1] += v[i];\n }\n REPO(i, m) {\n cin >> t[i] >> s[i];\n }\n REPO(i, n) {//i個目まで買ったときの最大のstr\n str[i] += h[i];\n str[i + 1] += abs(h[i] - h[i + 1]) + str[i];\n //cout << i << \" ! \" << str[i] << endl;\n }\n REP(i, m) {\n //if(dp[i][j])\n ll sonsitsu = dp[i][0];\n ll nowev = i + 1;\n REP(j, n + 1) {//jこ買った\n if(t[nowev] < v[j]) break;\n dp[nowev][j] = min(dp[nowev][j], sonsitsu);\n if(j > 0)sonsitsu = min(sonsitsu, dp[i][j] + abs(h[j] - h[j + 1]));\n\n dp[nowev][j] = min(dp[nowev][j], dp[i][j]);\n //powercheck\n ll okson = str[j] - s[nowev];\n if (okson < dp[nowev][j]) dp[nowev][j] = INF;\n // cout << i + 1 << \" \" << j << \" \" << dp[i + 1][j] << \" \" << okson << endl;\n }\n }\n ll mi = INF;\n REP(i, n + 1) {\n if (dp[m][i] < INF) mi = min(mi, i);\n }\n ll ans = t[m];\n if (mi == INF) {\n cout << -1 << endl;\n return 0;\n }\n ans -= v[mi];\n cout << ans << endl;\n}", "accuracy": 0.4666666666666667, "time_ms": 10, "memory_kb": 78144, "score_of_the_acc": -0.4549, "final_rank": 20 }, { "submission_id": "aoj_0344_4411210", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<int> vs(n), hs(n), ts(m), ss(m);\n vector<int> vsum(n+1);\n for (int i = 0; i < n; ++i) {\n cin >> vs[i] >> hs[i];\n vsum[i+1] = vsum[i]+vs[i];\n }\n for (int i = 0; i < m; ++i) cin >> ts[i] >> ss[i];\n auto dp = make_v(m+1, n+1, -INF<ll>);\n\n dp[0][0] = 0;\n for (int i = 1; i <= m; ++i) {\n ll val1 = -INF<ll>, val2 = dp[i-1][0];\n for (int j = 0; j <= n; ++j) {\n if(j){\n val1 += hs[j-1]; val2 += hs[j-1];\n if(j >= 2){\n val1 += abs(hs[j-1]-hs[j-2]);\n }\n }\n val1 = max(val1, val2);\n val2 = dp[i-1][j];\n if(ts[i-1] >= vsum[j]) dp[i][j] = max(val1, val2);\n if(dp[i][j] < ss[i-1]) dp[i][j] = -INF<ll>;\n }\n }\n int ans = ts.back();\n for (int i = 0; i <= n; ++i) {\n if(dp.back()[i] >= 0){\n cout << ans << \"\\n\";\n return 0;\n }\n if(i != n) ans -= vs[i];\n }\n cout << -1 << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26352, "score_of_the_acc": -0.14, "final_rank": 6 } ]
aoj_0349_cpp
環状すごろく ユキさんは、子供会の催しでみんなで遊べるようにすごろくを作りました。このすごろくでは、環状にマスが並んでいて、それぞれのマスには1以上の整数が書いてあります。 プレイヤーは出発点としてどこかのマスを選んで自分の駒を置きます。そのマスに書いてある数だけ、時計回りに駒を進めます。止まったマスに書いてある数だけ、再び時計回りに駒を進めます。これを繰り返して、出発点に選んだマスの上で駒が止まったら「あがり」です。 実際には、マスの選び方によっては絶対に「あがり」にならない場合もあります。ユキさんは、このすごろくで「あがり」にたどり着けるマスの個数を数えようとしています。 すごろくの情報を入力とし、「あがり」にたどり着けるマスの個数を報告するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N a 1 a 2 ... a N 1行目にすごろくに含まれるすべてのマスの個数 N (1 ≤ N ≤ 100000) が与えられる。2行目に、それぞれのマスに書かれた数 a i (1 ≤ a i ≤ 10 9 ) が、時計回りに順番に与えられる。 Output 「あがり」にたどり着けるマスの個数を1行に出力する。 Sample Input 1 3 1 1 1 Sample Output 1 3 Sample Input 2 3 1 1 2 Sample Output 2 2 Sample Input 3 8 2 3 7 3 3 3 4 4 Sample Output 3 6
[ { "submission_id": "aoj_0349_11030870", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n#define ll long long\n#define ld long double\n#define vec vector\n#define vi vec<int>\n#define vll vec<ll>\n#define vld vec<ld>\n#define pq priority_queue\n#define rep(i, l, r) for(int i = (int)(l); i < (int)(r); i++)\n\ntemplate<class T>\nbool chmin(T &a, T b) {\n\tif(a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\ntemplate<class T>\nbool chmax(T &a, T b) {\n\tif(a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nsigned main() {\n\tint n; cin >> n;\n\tvi a(n); rep(i, 0, n) cin >> a[i];\n\tvi to(n); rep(i, 0, n) to[i] = (i + a[i]) % n;\n\tvi ok(n, -1);\n\tvec<bool> vis(n, false);\n\trep(i, 0, n) {\n\t\tif(vis[i]) continue;\n\t\tint pos = i;\n\t\twhile(true) {\n\t\t\tok[pos]++;\n\t\t\tif(ok[pos] == 2) {ok[pos] = 1; break;}\n\t\t\tpos = to[pos];\n\t\t\tif(vis[pos]) break;\n\t\t}\n\t\tpos = i;\n\t\twhile(true) {\n\t\t\tvis[pos] = true;\n\t\t\tpos = to[pos];\n\t\t\tif(vis[pos]) break;\n\t\t}\n\t}\n\tint ans = 0;\n\trep(i, 0, n) if(ok[i] > 0) ans++;\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5276, "score_of_the_acc": -0.0885, "final_rank": 8 }, { "submission_id": "aoj_0349_11017168", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int N;\n cin>>N;\n vector<int> P(N);\n for(int i=0;i<N;i++){\n int a;\n cin>>a;\n P[i] = (i+a)%N;\n }\n for(int i=0;i<20;i++){\n vector<int> A(N);\n for(int j=0;j<N;j++) A[j] = P[P[j]];\n P = A;\n }\n set<int> s;\n for(int x:P) s.insert(x);\n cout<<s.size()<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8316, "score_of_the_acc": -0.2705, "final_rank": 11 }, { "submission_id": "aoj_0349_10945579", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector<int> A(N);\n\trep(i, 0, N) {\n\t\tcin >> A[i];\n\t\tA[i] %= N;\n\t}\n\t\n\tvector<int> res(N, -1);\n\trep(i, 0, N) if (res[i] == -1) {\n\t\tvector<int> vis;\n\t\tset<int> S;\n\t\tint cur = i;\n\t\tvis.push_back(i);\n\t\tS.insert(i);\n\t\t\n\t\twhile (true) {\n\t\t\tint next = (cur + A[cur]) % N;\n\t\t\t\n\t\t\tif (S.count(next)) {\n\t\t\t\tbool flag = false;\n\t\t\t\tfor (int v : vis) {\n\t\t\t\t\tif (v == next) flag = true;\n\t\t\t\t\tif (flag) res[v] = 1;\n\t\t\t\t\telse res[v] = 0;\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t\n\t\t\tif (res[next] != -1) {\n\t\t\t\tfor (int v : vis) res[v] = 0;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\t\n\t\t\tvis.push_back(next);\n\t\t\tS.insert(next);\n\t\t\tcur = next;\n\t\t}\n\t}\n\t\n\tint ans = 0;\n\trep(i, 0, N) if (res[i] == 1) ++ans;\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8788, "score_of_the_acc": -0.2785, "final_rank": 12 }, { "submission_id": "aoj_0349_10848679", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, int>;\n\nint main() {\n int N;\n cin >> N;\n vector<int> a(N);\n for(int i=0; i<N; ++i) {\n cin >> a[i];\n }\n vector<int> cnt(N, -1);\n vector<int> id(N, -1);\n int res = 0;\n for(int i=0; i<N; ++i) {\n if(cnt[i] == -1) {\n int sum = 0;\n int now = i;\n while(cnt[now] == -1) {\n cnt[now] = sum++;\n id[now] = i;\n (now += a[now]) %= N;\n }\n if(id[now] == i) {\n res += sum - cnt[now];\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4172, "score_of_the_acc": -0.0288, "final_rank": 5 }, { "submission_id": "aoj_0349_8455777", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n int n,ind = 0;\n cin >> n;\n vector<vector<int>> vec(n,vector<int>(3,-1));\n for(int i = 0; i < n; i++) vec[i][2] = 0;\n for(int i = 0; i < n; i++) cin >> vec[i][0];\n \n for(int i = 0; i < n; i++){\n if(vec[i][1] >= 0) continue;\n \n int p = i;\n bool isEnd = false;\n while(true){\n if(vec[p][1] == ind){\n vec[p][2] = 1;\n break;\n }else if(vec[p][1] >= 0){\n isEnd = true;\n break;\n }\n vec[p][1] = ind;\n p = (vec[p][0] % n + p) % n;\n }\n ind++;\n if(isEnd) continue;\n while(true){\n p = (vec[p][0] % n + p) % n;\n if(vec[p][2] == 0) vec[p][2] = 1;\n else break;\n }\n }\n int count = 0;\n for(int i = 0; i < n; i++) if(vec[i][2]) count++;\n cout << count << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8616, "score_of_the_acc": -0.2867, "final_rank": 13 }, { "submission_id": "aoj_0349_8268110", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n, a, to[100010];\n bool alr[100010];\n bool ok[100010]={};\n queue<int> que;\n cin >> n;\n for(int i=0;i<n;i++){\n cin >> a;\n to[i] = (i+a)%n;\n }\n int ans=0;\n for(int i=0;i<n;i++){\n if(ok[i]) continue;\n int now=i;\n memset(alr, false, sizeof(alr));\n while(!alr[now]){\n que.push(now);\n alr[now] = true;\n now = to[now];\n if(ok[now]){\n while(!que.empty()) que.pop();\n alr[now] = true;\n }\n }\n while(!que.empty() && que.front()!=now) que.pop();\n while(!que.empty()){\n ok[que.front()] = true;\n que.pop();\n ans++;\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 3992, "score_of_the_acc": -0.4752, "final_rank": 17 }, { "submission_id": "aoj_0349_8265715", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n int a;\n cin>>a;\n long b[a];\n long c[a];\n for(int i=0;i<a;i+=1){\n cin>>b[i];\n c[i]=-1;\n }\n map<int,int> e;\n for(int i=0;i<a;i+=1){\n long t=i;\n if(!e.count(t)){\n while(!e.count(t)){\n e[t]=1;\n t=(b[t]+t)%a;\n }\n while(c[t]==-1){\n c[t]=1;\n t=(b[t]+t)%a;\n }\n t=i;\n while(c[t]==-1){\n c[t]=0;\n t=(b[t]+t)%a;\n }\n }\n }\n int ans=0;\n for(int i=0;i<a;i+=1){\n ans+=c[i];\n //cout<<c[i]<<endl;\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 9576, "score_of_the_acc": -0.3913, "final_rank": 16 }, { "submission_id": "aoj_0349_7054378", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\n\n#define rep(i,n) for(int i=0;i<int(n);i++)\n#define rep2(i,s,n) for(int i=int(s);i<int(n);i++)\n\ntemplate<typename T>\nbool chmax(T &a,T b){\n return (a<b ? a=b,true:false);\n}\n\n\nint main(){\n cout << fixed << setprecision(20);\n int n;\n cin >> n;\n vector<int> a(n);\n rep(i,n)cin >> a[i],a[i]%=n;\n vector<int> al(n,-1);\n int ans=0;\n rep(i,n)if(al[i]==-1){\n al[i]=0;\n int j=i;\n queue<int> seen_now;\n while(true){\n seen_now.emplace(j);\n if(al[(j+a[j])%n]==-2)break;\n else if(al[(j+a[j])%n]==-1){\n al[(j+a[j])%n]=al[j]+1;\n j+=a[j];\n j%=n;\n continue;\n }\n else{\n //数字が書いてある!\n ans+=al[j]-al[(j+a[j])%n]+1;\n break;\n }\n }\n while(!seen_now.empty()){\n al[seen_now.front()]=-2;\n seen_now.pop();\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4364, "score_of_the_acc": -0.0392, "final_rank": 7 }, { "submission_id": "aoj_0349_6403691", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nclass SCC{\nprivate:\n vector<vector<int>> G;\n vector<vector<int>> rG;\n vector<bool> visited;\n vector<int> vs;\n vector<int> cmp;\n\n void dfs1(int v){\n visited[v] = true;\n for(auto &nex: G[v]){\n if(visited[nex]) continue;\n dfs1(nex);\n }\n vs.emplace_back(v);\n }\n\n void dfs2(int v, int k){\n visited[v] = true;\n cmp[v] = k;\n for(auto &nex: rG[v]){\n if(visited[nex]) continue;\n dfs2(nex, k);\n }\n }\npublic:\n SCC(int n):\n G(vector<vector<int>>(n)), rG(vector<vector<int>>(n)),\n visited(vector<bool>(n, false)), cmp(vector<int>(n)) {}\n\n void add_edge(int from, int to){\n G[from].emplace_back(to);\n rG[to].emplace_back(from);\n }\n\n vector<vector<int>> scc(){\n for(int i = 0; i < G.size(); i++){\n if(!visited[i]) dfs1(i);\n }\n\n fill(visited.begin(), visited.end(), false);\n reverse(vs.begin(), vs.end());\n int k = 0;\n for(auto &it: vs){\n if(visited[it]) continue;\n dfs2(it, k);\n k++;\n }\n\n vector<vector<int>> res(k);\n for(int i = 0; i < G.size(); i++) res[cmp[i]].emplace_back(i);\n return res;\n }\n};\n\nint main(){\n int n; cin >> n;\n vector<int> a(n);\n for(auto &it: a) cin >> it;\n SCC G(n);\n for(int i = 0; i < n; i++){\n G.add_edge(i, (i+a[i])%n);\n }\n\n auto res = G.scc();\n int ans = 0;\n for(auto vec: res){\n if(vec.size() > 1) ans += vec.size();\n }\n for(auto &it: a){\n if(it%n == 0) ans++;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 22124, "score_of_the_acc": -1.0175, "final_rank": 19 }, { "submission_id": "aoj_0349_6039293", "code_snippet": "#ifdef LOGX\n#define _GLIBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\n/*---------macro---------*/\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = s; i < (int)(n); i++)\n#define unless(x) if(!(x))\n#define until(x) while(!(x))\n#define ALL(a) a.begin(),a.end()\n#define RALL(a) a.rbegin(),a.rend()\n#define mybit(i,j) (((i)>>(j))&1)\n\n/*---------type/const---------*/\nconst int big=1000000007;\n//const int big=998244353;\nconst double EPS=1e-8; //適宜変える\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef std::string::const_iterator state; //構文解析\nconst int dx[4]={1,0,-1,0};\nconst int dy[4]={0,1,0,-1};\nconst char newl='\\n';\nstruct{\n constexpr operator int(){return -int(1e9)-10;}\n constexpr operator ll(){return -ll(1e18)-10;}\n}neginf;\nstruct{\n constexpr operator int(){return int(1e9)+10;}\n constexpr operator ll(){return ll(1e18)+10;}\n constexpr auto operator -(){return neginf;}\n}inf;\n\n/*---------debug---------*/\n#ifdef LOGX\n#include <template/debug.hpp>\n#else\n#define dbg(...) ;\n#define dbgnewl ;\n#define prt(x) ;\n#define _prt(x) ;\n#endif\n\n/*---------function---------*/\ntemplate<typename T> T max(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=max(ans,elem);}return ans;}\ntemplate<typename T> T min(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=min(ans,elem);}return ans;}\ntemplate<typename T,typename U> bool chmin(T &a,const U b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T,typename U> bool chmax(T &a,const U b){if(a<b){a=b;return true;}return false;}\nbool valid(int i,int j,int h,int w){return (i>=0 && j>=0 && i<h && j<w);}\ntemplate<class T,class U>T expm(T x,U y,const ll mod=big){T res=1;while(y){if(y&1)(res*=x)%=mod;(x*=x)%=mod;y>>=1;}return res;}\ntemplate<class T,class U>T exp(T x,U y){T res=1;while(y){if(y&1)res*=x;x*=x;y>>=1;}return res;}\n\n\n\nint main(){\n //std::ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n std::cout.precision(10);\n/*------------------------------------*/\n \n int n;\n cin >> n;\n vector<int> g(n);\n rep(i,n){\n int a;\n cin >> a;\n g[i]=(i+a)%n;\n }\n int ans=0;\n vector<int> d(n);\n //0:まだ 1:調査中 2:済み\n vector<int> seen(n);\n auto dfs=[&](int v,auto &dfs)->void{\n if(seen[g[v]]==1){\n ans+=d[v]-d[g[v]]+1;\n }\n else if(seen[g[v]]==0){\n seen[v]=1;\n d[g[v]]=d[v]+1;\n dfs(g[v],dfs);\n }\n seen[v]=2;\n return;\n };\n rep(i,n)if(seen[i]==0){\n dfs(i,dfs);\n }\n cout << ans << newl;\n}\n/*\n無向グラフに直して閉路検出すれば良い dfsだと楽\n*/", "accuracy": 1, "time_ms": 20, "memory_kb": 7268, "score_of_the_acc": -0.1963, "final_rank": 10 }, { "submission_id": "aoj_0349_6022388", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint s[100005];\nint to[100005];\nbool c[100005];\nint dfs(int u){\n if(s[u]==2)return 2;\n if(s[u]==1){s[u]=2; return 3;}\n s[u]=1;\n int res=dfs(to[u]);\n if(res==2){s[u]=2; return 2;}\n if(res==3){\n c[u]=true;\n if(s[u]==2)return 2;\n else {\n s[u]=2;\n return 3;\n }\n }\n}\n\nint main(){\n int n; cin>>n;\n vector<int> a(n); for(int i=0; i<n; i++) cin>>a[i], to[i]=(i+a[i])%n;\n int ans=0;\n for(int i=0; i<n; i++) {\n dfs(i);\n // cout<<c[i]<<\" \";\n ans+=c[i];\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5544, "score_of_the_acc": -0.1206, "final_rank": 9 }, { "submission_id": "aoj_0349_5789473", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <string>\n#include <set>\n#include <map>\n#include <random>\n#include <bitset>\n#define rep(i,n) for (int i = 0; i < int(n); ++i)\n#define repp(i,n,m) for (int i = m; i < int(n); ++i)\n#define repb(i,n) for (int i = int(n)-1; i >= 0; --i)\n#define fi first\n#define se second\nusing namespace std;\n\nconst string alp = \"abcdefghijklmnopqrstuvwxyz\";\nusing ll = long long;\nusing ld = long double;\nusing P = pair<int, int>;\nusing PL = pair<long long, long long>;\nusing Pxy = pair<long double, long double>;\nusing pil = pair<int,ll>;\nusing pli = pair<ll,int>;\nconst int INF = 1001001007;\nconst long long mod1 = 1000000007LL;\nconst long long mod2 = 998244353LL;\nconst ll inf = 2e18;\nconst ld pi = 3.14159265358979323;\nconst ld eps = 1e-7;\ntemplate<typename T>void rev(vector<T> &v){reverse(v.begin(),v.end());}\ntemplate<typename T>void sor(vector<T> &v, int f=0){sort(v.begin(),v.end());if(f!=0) rev(v);}\ntemplate<typename T>bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T>bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}\nvoid dout(ld h=-1.23456789){cout<<setprecision(20);if(abs(h+1.23456789)>eps)cout<<h<<endl;}\ntemplate<typename T,typename U> void pout(pair<T,U> p){cout<<p.fi<<\" \"<<p.se<<endl;}\n\nstruct vs{\n vector<int> to;\n};\n\nint main(){\n int n; cin >> n;\n vector<int> ar(n);\n rep(i,n) cin >> ar[i], ar[i] %= n;\n int ans = 0;\n map<int,int> mp;\n set<int> st;\n int ti = 0;\n rep(i,n) st.insert(i);\n while (!st.empty()){\n int p = *st.begin();\n st.erase(p);\n mp[p] = ti;\n int ima = p;\n while (true){\n int nex = (ima + ar[ima]) % n;\n ti++;\n if (mp.find(nex) == mp.end()){\n mp[nex] = ti;\n st.erase(nex);\n ima = nex;\n }\n else {\n if (mp[nex] != -1){\n ans += ti - mp[nex];\n }\n ima = p;\n mp[p] = -1;\n while (true){\n int tug = (ima + ar[ima]) % n;\n if (mp[tug] != -1) mp[tug] = -1, ima = tug;\n else break;\n }\n break;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 8136, "score_of_the_acc": -0.3836, "final_rank": 15 }, { "submission_id": "aoj_0349_5565985", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto N=in();\n\tvll V=vecin(N);\n\tvll F(N,-1);\n\tREP(i,N){\n\t\tif(F[i]>=0) continue;\n\n\t\tset<ll> check;\n\t\tvll history;\n\n\t\tcheck.emplace(i);\n\t\thistory.push_back(i);\n\t\tll pos = i;\n\t\twhile(true){\n\t\t\tauto d = (pos+V[pos])%N;\n\t\t\tif(F[d]>=0){\n\t\t\t\tfor(auto& x:history){\n\t\t\t\t\tF[x] = 0;\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tif(check.find(d)==check.end()){\n\t\t\t\tcheck.emplace(d);\n\t\t\t\thistory.push_back(d);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(d==i){\n\t\t\t\t\tfor(auto& x:history){\n\t\t\t\t\t\tF[x] = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tll failed = 0;\n\t\t\t\t\tREP(j,history.size()){\n\t\t\t\t\t\tfailed = j;\n\t\t\t\t\t\tif(history[j]==d) break;\n\t\t\t\t\t\tF[history[j]] = 0;\n\t\t\t\t\t}\n\t\t\t\t\tfor(int j=failed;j<history.size();j++){\n\t\t\t\t\t\tF[history[j]] = 1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tpos = d;\n\t\t}\n\t}\n\tout(count(ALL(F),1));\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10136, "score_of_the_acc": -0.369, "final_rank": 14 }, { "submission_id": "aoj_0349_5480062", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n);\n vector<int> b(n, 0);\n for(int i=0; i<n; i++){\n cin >> a[i];\n a[i] = (a[i]+i) %n;\n b[a[i]]++;\n }\n vector<int> wait;\n for(int i=0; i<n; i++){\n if(b[i] == 0){\n wait.push_back(i);\n }\n }\n int ans = n;\n while(!wait.empty()){\n int c = wait.back();\n wait.pop_back();\n ans--;\n b[a[c]]--;\n if(b[a[c]] == 0){\n wait.push_back(a[c]);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4056, "score_of_the_acc": -0.0225, "final_rank": 4 }, { "submission_id": "aoj_0349_5025510", "code_snippet": "#include<iostream>\nusing namespace std;\nint N,A[1<<17];\nbool vis[1<<17],sed[1<<17];\nmain()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>A[i];\n\t\tA[i]=(i+A[i])%N;\n\t}\n\tint ans=0;\n\tfor(int i=0;i<N;i++)if(!vis[i])\n\t{\n\t\tint t=i;\n\t\tdo{\n\t\t\tvis[t]=true;\n\t\t\tt=A[t];\n\t\t}while(!vis[t]);\n\t\tif(!sed[t])\n\t\t{\n\t\t\tint u=t;\n\t\t\tdo{\n\t\t\t\tsed[u]=true;\n\t\t\t\tu=A[u];\n\t\t\t\tans++;\n\t\t\t}while(u!=t);\n\t\t}\n\t\tint u=i;\n\t\twhile(!sed[u])\n\t\t{\n\t\t\tsed[u]=true;\n\t\t\tu=A[u];\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3684, "score_of_the_acc": -0.0024, "final_rank": 2 }, { "submission_id": "aoj_0349_4989871", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,x,y) for(int i=x;i<y;i++)\n#define range(a) (a).begin(),(a).end()\n#define print(A,x,n) rep(i,0,n){cout<<(i ? \" \":\"\")<<A[i]x;}cout<<endl;\n#define pprint(A,y,m,n) rep(j,0,m){print(A[j],y,n);}\nconst long mod=1e9+7;\nconst int siz=1e5;\nconst int inf=1e9;\nint g[siz];\nint visit[siz] = {};\nint ans = 0;\nvoid dfs(int v){\n\tif(visit[g[v]] == visit[v]){\n int u = v;\n do{\n u = g[u];\n ans++;\n }while(u != v);\n\t\treturn;\n\t}\n\tif(visit[g[v]] == 0){\n visit[g[v]] = visit[v];\n dfs(g[v]);\n }\n}\nint main(){\n\tint N; cin>>N;\n\trep(i,0,N){\n cin>>g[i];\n g[i] = (i + g[i]) % N;\n }\n\trep(i,0,N)if(!visit[i]){ visit[i] = i+1; dfs(i); }\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3868, "score_of_the_acc": -0.0123, "final_rank": 3 }, { "submission_id": "aoj_0349_4973724", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\nint N;\nvector<int> A;\nvector<int> F;\n\nint main() {\n cin>>N;\n A.resize(N);\n rep(i,N){ cin>>A[i]; A[i] = (i+A[i])%N; }\n\n F.assign(N,-1);\n rep(s,N){\n if(F[s]!=-1) continue;\n int p=s;\n while(F[p]==-1){ F[p]=s; p=A[p]; }\n if(F[p]!=s) continue;\n while(F[p]!=N){ F[p]=N; p=A[p]; }\n }\n\n int ans=0;\n rep(i,N) if(F[i]==N) ans++;\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3640, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0349_4813801", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int> a[100005];\nint dfs(int d,int c){\n int u=0;\n for(int i=0;i<a[d].size();i++){\n if(a[d][i]==c){\n return 1;\n }\n else{\n u=dfs(a[d][i],c);\n if(u==1) break;\n }\n }\n return u;\n}\nsigned main(){\n int n,b,c=0,sum=0;\n map<int,int> d; \n cin>>n;\n for(int i=0;i<n;i++){\n cin>>b;\n if((b+i)%n!=i) a[(b+i)%n].push_back(i);\n else sum++;\n d[(b+i)%n]++;\n }\n if(d.size()==n) sum=n;\n else{\n for(int i=0;i<n;i++){\n sum+=dfs(i,i);\n }\n }\n cout<<sum<<\"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 13220, "score_of_the_acc": -1.5183, "final_rank": 20 }, { "submission_id": "aoj_0349_4631092", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N;\nint DataInfo[100000];\nint User[100000];\n\nint solve() {\n\tint curPos, tmp, sum;\n\n\tsum = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (User[i] != 0) {\n\t\t\tcontinue;\n\t\t}\n\t\tcurPos = i;\n\t\twhile (User[curPos] == 0) {\n\t\t\tUser[curPos] = i + 1;\n\t\t\tcurPos = (curPos + DataInfo[curPos]) % N;\n\t\t}\n\t\tif (User[curPos] != i + 1) {\n\t\t\tcontinue;\n\t\t}\n\t\ttmp = curPos;\n\t\tdo {\n\t\t\t++sum;\n\t\t\tcurPos = (curPos + DataInfo[curPos]) % N;\n\t\t} while (curPos != tmp);\n\t}\n\n\treturn sum;\n}\n\nint main() {\n\t\n\tcin >> N;\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> DataInfo[i];\n\t}\n\tcout << solve() << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3860, "score_of_the_acc": -0.0294, "final_rank": 6 }, { "submission_id": "aoj_0349_4562404", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nstruct SCC {\n vector<vector<int>> G, G_r, G_out;\n vector<int> vs, used, cmp, sz;\n SCC() = default;\n explicit SCC(int n) : G(n), G_r(n), G_out(n), used(n), cmp(n), sz(n) {}\n\n void add_edge(int a, int b){\n G[a].emplace_back(b);\n G_r[b].emplace_back(a);\n }\n\n void dfs(int v){\n used[v] = 1;\n for (auto &&u : G[v]) if(!used[u]) dfs(u);\n vs.emplace_back(v);\n }\n\n void dfs_r(int v, int k){\n used[v] = 1;\n cmp[v] = k;\n sz[k]++;\n for (auto &&u : G_r[v]) if(!used[u]) dfs_r(u, k);\n }\n\n int build() {\n int n = G.size();\n for (int i = 0; i < n; ++i) if(!used[i]) dfs(i);\n fill(used.begin(),used.end(), 0);\n int k = 0;\n for (int i = n - 1; i >= 0; --i) {\n if(!used[vs[i]]){\n dfs_r(vs[i], k++);\n }\n }\n G_out.resize(k);\n sz.resize(k);\n for (int i = 0; i < n; ++i) {\n for (auto &&j : G[i]) {\n if(cmp[i] != cmp[j]){\n G_out[cmp[i]].emplace_back(cmp[j]);\n }\n }\n }\n for (auto &&l : G_out) {\n sort(l.begin(), l.end());\n l.erase(unique(l.begin(), l.end()), l.end());\n }\n return k;\n }\n\n int operator[](int k) const { return cmp[k]; }\n};\n\n\nint main() {\n int n;\n cin >> n;\n SCC G(n);\n int ans = 0;\n for (int i = 0; i < n; ++i) {\n int x;\n cin >> x;\n if(x%n == 0) ans++;\n else G.add_edge(i, (i+x)%n);\n }\n G.build();\n\n for (auto &&j : G.sz) {\n if(j != 1) ans += j;\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 20332, "score_of_the_acc": -0.9557, "final_rank": 18 } ]
aoj_0351_cpp
静かな町 アイヅ国では、毎年、駅伝大会が開催されています。アイヅ国には N 個の町が点在しており、それぞれ 1 から N までの番号が付いています。いくつかの町の間は、互いに直接行き来できる道でつながっています。また、どの町の間もいくつかの道を辿って行き来ができます。大会のコースは、次のようにして決めます。 2つの町のすべての組み合わせについて、最短経路の距離を求める。 それらの中で、最短経路の距離が最大になるような2つの町を、スタートの町とゴールの町とする。町の組み合わせが複数ある場合、そのうちのどれか一つを選ぶ。 選ばれたスタートの町とゴールの町の間の最短経路を大会のコースとする。最短経路が複数ある場合、そのうちのどれか一つを選ぶ。 ヤマト国から来たお坊さんのトクイツは、アイヅ国のできるだけ静かな町に新しいお寺を開きたいと考えています。そのため、駅伝大会のコースに使われる可能性がない町を知りたがっています。 アイヅ国の町を結ぶ道の情報が与えられたとき、駅伝大会のコースに使われる可能性がない町を求めるプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N R s 1 t 1 d 1 s 2 t 2 d 2 : s R t R d R 1行目に町の数 N (2 ≤ N ≤ 1500) と、町の間を直接つなぐ道の数 R (1 ≤ R ≤ 3000) が与えられる。続く R 行に2つの町を双方向に直接つなぐ道が与えられる。 s i と t i (1 ≤ s i < t i ≤ N ) は i 番目の道がつなぐ2つの町の番号を表し、 d i (1 ≤ d i ≤ 1000) はその道の長さを表す。ただし、どの2つの町についても、それらを直接つなぐ道は高々1本とする。 Output 与えられた道の情報に対して、駅伝大会のコースになることがない町をすべて出力する。1行目に駅伝大会のコースになることがない町の数 M を出力する。続く M 行に、そのような町の番号を昇順で出力する。 Sample Input 1 4 5 1 2 2 1 3 2 2 3 1 2 4 2 3 4 1 Sample Output 1 1 2 Sample Input 2 7 11 1 2 2 1 3 1 2 4 2 2 5 2 2 6 1 3 4 1 3 5 1 3 6 1 4 7 2 5 7 2 6 7 1 Sample Output 2 3 2 4 5
[ { "submission_id": "aoj_0351_11017195", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int N,M;\n cin>>N>>M;\n vector<vector<pair<int,int>>> G(N);\n for(int i=0;i<M;i++){\n int a,b,c;\n cin>>a>>b>>c;\n a--;\n b--;\n G[a].push_back({b,c});\n G[b].push_back({a,c});\n }\n int ma = 0;\n {\n for(int i=0;i<N;i++){\n vector<int> dist(N,1e18);\n dist[i] = 0;\n priority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> pq;\n pq.push({0,i});\n while(!pq.empty()){\n auto [w,u] = pq.top();\n pq.pop();\n for(auto [v,x]:G[u])if(dist[v] > w+x){\n dist[v] = w+x;\n pq.push({dist[v],v});\n }\n }\n ma = max(ma,*max_element(dist.begin(),dist.end()));\n }\n }\n set<int> s;\n {\n for(int i=0;i<N;i++){\n vector<int> dist(N,1e18);\n dist[i] = 0;\n priority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> pq;\n pq.push({0,i});\n while(!pq.empty()){\n auto [w,u] = pq.top();\n pq.pop();\n for(auto [v,x]:G[u])if(dist[v] > w+x){\n dist[v] = w+x;\n pq.push({dist[v],v});\n }\n }\n vector<int> dis(N,1e18);\n for(int i=0;i<N;i++)if(dist[i] == ma){\n dis[i] = 0;\n pq.push({0,i});\n }\n while(!pq.empty()){\n auto [w,u] = pq.top();\n pq.pop();\n for(auto [v,x]:G[u])if(dis[v] > w+x){\n dis[v] = w+x;\n pq.push({dis[v],v});\n }\n }\n for(int i=0;i<N;i++)if(dist[i]+dis[i] == ma) s.insert(i);\n }\n }\n cout<<N-s.size()<<endl;\n for(int i=0;i<N;i++)if(!s.count(i)) cout<<i+1<<endl;\n //cout<<endl;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 3764, "score_of_the_acc": -0.1566, "final_rank": 3 }, { "submission_id": "aoj_0351_10866671", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, int>;\n\nstruct edge {\n int to, cost;\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\nconstexpr int INF = 1e9;\n\nvector<int> dijkstra(graph& g, int s, vector<vector<int>>& prev) {\n vector<int> d(g.size(), INF);\n d[s] = 0;\n priority_queue<P, vector<P>, greater<P>> que;\n que.push(make_pair(0, s));\n while(!que.empty()) {\n P p = que.top();\n que.pop();\n int v = p.second;\n if(d[v] < p.first) {\n continue;\n }\n for(auto& e : g[v]) {\n if(d[e.to] >= d[v] + e.cost) {\n if(d[e.to] > d[v] + e.cost) {\n prev[e.to].clear();\n }\n prev[e.to].push_back(v);\n d[e.to] = d[v] + e.cost;\n que.push(make_pair(d[e.to], e.to));\n }\n }\n }\n return d;\n}\n\nvoid dfs(int v, vector<vector<int>> const& prev, set<int>& s) {\n s.insert(v);\n for(auto x : prev[v]) {\n dfs(x, prev, s);\n }\n}\n\nint main() {\n int N, R;\n cin >> N >> R;\n graph g(N);\n for(int i=0; i<R; ++i) {\n int s, t, d;\n cin >> s >> t >> d;\n s--; t--;\n g[s].push_back((edge){t, d});\n g[t].push_back((edge){s, d});\n }\n int ma = 0;\n set<int> s;\n for(int i=0; i<N; ++i) {\n vector<vector<int>> prev(N);\n vector<int> d = dijkstra(g, i, prev);\n int max_d = *max_element(d.begin(), d.end());\n if(ma <= max_d) {\n if(ma < max_d) {\n s.clear();\n }\n vector<int> max_v;\n for(int j=0; j<N; ++j) {\n if(d[j] == max_d) {\n max_v.push_back(j);\n }\n }\n for(auto v : max_v) {\n dfs(v, prev, s);\n }\n ma = max_d;\n }\n }\n cout << N - s.size() << endl;\n for(int i=0; i<N; ++i) {\n if(s.count(i) == 0) {\n cout << i + 1 << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 3728, "score_of_the_acc": -0.1517, "final_rank": 2 }, { "submission_id": "aoj_0351_8528062", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0351.cc: 静かな町\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 1500;\nconst int INF = 1 << 30;\n\n/* typedef */\n\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\n\n/* global variables */\n\nvpii nbrs[MAX_N];\nvi ps[MAX_N];\nint ds[MAX_N], vs[MAX_N];\nbool used[MAX_N], fs[MAX_N];\n\n/* subroutines */\n\nint dijkstra(int n, int st) {\n fill(ds, ds + n, INF);\n ds[st] = 0;\n ps[st].clear();\n\n priority_queue<pii> q;\n q.push(pii(0, st));\n\n int maxd = 0, maxu = st;\n while (! q.empty()) {\n auto ue = q.top(); q.pop();\n int ud = -ue.first, u = ue.second;\n if (ds[u] != ud) continue;\n\n if (maxd < ud) maxd = ud, maxu = u;\n\n for (auto vw: nbrs[u]) {\n int v = vw.first, vd = ud + vw.second;\n if (ds[v] > vd) {\n\tds[v] = vd;\n\tps[v].assign(1, u);\n\tq.push(pii(-vd, v));\n }\n else if (ds[v] == vd)\n\tps[v].push_back(u);\n }\n }\n return maxu;\n}\n\n/* main */\n\nint main() {\n int n, r;\n scanf(\"%d%d\", &n, &r);\n\n for (int i = 0; i < r; i++) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n u--, v--;\n nbrs[u].push_back(pii(v, w));\n nbrs[v].push_back(pii(u, w));\n }\n\n int t0 = dijkstra(n, 0);\n int t1 = dijkstra(n, t0);\n int dia = ds[t1];\n //printf(\"t0=%d, t1=%d, dia=%d\\n\", t0, t1, dia);\n\n for (int st = 0; st < n; st++) {\n dijkstra(n, st);\n //for (int u = 0; u < n; u++) printf(\" %d\", ds[u]); putchar('\\n');\n\n fill(used, used + n, false);\n qi q;\n for (int u = 0; u < n; u++)\n if (ds[u] == dia) used[u] = true, q.push(u);\n while (! q.empty()) {\n int u = q.front(); q.pop();\n for (auto v: ps[u])\n\tif (! used[v]) {\n\t used[v] = true;\n\t q.push(v);\n\t}\n }\n\n for (int u = 0; u < n; u++) fs[u] = fs[u] || used[u];\n }\n\n int m = 0;\n for (int u = 0; u < n; u++)\n if (! fs[u]) vs[m++] = u;\n \n printf(\"%d\\n\", m);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", vs[i] + 1);\n\n return 0;\n}", "accuracy": 0.25, "time_ms": 230, "memory_kb": 3144, "score_of_the_acc": -0.0261, "final_rank": 18 }, { "submission_id": "aoj_0351_7820027", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <string.h>\nstruct E{\n\tint p;\n\tlong long int c;\n\tbool operator<(const E& e)const{\n\t\treturn c>e.c;\n\t}\n};\n\nusing namespace std;\nlong long int dp[1502][1502];\nvector<E> gs[1502];\nlong long int maxlen=0;\nvoid f(int s){\n\tE e;\n\te.p=s;\n\te.c=0;\n\tlong long int dp2[1502];\n\tmemset(dp2,-1,sizeof(dp2));\n\tdp2[s]=0;\n\tpriority_queue<E> pq;\n\tpq.push(e);\n\twhile(pq.size()>0){\n\t\te=pq.top();\n\t\tpq.pop();\n\t\tif(dp2[e.p]==-2)continue;\n\t\te.c=dp2[e.p];\n\t\tdp[s][e.p]=e.c;\n\t\tdp[e.p][s]=e.c;\n\t\tif(maxlen<e.c){\n\t\t\tmaxlen=e.c;\n\t\t}\n\t\tdp2[e.p]=-2;\n\t\tfor(int i=0;i<gs[e.p].size();i++){\n\t\t\tE e2=gs[e.p][i];\n\t\t\tE e3;\n\t\t\te3.p=e2.p;\n\t\t\te3.c=e.c+e2.c;\n\t\t\tif(dp2[e2.p]==-1 || dp2[e2.p]>e3.c){\n\t\t\t\tdp2[e2.p]=e3.c;\n\t\t\t\tpq.push(e3);\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tint n,m;\n\tcin>>n>>m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b,c;\n\t\tE e;\n\t\tcin>>a>>b>>e.c;\n\t\te.p=b;\n\t\tgs[a].push_back(e);\n\t\te.p=a;\n\t\tgs[b].push_back(e);\n\t}\n\tfor(int s=1;s<=n;s++){\n\t\tf(s);\n\t}\n\tint ans[1501];\n\tmemset(ans,0,sizeof(ans));\n\tfor(int s=1;s<=n;s++){\n\t\tfor(int p=1;p<=n;p++){\n\t\t\tif(ans[p]==1)continue;\n\t\t\tfor(int g=s+1;g<=n;g++){\n\t\t\t\tif(dp[s][g]==dp[s][p]+dp[p][g] && dp[s][g]==maxlen){\n\t\t\t\t\tans[p]=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ansc=0;\n\tfor(int p=1;p<=n;p++){\n\t\tif(ans[p]==0)ansc++;\n\t}\n\tcout<<ansc<<endl;\n\tfor(int p=1;p<=n;p++){\n\t\tif(ans[p]==0)cout<<p<<endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1570, "memory_kb": 21040, "score_of_the_acc": -0.8621, "final_rank": 14 }, { "submission_id": "aoj_0351_7078009", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n\nstruct edge{\n\tint to, cost;\n};\nusing P = pair<int, int>;\nusing Graph = vector<vector<edge>>;\n\nvector<int> Dijkstra(Graph &g, int s){\n\tint n = int(g.size());\n\tconst int INF = 1e9;\n\n\tvector<int> dist(n, INF);\n\tdist[s] = 0;\n\tpriority_queue<P, vector<P>, greater<P>> que;\n\tque.push({0, s});\n\twhile(!que.empty()){\n\t\tauto top = que.top();\n\t\tque.pop();\n\t\tint cost = top.first;\n\t\tint at = top.second;\n\t\tif(dist[at] < cost) continue;\n\n\t\tfor(auto e: g[at]){\n\t\t\tint to = e.to;\n\t\t\tif(dist[to] > cost + e.cost){\n\t\t\t\tdist[to] = cost + e.cost;\n\t\t\t\tque.push({dist[to], to});\n\t\t\t}\n\t\t}\n\t}\n\n\treturn dist;\n}\n\nvector<int> dists[1515];\n\nint main(){\n\tint n, r;\n\tcin >> n >> r;\n\tGraph g(n);\n\trep(_, r){\n\t\tint s, t, d;\n\t\tcin >> s >> t >> d;\n\t\ts--, t--;\n\n\t\tg[s].push_back({t, d});\n\t\tg[t].push_back({s, d});\n\t}\n\n\tint max_d = 0;\n\trep(i, n){\n\t\tdists[i] = Dijkstra(g, i);\n\t\trep(j, n) max_d = max(max_d, dists[i][j]);\n\t}\n\n\tvector<int> offs;\n\trep(i, n) offs.push_back(i);\n\trep(s, n){\n\t\tvector<int> gs;\n\t\trep(i, s){\n\t\t\tif(dists[s][i] == max_d){\n\t\t\t\tgs.push_back(i);\n\t\t\t}\n\t\t}\n\n\t\tvector<int> outs;\n\t\tfor(int v: offs){\n\t\t\tfor(int g: gs){\n\t\t\t\tif(dists[s][v] + dists[g][v] == dists[s][g]){\n\t\t\t\t\touts.push_back(v);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor(int v: outs){\n\t\t\toffs.erase(find(offs.begin(), offs.end(), v));\n\t\t}\n\t}\n\n\tcout << offs.size() << endl;\n\tfor(int v: offs) cout << v + 1 << endl;\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 12352, "score_of_the_acc": -0.3478, "final_rank": 5 }, { "submission_id": "aoj_0351_7054460", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\nusing P=pair<ll,int>;\nconstexpr int inf=1e9+10;\n\n#define rep(i,n) for(int i=0;i<int(n);i++)\n#define rep2(i,s,n) for(int i=int(s);i<int(n);i++)\n\ntemplate<typename T>\nbool chmax(T &a,T b){\n return (a<b ? a=b,true:false);\n}\ntemplate<typename T>\nbool chmin(T &a,T b){\n return (a>b ? a=b,true:false);\n}\n\nstruct Q{\n ll a,b;\n Q(ll x,ll y):a(x),b(y){\n ll g=__gcd(a,b);\n a/=g,b/=g;\n }\n Q operator+=(const Q r){\n return (*this)=(*this)+r;\n }\n friend Q operator+(const Q l,const Q r){\n return Q(l.a*r.b+r.a*l.b,l.b*r.b);\n }\n friend Q operator*(const Q l,const Q r){\n return Q(l.a*r.a,l.b*r.b);\n }\n friend ostream& operator<<(ostream &os,Q x){\n os << x.a << '/' << x.b;\n return os;\n }\n};\nll pow(int a,int b){\n ll ans=1;\n rep(i,b)ans*=a;\n return ans;\n}\n\n\nint main(){\n cout << fixed << setprecision(20);\n int n,m;\n cin >> n >> m;\n vector<vector<pair<int,int>>> g(n);\n rep(i,m){\n int s,t,d;\n cin >> s >> t >> d;\n s--,t--;\n g[s].emplace_back(t,d);\n g[t].emplace_back(s,d);\n }\n int ans=0;\n vector<bool> res(n,false);\n rep(s,n){\n vector<int> dist(n,inf);\n dist[s]=0;\n priority_queue<P,vector<P>,greater<P>> q;\n q.emplace(0,s);\n while(!q.empty()){\n auto di=q.top();q.pop();\n int d=di.first,i=di.second;\n if(d!=dist[i])continue;\n for(auto p:g[i])if(chmin(dist[p.first],d+p.second)){\n q.emplace(dist[p.first],p.first);\n }\n }\n\n int mx=0;\n rep(i,n)chmax(mx,dist[i]);\n if(mx < ans)continue;\n if(mx > ans)rep(i,n)res[i]=false;\n chmax(ans,mx);\n vector<bool> now_ans(n,false);\n rep(i,n){\n if(mx==dist[i]){\n now_ans[i]=true;\n queue<int> q;\n q.emplace(i);\n while(!q.empty()){\n int now=q.front();q.pop();\n for(auto p:g[now])if(!now_ans[p.first]){\n if(dist[p.first]+p.second == dist[now]){\n now_ans[p.first]=true;\n q.emplace(p.first);\n }\n }\n }\n }\n }\n rep(i,n)if(now_ans[i])res[i]=true;\n }\n int cnt=0;\n rep(i,n)if(!res[i])cnt++;\n cout << cnt << endl;\n rep(i,n)if(!res[i])cout << i+1 << endl;;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 3564, "score_of_the_acc": -0.0538, "final_rank": 1 }, { "submission_id": "aoj_0351_7054447", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\nusing P=pair<ll,int>;\nconstexpr int inf=1e9+10;\n\n#define rep(i,n) for(int i=0;i<int(n);i++)\n#define rep2(i,s,n) for(int i=int(s);i<int(n);i++)\n\ntemplate<typename T>\nbool chmax(T &a,T b){\n return (a<b ? a=b,true:false);\n}\ntemplate<typename T>\nbool chmin(T &a,T b){\n return (a>b ? a=b,true:false);\n}\n\nstruct Q{\n ll a,b;\n Q(ll x,ll y):a(x),b(y){\n ll g=__gcd(a,b);\n a/=g,b/=g;\n }\n Q operator+=(const Q r){\n return (*this)=(*this)+r;\n }\n friend Q operator+(const Q l,const Q r){\n return Q(l.a*r.b+r.a*l.b,l.b*r.b);\n }\n friend Q operator*(const Q l,const Q r){\n return Q(l.a*r.a,l.b*r.b);\n }\n friend ostream& operator<<(ostream &os,Q x){\n os << x.a << '/' << x.b;\n return os;\n }\n};\nll pow(int a,int b){\n ll ans=1;\n rep(i,b)ans*=a;\n return ans;\n}\n\n\nint main(){\n cout << fixed << setprecision(20);\n int n,m;\n cin >> n >> m;\n vector<vector<pair<int,int>>> g(n);\n rep(i,m){\n int s,t,d;\n cin >> s >> t >> d;\n s--,t--;\n g[s].emplace_back(t,d);\n g[t].emplace_back(s,d);\n }\n int ans=0;\n vector<bool> res(n,false);\n rep(s,n){\n vector<int> dist(n,inf);\n dist[s]=0;\n priority_queue<P,vector<P>,greater<P>> q;\n q.emplace(0,s);\n while(!q.empty()){\n auto di=q.top();q.pop();\n int d=di.first,i=di.second;\n if(d!=dist[i])continue;\n for(auto p:g[i])if(chmin(dist[p.first],d+p.second)){\n q.emplace(dist[p.first],p.first);\n }\n }\n\n int mx=0;\n rep(i,n)chmax(mx,dist[i]);\n if(mx < ans)continue;\n if(mx > ans)rep(i,n)res[i]=false;\n vector<bool> now_ans(n,false);\n rep(i,n){\n if(mx==dist[i]){\n now_ans[i]=true;\n queue<int> q;\n q.emplace(i);\n while(!q.empty()){\n int now=q.front();q.pop();\n for(auto p:g[now])if(!now_ans[p.first]){\n if(dist[p.first]+p.second == dist[now]){\n now_ans[p.first]=true;\n q.emplace(p.first);\n }\n }\n }\n }\n }\n rep(i,n)if(now_ans[i])res[i]=true;\n }\n int cnt=0;\n rep(i,n)if(!res[i])cnt++;\n cout << cnt << endl;\n rep(i,n)if(!res[i])cout << i+1 << endl;;\n}", "accuracy": 0.25, "time_ms": 220, "memory_kb": 3520, "score_of_the_acc": -0.0271, "final_rank": 20 }, { "submission_id": "aoj_0351_6969626", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0351.cc: 静かな町\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 1500;\nconst int INF = 1 << 30;\n\n/* typedef */\n\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\n\n/* global variables */\n\nvpii nbrs[MAX_N];\nvi ps[MAX_N];\nint ds[MAX_N], vs[MAX_N];\nbool used[MAX_N], zs[MAX_N];\n\n/* subroutines */\n\nint dijkstra(int n, int st) {\n for (int i = 0; i < n; i++) ps[i].clear();\n fill(ds, ds + n, INF);\n ds[st] = 0;\n\n priority_queue<pii> q;\n q.push(pii(0, st));\n\n int maxd = 0, maxu = st;\n while (! q.empty()) {\n pii e = q.top(); q.pop();\n int ud = -e.first, u = e.second;\n if (ds[u] != ud) continue;\n\n if (maxd < ud) maxd = ud, maxu = u;\n\n for (auto vw: nbrs[u]) {\n int v = vw.first, vd = ud + vw.second;\n if (ds[v] > vd) {\n\tds[v] = vd;\n\tps[v].clear(), ps[v].push_back(u);\n\tq.push(pii(-vd, v));\n }\n else if (ds[v] == vd) ps[v].push_back(u);\n }\n }\n return maxu;\n}\n\n/* main */\n\nint main() {\n int n, r;\n scanf(\"%d%d\", &n, &r);\n\n for (int i = 0; i < r; i++) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n u--, v--;\n nbrs[u].push_back(pii(v, w));\n nbrs[v].push_back(pii(u, w));\n }\n\n int t0 = dijkstra(n, 0);\n int t1 = dijkstra(n, t0);\n int dia = ds[t1];\n //printf(\"dia=%d\\n\", dia);\n\n for (int st = 0; st < n; st++) {\n fill(used, used + n, false);\n\n int t = dijkstra(n, st);\n if (ds[t] < dia) continue;\n\n qi q;\n for (int u = 0; u < n; u++)\n if (ds[u] == dia) used[u] = true, q.push(u);\n\n while (! q.empty()) {\n int u = q.front(); q.pop();\n for (auto v: ps[u])\n\tif (! used[v]) used[v] = true, q.push(v);\n }\n\n for (int u = 0; u < n; u++)\n if (used[u]) zs[u] = true;\n }\n\n int m = 0;\n for (int u = 0; u < n; u++)\n if (! zs[u]) vs[m++] = u;\n\n printf(\"%d\\n\", m);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", vs[i] + 1);\n return 0;\n}", "accuracy": 0.25, "time_ms": 230, "memory_kb": 3204, "score_of_the_acc": -0.0269, "final_rank": 19 }, { "submission_id": "aoj_0351_6022304", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define LL int\n#define PA pair<LL,LL>\n#define VE vector\n#define VL VE<LL>\n#define VVL VE<VL>\n#define VP VE<PA>\n#define PB push_back\n#define MP make_pair\n#define PQ priority_queue\n#define FI first\n#define SE second\n#define rep(i,n) for(int i=0;i<n;i++)\n#define INF 1000000003\n\ntemplate<typename T>bool chmax(T &a,T b){\n if(a<b){\n a=b;\n return 1;\n }\n return 0;\n}\ntemplate<typename T>bool chmin(T &a,T b){\n if(a>b){\n a=b;\n return 1;\n }\n return 0;\n}\n\ntypedef struct{\n VP t;LL f,c,n;\n}Node;\n\nstruct Dijkstra{\n VE<Node> node;\n Dijkstra(LL n){\n node.resize(n);\n rep(i,n)node[i].n=i,node[i].f=-1,node[i].c=INF;\n }\n void add(LL s,LL e,LL c){\n node[s].t.PB(MP(c,e));\n }\n void run(LL s=0,LL c=0){\n LL i;\n PQ<PA,VP,greater<PA>> pq;\n node[s].c=c;\n pq.push(MP(c,s));\n while(pq.size()){\n PA now=pq.top();\n pq.pop();\n LL nowc=now.FI,nown=now.SE;\n if(nowc>node[nown].c)continue;\n for(auto ne:node[nown].t){\n LL nec=nowc+ne.FI,nen=ne.SE;\n if(chmin(node[nen].c,nec))pq.push(MP(nec,nen)),node[nen].f=nown;\n }\n }\n }\n};\n\nint main(){\n LL N,R;\n cin>>N>>R;\n LL mx=-1;\n VL ans(N,1),s(R),t(R),d(R);\n Dijkstra D(N);\n rep(i,R){\n cin>>s[i]>>t[i]>>d[i];\n s[i]--,t[i]--;\n D.add(s[i],t[i],d[i]);\n D.add(t[i],s[i],d[i]);\n }\n VVL V(N,VL(N));\n rep(i,N){\n Dijkstra E=D;\n E.run(i);\n rep(j,N)V[i][j]=E.node[j].c,chmax(mx,V[i][j]);\n }\n VP v;\n rep(i,N)for(int j=i+1;j<N;j++)if(V[i][j]==mx)v.PB(MP(i,j)),ans[i]=ans[j]=0;\n VL a;\n rep(i,N)if(ans[i])a.PB(i);\n for(auto p:v){\n VL b;\n for(LL i:a)if(V[p.FI][i]!=mx-V[p.SE][i])b.PB(i);\n a=b;\n }\n cout<<a.size()<<endl;\n for(LL i:a)cout<<i+1<<endl;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 29688, "score_of_the_acc": -0.4455, "final_rank": 7 }, { "submission_id": "aoj_0351_5789525", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <string>\n#include <set>\n#include <map>\n#include <random>\n#include <bitset>\n#define rep(i,n) for (int i = 0; i < int(n); ++i)\n#define repp(i,n,m) for (int i = m; i < int(n); ++i)\n#define repb(i,n) for (int i = int(n)-1; i >= 0; --i)\n#define fi first\n#define se second\nusing namespace std;\n\nconst string alp = \"abcdefghijklmnopqrstuvwxyz\";\nusing ll = long long;\nusing ld = long double;\nusing P = pair<int, int>;\nusing PL = pair<long long, long long>;\nusing Pxy = pair<long double, long double>;\nusing pil = pair<int,ll>;\nusing pli = pair<ll,int>;\nconst int INF = 1001001007;\nconst long long mod1 = 1000000007LL;\nconst long long mod2 = 998244353LL;\nconst ll inf = 2e18;\nconst ld pi = 3.14159265358979323;\nconst ld eps = 1e-7;\ntemplate<typename T>void rev(vector<T> &v){reverse(v.begin(),v.end());}\ntemplate<typename T>void sor(vector<T> &v, int f=0){sort(v.begin(),v.end());if(f!=0) rev(v);}\ntemplate<typename T>bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T>bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}\nvoid dout(ld h=-1.23456789){cout<<setprecision(20);if(abs(h+1.23456789)>eps)cout<<h<<endl;}\ntemplate<typename T,typename U> void pout(pair<T,U> p){cout<<p.fi<<\" \"<<p.se<<endl;}\n\nstruct vs{\n vector<pair<int, long long>> to;\n};\n\nstruct Graph{\n using pli = pair<long long, int>;\n using pil = pair<int, long long>;\n int n, m;\n vector<vs> ar;\n // n : 頂点数 , m : 辺数 , c = 1 : コストを入力 , dual = 1 : 辺が双方向\n Graph(int _n, int _m, int c = 1, int dual = 1) : n(_n), m(_m), ar(n) {\n for (int i = 0; i < m; i++){\n int u, v; cin >> u >> v;\n long long d = 1;\n if (c == 1) cin >> d;\n ar[u-1].to.emplace_back(pil(v-1,d));\n if (dual == 1) ar[v-1].to.emplace_back(pil(u-1,d));\n }\n }\n Graph(vector<vs> _ar, int _n, int _m = 0) : ar(_ar), n(_n), m(_m){}\n vector<long long> dijkstra(int s){\n priority_queue<pli, vector<pli>, greater<pli>> pque;\n vector<long long> dist(n,1e18);\n dist[s] = 0;\n pque.push(pli(0,s));\n while (!pque.empty()){\n pli p = pque.top(); pque.pop();\n if (dist[p.second] < p.first) continue;\n for (pil x : ar[p.second].to){\n if (dist[x.first] > p.first + x.second){\n dist[x.first] = p.first + x.second;\n pque.push(pli(dist[x.first],x.first));\n }\n }\n }\n return dist;\n }\n vector<vector<long long>> washall_floyd(){\n vector<vector<long long>> dist(n,vector<long long>(n,2e18));\n for (int i = 0; i < n; i++) dist[i][i] = 0;\n for (int i = 0; i < n; i++){\n for (pil x : ar[i].to){\n dist[i][x.first] = min(dist[i][x.first], x.second);\n }\n }\n for (int k = 0; k < n; k++){\n for (int i = 0; i < n; i++){\n for (int j = 0; j < n; j++){\n dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n }\n }\n }\n return dist;\n }\n};\nint main(){\n int n, r; cin >> n >> r;\n Graph g(n,r);\n vector<vector<ll>> dis(n);\n rep(i,n) dis[i] = g.dijkstra(i);\n ll ma = 0;\n rep(i,n) rep(j,n) chmax(ma,dis[i][j]);\n set<P> st;\n rep(i,n-1) repp(j,n,i+1) if (dis[i][j] == ma) st.insert(P(i,j));\n set<int> cnt;\n for (P p : st) cnt.insert(p.first), cnt.insert(p.second);\n int ans = n - cnt.size();\n vector<int> res;\n rep(i,n){\n if (cnt.find(i) != cnt.end()) continue;\n bool t = false;\n for (P p : st){\n if (dis[p.first][i] + dis[i][p.second] == ma){\n t = true;\n break;\n }\n }\n if (t) ans--;\n else res.emplace_back(i);\n }\n cout << ans << endl;\n rep(i,ans) cout << res[i] + 1 << endl;\n}", "accuracy": 1, "time_ms": 510, "memory_kb": 73756, "score_of_the_acc": -1.1478, "final_rank": 17 }, { "submission_id": "aoj_0351_5025993", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\nusing namespace std;\nint N,M;\nvector<pair<int,int> >G[1500];\nvector<int>D[1500];\nvector<int>dijkstra(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first;\n\t\t\tint nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nbool ok[1500];\nbool vis[1500];\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tint dist=0;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tD[i]=dijkstra(i);\n\t\tfor(int d:D[i])if(dist<d)dist=d;\n\t}\n\tfor(int i=0;i<N;i++)ok[i]=true;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tfor(int j=0;j<N;j++)vis[j]=false;\n\t\tqueue<int>Q;\n\t\tfor(int j=0;j<N;j++)if(D[i][j]==dist)\n\t\t{\n\t\t\tvis[j]=true;\n\t\t\tok[j]=false;\n\t\t\tQ.push(j);\n\t\t}\n\t\twhile(!Q.empty())\n\t\t{\n\t\t\tint u=Q.front();Q.pop();\n\t\t\tfor(pair<int,int>e:G[u])\n\t\t\t{\n\t\t\t\tint v=e.first;\n\t\t\t\tif(!vis[v]&&D[i][v]+e.second==D[i][u])\n\t\t\t\t{\n\t\t\t\t\tvis[v]=true;\n\t\t\t\t\tok[v]=false;\n\t\t\t\t\tQ.push(v);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<int>ans;\n\tfor(int i=0;i<N;i++)if(ok[i])ans.push_back(i);\n\tcout<<ans.size()<<endl;\n\tfor(int u:ans)cout<<u+1<<endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 12044, "score_of_the_acc": -0.1608, "final_rank": 4 }, { "submission_id": "aoj_0351_5025879", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\nusing namespace std;\nint N,M;\nvector<pair<int,int> >G[1500];\nvector<int>D[1500];\nvector<int>dijkstra(int st)\n{\n\tvector<int>ret(N,1e9);\n\tret[st]=0;\n\tpriority_queue<pair<int,int> >P;\n\tP.push(make_pair(0,st));\n\twhile(!P.empty())\n\t{\n\t\tint cost=-P.top().first,u=P.top().second;\n\t\tP.pop();\n\t\tif(ret[u]<cost)continue;\n\t\tfor(pair<int,int>e:G[u])\n\t\t{\n\t\t\tint v=e.first;\n\t\t\tint nxt=cost+e.second;\n\t\t\tif(ret[v]>nxt)\n\t\t\t{\n\t\t\t\tret[v]=nxt;\n\t\t\t\tP.push(make_pair(-nxt,v));\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nbool ok[1500];\nmain()\n{\n\tcin>>N>>M;\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint a,b,c;cin>>a>>b>>c;\n\t\ta--,b--;\n\t\tG[a].push_back(make_pair(b,c));\n\t\tG[b].push_back(make_pair(a,c));\n\t}\n\tint dist=0;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tD[i]=dijkstra(i);\n\t\tfor(int d:D[i])if(dist<d)dist=d;\n\t}\n\tfor(int i=0;i<N;i++)ok[i]=true;\n\tvector<pair<int,int> >E;\n\tfor(int i=0;i<N;i++)for(int j=i+1;j<N;j++)if(D[i][j]==dist)\n\t{\n\t\tok[i]=ok[j]=false;\n\t\tE.push_back(make_pair(i,j));\n\t}\n\tvector<int>ans;\n\tfor(int i=0;i<N;i++)if(ok[i])\n\t{\n\t\tbool out=false;\n\t\tfor(pair<int,int>e:E)if(D[i][e.first]+D[i][e.second]==dist)\n\t\t{\n\t\t\tout=true;\n\t\t\tbreak;\n\t\t}\n\t\tif(!out)ans.push_back(i+1);\n\t}\n\tcout<<ans.size()<<endl;\n\tfor(int u:ans)cout<<u<<endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 28224, "score_of_the_acc": -0.39, "final_rank": 6 }, { "submission_id": "aoj_0351_4974107", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\nLL GCD(LL a,LL b){ return b?GCD(b,a%b):a; }\n\nstruct Edge{\n int to,d;\n};\n\nstruct DistBuf{\n int D[1500];\n int RD[1500];\n};\n\nstruct QueNode{\n int to,d;\n bool operator<(QueNode r)const{ return d>r.d; }\n};\n\nint N,M;\nvector<Edge> E[1500];\nDistBuf D[1500];\nint F[1500];\n\nint main() {\n cin>>N>>M;\n rep(i,M){\n int s,t,d; cin>>s>>t>>d; s--; t--;\n E[s].push_back({t,d});\n E[t].push_back({s,d});\n }\n\n {\n priority_queue<QueNode> G;\n rep(s,N){\n rep(to,N){ D[s].D[to]=-1; }\n G.push({s,0});\n while(G.size()){\n int p=G.top().to;\n int d=G.top().d;\n G.pop();\n if(D[s].D[p]!=-1) continue;\n D[s].D[p]=d;\n for(Edge e : E[p])\n G.push({e.to, d+e.d});\n }\n }\n }\n\n int maxD = 0;\n rep(i,N) rep(j,N) maxD=max(maxD, D[i].D[j]);\n\n rep(i,N) F[i]=0;\n\n {\n priority_queue<QueNode> G;\n rep(s,N){\n rep(to,N){ D[s].RD[to]=-1; }\n rep(to,N) if(D[s].D[to]==maxD) G.push({to,0});\n while(G.size()){\n int p=G.top().to;\n int d=G.top().d;\n G.pop();\n if(D[s].RD[p]!=-1) continue;\n D[s].RD[p]=d;\n for(Edge e : E[p])\n G.push({e.to, d+e.d});\n }\n }\n }\n\n rep(i,N) rep(j,N) if(D[i].D[j]+D[i].RD[j] == maxD) F[j]=1;\n\n vector<int> ans;\n rep(i,N) if(!F[i]) ans.push_back(i+1);\n cout<<ans.size()<<endl;\n for(int a:ans) cout<<a<<endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 810, "memory_kb": 20976, "score_of_the_acc": -0.5308, "final_rank": 8 }, { "submission_id": "aoj_0351_4630674", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\tpriority_queue<pair<int, int> > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\tif (startNode == curNode) {\n\t\treturn;\n\t}\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 12096, "score_of_the_acc": -0.8442, "final_rank": 13 }, { "submission_id": "aoj_0351_4630653", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nvector<pair<int, int> > CourseInfo;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\tpriority_queue<pair<int, int> > NodeList;\n\t//priority_queue<pair<int, int>,vector<pair<int, int> >,greater<pair<int, int> > > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\t/*if (startNode == curNode) {\n\t\treturn;\n\t}*/\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\t/*if (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}*/\n\t\tif (Result.count(i) == 0) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 12044, "score_of_the_acc": -0.8434, "final_rank": 10 }, { "submission_id": "aoj_0351_4630647", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nvector<pair<int, int> > CourseInfo;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\tpriority_queue<pair<int, int> > NodeList;\n\t//priority_queue<pair<int, int>,vector<pair<int, int> >,greater<pair<int, int> > > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\t/*if (startNode == curNode) {\n\t\treturn;\n\t}*/\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 12076, "score_of_the_acc": -0.8439, "final_rank": 12 }, { "submission_id": "aoj_0351_4630643", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nvector<pair<int, int> > CourseInfo;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\tpriority_queue<pair<int, int> > NodeList;\n\t//priority_queue<pair<int, int>,vector<pair<int, int> >,greater<pair<int, int> > > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\tif (startNode == curNode) {\n\t\treturn;\n\t}\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1890, "memory_kb": 12108, "score_of_the_acc": -0.8748, "final_rank": 15 }, { "submission_id": "aoj_0351_4630641", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nvector<pair<int, int> > CourseInfo;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\t//priority_queue<pair<int, int> > NodeList;\n\tpriority_queue<pair<int, int>,vector<pair<int, int> >,greater<pair<int, int> > > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\tif (startNode == curNode) {\n\t\treturn;\n\t}\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2470, "memory_kb": 12144, "score_of_the_acc": -1.1275, "final_rank": 16 }, { "submission_id": "aoj_0351_4630633", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N,R;\nvector<vector<pair<int, int> > > MapData;\nvector<pair<int, int> > CourseInfo;\nint ShortDistOfEachNode[1501][1501];\nbool Used[1501];\nset<int> Result;\n\nconst int INF = 1e9;\n\nvoid findShortDistOfEachNode(int StartNode, int *dist) {\n\tint curNode, cost, sizeOfTo, nextNode, costTo;\n\tpriority_queue<pair<int, int> > NodeList;\n\tpair<int, int> tmp;\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfill(dist, dist + N + 1, INF);\n\t}\n\tdist[StartNode] = 0;\n\tNodeList.push({ StartNode,0 });\n\twhile (!NodeList.empty()) {\n\t\ttmp = NodeList.top();\n\t\tNodeList.pop();\n\n\t\tcurNode = tmp.first;\n\t\tcost = tmp.second;\n\t\tif (cost > dist[curNode]) {\n\t\t\tcontinue;\n\t\t}\n\t\tsizeOfTo = MapData[curNode].size();\n\t\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\t\tnextNode = MapData[curNode][i].first;\n\t\t\tcostTo = MapData[curNode][i].second;\n\t\t\tif (cost + costTo < dist[nextNode]) {\n\t\t\t\tdist[nextNode] = cost + costTo;\n\t\t\t\tNodeList.push({ nextNode,dist[nextNode] });\n\t\t\t}\n\t\t}\n\n\t}\n}\n\nvoid findNode(int startNode, int curNode, int *dist) {\n\tint sizeOfTo, preNode, cost;\n\n\tif (Used[curNode]) {\n\t\treturn;\n\t}\n\tUsed[curNode] = true;\n\tResult.insert(curNode);\n\tif (startNode == curNode) {\n\t\treturn;\n\t}\n\n\tsizeOfTo = MapData[curNode].size();\n\tfor (int i = 0; i < sizeOfTo; ++i) {\n\t\tpreNode = MapData[curNode][i].first;\n\t\tcost = MapData[curNode][i].second;\n\t\tif (dist[curNode] == dist[preNode] + cost) {\n\t\t\tfindNode(startNode, preNode, dist);\n\t\t}\n\t}\n}\n\nint main() {\n\tint s, t, d, maxShortLen;\n\n\tcin >> N >> R;\n\tMapData.resize(N + 1);\n\tfor (int i = 0; i < R; ++i) {\n\t\tcin >> s >> t >> d;\n\t\tMapData[s].push_back({ t,d });\n\t\tMapData[t].push_back({ s,d });\n\t}\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfindShortDistOfEachNode(i,ShortDistOfEachNode[i]);\n\t}\n\t\n\tmaxShortLen = 0;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == INF) {\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tmaxShortLen = max(maxShortLen, ShortDistOfEachNode[i][j]);\n\t\t}\n\t}\n\n\tfor (int i = 1; i <= N; ++i) {\n\t\tmemset(Used, false, sizeof(Used));\n\t\tfor (int j = 1; j <= N; ++j) {\n\t\t\tif (ShortDistOfEachNode[i][j] == maxShortLen) {\n\t\t\t\tfindNode(i, j, ShortDistOfEachNode[i]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << N - Result.size() << endl;\n\tfor (int i = 1; i <= N; ++i) {\n\t\tif (Result.find(i) == Result.end()) {\n\t\t\tcout << i << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 12072, "score_of_the_acc": -0.8438, "final_rank": 11 }, { "submission_id": "aoj_0351_4630279", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <typename T>\nstruct edge {\n int from, to; T cost;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n};\n\ntemplate <class K, class V>\nclass RadixHeap {\n static constexpr int bit_length = sizeof(K)*8;\n K last;\n size_t sz, cnt;\n\n array<vector<pair<K, V>>, bit_length> v;\n static inline int bsr(int x){\n return x ? bit_length-__builtin_clz(x) : 0;\n }\n static inline int bsr(ll x){\n return x ? bit_length-__builtin_clzll(x) : 0;\n }\n\n void pull() {\n if(cnt < v[0].size()) return;;\n int i = 1;\n while(v[i].empty()) i++;\n last = min_element(v[i].begin(),v[i].end())->first;\n for (auto &&x : v[i]) v[bsr(x.first ^ last)].push_back(x);\n v[i].clear();\n }\npublic:\n RadixHeap() : last(0), sz(0), cnt(0) {}\n void emplace(K x, V val){\n sz++;\n v[bsr(x^last)].emplace_back(x, val);\n }\n\n pair<K, V> top() {\n pull();\n return v[0][cnt];\n }\n\n void pop() {\n pull();\n sz--;\n cnt++;\n }\n\n size_t size() const { return sz; }\n bool empty() const { return !sz; }\n};\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<vector<edge<int>>> G(n);\n for (int i = 0; i < m; ++i) {\n int s, t, d;\n scanf(\"%d %d %d\", &s, &t, &d);\n s--; t--;\n G[s].emplace_back(t, d);\n G[t].emplace_back(s, d);\n }\n RadixHeap<int, int> Q;\n auto d = make_v(n, n, INF<int>);\n vector<int> ok(n, 1);\n for (int s = 0; s < n; ++s) {\n d[s][s] = 0;\n Q.emplace(0, s);\n while(!Q.empty()){\n int cost; int i;\n tie(cost, i) = Q.top(); Q.pop();\n if(d[s][i] < cost) continue;\n for (auto &&e : G[i]) {\n auto cost2 = cost + e.cost;\n if(d[s][e.to] <= cost2) continue;\n d[s][e.to] = cost2;\n Q.emplace(d[s][e.to], e.to);\n }\n }\n }\n int val = 0;\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n chmax(val, d[i][j]);\n }\n }\n for (int i = 0; i < n; ++i) {\n queue<int> q;\n vector<int> visited(n);\n for (int j = 0; j < n; ++j) {\n if(d[i][j] == val){\n q.emplace(j);\n visited[j] = 1;\n }\n }\n while(!q.empty()){\n int x = q.front(); q.pop();\n ok[x] = 0;\n for (auto &&y : G[x]) {\n if(!visited[y.to] && d[i][y.to]+y.cost == d[i][x]){\n q.emplace(y.to);\n visited[y.to] = 1;\n }\n }\n }\n }\n cout << accumulate(ok.begin(),ok.end(), 0) << \"\\n\";\n for (int i = 0; i < n; ++i) {\n if(ok[i]) cout << i+1 << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 45024, "score_of_the_acc": -0.5931, "final_rank": 9 } ]
aoj_0360_cpp
Reservation System The supercomputer system L in the PCK Research Institute performs a variety of calculations upon request from external institutes, companies, universities and other entities. To use the L system, you have to reserve operation time by specifying the start and end time. No two reservation periods are allowed to overlap each other. Write a program to report if a new reservation overlaps with any of the existing reservations. Note that the coincidence of start and end times is not considered to constitute an overlap. All the temporal data is given as the elapsed time from the moment at which the L system starts operation. Input The input is given in the following format. a b N s_1 f_1 s_2 f_2 : s_N f_N The first line provides new reservation information, i.e., the start time a and end time b (0 ≤ a < b ≤ 1000) in integers. The second line specifies the number of existing reservations N (0 ≤ N ≤ 100). Subsequent N lines provide temporal information for the i -th reservation: start time s_i and end time f_i (0 ≤ s_i < f_i ≤ 1000) in integers. No two existing reservations overlap. Output Output "1" if the new reservation temporally overlaps with any of the existing ones, or "0" otherwise. Sample Input 1 5 7 3 1 4 4 5 7 10 Sample Output 1 0 Sample Input 2 3 7 3 7 10 1 4 4 5 Sample Output 2 1
[ { "submission_id": "aoj_0360_9615818", "code_snippet": "#include<bits/stdc++.h>\n#include <iostream>\nusing namespace std;\nint main(void){\n\tint a,b,n,s[101],f[101],cnt=0;\n\tcin>>a>>b>>n;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>s[i];\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tcin>>f[i];\n\t}\n\tfor(int i=a+1;i<b;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\tfor(int k=s[i];k<f[i];k++){\n\t\t\tif(i==k){\n\t\t\t\tcnt=1;\n\t\t\t\tbreak;\n\t\t}\n\t\t}\n\t}\n\t}\n\tcout<<cnt<<endl;\n\treturn 0;\n}", "accuracy": 0.03125, "time_ms": 550, "memory_kb": 3076, "score_of_the_acc": -1, "final_rank": 2 }, { "submission_id": "aoj_0360_9615796", "code_snippet": "#include<bits/stdc++.h>\n#include <iostream>\nusing namespace std;\nint main(void){\n\tint a,b,n,s[101],f[101],cnt=0;\n\tcin>>a>>b>>n;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>s[i];\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tcin>>f[i];\n\t}\n\tfor(int i=a+1;i<b;i++){\n\t\tfor(int j=s[i];j<f[i];j++){\n\t\t\tif(i==j){\n\t\t\t\tcnt++;\n\t\t\t\tbreak;\n\t\t}\n\t\t}\n\t}\n\tcout<<cnt<<endl;\n\treturn 0;\n}", "accuracy": 0.03125, "time_ms": 370, "memory_kb": 3116, "score_of_the_acc": -1.28, "final_rank": 3 }, { "submission_id": "aoj_0360_9615771", "code_snippet": "#include<bits/stdc++.h>\n#include <iostream>\nusing namespace std;\nint main(void){\n\tint a,b,n,s[101],f[101],cnt=0;\n\tcin>>a>>b>>n;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>s[i];\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tcin>>f[i];\n\t}\n\tfor(int i=a+1;i<b;i++){\n\t\tfor(int j=s[i];j<f[i];j++){\n\t\t\tif(i==j){\n\t\t\t\tcnt++;\n\t\t}\n\t\t}\n\t}\n\tif(cnt>=1){\n\t\tcout<<1<<endl;\n\t}\n\telse {\n\t\tcout<<0<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.03125, "time_ms": 300, "memory_kb": 3112, "score_of_the_acc": -0.9, "final_rank": 1 } ]
aoj_0352_cpp
勢力の予想 信夫くんと静夫くんは長方形の島で領地を取り合うゲームをしています。下の図①のように、島全体は格子状に区切られた正方形の区画でできており、区画にはそこから生じる損得が整数で示されています。 このゲームでは1つの駒を動かして領地の境界線を決めていきます。ゲーム開始時、駒は島の北西端にあります(図①)。この駒を島の南東端まで動かしていったときの駒の軌跡が領地の境界線となります。二人のプレーヤーは交互に駒を動かします。駒は南隣の格子点か東隣の格子点にのみ動かすことができます(図②)。駒が島の端に到達した場合は、南か東のうち動かせる方向に動かします。駒が南東端に到達したらゲーム終了です。 ゲーム終了後の境界線から北東側の領域が先攻プレーヤーの領域、南西側の領域が後攻プレーヤーの領 域です(図③)。各プレーヤーの領域内に含まれる、区画から生じる損得の合計がそのプレーヤーのス コアとなります。二人ともゲームにはかなり慣れており、最終的に自分のスコアから相手のスコアをひ いた値が一番大きくなるように正確に駒を動かします。 島の大きさとそれぞれの区画から生じる損得が与えられたとき、ゲーム終了時の結果を計算するプログラムを作成せよ。結果は、信夫くんと静夫くんのスコアの差の絶対値とする。 Input 入力は以下の形式で与えられる。 W H s 1,1 s 1,2 ... s 1,W s 2,1 s 2,2 ... s 2,W : s H,1 s H,2 ... s H,W 1行目に島に含まれる東西方向と南北方向の区画の数 W , H (1 ≤ W , H ≤ 1000) が与えられる。続く H 行に i 行 j 列目の区画から生じる損得 s i,j (-1000 ≤ s i,j ≤ 1000) が与えられる。ただし、 i の値が増加する方向を南、 j の値が増加する方向を東とする。 Output 信夫くんと静夫くんのスコアの差の絶対値を1行に出力する。 Sample Input 1 2 1 -2 1 Sample Output 1 1 Sample Input 2 2 2 2 -3 3 -1 Sample Output 2 3 Sample Input 3 5 4 5 3 2 -5 2 2 -4 2 8 -4 2 3 -7 6 7 3 -4 10 -3 -3 Sample Output 3 5
[ { "submission_id": "aoj_0352_11017206", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int H,W;\n cin>>W>>H;\n vector<vector<int>> A(H,vector<int>(W));\n vector<vector<int>> R(H+1,vector<int>(W));\n for(int i=0;i<H;i++)for(int j=0;j<W;j++) cin>>A[i][j];\n for(int i=0;i<H;i++)for(int j=0;j<W;j++) R[i+1][j] += R[i][j]+A[i][j];\n int ans = 0;\n map<pair<int,int>,int> m;\n auto f = [&](auto &&self, int a, int b) -> int {\n if(m.count({a,b})) return m[{a,b}];\n if(b == W) return 0;\n int p = (a+b)%2;\n if(p == 0){\n int ans = -1e18;\n ans = max(ans,self(self,a,b+1)-R[H][b]+2*R[a][b]);\n if(a != H) ans = max(ans,self(self,a+1,b));\n return m[{a,b}] = ans;\n }\n if(p == 1){\n int ans = 1e18;\n ans = min(ans,self(self,a,b+1)-R[H][b]+2*R[a][b]);\n if(a != H) ans = min(ans,self(self,a+1,b));\n return m[{a,b}] = ans;\n }\n return 0;\n };\n cout<<abs(f(f,0,0))<<endl;\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 81768, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0352_10851252", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <vector>\n#define int long long\nusing namespace std;\n\nint w, h;\nint rs[1001][1001];\nbool calced[1001][1001];\nint dp[1001][1001];\n\n//[lx, rx), [ly, ry)\nint getSum(int ly, int lx, int ry, int rx) {\n\treturn rs[ry][rx] - rs[ry][lx] - rs[ly][rx] + rs[ly][lx];\n}\n\n//駒が(y, x)にある状態からスタートしたときに、駒が(0, 0)にあるときに先手だった人が得られるスコア(先手領地 - 後手領地).\nint dfs(int y, int x) {\n\tif (y == h && x == w) { return 0; }\n\tif (calced[y][x]) return dp[y][x];\n\t\n\tvector<int> res;\n\t\n\tif (y < h) {\n\t\tres.push_back(getSum(y, x, y + 1, w) + dfs(y + 1, x));\n\t}\n\tif (x < w) {\n\t\tres.push_back(-getSum(y, x, h, x + 1) + dfs(y, x + 1));\n\t}\n\t\n\tint ret;\n\tif (res.size() == 1) ret = res[0];\n\telse if ((y + x) % 2 == 0) ret = max(res[0], res[1]);\n\telse ret = min(res[0], res[1]);\n\t\n\tcalced[y][x] = true;\n\treturn dp[y][x] = ret;\n}\n\nsigned main() {\n\tint i, j;\n\t\n\tcin >> w >> h;\n\tfor (i = 1; i <= h; i++) for (j = 1; j <= w; j++) cin >> rs[i][j];\n\tfor (i = 1; i <= h; i++) for (j = 1; j <= w; j++) rs[i][j] += rs[i][j - 1];\n\tfor (j = 1; j <= w; j++) for (i = 1; i <= h; i++) rs[i][j] += rs[i - 1][j];\n\tcout << abs(dfs(0, 0)) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 20180, "score_of_the_acc": -0.4124, "final_rank": 11 }, { "submission_id": "aoj_0352_7855818", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint func(){\n int w;\n int h;\n cin >> w >> h;\n vector<vector<int>> table(h,vector<int>(w));\n vector<vector<int>> sums(h+1,vector<int>(w+1,0));\n vector<vector<int>> rows(h+1,vector<int>(w+1,0));\n for(auto &i:table)for(auto &j:i)cin >> j;\n for(int i=0;i<h;++i){\n for(int j=0;j<w;++j){\n sums[i+1][j+1] = table[i][j];\n }\n }\n for(int i=0;i<h+1;++i){\n for(int j=0;j<w;++j){\n sums[i][j+1] += sums[i][j];\n }\n }\n rows = sums;\n for(int i=0;i<h;++i){\n for(int j=0;j<w+1;++j){\n sums[i+1][j] += sums[i][j];\n }\n }\n vector<vector<int>> dp(h,vector<int>(w,0));\n vector<vector<int>> used(h,vector<int>(w,false));\n function<int(int,int,int)> rec = [&](int y,int x,int turn_a) -> int{\n if(y == h){\n return 0;\n }\n if(x == w){\n int v = sums[h][w] - sums[y][w];\n if(turn_a){\n v = -v;\n }\n return v;\n }\n int &it = dp[y][x];\n if(used[y][x])return it;\n used[y][x] = true;\n it = -1e9;\n it = max(it, -rec(y,x+1,not turn_a));\n int left = rows[y+1][x];\n int right = rows[y+1][w] - left;\n int add = left - right;\n if(turn_a)add = -add;\n it = max(it, -rec(y+1,x,not turn_a) + add);\n return it;\n };\n return abs(rec(0,0,true));\n}\n\nint main(){\n cout << func() << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 23152, "score_of_the_acc": -0.4142, "final_rank": 12 }, { "submission_id": "aoj_0352_7054498", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\nusing P=pair<ll,int>;\nconstexpr int inf=1e9+10;\n\n#define rep(i,n) for(int i=0;i<int(n);i++)\n#define rep2(i,s,n) for(int i=int(s);i<int(n);i++)\n\ntemplate<typename T>\nbool chmax(T &a,T b){\n return (a<b ? a=b,true:false);\n}\ntemplate<typename T>\nbool chmin(T &a,T b){\n return (a>b ? a=b,true:false);\n}\n\nstruct Q{\n ll a,b;\n Q(ll x,ll y):a(x),b(y){\n ll g=__gcd(a,b);\n a/=g,b/=g;\n }\n Q operator+=(const Q r){\n return (*this)=(*this)+r;\n }\n friend Q operator+(const Q l,const Q r){\n return Q(l.a*r.b+r.a*l.b,l.b*r.b);\n }\n friend Q operator*(const Q l,const Q r){\n return Q(l.a*r.a,l.b*r.b);\n }\n friend ostream& operator<<(ostream &os,Q x){\n os << x.a << '/' << x.b;\n return os;\n }\n};\nll pow(int a,int b){\n ll ans=1;\n rep(i,b)ans*=a;\n return ans;\n}\n\n\nint main(){\n cout << fixed << setprecision(20);\n int w,h;\n cin >> w >> h;\n vector<vector<ll>> s(h,vector<ll>(w));\n rep(i,h)rep(j,w)cin >> s[i][j];\n vector<vector<ll>> sum(h+1,vector<ll>(w+1));\n rep(i,h)rep(j,w)sum[i+1][j+1]=s[i][j];\n rep(i,h+1)rep(j,w)sum[i][j+1]+=sum[i][j];\n rep(i,h)rep(j,w+1)sum[i+1][j]+=sum[i][j];\n auto getsum=[&](int li,int lj,int ri,int rj){\n return sum[ri][rj]+sum[li][lj]-sum[ri][lj]-sum[li][rj];\n };\n\n vector<vector<ll>> dp(h+1,vector<ll>(w+1,-inf));\n for(int i=h;i>=0;i--)for(int j=w;j>=0;j--){\n bool sen=(i+j+1)%2;\n if(i==h && j==w)dp[i][j]=0;\n else if(i==h){\n dp[i][j]=getsum(0,j,h,j+1)*(sen ? 1:-1)-dp[i][j+1];\n }\n else if(j==w){\n dp[i][j]=getsum(i,0,i+1,w)*(sen ? -1:1)-dp[i+1][j];\n }\n else{\n chmax(dp[i][j],getsum(0,j,i,j+1)*(sen ? 1:-1)-dp[i][j+1]);\n chmax(dp[i][j],getsum(i,0,i+1,j)*(sen ? -1:1)-dp[i+1][j]);\n }\n }\n cout << abs(dp[0][0]) << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 26540, "score_of_the_acc": -0.422, "final_rank": 13 }, { "submission_id": "aoj_0352_6969821", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0352.cc: 勢力の予想 \n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_H = 1000;\nconst int MAX_W = 1000;\nconst int INF = (1 << 30) - 1;\n\n/* typedef */\n\n/* global variables */\n\nint ass[MAX_H + 1][MAX_W + 1], dp[MAX_H + 1][MAX_W + 1];\n\n/* subroutines */\n\ninline int rect(int i0, int j0, int i1, int j1) {\n return ass[i1][j1] - ass[i1][j0] - ass[i0][j1] + ass[i0][j0];\n}\n\ninline void setmin(int &a, int b) { if (a > b) a = b; }\ninline void setmax(int &a, int b) { if (a < b) a = b; }\n\n/* main */\n\nint main() {\n int w, h;\n scanf(\"%d%d\", &w, &h);\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) {\n int aij;\n scanf(\"%d\", &aij);\n ass[i + 1][j + 1] = aij + ass[i + 1][j] + ass[i][j + 1] - ass[i][j];\n }\n\n for (int i = h; i >= 0; i--)\n for (int j = w; j >= 0; j--) {\n if (i == h && j == w) { dp[i][j] = 0; continue; }\n\n if (! ((i + j) & 1)) { // First\n\tdp[i][j] = -INF;\n\tif (i < h)\n\t setmax(dp[i][j], dp[i + 1][j] + rect(i, j, i + 1, w));\n\tif (j < w)\n\t setmax(dp[i][j], dp[i][j + 1] - rect(i, j, h, j + 1));\n }\n else { // Second\n\tdp[i][j] = INF;\n\tif (i < h)\n\t setmin(dp[i][j], dp[i + 1][j] + rect(i, j, i + 1, w));\n\tif (j < w)\n\t setmin(dp[i][j], dp[i][j + 1] - rect(i, j, h, j + 1));\n }\n }\n\n printf(\"%d\\n\", abs(dp[0][0]));\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 10784, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0352_6022610", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#define LL int\n#define LL long long\n#define PA pair<LL,LL>\n#define VE vector\n#define VL VE<LL>\n#define VVL VE<VL>\n#define VP VE<PA>\n#define PB push_back\n#define MP make_pair\n#define PQ priority_queue\n#define FI first\n#define SE second\n#define rep(i,n) for(int i=0;i<n;i++)\n#define INF 1000000000000000003\n//#define INF 1000000003\n\ntemplate<typename T>bool chmax(T &a,T b){\n if(a<b){\n a=b;\n return 1;\n }\n return 0;\n}\ntemplate<typename T>bool chmin(T &a,T b){\n if(a>b){\n a=b;\n return 1;\n }\n return 0;\n}\n\n/*typedef struct{\n VP t;LL f,c,n;\n}Node;\n\nstruct Dijkstra{\n VE<Node> node;\n Dijkstra(LL n){\n node.resize(n);\n rep(i,n)node[i].n=i,node[i].f=-1,node[i].c=INF;\n }\n void add(LL s,LL e,LL c){\n node[s].t.PB(MP(c,e));\n }\n void run(LL s=0,LL c=0){\n LL i;\n PQ<PA,VP,greater<PA>> pq;\n node[s].c=c;\n pq.push(MP(c,s));\n while(pq.size()){\n PA now=pq.top();\n pq.pop();\n LL nowc=now.FI,nown=now.SE;\n if(nowc>node[nown].c)continue;\n for(auto ne:node[nown].t){\n LL nec=nowc+ne.FI,nen=ne.SE;\n if(chmin(node[nen].c,nec))pq.push(MP(nec,nen)),node[nen].f=nown;\n }\n }\n }\n};*/\n\nint main(){\n LL W,H;\n LL sum=0;\n cin>>W>>H;\n VVL s(H,VL(W));\n rep(i,H)rep(j,W){\n cin>>s[i][j];\n sum+=s[i][j];\n }\n VVL S(H,VL(W+1)),dp(W+1,VL(H+1));\n rep(i,H)rep(j,W)S[i][j+1]=S[i][j]+s[i][j];\n for(int i=W;i>=0;i--)for(int j=H;j>=0;j--){\n if(i==W&&j==H)continue;\n if(i==W)dp[i][j]=dp[i][j+1]+S[j][W]-S[j][i];\n else if(j==H)dp[i][j]=dp[i+1][j];\n else{\n if((i+j)&1)dp[i][j]=min(dp[i][j+1]+S[j][W]-S[j][i],dp[i+1][j]);\n else dp[i][j]=max(dp[i][j+1]+S[j][W]-S[j][i],dp[i+1][j]);\n }\n }\n LL A=dp[0][0],B=sum-A;\n cout<<abs(A-B)<<endl;\n /*rep(i,H+1){\n rep(j,W+1)cout<<dp[j][i]<<\" \";\n cout<<endl;\n }*/\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 26564, "score_of_the_acc": -0.4223, "final_rank": 14 }, { "submission_id": "aoj_0352_5958410", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1000000000;\nint main(){\n int W, H;\n cin >> W >> H;\n vector<vector<int>> s(H, vector<int>(W));\n for (int i = 0; i < H; i++){\n for (int j = 0; j < W; j++){\n cin >> s[i][j];\n }\n }\n vector<vector<int>> sh(H, vector<int>(W + 1));\n for (int i = 0; i < H; i++){\n sh[i][W] = 0;\n for (int j = W - 1; j >= 0; j--){\n sh[i][j] = sh[i][j + 1] + s[i][j];\n }\n }\n vector<vector<int>> sv(H + 1, vector<int>(W));\n for (int i = 0; i < W; i++){\n sv[H][i] = 0;\n for (int j = H - 1; j >= 0; j--){\n sv[j][i] = sv[j + 1][i] + s[j][i];\n }\n }\n vector<vector<int>> dp(H + 1, vector<int>(W + 1, -INF));\n dp[H][W] = 0;\n for (int i = H; i >= 0; i--){\n for (int j = W; j >= 0; j--){\n if (i < H){\n if ((i + j) % 2 == 0){\n dp[i][j] = max(dp[i][j], sh[i][j] - dp[i + 1][j]);\n } else {\n dp[i][j] = max(dp[i][j], -sh[i][j] - dp[i + 1][j]);\n }\n }\n if (j < W){\n if ((i + j) % 2 == 1){\n dp[i][j] = max(dp[i][j], sv[i][j] - dp[i][j + 1]);\n } else {\n dp[i][j] = max(dp[i][j], -sv[i][j] - dp[i][j + 1]);\n }\n }\n }\n }\n cout << abs(dp[0][0]) << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 19140, "score_of_the_acc": -0.3177, "final_rank": 8 }, { "submission_id": "aoj_0352_5026048", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint H,W;\nint S[1010][1010];\nint dp[1010][1010];\nmain()\n{\n\tcin>>W>>H;\n\tfor(int i=0;i<H;i++)\n\t{\n\t\tfor(int j=0;j<W;j++)\n\t\t{\n\t\t\tcin>>S[i][j+1];\n\t\t\tS[i][j+1]+=S[i][j];\n\t\t}\n\t}\n\tfor(int i=H;i--;)for(int j=W;j>=0;j--)\n\t{\n\t\tint L=-2e9,R=-2e9;\n\t\tL=(S[i][W]-S[i][j]*2)*((i+j)%2==0?1:-1)-dp[i+1][j];\n\t\tif(j<W)R=-dp[i][j+1];\n\t\tdp[i][j]=max(L,R);\n\t}\n\tcout<<abs(dp[0][0])<<endl;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 10984, "score_of_the_acc": -0.2828, "final_rank": 7 }, { "submission_id": "aoj_0352_4973796", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\nint H,W;\nint G[1000][1000];\nint S[1001][1001];\n\nint dp[1001][1001];\n\nint range_sum(int l,int r,int t,int b){\n return S[l][t] - S[l][b] - S[r][t] + S[r][b];\n}\n\nint main(){\n cin>>W>>H;\n rep(y,H) rep(x,W) cin>>G[x][y];\n\n rep(x,W+1) rep(y,H+1) S[x][y]=0;\n rep(x,W) rep(y,H) S[x+1][y+1]=G[x][y];\n rep(x,W+1) rep(y,H) S[x][y+1]+=S[x][y];\n rep(x,W) rep(y,H+1) S[x+1][y]+=S[x][y];\n\n rep(x,W) rep(y,H) dp[x][y]=0;\n for(int x=W-1; x>=0; x--) for(int y=H-1; y>=0; y--){\n int plan_a = dp[x+1][y] - range_sum(x,x+1,y,H);\n int plan_b = dp[x][y+1] + range_sum(x,W,y,y+1);\n if((x+y)%2==0) dp[x][y]=max(plan_a,plan_b);\n else dp[x][y]=min(plan_a,plan_b);\n }\n\n cout<<abs(dp[0][0])<<endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 14816, "score_of_the_acc": -0.3368, "final_rank": 9 }, { "submission_id": "aoj_0352_4631374", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int h, w;\n cin >> w >> h;\n auto S = make_v(h+1, w, 0);\n auto T = make_v(h, w+1, 0);\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n scanf(\"%d\", &S[i][j]);\n T[i][j] = S[i][j];\n }\n }\n for (int i = h-1; i >= 0; --i) {\n for (int j = w-1; j >= 0; --j) {\n S[i][j] += S[i+1][j];\n T[i][j] += T[i][j+1];\n }\n }\n auto dp = make_v(h+1, w+1, -INF<int>);\n dp.back().back() = 0;\n for (int i = h; i >= 0; --i) {\n for (int j = w; j >= 0; --j) {\n if((i+j)&1){\n if(i) chmax(dp[i-1][j], -dp[i][j]+T[i-1][j]);\n if(j) chmax(dp[i][j-1], -dp[i][j]-S[i][j-1]);\n }else {\n if(i) chmax(dp[i-1][j], -dp[i][j]-T[i-1][j]);\n if(j) chmax(dp[i][j-1], -dp[i][j]+S[i][j-1]);\n }\n }\n }\n cout << abs(dp[0][0]) << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 14832, "score_of_the_acc": -0.077, "final_rank": 3 }, { "submission_id": "aoj_0352_4549620", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nint dp[1005][1005],t[1005][1005],T,a,m,n,o;\nint dq(int x,int y)\n{\n if (x==m && y==n)\n return 0;\n if (dp[x][y]!=o)\n return dp[x][y];\n\n vector<int> v;\n\n if (x<m)\n v.push_back(dq(x+1,y));\n if (y<n)\n v.push_back(dq(x,y+1)+t[x][y+1]-(t[m][y+1]-t[x][y+1]));\n\n int h=(x+y)%2,kq;\n if (h==0)\n {\n kq=-o;\n for (int i=0; i<v.size(); ++i)\n kq=max(kq,v[i]);\n }\n else\n {\n kq=o;\n for (int i=0; i<v.size(); ++i)\n kq=min(kq,v[i]);\n\n }\n return dp[x][y]=kq;\n\n}\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n cin>>n>>m;\n for (int i=1; i<=m; ++i)\n for (int j=1; j<=n; ++j)\n {\n cin>>a;\n t[i][j]=t[i-1][j]+a;\n T+=a;\n }\n o=2000000000;\n for (int i=0; i<=m; ++i)\n for (int j=0; j<=n; ++j)\n dp[i][j]=o;\n a=(dq(0,0));\n if (a<0)a=-a;\n cout<<a<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 11252, "score_of_the_acc": -0.1266, "final_rank": 5 }, { "submission_id": "aoj_0352_3978225", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nll W,H;\nll s[1003][1003];\n\nll memo[1003][1003];\nll dp[1003][1003];\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> W >> H;\n\n for (int i = 0;i < H;i++){\n for (int j = 0;j < W;j++){\n cin >> s[i][j];\n }\n }\n\n for (int i = 0;i < H;i++){\n ll sum = 0;\n for (int j = 0;j < W;j++){\n sum += s[i][j];\n }\n ll tmp = 0;\n for (int j = 0;j <= W;j++){\n memo[i][j] = tmp-(sum-tmp);\n if((i+j)%2 == 0){\n memo[i][j] *= -1;\n }\n if(j != W) tmp += s[i][j];\n }\n }\n\n for (int i = H;i >= 0;i--){\n for (int j = W;j >= 0;j--){\n if(i == H) dp[i][j] = 0;\n else if(j == W) dp[i][j] = memo[i][j]-dp[i+1][j];\n else dp[i][j] = max(-dp[i][j+1],memo[i][j]-dp[i+1][j]);\n }\n }\n\n cout << abs(dp[0][0]) << endl;\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 26668, "score_of_the_acc": -0.2238, "final_rank": 6 }, { "submission_id": "aoj_0352_3968333", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nusing int64 = long long;\nusing i64 = int64;\n\nconst int inf = 1<<30;\nconst int64 inf64 = 1ll<<60;\n\n#define rep(i,N) for(int i=0; i<(int)N; ++i)\n\nint64 dp[1001][1001];\nint s[1001][1001];\ni64 sumh[1001][1001], sumw[1001][1001];\n\nsigned main() {\n\tint W, H; cin >> W >> H;\n\trep(i, H) rep(j, W) cin >> s[i][j];\n\t\n\trep(i, H) {\n\t\tsumh[i][0] = s[i][0];\n\t\tfor(int j=1; j<W; ++j) sumh[i][j] += sumh[i][j-1] + s[i][j];\n\t}\n\trep(j, W) {\n\t\tsumw[0][j] = s[0][j];\n\t\tfor(int i=1; i<H; ++i) sumw[i][j] += sumw[i-1][j] + s[i][j];\n\t}\n\t\n\tdp[H-1][W-1] = 0;\n\tfor(int i=H; i>=0; --i) {\n\t\tfor(int j=W; j>=0; --j) {\n\t\t\tif(i == H && j == W) continue;\n\t\t\t\n\t\t\ti64 n1 = inf64;\n\t\t\tif(i + 1 <= H) {\n\t\t\t\tif(j != 0) n1 = dp[i+1][j] + (sumh[i][W-1] - sumh[i][j-1]);\n\t\t\t\telse n1 = dp[i+1][j] + sumh[i][W-1];\n\t\t\t}\n\t\t\t\n\t\t\ti64 n2 = inf64;\n\t\t\tif(j + 1 <= W) {\n\t\t\t\tif(i != 0) n2 = dp[i][j+1] - (sumw[H-1][j] - sumw[i-1][j]);\n\t\t\t\telse n2 = dp[i][j+1] - sumw[H-1][j];\n\t\t\t}\n\t\t\t\n\t\t\tif((i + j) % 2 == 0) {\n\t\t\t\tif(n1 == inf64) dp[i][j] = n2;\n\t\t\t\telse if(n2 == inf64) dp[i][j] = n1;\n\t\t\t\telse dp[i][j] = max({ n1, n2});\n\t\t\t}\n\t\t\telse {\n\t\t\t\tdp[i][j] = min({n1, n2});\n\t\t\t}\n\t\t}\n\t}\n\t\n\t/*\n\trep(i, H + 1) {\n\t\trep(j, W + 1) cout << dp[i][j] << \" \";\n\t\tcout << endl;\n\t}*/\n\t\n\t\n\tcout << abs(dp[0][0]) << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 30472, "score_of_the_acc": -0.5974, "final_rank": 18 }, { "submission_id": "aoj_0352_3943921", "code_snippet": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<math.h>\nusing namespace std;\ntypedef long long ll;\n#define int long long\ntypedef vector<int> VI;\ntypedef pair<int, int> pii;\n#define fore(i,a) for(auto &i:a)\n#define REP(i,n) for(int i=0;i<n;i++)\n#define eREP(i,n) for(int i=0;i<=n;i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define eFOR(i,a,b) for(int i=(a);i<=(b);++i)\n#define SORT(c) sort((c).begin(),(c).end())\n#define rSORT(c) sort((c).rbegin(),(c).rend())\n#define LB(x,a) lower_bound((x).begin(),(x).end(),(a))\n#define UB(x,a) upper_bound((x).begin(),(x).end(),(a))\n#define INF 1000000000\n#define LLINF 9223372036854775807\n#define mod 1000000007\n//vector<vector<int> > dp;\n//vector<vector<vector<int> > > vvvi;\n//dp=vector<vector<int> >(N, vector<int>(M,0));\n//vector<pair<int,int> > v;\n//v.push_back(make_pair(x,y));\n//priority_queue<int,vector<int>, greater<int> > q2;\nint W, H;\nint s[1010][1010] = { 0 };\n\nint score(int i, int j) {\n\tif ((i + j) % 2 == 0)return (s[i + 1][W] - s[i + 1][j]) - s[i + 1][j];\n\treturn s[i + 1][j] - (s[i + 1][W] - s[i + 1][j]);\n}\n\nsigned main(){\ncin.tie(0);\nios::sync_with_stdio(false);\n\n\tint dp[1010][1010];\n\tcin >> W >> H;\n\teFOR(i,1, H) {\n\t\teFOR(j,1, W) {\n\t\t\tcin >> s[i][j];\n\t\t\ts[i][j] += s[i][j - 1];\n\t\t}\n\t}\n\t\n\tfor (int i = H; i >= 0; i--) {\n\t\tfor (int j = W; j >= 0; j--) {\n\t\t\tif (i == H)dp[i][j] = 0;\n\t\t\telse if (j == W)dp[i][j] = score(i, j) - dp[i + 1][j];\n\t\t\telse dp[i][j] = max(-dp[i][j + 1], score(i, j) - dp[i + 1][j]);\n\t\t}\n\t}\n\tcout << abs(dp[0][0]) << endl;\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 18956, "score_of_the_acc": -0.1151, "final_rank": 4 }, { "submission_id": "aoj_0352_3899023", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set>\nusing namespace std;\n//int p = 998244353;\nint p = 1000000007;\n#define int long long\n#define vel vector<long long>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\nint max_kai = 150000;\nvel kai(max_kai, 1);\nvel inv_kai;\nint rui(int a, int n) {\n\tif (n == 0) { return 1; }\n\tint x = rui(a, n / 2);\n\tx *= x; x %= p;\n\tif (n % 2 == 1) { x *= a; x %= p; }\n\treturn x;\n}\nint inv(int a) { return rui(a, p - 2); }\nvoid make_kai() {\n\tfor (int i = 1; i < max_kai; i++) { kai[i] = kai[i - 1] * i; kai[i] %= p; }\n\tinv_kai = kai;\n\trep(i, max_kai) { inv_kai[i] = inv(kai[i]); }\n}\nint nCr(int n, int r) {\n\tint a = kai[n] * inv_kai[r]; a %= p;\n\ta *= inv_kai[n - r]; a %= p;\n\treturn a;\n}\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) {pa[x] = y;}\n}\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)-h.begin()\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)-h.begin()\nint num_lp(int a, vel &nex) {\n\tunordered_set<int> se;\n\tint ans = 0;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {\n\t\t\tbreak;\n\t\t}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t\tans++;\n\t}\n\treturn ans;\n}\nint find_cr(int a, vel &nex) {\n\tunordered_set<int> se;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {break;}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t}\n\treturn num_lp(a, nex);\n}\nint inf = 2000000000;\nvvel dp;\nint solve(vvel &sum, int i, int j, bool is_f) {\n\tint h = sum.size(); h--;\n\tint w = sum[0].size();\n\tif (i == h || j == w) { return 0; }\n\tif (dp[i][j] == inf) {\n\t\tint ans1 = solve(sum, i + 1, j, !is_f);\n\t\tint ans2 = solve(sum, i, j + 1, !is_f);\n\t\tans2 += sum[i][j];\n\t\tif (is_f) {\n\t\t\tdp[i][j] = min(ans1, ans2);\n\t\t}\n\t\telse {\n\t\t\tdp[i][j] = max(ans1, ans2);\n\t\t}\n\t}\n\treturn dp[i][j];\n}\nsigned main(){\n\tint w, h; cin >> w >> h;\n\tvvel s(h, vel(w));\n\tint sum1 = 0;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tcin >> s[i][j];\n\t\t\tsum1 += s[i][j];\n\t\t}\n\t}\n\tvvel sum(h + 1, vel(w, 0));\n\tdp = vvel(h + 1, vel(w +1,inf));\n\trep(j, w) {\n\t\tfor (int i = h - 1; i >= 0; i--) {\n\t\t\tsum[i][j] = sum[i + 1][j] + s[i][j];\n\t\t}\n\t}\n\tcout << abs(solve(sum, 0, 0, true)*2-sum1) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 27620, "score_of_the_acc": -0.5572, "final_rank": 17 }, { "submission_id": "aoj_0352_3855105", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i64 = long long;\n#define rep(i,s,e) for(i64 (i) = (s);(i) < (e);(i)++)\n#define all(x) x.begin(),x.end()\n#define let auto const\n\ntemplate<typename... Types>\nstruct dynarr: std::vector<Types...> {\n using std::vector<Types...>::vector;\n using size_type = typename std::vector<Types...>::size_type;\n auto&& operator[](size_type i) { return this->at(i); }\n auto&& operator[](size_type i) const { return this->at(i); }\n};\n\nint main() {\n i64 W, H;\n cin >> W >> H;\n dynarr<dynarr<i64>> s(H, dynarr<i64>(W));\n rep(i,0,H) rep(j,0,W) cin >> s[i][j];\n dynarr<dynarr<i64>> Hsum(H + 1, dynarr<i64>(W));\n dynarr<dynarr<i64>> Wsum(H, dynarr<i64>(W + 1));\n rep(j,0,W) rep(i,0,H) {\n Hsum[i + 1][j] = Hsum[i][j] + s[i][j];\n }\n rep(i,0,H) rep(j,0,W) {\n Wsum[i][j + 1] = Wsum[i][j] + s[i][j];\n }\n dynarr<dynarr<i64>> dp(H + 1, dynarr<i64>(W + 1));\n dp[H][W] = 0;\n for(int i = H; i >= 0; i--) {\n for(int j = W;j >= 0;j--) {\n if(i == H && j == W) continue;\n if((i + j) % 2 == 0) {\n dp[i][j] = -1e18;\n // left ... +\n if(j + 1 <= W) {\n dp[i][j] = max(dp[i][j], dp[i][j + 1] + Hsum[i][j]);\n }\n // up ... -\n if(i + 1 <= H) {\n dp[i][j] = max(dp[i][j], dp[i + 1][j] - Wsum[i][j]);\n }\n }\n else {\n dp[i][j] = 1e18;\n if(j + 1 <= W) {\n dp[i][j] = min(dp[i][j], dp[i][j + 1] + Hsum[i][j]);\n }\n // up ... +\n if(i + 1 <= H) {\n dp[i][j] = min(dp[i][j], dp[i + 1][j] - Wsum[i][j]);\n }\n }\n }\n }\n cout << abs(dp[0][0]) << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 34204, "score_of_the_acc": -0.6499, "final_rank": 19 }, { "submission_id": "aoj_0352_3850284", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing i64 = int64_t;\nconst i64 MOD = 1e9 + 7;\nconst i64 INF = i64(1e18) + 7;\n\nstruct RectangleSum{\n vector<vector<i64>> sum;\n i64 h, w;\n RectangleSum(vector<vector<i64>>& v) :\n h(v.size()),\n w(v[0].size())\n {\n sum.assign(h + 1, vector<i64>(w + 1, 0));\n for(i64 i = 0; i < h; ++i)\n for(i64 j = 0; j < w; ++j)\n sum[i + 1][j + 1] = v[i][j];\n\n for(i64 i = 0; i < h + 1; ++i)\n for(i64 j = 0; j < w; ++j)\n sum[i][j + 1] += sum[i][j];\n for(i64 j = 0; j < w + 1; ++j)\n for(i64 i = 0; i < h; ++i)\n sum[i + 1][j] += sum[i][j];\n }\n i64 getSum(i64 sx, i64 sy, i64 ex, i64 ey){\n return sum[ex][ey] + sum[sx][sy] - sum[sx][ey] - sum[ex][sy];\n }\n\n};\n\nsigned main(){\n i64 w, h;\n cin >> w >> h;\n vector<vector<i64>> v(h, vector<i64>(w));\n for(auto& x : v)\n for(auto& y : x)\n cin >> y;\n\n RectangleSum r(v);\n\n vector<vector<i64>> dp(h + 1, vector<i64>(w + 1, -INF));\n dp[h][w] = 0;\n function<i64(i64,i64)> f = [&](i64 x, i64 y){\n if(dp[x][y] != -INF)\n return dp[x][y];\n i64 res_1 = (x == h ? -INF : -f(x + 1, y) + ((x + y) % 2 == 1 ? 1 : -1) * r.getSum(x, 0, x + 1, y));\n i64 res_2 = (y == w ? -INF : -f(x, y + 1) + ((x + y) % 2 == 0 ? 1 : -1) * r.getSum(0, y, x, y + 1));\n return dp[x][y] = max(res_1, res_2);\n };\n f(0, 0);\n cout << abs(dp[0][0]) << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 26644, "score_of_the_acc": -0.5434, "final_rank": 16 }, { "submission_id": "aoj_0352_3720638", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\n#define int long long int\nconst int INF = 1001001001001001LL;\nconst int MOD = 1000000007;\n\n\nsigned main(){\n \n int h, w; cin >> w >> h;\n vector<vector<int>> s(h + 1, vector<int> (w + 1, 0));\n for(int i = 1; i <= h; i++) for(int j = 1; j <= w; j++) cin >> s[i][j];\n for(int i = 1; i <= h; i++) for(int j = 1; j <= w; j++) s[i][j] += s[i][j - 1];\n for(int j = 1; j <= w; j++) for(int i = 1; i <= h; i++) s[i][j] += s[i - 1][j];\n\n vector<vector<int>> dp(h + 1, vector<int> (w + 1, -1));\n for(int i = 0; i <= h; i++) dp[i][w] = 0;\n for(int j = 0; j <= w; j++) dp[h][j] = 0;\n\n for(int i = h - 1; i >= 0; i--){\n for(int j = w - 1; j >= 0; j--){\n \n int turn = (i + j) % 2;\n \n if(turn == 0){\n // 先手\n //スコアを最大化したい\n int score = max(dp[i + 1][j] + s[i + 1][w] - s[i + 1][j] - s[i][w] + s[i][j], dp[i][j + 1] - (s[h][j + 1] - s[h][j] - s[i][j + 1] + s[i][j]));\n dp[i][j] = score;\n }else{\n int score = min(dp[i + 1][j] + s[i + 1][w] - s[i + 1][j] - s[i][w] + s[i][j], dp[i][j + 1] - (s[h][j + 1] - s[h][j] - s[i][j + 1] + s[i][j]));\n dp[i][j] = score;\n }\n }\n }\n \n /*\n cout << h << \" \" << w << endl;\n for(int i = 0; i <= h; i++){\n for(int j = 0; j <= w; j++){\n cout << dp[i][j] << \" \";\n }\n cout << endl;\n }*/\n\n int ans = dp[0][0];\n if(ans < 0) ans = -ans;\n \n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 18736, "score_of_the_acc": -0.412, "final_rank": 10 }, { "submission_id": "aoj_0352_3720403", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cstdio>\nusing namespace std;\nusing int64 = long long int;\nconst int64 INF = 1LL << 60;\n\n// first - second\nint W, H; int64 dp[1010][1010];\nvector< vector<int> > rows;\nvector< vector<int> > cols;\n\nint64 solve(int r, int c) {\n // fprintf(stderr, \"r = %d, c = %d\\n\", r, c);\n int64 &res = dp[r][c];\n if(res != INF) return res;\n if(r == H and c == W) return res = 0;\n bool is_second = (r + c) % 2 == 1;\n \n res = (is_second ? INF : -INF);\n // second\n if(is_second) {\n if(r + 1 <= H) {\n int64 val = rows[r][W] - rows[r][c];\n int64 fs = solve(r+1, c);\n fs += val;\n res = min(res, fs);\n }\n if(c + 1 <= W) {\n int64 val = cols[c][H] - cols[c][r];\n int64 fs = solve(r, c+1);\n fs -= val;\n res = min(res, fs);\n }\n }\n // first\n else {\n if(r + 1 <= H) {\n int64 val = rows[r][W] - rows[r][c];\n int64 fs = solve(r+1, c);\n fs += val;\n res = max(res, fs);\n }\n if(c + 1 <= W) {\n int64 val = cols[c][H] - cols[c][r];\n int64 fs = solve(r, c+1);\n fs -= val;\n res = max(res, fs);\n }\n }\n return res;\n}\n\nint main() {\n cin >> W >> H;\n rows.resize(H);\n cols.resize(W);\n for(int i=0; i<H; i++) rows[i].emplace_back(0);\n for(int i=0; i<W; i++) cols[i].emplace_back(0);\n\n for(int i=0; i<H; i++) {\n for(int j=0; j<W; j++) {\n int val; cin >> val;\n rows[i].emplace_back(rows[i].back() + val);\n cols[j].emplace_back(cols[j].back() + val);\n }\n }\n\n fill(dp[0], dp[H+1], INF);\n cout << abs(solve(0, 0)) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 18980, "score_of_the_acc": -0.4355, "final_rank": 15 }, { "submission_id": "aoj_0352_3697332", "code_snippet": "#include<algorithm>\n#include<climits>\n#include<cmath>\n#include<cstring>\n#include<deque>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<queue>\n#include<set>\n#include<stack>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = int(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = int(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = int(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = int(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = int(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << endl\n\nconst int IINF = (1 << 30) - 1;\nconst long long LLINF = 1LL << 61;\nconst int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconst int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\nconst double EPS = 1e-8;\n\nint w, h;\nvector< vector<int> > s;\nvector< vector<int> > sum;\nint dp[1005][1005];\n\ntemplate<typename T>\nbool chmax(T &_a, T _b){\n if(_a < _b){\n _a = _b;\n return true;\n }else{\n return false;\n }\n}\n\ntemplate<typename T>\nbool chmin(T &_a, T _b){\n if(_a > _b){\n _a = _b;\n return true;\n }else{\n return false;\n }\n}\n\nint solve(int i, int j){\n if(dp[i][j] < IINF){\n return dp[i][j];\n }else if(i == h && j == w){\n return dp[i][j] = 0;\n }\n\n int res;\n if((i + j) % 2 == 0){\n res = -IINF;\n if(i + 1 <= h) chmax(res, solve(i + 1, j) + (sum[i + 1][w] - sum[i + 1][j] - sum[i][w] + sum[i][j]));\n if(j + 1 <= w) chmax(res, solve(i, j + 1) - (sum[h][j + 1] - sum[h][j] - sum[i][j + 1] + sum[i][j]));\n }else{\n res = IINF;\n if(i + 1 <= h) chmin(res, solve(i + 1, j) + (sum[i + 1][w] - sum[i + 1][j] - sum[i][w] + sum[i][j]));\n if(j + 1 <= w) chmin(res, solve(i, j + 1) - (sum[h][j + 1] - sum[h][j] - sum[i][j + 1] + sum[i][j]));\n }\n\n return dp[i][j] = res;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> w >> h;\n\n s.resize(h);\n sum.resize(h + 1);\n sum[0].resize(w + 1);\n rep(i, h){\n s[i].resize(w);\n sum[i + 1].resize(w + 1);\n rep(j, w){\n cin >> s[i][j];\n sum[i + 1][j + 1] = s[i][j];\n }\n }\n\n rep(i, h + 1){\n reps(j, w){\n sum[i][j] += sum[i][j - 1];\n }\n }\n\n rep(j, w + 1){\n reps(i, h){\n sum[i][j] += sum[i - 1][j];\n }\n }\n\n fill(dp[0], dp[1005], IINF);\n\n cout << abs(solve(0, 0)) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 14720, "score_of_the_acc": -0.0754, "final_rank": 2 } ]
aoj_0356_cpp
夕暮れ AIZU 国の夕暮れ時は、スマートフォンを西の空へ構えて立ち止まる観光客で賑わう。AIZU 国は無数のビルが建ち並ぶ大都市であり、ビルの谷間が長く連なる西の空には、ビルのシルエットとそれらから漏れ出す太陽の光による絶景が広がる。 AIZU 観光協会の若松氏によると、太陽を表す円が、その面積のちょうど半分だけ遮られているとき、格段の絶景になるという。 図のように、西の空を、地平線を x 軸、太陽の中心の軌跡を y 軸とするような x - y 平面で表し、太陽を半径 R の円、それぞれのビルのシルエットを長方形とする。 各ビルのシルエットの底辺は x 軸上にあり、太陽は十分高い位置から地平線に対して垂直に沈んでいく。太陽はビルのシルエットあるいは地平線を上端とする地面に遮られ、やがて地平線の下へ消えてゆく。 太陽の半径と各ビルのシルエットの情報が与えられたとき、太陽の面積のちょうど半分が遮られるような、最も高い太陽の高さ(中心の y 座標)を求めるプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N R x 1 w 1 h 1 x 2 w 2 h 2 : x N w N h N 1行目にビルの数 N (0 ≤ N ≤ 100) と太陽を表す円の半径 R (1 ≤ R ≤ 100) が与えられる。続く N 行に i 番目のビルのシルエットの左下角の x 座標 x i (-100 ≤ x i ≤ 100, x i < x i+1 )、幅 w i (1 ≤ w i ≤ 100)、高さ h i (1 ≤ h i ≤ 100) が与えられる。入力はすべて整数で与えられる。 入力は以下の条件を満たす。 ビルのシルエットが重なることはない( x i + w i ≤ x i+1 )。 2つの隣接するビルのシルエットの高さの差は、 R を超えない。 ビルの左側( x 軸の負の方向)または右側( x 軸の正の方向)に隣接するビルがない場合、その高さは R を超えない。 Output 太陽の高さ(円の中心の y 座標)を1行に出力する。ただし、誤差がプラスマイナス 10 -6 を超えてはならない。 Sample Input 1 0 2 Sample Output 1 0.00000000 Sample Input 2 3 2 -2 1 1 -1 1 2 0 2 1 Sample Output 2 1.25065774
[ { "submission_id": "aoj_0356_10203506", "code_snippet": "// AOJ #356\n// Evening 2025.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\nconst double eps = 1e-10;\nconst double PI = acos(-1.0);\n \ndouble groundIntersection(double Y, double R) {\n double circleArea = PI * R * R;\n if(Y >= R) return 0.0;\n if(Y <= -R) return circleArea;\n if(Y >= 0) {\n double theta = acos(Y / R);\n double segArea = R * R * theta - Y * sqrt(R * R - Y * Y);\n return segArea;\n } else {\n double d = -Y; // d>0\n double theta = acos(d / R);\n double capArea = R * R * theta - d * sqrt(R * R - d * d);\n return circleArea - capArea;\n }\n}\n \ndouble simpson_rule(function<double(double)> f, double a, double b) {\n double c = (a + b) * 0.5;\n return (b - a) / 6.0 * (f(a) + 4.0*f(c) + f(b));\n}\n \ndouble adaptiveSimpson(function<double(double)> f, double a, double b, double eps, double whole) {\n double c = (a+b)/2.0;\n double left = simpson_rule(f, a, c);\n double right = simpson_rule(f, c, b);\n if(fabs(left + right - whole) <= 15 * eps)\n return left + right + (left+right - whole) / 15.0;\n return adaptiveSimpson(f, a, c, eps/2, left) + adaptiveSimpson(f, c, b, eps/2, right);\n}\n \ndouble integrate(function<double(double)> f, double a, double b, double eps=1e-8) {\n double initial = simpson_rule(f, a, b);\n return adaptiveSimpson(f, a, b, eps, initial);\n}\n \ndouble buildingIntegrand(double x, double Y, double H, double R) {\n double under = R*R - x*x;\n if(under < 0) return 0.0;\n double t = sqrt(under);\n double lowCircle = Y - t;\n double highCircle = Y + t;\n double lowInt = max(0.0, lowCircle);\n double highInt = min(H, highCircle);\n double ret = highInt - lowInt;\n return (ret > 0 ? ret : 0.0);\n}\n \ndouble buildingIntersection(double Y, double X, double w, double H, double R) {\n double xLow = max(X, -R);\n double xHigh = min(X + w, R);\n if(xHigh <= xLow) return 0.0;\n auto f = [=](double x) {\n return buildingIntegrand(x, Y, H, R);\n };\n double area = integrate(f, xLow, xHigh, 1e-8);\n return area;\n}\n \nstruct Building {\n double x, w, h;\n};\n \ndouble totalOccludedArea(double Y, double R, const vector<Building>& buildings) {\n double area = 0.0;\n area += groundIntersection(Y, R);\n for (auto &b : buildings) {\n area += buildingIntersection(Y, b.x, b.w, b.h, R);\n }\n return area;\n}\n \nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);\n \n int N;\n double R;\n cin >> N >> R;\n vector<Building> buildings;\n for (int i = 0; i < N; i++){\n Building b;\n cin >> b.x >> b.w >> b.h;\n buildings.push_back(b);\n }\n \n double sunArea = PI * R * R;\n double target = sunArea / 2.0;\n \n double lo = -R, hi = R + 100.0;\n for(int iter = 0; iter < 100; iter++){\n double mid = (lo + hi) / 2.0;\n double occ = totalOccludedArea(mid, R, buildings);\n double diff = occ - target;\n if(diff > 0) lo = mid;\n else hi = mid;\n }\n double Y_ans = (lo + hi) / 2.0;\n if (fabs(Y_ans) <= eps) Y_ans = 0;\n cout << fixed << setprecision(10) << Y_ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3980, "score_of_the_acc": -1, "final_rank": 2 }, { "submission_id": "aoj_0356_6022594", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\nld u;\n\nint main(){\n int n, r; cin>>n>>r;\n u=(ld)r/500000.0;\n vector<ld> h(300);\n for(int i=0; i<n; i++){\n int x, w, H;cin>>x>>w>>H;\n for(int j=0; j<w; j++){\n h[x+105+j]=H;\n }\n }\n ld L=0, R=100;\n for(int _=0;_<30; _++){\n ld m=(L+R)/2.0;\n ld area=0;\n for(int i=-500000; i<500000; i++){\n ld x=(ld)r*i/500000.0;\n ld y=sqrt((ld)r*r-x*x)+sqrt((ld)r*r-(x+u)*(x+u)); y/=2.0;\n ld si=m-y, ue=m+y;\n ld mid=h[105+x];\n if(si<=mid&&mid<=ue) area+=(mid-si)*u;\n if(ue<mid) area+=(ue-si)*u;\n }\n if(area*2<(ld)r*r*3.1415926535897932) R=m;\n else L=m;\n }\n cout<<fixed<<setprecision(10)<<L<<endl;\n}", "accuracy": 0.23529411764705882, "time_ms": 280, "memory_kb": 3500, "score_of_the_acc": -0.8387, "final_rank": 5 }, { "submission_id": "aoj_0356_3240223", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <cmath>\nusing namespace std;\n\nconst long double PI = 3.14159265358979323L;\nint N, V, A[109], B[109], C[109], E[309];\n\nlong double calc_area(vector<pair<long double, long double>>X) {\n\tlong double G = 0;\n\tfor (int i = 0; i < X.size(); i++) {\n\t\tG += (X[i].first - X[(i + 1) % X.size()].first) * (X[i].second + X[(i + 1) % X.size()].second);\n\t}\n\treturn 0.5L * abs(G);\n}\n\nlong double calc_kakudo(long double x, long double y) {\n\tlong double L = 0, R = 180, M, HIRITSU = y * 1.0L / V;\n\tfor (int i = 0; i < 60; i++) {\n\t\tM = (L + R) / 2;\n\t\tlong double F = cos(M * PI / 180.0L);\n\t\tif (F > HIRITSU) L = M;\n\t\telse R = M;\n\t}\n\treturn M;\n}\n\nlong double calc_angle(long double T) {\n\tlong double E1 = 1.0L * V * V * T / 360.0L * PI;\n\tlong double E2 = 0.5L * sin(T * PI / 180.0L) * V * V;\n\treturn E1 - E2;\n}\n\nlong double calc(long double X, long double H) {\n\t// 円は (0, 0) を中心としてよい\n\tlong double Y1 = -sqrtl(V * V - X * X);\n\tlong double Y2 = -sqrtl(V * V - (X + 1) * (X + 1));\n\tlong double Y3 = sqrtl(V * V - (X + 1) * (X + 1));\n\tlong double Y4 = sqrtl(V * V - X * X);\n\n\tlong double rem = 0;\n\tif (H < Y1) {\n\t\tlong double D1 = calc_kakudo(X, Y1);\n\t\tlong double D2 = calc_kakudo(X + 1.0L, Y2);\n\t\trem += 2.0L * calc_angle(abs(D1 - D2));\n\n\t\tvector<pair<long double, long double>>T;\n\t\tT.push_back(make_pair(X, Y1));\n\t\tT.push_back(make_pair(X + 1.0L, Y2));\n\t\tT.push_back(make_pair(X + 1.0L, Y3));\n\t\tT.push_back(make_pair(X, Y4));\n\t\trem += calc_area(T);\n\t}\n\telse if (H < Y2) {\n\t\tlong double FE = sqrtl(V * V - H * H);\n\t\tlong double D1 = calc_kakudo(X, Y1);\n\t\tlong double D2 = calc_kakudo(X + 1.0L, Y2);\n\t\tlong double D3 = calc_kakudo(FE, H);\n\t\trem += 1.0L * calc_angle(abs(D1 - D2));\n\t\trem += 1.0L * calc_angle(abs(D2 - D3));\n\n\t\tvector<pair<long double, long double>>T;\n\t\tT.push_back(make_pair(X, H));\n\t\tT.push_back(make_pair(FE, H));\n\t\tT.push_back(make_pair(X + 1.0L, Y2));\n\t\tT.push_back(make_pair(X + 1.0L, Y3));\n\t\tT.push_back(make_pair(X, Y4));\n\t\trem += calc_area(T);\n\t}\n\telse if (H < Y3) {\n\t\tlong double D1 = calc_kakudo(X, Y1);\n\t\tlong double D2 = calc_kakudo(X + 1.0L, Y2);\n\t\trem += 1.0L * calc_angle(abs(D1 - D2));\n\n\t\tvector<pair<long double, long double>>T;\n\t\tT.push_back(make_pair(X, H));\n\t\tT.push_back(make_pair(X + 1.0L, H));\n\t\tT.push_back(make_pair(X + 1.0L, Y3));\n\t\tT.push_back(make_pair(X, Y4));\n\t\trem += calc_area(T);\n\t}\n\telse if (H < Y4) {\n\t\tlong double FE = sqrtl(V * V - H * H);\n\t\tlong double D1 = calc_kakudo(X, Y4);\n\t\tlong double D3 = calc_kakudo(FE, H);\n\t\trem += 1.0L * calc_angle(abs(D1 - D3));\n\n\t\tvector<pair<long double, long double>>T;\n\t\tT.push_back(make_pair(X, H));\n\t\tT.push_back(make_pair(FE, H));\n\t\tT.push_back(make_pair(X, Y4));\n\t\trem += calc_area(T);\n\t}\n\telse {\n\t\trem = 0;\n\t}\n\treturn rem;\n}\n\nlong double solve(long double res) {\n\tlong double ret = 0;\n\tfor (int i = -V; i <= V - 1; i++) {\n\t\tret += calc(min(abs(i), abs(i + 1)), 1.0L * E[100 + i] - res);\n\t}\n\treturn ret;\n}\n\nint main() {\n\tcin >> N >> V;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> A[i] >> B[i] >> C[i];\n\t\tfor (int j = A[i]; j < A[i] + B[i]; j++) E[100 + j] = max(E[100 + j], C[i]);\n\t}\n\tlong double L = 0, R = 100, M, GOAL = 0.5L * V * V * PI;\n\tfor (int i = 0; i < 100; i++) {\n\t\tM = (L + R) / 2;\n\t\tlong double ss = solve(M);\n\t\tif (ss < GOAL) L = M;\n\t\telse R = M;\n\t}\n\tprintf(\"%.12Lf\\n\", M);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3540, "score_of_the_acc": -1.0833, "final_rank": 4 }, { "submission_id": "aoj_0356_2186920", "code_snippet": "////////////////////\n// ???????????????\n#include<cmath>\n#include<algorithm>\n#include<cassert>\n////////////////////\n// ??¨????????¢???\nusing D = double;\n////////////////////\n// ?????°\nconst D EPS = 1e-9; // |EPS|???????????°???0??¨????????±???\nenum POSITION {ONLINE_FRONT = -2, CLOCKWISE, ON_SEGMENT, COUNTER_CLOCKWISE, ONLINE_BACK}; // 3??????????????¢???\n////////////////////\n// ?§???????\nstruct Point {\n D x, y;\n Point(const D d = 0.0) : x(d), y(d) {}\n Point(const D x, const D y) : x(x), y(y) {}\n};\nstruct Segment {\n Point initial, terminal;\n Segment(const Point& initial, const Point& terminal) : initial(initial), terminal(terminal) {}\n Segment(const D x1, const D y1, const D x2, const D y2) : initial(x1, y1), terminal(x2, y2) {}\n};\nstruct Line {\n Point initial, terminal;\n Line(const Point& initial, const Point& terminal) : initial(initial), terminal(terminal) {}\n Line(const D x1, const D y1, const D x2, const D y2) : initial(x1, y1), terminal(x2, y2) {}\n Line(const Segment& s) : initial(s.initial), terminal(s.terminal) {}\n};\n////////////////////\n// ????£?\nbool relative_equal(const D d1, const D d2) {return d1 == 0 ? std::abs(d2) < EPS : std::abs((d1 - d2) / d1) < EPS;}\n// ??????????????????????????????\nbool operator==(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) && relative_equal(lhs.y, rhs.y);}\nbool operator<(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y < rhs.y : lhs.x < rhs.x;}\nbool operator>(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y > rhs.y : lhs.x > rhs.x;}\nbool operator!=(const Point& lhs, const Point& rhs) {return !(lhs == rhs);}\nbool operator<=(const Point& lhs, const Point& rhs) {return !(lhs > rhs);}\nbool operator>=(const Point& lhs, const Point& rhs) {return !(lhs < rhs);}\nconst Point operator+(const Point& lhs, const Point& rhs) {return Point(lhs.x + rhs.x, lhs.y + rhs.y);}\nconst Point operator-(const Point& lhs, const Point& rhs) {return Point(lhs.x - rhs.x, lhs.y - rhs.y);}\nconst Point operator*(const Point& lhs, const Point& rhs) {return Point(lhs.x * rhs.x, lhs.y * rhs.y);}\nconst Point operator/(const Point& lhs, const Point& rhs) {return Point(lhs.x / rhs.x, lhs.y / rhs.y);}\nconst Point operator-(const Point& p) {return Point(-p.x, -p.y);}\n// ???\nD abs(const Point& p) {return std::hypot(p.x, p.y);}\nD norm(const Point& p) {return p.x * p.x + p.y * p.y;}\nD dot(const Point& a, const Point& b) {return a.x * b.x + a.y * b.y;}\nD cross(const Point& a, const Point& b) {return a.x * b.y - a.y * b.x;}\n// ??´???\nbool parallel(const Line& l1, const Line& l2) {return relative_equal(0.0, cross(l2.terminal - l2.initial, l1.terminal - l1.initial));}\nbool orthogonal(const Line& l1, const Line& l2) {return relative_equal(0.0, dot(l2.terminal - l2.initial, l1.terminal - l1.initial));}\n// 3??????????????¢???\nPOSITION ccw(const Point& a, const Point& b, const Point& p) {\n Point v1 = b - a;\n Point v2 = p - a;\n if(cross(v1, v2) >= EPS) return COUNTER_CLOCKWISE;\n if(cross(v1, v2) <= -EPS) return CLOCKWISE;\n if(dot(v1, v2) <= -EPS) return ONLINE_BACK;\n if(norm(v1) < norm(v2)) return ONLINE_FRONT; // ????????????: norm(v1)<norm(v2)+EPS?????¨WrongAnswer\n return ON_SEGMENT;\n}\n// ????????????\nbool intersect(const Point& p1, const Point& p2) {return p1 == p2;}\nbool intersect(const Point& p, const Segment& s) {return abs(p - s.initial) + abs(p - s.terminal) - abs(s.initial - s.terminal) <= EPS;}\nbool intersect(const Segment& s, const Point& p) {return intersect(p, s);}\nbool intersect(const Point& p, const Line& l) {return !parallel(Line(p, l.initial), Line(p, l.terminal));}\nbool intersect(const Line& l, const Point& p) {return intersect(p, l);}\nbool intersect(const Segment& s1, const Segment& s2) {\n return ccw(s1.initial, s1.terminal, s2.initial) * ccw(s1.initial, s1.terminal, s2.terminal) <= 0\n && ccw(s2.initial, s2.terminal, s1.initial) * ccw(s2.initial, s2.terminal, s1.terminal) <= 0;\n}\nbool intersect(const Segment& s, const Line& l) {\n auto v1 = l.terminal - l.initial;\n auto v2 = s.initial - l.initial;\n auto v3 = s.terminal - l.initial;\n return cross(v1, v2) * cross(v1, v3) <= EPS;\n}\nbool intersect(const Line& l, const Segment& s) {return intersect(s, l);}\nbool intersect(const Line& l1, const Line& l2) {return !parallel(l1, l2) || intersect(l1.initial, l2);}\n// ???????§????\nPoint rotate(const Point& p, const D a) {return Point(p.x * std::cos(a) - p.y * std::sin(a), p.x * std::sin(a) + p.y * std::cos(a));}\nPoint projection(const Point& p, const Line& l) {\n auto v = l.initial - l.terminal;\n return l.initial + dot(p - l.initial, v) / norm(v) * v;\n}\nPoint projection(const Line& l, const Point& p) {return projection(p, l);}\nPoint reflection(const Point& p, const Line& l) {return p + 2 * (projection(p, l) - p);}\nPoint reflection(const Line& l, const Point& p) {return reflection(p, l);}\n// ?????¢\nD distance(const Point& p1, const Point& p2) {\n auto p = p1 - p2;\n return hypot(p.x, p.y);\n}\nD distance(const Point& p, const Segment& s) {\n auto r = projection(s, p);\n return intersect(r, s) ? distance(p, r) : std::min(distance(p, s.initial), distance(p, s.terminal));\n}\nD distance(const Segment& s, const Point& p) {return distance(p, s);}\nD distance(const Point& p, const Line& l) {return distance(p, projection(p, l));}\nD distance(const Line& l, const Point& p) {return distance(p, l);}\nD distance(const Segment& s1, const Segment& s2) {\n return intersect(s1, s2) ? 0.0 : std::min({distance(s1, s2.initial), distance(s1, s2.terminal), distance(s2, s1.initial), distance(s2, s1.terminal)});\n}\nD distance(const Segment& s, const Line& l) {return intersect(s, l) ? 0.0 : std::min(distance(s.initial, l), distance(s.terminal, l));}\nD distance(const Line& l,const Segment& s) {return distance(s, l);}\nD distance(const Line& l1, const Line& l2) {return intersect(l1, l2) ? 0.0 : distance(l1.initial, l2);}\n// ??????\nconst Point crosspoint(const Line& l1, const Line& l2) {\n assert(intersect(l1, l2));\n if(parallel(l1, l2)) return l1.initial; // ???????????¨???l1????§?????????????\n D A = cross(l1.terminal - l1.initial, l2.terminal - l2.initial);\n D B = cross(l1.terminal - l1.initial, l1.terminal - l2.initial);\n return l2.initial + B / A * (l2.terminal - l2.initial);\n}\nconst Point crosspoint(const Segment& s, const Line& l) {\n assert(intersect(s, l));\n if(parallel(s, l)) return s.initial;\n return crosspoint(Line(s), l);\n}\nconst Point crosspoint(const Line& l, const Segment& s) {return crosspoint(s, l);}\nconst Point crosspoint(const Segment& s1, const Segment& s2) {\n assert(intersect(s1, s2));\n if(parallel(s1, s2)) { // ???????????¨?????????????????????????????????\n if(intersect(s1.initial, s2)) return s1.initial;\n if(intersect(s1.terminal, s2)) return s1.terminal;\n if(intersect(s2.initial, s1)) return s2.initial;\n if(intersect(s2.terminal, s1)) return s2.terminal;\n }\n return crosspoint(Line(s1), Line(s2));\n}\n////////////////////////////////////////////////////////////////////////////////\n// ???\n#include<vector>\nconst D PI = std::acos(-1);\nstruct Circle {\n Point center;\n D radius;\n Circle(const Point& center = 0, const D radius = 0) : center(center), radius(radius) {}\n Circle(const D x, const D y, const D radius) : center(x, y), radius(radius) {}\n};\nD area(const Circle& c) {return PI * c.radius * c.radius;}\nbool contain(const Circle& c, const Point& p) {\n D d = abs(p - c.center);\n if(relative_equal(c.radius, d)) return true;\n return d < c.radius;\n}\nbool contain(const Point& p, const Circle& c) {return contain(c, p);}\nstd::vector<Point> crosspoint(const Circle& c, const Line& l) {\n std::vector<Point> cp;\n Point p = projection(c.center, l);\n if(!contain(c, p)) return cp;\n Point v = p - c.center;\n if(relative_equal(abs(v), 0)) {\n Point p = l.initial - c.center;\n if(p == 0) p = l.terminal - c.center;\n p = (c.radius * p / abs(p));\n cp.push_back(c.center + p);\n cp.push_back(c.center - p);\n return cp;\n }\n D angle = acos(abs(v) / c.radius);\n for(D a: {angle, -angle}) cp.push_back(c.center + c.radius * (rotate(v, a) / abs(v)));\n return cp;\n}\nstd::vector<Point> crosspoint(const Line& l, const Circle& c) {return crosspoint(c, l);}\nint tangent(const Circle& c1, const Circle& c2) {\n D d = abs(c1.center - c2.center);\n D r = c1.radius + c2.radius;\n if(relative_equal(d, r)) return 3; // ?????\\\n if(r < d) return 4; // ?????¢\n r = std::abs(c1.radius - c2.radius);\n if(relative_equal(d, r)) return 1; // ?????\\\n if(r < d) return 2; // ??????\n return 0; // ??????\n}\n\n#include<bits/stdc++.h>\nusing namespace std;\n\nint N;\nD R;\nvector<Point> P;\n\nD triangle(const Point& a, const Point& b, const Point& c) {\n return abs(cross(b - a, c - a)) / 2.0;\n}\n\nD sector(const Circle& c, Point a, Point b) {\n a = a - c.center;\n b = b - c.center;\n auto angle = acos(dot(a, b) / abs(a) / abs(b));\n return c.radius * c.radius * angle / 2.0;\n}\n\nD area(const Circle& c, Point a, Point b) {\n if(a > b) swap(a, b);\n if(a == b || c.center == a || c.center == b) return 0;\n // ??????2????????????\n if(contain(c, a) && contain(c, b)) return triangle(c.center, a, b);\n auto cp = crosspoint(c, Line(a, b));\n // ????§???¢????????§?????????\n if(cp.empty()) return sector(c, a, b);\n if(cp[0] > cp[1]) swap(cp[0], cp[1]);\n // 2???????????????\n if(!contain(c, a) && !contain(c, b)) {\n if(b < cp[0] || cp[1] < a) return sector(c, a, b);\n else return sector(c, a, cp[0]) + triangle(c.center, cp[0], cp[1]) + sector(c, cp[1], b);\n }\n // 1?????????????????????\n if(contain(c, a)) return triangle(c.center, a, cp[1]) + sector(c, cp[1], b);\n else return triangle(c.center, cp[0], b) + sector(c, a, cp[0]);\n}\n\nbool ok(D h) {\n D covered = 0;\n Circle c(0, h, R);\n for(auto i = 0; i < P.size(); ++i) {\n auto& cur = P[i], nex = P[(i + 1) % P.size()];\n auto rev = ccw(c.center, cur, nex) == COUNTER_CLOCKWISE;\n covered += area(c, cur, nex) * (rev ? -1 : 1);\n }\n return covered < area(c) / 2.0;\n}\n\nint main() {\n cin >> N >> R;\n\n D p = -200;\n P.emplace_back(p, -200);\n for(auto i = 0; i < N; ++i) {\n D x, w, h;\n cin >> x >> w >> h;\n if(p != x) P.emplace_back(p, 0);\n if(p != x) P.emplace_back(x, 0);\n P.emplace_back(x, h);\n P.emplace_back(x + w, h);\n p = x + w;\n }\n P.emplace_back(p, 0);\n P.emplace_back(200, 0);\n P.emplace_back(200, -200);\n\n const int LIMIT = 1e3;\n D low = -100, high = 200;\n for(auto step = 0; step < LIMIT; ++step) {\n auto middle = (low + high) / 2.0;\n if(ok(middle)) high = middle;\n else low = middle;\n }\n\n cout << setprecision(8) << fixed << low << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3648, "score_of_the_acc": -0.3406, "final_rank": 1 }, { "submission_id": "aoj_0356_2186919", "code_snippet": "////////////////////\n// ???????????????\n#include<cmath>\n#include<algorithm>\n#include<cassert>\n////////////////////\n// ??¨????????¢???\nusing D = double;\n////////////////////\n// ?????°\nconst D EPS = 1e-9; // |EPS|???????????°???0??¨????????±???\nenum POSITION {ONLINE_FRONT = -2, CLOCKWISE, ON_SEGMENT, COUNTER_CLOCKWISE, ONLINE_BACK}; // 3??????????????¢???\n////////////////////\n// ?§???????\nstruct Point {\n D x, y;\n Point(const D d = 0.0) : x(d), y(d) {}\n Point(const D x, const D y) : x(x), y(y) {}\n};\nstruct Segment {\n Point initial, terminal;\n Segment(const Point& initial, const Point& terminal) : initial(initial), terminal(terminal) {}\n Segment(const D x1, const D y1, const D x2, const D y2) : initial(x1, y1), terminal(x2, y2) {}\n};\nstruct Line {\n Point initial, terminal;\n Line(const Point& initial, const Point& terminal) : initial(initial), terminal(terminal) {}\n Line(const D x1, const D y1, const D x2, const D y2) : initial(x1, y1), terminal(x2, y2) {}\n Line(const Segment& s) : initial(s.initial), terminal(s.terminal) {}\n};\n////////////////////\n// ????£?\nbool relative_equal(const D d1, const D d2) {return d1 == 0 ? std::abs(d2) < EPS : std::abs((d1 - d2) / d1) < EPS;}\n// ??????????????????????????????\nbool operator==(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) && relative_equal(lhs.y, rhs.y);}\nbool operator<(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y < rhs.y : lhs.x < rhs.x;}\nbool operator>(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y > rhs.y : lhs.x > rhs.x;}\nbool operator!=(const Point& lhs, const Point& rhs) {return !(lhs == rhs);}\nbool operator<=(const Point& lhs, const Point& rhs) {return !(lhs > rhs);}\nbool operator>=(const Point& lhs, const Point& rhs) {return !(lhs < rhs);}\nconst Point operator+(const Point& lhs, const Point& rhs) {return Point(lhs.x + rhs.x, lhs.y + rhs.y);}\nconst Point operator-(const Point& lhs, const Point& rhs) {return Point(lhs.x - rhs.x, lhs.y - rhs.y);}\nconst Point operator*(const Point& lhs, const Point& rhs) {return Point(lhs.x * rhs.x, lhs.y * rhs.y);}\nconst Point operator/(const Point& lhs, const Point& rhs) {return Point(lhs.x / rhs.x, lhs.y / rhs.y);}\nconst Point operator-(const Point& p) {return Point(-p.x, -p.y);}\n// ???\nD abs(const Point& p) {return std::hypot(p.x, p.y);}\nD norm(const Point& p) {return p.x * p.x + p.y * p.y;}\nD dot(const Point& a, const Point& b) {return a.x * b.x + a.y * b.y;}\nD cross(const Point& a, const Point& b) {return a.x * b.y - a.y * b.x;}\n// ??´???\nbool parallel(const Line& l1, const Line& l2) {return relative_equal(0.0, cross(l2.terminal - l2.initial, l1.terminal - l1.initial));}\nbool orthogonal(const Line& l1, const Line& l2) {return relative_equal(0.0, dot(l2.terminal - l2.initial, l1.terminal - l1.initial));}\n// 3??????????????¢???\nPOSITION ccw(const Point& a, const Point& b, const Point& p) {\n Point v1 = b - a;\n Point v2 = p - a;\n if(cross(v1, v2) >= EPS) return COUNTER_CLOCKWISE;\n if(cross(v1, v2) <= -EPS) return CLOCKWISE;\n if(dot(v1, v2) <= -EPS) return ONLINE_BACK;\n if(norm(v1) < norm(v2)) return ONLINE_FRONT; // ????????????: norm(v1)<norm(v2)+EPS?????¨WrongAnswer\n return ON_SEGMENT;\n}\n// ????????????\nbool intersect(const Point& p1, const Point& p2) {return p1 == p2;}\nbool intersect(const Point& p, const Segment& s) {return abs(p - s.initial) + abs(p - s.terminal) - abs(s.initial - s.terminal) <= EPS;}\nbool intersect(const Segment& s, const Point& p) {return intersect(p, s);}\nbool intersect(const Point& p, const Line& l) {return !parallel(Line(p, l.initial), Line(p, l.terminal));}\nbool intersect(const Line& l, const Point& p) {return intersect(p, l);}\nbool intersect(const Segment& s1, const Segment& s2) {\n return ccw(s1.initial, s1.terminal, s2.initial) * ccw(s1.initial, s1.terminal, s2.terminal) <= 0\n && ccw(s2.initial, s2.terminal, s1.initial) * ccw(s2.initial, s2.terminal, s1.terminal) <= 0;\n}\nbool intersect(const Segment& s, const Line& l) {\n auto v1 = l.terminal - l.initial;\n auto v2 = s.initial - l.initial;\n auto v3 = s.terminal - l.initial;\n return cross(v1, v2) * cross(v1, v3) <= EPS;\n}\nbool intersect(const Line& l, const Segment& s) {return intersect(s, l);}\nbool intersect(const Line& l1, const Line& l2) {return !parallel(l1, l2) || intersect(l1.initial, l2);}\n// ???????§????\nPoint rotate(const Point& p, const D a) {return Point(p.x * std::cos(a) - p.y * std::sin(a), p.x * std::sin(a) + p.y * std::cos(a));}\nPoint projection(const Point& p, const Line& l) {\n auto v = l.initial - l.terminal;\n return l.initial + dot(p - l.initial, v) / norm(v) * v;\n}\nPoint projection(const Line& l, const Point& p) {return projection(p, l);}\nPoint reflection(const Point& p, const Line& l) {return p + 2 * (projection(p, l) - p);}\nPoint reflection(const Line& l, const Point& p) {return reflection(p, l);}\n// ?????¢\nD distance(const Point& p1, const Point& p2) {\n auto p = p1 - p2;\n return hypot(p.x, p.y);\n}\nD distance(const Point& p, const Segment& s) {\n auto r = projection(s, p);\n return intersect(r, s) ? distance(p, r) : std::min(distance(p, s.initial), distance(p, s.terminal));\n}\nD distance(const Segment& s, const Point& p) {return distance(p, s);}\nD distance(const Point& p, const Line& l) {return distance(p, projection(p, l));}\nD distance(const Line& l, const Point& p) {return distance(p, l);}\nD distance(const Segment& s1, const Segment& s2) {\n return intersect(s1, s2) ? 0.0 : std::min({distance(s1, s2.initial), distance(s1, s2.terminal), distance(s2, s1.initial), distance(s2, s1.terminal)});\n}\nD distance(const Segment& s, const Line& l) {return intersect(s, l) ? 0.0 : std::min(distance(s.initial, l), distance(s.terminal, l));}\nD distance(const Line& l,const Segment& s) {return distance(s, l);}\nD distance(const Line& l1, const Line& l2) {return intersect(l1, l2) ? 0.0 : distance(l1.initial, l2);}\n// ??????\nconst Point crosspoint(const Line& l1, const Line& l2) {\n assert(intersect(l1, l2));\n if(parallel(l1, l2)) return l1.initial; // ???????????¨???l1????§?????????????\n D A = cross(l1.terminal - l1.initial, l2.terminal - l2.initial);\n D B = cross(l1.terminal - l1.initial, l1.terminal - l2.initial);\n return l2.initial + B / A * (l2.terminal - l2.initial);\n}\nconst Point crosspoint(const Segment& s, const Line& l) {\n assert(intersect(s, l));\n if(parallel(s, l)) return s.initial;\n return crosspoint(Line(s), l);\n}\nconst Point crosspoint(const Line& l, const Segment& s) {return crosspoint(s, l);}\nconst Point crosspoint(const Segment& s1, const Segment& s2) {\n assert(intersect(s1, s2));\n if(parallel(s1, s2)) { // ???????????¨?????????????????????????????????\n if(intersect(s1.initial, s2)) return s1.initial;\n if(intersect(s1.terminal, s2)) return s1.terminal;\n if(intersect(s2.initial, s1)) return s2.initial;\n if(intersect(s2.terminal, s1)) return s2.terminal;\n }\n return crosspoint(Line(s1), Line(s2));\n}\n////////////////////////////////////////////////////////////////////////////////\n// ?????????\n#include<vector>\nconst D PI = std::acos(-1);\nstruct Circle {\n Point center;\n D radius;\n Circle(const Point& center = 0, const D radius = 0) : center(center), radius(radius) {}\n Circle(const D x, const D y, const D radius) : center(x, y), radius(radius) {}\n};\nD area(const Circle& c) {return PI * c.radius * c.radius;}\nbool contain(const Circle& c, const Point& p) {\n D d = abs(p - c.center);\n if(relative_equal(c.radius, d)) return true;\n return d < c.radius;\n}\nbool contain(const Point& p, const Circle& c) {return contain(c, p);}\n#include<bits/stdc++.h>\nusing namespace std;\nstd::vector<Point> crosspoint(const Circle& c, const Line& l) {\n std::vector<Point> cp;\n Point p = projection(c.center, l);\n if(!contain(c, p)) return cp;\n Point v = p - c.center;\n if(relative_equal(abs(v), 0)) {\n Point p = l.initial - c.center;\n if(p == 0) p = l.terminal - c.center;\n p = (c.radius * p / abs(p));\n cp.push_back(c.center + p);\n cp.push_back(c.center - p);\n return cp;\n }\n D angle = acos(abs(v) / c.radius);\n for(D a: {angle, -angle}) cp.push_back(c.center + c.radius * (rotate(v, a) / abs(v)));\n return cp;\n}\nstd::vector<Point> crosspoint(const Line& l, const Circle& c) {return crosspoint(c, l);}\nint tangent(const Circle& c1, const Circle& c2) {\n D d = abs(c1.center - c2.center);\n D r = c1.radius + c2.radius;\n if(relative_equal(d, r)) return 3; // ?????\\\n if(r < d) return 4; // ?????¢\n r = std::abs(c1.radius - c2.radius);\n if(relative_equal(d, r)) return 1; // ?????\\\n if(r < d) return 2; // ??????\n return 0; // ??????\n}\n\n#include<bits/stdc++.h>\nusing namespace std;\n\nint N;\nD R;\nvector<Point> P;\n\nD triangle(const Point& a, const Point& b, const Point& c) {\n return abs(cross(b - a, c - a)) / 2.0;\n}\n\nD sector(const Circle& c, Point a, Point b) {\n a = a - c.center;\n b = b - c.center;\n auto angle = acos(dot(a, b) / abs(a) / abs(b));\n return c.radius * c.radius * angle / 2.0;\n// auto a1 = atan2(a.y - c.center.y, a.x - c.center.x);\n// auto a2 = atan2(b.y - c.center.y, b.x - c.center.x);\n// auto angle = a2 - a1;\n// cout<<a1<<\" \"<<a2<<endl;\n// cout<<angle<<endl;\n// return c.radius * c.radius * angle / 2.0;\n}\n\nD area(const Circle& c, Point a, Point b) {\n if(a > b) swap(a, b);\n if(a == b || c.center == a || c.center == b) return 0;\n // ??????2????????????\n if(contain(c, a) && contain(c, b)) return triangle(c.center, a, b);\n auto cp = crosspoint(c, Line(a, b));\n // ????§???¢????????§?????????\n if(cp.empty()) return sector(c, a, b);\n if(cp[0] > cp[1]) swap(cp[0], cp[1]);\n // 2???????????????\n if(!contain(c, a) && !contain(c, b)) {\n if(b < cp[0] || cp[1] < a) return sector(c, a, b);\n else return sector(c, a, cp[0]) + triangle(c.center, cp[0], cp[1]) + sector(c, cp[1], b);\n }\n // 1?????????????????????\n if(contain(c, a)) return triangle(c.center, a, cp[1]) + sector(c, cp[1], b);\n else return triangle(c.center, cp[0], b) + sector(c, a, cp[0]);\n}\n\nbool ok(D h) {\n D covered = 0;\n Circle c(0, h, R);\n for(auto i = 0; i < P.size(); ++i) {\n auto& cur = P[i], nex = P[(i + 1) % P.size()];\n auto rev = ccw(c.center, cur, nex) == COUNTER_CLOCKWISE;\n covered += area(c, cur, nex) * (rev ? -1 : 1);\n }\n return covered < area(c) / 2.0;\n}\n\nint main() {\n cin >> N >> R;\n\n D p = -200;\n P.emplace_back(p, -200);\n for(auto i = 0; i < N; ++i) {\n D x, w, h;\n cin >> x >> w >> h;\n if(p != x) P.emplace_back(p, 0);\n if(p != x) P.emplace_back(x, 0);\n P.emplace_back(x, h);\n P.emplace_back(x + w, h);\n p = x + w;\n }\n P.emplace_back(p, 0);\n P.emplace_back(200, 0);\n P.emplace_back(200, -200);\n\n const int LIMIT = 1e4;\n D low = -100, high = 200;\n for(auto step = 0; step < LIMIT; ++step) {\n auto middle = (low + high) / 2.0;\n if(ok(middle)) high = middle;\n else low = middle;\n }\n\n cout << setprecision(8) << fixed << low << endl;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 3660, "score_of_the_acc": -1.0108, "final_rank": 3 } ]
aoj_0354_cpp
蟻 大きなチェス盤上に、それぞれ1から N までの番号が割り振られた N 匹の蟻がいます。図のように、チェス盤は H×W のマスからなる長方形で、北西角を白として、白マスと黒マスが交互に並んでいます。 最初、どの蟻もチェス盤のマスの中にいて、東または南を向いています。1つのマスの中に2匹以上の蟻がいることはありません。 今、蟻たちが一斉に動き出します。すべての蟻は 1 単位時間に向いている方向のマスに1つ移動します。ただし、移動先がチェス盤の外の場合、落下してチェス盤から姿を消します。 チェス盤上で2匹の蟻が同じマスに入ると、それらの蟻は以下のような行動をとります: そのマスの色が白ならば、東方向に進んでいた蟻は南方向へ、南方向に進んでいた蟻は東方向へ向きを変える。 そのマスの色が黒ならば、それぞれの蟻は進む方向を維持する。 チェス盤の大きさと蟻の情報が与えられたとき、落下する順番に蟻の番号を報告するプログラムを作成せよ。ただし、同じ時刻に複数の蟻が落下する場合は、番号がより小さい方を先に報告する。 Input 入力は以下の形式で与えられる。 W H N x 1 y 1 d 1 x 2 y 2 d 2 : x N y N d N 1行目にチェス盤の東西方向のマスの数 W と南北方向のマスの数 H (2 ≤ W , H ≤ 10 9 ) と蟻の数 N (1 ≤ N ≤ 200000) が与えられる。続く N 行に i 番目の蟻の東西方向の位置 x i (1 ≤ x i ≤ W )、南北方向の位置 y i (1 ≤ y i ≤ H )、向きを表す文字 d i (東向きの場合「E」、南向きの場合「S」)が与えられる。ここで、チェス盤の北西角のマスを (1,1)、 x が増加する方向を東、 y が増加する方向を南とする。 Output 落下する順番に、蟻の番号を1行ずつ出力する。 Sample Input 1 3 3 3 2 1 S 1 2 E 2 2 E Sample Output 1 3 1 2 Sample Input 2 5 4 3 3 1 S 2 2 E 1 3 E Sample Output 2 2 3 1
[ { "submission_id": "aoj_0354_10865835", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define INF 2e+9\n#define mp make_pair\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> PP;\n\nint w,h,n,x[200000],y[200000],ans[200000];\nstring d[200000];\nvector<int> vec[200000],xys;\nvector<P> tim;\n\nvoid solve(vector<int> vecvec,int add){\n\tvector<int> tmp;\n\tvector<PP> ord;\n\tmap<int,int> cnt;\n\tfor(int v : vecvec){\n\t\tcnt[x[v]]++;\n\t}\n\tfor(int v : vecvec){\n\t\tif(cnt[x[v]] >= 2){\n\t\t\tif(d[v] == \"S\") d[v] = \"E\";\n\t\t\telse d[v] = \"S\";\n\t\t}\n\t\tif(d[v] == \"S\") ord.push_back(mp(x[v],mp(0,v)));\n\t\telse ord.push_back(mp(x[v],mp(1,v)));\n\t}\n\tsort(ord.begin(),ord.end());\n\tfor(int i = 0;i < vecvec.size();i++) vecvec[i] = ord[i].second.second;\n\tmap<int,int> mp[2];\n\tfor(int v : vecvec){\n\t\tint pos = x[v] - y[v];\n\t\tif(d[v] == \"S\"){\n\t\t\tmp[1][pos] = h - y[v];\n\t\t\tpos -= INF;\n\t\t}\n\t\telse{\n\t\t\tmp[0][pos] = w - x[v];\n\t\t\tpos += INF;\n\t\t}\n\t\ttmp.push_back(pos);\n\t}\n\tsort(tmp.begin(),tmp.end());\n\tfor(int i = 0;i < vecvec.size();i++){\n\t\tif(tmp[i] < 0){\n\t\t\ttmp[i] += INF;\n\t\t\tans[vecvec[i]] = mp[1][tmp[i]] + add;\n\t\t}\n\t\telse{\n\t\t\ttmp[i] -= INF;\n\t\t\tans[vecvec[i]] = mp[0][tmp[i]] + add;\n\t\t}\n\t}\n}\n\nsigned main(){\n\tcin >> w >> h >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> x[i] >> y[i] >> d[i];x[i]--;y[i]--;\n\t\txys.push_back(x[i] + y[i]);\n\t}\n\tsort(xys.begin(),xys.end());\n\txys.erase(unique(xys.begin(),xys.end()),xys.end());\n\tfor(int i = 0;i < n;i++){\n\t\tint ind = lower_bound(xys.begin(),xys.end(),x[i] + y[i]) - xys.begin();\n\t\tvec[ind].push_back(i);\n\t}\n\tfor(int i = 0;i < xys.size();i++){\n\t\tif(xys[i] % 2 == 0){\n\t\t\tvector<int> vs1,vs2;\n\t\t\tfor(int v : vec[i]){\n\t\t\t\tif(x[v] % 2) vs1.push_back(v);\n\t\t\t\telse vs2.push_back(v);\n\t\t\t}\n\t\t\tsolve(vs1,0);\n\t\t\tsolve(vs2,0);\n\t\t}else{\n\t\t\tvector<int> vs1,vs2;\n\t\t\tfor(int v : vec[i]){\n\t\t\t\tif(d[v] == \"E\") x[v]++;\n\t\t\t\telse y[v]++;\n\t\t\t\tif(x[v] == w) ans[v] = 1;\n\t\t\t\telse if(y[v] == h) ans[v] = 1;\n\t\t\t\telse if(x[v] % 2) vs1.push_back(v);\n\t\t\t\telse vs2.push_back(v);\n\t\t\t}\n\t\t\tsolve(vs1,1);\n\t\t\tsolve(vs2,1);\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++) {\n\t\ttim.push_back(P(ans[i],i));\n\t}\n\tsort(tim.begin(),tim.end());\n\tfor(int i = 0;i < n;i++) cout << tim[i].second + 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 57548, "score_of_the_acc": -0.5785, "final_rank": 15 }, { "submission_id": "aoj_0354_7237777", "code_snippet": "#include <cmath>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <stdlib.h>\nusing namespace std;\nstruct E{\n\tint x,y,no,p1;\n\tstring str;\n};\nstruct E2{\n\tint no,t;\n\tbool operator<(const E2& e2){\n\t\tif(t!=e2.t)return t<e2.t;\n\t\treturn no<e2.no;\n\t}\n};\n\nmap<int,map<int,int> > msDki,msRki,msDgu,msRgu,DKitoNo,DGutoNo,RKitoNo,RgutoNo;\nvector<E> vs;\nset<int> ssD,ssR;\nint w,h,n;\nint f3(map<int,int>& mr,map<int,int>& md,map<int,int>& toR,map<int,int>& toD,E& e1){\n\tint ans=0;\n\tmap<int,int>::iterator it,it2;\n\tif(e1.str==\"S\"){\n\t\t//下向き\n\t\tit=mr.lower_bound(e1.x);\n\t\tif(it==mr.begin()){\n\t\t\t//cout<<\"D1= \"<<e1.no<<endl;\n\t\t\treturn h-e1.y+1;\n\t\t}\n\t\tit--;\n\t\tans=abs(e1.y-abs(e1.p1-(*it).first));\n\t\t\n\t\tit2=md.upper_bound(e1.x);\n\t\tif(it2==md.end()){\n\t\t\t//cout<<\"D2= \"<<e1.no<<endl;\n\t\t\treturn ans+w-e1.x+1;\n\t\t}\n\t\tint nor=(*it).second;\n\t\tint nod=(*it2).second;\n\t\tif(nor<=nod){\n\t\t\t//あと少しで完成だがこんな巨大なコードになるの多分俺の設計ミス\n\t\t\t//これがうまく動くまで修正してもあまり褒められたことではないな。\n\t\t\tint nor2=nod-nor+1;\n\t\t\tans=abs(h-e1.y+1);\n\t\t\tans+=abs(e1.x-toD[nor2]);\n\t\t//\tcout<<\"D3= \"<<e1.no<<endl;\n\t\t}else{\n\t\t\tint nor2=nor-nod;\n\t\t\tans=w-e1.x+1;\n\t\t\tans+=abs(e1.y-abs(e1.p1-toR[nor2]));\n\t\t//\tcout<<\"D4= \"<<e1.no<<endl;\n\t\t}\n\t}else{\n\t\t//右向き\n\t\tit=md.upper_bound(e1.x);\n\t\tif(it==md.end()){\n\t\t\t//cout<<\"R1= \"<<e1.no<<endl;\n\t\t\treturn w-e1.x+1;\n\t\t}\n\t\tans=abs((*it).first-e1.x);\n\t\tit2=mr.lower_bound(e1.x);\n\t\t\n\t\tif(it2==mr.begin()){\n\t\t\tans=ans+h-e1.y+1;\n\t\t\t//cout<<\"R2= \"<<e1.no<<endl;\n\t\t\treturn ans;\n\t\t}\n\t\tit2--;\n\t\tint nod=(*it).second;\n\t\tint nor=(*it2).second;\n\t\tif(nod<=nor){\n\t\t\tans=w-e1.x+1;\n\t\t\tint nod2=nor-nod+1;\n\t\t\tans+=abs(e1.y-abs(e1.p1-toR[nod2]));\n\t\t\t//if(e1.no==3){\n\t\t\t//\tcout<<\"x \"<<e1.x<<\" y\"<<e1.y<<\" p1\"<<e1.p1<<\" nod\"<<nod<<\" nor\"<<nor<<\" toD\"<<toR[nod2];\n\t\t\t//\tcout<<\" no=\"<<e1.no<<\" ans=\"<<ans<<endl;\n\t\t\t//\tfor(map<int,int>::iterator it=mr.begin();it!=mr.end();it++){\n\t\t\t//\t\tcout<<\"x=\"<<(*it).first<<\" no\"<<(*it).second<<endl;\n\t\t\t//\t}\n\t\t\t//\tcout<<endl;\n\t\t\t//}\n\t\t\t//cout<<\"R3= \"<<e1.no<<endl;\n\t\t}else{\n\t\t\tans=h-e1.y+1;\n\t\t\tint nor2=nod-nor;\n\t\t\tans+=abs(e1.x-abs(toD[nor2]));\n\t\t\t//cout<<\"R4= \"<<e1.no<<endl;\n\t\t}\n\t}\n\t//cout<<ans<<endl;\n\treturn ans;\n}\nvoid f2p(map<int,map<int,int> >& ms,set<int>& ks){\n\tset<int>::iterator it;\n\tmap<int,int>::iterator it2;\n\tfor(it=ks.begin();it!=ks.end();it++){\n\t\tint t=(*it);\n\t\tint no=0;\n\t\tfor(it2=ms[t].begin();it2!=ms[t].end();it2++){\n\t\t\tcout<<(*it2).first<<\" \"<<(*it2).second<<endl;\n\t\t}\n\t}\n}\nvoid f2(map<int,map<int,int> >& ms,map<int,map<int,int> >& toNo,set<int>& ks){\n\tset<int>::iterator it;\n\tmap<int,int>::iterator it2;\n\tfor(it=ks.begin();it!=ks.end();it++){\n\t\tint t=(*it);\n\t\tint no=0;\n\t\tfor(it2=ms[t].begin();it2!=ms[t].end();it2++){\n\t\t\tno++;\n\t\t\t(*it2).second=no;\n\t\t\ttoNo[t][no]=(*it2).first;\n\t\t}\n\t}\n}\nvoid f2r(map<int,map<int,int> >& ms,map<int,map<int,int> >& toNo,set<int>& ks){\n\tset<int>::iterator it;\n\tmap<int,int>::reverse_iterator it2;\n\tfor(it=ks.begin();it!=ks.end();it++){\n\t\tint t=(*it);\n\t\tint no=0;\n\t\tfor(it2=ms[t].rbegin();it2!=ms[t].rend();it2++){\n\t\t\tno++;\n\t\t\t(*it2).second=no;\n\t\t\ttoNo[t][no]=(*it2).first;\n\t\t}\n\t}\n}\n\n\nvoid f(){\n\tmap<int,int> m1;\n\tfor(int i=0;i<n;i++){\n\t\tE e1;\n\t\tstring str;\n\t\tcin>>e1.x>>e1.y>>e1.str;\n\t\te1.no=i+1;\n\t\tint p1=e1.x+e1.y;\n\t\te1.p1=p1;\n\t\tvs.push_back(e1);\n\t\tif(e1.str==\"S\"){\n\t\t\tssD.insert(p1);\n\t\t}else{\n\t\t\tssR.insert(p1);\n\t\t}\n\t}\n\tset<int>::iterator it;\n\tfor(it=ssD.begin();it!=ssD.end();it++){\n\t\tmsDki[(*it)]=m1;\n\t\tmsDgu[(*it)]=m1;\n\t\tDKitoNo[(*it)]=m1;\n\t\tDGutoNo[(*it)]=m1;\n\t\t\n\t}\n\tfor(it=ssR.begin();it!=ssR.end();it++){\n\t\tmsRki[(*it)]=m1;\n\t\tmsRgu[(*it)]=m1;\n\t\tRKitoNo[(*it)]=m1;\n\t\tRgutoNo[(*it)]=m1;\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tE e1=vs[i];\n\t\tif(e1.str==\"S\"){\n\t\t\tif((e1.x%2)==0){\n\t\t\t\tmsDgu[e1.p1][e1.x]=0;\n\t\t\t}else{\n\t\t\t\tmsDki[e1.p1][e1.x]=0;\n\t\t\t}\n\t\t}else{\n\t\t\tif((e1.x%2)==0){\n\t\t\t\tmsRgu[e1.p1][e1.x]=0;\n\t\t\t}else{\n\t\t\t\tmsRki[e1.p1][e1.x]=0;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tf2(msRki,RKitoNo,ssR);\n\tf2(msRgu,RgutoNo,ssR);\n\tf2r(msDgu,DGutoNo,ssD);\n\tf2r(msDki,DKitoNo,ssD);\n\tvector<E2> ans;\n\tfor(int i=0;i<n;i++){\n\t\tE e1=vs[i];\n\t\tint p1=e1.p1;\n\t\tE2 e2;\n\t\te2.no=e1.no;\n\t\t//8パターンの場合分けがあってめんどくさいなこれ。ちょっと休憩しよう。多分設計をちょっと間違えた\n\t\tif(e1.str==\"E\"){\n\t\t\tif(e1.p1%2==0){\n\t\t\t\t//msDki,msRki,msDgu,msRgu,DKitoNo,DGutoNo,RKitoNo,RgutoNo\n\t\t\t\tif(e1.x%2==0){\n\t\t\t\t\t//東白偶数\n\t\t\t\t\te2.t=f3(msRgu[p1],msDgu[p1],RgutoNo[p1],DGutoNo[p1],e1);\n\t\t\t\t}else{\n\t\t\t\t\t//東白奇数\n\t\t\t\t\te2.t=f3(msRki[p1],msDki[p1],RKitoNo[p1],DKitoNo[p1],e1);\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\t\n\t\t\t\tif(e1.x%2==0){\n\t\t\t\t\t//東黒偶数\n\t\t\t\t\te2.t=f3(msRgu[p1],msDki[p1],RgutoNo[p1],DKitoNo[p1],e1);\n\t\t\t\t}else{\n\t\t\t\t\t//東黒奇数\n\t\t\t\t\te2.t=f3(msRki[p1],msDgu[p1],RKitoNo[p1],DGutoNo[p1],e1);\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tif(e1.p1%2==0){\n\t\t\t\tif(e1.x%2==0){\n\t\t\t\t\t//南白偶数\n\t\t\t\t\te2.t=f3(msRgu[p1],msDgu[p1],RgutoNo[p1],DGutoNo[p1],e1);\n\t\t\t\t}else{\n\t\t\t\t\t//南白奇数\n\t\t\t\t\te2.t=f3(msRki[p1],msDki[p1],RKitoNo[p1],DKitoNo[p1],e1);\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\t\n\t\t\t\tif(e1.x%2==0){\n\t\t\t\t\t//南黒偶数\n\t\t\t\t\te2.t=f3(msRki[p1],msDgu[p1],RKitoNo[p1],DGutoNo[p1],e1);\n\t\t\t\t}else{\n\t\t\t\t\t//南黒奇数\n\t\t\t\t\te2.t=f3(msRgu[p1],msDki[p1],RgutoNo[p1],DKitoNo[p1],e1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t//cout<<e2.no<<\" \"<<e2.t<<endl;\n\t\tans.push_back(e2);\n\t}\n\tsort(ans.begin(),ans.end());\n\tfor(int i=0;i<n;i++){\n\t\tcout<<ans[i].no<<endl;\n\t}\n}\n\nint main() {\n\tcin>>w>>h>>n;\n\tf();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 158964, "score_of_the_acc": -2, "final_rank": 17 }, { "submission_id": "aoj_0354_5027552", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<map>\nusing namespace std;\nint H,W,N;\nmap<int,vector<pair<pair<int,int>,pair<bool,int> > > >mp;\nmain()\n{\n\tcin>>W>>H>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint x,y;char d;\n\t\tcin>>x>>y>>d;\n\t\tx--,y--;\n\t\tmp[x+y].push_back(make_pair(make_pair(x,y),make_pair(d=='S',i+1)));\n\t}\n\tvector<pair<int,int> >ans;\n\tans.reserve(N);\n\tfor(auto it=mp.begin();it!=mp.end();it++)\n\t{\n\t\tvector<pair<pair<int,int>,pair<bool,int> > >A=it->second;\n\t\tsort(A.begin(),A.end());\n\t\tint off=0;\n\t\tif(it->first%2==1)\n\t\t{\n\t\t\toff=1;\n\t\t\tfor(int i=0;i<A.size();i++)\n\t\t\t{\n\t\t\t\tif(A[i].second.first)A[i].first.second++;\n\t\t\t\telse\n\t\t\t\t{\n\t\t\t\t\tA[i].first.first++;\n\t\t\t\t\tif(i+1<A.size()&&A[i+1].first.first==A[i].first.first&&A[i+1].second.first)\n\t\t\t\t\t{\n\t\t\t\t\t\tA[i].second.first=true;\n\t\t\t\t\t\tA[i+1].second.first=false;\n\t\t\t\t\t\tA[i+1].first.second++;\n\t\t\t\t\t\ti++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<pair<pair<int,int>,pair<bool,int> > >B[2];\n\t\tfor(int i=0;i<A.size();i++)\n\t\t{\n\t\t\tB[A[i].first.first%2].push_back(A[i]);\n\t\t}\n\t\tfor(int i=0;i<2;i++)\n\t\t{\n\t\t\tauto A=B[i];\n\t\t\tint id=0;\n\t\t\tfor(int i=0;i<A.size();i++)if(A[i].second.first)\n\t\t\t{\n\t\t\t\tint dx=A[i].first.first-A[id].first.first;\n\t\t\t\tint dy=H-A[id].first.second;\n\t\t\t\tans.push_back(make_pair(dx+dy+off,A[id++].second.second));\n\t\t\t}\n\t\t\tfor(int i=0;i<A.size();i++)if(!A[i].second.first)\n\t\t\t{\n\t\t\t\tint dx=W-A[id].first.first;\n\t\t\t\tint dy=A[i].first.second-A[id].first.second;\n\t\t\t\tans.push_back(make_pair(dx+dy+off,A[id++].second.second));\n\t\t\t}\n\t\t}\n\t}\n\tsort(ans.begin(),ans.end());\n\tfor(int i=0;i<N;i++)cout<<ans[i].second<<endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 26224, "score_of_the_acc": -0.4137, "final_rank": 11 }, { "submission_id": "aoj_0354_4974028", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\nstruct Ant{\n char ty; int x,y; int i;\n bool operator<(Ant r)const{ return x-y < r.x-r.y; }\n};\n\nint H,W,N;\nmap<pair<int,int>,vector<Ant>> A;\nvector<pair<int,int>> ans;\n\nint main(){\n cin>>W>>H>>N;\n rep(i,N){\n char ty; int x,y; cin>>x>>y>>ty; x--; y--;\n int mat = 0;\n mat = (x+H-y)/2;\n if((x+y)%2==1) if(ty=='E') mat++;\n A[{mat%2,x+y}].push_back({ty,x,y,i});\n }\n\n ans.resize(N);\n\n for(auto& Axitr : A){\n auto& Ax = Axitr.second;\n if(Ax.size()==0) continue;\n\n vector<Ant> fall;\n for(Ant& a : Ax){\n Ant falltmp;\n if(a.ty=='E') falltmp = {'E',W,a.y,0};\n if(a.ty=='S') falltmp = {'S',a.x,H,0};\n fall.push_back(falltmp);\n }\n sort(fall.begin(),fall.end());\n sort(Ax.begin(),Ax.end());\n\n rep(x,Ax.size()){\n Ant a = Ax[x];\n Ant f = fall[x];\n ans[a.i] = {(f.y-a.y) + (f.x-a.x), a.i+1};\n }\n }\n\n sort(ans.begin(),ans.end());\n rep(i,N) cout<<ans[i].second<<endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 26272, "score_of_the_acc": -0.4072, "final_rank": 10 }, { "submission_id": "aoj_0354_4798412", "code_snippet": "#pragma GCC target (\"avx2\")\n#pragma GCC optimize (\"unroll-loops\")\n#pragma GCC optimize (\"O3\")\n#include \"bits/stdc++.h\"\n#include <unordered_set>\n#include <unordered_map>\n#include <random>\nusing namespace std;\ntypedef long long ll;\nconst ll MOD = 1'000'000'007LL; /*998'244'353LL;*/\n#define pb push_back\n#define mp make_pair\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\nconst int dx[4]={ 1,0,-1,0 };\nconst int dy[4]={ 0,1,0,-1 };\n\nll W, H;\nint N;\nll x[400000], y[400000];\nchar d[400000];\n\nvector<ll> cand;\nunordered_map<ll,vector<pair<ll, int>>> v[2][2]; // →:1,↓:0\nvector<pair<ll, int>> ans;\n\nsigned main(){\n cin >> W >> H >> N;\n rep(i, N){\n cin >> x[i] >> y[i] >> d[i];\n cand.pb(x[i]+y[i]);\n v[d[i] == 'E'][x[i]%2][x[i]+y[i]].pb({ x[i], i });\n }\n sort(all(cand));\n cand.erase(unique(all(cand)), cand.end());\n\n rep(t, cand.size()){\n ll i = cand[t];\n rep(j, 2) rep(k, 2) sort(all(v[j][k][i]));\n if(i%2 == 0){ // 白\n rep(k, 2){\n vector<pair<ll, ll>> tmp;\n vector<pair<ll, int>> marge;\n rep(j, v[0][k][i].size()){\n marge.pb(v[0][k][i][j]);\n int idx = v[0][k][i][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[1][k][i].size()){\n marge.pb(v[1][k][i][j]);\n int idx = v[1][k][i][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n else{ // 黒\n rep(k, 2){\n vector<pair<ll, ll>> tmp;\n vector<pair<ll, int>> marge;\n rep(j, v[0][k][i].size()){\n marge.pb(v[0][k][i][j]);\n int idx = v[0][k][i][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[1][k^1][i].size()){\n marge.pb(v[1][k^1][i][j]);\n int idx = v[1][k^1][i][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n }\n sort(all(ans));\n rep(i, N) cout << ans[i].second+1 << endl;\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 62536, "score_of_the_acc": -0.8139, "final_rank": 16 }, { "submission_id": "aoj_0354_4798401", "code_snippet": "#line 2 \"lib/template.cpp\"\n\n#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <cstring>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing VI = vector<int>;\nusing VVI = vector<vector<int>>;\nusing VLL = vector<ll>;\nusing VVLL = vector<vector<ll>>;\nusing VB = vector<bool>;\nusing PII = pair<int, int>;\nusing PLL = pair<ll, ll>;\nconstexpr int INF = 1000000007;\nconstexpr ll INF_LL = 1'000'000'000'000'000'007;\n#define all(x) begin(x), end(x)\n#define rall(x) rbegin(x), rend(x)\n#define newl '\\n'\n\n// loops rep(until) / rep(var, until) / rep(var, from, until) / repr (reversed order)\n#define OVERLOAD3(_1, _2, _3, name, ...) name\n#define rep(...) OVERLOAD3(__VA_ARGS__, REPEAT_FROM_UNTIL, REPEAT_UNTIL, REPEAT)(__VA_ARGS__)\n#define REPEAT(times) REPEAT_CNT(_repeat, __COUNTER__, times)\n#define REPEAT_CNT(_repeat, cnt, times) REPEAT_CNT_CAT(_repeat, cnt, times)\n#define REPEAT_CNT_CAT(_repeat, cnt, times) REPEAT_FROM_UNTIL(_repeat ## cnt, 0, times)\n#define REPEAT_UNTIL(name, times) REPEAT_FROM_UNTIL(name, 0, times)\n#define REPEAT_FROM_UNTIL(name, from, until) for (int name = from, name ## __until = (until); name < name ## __until; name++)\n#define repr(...) OVERLOAD3(__VA_ARGS__, REPR_FROM_UNTIL, REPR_UNTIL, REPEAT)(__VA_ARGS__)\n#define REPR_UNTIL(name, times) REPR_FROM_UNTIL(name, 0, times)\n#define REPR_FROM_UNTIL(name, from, until) for (int name = (until)-1, name ## __from = (from); name >= name ## __from; name--)\n\ntemplate <typename T>\nbool chmin(T& var, T x) { if (var > x) { var = x; return true; } else return false; }\ntemplate <typename T>\nbool chmax(T& var, T x) { if (var < x) { var = x; return true; } else return false; }\nll power(ll e, ll t, ll mod = INF_LL) {\n ll res = 1; for (; t; t >>= 1, (e *= e) %= mod) if (t & 1) (res *= e) %= mod; return res;\n}\ntemplate <typename T> T divceil(T m, T d) { return (m + d - 1) / d; }\ntemplate <typename T> vector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_v(size_t a, Ts... ts) {\n return vector<decltype(make_v(ts...))>(a, make_v(ts...));\n}\nstruct desync { desync() { cin.tie(nullptr); ios_base::sync_with_stdio(false); }} desync_;\n\n// dump(...) for debug\n#define repi(it, ds) for (auto it = ds.begin(); it != ds.end(); it++)\nclass DebugPrint { public: template <typename T> DebugPrint& operator <<(const T& v) {\n#ifdef LOCAL\n cerr << v;\n#endif\nreturn *this; } } debugos; template <typename T> DebugPrint& operator<<(DebugPrint& os, const\nvector<T>& vec) { os << \"{\"; for (int i = 0; i < vec.size(); i++) os << vec[i] << (i + 1 ==\nvec.size() ? \"\" : \", \"); os << \"}\"; return os; } template <typename T, typename U> DebugPrint&\noperator<<(DebugPrint& os, const map<T, U>& map_var) { os << \"{\"; repi(itr, map_var) { os << *\nitr; itr++; if (itr != map_var.end()) os << \", \"; itr--; } os << \"}\"; return os; } template <\ntypename T> DebugPrint& operator<<(DebugPrint& os, const set<T>& set_var) { os << \"{\"; repi(\nitr, set_var) { os << *itr; itr++; if (itr != set_var.end()) os << \", \"; itr--; } os << \"}\";\nreturn os; } template <typename T, typename U> DebugPrint& operator<<(DebugPrint& os, const\npair<T, U>& p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; } void dump_func(\n) { debugos << newl; } template <class Head, class... Tail> void dump_func(Head &&head, Tail\n&&... tail) { debugos << head; if (sizeof...(Tail) > 0) { debugos << \", \"; } dump_func(forward\n<Tail>(tail)...); }\n#ifdef LOCAL\n#define dump(...) debugos << \" \" << #__VA_ARGS__ << \": \" << \"[\" << __LINE__ \\\n<< \":\" << __FUNCTION__ << \"]\" << newl << \" \", dump_func(__VA_ARGS__)\n#else\n#define dump(...) ((void)0)\n#endif\n\n\n#line 2 \"main.cpp\"\n\nint h, w, n;\nvector<pair<PII, int>> ps; string d;\nvector<int> fall;\n\nint diag(int r, int c) {\n return r + c;\n}\n\n// black -> 1\nbool col(int r, int c) {\n return (r + c) % 2;\n}\n\nint di_left_time(int i, int di) {\n return h - ps[i].first.first;\n}\n\nint di_right_time(int i, int di) {\n return w - ps[i].first.second;\n}\n\nvoid proc(VI& black, VI& white, int di) {\n auto key = [](auto i){return ps[i].first.second;};\n sort(all(black), [&](auto& a, auto& b){return key(a) < key(b); });\n sort(all(white), [&](auto& a, auto& b){return key(a) < key(b); });\n VI total; merge(all(black), all(white), back_inserter(total), [&](auto& a, auto& b){return key(a) < key(b); });\n dump(black, white, total);\n rep(ii, white.size()) {\n chmin(fall[ps[total[ii]].second], di_left_time(white[ii], di));\n }\n reverse(all(total)); reverse(all(black));\n rep(ii, black.size()) {\n chmin(fall[ps[total[ii]].second], di_right_time(black[ii], di));\n }\n}\n\nint main() {\n cin >> w >> h >> n;\n ps.resize(n); d = string(n, '%');\n rep(i, n) cin >> ps[i].first.second >> ps[i].first.first >> d[i];\n rep(i, n) ps[i].first.first--, ps[i].first.second--, ps[i].second = i;\n sort(all(ps), [&](auto a, auto b){\n return diag(a.first.first, a.first.second) < diag(b.first.first, b.first.second);\n });\n fall.assign(n, numeric_limits<int>::max());\n\n for (auto iter = ps.begin(); iter != ps.end();) {\n int di = diag(iter->first.first, iter->first.second);\n int color = col(iter->first.first, iter->first.second);\n dump(di, color);\n VI black[2], white[2];\n for (; iter != ps.end() && di == diag(iter->first.first, iter->first.second); iter++) {\n if (d[iter->second] == 'E') {\n black[iter->first.second & 1].push_back(iter-ps.begin());\n } else {\n white[iter->first.second & 1].push_back(iter-ps.begin());\n }\n }\n if (color) {\n proc(black[0], white[1], di);\n proc(black[1], white[0], di);\n } else {\n proc(black[0], white[0], di);\n proc(black[1], white[1], di);\n }\n }\n dump(ps);\n dump(fall);\n\n vector<PII> ti(n); rep(i, n) ti[i].first = fall[i], ti[i].second = i;\n sort(all(ti));\n\n rep(i, n) cout << ti[i].second+1 << \"\\n\";\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7976, "score_of_the_acc": -0.0508, "final_rank": 1 }, { "submission_id": "aoj_0354_4798390", "code_snippet": "#pragma GCC target (\"avx2\")\n#pragma GCC optimize (\"unroll-loops\")\n#pragma GCC optimize (\"O3\")\n#include \"bits/stdc++.h\"\n#include <unordered_set>\n#include <unordered_map>\n#include <random>\nusing namespace std;\ntypedef long long ll;\nconst ll MOD = 1'000'000'007LL; /*998'244'353LL;*/\n#define pb push_back\n#define mp make_pair\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\nconst int dx[4]={ 1,0,-1,0 };\nconst int dy[4]={ 0,1,0,-1 };\n\nll W, H;\nint N;\nll x[400000], y[400000];\nchar d[400000];\n\nvector<pair<ll, int>> v[800005][2][2]; // →:1,↓:0\nvector<pair<ll, int>> ans;\n\nsigned main(){\n cin >> W >> H >> N;\n rep(i, N){\n cin >> x[i] >> y[i] >> d[i];\n v[x[i]+y[i]][d[i] == 'E'][x[i]%2].pb({ x[i], i });\n }\n\n rep(i, H+W+3){\n rep(j, 2) rep(k, 2) sort(all(v[i][j][k]));\n if(i%2 == 0){ // 白\n rep(k, 2){\n vector<pair<ll, ll>> tmp;\n vector<pair<ll, int>> marge;\n rep(j, v[i][0][k].size()){\n marge.pb(v[i][0][k][j]);\n int idx = v[i][0][k][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[i][1][k].size()){\n marge.pb(v[i][1][k][j]);\n int idx = v[i][1][k][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n else{ // 黒\n rep(k, 2){\n vector<pair<ll, ll>> tmp;\n vector<pair<ll, int>> marge;\n rep(j, v[i][0][k].size()){\n marge.pb(v[i][0][k][j]);\n int idx = v[i][0][k][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[i][1][k^1].size()){\n marge.pb(v[i][1][k^1][j]);\n int idx = v[i][1][k^1][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n }\n sort(all(ans));\n rep(i, N) cout << ans[i].second+1 << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 20, "memory_kb": 78228, "score_of_the_acc": -0.4775, "final_rank": 20 }, { "submission_id": "aoj_0354_4798383", "code_snippet": "#pragma GCC target (\"avx2\")\n#pragma GCC optimize (\"unroll-loops\")\n#pragma GCC optimize (\"O3\")\n#include \"bits/stdc++.h\"\n#include <unordered_set>\n#include <unordered_map>\n#include <random>\nusing namespace std;\ntypedef long long ll;\nconst ll MOD = 1'000'000'007LL; /*998'244'353LL;*/\n#define pb push_back\n#define mp make_pair\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\nconst int dx[4]={ 1,0,-1,0 };\nconst int dy[4]={ 0,1,0,-1 };\n\nll W, H;\nint N;\nint x[200000], y[200000];\nchar d[200000];\n\nvector<pair<int, int>> v[400005][2][2]; // →:1,↓:0\nvector<pair<ll, int>> ans;\n\nsigned main(){\n cin >> W >> H >> N;\n rep(i, N){\n cin >> x[i] >> y[i] >> d[i];\n v[x[i]+y[i]][d[i] == 'E'][x[i]%2].pb({ x[i], i });\n }\n\n rep(i, H+W+3){\n rep(j, 2) rep(k, 2) sort(all(v[i][j][k]));\n if(i%2 == 0){ // 白\n rep(k, 2){\n vector<pair<int, int>> tmp;\n vector<pair<int, int>> marge;\n rep(j, v[i][0][k].size()){\n marge.pb(v[i][0][k][j]);\n int idx = v[i][0][k][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[i][1][k].size()){\n marge.pb(v[i][1][k][j]);\n int idx = v[i][1][k][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n else{ // 黒\n rep(k, 2){\n vector<pair<int, int>> tmp;\n vector<pair<int, int>> marge;\n rep(j, v[i][0][k].size()){\n marge.pb(v[i][0][k][j]);\n int idx = v[i][0][k][j].second;\n tmp.pb({ x[idx],H });\n }\n rep(j, v[i][1][k^1].size()){\n marge.pb(v[i][1][k^1][j]);\n int idx = v[i][1][k^1][j].second;\n tmp.pb({ W,y[idx] });\n }\n sort(all(marge));\n rep(j, marge.size()){\n int idx = marge[j].second;\n ans.pb({ tmp[j].first-x[idx]+tmp[j].second-y[idx], idx });\n }\n }\n }\n }\n sort(all(ans));\n rep(i, N) cout << ans[i].second+1 << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 10, "memory_kb": 40636, "score_of_the_acc": -0.2244, "final_rank": 19 }, { "submission_id": "aoj_0354_4798346", "code_snippet": "#include <map>\n#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint H, W, N;\n\tcin >> W >> H >> N;\n\tvector<int> X(N), Y(N); vector<char> D(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> Y[i] >> X[i] >> D[i]; --Y[i], --X[i];\n\t}\n\tmap<int, vector<int> > g;\n\tfor (int i = 0; i < N; ++i) {\n\t\tg[X[i] + Y[i]].push_back(i);\n\t}\n\tvector<int> ans(N);\n\tfor (pair<int, vector<int> > i : g) {\n\t\tvector<int> ants = i.second;\n\t\tsort(ants.begin(), ants.end(), [&](int va, int vb) { return Y[va] < Y[vb]; });\n\t\tqueue<int> q_even, q_odd;\n\t\tfor (int j : ants) {\n\t\t\tif (D[j] == 'E') {\n\t\t\t\tif (X[j] % 2 == 0) q_even.push(j);\n\t\t\t\telse q_odd.push(j);\n\t\t\t}\n\t\t\telse if (Y[j] % 2 == 0) {\n\t\t\t\tif (q_even.empty()) {\n\t\t\t\t\tans[j] = H - X[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tint u = q_even.front(); q_even.pop();\n\t\t\t\t\tans[u] = (H - X[u]) + (Y[j] - Y[u]);\n\t\t\t\t\tq_even.push(j);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (q_odd.empty()) {\n\t\t\t\t\tans[j] = H - X[j];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tint u = q_odd.front(); q_odd.pop();\n\t\t\t\t\tans[u] = (H - X[u]) + (Y[j] - Y[u]);\n\t\t\t\t\tq_odd.push(j);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j : ants) {\n\t\t\tif (D[j] == 'E') {\n\t\t\t\tif (X[j] % 2 == 0) {\n\t\t\t\t\tint u = q_even.front(); q_even.pop();\n\t\t\t\t\tans[u] = (W - Y[u]) + (X[j] - X[u]);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tint u = q_odd.front(); q_odd.pop();\n\t\t\t\t\tans[u] = (W - Y[u]) + (X[j] - X[u]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<int> perm(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tperm[i] = i;\n\t}\n\tsort(perm.begin(), perm.end(), [&](int i, int j) { return ans[i] != ans[j] ? ans[i] < ans[j] : i < j; });\n\tfor (int i = 0; i < N; ++i) {\n\t\tcout << perm[i] + 1 << '\\n';\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 28152, "score_of_the_acc": -0.2777, "final_rank": 8 }, { "submission_id": "aoj_0354_4798319", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\n\nint ri() {\n\tint n;\n\tscanf(\"%d\", &n);\n\treturn n;\n}\n\nstruct Ant {\n\tint x_y; // x - y\n\tbool dir;\n\tint dtime; // estimated\n\tint id;\n};\n\nint div2(int n) {\n\tif (n % 2 == 0) return n / 2;\n\treturn (n - 1) / 2;\n}\n\nint main() {\n\tint h = ri();\n\tint w = ri();\n\tint n = ri();\n\tstd::map<int, std::vector<Ant> > all;\n\tfor (int i = 0; i < n; i++) {\n\t\tint x = ri() - 1;\n\t\tint y = ri() - 1;\n\t\tstd::string s;\n\t\tstd::cin >> s;\n\t\tall[x + y].push_back({div2(x - y), s[0] == 'S', s[0] == 'S' ? w - y : h - x, i});\n\t}\n\t\n\tstd::map<int, std::vector<int> > res;\n\tauto process = [&] (std::vector<Ant> &a, std::vector<Ant> &b) {\n\t\t/*\n\t\tstd::cerr << \"process\" << std::endl;\n\t\tstd::cerr << \" \";\n\t\tfor (auto i : a) std::cerr << i.x_y << \",\" << i.dir << \",\" << i.dtime << \",\" << i.id << \" \";\n\t\tstd::cerr << std::endl;\n\t\tstd::cerr << \" \";\n\t\tfor (auto i : b) std::cerr << i.x_y << \",\" << i.dir << \",\" << i.dtime << \",\" << i.id << \" \";\n\t\tstd::cerr << std::endl;\n\t\t*/\n\t\t\n\t\tstd::vector<int> dtimes;\n\t\tstd::sort(a.begin(), a.end(), [] (auto i, auto j) { return i.x_y < j.x_y; });\n\t\tstd::sort(b.begin(), b.end(), [] (auto i, auto j) { return i.x_y < j.x_y; });\n\t\tfor (auto i : b) dtimes.push_back(i.dtime);\n\t\tfor (auto i : a) dtimes.push_back(i.dtime);\n\t\t\n\t\tstd::vector<Ant> all = a;\n\t\tfor (auto i : b) all.push_back(i);\n\t\tstd::sort(all.begin(), all.end(), [] (auto i, auto j) { return i.x_y < j.x_y; });\n\t\t\n\t\tfor (int i = 0; i < (int) all.size(); i++) res[dtimes[i]].push_back(all[i].id);\n\t};\n\t\n\tfor (auto &i : all) {\n\t\tstd::vector<Ant> ants[2][2];\n\t\tfor (auto j : i.second) {\n\t\t\tants[j.dir][(j.x_y % 2 + 2) % 2].push_back(j);\n\t\t}\n\t\tif (i.first & 1) { // different -> collide\n\t\t\tprocess(ants[0][0], ants[1][1]);\n\t\t\tprocess(ants[0][1], ants[1][0]);\n\t\t} else { // same -> collide\n\t\t\tprocess(ants[0][0], ants[1][0]);\n\t\t\tprocess(ants[0][1], ants[1][1]);\n\t\t}\n\t}\n\tfor (auto &i : res) {\n\t\tstd::sort(i.second.begin(), i.second.end());\n\t\tfor (auto j : i.second) printf(\"%d\\n\", j + 1);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 47008, "score_of_the_acc": -0.4823, "final_rank": 13 }, { "submission_id": "aoj_0354_4798299", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<unordered_map>\n#include<functional>\n#include<map>\n#include<iomanip>\n#include<limits>\n#include<unordered_set>\n#include<cmath>\n#include <numeric>\n#include <array>\n#include<utility>\n#include <complex>\nusing namespace std;\n#pragma region define\n//#define M_PI 3.141592653589793238\n#define upperbound(v,val) upper_bound(v.begin(),v.end(),val)-v.begin()\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)-v.begin()\n#define int long long\n#define ll long long\n#define vel vector<ll>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp(a,b) make_pair(a,b)\n#define pin pair<ll,ll>\n#define qin pair<pin,ll>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define fcout cout << fixed << setprecision(15)\n#define rev(s) reverse(s.begin(),s.end())\n#define lower(h,val) (lower_bound(h.begin(),h.end(),val)-h.begin())\n#define upper(h,val) (upper_bound(h.begin(),h.end(),val)-h.begin())\n#define vveb V<veb>\n#define omajinai cin.tie(0);ios::sync_with_stdio(false);\n#define endl \"\\n\"\n#define pb push_back\n#pragma endregion\n#pragma region Inner Class\nint root(int x, vel& pa) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x], pa); pa[x] = ans;\n\treturn ans;\n}\nbool mar(int x, int y, vel& pa) {\n\tx = root(x, pa);\n\ty = root(y, pa);\n\tif (x != y) { pa[x] = y; }\n\treturn (x != y);\n}\nint gcd(int x, int y) {\n\tif (x < y) { return gcd(y, x); }\n\tif (y == 0) { return x; }\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\tx = abs(x); y = abs(y);\n\treturn x * (y / gcd(x, y));\n}\nV<ll> dijk(V<V<pin>> way, int st, ll inf) {\n\tint n = way.size();\n\tV<ll> dist(n, inf); dist[st] = 0;\n\tpriority_queue<pin, vector<pin>, greater<pin>> pq;\n\tpq.push(mkp(0, st));\n\tveb is_checked(n, false);\n\twhile (!pq.empty()) {\n\t\tpin x = pq.top(); pq.pop();\n\t\tint pot = x.second;\n\t\tif (!is_checked[pot]) {\n\t\t\tis_checked[pot] = true;\n\t\t\tfor (auto y : way[pot]) {\n\t\t\t\tll nex_dist = x.first + y.second;\n\t\t\t\tint nex_pot = y.first;\n\t\t\t\tif (dist[nex_pot] > nex_dist) {\n\t\t\t\t\tdist[nex_pot] = nex_dist;\n\t\t\t\t\tpq.push(mkp(nex_dist, y.first));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn dist;\n}\nint inf = 1234567890;\nV<V<pin>> make_w(vvel v) {\n\tint n = v.size();\n\tV<V<pin>> ret(n);\n\trep(i, n) {\n\t\tfor (int x : v[i]) {\n\t\t\tret[i].push_back(mkp(x, 1));\n\t\t}\n\t}\n\treturn ret;\n}\nvoid make_tree(vvel& chi, V<pin>& par, int n, V<V<pin>>& way) {\n\tV<ll> dist = dijk(way, 0, inf * inf);\n\tpar = V<pin>(n, mkp(0, 0));\n\tchi = vvel(n);\n\trep(i, n) {\n\t\tfor (auto nex : way[i]) {\n\t\t\tint pot = nex.first;\n\t\t\tif (dist[pot] > dist[i]) { chi[i].push_back(pot); }\n\t\t\telse { par[i] = mkp(pot, dist[i] - dist[pot]); }\n\t\t}\n\t}\n}\nvoid pri(vel& v) {\n\tif (v.size() == 0) { return; }\n\tcout << v[0];\n\trep(i, v.size() - 1) { cout << \" \" << v[i + 1]; }\n\tcout << endl;\n\treturn;\n}\nvvel disj_min(vel& v) {\n\tint n = v.size();\n\tvvel ret(22, vel(n));\n\tret[0] = v;\n\trep(i, 21) {\n\t\trep(j, n) {\n\t\t\tint nex = j + (1 << i);\n\t\t\tif (nex < n) {\n\t\t\t\tret[i + 1][j] = min(ret[i][j], ret[i][nex]);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tret[i + 1][j] = ret[i][j];\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nint find_min(vvel& dv, int l, int r) {\n\tint i = 21;\n\twhile (l + (1 << i) > r) {\n\t\ti--;\n\t}\n\twhile (i >= 0) {\n\t\tif (dv[i][l] > dv[i][r - (1 << i)]) {\n\t\t\tl = r - (1 << i);\n\t\t}\n\t\telse {\n\t\t\tr = l + (1 << i);\n\t\t}\n\t\ti--;\n\t}\n\treturn l;\n}\nV<V<pin>> dbl(V<pin>& v) {\n\tV<V<pin>> ans(20, V<pin>(v));\n\tint n = v.size();\n\trep(i, 19) {\n\t\trep(j, n) {\n\t\t\tans[i + 1][j].first = ans[i][ans[i][j].first].first;\n\t\t\tans[i + 1][j].second = max(ans[i][j].second, ans[i][ans[i][j].first].second);\n\t\t}\n\t}\n\treturn ans;\n}\npin lca(int s, int t, int diff, V<V<pin>>& pa) {\n\tif (diff < 0) { return lca(t, s, -diff, pa); }\n\tint ans = 0;\n\trep(i, 19) {\n\t\tif ((diff & (1 << i)) != 0) {\n\t\t\tmmax(ans, pa[i][s].second);\n\t\t\ts = pa[i][s].first;\n\t\t}\n\t}\n\tfor (int i = 19; i >= 0; i--) {\n\t\tif (pa[i][s] != pa[i][t]) {\n\t\t\tmmax(ans, pa[i][s].second);\n\t\t\ts = pa[i][s].first;\n\t\t\tmmax(ans, pa[i][t].second);\n\t\t\tt = pa[i][t].first;\n\t\t}\n\t}\n\tif (s != t) {\n\t\tmmax(ans, pa[0][s].second);\n\t\tmmax(ans, pa[0][t].second);\n\t\ts = pa[0][s].first;\n\t}\n\treturn mkp(s, ans);\n}\n\nvel dx = { 0,0,-1,1,1,-1 };\nvel dy = { 1,-1,0,0,1,1 };\n#define all(a) a.begin(),a.end()\ntemplate<typename T>\nvoid mk_uni(V<T>& a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\n#pragma endregion\n\n\n\nsigned main() {\n\tint h, w, n; cin >> w >> h >> n;\n\tvel x(n), y(n); veb d(n,true);\n\tV<pin> lis(n);\n\trep(i, n) { \n\t\tcin >> x[i] >> y[i];\n\t\tchar a; cin >> a;\n\t\tint qx = x[i];\n\t\tif (a == 'E') { \n\t\t\td[i] = false;\n\t\t\tif ((x[i] + y[i]) % 2 == 1) { qx++; }\n\t\t}\n\t\tif (qx % 2 == 0) {lis[i] = mkp(x[i] + y[i], i);}\n\t\telse {lis[i] = mkp(x[i] + y[i] + 2 * (h + w), i);}\n\t}\n\tsor(lis);\n\tint pot = 0;\n\tV<pin> ans;\n\twhile (pot < n) {\n\t\tint now_pl = lis[pot].first;\n\t\tV<pin> al_x;\n\t\tvel al_e;\n\t\tvel al_s;\n\t\twhile (pot < n) {\n\t\t\tif (now_pl != lis[pot].first) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint num = lis[pot].second;\n\t\t\tal_x.push_back(mkp(x[num],num));\n\t\t\tif (d[num]) { al_s.push_back(h - y[num]); }\n\t\t\telse { al_e.push_back(w - x[num]); }\n\t\t\tpot++;\n\t\t}\n\t\tsor(al_x); sor(al_e); sor(al_s);\n\t\tint sz = al_x.size();\n\t\tint szs = al_s.size();\n\t\trep(i,sz) {\n\t\t\tint num = al_x[i].second;\n\t\t\tif (i < szs) {\n\t\t\t\tans.push_back(mkp(al_s[i], num));\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans.push_back(mkp(al_e[sz - 1 - i], num));\n\t\t\t}\n\t\t}\n\t}\n\tsor(ans);\n\tfor (auto b : ans) { cout << b.second + 1 << endl; }\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 20972, "score_of_the_acc": -0.1968, "final_rank": 6 }, { "submission_id": "aoj_0354_4798286", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<unordered_map>\n#include<functional>\n#include<map>\n#include<iomanip>\n#include<limits>\n#include<unordered_set>\n#include<cmath>\n#include <numeric>\n#include <array>\n#include<utility>\n#include <complex>\nusing namespace std;\n#pragma region define\n//#define M_PI 3.141592653589793238\n#define upperbound(v,val) upper_bound(v.begin(),v.end(),val)-v.begin()\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)-v.begin()\n#define ll long long\n#define vel vector<int>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp(a,b) make_pair(a,b)\n#define pin pair<int,int>\n#define qin pair<pin,int>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define fcout cout << fixed << setprecision(15)\n#define rev(s) reverse(s.begin(),s.end())\n#define lower(h,val) (lower_bound(h.begin(),h.end(),val)-h.begin())\n#define upper(h,val) (upper_bound(h.begin(),h.end(),val)-h.begin())\n#define vveb V<veb>\n#define omajinai cin.tie(0);ios::sync_with_stdio(false);\n#define endl \"\\n\"\n#define pb push_back\n#pragma endregion\n#pragma region Inner Class\nint root(int x, vel& pa) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x], pa); pa[x] = ans;\n\treturn ans;\n}\nbool mar(int x, int y, vel& pa) {\n\tx = root(x, pa);\n\ty = root(y, pa);\n\tif (x != y) { pa[x] = y; }\n\treturn (x != y);\n}\nint gcd(int x, int y) {\n\tif (x < y) { return gcd(y, x); }\n\tif (y == 0) { return x; }\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\tx = abs(x); y = abs(y);\n\treturn x * (y / gcd(x, y));\n}\nV<ll> dijk(V<V<pin>> way, int st, ll inf) {\n\tint n = way.size();\n\tV<ll> dist(n, inf); dist[st] = 0;\n\tpriority_queue<pin, vector<pin>, greater<pin>> pq;\n\tpq.push(mkp(0, st));\n\tveb is_checked(n, false);\n\twhile (!pq.empty()) {\n\t\tpin x = pq.top(); pq.pop();\n\t\tint pot = x.second;\n\t\tif (!is_checked[pot]) {\n\t\t\tis_checked[pot] = true;\n\t\t\tfor (auto y : way[pot]) {\n\t\t\t\tll nex_dist = x.first + y.second;\n\t\t\t\tint nex_pot = y.first;\n\t\t\t\tif (dist[nex_pot] > nex_dist) {\n\t\t\t\t\tdist[nex_pot] = nex_dist;\n\t\t\t\t\tpq.push(mkp(nex_dist, y.first));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn dist;\n}\nint inf = 1234567890;\nV<V<pin>> make_w(vvel v) {\n\tint n = v.size();\n\tV<V<pin>> ret(n);\n\trep(i, n) {\n\t\tfor (int x : v[i]) {\n\t\t\tret[i].push_back(mkp(x, 1));\n\t\t}\n\t}\n\treturn ret;\n}\nvoid make_tree(vvel& chi, V<pin>& par, int n, V<V<pin>>& way) {\n\tV<ll> dist = dijk(way, 0, inf * inf);\n\tpar = V<pin>(n, mkp(0, 0));\n\tchi = vvel(n);\n\trep(i, n) {\n\t\tfor (auto nex : way[i]) {\n\t\t\tint pot = nex.first;\n\t\t\tif (dist[pot] > dist[i]) { chi[i].push_back(pot); }\n\t\t\telse { par[i] = mkp(pot, dist[i] - dist[pot]); }\n\t\t}\n\t}\n}\nvoid pri(vel& v) {\n\tif (v.size() == 0) { return; }\n\tcout << v[0];\n\trep(i, v.size() - 1) { cout << \" \" << v[i + 1]; }\n\tcout << endl;\n\treturn;\n}\nvvel disj_min(vel& v) {\n\tint n = v.size();\n\tvvel ret(22, vel(n));\n\tret[0] = v;\n\trep(i, 21) {\n\t\trep(j, n) {\n\t\t\tint nex = j + (1 << i);\n\t\t\tif (nex < n) {\n\t\t\t\tret[i + 1][j] = min(ret[i][j], ret[i][nex]);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tret[i + 1][j] = ret[i][j];\n\t\t\t}\n\t\t}\n\t}\n\treturn ret;\n}\nint find_min(vvel& dv, int l, int r) {\n\tint i = 21;\n\twhile (l + (1 << i) > r) {\n\t\ti--;\n\t}\n\twhile (i >= 0) {\n\t\tif (dv[i][l] > dv[i][r - (1 << i)]) {\n\t\t\tl = r - (1 << i);\n\t\t}\n\t\telse {\n\t\t\tr = l + (1 << i);\n\t\t}\n\t\ti--;\n\t}\n\treturn l;\n}\nV<V<pin>> dbl(V<pin>& v) {\n\tV<V<pin>> ans(20, V<pin>(v));\n\tint n = v.size();\n\trep(i, 19) {\n\t\trep(j, n) {\n\t\t\tans[i + 1][j].first = ans[i][ans[i][j].first].first;\n\t\t\tans[i + 1][j].second = max(ans[i][j].second, ans[i][ans[i][j].first].second);\n\t\t}\n\t}\n\treturn ans;\n}\npin lca(int s, int t, int diff, V<V<pin>>& pa) {\n\tif (diff < 0) { return lca(t, s, -diff, pa); }\n\tint ans = 0;\n\trep(i, 19) {\n\t\tif ((diff & (1 << i)) != 0) {\n\t\t\tmmax(ans, pa[i][s].second);\n\t\t\ts = pa[i][s].first;\n\t\t}\n\t}\n\tfor (int i = 19; i >= 0; i--) {\n\t\tif (pa[i][s] != pa[i][t]) {\n\t\t\tmmax(ans, pa[i][s].second);\n\t\t\ts = pa[i][s].first;\n\t\t\tmmax(ans, pa[i][t].second);\n\t\t\tt = pa[i][t].first;\n\t\t}\n\t}\n\tif (s != t) {\n\t\tmmax(ans, pa[0][s].second);\n\t\tmmax(ans, pa[0][t].second);\n\t\ts = pa[0][s].first;\n\t}\n\treturn mkp(s, ans);\n}\n\nvel dx = { 0,0,-1,1,1,-1 };\nvel dy = { 1,-1,0,0,1,1 };\n#define all(a) a.begin(),a.end()\ntemplate<typename T>\nvoid mk_uni(V<T>& a) {\n\tstd::sort(a.begin(), a.end());\n\ta.erase(std::unique(a.begin(), a.end()), a.end());\n}\n#pragma endregion\n\n\n\nsigned main() {\n\tint h, w, n; cin >> w >> h >> n;\n\tvel x(n), y(n); veb d(n,true);\n\tV<pin> lis(n);\n\trep(i, n) { \n\t\tcin >> x[i] >> y[i];\n\t\tchar a; cin >> a;\n\t\tint qx = x[i];\n\t\tif (a == 'E') { \n\t\t\td[i] = false;\n\t\t\tif ((x[i] + y[i]) % 2 == 1) { qx++; }\n\t\t}\n\t\tif (qx % 2 == 0) {lis[i] = mkp(x[i] + y[i], i);}\n\t\telse {lis[i] = mkp(x[i] + y[i] + 2 * (h + w), i);}\n\t}\n\tsor(lis);\n\tint pot = 0;\n\tV<pin> ans;\n\twhile (pot < n) {\n\t\tint now_pl = lis[pot].first;\n\t\tV<pin> al_x;\n\t\tvel al_e;\n\t\tvel al_s;\n\t\twhile (pot < n) {\n\t\t\tif (now_pl != lis[pot].first) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint num = lis[pot].second;\n\t\t\tal_x.push_back(mkp(x[num],num));\n\t\t\tif (d[num]) { al_s.push_back(h - y[num]); }\n\t\t\telse { al_e.push_back(w - x[num]); }\n\t\t\tpot++;\n\t\t}\n\t\tsor(al_x); sor(al_e); sor(al_s);\n\t\tint sz = al_x.size();\n\t\tint szs = al_s.size();\n\t\trep(i,sz) {\n\t\t\tint num = al_x[i].second;\n\t\t\tif (i < szs) {\n\t\t\t\tans.push_back(mkp(al_s[i], num));\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans.push_back(mkp(al_e[sz - 1 - i], num));\n\t\t\t}\n\t\t}\n\t}\n\tsor(ans);\n\tfor (auto b : ans) { cout << b.second + 1 << endl; }\n\treturn 0;\n}", "accuracy": 0.7916666666666666, "time_ms": 160, "memory_kb": 8072, "score_of_the_acc": -0.1123, "final_rank": 18 }, { "submission_id": "aoj_0354_4647243", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int w, h, n;\n cin >> w >> h >> n;\n vector<int> zxy(n);\n vector<array<int, 4>> ant(n);\n for (int i = 0; i < n; ++i) {\n int x, y; char c;\n cin >> x >> y >> c;\n zxy.emplace_back(x+y);\n ant[i] = {x, y, c == 'S', i};\n }\n vector<int> ans(n);\n sort(zxy.begin(), zxy.end());\n zxy.erase(unique(zxy.begin(), zxy.end()), zxy.end());\n vector<vector<array<int, 4>>> ants(zxy.size());\n for (int i = 0; i < n; ++i) {\n int x = lower_bound(zxy.begin(),zxy.end(), ant[i][0]+ant[i][1]) - zxy.begin();\n ants[x].emplace_back(ant[i]);\n }\n for (int i = 0; i < zxy.size(); ++i) {\n int c = zxy[i]&1;\n sort(ants[i].begin(),ants[i].end());\n vector<queue<int>> a(2);\n for (auto &&e : ants[i]) {\n if(e[2]){\n int k = (e[1]&1)^c;\n a[k].emplace(e[3]);\n int tmp = a[k].front(); a[k].pop();\n ans[tmp] = h-e[1];\n }else {\n a[e[1]&1].emplace(e[3]);\n }\n }\n for (auto &&e : ants[i]) {\n if(!e[2]){\n int k = (e[1]&1);\n a[k].emplace(e[3]);\n int tmp = a[k].front(); a[k].pop();\n ans[tmp] = w-e[0];\n }\n }\n }\n vector<int> perm(n);\n iota(perm.begin(),perm.end(), 0);\n sort(perm.begin(),perm.end(), [&](int x, int y){\n if(ans[x] != ans[y]) return ans[x] < ans[y];\n else return x < y;\n });\n for (auto &&j : perm) {\n printf(\"%d\\n\", j+1);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 20052, "score_of_the_acc": -0.2516, "final_rank": 7 }, { "submission_id": "aoj_0354_4557031", "code_snippet": "#include <bits/stdc++.h>\n#define _ pair<pair<int,int>,int>\nusing namespace std;\nvector<_> A,B,C,D,v1,v2;\npair<int,int> a[200005];\n_ b[200005],c[200005];\nint cnt1,cnt2,n,i,j,x,y,m,k;\nchar kitu;\nint T(_ x)\n{\n return x.first.first+x.first.second;\n}\nbool cmp(_ x,_ y)\n{\n if (T(x)==T(y)) return x.first.first>y.first.first;\n return T(x)<T(y);\n}\nvoid xuly()\n{\n //if (A.empty() || B.empty()) return;\n //cout<<A.size()<<' '<<B.size()<<endl;\n C.clear();\n int i,j;i=j=0;\n while (i<A.size() && j<B.size())\n {\n if (A[i].first.first>B[j].first.first) {C.push_back(A[i]);i++;}\n else {C.push_back(B[j]);j++;}\n }\n while (i<A.size()) {C.push_back(A[i]);i++;}\n while (j<B.size()) {C.push_back(B[j]);j++;}\n D.clear();\n for (int i=0;i<A.size();++i) D.push_back(A[i]);\n for (int j=0;j<B.size();++j) D.push_back(B[j]);\n for (int i=0;i<C.size();++i) a[D[i].second].second=C[i].second;\n}\nvoid tach()\n{\n\n if (x%2==0)\n {\n\n A.clear();B.clear();\n for (int i=0;i<v1.size();++i) if (v1[i].first.first%2==0) A.push_back(v1[i]);\n for (int i=0;i<v2.size();++i) if (v2[i].first.first%2==0) B.push_back(v2[i]);\n xuly();\n A.clear();B.clear();\n for (int i=0;i<v1.size();++i) if (v1[i].first.first%2) A.push_back(v1[i]);\n for (int i=0;i<v2.size();++i) if (v2[i].first.first%2) B.push_back(v2[i]);\n xuly();\n }\n else\n {\n A.clear();B.clear();\n for (int i=0;i<v1.size();++i) if (v1[i].first.first%2==0) A.push_back(v1[i]);\n for (int i=0;i<v2.size();++i) if (v2[i].first.first%2) B.push_back(v2[i]);\n xuly();\n A.clear();B.clear();\n for (int i=0;i<v1.size();++i) if (v1[i].first.first%2) A.push_back(v1[i]);\n for (int i=0;i<v2.size();++i) if (v2[i].first.first%2==0) B.push_back(v2[i]);\n xuly();\n }\n\n}\nint main()\n{\n ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n cin>>n>>m>>k;\n for (int i=1;i<=k;++i)\n {\n cin>>y>>x;\n cin>>kitu;\n if (kitu=='S')\n {\n a[i].first=m-x;\n b[++cnt1]={{x,y},i};\n }\n else\n {\n a[i].first=n-y;\n c[++cnt2]={{x,y},i};\n }\n a[i].second=i;\n }\n sort(b+1,b+cnt1+1,cmp);\n sort(c+1,c+cnt2+1,cmp);\n i=1;j=1;\n while (i<=cnt1)\n {\n v1.clear();\n v2.clear();\n v1.push_back(b[i]);x=T(b[i]);\n i++;\n while (i<=cnt1 && T(b[i])==x) {v1.push_back(b[i]);i++;}\n while (j<=cnt2 && T(c[j])<x) j++;\n while (j<=cnt2 && T(c[j])==x)\n {\n v2.push_back(c[j]);j++;\n }\n\n tach();\n }\n // for (int i=1;i<=k;++i) cout<<a[i].first<<' '<<a[i].second<<endl;\n sort(a+1,a+k+1);\n for (int i=1;i<=k;++i) cout<<a[i].second<<'\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 20680, "score_of_the_acc": -0.1341, "final_rank": 4 }, { "submission_id": "aoj_0354_3968321", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\nenum class Direction: char {\n\tEast, South\n};\nstd::istream& operator>>(std::istream& is, Direction& dir) {\n\tchar c; is >> c;\n\tswitch (c) {\n\tcase 'E': dir = Direction::East; break;\n\tcase 'S': dir = Direction::South; break;\n\tdefault: throw 0;\n\t}\n\treturn is;\n}\nstruct Ant {\n\tint x, y, id;\n\tDirection dir;\n\tint time_until_drop(int w, int h) const {\n\t\tswitch (dir) {\n\t\tcase Direction::East: return w - x + 1;\n\t\tcase Direction::South: return h - y + 1;\n\t\tdefault: throw 0;\n\t\t}\n\t}\n};\nint main() {\n\tint w, h, n; std::cin >> w >> h >> n;\n\tstd::vector<Ant> ants(n);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tants[i].id = i + 1;\n\t\tstd::cin >> ants[i].x >> ants[i].y >> ants[i].dir;\n\t}\n\tstd::sort(ants.begin(), ants.end(), [](const Ant& a, const Ant& b) {return (a.y + a.x == b.y + b.x) ? a.x < b.x : a.y + a.x < b.y + b.x; });\n\tstd::vector<std::queue<int>> queue(2);\n\tfor (auto current = ants.begin(); current != ants.end(); ) {\n\t\tauto last = std::upper_bound(current, ants.end(), current->y + current->x, [](const int val, const Ant& a) {return val < a.y + a.x; });\n\t\tfor (auto itr = current; itr != last; ++itr) {\n\t\t\tswitch (itr->dir) {\n\t\t\tcase Direction::South:\n\t\t\t\tif (!queue[itr->y % 2].empty()) {\n\t\t\t\t\tqueue[itr->y % 2].push(itr->id);\n\t\t\t\t\titr->id = queue[itr->y % 2].front(); queue[itr->y % 2].pop();\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\tcase Direction::East: queue[itr->x % 2].push(itr->id); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t\tfor (; current != last; ++current) {\n\t\t\tswitch (current->dir) {\n\t\t\tcase Direction::South: break;\n\t\t\tcase Direction::East: current->id = queue[current->x % 2].front(); queue[current->x % 2].pop(); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t}\n\tstd::sort(ants.begin(), ants.end(), [w, h](const Ant& a, const Ant& b) {return (a.time_until_drop(w, h) == b.time_until_drop(w, h)) ? a.id < b.id : a.time_until_drop(w, h) < b.time_until_drop(w, h); });\n\tfor (const auto& ant : ants) std::cout << ant.id << '\\n';\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 6492, "score_of_the_acc": -0.1087, "final_rank": 3 }, { "submission_id": "aoj_0354_3968309", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n\nenum class Direction: char {\n\tEast, South\n};\nstd::istream& operator>>(std::istream& is, Direction& dir) {\n\tchar c; is >> c;\n\tswitch (c) {\n\tcase 'E': dir = Direction::East; break;\n\tcase 'S': dir = Direction::South; break;\n\tdefault: throw 0;\n\t}\n\treturn is;\n}\nstruct Ant {\n\tint x, y, id;\n\tDirection dir;\n\tint time_until_drop(int w, int h) const {\n\t\tswitch (dir) {\n\t\tcase Direction::East: return w - x + 1;\n\t\tcase Direction::South: return h - y + 1;\n\t\tdefault: throw 0;\n\t\t}\n\t}\n};\nint main() {\n\tint w, h, n; std::cin >> w >> h >> n;\n\tstd::vector<Ant> ants(n);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tants[i].id = i + 1;\n\t\tstd::cin >> ants[i].x >> ants[i].y >> ants[i].dir;\n\t}\n\tstd::sort(ants.begin(), ants.end(), [](const Ant& a, const Ant& b) {return (a.y + a.x == b.y + b.x) ? a.x < b.x : a.y + a.x < b.y + b.x; });\n\tstd::vector<std::queue<int>> queue(2);\n\tfor (auto current = ants.begin(); current != ants.end(); ) {\n\t\tauto last = std::upper_bound(current, ants.end(), current->y + current->x, [](const int val, const Ant& a) {return val < a.y + a.x; });\n\t\tconst auto parity = (current->x + current->y) % 2;\n\t\tfor (auto itr = current; itr != last; ++itr) {\n\t\t\tswitch (itr->dir) {\n\t\t\tcase Direction::South:\n\t\t\t\tif (!queue[(itr->x + parity) % 2].empty()) {\n\t\t\t\t\tqueue[(itr->x + parity) % 2].push(itr->id);\n\t\t\t\t\titr->id = queue[(itr->x + parity) % 2].front(); queue[(itr->x + parity) % 2].pop();\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\tcase Direction::East: queue[itr->x % 2].push(itr->id); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t\tfor (; current != last; ++current) {\n\t\t\tswitch (current->dir) {\n\t\t\tcase Direction::South: break;\n\t\t\tcase Direction::East: current->id = queue[current->x % 2].front(); queue[current->x % 2].pop(); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t}\n\tstd::sort(ants.begin(), ants.end(), [w, h](const Ant& a, const Ant& b) {return (a.time_until_drop(w, h) == b.time_until_drop(w, h)) ? a.id < b.id : a.time_until_drop(w, h) < b.time_until_drop(w, h); });\n\tfor (const auto& ant : ants) std::cout << ant.id << '\\n';\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 6420, "score_of_the_acc": -0.1082, "final_rank": 2 }, { "submission_id": "aoj_0354_3968248", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n\n\n\nenum class Direction {\n\tEast, South\n};\nstd::istream& operator>>(std::istream& is, Direction& dir) {\n\tchar c; is >> c;\n\tswitch (c) {\n\tcase 'E': dir = Direction::East; break;\n\tcase 'S': dir = Direction::South; break;\n\tdefault: throw 0;\n\t}\n\treturn is;\n}\nstruct Ant {\n\tint x, y, id;\n\tDirection dir;\n\tint time_until_drop(int w, int h) const {\n\t\tswitch (dir) {\n\t\tcase Direction::East: return w - x + 1;\n\t\tcase Direction::South: return h - y + 1;\n\t\tdefault: throw 0;\n\t\t}\n\t}\n\tbool is_on_black() const { return (x + y) % 2 == 1; }\n};\nint main() {\n\tint w, h, n; std::cin >> w >> h >> n;\n\tstd::vector<Ant> ants(n);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tants[i].id = i + 1;\n\t\tstd::cin >> ants[i].x >> ants[i].y >> ants[i].dir;\n\t}\n\tstd::sort(ants.begin(), ants.end(), [](const Ant& a, const Ant& b) {return (a.y + a.x == b.y + b.x) ? a.x < b.x : a.y + a.x < b.y + b.x; });\n\tfor (auto current = ants.begin(); current != ants.end(); ) {\n\t\tauto last = std::upper_bound(current, ants.end(), current->y + current->x, [](const int val, const Ant& a) {return val < a.y + a.x; });\n\t\tconst auto parity = (current->x + current->y) % 2;\n\t\tstd::vector<std::queue<int>> queue(2);\n\t\tfor (auto itr = current; itr != last; ++itr) {\n\t\t\tswitch (itr->dir) {\n\t\t\tcase Direction::South:\n\t\t\t\tif (!queue[(itr->x + parity) % 2].empty()) {\n\t\t\t\t\tqueue[(itr->x + parity) % 2].push(itr->id);\n\t\t\t\t\titr->id = queue[(itr->x + parity) % 2].front(); queue[(itr->x + parity) % 2].pop();\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\tcase Direction::East: queue[itr->x % 2].push(itr->id); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t\tfor (; current != last; ++current) {\n\t\t\tswitch (current->dir) {\n\t\t\tcase Direction::South: break;\n\t\t\tcase Direction::East: current->id = queue[current->x % 2].front(); queue[current->x % 2].pop(); break;\n\t\t\tdefault: throw 0;\n\t\t\t}\n\t\t}\n\t}\n\tstd::sort(ants.begin(), ants.end(), [w, h](const Ant& a, const Ant& b) {return (a.time_until_drop(w, h) == b.time_until_drop(w, h)) ? a.id < b.id : a.time_until_drop(w, h) < b.time_until_drop(w, h); });\n\tfor (const auto& ant : ants) std::cout << ant.id << '\\n';\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 6408, "score_of_the_acc": -0.1486, "final_rank": 5 }, { "submission_id": "aoj_0354_3959313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\nint w, h, n;\nint x[200010];\nint y[200010];\nchar d[200010];\n\nmap<int, int> zip;\nvector<pair<int, int> > member[200010];\n\nint id[200010];\n\nsigned main(){\n cin >> w >> h >> n;\n vector<int> vec;\n\n {\n for(int i = 0;i < n;i++){\n cin >> x[i] >> y[i] >> d[i];\n vec.push_back(y[i]+x[i]);\n }\n\n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n\n for(int i = 0;i < vec.size();i++){\n zip[vec[i]] = i;\n }\n }\n\n for(int i = 0;i < n;i++){\n member[zip[y[i]+x[i]]].push_back(make_pair(x[i], i));\n }\n\n for(int i = 0;i < vec.size();i++){\n sort(member[i].begin(), member[i].end(), greater<pair<int, int> >());\n\n queue<int> que1;\n queue<int> que2;\n\n queue<int> ans;\n\n for(int j = 0;j < member[i].size();j++){\n int idx = member[i][j].second;\n if(d[idx] == 'S'){\n if(x[idx] % 2 == 0){\n que1.push(idx);\n }else{\n que2.push(idx);\n }\n }else{\n if((y[idx]+x[idx])%2 == 0){\n if(x[idx]%2 == 0){\n que1.push(idx);\n ans.push(que1.front());\n que1.pop();\n }else{\n que2.push(idx);\n ans.push(que2.front());\n que2.pop();\n }\n }else{\n if(x[idx]%2 == 1){\n que1.push(idx);\n ans.push(que1.front());\n que1.pop();\n }else{\n que2.push(idx);\n ans.push(que2.front());\n que2.pop();\n }\n }\n }\n }\n\n for(int j = 0;j < member[i].size();j++){\n int idx = member[i][j].second;\n if(d[idx] == 'S'){\n if(x[idx] % 2 == 0){\n id[idx] = que1.front();\n que1.pop();\n }else{\n id[idx] = que2.front();\n que2.pop();\n }\n }else{\n id[idx] = ans.front();\n ans.pop();\n }\n }\n }\n\n priority_queue<pair<int, int> > ans;\n\n for(int i = 0;i < n;i++){\n if(d[i] == 'S'){\n ans.push(make_pair(-(h-y[i]), -id[i]));\n }else{\n ans.push(make_pair(-(w-x[i]), -id[i]));\n }\n }\n\n while(!ans.empty()){\n cout << -ans.top().second+1 << endl;\n ans.pop();\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 570, "memory_kb": 36912, "score_of_the_acc": -0.5783, "final_rank": 14 }, { "submission_id": "aoj_0354_3240146", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <tuple>\n#include <algorithm>\nusing namespace std;\n#pragma warning (disable: 4996)\n\nint W, H, N, x[200009], y[200009], ans[200009]; char c[200009]; bool used[200009];\nmap<int, vector<tuple<int, char, int>>>vec; vector<int>K;\n\nvoid solve(int pos) {\n\tvector<tuple<int, char, int>>tup = vec[pos];\n\tsort(tup.begin(), tup.end());\n\n\tvector<pair<int, int>> GX, GY;\n\tfor (int i = 0; i < tup.size(); i++) {\n\t\tif (get<1>(tup[i]) == 'E') GX.push_back(make_pair(i, get<2>(tup[i])));\n\t\tif (get<1>(tup[i]) == 'A') GY.push_back(make_pair(i, get<2>(tup[i])));\n\t}\n\n\tfor (int i = 0; i < GX.size(); i++) {\n\t\tint T1 = i, T2 = lower_bound(GY.begin(), GY.end(), make_pair(GX[i].first, 0)) - GY.begin(); int KOSUU = GY.size() - T2;\n\t\tif (T1 < KOSUU) {\n\t\t\tans[GY[T2 + T1].second] = GX[i].second;\n\t\t}\n\t\telse {\n\t\t\tans[GX[T1 - KOSUU].second] = GX[i].second;\n\t\t}\n\t}\n\tfor (int i = 0; i < GY.size(); i++) {\n\t\tint T1 = i, T2 = lower_bound(GX.begin(), GX.end(), make_pair(GY[i].first, 0)) - GX.begin(); int KOSUU = GY.size() - T1 - 1;\n\t\tif (KOSUU < T2) {\n\t\t\tans[GX[(T2 - 1) - KOSUU].second] = GY[i].second;\n\t\t}\n\t\telse {\n\t\t\tans[GY[T1 + T2].second] = GY[i].second;\n\t\t}\n\t}\n}\n\nint main() {\n\tcin >> W >> H >> N;\n\tfor (int i = 1; i <= N; i++) {\n\t\tcin >> x[i] >> y[i] >> c[i]; if (c[i] == 'S') c[i] = 'A';\n\t\tint ID = x[i] + y[i];\n\t\tif ((x[i] + y[i]) % 2 == 1) {\n\t\t\tif (c[i] == 'E') x[i]--;\n\t\t\tif (c[i] == 'A') y[i]--;\n\t\t\tused[i] = true;\n\t\t}\n\t\tif (x[i] % 2 == 1) ID += (H + W);\n\t\tvec[ID].push_back(make_tuple(x[i], c[i], i));\n\t\tK.push_back(ID);\n\t}\n\tsort(K.begin(), K.end()); K.erase(unique(K.begin(), K.end()), K.end());\n\n\tfor (int i = 0; i < K.size(); i++) solve(K[i]);\n\tfor (int i = 1; i <= N; i++) { if (ans[i] == 0) ans[i] = i; } // i 番ルートを通る蟻の番号\n\n\tvector<pair<int, int>>ret;\n\tfor (int i = 1; i <= N; i++) {\n\t\tint G = 1; if (used[i] == true) G = 0;\n\t\tif (c[i] == 'E') ret.push_back(make_pair(W - x[i] + G, ans[i]));\n\t\tif (c[i] == 'A') ret.push_back(make_pair(H - y[i] + G, ans[i]));\n\t}\n\tsort(ret.begin(), ret.end());\n\tfor (int i = 0; i < N; i++) cout << ret[i].second << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 30268, "score_of_the_acc": -0.4469, "final_rank": 12 }, { "submission_id": "aoj_0354_3092215", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <utility>\n#include <map>\n#include <deque>\n#include <vector>\nusing namespace std;\ntypedef pair<int,int> pi;\n#define F first\n#define S second\n#define PB push_back\nconst int N=2e5+10;\nstruct ant{\n int x;\n int y;\n bool face;\n void in(){\n char c[5];\n scanf(\"%d%d\",&x,&y);\n scanf(\"%s\",c);\n face=c[0]=='E';\n return ;\n }\n int pos(){return x+y;}\n bool black(){return (x+y)%2;}\n};\n\nint main(){\n vector<pi> ans,temp;\n vector<int> emp,l[2],r[2];\n map<int,vector<int>>m;\n deque<int>dq[2];\n int n,w,h,p[N];\n ant a[N];\n scanf(\"%d%d%d\",&w,&h,&n);\n for(int i=1;i<=n;i++){\n a[i].in();\n if(m.find(a[i].pos())==m.end())m.insert({a[i].pos(),emp});\n m[a[i].pos()].PB(i);\n }\n for(pair<int,vector<int>> i:m){\n l[0].clear();\n l[1].clear();\n r[0].clear();\n r[1].clear();\n temp.clear();\n for(int j:i.S)temp.PB({a[j].x,j});\n sort(temp.begin(),temp.end());\n reverse(temp.begin(),temp.end());\n if(a[temp.front().S].black()){\n for(pi j:temp){\n if(a[j.S].face){\n if(dq[(j.F+1)%2].empty())p[j.S]=j.S;\n else{\n p[j.S]=dq[(j.F+1)%2].front();\n dq[(j.F+1)%2].pop_front();\n dq[(j.F+1)%2].PB(j.S);\n }\n }\n else {\n l[j.F%2].PB(j.S);\n dq[j.F%2].PB(j.S);\n }\n }\n }\n else{\n for(pi j:temp){\n if(a[j.S].face){\n if(dq[j.F%2].empty())p[j.S]=j.S;\n else{\n p[j.S]=dq[j.F%2].front();\n dq[j.F%2].pop_front();\n dq[j.F%2].PB(j.S);\n }\n }\n else {\n l[j.F%2].PB(j.S);\n dq[j.F%2].PB(j.S);\n }\n }\n }\n while(!dq[0].empty()){\n r[0].PB(dq[0].front());\n dq[0].pop_front();\n }\n while(!dq[1].empty()){\n r[1].PB(dq[1].front());\n dq[1].pop_front();\n }\n for(int j=0;j<r[0].size();j++)p[l[0][j]]=r[0][j];\n for(int j=0;j<r[1].size();j++)p[l[1][j]]=r[1][j];\n }\n for(int i=1;i<=n;i++)if(a[i].face)ans.PB({w-a[i].x,p[i]});\n else ans.PB({h-a[i].y,p[i]});\n sort(ans.begin(),ans.end());\n for(pi i:ans)printf(\"%d\\n\",i.S);\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 29428, "score_of_the_acc": -0.2928, "final_rank": 9 } ]
aoj_0353_cpp
ソート 高校入学後、プログラミング部に入部したタケ子さんは、次第にアルゴリズムの面白さにのめりこんでいきました。いまでは、2年生になったらプログラミング甲子園に出場してみたいと考えています。 あるとき、ソート・アルゴリズムについて学んだタケ子さんは、ソート・アルゴリズムを自分で設計してみました。タケ子さんが作ったソート・アルゴリズムでは、入力として要素の間に重複のない、1個以上の自然数からなる列が与えられたとき、以下の処理を実行します。 はじめに、列の先頭の要素を選ぶ。 選んだ要素の直前に要素があるとき、選んだ要素とその直前の要素を比べる。直前の要素のほうが大きいなら、それを列の末尾の直後に移動させる(図)。この操作を、選んだ要素が列の先頭になるか、選んだ要素よりその直前の要素の方が小さくなるまで続ける。 選んだ要素が列の末尾なら終了。そうでなければ、選んだ要素の直後の要素を新たに選び、2 へ戻る。 タケ子さんはこのアルゴリズムがどのくらいの計算時間を必要とするか見積もるために、要素を列の末尾の直後に移動させる操作の回数を数えることにしました。 列の情報を入力とし、要素を列の末尾の直後に移動させる操作の回数を報告するプログラムを作成せよ。 Input 入力は以下の形式で与えられる。 N a 1 a 2 ... a N 1行目に列に含まれる要素の個数 N (1 ≤ N ≤ 200000) が与えられる。2行目に列の要素 a i (1 ≤ a i ≤ 10 9 ) が先頭から順番に与えられる。要素 a i に重複はない。 Output 要素を列の末尾の直後に移動させる操作の回数を1行に出力する。 Sample Input 1 6 1 3 6 5 8 2 Sample Output 1 10 入力例1では、要素の移動が行われるたびに、以下のように列が変化していく。 0回目: 1 3 6 5 8 2 1回目: 1 3 5 8 2 6 2回目: 1 3 5 2 6 8 3回目: 1 3 2 6 8 5 4回目: 1 2 6 8 5 3 5回目: 1 2 6 5 3 8 6回目: 1 2 5 3 8 6 7回目: 1 2 3 8 6 5 8回目: 1 2 3 6 5 8 9回目: 1 2 3 5 8 6 10回目: 1 2 3 5 6 8 Sample Input 2 4 4 3 2 1 Sample Output 2 6
[ { "submission_id": "aoj_0353_11019202", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\nusing namespace std;\n\nint find_parent(vector<int>& parent, int x) {\n if (parent[x] < 0) return x;\n return parent[x] = find_parent(parent, parent[x]);\n}\n\nvoid union_sets(vector<int>& parent, int x, int y) {\n x = find_parent(parent, x);\n y = find_parent(parent, y);\n if (x == y) return;\n \n if (parent[x] > parent[y]) swap(x, y);\n parent[x] += parent[y];\n parent[y] = x;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n \n int n;\n cin >> n;\n \n vector<pair<int, int>> elements(n);\n for (int i = 0; i < n; i++) {\n cin >> elements[i].first;\n elements[i].second = i;\n }\n \n sort(elements.begin(), elements.end());\n \n vector<int> parent(n, -1);\n deque<int> dq;\n for (int i = 0; i < n; i++) {\n dq.push_back(i);\n }\n \n long long result = 0;\n \n for (int i = 0; i < n; i++) {\n while (true) {\n int u = find_parent(parent, elements[i].second);\n int v = find_parent(parent, dq.front());\n dq.pop_front();\n \n if (u == v) break;\n \n union_sets(parent, u, v);\n }\n \n int u = find_parent(parent, elements[i].second);\n result += -parent[u] - 1;\n parent[u]++;\n \n if (parent[u] < 0) {\n dq.push_back(u);\n }\n }\n \n cout << result << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6236, "score_of_the_acc": -0.0314, "final_rank": 1 }, { "submission_id": "aoj_0353_5059365", "code_snippet": "#include<iostream>\n#include<stack>\n#include<queue>\n#include<algorithm>\n#include<set>\nusing namespace std;\nint N;\nlong ans;\nint A[2<<17],V[2<<17];\nqueue<set<int> >P;\nstack<int>S;\nvoid ad(set<int>&s)\n{\n\tif(!P.empty()&&*P.back().begin()>*s.rbegin())\n\t{\n\t\tif(P.back().size()<s.size())P.back().swap(s);\n\t\tP.back().merge(s);\n\t}\n\telse\n\t{\n\t\tP.push(set<int>());\n\t\tP.back().swap(s);\n\t}\n}\nint main()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>A[i];\n\t\tV[i]=A[i];\n\t}\n\tsort(V,V+N);\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint a=lower_bound(V,V+N,A[i])-V;\n\t\tset<int>s={a};\n\t\tad(s);\n\t}\n\twhile(!P.empty())\n\t{\n\t\tset<int>p;\n\t\tp.swap(P.front());\n\t\tP.pop();\n\t\tint mn=*p.begin();\n\t\twhile(!S.empty()&&S.top()>mn)\n\t\t{\n\t\t\tp.insert(S.top());\n\t\t\tS.pop();\n\t\t}\n\t\tS.push(mn);\n\t\tp.erase(p.begin());\n\t\tans+=p.size();\n\t\tif(!p.empty())ad(p);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 1240, "memory_kb": 24092, "score_of_the_acc": -0.9265, "final_rank": 16 }, { "submission_id": "aoj_0353_5059357", "code_snippet": "#include<iostream>\n#include<stack>\n#include<queue>\n#include<algorithm>\n#include<set>\nusing namespace std;\nint N;\nlong ans;\nint A[2<<17],V[2<<17];\nqueue<set<int> >P;\nstack<int>S;\nvoid ad(set<int>&s)\n{\n\tif(!P.empty()&&*P.back().begin()>*s.rbegin())\n\t{\n\t\tP.back().merge(s);\n\t}\n\telse\n\t{\n\t\tP.push(set<int>());\n\t\tP.back().swap(s);\n\t}\n}\nint main()\n{\n\tcin>>N;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tcin>>A[i];\n\t\tV[i]=A[i];\n\t}\n\tsort(V,V+N);\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint a=lower_bound(V,V+N,A[i])-V;\n\t\tset<int>s={a};\n\t\tad(s);\n\t}\n\twhile(!P.empty())\n\t{\n\t\tset<int>p;\n\t\tp.swap(P.front());\n\t\tP.pop();\n\t\tint mn=*p.begin();\n\t\twhile(!S.empty()&&S.top()>mn)\n\t\t{\n\t\t\tp.insert(S.top());\n\t\t\tS.pop();\n\t\t}\n\t\tS.push(mn);\n\t\tp.erase(p.begin());\n\t\tans+=p.size();\n\t\tif(!p.empty())ad(p);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 1230, "memory_kb": 24024, "score_of_the_acc": -0.9206, "final_rank": 15 }, { "submission_id": "aoj_0353_4798317", "code_snippet": "#include<deque>\n#include<queue>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<set>\n#include<cmath>\n#include<tuple>\n#include<string>\n#include<chrono>\n#include<functional>\n#include<iterator>\n#include<random>\n#include<unordered_set>\n#include<array>\n#include<map>\n#include<iomanip>\n#include<assert.h>\n#include<list>\n#include<bitset>\n#include<stack>\n#include<memory>\n#include<numeric>\nusing namespace std;\nusing namespace std::chrono;\ntypedef long long int llint;\ntypedef long double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n#define REP(i, n) for(int i = 0;i < (n);i++)\n/*cout<<fixed<<setprecision(20);cin.tie(0);ios::sync_with_stdio(false);*/\nconst llint mod=1000000007;\nconst llint inf=2.19e18+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-10;\ntemplate <class T,class U>bool chmin(T& a,U b){if(a>b){a=b;return true;}return false;}\ntemplate <class T,class U>bool chmax(T& a,U b){if(a<b){a=b;return true;}return false;}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\nllint lcm(llint a,llint b){if(a==0){return b;}return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>llint LBI(const vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>llint UBI(const vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\n\nint main(void){\n\tint i,n;cin>>n;\n\tvector<int>a(n);\n\tfor(i=0;i<n;i++){cin>>a[i];}\n\tauto sa=a;SO(sa);\n\tset<int>kara;\n\tdeque<set<int>>b(n);\n\tfor(i=0;i<n;i++){b[i].ins(LBI(sa,a[i]));}\n\tllint ans=0;\n\tfor(i=0;i<n;i++){\n\t\twhile(b[0].count(i)==0){\n\t\t\tauto c=move(b[0]);\n\t\t\tb.pop_front();\n\t\t\tif(b[0].size()<c.size()){swap(b[0],c);}\n\t\t\tfor(auto it:c){b[0].ins(it);}\n\t\t}\n\t\tb[0].erase(i);\n\t\tans+=b[0].size();\n\t\tb.push_back(kara);\n\t\tswap(b[0],b.back());\n\t\tb.pop_front();\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 23752, "score_of_the_acc": -0.4227, "final_rank": 9 }, { "submission_id": "aoj_0353_4635729", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <typename T>\nusing GPQ = priority_queue<T, vector<T>, greater<T>>;\n\nint main() {\n int n;\n cin >> n;\n vector<int> v(n);\n for (auto &&i : v) scanf(\"%d\", &i);\n auto z = v;\n sort(z.begin(), z.end());\n z.erase(unique(z.begin(), z.end()), z.end());\n for (auto &&j : v) j = lower_bound(z.begin(),z.end(), j) - z.begin();\n\n auto merge = [&](GPQ<int> &a, GPQ<int> &b){\n if(a.size() < b.size()) swap(a, b);\n while(!b.empty()){\n a.emplace(b.top());\n b.pop();\n }\n };\n ll ans = 0;\n queue<int> Q;\n vector<GPQ<int>> a(n);\n for (int i = 0; i < n; ++i) {\n a[i].emplace(i);\n Q.emplace(v[i]);\n }\n for (int i = 0; i < n; ++i) {\n int x = Q.front(); Q.pop();\n while(a[x].top() != i) merge(a[x], a[Q.front()]), Q.pop();\n a[x].pop();\n ans += a[x].size();\n if(!a[x].empty()) Q.emplace(x);\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 19400, "score_of_the_acc": -0.2972, "final_rank": 6 }, { "submission_id": "aoj_0353_4553430", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nlong long kq,f[200005],n,u,v;\ndeque<int> dq;\npair<int,int> a[200005];\nint phin(int u)\n{\n return f[u]<=0 ? u : f[u]=phin(f[u]);\n}\nvoid uni(int u,int v)\n{\n if (f[u]>f[v]) swap(u,v);\n f[u]+=f[v];\n f[v]=u;\n}\nint main()\n{\n ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n cin>>n;\n for (int i=1;i<=n;++i)\n {\n cin>>a[i].first;\n a[i].second=i;\n dq.push_back(i);\n }\n\n sort(a+1,a+n+1);\n memset(f,-1,sizeof(f));\n for (int i=1;i<=n;++i)\n {\n while (1)\n {\n u=phin(a[i].second);\n v=phin(dq.front());dq.pop_front();\n if (u==v) break;\n uni(u,v);\n }\n u=phin(a[i].second);\n kq=kq-f[u]-1;\n f[u]++;\n if (f[u]<0) dq.push_back(u);\n }\n cout<<kq<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6808, "score_of_the_acc": -0.0417, "final_rank": 4 }, { "submission_id": "aoj_0353_4221200", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing S = set<int>;\n\nS* merge(S* a, S* b){\n if(a->size() < b->size()) swap(a, b);\n for(auto x : *b){\n a->insert(x);\n }\n return a;\n}\n\nvoid compress(vector<int> &v){\n auto tmp = v;\n sort(tmp.begin(), tmp.end());\n map<int,int> ord;\n for(int i=0;i<int(tmp.size());i++){\n ord[tmp[i]] = i;\n }\n for(auto& x : v) x = ord[x];\n}\n\nint main() {\n int n;\n cin >> n;\n vector<int> a(n);\n for(int i=0;i<n;i++){\n cin >> a[i];\n }\n compress(a);\n vector<S> sv(n);\n queue<S(*)> que;\n for(int i=0;i<n;i++){\n sv[i].insert(a[i]);\n que.push(&sv[i]);\n }\n long long ans = 0;\n for(int i=0;i<n;i++){\n while(1){\n auto s = que.front();\n que.pop();\n if(s->find(i) != s->end()){\n s->erase(i);\n ans += s->size();\n if(!s->empty()) que.push(s);\n break;\n }else{\n que.front() = merge(que.front(), s);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 36220, "score_of_the_acc": -0.6713, "final_rank": 12 }, { "submission_id": "aoj_0353_3312824", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef set<int> si;\nconst int N=2e5+10;\nint n; si a[N];\nqueue<si*> q;\npriority_queue<int, vector<int>, greater<int> > vals;\n\nsi* smer (si* s, si* t) {\n if (s->size()<t->size()) swap(s,t);\n while (!t->empty()) {\n s->insert(*(t->begin()));\n t->erase(t->begin());\n }\n return s;\n}\n\nint main()\n{/*\n freopen(\"input.txt\",\"r\",stdin); //*/\n scanf(\"%d\",&n);\n for (int i=1; i<=n; ++i) {\n int u; scanf(\"%d\",&u);\n a[i].insert(u); vals.push(u);\n }\n for (int i=1; i<=n; ++i) {\n q.push(&a[i]);\n }\n long long ans = 0ll;\n while (!vals.empty()) {\n int u = vals.top(); vals.pop();\n si* dummy = q.front(); q.pop();\n while (!dummy->count(u)) {\n dummy = smer(dummy, q.front());\n q.pop();\n }\n dummy->erase(u);\n ans += dummy->size();\n if (!dummy->empty())\n q.push(dummy);\n }\n printf(\"%lld\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 24084, "score_of_the_acc": -0.4053, "final_rank": 7 }, { "submission_id": "aoj_0353_3161417", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n int n; cin >> n;\n vector<int> a(n);\n for(int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n\n { // compress\n auto b = a;\n sort(begin(b), end(b));\n for(int i = 0; i < n; ++i) {\n a[i] = lower_bound(begin(b), end(b), a[i]) - begin(b);\n }\n }\n\n using S = priority_queue<int, vector<int>, greater<>>;\n function<void(S&, S&)> merge = [] (S& s1, S& s2) {\n if(s1.size() < s2.size()) swap(s1, s2);\n while(!s2.empty()) {\n s1.push(s2.top()); s2.pop();\n }\n };\n\n queue<shared_ptr<S>> que;\n for(int i = 0; i < n; ++i) {\n auto q = make_shared<S>(); q->push(a[i]);\n que.push(move(q));\n }\n\n ll ans = 0;\n for(int i = 0; i < n; ++i) {\n auto s = que.front(); que.pop();\n while(s->top() != i) {\n auto v = que.front(); que.pop();\n merge(*s, *v);\n }\n s->pop();\n ans += s->size();\n que.push(s);\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 25720, "score_of_the_acc": -0.4207, "final_rank": 8 }, { "submission_id": "aoj_0353_3099276", "code_snippet": "#include <stdio.h>\n#include <queue>\n#include <stack>\nusing namespace std;\nint main(){\n int n,temp,last;\n bool up=true;\n long long int ans=0;\n queue<priority_queue<int,vector<int>,greater<int>>*>q;\n stack<int> s;\n priority_queue<int,vector<int>,greater<int>>* pq;\n scanf(\"%d\",&n);\n while(n--){\n scanf(\"%d\",&temp);\n if(!s.empty()){\n if(up){\n if(temp<s.top())up=false;\n }\n else{\n if(temp>s.top()){\n last=temp;\n temp=s.top();\n s.pop();\n pq=new priority_queue<int,vector<int>,greater<int>>;\n pq->push(s.top());\n s.pop();\n while(!s.empty()){\n if(s.top()>temp){\n pq->push(s.top());\n s.pop();\n }\n else break;\n }\n ans+=pq->size();\n q.push(pq);\n up=true;\n s.push(temp);\n temp=last;\n }\n }\n }\n s.push(temp);\n }\n if(!up){\n temp=s.top();\n s.pop();\n pq=new priority_queue<int,vector<int>,greater<int>>;\n pq->push(s.top());\n s.pop();\n while(!s.empty()){\n if(s.top()>temp){\n pq->push(s.top());\n s.pop();\n }\n else break;\n }\n ans+=pq->size();\n q.push(pq);\n s.push(temp);\n }\n while(!q.empty()){\n pq=q.front();\n q.pop();\n if(pq->empty())continue;\n temp=pq->top();\n pq->pop();\n while(!s.empty()){\n if(s.top()>temp){\n pq->push(s.top());\n s.pop();\n }\n else break;\n }\n s.push(temp);\n ans+=pq->size();\n q.push(pq);\n }\n printf(\"%lld\\n\",ans);\n}", "accuracy": 1, "time_ms": 1170, "memory_kb": 13748, "score_of_the_acc": -0.7069, "final_rank": 13 }, { "submission_id": "aoj_0353_2817547", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\ntypedef set<int> Group;\n\nGroup* make_group(int num){\n\tGroup *new_group = new Group();\n\tnew_group->insert(num);\n\treturn new_group;\n}\n\nGroup* merge(Group* left,Group* right){\n\tif(left->size() < right->size()){\n\t\tswap(left,right);\n\t}\n\tfor(Group::iterator it = right->begin(); it != right->end(); it++)left->insert(*it);\n\n\treturn left;\n}\n\nint main(){\n\n\tint N;\n\tscanf(\"%d\",&N);\n\tqueue<Group*> Q;\n\n\tvector<int> V,WORK;\n\n\tint tmp;\n\tmap<int,int> MAP;\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d\",&tmp);\n\t\tV.push_back(tmp);\n\t\tWORK.push_back(tmp);\n\t}\n\n\tsort(WORK.begin(),WORK.end());\n\n\tfor(int i = 0; i < N; i++){\n\t\tMAP[WORK[i]] = i+1;\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tV[i] = MAP[V[i]];\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tQ.push(make_group(V[i]));\n\t}\n\n\tll ans = 0;\n\tfor(int num = 1; num <= N; num++){\n\t\tGroup* group = Q.front();\n\t\tQ.pop();\n\n\t\twhile(true){\n\t\t\tif(*(group->begin()) == num){\n\t\t\t\tgroup->erase(group->begin());\n\t\t\t\tans += group->size();\n\t\t\t\tif(group->size() > 0){\n\t\t\t\t\tQ.push(group);\n\t\t\t\t}\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tGroup* next_group = Q.front();\n\t\t\tQ.pop();\n\t\t\tgroup = merge(group,next_group);\n\t\t}\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 49808, "score_of_the_acc": -0.8978, "final_rank": 14 }, { "submission_id": "aoj_0353_2730777", "code_snippet": "#include <bits/stdc++.h>\n#define FOR(i, a, b) for (int i = a; i <= b; ++i)\n#define ii pair <int, int>\nusing namespace std;\nconst int N = 2e5 + 3;\nint n, dsu[N];\nlong long res;\nvector <ii> V;\ndeque <int> dq;\n\nvoid init() {\n ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n //freopen(\"main.inp\",\"r\",stdin);\n //freopen(\"main.out\",\"w\",stdout);\n}\n\nint root(int x) { return dsu[x] <= 0 ? x : dsu[x] = root(dsu[x]); }\nvoid merge(int u, int v) {\n if (dsu[u] > dsu[v]) swap(u, v);\n dsu[u] += dsu[v], dsu[v] = u;\n}\n\nvoid solve() {\n cin >> n;\n FOR(i, 1, n) { int x; cin >> x; V.push_back({ x, i }); dq.push_back(i); }\n\n memset(dsu, -1, sizeof dsu);\n sort(V.begin(), V.end());\n for (ii it : V) {\n while (1) {\n int id1 = root(it.second);\n int id2 = root(dq.front()); dq.pop_front();\n if (id2 == id1) break;\n merge(id1, id2);\n }\n int id1 = root(it.second);\n res += 0LL - dsu[id1] - 1; dsu[id1]++;\n if (dsu[id1] < 0) dq.push_back(id1);\n }\n\n cout << res << '\\n';\n}\n\nmain() {\n init(); solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6224, "score_of_the_acc": -0.0359, "final_rank": 2 }, { "submission_id": "aoj_0353_2730643", "code_snippet": "#include <bits/stdc++.h>\n\n#define fto(i, x, y) for(int i = (x); i <= (y); ++i)\n#define fdto(i, x, y) for(int i = (x); i >= (y); --i)\n#define ftoa(i, x, y, a) for(int i = (x); i <= (y); i += a)\n#define ftoit(it, var) for (__typeof(var.begin()) it = var.begin(); it != var.end(); ++it)\n\n#define ii pair<int, int>\n#define mp make_pair\n#define FF first\n#define SS second\n\n#define vi vector<int>\n#define vii vector<ii>\n#define ll long long\n#define vll vector<ll>\n\n#define eb emplace_back\n#define ef emplace_front\n#define lb lower_bound\n#define ub upper_bound\n#define sz(a) (int)a.size()\n\n#define oo 1000000007\n#define OO 1000000000000000007LL\n\nusing namespace std;\n\n#define Pro \"tmp\"\n#define maxN 300007\n\nint a[maxN], b[maxN];\nset <int> st[maxN];\n\nint mergeSet(int a, int b) {\n if ((int)st[a].size() < (int)st[b].size()) swap(a, b);\n ftoit (it, st[b]) st[a].insert(*it);\n st[b].clear();\n return a;\n}\n\nint main() {\n\n int n;\n scanf(\"%d\", &n);\n\n fto (i, 1, n) {\n scanf(\"%d\", &a[i]);\n b[i] = a[i];\n }\n sort(b+1, b+n+1);\n\n queue <int> q;\n fto (i, 1, n) {\n st[i].insert(a[i]);\n q.push(i);\n }\n\n ll sol = 0LL;\n fto (i, 1, n) {\n int ans = 0;\n set <int> cur_set;\n\n int new_idx = 0;\n while (!q.empty()) {\n int idx = q.front();\n q.pop();\n\n ans += (int)st[idx].size();\n if (st[idx].count(b[i])) {\n st[idx].erase(b[i]);\n new_idx = mergeSet(idx, new_idx);\n\n if ((int)st[new_idx].size()) q.push(new_idx);\n break;\n }\n\n new_idx = mergeSet(idx, new_idx);\n }\n\n sol += ans-1;\n }\n\n printf(\"%lld\\n\", sol);\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 32804, "score_of_the_acc": -0.5486, "final_rank": 11 }, { "submission_id": "aoj_0353_2730320", "code_snippet": "#include <bits/stdc++.h>\n#define fo(i,a,b) for(int i=a;i<=b;++i)\n#define fd(i,a,b) for(int i=a;i>=b;--i)\n#define rep(i,a,b) for(int i=a;i<b;++i)\n#define fore(i,a) for(__typeof(a.begin()) i=a.begin();i!=a.end();++i)\n#define __unique(V) V.resize(unique(V.begin(),V.end())-V.begin())\n#define cntbit(X) __builtin_popcount(X)\n#define fi first\n#define se second\n#define LL long long\n#define ii pair<int,int>\n#define iii pair<int,ii>\n#define TASK \"sort\"\nusing namespace std;\nLL ans,n;\nint dd;\nii a[200005];\n///--------------------------\nvoid readf(){\n cin>>n;\n fo(i,1,n) cin>>a[i].fi;\n fo(i,1,n) a[i].se=i;\n}\n///--------------------------\nvoid solve(){\n sort(a+1,a+n+1);\n a[0].se=0;\n ans=0;dd=n;\n fo(i,1,n){\n ans+=a[i].se-a[i-1].se-1;\n if (a[i].se>a[i+1].se){\n ans+=((LL)(n-i-1)*(n-i))/2;\n break;\n }\n if (a[i-1].se<a[i].se-1)\n fo(j,i+2,n) if (a[i].se>a[j].se){\n fo(t,j+1,n) if (a[i].se>a[t].se)\n a[t].se=++dd;\n a[j].se=++dd;\n break;\n }\n }\n cout<<ans<<'\\n';\n}\n///--------------------------\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n readf();\n solve();\n}", "accuracy": 0.875, "time_ms": 2130, "memory_kb": 4804, "score_of_the_acc": -0.9962, "final_rank": 18 }, { "submission_id": "aoj_0353_2730317", "code_snippet": "#include <bits/stdc++.h>\n#define fo(i,a,b) for(int i=a;i<=b;++i)\n#define fd(i,a,b) for(int i=a;i>=b;--i)\n#define rep(i,a,b) for(int i=a;i<b;++i)\n#define fore(i,a) for(__typeof(a.begin()) i=a.begin();i!=a.end();++i)\n#define __unique(V) V.resize(unique(V.begin(),V.end())-V.begin())\n#define cntbit(X) __builtin_popcount(X)\n#define fi first\n#define se second\n#define LL long long\n#define ii pair<int,int>\n#define iii pair<int,ii>\n#define TASK \"sort\"\nusing namespace std;\nLL ans,n;\nint dd;\nii a[200005];\n///--------------------------\nvoid readf(){\n cin>>n;\n fo(i,1,n) cin>>a[i].fi;\n fo(i,1,n) a[i].se=i;\n}\n///--------------------------\nvoid solve(){\n sort(a+1,a+n+1);\n a[0].se=0;\n ans=0;dd=n;\n fo(i,1,n){\n ans+=a[i].se-a[i-1].se-1;\n if (a[i].se>a[i+1].se){\n ans+=((n-i-1)*(n-i))/2;\n break;\n }\n if (a[i-1].se<a[i].se-1)\n fo(j,i+2,n) if (a[i].se>a[j].se){\n fo(t,j+1,n) if (a[i].se>a[t].se)\n a[t].se=++dd;\n a[j].se=++dd;\n break;\n }\n }\n cout<<ans<<'\\n';\n}\n///--------------------------\nint main(){\n ios::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n readf();\n solve();\n}", "accuracy": 0.875, "time_ms": 2140, "memory_kb": 4756, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_0353_2730251", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define removeDuplicate(a) sort(a.begin(), a.end()); a.resize(distance(a.begin(), unique(a.begin(), a.end())));\n\n\nconst int N = 6e5 + 10; \n\nint n;\nint a[N]; \nset<int> *q[N]; \n\nvoid merge (set<int> *&a, set<int> *&b) {\n\tif (a -> size() > b -> size()) { \n\t\tfor (auto value : *b) { \n\t\t\ta -> insert(value); \n\t\t}\n\t\tb -> clear(); \n\t}\n\telse { \n\t\tfor (auto value : *a) { \n\t\t\tb -> insert(value); \n\t\t}\n\t\ta -> clear(); \n\t\ta = b; \n\t}\n}\n\nvoid zip () { \n\tvector<int> rar; \n\tfor (int i = 1; i <= n; i++) { \n\t\trar.push_back(a[i]); \n\t}\n\tremoveDuplicate(rar); \n\tfor (int i = 1; i <= n; i++) { \n\t\ta[i] = lower_bound(rar.begin(), rar.end(), a[i]) - rar.begin() + 1; \n\t}\n}\n\nint main()\n{\n #define file \"9\"\n //freopen(file\".inp\", \"r\", stdin); freopen(file\".out\", \"w\", stdout);\n\n cin >> n; \n for (int i = 1; i <= 3 * n; i++) { \n \tq[i] = new set<int>; \n }\n for (int i = 1; i <= n; i++) { \n \tint value; \n \tcin >> value;\n \ta[i] = value; \n }\n zip(); \n for (int i = 1; i <= n; i++) { \n \tq[i] -> insert(a[i]); \n }\n long long ret = 0; \n int front = 1, back = n; \n for (int value = 1; value <= n; value++) { \n \tfor (int i = front; i <= back; i++) { \n \t\tmerge(q[back + 1], q[i]);\n \t\tfront++; \n \t\tif (q[back + 1] -> find(value) != q[back + 1] -> end()) { \n \t\t\tbreak; \n \t\t}\n \t}\n \tback++; \n \tq[back] -> erase(value); \n \tif (q[back] -> empty()) { \n \t\tback--; \n \t\tcontinue; \t\n \t}\n \tret += ((int)(q[back] -> size()));\n }\n cout << ret << endl; \n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 60148, "score_of_the_acc": -1.0751, "final_rank": 17 }, { "submission_id": "aoj_0353_2730248", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define removeDuplicate(a) sort(a.begin(), a.end()); a.resize(distance(a.begin(), unique(a.begin(), a.end())));\n\n\nconst int N = 2e5 + 10; \n\nint n;\nint a[N]; \nset<int> *q[N]; \n\nvoid merge (set<int> *&a, set<int> *&b) {\n\tif (a -> size() > b -> size()) { \n\t\tfor (auto value : *b) { \n\t\t\ta -> insert(value); \n\t\t}\n\t\tb -> clear(); \n\t}\n\telse { \n\t\tfor (auto value : *a) { \n\t\t\tb -> insert(value); \n\t\t}\n\t\ta -> clear(); \n\t\ta = b; \n\t}\n}\n\nvoid zip () { \n\tvector<int> rar; \n\tfor (int i = 1; i <= n; i++) { \n\t\trar.push_back(a[i]); \n\t}\n\tremoveDuplicate(rar); \n\tfor (int i = 1; i <= n; i++) { \n\t\ta[i] = lower_bound(rar.begin(), rar.end(), a[i]) - rar.begin() + 1; \n\t}\n}\n\nint main()\n{\n #define file \"9\"\n //freopen(file\".inp\", \"r\", stdin); freopen(file\".out\", \"w\", stdout);\n\n cin >> n; \n for (int i = 1; i <= 3 * n; i++) { \n \tq[i] = new set<int>; \n }\n for (int i = 1; i <= n; i++) { \n \tint value; \n \tcin >> value;\n \ta[i] = value; \n }\n zip(); \n for (int i = 1; i <= n; i++) { \n \tq[i] -> insert(a[i]); \n }\n long long ret = 0; \n int front = 1, back = n; \n for (int value = 1; value <= n; value++) { \n \tfor (int i = front; i <= back; i++) { \n \t\tmerge(q[back + 1], q[i]);\n \t\tfront++; \n \t\tif (q[back + 1] -> find(value) != q[back + 1] -> end()) { \n \t\t\tbreak; \n \t\t}\n \t}\n \tback++; \n \tq[back] -> erase(value); \n \tif (q[back] -> empty()) { \n \t\tback--; \n \t\tcontinue; \t\n \t}\n \tret += ((int)(q[back] -> size()));\n }\n cout << ret << endl; \n return 0;\n}", "accuracy": 0.625, "time_ms": 10, "memory_kb": 8768, "score_of_the_acc": -0.0724, "final_rank": 20 }, { "submission_id": "aoj_0353_2730160", "code_snippet": "#include <bits/stdc++.h>\n#define up(i, a, b) for (int i = a, _b = b; i <= _b; i++)\n#define down(i, a, b) for (int i = a, _b = b; i >= _b; i--)\n#define long long long\n#define endl '\\n'\n#define X first\n#define Y second\n#define II pair<int, int>\n#define debug(X) cerr << #X << \" = \" << X << endl\n#define debug2(X, Y) cerr << #X << \" = \" << X << \" , \" << #Y << \" = \" << Y << endl\n#define show(X, a, b) { cerr << #X << \" = \"; up(_, a, b) cerr << X[_] << \" \"; cerr << endl; }\n#define gc getchar\n#define pc putchar\nusing namespace std;\ninline void read(int &x) {\n register int c = gc();\n x = 0;\n int neg = 0;\n for (; ((c<48 || c>57) && c != '-'); c = gc());\n if(c=='-') {neg=1; c=gc();}\n for(; c>47 && c<58; c = gc()) {x = (x<<1) + (x<<3) + c - 48;}\n if(neg) x=-x;\n}\ninline void writeln(int x) {\n\n char buffor[21];\n register int i=0;\n int neg=0; if (x<0) {neg=1; x= -x;}\n do {\n buffor[i++]=(x%10)+'0';\n x/=10;\n } while(x);\n i--;\n if (neg) pc('-');\n while(i>=0) pc(buffor[i--]);\n pc('\\n');\n}\nint n, a[200010];\nmap<int, int> rr;\npriority_queue<int, vector<int>, greater<int> > pq[200010];\ndeque<int> dq;\nvoid input() {\n cin >> n;\n up(i, 1, n) cin >> a[i], rr[a[i]] = 1;\n int cnt = 0;\n for (auto u: rr) rr[u.X] = ++cnt;\n up(i, 1, n) a[i] = rr[a[i]];\n}\nvoid merge(int u, int v) {\n if (pq[u].size() > pq[v].size()) pq[u].swap(pq[v]);\n while (!pq[u].empty()) pq[v].push(pq[u].top()), pq[u].pop();\n}\nvoid solve() {\n up(i, 1, n) pq[i].push(a[i]), dq.push_back(i);\n long res = 0;\n up(i, 1, n) {\n while (dq.size() > 1 && pq[dq.front()].top() != i) {\n int u = dq.front(); dq.pop_front();\n int v = dq.front(); merge(u, v);\n }\n int v = dq.front(); dq.pop_front();\n pq[v].pop(); res += pq[v].size();\n if (!pq[v].empty()) dq.push_back(v);\n }\n cout << res << endl;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n #ifdef I_Love_Pork\n #define TASK \"tmp\"\n freopen(TASK \".inp\",\"r\",stdin);\n freopen(TASK \".out\",\"w\",stdout);\n #endif\n\n\n input();\n solve();\n\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 27840, "score_of_the_acc": -0.4966, "final_rank": 10 }, { "submission_id": "aoj_0353_2730137", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define mp make_pair\n#define pb push_back\n#define fi first\n#define se second\nint n;\nint a[200007],b[200007],pset[200007];\nlong long ans=0;\nqueue <int> q;\nint fset(int x){\n\tif(pset[x]<=0) return x;\n\treturn pset[x]=fset(pset[x]);\n}\nvoid unite(int x,int y){\n\tx=fset(x);\n\ty=fset(y);\n\tif(x==y) return;\n\tif(pset[x]<=pset[y]){\n\t\tpset[x]+=pset[y];\n\t\tpset[y]=x;\n\t}\n\telse{\n\t\tpset[y]+=pset[x];\n\t\tpset[x]=y;\n\t}\n}\nbool cmp(int x,int y){\n\treturn (a[x]<a[y] || (a[x]==a[y] && x<y));\n}\nint main(){\n\tios_base::sync_with_stdio(0);\n\tcin>>n;\n\tfor(int i=1;i<=n;i++){\n\t\tcin>>a[i];\n\t\tpset[i]=-1;\n\t\tb[i]=i;\n\t}\n\tsort(b+1,b+1+n,cmp);\n\tfor(int i=1;i<=n;i++){\n\t\ta[b[i]]=i;\n\t}\n\tfor(int i=1;i<=n;i++) q.push(a[i]);\n\tfor(int i=1;i<=n;i++){\n\t\t//cout<<b[i]<<endl;\n\t\twhile(1){\n\t\t\tint x=q.front();\n\t\t\tq.pop();\n\t\t\tif(fset(x)!=fset(i)){\n\t\t\t\tunite(x,i);\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\tans-=pset[fset(i)]+1;\n\t\tpset[fset(i)]++;\n\t\tq.push(fset(i));\n\t}\n\tcout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6080, "score_of_the_acc": -0.038, "final_rank": 3 }, { "submission_id": "aoj_0353_2730133", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> ii;\n#define mk make_pair\n#define f first\n#define s second\n\nconst int N = 2e5 + 7;\nint t, n, m;\nint a[N], dad[N];\nll num[N], res;\ndeque<int> now;\nii val[N];\n\nint root(int u){ return (u == dad[u] ? u : dad[u] = root(dad[u])); }\n\nmain()\n{\n#define file \"r\"\n// freopen(file\".inp\", \"r\", stdin);\n// freopen(file\".out\", \"w\", stdout);\n ios_base::sync_with_stdio(false);\n cin >> n;\n for(int i = 1; i <= n; i ++)\n {\n cin >> a[i];\n val[i] = mk(a[i], i);\n dad[i] = i; now.push_back(i); num[i] = 1;\n }\n sort(val + 1, val + n + 1);\n for(int i = 1; i <= n; i ++)\n {\n t = root(val[i].s);\n while(1)\n {\n int tmp = root(now.front()); now.pop_front();\n if(t == tmp) break;\n if(num[t] > num[tmp])\n {\n num[t] += num[tmp]; num[tmp] = 0; dad[tmp] = t;\n }\n else\n {\n swap(t, tmp);\n num[t] += num[tmp]; num[tmp] = 0; dad[tmp] = t;\n }\n }\n res = res + 1LL*num[t] - 1LL; num[t] --;\n// cout << i << \" \" << t << \" \" << num[t] << \"\\n\";\n if(num[t] > 0) now.push_back(t);\n// cout << i << \" \" << res << \" \" << t << \"\\n\";\n }\n cout << res << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8340, "score_of_the_acc": -0.0788, "final_rank": 5 } ]
aoj_0362_cpp
Trampoline A plurality of trampolines are arranged in a line at 10 m intervals. Each trampoline has its own maximum horizontal distance within which the jumper can jump safely. Starting from the left-most trampoline, the jumper jumps to another trampoline within the allowed jumping range. The jumper wants to repeat jumping until he/she reaches the right-most trampoline, and then tries to return to the left-most trampoline only through jumping. Can the jumper complete the roundtrip without a single stepping-down from a trampoline? Write a program to report if the jumper can complete the journey using the list of maximum horizontal reaches of these trampolines. Assume that the trampolines are points without spatial extent. Input The input is given in the following format. N d_1 d_2 : d_N The first line provides the number of trampolines N (2 ≤ N ≤ 3 × 10 5 ). Each of the subsequent N lines gives the maximum allowable jumping distance in integer meters for the i -th trampoline d_i (1 ≤ d_i ≤ 10 6 ). Output Output " yes " if the jumper can complete the roundtrip, or " no " if he/she cannot. Sample Input 1 4 20 5 10 1 Sample Output 1 no Sample Input 2 3 10 5 10 Sample Output 2 no Sample Input 3 4 20 30 1 20 Sample Output 3 yes
[ { "submission_id": "aoj_0362_10873479", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\n\nint main(){\n \n int N;\n cin>>N;\n vector<int> D(N);\n rep(i,N)cin>>D[i],D[i]/=10;\n \n\n rep(_,2){\n int ma=0;\n rep(i,N){\n if(i<=ma){\n chmax(ma, i+D[i]);\n }\n }\n if(ma<N-1){\n cout<<\"no\\n\";\n return 0;\n }\n\n reverse(all(D));\n }\n cout<<\"yes\\n\";\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4480, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0362_10866730", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i=0;i<(ll)(N);i++)\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\nint main(){\n int N;cin>>N;\n vector<ll>D(N);\n rep(i,N)cin>>D[i];\n ll v = 0;\n rep(i,N){\n if(v>=i*10){\n v = max(v,i*10+D[i]);\n }\n else {\n cout<<\"no\"<<endl;\n return 0;\n }\n }\n v = (N-1)*10;\n for(int i=N-1;i>=0;i--){\n if(v<=i*10){\n v = min(v,i*10-D[i]);\n }\n else{\n cout<<\"no\"<<endl;\n return 0;\n }\n }\n cout<<\"yes\"<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5392, "score_of_the_acc": -0.4873, "final_rank": 4 }, { "submission_id": "aoj_0362_10865132", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//vector<ll> saiki(ll bit,ll n){\n//\tvector<ll> s(n);\n//\tfor(ll i=0;i<n;i++){\n//\t\tif(bit&(1<<i)){\n//\t\t\ts[i]=1;\n//\t\t}else s[i]=0;\n//\t}\n//\treturn s;\n//}\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll n;\n\tcin>>n;\n\tvector<ll> a(n);\n\trep(i,n)cin>>a[i];\n\n\tvector<ll> ans(n+1,0);\n\tvector<ll> ans2(n+1,0);\n\n\tfor(ll i=0;i<n-1;i++){\n\t\tll v=a[i]/10;\n\t\tif(a[i]>=10){\n\t\t\tans[i+1]+=1;\n\t\t\tans[min(i+1+v,n)]-=1;\n\t\t}\n\t}\n\tfor(ll i=n-1;i>=1;i--){\n\t\tll v=a[i]/10;\n\t\tif(a[i]>=10){\n\t\t\tans2[i]+=1;\n\t\t\tans2[max(i-v,n-n)]-=1;\n\t\t}\n\t}\n\tfor(ll i=1;i<n-1;i++){\n\t\tans[i]=ans[i-1]+ans[i];\n\t\tif(ans[i]==0){\n\t\t\tcout<<\"no\"<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tfor(ll i=n-1;i>=1;i--){\n\t\tans2[i]=ans2[i+1]+ans2[i];\n\t\tif(ans2[i]==0){\n\t\t\tcout<<\"no\"<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<\"yes\"<<endl;\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10184, "score_of_the_acc": -0.5459, "final_rank": 7 }, { "submission_id": "aoj_0362_10858007", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nbool JG(vector<int> D) {\n\tint N = D.size();\n\tint mx = D[0];\n\tfor (int i = 1;i < N;i++) {\n\t\tif (i <= mx) {\n\t\t\tmx = max(mx, i + D[i]);\n\t\t} else {\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint main() {\n\tint N;cin >> N;\n\tvector<int> D(N);\n\tfor (int i = 0;i < N;i++) {\n\t\tcin >> D[i];\n\t\tD[i] /= 10;\n\t}\n\tif (!JG(D)) {\n\t\tcout << \"no\" << endl;\n\t\treturn 0;\n\t}\n\treverse(D.begin(), D.end());\n\tif (JG(D)) {\n\t\tcout << \"yes\" << endl;\n\t} else {\n\t\tcout << \"no\" << endl;\n\t}\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5728, "score_of_the_acc": -0.4194, "final_rank": 3 }, { "submission_id": "aoj_0362_10857646", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nbool solve(vector<int> &D, int N) {\n int maxi = 0;\n rep(i, 0, N) {\n if (i*10 <= maxi) maxi = max(maxi, i*10 + D[i]);\n }\n return ((N - 1)*10 <= maxi);\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int N;\n cin >> N;\n vector<int> D(N), invD(N);\n rep(i, 0, N) {\n cin >> D[i];\n invD[N - i - 1] = D[i];\n }\n \n if (solve(D, N) && solve(invD, N)) cout << \"yes\\n\";\n else cout << \"no\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5424, "score_of_the_acc": -0.0904, "final_rank": 2 }, { "submission_id": "aoj_0362_10857641", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nbool solve(vector<int> &D, int N) {\n int maxi = 0;\n rep(i, 0, N) {\n if (i*10 <= maxi) maxi = max(maxi, D[i]);\n }\n return ((N - 1)*10 <= maxi);\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int N;\n cin >> N;\n vector<int> D(N), invD(N);\n rep(i, 0, N) {\n cin >> D[i];\n invD[N - i - 1] = D[i];\n }\n \n if (solve(D, N) && solve(invD, N)) cout << \"yes\\n\";\n else cout << \"no\\n\";\n}", "accuracy": 0.175, "time_ms": 10, "memory_kb": 5272, "score_of_the_acc": -0.0758, "final_rank": 20 }, { "submission_id": "aoj_0362_10853192", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nconst ll MOD=10000000;\nconst ll INF=1000000001;\nconst ll LINF=4000000000000000010;\nconst double EPS=1e-9;\nint dx[5]={0,1,0,-1,0};\nint dy[5]={1,0,-1,0,0};\nint d[300010];\nint ma[300010],mi[300010];\nint main(){\n int n;cin>>n;\n for(int i=0;i<n;i++){\n cin>>d[i];\n d[i]/=10;\n if(i){\n ma[i]=max(ma[i-1],i+d[i]);\n }else{\n ma[i]=i+d[i];\n }\n }\n fill(mi,mi+n,INF);\n for(int i=n-1;i>=0;i--){\n if(i<n-1){\n mi[i]=min(mi[i+1],i-d[i]);\n }else{\n mi[i]=i-d[i];\n }\n }\n int pos=0;\n while(pos<n-1){\n if(pos==ma[pos]){\n cout<<\"no\"<<endl;\n return 0;\n }\n pos=ma[pos];\n }\n pos=n-1;\n while(pos>0){\n if(pos==mi[pos]){\n cout<<\"no\"<<endl;\n return 0;\n }\n pos=mi[pos];\n }\n cout<<\"yes\"<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6956, "score_of_the_acc": -0.637, "final_rank": 9 }, { "submission_id": "aoj_0362_10823820", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nbool solve(vector<int> v){\n int tal=0;\n for(int i=0;i<v.size();i++){\n if(tal>=i*10){\n tal=max(tal,i*10+v[i]);\n }else return false;\n }\n if(10*(v.size()-1)<=tal)return true;\n else return false;\n}\nint main(){\n int n;\n cin >> n;\n vector<int> s(n),d;\n for(int i=0;i<n;i++)cin >> s[i];\n d=s;\n reverse(s.begin(),s.end());\n if(solve(d)&&solve(s))cout << \"yes\" << endl;\n else cout << \"no\" << endl; \n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7864, "score_of_the_acc": -0.7239, "final_rank": 11 }, { "submission_id": "aoj_0362_10777427", "code_snippet": "#include<bits/stdc++.h>\n#include <vector>\nusing namespace std;\nint d[300001],wk[300001];\n//typedef pair<long long,long long>P;\nint main(void)\n{\n\tint n,mx,f;\n\tcin>>n;\n\tfor(int i=0;i<n;i++) cin>>d[i];\n\tf=1;\n\tfor(int i=0;i<n;i++) wk[i]=d[i];\n\tmx=0;\n\tfor(int i=0;i<n-1;i++){\n\t\tmx=max(mx,i*10+wk[i]);\n\t\tif(mx<(i+1)*10){\n\t\t\tf=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(int i=0;i<n;i++) wk[n-i-1]=d[i];\n\tmx=0;\n\tfor(int i=0;i<n-1;i++){\n\t\tmx=max(mx,i*10+wk[i]);\n\t\tif(mx<(i+1)*10){\n\t\t\tf=0;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(f==1) cout<<\"yes\"<<endl;\n\telse cout<<\"no\"<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5712, "score_of_the_acc": -0.5179, "final_rank": 6 }, { "submission_id": "aoj_0362_10776365", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint d[300000],f[300000];\nint main()\n{\n\tint n,i,j=0,flg=0,mx=-1,cnt=-2;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>d[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(d[i]<10){\n\t\t\tcnt=cnt+10;\n\t\t}\n\t\telse{\n\t\t\tmx=-1;\n\t\t\tif(mx<d[i]&&d[i]>=20){\n\t\t\t\tmx=d[i];\n\t\t\t\tcnt=-2;\n\t\t\t}\n\t\t}\n\t\tif(cnt>mx){\n\t\t\tflg=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor(i=n-1;i>=0;i--){\n\t\tf[j]=d[i];\n\t\tj++;\n\t}\n\tmx=-1;\n\tcnt=-2;\n\tfor(i=0;i<n;i++){\n\t\tif(f[i]<10){\n\t\t\tcnt=cnt+10;\n\t\t}\n\t\telse{\n\t\t\tmx=-1;\n\t\t\tif(mx<f[i]&&f[i]>=20){\n\t\t\t\tmx=f[i];\n\t\t\t\tcnt=-2;\n\t\t\t}\n\t\t}\n\t\tif(cnt>mx){\n\t\t\tflg=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(flg==0)\tcout<<\"yes\"<<endl;\n\telse \tcout<<\"no\"<<endl;\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 50, "memory_kb": 5712, "score_of_the_acc": -0.5179, "final_rank": 19 }, { "submission_id": "aoj_0362_10776187", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tint i, n, d[1000001], mx=0, flg=0;\n\tcin >> n;\n\tfor(i=0;i<n;i++) cin >> d[i];\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(mx < d[i]) mx = d[i];\n\t\tif(mx-10 < 0){\n\t\t\tflg = 1;\n\t\t\tbreak;\n\t\t}\n\t\tmx -= 10;\n\t}\n\tmx = 0;\n\tfor(i=n-1;i>=0;i--)\n\t{\n\t\tif(mx < d[i]) mx = d[i];\n\t\tif(mx-10 < 0){\n\t\t\tflg = 1;\n\t\t\tbreak;\n\t\t}\n\t\tmx -= 10;\n\t}\n\tif(flg == 1) cout << \"no\" << endl;\n\telse cout << \"yes\" << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6324, "score_of_the_acc": -0.5765, "final_rank": 8 }, { "submission_id": "aoj_0362_10776113", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\n#define MOD 998244353\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater<ll>())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x,y) reverse(x,x+y)\n#define REV(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\n#define POW(x,y) (ll)pow(x,y)\nll p,f;\nvoid solve() {\n\tll n; cin>>n;\n\tll d[n];\n\trep(i,0,n) cin>>d[i];\n\trep(i,0,n-1) { p+=d[i]-10; if (p<0) { f=1; break; } }\n\trev(d,n);\n\trep(i,0,n-1) { p+=d[i]-10; if (p<0) { f=1; break; } }\n\tputs( f==0 ? \"yes\" : \"no\" );\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 0.3, "time_ms": 10, "memory_kb": 5712, "score_of_the_acc": -0.1179, "final_rank": 14 }, { "submission_id": "aoj_0362_10776074", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tint n,d[300000],i,flg=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>d[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(d[i]>=20&&d[i+1]<10){\n\t\t\ti++;\n\t\t}\n\t\telse if(d[i]<10){\n\t\t\tflg=1;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(flg==0)\tcout<<\"yes\"<<endl;\n\telse \tcout<<\"no\"<<endl;\n\treturn 0;\n}", "accuracy": 0.25, "time_ms": 50, "memory_kb": 4512, "score_of_the_acc": -0.4031, "final_rank": 18 }, { "submission_id": "aoj_0362_10732710", "code_snippet": "#include <bits/stdc++.h>\n#define asb(a,b) ((a)-(b)>0?(a)-(b):(b)-(a))\n#define atio(v,n) for(int g=0;g<(n);++g)cin >> v[g]\n#define atv(v) for(int g=0;g<((v).size());++g)cin >> v[g]\n#define atdp(v,en) {int bbbbbb=0;for(auto o:v){if(bbbbbb)cout << en;bbbbbb=1;cout << o;}cout << endl;}\n#define atfs(a) printf(\"%lld %lld\\n\",(a).first,(a).second)\n#define ri(n) rp(i,n)\n#define rj(n) rp(j,n)\n#define rk(n) rp(k,n)\n#define rl(n) rp(l,n)\n#define rp(e,c) for(int e=0;e<(c);++e)\n#define rix(s,h) rpx(i,s,h)\n#define rjx(s,h) rpx(j,s,h)\n#define rkx(s,h) rpx(k,s,h)\n#define rlx(s,h) rpx(l,s,h)\n#define rpx(e,s,h) for(int e=s;e<(h);++e)\n#define ci(d,r) ((d)/(r)+(((d)%(r))!=0))\n#define pn {pr(\"No\");return 0;}\n#define py {pr(\"Yes\");return 0;}\n#define pr(a) cout << (a) << endl\n#define sbg(a) sort(bgen(a))\n#define bgen(a) a.begin(),a.end()\n#define INF 114514810\n#define LNF 1ll<<60\n#define upn(a,b) a=min(a,b)\n#define upx(a,b) a=max(a,b)\n#define asr(q,n) (0<=(q) && (q)<(n))\nusing namespace std;\nusing ll=long long;\nusing vi=vector<int>;\nusing vll=vector<ll>;\nusing pii=pair<int,int>;\nusing pll=pair<ll,ll>;\nusing si=set<int>;\nusing sll=set<ll>;\nusing qi=queue<int>;\nusing qll=queue<ll>;\nusing qpii=queue<pii>;\nusing qpll=queue<pll>;\nusing vst=vector<string>;\nusing vsi=vector<si>;\nusing vvi=vector<vi>;\nusing vvl=vector<vll>;\nusing tiii=tuple<int,int,int>;\nusing tlll=tuple<ll,ll,ll>;\nusing mii=map<int,int>;\nusing mll=map<ll,ll>;\nusing stki=stack<int>;\nusing stkll=stack<ll>;\nusing tiis=tuple<int,int,string>;\nint dx[4]={1,0,-1,0};\nint dy[4]={0,-1,0,1};\n\ntemplate <typename T,class Fn>\nstruct sgt{ // 1-indexed\n vector<T> seg;\n int n;\n T d;\n Fn f;\n sgt(vector<T>& n2,T d,Fn f) : n(n2.size()),d(d), f(f){\n int b=n;\n while(!(b&1))b>>=1;\n if(b!=1){\n int c=0;\n b=n;\n while(b){b>>=1;++c;}\n n=1<<c;\n }\n seg=vector<T>(n<<1,d);\n b=n2.size();\n ri(b)seg[n+i]=n2[i];\n b=n;\n while(b>1){\n for(int i=b/2;i<b;++i)seg[i]=f(seg[2*i],seg[2*i+1]);\n b/=2;\n }\n\treturn;\n }\n void update(int pos,T val){\n int i=n+pos;\n seg[i]=val;\n while(i/=2)seg[i]=f(seg[2*i],seg[2*i+1]);\n\treturn;\n }\n T get(int l,int r){\n T tmp=d;\n int p=l;\n int c=0;\n while((p+(1<<c))<=r){\n if(p&(1<<c)){\n tmp=f(tmp,seg[(p>>c)+(n>>c)]);\n p+=1<<c;\n }\n ++c;\n }\n --c;\n while(p<r){\n if((r-p)&(1<<c)){\n tmp=f(tmp,seg[(p>>c)+(n>>c)]);\n p+=(1<<c);\n }\n --c;\n }\n return tmp;\n }\n T get(int pos){\n return seg[n+pos];\n }\n};\n\nint ad(int a,int b){return a+b;}\n\nint main(){\n int n;\n cin >> n;\n vi d(n),enb(n+1),reb(n+1);\n sgt en(enb,0,ad),re(reb,0,ad);\n en.update(0,1);\n en.update(1,-1);\n re.update(0,1);\n re.update(1,-1);\n atv(d);\n ri(n-1){\n if(!en.get(0,i+1))continue;\n int t=min(n,i+1+d[i]/10);\n en.update(i,en.get(i)+1);\n en.update(t,en.get(t)-1);\n }\n ri(n-1){\n if(!re.get(0,i+1))continue;\n int t=min(n,i+1+d[n-1-i]/10);\n re.update(i,re.get(i)+1);\n re.update(t,re.get(t)-1);\n }\n // ri(n+1)pr(en.get(i));\n // ri(n+1)pr(re.get(i));\n if(en.get(0,n)!=0 && re.get(0,n)!=0)pr(\"yes\");else pr(\"no\");\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 14828, "score_of_the_acc": -1.9904, "final_rank": 13 }, { "submission_id": "aoj_0362_10732651", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n;\nvector<int> d;\nbool jump_go(int location) {\n if(location >= n) location = n;\n if (location >= d.size() - 1) {\n return true;\n }\n if(d[location] / 10 == 0){\n return false;\n }\n for (int i = 1; i <= d[location] / 10; i++) {\n if(jump_go(location + i)) return true;\n }\n return false;\n}\n\nbool jump_back(int location) {\n if(location < 0) location = 0;\n if (location <= 0) {\n return true;\n }\n if(d[location] / 10 == 0){\n return false;\n }\n for (int i = 1; i <= d[location] / 10; i++) {\n if(jump_go(location - i)) return true;\n }\n return false;\n}\n\nint main() {\n cin >> n;\n int karivalue;\n for (int i = 0; i < n; i++){\n cin >> karivalue;\n d.push_back(karivalue);\n } \n\n int location = 0;\n if (!jump_go(location)) {\n cout << \"no\" << endl;\n return 0;\n }\n\n location = n - 1;\n if(!jump_back(location)){\n cout << \"no\" << endl;\n return 0;\n }\n\n cout << \"yes\" << endl;\n\n return 0;\n}", "accuracy": 0.275, "time_ms": 40, "memory_kb": 14032, "score_of_the_acc": -1.2142, "final_rank": 16 }, { "submission_id": "aoj_0362_10732563", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n;\nvector<int> d;\nbool jump_go(int location) {\n if(location >= n) location = n;\n if (location >= d.size()) {\n return true;\n }\n if(d[location] / 10 == 0){\n return false;\n }\n for (int i = 1; i <= d[location] / 10; i++) {\n if(jump_go(location + i)) return true;\n }\n return false;\n}\n\nbool jump_back(int location) {\n if(location < 0) location = 0;\n if (location <= 0) {\n return true;\n }\n if(d[location] / 10 == 0){\n return false;\n }\n for (int i = 1; i <= d[location] / 10; i++) {\n if(jump_go(location - i)) return true;\n }\n return false;\n}\n\nint main() {\n cin >> n;\n int karivalue;\n for (int i = 0; i < n; i++){\n cin >> karivalue;\n d.push_back(karivalue);\n } \n\n int location = 0;\n if (!jump_go(location)) {\n cout << \"no\" << endl;\n return 0;\n }\n\n location = n - 1;\n if(!jump_back(location)){\n cout << \"no\" << endl;\n return 0;\n }\n\n cout << \"yes\" << endl;\n\n return 0;\n}", "accuracy": 0.275, "time_ms": 40, "memory_kb": 14928, "score_of_the_acc": -1.3, "final_rank": 17 }, { "submission_id": "aoj_0362_10732416", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rp(e,c) for(int e=0;e<c;e++)\n#define vec(i) vector<i>\n#define ri(n) rp(i, n)\n#define rj(n) rp(j, n)\n#define rk(n) rp(k, n)\n#define all(a) a.begin(),a.end()\n#define mkp(a,b) make_pair(a, b)\n#define st(a) sort(all(a))\n#define rst(a) sort(a.rbegin(), a.rend())\n#define si(a) a.size()\n#define fi first\n#define se second\n#define str string\n#define el endl\n#define Graph vector<vector<int>>\n#define Glit vector<str>\n#define pr(a) cout << a << el\n#define tpr(a, b) cout << a << ' ' << b << el\n#define in(a) cin >> a\n#define twin(a, b) cin >> a >> b\n#define trin(a, b, c) cin >> a >> b >> c\n#define fin(a, b, c, d) cin >> a >> b >> c >> d\n\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing mii = map<int, int>;\nusing mll = map<ll, ll>;\nusing msi = map<str, int>;\nusing mci = map<char, int>;\nusing qll = queue<ll>;\nusing BFS_list = queue<ll>;\nusing DFS_list = stack<ll>;\nusing sei = set<int>;\nusing sell = set<ll>;\nusing dei = deque<int>;\n\nbool prime_judge(int n){\n if (n == 1){\n return false;\n }\n for(int i = 2; i * i <= n;i++){\n if (n % i == 0){\n return false;\n }\n }\n return true;\n}\n\nint kai(int n){\n int num_ = 1;\n for(int i = 1;i <= n;i++){\n num_ *= i;\n }\n return num_;\n}\n\nll max_keta(ll n, ll a){\n int cnt = 0;\n while(n != 0){\n cnt++;\n n /= a;\n }\n return cnt;\n}\n\nstring to16_from10(int x, int size = 0) {\n char hex_buf[16];\n sprintf(hex_buf, \"%X\", x);\n string hex_str = hex_buf;\n if (size == 0) {\n return hex_str;\n }\n string front;\n if (x >= 0) front = \"0\";\n else front = \"F\";\n int diff = size - hex_str.length();\n for (int i=0; i < diff; i++){\n hex_str = front + hex_str;\n }\n if (diff < 0) {\n hex_str.erase(0, -diff);\n }\n return hex_str;\n}\n\npii pi_sa(pii a, pii b){\n pii sa = mkp(a.fi - b.fi, a.se - b.se);\n return sa;\n}\n\npii pi_wa(pii a, pii b){\n pii wa = mkp(a.fi + b.fi, a.se + b.se);\n return wa;\n}\n\nint max_devid(int n, int a){\n if (n % a != 0){\n return 0;\n }\n int cnt = 0;\n while(n != 1){\n cnt++;\n n /= a;\n }\n return cnt;\n}\n\n#define plase(cnt, a) cnt[a.fi][a.se]\n\nint h_n(char hou){\n if (hou == 'U'){\n return 0;\n }else if(hou == 'D'){\n return 2;\n }else if(hou == 'L'){\n return 3;\n }else{\n return 1;\n }\n}\n\npii shi(pii now, int hou){\n switch (hou % 4) {//0:上 1:右 2:下 3:左\n case 0:{\n now.fi--;\n break;\n }\n case 1:{\n now.se++;\n break;\n }\n case 2:{\n now.fi++;\n break;\n }\n case 3:{\n now.se--;\n break;\n }\n }\n return now;\n}\n\n#define MOD_INF 998244353\n\nbool check(ll n){\n ll kura = -1;\n while(n != 0){\n if (kura >= n % 10){\n return false;\n }else{\n kura = n % 10;\n n /= 10;\n }\n }\n return true;\n}\n\nbool big_pair_small(pii a, pii b){\n if (a.fi >= b.fi && a.se >= b.se){\n return true;\n }\n return false;\n}\n\nvector<pair<long long, long long> > prime_factorize(long long N) {\n // 答えを表す可変長配列\n vector<pair<long long, long long> > res;\n\n // √N まで試し割っていく\n for (long long p = 2; p * p <= N; ++p) {\n // N が p で割り切れないならばスキップ\n if (N % p != 0) {\n continue;\n }\n\n // N の素因数 p に対する指数を求める\n int e = 0;\n while (N % p == 0) {\n // 指数を 1 増やす\n ++e;\n\n // N を p で割る\n N /= p;\n }\n\n // 答えに追加\n res.emplace_back(p, e);\n }\n\n // 素数が最後に残ることがありうる\n if (N != 1) {\n res.emplace_back(N, 1);\n }\n return res;\n}\n\n#include <cmath>\n\n\nint main(void) {\n int n;\n cin >> n;\n vec(int) d(n);\n ri(n){\n cin >> d[i];\n d[i] /= 10;\n }\n\n vec(int) kyo(n, 0);\n ri(n - 1){\n kyo[i + 1] = max(kyo[i] - 1, d[i]);\n // cout << kyo[i + 1] << endl;\n if (kyo[i + 1] == 0){\n cout << \"no\" << endl;\n return 0;\n }\n }\n //cout << \"-----\" << endl;\n reverse(all(d));\n vec(int) kyo2(n + 1, 0);\n ri(n - 1){\n kyo[i + 1] = max(kyo[i] - 1, d[i]);\n // cout << kyo[i + 1] << endl;\n if (kyo[i + 1] == 0){\n cout << \"no\" << endl;\n return 0;\n }\n }\n cout << \"yes\" << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6552, "score_of_the_acc": -0.6983, "final_rank": 10 }, { "submission_id": "aoj_0362_10732407", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(T) T.begin(), T.end()\nusing ll = long long;\nusing P = pair<int, int>;\nconst int di[] = {-1, 0, 1, 0};\nconst int dj[] = {0, -1, 0, 1};\n\nll n;\nvector<ll> d;\nbool chk() {\n vector<bool> can(n);\n can[0] = true;\n ll mx=0;\n rep(i, n - 1) {\n if(mx>=i)mx=max(mx,(ll)i+d[i]);\n }\n if (mx>=n-1)\n return true;\n else\n return false;\n}\n\nint main() {\n cin >> n;\n d.resize(n);\n rep(i, n) cin >> d[i];\n rep(i, n) d[i] /= 10;\n if (chk()) {\n reverse(all(d));\n if (chk()) {\n cout << \"yes\" << endl;\n } else\n cout << \"no\" << endl;\n } else\n cout << \"no\" << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5452, "score_of_the_acc": -0.493, "final_rank": 5 }, { "submission_id": "aoj_0362_10732405", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nlong long int a = 0, b = 0, c = 0, d = 0, e = 0, sum = 0, ans = 0, num = 0, counter = 0;\nstring sa, sb, sc, sd, se, sans;\nchar cha, chb, chc, chd, che;\nusing vll = vector<long long>;\nusing vst = vector<string>;\nusing ll = long long;\nusing pll = pair<int64_t, int64_t>;\n#define pa(types) {pair<types, types>}\n#define pb(type_a, type_b) {pair<type_a, type_b>}\n#define rep2(variable2, start2, end2) for (long long variable2 = (start2); variable2 < (end2); variable2++)\n#define rep(variable, end) rep2(variable, 0, end)\n#define in(nyuuryoku) cin >> (nyuuryoku);\n#define out(nuu) \\\n { \\\n auto qwertyui = (nuu); \\\n cout << qwertyui << \"\\n\"; \\\n }\n\nll GCDr(ll a, ll b) {\n // b min\n if (b == 0) {\n return a;\n }\n return GCDr(b, a % b);\n}\nll GCD(ll a, ll b) {\n // b min\n while (b != 0) {\n ll t = a % b;\n a = b;\n b = t;\n }\n return a;\n}\nll LCM(ll a, ll b) { return a * b / GCD(a, b); }\nint main() {\n in(a)vll dist(a), able_go(a), able_back(a);\n rep(i, a){in(dist[i])} ll able_reach_last = 0, able_reach_begin = 0;\n able_go[0] = 1;\n able_back[a - 1] = 1;\n\n // rep(i, a) {\n // d = dist[i];\n // if (able_go[i] == 1) {\n // rep(j, d / 10) {\n // if (i + j + 1 < a) able_go[i + j + 1] = 1;\n // }\n // }\n // }\n // for (ll i = a - 1; i >= 0; i--) {\n // d = dist[i];\n // if (able_back[i]) {\n // rep(j, d / 10) {\n // if (i - j - 1 >= 0) able_back[i - j - 1] = 1;\n // }\n // }\n // }\n // if (able_go[a - 1] == 1 && able_back[0] == 1) out(\"yes\") else out(\"no\")\n able_reach_last = 0;\n able_reach_begin = a - 1;\n\n // go\n rep(i, a) {\n d = dist[i];\n if (i <= able_reach_last) {\n // able_reach_last = able_reach_last + d / 10;\n able_reach_last = max(able_reach_last, (i + d / 10));\n }\n }\n\n // back\n for (ll i = a - 1; i >= 0; i--) {\n d = dist[i];\n if (able_reach_begin <= i) {\n // able_reach_begin = able_reach_begin - d / 10;\n able_reach_begin = min(able_reach_begin, (i - d / 10));\n }\n }\n // if (able_go[a - 1] == 1 && able_back[0] == 1) out(\"yes\") else out\n if (able_reach_last >= a - 1 && able_reach_begin <= 0) out(\"yes\") else out(\"no\")\n\n // out(able_reach_last) out(able_reach_begin)\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10356, "score_of_the_acc": -0.8624, "final_rank": 12 }, { "submission_id": "aoj_0362_10732325", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nlong long int a = 0, b = 0, c = 0, d = 0, e = 0, sum = 0, ans = 0, num = 0, counter = 0;\nstring sa, sb, sc, sd, se, sans;\nchar cha, chb, chc, chd, che;\nusing vll = vector<long long>;\nusing vst = vector<string>;\nusing ll = long long;\nusing pll = pair<int64_t, int64_t>;\n#define pa(types) {pair<types, types>}\n#define pb(type_a, type_b) {pair<type_a, type_b>}\n#define rep2(variable2, start2, end2) for (long long variable2 = (start2); variable2 < (end2); variable2++)\n#define rep(variable, end) rep2(variable, 0, end)\n#define in(nyuuryoku) cin >> (nyuuryoku);\n#define out(nuu) \\\n { \\\n auto qwertyui = (nuu); \\\n cout << qwertyui << \"\\n\"; \\\n }\n\nll GCDr(ll a, ll b) {\n // b min\n if (b == 0) {\n return a;\n }\n return GCDr(b, a % b);\n}\nll GCD(ll a, ll b) {\n // b min\n while (b != 0) {\n ll t = a % b;\n a = b;\n b = t;\n }\n return a;\n}\nll LCM(ll a, ll b) { return a * b / GCD(a, b); }\nint main() {\n in(a)vll dist(a), able_go(a), able_back(a);\n rep(i, a){in(dist[i])} ll able_reach_last = 0, able_reach_begin = 0;\n able_go[0] = 1;\n able_back[a - 1] = 1;\n\n // rep(i, a) {\n // d = dist[i];\n // if (able_go[i] == 1) {\n // rep(j, d / 10) {\n // if (i + j + 1 < a) able_go[i + j + 1] = 1;\n // }\n // }\n // }\n // for (ll i = a - 1; i >= 0; i--) {\n // d = dist[i];\n // if (able_back[i]) {\n // rep(j, d / 10) {\n // if (i - j - 1 >= 0) able_back[i - j - 1] = 1;\n // }\n // }\n // }\n // if (able_go[a - 1] == 1 && able_back[0] == 1) out(\"yes\") else out(\"no\")\n able_reach_last = 0;\n able_reach_begin = a - 1;\n\n // go\n rep(i, a) {\n d = dist[i];\n if (i <= able_reach_last) {\n able_reach_last = able_reach_last + d / 10;\n }\n }\n\n // back\n for (ll i = a - 1; i >= 0; i--) {\n d = dist[i];\n if (able_reach_begin <= i) {\n able_reach_begin = able_reach_begin - d / 10;\n }\n }\n // if (able_go[a - 1] == 1 && able_back[0] == 1) out(\"yes\") else out\n if (able_reach_last >= a - 1 && able_reach_begin <= 0) out(\"yes\") else out(\"no\")\n}", "accuracy": 0.3, "time_ms": 40, "memory_kb": 10356, "score_of_the_acc": -0.8624, "final_rank": 15 } ]
aoj_0355_cpp
文字列ゲーム あなたは、双子のアイ君とヅー君に文字列を使ったゲームのプログラムをプレゼントしました。このゲームでは、アイ君とヅー君が文字列の中から部分文字列をそれぞれ選び、それらを比較して小さい方を選んだ人に得点が加算されます。二人は競い合い、何度もゲームを行いました。ところが、同じ文字列に対して何度もゲームをしているうちに飽きてしまいました。そこであなたは、文字列が変化するようにプログラムを修正することにしました。 長さ N の文字列 U と Q 個の命令文が与えられたとき、以下の命令を処理するプログラムを作成せよ。 文字列 U の指定された範囲にあるすべての文字を、指定された文字に置き換える。 文字列 U の指定された2つの部分文字列 S , T を辞書順で比較して、それらの大小関係を出力する。 Input 入力は以下の形式で与えられる。 N U Q query 1 query 2 : query Q 1行目に文字列の長さ N (1 ≤ N ≤ 200000)、2行目に文字列 U (英小文字のみを含む文字列)が与えられる。3行目に命令の数 Q (1 ≤ Q ≤ 100000) が与えられる。続く Q 行に i 番目の命令 query i が与えられる。各 query i は、以下のいずれかの形式で与えられる。 set x y z または comp a b c d set x y z は文字列 U の x 文字目から y 文字目までを、指定された文字 z に置き換えることを表す。ただし、1 ≤ x ≤ y ≤ N であり、 z は英小文字である。 comp a b c d は文字列 U の a 文字目から b 文字目までの部分文字列を S 、文字列 U の c 文字目から d 文字目までの部分文字列を T としたとき、文字列 S と文字列 T を辞書順で比較することを表す。ただし、1 ≤ a ≤ b ≤ N かつ 1 ≤ c ≤ d ≤ N である。 Output 各 comp 命令について、 S の方が小さいならば「s」、 T の方が小さいならば「t」、両者が一致しているならば「e」と1行に出力する。 Sample Input 1 13 aizualgorithm 9 comp 1 1 4 5 comp 2 6 1 5 set 9 12 b comp 9 9 10 10 comp 5 8 1 4 set 1 10 z set 11 13 x comp 8 10 1 5 comp 1 5 1 5 Sample Output 1 s t e t s e
[ { "submission_id": "aoj_0355_10867757", "code_snippet": "#include <bits/stdc++.h>\n#define N 500500\n\ntypedef long long ll;\nusing namespace std;\n\nconst int MOD = 1e9 + 7;\n\nchar c[N * 4];\n\nint mult(ll x, ll y) {\n return (x * y) % MOD;\n}\n\nint sm(ll x, ll y) {\n return (x + y) % MOD;\n}\n\nint P[N], sum_P[N], t[N * 4], psh[N * 4];\n\nvoid bld(int v, int l, int r) {\n if (l == r) {\n t[v] = 1 + c[l] - 'a';\n return;\n }\n\n int md = (l + r) / 2;\n\n bld(v + v, l, md);\n bld(v + v + 1, md + 1, r);\n\n t[v] = sm(t[v + v], mult(P[md - l + 1], t[v + v + 1]));\n}\n\nvoid push(int v, int tl, int tr) {\n if (psh[v] == 0)\n return;\n\n t[v] = mult(psh[v], sum_P[tr - tl]);\n\n psh[v + v] = psh[v + v + 1] = psh[v];\n\n psh[v] = 0;\n}\n\nint intersect(int l, int r, int L, int R) {\n int mx = max(l, L);\n int mn = min(R, r);\n\n return max(0, mn - mx + 1);\n}\n\nint get(int v, int tl, int tr, int l, int r) {\n push(v, tl, tr);\n\n if (l <= tl && tr <= r)\n return t[v];\n\n if (r < tl || tr < l)\n return 0;\n\n int md = (tl + tr) / 2;\n\n int a = get(v + v, tl, md, l, r);\n int b = get(v + v + 1, md + 1, tr, l, r);\n\n return sm(a, mult(b, P[intersect(tl, md, l, r)]));\n}\n\nvoid upd(int v, int tl, int tr, int l, int r, char c) {\n push(v, tl, tr);\n\n if (l <= tl && tr <= r) {\n psh[v] = 1 + c - 'a';\n\n push(v, tl, tr);\n\n return;\n }\n\n if (r < tl || tr < l)\n return;\n\n int md = (tl + tr) / 2;\n\n upd(v + v, tl, md, l, r, c);\n upd(v + v + 1, md + 1, tr, l, r, c);\n\n t[v] = sm(t[v + v], mult(P[md - tl + 1], t[v + v + 1]));\n}\n\nint main() {\n\n sum_P[0] = P[0] = 1;\n for (int i = 1; i < N; i++)\n {\n P[i] = mult(P[i - 1], 31);\n sum_P[i] = sm(sum_P[i - 1], P[i]);\n }\n\n int n;\n cin >> n;\n\n for (int i = 1; i <= n; i++)\n cin >> c[i];\n\n bld(1, 1, n);\n\n int q;\n cin >> q;\n\n while (q--) {\n string s;\n cin >> s;\n if (s == \"comp\") {\n int l1, l2, r1, r2;\n cin >> l1 >> r1 >> l2 >> r2;\n\n int len = min(r1 - l1 + 1, r2 - l2 + 1);\n\n int L = 0, R = len;\n\n while (L < R) {\n int md = (L + R + 1) / 2;\n\n int hsh1 = get(1, 1, n, l1, l1 + md - 1);\n int hsh2 = get(1, 1, n, l2, l2 + md - 1);\n\n if (hsh1 == hsh2) {\n L = md;\n } else R = md - 1;\n }\n\n if (len == L) {\n if (r2 - l2 == r1 - l1) {\n cout << \"e\" << '\\n';\n continue;\n }\n\n if (r2 - l2 + 1 == len) {\n cout << \"t\" << '\\n';\n continue;\n }\n\n cout << \"s\" << '\\n';\n continue;\n }\n\n int c1 = get(1, 1, n, l1 + L, l1 + L);\n int c2 = get(1, 1, n, l2 + L, l2 + L);\n\n if (c1 < c2) {\n cout << \"s\" << '\\n';\n } else {\n cout << \"t\" << '\\n';\n }\n\n } else {\n int l, r;\n char t;\n\n cin >> l >> r;\n cin >> t;\n\n upd(1, 1, n, l, r, t);\n }\n }\n}", "accuracy": 1, "time_ms": 1010, "memory_kb": 19720, "score_of_the_acc": -0.4274, "final_rank": 7 }, { "submission_id": "aoj_0355_10203898", "code_snippet": "// AOJ #355\n// String Game 2025.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nchar temp[200005];\nstring Cins() { // 文字列の入力 スペース以下の文字で入力終了\n char *s = temp;\n\tdo *s = gc();\n\twhile (*s++ > ' ');\n\t*(s-1) = 0;\n string input(temp); // 文字配列からstringを作成\n return input;\n}\n\nbool Cset() { // 文字列の入力 スペース以下の文字で入力終了\n char temp[10];\n char *s = temp;\n\tdo *s = gc();\n\twhile (*s++ > ' ');\n return temp[0] == 's';\n}\n\nvoid Cout(char e) {\n\tpc(e), pc('\\n');\n}\n\nconst int MOD1 = 1000000007;\nconst int MOD2 = 1000000009;\nconst int P = 131;\n \nvector<ll> pow1, pow2, geo1, geo2;\n \nstruct Node {\n int l, r;\n ll hash1, hash2;\n bool lazy;\n int lazyVal;\n};\n \nvector<Node> segTree;\n \nstruct QueryRes {\n int len;\n ll hash1, hash2;\n};\n \nQueryRes combineQuery(const QueryRes &left, const QueryRes &right) {\n QueryRes res;\n res.len = left.len + right.len;\n res.hash1 = ( left.hash1 * pow1[right.len] + right.hash1 ) % MOD1;\n res.hash2 = ( left.hash2 * pow2[right.len] + right.hash2 ) % MOD2;\n return res;\n}\n \nvoid buildTree(const string &s, int idx, int l, int r) {\n segTree[idx].l = l;\n segTree[idx].r = r;\n segTree[idx].lazy = false;\n if(l == r){\n int cval = s[l-1] - 'a' + 1;\n segTree[idx].hash1 = cval;\n segTree[idx].hash2 = cval;\n return;\n }\n int mid = (l + r) / 2;\n buildTree(s, idx*2, l, mid);\n buildTree(s, idx*2+1, mid+1, r);\n int rightLen = segTree[idx*2+1].r - segTree[idx*2+1].l + 1;\n segTree[idx].hash1 = ( segTree[idx*2].hash1 * pow1[rightLen] + segTree[idx*2+1].hash1 ) % MOD1;\n segTree[idx].hash2 = ( segTree[idx*2].hash2 * pow2[rightLen] + segTree[idx*2+1].hash2 ) % MOD2;\n}\n \nvoid applyLazy(int idx, int val) {\n int len = segTree[idx].r - segTree[idx].l + 1;\n segTree[idx].hash1 = ( (ll) val * geo1[len] ) % MOD1;\n segTree[idx].hash2 = ( (ll) val * geo2[len] ) % MOD2;\n segTree[idx].lazy = true;\n segTree[idx].lazyVal = val;\n}\n \nvoid pushDown(int idx) {\n if(segTree[idx].lazy) {\n applyLazy(idx*2, segTree[idx].lazyVal);\n applyLazy(idx*2+1, segTree[idx].lazyVal);\n segTree[idx].lazy = false;\n }\n}\n \nvoid updateTree(int idx, int ql, int qr, int val) {\n int l = segTree[idx].l, r = segTree[idx].r;\n if(ql <= l && r <= qr) {\n applyLazy(idx, val);\n return;\n }\n pushDown(idx);\n int mid = (l + r) / 2;\n if(ql <= mid) updateTree(idx*2, ql, qr, val);\n if(qr > mid) updateTree(idx*2+1, ql, qr, val);\n int rightLen = segTree[idx*2+1].r - segTree[idx*2+1].l + 1;\n segTree[idx].hash1 = ( segTree[idx*2].hash1 * pow1[rightLen] + segTree[idx*2+1].hash1 ) % MOD1;\n segTree[idx].hash2 = ( segTree[idx*2].hash2 * pow2[rightLen] + segTree[idx*2+1].hash2 ) % MOD2;\n}\n \nQueryRes queryTree(int idx, int ql, int qr) {\n int l = segTree[idx].l, r = segTree[idx].r;\n if(ql <= l && r <= qr) {\n QueryRes res;\n res.len = r - l + 1;\n res.hash1 = segTree[idx].hash1;\n res.hash2 = segTree[idx].hash2;\n return res;\n }\n pushDown(idx);\n int mid = (l + r) / 2;\n QueryRes res;\n res.len = 0; res.hash1 = 0; res.hash2 = 0;\n bool started = false;\n if(ql <= mid) {\n QueryRes leftRes = queryTree(idx*2, ql, qr);\n res = leftRes;\n started = true;\n }\n if(qr > mid) {\n QueryRes rightRes = queryTree(idx*2+1, ql, qr);\n if(!started) res = rightRes;\n else res = combineQuery(res, rightRes);\n }\n return res;\n}\n \nint getCharVal(int pos) {\n QueryRes qr = queryTree(1, pos, pos);\n return (int)qr.hash1;\n}\n \nint main(){\n int N = Cin();\n string U = Cins();\n int Q = Cin();\n \n pow1.resize(N+1); pow2.resize(N+1);\n geo1.resize(N+1); geo2.resize(N+1);\n pow1[0] = 1; pow2[0] = 1;\n for (int i = 1; i <= N; i++){\n pow1[i] = (pow1[i-1] * P) % MOD1;\n pow2[i] = (pow2[i-1] * P) % MOD2;\n }\n geo1[0] = 0; geo2[0] = 0;\n for (int i = 1; i <= N; i++){\n geo1[i] = (geo1[i-1] + pow1[i-1]) % MOD1;\n geo2[i] = (geo2[i-1] + pow2[i-1]) % MOD2;\n }\n \n segTree.resize(4 * N + 10);\n buildTree(U, 1, 1, N);\n \n for (int qi = 0; qi < Q; qi++){\n bool cmd = Cset();\n if (cmd){\n int x = Cin(), y = Cin();\n int val = gc() - 'a' + 1; gc();\n updateTree(1, x, y, val);\n } else {\n int a = Cin(), b = Cin(), c = Cin(), d = Cin();\n int lenS = b - a + 1;\n int lenT = d - c + 1;\n int L = min(lenS, lenT);\n \n int lo = 0, hi = L + 1;\n while (lo + 1 < hi) {\n int mid = (lo + hi) >> 1;\n QueryRes qS = queryTree(1, a, a + mid - 1);\n QueryRes qT = queryTree(1, c, c + mid - 1);\n if(qS.hash1 == qT.hash1 && qS.hash2 == qT.hash2) lo = mid;\n else hi = mid;\n }\n \n if(lo == L){\n if(lenS == lenT) Cout('e');\n else if(lenS < lenT) Cout('s');\n else Cout('t');\n } else {\n int charS = getCharVal(a + lo);\n int charT = getCharVal(c + lo);\n if(charS < charT) Cout('s');\n else Cout('t');\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 850, "memory_kb": 34712, "score_of_the_acc": -0.5076, "final_rank": 8 }, { "submission_id": "aoj_0355_9037082", "code_snippet": "#pragma region Macros\n\n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2\")\n\n#include <bits/extc++.h>\nusing namespace std;\nusing namespace __gnu_pbds;\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n\n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n\n#define next asdnext\n#define prev asdprev\n\nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\nconst int MOD = 998244353;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n\nchrono::system_clock::time_point start, now;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n\n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\n\npair<int, int> max(const pair<int, int> &a, const pair<int, int> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\npair<int, int> min(const pair<int, int> &a, const pair<int, int> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n\n\nint countl_zero(int x) { return __builtin_clzll(x); }\nint countl_one(int x) {\n int ret = 0; while (x % 2) { x /= 2; ret++; } return ret;\n}\nint countr_zero(int x) { return __builtin_ctzll(x); }\nint countr_one(int x) {\n int ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\nint popcount(int x) { return __builtin_popcountll(x); }\nint unpopcount(int x) { return 64 - __builtin_clzll(x) - __builtin_popcountll(x); }\n\nint top_bit(int x) { return 63 - __builtin_clzll(x);} // 2^kの位\nint bot_bit(int x) { return __builtin_ctz(x);} // 2^kの位\nint MSB(int x) { return 1 << (63 - __builtin_clzll(x)); } // mask\nint LSB(int x) { return (x & -x); } // mask\n\nint bit_width(int x) { return 64 - __builtin_clzll(x); } // 桁数\nint ceil_log2(int x) { return 63 - __builtin_clzll(x); }\nint bit_floor(int x) { return 1 << (63 - __builtin_clzll(x)); }\nint floor_log2(int x) { return 64 - __builtin_clzll(x-1); }\nint bit_ceil(int x) { return 1 << (64 - __builtin_clzll(x-1)) - (x==1); }\n\nint hamming(int a, int b) { return popcount(a ^ b); }\nint compcnt(int x) { return (popcount(x^(x >> 1)) + (x&1)) / 2; }\n\n\ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n\n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n\nusing mint = Modint<MOD>;\n// using Mint = modint998244353;\n\nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n\nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0 && x > 0);\n if (x == 1) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n\nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n\n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n\n\n#pragma endregion\n\nunsigned _bit_ceil(unsigned n) {\n unsigned x = 1;\n while (x < (unsigned)(n)) x *= 2;\n return x;\n}\n\nint _countr_zero(unsigned n) {\n return __builtin_ctz(n);\n}\n\ntemplate <class S,\n S (*op)(S, S),\n S (*e)(),\n class F,\n S (*mapping)(F, S),\n F (*composition)(F, F),\n F (*id)()>\nstruct lazy_segtree {\npublic:\n lazy_segtree() : lazy_segtree(0) {}\n explicit lazy_segtree(int n) : lazy_segtree(vector<S>(n, e())) {}\n explicit lazy_segtree(const vector<S>& v) : _n(int(v.size())) {\n size = (int)_bit_ceil((unsigned)(_n));\n log = _countr_zero((unsigned)size);\n d = vector<S>(2 * size, e());\n lz = vector<F>(size, id());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n return d[p];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return e();\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n S sml = e(), smr = e();\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n void apply(int p, F f) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = mapping(f, d[p]);\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n void apply(int l, int r, F f) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return;\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n {\n int l2 = l, r2 = r;\n while (l < r) {\n if (l & 1) all_apply(l++, f);\n if (r & 1) all_apply(--r, f);\n l >>= 1;\n r >>= 1;\n }\n l = l2;\n r = r2;\n }\n\n for (int i = 1; i <= log; i++) {\n if (((l >> i) << i) != l) update(l >> i);\n if (((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n\n template <bool (*g)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return g(x); });\n }\n template <class G> int max_right(int l, G g) {\n assert(0 <= l && l <= _n);\n assert(g(e()));\n if (l == _n) return _n;\n l += size;\n for (int i = log; i >= 1; i--) push(l >> i);\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!g(op(sm, d[l]))) {\n while (l < size) {\n push(l);\n l = (2 * l);\n if (g(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*g)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return g(x); });\n }\n template <class G> int min_left(int r, G g) {\n assert(0 <= r && r <= _n);\n assert(g(e()));\n if (r == 0) return 0;\n r += size;\n for (int i = log; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < size) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\nprivate:\n int _n, size, log;\n vector<S> d;\n vector<F> lz;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n void all_apply(int k, F f) {\n d[k] = mapping(f, d[k]);\n if (k < size) lz[k] = composition(f, lz[k]);\n }\n void push(int k) {\n all_apply(2 * k, lz[k]);\n all_apply(2 * k + 1, lz[k]);\n lz[k] = id();\n }\n};\n\nconst int base = 34141;\nconst int MOD1 = 1919191903;\nusing Mint = Modint<MOD1>;\nvector<Mint> P, sum;\n\nusing F = int;\nusing S = pair<Mint, int>; // 値, 幅\nconst F ID = 300;\nS op(S x, S y) {\n Mint a = x.first * P[y.second] + y.first;\n int b = x.second + y.second;\n return make_pair(a, b);\n}\nS e() { return make_pair(0, 0); }\n\nS mapping(F f, S x) {\n if (f == ID) return x;\n else return make_pair(sum[x.second]*f, x.second);\n}\nF composition(F f, F g) { return (f == ID ? g : f); }\nF id() { return ID; }\n\nusing S2 = long long;\nusing F2 = long long;\n\nconst S2 inf2 = INFL;\nconst F2 ID2 = INFL;\n\nS2 op2(S2 a, S2 b) { return min(a, b); }\nS2 e2() { return inf2; }\nS2 mapping2(F2 f, S2 x) { return (f == ID2 ? x : f); }\nF2 composition2(F2 f, F2 g) { return (f == ID2 ? g : f); }\nF2 id2() { return ID2; }\n\nstruct RollingHash {\n int N;\n lazy_segtree<S, op, e, F, mapping, composition, id> H, revH; // ハッシュ\n lazy_segtree<S2, op2, e2, F2, mapping2, composition2, id2> s; // 生文字列\n\n RollingHash(string &str) : N((int)str.size()) {\n if (P.size() == 0) {\n P.resize(N + 2);\n sum.resize(N + 3);\n P[0] = 1;\n for (int i = 1; i <= N + 1; i++) {\n P[i] = P[i - 1] * base;\n }\n for (int i = 0; i <= N; i++) {\n sum[i + 1] = sum[i] + P[i];\n }\n }\n\n lazy_segtree<S, op, e, F, mapping, composition, id> h(N + 1), revh(N + 1);\n for (int i = 0; i < N; i++) {\n h.set(i, make_pair(str[i], 1));\n revh.set(i, make_pair(str[N - 1 - i], 1));\n }\n H = h;\n revH = revh;\n\n lazy_segtree<S2, op2, e2, F2, mapping2, composition2, id2> s2(N);\n for (int i = 0; i < N; i++) {\n s2.set(i, str[i]);\n }\n s = s2;\n }\n\n Mint get_hash(int l, int r) {\n Mint ret = H.prod(l, r).first;\n return ret;\n }\n\n bool is_palindrome(int l, int r) {\n Mint h1 = H.prod(l, r).first;\n Mint h2 = revH.prod(N - r, N - l).first;\n if (h1 == h2) return true;\n else return false;\n }\n\n void set(int l, int r, char c) {\n H.apply(l, r, c);\n revH.apply(N - r, N - l, c);\n s.apply(l, r, c);\n }\n void set(int k, char c) {\n set(k, k + 1, c);\n }\n\n static int lcp(RollingHash &RS, RollingHash &RT, int ls, int lt) {\n int ok = 0, ng = min(RS.size() - ls, RT.size() - lt) + 1;\n while (ok + 1 < ng) {\n int mid = (ok + ng) / 2;\n (RS.get_hash(ls, mid + ls) == RT.get_hash(lt, mid + lt) ? ok : ng) = mid;\n }\n return ok;\n }\n\n static int strcmp(RollingHash &RS, RollingHash &RT,\n int ls, int lt, int rs = -1, int rt = -1) {\n if (rs == -1) rs = RS.size();\n if (rt == -1) rt = RT.size();\n int n = min<int>({lcp(RS, RT, ls, lt), rs - ls, rt - lt});\n\n return ls + n == rs ? lt + n == rt ? 0 : -1\n : lt + n == rt ? 1\n : RS.s.get(ls + n) < RT.s.get(lt + n) ? -1\n : 1;\n }\n\n int size() { return N; }\n};\n\nsigned main() {\n int N, Q;\n string str;\n cin >> N >> str >> Q;\n\n RollingHash RS(str);\n\n for (int i = 0; i < Q; i++) {\n string t;\n cin >> t;\n if (t == \"set\") {\n int l, r;\n char c;\n cin >> l >> r >> c;\n l--; r--;\n\n RS.set(l, r + 1, c);\n } else {\n int l1, r1, l2, r2;\n cin >> l1 >> r1 >> l2 >> r2;\n l1--; r1--; l2--; r2--;\n int com = RS.strcmp(RS, RS, l1, l2, r1 + 1, r2 + 1);\n if (com == -1) cout << \"s\" << endl;\n else if (com == 0) cout << \"e\" << endl;\n else cout << \"t\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 62536, "score_of_the_acc": -0.7286, "final_rank": 12 }, { "submission_id": "aoj_0355_8719022", "code_snippet": "#pragma region Template\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing vvi = vector<vi>;\nusing vvl = vector<vl>;\n#define REP(i, n) for (int i = 0, i##_len = (n); i < i##_len; ++i)\n#define FOR(i, a, b) for (int i = (a), i##_len = (b); i < i##_len; ++i)\n#define ALL(x) (x).begin(), (x).end() // sortなどの引数を省略したい\n#ifdef _DEBUG\n#define PRE_COMMAND \\\n cout << fixed << setprecision(15); \\\n cin.rdbuf(in.rdbuf()), cout.rdbuf(out.rdbuf());\n#else\n#define PRE_COMMAND \\\n cout << fixed << setprecision(15); \\\n ios::sync_with_stdio(false), cin.tie(0);\n#endif\nconst double EPS = 1e-10, PI = acos(-1.0);\n// 標準入出力\ntemplate <size_t... Is, class Tp>\nvoid CIN_TUPLE(istream& is, Tp& t, index_sequence<Is...>) {\n ((is >> get<Is>(t)), ...);\n}\ntemplate <class... Tp> istream& operator>>(istream& is, tuple<Tp...>& t) {\n CIN_TUPLE(is, t, index_sequence_for<Tp...>());\n return is;\n}\ntemplate <class T> istream& operator>>(istream& is, vector<T>& vec) {\n for (T& x : vec) is >> x;\n return is;\n}\ntemplate <size_t... Is, class Tp>\nvoid COUT_TUPLE(ostream& os, const Tp& t, index_sequence<Is...>) {\n ((os << (Is == 0 ? \"\" : \" \") << get<Is>(t)), ...);\n}\ntemplate <class... Tp> ostream& operator<<(ostream& os, const tuple<Tp...>& t) {\n COUT_TUPLE(os, t, index_sequence_for<Tp...>());\n return os;\n}\ntemplate <class T> ostream& COUT_MAIN(ostream& os, const T& v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class T> ostream& operator<<(ostream& os, const vector<T>& v) {\n return COUT_MAIN(os, v);\n}\ntemplate <class T> ostream& operator<<(ostream& os, const set<T>& v) {\n return COUT_MAIN(os, v);\n}\ntemplate <class T, class S>\nostream& operator<<(ostream& os, const map<T, S>& m) {\n for (auto it = m.begin(); it != m.end(); ++it) {\n os << (it == m.begin() ? \"\" : \"\\n\")\n << make_tuple(it->first, it->second);\n }\n return os;\n}\n// 出力用関数\nvoid PRINT() {}\ntemplate <class Head> void PRINT(Head&& head) { cout << head << '\\n'; }\ntemplate <class Head, class... Tail> void PRINT(Head&& head, Tail&&... tail) {\n cout << head << ' ', PRINT(forward<Tail>(tail)...);\n}\ntemplate <class T> auto MAX(T& seq) { return *max_element(ALL(seq)); }\ntemplate <class T> auto MIN(T& seq) { return *min_element(ALL(seq)); }\ntemplate <class T> auto SUM(T& seq) {\n return accumulate(++ALL(seq), *seq.begin());\n}\ntemplate <class T> void REV(T& seq) { reverse(ALL(seq)); }\ntemplate <class T> void SORT(T& seq) { sort(ALL(seq)); }\ntemplate <class T, class S> void SORT(T& seq, S ordr) { sort(ALL(seq), ordr); }\ntemplate <class T> void SORTR(vector<T>& seq) { sort(ALL(seq), greater<T>()); }\nvoid yn(bool flag) { PRINT(flag ? \"Yes\" : \"No\"); }\ntemplate <class T> ll pow(ll n, T k) {\n ll now = 1;\n while (k) {\n if (k & 1) now *= n;\n k >>= 1;\n if (k) n *= n;\n }\n return now;\n}\ntemplate <class T> ll pow(int n, T k) { return pow((ll)n, k); }\ntemplate <class T> int pow(int n_0, T k, int mod) {\n n_0 = ((n_0 % mod) + mod) % mod;\n unsigned long long n = (unsigned long long)n_0, now = 1;\n while (k) {\n if (k & 1) now = (now * n) % mod;\n n = (n * n) % mod;\n k >>= 1;\n }\n return (int)now;\n}\n#pragma endregion Template\n\ntemplate <class S, S (*op)(S, S), S (*e)(), class F, S (*mapping)(F, S),\n F (*composition)(F, F), F (*id)()>\nstruct lazy_segtree {\n int n, num, depth = 0;\n std::vector<S> d;\n std::vector<F> lz;\n // 元の配列, op, e, mapping, composition, id\n lazy_segtree(vector<S>& base) { init(base); }\n lazy_segtree() {}\n // 初期化に使用する関数\n void init(vector<S>& base) {\n n = int(base.size());\n while ((1 << depth) < n) depth++;\n num = 1 << depth;\n d = std::vector<S>(num << 1, e());\n lz = std::vector<F>(num, id());\n for (int i = 0; i < n; i++) d[num + i] = base[i];\n for (int i = num - 1; i >= 1; i--) update(i);\n }\n // 頂点kについて、dを下から計算しなおす(上方向に更新)\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n // 頂点kについて、dとlzにそれぞれfを作用させる\n void propagate(F f, int k) {\n d[k] = mapping(f, d[k]);\n if (k < num) lz[k] = composition(f, lz[k]);\n }\n // 頂点kについて、lzの中身を一つ下に伝搬させ、lzを単位元にする\n void push(int k) {\n propagate(lz[k], 2 * k);\n propagate(lz[k], 2 * k + 1);\n lz[k] = id();\n }\n // 配列の位置iの値をxにして、根まで順番に上に伝播させる\n void set(S x, int i) {\n assert(0 <= i && i < n);\n i += num;\n for (int j = depth; j >= 1; j--) push(i >> j);\n d[i] = x;\n for (int j = 1; j <= depth; j++) update(i >> j);\n }\n // 配列の[l, r)の区間積を取得する\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= n);\n // 区間サイズが0なら単位元を出力\n if (l == r) return e();\n l += num, r += num;\n // 区間の大きい方から見て行って、lやrが区間の左端でなければpushして伝播\n for (int i = depth; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push(r >> i);\n }\n S sml = e(), smr = e();\n // 既に必要箇所の伝播が終わっているので、下から順番にopでマージしていく\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1, r >>= 1;\n }\n return op(sml, smr);\n }\n // 全区間の積を出力\n S all_prod() { return d[1]; }\n // 配列の位置pにfを作用させる\n void apply(F f, int i) {\n assert(0 <= i && i < n);\n i += num;\n // 上から順番にpushで伝播\n for (int j = depth; j >= 1; j--) push(i >> j);\n // pにfを作用させる(d[i]に直接作用させる)\n d[i] = mapping(f, d[i]);\n // 上方向に向かって更新する\n for (int j = 1; j <= depth; j++) update(i >> j);\n }\n // [l, r)にfを作用させる\n void apply(F f, int l, int r) {\n assert(0 <= l && l <= r && r <= n);\n // 区間サイズが0のときは何もしない\n if (l == r) return;\n l += num, r += num;\n for (int i = depth; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n // ACLではupdate((r - 1) >> i)になっているが、同じなはず\n if (((r >> i) << i) != r) push(r >> i);\n }\n int l2 = l, r2 = r;\n while (l < r) {\n // 必要な箇所に下からfを作用させていく\n if (l & 1) propagate(f, l++);\n if (r & 1) propagate(f, --r);\n l >>= 1, r >>= 1;\n }\n l = l2, r = r2;\n // 上方向に向かって更新する\n for (int i = 1; i <= depth; i++) {\n if (((l >> i) << i) != l) update(l >> i);\n // ACLではupdate((r - 1) >> i)になっているが、同じなはず\n if (((r >> i) << i) != r) update(r >> i);\n }\n }\n // op(a[l], a[l+1], ..., a[r-1]) = Trueかつ\n // op(a[l], a[l+1], ..., a[r]) = Falseとなるrを出力、\n // 下式を満たすrがなければnを出力\n template <class G> int max_right(G g, int l = 0) {\n assert(0 <= l && l <= n);\n assert(g(e()));\n if (l == n) return n;\n l += num;\n // 必要な部分について伝播を行っておく\n for (int i = depth; i >= 1; i--) push(l >> i);\n S sm = e();\n // 1が立っているbitが1つになるまで、\n // つまり配列を右端まで探索し終わるまで繰り返す\n do {\n // lを含む区間が右側に来るまで上る\n while (!(l & 1)) l >>= 1;\n // もしダメだったら下に検索していく\n if (!g(op(sm, d[l]))) {\n while (l < num) {\n push(l);\n l <<= 1;\n if (g(op(sm, d[l]))) sm = op(sm, d[l++]);\n }\n return l - num;\n }\n // OKだったら一つ右にずれる、配列の端にいたらl=2^xの形になる\n sm = op(sm, d[l++]);\n } while ((l & -l) != l);\n return n;\n }\n // op(a[l], a[l+1], ..., a[r-1]) = Trueかつ\n // op(a[l-1], a[l], ..., a[r-1]) = Falseとなるlを出力、\n // 下式を満たすlがなければ0を出力\n template <class G> int min_left(G g, int r = -1) {\n if (r == -1) r = n;\n assert(0 <= r && r <= n);\n assert(g(e()));\n if (r == 0) return 0;\n r += num;\n for (int i = depth; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while ((r & 1) && r > 1) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < num) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) sm = op(d[r--], sm);\n }\n return r + 1 - num;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n // 一点取得:配列の位置iの値を取得する\n S operator[](int i) {\n assert(0 <= i && i < n);\n i += num;\n // 根から順番にpush\n for (int j = depth; j >= 1; j--) push(i >> j);\n // 伝播が終わったので出力\n return d[i];\n }\n // coutによる出力\n friend ostream& operator<<(\n ostream& os, lazy_segtree<S, op, e, F, mapping, composition, id>& s) {\n for (int i = 0; i < s.num; i++) s.push(i);\n if (s.num > 0) os << s.d[s.num];\n for (int i = 1; i < s.n; i++) os << ' ' << s.d[i + s.num];\n return os;\n }\n};\n\n// baseの作成\nstd::random_device rd;\nstd::mt19937 eng(1);\nstd::uniform_int_distribution<int> distr(1000000, 999999999);\nint base_of_rollinghash = distr(eng);\n\nstruct rolling_hash_seg {\n using ul = unsigned long long;\n static const ul mod = (1ULL << 61) - 1;\n static const ul mask31 = (1ULL << 31) - 1, mask30 = (1ULL << 30) - 1;\n static vector<ul> pow_list;\n static ul inv_of_base;\n // 二項演算と単位元\n static const ul ID = 8e18;\n static array<ul, 2> op(array<ul, 2> l, array<ul, 2> r) {\n return {calcmod(l[0] + mul(r[0], pow_list[l[1]])), l[1] + r[1]};\n }\n static array<ul, 2> e() { return {0, 0}; }\n static array<ul, 2> mapping(ul f, array<ul, 2> x) {\n if (f != ID) {\n x[0] = mul(calcmod(1 - pow_list[x[1]] + mod), mul(f, inv_of_base));\n }\n return x;\n }\n static ul composition(ul f, ul g) { return (f == ID ? g : f); }\n static ul id() { return ID; }\n // 本体のセグ木\n lazy_segtree<array<ul, 2>, op, e, ul, mapping, composition, id> seg;\n // 初期化\n rolling_hash_seg(const string& seq)\n : rolling_hash_seg(vector<int>(seq.begin(), seq.end())) {}\n rolling_hash_seg(const vector<int>& seq) {\n int n = (int)seq.size();\n pow_list.assign(n + 1, 1);\n for (int i = 0; i < n; i++) {\n pow_list[i + 1] = mul(pow_list[i], base_of_rollinghash);\n }\n // ここで逆数計算\n ul x = (1 - base_of_rollinghash + mod) % mod, p = mod - 2;\n while (p) {\n if (p & 1) inv_of_base = mul(inv_of_base, x);\n x = mul(x, x);\n p >>= 1;\n }\n vector<array<ul, 2>> v(n);\n for (int i = 0; i < n; i++) v[i] = {(ul)seq[i], 1};\n seg.init(v);\n }\n // 位置iに値xをセット\n void set(int x, int i) { seg.set({ul(x), 1}, i); }\n // 位置iに文字cをセット\n void set(char c, int i) { seg.set({ul(c), 1}, i); }\n // 位置[l, r)に値xをセット\n void set(int x, int l, int r) { seg.apply(ul(x), l, r); }\n // 位置[l, r)に文字cをセット\n void set(char c, int l, int r) { seg.apply(ul(c), l, r); }\n // s[l1:r1]とs[l2:r2]を比較、true or falseで返す\n bool same(int l1, int r1, int l2, int r2) {\n if (r1 - l1 != r2 - l2) return false;\n return calc_hash(l1, r1) == calc_hash(l2, r2);\n }\n // s[l1:r1]とs[l2:r2]を比較、一致→0、前者の方が大→1、後者の方が大→2\n int comp(int l1, int r1, int l2, int r2) {\n int n1 = r1 - l1, n2 = r2 - l2;\n if (same(l1, r1, l2, r2)) return 0;\n if (n1 > n2 and same(l1, l1 + n2, l2, r2)) return 1;\n if (n1 <= n2 and same(l1, r1, l2, l2 + n2)) return 2;\n int ok = 0, ng = min(n1, n2), mid = min(n1, n2) / 2;\n while (abs(ok - ng) > 1) {\n mid = (ok + ng) / 2;\n if (calc_hash(l1, l1 + mid) == calc_hash(l2, l2 + mid)) {\n ok = mid;\n } else {\n ng = mid;\n }\n }\n return seg[l1 + ok][0] > seg[l2 + ok][0] ? 1 : 2;\n }\n // l文字目からr - 1文字目までのハッシュ値\n long long calc_hash(int l, int r) { return (seg.prod(l, r))[0]; }\n // 剰余を計算する\n static ul calcmod(ul x) {\n ul t = (x >> 61) + (x & mod);\n return t - (t >= mod ? mod : 0);\n }\n // 掛け算の関数\n static ul mul(ul a, ul b) {\n ul ad = a & mask31, bd = b & mask31;\n a >>= 31, b >>= 31;\n return calcmod(a * b * 2 + ((a * bd + ad * b) >> 30) +\n (((a * bd + ad * b) & mask30) << 31) + ad * bd);\n }\n // 一点取得:配列の位置iの値を取得する\n ul operator[](int i) { return seg[i][0]; }\n};\nvector<unsigned long long> rolling_hash_seg::pow_list;\nunsigned long long rolling_hash_seg::inv_of_base = 1; // 実際は1 - inv\n\nint main() {\n PRE_COMMAND\n int n, q;\n cin >> n;\n string s;\n cin >> s >> q;\n rolling_hash_seg seg(s);\n REP(i, q) {\n string com;\n cin >> com;\n if (com == \"comp\") {\n int a, b, c, d;\n cin >> a >> b >> c >> d;\n int p = seg.comp(a - 1, b, c - 1, d);\n if (p == 1) {\n PRINT(\"t\");\n } else if (p == 2) {\n PRINT(\"s\");\n } else {\n PRINT(\"e\");\n }\n\n } else {\n int x, y;\n char c;\n cin >> x >> y >> c;\n seg.set(c, x - 1, y);\n }\n }\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 19128, "score_of_the_acc": -0.1735, "final_rank": 2 }, { "submission_id": "aoj_0355_6956131", "code_snippet": "#line 1 \"0355.test.cpp\"\n#include <algorithm>\n#include <array>\n#include <cassert>\n#include <random>\n#include <vector>\n\n#line 4 \"/Users/gyouzasushi/kyopro/library/datastructure/lazy_segment_tree.hpp\"\ntemplate <class S, S (*op)(S, S), S (*e)(), class F, S (*mapping)(F, S),\n F (*composition)(F, F), F (*id)()>\nstruct LazySegmentTree {\npublic:\n LazySegmentTree() : LazySegmentTree(0) {\n }\n LazySegmentTree(int n) : LazySegmentTree(std::vector<S>(n, e())) {\n }\n LazySegmentTree(const std::vector<S>& v) : _n(int(v.size())) {\n log = ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n lz = std::vector<F>(size, id());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n return d[p];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return e();\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push(r >> i);\n }\n\n S sml = e(), smr = e();\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n\n return op(sml, smr);\n }\n\n S all_prod() {\n return d[1];\n }\n\n void apply(int p, F f) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = mapping(f, d[p]);\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n void apply(int l, int r, F f) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return;\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n {\n int l2 = l, r2 = r;\n while (l < r) {\n if (l & 1) all_apply(l++, f);\n if (r & 1) all_apply(--r, f);\n l >>= 1;\n r >>= 1;\n }\n l = l2;\n r = r2;\n }\n\n for (int i = 1; i <= log; i++) {\n if (((l >> i) << i) != l) update(l >> i);\n if (((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n\n template <bool (*g)(S)>\n int max_right(int l) {\n return max_right(l, [](S x) { return g(x); });\n }\n template <class G>\n int max_right(int l, G g) {\n assert(0 <= l && l <= _n);\n assert(g(e()));\n if (l == _n) return _n;\n l += size;\n for (int i = log; i >= 1; i--) push(l >> i);\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!g(op(sm, d[l]))) {\n while (l < size) {\n push(l);\n l = (2 * l);\n if (g(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*g)(S)>\n int min_left(int r) {\n return min_left(r, [](S x) { return g(x); });\n }\n template <class G>\n int min_left(int r, G g) {\n assert(0 <= r && r <= _n);\n assert(g(e()));\n if (r == 0) return 0;\n r += size;\n for (int i = log; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < size) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\nprivate:\n int _n, size, log;\n std::vector<S> d;\n std::vector<F> lz;\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n void update(int k) {\n d[k] = op(d[2 * k], d[2 * k + 1]);\n }\n void all_apply(int k, F f) {\n d[k] = mapping(f, d[k]);\n if (k < size) lz[k] = composition(f, lz[k]);\n }\n void push(int k) {\n all_apply(2 * k, lz[k]);\n all_apply(2 * k + 1, lz[k]);\n lz[k] = id();\n }\n};\n#line 2 \"/Users/gyouzasushi/kyopro/library/math/modint2305843009213693951.hpp\"\n#include <cstdint>\nstruct modint2305843009213693951 {\n using mint = modint2305843009213693951;\n\npublic:\n static constexpr uint64_t mod = 2305843009213693951;\n modint2305843009213693951() : _v(0) {\n }\n modint2305843009213693951(uint64_t v) : _v(fast_mod(v)) {\n }\n static constexpr uint64_t fast_mod(uint64_t v) {\n uint64_t u = v >> 61;\n uint64_t d = v & mod;\n uint64_t x = u + d;\n if (x > mod) x -= mod;\n return x;\n }\n uint64_t val() const {\n return _v;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= mod) _v -= mod;\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= mod) _v += mod;\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n static constexpr uint64_t mask31 = (uint64_t(1) << 31) - 1;\n static constexpr uint64_t mask30 = (uint64_t(1) << 30) - 1;\n uint64_t au = _v >> 31;\n uint64_t ad = _v & mask31;\n uint64_t bu = rhs._v >> 31;\n uint64_t bd = rhs._v & mask31;\n uint64_t m = ad * bu + au * bd;\n uint64_t mu = m >> 30;\n uint64_t md = m & mask30;\n _v = fast_mod((au * bu << 1) + mu + (md << 31) + ad * bd);\n return *this;\n }\n mint operator+() const {\n return *this;\n }\n mint operator-() const {\n return mint() - *this;\n }\n mint pow(uint64_t n) const {\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\nprivate:\n uint64_t _v;\n};\n#line 2 \"/Users/gyouzasushi/kyopro/library/math/pow_sum_table.hpp\"\ntemplate <typename mint>\nstruct pow_mod_sums {\n pow_mod_sums() {\n }\n pow_mod_sums(mint base, int n) : base(base) {\n ensure(n);\n }\n // sum(pow[0..i])\n const mint& operator[](int i) const {\n ensure(i);\n return pow_sums[i];\n }\n void ensure(int n) const {\n int sz = pow_sums.size();\n if (sz > n) return;\n pow_sums.resize(n + 1);\n pows.resize(n + 1);\n for (int i = sz; i <= n; i++) {\n pows[i] = base * pows[i - 1];\n pow_sums[i] = pow_sums[i - 1] + pows[i - 1];\n }\n }\n\nprivate:\n mutable std::vector<mint> pow_sums{0};\n mutable std::vector<mint> pows{1};\n mint base;\n static constexpr int mod = mint::mod;\n};\n#line 3 \"/Users/gyouzasushi/kyopro/library/math/pow_table.hpp\"\ntemplate <typename mint>\nstruct pow_mods {\n pow_mods() {\n }\n pow_mods(mint base, int n) : base(base) {\n ensure(n);\n }\n const mint& operator[](int i) const {\n ensure(i);\n return pows[i];\n }\n void ensure(int n) const {\n int sz = pows.size();\n if (sz > n) return;\n pows.resize(n + 1);\n for (int i = sz; i <= n; i++) pows[i] = base * pows[i - 1];\n }\n\nprivate:\n mutable std::vector<mint> pows{1};\n mint base;\n static constexpr int mod = mint::mod;\n};\n#line 11 \"0355.test.cpp\"\ntemplate <int base_num = 1, typename mint = modint2305843009213693951>\nstruct RangeUpdateRangeHash {\npublic:\n RangeUpdateRangeHash() {\n }\n RangeUpdateRangeHash(const std::vector<int>& a) : n(a.size()) {\n std::vector<S> v(n);\n for (int i = 0; i < n; i++) {\n for (int base_id = 0; base_id < base_num; base_id++) {\n v[i].hash[base_id] = a[i];\n }\n v[i].size = 1;\n v[i].is_e = false;\n }\n segt = LazySegmentTree<S, op, e, F, mapping, composition, id>(v);\n }\n template <typename Iterable>\n static RangeUpdateRangeHash from(const Iterable& s) {\n std::vector<int> a;\n for (auto&& e : s) a.push_back(int(e));\n return RangeUpdateRangeHash(a);\n }\n\n template <typename T>\n void set(int p, T x) {\n segt.set(p, int(x));\n }\n std::array<mint, base_num> get(int p) {\n return segt.get(p).hash;\n }\n std::array<mint, base_num> prod(int l, int r) {\n return segt.prod(l, r).hash;\n }\n std::array<mint, base_num> all_prod() {\n return segt.all_prod();\n }\n template <typename T>\n void apply(int l, int r, T x) {\n segt.apply(l, r, {int(x), false});\n }\n int lcp(int l1, int r1, int l2, int r2) {\n int len = std::min(r1 - l1, r2 - l2);\n int ok = 0, ng = len + 1;\n while (ng - ok > 1) {\n int mid = (ok + ng) / 2;\n bool f = prod(l1, l1 + mid) == prod(l2, l2 + mid);\n (f ? ok : ng) = mid;\n }\n return ok;\n }\n int cmp(int l1, int r1, int l2, int r2) {\n int x = std::min({lcp(l1, r1, l2, r2), r1 - l1, r2 - l2});\n if (l1 + x == r1 && l2 + x != r2) return -1;\n if (l1 + x == r1 && l2 + x == r2) return 0;\n if (l1 + x != r1 && l2 + x == r2) return 1;\n return get(l1 + x)[0].val() < get(l2 + x)[0].val() ? -1 : 1;\n }\n\nprivate:\n static inline std::array<mint, base_num> gen_bases() {\n static std::mt19937_64 rng(std::random_device{}());\n std::array<mint, base_num> bases;\n for (int i = 0; i < base_num; i++) {\n while (true) {\n uint64_t k = std::uniform_int_distribution<uint64_t>(\n 1, mint::mod - 1)(rng);\n if (std::gcd(k, mint::mod - 1) != 1) continue;\n uint64_t b = mint(r).pow(k).val();\n if (b <= A) continue;\n bases[i] = b;\n break;\n }\n }\n return bases;\n }\n static inline std::array<pow_mod_sums<mint>, base_num> init_pow_sums(\n const std::array<mint, base_num>& bases) {\n std::array<pow_mod_sums<mint>, base_num> pow_sums;\n for (int i = 0; i < base_num; i++) {\n pow_sums[i] = pow_mod_sums<mint>(bases[i], 0);\n }\n return pow_sums;\n }\n static inline std::array<pow_mods<mint>, base_num> init_pows(\n const std::array<mint, base_num>& bases) {\n std::array<pow_mods<mint>, base_num> pows;\n for (int i = 0; i < base_num; i++) {\n pows[i] = pow_mods<mint>(bases[i], 0);\n }\n return pows;\n }\n static inline std::array<mint, base_num> bases = gen_bases();\n static inline std::array<pow_mod_sums<mint>, base_num> pow_sums =\n init_pow_sums(bases);\n static inline std::array<pow_mods<mint>, base_num> pows = init_pows(bases);\n int n;\n static constexpr uint64_t r = 37;\n static constexpr uint64_t A = 2147483647;\n\n struct S {\n std::array<mint, base_num> hash;\n int size;\n bool is_e;\n };\n static S op(S a, S b) {\n if (a.is_e) return b;\n if (b.is_e) return a;\n for (int base_id = 0; base_id < base_num; base_id++) {\n b.hash[base_id] += a.hash[base_id] * pows[base_id][b.size];\n }\n b.size += a.size;\n return b;\n }\n static S e() {\n return {std::array<mint, base_num>(), 0, true};\n }\n struct F {\n int f;\n bool is_id;\n };\n static S mapping(F f, S x) {\n if (!f.is_id) {\n for (int base_id = 0; base_id < base_num; base_id++) {\n x.hash[base_id] = f.f * pow_sums[base_id][x.size];\n }\n }\n return x;\n }\n static F composition(F f, F g) {\n return (f.is_id ? g : f);\n }\n static F id() {\n return {0, true};\n }\n LazySegmentTree<S, op, e, F, mapping, composition, id> segt;\n};\n\n#include <iostream>\nint main() {\n int n;\n std::string u;\n std::cin >> n >> u;\n auto rh = RangeUpdateRangeHash<>::from(u);\n int q;\n std::cin >> q;\n while (q--) {\n std::string t;\n std::cin >> t;\n if (t == \"set\") {\n int x, y;\n char z;\n std::cin >> x >> y >> z;\n rh.apply(--x, y, z);\n }\n if (t == \"comp\") {\n int a, b, c, d;\n std::cin >> a >> b >> c >> d;\n int sgn = rh.cmp(--a, b, --c, d);\n std::cout << (sgn == -1 ? 's' : sgn == 0 ? 'e' : 't') << '\\n';\n }\n }\n}", "accuracy": 1, "time_ms": 1910, "memory_kb": 19036, "score_of_the_acc": -0.8935, "final_rank": 14 }, { "submission_id": "aoj_0355_6002091", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long BASE = 1234567;\nconst long long INV = 616677444;\nconst long long MOD = 1000000007;\nlong long modpow(long long a, long long b){\n long long ans = 1;\n while (b > 0){\n if (b % 2 == 1){\n ans *= a;\n ans %= MOD;\n }\n a *= a;\n a %= MOD;\n b /= 2;\n }\n return ans;\n}\nlong long modinv(long long a){\n return modpow(a, MOD - 2);\n}\nstruct lazy_segment_tree{\n int N;\n vector<long long> sum, p, lazy;\n lazy_segment_tree(string S){\n int N2 = S.size();\n N = 1;\n while (N < N2){\n N *= 2;\n }\n sum = vector<long long>(N * 2 - 1, 0);\n p = vector<long long>(N * 2 - 1, BASE);\n lazy = vector<long long>(N * 2 - 1, -1);\n for (int i = 0; i < N2; i++){\n sum[N - 1 + i] = S[i];\n }\n for (int i = N - 2; i >= 0; i--){\n sum[i] = (sum[i * 2 + 1] + sum[i * 2 + 2] * p[i * 2 + 1]) % MOD;\n p[i] = p[i * 2 + 1] * p[i * 2 + 2] % MOD;\n }\n }\n void eval(int i){\n if (lazy[i] != -1){\n if (i < N - 1){\n lazy[i * 2 + 1] = lazy[i];\n lazy[i * 2 + 2] = lazy[i];\n }\n sum[i] = lazy[i] * (p[i] - 1) % MOD * INV % MOD;\n lazy[i] = -1;\n }\n }\n void range_update(int L, int R, int x, int i, int l, int r){\n eval(i);\n if (r <= L || R <= l){\n return;\n } else if (L <= l && r <= R){\n lazy[i] = x;\n eval(i);\n } else {\n int m = (l + r) / 2;\n range_update(L, R, x, i * 2 + 1, l, m);\n range_update(L, R, x, i * 2 + 2, m, r);\n sum[i] = (sum[i * 2 + 1] + sum[i * 2 + 2] * p[i * 2 + 1]) % MOD;\n }\n }\n void range_update(int L, int R, int x){\n range_update(L, R, x, 0, 0, N);\n }\n pair<long long, long long> range_sum(int L, int R, int i, int l, int r){\n eval(i);\n if (r <= L || R <= l){\n return make_pair(0, 1);\n } else if (L <= l && r <= R){\n return make_pair(sum[i], p[i]);\n } else {\n int m = (l + r) / 2;\n pair<long long, long long> P1 = range_sum(L, R, i * 2 + 1, l, m);\n pair<long long, long long> P2 = range_sum(L, R, i * 2 + 2, m, r);\n long long S = (P1.first + P2.first * P1.second) % MOD;\n long long P = P1.second * P2.second % MOD;\n return make_pair(S, P);\n }\n }\n pair<long long, long long> range_sum(int L, int R){\n return range_sum(L, R, 0, 0, N);\n }\n};\nint main(){\n int N;\n cin >> N;\n string U;\n cin >> U;\n lazy_segment_tree ST(U);\n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n string t;\n cin >> t;\n if (t == \"set\"){\n int x, y;\n char z;\n cin >> x >> y >> z;\n x--;\n ST.range_update(x, y, z);\n }\n if (t == \"comp\"){\n int a, b, c, d;\n cin >> a >> b >> c >> d;\n a--;\n c--;\n int tv = 0, fv = min(b - a, d - c) + 1;\n while (fv - tv > 1){\n int mid = (tv + fv) / 2;\n long long hash1 = ST.range_sum(a, a + mid).first;\n long long hash2 = ST.range_sum(c, c + mid).first;\n if (hash1 == hash2){\n tv = mid;\n } else {\n fv = mid;\n }\n }\n if (tv == b - a && tv == d - c){\n cout << \"e\" << endl;\n } else if (tv == b - a){\n cout << \"s\" << endl;\n } else if (tv == d - c){\n cout << \"t\" << endl;\n } else {\n long long x = ST.range_sum(a + tv, a + tv + 1).first;\n long long y = ST.range_sum(c + tv, c + tv + 1).first;\n if (x < y){\n cout << \"s\" << endl;\n } else {\n cout << \"t\" << endl;\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 1030, "memory_kb": 15980, "score_of_the_acc": -0.3969, "final_rank": 6 }, { "submission_id": "aoj_0355_5067894", "code_snippet": "#include<iostream>\n#include<algorithm>\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n unsigned int umod() const { return _m; }\n\n unsigned int mul(unsigned int a, unsigned int b) const {\n\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <algorithm>\n#include <cassert>\n#include <iostream>\n#include <vector>\n\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\nint bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\ntemplate <class S,\n S (*op)(S, S),\n S (*e)(),\n class F,\n S (*mapping)(F, S),\n F (*composition)(F, F),\n F (*id)()>\nstruct lazy_segtree {\n public:\n lazy_segtree() : lazy_segtree(0) {}\n lazy_segtree(int n) : lazy_segtree(std::vector<S>(n, e())) {}\n lazy_segtree(const std::vector<S>& v) : _n(int(v.size())) {\n log = internal::ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n lz = std::vector<F>(size, id());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n return d[p];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return e();\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push(r >> i);\n }\n\n S sml = e(), smr = e();\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n void apply(int p, F f) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = mapping(f, d[p]);\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n void apply(int l, int r, F f) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return;\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n {\n int l2 = l, r2 = r;\n while (l < r) {\n if (l & 1) all_apply(l++, f);\n if (r & 1) all_apply(--r, f);\n l >>= 1;\n r >>= 1;\n }\n l = l2;\n r = r2;\n }\n\n for (int i = 1; i <= log; i++) {\n if (((l >> i) << i) != l) update(l >> i);\n if (((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n\n template <bool (*g)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return g(x); });\n }\n template <class G> int max_right(int l, G g) {\n assert(0 <= l && l <= _n);\n assert(g(e()));\n if (l == _n) return _n;\n l += size;\n for (int i = log; i >= 1; i--) push(l >> i);\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!g(op(sm, d[l]))) {\n while (l < size) {\n push(l);\n l = (2 * l);\n if (g(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*g)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return g(x); });\n }\n template <class G> int min_left(int r, G g) {\n assert(0 <= r && r <= _n);\n assert(g(e()));\n if (r == 0) return 0;\n r += size;\n for (int i = log; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < size) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n std::vector<F> lz;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n void all_apply(int k, F f) {\n d[k] = mapping(f, d[k]);\n if (k < size) lz[k] = composition(f, lz[k]);\n }\n void push(int k) {\n all_apply(2 * k, lz[k]);\n all_apply(2 * k + 1, lz[k]);\n lz[k] = id();\n }\n};\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\nusing mint=modint1000000007;\nconst mint Base=113;\nint N,Q;\nstring U;\nmint pB[2<<17],invpB[2<<17];\nstruct dat{\n\tmint V,B;\n\tdat():V(0),B(0){}\n\tdat(mint v,mint b):V(v),B(b){}\n};\ndat op(dat a,dat b){return dat(a.V+b.V,a.B+b.B);}\ndat e(){return dat(0,0);}\ndat mapping(int f,dat x){return f==-1?x:dat(x.B*f,x.B);}\nint composition(int f,int g){return f==-1?g:f;}\nint id(){return -1;}\nmain()\n{\n\tcin>>N>>U>>Q;\n\tvector<dat>init(N);\n\tpB[0]=1;\n\tinvpB[0]=1;\n\tmint invB=Base.inv();\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tpB[i+1]=pB[i]*Base;\n\t\tinvpB[i+1]=invpB[i]*invB;\n\t\tinit[i]=dat(pB[i]*U[i],pB[i]);\n\t}\n\tlazy_segtree<dat,op,e,int,mapping,composition,id>P(init);\n\tfor(;Q--;)\n\t{\n\t\tstring query;\n\t\tcin>>query;\n\t\tif(query==\"set\")\n\t\t{\n\t\t\tint x,y;char z;\n\t\t\tcin>>x>>y>>z;\n\t\t\tP.apply(x-1,y,(int)z);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tint a,b,c,d;\n\t\t\tcin>>a>>b>>c>>d;\n\t\t\ta--,c--;\n\t\t\tint len=min(b-a,d-c);\n\t\t\tint L=0,R=len+1;\n\t\t\twhile(R-L>1)\n\t\t\t{\n\t\t\t\tint mid=(L+R)/2;\n\t\t\t\tmint x=P.prod(a,a+mid).V,y=P.prod(c,c+mid).V;\n\t\t\t\tx*=invpB[a];\n\t\t\t\ty*=invpB[c];\n\t\t\t\tif(x!=y)R=mid;\n\t\t\t\telse L=mid;\n\t\t\t}\n\t\t\tif(L<len)\n\t\t\t{\n\t\t\t\tint x=(P.get(a+L).V*invpB[a+L]).val();\n\t\t\t\tint y=(P.get(c+L).V*invpB[c+L]).val();\n\t\t\t\tcout<<(x<y?\"s\":\"t\")<<endl;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcout<<(b-a<d-c?\"s\":b-a>d-c?\"t\":\"e\")<<endl;\n\t\t\t}\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 11948, "score_of_the_acc": -0.1684, "final_rank": 1 }, { "submission_id": "aoj_0355_4648971", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n#include <chrono>\n\nstatic const int MOD1 = 1000000861, MOD2 = 1000000933;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\nclass xor_shift {\n uint32_t x, y, z, w;\npublic:\n xor_shift() : x(static_cast<uint32_t>((chrono::system_clock::now().time_since_epoch().count())&((1LL << 32)-1))),\n y(1068246329), z(321908594), w(1234567890) {};\n\n uint32_t urand(){\n uint32_t t;\n t = x ^ (x << 11);\n x = y; y = z; z = w;\n w = (w ^ (w >> 19)) ^ (t ^ (t >> 8));\n return w;\n };\n\n int rand(int n){\n if(n < 0) return -rand(-n);\n uint32_t t = numeric_limits<uint32_t>::max()/(n+1)*(n+1);\n uint32_t e = urand();\n while(e >= t) e = urand();\n return static_cast<int>(e%(n+1));\n }\n\n int rand(int a, int b){\n if(a > b) swap(a, b);\n return a+rand(b-a);\n }\n};\n\n\nxor_shift rd;\n\ntemplate<int M>\nstruct rolling_hash {\n static ll &B() {\n static ll B_ = rd.rand(2, M-1);\n return B_;\n }\n static vector<ll> &p() {\n static vector<ll> p_{1, B()};\n return p_;\n }\n vector<ll> hash;\n explicit rolling_hash(const string &s) {\n if(p().size() <= s.size()){\n int l = p().size();\n p().resize(s.size()+1);\n for (int i = l; i < p().size(); ++i) {\n p()[i] = (p()[i-1]*p()[1])%M;\n }\n }\n hash.resize(s.size()+1, 0);\n for (int i = 0; i < s.size(); ++i) {\n hash[i+1] = (hash[i]*B() + s[i]) % M;\n }\n };\n\n ll get(int l, int r){\n ll res = hash[r]+M-hash[l]*p()[r-l]%M;\n return res >= M ? res-M : res;\n }\n};\n\n\nvector<rolling_hash<MOD1>> hashs1;\nvector<rolling_hash<MOD2>> hashs2;\n\ntemplate <class M>\nstruct LazySegmentTree{\n using T = typename M::T;\n using L = typename M::L;\n int sz, height{};\n vector<T> seg; vector<L> lazy;\n explicit LazySegmentTree(int n) {\n sz = 1; while(sz < n) sz <<= 1, height++;\n seg.assign(2*sz, M::e());\n lazy.assign(2*sz, M::l());\n }\n\n void set(int k, const T &x){\n seg[k + sz] = x;\n }\n\n void build(){\n for (int i = sz-1; i > 0; --i) seg[i] = M::f(seg[i<<1], seg[(i<<1)|1]);\n }\n\n T reflect(int k){ return lazy[k] == M::l() ? seg[k] : M::g(seg[k], lazy[k]); }\n\n void eval(int k){\n if(lazy[k] == M::l()) return;\n lazy[(k<<1)|0] = M::h(lazy[(k<<1)|0], lazy[k]);\n lazy[(k<<1)|1] = M::h(lazy[(k<<1)|1], lazy[k]);\n seg[k] = reflect(k);\n lazy[k] = M::l();\n }\n void thrust(int k){ for (int i = height; i; --i) eval(k>>i); }\n void recalc(int k) { while(k >>= 1) seg[k] = M::f(reflect((k<<1)|0), reflect((k<<1)|1));}\n void update(int a, int b, const L &x){\n thrust(a += sz); thrust(b += sz-1);\n for (int l = a, r = b+1;l < r; l >>=1, r >>= 1) {\n if(l&1) lazy[l] = M::h(lazy[l], x), l++;\n if(r&1) --r, lazy[r] = M::h(lazy[r], x);\n }\n recalc(a);\n recalc(b);\n }\n\n T query(int a, int b){ // [l, r)\n thrust(a += sz);\n thrust(b += sz-1);\n T ll = M::e(), rr = M::e();\n for(int l = a, r = b+1; l < r; l >>=1, r>>=1) {\n if (l & 1) ll = M::f(ll, reflect(l++));\n if (r & 1) rr = M::f(reflect(--r), rr);\n }\n return M::f(ll, rr);\n }\n};\n\nstruct Monoid{\n using T = array<ll, 3>;\n using L = char;\n static T f(T a, T b) {\n return {(a[0]*rolling_hash<MOD1>::p()[b[2]]+b[0])%MOD1, (a[1]*rolling_hash<MOD2>::p()[b[2]]+b[1])%MOD2, a[2]+b[2]};\n }\n static T g(T a, L b) {\n if(b == l()) return a;\n else {\n return {hashs1[b-'a'].get(0, a[2]), hashs2[b-'a'].get(0, a[2]), a[2]};\n }\n }\n static L h(L a, L b) {\n if(b == l()) return a; else return b;\n }\n static T e() { return {0, 0, 0}; }\n static L l() { return 0; }\n};\n\nint main() {\n int n;\n string s;\n cin >> n >> s;\n for (int i = 'a'; i <= 'z'; ++i) {\n hashs1.emplace_back(string(n, i));\n hashs2.emplace_back(string(n, i));\n }\n LazySegmentTree<Monoid> seg(n);\n for (int i = 0; i < n; ++i) {\n seg.set(i, {s[i], s[i], 1});\n }\n seg.build();\n int q;\n cin >> q;\n for (int i = 0; i < q; ++i) {\n string qq;\n cin >> qq;\n if(qq == \"comp\"){\n int a, b, c, d;\n cin >> a >> b >> c >> d;\n a--; c--;\n int ok = 0, ng = min(b-a+1, d-c+1);\n while(ng-ok > 1){\n int mid = (ok+ng)/2;\n if(seg.query(a, a+mid) == seg.query(c, c+mid)) ok = mid;\n else ng = mid;\n }\n if(a+ok == b && c+ok == d){\n puts(\"e\");\n }else if(a+ok == b){\n puts(\"s\");\n }else if(c+ok == d){\n puts(\"t\");\n }else if(seg.query(a+ok, a+ng) < seg.query(c+ok, c+ng)){\n puts(\"s\");\n }else {\n puts(\"t\");\n }\n }else {\n int a, b; char c;\n cin >> a >> b >> c;\n a--;\n seg.update(a, b, c);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1090, "memory_kb": 100544, "score_of_the_acc": -1.356, "final_rank": 18 }, { "submission_id": "aoj_0355_4405438", "code_snippet": "#line 1 \"test/aoj_0355.test.cpp\"\n#define PROBLEM \"http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0355\"\n\n#include <cstdint>\n#include <cstdio>\n#include <algorithm>\n#include <utility>\n#include <vector>\n\n#line 1 \"ModularArithmetic/modint.cpp\"\n\n\n\n/**\n * @brief 合同算術用クラス\n * @author えびちゃん\n */\n\n#line 10 \"ModularArithmetic/modint.cpp\"\n#include <limits>\n#include <type_traits>\n#line 13 \"ModularArithmetic/modint.cpp\"\n\ntemplate <intmax_t Modulo>\nclass modint {\npublic:\n using value_type = typename std::conditional<\n (0 < Modulo && Modulo < std::numeric_limits<int>::max() / 2), int, intmax_t\n >::type;\n\nprivate:\n static constexpr value_type S_cmod = Modulo; // compile-time\n static value_type S_rmod; // runtime\n value_type M_value = 0;\n\n static constexpr value_type S_inv(value_type n, value_type m) {\n value_type x = 0;\n value_type y = 1;\n value_type a = n;\n value_type b = m;\n for (value_type u = y, v = x; a;) {\n value_type q = b / a;\n std::swap(x -= q*u, u);\n std::swap(y -= q*v, v);\n std::swap(b -= q*a, a);\n }\n if ((x %= m) < 0) x += m;\n return x;\n }\n\n static value_type S_normalize(intmax_t n, value_type m) {\n if (n >= m) {\n n %= m;\n } else if (n < 0) {\n if ((n %= m) < 0) n += m;\n }\n return n;\n }\n\npublic:\n modint() = default;\n modint(intmax_t n): M_value(S_normalize(n, get_modulo())) {}\n\n modint& operator =(intmax_t n) {\n M_value = S_normalize(n, get_modulo());\n return *this;\n }\n\n modint& operator +=(modint const& that) {\n if ((M_value += that.M_value) >= get_modulo()) M_value -= get_modulo();\n return *this;\n }\n modint& operator -=(modint const& that) {\n if ((M_value -= that.M_value) < 0) M_value += get_modulo();\n return *this;\n }\n modint& operator *=(modint const& that) {\n intmax_t tmp = M_value;\n tmp *= that.M_value;\n M_value = tmp % get_modulo();\n return *this;\n }\n modint& operator /=(modint const& that) {\n intmax_t tmp = M_value;\n tmp *= S_inv(that.M_value, get_modulo());\n M_value = tmp % get_modulo();\n return *this;\n }\n\n modint& operator ++() {\n if (++M_value == get_modulo()) M_value = 0;\n return *this;\n }\n modint& operator --() {\n if (M_value-- == 0) M_value = get_modulo()-1;\n return *this;\n }\n\n modint operator ++(int) { modint tmp(*this); ++*this; return tmp; }\n modint operator --(int) { modint tmp(*this); --*this; return tmp; }\n\n friend modint operator +(modint lhs, modint const& rhs) { return lhs += rhs; }\n friend modint operator -(modint lhs, modint const& rhs) { return lhs -= rhs; }\n friend modint operator *(modint lhs, modint const& rhs) { return lhs *= rhs; }\n friend modint operator /(modint lhs, modint const& rhs) { return lhs /= rhs; }\n\n modint operator +() const { return *this; }\n modint operator -() const {\n if (M_value == 0) return *this;\n return modint(get_modulo() - M_value);\n }\n\n friend bool operator ==(modint const& lhs, modint const& rhs) {\n return lhs.M_value == rhs.M_value;\n }\n friend bool operator !=(modint const& lhs, modint const& rhs) {\n return !(lhs == rhs);\n }\n\n value_type get() const { return M_value; }\n static value_type get_modulo() { return ((S_cmod > 0)? S_cmod: S_rmod); }\n\n template <int M = Modulo, typename Tp = typename std::enable_if<(M <= 0)>::type>\n static Tp set_modulo(value_type m) { S_rmod = m; }\n};\n\ntemplate <intmax_t N>\nconstexpr typename modint<N>::value_type modint<N>::S_cmod;\ntemplate <intmax_t N>\ntypename modint<N>::value_type modint<N>::S_rmod;\n\n\n#line 1 \"utility/monoid/rolling_hash.cpp\"\n\n\n\n/**\n * @brief ロリハの演算のモノイド\n * @author えびちゃん\n */\n\n#line 10 \"utility/monoid/rolling_hash.cpp\"\n\ntemplate <typename ModInt>\nclass rolling_hash_monoid {\npublic:\n using value_type = ModInt;\n\nprivate:\n value_type M_x = 0, M_p = 1;\n\npublic:\n rolling_hash_monoid() = default; // identity\n\n rolling_hash_monoid(value_type const& x, value_type const& p): M_x(x), M_p(p) {};\n\n rolling_hash_monoid& operator +=(rolling_hash_monoid const& that) {\n M_x = M_x * that.M_p + that.M_x;\n M_p *= that.M_p;\n return *this;\n }\n friend bool operator ==(rolling_hash_monoid const& lhs, rolling_hash_monoid const& rhs) {\n return lhs.M_x == rhs.M_x && lhs.M_p == rhs.M_p;\n }\n\n friend rolling_hash_monoid operator +(rolling_hash_monoid lhs, rolling_hash_monoid const& rhs) {\n return lhs += rhs;\n }\n friend bool operator !=(rolling_hash_monoid const& lhs, rolling_hash_monoid const& rhs) {\n return !(lhs == rhs);\n }\n\n value_type const& get() const { return M_x; }\n value_type const& coefficient() const { return M_p; }\n};\n\n\n#line 1 \"utility/monoid/set.cpp\"\n\n\n\n/**\n * @brief モノイドクラス\n * @author えびちゃん\n */\n\ntemplate <typename Tp>\nclass set_monoid {\npublic:\n using value_type = Tp;\n\nprivate:\n bool M_empty = true;\n value_type M_x;\n\npublic:\n set_monoid() = default; // identity\n\n set_monoid(value_type const& x): M_empty(false), M_x(x) {}\n\n set_monoid& operator +=(set_monoid const& that) {\n M_empty = that.M_empty;\n if (!that.M_empty) M_x = that.M_x;\n return *this;\n }\n friend bool operator ==(set_monoid const& lhs, set_monoid const& rhs) {\n if (lhs.M_empty && rhs.M_empty) return true;\n if (lhs.M_empty != rhs.M_empty) return false;\n return lhs.M_x == rhs.M_x;\n }\n\n friend set_monoid operator +(set_monoid lhs, set_monoid const& rhs) { return lhs += rhs; }\n friend bool operator !=(set_monoid const& lhs, set_monoid const& rhs) {\n return !(lhs == rhs);\n }\n\n bool empty() const noexcept { return M_empty; }\n value_type const& get() const { return M_x; }\n};\n\n\n#line 1 \"DataStructure/segment_tree.cpp\"\n\n\n\n/**\n * @brief 区間作用・区間和セグメント木\n * @author えびちゃん\n */\n\n#include <cstddef>\n#line 11 \"DataStructure/segment_tree.cpp\"\n\n#line 1 \"integer/bit.cpp\"\n\n\n\n/** \n * @brief ビット演算\n * @author えびちゃん\n */\n\n// XXX integral promotion 関連の注意をあまりしていません\n\n#include <climits>\n#include <type_traits>\n\ntemplate <typename Tp>\nconstexpr auto countl_zero(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{\n using value_type = typename std::make_unsigned<Tp>::type;\n int bits = (sizeof(value_type) * CHAR_BIT);\n if (n == 0) return bits;\n int res = 0;\n for (int i = bits / 2; i > 0; i /= 2) {\n value_type mask = ((static_cast<value_type>(1) << i) - 1) << i;\n if (n & mask) n >>= i;\n else res += i;\n }\n return res;\n}\ntemplate <typename Tp>\nconstexpr auto countl_one(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{\n using value_type = typename std::make_unsigned<Tp>::type;\n return countl_zero(static_cast<value_type>(~n));\n}\n\ntemplate <typename Tp>\nconstexpr auto countr_zero(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{\n using value_type = typename std::make_unsigned<Tp>::type;\n int bits = (sizeof(value_type) * CHAR_BIT);\n if (n == 0) return bits;\n int res = 0;\n for (int i = bits / 2; i > 0; i /= 2) {\n value_type mask = ((static_cast<value_type>(1) << i) - 1);\n if (!(n & mask)) res += i, n >>= i;\n }\n return res;\n}\ntemplate <typename Tp>\nconstexpr auto countr_one(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{\n using value_type = typename std::make_unsigned<Tp>::type;\n return countr_zero(static_cast<value_type>(~n));\n}\n\nconstexpr unsigned long long half_mask[] = {\n 0x5555555555555555uLL, 0x3333333333333333uLL, 0x0F0F0F0F0F0F0F0FuLL,\n 0x00FF00FF00FF00FFuLL, 0x0000FFFF0000FFFFuLL, 0x00000000FFFFFFFFuLL\n};\n\ntemplate <typename Tp>\nconstexpr auto popcount(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{\n int bits = static_cast<int>((sizeof n) * CHAR_BIT);\n for (int i = 0, j = 1; j < bits; ++i, j *= 2) {\n if (j <= 8) n = (n & half_mask[i]) + ((n >> j) & half_mask[i]);\n else n += n >> j;\n }\n return n & 0xFF;\n}\n\ntemplate <typename Tp>\nconstexpr auto parity(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, int>::type\n{ return popcount(n) & 1; }\n\n\ntemplate <typename Tp>\nint clz(Tp n) { return countl_zero(static_cast<typename std::make_unsigned<Tp>::type>(n)); }\ntemplate <typename Tp>\nint ctz(Tp n) { return countr_zero(static_cast<typename std::make_unsigned<Tp>::type>(n)); }\n\ntemplate <typename Tp>\nint ilog2(Tp n) {\n return (CHAR_BIT * sizeof(Tp) - 1) - clz(static_cast<typename std::make_unsigned<Tp>::type>(n));\n}\ntemplate <typename Tp>\nbool is_pow2(Tp n) { return (n > 0) && ((n & (n-1)) == 0); }\ntemplate <typename Tp>\nTp floor2(Tp n) { return is_pow2(n)? n: static_cast<Tp>(1) << ilog2(n); }\ntemplate <typename Tp>\nTp ceil2(Tp n) { return is_pow2(n)? n: static_cast<Tp>(2) << ilog2(n); }\n\ntemplate <typename Tp>\nconstexpr auto reverse(Tp n)\n -> typename std::enable_if<std::is_unsigned<Tp>::value, Tp>::type\n{\n int bits = static_cast<int>((sizeof n) * CHAR_BIT);\n for (int i = 0, j = 1; j < bits; ++i, j *= 2) {\n n = ((n & half_mask[i]) << j) | ((n >> j) & half_mask[i]);\n }\n return n;\n}\n\n\n#line 13 \"DataStructure/segment_tree.cpp\"\n\ntemplate <typename Operation>\nclass segment_tree {\npublic:\n using size_type = size_t;\n using operation = Operation;\n using operand_type = typename operation::operand_type;\n using action_type = typename operation::action_type;\n using value_type = operand_type;\n\nprivate:\n size_type M_n;\n std::vector<operand_type> M_c;\n std::vector<action_type> M_d; // deferred\n\n void M_build(size_type i) {\n while (i > 1) {\n i >>= 1;\n M_c[i] = (M_c[i<<1|0] + M_c[i<<1|1]);\n operation::act(M_c[i], M_d[i]);\n }\n }\n\n void M_resolve(size_type i) {\n size_type h = ilog2(M_n) + 2; // ilog2p1(M_n*2)\n for (size_type s = h; s > 0; --s) {\n size_type p = i >> s;\n action_type id{};\n if (M_d[p] != id) {\n M_apply(p<<1|0, M_d[p]);\n M_apply(p<<1|1, M_d[p]);\n M_d[p] = id;\n }\n }\n }\n\n void M_apply(size_type i, action_type const& x) {\n operation::act(M_c[i], x);\n if (i < M_n) M_d[i] += x;\n }\n\npublic:\n segment_tree() = default;\n explicit segment_tree(size_type n):\n M_n(n), M_c(n+n, operand_type{}), M_d(n, action_type{}) {}\n\n segment_tree(size_type n, operand_type const& x):\n M_n(n), M_c(n+n, x), M_d(n, action_type{})\n {\n for (size_type i = n; i--;) M_c[i] = M_c[i<<1|0] + M_c[i<<1|1];\n }\n\n template <typename InputIt>\n segment_tree(InputIt first, InputIt last): M_c(first, last) {\n M_n = M_c.size();\n M_d.assign(M_n, action_type{});\n M_c.insert(M_c.begin(), M_n, operand_type{});\n for (size_type i = M_n; i--;) M_c[i] = M_c[i<<1|0] + M_c[i<<1|1];\n }\n\n void assign(size_type n) {\n M_n = n;\n M_c(n+n, operand_type{});\n M_d(n, action_type{});\n }\n\n void assign(size_type n, operand_type const& x) {\n M_n = n;\n M_c(n+n, x);\n M_d(n, action_type{});\n for (size_type i = n; i--;) M_c[i] = M_c[i<<1|0] + M_c[i<<1|1];\n }\n\n template <typename InputIt>\n void assign(InputIt first, InputIt last) {\n M_c.assign(first, last);\n M_n = M_c.size();\n M_d.assign(M_n, action_type{});\n M_c.insert(M_c.begin(), M_n, operand_type{});\n for (size_type i = M_n; i--;) M_c[i] = M_c[i<<1|0] + M_c[i<<1|1];\n }\n\n void act(size_type l, size_type r, action_type const& x) {\n if (l == r) return;\n l += M_n;\n r += M_n;\n size_type l0 = l;\n size_type r0 = r;\n M_resolve(l0);\n M_resolve(r0-1);\n while (l < r) {\n if (l & 1) M_apply(l++, x);\n if (r & 1) M_apply(--r, x);\n l >>= 1;\n r >>= 1;\n }\n M_build(l0);\n M_build(r0-1);\n }\n\n operand_type fold(size_type l, size_type r) {\n operand_type resl{}, resr{};\n if (l == r) return resl;\n\n l += M_n;\n r += M_n;\n M_resolve(l);\n M_resolve(r-1);\n while (l < r) {\n if (l & 1) resl += M_c[l++];\n if (r & 1) resr = M_c[--r] + std::move(resr);\n l >>= 1;\n r >>= 1;\n }\n return resl += resr;\n }\n\n operand_type operator [](size_type i) {\n i += M_n;\n M_resolve(i);\n return M_c[i];\n }\n};\n\n\n#line 13 \"test/aoj_0355.test.cpp\"\n\nconstexpr intmax_t mod = 998244353;\nusing mi = modint<mod>;\n\ntemplate <typename ModInt>\nstruct action_set_to_rolling_hash {\n using operand_type = rolling_hash_monoid<ModInt>;\n using action_type = set_monoid<std::pair<ModInt, ModInt>>;\n\n static void act(operand_type& op, action_type const& a) {\n if (a.empty()) return;\n operand_type tmp(a.get().first, a.get().second);\n if (op.coefficient() == 1) {\n op = tmp;\n return;\n }\n while (tmp.coefficient() != op.coefficient()) tmp += tmp;\n op = tmp;\n }\n};\n\nint main() {\n size_t n;\n char buf[262144];\n int q;\n scanf(\"%zu %s %d\", &n, buf, &q);\n std::string s = buf;\n\n intmax_t b1 = 2352983, b2 = 4986917;\n segment_tree<action_set_to_rolling_hash<mi>> s1(n), s2(n);\n auto f = [](auto x, auto y) {\n return set_monoid<std::pair<mi, mi>>({x, y});\n };\n for (size_t i = 0; i < n; ++i) {\n s1.act(i, i+1, f(s[i], b1));\n s2.act(i, i+1, f(s[i], b2));\n }\n\n for (int i = 0; i < q; ++i) {\n scanf(\"%s\", buf);\n std::string type = buf;\n if (type == \"set\") {\n size_t x, y;\n char z;\n scanf(\"%zu %zu %c\", &x, &y, &z);\n --x, --y;\n s1.act(x, y+1, f(z, b1));\n s2.act(x, y+1, f(z, b2));\n } else if (type == \"comp\") {\n size_t a, b, c, d;\n scanf(\"%zu %zu %zu %zu\", &a, &b, &c, &d);\n --a, --b, --c, --d;\n size_t sl = b-a+1, tl = d-c+1;\n auto eq = [&](size_t l) {\n return s1.fold(a, a+l) == s1.fold(c, c+l) && s2.fold(a, a+l) == s2.fold(c, c+l);\n };\n if (eq(std::min(sl, tl))) {\n printf(\"%c\\n\", ((sl < tl)? 's': (sl > tl)? 't': 'e'));\n continue;\n }\n size_t lb = 0, ub = std::min(sl, tl);\n while (ub-lb > 1) {\n size_t mid = (lb+ub) >> 1;\n (eq(mid)? lb: ub) = mid;\n }\n int sc = s1[a+lb].get().get(), tc = s1[c+lb].get().get();\n printf(\"%c\\n\", ((sc < tc)? 's': 't'));\n }\n }\n}", "accuracy": 1, "time_ms": 840, "memory_kb": 13864, "score_of_the_acc": -0.2736, "final_rank": 4 }, { "submission_id": "aoj_0355_4400783", "code_snippet": "#ifndef LOCAL\n#pragma GCC optimize (\"O3\")\n#pragma GCC optimize (\"unroll-loops\")\n#pragma GCC target (\"avx\")\n#endif\n\n#include <vector>\n#include <set>\n#include <map>\n#include <tuple>\n#include <queue>\n#include <stack>\n#include <bitset>\n#include <functional>\n#include <algorithm>\n#include <utility>\n#include <numeric>\n#include <iostream>\n#include <cmath>\n#include <cassert>\n#include <cstring>\n\nusing namespace std;\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing VI = vector<int>;\nusing VVI = vector<vector<int>>;\nusing VLL = vector<ll>;\nusing VVLL = vector<vector<ll>>;\nusing VB = vector<bool>;\nusing PII = pair<int, int>;\nusing PLL = pair<ll, ll>;\ntemplate <typename T>\nusing minheap = priority_queue<T, vector<T>, greater<T>>;\nconst int INF = 1000000007;\nconst ll INF_LL = 1'000'000'000'000'000'007;\n\n#define __overload3(_1, _2, _3, name,...) name\n#define rep(...) __overload3(__VA_ARGS__, repFromUntil, repUntil, repeat)(__VA_ARGS__)\n#define repeat(times) repFromUntil(_name##__LINE__, 0, times)\n#define repUntil(name, times) repFromUntil(name, 0, times)\n#define repFromUntil(name, from, until) for (int name = from, name##__until = (until); name < name##__until; name++)\n#define repr(...) __overload3(__VA_ARGS__, reprFromUntil, reprUntil, repeat)(__VA_ARGS__)\n#define reprUntil(name, times) reprFromUntil(name, 0, times)\n#define reprFromUntil(name, from, until) for (int name = (until) - 1, name##__from = (from); name >= name##__from; name--)\n\n#define EXIT(out) do { OUT(out); exit(0); } while (0)\n\n#define all(x) begin(x), end(x)\n#define rall(x) rbegin(x), rend(x)\n\n#ifdef LOCAL\n#define debug(v) do {debugos << \"L\" << __LINE__ << \" \" << #v << \" > \";debugos<<(v)<<newl;} while (0)\n#define debugv(v) do {debugos << \"L\" << __LINE__ << \" \" << #v << \" > \";for(auto e:(v)){debugos<<e<<\" \";}debugos<<newl;} while (0)\n#define debuga(m,w) do {debugos << \"L\" << __LINE__ << \" \" << #m << \" > \";for(int x=0;x<(w);x++){debugos<<(m)[x]<<\" \";}debugos<<newl;} while (0)\n#define debugaa(m,h,w) do {debugos << \"L\" << __LINE__ << \" \" << #m << \" > \\n\";for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){debugos<<(m)[y][x]<<\" \";}debugos<<newl;}} while (0)\n#else\n#define debug(v) do {v;} while (0)\n#define debugv(v) do; while (0)\n#define debuga(m,w) do; while (0)\n#define debugaa(m,h,w) do; while (0)\n#endif\n\n#define newl \"\\n\"\n\ntemplate <typename T, typename U> bool chmin(T& var, U x) {\n if (var > x) {\n var = x;\n return true;\n } else return false;\n}\n\ntemplate <typename T, typename U> bool chmax(T& var, U x) {\n if (var < x) {\n var = x;\n return true;\n } else return false;\n}\n\ntemplate <typename T> int sgn(T val) { return (T(0) < val) - (val < T(0)); }\n\nll power(ll e, int t, ll mod = INF_LL) {\n ll res = 1;\n while (t) {\n if (t&1) res = (res * e) % mod;\n t >>= 1;\n e = (e * e) % mod;\n }\n return res;\n}\n\ntemplate <typename T> T divceil(T m, T d) {\n assert(m >= 0 and d > 0);\n return (m+d-1)/d;\n}\n\ntemplate<typename T>\nvector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\n\ntemplate<typename... Ts>\nauto make_v(size_t a, Ts... ts) {\n return vector<decltype(make_v(ts...))>(a, make_v(ts...));\n}\n\nstring operator*(const string& s, int times) {\n string res = \"\";\n rep(times) res += s;\n return res;\n}\n\nstruct Edge {\n int to; ll cost;\n Edge(int _to): to(_to), cost(1) {}\n Edge(int _to, ll _cost): to(_to), cost(_cost) {}\n operator int() { return to; }\n};\n\nusing Graph = vector<vector<Edge>>;\n\nclass MyScanner {\npublic:\n int offset = 0;\n char nc(){\n#ifdef LOCAL\n return getchar();\n#else\n return getchar_unlocked();\n#endif\n }\n template <typename T> void input_integer(T& var) {\n var = 0; T sign = 1;\n int cc = nc();\n for (; cc<'0' || '9'<cc; cc = nc())\n if (cc == '-') sign = -1;\n for (; '0' <= cc && cc <= '9'; cc = nc())\n var = (var << 3) + (var << 1) + cc - '0';\n var = var * sign; var += offset;\n }\n int c() { char c; while (c = nc(), c == ' ' or c == '\\n'); return c; }\n MyScanner& operator>>(char& var) { var = c(); return *this; }\n MyScanner& operator>>(int& var) { input_integer<int>(var); return *this; }\n MyScanner& operator>>(ll& var) { input_integer<ll>(var); return *this; }\n MyScanner& operator>>(string& var) {\n var = \"\"; int cc = nc();\n for (; !isvisiblechar(cc); cc = nc());\n for (; isvisiblechar(cc); cc = nc())\n var.push_back(cc);\n return *this;\n }\n template <typename T>\n operator T() { T x; *this >> x; return x; }\n template <typename T>\n void operator()(T &t) { *this >> t; }\n template <typename T, typename... Ts>\n void operator()(T &t, Ts &...ts) { *this >> t; this->operator()(ts...); }\n template <typename Iter>\n void iter(Iter first, Iter last) { while (first != last) *this >> *first, first++; }\n VI vi(int n) { VI res(n); iter(all(res)); return res; }\n VVI vvi(int n, int m) { VVI res(n); rep(i, n) res[i] = vi(m); return res; }\n VLL vll(int n) { VLL res(n); iter(all(res)); return res; }\n VVLL vvll(int n, int m) { VVLL res(n); rep(i, n) res[i] = vll(m); return res; }\n template <typename T>\n vector<T> v(int n) { vector<T> res(n); iter(all(res)); return res; }\nprivate:\n int isvisiblechar(int c) { return 0x21 <= c && c <= 0x7E; }\n} IN, IN1{-1};\n\nclass MyPrinter {\npublic:\n int offset = 0;\n template <typename T>\n void output_integer(T var) {\n var += offset;\n if (var == 0) { putchar('0'); return; }\n if (var < 0) putchar('-'), var = -var;\n char stack[32]; int stack_p = 0;\n while (var) stack[stack_p++] = '0' + (var % 10), var /= 10;\n while (stack_p) putchar(stack[--stack_p]);\n }\n MyPrinter& operator<<(char c) { putchar(c); return *this; }\n MyPrinter& operator<<(double x) { printf(\"%.10f\", x); return *this; }\n template <typename T> MyPrinter& operator<<(T var) { output_integer<T>(var); return *this; }\n MyPrinter& operator<<(char* str_p) { while (*str_p) putchar(*(str_p++)); return *this; }\n MyPrinter& operator<<(const char* str_p) { while (*str_p) putchar(*(str_p++)); return *this; }\n MyPrinter& operator<<(const string& str) {\n const char* p = str.c_str();\n const char* l = p + str.size();\n while (p < l) putchar(*p++);\n return *this;\n }\n template <typename T>\n void operator()(T x) { *this << x << newl; }\n template <typename T, typename... Ts>\n void operator()(T x, Ts ...xs) { *this << x << \" \"; this->operator()(xs...); }\n template <typename Iter>\n void iter(Iter s, Iter t) {\n if (s == t) *this << \"\\n\";\n else for (; s != t; s++) *this << *s << \" \\n\"[next(s, 1) == t];\n }\n template <typename Range>\n void range(const Range& r) { iter(begin(r), end(r)); }\n} OUT, OUT1{1};\n\nclass DebugPrint {\npublic:\n template <typename T>\n DebugPrint& operator <<(const T& v) {\n#ifdef LOCAL\n cerr << v;\n#endif\n return *this;\n }\n} debugos;\n\ntemplate <typename OutStream, typename T, typename U>\nOutStream& operator<<(OutStream& out, const pair<T, U>& var) {\n return out << var.first << \" \" << var.second;\n}\ntemplate <typename OutStream, typename Tuple, size_t I, size_t N,\n enable_if_t<I == N>* = nullptr>\nOutStream& tuple_impl(OutStream& out, const Tuple& var) {\n return out;\n}\ntemplate <typename OutStream, typename Tuple, size_t I, size_t N,\n enable_if_t<I != N>* = nullptr>\nOutStream& tuple_impl(OutStream& out, const Tuple& var) {\n out << get<I>(var) << \" \";\n return tuple_impl<OutStream, Tuple, I+1, N>(out, var);\n}\ntemplate <typename OutStream, typename... Ts>\nOutStream& operator<<(OutStream& out, const tuple<Ts...>& var) {\n return tuple_impl<OutStream, tuple<Ts...>, 0, sizeof...(Ts)>(out, var);\n}\ntemplate <typename InStream, typename T, typename U>\nInStream& operator>>(InStream& in, pair<T, U>& var) {\n return in >> var.first >> var.second;\n}\ntemplate <typename InStream, typename Tuple, size_t I, size_t N,\n enable_if_t<I == N>* = nullptr>\nInStream& tuple_impl(InStream& in, Tuple& var) {\n return in;\n}\ntemplate <typename InStream, typename Tuple, size_t I, size_t N,\n enable_if_t<I != N>* = nullptr>\nInStream& tuple_impl(InStream& in, Tuple& var) {\n in >> get<I>(var);\n return tuple_impl<InStream, Tuple, I+1, N>(in, var);\n}\ntemplate <typename InStream, typename... Ts>\nInStream& operator>>(InStream& in, tuple<Ts...>& var) {\n return tuple_impl<InStream, tuple<Ts...>, 0, sizeof...(Ts)>(in, var);\n}\n\n\n#pragma GCC diagnostic ignored \"-Wshadow\"\ntemplate <typename T, typename U, typename Merge, typename EMerge, typename Upd>\nstruct LazySegmentTree {\n private:\n const size_t n, h;\n const T unit;\n const U eunit;\n const Merge merge;\n const EMerge emerge;\n const Upd upd;\n vector<T> data;\n vector<U> lazy;\n\n public:\n LazySegmentTree(size_t n = 0, T unit = T(), U eunit = U(),\n Merge merge = Merge(), EMerge emerge = EMerge(),\n Upd upd = Upd())\n : n(n), h(32 - __builtin_clz(n)), unit(unit), eunit(eunit), merge(merge),\n emerge(emerge), upd(upd), data(n << 1, unit), lazy(n, eunit) {\n build(0, n);\n }\n\n template <typename Iter,\n enable_if_t<is_same<typename Iter::value_type, T>::value>* = nullptr>\n LazySegmentTree(Iter first, Iter last, size_t n, T unit = T(), U eunit = U(),\n Merge merge = Merge(), EMerge emerge = EMerge(),\n Upd upd = Upd())\n : n(n), h(32 - __builtin_clz(n)), unit(unit), eunit(eunit), merge(merge),\n emerge(emerge), upd(upd), data(n << 1, unit), lazy(n, eunit) {\n assign(first, last);\n }\n\n template <typename Iter,\n enable_if_t<!is_same<typename Iter::value_type, T>::value>* = nullptr>\n LazySegmentTree(Iter first, Iter last, size_t n, T unit = T(),\n U eunit = U(), Merge merge = Merge(),\n EMerge emerge = EMerge(), Upd upd = Upd())\n : n(n), h(32 - __builtin_clz(n)), unit(unit), eunit(eunit), merge(merge),\n emerge(emerge), upd(upd), data(n << 1, unit), lazy(n, eunit) {\n assign(first, last);\n }\n\n template <typename Iter>\n LazySegmentTree(Iter first, Iter last, T unit = T(), U eunit = U(),\n Merge merge = Merge(), EMerge emerge = EMerge(),\n Upd upd = Upd())\n : LazySegmentTree(first, last, distance(first, last), unit, eunit, merge,\n emerge, upd) {}\n\n private:\n void apply(int p, U e, int sz) {\n if (e == eunit) return;\n data[p] = upd(data[p], e, sz);\n if (p < n) {\n if (lazy[p] == eunit) lazy[p] = e;\n else lazy[p] = emerge(lazy[p], e);\n }\n }\n\n void pushdown(int p, int sz) {\n if (p >= n or lazy[p] == eunit) return;\n apply(p << 1, lazy[p], sz >> 1);\n apply(p << 1 | 1, lazy[p], sz >> 1);\n lazy[p] = eunit;\n }\n\n void pushup(int p, int sz) {\n if (p >= n) return;\n data[p] = merge(data[p << 1], data[p << 1 | 1]);\n if (lazy[p] != eunit) data[p] = upd(data[p], lazy[p], sz);\n }\n\n void flush(int l, int r) {\n int s = h, k = 1 << h;\n for (l += n, r += n - 1; s > 0; s--, k >>= 1)\n for (int p = l >> s; p <= r >> s; p++)\n pushdown(p, k);\n }\n\n void build(int l, int r) {\n int sz = 2;\n for (l += n, r += n - 1; l > 1; sz <<= 1) {\n l >>= 1, r >>= 1;\n for (int p = l; p <= r; p++) pushup(p, sz);\n }\n }\n\n template <typename Iter>\n void assign(Iter first, Iter last) {\n copy(first, last, data.begin() + n);\n build(0, n);\n }\n\n public:\n void modify(int l, int r, U e) {\n if (e == eunit) return;\n flush(l, l + 1);\n flush(r - 1, r);\n int l0 = l, r0 = r, k = 1;\n for (l += n, r += n; l < r; l >>= 1, r >>= 1, k <<= 1) {\n if (l & 1) apply(l++, e, k);\n if (r & 1) apply(--r, e, k);\n }\n build(l0, l0 + 1);\n build(r0 - 1, r0);\n }\n\n T query(int l, int r) {\n flush(l, l + 1);\n flush(r - 1, r);\n T resl = unit, resr = unit;\n for (l += n, r += n; l < r; l >>= 1, r >>= 1) {\n if (l & 1) resl = merge(resl, data[l++]);\n if (r & 1) resr = merge(data[--r], resr);\n }\n return merge(resl, resr);\n }\n};\n#pragma GCC diagnostic warning \"-Wshadow\"\n\n#pragma GCC diagnostic ignored \"-Wunused-parameter\"\nstruct minT {\n template <typename T>\n T operator()(T a, T b) const { return min(a, b); }\n};\n\nstruct maxT {\n template <typename T>\n T operator()(T a, T b) const { return max(a, b); }\n};\n\nstruct assignT {\n template <typename T>\n T operator()(T a, T b, int k = 0) const { return b; }\n};\n#pragma GCC diagnostic ignored \"-Wunused-parameter\"\n\nstruct plusT {\n template <typename T>\n T operator()(T a, T b, int k) const { return a + b * k; }\n};\n\n\nnamespace rolling_hash {\n\nconstexpr ull mask30 = (1ULL << 30) - 1;\nconstexpr ull mask31 = (1ULL << 31) - 1;\nconstexpr ull MOD = (1ULL << 61) - 1;\nint base = rand();\nvector<ull> pows{1};\n\null mod(ull val) {\n val = (val & MOD) + (val >> 61);\n return val >= MOD ? val - MOD : val;\n}\n\null mul(ull l, ull r) {\n ull lu = l >> 31, ld = l & mask31;\n ull ru = r >> 31, rd = r & mask31;\n ull middle = ld * ru + lu * rd;\n return ((lu * ru) << 1) + ld * rd + ((middle & mask30) << 31) +\n (middle >> 30);\n}\n\null mul(ull l, int r) {\n ull lu = l >> 31, ld = l & mask31;\n ull middle = lu * r;\n return ld * r + ((middle & mask30) << 31) + (middle >> 30);\n}\n\nvoid prepare_pows(size_t sz) {\n rep(i, pows.size() - 1, sz - 1) pows.push_back(mod(mul(pows[i], base)));\n}\n\nclass Calculator {\n private:\n vector<ull> hash;\n\n public:\n template <typename Iter>\n Calculator(Iter first, Iter last) : hash(last - first + 1) {\n prepare_pows(last - first + 1);\n rep(i, last - first) hash[i + 1] = mod(mul(hash[i], base) + first[i]);\n // assert(hash[i+1] < (1ULL << 62));\n }\n\n public:\n ull operator()(int l, int r) const {\n static constexpr ull large = MOD * ((1 << 2) - 1);\n return mod(hash[r] + large - mul(hash[l], pows[r - l]));\n }\n};\n\n} // namespace rolling_hash\n\n\nnamespace hash_monoid {\n\nusing namespace rolling_hash;\n\nvector<ull> sum_pows{1};\n\nvoid prepare_sum_pows(size_t sz) {\n prepare_pows(sz);\n rep(i, sum_pows.size() - 1, sz - 1) {\n sum_pows.push_back(mod(sum_pows[i] + pows[i + 1]));\n }\n}\n\n// monoid\nstruct Hash {\n ull value;\n int length;\n\n Hash() : value(0), length(0) {} // unit\n Hash(ull _value, int _length) : value(_value), length(_length) {}\n Hash(char c, int _length = 1) : value(calc_hash(c, _length)), length(_length) {}\n\n private:\n ull calc_hash(char c, int _length) {\n prepare_sum_pows(_length);\n return mod(mul(sum_pows[_length - 1], c));\n }\n\n public:\n operator ull() { return value; }\n bool operator==(const Hash &rhs) {\n return value == rhs.value && length == rhs.length;\n }\n bool operator!=(const Hash &rhs) {\n return value == rhs.value && length == rhs.length;\n }\n};\n\n\nstruct mergeT {\n Hash operator()(const Hash &lhs, const Hash &rhs) const {\n prepare_pows(rhs.length+1);\n return Hash(mod(mul(lhs.value, pows[rhs.length]) + rhs.value),\n lhs.length + rhs.length);\n }\n};\n\n#pragma GCC diagnostic ignored \"-Wunused-parameter\"\nstruct updT {\n Hash operator()(const Hash &lhs, char c, int k = 1) const {\n return Hash(c, k);\n }\n};\n#pragma GCC diagnostic warning \"-Wunused-parameter\"\n\n// using HashSegTree = SegmentTree<Hash, mergeT, updT>;\nusing HashSegTree = LazySegmentTree<Hash, char, mergeT, assignT, updT>;\n\n} // namespace hash_monoid\n\n\n\nint main() {\n int n = IN;\n string u = IN;\n\n hash_monoid::HashSegTree hash(all(u), n);\n\n rep(IN) {\n string cmd = IN;\n if (cmd[0] == 's') {\n int x = IN1, y = IN1; string z = IN;\n hash.modify(x, y+1, z[0]);\n } else {\n int a = IN1, b = IN1, c = IN1, d = IN1;\n b++; d++;\n int eq = 0, neq = min(b-a, d-c)+1;\n while (neq - eq > 1) {\n int m = (eq + neq) / 2;\n auto l = hash.query(a, a+m);\n auto r = hash.query(c, c+m);\n (l == r ? eq : neq) = m;\n }\n if (eq == b-a and eq == d-c) OUT(\"e\");\n else if (eq == b-a) OUT(\"s\");\n else if (eq == d-c) OUT(\"t\");\n else {\n auto s = hash.query(a+eq, a+eq+1).value;\n auto t = hash.query(c+eq, c+eq+1).value;\n OUT(s < t ? \"s\" : \"t\");\n }\n }\n }\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 12620, "score_of_the_acc": -0.2968, "final_rank": 5 }, { "submission_id": "aoj_0355_3953901", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <functional>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <set>\n#include <cstdint>\nusing namespace std;\nusing llong = long long;\n\n//===\ntemplate<typename Monoid, typename Laz>\nstruct LazySegmentTree {\n\n const function<Monoid(Monoid, Monoid)> mergeMonoid;\n const function<Monoid(Monoid, Laz, int)> applyLaz;\n const function<Laz(Laz, Laz)> mergeLaz;\n \n const Monoid e; // neutral element\n \n vector<Monoid> seg;\n vector<Laz> lazy;\n vector<bool> isUpdated;\n \n int size;\n \n LazySegmentTree(int nmemb, const Monoid &e,\n function<Monoid(Monoid, Monoid)> f,\n function<Monoid(Monoid, Laz, int)> g,\n function<Laz(Laz, Laz)> h):\n e(e), mergeMonoid(f), applyLaz(g), mergeLaz(h)\n {\n size = 1;\n while (size < nmemb) {\n size *= 2;\n }\n\n seg.assign(2 * size - 1, e);\n isUpdated.assign(2 * size - 1, true);\n lazy.resize(2 * size - 1); \n }\n\n inline void propagation(int k, int len) {\n if (!isUpdated[k]) {\n seg[k] = applyLaz(seg[k], lazy[k], len);\n if (len > 1) {\n if (isUpdated[2 * k + 1])\n lazy[2 * k + 1] = lazy[k], isUpdated[2 * k + 1] = false;\n else\n lazy[2 * k + 1] = mergeLaz(lazy[2 * k + 1], lazy[k]);\n \n if (isUpdated[2 * k + 2])\n lazy[2 * k + 2] = lazy[k], isUpdated[2 * k + 2] = false;\n else\n lazy[2 * k + 2] = mergeLaz(lazy[2 * k + 2], lazy[k]);\n }\n isUpdated[k] = true;\n }\n }\n\n Monoid update(int k, int nl, int nr, int ql, int qr, Laz dat) {\n propagation(k, nr - nl);\n\n if (nr <= ql || qr <= nl) return seg[k];\n\n if (ql <= nl && nr <= qr) {\n lazy[k] = dat;\n isUpdated[k] = false;\n propagation(k, nr - nl);\n return seg[k];\n }\n else {\n seg[k] = mergeMonoid(update(2 * k + 1, nl, (nl + nr) / 2, ql, qr, dat),\n update(2 * k + 2, (nl + nr) / 2, nr, ql, qr, dat));\n return seg[k];\n }\n }\n\n // [l, r) <= dat\n void update(int l, int r, Laz dat) {\n update(0, 0, size, l, r, dat);\n }\n\n Monoid fold(int k, int nl, int nr, int ql, int qr) {\n\n propagation(k, nr - nl);\n \n if (nr <= ql || qr <= nl) return e;\n\n if (ql <= nl && nr <= qr) return seg[k];\n else return mergeMonoid(fold(2 * k + 1, nl, (nl + nr) / 2, ql, qr),\n fold(2 * k + 2, (nl + nr) / 2, nr, ql, qr));\n }\n\n // [l, r)\n Monoid fold(int l, int r) {\n if (r <= l) return e;\n return fold(0, 0, size, l, r);\n }\n\n Monoid operator [](const int &k) {\n return fold(k, k + 1);\n }\n};\n//===\n\ntemplate<uint64_t mod, uint64_t base>\nstruct RollingHashMonoid {\n using rh = RollingHashMonoid<mod, base>;\n \n int sz;\n uint64_t h;\n\n static vector<uint64_t> p;\n\n RollingHashMonoid() {};\n RollingHashMonoid(uint64_t ch): sz(1), h(ch % mod) {};\n \n static rh neutral() {\n RollingHashMonoid res;\n res.sz = 0, res.h = 0;\n return res;\n };\n\n rh operator + (const rh &r) const {\n const rh &l = *this;\n rh res = neutral();\n\n while (p.size() <= r.sz) p.push_back(p.back() * base % mod);\n\n res.sz = l.sz + r.sz;\n res.h = (l.h * p[r.sz] % mod + r.h) % mod;\n return res;\n };\n};\ntemplate<uint64_t mod, uint64_t base>\nvector<uint64_t> RollingHashMonoid<mod, base>::p = vector<uint64_t>(1, 1);\n//===\n\nconst uint64_t base = 100;\nconst uint64_t mod = (uint64_t)(1e9) + 9;\nusing rh = RollingHashMonoid<mod, base>;\n\nuint64_t pow_t[200005];\nLazySegmentTree<rh, char> hash_str(200005, rh::neutral(),\n [](rh l, rh r){\n return l + r;\n },\n [](rh l, char r, int len){\n rh res(r * pow_t[len] % mod);\n res.sz = len;\n return res;\n },\n [](char l, char r) {\n return r;\n } );\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n //init\n {\n uint64_t b = 1;\n pow_t[0] = pow_t[1] = 1;\n for (int i = 2; i <= 200003; i++) {\n b = b * base % mod;\n pow_t[i] = (pow_t[i - 1] + b) % mod;\n }\n }\n\n llong n;\n llong q;\n string u;\n string com;\n\n cin >> n >> u >> q;\n\n for (int i = 0; i < n; i++) {\n hash_str.update(i, i + 1, u[i]);\n }\n\n while (q--) {\n llong a, b, c, d;\n llong x, y;\n char z;\n \n cin >> com;\n if (com == \"set\") {\n cin >> x >> y >> z;\n hash_str.update(x - 1, y, z);\n }\n else {\n cin >> a >> b >> c >> d;\n --a, --c;\n\n llong valid = 0;\n llong invalid = min(b - a, d - c) + 1;\n llong mid;\n\n while (invalid - valid > 1) {\n mid = (valid + invalid) / 2;\n if (hash_str.fold(a, a + mid).h ==\n hash_str.fold(c, c + mid).h) {\n valid = mid;\n }\n else {\n invalid = mid;\n }\n }\n \n if (valid == min(b - a, d - c)) {\n if (b - a < d - c) {\n cout << \"s\\n\";\n }\n else if (b - a == d - c) {\n cout << \"e\\n\";\n }\n else {\n cout << \"t\\n\";\n }\n }\n else {\n if (hash_str[a + valid].h < hash_str[c + valid].h) {\n cout << \"s\\n\";\n }\n else {\n cout << \"t\\n\";\n }\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1440, "memory_kb": 14432, "score_of_the_acc": -0.5957, "final_rank": 9 }, { "submission_id": "aoj_0355_3953889", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <functional>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <set>\n#include <cstdint>\nusing namespace std;\nusing llong = long long;\n\n//===\ntemplate<typename Monoid, typename Laz>\nstruct LazySegmentTree {\n\n const function<Monoid(Monoid, Monoid)> mergeMonoid;\n const function<Monoid(Monoid, Laz, int)> applyLaz;\n const function<Laz(Laz, Laz)> mergeLaz;\n \n const Monoid e; // neutral element\n \n vector<Monoid> seg;\n vector<Laz> lazy;\n vector<bool> isUpdated;\n \n int size;\n \n LazySegmentTree(int nmemb, const Monoid &e,\n function<Monoid(Monoid, Monoid)> f,\n function<Monoid(Monoid, Laz, int)> g,\n function<Laz(Laz, Laz)> h):\n e(e), mergeMonoid(f), applyLaz(g), mergeLaz(h)\n {\n size = 1;\n while (size < nmemb) {\n size *= 2;\n }\n\n seg.assign(2 * size - 1, e);\n isUpdated.assign(2 * size - 1, true);\n lazy.resize(2 * size - 1); \n }\n\n inline void propagation(int k, int len) {\n if (!isUpdated[k]) {\n seg[k] = applyLaz(seg[k], lazy[k], len);\n if (len > 1) {\n if (isUpdated[2 * k + 1])\n lazy[2 * k + 1] = lazy[k], isUpdated[2 * k + 1] = false;\n else\n lazy[2 * k + 1] = mergeLaz(lazy[2 * k + 1], lazy[k]);\n \n if (isUpdated[2 * k + 2])\n lazy[2 * k + 2] = lazy[k], isUpdated[2 * k + 2] = false;\n else\n lazy[2 * k + 2] = mergeLaz(lazy[2 * k + 2], lazy[k]);\n }\n isUpdated[k] = true;\n }\n }\n\n Monoid update(int k, int nl, int nr, int ql, int qr, Laz dat) {\n propagation(k, nr - nl);\n\n if (nr <= ql || qr <= nl) return seg[k];\n\n if (ql <= nl && nr <= qr) {\n lazy[k] = dat;\n isUpdated[k] = false;\n propagation(k, nr - nl);\n return seg[k];\n }\n else {\n seg[k] = mergeMonoid(update(2 * k + 1, nl, (nl + nr) / 2, ql, qr, dat),\n update(2 * k + 2, (nl + nr) / 2, nr, ql, qr, dat));\n return seg[k];\n }\n }\n\n // [l, r) <= dat\n void update(int l, int r, Laz dat) {\n update(0, 0, size, l, r, dat);\n }\n\n Monoid fold(int k, int nl, int nr, int ql, int qr) {\n\n propagation(k, nr - nl);\n \n if (nr <= ql || qr <= nl) return e;\n\n if (ql <= nl && nr <= qr) return seg[k];\n else return mergeMonoid(fold(2 * k + 1, nl, (nl + nr) / 2, ql, qr),\n fold(2 * k + 2, (nl + nr) / 2, nr, ql, qr));\n }\n\n // [l, r)\n Monoid fold(int l, int r) {\n if (r <= l) return e;\n return fold(0, 0, size, l, r);\n }\n\n Monoid operator [](const int &k) {\n return fold(k, k + 1);\n }\n};\n//===\n\ntemplate<uint64_t mod, uint64_t base>\nstruct RollingHashMonoid {\n using rh = RollingHashMonoid<mod, base>;\n \n int sz;\n uint64_t h;\n\n static vector<uint64_t> p;\n\n RollingHashMonoid() {};\n RollingHashMonoid(uint64_t ch): sz(1), h(ch % mod) {};\n \n static rh neutral() {\n RollingHashMonoid res;\n res.sz = 0, res.h = 0;\n return res;\n };\n\n rh operator + (const rh &r) const {\n const rh &l = *this;\n rh res = neutral();\n\n while (p.size() <= r.sz) p.push_back(p.back() * base % mod);\n\n res.sz = l.sz + r.sz;\n res.h = (l.h * p[r.sz] % mod + r.h) % mod;\n return res;\n };\n};\ntemplate<uint64_t mod, uint64_t base>\nvector<uint64_t> RollingHashMonoid<mod, base>::p = vector<uint64_t>(1, 1);\n//===\n\nconst uint64_t base = 100;\nconst uint64_t mod = (uint64_t)(1e9) + 9;\nusing rh = RollingHashMonoid<mod, base>;\n\nuint64_t pow_t[200005];\nLazySegmentTree<rh, char> hash_str(200005, rh::neutral(),\n [](rh l, rh r){\n return l + r;\n },\n [](rh l, char r, int len){\n rh res(r * pow_t[len] % mod);\n res.sz = len;\n return res;\n },\n [](char l, char r) {\n return r;\n } );\n\nint main() {\n //init\n {\n uint64_t b = 1;\n pow_t[0] = pow_t[1] = 1;\n for (int i = 2; i <= 200003; i++) {\n b = b * base % mod;\n pow_t[i] = (pow_t[i - 1] + b) % mod;\n }\n }\n\n llong n;\n llong q;\n string u;\n string com;\n\n cin >> n >> u >> q;\n\n for (int i = 0; i < n; i++) {\n hash_str.update(i, i + 1, u[i]);\n }\n\n while (q--) {\n llong a, b, c, d;\n llong x, y;\n char z;\n \n cin >> com;\n if (com == \"set\") {\n cin >> x >> y >> z;\n hash_str.update(x - 1, y, z);\n }\n else {\n cin >> a >> b >> c >> d;\n --a, --c;\n\n llong valid = 0;\n llong invalid = min(b - a, d - c) + 1;\n llong mid;\n\n while (invalid - valid > 1) {\n mid = (valid + invalid) / 2;\n if (hash_str.fold(a, a + mid).h ==\n hash_str.fold(c, c + mid).h) {\n valid = mid;\n }\n else {\n invalid = mid;\n }\n }\n \n if (valid == min(b - a, d - c)) {\n if (b - a < d - c) {\n cout << \"s\\n\";\n }\n else if (b - a == d - c) {\n cout << \"e\\n\";\n }\n else {\n cout << \"t\\n\";\n }\n }\n else {\n if (hash_str[a + valid].h < hash_str[c + valid].h) {\n cout << \"s\\n\";\n }\n else {\n cout << \"t\\n\";\n }\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1620, "memory_kb": 14544, "score_of_the_acc": -0.6916, "final_rank": 11 }, { "submission_id": "aoj_0355_3855343", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i64 = long long;\n#define rep(i,s,e) for(i64 (i) = (s);(i) < (e);(i)++)\n#define all(x) x.begin(),x.end()\n#define let auto const\n\nstruct tt {\n i64 val;\n i64 base;\n};\n\nstruct lazy_segment_tree {\n using T = tt;\n using L = i64;\n const i64 mod = 1e9 + 7;\n const i64 base = 9973;\n T t_ide() { return { 0, 1 }; }\n L l_ide() { return 0; }\n T ope(const T& a, const T& b) {\n return { (a.val * b.base + b.val) % mod, a.base * b.base % mod };\n }\n L lazy_ope(const L& a, const L& b) { return b; }\n T effect(const T& t, const L& l, const i64 len) { return { l * bsum[len] % mod, t.base }; }\n\n i64 n;\n vector<T> node;\n vector<L> lazy;\n vector<bool> flag;\n vector<i64> bsum;\n\n /* create lazy_segment_tree for sequence [t_ide; sz]A */\n lazy_segment_tree(std::vector<i64> init) {\n n = 1;\n while(n < init.size()) n *= 2;\n node.assign(n * 2, t_ide());\n lazy.assign(n * 2, l_ide());\n flag.assign(n * 2, false);\n for(int i = 0;i < init.size();i++) node[i + n - 1] = { init[i], base };\n for(int i = n - 2;i >= 0;i--) {\n node[i] = ope(node[i * 2 + 1], node[i * 2 + 2]);\n }\n bsum.assign(n + 1, 0);\n for(int i = 1;i <= n;i++) bsum[i] = (bsum[i - 1] * base + 1) % mod;\n }\n \n\n void eval(i64 l, i64 r, i64 k) {\n if(flag[k]) {\n node[k] = effect(node[k], lazy[k], r - l);\n \n if(r - l > 1) {\n lazy[k * 2 + 1] = lazy_ope(lazy[k * 2 + 1], lazy[k]);\n flag[k * 2 + 1] = true;\n lazy[k * 2 + 2] = lazy_ope(lazy[k * 2 + 2], lazy[k]);\n flag[k * 2 + 2] = true;\n }\n\n flag[k] = false;\n lazy[k] = l_ide();\n }\n }\n \n /* for i in [a, b) effect(a[i], lx) */\n void update(i64 a, i64 b, L lx, i64 l = 0, i64 r = -1, i64 k = 0) {\n if(r < 0) r = n;\n eval(l, r, k);\n if(b <= l || r <= a) return;\n else if(a <= l && r <= b) {\n lazy[k] = lazy_ope(lazy[k], lx);\n flag[k] = true;\n eval(l, r, k);\n }\n else {\n update(a, b, lx, l, (l + r) / 2, k * 2 + 1);\n update(a, b, lx, (l + r) / 2, r, k * 2 + 2);\n node[k] =ope(node[k * 2 + 1], node[k * 2 + 2]);\n }\n }\n \n /* the sum of a[i] for i in [a, b) */\n T get(i64 a, i64 b, i64 l = 0, i64 r = -1, i64 k = 0) {\n if(r < 0) r = n;\n eval(l, r, k);\n if(b <= l || r <= a) return t_ide();\n else if(a <= l && r <= b) return node[k];\n else return ope(get(a, b, l, (l + r) / 2, k * 2 + 1), get(a, b, (l + r) / 2, r, k * 2 + 2));\n }\n};\n\nint main() {\n i64 N;\n cin >> N;\n string U;\n cin >> U;\n vector<i64> u(N);\n rep(i,0,N) u[i] = (i64)(U[i] - 'a');\n\n lazy_segment_tree seg(u);\n i64 Q;\n cin >> Q;\n\n rep(q,0,Q) {\n string que;\n cin >> que;\n if(que == \"set\") {\n i64 x, y;\n char z;\n cin >> x >> y >> z;\n seg.update(x - 1, y, (i64)(z - 'a'));\n }\n else {\n i64 a, b, c, d;\n cin >> a >> b >> c >> d;\n a--;\n c--;\n i64 OK = 0;\n i64 NG = min(b - a, d - c) + 1;\n while(NG - OK > 1) {\n i64 mid = (OK + NG) / 2;\n //cout << mid << endl;\n //cout << a << \" \" << a + mid << \" = \" << seg.get(a, a + mid).val << endl;\n //cout << c << \" \" << c + mid << \" = \" << seg.get(c , c + mid).val << endl;\n if(seg.get(a, a + mid).val == seg.get(c, c + mid).val) {\n OK = mid;\n }\n else {\n NG = mid;\n }\n }\n if(a + OK == b && c + OK == d) {\n cout << \"e\" << endl;\n }\n else if(a + OK == b) {\n cout << \"s\" << endl;\n }\n else if(c + OK == d) {\n cout << \"t\" << endl;\n }\n else if(seg.get(a + OK, a + OK + 1).val < seg.get(c + OK, c + OK + 1).val) {\n cout << \"s\" << endl;\n }\n else {\n cout << \"t\" << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 2260, "memory_kb": 20684, "score_of_the_acc": -1.0958, "final_rank": 16 }, { "submission_id": "aoj_0355_3629128", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 200005\n#define NUM1 1000000007\n#define NUM2 99999883\n\n\nstruct Data{\n\tData(){\n\n\t\thash_1 = 0;\n\t\thash_2 = 0;\n\t\tlength = 0;\n\t}\n\tData(ull arg_hash_1,ull arg_hash_2,ull arg_length){\n\t\thash_1 = arg_hash_1;\n\t\thash_2 = arg_hash_2;\n\t\tlength = arg_length;\n\t}\n\n\tull hash_1,hash_2;\n\tull length;\n};\n\nint N;\nint LENGTH;\nchar buf[SIZE];\nint data[8*SIZE]; //文字を持つ\null HASH[8*SIZE][2];\null POW[SIZE][2],TABLE[26][SIZE][2];\n\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(int update_left,int update_right,int new_value,int node_id,int node_left,int node_right){\n\tif(update_right < node_left || update_left > node_right)return; //区間に重なりがなければreturn\n\telse if(update_left <= node_left && update_right >= node_right){ //このノードがカバーしている区間が、更新区間の部分区間である場合\n\n\t\tdata[node_id] = new_value; //文字('a'からの差)\n\t\tHASH[node_id][0] = TABLE[new_value][node_right-node_left+1][0];\n\t\tHASH[node_id][1] = TABLE[new_value][node_right-node_left+1][1];\n\n\t}else{ //一部に重なりがある場合\n\t\t//データを左右の子に引き継ぐ\n\t\tif(data[node_id] >= 0){\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+1,node_left,(node_left+node_right)/2);\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\t\tdata[node_id] = -1; //値を持っていないことを表す\n\t\t}\n\t\tupdate(update_left,update_right,new_value,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tupdate(update_left,update_right,new_value,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\t\tull right_len = node_right-(node_left+node_right)/2;\n\n\t\tHASH[node_id][0] = HASH[2*node_id+1][0]*POW[right_len][0]+HASH[2*node_id+2][0];\n\t\tHASH[node_id][1] = HASH[2*node_id+1][1]*POW[right_len][1]+HASH[2*node_id+2][1];\n\t}\n}\n\n//ハッシュ値および区間の長さを返却する\nData query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\tif(search_right < node_left || search_left > node_right){\n\t\treturn Data(0,0,0);\n\t}else if(node_left >= search_left && node_right <= search_right){\n\t\treturn Data(HASH[node_id][0],HASH[node_id][1],(ull)(node_right-node_left+1));\n\t}else{\n\n\t\tif(data[node_id] >= 0){\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+1,node_left,(node_left+node_right)/2);\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\t\tdata[node_id] = -1; //値を持っていないことを表す\n\t\t\tull right_len = node_right-(node_left+node_right)/2;\n\n\t\t\tHASH[node_id][0] = HASH[2*node_id+1][0]*POW[right_len][0]+HASH[2*node_id+2][0];\n\t\t\tHASH[node_id][1] = HASH[2*node_id+1][1]*POW[right_len][1]+HASH[2*node_id+2][1];\n\t\t}\n\n\t\tData left = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tData right = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\t\treturn Data(left.hash_1*POW[right.length][0]+right.hash_1,left.hash_2*POW[right.length][1]+right.hash_2,left.length+right.length);\n\t}\n}\n\nint find_word(Data info){\n\n\tfor(int i = 0; i < 26; i++){\n\n\t\tif(info.hash_1 == TABLE[i][1][0] && info.hash_2 == TABLE[i][1][1]){\n\t\t\treturn i;\n\t\t}\n\t}\n\treturn -1;\n}\n\nint main(){\n\n\tscanf(\"%d\",&LENGTH);\n\n\t//POWテーブル作成\n\tPOW[0][0] = 1;\n\tPOW[0][1] = 1;\n\n\tfor(int i = 1; i <= LENGTH; i++){\n\n\t\tPOW[i][0] = POW[i-1][0]*NUM1;\n\t\tPOW[i][1] = POW[i-1][1]*NUM2;\n\t}\n\n\t//文字のハッシュ値をあらかじめ作っておく\n\tfor(int i = 0; i < 26; i++){\n\t\tTABLE[i][0][0] = 0;\n\t\tTABLE[i][0][1] = 0;\n\t\tfor(int k = 1; k <= LENGTH; k++){\n\t\t\tTABLE[i][k][0] = ('a'+i) + TABLE[i][k-1][0]*NUM1;\n\t\t\tTABLE[i][k][1] = ('a'+i) + TABLE[i][k-1][1]*NUM2;\n\t\t}\n\t}\n\n\tN = 1;\n\tinit(LENGTH);\n\tfor(int i = 0; i <= 2*N-2; i++)data[i] = -1;\n\n\tscanf(\"%s\",buf);\n\tfor(int i = 0; i < LENGTH; i++){\n\t\tupdate(i,i,buf[i]-'a',0,0,N-1);\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tchar order[6],z[2];\n\tint x,y,a,b,c,d;\n\tint L,R,mid,match_len;\n\n\tData A,B;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%s\",order);\n\n\t\tif(order[0] == 's'){\n\n\t\t\tscanf(\"%d %d %s\",&x,&y,z);\n\t\t\tupdate(x-1,y-1,z[0]-'a',0,0,N-1);\n\n\t\t}else{ //比較命令\n\n\t\t\tscanf(\"%d %d %d %d\",&a,&b,&c,&d);\n\n\t\t\ta--;\n\t\t\tb--;\n\t\t\tc--;\n\t\t\td--;\n\n\t\t\tL = 0,R = min(b-a+1,d-c+1),mid = (L+R)/2;\n\t\t\tmatch_len = 0;\n\n\t\t\twhile(L <= R){\n\n\t\t\t\tA = query(a,a+mid-1,0,0,N-1);\n\t\t\t\tB = query(c,c+mid-1,0,0,N-1);\n\n\t\t\t\tif(A.hash_1==B.hash_1 && A.hash_2 == B.hash_2){\n\n\t\t\t\t\tmatch_len = mid;\n\t\t\t\t\tL = mid+1;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tR = mid-1;\n\t\t\t\t}\n\t\t\t\tmid = (L+R)/2;\n\t\t\t}\n\n\t\t\tif(match_len == b-a+1 && match_len == d-c+1){\n\n\t\t\t\tprintf(\"e\\n\");\n\t\t\t}else{\n\t\t\t\tif(match_len == b-a+1 || (match_len != d-c+1 && find_word(query(a+match_len,a+match_len,0,0,N-1)) < find_word(query(c+match_len,c+match_len,0,0,N-1)))){\n\n\t\t\t\t\tprintf(\"s\\n\");\n\t\t\t\t}else{\n\t\t\t\t\tprintf(\"t\\n\");\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1040, "memory_kb": 96032, "score_of_the_acc": -1.2802, "final_rank": 17 }, { "submission_id": "aoj_0355_3629127", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 200005\n#define NUM1 1000000007\n#define NUM2 99999883\n\n\nstruct Data{\n\tData(){\n\n\t\thash_1 = 0;\n\t\thash_2 = 0;\n\t\tlength = 0;\n\t}\n\tData(ull arg_hash_1,ull arg_hash_2,ull arg_length){\n\t\thash_1 = arg_hash_1;\n\t\thash_2 = arg_hash_2;\n\t\tlength = arg_length;\n\t}\n\n\tull hash_1,hash_2;\n\tull length;\n};\n\nint N;\nint LENGTH;\nchar buf[SIZE];\nint data[8*SIZE]; //文字を持つ\null HASH[8*SIZE][2];\null POW[SIZE][2],TABLE[26][SIZE][2];\n\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(int update_left,int update_right,int new_value,int node_id,int node_left,int node_right){\n\tif(update_right < node_left || update_left > node_right)return; //区間に重なりがなければreturn\n\telse if(update_left <= node_left && update_right >= node_right){ //このノードがカバーしている区間が、更新区間の部分区間である場合\n\n\t\tdata[node_id] = new_value; //文字('a'からの差)\n\t\tHASH[node_id][0] = TABLE[new_value][node_right-node_left+1][0];\n\t\tHASH[node_id][1] = TABLE[new_value][node_right-node_left+1][1];\n\n\t}else{ //一部に重なりがある場合\n\t\t//データを左右の子に引き継ぐ\n\t\tif(data[node_id] >= 0){\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+1,node_left,(node_left+node_right)/2);\n\t\t\tupdate(node_left,node_right,data[node_id],2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\t\tdata[node_id] = -1; //値を持っていないことを表す\n\t\t}\n\t\tupdate(update_left,update_right,new_value,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tupdate(update_left,update_right,new_value,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\t\tull right_len = node_right-(node_left+node_right)/2;\n\n\t\tHASH[node_id][0] = HASH[2*node_id+1][0]*POW[right_len][0]+HASH[2*node_id+2][0];\n\t\tHASH[node_id][1] = HASH[2*node_id+1][1]*POW[right_len][1]+HASH[2*node_id+2][1];\n\t}\n}\n\n//ハッシュ値および区間の長さを返却する\nData query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\tif(data[node_id] >= 0){\n\t\tupdate(node_left,node_right,data[node_id],2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tupdate(node_left,node_right,data[node_id],2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\tdata[node_id] = -1; //値を持っていないことを表す\n\t\tull right_len = node_right-(node_left+node_right)/2;\n\n\t\tHASH[node_id][0] = HASH[2*node_id+1][0]*POW[right_len][0]+HASH[2*node_id+2][0];\n\t\tHASH[node_id][1] = HASH[2*node_id+1][1]*POW[right_len][1]+HASH[2*node_id+2][1];\n\t}\n\n\tif(search_right < node_left || search_left > node_right){\n\t\treturn Data(0,0,0);\n\t}else if(node_left >= search_left && node_right <= search_right){\n\t\treturn Data(HASH[node_id][0],HASH[node_id][1],(ull)(node_right-node_left+1));\n\t}else{\n\n\t\tData left = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tData right = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\t\treturn Data(left.hash_1*POW[right.length][0]+right.hash_1,left.hash_2*POW[right.length][1]+right.hash_2,left.length+right.length);\n\t}\n}\n\nint find_word(Data info){\n\n\tfor(int i = 0; i < 26; i++){\n\n\t\tif(info.hash_1 == TABLE[i][1][0] && info.hash_2 == TABLE[i][1][1]){\n\t\t\treturn i;\n\t\t}\n\t}\n\treturn -1;\n}\n\nint main(){\n\n\tscanf(\"%d\",&LENGTH);\n\n\t//POWテーブル作成\n\tPOW[0][0] = 1;\n\tPOW[0][1] = 1;\n\n\tfor(int i = 1; i <= LENGTH; i++){\n\n\t\tPOW[i][0] = POW[i-1][0]*NUM1;\n\t\tPOW[i][1] = POW[i-1][1]*NUM2;\n\t}\n\n\t//文字のハッシュ値をあらかじめ作っておく\n\tfor(int i = 0; i < 26; i++){\n\t\tTABLE[i][0][0] = 0;\n\t\tTABLE[i][0][1] = 0;\n\t\tfor(int k = 1; k <= LENGTH; k++){\n\t\t\tTABLE[i][k][0] = ('a'+i) + TABLE[i][k-1][0]*NUM1;\n\t\t\tTABLE[i][k][1] = ('a'+i) + TABLE[i][k-1][1]*NUM2;\n\t\t}\n\t}\n\n\tN = 1;\n\tinit(LENGTH);\n\tfor(int i = 0; i <= 2*N-2; i++)data[i] = -1;\n\n\tscanf(\"%s\",buf);\n\tfor(int i = 0; i < LENGTH; i++){\n\t\tupdate(i,i,buf[i]-'a',0,0,N-1);\n\t}\n\n\tint num_query;\n\tscanf(\"%d\",&num_query);\n\n\tchar order[6],z[2];\n\tint x,y,a,b,c,d;\n\tint L,R,mid,match_len;\n\n\tData A,B;\n\n\tfor(int loop = 0; loop < num_query; loop++){\n\n\t\tscanf(\"%s\",order);\n\n\t\tif(order[0] == 's'){\n\n\t\t\tscanf(\"%d %d %s\",&x,&y,z);\n\t\t\tupdate(x-1,y-1,z[0]-'a',0,0,N-1);\n\n\t\t}else{ //比較命令\n\n\t\t\tscanf(\"%d %d %d %d\",&a,&b,&c,&d);\n\n\t\t\ta--;\n\t\t\tb--;\n\t\t\tc--;\n\t\t\td--;\n\n\t\t\tL = 0,R = min(b-a+1,d-c+1),mid = (L+R)/2;\n\t\t\tmatch_len = 0;\n\n\t\t\twhile(L <= R){\n\n\t\t\t\tA = query(a,a+mid-1,0,0,N-1);\n\t\t\t\tB = query(c,c+mid-1,0,0,N-1);\n\n\t\t\t\tif(A.hash_1==B.hash_1 && A.hash_2 == B.hash_2){\n\n\t\t\t\t\tmatch_len = mid;\n\t\t\t\t\tL = mid+1;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tR = mid-1;\n\t\t\t\t}\n\t\t\t\tmid = (L+R)/2;\n\t\t\t}\n\n\t\t\tif(match_len == b-a+1 && match_len == d-c+1){\n\n\t\t\t\tprintf(\"e\\n\");\n\t\t\t}else{\n\t\t\t\tif(match_len == b-a+1 || (match_len != d-c+1 && find_word(query(a+match_len,a+match_len,0,0,N-1)) < find_word(query(c+match_len,c+match_len,0,0,N-1)))){\n\n\t\t\t\t\tprintf(\"s\\n\");\n\t\t\t\t}else{\n\t\t\t\t\tprintf(\"t\\n\");\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 102388, "score_of_the_acc": -1.3605, "final_rank": 19 }, { "submission_id": "aoj_0355_3437930", "code_snippet": "# include <iostream>\n# include <algorithm>\n#include <array>\n# include <cassert>\n#include <cctype>\n#include <climits>\n#include <numeric>\n# include <vector>\n# include <string>\n# include <set>\n# include <map>\n# include <cmath>\n# include <iomanip>\n# include <functional>\n# include <tuple>\n# include <utility>\n# include <stack>\n# include <queue>\n# include <list>\n# include <bitset>\n# include <complex>\n# include <chrono>\n# include <random>\n# include <limits.h>\n# include <unordered_map>\n# include <unordered_set>\n# include <deque>\n# include <cstdio>\n# include <cstring>\n#include <stdio.h>\n#include<time.h>\n#include <stdlib.h>\n#include <cstdint>\n#include <cfenv>\n#include<fstream>\n//#include <bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n//long long MOD = 1000000000 + 7;//1000000000 + 7 998244353 924844033 1000000000 + 9;\nconstexpr long long INF = 1LL << 60;//numeric_limits<LL>::max();\nconst double PI = acos(-1);\n#define fir first\n#define sec second\n#define thi third\n#define debug(x) cerr<<#x<<\": \"<<x<<'\\n'\ntypedef pair<LL, LL> Pll;\ntypedef pair<double, double> Dll;\ntypedef pair<LL, pair<LL, LL>> Ppll;\ntypedef pair<LL, pair<LL, bitset<100001>>> Pbll;\ntypedef pair<LL, pair<LL, vector<LL>>> Pvll;\ntypedef pair<LL, LL> Vec2;\nstruct Tll { LL first, second, third; };\nstruct Fll { LL first, second, third, fourth; };\ntypedef pair<LL, Tll> Ptll;\n#define rep(i,rept) for(LL i=0;i<rept;i++)\n#define Rrep(i,mf) for(LL i=mf-1;i>=0;i--)\nvoid YN(bool f) {\n\tif (f)\n\t\tcout << \"YES\" << endl;\n\telse\n\t\tcout << \"NO\" << endl;\n}\nvoid yn(bool f) {\n\tif (f)\n\t\tcout << \"Yes\" << endl;\n\telse\n\t\tcout << \"No\" << endl;\n}\nstruct Edge { LL to, cost; };\nstruct edge {\n\tLL from, to, cost;\n};\nvector<vector<LL>>g;\nvector<edge>ed;\nvector<Pll>pv;\nset<LL>st;\nmap<Pll, LL>ma;\nint di[4][2] = { { 0,1 },{ 1,0 },{ 0,-1 },{ -1,0 } };\nstring str, ss;\nbool f;\nLL n, m, s, t, h, w, k,q, ans,sum, cnt,a[20];\n\nconst int P = 1685440109;\nconst int MOD = 2000000087;\nclass SegmentTree{\nprivate:\n\tstatic const LL INIT_DATA=0;\n\tstatic const char INIT_DELAY = '\\0';\n\tLL updateData(LL prev, int len, LL x) {\n\t\t//現在の範囲がすべて文字xで更新された場合\n\t\tif (x == INIT_DELAY)\n\t\t\treturn prev;\n\t\telse\n\t\t\treturn x * pPowSum[len] % MOD;\n\t}\n\tchar updateDelay(char x1, char x2) {\n\t\t//x1にx2を伝播する\n\t\tif (x2 == INIT_DELAY)\n\t\t\treturn x1;\n\t\telse\n\t\t\treturn x2;\n\t}\n\tLL uniteData(LL v1, int len1, LL v2, int len2) {\n\t\treturn (v1 + v2 * pPow[len1]) % MOD;\n\t}\n\tvector<long long> pPow, pPowSum;\n\tint n;\n\tvector<LL> node;\n\tvector<char> delay;\n\tvoid updateTree(int a, int b, int k, int l, int r, char x) {\n\t\t//[l,r]\n\t\tif (a <= l && r <= b) {\n\t\t\tnode[k] = updateData(node[k], r - l + 1, x);\n\t\t\tdelay[k] = updateDelay(delay[k], x);\n\t\t}\n\t\telse if (a <= r && l <= b) {\n\t\t\tint len = (r - l + 1) / 2;\n\t\t\tfor (int i = 0; i<2; ++i) {\n\t\t\t\tnode[k * 2 + 1 + i] = updateData(node[k * 2 + 1 + i], len, delay[k]);\n\t\t\t\tdelay[k * 2 + 1 + i] = updateDelay(delay[k * 2 + 1 + i], delay[k]);\n\t\t\t}\n\t\t\tdelay[k] = INIT_DELAY;\n\t\t\tupdateTree(a, b, k * 2 + 1, l, (l + r) / 2, x);\n\t\t\tupdateTree(a, b, k * 2 + 2, (l + r + 1) / 2, r, x);\n\t\t\tnode[k] = uniteData(node[k * 2 + 1], len, node[k * 2 + 2], len);\n\t\t}\n\t}\n\tLL getValue(int a, int b, int k, int l, int r) {\n\t\tif (a <= l && r <= b) {\n\t\t\treturn node[k];\n\t\t}\n\t\telse if (a <= r && l <= b) {\n\t\t\tint len = (r - l + 1) / 2;\n\t\t\tfor (int i = 0; i<2; ++i) {\n\t\t\t\tnode[k * 2 + 1 + i] = updateData(node[k * 2 + 1 + i], len, delay[k]);\n\t\t\t\tdelay[k * 2 + 1 + i] = updateDelay(delay[k * 2 + 1 + i], delay[k]);\n\t\t\t}\n\t\t\tdelay[k] = INIT_DELAY;\n\t\t\tint len1 = max(0, min(b, (l + r) / 2) - max(a, l) + 1);\n\t\t\tint len2 = max(0, min(b, r) - max(a, (l + r + 1) / 2) + 1);\n\t\t\tLL v1 = getValue(a, b, k * 2 + 1, l, (l + r) / 2);\n\t\t\tLL v2 = getValue(a, b, k * 2 + 2, (l + r + 1) / 2, r);\n\t\t\treturn uniteData(v1, len1, v2, len2);\n\t\t}\n\t\telse {\n\t\t\treturn INIT_DATA;\n\t\t}\n\t}\npublic:\n\tSegmentTree(int n0) {\n\t\tn = 1;\n\t\twhile (n < n0)\n\t\t\tn *= 2;\n\t\tnode.assign(2 * n - 1, INIT_DATA);\n\t\tdelay.assign(2 * n - 1, INIT_DELAY);\n\t\tpPow.resize(n + 1, 1);\n\t\tpPowSum.resize(n + 1, 0);\n\t\tfor (int i = 1; i <= n; ++i) {\n\t\t\tpPow[i] = pPow[i - 1] * P % MOD;\n\t\t\tpPowSum[i] = pPowSum[i - 1] + pPow[i - 1];\n\t\t}\n\t}\n\tvoid update(int a, int b, char x) {\n\t\tupdateTree(a, b, 0, 0, n - 1, x);\n\t}\n\tLL get(int a, int b) {\n\t\treturn getValue(a, b, 0, 0, n - 1);\n\t}\n};\nSegmentTree seg(210000);\nint main() {\n\tcin >> n;\n\tcin >> str;\n\tcin >> q;\n\trep(i, str.size())seg.update(i, i, str[i]);\n\trep(i, q) {\n\t\tLL x, y, z, w;\n\t\tchar c;\n\t\tcin >> ss;\n\t\tif (ss == \"comp\") {\n\t\t\tcin >> x >> y >> z >> w;\n\t\t\tx--, y--, z--, w--;\n\t\t\tLL size = min(y - x, w - z);\n\t\t\tLL l = -1, r = size + 1, mid;\n\t\t\twhile (r-l>1) {\n\t\t\t\tmid = (l + r) / 2;\n\t\t\t\tLL s1 = seg.get(x, x + mid);\n\t\t\t\tLL s2 = seg.get(z, z + mid);\n\t\t\t\tif (s1 == s2)\n\t\t\t\t\tl = mid;\n\t\t\t\telse\n\t\t\t\t\tr = mid;\n\t\t\t}\n\t\t\tif (l == size) {\n\t\t\t\tif (y - x == w - z)\n\t\t\t\t\tcout << \"e\" << endl;\n\t\t\t\telse if (y - x < w - z)\n\t\t\t\t\tcout << \"s\" << endl;\n\t\t\t\telse\n\t\t\t\t\tcout<<\"t\"<<endl;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (seg.get(x + l+1, x + l+1) < seg.get(z + l+1, z + l+1)) \n\t\t\t\t\tcout << \"s\" << endl;\n\t\t\t\telse\n\t\t\t\t\tcout << \"t\" << endl;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tcin >> x >> y >> c;\n\t\t\tx--, y--;\n\t\t\tseg.update(x, y, c);\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1670, "memory_kb": 12048, "score_of_the_acc": -0.6906, "final_rank": 10 }, { "submission_id": "aoj_0355_3240394", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\ntemplate <typename T,typename E>\nstruct SegmentTree{\n using F = function<T(T,T)>;\n using G = function<T(T,E)>;\n using H = function<E(E,E)>;\n int n,height;\n F f;\n G g;\n H h;\n T ti;\n E ei;\n vector<T> dat;\n vector<E> laz;\n SegmentTree(F f,G g,H h,T ti,E ei):\n f(f),g(g),h(h),ti(ti),ei(ei){}\n \n void init(int n_){\n n=1;height=0;\n while(n<n_) n<<=1,height++;\n dat.assign(2*n,ti);\n laz.assign(2*n,ei);\n }\n void build(const vector<T> &v){\n int n_=v.size();\n init(n_);\n for(int i=0;i<n_;i++) dat[n+i]=v[i];\n for(int i=n-1;i;i--)\n dat[i]=f(dat[(i<<1)|0],dat[(i<<1)|1]);\n }\n inline T reflect(int k){\n return laz[k]==ei?dat[k]:g(dat[k],laz[k]);\n }\n inline void eval(int k){\n if(laz[k]==ei) return;\n laz[(k<<1)|0]=h(laz[(k<<1)|0],laz[k]);\n laz[(k<<1)|1]=h(laz[(k<<1)|1],laz[k]);\n dat[k]=reflect(k);\n laz[k]=ei;\n }\n inline void thrust(int k){\n for(int i=height;i;i--) eval(k>>i);\n }\n inline void recalc(int k){ \n while(k>>=1)\n dat[k]=f(reflect((k<<1)|0),reflect((k<<1)|1));\n }\n void update(int a,int b,E x){\n thrust(a+=n);\n thrust(b+=n-1);\n for(int l=a,r=b+1;l<r;l>>=1,r>>=1){\n if(l&1) laz[l]=h(laz[l],x),l++;\n if(r&1) --r,laz[r]=h(laz[r],x);\n }\n recalc(a);\n recalc(b);\n }\n void set_val(int a,T x){\n thrust(a+=n);\n dat[a]=x;laz[a]=ei;\n recalc(a);\n }\n T query(int a,int b){\n thrust(a+=n);\n thrust(b+=n-1);\n T vl=ti,vr=ti;\n for(int l=a,r=b+1;l<r;l>>=1,r>>=1) {\n if(l&1) vl=f(vl,reflect(l++));\n if(r&1) vr=f(reflect(--r),vr);\n }\n return f(vl,vr);\n }\n};\n\n\nstruct FastIO{\n FastIO(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n }\n}fastio_beet;\n\n//INSERT ABOVE HERE\nsigned main(){\n int n;\n cin>>n;\n string s;\n cin>>s;\n int q;\n cin>>q;\n\n using ull = unsigned long long;\n using P = pair<ull, int>;\n \n const ull B = 1777771;\n vector<ull> po(n<<1,1);\n for(int i=1;i<(int)po.size();i++) po[i]=po[i-1]*B;\n\n vector<vector<ull> > hs(26,vector<ull>(n<<1,0));\n for(int c=0;c<26;c++){\n for(int i=1;i<(int)hs[c].size();i++)\n hs[c][i]=hs[c][i-1]*B+(c+'a');\n }\n auto f=[&](P a,P b){\n return P(a.first*po[b.second]+b.first,a.second+b.second);};\n auto g=[&](P a,int b){\n return P(hs[b][a.second],a.second);};\n auto h=[&](int a,int b){a++;return b;};\n\n P ti(0,0);\n int ei=-1;\n SegmentTree<P, int> seg(f,g,h,ti,ei);\n \n vector<P> vp;\n for(int i=0;i<n;i++) vp.emplace_back((ull)s[i],1);\n seg.build(vp);\n \n for(int i=0;i<q;i++){\n string type;\n cin>>type;\n if(type==\"set\"){\n int x,y;\n char z;\n cin>>x>>y>>z;\n x--;\n seg.update(x,y,z-'a');\n }\n if(type==\"comp\"){\n int a,b,c,d;\n cin>>a>>b>>c>>d;\n a--;c--;\n if(seg.query(a,b)==seg.query(c,d)){\n cout<<\"e\\n\";\n continue;\n }\n int w=min(b-a,d-c);\n //cout<<seg.query(a,a+w).first<<\" \"<<seg.query(a,a+w).second<<endl;\n //cout<<seg.query(c,c+w).first<<\" \"<<seg.query(c,c+w).second<<endl;\n if(seg.query(a,a+w)==seg.query(c,c+w)){\n cout<<(b-a<d-c?\"s\":\"t\")<<\"\\n\";\n continue;\n }\n int l=0,r=w;\n while(l+1<r){\n int m=(l+r)>>1;\n if(seg.query(a,a+m)==seg.query(c,c+m)) l=m;\n else r=m;\n }\n //cout<<a<<\" \"<<c<<\":\"<<l<<\" \"<<r<<endl;\n cout<<(seg.query(a+l,a+r)<seg.query(c+l,c+r)?\"s\":\"t\")<<\"\\n\";\n }\n }\n cout<<flush;\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 103112, "score_of_the_acc": -1, "final_rank": 15 }, { "submission_id": "aoj_0355_3240174", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define MAX 200012\n\n__int128 MOD=1007ll;\n__int128 MOD2=1000000000000000031LL;\n\nstruct st{\n\tint sz;\n\t__int128 val;\n\tchar lazy;\n\tst(){\n\t\tval=0;\n\t\tsz=0;\n\t\tlazy=0;\n\t}\n};\nst seg[MAX*4];\nchar buf[MAX];\nstring s;\nint n;\n__int128 pw[MAX];\n__int128 im[MAX];\n\nst merge(st a,st b){\n\tst r;\n\tr.sz=a.sz+b.sz;\n\tr.val=a.val+b.val*pw[a.sz];\n\tif(r.val>=MOD2)r.val%=MOD2;\n\treturn r;\n}\n\ninline void init(int b,int l,int r){\n\tif(l+1==r){\n\t\tseg[b].val=s[l];\n\t\tseg[b].sz=1;\n\t\treturn;\n\t}\n\tinit(b*2+1,l,(l+r)>>1);\n\tinit(b*2+2,(l+r)>>1,r);\n\tseg[b]=merge(seg[b*2+1],seg[b*2+2]);\n}\ninline void update(int b){\n\tif(seg[b].lazy==0)return;\n\tseg[b].val=im[seg[b].sz-1]*seg[b].lazy;\n\tif(seg[b].val>=MOD2)seg[b].val%=MOD2;\n\tif(b*2+2<MAX*4){\n\t\tseg[b*2+1].lazy=seg[b].lazy;\n\t\tseg[b*2+2].lazy=seg[b].lazy;\n\t}\n\tseg[b].lazy=0;\n}\ninline void add(int b,int l,int r,int ll,int rr,char z){\n\tupdate(b);\n\tif(r<=ll||rr<=l)return;\n\tif(ll<=l&&r<=rr){\n\t\tseg[b].lazy=z;\n\t\tupdate(b);\n\t\treturn;\n\t}\n\tadd(b*2+1,l,(l+r)>>1,ll,rr,z);\n\tadd(b*2+2,(l+r)>>1,r,ll,rr,z);\n\tseg[b]=merge(seg[b*2+1],seg[b*2+2]);\n}\ninline st get_val(int b,int l,int r,int ll,int rr){\n\tupdate(b);\n\tif(r<=ll||rr<=l)return st();\n\tif(ll<=l&&r<=rr){\n\t\treturn seg[b];\n\t}\n\treturn merge(get_val(b*2+1,l,(l+r)>>1,ll,rr),get_val(b*2+2,(l+r)>>1,r,ll,rr));\n}\n\nint q;\nlong long int hs(int a,int b){\n\treturn get_val(0,0,n,a,b+1).val;\n}\nint main(){\n\tpw[0]=1;\n\tfor(int i=1;i<MAX;i++){\n\t\tpw[i]=pw[i-1];\n\t\tpw[i]*=MOD;\n\t\tpw[i]%=MOD2;\n\t}\n\tim[0]=pw[0];\n\tfor(int i=1;i<MAX;i++){\n\t\tim[i]=im[i-1]+pw[i];\n\t\tif(im[i]>=MOD2)im[i]%=MOD2;\n\t}\n\tcin>>n;\n\tscanf(\"%s\",buf);\n\ts=buf;\n\tinit(0,0,n);\n\tcin>>q;\n\twhile(q--){\n\t\tscanf(\"%s\",buf);\n\t\tif(buf[0]=='s'){\n\t\t\tint l,r;\n\t\t\tscanf(\"%d%d\",&l,&r);\n\t\t\tscanf(\"%s\",buf);\n\t\t\tl--;\n\t\t\tadd(0,0,n,l,r,buf[0]);\n\t\t\tcontinue;\n\t\t}\t\n\t\t//cout<<\"end\"<<endl;\n\t\tint a,b;\n\t\tscanf(\"%d%d\",&a,&b);\n\t\tint c,d;\n\t\tscanf(\"%d%d\",&c,&d);\n\t\ta--;\n\t\tb--;\n\t\tc--;\n\t\td--;\n\t\tchar f='s';\n\t\tchar s='t';\n\t\tif((b-a)>(d-c)){\n\t\t\tswap(a,c);\n\t\t\tswap(b,d);\n\t\t\tswap(f,s);\n\t\t}\n\t\tint len=b-a;\n\t\tif(hs(a,b)==hs(c,c+len)){\n\t\t\tif((b-a)!=(d-c)){\n\t\t\t\tbuf[0]=f;\n\t\t\t\tbuf[1]='\\0';\n\t\t\t\tprintf(\"%s\",buf);\n\t\t\t\tputs(\"\");\n\t\t\t}\n\t\t\telse{\n\t\t\t\tputs(\"e\");\n\t\t\t}\n\t\t\tcontinue;\n\t\t}\n\t\tint mint=0;\n\t\tint maxt=len;\n\t\twhile(mint+1<maxt){\n\t\t\tint mid=(mint+maxt)/2;\n\t\t\tif(hs(a,a+mid)==hs(c,c+mid)){\n\t\t\t\tmint=mid+1;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tmaxt=mid;\n\t\t\t}\n\t\t}\n\t\tif(hs(a,a+mint)==hs(c,c+mint)){\n\t\t\tmint++;\n\t\t}\n\t\tint mid=mint;\n\t\tif(hs(a+mid,a+mid)<hs(c+mid,c+mid)){\n\t\t\tbuf[0]=f;\n\t\t\tbuf[1]='\\0';\n\t\t\tprintf(\"%s\",buf);\n\t\t\tputs(\"\");\n\t\t}\n\t\telse{\n\t\t\tbuf[0]=s;\n\t\t\tbuf[1]='\\0';\n\t\t\tprintf(\"%s\",buf);\n\t\t\tputs(\"\");\n\t\t}\n\t\t//cout<<\"end\"<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1150, "memory_kb": 47356, "score_of_the_acc": -0.8042, "final_rank": 13 }, { "submission_id": "aoj_0355_3239756", "code_snippet": "#include<deque>\n#include<queue>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<set>\n#include<cmath>\n#include<tuple>\n#include<string>\n//#include<chrono>\n#include<functional>\n#include<iterator>\n#include<random>\n#include<list>\n#include<unordered_set>\n#include<array>\n#include<map>\n#include<iomanip>\n#include<assert.h>\n#include<bitset>\n#include<stack>\nusing namespace std;\ntypedef long long int llint;\ntypedef long double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n/*\ncout<<setprecision(20);\ncin.tie(0);\nios::sync_with_stdio(false);\n*/\nconst llint moA=1e9+7;\nconst llint moB=1e9+9;\nconst llint big=2.19e15+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-15;\ntemplate <class T,class U>void mineq(T& a,U b){if(a>b){a=b;}}\ntemplate <class T,class U>void maxeq(T& a,U b){if(a<b){a=b;}}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\n//llint lcm(llint a,llint b){return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>llint LBI(vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>llint UBI(vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\n//segtree\n//hash値,埋めるの発生有無\n//長さは262144固定?\n//Qlog^2 n\nllint zyA[20],zyB[20];\nllint ruA[20],ruB[20];\nclass rori{public:\n\tllint hA,hB;\n\tchar ume;\n\trori(void){hA=0;hB=0;ume=0;}\n\trori(int inA,int inB,int dumy){hA=inA,hB=inB,ume=0;}\n\trori(int in,int naga){ume=in;hA=(in*ruA[naga])%moA,hB=(in*ruB[naga])%moB;}\n};\nrori tna(rori me,rori us,int an){return rori((me.hA*zyA[an]+us.hA)%moA,(me.hB*zyB[an]+us.hB)%moB,0);}\nrori tna(rori me,rori us,llint Ak,llint Bk){return rori((me.hA*Ak+us.hA)%moA,(me.hB*Bk+us.hB)%moB,0);}\n\nvoid bun(rori&per,rori&kox,rori&koy,int an){//anは子のを入れる\n\tif(per.ume){kox=rori(per.ume,an);koy=kox;per.ume=0;}\n}\nint main(void){\n\tllint n,h,i,j;cin>>n;\n\tzyA[0]=101,zyB[0]=101;\n\tfor(i=1;i<20;i++){zyA[i]=(zyA[i-1]*zyA[i-1])%moA;zyB[i]=(zyB[i-1]*zyB[i-1])%moB;}\n\tfor(i=0;i<20;i++){\n\t\tllint AA=1,BB=1;\n\t\truA[i]=0;ruB[i]=0;\n\t\tfor(j=0;j<(1<<i);j++){ruB[i]+=BB;ruB[i]%=moB;BB*=101;BB%=moB;ruA[i]+=AA;ruA[i]%=moA;AA*=101;AA%=moA;}\n\t}\n\tstring U;cin>>U;\n\tstatic rori seg[524288];\n\tfor(i=1;i<=n;i++){seg[i+262144]=rori(U[i-1],0);}\n\tfor(i=n+1;i<262144;i++){seg[i+262144]=rori(0,0);}\n\th=0;\n\tfor(i=262143;i>0;i--){\n\t\tseg[i]=tna(seg[i+i],seg[i+i+1],h);\n\t\tif((i&(-i))==i){h++;}\n\t}\n\tint Q;cin>>Q;\n\twhile(Q--){\n\t\tstring mei;cin>>mei;\n\t\tif(mei==\"set\"){\n\t\t\tint x,y;char z;cin>>x>>y>>z;\n\t\t\tx+=262143;y+=262145;int xx=x,yy=y;\n\t\t\tfor(h=18;h>0;h--){int G=x>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=y>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\th=0;\n\t\t\twhile(x+1<y){\n\t\t\t\tif(x%2==0){seg[x+1]=rori(z,h);}\n\t\t\t\tif(y%2==1){seg[y-1]=rori(z,h);}\n\t\t\t\tx>>=1;y>>=1;h++;\n\t\t\t}\n\t\t\tx=xx;y=yy;\n\t\t\th=0;\n\t\t\twhile(x>1){\n\t\t\t\tx>>=1;y>>=1;\n\t\t\t\tseg[x]=tna(seg[x<<1],seg[(x<<1)+1],h);\n\t\t\t\tseg[y]=tna(seg[y<<1],seg[(y<<1)+1],h);\n\t\t\t\th++;\n\t\t\t}\n\t\t}else{\n\t\t\tint a,b,c,d;cin>>a>>b>>c>>d;\n\t\t\tint bmin=0,bmax=min(b-a+1,d-c+1)+1;\n\t\t\t//普通に二分探索! セグ木上の二分探索テクは使用不可\n\t\t\t//最大何文字が一致しているか調べる\n\t\t\t//bmin文字一致している\n\t\t\tint Sa=a+262143,Ta=c+262143;\n\t\t\tfor(h=18;h>0;h--){int G=Sa>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=Ta>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\twhile(bmax-bmin>1){\n\t\t\t\t\n\t\t\t\tSa=a+262143;Ta=c+262143;\n\t\t\t\tint bgen=(bmin+bmax)>>1;\n\t\t\t\tint Se=a+bgen+262144,Te=c+bgen+262144;\n\t\t\t\tfor(h=18;h>0;h--){int G=Se>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=Te>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\t\trori Sans,Tans;\n\t\t\t\t{\n\t\t\t\t\tllint Auk=1,Buk=1;\n\t\t\t\t\trori nowM,nowU;\n\t\t\t\t\tint h=0;\n\t\t\t\t\twhile(Sa+1<Se){\n\t\t\t\t\t\tif(Sa%2==0){nowM=tna(nowM,seg[Sa+1],h);}\n\t\t\t\t\t\tif(Se%2==1){nowU=tna(seg[Se-1],nowU,Auk,Buk);Auk*=zyA[h];Auk%=moA;Buk*=zyB[h];Buk%=moB;}\n\t\t\t\t\t\tSa>>=1;Se>>=1;h++;\n\t\t\t\t\t}\n\t\t\t\t\t//cerr<<\"M,U=\"<<nowM.hA<<\" \"<<nowU.hA<<\" \";\n\t\t\t\t\tSans=tna(nowM,nowU,Auk,Buk);\n\t\t\t\t\t//cerr<<Sans.hA<<endl;\n\t\t\t\t}\n\t\t\t\t{\n\t\t\t\t\tllint Auk=1,Buk=1;\n\t\t\t\t\trori nowM,nowU;\n\t\t\t\t\tint h=0;\n\t\t\t\t\twhile(Ta+1<Te){\n\t\t\t\t\t\tif(Ta%2==0){nowM=tna(nowM,seg[Ta+1],h);}\n\t\t\t\t\t\tif(Te%2==1){nowU=tna(seg[Te-1],nowU,Auk,Buk);Auk*=zyA[h];Auk%=moA;Buk*=zyB[h];Buk%=moB;}\n\t\t\t\t\t\tTa>>=1;Te>>=1;h++;\n\t\t\t\t\t}\n\t\t\t\t\t//cerr<<\"M,U=\"<<nowM.hA<<\" \"<<nowU.hA<<\" \";\n\t\t\t\t\tTans=tna(nowM,nowU,Auk,Buk);\n\t\t\t\t\t//cerr<<Tans.hA<<endl;\n\t\t\t\t}\n\t\t\t\tif(Sans.hA==Tans.hA&&Sans.hB==Tans.hB){bmin=bgen;}else{bmax=bgen;}\n\t\t\t\t//cerr<<\"bmin=\"<<bmin<<endl;\n\t\t\t}\n\t\t\tchar kota;\n\t\t\tint aaa=262144+a+bmin,ccc=262144+c+bmin;\n\t\t\tfor(h=18;h>0;h--){int G=aaa>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=ccc>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\t//cerr<<seg[262144+a+bmin].ume<<endl;\n\t\t\tif(b-a+1==d-c+1&&d-c+1==bmin){kota='e';}\n\t\t\telse if(b-a+1>d-c+1&&d-c+1==bmin){kota='t';}\n\t\t\telse if(b-a+1<d-c+1&&b-a+1==bmin){kota='s';}\n\t\t\telse if(seg[262144+a+bmin].ume<seg[262144+c+bmin].ume){kota='s';}\n\t\t\telse{kota='t';}\n\t\t\tcout<<kota<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 15628, "score_of_the_acc": -0.2088, "final_rank": 3 }, { "submission_id": "aoj_0355_3239740", "code_snippet": "#include<deque>\n#include<queue>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<set>\n#include<cmath>\n#include<tuple>\n#include<string>\n//#include<chrono>\n#include<functional>\n#include<iterator>\n#include<random>\n#include<list>\n#include<unordered_set>\n#include<array>\n#include<map>\n#include<iomanip>\n#include<assert.h>\n#include<bitset>\n#include<stack>\nusing namespace std;\ntypedef long long int llint;\ntypedef long double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n/*\ncout<<setprecision(20);\ncin.tie(0);\nios::sync_with_stdio(false);\n*/\nconst llint moA=1e9+7;\nconst llint moB=1e9+9;\nconst llint big=2.19e15+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-15;\ntemplate <class T,class U>void mineq(T& a,U b){if(a>b){a=b;}}\ntemplate <class T,class U>void maxeq(T& a,U b){if(a<b){a=b;}}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\n//llint lcm(llint a,llint b){return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>llint LBI(vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>llint UBI(vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\n//segtree\n//hash値,埋めるの発生有無\n//長さは262144固定?\n//Qlog^2 n\nllint zyA[20],zyB[20];\nllint ruA[20],ruB[20];\nclass rori{public:\n\tllint hA,hB;\n\tchar ume;\n\trori(void){hA=0;hB=0;ume=0;}\n\trori(int inA,int inB,int dumy){hA=inA,hB=inB,ume=0;}\n\trori(int in,int naga){ume=in;hA=(in*ruA[naga])%moA,hB=(in*ruB[naga])%moB;}\n};\nrori tna(rori me,rori us,int an){return rori((me.hA*zyA[an]+us.hA)%moA,(me.hB*zyB[an]+us.hB)%moB,0);}\nrori tna(rori me,rori us,llint Ak,llint Bk){return rori((me.hA*Ak+us.hA)%moA,(me.hB*Bk+us.hB)%moB,0);}\n\nvoid bun(rori&per,rori&kox,rori&koy,int an){//anは子のを入れる\n\tif(per.ume){kox=rori(per.ume,an);koy=kox;per.ume=0;}\n}\nint main(void){\n\tllint n,h,i,j;cin>>n;\n\tzyA[0]=101,zyB[0]=101;\n\tfor(i=1;i<20;i++){zyA[i]=(zyA[i-1]*zyA[i-1])%moA;zyB[i]=(zyB[i-1]*zyB[i-1])%moB;}\n\tfor(i=0;i<20;i++){\n\t\tllint AA=1,BB=1;\n\t\truA[i]=0;ruB[i]=0;\n\t\tfor(j=0;j<(1<<i);j++){ruB[i]+=BB;ruB[i]%=moB;BB*=101;BB%=moB;ruA[i]+=AA;ruA[i]%=moA;AA*=101;AA%=moA;}\n\t}\n\tstring U;cin>>U;\n\tstatic rori seg[524288];\n\tfor(i=1;i<=n;i++){seg[i+262144]=rori(U[i-1],0);}\n\tfor(i=n+1;i<262144;i++){seg[i+262144]=rori(0,0);}\n\th=1;\n\tfor(i=262143;i>0;i--){\n\t\tseg[i]=tna(seg[i+i],seg[i+i+1],0);\n\t\tif((i&(-i))==i){h++;}\n\t}\n\tint Q;cin>>Q;\n\twhile(Q--){\n\t\tstring mei;cin>>mei;\n\t\tif(mei==\"set\"){\n\t\t\tint x,y;char z;cin>>x>>y>>z;\n\t\t\tx+=262143;y+=262145;int xx=x,yy=y;\n\t\t\tfor(h=18;h>0;h--){int G=x>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=y>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\th=0;\n\t\t\twhile(x+1<y){\n\t\t\t\tif(x%2==0){seg[x+1]=rori(z,h);}\n\t\t\t\tif(y%2==1){seg[y-1]=rori(z,h);}\n\t\t\t\tx>>=1;y>>=1;h++;\n\t\t\t}\n\t\t\tx=xx;y=yy;\n\t\t\th=0;\n\t\t\twhile(x>1){\n\t\t\t\tx>>=1;y>>=1;\n\t\t\t\tseg[x]=tna(seg[x<<1],seg[(x<<1)+1],h);\n\t\t\t\tseg[y]=tna(seg[y<<1],seg[(y<<1)+1],h);\n\t\t\t\th++;\n\t\t\t}\n\t\t}else{\n\t\t\tint a,b,c,d;cin>>a>>b>>c>>d;\n\t\t\tint bmin=0,bmax=min(b-a+1,d-c+1)+1;\n\t\t\t//普通に二分探索! セグ木上の二分探索テクは使用不可\n\t\t\t//最大何文字が一致しているか調べる\n\t\t\t//bmin文字一致している\n\t\t\tint Sa=a+262143,Ta=c+262143;\n\t\t\tfor(h=18;h>0;h--){int G=Sa>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=Ta>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\twhile(bmax-bmin>1){\n\t\t\t\t\n\t\t\t\tSa=a+262143;Ta=c+262143;\n\t\t\t\tint bgen=(bmin+bmax)>>1;\n\t\t\t\tint Se=a+bgen+262144,Te=c+bgen+262144;\n\t\t\t\tfor(h=18;h>0;h--){int G=Se>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=Te>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\t\trori Sans,Tans;\n\t\t\t\t{\n\t\t\t\t\tllint Auk=1,Buk=1;\n\t\t\t\t\trori nowM,nowU;\n\t\t\t\t\tint h=0;\n\t\t\t\t\twhile(Sa+1<Se){\n\t\t\t\t\t\tif(Sa%2==0){nowM=tna(nowM,seg[Sa+1],h);}\n\t\t\t\t\t\tif(Se%2==1){nowU=tna(seg[Se-1],nowU,Auk,Buk);Auk*=zyA[h];Auk%=moA;Buk*=zyB[h];Buk%=moB;}\n\t\t\t\t\t\tSa>>=1;Se>>=1;h++;\n\t\t\t\t\t}\n\t\t\t\t\t//cerr<<\"M,U=\"<<nowM.hA<<\" \"<<nowU.hA<<\" \";\n\t\t\t\t\tSans=tna(nowM,nowU,Auk,Buk);\n\t\t\t\t\t//cerr<<Sans.hA<<endl;\n\t\t\t\t}\n\t\t\t\t{\n\t\t\t\t\tllint Auk=1,Buk=1;\n\t\t\t\t\trori nowM,nowU;\n\t\t\t\t\tint h=0;\n\t\t\t\t\twhile(Ta+1<Te){\n\t\t\t\t\t\tif(Ta%2==0){nowM=tna(nowM,seg[Ta+1],h);}\n\t\t\t\t\t\tif(Te%2==1){nowU=tna(seg[Te-1],nowU,Auk,Buk);Auk*=zyA[h];Auk%=moA;Buk*=zyB[h];Buk%=moB;}\n\t\t\t\t\t\tTa>>=1;Te>>=1;h++;\n\t\t\t\t\t}\n\t\t\t\t\t//cerr<<\"M,U=\"<<nowM.hA<<\" \"<<nowU.hA<<\" \";\n\t\t\t\t\tTans=tna(nowM,nowU,Auk,Buk);\n\t\t\t\t\t//cerr<<Tans.hA<<endl;\n\t\t\t\t}\n\t\t\t\tif(Sans.hA==Tans.hA&&Sans.hB==Tans.hB){bmin=bgen;}else{bmax=bgen;}\n\t\t\t\t//cerr<<\"bmin=\"<<bmin<<endl;\n\t\t\t}\n\t\t\tchar kota;\n\t\t\tint aaa=262144+a+bmin,ccc=262144+c+bmin;\n\t\t\tfor(h=18;h>0;h--){int G=aaa>>h;bun(seg[G],seg[(G<<1)],seg[(G<<1)+1],h-1);int F=ccc>>h;bun(seg[F],seg[(F<<1)],seg[(F<<1)+1],h-1);}\n\t\t\t//cerr<<seg[262144+a+bmin].ume<<endl;\n\t\t\tif(b-a+1==d-c+1&&d-c+1==bmin){kota='e';}\n\t\t\telse if(b-a+1>d-c+1&&d-c+1==bmin){kota='t';}\n\t\t\telse if(b-a+1<d-c+1&&b-a+1==bmin){kota='s';}\n\t\t\telse if(seg[262144+a+bmin].ume<seg[262144+c+bmin].ume){kota='s';}\n\t\t\telse{kota='t';}\n\t\t\tcout<<kota<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.5555555555555556, "time_ms": 500, "memory_kb": 15652, "score_of_the_acc": -0.1143, "final_rank": 20 } ]
aoj_0370_cpp
Age Difference A trick of fate caused Hatsumi and Taku to come to know each other. To keep the encounter in memory, they decided to calculate the difference between their ages. But the difference in ages varies depending on the day it is calculated. While trying again and again, they came to notice that the difference of their ages will hit a maximum value even though the months move on forever. Given the birthdays for the two, make a program to report the maximum difference between their ages. The age increases by one at the moment the birthday begins. If the birthday coincides with the 29 th of February in a leap year, the age increases at the moment the 1 st of March arrives in non-leap years. Input The input is given in the following format. y_1 m_1 d_1 y_2 m_2 d_2 The first and second lines provide Hatsumi’s and Taku’s birthdays respectively in year y_i (1 ≤ y_i ≤ 3000), month m_i (1 ≤ m_i ≤ 12), and day d_i (1 ≤ d_i ≤ D max ) format. Where D max is given as follows: 28 when February in a non-leap year 29 when February in a leap-year 30 in April, June, September, and November 31 otherwise. It is a leap year if the year represented as a four-digit number is divisible by 4. Note, however, that it is a non-leap year if divisible by 100, and a leap year if divisible by 400. Output Output the maximum difference between their ages. Sample Input 1 1999 9 9 2001 11 3 Sample Output 1 3 In this example, the difference of ages between them in 2002 and subsequent years is 3 on the 1 st of October, but 2 on the 1 st of December. Sample Input 2 2008 2 29 2015 3 1 Sample Output 2 8 In this example, the difference of ages will become 8 on the 29 th of February in and later years than 2016.
[ { "submission_id": "aoj_0370_3737126", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\n#define int long long int\nconst int INF = 1001001001001001LL;\nconst int MOD = 1000000007;\n\nint di[] = {-1, 0, 1, 0, -1, 1, 1, -1};\nint dj[] = {0, 1, 0, -1, 1, 1, -1, -1};\n\nbool isuru(int y){\n if(y % 400 == 0) return true;\n else if(y % 100 == 0) return false;\n else if(y % 4 == 0) return true;\n else return false;\n}\n\nsigned main(){\n \n int y1, m1, d1; cin >> y1 >> m1 >> d1;\n int y2, m2, d2; cin >> y2 >> m2 >> d2;\n\n int cury = 1;\n int curm = 1;\n int curd = 1;\n int age1 = 0;\n int age2 = 0;\n\n bool isuru1 = false; \n bool isuru2 = false;\n if(m1 == 2 and d1 == 29 and isuru(y1)) isuru1 = true;\n if(m2 == 2 and d2 == 29 and isuru(y2)) isuru2 = true;\n\n\n int ans = 0;\n while(cury < 10000){\n if(cury >= y1 and curm == m1 and curd == d1) age1++;\n if(isuru1 and !isuru(cury) and cury >= y1 and curm == 3 and curd == 1) age1++;\n\n if(cury >= y2 and curm == m2 and curd == d2) age2++;\n if(isuru2 and !isuru(cury) and cury >= y2 and curm == 3 and curd == 1) age2++;\n \n //cerr << cury << \" \" << curm << \" \" << curd << \" \" << age1 << \" \" << age2 << endl; \n\n ans = max(ans, (int)abs(age1 - age2));\n \n curd++;\n if(!isuru(cury) and curm == 2 and curd == 29){\n curd = 1;\n curm++;\n }else if(isuru(cury) and curm == 2 and curd == 30){\n curd = 1;\n curm++;\n }else if((curm == 4 or curm == 6 or curm == 9 or curm == 11) and curd == 31){\n curd = 1;\n curm++;\n }else if(curd == 32){\n curd = 1;\n curm++;\n }\n\n if(curm == 13){\n curm = 1;\n cury++;\n }\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3104, "score_of_the_acc": -0.1964, "final_rank": 1 }, { "submission_id": "aoj_0370_2669734", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const int inf = (int)1e9;const double INF = 1e12, EPS = 1e-9;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\ttuple<int,int,int> a, b, now;\n\tint x, y, z;\n\tcin >> x >> y >> z; a = tie(x, y, z);\n\tcin >> x >> y >> z; b = tie(x, y, z);\n\tif(a > b) swap(a, b);\n\tif(a == b){\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tauto inc = [](tuple<int,int,int> &x){\n\t\tauto numd = [](int y, int m){\n\t\t\tconst int a[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\t\t\tif(m != 2) return a[m - 1];\n\t\t\tif(y % 400 == 0 || y % 4 == 0 && y % 100) return 29;\n\t\t\treturn 28;\n\t\t};\n\t\t\n\t\tint y, m, d; tie(y, m, d) = x;\n\t\tif(++d > numd(y, m)){\n\t\t\td = 1;\n\t\t\tif(++m > 12) m = 1, y++;\n\t\t}\n\t\tx = tie(y, m, d);\n\t};\n\tauto ok = [](tuple<int,int,int> b, tuple<int,int,int> a){\n\t\tif(get<1>(a) == get<1>(b) && get<2>(a) == get<2>(b)) return 1;\n\t\tif(get<1>(a) == 2 && get<2>(a) == 29 && \n\t\t\tget<1>(b) == 3 && get<2>(b) == 1 &&\n\t\t\t!(get<0>(b) % 400 == 0 || get<0>(b) % 4 == 0 && get<0>(b) % 100))\n\t\treturn 1;\n\t\treturn 0;\n\t};\n\t\n\tnow = a;\n\tint ya = 0, yb = 0, ans = 0;\n\twhile(now < b){\n\t\tinc(now);\n\t\tif(ok(now, a)) ya++;\n\t\tans = max(ans, ya - yb);\n\t}\n\t//dbg(get<0>(now),get<1>(now),get<2>(now));\n\trep(it, 365 * 4400){\n\t\tinc(now);\n\t\tif(ok(now, a)) ya++;\n\t\tif(ok(now, b)) yb++;\n\t\tans = max(ans, ya - yb);\n\t}\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3160, "score_of_the_acc": -1, "final_rank": 2 }, { "submission_id": "aoj_0370_2669728", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const int inf = (int)1e9;const double INF = 1e12, EPS = 1e-9;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\ttuple<int,int,int> a, b, now;\n\tint x, y, z;\n\tcin >> x >> y >> z; a = tie(x, y, z);\n\tcin >> x >> y >> z; b = tie(x, y, z);\n\tif(a > b) swap(a, b);\n\tif(a == b){\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tauto inc = [](tuple<int,int,int> &x){\n\t\tauto numd = [](int y, int m){\n\t\t\tconst int a[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};\n\t\t\tif(m != 2) return a[m - 1];\n\t\t\tif(y % 400 == 0 || y % 4 == 0 && y % 100) return 29;\n\t\t\treturn 28;\n\t\t};\n\t\t\n\t\tint y, m, d; tie(y, m, d) = x;\n\t\tif(++d > numd(y, m)){\n\t\t\td = 1;\n\t\t\tif(++m >= 12) m = 1, y++;\n\t\t}\n\t\tx = tie(y, m, d);\n\t};\n\tauto ok = [](tuple<int,int,int> b, tuple<int,int,int> a){\n\t\tif(get<1>(a) == get<1>(b) && get<2>(a) == get<2>(b)) return 1;\n\t\tif(get<1>(a) == 2 && get<2>(a) == 29 && \n\t\t\tget<1>(b) == 3 && get<2>(b) == 1 &&\n\t\t\t!(get<0>(b) % 400 == 0 || get<0>(b) % 4 == 0 && get<0>(b) % 100))\n\t\treturn 1;\n\t\treturn 0;\n\t};\n\t\n\tnow = a;\n\tint ya = 0, yb = 0, ans = 0;\n\twhile(now < b){\n\t\tinc(now);\n\t\tif(ok(now, a)) ya++;\n\t\tans = max(ans, ya - yb);\n\t}\n\t//dbg(get<0>(now),get<1>(now),get<2>(now));\n\trep(it, 365 * 4400){\n\t\tinc(now);\n\t\tif(ok(now, a)) ya++;\n\t\tif(ok(now, b)) yb++;\n\t\tans = max(ans, ya - yb);\n\t}\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 0.125, "time_ms": 10, "memory_kb": 3160, "score_of_the_acc": -1, "final_rank": 4 }, { "submission_id": "aoj_0370_2606471", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint days(int y,int m,int d){\n if(m<3)y--,m+=12;\n return 365*y+y/4-y/100+y/400+(153*m+8)/5+d;\n}\n\nvoid ymd(int day,int &y,int &m,int &d){\n int lo=-1,hi=100000,mid;\n while(lo+1<hi){\n mid=(lo+hi)/2;\n if(days(mid,12,31)<day)lo=mid;\n else hi=mid;\n }\n y=hi;\n for(m=1;m<12;m++)if(days(y,m+1,1)>day)break;\n d=day-days(y,m,0);\n}\n\nint main() {\n int y1,m1,d1,y2,m2,d2,a1=-1,a2=-1,ans=-1;\n cin >> y1 >> m1 >> d1 >> y2 >> m2 >> d2;\n int s=min(days(y1,m1,d1),days(y2,m2,d2));\n for(int i=s; i<=s+3500*366; i++) {\n int y,m,d;\n ymd(i,y,m,d);\n if(i>=days(y1,m1,d1)) {\n if(m==m1&&d==d1) a1++;\n else if(m1==2&&d1==29) {\n int yy,mm,dd;\n ymd(i-1,yy,mm,dd);\n if(mm==2&&dd==28) a1++;\n }\n }\n if(i>=days(y2,m2,d2)) {\n if(m==m2&&d==d2) a2++;\n else if(m2==2&&d2==29) {\n int yy,mm,dd;\n ymd(i-1,yy,mm,dd);\n if(mm==2&&dd==28) a2++;\n }\n }\n if(a1>=0&&a2>=0) ans=max(ans,abs(a1-a2));\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3096, "score_of_the_acc": -1, "final_rank": 2 } ]
aoj_0363_cpp
Loading Aizu Ocean Transport Company (AOTC) accepted a new shipping order. The pieces of the cargo included in this order all have the same square footprint (2m x 2m). The cargo room has a rectangular storage space of 4m width with various longitudinal extents. Each pieces of cargo must be placed in alignment with partition boundaries which form a 1m x 1m square grid. A straddling arrangement with a neighboring partition (for example, protrusion by 50 cm) is not allowed. Neither an angled layout nor stacked placement are allowed. Note also that there may be some partitions on which any cargo loading is prohibited. AOTC wishes to use the currently available ship for this consignment and needs to know how many pieces of cargo it can accommodate. Make a program to report the maximum cargo capacity of the cargo space given the following information: the depth (m) of the cargo space and the loading-inhibited partitions. Input The input is given in the following format. H N x_1 y_1 x_2 y_2 : x_N y_N The first line provides the longitudinal depth H (2 ≤ H ≤ 10 4 ) of the cargo space in meters and the number of load-inhibited partitions N (0 ≤ N ≤ 4 × 10 4 ). Each of the subsequent N lines defines the position of the i -th load-inhibited partition x_i (0 ≤ x_i ≤ 3) and y_i (0 ≤ y_i ≤ H -1) in integers, where x = 0 and y = 0 indicate the bottom-left corner partition. A load-inhibited partition appears only once in the list. Output Output the maximum number of cargo pieces loaded into the cargo space. Sample Input 1 5 3 0 1 1 2 3 3 Sample Output 1 2 Input example 1 corresponds to the cargo layout shown in the left-most figure. Sample Input 2 6 4 0 2 1 3 3 4 0 5 Sample Output 2 4
[ { "submission_id": "aoj_0363_10866776", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i=0;i<(ll)(N);i++)\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\nint main(){\n ll H,N;cin>>H>>N;\n vector<vector<int>>G(4,vector<int>(H,0));\n rep(i,N){\n int x,y;cin>>x>>y;\n G[x][y]=1;\n }\n vector<int>DP(16,-998244353);\n int vv = 0;\n rep(i,4){\n vv+=G[i][0]*(1<<i);\n }\n DP[vv]=0;\n for(int i = 1;i<H;i++){\n int v =0;\n rep(j,4){\n v+=G[j][i]*(1<<j);\n }\n vector<int>nDP(16,-998244353);\n rep(j,16){\n if(DP[j]<0)continue;\n nDP[v]=max(nDP[v],DP[j]);\n if((j&3)==0&&(v&3)==0){\n nDP[v+3]=max(nDP[v+3],DP[j]+1);\n }\n if((j&12)==0&&(v&12)==0){\n nDP[v+12]=max(nDP[v+12],DP[j]+1);\n }\n if((j&6)==0&&(v&6)==0){\n nDP[v+6]=max(nDP[v+6],DP[j]+1);\n }\n if(j==0&&v==0){\n nDP[15]=max(nDP[15],DP[j]+2);\n }\n }\n DP = nDP;\n }\n int ans = 0;\n rep(i,16)ans = max(ans,DP[i]);\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3580, "score_of_the_acc": -0.0039, "final_rank": 4 }, { "submission_id": "aoj_0363_10848931", "code_snippet": "#pragma GCC target (\"avx\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) (int)(a).size()\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all(b),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",qq123_+1)\n#define readv(a,n) a.resize(n,0);rep(i,(n)) a[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = (ll)15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll popcount(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n};\nclass mint {\npublic:ll v;\n mint(ll v = 0) { s(v % mod + mod); }\n constexpr static int mod = (ll)1e9 + 7;\n constexpr static int fn_ = (ll)2e6 + 5;\n static mint fact[fn_], comp[fn_];\n mint pow(int x) const {\n mint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline mint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline mint inv()const { return pow(mod - 2); }\n inline mint operator-()const { return mint() - *this; }\n inline mint& operator+=(const mint b) { return s(v + b.v); }\n inline mint& operator-=(const mint b) { return s(v + mod - b.v); }\n inline mint& operator*=(const mint b) { v = v * b.v % mod; return *this; }\n inline mint& operator/=(const mint b) { v = v * b.inv().v % mod; return *this; }\n inline mint operator+(const mint b) const { return mint(v) += b; }\n inline mint operator-(const mint b) const { return mint(v) -= b; }\n inline mint operator*(const mint b) const { return mint(v) *= b; }\n inline mint operator/(const mint b) const { return mint(v) /= b; }\n friend ostream& operator<<(ostream& os, const mint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, mint& m) {\n int x; is >> x; m = mint(x);\n return is;\n }\n bool operator<(const mint& r)const { return v < r.v; }\n bool operator>(const mint& r)const { return v > r.v; }\n bool operator<=(const mint& r)const { return v <= r.v; }\n bool operator>=(const mint& r)const { return v >= r.v; }\n bool operator==(const mint& r)const { return v == r.v; }\n bool operator!=(const mint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n mint comb(mint k) {\n if (k > * this) return mint();\n if (!fact[0]) combinit();\n if (v >= fn_) {\n if (k > * this - k) k = *this - k;\n mint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= mint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n mint perm(mint k) {\n if (k > * this) return mint();\n if (!fact[0]) combinit();\n if (v >= fn_) {\n mint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= mint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * mint(i);\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * mint(i + 1);\n }\n}; mint mint::fact[fn_], mint::comp[fn_];\n//--------------------------------------------------------------\n\n//---------------------------------------------------------------------\n\nbool a[20000][4];\nint h;\nint dp[20000][1 << 4];\nsigned main() {\n cin >> h;\n cdf(read()) {\n int x, y; cin >> x >> y;\n a[y][x] = 1;\n }\n int mx = 0;\n rep(i, h - 1)rep(j, 1 << 4) {\n chmax(dp[i + 1][0], dp[i][j]);\n if (!(j & 1) && !(j & 2) && !a[i][0] && !a[i][1] && !a[i + 1][0] && !a[i + 1][1]) {\n chmax(dp[i + 1][1 | 2], dp[i][j] + 1);\n }\n if (!(j & 2) && !(j & 4) && !a[i + 1][1] && !a[i + 1][2] && !a[i][1] && !a[i][2]) {\n chmax(dp[i + 1][2 | 4], dp[i][j] + 1);\n }\n if (!(j & 4) && !(j & 8) && !a[i + 1][2] && !a[i + 1][3] && !a[i][2] && !a[i][3]) {\n chmax(dp[i + 1][4 | 8], dp[i][j] + 1);\n }\n if (j == 0 && !a[i + 1][0] && !a[i + 1][1] && !a[i + 1][2] && !a[i + 1][3] && !a[i][0] && !a[i][1] && !a[i][2] && !a[i][3]) {\n chmax(dp[i + 1][1 | 2 | 4 | 8], dp[i][j] + 2);\n }\n rep(j, 1 << 4) chmax(mx, dp[i + 1][j]);\n }\n cout << mx << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 35424, "score_of_the_acc": -1, "final_rank": 19 }, { "submission_id": "aoj_0363_10732311", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nconstexpr int INF = (1 << 30) - 1;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int H, N;\n cin >> H >> N;\n // S[i][j] := おけない区画か\n vector S(H + 1, vector<int>(4));\n for (int i = 0; i < N; i++) {\n int x, y;\n cin >> y >> x;\n S[x][y] = true;\n }\n // 番兵\n for (int j = 0; j < 4; j++) S[H][j] = true;\n debug(S);\n\n // dp[i][v] := i, i + 1 行目の状況が v であるときの荷物の max\n vector dp(H, vector<int>(1 << 8, -INF));\n // 初期値\n dp[0][0] = 0;\n for (int i = 0; i < H - 1; i++) {\n for (int bit = 0; bit < (1 << 8); bit++) {\n // 置かない場合\n {\n int nbit = 0;\n // bit の 2 行目の状況を nbit の 1 行目にする\n for (int y = 0; y < 4; y++) {\n if (bit & (1 << (4 + y))) nbit |= (1 << y);\n }\n dp[i + 1][nbit] = max(dp[i + 1][nbit], dp[i][bit]);\n }\n // 1 個置く場合\n for (int j = 0; j < 3; j++) {\n // [i, i + 1] × [j, j + 1] に置けるか\n bool flag = true;\n for (int x = 0; x < 2; x++) {\n for (int y = j; y < j + 2; y++) {\n if (S[i + x][y] || (bit & (1 << (x * 4 + y)))) flag = false;\n }\n }\n if (flag) {\n int nbit = 0;\n // bit の 2 行目の状況を nbit の 1 行目にする\n for (int y = 0; y < 4; y++) {\n if (bit & (1 << (4 + y))) nbit |= (1 << y);\n }\n // 置く\n for (int y = j; y < j + 2; y++) nbit |= (1 << y);\n dp[i + 1][nbit] = max(dp[i + 1][nbit], dp[i][bit] + 1);\n }\n }\n // 2 個置く場合\n {\n // [i, i + 1] × [0, 4] に置けるか\n bool flag = true;\n for (int x = 0; x < 2; x++) {\n for (int y = 0; y < 4; y++) {\n if (S[i + x][y] || (bit & (1 << (x * 4 + y)))) flag = false;\n }\n }\n if (flag) {\n int nbit = 0;\n // bit の 2 行目の状況を nbit の 1 行目にする\n for (int y = 0; y < 4; y++) {\n if (bit & (1 << (4 + y))) nbit |= (1 << y);\n }\n // 置く\n for (int y = 0; y < 4; y++) nbit |= (1 << y);\n dp[i + 1][nbit] = max(dp[i + 1][nbit], dp[i][bit] + 2);\n }\n }\n }\n }\n\n int ans = *max_element(dp[H - 1].begin(), dp[H - 1].end());\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 14168, "score_of_the_acc": -1.3351, "final_rank": 20 }, { "submission_id": "aoj_0363_9573983", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint h,n,w = 4;\n\tcin >> h >> n;\n\tvector<vector<int>> a(h,vector<int>(w,false));\n\tfor(int i = 0;i < n;i++){\n\t\tint x,y;\n\t\tcin >> x >> y;\n\t\ta[y][x] = true;\n\t}\n\tvector<vector<int>> dp(h,vector<int>((1 << w),-INT_MAX));\n\t{\n\t\tint it = 0;\n\t\tfor(int i = 0;i < w;i++){\n\t\t\tif(a[0][i]){\n\t\t\t\tit |= (1 << i);\n\t\t\t}\n\t\t}\n\t\tdp[0][it] = 0;\n\t}\n\tfor(int i = 1;i < h;i++){\n\t\tint it = 0;\n\t\tfor(int j = 0;j < w;j++){\n\t\t\tif(a[i][j]){\n\t\t\t\tit |= (1 << j);\n\t\t\t}\n\t\t}\n\t\tfor(int j = 0;j < (1 << w);j++){\n\t\t\tif(dp[i - 1][j] == -INT_MAX) continue;\n\t\t\tdp[i][it] = max(dp[i][it],dp[i - 1][j]);\n\t\t\tfor(int k = 0;k < w - 1;k++){\n\t\t\t\tif((j & (1 << k)) == 0 && (j & (1 << (k + 1))) == 0 && !a[i][k] && !a[i][k + 1]){\n\t\t\t\t\tlong long t = it | (1 << k) | (1 << (k + 1));\n\t\t\t\t\tdp[i][t] = max(dp[i][t],dp[i - 1][j] + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j == 0 && it == 0){\n\t\t\t\tdp[i][(1 << w) - 1] = max(dp[i][(1 << w) - 1],dp[i - 1][0] + 2);\n\t\t\t}\n\t\t}\n\t}\n\tcout << *max_element(dp[h - 1].begin(),dp[h - 1].end()) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4668, "score_of_the_acc": -0.0379, "final_rank": 14 }, { "submission_id": "aoj_0363_9033466", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int H, N;\n cin >> H >> N;\n vector<int> block(H);\n for(int i = 0; i < N; i++) {\n int x, y;\n cin >> x >> y;\n block[y] |= 1<<x;\n }\n vector dp(H, vector<int>(16));\n vector<pair<int, int>> tr = {{15, 2}, {3, 1}, {6, 1}, {12, 1}, {0, 0}};\n for(int i = 0; i < H-1; i++) {\n for(int s = 0; s < 16; s++) {\n for(int t = 0; t < 16; t++) {\n for(auto [m, delta] : tr) {\n if((s&m) != 0 || (t&m) != 0) continue;\n if((block[i]&m) != 0 || (block[i+1]&m) != 0) continue;\n dp[i+1][t|m] = max(dp[i+1][t|m], dp[i][s]+delta);\n }\n }\n }\n }\n cout << *max_element(dp[H-1].begin(), dp[H-1].end()) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4252, "score_of_the_acc": -0.0249, "final_rank": 9 }, { "submission_id": "aoj_0363_8387565", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\tint H, N;\n\tcin >> H >> N;\n\tvector<int> bit(H);\n\tfor (int i = 0; i < N; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tbit[y] |= 1 << x;\n\t}\n\tconst int INF = 1012345678;\n\tvector<int> dp(16, -INF);\n\tdp[15] = 0;\n\tconst vector<int> z = { 0, 3, 6, 12, 15 };\n\tfor (int i = 0; i < H; i++) {\n\t\tvector<int> ndp(16, -INF);\n\t\tfor (int j = 0; j < 16; j++) {\n\t\t\tif (dp[j] != -INF) {\n\t\t\t\tint vacant = ~(j | bit[i]) & 15;\n\t\t\t\tfor (int k : z) {\n\t\t\t\t\tif ((vacant & k) == k) {\n\t\t\t\t\t\tndp[bit[i] | k] = max(ndp[bit[i] | k], dp[j] + (k == 0 ? 0 : k == 15 ? 2 : 1));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdp = ndp;\n\t}\n\tcout << *max_element(dp.begin(), dp.end()) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0363_8266654", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\tint H, N;\n\tcin >> H >> N;\n\tvector<vector<int>> S(H, vector<int>(4));\n\tfor (int i = 0; i < N; i++){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tS[y][x] = 1;\n\t}\n\tvector<vector<int>> dp(H, vector<int>(8, -1e9));\n\tdp[0][0] = 0;\n\tfor (int i = 0; i < H - 1; i++){\n\t\tfor (int j : {0, 1, 2, 4, 5}){\n\t\t\tfor (int k : {0, 1, 2, 4, 5}){\n\t\t\t\tfor (int l = 0; l < 3; l++){\n\t\t\t\t\tif ((j >> l) & 1){\n\t\t\t\t\t\tS[i][l]++;\n\t\t\t\t\t\tS[i][l + 1]++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tbool ok = true;\n\t\t\t\tfor (int l = 0; l < 3; l++){\n\t\t\t\t\tif ((k >> l) & 1){\n\t\t\t\t\t\tif (S[i][l] + S[i + 1][l] + S[i][l + 1] + S[i + 1][l + 1] > 0){\n\t\t\t\t\t\t\tok = false;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (ok){\n\t\t\t\t\tdp[i + 1][k] = max(dp[i + 1][k], dp[i][j] + __builtin_popcount(k));\n\t\t\t\t}\n\t\t\t\tfor (int l = 0; l < 3; l++){\n\t\t\t\t\tif ((j >> l) & 1){\n\t\t\t\t\t\tS[i][l]--;\n\t\t\t\t\t\tS[i][l + 1]--;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << *max_element(dp[H - 1].begin(), dp[H - 1].end()) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4452, "score_of_the_acc": -0.0312, "final_rank": 13 }, { "submission_id": "aoj_0363_8094426", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nint main() {\n ll h, n;\n cin >> h >> n;\n vector f(4, vector<bool>(h));\n for (int i = 0; i < n; i++) {\n int x, y;\n cin >> x >> y;\n f[x][y] = 1;\n }\n vector dp(h, vector<ll>(16));\n ll cnt = 0;\n for (int i = 1; i < h; i++) {\n ll blo = 0;\n vector<bool> ok(4);\n for (int j = 0; j < 4; j++)\n if (f[j][i])\n blo += (1 << j);\n else\n ok[j] = 1;\n for (int j = 0; j < 16; j++) dp[i][blo] = max(dp[i][blo], dp[i - 1][j]);\n for (int j = 0; j < 3; j++) {\n if (ok[j] && ok[j + 1]) {\n if (!f[j][i - 1] && !f[j + 1][i - 1]) {\n ll ma = 0;\n for (int k = 0; k < 16; k++) {\n if (k & (1 << j)) continue;\n if (k & (1 << (j + 1))) continue;\n ma = max(ma, dp[i - 1][k]);\n }\n dp[i][blo + (1 << j) + (1 << (j + 1))] = ma + 1;\n }\n }\n }\n if (blo == 0) {\n if (!f[0][i - 1] && !f[1][i - 1] && !f[2][i - 1] && !f[3][i - 1]) {\n dp[i][15] = dp[i - 1][0] + 2;\n }\n }\n }\n // for (int i = 0; i < h; i++) {\n // for (int j = 0; j < 16; j++) cout << dp[i][j] << \" \";\n // cout << endl;\n // }\n ll res = 0;\n for (int i = 0; i < 16; i++) res = max(res, dp[h - 1][i]);\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4784, "score_of_the_acc": -0.0415, "final_rank": 15 }, { "submission_id": "aoj_0363_7611214", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define chmax(a,b) a = max(a,b)\nint main(){\n int h,n;\n cin>>h>>n;\n vector<vector<int> >e(h);\n for(int i = 0;i<n;i++){\n int x,y;\n cin>>x>>y;\n e[h-1-y].push_back(x);\n }\n vector<vector<int> >dp(1<<4,vector<int>(h+1,0));\n int now = 0;\n for(int i = 0;i<h;i++){\n //cout<<now<<endl;\n int mask = 0;\n for(auto j:e[i]) mask |= 1 << j;\n //cout<<mask<<endl;\n for(int j = 0;j<1<<4;j++){\n if(mask&j) dp[j][i] = 0;\n }\n for(int j = 0;j<1<<4;j++){\n if(mask&j) continue;\n chmax(dp[j|mask][i],dp[j][i]);\n if(mask!=0) dp[j][i] = 0;\n }\n chmax(dp[mask][i],now);\n //cout<<now<<\" \"<<i<<\" \"<<mask<<endl;\n if(i==h-1) break;\n for(int j = 0;j<1<<4;j++){\n chmax(now,dp[j][i]);\n if(~j&mask) continue;\n for(int k = 0;k<3;k++){\n if((~j>>k&1)&&(((~j)>>(k+1))&1)){\n chmax(dp[(1<<k)|(1<<(k+1))][i+1],dp[j][i]+1);\n }\n }\n }\n if(mask==0) chmax(dp[15][i+1],dp[0][i]+2);\n }\n int ans = 0;\n for(int i = 0;i<1<<4;i++) ans = max(ans,dp[i][h-1]);\n\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4428, "score_of_the_acc": -0.0304, "final_rank": 12 }, { "submission_id": "aoj_0363_6901466", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\nusing namespace std;\nusing ll = long long;\n\nll ll_gcd(ll a, ll b) {\n\tif (a < b) return ll_gcd(b, a);\n\tll r;\n\twhile ((r = a % b)) {\n\t\ta = b;\n\t\tb = r;\n\t}\n\treturn b;\n}\n\nbool x(vector<ll>& z) {\n\tll now = 0;\n\tfor (int i = 0; i < z.size(); i++) {\n\t\tif (now < i * 10)return false;\n\t\tnow = max(now, i * 10 + z[i]);\n\t}\n\treturn true;\n}\n\nint main(){\n\tll h, n;\n\tcin >> n >> h;\n\tvector<int> z(n);\n\tfor (int i = 0; i < h; i++) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tz[b] |= (1 << a);\n\t}\n\tvector<vector<int>> dp(n, vector<int>(16,-10000000));\n\tdp[0][z[0]] = 0;\n\tfor (int i = 0; i < n-1; i++) {\n\t\tfor (int j = 0; j < 16; j++) {\n\t\t\tdp[i + 1][z[i + 1]] = max(dp[i + 1][z[i + 1]], dp[i][j]);\n\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\tif ((!(j & (1 << k))) && (!(j & (1 << (k + 1)))) && (!(z[i + 1] & (1 << k))) && (!(z[i + 1] & (1 << (k + 1)))))dp[i + 1][z[i + 1] + 3 * (1 << k)] = max(dp[i + 1][z[i + 1] + 3 * (1 << k)], dp[i][j] + 1);\n\t\t\t\tif (j == 0 && z[i + 1] == 0)dp[i + 1][15] = max(dp[i + 1][15], dp[i][j] + 2);\n\t\t\t}\n\t\t}\n\t}\n\t\tint ans = 0;\n\t\tfor (int i = 0; i < 16; i++) {\n\t\t\tans = max(ans, dp[n - 1][i]);\n\t\t}\n\t\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4244, "score_of_the_acc": -0.0246, "final_rank": 8 }, { "submission_id": "aoj_0363_5948182", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 100000;\nint main(){\n int H, N;\n cin >> H >> N;\n vector<int> x(N), y(N);\n for (int i = 0; i < N; i++){\n cin >> x[i] >> y[i];\n }\n vector<int> S(H, 0);\n for (int i = 0; i < N; i++){\n S[y[i]] |= 1 << x[i];\n }\n vector<vector<int>> dp(H + 1, vector<int>(16, -INF));\n dp[0][15] = 0;\n for (int i = 0; i < H; i++){\n for (int j = 0; j < 16; j++){\n dp[i + 1][S[i]] = max(dp[i + 1][S[i]], dp[i][j]);\n if ((j & 3) == 0 && (S[i] & 3) == 0){\n int x = S[i] | 3;\n dp[i + 1][x] = max(dp[i + 1][x], dp[i][j] + 1);\n }\n if ((j & 6) == 0 && (S[i] & 6) == 0){\n int x = S[i] | 6;\n dp[i + 1][x] = max(dp[i + 1][x], dp[i][j] + 1);\n }\n if ((j & 12) == 0 && (S[i] & 12) == 0){\n int x = S[i] | 12;\n dp[i + 1][x] = max(dp[i + 1][x], dp[i][j] + 1);\n }\n if ((j & 15) == 0 && (S[i] & 15) == 0){\n int x = S[i] | 15;\n dp[i + 1][x] = max(dp[i + 1][x], dp[i][j] + 2);\n }\n }\n }\n int ans = 0;\n for (int i = 0; i < 16; i++){\n ans = max(ans, dp[H][i]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4408, "score_of_the_acc": -0.0298, "final_rank": 11 }, { "submission_id": "aoj_0363_5867589", "code_snippet": "#ifndef ONLINE_JUDGE\n#define _GLIBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\n#define rep2(i,s,n) for (int i = s; i < (int)(n); i++)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nll max(ll x,ll y){\nif(x>y)return x;\nelse return y;\n}\nll min(ll x,ll y){\nif(x<y)return x;\nelse return y;\n}\n\nconst vector<int> ne={0,3,3<<1,3<<2,15};\n\n\nint main(){\n int h,n;\n cin >> h >> n;\n vector<int> cant(h);\n rep(i,n){\n int a,b;\n cin >> a >> b;\n cant[b]|=1<<a;\n }\n vector<vector<int>> dp(h,vector<int>(1<<4));\n\n rep(i,h-1)rep(S,1<<4){\n for(int T:ne){\n if(S&T)continue;\n if(T&cant[i])continue;\n if(T&cant[i+1])continue;\n dp[i+1][T|cant[i+1]]=max(dp[i+1][T|cant[i+1]],dp[i][S]+(T==15 ? 2:(T==0 ? 0:1)));\n }\n }\n int ans=0;\n for(int res:dp.back())ans=max(ans,res);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4424, "score_of_the_acc": -0.2803, "final_rank": 17 }, { "submission_id": "aoj_0363_5859408", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define all(a) a.begin(), a.end()\nusing namespace std;\nusing ll = long long;\ntemplate<typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; }\n\nint main() {\n int h, n; cin >> h >> n;\n int board[10010][4];\n rep(i, h) rep(j, 4) board[i][j] = 0;\n rep(i, n) { \n int x, y; cin >> x >> y;\n board[y][x] = 1;\n }\n int dp[h-1+10][5];\n rep(i, h-1) rep(j, 5) dp[i][j] = 0;\n int l = board[0][0]+board[0][1]+board[1][0]+board[1][1];\n int c = board[0][1]+board[0][2]+board[1][1]+board[1][2];\n int r = board[0][2]+board[0][3]+board[1][2]+board[1][3];\n if (l == 0) dp[0][0] = 1;\n if (c == 0) dp[0][1] = 1;\n if (r == 0) dp[0][2] = 1;\n if (l+r == 0) dp[0][3] = 2;\n \n rep(i, h-1) {\n int l = board[i+1][0]+board[i+1][1]+board[i+2][0]+board[i+2][1];\n int c = board[i+1][1]+board[i+1][2]+board[i+2][1]+board[i+2][2];\n int r = board[i+1][2]+board[i+1][3]+board[i+2][2]+board[i+2][3];\n if (c == 0) chmax(dp[i+1][1], dp[i][4]+1);\n if (l == 0) {\n chmax(dp[i+1][0], dp[i][4]+1);\n chmax(dp[i+1][0], dp[i][2]+1);\n }\n if (r == 0) {\n chmax(dp[i+1][2], dp[i][4]+1);\n chmax(dp[i+1][2], dp[i][0]+1);\n }\n if (l+r == 0) {\n chmax(dp[i+1][3], dp[i][4]+2);\n }\n chmax(dp[i+1][4], dp[i][0]);\n chmax(dp[i+1][4], dp[i][1]);\n chmax(dp[i+1][4], dp[i][2]);\n chmax(dp[i+1][4], dp[i][3]);\n chmax(dp[i+1][4], dp[i][4]);\n }\n int ans = 0;\n rep(i, 5) chmax(ans, dp[h-2][i]);\n cout << ans << endl;\n /*\n rep(i, h-1) {\n rep(j, 5) {\n cout << dp[i][j] << \" \";\n }\n cout << endl;\n }\n */\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3484, "score_of_the_acc": -0.0009, "final_rank": 3 }, { "submission_id": "aoj_0363_5846227", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n int H,N;\n cin >> H >> N;\n long long int INF = 1000000000000000000;\n vector<vector<long long int> > dp(H,vector<long long int>(16,-INF));\n vector<vector<bool> > vec(H,vector<bool>(4,true));\n for(int i=0;i<N;i++){\n int x,y;\n cin >> x >> y;\n vec[y][x] = false;\n }\n int a = 0;\n for(int i=0;i<4;i++) if(!vec[0][i]) a += (1<<i);\n dp[0][a] = 0;\n for(int i=1;i<H;i++){\n int b = 0;\n for(int j=0;j<4;j++) if(!vec[i][j]) b += (1<<j);\n long long int M = 0;\n for(int j=0;j<16;j++) M = max(M,dp[i-1][j]);\n dp[i][b] = M;\n for(int j=0;j<16;j++){\n bool flag = true;\n for(int k=0;k<4;k++) if(!vec[i][k]) if(!(j & (1<<k))) flag = false;\n if(!flag) continue;\n int t = j;\n for(int k=0;k<4;k++) if(!vec[i][k]) t -= (1<<k);\n if(t == 12) for(int k=0;k<16;k++) if((!(k & (1<<3))) && (!(k & (1<<2)))) dp[i][j] = max(dp[i][j],dp[i-1][k]+1);\n if(t == 6) for(int k=0;k<16;k++) if((!(k & (1<<2))) && (!(k & (1<<1)))) dp[i][j] = max(dp[i][j],dp[i-1][k]+1);\n if(t == 3) for(int k=0;k<16;k++) if((!(k & (1<<1))) && (!(k & (1<<0)))) dp[i][j] = max(dp[i][j],dp[i-1][k]+1);\n if(t == 15) dp[i][j] = max(dp[i][j],dp[i-1][0]+2);\n }\n }\n long long int ans = -INF;\n for(int i=0;i<16;i++) ans = max(ans,dp[H-1][i]);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5268, "score_of_the_acc": -0.0567, "final_rank": 16 }, { "submission_id": "aoj_0363_5837855", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<climits>\n#include<iomanip>\n#include<cctype>\n#include<sstream>\n#include<regex>\n#include<bitset>\n#include<random>\n#include<complex>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nint dp[2][32];\nbool mp[4][10000];\nsigned main(){\n\tint h,n,x,y;\n\tcin>>h>>n;\n\twhile(cin>>x>>y)\n\t\tmp[x][y]=1;\n\tint*tmp=dp[0],*nxt=dp[1];\n\tfor(int i=0;i<31;i++)\n\t\ttmp[i]=-inf;\n\tfor(int i=0;i<4*h;i++){\n\t\tfor(int j=0;j<32;j++)\n\t\t\tnxt[j]=-inf;\n\t\tfor(int j=0;j<32;j++){\n\t\t\tnxt[j<<1&31|mp[i%4][i/4]]=max(nxt[j<<1&31|mp[i%4][i/4]],tmp[j]);\n\t\t\tif(!mp[i%4][i/4]&&i%4!=0&&(j&25)==0)\n\t\t\t\tnxt[j<<1&31|19]=max(nxt[j<<1&31|19],tmp[j]+1);\n\t\t}\n\t\tswap(tmp,nxt);\n\t}\n\tint ans=0;\n\tfor(int i=0;i<32;i++)\n\t\tans=max(ans,tmp[i]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0001, "final_rank": 2 }, { "submission_id": "aoj_0363_5738525", "code_snippet": "#include<iostream>\n#include<stdio.h>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<string>\n#include<map>\n#include<string.h>\n#include<complex>\n#include<math.h>\n#include<queue>\n#include <functional>\n#include<time.h>\n#include<iomanip>\n#include<cassert>\n#include<bitset>\n#include<sstream>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nclass UnionFind {\npublic:\n\t//親の番号を格納する。親だった場合は-(その集合のサイズ)\n\tvector<int> Parent;\n\n\t//作るときはParentの値を全て-1にする\n\t//こうすると全てバラバラになる\n\tUnionFind(int N) {\n\t\tParent = vector<int>(N, -1);\n\t}\n\n\t//Aがどのグループに属しているか調べる\n\tint root(int A) {\n\t\tif (Parent[A] < 0) return A;\n\t\treturn Parent[A] = root(Parent[A]);\n\t}\n\n\t//自分のいるグループの頂点数を調べる\n\tint size(int A) {\n\t\treturn -Parent[root(A)];//親をとってきたい\n\t}\n\n\t//AとBをくっ付ける\n\tbool connect(int A, int B) {\n\t\t//AとBを直接つなぐのではなく、root(A)にroot(B)をくっつける\n\t\tA = root(A);\n\t\tB = root(B);\n\t\tif (A == B) {\n\t\t\t//すでにくっついてるからくっ付けない\n\t\t\treturn false;\n\t\t}\n\n\t\t//大きい方(A)に小さいほう(B)をくっ付けたい\n\t\t//大小が逆だったらひっくり返しちゃう。\n\t\tif (size(A) < size(B)) swap(A, B);\n\n\t\t//Aのサイズを更新する\n\t\tParent[A] += Parent[B];\n\t\t//Bの親をAに変更する\n\t\tParent[B] = A;\n\n\t\treturn true;\n\t}\n};\n\n//セグ木・0-indexed・非再帰・(大きさ・単位元・関数)で初期化\ntemplate<typename T>\nstruct SegTree {\n\t//比較関数の型\n\tusing F = function<T(T, T)>;\n\t//二分木を配列で表したもの\n\tvector<T>seg;\n\t//木の半分の大きさ\n\tint siz;\n\t//単位元\n\tconst T unit;\n\t//比較する関数\n\tconst F f;\n\n\t//大きさn、unit(単位元)、f(モノイド)でsegtreeを初期化する\n\tSegTree(int n, const T unit, const F f) : unit(unit), f(f) {\n\t\tsiz = 1;\n\t\twhile (siz < n)siz <<= 1;\n\t\tseg.assign(siz * 2 - 1, unit);\n\t\tsiz--;\n\t}\n\n\t//k番目にtを入力\n\tvoid set(int k, const T& t) {\n\t\tseg[k + siz] = t;\n\t}\n\n\t//fによって木を構築する\n\tvoid build() {\n\t\tfor (int i = siz - 1; 0 <= i; i--) {\n\t\t\tseg[i] = f(seg[i * 2 + 1], seg[i * 2 + 2]);\n\t\t}\n\t}\n\n\tT operator[](const int i) {\n\t\treturn seg[i + siz];\n\t}\n\n\t//k番目をxに更新する\n\tvoid update(int k, T x) {\n\t\tk += siz;\n\t\tseg[k] = x;\n\t\twhile (0 < k) {\n\t\t\tk = (k - 1) >> 1;\n\t\t\tseg[k] = f(seg[k * 2 + 1], seg[k * 2 + 2]);\n\t\t}\n\t}\n\n\t//[a,b)について、fした結果を返す\n\t//半開区域のためa以上b未満の位置を指す\n\tT query(int a, int b) {\n\t\tT l = unit, r = unit;\n\t\tfor (a += siz, b += siz; a < b; a >>= 1, b >>= 1) {\n\t\t\tif (!(a & 1))l = f(l, seg[a++]);\n\t\t\tif (!(b & 1))r = f(seg[--b], r);\n\t\t}\n\t\treturn f(l, r);\n\t}\n};\n\n//aとbの最大公約数を求めるよ\nlong long GCD(long long a, long long b) {\n\tif (b == 0) return a;\n\telse return GCD(b, a % b);\n}\n\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\nlong long extGCD(long long a, long long b, long long& x, long long& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tlong long d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\n\n// mod. m での a の逆元 a^{-1} を計算する\nlong long modinv(long long a, long long m) {\n\tlong long b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\n\n//nCrをmで割った余りを求める\nllint nCr(llint n, llint r, llint m) {\n\tllint ans = 1;\n\tfor (llint i = 0; i < r; i++) {\n\t\tans *= n - i;\n\t\tans %= m;\n\t}\n\tfor (llint i = 1; i <= r; i++) {\n\t\tans *= modinv(i, m);\n\t\tans %= m;\n\t}\n\treturn ans;\n}\n\n//aのb乗をmで割った余りを求める\nllint power(llint a, llint b, llint m) {\n\tif (b == 1)return a;\n\tif (b == 0)return 1;\n\tllint tmp = power(a, (llint)b / 2, m);\n\ttmp *= tmp;\n\ttmp %= m;\n\tif (b % 2 == 1) {\n\t\ttmp *= a;\n\t\ttmp %= m;\n\t}\n\treturn tmp;\n}\n\n//bitを表すsub,要素数を表すlength\nbool next_combination(llint& sub, int length) {\n\tllint x = sub & -sub, y = sub + x;\n\tsub = (((sub & ~y) / x) >> 1) | y;\n\treturn sub < (llint)(1 << (llint)length);\n}\n\nvoid Zalgorithm(string& s, vint& a) {\n\ta[0] = s.size();\n\tint i = 1, j = 0;\n\twhile (i < s.size()) {\n\t\twhile (i + j < s.size() && s[j] == s[i + j])j++;\n\t\ta[i] = j;\n\t\tif (j == 0) { i++; continue; }\n\t\tint k = 1;\n\t\twhile (i + k < s.size() && a[k] + k < j) {\n\t\t\ta[i + k] += a[k]; k++;\n\t\t}\n\t\ti += k; j -= k;\n\t}\n\treturn;\n}\n\nint main() {\n\tint h, n;\n\tcin >> h >> n;\n\tvint isOK(h, 15);\n\trep(i, n) {\n\t\tint x, y;\n\t\tcin >> y >> x;\n\t\tisOK[x] -= 1 << y;\n\t}\n\tvvint dp(h, vint(16, 0));\n\trep(i, h) {\n\t\tif (i == 0) {\n\t\t\trep(j, 1 << 4)dp[i][j] = -Inf;\n\t\t\tdp[i][isOK[i]] = 0;\n\t\t}\n\t\telse {\n\t\t\trep(j, 1 << 4) {\n\t\t\t\tbool tmp = false;\n\t\t\t\trep(k, 4)if (j & (1 << k) && !(isOK[i] & (1 << k)))tmp = true;\n\t\t\t\tif (tmp)dp[i][j] = -Inf;\n\t\t\t}\n\t\t\tint tmp = 0;\n\t\t\trep(j, 1 << 4)tmp = max(tmp, dp[i - 1][j]);\n\t\t\tdp[i][isOK[i]] = tmp;\n\t\t\tif ((isOK[i] & 12) == 12) {\n\t\t\t\trep(j, 1 << 4) {\n\t\t\t\t\tif ((j & 12) == 12) {\n\t\t\t\t\t\tdp[i][isOK[i] & (15 - 12)] = max(dp[i][isOK[i] & (15 - 12)], dp[i - 1][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif ((isOK[i] & 6) == 6) {\n\t\t\t\trep(j, 1 << 4) {\n\t\t\t\t\tif ((j & 6) == 6) {\n\t\t\t\t\t\tdp[i][isOK[i] & (15 - 6)] = max(dp[i][isOK[i] & 15 - 6], dp[i - 1][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif ((isOK[i] & 3) == 3) {\n\t\t\t\trep(j, 1 << 4) {\n\t\t\t\t\tif ((j & 3) == 3) {\n\t\t\t\t\t\tdp[i][isOK[i] & (15 - 3)] = max(dp[i][isOK[i] & (15 - 3)], dp[i - 1][j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif ((isOK[i] & 15) == 15) {\n\t\t\t\trep(j, 1 << 4) {\n\t\t\t\t\tif ((j & 15) == 15) {\n\t\t\t\t\t\tdp[i][0] = max(dp[i][0], dp[i - 1][j] + 2);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\trep(i, 1 << 4)ans = max(ans, dp[h - 1][i]);\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4264, "score_of_the_acc": -0.0253, "final_rank": 10 }, { "submission_id": "aoj_0363_5732736", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < int(n); i++)\n#define repp(i,n,m) for (int i = m; i < int(n); i++)\nusing namespace std;\nint main(){\n int h, n; cin >> h >> n;\n vector<vector<int>> ar(h,vector<int>(4,0));\n rep(i,n){\n int x, y; cin >> x >> y;\n ar[y][x] += 2;\n }\n vector<int> dp(h+1,0);\n vector<int> jun = {0,2,1};\n vector<vector<int>> best = ar;\n rep(i,h-1){\n int pl = 0;\n int pr = 0;\n rep(d,3){\n int c = jun[d];\n int cnt = 0;\n rep(y,2) cnt += best[i][c+y];\n rep(y,2) cnt += best[i+1][c+y];\n if (cnt == 0){\n rep(y,2) best[i+1][c+y]++;\n pr++;\n }\n }\n vector<int> vest = ar[i+1];\n rep(d,3){\n int c = jun[d];\n int cnt = 0;\n rep(y,2) cnt += ar[i][c+y];\n rep(y,2) cnt += vest[c+y];\n if (cnt == 0){\n rep(y,2) vest[c+y]++;\n pl++;\n }\n }\n if (dp[i+1] + pr >= dp[i] + pl){\n dp[i+2] = dp[i+1] + pr;\n }\n else {\n dp[i+2] = dp[i] + pl;\n best[i+1] = vest;\n }\n }\n cout << dp[h] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4172, "score_of_the_acc": -0.0224, "final_rank": 7 }, { "submission_id": "aoj_0363_5708853", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvoid chmax(int &a,int b){\n a=max(a,b);\n}\nint main(){\n int H,N;\n cin>>H>>N;\n vector<array<int,16>>dp(H);\n vector<int>A(H);\n for(int i=0,a,b;i<N;i++){\n cin>>a>>b;\n A[b]|=1<<a;\n }\n if((A[0]&0b0011)==0&&(A[1]&0b0011)==0)dp[1][A[1]|0b0011]=1;\n if((A[0]&0b0110)==0&&(A[1]&0b0110)==0)dp[1][A[1]|0b0110]=1;\n if((A[0]&0b1100)==0&&(A[1]&0b1100)==0)dp[1][A[1]|0b1100]=1;\n if((A[0]&0b1111)==0&&(A[1]&0b1111)==0)dp[1][A[1]|0b1111]=2;\n for(int i=2;i<H;i++){\n int t=0;\n for(int j=0;j<16;j++)t=max(dp[i-1][j],t);\n dp[i][A[i]]=t;\n for(int j=0;j<16;j++){\n if(((j^A[i-1])&A[i-1])!=0)continue;\n if((j&0b0011)==0&&(A[i]&0b0011)==0)chmax(dp[i][A[i]|0b0011],1+dp[i-1][j]);\n if((j&0b0110)==0&&(A[i]&0b0110)==0)chmax(dp[i][A[i]|0b0110],1+dp[i-1][j]);\n if((j&0b1100)==0&&(A[i]&0b1100)==0)chmax(dp[i][A[i]|0b1100],1+dp[i-1][j]);\n if((j&0b1111)==0&&(A[i]&0b1111)==0)chmax(dp[i][A[i]|0b1111],2+dp[i-1][j]);\n }\n }\n int ans=0;\n for(int i=0;i<16;i++)chmax(ans,dp[H-2][i]),chmax(ans,dp[H-1][i]);\n cout<<ans<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3908, "score_of_the_acc": -0.0141, "final_rank": 6 }, { "submission_id": "aoj_0363_4996166", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nvoid chmax(int&a,int b){if(a<b)a=b;}\nint H,N;\nint B[10101];\nint dp[10101][1<<8];\nmain()\n{\n\tcin>>H>>N;\n\tfor(int i=0;i<H;i++)for(int j=0;j<1<<8;j++)dp[i][j]=-1e9;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint x,y;cin>>x>>y;\n\t\tB[y]|=1<<x;\n\t}\n\tdp[0][B[1]<<4|B[0]]=0;\n\tfor(int i=0;i<H-1;i++)for(int j=0;j<1<<8;j++)if(dp[i][j]>=0)\n\t{\n\t\tchmax(dp[i+1][B[i+2]<<4|j>>4],dp[i][j]);\n\t\tif(!j)chmax(dp[i+1][B[i+2]<<4|15],dp[i][j]+2);\n\t\tif(!(j&0b110011))chmax(dp[i+1][B[i+2]<<4|j>>4|3],dp[i][j]+1);\n\t\tif(!(j&0b1100110))chmax(dp[i+1][B[i+2]<<4|j>>4|6],dp[i][j]+1);\n\t\tif(!(j&0b11001100))chmax(dp[i+1][B[i+2]<<4|j>>4|12],dp[i][j]+1);\n\t}\n\tint ans=0;\n\tfor(int j=0;j<1<<8;j++)chmax(ans,dp[H-1][j]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 13152, "score_of_the_acc": -0.3033, "final_rank": 18 }, { "submission_id": "aoj_0363_4918873", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nint main()\n{\n\tint H, N;\n\tcin >> H >> N;\n\tint* map = new int[H];\n for (int i = 0; i < H; i++)\n\t\tmap[i] = 0;\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tmap[y] += 1 << x;\n\t}\n\tint dp[10000][1 << 4];\n\tfor (int i = 0; i < H; i++)\n\t\tfor (int j = 0; j < 1 << 4; j++)\n\t\t\tdp[i][j] = -1;\n\tint put[4] = { 3,6,12,15 };\n\tdp[0][map[0]] = 0;\n\tfor (int i = 1; i < H; i++)\n\t{\n\t\tfor (int j = 0; j < 4; j++)\n\t\t{\n\t\t\tfor (int k = 0; k < 1 << 4; k++)\n\t\t\t{\n\t\t\t\tif (dp[i - 1][k] < 0) continue;\n\t\t\t\tif (put[j] & k || put[j] & map[i])\n\t\t\t\t\tdp[i][map[i]] = max(dp[i][map[i]], dp[i - 1][k]);\n\t\t\t\telse\n\t\t\t\t\tdp[i][map[i] | put[j]] = \n\t\t\t\t\tmax(dp[i][map[i] | put[j]], dp[i - 1][k] + (j == 3 ? 2 : 1));\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 0; i < 1 << 4; i++)\n\t\tans = max(ans, dp[H - 1][i]);\n\tcout << ans << endl;\n\t//cin >> H;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3792, "score_of_the_acc": -0.0105, "final_rank": 5 } ]
aoj_0366_cpp
Road Improvement Aizu is a country famous for its rich tourism resources and has N cities, each of which is uniquely identified with a number (0 to N -1). It has a road network consisting of M one-way roads connecting a city to another. All the roads connecting the cities in Aizu have a row of cherry trees along their routes. For enhancing the cherry-viewing experience, a proposal was made to modify the road network so that a tourist can travel around all the roads. To achieve this target, it was decided to construct several one-way roads, each connecting two cities and abiding by the following rules. The newly constructed road is for one-way traffic Starting from any city, a tourist is able to make a roundtrip and return to the city, whereby he/she drives all the roads exhaustively, including the newly constructed ones. Multiple passages of some of the roads are allowed. You, as a tourism promotion officer, are assigned with the task of writing a program for the road construction project. Write a program to determine the minimum number of roads to be constructed given the road network information in Aizu. Input The input is given in the following format. N M s_1 t_1 s_2 t_2 : s_M t_M The first line provides the number of cities N (1 ≤ N ≤ 10 4 ) and roads M (0 ≤ M ≤ 10 5 ). Each of the subsequent M lines provides the numbers assigned to start and destination cities for the i -th road: s_i , t_i (0 ≤ s_i , t_i ≤ N -1) , where s_i ≠ t_i . (no duplicate appearance of a road) Output Output the minimum number of roads to be newly constructed. Sample Input 1 6 7 0 2 2 1 1 0 2 3 4 3 4 5 5 4 Sample Output 1 2 Sample Input 2 6 9 0 2 2 1 1 0 2 3 4 3 4 5 5 4 5 2 3 4 Sample Output 2 0
[ { "submission_id": "aoj_0366_10873655", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\nstruct SCC {\n vector<vector<int>> g,rg;\n vector<int> comp, ord, used;\n int num;\n\n SCC(vector<vector<int>> g) : g(g), rg(si(g)), comp(si(g), -1), ord(si(g)), used(si(g)) {\n rep(i, si(g)) for(auto&& e: g[i]) rg[e].emplace_back(i);\n build();\n };\n int operator[](int k) { return comp[k]; }\n void dfs(int x) {\n if (used[x]) return;\n used[x] = true;\n for(auto&& e : g[x]) if (!used[e]) dfs(e);\n ord.emplace_back(x);\n }\n void rdfs(int x, int cnt) {\n if (comp[x] != -1) return;\n comp[x] = cnt;\n for(auto&& e: rg[x]) if (comp[e] == -1) rdfs(e, cnt);\n }\n void build() {\n rep(i, g.size()) dfs(i);\n reverse(all(ord));\n num = 0;\n for(auto&& i: ord) if (comp[i] == -1) { rdfs(i, num), num++; }\n }\n vector<vector<int>> groups(){\n vector<vector<int>> gp(num);\n for (int v = 0; v < (int)g.size(); v++) {\n gp[comp[v]].push_back(v);\n }\n return gp;\n }\n};\n\n\nint main(){\n int N,M;\n cin>>N>>M;\n vector<vector<int>> G(N);\n rep(i,M){\n int s,t;\n cin>>s>>t;\n G[s].push_back(t);\n }\n SCC scc(G);\n vector<vector<int>> H(scc.num);\n rep(i,N) for(int e: G[i]) {\n if(scc.comp[i]==scc.comp[e]) continue;\n H[scc.comp[i]].push_back(scc.comp[e]);\n }\n rep(i,scc.num) sort(all(H[i])), H[i].erase(unique(all(H[i])),H[i].end());\n\n\n if(scc.num==1){\n cout<<0<<\"\\n\";\n return 0;\n }\n \n vector<int> in(scc.num,0),out(scc.num,0);\n rep(i,scc.num) out[i]=H[i].size();\n rep(i,scc.num) for(int e: H[i]) in[e]++;\n int i0=0,o0=0;\n rep(i,scc.num) o0+=(out[i]==0);\n rep(i,scc.num) i0+=(in[i]==0);\n cout<<max(o0,i0)<<\"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7424, "score_of_the_acc": -0.1419, "final_rank": 2 }, { "submission_id": "aoj_0366_10867144", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i=0;i<(ll)(N);i++)\n#define fi first \n#define se second\n#define pb push_back\n#define all(X) (X).begin(),(X).end()\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\n\nclass segtree{\n public:\n int N;\n vector<ll>data;\n vector<ll>lazy;\n void init (int n){\n N = 1;\n while(N<n)N*=2;\n data.assign(N*2-1,0);\n lazy.assign(N*2-1,0);\n }\n void eval(int k){\n if(lazy[k]==0)return;\n data[k]+=lazy[k];\n if(2*k+2<N*2-1){\n lazy[2*k+1]+=lazy[k];\n lazy[2*k+2]+=lazy[k];\n }\n lazy[k]=0;\n }\n void update(int a,int b,ll x,int k=0,int l=0,int r = -1){\n if(r<0)r=N;\n eval(k);\n if(b<=l||r<=a)return;\n if(a<=l&&r<=b){\n lazy[k]+=x;\n eval(k);\n return;\n }\n update(a,b,x,2*k+1,l,(l+r)/2);\n update(a,b,x,2*k+2,(l+r)/2,r);\n data[k]=max(data[2*k+1],data[2*k+2]);\n }\n ll get(int a,int b,int k=0,int l=0,int r = -1){\n if(r<0)r=N;\n eval(k);\n if(b<=l||r<=a)return 0;\n if(a<=l&&r<=b){\n return data[k];\n }\n ll L=get(a,b,k*2+1,l,(l+r)/2),R=get(a,b,k*2+2,(l+r)/2,r);\n return max(L,R);\n }\n};\n\ntemplate< typename G >\nstruct StronglyConnectedComponents {\n const G &g;\n vector<vector<int>> gg, rg;\n vector< int > comp, order, used;\n\n StronglyConnectedComponents(G &g) : g(g), gg(g.size()), rg(g.size()), comp(g.size(), -1), used(g.size()) {\n for(int i = 0; i < g.size(); i++) {\n for(auto e : g[i]) {\n gg[i].emplace_back((int) e);\n rg[(int) e].emplace_back(i);\n }\n }\n }\n\n int operator[](int k) {\n return comp[k];\n }\n\n void dfs(int idx) {\n if(used[idx]) return;\n used[idx] = true;\n for(int to : gg[idx]) dfs(to);\n order.push_back(idx);\n }\n\n void rdfs(int idx, int cnt) {\n if(comp[idx] != -1) return;\n comp[idx] = cnt;\n for(int to : rg[idx]) rdfs(to, cnt);\n }\n\n void build(vector<vector<int>> &t) {\n for(int i = 0; i < gg.size(); i++) dfs(i);\n reverse(begin(order), end(order));\n int ptr = 0;\n for(int i : order) if(comp[i] == -1) rdfs(i, ptr), ptr++;\n\n t.resize(ptr);\n for(int i = 0; i < g.size(); i++) {\n for(auto &to : g[i]) {\n int x = comp[i], y = comp[to];\n if(x == y) continue;\n t[x].push_back(y);\n }\n }\n }\n};\n\nint main(){\n int N,M;cin>>N>>M;\n vector<vector<int>>G(N);\n rep(i,M){\n int s,t;cin>>s>>t;\n G[s].pb(t);\n }\n StronglyConnectedComponents SCC(G);\n vector<vector<int>>nG;\n SCC.build(nG);\n if(nG.size()==1){\n cout<<0<<endl;\n return 0;\n }\n vector<int>inc(nG.size(),0);\n ll ct = 0;\n rep(i,nG.size()){\n if(nG[i].size()==0)ct++;\n for(auto e : nG[i]){\n inc[e]++;\n }\n }\n ll z = 0;\n for(auto e : inc){\n if(e==0)z++;\n }\n cout<<max(z,ct)<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7296, "score_of_the_acc": -0.4643, "final_rank": 4 }, { "submission_id": "aoj_0366_10863853", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nnamespace atcoder {\n namespace internal {\n\n template <class E> struct csr {\n std::vector<int> start;\n std::vector<E> elist;\n csr(int n, const std::vector<std::pair<int, E>>& edges)\n : start(n + 1), elist(edges.size()) {\n for (auto e : edges) {\n start[e.first + 1]++;\n }\n for (int i = 1; i <= n; i++) {\n start[i] += start[i - 1];\n }\n auto counter = start;\n for (auto e : edges) {\n elist[counter[e.first]++] = e.second;\n }\n }\n };\n\n struct scc_graph {\n public:\n scc_graph(int n) : _n(n) {}\n\n int num_vertices() { return _n; }\n\n void add_edge(int from, int to) { edges.push_back({ from, {to} }); }\n\n std::pair<int, std::vector<int>> scc_ids() {\n auto g = csr<edge>(_n, edges);\n int now_ord = 0, group_num = 0;\n std::vector<int> visited, low(_n), ord(_n, -1), ids(_n);\n visited.reserve(_n);\n auto dfs = [&](auto self, int v) -> void {\n low[v] = ord[v] = now_ord++;\n visited.push_back(v);\n for (int i = g.start[v]; i < g.start[v + 1]; i++) {\n auto to = g.elist[i].to;\n if (ord[to] == -1) {\n self(self, to);\n low[v] = std::min(low[v], low[to]);\n }\n else {\n low[v] = std::min(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (true) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = _n;\n ids[u] = group_num;\n if (u == v) break;\n }\n group_num++;\n }\n };\n for (int i = 0; i < _n; i++) {\n if (ord[i] == -1) dfs(dfs, i);\n }\n for (auto& x : ids) {\n x = group_num - 1 - x;\n }\n return { group_num, ids };\n }\n\n std::vector<std::vector<int>> scc() {\n auto ids = scc_ids();\n int group_num = ids.first;\n std::vector<int> counts(group_num);\n for (auto x : ids.second) counts[x]++;\n std::vector<std::vector<int>> groups(ids.first);\n for (int i = 0; i < group_num; i++) {\n groups[i].reserve(counts[i]);\n }\n for (int i = 0; i < _n; i++) {\n groups[ids.second[i]].push_back(i);\n }\n return groups;\n }\n\n private:\n int _n;\n struct edge {\n int to;\n };\n std::vector<std::pair<int, edge>> edges;\n };\n\n }\n\n}\nnamespace atcoder {\n\n struct scc_graph {\n public:\n scc_graph() : internal(0) {}\n scc_graph(int n) : internal(n) {}\n\n void add_edge(int from, int to) {\n int n = internal.num_vertices();\n assert(0 <= from && from < n);\n assert(0 <= to && to < n);\n internal.add_edge(from, to);\n }\n\n std::vector<std::vector<int>> scc() { return internal.scc(); }\n\n private:\n internal::scc_graph internal;\n };\n\n}\nusing namespace atcoder;\nint main() {\n int n, m; cin >> n >> m;\n scc_graph graph(n);\n vector<vector<int>> g(n);\n rep(i, m) {\n int s, t; cin >> s >> t;\n graph.add_edge(s, t);\n g[s].push_back(t);\n }\n auto scc = graph.scc();\n if (scc.size() == 1) {\n cout << 0 << endl;\n return 0;\n }\n vector<int> idx(n);\n rep(i, scc.size())rep(j, scc[i].size()) {\n idx[scc[i][j]] = i;\n }\n vector<int> icnt(scc.size()), ocnt(scc.size());\n rep(i, n)rep(j, g[i].size()) {\n if (idx[i] != idx[g[i][j]]) {\n icnt[idx[g[i][j]]]++;\n ocnt[idx[i]]++;\n }\n }\n int in = 0, out = 0;\n rep(i, scc.size()) {\n if (icnt[i] == 0)in++;\n if (ocnt[i] == 0)out++;\n }\n cout << max(in, out) << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7056, "score_of_the_acc": -0.4439, "final_rank": 3 }, { "submission_id": "aoj_0366_10853995", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing LL = long long int;\n\nconst int MAX_V = 10005;\n\nint V, M;\nvector<int> G[MAX_V];\nvector<int> rG[MAX_V];\nvector<int> vs;\nbool used[MAX_V];\nint cmp[MAX_V];\nvector<vector<int>> GG;\nvector<vector<int>> GGEdge;\nvector<int> GInput;\n\nvoid add_edge(int from, int to)\n{\n G[from].push_back(to);\n rG[to].push_back(from);\n}\n\nvoid dfs(int v)\n{\n used[v] = true;\n for(unsigned int i = 0; i < G[v].size(); i++) {\n if(!used[G[v][i]]) dfs(G[v][i]);\n }\n vs.push_back(v);\n}\n\nvoid rdfs(int v, int k)\n{\n used[v] = true;\n cmp[v] = k; GG[k].push_back(v);\n for(unsigned int i = 0; i < rG[v].size(); i++) {\n if(!used[rG[v][i]]) rdfs(rG[v][i], k);\n }\n}\n\nint scc()\n{\n memset(used, 0, sizeof(used));\n vs.clear();\n for(int v = 0; v < V; v++) {\n if(!used[v]) dfs(v);\n }\n memset(used, 0, sizeof(used));\n int k = 0;\n for(int i = vs.size()-1; i >= 0; i--) {\n if(!used[vs[i]]) {\n GG.push_back(vector<int>());\n rdfs(vs[i], k++);\n }\n }\n return k;\n}\n\nclass UnionFind{\npublic:\n int par[MAX_V];\n UnionFind(){\n init();\n }\n void init() {\n for(int i = 0; i < MAX_V; i++) {\n par[i] = i;\n }\n }\n int find(int x) {\n if(x == par[x]) {\n return x;\n } else {\n return par[x] = find(par[x]);\n }\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if(x == y) {\n return;\n }\n par[x] = y;\n }\n bool same(int x, int y) {\n return find(x) == find(y);\n }\n}uf;\n\nint solve(int v, bool flag = true)\n{\n used[v] = true;\n if(GGEdge[v].size() == 0 && flag) {\n return 0;\n } else if(GGEdge[v].size() == 0) {\n return 1;\n } else {\n int ret = 0;\n for(int next : GGEdge[v]) {\n if(!used[next]) {\n uf.unite(v, next);\n ret += solve(next, false);\n } else {\n if(!uf.same(v, next)){\n ret++;\n uf.unite(v, next);\n }\n }\n }\n return ret;\n }\n}\n\nvector<int> GGIn, GGOut;\n\nint main()\n{\n cin >> V >> M;\n for(int i = 0; i < M; i++) {\n int f, t; cin >> f >> t;\n add_edge(f, t);\n }\n\n scc();\n\n GGEdge.resize(GG.size());\n GGIn.resize(GG.size()); GGOut.resize(GG.size());\n for(unsigned int k = 0; k < GG.size(); k++) {\n //cerr << k << \": \";\n set<int> S; S.insert(k);\n for(unsigned int i = 0; i < GG[k].size(); i++) {\n int v = GG[k][i];\n //cerr << v << \" \";\n for(unsigned int j = 0; j < G[v].size(); j++) {\n int next = G[v][j];\n if(S.insert(cmp[next]).second){\n GGEdge[cmp[v]].push_back(cmp[next]);\n GGIn[cmp[next]]++;\n GGOut[cmp[v]]++;\n }\n\n }\n }\n //cerr << endl;\n }\n/*\n for(unsigned int v = 0; v < GG.size(); v++) {\n cerr << v << \": \" ;\n for(int next : GGEdge[v]) {\n cerr << next << \" \";\n }\n cerr << endl;\n }\n*/\n/*\n int ans = 0;\n memset(used, 0, sizeof(used));\n for(unsigned int v = 0; v < GG.size(); v++) {\n if(!used[v]) {\n ans += solve(v);\n }\n //cerr << ans << endl;\n }\n\n set<int> S;\n for(unsigned int v = 0; v < GG.size(); v++) {\n S.insert(uf.find(v));\n }\n\n //cerr << ans << \" \" << S.size() << endl;\n\n if(S.size() > 1) {\n ans += S.size();\n }\n\n cout << ans << endl;\n*/\n\n if(GG.size()==1) {\n cout << 0 << endl;\n return 0;\n }\n\n int in = 0, out = 0;\n for(unsigned int i = 0; i < GG.size(); i++) {\n if(GGIn[i] == 0) {\n in++;\n }\n if(GGOut[i] == 0) {\n out++;\n }\n }\n\n cout << max(in, out) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6636, "score_of_the_acc": -0.7414, "final_rank": 5 }, { "submission_id": "aoj_0366_10779294", "code_snippet": "#include <bits/stdc++.h>\n#define reb(i,n) for (int i = 0; i < (n); i++)\n#define rep(i, n0, n) for (int i = (n0); i < (n); i++)\n#define repp(i, n0, n) for (int i = (n0); i <= (n); i++)\n#define rrep(i, n0, n) for (int i = (n0); i >= (n); i--) \n#define bit(n,k) ((n>>k)&1)\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pl = pair<ll,ll>;\nusing pi = pair<int,int>;\ntemplate<class T> inline bool chmax(T& a, T b) { if(a<b) { a = b; return true;} return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if(a>b) { a = b; return true;} return false; }\n\nvoid solve() {\n int N, M; cin >> N >> M;\n vector<vector<int>> g(N), r(N);\n reb(i,M) {\n int s, t; cin >> s >> t;\n g[s].emplace_back(t);\n r[t].emplace_back(s);\n }\n\n int now = 0;\n vector<bool> visited(N);\n vector<int> t(N);\n auto dfs = [&](auto dfs, int v) -> void {\n visited[v] = true;\n for (auto nv : g[v]) {\n if (visited[nv]) continue;\n dfs(dfs,nv);\n }\n t[now++] = v;\n };\n reb(v,N) {\n if (visited[v]) continue;\n dfs(dfs,v);\n }\n\n int cn = 0;\n vector<unordered_set<int>> groups;\n vector<bool> visited2(N);\n auto dfs2 = [&](auto dfs2, int v) -> void {\n visited2[v] = true;\n groups[cn].emplace(v);\n for (auto nv : r[v]) {\n if (visited2[nv]) continue;\n dfs2(dfs2,nv);\n }\n };\n rrep(d,N-1,0) {\n int v = t[d];\n if (visited2[v]) continue;\n groups.emplace_back(unordered_set<int>());\n dfs2(dfs2,v);\n cn++;\n }\n\n vector<int> cc(N), indeg(cn), outdeg(cn);\n vector<unordered_set<int>> G(cn), R(cn);\n reb(c,cn) {\n auto grp = groups[c];\n for (int v : grp) {\n cc[v] = c;\n }\n }\n reb(c,cn) {\n auto grp = groups[c];\n for (int v : grp) {\n for (int nv : g[v]) if (!grp.contains(nv) and !G[c].contains(cc[nv])) G[c].emplace(cc[nv]), outdeg[c]++;\n for (int pv : r[v]) if (!grp.contains(pv) and !R[c].contains(cc[pv])) R[c].emplace(cc[pv]), indeg[c]++;\n }\n }\n\n int ans = max(ranges::count(indeg,0), ranges::count(outdeg,0));\n cout << ((int)groups.size() == 1 ? 0 : ans) << endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 17480, "score_of_the_acc": -1.333, "final_rank": 14 }, { "submission_id": "aoj_0366_10779293", "code_snippet": "#include <bits/stdc++.h>\n#define reb(i,n) for (int i = 0; i < (n); i++)\n#define rep(i, n0, n) for (int i = (n0); i < (n); i++)\n#define repp(i, n0, n) for (int i = (n0); i <= (n); i++)\n#define rrep(i, n0, n) for (int i = (n0); i >= (n); i--) \n#define bit(n,k) ((n>>k)&1)\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pl = pair<ll,ll>;\nusing pi = pair<int,int>;\ntemplate<class T> inline bool chmax(T& a, T b) { if(a<b) { a = b; return true;} return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if(a>b) { a = b; return true;} return false; }\n\nvoid solve() {\n int N, M; cin >> N >> M;\n vector<vector<int>> g(N), r(N);\n reb(i,M) {\n int s, t; cin >> s >> t;\n g[s].emplace_back(t);\n r[t].emplace_back(s);\n }\n\n int now = 0;\n vector<bool> visited(N);\n vector<int> t(N);\n auto dfs = [&](auto dfs, int v) -> void {\n visited[v] = true;\n for (auto nv : g[v]) {\n if (visited[nv]) continue;\n dfs(dfs,nv);\n }\n t[now++] = v;\n };\n reb(v,N) {\n if (visited[v]) continue;\n dfs(dfs,v);\n }\n\n int cn = 0;\n vector<unordered_set<int>> groups;\n vector<bool> visited2(N);\n auto dfs2 = [&](auto dfs2, int v) -> void {\n visited2[v] = true;\n groups[cn].emplace(v);\n for (auto nv : r[v]) {\n if (visited2[nv]) continue;\n dfs2(dfs2,nv);\n }\n };\n rrep(d,N-1,0) {\n int v = t[d];\n if (visited2[v]) continue;\n groups.emplace_back(unordered_set<int>());\n dfs2(dfs2,v);\n cn++;\n }\n\n vector<int> cc(N), indeg(cn), outdeg(cn);\n vector<unordered_set<int>> G(cn), R(cn);\n reb(c,cn) {\n auto grp = groups[c];\n for (int v : grp) {\n cc[v] = c;\n }\n }\n reb(c,cn) {\n auto grp = groups[c];\n for (int v : grp) {\n for (int nv : g[v]) if (!grp.contains(nv) and !G[c].contains(cc[nv])) G[c].emplace(cc[nv]), outdeg[c]++;\n for (int pv : r[v]) if (!grp.contains(pv) and !R[c].contains(cc[pv])) R[c].emplace(cc[pv]), indeg[c]++;\n }\n }\n\n // vector<bool> visited3(cn);\n // auto dfs3 = [&](auto dfs3, int c) -> void {\n // visited3[c] = true;\n // for (int nc : G[c]) {\n // if (visited3[nc]) continue;\n // dfs3(dfs3, nc);\n // }\n // for (int nc : R[c]) {\n // if (visited3[nc]) continue;\n // dfs3(dfs3, nc);\n // }\n // };\n\n // int ccnt = 0;\n // reb(c,cn) {\n // if (visited3[c]) continue;\n // dfs3(dfs3, c);\n // ccnt++;\n // }\n\n int ans = max(ranges::count(indeg,0), ranges::count(outdeg,0));\n cout << ((int)groups.size() == 1 ? 0 : ans) << endl;\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 17484, "score_of_the_acc": -1.3333, "final_rank": 15 }, { "submission_id": "aoj_0366_10734984", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nstruct StrongConnectedComponents {\n int N;\n vector<int> order, comp;\n vector<vector<int>> G_rev, groups, dag;\n StrongConnectedComponents(const vector<vector<int>>& G) : N(G.size()) {\n // 辺が逆向きのグラフ G_rev を構築\n G_rev.resize(N);\n for (int u = 0; u < N; u++) {\n for (auto&& v : G[u]) {\n G_rev[v].emplace_back(u);\n }\n }\n comp.resize(N, -2);\n // comp[i] = -2: 未訪問, -1: dfs で訪問済, id: dfs2 で訪問済\n for (int i = 0; i < N; i++) {\n if (comp[i] != -2) continue;\n dfs(G, i);\n }\n int id = 0;\n for (int i = N - 1; i >= 0; i--) {\n if (comp[order[i]] != -1) continue;\n dfs2(order[i], id), id++;\n }\n G_rev.clear(), order.clear();\n groups.resize(id), dag.resize(id);\n for (int i = 0; i < N; i++) {\n groups[comp[i]].emplace_back(i);\n for (auto&& to : G[i]) {\n if (comp[i] == comp[to]) continue;\n dag[comp[i]].emplace_back(comp[to]);\n }\n }\n }\n void dfs(const vector<vector<int>>& G, int pos) {\n comp[pos] = -1;\n for (auto&& to : G[pos]) {\n if (comp[to] != -2) continue;\n dfs(G, to);\n }\n order.emplace_back(pos);\n }\n void dfs2(int pos, int id) {\n comp[pos] = id;\n for (auto&& to : G_rev[pos]) {\n if (comp[to] != -1) continue;\n dfs2(to, id);\n }\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<vector<int>> G(N);\n for (int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n G[u].emplace_back(v);\n }\n\n StrongConnectedComponents scc(G);\n int N2 = ssize(scc.groups);\n\n // 入次数が 0 または出次数が 0 のものを数える\n vector<int> in(N2, 0), out(N2, 0);\n for (int from = 0; from < N2; from++) {\n for (auto&& to : scc.dag[from]) {\n in[to]++, out[from]++;\n }\n }\n\n int ans = max(ranges::count(in, 0), ranges::count(out, 0));\n cout << (N2 == 1 ? 0 : ans) << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6272, "score_of_the_acc": -0.0437, "final_rank": 1 }, { "submission_id": "aoj_0366_10734959", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nstruct StrongConnectedComponents {\n int N;\n vector<int> order, comp;\n vector<vector<int>> G_rev, groups, dag;\n StrongConnectedComponents(const vector<vector<int>>& G) : N(G.size()) {\n // 辺が逆向きのグラフ G_rev を構築\n G_rev.resize(N);\n for (int u = 0; u < N; u++) {\n for (auto&& v : G[u]) {\n G_rev[v].emplace_back(u);\n }\n }\n comp.resize(N, -2);\n // comp[i] = -2: 未訪問, -1: dfs で訪問済, id: dfs2 で訪問済\n for (int i = 0; i < N; i++) {\n if (comp[i] != -2) continue;\n dfs(G, i);\n }\n int id = 0;\n for (int i = N - 1; i >= 0; i--) {\n if (comp[order[i]] != -1) continue;\n dfs2(order[i], id), id++;\n }\n G_rev.clear(), order.clear();\n groups.resize(id), dag.resize(id);\n for (int i = 0; i < N; i++) {\n groups[comp[i]].emplace_back(i);\n for (auto&& to : G[i]) {\n if (comp[i] == comp[to]) continue;\n dag[comp[i]].emplace_back(comp[to]);\n }\n }\n }\n void dfs(const vector<vector<int>>& G, int pos) {\n comp[pos] = -1;\n for (auto&& to : G[pos]) {\n if (comp[to] != -2) continue;\n dfs(G, to);\n }\n order.emplace_back(pos);\n }\n void dfs2(int pos, int id) {\n comp[pos] = id;\n for (auto&& to : G_rev[pos]) {\n if (comp[to] != -1) continue;\n dfs2(to, id);\n }\n }\n};\n\nstruct UnionFind {\n int n, counter;\n vector<int> data;\n UnionFind(int size) : n(size), counter(size), data(size, -1) {}\n int root(int x) { return (data[x] < 0 ? x : data[x] = root(data[x])); }\n bool same(int x, int y) { return root(x) == root(y); }\n bool merge(int x, int y) {\n x = root(x), y = root(y);\n if (x == y) return false;\n if (-data[x] < -data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n counter--;\n return true;\n }\n int size(int x) { return -data[root(x)]; }\n int size() { return counter; }\n vector<int> group(int x) {\n vector<int> res;\n for (int i = 0; i < n; i++)\n if (same(x, i)) res.emplace_back(i);\n return res;\n }\n vector<vector<int>> groups() {\n vector<vector<int>> res(n);\n for (int i = 0; i < n; i++) res[root(i)].emplace_back(i);\n res.erase(remove_if(res.begin(), res.end(), [&](const vector<int>& v) { return v.empty(); }), res.end());\n return res;\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<vector<int>> G(N);\n for (int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n G[u].emplace_back(v);\n }\n\n StrongConnectedComponents scc(G);\n int N2 = ssize(scc.groups);\n\n // dag の連結成分数, 入次数が 0 または出次数が 0 のものを数える\n UnionFind uf(N2);\n vector<int> in(N2, 0), out(N2, 0);\n for (int from = 0; from < N2; from++) {\n for (auto&& to : scc.dag[from]) {\n in[to]++, out[from]++;\n uf.merge(from, to);\n }\n }\n\n int ans = ranges::count(in, 0);\n cout << (N2 == 1 ? 0 : ans) << '\\n';\n}", "accuracy": 0.5666666666666667, "time_ms": 10, "memory_kb": 6272, "score_of_the_acc": -0.0437, "final_rank": 18 }, { "submission_id": "aoj_0366_10734931", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nstruct StrongConnectedComponents {\n int N;\n vector<int> order, comp;\n vector<vector<int>> G_rev, groups, dag;\n StrongConnectedComponents(const vector<vector<int>>& G) : N(G.size()) {\n // 辺が逆向きのグラフ G_rev を構築\n G_rev.resize(N);\n for (int u = 0; u < N; u++) {\n for (auto&& v : G[u]) {\n G_rev[v].emplace_back(u);\n }\n }\n comp.resize(N, -2);\n // comp[i] = -2: 未訪問, -1: dfs で訪問済, id: dfs2 で訪問済\n for (int i = 0; i < N; i++) {\n if (comp[i] != -2) continue;\n dfs(G, i);\n }\n int id = 0;\n for (int i = N - 1; i >= 0; i--) {\n if (comp[order[i]] != -1) continue;\n dfs2(order[i], id), id++;\n }\n G_rev.clear(), order.clear();\n groups.resize(id), dag.resize(id);\n for (int i = 0; i < N; i++) {\n groups[comp[i]].emplace_back(i);\n for (auto&& to : G[i]) {\n if (comp[i] == comp[to]) continue;\n dag[comp[i]].emplace_back(comp[to]);\n }\n }\n }\n void dfs(const vector<vector<int>>& G, int pos) {\n comp[pos] = -1;\n for (auto&& to : G[pos]) {\n if (comp[to] != -2) continue;\n dfs(G, to);\n }\n order.emplace_back(pos);\n }\n void dfs2(int pos, int id) {\n comp[pos] = id;\n for (auto&& to : G_rev[pos]) {\n if (comp[to] != -1) continue;\n dfs2(to, id);\n }\n }\n};\n\nstruct UnionFind {\n int n, counter;\n vector<int> data;\n UnionFind(int size) : n(size), counter(size), data(size, -1) {}\n int root(int x) { return (data[x] < 0 ? x : data[x] = root(data[x])); }\n bool same(int x, int y) { return root(x) == root(y); }\n bool merge(int x, int y) {\n x = root(x), y = root(y);\n if (x == y) return false;\n if (-data[x] < -data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n counter--;\n return true;\n }\n int size(int x) { return -data[root(x)]; }\n int size() { return counter; }\n vector<int> group(int x) {\n vector<int> res;\n for (int i = 0; i < n; i++)\n if (same(x, i)) res.emplace_back(i);\n return res;\n }\n vector<vector<int>> groups() {\n vector<vector<int>> res(n);\n for (int i = 0; i < n; i++) res[root(i)].emplace_back(i);\n res.erase(remove_if(res.begin(), res.end(), [&](const vector<int>& v) { return v.empty(); }), res.end());\n return res;\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<vector<int>> G(N);\n for (int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n G[u].emplace_back(v);\n }\n\n StrongConnectedComponents scc(G);\n int N2 = ssize(scc.groups);\n\n // dag の連結成分数, 入次数が 0 または出次数が 0 のものを数える\n UnionFind uf(N2);\n vector<int> in(N2, 0), out(N2, 0);\n for (int from = 0; from < N2; from++) {\n for (auto&& to : scc.dag[from]) {\n in[to]++, out[from]++;\n uf.merge(from, to);\n }\n }\n\n int ans = count(in.begin(), in.end(), 0) + count(out.begin(), out.end(), 0) - uf.size();\n cout << (N2 == 1 ? 0 : ans) << '\\n';\n}", "accuracy": 0.3, "time_ms": 10, "memory_kb": 5760, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0366_10734803", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nstruct StrongConnectedComponents {\n int N;\n vector<int> order, comp;\n vector<vector<int>> G_rev, groups, dag;\n StrongConnectedComponents(const vector<vector<int>>& G) : N(G.size()) {\n // 辺が逆向きのグラフ G_rev を構築\n G_rev.resize(N);\n for (int u = 0; u < N; u++) {\n for (auto&& v : G[u]) {\n G_rev[v].emplace_back(u);\n }\n }\n comp.resize(N, -2);\n // comp[i] = -2: 未訪問, -1: dfs で訪問済, id: dfs2 で訪問済\n for (int i = 0; i < N; i++) {\n if (comp[i] != -2) continue;\n dfs(G, i);\n }\n int id = 0;\n for (int i = N - 1; i >= 0; i--) {\n if (comp[order[i]] != -1) continue;\n dfs2(order[i], id), id++;\n }\n G_rev.clear(), order.clear();\n groups.resize(id), dag.resize(id);\n for (int i = 0; i < N; i++) {\n groups[comp[i]].emplace_back(i);\n for (auto&& to : G[i]) {\n if (comp[i] == comp[to]) continue;\n dag[comp[i]].emplace_back(comp[to]);\n }\n }\n }\n void dfs(const vector<vector<int>>& G, int pos) {\n comp[pos] = -1;\n for (auto&& to : G[pos]) {\n if (comp[to] != -2) continue;\n dfs(G, to);\n }\n order.emplace_back(pos);\n }\n void dfs2(int pos, int id) {\n comp[pos] = id;\n for (auto&& to : G_rev[pos]) {\n if (comp[to] != -1) continue;\n dfs2(to, id);\n }\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, M;\n cin >> N >> M;\n vector<vector<int>> G(N);\n for (int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n G[u].emplace_back(v);\n }\n\n StrongConnectedComponents scc(G);\n int N2 = ssize(scc.groups);\n\n // dag の連結成分数が答え (dag の頂点数が 1 の場合は 0)\n int ans = 0;\n vector<int> seen(N2);\n for (int i = 0; i < N2; i++) {\n if (!seen[i]) seen[i] = true, ans++;\n for (auto&& to : scc.dag[i]) {\n if (!seen[to]) seen[to] = true;\n }\n }\n\n cout << (N2 == 1 ? 0 : ans) << '\\n';\n}", "accuracy": 0.5666666666666667, "time_ms": 10, "memory_kb": 6144, "score_of_the_acc": -0.0328, "final_rank": 17 }, { "submission_id": "aoj_0366_10695939", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\n#define mod 1000000007\n#define endl '\\n'\n#define pii pair<int,int>\n#define I_am_weak ios::sync_with_stdio(0),cin.tie(0);\nusing namespace std;\n#define MXN 10055\nstruct Scc{\n #define PB push_back\n int n, nScc, vst[MXN], bln[MXN];\n vector<int> E[MXN], rE[MXN], vec;\n void init(int _n){\n n = _n;\n for (int i=0; i<MXN; i++)\n E[i].clear(), rE[i].clear();\n }\n void addEdge(int u, int v){\n E[u].PB(v); rE[v].PB(u);\n }\n void DFS(int u){\n vst[u]=1;\n for (auto v : E[u]) if (!vst[v]) DFS(v);\n vec.PB(u);\n }\n void rDFS(int u){\n vst[u] = 1; bln[u] = nScc;\n for (auto v : rE[u]) if (!vst[v]) rDFS(v);\n }\n void solve(){\n nScc = 0;\n vec.clear();\n memset(vst,0,sizeof(vst));\n for (int i=0; i<n; i++)\n if (!vst[i]) DFS(i);\n reverse(vec.begin(),vec.end());\n memset(vst,0,sizeof(vst));\n for (auto v : vec)\n if (!vst[v]){\n rDFS(v); nScc++;\n }\n }\n}ggg;\n\nvector<pii>edge;\nvector<int>v[10005];\nint in[10005];\nsigned main(){\n //注意多筆測資輸入!!!\n I_am_weak\n int n,m;\n memset(in,0,sizeof(in));\n cin>>n>>m;\n ggg.init(n);\n for(int i=0;i<m;i++){\n int x,y;\n cin>>x>>y;\n edge.push_back({x,y});\n ggg.addEdge(x,y);\n }\n ggg.solve();\n for(auto [x,y]:edge){\n if(ggg.bln[x]!=ggg.bln[y]){\n //cout<<ggg.bln[x]<<\" \"<<ggg.bln[y]<<endl;\n v[ggg.bln[x]].push_back(ggg.bln[y]);\n in[ggg.bln[y]]++;\n }\n }\n if(ggg.nScc==1){\n cout<<0<<endl;\n return 0;\n }\n int cnt=0;\n for(int i=0;i<ggg.nScc;i++){\n if(in[i]==0)cnt++;\n }\n cout<<cnt<<endl;\n \n \n}", "accuracy": 0.5666666666666667, "time_ms": 10, "memory_kb": 9772, "score_of_the_acc": -0.3422, "final_rank": 19 }, { "submission_id": "aoj_0366_9955208", "code_snippet": "// ### test.cpp ###\n#include <bits/stdc++.h>\n#ifdef __DEBUG_VECTOR\nnamespace for_debugging{\n struct subscript_and_location{\n int sub;\n std::source_location loc;\n subscript_and_location(int sub_,std::source_location loc_=std::source_location::current()){\n sub=sub_;\n loc=loc_;\n }\n void check_out_of_range(size_t sz){\n if(sub<0||(int)sz<=sub){\n std::clog << loc.file_name() << \":(\" << loc.line() << \":\" << loc.column() << \"):\" << loc.function_name() << std::endl;\n std::clog << \"out of range: subscript = \" << sub << \", vector_size = \" << sz << std::endl;\n exit(EXIT_FAILURE);\n }\n }\n };\n}\nnamespace std{\n template<class T,class Allocator=std::allocator<T>> class vector_for_debugging:public std::vector<T,Allocator>{\n using std::vector<T,Allocator>::vector;\n public:\n [[nodiscard]] constexpr std::vector<T,Allocator>::reference operator[](for_debugging::subscript_and_location n) noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n [[nodiscard]] constexpr std::vector<T,Allocator>::const_reference operator[](for_debugging::subscript_and_location n) const noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n };\n namespace pmr{\n template<class T> using vector_for_debugging=std::vector_for_debugging<T,std::pmr::polymorphic_allocator<T>>;\n }\n}\n#define vector vector_for_debugging\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing sll = __int128_t;\nusing db = double;\nusing Pr = pair<ll, ll>;\nusing Pd = pair<double, double>;\nusing vi = vector<int>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vl = vector<ll>;\nusing vb = vector<bool>;\nusing vd = vector<double>;\nusing vp = vector<Pr>;\nusing vpd = vector<Pd>;\nusing vvi = vector<vector<int>>;\nusing vvc = vector<vector<char>>;\nusing vvl = vector<vector<ll>>;\nusing vvp = vector<vector<Pr>>;\nusing vvb = vector<vector<bool>>;\nusing vvd = vector<vector<double>>;\nusing vvs = vector<vector<string>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvb = vector<vector<vector<bool>>>;\nusing vvvd = vector<vector<vector<double>>>;\nusing t3 = tuple<ll,ll,ll>;\nusing t3d = tuple<db,db,db>;\nusing t4 = tuple<ll,ll,ll,ll>;\nusing vt3 = vector<t3>;\nusing vt3d = vector<t3d>;\nusing vt4 = vector<t4>;\nusing vvt3 = vector<vector<t3>>;\nusing vvt3d = vector<vector<t3d>>;\nusing vvt4 = vector<vector<t4>>;\nusing pq = priority_queue<Pr,vector<Pr>,greater<Pr>>;\nusing cl = complex<ll>;\nusing cd = complex<double>;\n#define rep(i, N) for (ll i=0; i<(ll)(N); ++i)\n#define repr(i, N) for (ll i = (ll)(N) - 1; i >= 0; --i)\n#define repk(i, k, N) for (ll i = k; i < (ll)(N); ++i)\n#define rep1(i, N) for (ll i=1; i<(ll)(N+1); ++i)\n#define rep1r(i, N) for (ll i=(ll)(N); i>0; i--)\n#define all(v) (v).begin(), (v).end()\n#define allr(v) (v).rbegin(), (v).rend()\n#define SIZE(v) (ll)((v).size())\n#define PYes {puts(\"Yes\"); exit(0);}\n#define PNo {puts(\"No\"); exit(0);}\n#define PFi {puts(\"First\"); exit(0);}\n#define PSe {puts(\"Second\"); exit(0);}\n#define Pm0 {puts(\"0\"); exit(0);}\n#define Pm1 {puts(\"-1\"); exit(0);}\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define INTM(...) int __VA_ARGS__; inm(__VA_ARGS__)\n#define LONG(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define LONGM(...) ll __VA_ARGS__; inm(__VA_ARGS__)\n#define DOUBLE(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define STRING(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define VI(ivec, n) vi ivec(n); input_ivec(ivec, n)\n#define VIM(ivec, n) vi ivec(n); input_ivecm(ivec, n)\n#define VL(lvec, n) vl lvec(n); input_lvec(lvec, n)\n#define VLM(lvec, n) vl lvec(n); input_lvecm(lvec, n)\n#define VL2(lvec1, lvec2, n) vl lvec1(n), lvec2(n); input_lvec12(lvec1, lvec2, n)\n#define VL2M(lvec1, lvec2, n) vl lvec1(n), lvec2(n); input_lvec12m(lvec1, lvec2, n)\n#define VC(cvec, n) vc cvec(n); input_cvec(cvec, n)\n#define VS(svec, n) vs svec(n); input_svec(svec, n)\n#define VD(dvec, n) vd dvec(n); input_dvec(dvec, n)\n#define VP(pvec, n) vp pvec(n); input_pvec(pvec, n)\n#define VPD(pvec, n) vpd pvec(n); input_pvecd(pvec, n)\n#define VPM(pvec, n) vp pvec(n); input_pvecm(pvec, n)\n#define VVI(ivec2, h, w) vvi ivec2(h, vi(w)); input_ivec2(ivec2, h, w)\n#define VVL(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2(lvec2, h, w)\n#define VVLM(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2m(lvec2, h, w)\n#define VVC(cvec2, h, w) vvc cvec2(h, vc(w)); input_cvec2(cvec2, h, w)\n#define pcnt(x) (ll)__builtin_popcountll(x)\n#define parity(x) (ll)__builtin_parityll(x)\n#define uset unordered_set\n#define umap unordered_map\ninline void Out(double x) {printf(\"%.15f\",x);cout<<'\\n';}\ntemplate<typename T> inline void Out(pair<T,T> x) {cout<<x.first<<' '<<x.second<<'\\n';}\ntemplate<typename T> inline void Out(T x) {cout<<x<<'\\n';}\ninline void Out(vector<string> v) {rep(i,SIZE(v)) cout<<v[i]<<'\\n';}\ntemplate<typename T> inline void Out(queue<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop();} cout<<endl;}\ntemplate<typename T> inline void Out(deque<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop_front();} cout<<endl;}\ntemplate<typename T> inline void Out(vector<T> v) {rep(i,SIZE(v)) cout<<v[i]<<(i==SIZE(v)-1?'\\n':' ');}\ntemplate<typename T> inline void Out(vector<vector<T>> &vv){for(auto &v: vv) Out(v);}\ntemplate<typename T> inline void Out(vector<pair<T,T>> v) {for(auto p:v) Out(p);}\ntemplate<typename T> inline void Outend(T x) {Out(x); exit(0);}\ntemplate<typename T> inline void chmin(T &a, T b) { a = min(a, b); }\ntemplate<typename T> inline void chmax(T &a, T b) { a = max(a, b); }\ninline void mi(void) {return;}\ntemplate<typename T1, typename... T2> void mi(T1& f, T2&... r) {--f; mi(r...);}\ntemplate<class... T> void in(T&... x) {(cin >> ... >> x);}\ntemplate<class... T> void inm(T&... x) {(cin >> ... >> x); mi(x...);}\ninline void input_ivec(vi &ivec, int n) {rep(i, n) {cin>>ivec[i];}}\ninline void input_ivecm(vi &ivec, int n) {rep(i, n) {cin>>ivec[i];--ivec[i];}}\ninline void input_lvec(vl &lvec, ll n) {rep(i, n) {cin>>lvec[i];}}\ninline void input_lvecm(vl &lvec, ll n) {rep(i, n) {cin>>lvec[i];--lvec[i];}}\ninline void input_lvec12(vl &lvec1, vl &lvec2, ll n) {rep(i, n) {cin>>lvec1[i]>>lvec2[i];}}\ninline void input_lvec12m(vl &lvec1, vl &lvec2, ll n) {rep(i, n) {cin>>lvec1[i]>>lvec2[i];--lvec1[i];--lvec2[i];}}\ninline void input_cvec(vc &cvec, ll n) {rep (i, n) {cin>>cvec[i];}}\ninline void input_svec(vs &svec, ll n) {rep (i, n) {cin>>svec[i];}}\ninline void input_dvec(vd &dvec, ll n) {rep (i, n) {cin>>dvec[i];}}\ninline void input_pvec(vp &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;}}\ninline void input_pvecm(vp &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;pvec[i].first--,pvec[i].second--;}}\ninline void input_pvecd(vpd &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;}}\ninline void input_ivec2(vvi &ivec2, int h, int w) {rep(i, h) rep(j, w) {cin>>ivec2[i][j];}}\ninline void input_lvec2(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>lvec2[i][j];}}\ninline void input_lvec2m(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>lvec2[i][j];--lvec2[i][j];}}\ninline void input_cvec2(vvc &cvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>cvec2[i][j];}}\ninline bool isin(ll i, ll j, ll h, ll w) {if(i<0||i>=h||j<0||j>=w) return false; else return true;}\ntemplate<typename T> inline T TmpPercent(T a, T b) {if(b<0){a=-a,b=-b;} return (a%b+b)%b;}\ntemplate<typename T> inline T Percent(T a, T b) {if(b<0) return -TmpPercent(a,b); return TmpPercent(a,b);}\ntemplate<typename T> inline T Div(T a, T b) {if(b<0){a=-a,b=-b;} return (a-TmpPercent(a,b))/b; }\ntemplate<typename T> inline T Divceil(T a, T b) {if(TmpPercent(a,b)==0) return Div(a,b); return Div(a,b)+1;}\ntemplate<typename T> void erase(multiset<T> &st, T x) {if(st.contains(x)) st.erase(st.find(x));}\ntemplate<typename T> T pop(vector<T> &x) {T ret=x.back(); x.pop_back(); return ret;}\n#ifdef __DEBUG\n#define de(var) {cerr << #var << \": \"; debug_view(var);}\n#define de2(var1,var2) {cerr<<#var1<<' '<<#var2<<\": \"; debug_view(var1,var2);}\n#define de3(var1,var2,var3) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<\": \"; debug_view(var1,var2,var3);}\n#define de4(var1,var2,var3,var4) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<' '<<#var4<<\": \"; debug_view(var1,var2,var3,var4);}\n#define de5(var1,var2,var3,var4,var5) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<' '<<#var4<<' '<<#var5<<\": \"; debug_view(var1,var2,var3,var4,var5);}\ntemplate<typename T> inline void debug_view(T e){cerr << e << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(T1 e1, T2 e2){cerr<<e1<<' '<<e2<<endl;}\ntemplate<typename T1, typename T2, typename T3> inline void debug_view(T1 e1, T2 e2, T3 e3){cerr<<e1<<' '<<e2<<' '<<e3<<endl;}\ntemplate<typename T1, typename T2, typename T3, typename T4> inline void debug_view(T1 e1, T2 e2, T3 e3, T4 e4){cerr<<e1<<' '<<e2<<' '<<e3<<' '<<e4<<endl;}\ntemplate<typename T1, typename T2, typename T3, typename T4, typename T5> inline void debug_view(T1 e1, T2 e2, T3 e3, T4 e4, T5 e5){cerr<<e1<<' '<<e2<<' '<<e3<<' '<<e4<<' '<<e5<<endl;}\ntemplate<typename T1, typename T2> inline void debug_view(pair<T1,T2> &p){cerr<<\"{\"<<p.first<<\" \"<<p.second<<\"}\\n\";}\ntemplate<typename T1, typename T2> inline void debug_view(vector<pair<T1,T2>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(set<pair<T1,T2>> &s){for(auto [a,b]: s){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(tuple<T,T,T> t){cerr<<get<0>(t)<<' '<<get<1>(t)<<' '<<get<2>(t)<< endl;}\ntemplate<typename T> inline void debug_view(queue<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop();}cerr << endl;}\ntemplate<typename T> inline void debug_view(deque<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop_front();}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(unordered_set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<pair<T,T>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ninline void debug_view(vector<string> &v){cerr << \"----\" << endl; for(auto s: v) debug_view(s);}\ntemplate<typename T> inline void debug_view(vector<T> &v){for(auto e: v){cerr << e << \" \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<pair<T,T>>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<T>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(unordered_map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,vector<T2>> &mp){cerr<<\"----\"<<endl;for(auto [k,v]: mp){cerr<<k<<\": \";debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2,typename T3> inline void debug_view(map<pair<T1,T2>,T3> &mp){cerr << \"----\" << endl;for(auto [p,v]: mp){cerr<<'{'<<p.first<<' '<<p.second<<'}'<<\": \"<<v<<endl;} cerr<<\"--------\"<<endl;}\n#define deb(var) {cerr << #var << \": \"; debugb_view(var);}\ntemplate<typename T> inline void debugb_view(T e){bitset<20> b(e); cerr<<b<<endl;}\ntemplate<typename T> inline void debugb_view(vector<T> &v){cerr<<\"----\"<<endl;for(auto e: v){debugb_view(e);}}\n#else\n#define de(var) {}\n#define de2(var1,var2) {}\n#define de3(var1,var2,var3) {}\n#define de4(var1,var2,var3,var4) {}\n#define de5(var1,var2,var3,var4,var5) {}\n#define deb(var) {}\n#endif\nint IINF = 1001001001;\nll INF = 3e18;\nconst ll M998 = 998244353;\nconst ll M107 = 1000000007;\ntemplate<typename T> inline void ch1(T &x){if(x==INF)x=-1;}\nconst double PI = acos(-1);\nconst double EPS = 1e-8; //eg) if x=1e6, EPS >= 1e6/1e14(=1e-8)\nconst vi di = {0, 1, 0, -1};\nconst vi dj = {1, 0, -1, 0};\nconst vp dij = {{0,1},{1,0},{0,-1},{-1,0}};\nconst vp hex0 = {{-1,-1},{-1,0},{0,-1},{0,1},{1,-1},{1,0}}; // tobide\nconst vp hex1 = {{-1,0},{-1,1},{0,-1},{0,1},{1,0},{1,1}}; // hekomi\nconst vi di8 = {-1, -1, -1, 0, 0, 1, 1, 1};\nconst vi dj8 = {-1, 0, 1, -1, 1, -1, 0, 1};\nconst vp dij8 = {{0,1},{1,0},{0,-1},{-1,0},{1,1},{1,-1},{-1,1},{-1,-1}};\nPr operator+ (Pr a, Pr b) {return {a.first+b.first, a.second+b.second};}\nPr operator- (Pr a, Pr b) {return {a.first-b.first, a.second-b.second};}\nPr operator* (Pr a, Pr b) {return {a.first*b.first, a.second*b.second};}\nPr operator/ (Pr a, Pr b) {return {a.first/b.first, a.second/b.second};}\n\n\nstruct SCC {\n SCC (long long _n): n(_n), from(_n), ifrom(_n) {}\n void add_edge (long long a, long long b) {\n from[a].push_back(b);\n ifrom[b].push_back(a);\n }\n vector<vector<long long>> scc () {\n vector<vector<long long>> group;\n back_num.clear();\n selected.assign(n, false);\n for (long long i=0; i < n; ++i) {\n if (!selected[i]) dfs1(i);\n }\n selected.assign(n, false);\n for (long long i=n-1; i >= 0; --i) {\n long long x = back_num[i];\n if (selected[x]) continue;\n vector<long long> emp;\n dfs2(x, emp);\n group.push_back(emp);\n }\n return group;\n }\nprivate:\n long long n;\n vector<vector<long long>> from, ifrom;\n vector<long long> back_num;\n vector<bool> selected;\n void dfs1 (long long x) {\n selected[x] = true;\n for (auto y: from[x]) {\n if (selected[y]) continue;\n dfs1(y);\n }\n back_num.push_back(x);\n }\n void dfs2 (long long x, vector<long long> &vec) {\n selected[x] = true;\n vec.push_back(x);\n for (auto y: ifrom[x]) {\n if (selected[y]) continue;\n dfs2(y, vec);\n }\n }\n};\n\nvoid solve() {\n LONG(N, M);\n vvl from(N), ifrom(N);\n SCC scc(N);\n rep(i, M) {\n LONG(a, b);\n from[a].emplace_back(b);\n ifrom[b].emplace_back(a);\n scc.add_edge(a,b);\n }\n\n auto grs = scc.scc();\n if(SIZE(grs)==1) Pm0\n\n ll ind=0, outd=0;\n for(auto gr: grs) {\n if(SIZE(gr)==1) {\n if(SIZE(from[gr[0]])==0) ++outd;\n if(SIZE(ifrom[gr[0]])==0) ++ind;\n continue;\n }\n uset<ll> st;\n for(auto v: gr) st.insert(v);\n bool inward=false, outward=false;\n for(auto v: gr) {\n for(auto nv: from[v]) {\n if(st.count(nv)) continue;\n outward = true;\n }\n for(auto nv: ifrom[v]) {\n if(st.count(nv)) continue;\n inward = true;\n }\n }\n if(!inward) ++ind;\n if(!outward) ++outd;\n }\n Out(max(ind,outd));\n\n\n}\n\nint main () {\n // ios::sync_with_stdio(false);\n cin.tie(nullptr);\n solve();\n}\n\n// ### test.cpp ###", "accuracy": 1, "time_ms": 40, "memory_kb": 10520, "score_of_the_acc": -1.406, "final_rank": 16 }, { "submission_id": "aoj_0366_9945936", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n#define rep(i, n) for(int i=0; i<(n); i++)\n\nint N, M;\nint s[100001], t[100001];\nvector<int> G[10001];\nvector<int> rG[10001];\nint deg_in[10001], deg_out[10001];\nbool visit[10001];\nint idx[10001];\n\nvoid add_edge(int from, int to){\n G[from].emplace_back(to);\n rG[to].emplace_back(from);\n}\n\nvoid dfs(int pos, vector<int>& vs){\n visit[pos] = true;\n for(int to : G[pos]){\n if(visit[to]) continue;\n dfs(to, vs);\n }\n vs.emplace_back(pos);\n}\n\nvoid rdfs(int pos, int k){\n visit[pos] = true;\n idx[pos] = k;\n for(int to : rG[pos]){\n if(visit[to]) continue;\n rdfs(to, k);\n }\n}\n\nvoid dfs_dag(int pos){\n visit[pos] = true;\n for(int to : G[pos]){\n if(idx[pos] != idx[to]){\n deg_out[idx[pos]]++;\n deg_in[idx[to]]++;\n }\n if(visit[to]) continue;\n dfs_dag(to);\n }\n}\n\nint scc(){\n rep(i, N){\n visit[i] = false;\n idx[i] = -1;\n }\n vector<int> vs;\n rep(i, N){\n if(!visit[i]) dfs(i, vs);\n }\n rep(i, N) visit[i] = false;\n int k = 0;\n for(int i=N-1; i>=0; i--){\n if(!visit[vs[i]]) rdfs(vs[i], k++);\n }\n rep(i, N) visit[i] = false;\n rep(i, N) if(!visit[i]) dfs_dag(i);\n return k;\n}\n\nint main(){\n cin >> N >> M;\n rep(i, M){\n cin >> s[i] >> t[i];\n add_edge(s[i], t[i]);\n }\n\n int K = scc();\n int cnt_in = 0, cnt_out = 0;\n rep(i, K){\n if(deg_in[i] == 0) cnt_in++;\n if(deg_out[i] == 0) cnt_out++;\n }\n\n int ans = max(cnt_in, cnt_out);\n if(K == 1) ans = 0;\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6880, "score_of_the_acc": -0.7622, "final_rank": 7 }, { "submission_id": "aoj_0366_9709638", "code_snippet": "// ### test.cpp ###\n#include <bits/stdc++.h>\n#ifdef __DEBUG_VECTOR\nnamespace for_debugging{\n struct subscript_and_location{\n int sub;\n std::source_location loc;\n subscript_and_location(int sub_,std::source_location loc_=std::source_location::current()){\n sub=sub_;\n loc=loc_;\n }\n void check_out_of_range(size_t sz){\n if(sub<0||(int)sz<=sub){\n std::clog << loc.file_name() << \":(\" << loc.line() << \":\" << loc.column() << \"):\" << loc.function_name() << std::endl;\n std::clog << \"out of range: subscript = \" << sub << \", vector_size = \" << sz << std::endl;\n exit(EXIT_FAILURE);\n }\n }\n };\n}\nnamespace std{\n template<class T,class Allocator=std::allocator<T>> class vector_for_debugging:public std::vector<T,Allocator>{\n using std::vector<T,Allocator>::vector;\n public:\n [[nodiscard]] constexpr std::vector<T,Allocator>::reference operator[](for_debugging::subscript_and_location n) noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n [[nodiscard]] constexpr std::vector<T,Allocator>::const_reference operator[](for_debugging::subscript_and_location n) const noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n };\n namespace pmr{\n template<class T> using vector_for_debugging=std::vector_for_debugging<T,std::pmr::polymorphic_allocator<T>>;\n }\n}\n#define vector vector_for_debugging\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing sll = __int128_t;\nusing db = double;\nusing Pr = pair<ll, ll>;\nusing Pd = pair<double, double>;\nusing vi = vector<int>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vl = vector<ll>;\nusing vb = vector<bool>;\nusing vd = vector<double>;\nusing vp = vector<Pr>;\nusing vpd = vector<Pd>;\nusing vvi = vector<vector<int>>;\nusing vvc = vector<vector<char>>;\nusing vvl = vector<vector<ll>>;\nusing vvp = vector<vector<Pr>>;\nusing vvb = vector<vector<bool>>;\nusing vvd = vector<vector<double>>;\nusing vvs = vector<vector<string>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvb = vector<vector<vector<bool>>>;\nusing vvvd = vector<vector<vector<double>>>;\nusing t3 = tuple<ll,ll,ll>;\nusing t3d = tuple<db,db,db>;\nusing t4 = tuple<ll,ll,ll,ll>;\nusing vt3 = vector<t3>;\nusing vt3d = vector<t3d>;\nusing vt4 = vector<t4>;\nusing vvt3 = vector<vector<t3>>;\nusing vvt3d = vector<vector<t3d>>;\nusing vvt4 = vector<vector<t4>>;\nusing pq = priority_queue<Pr,vector<Pr>,greater<Pr>>;\nusing cl = complex<ll>;\nusing cd = complex<double>;\n#define rep(i, N) for (ll i=0; i<(ll)(N); i++)\n#define repr(i, N) for (ll i = (ll)(N) - 1; i >= 0; i--)\n#define repk(i, k, N) for (ll i = k; i < (ll)(N); i++)\n#define rep1(i, N) for (ll i=1; i<(ll)(N+1); i++)\n#define all(v) (v).begin(), (v).end()\n#define allr(v) (v).rbegin(), (v).rend()\n#define SIZE(v) (ll)((v).size())\n#define PYes {puts(\"Yes\"); exit(0);}\n#define PNo {puts(\"No\"); exit(0);}\n#define Pm0 {puts(\"0\"); exit(0);}\n#define Pm1 {puts(\"-1\"); exit(0);}\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define INTM(...) int __VA_ARGS__; inm(__VA_ARGS__)\n#define LONG(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define LONGM(...) ll __VA_ARGS__; inm(__VA_ARGS__)\n#define DOUBLE(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define STRING(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define VI(ivec, n) vi ivec(n); input_ivec(ivec, n)\n#define VIM(ivec, n) vi ivec(n); input_ivecm(ivec, n)\n#define VL(lvec, n) vl lvec(n); input_lvec(lvec, n)\n#define VLM(lvec, n) vl lvec(n); input_lvecm(lvec, n)\n#define VL2(lvec1, lvec2, n) vl lvec1(n), lvec2(n); input_lvec12(lvec1, lvec2, n)\n#define VL2M(lvec1, lvec2, n) vl lvec1(n), lvec2(n); input_lvec12m(lvec1, lvec2, n)\n#define VC(cvec, n) vc cvec(n); input_cvec(cvec, n)\n#define VS(svec, n) vs svec(n); input_svec(svec, n)\n#define VD(dvec, n) vd dvec(n); input_dvec(dvec, n)\n#define VP(pvec, n) vp pvec(n); input_pvec(pvec, n)\n#define VPD(pvec, n) vpd pvec(n); input_pvecd(pvec, n)\n#define VPM(pvec, n) vp pvec(n); input_pvecm(pvec, n)\n#define VVI(ivec2, h, w) vvi ivec2(h, vi(w)); input_ivec2(ivec2, h, w)\n#define VVL(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2(lvec2, h, w)\n#define VVLM(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2m(lvec2, h, w)\n#define VVC(cvec2, h, w) vvc cvec2(h, vc(w)); input_cvec2(cvec2, h, w)\n#define pcnt(x) (ll)__builtin_popcountll(x)\n#define parity(x) (ll)__builtin_parityll(x)\n#define uset unordered_set\n#define umap unordered_map\ninline void Out(double x) {printf(\"%.15f\",x);cout<<'\\n';}\ntemplate<typename T> inline void Out(pair<T,T> x) {cout<<x.first<<' '<<x.second<<'\\n';}\ntemplate<typename T> inline void Out(T x) {cout<<x<<'\\n';}\ninline void Out(vector<string> v) {rep(i,SIZE(v)) cout<<v[i]<<'\\n';}\ntemplate<typename T> inline void Out(queue<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop();} cout<<endl;}\ntemplate<typename T> inline void Out(deque<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop_front();} cout<<endl;}\ntemplate<typename T> inline void Out(vector<T> v) {rep(i,SIZE(v)) cout<<v[i]<<(i==SIZE(v)-1?'\\n':' ');}\ntemplate<typename T> inline void Out(vector<vector<T>> &vv){for(auto &v: vv) Out(v);}\ntemplate<typename T> inline void Out(vector<pair<T,T>> v) {for(auto p:v) Out(p);}\ntemplate<typename T> inline void Outend(T x) {Out(x); exit(0);}\ntemplate<typename T> inline void chmin(T &a, T b) { a = min(a, b); }\ntemplate<typename T> inline void chmax(T &a, T b) { a = max(a, b); }\ninline void mi(void) {return;}\ntemplate<typename T1, typename... T2> void mi(T1& f, T2&... r) {--f; mi(r...);}\ntemplate<class... T> void in(T&... x) {(cin >> ... >> x);}\ntemplate<class... T> void inm(T&... x) {(cin >> ... >> x); mi(x...);}\ninline void input_ivec(vi &ivec, int n) {rep(i, n) {cin>>ivec[i];}}\ninline void input_ivecm(vi &ivec, int n) {rep(i, n) {cin>>ivec[i];--ivec[i];}}\ninline void input_lvec(vl &lvec, ll n) {rep(i, n) {cin>>lvec[i];}}\ninline void input_lvecm(vl &lvec, ll n) {rep(i, n) {cin>>lvec[i];--lvec[i];}}\ninline void input_lvec12(vl &lvec1, vl &lvec2, ll n) {rep(i, n) {cin>>lvec1[i]>>lvec2[i];}}\ninline void input_lvec12m(vl &lvec1, vl &lvec2, ll n) {rep(i, n) {cin>>lvec1[i]>>lvec2[i];--lvec1[i];--lvec2[i];}}\ninline void input_cvec(vc &cvec, ll n) {rep (i, n) {cin>>cvec[i];}}\ninline void input_svec(vs &svec, ll n) {rep (i, n) {cin>>svec[i];}}\ninline void input_dvec(vd &dvec, ll n) {rep (i, n) {cin>>dvec[i];}}\ninline void input_pvec(vp &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;}}\ninline void input_pvecm(vp &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;pvec[i].first--,pvec[i].second--;}}\ninline void input_pvecd(vpd &pvec, ll n) {rep (i, n) {cin>>pvec[i].first>>pvec[i].second;}}\ninline void input_ivec2(vvi &ivec2, int h, int w) {rep(i, h) rep(j, w) {cin>>ivec2[i][j];}}\ninline void input_lvec2(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>lvec2[i][j];}}\ninline void input_lvec2m(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>lvec2[i][j];--lvec2[i][j];}}\ninline void input_cvec2(vvc &cvec2, ll h, ll w) {rep(i, h) rep(j, w) {cin>>cvec2[i][j];}}\ninline bool isin(ll i, ll j, ll h, ll w) {if(i<0||i>=h||j<0||j>=w) return false; else return true;}\ninline ll TmpPercent(ll a, ll b) {if(b<0){a=-a,b=-b;} return (a%b+b)%b;}\ninline ll Percent(ll a, ll b) {if(b<0) return -TmpPercent(a,b); return TmpPercent(a,b);}\ninline ll Div(ll a, ll b) {if(b<0){a=-a,b=-b;} return (a-TmpPercent(a,b))/b; }\ninline ll Divceil(ll a, ll b) {if(TmpPercent(a,b)==0) return Div(a,b); return Div(a,b)+1;}\n#ifdef __DEBUG\n#define de(var) {cerr << #var << \": \"; debug_view(var);}\n#define de2(var1,var2) {cerr<<#var1<<' '<<#var2<<\": \"; debug_view(var1,var2);}\n#define de3(var1,var2,var3) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<\": \"; debug_view(var1,var2,var3);}\n#define de4(var1,var2,var3,var4) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<' '<<#var4<<\": \"; debug_view(var1,var2,var3,var4);}\ntemplate<typename T> inline void debug_view(T e){cerr << e << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(T1 e1, T2 e2){cerr<<e1<<' '<<e2<<endl;}\ntemplate<typename T1, typename T2, typename T3> inline void debug_view(T1 e1, T2 e2, T3 e3){cerr<<e1<<' '<<e2<<' '<<e3<<endl;}\ntemplate<typename T1, typename T2, typename T3, typename T4> inline void debug_view(T1 e1, T2 e2, T3 e3, T4 e4){cerr<<e1<<' '<<e2<<' '<<e3<<' '<<e4<<endl;}\ntemplate<typename T1, typename T2> inline void debug_view(pair<T1,T2> &p){cerr<<\"{\"<<p.first<<\" \"<<p.second<<\"}\\n\";}\ntemplate<typename T1, typename T2> inline void debug_view(vector<pair<T1,T2>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(set<pair<T1,T2>> &s){for(auto [a,b]: s){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(tuple<T,T,T> t){cerr<<get<0>(t)<<' '<<get<1>(t)<<' '<<get<2>(t)<< endl;}\ntemplate<typename T> inline void debug_view(queue<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop();}cerr << endl;}\ntemplate<typename T> inline void debug_view(deque<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop_front();}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(unordered_set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<pair<T,T>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ninline void debug_view(vector<string> &v){cerr << \"----\" << endl; for(auto s: v) debug_view(s);}\ntemplate<typename T> inline void debug_view(vector<T> &v){for(auto e: v){cerr << e << \" \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<pair<T,T>>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<T>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(unordered_map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,vector<T2>> &mp){cerr<<\"----\"<<endl;for(auto [k,v]: mp){cerr<<k<<\": \";debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2,typename T3> inline void debug_view(map<pair<T1,T2>,T3> &mp){cerr << \"----\" << endl;for(auto [p,v]: mp){cerr<<'{'<<p.first<<' '<<p.second<<'}'<<\": \"<<v<<endl;} cerr<<\"--------\"<<endl;}\n#define deb(var) {cerr << #var << \": \"; debugb_view(var);}\ntemplate<typename T> inline void debugb_view(T e){bitset<20> b(e); cerr<<b<<endl;}\ntemplate<typename T> inline void debugb_view(vector<T> &v){cerr<<\"----\"<<endl;for(auto e: v){debugb_view(e);}}\n#else\n#define de(var) {}\n#define de2(var1,var2) {}\n#define de3(var1,var2,var3) {}\n#define de4(var1,var2,var3,var4) {}\n#define deb(var) {}\n#endif\nll INF = 3e18;\nconst ll M998 = 998244353;\nconst ll M107 = 1000000007;\ntemplate<typename T> inline void ch1(T &x){if(x==INF)x=-1;}\nconst double PI = acos(-1);\nconst double EPS = 1e-8; //eg) if x=1e9, EPS >= 1e9/1e15(=1e-6)\nconst vi di = {0, 1, 0, -1};\nconst vi dj = {1, 0, -1, 0};\nconst vp dij = {{0,1},{1,0},{0,-1},{-1,0}};\nconst vi di8 = {-1, -1, -1, 0, 0, 1, 1, 1};\nconst vi dj8 = {-1, 0, 1, -1, 1, -1, 0, 1};\nPr operator+ (Pr a, Pr b) {return {a.first+b.first, a.second+b.second};}\nPr operator- (Pr a, Pr b) {return {a.first-b.first, a.second-b.second};}\nPr operator* (Pr a, Pr b) {return {a.first*b.first, a.second*b.second};}\nPr operator/ (Pr a, Pr b) {return {a.first/b.first, a.second/b.second};}\nstruct SCC {\n SCC (long long _n): n(_n), from(_n), ifrom(_n) {}\n void add_edge (long long a, long long b) {\n from[a].push_back(b);\n ifrom[b].push_back(a);\n }\n vector<vector<long long>> scc () {\n vector<vector<long long>> group;\n back_num.clear();\n selected.assign(n, false);\n for (long long i=0; i < n; ++i) {\n if (!selected[i]) dfs1(i);\n }\n selected.assign(n, false);\n for (long long i=n-1; i >= 0; --i) {\n long long x = back_num[i];\n if (selected[x]) continue;\n vector<long long> emp;\n dfs2(x, emp);\n group.push_back(emp);\n }\n return group;\n }\nprivate:\n long long n;\n vector<vector<long long>> from, ifrom;\n vector<long long> back_num;\n vector<bool> selected;\n void dfs1 (long long x) {\n selected[x] = true;\n for (auto y: from[x]) {\n if (selected[y]) continue;\n dfs1(y);\n }\n back_num.push_back(x);\n }\n void dfs2 (long long x, vector<long long> &vec) {\n selected[x] = true;\n vec.push_back(x);\n for (auto y: ifrom[x]) {\n if (selected[y]) continue;\n dfs2(y, vec);\n }\n }\n};\n\n\nint main () {\n // ios::sync_with_stdio(false);\n cin.tie(nullptr);\n LONG(N, M);\n vvl from(N), ifrom(N);\n SCC scc(N);\n rep(i, M) {\n LONG(a,b);\n from[a].push_back(b);\n ifrom[b].push_back(a);\n scc.add_edge(a,b);\n }\n\n auto grs = scc.scc();\n if(SIZE(grs)==1) Pm0\n\n vb used(N);\n ll outnum = 0, innum = 0;\n for(auto gr: grs) {\n for(auto v: gr) used[v] = true;\n bool indeg=false, outdeg=false;\n for(auto v: gr) {\n for(auto nv: from[v]) {\n if(used[nv]) continue;\n outdeg=true;\n }\n }\n for(auto v: gr) {\n for(auto nv: ifrom[v]) {\n if(used[nv]) continue;\n indeg=true;\n }\n }\n if(!outdeg) outnum++;\n if(!indeg) innum++;\n for(auto v: gr) used[v] = false;\n de(gr)\n de2(outdeg, indeg)\n }\n de2(outnum, innum)\n\n Out(max(outnum, innum));\n \n}\n\n// ### test.cpp ###", "accuracy": 1, "time_ms": 30, "memory_kb": 10368, "score_of_the_acc": -1.0597, "final_rank": 11 }, { "submission_id": "aoj_0366_9639320", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cstring>\n#include <utility>\n\nusing namespace std;\nusing ll = long long;\nusing info = pair<int, int>;\n\n#define rep(i, N) for (int i = 0; i < N; ++i)\n#define maxn 10009\n#define maxe 100009\n\nint mark[maxn];\nvector<int> g[maxn], rg[maxn];\nvector<int> Eus(maxe), Ev(maxe);\n\nvoid dfs(int v, vector<int> *g, vector<int> &vec)\n{\n mark[v] = 1;\n for (auto u : g[v])\n if (!mark[u])\n dfs(u, g, vec);\n vec.push_back(v);\n}\n\nint main()\n{\n int n, m;\n cin >> n >> m;\n rep(i, m)\n {\n int s, t;\n cin >> s >> t;\n Eus[i] = s;\n Ev[i] = t;\n g[s].push_back(t);\n rg[t].push_back(s);\n }\n // step1 sccを行う\n vector<int> alls;\n for (int i = 0; i < n; i++)\n {\n if (!mark[i])\n dfs(i, g, alls);\n }\n memset(mark, 0, sizeof mark);\n std::reverse(alls.begin(), alls.end());\n int gp = 1;\n for (auto v : alls)\n {\n if (mark[v])\n continue;\n vector<int> comp;\n dfs(v, rg, comp);\n for (int g : comp)\n {\n mark[g] = gp;\n }\n gp++;\n }\n /*rep(i, n) cout << mark[i] << \" \";\n cout << endl; */\n if (gp == 2)\n {\n cout << 0 << endl;\n return 0;\n }\n // step2 新しい有向グラフを構成する(ただし、入次数と出次数のみ管理)\n vector<info> sugar_newG(gp, info{0, 0});\n rep(i, m)\n {\n int u = Eus[i], v = Ev[i];\n if (mark[u] == mark[v])\n continue;\n sugar_newG[mark[u]].first++;\n sugar_newG[mark[v]].second++;\n }\n ll indig = 0, outdig = 0;\n for (int i = 1; i < gp; ++i)\n {\n if (sugar_newG[i].first == 0)\n outdig++;\n if (sugar_newG[i].second == 0)\n indig++;\n }\n cout << max(indig, outdig) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6704, "score_of_the_acc": -0.7472, "final_rank": 6 }, { "submission_id": "aoj_0366_9574656", "code_snippet": "#pragma region Macros\n \n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2,popcnt\")\n \n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n \n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n \n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n \n// #define next asdnext\n// #define prev asdprev\n \nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\nconst int MOD = 998244353;\n// const int MOD = 1000000007;\n \nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n \nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n \n#define EC int\nstruct Edge {\n int from, to;\n EC cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, EC cost) : to(to), cost(cost) {}\n Edge(int from, int to, EC cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n bool operator <(const Edge& e) { return this->cost < e.cost; }\n bool operator >(const Edge& e) { return this->cost > e.cost; }\n};\n \nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n \nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int() {\n return dist_x(rng);\n }\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n\nnamespace bit_function {\n using i64 = ll;\n // using i64 = uint64_t;\n // bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\n i64 lrmask(int l, int r) { return (1LL << r) - (1LL << l); }\n i64 sub_bit(i64 x, int l, int r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\n i64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n \n i64 popcount(i64 x) { return __builtin_popcountll(x); }\n i64 popcount(i64 x, int l, int r) { return __builtin_popcountll(sub_bit(x, l, r)); }\n i64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); } // 最上位bitより下のみ\n i64 unpopcount(i64 x, int l, int r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); } // 最上位bitより上も含まれうる\n bool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; } // xが負のときは常にfalse\n bool is_pow4(i64 x) { return __builtin_popcountll(x) == 1 && __builtin_ctz(x) % 2 == 0; }\n //bool is_pow4(ll x) { return __builtin_popcountll(x) == 1 && (x&0x55555555); }\n \n int top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\n int bot_bit(i64 x) { return __builtin_ctzll(x);} // 2^kの位 (x > 0)\n int next_bit(i64 x, int k) { // upper_bound\n x >>= (k + 1);\n int pos = k + 1;\n while (x > 0) {\n if (x & 1) return pos;\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int prev_bit(i64 x, int k) {\n // k = min(k, bit_width(x)); ?\n int pos = 0;\n while (x > 0 && pos < k) {\n if (x & 1) {\n if (pos < k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int kth_bit(i64 x, int k) { // kは1-indexed\n int pos = 0, cnt = 0;\n while (x > 0) {\n if (x & 1) {\n cnt++;\n if (cnt == k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n i64 msb(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\n i64 lsb(i64 x) { return (x & -x); } // mask\n \n int countl_zero(i64 x) { return __builtin_clzll(x); }\n int countl_one(i64 x) { // countl_oneと定義が異なるので注意\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n }\n int countr_zero(i64 x) { return __builtin_ctzll(x); } // x=0のとき64\n int countr_one(i64 x) { int ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n // int countr_one(ll x) { return __builtin_popcount(x ^ (x & -~x));\n\n i64 l_one(i64 x) { // 最上位で連なってる1のmask\n if (x == 0) return 0;\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { ret += 1LL << k; k--; }\n return ret;\n }\n \n int floor_log2(i64 x) { return 63 - __builtin_clzll(x); } // top_bit\n int ceil_log2(i64 x) { return 64 - __builtin_clzll(x - 1); }\n i64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // msb\n i64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n \n i64 rotl(i64 x, int k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\n i64 rotr(i64 x, int k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\n i64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n }\n // i64 bit_reverse(i64 x, int l, int r) {}\n \n bool is_palindrome(i64 x) { return x == bit_reverse(x); }\n bool is_palindrome(i64 x, int l, int r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\n i64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\n i64 erase(i64 x, int l, int r) { return x >> r << l | x & ((1LL << l) - 1); } // [l, r) をカット\n \n i64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\n i64 hamming(i64 a, i64 b, int l, int r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\n i64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\n i64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\n i64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n \n i64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctzll(x) + 1));\n }\n} using namespace bit_function;\n\nnamespace util_function {\n namespace Std = std;\n __int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n // assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n // assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n }\n int per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n }\n int mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n return x - y * per(x, y);\n } // https://yukicoder.me/problems/no/2781\n int floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n }\n int ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n }\n int round(int x, int y) { // (ld)(x/y)を小数点第1位について四捨五入\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n }\n int round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0 && k >= 0);\n if (k == 0) return (x * 2 + y) / (y * 2);\n x /= y * POW(10, k - 1);\n if (x % 10 >= 5) return (x + 10 - x % 10) * POW(10, k - 1);\n return x * POW(10, k - 1);\n }\n int round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = x / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n }\n ld round(ld x, int k) { // xを10^kの位に関して四捨五入. to_string(x, k)優先\n // x += EPS;\n ld d = pow(10, -k);\n return Std::round(x * d) / d;\n }\n ld floor(ld x, int k) { // xを10^kの位に関してflooring\n // x += EPS;\n ld d = pow(10, -k);\n return Std::floor(x * d) / d; // 未verify\n }\n ld ceil(ld x, int k) { // xを10^kの位に関してceiling\n // x -= EPS;\n ld d = pow(10, -k);\n return Std::ceil(x * d) / d; // 未verify\n }\n // int kth(int x, int y, int k) { // x / yの10^kの位の桁\n // }\n int floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return Std::floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n }\n int ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return Std::ceil(x / y);\n // ceil(x) = floor(x + 1)\n }\n int perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return Std::floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -Std::floor(x / fabs(y));\n if (x < 0 && y < 0) return Std::floor(x / y) + (x - Std::floor(x/y)*y < -EPS);\n return Std::floor(x / y) - (x - Std::floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n }\n ld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n }\n int seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\n int modf(ld x) {\n if (x < 0) return ceill(x);\n else return floorl(x);\n }\n // 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\n int seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n }\n int seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n }\n\n int floor_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now <= x) {\n now *= base;\n if (now <= x) ret++;\n }\n return ret;\n }\n int ceil_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now < x) {\n now *= base;\n ret++;\n }\n return ret;\n }\n\n template <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n }\n template <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n }\n \n template <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n }\n template <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n }\n template <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - Std::max({a, b, c}) - Std::min({a, b, c});\n }\n template <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) if (a > b) swap(a, b);\n else if (b > a) swap(b, a);\n }\n template <typename T, typename... Args>\n void Sort(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.begin(), vec.end());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n template <typename T, typename... Args>\n void Sortr(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.rbegin(), vec.rend());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n\n istream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n }\n ostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n }\n \n __int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n }\n __int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n __int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n }\n \n string to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n \n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n }\n string to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n }\n string to_string(char c) { string s = \"\"; s += c; return s; }\n} using namespace util_function;\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n \n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n \n#pragma endregion\n\ntemplate <class E> struct csr {\n vector<int> start;\n vector<E> elist;\n explicit csr(int n, const vector<pair<int, E>> &edges)\n : start(n + 1), elist(edges.size()) {\n for (auto e : edges) {\n start[e.first + 1]++;\n }\n for (int i = 1; i <= n; i++) {\n start[i] += start[i - 1];\n }\n auto counter = start;\n for (auto e : edges) {\n elist[counter[e.first]++] = e.second;\n }\n }\n};\n\nstruct _scc_graph {\npublic:\n explicit _scc_graph(int n) : _n(n) {}\n\n int num_vertices() { return _n; }\n\n void add_edge(int from, int to) { edges.push_back({from, {to}}); }\n\n pair<int, vector<int>> scc_ids() {\n auto g = csr<edge>(_n, edges);\n int now_ord = 0, group_num = 0;\n vector<int> visited, low(_n), ord(_n, -1), ids(_n);\n visited.reserve(_n);\n auto dfs = [&](auto self, int v) -> void {\n low[v] = ord[v] = now_ord++;\n visited.push_back(v);\n for (int i = g.start[v]; i < g.start[v + 1]; i++) {\n auto to = g.elist[i].to;\n if (ord[to] == -1) {\n self(self, to);\n low[v] = min(low[v], low[to]);\n } else {\n low[v] = min(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (true) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = _n;\n ids[u] = group_num;\n if (u == v) break;\n }\n group_num++;\n }\n };\n for (int i = 0; i < _n; i++) {\n if (ord[i] == -1) dfs(dfs, i);\n }\n for (auto& x : ids) {\n x = group_num - 1 - x;\n }\n return {group_num, ids};\n }\n\n vector<vector<int>> scc() {\n ids = scc_ids();\n int group_num = ids.first;\n vector<int> counts(group_num);\n for (auto x : ids.second) counts[x]++;\n vector<vector<int>> groups(ids.first);\n for (int i = 0; i < group_num; i++) {\n groups[i].reserve(counts[i]);\n }\n for (int i = 0; i < _n; i++) {\n groups[ids.second[i]].push_back(i);\n }\n return groups;\n }\n\npublic:\n int _n;\n pair<int, vector<int>> ids;\nprivate:\n struct edge {\n int to;\n };\n vector<pair<int, edge>> edges;\n};\n\nstruct scc_graph {\npublic:\n scc_graph() : internal(0) {}\n explicit scc_graph(int n) : internal(n) {}\n\n void add_edge(int from, int to) {\n int n = internal.num_vertices();\n assert(0 <= from && from < n);\n assert(0 <= to && to < n);\n internal.add_edge(from, to);\n E.pb(make_pair(from, to));\n }\n\n vector<vector<int>> DAG() {\n int new_n = internal.ids.first; // 圧縮後の頂点数\n\n scc_id();\n \n vector<vector<int>> ret(new_n);\n indeg.resize(new_n);\n outdeg.resize(new_n);\n for (int i = 0; i < (int)E.size(); i++) {\n int u = E[i].first;\n int v = E[i].second;\n if (u == v) continue;\n if (ids[u] != ids[v]) {\n if (mp[minmax(ids[u], ids[v])]) continue;\n ret[ids[u]].pb(ids[v]);\n indeg[ids[v]]++;\n outdeg[ids[u]]++;\n mp[minmax(ids[u], ids[v])]++;\n }\n }\n return ret;\n }\n\n vector<vector<int>> scc() { return internal.scc(); }\n\n vector<int> scc_id() {\n ids = internal.ids.second;\n return ids; \n }\n\n vector<vector<int>> rev(const vector<vector<int>> &G) {\n int N = G.size();\n vector<vector<int>> G2(N);\n for (int i = 0; i < N; i++) {\n for (auto nv : G[i]) {\n G2[nv].pb(i);\n }\n }\n return G2;\n }\n\npublic:\n vector<pair<int, int>> E;\n vector<int> indeg, outdeg; // 再構築したグラフの入次数, 出次数\nprivate:\n _scc_graph internal;\n vector<int> ids;\n unordered_map<pair<int, int>, int> mp;\n};\n\nsigned main() {\n int N, M;\n cin >> N >> M;\n\n scc_graph G(N);\n for (int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n // u--; v--;\n G.add_edge(u, v);\n }\n\n // 各強連結成分の頂点集合(Sはトポロジカル順)\n vector<vector<int>> S = G.scc();\n\n // 強連結成分の個数\n \tint k = S.size();\n\n if (k == 1) {\n cout << 0 << endl;\n return 0;\n }\n\n // scc[i] := 頂点iの属す強連結成分の番号\n vector<int> scc = G.scc_id();\n \n // 強連結成分ごとに押しつぶしたグラフ(DAG)\n vector<vector<int>> G2 = G.DAG();\n\n int a = 0, b = 0;\n\n for (auto &x : G.indeg) {\n if (x == 0) a++;\n }\n for (auto &x : G.outdeg) {\n if (x == 0) b++;\n }\n cout << max(a, b) << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 14516, "score_of_the_acc": -1.0802, "final_rank": 12 }, { "submission_id": "aoj_0366_9573324", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct SCC {\n\tlong long n;\n\tvector<vector<pair<long long,long long>>> g;\n\tstack<long long> s;\n\tvector<long long> c;\n\tvector<vector<long long>> r;\n\tSCC(vector<vector<long long>> g) : n(g.size()) {\n\t\tthis->g.resize(g.size(),{});\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tif(g[i].empty()) continue;\n\t\t\tfor(long long j : g[i]){\n\t\t\t\tthis->g[i].push_back({j,true});\n\t\t\t\tthis->g[j].push_back({i,false});\n\t\t\t}\n\t\t}\n\t}\n\tvector<vector<long long>> get(){\n\t\tc.resize(n,false);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tif(!c[i]){\n\t\t\t\tdfs(i);\n\t\t\t}\n\t\t}\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tc[i] = false;\n\t\t}\n\t\tr = {};\n\t\twhile(!s.empty()){\n\t\t\tlong long it = s.top();\n\t\t\ts.pop();\n\t\t\tif(!c[it]){\n\t\t\t\tr.push_back({});\n\t\t\t\tdfs2(it);\n\t\t\t}\n\t\t}\n\t\treturn r;\n\t}\n\tvoid dfs(long long x){\n\t\tc[x] = true;\n\t\tif(!g[x].empty()){\n\t\t\tfor(pair<long long,long long> i : g[x]){\n\t\t\t\tif(!i.second) continue;\n\t\t\t\tif(c[i.first]) continue;\n\t\t\t\tdfs(i.first);\n\t\t\t}\n\t\t}\n\t\ts.push(x);\n\t}\n\tvoid dfs2(long long x){\n\t\tc[x] = true;\n\t\tr.back().push_back(x);\n\t\tif(g[x].empty()) return;\n\t\tfor(pair<long long,long long> i : g[x]){\n\t\t\tif(i.second) continue;\n\t\t\tif(c[i.first]) continue;\n\t\t\tdfs2(i.first);\n\t\t}\n\t}\n};\nint main()\n{\n\tlong long n,m;\n\tcin >> n >> m;\n\tvector<vector<long long>> g(n,vector<long long>());\n\tfor(long long i = 0ll;i < m;i++){\n\t\tlong long u,v;\n\t\tcin >> u >> v;\n\t\tg[u].push_back(v);\n\t}\n\tSCC sg(g);\n\tvector<vector<long long>> it = sg.get();\n\tvector<long long> t(n);\n\tvector<pair<long long,long long>> cou(it.size(),pair<long long,long long>(0ll,0ll));\n\tif((long long)it.size() == 1ll){\n\t\tcout << 0ll << endl;\n\t\texit(0ll);\n\t}\n\tfor(long long i = 0ll;i < (long long)it.size();i++){\n\t\tfor(long long j : it[i]){\n\t\t\tt[j] = i;\n\t\t}\n\t}\n\tfor(long long i = 0ll;i < n;i++){\n\t\tif(!g[i].empty()){\n\t\t\tfor(long long j : g[i]){\n\t\t\t\tif(t[i] != t[j]){\n\t\t\t\t\tcou[t[i]].first++;\n\t\t\t\t\tcou[t[j]].second++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tpair<long long,long long> p(0ll,0ll);\n\tfor(long long i = 0ll;i < (long long)cou.size();i++){\n\t\tif(cou[i].first == 0ll){\n\t\t\tp.first++;\n\t\t}\n\t\tif(cou[i].second == 0ll){\n\t\t\tp.second++;\n\t\t}\n\t}\n\tlong long ans = max(p.first,p.second);\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 11572, "score_of_the_acc": -1.1624, "final_rank": 13 }, { "submission_id": "aoj_0366_9573292", "code_snippet": "#include <bits/stdc++.h>\n\n#include <algorithm>\n\n#include <algorithm>\n#include <utility>\n#include <vector>\n\nnamespace atcoder {\nnamespace internal {\n\ntemplate <class E> struct csr {\n std::vector<int> start;\n std::vector<E> elist;\n csr(int n, const std::vector<std::pair<int, E>>& edges)\n : start(n + 1), elist(edges.size()) {\n for (auto e : edges) {\n start[e.first + 1]++;\n }\n for (int i = 1; i <= n; i++) {\n start[i] += start[i - 1];\n }\n auto counter = start;\n for (auto e : edges) {\n elist[counter[e.first]++] = e.second;\n }\n }\n};\n\n// Reference:\n// R. Tarjan,\n// Depth-First Search and Linear Graph Algorithms\nstruct scc_graph {\n public:\n scc_graph(int n) : _n(n) {}\n\n int num_vertices() { return _n; }\n\n void add_edge(int from, int to) { edges.push_back({from, {to}}); }\n\n // @return pair of (# of scc, scc id)\n std::pair<int, std::vector<int>> scc_ids() {\n auto g = csr<edge>(_n, edges);\n int now_ord = 0, group_num = 0;\n std::vector<int> visited, low(_n), ord(_n, -1), ids(_n);\n visited.reserve(_n);\n auto dfs = [&](auto self, int v) -> void {\n low[v] = ord[v] = now_ord++;\n visited.push_back(v);\n for (int i = g.start[v]; i < g.start[v + 1]; i++) {\n auto to = g.elist[i].to;\n if (ord[to] == -1) {\n self(self, to);\n low[v] = std::min(low[v], low[to]);\n } else {\n low[v] = std::min(low[v], ord[to]);\n }\n }\n if (low[v] == ord[v]) {\n while (true) {\n int u = visited.back();\n visited.pop_back();\n ord[u] = _n;\n ids[u] = group_num;\n if (u == v) break;\n }\n group_num++;\n }\n };\n for (int i = 0; i < _n; i++) {\n if (ord[i] == -1) dfs(dfs, i);\n }\n for (auto& x : ids) {\n x = group_num - 1 - x;\n }\n return {group_num, ids};\n }\n\n std::vector<std::vector<int>> scc() {\n auto ids = scc_ids();\n int group_num = ids.first;\n std::vector<int> counts(group_num);\n for (auto x : ids.second) counts[x]++;\n std::vector<std::vector<int>> groups(ids.first);\n for (int i = 0; i < group_num; i++) {\n groups[i].reserve(counts[i]);\n }\n for (int i = 0; i < _n; i++) {\n groups[ids.second[i]].push_back(i);\n }\n return groups;\n }\n\n private:\n int _n;\n struct edge {\n int to;\n };\n std::vector<std::pair<int, edge>> edges;\n};\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <vector>\n\nnamespace atcoder {\n\nstruct scc_graph {\n public:\n scc_graph() : internal(0) {}\n scc_graph(int n) : internal(n) {}\n\n void add_edge(int from, int to) {\n int n = internal.num_vertices();\n assert(0 <= from && from < n);\n assert(0 <= to && to < n);\n internal.add_edge(from, to);\n }\n\n std::vector<std::vector<int>> scc() { return internal.scc(); }\n\n private:\n internal::scc_graph internal;\n};\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\n\nint main()\n{\n\tint n,m;\n\tcin >> n >> m;\n\tscc_graph sg(n);\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < m;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tsg.add_edge(u,v);\n\t\tg[u].push_back(v);\n\t}\n\tvector<vector<int>> it = sg.scc();\n\tvector<int> t(n);\n\tvector<pair<int,int>> cou(it.size(),pair<int,int>(0,0));\n\tif((int)it.size() == 1){\n\t\tcout << 0 << endl;\n\t\texit(0);\n\t}\n\tfor(int i = 0;i < (int)it.size();i++){\n\t\tfor(int j : it[i]){\n\t\t\tt[j] = i;\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tif(!g[i].empty()){\n\t\t\tfor(int j : g[i]){\n\t\t\t\tif(t[i] != t[j]){\n\t\t\t\t\tcou[t[i]].first++;\n\t\t\t\t\tcou[t[j]].second++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tpair<int,int> p(0,0);\n\tfor(int i = 0;i < (int)cou.size();i++){\n\t\tif(cou[i].first == 0){\n\t\t\tp.first++;\n\t\t}\n\t\tif(cou[i].second == 0){\n\t\t\tp.second++;\n\t\t}\n\t}\n\tint ans = max(p.first,p.second);\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6896, "score_of_the_acc": -0.7636, "final_rank": 8 }, { "submission_id": "aoj_0366_9571749", "code_snippet": "// ### test.cpp ###\n#include <bits/stdc++.h>\n#ifdef __DEBUG_VECTOR\nnamespace for_debugging{\n struct subscript_and_location{\n int sub;\n std::source_location loc;\n subscript_and_location(int sub_,std::source_location loc_=std::source_location::current()){\n sub=sub_;\n loc=loc_;\n }\n void check_out_of_range(size_t sz){\n if(sub<0||(int)sz<=sub){\n std::clog << loc.file_name() << \":(\" << loc.line() << \":\" << loc.column() << \"):\" << loc.function_name() << std::endl;\n std::clog << \"out of range: subscript = \" << sub << \", vector_size = \" << sz << std::endl;\n exit(EXIT_FAILURE);\n }\n }\n };\n}\nnamespace std{\n template<class T,class Allocator=std::allocator<T>> class vector_for_debugging:public std::vector<T,Allocator>{\n using std::vector<T,Allocator>::vector;\n public:\n [[nodiscard]] constexpr std::vector<T,Allocator>::reference operator[](for_debugging::subscript_and_location n) noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n [[nodiscard]] constexpr std::vector<T,Allocator>::const_reference operator[](for_debugging::subscript_and_location n) const noexcept(!std::is_same<T,bool>::value){\n n.check_out_of_range(this->size());\n return std::vector<T,Allocator>::operator[](n.sub);\n }\n };\n namespace pmr{\n template<class T> using vector_for_debugging=std::vector_for_debugging<T,std::pmr::polymorphic_allocator<T>>;\n }\n}\n#define vector vector_for_debugging\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing db = double;\nusing Pr = pair<ll, ll>;\nusing Pd = pair<double, double>;\nusing vi = vector<int>;\nusing vs = vector<string>;\nusing vc = vector<char>;\nusing vl = vector<ll>;\nusing vb = vector<bool>;\nusing vd = vector<double>;\nusing vp = vector<Pr>;\nusing vpd = vector<Pd>;\nusing vvi = vector<vector<int>>;\nusing vvc = vector<vector<char>>;\nusing vvl = vector<vector<ll>>;\nusing vvp = vector<vector<Pr>>;\nusing vvb = vector<vector<bool>>;\nusing vvd = vector<vector<double>>;\nusing vvs = vector<vector<string>>;\nusing vvvi = vector<vector<vector<int>>>;\nusing vvvl = vector<vector<vector<ll>>>;\nusing vvvb = vector<vector<vector<bool>>>;\nusing vvvd = vector<vector<vector<double>>>;\nusing t3 = tuple<ll,ll,ll>;\nusing t4 = tuple<ll,ll,ll,ll>;\nusing vt3 = vector<t3>;\nusing vt4 = vector<t4>;\nusing vvt3 = vector<vector<t3>>;\nusing vvt4 = vector<vector<t4>>;\nusing pq = priority_queue<Pr,vector<Pr>,greater<Pr>>;\nusing cl = complex<ll>;\nusing cd = complex<double>;\n#define rep(i, N) for (ll i=0; i<(ll)(N); i++)\n#define repr(i, N) for (ll i = (ll)(N) - 1; i >= 0; i--)\n#define repk(i, k, N) for (ll i = k; i < (ll)(N); i++)\n#define rep1(i, N) for (ll i=1; i<(ll)(N+1); i++)\n#define all(v) (v).begin(), (v).end()\n#define allr(v) (v).rbegin(), (v).rend()\n#define SIZE(v) (ll)((v).size())\n#define PYes {puts(\"Yes\"); exit(0);}\n#define PNo {puts(\"No\"); exit(0);}\n#define Pm0 {puts(\"0\"); exit(0);}\n#define Pm1 {puts(\"-1\"); exit(0);}\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define INTM(...) int __VA_ARGS__; inm(__VA_ARGS__)\n#define LONG(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define LONGM(...) ll __VA_ARGS__; inm(__VA_ARGS__)\n#define DOUBLE(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define CHAR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define STRING(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define VI(ivec, n) vi ivec; input_ivec(ivec, n)\n#define VIM(ivec, n) vi ivec; input_ivecm(ivec, n)\n#define VL(lvec, n) vl lvec; input_lvec(lvec, n)\n#define VLM(lvec, n) vl lvec; input_lvecm(lvec, n)\n#define VC(cvec, n) vc cvec; input_cvec(cvec, n)\n#define VS(svec, n) vs svec; input_svec(svec, n)\n#define VD(dvec, n) vd dvec; input_dvec(dvec, n)\n#define VP(pvec, n) vp pvec; input_pvec(pvec, n)\n#define VPD(pvec, n) vpd pvec; input_pvecd(pvec, n)\n#define VPM(pvec, n) vp pvec; input_pvecm(pvec, n)\n#define VVI(ivec2, h, w) vvi ivec2(h, vi(w)); input_ivec2(ivec2, h, w)\n#define VVL(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2(lvec2, h, w)\n#define VVLM(lvec2, h, w) vvl lvec2(h, vl(w)); input_lvec2m(lvec2, h, w)\n#define VVC(cvec2, h, w) vvc cvec2(h, vc(w)); input_cvec2(cvec2, h, w)\n#define pcnt(x) (ll)__builtin_popcountll(x)\n#define parity(x) (ll)__builtin_parityll(x)\n#define abs(x) llabs(x)\n#define uset unordered_set\n#define umap unordered_map\ninline void Out(double x) {printf(\"%.15f\",x);cout<<'\\n';}\ntemplate<typename T> inline void Out(pair<T,T> x) {cout<<x.first<<' '<<x.second<<'\\n';}\ntemplate<typename T> inline void Out(T x) {cout<<x<<'\\n';}\ninline void Out(vector<string> v) {rep(i,SIZE(v)) cout<<v[i]<<'\\n';}\ntemplate<typename T> inline void Out(queue<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop();} cout<<endl;}\ntemplate<typename T> inline void Out(deque<T> q){while(!q.empty()) {cout<<q.front()<<\" \"; q.pop_front();} cout<<endl;}\ntemplate<typename T> inline void Out(vector<T> v) {rep(i,SIZE(v)) cout<<v[i]<<(i==SIZE(v)-1?'\\n':' ');}\ntemplate<typename T> inline void Out(vector<vector<T>> &vv){for(auto &v: vv) Out(v);}\ntemplate<typename T> inline void Out(vector<pair<T,T>> v) {for(auto p:v) Out(p);}\ntemplate<typename T> inline void Outend(T x) {Out(x); exit(0);}\ntemplate<typename T> inline void chmin(T &a, T b) { a = min(a, b); }\ntemplate<typename T> inline void chmax(T &a, T b) { a = max(a, b); }\ninline void mi(void) {return;}\ntemplate<typename T1, typename... T2> void mi(T1& f, T2&... r) {--f; mi(r...);}\ntemplate<class... T> void in(T&... x) {(cin >> ... >> x);}\ntemplate<class... T> void inm(T&... x) {(cin >> ... >> x); mi(x...);}\ninline void input_ivec(vi &ivec, int n) {rep(i, n) {int x; cin >> x; ivec.push_back(x);}}\ninline void input_ivecm(vi &ivec, int n) {rep(i, n) {int x; cin >> x; ivec.push_back(--x);}}\ninline void input_lvec(vl &lvec, ll n) {rep(i, n) {ll x; cin >> x; lvec.push_back(x);}}\ninline void input_lvecm(vl &lvec, ll n) {rep(i, n) {ll x; cin >> x; lvec.push_back(--x);}}\ninline void input_cvec(vc &cvec, ll n) {rep (i, n) {char c; cin >> c; cvec.push_back(c);}}\ninline void input_svec(vs &svec, ll n) {rep (i, n) {string s; cin >> s; svec.push_back(s);}}\ninline void input_dvec(vd &dvec, ll n) {rep (i, n) {double d; cin >> d; dvec.push_back(d);}}\ninline void input_pvec(vp &pvec, ll n) {rep (i, n) {ll a, b; cin >> a >> b; pvec.emplace_back(a, b);}}\ninline void input_pvecm(vp &pvec, ll n) {rep (i, n) {ll a, b; cin >> a >> b; pvec.emplace_back(--a, --b);}}\ninline void input_pvecd(vpd &pvec, ll n) {rep (i, n) {double a, b; cin >> a >> b; pvec.emplace_back(a, b);}}\ninline void input_ivec2(vvi &ivec2, int h, int w) {rep(i, h) rep(j, w) {int x; cin >> x; ivec2[i][j] = x;}}\ninline void input_lvec2(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {ll x; cin >> x; lvec2[i][j] = x;}}\ninline void input_lvec2m(vvl &lvec2, ll h, ll w) {rep(i, h) rep(j, w) {ll x; cin >> x; lvec2[i][j] = --x;}}\ninline void input_cvec2(vvc &cvec2, ll h, ll w) {rep(i, h) rep(j, w) {char c; cin >> c; cvec2[i][j] = c;}}\ninline bool isin(ll i, ll j, ll h, ll w) {if(i<0||i>=h||j<0||j>=w) return false; else return true;}\ninline ll TmpPercent(ll a, ll b) {if(b<0){a=-a,b=-b;} return (a%b+b)%b;}\ninline ll Percent(ll a, ll b) {if(b<0) return -TmpPercent(a,b); return TmpPercent(a,b);}\ninline ll Div(ll a, ll b) {if(b<0){a=-a,b=-b;} return (a-TmpPercent(a,b))/b; }\ninline ll Divceil(ll a, ll b) {if(TmpPercent(a,b)==0) return Div(a,b); return Div(a,b)+1;}\n#ifdef __DEBUG\n#define de(var) {cerr << #var << \": \"; debug_view(var);}\n#define de2(var1,var2) {cerr<<#var1<<' '<<#var2<<\": \"; debug_view(var1,var2);}\n#define de3(var1,var2,var3) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<\": \"; debug_view(var1,var2,var3);}\n#define de4(var1,var2,var3,var4) {cerr<<#var1<<' '<<#var2<<' '<<#var3<<' '<<#var4<<\": \"; debug_view(var1,var2,var3,var4);}\ntemplate<typename T> inline void debug_view(T e){cerr << e << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(T1 e1, T2 e2){cerr<<e1<<' '<<e2<<endl;}\ntemplate<typename T1, typename T2, typename T3> inline void debug_view(T1 e1, T2 e2, T3 e3){cerr<<e1<<' '<<e2<<' '<<e3<<endl;}\ntemplate<typename T1, typename T2, typename T3, typename T4> inline void debug_view(T1 e1, T2 e2, T3 e3, T4 e4){cerr<<e1<<' '<<e2<<' '<<e3<<' '<<e4<<endl;}\ntemplate<typename T1, typename T2> inline void debug_view(pair<T1,T2> &p){cerr<<\"{\"<<p.first<<\" \"<<p.second<<\"}\\n\";}\ntemplate<typename T1, typename T2> inline void debug_view(vector<pair<T1,T2>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T1, typename T2> inline void debug_view(set<pair<T1,T2>> &s){for(auto [a,b]: s){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(tuple<T,T,T> t){cerr<<get<0>(t)<<' '<<get<1>(t)<<' '<<get<2>(t)<< endl;}\ntemplate<typename T> inline void debug_view(queue<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop();}cerr << endl;}\ntemplate<typename T> inline void debug_view(deque<T> q){while(!q.empty()) {cerr << q.front() << \" \"; q.pop_front();}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(set<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(unordered_set<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(multiset<T,greater<T>> s){for(auto x:s){cerr << x << ' ';}cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<pair<T,T>> &v){for(auto [a,b]: v){cerr<<\"{\"<<a<<\" \"<<b<<\"} \";} cerr << endl;}\ninline void debug_view(vector<string> &v){cerr << \"----\" << endl; for(auto s: v) debug_view(s);}\ntemplate<typename T> inline void debug_view(vector<T> &v){for(auto e: v){cerr << e << \" \";} cerr << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<pair<T,T>>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T> inline void debug_view(vector<vector<T>> &vv){cerr << \"----\" << endl;for(auto &v: vv){debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(unordered_map<T1,T2> &mp){cerr << \"----\" << endl;for(auto [k,v]: mp){cerr << k << ' ' << v << endl;} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2> inline void debug_view(map<T1,vector<T2>> &mp){cerr<<\"----\"<<endl;for(auto [k,v]: mp){cerr<<k<<\": \";debug_view(v);} cerr << \"--------\" << endl;}\ntemplate<typename T1,typename T2,typename T3> inline void debug_view(map<pair<T1,T2>,T3> &mp){cerr << \"----\" << endl;for(auto [p,v]: mp){cerr<<'{'<<p.first<<' '<<p.second<<'}'<<\": \"<<v<<endl;} cerr<<\"--------\"<<endl;}\n#define deb(var) {cerr << #var << \": \"; debugb_view(var);}\ntemplate<typename T> inline void debugb_view(T e){bitset<20> b(e); cerr<<b<<endl;}\ntemplate<typename T> inline void debugb_view(vector<T> &v){cerr<<\"----\"<<endl;for(auto e: v){debugb_view(e);}}\n#else\n#define de(var) {}\n#define de2(var1,var2) {}\n#define de3(var1,var2,var3) {}\n#define de4(var1,var2,var3,var4) {}\n#define deb(var) {}\n#endif\nll INF = 3e18;\nconst ll M998 = 998244353;\nconst ll M107 = 1000000007;\ntemplate<typename T> inline void ch1(T &x){if(x==INF)x=-1;}\nconst double PI = acos(-1);\nconst double EPS = 1e-8; //eg) if x=1e9, EPS >= 1e9/1e15(=1e-6)\nconst vi di = {0, 1, 0, -1};\nconst vi dj = {1, 0, -1, 0};\nconst vp dij = {{0,1},{1,0},{0,-1},{-1,0}};\nconst vi di8 = {-1, -1, -1, 0, 0, 1, 1, 1};\nconst vi dj8 = {-1, 0, 1, -1, 1, -1, 0, 1};\nPr operator+ (Pr a, Pr b) {return {a.first+b.first, a.second+b.second};}\nPr operator- (Pr a, Pr b) {return {a.first-b.first, a.second-b.second};}\nPr operator* (Pr a, Pr b) {return {a.first*b.first, a.second*b.second};}\nPr operator/ (Pr a, Pr b) {return {a.first/b.first, a.second/b.second};}\n\nstruct SCC {\n SCC (long long _n): n(_n), from(_n), ifrom(_n) {}\n void add_edge (long long a, long long b) {\n from[a].push_back(b);\n ifrom[b].push_back(a);\n }\n vector<vector<long long>> scc () {\n vector<vector<long long>> group;\n back_num.clear();\n selected.assign(n, false);\n for (long long i=0; i < n; ++i) {\n if (!selected[i]) dfs1(i);\n }\n selected.assign(n, false);\n for (long long i=n-1; i >= 0; --i) {\n long long x = back_num[i];\n if (selected[x]) continue;\n vector<long long> emp;\n dfs2(x, emp);\n group.push_back(emp);\n }\n return group;\n }\nprivate:\n long long n;\n vector<vector<long long>> from, ifrom;\n vector<long long> back_num;\n vector<bool> selected;\n void dfs1 (long long x) {\n selected[x] = true;\n for (auto y: from[x]) {\n if (selected[y]) continue;\n dfs1(y);\n }\n back_num.push_back(x);\n }\n void dfs2 (long long x, vector<long long> &vec) {\n selected[x] = true;\n vec.push_back(x);\n for (auto y: ifrom[x]) {\n if (selected[y]) continue;\n dfs2(y, vec);\n }\n }\n};\n\n\n\nint main () {\n // ios::sync_with_stdio(false);\n cin.tie(nullptr);\n LONG(N, M);\n SCC scc(N);\n vp edge;\n rep(i, M) {\n LONG(s, t);\n scc.add_edge(s, t);\n edge.emplace_back(s, t);\n }\n auto grs = scc.scc();\n vl group(N);\n ll idx = 0;\n for(auto gr: grs) {\n for(auto v: gr) {\n group[v] = idx;\n }\n ++idx;\n }\n if(SIZE(grs)==1) Pm0\n de(grs)\n ll Z = SIZE(grs);\n vl ind(Z), outd(Z);\n for(auto [s,t]: edge) {\n if(group[s]==group[t]) continue;\n outd[group[s]]++;\n ind[group[t]]++;\n }\n ll nin=0, nout=0;\n de(ind)de(outd)\n rep(i, Z) {\n if(ind[i]==0) nin++;\n if(outd[i]==0) nout++;\n }\n Out(max(nin, nout));\n \n}\n\n// ### test.cpp ###", "accuracy": 1, "time_ms": 30, "memory_kb": 9120, "score_of_the_acc": -0.9533, "final_rank": 10 }, { "submission_id": "aoj_0366_9542318", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint N = 11000, c = 0;\n\n//辺を保存(way2は逆向きで)\nvector < vector < int > > way(N) ,way2(N);\n\n//dfsにおいて判定したかどうか\nvector < bool > checked(N ,0);\n\n//dfsにより並び替えた後の配列\nvector < int > LIST(N, -1);\n\n//頂点が属する連結成分の番号\nvector < int > ans(N, -1);\n\n//番号の割り付け\nvoid dfs(int pos){\n checked[pos] = 1;\n for(auto i : way[pos]){\n if(checked[i] == 0){\n dfs(i);\n }\n }\n LIST[c] = pos;\n c++;\n}\n\n//頂点が属する連結成分の判定\nvoid dfs2(int pos,int num){\n ans[pos] = num;\n for(auto i : way2[pos]){\n if(ans[i] == -1){\n dfs2(i, num);\n }\n }\n}\n\nint main(){\n int v, e;\n cin >> v >> e ;\n for(int i = 0;i < e;i++){\n int s, t;\n cin >> s >> t ;\n // s--,t--;\n way[s].push_back(t);\n way2[t].push_back(s);\n }\n\n for(int i = 0;i < v;i++){\n if(checked[i] == 0){\n dfs(i);\n }\n }\n\n for(int i = v-1;i >= 0&&LIST[i] != -1;i--){\n if(ans[ LIST[i] ] == -1){\n dfs2(LIST[i],LIST[i]);\n }\n }\n\n //新しいグラフに直す\n //座圧 -> グラフの作成(辺の本数を記録、逆方向の辺も張る)\n vector<int>zaatu(v);\n for(int i = 0;i < v;i++)zaatu[i] = ans[i];\n sort(zaatu.begin(),zaatu.end());\n zaatu.erase(unique(zaatu.begin(),zaatu.end()),zaatu.end());\n if(zaatu.size() == 1){\n cout <<\"0\\n\";\n return 0;\n }\n\n for(int i = 0;i < v;i++){\n ans[i] = lower_bound(zaatu.begin(),zaatu.end(),ans[i])-zaatu.begin();\n }\n \n vector<vector<int>>way3(zaatu.size()),way4(zaatu.size());\n for(int i = 0;i < v;i++){\n for(auto j:way[i]){\n if(ans[i] == ans[j])continue;\n way3[ans[i]].push_back(ans[j]);\n }\n for(auto j:way2[i]){\n if(ans[i] == ans[j])continue;\n way4[ans[i]].push_back(ans[j]);\n }\n }\n\n int in = 0,out = 0;\n for(auto i:way3)if(i.empty())in++;\n for(auto i:way4)if(i.empty())out++;\n\n cout <<max(in,out)<<\"\\n\";\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6896, "score_of_the_acc": -0.7636, "final_rank": 8 } ]
aoj_0365_cpp
Swapping Characters You are given a string and a number k . You are suggested to generate new strings by swapping any adjacent pair of characters in the string up to k times. Write a program to report the lexicographically smallest string among them. Input The input is given in the following format. s k The first line provides a string s . The second line provides the maximum number of swapping operations k (0 ≤ k ≤ 10 9 ). The string consists solely of lower-case alphabetical letters and has a length between 1 and 2 × 10 5 . Output Output the lexicographically smallest string. Sample Input 1 pckoshien 3 Sample Output 1 ckopshien Sample Input 2 pckoshien 10 Sample Output 2 cekophsin
[ { "submission_id": "aoj_0365_11011873", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\n/**2025/10/18\n * BIT\n * 残りのスワップ回数以内で交換可能な文字のうち、辞書順最小の文字で、一番左にあるものから先頭に持っていくことを\n * 確定させるイメージ。\n * i番目の文字をすでに確定させた文字列のすぐ次の位置に持ってくるのに必要なスワップ回数は、\n * 元々の文字列でi番目より手前ですでに確定させた文字がx個とするとi-x回。\n * xはBITで文字を一つ確定させた後にそれが元々あった位置に+1することで高速で求まる。\n */\n\ntemplate <typename T>\nstruct BIT {\n int n; // 配列の要素数(数列の要素数+1)\n vector<T> bit; // データの格納先\n BIT(int n_) : n(n_ + 1), bit(n, 0) {}\n void add(int i, T x) {\n i++;\n for (int idx = i; idx < n; idx += (idx & -idx)) {\n bit[idx] += x;\n }\n }\n // 0番目からl-1番目までの累積和\n T sum(int i) {\n T s(0);\n for (int idx = i; idx > 0; idx -= (idx & -idx)) {\n s += bit[idx];\n }\n return s;\n }\n // [l, r)の要素の総和\n T sum(int l, int r){\n T ret_l = sum(l);\n T ret_r = sum(r);\n return ret_r - ret_l;\n }\n\n // 累積和が x 以上になる最小のインデックスを返す(x >= 0)\n int lower_bound(T x) {\n int idx = 0;\n int k = 1;\n while (k * 2 < n) k *= 2; // 最大の 2^k\n\n for (; k > 0; k /= 2) {\n if (idx + k < n && bit[idx + k] < x) {\n x -= bit[idx + k];\n idx += k;\n }\n }\n return idx; // 0-indexed int idx = 0;\n }\n};\n \nint main(){\n string s;\n cin >> s;\n ll k;\n cin >> k;\n\n vvl pos(26, vl());\n ll n = s.size();\n rep(i, n) pos[s[i] - 'a'].pb(i);\n rep(i, 26) reverse(nall(pos[i]));\n\n BIT<ll> bit(n);\n\n string ans = \"\";\n rep(i, n){\n rep(j, 26){\n if(pos[j].empty()) continue;\n ll l = pos[j].back();\n\n ll sum = bit.sum(0, l); // l番目の文字より手前ですでに選ばれた文字の個数\n ll need = l - sum;\n if(need <= k){\n k -= need;\n ans.pb((char)('a' + j));\n bit.add(l, 1);\n pos[j].pop_back();\n break;\n }\n }\n }\n\n cout << ans << endl;\n\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6952, "score_of_the_acc": -0.0539, "final_rank": 4 }, { "submission_id": "aoj_0365_10986823", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long \n#define ls u<<1\n#define rs u<<1|1\nconst int N=5e5+5;\nll n,k;\nstring s,ans;\nint pos[30][N],cnt[30],idx[30];\nbool vis[N];\nint a[N],t[N*4],d[N*2];\nint lowbit(int x){\n\treturn x&(-x);\n}\nvoid pushup(int u){\n\tt[u]=min(t[ls],t[rs]); \n}\nvoid build(int u,int l,int r){\n\tif(l==r){\n\t\tt[u]=a[l];\n\t\treturn ;\n\t}\n\tint mid=l+r>>1;\n\tbuild(ls,l,mid);\n\tbuild(rs,mid+1,r);\n\tpushup(u);\n}\nvoid modify(int u,int loc,int l,int r){\n\tif(l==r){\n\t\tt[u]=100;\n\t\treturn ;\n\t}\n\tint mid=l+r>>1;\n\tif(loc<=mid) modify(ls,loc,l,mid);\n\telse modify(rs,loc,mid+1,r);\n\tpushup(u);\n}\nint query(int u,int L,ll R,int l,int r){\n\tif(L<=l&&r<=R){\n\t\treturn t[u];\n\t}\n\tint mid=l+r>>1,res=100;\n\tif(L<=mid) res=min(res,query(ls,L,R,l,mid));\n\tif(R>mid) res=min(res,query(rs,L,R,mid+1,r));\n\treturn res;\n}\nvoid addx(int u,int v){\n\twhile(u<=n){\n\t\td[u]+=v;\n\t\tu+=lowbit(u);\n\t}\n}\nint askx(int u){\n\tint res=0;\n\twhile(u){\n\t\tres+=d[u];\n\t\tu-=lowbit(u);\n\t}\n\treturn res;\n}\nbool check(int x,int p){\n\treturn askx(x)-askx(p)<k;\n}\nint main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);cout.tie(0);\n\tcin>>s;\n\tcin>>k;\n\tn=s.size();\n\tfor(int i=0;i<n;i++){\n\t\ta[i+1]=s[i]-'a'+1;\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tpos[a[i]][++cnt[a[i]]]=i;\n\t\tidx[a[i]]=1;\n\t}\n\tbuild(1,1,n);\n\tfor(int i=1;i<=n;i++) addx(i,1);\n\tfor(int i=1;i<=n;){\n\t\tif(vis[i]){\n\t\t\ti++;\n\t\t\tcontinue;\n\t\t} \n\t\tint l=i,r=n;\n\t\twhile(l<r){\n\t\t\tint mid=l+r>>1;\n\t\t\tif(check(mid,i)) l=mid+1;\n\t\t\telse r=mid;\n\t\t}\n\t\tint x=query(1,i+1,r,1,n);\n\t\tif(x>=a[i]){\n\t\t\tans+=char(a[i]+'a'-1);\n\t\t\tvis[i]=1;\n\t\t\tidx[a[i]]++;i++;\n\t\t\tcontinue;\n\t\t}\n\t\tint p=pos[x][idx[x]];\n\t\tidx[x]++;\n\t\tvis[p]=1;\n\t\tk-=(askx(p)-askx(i));\n\t\taddx(p,-1);\n\t\tans+=char(x+'a'-1);\n\t\tmodify(1,p,1,n);\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tif(!vis[i]) ans+=char(a[i]+'a'-1);\n\t}\n\tcout<<ans<<'\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 63716, "score_of_the_acc": -1.125, "final_rank": 18 }, { "submission_id": "aoj_0365_10953451", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\n/**2025/10/18\n * BIT\n * 残りのスワップ回数以内で交換可能な文字のうち、辞書順最小の文字で、一番左にあるものから先頭に持っていくことを\n * 確定させるイメージ。\n * i番目の文字をすでに確定させた文字列のすぐ次の位置に持ってくるのに必要なスワップ回数は、\n * 元々の文字列でi番目より手前ですでに確定させた文字がx個とするとi-x回。\n * xはBITで文字を一つ確定させた後にそれが元々あった位置に+1することで高速で求まる。\n */\n\ntemplate <typename T>\nstruct BIT {\n int n; // 配列の要素数(数列の要素数+1)\n vector<T> bit; // データの格納先\n BIT(int n_) : n(n_ + 1), bit(n, 0) {}\n void add(int i, T x) {\n i++;\n for (int idx = i; idx < n; idx += (idx & -idx)) {\n bit[idx] += x;\n }\n }\n // 0番目からl-1番目までの累積和\n T sum(int i) {\n T s(0);\n for (int idx = i; idx > 0; idx -= (idx & -idx)) {\n s += bit[idx];\n }\n return s;\n }\n // [l, r)の要素の総和\n T sum(int l, int r){\n T ret_l = sum(l);\n T ret_r = sum(r);\n return ret_r - ret_l;\n }\n\n // 累積和が x 以上になる最小のインデックスを返す(x >= 0)\n int lower_bound(T x) {\n int idx = 0;\n int k = 1;\n while (k * 2 < n) k *= 2; // 最大の 2^k\n\n for (; k > 0; k /= 2) {\n if (idx + k < n && bit[idx + k] < x) {\n x -= bit[idx + k];\n idx += k;\n }\n }\n return idx; // 0-indexed int idx = 0;\n }\n};\n \nint main(){\n string s;\n ll k;\n cin >> s >> k;\n ll n = s.size();\n vc<set<ll>> v(26, set<ll>()); // s上で文字'a'+iの位置の集合\n \n rep(i, n){\n v[s[i] - 'a'].insert(i);\n }\n\n BIT<ll> bit(n);\n\n // 先頭から1文字ずつ決定する\n rep(i, n){\n // 辞書順の小さい文字から残り回数以内で先頭人持ってこれる文字を貪欲に選ぶ\n rep(j, 26){\n if(v[j].empty()) continue;\n ll idx = *v[j].begin(); // まだ使用していない'a'+jのうち、一番左にあるものの位置\n ll x = bit.sum(0, idx); // s[idx]より左側ですでに使用した文字の個数\n ll need = idx - x; // s[idx]をすでに確定させた文字列の次の位置に持ってくるのに必要なスワップ回数\n if(need > k) continue; // 操作回数が足りないならスキップ\n k -= need; // 足りた場合\n cout << (char)('a'+j);\n bit.add(idx, 1); // BITにidx文字目を使用したことを記録\n v[j].erase(idx);\n break;\n }\n }\n\n cout << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 14284, "score_of_the_acc": -0.2293, "final_rank": 7 }, { "submission_id": "aoj_0365_10937992", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nint main(){\n string S; cin>>S;\n int K; cin>>K;\n\n vector<vector<int>> Sid(26);\n vector<int> Scont(26,0);\n for(int i=0;i<S.size();i++) Sid[S[i]-'a'].push_back(i);\n\n vector<int> bit(S.size()+1,0);\n for(int i=1;i<=S.size();i++) bit[i]=i&-i;\n\n string ans;\n for(int i=0;i<S.size();i++){\n for(int j=0;j<26;j++){\n if(Scont[j]>=Sid[j].size()) continue;\n\n int bit_sum=0,idx=Sid[j][Scont[j]];\n while(idx>0){\n bit_sum+=bit[idx];\n idx-=idx&-idx;\n }\n if(bit_sum>K) continue;\n\n ans.push_back(j+'a');\n K-=bit_sum;\n idx=Sid[j][Scont[j]]+1;\n while(idx<=S.size()){\n bit[idx]--;\n idx+=idx&-idx;\n }\n Scont[j]++;\n break;\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5264, "score_of_the_acc": -0.025, "final_rank": 2 }, { "submission_id": "aoj_0365_10873530", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\ntemplate<class S, S (*op)(S, S), S (*e)()> struct segtree {\n segtree(int n) : segtree(vector<S>(n,e())) {}\n segtree(const vector<S>& v) : n(si(v)) {\n s=__bit_ceil(unsigned(n));\n log = __countr_zero(unsigned(s));\n d=vector<S>(2*s, e());\n rep(i,n) d[s+i]=v[i];\n for(int i=s;--i;) update(i);\n }\n void set(int p, S x){\n d[p+=s]=x;\n for(int i=1;i<=log;i++) update(p>>i);\n }\n S prod(int l, int r) const {\n S sml=e(), smr=e();\n l+=s;r+=s;\n while(l<r){\n if(l&1) sml=op(sml, d[l++]);\n if(r&1) smr=op(d[--r], smr);\n l>>=1,r>>=1;\n }\n return op(sml,smr);\n }\n S all_prod() const {\n return d[1];\n }\n template<typename F> int max_right(int l, F f) const {\n if(l==n) return n;\n l+=s;\n S sm=e();\n do {\n while(~l&1) l>>=1;\n if(!f(op(sm, d[l]))){\n while(l<s){\n\n l<<=1;\n if(f(op(sm, d[l]))) sm=op(sm, d[l++]);\n }\n return l-s;\n }\n sm=op(sm, d[l++]);\n } while((l&-1)!=1);\n return n;\n }\n \n\nprivate:\n int n,s,log;\n vector<S>d;\n void update(int k){\n d[k]=op(d[k*2], d[k*2+1]);\n }\n};\n\nusing S=pair<int,int>;\nS op(S l, S r){\n return min(l,r);\n}\nS e(){\n return S{1e9,1e9};\n}\n\nint op2(int l, int r){\n return l+r;\n}\nint e2(){\n return 0;\n}\n\nint main(){\n string s;\n int K;\n cin>>s>>K;\n int N=si(s);\n\n vector<pair<int,int>> A(N);\n rep(i,N) A[i]=make_pair(s[i]-'a', i);\n\n segtree<S,op,e> seg(A);\n segtree<int,op2,e2> ex(N);\n rep(i,N) ex.set(i, 1);\n\n string ans;\n rep(i,N){\n int mv=min(K, N-i-1);\n int r=ex.max_right(0,[&](int x){return x<=mv;});\n S ret=seg.prod(0,r+1);\n ex.set(ret.se,0);\n seg.set(ret.se, e());\n ans+='a'+ret.fi;\n\n K-=ex.prod(0, ret.se);\n }\n cout<<ans<<\"\\n\";\n\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 12232, "score_of_the_acc": -0.1942, "final_rank": 5 }, { "submission_id": "aoj_0365_10866808", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i=0;i<(ll)(N);i++)\n#define fi first \n#define se second\n#define pb push_back\n#define all(X) (X).begin(),(X).end()\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\n\nclass segtree{\n public:\n int N;\n vector<ll>data;\n vector<ll>lazy;\n void init (int n){\n N = 1;\n while(N<n)N*=2;\n data.assign(N*2-1,0);\n lazy.assign(N*2-1,0);\n }\n void eval(int k){\n if(lazy[k]==0)return;\n data[k]+=lazy[k];\n if(2*k+2<N*2-1){\n lazy[2*k+1]+=lazy[k];\n lazy[2*k+2]+=lazy[k];\n }\n lazy[k]=0;\n }\n void update(int a,int b,ll x,int k=0,int l=0,int r = -1){\n if(r<0)r=N;\n eval(k);\n if(b<=l||r<=a)return;\n if(a<=l&&r<=b){\n lazy[k]+=x;\n eval(k);\n return;\n }\n update(a,b,x,2*k+1,l,(l+r)/2);\n update(a,b,x,2*k+2,(l+r)/2,r);\n data[k]=max(data[2*k+1],data[2*k+2]);\n }\n ll get(int a,int b,int k=0,int l=0,int r = -1){\n if(r<0)r=N;\n eval(k);\n if(b<=l||r<=a)return 0;\n if(a<=l&&r<=b){\n return data[k];\n }\n ll L=get(a,b,k*2+1,l,(l+r)/2),R=get(a,b,k*2+2,(l+r)/2,r);\n return max(L,R);\n }\n};\n\nint main(){\n string S;cin>>S;\n int K;cin>>K;\n int N = S.size();\n segtree seg;\n seg.init(N);\n vector<queue<int>>Q(26);\n rep(i,N){\n Q[S[i]-'a'].push(i);\n }\n string ans;\n rep(i,N){\n rep(j,26){\n if(Q[j].empty())continue;\n int v = Q[j].front();\n ll pos = v+seg.get(v,v+1);\n pos -=i;\n if(pos<=K){\n K-=pos;\n seg.update(0,v+1,1);\n ans.pb('a'+j);\n Q[j].pop();\n break;\n }\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 12616, "score_of_the_acc": -0.7508, "final_rank": 17 }, { "submission_id": "aoj_0365_10863593", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nnamespace atcoder {\n\n namespace internal {\n\n#ifndef _MSC_VER\n template <class T>\n using is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\n template <class T>\n using is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_signed_int = typename std::conditional<(is_integral<T>::value&&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int =\n typename std::conditional<(is_integral<T>::value&&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\n template <class T> using is_integral = typename std::is_integral<T>;\n\n template <class T>\n using is_signed_int =\n typename std::conditional<is_integral<T>::value&& std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using is_unsigned_int =\n typename std::conditional<is_integral<T>::value&&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\n template <class T>\n using to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\n template <class T>\n using is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\n template <class T>\n using is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\n template <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n }\n\n}\nnamespace atcoder {\n\n template <class T> struct fenwick_tree {\n using U = internal::to_unsigned_t<T>;\n\n public:\n fenwick_tree() : _n(0) {}\n fenwick_tree(int n) : _n(n), data(n) {}\n\n void add(int p, T x) {\n assert(0 <= p && p < _n);\n p++;\n while (p <= _n) {\n data[p - 1] += U(x);\n p += p & -p;\n }\n }\n\n T sum(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n return sum(r) - sum(l);\n }\n\n private:\n int _n;\n std::vector<U> data;\n\n U sum(int r) {\n U s = 0;\n while (r > 0) {\n s += data[r - 1];\n r -= r & -r;\n }\n return s;\n }\n };\n\n}\nusing namespace atcoder;\nint main() {\n string s; int k; cin >> s >> k;\n vector<set<int>> ary(26);\n fenwick_tree<int> fw(s.size());\n rep(i, s.size()) {\n ary[s[i] - 'a'].insert(i);\n fw.add(i, 1);\n }\n rep(i, s.size()) {\n rep(j, 26) {\n if (ary[j].size() == 0)continue;\n int sum = fw.sum(0, *ary[j].begin());\n if (sum > k)continue;\n k -= sum;\n s[i] = j + 'a';\n break;\n }\n fw.add(*ary[s[i] - 'a'].begin(), -1);\n ary[s[i] - 'a'].erase(ary[s[i] - 'a'].begin());\n }\n cout << s << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 13696, "score_of_the_acc": -0.1943, "final_rank": 6 }, { "submission_id": "aoj_0365_10858316", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nstruct SegTree {\n\tint n, N;\n\tvector<ll> dat;\n\tSegTree (int M) {\n\t\tint x = 0;\n\t\twhile ((1<<x) < M) x++;\n\t\tn = (1<<x);\n\t\tN = 2 * n;\n\t\tdat.assign(N, 0);\n\t}\n\tvoid add(int x, ll p) {\n\t\tx += n - 1;\n\t\tdat[x] += p;\n\t\twhile (x > 0) {\n\t\t\tx = (x-1)/2;\n\t\t\tdat[x] = dat[(2*x)+1] + dat[(2*x)+2];\n\t\t}\n\t}\n\tll dfs(int a, int b, int k, int l, int r) {\n\t\tif (b <= l or r <= a) {\n\t\t\treturn 0;\n\t\t}\n\t\tif (a <= l and r <= b) {\n\t\t\treturn dat[k];\n\t\t}\n\t\tll vl = dfs(a, b, (2*k)+1, l, (l+r)/2);\n\t\tll vr = dfs(a, b, (2*k)+2, (l+r)/2, r);\n\t\treturn vl+vr;\n\t}\n\tll query(int a, int b) {\n\t\treturn dfs(a, b, 0, 0, n);\n\t}\n};\nint main() {\n\tstring S;cin >> S;\n\tll K;cin >> K;\n\tvector<queue<int>> ID(26);\n\tint N = S.size();\n\tSegTree dec(N+2), non(N+2);\n\tfor (int i = 0;i < N;i++) {\n\t\tID[S[i]-'a'].push(i);\n\t\tnon.add(i, 1);\n\t}\n\tll tens = 0;\n\tfor (int i = 0;i < N;i++) {\n\t\tfor (int j = 0;j < 26;j++) {\n\t\t\tif (ID[j].empty()) continue;\n\t\t\tint nid = ID[j].front();\n\t\t\tll newten = tens + non.query(0,nid);\n\t\t\tif (newten <= K) {\n\t\t\t\tchar nc = 'a';nc += j;\n\t\t\t\tcout << nc;\n\t\t\t\tdec.add(nid, 1);\n\t\t\t\tnon.add(nid, -1);\n\t\t\t\tID[j].pop();\n\t\t\t\ttens = newten;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 12576, "score_of_the_acc": -0.3751, "final_rank": 11 }, { "submission_id": "aoj_0365_10852678", "code_snippet": "#pragma GCC target (\"avx\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) (int)(a).size()\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all(b),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",qq123_+1)\n#define readv(a,n) a.resize(n,0);rep(i,(n)) a[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = (ll)15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll popcount(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n};\nclass mint {\npublic:ll v;\n mint(ll v = 0) { s(v % mod + mod); }\n constexpr static int mod = (ll)1e9 + 7;\n constexpr static int fn_ = (ll)2e6 + 5;\n static mint fact[fn_], comp[fn_];\n mint pow(int x) const {\n mint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline mint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline mint inv()const { return pow(mod - 2); }\n inline mint operator-()const { return mint() - *this; }\n inline mint& operator+=(const mint b) { return s(v + b.v); }\n inline mint& operator-=(const mint b) { return s(v + mod - b.v); }\n inline mint& operator*=(const mint b) { v = v * b.v % mod; return *this; }\n inline mint& operator/=(const mint b) { v = v * b.inv().v % mod; return *this; }\n inline mint operator+(const mint b) const { return mint(v) += b; }\n inline mint operator-(const mint b) const { return mint(v) -= b; }\n inline mint operator*(const mint b) const { return mint(v) *= b; }\n inline mint operator/(const mint b) const { return mint(v) /= b; }\n friend ostream& operator<<(ostream& os, const mint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, mint& m) {\n int x; is >> x; m = mint(x);\n return is;\n }\n bool operator<(const mint& r)const { return v < r.v; }\n bool operator>(const mint& r)const { return v > r.v; }\n bool operator<=(const mint& r)const { return v <= r.v; }\n bool operator>=(const mint& r)const { return v >= r.v; }\n bool operator==(const mint& r)const { return v == r.v; }\n bool operator!=(const mint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n mint comb(mint k) {\n if (k > * this) return mint();\n if (!fact[0]) combinit();\n if (v >= fn_) {\n if (k > * this - k) k = *this - k;\n mint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= mint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n mint perm(mint k) {\n if (k > * this) return mint();\n if (!fact[0]) combinit();\n if (v >= fn_) {\n mint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= mint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * mint(i);\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * mint(i + 1);\n }\n}; mint mint::fact[fn_], mint::comp[fn_];\n//--------------------------------------------------------------\n\nclass BIT {\n using ll = long long;\n int size;\n vector<ll>dat;\npublic:\n BIT() {}\n BIT(int n) { init(n); }\n void init(int n) {\n size = n;\n dat.clear();\n dat.assign(size + 1, 0);\n }\n void add(int i, ll x) {\n if (i <= 0)\n i++;\n while (i <= size) {\n dat[i] += x;\n i += i & -i;\n }\n }//0-indexed\n void add(int l, int r, ll x) {\n add(l, x); add(r, -x);\n }//[l,r)\n ll query(int i) {\n i++;\n ll sum = 0;\n while (i > 0) {\n sum += dat[i];\n i -= i & -i;\n }\n return sum;\n }//0-indexed\n ll query(int l, int r) {\n return query(r - 1) - query(l - 1);\n }//[l,r)\n};//size, 0-indexed\n//---------------------------------------------------------------------\nBIT bit;\nsigned main() {\n string s; int k;\n cin >> s >> k;\n deque<int>pls[26];\n rep(i, siz(s)) {\n pls[int(s[i] - 'a')].pb(i);\n }\n bit.init(siz(s));\n string ans = \"\";\n rep(i, siz(s)) {\n rep(j, 26) {\n //もしもjがiに置けるなら\n if (pls[j].empty()) continue;\n int t = pls[j].front();\n if (t - i + bit.query(t) > k) continue;\n pls[j].pop_front();\n k -= t - i + bit.query(t);\n bit.add(0, t + 1, 1);\n ans += char(j + 'a');\n break;\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 37392, "score_of_the_acc": -0.5996, "final_rank": 15 }, { "submission_id": "aoj_0365_10758451", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\ntemplate <typename T>\nstruct BIT {\n int n; // 配列の要素数(数列の要素数+1)\n vector<T> bit; // データの格納先\n BIT(int n_) : n(n_ + 1), bit(n, 0) {}\n void add(int i, T x) {\n i++;\n for (int idx = i; idx < n; idx += (idx & -idx)) {\n bit[idx] += x;\n }\n }\n // 0番目からl-1番目までの累積和\n T sum(int i) {\n T s(0);\n for (int idx = i; idx > 0; idx -= (idx & -idx)) {\n s += bit[idx];\n }\n return s;\n }\n // [l, r)の要素の総和\n T sum(int l, int r){\n T ret_l = sum(l);\n T ret_r = sum(r);\n return ret_r - ret_l;\n }\n\n // 累積和が x 以上になる最小のインデックスを返す(x >= 0)\n int lower_bound(T x) {\n int idx = 0;\n int k = 1;\n while (k * 2 < n) k *= 2; // 最大の 2^k\n\n for (; k > 0; k /= 2) {\n if (idx + k < n && bit[idx + k] < x) {\n x -= bit[idx + k];\n idx += k;\n }\n }\n return idx; // 0-indexed int idx = 0;\n }\n};\n\nint main(){\n string s;\n ll k;\n cin >> s >> k;\n\n vc<deque<ll>> pos(26, deque<ll>());\n rep(i, s.size()){\n pos[s[i] - 'a'].push_back(i);\n }\n\n BIT<ll> bit(s.size());\n \n rep(j, s.size()){\n rep(i, 26){\n if(pos[i].empty()) continue;\n ll f = pos[i].front();\n ll cnt = f - bit.sum(f);\n\n if(cnt <= k){\n cout << char('a' + i);\n\n pos[i].pop_front();\n bit.add(f, 1);\n k -= cnt;\n break;\n }\n }\n }\n\n cout << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6552, "score_of_the_acc": -0.047, "final_rank": 3 }, { "submission_id": "aoj_0365_10738951", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include <atcoder/all>\nusing namespace atcoder;\n\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\nusing ld = long double;\nusing bl = bool;\nusing mint = modint998244353;\n// using mint = modint1000000007;\n// using mint = modint;\n// mint::set_mod(m);\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>;\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>;\n//-----------------------------------\n\n//-------------2.配列系--------------\n\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v)\n{\n rep(j, size(v)) i >> v[j];\n return i;\n}\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n//--------3.コード短縮化とか---------\nconst double PI = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++)\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--)\n\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n\n#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end());\n#define vc_rotate(v) rotate(v.begin(), v.begin() + 1, v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(), v.end())\n\n//-------------------------------\n\n//---------4.グリッド系----------\nvector<int> dx = {1, 0, -1, 0}; // dx={1,1,0,-1,-1,-1,0,1};\nvector<int> dy = {0, 1, 0, -1}; // dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w = -1)\n{\n if (w == -1)\n {\n w = h;\n }\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_rotate(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 時計回りに90°回転\n// #define vvl_rotate(v) {ll n = size(v);vvl\n// nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_rotate(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 文字列版 時計回りに90°回転\n// #define vs_rotate(v) {ll n = size(v);vs\n// nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n#define vvl_transpos(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n#define vs_transpos(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n\n//--------------------------------\n\n//-----------5.数学系--------------\n#define euclid(x, y) ((x) * (x) + (y) * (y)) // ユークリッド距離 2乗のまま\n#define manhattan(x1, x2, y1, y2) \\\n (abs(x1 - x2) + abs(y1 - y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate <class T>\nT tousa_sum1(T l, T d, T r)\n{ // 初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate <class T>\nT tousa_sum2(T a, T d, T n)\n{ // 初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d)\n{ // 初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\nmint touhi_sum(mint a, mint r,\n ll n)\n{ // 初項,公比,項数で等比数列の総和を求める\n if (r == 1)\n {\n return a * n;\n }\n mint bunsi = a * (r.pow(n) - mint(1));\n mint bunbo = r - 1;\n return bunsi / bunbo;\n}\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\n#define print_vec(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << \" \"; \\\n cout << endl; \\\n } // 一次元配列を出力する(改行なし)\n\n#define vc_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << endl; \\\n } // 一次元配列を出力する(改行あり)\n#define vv_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n//----------------------------------------------\n// Segment Tree\ntemplate <class Monoid>\nstruct SegmentTree\n{\n using Func = function<Monoid(Monoid, Monoid)>;\n\n // core member\n int N;\n Func OP;\n Monoid IDENTITY;\n\n // inner data\n int log, offset;\n vector<Monoid> dat;\n\n // constructor\n SegmentTree() {}\n SegmentTree(int n, const Func &op, const Monoid &identity)\n {\n init(n, op, identity);\n }\n SegmentTree(const vector<Monoid> &v, const Func &op, const Monoid &identity)\n {\n init(v, op, identity);\n }\n void init(int n, const Func &op, const Monoid &identity)\n {\n N = n;\n OP = op;\n IDENTITY = identity;\n log = 0, offset = 1;\n while (offset < N)\n ++log, offset <<= 1;\n dat.assign(offset * 2, IDENTITY);\n }\n void init(const vector<Monoid> &v, const Func &op, const Monoid &identity)\n {\n init((int)v.size(), op, identity);\n build(v);\n }\n void pull(int k)\n {\n dat[k] = OP(dat[k * 2], dat[k * 2 + 1]);\n }\n void build(const vector<Monoid> &v)\n {\n assert(N == (int)v.size());\n for (int i = 0; i < N; ++i)\n dat[i + offset] = v[i];\n for (int k = offset - 1; k > 0; --k)\n pull(k);\n }\n int size() const\n {\n return N;\n }\n Monoid operator[](int i) const\n {\n return dat[i + offset];\n }\n\n // update A[i], i is 0-indexed, O(log N)\n void set(int i, const Monoid &v)\n {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] = v;\n while (k >>= 1)\n pull(k);\n }\n\n void add(int i, const Monoid &v)\n {\n assert(0 <= i && i < N);\n int k = i + offset;\n dat[k] += v;\n while (k >>= 1)\n pull(k);\n }\n\n // get [l, r), l and r are 0-indexed, O(log N)\n Monoid prod(int l, int r)\n {\n assert(0 <= l && l <= r && r <= N);\n Monoid val_left = IDENTITY, val_right = IDENTITY;\n l += offset, r += offset;\n for (; l < r; l >>= 1, r >>= 1)\n {\n if (l & 1)\n val_left = OP(val_left, dat[l++]);\n if (r & 1)\n val_right = OP(dat[--r], val_right);\n }\n return OP(val_left, val_right);\n }\n Monoid all_prod()\n {\n return dat[1];\n }\n\n // get max r that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int max_right(const function<bool(Monoid)> f, int l = 0)\n {\n if (l == N)\n return N;\n l += offset;\n Monoid sum = IDENTITY;\n do\n {\n while (l % 2 == 0)\n l >>= 1;\n if (!f(OP(sum, dat[l])))\n {\n while (l < offset)\n {\n l = l * 2;\n if (f(OP(sum, dat[l])))\n {\n sum = OP(sum, dat[l]);\n ++l;\n }\n }\n return l - offset;\n }\n sum = OP(sum, dat[l]);\n ++l;\n } while ((l & -l) != l); // stop if l = 2^e\n return N;\n }\n\n // get min l that f(get(l, r)) = True (0-indexed), O(log N)\n // f(IDENTITY) need to be True\n int min_left(const function<bool(Monoid)> f, int r = -1)\n {\n if (r == 0)\n return 0;\n if (r == -1)\n r = N;\n r += offset;\n Monoid sum = IDENTITY;\n do\n {\n --r;\n while (r > 1 && (r % 2))\n r >>= 1;\n if (!f(OP(dat[r], sum)))\n {\n while (r < offset)\n {\n r = r * 2 + 1;\n if (f(OP(dat[r], sum)))\n {\n sum = OP(dat[r], sum);\n --r;\n }\n }\n return r + 1 - offset;\n }\n sum = OP(dat[r], sum);\n } while ((r & -r) != r);\n return 0;\n }\n\n // debug\n friend ostream &operator<<(ostream &s, const SegmentTree &seg)\n {\n for (int i = 0; i < (int)seg.size(); ++i)\n {\n s << seg[i];\n if (i != (int)seg.size() - 1)\n s << \" \";\n }\n return s;\n }\n};\nusing S = pair<char, int>;\nS e = {'{', inf};\nS op(S a, S b)\n{\n if (a.first == b.first)\n {\n if (a.second <= b.second)\n return a;\n else\n return b;\n }\n else\n {\n if (a.first < b.first)\n return a;\n else\n return b;\n }\n}\n\nusing T = int;\nT et = 0;\nT opt(T a, T b) { return a + b; }\nint k;\nbool f(int a)\n{\n return a <= k + 1;\n}\nint main()\n{\n cout << fixed << setprecision(10);\n string s;\n cin >> s >> k;\n int n = s.size();\n vector<S> a(n);\n rep(i, n) a[i] = {s[i], i};\n\n vector<T> b(n, 1);\n SegmentTree<S> seg(a, op, e);\n SegmentTree<T> cnt(b, opt, et);\n\n string ans;\n rep(i, n)\n {\n int idx = cnt.max_right(f);\n auto [c, l] = seg.prod(0, idx);\n\n ans.push_back(c);\n k -= cnt.prod(0, l);\n seg.set(l, {'{', inf});\n cnt.set(l, 0);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 12512, "score_of_the_acc": -0.299, "final_rank": 9 }, { "submission_id": "aoj_0365_10734424", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\ntemplate <class T>\nstruct BinaryIndexedTree {\n int N;\n vector<T> data;\n\n BinaryIndexedTree() = default;\n BinaryIndexedTree(int size) : N(size), data(size + 1, 0) {}\n BinaryIndexedTree(const vector<T>& v) : N(ssize(v)), data(N + 1) {\n for (int i = 1; i <= N; i++) {\n data[i] += v[i - 1];\n int j = i + (i & -i);\n if (j <= N) data[j] += data[i];\n }\n }\n // i 番目に x を加算\n void add(int i, T x) {\n assert(0 <= i && i < N);\n for (++i; i <= N; i += i & -i) data[i] += x;\n }\n // [l, r) に x を加算 (imos 法)\n void imos(int l, int r, T x) { add(l, x), add(r, -x); }\n // [0, i) の和 (imos 法で区間加算して i 番目の値を取るときは sum(i + 1))\n T sum(int i) const {\n if (i < 0) return T{};\n T res{};\n for (; i > 0; i -= i & -i) res += data[i];\n return res;\n }\n // [l, r) の和\n T sum(int l, int r) const { return sum(r) - sum(l); }\n // i 番目の値\n T operator[](int i) const { return sum(i + 1) - sum(i); }\n // [0, i) の和が w 以上となる最小の i\n int lower_bound(T w) const {\n if (w <= 0) return 0;\n int i = 0;\n for (int k = 1 << __lg(N); k > 0; k >>= 1) {\n if (i + k <= N && data[i + k] < w) {\n w -= data[i + k];\n i += k;\n }\n }\n return i + 1;\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n string s;\n int k;\n cin >> s >> k;\n\n int n = s.size();\n vector<queue<int>> pos(26);\n for (int i = 0; i < n; i++) pos[s[i] - 'a'].emplace(i);\n\n // bit[i] := i 文字目が未使用なら 1, 使用済みなら 0\n BinaryIndexedTree<int> bit(vector<int>(n, 1));\n\n // 辞書順に決定していく\n string ans = \"\";\n while (true) {\n bool is_update = false;\n for (int c = 0; c < 26; c++) {\n if (!pos[c].empty()) {\n int i = pos[c].front();\n int cost = bit.sum(i);\n if (cost <= k) {\n k -= cost;\n bit.add(i, -1); // 使用\n pos[c].pop();\n ans += (char)('a' + c);\n is_update = true;\n }\n }\n if (is_update) break;\n }\n if (!is_update) break;\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6016, "score_of_the_acc": -0.0129, "final_rank": 1 }, { "submission_id": "aoj_0365_10721114", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\ntemplate <typename T>\nstruct BIT {\n int n; // 配列の要素数(数列の要素数+1)\n vector<T> bit; // データの格納先\n BIT(int n_) : n(n_ + 1), bit(n, 0) {}\n void add(int i, T x) {\n i++;\n for (int idx = i; idx < n; idx += (idx & -idx)) {\n bit[idx] += x;\n }\n }\n // 0番目からl-1番目までの累積和\n T sum(int i) {\n T s(0);\n for (int idx = i; idx > 0; idx -= (idx & -idx)) {\n s += bit[idx];\n }\n return s;\n }\n // [l, r)の要素の総和\n T sum(int l, int r){\n T ret_l = sum(l);\n T ret_r = sum(r);\n return ret_r - ret_l;\n }\n\n // 累積和が x 以上になる最小のインデックスを返す(x >= 0)\n int lower_bound(T x) {\n int idx = 0;\n int k = 1;\n while (k * 2 < n) k *= 2; // 最大の 2^k\n\n for (; k > 0; k /= 2) {\n if (idx + k < n && bit[idx + k] < x) {\n x -= bit[idx + k];\n idx += k;\n }\n }\n return idx; // 0-indexed int idx = 0;\n }\n};\n\nint main(){\n string s;\n ll k;\n cin >> s >> k;\n ll n = s.size();\n vc<set<ll>> v(26, set<ll>());\n\n BIT<ll> bit(n);\n\n rep(i, n){\n v[s[i] - 'a'].insert(i);\n }\n\n rep(i, n){\n rep(j, 26){\n if(v[j].size() == 0) continue;\n ll idx = *v[j].begin();\n ll flg = idx - bit.sum(idx);\n if(flg > k) continue;\n k -= flg;\n cout << char('a' + j);\n v[j].erase(idx);\n bit.add(idx, 1);\n break;\n }\n }\n cout << endl;\n\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 14300, "score_of_the_acc": -0.2296, "final_rank": 8 }, { "submission_id": "aoj_0365_10567023", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n;\nlong long m;\nstring s;\nconst int N = 3e5 + 10;\n\nint son[N][2], sz[N], fa[N], idx;\nchar val[N];\npair<char,int> mn[N];\n\n#define ls son[p][0]\n#define rs son[p][1]\n\nvoid pushup(int p) {\n\tif (ls == 0 && rs == 0) {\n\t\tmn[p] = make_pair(val[p], p);\n\t} else if (ls == 0) {\n\t\tif (val[p] <= mn[rs].first) {\n\t\t\tmn[p] = make_pair(val[p], p);\n\t\t} else mn[p] = mn[rs];\n\t} else if (rs == 0) {\n\t\tif (val[p] < mn[ls].first) {\n\t\t\tmn[p] = make_pair(val[p], p);\n\t\t} else mn[p] = mn[ls];\n\t} else {\n\t\tvector<tuple<char,int,int>> tmp(3);\n\t\ttmp[0] = make_tuple(mn[ls].first, 0, mn[ls].second);\n\t\ttmp[1] = make_tuple(val[p], 1, p);\n\t\ttmp[2] = make_tuple(mn[rs].first, 2, mn[rs].second);\n\t\tsort(tmp.begin(), tmp.end());\n\t\tmn[p] = make_pair(get<0>(tmp.front()), get<2>(tmp.front()));\n\t}\n\tsz[0] = 0;\n\tsz[p] = sz[ls] + sz[rs] + 1; \n}\n\nvoid rotate(int p) {\n\tint f = fa[p], ff = fa[f], k = (p == son[f][1]);\n\tson[ff][f == son[ff][1]] = p;\n\tson[f][k] = son[p][k ^ 1], fa[son[p][k ^ 1]] = f;\n\tson[p][k ^ 1] = f;\n\tfa[f] = p; fa[p] = ff;\n\tpushup(f);\n\tpushup(p);\n}\nint root;\n\nvoid splay(int p, int t) {\n\tint cnt = 0;\n\tfor (int f; f = fa[p], t != f; rotate(p)) {\n\t\tif (fa[f] != t) rotate((son[fa[f]][1] == f) == (son[f][1] == p) ? f : p);\n\t}\n\tif (!t) root = p;\n}\n\nint pre(int p) {\n\tsplay(p, 0);\n\tint res = ls;\n\twhile (son[res][1]) res = son[res][1];\n\treturn res;\n}\nint nxt(int p) {\n\tsplay(p, 0);\n\tint res = rs;\n\twhile (son[res][0]) res = son[res][0];\n\treturn res;\n}\n\nint getidbyrk(int rk) {\n\t++rk;\n\tint p = root;\n\tsz[0] = 0;\n\twhile (1) {\n\t\tif (sz[ls] >= rk) p = ls;\n\t\telse if (sz[ls] + 1 >= rk) break;\n\t\telse rk -= sz[ls] + 1, p = rs;\n\t}\n\tsplay(p, 0);\n\treturn p;\n}\nvoid del(int p) {\n\tint pr = pre(p);\n\tint nt = nxt(p);\n\tsplay(pr, 0);\n//\t\tcout << root << ':' << endl;\n//\tfor (int _ = 1; _ <= idx; _++) {\n//\t\tcout << _ << ',' << val[_] << ',' << son[_][0] << ',' << son[_][1] << ',' << fa[_] << ',' << sz[_] << endl;\n//\t}\n\tsplay(nt, pr);\n\tson[nt][0] = 0;\n\tpushup(nt);\n\tpushup(pr);\n}\n\nvoid insert(int rk, char c) {\n\tint p = getidbyrk(rk);\n\tint nt = nxt(p);\n\tsplay(p, 0);\n\tsplay(nt, p);\n\tson[nt][0] = ++idx;\n\tfa[idx] = nt;\n\tval[idx] = c;\n\tpushup(idx);\n\tpushup(nt);\n\tpushup(p);\n}\n\npair<char,int> query(int l, int r) {\n\tl = getidbyrk(l); \n\tr = getidbyrk(r);\n\tint pr = pre(l);\n\tint nt = nxt(r);\n\tsplay(pr, 0);\n\tsplay(nt, pr);\n\treturn mn[son[nt][0]];\n}\n\nint getrkbyid(int p) {\n\tsplay(p, 0);\n\treturn sz[ls];\n}\nint main() {\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\troot = idx = 2;\n\tfa[1] = 2;\n\tson[2][0] = 1;\n\tval[1] = 127;\n\tval[2] = 127;\n\tpushup(1);\n\tpushup(2);\n\tcin >> s >> m;\n\tn = s.length();\n\ts = ' ' + s;\n\tfor (int i = 1; i <= n; i++) {\n\t\tinsert(i - 1, s[i]);\n\t}\n//\tfor (int i = 1; i <= n; i++) {\n//\t\tcout << val[getidbyrk(i)] << endl;\n//\t}\n//\tcout << root << ':' << endl;\n//\tfor (int _ = 1; _ <= idx; _++) {\n//\t\tcout << _ << ',' << val[_] << ',' << son[_][0] << ',' << son[_][1] << ',' << fa[_] << ',' << sz[_] << endl;\n//\t}\n\tfor (int i = 1; i < n; i++) {\n\t\tif (m == 0) break;\n\t\tint l = i + 1;\n\t\tint r = min((long long) n, i + m);\n\t\tauto res = query(l, r);\n\t\tif (res.first >= val[getidbyrk(i)]) continue;\n\t\tm -= getrkbyid(res.second) - i; \n\t\tdel(res.second);\n\t\tinsert(i - 1, res.first); \n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tcout << val[getidbyrk(i)];\n\t}\n\tcout << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 9664, "score_of_the_acc": -0.4003, "final_rank": 12 }, { "submission_id": "aoj_0365_10272264", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lli=long long int;\nusing vi=vector<int>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vl=vector<lli>;\nusing vvl=vector<vl>;\n#define all(s) s.begin(),s.end()\n#define rall(s) s.rbegin(),s.rend()\n#define rep(i,s,e) for(int i=s;i<e;i++)\n#define rrep(i,s,e) for(int i=s-1;i>=e;i--)\n#define in(v,seq) for(auto v:seq)\n#define pub(x) push_back(x)\n#define puf(x) push_front(x)\n#define pob(x) pop_back(x)\n#define pof(x) pop_front(x)\n#define emb(x) emplace_back(x)\n#define print(s) cout << s << endl;\nconst string alp=\"abcdefghijklmnopqrstuvwxyz\";\nconst int let=alp.size(); // 26\n\ntemplate<typename S> struct ST{\n function<S(S,S)> op; // calc\n S e; // monoid\n int n; // size of bottom\n vector<int> val;\n vector<S> data; // save value\n\n // initialization\n ST(int N,function<S(S,S)> op,S e):op(op),e(e){\n n=1;\n while(n<N) n*=2;\n data.assign(2*n,e);\n val.assign(2*n,0);\n }\n ST(vector<S> a,function<S(S,S)> op,S e):op(op),e(e){\n n=1;\n while(n<(int)a.size()) n*=2;\n data.assign(2*n,e);\n val.assign(2*n,0);\n \n for(int i=0;i<(int)a.size();i++){\n data.at(i+n)=a.at(i);\n }\n for(int i=n-1;i>0;i--){\n data.at(i)=op(data.at(2*i),data.at(2*i+1));\n }\n }\n\n void set(int i,S v){\n i+=n; data.at(i)=v;\n while(i>1){\n i/=2;\n data.at(i)=op(data.at(2*i),data.at(2*i+1));\n }\n }\n S at(int i){\n return data.at(i+n);\n }\n // [l,r)\n S calc(int l,int r){\n return pre_calc(l,r,1,0,n);\n }\n // recursive function\n S pre_calc(int l,int r,int k,int a,int b){\n if(r<=a || b<=l) return e;\n if(l<=a && b<=r) return data.at(k);\n return op(pre_calc(l,r,k*2,a,(a+b)/2),pre_calc(l,r,k*2+1,(a+b)/2,b));\n }\n\n void plus(int i,int a){\n i+=n; val.at(i)+=a;\n while(i>1){\n i/=2;\n val.at(i)=val.at(2*i)+val.at(2*i+1);\n }\n }\n\n int sum(int b){\n return pre_sum(b,n,1,0,n);\n }\n\n int pre_sum(int l,int r,int k,int a,int b){\n if(r<=a || b<=l) return 0;\n if(l<=a && b<=r) return val.at(k);\n return pre_sum(l,r,k*2,a,(a+b)/2)+pre_sum(l,r,k*2+1,(a+b)/2,b);\n }\n};\n\nchar e='z'+1;\nchar op(char a,char b){ return min(a,b); }\n\n\nint main(){\n string Str; cin >> Str;\n vector<char> s(Str.begin(),Str.end());\n int n=Str.size(),k; cin >> k;\n \n vvi v(let);\n vi cnt(let);\n ST<char> stree(s,op,e);\n rep(i,0,n){\n v.at(s.at(i)-'a').pub(i);\n }\n\n string ans=\"\";\n rep(i,0,n){\n int l=0,r=n;\n while(l<r){\n int mid=(l+r)/2;\n if(mid-i+stree.sum(mid)>k){\n r=mid;\n }else{\n l=mid+1;\n }\n }\n\n char c=stree.calc(0,l);\n ans+=c;\n int ind=v.at(c-'a').at(cnt.at(c-'a'));\n cnt.at(c-'a')++;\n k-=ind-i+stree.sum(ind);\n stree.set(ind,e);\n stree.plus(ind,1);\n }\n\n print(ans);\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 7644, "score_of_the_acc": -0.4657, "final_rank": 13 }, { "submission_id": "aoj_0365_9648104", "code_snippet": "#pragma region Macros\n \n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2,popcnt\")\n \n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n \n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n// Bdouble Beps = 0.00000000000000000000000000000001; // 1e-32\n// const bool equals(Bdouble a, Bdouble b) { return mp::fabs(a - b) < Beps; }\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n \n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n \n// #define next asdnext\n// #define prev asdprev\n \nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\nconst int MOD = 998244353;\n// const int MOD = 1000000007;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n \nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n \n#define EC int\nstruct Edge {\n int from, to;\n EC cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, EC cost) : to(to), cost(cost) {}\n Edge(int from, int to, EC cost) : from(from), to(to), cost(cost) {}\n bool operator ==(const Edge& e) {\n return this->from == e.from && this->to == e.to && this->cost == e.cost;\n }\n bool operator !=(const Edge& e) {\n return this->from != e.from or this->to != e.to or this->cost != e.cost;\n }\n bool operator <(const Edge& e) { return this->cost < e.cost; }\n bool operator >(const Edge& e) { return this->cost > e.cost; }\n};\n \nchrono::system_clock::time_point start;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n \nrandom_device seed_gen;\nmt19937_64 rng(seed_gen());\nuniform_int_distribution<int> dist_x(0, 1e9);\nstruct RNG {\n unsigned Int() {\n return dist_x(rng);\n }\n unsigned Int(unsigned l, unsigned r) {\n return dist_x(rng) % (r - l + 1) + l;\n }\n ld Double() {\n return ld(dist_x(rng)) / 1e9;\n }\n} rnd;\n\nnamespace bit_function {\n using i64 = ll;\n // using i64 = uint64_t;\n // bit演算, x==0の場合は例外処理した方がよさそう. 区間は [l, r)\n i64 lrmask(int l, int r) { return (1LL << r) - (1LL << l); }\n i64 sub_bit(i64 x, int l, int r) { i64 b = x & ((1LL << r) - (1LL << l)); return b >> l; } // r溢れ可\n i64 bit_width(i64 x) { return 64 - __builtin_clzll(x) + (x == 0); }\n \n i64 popcount(i64 x) { return __builtin_popcountll(x); }\n i64 popcount(i64 x, int l, int r) { return __builtin_popcountll(sub_bit(x, l, r)); }\n i64 unpopcount(i64 x) { return bit_width(x) - __builtin_popcountll(x); } // 最上位bitより下のみ\n i64 unpopcount(i64 x, int l, int r) { return r - l - __builtin_popcountll(sub_bit(x, l, r)); } // 最上位bitより上も含まれうる\n bool is_pow2(i64 x) { return __builtin_popcountll(x) == 1; } // xが負のときは常にfalse\n bool is_pow4(i64 x) { return __builtin_popcountll(x) == 1 && __builtin_ctz(x) % 2 == 0; }\n //bool is_pow4(ll x) { return __builtin_popcountll(x) == 1 && (x&0x55555555); }\n \n int top_bit(i64 x) { return 63 - __builtin_clzll(x);} // 2^kの位 (x > 0)\n int bot_bit(i64 x) { return __builtin_ctzll(x);} // 2^kの位 (x > 0)\n int next_bit(i64 x, int k) { // upper_bound\n x >>= (k + 1);\n int pos = k + 1;\n while (x > 0) {\n if (x & 1) return pos;\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int prev_bit(i64 x, int k) {\n // k = min(k, bit_width(x)); ?\n int pos = 0;\n while (x > 0 && pos < k) {\n if (x & 1) {\n if (pos < k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n int kth_bit(i64 x, int k) { // kは1-indexed\n int pos = 0, cnt = 0;\n while (x > 0) {\n if (x & 1) {\n cnt++;\n if (cnt == k) return pos;\n }\n x >>= 1;\n pos++;\n }\n return -1;\n }\n i64 msb(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // mask\n i64 lsb(i64 x) { return (x & -x); } // mask\n \n int countl_zero(i64 x) { return __builtin_clzll(x); }\n int countl_one(i64 x) { // countl_oneと定義が異なるので注意\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n }\n int countr_zero(i64 x) { return __builtin_ctzll(x); } // x=0のとき64\n int countr_one(i64 x) { int ret = 0; while (x & 1) { x >>= 1; ret++; } return ret; }\n // int countr_one(ll x) { return __builtin_popcount(x ^ (x & -~x));\n\n i64 l_one(i64 x) { // 最上位で連なってる1のmask\n if (x == 0) return 0;\n i64 ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { ret += 1LL << k; k--; }\n return ret;\n }\n \n int floor_log2(i64 x) { return 63 - __builtin_clzll(x); } // top_bit\n int ceil_log2(i64 x) { return 64 - __builtin_clzll(x - 1); }\n i64 bit_floor(i64 x) { if (x == 0) return 0; return 1LL << (63 - __builtin_clzll(x)); } // msb\n i64 bit_ceil(i64 x) { if (x == 0) return 0; return 1LL << (64 - __builtin_clzll(x - 1)); }\n \n i64 rotl(i64 x, int k) { // 有効bit内でrotate. オーバーフロー注意\n i64 w = bit_width(x); k %= w;\n return ((x << k) | (x >> (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotl(i64 x, i64 l, i64 m, i64 r) {}\n i64 rotr(i64 x, int k) {\n i64 w = bit_width(x); k %= w;\n return ((x >> k) | (x << (w - k))) & ((1LL << w) - 1);\n }\n // i64 rotr(i64 x, i64 l, i64 m, i64 r) {}\n i64 bit_reverse(i64 x) { // 有効bit内で左右反転\n i64 r = 0, w = bit_width(x);\n for (i64 i = 0; i < w; i++) r |= ((x >> i) & 1) << (w - i - 1);\n return r;\n }\n // i64 bit_reverse(i64 x, int l, int r) {}\n \n bool is_palindrome(i64 x) { return x == bit_reverse(x); }\n bool is_palindrome(i64 x, int l, int r) { i64 b = sub_bit(x, l, r); return b == bit_reverse(b); }\n i64 concat(i64 a, i64 b) { return (a << bit_width(b)) | b; } // オーバーフロー注意\n i64 erase(i64 x, int l, int r) { return x >> r << l | x & ((1LL << l) - 1); } // [l, r) をカット\n \n i64 hamming(i64 a, i64 b) { return __builtin_popcountll(a ^ b); }\n i64 hamming(i64 a, i64 b, int l, int r) { return __builtin_popcountll(sub_bit(a, l, r) ^ sub_bit(b, l, r)); }\n i64 compcount(i64 x) { return (__builtin_popcountll(x ^ (x >> 1)) + (x & 1)) / 2; }\n i64 compcount2(i64 x) { return compcount(x & (x >> 1)); } // 長さ2以上の連結成分の個数\n i64 adjacount(i64 x) { return __builtin_popcountll(x & (x >> 1)); } // 隣接する1のペアの個数\n \n i64 next_combination(i64 x) {\n i64 t = x | (x - 1); return (t + 1) | (((~t & -~t) - 1) >> (__builtin_ctzll(x) + 1));\n }\n} using namespace bit_function;\n\nnamespace util_function {\n namespace Std = std;\n __int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n // assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n // assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n }\n int per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n }\n int mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n return x - y * per(x, y);\n } // https://yukicoder.me/problems/no/2781\n int floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n }\n int ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n }\n int round(int x, int y) { // (ld)(x/y)を小数点第1位について四捨五入\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n }\n int round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0 && k >= 0);\n if (k == 0) return (x * 2 + y) / (y * 2);\n x /= y * POW(10, k - 1);\n if (x % 10 >= 5) return (x + 10 - x % 10) * POW(10, k - 1);\n return x * POW(10, k - 1);\n }\n int round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = x / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n }\n ld round(ld x, int k) { // xを10^kの位に関して四捨五入. to_string(x, k)優先\n // x += EPS;\n ld d = pow(10, -k);\n return Std::round(x * d) / d;\n }\n ld floor(ld x, int k) { // xを10^kの位に関してflooring\n // x += EPS;\n ld d = pow(10, -k);\n return Std::floor(x * d) / d; // 未verify\n }\n ld ceil(ld x, int k) { // xを10^kの位に関してceiling\n // x -= EPS;\n ld d = pow(10, -k);\n return Std::ceil(x * d) / d; // 未verify\n }\n // int kth(int x, int y, int k) { // x / yの10^kの位の桁\n // }\n int floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return Std::floor(x / y);\n // floor(x) = ceil(x - 1) という話も\n }\n int ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return Std::ceil(x / y);\n // ceil(x) = floor(x + 1)\n }\n int perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return Std::floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -Std::floor(x / fabs(y));\n if (x < 0 && y < 0) return Std::floor(x / y) + (x - Std::floor(x/y)*y < -EPS);\n return Std::floor(x / y) - (x - Std::floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n }\n ld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n }\n int seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\n int modf(ld x) {\n if (x < 0) return ceill(x);\n else return floorl(x);\n }\n // 正なら+EPS, 負なら-EPSしてから、文字列に直して小数点以下を捨てる?\n int seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n }\n int seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n }\n\n int floor_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now <= x) {\n now *= base;\n if (now <= x) ret++;\n }\n return ret;\n }\n int ceil_log(int base, int x) {\n assert(base >= 2);\n int ret = 0, now = 1;\n while (now < x) {\n now *= base;\n ret++;\n }\n return ret;\n }\n\n template <class T> pair<T, T> max(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n }\n template <class T> pair<T, T> min(const pair<T, T> &a, const pair<T, T> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n }\n \n template <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n }\n template <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n }\n template <class T> T mid(T a, T b, T c) { // 誤差対策TODO\n return a + b + c - Std::max({a, b, c}) - Std::min({a, b, c});\n }\n template <class T> void Sort(T &a, T &b, bool rev = false) { \n if (rev == false) if (a > b) swap(a, b);\n else if (b > a) swap(b, a);\n }\n template <typename T, typename... Args>\n void Sort(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.begin(), vec.end());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n template <typename T, typename... Args>\n void Sortr(T& a, T& b, T& c, Args&... args) {\n vector<T> vec = {a, b, c, args...};\n sort(vec.rbegin(), vec.rend());\n auto it = vec.begin();\n a = *it++; b = *it++; c = *it++;\n int dummy[] = { (args = *it++, 0)... };\n static_cast<void>(dummy);\n }\n\n istream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n }\n ostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n }\n \n __int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n }\n __int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n __int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n }\n \n string to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n \n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n }\n string to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n }\n string to_string(char c) { string s = \"\"; s += c; return s; }\n} using namespace util_function;\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n \n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n\ntemplate<typename T>\nclass Compress { // 試験運用, バグったらTをintにする\npublic:\n int sz = 0;\n // gp_hash_table<T, int, custom_hash> Z;\n // gp_hash_table<int, T, custom_hash> UZ;\n unordered_map<T, int> Z; // 元の値 -> 圧縮した値\n unordered_map<int, T> UZ; // 圧縮した値 -> 元の値\n \n Compress() {}\n Compress(const vector<T> &V, T base = 0) {\n this->sz = base;\n set<T> s(V.begin(), V.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2, T base = 0) {\n this->sz = base;\n vector<T> V3 = V2;\n V3.insert(V3.end(), V1.begin(), V1.end());\n set<T> s(V3.begin(), V3.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2, const vector<T> &V3, T base = 0) {\n this->sz = base;\n vector<T> V4 = V1;\n V4.insert(V4.end(), V2.begin(), V2.end());\n V4.insert(V4.end(), V3.begin(), V3.end());\n set<T> s(V4.begin(), V4.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n Compress(const vector<T> &V1, const vector<T> &V2,\n const vector<T> &V3, const vector<T> &V4, T base = 0) {\n this->sz = base;\n vector<T> V5 = V1;\n V5.insert(V5.end(), V2.begin(), V2.end());\n V5.insert(V5.end(), V3.begin(), V3.end());\n V5.insert(V5.end(), V4.begin(), V4.end());\n set<T> s(V5.begin(), V5.end());\n \n for (T x : s) {\n this->Z[x] = this->sz;\n this->UZ[this->sz] = x;\n this->sz++;\n }\n }\n \n vector<int> zip(const vector<T> &V) {\n vector<int> ret(V.size());\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = Z[V[i]];\n }\n return ret;\n }\n \n vector<T> unzip(const vector<int> &V) {\n vector<T> ret(V.size());\n for (int i = 0; i < (int)V.size(); i++) {\n ret[i] = UZ[V[i]];\n }\n return ret;\n }\n \n int size() { return sz; }\n \n T encode(int x) { return Z[x]; }\n int decode(T x) {\n if (UZ.find(x) == UZ.end()) return -1; // xが元の配列に存在しないとき\n return UZ[x];\n }\n};\n \n \n#pragma endregion\n\n// https://atcoder.jp/contests/abc350/submissions/52583195\ntemplate <class S, S(*op)(S, S), S(*e)(), class F, S(*act)(F, S), F(*comp)(F, F), F(*id)()>\nclass Implicit_treap {\n\tinline static bool first_call = true;\n\tinline static mt19937 rnd;\n\n\tstruct Node {\n\t\tS value;\t\t\t\t// 頂点の値\n\t\tS acc;\t\t\t\t\t// 部分木のノードの総和\n\t\tF lazy;\t\t\t\t\t// 部分木のノードへの遅延作用\n\t\tuint64_t priority;\t // ランダムに決めた優先度. 多分uint32_tで十分\n\t\tint cnt;\t\t\t\t// 部分木のノード数\n\t\tbool rev;\t\t\t\t// 部分木が反転されているか\n\t\tNode* l, * r;\t\t\t// 左右の子へのポインタ\n\t\tNode(S value, uint64_t priority) : value(value), acc(e()), lazy(id()), priority(priority),\n\t\t\tcnt(1), rev(false), l(nullptr), r(nullptr) {}\n\t};\n\n\tNode* root;\n\n\tint cnt(Node* t) {\n\t\treturn t ? t->cnt : 0;\n\t}\n\n\tS acc(Node* t) {\n\t\treturn t ? t->acc : e();\n\t}\n\n\tvoid update_cnt(Node* t) {\n\t\tif (t) t->cnt = cnt(t->l) + 1 + cnt(t->r);\n\t}\n\n\tvoid update_acc(Node* t) {\n\t\tif (t) t->acc = op(acc(t->l), op(t->value, acc(t->r)));\n\t}\n\n\tvoid pushup(Node* t) {\n\t\tupdate_cnt(t);\n\t\tupdate_acc(t);\n\t}\n\n\tvoid pushdown(Node* t) {\n\t\tif (t && t->rev) {\n\t\t\tt->rev = false;\n\t\t\tswap(t->l, t->r);\n\t\t\tif (t->l) t->l->rev ^= 1;\n\t\t\tif (t->r) t->r->rev ^= 1;\n\t\t}\n\t\tif (t && t->lazy != id()) {\n\t\t\tif (t->l) {\n\t\t\t\tt->l->lazy = comp(t->lazy, t->l->lazy);\n\t\t\t\tt->l->acc = act(t->lazy, t->l->acc);\n\t\t\t}\n\t\t\tif (t->r) {\n\t\t\t\tt->r->lazy = comp(t->lazy, t->r->lazy);\n\t\t\t\tt->r->acc = act(t->lazy, t->r->acc);\n\t\t\t}\n\n\t\t\tt->value = act(t->lazy, t->value);\n\t\t\tt->lazy = id();\n\t\t}\n\t\tpushup(t);\n\t}\n\n\tvoid split(Node* t, int key, Node*& l, Node*& r) {\n\t\tif (!t) {\n\t\t\tl = r = nullptr;\n\t\t\treturn;\n\t\t}\n\t\tpushdown(t);\n\t\tint implicit_key = cnt(t->l);\n\n\t\tif (key <= implicit_key) {\n\t\t\tsplit(t->l, key, l, t->l);\n\t\t\tr = t;\n\t\t}\n\t\telse {\n\t\t\tsplit(t->r, key - implicit_key - 1, t->r, r);\n\t\t\tl = t;\n\t\t}\n\t\tpushup(t);\n\t}\n\n\tvoid merge(Node*& t, Node* l, Node* r) {\n\t\tpushdown(l);\n\t\tpushdown(r);\n\t\tif (!l) t = r;\n\t\telse if (!r) t = l;\n\t\telse if (l->priority > r->priority) {\n\t\t\tmerge(l->r, l->r, r);\n\t\t\tt = l;\n\t\t}\n\t\telse {\n\t\t\tmerge(r->l, l, r->l);\n\t\t\tt = r;\n\t\t}\n\n\t\tpushup(t);\n\t}\n\n\tvoid get_all(Node* t, vector<S>& seq) {\n\t\tif (!t) return;\n\t\tpushdown(t);\n\t\tget_all(t->l, seq);\n\t\tseq.emplace_back(t->value);\n\t\tget_all(t->r, seq);\n\t}\n\npublic:\n\tImplicit_treap() : root(nullptr) {\n\t\tif (Implicit_treap::first_call) {\n\t\t\trnd = mt19937((int)time(NULL));\n\t\t\tImplicit_treap::first_call = false;\n\t\t}\n\t}\n\n\tImplicit_treap(const vector<S>& a) : root(nullptr) {\n\t\tif (Implicit_treap::first_call) {\n\t\t\trnd = mt19937((int)time(NULL));\n\t\t\tImplicit_treap::first_call = false;\n\t\t}\n\n\t\tfor (int i = 0; i < a.size(); i++) {\n\t\t\tinsert(i, a[i]);\n\t\t}\n\t}\n\n\tbool empty() {\n\t\treturn !(bool)root;\n\t}\n\n\tint size() {\n\t\treturn cnt(root);\n\t}\n\n\tvoid apply(int l, int r, F f) {\n\t\tif (l >= r) return;\n\t\tNode* lt, * mt, * rt;\n\t\tsplit(root, l, lt, rt);\n\t\tsplit(rt, r - l, mt, rt);\n\t\tif (mt) {\n\t\t\tmt->lazy = comp(f, mt->lazy);\n\t\t\tmt->acc = act(f, mt->acc);\n\t\t}\n\t\tmerge(rt, mt, rt);\n\t\tmerge(root, lt, rt);\n\t}\n\n\tvoid apply(int i, F f) {\n\t\tapply(i, i + 1, f);\n\t}\n\n\tS prod(int l, int r) {\n\t\tif (l >= r) return e();\n\t\tNode* lt, * mt, * rt;\n\t\tsplit(root, l, lt, rt);\n\t\tsplit(rt, r - l, mt, rt);\n\t\tS res = acc(mt);\n\t\tmerge(rt, mt, rt);\n\t\tmerge(root, lt, rt);\n\n\t\treturn res;\n\t}\n\n\tS get(int i) {\n\t\treturn prod(i, i + 1);\n\t}\n\n\tvoid insert(int i, S x) {\n\t\tNode* lt, * rt;\n\t\tsplit(root, i, lt, rt);\n\t\tmerge(lt, lt, new Node(x, rnd()));\n\t\tmerge(root, lt, rt);\n\t}\n\n\tvoid erase(int i) {\n\t\tNode* lt, * mt, * rt;\n\t\tsplit(root, i + 1, lt, rt);\n\t\tsplit(lt, i, lt, mt);\n\t\tmerge(root, lt, rt);\n\t}\n\n\tvoid reverse(int l, int r) {\n\t\tif (l >= r) return;\n\t\tNode* lt, * mt, * rt;\n\t\tsplit(root, l, lt, rt);\n\t\tsplit(rt, r - l, mt, rt);\n\t\tmt->rev ^= 1;\n\t\tmerge(rt, mt, rt);\n\t\tmerge(root, lt, rt);\n\t}\n\n\tvoid rotate(int l, int m, int r) {\n\t\treverse(l, r);\n\t\treverse(l, l + r - m);\n\t\treverse(l + r - m, r);\n\t}\n\n\tImplicit_treap split(int key) {\n\t\tNode* l, * r;\n\t\tsplit(root, key, l, r);\n\t\troot = l;\n\t\tImplicit_treap ret;\n\t\tret.root = r;\n\t\treturn ret;\n\t}\n\n\tvoid merge(Implicit_treap& IT) {\n\t\tmerge(root, root, IT.root);\n\t}\n\n\tvector<S> get_all() {\n\t\tvector<S> seq;\n\t\tget_all(root, seq);\n\t\treturn seq;\n\t}\n};\n\nusing S = pair<int, int>;\nS op(S x, S y) { return min({x, y}); }\nS e() { return {INF, INF}; }\n\nusing F = int;\nS mapping(F f, S x) { return {x.first, x.second + f}; }\nF composition(F f, F g) { return f + g; }\nF id() { return 0; }\n\nsigned main() {\n int K;\n string s;\n cin >> s >> K;\n int N = s.size();\n\n vector<S> A(N);\n for (int i = 0; i < N; i++) {\n A[i].first = s[i] - 'a';\n A[i].second = i;\n }\n\n Implicit_treap<S, op, e, F, mapping, composition, id> tr(A);\n\n int br = false;\n for (int i = 0; i < N; i++) {\n auto p = tr.prod(i, min(i + K + 1, N)); // (最小値, 最小値を取るindex)\n int dest = i;\n\n if (abs(dest - p.second) <= K) {\n tr.erase(p.second);\n tr.insert(i, {p.first, i});\n tr.apply(i + 1, p.second + 1, 1);\n K -= abs(dest - p.second);\n } else break;\n }\n\n vector<S> ret = tr.get_all();\n vector<int> ans(N);\n for (int i = 0; i < N; i++) ans[i] = ret[i].first;\n\n for (int i = 0; i < (int)ans.size(); i++) {\n cout << (char)('a' + ans[i]) << (i != (int)ans.size() - 1 ? \"\" : \"\\n\");\n }\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 50360, "score_of_the_acc": -1.7715, "final_rank": 20 }, { "submission_id": "aoj_0365_9573793", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T,T e>\nstruct segtreesum {\n\tvector<long long> v;\n\tlong long n;\n\tT f(T a,T b){\n\t\treturn a + b;\n\t}\n\tsegtreesum(long long n) : n(n) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtreesum(vector<T> x) : n(x.size()) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1;i >= 0;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,long long b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\ntemplate<typename T,T e>\nstruct segtree {\n\tvector<long long> v;\n\tlong long n;\n\tT f(T a,T b){\n\t\treturn min(a,b);\n\t}\n\tsegtree(long long n) : n(n) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtree(vector<T> x) : n(x.size()) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1;i >= 0;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,long long b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tstring S;\n\tcin >> S;\n\tint n = S.size(),k;\n\tvector<int> s(n);\n\tfor(int i = 0;i < n;i++){\n\t\ts[i] = S[i];\n\t}\n\tcin >> k;\n\tsegtree<int,'z' + 1> seg(s);\n\tsegtreesum<int,0> cou(n);\n\tstring ans = \"\";\n\tfor(int i = 0;i < n;i++){\n\t\tint low = 0,high = n - 1;\n\t\twhile(low < high){\n\t\t\tint mid = (low + high + 1) / 2;\n\t\t\tif(mid - cou.prod(0,mid + 1) <= k){\n\t\t\t\tlow = mid;\n\t\t\t}else{\n\t\t\t\thigh = mid - 1;\n\t\t\t}\n\t\t}\n\t\tint it = seg.prod(0,low + 1);\n\t\tlow = 0;\n\t\twhile(low < high){\n\t\t\tint mid = (low + high) / 2;\n\t\t\tif(seg.prod(0,mid + 1) != it){\n\t\t\t\tlow = mid + 1;\n\t\t\t}else{\n\t\t\t\thigh = mid;\n\t\t\t}\n\t\t}\n\t\tint pos = low;\n\t\tk -= pos - cou.prod(0,pos + 1);\n\t\tans += (char)it;\n\t\tcou.set(pos,1);\n\t\tseg.set(pos,'z' + 1);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 10848, "score_of_the_acc": -0.5955, "final_rank": 14 }, { "submission_id": "aoj_0365_9503547", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define rep(i, m, n) for (int i = (int)(m); i < (int)(n); i++)\n\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\n\nint n0;\nint a[100009];\n\nint INF = 0;\n\ntypedef long long ll;\n#define all(v) v.begin(), v.end()\n\n// sort(a.begin(), a.end());\n// long long x = lower_bound(a.begin(), a.end(), t) - a.begin();\n\nclass segment_tree {\nprivate:\n\tint size;\n\tvector<ll> v;\npublic:\n\tsegment_tree(vector<ll> w) {\n\t\tn0 = 1; while (n0 < w.size()) n0 *= 2;\n\t\tsize = n0;\n\t\tv.resize(2 * n0, INF);\n\t\tfor (int i = 0; i < w.size(); i++) v[i + size] = w[i];\n\t\tfor (int i = n0 - 1; i >= 1; i--) v[i] = v[2 * i + 0] + v[2 * i + 1];\n\t}\n\tvoid add(int pos, ll x) {\n\t\tpos += size;\n\t\tv[pos] += x;\n\t\twhile (pos > 1) {\n\t\t\tpos /= 2;\n\t\t\tv[pos] = v[pos * 2 + 0] + v[pos * 2 + 1];\n\t\t}\n\t}\n\tvoid set(int pos, ll x) {\n\t\tpos += size;\n\t\tv[pos] = x;\n\t\twhile (pos > 1) {\n\t\t\tpos /= 2;\n\t\t\tv[pos] = v[pos * 2 + 0] + v[pos * 2 + 1];\n\t\t}\n\t}\n\tint query(int l, int r) const {\n\t\tl += size; r += size;\n\t\tint res = 0;\n\t\twhile (l != r) {\n\t\t\tif (l & 1) res += v[l++];\n\t\t\tif (r & 1) res += v[--r];\n\t\t\tl /= 2; r /= 2;\n\t\t}\n\t\treturn res;\n\t}\n};\n\n\nint main() {\n\tstring s;\n\tll k;\n\tcin >> s >> k;\n\tvector<set<ll>> alp(26);\n\tvector<ll> mi(26, 0);\n\tset<ll> us;\n\tmap<ll, ll> m;\n\tvector<ll> w(26, 0);\n\tsegment_tree seg(w);\n\trep(i, 0, s.size()) {\n\t\tll x = s[i] - 'a';\n\t\tif (x == 25) m[i] = 0;\n\t\telse m[i] = seg.query(x+1, 26);\n\t\tseg.add(x, 1);\n\t\talp[x].insert(i);\n\t}\n\tstring t = \"\";\n\trep(j, 0, s.size()) {\n\t\tif (k == 0) break;\n\t\trep(i, 0, 26) {\n\t\t\tchar c = 'a' + i;\n\t\t\tbool ok = false;\n\t\t\tfor (auto z : alp[i]) {\n\t\t\t\tif (m[z]-mi[i] <= k) {\n\t\t\t\t\tk -= m[z];\n\t\t\t\t\tt += c;\n\t\t\t\t\tus.insert(z);\n\t\t\t\t\talp[i].erase(z);\n\t\t\t\t\tok = true;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse { mi[i]++; break; }\n\t\t\t}\n\t\t\tif (ok) break;\n\t\t}\n\t}\n\trep(i, 0, s.size()) {\n\t\tif (us.count(i)) continue;\n\t\telse t += s[i];\n\t}\n\tcout << t << endl;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 25680, "score_of_the_acc": -1.1493, "final_rank": 19 }, { "submission_id": "aoj_0365_9462745", "code_snippet": "//\n#include<iostream>\n#include<string>\n#include<queue>\n#include<vector>\n#include<cassert>\n#include<random>\n#include<set>\n#include<map>\n#include<cassert>\n#include<unordered_map>\n#include<bitset>\n#include<algorithm>\nusing namespace std;\nusing ll = long long;\nconst int inf=1<<30;\nconst ll INF=1LL<<62;\nusing P=pair<int,int>;\nusing PP=pair<ll,P>; \n\n\nusing Type=ll;\n\nType op(Type x, Type y){\n //(x,y)を比較する任意の演算子.今回はmaxとした\n return (x+y);\n}\n\nType e(){\n //initialize value\n return 0;\n}\n\n\ntemplate<class Type,\n Type (*op)(Type,Type),\n Type (*e)()\n > class segment_tree{\n \n public:\n \n std::vector<Type> dat;\n int n=1;\n segment_tree(int n_){ \n while(n < n_){\n n*=2;\n }\n dat = std::vector<Type>(2*n-1,e());// 0,1,2,...,2*n-1,2*n-2\n }\n\n ~segment_tree(){\n std::vector<Type>().swap(dat);\n }\n\n void set(int k,Type a){\n update(k,a);\n }\n\n\n void update(int k,Type a){\n k+=n-1;\n dat[k] = a;\n while(k>0){\n k = (k-1)/2;\n dat[k]=op(dat[2*k+1],dat[2*k+2]);\n }\n }\n\n //[a,b)\n Type query(int a,int b,int k,int l,int r){\n if(r<=a || b<=l) return e();\n if(a<=l && r<=b) return dat[k];\n else{\n\n Type vl = query(a,b,2*k+1,l,(l+r)/2);\n Type vr = query(a,b,2*k+2,(l+r)/2,r);\n return op(vl,vr);\n }\n }\n\n //[a,b)の範囲でのmax\n Type query(int a,int b){\n return query(a,b,0,0,n);\n }\n\n Type operator[](int index){\n \n return get(index);\n }\n\n Type get(int index){\n index += n-1;\n return dat[index];\n }\n\n void add(int index,Type val){\n update(index,op(get(index),val));\n }\n};\nint main(){\n string s;\n cin>>s;\n ll K;\n cin>>K;\n int N=s.size();\n vector<int> p(N);\n const int M=26;\n\n\n segment_tree<Type,op,e> seg(N+5);\n \n vector<set<int>> pos(M);\n\n for(int i=0;i<N;i++){\n p[i]=s[i]-'a';\n pos[p[i]].insert(i);\n }\n\n \n vector<char> ans;\n\n for(int i=0;i<N;i++){\n for(char c=0;c<M;c++){\n if(pos[c].empty())continue;\n int index=*pos[c].begin();\n\n //[0,index)にあるcの数\n int flg=index - seg.query(0,index);\n\n if(flg>K)continue;\n K-=flg;\n ans.push_back('a'+c);\n pos[c].erase(index);\n seg.add(index,1);\n break;\n }\n }\n\n for(int i=0;i<N;i++){\n cout<<ans[i];\n }\n cout<<endl;\n\n\n\n\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 17688, "score_of_the_acc": -0.6376, "final_rank": 16 }, { "submission_id": "aoj_0365_9217813", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct SegmentTree {\n vector<int> s; int seg_len;\n\n SegmentTree(int n) {\n seg_len = n;\n while (__builtin_popcount(seg_len) != 1) seg_len++;\n s.reserve(2 * seg_len);\n }\n\n void insert(int i) {\n int pos = i + seg_len;\n while (pos >= 1) s[pos] += 1, pos /= 2;\n }\n\n int num_earlier(int i) {\n int res = 0, l = seg_len, r = i + seg_len;\n while (l < r) {\n if (l % 2 == 1) res += s[l], l++;\n if (r % 2 == 1) res += s[r - 1], r--;\n l /= 2, r /=2;\n }\n return res;\n }\n};\n\nint main() {\n string s; cin >> s;\n int k; cin >> k;\n \n unordered_map<char,queue<int>> index;\n for (int i = 0; i < s.size(); i++) index[s[i]].push(i);\n \n SegmentTree st(s.size());\n for (int i = 0; i < s.size(); i++) {\n for (int j = 0; j < 26; j++) {\n char c = j + 'a';\n if (index[c].empty()) continue;\n int idx = index[c].front();\n int swaps = idx - st.num_earlier(idx);\n if (swaps <= k) {\n k -= swaps;\n st.insert(idx);\n index[c].pop();\n cout << c;\n break;\n } \n }\n }\n cout << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 5840, "score_of_the_acc": -0.3349, "final_rank": 10 } ]
aoj_0364_cpp
Dungeon Bob is playing a popular game called "Dungeon". The game is played on a rectangular board consisting of W × H squares. Each square is identified with its column and row number, thus the square located in the x -th column and the y -th row is represented as ( x , y ). The left-most square in the top row is (0, 0) and the right-most square in the bottom row is ( W -1, H -1). Bob moves a character "BomBom" to clear the game. BomBom is initially located at (0, 0). The game is won if Bob successfully destroys all the enemy characters on the board by manipulating BomBom cleverly. The enemy characters are fixed on specific squares, and Bob can manipulate BomBom using the following two operations any number of times. One-square movement in the up, down, left, or right direction within the board Using a bomb, eliminate all the enemy characters that are located in the same column and row as that of BomBom BomBom consumes a Cost when it moves from one square to another. BomBom can use a bomb any number of times without consuming a Cost. Use of a bomb has no effect on BomBom’s behavior and it can move even to a square where an enemy character is located. Given the board size and enemy information, make a program to evaluate the minimum Cost BomBom consumes before it destroys all enemy characters. Input The input is given in the following format. W H N x_1 y_1 x_2 y_2 : x_N y_N The first line provides the number of squares in the horizontal direction W (1 ≤ W ≤ 10 5 ), in the vertical direction H (1 ≤ H ≤ 10 5 ), and the number of enemy characters N (1 ≤ N ≤ 10 5 ). Each of the subsequent N lines provides location information of the i -th enemy, column x_i (0 ≤ x_i ≤ W -1) and row y_i (0 ≤ y_i ≤ H -1). The number of enemy characters in a specific square can be either one or zero. Output Output the minimum Cost in a line. Sample Input 1 5 4 4 0 3 1 1 2 2 2 3 Sample Output 1 2 Sample Input 2 6 6 5 2 1 5 2 3 3 1 4 1 5 Sample Output 2 4 Sample Input 3 8 8 4 6 0 7 0 0 6 0 7 Sample Output 3 0
[ { "submission_id": "aoj_0364_10866790", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i=0;i<(ll)(N);i++)\n#define fi first \n#define se second\n#define all(X) (X).begin(),(X).end()\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\nint main(){\n ll W,H,N;cin>>W>>H>>N;\n vector<pair<ll,ll>>X(N);\n rep(i,N)cin>>X[i].fi>>X[i].se;\n sort(all(X));\n vector<ll>M(N+1,0);\n for(int i = N-1;i>=0;i--){\n M[i] = max(M[i+1],X[i].se);\n }\n ll ans = M[0];\n rep(i,N){\n ans = min(ans,X[i].fi+M[i+1]);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5436, "score_of_the_acc": -0.341, "final_rank": 13 }, { "submission_id": "aoj_0364_10863266", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int w, h, n; cin >> w >> h >> n;\n int sz = 1e5;\n vector<int> MX(sz + 1);\n rep(i, n) {\n int x, y; cin >> x >> y;\n if(y)chmax(MX[y - 1], x);\n }\n for (int i = sz - 1; i >= 0; --i)chmax(MX[i], MX[i + 1]);\n int ans = inf;\n rep(i, sz + 1) {\n chmin(ans, i + MX[i]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3712, "score_of_the_acc": -0.1316, "final_rank": 4 }, { "submission_id": "aoj_0364_10860397", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int W, H, N;\n cin >> W >> H >> N;\n \n vector<int> A(H);\n rep(i, 0, N) {\n int x, y;\n cin >> x >> y;\n A[y] = max(A[y], x);\n }\n \n for (int i = H - 2; i >= 0; --i) A[i] = max(A[i], A[i + 1]);\n\n int ans = H - 1;\n rep(i, 0, H - 1) {\n ans = min(ans, i + A[i + 1]);\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3580, "score_of_the_acc": -0.013, "final_rank": 2 }, { "submission_id": "aoj_0364_10858268", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n\tint W, H, N;cin >> W >>H >> N;\n\tvector<pair<int, int>> st;\n\tint res = (int)1e9;\n\tfor (int i = 0;i < N;i++) {\n\t\tint x, y;cin >> x >> y;\n\t\tst.push_back({x, y});\n\n\t}\n\tsort(st.begin(), st.end());\n\tvector<int> LMX(N, 0);\n\tint mx = 0;\n\tfor (int i = N-1;i >= 0;i--) {\n\t\tmx = max(mx, st[i].second);\n\t\tLMX[i] = mx;\n\t}\n\tres = mx;\n\tfor (int i = 0;i < N;i++) {\n\t\tif (i+1 == N) {\n\t\t\tres = min(res, st[i].first);continue;\n\t\t}\n\t\tres = min(res, st[i].first + LMX[i+1]);\n\t}\n\tcout << res << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4560, "score_of_the_acc": -0.18, "final_rank": 5 }, { "submission_id": "aoj_0364_10848630", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nconst ll MOD=10000000;\nconst ll INF=1000000001;\nconst ll LINF=4000000000000000010;\nconst double EPS=1e-9;\nint dx[5]={0,1,0,-1,0};\nint dy[5]={1,0,-1,0,0};\nvector<int> v[100010];\nint ma[100010];\nint main(){\n int w,h,n;cin>>w>>h>>n;\n for(int i=0;i<n;i++){\n int x,y;cin>>x>>y;\n v[x].push_back(y);\n }\n for(int i=w-1;i>=1;i--){\n int maa=0;\n for(auto a:v[i]){\n maa=max(a,maa);\n }\n ma[i-1]=max(ma[i],maa);\n }\n int ans=INF;\n for(int i=0;i<w;i++){\n int s=i+ma[i];\n ans=min(s,ans);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 9304, "score_of_the_acc": -0.5614, "final_rank": 18 }, { "submission_id": "aoj_0364_10732430", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug.hpp>\n#else\n#define debug(...)\n#endif\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int W, H, N;\n cin >> H >> W >> N;\n multiset<int> XS, YS;\n vector<vector<int>> X(H), Y(W);\n for (int i = 0; i < N; i++) {\n int x, y;\n cin >> x >> y;\n X[x].emplace_back(y);\n Y[y].emplace_back(x);\n XS.insert(x);\n YS.insert(y);\n }\n\n int ans = min(H, W);\n // x 座標を走査\n for (int i = 0; i < H; i++) {\n // x 座標が [0, i + 1) は駆逐\n for (auto y : X[i]) YS.erase(YS.find(y));\n // それ以外での y 座標の max\n ans = min(ans, i + (YS.empty() ? 0 : *YS.rbegin()));\n }\n\n // y 座標を走査\n for (int i = 0; i < W; i++) {\n // y 座標が [0, i + 1) は駆逐\n for (auto x : Y[i]) XS.erase(XS.find(x));\n // それ以外での x 座標の max\n ans = min(ans, i + (XS.empty() ? 0 : *XS.rbegin()));\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 20900, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0364_9573837", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T,T e>\nstruct segtree {\n\tvector<long long> v;\n\tlong long n;\n\tT f(T a,T b){\n\t\treturn max(a,b);\n\t}\n\tsegtree(long long n) : n(n) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtree(vector<T> x) : n(x.size()) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1;i >= 0;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,long long b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tint w,h,n;\n\tcin >> w >> h >> n;\n\tvector<pair<int,int>> a(n,pair<int,int>());\n\tsegtree<int,0> seg(w + 1);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i].first >> a[i].second;\n\t\tseg.set(a[i].first,max(seg[a[i].first],a[i].second));\n\t}\n\tint ans = INT_MAX;\n\tfor(int i = 0;i <= w;i++){\n\t\tint it = seg.prod(i + 1,w + 1);\n\t\tans = min(ans,i + it);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5460, "score_of_the_acc": -0.3423, "final_rank": 14 }, { "submission_id": "aoj_0364_9475303", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> P;\nP pp[100000];\nint main(void)\n{\n\tint w,h,n,mx,i,my,mm;\n\tcin >>w>>h>>n;\n\tfor(i=0;i<n;i++)\t{\n\t\tcin >>pp[i].first>>pp[i].second;\n\t}\n\tsort(pp,pp+n);\n\tmx=pp[n-1].first;\n\tmy=0;\n\tmm=mx+my;\n\tfor(i=n-2;i>=0;i--)\t{\n\t\tmx=pp[i].first;\n\t\tmy=max(my,pp[i+1].second);\n\t\tmm=min(mm,mx+my);\n\t}\n\tmy=max(my,pp[0].second);\n\tmm=min(mm,my);\n\tcout <<mm<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3880, "score_of_the_acc": -0.3634, "final_rank": 15 }, { "submission_id": "aoj_0364_9464128", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int,int>;\n\nint n;\nstring s;\n\nint main(){\n //\n int w,h,n;\n cin >> w >> h >> n;\n \n vector<pair<int,int>> graph(n);\n for (int i = 0;i < n;i++){\n cin >> graph[i].first >> graph[i].second;\n }\n sort(graph.begin(),graph.end());\n\n vector<int> max_x(w);\n int cnt = 0;\n int ans = w;\n for (int i = n - 1;i >= 0;i--){\n ans = min(ans,graph[i].first + cnt);\n cnt = max(cnt,graph[i].second);\n }\n ans = min(ans,cnt);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4048, "score_of_the_acc": -0.2619, "final_rank": 6 }, { "submission_id": "aoj_0364_9425292", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int w, h, n;\n cin >> w >> h >> n;\n int x[n], y[n];\n int Max[w] = {};\n for (int i = 0; i < n; i++) {\n cin >> x[i] >> y[i];\n Max[x[i]] = max(Max[x[i]], y[i]);\n }\n for (int i = w - 2; i >= 0; i--) {\n Max[i] = max(Max[i], Max[i + 1]);\n }\n int Min = w - 1;\n for (int i = 0; i < w - 1; i++) { //曲がるところ\n Min = min(Min, Max[i + 1] + i);\n }\n cout << Min << \"\\n\";\n return(0);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4608, "score_of_the_acc": -0.2938, "final_rank": 11 }, { "submission_id": "aoj_0364_9033470", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N >> N >> N;\n vector<pair<int, int>> p(N);\n for(int i = 0; i < N; i++) {\n cin >> p[i].first >> p[i].second;\n }\n sort(p.begin(), p.end());\n vector<int> mx(N+1);\n for(int i = N-1; i >= 0; i--) {\n mx[i] = max(mx[i+1], p[i].second);\n }\n int ans = mx[0];\n for(int i = 0; i < N; i++) {\n ans = min(ans, p[i].first+mx[i+1]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4160, "score_of_the_acc": -0.2683, "final_rank": 7 }, { "submission_id": "aoj_0364_8370122", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct cell {\n\tint x, y;\n};\n\nint main() {\n\tint W, H, N;\n\tcin >> W >> H >> N;\n\tvector<cell> C(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> C[i].x >> C[i].y;\n\t}\n\tsort(C.begin(), C.end(), [](const cell& c1, const cell& c2) {\n\t\treturn c1.x != c2.x ? c1.x < c2.x : c1.y < c2.y;\n\t});\n\tvector<cell> st;\n\tfor (cell c : C) {\n\t\twhile (!st.empty() && st.back().y <= c.y) {\n\t\t\tst.pop_back();\n\t\t}\n\t\tst.push_back(c);\n\t}\n\tint answer = min(st[0].y, st.back().x);\n\tfor (int i = 1; i < st.size(); i++) {\n\t\tanswer = min(answer, st[i - 1].x + st[i].y);\n\t}\n\tcout << answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4188, "score_of_the_acc": -0.2699, "final_rank": 8 }, { "submission_id": "aoj_0364_8266841", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n\tint H, W, N;\n\tcin >> H >> W >> N;\n\tvector<vector<int>> A(H + 1);\n\tfor (int i = 0; i < N; i++){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tA[x].push_back(y);\n\t}\n\tint ans = 1e9;\n\tint m = 0;\n\tfor (int i = H; i >= 0; i--){\n\t\tans = min(ans, i + m);\n\t\tfor (int j : A[i]){\n\t\t\tm = max(m, j);\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8428, "score_of_the_acc": -0.5115, "final_rank": 17 }, { "submission_id": "aoj_0364_8140038", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,n) for(long long i=a;i<n;i++)\n#define repp(i,a,n) for(long long i=a;i>=n;i--)\n#define so(z) sort(z.begin(),z.end())\n#define sor(z) sort(z.rbegin(),z.rend())\n#define re(z) reverse(z.begin(),z.end())\n#define su(a) substr(a)\n#define sub(a,b) substr(a,b)\n#define yess cout<<\"YES\"<<nn\n#define noo cout<<\"NO\"<<nn\n#define yes cout<<\"Yes\"<<\"\\n\"\n#define no cout<<\"No\"<<\"\\n\"\n#define yesr cout<<\"Yes\"<<\"\\n\";return(0)\n#define nor cout<<\"No\"<<\"\\n\";return(0)\n#define fi first\n#define se second\n#define fr() front()\n#define mp make_pair\n#define pb push_back\n#define nn \"\\n\"\n#define ll long long\n#define mod 1000000007\n#define IM INT_MAX\n#define LM LONG_LONG_MAX\n#define gcd(x,y) __gcd(x,y) //最大公約数\n#define lcm(x,y) x/(__gcd(x,y))*y //最小公倍数\n#define prev(a) prev_permutation(a.begin(),a.end()) //辞書前\n#define next(a) next_permutation(a.begin(),a.end()) //辞書後\n#define get(s) getline(cin,s) // 空白の空いたstringの入力\n#define fixed(a) fixed<<setprecision(a) //小数点何桁か指定\n#define ro(a) round(a) //四捨五入\n#define ce(a) ceil(a) //切り上げ\n#define up(a,v) upper_bound(a.begin(),a.end(),v)\n#define lo(a,v) lower_bound(a.begin(),a.end(),v)\n#define bi(a,v) binary_bound(a.begin(),a.end(),v)\n#define pp priority_queue<pair<long long,long long>, vector<pair<long long,long long>>, greater<pair<long long,long long>> > // priority_queue\nusing namespace std;\nint main(){\n cin.tie(NULL);\n ios::sync_with_stdio(false);\n ll w,h,n,ans=LM;\n cin>>w>>h>>n;\n vector<ll>x(n),y(n),z(h+1,0);\n rep(i,0,n){\n cin>>x[i]>>y[i];\n z[y[i]]=max(z[y[i]],x[i]);\n }\n /*\n rep(i,0,h){\n cout<<z[i]<<\" \";\n }\n cout<<nn;\n */\n repp(i,h-2,0){\n z[i]=max(z[i],z[i+1]);\n }\n /*\n rep(i,0,h){\n cout<<z[i]<<\" \";\n }\n cout<<nn;\n */\n rep(i,0,h){\n ans=min(ans,z[i+1]+i);\n }\n cout<<ans<<nn;\n return(0);\n}\n/*\n00000\n0x000\nx0x00\n00x00\n\n000000\n00x000\n00000x\n000x00\n0x0000\n0x0000\n\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 5128, "score_of_the_acc": -0.1012, "final_rank": 3 }, { "submission_id": "aoj_0364_6971796", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0364.cc: Dungeon\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_H = 100000;\nconst int INF = 1 << 30;\n\n/* typedef */\n\n/* global variables */\n\nint mxs[MAX_H + 1];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int w, h, n;\n scanf(\"%d%d%d\", &w, &h, &n);\n\n for (int i = 0; i < n; i++) {\n int x, y;\n scanf(\"%d%d\", &x, &y);\n mxs[y] = max(mxs[y], x);\n }\n\n for (int y = h - 1; y >= 0; y--)\n mxs[y] = max(mxs[y], mxs[y + 1]);\n //for (int y = 0; y <= h; y++) printf(\"%d \",mxs[y]); putchar('\\n');\n\n int minl = INF;\n for (int y = 0; y < h; y++) {\n int l = y + mxs[y + 1];\n minl = min(minl, l);\n }\n\n printf(\"%d\\n\", minl);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0364_6901603", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\nusing namespace std;\nusing ll = long long;\n\nll ll_gcd(ll a, ll b) {\n\tif (a < b) return ll_gcd(b, a);\n\tll r;\n\twhile ((r = a % b)) {\n\t\ta = b;\n\t\tb = r;\n\t}\n\treturn b;\n}\n\nbool x(vector<ll>& z) {\n\tll now = 0;\n\tfor (int i = 0; i < z.size(); i++) {\n\t\tif (now < i * 10)return false;\n\t\tnow = max(now, i * 10 + z[i]);\n\t}\n\treturn true;\n}\n\nint main(){\n\tll w, h, n;\n\tcin >> w >> h >> n;\n\tn++;\n\tvector<pair<ll,ll>> z(n);\n\tfor (int i = 0; i < n-1; i++) {\n\t\tcin >> z[i].first >> z[i].second;\n\t}\n\tz[n-1] = make_pair(0, 0);\n\tsort(z.begin(), z.end());\n\treverse(z.begin(), z.end());\n\tll ans = 999999999;\n\tll nmax = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tans = min(ans, nmax + z[i].first);\n\t\tnmax = max(nmax, z[i].second);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4664, "score_of_the_acc": -0.297, "final_rank": 12 }, { "submission_id": "aoj_0364_6220296", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\ntemplate <typename T>\nstruct FenwickTree{\n const int n;\n vector<T> arr;\n FenwickTree() = default;\n FenwickTree(int n): n(n), arr(vector<T>(n+1, 0)){}\n\n void add(int ind, T x){\n for(int i = ind+1; i <= n; i += i & (-i)){\n arr[i] += x;\n }\n }\n\n T sum_sub(int end){\n T res = 0;\n for(int i = end; i > 0; i -= i & (-i)){\n res += arr[i];\n }\n return res;\n }\n\n T sum(int start, int end){\n return sum_sub(end) - sum_sub(start);\n }\n\n int lower_bound(T w){\n if(w <= 0) return 0;\n int x = 0;\n int k = 1 << 30;\n while(k > n) k /= 2;\n for(; k > 0; k /= 2){\n if(x+k <= n && arr[x+k] < w){\n w -= arr[x+k];\n x += k;\n }\n }\n return x;\n }\n};\n\nint main(){\n int w, h, n;\n cin >> w >> h >> n;\n vector<P> ps(n);\n for(auto &it: ps) cin >> it.first >> it.second;\n\n FenwickTree<int> ft(100010);\n for(auto &it: ps) ft.add(it.second, 1);\n sort(ps.begin(), ps.end());\n int ans = ft.lower_bound(ft.sum(0, 100010));\n for(auto &it: ps){\n ft.add(it.second, -1);\n ans = min(ans, it.first+ft.lower_bound(ft.sum(0, 100010)));\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4316, "score_of_the_acc": -0.3883, "final_rank": 16 }, { "submission_id": "aoj_0364_5979629", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1000000;\nint main(){\n int W, H, N;\n cin >> W >> H >> N;\n vector<int> x(N), y(N);\n for (int i = 0; i < N; i++){\n cin >> x[i] >> y[i];\n }\n vector<int> d(W, 0);\n for (int i = 0; i < N; i++){\n if (x[i] > 0){\n d[x[i] - 1] = max(d[x[i] - 1], y[i]);\n }\n }\n for (int i = W - 2; i >= 0; i--){\n d[i] = max(d[i], d[i + 1]);\n }\n int ans = INF;\n for (int i = 0; i < W; i++){\n ans = min(ans, i + d[i]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4312, "score_of_the_acc": -0.2769, "final_rank": 9 }, { "submission_id": "aoj_0364_5867591", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\n#define rep2(i,s,n) for (int i = s; i < (int)(n); i++)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nll max(ll x,ll y){\nif(x>y)return x;\nelse return y;\n}\nll min(ll x,ll y){\nif(x<y)return x;\nelse return y;\n}\n\n\nint main(){\n int h,w,n;\n cin >> w >> h >> n;\n vector<int> pl(w,-1);\n rep(i,n){\n int x,y;\n cin >> x >> y;\n pl[x]=max(pl[x],y);\n }\n priority_queue<P,vector<P>,greater<P>> q;\n rep(j,w)if(pl[j]!=-1){\n while(q.size() && q.top().first<=pl[j])q.pop();\n q.emplace(pl[j],j);\n }\n vector<P> res;\n while(q.size()){\n res.push_back(q.top());\n q.pop();\n }\n sort(all(res),[&](P a,P b){return a.second<b.second;});\n if(res.size()==1){\n cout << min(res[0].first,res[0].second) << endl;\n return 0;\n }\n int ans=1000000000;\n rep(idx,res.size()-1){\n ans=min(ans,res[idx].second+res[idx+1].first);\n }\n ans=min(ans,res[0].first);\n ans=min(ans,res.back().second);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4532, "score_of_the_acc": -0.2895, "final_rank": 10 }, { "submission_id": "aoj_0364_5859201", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define all(a) a.begin(), a.end()\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int w, h, n;\n cin >> w >> h >> n;\n map<int, int> b;\n rep(i, n) {\n int x, y; cin >> x >> y;\n if (b.count(y)) {\n b[y] = max(b[y], x);\n } else {\n b[y] = x;\n }\n }\n int max_x = 0;\n int ans = 1e9;\n for (int y=100010; y >= 0; y--) {\n int dist = y + max_x;\n ans = min(ans, dist);\n if (b.count(y)) {\n max_x = max(max_x, b[y]);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7756, "score_of_the_acc": -0.9176, "final_rank": 19 } ]
aoj_0375_cpp
Lake Survery The Onogawa Expedition is planning to conduct a survey of the Aizu nature reserve. The expedition planner wants to take the shortest possible route from the start to end point of the survey, while the expedition has to go around the coast of the Lake of Onogawa en route. The expedition walks along the coast of the lake, but can not wade across the lake. Based on the base information including the start and end point of the survey and the area of Lake Onogawa as convex polygon data, make a program to find the shortest possible route for the expedition and calculate its distance. Note that the expedition can move along the polygonal lines passing through the nodes, but never enter within the area enclosed by the polygon. Input The input is given in the following format. x_s y_s x_g y_g N x_1 y_1 x_2 y_2 : x_N y_N The first line provides the start point of the survey x_s,y_s (0≤ x_s,y_s ≤10 4 ), and the second line provides the end point x_g,y_g (0 ≤ x_g,y_g ≤ 10 4 ) all in integers. The third line provides the number of apexes N (3 ≤ N ≤ 100) of the polygon that represents the lake, and each of the subsequent N lines provides the coordinate of the i -th apex x_i,y_i (0 ≤ x_i,y_i ≤ 10 4 ) in counter-clockwise order. These data satisfy the following criteria: Start and end points of the expedition are not within the area enclosed by the polygon nor on boundaries. Start and end points of the expedition are not identical, i.e., x_s ≠ x_g or y_s ≠ y_g . No duplicate coordinates are given, i.e., if i ≠ j then x_i ≠ x_r or y_i ≠ y_j . The area enclosed by the polygon has a positive value. Any three coordinates that define an area are not aligned on a line. Output Output the distance of the shortest possible expedition route. Any number of decimal places can be selected as long as the error does not exceed ± 10 -3 . Sample Input 1 0 0 4 0 4 1 1 2 1 3 3 1 2 Sample Output 1 4.472136 Sample Input 2 4 4 0 0 4 1 1 3 1 3 3 1 3 Sample Output 2 6.32455
[ { "submission_id": "aoj_0375_3240241", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iomanip>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nclass point2d {\npublic:\n\tdouble x, y;\n\tpoint2d() : x(0), y(0) {};\n\tpoint2d(double x_, double y_) : x(x_), y(y_) {};\n\tbool operator==(const point2d& p) const { return x == p.x && y == p.y; }\n\tbool operator!=(const point2d& p) const { return x != p.x || y != p.y; }\n\tpoint2d& operator+=(const point2d& p) { x += p.x; y += p.y; return *this; }\n\tpoint2d& operator-=(const point2d& p) { x -= p.x; y -= p.y; return *this; }\n\tpoint2d& operator*=(const double v) { x *= v; y *= v; return *this; }\n\tpoint2d operator+(const point2d& p) const { return point2d(*this) += p; }\n\tpoint2d operator-(const point2d& p) const { return point2d(*this) -= p; }\n\tpoint2d operator*(const double v) const { return point2d(*this) *= v; }\n\tdouble norm() const { return x * x + y * y; }\n\tdouble abs() const { return std::sqrt(x * x + y * y); }\n\tdouble dot(const point2d& p) const { return x * p.x + y * p.y; }\n\tdouble cross(const point2d& p) const { return x * p.y - y * p.x; }\n\tint ccw(const point2d& p1, const point2d& p2) const {\n\t\tpoint2d pr1 = p1 - point2d(*this);\n\t\tpoint2d pr2 = p2 - point2d(*this);\n\t\tif (pr1.cross(pr2) != 0) return pr1.cross(pr2) > 0 ? 1 : -1;\n\t\tif (pr1.dot(pr2) < 0) return 2;\n\t\treturn pr1.norm() < pr2.norm() ? -2 : 0;\n\t}\n};\nclass segment2d {\npublic:\n\tpoint2d p1, p2;\n\tsegment2d() : p1(), p2() {};\n\tsegment2d(const point2d& p1_, const point2d& p2_) : p1(p1_), p2(p2_) {};\n\tdouble norm() const { return (p1 - p2).norm(); }\n\tdouble abs() const { return (p1 - p2).abs(); }\n};\nbool intersect(const segment2d& s1, const segment2d& s2) {\n\tif (s1.p1 == s2.p1 || s1.p1 == s2.p2 || s1.p2 == s2.p1 || s1.p2 == s2.p2) return false; // EXCEPTION !!!\n\treturn s1.p1.ccw(s1.p2, s2.p1) * s1.p1.ccw(s1.p2, s2.p2) <= 0 && s2.p1.ccw(s2.p2, s1.p1) * s2.p1.ccw(s2.p2, s1.p2) <= 0;\n}\npoint2d intersect_point(const segment2d &s1, const segment2d &s2) {\n\tpoint2d base = s2.p2 - s2.p1;\n\tdouble d1 = std::abs(base.cross(s1.p1 - s2.p1));\n\tdouble d2 = std::abs(base.cross(s1.p2 - s2.p1));\n\treturn s1.p1 + (s1.p2 - s1.p1) * (d1 / (d1 + d2));\n}\nbool contain(const std::vector<point2d>& v, const point2d& p) {\n\tint ans = -1;\n\tfor (int i = 0; i < v.size(); ++i) {\n\t\tpoint2d p1 = v[i] - p;\n\t\tpoint2d p2 = v[(i + 1) % v.size()] - p;\n\t\tif (p1.x > p2.x) std::swap(p1, p2);\n\t\tif (p1.x <= 0 && 0 < p2.x && p1.cross(p2) < 0) ans *= -1;\n\t}\n\treturn (ans == 1);\n}\nint main() {\n\tint n;\n\tvector<point2d> v(2);\n\tcin >> v[0].x >> v[0].y >> v[1].x >> v[1].y;\n\tcin >> n;\n\tv.resize(n + 2);\n\tfor (int i = 2; i < n + 2; ++i) {\n\t\tcin >> v[i].x >> v[i].y;\n\t}\n\t// Shortest Path (Warshall-Floyd Algorithm)\n\tvector<vector<double> > d(n + 2, vector<double>(n + 2, 1.0e+99));\n\tfor (int i = 0; i < n + 2; ++i) {\n\t\td[i][i] = 0;\n\t}\n\tfor (int i = 0; i < n + 2; ++i) {\n\t\tfor (int j = 0; j < i; ++j) {\n\t\t\t// Going to vertex j from vertex i\n\t\t\tbool ok = true;\n\t\t\tfor (int k = 0; k < v.size() - 2; ++k) {\n\t\t\t\tsegment2d s(v[k + 2], v[(k + 1) % (v.size() - 2) + 2]);\n\t\t\t\tif (intersect(s, segment2d(v[i], v[j]))) {\n\t\t\t\t\t//cout << i << ' ' << j << ' ' << k << \"-\" << k + 1 << endl;\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (contain(vector<point2d>(v.begin() + 2, v.end()), (v[i] + v[j]) * 0.5)) {\n\t\t\t\tok = false;\n\t\t\t}\n\t\t\tif (ok || (j >= 2 && i - j == 1) || (j == 2 && i == n + 1)) {\n\t\t\t\t//cout << i << ' ' << j << endl;\n\t\t\t\td[i][j] = (v[i] - v[j]).abs();\n\t\t\t\td[j][i] = (v[i] - v[j]).abs();\n\t\t\t}\n\t\t}\n\t}\n\td[0][1] = 1.0e+99;\n\td[1][0] = 1.0e+99;\n\tfor (int i = 0; i < n + 2; ++i) {\n\t\tfor (int j = 0; j < n + 2; ++j) {\n\t\t\tfor (int k = 0; k < n + 2; ++k) {\n\t\t\t\td[j][k] = min(d[j][k], d[j][i] + d[i][k]);\n\t\t\t}\n\t\t}\n\t}\n\tdouble ans = d[0][1];\n\tfor (int i = 0; i < n; ++i) {\n\t\tpoint2d p1 = v[i + 2], p2 = v[(i + 1) % (v.size() - 2) + 2];\n\t\tpoint2d bs = p1 + (p2 - p1) * (v[1] - p1).dot(p2 - p1) * (1.0 / (p2 - p1).norm());\n\t\tpoint2d rfl = bs * 2 - v[1];\n\t\tpoint2d crp = intersect_point(segment2d(p1, p2), segment2d(v[0], rfl));\n\t\tif (min(p1.x, p2.x) <= crp.x && crp.x <= max(p1.x, p2.x) && min(p1.y, p2.y) <= crp.y && crp.y <= max(p1.y, p2.y)) {\n\t\t\tbool ok = true;\n\t\t\tfor (int j = 0; j < n; ++j) {\n\t\t\t\tpoint2d pp1 = v[j + 2], pp2 = v[(j + 1) % (v.size() - 2) + 2];\n\t\t\t\tif (intersect(segment2d(pp1, pp2), segment2d(v[0], v[1]))) {\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (ok) {\n\t\t\t\tdouble d0 = (crp - v[0]).abs();\n\t\t\t\tdouble d1 = (crp - v[1]).abs();\n\t\t\t\tans = min(ans, d0 + d1);\n\t\t\t}\n\t\t}\n\t}\n\tcout << fixed << setprecision(15) << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3360, "score_of_the_acc": -0.0287, "final_rank": 2 }, { "submission_id": "aoj_0375_2912496", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef complex<double> P;\ntypedef complex<double> V;\ntypedef vector<P> vecP;\ntypedef pair<P,P> L;\ntypedef pair<P,P> S;\ntypedef pair<P,double> C;\nconst double eps=1e-8;\nconst double PI=acos(-1);\nconst double PI2=PI*2.0;\n \nnamespace std{\n bool operator < (const P &a,const P &b){\n return (a.real()!=b.real()?\n a.real() <b.real():\n a.imag() <b.imag());\n }\n};\n \nV normal(V a){\n assert( abs(a)>0 );\n return a/abs(a);\n}\n \ndouble Sqrt( double x ){\n if(x<0)return 0;\n else return sqrt(x);\n}\n \nP Vector(L a){\n return a.second-a.first;\n}\n \nbool eq(double a,double b){\n return (-eps<a-b&&a-b<eps);\n}\n \nbool eq(P a,P b){\n return ( eq(a.real(),b.real()) && eq(a.imag(),b.imag()) );\n}\n \ndouble dot(P a,P b){\n return real(b*conj(a));\n}\n \ndouble cross(P a,P b){\n return imag(b*conj(a));\n}\n \ndouble getArg(P a,P b){\n return arg(b*conj(a));\n}\n \ndouble getTime(V a,V b){\n assert( eq(cross(a,b),0) );\n return ( dot(a,b) < 0 ? -1.0 : 1.0 ) * abs(b) / abs(a);\n}\n \n \nP project(P a,P b,P c){\n b-=a,c-=a;\n return a+b*real(c/b);\n}\n \nP reflect(P a,P b,P c){\n b-=a,c-=a;\n return a+b*conj(c/b);\n}\n \nint ccw(P a,P b,P c){\n P ab=b-a,ac=c-a;\n P k=ac*conj(ab);\n if(k.imag()>0)return 1;\n if(k.imag()<0)return -1;\n if(k.real()<0)return 2;\n if(abs(ab)<abs(ac))return -2;\n return 0;\n}\n \nbool isParallel(P a,P b){\n return eq(0, cross(a,b));\n}\n \nbool isParallel(S a,S b){\n return eq(0, cross( Vector(a) , Vector(b) ) );\n}\n \nbool onLP(L l,P p){\n P a=l.first, b=l.second;\n return eq(0, cross(b-a,p-a));\n}\n \nbool onSP(S s,P p){\n return ( ccw(s.first, s.second ,p) == 0 );\n}\n \nbool isCrossSS(S s0,S s1){\n P a=s0.first, b=s0.second;\n P c=s1.first, d=s1.second;\n int f0 = ccw(a,b,c) * ccw(a,b,d);\n int f1 = ccw(c,d,a) * ccw(c,d,b);\n return (f0<=0 && f1<=0);\n}\n \nbool isCrossLS(L l,S s){\n P a=l.first, b=l.second;\n P c=s.first, d=s.second;\n return ( ccw(a,b,c) * ccw(a,b,d) <= 0 );\n}\n \ndouble distLP(L l,P p){\n P a=l.first, b=l.second;\n double res = cross(b-a,p-a) / abs(b-a);\n return abs(res);\n}\n \ndouble distSP(S s,P p){\n P a=s.first, b=s.second;\n if( dot(b-a,p-a) < eps )return abs(p-a);\n if( dot(a-b,p-b) < eps )return abs(p-b);\n return distLP(s,p);\n}\n \ndouble distSS(S s0,S s1){\n if( isCrossSS(s0,s1) )return 0;\n double res0 = min( distSP( s0, s1.first ) , distSP(s0, s1.second) );\n double res1 = min( distSP( s1, s0.first ) , distSP(s1, s0.second) );\n return min(res0,res1);\n}\n \nP getCrossLL(L l0,L l1){\n P a=l0.first, b=l0.second;\n P c=l1.first, d=l1.second;\n a-=d;b-=d;c-=d;\n return d+a+(b-a)*imag(a/c)/imag(a/c-b/c);\n}\n \n \n \nint inPolygon(vecP &t,P p){\n int n=t.size();\n double sum=0;\n for(int i=0;i<n;i++){\n P a=t[i],b=t[(i+1==n?0:i+1)];\n if( ccw(a,b,p)==0 )return 1;\n sum+= getArg(a-p,b-p);\n }\n if( abs(sum) < eps )return 0;\n else return 2;\n}\n \nvecP andrewScan(vecP &t){\n int N=t.size(),C=0;\n vecP R(N);\n for(int i=0;i<N;i++){\n while(2<=C&&ccw(R[C-2],R[C-1],t[i])==-1)C--;\n R[C++]=t[i];\n }\n vecP res(C);\n for(int i=0;i<C;i++)res[i]=R[i];\n return res;\n}\n \nvecP convexHull(vecP &t){\n sort(t.begin(),t.end());\n vecP u=andrewScan(t);\n reverse(t.begin(),t.end());\n vecP l=andrewScan(t);\n for(int i=1;i+1<(int)l.size();i++)u.push_back(l[i]);\n return u;\n}\n \nvecP cutConvex(vecP &t,L l){\n P a=l.first, b=l.second;\n int N=t.size();\n vecP res;\n for(int i=0;i<N;i++){\n P c=t[i],d=t[(i+1)%N];\n int C=ccw(a,b,c),D=ccw(a,b,d);\n if(C!=-1)res.push_back(c);\n if(C==-D&&abs(C)==1)res.push_back(getCrossLL( l ,L(c,d) ));\n }\n return res;\n}\n \nP getVector(const vecP &t, int id){\n int n=t.size();\n return t[ (id+1)%n ] - t[id%n];\n}\n \ndouble convex_diameter(vecP &t) {\n int n = t.size();\n int is = 0, js = 0;\n for (int i = 1; i < n; ++i) {\n if (imag(t[i]) > imag(t[is])) is = i;\n if (imag(t[i]) < imag(t[js])) js = i;\n }\n double maxd = norm(t[is]-t[js]);\n \n int i, maxi, j, maxj;\n i = maxi = is;\n j = maxj = js;\n do {\n \n if (cross( getVector(t,i), getVector(t,j)) >= 0) j = (j+1) % n;\n \n else i = (i+1) % n;\n if (norm(t[i]-t[j]) > maxd) {\n maxd = norm(t[i]-t[j]);\n maxi = i; maxj = j;\n }\n } while (i != is || j != js);\n return sqrt(maxd); /* farthest pair is (maxi, maxj). */\n}\n \nbool compare_y(const P &a,const P &b){\n return a.imag() < b.imag();\n}\n \ndouble closest_pair(P *a, int n){\n if(n <= 1) return 1e30;\n int m = n / 2;\n double x = a[m].real();\n double d = min(closest_pair(a, m), closest_pair(a + m, n - m));\n inplace_merge(a, a + m, a + n, compare_y);\n vector<P> b;\n for(int i=0;i<n;i++){\n if( abs(a[i].real() - x) >= d) continue;\n for(int j=0;j<(int)b.size();j++){\n double dx = real(a[i] - b[b.size() - j - 1]);\n double dy = imag(a[i] - b[b.size() - j - 1]);\n if(dy >= d) break;\n d = min(d, sqrt(dx * dx + dy * dy));\n }\n b.push_back(a[i]);\n }\n return d;\n}\n \nP _pool[200005];\ndouble minDist(vecP &t){\n int n=t.size();\n for(int i=0;i<n;i++)_pool[i]=t[i];\n sort( _pool, _pool+n);\n return closest_pair(_pool, n);\n}\n \nint getStateCC(C a,C b){\n double ar=a.second, br=b.second;\n double dist=abs(a.first-b.first);\n if(dist>ar+br+eps)return 4;\n if(dist>ar+br-eps)return 3;\n if(dist>abs(ar-br)+eps)return 2;\n if(dist>abs(ar-br)-eps)return 1;\n return 0;\n}\n \nP getCrossCC(C a,C b){\n P p1=a.first, p2=b.first;\n double r1=a.second, r2=b.second;\n double cA = (r1*r1+norm(p1-p2)-r2*r2) / (2.0*r1*abs(p1-p2));\n return p1+(p2-p1)/abs(p1-p2)*r1*P(cA,Sqrt(1.0-cA*cA));\n}\n \nP getTangentCP_(C a,P p,int flg){\n P base=a.first-p;\n double ar=a.second;\n double w=Sqrt(norm(base)-ar*ar);\n P s=p+base*P(w,ar * flg)/norm(base)*w;\n return s;\n}\n \nvector<S> getTangentCP(C a,P p){\n vector<S> res;\n P s=getTangentCP_(a,p,1);\n P t=getTangentCP_(a,p,-1);\n \n if( eq(s,t) ){\n res.push_back( S(s, s+(a.first-p)*P(0,1) ) ); \n }else{\n res.push_back( S(p,s) );\n res.push_back( S(p,t) );\n }\n return res;\n}\n \nS getInTangent(C a,C b,double flg=1.0){\n P ap=a.first,bp=b.first;\n double ar=a.second,br=b.second;\n \n P base=bp-ap;\n double w=ar+br;\n double h=Sqrt(norm(base)-w*w);\n P k=base*P(w,h*flg)/norm(base);\n return S(ap+k*ar,bp-k*br);\n}\n \nS getOutTangent(C a,C b,double flg=1.0){\n P ap=a.first,bp=b.first;\n double ar=a.second,br=b.second;\n \n P base=bp-ap;\n double h=br-ar;\n \n double w=Sqrt(norm(base)-h*h);\n P k=base*P(w,h*flg)/norm(base)*P(0,flg);\n return S(ap+k*ar,bp+k*br);\n}\n \nvector<S> getTangentCC(C a,C b){\n P ap=a.first,bp=b.first;\n double ar=a.second,br=b.second;\n \n vector<S> res;\n double dist=abs(ap-bp);\n \n if(dist>ar+br+eps)\n res.push_back(getInTangent(a,b,1));\n \n if(dist>ar+br-eps)\n res.push_back(getInTangent(a,b,-1));\n \n if(dist>abs(ar-br)+eps)\n res.push_back(getOutTangent(a,b,1));\n \n if(dist>abs(ar-br)-eps)\n res.push_back(getOutTangent(a,b,-1));\n \n return res;\n}\n \n \nvecP getCrossCL(C cir,L l){\n P a=l.first, b=l.second;\n double cr=cir.second;\n P cp=cir.first;\n \n vecP res;\n P base=b-a, target=project(a,b,cp);\n \n double length=abs(base), h=abs(cp-target);\n base/=length;\n \n if(cr+eps<h)return res;\n double w=Sqrt(cr*cr-h*h);\n double L=getTime( normal(b-a) ,target-a)-w, R=L+w*2.0;\n \n res.push_back(a+base*L);\n if( eq(L,R) )return res;\n res.push_back(a+base*R);\n \n return res;\n}\n \nvecP getCrossCS(C cir,S s){\n vecP tmp=getCrossCL(cir,s);\n vecP res;\n for(int i=0;i<(int)tmp.size();i++)\n // if( ccw(s.first,s.second, tmp[i] ) == 0)\n if( onSP( s, tmp[i] ) )\n res.push_back(tmp[i]);\n return res;\n}\n \ndouble getArea(C c,P a,P b){\n P cp=c.first;\n double cr=c.second;\n \n P va=cp-a, vb=cp-b;\n double A=abs(va), B=abs(vb);\n double f=cross(va,vb), d=distSP( S(a,b) ,cp), res=0;\n \n if( eq(0, f ) )return 0;\n if(A<cr+eps&&B<cr+eps)return f*0.5;\n if(d>cr-eps)return cr*cr*PI*getArg(va,vb)/PI2;\n \n vecP u=getCrossCS(c, S(a,b) );\n \n assert( !u.empty() );\n u.insert(u.begin(), a), u.push_back(b);\n \n for(int i=0;i+1<(int)u.size();i++) res+=getArea(c,u[i],u[i+1]);\n return res;\n}\n \ndouble getCrossArea(vecP t,C c){\n int n=t.size();\n if(n<3)return 0;\n double res=0;\n for(int i=0;i<n;i++){\n P a=t[i], b=t[(i+1)%n];\n res+=getArea(c,a,b);\n }\n return res;\n}\n \n \ndouble calcPolygonArea(const vecP &t){\n double res=0;\n int n=t.size();\n for(int i=0;i<n;i++){\n res+= cross( t[ (i+1)%n ],t[i] );\n }\n return abs(res)*0.5;\n}\n\nbool check( vecP &A, P s,P t,bool f=false){\n int n=A.size();\n for(int i=0;i<n;i++){\n P a=A[i];\n P b=A[(i+1)%n];\n if( isParallel( a-b, s-t) )continue;\n if( !isCrossSS( S(a,b) , S(s,t) ) )continue;\n\n if( f )return false;\n \n P p=getCrossLL( L(a,b) , L(s,t) );\n int cnt=0;\n if( eq(p,a) )cnt++;\n if( eq(p,b) )cnt++;\n if( eq(p,s) )cnt++;\n if( eq(p,t) )cnt++;\n if(cnt<=1) return false;\n }\n return true;\n}\n\nint main(){\n double G[200][200];\n int n;\n vecP A;\n P s,t;\n int sx,sy,tx,ty;\n cin>>sx>>sy>>tx>>ty;\n s=P(sx,sy);\n t=P(tx,ty);\n cin>>n;\n for(int i=0;i<n;i++){\n int x,y;\n cin>>x>>y;\n A.push_back(P(x,y));\n }\n \n\n double ans=1e9;\n if( check(A,s,t,true) ){\n for(int i=0;i<n;i++){\n ans=min(ans, abs(A[i]-s) + abs(A[i]-t) );\n int j=(i+1)%n;\n P nt=reflect(A[i],A[j],t);\n if( isCrossSS( S(s,nt) , S(A[i],A[j]) ) )\n ans=min(ans, abs(s - nt ) );\n }\n }else{\n \n for(int i=0;i<n;i++)\n for(int j=0;j<n;j++)\n G[i][j]=(i==j? 0.0 : 1e9 );\n \n for(int i=0;i<n;i++){\n int j=(i+1)%n;\n G[i][j]=G[j][i]=abs(A[i]-A[j]);\n }\n \n for(int k=0;k<n;k++)\n for(int i=0;i<n;i++)\n for(int j=0;j<n;j++)\n G[i][j]=min(G[i][j],G[i][k]+G[k][j]);\n \n for(int i=0;i<n;i++){\n if(check(A,s,A[i])){\n for(int j=0;j<n;j++){\n if(check(A,A[j],t)){\n ans=min(ans,abs(A[i]-s) + abs(A[j]-t) + G[i][j]);\n }\n }\n }\n }\n \n }\n printf(\"%.10f\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6608, "score_of_the_acc": -1, "final_rank": 6 }, { "submission_id": "aoj_0375_2670459", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;\nconst double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nbool intersectSS(const L &s, const L &t) {\n return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) < 0 &&\n ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) < 0;\n}\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tP s, t;\n\tG ps;\n\tint x, y, n;\n\tcin >> x >> y; s = P(x, y);\n\tcin >> x >> y; t = P(x, y);\n\tcin >> n;\n\trep(i, n){\n\t\tcin >> x >> y;\n\t\tps.emplace_back(x, y);\n\t}\n\tvector<vector<double>> d(n, vector<double>(n, INF));\n\trep(i, n){\n\t\td[i][i] = 0;\n\t\td[(i + 1) % n][i] = d[i][(i + 1) % n] = abs(ps[i] - ps[(i + 1) % n]);\n\t}\n\trep(k, n) rep(i, n) rep(j, n) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\t\n\tauto ok = [&](const P &a, const P &b){\n\t\tconst L l(a, b);\n\t\trep(i, n){\n\t\t\tif(intersectSS(l, L(ps[i], ps[(i + 1) % n]))) return 0;\n\t\t\tif(ccw(ps[i], l[0], l[1]) == 2) return 0;\n\t\t}\n\t\treturn 1;\n\t};\n\t\n\tdouble ans = INF;\n\trep(i, n) rep(j, n){\n\t\tif(!ok(s, ps[i])) continue;\n\t\tif(!ok(t, ps[j])) continue;\n\t\tans = min(ans, abs(s - ps[i]) + d[i][j] + abs(t - ps[j]));\n\t}\n\t#if 1\n\tint cnt = 0;\n\trep(i, n){\n\t\tP a = ps[i], b = ps[(i + 1) % n];\n\t\tif(!(ok(s, a) && ok(s, b) && ok(t, a) && ok(t, b))) continue;\n\t\tdouble lo = 0, hi = 1, l, r;\n\t\trep(it, 100){\n\t\t\tl = (2 * lo + hi) / 3;\n\t\t\tr = (lo + 2 * hi) / 3;\n\t\t\tP p1 = a * (1 - l) + b * l;\n\t\t\tP p2 = a * (1 - r) + b * r;\n\t\t\tif(abs(p1 - s) + abs(p1 - t) < abs(p2 - s) + abs(p2 - t)) hi = r;\n\t\t\telse lo = l;\n\t\t}\n\t\tP p = a * (1 - lo) + b * lo;\n\t\tans = min(ans, abs(p - s) + abs(p - t));\n\t\t//assert(++cnt <= 2);\n\t}\n\t#endif\n\tprintf(\"%.20f\\n\", ans);\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3440, "score_of_the_acc": -0.9276, "final_rank": 5 }, { "submission_id": "aoj_0375_2670457", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;\nconst double EPS = 1e-8, INF = 1e12, PI = acos(-1.0);\ntypedef complex<double> P;\nnamespace std{\n\tbool operator<(const P& a, const P& b){\n\t\treturn real(a) != real(b) ? real(a) < real(b) : imag(a) < imag(b);\n\t}\n}\ninline double cross(const P& a, const P& b){ return imag(conj(a)*b); }\ninline double dot(const P& a, const P& b){ return real(conj(a)*b); }\nstruct L : public vector<P>{\n\tL(const P &a, const P &b) {\n\t\tpush_back(a); push_back(b);\n\t}\n};\ntypedef vector<P> G;\ninline int ccw(P a, P b, P c) {\n\tb -= a; c -= a;\n\tif(cross(b, c) > EPS) return +1; // counter clockwise\n\tif(cross(b, c) < -EPS) return -1; // clockwise\n\tif(dot(b, c) < -EPS) return +2; // c--a--b on line\n\tif(norm(b)+EPS <norm(c)) return -2; // a--b--c on line\n\treturn 0; // c is between a and b (inclusive)\n}\nbool intersectSS(const L &s, const L &t) {\n return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) < 0 &&\n ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) < 0;\n}\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tP s, t;\n\tG ps;\n\tint x, y, n;\n\tcin >> x >> y; s = P(x, y);\n\tcin >> x >> y; t = P(x, y);\n\tcin >> n;\n\trep(i, n){\n\t\tcin >> x >> y;\n\t\tps.emplace_back(x, y);\n\t}\n\tvector<vector<double>> d(n, vector<double>(n, INF));\n\trep(i, n){\n\t\td[i][i] = 0;\n\t\td[(i + 1) % n][i] = d[i][(i + 1) % n] = abs(ps[i] - ps[(i + 1) % n]);\n\t}\n\trep(k, n) rep(i, n) rep(j, n) d[i][j] = min(d[i][j], d[i][k] + d[k][j]);\n\t\n\tauto ok = [&](const P &a, const P &b){\n\t\tconst L l(a, b);\n\t\trep(i, n){\n\t\t\tif(intersectSS(l, L(ps[i], ps[(i + 1) % n]))) return 0;\n\t\t\tif(ccw(ps[i], l[0], l[1]) == 2) return 0;\n\t\t}\n\t\treturn 1;\n\t};\n\t\n\tdouble ans = INF;\n\trep(i, n) rep(j, n){\n\t\tif(!ok(s, ps[i])) continue;\n\t\tif(!ok(t, ps[j])) continue;\n\t\tans = min(ans, abs(s - ps[i]) + d[i][j] + abs(t - ps[j]));\n\t}\n\t#if 1\n\tint cnt = 0;\n\trep(i, n){\n\t\tP a = ps[i], b = ps[(i + 1) % n];\n\t\tif(!(ok(s, a) && ok(s, b) && ok(t, a) && ok(t, b))) continue;\n\t\tdouble lo = 0, hi = 1, l, r;\n\t\trep(it, 100){\n\t\t\tl = (2 * lo + hi) / 3;\n\t\t\tr = (lo + 2 * hi) / 3;\n\t\t\tP p1 = a * (1 - l) + b * l;\n\t\t\tP p2 = a * (1 - r) + b * r;\n\t\t\tif(abs(p1 - s) + abs(p1 - t) < abs(p2 - s) + abs(p2 - t)) hi = r;\n\t\t\telse lo = l;\n\t\t}\n\t\tP p = a * (1 - lo) + b * lo;\n\t\tans = min(ans, abs(p - s) + abs(p - t));\n\t\tassert(++cnt <= 2);\n\t}\n\t#endif\n\tprintf(\"%.20f\\n\", ans);\n\t\n\treturn 0;\n}", "accuracy": 0.625, "time_ms": 50, "memory_kb": 3396, "score_of_the_acc": -0.5395, "final_rank": 8 }, { "submission_id": "aoj_0375_2656130", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing D = double;\nstruct Point {\n D x, y;\n Point(const D d = 0.0) : x(d), y(d) {}\n Point(const D x, const D y) : x(x), y(y) {}\n};\nstruct Segment {\n Point ab, to;\n Segment(const Point& ab, const Point& to) : ab(ab), to(to) {}\n Segment(const D x1, const D y1, const D x2, const D y2) : ab(x1, y1), to(x2, y2) {}\n};\nusing Polygon = vector<Point>;\n\nconst D EPS = 1e-9;\nenum POSITION {ONLINE_FRONT = -2, CLOCKWISE, ON_SEGMENT, COUNTER_CLOCKWISE, ONLINE_BACK};\n\nbool relative_equal(const D d1, const D d2) {return d1 == 0 ? std::abs(d2) < EPS : std::abs((d1 - d2) / d1) < EPS;}\nbool operator==(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) && relative_equal(lhs.y, rhs.y);}\nbool operator<(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y < rhs.y : lhs.x < rhs.x;}\nbool operator>(const Point& lhs, const Point& rhs) {return relative_equal(lhs.x, rhs.x) ? lhs.y > rhs.y : lhs.x > rhs.x;}\nbool operator!=(const Point& lhs, const Point& rhs) {return !(lhs == rhs);}\nbool operator<=(const Point& lhs, const Point& rhs) {return !(lhs > rhs);}\nbool operator>=(const Point& lhs, const Point& rhs) {return !(lhs < rhs);}\nconst Point operator+(const Point& lhs, const Point& rhs) {return Point(lhs.x + rhs.x, lhs.y + rhs.y);}\nconst Point operator-(const Point& lhs, const Point& rhs) {return Point(lhs.x - rhs.x, lhs.y - rhs.y);}\nconst Point operator*(const Point& lhs, const Point& rhs) {return Point(lhs.x * rhs.x, lhs.y * rhs.y);}\nconst Point operator/(const Point& lhs, const Point& rhs) {return Point(lhs.x / rhs.x, lhs.y / rhs.y);}\nD abs(const Point& p) {return hypot(p.x, p.y);}\nD norm(const Point& p) {return p.x * p.x + p.y * p.y;}\nD dot(const Point& a, const Point& b) {return a.x * b.x + a.y * b.y;}\nD cross(const Point& a, const Point& b) {return a.x * b.y - a.y * b.x;}\nPOSITION ccw(const Point& a, const Point& b, const Point& p) {\n Point v1 = b - a;\n Point v2 = p - a;\n if(cross(v1, v2) >= EPS) return COUNTER_CLOCKWISE;\n if(cross(v1, v2) <= -EPS) return CLOCKWISE;\n if(dot(v1, v2) <= -EPS) return ONLINE_BACK;\n if(norm(v1) < norm(v2)) return ONLINE_FRONT;\n return ON_SEGMENT;\n}\nostream& operator<<(ostream& os, const Point& p) {os<<\"point: \"; os<<\"(\"<<p.x<<\",\"<<p.y<<\")\"; return os;}\n\nbool intersect(Segment s, Segment t) {return ccw(s.ab, s.to, t.ab)*ccw(s.ab, s.to, t.to) <= 0 && ccw(t.ab, t.to, s.ab)*ccw(t.ab, t.to, s.to) <= 0;}\n\nbool intersect(Polygon P, Segment S) {\n for(auto i = 0; i < P.size(); ++i) {\n Segment T(P[i], P[(i+1) % P.size()]);\n if(intersect(S, T)) return true;\n }\n return false;\n}\n\nD tsearch(auto S, auto G, auto P) {\n auto d = [&](auto p) {return abs(p - S) + abs(G - p);};\n auto point = [&](auto p, auto q, auto x) {return p + (q - p) * x;};\n D r = 1e9;\n for(auto i = 0; i < P.size(); ++i) {\n auto s = P[i], g = P[(i+1) % P.size()];\n D l = 0, h = 1;\n for(auto j = 0; j < 1000; ++j) {\n auto m1 = (h + 2 * l) / 3;\n auto m2 = (2 * h + l) / 3;\n auto d1 = d(point(s, g, m1));\n auto d2 = d(point(s, g, m2));\n if(d1 < d2) h = m2;\n else l = m1;\n }\n r = min(r, d(point(s, g, h)));\n }\n return r;\n}\n\nD chull(auto S, auto G, auto P) {\n if(S > G) swap(S, G);\n P.emplace_back(S);\n P.emplace_back(G);\n sort(begin(P), end(P));\n P.insert(end(P), P.rbegin() + 1, P.rend());\n Polygon ch;\n for(const auto& p: P) {\n while(ch.size() >= 2 && ccw(ch[ch.size() - 2], ch.back(), p) == CLOCKWISE) ch.pop_back();\n ch.emplace_back(p);\n }\n ch.pop_back();\n\n auto solve = [&](auto b, auto e) {\n D res = 0;\n auto pass = false;\n for(auto i = 0; i < 2 * ch.size(); ++i) {\n auto p = ch[i % ch.size()], q = ch[(i + 1) % ch.size()];\n if(p == b) pass = true;\n if(!pass) continue;\n res += abs(p - q);\n if(q == e) return res;\n }\n return 1e9;\n };\n return min(solve(S, G), solve(G, S));\n}\n\nint main() {\n Point S, G;\n int N;\n cin >> S.x >> S.y >> G.x >> G.y >> N;\n\n Polygon P(N);\n for(auto& i: P) cin >> i.x >> i.y;\n\n if(intersect(P, Segment{S, G})) cout << setprecision(8) << fixed << chull(S, G, P) << endl;\n else cout << setprecision(8) << fixed << tsearch(S, G, P) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3360, "score_of_the_acc": -0.0287, "final_rank": 2 }, { "submission_id": "aoj_0375_2636522", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define pb push_back\n#define all(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntypedef vector<int>vint;\ntypedef pair<int,int>pint;\ntypedef vector<pint>vpint;\n\ntemplate<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}\ntemplate<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}\n\ntypedef double D;\ntypedef complex<D>Point;\ntypedef vector<Point>Polygon;\n\nconst D EPS=1e-5;\n\nconst int COUNTER_CLOCKWISE=1;\nconst int CLOCKWISE=-1;\nconst int ONLINE_FRONT=2;\nconst int ONLINE_BACK=-2;\nconst int ON_SEGMENT=0;\n\nstruct Segment{\n Point p1,p2;\n Segment(const Point &p1=Point(),const Point &p2=Point()):p1(p1),p2(p2){}\n};\n\nistream& operator>>(istream &is,Point &a){\n D x,y;\n is>>x>>y;\n a=Point(x,y);\n return is;\n}\n\nD dot(const Point &a,const Point &b){\n return real(a)*real(b)+imag(a)*imag(b);\n}\nD cross(const Point &a,const Point &b){\n return real(a)*imag(b)-real(b)*imag(a);\n}\n\nPoint projection(const Point &a,const Point &b){\n return a*real(b/a);\n}\n\nPoint projection(const Segment &s,const Point &a){\n return s.p1+projection(s.p2-s.p1,a-s.p1);\n}\n\nPoint reflection(const Segment &s,const Point &a){\n Point p=projection(s,a);\n return 2.0*p-a;\n}\n\nint ccw(Point a,Point b,Point c){\n b-=a;c-=a;\n if(cross(b,c)>EPS)return COUNTER_CLOCKWISE;\n if(cross(b,c)<-EPS)return CLOCKWISE;\n if(dot(b,c)<-EPS)return ONLINE_BACK;\n if(norm(b)+EPS<norm(c))return ONLINE_FRONT;\n return ON_SEGMENT;\n}\n\nbool intersect(const Point &a1,const Point a2,const Point &b1,const Point &b2){\n return ccw(a1,a2,b1)*ccw(a1,a2,b2)<=0&&\n ccw(b1,b2,a1)*ccw(b1,b2,a2)<=0;\n}\n\nsigned main(){\n Point A,B;\n cin>>A>>B;\n\n int N;cin>>N;\n Polygon G(N);\n rep(i,N)cin>>G[i];\n\n double ans=1e18;\n\n rep(i,N){\n if(ccw(G[i],G[(i+1)%N],A)==CLOCKWISE&&ccw(G[i],G[(i+1)%N],B)==CLOCKWISE){\n Point p=reflection(Segment(G[i],G[(i+1)%N]),B);\n if(intersect(G[i],G[(i+1)%N],A,p))chmin(ans,abs(p-A));\n }\n }\n\n vint okA(N),okB(N);\n rep(i,N){\n if(ccw(G[(i-1+N)%N],G[i],A)!=COUNTER_CLOCKWISE||ccw(G[i],G[(i+1)%N],A)!=COUNTER_CLOCKWISE)okA[i]=true;\n if(ccw(G[(i-1+N)%N],G[i],B)!=COUNTER_CLOCKWISE||ccw(G[i],G[(i+1)%N],B)!=COUNTER_CLOCKWISE)okB[i]=true;\n }\n\n rep(i,N){\n if(!okA[i])continue;\n rep(j,N){\n if(!okB[j])continue;\n double tmp=abs(G[i]-A)+abs(G[j]-B);\n int v=i;\n while(v!=j){\n tmp+=abs(G[v]-G[(v+1)%N]);\n v=(v+1)%N;\n }\n chmin(ans,tmp);\n\n\n tmp=abs(G[i]-A)+abs(G[j]-B);\n v=i;\n while(v!=j){\n tmp+=abs(G[v]-G[(v-1+N)%N]);\n v=(v-1+N)%N;\n }\n chmin(ans,tmp);\n }\n }\n\n\n\n printf(\"%.20f\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0375_2635918", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst double EPS = 1e-8, PI = acos(-1);\n\ninline bool eq(double a, double b) { return fabs(b - a) < EPS; }\n\nstruct Point\n{\n double x, y;\n\n Point() {}\n\n Point(double x, double y) : x(x), y(y) {}\n\n Point operator+(const Point &b) const { return Point(x + b.x, y + b.y); }\n\n Point operator-(const Point &b) const { return Point(x - b.x, y - b.y); }\n\n Point operator*(const double b) const { return Point(x * b, y * b); }\n\n Point operator*(const Point &b) const { return Point(x * b.x - y * b.y, x * b.y + y * b.x); }\n\n Point operator/(const double b) const { return Point(x / b, y / b); }\n\n bool operator<(const Point &b) const { return x != b.x ? x < b.x : y < b.y; }\n\n bool operator==(const Point &b) const { return eq(x, b.x) && eq(y, b.y); }\n\n double norm() { return x * x + y * y; }\n\n double arg() { return atan2(x, y); }\n\n double abs() { return sqrt(norm()); }\n\n Point rotate(double theta) { return Point(cos(theta) * x - sin(theta) * y, sin(theta) * x + cos(theta) * y); }\n\n Point rotate90() { return Point(-y, x); }\n\n friend ostream &operator<<(ostream &os, Point &p) { return os << \"(\" << p.x << \",\" << p.y << \")\"; }\n\n friend istream &operator>>(istream &is, Point &a) { return is >> a.x >> a.y; }\n};\n\ndouble cross(const Point &a, const Point &b)\n{\n return a.x * b.y - a.y * b.x;\n}\n\ndouble dot(const Point &a, const Point &b)\n{\n return a.x * b.x + a.y * b.y;\n}\n\ndouble RadianToDegree(double r)\n{\n return (r * 180.0 / acos(-1));\n}\n\ndouble DegreeToRadian(double d)\n{\n return (d * acos(-1) / 180.0);\n}\n\ndouble GetAngle(const Point &a, const Point &b, const Point &c)\n{\n const Point v = b - a, w = c - b;\n double alpha = atan2(v.y, v.x), beta = atan2(w.y, w.x);\n if(alpha > beta) swap(alpha, beta);\n double theta = (beta - alpha);\n return min(theta, 2 * acos(-1) - theta);\n}\n\nstruct Line\n{\n Point a, b;\n\n Line() {};\n\n Line(Point a, Point b) : a(a), b(b) {};\n\n // Ax + By = C\n Line(double A, double B, double C)\n {\n if(eq(A, 0)) {\n a = Point(0, C / B);\n b = Point(1, C / B);\n } else if(eq(B, 0)) {\n a = Point(C / A, 0);\n b = Point(C / A, 1);\n } else {\n a = Point(0, C / B);\n b = Point(C / A, 0);\n }\n }\n\n friend ostream &operator<<(ostream &os, Line &p) { return os << \"(\" << p.a.x << \",\" << p.a.y << \") to (\" << p.b.x << \",\" << p.b.y << \")\"; }\n\n friend istream &operator>>(istream &is, Line &a) { return is >> a.a.x >> a.a.y >> a.b.x >> a.b.y; }\n};\n\nstruct Segment\n{\n Point a, b;\n\n Segment() {};\n\n Segment(Point a, Point b) : a(a), b(b) {};\n\n friend ostream &operator<<(ostream &os, Segment &p) { return os << \"(\" << p.a.x << \",\" << p.a.y << \") to (\" << p.b.x << \",\" << p.b.y << \")\"; }\n\n friend istream &operator>>(istream &is, Segment &a) { return is >> a.a.x >> a.a.y >> a.b.x >> a.b.y; }\n};\n\ntypedef vector< Point > Polygon;\n\nint ccw(const Point &a, Point b, Point c)\n{\n b = b - a, c = c - a;\n if(cross(b, c) > EPS) return +1;\n if(cross(b, c) < -EPS) return -1;\n if(dot(b, c) < 0) return +2;\n if(b.norm() < c.norm()) return -2;\n return 0;\n}\n\nbool Intersect(const Segment &s, const Segment &t)\n{\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool Intersect(const Segment &s, const Point &p)\n{\n return ccw(s.a, s.b, p) == 0;\n}\n\nvoid WarshallFloyd(vector< vector< double > > &g)\n{\n for(int k = 0; k < g.size(); k++) {\n for(int i = 0; i < g.size(); i++) {\n for(int j = 0; j < g.size(); j++) {\n g[i][j] = min(g[i][j], g[i][k] + g[k][j]);\n }\n }\n }\n}\n\n\nint main()\n{\n Point pt[2];\n cin >> pt[0] >> pt[1];\n int N;\n cin >> N;\n Polygon ps(N);\n for(auto &p : ps) cin >> p;\n\n vector< vector< double > > g(N + 2, vector< double >(N + 2, 1e9));\n for(int i = 0; i < g.size(); i++) g[i][i] = 0;\n\n auto add = [&](int u, int v, double cost)\n {\n g[u][v] = g[v][u] = min(g[v][u], cost);\n };\n\n for(int i = 0; i < N; i++) {\n add(i, (i + 1) % N, (ps[i] - ps[(i + 1) % N]).abs());\n }\n for(int i = 0; i < 2; i++) {\n for(int j = 0; j < N; j++) {\n Segment base(pt[i], ps[j]);\n bool intersect = false;\n for(int k = 0; k < N; k++) {\n if(j == k) continue;\n if(j == (k + 1) % N) continue;\n intersect |= Intersect((Segment) {ps[k], ps[(k + 1) % N]}, base);\n }\n if(!intersect) add(i + N, j, (base.a - base.b).abs());\n }\n }\n\n WarshallFloyd(g);\n double ret = g[N][N + 1];\n for(int i = 0; i < N; i++) {\n double low = 0, high = 1.0;\n Segment s(ps[i], ps[(i + 1) % N]);\n\n auto getDist = [&](double v)\n {\n Point peet = s.a + (s.b - s.a) * v;\n Segment latte = Segment(pt[0], peet);\n Segment malta = Segment(pt[1], peet);\n bool intersect = false;\n for(int k = 0; k < N; k++) {\n if(i == k) continue;\n intersect |= Intersect(latte, (Segment) {ps[k], ps[(k + 1) % N]});\n intersect |= Intersect(malta, (Segment) {ps[k], ps[(k + 1) % N]});\n }\n double dist = 1145141919;\n if(!intersect) dist = (latte.a - latte.b).abs() + (malta.a - malta.b).abs();\n return (dist);\n };\n\n for(int j = 0; j < 100; j++) {\n double left = (low * 2 + high) / 3;\n double right = (low + high * 2) / 3;\n\n if(getDist(left) < getDist(right)) high = right;\n else low = left;\n }\n ret = min(ret, getDist(low));\n }\n\n cout << fixed << setprecision(10) << ret << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3352, "score_of_the_acc": -0.2763, "final_rank": 4 }, { "submission_id": "aoj_0375_2635912", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst double EPS = 1e-8, PI = acos(-1);\n\ninline bool eq(double a, double b) { return fabs(b - a) < EPS; }\n\nstruct Point\n{\n double x, y;\n\n Point() {}\n\n Point(double x, double y) : x(x), y(y) {}\n\n Point operator+(const Point &b) const { return Point(x + b.x, y + b.y); }\n\n Point operator-(const Point &b) const { return Point(x - b.x, y - b.y); }\n\n Point operator*(const double b) const { return Point(x * b, y * b); }\n\n Point operator*(const Point &b) const { return Point(x * b.x - y * b.y, x * b.y + y * b.x); }\n\n Point operator/(const double b) const { return Point(x / b, y / b); }\n\n bool operator<(const Point &b) const { return x != b.x ? x < b.x : y < b.y; }\n\n bool operator==(const Point &b) const { return eq(x, b.x) && eq(y, b.y); }\n\n double norm() { return x * x + y * y; }\n\n double arg() { return atan2(x, y); }\n\n double abs() { return sqrt(norm()); }\n\n Point rotate(double theta) { return Point(cos(theta) * x - sin(theta) * y, sin(theta) * x + cos(theta) * y); }\n\n Point rotate90() { return Point(-y, x); }\n\n friend ostream &operator<<(ostream &os, Point &p) { return os << \"(\" << p.x << \",\" << p.y << \")\"; }\n\n friend istream &operator>>(istream &is, Point &a) { return is >> a.x >> a.y; }\n};\n\ndouble cross(const Point &a, const Point &b)\n{\n return a.x * b.y - a.y * b.x;\n}\n\ndouble dot(const Point &a, const Point &b)\n{\n return a.x * b.x + a.y * b.y;\n}\n\ndouble RadianToDegree(double r)\n{\n return (r * 180.0 / acos(-1));\n}\n\ndouble DegreeToRadian(double d)\n{\n return (d * acos(-1) / 180.0);\n}\n\ndouble GetAngle(const Point &a, const Point &b, const Point &c)\n{\n const Point v = b - a, w = c - b;\n double alpha = atan2(v.y, v.x), beta = atan2(w.y, w.x);\n if(alpha > beta) swap(alpha, beta);\n double theta = (beta - alpha);\n return min(theta, 2 * acos(-1) - theta);\n}\n\nstruct Line\n{\n Point a, b;\n\n Line() {};\n\n Line(Point a, Point b) : a(a), b(b) {};\n\n // Ax + By = C\n Line(double A, double B, double C)\n {\n if(eq(A, 0)) {\n a = Point(0, C / B);\n b = Point(1, C / B);\n } else if(eq(B, 0)) {\n a = Point(C / A, 0);\n b = Point(C / A, 1);\n } else {\n a = Point(0, C / B);\n b = Point(C / A, 0);\n }\n }\n\n friend ostream &operator<<(ostream &os, Line &p) { return os << \"(\" << p.a.x << \",\" << p.a.y << \") to (\" << p.b.x << \",\" << p.b.y << \")\"; }\n\n friend istream &operator>>(istream &is, Line &a) { return is >> a.a.x >> a.a.y >> a.b.x >> a.b.y; }\n};\n\nstruct Segment\n{\n Point a, b;\n\n Segment() {};\n\n Segment(Point a, Point b) : a(a), b(b) {};\n\n friend ostream &operator<<(ostream &os, Segment &p) { return os << \"(\" << p.a.x << \",\" << p.a.y << \") to (\" << p.b.x << \",\" << p.b.y << \")\"; }\n\n friend istream &operator>>(istream &is, Segment &a) { return is >> a.a.x >> a.a.y >> a.b.x >> a.b.y; }\n};\n\ntypedef vector< Point > Polygon;\n\nint ccw(const Point &a, Point b, Point c)\n{\n b = b - a, c = c - a;\n if(cross(b, c) > EPS) return +1;\n if(cross(b, c) < -EPS) return -1;\n if(dot(b, c) < 0) return +2;\n if(b.norm() < c.norm()) return -2;\n return 0;\n}\n\nbool Intersect(const Segment &s, const Segment &t)\n{\n return ccw(s.a, s.b, t.a) * ccw(s.a, s.b, t.b) <= 0 && ccw(t.a, t.b, s.a) * ccw(t.a, t.b, s.b) <= 0;\n}\n\nbool Intersect(const Segment &s, const Point &p)\n{\n return ccw(s.a, s.b, p) == 0;\n}\n\nvoid WarshallFloyd(vector< vector< double > > &g)\n{\n for(int k = 0; k < g.size(); k++) {\n for(int i = 0; i < g.size(); i++) {\n for(int j = 0; j < g.size(); j++) {\n g[i][j] = min(g[i][j], g[i][k] + g[k][j]);\n }\n }\n }\n}\n\n\nint main()\n{\n Point pt[2];\n cin >> pt[0] >> pt[1];\n int N;\n cin >> N;\n Polygon ps(N);\n for(auto &p : ps) cin >> p;\n\n vector< vector< double > > g(N + 2, vector< double >(N + 2, 1e9));\n for(int i = 0; i < g.size(); i++) g[i][i] = 0;\n\n auto add = [&](int u, int v, double cost)\n {\n g[u][v] = g[v][u] = min(g[v][u], cost);\n };\n\n for(int i = 0; i < N; i++) {\n add(i, (i + 1) % N, (ps[i] - ps[(i + 1) % N]).abs());\n }\n for(int i = 0; i < 2; i++) {\n for(int j = 0; j < N; j++) {\n Segment base(pt[i], ps[j]);\n bool intersect = false;\n for(int k = 0; k < N; k++) {\n if(j == k) continue;\n if(j == (k + 1) % N) continue;\n intersect |= Intersect((Segment) {ps[k], ps[(k + 1) % N]}, base);\n }\n if(!intersect) add(i + N, j, (base.a - base.b).abs());\n }\n }\n\n WarshallFloyd(g);\n double ret = g[N][N + 1];\n for(int i = 0; i < N; i++) {\n double low = 0, high = 1.0;\n Segment s(ps[i], ps[(i + 1) % N]);\n\n auto getDist = [&](double v)\n {\n Point peet = s.a + (s.b - s.a) * v;\n Segment latte = Segment(pt[0], peet);\n Segment malta = Segment(pt[1], peet);\n bool intersect = false;\n for(int k = 0; k < N; k++) {\n if(i == k) continue;\n intersect |= Intersect(latte, (Segment) {ps[k], ps[(k + 1) % N]});\n intersect |= Intersect(malta, (Segment) {ps[k], ps[(k + 1) % N]});\n }\n double dist = 1145141919;\n if(!intersect) dist = (latte.a - latte.b).abs() + (malta.a - malta.b).abs();\n return (dist);\n };\n\n for(int j = 0; j < 300; j++) {\n double left = (low * 2 + high) / 3;\n double right = (low + high * 2) / 3;\n\n if(getDist(left) < getDist(right)) high = right;\n else low = left;\n }\n ret = min(ret, getDist(low));\n }\n\n cout << fixed << setprecision(10) << ret << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3368, "score_of_the_acc": -1.0311, "final_rank": 7 } ]
aoj_0371_cpp
Electric Metronome A boy named PCK is playing with N electric metronomes. The i -th metronome is set to tick every t_i seconds. He started all of them simultaneously. He noticed that, even though each metronome has its own ticking interval, all of them tick simultaneously from time to time in certain intervals. To explore this interesting phenomenon more fully, he is now trying to shorten the interval of ticking in unison by adjusting some of the metronomes’ interval settings. Note, however, that the metronomes do not allow any shortening of the intervals. Given the number of metronomes and their preset intervals t_i (sec), write a program to make the tick-in-unison interval shortest by adding a non-negative integer d_i to the current interval setting of the i -th metronome, and report the minimum value of the sum of all d_i . Input The input is given in the following format. N t_1 t_2 : t_N The first line provides the number of metronomes N (1 ≤ N ≤ 10 5 ). Each of the subsequent N lines provides the preset ticking interval t_i (1 ≤ t_i ≤ 10 4 ) of the i -th metronome. Output Output the minimum value. Sample Input 1 3 3 6 8 Sample Output 1 3 If we have three metronomes each with a ticking interval of 3, 6, and 8 seconds, respectively, simultaneous activation of these will produce a tick in unison every 24 seconds. By extending the interval by 1 second for the first, and 2 seconds for the second metronome, the interval of ticking in unison will be reduced to 8 seconds, which is the shortest possible for the system. Sample Input 2 2 10 10 Sample Output 2 0 If two metronomes are both set to 10 seconds, then simultaneous activation will produce a tick in unison every 10 seconds, which is the shortest possible for this system.
[ { "submission_id": "aoj_0371_11026002", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int N;\n cin>>N;\n vector<int> A(N);\n for(int i=0;i<N;i++) cin>>A[i];\n sort(A.begin(),A.end());\n int ans = 0;\n int now = 1;\n for(int x:A){\n while(A[N-1]%now || now < x) now++;\n ans += x-now;\n }\n cout<<-ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3904, "score_of_the_acc": -0.8114, "final_rank": 11 }, { "submission_id": "aoj_0371_10853855", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tint n;\n\tcin>>n;\n\tvector<int> vec(n);\n\tfor(int i=0;i<n;i++){\n\t\tcin>>vec[i];\n\t}\n\tint ma=*max_element(vec.begin(),vec.end());\n\tvector<int> div;\n\tfor(int i=1;i*i<=ma;i++){\n\t\tif(ma%i==0){\n\t\t\tdiv.push_back(i);\n\t\t\tif(i!=ma/i)div.push_back(ma/i);\n\t\t}\n\t}\n\tsort(div.begin(),div.end());\n\tint ans=0;\n\tfor(int i=0;i<n;i++){\n\t\tans+=*lower_bound(div.begin(),div.end(),vec[i])-vec[i];\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.4298, "final_rank": 4 }, { "submission_id": "aoj_0371_10791410", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int n;cin >>n;\n vector<int> t(n);\n int mx=0;\n for (int i=0;i<n;i++) {\n cin>>t[i];\n mx=max(mx,t[i]);\n }\n vector<int> ds;\n for (int x=1;x<=mx;x++) if (mx%x==0)ds.push_back(x);\n long long ans=0;\n for (auto x : t) {\n for (auto v : ds) {\n if (v>=x) {\n ans+=v-x;\n break;\n }\n }\n }\n cout << ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3712, "score_of_the_acc": -0.6009, "final_rank": 6 }, { "submission_id": "aoj_0371_10046701", "code_snippet": "#include <algorithm>\n#include <cstdlib>\n#include <iomanip>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst size_t N_MIN = 1;\nconst size_t N_MAX = 1e5;\nconst size_t T_MIN = 1;\nconst size_t T_MAX = 1e4;\n\nint main()\n{\n int n = 0;\n cin >> n;\n if (n < N_MIN || N_MAX < n)\n {\n cout << N_MIN << \" <= n <= \" << N_MAX << \") but input \" << n << endl;\n exit(1);\n }\n vector<int> tlist(n);\n for (int i = 0; i < n; i++)\n {\n cin >> tlist[i];\n if (tlist[i] < T_MIN || T_MAX < tlist[i])\n {\n cout << T_MIN << \" <= xi <= \" << T_MAX << \") but input \" << tlist[i] << endl;\n exit(1);\n }\n }\n // 昇順ソート\n sort(tlist.begin(), tlist.end());\n // maxの約数を列挙\n vector<int> divisor(tlist[n - 1]);\n int maxt = tlist[n - 1];\n int dCount = 0;\n for (int i = 1; i <= maxt; i++)\n {\n if ((maxt % i) == 0)\n {\n divisor[dCount++] = i;\n }\n }\n long long ans = 0;\n for (int i = 0; i < n; i++)\n {\n // tを増やして、最初に一致する約数を検索\n for (int j = 0; j < dCount; j++)\n {\n if (divisor[j] >= tlist[i])\n {\n ans += (divisor[j] - tlist[i]);\n break;\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3608, "score_of_the_acc": -0.4868, "final_rank": 5 }, { "submission_id": "aoj_0371_9520069", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nlong long n,t,i,j,a,flg[9999],d,mx;\nint main(void){\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>t;\n\t\tif(mx<t) mx=t;\n\t\tflg[t-1]++;\n\t}\n\tfor(i=0;i<mx;i++){\n\t\tif(flg[i]>0){\n\t\t\tfor(j=0;j<=10000;j++){\n\t\t\t\tif(mx%(i+1+j)==0){\n\t\t\t\t\td+=flg[i]*j;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<d<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3164, "score_of_the_acc": -0.3871, "final_rank": 3 }, { "submission_id": "aoj_0371_9519712", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,t[100000],i,j,a,d=0,mx=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>t[i];\n\t\tif(mx<t[i]) mx=t[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<=4500;j++){\n\t\t\ta=t[i]+j;\n\t\t\tif(mx%a==0){\n\t\t\t\td+=j;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<d<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 220, "memory_kb": 3272, "score_of_the_acc": -0.7958, "final_rank": 19 }, { "submission_id": "aoj_0371_9519689", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,t[100000],i,j,a,d=0,mx=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>t[i];\n\t\tif(mx<t[i]) mx=t[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<=4000;j++){\n\t\t\ta=t[i]+j;\n\t\t\tif(mx%a==0){\n\t\t\t\td+=j;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<d<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 220, "memory_kb": 3240, "score_of_the_acc": -0.7608, "final_rank": 18 }, { "submission_id": "aoj_0371_9519681", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,t[100000],i,j,a,d=0,mx=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>t[i];\n\t\tif(mx<t[i]) mx=t[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<=2500;j++){\n\t\t\ta=t[i]+j;\n\t\t\tif(mx%a==0){\n\t\t\t\td+=j;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<d<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 180, "memory_kb": 3324, "score_of_the_acc": -0.7238, "final_rank": 17 }, { "submission_id": "aoj_0371_9519571", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,t[100000],i,j,a,d=0,mx=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>t[i];\n\t\tif(mx<t[i]) mx=t[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<=1000;j++){\n\t\t\ta=t[i]+j;\n\t\t\tif(mx%a==0){\n\t\t\t\td+=j;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<d<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 100, "memory_kb": 3236, "score_of_the_acc": -0.3693, "final_rank": 16 }, { "submission_id": "aoj_0371_9519392", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,i,t[100001];\n\nint main()\n{\n\tlong long max=0,k=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++) {\n\t\tcin>>t[i];\n\t\tif(max<t[i])max=t[i];\n\t}\n\tint j;\n\tfor(i=0;i<n;i++){\n\t\tif(max%t[i]!=0){\n\t\t\tfor(j=0;j<1001;j++){\n\t\t\t\tif(max%t[i]==0)break;\n\t\t\t\tt[i]++;\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<k<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 320, "memory_kb": 3272, "score_of_the_acc": -1.1184, "final_rank": 20 }, { "submission_id": "aoj_0371_9519060", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,i,t[100001],k=0;\n\nint main()\n{\n\tlong long max=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++) {\n\t\tcin>>t[i];\n\t\tif(max<t[i])max=t[i];\n\t}\n\tint j;\n\tfor(i=0;i<n;i++){\n\t\tif(max%t[i]!=0){\n\t\t\tfor(j=0;j<100;j++){\n\t\t\t\tif(max%t[i]==0)break;\n\t\t\t\tt[i]++;\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<k<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 50, "memory_kb": 3276, "score_of_the_acc": -0.2518, "final_rank": 15 }, { "submission_id": "aoj_0371_9518940", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n,i,t[100001],k=0;\nint main()\n{\n\tint max=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++) {\n\t\tcin>>t[i];\n\t\tif(max<t[i])max=t[i];\n\t}\n\tint j;\n\tfor(i=0;i<n;i++){\n\t\tif(max%t[i]!=0){\n\t\t\tfor(j=0;j<100;j++){\n\t\t\t\tif(max%t[i]==0)break;\n\t\t\t\tt[i]++;\n\t\t\t\tk++;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<k<<endl;\n\treturn 0;\n}", "accuracy": 0.36363636363636365, "time_ms": 20, "memory_kb": 3324, "score_of_the_acc": -0.2077, "final_rank": 14 }, { "submission_id": "aoj_0371_8456502", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tlong long n;\n\tcin >> n;\n\tvector<long long> a(n);\n\tfor(long long i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tsort(a.begin(),a.end());\n\tlong long it = a.back();\n\tvector<long long> p;\n\tfor(long long i = 1;i <= it;i++){\n\t\tif(it % i == 0){\n\t\t\tp.push_back(i);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor(long long i = 0;i < n - 1;i++){\n\t\tauto pos = lower_bound(p.begin(),p.end(),a[i]);\n\t\tans += *pos - a[i];\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3888, "score_of_the_acc": -0.7939, "final_rank": 10 }, { "submission_id": "aoj_0371_8291487", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n int N, t[100000];\n cin >> N;\n for (int i = 0; i < N; i++) {\n cin >> t[i];\n }\n\n int max_t = *max_element(t, t + N);\n vector<int> divs_mt;\n for (int i = 1; i*i <= max_t; i++) {\n if (max_t % i == 0) {\n divs_mt.push_back(i);\n divs_mt.push_back(max_t / i);\n }\n }\n sort(divs_mt.begin(), divs_mt.end());\n \n \n int ans = 0;\n for (int i = 0; i < N; i++) {\n ans += *lower_bound(divs_mt.begin(),\n divs_mt.end(), t[i]) - t[i];\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3732, "score_of_the_acc": -0.6228, "final_rank": 7 }, { "submission_id": "aoj_0371_8291480", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n int N, t[100000];\n cin >> N;\n for (int i = 0; i < N; i++) {\n cin >> t[i];\n }\n\n int max_t = *max_element(t, t + N);\n vector<int> divs_mt;\n for (int i = 1; i <= max_t; i++) {\n if (max_t % i == 0) {\n divs_mt.push_back(i);\n }\n }\n \n \n int ans = 0;\n for (int i = 0; i < N; i++) {\n ans += *lower_bound(divs_mt.begin(),\n divs_mt.end(), t[i]) - t[i];\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3808, "score_of_the_acc": -0.7061, "final_rank": 8 }, { "submission_id": "aoj_0371_8257067", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a;\n cin>>a;\n vector<int> b(a);\n for(int i=0;i<a;i+=1){\n cin>>b.at(i);\n }\n sort(b.begin(),b.end());\n int cycle=b.at(a-1);\n vector<int> c(0);\n for(int i=1;i*i<=cycle;i+=1){\n if(cycle%i==0){\n c.push_back(i);\n c.push_back(cycle/i);\n }\n }\n sort(c.begin(),c.end());\n int ans=0;\n for(int i=0;i<a-1;i+=1){\n ans+=*lower_bound(c.begin(),c.end(),b.at(i))-b.at(i);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3276, "score_of_the_acc": -0.1551, "final_rank": 2 }, { "submission_id": "aoj_0371_7077920", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nll mod1 = 1000000007;\n\n\nint main(){\n ll N;cin >> N;\n vector<ll> t(N);\n ll ma = 0;\n vector<ll> a(0);\n for(int i = 0; i < N; i++) cin >> t[i];\n for(int i = 0; i < N; i++){\n ma = max(ma,t[i]);\n }\n for(int i = 1; i <= ma; i++){\n if((ma%i) == 0) a.push_back(i);\n }\n ll d = 0;\n for(int i = 0; i < N; i++){\n for(auto aa: a){\n if(t[i]<=aa){\n d+=aa-t[i];\n break;\n }\n }\n }\n cout << d << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3876, "score_of_the_acc": -0.7807, "final_rank": 9 }, { "submission_id": "aoj_0371_7072549", "code_snippet": "#include<bits/stdc++.h>\nusing ll=long long;\nusing namespace std;\nvector<ll>AllDivisors(ll a)\n{\n auto back=vector<ll>();\n for(int i=1; pow(i,2)<=a; i++)\n {\n if(a%i==0)\n {\n back.push_back(i);\n back.push_back(a/i);\n }\n }\n return back;\n}\n\n\nint main()\n{\n int n; cin>>n;\n auto t=vector<ll>();\n ll big=0;\n for(int i=0; i<n; i++)\n {\n ll a; cin>>a;\n t.push_back(a);\n big=max(big,a);\n }\n auto d=AllDivisors(big);\n sort(d.begin(),d.end());\n ll ans=0;\n for(auto i:t)\n {\n auto p=lower_bound(d.begin(),d.end(),i);\n ans+=*p-i;\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4076, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0371_7072485", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//#include <boost/multiprecision/cpp_int.hpp>\n//namespace mp = boost::multiprecision;\nusing namespace std;\n//using namespace atcoder;\n//using mint = modint1000000007;\n//using mint2 = modint998244353;\ntypedef long long ll;\n#define rep1(i, m, n) for(int i = m; i < (int)(n); i++)\n#define rep2(i, m, n) for(int i = m; i <= (int)(n); i++)\n#define all(x) x.begin(), x.end()\n#define rall(x) x.rbegin(), x.rend()\ntemplate<class T> inline bool chmax(T& a, T b) { if(a < b) {a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if(a > b) {a = b; return true; } return false; }\nconst ll INF = 1LL << 60;\n//#define _GLIBCXX_DEBUG\n// 範囲外エラーを教えてくれる。使うときはincludeより上に置く。\n \n// const char newl='\\n';\n\nvector<long long> divisor(long long n) {\n vector<long long> ret;\n for (long long i = 1; i * i <= n; i++) {\n if (n % i == 0) {\n ret.push_back(i);\n if (i * i != n) ret.push_back(n / i);\n }\n }\n sort(ret.begin(), ret.end()); // 昇順に並べる\n return ret;\n}\n\nint lcm(int a, int b){\n return a*b / __gcd(a, b);\n}\n\nint main() {\n int n; cin >> n;\n vector<int> t(n);\n int mt=0;\n for (int i=0; i<n; i++) {\n cin >> t[i];\n mt=max(mt,t[i]);\n }\n vector<ll> d=divisor(ll(mt));\n int ans=0;\n for (int i=0; i<n; i++) {\n std::vector<long long>::iterator ite=lower_bound(all(d),t[i]);\n ans+=*ite-t[i];\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3244, "score_of_the_acc": -0.0877, "final_rank": 1 }, { "submission_id": "aoj_0371_7071686", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\nusing namespace std;\nusing ll = long long;\n\nll ll_gcd(ll a, ll b) {\n if (a < b) return ll_gcd(b, a);\n ll r;\n while ((r = a % b)) {\n a = b;\n b = r;\n }\n return b;\n}\n\nint main() {\n ll n;\n cin >> n;\n vector<ll> z(n);\n for (int i = 0; i < n; i++) {\n cin >> z[i];\n }\n sort(z.begin(), z.end());\n ll t = z[n-1];\n vector<ll> c;\n for (int i = 0; i < t; i++) {\n if (t % (i + 1) == 0)c.push_back(i + 1);\n }\n ll ans = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < c.size(); j++) {\n if (c[j] >= z[i]) {\n ans += c[j] - z[i];\n break;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3948, "score_of_the_acc": -0.8596, "final_rank": 12 } ]
aoj_0374_cpp
Paper Fortune If you visit Aizu Akabeko shrine, you will find a unique paper fortune on which a number with more than one digit is written. Each digit ranges from 1 to 9 (zero is avoided because it is considered a bad omen in this shrine). Using this string of numeric values, you can predict how many years it will take before your dream comes true. Cut up the string into more than one segment and compare their values. The difference between the largest and smallest value will give you the number of years before your wish will be fulfilled. Therefore, the result varies depending on the way you cut up the string. For example, if you are given a string 11121314 and divide it into segments, say, as 1,11,21,3,14, then the difference between the largest and smallest is 21 - 1 = 20. Another division 11,12,13,14 produces 3 (i.e. 14 - 11) years. Any random division produces a game of luck. However, you can search the minimum number of years using a program. Given a string of numerical characters, write a program to search the minimum years before your wish will be fulfilled. Input The input is given in the following format. n An integer n is given. Its number of digits is from 2 to 100,000, and each digit ranges from 1 to 9. Output Output the minimum number of years before your wish will be fulfilled. Sample Input 1 11121314 Sample Output 1 3 Sample Input 2 123125129 Sample Output 2 6 Sample Input 3 119138 Sample Output 3 5
[ { "submission_id": "aoj_0374_10874359", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, l, n) for(int i = int(l); i < int(n); i++)\n#define ll long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate<class T> bool chmin(T &a, T b) {if(a > b) {a = b; return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a < b) {a = b; return true;} return false;}\ntemplate<class T> using spq = priority_queue<T, vector<T>, greater<T>>;\n\n// bool -> Yes/No\nstring answer(bool b) {return b ? \"Yes\" : \"No\";}\n\nvoid fix(int k) {cout << fixed << setprecision(k);}\n\nconst int inf = 2e9;\nconst long long INF = 2e18;\nconst long double eps = 1e-12;\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};\n\nvoid main_program() {\n string s; cin >> s;\n int n = s.size();\n // 1桁のみに分ける場合\n int mn = inf, mx = 0;\n rep(i, 0, n) {\n int c = s[i] - '0';\n chmin(mn, c);\n chmax(mx, c);\n }\n int ans = mx - mn;\n if(n == 2) {\n cout << ans << \"\\n\";\n return;\n }\n // 1桁と2桁のみに分ける場合\n mn = inf, mx = 0;\n rep(i, 0, n) {\n if(s[i] != '1') {\n int c = s[i] - '0';\n chmin(mn, c); chmax(mx, c);\n }\n else {\n if(i < n - 1) {\n int c = s[i + 1] - '0';\n chmin(mn, c + 10); chmax(mx, c + 10);\n i++;\n }\n else {\n chmin(mn, 1); chmax(mx, 1);\n }\n }\n }\n chmin(ans, mx - mn);\n // k >= 2 として、k桁のみに分ける場合\n for(int k = 2; k < n; k++) {\n if(n % k) continue;\n mn = inf, mx = 0;\n rep(i, 0, n) {\n if(i % k == k - 2) {\n assert(i + 1 < n);\n int c = (s[i] - '0') * 10 + (s[i + 1] - '0');\n chmin(mn, c); chmax(mx, c);\n i++;\n }\n else {\n if(s[i] != s[(i + k) % n]) {\n mn = 0, mx = inf;\n }\n }\n }\n chmin(ans, mx - mn);\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int T = 1;\n //cin >> T;\n while(T--) {\n main_program();\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3580, "score_of_the_acc": -0.0157, "final_rank": 4 }, { "submission_id": "aoj_0374_10873585", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, l, n) for(int i = int(l); i < int(n); i++)\n#define ll long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate<class T> bool chmin(T &a, T b) {if(a > b) {a = b; return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a < b) {a = b; return true;} return false;}\ntemplate<class T> using spq = priority_queue<T, vector<T>, greater<T>>;\n\n// bool -> Yes/No\nstring answer(bool b) {return b ? \"Yes\" : \"No\";}\n\nvoid fix(int k) {cout << fixed << setprecision(k);}\n\nconst int inf = 2e9;\nconst long long INF = 2e18;\nconst long double eps = 1e-12;\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};\n\nvoid main_program() {\n string s; cin >> s;\n int n = s.size();\n // 1桁のみに分ける場合\n int mn = inf, mx = 0;\n rep(i, 0, n) {\n int c = s[i] - '0';\n chmin(mn, c);\n chmax(mx, c);\n }\n int ans = mx - mn;\n // 1桁と2桁のみに分ける場合\n mn = inf, mx = 0;\n rep(i, 0, n) {\n if(s[i] != '1') {\n int c = s[i] - '0';\n chmin(mn, c); chmax(mx, c);\n }\n else {\n if(i < n - 1) {\n int c = s[i + 1] - '0';\n chmin(mn, c + 10); chmax(mx, c + 10);\n i++;\n }\n else {\n chmin(mn, 1); chmax(mx, 1);\n }\n }\n }\n chmin(ans, mx - mn);\n // k >= 2 として、k桁のみに分ける場合\n for(int k = 2; k < n; k++) {\n if(n % k) continue;\n mn = inf, mx = 0;\n rep(i, 0, n) {\n if(i % k == k - 2) {\n assert(i + 1 < n);\n int c = (s[i] - '0') * 10 + (s[i + 1] - '0');\n chmin(mn, c); chmax(mx, c);\n i++;\n }\n else {\n if(s[i] != s[(i + k) % n]) {\n mn = 0, mx = inf;\n }\n }\n }\n chmin(ans, mx - mn);\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int T = 1;\n //cin >> T;\n while(T--) {\n main_program();\n }\n}", "accuracy": 0.3, "time_ms": 20, "memory_kb": 3472, "score_of_the_acc": -0.0144, "final_rank": 16 }, { "submission_id": "aoj_0374_7077958", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nint main()\n{\n string S;\n cin >> S;\n ll Min = 10, Max = -1;\n for (char ch : S)\n {\n Min = min(Min, (ll)(ch - '0'));\n Max = max(Max, (ll)(ch - '0'));\n }\n ll ans = Max - Min;\n for (ll i = 2; i * i <= S.size(); i++)\n {\n if ((ll)S.size() % i == 0)\n {\n set<ll> A;\n ll num = 0;\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % i == i - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n if (i * i != S.size())\n {\n ll m = (ll)S.size() / i;\n A.clear();\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % m == m - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n }\n }\n }\n set<ll>B;\n ll num = 0;\n for (ll i = 0; i < S.size(); i++) {\n num *= 10;\n num += S[i] - '0';\n num %= 100;\n if (num != 1) {\n B.insert(num); num = 0;\n }\n }\n if (num != 0) B.insert(num);\n if (B.size() > 1) ans = min(ans, *prev(B.end(), 1) - *B.begin());\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4228, "score_of_the_acc": -0.0676, "final_rank": 7 }, { "submission_id": "aoj_0374_7077957", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nint main()\n{\n string S;\n cin >> S;\n ll Min = 10, Max = -1;\n for (char ch : S)\n {\n Min = min(Min, (ll)(ch - '0'));\n Max = max(Max, (ll)(ch - '0'));\n }\n ll ans = Max - Min;\n for (ll i = 2; i * i <= S.size(); i++)\n {\n if ((ll)S.size() % i == 0)\n {\n set<ll> A;\n ll num = 0;\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % i == i - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n if (i * i != S.size())\n {\n ll m = (ll)S.size() / i;\n A.clear();\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % m == m - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n }\n }\n }\n set<ll>B;\n ll num = 0;\n for (ll i = 0; i < S.size(); i++) {\n num *= 10;\n num += S[i] - '0';\n num %= 100;\n if (num != 1) {\n B.insert(num); num = 0;\n }\n }\n \n if (B.size() > 1) ans = min(ans, *prev(B.end(), 1) - *B.begin());\n\n cout << ans << endl;\n}", "accuracy": 0.475, "time_ms": 60, "memory_kb": 3428, "score_of_the_acc": -0.0578, "final_rank": 14 }, { "submission_id": "aoj_0374_7077954", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nint main()\n{\n string S;\n cin >> S;\n ll Min = 10, Max = -1;\n for (char ch : S)\n {\n Min = min(Min, (ll)(ch - '0'));\n Max = max(Max, (ll)(ch - '0'));\n }\n ll ans = Max - Min;\n for (ll i = 2; i * i <= S.size(); i++)\n {\n if ((ll)S.size() % i == 0)\n {\n set<ll> A;\n ll num = 0;\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % i == i - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n if (i * i != S.size())\n {\n ll m = (ll)S.size() / i;\n A.clear();\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n num %= 1000000007;\n if (j % m == m - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n }\n }\n }\n set<ll>B;\n ll num = 0;\n for (ll i = 0; i < S.size(); i++) {\n num *= 10;\n num += S[i] - '0';\n num %= 100;\n if (num != 1) {\n B.insert(num); num = 0;\n }\n }\n ans = min(ans, *prev(B.end(), 1) - *B.begin());\n\n cout << ans << endl;\n}", "accuracy": 0.3, "time_ms": 60, "memory_kb": 3352, "score_of_the_acc": -0.0569, "final_rank": 17 }, { "submission_id": "aoj_0374_7077943", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nint main()\n{\n string S;\n cin >> S;\n ll Min = 10, Max = -1;\n for (char ch : S)\n {\n Min = min(Min, (ll)(ch - '0'));\n Max = max(Max, (ll)(ch - '0'));\n }\n ll ans = Max - Min;\n for (ll i = 2; i * i <= S.size(); i++)\n {\n if ((ll)S.size() % i == 0)\n {\n set<ll> A;\n ll num = 0;\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n if (j % i == i - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n if (i * i != S.size())\n {\n ll m = (ll)S.size() / i;\n A.clear();\n for (ll j = 0; j < S.size(); j++)\n {\n num *= 10;\n num += S[j] - '0';\n if (j % m == m - 1)\n {\n A.insert(num);\n num = 0;\n }\n }\n ans = min(ans, *prev(A.end(), 1) - *A.begin());\n }\n }\n }\n set<ll>B;\n ll num = 0;\n for (ll i = 0; i < S.size(); i++) {\n num *= 10;\n num += S[i] - '0';\n if (num != 1) {\n B.insert(num); num = 0;\n }\n }\n ans = min(ans, *prev(B.end(), 1) - *B.begin());\n\n cout << ans << endl;\n}", "accuracy": 0.275, "time_ms": 50, "memory_kb": 3472, "score_of_the_acc": -0.0474, "final_rank": 20 }, { "submission_id": "aoj_0374_7072426", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<int(n);i++)\nusing ll=long long;\n\ntemplate<typename T>\nbool chmin(T &a,T b){\n return a>b ? a=b,true:false;\n}\n\nint main(){\n string s;\n cin >> s;\n int ans=10;\n\n //全て同じ長さで切る場合(3以上)\n auto all_same=[&](int len){\n assert(s.size()%len==0);\n assert(len>=3);\n string mx=s.substr(0,len);\n string mn=s.substr(0,len);\n for(int i=len;i<int(s.size());i+=len){\n mx=max(mx,s.substr(i,len));\n mn=min(mn,s.substr(i,len));\n }\n //cout << mx << ' ' << mn << endl;\n //cout << stoi(mx.substr(mx.size()-2)) << ' ' << stoi(mn.substr(mn.size()-2)) << endl;\n if(mx.substr(0,mx.size()-2)!=mn.substr(0,mn.size()-2))return 10;\n else return stoi(mx.substr(mx.size()-2))-stoi(mn.substr(mn.size()-2));\n };\n //全て2桁以下 dpがまわる?\n //dp[i][j]=i桁みて、最小値がjの時、そこまでの最大値min\n {\n vector<vector<int>> dp(s.size()+1,vector<int>(100,1000));\n dp[1][s[0]-'0']=s[0]-'0';\n //2桁だったらこれはダメ\n if(s.size()!=2)dp[2][stoi(s.substr(0,2))]=stoi(s.substr(0,2));\n for(int i=1;i<int(s.size());i++)rep(j,100){\n //1だけ伸ばす\n chmin(dp[i+1][min(j,s[i]-'0')],max(dp[i][j],s[i]-'0'));\n //2伸ばす\n if(i+2<=int(s.size()))chmin(dp[i+2][min(j,stoi(s.substr(i,2)))],max(dp[i][j],stoi(s.substr(i,2))));\n }\n rep(j,100)chmin(ans,dp.back()[j]-j);\n }\n //デバッグ出力\n //cout << ans << endl;\n\n\n for(int i=1;i*i<=int(s.size());i++)if(s.size()%i==0){\n if(i>2)chmin(ans,all_same(i));\n if(i>1)chmin(ans,all_same(s.size()/i));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 46116, "score_of_the_acc": -0.8532, "final_rank": 11 }, { "submission_id": "aoj_0374_7049771", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\n\n\nint solve(){\n string s; cin >> s;\n int n = s.size();\n vi a(s.size());\n rep(i,0,s.size())a[i] = s[i]-'0';\n rep(i,0,8){\n rep(mi,1,99){\n int ma = mi+i;\n int now = 0;\n int ind = 0;\n bool ok = 1;\n int cnt = 0;\n while(ind < n){\n now = 10*now + a[ind];\n if(mi <= now && now <= ma){\n cnt++;\n now = 0;\n }\n else if(ma < now){\n ok = 0;\n break;\n }\n ind++;\n }\n if(now != 0)ok = 0;\n if(cnt == 1)ok = 0;\n if(ok){\n cout << i << endl;\n return 0;\n }\n }\n rep(k,3,n){\n if(n % k != 0)continue;\n vector<string> vs;\n int ind = 0;\n while(ind < n){\n string tmps;\n rep(j,ind,min(ind+k,(ll)n))tmps.push_back(s[j]);\n vs.push_back(tmps);\n ind += k;\n }\n sort(all(vs));\n string l = vs[0];\n string h = vs.back();\n string nl;\n int tmp = i;\n for(int j = l.size()-1; j >= 0; --j){\n tmp += (l[j]-'0');\n nl.push_back('0'+(tmp%10));\n tmp /= 10;\n }\n while(tmp > 0){\n nl.push_back('0'+(tmp%10));\n tmp /= 10;\n }\n while(nl.size() < h.size())nl.push_back('0');\n reverse(all(nl));\n if(nl >= h){\n cout << i << endl;\n return 0;\n }\n }\n }\n cout << 8 << endl;\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 5584, "score_of_the_acc": -0.183, "final_rank": 8 }, { "submission_id": "aoj_0374_7049749", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vl = vector<ll>;\nusing pi = pair<int,int>;\nusing pl = pair<ll,ll>;\n#define all(x) x.begin(),x.end()\n#define rep(i,j,n) for (long long i = j; i < (long long)(n); i++)\nconst long long MOD = 1000000007;\nconst long long MOD2 = 998244353;\nconst int INF = ((1<<30)-1);\nconst long long LINF = (1LL<<60);\nconst double PI = 3.141592653589793238;\ntemplate<class T> inline void chmax(T& a, T b) {if (a < b) {a = b;}}\ntemplate<class T> inline void chmin(T& a, T b) {if (a > b) {a = b;}}\n\n\n\nint solve(){\n string s; cin >> s;\n int n = s.size();\n vi a(s.size());\n rep(i,0,s.size())a[i] = s[i]-'0';\n rep(i,0,8){\n rep(mi,1,99){\n int ma = mi+i;\n int now = 0;\n int ind = 0;\n bool ok = 1;\n int cnt = 0;\n while(ind < n){\n now = 10*now + a[ind];\n if(mi <= now && now <= ma){\n cnt++;\n now = 0;\n }\n else if(ma < now){\n ok = 0;\n break;\n }\n ind++;\n }\n if(now != 0)ok = 0;\n if(cnt == 1)ok = 0;\n if(ok){\n cout << i << endl;\n return 0;\n }\n }\n rep(k,3,n){\n vector<string> vs;\n int ind = 0;\n while(ind < n){\n string tmps;\n rep(j,ind,min(ind+k,(ll)n))tmps.push_back(s[j]);\n vs.push_back(tmps);\n ind += k;\n }\n sort(all(vs));\n string l = vs[0];\n string h = vs.back();\n string nl;\n int tmp = i;\n for(int j = l.size()-1; j >= 0; --j){\n tmp += (l[j]-'0');\n nl.push_back('0'+(tmp%10));\n tmp /= 10;\n }\n while(tmp > 0){\n nl.push_back('0'+(tmp%10));\n tmp /= 10;\n }\n reverse(all(nl));\n if(nl >= h){\n cout << i << endl;\n return 0;\n }\n }\n }\n cout << 8 << endl;\n\n\n\n return 0;\n}\n\nint main(){\n cout << fixed << setprecision(10);\n ios::sync_with_stdio(0), cin.tie(0);\n int t = 1; \n //cin >> t;\n for(int i = 0; i < t; i++){\n solve();\n }\n\treturn 0;\n}", "accuracy": 0.425, "time_ms": 920, "memory_kb": 5052, "score_of_the_acc": -1.0227, "final_rank": 15 }, { "submission_id": "aoj_0374_6973225", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0374.cc: Paper Fortune\n */\n\n#include<cstdio>\n#include<cstring>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\n\n/* typedef */\n\ntypedef vector<int> vi;\n\n/* global variables */\n\nchar s[MAX_N + 4];\n\n/* subroutines */\n\nint subv(const vi &a, const vi &b) {\n int ret = -1, co = 0;\n for (int i = a.size() - 1; i >= 0; i--) {\n int d = a[i] - b[i] - co;\n if (d < 0) d += 10, co = 1;\n else co = 0;\n if (i == a.size() - 1) ret = d;\n else if (d > 0) return -1;\n }\n if (co > 0) return -1;\n return ret;\n}\n\n/* main */\n\nint main() {\n scanf(\"%s\", s);\n int n = strlen(s);\n\n vi ss(n);\n for (int i = 0; i < n; i++) ss[i] = s[i] - '0';\n\n vi ds(1, 1);\n for (int p = 2; p * p <= n; p++)\n if (n % p == 0) {\n ds.push_back(p);\n int q = n / p;\n if (q != p) ds.push_back(q);\n }\n sort(ds.begin(), ds.end());\n\n int mind = 10;\n for (auto l: ds) {\n vi minv(ss.begin(), ss.begin() + l);\n vi maxv(minv);\n for (int i = l; i < n; i+= l) {\n vi v(ss.begin() + i, ss.begin() + i + l);\n if (minv > v) minv = v;\n if (maxv < v) maxv = v;\n }\n int d = subv(maxv, minv);\n if (d >= 0) mind = min(mind, d);\n }\n\n int mint = 10, maxt = 0;\n for (int i = 0; i < n;) {\n if (ss[i] == 1 && i + 1 < n) {\n int t = ss[i] * 10 + ss[i + 1];\n mint = min(mint, t);\n maxt = max(maxt, t);\n i += 2;\n }\n else {\n mint = min(mint, ss[i]);\n maxt = max(maxt, ss[i]);\n i++;\n }\n }\n mind = min(mind, maxt - mint);\n\n printf(\"%d\\n\", mind);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3848, "score_of_the_acc": -0.008, "final_rank": 2 }, { "submission_id": "aoj_0374_6048045", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\nusing ll = long long;\n\n#define rep(i, n) for (ll i = 0; (i) < (ll) (n); (i)++)\n#define rep2(i, s, n) for(ll i = (ll) (s); (i) < (ll) (n); (i)++)\n#define rrep(i, n) for (ll i = (ll) (n) - 1; (i) >= 0; (i)--)\n\ntemplate<class T>\nbool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T>\nbool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T>\nvoid vecout(const vector<T> &v, char div = '\\n') {\n rep(i, v.size()) {\n if (i) cout << div;\n cout << v[i];\n }\n cout << endl;\n}\n\nint main() {\n string s;\n cin >> s;\n\n int n = s.size();\n\n if (n == 2) {\n cout << abs(s[0] - s[1]) << endl;\n return 0;\n }\n\n vector<int> divisors;\n rep2(i, 1, n + 1) {\n if (i * i > n) break;\n if (n % i == 0) {\n divisors.push_back(i);\n if (i * i != n) {\n divisors.push_back(n / i);\n }\n }\n }\n\n sort(divisors.begin(), divisors.end());\n\n ll ans = 10;\n\n // 桁数が 3 以上の場合\n for (auto len: divisors) {\n if (len <= 2 || len == n) continue;\n// cerr << len << endl;\n string t = s.substr(0, len - 2);\n int mx = stoi(s.substr(len - 2, 2));\n int mn = mx;\n rep(i, n / len) {\n int start = i * len;\n string t1 = s.substr(start, len - 2);\n if (t != t1) {\n goto CONTINUE;\n }\n int p = stoi(s.substr(start + len - 2, 2));\n chmax(mx, p);\n chmin(mn, p);\n }\n chmin(ans, ll(mx - mn));\n\n CONTINUE:;\n }\n\n // 桁数が 2 以下である場合\n {\n // dp[i][j] = s[0..i) まで見て,切り分けた最小値が j であるときの,最大値の最小値\n vector<vector<ll>> dp(n + 1, vector<ll>(100, 10000));\n rep(j, 100) dp[0][j] = 0;\n rep(i, n) {\n// vecout(dp[i], ' ');\n rep(j, 100) {\n // 一桁で切る\n {\n ll p = stoi(s.substr(i, 1));\n chmin(dp[i + 1][min(j, p)], max(dp[i][j], p));\n }\n\n // 二桁で切る\n if (i + 2 <= n) {\n ll p = stoi(s.substr(i, 2));\n chmin(dp[i + 2][min(j, p)], max(dp[i][j], p));\n }\n }\n }\n\n rep(j, 100) {\n chmin(ans, dp[n][j] - j);\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 85184, "score_of_the_acc": -1.3626, "final_rank": 13 }, { "submission_id": "aoj_0374_6039230", "code_snippet": "#ifdef LOGX\n#define _GLIBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\n/*---------macro---------*/\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = s; i < (int)(n); i++)\n#define unless(x) if(!(x))\n#define until(x) while(!(x))\n#define ALL(a) a.begin(),a.end()\n#define RALL(a) a.rbegin(),a.rend()\n#define mybit(i,j) (((i)>>(j))&1)\n\n/*---------type/const---------*/\nconst int big=1000000007;\n//const int big=998244353;\nconst double EPS=1e-8; //適宜変える\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef std::string::const_iterator state; //構文解析\nconst int dx[4]={1,0,-1,0};\nconst int dy[4]={0,1,0,-1};\nconst char newl='\\n';\nstruct{\n constexpr operator int(){return -int(1e9)-10;}\n constexpr operator ll(){return -ll(1e18)-10;}\n}neginf;\nstruct{\n constexpr operator int(){return int(1e9)+10;}\n constexpr operator ll(){return ll(1e18)+10;}\n constexpr auto operator -(){return neginf;}\n}inf;\n\n/*---------debug---------*/\n#ifdef LOGX\n#include <template/debug.hpp>\n#else\n#define dbg(...) ;\n#define dbgnewl ;\n#define prt(x) ;\n#define _prt(x) ;\n#endif\n\n/*---------function---------*/\ntemplate<typename T> T max(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=max(ans,elem);}return ans;}\ntemplate<typename T> T min(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=min(ans,elem);}return ans;}\ntemplate<typename T,typename U> bool chmin(T &a,const U b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T,typename U> bool chmax(T &a,const U b){if(a<b){a=b;return true;}return false;}\nbool valid(int i,int j,int h,int w){return (i>=0 && j>=0 && i<h && j<w);}\ntemplate<class T,class U>T expm(T x,U y,const ll mod=big){T res=1;while(y){if(y&1)(res*=x)%=mod;(x*=x)%=mod;y>>=1;}return res;}\ntemplate<class T,class U>T exp(T x,U y){T res=1;while(y){if(y&1)res*=x;x*=x;y>>=1;}return res;}\n\nstring s;\nint sz;\n//len>=3\nint solve_len(int len){\n if(len<3 || len==sz)return 100;\n vector<string> x(sz/len);\n rep(i,sz/len){\n x[i]=s.substr(i*len,len);\n }\n string l=min(x),r=max(x);\n dbg(len,l,r);\n //下から2桁目より上のいずれかが異なっている => 差は((R)*100+(2桁))-((L)*100+(2桁))>=100+(2桁-2桁)>=12 (111-99が最適)\n if(l.substr(0,len-2)!=r.substr(0,len-2))return 10;\n else return stoi(r.substr(len-2))-stoi(l.substr(len-2));\n}\nint solve_12(){\n //そもそものlenが2だと切り分けていない場合があるので別処理\n if(sz==2)return abs(s[0]-s[1]);\n //dp[i][j]=i文字処理して、最小がjの時の最大値の最小\n vector<vector<int>> dp(sz+1,vector<int>(100,1000));\n dp[0][99]=0;\n rep(i,sz)rep(j,100)for(int k:{1,2})if(i+k<=sz){\n //dp[i][j]から、s[i,i+k)を追加した時の遷移\n int J=min(j,stoi(s.substr(i,k)));\n int val=max(dp[i][j],stoi(s.substr(i,k)));\n chmin(dp[i+k][J],val);\n }\n dbg(dp);\n int ans=10;\n rep(j,100)chmin(ans,dp[sz][j]-j);\n return ans;\n}\n\nint main(){\n //std::ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n std::cout.precision(10);\n/*------------------------------------*/\n \n cin >> s;\n sz=s.size();\n int ans=solve_12();\n dbg(ans);\n for(int i=1;i*i<=sz;i++)if(sz%i==0){\n chmin(ans,solve_len(i));\n chmin(ans,solve_len(sz/i));\n }\n cout << ans << newl;\n}\n/*\nそもそも答えは8以下なので、答え全探索はできる。一番左の桁数も決め打つ。\n一番左が1,2桁:適当にdp 最適な分割方法に3桁以上は現れない(3桁-2桁の最小は12(>8))\n3桁以上:n桁-(n-1)桁>=111-99=12>8, (n+1)桁-n桁>8 なので全てn桁でないといけない。\n*/", "accuracy": 1, "time_ms": 610, "memory_kb": 46148, "score_of_the_acc": -1.1832, "final_rank": 12 }, { "submission_id": "aoj_0374_6019072", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 1000;\nvector<int> z_algorithm(string S){\n int N = S.size();\n vector<int> ans(N);\n for (int i = 1, j = 0; i < N; i++){\n if (i + ans[i - j] < j + ans[j]){\n ans[i] = ans[i - j];\n } else {\n int k = max(0, j + ans[j] - i);\n while (i + k < N && S[k] == S[i + k]){\n k++;\n }\n ans[i] = k;\n j = i;\n }\n }\n ans[0] = N;\n return ans;\n}\nint main(){\n string n;\n cin >> n;\n int L = n.size();\n vector<int> Z = z_algorithm(n);\n int ans = 8;\n for (int i = 1; i < L; i++){\n if (L % i == 0){\n bool ok = true;\n for (int j = 0; j < L; j += i){\n if (Z[j] < i - 1){\n ok = false;\n }\n }\n if (ok){\n int mx = 1, mn = 9;\n for (int j = i - 1; j < L; j += i){\n mx = max(mx, n[j] - '0');\n mn = min(mn, n[j] - '0');\n }\n ans = min(ans, mx - mn);\n }\n }\n }\n for (int i = 1; i <= 99; i++){\n vector<int> dp(L + 1, INF);\n dp[0] = i;\n for (int j = 0; j < L; j++){\n int x = n[j] - '0';\n if (x >= i){\n dp[j + 1] = min(dp[j + 1], max(dp[j], x));\n }\n if (j < L - 1 && !(j == 0 && j + 2 == L)){\n int y = (n[j] - '0') * 10 + (n[j + 1] - '0');\n if (y >= i){\n dp[j + 2] = min(dp[j + 2], max(dp[j], y));\n }\n }\n }\n ans = min(ans, dp[L] - i);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4132, "score_of_the_acc": -0.0444, "final_rank": 5 }, { "submission_id": "aoj_0374_5852318", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nusing i64 = long long;\nusing u64 = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\n\nlong long sumvec(vector<int> A){\n\tlong long res = 0;\n\tfor (auto a : A) res += a;\n\treturn res;\n}\n\n\nint solve1(string S, int d){\n\tint n = S.size();\n\tint ansl = 0;\n\tint ansr = 0;\n\tfor (int s = 0; s < n; s += d){\n\t\tint tmp = 0;\n\t\trep(i, d){\n\t\t\ttmp *= 10;\n\t\t\ttmp += S[s + i] - S[i];\n\t\t\tif (tmp > 10) tmp = 10;\n\t\t\tif (tmp < -10) tmp = -10;\n\t\t}\n\t\tansl = min(ansl, tmp);\n\t\tansr = max(ansr, tmp);\n\t}\n\tint ans = ansr - ansl;\n\t//cout << \"solve1(\" << d << \") = \" << ans << endl;\n\treturn ans;\n}\n\nint solve2(string S, int d){\n\tint p = 0;\n\tint res = 0;\n\tfor (char c : S){\n\t\tp = p * 10 + (c - '0');\n\t\tif (p >= d){\n\t\t\tres = max(res, p);\n\t\t\tp = 0;\n\t\t}\n\t}\n\tint ans = 10;\n\tif (p == 0) ans = res - d;\n\t//cout << \"solve2(\" << d << \") = \" << ans << endl;\n\treturn ans;\n}\n\n\nint main(){\n\tstring S; cin >> S;\n\tint N = S.size();\n\tint ans = 10;\n\tfor (int i = 2; i < N; i++) if (N%i == 0){\n\t\tans = min(ans, solve1(S, i));\n\t}\n\tfor (int i = 1; i < 10; i++){\n\t\tans = min(ans, solve2(S, i));\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}\n\n\n\n\nstruct ios_improve_speed{\n\tios_improve_speed(){\n\t\tios::sync_with_stdio(0);\n\t\tcin.tie(0);\n\t}\n} ios_improve_speed_instance;", "accuracy": 1, "time_ms": 10, "memory_kb": 3624, "score_of_the_acc": -0.0053, "final_rank": 1 }, { "submission_id": "aoj_0374_5028517", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\nusing namespace std;\nstring N;\nint f(int L)\n{\n\tvector<string>A(N.size()/L);\n\tfor(int i=0;i<N.size();i+=L)A[i/L]=N.substr(i,L);\n\tsort(A.begin(),A.end());\n\tint ret=0;\n\tfor(int i=0;i<L;i++)\n\t{\n\t\tret=ret*10+A.back()[i]-A[0][i];\n\t\tif(ret>=10)return ret;\n\t}\n\treturn ret;\n}\nbool dp[1<<17][20][20];\nmain()\n{\n\tcin>>N;\n\tif(N.size()==2)\n\t{\n\t\tcout<<abs(N[0]-N[1])<<endl;\n\t\treturn 0;\n\t}\n\tdp[1][N[0]-'0'][N[0]-'0']=true;\n\tif(N[0]=='1')\n\t{\n\t\tint t=(N[0]-'0')*10+N[1]-'0';\n\t\tdp[2][t][t]=true;\n\t}\n\tfor(int i=1;i<N.size();i++)for(int j=0;j<20;j++)for(int k=j;k<20;k++)if(dp[i][j][k])\n\t{\n\t\tint t=N[i]-'0';\n\t\tdp[i+1][min(j,t)][max(k,t)]=true;\n\t\tif(t==1&&i+1<N.size())\n\t\t{\n\t\t\tt=t*10+N[i+1]-'0';\n\t\t\tdp[i+2][min(j,t)][max(k,t)]=true;\n\t\t}\n\t}\n\tint ans=10;\n\tfor(int j=0;j<20;j++)for(int k=j;k<20;k++)if(dp[N.size()][j][k])ans=min(ans,k-j);\n\tfor(int i=1;i*i<=N.size();i++)if(N.size()%i==0)\n\t{\n\t\tans=min(ans,f(i));\n\t\tif(i>1&&i*i<N.size())ans=min(ans,f(N.size()/i));\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 47480, "score_of_the_acc": -0.5951, "final_rank": 10 }, { "submission_id": "aoj_0374_4987966", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\n#define eb emplace_back\nusing namespace std;\nconst char newl='\\n';\ntemplate<class T>\nusing V=vector<T>;\nstring s;\nint f(int st,int len){\n if(len==1){\n return s[st]-'0';\n }else if(len==2){\n return (s[st+1]-'0')+(s[st]-'0')*10;\n }\n}\nint main(){\n cin>>s;\n int n=s.length();\n V<V<int>> dp(n+1,V<int>(100,1<<30));\n for(int i=0;i<=s[0]-'0';i++){\n dp[0][i]=s[0]-'0';\n }\n if(n>2){\n for(int i=0;i<=f(0,2);i++){\n dp[1][i]=f(0,2);\n }\n }\n for(int i=0;i<=f(1,1);i++){\n dp[1][i]=min(dp[1][i],max(dp[0][i],f(1,1)));\n }\n for(int i=2;i<n;i++){\n for(int j=0;j<=f(i,1);j++){\n dp[i][j]=min(dp[i][j],max(dp[i-1][j],f(i,1)));\n }\n for(int j=0;j<=f(i-1,2);j++){\n dp[i][j]=min(dp[i][j],max(dp[i-2][j],f(i-1,2)));\n }\n }\n int res=1<<30;\n for(int i=0;i<100;i++){\n res=min(res,dp[n-1][i]-i);\n }\n //cout<<res<<newl;\n for(int i=1;i<n;i++){\n if(n%i==0){\n string st=s.substr(0,i-2);\n bool fl=true;\n int mi=f(i-2,2),ma=f(i-2,2);\n for(int j=0;j<n;j+=i){\n if(st!=s.substr(j,i-2)){\n fl=false;\n break;\n }\n mi=min(mi,f(j+i-2,2));\n ma=max(ma,f(j+i-2,2));\n }\n if(fl){\n res=min(res,ma-mi);\n }\n }\n }\n cout<<res<<newl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 46284, "score_of_the_acc": -0.5805, "final_rank": 9 }, { "submission_id": "aoj_0374_4987545", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,x,y) for(int i=x;i<y;i++)\n#define range(a) (a).begin(),(a).end()\n#define print(A,x,n) rep(i,0,n){cout<<(i ? \" \":\"\")<<A[i]x;}cout<<endl;\n#define pprint(A,y,m,n) rep(j,0,m){print(A[j],y,n);}\nconst long mod=1e9+7;\nconst int siz=1e5;\nconst int inf=1e9;\nint main(){\n\tstring s; cin>>s;\n\tint n = s.size();\n\tint ans = 8;\n\trep(i,2,10){\n\t\tint m = 11;\n\t\tfor(int j = n-1; j >= 0; j--){\n\t\t\tif(s[j] - '0' < i){\n if(j == 0 || s[j-1] - '0' > 1){ m = inf; break; }\n\t\t\t\telse{ m = max(m, s[j] - '0' + 10); j--; }\n\t\t\t}\n\t\t}ans = min(ans, m - i);\n\t}\n\trep(i,1,n){\n\t\tif(n % i != 0) continue;\n\t\tstring a = \"\", b = \"\";\n rep(j,0,i){ a += \"9\"; b += \"1\"; }\n\t\trep(j,0,n/i){\n string t = \"\";\n rep(k,0,i){\n\t\t\t if(a[k] < s[i*j+k] && s[i*j+k] < b[k]) break;\n else t += s[i*j+k];\n }\n if((int)t.size() == i){\n if(t < a) a = t;\n if(b < t) b = t;\n }\n\t\t}\n rep(j,0,i){\n if(a[j] <= b[j]) b[j] = b[j] - a[j] + '0';\n else b[j] = 10*(b[j-1]-'0') + (b[j]-a[j]) + '0';\n }rep(j,0,i){\n if(j == i-1) ans = min(ans, b[j] - '0');\n else if(b[j] > '0') break;\n }\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3340, "score_of_the_acc": -0.0568, "final_rank": 6 }, { "submission_id": "aoj_0374_4987448", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,x,y) for(int i=x;i<y;i++)\n#define range(a) (a).begin(),(a).end()\n#define print(A,x,n) rep(i,0,n){cout<<(i ? \" \":\"\")<<A[i]x;}cout<<endl;\n#define pprint(A,y,m,n) rep(j,0,m){print(A[j],y,n);}\nconst long mod=1e9+7;\nconst int siz=1e5;\nconst int inf=1e9;\nint main(){\n\tstring s; cin>>s;\n\tint n = s.size();\n\tint ans = 8;\n\trep(i,2,10){\n\t\tint m = 11;\n\t\tfor(int j = n-1; j >= 0; j--){\n\t\t\tif(s[j] - '0' < i){\n if(j == 0 || s[j-1] - '0' > 1){ m = inf; break; }\n\t\t\t\telse{ m = max(m, s[j] - '0' + 10); j--; }\n\t\t\t}\n\t\t}ans = min(ans, m - i);\n\t}\n\trep(i,1,n){\n\t\tif(n % i != 0) continue;\n\t\tint t = 0;\n\t\tint a = inf, b = 0;\n\t\trep(j,0,n){\n\t\t\tt = 10 * t + (s[j] - '0');\n\t\t\tif(j % i == i - 1){\n\t\t\t\ta = min(a, t); b = max(b, t);\n\t\t\t\tt = 0;\n\t\t\t}\n\t\t}ans = min(ans, b - a);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 0.275, "time_ms": 20, "memory_kb": 3340, "score_of_the_acc": -0.0128, "final_rank": 19 }, { "submission_id": "aoj_0374_4987412", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,x,y) for(int i=x;i<y;i++)\n#define range(a) (a).begin(),(a).end()\n#define print(A,x,n) rep(i,0,n){cout<<(i ? \" \":\"\")<<A[i]x;}cout<<endl;\n#define pprint(A,y,m,n) rep(j,0,m){print(A[j],y,n);}\nconst long mod=1e9+7;\nconst int siz=1e5;\nconst int inf=1e9;\nint main(){\n\tstring s; cin>>s;\n\tint n = s.size();\n\tint ans = 8;\n\trep(i,2,10){\n\t\tint m = 11;\n\t\tfor(int j = n-1; j > 0; j--){\n\t\t\tif(s[j] - '0' < i){\n\t\t\t\tif(s[j-1] - '0' > 1){ m = inf; break; }\n\t\t\t\telse{ m = max(m, s[j] - '0' + 10); j--; }\n\t\t\t}\n\t\t}ans = min(ans, m - i);\n\t}\n\trep(i,1,n){\n\t\tif(n % i != 0) continue;\n\t\tint t = 0;\n\t\tint a = inf, b = 0;\n\t\trep(j,0,n){\n\t\t\tt = 10 * t + (s[j] - '0');\n\t\t\tif(j % i == i - 1){\n\t\t\t\ta = min(a, t); b = max(b, t);\n\t\t\t\tt = 0;\n\t\t\t}\n\t\t}ans = min(ans, b - a);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 0.275, "time_ms": 20, "memory_kb": 3192, "score_of_the_acc": -0.011, "final_rank": 18 }, { "submission_id": "aoj_0374_4981047", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int>\n#define vvel V<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define sor(s) sort(s.begin(),s.end())\nsigned main() {\n\tstring s; cin >> s;\n\tint sz = s.size();\n\tif (sz == 2) {\n\t\tsor(s);\n\t\tcout << s[1] - s[0] << endl; return 0;\n\t}\n\tint ans = 100;\n\tfor (int i = 2; i < sz; i++) {\n\t\tif (sz % i == 0) {\n\t\t\tstring mxs = s.substr(0, i);\n\t\t\tstring mns = mxs;\n\t\t\tfor (int j = 0; j < sz / i; j++) {\n\t\t\t\tmmax(mxs, s.substr(j * i, i));\n\t\t\t\tmmin(mns, s.substr(j * i, i));\n\t\t\t}\n\t\t\tif (mxs.substr(0, i - 2) == mns.substr(0, i - 2)) {\n\t\t\t\tint mxn = mxs[i - 2] * 10 + mxs[i - 1];\n\t\t\t\tint mnn = mns[i - 2] * 10 + mns[i - 1];\n\t\t\t\tmmin(ans, mxn - mnn);\n\t\t\t}\n\t\t}\n\t}\n\tint mx = 0;\n\tint mn = 100;\n\tint pot = 0;\n\twhile (pot < sz) {\n\t\tint nval;\n\t\tif (s[pot] == '1' && pot + 2 <= sz) {\n\t\t\tnval = (s[pot] - '0') * 10 + (s[pot + 1] - '0');\n\t\t\tpot += 2;\n\t\t}\n\t\telse {\n\t\t\tnval = (s[pot] - '0');\n\t\t\tpot++;\n\t\t}\n\t\tmmin(mn, nval);\n\t\tmmax(mx, nval);\n\t}\n\tmmin(ans, mx - mn);\n\tsor(s);\n\tmmin(ans, (int)(s[sz-1]-'0') - (s[0]-'0'));\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3300, "score_of_the_acc": -0.0123, "final_rank": 3 } ]
aoj_0373_cpp
Checkered Pattern You have a cross-section paper with W x H squares, and each of them is painted either in white or black. You want to re-arrange the squares into a neat checkered pattern, in which black and white squares are arranged alternately both in horizontal and vertical directions (the figure shown below is a checkered patter with W = 5 and H = 5 ). To achieve this goal, you can perform the following two operations as many times you like in an arbitrary sequence: swapping of two arbitrarily chosen columns, and swapping of two arbitrarily chosen rows. Create a program to determine, starting from the given cross-section paper, if you can re-arrange them into a checkered pattern. Input The input is given in the following format. W H c 1,1 c 1,2 ... c 1,W c 2,1 c 2,2 ... c 2,W : c H,1 c H,2 ... c H,W The first line provides the number of squares in horizontal direction W (2≤ W ≤1000) and those in vertical direction H (2≤ H ≤1000). Each of subsequent H lines provides an array of W integers c i,j corresponding to a square of i -th row and j -th column. The color of the square is white if c i,j is 0, and black if it is 1. Output Output "yes" if the goal is achievable and "no" otherwise. Sample Input 1 3 2 1 1 0 0 0 1 Sample Output 1 yes Sample Input 2 2 2 0 0 1 1 Sample Output 2 no
[ { "submission_id": "aoj_0373_11022526", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <map>\n#include <algorithm>\n#include <iomanip>\n#include <numeric>\n#include <queue>\n#include <stack>\nusing namespace std;\nusing ll = long long;\nint main() {\n\tint W, H;cin >> W >> H;\n\tset<string> st;\n\tmap<string, int> cnt;\n\tfor (int i = 0;i < H;i++) {\n\t\tstring s = \"\";\n\t\tfor (int j = 0;j < W;j++) {\n\t\t\tchar c;cin >> c;\n\t\t\ts += c;\n\t\t}\n\t\tst.insert(s);\n\t\tcnt[s]++;\n\t}\t\n\tif (st.size() != 2) {\n\t\tcout << \"no\" << endl;\n\t\treturn 0;\n\t}\n\tstring a = *st.begin();\n\tstring b = *st.rbegin();\n\tif (abs(cnt[a]-cnt[b]) > 1) {\n\t\tcout << \"no\" << endl;\n\t\treturn 0;\n\t}\n\tint da = 0;int db = 0;\n\tfor (int i = 0;i < W;i++) {\n\t\tif (a[i] == b[i]) {\n\t\t\tcout << \"no\" << endl;\n\t\t\treturn 0;\n\t\t}\n\t\tda += (a[i] == '1' ? 1 : -1);\n\t\tdb += (b[i] == '1' ? 1 : -1);\t\n\t}\n\tif (abs(da) <= 1 and abs(db) <= 1) {\n\t\tcout << \"yes\" << endl;\n\t} else {\n\t\tcout << \"no\" << endl;\n\t}\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5632, "score_of_the_acc": -0.1613, "final_rank": 2 }, { "submission_id": "aoj_0373_10907623", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, l, n) for(int i = int(l); i < int(n); i++)\n#define ll long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate<class T> bool chmin(T &a, T b) {if(a > b) {a = b; return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a < b) {a = b; return true;} return false;}\ntemplate<class T> using spq = priority_queue<T, vector<T>, greater<T>>;\n\n// bool -> Yes/No\nstring answer(bool b) {return b ? \"Yes\" : \"No\";}\n\nvoid fix(int k) {cout << fixed << setprecision(k);}\n\nconst int inf = 2e9;\nconst long long INF = 2e18;\nconst long double eps = 1e-12;\nconst long double pi = 3.14159265358979323846264338;\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};\n\nvoid f() {\n cout << \"no\\n\";\n exit(0);\n}\n\nvoid main_program() {\n int w, h; cin >> w >> h;\n string s[h];\n rep(i, 0, h) {\n int cnt[2];\n cnt[0] = cnt[1] = 0;\n string t;\n rep(j, 0, w) {\n int c; cin >> c;\n cnt[c]++;\n t += (char)('0' + c);\n }\n if(abs(cnt[0] - cnt[1]) > 1) f();\n s[i] = t;\n }\n sort(s, s + h);\n int c = 0;\n rep(i, 0, h - 1) {\n if(s[i] != s[i + 1]) {\n if(c) f();\n c++;\n }\n }\n rep(i, 0, w) if(s[0][i] == s[h - 1][i]) f();\n cout << \"yes\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int T = 1;\n //cin >> T;\n while(T--) {\n main_program();\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4092, "score_of_the_acc": -0.04, "final_rank": 1 }, { "submission_id": "aoj_0373_8300828", "code_snippet": "#include <cmath>\n#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\tint H, W;\n\tcin >> W >> H;\n\tvector<vector<int> > S(H, vector<int>(W));\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tcin >> S[i][j];\n\t\t}\n\t}\n\tsort(S.begin(), S.end());\n\tvector<vector<int> > T = S;\n\tT.erase(unique(T.begin(), T.end()), T.end());\n\tif (T.size() != 2) {\n\t\tcout << \"no\" << endl;\n\t}\n\telse {\n\t\tint c0 = 0, c1 = 0;\n\t\tfor (int i = 0; i < H; i++) {\n\t\t\tif (S[i] == T[0]) {\n\t\t\t\tc0 += 1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tc1 += 1;\n\t\t\t}\n\t\t}\n\t\tif (abs(c0 - c1) >= 2) {\n\t\t\tcout << \"no\" << endl;\n\t\t}\n\t\telse {\n\t\t\tbool flag = true;\n\t\t\tfor (int i = 0; i < W; i++) {\n\t\t\t\tif (T[0][i] == T[1][i]) {\n\t\t\t\t\tflag = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint d0 = 0, d1 = 0;\n\t\t\tfor (int i = 0; i < W; i++) {\n\t\t\t\tif (T[0][i] == 1) {\n\t\t\t\t\td0 += 1;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\td1 += 1;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (abs(d0 - d1) >= 2) {\n\t\t\t\tflag = false;\n\t\t\t}\n\t\t\tcout << (flag ? \"yes\" : \"no\") << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 11240, "score_of_the_acc": -0.9362, "final_rank": 12 }, { "submission_id": "aoj_0373_8257265", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int x,y;\n cin>>x>>y;\n vector<vector<int> > masu(x,vector<int> (y));\n vector<vector<int> > masu2(x,vector<int> (y));\n vector<vector<int> > sample(x,vector<int> (y));\n vector<vector<int> > sample2(x,vector<int> (y));\n vector<int> tate(x);\n vector<int> yoko(y);\n for(int i=0;i<x;i+=1){\n tate.at(i)=0;\n }\n for(int i=0;i<y;i+=1){\n yoko.at(i)=0;\n }\n for(int j=0;j<y;j+=1){\n for(int i=0;i<x;i+=1){\n cin>>masu.at(i).at(j);\n if(masu.at(i).at(j)==1){\n tate.at(i)+=1;\n yoko.at(j)+=1;\n }\n }\n }\n for(int i=0;i<x;i+=1){\n for(int j=0;j<y;j+=1){\n int r=0;\n if(masu.at(i).at(j)==1){\n r+=(tate.at(i)-1)*10000+yoko.at(j)-1;\n r*=-1;\n r-=1;\n }else{\n r+=tate.at(i)*10000+yoko.at(j);\n }\n masu2.at(i).at(j)=r;\n if((i+j)%2==1){\n sample.at(i).at(j)=-(((y+(i%2))/2-1)*10000+(x+(j%2))/2-1)-1;\n sample2.at(i).at(j)=((y+((i+1)%2))/2)*10000+(x+((j+1)%2))/2;\n }else{\n sample.at(i).at(j)=(((y+(i%2))/2)*10000+(x+(j%2))/2);\n sample2.at(i).at(j)=-(((y+((i+1)%2))/2-1)*10000+(x+((j+1)%2))/2-1)-1;\n }\n }\n }\n for(int j=0;j<x;j+=1){\n sort(masu2.at(j).begin(),masu2.at(j).end());\n }\n sort(masu2.begin(),masu2.end());\n for(int j=0;j<x;j+=1){\n sort(sample.at(j).begin(),sample.at(j).end());\n }\n sort(sample.begin(),sample.end());\n for(int j=0;j<x;j+=1){\n sort(sample2.at(j).begin(),sample2.at(j).end());\n }\n sort(sample2.begin(),sample2.end());\n int ans=1,ans2=1;\n for(int i=0;i<x;i+=1){\n for(int j=0;j<y;j+=1){\n if(masu2.at(i).at(j)!=sample.at(i).at(j)){\n ans=0;\n }\n if(masu2.at(i).at(j)!=sample2.at(i).at(j)){\n ans2=0;\n }\n }\n }\n \n if(ans==1||ans2==1){\n cout<<\"yes\"<<endl;\n }else{\n cout<<\"no\"<<endl;\n }\n}", "accuracy": 0.5555555555555556, "time_ms": 120, "memory_kb": 16244, "score_of_the_acc": -1.7469, "final_rank": 20 }, { "submission_id": "aoj_0373_8257251", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int x,y;\n cin>>x>>y;\n vector<vector<int> > masu(x,vector<int> (y));\n vector<vector<int> > masu2(x,vector<int> (y));\n vector<vector<int> > sample(x,vector<int> (y));\n vector<vector<int> > sample2(x,vector<int> (y));\n vector<int> tate(x);\n vector<int> yoko(y);\n for(int i=0;i<x;i+=1){\n tate.at(i)=0;\n }\n for(int i=0;i<y;i+=1){\n yoko.at(i)=0;\n }\n for(int j=0;j<y;j+=1){\n for(int i=0;i<x;i+=1){\n cin>>masu.at(i).at(j);\n if(masu.at(i).at(j)==1){\n tate.at(i)+=1;\n yoko.at(j)+=1;\n \n }\n }\n }\n for(int i=0;i<x;i+=1){\n for(int j=0;j<y;j+=1){\n int r=0;\n if(masu.at(i).at(j)==1){\n r+=(tate.at(i)-1)*1000+yoko.at(j)-1;\n r*=-1;\n r-=1;\n }else{\n r+=tate.at(i)*1000+yoko.at(j);\n }\n masu2.at(i).at(j)=r;\n if((i+j)%2==1){\n sample.at(i).at(j)=-(((y+(i%2))/2-1)*1000+(x+(j%2))/2-1)-1;\n sample2.at(i).at(j)=((y+((i+1)%2))/2)*1000+(x+((j+1)%2))/2;\n }else{\n sample.at(i).at(j)=(((y+(i%2))/2)*1000+(x+(j%2))/2);\n sample2.at(i).at(j)=-(((y+((i+1)%2))/2-1)*1000+(x+((j+1)%2))/2-1)-1;\n }\n }\n }\n for(int j=0;j<x;j+=1){\n sort(masu2.at(j).begin(),masu2.at(j).end());\n }\n sort(masu2.begin(),masu2.end());\n for(int j=0;j<x;j+=1){\n sort(sample.at(j).begin(),sample.at(j).end());\n }\n sort(sample.begin(),sample.end());\n for(int j=0;j<x;j+=1){\n sort(sample2.at(j).begin(),sample2.at(j).end());\n }\n sort(sample2.begin(),sample2.end());\n int ans=1,ans2=1;\n for(int i=0;i<x;i+=1){\n for(int j=0;j<y;j+=1){\n if(masu2.at(i).at(j)!=sample.at(i).at(j)){\n ans=0;\n }\n if(masu2.at(i).at(j)!=sample2.at(i).at(j)){\n ans2=0;\n }\n }\n }\n \n if(ans==1||ans2==1){\n cout<<\"yes\"<<endl;\n }else{\n cout<<\"no\"<<endl;\n }\n}", "accuracy": 0.5555555555555556, "time_ms": 120, "memory_kb": 16236, "score_of_the_acc": -1.7462, "final_rank": 19 }, { "submission_id": "aoj_0373_7077964", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nint main()\n{\n ll W, H; cin >> W >> H;\n vector<vector<ll>>A(H, vector<ll>(W));\n for (ll i = 0; i < H; i++) {\n for (ll j = 0; j < W; j++) {\n cin >> A[i][j];\n }\n }\n map<string, ll>MAP;\n set<string>S;\n for (ll i = 0; i < H; i++) {\n string T;\n for (ll j = 0; j < W; j++) {\n T.push_back(char(A[i][j] + '0'));\n }\n S.insert(T);\n if (MAP.count(T)) MAP[T]++;\n else MAP[T] = 1;\n }\n if (S.size() != 2) {\n cout << \"no\" << endl;\n return 0;\n }\n if (abs(MAP[*S.begin()] - MAP[*prev(S.end(), 1)]) != H % 2) {\n cout << \"no\" << endl;\n return 0;\n }\n MAP.clear(); S.clear();\n for (ll i = 0; i < W; i++) {\n string T;\n for (ll j = 0; j < H; j++) {\n T.push_back(char(A[j][i] + '0'));\n }\n S.insert(T);\n if (MAP.count(T)) MAP[T]++;\n else MAP[T] = 1;\n }\n if (S.size() != 2) {\n cout << \"no\" << endl;\n return 0;\n }\n if (abs(MAP[*S.begin()] - MAP[*prev(S.end(), 1)]) != W % 2) {\n cout << \"no\" << endl;\n return 0;\n }\n cout << \"yes\" << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 13332, "score_of_the_acc": -1.1009, "final_rank": 14 }, { "submission_id": "aoj_0373_7049661", "code_snippet": "#include\"bits/stdc++.h\"\n#include<random>\nusing namespace std;\ntypedef long long int llint;\ntypedef pair<int, int> pint;\ntypedef pair<llint, llint> pllint;\ntypedef vector<int> vint;\ntypedef vector<llint> vllint;\ntypedef vector<pint> vpint;\ntypedef vector<string> vstring;\ntypedef vector<pair<llint, llint>> vpllint;\ntypedef vector<vector<int>> vvint;\ntypedef vector<vector<llint>> vvllint;\ntypedef vector<vector<pint>> vvpint;\ntypedef vector<bool> vbool;\ntypedef vector<vbool> vvbool;\ntypedef vector<vpllint> vvpllint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define drep(i,n) for(int i=n-1;0<=i;i--)\n#define yes(ans) if(ans)cout<<\"yes\"<<endl;else cout<<\"no\"<<endl;\n#define Yes(ans) if(ans)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;\n#define YES(ans) if(ans)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;\n#define POSSIBLE(ans) if(ans)cout<<\"POSSIBLE\"<<endl;else cout<<\"IMPOSSIBLE\"<<endl;\n#define Pi 3.1415926535897932384626\n#define mod llint(1e9+7)\n#define mod9 998244353\n#define Inf 2147483647\n#define llInf 9223372036854775807\n#define all(x) x.begin(),x.end()\n#define isin(i,n) (0<=i&&i<n)\n\nint main() {\n\tint w, h;\n\tcin >> w >> h;\n\tvvbool table(h, vbool(w));\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tint x;\n\t\t\tcin >> x;\n\t\t\ttable[i][j] = x == 1;\n\t\t}\n\t}\n\tvint a(h), b(w);\n\trep(i, h)a[i] = i;\n\trep(i, w)b[i] = i;\n\n\tint cnt = 0;\n\tint x, y;\n\trep(i, h) {\n\t\tif (table[a[i]][b[0]]) {\n\t\t\tswap(a[i], a[cnt]);\n\t\t\tcnt++;\n\t\t}\n\t}\n\tif (!(h % 2 == 0 && cnt == h / 2) &&\n\t\t!(h % 2 == 1 && cnt == h / 2 + 1) &&\n\t\t!(h % 2 == 1 && cnt == h / 2)) {\n\t\tcout << \"no\" << endl;\n\t\treturn 0;\n\t}\n\tx = cnt;\n\tcnt = 0;\n\trep(i, w) {\n\t\tif (table[a[0]][b[i]]) {\n\t\t\tswap(b[i], b[cnt]);\n\t\t\tcnt++;\n\t\t}\n\t}\n\tif (!(w % 2 == 0 && cnt == w / 2) &&\n\t\t!(w % 2 == 1 && cnt == w / 2 + 1) &&\n\t\t!(w % 2 == 1 && cnt == w / 2)) {\n\t\tcout << \"no\" << endl;\n\t\treturn 0;\n\t}\n\ty = cnt;\n\trep(i, h)rep(j, w) {\n\t\tif (table[a[i]][b[j]] == (i < x ^ j < y)) {\n\t\t\tcout << \"no\" << endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout << \"yes\" << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3584, "score_of_the_acc": -0.3333, "final_rank": 4 }, { "submission_id": "aoj_0373_6973167", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0373.cc: Checkered Pattern\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_W = 1000;\nconst int MAX_H = 1000;\n\n/* typedef */\n\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\n\n/* global variables */\n\nint cs[MAX_H][MAX_W];\nint hs[MAX_H], vs[MAX_W];\n\n/* subroutines */\n\nint vsum(vi &v) {\n int sum = 0;\n for (auto u: v) sum += u;\n return sum;\n}\n\nbool check(vvi &vs) {\n int k = 0, c0 = 0, c1 = 0;\n vi v0, v1;\n for (auto v: vs) {\n if (k == 0) k++, c0++, v0 = v;\n else if (k == 1) {\n if (v0 == v) c0++;\n else k++, c1++, v1 = v;\n }\n else {\n if (v0 == v) c0++;\n else if (v1 == v) c1++;\n else return false;\n }\n }\n if (k != 2 || abs(c1 - c0) > 1) return false;\n\n int w = v0.size();\n int s0 = vsum(v0), s1 = vsum(v1);\n if (! (w & 1)) return (s0 == w / 2 && s1 == w / 2);\n\n int w0 = (w + 1) / 2, w1 = w - w0;\n return ((s0 == w0 && s1 == w1) || (s0 == w1 && s1 == w0));\n}\n\n/* main */\n\nint main() {\n int w, h;\n scanf(\"%d%d\", &w, &h);\n\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) scanf(\"%d\", cs[i] + j);\n\n vvi vs(h, vi(w));\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) vs[i][j] = cs[i][j];\n if (! check(vs)) { puts(\"no\"); return 0; }\n\n vs.assign(w, vi(h));\n for (int j = 0; j < w; j++)\n for (int i = 0; i < h; i++) vs[j][i] = cs[i][j];\n if (! check(vs)) { puts(\"no\"); return 0; }\n\n puts(\"yes\");\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 12492, "score_of_the_acc": -0.7014, "final_rank": 8 }, { "submission_id": "aoj_0373_6038803", "code_snippet": "#ifdef LOGX\n#define _GLIBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\n\n/*---------macro---------*/\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = s; i < (int)(n); i++)\n#define unless(x) if(!(x))\n#define until(x) while(!(x))\n#define ALL(a) a.begin(),a.end()\n#define RALL(a) a.rbegin(),a.rend()\n#define mybit(i,j) (((i)>>(j))&1)\n\n/*---------type/const---------*/\nconst int big=1000000007;\n//const int big=998244353;\nconst double EPS=1e-8; //適宜変える\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef std::string::const_iterator state; //構文解析\nconst int dx[4]={1,0,-1,0};\nconst int dy[4]={0,1,0,-1};\nconst char newl='\\n';\nstruct{\n constexpr operator int(){return -int(1e9)-10;}\n constexpr operator ll(){return -ll(1e18)-10;}\n}neginf;\nstruct{\n constexpr operator int(){return int(1e9)+10;}\n constexpr operator ll(){return ll(1e18)+10;}\n constexpr auto operator -(){return neginf;}\n}inf;\n\n/*---------debug---------*/\n#ifdef LOGX\n#include <template/debug.hpp>\n#else\n#define dbg(...) ;\n#define dbgnewl ;\n#define prt(x) ;\n#define _prt(x) ;\n#endif\n\n/*---------function---------*/\ntemplate<typename T> T max(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=max(ans,elem);}return ans;}\ntemplate<typename T> T min(const std::vector<T> &a){T ans=a[0];for(T elem:a){ans=min(ans,elem);}return ans;}\ntemplate<typename T,typename U> bool chmin(T &a,const U b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T,typename U> bool chmax(T &a,const U b){if(a<b){a=b;return true;}return false;}\nbool valid(int i,int j,int h,int w){return (i>=0 && j>=0 && i<h && j<w);}\ntemplate<class T,class U>T expm(T x,U y,const ll mod=big){T res=1;while(y){if(y&1)(res*=x)%=mod;(x*=x)%=mod;y>>=1;}return res;}\ntemplate<class T,class U>T exp(T x,U y){T res=1;while(y){if(y&1)res*=x;x*=x;y>>=1;}return res;}\n\n\n\nint main(){\n //std::ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n std::cout.precision(10);\n/*------------------------------------*/\n \n int h,w;\n cin >> w >> h;\n vector<vector<int>> g(h,vector<int>(w));\n rep(i,h)rep(j,w)cin >> g[i][j];\n bool ok=true;\n rep(i,h){\n int cnt=0;\n rep(j,w)cnt+=g[i][j]==1;\n ok&=(cnt==w/2 || cnt==(w+1)/2);\n }\n rep(j,w){\n int cnt=0;\n rep(i,h)cnt+=g[i][j]==1;\n ok&=(cnt==h/2 || cnt==(h+1)/2);\n }\n if(!ok){\n cout << \"no\" << newl;\n return 0;\n }\n //一番上の行と同じ形の箇所がh/2 or (h+1)/2 個あり、かつそれと異なる(ちょうど反転になっている)ものが残り全てなら良い)\n int cnt=0;\n int cnt2=0;\n rep(i,h){\n cnt+=g[i]==g[0];\n bool now=true;\n rep(j,w)now&=(g[i][j]==!g[0][j]);\n cnt2+=now;\n }\n cout << ((cnt==h/2 || cnt==(h+1)/2) && cnt+cnt2==h ? \"yes\":\"no\") << newl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7296, "score_of_the_acc": -0.6256, "final_rank": 6 }, { "submission_id": "aoj_0373_5982501", "code_snippet": "//#pragma GCC target(\"avx512f,avx512dq,avx512cd,avx512bw,avx512vl\")\n//#pragma GCC target(\"arch=skylake-avx512\")\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define LL long long\n#define DB double\n#define LD long double\n#define ST string\n#define BS bitset\n#define PA pair<LL,LL>\n#define VE vector\n#define VL VE<LL>\n#define VS VE<ST>\n#define VP VE<PA>\n#define VVL VE<VL>\n#define VVVL VE<VVL>\n#define PQ priority_queue\n#define PQS priority_queue<LL,vector<LL>,greater<LL>>\n#define FI first\n#define SE second\n#define PB push_back\n#define POB pop_back\n#define PF push_front\n#define POF pop_front\n#define MP make_pair\n#define TS to_string\n#define TU to_ullong\n#define BPL __builtin_popcountll\n#define rep1(i,a,b,c) for(int i=a;i<b;i+=c)\n#define rep2(i,a,b) rep1(i,a,b,1)\n#define rep3(i,a) rep2(i,0,a)\n#define rep4(a) rep3(i,a)\n#define repr1(i,a,b,c) for(int i=b-1;i>=a;i-=c)\n#define repr2(i,a,b) repr1(i,a,b,1)\n#define repr3(i,a) repr2(i,0,a)\n#define repr4(a) repr3(i,a)\n#define overload4(a,b,c,d,e,...) e\n#define rep(...) overload4(__VA_ARGS__,rep1,rep2,rep3,rep4)(__VA_ARGS__)\n#define repr(...) overload4(__VA_ARGS__,repr1,repr2,repr3,repr4)(__VA_ARGS__)\n#define ALL(a) a.begin(),a.end()\n#define RALL(a) a.rbegin(),a.rend()\n#define SORT(a) sort(ALL(a))\n#define REV(a) reverse(ALL(a))\n#define UB(a,n) *upper_bound(ALL(a),n)\n#define UBn(a,n) upper_bound(ALL(a),n)-a.begin()\n#define LB(a,n) *lower_bound(ALL(a),n)\n#define LBn(a,n) lower_bound(ALL(a),n)-a.begin()\n#define INF 1000000000000000003\n#define PI 3.14159265358979323846264338327950288\n//#define MOD 1000000007\n#define MOD 998244353\n#define EPS 1e-10\n#define coutl cout<<fixed<<setprecision(15)\n#define FAST cin.tie(0);ios::sync_with_stdio(false)\n\nvoid Yn(LL a){if(a)cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid YN(LL a){if(a)cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nbool zero(LD d){return d<-EPS||EPS<d;}\nLL pwmn(LL a,LL n){LL ans=1;while(ans<a)ans*=n;return ans;}\nLL dig(LL n){LL ret=0;while(n)n/=10,++ret;return ret;}\nLL GCD(LL a,LL b){LL c=max(a,b);b=a+b-c;a=c;while(c!=0){c=a%b;a=b;b=c;}return a;}\nLL LCM(LL a,LL b){return a*b/GCD(a,b);}\nLL cmod(LL a,LL m){if(a%m<0)return a%m+abs(m);else return a%m;}\nLL cdiv(LL a,LL b){return ((a<0&&b<0)||(a>=0&&b>=0)?a/b:(a-b+1)/b);}\nLL DIV(LL a,LL d,LL m){LL l=m,x=1,y=0,k;while(l){k=d/l;d-=k*l;swap(l,d);x-=k*y;swap(x,y);}return cmod(a*cmod(x,m),m);}\nLL POW(LL a,LL n,LL m){LL ans=1;while(n>0){if(n&1)ans=ans*a%m;a=a*a%m;n>>=1;}return ans;}\nVL fact,finv,inv;\nvoid comi(LL n){fact.resize(max(2LL,n+1));finv.resize(max(2LL,n+1));inv.resize(max(2LL,n+1));fact[0]=fact[1]=1;finv[0]=finv[1]=1;inv[0]=inv[1]=1;rep(i,2,n+1){fact[i]=fact[i-1]*i%MOD;inv[i]=MOD-inv[MOD%i]*(MOD/i)%MOD;finv[i]=finv[i-1]*inv[i]%MOD;}}\nLL com(LL n,LL k){if(n<k||n<0||k<0)return 0;return fact[n]*(finv[k]*finv[n-k]%MOD)%MOD;}\nbool cmps(PA a,PA b){if(a.SE!=b.SE)return a.SE<b.SE;return a.FI<b.FI;}\ntemplate<typename T>bool chmax(T &a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<typename T>bool chmin(T &a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T>void vin(VE<T> &v,LL d=0){for(auto &a:v){cin>>a;a-=d;}}\ntemplate<typename T>void vout(VE<T> &v,LL d=0){rep(v.size()){cout<<v[i]+d;if(i<v.size()-1)cout<<\" \";}cout<<endl;}\ntemplate<typename T>void v2in(VE<VE<T>> &v,LL d=0){for(auto &a:v)for(auto &b:a){cin>>b;b-=d;}}\ntemplate<typename T>void v2out(VE<VE<T>> &v,LL d=0){for(auto a:v)vout(a,d);}\ntemplate<typename T>void vin2(VE<T> &u,VE<T> &v,LL d=0){rep(u.size()){cin>>u[i]>>v[i];u[i]-=d,v[i]-=d;}}\ntemplate<typename T>void vout2(VE<T> &u,VE<T> &v,LL d=0){rep(u.size())cout<<u[i]+d<<\" \"<<v[i]+d<<endl;}\ntemplate<typename T>void pin(VE<pair<T,T>> &p,bool r=0,LL d=0){rep(p.size()){if(r)cin>>p[i].SE>>p[i].FI;else cin>>p[i].FI>>p[i].SE;p[i].FI-=d,p[i].SE-=d;}}\ntemplate<typename T>void pout(VE<pair<T,T>> &p,bool r=0,LL d=0){rep(p.size()){if(r)cout<<p[i].SE+d<<\" \"<<p[i].FI+d<<endl;else cout<<p[i].FI+d<<\" \"<<p[i].SE+d<<endl;}}\ntemplate<typename T>void gin(VE<VE<T>> &g,VE<T> &u,VE<T> &v,bool d=1,LL z=1){rep(u.size()){cin>>u[i]>>v[i];u[i]-=z,v[i]-=z;g[u[i]].PB(v[i]);if(d)g[v[i]].PB(u[i]);}}\ntemplate<typename T>void wgin(VE<VE<pair<T,T>>> &g,VE<T> &u,VE<T> &v,VE<T> &c,bool d=1,LL z=1){rep(u.size()){cin>>u[i]>>v[i]>>c[i];u[i]-=z,v[i]-=z;g[u[i]].PB({v[i],c[i]});if(d)g[v[i]].PB({u[i],c[i]});}}\ntemplate<class... T>constexpr auto MIN(T... a){return min(initializer_list<common_type_t<T...>>{a...});}\ntemplate<class... T>constexpr auto MAX(T... a){return max(initializer_list<common_type_t<T...>>{a...});}\ntemplate<class... T>void input(T&... a){(cin>>...>>a);}\nvoid print(){cout<<endl;}\ntemplate<class T,class... Ts>void print(const T& a,const Ts&... b){cout<<a;(cout<<...<<(cout<<' ',b));cout<<endl;}\n\nint main(){\n\tFAST;\n\tLL W,H;\n\tcin>>W>>H;\n\tVVL c(H,VL(W));\n\tv2in(c);\n\tLL h=0,w=0,f=1;\n\trep(W)if(c[0][i]==1)w++;\n\trep(H)if(c[i][0]==1)h++;\n\tif(W/2==w)f=0;\n\tif(W%2==1&&W/2+1==w)f=0;\n\tif(f){\n\t\tcout<<\"no\"<<endl;\n\t\treturn 0;\n\t}\n\tf=1;\n\tif(H/2==h)f=0;\n\tif(H%2==1&&H/2+1==h)f=0;\n\tif(f){\n\t\tcout<<\"no\"<<endl;\n\t\treturn 0;\n\t}\n\tVVL t(H,VL(W));\n\trep(W)t[0][i]=c[0][i];\n\trep(H)t[i][0]=c[i][0];\n\trep(H-1){\n\t\tif(t[0][0]!=t[i+1][0])rep(j,W-1)t[i+1][j+1]=t[0][j+1]^1;\n\t\telse rep(j,W-1)t[i+1][j+1]=t[0][j+1];\n\t}\n\tif(t==c)cout<<\"yes\"<<endl;\n\telse cout<<\"no\"<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 16284, "score_of_the_acc": -1, "final_rank": 13 }, { "submission_id": "aoj_0373_5852244", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nusing i64 = long long;\nusing u64 = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\n\nlong long sumvec(vector<int> A){\n\tlong long res = 0;\n\tfor (auto a : A) res += a;\n\treturn res;\n}\n\n\nstruct Order{\n\tint l[3], r[3];\n};\n\n\nbool solve(){\n\tint W, H; cin >> W >> H;\n\tvector<vector<int>> A(H, vector<int>(W));\n\trep(y, H) rep(x, W) cin >> A[y][x];\n\tif (sumvec(A[0]) < W / 2 || (W + 1) / 2 < sumvec(A[0])) return false;\n\tfor (int y = H - 1; y >= 0; y--){\n\t\trep(x, W) A[y][x] ^= A[0][x];\n\t}\n\tint C = 0;\n\trep(y, H){\n\t\tint s = sumvec(A[y]);\n\t\tif (s != W && s != 0) return false;\n\t\tC += s / W;\n\t}\n\tif (C < H / 2 || (H + 1) / 2 < C) return false;\n\treturn true;\n}\n\n\nint main(){\n\tif(solve()) cout << \"yes\\n\";\n\telse cout << \"no\\n\";\n\treturn 0;\n}\n\n\n\n\nstruct ios_improve_speed{\n\tios_improve_speed(){\n\t\tios::sync_with_stdio(0);\n\t\tcin.tie(0);\n\t}\n} ios_improve_speed_instance;", "accuracy": 1, "time_ms": 30, "memory_kb": 6880, "score_of_the_acc": -0.2595, "final_rank": 3 }, { "submission_id": "aoj_0373_5028503", "code_snippet": "#include<iostream>\n#include<vector>\n#include<map>\n#include<algorithm>\nusing namespace std;\nint W,H;\nmap<vector<int>,int>mp;\nmain()\n{\n\tcin>>W>>H;\n\tfor(int i=0;i<H;i++)\n\t{\n\t\tvector<int>now(W);\n\t\tfor(int j=0;j<W;j++)cin>>now[j];\n\t\tmp[now]++;\n\t}\n\tauto it=mp.begin();\n\tvector<int>A,B;\n\tint ca,cb;\n\tA=it->first;\n\tca=it->second;\n\tit++;\n\tif(it==mp.end())\n\t{\n\t\tcout<<\"no\"<<endl;\n\t\treturn 0;\n\t}\n\tB=it->first;\n\tcb=it->second;\n\tit++;\n\tbool ok=abs(ca-cb)<=1;\n\tint da=0,db=0;\n\tfor(int i=0;i<W;i++)\n\t{\n\t\tif(A[i]==B[i])ok=false;\n\t\tif(A[i]==1)da++;\n\t\telse db++;\n\t}\n\tok=ok&&abs(da-db)<=1;\n\tif(it!=mp.end()||!ok)\n\t{\n\t\tcout<<\"no\"<<endl;\n\t}\n\telse\n\t{\n\t\tcout<<\"yes\"<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 7160, "score_of_the_acc": -0.8649, "final_rank": 10 }, { "submission_id": "aoj_0373_4987926", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\n#define eb emplace_back\nusing namespace std;\nconst char newl='\\n';\ntemplate<class T>\nusing V=vector<T>;\nint main(){\n int w,h;cin>>w>>h;\n V<V<int>> c(h,V<int>(w));\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cin>>c[i][j];\n }\n }\n set<int> v1,v0;\n for(int i=0;i<h;i++){\n if(c[i][0]==1&&v1.empty()){\n for(int j=0;j<w;j++){\n if(c[i][j])v1.insert(j);\n }\n }\n if(c[i][0]==0&&v0.empty()){\n for(int j=0;j<w;j++){\n if(c[i][j])v0.insert(j);\n }\n }\n }\n if(v0.empty()||v1.empty()){\n cout<<\"no\"<<newl;\n return 0;\n }\n int c0=0,c1=0;\n for(int i=0;i<h;i++){\n if(c[i][0]==0){\n c0++;\n }else{\n c1++;\n }\n for(int j=0;j<w;j++){\n if(c[i][0]==0){\n if(v0.count(j)&&c[i][j]==0){\n cout<<\"no\"<<newl;\n return 0;\n }\n if(!v0.count(j)&&c[i][j]){\n cout<<\"no\"<<newl;\n return 0;\n }\n }else{\n if(v1.count(j)&&c[i][j]==0){\n cout<<\"no\"<<newl;\n return 0;\n }\n if(!v1.count(j)&&c[i][j]){\n cout<<\"no\"<<newl;\n return 0;\n }\n }\n }\n }\n for(auto e:v0){\n if(v1.count(e)){\n cout<<\"no\"<<newl;\n return 0;\n }\n }\n if(v0.size()+v1.size()!=w){\n cout<<\"no\"<<newl;\n return 0;\n }\n if(abs(c1-c0)==h%2&&abs((int)v1.size()-(int)v0.size())==w%2){\n cout<<\"yes\"<<newl;\n return 0;\n }\n cout<<\"no\"<<newl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 6964, "score_of_the_acc": -1.2661, "final_rank": 17 }, { "submission_id": "aoj_0373_4983139", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,x,y) for(int i=x;i<y;i++)\n#define range(a) (a).begin(),(a).end()\n#define print(A,x,n) rep(i,0,n){cout<<(i ? \" \":\"\")<<A[i]x;}cout<<endl;\n#define pprint(A,y,m,n) rep(j,0,m){print(A[j],y,n);}\nconst long mod=1e9+7;\nconst int size=1e5;\nconst int inf=1e9;\nint main(){\n\tint W, H; cin>>W>>H;\n\tint c[H][W];\n\trep(i,0,H){\n int sum = 0;\n rep(j,0,W){ cin>>c[i][j]; sum += c[i][j]; }\n if(sum != W/2 && sum != (W+1)/2){ cout<<\"no\"<<endl; return 0; }\n } \n\tint cnt = 0;\n\trep(i,0,H){\n\t\trep(j,0,W){\n\t\t\tif((c[i][j] ^ c[0][j]) != (c[i][0] ^ c[0][0])){ cout<<\"no\"<<endl; return 0; }\n\t\t}\n if(c[i][0] ^ c[0][0]) cnt++;\n\t}\n\tif(cnt == H/2 || cnt == (H+1)/2) cout<<\"yes\"<<endl;\n\telse cout<<\"no\"<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 6380, "score_of_the_acc": -0.7202, "final_rank": 9 }, { "submission_id": "aoj_0373_4980979", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int>\n#define vvel V<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\nsigned main() {\n\tint w, h; cin >> w >> h;\n\tvvel c(h, vel(w));\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tcin >> c[i][j];\n\t\t}\n\t}\n\tint x = c[0][0];\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tc[i][j] ^= x;\n\t\t}\n\t}\n\tint cnth = 0;\n\tint cntw = 0;\n\trep(i, h) { cnth += c[i][0]; }\n\trep(i, w) { cntw += c[0][i]; }\n\tif (abs(h - 2 * cnth) > 1) { cout << \"no\" << endl; return 0; }\n\tif (abs(w - 2 * cntw) > 1) { cout << \"no\" << endl; return 0; }\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif (c[i][j] != (c[i][0] ^ c[0][j])) {\n\t\t\t\tcout << \"no\" << endl; return 0;\n\t\t\t}\n\t\t}\n\t}\n\tcout << \"yes\" << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 10700, "score_of_the_acc": -1.1436, "final_rank": 16 }, { "submission_id": "aoj_0373_4978676", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <string>\n#include <set>\n#include <map>\n#include <random>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define repp(i,n,m) for (int i = m; i < (n); ++i)\n#define repl(i,n) for (long long i = 0; i < (n); ++i)\n#define reppl(i,n,m) for (long long i = m; i < (n); ++i)\n//#define int long long\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing ld = long double;\nusing P = pair<int, int>;\nusing PI = pair<pair<int,int>,int>;\nusing PL = pair<long long, long long>;\nusing PLL = pair<pair<long long, long long>, long long>;\nusing Pxy = pair<long double, long double>;\nusing Tiib = tuple<int, int, bool>;\nconst int INF = 1001001007;\nconst int modd = 1000000007;\nconst long long modl = 1000000007LL;\nconst long long mod = 998244353LL;\nconst ll inf = 1e18;\ntemplate <typename AT>\nvoid printvec(vector<AT> &ar){\n rep(i,ar.size()-1) cout << ar[i] << \" \";\n cout << ar[ar.size()-1] << endl;\n}\ntemplate <typename Q>\nvoid printvvec(vector<vector<Q>> &ar){\n rep(i,ar.size()){\n rep(j,ar[0].size()-1) cout << ar[i][j] << \" \";\n cout << ar[i][ar[0].size()-1] << endl;\n }\n}\ntemplate <typename S>\nbool range(S a, S b, S x){\n return (a <= x && x < b);\n}\n\nvoid yes(){\n cout << \"Yes\" << endl;\n}\n\nvoid no (){\n cout << \"No\" << endl;\n}\n\nll cel (ll a, ll b){\n if (a % b == 0) return a / b;\n else return a / b + 1;\n}\n\nll gcds(ll a, ll b){\n ll c = a % b;\n while (c != 0){\n a = b;\n b = c;\n c = a % b;\n }\n return b;\n}\n\nint main(){\n int h, w; cin >> w >> h;\n vector<vector<int>> ar(h,vector<int>(w));\n rep(i,h) rep(j,w) cin >> ar[i][j];\n vector<P> ta(h,P(0,0));\n vector<P> yo(w,P(0,0));\n rep(i,h){\n rep(j,w){\n if (ar[i][j] == 0) ta[i].first++;\n else ta[i].second++;\n }\n }\n rep(i,w){\n rep(j,h){\n if (ar[j][i] == 0) yo[i].first++;\n else yo[i].second++;\n }\n }\n bool t = true;\n if (w % 2 == 0){\n rep(i,h) if (ta[i].first != ta[i].second) t = false;\n }\n else {\n if (h % 2 == 1){\n int ze = 0;\n rep(i,h){\n if (abs(ta[i].first - ta[i].second) != 1) t = false;\n else {\n if (ta[i].first > ta[i].second) ze++;\n }\n }\n if (abs(h - 2*ze) != 1) t = false;\n int zt = 0;\n rep(i,w){\n if (abs(yo[i].first - yo[i].second) != 1) t = false;\n else {\n if (yo[i].first > yo[i].second) zt++;\n }\n }\n if (zt != ze) t = false;\n }\n }\n if (!t) {cout << \"no\" << endl; return 0;}\n bool s = true;\n if (h % 2 == 0){\n rep(i,w) if (yo[i].second != yo[i].first) s = false;\n }\n if (t && s) {\n vector<int> f;\n int ima = 0;\n rep(i,w){\n if (i == w-1 || ar[0][i] != ar[0][i+1]){\n f.emplace_back(ima+1);\n }\n else ima++;\n }\n repp(i,h,1){\n vector<int> g;\n int im = 0;\n rep(j,w){\n if (j == w-1 || ar[i][j] != ar[i][j+1]){\n g.emplace_back(im+1);\n }\n else im++;\n }\n if (f != g) s = false;\n }\n if (s) cout << \"yes\" << endl;\n else cout << \"no\" << endl;\n }\n else cout << \"no\" << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 7324, "score_of_the_acc": -0.6278, "final_rank": 7 }, { "submission_id": "aoj_0373_4978627", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int W, H;\n cin >> W >> H;\n vector<vector<int>> c(H, vector<int>(W));\n for (int i = 0; i < H; i++){\n for (int j = 0; j < W; j++){\n cin >> c[i][j];\n }\n }\n vector<vector<int>> E(H + W);\n for (int i = 0; i < H; i++){\n for (int j = 0; j < W; j++){\n if (c[i][j] == 1){\n E[i].push_back(H + j);\n E[H + j].push_back(i);\n }\n }\n }\n int cnt = 0;\n vector<int> cc(H + W, -1);\n for (int i = 0; i < H + W; i++){\n if (cc[i] == -1){\n cc[i] = cnt;\n queue<int> Q;\n Q.push(i);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : E[v]){\n if (cc[w] == -1){\n cc[w] = cnt;\n Q.push(w);\n }\n }\n }\n cnt++;\n }\n }\n for (int i = 0; i < H; i++){\n for (int j = 0; j < W; j++){\n if ((cc[i] == cc[H + j]) && c[i][j] == 0){\n cout << \"no\" << endl;\n return 0;\n }\n }\n }\n vector<int> row(cnt, 0);\n vector<int> col(cnt, 0);\n for (int i = 0; i < H; i++){\n row[cc[i]]++;\n }\n for (int i = 0; i < W; i++){\n col[cc[H + i]]++;\n }\n if (cnt != 2){\n cout << \"no\" << endl;\n return 0;\n }\n if (row[0] != H / 2 && row[0] != (H + 1) / 2){\n cout << \"no\" << endl;\n } else if (col[0] != W / 2 && col[0] != (W + 1) / 2){\n cout << \"no\" << endl;\n } else {\n cout << \"yes\" << endl;\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 15180, "score_of_the_acc": -1.5797, "final_rank": 18 }, { "submission_id": "aoj_0373_4879571", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int w, h;\n cin >> w >> h;\n vector v(h, vector(w, 0));\n vector<string> ss;\n for (auto &&i : v) {\n string s;\n for (auto &&j : i) scanf(\"%d\", &j), s += '0'+j;\n ss.emplace_back(s);\n }\n string a, b;\n int cnt1 = 0, cnt2 = 0;\n for (auto &&s : ss) {\n if(a.empty()) {\n a = s;\n cnt1++;\n }else if(a == s){\n cnt1++;\n }else if(b.empty()){\n b = s;\n cnt2++;\n }else if(b == s) {\n cnt2++;\n }else {\n puts(\"no\");\n return 0;\n }\n }\n int ccnt = 0;\n if(a.empty() || b.empty()) {\n puts(\"no\");\n return 0;\n }\n for (int i = 0; i < w; ++i) {\n if(a[i]-'0'+b[i]-'0' != 1){\n puts(\"no\");\n return 0;\n } else if(a[i]-'0') ccnt++;\n else ccnt--;\n }\n if(abs(ccnt) <= 1 && abs(cnt1-cnt2) <= 1) puts(\"yes\");\n else puts(\"no\");\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8480, "score_of_the_acc": -0.3855, "final_rank": 5 }, { "submission_id": "aoj_0373_4578239", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define all(a) a.begin(),a.end()\n#define pb emplace_back\n#define eb emplace_back\n#define lb(v,k) (lower_bound(all(v),k)-v.begin())\n#define ub(v,k) (upper_bound(all(v),k)-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define dupli(a) a.erase(unique(all(a)),a.end())\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\ntypedef multiset<ll> S;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=1000000007;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void noyes(T b){if(b)out(\"no\");else out(\"yes\");}\ntemplate<class T> void NoYes(T b){if(b)out(\"No\");else out(\"Yes\");}\ntemplate<class T> void NOYES(T b){if(b)out(\"NO\");else out(\"YES\");}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\nint main(){\n ll n,m;cin>>m>>n;\n vvi v(n,vi(m));\n rep(i,n)rep(j,m)cin>>v[i][j];\n vi a,b;\n rep(i,m){\n if(v[0][i])b.pb(i);\n else a.pb(i);\n }\n if(abs((ll)(a.size())-(ll)(b.size()))>1)dame(\"no\");\n ll c=0,d=0;\n rep(i,n){\n ll k=-1;\n rep(j,m){\n if(v[i][j]==v[0][j]){\n if(k==1)dame(\"no\");\n k=0;\n }\n else{\n if(k==0)dame(\"no\");\n k=1;\n }\n }\n if(k)c++;\n else d++;\n }\n yesno(abs(c-d)<2);\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 10692, "score_of_the_acc": -1.143, "final_rank": 15 }, { "submission_id": "aoj_0373_4171591", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int,P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1<<29;\nconstexpr ll MOD = ll(1e9)+7;\nconstexpr int di[] = {0,1,0,-1};\nconstexpr int dj[] = {1,0,-1,0};\n\n\nint main(){\n int h, w;\n cin >> w >> h;\n vector<vector<int> > a(h, vector<int>(w));\n int cnt = 0;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cin >> a[i][j];\n if(a[i][j]) cnt++;\n else cnt--;\n }\n }\n bool ok = abs(cnt) <= 1;\n for(int i=0;i<h-1;i++){\n for(int j=0;j<w-1;j++){\n int x = 0;\n for(int k=0;k<4;k++){\n x += a[i+k/2][j+k%2];\n }\n if(x&1) ok = false;\n }\n }\n for(int i=0;i<h;i++){\n int x = 0;\n for(int j=0;j<w;j++){\n if(a[i][j]) x++;\n else x--;\n }\n ok &= abs(x) <= 1;\n }\n for(int j=0;j<w;j++){\n int x = 0;\n for(int i=0;i<h;i++){\n if(a[i][j]) x++;\n else x--;\n }\n ok &= abs(x) <= 1;\n }\n cout << (ok ? \"yes\" : \"no\") << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 6792, "score_of_the_acc": -0.9193, "final_rank": 11 } ]
aoj_0376_cpp
Lottery Box A lottery is being held in a corner of the venue of the Aizu festival. Several types of balls are inside the lottery box and each type has its unique integer printed on the surfaces of the balls. An integer T is printed on the lottery box. In the lottery, you first declare two integers A and B , and draw up to M balls from the box. Let the sum of the integers printed on the balls be S . You can get a wonderful gift if the following two criteria are met: S divided by T gives a remainder greater than or equal to A , and S divided by T gives a quotient (fractional portion dropped) greater than or equal to B . Write a program to determine if you have any chance of getting the gift given the following information: the number of ball types, ball-type specific integers, the maximum number of balls to be drawn from the box, the integer printed on the lottery box, and two integers declared before drawing. Assume that each ball type has sufficient (≥M) population in the box. Note also that there may be a chance of getting the gift even without drawing any ball. Input The input is given in the following format. N M T a_1 a_2 : a_N Q A_1 B_1 A_2 B_2 : A_Q B_Q The first line provides the number of ball types N (1≤ N ≤10 5 ), the maximum number of balls you can draw from the box M (1≤ M ≤10 5 ), and the integer printed on the box T (1≤ T ≤1000). Each of the subsequent N lines provides an integer a_i (1≤ a_i ≤10 9 ) printed on the i -th ball type. The next line following these provides the number of declarations Q (1≤ Q ≤10 5 ). Each of the Q lines following this provides a pair of integers A_i (0 ≤ A_i < T ), B_i (0 ≤ B_i ≤ 10 9 ) that constitute the i -th declaration. Output Output a line for each pair of declaration A and B that contains " yes " if there is a chance of getting the gift or " no " otherwise. Sample Input 1 3 2 7 8 3 6 5 2 2 3 2 4 1 6 1 6 0 Sample Output 1 yes no yes no yes
[ { "submission_id": "aoj_0376_10203930", "code_snippet": "// AOJ #376\n// Lottery Box 2025.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(bool yes) { // 整数の表示(出力)\n if (yes) pc('y'), pc('e'), pc('s');\n else pc('n'), pc('o');\n pc('\\n');\n}\n\n\nconst ll NEG_INF = -1000000000000000000LL;\n \nint T_val;\n \n \nvector<ll> convFunc(const vector<ll>& A, const vector<ll>& B) {\n int T = T_val;\n vector<ll> C(T, NEG_INF);\n for (int x = 0; x < T; x++) {\n ll best = NEG_INF;\n for (int k = 0; k <= x; k++) {\n ll aVal = A[k], bVal = B[x - k];\n if(aVal==NEG_INF || bVal==NEG_INF) continue;\n ll cand = aVal + bVal;\n if(cand > best) best = cand;\n }\n for (int k = x+1; k < T; k++) {\n ll aVal = A[k], bVal = B[x + T - k];\n if(aVal==NEG_INF || bVal==NEG_INF) continue;\n ll cand = aVal + bVal + 1;\n if(cand > best) best = cand;\n }\n C[x] = best;\n }\n return C;\n}\n \nint main() {\n int N = Cin();\n ll M = Cin();\n int T = Cin();\n T_val = T;\n vector<ll> bestW(T, NEG_INF);\n for (int i = 0; i < N; i++){\n int a = Cin();\n int r = a % T;\n ll q = a / T;\n bestW[r] = max(bestW[r], q);\n }\n \n vector<ll> baseFunc(T, NEG_INF);\n for (int x = 0; x < T; x++){\n baseFunc[x] = bestW[x];\n }\n \n int maxPow = 0;\n while ((1LL << (maxPow+1)) <= M) maxPow++;\n \n vector< vector<ll> > powFunc(maxPow+1, vector<ll>(T, NEG_INF));\n powFunc[0] = baseFunc;\n for (int i = 1; i <= maxPow; i++){\n powFunc[i] = convFunc(powFunc[i-1], powFunc[i-1]);\n }\n \n vector<ll> dp(T, NEG_INF);\n dp[0] = 0;\n for (int i = 0; i <= maxPow; i++){\n if (M & (1LL << i)) dp = convFunc(dp, powFunc[i]);\n }\n \n vector<ll> tot(T, NEG_INF);\n for (int x = 0; x < T; x++){\n if(dp[x]==NEG_INF) tot[x] = NEG_INF;\n else tot[x] = (ll)T * dp[x] + x;\n }\n \n int Q = Cin();\n for (int i = 0; i < Q; i++){\n int A = Cin(), B = Cin();\n ll threshold = (ll)T * B + A;\n ll best = NEG_INF;\n for (int r = A; r < T; r++){\n best = max(best, tot[r]);\n }\n Cout(best >= threshold);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3552, "score_of_the_acc": -0.2164, "final_rank": 5 }, { "submission_id": "aoj_0376_8297441", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\t// step #1. input\n\tint N, M, T;\n\tcin >> N >> M >> T;\n\tvector<long long> X(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> X[i];\n\t}\n\tint Q;\n\tcin >> Q;\n\tvector<int> A(Q);\n\tvector<long long> B(Q);\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> A[i] >> B[i];\n\t}\n\n\t// step #2. find best\n\tconst long long INF = (3LL << 60);\n\tvector<long long> Z(T, -INF);\n\tfor (int i = 0; i < N; i++) {\n\t\tZ[X[i] % T] = max(Z[X[i] % T], X[i] / T);\n\t}\n\n\t// step #3. dynamic programming\n\tauto merge = [&](const vector<long long>& v1, const vector<long long>& v2) -> vector<long long> {\n\t\tvector<long long> v(T, -INF);\n\t\tfor (int i = 0; i < T; i++) {\n\t\t\tfor (int j = 0; j < T; j++) {\n\t\t\t\tif (v1[i] != -INF && v2[j] != -INF) {\n\t\t\t\t\tif (i + j < T) {\n\t\t\t\t\t\tv[i + j] = max(v[i + j], v1[i] + v2[j]);\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tv[i + j - T] = max(v[i + j - T], v1[i] + v2[j] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn v;\n\t};\n\tvector<long long> cur = Z;\n\tvector<long long> dp(T, -INF);\n\tdp[0] = 0;\n\twhile (M >= 1) {\n\t\tif (M % 2 == 1) {\n\t\t\tdp = merge(dp, cur);\n\t\t}\n\t\tcur = merge(cur, cur);\n\t\tM /= 2;\n\t}\n\n\t// step #4. reform answer\n\tvector<long long> answer = dp;\n\tfor (int i = T - 2; i >= 0; i--) {\n\t\tanswer[i] = max(answer[i], answer[i + 1]);\n\t}\n\t\n\t// step #5. answer queries\n\tfor (int i = 0; i < Q; i++) {\n\t\tcout << (answer[A[i]] >= B[i] ? \"yes\\n\" : \"no\\n\");\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5064, "score_of_the_acc": -1.0517, "final_rank": 18 }, { "submission_id": "aoj_0376_6973746", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0376.cc: Lottery Box\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_T = 1000;\nconst int BN = 17;\n\n/* typedef */\n\ntypedef long long ll;\n\n/* global variables */\n\nint as[MAX_N];\nll bs[BN][MAX_T], mbs[MAX_T], tmp[MAX_T], mxds[MAX_T + 1];\n\n/* subroutines */\n\nvoid setmax(ll &a, ll b) { if (a < b) a = b; }\n\nvoid mulv(int t, const ll a[], const ll b[], ll c[]) {\n fill(c, c + t, -1);\n for (int i = 0; i < t; i++)\n if (a[i] >= 0)\n for (int j = 0; j < t; j++)\n\tif (b[j] >= 0) {\n\t ll q = a[i] + b[j] + (i + j) / t;\n\t int r = (i + j) % t;\n\t setmax(c[r], q);\n\t}\n}\n\n/* main */\n\nint main() {\n int n, m, t;\n scanf(\"%d%d%d\", &n, &m, &t);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n fill(bs[0], bs[0] + t, -1);\n for (int i = 0; i < n; i++) {\n int q = as[i] / t, r = as[i] % t;\n bs[0][r] = max(bs[0][r], (ll)q);\n }\n\n for (int i = 0; i < BN - 1; i++)\n mulv(t, bs[i], bs[i], bs[i + 1]);\n\n fill(mbs, mbs + t, -1);\n mbs[0] = 0;\n\n for (int i = 0, bi = 1; i < BN; i++, bi <<= 1)\n if (m & bi) {\n mulv(t, mbs, bs[i], tmp);\n copy(tmp, tmp + t, mbs);\n }\n\n mxds[t] = -1;\n for (int i = t - 1; i >= 0; i--)\n mxds[i] = max(mxds[i + 1], mbs[i]);\n //for (int i = 0; i < t; i++) printf(\"%lld \", mxds[i]); putchar('\\n');\n\n int qn;\n scanf(\"%d\", &qn);\n\n while (qn--) {\n int a, b;\n scanf(\"%d%d\", &a, &b);\n\n if (mxds[a] >= b) puts(\"yes\");\n else puts(\"no\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3352, "score_of_the_acc": -0.1277, "final_rank": 3 }, { "submission_id": "aoj_0376_5028772", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint N,M,T;\nlong A[17][1000];\nlong dp[1000],tmp[1000];\nmain()\n{\n\tcin>>N>>M>>T;\n\tfor(int i=1;i<T;i++)A[0][i]=-1e18;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint a;cin>>a;\n\t\tA[0][a%T]=max(A[0][a%T],(long)a/T);\n\t}\n\tfor(int i=1;i<17;i++)\n\t{\n\t\tfor(int j=1;j<T;j++)A[i][j]=-1e18;\n\t\tfor(int j=0;j<T;j++)for(int k=0;k<T;k++)\n\t\t{\n\t\t\tA[i][(j+k)%T]=max(A[i][(j+k)%T],A[i-1][j]+A[i-1][k]+(j+k)/T);\n\t\t}\n\t}\n\tfor(int j=1;j<T;j++)dp[j]=-1e18;\n\tfor(int i=0;i<17;i++)if(M>>i&1)\n\t{\n\t\tfor(int j=0;j<T;j++)\n\t\t{\n\t\t\ttmp[j]=dp[j];\n\t\t\tdp[j]=-1e18;\n\t\t}\n\t\tdp[0]=0;\n\t\tfor(int j=0;j<T;j++)for(int k=0;k<T;k++)\n\t\t{\n\t\t\tdp[(j+k)%T]=max(dp[(j+k)%T],A[i][j]+tmp[k]+(j+k)/T);\n\t\t}\n\t}\n\tfor(int j=T-1;j--;)dp[j]=max(dp[j],dp[j+1]);\n\tint Q;cin>>Q;\n\tfor(;Q--;)\n\t{\n\t\tint A,B;cin>>A>>B;\n\t\tcout<<(dp[A]>=B?\"yes\":\"no\")<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3264, "score_of_the_acc": -0.3742, "final_rank": 12 }, { "submission_id": "aoj_0376_4988413", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\n#define eb emplace_back\nusing namespace std;\nconst char newl='\\n';\ntemplate<class T>\nusing V=vector<T>;\nusing ll=long long;\nconst ll inf=1LL<<60;\nint main(){\n ll n,m,t;cin>>n>>m>>t;\n V<ll> a(n),b(t,-inf);\n b[0]=0;\n for(int i=0;i<n;i++){\n cin>>a[i];\n b[a[i]%t]=max(b[a[i]%t],a[i]);\n }\n V<V<ll>> dp(30,V<ll>(t,-inf));\n for(int i=0;i<t;i++){\n dp[0][i]=b[i];\n }\n for(int i=0;i+1<30;i++){\n for(int j=0;j<t;j++){\n for(int k=0;k<t;k++){\n if(dp[i][j]==-inf||dp[i][k]==-inf)continue;\n dp[i+1][(j+k)%t]=max(dp[i+1][(j+k)%t],dp[i][j]+dp[i][k]);\n }\n }\n }\n V<V<ll>> ma(2,V<ll>(t,-inf));\n int pre=0,cur=1;\n ma[pre][0]=0;\n for(int i=29;i>=0;i--){\n if((m>>i)&1){\n for(int j=0;j<t;j++)ma[cur][j]=-inf;\n for(int j=0;j<t;j++){\n if(ma[pre][j]==-inf)continue;\n for(int k=0;k<t;k++){\n if(dp[i][k]==-inf)continue;\n ma[cur][(j+k)%t]=max(ma[cur][(j+k)%t],ma[pre][j]+dp[i][k]);\n }\n }\n swap(pre,cur);\n }\n }\n for(int i=t-2;i>=0;i--){\n ma[pre][i]=max(ma[pre][i+1],ma[pre][i]);\n // cout<<i<<\" \"<<ma[pre][i]<<newl;\n }\n int q;cin>>q;\n while(q--){\n int A,B;cin>>A>>B;\n if(ma[pre][A]>=B*t){\n cout<<\"yes\"<<newl;\n }else{\n cout<<\"no\"<<newl;\n }\n }\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 3844, "score_of_the_acc": -0.9917, "final_rank": 17 }, { "submission_id": "aoj_0376_4981265", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n#define int long long\n#define V vector\n#define vel V<int>\n#define vvel V<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define sor(s) sort(s.begin(),s.end())\nvel mul(vel a, vel b) {\n\tint t = a.size();\n\tvel ans(t, -1);\n\trep(i, t) {\n\t\trep(j, t) {\n\t\t\tif (a[i] >= 0 && b[j] >= 0) {\n\t\t\t\tmmax(ans[(i + j) % t], a[i] + b[j] + ((i + j) / t));\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\nvel rui(int a, vel & nex) {\n\tif (a == 1) { return nex; }\n\tvel ans = rui(a / 2, nex);\n\tans = mul(ans, ans);\n\tif (a % 2 == 1) {\n\t\tans = mul(ans, nex);\n\t}\n\treturn ans;\n}\nsigned main() {\n\tint n, m, t; cin >> n >> m >> t;\n\tvel nex(t, -1); nex[0] = 0;\n\trep(i, n) {\n\t\tint a;\n\t\tcin >> a;\n\t\tmmax(nex[a % t], a / t);\n\t}\n\tvel ans = rui(m, nex);\n\tfor (int i = t - 2; i >= 0; i--) {\n\t\tmmax(ans[i], ans[i + 1]);\n\t}\n\tint q; cin >> q;\n\trep(i, q) {\n\t\tint a, b; cin >> a >> b;\n\t\tif (ans[a] >= b) { cout << \"yes\" << endl; }\n\t\telse { cout << \"no\" << endl; }\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 3196, "score_of_the_acc": -0.4244, "final_rank": 15 }, { "submission_id": "aoj_0376_4978836", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\nconstexpr lint mod = 998244353;\n#define all(x) (x).begin(), (x).end()\n#define bitcount(n) __builtin_popcountl((lint)(n))\n#define fcout cout << fixed << setprecision(15)\n#define highest(x) (63 - __builtin_clzl(x))\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, r) for(int i = int(l); i < int(r); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, r) for(int i = int(r) - 1; i >= int(l); i--)\n\nint main(){\n int N, M, T;\n cin >> N >> M >> T;\n vector<lint> max_by_mod(T, -1);\n max_by_mod[0] = 0;\n rep(i, N){\n lint a;\n cin >> a;\n max_by_mod[a % T] = max(max_by_mod[a % T], a);\n }\n \n lint doubling[20][T];\n rep(i, T){\n doubling[0][i] = max_by_mod[i];\n }\n rep2(i, 1, 20){\n rep(j, T){\n doubling[i][j] = -1;\n rep(k, T){\n if(doubling[i - 1][k] == -1 || doubling[i - 1][(j - k + T) % T] == -1){\n continue;\n }\n doubling[i][j] = max(doubling[i][j], doubling[i - 1][k] + doubling[i - 1][(j - k + T) % T]);\n }\n }\n }\n \n lint doubling_M[21][T]; // あとでTにする\n rep(i, T) doubling_M[20][i] = -1;\n doubling_M[20][0] = 0;\n repr(i, 20){\n rep(j, T){\n if(~(M >> i) & 1){\n doubling_M[i][j] = doubling_M[i + 1][j];\n continue;\n }\n if(i == 0 && j == 3){\n \n }\n doubling_M[i][j] = -1;\n rep(k, T){\n if(doubling_M[i + 1][k] == -1 || doubling[i][(j - k + T) % T] == -1){\n continue;\n }\n doubling_M[i][j] = max(doubling_M[i][j], doubling_M[i + 1][k] + doubling[i][(j - k + T) % T]);\n }\n }\n }\n lint cum_max[T + 1];\n cum_max[T] = -1;\n repr(i, T){\n cum_max[i] = max(cum_max[i + 1], doubling_M[0][i]);\n }\n \n int Q;\n cin >> Q;\n rep(i, Q){\n lint A, B;\n cin >> A >> B;\n if(cum_max[A] >= B * T + A){\n cout << \"yes\" << endl;\n }else{\n cout << \"no\" << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3316, "score_of_the_acc": -0.35, "final_rank": 11 }, { "submission_id": "aoj_0376_4885162", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int n, m, t;\n cin >> n >> m >> t;\n vector<ll> v(t, -INF<ll>);\n v[0] = 0;\n for (int i = 0; i < n; ++i) {\n ll x; scanf(\"%lld\", &x);\n chmax(v[x%t], x/t);\n }\n vector<ll> a(t, -INF<ll>);\n a[0] = 0;\n auto merge = [&](vector<ll> &a, vector<ll> &b){\n vector<ll> ans(t, -INF<ll>);\n for (int i = 0; i < t; ++i) {\n for (int j = 0; j < t; ++j) {\n if(i+j >= t) chmax(ans[i+j-t], a[i]+b[j]+1);\n else chmax(ans[i+j], a[i]+b[j]);\n }\n }\n return ans;\n };\n while(m){\n if(m&1) a = merge(a, v);\n v = merge(v, v);\n m >>= 1;\n }\n for (int i = t-1; i > 0; --i) {\n chmax(a[i-1], a[i]);\n }\n int q;\n cin >> q;\n while(q--){\n int x, y; scanf(\"%d %d\", &x, &y);\n puts(a[x] >= y ? \"yes\" : \"no\");\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3492, "score_of_the_acc": -0.1674, "final_rank": 4 }, { "submission_id": "aoj_0376_4017236", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n\nint main() {\n\tint n, m, t; std::cin >> n >> m >> t;\n\tstd::vector<int> balls(n); for (auto& a : balls) std::cin >> a;\n\tstd::vector<std::vector<long long int>> max_b{ std::vector<long long int>(t, -1) };\n\tfor (const auto a : balls) {\n\t\tmax_b[0][a % t] = std::max(max_b[0][a % t], (long long int)a / t);\n\t}\n\tfor (auto _c = 1; (1 << _c) <= m; ++_c) {\n\t\tstd::vector<long long int> last(t, -1);\n\t\tfor (auto i = 0; i < t; ++i) if (max_b.back()[i] != -1) {\n\t\t\tfor (auto j = 0; j <= i; ++j) if (max_b.back()[j] != -1) {\n\t\t\t\tlast[(i + j) % t] = std::max(last[(i + j) % t], max_b.back()[i] + max_b.back()[j] + (i + j) / t);\n\t\t\t}\n\t\t}\n\t\tmax_b.push_back(std::move(last));\n\t}\n\tauto result = max_b.back();\n\tfor (auto i = 0; i + 1 < max_b.size(); ++i) if ((m & (1 << i)) != 0) {\n\t\tauto last = result;\n\t\tfor (auto j = 0; j < t; ++j) if (max_b[i][j] != -1) {\n\t\t\tfor (auto k = 0; k < t; ++k) if (last[k] != -1) {\n\t\t\t\tresult[(j + k) % t] = std::max(result[(j + k) % t], max_b[i][j] + last[k] + (j + k) / t);\n\t\t\t}\n\t\t}\n\t}\n\tfor (auto i = 2; i <= result.size(); ++i) {\n\t\tresult[result.size() - i] = std::max(result[result.size() - i], result[result.size() - i + 1]);\n\t}\n\tint q; std::cin >> q;\n\tfor (auto i = 0; i < q; ++i) {\n\t\tint a, b; std::cin >> a >> b;\n\t\tstd::cout << (result[a] >= b ? \"yes\\n\" : \"no\\n\");\n\t}\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3316, "score_of_the_acc": -0.3155, "final_rank": 9 }, { "submission_id": "aoj_0376_3956359", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nconstexpr ll INF = INT_MAX;\n\nvoid chmax(ll &a, ll b){\n a = max(a, b);\n}\n\nint main() {\n int N, M, T;\n cin >> N >> M >> T;\n vector<vector<ll> > dp(21,vector<ll>(T,-INF/2)); // dp[i][j] 2^i個以下のボールを使って余りをjにするときの商の最大\n dp[0][0] = 0;\n for(int i=0;i<N;i++){\n ll a;\n cin >> a;\n chmax(dp[0][a%T], a/T);\n }\n // ダブリング\n for(int i=0;i<20;i++){\n for(int j=0;j<T;j++){\n for(int k=j;k<T;k++){\n int l = (j+k)%T, c = (j+k)/T;\n chmax(dp[i+1][l], dp[i][l]);\n if(dp[i][j] >= 0 && dp[i][j] >= 0){\n chmax(dp[i+1][l], dp[i][j]+dp[i][k] + c);\n }\n }\n }\n }\n // dpを元にM個以下のときの最大値を計算\n vector<vector<ll> > ans(2,vector<ll>(T,-INF/2));\n ans[0][0] = 0;\n for(int m=M,i=0;m>0;m>>=1,i++){\n if(m&1){\n for(int j=0;j<T;j++){\n for(int k=0;k<T;k++){\n int l = (j+k)%T, c = (j+k)/T;\n chmax(ans[1][l], ans[0][l]);\n if(ans[0][j] >= 0 && dp[i][k] >= 0){\n chmax(ans[1][l], ans[0][j]+dp[i][k]+c);\n }\n }\n }\n for(int j=0;j<T;j++){\n ans[0][j] = ans[1][j];\n }\n }\n }\n // 累積max\n for(int i=T-2;i>=0;i--){\n chmax(ans[0][i], ans[0][i+1]);\n }\n int Q;\n cin >> Q;\n for(;Q>0;Q--){\n ll a, b;\n cin >> a >> b;\n if(ans[0][a] >= b){\n cout << \"yes\" << endl;\n }\n else{\n cout << \"no\" << endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3248, "score_of_the_acc": -0.2968, "final_rank": 8 }, { "submission_id": "aoj_0376_3956337", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nconstexpr ll INF = INT_MAX;\n\nvoid chmax(ll &a, ll b){\n a = max(a, b);\n}\n\ntemplate <typename Monoid>\nstruct SegmentTree{\nprivate:\n using F = function<Monoid(Monoid, Monoid)>;\n int N;\n vector<Monoid> node;\n F f;\n Monoid e; // identity element\n\npublic:\n SegmentTree(){}\n SegmentTree(F f, Monoid e):f(f), e(e){}\n void init(int sz){\n N = 1;\n while(N < sz) N <<= 1;\n node.assign(2*N-1, e);\n }\n void build(vector<Monoid>& v){\n int sz = int(v.size());\n init(sz);\n for(int i=0; i<sz; i++){\n node[i+N-1] = v[i];\n }\n for(int i=N-2; i>=0; i--){\n node[i] = f(node[i*2+1], node[i*2+2]);\n }\n }\n void update(int k, Monoid x){\n k += N-1;\n node[k] = x;\n while(k > 0){\n k = (k-1)/2;\n node[k] = f(node[2*k+1], node[2*k+2]);\n }\n }\n // [a,b)\n Monoid query(int a, int b){return query(a, b, 0, 0, N);}\n Monoid query(int a, int b, int k, int l, int r){\n if(b <= l || r <= a) return e;\n if(a <= l && r <= b) return node[k];\n Monoid vl, vr;\n vl = query(a, b, 2*k+1, l, (l+r)/2);\n vr = query(a, b, 2*k+2, (l+r)/2, r);\n return f(vl, vr);\n }\n};\n\nauto f = [=](ll a, ll b){return max(a, b);};\nSegmentTree<ll> seg(f,-INF);\n \n\nint main() {\n int N, M, T;\n cin >> N >> M >> T;\n vector<vector<ll> > dp(21,vector<ll>(T,-INF/2)); // dp[i][j] 2^i個以下のボールを使って余りをjにするときの商の最大\n dp[0][0] = 0;\n for(int i=0;i<N;i++){\n ll a;\n cin >> a;\n chmax(dp[0][a%T], a/T);\n }\n for(int i=0;i<20;i++){\n for(int j=0;j<T;j++){\n for(int k=j;k<T;k++){\n int l = (j+k)%T, c = (j+k)/T;\n chmax(dp[i+1][l], dp[i][l]);\n if(dp[i][j] >= 0 && dp[i][j] >= 0){\n chmax(dp[i+1][l], dp[i][j]+dp[i][k] + c);\n }\n }\n }\n }\n vector<vector<ll> > ans(2,vector<ll>(T,-INF/2));\n ans[0][0] = 0;\n for(int m=M,i=0;m>0;m>>=1,i++){\n if(m&1){\n for(int j=0;j<T;j++){\n for(int k=0;k<T;k++){\n int l = (j+k)%T, c = (j+k)/T;\n chmax(ans[1][l], ans[0][l]);\n if(ans[0][j] >= 0 && dp[i][k] >= 0){\n chmax(ans[1][l], ans[0][j]+dp[i][k]+c);\n }\n }\n }\n for(int j=0;j<T;j++){\n ans[0][j] = ans[1][j];\n }\n }\n }\n seg.build(ans[0]);\n int Q;\n cin >> Q;\n for(;Q>0;Q--){\n ll a, b;\n cin >> a >> b;\n if(seg.query(a,T) >= b){\n cout << \"yes\" << endl;\n }\n else{\n cout << \"no\" << endl;\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3280, "score_of_the_acc": -0.3309, "final_rank": 10 }, { "submission_id": "aoj_0376_3945339", "code_snippet": "#include<algorithm>\n#include<bitset>\n#include<cassert>\n#include<cfloat>\n#include<climits>\n#include<cmath>\n#include<deque>\n#include<functional>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<queue>\n#include<set>\n#include<stack>\n#include<string>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = (int)(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = (int)(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = (int)(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = (int)(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = (int)(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define REVERSE(x) reverse((x).begin(), (x).end())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << '\\n'\n#define endl '\\n'\n\nconstexpr int IINF = (1 << 30) - 1;\nconstexpr long long LLINF = 1LL << 61;\nconstexpr double EPS = 1e-10;\n\nconstexpr int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconstexpr int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nbool chmin(T& a, T b){\n if(b < a){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n\n int n, m, t;\n cin >> n >> m >> t;\n\n lint dp1[20][1000];\n fill(dp1[0], dp1[20], -1LL);\n\n lint dp2[1000];\n fill(dp2, dp2 + t, -1LL);\n\n rep(i, n){\n lint a;\n cin >> a;\n chmax(dp1[0][a % t], a);\n }\n\n rep(i, 19){\n rep(j, t){\n chmax(dp1[i + 1][j], dp1[i][j]);\n rep(k, t){\n if(dp1[i][j] >= 0LL && dp1[i][k] >= 0LL){\n chmax(dp1[i + 1][(j + k) % t], dp1[i][j] + dp1[i][k]);\n }\n }\n }\n }\n\n rep(i, 20){\n if(!(m >> i & 1)){\n continue;\n }\n lint dp3[1000];\n rep(j, t){\n dp3[j] = dp2[j];\n }\n rep(j, t){\n chmax(dp3[j], dp1[i][j]);\n rep(k, t){\n if(dp1[i][j] >= 0LL && dp2[k] >= 0LL){\n chmax(dp3[(j + k) % t], dp1[i][j] + dp2[k]);\n }\n }\n }\n rep(j, t){\n dp2[j] = dp3[j];\n }\n }\n\n rrep(j, t - 1){\n chmax(dp2[j], dp2[j + 1]);\n }\n\n int q;\n cin >> q;\n\n while(q--){\n int a, b;\n cin >> a >> b;\n if(dp2[a] >= 0LL && dp2[a] / t >= b){\n cout << \"yes\" << endl;\n }else{\n cout << \"no\" << endl;\n }\n }\n\n cout << flush;\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3284, "score_of_the_acc": -0.1262, "final_rank": 2 }, { "submission_id": "aoj_0376_3921111", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n \nint a[2000];\nll dp[18][2000];\nll DP[2][2000];\nll sum[2000];\n\nint main(){\n int n,m,T;cin>>n>>m>>T;\n memset(a,-1,sizeof(a));\n a[0]=0;\n rep(i,n){\n int b;scanf(\"%d\",&b);\n a[b%T]=max(a[b%T],b);\n }\n memset(dp,-1,sizeof(dp));\n rep(i,T){\n dp[0][i]=a[i];\n }\n rep(i,18){\n rep(j,T){\n if(dp[i][j]==-1)continue; \n rep(k,T){\n if(dp[i][k]==-1)continue;\n dp[i+1][(j+k)%T]=max(dp[i+1][(j+k)%T],dp[i][j]+dp[i][k]);\n }\n }\n }\n memset(DP,-1,sizeof(DP));\n DP[0][0]=0;\n rep(i,18){\n rep(j,T)DP[(i+1)%2][j]=max(DP[(i+1)%2][j],DP[i%2][j]);\n if(!(m>>i&1))continue;\n rep(j,T){\n rep(k,T){\n if(DP[i%2][j]==-1||dp[i][k]==-1)continue;\n DP[(i+1)%2][(j+k)%T]=max(DP[(i+1)%2][(j+k)%T],DP[i%2][j]+dp[i][k]);\n }\n\t\t}\n\t}\n\tsum[T]=-1;\n for(int i=T-1;i>=0;i--){\n sum[i]=max(DP[0][i],sum[i+1]);\n }\n int q;cin>>q;\n rep(i,q){\n int a,b;scanf(\"%d%d\",&a,&b);\n if(sum[a]>=T*(ll)b){\n puts(\"yes\");\n }\n else puts(\"no\");\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3456, "score_of_the_acc": -0.2173, "final_rank": 6 }, { "submission_id": "aoj_0376_3902331", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set>\nusing namespace std;\n//int p = 998244353;\nint p = 1000000007;\n#define int long long\n#define vel vector<long long>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\nint max_kai = 150000;\nvel kai(max_kai, 1);\nvel inv_kai;\nint rui(int a, int n) {\n\tif (n == 0) { return 1; }\n\tint x = rui(a, n / 2);\n\tx *= x; x %= p;\n\tif (n % 2 == 1) { x *= a; x %= p; }\n\treturn x;\n}\nint inv(int a) { return rui(a, p - 2); }\nvoid make_kai() {\n\tfor (int i = 1; i < max_kai; i++) { kai[i] = kai[i - 1] * i; kai[i] %= p; }\n\tinv_kai = kai;\n\trep(i, max_kai) { inv_kai[i] = inv(kai[i]); }\n}\nint nCr(int n, int r) {\n\tint a = kai[n] * inv_kai[r]; a %= p;\n\ta *= inv_kai[n - r]; a %= p;\n\treturn a;\n}\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) {pa[x] = y;}\n}\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)-h.begin()\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)-h.begin()\nint num_lp(int a, vel &nex) {\n\tunordered_set<int> se;\n\tint ans = 0;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {\n\t\t\tbreak;\n\t\t}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t\tans++;\n\t}\n\treturn ans;\n}\nint find_cr(int a, vel &nex) {\n\tunordered_set<int> se;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {break;}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t}\n\treturn num_lp(a, nex);\n}\nint inf = 2000000000;\nvvel dp;\nint solve(vvel &sum, int i, int j, bool is_f) {\n\tint h = sum.size(); h--;\n\tint w = sum[0].size();\n\tif (i == h || j == w) { return 0; }\n\tif (dp[i][j] == inf) {\n\t\tint ans1 = solve(sum, i + 1, j, !is_f);\n\t\tint ans2 = solve(sum, i, j + 1, !is_f);\n\t\tans2 += sum[i][j];\n\t\tif (is_f) {\n\t\t\tdp[i][j] = min(ans1, ans2);\n\t\t}\n\t\telse {\n\t\t\tdp[i][j] = max(ans1, ans2);\n\t\t}\n\t}\n\treturn dp[i][j];\n}\nint rui10(int a) {\n\tif (a == 0) { return 1; }\n\treturn 10 * rui10(a - 1);\n}\nint gcd(int a, int b) {\n\tif (a < b) { swap(a, b); }\n\tif (b == 0) { return a; }\n\treturn gcd(b, a%b);\n}\nvel mul(vel &a, vel &b) {\n\tint n = a.size();\n\tvel c(n,-1);\n\trep(i, n) {\n\t\trep(j, n) {\n\t\t\tif (a[i] >= 0 && b[j] >= 0) {\n\t\t\t\tmmax(c[(i + j) % n], a[i] + b[j]);\n\t\t\t}\n\t\t}\n\t}\n\treturn c;\n}\nvel rui(vel &a, int n) {\n\tif (n == 1) { return a; }\n\tvel b = rui(a, n / 2);\n\tb = mul(b, b);\n\tif (n % 2 == 1) {\n\t\tb = mul(b, a);\n\t}\n\treturn b;\n}\nsigned main(){\n\tint n, m, t; cin >> n >> m >> t;\n\tvel a(t, -1); a[0] = 0;\n\trep(i, n) {\n\t\tint x; cin >> x;\n\t\tmmax(a[x%t], x);\n\t}\n\tvel ans = rui(a, m);\n\tfor (int i = t - 2; i >= 0; i--) {\n\t\tmmax(ans[i], ans[i + 1]);\n\t}\n\tint q; cin >> q;\n\trep(i, q) {\n\t\tint x, y; cin >> x >> y;\n\t\tif (ans[x] >= y * t + x) { cout << \"yes\" << endl; }\n\t\telse { cout << \"no\" << endl; }\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 4184, "score_of_the_acc": -0.9649, "final_rank": 16 }, { "submission_id": "aoj_0376_3902323", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<set>\n#include<queue>\n#include<stack>\n#include<bitset>\n#include<functional>\n#include<map>\n#include<unordered_set>\nusing namespace std;\n//int p = 998244353;\nint p = 1000000007;\n#define vel vector<int>\n#define vvel vector<vel>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define sor(v) sort(v.begin(),v.end())\n#define mmax(a,b) a=max(a,b)\n#define mmin(a,b) a=min(a,b)\n#define mkp make_pair\n#define pin pair<int,int>\n#define qin pair<int,pin>\n#define V vector\n#define Endl endl\n#define veb vector<bool>\n#define rev(s) reverse(s.begin(),s.end())\nint max_kai = 150000;\nvel kai(max_kai, 1);\nvel inv_kai;\nint rui(int a, int n) {\n\tif (n == 0) { return 1; }\n\tint x = rui(a, n / 2);\n\tx *= x; x %= p;\n\tif (n % 2 == 1) { x *= a; x %= p; }\n\treturn x;\n}\nint inv(int a) { return rui(a, p - 2); }\nvoid make_kai() {\n\tfor (int i = 1; i < max_kai; i++) { kai[i] = kai[i - 1] * i; kai[i] %= p; }\n\tinv_kai = kai;\n\trep(i, max_kai) { inv_kai[i] = inv(kai[i]); }\n}\nint nCr(int n, int r) {\n\tint a = kai[n] * inv_kai[r]; a %= p;\n\ta *= inv_kai[n - r]; a %= p;\n\treturn a;\n}\nvel pa;\nint root(int x) {\n\tif (pa[x] == -1) { return x; }\n\tint ans = root(pa[x]); pa[x] = ans;\n\treturn ans;\n}\nvoid marge(int x, int y) {\n\tx = root(x);\n\ty = root(y);\n\tif (x != y) {pa[x] = y;}\n}\n#define lower(h,val) lower_bound(h.begin(),h.end(),val)-h.begin()\n#define upper(h,val) upper_bound(h.begin(),h.end(),val)-h.begin()\nint num_lp(int a, vel &nex) {\n\tunordered_set<int> se;\n\tint ans = 0;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {\n\t\t\tbreak;\n\t\t}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t\tans++;\n\t}\n\treturn ans;\n}\nint find_cr(int a, vel &nex) {\n\tunordered_set<int> se;\n\twhile (true) {\n\t\tif (se.find(a) != se.end()) {break;}\n\t\tse.insert(a);\n\t\ta = nex[a];\n\t}\n\treturn num_lp(a, nex);\n}\nint inf = 2000000000;\nvvel dp;\nint solve(vvel &sum, int i, int j, bool is_f) {\n\tint h = sum.size(); h--;\n\tint w = sum[0].size();\n\tif (i == h || j == w) { return 0; }\n\tif (dp[i][j] == inf) {\n\t\tint ans1 = solve(sum, i + 1, j, !is_f);\n\t\tint ans2 = solve(sum, i, j + 1, !is_f);\n\t\tans2 += sum[i][j];\n\t\tif (is_f) {\n\t\t\tdp[i][j] = min(ans1, ans2);\n\t\t}\n\t\telse {\n\t\t\tdp[i][j] = max(ans1, ans2);\n\t\t}\n\t}\n\treturn dp[i][j];\n}\nint rui10(int a) {\n\tif (a == 0) { return 1; }\n\treturn 10 * rui10(a - 1);\n}\nint gcd(int a, int b) {\n\tif (a < b) { swap(a, b); }\n\tif (b == 0) { return a; }\n\treturn gcd(b, a%b);\n}\nvel mul(vel &a, vel &b) {\n\tint n = a.size();\n\tvel c(n,-1);\n\trep(i, n) {\n\t\trep(j, n) {\n\t\t\tif (a[i] >= 0 && b[j] >= 0) {\n\t\t\t\tmmax(c[(i + j) % n], a[i] + b[j]);\n\t\t\t}\n\t\t}\n\t}\n\treturn c;\n}\nvel rui(vel &a, int n) {\n\tif (n == 1) { return a; }\n\tvel b = rui(a, n / 2);\n\tb = mul (b, b);\n\tif (n % 2 == 1) {\n\t\tb = mul(b, a);\n\t}\n\treturn b;\n}\nsigned main(){\n\tint n, m, t; cin >> n >> m >> t;\n\tvel a(t, -1); a[0] = 0;\n\trep(i, n) {\n\t\tint x; cin >> x;\n\t\tmmax(a[x%t], x);\n\t}\n\tvel ans = rui(a, m);\n\tfor (int i = t - 2; i >= 0; i--) {\n\t\tmmax(ans[i], ans[i + 1]);\n\t}\n\tint q; cin >> q;\n\trep(i, q) {\n\t\tint x, y; cin >> x >> y;\n\t\tif (ans[x] >= y * t + x) { cout << \"yes\" << endl; }\n\t\telse { cout << \"no\" << endl; }\n\t}\n\treturn 0;\n}", "accuracy": 0.375, "time_ms": 130, "memory_kb": 3196, "score_of_the_acc": -0.183, "final_rank": 20 }, { "submission_id": "aoj_0376_3238738", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define DBG(x) ;//cerr<<#x<<\" = \"<<x<<endl\nusing LL = long long;\n\nLL N,M,T;\n\nLL INF = 123456789012345678;\n\nstruct node{\n\tvector<LL>vec;\n\tnode(){\n\t\tvec.resize(T);\n\t}\n\tnode operator + (const node&o){\n\t\tnode x = *this;\n\t\tfor(int i = 0;i < T;++i){\n\t\t\tfor(int j = 0;j < T;++j){\n\t\t\t\tx.vec[(i+j)%T] = max(x.vec[(i+j)%T],\n\t\t\t\tvec[i]+o.vec[j]);\n\t\t\t}\n\t\t}\n\t\treturn x;\n\t}\n};\n\nnode m_pow(const node&e,LL x){\n\tif(x == 1)return e;\n\tnode half = m_pow(e,x/2);\n\thalf = half + half;\n\tif(x % 2)half = half + e;\n\treturn half;\n}\n\nint main(){\n\tcin>>N>>M>>T;\n\tnode e;\n\tfill(e.vec.begin(),e.vec.end(),-INF);\n\te.vec[0] = 0;\n\tfor(int i=0;i<N;++i){\n\t\tLL a;cin>>a;\n\t\te.vec[a%T]=max(a,e.vec[a%T]);\n\t}\n\tauto res = m_pow(e,M);\n\tvector<LL>ans(T+1,-INF);\n\tfor(int i=0;i<T;++i){\n\t\tans[i]=res.vec[i];\n\t}\n\tfor(int i=T-1;i>=0;--i){\n\t\tans[i]=max(ans[i],ans[i+1]);\n\t}\n\tfor(int i=0;i<T;++i){\n\t\tans[i]/=T;\n\t\t//ans[i]++;\n\t\tDBG(ans[i]);\n\t}\n\tint Q;\n\tcin>>Q;\n\tfor(int q=0;q<Q;++q){\n\t\tLL A,B;\n\t\tcin>>A>>B;\n\t\tif(ans[A]>=B){\n\t\t\tcout<<\"yes\"<<endl;\n\t\t}else{\n\t\t\tcout<<\"no\"<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 3180, "score_of_the_acc": -0.4159, "final_rank": 14 }, { "submission_id": "aoj_0376_3238247", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define MAX 100002\n\nint n;\nint m;\n\nint t;\n\nmap<long long int,long long int> mp;\n\nint q;\n\n#define MAX_T 1002\n\nlong long int dp[MAX_T];\nlong long int f[MAX_T];\n\nlong long int tmp[MAX_T];\n\nint main(){\n\tcin>>n>>m>>t;\n\tmp[0]=0;\n\tfor(int i=0;i<n;i++){\n\t\tint a;\n\t\tscanf(\"%d\",&a);\n\t\tif(mp.count(a%t)==0){\n\t\t\tmp[a%t]=0;\n\t\t}\n\t\tmp[a%t]=max(mp[a%t],(long long int)a);\n\t}\n\tfor(int i=0;i<t;i++)dp[i]=LLONG_MIN;\n\tdp[0]=0;\n\tfor(int i=0;i<t;i++){\n\t\tf[i]=LLONG_MIN;\n\t\tif(mp.count(i)){\n\t\t\tf[i]=mp[i];\n\t\t}\n\t}\n\twhile(m){\n\t\tif(m&1){\n\t\t\tfor(int j=0;j<t;j++)tmp[j]=dp[j];\n\t\t\tfor(int j=0;j<t;j++){\n\t\t\tif(dp[j]==LLONG_MIN)continue;\n\t\t\t\tfor(int k=0;k<t;k++){\n\t\t\t\tif(f[k]==LLONG_MIN)continue;\n\t\t\t\t\ttmp[(j+k)%t]=max(tmp[(j+k)%t],dp[j]+f[k]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int j=0;j<t;j++)dp[j]=tmp[j];\n\t\t}\n\t\tfor(int j=0;j<t;j++)tmp[j]=f[j];\n\t\t\tfor(int j=0;j<t;j++){\n\t\t\tif(f[j]==LLONG_MIN)continue;\n\t\t\t\tfor(int k=0;k<t;k++){\n\t\t\t\tif(f[k]==LLONG_MIN)continue;\n\t\t\t\t\ttmp[(j+k)%t]=max(tmp[(j+k)%t],f[j]+f[k]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int j=0;j<t;j++)f[j]=tmp[j];\n\t\tm>>=1;\n\t}\n\tfor(int j=t-2;j>=0;j--){\n\t\tdp[j]=max(dp[j],dp[j+1]);\n\t}\n\tcin>>q;\n\twhile(q--){\n\t\tint a,b;\n\t\tscanf(\"%d%d\",&a,&b);\n\t\tif(dp[a]>=(long long int)(b)*(long long int)(t)){\n\t\t\tputs(\"yes\");\n\t\t}\n\t\telse{\n\t\t\tputs(\"no\");\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3248, "score_of_the_acc": -0.1243, "final_rank": 1 }, { "submission_id": "aoj_0376_3238206", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<cstring>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<set>\n#include<map>\nusing namespace std;\n#define MOD 1000000007\n#define f(i,n) for(long long i=0;i<(long long)(n);i++)\n#define N 100000\n\n\nint main(void){\nlong long n,m;\nlong long t;\nlong long s,tt;\nlong long a[2000][30];\nlong long b[2000];\nlong long b2[2000];\nf(i,2000){\nf(j,30)a[i][j]=-1;\nb[i]=-1;\nb2[i]=-1;\n}\na[0][0]=0;\nlong long x,y,z;\nscanf(\"%lld %lld %lld\",&n,&m,&t);\nf(i,n){\nscanf(\"%lld\",&x);\nif(a[(x%t)][0]<x)a[(x%t)][0]=x;\n}\nf(ii,29){\nf(i,t)a[i][ii+1]=a[i][ii];\nf(i,t){\nf(j,t){\nif(a[i][ii]!=-1&&a[j][ii]!=-1){\ns=(i+j)%t;\nif(a[s][ii+1]<a[i][ii]+a[j][ii])a[s][ii+1]=a[i][ii]+a[j][ii];\n}\n}\n}\n}\ntt=0;\nf(ii,30){\nif(m%2==1){\nif(tt==0){\nf(i,t)b[i]=a[i][ii];\n}\nelse{\nf(i,t)b2[i]=b[i];\nf(i,t){\nf(j,t){\nif(b[i]!=-1&&a[j][ii]!=-1){\ns=(i+j)%t;\nif(b2[s]<b[i]+a[j][ii])b2[s]=b[i]+a[j][ii];\n}\n}\n}\nf(i,t)b[i]=b2[i];\n}\ntt++;\n}\nm=m/2;\n}\nf(i,t)if(b[i]!=-1)b[i]=b[i]/t;\nf(i,t-1)b[t-i-2]=max(b[t-i-2],b[t-i-1]);\nlong long q;\nlong long aa;\nlong long bb;\nscanf(\"%lld\",&q);\nf(i,q){\nscanf(\"%lld %lld\",&aa,&bb);\nif(bb<=b[aa])printf(\"yes\\n\");\nelse printf(\"no\\n\");\n\n}\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3176, "score_of_the_acc": -0.3793, "final_rank": 13 }, { "submission_id": "aoj_0376_3237556", "code_snippet": "#include <bits/stdc++.h>\ntypedef long long i64;\nusing std::cout;\nusing std::endl;\nusing std::cin;\n\nint main() {\n\ti64 n, m, t; cin >> n >> m >> t; std::vector<i64> a(n);\n\tfor(int i = 0; i < n; i++) cin >> a[i];\n\tsort(begin(a), end(a));\n\t\n\tstd::vector<std::vector<i64>> dp(20, std::vector<i64>(t, -(1LL << 60))); dp[0][0] = 0;\n\tfor(int i = 0; i < n; i++) {\n\t\tdp[0][a[i] % t] = std::max(dp[0][a[i] % t], a[i]);\n\t}\n\t\n\tfor(int k = 0; m >> (k + 1); k++) {\n\t\tfor(int i = 0; i < t; i++) {\n\t\t\tfor(int j = 0; j < t; j++) {\n\t\t\t\tdp[k + 1][(i + j) % t] = std::max(dp[k + 1][(i + j) % t], dp[k][i] + dp[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint c = 0;\n\tstd::vector<std::vector<i64>> dp2(2, std::vector<i64>(t, -(1LL << 60))); dp2[0][0] = 0;\n\tfor(int k = 0; m >> k; k++) {\n\t\tif((m >> k & 1) == 0) continue;\n\t\t\n\t\tint cur = c % 2, to = 1 - c % 2; c++;\n\t\tdp2[to] = std::vector<i64>(t, -(1LL << 60)); dp2[0][0] = 0;\n\t\tfor(int i = 0; i < t; i++) {\n\t\t\tfor(int j = 0; j < t; j++) {\n\t\t\t\tdp2[to][(i + j) % t] = std::max(dp2[to][(i + j) % t], dp2[cur][i] + dp[k][j]);\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint q; cin >> q;\n\twhile(q--) {\n\t\tint a, b; cin >> a >> b;\n\t\t\n\t\tbool f = false;\n\t\tfor(int i = a; i < t; i++) f |= b <= dp2[c % 2][i] / t;\n\t\tif(f) cout << \"yes\" << endl;\n\t\telse cout << \"no\" << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 3696, "score_of_the_acc": -1.2754, "final_rank": 19 }, { "submission_id": "aoj_0376_3234593", "code_snippet": "#include<deque>\n#include<queue>\n#include<vector>\n#include<algorithm>\n#include<iostream>\n#include<set>\n#include<cmath>\n#include<tuple>\n#include<string>\n#include<chrono>\n#include<functional>\n#include<iterator>\n#include<random>\n#include<unordered_set>\n#include<array>\n#include<map>\n#include<iomanip>\n#include<assert.h>\n#include<bitset>\n#include<stack>\n#include<memory>\nusing namespace std;\nusing namespace std::chrono;\ntypedef long long int llint;\ntypedef double lldo;\n#define mp make_pair\n#define mt make_tuple\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define pof pop_front\n#define fir first\n#define sec second\n#define res resize\n#define ins insert\n#define era erase\n/*\ncout<<fixed<<setprecision(20);\ncin.tie(0);\nios::sync_with_stdio(false);\n*/\nconst llint mod=998244353;\nconst llint big=2.19e15+1;\nconst long double pai=3.141592653589793238462643383279502884197;\nconst long double eps=1e-15;\ntemplate <class T,class U>bool mineq(T& a,U b){if(a>b){a=b;return true;}return false;}\ntemplate <class T,class U>bool maxeq(T& a,U b){if(a<b){a=b;return true;}return false;}\nllint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}\nllint lcm(llint a,llint b){if(a==0){return b;}return a/gcd(a,b)*b;}\ntemplate<class T> void SO(T& ve){sort(ve.begin(),ve.end());}\ntemplate<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}\ntemplate<class T>llint LBI(vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}\ntemplate<class T>llint UBI(vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}\nvector<int>atu;\nint scan(void){int h,m;cin>>h>>m;atu.pub(h*60+m);return h*60+m;}\nint main(void){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint n,m,T,h,i,j;cin>>n>>m>>T;\n\tllint balls[17][1000];//合計\n\tfor(h=0;h<=16;h++){\n\t\tfor(i=0;i<T;i++){balls[h][i]=-big;}\n\t}\n\tballs[0][0]=0;\n\tfor(i=0;i<n;i++){\n\t\tllint a;cin>>a;\n\t\tmaxeq(balls[0][a%T],a);\n\t}\n\tfor(h=1;h<=16;h++){\n\t\tfor(i=0;i<T;i++){\n\t\t\tfor(j=0;j<T;j++){\n\t\t\t\tmaxeq(balls[h][(i+j)%T],balls[h-1][i]+balls[h-1][j]);\n\t\t\t}\n\t\t}\n\t\t//for(i=0;i<T;i++){cerr<<balls[h][i]<<\" \";}cerr<<endl;\n\t}\n\tllint kei[1000];\n\tfor(i=0;i<T;i++){kei[i]=-mod;}\n\tkei[0]=0;\n\tfor(h=0;h<=16;h++){\n\t\tif(!(m&(1<<h))){continue;}\n\t\tllint ata[1000];\n\t\tfor(i=0;i<T;i++){ata[i]=-mod;}\n\t\tfor(i=0;i<T;i++){\n\t\t\tfor(j=0;j<T;j++){\n\t\t\t\tmaxeq(ata[(i+j)%T],kei[i]+balls[h][j]);\n\t\t\t}\n\t\t}\n\t\tswap(ata,kei);\n\t}\n\tfor(i=T-1;i>0;i--){maxeq(kei[i-1],kei[i]-1);}\n\t\n\tint Q;cin>>Q;\n\twhile(Q--){\n\t\tllint A,B;cin>>A>>B;\n\t\tcout<<(kei[A]>=(B*T+A)?\"yes\":\"no\")<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3316, "score_of_the_acc": -0.2638, "final_rank": 7 } ]
aoj_0377_cpp
Party The students in a class in Akabe high-school define the relation “acquaintance” as: If A and B are friends, then A is acquainted with B. If A and B are friends and B is acquainted with C, then A is acquainted with C. They define the relation “companion” as: Suppose A is acquainted with B, and two classmates who have been friend distance. If A is still acquainted with B, then A and B are companions. A boy PCK joined the class recently and wishes to hold a party inviting his class fellows. He wishes to invite as many boys and girls as possible to the party and has written up an invitation list. In arranging the list, he placed the following conditions based on the acquaintanceship within the class before he joined. When T is in the list: U is listed if he/she is a companion of T. If U is not a companion of T, U is not listed if he/she and T are friends, or he/she and some of T’s companions are friends. PCK made the invitation list so that the maximum number of his classmates is included. Given the number of classmates N and the friendships among them, write a program to estimate the number of boys and girls in the list. All the classmates are identified by an index that ranges from 0 to N -1. Input The input is given in the following format. N M s_1 t_1 s_2 t_2 : s_M t_M The first line provides the number of classmates N (2 ≤ N ≤ 10 5 ) and the number of friendships M (1 ≤ M ≤ 2×10 5 ). Each of the M subsequent lines provides two of the classmates s_i, t_i (0 ≤ s_i,t_i ≤ N -1) indicating they are friends. No duplicate relationship appears among these lines. Output Output the maximum number of classmates PCK invited to the party. Sample Input 1 7 8 0 1 1 2 1 3 2 3 0 4 4 5 4 6 5 6 Sample Output 1 6 Sample Input 2 3 2 0 1 1 2 Sample Output 2 2
[ { "submission_id": "aoj_0377_10205417", "code_snippet": "// AOJ #377\n// Party 2025.2.9\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(ll n) { // 整数の表示(出力)\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n\tpc('\\n');\n}\n\nstruct Edge {\n int to;\n int id;\n};\n \nint timer = 0;\n \nvoid dfs_bridges(int v, int parentEdge, const vector<vector<Edge>> &g, \n vector<int> &tin, vector<int> &low, vector<bool> &visited, \n vector<bool> &isBridge) {\n visited[v] = true;\n tin[v] = low[v] = timer++;\n for(auto &edge : g[v]){\n int to = edge.to, id = edge.id;\n if(id == parentEdge) continue;\n if(!visited[to]){\n dfs_bridges(to, id, g, tin, low, visited, isBridge);\n low[v] = min(low[v], low[to]);\n if(low[to] > tin[v]){\n isBridge[id] = true;\n }\n } else {\n low[v] = min(low[v], tin[to]);\n }\n }\n}\n \nint main() {\n int N = Cin(), M = Cin();\n vector<vector<Edge>> g(N);\n vector<pair<int,int>> edges;\n edges.reserve(M);\n \n for (int i = 0; i < M; i++){\n int u = Cin(), v = Cin();\n edges.push_back({u,v});\n g[u].push_back({v, i});\n g[v].push_back({u, i});\n }\n \n vector<int> tin(N, -1), low(N, -1);\n vector<bool> visited(N, false);\n vector<bool> isBridge(M, false);\n timer = 0;\n for (int i = 0; i < N; i++){\n if(!visited[i])\n dfs_bridges(i, -1, g, tin, low, visited, isBridge);\n }\n \n vector<int> comp(N, -1);\n int compIndex = 0;\n for (int i = 0; i < N; i++){\n if(comp[i] == -1){\n queue<int> q;\n q.push(i);\n comp[i] = compIndex;\n while(!q.empty()){\n int cur = q.front();\n q.pop();\n for(auto &edge : g[cur]){\n if(isBridge[edge.id]) continue;\n int nxt = edge.to;\n if(comp[nxt] == -1){\n comp[nxt] = compIndex;\n q.push(nxt);\n }\n }\n }\n compIndex++;\n }\n }\n \n vector<int> compWeight(compIndex, 0);\n for (int i = 0; i < N; i++){\n compWeight[ comp[i] ]++;\n }\n \n vector<vector<int>> tree(compIndex);\n for (int i = 0; i < M; i++){\n if(isBridge[i]){\n int u = edges[i].first, v = edges[i].second;\n int cu = comp[u], cv = comp[v];\n tree[cu].push_back(cv);\n tree[cv].push_back(cu);\n }\n }\n \n vector<bool> visTree(compIndex, false);\n vector<array<ll,2>> dp(compIndex, {0,0});\n \n function<void(int,int)> dfs_tree = [&](int u, int parent){\n visTree[u] = true;\n dp[u][1] = compWeight[u];\n dp[u][0] = 0;\n for (int v : tree[u]){\n if(v == parent) continue;\n if(!visTree[v]) dfs_tree(v, u);\n dp[u][1] += dp[v][0];\n dp[u][0] += max(dp[v][0], dp[v][1]);\n }\n };\n \n ll ans = 0;\n for (int i = 0; i < compIndex; i++){\n if(!visTree[i]){\n dfs_tree(i, -1);\n ans += max(dp[i][0], dp[i][1]);\n }\n }\n Cout(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 18324, "score_of_the_acc": -0.1179, "final_rank": 1 }, { "submission_id": "aoj_0377_6973842", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0377.cc: Party\n */\n\n#include<cstdio>\n#include<vector>\n#include<stack>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_M = 200000;\n\n/* typedef */\n\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<bool> vb;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vpii;\ntypedef stack<int> si;\n\n/* global variables */\n\npii es[MAX_M];\nvi nbrs[MAX_N], gnbrs[MAX_N];\nint gids[MAX_N], ps[MAX_N], cis[MAX_N], mss[MAX_N][2];\nbool used[MAX_N];\n\n/* subroutines */\n\nvoid bcc_visit(const vi *nbrs, int v, int u, vpii& brdg, vvi& tecomp,\n\t si& roots, si& S, vb& inS, vi& num, int& time) {\n num[v] = ++time;\n S.push(v); inS[v] = true;\n roots.push(v);\n\n const vi& nbrv = nbrs[v];\n for (vi::const_iterator vit = nbrv.begin(); vit != nbrv.end(); vit++) {\n const int& w = *vit;\n if (num[w] == 0)\n bcc_visit(nbrs, w, v, brdg, tecomp, roots, S, inS, num, time);\n else if (u != w && inS[w])\n while (num[roots.top()] > num[w]) roots.pop();\n }\n\n if (v == roots.top()) {\n brdg.push_back(pii(u, v));\n tecomp.push_back(vi());\n for (;;) {\n int w = S.top(); S.pop(); inS[w] = false;\n tecomp.back().push_back(w);\n if (v == w) break;\n }\n roots.pop();\n }\n}\n\nvoid calc_bcc(const int n, const vi *nbrs, vpii& brdg, vvi& tecomp) {\n vi num(n);\n vb inS(n);\n si roots, S;\n int time = 0;\n\n for (int u = 0; u < n; u++)\n if (num[u] == 0) {\n bcc_visit(nbrs, u, n, brdg, tecomp, roots, S, inS, num, time);\n brdg.pop_back();\n }\n}\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n\n for (int i = 0; i < m; i++) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n es[i] = pii(u, v);\n nbrs[u].push_back(v);\n nbrs[v].push_back(u);\n }\n\n vpii brdg;\n vvi tcmp;\n calc_bcc(n, nbrs, brdg, tcmp);\n\n int gn = tcmp.size();\n for (int i = 0; i < gn; i++)\n for (auto u: tcmp[i]) gids[u] = i;\n\n //printf(\"gn=%d\\n\", gn);\n //for (int i = 0; i < gn; i++) printf(\"%d \", (int)tcmp[i].size());\n //putchar('\\n');\n\n for (int i = 0; i < m; i++) {\n int gu = gids[es[i].first], gv = gids[es[i].second];\n if (gu != gv) {\n gnbrs[gu].push_back(gv);\n gnbrs[gv].push_back(gu);\n //printf(\"%d-%d\\n\", gu, gv);\n }\n }\n\n int sum = 0;\n for (int st = 0; st < gn; st++)\n if (! used[st]) {\n ps[st] = -1, used[st] = true;\n \n for (int u = st; u >= 0;) {\n\tvi &gnbru = gnbrs[u];\n\tint up = ps[u];\n\n\tif (cis[u] < gnbru.size()) {\n\t int v = gnbru[cis[u]++];\n\t if (! used[v]) {\n\t ps[v] = u, used[v] = true;\n\t u = v;\n\t }\n\t}\n\telse {\n\t mss[u][1] += tcmp[u].size();\n\n\t if (up >= 0) {\n\t mss[up][0] += max(mss[u][0], mss[u][1]);\n\t mss[up][1] += mss[u][0];\n\t }\n\t \n\t u = up;\n\t}\n }\n\n sum += max(mss[st][0], mss[st][1]);\n }\n\n printf(\"%d\\n\", sum);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 23284, "score_of_the_acc": -0.4139, "final_rank": 5 }, { "submission_id": "aoj_0377_6045308", "code_snippet": "//#pragma GCC target (\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing H = pair<ll, ll>;\nusing P = pair<ll, H>;\nusing vi = vector<ll>;\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define Q(i,j,k) mkp((i),mkp((j),(k)))\n#define rng(i,s,n) for(ll i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define pb emplace_back\n#define siz(a) int((a).size())\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) (lower_bound(all((b)),(i))-(b).begin())\n#define ssp(i,n) (i==(ll)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)((c)-'0')\n#define itoc(c) (char)((c)+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) for(int quetimes_=(n);quetimes_>0;quetimes_--)\n#define gcj printf(\"Case #%lld: \",quetimes_+1)\n#define readv(a,n) (a).resize((n),0);rep(i,(n)) (a)[i]=read()\n#define found(a,x) (a.find(x)!=a.end())\nconstexpr ll mod = (ll)1e9 + 7;\nconstexpr ll Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = (ll)3 * 1e18;\nconstexpr int Inf = 1e9;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(short g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g == 1) u.fs--, u.sc--; if (g == 2) u.fs--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll ppc(ll x) {\n int sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n return sum;\n}\ntemplate<typename T>\nvoid fin(T x) { cout << x << endl; exit(0); }\n\ntemplate<typename T>\nclass csum {\n vec<T> v;\npublic:\n csum(vec<T>& a) :v(a) { build(); }\n csum() {}\n csum(int sz) { init(sz); }\n void init(int sz) { v = vector<T>(sz + 1, 0); }\n void init(vec<T>& a) { v = a; build(); }\n void build() {\n for (int i = 1; i < v.size(); i++) v[i] += v[i - 1];\n }\n void add(int l, int r, T x) {\n v[l] += x;\n v[r] -= x;\n }//[l,r)\n void add(int t, T x) {\n v[t] += x;\n }//[l,r)\n //[l,r]\n T a(int l, int r) {\n if (r < l) return 0;\n return v[r] - (l == 0 ? 0 : v[l - 1]);\n }\n //[l,r)\n T b(int l, int r) {\n return a(l, r - 1);\n }\n T a(pair<int, int>t) {\n return a(t.first, t.second);\n }\n T b(pair<int, int>t) {\n return b(t.first, t.second);\n }\n T operator[](int x)const {\n return v[x];\n }\n};\nclass via {\n using H = pair<ll, ll>;\n bool comp;\npublic:\n vector<H>a;\n via() :comp(true) {}\n via(vector<H>dat) :a(dat), comp(false) { build(); }\n void push(int l, int r) { a.push_back(H{ l,r }); comp = false; }\n void push(H a) { push(a.first, a.second); }\n void build() {\n if (comp) return;\n comp = true;\n sort(a.begin(), a.end());\n int fst = -1; ll lst = -1;\n vector<H>b;\n for (int i = 0; i < a.size(); i++) {\n if (fst < 0) fst = i, lst = a[i].second;\n if (lst < a[i].first) {\n b.push_back(H{ a[fst].first,lst });\n fst = i, lst = a[i].second;\n }\n else if (lst < a[i].second) lst = a[i].second;\n }\n if (~fst) b.push_back(H{ a[fst].first, lst });\n a = b;\n }\n ll size() { return ll(a.size()); }\n ll sum() {\n build();\n ll sum = 0;\n for (auto g : a) sum += g.second - g.first;\n return sum;\n }\n via inter(via& v) {\n build(); v.build();\n via ret;\n for (auto g : a) ret.push(g);\n for (auto g : v.a) ret.push(g);\n ret.build(); return ret;\n }\n via comb(via& v) {\n build(); v.build();\n int s = 0, t = 0;\n via ret;\n while (s < a.size() && t < v.size()) {\n if (v[t].second <= a[s].first) t++;\n else if (a[s].second <= v[t].first) s++;\n else {\n ret.push(max(a[s].first, v[t].first), min(a[s].second, v[t].second));\n if (a[s].second <= v[t].second) s++;\n else t++;\n }\n }\n return ret;\n }\n H& operator[](int t) { return a[t]; }\n};\ntemplate<ll mod>\nclass modint {\npublic:ll v;\n modint(ll v = 0) { s(v % mod + mod); }\n constexpr static int fn_ = (ll)2e6 + 5;\n static vector<modint>fact, comp;\n modint pow(ll x) const {\n modint b(v), c(1);\n while (x) {\n if (x & 1) c *= b;\n b *= b;\n x >>= 1;\n }\n return c;\n }\n inline modint& s(int vv) {\n v = vv < mod ? vv : vv - mod;\n return *this;\n }\n inline modint inv()const { return pow(mod - 2); }\n inline modint operator-()const { return modint() - *this; }\n inline modint& operator+=(const modint b) { return s(v + b.v); }\n inline modint& operator-=(const modint b) { return s(v + mod - b.v); }\n inline modint& operator*=(const modint b) { v = v * b.v % mod; return *this; }\n inline modint& operator/=(const modint b) { v = v * b.inv().v % mod; return *this; }\n inline modint operator+(const modint& b) const { return modint(v) += b; }\n inline modint operator-(const modint& b) const { return modint(v) -= b; }\n inline modint operator*(const modint& b) const { return modint(v) *= b; }\n inline modint operator/(const modint& b) const { return modint(v) /= b; }\n friend ostream& operator<<(ostream& os, const modint& m) {\n return os << m.v;\n }\n friend istream& operator>>(istream& is, modint& m) {\n int x; is >> x; m = modint(x);\n return is;\n }\n bool operator<(const modint& r)const { return v < r.v; }\n bool operator>(const modint& r)const { return v > r.v; }\n bool operator<=(const modint& r)const { return v <= r.v; }\n bool operator>=(const modint& r)const { return v >= r.v; }\n bool operator==(const modint& r)const { return v == r.v; }\n bool operator!=(const modint& r)const { return v != r.v; }\n explicit operator bool()const { return v; }\n explicit operator int()const { return v; }\n modint comb(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n if (k > *this - k) k = *this - k;\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp * comp[k.v];\n }\n return fact[v] * comp[k.v] * comp[v - k.v];\n }//nCk\n modint perm(modint k) {\n if (k > *this) return modint();\n if (fact.empty()) combinit();\n if (v >= fn_) {\n modint tmp(1);\n for (int i = v; i >= v - k.v + 1; i--) tmp *= modint(i);\n return tmp;\n }\n return fact[v] * comp[v - k.v];\n }//nPk\n static void combinit() {\n fact.assign(fn_, modint());\n fact[0] = 1;\n for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * modint(i);\n comp.assign(fn_, modint());\n comp[fn_ - 1] = fact[fn_ - 1].inv();\n for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * modint(i + 1);\n }\n};\nusing mint = modint<ll(1e9 + 7)>; template<>vec<mint> mint::fact = vec<mint>(); template<>vec<mint> mint::comp = vec<mint>();\n//--------------------------------------------------------------\n//--------------------------------------------------------------\nclass unionfind {\n int size = 0, grps = 0;\n vector<int>pa;\npublic:\n unionfind() {}\n unionfind(int n) {\n init(n);\n }\n void init(int n) {\n size = n, grps = n;\n pa.assign(n, -1);\n }\n int root(int x) {\n if (pa[x] < 0) return x;\n return pa[x] = root(pa[x]);\n }\n bool unite(int x, int y) {\n x = root(x); y = root(y);\n if (x == y) return false;\n grps--;\n if (pa[x] > pa[y]) swap(x, y);\n pa[x] += pa[y];\n pa[y] = x;\n return true;\n }\n bool same(int x, int y) {\n return root(x) == root(y);\n }\n bool isroot(int x) {\n return x == root(x);\n }\n int sz(int x) {\n return -pa[root(x)];\n }\n int groups() {\n return grps;\n }\n H operator[](int x) {\n x = root(x);\n return H{ x,-pa[x] };\n }\n};\n\n\nint n, m;\nvec<int>e[200000], f[200000];\nvec<H>edg;\nunionfind uf;\nint dpt[200000];\nint solve(int x, int p, int d) {\n dpt[x] = d;\n int mn = n + 1;\n for (auto g : e[x]) {\n if (g == p) continue;\n if (~dpt[g]) chmin(mn, dpt[g]);\n else chmin(mn, solve(g, x, d + 1));\n }\n if (mn < d) {\n uf.unite(x, p);\n }\n return mn;\n}\n\nint sz[200000];\nint dp[200000][2];\n\nint dfs(int x, int p, int can, int d) {\n if (d > 2e5) {\n return 0;\n }\n if (~dp[x][can]) return dp[x][can];\n int zero = 0, one = 0;\n for (auto g : f[x]) {\n if (g == p) continue;\n zero += dfs(g, x, 1, d + 1);\n one += dfs(g, x, 0, d + 1);\n }\n dp[x][1] = max(zero, one + sz[x]);\n dp[x][0] = zero;\n return dp[x][can];\n}\n\n\nsigned main() {\n mt19937 rnd;\n //while (1) {\n cin >> n >> m;\n //n = rnd() % 100000, m = rnd() % 200000;\n rep(i, n) {\n e[i].clear(), f[i].clear(), sz[i] = 0, dp[i][0] = dp[i][1] = -1;\n }\n edg.clear();\n\n unionfind uf2(n);\n rep(i, m) {\n int u, v; cin >> u >> v;\n //u = rnd() % n, v = rnd() % n; while (u == v) v = rnd() % n;\n e[u].pb(v); e[v].pb(u);\n edg.pb(u, v);\n uf2.unite(u, v);\n }\n uf = unionfind(n);\n\n rep(i, n) dpt[i] = -1;\n rep(i,n) if(uf2.root(i)==i) solve(i, -1, 0);\n vec<int>pos;\n rep(i, n) {\n if (uf.root(i) == i) {\n pos.pb(i);\n sz[i] = uf.sz(i);\n }\n }\n rep(i, m) {\n if (!uf.same(edg[i].fs, edg[i].sc)) {\n f[uf.root(edg[i].fs)].pb(uf.root(edg[i].sc));\n f[uf.root(edg[i].sc)].pb(uf.root(edg[i].fs));\n }\n }\n\n vec<bool>eval(n, 0);\n int ans = 0;\n rep(i, n) {\n if (uf.root(i) == i && !eval[uf2.root(i)]) {\n ans += dfs(i, -1, 1, 0);\n eval[uf2.root(i)] = 1;\n }\n }\n cout << ans << endl;\n \n}", "accuracy": 1, "time_ms": 50, "memory_kb": 23812, "score_of_the_acc": -0.5911, "final_rank": 9 }, { "submission_id": "aoj_0377_5529635", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <iomanip>\n#include <fstream>\n#include <algorithm>\n#include <set>\n#include <queue>\n#include <string>\n#include <map>\n#include <stack>\n#include <climits>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <memory>\n#include <functional>\n#include <cfloat>\n#include <numeric>\n#include <random>\n#include <sstream>\n#include <bitset>\n#include <complex>\n#include <chrono>\n#include <cassert>\n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n\nint main() {\n\tint n, m; std::cin >> n >> m;\n\tstd::vector<std::vector<int>> nodes(n);\n\tfor (auto i = 0; i < m; ++i) {\n\t\tint s, t; std::cin >> s >> t;\n\t\tnodes[s].push_back(t);\n\t\tnodes[t].push_back(s);\n\t}\n\tstd::vector<int> in_time(n, -1), out_time(n, -1), parent(n, -1);\n\tint time{ 0 };\n\tstd::stack<int> stack;\n\tfor (auto i = 0; i < n; ++i) {\n\t\tif (in_time[i] >= 0) continue;\n\t\tstack.push(i);\n\t\twhile (!stack.empty()) {\n\t\t\tconst auto top = stack.top(); stack.pop();\n\t\t\tif (top >= 0) {\n\t\t\t\tif (in_time[top] >= 0) continue;\n\t\t\t\tin_time[top] = time++;\n\t\t\t\tstack.push(-1 - top);\n\t\t\t\tfor (const auto next : nodes[top]) {\n\t\t\t\t\tif (in_time[next] >= 0) continue;\n\t\t\t\t\tstack.push(next);\n\t\t\t\t\tparent[next] = top;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tout_time[-1 - top] = time++;\n\t\t\t}\n\t\t}\n\t}\n\tstd::vector<int> root(n); std::iota(root.begin(), root.end(), 0);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tfor (const auto j : nodes[i]) {\n\t\t\tif (j == parent[i]) continue;\n\t\t\tif (in_time[i] < in_time[j]) continue;\n\t\t\tauto r = j;\n\t\t\twhile (out_time[r] < out_time[i] || root[r] != r) {\n\t\t\t\tif (root[r] != r) {\n\t\t\t\t\tr = root[r];\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tr = parent[r];\n\t\t\t\t}\n\t\t\t}\n\t\t\tauto p = j;\n\t\t\twhile (p != r) {\n\t\t\t\tif (root[p] != p) {\n\t\t\t\t\tconst auto next = root[p];\n\t\t\t\t\troot[p] = r;\n\t\t\t\t\tp = next;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\troot[p] = r;\n\t\t\t\t\tp = parent[p];\n\t\t\t\t}\n\t\t\t}\n\t\t\tp = i;\n\t\t\twhile (p != r) {\n\t\t\t\tif (root[p] != p) {\n\t\t\t\t\tconst auto next = root[p];\n\t\t\t\t\troot[p] = r;\n\t\t\t\t\tp = next;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\troot[p] = r;\n\t\t\t\t\tp = parent[p];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (auto i = 0; i < n; ++i) {\n\t\tif (root[i] != i) {\n\t\t\tauto r = i;\n\t\t\twhile (root[r] != r) {\n\t\t\t\tr = root[r];\n\t\t\t}\n\t\t\tauto p = i;\n\t\t\twhile (root[p] != r) {\n\t\t\t\tconst auto next = root[p];\n\t\t\t\troot[p] = r;\n\t\t\t\tp = next;\n\t\t\t}\n\t\t}\n\t}\n\tstd::vector<std::vector<int>> group(n);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tgroup[root[i]].push_back(i);\n\t}\n\tstd::vector<int> invite(n, 0), not_invite(n, 0), history, roots;\n\tstd::vector<bool> visit(n, false);\n\tfor (auto i = 0; i < n; ++i) {\n\t\tif (visit[root[i]]) continue;\n\t\troots.push_back(i);\n\t\tvisit[root[i]] = true;\n\t\tstack.push(root[i]);\n\t\twhile (!stack.empty()) {\n\t\t\tconst auto top = stack.top(); stack.pop();\n\t\t\thistory.push_back(top);\n\t\t\tfor (const auto s : group[top]) {\n\t\t\t\tfor (const auto next : nodes[s]) {\n\t\t\t\t\tif (visit[root[next]]) continue;\n\t\t\t\t\tvisit[root[next]] = true;\n\t\t\t\t\tstack.push(root[next]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tstd::reverse(history.begin(), history.end());\n\tfor (const auto i : history) {\n\t\tint invite_count = group[i].size(), not_invite_count = 0;\n\t\tfor (const auto s : group[i]) {\n\t\t\tfor (const auto next : nodes[s]) {\n\t\t\t\tif (i == root[next]) continue;\n\t\t\t\tinvite_count += not_invite[next];\n\t\t\t\tnot_invite_count += std::max(not_invite[next], invite[next]);\n\t\t\t}\n\t\t}\n\t\tinvite[i] = invite_count;\n\t\tnot_invite[i] = not_invite_count;\n\t}\n\tint result{ 0 };\n\tfor (const auto r : roots) {\n\t\tresult += std::max(invite[r], not_invite[r]);\n\t}\n\tstd::cout << result << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 16960, "score_of_the_acc": -0.2884, "final_rank": 2 }, { "submission_id": "aoj_0377_5028809", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n#line 1 \"/home/kotatsugame/library/graph/TECC.cpp\"\n//Two Edge Connected Components require bridge\n#line 1 \"/home/kotatsugame/library/graph/bridge.cpp\"\n#include<vector>\n#line 3 \"/home/kotatsugame/library/graph/bridge.cpp\"\nstruct bridge{\n\tint n;\n\tvector<int>ord,low;\n\tvector<bool>art;\n\tvector<vector<int> >G;\n\tbridge(int n_=0):n(n_),ord(n_,-1),low(n_),art(n_,false),G(n_){}\n\tvoid add_edge(int u,int v)\n\t{\n\t\tG[u].push_back(v);\n\t\tG[v].push_back(u);\n\t}\n\tbool operator[](int i)const{return art[i];}\n\tbool is_bridge(int a,int b)const\n\t{\n\t\tif(ord[a]>ord[b])swap(a,b);\n\t\treturn ord[a]<low[b];\n\t}\n\tvoid dfs(int u,int p,int&k)\n\t{\n\t\tlow[u]=ord[u]=k++;\n\t\tbool now=false;\n\t\tint pc=0;\n\t\tfor(int v:G[u])\n\t\t{\n\t\t\tif(ord[v]==-1)\n\t\t\t{\n\t\t\t\tdfs(v,u,k);\n\t\t\t\tlow[u]=min(low[u],low[v]);\n\t\t\t\tnow=now||ord[u]<=low[v];\n\t\t\t}\n\t\t\telse if(v!=p||pc++)\n\t\t\t{\n\t\t\t\tlow[u]=min(low[u],ord[v]);\n\t\t\t}\n\t\t}\n\t\tart[u]=now;\n\t}\n\tvoid build()\n\t{\n\t\tint k=0;\n\t\tfor(int u=0;u<n;u++)if(ord[u]==-1)\n\t\t{\n\t\t\tint cnt=0;\n\t\t\tlow[u]=ord[u]=k++;\n\t\t\tfor(int v:G[u])if(ord[v]==-1)\n\t\t\t{\n\t\t\t\tdfs(v,u,k);\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t\tif(cnt>=2)art[u]=true;\n\t\t}\n\t}\n};\n#line 3 \"/home/kotatsugame/library/graph/TECC.cpp\"\nstruct TECC:bridge{\n\tvector<int>comp;\n\tTECC(int n_=0):bridge(n_),comp(n_,-1){}\n\tint operator[](int i)const{return comp[i];}\n\tvoid dfs(int u,int p,int&k)\n\t{\n\t\tcomp[u]=p==-1||is_bridge(p,u)?k++:comp[p];\n\t\tfor(int v:G[u])if(comp[v]==-1)dfs(v,u,k);\n\t}\n\tint build()\n\t{\n\t\tbridge::build();\n\t\tint k=0;\n\t\tfor(int u=0;u<n;u++)if(comp[u]==-1)dfs(u,-1,k);\n\t\treturn k;\n\t}\n\tint build(vector<vector<int> >&H)\n\t{\n\t\tint k=build();\n\t\tH.assign(k,vector<int>());\n\t\tfor(int u=0;u<n;u++)\n\t\t{\n\t\t\tfor(int v:G[u])if(comp[u]!=comp[v])\n\t\t\t{\n\t\t\t\tH[comp[u]].push_back(comp[v]);\n\t\t\t}\n\t\t}\n\t\treturn k;\n\t}\n};\n#line 5 \"a.cpp\"\nint N,M,K;\nvector<vector<int> >G;\nint cnt[1<<17];\nbool vis[1<<17];\npair<int,int>dfs(int u)\n{\n\tvis[u]=true;\n\tpair<int,int>ret;\n\tret.first=cnt[u];\n\tret.second=0;\n\tfor(int v:G[u])if(!vis[v])\n\t{\n\t\tpair<int,int>q=dfs(v);\n\t\tret.first+=q.second;\n\t\tret.second+=q.first;\n\t}\n\tif(ret.first<ret.second)ret.first=ret.second;\n\treturn ret;\n}\nmain()\n{\n\tcin>>N>>M;\n\tTECC P(N);\n\tfor(int i=0;i<M;i++)\n\t{\n\t\tint u,v;cin>>u>>v;\n\t\tP.add_edge(u,v);\n\t}\n\tK=P.build(G);\n\tfor(int i=0;i<N;i++)cnt[P[i]]++;\n\tint ans=0;\n\tfor(int i=0;i<K;i++)if(!vis[i])\n\t{\n\t\tans+=dfs(i).first;\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15656, "score_of_the_acc": -0.3846, "final_rank": 3 }, { "submission_id": "aoj_0377_4988092", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\n#define eb emplace_back\nusing namespace std;\nconst char newl='\\n';\ntemplate<class T>\nusing V=vector<T>;\nusing P=pair<int,int>;\nusing ll=long long;\nconst ll inf=1LL<<60;\nvoid ok(){\n cout<<\"OK\"<<newl;\n}\nint n,m;\nV<V<int>> G,g;\nV<int> ord,low,vis,cnt;\nint pos;\nvoid dfs(int i,int p){\n vis[i]=1;\n ord[i]=pos;\n pos++;\n low[i]=ord[i];\n bool f=false;\n for(auto &e:G[i]){\n if(vis[e]){\n if(e!=p||f)low[i]=min(low[i],ord[e]);\n if(e==p)f=true;\n continue;\n }\n dfs(e,i);\n low[i]=min(low[i],low[e]);\n }\n}\nvoid bcc(int i,int c){\n vis[i]=1;\n cnt[c]++;\n for(auto &e:G[i]){\n if(vis[e])continue;\n if(ord[i]<low[e]){\n pos++;\n g[c].eb(pos);\n g[pos].eb(c);\n bcc(e,pos);\n }else{\n bcc(e,c);\n }\n }\n}\nV<V<int>> dp;\nvoid calc(int i,int p){\n dp[i][0]=0;\n dp[i][1]=cnt[i];\n int s1=0;\n for(auto &e:g[i]){\n if(e==p)continue;\n calc(e,i);\n dp[i][1]+=dp[e][0];\n dp[i][0]+=max(dp[e][0],dp[e][1]);\n }\n}\nint main(){\n cin>>n>>m;\n G.resize(n);\n g.resize(n);\n ord.resize(n);\n low.resize(n);\n cnt.resize(n);\n vis.resize(n);\n for(int i=0;i<m;i++){\n int s,t;cin>>s>>t;\n G[s].eb(t);\n G[t].eb(s);\n }\n pos=0;\n for(int i=0;i<n;i++){\n if(!vis[i]){\n dfs(i,-1);\n }\n }\n pos=-1;\n vis.assign(n,0);\n for(int i=0;i<n;i++){\n if(!vis[i]){\n pos++;\n bcc(i,pos);\n }\n }\n pos++;\n dp.resize(pos,V<int>(2,-1));\n int res=0;\n for(int i=0;i<pos;i++){\n if(dp[i][0]==-1){\n calc(i,-1);\n res+=max(dp[i][0],dp[i][1]);\n }\n }\n cout<<res<<newl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 21016, "score_of_the_acc": -0.6214, "final_rank": 11 }, { "submission_id": "aoj_0377_4981200", "code_snippet": "#include <set>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, M;\n\tcin >> N >> M;\n\tvector<vector<int> > G(N);\n\tfor (int i = 0; i < M; ++i) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tG[a].push_back(b);\n\t\tG[b].push_back(a);\n\t}\n\tvector<bool> vis(N);\n\tvector<int> par(N, -1), depth(N), lowlink(N, 1 << 30);\n\tfunction<void(int)> build_tree = [&](int pos) {\n\t\tvis[pos] = true;\n\t\tfor (int i : G[pos]) {\n\t\t\tif (vis[i]) continue;\n\t\t\tpar[i] = pos;\n\t\t\tdepth[i] = depth[pos] + 1;\n\t\t\tbuild_tree(i);\n\t\t}\n\t};\n\tfunction<void(int)> get_lowlink = [&](int pos) {\n\t\tfor (int i : G[pos]) {\n\t\t\tif (par[i] != pos && par[pos] != i) {\n\t\t\t\tlowlink[pos] = min(lowlink[pos], depth[i]);\n\t\t\t}\n\t\t}\n\t\tfor (int i : G[pos]) {\n\t\t\tif (par[i] == pos) {\n\t\t\t\tget_lowlink(i);\n\t\t\t\tlowlink[pos] = min(lowlink[pos], lowlink[i]);\n\t\t\t}\n\t\t}\n\t};\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (!vis[i]) {\n\t\t\tbuild_tree(i);\n\t\t\tget_lowlink(i);\n\t\t}\n\t}\n\tset<pair<int, int> > bridge;\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (par[i] != -1 && lowlink[i] >= depth[i]) {\n\t\t\tbridge.insert(make_pair(i, par[i]));\n\t\t\tbridge.insert(make_pair(par[i], i));\n\t\t}\n\t}\n\tvector<vector<int> > G2(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j : G[i]) {\n\t\t\tif (bridge.find(make_pair(i, j)) == bridge.end()) {\n\t\t\t\tG2[i].push_back(j);\n\t\t\t}\n\t\t}\n\t}\n\tvector<int> comps(N, -1);\n\tfunction<void(int, int)> find_comps = [&](int pos, int col) {\n\t\tcomps[pos] = col;\n\t\tfor (int i : G2[pos]) {\n\t\t\tif (comps[i] == -1) {\n\t\t\t\tfind_comps(i, col);\n\t\t\t}\n\t\t}\n\t};\n\tint scol = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tif (comps[i] == -1) {\n\t\t\tfind_comps(i, scol);\n\t\t\t++scol;\n\t\t}\n\t}\n\tvector<int> scomp(scol);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++scomp[comps[i]];\n\t}\n\tvector<vector<int> > G3(scol);\n\tfor (pair<int, int> i : bridge) {\n\t\tG3[comps[i.first]].push_back(comps[i.second]);\n\t}\n\tvector<bool> vis3(scol, false);\n\tfunction<pair<int, int>(int, int)> calc = [&](int pos, int pre) {\n\t\tvis3[pos] = true;\n\t\tint s1 = 0, s2 = 0;\n\t\tfor (int i : G3[pos]) {\n\t\t\tif (i == pre) continue;\n\t\t\tpair<int, int> res = calc(i, pos);\n\t\t\ts1 += res.first;\n\t\t\ts2 += max(res.first, res.second);\n\t\t}\n\t\treturn make_pair(s2, s1 + scomp[pos]);\n\t};\n\tint ans = 0;\n\tfor (int i = 0; i < scol; ++i) {\n\t\tif (!vis3[i]) {\n\t\t\tpair<int, int> res = calc(i, -1);\n\t\t\tans += max(res.first, res.second);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 27540, "score_of_the_acc": -1.2173, "final_rank": 14 }, { "submission_id": "aoj_0377_4978875", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nnamespace lowlink{\n vector<vector<pair<int, int>>> roads_l;\n vector<int> label, lowlink;\n vector<bool> is_bridge;\n int dfs(int now, int back){\n lowlink[now] = label[now];\n int label_num = label[now];\n for (auto to : roads_l[now]){\n if (to.second == back){\n continue;\n }\n if (label[to.first] == -1){\n label[to.first] = label_num + 1;\n label_num = dfs(to.first, to.second);\n if (label[now] < lowlink[to.first]){\n is_bridge[to.second] = true;\n }\n }\n lowlink[now] = min(lowlink[now], lowlink[to.first]);\n }\n return label_num;\n }\n vector<bool> get_bridge(int N, vector<pair<int, int>> edges){\n roads_l.resize(N);\n int cnt = 0;\n for (auto i : edges){\n roads_l[i.first].push_back({i.second, cnt});\n roads_l[i.second].push_back({i.first, cnt});\n cnt++;\n }\n label = vector<int>(N, -1);\n lowlink = vector<int>(N, -1);\n is_bridge = vector<bool>(edges.size(), false);\n for (int i = 0; i < N; i++){\n if (label[i] == -1){\n label[i] = 0;\n dfs(i, -1);\n }\n }\n return is_bridge;\n }\n}\nvoid dfs(vector<int> &dp1, vector<int> &dp2, vector<vector<int>> &c, vector<int> &a, int v){\n dp1[v] = 0;\n dp2[v] = a[v];\n for (int w : c[v]){\n dfs(dp1, dp2, c, a, w);\n dp1[v] += max(dp1[w], dp2[w]);\n dp2[v] += dp1[w];\n }\n}\nint main(){\n int N, M;\n cin >> N >> M;\n vector<int> s(M), t(M);\n for (int i = 0; i < M; i++){\n cin >> s[i] >> t[i];\n }\n vector<pair<int, int>> edges(M);\n for (int i = 0; i < M; i++){\n edges[i] = make_pair(s[i], t[i]);\n }\n vector<bool> b = lowlink::get_bridge(N, edges);\n vector<vector<int>> E(N);\n for (int i = 0; i < M; i++){\n if (b[i] == 0){\n E[s[i]].push_back(t[i]);\n E[t[i]].push_back(s[i]);\n }\n }\n vector<int> con(N, -1);\n int cnt = 0;\n for (int i = 0; i < N; i++){\n if (con[i] == -1){\n con[i] = cnt;\n queue<int> Q;\n Q.push(i);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : E[v]){\n if (con[w] == -1){\n con[w] = cnt;\n Q.push(w);\n }\n }\n }\n cnt++;\n }\n }\n vector<int> a(cnt, 0);\n for (int i = 0; i < N; i++){\n a[con[i]]++;\n }\n vector<vector<int>> E2(cnt + 1);\n for (int i = 0; i < M; i++){\n if (con[s[i]] != con[t[i]]){\n E2[con[s[i]]].push_back(con[t[i]]);\n E2[con[t[i]]].push_back(con[s[i]]);\n }\n }\n a.push_back(0);\n vector<bool> used(cnt, false);\n for (int i = 0; i < cnt; i++){\n if (!used[i]){\n E2[i].push_back(cnt);\n E2[cnt].push_back(i);\n used[i] = true;\n queue<int> Q;\n Q.push(i);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : E2[v]){\n if (!used[w]){\n used[w] = true;\n Q.push(w);\n }\n }\n }\n }\n }\n cnt++;\n vector<int> p(cnt, -1);\n vector<vector<int>> c(cnt);\n queue<int> Q;\n Q.push(cnt - 1);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : E2[v]){\n if (w != p[v]){\n p[w] = v;\n c[v].push_back(w);\n Q.push(w);\n }\n }\n }\n vector<int> dp1(cnt, 0);\n vector<int> dp2(cnt, 0);\n dfs(dp1, dp2, c, a, cnt - 1);\n cout << max(dp1[cnt - 1], dp2[cnt - 1]) << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 25348, "score_of_the_acc": -0.9666, "final_rank": 13 }, { "submission_id": "aoj_0377_4885219", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass TwoEdgeConnectedComponents {\n void dfs(int i, int &pos){\n ord[i] = low[i] = pos++;\n int mul = 0;\n for (auto &&j : G[i]) {\n if(j == par[i] && !mul){\n mul = 1;\n continue;\n }\n if(~ord[j]){\n low[i] = min(low[i], ord[j]);\n continue;\n }\n par[j] = i;\n dfs(j, pos);\n size[i] += size[j];\n low[i] = min(low[i], low[j]);\n }\n }\n\n void dfs2(int i){\n out[bridge[i]].emplace_back(i);\n for (auto &&j : G[i]) {\n if(~bridge[j] || is_bridge(i, j)) continue;\n bridge[j] = bridge[i];\n dfs2(j);\n }\n }\npublic:\n vector<int> ord, low, par, bridge, size;\n vector<vector<int>> G, out;\n explicit TwoEdgeConnectedComponents(int n): ord(n, -1), low(n), par(n, -1), bridge(n, -1), size(n, 1), G(n){}\n\n inline bool is_bridge(int i, int j){\n if(ord[i] > ord[j]) swap(i, j);\n return ord[i] < low[j];\n }\n\n void add_edge(int u, int v){\n if(u != v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n }\n\n int build(){\n int n = G.size(), pos = 0;\n for (int i = 0; i < n; ++i) {\n if(ord[i] < 0) dfs(i, pos);\n }\n int k = 0;\n for (int i = 0; i < n; ++i) {\n if(!~bridge[i]){\n bridge[i] = k++;\n out.emplace_back();\n dfs2(i);\n }\n }\n return k;\n }\n};\n\nclass UnionFind {\n int n;\n vector<int> uni;\n int forest_size;\npublic:\n explicit UnionFind(int n) : n(n), uni(static_cast<u32>(n), -1), forest_size(n) {};\n\n int root(int a){\n if (uni[a] < 0) return a;\n else return (uni[a] = root(uni[a]));\n }\n\n bool unite(int a, int b) {\n a = root(a);\n b = root(b);\n if(a == b) return false;\n if(uni[a] > uni[b]) swap(a, b);\n uni[a] += uni[b];\n uni[b] = a;\n forest_size--;\n return true;\n }\n int size(){ return forest_size; }\n int size(int i){ return -uni[root(i)]; }\n bool same(int a, int b) { return root(a) == root(b); }\n};\n\nint main() {\n int n, m;\n cin >> n >> m;\n TwoEdgeConnectedComponents G(n);\n for (int i = 0; i < m; ++i) {\n int a, b;\n scanf(\"%d %d\", &a, &b);\n G.add_edge(a, b);\n }\n int k = G.build();\n vector<vector<int>> g(k);\n vector<int> v(k);\n UnionFind uf(k);\n for (int i = 0; i < k; ++i) v[i] = G.out[i].size();\n for (int i = 0; i < n; ++i) {\n for (auto &&j : G.G[i]) {\n if(G.is_bridge(i, j)){\n g[G.bridge[i]].emplace_back(G.bridge[j]);\n uf.unite(G.bridge[i], G.bridge[j]);\n }\n }\n }\n int ans = 0;\n vector<int> dp1(v), dp2(k);\n auto dfs = [&](int x, int par, auto &&f) -> void{\n for (auto &&y : g[x]) {\n if(y == par) continue;\n f(y, x, f);\n dp2[x] += max(dp1[y], dp2[y]);\n dp1[x] += dp2[y];\n }\n };\n for (int i = 0; i < k; ++i) {\n if(uf.root(i) == i) {\n dfs(i, -1, dfs);\n ans += max(dp1[i], dp2[i]);\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 23460, "score_of_the_acc": -0.4986, "final_rank": 7 }, { "submission_id": "aoj_0377_4256153", "code_snippet": "#define PROBLEM \"http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0377\"\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define call_from_test\n#ifndef call_from_test\n#include<bits/stdc++.h>\nusing namespace std;\n#endif\n//BEGIN CUT HERE\ntemplate<typename F>\nstruct FixPoint : F{\n FixPoint(F&& f):F(forward<F>(f)){}\n template<typename... Args>\n decltype(auto) operator()(Args&&... args) const{\n return F::operator()(*this,forward<Args>(args)...);\n }\n};\ntemplate<typename F>\ninline decltype(auto) MFP(F&& f){\n return FixPoint<F>{forward<F>(f)};\n}\n//END CUT HERE\n#ifndef call_from_test\n//INSERT ABOVE HERE\nsigned main(){\n return 0;\n}\n#endif\n\n#ifndef call_from_test\n#include<bits/stdc++.h>\nusing namespace std;\n#endif\n//BEGIN CUT HERE\n// work with multigraph\nstruct TwoEdgeConnectedComponents{\n vector<int> ord,low,par,blg,sz;\n vector<vector<int>> G,C;\n\n TwoEdgeConnectedComponents(int n):\n ord(n,-1),low(n),par(n,-1),blg(n,-1),sz(n,1),G(n){}\n\n void add_edge(int u,int v){\n if(u==v) return;\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n bool is_bridge(int u,int v){\n if(ord[u]>ord[v]) swap(u,v);\n return ord[u]<low[v];\n }\n\n void dfs(int v,int &pos){\n ord[v]=low[v]=pos++;\n int dup=0;\n for(int u:G[v]){\n if(u==par[v] and !dup){\n dup=1;\n continue;\n }\n if(~ord[u]){\n low[v]=min(low[v],ord[u]);\n continue;\n }\n par[u]=v;\n dfs(u,pos);\n sz[v]+=sz[u];\n low[v]=min(low[v],low[u]);\n }\n }\n\n void fill_component(int v){\n C[blg[v]].emplace_back(v);\n for(int u:G[v]){\n if(~blg[u]||is_bridge(u,v)) continue;\n blg[u]=blg[v];\n fill_component(u);\n }\n }\n\n void add_component(int v,int &k){\n if(~blg[v]) return;\n blg[v]=k++;\n C.emplace_back();\n fill_component(v);\n }\n\n int build(){\n int n=G.size(),pos=0;\n for(int i=0;i<n;i++)\n if(ord[i]<0) dfs(i,pos);\n\n int k=0;\n for(int i=0;i<n;i++) add_component(i,k);\n\n return k;\n }\n\n const vector<int>& operator[](int i)const{return C[i];}\n\n vector<vector<int>> forest(){\n int n=G.size(),k=C.size();\n vector<vector<int>> T(k);\n for(int v=0;v<n;v++)\n for(int u:G[v])\n if(blg[v]!=blg[u])\n T[blg[v]].emplace_back(blg[u]);\n return T;\n }\n};\n//END CUT HERE\n#ifndef call_from_test\n//INSERT ABOVE HERE\nsigned main(){\n return 0;\n}\n#endif\n\n#undef call_from_test\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n int n,m;\n cin>>n>>m;\n TwoEdgeConnectedComponents tecc(n);\n for(int i=0;i<m;i++){\n int a,b;\n cin>>a>>b;\n tecc.add_edge(a,b);\n }\n int k=tecc.build();\n auto G=tecc.forest();\n\n vector<int> cs(k);\n for(int i=0;i<k;i++) cs[i]=tecc[i].size();\n\n vector< vector<int> > dp(2,vector<int>(k,0));\n vector<int> used(k,0);\n auto dfs=\n MFP([&](auto dfs,int v,int p)->void{\n if(used[v]) return;\n used[v]=1;\n dp[0][v]=0;\n dp[1][v]=cs[v];\n for(int u:G[v]){\n if(u==p) continue;\n dfs(u,v);\n dp[0][v]+=max(dp[0][u],dp[1][u]);\n dp[1][v]+=dp[0][u];\n }\n return;\n });\n\n int ans=0;\n for(int i=0;i<k;i++){\n if(used[i]) continue;\n dfs(i,-1);\n ans+=max(dp[0][i],dp[1][i]);\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 22692, "score_of_the_acc": -0.4647, "final_rank": 6 }, { "submission_id": "aoj_0377_4212725", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nstruct UnionFindTree {\n int V;\n vector<int> par;\n vector<int> rank;\n vector<int> siz;\n\n void init(int n) {\n V = n;\n par.resize(n);\n rank.resize(n);\n siz.resize(n);\n for (int i = 0; i < n; i++) {\n par[i] = i;\n rank[i] = 0;\n siz[i] = 1;\n }\n }\n int find(int x) {\n if (par[x] == x) {\n return x;\n } else {\n return par[x] = find(par[x]);\n }\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n V--;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) rank[x]++;\n par[y] = x;\n siz[x] += siz[y];\n }\n bool is_same(int x, int y) {\n return find(x) == find(y);\n }\n int size(int x) {\n x = find(x);\n return siz[x];\n }\n};\n\nint N, M;\n\nvector<vector<int> > g, G;\nvector<int> ord, low;\nvector<bool> is_articulation, visited;\nvector<P> bridges, non_bridges;\n\nvoid dfs(int u, int par, int &k){\n ord[u] = k;\n k++;\n low[u] = ord[u];\n visited[u] = true;\n int cnt = 0;\n for(auto v : g[u]){\n // dfsの子ノードへ移動\n if(ord[v] == -1){\n cnt++;\n dfs(v, u, k);\n low[u] = min(low[u], low[v]);\n if(par!=-1 && ord[u] <= low[v]){\n is_articulation[u] = true;\n }\n if(ord[u] < low[v]){\n bridges.push_back(make_pair(min(u,v), max(u,v)));\n }else{\n non_bridges.push_back(make_pair(min(u,v), max(u,v)));\n }\n }\n // dfs木の後退辺を移動\n else if(v != par)low[u] = min(low[u], ord[v]);\n }\n if(par == -1){\n is_articulation[u] = cnt >= 2; // 根はdfs木の次数が2以上ならば関節点\n }\n}\n\nvoid lowlink(){\n ord.assign(g.size(), -1);\n low.assign(g.size(), INF);\n visited.assign(g.size(), false);\n is_articulation.assign(g.size(), false);\n int k = 0;\n for(int i=0;i<int(g.size());i++){\n if(!visited[i]) dfs(i, -1, k);\n }\n}\n\nUnionFindTree uf;\nmap<int,int> id;\nvector<int> val;\nvector<vector<int> > dp;\n\nint rec(int i, int c, int p){\n if(dp[i][c] != -1) return dp[i][c];\n visited[i] = true;\n int res = 0;\n for(auto &j : G[i]){\n if(j == p) continue;\n res += rec(j,1,i);\n }\n if(c == 1){\n int sum = val[i];\n for(auto &j : G[i]){\n if(j == p) continue;\n sum += rec(j,0,i); \n }\n res = max(res, sum);\n }\n return dp[i][c] = res;\n}\n\nint main() {\n cin >> N >> M;\n g.resize(N);\n for(int i=0;i<M;i++){\n int s, t;\n cin >> s >> t;\n g[s].emplace_back(t);\n g[t].emplace_back(s);\n }\n lowlink();\n uf.init(N);\n for(auto &e : non_bridges){\n int s = e.first, t = e.second;\n uf.unite(s,t);\n }\n val.resize(uf.V);\n for(int i=0,idx=0;i<N;i++){\n if(id.find(uf.find(i))==id.end()){\n id[uf.find(i)] = idx;\n val[idx] = uf.size(i);\n idx++;\n }\n }\n G.resize(uf.V);\n for(auto &e : bridges){\n int s = uf.find(e.first), t = uf.find(e.second);\n G[id[s]].push_back(id[t]);\n G[id[t]].push_back(id[s]);\n }\n dp.resize(uf.V, vector<int>(2, -1));\n fill(visited.begin(), visited.end(), false);\n int ans = 0;\n for(int i=0;i<uf.V;i++){\n if(!visited[i]){\n ans += rec(i,1,-1);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 27012, "score_of_the_acc": -1.5017, "final_rank": 17 }, { "submission_id": "aoj_0377_4212710", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nstruct UnionFindTree {\n int V;\n vector<int> par;\n vector<int> rank;\n vector<int> siz;\n\n void init(int n) {\n V = n;\n par.resize(n);\n rank.resize(n);\n siz.resize(n);\n for (int i = 0; i < n; i++) {\n par[i] = i;\n rank[i] = 0;\n siz[i] = 1;\n }\n }\n int find(int x) {\n if (par[x] == x) {\n return x;\n } else {\n return par[x] = find(par[x]);\n }\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n V--;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) rank[x]++;\n par[y] = x;\n siz[x] += siz[y];\n }\n bool is_same(int x, int y) {\n return find(x) == find(y);\n }\n int size(int x) {\n x = find(x);\n return siz[x];\n }\n};\n\nint N, M;\n\nvector<vector<int> > g, G;\nvector<int> ord, low;\nvector<bool> is_articulation, visited;\nvector<P> bridges, es;\n\nvoid dfs(int u, int par, int &k){\n ord[u] = k;\n k++;\n low[u] = ord[u];\n visited[u] = true;\n int cnt = 0;\n for(auto v : g[u]){\n // dfsの子ノードへ移動\n if(ord[v] == -1){\n cnt++;\n dfs(v, u, k);\n low[u] = min(low[u], low[v]);\n if(par!=-1 && ord[u] <= low[v]){\n is_articulation[u] = true;\n }\n if(ord[u] < low[v]){\n bridges.push_back(make_pair(min(u,v), max(u,v)));\n }\n }\n // dfs木の後退辺を移動\n else if(v != par)low[u] = min(low[u], ord[v]);\n }\n if(par == -1){\n is_articulation[u] = cnt >= 2; // 根はdfs木の次数が2以上ならば関節点\n }\n}\n\nvoid lowlink(){\n ord.assign(g.size(), -1);\n low.assign(g.size(), INF);\n visited.assign(g.size(), false);\n is_articulation.assign(g.size(), false);\n int k = 0;\n for(int i=0;i<int(g.size());i++){\n if(!visited[i]) dfs(i, -1, k);\n }\n}\n\nUnionFindTree uf;\nmap<int,int> id;\nvector<int> val;\nvector<vector<int> > dp;\n\nint rec(int i, int c, int p){\n if(dp[i][c] != -1) return dp[i][c];\n visited[i] = true;\n int res = 0;\n for(auto &j : G[i]){\n if(j == p) continue;\n res += rec(j,1,i);\n }\n if(c == 1){\n int sum = val[i];\n for(auto &j : G[i]){\n if(j == p) continue;\n sum += rec(j,0,i); \n }\n res = max(res, sum);\n }\n return dp[i][c] = res;\n}\n\nint main() {\n cin >> N >> M;\n g.resize(N);\n for(int i=0;i<M;i++){\n int s, t;\n cin >> s >> t;\n g[s].emplace_back(t);\n g[t].emplace_back(s);\n es.push_back(P(s,t));\n }\n lowlink();\n uf.init(N);\n for(auto &e : es){\n int s = e.first, t = e.second;\n if(low[s] == low[t]){\n uf.unite(s,t);\n }\n }\n val.resize(uf.V);\n for(int i=0,idx=0;i<N;i++){\n if(id.find(uf.find(i))==id.end()){\n id[uf.find(i)] = idx;\n val[idx] = uf.size(i);\n idx++;\n }\n }\n G.resize(uf.V);\n for(auto &e : bridges){\n int s = uf.find(e.first), t = uf.find(e.second);\n G[id[s]].push_back(id[t]);\n G[id[t]].push_back(id[s]);\n }\n dp.resize(uf.V, vector<int>(2, -1));\n fill(visited.begin(), visited.end(), false);\n int ans = 0;\n for(int i=0;i<uf.V;i++){\n if(!visited[i]){\n ans += rec(i,1,-1);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.6333333333333333, "time_ms": 30, "memory_kb": 17872, "score_of_the_acc": -0.1748, "final_rank": 19 }, { "submission_id": "aoj_0377_4212660", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nstruct UnionFindTree {\n int N;\n vector<int> par;\n vector<int> rank;\n vector<int> siz;\n\n void init(int n) {\n N = n;\n par.resize(n);\n rank.resize(n);\n siz.resize(n);\n for (int i = 0; i < n; i++) {\n par[i] = i;\n rank[i] = 0;\n siz[i] = 1;\n }\n }\n int find(int x) {\n if (par[x] == x) {\n return x;\n } else {\n return par[x] = find(par[x]);\n }\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n N--;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) rank[x]++;\n par[y] = x;\n siz[x] += siz[y];\n }\n bool is_same(int x, int y) {\n return find(x) == find(y);\n }\n int size(int x) {\n x = find(x);\n return siz[x];\n }\n};\n\nint N, M;\n\nvector<vector<int> > g, G;\nvector<int> ord, low;\nvector<bool> is_articulation, visited;\nvector<P> bridges, es;\n\nvoid dfs(int u, int par, int &k){\n ord[u] = k;\n k++;\n low[u] = ord[u];\n visited[u] = true;\n int cnt = 0;\n for(auto v : g[u]){\n // dfsの子ノードへ移動\n if(ord[v] == -1){\n cnt++;\n dfs(v, u, k);\n low[u] = min(low[u], low[v]);\n if(par!=-1 && ord[u] <= low[v]){\n is_articulation[u] = true;\n }\n if(ord[u] < low[v]){\n bridges.push_back(make_pair(min(u,v), max(u,v)));\n }\n }\n // dfs木の後退辺を移動\n else if(v != par)low[u] = min(low[u], ord[v]);\n }\n if(par == -1){\n is_articulation[u] = cnt >= 2; // 根はdfs木の次数が2以上ならば関節点\n }\n}\n\nvoid lowlink(){\n ord.resize(g.size(), -1);\n low.resize(g.size());\n visited.resize(g.size(), false);\n is_articulation.resize(g.size(), false);\n int k = 0;\n for(int i=0;i<int(g.size());i++){\n if(!visited[i]) dfs(i, -1, k);\n }\n}\n\nUnionFindTree uf;\nmap<int,int> id;\nvector<int> val;\nvector<vector<int> > dp;\n\nint rec(int i, int c, int p){\n if(dp[i][c] != -1) return dp[i][c];\n visited[i] = true;\n int res = 0;\n for(auto &j : G[i]){\n if(j == p) continue;\n res += rec(j,1,i);\n }\n if(c == 1){\n int sum = val[i];\n for(auto &j : G[i]){\n if(j == p) continue;\n sum += rec(j,0,i); \n }\n res = max(res, sum);\n }\n return dp[i][c] = res;\n}\n\nint main() {\n cin >> N >> M;\n g.resize(N);\n for(int i=0;i<M;i++){\n int s, t;\n cin >> s >> t;\n g[s].emplace_back(t);\n g[t].emplace_back(s);\n es.push_back(P(s,t));\n }\n lowlink();\n uf.init(N);\n for(auto &e : es){\n int s = e.first, t = e.second;\n if(low[s] == low[t]){\n uf.unite(s,t);\n }\n }\n val.resize(uf.N);\n for(int i=0,idx=0;i<N;i++){\n if(id.find(uf.find(i))==id.end()){\n id[uf.find(i)] = idx;\n val[idx] = uf.size(i);\n idx++;\n }\n }\n G.resize(uf.N);\n for(auto &e : bridges){\n int s = uf.find(e.first), t = uf.find(e.second);\n G[id[s]].push_back(id[t]);\n G[id[t]].push_back(id[s]);\n }\n dp.resize(uf.N, vector<int>(2, -1));\n fill(visited.begin(), visited.end(), false);\n int ans = 0;\n for(int i=0;i<uf.N;i++){\n if(!visited[i]){\n ans += rec(i,1,-1);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.6333333333333333, "time_ms": 40, "memory_kb": 17864, "score_of_the_acc": -0.2514, "final_rank": 20 }, { "submission_id": "aoj_0377_4212619", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int, P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1 << 30;\nconstexpr ll MOD = ll(1e9) + 7;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n\nstruct UnionFindTree {\n int N;\n vector<int> par;\n vector<int> rank;\n vector<int> siz;\n\n void init(int n) {\n N = n;\n par.resize(n);\n rank.resize(n);\n siz.resize(n);\n for (int i = 0; i < n; i++) {\n par[i] = i;\n rank[i] = 0;\n siz[i] = 1;\n }\n }\n int find(int x) {\n if (par[x] == x) {\n return x;\n } else {\n return par[x] = find(par[x]);\n }\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n N--;\n if (rank[x] < rank[y]) swap(x, y);\n if (rank[x] == rank[y]) rank[x]++;\n par[y] = x;\n siz[x] += siz[y];\n }\n bool is_same(int x, int y) {\n return find(x) == find(y);\n }\n int size(int x) {\n x = find(x);\n return siz[x];\n }\n};\n\nint N, M;\n\nvector<vector<int> > g, G;\nvector<int> ord, low;\nvector<bool> is_articulation, visited;\nvector<P> bridges, es;\n\nvoid dfs(int u, int par, int &k){\n ord[u] = k;\n k++;\n low[u] = ord[u];\n visited[u] = true;\n int cnt = 0;\n for(auto v : g[u]){\n // dfsの子ノードへ移動\n if(ord[v] == -1){\n cnt++;\n dfs(v, u, k);\n low[u] = min(low[u], low[v]);\n if(par!=-1 && ord[u] <= low[v]){\n is_articulation[u] = true;\n }\n if(ord[u] < low[v]){\n bridges.push_back(make_pair(min(u,v), max(u,v)));\n }\n }\n // dfs木の後退辺を移動\n else if(v != par)low[u] = min(low[u], ord[v]);\n }\n if(par == -1){\n is_articulation[u] = cnt >= 2; // 根はdfs木の次数が2以上ならば関節点\n }\n}\n\nvoid lowlink(){\n ord.resize(g.size(), -1);\n low.resize(g.size());\n visited.resize(g.size(), false);\n is_articulation.resize(g.size(), false);\n int k = 0;\n for(int i=0;i<int(g.size());i++){\n if(!visited[i]) dfs(i, -1, k);\n }\n}\n\nUnionFindTree uf;\nmap<int,int> id;\nvector<int> val;\nvector<vector<int> > dp;\n\nint rec(int i, int c, int p){\n if(dp[i][c] != -1) return dp[i][c];\n visited[i] = true;\n int res = 0;\n for(auto &j : G[i]){\n if(j == p) continue;\n res += rec(j,1,i);\n }\n if(c == 1){\n int sum = val[i];\n for(auto &j : G[i]){\n if(j == p) continue;\n sum += rec(j,0,i); \n }\n res = max(res, sum);\n }\n return dp[i][c] = res;\n}\n\nint main() {\n cin >> N >> M;\n g.resize(N);\n for(int i=0;i<M;i++){\n int s, t;\n cin >> s >> t;\n g[s].emplace_back(t);\n g[t].emplace_back(s);\n es.push_back(P(s,t));\n }\n lowlink();\n uf.init(N);\n for(auto &e : es){\n int s = e.first, t = e.second;\n if(low[s] == low[t]){\n uf.unite(s,t);\n }\n }\n val.resize(uf.N);\n for(int i=0,idx=0;i<N;i++){\n if(id.find(uf.find(i))==id.end()){\n id[uf.find(i)] = idx;\n val[idx] = uf.size(i);\n idx++;\n }\n }\n G.resize(uf.N);\n for(auto &e : bridges){\n int s = uf.find(e.first), t = uf.find(e.second);\n G[id[s]].push_back(id[t]);\n G[id[t]].push_back(id[s]);\n }\n dp.resize(uf.N, vector<int>(2, -1));\n visited.assign(uf.N, false);\n int ans = 0;\n for(int i=0;i<uf.N;i++){\n if(!visited[i]){\n ans += rec(i,1,-1);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.6333333333333333, "time_ms": 30, "memory_kb": 17780, "score_of_the_acc": -0.1708, "final_rank": 18 }, { "submission_id": "aoj_0377_3969896", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing ull=unsigned long long;\nusing uint=unsigned int;\nusing pcc=pair<char,char>;\nusing pii=pair<int,int>;\nusing pll=pair<ll,ll>;\nusing pdd=pair<double,double>;\nusing tuplis=pair<ll,pll>;\nusing tuplis2=pair<pll,ll>;\ntemplate<class T> using pq=priority_queue<T,vector<T>,greater<T>>;\nconst ll LINF=0x1fffffffffffffff;\nconst ll MINF=0x7fffffffffff;\nconst int INF=0x3fffffff;\nconst ll MOD=1000000007;\nconst ll MODD=998244353;\nconst ld DINF=numeric_limits<ld>::infinity();\nconst ld EPS=1e-9;\nconst ld PI=3.141592653589793238462643383279;\nconst vector<ll>four{0,1,0,-1,0};\n#define _overload4(_1,_2,_3,_4,name,...) name\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep1(n) for(ll i=0;i<n;++i)\n#define _rep2(i,n) for(ll i=0;i<n;++i)\n#define _rep3(i,a,b) for(ll i=a;i<b;++i)\n#define _rep4(i,a,b,c) for(ll i=a;i<b;i+=c)\n#define rep(...) _overload4(__VA_ARGS__,_rep4,_rep3,_rep2,_rep1)(__VA_ARGS__)\n#define _rrep1(n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep2(i,n) for(ll i=(n)-1;i>=0;i--)\n#define _rrep3(i,a,b) for(ll i=(b)-1;i>=(a);i--)\n#define _rrep4(i,a,b,c) for(ll i=a+(b-a-1)/c*c;i>=a;i-=c)\n#define rrep(...) _overload4(__VA_ARGS__,_rrep4,_rrep3,_rrep2,_rrep1)(__VA_ARGS__)\n#define each(i,a) for(auto &i:a)\n#define sum(...) accumulate(range(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(range(__VA_ARGS__),double(0))\n#define _range(i) (i).begin(),(i).end()\n#define _range2(i,k) (i).begin(),(i).begin()+k\n#define _range3(i,a,b) (i).begin()+a,(i).begin()+b\n#define range(...) _overload3(__VA_ARGS__,_range3,_range2,_range)(__VA_ARGS__)\n#define _rrange(i) (i).rbegin(),(i).rend()\n#define _rrange2(i,k) (i).rbegin(),(i).rbegin()+k\n#define _rrange3(i,a,b) (i).rbegin()+a,(i).rbegin()+b\n#define rrange(...) _overload3(__VA_ARGS__,_rrange3,_rrange2,_rrange)(__VA_ARGS__)\n#define elif else if\n#define unless(a) if(!(a))\n#define mp make_pair\n#define mt make_tuple\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__;in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__;in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__;in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__;in(__VA_ARGS__)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size);in(name)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define VV(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__));in(name)\n#define vvv(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\ninline constexpr ll gcd(ll a,ll b){while(b){ll c=b;b=a%b;a=c;}return a;}\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\ntemplate<class T> inline constexpr T min(vector<T> &v){return *min_element(range(v));}\ninline char min(string &v){return *min_element(range(v));}\ntemplate<class T> inline constexpr T max(vector<T> &v){return *max_element(range(v));}\ninline char max(string &v){return *max_element(range(v));}\ninline constexpr ll intpow(ll a,ll b){ll ans=1;for(ll i=1;b;i*=2){if(b&i){b^=i;ans*=a;}a*=a;}return ans;}\ntemplate<typename T>\ninline constexpr bool chmin(T &mn,const T &cnt){if(mn>cnt){mn=cnt;return 1;}else return 0;}\ntemplate<typename T>\ninline constexpr bool chmax(T &mx,const T &cnt){if(mx<cnt){mx=cnt;return 1;}else return 0;}\ntemplate<class T> unordered_map<T,ll> press(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); unordered_map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ntemplate<class T> map<T,ll> press_map(vector<T> &a){ auto b = a; sort(range(b)); b.erase(unique(range(b)), b.end()); map<T,ll> ans; rep(b.size()) ans[b[i]] = i; each(i, a) i = ans[i]; return ans; }\ninline int scan(){ return getchar(); }\ninline void scan(int &a){ scanf(\"%d\", &a); }\ninline void scan(unsigned &a){ scanf(\"%u\", &a); }\ninline void scan(long &a){ scanf(\"%ld\", &a); }\ninline void scan(long long &a){ scanf(\"%lld\", &a); }\ninline void scan(unsigned long long &a){ scanf(\"%llu\", &a); }\ninline void scan(char &a){ cin >> a; }\ninline void scan(float &a){ scanf(\"%f\", &a); }\ninline void scan(double &a){ scanf(\"%lf\", &a); }\ninline void scan(long double &a){ scanf(\"%Lf\", &a); }\ninline void scan(vector<bool> &vec){ for(unsigned i = 0; i < vec.size(); i++) { int a; scan(a); vec[i] = a; } }\ninline void scan(char a[]){ scanf(\"%s\", a); }\ninline void scan(string &a){ cin >> a; }\ntemplate<class T> inline void scan(vector<T> &vec);\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec);\ntemplate<class T, class L> inline void scan(pair<T, L> &p);\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]);\ntemplate<class T> inline void scan(vector<T> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, size_t size> inline void scan(array<T, size> &vec){ for(auto &i : vec) scan(i); }\ntemplate<class T, class L> inline void scan(pair<T, L> &p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> inline void scan(T (&vec)[size]){ for(auto &i : vec) scan(i); }\ntemplate<class T> inline void scan(T &a){ cin>>a; }\ninline void in(){}\ntemplate <class Head, class... Tail> inline void in(Head &head, Tail&... tail){ scan(head); in(tail...); }\ninline void print(){ putchar(' '); }\ninline void print(const bool &a){ printf(\"%d\", a); }\ninline void print(const int &a){ printf(\"%d\", a); }\ninline void print(const unsigned &a){ printf(\"%u\", a); }\ninline void print(const long &a){ printf(\"%ld\", a); }\ninline void print(const long long &a){ printf(\"%lld\", a); }\ninline void print(const unsigned long long &a){ printf(\"%llu\", a); }\ninline void print(const char &a){ printf(\"%c\", a); }\ninline void print(const char a[]){ printf(\"%s\", a); }\ninline void print(const float &a){ printf(\"%.15f\", a); }\ninline void print(const double &a){ printf(\"%.15f\", a); }\ninline void print(const long double &a){ printf(\"%.15Lf\", a); }\ninline void print(const string &a){ each(i, a) print(i); }\ntemplate<class T> void print(const vector<T> &vec);\ntemplate<class T, size_t size> void print(const array<T, size> &vec);\ntemplate<class T, class L> void print(const pair<T, L> &p);\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]);\ntemplate<class T> void print(const vector<T> &vec){ if(vec.empty()) return; print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size> &vec){ print(vec[0]); for(auto i = vec.begin(); ++i != vec.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L> &p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> inline void print(const T (&vec)[size]){ print(vec[0]); for(auto i = vec; ++i != end(vec); ){ putchar(' '); print(*i); } }\ntemplate<class T> inline void print(const T &a){ cout << a; }\ninline int out(){ putchar('\\n'); return 0; }\ntemplate<class T> inline int out(const T &t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> inline int out(const Head &head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\ntemplate <class T> inline void err(T t){cerr<<t<<'\\n';}\ntemplate<class Head, class... Tail> inline void err(const Head &head, const Tail&... tail){ cerr<<head<<' '; err(tail...); }\ninline void err(){cerr<<'\\n';}\ninline int first(const bool &i){return out(i?\"first\":\"second\");}\ninline int yes(const bool &i){return out(i?\"yes\":\"no\");}\ninline int Yes(const bool &i){return out(i?\"Yes\":\"No\");}\ninline int YES(const bool &i){return out(i?\"YES\":\"NO\");}\ninline int Yay(const bool &i){return out(i?\"Yay!\":\":(\");}\ninline int Possible(const bool &i){return out(i?\"Possible\":\"Impossible\");}\ninline int POSSIBLE(const bool &i){return out(i?\"POSSIBLE\":\"IMPOSSIBLE\");}\ninline void Case(ll i){printf(\"Case #%lld: \",i);}\n\n\nstruct UnionFind{\n vector<ll>data;\n UnionFind(ll n):data(n,-1){}\n bool unite(ll a,ll b){\n a=root(a);b=root(b);\n if(a==b)return 1;\n if(data[a]>data[b])swap(a,b);\n data[a]+=data[b];\n data[b]=a;\n return 0;\n }\n bool find(ll a,ll b){return root(a)==root(b);}\n ll root(ll a){return data[a]<0?a:data[a]=root(data[a]);}\n ll size(ll a){return -data[root(a)];}\n ll operator[](ll a){return root(a);}\n};\nstruct BiConnected{\n ll cnt = 0, n;\n const vector<vector<ll>>& _g;\n vector<vector<ll>> g;\n vector<ll> low, pre, id, siz;\n UnionFind uf;\n BiConnected(const vector<vector<ll>>& _g): n(_g.size()), _g(_g), low(n), pre(n, LINF), id(n), uf(n){\n dfs(-1, 0);\n cnt = 0;\n rep(n) if(uf.data[i] < 0) id[i] = cnt++;\n siz.resize(cnt);\n rep(n){\n id[i] = id[uf[i]];\n siz[id[i]]++;\n }\n g.resize(cnt);\n rep(n) each(j, _g[i]) if(id[i] != id[j]) g[id[i]].push_back(id[j]);\n }\n void dfs(ll from, ll at){\n pre[at] = low[at] = cnt++;\n each(i, _g[at]) if(i != from){\n if(pre[i] == LINF) dfs(at, i);\n chmin(low[at], low[i]);\n if(low[i] != pre[i]) uf.unite(at, i);\n }\n }\n ll size(){ return cnt; }\n ll size(ll x){ return siz[x]; }\n vector<ll>& operator[](ll x){ return g[x]; }\n operator vector<vector<ll>>&(){ return g; }\n};\nsigned main(){\n LL(n, m);\n vector<vector<ll>> g(n), a(n);\n UnionFind uf(n);\n rep(m){\n LL(a, b);\n g[a].push_back(b);\n g[b].push_back(a);\n uf.unite(a, b);\n }\n rep(n) a[uf[i]].push_back(i);\n ll ans = 0;\n each(v, a) if(v.size()){\n ll cnt = 0;\n unordered_map<ll,ll> press;\n each(i, v) press[i] = cnt++;\n vector<vector<ll>> gg(v.size());\n rep(i, v.size()) each(k, g[v[i]]) gg[i].push_back(press[k]);\n BiConnected g(gg);\n vv(ll, dp, g.size(), 2);\n auto dfs=[&g, &dp](ll from, ll at, auto& f) -> void {\n dp[at][1] += g.size(at);\n each(i,g[at])if(i!=from){\n f(at, i, f);\n dp[at][1] += dp[i][0];\n dp[at][0] += max(dp[i]);\n }\n };\n dfs(-1, 0, dfs);\n ans += max(dp[0]);\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 38292, "score_of_the_acc": -1.4615, "final_rank": 16 }, { "submission_id": "aoj_0377_3967408", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<typename G>\nstruct LowLink {\n const G &g;\n vector<int> used, ord, low;\n vector<int> articulation;\n vector<pair<int, int> > bridge;\n LowLink(const G &g):g(g) {};\n int dfs(int idx, int k, int par) {\n used[idx] = true;\n ord[idx] = k++;\n low[idx] = ord[idx];\n bool is_articulation = false;\n int cnt = 0;\n for (auto &to : g[idx]) {\n if (!used[to]) {\n ++cnt;\n k = dfs(to, k, idx);\n low[idx] = min(low[idx], low[to]);\n is_articulation |= ~par && low[to] >= ord[idx];\n if (ord[idx] < low[to]) bridge.emplace_back(minmax(idx, (int)to));\n } else if (to != par) {\n low[idx] = min(low[idx], ord[to]);\n }\n }\n is_articulation |= par == -1 && cnt > 1;\n if (is_articulation) articulation.push_back(idx);\n return k;\n };\n virtual void build() {\n used.assign(g.size(), 0);\n ord.assign(g.size(), 0);\n low.assign(g.size(), 0);\n int k = 0;\n for (int i = 0; i < g.size(); i++) {\n if (!used[i]) k = dfs(i, k, -1);\n }\n };\n};\ntemplate<typename G>\nstruct TwoEdgeConnectComponents : LowLink<G> {\n using LL = LowLink<G>;\n vector<int> comp;\n TwoEdgeConnectComponents(const G &g) : LL(g) {};\n int operator[] (const int &k) {\n return comp[k];\n };\n void dfs(int idx, int par, int &k) {\n if (~par && this->ord[par] >= this->low[idx]) comp[idx] = comp[par];\n else comp[idx] = k++;\n for (auto &to : this->g[idx]) {\n if (comp[to] == -1) dfs(to, idx, k);\n }\n };\n void build(G &t) {\n LL::build();\n comp.assign(this->g.size(), -1);\n int k = 0;\n for (int i = 0; i < comp.size(); i++) {\n if (comp[i] == -1) dfs(i, -1, k);\n }\n t.resize(k);\n for (auto &e : this->bridge) {\n int x = comp[e.first], y = comp[e.second];\n t[x].push_back(y);\n t[y].push_back(x);\n }\n }\n};\nvector<vector<int> > g;\nvector<vector<int> > t;\nint node_sum[100005];\nint memo[100010][2];\nint dp(int i, int par){\n for(auto e : t[i]){\n if(e != par) dp(e, i);\n }\n int n1 = 0;\n int n2 = node_sum[i];\n for(auto e : t[i]){\n if(e == par) continue;\n n1 += max(memo[e][0], memo[e][1]);\n n2 += memo[e][0];\n }\n memo[i][0] = n1;\n memo[i][1] = n2;\n\n return max(n1, n2);\n}\n\nint main() {\n int n, m;\n cin >> n >> m;\n \n g.resize(n);\n for (int i = 0; i < m; i++) {\n int s, t;\n cin >> s >> t;\n g[s].push_back(t);\n g[t].push_back(s);\n }\n TwoEdgeConnectComponents<vector<vector<int> > > bcc(g);\n bcc.build(t);\n \n for (int i = 0; i < n; i++) {\n int u = bcc[i];\n node_sum[u]++;\n }\n \n int ans = 0;\n for (int i = 0; i < n; i++) {\n int u = bcc[i];\n if (memo[u][0] == 0 && memo[u][1] == 0) {\n ans += dp(u, -1);\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 17608, "score_of_the_acc": -0.3939, "final_rank": 4 }, { "submission_id": "aoj_0377_3732301", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nusing UnWeightedGraph = vector<vector<int>>;\nstruct LowLink {\n const UnWeightedGraph &g;\n vector<int> aps; // articulation points\n vector<pair<int, int>> brs; // brides\n vector<int> seen, ord, low;\n LowLink(const UnWeightedGraph &g) : g(g) { }\n int dfs(int u, int p = -1, int time = 0) {\n seen[u] = true;\n ord[u] = low[u] = time++;\n bool exists = false;\n int cnt_ch = 0;\n for (int v: g[u]) {\n if (!seen[v]) {\n ++cnt_ch;\n time = dfs(v, u, time);\n low[u] = min(low[u], low[v]); // forward edge\n if (ord[u] < low[v]) brs.emplace_back(u, v);\n if (ord[u] <= low[v]) exists = true;\n } else if (v != p) {\n low[u] = min(low[u], ord[v]); // back edge\n }\n }\n if ((p == -1 && cnt_ch > 1) || (p != -1 && exists)) aps.emplace_back(u);\n return time;\n }\n void build() {\n int N = g.size();\n seen.assign(N, 0); ord.resize(N); low.resize(N);\n aps.clear(); brs.clear();\n for (int v = 0; v < N; ++v) if (!seen[v]) dfs(v);\n for (auto &br: brs) if (br.first > br.second) swap(br.first, br.second);\n sort(brs.begin(), brs.end());\n sort(aps.begin(), aps.end());\n }\n};\nstruct TwoEdgeConnectedComponents : LowLink {\n using LL = LowLink;\n vector<int> comp;\n TwoEdgeConnectedComponents(const UnWeightedGraph &g) : LL(g) { }\n int operator[](int k) { return comp[k]; }\n void dfs(int u, int p, int &k) {\n if (~p && this->ord[p] >= this->low[u]) comp[u] = comp[p];\n else comp[u] = k++;\n for (int v: this->g[u]) if (comp[v] == -1) dfs(v, u, k);\n }\n UnWeightedGraph build() {\n LL::build();\n comp.assign(this->g.size(), -1);\n int k = 0;\n for (int i = 0; i < comp.size(); ++i) if (comp[i] == -1) dfs(i, -1, k);\n UnWeightedGraph t_comp(k);\n for (auto &e: this->brs) {\n int x = comp[e.first], y = comp[e.second];\n t_comp[x].emplace_back(y);\n t_comp[y].emplace_back(x);\n }\n return t_comp;\n }\n};\n\nUnWeightedGraph tree;\nvector<int> size;\nvector<vector<int>> dp;\nvoid dfs(int u, int p) {\n dp[0][u] = 0;\n dp[1][u] = size[u];\n for (int v: tree[u]) if (v != p) {\n dfs(v, u);\n dp[0][u] += max(dp[0][v], dp[1][v]);\n dp[1][u] += dp[0][v];\n }\n}\nint main() {\n int N, M; cin >> N >> M;\n UnWeightedGraph g(N);\n for (int i = 0; i < M; i++) {\n int s, t; cin >> s >> t;\n g[s].emplace_back(t);\n g[t].emplace_back(s);\n }\n TwoEdgeConnectedComponents bcc(g);\n tree = bcc.build();\n int V = tree.size();\n size.assign(V, 0);\n for (int i = 0; i < N; i++) size[bcc[i]]++;\n int ans = 0;\n dp.assign(2, vector<int>(V, -1));\n for (int i = 0; i < V; i++) if (dp[0][i] == -1) { // 森\n dfs(i, -1);\n ans += max(dp[0][i], dp[1][i]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 17868, "score_of_the_acc": -0.5593, "final_rank": 8 }, { "submission_id": "aoj_0377_3608657", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n//BEGIN CUT HERE\nstruct LowLink{\n int n,pos;\n vector<int> ord,low,par,blg,num;\n vector<vector<int> > G,C,T;\n vector<vector<pair<int, int> > > E;\n \n vector<int> ap;\n vector<pair<int, int> > bs,cand;\n\n LowLink(int n):n(n),pos(0),ord(n,-1),low(n),\n par(n,-1),blg(n,-1),num(n,1),G(n){}\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n bool is_bridge(int u,int v){\n if(ord[u]>ord[v]) swap(u,v);\n return ord[u]<low[v];\n }\n\n void dfs(int v){\n ord[v]=low[v]=pos++;\n for(int u:G[v]){\n if(u==par[v]) continue; \n if(ord[u]<ord[v])\n cand.emplace_back(min(u,v),max(u,v)); \n if(~ord[u]){\n low[v]=min(low[v],ord[u]);\n continue;\n }\n par[u]=v;\n dfs(u);\n num[v]+=num[u];\n low[v]=min(low[v],low[u]);\n if(is_bridge(u,v)) bs.emplace_back(u,v);\n if(low[u]>=ord[v]){\n E.emplace_back();\n while(1){\n auto e=cand.back();\n cand.pop_back();\n E.back().emplace_back(e);\n if(make_pair(min(u,v),max(u,v))==e) break; \n }\n }\n }\n }\n\n void fill_component(int v){\n C[blg[v]].emplace_back(v);\n for(int u:G[v]){\n if(~blg[u]||is_bridge(u,v)) continue;\n blg[u]=blg[v];\n fill_component(u);\n }\n }\n\n void add_component(int v,int &k){\n if(~blg[v]) return;\n blg[v]=k++;\n C.emplace_back();\n fill_component(v);\n }\n \n int build(){\n for(int i=0;i<n;i++)\n if(ord[i]<0) dfs(i);\n \n vector<int> cnt(n,0);\n for(int i=0;i<n;i++){\n int p=par[i];\n if(p<0) continue;\n if(par[p]<0) cnt[p]++;\n else if(ord[p]<=low[i]) ap.emplace_back(p);\n }\n \n for(int i=0;i<n;i++)\n if(cnt[i]>1) ap.emplace_back(i);\n\n sort(ap.begin(),ap.end());\n ap.erase(unique(ap.begin(),ap.end()),ap.end());\n\n int k=0; \n for(int i=0;i<n;i++) add_component(i,k);\n\n T.assign(k,vector<int>()); \n for(auto e:bs){\n int u=blg[e.first],v=blg[e.second];\n T[u].emplace_back(v);\n T[v].emplace_back(u);\n }\n return k;\n }\n};\n//END CUT HERE\n\nstruct UnionFind{\n int n,num;\n vector<int> r,p;\n UnionFind(){}\n UnionFind(int sz):n(sz),num(sz),r(sz,1),p(sz,0){iota(p.begin(),p.end(),0);}\n int find(int x){\n return (x==p[x]?x:p[x]=find(p[x]));\n }\n bool same(int x,int y){\n return find(x)==find(y);\n }\n void unite(int x,int y){\n x=find(x);y=find(y);\n if(x==y) return;\n if(r[x]<r[y]) swap(x,y);\n r[x]+=r[y];\n p[y]=x;\n num--;\n }\n int size(int x){\n return r[find(x)];\n }\n int count() const{\n return num;\n }\n};\n\ntemplate<typename T,T MOD = 1000000007>\nstruct Mint{\n T v;\n Mint():v(0){}\n Mint(signed v):v(v){}\n Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}\n\n Mint pow(long long k){\n Mint res(1),tmp(v);\n while(k){\n if(k&1) res*=tmp;\n tmp*=tmp;\n k>>=1;\n }\n return res;\n }\n \n static Mint add_identity(){return Mint(0);}\n static Mint mul_identity(){return Mint(1);}\n \n Mint inv(){return pow(MOD-2);}\n \n Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}\n Mint& operator/=(Mint a){return (*this)*=a.inv();}\n \n Mint operator+(Mint a) const{return Mint(v)+=a;};\n Mint operator-(Mint a) const{return Mint(v)-=a;};\n Mint operator*(Mint a) const{return Mint(v)*=a;};\n Mint operator/(Mint a) const{return Mint(v)/=a;};\n\n Mint operator-() const{return v?Mint(MOD-v):Mint(v);}\n\n bool operator==(const Mint a)const{return v==a.v;}\n bool operator!=(const Mint a)const{return v!=a.v;}\n bool operator <(const Mint a)const{return v <a.v;}\n};\n\n\ntemplate<typename M>\nstruct Enumeration{\n static vector<M> fact,finv,invs;\n \n static void init(int n){\n int m=fact.size();\n if(n<m) return;\n \n fact.resize(n+1,1);\n finv.resize(n+1,1);\n invs.resize(n+1,1);\n \n if(m==0) m=1;\n for(int i=m;i<=n;i++) fact[i]=fact[i-1]*M(i);\n finv[n]=M(1)/fact[n];\n for(int i=n;i>=m;i--) finv[i-1]=finv[i]*M(i);\n for(int i=m;i<=n;i++) invs[i]=finv[i]*fact[i-1];\n }\n \n static M C(int n,int k){\n if(n<k||k<0) return M(0);\n init(n);\n return fact[n]*finv[n-k]*finv[k];\n }\n \n static M H(int n,int k){\n if(n<0||k<0) return M(0);\n if(!n&&!k) return M(1);\n init(n+k-1);\n return C(n+k-1,k);\n }\n};\ntemplate<typename M>\nvector<M> Enumeration<M>::fact = vector<M>();\ntemplate<typename M>\nvector<M> Enumeration<M>::finv = vector<M>();\ntemplate<typename M>\nvector<M> Enumeration<M>::invs = vector<M>();\n\n//INSERT ABOVE HERE\nsigned GRL_3_A(){\n int n,m;\n scanf(\"%d %d\",&n,&m);\n LowLink G(n);\n for(int i=0;i<m;i++){\n int u,v;\n scanf(\"%d %d\",&u,&v);\n G.add_edge(u,v);\n }\n G.build();\n auto ap=G.ap;\n sort(ap.begin(),ap.end());\n for(int v:ap) printf(\"%d\\n\",v);\n return 0;\n}\n/*\n verified on 2019/05/29\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_3_A&lang=jp\n*/\n\nsigned GRL_3_B(){\n int n,m;\n scanf(\"%d %d\",&n,&m);\n \n LowLink G(n);\n for(int i=0;i<m;i++){\n int u,v;\n scanf(\"%d %d\",&u,&v);\n G.add_edge(u,v);\n }\n G.build();\n \n auto bs=G.bs;\n for(auto &e:bs)\n if(e.first>e.second) swap(e.first, e.second);\n \n sort(bs.begin(),bs.end());\n for(auto e:bs) printf(\"%d %d\\n\",e.first, e.second);\n \n return 0;\n}\n/*\n verified on 2019/03/23\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_3_B&lang=jp\n*/\n\nsigned AOJ_0377(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int n,m;\n cin>>n>>m;\n LowLink bg(n);\n for(int i=0;i<m;i++){\n int a,b;\n cin>>a>>b;\n bg.add_edge(a,b);\n }\n int k=bg.build();\n auto& G=bg.T;\n \n vector<int> c(k);\n for(int i=0;i<k;i++) c[i]=bg.C[i].size();\n vector<vector<int> > dp(2,vector<int>(k,0));\n vector<int> used(k,0);\n function<void(int,int)> dfs=[&](int v,int p){\n if(used[v]) return;\n used[v]=1;\n dp[0][v]=0;\n dp[1][v]=c[v];\n for(int u:G[v]){\n if(u==p) continue;\n dfs(u,v);\n dp[0][v]+=max(dp[0][u],dp[1][u]);\n dp[1][v]+=dp[0][u];\n }\n return;\n };\n int ans=0;\n for(int i=0;i<k;i++){\n if(used[i]) continue;\n dfs(i,-1);\n ans+=max(dp[0][i],dp[1][i]);\n }\n cout<<ans<<endl;\n return 0;\n}\n\n/*\n verified on 2019/05/29\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0377\n*/\n\nsigned ARC045_D(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int n;\n cin>>n;\n vector<int> xs(2*n+1),ys(2*n+1);\n for(int i=0;i<2*n+1;i++) cin>>xs[i]>>ys[i];\n\n vector<vector<int> > R(2*n+2),C(2*n+2);\n for(int i=0;i<2*n+1;i++) R[xs[i]].emplace_back(i);\n for(int i=0;i<2*n+1;i++) C[ys[i]].emplace_back(i);\n\n UnionFind uf(2*n+1);\n for(auto &v:R)\n for(auto u:v) uf.unite(v[0],u);\n for(auto &v:C)\n for(auto u:v) uf.unite(v[0],u);\n\n vector<int> vs;\n for(int i=0;i<2*n+1;i++){\n if(uf.find(i)!=i) continue;\n if(uf.size(i)&1) vs.emplace_back(i);\n }\n assert(!vs.empty());\n \n if(vs.size()>1u){\n for(int i=0;i<2*n+1;i++) cout<<\"NG\\n\";\n cout<<flush;\n return 0; \n }\n \n LowLink G(2*n+1);\n auto add_edge=\n [&](auto &V)->void{\n for(auto &v:V){\n if(v.empty()) continue;\n if(!uf.same(vs[0],v[0])) continue;\n if(v.size()>0u) for(auto u:v) G.add_edge(v[0],u);\n if(v.size()>1u) for(auto u:v) G.add_edge(v[1],u);\n }\n };\n add_edge(R);\n add_edge(C);\n\n G.build();\n auto ap=G.ap; \n \n vector<int> ans(2*n+1,0);\n for(int i=0;i<2*n+1;i++)\n if(uf.same(vs[0],i)) ans[i]=1;\n\n for(int v:ap){\n if(!uf.same(vs[0],v)) continue;\n for(int u:G.G[v]){\n if(G.par[u]!=v) continue; \n if(~G.par[v]&&G.ord[v]>G.low[u]) continue; \n if(G.num[u]&1) ans[v]=0;\n }\n }\n \n for(int i=0;i<2*n+1;i++) cout<<(ans[i]?\"OK\\n\":\"NG\\n\");\n cout<<flush;\n return 0;\n}\n/*\n verified on 2019/03/23\n https://atcoder.jp/contests/arc045/tasks/arc045_d\n*/\n\n\nsigned ARC062_F(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int n,m,k;\n cin>>n>>m>>k;\n\n using P = pair<int, int>;\n map<P, int> idx;\n \n LowLink G(n);\n for(int i=0;i<m;i++){\n int a,b;\n cin>>a>>b;\n a--;b--;\n G.add_edge(a,b);\n idx[P(a,b)]=idx[P(b,a)]=i;\n }\n\n G.build();\n \n UnionFind uf(m);\n for(auto vs:G.E)\n for(auto p:vs) uf.unite(idx[p],idx[vs[0]]); \n\n vector<set<int>> cnt(m); \n for(auto vs:G.E){\n for(auto p:vs){\n cnt[uf.find(idx[p])].emplace(p.first); \n cnt[uf.find(idx[p])].emplace(p.second);\n }\n }\n \n using M = Mint<int>;\n using E = Enumeration<M>;\n E::init(1000);\n \n auto calc1=\n [&](int x)->M{ \n M res{0};\n \n for(int i=0;i<x;i++)\n res+=M(k).pow(__gcd(i,x));\n \n res*=E::invs[x];\n return res;\n };\n\n M ans{1};\n for(int i=0;i<m;i++){\n if(uf.find(i)!=i) continue;\n if(uf.size(i)< (int)cnt[i].size()) ans*=M(k).pow(uf.size(i));\n if(uf.size(i)==(int)cnt[i].size()) ans*=calc1(uf.size(i));\n if(uf.size(i)> (int)cnt[i].size()) ans*=E::H(k,uf.size(i));\n } \n cout<<ans.v<<endl;\n return 0;\n}\n/*\n verified on 2019/05/29\n https://atcoder.jp/contests/arc062/tasks/arc062_d\n*/\n\n\nsigned main(){\n //GRL_3_A();\n //GRL_3_B();\n AOJ_0377();\n //ARC045_D(); \n //ARC062_F();\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 29544, "score_of_the_acc": -0.9212, "final_rank": 12 }, { "submission_id": "aoj_0377_3608190", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n//BEGIN CUT HERE\nstruct LowLink{\n int n,pos;\n vector<int> ord,low,par,blg,num;\n vector<vector<int> > G,C,T;\n \n vector<int> ap;\n vector<pair<int, int> > bs;\n\n LowLink(int n):n(n),pos(0),ord(n,-1),low(n),\n par(n,-1),blg(n,-1),num(n,1),G(n){}\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n bool is_bridge(int u,int v){\n if(ord[u]>ord[v]) swap(u,v);\n return ord[u]<low[v];\n }\n\n void dfs(int v){\n ord[v]=low[v]=pos++;\n for(int u:G[v]){\n if(u==par[v]) continue;\n if(~ord[u]){\n low[v]=min(low[v],ord[u]);\n continue;\n }\n par[u]=v;\n dfs(u);\n num[v]+=num[u];\n low[v]=min(low[v],low[u]);\n if(is_bridge(u,v)) bs.emplace_back(u,v);\n }\n }\n\n void fill_component(int v){\n C[blg[v]].emplace_back(v);\n for(int u:G[v]){\n if(~blg[u]||is_bridge(u,v)) continue;\n blg[u]=blg[v];\n fill_component(u);\n }\n }\n\n void add_component(int v,int &k){\n if(~blg[v]) return;\n blg[v]=k++;\n C.emplace_back();\n fill_component(v);\n }\n \n int build(){\n for(int i=0;i<n;i++)\n if(ord[i]<0) dfs(i);\n \n vector<int> cnt(n,0);\n for(int i=0;i<n;i++){\n int p=par[i];\n if(p<0) continue;\n if(par[p]<0) cnt[p]++;\n else if(ord[p]<=low[i]) ap.emplace_back(p);\n }\n \n for(int i=0;i<n;i++)\n if(cnt[i]>1) ap.emplace_back(i);\n\n sort(ap.begin(),ap.end());\n ap.erase(unique(ap.begin(),ap.end()),ap.end());\n\n int k=0; \n for(int i=0;i<n;i++) add_component(i,k);\n\n T.assign(k,vector<int>()); \n for(auto e:bs){\n int u=blg[e.first],v=blg[e.second];\n T[u].emplace_back(v);\n T[v].emplace_back(u);\n }\n return k;\n }\n};\n//END CUT HERE\n\nstruct UnionFind{\n int n;\n vector<int> r,p;\n UnionFind(){}\n UnionFind(int sz):n(sz),r(sz,1),p(sz,0){iota(p.begin(),p.end(),0);}\n int find(int x){\n return (x==p[x]?x:p[x]=find(p[x]));\n }\n bool same(int x,int y){\n return find(x)==find(y);\n }\n void unite(int x,int y){\n x=find(x);y=find(y);\n if(x==y) return;\n if(r[x]<r[y]) swap(x,y);\n r[x]+=r[y];\n p[y]=x;\n }\n int size(int x){\n return r[find(x)];\n }\n};\n\n//INSERT ABOVE HERE\nsigned GRL_3_A(){\n int n,m;\n scanf(\"%d %d\",&n,&m);\n LowLink G(n);\n for(int i=0;i<m;i++){\n int u,v;\n scanf(\"%d %d\",&u,&v);\n G.add_edge(u,v);\n }\n G.build();\n auto ap=G.ap;\n sort(ap.begin(),ap.end());\n for(int v:ap) printf(\"%d\\n\",v);\n return 0;\n}\n/*\n verified on 2019/03/23\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_3_A&lang=jp\n*/\nsigned GRL_3_B(){\n int n,m;\n scanf(\"%d %d\",&n,&m);\n \n LowLink G(n);\n for(int i=0;i<m;i++){\n int u,v;\n scanf(\"%d %d\",&u,&v);\n G.add_edge(u,v);\n }\n G.build();\n \n auto bs=G.bs;\n for(auto &e:bs)\n if(e.first>e.second) swap(e.first, e.second);\n \n sort(bs.begin(),bs.end());\n for(auto e:bs) printf(\"%d %d\\n\",e.first, e.second);\n \n return 0;\n}\n/*\n verified on 2019/03/23\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_3_B&lang=jp\n*/\n\nsigned ARC045_D(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int n;\n cin>>n;\n vector<int> xs(2*n+1),ys(2*n+1);\n for(int i=0;i<2*n+1;i++) cin>>xs[i]>>ys[i];\n\n vector<vector<int> > R(2*n+2),C(2*n+2);\n for(int i=0;i<2*n+1;i++) R[xs[i]].emplace_back(i);\n for(int i=0;i<2*n+1;i++) C[ys[i]].emplace_back(i);\n\n UnionFind uf(2*n+1);\n for(auto &v:R)\n for(auto u:v) uf.unite(v[0],u);\n for(auto &v:C)\n for(auto u:v) uf.unite(v[0],u);\n\n vector<int> vs;\n for(int i=0;i<2*n+1;i++){\n if(uf.find(i)!=i) continue;\n if(uf.size(i)&1) vs.emplace_back(i);\n }\n assert(!vs.empty());\n \n if(vs.size()>1u){\n for(int i=0;i<2*n+1;i++) cout<<\"NG\\n\";\n cout<<flush;\n return 0; \n }\n \n LowLink G(2*n+1);\n auto add_edge=\n [&](auto &V)->void{\n for(auto &v:V){\n if(v.empty()) continue;\n if(!uf.same(vs[0],v[0])) continue;\n if(v.size()>0u) for(auto u:v) G.add_edge(v[0],u);\n if(v.size()>1u) for(auto u:v) G.add_edge(v[1],u);\n }\n };\n add_edge(R);\n add_edge(C);\n\n G.build();\n auto ap=G.ap; \n \n vector<int> ans(2*n+1,0);\n for(int i=0;i<2*n+1;i++)\n if(uf.same(vs[0],i)) ans[i]=1;\n\n for(int v:ap){\n if(!uf.same(vs[0],v)) continue;\n for(int u:G.G[v]){\n if(G.par[u]!=v) continue; \n if(~G.par[v]&&G.ord[v]>G.low[u]) continue; \n if(G.num[u]&1) ans[v]=0;\n }\n }\n \n for(int i=0;i<2*n+1;i++) cout<<(ans[i]?\"OK\\n\":\"NG\\n\");\n cout<<flush;\n return 0;\n}\n/*\n verified on 2019/03/23\n https://atcoder.jp/contests/arc045/tasks/arc045_d\n*/\n\nsigned AOJ_0377(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int n,m;\n cin>>n>>m;\n LowLink bg(n);\n for(int i=0;i<m;i++){\n int a,b;\n cin>>a>>b;\n bg.add_edge(a,b);\n }\n int k=bg.build();\n auto& G=bg.T;\n \n vector<int> c(k);\n for(int i=0;i<k;i++) c[i]=bg.C[i].size();\n vector<vector<int> > dp(2,vector<int>(k,0));\n vector<int> used(k,0);\n function<void(int,int)> dfs=[&](int v,int p){\n if(used[v]) return;\n used[v]=1;\n dp[0][v]=0;\n dp[1][v]=c[v];\n for(int u:G[v]){\n if(u==p) continue;\n dfs(u,v);\n dp[0][v]+=max(dp[0][u],dp[1][u]);\n dp[1][v]+=dp[0][u];\n }\n return;\n };\n int ans=0;\n for(int i=0;i<k;i++){\n if(used[i]) continue;\n dfs(i,-1);\n ans+=max(dp[0][i],dp[1][i]);\n }\n cout<<ans<<endl;\n return 0;\n}\n\n/*\n verified on 2019/05/29\n http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0377\n*/\n\nsigned main(){\n //GRL_3_A();\n //GRL_3_B();\n //ARC045_D(); \n AOJ_0377(); \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 23988, "score_of_the_acc": -0.5989, "final_rank": 10 }, { "submission_id": "aoj_0377_3291347", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <stdlib.h>\n#include <stack>\n#include <set>\n#include <map>\n#include <functional>\n#include <array>\n\nusing namespace std;\nstruct LowLink {\n\tset<pair<int, int>> bridge;\n\tvector<int> articulation, ord, low;\n\tvector<bool> used;\n\tvector<vector<int>> g;\n\tint n, k = 0;\n\tLowLink(const vector<vector<int>> &g) : g(g) {\n\t\tn = g.size();\n\t\tord.resize(n, 0);\n\t\tlow.resize(n, 0);\n\t\tused.resize(n, false);\n\t}\n\tvoid dfs(int u, int prev) {\n\n\t\tused[u] = true;\n\t\tord[u] = k++;\n\t\tlow[u] = ord[u];\n\t\tbool is_articulation = false;\n\t\tint cnt = 0;\n\t\tfor (auto v : g[u]) if (v != prev) {\n\t\t\tif (!used[v]) {\n\t\t\t\tcnt++;\n\t\t\t\tdfs(v, u);\n\t\t\t\tlow[u] = min(low[u], low[v]);\n\t\t\t\tif (low[v] > ord[u]) {\n\t\t\t\t\tbridge.emplace(min(u, v), max(u, v));\n\t\t\t\t}\n\t\t\t\tif (prev != -1 && low[v] >= ord[u]) {\n\t\t\t\t\tis_articulation = true;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tlow[u] = min(low[u], ord[v]);\n\t\t\t}\n\t\t}\n\t\tif (prev == -1 && cnt > 1) is_articulation = true;\n\t\tif (is_articulation) articulation.push_back(u);\n\t}\n};\nstruct TwoEdgeConnectedComponent {\n\tint n;\n\tvector<vector<int>> g, tree;\n\tvector<int> cmp;\n\tTwoEdgeConnectedComponent(const vector<vector<int>> &g) : g(g) {\n\t\tn = (int)g.size();\n\t\tcmp.assign(n, -1);\n\t}\n\tvoid build() {\n\t\tLowLink lnk(g);\n\t\tfor (int i = 0; n > i; i++) {\n\t\t\tif(lnk.used[i] == false)\n\t\t\t\tlnk.dfs(i, -1);\n\t\t}\n\t\tint k = 0;\n\t\tfunction<void(int, int)> dfs = [&](int u, int prev) {\n\t\t\tcmp[u] = k;\n\t\t\tfor (auto v : g[u]) if (cmp[v] == -1 && lnk.bridge.count({ min(u, v), max(u, v) }) == 0) {\n\t\t\t\tdfs(v, u);\n\t\t\t}\n\t\t};\n\t\tfor (int i = 0; i < n; i++) if (cmp[i] == -1) {\n\t\t\tdfs(i, -1);\n\t\t\tk++;\n\t\t}\n\t\ttree.resize(k);\n\t\tfor (auto e : lnk.bridge) {\n\t\t\ttree[cmp[e.first]].push_back(cmp[e.second]);\n\t\t\ttree[cmp[e.second]].push_back(cmp[e.first]);\n\t\t}\n\t}\n};\n\nint main() {\n\n\tint n, m;\n\tcin >> n >> m;\n\tvector<vector<int>> g(n);\n\n\tfor (int i = 0; m > i; i++) {\n\t\tint s, t;\n\t\tcin >> s >> t;\n\t\tg[s].push_back(t);\n\t\tg[t].push_back(s);\n\t}\n\n\tTwoEdgeConnectedComponent tecc(g);\n\ttecc.build();\n\t\n\tvector<int> sz(tecc.tree.size());\n\tvector<array<int, 2>> dp(tecc.tree.size());\n\n\tfor (int i = 0; n > i; i++) {\n\t\tsz[tecc.cmp[i]]++;\n\t}\n\n\tfunction<void(int, int)> dfs = [&](int cur, int par){\n\t\tdp[cur][1] = sz[cur];\n\t\tfor (auto itr : tecc.tree[cur]) {\n\t\t\tif (itr == par) continue;\n\t\t\tdfs(itr, cur);\n\t\t\tdp[cur][0] += max(dp[itr][0], dp[itr][1]);\n\t\t\tdp[cur][1] += dp[itr][0];\n\t\t}\n\t};\n\n\tint ans = 0;\n\n\tfor (int i = 0; tecc.tree.size() > i; i++) {\n\t\tif (dp[i][1] == 0) {\n\t\t\tdfs(i, -1);\n\t\t\tans += max(dp[i][0],dp[i][1]);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 31068, "score_of_the_acc": -1.3732, "final_rank": 15 } ]
aoj_0379_cpp
Iron Bars A boy PCK had N straight iron bars, which were serially indexed. Unfortunately, the first M bars (0 ≤ M ≤ N ) among them were bent during transportation. They all suffered a perpendicular bend at one point. He is planning to make a cube using a set of bars selected using the following rules: X bars from bent ones, Y bars from straight ones, where 2X + Y = 12 . Any two bars can be jointed only at the apexes of the cube. He wants to count how many types of rectangular parallelepipeds (hereafter RP) he can make using these bars. Make a program to count out types (different shapes) of RPs that PCK can make using the following information: the number of bars and length of each one, position of the bend, and the number of bars to be used to construct an RP. Note that any two RPs similar in shape are considered identical: namely if the length of three defining sides of two RPs coincide if arranged in increasing/decreasing order (e.g., three sides of RP i and j are A_i, B_i, C_i , and A_j, B_j and C_j in increasing order, then the relations A_i = A_j, B_i = B_j , and C_i = C_j hold. Note also that the bars are sufficiently thin to allow you to consider them as idealized lines. Input The input is given in the following format. N M X Y a_1 a_2 : a_N b_1 b_2 : b_M The first line provides the total number of iron bars and bent bars, and those straight and bent bars used to construct an RP: N (6 ≤ N ≤ 6000), M (0 ≤ M ≤ N ), X (0 ≤ X ≤ 6), and Y (0 ≤ Y ≤ 12). The following relations always hold for them: 2X+Y=12 , X+Y ≤ N , X ≤ M . Each of the subsequent N lines provides the length of the i -th bar a_i (1 ≤ a_i ≤ 6000) in integers. Furthermore, each of the subsequent M lines provides the location at which the i -th bent bar suffered a perpendicular bend b_i (1 ≤ b_i ≤ 3000) in centimeters from one end of the bar (note: 1 ≤ a_i-b_i ≤ 3000). Output Output the number of constructible rectangular parallelepipeds. Sample Input 1 18 8 3 6 4 3 3 3 3 2 2 2 1 1 1 1 1 2 2 3 3 3 1 1 1 1 1 1 1 1 Sample Output 1 3
[ { "submission_id": "aoj_0379_10205452", "code_snippet": "// AOJ #379\n// Iron Bars 2025.2.9\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\nstruct FastBitset {\n vector<ull> data;\n int size;\n FastBitset() {}\n FastBitset(int n) : size(n) {\n int blocks = (n + 63) / 64;\n data.assign(blocks, 0ULL);\n }\n void init(int n) {\n size = n;\n int blocks = (n + 63) / 64;\n data.assign(blocks, 0ULL);\n }\n void set(int i) {\n data[i >> 6] |= (1ULL << (i & 63));\n }\n bool test(int i) const {\n return (data[i >> 6] >> (i & 63)) & 1ULL;\n }\n void reset() {\n fill(data.begin(), data.end(), 0ULL);\n }\n void bit_and(const FastBitset &other) {\n int sz = data.size();\n for (int i = 0; i < sz; i++)\n data[i] &= other.data[i];\n }\n FastBitset operator&(const FastBitset &other) const {\n FastBitset ret;\n ret.size = size;\n ret.data.resize(data.size());\n int sz = data.size();\n for (int i = 0; i < sz; i++)\n ret.data[i] = data[i] & other.data[i];\n return ret;\n }\n int popcount() const {\n int cnt = 0;\n for (auto &x : data)\n cnt += __builtin_popcountll(x);\n return cnt;\n }\n};\n \nstruct PairKey { int p, q; };\nstruct PairKeyHash {\n std::size_t operator()(const PairKey &pk) const {\n return ((size_t)pk.p * 6007ULL) ^ ((size_t)pk.q);\n }\n};\nstruct PairKeyEqual {\n bool operator()(const PairKey &a, const PairKey &b) const {\n return a.p == b.p && a.q == b.q;\n }\n};\n \nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n \n int N, M, X, Y;\n cin >> N >> M >> X >> Y;\n vector<int> a(N), b(M);\n for (int i = 0; i < N; i++) cin >> a[i];\n for (int i = 0; i < M; i++) cin >> b[i];\n \n const int MAXLEN = 6000;\n vector<int> straightCount(MAXLEN+1, 0);\n for (int i = M; i < N; i++) straightCount[a[i]]++;\n \n unordered_map<PairKey,int,PairKeyHash,PairKeyEqual> bentMap;\n bentMap.reserve(M*2);\n for (int i = 0; i < M; i++){\n int tot = a[i];\n int bendPos = b[i];\n int seg1 = bendPos, seg2 = tot - bendPos;\n int p = min(seg1, seg2), q = max(seg1, seg2);\n PairKey key { p, q };\n bentMap[key]++;\n }\n auto getBentCount = [&](int p, int q) -> int {\n PairKey key { p, q };\n auto it = bentMap.find(key);\n return (it == bentMap.end()) ? 0 : it->second;\n };\n \n vector<bool> candidateFlag(MAXLEN+1, false);\n for (int d = 1; d <= MAXLEN; d++){\n if(straightCount[d] > 0)\n candidateFlag[d] = true;\n }\n for(auto &entry : bentMap){\n candidateFlag[entry.first.p] = true;\n candidateFlag[entry.first.q] = true;\n }\n vector<int> cand;\n for (int d = 1; d <= MAXLEN; d++){\n if(candidateFlag[d])\n cand.push_back(d);\n }\n sort(cand.begin(), cand.end());\n int n = cand.size();\n \n vector<int> candStraight(n);\n for (int i = 0; i < n; i++){\n candStraight[i] = straightCount[cand[i]];\n }\n vector<int> selfB(n, 0);\n for (int i = 0; i < n; i++){\n selfB[i] = getBentCount(cand[i], cand[i]);\n }\n vector<vector<unsigned char>> bentVal(n);\n for (int i = 0; i < n; i++){\n bentVal[i].resize(n - i - 1, 0);\n for (int j = i + 1; j < n; j++){\n int cnt = getBentCount(cand[i], cand[j]);\n if(cnt > 5) cnt = 5;\n bentVal[i][j - i - 1] = (unsigned char) cnt;\n }\n }\n \n struct Distrib { int x12, x13, x23, r1, r2, r3; };\n vector<Distrib> Dvec;\n for (int x12 = 0; x12 <= X; x12++){\n for (int x13 = 0; x13 <= X - x12; x13++){\n int x23 = X - x12 - x13;\n if(x12 + x13 > 4) continue;\n if(x12 + x23 > 4) continue;\n if(x13 + x23 > 4) continue;\n Distrib d;\n d.x12 = x12; d.x13 = x13; d.x23 = x23;\n d.r1 = 4 - (x12 + x13);\n d.r2 = 4 - (x12 + x23);\n d.r3 = 4 - (x13 + x23);\n Dvec.push_back(d);\n }\n }\n \n int mwords = (n + 63) / 64;\n vector<FastBitset> maskFrom(n + 1, FastBitset(n));\n for (int j = 0; j <= n; j++){\n maskFrom[j].init(n);\n int startBlock = j >> 6, startOffset = j & 63;\n for (int b = startBlock; b < mwords; b++){\n ull blockVal = ~0ULL;\n if(b == startBlock)\n blockVal &= ~((1ULL << startOffset) - 1ULL);\n if(b == mwords - 1){\n int extra = mwords * 64 - n;\n if(extra > 0)\n blockVal &= ~0ULL >> extra;\n }\n maskFrom[j].data[b] = blockVal;\n }\n }\n vector<FastBitset> maskTo(n + 1, FastBitset(n));\n for (int j = 0; j <= n; j++){\n maskTo[j].init(n);\n for (int b = 0; b < mwords; b++){\n int blockStart = b * 64, blockEnd = min(n, (b + 1) * 64);\n ull bits = 0ULL;\n for (int i = blockStart; i < blockEnd; i++){\n if(i < j)\n bits |= (1ULL << (i - blockStart));\n }\n maskTo[j].data[b] = bits;\n }\n }\n \n int maxStraightThr = 12;\n vector<FastBitset> straightBS(maxStraightThr + 1, FastBitset(n));\n for (int thr = 0; thr <= maxStraightThr; thr++){\n straightBS[thr].init(n);\n for (int i = 0; i < n; i++){\n if(candStraight[i] >= thr){\n int block = i >> 6;\n int bit = i & 63;\n straightBS[thr].data[block] |= (1ULL << bit);\n }\n }\n }\n \n int maxBentThr = 6;\n vector<vector<FastBitset>> bs(n, vector<FastBitset>(maxBentThr + 1, FastBitset(n)));\n for (int i = 0; i < n; i++){\n for (int t = 0; t <= maxBentThr; t++){\n bs[i][t].init(n);\n for (int j = i + 1; j < n; j++){\n bool ok = (t == 0) ? true : (((int)bentVal[i][j - i - 1]) >= t);\n if(ok){\n int block = j >> 6;\n int bit = j & 63;\n bs[i][t].data[block] |= (1ULL << bit);\n }\n }\n }\n }\n vector<vector<FastBitset>> bentRev(n, vector<FastBitset>(maxBentThr + 1, FastBitset(n)));\n for (int j = 0; j < n; j++){\n for (int t = 0; t <= maxBentThr; t++){\n bentRev[j][t].init(n);\n for (int i = 0; i < j; i++){\n bool ok = (t == 0) ? true : (((int)bentVal[i][j - i - 1]) >= t);\n if(ok){\n int block = i >> 6;\n int bit = i & 63;\n bentRev[j][t].data[block] |= (1ULL << bit);\n }\n }\n }\n }\n \n int dSize = Dvec.size();\n ll ans = 0;\n int totalSubs = 1 << dSize;\n for (int mask = 1; mask < totalSubs; mask++){\n int bits = 0;\n int agg_R1 = 0, agg_R2 = 0, agg_R3 = 0;\n int agg_S12 = 0, agg_S23 = 0;\n int agg_S123 = Y;\n int agg_B12 = 0, agg_B13 = 0, agg_B23 = 0;\n int agg_S_AC = 0, agg_S_AB = 0;\n int agg_S_total = X;\n for (int i = 0; i < dSize; i++){\n if(mask & (1 << i)){\n bits++;\n Distrib d = Dvec[i];\n agg_R1 = max(agg_R1, d.r1);\n agg_R2 = max(agg_R2, d.r2);\n agg_R3 = max(agg_R3, d.r3);\n agg_S12 = max(agg_S12, d.r1 + d.r2);\n agg_S23 = max(agg_S23, d.r2 + d.r3);\n agg_B12 = max(agg_B12, d.x12);\n agg_B13 = max(agg_B13, d.x13);\n agg_B23 = max(agg_B23, d.x23);\n agg_S_AC = max(agg_S_AC, d.x13 + d.x23);\n agg_S_AB = max(agg_S_AB, d.x12 + d.x13);\n }\n }\n if(agg_B12 > 5 || agg_B13 > 5 || agg_B23 > 5 || agg_S_AC > 5 || agg_S_AB > 5)\n continue;\n \n ll fcount = 0;\n \n for (int i = 0; i < n; i++){\n if(candStraight[i] >= agg_S123 && selfB[i] >= agg_S_total)\n fcount++;\n }\n \n for (int i = 0; i < n; i++){\n if(candStraight[i] < agg_S12) continue;\n if(selfB[i] < agg_B12) continue;\n FastBitset bsIntersect = bs[i][agg_S_AC];\n int sz = bsIntersect.data.size();\n for (int b = 0; b < sz; b++){\n bsIntersect.data[b] &= straightBS[agg_R3].data[b];\n }\n bsIntersect.bit_and(maskFrom[i+1]);\n fcount += bsIntersect.popcount();\n }\n \n for (int j = 1; j < n; j++){\n if(candStraight[j] < agg_S23) continue;\n if(selfB[j] < agg_B23) continue;\n FastBitset bsIntersect = bentRev[j][agg_S_AB];\n int sz = bsIntersect.data.size();\n for (int b = 0; b < sz; b++){\n bsIntersect.data[b] &= straightBS[agg_R1].data[b];\n bsIntersect.data[b] &= maskTo[j].data[b];\n }\n fcount += bsIntersect.popcount();\n }\n \n for (int i = 0; i < n; i++){\n if(candStraight[i] < agg_R1) continue;\n FastBitset validJ = bs[i][agg_B12];\n int sz = validJ.data.size();\n for (int b = 0; b < sz; b++){\n validJ.data[b] &= straightBS[agg_R2].data[b];\n }\n validJ.bit_and(maskFrom[i+1]);\n for (int block = 0; block < sz; block++){\n ull bitsVal = validJ.data[block];\n while(bitsVal){\n int j = (block << 6) | __builtin_ctzll(bitsVal);\n bitsVal &= bitsVal - 1;\n FastBitset candK = bs[i][agg_B13];\n int szK = candK.data.size();\n for (int b2 = 0; b2 < szK; b2++){\n candK.data[b2] &= bs[j][agg_B23].data[b2];\n candK.data[b2] &= straightBS[agg_R3].data[b2];\n }\n candK.bit_and(maskFrom[j+1]);\n fcount += candK.popcount();\n }\n }\n }\n \n int sign = (bits % 2 == 1) ? 1 : -1;\n ans += sign * fcount;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1620, "memory_kb": 37828, "score_of_the_acc": -1.1759, "final_rank": 8 }, { "submission_id": "aoj_0379_8287888", "code_snippet": "#include <iostream>\n#include <tuple>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N, A[6009];\nint M, B[6009];\nvector<int> L1;\nvector<pair<int, int>> L2;\nint Cnt1[6009];\nint Cnt2[6009][6009];\nint X;\nint Y;\nvector<tuple<int, int, int>> Cand[7];\n\nvoid Initialize() {\n\tfor (int i = 0; i <= 6; i++) {\n\t\tfor (int j = 0; j <= 6; j++) {\n\t\t\tfor (int k = 0; k <= 6; k++) {\n\t\t\t\tif (i + j + k >= 7) continue;\n\t\t\t\tif (i + j + k == 6 && !(i == 2 && j == 2 && k == 2)) continue;\n\t\t\t\tif (i + j + k == 5 && i * j * k == 0) continue;\n\t\t\t\tCand[i + j + k].push_back(make_tuple(i, j, k));\n\t\t\t}\n\t\t}\n\t}\n}\n\n// =============================================================================== Solve when X=0\nlong long solve_Subtask1() {\n\tvector<int> Sum(6009, 0);\n\tfor (int i = 6007; i >= 0; i--) {\n\t\tSum[i] = Sum[i + 1];\n\t\tif (Cnt1[i] >= 4) Sum[i] += 1;\n\t}\n\n\t// Counting\n\tlong long Answer = 0;\n\tfor (int i = 0; i <= 6000; i++) {\n\t\tfor (int j = i; j <= 6000; j++) {\n\t\t\tbool flag = false;\n\t\t\tCnt1[i] -= 4; Cnt1[j] -= 4;\n\t\t\tif (Cnt1[i] < 0) flag = true;\n\t\t\tif (Cnt1[j] < 0) flag = true;\n\t\t\tint ways = Sum[j + 1];\n\t\t\tif (Cnt1[j] >= 4) ways += 1;\n\t\t\tif (flag == false) Answer += ways;\n\t\t\tCnt1[i] += 4; Cnt1[j] += 4;\n\t\t}\n\t}\n\treturn Answer;\n}\n\n// =============================================================================== Solve when 1<=X<=5\nbool helper(int pa, int pb, int pc) {\n\tfor (tuple<int, int, int> v : Cand[X]) {\n\t\tCnt2[pa][pb] -= get<0>(v);\n\t\tCnt2[pa][pc] -= get<1>(v);\n\t\tCnt2[pb][pc] -= get<2>(v);\n\t\tCnt1[pa] -= 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] -= 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] -= 4 - get<1>(v) - get<2>(v);\n\t\tbool flag = false;\n\t\tif (Cnt2[pa][pb] < 0) flag = true;\n\t\tif (Cnt2[pa][pc] < 0) flag = true;\n\t\tif (Cnt2[pb][pc] < 0) flag = true;\n\t\tif (Cnt1[pa] < 0) flag = true;\n\t\tif (Cnt1[pb] < 0) flag = true;\n\t\tif (Cnt1[pc] < 0) flag = true;\n\t\tCnt2[pa][pb] += get<0>(v);\n\t\tCnt2[pa][pc] += get<1>(v);\n\t\tCnt2[pb][pc] += get<2>(v);\n\t\tCnt1[pa] += 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] += 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] += 4 - get<1>(v) - get<2>(v);\n\t\tif (flag == false) return true;\n\t}\n\treturn false;\n}\n\nlong long solve_Subtask2() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L1.size(); i++) {\n\t\tfor (int j = 0; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tvec.push_back(L1[i]);\n\t\t\tvec.push_back(L2[j].first);\n\t\t\tvec.push_back(L2[j].second);\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) {\n\t\t\t\tAnswer.push_back(make_tuple(pa, pb, pc));\n\t\t\t}\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\n// =============================================================================== Solve when X=6\nlong long solve_Subtask3() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L2.size(); i++) {\n\t\tfor (int j = i; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tif (L2[i].first == L2[j].first) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].first == L2[j].second) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].first); }\n\t\t\telse if (L2[i].second == L2[j].first) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].second == L2[j].second) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].first); }\n\t\t\tif (vec.size() == 0) continue;\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) Answer.push_back(make_tuple(pa, pb, pc));\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> M >> X >> Y;\n\tfor (int i = 1; i <= N; i++) cin >> A[i];\n\tfor (int i = 1; i <= M; i++) cin >> B[i];\n\tInitialize();\n\n\t// Step 2. Precount\n\tfor (int i = 1; i <= M; i++) {\n\t\tint c1 = B[i], c2 = A[i] - B[i];\n\t\tif (c1 > c2) swap(c1, c2);\n\t\tL2.push_back(make_pair(c1, c2));\n\t\tCnt2[c1][c2] += 1;\n\t}\n\tfor (int i = M + 1; i <= N; i++) {\n\t\tL1.push_back(A[i]);\n\t\tCnt1[A[i]] += 1;\n\t}\n\tsort(L1.begin(), L1.end()); L1.erase(unique(L1.begin(), L1.end()), L1.end());\n\tsort(L2.begin(), L2.end()); L2.erase(unique(L2.begin(), L2.end()), L2.end());\n\n\t// Step 3. Output\n\tif (X == 0) cout << solve_Subtask1() << endl;\n\tif (X == 1) cout << solve_Subtask2() << endl;\n\tif (X == 2) cout << solve_Subtask2() << endl;\n\tif (X == 3) cout << solve_Subtask2() << endl;\n\tif (X == 4) cout << solve_Subtask2() << endl;\n\tif (X == 5) cout << solve_Subtask2() << endl;\n\tif (X == 6) cout << solve_Subtask3() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 62740, "score_of_the_acc": -0.6322, "final_rank": 4 }, { "submission_id": "aoj_0379_8287870", "code_snippet": "#include <iostream>\n#include <tuple>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N, A[6009];\nint M, B[6009];\nvector<int> L1;\nvector<pair<int, int>> L2;\nint Cnt1[3009];\nint Cnt2[3009][3009];\nint X;\nint Y;\nvector<tuple<int, int, int>> Cand[7];\n\nvoid Initialize() {\n\tfor (int i = 0; i <= 6; i++) {\n\t\tfor (int j = 0; j <= 6; j++) {\n\t\t\tfor (int k = 0; k <= 6; k++) {\n\t\t\t\tif (i + j + k >= 7) continue;\n\t\t\t\tif (i + j + k == 6 && !(i == 2 && j == 2 && k == 2)) continue;\n\t\t\t\tif (i + j + k == 5 && i * j * k == 0) continue;\n\t\t\t\tCand[i + j + k].push_back(make_tuple(i, j, k));\n\t\t\t}\n\t\t}\n\t}\n}\n\n// =============================================================================== Solve when X=0\nlong long solve_Subtask1() {\n\tvector<int> Sum(3009, 0);\n\tfor (int i = 3007; i >= 0; i--) {\n\t\tSum[i] = Sum[i + 1];\n\t\tif (Cnt1[i] >= 4) Sum[i] += 1;\n\t}\n\n\t// Counting\n\tlong long Answer = 0;\n\tfor (int i = 0; i <= 3000; i++) {\n\t\tfor (int j = i; j <= 3000; j++) {\n\t\t\tbool flag = false;\n\t\t\tCnt1[i] -= 4; Cnt1[j] -= 4;\n\t\t\tif (Cnt1[i] < 0) flag = true;\n\t\t\tif (Cnt1[j] < 0) flag = true;\n\t\t\tint ways = Sum[j + 1];\n\t\t\tif (Cnt1[j] >= 4) ways += 1;\n\t\t\tif (flag == false) Answer += ways;\n\t\t\tCnt1[i] += 4; Cnt1[j] += 4;\n\t\t}\n\t}\n\treturn Answer;\n}\n\n// =============================================================================== Solve when 1<=X<=5\nbool helper(int pa, int pb, int pc) {\n\tfor (tuple<int, int, int> v : Cand[X]) {\n\t\tCnt2[pa][pb] -= get<0>(v);\n\t\tCnt2[pa][pc] -= get<1>(v);\n\t\tCnt2[pb][pc] -= get<2>(v);\n\t\tCnt1[pa] -= 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] -= 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] -= 4 - get<1>(v) - get<2>(v);\n\t\tbool flag = false;\n\t\tif (Cnt2[pa][pb] < 0) flag = true;\n\t\tif (Cnt2[pa][pc] < 0) flag = true;\n\t\tif (Cnt2[pb][pc] < 0) flag = true;\n\t\tif (Cnt1[pa] < 0) flag = true;\n\t\tif (Cnt1[pb] < 0) flag = true;\n\t\tif (Cnt1[pc] < 0) flag = true;\n\t\tCnt2[pa][pb] += get<0>(v);\n\t\tCnt2[pa][pc] += get<1>(v);\n\t\tCnt2[pb][pc] += get<2>(v);\n\t\tCnt1[pa] += 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] += 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] += 4 - get<1>(v) - get<2>(v);\n\t\tif (flag == false) return true;\n\t}\n\treturn false;\n}\n\nlong long solve_Subtask2() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L1.size(); i++) {\n\t\tfor (int j = 0; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tvec.push_back(L1[i]);\n\t\t\tvec.push_back(L2[j].first);\n\t\t\tvec.push_back(L2[j].second);\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) {\n\t\t\t\tAnswer.push_back(make_tuple(pa, pb, pc));\n\t\t\t}\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\n// =============================================================================== Solve when X=6\nlong long solve_Subtask3() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L2.size(); i++) {\n\t\tfor (int j = i; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tif (L2[i].first == L2[j].first) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].first == L2[j].second) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].first); }\n\t\t\telse if (L2[i].second == L2[j].first) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].second == L2[j].second) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].first); }\n\t\t\tif (vec.size() == 0) continue;\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) Answer.push_back(make_tuple(pa, pb, pc));\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> M >> X >> Y;\n\tfor (int i = 1; i <= N; i++) cin >> A[i];\n\tfor (int i = 1; i <= M; i++) cin >> B[i];\n\tInitialize();\n\n\t// Step 2. Precount\n\tfor (int i = 1; i <= M; i++) {\n\t\tint c1 = B[i], c2 = A[i] - B[i];\n\t\tif (c1 > c2) swap(c1, c2);\n\t\tL2.push_back(make_pair(c1, c2));\n\t\tCnt2[c1][c2] += 1;\n\t}\n\tfor (int i = M + 1; i <= N; i++) {\n\t\tL1.push_back(A[i]);\n\t\tCnt1[A[i]] += 1;\n\t}\n\tsort(L1.begin(), L1.end()); L1.erase(unique(L1.begin(), L1.end()), L1.end());\n\tsort(L2.begin(), L2.end()); L2.erase(unique(L2.begin(), L2.end()), L2.end());\n\n\t// Step 3. Output\n\tif (X == 0) cout << solve_Subtask1() << endl;\n\tif (X == 1) cout << solve_Subtask2() << endl;\n\tif (X == 2) cout << solve_Subtask2() << endl;\n\tif (X == 3) cout << solve_Subtask2() << endl;\n\tif (X == 4) cout << solve_Subtask2() << endl;\n\tif (X == 5) cout << solve_Subtask2() << endl;\n\tif (X == 6) cout << solve_Subtask3() << endl;\n\treturn 0;\n}", "accuracy": 0.8478260869565217, "time_ms": 10, "memory_kb": 3732, "score_of_the_acc": -0.0018, "final_rank": 11 }, { "submission_id": "aoj_0379_8287863", "code_snippet": "#include <iostream>\n#include <tuple>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N, A[6009];\nint M, B[6009];\nvector<int> L1;\nvector<pair<int, int>> L2;\nint Cnt1[3009];\nint Cnt2[3009][3009];\nint X;\nint Y;\nvector<tuple<int, int, int>> Cand[7];\n\nvoid Initialize() {\n\tfor (int i = 0; i <= 6; i++) {\n\t\tfor (int j = 0; j <= 6; j++) {\n\t\t\tfor (int k = 0; k <= 6; k++) {\n\t\t\t\tif (i + j + k >= 7) continue;\n\t\t\t\tif (i + j + k == 6 && !(i == 2 && j == 2 && k == 2)) continue;\n\t\t\t\tif (i + j + k == 5 && i * j * k == 0) continue;\n\t\t\t\tCand[i + j + k].push_back(make_tuple(i, j, k));\n\t\t\t}\n\t\t}\n\t}\n}\n\n// =============================================================================== Solve when X=0\nlong long solve_Subtask1() {\n\tvector<int> Sum(3009, 0);\n\tfor (int i = 3007; i >= 0; i--) {\n\t\tSum[i] = Sum[i + 1];\n\t\tif (Cnt1[i] >= 4) Sum[i] += 1;\n\t}\n\n\t// Counting\n\tlong long Answer = 0;\n\tfor (int i = 0; i <= 3000; i++) {\n\t\tfor (int j = i; j <= 3000; j++) {\n\t\t\tbool flag = false;\n\t\t\tCnt1[i] -= 4; Cnt1[j] -= 4;\n\t\t\tif (Cnt1[i] < 0) flag = true;\n\t\t\tif (Cnt1[j] < 0) flag = true;\n\t\t\tint ways = Sum[j + 1];\n\t\t\tif (Cnt1[j] >= 4) ways += 1;\n\t\t\tif (flag == false) Answer += ways;\n\t\t\tCnt1[i] += 4; Cnt1[j] += 4;\n\t\t}\n\t}\n\treturn Answer;\n}\n\n// =============================================================================== Solve when 1<=X<=5\nbool helper(int pa, int pb, int pc) {\n\tfor (tuple<int, int, int> v : Cand[X]) {\n\t\tCnt2[pa][pb] -= get<0>(v);\n\t\tCnt2[pa][pc] -= get<1>(v);\n\t\tCnt2[pb][pc] -= get<2>(v);\n\t\tCnt1[pa] -= 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] -= 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] -= 4 - get<1>(v) - get<2>(v);\n\t\tbool flag = false;\n\t\tif (Cnt2[pa][pb] < 0) flag = true;\n\t\tif (Cnt2[pa][pc] < 0) flag = true;\n\t\tif (Cnt2[pb][pc] < 0) flag = true;\n\t\tif (Cnt1[pa] < 0) flag = true;\n\t\tif (Cnt1[pb] < 0) flag = true;\n\t\tif (Cnt1[pc] < 0) flag = true;\n\t\tCnt2[pa][pb] += get<0>(v);\n\t\tCnt2[pa][pc] += get<1>(v);\n\t\tCnt2[pb][pc] += get<2>(v);\n\t\tCnt1[pa] += 4 - get<0>(v) - get<1>(v);\n\t\tCnt1[pb] += 4 - get<0>(v) - get<2>(v);\n\t\tCnt1[pc] += 4 - get<1>(v) - get<2>(v);\n\t\tif (flag == false) return true;\n\t}\n\treturn false;\n}\n\nlong long solve_Subtask2() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L1.size(); i++) {\n\t\tfor (int j = 0; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tvec.push_back(L1[i]);\n\t\t\tvec.push_back(L2[j].first);\n\t\t\tvec.push_back(L2[j].second);\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) {\n\t\t\t\tAnswer.push_back(make_tuple(pa, pb, pc));\n\t\t\t}\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\n// =============================================================================== Solve when X=6\nlong long solve_Subtask3() {\n\tlong long ways = 0;\n\tvector<tuple<int, int, int>> Answer;\n\tfor (int i = 0; i < L2.size(); i++) {\n\t\tfor (int j = i + 1; j < L2.size(); j++) {\n\t\t\tvector<int> vec;\n\t\t\tif (L2[i].first == L2[j].first) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].first == L2[j].second) { vec.push_back(L2[i].first); vec.push_back(L2[i].second); vec.push_back(L2[j].first); }\n\t\t\telse if (L2[i].second == L2[j].first) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].second); }\n\t\t\telse if (L2[i].second == L2[j].second) { vec.push_back(L2[i].second); vec.push_back(L2[i].first); vec.push_back(L2[j].first); }\n\t\t\tif (vec.size() == 0) continue;\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\tint pa = vec[0], pb = vec[1], pc = vec[2];\n\t\t\tif (helper(pa, pb, pc) == true) Answer.push_back(make_tuple(pa, pb, pc));\n\t\t}\n\t}\n\tsort(Answer.begin(), Answer.end());\n\tAnswer.erase(unique(Answer.begin(), Answer.end()), Answer.end());\n\treturn (long long)Answer.size();\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> M >> X >> Y;\n\tfor (int i = 1; i <= N; i++) cin >> A[i];\n\tfor (int i = 1; i <= M; i++) cin >> B[i];\n\tInitialize();\n\n\t// Step 2. Precount\n\tfor (int i = 1; i <= M; i++) {\n\t\tint c1 = B[i], c2 = A[i] - B[i];\n\t\tif (c1 > c2) swap(c1, c2);\n\t\tL2.push_back(make_pair(c1, c2));\n\t\tCnt2[c1][c2] += 1;\n\t}\n\tfor (int i = M + 1; i <= N; i++) {\n\t\tL1.push_back(A[i]);\n\t\tCnt1[A[i]] += 1;\n\t}\n\tsort(L1.begin(), L1.end()); L1.erase(unique(L1.begin(), L1.end()), L1.end());\n\tsort(L2.begin(), L2.end()); L2.erase(unique(L2.begin(), L2.end()), L2.end());\n\n\t// Step 3. Output\n\tif (X == 0) cout << solve_Subtask1() << endl;\n\tif (X == 1) cout << solve_Subtask2() << endl;\n\tif (X == 2) cout << solve_Subtask2() << endl;\n\tif (X == 3) cout << solve_Subtask2() << endl;\n\tif (X == 4) cout << solve_Subtask2() << endl;\n\tif (X == 5) cout << solve_Subtask2() << endl;\n\tif (X == 6) cout << solve_Subtask3() << endl;\n\treturn 0;\n}", "accuracy": 0.17391304347826086, "time_ms": 10, "memory_kb": 3380, "score_of_the_acc": 0, "final_rank": 12 }, { "submission_id": "aoj_0379_4981345", "code_snippet": "#include <tuple>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nbool flag[7][7][7][7][7][7];\nint main() {\n\tint N, M, X, Y;\n\tcin >> N >> M >> X >> Y;\n\tvector<int> A(N), B(M);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> A[i];\n\t}\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin >> B[i];\n\t}\n\tif (X == 0) {\n\t\tint maxlen = *max_element(A.begin(), A.end());\n\t\tvector<int> ca(maxlen + 1);\n\t\tfor (int i = M; i < N; ++i) {\n\t\t\t++ca[A[i]];\n\t\t}\n\t\tlong long ans = 0;\n\t\tfor (int i = 1; i <= maxlen; ++i) {\n\t\t\tfor (int j = 1; j <= maxlen; ++j) {\n\t\t\t\tif (i != j && ca[i] >= 8 && ca[j] >= 4) {\n\t\t\t\t\t++ans;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int i = 1; i <= maxlen; ++i) {\n\t\t\tif (ca[i] >= 12) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t}\n\t\tint fourcnt = 0;\n\t\tfor (int i = 1; i <= maxlen; ++i) {\n\t\t\tif (ca[i] >= 4) {\n\t\t\t\t++fourcnt;\n\t\t\t}\n\t\t}\n\t\tans += 1LL * fourcnt * (fourcnt - 1) * (fourcnt - 2) / 6;\n\t\tcout << ans << endl;\n\t\treturn 0;\n\t}\n\telse {\n\t\tfor (int x = 0; x <= 4; ++x) {\n\t\t\tfor (int y = 0; y <= 4; ++y) {\n\t\t\t\tfor (int z = 0; z <= 4; ++z) {\n\t\t\t\t\tfor (int xy = 0; xy <= 4; ++xy) {\n\t\t\t\t\t\tfor (int xz = 0; xz <= 4; ++xz) {\n\t\t\t\t\t\t\tfor (int yz = 0; yz <= 4; ++yz) {\n\t\t\t\t\t\t\t\tfor (int i = 0; i <= xy; ++i) {\n\t\t\t\t\t\t\t\t\tfor (int j = 0; j <= xz; ++j) {\n\t\t\t\t\t\t\t\t\t\tfor (int k = 0; k <= yz; ++k) {\n\t\t\t\t\t\t\t\t\t\t\tif (i + j + k != X) continue;\n\t\t\t\t\t\t\t\t\t\t\tint rx = 4 - i - j, ry = 4 - i - k, rz = 4 - j - k;\n\t\t\t\t\t\t\t\t\t\t\tif (rx >= 0 && ry >= 0 && rz >= 0 && rx <= x && ry <= y && rz <= z) {\n\t\t\t\t\t\t\t\t\t\t\t\tflag[x][y][z][xy][xz][yz] = true;\n\t\t\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint maxlen = 0;\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tif (B[i] > A[i] - B[i]) {\n\t\t\t\tB[i] = A[i] - B[i];\n\t\t\t}\n\t\t\tmaxlen = max(maxlen, A[i] - B[i]);\n\t\t}\n\t\tfor (int i = M; i < N; ++i) {\n\t\t\tmaxlen = max(maxlen, A[i]);\n\t\t}\n\t\tvector<vector<int> > tbl(maxlen + 1, vector<int>(maxlen + 1));\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\t++tbl[B[i]][A[i] - B[i]];\n\t\t}\n\t\tvector<int> ca(maxlen + 1);\n\t\tfor (int i = M; i < N; ++i) {\n\t\t\tif (A[i] <= maxlen) {\n\t\t\t\t++ca[A[i]];\n\t\t\t}\n\t\t}\n\t\t// count (A, B, C) where A != B, B != C and C != A\n\t\tvector<tuple<short, short, short> > g;\n\t\tfor (int i = 0; i < M; ++i) {\n\t\t\tif (B[i] == A[i] - B[i]) continue;\n\t\t\tfor (int j = 1; j <= maxlen; ++j) {\n\t\t\t\tif (B[i] != j && A[i] - B[i] != j) {\n\t\t\t\t\tvector<int> arr = { B[i], A[i] - B[i], j };\n\t\t\t\t\tif (arr[0] > arr[1]) swap(arr[0], arr[1]);\n\t\t\t\t\tif (arr[0] > arr[2]) swap(arr[0], arr[2]);\n\t\t\t\t\tif (arr[1] > arr[2]) swap(arr[1], arr[2]);\n\t\t\t\t\tg.push_back(make_tuple(arr[0], arr[1], arr[2]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(g.begin(), g.end());\n\t\tg.erase(unique(g.begin(), g.end()), g.end());\n\t\tint ans = 0;\n\t\tfor (tuple<short, short, short> i : g) {\n\t\t\tint x = get<0>(i), y = get<1>(i), z = get<2>(i);\n\t\t\tif (flag[min(ca[x], 4)][min(ca[y], 4)][min(ca[z], 4)][min(tbl[x][y], 4)][min(tbl[x][z], 4)][min(tbl[y][z], 4)]) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t}\n\t\t// count (A, A, B) where A != B\n\t\tfor (int i = 1; i <= maxlen; ++i) {\n\t\t\tfor (int j = 1; j <= maxlen; ++j) {\n\t\t\t\tif (i == j) continue;\n\t\t\t\tint ct = min(tbl[min(i, j)][max(i, j)], 4);\n\t\t\t\tfor (int k = 0; k <= ct && k <= X; ++k) {\n\t\t\t\t\tint ra = 8 - k, rb = 4 - k;\n\t\t\t\t\tif (tbl[i][i] < X - k || ra < 2 * (X - k)) continue;\n\t\t\t\t\tra -= 2 * (X - k);\n\t\t\t\t\tif (ca[i] >= ra && ca[j] >= rb) {\n\t\t\t\t\t\t++ans;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t// count (A, A, A)\n\t\tfor (int i = 1; i <= maxlen; ++i) {\n\t\t\tif (tbl[i][i] >= X && ca[i] >= Y) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1410, "memory_kb": 199268, "score_of_the_acc": -1.8696, "final_rank": 10 }, { "submission_id": "aoj_0379_4958619", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 9223372036854775807\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 6005\n\nstruct Info{\n\n\tint small,large;\n};\nint N,M,X,Y;\nint input[SIZE];\nint num_A[SIZE],num_B[3005][SIZE];\nInfo info[SIZE];\nmap<ll,bool> MAP;\n\n\n\nint main(){\n\n\tscanf(\"%d %d %d %d\",&N,&M,&X,&Y);\n\n\tint minimum = BIG_NUM,maximum = -BIG_NUM;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&input[i]);\n\t\tmaximum = max(maximum,input[i]);\n\t}\n\n\tfor(int i = 0; i <= maximum; i++){\n\n\t\tnum_A[i] = 0;\n\t}\n\tfor(int i = 0; i <= (maximum+1)/2; i++){\n\t\tfor(int k = 0; k <= maximum; k++){\n\t\t\tnum_B[i][k] = 0;\n\t\t}\n\t}\n\n\tint tmp;\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\tnum_B[min(tmp,input[i]-tmp)][max(tmp,input[i]-tmp)]++;\n\t\tminimum = min(minimum,min(tmp,input[i]-tmp));\n\n\t\tinfo[i].small = min(tmp,input[i]-tmp);\n\t\tinfo[i].large = max(tmp,input[i]-tmp);\n\t}\n\tfor(int i = M; i < N; i++){\n\n\t\tnum_A[input[i]]++;\n\t\tminimum = min(minimum,input[i]);\n\t}\n\n\t//直方体\n\tll ans = 0;\n\tfor(int len = minimum; len <= maximum; len++){\n\n\t\tif(X == 0){\n\n\t\t\tif(num_A[len] >= 12)ans++;\n\n\t\t}else{\n\t\t\tif(len > (maximum+1)/2)break;\n\t\t\tif(num_A[len] >= Y && num_B[len][len] >= X)ans++;\n\t\t}\n\t}\n\n\t//2辺が同じ\n\tfor(int p = minimum; p <= maximum; p++){\n\t\tfor(int q = minimum; q <= maximum; q++){\n\t\t\tif(q == p)continue;\n\n\t\t\t//p8辺,q4辺\n\t\t\tif(X == 0){ //全てまっすぐな棒\n\n\t\t\t\tif(num_A[p] >= 8 && num_A[q] >= 4){\n\n\t\t\t\t\tans++;\n\t\t\t\t}\n\n\t\t\t}else{\n\n\t\t\t\tif(p > (maximum+1)/2)break;\n\n\t\t\t\tfor(int pp = 0; pp <= X; pp++){ //折れ曲がり辺はppまたはpq\n\n\t\t\t\t\tif(num_B[p][p] < pp)continue;\n\n\t\t\t\t\tint pq = X-pp;\n\n\t\t\t\t\tif(num_B[min(p,q)][max(p,q)] < pq)continue;\n\n\t\t\t\t\tint num_p = 2*pp+pq;\n\t\t\t\t\tint num_q = pq;\n\n\t\t\t\t\tif(num_p > 8 || num_q > 4)continue;\n\n\t\t\t\t\tint rest_p = 8-num_p;\n\t\t\t\t\tint rest_q = 4-num_q;\n\n\t\t\t\t\tif(num_A[p] >= rest_p && num_A[q] >= rest_q){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t\tbreak; //2回以上計上しないようにする\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//3辺異なる\n\tif(X == 0){\n\n\t\tll num = 0;\n\n\t\tfor(int i = minimum; i <= maximum; i++){\n\t\t\tif(num_A[i] >= 4)num++;\n\t\t}\n\n\t\tans += ((num)*(num-1)*(num-2))/6;\n\n\t}else{\n\n\t\tint work[3];\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tif(info[i].small == info[i].large)continue;\n\n\t\t\tfor(int p = minimum; p <= maximum; p++){\n\t\t\t\tif(p == info[i].small || p == info[i].large)continue;\n\n\t\t\t\twork[0] = info[i].small;\n\t\t\t\twork[1] = info[i].large;\n\t\t\t\twork[2] = p;\n\t\t\t\tsort(work,work+3);\n\n\t\t\t\tll tmp_code = work[0]*1000000000+work[1]*10000+work[2];\n\n\t\t\t\tauto at = MAP.find(tmp_code);\n\t\t\t\tif(at != MAP.end())continue;\n\n\t\t\t\tbool FLG = false;\n\n\t\t\t\t//work[0]4本、work[1]4本,work[2]4本\n\t\t\t\tfor(int a = 0; a <= min(4,X); a++){ //work[0]&work[1]\n\t\t\t\t\tif(num_B[work[0]][work[1]] < a)continue;\n\t\t\t\t\tfor(int b = 0; b <= min(4,X); b++){ //work[0]&work[2]\n\t\t\t\t\t\tif(b+a > min(4,X))break;\n\t\t\t\t\t\tif(num_B[work[0]][work[2]] < b)continue;\n\t\t\t\t\t\tint c = X-(a+b); //work[1]&work[2]\n\t\t\t\t\t\tif(num_B[work[1]][work[2]] < c)continue;\n\n\t\t\t\t\t\tint rest_0 = 4-(a+b);\n\t\t\t\t\t\tif(rest_0 < 0)continue;\n\n\t\t\t\t\t\tint rest_1 = 4-(a+c);\n\t\t\t\t\t\tif(rest_1 < 0)continue;\n\n\t\t\t\t\t\tint rest_2 = 4-(b+c);\n\t\t\t\t\t\tif(rest_2 < 0)continue;\n\n\t\t\t\t\t\tif(num_A[work[0]] >= rest_0 && num_A[work[1]] >= rest_1 &&\n\t\t\t\t\t\t\t\tnum_A[work[2]] >= rest_2){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(FLG)break;\n\t\t\t\t}\n\n\t\t\t\tif(FLG){\n\t\t\t\t\tans++;\n\t\t\t\t\tMAP[tmp_code] = true;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 73616, "score_of_the_acc": -0.5759, "final_rank": 2 }, { "submission_id": "aoj_0379_4958617", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 9223372036854775807\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 6005\n\nstruct Info{\n\n\tint small,large;\n};\nint N,M,X,Y;\nint input[SIZE];\nint num_A[SIZE],num_B[3005][SIZE];\nInfo info[SIZE];\nmap<ll,bool> MAP;\n\n\n\nint main(){\n\n\tscanf(\"%d %d %d %d\",&N,&M,&X,&Y);\n\n\tint minimum = BIG_NUM,maximum = -BIG_NUM;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&input[i]);\n\t\tmaximum = max(maximum,input[i]);\n\t}\n\n\tfor(int i = 0; i <= maximum; i++){\n\n\t\tnum_A[i] = 0;\n\t}\n\tfor(int i = 0; i <= (maximum+1)/2; i++){\n\t\tfor(int k = 0; k <= maximum; k++){\n\t\t\tnum_B[i][k] = 0;\n\t\t}\n\t}\n\n\tint tmp;\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d\",&tmp);\n\t\tnum_B[min(tmp,input[i]-tmp)][max(tmp,input[i]-tmp)]++;\n\t\tminimum = min(minimum,min(tmp,input[i]-tmp));\n\n\t\tinfo[i].small = min(tmp,input[i]-tmp);\n\t\tinfo[i].large = max(tmp,input[i]-tmp);\n\t}\n\tfor(int i = M; i < N; i++){\n\n\t\tnum_A[input[i]]++;\n\t\tminimum = min(minimum,input[i]);\n\t}\n\n\t//直方体\n\tll ans = 0;\n\tfor(int len = minimum; len <= maximum; len++){\n\n\t\tif(X == 0){\n\n\t\t\tif(num_A[len] >= 12)ans++;\n\n\t\t}else{\n\t\t\tif(len > (maximum+1)/2)break;\n\t\t\tif(num_A[len] >= Y && num_B[len][len] >= X)ans++;\n\t\t}\n\t}\n\n\t//printf(\"直方体:ans:%lld\\n\",ans);\n\n\t//2辺が同じ\n\tfor(int p = minimum; p <= maximum; p++){\n\t\tfor(int q = minimum; q <= maximum; q++){\n\t\t\tif(q == p)continue;\n\n\t\t\t//p8辺,q4辺\n\t\t\tif(X == 0){ //全てまっすぐな棒\n\n\t\t\t\tif(num_A[p] >= 8 && num_A[q] >= 4){\n\n\t\t\t\t\tans++;\n\t\t\t\t}\n\n\t\t\t}else{\n\n\t\t\t\tif(p > (maximum+1)/2)break;\n\n\t\t\t\tfor(int pp = 0; pp <= X; pp++){ //折れ曲がり辺はppまたはpq\n\n\t\t\t\t\tif(num_B[p][p] < pp)continue;\n\n\t\t\t\t\tint pq = X-pp;\n\n\t\t\t\t\tif(num_B[min(p,q)][max(p,q)] < pq)continue;\n\n\t\t\t\t\tint num_p = 2*pp+pq;\n\t\t\t\t\tint num_q = pq;\n\n\t\t\t\t\tif(num_p > 8 || num_q > 4)continue;\n\n\t\t\t\t\tint rest_p = 8-num_p;\n\t\t\t\t\tint rest_q = 4-num_q;\n\n\t\t\t\t\tif(num_A[p] >= rest_p && num_A[q] >= rest_q){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t\tbreak; //2回以上計上しないようにする\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//printf(\"2片々:ans:%lld\\n\",ans);\n\n\t//3辺異なる\n\tif(X == 0){\n\n\t\tll num = 0;\n\n\t\tfor(int i = minimum; i <= maximum; i++){\n\t\t\tif(num_A[i] >= 4)num++;\n\t\t}\n\n\t\tans += ((num)*(num-1)*(num-2))/6;\n\n\t}else{\n\n\t\tint work[3];\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tif(info[i].small == info[i].large)continue;\n\n\t\t\tfor(int p = minimum; p <= maximum; p++){\n\t\t\t\tif(p == info[i].small || p == info[i].large)continue;\n\n\t\t\t\twork[0] = info[i].small;\n\t\t\t\twork[1] = info[i].large;\n\t\t\t\twork[2] = p;\n\t\t\t\tsort(work,work+3);\n\n\t\t\t\tll tmp_code = work[0]*1000000000+work[1]*10000+work[2];\n\n\t\t\t\tauto at = MAP.find(tmp_code);\n\t\t\t\tif(at != MAP.end())continue;\n\n\t\t\t\tbool FLG = false;\n\n\t\t\t\t//work[0]4本、work[1]4本,work[2]4本\n\t\t\t\tfor(int a = 0; a <= min(4,X); a++){ //work[0]&work[1]\n\t\t\t\t\tif(num_B[work[0]][work[1]] < a)continue;\n\t\t\t\t\tfor(int b = 0; b <= min(4,X); b++){ //work[0]&work[2]\n\t\t\t\t\t\tif(b+a > min(4,X))break;\n\t\t\t\t\t\tif(num_B[work[0]][work[2]] < b)continue;\n\t\t\t\t\t\tint c = X-(a+b); //work[1]&work[2]\n\t\t\t\t\t\tif(num_B[work[1]][work[2]] < c)continue;\n\n\t\t\t\t\t\tint rest_0 = 4-(a+b);\n\t\t\t\t\t\tif(rest_0 < 0)continue;\n\n\t\t\t\t\t\tint rest_1 = 4-(a+c);\n\t\t\t\t\t\tif(rest_1 < 0)continue;\n\n\t\t\t\t\t\tint rest_2 = 4-(b+c);\n\t\t\t\t\t\tif(rest_2 < 0)continue;\n\n\t\t\t\t\t\tif(num_A[work[0]] >= rest_0 && num_A[work[1]] >= rest_1 &&\n\t\t\t\t\t\t\t\tnum_A[work[2]] >= rest_2){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif(FLG)break;\n\t\t\t\t}\n\n\t\t\t\tif(FLG){\n\t\t\t\t\tans++;\n\t\t\t\t\tMAP[tmp_code] = true;\n\t\t\t\t\t//printf(\"文字:%s\\n\",tmp_str.c_str());\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 73628, "score_of_the_acc": -0.576, "final_rank": 3 }, { "submission_id": "aoj_0379_4891702", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int n, m, x, y;\n cin >> n >> m >> x >> y;\n vector<int> A(n), B(m);\n for (auto &&i : A) scanf(\"%d\", &i);\n for (auto &&i : B) scanf(\"%d\", &i);\n int M = 6000;\n vector<int> cnt(M+1);\n vector<vector<int>> cntl(M+1, vector<int>(M+1, 0));\n for (int i = 0; i < n; ++i) {\n if(i < m){\n if(A[i] != B[i]*2) cntl[B[i]][A[i]-B[i]]++;\n cntl[A[i]-B[i]][B[i]]++;\n }else {\n cnt[A[i]]++;\n }\n }\n ll ans = 0;\n for (int i = 1; i <= M; ++i) { // (i, i, i)\n if(cnt[i] >= y && cntl[i][i] >= x) ans++;\n }\n for (int i = 1; i <= M; ++i) {\n for (int j = 1; j <= M; ++j) { // (i, i, j)\n if(i == j) continue;\n int ok = 0;\n for (int k = max(0, x-4); k <= min(x, 8-x); ++k) {\n if(cntl[i][i] >= k && cntl[i][j] >= x-k && cnt[i] >= 8-x-k && cnt[j] >= 4-x+k){\n ok = 1;\n break;\n }\n }\n ans += ok;\n }\n }\n if(x == 0){\n ll c = 0;\n for (int i = 1; i <= M; ++i) c += cnt[i] >= 4;\n cout << ans + c*(c-1)*(c-2)/6 << \"\\n\";\n return 0;\n }\n set<ll> v;\n for (int i = 0; i < m; ++i) {\n if(B[i]*2 == A[i]) continue;\n int a = B[i], b = A[i]-B[i];\n for (int c = 1; c <= M; ++c) { // (a, b-a, j)\n if(a == c || b == c) continue;\n for (int p = max(1, x-4); p <= min(4, x); ++p) {\n for (int q = max(0, x-4); p+q <= min(4, x); ++q) {\n if(cntl[a][b] >= p && cntl[b][c] >= q && cntl[c][a] >= x-p-q && cnt[a] >= 4-x+q && cnt[b] >= 4-p-q && cnt[c] >= 4-x+p){\n int aa = min({a, b, c}), cc = max({a, b, c}), bb = a+b+c-aa-cc;\n v.emplace(aa+bb*10000LL+cc*100000000LL);\n }\n }\n }\n }\n }\n cout << ans + v.size() << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 144580, "score_of_the_acc": -1.0749, "final_rank": 6 }, { "submission_id": "aoj_0379_4891698", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int n, m, x, y;\n cin >> n >> m >> x >> y;\n vector<int> A(n), B(m);\n for (auto &&i : A) scanf(\"%d\", &i);\n for (auto &&i : B) scanf(\"%d\", &i);\n int M = 6000;\n vector<int> cnt(M+1);\n vector<vector<int>> cntl(M+1, vector<int>(M+1, 0));\n for (int i = 0; i < n; ++i) {\n if(i < m){\n cntl[B[i]][A[i]-B[i]]++;\n cntl[A[i]-B[i]][B[i]]++;\n }else {\n cnt[A[i]]++;\n }\n }\n ll ans = 0;\n for (int i = 1; i <= M; ++i) { // (i, i, i)\n if(cnt[i] >= y && cntl[i][i] >= x) ans++;\n }\n for (int i = 1; i <= M; ++i) {\n for (int j = 1; j <= M; ++j) { // (i, i, j)\n if(i == j) continue;\n int ok = 0;\n for (int k = max(0, x-4); k <= min(x, 8-x); ++k) {\n if(cntl[i][i] >= k && cntl[i][j] >= x-k && cnt[i] >= 8-x-k && cnt[j] >= 4-x+k){\n ok = 1;\n break;\n }\n }\n ans += ok;\n }\n }\n if(x == 0){\n ll c = 0;\n for (int i = 1; i <= M; ++i) c += cnt[i] >= 4;\n cout << ans + c*(c-1)*(c-2)/6 << \"\\n\";\n return 0;\n }\n set<ll> v;\n for (int i = 0; i < m; ++i) {\n if(B[i]*2 == A[i]) continue;\n int a = B[i], b = A[i]-B[i];\n for (int c = 1; c <= M; ++c) { // (a, b-a, j)\n if(a == c || b == c) continue;\n for (int p = max(1, x-4); p <= min(4, x); ++p) {\n for (int q = max(0, x-4); p+q <= min(4, x); ++q) {\n if(cntl[a][b] >= p && cntl[b][c] >= q && cntl[c][a] >= x-p-q && cnt[a] >= 4-x+q && cnt[b] >= 4-p-q && cnt[c] >= 4-x+p){\n int aa = min({a, b, c}), cc = max({a, b, c}), bb = a+b+c-aa-cc;\n v.emplace(aa+bb*10000LL+cc*100000000LL);\n }\n }\n }\n }\n }\n cout << ans + v.size() << \"\\n\";\n return 0;\n}", "accuracy": 0.021739130434782608, "time_ms": 120, "memory_kb": 144076, "score_of_the_acc": -0.7866, "final_rank": 20 }, { "submission_id": "aoj_0379_2686345", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint N, M, X, Y;\nvector<int> A, B;\nint D[6001], E[6001][6001];\n\nint combination(auto n, auto r) {\n if(n < r) return 0;\n auto res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nint straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n if( 8 <= i) ++eight;\n if( 4 <= i) ++four;\n }\n return combination(four, 3) + combination(eight, 1) * combination(four - 1, 1) + combination(twelve, 1);\n}\n\nvector<vector<int>> split() {\n static vector<vector<int>> memo;\n if(!memo.empty()) return memo;\n vector<vector<int>> res;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) res.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo = res;\n}\n\nbool cube(auto x) {\n if(E[x][x] < X) return false;\n if(2 * X + D[x] < 12) return false;\n return true;\n}\n\nbool cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return false;\n if(2 * E[x][x] + E[x][y] + D[x] < 8) return false;\n if(E[x][y] + D[y] < 4) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 < 2 * i + j) continue;\n if(4 < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return false;\n if(E[x][y] + D[x] < 4) return false;\n if(E[x][y] + 2 * E[y][y] + D[y] < 8) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 < i) continue;\n if(8 < i + 2 * j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return false;\n if(E[x][y] + E[x][z] + D[x] < 4) return false;\n if(E[x][z] + E[y][z] + D[z] < 4) return false;\n if(E[x][y] + E[y][z] + D[y] < 4) return false;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 < a || 4 < b || 4 < c) continue;\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return true;\n }\n return false;\n}\n\nint solve() {\n auto res = 0;\n set<long long> used;\n auto memo = [](const auto& L) {return L[0] + 1e4*L[1] + 1e8*L[2];};\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n bool ok;\n if(L[0] == L[2]) ok = cube(L[0]);\n else if(L[0] == L[1]) ok = cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) ok = cuboidB(L[0], L[1]);\n else ok = cuboidC(L[0], L[1], L[2]);\n\n if(!ok) continue;\n if(used.count(memo(L))) continue;\n used.emplace(memo(L));\n ++res;\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 9616, "score_of_the_acc": -0.4418, "final_rank": 1 }, { "submission_id": "aoj_0379_2686344", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nint combination(auto n, auto r) {\n if(n < r) return 0;\n auto res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nint straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n if( 8 <= i) ++eight;\n if( 4 <= i) ++four;\n }\n return combination(four, 3) + combination(eight, 1) * combination(four - 1, 1) + combination(twelve, 1);\n}\n\nvector<vector<int>> split() {\n static vector<vector<int>> memo;\n if(!memo.empty()) return memo;\n vector<vector<int>> res;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) res.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo = res;\n}\n\nbool cube(auto x) {\n if(E[x][x] < X) return false;\n if(2 * X + D[x] < 12) return false;\n return true;\n}\n\nbool cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return false;\n if(2 * E[x][x] + E[x][y] + D[x] < 8) return false;\n if(E[x][y] + D[y] < 4) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 < 2 * i + j) continue;\n if(4 < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return false;\n if(E[x][y] + D[x] < 4) return false;\n if(E[x][y] + 2 * E[y][y] + D[y] < 8) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 < i) continue;\n if(8 < i + 2 * j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return false;\n if(E[x][y] + E[x][z] + D[x] < 4) return false;\n if(E[x][z] + E[y][z] + D[z] < 4) return false;\n if(E[x][y] + E[y][z] + D[y] < 4) return false;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 < a || 4 < b || 4 < c) continue;\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return true;\n }\n return false;\n}\n\nint solve() {\n auto res = 0;\n set<long long> used;\n auto memo = [](const auto& L) {return L[0] + 1e4*L[1] + 1e8*L[2];};\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n bool ok;\n if(L[0] == L[2]) ok = cube(L[0]);\n else if(L[0] == L[1]) ok = cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) ok = cuboidB(L[0], L[1]);\n else ok = cuboidC(L[0], L[1], L[2]);\n\n if(!ok) continue;\n if(used.count(memo(L))) continue;\n used.emplace(memo(L));\n ++res;\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 144372, "score_of_the_acc": -1.1856, "final_rank": 9 }, { "submission_id": "aoj_0379_2686340", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n if( 8 <= i) ++eight;\n if( 4 <= i) ++four;\n }\n return combination(four, 3) + combination(eight, 1) * combination(four - 1, 1) + combination(twelve, 1);\n}\n\nvector<vector<int>> split() {\n static vector<vector<int>> memo;\n if(!memo.empty()) return memo;\n vector<vector<int>> res;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) res.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo = res;\n}\n\nbool cube(auto x) {\n if(E[x][x] < X) return false;\n if(2 * X + D[x] < 12) return false;\n return true;\n}\n\nbool cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return false;\n if(2 * E[x][x] + E[x][y] + D[x] < 8) return false;\n if(E[x][y] + D[y] < 4) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 < 2 * i + j) continue;\n if(4 < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return false;\n if(E[x][y] + D[x] < 4) return false;\n if(E[x][y] + 2 * E[y][y] + D[y] < 8) return false;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 < i) continue;\n if(8 < i + 2 * j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return true;\n }\n return false;\n}\n\nbool cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return false;\n if(E[x][y] + E[x][z] + D[x] < 4) return false;\n if(E[x][z] + E[y][z] + D[z] < 4) return false;\n if(E[x][y] + E[y][z] + D[y] < 4) return false;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 < a || 4 < b || 4 < c) continue;\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return true;\n }\n return false;\n}\n\nLL solve() {\n auto res = 0;\n set<LL> used;\n auto memo = [](const auto& L) {return L[0] + 1e4*L[1] + 1e8*L[2];};\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n bool ok;\n if(L[0] == L[2]) ok = cube(L[0]);\n else if(L[0] == L[1]) ok = cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) ok = cuboidB(L[0], L[1]);\n else ok = cuboidC(L[0], L[1], L[2]);\n\n if(!ok) continue;\n if(used.count(memo(L))) continue;\n used.emplace(memo(L));\n ++res;\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 144284, "score_of_the_acc": -1.1603, "final_rank": 7 }, { "submission_id": "aoj_0379_2677561", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n if( 8 <= i) ++eight;\n if( 4 <= i) ++four;\n }\n return combination(four, 3) + combination(eight, 1) * combination(four - 1, 1) + combination(twelve, 1);\n}\n\nvector<vector<int>> split(auto x) {\n vector<vector<int>> res;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) res.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(x, 0);\n return res;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * X + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split(X)) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 < a || 4 < b || 4 < c) continue;\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.17391304347826086, "time_ms": 50, "memory_kb": 145936, "score_of_the_acc": -0.7526, "final_rank": 13 }, { "submission_id": "aoj_0379_2676437", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n if( 8 <= i) ++eight;\n if( 4 <= i) ++four;\n }\n return combination(four, 3) + combination(eight, 1) * combination(four - 1, 1) + combination(twelve, 1);\n}\n\nvector<vector<int>> split(auto x) {\n vector<vector<int>> res;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) res.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(x, 0);\n return res;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * X + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split(X)) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.17391304347826086, "time_ms": 60, "memory_kb": 145960, "score_of_the_acc": -0.7589, "final_rank": 15 }, { "submission_id": "aoj_0379_2675415", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n assert(false);\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n else if(8 <= i) ++eight;\n else if(4 <= i) ++four;\n }\n return combination(twelve, 1)\n + combination(eight, 1) * combination(four, 1) + combination(twelve, 1) * combination(four, 1) + 2 * combination(twelve, 1) * combination(eight, 1)\n + combination(four, 3) + combination(twelve, 1) * combination(four, 2) + combination(eight, 1) * combination(four, 2) + combination(twelve, 2) * combination(four, 1) + combination(eight, 2) * combination(four, 1) + combination(twelve, 1) * combination(eight, 1) * combination(four, 1) + combination(twelve, 3);\n}\n\nvector<vector<int>> memo;\nvector<vector<int>> split() {\n if(!memo.empty()) return memo;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) memo.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * X + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.15217391304347827, "time_ms": 50, "memory_kb": 145908, "score_of_the_acc": -0.7524, "final_rank": 16 }, { "submission_id": "aoj_0379_2675414", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n else if(8 <= i) ++eight;\n else if(4 <= i) ++four;\n }\n return combination(twelve, 1)\n + combination(eight, 1) * combination(four, 1) + combination(twelve, 1) * combination(four, 1) + 2 * combination(twelve, 1) * combination(eight, 1)\n + combination(four, 3) + combination(twelve, 1) * combination(four, 2) + combination(eight, 1) * combination(four, 2) + combination(twelve, 2) * combination(four, 1) + combination(eight, 2) * combination(four, 1) + combination(twelve, 1) * combination(eight, 1) * combination(four, 1) + combination(twelve, 3);\n}\n\nvector<vector<int>> memo;\nvector<vector<int>> split() {\n if(!memo.empty()) return memo;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) memo.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * X + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i + j + D[x] && 4 <= j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i <= X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i + D[x] && 8 <= i + 2 * j + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = v[0] + v[1];\n auto b = v[0] + v[2];\n auto c = v[1] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.17391304347826086, "time_ms": 50, "memory_kb": 145936, "score_of_the_acc": -0.7526, "final_rank": 13 }, { "submission_id": "aoj_0379_2675391", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6001, vector<int>(6001));\nvector<int> D(6001);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n else if(8 <= i) ++eight;\n else if(4 <= i) ++four;\n }\n return combination(twelve, 1)\n + combination(eight, 1) * combination(four, 1) + combination(twelve, 1) * combination(four, 1) + 2 * combination(twelve, 1) * combination(eight, 1)\n + combination(four, 3) + combination(twelve, 1) * combination(four, 2) + combination(eight, 1) * combination(four, 2) + combination(twelve, 2) * combination(four, 1) + combination(eight, 2) * combination(four, 1) + combination(twelve, 1) * combination(eight, 1) * combination(four, 1) + combination(twelve, 3);\n}\n\nvector<vector<int>> memo;\nvector<vector<int>> split() {\n if(!memo.empty()) return memo;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) memo.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * E[x][x] + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i * E[x][x] + j * E[x][y] + D[x] && 4 <= j * E[x][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i * E[x][y] + D[x] && 8 <= i * E[x][y] + 2 * j * E[y][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = E[x][y] * v[0] + E[x][z] + v[1];\n auto b = E[x][y] * v[0] + E[y][z] + v[2];\n auto c = E[x][z] * v[1] + E[y][z] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 6000; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.043478260869565216, "time_ms": 50, "memory_kb": 145792, "score_of_the_acc": -0.7519, "final_rank": 19 }, { "submission_id": "aoj_0379_2675386", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6000, vector<int>(6000));\nvector<int> D(6000);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n assert(false);\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n else if(8 <= i) ++eight;\n else if(4 <= i) ++four;\n }\n return combination(twelve, 1)\n + combination(eight, 1) * combination(four, 1) + combination(twelve, 1) * combination(four, 1) + 2 * combination(twelve, 1) * combination(eight, 1)\n + combination(four, 3) + combination(twelve, 1) * combination(four, 2) + combination(eight, 1) * combination(four, 2) + combination(twelve, 2) * combination(four, 1) + combination(eight, 2) * combination(four, 1) + combination(twelve, 1) * combination(eight, 1) * combination(four, 1) + combination(twelve, 3);\n}\n\nvector<vector<int>> memo;\nvector<vector<int>> split() {\n if(!memo.empty()) return memo;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) memo.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * E[x][x] + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i * E[x][x] + j * E[x][y] + D[x] && 4 <= j * E[x][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i * E[x][y] + D[x] && 8 <= i * E[x][y] + 2 * j * E[y][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = E[x][y] * v[0] + E[x][z] + v[1];\n auto b = E[x][y] * v[0] + E[y][z] + v[2];\n auto c = E[x][z] * v[1] + E[y][z] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 3; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.043478260869565216, "time_ms": 40, "memory_kb": 143904, "score_of_the_acc": -0.736, "final_rank": 18 }, { "submission_id": "aoj_0379_2675383", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\n\nint N, M, X, Y;\nvector<int> A, B;\nvector<vector<int>> E(6000, vector<int>(6000));\nvector<int> D(6000);\n\nLL combination(auto n, auto r) {\n if(n < r) return 0;\n LL res = 1;\n for(auto i = 0; i < r; ++i) res *= n - i;\n for(auto i = 0; i < r; ++i) res /= i + 1;\n return res;\n}\n\nLL straight() {\n auto four = 0, eight = 0, twelve = 0;\n for(auto i: D) {\n if(12 <= i) ++twelve;\n else if(8 <= i) ++eight;\n else if(4 <= i) ++four;\n }\n return combination(twelve, 1)\n + combination(eight, 1) * combination(four, 1) + combination(twelve, 1) * combination(four, 1) + 2 * combination(twelve, 1) * combination(eight, 1)\n + combination(four, 3) + combination(twelve, 1) * combination(four, 2) + combination(eight, 1) * combination(four, 2) + combination(twelve, 2) * combination(four, 1) + combination(eight, 2) * combination(four, 1) + combination(twelve, 1) * combination(eight, 1) * combination(four, 1) + combination(twelve, 3);\n}\n\nvector<vector<int>> memo;\nvector<vector<int>> split() {\n if(!memo.empty()) return memo;\n vector<int> v(3);\n function<void(int, int)> dfs = [&](auto x, auto d) {\n if(d == 3) {\n if(x == 0) memo.emplace_back(v);\n return;\n }\n for(auto i = 0; i <= min(4, x); ++i) {\n v[d] = i;\n dfs(x - i, d + 1);\n }\n };\n dfs(X, 0);\n return memo;\n}\n\nLL cube(auto x) {\n if(E[x][x] < X) return 0;\n if(2 * E[x][x] + D[x] < 12) return 0;\n return 1;\n}\n\nLL cuboidA(auto x, auto y) {\n if(E[x][x] + E[x][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][x] < i) continue;\n if(E[x][y] < j) continue;\n if(8 <= 2 * i * E[x][x] + j * E[x][y] + D[x] && 4 <= j * E[x][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidB(auto x, auto y) {\n if(E[x][y] + E[y][y] < X) return 0;\n for(auto i = 0; i < X; ++i) {\n auto j = X - i;\n if(E[x][y] < i) continue;\n if(E[y][y] < j) continue;\n if(4 <= i * E[x][y] + D[x] && 8 <= i * E[x][y] + 2 * j * E[y][y] + D[y]) return 1;\n }\n return 0;\n}\n\nLL cuboidC(auto x, auto y, auto z) {\n if(E[x][y] + E[x][z] + E[y][z] < X) return 0;\n for(auto v: split()) {\n if(E[x][y] < v[0]) continue;\n if(E[x][z] < v[1]) continue;\n if(E[y][z] < v[2]) continue;\n auto a = E[x][y] * v[0] + E[x][z] + v[1];\n auto b = E[x][y] * v[0] + E[y][z] + v[2];\n auto c = E[x][z] * v[1] + E[y][z] + v[2];\n if(4 <= a + D[x] && 4 <= b + D[y] && 4 <= c + D[z]) return 1;\n }\n return 0;\n}\n\nLL solve() {\n auto res = 0;\n set<vector<int>> used;\n for(auto i = 0; i < M; ++i) for(auto j = 1; j <= 3; ++j) {\n vector<int> L = {A[i], B[i], j};\n sort(begin(L), end(L));\n\n if(used.count(L)) continue;\n used.emplace(L);\n\n if(L[0] == L[1] && L[1] == L[2]) res += cube(L[0]);\n else if(L[0] == L[1]) res += cuboidA(L[0], L[2]);\n else if(L[1] == L[2]) res += cuboidB(L[0], L[1]);\n else res += cuboidC(L[0], L[1], L[2]);\n }\n return res;\n}\n\nint main() {\n cin >> N >> M >> X >> Y;\n A.resize(N);\n for(auto& i: A) cin >> i;\n B.resize(M);\n for(auto& i: B) cin >> i;\n\n for(auto i = 0; i < N; ++i) {\n if(i < M) {\n A[i] -= B[i];\n if(A[i] > B[i]) swap(A[i], B[i]);\n ++E[A[i]][B[i]];\n } else {\n ++D[A[i]];\n }\n }\n\n if(X) cout << solve() << endl;\n else cout << straight() << endl;\n}", "accuracy": 0.043478260869565216, "time_ms": 40, "memory_kb": 143868, "score_of_the_acc": -0.7358, "final_rank": 17 }, { "submission_id": "aoj_0379_2670927", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const int inf = (int)1e9;const double INF = 1e12, EPS = 1e-9;\n/*\nnamespace std{\n\ttemplate<int N, class Tuple>size_t get_hash(const Tuple &t){\n\t\treturn 1;\n\t}\n\ttemplate<int N, class Tuple, class H, class ...Ts> size_t get_hash(const Tuple &t){\n\t\treturn hash<H>()(get<N>(t)) + ((size_t)1e9+7)*get_hash<N+1,Tuple,Ts...>(t);\n\t}\n\ttemplate<class ...Ts>struct hash<tuple<Ts...>>{\n\t\tsize_t operator()(const tuple<Ts...>&t)const{\n\t\t\treturn get_hash<0, tuple<Ts...>, Ts...>(t);\n\t\t}\n\t};\n}\n*/\nnamespace std{\n namespace\n {\n\n // Code from boost\n // Reciprocal of the golden ratio helps spread entropy\n // and handles duplicates.\n // See Mike Seymour in magic-numbers-in-boosthash-combine:\n // http://stackoverflow.com/questions/4948780\n\n template <class T>\n inline void hash_combine(std::size_t& seed, T const& v)\n {\n seed ^= std::hash<T>()(v) + 0x9e3779b9 + (seed<<6) + (seed>>2);\n }\n\n // Recursive template code derived from Matthieu M.\n template <class Tuple, size_t Index = std::tuple_size<Tuple>::value - 1>\n struct HashValueImpl\n {\n static void apply(size_t& seed, Tuple const& tuple)\n {\n HashValueImpl<Tuple, Index-1>::apply(seed, tuple);\n hash_combine(seed, std::get<Index>(tuple));\n }\n };\n\n template <class Tuple>\n struct HashValueImpl<Tuple,0>\n {\n static void apply(size_t& seed, Tuple const& tuple)\n {\n hash_combine(seed, std::get<0>(tuple));\n }\n };\n }\n\n template <typename ... TT>\n struct hash<std::tuple<TT...>> \n {\n size_t\n operator()(std::tuple<TT...> const& tt) const\n { \n size_t seed = 0; \n HashValueImpl<std::tuple<TT...> >::apply(seed, tt); \n return seed; \n } \n\n };\n}\n\ntemplate<class T> inline int num(const unordered_map<T, int> &m, T k){\n\tauto it = m.find(k);\n\tif(it == m.end()) return 0;\n\treturn it->second;\n}\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint n, m, X, Y;\n\tcin >> n >> m >> X >> Y;\n\tvi v(n + m); rep(i, n + m) cin >> v[i];\n\t\n\tll ans = 0;\n\tunordered_set<int> lens;\n\tunordered_map<int,int> cnt;\n\tunordered_map<pi,int> cnt2;\n\tunordered_set<tuple<int,int,int>> vis;\n\trep(i, n){\n\t\tif(i < m){\n\t\t\tint a = v[i] - v[i + n], b = v[i + n];\n\t\t\tlens.insert(a);\n\t\t\tlens.insert(b);\n\t\t\t++cnt2[pi(min(a, b), max(a, b))];\n\t\t}\n\t\telse{\n\t\t\t++cnt[v[i]];\n\t\t\tlens.insert(v[i]);\n\t\t}\n\t}\n\t\n\tif(X == 0){\n\t\tvector<pi> vs;\n\t\tfor(auto i : cnt) if(i.second >= 4) vs.emplace_back(i.first, i.second);\n\t\tsort(all(vs), [](pi a, pi b){ return a.second != b.second ? a.second < b.second : a < b; });\n\t\trep(i, vs.size()){\n\t\t\tif(vs[i].second >= 12) ans++;\n\t\t\tif(vs[i].second >= 8) ans += (int)vs.size() - i - 1;\n\t\t\tfor(int j = i + 1; j < vs.size(); j++){\n\t\t\t\tif(vs[j].second >= 8) ans++;\n\t\t\t\tans += (int)vs.size() - j - 1;\n\t\t\t}\n\t\t}\n\t\tcout << ans << endl;\n\t\treturn 0;\n\t}\n\t\n\tfor(auto i : cnt2) for(int j : lens){\n\t\tvi l = {i.first.first, i.first.second, j};\n\t\tsort(all(l));\n\t\t\n\t\tif(vis.count(tie(l[0], l[1], l[2]))) continue;\n\t\t\n\t\tif(l[0] == l[1] && l[1] == l[2]){\n\t\t\tint x = min(X, num(cnt2, pi(l[0], l[1])));\n\t\t\tint y = num(cnt, l[0]);\n\t\t\tif(x == X && 2 * x + y >= 12) vis.emplace(l[0], l[1], l[2]);\n\t\t}\n\t\telse if(l[0] == l[1]){\n\t\t\tint x0 = min(X, num(cnt2, pi(l[0], l[1])));\n\t\t\tint x1 = min(X, num(cnt2, pi(l[0], l[2])));\n\t\t\tbool ok = 0;\n\t\t\trep(i, x0+1){\n\t\t\t\tif(X - i > x1) continue;\n\t\t\t\tint a = 2 * i + X - i, c = X - i;\n\t\t\t\tif(a > 8 || c > 4) continue;\n\t\t\t\tif(a + num(cnt, l[0]) >= 8 &&\n\t\t\t\t\tc + num(cnt, l[2]) >= 4){\n\t\t\t\t\tok = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ok) vis.emplace(l[0], l[1], l[2]);\n\t\t}\n\t\telse if(l[1] == l[2]){\n\t\t\tint x0 = min(X, num(cnt2, pi(l[0], l[1])));\n\t\t\tint x1 = min(X, num(cnt2, pi(l[1], l[2])));\n\t\t\tbool ok = 0;\n\t\t\trep(i, x0+1){\n\t\t\t\tif(X - i > x1) continue;\n\t\t\t\tint a = i, c = i + 2*(X - i);\n\t\t\t\tif(a > 4 || c > 8) continue;\n\t\t\t\tif(a + num(cnt, l[0]) >= 4 &&\n\t\t\t\t\tc + num(cnt, l[2]) >= 8){\n\t\t\t\t\tok = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ok) vis.emplace(l[0], l[1], l[2]);\n\t\t}\n\t\telse{\n\t\t\tint x0 = min(X, num(cnt2, pi(l[0], l[1])));\n\t\t\tint x1 = min(X, num(cnt2, pi(l[1], l[2])));\n\t\t\tint x2 = min(X, num(cnt2, pi(l[0], l[2])));\n\t\t\tbool ok = 0;\n\t\t\trep(i, x0+1) rep(j, x1+1){\n\t\t\t\tif(X - i - j > x2 || i + j > X) continue;\n\t\t\t\tint a = i + (X - i - j), b = i + j, c = j + (X - i - j);\n\t\t\t\tif(a > 4 || b > 4 || c > 4) continue;\n\t\t\t\tif(a + num(cnt, l[0]) >= 4 &&\n\t\t\t\t\tb + num(cnt, l[1]) >= 4 &&\n\t\t\t\t\tc + num(cnt, l[2]) >= 4){\n\t\t\t\t\tok = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ok) vis.emplace(l[0], l[1], l[2]);\n\t\t}\n\t}\n\tcout << vis.size() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1300, "memory_kb": 3584, "score_of_the_acc": -0.8023, "final_rank": 5 } ]
aoj_0378_cpp
Aerial Photos Hideyo has come by two aerial photos of the same scale and orientation. You can see various types of buildings, but some areas are hidden by clouds. Apparently, they are of the same area, and the area covered by the second photograph falls entirely within the first. However, because they were taken at different time points, different shapes and distribution of clouds obscure identification where the area in the second photograph is located in the first. There may even be more than one area within the first that the second fits equally well. A set of pixel information is given for each of the photographs. Write a program to extract candidate sub-areas within the first photograph that compare with the second equally well and output the number of the candidates. Input The input is given in the following format. AW AH BW BH arow 1 arow 2 : arow AH brow 1 brow 2 : brow BH The first line provides the number of pixels in the horizontal and the vertical direction AW (1 ≤ AW ≤ 800) and AH (1 ≤ AH ≤ 800) for the first photograph, followed by those for the second BW (1 ≤ BW ≤ 100) and BH (1 ≤ BH ≤ 100) ( AW ≥ BW and AH ≥ BH ). Each of the subsequent AH lines provides pixel information ( arow i ) of the i -th row from the top of the first photograph. Each of the B H lines that follows provides pixel information ( brow i ) of the i -th row from the top of the second photograph. Each of the pixel information arow i and brow i is a string of length AW and BW , respectively, consisting of upper/lower-case letters, numeric characters, or " ? ". Each one character represents a pixel, whereby upper/lower-case letters and numeric characters represent a type of building, and " ? " indicates a cloud-covered area. Output Output the number of the candidates. Sample Input 1 5 5 3 3 AF??z W?p88 ???Hk pU?m? F???c F?? p?8 ?H? Sample Output 1 4 Sample Input 2 6 5 4 2 aaaaaa aaaaaa aaaaaa aaaaaa aaaaaa aaaa aaaa Sample Output 2 12
[ { "submission_id": "aoj_0378_10205430", "code_snippet": "// AOJ #378\n// Aerial Photo 2025.2.9\n\n#include <iostream>\n#include <vector>\n#include <string>\n#include <emmintrin.h> // SSE2 ヘッダ\nusing namespace std;\nusing ll = long long;\n\nstatic inline bool checkRowSSE(const char* a, const char* b, int len) {\n __m128i q = _mm_set1_epi8('?');\n int i = 0;\n for(; i <= len - 16; i += 16) {\n __m128i va = _mm_loadu_si128((const __m128i*)(a + i));\n __m128i vb = _mm_loadu_si128((const __m128i*)(b + i));\n __m128i cmpA = _mm_cmpeq_epi8(va, q);\n __m128i cmpB = _mm_cmpeq_epi8(vb, q);\n __m128i cmpEq = _mm_cmpeq_epi8(va, vb);\n __m128i valid = _mm_or_si128(cmpA, _mm_or_si128(cmpB, cmpEq));\n int mask = _mm_movemask_epi8(valid);\n if (mask != 0xFFFF)\n return false;\n }\n for(; i < len; i++) {\n char ca = a[i], cb = b[i];\n if(ca != '?' && cb != '?' && ca != cb)\n return false;\n }\n return true;\n}\n \nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n \n int AW, AH, BW, BH;\n cin >> AW >> AH >> BW >> BH;\n vector<string> A(AH), B(BH);\n for (int i = 0; i < AH; i++) cin >> A[i];\n for (int i = 0; i < BH; i++) cin >> B[i];\n \n ll ans = 0;\n for (int y = 0; y <= AH - BH; y++){\n for (int x = 0; x <= AW - BW; x++){\n bool valid = true;\n for (int i = 0; i < BH; i++){\n if(!checkRowSSE(A[y+i].c_str() + x, B[i].c_str(), BW)){\n valid = false;\n break;\n }\n }\n if(valid) ans++;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 4164, "score_of_the_acc": -0.234, "final_rank": 8 }, { "submission_id": "aoj_0378_7518517", "code_snippet": "#line 1 \"test/aoj/0378.test.cpp\"\n#define PROBLEM \"https://onlinejudge.u-aizu.ac.jp/problems/0378\"\n#include <iostream>\n\n#line 2 \"math/convolution.hpp\"\n#include <cassert>\n#include <type_traits>\n#include <vector>\n\n#line 2 \"math/modint.hpp\"\n\n#include <algorithm>\n#include <array>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\nint bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\n} // namespace internal\n\n#include <utility>\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast moduler by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {\n }\n\n // @return m\n unsigned int umod() const {\n return _m;\n }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1)\n // < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n for (long long a : {2, 7, 61}) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n>\nconstexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m>\nconstexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n#line 212 \"math/modint.hpp\"\n#include <numeric>\n#line 214 \"math/modint.hpp\"\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value, __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral =\n typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value, make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value, std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T>\nusing is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type, std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned =\n typename std::conditional<is_signed_int<T>::value, std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T>\nusing to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n#line 299 \"math/modint.hpp\"\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T>\nusing is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T>\nusing is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\npublic:\n static constexpr int mod() {\n return m;\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {\n }\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n static_modint(bool v) {\n _v = ((unsigned int)(v) % umod());\n }\n\n unsigned int val() const {\n return _v;\n }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) {\n return *this = *this * rhs.inv();\n }\n\n mint operator+() const {\n return *this;\n }\n mint operator-() const {\n return mint() - *this;\n }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\nprivate:\n unsigned int _v;\n static constexpr unsigned int umod() {\n return m;\n }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id>\nstruct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\npublic:\n static int mod() {\n return (int)(bt.umod());\n }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {\n }\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n dynamic_modint(bool v) {\n _v = ((unsigned int)(v) % mod());\n }\n\n unsigned int val() const {\n return _v;\n }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) {\n return *this = *this * rhs.inv();\n }\n\n mint operator+() const {\n return *this;\n }\n mint operator-() const {\n return mint() - *this;\n }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\nprivate:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() {\n return bt.umod();\n }\n};\n\ntemplate <int id>\ninternal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class>\nstruct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n#line 599 \"math/modint.hpp\"\ntemplate <typename T, typename std::enable_if_t<internal::is_modint<T>::value,\n std::nullptr_t> = nullptr>\nstd::istream& operator>>(std::istream& is, T& v) {\n long long x;\n is >> x;\n v = x;\n return is;\n}\ntemplate <typename T, typename std::enable_if_t<internal::is_modint<T>::value,\n std::nullptr_t> = nullptr>\nstd::ostream& operator<<(std::ostream& os, const T& v) {\n os << v.val();\n return os;\n}\n#line 7 \"math/convolution.hpp\"\nnamespace internal {\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_e[30]; // sum_e[i] = ies[0] * ... * ies[i - 1] * es[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = internal::bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i < cnt2 - 2; i++) {\n sum_e[i] = es[i] * now;\n now *= ies[i];\n }\n }\n for (int ph = 1; ph <= h; ph++) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint now = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p] * now;\n a[i + offset] = l + r;\n a[i + offset + p] = l - r;\n }\n now *= sum_e[internal::bsf(~(unsigned int)(s))];\n }\n }\n}\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly_inv(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_ie[30]; // sum_ie[i] = es[0] * ... * es[i - 1] * ies[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = internal::bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i < cnt2 - 2; i++) {\n sum_ie[i] = ies[i] * now;\n now *= es[i];\n }\n }\n\n for (int ph = h; ph >= 1; ph--) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint inow = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p];\n a[i + offset] = l + r;\n a[i + offset + p] =\n (unsigned long long)(mint::mod() + l.val() - r.val()) *\n inow.val();\n }\n inow *= sum_ie[internal::bsf(~(unsigned int)(s))];\n }\n }\n}\n\n} // namespace internal\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nstd::vector<mint> convolution(std::vector<mint> a, std::vector<mint> b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n if (std::min(n, m) <= 60) {\n if (n < m) {\n std::swap(n, m);\n std::swap(a, b);\n }\n std::vector<mint> ans(n + m - 1);\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < m; j++) {\n ans[i + j] += a[i] * b[j];\n }\n }\n return ans;\n }\n int z = 1 << internal::ceil_pow2(n + m - 1);\n a.resize(z);\n internal::butterfly(a);\n b.resize(z);\n internal::butterfly(b);\n for (int i = 0; i < z; i++) {\n a[i] *= b[i];\n }\n internal::butterfly_inv(a);\n a.resize(n + m - 1);\n mint iz = mint(z).inv();\n for (int i = 0; i < n + m - 1; i++) a[i] *= iz;\n return a;\n}\n\ntemplate <unsigned int mod = 998244353, class T,\n std::enable_if_t<internal::is_integral<T>::value>* = nullptr>\nstd::vector<T> convolution(const std::vector<T>& a, const std::vector<T>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n using mint = static_modint<mod>;\n std::vector<mint> a2(n), b2(m);\n for (int i = 0; i < n; i++) {\n a2[i] = mint(a[i]);\n }\n for (int i = 0; i < m; i++) {\n b2[i] = mint(b[i]);\n }\n auto c2 = convolution(move(a2), move(b2));\n std::vector<T> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n c[i] = c2[i].val();\n }\n return c;\n}\n\nstd::vector<long long> convolution_ll(const std::vector<long long>& a,\n const std::vector<long long>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n static constexpr unsigned long long MOD1 = 754974721; // 2^24\n static constexpr unsigned long long MOD2 = 167772161; // 2^25\n static constexpr unsigned long long MOD3 = 469762049; // 2^26\n static constexpr unsigned long long M2M3 = MOD2 * MOD3;\n static constexpr unsigned long long M1M3 = MOD1 * MOD3;\n static constexpr unsigned long long M1M2 = MOD1 * MOD2;\n static constexpr unsigned long long M1M2M3 = MOD1 * MOD2 * MOD3;\n\n static constexpr unsigned long long i1 =\n internal::inv_gcd(MOD2 * MOD3, MOD1).second;\n static constexpr unsigned long long i2 =\n internal::inv_gcd(MOD1 * MOD3, MOD2).second;\n static constexpr unsigned long long i3 =\n internal::inv_gcd(MOD1 * MOD2, MOD3).second;\n\n auto c1 = convolution<MOD1>(a, b);\n auto c2 = convolution<MOD2>(a, b);\n auto c3 = convolution<MOD3>(a, b);\n\n std::vector<long long> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n unsigned long long x = 0;\n x += (c1[i] * i1) % MOD1 * M2M3;\n x += (c2[i] * i2) % MOD2 * M1M3;\n x += (c3[i] * i3) % MOD3 * M1M2;\n // B = 2^63, -B <= x, r(real value) < B\n // (x, x - M, x - 2M, or x - 3M) = r (mod 2B)\n // r = c1[i] (mod MOD1)\n // focus on MOD1\n // r = x, x - M', x - 2M', x - 3M' (M' = M % 2^64) (mod 2B)\n // r = x,\n // x - M' + (0 or 2B),\n // x - 2M' + (0, 2B or 4B),\n // x - 3M' + (0, 2B, 4B or 6B) (without mod!)\n // (r - x) = 0, (0)\n // - M' + (0 or 2B), (1)\n // -2M' + (0 or 2B or 4B), (2)\n // -3M' + (0 or 2B or 4B or 6B) (3) (mod MOD1)\n // we checked that\n // ((1) mod MOD1) mod 5 = 2\n // ((2) mod MOD1) mod 5 = 3\n // ((3) mod MOD1) mod 5 = 4\n long long diff =\n c1[i] - internal::safe_mod((long long)(x), (long long)(MOD1));\n if (diff < 0) diff += MOD1;\n static constexpr unsigned long long offset[5] = {\n 0, 0, M1M2M3, 2 * M1M2M3, 3 * M1M2M3};\n x -= offset[diff % 5];\n c[i] = x;\n }\n\n return c;\n}\n#line 3 \"string/wildcard_matching.hpp\"\nstd::vector<bool> wildcard_matching(std::string s, std::string t) {\n int n = s.size(), m = t.size();\n assert(n >= m);\n std::vector<long long> a1(n), a2(n), a3(n);\n for (int i = 0; i < n; i++) {\n a1[i] = s[i] == '?' ? 0 : (long long)s[i];\n a2[i] = a1[i] * a1[i];\n a3[i] = a2[i] * a1[i];\n }\n std::vector<long long> b1(m), b2(m), b3(m);\n for (int i = 0; i < m; i++) {\n b1[i] = t[i] == '?' ? 0 : (long long)t[i];\n b2[i] = b1[i] * b1[i];\n b3[i] = b2[i] * b1[i];\n }\n auto f = [](const std::vector<long long> &a, std::vector<long long> &b) {\n std::reverse(b.begin(), b.end());\n std::vector<long long> c = convolution_ll(a, b);\n return std::vector<long long>(c.begin() + b.size() - 1, c.end());\n };\n std::vector<long long> c1 = f(a3, b1);\n std::vector<long long> c2 = f(a2, b2);\n std::vector<long long> c3 = f(a1, b3);\n std::vector<bool> ret(n - m + 1);\n for (int i = 0; i < n - m + 1; i++) {\n ret[i] = c1[i] - c2[i] * 2 + c3[i] == 0;\n }\n return ret;\n}\n#line 5 \"test/aoj/0378.test.cpp\"\nint main() {\n int aw, ah, bw, bh;\n std::cin >> aw >> ah >> bw >> bh;\n std::string s, t;\n for (int i = 0; i < ah; i++) {\n std::string a;\n std::cin >> a;\n s += a;\n }\n for (int i = 0; i < bh; i++) {\n std::string b;\n std::cin >> b;\n t += b;\n if (i < bh - 1) t += std::string(aw - bw, '?');\n }\n std::vector<bool> ok = wildcard_matching(s, t);\n int ans = 0;\n for (int i = 0; i < ah - bh + 1; i++) {\n for (int j = 0; j < aw - bw + 1; j++) {\n ans += ok[i * aw + j];\n }\n }\n std::cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 55584, "score_of_the_acc": -0.569, "final_rank": 12 }, { "submission_id": "aoj_0378_5205797", "code_snippet": "#line 1 \"test.cpp\"\n#include <bits/stdc++.h>\nusing namespace std::literals::string_literals;\nusing i64 = std::int_fast64_t;\nusing std::cout;\nusing std::cerr;\nusing std::endl;\nusing std::cin;\n\ntemplate<typename T>\nstd::vector<T> make_v(size_t a){return std::vector<T>(a);}\n\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts){\n return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\n\n#line 2 \"wildcard_matching.hpp\"\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/fast_fourier_transform.hpp\"\n\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/polynomial.hpp\"\n\n\n\n#line 8 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/polynomial.hpp\"\n\nnamespace cplib {\ntemplate<class T>\nclass polynomial: public std::vector<T> {\npublic:\n\tusing std::vector<T>::vector;\n\tusing value_type = typename std::vector<T>::value_type;\n\tusing reference = typename std::vector<T>::reference;\n\tusing const_reference = typename std::vector<T>::const_reference;\n\tusing size_type = typename std::vector<T>::size_type;\n\npublic:\n\tpolynomial(const std::vector<T>& r): std::vector<T>(r) {}\n\tpolynomial(size_t size, std::function<T(size_t)> f): std::vector<T>(size) {\n\t\tfor(size_t i = 0; i < size; i++) (*this)[i] = f(i);\n\t}\n\n\tpolynomial operator+(const polynomial& r) const { return polynomial(*this) += r; }\n\tpolynomial operator+(const_reference r) const { return polynomial(*this) += r; }\n\tfriend polynomial operator+(const_reference l, polynomial r) { return r += l; }\n\tpolynomial operator-(const polynomial& r) const { return polynomial(*this) -= r; }\n\tpolynomial operator-(const_reference r) const { return polynomial(*this) -= r; }\n\tfriend polynomial operator-(const_reference l, polynomial r) { return r -= l; }\n\tpolynomial operator*(const_reference r) const { return polynomial(*this) *= r; }\n\tfriend polynomial operator*(const_reference l, polynomial r) { return r *= l; }\n\tpolynomial operator*(const polynomial& r) const { return polynomial(*this) *= r; }\n\tpolynomial operator/(const_reference r) const { return polynomial(*this) /= r; }\n\tpolynomial operator<<(size_type r) const { return polynomial(*this) <<= r; }\n\tpolynomial operator>>(size_type r) const { return polynomial(*this) >>= r; }\n\tpolynomial operator-() const {\n\t\tpolynomial ret(this->size());\n\t\tfor(size_t i = 0; i < this->size(); i++) ret[i] = -(*this)[i];\n\t\treturn ret;\n\t}\n\tpolynomial& operator+=(const polynomial& r) {\n\t\tif(r.size() > this->size()) this->resize(r.size());\n\t\tfor(size_t i = 0; i < r.size(); i++) (*this)[i] = (*this)[i] + r[i];\n\t\treturn *this;\n\t}\n\tpolynomial& operator+=(const_reference r) {\n\t\tif(this->empty()) this->push_back(T{});\n\t\t(*this)[0] += r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator-=(const polynomial& r) {\n\t\tif(r.size() > this->size()) this->resize(r.size());\n\t\tfor(size_t i = 0; i < r.size(); i++) (*this)[i] = (*this)[i] - r[i];\n\t\treturn *this;\n\t}\n\tpolynomial& operator-=(const_reference r) {\n\t\tif(this->empty()) this->push_back(T{});\n\t\t(*this)[0] -= r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator*=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator/=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] / r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator<<=(size_type r) {\n\t\tthis->insert(begin(*this), r, T{});\n\t\treturn *this;\n\t}\n\tpolynomial& operator>>=(size_type r) {\n\t\tif(r >= this->size()) this->clear();\n\t\telse this->erase(begin(*this), begin(*this) + r);\n\t\treturn *this;\n\t}\n\tpolynomial& operator*=(const polynomial& r) {\n\t\tpolynomial ret(this->degree() + r.degree() + 1);\n\t\tfor(size_t i = 0; i < this->size(); i++) {\n\t\t\tif((*this)[i] == T{}) continue;\n\t\t\tfor(size_t j = 0; j < r.size(); j++) ret[i + j] += (*this)[i] * r[j];\n\t\t}\n\t\treturn *this = std::move(ret);\n\t};\n\n\tpolynomial differential(size_type k) const {\n\t\tpolynomial ret(*this);\n\t\tfor(size_t i = 0; i < k; i++) ret = ret.differential();\n\t\treturn ret;\n\t}\n\tpolynomial differential() const {\n\t\tif(degree() < 1) return polynomial();\n\t\tpolynomial ret(this->size() - 1);\n\t\tfor(size_t i = 1; i < this->size(); i++) ret[i - 1] = (*this)[i] * T(i);\n\t\treturn ret;\n\t}\n\tpolynomial integral(size_type k) const {\n\t\tpolynomial ret(*this);\n\t\tfor(size_t i = 0; i < k; i++) ret = ret.integral();\n\t\treturn ret;\n\t}\n\tpolynomial integral() const {\n\t\tpolynomial ret(this->size() + 1);\n\t\tfor(size_t i = 0; i < this->size(); i++) ret[i + 1] = (*this)[i] / T(i + 1);\n\t\treturn ret;\n\t}\n\tpolynomial prefix(size_type size) const {\n\t\treturn polynomial(begin(*this), begin(*this) + std::min(this->size(), size));\n\t}\n\tvoid shrink() {\n\t\twhile(!this->empty() and this->back() == T{}) this->pop_back();\n\t}\n\npublic:\n\tpolynomial sparse_convex(const polynomial& r) const {\n\t\tif(this->nonzeros() < r.nonzeros()) return (*this) * r;\n\t\treturn r * (*this);\n\t}\n\tsize_type degree() const { return std::max<size_type>(1, this->size()) - 1; }\n\tsize_type nonzeros() const {\n\t\tsize_type ret = 0;\n\t\tfor(size_t i = 0; i < this->size(); i++) {\n\t\t\tif((*this)[i] != T{}) ret++;\n\t\t}\n\t\treturn ret;\n\t}\n\tT operator()(T x) const { return eval(x); }\n\tT eval(T x) const {\n\t\tT ret = (*this)[0], tmp = x;\n\t\tfor(size_t i = 1; i < this->size(); i++) {\n\t\t\tret = ret + (*this)[i] * tmp;\n\t\t\ttmp = tmp * x;\n\t\t}\n\t\treturn ret;\n\t}\n\n\tstatic polynomial<T> one() { return term(0); }\n\tstatic polynomial<T> zero() { return polynomial<T>({T{0}}); }\n\tstatic polynomial<T> term(int k) { return polynomial<T>({T{1}}) << k; }\n};\n\ntemplate<class T> T convex_all(std::vector<T> polies, int size = -1) {\n\tif(polies.empty()) return T::zero();\n\n\tstd::deque<int> qu;\n\tfor(int i = 0; i < polies.size(); i++) qu.push_back(i);\n\twhile(qu.size() > 1) {\n\t\tint a = qu.front(); qu.pop_front();\n\t\tint b = qu.front(); qu.pop_front();\n\n\t\tpolies.push_back(polies[a] * polies[b]);\n\t\tif(size != -1) polies.back().resize(size);\n\t\tqu.push_back((int)polies.size() - 1);\n\t}\n\treturn polies.back();\n}\n}\n\n\n#line 6 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/fast_fourier_transform.hpp\"\n\nnamespace cplib {\ntemplate<class T, class Real = double, class Complex = std::complex<Real>>\nclass fast_fourier_transform: public polynomial<T> {\npublic:\n\tusing polynomial<T>::polynomial;\n\tusing value_type = typename polynomial<T>::value_type;\n\tusing reference = typename polynomial<T>::reference;\n\tusing const_reference = typename polynomial<T>::const_reference;\n\tusing size_type = typename polynomial<T>::size_type;\n\nprivate:\n\t// constexpr Real PI = std::numbers::pi_v<Real>;\n\tstatic constexpr Real PI = std::acos(Real(-1));;\n\n\tvoid transform(polynomial<Complex>& a, bool inverse = false) {\n\t\tsize_type n = 0;\n\t\twhile((1 << n) < a.size()) n++;\n\t\tsize_type N = 1 << n;\n\t\ta.resize(N);\n\n\t\tsize_type mask = N - 1;\n\t\tpolynomial<Complex> tmp(N);\n\t\tfor(int i = N >> 1; i >= 1; i >>= 1) {\n\t\t\tReal theta = 2 * PI * i * (inverse ? -1 : 1) / N;\n\t\t\tComplex zeta(std::cos(theta), std::sin(theta));\n\t\t\tComplex powZeta(1);\n\n\t\t\tfor(int j = 0; j < N; j += i) {\n\t\t\t\tfor(int k = 0; k < i; k++) {\n\t\t\t\t\ttmp[j + k] = a[((j << 1) & mask) | k] + powZeta * a[(((j << 1) | i) & mask) | k];\n\t\t\t\t}\n\t\t\t\tpowZeta *= zeta;\n\t\t\t}\n\t\t\ta.swap(tmp);\n\t\t}\n\n\t\tif(n & 1) {\n\t\t\tstd::swap(a, tmp);\n\t\t\tfor(int i = 0; i < N; i++) a[i] = tmp[i];\n\t\t}\n\t\tif(inverse) for(int i = 0; i < N; i++) a[i] /= N;\n\t}\n\tfast_fourier_transform convolution(const fast_fourier_transform& ar, const fast_fourier_transform& br) {\n\t\tsize_type size = ar.degree() + br.degree() + 1;\n\t\tpolynomial<Complex> a(size);\n\t\tfor(int i = 0; i < ar.size(); i++) a[i].real(ar[i]);\n\t\tfor(int i = 0; i < br.size(); i++) a[i].imag(br[i]);\n\t\ttransform(a, false);\n\n\t\tint N = a.size();\n\t\tpolynomial<Complex> c(N);\n\t\tfor(int i = 0; i < N; i++) {\n\t\t\tint j = (i == 0 ? 0 : N - i);\n\t\t\tc[i] = (a[i] + conj(a[j])) * (a[i] - conj(a[j])) * Complex(0, -.25);\n\t\t}\n\t\ttransform(c, true);\n\n\t\tfast_fourier_transform ret(size);\n\t\tfor(int i = 0; i < size; i++) ret[i] = round(c[i].real());\n\t\treturn ret;\n\n\t}\npublic:\n\tfast_fourier_transform(const polynomial<T>& p): polynomial<T>(p) {}\n\n\tfast_fourier_transform operator*(const_reference r) const { return fast_fourier_transform(*this) *= r; }\n\tfast_fourier_transform& operator*=(const_reference r) {\n\t\tfor(int i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\tfast_fourier_transform operator*(const fast_fourier_transform& r) const { return fast_fourier_transform(*this) *= r; }\n\tfast_fourier_transform& operator*=(const fast_fourier_transform& r) {\n\t\treturn (*this) = convolution((*this), r);\n\t}\n};\n}\n\n// @docs docs/fast_fourier_transform.md\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/number_theoritic_transform.hpp\"\n\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/modint.hpp\"\n\n\n\n#line 5 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/modint.hpp\"\n\nnamespace cplib {\ntemplate <std::uint_fast64_t Modulus>\nclass modint {\n\tusing u32 = std::uint_fast32_t;\n\tusing u64 = std::uint_fast64_t;\n\tusing i32 = std::int_fast32_t;\n\tusing i64 = std::int_fast64_t;\n\n\tinline u64 apply(i64 x) { return (x < 0 ? x + Modulus : x); };\n\npublic:\n\tu64 a;\n\tstatic constexpr u64 mod = Modulus;\n\n\tconstexpr modint(const i64& x = 0) noexcept: a(apply(x % (i64)Modulus)) {}\n\n\tconstexpr modint operator+(const modint& rhs) const noexcept { return modint(*this) += rhs; }\n\tconstexpr modint operator-(const modint& rhs) const noexcept { return modint(*this) -= rhs; }\n\tconstexpr modint operator*(const modint& rhs) const noexcept { return modint(*this) *= rhs; }\n\tconstexpr modint operator/(const modint& rhs) const noexcept { return modint(*this) /= rhs; }\n\tconstexpr modint operator^(const u64& k) const noexcept { return modint(*this) ^= k; }\n\tconstexpr modint operator^(const modint& k) const noexcept { return modint(*this) ^= k.value(); }\n\tconstexpr modint operator-() const noexcept { return modint(Modulus - a); }\n\tconstexpr modint operator++() noexcept { return (*this) = modint(*this) + 1; }\n\tconstexpr modint operator--() noexcept { return (*this) = modint(*this) - 1; }\n\tconst bool operator==(const modint& rhs) const noexcept { return a == rhs.a; };\n\tconst bool operator!=(const modint& rhs) const noexcept { return a != rhs.a; };\n\tconst bool operator<=(const modint& rhs) const noexcept { return a <= rhs.a; };\n\tconst bool operator>=(const modint& rhs) const noexcept { return a >= rhs.a; };\n\tconst bool operator<(const modint& rhs) const noexcept { return a < rhs.a; };\n\tconst bool operator>(const modint& rhs) const noexcept { return a > rhs.a; };\n\tconstexpr modint& operator+=(const modint& rhs) noexcept {\n\t\ta += rhs.a;\n\t\tif (a >= Modulus) a -= Modulus;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator-=(const modint& rhs) noexcept {\n\t\tif (a < rhs.a) a += Modulus;\n\t\ta -= rhs.a;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator*=(const modint& rhs) noexcept {\n\t\ta = a * rhs.a % Modulus;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator/=(modint rhs) noexcept {\n\t\tu64 exp = Modulus - 2;\n\t\twhile (exp) {\n\t\t\tif (exp % 2) (*this) *= rhs;\n\n\t\t\trhs *= rhs;\n\t\t\texp /= 2;\n\t\t}\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator^=(u64 k) noexcept {\n\t\tauto b = modint(1);\n\t\twhile(k) {\n\t\t\tif(k & 1) b = b * (*this);\n\t\t\t(*this) *= (*this);\n\t\t\tk >>= 1;\n\t\t}\n\t\treturn (*this) = b;\n\t}\n\tconstexpr modint& operator=(const modint& rhs) noexcept {\n\t\ta = rhs.a;\n\t\treturn (*this);\n\t}\n\n\tconst modint inverse() const {\n\t\treturn modint(1) / *this;\n\t}\n\tconst modint power(i64 k) const {\n\t\tif(k < 0) return modint(*this).inverse() ^ (-k);\n\t\treturn modint(*this) ^ k;\n\t}\n\n\texplicit operator bool() const { return a; }\n\texplicit operator u64() const { return a; }\n\tconstexpr u64& value() noexcept { return a; }\n\tconstexpr const u64& value() const noexcept { return a; }\n\n\tfriend std::ostream& operator<<(std::ostream& os, const modint& p) {\n\t\treturn os << p.a;\n\t}\n\tfriend std::istream& operator>>(std::istream& is, modint& p) {\n\t\tu64 t;\n\t\tis >> t;\n\t\tp = modint(t);\n\t\treturn is;\n\t}\n};\n}\n\n\n#line 7 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/number_theoritic_transform.hpp\"\n\nnamespace cplib {\ntemplate<std::uint_fast64_t MOD,\n\tint primitive_root = 3,\n\tclass T = modint<MOD>>\nclass number_theoritic_transform: public polynomial<T> {\npublic:\n\tusing polynomial<T>::polynomial;\n\tusing value_type \t = typename polynomial<T>::value_type;\n\tusing reference \t = typename polynomial<T>::reference;\n\tusing const_reference = typename polynomial<T>::const_reference;\n\tusing size_type \t = typename polynomial<T>::size_type;\n\npublic:\n\tnumber_theoritic_transform(const polynomial<T>& p): polynomial<T>(p) {}\n\nprotected:\n\tstatic void ntt(number_theoritic_transform& a) {\n\t\tsize_t N = a.size();\n\t\tstatic std::vector<T> dw;\n\t\tif(dw.size() < N) {\n\t\t\tint n = dw.size();\n\t\t\tdw.resize(N);\n\t\t\tfor(size_t i = n; i < N; i++) dw[i] = -(T(primitive_root) ^ ((T::mod - 1) >> (i + 2)));\n\t\t}\n\n\t\tfor(size_t m = N; m >>= 1;) {\n\t\t\tT w = 1;\n\t\t\tfor(size_t s = 0, k = 0; s < N; s += 2 * m) {\n\t\t\t\tfor(size_t i = s, j = s + m; i < s + m; i++, j++) {\n\t\t\t\t\tT x = a[i], y = a[j] * w;\n\t\t\t\t\ta[i] = x + y;\n\t\t\t\t\ta[j] = x - y;\n\t\t\t\t}\n\t\t\t\tw *= dw[__builtin_ctz(++k)];\n\t\t\t}\n\t\t}\n\t}\n\tstatic void intt(number_theoritic_transform& a) {\n\t\tsize_t N = a.size();\n\t\tstatic std::vector<T> idw;\n\t\tif(idw.size() < N) {\n\t\t\tsize_t n = idw.size();\n\t\t\tidw.resize(N);\n\t\t\tfor(size_t i = n; i < N; i++) idw[i] = (-(T(primitive_root) ^ ((T::mod - 1) >> (i + 2)))).inverse();\n\t\t}\n\n\t\tfor(size_t m = 1; m < N; m *= 2) {\n\t\t\tT w = 1;\n\t\t\tfor(size_t s = 0, k = 0; s < N; s += 2 * m) {\n\t\t\t\tfor(size_t i = s, j = s + m; i < s + m; i++, j++) {\n\t\t\t\t\tT x = a[i], y = a[j];\n\t\t\t\t\ta[i] = x + y;\n\t\t\t\t\ta[j] = (x - y) * w;\n\t\t\t\t}\n\t\t\t\tw *= idw[__builtin_ctz(++k)];\n\t\t\t}\n\t\t}\n\t}\n\tstatic void transform(number_theoritic_transform& a, bool inverse = false) {\n\t\tsize_type n = 0;\n\t\twhile((1ul << n) < a.size()) n++;\n\t\tsize_type N = 1 << n;\n\t\ta.resize(N);\n\n\t\tif(!inverse) {\n\t\t\tntt(a);\n\t\t} else {\n\t\t\tintt(a);\n\t\t\tT inv = T(N).inverse();\n\t\t\tfor(size_t i = 0; i < a.size(); i++) a[i] *= inv;\n\t\t}\n\t}\n\n\tstatic number_theoritic_transform convolution(const number_theoritic_transform& ar, const number_theoritic_transform& br) {\n\t\tsize_type size = ar.degree() + br.degree() + 1;\n\t\tnumber_theoritic_transform a(ar), b(br);\n\t\ta.resize(size);\n\t\tb.resize(size);\n\n\t\ttransform(a, false);\n\t\ttransform(b, false);\n\n\t\tfor(size_t i = 0; i < a.size(); i++) a[i] *= b[i];\n\t\ttransform(a, true);\n\t\ta.resize(size);\n\t\treturn a;\n\t}\n\npublic:\n\tnumber_theoritic_transform convolute(const number_theoritic_transform& r) const { return (*this) * r; }\n\tnumber_theoritic_transform operator*(const number_theoritic_transform& r) const { return number_theoritic_transform(*this) *= r; }\n\tnumber_theoritic_transform& operator*=(const number_theoritic_transform& r) {\n\t\treturn (*this) = convolution((*this), r);\n\t}\n\tnumber_theoritic_transform operator*(const_reference r) const { return number_theoritic_transform(*this) *= r; }\n\tnumber_theoritic_transform& operator*=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\n};\n}\n// @docs docs/number_theoritic_transform.md\n\n\n#line 8 \"wildcard_matching.hpp\"\n\n/*\n# 注意\n\t計算時に用いる値の最大値は、文字の種類数 σ とマッチング文字列の長さ N について、2Nσ^2 となる。\n\tデフォルト実装では NTT<998244353> を用いているので、上記の値が 998244353 をこえるとバグる。\n\t対策: 大きい MOD を使う。FFT を使う。\n*/\n\nnamespace cplib {\ntemplate<class convolution = number_theoritic_transform<998244353>> struct wildcard_matching_t {\n\tusing value_type = typename convolution::value_type;\n\tusing size_type = size_t;\n\n\tchar wildcard = '?';\n\nprivate:\n\t// \"?abcde...\" -> \"012345...\"\n\tconstexpr std::vector<value_type> string_to_num_array(const std::string& s, char offset = 'a') const {\n\t\tstd::vector<value_type> ret(s.size());\n\t\tfor(size_t i = 0; i < s.size(); i++) {\n\t\t\tret[i] = s[i] - offset + 1;\n\t\t\tif(s[i] == wildcard) ret[i] = 0;\n\t\t}\n\t\treturn std::move(ret);\n\t}\n\t// \"?abcde...\" -> \"011111...\"\n\tconstexpr std::vector<value_type> string_to_bin_array(const std::string& s) const {\n\t\tstd::vector<value_type> ret(s.size(), 1);\n\t\tfor(size_t i = 0; i < s.size(); i++) if(s[i] == wildcard) ret[i] = 0;\n\t\treturn std::move(ret);\n\t}\n\npublic:\n\t// c_k = \\sum_{i = 0}^{M - 1}a_{i + k}b_i\n\tconstexpr std::vector<value_type> cross_correlation(std::vector<value_type> a, std::vector<value_type> b) const {\n\t\treverse(begin(a), end(a));\n\t\tauto c = convolution{a}.convolute(b).prefix(a.size());\n\t\tc.erase(begin(c), begin(c) + (b.size() - 1));\n\t\treverse(begin(c), end(c));\n\t\treturn std::move(c);\n\t}\n\npublic:\n\ttemplate<class T>\n\tconstexpr std::vector<bool> matching(const std::vector<T>& a, const std::vector<T>& b) const {\n\t\tstd::vector<value_type> c(a.size()), d(b.size());\n\t\tfor(size_t i = 0; i < a.size(); i++) c[i] = (a[i] != 0);\n\t\tfor(size_t i = 0; i < b.size(); i++) d[i] = (b[i] != 0);\n\t\tauto A(c); for(size_t i = 0; i < A.size(); i++) A[i] = c[i] * a[i] * a[i];\n\t\tauto B(c); for(size_t i = 0; i < B.size(); i++) B[i] = c[i] * a[i];\n\t\tauto C(d); for(size_t i = 0; i < C.size(); i++) C[i] = d[i] * b[i];\n\t\tauto D(d); for(size_t i = 0; i < D.size(); i++) D[i] = d[i] * b[i] * b[i];\n\n\t\tstd::vector<bool> m(a.size() - b.size() + 1);\n\t\tauto X = cross_correlation(A, d);\n\t\tauto Y = cross_correlation(B, C);\n\t\tauto Z = cross_correlation(c, D);\n\t\tfor(size_t i = 0; i < m.size(); i++) m[i] = (X[i] - Y[i] * 2 + Z[i] == 0);\n\t\treturn std::move(m);\n\t}\n\n\tconstexpr std::vector<bool> matching(const std::string& s, const std::string& p) const {\n\t\tassert(!s.empty());\n\t\tassert(!p.empty());\n\t\treturn matching(string_to_num_array(s), string_to_num_array(p));\n\t}\n\tconstexpr std::vector<size_t> matching_index(const std::string& s, const std::string& p) const {\n\t\tauto match = matching(std::move(s), std::move(p));\n\t\tstd::vector<size_t> ret;\n\t\tfor(size_t i = 0; i < match.size(); i++) if(match[i]) ret.push_back(i);\n\t\treturn std::move(ret);\n\t}\n\n\tchar get_wildcard() const { return wildcard; }\n\tvoid set_wildcard(const char c) { wildcard = c; }\n};\nconstexpr wildcard_matching_t<> wildcard_matching = wildcard_matching_t<>();\n}\n#line 18 \"test.cpp\"\n\nint main() {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(nullptr);\n\n int AW, AH, BW, BH;\n std::cin >> AW >> AH >> BW >> BH;\n std::vector<int> s(AH * AW), p(AW * (BH - 1) + BW, 0);\n\n const auto convert = [](const char c) -> int {\n if (c == '?') {\n return 0;\n } else if ('0' <= c && c <= '9') {\n return c - '0' + 1;\n } else if ('a' <= c && c <= 'z') {\n return c - 'a' + 10 + 1;\n } else {\n return c - 'A' + 10 + 26 + 1;\n }\n };\n\n for (int i = 0; i != AH; ++i) {\n for (int j = 0; j != AW; ++j) {\n char c;\n std::cin >> c;\n s[AW * i + j] = convert(c);\n }\n }\n\n for (int i = 0; i != BH; ++i) {\n for (int j = 0; j != BW; ++j) {\n char c;\n std::cin >> c;\n p[AW * i + j] = convert(c);\n }\n }\n\n const auto m = cplib::wildcard_matching.matching(s, p);\n\n int ans = 0;\n for (int i = 0; i + BH <= AH; ++i) {\n for (int j = 0; j + BW <= AW; ++j) {\n if (m[AW * i + j]) {\n ++ans;\n }\n }\n }\n\n std::cout << ans << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 98540, "score_of_the_acc": -0.5331, "final_rank": 10 }, { "submission_id": "aoj_0378_5205793", "code_snippet": "#line 1 \"test.cpp\"\n#include <bits/stdc++.h>\nusing namespace std::literals::string_literals;\nusing i64 = std::int_fast64_t;\nusing std::cout;\nusing std::cerr;\nusing std::endl;\nusing std::cin;\n\ntemplate<typename T>\nstd::vector<T> make_v(size_t a){return std::vector<T>(a);}\n\ntemplate<typename T,typename... Ts>\nauto make_v(size_t a,Ts... ts){\n return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));\n}\n\n#line 2 \"wildcard_matching.hpp\"\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/fast_fourier_transform.hpp\"\n\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/polynomial.hpp\"\n\n\n\n#line 8 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/polynomial.hpp\"\n\nnamespace cplib {\ntemplate<class T>\nclass polynomial: public std::vector<T> {\npublic:\n\tusing std::vector<T>::vector;\n\tusing value_type = typename std::vector<T>::value_type;\n\tusing reference = typename std::vector<T>::reference;\n\tusing const_reference = typename std::vector<T>::const_reference;\n\tusing size_type = typename std::vector<T>::size_type;\n\npublic:\n\tpolynomial(const std::vector<T>& r): std::vector<T>(r) {}\n\tpolynomial(size_t size, std::function<T(size_t)> f): std::vector<T>(size) {\n\t\tfor(size_t i = 0; i < size; i++) (*this)[i] = f(i);\n\t}\n\n\tpolynomial operator+(const polynomial& r) const { return polynomial(*this) += r; }\n\tpolynomial operator+(const_reference r) const { return polynomial(*this) += r; }\n\tfriend polynomial operator+(const_reference l, polynomial r) { return r += l; }\n\tpolynomial operator-(const polynomial& r) const { return polynomial(*this) -= r; }\n\tpolynomial operator-(const_reference r) const { return polynomial(*this) -= r; }\n\tfriend polynomial operator-(const_reference l, polynomial r) { return r -= l; }\n\tpolynomial operator*(const_reference r) const { return polynomial(*this) *= r; }\n\tfriend polynomial operator*(const_reference l, polynomial r) { return r *= l; }\n\tpolynomial operator*(const polynomial& r) const { return polynomial(*this) *= r; }\n\tpolynomial operator/(const_reference r) const { return polynomial(*this) /= r; }\n\tpolynomial operator<<(size_type r) const { return polynomial(*this) <<= r; }\n\tpolynomial operator>>(size_type r) const { return polynomial(*this) >>= r; }\n\tpolynomial operator-() const {\n\t\tpolynomial ret(this->size());\n\t\tfor(size_t i = 0; i < this->size(); i++) ret[i] = -(*this)[i];\n\t\treturn ret;\n\t}\n\tpolynomial& operator+=(const polynomial& r) {\n\t\tif(r.size() > this->size()) this->resize(r.size());\n\t\tfor(size_t i = 0; i < r.size(); i++) (*this)[i] = (*this)[i] + r[i];\n\t\treturn *this;\n\t}\n\tpolynomial& operator+=(const_reference r) {\n\t\tif(this->empty()) this->push_back(T{});\n\t\t(*this)[0] += r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator-=(const polynomial& r) {\n\t\tif(r.size() > this->size()) this->resize(r.size());\n\t\tfor(size_t i = 0; i < r.size(); i++) (*this)[i] = (*this)[i] - r[i];\n\t\treturn *this;\n\t}\n\tpolynomial& operator-=(const_reference r) {\n\t\tif(this->empty()) this->push_back(T{});\n\t\t(*this)[0] -= r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator*=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator/=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] / r;\n\t\treturn *this;\n\t}\n\tpolynomial& operator<<=(size_type r) {\n\t\tthis->insert(begin(*this), r, T{});\n\t\treturn *this;\n\t}\n\tpolynomial& operator>>=(size_type r) {\n\t\tif(r >= this->size()) this->clear();\n\t\telse this->erase(begin(*this), begin(*this) + r);\n\t\treturn *this;\n\t}\n\tpolynomial& operator*=(const polynomial& r) {\n\t\tpolynomial ret(this->degree() + r.degree() + 1);\n\t\tfor(size_t i = 0; i < this->size(); i++) {\n\t\t\tif((*this)[i] == T{}) continue;\n\t\t\tfor(size_t j = 0; j < r.size(); j++) ret[i + j] += (*this)[i] * r[j];\n\t\t}\n\t\treturn *this = std::move(ret);\n\t};\n\n\tpolynomial differential(size_type k) const {\n\t\tpolynomial ret(*this);\n\t\tfor(size_t i = 0; i < k; i++) ret = ret.differential();\n\t\treturn ret;\n\t}\n\tpolynomial differential() const {\n\t\tif(degree() < 1) return polynomial();\n\t\tpolynomial ret(this->size() - 1);\n\t\tfor(size_t i = 1; i < this->size(); i++) ret[i - 1] = (*this)[i] * T(i);\n\t\treturn ret;\n\t}\n\tpolynomial integral(size_type k) const {\n\t\tpolynomial ret(*this);\n\t\tfor(size_t i = 0; i < k; i++) ret = ret.integral();\n\t\treturn ret;\n\t}\n\tpolynomial integral() const {\n\t\tpolynomial ret(this->size() + 1);\n\t\tfor(size_t i = 0; i < this->size(); i++) ret[i + 1] = (*this)[i] / T(i + 1);\n\t\treturn ret;\n\t}\n\tpolynomial prefix(size_type size) const {\n\t\treturn polynomial(begin(*this), begin(*this) + std::min(this->size(), size));\n\t}\n\tvoid shrink() {\n\t\twhile(!this->empty() and this->back() == T{}) this->pop_back();\n\t}\n\npublic:\n\tpolynomial sparse_convex(const polynomial& r) const {\n\t\tif(this->nonzeros() < r.nonzeros()) return (*this) * r;\n\t\treturn r * (*this);\n\t}\n\tsize_type degree() const { return std::max<size_type>(1, this->size()) - 1; }\n\tsize_type nonzeros() const {\n\t\tsize_type ret = 0;\n\t\tfor(size_t i = 0; i < this->size(); i++) {\n\t\t\tif((*this)[i] != T{}) ret++;\n\t\t}\n\t\treturn ret;\n\t}\n\tT operator()(T x) const { return eval(x); }\n\tT eval(T x) const {\n\t\tT ret = (*this)[0], tmp = x;\n\t\tfor(size_t i = 1; i < this->size(); i++) {\n\t\t\tret = ret + (*this)[i] * tmp;\n\t\t\ttmp = tmp * x;\n\t\t}\n\t\treturn ret;\n\t}\n\n\tstatic polynomial<T> one() { return term(0); }\n\tstatic polynomial<T> zero() { return polynomial<T>({T{0}}); }\n\tstatic polynomial<T> term(int k) { return polynomial<T>({T{1}}) << k; }\n};\n\ntemplate<class T> T convex_all(std::vector<T> polies, int size = -1) {\n\tif(polies.empty()) return T::zero();\n\n\tstd::deque<int> qu;\n\tfor(int i = 0; i < polies.size(); i++) qu.push_back(i);\n\twhile(qu.size() > 1) {\n\t\tint a = qu.front(); qu.pop_front();\n\t\tint b = qu.front(); qu.pop_front();\n\n\t\tpolies.push_back(polies[a] * polies[b]);\n\t\tif(size != -1) polies.back().resize(size);\n\t\tqu.push_back((int)polies.size() - 1);\n\t}\n\treturn polies.back();\n}\n}\n\n\n#line 6 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/fast_fourier_transform.hpp\"\n\nnamespace cplib {\ntemplate<class T, class Real = double, class Complex = std::complex<Real>>\nclass fast_fourier_transform: public polynomial<T> {\npublic:\n\tusing polynomial<T>::polynomial;\n\tusing value_type = typename polynomial<T>::value_type;\n\tusing reference = typename polynomial<T>::reference;\n\tusing const_reference = typename polynomial<T>::const_reference;\n\tusing size_type = typename polynomial<T>::size_type;\n\nprivate:\n\t// constexpr Real PI = std::numbers::pi_v<Real>;\n\tstatic constexpr Real PI = std::acos(Real(-1));;\n\n\tvoid transform(polynomial<Complex>& a, bool inverse = false) {\n\t\tsize_type n = 0;\n\t\twhile((1 << n) < a.size()) n++;\n\t\tsize_type N = 1 << n;\n\t\ta.resize(N);\n\n\t\tsize_type mask = N - 1;\n\t\tpolynomial<Complex> tmp(N);\n\t\tfor(int i = N >> 1; i >= 1; i >>= 1) {\n\t\t\tReal theta = 2 * PI * i * (inverse ? -1 : 1) / N;\n\t\t\tComplex zeta(std::cos(theta), std::sin(theta));\n\t\t\tComplex powZeta(1);\n\n\t\t\tfor(int j = 0; j < N; j += i) {\n\t\t\t\tfor(int k = 0; k < i; k++) {\n\t\t\t\t\ttmp[j + k] = a[((j << 1) & mask) | k] + powZeta * a[(((j << 1) | i) & mask) | k];\n\t\t\t\t}\n\t\t\t\tpowZeta *= zeta;\n\t\t\t}\n\t\t\ta.swap(tmp);\n\t\t}\n\n\t\tif(n & 1) {\n\t\t\tstd::swap(a, tmp);\n\t\t\tfor(int i = 0; i < N; i++) a[i] = tmp[i];\n\t\t}\n\t\tif(inverse) for(int i = 0; i < N; i++) a[i] /= N;\n\t}\n\tfast_fourier_transform convolution(const fast_fourier_transform& ar, const fast_fourier_transform& br) {\n\t\tsize_type size = ar.degree() + br.degree() + 1;\n\t\tpolynomial<Complex> a(size);\n\t\tfor(int i = 0; i < ar.size(); i++) a[i].real(ar[i]);\n\t\tfor(int i = 0; i < br.size(); i++) a[i].imag(br[i]);\n\t\ttransform(a, false);\n\n\t\tint N = a.size();\n\t\tpolynomial<Complex> c(N);\n\t\tfor(int i = 0; i < N; i++) {\n\t\t\tint j = (i == 0 ? 0 : N - i);\n\t\t\tc[i] = (a[i] + conj(a[j])) * (a[i] - conj(a[j])) * Complex(0, -.25);\n\t\t}\n\t\ttransform(c, true);\n\n\t\tfast_fourier_transform ret(size);\n\t\tfor(int i = 0; i < size; i++) ret[i] = round(c[i].real());\n\t\treturn ret;\n\n\t}\npublic:\n\tfast_fourier_transform(const polynomial<T>& p): polynomial<T>(p) {}\n\n\tfast_fourier_transform operator*(const_reference r) const { return fast_fourier_transform(*this) *= r; }\n\tfast_fourier_transform& operator*=(const_reference r) {\n\t\tfor(int i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\tfast_fourier_transform operator*(const fast_fourier_transform& r) const { return fast_fourier_transform(*this) *= r; }\n\tfast_fourier_transform& operator*=(const fast_fourier_transform& r) {\n\t\treturn (*this) = convolution((*this), r);\n\t}\n};\n}\n\n// @docs docs/fast_fourier_transform.md\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/number_theoritic_transform.hpp\"\n\n\n\n#line 1 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/modint.hpp\"\n\n\n\n#line 5 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/modint.hpp\"\n\nnamespace cplib {\ntemplate <std::uint_fast64_t Modulus>\nclass modint {\n\tusing u32 = std::uint_fast32_t;\n\tusing u64 = std::uint_fast64_t;\n\tusing i32 = std::int_fast32_t;\n\tusing i64 = std::int_fast64_t;\n\n\tinline u64 apply(i64 x) { return (x < 0 ? x + Modulus : x); };\n\npublic:\n\tu64 a;\n\tstatic constexpr u64 mod = Modulus;\n\n\tconstexpr modint(const i64& x = 0) noexcept: a(apply(x % (i64)Modulus)) {}\n\n\tconstexpr modint operator+(const modint& rhs) const noexcept { return modint(*this) += rhs; }\n\tconstexpr modint operator-(const modint& rhs) const noexcept { return modint(*this) -= rhs; }\n\tconstexpr modint operator*(const modint& rhs) const noexcept { return modint(*this) *= rhs; }\n\tconstexpr modint operator/(const modint& rhs) const noexcept { return modint(*this) /= rhs; }\n\tconstexpr modint operator^(const u64& k) const noexcept { return modint(*this) ^= k; }\n\tconstexpr modint operator^(const modint& k) const noexcept { return modint(*this) ^= k.value(); }\n\tconstexpr modint operator-() const noexcept { return modint(Modulus - a); }\n\tconstexpr modint operator++() noexcept { return (*this) = modint(*this) + 1; }\n\tconstexpr modint operator--() noexcept { return (*this) = modint(*this) - 1; }\n\tconst bool operator==(const modint& rhs) const noexcept { return a == rhs.a; };\n\tconst bool operator!=(const modint& rhs) const noexcept { return a != rhs.a; };\n\tconst bool operator<=(const modint& rhs) const noexcept { return a <= rhs.a; };\n\tconst bool operator>=(const modint& rhs) const noexcept { return a >= rhs.a; };\n\tconst bool operator<(const modint& rhs) const noexcept { return a < rhs.a; };\n\tconst bool operator>(const modint& rhs) const noexcept { return a > rhs.a; };\n\tconstexpr modint& operator+=(const modint& rhs) noexcept {\n\t\ta += rhs.a;\n\t\tif (a >= Modulus) a -= Modulus;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator-=(const modint& rhs) noexcept {\n\t\tif (a < rhs.a) a += Modulus;\n\t\ta -= rhs.a;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator*=(const modint& rhs) noexcept {\n\t\ta = a * rhs.a % Modulus;\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator/=(modint rhs) noexcept {\n\t\tu64 exp = Modulus - 2;\n\t\twhile (exp) {\n\t\t\tif (exp % 2) (*this) *= rhs;\n\n\t\t\trhs *= rhs;\n\t\t\texp /= 2;\n\t\t}\n\t\treturn *this;\n\t}\n\tconstexpr modint& operator^=(u64 k) noexcept {\n\t\tauto b = modint(1);\n\t\twhile(k) {\n\t\t\tif(k & 1) b = b * (*this);\n\t\t\t(*this) *= (*this);\n\t\t\tk >>= 1;\n\t\t}\n\t\treturn (*this) = b;\n\t}\n\tconstexpr modint& operator=(const modint& rhs) noexcept {\n\t\ta = rhs.a;\n\t\treturn (*this);\n\t}\n\n\tconst modint inverse() const {\n\t\treturn modint(1) / *this;\n\t}\n\tconst modint power(i64 k) const {\n\t\tif(k < 0) return modint(*this).inverse() ^ (-k);\n\t\treturn modint(*this) ^ k;\n\t}\n\n\texplicit operator bool() const { return a; }\n\texplicit operator u64() const { return a; }\n\tconstexpr u64& value() noexcept { return a; }\n\tconstexpr const u64& value() const noexcept { return a; }\n\n\tfriend std::ostream& operator<<(std::ostream& os, const modint& p) {\n\t\treturn os << p.a;\n\t}\n\tfriend std::istream& operator>>(std::istream& is, modint& p) {\n\t\tu64 t;\n\t\tis >> t;\n\t\tp = modint(t);\n\t\treturn is;\n\t}\n};\n}\n\n\n#line 7 \"/home/ecasdqina/cpcpp/libs/library_cpp/math/number_theoritic_transform.hpp\"\n\nnamespace cplib {\ntemplate<std::uint_fast64_t MOD,\n\tint primitive_root = 3,\n\tclass T = modint<MOD>>\nclass number_theoritic_transform: public polynomial<T> {\npublic:\n\tusing polynomial<T>::polynomial;\n\tusing value_type \t = typename polynomial<T>::value_type;\n\tusing reference \t = typename polynomial<T>::reference;\n\tusing const_reference = typename polynomial<T>::const_reference;\n\tusing size_type \t = typename polynomial<T>::size_type;\n\npublic:\n\tnumber_theoritic_transform(const polynomial<T>& p): polynomial<T>(p) {}\n\nprotected:\n\tstatic void ntt(number_theoritic_transform& a) {\n\t\tsize_t N = a.size();\n\t\tstatic std::vector<T> dw;\n\t\tif(dw.size() < N) {\n\t\t\tint n = dw.size();\n\t\t\tdw.resize(N);\n\t\t\tfor(size_t i = n; i < N; i++) dw[i] = -(T(primitive_root) ^ ((T::mod - 1) >> (i + 2)));\n\t\t}\n\n\t\tfor(size_t m = N; m >>= 1;) {\n\t\t\tT w = 1;\n\t\t\tfor(size_t s = 0, k = 0; s < N; s += 2 * m) {\n\t\t\t\tfor(size_t i = s, j = s + m; i < s + m; i++, j++) {\n\t\t\t\t\tT x = a[i], y = a[j] * w;\n\t\t\t\t\ta[i] = x + y;\n\t\t\t\t\ta[j] = x - y;\n\t\t\t\t}\n\t\t\t\tw *= dw[__builtin_ctz(++k)];\n\t\t\t}\n\t\t}\n\t}\n\tstatic void intt(number_theoritic_transform& a) {\n\t\tsize_t N = a.size();\n\t\tstatic std::vector<T> idw;\n\t\tif(idw.size() < N) {\n\t\t\tsize_t n = idw.size();\n\t\t\tidw.resize(N);\n\t\t\tfor(size_t i = n; i < N; i++) idw[i] = (-(T(primitive_root) ^ ((T::mod - 1) >> (i + 2)))).inverse();\n\t\t}\n\n\t\tfor(size_t m = 1; m < N; m *= 2) {\n\t\t\tT w = 1;\n\t\t\tfor(size_t s = 0, k = 0; s < N; s += 2 * m) {\n\t\t\t\tfor(size_t i = s, j = s + m; i < s + m; i++, j++) {\n\t\t\t\t\tT x = a[i], y = a[j];\n\t\t\t\t\ta[i] = x + y;\n\t\t\t\t\ta[j] = (x - y) * w;\n\t\t\t\t}\n\t\t\t\tw *= idw[__builtin_ctz(++k)];\n\t\t\t}\n\t\t}\n\t}\n\tstatic void transform(number_theoritic_transform& a, bool inverse = false) {\n\t\tsize_type n = 0;\n\t\twhile((1ul << n) < a.size()) n++;\n\t\tsize_type N = 1 << n;\n\t\ta.resize(N);\n\n\t\tif(!inverse) {\n\t\t\tntt(a);\n\t\t} else {\n\t\t\tintt(a);\n\t\t\tT inv = T(N).inverse();\n\t\t\tfor(size_t i = 0; i < a.size(); i++) a[i] *= inv;\n\t\t}\n\t}\n\n\tstatic number_theoritic_transform convolution(const number_theoritic_transform& ar, const number_theoritic_transform& br) {\n\t\tsize_type size = ar.degree() + br.degree() + 1;\n\t\tnumber_theoritic_transform a(ar), b(br);\n\t\ta.resize(size);\n\t\tb.resize(size);\n\n\t\ttransform(a, false);\n\t\ttransform(b, false);\n\n\t\tfor(size_t i = 0; i < a.size(); i++) a[i] *= b[i];\n\t\ttransform(a, true);\n\t\ta.resize(size);\n\t\treturn a;\n\t}\n\npublic:\n\tnumber_theoritic_transform convolute(const number_theoritic_transform& r) const { return (*this) * r; }\n\tnumber_theoritic_transform operator*(const number_theoritic_transform& r) const { return number_theoritic_transform(*this) *= r; }\n\tnumber_theoritic_transform& operator*=(const number_theoritic_transform& r) {\n\t\treturn (*this) = convolution((*this), r);\n\t}\n\tnumber_theoritic_transform operator*(const_reference r) const { return number_theoritic_transform(*this) *= r; }\n\tnumber_theoritic_transform& operator*=(const_reference r) {\n\t\tfor(size_t i = 0; i < this->size(); i++) (*this)[i] = (*this)[i] * r;\n\t\treturn *this;\n\t}\n\n};\n}\n// @docs docs/number_theoritic_transform.md\n\n\n#line 8 \"wildcard_matching.hpp\"\n\n/*\n# 注意\n\t計算時に用いる値の最大値は、文字の種類数 σ とマッチング文字列の長さ N について、4Nσ^2 となる。\n\tデフォルト実装では NTT<998244353> を用いているので、上記の値が 998244353 をこえるとバグる。\n\t対策: 大きい MOD を使う。FFT を使う。\n\n# アルゴリズム\n\t文字列を数値列に変換しておく。ワイルドカードを 0 に、それ以外の文字は distinct な値に変換する。\n\t文字列 S, T がマッチしているかどうかは以下の式の値が 0 になるかどうかで分かる。\n\t\\sum_{i = 1}^{|S|} s_i * t_i * (s_i - t_i)^2\n*/\n\nnamespace cplib {\ntemplate<class convolution = number_theoritic_transform<998244353>> struct wildcard_matching_t {\n\tusing value_type = typename convolution::value_type;\n\tusing size_type = size_t;\n\n\tchar wildcard = '?';\n\nprivate:\n\t// \"?abcde...\" -> \"012345...\"\n\tconstexpr std::vector<value_type> string_to_num_array(const std::string& s, char offset = 'a') const {\n\t\tstd::vector<value_type> ret(s.size());\n\t\tfor(size_t i = 0; i < s.size(); i++) {\n\t\t\tret[i] = s[i] - offset + 1;\n\t\t\tif(s[i] == wildcard) ret[i] = 0;\n\t\t}\n\t\treturn std::move(ret);\n\t}\n\t// \"?abcde...\" -> \"011111...\"\n\tconstexpr std::vector<value_type> string_to_bin_array(const std::string& s) const {\n\t\tstd::vector<value_type> ret(s.size(), 1);\n\t\tfor(size_t i = 0; i < s.size(); i++) if(s[i] == wildcard) ret[i] = 0;\n\t\treturn std::move(ret);\n\t}\n\npublic:\n\t// c_k = \\sum_{i = 0}^{M - 1}a_{i + k}b_i\n\tconstexpr std::vector<value_type> cross_correlation(std::vector<value_type> a, std::vector<value_type> b) const {\n\t\treverse(begin(a), end(a));\n\t\tauto c = convolution{a}.convolute(b).prefix(a.size());\n\t\tc.erase(begin(c), begin(c) + (b.size() - 1));\n\t\treverse(begin(c), end(c));\n\t\treturn std::move(c);\n\t}\n\npublic:\n\ttemplate<class T>\n\tconstexpr std::vector<bool> matching(const std::vector<T>& a, const std::vector<T>& b) const {\n\t\tstd::vector<value_type> c(a.size()), d(b.size());\n\t\tfor(size_t i = 0; i < a.size(); i++) c[i] = (a[i] != 0);\n\t\tfor(size_t i = 0; i < b.size(); i++) d[i] = (b[i] != 0);\n\t\tauto A(c); for(size_t i = 0; i < A.size(); i++) A[i] = c[i] * a[i] * a[i];\n\t\tauto B(c); for(size_t i = 0; i < B.size(); i++) B[i] = c[i] * a[i];\n\t\tauto C(d); for(size_t i = 0; i < C.size(); i++) C[i] = d[i] * b[i];\n\t\tauto D(d); for(size_t i = 0; i < D.size(); i++) D[i] = d[i] * b[i] * b[i];\n\n\t\tstd::vector<bool> m(a.size() - b.size() + 1);\n\t\tauto X = cross_correlation(A, d);\n\t\tauto Y = cross_correlation(B, C);\n\t\tauto Z = cross_correlation(c, D);\n\t\tfor(size_t i = 0; i < m.size(); i++) m[i] = (X[i] - Y[i] * 2 + Z[i] == 0);\n\t\treturn std::move(m);\n\t}\n\n\tconstexpr std::vector<bool> matching(const std::string& s, const std::string& p) const {\n\t\tassert(!s.empty());\n\t\tassert(!p.empty());\n\t\treturn matching(string_to_num_array(s), string_to_num_array(p));\n\t}\n\tconstexpr std::vector<size_t> matching_index(const std::string& s, const std::string& p) const {\n\t\tauto match = matching(std::move(s), std::move(p));\n\t\tstd::vector<size_t> ret;\n\t\tfor(size_t i = 0; i < match.size(); i++) if(match[i]) ret.push_back(i);\n\t\treturn std::move(ret);\n\t}\n\n\tchar get_wildcard() const { return wildcard; }\n\tvoid set_wildcard(const char c) { wildcard = c; }\n};\nconstexpr wildcard_matching_t<> wildcard_matching = wildcard_matching_t<>();\n}\n#line 18 \"test.cpp\"\n\nint main() {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(nullptr);\n\n int AW, AH, BW, BH;\n std::cin >> AW >> AH >> BW >> BH;\n std::vector<int> s(AH * AW), p(AW * (BH - 1) + BW, 0);\n\n const auto convert = [](const char c) -> int {\n if (c == '?') {\n return 0;\n } else if ('0' <= c && c <= '9') {\n return c - '0' + 1;\n } else if ('a' <= c && c <= 'z') {\n return c - 'a' + 10 + 1;\n } else {\n return c - 'A' + 10 + 26 + 1;\n }\n };\n\n for (int i = 0; i != AH; ++i) {\n for (int j = 0; j != AW; ++j) {\n char c;\n std::cin >> c;\n s[AW * i + j] = convert(c);\n }\n }\n\n for (int i = 0; i != BH; ++i) {\n for (int j = 0; j != BW; ++j) {\n char c;\n std::cin >> c;\n p[AW * i + j] = convert(c);\n }\n }\n\n const auto m = cplib::wildcard_matching.matching(s, p);\n\n int ans = 0;\n for (int i = 0; i + BH <= AH; ++i) {\n for (int j = 0; j + BW <= AW; ++j) {\n if (m[AW * i + j]) {\n ++ans;\n }\n }\n }\n\n std::cout << ans << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 98584, "score_of_the_acc": -0.5403, "final_rank": 11 }, { "submission_id": "aoj_0378_5032279", "code_snippet": "#include<iostream>\n#include<algorithm>\n\n#include <algorithm>\n#include <array>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\nint bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n\n#include <utility>\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n static_modint(bool v) { _v = ((unsigned int)(v) % umod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n dynamic_modint(bool v) { _v = ((unsigned int)(v) % mod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <type_traits>\n#include <vector>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_e[30]; // sum_e[i] = ies[0] * ... * ies[i - 1] * es[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i <= cnt2 - 2; i++) {\n sum_e[i] = es[i] * now;\n now *= ies[i];\n }\n }\n for (int ph = 1; ph <= h; ph++) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint now = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p] * now;\n a[i + offset] = l + r;\n a[i + offset + p] = l - r;\n }\n now *= sum_e[bsf(~(unsigned int)(s))];\n }\n }\n}\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly_inv(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_ie[30]; // sum_ie[i] = es[0] * ... * es[i - 1] * ies[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i <= cnt2 - 2; i++) {\n sum_ie[i] = ies[i] * now;\n now *= es[i];\n }\n }\n\n for (int ph = h; ph >= 1; ph--) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint inow = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p];\n a[i + offset] = l + r;\n a[i + offset + p] =\n (unsigned long long)(mint::mod() + l.val() - r.val()) *\n inow.val();\n }\n inow *= sum_ie[bsf(~(unsigned int)(s))];\n }\n }\n}\n\n} // namespace internal\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nstd::vector<mint> convolution(std::vector<mint> a, std::vector<mint> b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n if (std::min(n, m) <= 60) {\n if (n < m) {\n std::swap(n, m);\n std::swap(a, b);\n }\n std::vector<mint> ans(n + m - 1);\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < m; j++) {\n ans[i + j] += a[i] * b[j];\n }\n }\n return ans;\n }\n int z = 1 << internal::ceil_pow2(n + m - 1);\n a.resize(z);\n internal::butterfly(a);\n b.resize(z);\n internal::butterfly(b);\n for (int i = 0; i < z; i++) {\n a[i] *= b[i];\n }\n internal::butterfly_inv(a);\n a.resize(n + m - 1);\n mint iz = mint(z).inv();\n for (int i = 0; i < n + m - 1; i++) a[i] *= iz;\n return a;\n}\n\ntemplate <unsigned int mod = 998244353,\n class T,\n std::enable_if_t<internal::is_integral<T>::value>* = nullptr>\nstd::vector<T> convolution(const std::vector<T>& a, const std::vector<T>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n using mint = static_modint<mod>;\n std::vector<mint> a2(n), b2(m);\n for (int i = 0; i < n; i++) {\n a2[i] = mint(a[i]);\n }\n for (int i = 0; i < m; i++) {\n b2[i] = mint(b[i]);\n }\n auto c2 = convolution(move(a2), move(b2));\n std::vector<T> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n c[i] = c2[i].val();\n }\n return c;\n}\n\nstd::vector<long long> convolution_ll(const std::vector<long long>& a,\n const std::vector<long long>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n static constexpr unsigned long long MOD1 = 754974721; // 2^24\n static constexpr unsigned long long MOD2 = 167772161; // 2^25\n static constexpr unsigned long long MOD3 = 469762049; // 2^26\n static constexpr unsigned long long M2M3 = MOD2 * MOD3;\n static constexpr unsigned long long M1M3 = MOD1 * MOD3;\n static constexpr unsigned long long M1M2 = MOD1 * MOD2;\n static constexpr unsigned long long M1M2M3 = MOD1 * MOD2 * MOD3;\n\n static constexpr unsigned long long i1 =\n internal::inv_gcd(MOD2 * MOD3, MOD1).second;\n static constexpr unsigned long long i2 =\n internal::inv_gcd(MOD1 * MOD3, MOD2).second;\n static constexpr unsigned long long i3 =\n internal::inv_gcd(MOD1 * MOD2, MOD3).second;\n\n auto c1 = convolution<MOD1>(a, b);\n auto c2 = convolution<MOD2>(a, b);\n auto c3 = convolution<MOD3>(a, b);\n\n std::vector<long long> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n unsigned long long x = 0;\n x += (c1[i] * i1) % MOD1 * M2M3;\n x += (c2[i] * i2) % MOD2 * M1M3;\n x += (c3[i] * i3) % MOD3 * M1M2;\n // B = 2^63, -B <= x, r(real value) < B\n // (x, x - M, x - 2M, or x - 3M) = r (mod 2B)\n // r = c1[i] (mod MOD1)\n // focus on MOD1\n // r = x, x - M', x - 2M', x - 3M' (M' = M % 2^64) (mod 2B)\n // r = x,\n // x - M' + (0 or 2B),\n // x - 2M' + (0, 2B or 4B),\n // x - 3M' + (0, 2B, 4B or 6B) (without mod!)\n // (r - x) = 0, (0)\n // - M' + (0 or 2B), (1)\n // -2M' + (0 or 2B or 4B), (2)\n // -3M' + (0 or 2B or 4B or 6B) (3) (mod MOD1)\n // we checked that\n // ((1) mod MOD1) mod 5 = 2\n // ((2) mod MOD1) mod 5 = 3\n // ((3) mod MOD1) mod 5 = 4\n long long diff =\n c1[i] - internal::safe_mod((long long)(x), (long long)(MOD1));\n if (diff < 0) diff += MOD1;\n static constexpr unsigned long long offset[5] = {\n 0, 0, M1M2M3, 2 * M1M2M3, 3 * M1M2M3};\n x -= offset[diff % 5];\n c[i] = x;\n }\n\n return c;\n}\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\nint AW,AH,BW,BH;\nmain()\n{\n\tcin>>AW>>AH>>BW>>BH;\n\tvector<long long>a1(AW*AH),a2(AW*AH),a3(AW*AH);\n\tfor(int i=0;i<AH;i++)\n\t{\n\t\tstring A;\n\t\tcin>>A;\n\t\tfor(int j=0;j<AW;j++)\n\t\t{\n\t\t\ta1[i*AW+j]=A[j]=='?'?0:A[j];\n\t\t\ta2[i*AW+j]=a1[i*AW+j]*a1[i*AW+j];\n\t\t\ta3[i*AW+j]=a1[i*AW+j]*a2[i*AW+j];\n\t\t}\n\t}\n\tint len=BH*AW-(AW-BW);\n\tvector<long long>b1(len),b2(len),b3(len);\n\tfor(int i=0;i<BH;i++)\n\t{\n\t\tstring B;\n\t\tcin>>B;\n\t\tfor(int j=0;j<BW;j++)\n\t\t{\n\t\t\tb1[i*AW+j]=B[j]=='?'?0:B[j];\n\t\t\tb2[i*AW+j]=b1[i*AW+j]*b1[i*AW+j];\n\t\t\tb3[i*AW+j]=b1[i*AW+j]*b2[i*AW+j];\n\t\t}\n\t}\n\treverse(b1.begin(),b1.end());\n\treverse(b2.begin(),b2.end());\n\treverse(b3.begin(),b3.end());\n\tvector<long long>c1=convolution_ll(a3,b1);\n\tvector<long long>c2=convolution_ll(a2,b2);\n\tvector<long long>c3=convolution_ll(a1,b3);\n\tint ans=0;\n\tfor(int i=0;i+BH<=AH;i++)\n\t{\n\t\tfor(int j=0;j<=AW-BW;j++)\n\t\t{\n\t\t\tlong t=c1[len-1+i*AW+j]-2*c2[len-1+i*AW+j]+c3[len-1+i*AW+j];\n\t\t\tif(t==0)ans++;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 55128, "score_of_the_acc": -0.7798, "final_rank": 14 }, { "submission_id": "aoj_0378_4981369", "code_snippet": "#include <bitset>\n#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\nusing namespace std;\nint transform(char ch) {\n\tif ('0' <= ch && ch <= '9') return ch - '0' + 1;\n\tif ('A' <= ch && ch <= 'Z') return ch - 'A' + 11;\n\tif ('a' <= ch && ch <= 'z') return ch - 'a' + 37;\n\treturn 0;\n}\nbitset<640> bit1[128], bit2[128], bit3[128], bit4[128];\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint AH, AW, BH, BW;\n\tcin >> AW >> AH >> BW >> BH;\n\tvector<vector<int> > A(AH, vector<int>(AW)), B(BH, vector<int>(BW));\n\tfor (int i = 0; i < AH; ++i) {\n\t\tstring str;\n\t\tcin >> str;\n\t\tfor (int j = 0; j < AW; ++j) {\n\t\t\tA[i][j] = transform(str[j]);\n\t\t}\n\t}\n\tfor (int i = 0; i < BH; ++i) {\n\t\tstring str;\n\t\tcin >> str;\n\t\tfor (int j = 0; j < BW; ++j) {\n\t\t\tB[i][j] = transform(str[j]);\n\t\t}\n\t}\n\tfor (int i = 0; i < BH; ++i) {\n\t\tfor (int j = 0; j < BW; ++j) {\n\t\t\tfor (int k = 0; k < 6; ++k) {\n\t\t\t\tbit3[i][j * 6 + k] = ((B[i][j] >> k) & 1);\n\t\t\t\tbit4[i][j * 6 + k] = (B[i][j] != 0 ? 1 : 0);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 0; i <= AH - BH; ++i) {\n\t\tfor (int j = 0; j < BH; ++j) {\n\t\t\tfor (int k = 0; k < BW; ++k) {\n\t\t\t\tfor (int l = 0; l < 6; ++l) {\n\t\t\t\t\tbit1[j][k * 6 + l] = ((A[i + j][k] >> l) & 1);\n\t\t\t\t\tbit2[j][k * 6 + l] = (A[i + j][k] != 0 ? 1 : 0);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j <= AW - BW; ++j) {\n\t\t\tbool ok = true;\n\t\t\tfor (int k = 0; k < BH; ++k) {\n\t\t\t\tif (((bit1[k] ^ bit3[k]) & (bit2[k] & bit4[k])) != 0) {\n\t\t\t\t\tok = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (ok) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t\tif (j != AW - BW) {\n\t\t\t\tfor (int k = 0; k < BH; ++k) {\n\t\t\t\t\tbit1[k] >>= 6;\n\t\t\t\t\tbit2[k] >>= 6;\n\t\t\t\t\tfor (int l = 0; l < 6; ++l) {\n\t\t\t\t\t\tbit1[k][BW * 6 - 6 + l] = ((A[i + k][j + BW] >> l) & 1);\n\t\t\t\t\t\tbit2[k][BW * 6 - 6 + l] = (A[i + k][j + BW] != 0 ? 1 : 0);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1380, "memory_kb": 5440, "score_of_the_acc": -0.8709, "final_rank": 15 }, { "submission_id": "aoj_0378_4978995", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint num(char c){\n if ('A' <= c && c <= 'Z'){\n return c - 'A';\n } else if ('a' <= c && c <= 'z'){\n return c - 'a' + 26;\n } else if ('0' <= c && c <= '9'){\n return c - '0' + 52;\n } else {\n return 62;\n }\n}\nint main(){\n int AW, AH, BW, BH;\n cin >> AW >> AH >> BW >> BH;\n vector<vector<char>> A(AH + 200, vector<char>(AW + 200, '#'));\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n cin >> A[i][j];\n }\n }\n vector<vector<char>> B(BH, vector<char>(BW));\n for (int i = 0; i < BH; i++){\n for (int j = 0; j < BW; j++){\n cin >> B[i][j];\n }\n }\n vector<vector<int>> id(AH + 200, vector<int>(AW + 200));\n for (int i = 0; i < AH + 200; i++){\n for (int j = 0; j < AW + 200; j++){\n id[i][j] = i * (AW + 200) + j;\n }\n }\n bitset<1000000> X(0);\n for (int i = 0; i < AH + 200; i++){\n for (int j = 0; j < AW + 200; j++){\n if (A[i][j] != '?'){\n X.set(id[i][j]);\n }\n }\n }\n vector<vector<int>> posA(63);\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n if (A[i][j] != '?'){\n posA[num(A[i][j])].push_back(id[i][j]);\n }\n }\n }\n vector<vector<int>> posB(63);\n for (int i = 0; i < BH; i++){\n for (int j = 0; j < BW; j++){\n if (B[i][j] != '?'){\n posB[num(B[i][j])].push_back(id[i][j]);\n }\n }\n }\n bitset<1000000> ans(0);\n for (int i = 0; i < 1000000; i++){\n ans.set(i);\n }\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n if (A[i][j] != '#' && A[i + BH - 1][j + BW - 1] != '#'){\n ans.reset(id[i][j]);\n }\n }\n }\n for (int i = 0; i < 62; i++){\n for (int j : posA[i]){\n X.reset(j);\n }\n for (int j : posB[i]){\n ans |= X >> j;\n }\n for (int j : posA[i]){\n X.set(j);\n }\n }\n int cnt = 0;\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n if (ans[id[i][j]] == 0){\n cnt++;\n }\n }\n }\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 10420, "score_of_the_acc": -0.1555, "final_rank": 7 }, { "submission_id": "aoj_0378_4978984", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint num(char c){\n if ('A' <= c && c <= 'Z'){\n return c - 'A';\n } else if ('a' <= c && c <= 'z'){\n return c - 'a' + 26;\n } else if ('0' <= c && c <= '9'){\n return c - '0' + 52;\n } else {\n return 62;\n }\n}\nint main(){\n int AW, AH, BW, BH;\n cin >> AW >> AH >> BW >> BH;\n vector<vector<char>> A(AH + 200, vector<char>(AW + 200, '#'));\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n cin >> A[i][j];\n }\n }\n vector<vector<char>> B(BH, vector<char>(BW));\n for (int i = 0; i < BH; i++){\n for (int j = 0; j < BW; j++){\n cin >> B[i][j];\n }\n }\n vector<vector<int>> id(AH + 200, vector<int>(AW + 200));\n for (int i = 0; i < AH + 200; i++){\n for (int j = 0; j < AW + 200; j++){\n id[i][j] = i * (AW + 200) + j;\n }\n }\n bitset<1000000> X(0);\n for (int i = 0; i < AH + 200; i++){\n for (int j = 0; j < AW + 200; j++){\n if (A[i][j] != '?'){\n X.set(id[i][j]);\n }\n }\n }\n vector<vector<int>> posA(63);\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n if (A[i][j] != '?'){\n posA[num(A[i][j])].push_back(id[i][j]);\n }\n }\n }\n vector<vector<int>> posB(63);\n for (int i = 0; i < BH; i++){\n for (int j = 0; j < BW; j++){\n if (B[i][j] != '?'){\n posB[num(B[i][j])].push_back(id[i][j]);\n }\n }\n }\n bitset<1000000> ans;\n for (int i = 0; i < 62; i++){\n for (int j : posA[i]){\n X.reset(j);\n }\n for (int j : posB[i]){\n ans |= X >> j;\n }\n for (int j : posA[i]){\n X.set(j);\n }\n }\n int cnt = 0;\n for (int i = 100; i < AH + 100; i++){\n for (int j = 100; j < AW + 100; j++){\n if (ans[id[i][j]] == 0){\n cnt++;\n }\n }\n }\n cout << cnt << endl;\n}", "accuracy": 0.5357142857142857, "time_ms": 260, "memory_kb": 8956, "score_of_the_acc": -0.0922, "final_rank": 19 }, { "submission_id": "aoj_0378_4899489", "code_snippet": "#include <algorithm>\n#include <array>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\nint bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n\n#include <cassert>\n#include <utility>\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast moduler by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n // _umul128(z, im, &x);\n x = 0;\n std::abort();\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n for (long long a : {2, 7, 61}) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n static_modint(bool v) { _v = ((unsigned int)(v) % umod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n dynamic_modint(bool v) { _v = ((unsigned int)(v) % mod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <type_traits>\n#include <vector>\n\nnamespace atcoder {\n\nnamespace internal {\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_e[30]; // sum_e[i] = ies[0] * ... * ies[i - 1] * es[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i < cnt2 - 2; i++) {\n sum_e[i] = es[i] * now;\n now *= ies[i];\n }\n }\n for (int ph = 1; ph <= h; ph++) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint now = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p] * now;\n a[i + offset] = l + r;\n a[i + offset + p] = l - r;\n }\n now *= sum_e[bsf(~(unsigned int)(s))];\n }\n }\n}\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nvoid butterfly_inv(std::vector<mint>& a) {\n static constexpr int g = internal::primitive_root<mint::mod()>;\n int n = int(a.size());\n int h = internal::ceil_pow2(n);\n\n static bool first = true;\n static mint sum_ie[30]; // sum_ie[i] = es[0] * ... * es[i - 1] * ies[i]\n if (first) {\n first = false;\n mint es[30], ies[30]; // es[i]^(2^(2+i)) == 1\n int cnt2 = bsf(mint::mod() - 1);\n mint e = mint(g).pow((mint::mod() - 1) >> cnt2), ie = e.inv();\n for (int i = cnt2; i >= 2; i--) {\n // e^(2^i) == 1\n es[i - 2] = e;\n ies[i - 2] = ie;\n e *= e;\n ie *= ie;\n }\n mint now = 1;\n for (int i = 0; i < cnt2 - 2; i++) {\n sum_ie[i] = ies[i] * now;\n now *= es[i];\n }\n }\n\n for (int ph = h; ph >= 1; ph--) {\n int w = 1 << (ph - 1), p = 1 << (h - ph);\n mint inow = 1;\n for (int s = 0; s < w; s++) {\n int offset = s << (h - ph + 1);\n for (int i = 0; i < p; i++) {\n auto l = a[i + offset];\n auto r = a[i + offset + p];\n a[i + offset] = l + r;\n a[i + offset + p] =\n (unsigned long long)(mint::mod() + l.val() - r.val()) *\n inow.val();\n }\n inow *= sum_ie[bsf(~(unsigned int)(s))];\n }\n }\n}\n\n} // namespace internal\n\ntemplate <class mint, internal::is_static_modint_t<mint>* = nullptr>\nstd::vector<mint> convolution(std::vector<mint> a, std::vector<mint> b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n if (std::min(n, m) <= 60) {\n if (n < m) {\n std::swap(n, m);\n std::swap(a, b);\n }\n std::vector<mint> ans(n + m - 1);\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < m; j++) {\n ans[i + j] += a[i] * b[j];\n }\n }\n return ans;\n }\n int z = 1 << internal::ceil_pow2(n + m - 1);\n a.resize(z);\n internal::butterfly(a);\n b.resize(z);\n internal::butterfly(b);\n for (int i = 0; i < z; i++) {\n a[i] *= b[i];\n }\n internal::butterfly_inv(a);\n a.resize(n + m - 1);\n mint iz = mint(z).inv();\n for (int i = 0; i < n + m - 1; i++) a[i] *= iz;\n return a;\n}\n\ntemplate <unsigned int mod = 998244353,\n class T,\n std::enable_if_t<internal::is_integral<T>::value>* = nullptr>\nstd::vector<T> convolution(const std::vector<T>& a, const std::vector<T>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n using mint = static_modint<mod>;\n std::vector<mint> a2(n), b2(m);\n for (int i = 0; i < n; i++) {\n a2[i] = mint(a[i]);\n }\n for (int i = 0; i < m; i++) {\n b2[i] = mint(b[i]);\n }\n auto c2 = convolution(move(a2), move(b2));\n std::vector<T> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n c[i] = c2[i].val();\n }\n return c;\n}\n\nstd::vector<long long> convolution_ll(const std::vector<long long>& a,\n const std::vector<long long>& b) {\n int n = int(a.size()), m = int(b.size());\n if (!n || !m) return {};\n\n static constexpr unsigned long long MOD1 = 754974721; // 2^24\n static constexpr unsigned long long MOD2 = 167772161; // 2^25\n static constexpr unsigned long long MOD3 = 469762049; // 2^26\n static constexpr unsigned long long M2M3 = MOD2 * MOD3;\n static constexpr unsigned long long M1M3 = MOD1 * MOD3;\n static constexpr unsigned long long M1M2 = MOD1 * MOD2;\n static constexpr unsigned long long M1M2M3 = MOD1 * MOD2 * MOD3;\n\n static constexpr unsigned long long i1 =\n internal::inv_gcd(MOD2 * MOD3, MOD1).second;\n static constexpr unsigned long long i2 =\n internal::inv_gcd(MOD1 * MOD3, MOD2).second;\n static constexpr unsigned long long i3 =\n internal::inv_gcd(MOD1 * MOD2, MOD3).second;\n\n auto c1 = convolution<MOD1>(a, b);\n auto c2 = convolution<MOD2>(a, b);\n auto c3 = convolution<MOD3>(a, b);\n\n std::vector<long long> c(n + m - 1);\n for (int i = 0; i < n + m - 1; i++) {\n unsigned long long x = 0;\n x += (c1[i] * i1) % MOD1 * M2M3;\n x += (c2[i] * i2) % MOD2 * M1M3;\n x += (c3[i] * i3) % MOD3 * M1M2;\n // B = 2^63, -B <= x, r(real value) < B\n // (x, x - M, x - 2M, or x - 3M) = r (mod 2B)\n // r = c1[i] (mod MOD1)\n // focus on MOD1\n // r = x, x - M', x - 2M', x - 3M' (M' = M % 2^64) (mod 2B)\n // r = x,\n // x - M' + (0 or 2B),\n // x - 2M' + (0, 2B or 4B),\n // x - 3M' + (0, 2B, 4B or 6B) (without mod!)\n // (r - x) = 0, (0)\n // - M' + (0 or 2B), (1)\n // -2M' + (0 or 2B or 4B), (2)\n // -3M' + (0 or 2B or 4B or 6B) (3) (mod MOD1)\n // we checked that\n // ((1) mod MOD1) mod 5 = 2\n // ((2) mod MOD1) mod 5 = 3\n // ((3) mod MOD1) mod 5 = 4\n long long diff =\n c1[i] - internal::safe_mod((long long)(x), (long long)(MOD1));\n if (diff < 0) diff += MOD1;\n static constexpr unsigned long long offset[5] = {\n 0, 0, M1M2M3, 2 * M1M2M3, 3 * M1M2M3};\n x -= offset[diff % 5];\n c[i] = x;\n }\n\n return c;\n}\n\n} // namespace atcoder\n\n\n#include <algorithm>\n#include <cassert>\n#include <cstddef>\n#include <vector>\n\nstd::vector<bool> wildcard_pattern_matching(const std::vector<int> &p,\n const std::vector<int> &s) {\n using ll = long long;\n using usize = std::size_t;\n static constexpr int mod = 1811939329;\n using mint = atcoder::static_modint<mod>;\n\n const usize n = p.size();\n const usize m = s.size();\n\n assert(1 <= n);\n assert(m <= m);\n assert(n + m - 1 <= (mod - 1 & ~(mod - 1) + 1));\n assert(std::all_of(p.begin(), p.end(), [](int x) { return -1 <= x < mod; }));\n assert(std::all_of(s.begin(), s.end(), [](int x) { return -1 <= x < mod; }));\n {\n const int max = std::max(*std::max_element(p.begin(), p.end()),\n *std::max_element(s.begin(), s.end()));\n assert(ll(max) * max < mod);\n assert(ll(max) * max * p.size() < mod);\n }\n\n std::vector<mint> sum(m - n + 1, mint(0));\n\n const auto add = [&](const auto f, const auto g) {\n std::vector<mint> x(n), y(m);\n for (usize i = 0; i != n; ++i) {\n x[i] = f(p[n - 1 - i]);\n }\n for (usize i = 0; i != m; ++i) {\n y[i] = g(s[i]);\n }\n const auto z = atcoder::convolution(x, y);\n for (usize i = 0; i != m - n + 1; ++i) {\n sum[i] += z[n - 1 + i];\n }\n };\n\n add([](const int v) { return ll(v != -1) * v * v; },\n [](const int v) { return int(v != -1); });\n add([](const int v) { return -2 * int(v != -1) * v; },\n [](const int v) { return int(v != -1) * v; });\n add([](const int v) { return int(v != -1); },\n [](const int v) { return ll(v != -1) * v * v; });\n\n std::vector<bool> res(m - n + 1);\n for (usize i = 0; i != m - n + 1; ++i) {\n res[i] = sum[i].val() == 0;\n }\n\n return res;\n}\n\n#include <iostream>\n#include <string>\n\nint main() {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(nullptr);\n\n int AW, AH, BW, BH;\n std::cin >> AW >> AH >> BW >> BH;\n std::vector<int> s(AH * AW), p(AW * (BH - 1) + BW, -1);\n\n const auto convert = [](const char c) -> int {\n if (c == '?') {\n return -1;\n } else if ('0' <= c && c <= '9') {\n return c - '0';\n } else if ('a' <= c && c <= 'z') {\n return c - 'a' + 10;\n } else {\n return c - 'A' + 10 + 26;\n }\n };\n\n for (int i = 0; i != AH; ++i) {\n for (int j = 0; j != AW; ++j) {\n char c;\n std::cin >> c;\n s[AW * i + j] = convert(c);\n }\n }\n\n for (int i = 0; i != BH; ++i) {\n for (int j = 0; j != BW; ++j) {\n char c;\n std::cin >> c;\n p[AW * i + j] = convert(c);\n }\n }\n\n const auto m = wildcard_pattern_matching(p, s);\n int ans = 0;\n for (int i = 0; i + BH <= AH; ++i) {\n for (int j = 0; j + BW <= AW; ++j) {\n if (m[AW * i + j]) {\n ++ans;\n }\n }\n }\n\n std::cout << ans << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 22408, "score_of_the_acc": -0.1237, "final_rank": 5 }, { "submission_id": "aoj_0378_4885390", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <class T, class U>\nvector<T> make_v(U size, const T& init){ return vector<T>(static_cast<size_t>(size), init); }\n\ntemplate<class... Ts, class U>\nauto make_v(U size, Ts... rest) { return vector<decltype(make_v(rest...))>(static_cast<size_t>(size), make_v(rest...)); }\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\n\nint main() {\n using bset = bitset<800>;\n int W, H, w, h;\n cin >> W >> H >> w >> h;\n vector<string> A(H), B(h);\n for (auto &&i : A) cin >> i;\n for (auto &&i : B) cin >> i;\n auto p = make_v(H, W-w+1, bset()), q = p;\n auto r = make_v(h, bset()), s = make_v(h, bset());\n for (int i = 0; i < H; ++i) {\n for (int j = 0; j+w-1 < W; ++j) {\n for (int k = 0; k < w; ++k) {\n if(A[i][j+k] == '?') {\n for (int l = k<<3; l < (k+1)<<3; ++l) {\n q[i][j].set(l);\n }\n }else {\n for (int l = 0; l < 8; ++l) {\n if(A[i][j+k]&(1 << l)) p[i][j].set((k<<3)|l), q[i][j].set((k<<3)|l);\n }\n }\n }\n }\n }\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n if(B[i][j] == '?') {\n for (int l = j<<3; l < (j+1)<<3; ++l) {\n s[i].set(l);\n }\n }else {\n for (int l = 0; l < 8; ++l) {\n if(B[i][j]&(1 << l)) r[i].set((j<<3)|l), s[i].set((j<<3)|l);\n }\n }\n }\n }\n int ans = 0;\n for (int i = 0; i+h-1 < H; ++i) {\n for (int j = 0; j+w-1 < W; ++j) {\n int ok = 1;\n for (int k = 0; k < h && ok; ++k) {\n ok &= ((p[i+k][j]&s[k]) == p[i+k][j]) & ((q[i+k][j]&r[k]) == r[k]);\n }\n if(ok) {\n ans++;\n }\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 1570, "memory_kb": 132224, "score_of_the_acc": -1.5693, "final_rank": 17 }, { "submission_id": "aoj_0378_2952274", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n#define NUM 64\n\nchar A[800][801];\nchar B[100][101];\n\nint AW,AH,BW,BH;\nint state_len;\n\nll MASK[100][3][256]; //MASK[パターンの行][列/64][文字]\nll state_table[100][3]; //状態配列\nll POW[NUM];\nll AMARI,NUMBER;\n\n\nvoid makeMask(){\n\n\tfor(int row = 0; row < BH; row++){\n\t\tfor(int col = 0; col < 3; col++){\n\t\t\tfor(int i = 0; i < 256; i++)MASK[row][col][i] = 0;\n\t\t}\n\t}\n\n\tAMARI = (ll)(BW%NUM);\n\n\tif(AMARI == 0){\n\t\tstate_len = BW/NUM;\n\t}else{\n\t\tstate_len = BW/NUM+1;\n\t}\n\n\tNUMBER = (1LL << (AMARI+(NUM-1))%NUM);\n\n \tstring L = \"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789?\";\n\n\tfor(int B_row = 0; B_row < BH; B_row++){ //パターンの行\n\t\tfor(int col = 0; col < L.size(); col++){ //文字等\n\t\t\tfor(int i = 0; i < state_len; i++){\n\t\t\t\tfor(int k = 0; k < NUM; k++){\n\t\t\t\t\tif(i*NUM+k >= BW)continue;\n\t\t\t\t\tif(B[B_row][i*NUM+k] == L[col] || L[col] == '?' || B[B_row][i*NUM+k] == '?'){\n\t\t\t\t\t\tMASK[B_row][i][L[col]] += POW[k]; //対象文字等との一致可能性をbitで表す\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint main(){\n\n\tfor(int i = 0; i < NUM; i++)POW[i] = pow(2,i);\n\n\tscanf(\"%d %d %d %d\",&AW,&AH,&BW,&BH);\n\n\tfor(int row = 0; row < AH; row++){\n\t\tscanf(\"%s\",A[row]);\n\t}\n\n\tfor(int row = 0; row < BH; row++){\n\t\tscanf(\"%s\",B[row]);\n\t}\n\n\tmakeMask();\n\n\tint ans = 0,match_num,tmp;\n\n\tfor(int A_row = 0; A_row+BH <= AH; A_row++){ //検索始点行\n\n\t\tfor(int B_row = 0; B_row < BH; B_row++){\n\t\t\tfor(int i= 0; i < state_len; i++){\n\t\t\t\tstate_table[B_row][i] = 0; //状態配列を初期化\n\t\t\t}\n\t\t}\n\n\t\tfor(int A_col = 0; A_col < AW; A_col++){ //検索始点列\n\n\t\t\tmatch_num = 0;\n\n\t\t\tfor(int B_row = 0; B_row < BH; B_row++){ //縦にBH分比較\n\n\t\t\t\tfor(int i = state_len-1; i >= 0; i--){ //デクリメント\n\t\t\t\t\tif(i == 0){\n\t\t\t\t\t\ttmp = 1; //最下位ビットは1\n\t\t\t\t\t}else{\n\n\t\t\t\t\t\tif(state_table[B_row][i-1] & POW[NUM-1]){ //★左に1ビットするので、新しい最下位ビットは、state_table[B_row][i-1]の最上位ビット★\n\t\t\t\t\t\t\ttmp = 1;\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\ttmp = 0;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tstate_table[B_row][i] = ((state_table[B_row][i] << 1)|tmp)&MASK[B_row][i][A[A_row+B_row][A_col]];\n\t\t\t\t}\n\t\t\t\tif(state_table[B_row][state_len-1]&NUMBER)match_num++; //最上位ビットが1なら、その行は一致\n\t\t\t}\n\t\t\tif(match_num == BH)ans++; //全部の行が一致した場合\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 4600, "score_of_the_acc": -0.0587, "final_rank": 3 }, { "submission_id": "aoj_0378_2675372", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst auto CHARS = 64;\nusing Bit = bitset<800>;\n\nint to_i(char c) {\n if(isdigit(c)) return c - '0';\n if(islower(c)) return c - 'a' + 10;\n if(isupper(c)) return c - 'A' + 36;\n return 63;\n}\n\nint main() {\n int AW, AH, BW, BH;\n cin >> AW >> AH >> BW >> BH;\n vector<string> a(AH), b(BH);\n for(auto v: {&a, &b}) for(auto& i: *v) cin >> i;\n\n vector<vector<int>> A(AH), B(BH);\n for(auto i = 0; i < AH; ++i) for(auto c: a[i]) A[i].emplace_back(to_i(c));\n for(auto i = 0; i < BH; ++i) for(auto c: b[i]) B[i].emplace_back(to_i(c));\n\n vector<vector<Bit>> T(CHARS, vector<Bit>(AH));\n for(auto i = 0; i < AH; ++i) for(auto j = 0; j < AW; ++j) {\n if(A[i][j] == to_i('?')) for(auto& k: T) k[i].set(j);\n else T[A[i][j]][i].set(j);\n }\n\n vector<Bit> ok(AH);\n for(auto& i: ok) i.set();\n for(auto i = 0; i < AH - BH + 1; ++i) {\n for(auto y = 0; y < BH; ++y) for(auto x = 0; x < BW; ++x) {\n auto c = B[y][x];\n if(c == to_i('?')) continue;\n ok[i] &= T[c][i+y] >> x;\n }\n }\n\n auto res = 0;\n for(auto i = 0; i < AH - BH + 1; ++i) for(auto j = 0; j < AW - BW + 1; ++j) if(ok[i][j]) ++res;\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 12380, "score_of_the_acc": -0.0578, "final_rank": 2 }, { "submission_id": "aoj_0378_2670638", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define all(c) (c).begin(),(c).end()\n#define pb push_back\n#define dbg(...) do{cerr<<__LINE__<<\": \";dbgprint(#__VA_ARGS__, __VA_ARGS__);}while(0);\n\nusing namespace std;\n\nnamespace std{template<class S,class T>struct hash<pair<S,T>>{size_t operator()(const pair<S,T>&p)const{return ((size_t)1e9+7)*hash<S>()(p.first)+hash<T>()(p.second);}};template<class T>struct hash<vector<T>>{size_t operator()(const vector<T> &v)const{size_t h=0;for(auto i : v)h=h*((size_t)1e9+7)+hash<T>()(i)+1;return h;}};}\ntemplate<class T>ostream& operator<<(ostream &os, const vector<T> &v){os<<\"[ \";rep(i,v.size())os<<v[i]<<(i==v.size()-1?\" ]\":\", \");return os;}template<class T>ostream& operator<<(ostream &os,const set<T> &v){os<<\"{ \"; for(const auto &i:v)os<<i<<\", \";return os<<\"}\";}\ntemplate<class T,class U>ostream& operator<<(ostream &os,const map<T,U> &v){os<<\"{\";for(const auto &i:v)os<<\" \"<<i.first<<\": \"<<i.second<<\",\";return os<<\"}\";}template<class T,class U>ostream& operator<<(ostream &os,const pair<T,U> &p){return os<<\"(\"<<p.first<<\", \"<<p.second<<\")\";}\nvoid dbgprint(const string &fmt){cerr<<endl;}template<class H,class... T>void dbgprint(const string &fmt,const H &h,const T&... r){cerr<<fmt.substr(0,fmt.find(\",\"))<<\"= \"<<h<<\" \";dbgprint(fmt.substr(fmt.find(\",\")+1),r...);}\ntypedef unsigned long long ll;typedef vector<int> vi;typedef pair<int,int> pi;const int inf = (int)1e9;const double INF = 1e12, EPS = 1e-9;\n\nint main(){\n\tcin.tie(0); cin.sync_with_stdio(0);\n\tint H, W, h, w;\n\tcin >> W >> H >> w >> h;\n\tvector<string> A(H), B(h);\n\tset<char> cs;\n\t\n\trep(i, H){ cin >> A[i]; for(char c : A[i]) cs.insert(c); }\n\trep(i, h){ cin >> B[i]; for(char c : B[i]) cs.insert(c); }\n\tcs.erase('?');\n\t\n\tvector<vector<bool>> ok(H, vector<bool>(W, 1));\n\t\n\tfor(char c : cs){\n\t\tint any = 0;\n\t\tvector<vector<ll>> t(H, vector<ll>(W));\n\t\trep(i, H) for(int j = W - 1; j >= 0; j--){\n\t\t\tif(j < W - 1) t[i][j] = t[i][j + 1] << 1;\n\t\t\tif(A[i][j] != c && A[i][j] != '?'){\n\t\t\t\tt[i][j] |= 1;\n\t\t\t\tany |= 1;\n\t\t\t}\n\t\t}\n\t\t\n\t\tvector<vector<ll>> u(h, vector<ll>(2));\n\t\trep(i, h) rep(j, w) if(B[i][j] == c){\n\t\t\tu[i][j / 64] |= 1ull << j % 64;\n\t\t\tany |= 2;\n\t\t}\n\t\tif(any != 3) continue;\n\t\t\n\t\trep(i, H - h + 1) rep(j, W - w + 1) if(ok[i][j]){\n\t\t\trep(k, h){\n\t\t\t\tif(u[k][0] & t[i + k][j]) goto BAD;\n\t\t\t\tif(w > 64 && (u[k][1] & t[i + k][j + 64])) goto BAD;\n\t\t\t}\n\t\t\tcontinue;\n\t\t\tBAD:\n\t\t\tok[i][j] = 0;\n\t\t}\n\t}\n\t\n\tint ans = 0;\n\trep(i, H - h + 1) rep(j, W - w + 1) if(ok[i][j]) ans++;\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 8788, "score_of_the_acc": -0.1482, "final_rank": 6 }, { "submission_id": "aoj_0378_2636829", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing bs = bitset< 800 >;\nusing ss = bitset< 100 >;\n\n\nint main()\n{\n int W, H, M, N;\n int mat[800][800], beet[100][100];\n\n auto to = [&](char c)\n {\n if(islower(c)) return (c - 'a' + 10);\n if(isupper(c)) return (c - 'A' + 36);\n if(isdigit(c)) return (c - '0' + 0);\n return (~0);\n };\n\n\n cin >> W >> H >> M >> N;\n for(int i = 0; i < H; i++) {\n string s;\n cin >> s;\n for(int j = 0; j < W; j++) {\n mat[i][j] = to(s[j]);\n }\n }\n\n for(int i = 0; i < N; i++) {\n string s;\n cin >> s;\n for(int j = 0; j < M; j++) {\n beet[i][j] = to(s[j]);\n }\n }\n\n ss mask = 1;\n mask <<= M - 1;\n\n auto matching = [&](vector< int > &latte, vector< int > &malta)\n {\n bs ret;\n int tail = 0;\n ss bit1[62], bit2;\n for(int i = 0; i < malta.size(); i++) {\n if(malta[i] < 0) for(int j = 0; j < 62; j++) bit1[j][i] = true;\n else bit1[malta[i]][i] = true;\n }\n for(int i = 0; i < W; i++) {\n bit2 <<= 1;\n bit2 |= 1;\n if(~latte[i]) bit2 &= bit1[latte[i]];\n if((bit2 & mask).count()) ret[i] = true;\n }\n return (ret);\n };\n\n bs bits[800][100];\n for(int i = 0; i < H; i++) {\n for(int j = 0; j < N; j++) {\n vector< int > vec1(W), vec2(M);\n for(int k = 0; k < W; k++) vec1[k] = mat[i][k];\n for(int k = 0; k < M; k++) vec2[k] = beet[j][k];\n bits[i][j] = matching(vec1, vec2);\n }\n }\n\n int ret = 0;\n for(int i = 0; i <= H - N; i++) {\n for(int k = 0; k < W; k++) {\n bool flag = true;\n for(int j = 0; j < N; j++) {\n flag &= bits[i + j][j][k];\n }\n ret += flag;\n }\n }\n\n cout << ret << endl;\n}", "accuracy": 1, "time_ms": 750, "memory_kb": 13712, "score_of_the_acc": -0.4609, "final_rank": 9 }, { "submission_id": "aoj_0378_2636359", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define pb push_back\n#define all(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntypedef vector<int>vint;\ntypedef pair<int,int>pint;\ntypedef vector<pint>vpint;\n\ntemplate<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}\ntemplate<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}\n\ntypedef bitset<800>bs;\nbs X;\nint H,W,h,w;\n\nint A[888][888];\nint a[888][888];\n\nbs latte[888];\n\nbs malta[888][62];\n\nint conv(char c){\n if(isupper(c))return c-'A';\n if(islower(c))return 26+c-'a';\n if(isdigit(c))return 52+c-'0';\n return -1;\n}\n\nsigned main(){\n cin>>W>>H>>w>>h;\n\n rep(i,H){\n string s;cin>>s;\n rep(j,W)A[i][j]=conv(s[j]);\n }\n\n rep(i,h){\n string s;cin>>s;\n rep(j,w)a[i][j]=conv(s[j]);\n }\n\n rep(i,W)X[i]=1;\n\n rep(i,H)latte[i]=X;\n\n rep(i,H)rep(j,W)if(i+h>H||j+w>W)latte[i][j]=0;\n\n rep(i,H){\n rep(j,W){\n if(A[i][j]>=0)malta[i][A[i][j]][j]=1;\n else rep(k,62)malta[i][k][j]=1;\n }\n }\n\n for(int j=0;j<h;j++){\n for(int i=j;i<H;i++){\n for(int k=0;k<w;k++){\n if(a[j][k]>=0)latte[i-j]&=malta[i][a[j][k]]>>k;\n }\n }\n }\n\n int ans=0;\n rep(i,H)rep(j,W)ans+=latte[i][j];\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 14240, "score_of_the_acc": -0.0448, "final_rank": 1 }, { "submission_id": "aoj_0378_2606895", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n \nint w1, w2, h1, h2, sum;\nlong long hash_a[800][800][10], hash_b[800][10];\nlong long cumo_a[800][800][10], cumo_b[800][10];\nchar s[800][700],t[800][800];\n \n \nvoid make_table(){\n rep(i,h1) rep(j,w1-w2+1) {\n rep(k,w2){\n rep(l,6) hash_a[i][j][(k*6)/60] = hash_a[i][j][(k*6)/60]*2 + ( ((s[i][j+k]>>l)&1)?1:0);\n rep(l,6) cumo_a[i][j][(k*6)/60] = cumo_a[i][j][(k*6)/60]*2 + (s[i][j+k]==63?1:0);\n }\n }\n rep(i,h2) {\n rep(j,w2){\n rep(k,6) hash_b[i][(j*6)/60] = hash_b[i][(j*6)/60]*2 + (((t[i][j]>>k)&1)?1:0);\n rep(k,6) cumo_b[i][(j*6)/60] = cumo_b[i][(j*6)/60]*2 + (t[i][j]==63?1:0);\n }\n }\n}\n \nvoid count_s(){\n rep(i,h1-h2+1) {\n rep(j,w1-w2+1) {\n rep(k,h2) {\n int p1[10]={} ,p2[10]={} ;int flag = 0;\n rep(l,10){\n p1[l] = hash_a[i+k][j][l] ^ hash_b[k][l];\n p2[l] = cumo_a[i+k][j][l] | cumo_b[k][l];\n if( (p1[l] | p2[l]) != p2[l] ) { flag ++; break; }\n }\n if( flag ) break ;\n if( k == h2-1 ) sum++;\n }\n }\n }\n}\n \nvoid Za_a_tsu(){\n rep(i,h1)rep(j,w1){\n if('0'<=s[i][j]&&s[i][j]<='9')s[i][j]=(s[i][j]-'0');\n if('a'<=s[i][j]&&s[i][j]<='z')s[i][j]=(s[i][j]-'a'+11);\n if('A'<=s[i][j]&&s[i][j]<='Z')s[i][j]=(s[i][j]-'A'+37);\n }\n rep(i,h2)rep(j,w2){\n if('0'<=t[i][j]&&t[i][j]<='9')t[i][j]=(t[i][j]-'0');\n if('a'<=t[i][j]&&t[i][j]<='z')t[i][j]=(t[i][j]-'a'+11);\n if('A'<=t[i][j]&&t[i][j]<='Z')t[i][j]=(t[i][j]-'A'+37);\n }\n}\n \nsigned main(){\n cin >> w1 >> h1 >> w2 >> h2;\n rep(i,h1) scanf(\"%s\", s[i]);\n rep(i,h2) scanf(\"%s\", t[i]);\n Za_a_tsu();\n make_table();\n count_s();\n cout << sum << endl;\n}", "accuracy": 0.32142857142857145, "time_ms": 350, "memory_kb": 75132, "score_of_the_acc": -0.4503, "final_rank": 20 }, { "submission_id": "aoj_0378_2606496", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cassert>\nusing namespace std;\ntypedef unsigned long long ll;\nstatic const int BIT = 64;\nstatic const int TH_MAX = 800;\nstatic const int TW_MAX = 800;\nstatic const int PH_MAX = 100;\nstatic const int PW_MAX = 100;\n\nchar T[TH_MAX][TW_MAX+1];\nchar P[PH_MAX][PW_MAX+1];\n\nint PH, PW, TH, TW;\nll K, R, Y;\n\nll M[PH_MAX][PW_MAX/BIT+1][256];\nll st[PH_MAX][PW_MAX/BIT+1];\n\nvoid makeMask(){\n R = PW%BIT;\n K = PW/BIT + (R>0?1:0);\n Y = (1LL<<(R + (BIT-1))%BIT);\n string L = \"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789?\";\n for ( int r = 0; r < PH; r++ ){\n for ( int c = 0; c < L.size(); c++ ){\n for ( int k = 0; k < K; k++ ){\n for ( int b = 0; b < BIT; b++ ){\n if ( k*BIT+b >= PW ) continue;\n if ( P[r][k*BIT+b] == L[c] || L[c] == '?' || P[r][k*BIT+b] == '?'){\n M[r][k][L[c]] += (1LL<<b);\n }\n }\n }\n }\n }\n}\n\nmain(){\n cin >> TW >> TH >> PW >> PH;\n for ( int i = 0; i < TH; i++ ) scanf(\"%s\", T[i]);\n for ( int i = 0; i < PH; i++ ) scanf(\"%s\", P[i]);\n\n makeMask();\n\n int ans = 0;\n for ( int h = 0; h < TH; h++ ){\n for ( int i = 0; i < PH; i++ ){\n for ( int j = 0; j < K; j++ ) st[i][j] = 0;\n }\n for ( int w = 0; w < TW; w++ ){\n int ok = 0;\n for ( int r = 0; r < PH; r++){\n if ( h + r >= TH ) continue;\n\n for ( int k = K-1; k >= 0; k-- ){\n int ca = (st[r][k-1] & (1LL<<(BIT-1)))>0?1:0;\n if ( k == 0 ) ca = 1;\n st[r][k] = ((st[r][k] << 1) | ca ) & M[r][k][T[h+r][w]];\n }\n if ( st[r][K-1] & Y ) ok++;\n }\n if ( ok == PH ) ans++;\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 4212, "score_of_the_acc": -0.1208, "final_rank": 4 }, { "submission_id": "aoj_0378_2606488", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int h,w,n,m;\n cin >> w >> h >> m >> n;\n string s[h],t[n];\n for(int i=0; i<h; i++) cin >> s[i];\n for(int i=0; i<n; i++) cin >> t[i];\n bitset<600> b[n][256];\n for(int i=0; i<n; i++) {\n for(int j=0; j<m; j++) {\n if(t[i][j]!='?') b[i][t[i][j]].set(j);\n else for(int k=0; k<256; k++) b[i][k].set(j);\n }\n }\n int ans=0;\n for(int i=0; i<h-n+1; i++) {\n bitset<600> r[n];\n for(int j=0; j<w; j++) {\n int cnt=0;\n for(int k=0; k<n; k++) {\n r[k]=(r[k]<<1).set(0);\n if(s[i+k][j]!='?') r[k]&=b[k][s[i+k][j]];\n if(r[k][m-1]) cnt++;\n }\n if(j>=m-1&&cnt==n) ans++;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1230, "memory_kb": 5828, "score_of_the_acc": -0.7663, "final_rank": 13 }, { "submission_id": "aoj_0378_2606335", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\nvector<int> match(string &t,string &p) {\n //cout<<t<<\" \"<<p<<endl;\n using BS = bitset<100>;\n int n = t.length(), m = p.length();\n vector<BS> M(100);\n vector<int> res(n,0);\n for (int i=0;i<m;i++){\n if(p[i]=='?') for(int j=0;j<100;j++) M[j][i]=1;\n if(isdigit(p[i])) M[p[i]-'0'][i]=1;\n if(islower(p[i])) M[10+p[i]-'a'][i]=1;\n if(isupper(p[i])) M[36+p[i]-'A'][i]=1;\n }\n BS S(0);\n for (int i = 0; i < n; i++) {\n S=((S<<1)|BS(1));\n if(isdigit(t[i])) S&=M[t[i]-'0'];\n if(islower(t[i])) S&=M[10+t[i]-'a'];\n if(isupper(t[i])) S&=M[36+t[i]-'A'];\n \n if((S&(BS(1)<<(m-1))).count()) res[i]=1;\n }\n //for(int i=0;i<n;i++) cout<<res[i];cout<<endl;\n return res;\n}\n\nsigned main(){\n int aw,ah,bw,bh;\n cin>>aw>>ah>>bw>>bh;\n string a[ah],b[bh];\n for(int i=0;i<ah;i++) cin>>a[i];\n for(int i=0;i<bh;i++) cin>>b[i];\n //for(int i=0;i<ah;i++) cout<<a[i]<<endl;;\n //for(int i=0;i<bh;i++) cout<<b[i]<<endl;;\n vector<int> G[ah][bh];\n for(int i=0;i<ah;i++)\n for(int j=0;j<bh;j++)\n G[i][j]=match(a[i],b[j]);\n \n int ans=0;\n for(int i=0;i<=ah-bh;i++){\n for(int j=0;j<aw;j++){\n int res=1;\n for(int k=0;k<bh;k++)\n\tres&=G[i+k][k][j];\n ans+=res;\n }\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 229096, "score_of_the_acc": -1.9433, "final_rank": 18 }, { "submission_id": "aoj_0378_2606244", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define rep(i,n) for(int i=0;i<n;i++)\nusing namespace std;\n\n//??????TLE??§??? m(_)m\n\nint w1,w2,h1,h2,sum;\nint hash_a[800][800][10],hash_b[800][10];\nint cumo_a[800][800][10],cumo_b[800][10];\nchar s[800][700],t[800][800];\n \n \nvoid make_table(){\n rep(i,h1) rep(j,w1-w2+1) {\n rep(k,w2){\n rep(l,6)hash_a[i][j][(k*6)/60] = hash_a[i][j][(k*6)/60]*2+(((s[i][j+k]>>l)&1)?1:0);\n rep(l,6)cumo_a[i][j][(k*6)/60] = cumo_a[i][j][(k*6)/60]*2+(s[i][j+k]==63?1:0);\n }\n }\n rep(i,h2) {\n rep(j,w2){\n rep(k,6)hash_b[i][(j*6)/60] = hash_b[i][(j*6)/60]*2+(((t[i][j]>>k)&1)?1:0);\n rep(k,6)cumo_b[i][(j*6)/60] = cumo_b[i][(j*6)/60]*2+(t[i][j]==63?1:0);\n }\n }\n}\n \nvoid count_s(){\n rep(i,h1-h2+1) {\n rep(j,w1-w2+1) {\n rep(k,h2) {\n int p1[10]={} ,p2[10]={} ;int flag = 0;\n rep(l,10){\n p1[l] = hash_a[i+k][j][l] ^ hash_b[k][l];\n p2[l] = cumo_a[i+k][j][l] | cumo_b[k][l];\n if( (p1[l] | p2[l]) != p2[l] ) { flag ++; break; }\n }\n if( flag ) break ;\n if( k == h2-1 ) sum++;\n }\n }\n }\n}\n \nvoid Za_a_tsu(){\n rep(i,h1)rep(j,w1){\n if('0'<=s[i][j]&&s[i][j]<='9')s[i][j]=(s[i][j]-'0');\n if('a'<=s[i][j]&&s[i][j]<='z')s[i][j]=(s[i][j]-'a'+11);\n if('A'<=s[i][j]&&s[i][j]<='Z')s[i][j]=(s[i][j]-'A'+37);\n }\n rep(i,h2)rep(j,w2){\n if('0'<=t[i][j]&&t[i][j]<='9')t[i][j]=(t[i][j]-'0');\n if('a'<=t[i][j]&&t[i][j]<='z')t[i][j]=(t[i][j]-'a'+11);\n if('A'<=t[i][j]&&t[i][j]<='Z')t[i][j]=(t[i][j]-'A'+37);\n }\n}\n \nsigned main(){\n cin >> w1 >> h1 >> w2 >> h2;\n rep(i,h1)scanf(\"%s\",s[i]);\n rep(i,h2)scanf(\"%s\",t[i]);\n Za_a_tsu();\n make_table();\n count_s();\n cout << sum << endl;\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 103696, "score_of_the_acc": -1.1233, "final_rank": 16 } ]
aoj_0367_cpp
Charging System for Network There is a network consisting of N machines (sequentially numbered from 0 to N -1) interconnected through N -1 bidirectional communication cables. Any two machines can perform bidirectional communication through one or more cables. From time to time, machines in the network are renewed. When a new machine is introduced, the cables directly connected to it are also replaced with thicker ones to cope with the increased volume of communication traffic. The communication fee arising from communication traffic between any two machines is calculated by summing the charges assigned to all the cables routing via the two. A unique charging scheme is employed in this system: if the size of a cable is a multiple of K , then the cable is not charged (free of charge). Other cables are charged according to their sizes. Based on the given information on the network topology and Q instructions, write a program to execute each instruction. Increase the sizes of all cables directly connected to the machine x by d . Report the communication charge between the machines s and t . Input The input is given in the following format. N K a_1 b_1 c_1 a_2 b_2 c_2 : a_{N−1} b_{N−1} c_{N−1} Q query_1 query_2 : query_Q The first line provides the number of machines N (2 ≤ N ≤ 10 5 ) and the cable size K (1 ≤ K ≤ 10 5 ) (the reference value for determining free of charge cables). Each of subsequent N -1 lines provides the i -th cable information that directly connects two machines a_i and b_i (0 ≤ a_i < b_i ≤ N -1), followed by the cable’s initial size c_i (1 ≤ c_i ≤ 10 5 ). For any pair of machines, the number of cables directly connecting them is either one or zero. The next line following them provides the number of instructions Q (1 ≤ Q ≤ 10 5 ). Each of the Q lines following it provides the i -th instruction query_i , which is either one of the following two: add x d or send s t The instruction add x d increase the size of all cables directly connected to machine x (0 ≤ x ≤ N -1) by d (1 ≤ d ≤ 10 5 ). The instruction send s t reports the charge imposed to the communication between the two machines s (0 ≤ s ≤ N -1) and t (0 ≤ t ≤ N -1), where s ≠ t . At least one send instruction is included in the input information. Output For each send command, output the communication charge between s and t . Sample Input 1 6 3 0 1 1 0 2 1 0 3 1 2 4 1 2 5 1 3 send 1 4 add 2 2 send 1 4 Sample Output 1 3 1
[ { "submission_id": "aoj_0367_10423002", "code_snippet": "// AOJ #0367 Charging System for Network\n// 2025.4.26\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nconst int NMAX = 200000;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() {\n\tint n = 0; int c = gc();\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nstring Cins() {\n char temp[10];\n char *s = temp;\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n string input(temp);\n return input;\n}\n\nvoid Cout(ll n) {\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n\tpc('\\n');\n}\n\nint K;\nint a[NMAX], b[NMAX], c[NMAX];\nvector<int> g[NMAX];\nll add[NMAX], sum[NMAX], baseCost[NMAX];\n\nstruct SegTree {\n int size;\n vector<ll> data;\n\n SegTree() {}\n SegTree(int n) {\n size = 1;\n while (size < n) size <<= 1;\n data.assign(2 * size, 0);\n }\n\n void update(int pos, ll val) {\n pos += size;\n data[pos] = val;\n for (pos >>= 1; pos > 0; pos >>= 1)\n data[pos] = data[pos * 2] + data[pos * 2 + 1];\n }\n\n ll query(int l, int r) {\n ll res = 0;\n for (l += size, r += size; l < r; l >>= 1, r >>= 1) {\n if (l & 1) res += data[l++];\n if (r & 1) res += data[--r];\n }\n return res;\n }\n} seg;\n\nnamespace HLD {\n int par[NMAX], sz[NMAX], ch[NMAX], vid[NMAX], heavy[NMAX], depth[NMAX];\n int curr_vid = 0;\n\n void dfs(int node, int parent, int d) {\n par[node] = parent;\n sz[node] = 1;\n depth[node] = d;\n for (int &to : g[node]) {\n if (to == parent) continue;\n dfs(to, node, d + 1);\n sz[node] += sz[to];\n }\n }\n\n void decompose(int node, int h) {\n ch[node] = h;\n vid[node] = curr_vid++;\n int heavy_child = -1, max_sz = 0;\n for (int to : g[node]) {\n if (to == par[node]) continue;\n if (sz[to] > max_sz) {\n max_sz = sz[to];\n heavy_child = to;\n }\n }\n if (heavy_child != -1) {\n heavy[node] = heavy_child;\n decompose(heavy_child, h);\n } else heavy[node] = -1;\n for (int to : g[node])\n if (to != par[node] && to != heavy_child) decompose(to, to);\n }\n\n ll path_query(int u, int v) {\n ll res = 0;\n while (true) {\n if (ch[u] == ch[v]) {\n if (vid[u] > vid[v]) swap(u, v);\n res += seg.query(vid[u] + 1, vid[v] + 1);\n return res;\n }\n if (depth[ch[u]] < depth[ch[v]]) swap(u, v);\n res += seg.query(vid[ch[u]] + 1, vid[u] + 1);\n ll extra = baseCost[ch[u]] + add[ch[u]] + (par[ch[u]] != -1 ? add[par[ch[u]]] : 0);\n if (extra % K) res += extra;\n u = par[ch[u]];\n }\n }\n}\n\nint main() {\n int n = Cin();\n K = Cin();\n for (int i = 0; i < n - 1; ++i) {\n a[i] = Cin(), b[i] = Cin(), c[i] = Cin();\n g[a[i]].push_back(b[i]);\n g[b[i]].push_back(a[i]);\n }\n\n HLD::dfs(0, -1, 0);\n HLD::decompose(0, 0);\n\n seg = SegTree(n);\n for (int i = 0; i < n - 1; ++i) {\n if (HLD::par[b[i]] != a[i]) swap(a[i], b[i]);\n sum[b[i]] = c[i];\n baseCost[b[i]] = c[i];\n seg.update(HLD::vid[b[i]], (c[i] % K ? c[i] : 0));\n }\n\n int q = Cin();\n string cmd;\n while (q--) {\n cmd = Cins();\n if (cmd[0] == 'a') {\n int x = Cin(), d = Cin();\n add[x] += d, sum[x] += d;\n seg.update(HLD::vid[x], (sum[x] % K ? sum[x] : 0));\n int y = HLD::heavy[x];\n if (y != -1) {\n sum[y] += d;\n seg.update(HLD::vid[y], (sum[y] % K ? sum[y] : 0));\n }\n } else {\n int s = Cin(), t = Cin();\n Cout(HLD::path_query(s, t));\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 29796, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0367_9573273", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct HLD {\n\tvector<vector<long long>> g;\n\tvector<long long> p,s,v,d,e,segt,sum;\n\tvector<pair<long long,long long>> a,ran;\n\tlong long n,K;\n\tHLD(vector<vector<long long>> g,long long k) : n(g.size()), g(g), K(k) {\n\t\tp.resize(n,-2ll);\n\t\ts.resize(n,0ll);\n\t\ta.resize(n);\n\t\td.resize(n,-1ll);\n\t\te.resize(n,-1ll);\n\t\tsegt.resize(n,0ll);\n\t\tsum.resize(n,0ll);\n\t\t{\n\t\t\tp[0ll] = -1ll;\n\t\t\td[0ll] = 0ll;\n\t\t\tqueue<long long> q;\n\t\t\tq.push(0ll);\n\t\t\twhile(!q.empty()){\n\t\t\t\tlong long it = q.front();\n\t\t\t\tq.pop();\n\t\t\t\tfor(long long i : g[it]){\n\t\t\t\t\tif(p[i] != -2ll) continue;\n\t\t\t\t\tp[i] = it;\n\t\t\t\t\td[i] = d[it] + 1ll;\n\t\t\t\t\tq.push(i);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsiz(0ll);\n\t\tran.push_back({0ll,-1ll});\n\t\tdfs(0ll,0ll);\n\t}\n\tlong long siz(long long x){\n\t\tif(s[x] != 0ll) return s[x];\n\t\ts[x] = 1ll;\n\t\tfor(long long i : g[x]){\n\t\t\tif(i == p[x]) continue;\n\t\t\ts[x] += siz(i);\n\t\t}\n\t\treturn s[x];\n\t}\n\tvoid dfs(long long x,long long r){\n\t\ta[x] = {(long long)v.size(),r};\n\t\tv.push_back(x);\n\t\tlong long ma = -1ll;\n\t\tran.back().second++;\n\t\tfor(long long i : g[x]){\n\t\t\tif(i == p[x]) continue;\n\t\t\tif(ma == -1ll || s[ma] < s[i]){\n\t\t\t\tma = i;\n\t\t\t}\n\t\t}\n\t\tif(ma == -1ll) return;\n\t\tdfs(ma,r);\n\t\te[x] = ma;\n\t\tfor(long long i : g[x]){\n\t\t\tif(i == p[x] || i == ma) continue;\n\t\t\tran.push_back({v.size(),v.size() - 1ll});\n\t\t\tdfs(i,i);\n\t\t}\n\t}\n\tvector<pair<long long,long long>> get(long long u,long long v){\n\t\tvector<pair<long long,long long>> res;\n\t\tlong long cou = 0ll;\n\t\twhile(a[u].second != a[v].second){\n\t\t\tif(d[a[u].second] <= d[a[v].second]){\n\t\t\t\tres.push_back({a[a[v].second].first,a[v].first});\n\t\t\t\tlong long it = segt[a[a[v].second].first];\n\t\t\t\tit += sum[a[a[v].second].first];\n\t\t\t\tit += sum[a[p[a[v].second]].first];\n\t\t\t\tif(it % K != 0ll){\n\t\t\t\t\tcou += it;\n\t\t\t\t}\n\t\t\t\tv = p[a[v].second];\n\t\t\t}else{\n\t\t\t\tres.push_back({a[a[u].second].first,a[u].first});\n\t\t\t\tlong long it = segt[a[a[u].second].first];\n\t\t\t\tit += sum[a[a[u].second].first];\n\t\t\t\tit += sum[a[p[a[u].second]].first];\n\t\t\t\tif(it % K != 0ll){\n\t\t\t\t\tcou += it;\n\t\t\t\t}\n\t\t\t\tu = p[a[u].second];\n\t\t\t}\n\t\t}\n\t\tres.push_back({min(a[u].first,a[v].first),max(a[u].first,a[v].first)});\n\t\tres.push_back({-1ll,cou});\n\t\treturn res;\n\t}\n\tlong long operator[](long long x){\n\t\treturn a[x].first;\n\t}\n\tlong long lca(long long u,long long v){\n\t\treturn this->v[get(u,v).back().first];\n\t}\n\tlong long depth(long long x){\n\t\treturn d[x];\n\t}\n\tlong long size(){\n\t\treturn ran.size();\n\t}\n\tlong long dist(long long u,long long v){\n\t\tlong long lc = lca(u,v);\n\t\treturn depth(u) + depth(v) - depth(lc) * 2ll;\n\t}\n};\ntemplate<typename T,T e>\nstruct segtree {\n\tvector<long long> v;\n\tlong long n;\n\tT f(T a,T b){\n\t\treturn a + b;\n\t}\n\tsegtree(long long n) : n(n) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n * 2ll;i++){\n\t\t\tv[i] = e;\n\t\t}\n\t}\n\tsegtree(vector<T> x) : n(x.size()) {\n\t\tv.resize(n * 2ll);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tv[i + n] = x[i];\n\t\t}\n\t\tfor(long long i = n - 1ll;i >= 0ll;i--){\n\t\t\tv[i] = f(v[i * 2ll],v[i * 2ll + 1ll]);\n\t\t}\n\t}\n\tT operator[](long long a){\n\t\treturn v[a + n];\n\t}\n\tvoid set(long long a,long long b){\n\t\ta += n;\n\t\tv[a] = b;\n\t\twhile(a >>= 1ll){\n\t\t\tv[a] = f(v[a * 2ll],v[a * 2ll + 1ll]);\n\t\t}\n\t}\n\tT prod(long long l,long long r){\n\t\tT res = e;\n\t\tfor(l += n,r += n;l < r;l >>= 1ll,r >>= 1ll){\n\t\t\tif(l & 1ll){\n\t\t\t\tres = f(res,v[l++]);\n\t\t\t}\n\t\t\tif(r & 1ll){\n\t\t\t\tres = f(res,v[--r]);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tlong long n,k;\n\tcin >> n >> k;\n\tvector<vector<pair<long long,long long>>> g(n,vector<pair<long long,long long>>());\n\tvector<vector<long long>> gh(n,vector<long long>());\n\tfor(long long i = 0ll;i < n - 1ll;i++){\n\t\tlong long u,v,w;\n\t\tcin >> u >> v >> w;\n\t\tgh[u].push_back(v);\n\t\tgh[v].push_back(u);\n\t\tg[u].push_back({v,w});\n\t\tg[v].push_back({u,w});\n\t}\n\tHLD hld(gh,k);\n\tvector<long long> v = hld.v;\n\tvector<pair<long long,long long>> a = hld.a;\n\tfor(long long i = 0ll;i < n;i++){\n\t\tfor(pair<long long,long long> j : g[i]){\n\t\t\tif(j.first < i) continue;\n\t\t\tif(hld.p[i] == j.first){\n\t\t\t\thld.segt[a[i].first] = j.second;\n\t\t\t}else{\n\t\t\t\thld.segt[a[j.first].first] = j.second;\n\t\t\t}\n\t\t}\n\t}\n\tsegtree<long long,0ll> seg(hld.segt);\n\tfor(long long i = 0ll;i < n;i++){\n\t\tif(hld.segt[i] % k == 0ll){\n\t\t\tseg.set(i,0ll);\n\t\t}\n\t}\n\tlong long Q;\n\tcin >> Q;\n\tfor(long long i = 0ll;i < Q;i++){\n\t\tstring s;\n\t\tcin >> s;\n\t\tlong long u,v;\n\t\tcin >> u >> v;\n\t\tif(s == \"add\"){\n\t\t\thld.sum[a[u].first] += v;\n\t\t\tif(hld.p[u] != -1ll && a[u].second == a[hld.p[u]].second){\n\t\t\t\thld.segt[a[u].first] += v;\n\t\t\t\tif(hld.segt[a[u].first] % k == 0ll){\n\t\t\t\t\tseg.set(a[u].first,0ll);\n\t\t\t\t}else{\n\t\t\t\t\tseg.set(a[u].first,hld.segt[a[u].first]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(hld.e[u] != -1ll){\n\t\t\t\thld.segt[a[hld.e[u]].first] += v;\n\t\t\t\tif(hld.segt[a[hld.e[u]].first] % k == 0ll){\n\t\t\t\t\tseg.set(a[hld.e[u]].first,0ll);\n\t\t\t\t}else{\n\t\t\t\t\tseg.set(a[hld.e[u]].first,hld.segt[a[hld.e[u]].first]);\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tlong long ans = 0ll;\n\t\t\tvector<pair<long long,long long>> it = hld.get(u,v);\n\t\t\tfor(pair<long long,long long> i : it){\n\t\t\t\tif(i.first == -1ll){\n\t\t\t\t\tans += i.second;\n\t\t\t\t}else{\n\t\t\t\t\tans += seg.prod(i.first,i.second + 1ll);\n\t\t\t\t\tlong long it = seg[i.first];\n\t\t\t\t\tans -= it;\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << ans << endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 41548, "score_of_the_acc": -0.4698, "final_rank": 9 }, { "submission_id": "aoj_0367_9023856", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct lca_tree {\n int n, lg;\n vector<int> dep;\n vector<vector<int>> dest;\n lca_tree(vector<vector<int>> tree, vector<int> a, vector<int> b) {\n n = tree.size();\n lg = 0;\n while((1<<lg) < n) lg++;\n dep = vector<int>(n, 0);\n dest = vector(lg+1, vector<int>(n+1, n));\n auto dfs = [&](auto dfs, int cur) -> void {\n for(int e : tree[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == dest[0][cur]) continue;\n dep[nxt] = dep[cur]+1;\n dest[0][nxt] = cur;\n dfs(dfs, nxt);\n }\n };\n dfs(dfs, 0);\n for(int k = 0; k < lg; k++) {\n for(int i = 0; i < n; i++) {\n dest[k+1][i] = dest[k][dest[k][i]];\n }\n }\n }\n void mov(int &u, int l) {\n for(int k = 0; k <= lg; k++) {\n if((l>>k)&1) {\n u = dest[k][u];\n }\n }\n }\n int operator()(int u, int v) {\n if(dep[u] > dep[v]) swap(u, v);\n mov(v, dep[v]-dep[u]);\n if(u == v) return u;\n for(int k = lg; k >= 0; k--) {\n if(dest[k][u] != dest[k][v]) {\n u = dest[k][u];\n v = dest[k][v];\n }\n }\n return dest[0][u];\n }\n};\n\nint main() {\n int N;\n long long K;\n cin >> N >> K;\n const int B = 1000;\n vector<int> a(N-1), b(N-1);\n vector<long long> c(N-1);\n vector<vector<int>> G(N);\n for(int i = 0; i < N-1; i++) {\n cin >> a[i] >> b[i] >> c[i];\n G[a[i]].push_back(i);\n G[b[i]].push_back(i);\n }\n unordered_set<int> naive;\n vector<int> dest(N, -1);\n vector<long long> cost(N), cv(N);\n auto f = [&](int e) -> long long {\n if((c[e]+cv[a[e]]+cv[b[e]])%K == 0) return 0;\n return c[e]+cv[a[e]]+cv[b[e]];\n };\n auto dfs = [&](auto dfs, int cur, int par) -> void {\n for(int &e : G[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == par) swap(e, G[cur][0]);\n }\n for(int &e : G[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == par) continue;\n if(!naive.count(cur) && !naive.count(nxt)) {\n dest[nxt] = naive.count(par) ? cur : dest[cur];\n cost[nxt] = cost[cur]+f(e);\n }\n else {\n dest[nxt] = cur;\n cost[nxt] = naive.count(nxt) ? 0 : f(e);\n }\n dfs(dfs, nxt, cur);\n }\n };\n auto mov = [&](auto mov, int u, int v) -> long long {\n if(u == v) {\n return 0;\n }\n else if(naive.count(u)) {\n int e = G[u][0];\n return mov(mov, a[e]^b[e]^u, v)+f(e);\n }\n else if(dest[u] == dest[v]) {\n return cost[u]-cost[v];\n }\n return cost[u]-cost[dest[u]]+mov(mov, dest[u], v);\n };\n int Q;\n cin >> Q;\n lca_tree lca(G, a, b);\n vector<array<int, 3>> query(Q);\n for(int i = 0; i < Q; i++) {\n string op;\n cin >> op >> query[i][1] >> query[i][2];\n query[i][0] = op == \"add\" ? 1 : 2;\n }\n for(int i = 0; i < Q; i+=B) {\n naive.clear();\n unordered_set<int> x_all;\n for(int j = i; j < min(i+B, Q); j++) {\n if(query[j][0] == 1) {\n int x = query[j][1];\n x_all.insert(x);\n }\n }\n for(const int x : x_all) {\n naive.insert(x);\n for(int e : G[x]) {\n int y = a[e]^b[e]^x;\n naive.insert(y);\n }\n }\n dfs(dfs, 0, -1);\n for(int j = i; j < min(i+B, Q); j++) {\n if(query[j][0] == 1) {\n int x = query[j][1];\n int d = query[j][2];\n cv[x] += d;\n }else {\n int s = query[j][1];\n int t = query[j][2];\n int v = lca(s, t);\n cout << mov(mov, s, v)+mov(mov, t, v) << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 830, "memory_kb": 41424, "score_of_the_acc": -0.7316, "final_rank": 16 }, { "submission_id": "aoj_0367_9023855", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct lca_tree {\n int n, lg;\n vector<int> dep;\n vector<vector<int>> dest;\n lca_tree(vector<vector<int>> tree, vector<int> a, vector<int> b) {\n n = tree.size();\n lg = 0;\n while((1<<lg) < n) lg++;\n dep = vector<int>(n, 0);\n dest = vector(lg+1, vector<int>(n+1, n));\n auto dfs = [&](auto dfs, int cur) -> void {\n for(int e : tree[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == dest[0][cur]) continue;\n dep[nxt] = dep[cur]+1;\n dest[0][nxt] = cur;\n dfs(dfs, nxt);\n }\n };\n dfs(dfs, 0);\n for(int k = 0; k < lg; k++) {\n for(int i = 0; i < n; i++) {\n dest[k+1][i] = dest[k][dest[k][i]];\n }\n }\n }\n void mov(int &u, int l) {\n for(int k = 0; k <= lg; k++) {\n if((l>>k)&1) {\n u = dest[k][u];\n }\n }\n }\n int operator()(int u, int v) {\n if(dep[u] > dep[v]) swap(u, v);\n mov(v, dep[v]-dep[u]);\n if(u == v) return u;\n for(int k = lg; k >= 0; k--) {\n if(dest[k][u] != dest[k][v]) {\n u = dest[k][u];\n v = dest[k][v];\n }\n }\n return dest[0][u];\n }\n};\n\nint main() {\n int N;\n long long K;\n cin >> N >> K;\n const int B = ceil(sqrt(N));\n vector<int> a(N-1), b(N-1);\n vector<long long> c(N-1);\n vector<vector<int>> G(N);\n for(int i = 0; i < N-1; i++) {\n cin >> a[i] >> b[i] >> c[i];\n G[a[i]].push_back(i);\n G[b[i]].push_back(i);\n }\n unordered_set<int> naive;\n vector<int> dest(N, -1);\n vector<long long> cost(N), cv(N);\n auto f = [&](int e) -> long long {\n if((c[e]+cv[a[e]]+cv[b[e]])%K == 0) return 0;\n return c[e]+cv[a[e]]+cv[b[e]];\n };\n auto dfs = [&](auto dfs, int cur, int par) -> void {\n for(int &e : G[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == par) swap(e, G[cur][0]);\n }\n for(int &e : G[cur]) {\n int nxt = a[e]^b[e]^cur;\n if(nxt == par) continue;\n if(!naive.count(cur) && !naive.count(nxt)) {\n dest[nxt] = naive.count(par) ? cur : dest[cur];\n cost[nxt] = cost[cur]+f(e);\n }\n else {\n dest[nxt] = cur;\n cost[nxt] = naive.count(nxt) ? 0 : f(e);\n }\n dfs(dfs, nxt, cur);\n }\n };\n auto mov = [&](auto mov, int u, int v) -> long long {\n if(u == v) {\n return 0;\n }\n else if(naive.count(u)) {\n int e = G[u][0];\n return mov(mov, a[e]^b[e]^u, v)+f(e);\n }\n else if(dest[u] == dest[v]) {\n return cost[u]-cost[v];\n }\n // cout << u << \" : \" << cost[u] << \" \" << dest[u] << endl;\n return cost[u]-cost[dest[u]]+mov(mov, dest[u], v);\n };\n int Q;\n cin >> Q;\n lca_tree lca(G, a, b);\n vector<array<int, 3>> query(Q);\n for(int i = 0; i < Q; i++) {\n string op;\n cin >> op >> query[i][1] >> query[i][2];\n query[i][0] = op == \"add\" ? 1 : 2;\n }\n for(int i = 0; i < Q; i+=B) {\n naive.clear();\n unordered_set<int> x_all;\n for(int j = i; j < min(i+B, Q); j++) {\n if(query[j][0] == 1) {\n int x = query[j][1];\n x_all.insert(x);\n }\n }\n for(const int x : x_all) {\n naive.insert(x);\n for(int e : G[x]) {\n int y = a[e]^b[e]^x;\n naive.insert(y);\n }\n }\n dfs(dfs, 0, -1);\n for(int j = i; j < min(i+B, Q); j++) {\n if(query[j][0] == 1) {\n int x = query[j][1];\n int d = query[j][2];\n cv[x] += d;\n }else {\n int s = query[j][1];\n int t = query[j][2];\n int v = lca(s, t);\n // int ms = mov(mov, s, v), mt = mov(mov, t, v);\n // cout << ms << \" \" << mt << endl;\n cout << mov(mov, s, v)+mov(mov, t, v) << endl;\n }\n }\n }\n}", "accuracy": 1, "time_ms": 2050, "memory_kb": 41424, "score_of_the_acc": -1.2811, "final_rank": 18 }, { "submission_id": "aoj_0367_8997398", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing P = pair<int,int>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\n\n// https://beet-aizu.github.io/library/tree/heavylightdecomposition.cpp\nstruct HLD{\n /*\n v := 隣接リスト\n id := 元々の頂点のHLD後の頂点番号。\n head := heavyな辺でつながれた頂点集合の代表元。もっとも浅い頂点。\n sub_sz := 部分木のサイズ\n par := 親\n inv := HLD後の頂点番号から元々の頂点番号をかえす\n\n add_edge(a,b) := a,b間の無向辺を追加\n build() := HLD 分解を実行。内部でdfs_szによる部分木の取得、dfs_hldによるHLD実行。\n lca(a,b) := a,bのLCAを返す\n for_each(a,b,f) := 頂点a,b間の頂点(a,bを含む)にfを実行。このfにseg木などが乗る。\n for_each_edge(a,b,f) := 頂点a,b間の辺にfを実行。辺はつながっている2つの頂点の内深い方と対応させる。\n */\n vector<vector<int>> v;\n vector<int> id,head,sub_sz,par,inv;\n HLD(int n) : v(n),id(n,-1),head(n),sub_sz(n,1),par(n,-1),inv(n){}\n\n void add_edge(int a,int b){\n v[a].push_back(b);\n v[b].push_back(a);\n }\n\n void dfs_sz(int ov,int pre){\n if(v[ov].size() && v[ov][0] == pre)swap(v[ov][0],v[ov].back());\n par[ov] = pre;\n for(auto &nv : v[ov]){\n if(nv == pre)continue;\n dfs_sz(nv,ov);\n sub_sz[ov] += sub_sz[nv];\n if(sub_sz[nv] > sub_sz[v[ov][0]])swap(nv,v[ov][0]);\n }\n }\n void dfs_hld(int ov,int &pos){\n id[ov] = pos++;\n inv[id[ov]] = ov;\n for(auto nv : v[ov]){\n if(nv == par[ov])continue;\n head[nv] = (nv == v[ov][0] ? head[ov] : nv);\n dfs_hld(nv,pos);\n }\n }\n void build(int root = 0){\n int pos = 0;\n dfs_sz(root,-1);\n head[root] = root;\n dfs_hld(root,pos);\n }\n int lca(int a,int b){\n while(1){\n if(id[a] > id[b])swap(a,b);\n if(head[a] == head[b])return a;\n b = par[head[b]];\n }\n }\n template<typename F>\n void for_each(int a,int b,const F& f){\n while(1){\n if(id[a] > id[b])swap(a,b);\n f(max(id[head[b]],id[a]),id[b]+1);\n if(head[a] != head[b])b = par[head[b]];\n else break;\n }\n }\n /*\n 関数内でfは半開区間で値を取得するように正規化するので,\n BITが閉区間で実装されている場合などは\n auto f = [&](int a,int b){return bit.sum(a,b-1);};\n の様に変更する.データ構造が半開区間で値を取得する場合は\n auto f = [&](int a,int b){return seg.get(a,b);};\n でよい.\n */\n template<typename F>\n void for_each_edge(int a,int b,const F& f){\n while(1){\n if(id[a] > id[b])swap(a,b);\n if(head[a] != head[b]){\n f(id[head[b]],id[b]+1);\n b = par[head[b]];\n }else{\n if(a != b)f(id[a]+1,id[b]+1);\n break;\n }\n }\n }\n};\ntemplate<typename T>\nclass Segtree{\n public:\n using F = function<T(T,T)>;\n int n;\n F f;\n T ti;\n vector<T> dat;\n Segtree(){};\n Segtree(F f,T ti): f(f),ti(ti){}\n void init(int N){\n n = 1;\n while(n < N)n <<= 1;\n dat.assign(n << 1,ti);\n }\n void build(const vector<T> &v){\n int N = v.size();\n init(N);\n for(int i = 0;i < N;i++)dat[n+i] = v[i];\n for(int i = n-1;i >= 0;i--)dat[i] = f(dat[(i << 1)|0],dat[(i << 1)|1]);\n }\n void set(int k,T x){\n dat[k+=n] = x;\n while(k >>= 1){\n dat[k] = f(dat[(k << 1)|0],dat[(k << 1)|1]);\n }\n }\n T get(int l,int r){\n T vl = ti,vr = ti;\n for(l += n,r += n;l < r;l >>= 1,r >>= 1){\n if(l & 1)vl = f(vl,dat[l++]);\n if(r & 1)vr = f(dat[--r],vr);\n }\n return f(vl,vr);\n }\n // max t s.t. check(query(st,t))\n template<typename C>\n int bs(int st,C &check,T &acc,int k,int l,int r){\n if(r-l <= 1){\n acc = f(acc,dat[k]);\n return check(acc) ? k-n : -1;\n }\n int mid = (l+r) >> 1;\n if(mid <= st)return bs(st,check,acc,(k << 1)|1,mid,r);\n if(st <= l && !check(f(acc,dat[k]))){\n acc = f(acc,dat[k]);\n return -1;\n }\n int vl = bs(st,check,acc,(k << 1)|0,l,mid);\n if(vl != -1)return vl;\n return bs(st,check,acc,(k << 1)|1,mid,r);\n }\n template<typename C>\n int bs(int st,C &check){\n T acc = ti;\n return bs(st,check,acc,1,0,n);\n }\n};\n\nstruct e{\n ll a,b,x;\n e(ll a = -1,ll b = -1,ll x = 0):a(a),b(b),x(x){}\n};\n// https://beet-aizu.github.io/library/test/aoj/0367.test.cpp\n// https://onlinejudge.u-aizu.ac.jp/challenges/search/titles/0367\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n ll n,K;\n cin >> n >> K;\n HLD hld(n);\n map<P,ll> mp;\n rep(i,n-1){\n ll a,b,c;cin >> a >> b >> c;\n hld.add_edge(a,b);\n mp[P{a,b}] = mp[P{b,a}] = c;\n }\n hld.build();\n vi w(n),dep(n,-1);\n auto dfs = [&](auto &dfs,ll ov,ll d)->void{\n dep[ov] = d;\n for(auto nv : hld.v[ov]){\n if(dep[nv] != -1)continue;\n dfs(dfs,nv,d + mp[{ov,nv}]);\n }\n };\n dfs(dfs,0,0);\n auto f = [&](e u,e v)->e{\n if(u.a < 0)return v;\n if(v.a < 0)return u;\n rep(i,2){\n rep(j,2){\n if(u.a == hld.par[v.a] || v.a == hld.par[u.a]){\n return e{u.b,v.b,u.x + v.x + ((w[u.a] + w[v.a] + abs(dep[u.a]-dep[v.a]))%K == 0 ? 0 : w[u.a] + w[v.a] + abs(dep[u.a]-dep[v.a]))};\n }\n swap(v.a,v.b);\n }\n swap(u.a,u.b);\n }\n return e{-1,-1,0};\n };\n Segtree<e> seg(f,e{-1,-1,0});\n {\n vector<e> vs(n,e{-1,-1,0});\n rep(i,n)vs[hld.id[i]].a = vs[hld.id[i]].b = i;\n seg.build(vs);\n }\n ll Q;cin >> Q;\n while(Q--){\n string s;cin >> s;\n if(s == \"add\"){\n ll x,d;cin >> x >> d;\n w[x] += d;\n seg.set(hld.id[x],e{x,x,0});\n }else{\n ll s,t;cin >> s >> t;\n e r1,r2;\n auto g = [&](ll a,ll b)->void{r1 = f(r1,seg.get(a,b));};\n auto gg = [&](ll a,ll b)->void{r2 = f(r2,seg.get(a,b));};\n ll u = hld.lca(s,t);\n hld.for_each(s,u,g);\n hld.for_each_edge(t,u,gg);\n cout << f(r1,r2).x << \"\\n\";\n }\n }\n \n \n\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 44028, "score_of_the_acc": -0.5129, "final_rank": 10 }, { "submission_id": "aoj_0367_8997393", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/all>\n// #include<boost/multiprecision/cpp_int.hpp>\n\nusing namespace std;\n// using namespace atcoder;\n// using bint = boost::multiprecision::cpp_int;\nusing ll = long long;\nusing ull = unsigned long long;\nusing P = pair<int,int>;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\n#define rep(i,n) for(ll i = 0;i < (ll)n;i++)\n#define ALL(x) (x).begin(),(x).end()\n#define sz(c) ((ll)(c).size())\n#define LB(A,x) (int)(lower_bound(A.begin(),A.end(),x)-A.begin())\n// #define MOD 1000000007\n#define MOD 998244353\ntemplate<typename T>using min_priority_queue=priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T>ostream&operator<<(ostream&os,vector<T>&v){for(int i = 0;i < v.size();i++)os<<v[i]<<(i+1!=v.size()?\" \":\"\");return os;}\ntemplate<typename T>istream&operator>>(istream&is,vector<T>&v){for(T&in:v)is>>in;return is;}\ntemplate<typename T1,typename T2>ostream&operator<<(ostream&os,pair<T1,T2>&p){os<<p.first<<\" \"<<p.second;return os;}\ntemplate<typename T1,typename T2>istream&operator>>(istream&is,pair<T1,T2>&p){is>>p.first>>p.second;return is;}\n\n// https://beet-aizu.github.io/library/tree/heavylightdecomposition.cpp\nstruct HLD{\n /*\n v := 隣接リスト\n id := 元々の頂点のHLD後の頂点番号。\n head := heavyな辺でつながれた頂点集合の代表元。もっとも浅い頂点。\n sub_sz := 部分木のサイズ\n par := 親\n inv := HLD後の頂点番号から元々の頂点番号をかえす\n\n add_edge(a,b) := a,b間の無向辺を追加\n build() := HLD 分解を実行。内部でdfs_szによる部分木の取得、dfs_hldによるHLD実行。\n lca(a,b) := a,bのLCAを返す\n for_each(a,b,f) := 頂点a,b間の頂点(a,bを含む)にfを実行。このfにseg木などが乗る。\n for_each_edge(a,b,f) := 頂点a,b間の辺にfを実行。辺はつながっている2つの頂点の内深い方と対応させる。\n */\n vector<vector<int>> v;\n vector<int> id,head,sub_sz,par,inv;\n HLD(int n) : v(n),id(n,-1),head(n),sub_sz(n,1),par(n,-1),inv(n){}\n\n void add_edge(int a,int b){\n v[a].push_back(b);\n v[b].push_back(a);\n }\n\n void dfs_sz(int ov,int pre){\n if(v[ov].size() && v[ov][0] == pre)swap(v[ov][0],v[ov].back());\n par[ov] = pre;\n for(auto &nv : v[ov]){\n if(nv == pre)continue;\n dfs_sz(nv,ov);\n sub_sz[ov] += sub_sz[nv];\n if(sub_sz[nv] > sub_sz[v[ov][0]])swap(nv,v[ov][0]);\n }\n }\n void dfs_hld(int ov,int &pos){\n id[ov] = pos++;\n inv[id[ov]] = ov;\n for(auto nv : v[ov]){\n if(nv == par[ov])continue;\n head[nv] = (nv == v[ov][0] ? head[ov] : nv);\n dfs_hld(nv,pos);\n }\n }\n void build(int root = 0){\n int pos = 0;\n dfs_sz(root,-1);\n head[root] = root;\n dfs_hld(root,pos);\n }\n int lca(int a,int b){\n while(1){\n if(id[a] > id[b])swap(a,b);\n if(head[a] == head[b])return a;\n b = par[head[b]];\n }\n }\n template<typename F>\n void for_each(int a,int b,const F& f){\n while(1){\n if(id[a] > id[b])swap(a,b);\n f(max(id[head[b]],id[a]),id[b]+1);\n if(head[a] != head[b])b = par[head[b]];\n else break;\n }\n }\n /*\n 関数内でfは半開区間で値を取得するように正規化するので,\n BITが閉区間で実装されている場合などは\n auto f = [&](int a,int b){return bit.sum(a,b-1);};\n の様に変更する.データ構造が半開区間で値を取得する場合は\n auto f = [&](int a,int b){return seg.get(a,b);};\n でよい.\n */\n template<typename F>\n void for_each_edge(int a,int b,const F& f){\n while(1){\n if(id[a] > id[b])swap(a,b);\n if(head[a] != head[b]){\n f(id[head[b]],id[b]+1);\n b = par[head[b]];\n }else{\n if(a != b)f(id[a]+1,id[b]+1);\n break;\n }\n }\n }\n};\ntemplate<typename T>\nclass Segtree{\n public:\n using F = function<T(T,T)>;\n int n;\n F f;\n T ti;\n vector<T> dat;\n Segtree(){};\n Segtree(F f,T ti): f(f),ti(ti){}\n void init(int N){\n n = 1;\n while(n < N)n <<= 1;\n dat.assign(n << 1,ti);\n }\n void build(const vector<T> &v){\n int N = v.size();\n init(N);\n for(int i = 0;i < N;i++)dat[n+i] = v[i];\n for(int i = n-1;i >= 0;i--)dat[i] = f(dat[(i << 1)|0],dat[(i << 1)|1]);\n }\n void set(int k,T x){\n dat[k+=n] = x;\n while(k >>= 1){\n dat[k] = f(dat[(k << 1)|0],dat[(k << 1)|1]);\n }\n }\n T get(int l,int r){\n T vl = ti,vr = ti;\n for(l += n,r += n;l < r;l >>= 1,r >>= 1){\n if(l & 1)vl = f(vl,dat[l++]);\n if(r & 1)vr = f(dat[--r],vr);\n }\n return f(vl,vr);\n }\n // max t s.t. check(query(st,t))\n template<typename C>\n int bs(int st,C &check,T &acc,int k,int l,int r){\n if(r-l <= 1){\n acc = f(acc,dat[k]);\n return check(acc) ? k-n : -1;\n }\n int mid = (l+r) >> 1;\n if(mid <= st)return bs(st,check,acc,(k << 1)|1,mid,r);\n if(st <= l && !check(f(acc,dat[k]))){\n acc = f(acc,dat[k]);\n return -1;\n }\n int vl = bs(st,check,acc,(k << 1)|0,l,mid);\n if(vl != -1)return vl;\n return bs(st,check,acc,(k << 1)|1,mid,r);\n }\n template<typename C>\n int bs(int st,C &check){\n T acc = ti;\n return bs(st,check,acc,1,0,n);\n }\n};\n\nstruct e{\n ll a,b,x;\n e(ll a = -1,ll b = -1,ll x = 0):a(a),b(b),x(x){}\n};\n// https://beet-aizu.github.io/library/test/aoj/0367.test.cpp\n// https://onlinejudge.u-aizu.ac.jp/challenges/search/titles/0367\n\nint main(){\n \n ios_base::sync_with_stdio(0), cin.tie(0);\n int n,K;\n cin >> n >> K;\n HLD hld(n);\n map<P,int> mp;\n rep(i,n-1){\n int a,b,c;cin >> a >> b >> c;\n hld.add_edge(a,b);\n mp[P{a,b}] = mp[P{b,a}] = c;\n }\n hld.build();\n vi w(n),dep(n,-1);\n auto dfs = [&](auto &dfs,int ov,int d)->void{\n dep[ov] = d;\n for(auto nv : hld.v[ov]){\n if(dep[nv] != -1)continue;\n dfs(dfs,nv,d + mp[{ov,nv}]);\n }\n };\n dfs(dfs,0,0);\n auto f = [&](e u,e v)->e{\n if(u.a < 0)return v;\n if(v.a < 0)return u;\n rep(i,2){\n rep(j,2){\n if(u.a == hld.par[v.a] || v.a == hld.par[u.a]){\n return e{u.b,v.b,u.x + v.x + ((w[u.a] + w[v.a] + abs(dep[u.a]-dep[v.a]))%K == 0 ? 0 : w[u.a] + w[v.a] + abs(dep[u.a]-dep[v.a]))};\n }\n swap(v.a,v.b);\n }\n swap(u.a,u.b);\n }\n return e{-1,-1,0};\n };\n Segtree<e> seg(f,e{-1,-1,0});\n {\n vector<e> vs(n,e{-1,-1,0});\n rep(i,n)vs[hld.id[i]].a = vs[hld.id[i]].b = i;\n seg.build(vs);\n }\n int Q;cin >> Q;\n while(Q--){\n string s;cin >> s;\n if(s == \"add\"){\n int x,d;cin >> x >> d;\n w[x] += d;\n seg.set(hld.id[x],e{x,x,0});\n }else{\n int s,t;cin >> s >> t;\n e r1,r2;\n auto g = [&](int a,int b)->void{r1 = f(r1,seg.get(a,b));};\n auto gg = [&](int a,int b)->void{r2 = f(r2,seg.get(a,b));};\n int u = hld.lca(s,t);\n hld.for_each(s,u,g);\n hld.for_each_edge(t,u,gg);\n cout << f(r1,r2).x << \"\\n\";\n }\n }\n \n \n\n return 0;\n}", "accuracy": 0.9523809523809523, "time_ms": 160, "memory_kb": 43956, "score_of_the_acc": -0.5106, "final_rank": 20 }, { "submission_id": "aoj_0367_8719815", "code_snippet": "#include <bits/stdc++.h>\n\nstruct Edge {\n Edge(int f, int t, long long w, int i): from(f), to(t), weight(w), id(i) {}\n int from;\n int to;\n long long weight;\n int id;\n};\n\nconst int ROOT = 0;\n\nstruct Doubling {\n static constexpr int LOG = 20;\n std::vector<std::vector<int>> parent;\n std::vector<int> depth;\n Doubling(const std::vector<std::vector<Edge>>& graph) {\n int n = graph.size();\n parent.resize(LOG + 1, std::vector<int>(n));\n depth.resize(n);\n auto dfs = [&](auto self, int u, int p) -> void {\n parent[0][u] = p;\n for (auto e: graph[u]) {\n if (e.to == p) continue;\n depth[e.to] = depth[u] + 1;\n self(self, e.to, u);\n }\n };\n dfs(dfs, ROOT, ROOT);\n for (int i = 0; i < LOG; i++) {\n for (int j = 0; j < n; j++) {\n parent[i + 1][j] = parent[i][parent[i][j]];\n }\n }\n }\n int lca(int lhs, int rhs) {\n if (depth[lhs] > depth[rhs]) std::swap(lhs, rhs);\n int diff = depth[rhs] - depth[lhs];\n for (int i = 0; i < LOG; i++) {\n if (diff & (1 << i)) {\n rhs = parent[i][rhs];\n }\n }\n assert(depth[lhs] == depth[rhs]);\n if (lhs == rhs) return lhs;\n for (int i = LOG; i >= 0; i--) {\n if (parent[i][lhs] != parent[i][rhs]) {\n lhs = parent[i][lhs];\n rhs = parent[i][rhs];\n }\n }\n assert(lhs != rhs);\n assert(parent[0][lhs] == parent[0][rhs]);\n return parent[0][lhs];\n }\n // u -> w -> .... -> v\n // となるwを探す\n int child(int u, int v) {\n assert(depth[u] < depth[v]);\n int diff = depth[v] - depth[u] - 1;\n for (int i = 0; i < LOG; i++) {\n if (diff & (1 << i)) {\n v = parent[i][v];\n }\n }\n assert(depth[u] + 1 == depth[v]);\n assert(parent[0][v] == u);\n return v;\n }\n};\n\nstruct FenwickTreeWithEulerTour {\n std::vector<int> in, out;\n std::vector<long long> data;\n int n;\n FenwickTreeWithEulerTour(const std::vector<std::vector<Edge>>& graph) {\n n = 2 * graph.size();\n in.resize(graph.size());\n out.resize(graph.size());\n data.resize(n + 1);\n int now = 0;\n auto dfs = [&](auto self, int u, int p) -> void {\n in[u] = now++;\n for (auto e: graph[u]) {\n if (e.to == p) continue;\n self(self, e.to, u);\n }\n out[u] = now++;\n };\n dfs(dfs, ROOT, ROOT);\n }\n\n void clear() {\n data.assign(n + 1, 0);\n }\n\n // uはvの祖先かどうか\n bool is_ancestor(int u, int v) {\n return in[u] <= in[v] && out[v] <= out[u];\n }\n\n long long dist(int u, int v, int w) {\n return path(u) + path(v) - 2 * path(w);\n }\n\n long long path(int u) {\n return sum(in[u]);\n }\n\n void add_edge(int u, long long diff) {\n add(in[u] - 1, diff);\n add(out[u] - 1, -diff);\n }\n\n void add(int pos, long long diff) {\n for (pos++; pos <= n; pos += pos & -pos) {\n data[pos] += diff;\n }\n }\n\n long long sum(int pos) {\n long long res = 0;\n for (; pos > 0; pos -= pos & -pos) {\n res += data[pos];\n }\n return res;\n }\n};\n\nint main() {\n int n;\n long long k;\n std::cin >> n >> k;\n std::vector<Edge> edges;\n edges.reserve(n - 1);\n std::vector graph(n, std::vector<Edge>());\n for (int i = 0; i + 1 < n; i++) {\n int u, v;\n long long w;\n std::cin >> u >> v >> w;\n edges.emplace_back(u, v, w, i);\n graph[u].emplace_back(u, v, w, i);\n graph[v].emplace_back(v, u, w, i);\n }\n Doubling doubling(graph);\n FenwickTreeWithEulerTour fenwick(graph);\n for (auto& e: edges) {\n if (fenwick.is_ancestor(e.to, e.from)) std::swap(e.from, e.to);\n }\n\n std::vector<int> parent_edge_id(n);\n auto dfs = [&](auto self, int u, int p) -> void {\n for (auto e: graph[u]) {\n if (e.to == p) {\n parent_edge_id[u] = e.id;\n } else {\n self(self, e.to, u);\n }\n }\n };\n dfs(dfs, ROOT, ROOT);\n\n auto eval = [&](long long w) {\n return w % k == 0 ? 0 : w;\n };\n\n int q;\n std::cin >> q;\n const int SQRT_Q = 500;\n std::vector<long long> cur_diff(n);\n std::vector<int> already(n);\n for (; q > 0; q -= SQRT_Q) {\n cur_diff.assign(n, 0);\n already.assign(n, 0);\n fenwick.clear();\n for (auto e: edges) {\n fenwick.add_edge(e.to, eval(e.weight));\n }\n\n std::vector<int> add_query_vertex;\n for (int i = 0; i < std::min(q, SQRT_Q); i++) {\n std::string type;\n std::cin >> type;\n if (type == \"add\") {\n int x, d;\n std::cin >> x >> d;\n cur_diff[x] += d;\n if (!already[x]) {\n already[x] = 1;\n add_query_vertex.push_back(x);\n }\n } else {\n int u, v;\n std::cin >> u >> v;\n int w = doubling.lca(u, v);\n // u -> v\n if (v == w) std::swap(u, v);\n long long ans = fenwick.dist(u, v, w);\n std::unordered_map<int, long long> edge_weight_diff;\n for (auto a: add_query_vertex) {\n bool on_path = true;\n if (u == w) {\n on_path &= fenwick.is_ancestor(u, a);\n on_path &= fenwick.is_ancestor(a, v);\n } else {\n on_path &= fenwick.is_ancestor(w, a);\n bool temp = false;\n temp |= fenwick.is_ancestor(a, u);\n temp |= fenwick.is_ancestor(a, v);\n on_path &= temp;\n }\n if (on_path) {\n for (auto b: {u, v}) {\n if (b == a) continue;\n if (fenwick.is_ancestor(a, b)) {\n int c = doubling.child(a, b);\n assert(edges[parent_edge_id[c]].from == a);\n edge_weight_diff[parent_edge_id[c]] += cur_diff[a];\n // ans -= eval(edges[parent_edge_id[c]].weight);\n // ans += eval(edges[parent_edge_id[c]].weight + cur_diff[a]);\n } else {\n edge_weight_diff[parent_edge_id[a]] += cur_diff[a];\n // ans -= eval(edges[parent_edge_id[a]].weight);\n // ans += eval(edges[parent_edge_id[a]].weight + cur_diff[a]);\n }\n }\n }\n }\n for (auto [id, diff]: edge_weight_diff) {\n ans -= eval(edges[id].weight);\n ans += eval(edges[id].weight + diff);\n }\n std::cout << ans << '\\n';\n }\n }\n\n for (auto u: add_query_vertex) {\n for (auto e: graph[u]) {\n edges[e.id].weight += cur_diff[u];\n }\n }\n }\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 35764, "score_of_the_acc": -0.6094, "final_rank": 14 }, { "submission_id": "aoj_0367_8481044", "code_snippet": "#include<bits/stdc++.h>\n#define PPque priority_queue<tuple<ll, ll, ll>, vector<tuple<ll, ll, ll>>, greater<tuple<ll, ll, ll>>>\n#define Pque priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>\n#define pque priority_queue<ll, vector<ll>, greater<ll>>\n#define umap unordered_map\n#define uset unordered_set\n#define rep(i, s, f) for(ll i = s; i <= f; i++)\n#define per(i, s, f) for(ll i = s; i >= f; i--)\n#define all0(x) (x).begin() ,(x).end()\n#define all(x) (x).begin() + 1, (x).end()\n#define vvvvl vector<vvvl>\n#define vvvi vector<vector<vector<int>>>\n#define vvvl vector<vector<vector<ll>>>\n#define vvvc vector<vector<vector<char>>>\n#define vvvd vector<vector<vector<double>>>\n#define vvvm vector<vector<vector<mint>>>\n#define vvi vector<vector<int>>\n#define vvl vector<vector<ll>>\n#define vvs vector<vector<string>>\n#define vvc vector<vector<char>>\n#define vvp vector<vector<pair<ll, ll>>>\n#define vvb vector<vector<bool>>\n#define vvd vector<vector<double>>\n#define vvm vector<vector<mint>>\n#define vp vector<pair<ll, ll>>\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define vc vector<char>\n#define vb vector<bool>\n#define vd vector<double>\n#define vm vector<mint>\n#define P pair<ll, ll>\n#define TU tuple<ll, ll, ll>\n#define rrr(l, r) mt()%(r-l+1)+l\n#define ENDL '\\n'\n#define ull unsigned long long\ntypedef long long ll;\nusing namespace std;\n\n////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//これが本当の組み込み関数ってね(笑)\n\ntemplate <typename T>\nT or_less(vector<T> &A, T x) { //x以下で最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT under(vector<T> &A, T x) { //x未満の最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT or_more(vector<T> &A, T x) { //x以上で最小要素の添字  前提: sort済み 存在しない: N . //distanceのA.beginは添字を出すために常にA.begin() NG: A.begin() + 1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nT over(vector<T> &A, T x) { //xより大きい最小要素の添字前提: sort済み 存在しない: N\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nvector<T> vec_shift_right(vector<T> A, ll step, ll dir = 1, ll indexed = 1) {//dir = 1 : 右シフト dir = -1 : 左シフト\n ll N = A.size() - indexed;\n vector<T> res(N+1);\n rep(i, indexed, N) {\n ll idx = i - step * dir;\n if(idx < indexed) idx += N;\n if(idx > N) idx -= N;\n res.at(i) = A.at(idx);\n }\n return res;\n}\ntemplate <typename T>\nvoid UNIQUE(vector<T> &A) {\n sort(all0(A));\n return A.erase(unique(A.begin(), A.end()), A.end());\n}\ntemplate <typename T>\nvoid rev90(vector<vector<T>> &A, int indexed = 1) {\n reverse(A.begin() + indexed, A.end());\n int n = A.size();\n rep(i, indexed, n-1) {\n rep(j, i+1, n-1) {\n swap(A.at(i).at(j), A.at(j).at(i));\n }\n }\n}\nvoid chmin(ll &a, ll b) {\n a = min(a, b);\n}\nvoid chmax(ll &a, ll b) {\n a = max(a, b);\n}\n//////////////////////////////////////////////////////////////////////\n//数学系\n///////////////////////////////////////////////////////////////////////\nll round(ll x, ll i) {return ll(x + 5 * pow(10, i-1))/ll(pow(10, i)) * ll(pow(10, i));}\nvp insu_bunkai(ll N) {\n vp res;\n for (ll i = 2; i * i <= N; i++) {\n ll cnt = 0;\n while(N % i == 0) {\n cnt++;\n N /= i;\n }\n if(cnt != 0) res.push_back(P(i, cnt));\n }\n if(N != 1) res.push_back(P(N, 1));\n return res;\n}\nll extgcd (ll a, ll b, ll &x, ll &y) {\n if(b == 0) { x = 1;y = 0;return a;}\n ll d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\ntemplate <typename T>\nT ceil(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b + 1;\n else return a / b;\n}\ntemplate <typename T>\nT floor(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b;\n else return a/b - 1;\n}\nll modpow(ll x, ll y, ll mod) {\n if(x > mod) x %= mod;\n if(y == 0) return 1;\n ll res = modpow(x, y >> 1, mod);\n res = res * res % mod;\n if(y & 1) res *= x, res %= mod;\n return res;\n}\nll sqrt_(ll a) {\n ll l = 0;\n ll r = 3000000000LL;\n while(l < r) {\n ll mid = (l + r + 1) / 2;\n if(mid * mid <= a) l = mid;\n else r = mid - 1;\n }\n return l;\n}\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//グローバル変数を置くところ(情報工学意識高め)\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\nconst ll int_max = 1001001001;\nconst ll ll_max = 1001001001001001001LL;\nconst double pi = 3.141592653589793;\nvl dx{0, 1, 0, -1, 0, 1, 1, -1, -1}; // (番兵) → ↓ ← ↑ ※ 右から時計回り \nvl dy{0, 0, -1, 0, 1, 1, -1, -1, 1};\n//const ll mod = 1000000007;\n//const ll mod = 998244353;\nll K;\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\n\n\n/////////////////////////////////////////////////////////////////////////////////////////////////////////\n//いじるところ。\n\n\n\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////\n\ntemplate <typename X>\nstruct HL {\n vector<int> siz;//[元の頂点番号] = サイズ\n vector<int> num;//[元の頂点番号] = 振り直した頂点番号\n vector<int> numrev;\n vector<int> par;//[振られた] = 振られた 自分の親\n vector<int> head;//[振られた番号] = 振られた番号 自分の連結成分の頭\n int N;\n vector<X> dat;//セグ木用の配列、0...上り 1...下り\n \n int n = 1;\n X def;\n X ide;\n \n\n HL(int _N, vvl& G, X _def, X _ide): N(_N), def(_def), ide(_ide) {\n par.resize(N+1);\n iota(par.begin(), par.end(), 0);\n siz.resize(N+1, 1);\n num.assign(N+1, -1);\n numrev.resize(N+1, -1);\n head.resize(N+1);\n while(n < N) n <<= 1;\n dat.assign(n*2, def);\n\n auto dfs_siz = [&](auto dfs_siz, int now, int prev) -> void {\n int sum = 1;\n for(int to : G[now]) {\n if(to == prev) continue;\n dfs_siz(dfs_siz, to, now);\n sum += siz[to];\n }\n siz[now] = sum;\n return;\n };\n dfs_siz(dfs_siz, 1, -1);\n rep(i, 1, N){\n sort(G[i].begin(), G[i].end(), [&](int a, int b) {\n return siz[a] > siz[b];\n });\n }\n\n int idx = 1;\n auto dfs_bunkai = [&](auto dfs_bunkai, int now, int prev, int hed) -> void {\n num[now] = idx;//番号付\n numrev[idx] = now;\n idx++;\n par[num[now]] = prev;//親の頂点 //1だけは直前も自分も1\n if(hed == -1)hed = num[now];\n head[num[now]] = hed;\n\n bool flag = true;\n \n rep(i, 0, int(G[now].size()) - 1) {\n if(num[G[now][i]] != -1) continue;\n if(flag) dfs_bunkai(dfs_bunkai, G[now][i], num[now], hed), flag = false;\n else dfs_bunkai(dfs_bunkai, G[now][i], num[now], -1);\n }\n return;\n };\n dfs_bunkai(dfs_bunkai, 1, 1, -1);\n }\n // 振り終わった\n //////////////////////////////////////////\n \n \n void change(int pos, ll x, int t) {\n pos = num[pos];//振り当てた番号で扱う!!!\n pos = n + pos - 1;\n dat[pos] = update(dat[pos], x, t);\n while(pos >= 2) {\n pos >>= 1;\n dat[pos] = op(dat[pos * 2], dat[pos * 2 + 1]);\n }\n }\n\n int getlca(int a, int b) {\n a = num[a];\n b = num[b];\n while(true) {\n if(a > b) swap(a, b);\n if(head[a] == head[b]) return numrev[a];\n b = par[head[b]];\n }\n }\n\n X query(int a, int b) {\n X L = ide, R = ide;\n a += n - 1, b += n - 1;\n while(a < b) {\n if(a & 1) L = op(L, dat[a++]);\n if(b & 1) R = op(dat[--b], R);\n a >>= 1, b >>= 1;\n } \n return op(L, R);\n }\n\n ll get(int u, int v) {//uからvへのパス上の頂点についてやる\n int w = num[getlca(u, v)];//lcaで左右に分ける\n u = num[u];\n v = num[v];\n X L = ide;\n while(u != w) {\n int hed = max<int>(head[u], w+1);\n L = op(query(hed, u+1), L); \n if(hed != w) u = par[hed];\n else break;\n } \n L = op(query(w, w+1), L);\n X R = ide;\n while(v != w) {\n int hed = max<int>(head[v], w+1);\n R = op(query(hed, v+1), R); \n if(hed != w) v = par[hed];\n else break;\n }\n R = op(query(w, w+1), R);\n //R = operation(query(1, size+1, w, w+1, 1), R); これをしてないので、RはまだLCAに辿り着いてない。\n return L.s + R.s;//交換則を要する時はこの行を変更する必要があるかもしれない : 無いと思うが\n }\n\n\n int parent(int a) {\n return numrev[par[num[a]]];\n }\n};\n\nstruct Monoid {\n bool e = false; \n ll l = 0, r = 0, s = 0;\n Monoid(){e = true;}\n Monoid(ll _l, ll _r, ll _s) : l(_l), r(_r), s(_s){e = false;}\n\n friend Monoid op(const Monoid a, const Monoid b) {\n if(a.e) return b;\n if(b.e) return a;\n Monoid res(0, 0, 0);\n res.l = a.l;\n res.r = b.r;\n res.s = a.s + b.s + a.r + b.l;\n if((a.r + b.l)%K == 0) res.s -= a.r + b.l;\n return res;\n }\n\n friend Monoid update(Monoid a, ll b, int t) {\n Monoid res = a;\n res.l += b;\n if(t == 1)res.r += b;\n return res;\n }\n};\nMonoid ide;//単位元\nMonoid def(0, 0, 0);//初期化の値\n\nvoid solve() {\n ll N;\n cin >> N >> K;\n vvl G(N+1);\n map<P, ll> w;\n rep(i,1,N-1) {\n ll a, b;\n cin >> a >> b; a++, b++;\n G[a].push_back(b);\n G[b].push_back(a);\n ll c;\n cin >> c;\n w[P(a, b)] = c;\n }\n\n \n HL<Monoid> hld(N, G, def, ide);\n\n for(auto [p, c] : w) {\n auto [a, b] = p;\n if(hld.parent(a) == b) swap(a, b);\n hld.change(b, c, 0);\n }\n ll Q;\n cin >> Q;\n rep(qi, 1, Q) {\n string type;\n cin >> type;\n if(type == \"add\") {\n ll x, d;\n cin >> x >> d;\n x++;\n hld.change(x, d, 1);\n }\n else {\n ll s, t;\n cin >> s >> t; s++, t++;\n cout << hld.get(s, t) << endl;\n }\n }\n \n\n \n\n}\n//無断で0を平方数にカウントする人もいる\n//”部分文字列”と”連続部分文字列”は違うので確認すること\n//一般のグラフと、有向辺かつその貼り方に制約がある(多くの場合:番号がで解放に伸びる)はだいぶ違うので確認すること\n//座標を2で割った時の”切り捨て側(左側)”を求めるには 誤:(x / 2) マイナスの時!!! 正:floor<ll>(x, 2);\n//stringでの数字の下から1桁目は 正:S.at(N-1) 誤:S.at(0)\n//if(S.at(i) == 1) ← charなのに1...?\n// modは取りましたか...?(´・ω・`)\n//sortの比較関数は、 a == b ならば falseを返す必要がある(そうで無いとRE(発生しない場合もある))\n\n\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(15);\n ll T = 1;\n //cin >> T;\n rep(i, 1, T) {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 34020, "score_of_the_acc": -0.2024, "final_rank": 4 }, { "submission_id": "aoj_0367_8461521", "code_snippet": "#include<bits/stdc++.h>\n#define PPque priority_queue<tuple<ll, ll, ll>, vector<tuple<ll, ll, ll>>, greater<tuple<ll, ll, ll>>>\n#define Pque priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>\n#define pque priority_queue<ll, vector<ll>, greater<ll>>\n#define umap unordered_map\n#define uset unordered_set\n#define rep(i, s, f) for(ll i = s; i <= f; i++)\n#define per(i, s, f) for(ll i = s; i >= f; i--)\n#define all0(x) (x).begin() ,(x).end()\n#define all(x) (x).begin() + 1, (x).end()\n#define vvvvl vector<vvvl>\n#define vvvi vector<vector<vector<int>>>\n#define vvvl vector<vector<vector<ll>>>\n#define vvvc vector<vector<vector<char>>>\n#define vvvd vector<vector<vector<double>>>\n#define vvvm vector<vector<vector<mint>>>\n#define vvi vector<vector<int>>\n#define vvl vector<vector<ll>>\n#define vvs vector<vector<string>>\n#define vvc vector<vector<char>>\n#define vvp vector<vector<pair<ll, ll>>>\n#define vvb vector<vector<bool>>\n#define vvd vector<vector<double>>\n#define vvm vector<vector<mint>>\n#define vp vector<pair<ll, ll>>\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define vc vector<char>\n#define vb vector<bool>\n#define vd vector<double>\n#define vm vector<mint>\n#define P pair<ll, ll>\n#define TU tuple<ll, ll, ll>\n#define rrr(l, r) mt()%(r-l+1)+l\n#define ENDL '\\n'\n#define ull unsigned long long\ntypedef long long ll;\nusing namespace std;\n\n////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//これが本当の組み込み関数ってね(笑)\n\ntemplate <typename T>\nT or_less(vector<T> &A, T x) { //x以下で最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT under(vector<T> &A, T x) { //x未満の最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT or_more(vector<T> &A, T x) { //x以上で最小要素の添字  前提: sort済み 存在しない: N . //distanceのA.beginは添字を出すために常にA.begin() NG: A.begin() + 1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nT over(vector<T> &A, T x) { //xより大きい最小要素の添字前提: sort済み 存在しない: N\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nvector<T> vec_shift_right(vector<T> A, ll step, ll dir = 1, ll indexed = 1) {//dir = 1 : 右シフト dir = -1 : 左シフト\n ll N = A.size() - indexed;\n vector<T> res(N+1);\n rep(i, indexed, N) {\n ll idx = i - step * dir;\n if(idx < indexed) idx += N;\n if(idx > N) idx -= N;\n res.at(i) = A.at(idx);\n }\n return res;\n}\ntemplate <typename T>\nvoid UNIQUE(vector<T> &A) {\n sort(all0(A));\n return A.erase(unique(A.begin(), A.end()), A.end());\n}\ntemplate <typename T>\nvoid rev90(vector<vector<T>> &A, int indexed = 1) {\n reverse(A.begin() + indexed, A.end());\n int n = A.size();\n rep(i, indexed, n-1) {\n rep(j, i+1, n-1) {\n swap(A.at(i).at(j), A.at(j).at(i));\n }\n }\n}\nvoid chmin(ll &a, ll b) {\n a = min(a, b);\n}\nvoid chmax(ll &a, ll b) {\n a = max(a, b);\n}\n//////////////////////////////////////////////////////////////////////\n//数学系\n///////////////////////////////////////////////////////////////////////\nll round(ll x, ll i) {return ll(x + 5 * pow(10, i-1))/ll(pow(10, i)) * ll(pow(10, i));}\nvp insu_bunkai(ll N) {\n vp res;\n for (ll i = 2; i * i <= N; i++) {\n ll cnt = 0;\n while(N % i == 0) {\n cnt++;\n N /= i;\n }\n if(cnt != 0) res.push_back(P(i, cnt));\n }\n if(N != 1) res.push_back(P(N, 1));\n return res;\n}\nll extgcd (ll a, ll b, ll &x, ll &y) {\n if(b == 0) { x = 1;y = 0;return a;}\n ll d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\ntemplate <typename T>\nT ceil(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b + 1;\n else return a / b;\n}\ntemplate <typename T>\nT floor(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b;\n else return a/b - 1;\n}\nll modpow(ll x, ll y, ll mod) {\n if(x > mod) x %= mod;\n if(y == 0) return 1;\n ll res = modpow(x, y >> 1, mod);\n res = res * res % mod;\n if(y & 1) res *= x, res %= mod;\n return res;\n}\nll sqrt_(ll a) {\n ll l = 0;\n ll r = 3000000000LL;\n while(l < r) {\n ll mid = (l + r + 1) / 2;\n if(mid * mid <= a) l = mid;\n else r = mid - 1;\n }\n return l;\n}\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//グローバル変数を置くところ(情報工学意識高め)\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\nconst ll int_max = 1001001001;\nconst ll ll_max = 1001001001001001001LL;\nconst double pi = 3.141592653589793;\nvl dx{0, 1, 0, -1, 0, 1, 1, -1, -1}; // (番兵) → ↓ ← ↑ ※ 右から時計回り \nvl dy{0, 0, -1, 0, 1, 1, -1, -1, 1};\n//const ll mod = 1000000007;\n//const ll mod = 998244353;\nll K;\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\n\n\n/////////////////////////////////////////////////////////////////////////////////////////////////////////\n//いじるところ。\nstruct XX {\n bool e = false; \n ll l = 0, r = 0, s = 0;\n XX(){e = true;}\n XX(ll _l, ll _r, ll _s) : l(_l), r(_r), s(_s){e = false;}\n};\nXX def;\nXX gen(0, 0, 0);\nXX operation(XX a, XX b) {\n if(a.e) return b;\n if(b.e) return a;\n XX res(0, 0, 0);\n res.l = a.l;\n res.r = b.r;\n res.s = a.s + b.s + a.r + b.l;\n if((a.r + b.l)%K == 0) res.s -= a.r + b.l;\n return res;\n}\n\nXX update(XX a, ll b, int t) {\n XX res = a;\n res.l += b;\n if(t == 1)res.r += b;\n return res;\n}\n\n\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////\n\ntemplate <typename X>\nstruct HL {\n vector<int> siz;//[元の頂点番号] = サイズ\n vector<int> num;//[元の頂点番号] = 振り直した頂点番号\n vector<int> numrev;\n vector<int> par;//[振られた] = 振られた 自分の親\n vector<int> head;//[振られた番号] = 振られた番号 自分の連結成分の頭\n int N;\n vector<X> dat;//セグ木用の配列、0...上り 1...下り\n \n int n = 1;\n \n\n HL(int _N, vvl& G): N(_N) {\n par.resize(N+1);\n iota(par.begin(), par.end(), 0);\n siz.resize(N+1, 1);\n num.assign(N+1, -1);\n numrev.resize(N+1, -1);\n head.resize(N+1);\n while(n < N) n <<= 1;\n dat.assign(n*2, gen);\n\n auto dfs_siz = [&](auto dfs_siz, int now, int prev) -> void {\n int sum = 1;\n for(int to : G[now]) {\n if(to == prev) continue;\n dfs_siz(dfs_siz, to, now);\n sum += siz[to];\n }\n siz[now] = sum;\n return;\n };\n dfs_siz(dfs_siz, 1, -1);\n rep(i, 1, N){\n sort(G[i].begin(), G[i].end(), [&](int a, int b) {\n return siz[a] > siz[b];\n });\n }\n\n int idx = 1;\n auto dfs_bunkai = [&](auto dfs_bunkai, int now, int prev, int hed) -> void {\n num[now] = idx;//番号付\n numrev[idx] = now;\n idx++;\n par[num[now]] = prev;//親の頂点 //1だけは直前も自分も1\n if(hed == -1)hed = num[now];\n head[num[now]] = hed;\n\n bool flag = true;\n \n rep(i, 0, int(G[now].size()) - 1) {\n if(num[G[now][i]] != -1) continue;\n if(flag) dfs_bunkai(dfs_bunkai, G[now][i], num[now], hed), flag = false;\n else dfs_bunkai(dfs_bunkai, G[now][i], num[now], -1);\n }\n return;\n };\n dfs_bunkai(dfs_bunkai, 1, 1, -1);\n }\n // 振り終わった\n //////////////////////////////////////////\n \n \n void change(int pos, ll x, int t) {\n pos = num[pos];//振り当てた番号で扱う!!!\n pos = n + pos - 1;\n dat[pos] = update(dat[pos], x, t);\n while(pos >= 2) {\n pos >>= 1;\n dat[pos] = operation(dat[pos * 2], dat[pos * 2 + 1]);\n }\n }\n\n int getlca(int a, int b) {\n a = num[a];\n b = num[b];\n while(true) {\n if(a > b) swap(a, b);\n if(head[a] == head[b]) return numrev[a];\n b = par[head[b]];\n }\n }\n\n X query(int a, int b) {\n X L = def, R = def;\n a += n - 1, b += n - 1;\n while(a < b) {\n if(a & 1) L = operation(L, dat[a++]);\n if(b & 1) R = operation(dat[--b], R);\n a >>= 1, b >>= 1;\n } \n return operation(L, R);\n }\n\n ll get(int u, int v) {//uからvへのパス上の頂点についてやる\n int w = num[getlca(u, v)];//lcaで左右に分ける\n u = num[u];\n v = num[v];\n X L = def;\n while(u != w) {\n int hed = max<int>(head[u], w+1);\n L = operation(query(hed, u+1), L); \n if(hed != w) u = par[hed];\n else break;\n } \n L = operation(query(w, w+1), L);\n X R = def;\n while(v != w) {\n int hed = max<int>(head[v], w+1);\n R = operation(query(hed, v+1), R); \n if(hed != w) v = par[hed];\n else break;\n }\n R = operation(query(w, w+1), R);\n //R = operation(query(1, size+1, w, w+1, 1), R); これをしてないので、RはまだLCAに辿り着いてない。\n return L.s + R.s;//交換則を要する時はこの行を変更する必要があるかもしれない : 無いと思うが\n }\n\n\n int parent(int a) {\n return numrev[par[num[a]]];\n }\n};\n\n\n\nvoid solve() {\n ll N;\n cin >> N >> K;\n vvl G(N+1);\n map<P, ll> w;\n rep(i,1,N-1) {\n ll a, b;\n cin >> a >> b; a++, b++;\n G[a].push_back(b);\n G[b].push_back(a);\n ll c;\n cin >> c;\n w[P(a, b)] = c;\n }\n\n \n HL<XX> hld(N, G);\n\n for(auto [p, c] : w) {\n auto [a, b] = p;\n if(hld.parent(a) == b) swap(a, b);\n hld.change(b, c, 0);\n }\n ll Q;\n cin >> Q;\n rep(qi, 1, Q) {\n string type;\n cin >> type;\n if(type == \"add\") {\n ll x, d;\n cin >> x >> d;\n x++;\n hld.change(x, d, 1);\n }\n else {\n ll s, t;\n cin >> s >> t; s++, t++;\n cout << hld.get(s, t) << endl;\n }\n }\n \n\n \n\n}\n//無断で0を平方数にカウントする人もいる\n//”部分文字列”と”連続部分文字列”は違うので確認すること\n//一般のグラフと、有向辺かつその貼り方に制約がある(多くの場合:番号がで解放に伸びる)はだいぶ違うので確認すること\n//座標を2で割った時の”切り捨て側(左側)”を求めるには 誤:(x / 2) マイナスの時!!! 正:floor<ll>(x, 2);\n//stringでの数字の下から1桁目は 正:S.at(N-1) 誤:S.at(0)\n//if(S.at(i) == 1) ← charなのに1...?\n// modは取りましたか...?(´・ω・`)\n//sortの比較関数は、 a == b ならば falseを返す必要がある(そうで無いとRE(発生しない場合もある))\n\n\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(15);\n ll T = 1;\n //cin >> T;\n rep(i, 1, T) {\n solve();\n }\n return 0;\n}\n/*\n3 100\n0 1 1\n1 2 1\n2\nsend 0 2\nsend 2 0\n\n*/", "accuracy": 1, "time_ms": 190, "memory_kb": 34240, "score_of_the_acc": -0.2139, "final_rank": 5 }, { "submission_id": "aoj_0367_8461503", "code_snippet": "#include<bits/stdc++.h>\n#define PPque priority_queue<tuple<ll, ll, ll>, vector<tuple<ll, ll, ll>>, greater<tuple<ll, ll, ll>>>\n#define Pque priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>\n#define pque priority_queue<ll, vector<ll>, greater<ll>>\n#define umap unordered_map\n#define uset unordered_set\n#define rep(i, s, f) for(ll i = s; i <= f; i++)\n#define per(i, s, f) for(ll i = s; i >= f; i--)\n#define all0(x) (x).begin() ,(x).end()\n#define all(x) (x).begin() + 1, (x).end()\n#define vvvvl vector<vvvl>\n#define vvvi vector<vector<vector<int>>>\n#define vvvl vector<vector<vector<ll>>>\n#define vvvc vector<vector<vector<char>>>\n#define vvvd vector<vector<vector<double>>>\n#define vvvm vector<vector<vector<mint>>>\n#define vvi vector<vector<int>>\n#define vvl vector<vector<ll>>\n#define vvs vector<vector<string>>\n#define vvc vector<vector<char>>\n#define vvp vector<vector<pair<ll, ll>>>\n#define vvb vector<vector<bool>>\n#define vvd vector<vector<double>>\n#define vvm vector<vector<mint>>\n#define vp vector<pair<ll, ll>>\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define vc vector<char>\n#define vb vector<bool>\n#define vd vector<double>\n#define vm vector<mint>\n#define P pair<ll, ll>\n#define TU tuple<ll, ll, ll>\n#define rrr(l, r) mt()%(r-l+1)+l\n#define ENDL '\\n'\n#define ull unsigned long long\ntypedef long long ll;\nusing namespace std;\n\n////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//これが本当の組み込み関数ってね(笑)\n\ntemplate <typename T>\nT or_less(vector<T> &A, T x) { //x以下で最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT under(vector<T> &A, T x) { //x未満の最大要素の添字 前提: sort済み 存在しない: -1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x)-1);\n}\ntemplate <typename T>\nT or_more(vector<T> &A, T x) { //x以上で最小要素の添字  前提: sort済み 存在しない: N . //distanceのA.beginは添字を出すために常にA.begin() NG: A.begin() + 1\n return distance(A.begin(), lower_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nT over(vector<T> &A, T x) { //xより大きい最小要素の添字前提: sort済み 存在しない: N\n return distance(A.begin(), upper_bound(A.begin(), A.end(), x));\n}\ntemplate <typename T>\nvector<T> vec_shift_right(vector<T> A, ll step, ll dir = 1, ll indexed = 1) {//dir = 1 : 右シフト dir = -1 : 左シフト\n ll N = A.size() - indexed;\n vector<T> res(N+1);\n rep(i, indexed, N) {\n ll idx = i - step * dir;\n if(idx < indexed) idx += N;\n if(idx > N) idx -= N;\n res.at(i) = A.at(idx);\n }\n return res;\n}\ntemplate <typename T>\nvoid UNIQUE(vector<T> &A) {\n sort(all0(A));\n return A.erase(unique(A.begin(), A.end()), A.end());\n}\ntemplate <typename T>\nvoid rev90(vector<vector<T>> &A, int indexed = 1) {\n reverse(A.begin() + indexed, A.end());\n int n = A.size();\n rep(i, indexed, n-1) {\n rep(j, i+1, n-1) {\n swap(A.at(i).at(j), A.at(j).at(i));\n }\n }\n}\nvoid chmin(ll &a, ll b) {\n a = min(a, b);\n}\nvoid chmax(ll &a, ll b) {\n a = max(a, b);\n}\n//////////////////////////////////////////////////////////////////////\n//数学系\n///////////////////////////////////////////////////////////////////////\nll round(ll x, ll i) {return ll(x + 5 * pow(10, i-1))/ll(pow(10, i)) * ll(pow(10, i));}\nvp insu_bunkai(ll N) {\n vp res;\n for (ll i = 2; i * i <= N; i++) {\n ll cnt = 0;\n while(N % i == 0) {\n cnt++;\n N /= i;\n }\n if(cnt != 0) res.push_back(P(i, cnt));\n }\n if(N != 1) res.push_back(P(N, 1));\n return res;\n}\nll extgcd (ll a, ll b, ll &x, ll &y) {\n if(b == 0) { x = 1;y = 0;return a;}\n ll d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\ntemplate <typename T>\nT ceil(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b + 1;\n else return a / b;\n}\ntemplate <typename T>\nT floor(T a, T b) {\n assert(b != 0);\n if(a % b == 0) return a / b;\n if((a <= 0 && b < 0) || (a >= 0 && b > 0)) return a/b;\n else return a/b - 1;\n}\nll modpow(ll x, ll y, ll mod) {\n if(x > mod) x %= mod;\n if(y == 0) return 1;\n ll res = modpow(x, y >> 1, mod);\n res = res * res % mod;\n if(y & 1) res *= x, res %= mod;\n return res;\n}\nll sqrt_(ll a) {\n ll l = 0;\n ll r = 3000000000LL;\n while(l < r) {\n ll mid = (l + r + 1) / 2;\n if(mid * mid <= a) l = mid;\n else r = mid - 1;\n }\n return l;\n}\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\n//グローバル変数を置くところ(情報工学意識高め)\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"unroll-loops\")\nconst ll int_max = 1001001001;\nconst ll ll_max = 1001001001001001001LL;\nconst double pi = 3.141592653589793;\nvl dx{0, 1, 0, -1, 0, 1, 1, -1, -1}; // (番兵) → ↓ ← ↑ ※ 右から時計回り \nvl dy{0, 0, -1, 0, 1, 1, -1, -1, 1};\n//const ll mod = 1000000007;\n//const ll mod = 998244353;\nll K;\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////\nstruct lca_getter {\n int N;\n vvl dp;\n vi depth;\n ll n = 0;\n lca_getter(){}\n void build(int _N, vvl& G) {\n N = _N;\n ll c_n = N;\n while(c_n > 0) {\n c_n >>= 1;\n n++;\n }\n //n回登れば超えるということは, 2^n-1の桁までの合計で表せる\n\n dp.resize(n);\n depth.resize(N+1, 0);\n rep(i,0,n-1)dp[i].resize(N+1);\n auto dfs = [&](auto dfs, ll now, ll prev) -> void {\n if(prev != -1) depth[now] = depth[prev] + 1;\n for(ll to : G[now]) {\n if(to == prev) continue;\n dp[0][to] = now;\n dfs(dfs, to, now);\n }\n };\n dfs(dfs, 1, -1);\n dp[0][1] = -1;\n rep(i, 1, n-1) {\n rep(j, 1, N) {\n if(dp[i-1][j] == -1) dp[i][j] = -1;\n else dp[i][j] = dp[i-1][dp[i-1][j]];\n }\n }\n }\n int get(int a, int b) {\n if(depth[a] < depth[b]) swap(a, b);\n if(depth[a] > depth[b]) {\n int diff = depth[a] - depth[b];\n rep(i, 0, n-1) {\n if(diff >> i & 1) a = dp[i][a];\n }\n }\n if(a == b) return a;\n per(i, n-1, 0) {\n if(dp[i][a] != dp[i][b]) a = dp[i][a], b = dp[i][b];\n }\n return dp[0][a];\n }\n};\n\n\n\n/////////////////////////////////////////////////////////////////////////////////////////////////////////\n//いじるところ。\nlca_getter LCA;//solveの中でbuildを呼べば良い。\nstruct XX {\n bool e = false; \n ll l = 0, r = 0, s = 0;\n XX(){e = true;}\n XX(ll _l, ll _r, ll _s) : l(_l), r(_r), s(_s){e = false;}\n};\nXX def;\nXX gen(0, 0, 0);\nXX operation(XX a, XX b) {\n if(a.e) return b;\n if(b.e) return a;\n XX res(0, 0, 0);\n res.l = a.l;\n res.r = b.r;\n res.s = a.s + b.s + a.r + b.l;\n if((a.r + b.l)%K == 0) res.s -= a.r + b.l;\n return res;\n}\n\nXX update(XX a, ll b, int t) {\n XX res = a;\n res.l += b;\n if(t == 1)res.r += b;\n return res;\n}\n\n\n\n//////////////////////////////////////////////////////////////////////////////////////////////////////////\n\ntemplate <typename X>\nstruct HL {\n vector<int> siz;//[元の頂点番号] = サイズ\n vector<int> num;//[元の頂点番号] = 振り直した頂点番号\n vector<int> numrev;\n vector<int> par;//[振られた] = 振られた 自分の親\n vector<int> head;//[振られた番号] = 振られた番号 自分の連結成分の頭\n int N;\n vector<X> dat;//セグ木用の配列、0...上り 1...下り\n \n int n = 1;\n \n\n HL(int _N, vvl& G): N(_N) {\n par.resize(N+1);\n iota(par.begin(), par.end(), 0);\n siz.resize(N+1, 1);\n num.assign(N+1, -1);\n numrev.resize(N+1, -1);\n head.resize(N+1);\n while(n < N) n <<= 1;\n dat.assign(n*2, gen);\n\n auto dfs_siz = [&](auto dfs_siz, int now, int prev) -> void {\n int sum = 1;\n for(int to : G[now]) {\n if(to == prev) continue;\n dfs_siz(dfs_siz, to, now);\n sum += siz[to];\n }\n siz[now] = sum;\n return;\n };\n dfs_siz(dfs_siz, 1, -1);\n rep(i, 1, N){\n sort(G[i].begin(), G[i].end(), [&](int a, int b) {\n return siz[a] > siz[b];\n });\n }\n\n int idx = 1;\n auto dfs_bunkai = [&](auto dfs_bunkai, int now, int prev, int hed) -> void {\n num[now] = idx;//番号付\n numrev[idx] = now;\n idx++;\n par[num[now]] = prev;//親の頂点 //1だけは直前も自分も1\n if(hed == -1)hed = num[now];\n head[num[now]] = hed;\n\n bool flag = true;\n \n rep(i, 0, int(G[now].size()) - 1) {\n if(num[G[now][i]] != -1) continue;\n if(flag) dfs_bunkai(dfs_bunkai, G[now][i], num[now], hed), flag = false;\n else dfs_bunkai(dfs_bunkai, G[now][i], num[now], -1);\n }\n return;\n };\n dfs_bunkai(dfs_bunkai, 1, 1, -1);\n }\n // 振り終わった\n //////////////////////////////////////////\n \n \n void change(int pos, ll x, int t) {\n pos = num[pos];//振り当てた番号で扱う!!!\n pos = n + pos - 1;\n dat[pos] = update(dat[pos], x, t);\n while(pos >= 2) {\n pos >>= 1;\n dat[pos] = operation(dat[pos * 2], dat[pos * 2 + 1]);\n }\n }\n\n X query(int a, int b) {\n X L = def, R = def;\n a += n - 1, b += n - 1;\n while(a < b) {\n if(a & 1) L = operation(L, dat[a++]);\n if(b & 1) R = operation(dat[--b], R);\n a >>= 1, b >>= 1;\n } \n return operation(L, R);\n }\n\n ll get(int u, int v) {//uからvへのパス上の頂点についてやる\n int w = num[LCA.get(u, v)];//lcaで左右に分ける\n u = num[u];\n v = num[v];\n X L = def;\n while(u != w) {\n int hed = max<int>(head[u], w+1);\n L = operation(query(hed, u+1), L); \n if(hed != w) u = par[hed];\n else break;\n } \n L = operation(query(w, w+1), L);\n X R = def;\n while(v != w) {\n int hed = max<int>(head[v], w+1);\n R = operation(query(hed, v+1), R); \n if(hed != w) v = par[hed];\n else break;\n }\n R = operation(query(w, w+1), R);\n //R = operation(query(1, size+1, w, w+1, 1), R); これをしてないので、RはまだLCAに辿り着いてない。\n return L.s + R.s;//交換則を要する時はこの行を変更する必要があるかもしれない : 無いと思うが\n }\n\n\n int parent(int a) {\n return numrev[par[num[a]]];\n }\n};\n\n\n\nvoid solve() {\n ll N;\n cin >> N >> K;\n vvl G(N+1);\n map<P, ll> w;\n rep(i,1,N-1) {\n ll a, b;\n cin >> a >> b; a++, b++;\n G[a].push_back(b);\n G[b].push_back(a);\n ll c;\n cin >> c;\n w[P(a, b)] = c;\n }\n\n \n \n LCA.build(N, G);\n HL<XX> hld(N, G);\n\n for(auto [p, c] : w) {\n auto [a, b] = p;\n if(hld.parent(a) == b) swap(a, b);\n hld.change(b, c, 0);\n }\n ll Q;\n cin >> Q;\n rep(qi, 1, Q) {\n string type;\n cin >> type;\n if(type == \"add\") {\n ll x, d;\n cin >> x >> d;\n x++;\n hld.change(x, d, 1);\n }\n else {\n ll s, t;\n cin >> s >> t; s++, t++;\n cout << hld.get(s, t) << endl;\n }\n }\n \n\n \n\n}\n//無断で0を平方数にカウントする人もいる\n//”部分文字列”と”連続部分文字列”は違うので確認すること\n//一般のグラフと、有向辺かつその貼り方に制約がある(多くの場合:番号がで解放に伸びる)はだいぶ違うので確認すること\n//座標を2で割った時の”切り捨て側(左側)”を求めるには 誤:(x / 2) マイナスの時!!! 正:floor<ll>(x, 2);\n//stringでの数字の下から1桁目は 正:S.at(N-1) 誤:S.at(0)\n//if(S.at(i) == 1) ← charなのに1...?\n// modは取りましたか...?(´・ω・`)\n//sortの比較関数は、 a == b ならば falseを返す必要がある(そうで無いとRE(発生しない場合もある))\n\n\n\nint main() {\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(15);\n ll T = 1;\n //cin >> T;\n rep(i, 1, T) {\n solve();\n }\n return 0;\n}\n/*\n3 100\n0 1 1\n1 2 1\n2\nsend 0 2\nsend 2 0\n\n*/", "accuracy": 1, "time_ms": 250, "memory_kb": 47848, "score_of_the_acc": -0.6754, "final_rank": 15 }, { "submission_id": "aoj_0367_8412076", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass fenwicktree {\nprivate:\n\tint n;\n\tvector<long long> cur, val;\n\tlong long sum(int r) const {\n\t\tlong long ans = 0;\n\t\tfor (int i = r; i >= 1; i -= i & (-i)) {\n\t\t\tans += val[i];\n\t\t}\n\t\treturn ans;\n\t}\npublic:\n\tfenwicktree() : n(0), cur(vector<long long>()), val(vector<long long>()) {}\n\tfenwicktree(int n_) : n(n_), cur(vector<long long>(n_)), val(vector<long long>(n_ + 1)) {}\n\tvoid update(int pos, long long x) {\n\t\tx -= cur[pos];\n\t\tfor (int i = pos + 1; i <= n; i += i & (-i)) {\n\t\t\tval[i] += x;\n\t\t}\n\t\tcur[pos] += x;\n\t}\n\tlong long sum(int l, int r) const {\n\t\treturn sum(r) - sum(l);\n\t}\n};\n\nstruct edge {\n\tint to; long long cost;\n};\n\nint main() {\n\t// step #1. input of tree\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint N; long long K;\n\tcin >> N >> K;\n\tvector<vector<edge> > G(N);\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tint a, b, c;\n\t\tcin >> a >> b >> c;\n\t\tG[a].push_back(edge{b, c});\n\t\tG[b].push_back(edge{a, c});\n\t}\n\n\t// step #2. ordering\n\tvector<int> subsize(N);\n\tvector<edge> par(N, edge{-1, 0LL});\n\tvector<vector<int> > child(N);\n\tauto ordering = [&](auto& self, int pos) -> void {\n\t\tfor (edge e : G[pos]) {\n\t\t\tif (e.to != par[pos].to) {\n\t\t\t\tchild[pos].push_back(e.to);\n\t\t\t\tpar[e.to] = edge{pos, e.cost};\n\t\t\t}\n\t\t}\n\t\tsubsize[pos] = 1;\n\t\tfor (int& v : child[pos]) {\n\t\t\tself(self, v);\n\t\t\tsubsize[pos] += subsize[v];\n\t\t\tif (subsize[v] > subsize[child[pos][0]]) {\n\t\t\t\tswap(v, child[pos][0]);\n\t\t\t}\n\t\t}\n\t};\n\tordering(ordering, 0);\n\n\t// step #3. build tree\n\tint counter = 0;\n\tvector<int> ord(N);\n\tvector<int> head(N);\n\tauto build_tree = [&](auto& self, int pos) -> void {\n\t\tord[pos] = counter++;\n\t\tfor (int v : child[pos]) {\n\t\t\thead[v] = (v == child[pos][0] ? head[pos] : v);\n\t\t\tself(self, v);\n\t\t}\n\t};\n\tbuild_tree(build_tree, 0);\n\tvector<int> upper(N, -1);\n\tvector<int> lower(N, -1);\n\tfor (int i = 0; i < N; i++) {\n\t\tif (!child[i].empty()) {\n\t\t\tupper[child[i][0]] = i;\n\t\t\tlower[i] = child[i][0];\n\t\t}\n\t}\n\n\t// step #4. heavy-light decomposition\n\tvector<long long> cv(N), ce(N);\n\tfenwicktree bit(N);\n\tauto f = [&](long long x) -> long long {\n\t\treturn x % K != 0 ? x : 0;\n\t};\n\tauto query = [&](int va, int vb) -> long long {\n\t\tlong long ans = 0;\n\t\twhile (head[va] != head[vb]) {\n\t\t\tif (ord[va] > ord[vb]) {\n\t\t\t\tswap(va, vb);\n\t\t\t}\n\t\t\tans += bit.sum(ord[head[vb]] + 1, ord[vb] + 1);\n\t\t\tvb = head[vb];\n\t\t\tans += f(cv[vb] + cv[par[vb].to] + par[vb].cost);\n\t\t\tvb = par[vb].to;\n\t\t}\n\t\tif (ord[va] > ord[vb]) {\n\t\t\tswap(va, vb);\n\t\t}\n\t\tans += bit.sum(ord[va] + 1, ord[vb] + 1);\n\t\treturn ans;\n\t};\n\t\n\t// step #5. initialization\n\tauto change = [&](int pos) -> void {\n\t\tif (upper[pos] != -1) {\n\t\t\tbit.update(ord[pos], f(cv[pos] + cv[upper[pos]] + par[pos].cost));\n\t\t}\n\t\tif (lower[pos] != -1) {\n\t\t\tbit.update(ord[lower[pos]], f(cv[pos] + cv[lower[pos]] + par[lower[pos]].cost));\n\t\t}\n\t};\n\tfor (int i = 0; i < N; i++) {\n\t\tchange(i);\n\t}\n\n\t// step #6. process query\n\tint Q;\n\tcin >> Q;\n\tfor (int id = 1; id <= Q; id++) {\n\t\tstring s; int x, y;\n\t\tcin >> s >> x >> y;\n\t\tif (s == \"send\") {\n\t\t\tlong long ans = query(x, y);\n\t\t\tcout << ans << '\\n';\n\t\t}\n\t\tif (s == \"add\") {\n\t\t\tcv[x] += y;\n\t\t\tchange(x);\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 32888, "score_of_the_acc": -0.1167, "final_rank": 2 }, { "submission_id": "aoj_0367_8254883", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct monoid{\n bool e;\n long long L, R, S;\n monoid(): e(true){\n }\n monoid(long long x): e(false), L(x), R(x), S(0){\n }\n};\nmonoid f(monoid A, monoid B, int K){\n if (A.e){\n return B;\n }\n if (B.e){\n return A;\n }\n monoid ans;\n ans.e = false;\n ans.L = A.L;\n ans.R = B.R;\n ans.S = A.S + B.S;\n if ((A.R + B.L) % K != 0){\n ans.S += A.R + B.L;\n }\n return ans;\n};\nstruct segment_tree{\n int N;\n array<vector<monoid>, 2> ST;\n int K;\n segment_tree(){\n }\n segment_tree(vector<long long> &A, int K): K(K){\n int N2 = A.size();\n N = 1;\n while (N < N2){\n N *= 2;\n }\n ST[0] = vector<monoid>(N * 2 - 1);\n ST[1] = vector<monoid>(N * 2 - 1);\n for (int i = 0; i < N2; i++){\n ST[0][N - 1 + i] = monoid(A[i]);\n ST[1][N - 1 + i] = monoid(A[i]);\n }\n for (int i = N - 2; i >= 0; i--){\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n void update(int i, int x){\n i += N - 1;\n ST[0][i].L += x;\n ST[0][i].R += x;\n ST[1][i].L += x;\n ST[1][i].R += x;\n while (i > 0){\n i = (i - 1) / 2;\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n monoid range_fold(int L, int R, int d, int i, int l, int r){\n if (r <= L || R <= l){\n return monoid();\n } else if (L <= l && r <= R){\n return ST[d][i];\n } else {\n int m = (l + r) / 2;\n if (d == 0){\n return f(range_fold(L, R, d, i * 2 + 1, l, m), range_fold(L, R, d, i * 2 + 2, m, r), K);\n } else {\n return f(range_fold(L, R, d, i * 2 + 2, m, r), range_fold(L, R, d, i * 2 + 1, l, m), K);\n }\n }\n }\n monoid range_fold(int L, int R, int d){\n return range_fold(L, R, d, 0, 0, N);\n }\n};\nstruct heavy_light_decomposition{\n vector<int> p, sz, in, next;\n segment_tree ST;\n int K;\n heavy_light_decomposition(vector<int> &p, vector<vector<int>> &c, vector<long long> &A, int K): p(p), K(K){\n int N = p.size();\n sz = vector<int>(N, 1);\n dfs1(c);\n in = vector<int>(N);\n next = vector<int>(N);\n next[0] = 0;\n int t = 0;\n dfs2(c, t);\n vector<long long> A2(N);\n for (int i = 0; i < N; i++){\n A2[in[i]] = A[i];\n }\n ST = segment_tree(A2, K);\n }\n void dfs1(vector<vector<int>> &c, int v = 0){\n for (int &w : c[v]){\n dfs1(c, w);\n sz[v] += sz[w];\n if (sz[w] > sz[c[v][0]]){\n swap(w, c[v][0]);\n }\n }\n }\n void dfs2(vector<vector<int>> &c, int &t, int v = 0){\n in[v] = t;\n t++;\n for (int w : c[v]){\n if (w == c[v][0]){\n next[w] = next[v];\n } else {\n next[w] = w;\n }\n dfs2(c, t, w);\n }\n }\n void update(int v, int x){\n ST.update(in[v], x);\n }\n int lca(int u, int v){\n while (true){\n if (in[u] > in[v]){\n swap(u, v);\n }\n if (next[u] == next[v]){\n return u;\n }\n v = p[next[v]];\n }\n }\n monoid path_fold(int u, int v){\n int w = lca(u, v);\n monoid L;\n while (next[u] != next[w]){\n L = f(L, ST.range_fold(in[next[u]], in[u] + 1, 1), K);\n u = p[next[u]];\n }\n L = f(L, ST.range_fold(in[w], in[u] + 1, 1), K);\n monoid R;\n while (next[v] != next[w]){\n R = f(ST.range_fold(in[next[v]], in[v] + 1, 0), R, K);\n v = p[next[v]];\n }\n R = f(ST.range_fold(in[w] + 1, in[v] + 1, 0), R, K);\n return f(L, R, K);\n }\n};\nint main(){\n int N, K;\n cin >> N >> K;\n vector<vector<pair<int, int>>> E(N);\n for (int i = 0; i < N - 1; i++){\n int a, b, c;\n cin >> a >> b >> c;\n E[a].push_back(make_pair(c, b));\n E[b].push_back(make_pair(c, a));\n }\n vector<int> p(N, -1);\n vector<vector<int>> c(N);\n vector<long long> a(N);\n a[0] = 0;\n queue<int> q;\n q.push(0);\n while (!q.empty()){\n int v = q.front();\n q.pop();\n for (auto P : E[v]){\n int w = P.second;\n if (w != p[v]){\n p[w] = v;\n c[v].push_back(w);\n a[w] = P.first - a[v];\n q.push(w);\n }\n }\n }\n heavy_light_decomposition T(p, c, a, K); \n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n string S;\n cin >> S;\n if (S == \"add\"){\n int x, d;\n cin >> x >> d;\n T.update(x, d);\n }\n if (S == \"send\"){\n int s, t;\n cin >> s >> t;\n cout << T.path_fold(s, t).S << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 41704, "score_of_the_acc": -0.5513, "final_rank": 11 }, { "submission_id": "aoj_0367_8214694", "code_snippet": "#include <bits/stdc++.h>\n#define U [7 << 15] = {}\n#define G )+((c=A[a]+A[P[a]]+C[a])%k?c:0)-M(\ntypedef long long L;\nusing namespace std;\nmap<L, L> T U;\nL P U, E U, Z U, H U, C U, A U, O U, X U, B U, k, n, a, b, c;\nchar s U;\nL M(L f) { return f ? B[f] + M(f ^ f & -f) : 0; }\nL S(L a, L i) {\n for (a = M(i++ G i); i < 2e5; i += i & -i)\n B[i] += a;\n}\nL W(L f) {\n X[f] = n;\n S(f = H[f], O[f] = ++b);\n f &&W(f);\n}\nL D(L f) {\n L d;\n Z[f] = 1;\n for (map<L, L>::iterator I = T[f].begin(); I != T[f].end(); I++)\n d = I->first, !Z[d] ? P[d] = f, E[d] = E[f] + 1, C[d] = I->second, D(d),\n Z[f] += Z[d], !H[f] | Z[H[f]] < Z[d] ? H[f] = d : 0 : 0;\n}\nL K(L f) {\n a = X[f];\n n = X[b];\n return a - n ? M(O[E[a] < E[n] ? a = n, n = b, b = f, n : f] G O[a]) + K(P[a])\n : abs(M(O[f]) - M(O[b]));\n}\nmain() {\n for (cin >> n >> k; --n; T[a][b] = T[b][a] = c)\n cin >> a >> b >> c;\n for (D(b = 0); n < *Z; n++)\n !b | H[P[n]] - n &&W(n);\n for (cin >> a; cin >> s >> a >> b; S(H[a], O[a]), S(a, O[a] - 1))\n *s & 2 ? cout << K(a) << endl, 0 : A[a] += b;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 38104, "score_of_the_acc": -0.3778, "final_rank": 8 }, { "submission_id": "aoj_0367_8214691", "code_snippet": "#include <bits/stdc++.h>\n#define U [7 << 15] = {}\n#define G )+((c=A[a]+A[P[a]]+C[a])%k?c:0)-M(\ntypedef long long L;\nusing namespace std;\nmap<L, L> T U;\nL P U, E U, Z U, H U, C U, A U, O U, X U, B U, k, n, a, b, c;\nchar s U;\nL M(L f) { return f ? B[f] + M(f ^ f & -f) : 0; }\nL S(L a, L i) {\n for (a = M(i++ G i); i < 2e5; i += i & -i)\n B[i] += a;\n}\nL D(L f) {\n L d;\n Z[f] = 1;\n for (map<L, L>::iterator I = T[f].begin(); I != T[f].end(); I++)\n d = I->first, !Z[d] ? P[d] = f, E[d] = E[f] + 1, C[d] = I->second, D(d),\n Z[f] += Z[d], !H[f] | Z[H[f]] < Z[d] ? H[f] = d : 0 : 0;\n}\nL K(L f) {\n a = X[f];\n n = X[b];\n return a - n ? M(O[E[a] < E[n] ? a = n, n = b, b = f, n : f] G O[a]) + K(P[a])\n : abs(M(O[f]) - M(O[b]));\n}\nmain() {\n for (cin >> n >> k; --n; T[a][b] = T[b][a] = c)\n cin >> a >> b >> c;\n for (D(a = b = 0); n < *Z; a = H[P[++n]] - n ? n : 0)\n for (; !b | a; S(a = H[a], O[a] = ++b))\n X[a] = n;\n for (cin >> a; cin >> s >> a >> b; S(H[a], O[a]), S(a, O[a] - 1))\n *s & 2 ? cout << K(a) << endl, 0 : A[a] += b;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 38100, "score_of_the_acc": -0.3777, "final_rank": 7 }, { "submission_id": "aoj_0367_8138293", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x), end(x)\n#define Fixed fixed << setprecision(12)\n#define int int32_t\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T,vector<T>,greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A,B>;\n \ntemplate <class T> inline void bye(T x) { cout << x << '\\n'; exit(0); }\n \ninline int square(int a){ return a * a;}\ninline int updiv(int a,int b){ return (a + b - 1) / b; }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n \nstruct HeavyLightDecomposition {\npublic:\n vector<vector<int> > g;\n vector<int> sz, in, out, head, rev, par, dep;\n \n HeavyLightDecomposition(const vector<vector<int> > &G) : g(G) {\n sz.resize(g.size(), 0);\n in.resize(g.size(), 0);\n out.resize(g.size(), 0);\n head.resize(g.size(), 0);\n rev.resize(g.size(), 0);\n par.resize(g.size(), 0);\n dep.resize(g.size(), 0);\n dfs_sz(0, -1, 0);\n dfs_hld(0, -1);\n }\n \n // 頂点vからk個遡った頂点\n int la(int v, int k) {\n while (true) {\n int u = head[v];\n if (in[v] - k >= in[u]) return (rev[in[v] - k]);\n k -= in[v] - in[u] + 1;\n v = par[u];\n }\n }\n \n int lca(int u, int v) const {\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v);\n if (head[u] == head[v]) return (u);\n }\n }\n \n int dist(int u, int v) const {\n return (dep[u] + dep[v] - 2 * dep[lca(u, v)]);\n }\n \n template<typename E, typename F, typename G, typename S>\n E query(int u, int v, const E &ti, const F &f, const G &g, const S &s, bool edge = false) {\n E l = ti, r = ti;\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v), swap(l, r);\n if (head[u] == head[v]) break;\n l = g(f(in[head[v]], in[v] + 1), l);\n }\n return (s(g(f(in[u] + edge, in[v] + 1), l), r));\n }\n \n template<typename E, typename F, typename G>\n E query(int u, int v, const E &ti, const F &f, const G &g, bool edge = false) {\n return (query(u, v, ti, f, g, g, edge));\n }\n \n template<typename G>\n void update(int u, int v, const G &g, bool edge = false) {\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v);\n if (head[u] == head[v]) break;\n g(in[head[v]], in[v] + 1);\n }\n g(in[u] + edge, in[v] + 1);\n }\n \n /* {parent, child} */\n vector<pair<int, int> > compress(vector<int> &remark) {\n auto comp = [&](int a, int b) { return (in[a] < in[b]); };\n sort(begin(remark), end(remark), comp);\n remark.erase(unique(begin(remark), end(remark)), end(remark));\n int K = (int) remark.size();\n for (int k = 1; k < K; ++k) remark.emplace_back(lca(remark[k - 1], remark[k]));\n sort(begin(remark), end(remark), comp);\n remark.erase(unique(begin(remark), end(remark)), end(remark));\n vector<pair<int, int> > es;\n vector<int> st;\n for (auto &k : remark) {\n while (!st.empty() && out[st.back()] <= in[k]) st.pop_back();\n if (!st.empty()) es.emplace_back(st.back(), k);\n st.emplace_back(k);\n }\n return (es);\n }\n \nprivate:\n void dfs_sz(int cur, int p, int d) {\n dep[cur] = d;\n par[cur] = p;\n sz[cur] = 1;\n if (!g[cur].empty() && g[cur][0] == p) swap(g[cur][0], g[cur].back());\n for (auto &to : g[cur]) {\n if (to == p) continue;\n dfs_sz(to, cur, d + 1);\n sz[cur] += sz[to];\n if (sz[g[cur][0]] < sz[to]) swap(g[cur][0], to);\n }\n }\n \n void dfs_hld(int cur, int p) {\n static int times = 0;\n in[cur] = times++;\n rev[in[cur]] = cur;\n for (auto &to : g[cur]) {\n if (to == p) continue;\n head[to] = (g[cur][0] == to ? head[cur] : to);\n dfs_hld(to, cur);\n }\n out[cur] = times;\n }\n};\n \ntemplate< typename Monoid, typename F >\nstruct SegmentTree {\n int n, sz;\n vector< Monoid > seg;\n \n const F f;\n const Monoid M1;\n \n SegmentTree(int n, const F f, const Monoid &M1) : n(n), f(f), M1(M1) {\n sz = 1;\n while(sz < n) sz <<= 1;\n seg.assign(2 * sz, M1);\n }\n \n void set(int k, const Monoid &x) {\n seg[k + sz] = x;\n }\n \n void build() {\n for(int k = sz - 1; k > 0; k--) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n \n void update(int k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while(k >>= 1) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n \n Monoid query(int a, int b) {\n Monoid L = M1, R = M1;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) L = f(L, seg[a++]);\n if(b & 1) R = f(seg[--b], R);\n }\n return f(L, R);\n }\n \n Monoid operator[](const int &k) const {\n return seg[k + sz];\n }\n \n template< typename C >\n int find_subtree(int a, const C &check, Monoid &M, bool type) {\n while(a < sz) {\n Monoid nxt = type ? f(seg[2 * a + type], M) : f(M, seg[2 * a + type]);\n if(check(nxt)) a = 2 * a + type;\n else M = nxt, a = 2 * a + 1 - type;\n }\n return a - sz;\n }\n \n template< typename C >\n int find_first(int a, const C &check) {\n Monoid L = M1;\n if(a <= 0) {\n if(check(f(L, seg[1]))) return find_subtree(1, check, L, false);\n return n;\n }\n int b = sz;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) {\n Monoid nxt = f(L, seg[a]);\n if(check(nxt)) return find_subtree(a, check, L, false);\n L = nxt;\n ++a;\n }\n }\n return n;\n }\n \n template< typename C >\n int find_last(int b, const C &check) {\n Monoid R = M1;\n if(b >= sz) {\n if(check(f(seg[1], R))) return find_subtree(1, check, R, true);\n return -1;\n }\n int a = sz;\n for(b += sz; a < b; a >>= 1, b >>= 1) {\n if(b & 1) {\n Monoid nxt = f(seg[--b], R);\n if(check(nxt)) return find_subtree(b, check, R, true);\n R = nxt;\n }\n }\n return -1;\n }\n};\n \ntemplate< typename Monoid, typename F >\nSegmentTree< Monoid, F > get_segment_tree(int N, const F& f, const Monoid& M1) {\n return {N, f, M1};\n}\n \nsigned main(void){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int n, k;\n cin >> n >> k;\n \n vector<vector<int> > tree(n);\n vector<vector<pair<int, int> > > graph(n);\n map<pair<int, int>, int64_t> cost;\n \n for (int i = 0; i < n - 1; ++i) {\n int a, b, c;\n cin >> a >> b >> c;\n tree[a].emplace_back(b);\n tree[b].emplace_back(a);\n graph[a].emplace_back(b, c);\n graph[b].emplace_back(a, c);\n cost[minmax(a, b)] = c;\n }\n \n HeavyLightDecomposition hld(tree);\n auto seg = get_segment_tree(n, [](auto a, auto b) { return (a + b); }, 0LL);\n for (int i = 1; i < n; ++i) {\n int c = cost[minmax(hld.par[i], i)];\n if (c % k == 0) c = 0;\n seg.set(hld.in[i], c);\n }\n seg.build();\n \n int q;\n cin >> q;\n \n vector<int_fast64_t> sum(n);\n vector<int> idx(n);\n vector<tuple<string, int, int> > queries;\n unordered_set<int> us;\n int u, v, x, y, to, c;\n string com;\n for (int i = 0; i < q; ++i) {\n string com;\n cin >> com;\n if (com == \"add\") {\n int x, d;\n cin >> x >> d;\n // nodes.emplace_back(x);\n us.insert(x);\n queries.emplace_back(com, x, d);\n } else {\n int s, t;\n cin >> s >> t;\n // nodes.emplace_back(s);\n // nodes.emplace_back(t);\n us.insert(s);\n us.insert(t);\n queries.emplace_back(com, s, t);\n }\n if (i == q - 1 || us.size() >= 100) {\n vector<int> nodes;\n for (auto e: us) nodes.emplace_back(e);\n auto edges = hld.compress(nodes);\n int sz = nodes.size();\n for (int i = 0; i < sz; ++i) {\n idx[nodes[i]] = i;\n }\n vector<vector<int> > g(sz);\n for (int l = 0; l < edges.size(); ++l) {\n tie(u, v) = edges[l];\n g[idx[u]].emplace_back(idx[v]);\n g[idx[v]].emplace_back(idx[u]);\n }\n \n for (int l = 0; l < queries.size(); ++l) {\n tie(com, x, y) = queries[l];\n if (com == \"add\") {\n sum[x] += y;\n } else {\n vector<int> nv;\n makeFixPoint([&](auto rec, auto cur, auto par) -> bool {\n nv.emplace_back(nodes[cur]);\n if (cur == idx[y]) {\n return (true);\n } else {\n for (auto to: g[cur]) {\n if (par == to) continue;\n if (rec(to, cur)) return (true);\n }\n }\n nv.pop_back();\n return (false);\n })(idx[x], -1);\n \n int vs = nv.size();\n int_fast64_t res = 0;\n for (int j = 0; j < vs - 1; ++j) {\n int u = nv[j], v = nv[j + 1]; \n if (hld.in[u] > hld.in[v]) swap(u, v);\n auto f = [&](int a, int b) { return (seg.query(a, b)); };\n auto g = [](int a, int b) { return (a + b); };\n res += hld.query(u, v, 0LL, f, g, true);\n int vh = hld.la(v, 1);\n int vc = cost[minmax(v, vh)] + sum[v] + sum[vh];\n res -= seg[hld.in[v]];\n if (vc % k != 0) res += vc;\n if (vh != u) {\n int ul = hld.la(v, hld.dist(u, v) - 1);\n int uc = cost[minmax(u, ul)] + sum[u] + sum[ul];\n res -= seg[hld.in[ul]];\n if (uc % k != 0) res += uc;\n }\n }\n cout << res << '\\n';\n }\n }\n \n for (auto e : nodes) {\n if (sum[e] == 0) continue;\n for (int l = 0; l < graph[e].size(); ++l) {\n tie(to, c) = graph[e][l];\n int u = e, v = to;\n if (hld.in[u] > hld.in[v]) swap(u, v);\n if ((cost[minmax(u, v)] += sum[e]) % k == 0) c = 0;\n else c = cost[minmax(u, v)];\n seg.update(hld.in[v], c);\n }\n sum[e] = 0;\n }\n \n queries.clear();\n us.clear();\n }\n }\n \n return (0);\n}", "accuracy": 1, "time_ms": 2250, "memory_kb": 41728, "score_of_the_acc": -1.3809, "final_rank": 19 }, { "submission_id": "aoj_0367_7267334", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint K;\n\ntemplate <typename T>\nstruct BinaryIndexedTree {\n int N;\n vector<T>bit;\n BinaryIndexedTree(){}\n BinaryIndexedTree(int x) {\n N = x;\n bit.resize(x+1);\n }\n void add(int x,T y) {\n x++;\n while(x <= N) {\n bit[x] += y;\n x += x&-x;\n }\n }\n T sum(int x) {\n x++;\n T res = 0;\n while(x) {\n res += bit[x];\n x -= x&-x;\n }\n return res;\n }\n inline T sum(int l, int r) {//[l,r)\n return sum(r-1)-sum(l-1);\n }\n inline T operator[](int k) {\n return sum(k)-sum(k-1);\n }\n};\n\nstruct HLD { // 根が 0 でない時に注意\n vector<int>p,sz,in,nxt;\n vector<long long>s,tr;\n vector<vector<int>>h;\n BinaryIndexedTree<long long> bit;\n void dfs1(vector<vector<int>>&c,int v = 0) {\n sz[v] = 1;\n for(int &w:c[v]) {\n dfs1(c,w);\n sz[v] += sz[w];\n if(sz[w] > sz[c[v][0]]) {\n swap(w,c[v][0]);\n }\n }\n }\n void dfs2(vector<vector<int>>&c,int &t,int v = 0) {\n in[v] = t;\n t++;\n for(int w:c[v]) {\n if(w == c[v][0]) {\n nxt[w] = nxt[v];\n h[v].push_back(w);\n h[w].push_back(v);\n }\n else {\n nxt[w] = w;\n }\n dfs2(c,t,w);\n }\n }\n HLD(vector<long long>&A,vector<int>&p,vector<vector<int>>&c):p(p) {\n int N = A.size();\n sz.resize(N,0);\n dfs1(c);\n in.resize(N,0);\n tr.resize(N,0);\n nxt.resize(N,0);\n h.resize(N);\n s.resize(N);\n int t = 0;\n dfs2(c,t);\n vector<long long>tmp(N);\n for(int i = 0; i < N; i++) {\n tr[i] = A[i];\n if(A[i]%K == 0) A[i] = 0;\n tmp[in[i]] = A[i];\n }\n BinaryIndexedTree<long long>init(tmp.size());\n for(int i = 0; i < tmp.size(); i++) {\n init.add(i,tmp[i]);\n }\n bit = init;\n }\n int lca(int u,int v) {\n while(true) {\n if(in[u] > in[v]) {\n swap(u,v);\n }\n if(nxt[u] == nxt[v]) {\n return u;\n }\n v = p[nxt[v]];\n }\n }\n long long diff(int x,long long d) {\n long long now = bit[in[x]];\n long long nxt = tr[x]+d;\n if(nxt%K == 0) nxt = 0;\n return nxt-now;\n }\n void update(int v,long long x) {\n s[v] += x;\n for(int i:h[v]) {\n if(i == p[v]) {\n bit.add(in[v],diff(v,x));\n tr[v] += x;\n }\n else {\n bit.add(in[i],diff(i,x));\n tr[i] += x;\n }\n }\n }\n long long query(int u,int v) {\n int w = lca(u,v);\n long long ans = 0;\n while(nxt[u] != nxt[w]) {\n ans += bit.sum(in[nxt[u]],in[u]+1);\n ans += diff(nxt[u],s[p[nxt[u]]]+s[nxt[u]]);\n u = p[nxt[u]];\n }\n ans += bit.sum(in[w]+1,in[u]+1);\n while(nxt[v] != nxt[w]) {\n ans += bit.sum(in[nxt[v]],in[v]+1);\n ans += diff(nxt[v],s[p[nxt[v]]]+s[nxt[v]]);\n v = p[nxt[v]];\n }\n ans += bit.sum(in[w]+1,in[v]+1);\n return ans;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int N;\n cin >> N >> K;\n vector<vector<pair<int,int>>>ki(N);\n for(int i = 0; i < N-1; i++) {\n int a,b,c;\n cin >> a >> b >> c;\n ki[a].push_back({b,c});\n ki[b].push_back({a,c});\n }\n vector<long long>a(N);\n vector<int>p(N,-1);\n vector<vector<int>>c(N);\n queue<int>que;\n que.push(0);\n while (!que.empty()) {\n int x = que.front();\n que.pop();\n for(auto i:ki[x]) {\n if(i.first != 0 && p[i.first] == -1) {\n a[i.first] = i.second;\n p[i.first] = x;\n c[x].push_back(i.first);\n que.push(i.first);\n }\n }\n }\n HLD hld(a,p,c);\n int q;\n cin >> q;\n while(q--) {\n string s;\n cin >> s;\n if(s == \"add\") {\n int x,d;\n cin >> x >> d;\n hld.update(x,d);\n }\n else {\n int s,t;\n cin >> s >> t;\n cout << hld.query(s,t) << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 33952, "score_of_the_acc": -0.1597, "final_rank": 3 }, { "submission_id": "aoj_0367_7252428", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nstruct monoid{\n bool e;\n ll L,R,S;\n monoid() : e(true) {}\n monoid(ll x) : e(false), L(x), R(x), S(0) {}\n};\nstruct segtree{\n int K;\n using S = monoid;\n S op(S a,S b) {\n if(a.e) return b;\n if(b.e) return a;\n S res;\n res.e = false;\n res.L = a.L; res.R = b.R;\n res.S = a.S + b.S;\n if((a.R + b.L) % K){\n res.S += (a.R + b.L);\n }\n return res;\n }\n S e() {return monoid();}\n int n;\n array<vector<S>, 2> tree;\n segtree() {}\n segtree(int nn){\n int lg = 0;\n while((1LL<<lg) < nn) lg++;\n n = 1<<lg;\n tree[0] = vector<S>(n*2,e());\n tree[1] = vector<S>(n*2,e());\n }\n void init(vector<ll> a){\n for (int i = 0; i < a.size(); ++i) {\n tree[0][n+i] = monoid(a[i]);\n tree[1][n+i] = monoid(a[i]);\n }\n for (int i = n-1; i > 0; i--) {\n tree[0][i] = op(tree[0][i*2], tree[0][i*2+1]);\n tree[1][i] = op(tree[1][i*2+1], tree[1][i*2]);\n }\n\n }\n void update(int pos,int val){\n pos += n;\n for (int i = 0; i < 2; ++i) {\n tree[i][pos].L += val;\n tree[i][pos].R += val;\n }\n while(pos > 1){\n int chl = pos, chr = pos^1;\n if(chl > chr) swap(chl, chr);\n tree[0][pos/2] = op(tree[0][chl], tree[0][chr]);\n tree[1][pos/2] = op(tree[1][chr], tree[1][chl]);\n pos /= 2;\n }\n }\n S query(int l,int r,int d){\n S sml = e(), smr = e();\n l += n; r += n;\n if(d == 0){\n for(;l < r; l >>= 1, r >>= 1){\n if(l%2) sml = op(sml, tree[0][l++]);\n if(r%2) smr = op(tree[0][--r], smr);\n }\n }\n else{\n for(;l < r; l >>= 1, r >>= 1){\n if(r%2) sml = op(sml, tree[1][--r]);\n if(l%2) smr = op(tree[1][l++], smr);\n }\n }\n return op(sml,smr);\n }\n};\n\nstruct HLD{\n vector<int> p, sz, in, next;\n vector<vector<int>> c;\n segtree seg;\n HLD(vector<int> &p, vector<vector<int>> &c, vector<ll> a, int K) : p(p), c(c){\n int n = p.size();\n sz = vector<int>(n,1);\n dfs1(0);\n in = vector<int>(n);\n next = vector<int>(n);\n next[0] = 0;\n int id = 0;\n dfs2(id, 0);\n seg = segtree(n);\n seg.K = K;\n vector<ll> na(n);\n for (int i = 0; i < n; ++i) {\n na[in[i]] = a[i];\n }\n seg.init(na);\n }\n void dfs1(int s){\n for(int &t:c[s]){\n dfs1(t);\n sz[s] += sz[t];\n if(sz[t] > sz[c[s][0]]){\n swap(t, c[s][0]);\n }\n }\n }\n void dfs2(int &id, int s){\n in[s] = id++;\n for(int t:c[s]){\n if(t == c[s][0]){\n next[t] = next[s];\n }\n else{\n next[t] = t;\n }\n dfs2(id, t);\n }\n }\n int lca(int s,int t){\n while(1){\n if(in[s] > in[t]){\n swap(s,t);\n }\n if(next[s] == next[t]){\n return s;\n }\n t = p[next[t]];\n }\n }\n void update(int s,int x){\n seg.update(in[s], x);\n }\n monoid path_fold(int s,int t){\n int w = lca(s,t);\n monoid L,R;\n while(next[s] != next[w]){\n L = seg.op(L, seg.query(in[next[s]], in[s]+1, 1));\n s = p[next[s]];\n }\n auto r = seg.query(in[w], in[s]+1, 1);\n L = seg.op(L, seg.query(in[w], in[s]+1, 1));\n while(next[t] != next[w]){\n R = seg.op(seg.query(in[next[t]], in[t]+1, 0), R);\n t = p[next[t]];\n }\n R = seg.op(seg.query(in[w]+1, in[t]+1, 0), R);\n return seg.op(L,R);\n }\n};\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,k; cin >> n >> k;\n vector<vector<pair<int,int>>> g(n);\n for (int i = 0; i < n - 1; ++i) {\n int a,b,c; cin >> a >> b >> c;\n g[a].push_back({b,c});\n g[b].push_back({a,c});\n }\n vector<int> p(n,-1);\n vector<vector<int>> c(n);\n vector<ll> a(n);\n a[0] = 0;\n queue<int> q;\n q.push(0);\n while(q.size()){\n int s = q.front(); q.pop();\n for(auto to:g[s]){\n int t = to.first;\n if(p[s] == t) continue;\n p[t] = s;\n c[s].push_back(t);\n a[t] = to.second - a[s];\n q.push(t);\n }\n }\n HLD T(p,c,a,k);\n auto seg = T.seg;\n int query; cin >> query;\n while(query--){\n string s; cin >> s;\n if(s == \"add\"){\n int x,d; cin >> x >> d;\n T.update(x, d);\n }\n else{\n int s,t; cin >> s >> t;\n cout << T.path_fold(s, t).S << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 61120, "score_of_the_acc": -1.027, "final_rank": 17 }, { "submission_id": "aoj_0367_5956782", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct monoid{\n bool e;\n long long L, R, S;\n monoid(): e(true){\n }\n monoid(long long x): e(false), L(x), R(x), S(0){\n }\n};\nmonoid f(monoid A, monoid B, int K){\n if (A.e){\n return B;\n }\n if (B.e){\n return A;\n }\n monoid ans;\n ans.e = false;\n ans.L = A.L;\n ans.R = B.R;\n ans.S = A.S + B.S;\n if ((A.R + B.L) % K != 0){\n ans.S += A.R + B.L;\n }\n return ans;\n};\nstruct segment_tree{\n int N;\n array<vector<monoid>, 2> ST;\n int K;\n segment_tree(){\n }\n segment_tree(vector<long long> &A, int K): K(K){\n int N2 = A.size();\n N = 1;\n while (N < N2){\n N *= 2;\n }\n ST[0] = vector<monoid>(N * 2 - 1);\n ST[1] = vector<monoid>(N * 2 - 1);\n for (int i = 0; i < N2; i++){\n ST[0][N - 1 + i] = monoid(A[i]);\n ST[1][N - 1 + i] = monoid(A[i]);\n }\n for (int i = N - 2; i >= 0; i--){\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n void update(int i, int x){\n i += N - 1;\n ST[0][i].L += x;\n ST[0][i].R += x;\n ST[1][i].L += x;\n ST[1][i].R += x;\n while (i > 0){\n i = (i - 1) / 2;\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n monoid range_fold(int L, int R, int d, int i, int l, int r){\n if (r <= L || R <= l){\n return monoid();\n } else if (L <= l && r <= R){\n return ST[d][i];\n } else {\n int m = (l + r) / 2;\n if (d == 0){\n return f(range_fold(L, R, d, i * 2 + 1, l, m), range_fold(L, R, d, i * 2 + 2, m, r), K);\n } else {\n return f(range_fold(L, R, d, i * 2 + 2, m, r), range_fold(L, R, d, i * 2 + 1, l, m), K);\n }\n }\n }\n monoid range_fold(int L, int R, int d){\n return range_fold(L, R, d, 0, 0, N);\n }\n};\nstruct heavy_light_decomposition{\n vector<int> p, sz, in, next;\n segment_tree ST;\n int K;\n heavy_light_decomposition(vector<int> &p, vector<vector<int>> &c, vector<long long> &A, int K): p(p), K(K){\n int N = p.size();\n sz = vector<int>(N, 1);\n dfs1(c);\n in = vector<int>(N);\n next = vector<int>(N);\n next[0] = 0;\n int t = 0;\n dfs2(c, t);\n vector<long long> A2(N);\n for (int i = 0; i < N; i++){\n A2[in[i]] = A[i];\n }\n ST = segment_tree(A2, K);\n }\n void dfs1(vector<vector<int>> &c, int v = 0){\n for (int &w : c[v]){\n dfs1(c, w);\n sz[v] += sz[w];\n if (sz[w] > sz[c[v][0]]){\n swap(w, c[v][0]);\n }\n }\n }\n void dfs2(vector<vector<int>> &c, int &t, int v = 0){\n in[v] = t;\n t++;\n for (int w : c[v]){\n if (w == c[v][0]){\n next[w] = next[v];\n } else {\n next[w] = w;\n }\n dfs2(c, t, w);\n }\n }\n void update(int v, int x){\n ST.update(in[v], x);\n }\n int lca(int u, int v){\n while (true){\n if (in[u] > in[v]){\n swap(u, v);\n }\n if (next[u] == next[v]){\n return u;\n }\n v = p[next[v]];\n }\n }\n monoid path_fold(int u, int v){\n int w = lca(u, v);\n monoid L;\n while (next[u] != next[w]){\n L = f(L, ST.range_fold(in[next[u]], in[u] + 1, 1), K);\n u = p[next[u]];\n }\n L = f(L, ST.range_fold(in[w], in[u] + 1, 1), K);\n monoid R;\n while (next[v] != next[w]){\n R = f(ST.range_fold(in[next[v]], in[v] + 1, 0), R, K);\n v = p[next[v]];\n }\n R = f(ST.range_fold(in[w] + 1, in[v] + 1, 0), R, K);\n return f(L, R, K);\n }\n};\nint main(){\n int N, K;\n cin >> N >> K;\n vector<vector<pair<int, int>>> E(N);\n for (int i = 0; i < N - 1; i++){\n int a, b, c;\n cin >> a >> b >> c;\n E[a].push_back(make_pair(c, b));\n E[b].push_back(make_pair(c, a));\n }\n vector<int> p(N, -1);\n vector<vector<int>> c(N);\n vector<long long> a(N);\n a[0] = 0;\n queue<int> q;\n q.push(0);\n while (!q.empty()){\n int v = q.front();\n q.pop();\n for (auto P : E[v]){\n int w = P.second;\n if (w != p[v]){\n p[w] = v;\n c[v].push_back(w);\n a[w] = P.first - a[v];\n q.push(w);\n }\n }\n }\n heavy_light_decomposition T(p, c, a, K);\t\n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n string S;\n cin >> S;\n if (S == \"add\"){\n int x, d;\n cin >> x >> d;\n T.update(x, d);\n }\n if (S == \"send\"){\n int s, t;\n cin >> s >> t;\n cout << T.path_fold(s, t).S << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 41616, "score_of_the_acc": -0.553, "final_rank": 12 }, { "submission_id": "aoj_0367_5956777", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct monoid{\n bool e;\n long long L, R, S;\n monoid(): e(true){\n }\n monoid(long long x): e(false), L(x), R(x), S(0){\n }\n};\nmonoid f(monoid A, monoid B, int K){\n if (A.e){\n return B;\n }\n if (B.e){\n return A;\n }\n monoid ans;\n ans.e = false;\n ans.L = A.L;\n ans.R = B.R;\n ans.S = A.S + B.S;\n if ((A.R + B.L) % K != 0){\n ans.S += A.R + B.L;\n }\n return ans;\n};\nstruct segment_tree{\n int N;\n array<vector<monoid>, 2> ST;\n int K;\n segment_tree(){\n }\n segment_tree(vector<long long> &A, int K): K(K){\n int N2 = A.size();\n N = 1;\n while (N < N2){\n N *= 2;\n }\n ST[0] = vector<monoid>(N * 2 - 1);\n ST[1] = vector<monoid>(N * 2 - 1);\n for (int i = 0; i < N2; i++){\n ST[0][N - 1 + i] = monoid(A[i]);\n ST[1][N - 1 + i] = monoid(A[i]);\n }\n for (int i = N - 2; i >= 0; i--){\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n void update(int i, int x){\n i += N - 1;\n ST[0][i].L += x;\n ST[0][i].R += x;\n ST[1][i].L += x;\n ST[1][i].R += x;\n while (i > 0){\n i = (i - 1) / 2;\n ST[0][i] = f(ST[0][i * 2 + 1], ST[0][i * 2 + 2], K);\n ST[1][i] = f(ST[1][i * 2 + 2], ST[1][i * 2 + 1], K);\n }\n }\n monoid range_fold(int L, int R, int d, int i, int l, int r){\n if (r <= L || R <= l){\n return monoid();\n } else if (L <= l && r <= R){\n return ST[d][i];\n } else {\n int m = (l + r) / 2;\n if (d == 0){\n return f(range_fold(L, R, d, i * 2 + 1, l, m), range_fold(L, R, d, i * 2 + 2, m, r), K);\n } else {\n return f(range_fold(L, R, d, i * 2 + 2, m, r), range_fold(L, R, d, i * 2 + 1, l, m), K);\n }\n }\n }\n monoid range_fold(int L, int R, int d){\n return range_fold(L, R, d, 0, 0, N);\n }\n};\nstruct heavy_light_decomposition{\n\tvector<int> p, sz, in, next;\n segment_tree ST;\n int K;\n heavy_light_decomposition(vector<int> &p, vector<vector<int>> &c, vector<long long> &A, int K): p(p), K(K){\n int N = p.size();\n sz = vector<int>(N, 1);\n dfs1(c);\n in = vector<int>(N);\n next = vector<int>(N);\n next[0] = 0;\n int t = 0;\n dfs2(c, t);\n vector<long long> A2(N);\n for (int i = 0; i < N; i++){\n A2[in[i]] = A[i];\n }\n ST = segment_tree(A2, K);\n }\n void dfs1(vector<vector<int>> &c, int v = 0){\n for (int &w : c[v]){\n dfs1(c, w);\n sz[v] += sz[w];\n if (sz[w] > sz[c[v][0]]){\n swap(w, c[v][0]);\n }\n }\n }\n void dfs2(vector<vector<int>> &c, int &t, int v = 0){\n in[v] = t;\n t++;\n for (int w : c[v]){\n if (w == c[v][0]){\n next[w] = next[v];\n } else {\n next[w] = w;\n }\n dfs2(c, t, w);\n }\n }\n void update(int v, int x){\n ST.update(in[v], x);\n }\n int lca(int u, int v){\n while (true){\n if (in[u] > in[v]){\n swap(u, v);\n }\n if (next[u] == next[v]){\n return u;\n }\n v = p[next[v]];\n }\n }\n monoid path_fold(int u, int v){\n int w = lca(u, v);\n monoid L;\n while (next[u] != next[w]){\n L = f(L, ST.range_fold(in[next[u]], in[u] + 1, 1), K);\n u = p[next[u]];\n }\n L = f(L, ST.range_fold(in[w], in[u] + 1, 1), K);\n monoid R;\n while (next[v] != next[w]){\n R = f(ST.range_fold(in[next[v]], in[v] + 1, 0), R, K);\n v = p[next[v]];\n }\n R = f(ST.range_fold(in[w] + 1, in[v] + 1, 0), R, K);\n return f(L, R, K);\n }\n};\nint main(){\n int N, K;\n cin >> N >> K;\n vector<vector<pair<int, int>>> E(N);\n for (int i = 0; i < N - 1; i++){\n int a, b, c;\n cin >> a >> b >> c;\n E[a].push_back(make_pair(c, b));\n E[b].push_back(make_pair(c, a));\n }\n vector<int> p(N, -1);\n vector<vector<int>> c(N);\n vector<long long> a(N);\n a[0] = 0;\n queue<int> q;\n q.push(0);\n while (!q.empty()){\n int v = q.front();\n q.pop();\n for (auto P : E[v]){\n int w = P.second;\n if (w != p[v]){\n p[w] = v;\n c[v].push_back(w);\n a[w] = P.first - a[v];\n q.push(w);\n }\n }\n }\n heavy_light_decomposition T(p, c, a, K);\t\n int Q;\n cin >> Q;\n for (int i = 0; i < Q; i++){\n string S;\n cin >> S;\n if (S == \"add\"){\n int x, d;\n cin >> x >> d;\n T.update(x, d);\n }\n if (S == \"send\"){\n int s, t;\n cin >> s >> t;\n cout << T.path_fold(s, t).S << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 41656, "score_of_the_acc": -0.5588, "final_rank": 13 }, { "submission_id": "aoj_0367_5858938", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \ntemplate< typename Monoid, typename F >\nstruct SegmentTree {\n int n, sz;\n vector< Monoid > seg;\n \n const F f;\n const Monoid M1;\n \n SegmentTree(int n, const F f, const Monoid &M1) : n(n), f(f), M1(M1) {\n sz = 1;\n while(sz < n) sz <<= 1;\n seg.assign(2 * sz, M1);\n }\n \n void set(int k, const Monoid &x) {\n seg[k + sz] = x;\n }\n \n void build() {\n for(int k = sz - 1; k > 0; k--) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n \n void update(int k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while(k >>= 1) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n \n Monoid query(int a, int b) {\n Monoid L = M1, R = M1;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) L = f(L, seg[a++]);\n if(b & 1) R = f(seg[--b], R);\n }\n return f(L, R);\n }\n \n Monoid operator[](const int &k) const {\n return seg[k + sz];\n }\n \n template< typename C >\n int find_subtree(int a, const C &check, Monoid &M, bool type) {\n while(a < sz) {\n Monoid nxt = type ? f(seg[2 * a + type], M) : f(M, seg[2 * a + type]);\n if(check(nxt)) a = 2 * a + type;\n else M = nxt, a = 2 * a + 1 - type;\n }\n return a - sz;\n }\n \n template< typename C >\n int find_first(int a, const C &check) {\n Monoid L = M1;\n if(a <= 0) {\n if(check(f(L, seg[1]))) return find_subtree(1, check, L, false);\n return n;\n }\n int b = sz;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) {\n Monoid nxt = f(L, seg[a]);\n if(check(nxt)) return find_subtree(a, check, L, false);\n L = nxt;\n ++a;\n }\n }\n return n;\n }\n \n template< typename C >\n int find_last(int b, const C &check) {\n Monoid R = M1;\n if(b >= sz) {\n if(check(f(seg[1], R))) return find_subtree(1, check, R, true);\n return -1;\n }\n int a = sz;\n for(b += sz; a < b; a >>= 1, b >>= 1) {\n if(b & 1) {\n Monoid nxt = f(seg[--b], R);\n if(check(nxt)) return find_subtree(b, check, R, true);\n R = nxt;\n }\n }\n return -1;\n }\n};\n \ntemplate< typename Monoid, typename F >\nSegmentTree< Monoid, F > get_segment_tree(int N, const F& f, const Monoid& M1) {\n return {N, f, M1};\n}\n \nstruct HeavyLightDecomposition {\npublic:\n vector<vector<int> > g;\n vector<int> sz, in, out, head, rev, par, dep;\n \n HeavyLightDecomposition(const vector<vector<int> > &G) : g(G) {\n sz.resize(g.size(), 0);\n in.resize(g.size(), 0);\n out.resize(g.size(), 0);\n head.resize(g.size(), 0);\n rev.resize(g.size(), 0);\n par.resize(g.size(), 0);\n dep.resize(g.size(), 0);\n dfs_sz(0, -1, 0);\n dfs_hld(0, -1);\n }\n \n // 頂点vからk個遡った頂点\n int la(int v, int k) {\n while (true) {\n int u = head[v];\n if (in[v] - k >= in[u]) return (rev[in[v] - k]);\n k -= in[v] - in[u] + 1;\n v = par[u];\n }\n }\n \n int lca(int u, int v) const {\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v);\n if (head[u] == head[v]) return (u);\n }\n }\n \n int dist(int u, int v) const {\n return (dep[u] + dep[v] - 2 * dep[lca(u, v)]);\n }\n \n template<typename E, typename F, typename G, typename S>\n E query(int u, int v, const E &ti, const F &f, const G &g, const S &s, bool edge = false) {\n E l = ti, r = ti;\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v), swap(l, r);\n if (head[u] == head[v]) break;\n l = g(f(in[head[v]], in[v] + 1), l);\n }\n return (s(g(f(in[u] + edge, in[v] + 1), l), r));\n }\n \n template<typename E, typename F, typename G>\n E query(int u, int v, const E &ti, const F &f, const G &g, bool edge = false) {\n return (query(u, v, ti, f, g, g, edge));\n }\n \n template<typename G>\n void update(int u, int v, const G &g, bool edge = false) {\n for (;; v = par[head[v]]) {\n if (in[u] > in[v]) swap(u, v);\n if (head[u] == head[v]) break;\n g(in[head[v]], in[v] + 1);\n }\n g(in[u] + edge, in[v] + 1);\n }\n \n /* {parent, child} */\n vector<pair<int, int> > compress(vector<int> &remark) {\n auto comp = [&](int a, int b) { return (in[a] < in[b]); };\n sort(begin(remark), end(remark), comp);\n remark.erase(unique(begin(remark), end(remark)), end(remark));\n int K = (int) remark.size();\n for (int k = 1; k < K; ++k) remark.emplace_back(lca(remark[k - 1], remark[k]));\n sort(begin(remark), end(remark), comp);\n remark.erase(unique(begin(remark), end(remark)), end(remark));\n vector<pair<int, int> > es;\n vector<int> st;\n for (auto &k : remark) {\n while (!st.empty() && out[st.back()] <= in[k]) st.pop_back();\n if (!st.empty()) es.emplace_back(st.back(), k);\n st.emplace_back(k);\n }\n return (es);\n }\n \nprivate:\n void dfs_sz(int cur, int p, int d) {\n dep[cur] = d;\n par[cur] = p;\n sz[cur] = 1;\n if (!g[cur].empty() && g[cur][0] == p) swap(g[cur][0], g[cur].back());\n for (auto &to : g[cur]) {\n if (to == p) continue;\n dfs_sz(to, cur, d + 1);\n sz[cur] += sz[to];\n if (sz[g[cur][0]] < sz[to]) swap(g[cur][0], to);\n }\n }\n \n void dfs_hld(int cur, int p) {\n static int times = 0;\n in[cur] = times++;\n rev[in[cur]] = cur;\n for (auto &to : g[cur]) {\n if (to == p) continue;\n head[to] = (g[cur][0] == to ? head[cur] : to);\n dfs_hld(to, cur);\n }\n out[cur] = times;\n }\n};\n \nstruct Data {\n long long par_cost;\n long long left_add;\n long long right_add;\n long long cost;\n};\n \n \nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int n, k;\n cin >> n >> k;\n \n vector<vector<int> > graph(n);\n vector<tuple<int, int, int> > edges(n - 1);\n map<pair<int, int>, int> def_cost;\n \n for (int i = 0; i < edges.size(); ++i) {\n int a, b, c;\n cin >> a >> b >> c;\n edges[i] = make_tuple(a, b, c);\n graph[a].emplace_back(b);\n graph[b].emplace_back(a);\n def_cost[minmax(a, b)] = c;\n }\n \n HeavyLightDecomposition hld(graph);\n auto f = [&k](Data a, Data b) {\n if (a.par_cost == -1) {\n return (Data{0, 0, b.right_add, a.cost + b.cost});\n } else if (b.par_cost == -1) {\n return (Data{a.par_cost, a.left_add, 0, a.cost + b.cost});\n }\n long long c = b.par_cost + a.right_add + b.left_add;\n return (Data{a.par_cost, a.left_add, b.right_add, a.cost + b.cost + (c % k == 0 ? 0 : c)});\n };\n auto seg = get_segment_tree(n, f, Data{-1, 0, 0, 0});\n for (int i = 0; i < n; ++i) {\n seg.set(hld.in[i], Data{def_cost[minmax(hld.la(i, 1), i)], 0, 0, 0});\n }\n \n seg.build();\n \n int q;\n cin >> q;\n \n for (int i = 0; i < q; ++i) {\n string com;\n cin >> com;\n if (com == \"add\") {\n int x, d;\n cin >> x >> d;\n auto data = seg[hld.in[x]];\n data.left_add += d;\n data.right_add += d;\n seg.update(hld.in[x], data);\n } else {\n int s, t;\n cin >> s >> t;\n \n auto query = [&](int u, int v) {\n long long sum = 0;\n while (true) {\n if (hld.in[u] > hld.in[v]) swap(u, v);\n if (hld.head[u] == hld.head[v]) break;\n int head = hld.head[v];\n int par = hld.par[head];\n auto head_data = seg[hld.in[head]];\n auto par_data = seg[hld.in[par]];\n long long cost = head_data.par_cost + head_data.left_add + par_data.right_add;\n sum += seg.query(hld.in[head], hld.in[v] + 1).cost + (cost % k == 0 ? 0 : cost);\n v = par;\n }\n return (seg.query(hld.in[u], hld.in[v] + 1).cost + sum);\n };\n \n cout << query(s, t) << '\\n';\n }\n }\n \n return (0);\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 39916, "score_of_the_acc": -0.3636, "final_rank": 6 } ]
aoj_0385_cpp
Bozosort Bozosort, as well as Bogosort, is a very inefficient sort algorithm. It is a random number-based algorithm that sorts sequence elements following the steps as below: Randomly select two elements and swap them. Verify if all the elements are sorted in increasing order. Finish if sorted, else return to 1. To analyze Bozosort, you have decided to simulate the process using several predetermined pairs of elements. You are given several commands to swap two elements. Make a program to evaluate how many times you have to run the command before the sequence is aligned in increasing order. Input The input is given in the following format. $N$ $a_1$ $a_2$ ... $a_N$ $Q$ $x_1$ $y_1$ $x_2$ $y_2$ $...$ $x_Q$ $y_Q$ The first line provides the number of sequence elements $N$ ($2 \leq N \leq 300,000$). The second line provides an array of integers $a_i$ ($1 \leq a_i \leq 10^9$) that constitutes the sequence. Each of the subsequent $Q$ lines provides a pair of integers $x_i,y_i$ ($1 \leq x_i,y_i \leq N$) that represent the $i$-th command, which swaps the two elements indicated by $x_i$ and $y_i$ ($x_i \ne y_i$). Output If neat alignment in increasing order is realized the first time after execution of multiple commands, output at what time it was. Output 0 if the initial sequence is aligned in increasing order, and -1 if exhaustive execution still failed to attain the goal. Sample Input 1 6 9 7 5 6 3 1 3 1 6 2 5 3 4 Sample Output 1 2 Sample Input 2 4 4 3 2 1 2 1 2 3 4 Sample Output 2 -1 Sample Input 3 5 1 1 1 2 2 1 1 2 Sample Input 3 0
[ { "submission_id": "aoj_0385_10874892", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nint main() {\n int N; scanf(\"%d\", &N);\n vector<int> A(N);\n rep (i, N) scanf(\"%d\", &A[i]);\n int Q; scanf(\"%d\", &Q);\n int cnt = 0;\n rep (i, N - 1) cnt += A[i] > A[i + 1];\n auto calc = [&](int i) {\n ll res = 0;\n if (i != 0 && A[i - 1] > A[i]) ++res;\n if (i != N - 1 && A[i] > A[i + 1]) ++res;\n return res;\n };\n rep (i, Q) {\n if (cnt == 0) {\n printf(\"%d\\n\", i);\n return 0;\n }\n int x, y; scanf(\"%d%d\", &x, &y);\n --x; --y;\n if (x - 1 == y) swap(x, y);\n if (x + 1 == y) {\n if (x != 0 && A[x - 1] > A[x]) --cnt;\n if (y != N - 1 && A[y] > A[y + 1]) --cnt;\n if (A[x] > A[y]) --cnt;\n swap(A[x], A[y]);\n if (x != 0 && A[x - 1] > A[x]) ++cnt;\n if (y != N - 1 && A[y] > A[y + 1]) ++cnt;\n if (A[x] > A[y]) ++cnt;\n }\n else {\n cnt -= calc(x) + calc(y);\n swap(A[x], A[y]);\n cnt += calc(x) + calc(y);\n }\n }\n if (cnt == 0) printf(\"%d\\n\", Q);\n else puts(\"-1\");\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4492, "score_of_the_acc": -0.0411, "final_rank": 1 }, { "submission_id": "aoj_0385_10874866", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int N;\n cin>>N;\n set<int> s;\n vector<int> A(N);\n for(int i=0;i<N;i++){\n cin>>A[i];\n s.insert(A[i]);\n }\n vector<int> B = A;\n sort(B.begin(),B.end());\n int c = 0;\n for(int i=0;i<N;i++) c += (A[i] == B[i]);\n if(c == N){\n cout<<0<<endl;\n return 0;\n }\n int Q;\n cin>>Q;\n for(int z=1;z<=Q;z++){\n int a,b;\n cin>>a>>b;\n a--;\n b--;\n c -= (A[a] == B[a]);\n c -= (A[b] == B[b]);\n swap(A[a],A[b]);\n c += (A[a] == B[a]);\n c += (A[b] == B[b]);\n if(c == N){\n cout<<z<<endl;\n return 0;\n }\n }\n cout<<-1<<endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 21844, "score_of_the_acc": -0.8525, "final_rank": 16 }, { "submission_id": "aoj_0385_10874598", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n;\n cin>>n;\n vector<int> a(n);\n for(int i=0;i<n;i++) cin>>a[i];\n auto sorta = a;\n sort(sorta.begin(),sorta.end());\n int cnt = 0;\n for(int i=0;i<n;i++) if(a[i] == sorta[i]) cnt++;\n if(cnt == n)\n {\n cout<<0<<endl;\n return 0;\n }\n int q;\n cin>>q;\n for(int i=1;i<=q;i++)\n {\n int x,y;\n cin>>x>>y;\n x--,y--;\n if(a[x] == sorta[x]) cnt--;\n if(a[y] == sorta[y]) cnt--;\n swap(a[x],a[y]);\n //for(auto ai : a) cout<<ai<<\" \";\n //cout<<endl;\n if(a[x] == sorta[x]) cnt++;\n if(a[y] == sorta[y]) cnt++;\n if(cnt == n)\n {\n cout<<i<<endl;\n return 0;\n }\n }\n cout<<-1<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 5476, "score_of_the_acc": -0.2391, "final_rank": 9 }, { "submission_id": "aoj_0385_10874529", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tint N;cin >> N;\n\tvector<int> A(N);\n\tmap<int, int> mns, mxs;\n\tfor (int i = 0;i < N;i++) {\n\t\tcin >> A[i];\n\t\tmns[A[i]] = N + 100;\n\t\tmxs[A[i]] = -1;\n\t}\n\tvector<int> B = A;\n\tsort(B.begin(), B.end());\n\tfor (int i = 0;i < N;i++) {\n\t\tmns[B[i]] = min(mns[B[i]], i);\n\t\tmxs[B[i]] = max(mxs[B[i]], i);\n\t}\n\tint cr = 0;\n\tfor (int i = 0;i < N;i++) if (mns[A[i]] <= i and i <= mxs[A[i]]) cr++;\n\tint Q;cin >> Q;\n\tint ret = -1;\n\tif (cr == N) ret = 0;\n\tfor (int i = 0;i < Q;i++) {\n\t\tint x, y;cin >> x >> y;\n\t\tx--;y--;\n\t\tif (mns[A[x]] <= x and x <= mxs[A[x]]) cr--;\n\t\tif (mns[A[y]] <= y and y <= mxs[A[y]]) cr--;\n\t\tswap(A[x], A[y]);\n\t\tif (mns[A[x]] <= x and x <= mxs[A[x]]) cr++;\n\t\tif (mns[A[y]] <= y and y <= mxs[A[y]]) cr++;\n\t\tif (ret == -1 and cr == N) ret = i + 1;\n\t}\n\tcout << ret << endl;\n}", "accuracy": 1, "time_ms": 750, "memory_kb": 33792, "score_of_the_acc": -2, "final_rank": 18 }, { "submission_id": "aoj_0385_10874282", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\nusing namespace std;\n\nint main(){\n int n; cin >> n;\n vector<int> A(n);\n for(int i=0;i<n;++i) cin >> A[i];\n vector<int> Ans(n);\n for(int i=0;i<n;++i) Ans[i]=A[i];\n sort(Ans.begin(),Ans.end());\n int now=0;\n for(int i=0;i<n;++i) if(A[i]==Ans[i]) now++;\n if(now==n){\n cout << 0 << endl;\n return 0;\n }\n int q; cin >> q;\n for(int i=0;i<q;++i){\n int a,b; cin >> a >> b;\n a--;b--;\n if(A[a]==Ans[a])now--;\n if(A[b]==Ans[b])now--;\n if(A[a]==Ans[b])now++;\n if(A[b]==Ans[a])now++;\n int u=A[a];\n A[a]=A[b];\n A[b]=u;\n if(now==n){\n cout << i+1 << endl;\n return 0;\n }\n }\n cout << -1 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 5472, "score_of_the_acc": -0.2389, "final_rank": 8 }, { "submission_id": "aoj_0385_10874279", "code_snippet": "#include<iostream>\n#include<string>\n#include<bitset>\n#include<vector>\n#include<deque>\n#include<queue>\n#include<algorithm>\n#include<set>\n#include<map>\n#include <unordered_map>\n#include<iomanip>\n#include<numeric>\n#include<stack>\n#include<tuple>\n#include<unordered_set>\n#define all(a) (a).begin(), (a).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define rep(i, x) for(long long i = 0; i < (x); i++)\n#define REP(i, x, limit) for (ll i = (ll)x; i <= (ll)limit; i++)\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YES cout << \"YES\" << endl\n#define NO cout << \"NO\" << endl\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing ll = long long;\nusing namespace std;\nusing Graph = vector<vector<int>>;\nint X[4] = { 1, 0, -1, 0 };//右、上、左、下\nint Y[4] = { 0, 1, 0, -1 };\n\nint main() {\n\tll N,Q;\n\tcin >> N;\n\tvector<ll>ans(N), nomal(N);\n\trep(i, N) {\n\t\tcin >> nomal[i];\n\t}\n\tans = nomal;\n\tsort(all(ans));\n\tll ok = 0;\n\trep(i, N) {\n\t\tif (nomal[i] == ans[i]) {\n\t\t\tok++;\n\t\t}\n\t}\n\tif (ok == N) {\n\t\tcout << '0' << endl;\n\t\treturn 0;\n\t}\n\tcin >> Q;\n\trep(i, Q) {\n\t\tll a, b;\n\t\tcin >> a >> b;\n\t\tif (nomal[a - 1] == ans[a - 1])ok--;\n\t\tif (nomal[b - 1] == ans[b - 1])ok--;\n\t\tswap(nomal[a - 1], nomal[b - 1]);\n\t\tif (nomal[a - 1] == ans[a - 1])ok++;\n\t\tif (nomal[b - 1] == ans[b - 1])ok++;\n\t\tif (ok == N) {\n\t\t\tcout << i + 1 << endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout << -1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 7780, "score_of_the_acc": -0.3177, "final_rank": 11 }, { "submission_id": "aoj_0385_10872223", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\ntemplate<class T> bool chmin(T &a, T b) {if(a>b) {a=b;return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a<b) {a=b;return true;} return false;}\nconstexpr int INF = 1e9;\n\nint main() {\n int N, Q; cin >> N;\n vi a(N);\n for (int i = 0; i < N; i++) cin >> a[i];\n cin >> Q;\n vi x(Q), y(Q);\n for (int i = 0; i < Q; i++) {\n cin >> x[i] >> y[i];\n x[i]--; y[i]--;\n }\n vi b = a;\n sort(b.begin(), b.end());\n int cnt = 0;\n for (int i = 0; i < N; i++) if (a[i]==b[i]) cnt++;\n if (cnt == N) {\n cout << 0 << endl;\n return 0;\n }\n for (int i = 0; i < Q; i++) {\n int k = 0;\n if (a[x[i]]==b[x[i]]) k--;\n if (a[y[i]]==b[y[i]]) k--;\n if (a[x[i]]==b[y[i]]) k++;\n if (a[y[i]]==b[x[i]]) k++;\n swap(a[x[i]], a[y[i]]);\n cnt += k;\n if (cnt == N) {\n cout << i+1 << endl;\n return 0;\n }\n }\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 7840, "score_of_the_acc": -0.3197, "final_rank": 13 }, { "submission_id": "aoj_0385_10870863", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int N;\n cin >> N;\n vector<int> A(N), sorted(N);\n rep(i, 0, N) {\n cin >> A[i];\n sorted[i] = A[i];\n }\n \n sort(all(sorted));\n \n int ok = 0;\n rep(i, 0, N) if (sorted[i] == A[i]) ++ok;\n \n if (ok == N) {\n cout << 0 << '\\n';\n return 0;\n }\n \n int Q;\n cin >> Q;\n rep(query, 0, Q) {\n int x, y;\n cin >> x >> y;\n --x, --y;\n \n if (sorted[x] == A[x]) --ok;\n if (sorted[y] == A[y]) --ok;\n \n swap(A[x], A[y]);\n \n if (sorted[x] == A[x]) ++ok;\n if (sorted[y] == A[y]) ++ok;\n \n if (ok == N) {\n cout << query + 1 << '\\n';\n return 0;\n }\n }\n cout << -1 << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5400, "score_of_the_acc": -0.0721, "final_rank": 3 }, { "submission_id": "aoj_0385_10870785", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<(ll)N;i++)\n#define all(X) X.begin(),X.end()\n\nint main(){\n ll N;cin>>N;\n vector<ll>A(N);\n rep(i,N)cin>>A[i];\n int Q;cin>>Q;\n vector<ll>B=A;\n sort(all(B));\n ll dif = 0;\n rep(i,N)if(A[i]!=B[i])dif++;\n rep(q,Q){\n if(dif==0){\n cout<<q<<endl;\n return 0;\n }\n int x,y;cin>>x>>y;x--;y--;\n if(A[x]==B[x])dif++;\n if(A[y]==B[y])dif++;\n if(A[x]==B[y])dif--;\n if(A[y]==B[x])dif--;\n swap(A[x],A[y]);\n }\n if(dif==0)cout<<Q<<endl;\n else cout<<-1<<endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 7816, "score_of_the_acc": -0.3189, "final_rank": 12 }, { "submission_id": "aoj_0385_10864936", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//vector<ll> saiki(ll bit,ll n){\n//\tvector<ll> s(n);\n//\tfor(ll i=0;i<n;i++){\n//\t\tif(bit&(1<<i)){\n//\t\t\ts[i]=1;\n//\t\t}else s[i]=0;\n//\t}\n//\treturn s;\n//}\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll n;\n\tcin>>n;\n\tvector<ll> a(n);\n\tvector<ll> b(n);\n\n\trep(i,n){\n\t\tcin>>a[i];\n\t\tb[i]=a[i];\n\t}\n\tll q;\n\tcin>>q;\n\tvector<Pll> V(q);\n\trep(i,q){\n\t\tll x,y;\n\t\tcin>>x>>y;\n\t\tV[i]={x,y};\n\t}\n//ソート\n\tsort(b.begin(),b.end());\n\tvector<ll> ans(n,0);\n\tll v=n;\n\trep(i,n){\n\t\tif(a[i]==b[i]){\n\t\t\tans[i]=1;\n\t\t\tv--;\n\t\t}\n\t}\n\tif(v==0){\n\t\tcout<<0<<endl;\n\t\treturn 0;\n\t}\n//判定\n\trep(i,q){\n\t\tll x=V[i].first,y=V[i].second;\n\t\tswap(a[x-1],a[y-1]);\n\t\tif(a[x-1]==b[x-1]){\n\t\t\tv-=1-ans[x-1];\n\t\t\tans[x-1]=1;\n\t\t}else{\n\t\t\tv+=ans[x-1];\n\t\t\tans[x-1]=0;\n\t\t}\n\t\tif(a[y-1]==b[y-1]){\n\t\t\tv-=1-ans[y-1];\n\t\t\tans[y-1]=1;\n\t\t}else{\n\t\t\tv+=ans[y-1];\n\t\t\tans[y-1]=0;\n\t\t}\n\t\tif(v==0){\n\t\t\tcout<<i+1<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<-1<<endl;\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 14840, "score_of_the_acc": -0.3943, "final_rank": 14 }, { "submission_id": "aoj_0385_10864932", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//vector<ll> saiki(ll bit,ll n){\n//\tvector<ll> s(n);\n//\tfor(ll i=0;i<n;i++){\n//\t\tif(bit&(1<<i)){\n//\t\t\ts[i]=1;\n//\t\t}else s[i]=0;\n//\t}\n//\treturn s;\n//}\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll n;\n\tcin>>n;\n\tvector<ll> a(n);\n\tvector<ll> b(n);\n\n\trep(i,n){\n\t\tcin>>a[i];\n\t\tb[i]=a[i];\n\t}\n\tll q;\n\tcin>>q;\n\tvector<Pll> V(q);\n\trep(i,q){\n\t\tll x,y;\n\t\tcin>>x>>y;\n\t\tV[i]={x,y};\n\t}\n//ソート\n\tsort(b.begin(),b.end());\n\tvector<ll> ans(n,0);\n\tll v=n;\n\trep(i,n){\n\t\tif(a[i]==b[i]){\n\t\t\tans[i]=1;\n\t\t\tv--;\n\t\t}\n\t}\n\tif(v==0){\n\t\tcout<<0<<endl;\n\t\treturn 0;\n\t}\n//判定\n\trep(i,q){\n\t\tll x=V[i].first,y=V[i].second;\n\t\tll B=max(a[x-1],a[y-1]),S=min(a[x-1],a[y-1]);\n\t\ta[min(x-1,y-1)]=S;\n\t\ta[max(x-1,y-1)]=B;\n\t\tif(a[x-1]==b[x-1]){\n\t\t\tv-=1-ans[x-1];\n\t\t\tans[x-1]=1;\n\t\t}else{\n\t\t\tv+=ans[x-1];\n\t\t\tans[x-1]=0;\n\t\t}\n\t\tif(a[y-1]==b[y-1]){\n\t\t\tv-=1-ans[y-1];\n\t\t\tans[y-1]=1;\n\t\t}else{\n\t\t\tv+=ans[y-1];\n\t\t\tans[y-1]=0;\n\t\t}\n\t\tif(v==0){\n\t\t\tcout<<i+1<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<-1<<endl;\n\n\treturn 0;\n\n}", "accuracy": 0.34615384615384615, "time_ms": 40, "memory_kb": 14612, "score_of_the_acc": -0.3728, "final_rank": 20 }, { "submission_id": "aoj_0385_10864930", "code_snippet": "#include<bits/stdc++.h>\n//#include<atcoder/all>\n\nusing namespace std;\n//using namespace atcoder;\n#define rep(i,n) for(ll i=0; i<n; i++)\n#define rrep(i,n) for(ll i=n-1; i>=0; i--)\n#define print(a) cout<<a<<endl\ntypedef long long ll;\n#define yn(flg) if(flg){cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}\n#define YN(flg) if(flg){cout<<\"YES\"<<endl;}else{cout<<\"NO\"<<endl;}\n#define so(a) sort(a.begin(),a.end())\n#define mp make_pair\n#define vi vector<int>\n#define vl vector<ll>\n#define vs vector<string>\n#define pb push_back\n#define a2i(a,s) (ll)(a-s)\n#define i2a(s,a) (char)(s+a)\n#define ssize(a) a.size()\ntypedef pair<int, int> Pii;\ntypedef pair<int, ll> Pil;\ntypedef pair<pair<ll,ll>,ll> P3;\ntypedef pair<pair<ll,ll>,pair<ll,ll>> P4;\n\ntypedef pair<ll, ll> Pll;\ntypedef pair<ll,Pll> Plll;\ntypedef pair<Pii, int> Piii;\nconst ll INF = 1000000000000000000;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\n//vector<ll> saiki(ll bit,ll n){\n//\tvector<ll> s(n);\n//\tfor(ll i=0;i<n;i++){\n//\t\tif(bit&(1<<i)){\n//\t\t\ts[i]=1;\n//\t\t}else s[i]=0;\n//\t}\n//\treturn s;\n//}\nint main(){\n//入力\n\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n\tll n;\n\tcin>>n;\n\tvector<ll> a(n);\n\tvector<ll> b(n);\n\n\trep(i,n){\n\t\tcin>>a[i];\n\t\tb[i]=a[i];\n\t}\n\tll q;\n\tcin>>q;\n\n//ソート\n\tsort(b.begin(),b.end());\n\tvector<ll> ans(n);\n\tll v=n;\n\trep(i,n){\n\t\tif(a[i]==b[i]){\n\t\t\tans[i]=1;\n\t\t\tv--;\n\t\t}\n\t}\n\tif(v==0){\n\t\tcout<<0<<endl;\n\t\treturn 0;\n\t}\n//判定\n\trep(i,q){\n\t\tll x,y;\n\t\tcin>>x>>y;\n\t\tll B=max(a[x-1],a[y-1]),S=min(a[x-1],a[y-1]);\n\t\ta[min(x-1,y-1)]=S;\n\t\ta[max(x-1,y-1)]=B;\n\t\tif(a[x-1]==b[x-1]){\n\t\t\tv-=1-ans[x-1];\n\t\t\tans[x-1]=1;\n\t\t}else{\n\t\t\tv+=ans[x-1];\n\t\t\tans[x-1]=0;\n\t\t}\n\t\tif(a[y-1]==b[y-1]){\n\t\t\tv-=1-ans[y-1];\n\t\t\tans[y-1]=1;\n\t\t}else{\n\t\t\tv+=ans[y-1];\n\t\t\tans[y-1]=0;\n\t\t}\n\t\tif(v==0){\n\t\t\tcout<<i+1<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<-1<<endl;\n\n\treturn 0;\n\n}", "accuracy": 0.34615384615384615, "time_ms": 20, "memory_kb": 9992, "score_of_the_acc": -0.1877, "final_rank": 19 }, { "submission_id": "aoj_0385_10849817", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define all(T) T.begin(), T.end()\nusing ll = long long;\nusing P = pair<int, int>;\nconst int di[] = {-1, 0, 1, 0};\nconst int dj[] = {0, -1, 0, 1};\n\nint main() {\n // bozo sort\n ll n;\n cin >> n;\n vector<ll> a(n);\n rep(i, n) cin >> a[i];\n ll q;\n cin >> q;\n vector<ll> b(n);\n rep(i, n) b[i] = a[i];\n sort(all(b));\n\n ll now = 0;\n rep(i, n) {\n if (b[i] != a[i]) now++;\n }\n if (now == 0) {\n cout << 0 << endl;\n return 0;\n }\n rep(qi, q) {\n ll x, y;\n cin >> x >> y;\n x--;\n y--;\n\n ll old = 0, next = 0;\n if (b[x] == a[x]) old++;\n if (b[y] == a[y]) old++;\n swap(a[x], a[y]);\n if (b[x] == a[x]) next++;\n if (b[y] == a[y]) next++;\n ll diff = next - old; // あたらしくそろった数\n now -= diff;\n if (now == 0) {\n cout << qi + 1 << endl;\n return 0;\n }\n }\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 8052, "score_of_the_acc": -0.2722, "final_rank": 10 }, { "submission_id": "aoj_0385_10848452", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n//#pragma GCC optimize (\"-O3\") \n#ifdef YANG33\n#include \"mydebug.hpp\"\n#else\n#define DD(x) \n#endif\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- __MAKE_TIME__ Problem: __PROBLEM__ / Link: __CONTEST_URL__ ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\n\n\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N; cin >> N;\n\tVL a(N);\n\tFOR(i, 0, N) {\n\t\tcin >> a[i];\n\t}\n\tVL b(a);\n\tSORT(b);\n\tint Q; cin >> Q;\n\tVL x(Q), y(Q);\n\tFOR(i, 0, Q) {\n\t\tcin >> x[i] >> y[i];\n\t\tx[i]--, y[i]--;\n\t}\n\t// 完成形は定まる\n\tVL oks(N, 0);\n\tFOR(i, 0, N) {\n\t\toks[i] = (a[i] == b[i]);\n\t}\n\tLL oksum = accumulate(ALL(oks), 0LL);\n\tif (oksum == N) {\n\t\tcout << 0 << endl; return 0;\n\t}\n\n\tFOR(i, 0, Q) {\n\t\toksum -= oks[x[i]];\n\t\toksum -= oks[y[i]];\n\n\t\tswap(a[x[i]], a[y[i]]);\n\t\toks[x[i]] = (a[x[i]] == b[x[i]]);\n\t\toks[y[i]] = (a[y[i]] == b[y[i]]);\n\n\t\toksum += oks[x[i]];\n\t\toksum += oks[y[i]];\n\n\t\tif (oksum == N) {\n\t\t\tcout << i + 1 << endl; return 0;\n\t\t}\n\t}\n\n\t//\n\tcout << -1 << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 14896, "score_of_the_acc": -0.3962, "final_rank": 15 }, { "submission_id": "aoj_0385_10844467", "code_snippet": "// 基本\n#include <bits/stdc++.h>\nusing namespace std;\n// 型名の省略\nusing ll = long long;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n// 定数\nconstexpr long long MOD = 1000000007LL;\ntemplate <class T>\nconstexpr T INF = 0;\ntemplate <>\nconstexpr int INF<int> = 1001001001;\ntemplate <>\nconstexpr long long INF<long long> = 1LL << 61;\ntemplate <>\nconstexpr double INF<double> = INF<long long>;\ntemplate <>\nconstexpr long double INF<long double> = INF<long long>;\n// 便利関数\n// 入出力処理\ntemplate <class... T>\nvoid input(T &...a)\n{\n (cin >> ... >> a);\n}\nvoid print()\n{\n cout << '\\n';\n}\ntemplate <class T, class... Ts>\nvoid print(const T &a, const Ts &...b)\n{\n cout << a;\n (cout << ... << (cout << ' ', b));\n cout << '\\n';\n}\n// 繰り返し処理\n#define overload4(a, b, c, d, e, ...) e\n#define rep1(a) for (int i = 0; i < a; i++)\n#define rep2(i, a) for (int i = 0; i < a; i++)\n#define rep3(i, a, b) for (int i = a; i < b; i++)\n#define rep4(i, a, b, c) for (int i = a; i < b; i += c)\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n// 配列処理\ntemplate <class T>\nbool operator==(const vector<T> &a, const vector<T> &b)\n{\n return (a.size() == b.size()) && equal(a.cbegin(), a.cend(), b.cbegin());\n}\ntemplate <class T>\nbool operator!=(const vector<T> &a, const vector<T> &b)\n{\n return !(a == b);\n}\n// 最小・最大処理\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n if (a < b)\n {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <class T>\ninline bool chmin(T &a, T b)\n{\n if (a > b)\n {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <class... Args>\ninline auto all_max(Args... args)\n{\n return max(initializer_list<common_type_t<Args...>>{args...});\n}\ntemplate <class... Args>\ninline auto all_min(Args... args)\n{\n return min(initializer_list<common_type_t<Args...>>{args...});\n}\n// 追加ライブラリ\n\n/// ここからコードを書く\n\nint main()\n{\n cin.tie(0);\n int n;\n input(n);\n vc<int> a(n), a_sorted(n);\n rep(i, n)\n {\n input(a[i]);\n }\n a_sorted = a;\n sort(a_sorted.begin(), a_sorted.end());\n int cur = 0;\n rep(i, n)\n {\n if (a[i] == a_sorted[i])\n {\n cur++;\n }\n }\n if (cur == n)\n {\n print(0);\n return 0;\n }\n int q;\n input(q);\n rep(iq, q)\n {\n int x, y;\n input(x, y);\n x--;\n y--;\n int xi = (a[x] == a_sorted[x] ? 1 : 0);\n int yi = (a[y] == a_sorted[y] ? 1 : 0);\n int temp = a[x];\n a[x] = a[y];\n a[y] = temp;\n int xj = (a[x] == a_sorted[x] ? 1 : 0);\n int yj = (a[y] == a_sorted[y] ? 1 : 0);\n if (xi == 1 && xj == 0)\n {\n cur--;\n }\n else if (xi == 0 && xj == 1)\n {\n cur++;\n }\n if (yi == 1 && yj == 0)\n {\n cur--;\n }\n else if (yi == 0 && yj == 1)\n {\n cur++;\n }\n if (cur == n)\n {\n print(iq + 1);\n return 0;\n }\n }\n print(-1);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 5632, "score_of_the_acc": -0.1759, "final_rank": 6 }, { "submission_id": "aoj_0385_10844327", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst int INF = 1 << 30;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n\n int n;\n cin >> n;\n vector<int> a(n), b(n);\n for (int i = 0; i < n; i++) cin >> a[i];\n b = a;\n sort(b.begin(), b.end());\n int q;\n cin >> q;\n\n int ans = 0, ok = 0;\n for (int i = 0; i < n; i++) {\n if (a[i] == b[i]) ok++;\n }\n if (ok == n) {\n cout << ans << endl;\n return 0;\n }\n // ok = 2\n while (q--) {\n ans++;\n int x, y;\n cin >> x >> y;\n x--, y--;\n\n if (a[x] == b[x]) ok--;\n if (a[y] == b[y]) ok--;\n swap(a[x], a[y]);\n if (a[x] == b[x]) ok++;\n if (a[y] == b[y]) ok++;\n if (ok == n) {\n cout << ans << endl;\n return 0;\n }\n }\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5760, "score_of_the_acc": -0.057, "final_rank": 2 }, { "submission_id": "aoj_0385_10844035", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\nusing namespace atcoder;\n#endif\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n\nconst int INF = 1e9 + 1;\nconst ll INFL = 1e18 + 1;\nconst double PI = 3.141592653589793238;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\nconst vector<int> dx = {-1, 0, 1, 0};\nconst vector<int> dy = {0, 1, 0, -1};\nconst vector<int> dx8 = {-1, 0, 1, 0, -1, -1, 1, 1};\nconst vector<int> dy8 = {0, 1, 0, -1, -1, 1, 1, -1};\nbool inRange(int i, int N) { return (0 <= i && i < N); }\nbool inField(int i, int j, int H, int W) { return (0 <= i && i < H && 0 <= j && j < W); }\nint encode(int i, int j, int W) { return (i * W + j); }\n\n#define euclid(x1, y1, x2, y2) (((x1) - (x2)) * ((x1) - (x2)) + ((y1) - (y2)) * ((y1) - (y2)))\n#define manhattan(x1, y1, x2, y2) (abs((x1) - (x2)) + abs((y1) - (y2)))\n\nint randInt(int a, int b) { return a + rand() % (b - a + 1); }\ndouble randDouble() { return 1.0 * rand() / RAND_MAX; }\n\nint op(int a, int b) { return max(a, b); }\nint e() { return -INF; }\n\n#define rep(i, n) for(int i = 0;i < (int)(n); i++)\n#define rep1(i, n) for(int i = 1; i <= (int)(n); i++)\n#define chmin(a, b) a = min(a,b)\n#define chmax(a, b) a = max(a,b)\n#define sz(a) ((int) a.size())\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN(a) cout << ((a) ? \"Yes\" : \"No\") << endl\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n\n int N;\n cin >> N;\n\n vector<int> A(N);\n for (int i = 0; i < N; i++) cin >> A[i];\n\n int Q;\n cin >> Q;\n\n vector<int> X(Q), Y(Q);\n for (int i = 0; i < Q; i++) {\n cin >> X[i] >> Y[i];\n X[i]--; Y[i]--;\n }\n\n // 前処理\n vector<int> B = A;\n sort(B.begin(), B.end());\n\n // same := 「A[i] = B[i]」となるiの個数\n int same = 0;\n for (int i = 0; i < N; i++) {\n if (A[i] == B[i]) same++;\n }\n\n // クエリ処理\n if (same == N) {\n cout << 0 << endl;\n return 0;\n }\n\n for (int i = 0; i < Q; i++) {\n if (A[X[i]] == B[X[i]]) same--;\n if (A[Y[i]] == B[Y[i]]) same--;\n if (A[Y[i]] == B[X[i]]) same++;\n if (A[X[i]] == B[Y[i]]) same++;\n swap(A[X[i]], A[Y[i]]);\n\n if (same == N) {\n cout << i + 1 << endl;\n return 0;\n }\n }\n\n cout << -1 << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7804, "score_of_the_acc": -0.1541, "final_rank": 4 }, { "submission_id": "aoj_0385_10844034", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include <atcoder/all>\nusing namespace atcoder;\n\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\nusing ld = long double;\nusing bl = bool;\nusing mint = modint998244353;\n// using mint = modint1000000007;\n// using mint = modint;\n// mint::set_mod(m);\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>;\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>;\n//-----------------------------------\n\n//-------------2.配列系--------------\n\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v)\n{\n rep(j, size(v)) i >> v[j];\n return i;\n}\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n//--------3.コード短縮化とか---------\nconst double PI = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++)\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--)\n\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n\n#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end());\n#define vc_rotate(v) rotate(v.begin(), v.begin() + 1, v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(), v.end())\n\n//-------------------------------\n\n//---------4.グリッド系----------\nvector<int> dx = {1, 0, -1, 0}; // dx={1,1,0,-1,-1,-1,0,1};\nvector<int> dy = {0, 1, 0, -1}; // dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w = -1)\n{\n if (w == -1)\n {\n w = h;\n }\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_rotate(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 時計回りに90°回転\n// #define vvl_rotate(v) {ll n = size(v);vvl\n// nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_rotate(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 文字列版 時計回りに90°回転\n// #define vs_rotate(v) {ll n = size(v);vs\n// nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n#define vvl_transpos(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n#define vs_transpos(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n\n//--------------------------------\n\n//-----------5.数学系--------------\n#define euclid(x, y) ((x) * (x) + (y) * (y)) // ユークリッド距離 2乗のまま\n#define manhattan(x1, x2, y1, y2) \\\n (abs(x1 - x2) + abs(y1 - y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate <class T>\nT tousa_sum1(T l, T d, T r)\n{ // 初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate <class T>\nT tousa_sum2(T a, T d, T n)\n{ // 初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d)\n{ // 初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\nmint touhi_sum(mint a, mint r,\n ll n)\n{ // 初項,公比,項数で等比数列の総和を求める\n if (r == 1)\n {\n return a * n;\n }\n mint bunsi = a * (r.pow(n) - mint(1));\n mint bunbo = r - 1;\n return bunsi / bunbo;\n}\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\n#define print_vec(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << \" \"; \\\n cout << endl; \\\n } // 一次元配列を出力する(改行なし)\n\n#define vc_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << endl; \\\n } // 一次元配列を出力する(改行あり)\n#define vv_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n//----------------------------------------------\n\nlong long modpow(long long a, long long n, long long mod)\n{\n long long res = 1;\n while (n > 0)\n {\n if (n & 1)\n res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(10);\n\n int n;\n cin >> n;\n vector<pair<int, int>> a(n);\n rep(i, n) cin >> a[i].first, a[i].second = i;\n\n sort(all(a));\n vector<int> p(n);\n rep(i, n) p[a[i].second] = a[i].first;\n\n map<int, pair<int, int>> mp;\n rep(i, n)\n {\n int l = lower_bound(all(a), make_pair(a[i].first, -1)) - a.begin();\n int r = lower_bound(all(a), make_pair(a[i].first, n)) - a.begin();\n mp[a[i].first].first = l, mp[a[i].first].second = r;\n }\n\n int ans = 0;\n rep(i, n) if (mp[p[i]].first <= i && i < mp[p[i]].second) ans++;\n\n bool f = false;\n if (ans == n)\n {\n cout << 0 << endl;\n f = true;\n }\n int q;\n cin >> q;\n rep(i, q)\n {\n int x, y;\n cin >> x >> y, x--, y--;\n if (f)\n continue;\n if (mp[p[x]].first <= x && x < mp[p[x]].second)\n ans--;\n if (mp[p[y]].first <= y && y < mp[p[y]].second)\n ans--;\n swap(p[x], p[y]);\n if (mp[p[x]].first <= x && x < mp[p[x]].second)\n ans++;\n if (mp[p[y]].first <= y && y < mp[p[y]].second)\n ans++;\n if (ans == n)\n {\n cout << i + 1 << endl;\n f = true;\n }\n }\n if (!f)\n cout << -1 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 25740, "score_of_the_acc": -1.1909, "final_rank": 17 }, { "submission_id": "aoj_0385_10777643", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\n#define MOD 998244353\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater<ll>())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x,y) reverse(x,x+y)\n#define REV(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\n#define POW(x,y) (ll)pow(x,y)\nll c,cc=-1;\nvoid solve() {\n\tll n; cin>>n;\n\tll a[n],p[n];\n\trep(i,0,n) { cin>>a[i]; p[i]=a[i]; }\n\tst(p,n);\n\trep(i,0,n) if (a[i]!=p[i]) c++;\n\tll q; cin>>q;\n\tll x,y;\n\tif (c==0) cc=0;\n\telse {\n\t\trep(i,0,q) { cin>>x>>y;\n\t\t\tx--; y--;\n\t\t\tll xa=a[x];\n\t\t\tll yb=a[y];\n\t\t\tswap(a[x],a[y]);\n\t\t\tif (xa!=p[x] && a[x]==p[x]) c--;\n\t\t\telse if (xa==p[x] && a[x]!=p[x]) c++;\n\t\t\tif (yb!=p[y] && a[y]==p[y]) c--;\n\t\t\telse if (yb==p[y] && a[y]!=p[y]) c++;\n\t\t\tif (c==0) { cc=i+1; break; }\n\t\t}\n\t}\n\tcout<<cc<<'\\n';\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8080, "score_of_the_acc": -0.1636, "final_rank": 5 }, { "submission_id": "aoj_0385_10777607", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,a[300001],q,x,y,i,b[300001],flg,cnt,lg;\nint main(void){\n\tcnt=0;\n\tflg=1;\n\tlg=0;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>a[i];\n\t\tb[i]=a[i];\n\t}\n\tsort(b,b+n);\n\tfor(i=0;i<n;i++){\n\t\tif(a[i]!=b[i]){\n\t\t\tflg=0;\n\t\t\tcnt++;\n\t\t}\n\t}\n\t\tcin>>q;\n\t\tfor(i=0;i<q;i++){\n\t\t\tcin>>x>>y;\n\t\t\tx--;\n\t\t\ty--;\n\t\t\tif(a[x]==b[x]) cnt++;\n\t\t\tif(a[x]==b[y]) cnt--;\n\t\t\tif(a[y]==b[y]) cnt++;\n\t\t\tif(a[y]==b[x]) cnt--;\n\t\t\tif(cnt==0 && flg==0){\n\t\t\t\tflg=1;\n\t\t\t\tlg=i+1;\n\t\t\t}\n\t\t\tswap(a[x],a[y]);\n\t\t}\n\tif(flg==0) cout<<-1<<endl;\n\telse cout<<lg<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 5800, "score_of_the_acc": -0.2364, "final_rank": 7 } ]
aoj_0372_cpp
Three Meals You are running a restaurant that serves dishes only three times a day. Each of your customer has his/her own separate timeframes for eating breakfast, lunch and supper. Thus, your customer enjoys your dish only when he/she visits your restaurant to meet your serving time settings. Your wish is to modify your serving time arrangement so that as many as possible of your customers can enjoy your meals three times a day. Write a program to enable as many as possible of customers can enjoy your service three times a day, i.e. breakfast, lunch, and supper. A list of customers eating timeframes is given, which you cannot change. Settings of your service time are your option. Coincidence between your service time and either edge of customer’s timframe (start or end time) does not hinder you to provide your service. Input The input is given in the following format. N ast_1 aet_1 hst_1 het_1 bst_1 bet_1 ast_2 aet_2 hst_2 het_2 bst_2 bet_2 : ast_N aet_N hst_N het_N bst_N bet_N The first line provides the number of customers N (1≤ N ≤50). Each of subsequent N lines provides timeframe information of i -th customer: start and end time of breakfast timzeframe ( ast_i , aet_i ), those of lunch timeframe ( hst_i , het_i ) and those of supper timeframe ( bst_i , bet_i ). The end time must be later in time as the start time. Timeframes do not overlap, i.e. hst_i is later in time than aet_i , and so on. Each time settings must not cross 0:00 midnight. h m Each time information is given by hour h (0≤ h ≤23) and minute m (0≤ m ≤59). Output Output the maximum number of customers that can be served all three meals (breakfast, lunch, and supper). Sample Input 1 5 1 0 2 0 3 30 4 30 6 0 7 0 2 30 3 0 4 0 5 0 5 30 6 30 1 30 2 30 4 30 5 0 6 30 7 0 2 30 3 0 5 0 6 0 6 30 7 0 1 0 2 0 3 0 3 30 4 0 5 0 Sample Output 1 3
[ { "submission_id": "aoj_0372_11026034", "code_snippet": "#pragma GCC target(\"avx2\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nint N;\nint A[50], B[50], C[50], D[50], E[50], F[50];\nsigned main(){\n set<int> st;\n cin>>N;\n for(int i=0;i<N;i++){\n int a,b;\n cin>>a>>b;\n A[i] = 60*a+b;\n st.insert(60*a+b);\n cin>>a>>b;\n B[i] = 60*a+b;\n st.insert(60*a+b);\n cin>>a>>b;\n C[i] = 60*a+b;\n st.insert(60*a+b);\n cin>>a>>b;\n D[i] = 60*a+b;\n st.insert(60*a+b);\n cin>>a>>b;\n E[i] = 60*a+b;\n st.insert(60*a+b);\n cin>>a>>b;\n F[i] = 60*a+b;\n st.insert(60*a+b);\n }\n {\n map<int,int> m;\n int now = 0;\n for(int x:st){\n m[x] = now;\n now++;\n }\n for(int i=0;i<N;i++){\n A[i] = m[A[i]];\n B[i] = m[B[i]];\n C[i] = m[C[i]];\n D[i] = m[D[i]];\n E[i] = m[E[i]];\n F[i] = m[F[i]];\n }\n }\n int ans = 0;\n for(int i=0;i<=300;i++)for(int j=i+1;j<300;j++)for(int k=j+1;k<=300;k++){\n int c = 0;\n for(int l=0;l<N;l++){\n c += (A[l] <= i && i <= B[l] && C[l] <= j & j <= D[l] && E[l] <= k && k <= F[l]);\n }\n ans = max(ans,c);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3380, "score_of_the_acc": -1.4126, "final_rank": 11 }, { "submission_id": "aoj_0372_10935972", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector t(N, vector<int>(6));\n\tvector<int> k(N * 6);\n\trep(i, 0, N) rep(j, 0, 6) {\n\t\tint h, m;\n\t\tcin >> h >> m;\n\t\tt[i][j] = h*60 + m;\n\t\tk[i*6 + j] = t[i][j];\n\t}\n\t\n\tsort(k.begin(), k.end());\n\t\n\tint ans = 0;\n\trep(a, 0, N*6) rep(b, a, N*6) rep(c, b, N*6) {\n\t\tint now = 0;\n\t\trep(i, 0, N) {\n\t\t\tbool ok = true;\n\t\t\tif (!(t[i][0] <= k[a] && k[a] <= t[i][1])) ok = false;\n\t\t\tif (!(t[i][2] <= k[b] && k[b] <= t[i][3])) ok = false;\n\t\t\tif (!(t[i][4] <= k[c] && k[c] <= t[i][5])) ok = false;\n\t\t\tif (ok) ++now;\n\t\t}\n\t\tans = max(ans, now);\n\t}\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 3436, "score_of_the_acc": -1.9767, "final_rank": 13 }, { "submission_id": "aoj_0372_10907487", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, l, n) for(int i = int(l); i < int(n); i++)\n#define ll long long\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n\ntemplate<class T> bool chmin(T &a, T b) {if(a > b) {a = b; return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a < b) {a = b; return true;} return false;}\ntemplate<class T> using spq = priority_queue<T, vector<T>, greater<T>>;\n\n// bool -> Yes/No\nstring answer(bool b) {return b ? \"Yes\" : \"No\";}\n\nvoid fix(int k) {cout << fixed << setprecision(k);}\n\nconst int inf = 2e9;\nconst long long INF = 2e18;\nconst long double eps = 1e-12;\nconst long double pi = 3.14159265358979323846264338;\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1}, dy[] = {1, 0, -1, 0, 1, -1, -1, 1};\n\nvoid main_program() {\n int n; cin >> n;\n int st[n][3], fin[n][3];\n rep(i, 0, n) {\n rep(j, 0, 3) {\n int h, m; cin >> h >> m;\n int t = h * 60 + m;\n st[i][j] = t;\n cin >> h >> m;\n t = h * 60 + m + 1;\n fin[i][j] = t;\n }\n }\n int ans = 0;\n rep(a, 0, 1440) {\n // 朝食\n rep(b, 0, 1440) {\n // 昼食\n vector<int> idx;\n vector<pair<int, int>> t;\n rep(i, 0, n) {\n if(a < st[i][0] || a >= fin[i][0]) continue;\n if(b < st[i][1] || b >= fin[i][1]) continue;\n idx.emplace_back(i);\n t.emplace_back(st[i][2], 1);\n t.emplace_back(fin[i][2], -1);\n }\n sort(all(t));\n int mx = 0, cur = 0;\n rep(i, 0, t.size()) {\n auto[k, s] = t[i];\n if(s == -1) cur--;\n else cur++;\n if(i + 1 < int(t.size()) && t[i + 1].first == k) continue;\n chmax(mx, cur);\n }\n chmax(ans, mx);\n }\n }\n cout << ans << \"\\n\";\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int T = 1;\n //cin >> T;\n while(T--) {\n main_program();\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3452, "score_of_the_acc": -1.5172, "final_rank": 12 }, { "submission_id": "aoj_0372_8809903", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\n\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\n\nint calc(int hour, int minute) { return 60 * hour + minute; }\n\nint main() {\n int N;\n std::cin >> N;\n\n std::vector<Info> info(N);\n std::vector<int> MORNING, LUNCH, DINNER;\n MORNING.reserve(2 * N);\n LUNCH.reserve(2 * N);\n DINNER.reserve(2 * N);\n\n for (int i = 0; i < N; i++) {\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n std::cin >> m_st_h >> m_st_m >> m_ed_h >> m_ed_m >> l_st_h >> l_st_m >>\n l_ed_h >> l_ed_m >> d_st_h >> d_st_m >> d_ed_h >> d_ed_m;\n\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n\n std::sort(MORNING.begin(), MORNING.end());\n std::sort(LUNCH.begin(), LUNCH.end());\n std::sort(DINNER.begin(), DINNER.end());\n\n int ans = 0;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n int tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n\n std::cout << ans << std::endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3156, "score_of_the_acc": -0.7767, "final_rank": 2 }, { "submission_id": "aoj_0372_8809902", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint calc(int hour, int minute) {\n return 60 * hour + minute;\n}\n\nint main() {\n int N;\n cin >> N;\n\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h, d_st_m, d_ed_h, d_ed_m;\n vector<int> morning_start, morning_end, lunch_start, lunch_end, dinner_start, dinner_end;\n\n for (int i = 0; i < N; i++) {\n cin >> m_st_h >> m_st_m >> m_ed_h >> m_ed_m >> l_st_h >> l_st_m >> l_ed_h >> l_ed_m >> d_st_h >> d_st_m >> d_ed_h >> d_ed_m;\n\n morning_start.push_back(calc(m_st_h, m_st_m));\n morning_end.push_back(calc(m_ed_h, m_ed_m));\n lunch_start.push_back(calc(l_st_h, l_st_m));\n lunch_end.push_back(calc(l_ed_h, l_ed_m));\n dinner_start.push_back(calc(d_st_h, d_st_m));\n dinner_end.push_back(calc(d_ed_h, d_ed_m));\n }\n\n sort(morning_start.begin(), morning_start.end());\n sort(morning_end.begin(), morning_end.end());\n sort(lunch_start.begin(), lunch_start.end());\n sort(lunch_end.begin(), lunch_end.end());\n sort(dinner_start.begin(), dinner_start.end());\n sort(dinner_end.begin(), dinner_end.end());\n\n int ans = 0;\n int tmp;\n for (int a = 0; a < morning_start.size(); a++) {\n for (int b = 0; b < lunch_start.size(); b++) {\n for (int c = 0; c < dinner_start.size(); c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (morning_start[i] <= morning_start[a] && morning_end[i] >= morning_start[a] &&\n lunch_start[i] <= lunch_start[b] && lunch_end[i] >= lunch_start[b] &&\n dinner_start[i] <= dinner_start[c] && dinner_end[i] >= dinner_start[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.21875, "time_ms": 10, "memory_kb": 3152, "score_of_the_acc": -0.564, "final_rank": 14 }, { "submission_id": "aoj_0372_8257098", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a;\n cin>>a;\n vector<vector<int> > r(a,vector<int> (6));\n vector<int> asa(a*2);\n vector<int> hiru(a*2);\n vector<int> ban(a*2);\n vector<int> hito(a);\n for(int i=0;i<a;i+=1){\n int c,d;\n for(int j=0;j<6;j+=1){\n cin>>c>>d;\n r.at(i).at(j)=c*60+d+j%2;\n if(j<2){\n asa.at(2*i+j%2)=c*60+d+j%2;\n }else\n if(j<4){\n hiru.at(2*i+j%2)=c*60+d+j%2;\n }else{\n ban.at(2*i+j%2)=c*60+d+j%2;\n }\n }\n }\n int ans=0;\n for(int i=0;i<a*2;i+=1){\n for(int j=0;j<a*2;j+=1){\n for(int k=0;k<a*2;k+=1){\n int t1=asa.at(i);\n int t2=hiru.at(j);\n int t3=ban.at(k);\n int w=0;\n if(t1<t2&&t2<t3){\n for(int i2=0;i2<a;i2+=1){\n if(r.at(i2).at(0)<=t1&&r.at(i2).at(1)>t1&&r.at(i2).at(2)<=t2&&r.at(i2).at(3)>t2&&r.at(i2).at(4)<=t3&&r.at(i2).at(5)>t3){\n w+=1; \n }\n }\n ans=max(ans,w);\n }\n }\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3180, "score_of_the_acc": -0.846, "final_rank": 4 }, { "submission_id": "aoj_0372_8214727", "code_snippet": "#include <algorithm>\n#include <vector>\n#include <cstdio>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n std::vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 2764, "score_of_the_acc": -0.2069, "final_rank": 1 }, { "submission_id": "aoj_0372_8214717", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp, morning_size = MORNING.size(), lunch_size = LUNCH.size(), dinner_size = DINNER.size();\n for (int a = 0; a < morning_size; a++) {\n for (int b = 0; b < lunch_size; b++) {\n for (int c = 0; c < dinner_size; c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n ans = max(ans, tmp);\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3260, "score_of_the_acc": -0.8933, "final_rank": 5 }, { "submission_id": "aoj_0372_8214713", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n MORNING.erase(unique(MORNING.begin(), MORNING.end()), MORNING.end());\n LUNCH.erase(unique(LUNCH.begin(), LUNCH.end()), LUNCH.end());\n DINNER.erase(unique(DINNER.begin(), DINNER.end()), DINNER.end());\n int ans = 0, tmp;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3256, "score_of_the_acc": -0.8186, "final_rank": 3 }, { "submission_id": "aoj_0372_8214710", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3260, "score_of_the_acc": -0.9278, "final_rank": 7 }, { "submission_id": "aoj_0372_8115162", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n tmp = 0;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3276, "score_of_the_acc": -0.9511, "final_rank": 8 }, { "submission_id": "aoj_0372_8115158", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\n\nint calc(int hour, int minute) { return 60 * hour + minute; }\n\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n \n // Declare variables outside the loop to avoid reallocating memory in each iteration\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n \n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp;\n \n // Declare variables outside the loop to avoid reallocating memory in each iteration\n int morning_size = MORNING.size(), lunch_size = LUNCH.size(), dinner_size = DINNER.size();\n \n for (int a = 0; a < morning_size; a++) {\n for (int b = 0; b < lunch_size; b++) {\n for (int c = 0; c < dinner_size; c++) {\n tmp = 0;\n \n // Declare variables outside the loop to avoid reallocating memory in each iteration\n int morning_a = MORNING[a], lunch_b = LUNCH[b], dinner_c = DINNER[c];\n \n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= morning_a &&\n info[i].morning_end >= morning_a &&\n info[i].lunch_start <= lunch_b &&\n info[i].lunch_end >= lunch_b &&\n info[i].dinner_start <= dinner_c &&\n info[i].dinner_end >= dinner_c) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3264, "score_of_the_acc": -0.8992, "final_rank": 6 }, { "submission_id": "aoj_0372_8115155", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\nstruct Info {\n int morning_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\nint calc(int hour, int minute) { return 60 * hour + minute; }\nint main() {\n int n;\n scanf(\"%d\", &n);\n Info info[n];\n vector<int> morning, lunch, dinner;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < n; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].morning_start = calc(m_st_h, m_st_m);\n info[i].morning_end = calc(m_ed_h, m_ed_m);\n morning.push_back(info[i].morning_start);\n morning.push_back(info[i].morning_end);\n info[i].lunch_start = calc(l_st_h, l_st_m);\n info[i].lunch_end = calc(l_ed_h, l_ed_m);\n lunch.push_back(info[i].lunch_start);\n lunch.push_back(info[i].lunch_end);\n info[i].dinner_start = calc(d_st_h, d_st_m);\n info[i].dinner_end = calc(d_ed_h, d_ed_m);\n dinner.push_back(info[i].dinner_start);\n dinner.push_back(info[i].dinner_end);\n }\n sort(morning.begin(), morning.end());\n sort(lunch.begin(), lunch.end());\n sort(dinner.begin(), dinner.end());\n int ans = 0, tmp;\n for (int a = 0; a < morning.size(); a++) {\n for (int b = 0; b < lunch.size(); b++) {\n for (int c = 0; c < dinner.size(); c++) {\n tmp = 0;\n for (int i = 0; i < n; i++) {\n if (info[i].morning_start <= morning[a] &&\n info[i].morning_end >= morning[a] &&\n info[i].lunch_start <= lunch[b] &&\n info[i].lunch_end >= lunch[b] &&\n info[i].dinner_start <= dinner[c] &&\n info[i].dinner_end >= dinner[c]) {\n tmp++;\n }\n }\n if (tmp > ans) {\n ans = tmp;\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3276, "score_of_the_acc": -0.9511, "final_rank": 8 }, { "submission_id": "aoj_0372_8115146", "code_snippet": "#include <algorithm>\n#include <cfloat>\n#include <cmath>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <stdio.h>\n#include <string>\n#include <time.h>\n#include <vector>\n#include <bitset>\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nstruct Info {\n int mornint_start, morning_end, lunch_start, lunch_end, dinner_start,\n dinner_end;\n};\n\nint main() {\n int N;\n scanf(\"%d\", &N);\n Info info[N];\n vector<int> MORNING, LUNCH, DINNER;\n int m_st_h, m_st_m, m_ed_h, m_ed_m, l_st_h, l_st_m, l_ed_h, l_ed_m, d_st_h,\n d_st_m, d_ed_h, d_ed_m;\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d %d %d %d %d %d %d %d %d\", &m_st_h, &m_st_m, &m_ed_h,\n &m_ed_m, &l_st_h, &l_st_m, &l_ed_h, &l_ed_m, &d_st_h, &d_st_m,\n &d_ed_h, &d_ed_m);\n info[i].mornint_start = 60 * m_st_h + m_st_m;\n info[i].morning_end = 60 * m_ed_h + m_ed_m;\n MORNING.push_back(info[i].mornint_start);\n MORNING.push_back(info[i].morning_end);\n info[i].lunch_start = 60 * l_st_h + l_st_m;\n info[i].lunch_end = 60 * l_ed_h + l_ed_m;\n LUNCH.push_back(info[i].lunch_start);\n LUNCH.push_back(info[i].lunch_end);\n info[i].dinner_start = 60 * d_st_h + d_st_m;\n info[i].dinner_end = 60 * d_ed_h + d_ed_m;\n DINNER.push_back(info[i].dinner_start);\n DINNER.push_back(info[i].dinner_end);\n }\n sort(MORNING.begin(), MORNING.end());\n sort(LUNCH.begin(), LUNCH.end());\n sort(DINNER.begin(), DINNER.end());\n int ans = 0, tmp;\n for (int a = 0; a < MORNING.size(); a++) {\n for (int b = 0; b < LUNCH.size(); b++) {\n for (int c = 0; c < DINNER.size(); c++) {\n tmp = 0;\n bitset<50> enabled;\n for (int i = 0; i < N; i++) {\n if (info[i].mornint_start <= MORNING[a] &&\n info[i].morning_end >= MORNING[a] &&\n info[i].lunch_start <= LUNCH[b] &&\n info[i].lunch_end >= LUNCH[b] &&\n info[i].dinner_start <= DINNER[c] &&\n info[i].dinner_end >= DINNER[c]) {\n enabled.set(i);\n }\n }\n if (enabled.count() > ans) {\n ans = enabled.count();\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3276, "score_of_the_acc": -0.9856, "final_rank": 10 } ]
aoj_0386_cpp
Transporter In the year 30XX, an expedition team reached a planet and found a warp machine suggesting the existence of a mysterious supercivilization. When you go through one of its entrance gates, you can instantaneously move to the exit irrespective of how far away it is. You can move even to the end of the universe at will with this technology! The scientist team started examining the machine and successfully identified all the planets on which the entrances to the machine were located. Each of these N planets (identified by an index from $1$ to $N$) has an entrance to, and an exit from the warp machine. Each of the entrances and exits has a letter inscribed on it. The mechanism of spatial mobility through the warp machine is as follows: If you go into an entrance gate labeled with c, then you can exit from any gate with label c. If you go into an entrance located on the $i$-th planet, then you can exit from any gate located on the $j$-th planet where $i < j$. Once you have reached an exit of the warp machine on a planet, you can continue your journey by entering into the warp machine on the same planet. In this way, you can reach a faraway planet. Our human race has decided to dispatch an expedition to the star $N$, starting from Star $1$ and using the warp machine until it reaches Star $N$. To evaluate the possibility of successfully reaching the destination. it is highly desirable for us to know how many different routes are available for the expedition team to track. Given information regarding the stars, make a program to enumerate the passages from Star $1$ to Star $N$. Input The input is given in the following format. $N$ $s$ $t$ The first line provides the number of the stars on which the warp machine is located $N$ ($2 \leq N \leq 100,000$). The second line provides a string $s$ of length $N$, each component of which represents the letter inscribed on the entrance of the machine on the star. By the same token, the third line provides a string $t$ of length $N$ consisting of the letters inscribed on the exit of the machine. Two strings $s$ and $t$ consist all of lower-case alphabetical letters, and the $i$-th letter of these strings corresponds respectively to the entrance and exit of Star $i$ machine. Output Divide the number of possible routes from Star $1$ to Star $N$ obtained above by 1,000,000,007, and output the remainder. Sample Input 1 6 abbaba baabab Sample Output 1 5 Sample Input 2 25 neihsokcpuziafoytisrevinu universityofaizupckoshien Sample Output 2 4
[ { "submission_id": "aoj_0386_9202923", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n//#include<atcoder/all>\n//using namespace atcoder;\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define rep1(i,n) for(int i=1;i<=(int)n;i++)\nusing ll = long long;\nusing ull = unsigned long long;\nusing P = pair<int, int>;\nusing Pl = pair<ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vd = vector<double>;\nusing vs = vector<string>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vl = vector<long long>;\nusing vvl = vector<vl>;\nusing vvvl = vector<vvl>;\n#define inf 947483642//int max\n#define linf 9000000000000000000\nconst double PI = 3.1415926535897932384626433832795028841971;\ntemplate<typename T>inline bool chmax(T& a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T>inline bool chmin(T& a, T b) { return ((a > b) ? (a = b, true) : (false)); }\nlong long llceil(long long a, long long b) { if (a % b == 0) { return a / b; }return (a / b) + 1; }\n#define yes cout<<\"Yes\"<<endl\n#define no cout<<\"No\"<<endl\n#define yesno(ans) cout<<(ans?\"Yes\":\"No\")<<endl\n#define sortu(a) sort(a.begin(),a.end())\n#define all(a) (a,begin(),a.end())\n//#define sortd(a) sort(a.begin(),a.end(),greater());\n//sort(a.begin(),a.end(),greater<int>());\nconst ll MOD = 1000000007;\n\nint main() {\n\n int n; cin >> n;\n string s, t; cin >> s >> t;\n\n map<char, ll>ent;\n \n for (char c = 'a'; c <= 'z'; c++) {\n rep(i, n) {\n if (t[i] == c)ent[c]++;\n }\n }\n\n map<char, ll>ans;\n \n rep(i, n) {\n ent[t[i]]--;\n\n\n if (i == 0) {\n ans[s[i]] += 1;\n continue;\n }\n if (i < n-1) {\n ans[s[i]] += ans[t[i]];\n ans[s[i]] %= MOD;\n }\n }\n\n cout << ans[t[n - 1]] << endl;\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3488, "score_of_the_acc": -0.0037, "final_rank": 3 }, { "submission_id": "aoj_0386_8250417", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tlong long n,mod = 1000000007;\n\tcin >> n;\n\tstring s,t;\n\tcin >> s >> t;\n\tvector<vector<long long>> sum(26,vector<long long>(n,0));\n\tvector<long long> last(26,-1);\n\tpriority_queue<long long,vector<long long>,greater<long long>> q;\n\tvector<long long> dp(n,0);\n\tdp[0] = 1;\n\tfor(long long it = 0;it < n;it++){\n\t\twhile(last[t[it] - 'a'] < it){\n\t\t\tlast[t[it] - 'a']++;\n\t\t\tif(last[t[it] - 'a'] == 0) continue;\n\t\t\tsum[t[it] - 'a'][last[t[it] - 'a']] += sum[t[it] - 'a'][last[t[it] - 'a'] - 1];\n\t\t\tsum[t[it] - 'a'][last[t[it] - 'a']] %= mod;\n\t\t}\n\t\tif(it != 0){\n\t\t\tdp[it] += sum[t[it] - 'a'][it - 1];\n\t\t}\n\t\tdp[it] %= mod;\n\t\tsum[s[it] - 'a'][it] += dp[it];\n\t\tsum[s[it] - 'a'][it] %= mod;\n\t}\n\tdp[n - 1] %= mod;\n\tcout << dp[n - 1] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 24376, "score_of_the_acc": -0.3792, "final_rank": 13 }, { "submission_id": "aoj_0386_6856651", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nchar s[100001],t[100001];\nlong long L=1000000007;\nint main(void)\n{\n int n;\n cin>>n>>s>>t;\n map<char,long long> a,b;\n a[s[0]]++;\n for(int i=1;i<n;i++){\n if(!(i==n-1&&s[i]==t[i])) a[s[i]]=(a[s[i]]+a[t[i]])%L;\n }\n cout<<a[t[n-1]]<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0386_4926818", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass RangeUpdate{\npublic:\n\tvirtual ll fa(ll x,ll m)=0;\n\tvirtual ll fm(ll m1,ll m2)=0;\n\tll em;\n};\n\nclass RangeUpdateAdd:public RangeUpdate{\npublic:\n\tRangeUpdateAdd(){em = 0;}\n\tll fa(ll x,ll m){return (x+m)%atcoder_mod;}\n\tll fm(ll m1,ll m2){return (m1+m2)%atcoder_mod;}\n};\n\nclass RangeQuery{\npublic:\n\tvirtual ll fx(ll x1,ll x2)=0;\n\tvirtual ll fp(ll m,ll n)=0;\n\tll ex;\n};\n\nclass RangeQueryMin:public RangeQuery{\npublic:\n\tRangeQueryMin(){ex = numeric_limits<ll>::max();}\n\tll fx(ll x1,ll x2){return min(x1,x2);}\n\tll fp(ll m,ll n){return m;}\n};\n\nclass SegmentTree{\n\tunique_ptr<RangeUpdate> range_update;\n\tunique_ptr<RangeQuery> range_query;\n\n\t/* lazy eval */\n\tvoid Eval(int k,int len){\n\t\tif(lazy[k]==range_update->em) return; // 更新するものが無ければ終了\n\t\tif(k<size-1){ // 葉でなければ子に伝搬\n\t\t\tlazy[k*2+1] = range_update->fm(lazy[k*2+1],lazy[k]);\n\t\t\tlazy[k*2+2] = range_update->fm(lazy[k*2+2],lazy[k]);\n\t\t}\n\t\t// 自身を更新\n\t\tdat[k] = range_update->fa(dat[k],range_query->fp(lazy[k],len));\n\t\tlazy[k] = range_update->em;\n\t}\n\n\tll Query(ll a, ll b, ll k, ll l, ll r){\n\t\tEval(k,r-l);\n\t\tif(r<=a || b<=l){ // 完全に外側の時\n\t\t\treturn range_query->ex;\n\t\t}\n\t\telse if(a <= l && r <= b){ // 完全に内側の時\n\t\t\treturn dat[k];\n\t\t}\n\t\telse{ // 一部区間が被る時\n\t\t\tll vl = Query(a,b,k*2+1,l,(l+r)/2);\n\t\t\tll vr = Query(a,b,k*2+2,(l+r)/2,r);\n\t\t\treturn range_query->fx(vl,vr);\n\t\t}\n\t}\n\n\tvoid Update(ll a, ll b, ll x, ll k, ll l, ll r) {\n\t\tEval(k,r-l);\n\t\tif(a<=l && r<=b){ // 完全に内側の時\n\t\t\tlazy[k] = range_update->fm(lazy[k],x);\n\t\t\tEval(k,r-l);\n\t\t}\n\t\telse if(a<r && l<b){ // 一部区間が被る時\n\t\t\tUpdate(a,b,x,k*2+1,l,(l+r)/2); // 左の子\n\t\t\tUpdate(a,b,x,k*2+2,(l+r)/2,r); // 右の子\n\t\t\tdat[k] = range_query->fx(dat[k*2+1],dat[k*2+2]);\n\t\t}\n\t}\npublic:\n\tll size;\n\tvector<ll> dat;\n\tvector<ll> lazy;\n\tSegmentTree(ll N, unique_ptr<RangeUpdate> rup,unique_ptr<RangeQuery> rqp)\n\t\t: range_update(std::move(rup)), range_query(std::move(rqp)){\n\t\tdat.resize(max(4*N,4ll),range_query->ex);\n\t\tlazy.resize(max(4*N,4ll),range_update->em);\n\t\tll x = 1;\n\t\twhile(N>x) x *= 2;\n\t\tsize = x;\n\t}\n\tvoid Set(int i,ll x){dat[i+size-1]=x;}\n\tvoid Build(){\n\t\tfor(ll k=size-2ll;k>=0;k--) dat[k] = range_query->fx(dat[2*k+1],dat[2*k+2]);\n\t}\n\n\tvoid Update(ll a, ll b, ll x){Update(a, b, x, 0, 0, size);}\n\tll Query(int a, int b){return Query(a, b, 0, 0, size);}\n};\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto N=in();\n\tstring S=in<string>(),T=in<string>();\n\tvvll M(26);\n\tREP(i,N){\n\t\tM[T[i]-'a'].push_back(i);\n\t}\n\n\tunique_ptr<SegmentTree> seg_tree[26];\n\tREP(i,26){\n\t\tll K=M[i].size();\n\t\tseg_tree[i] = make_unique<SegmentTree>(K,make_unique<RangeUpdateAdd>(),make_unique<RangeQueryMin>());\n\t\tREP(j,K){\n\t\t\tseg_tree[i]->Set(j,0);\n\t\t}\n\t\tseg_tree[i]->Build();\n\t}\n\tseg_tree[T[0]-'a']->Update(0,1,1);\n\tvll I(26,0);\n\tREP(i,N){\n\t\tll Q=S[i]-'a';\n\t\tll E=M[Q].size();\n\t\tauto res = upper_bound(ALL(M[Q]),i);\n\t\tll D=distance(M[Q].begin(),res);\n\t\tauto val = seg_tree[T[i]-'a']->Query(I[T[i]-'a'],I[T[i]-'a']+1);\n\t\tseg_tree[Q]->Update(D,E,val);\n\t\tI[T[i]-'a']++;\n\t}\n\n\tout(seg_tree[T[N-1]-'a']->Query(I[T[N-1]-'a']-1,I[T[N-1]-'a']));\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10964, "score_of_the_acc": -0.5666, "final_rank": 17 }, { "submission_id": "aoj_0386_4821983", "code_snippet": "#include <iostream> \n#include<vector>\n#include<algorithm>\n#include<map>\n#include<string>\n#include<iomanip>\n#include<set>\n#include<queue>\n#include<deque>\n#include<sstream>\n#include<cmath>\n#include<bitset>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define req(i,n) for(int i = 1;i <= n; i++)\ntypedef long long int ll;\nconst int MOD = 1000000007;\nint main(void) {\n string s, t; int n; cin >> n >> s >> t;\n vector<vector<int>> dp(n, vector<int>(26, 0));\n dp[0][s[0] - 'a'] = 1;\n req(i, n - 1) {\n dp[i][s[i] - 'a'] = (dp[i][s[i] - 'a'] + dp[i - 1][t[i] - 'a']) % MOD;\n rep(j, 26) dp[i][j] = (dp[i][j] + dp[i - 1][j]) % MOD;\n }cout << dp[n - 2][t[n - 1] - 'a'] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 16364, "score_of_the_acc": -0.2351, "final_rank": 8 }, { "submission_id": "aoj_0386_4821981", "code_snippet": "#include <iostream> \n#include<vector>\n#include<algorithm>\n#include<map>\n#include<string>\n#include<iomanip>\n#include<set>\n#include<queue>\n#include<deque>\n#include<sstream>\n#include<cmath>\n#include<bitset>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define req(i,n) for(int i = 1;i <= n; i++)\n#define rrep(i,n) for(int i = n-1;i >= 0;i--)\n#define ALL(obj) begin(obj), end(obj)\n#define RALL(a) rbegin(a),rend(a)\ntypedef long long int ll;\ntypedef long double ld;\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N], const T& val) {\n std::fill((T*)array, (T*)(array + N), val);\n}\nconst int MAX = 510000;\nconst int MOD = 1000000007;\nconst int inf = 1<<31-1;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nint main(void) {\n string s, t; int n; cin >> n >> s >> t;\n vector<vector<int>> dp(n, vector<int>(26, 0));\n dp[0][s[0] - 'a'] = 1;\n req(i, n - 1) {\n dp[i][s[i] - 'a'] = (dp[i][s[i] - 'a'] + dp[i - 1][t[i] - 'a']) % MOD;\n rep(j, 26) dp[i][j] = (dp[i][j] + dp[i - 1][j]) % MOD;\n }cout << dp[n - 2][t[n - 1] - 'a'] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 16360, "score_of_the_acc": -0.2351, "final_rank": 7 }, { "submission_id": "aoj_0386_4795867", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\n#define repeat(i, n) for (int i = 0; (i) < (n); ++(i))\n#define repeat_from(i, m, n) for (int i = (m); (i) < (n); ++(i))\nusing namespace std;\ntemplate <class T>\nvoid setmax(T &a, T const &b) {\n if (a < b) a = b;\n}\n\ntemplate <class T>\nvoid setmin(T &a, T const &b) {\n if (a > b) a = b;\n}\n\ntemplate <typename T, typename X>\nauto vectors(T a, X x) { return vector<T>(x, a); }\n\ntemplate <typename T, typename X, typename Y, typename... Zs>\nauto vectors(T a, X x, Y y, Zs... zs) {\n auto cont = vectors(a, y, zs...);\n return vector<decltype(cont)>(x, cont);\n}\n\n// もらうdpで行こう\nconst long long MOD = 1e9 + 7;\n\nint main() {\n int N;\n string S, T;\n cin >> N >> S >> T;\n\n const int alphabet = 'z' - 'a' + 1;\n // dp[i][j] := 星0~iの入口jから入れる累計数\n auto dp = vectors(0, N, alphabet);\n dp[0][S[0] - 'a'] = 1;\n repeat_from(i, 1, N) {\n dp[i][S[i] - 'a'] = (dp[i][S[i] - 'a'] + dp[i - 1][T[i] - 'a']) % MOD;\n repeat(j, alphabet) {\n dp[i][j] = (dp[i][j] + dp[i - 1][j]) % MOD;\n }\n }\n // 星N-2から星N-1の出口と同じタイプの入口に入れる通り\n cout << dp[N - 2][T[N - 1] - 'a'] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 16300, "score_of_the_acc": -0.234, "final_rank": 6 }, { "submission_id": "aoj_0386_4756416", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <string>\nusing namespace std;\n\n\nlong long int m=1000000007;\nstring str1;\nstring str2;\nconst int R=131071;\nlong long int xs[26][270000];\nint qs[26][270000];\nlong long int ms[100001];\n\nlong long int f(int no,int no2,long long int x,int l1,int r1,int l,int r){\n\tif(r1<l){\n\t\treturn xs[no][no2];\n\t}\n\tif(r<l1){\n\t\treturn 0;\n\t}\n\tif(r1==l1){\n\t\txs[no][no2]=(xs[no][no2]+x)%m;\n\t\treturn xs[no][no2];\n\t}\n\tif(l<=l1&&r1<=r){\n\t\txs[no][no2]=(xs[no][no2]+x)%m;\n\t\treturn xs[no][no2];\n\t}else{\n\t\t\n\t\tint m1=(l1+r1)/2;\n\t\tlong long int t1=f(no,no2*2+1,x,l1,m1,l,r);\n\t\tlong long int t2=f(no,no2*2+2,x,m1+1,r1,l,r);\n\t\txs[no][no2]=(t1+t2) % m;\n\t\treturn xs[no][no2];\n\t}\n}\n\nint main() {\n\t// your code goes here\n\tmemset(xs,0,sizeof(xs));\n\tint n;\n\tcin>>n;\n\tcin>>str1;\n\tcin>>str2;\n\t\n\tf(((int)str1[0])-97,0,1,0,R,0,0);\n\tms[0]=1;\n\tlong long int ans=0;\n\tfor(int i=1;i<n-1;i++){\n\t\tint t1=(int)str2[i] - 97;\n\t\tint t2=(int)str1[i] - 97;\n\t\tms[i]=f(t1,0,0,0,R,0,i-1);\n\t\tf(t2,0,ms[i],0,R,i,i);\n\t}\n\tint t2=(int)str2[n-1] - 97;\n\tcout<<f(t2,0,0,0,R,n-1,n-1)<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 58912, "score_of_the_acc": -2, "final_rank": 19 }, { "submission_id": "aoj_0386_4309725", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <cstdlib>\n#include <string>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <math.h>\n#include <random>\n#include <time.h>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775808\n#define LL_MAX 9223372036854775807\n\n/*\n//1\nint main(){\n int f;\n\tcin >> f;\n\n\tcout << (f - 30)/2 << endl;\n\n \n return 0;\n}\n*/\n\n\n\n/*\n//2\nint main(){\n int x1, x2;\n\tcin >> x1 >> x2;\n\n\tcout << abs(x1 - x2) << endl;\n\n \n return 0;\n}\n*/\n\n\n\n/*\n//3\nint main(){\n int N, C;\n\tcin >> N >> C;\n\n\tint sum = 0;\n\tfor(int i=0; i<C; i++){\n\t\tint p;\n\t\tcin >> p;\n\t\tsum += p;\n\t}\n\n\tint ans = sum/(N+1);\n\tif(sum%(N+1) != 0) ans++;\n\tcout << ans << endl;\n \n return 0;\n}\n*/\n\n/*\n//4\nint main(){\n int A, B, X;\n\tcin >> A >> B >> X;\n\tint ans;\n\n\tif(A < 2*B){\n\t\tans = X/1000 * A;\n\t\tint tmp = X%1000;\n\n\t\tif(tmp != 0){\n\t\t\tif(ans + A < ans + B * (tmp/500 + 1) ){\n\t\t\t\tans = ans + A;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tans = ans + B * (tmp/500 + 1);\n\t\t\t}\n\t\t}\n\t}\n\telse{\n\t\tans = X/500 * B;\n\t\tint tmp = X%500;\n\n\t\tif(tmp != 0){\n\t\t\tans += B;\n\t\t}\n\t}\n\n\tcout << ans << endl;\n \n return 0;\n}\n*/\n\n/*\nint A, N, M;\n\nint njo(int m, int n){\n\tif(n == 0) return 1;\n\tn--;\n\treturn m * njo(m, n);\n}\n\nint sum = 0;\nvoid solve(int X){\n\tif(X == 0) return;\n\tsum += X%10;\n\tsolve(X/10);\n}\n\n//5\nint main(){\n cin >> A >> N >> M;\n\n\tint ans = 0;\n\tfor(int i=1; i <= 73; i++){\n\t\tint x = njo(i + A, N);\n\t\tif(x > M) break;\n\n\t\tsum = 0;\n\t\tsolve(x);\n\t\tint y = sum;\n\n\t\tif(i == y) ans++;\n\t}\n\n\tcout << ans << endl;\n\n return 0;\n}\n*/\n\n\n\n/*\n//6\nint main(){\n int N, Q;\n\tint A[30000];\n\tbool b[30000];\n\tint sum = 0;\n\n\tcin >> N;\n\n\tfor(int i=0; i<N; i++){\n\t\tcin >> A[i];\n\t\tb[i] = false;\n\t}\n\n\tfor(int i=0; i<N-1; i++){\n\t\tif(A[i] > A[i+1]){\n\t\t\tb[i] = true;\n\t\t\tsum++;\n\t\t}\n\t}\n\n\tcin >> Q;\n\n\tif(sum == 0){\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\n\tfor(int i=0; i<Q; i++){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tx--;\n\t\ty--;\n\t\tif(x > y){\n\t\t\tint tmp = x;\n\t\t\tx = y;\n\t\t\ty = tmp;\n\t\t}\n\n\t\tint tmps = A[x];\n\t\tA[x] = A[y];\n\t\tA[y] = A[x];\n\n\t\tif(b[x] == true){\n\t\t\tif(A[x] <= A[x+1]){\n\t\t\t\tb[x] = false;\n\t\t\t\tsum--;\n\t\t\t}\n\t\t}\n\t\tif(x>=1){\n\t\t\tif(b[x-1] == true){\n\t\t\t\tif(A[x-1] <= A[x]){\n\t\t\t\t\tb[x-1] = false;\n\t\t\t\t\tsum--;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(b[y] == true){\n\t\t\tif(A[y] <= A[y+1]){\n\t\t\t\tb[y] = false;\n\t\t\t\tsum--;\n\t\t\t}\n\t\t}\n\t\tif(y>=1){\n\t\t\tif(b[y-1] == true && x+1 != y){\n\t\t\t\tif(A[y-1] <= A[x]){\n\t\t\t\t\tb[y-1] = false;\n\t\t\t\t\tsum--;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif(x < N-1){\n\t\t\tif(A[x] > A[x+1]){\n\t\t\t\tb[x] = true;\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif(x >=1){\n\t\t\tif(A[x-1] > A[x]){\n\t\t\t\tb[x-1] = true;\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\n\t\tif(y < N-1){\n\t\t\tif(A[y] > A[y+1]){\n\t\t\t\tb[y] = true;\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\t\tif(y >=1){\n\t\t\tif(A[y-1] > A[y] && x+1 != y){\n\t\t\t\tb[y-1] = true;\n\t\t\t\tsum++;\n\t\t\t}\n\t\t}\n\n\t\tif(sum == 0){\n\t\t\tcout << i + 1 << endl;\n\t\t\treturn 0;\n\t\t}\n\n\t}\n\n\tcout << -1 << endl;\n\n return 0;\n}\n*/\n\n\n\n\n//7\n\n#define MOD 1000000007\n\nint N;\nstring s,t;\nmap<char, set<int> > deguti;\nint dp[100000];\nint memo[100000];//���̓_�ȍ~�̗ݐϘa\n\nint solve(int now){\n\tif(now == N-1){\n\t\tmemo[now] = 1;\n\t\treturn 1;\n\t}\n\tif(dp[now] != -1) return dp[now];\n\n\tauto itr = deguti[s[now]].upper_bound(now);\n\tif(itr == deguti[s[now]].end()) dp[now] = 0;\n\telse dp[now] = memo[*itr];\n\n\titr = deguti[t[now]].upper_bound(now);\n\tif(itr == deguti[t[now]].end()) memo[now] = (dp[now] + memo[*itr]) % MOD;\n\telse memo[now] = dp[now];\n\n\treturn dp[now];\n}\n\nint main(){\n \n\tcin >> N >> s >> t;\n\tstring alpha = \"abcdefghijklmnopqrstuvwxyz\";\n\tset<int> none;\n\tfor(int i=0; i<alpha.size(); i++){\n\t\tdeguti[alpha[i]] = none;\n\t}\n\tfor(int i=0; i<N; i++){\n\t\tdeguti[t[i]].insert(i);\n\t\tdp[i] = -1;\n\t}\n\n\tdp[N-1] = 1;\n\tmemo[N-1] = 1;\n\tfor(int i=N-2; i>=0; i--){\n\t\tauto itr = deguti[s[i]].upper_bound(i);\n\t\tif(itr == deguti[s[i]].end()) dp[i] = 0;\n\t\telse dp[i] = memo[*itr];\n\n\t\titr = deguti[t[i]].upper_bound(i);\n\t\tif(itr == deguti[t[i]].end()) memo[i] = dp[i];\n\t\telse memo[i] = (dp[i] + memo[*itr]) % MOD;\n\t}\n\tcout << dp[0] << endl;\n\t//for(int i=0; i<N; i++) cout << dp[i] << endl;\n \n return 0;\n}\n\n\n\n\n/*\n//8\n\nint N;\nvector<pair<int,int>> all;\n\n//long long solve(int now, int cars){\n//\tif(now == N) return 0;\n//\t\n//\tlong long tmp = 0;\n//\tlong long ans = solve(now+1, cars+1);\n//\tfor(int i=0; i<cars; i++){\n//\t\tif(i >= c[now].size()) break;\n//\t\ttmp += c[now][i];\n//\t\tans = max(ans, tmp + solve(now+1, cars-i));\n//\t}\n//\treturn ans;\n//}\n\nint seg_size = 524288 * 2 - 1;\nint seg[1048575];\n\nint query(int a, int b, int k, int l, int r){\n\tif(r <= a || b <= l) return 0;\n\tif(a <= l && r <= b) return seg[k];\n\telse return query(a,b,k*2+1,l,(l+r)/2) + query(a,b,k*2+2,(l+r)/2,r);\n}\n\nint main(){\n \n\tcin >> N;\n\tfor(int i=0; i<N; i++){\n\t\tint M;\n\t\tcin >> M;\n\t\tfor(int j=0; j<M; j++){\n\t\t\tint tmp;\n\t\t\tcin >> tmp;\n\t\t\tall.push_back(make_pair(tmp, i));\n\t\t}\n\t}\n\tsort(all.begin(), all.end());\n\treverse(all.begin(), all.end());\n\t\n\tseg_size = 1;\n\twhile(seg_size < N) seg_size *= 2;\n\tseg_size = seg_size * 2 - 1;\n\tfor(int i=0; i<seg_size; i++) seg[i] = 0;\n\t\n\tlong long ans = 0;\n\tfor(int i=0; i<all.size(); i++){\n\t\tint place = all[i].second;\n\t\tif(query(0,place+1,0,0,(seg_size+1)/2) < place+1){\n\t\t\tcout << i << \" \" << query(0,place+1,0,0,(seg_size+1)/2) << endl;\n\t\t\tans += all[i].first;\n\n\t\t\tint j = seg_size/2 + place;\n\t\t\tseg[j]++;\n\t\t\twhile(j > 0){\n\t\t\t\tj = (j-1) / 2;\n\t\t\t\tseg[j]++;\n\t\t\t}\n\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n \n return 0;\n}*/\n\n\n/*\n//9\nint gcd(int a, int b){\n\tif(a == 0 || b == 0) return 1;\n\tif(b > a) swap(a,b);\n\tif(a % b == 0) return b;\n\treturn gcd(b, a%b);\n}\nint main(){\n \n\tint N,K;\n\tcin >> N >> K;\n\tint x[3000],y[3000];\n\tfor(int i=0; i<N; i++){\n\t\tcin >> x[i] >> y[i];\n\t}\n\n\tmap<pair<int,int> ,int> tmp;\n\tfor(int i=0; i<N; i++){\n\t\tfor(int j=i+1; j<N; j++){\n\t\t\tint x2 = x[j]-x[i];\n\t\t\tint y2 = y[j]-y[i];\n\t\t\tint g = gcd(x2,y2);\n\t\t\tx2 = x2 / g;\n\t\t\ty2 = y2 / g;\n\t\t\tif(x2 == 0) y2 = 1;\n\t\t\tif(y2 == 0) x2 = 1;\n\n\t\t\ttmp[make_pair(x2,y2)]++;\n\t\t\tif(tmp[make_pair(x2,y2)] >= K){\n\t\t\t\tcout << 1 << endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tcout << 0 << endl;\n \n return 0;\n}\n*/\n\n\n/*\n\n//11\nint main(){\n \n\tint K,N,Q;\n\tcin >> K >> N >> Q;\n\tint A[100000];\n\tset<int> change;\n\tint tmp = 1;\n\tint now = 0;\n\tfor(int i=0; i<N; i++){\n\t\tcin >> A[i];\n\t\tif(A[i] == 0){\n\t\t\ttmp *= -1;\n\t\t\tchange.insert(i);\n\t\t}\n\t\telse now += A[i];\n\t\twhile(now < 1) now += K;\n\t\twhile(now > K) now -= K;\n\t}\n\n\tfor(int i=0; i<Q; i++){\n\t\tint L,R;\n\t\tcin >> L >> R;\n\t\tif(change.count(L) == 0 && change.count(R) == 0){\n\t\t\tauto itr=change.begin();\n\t\t\tint tmp = 1;\n\t\t\twhile(*itr < L){\n\t\t\t\titr++;\n\t\t\t\ttmp *= -1;\n\t\t\t}\n\t\t\tsum -= A[L-1];\n\t\t}\n\t}\n\n \n return 0;\n}\n*/\n\n/*\nint main(){\n\tint A, B, X;\n\tcin >> A >> B >> X;\n\tint ans = INT_MAX;\n\tfor(int a=0; a<=40; a++){\n\t\tfor(int b=0; b<=40; b++){\n\t\t\tif(1000*a + 500*b >= X) ans = min(ans, A*a+B*b);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}\n*/", "accuracy": 1, "time_ms": 30, "memory_kb": 8736, "score_of_the_acc": -0.3837, "final_rank": 14 }, { "submission_id": "aoj_0386_4309718", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775808\n#define LL_MAX 9223372036854775807\n#define ROOP() while (true)\n\n#define MOD 1000000007\n\nint N;\nstring s,t;\nmap<char, vector<int> > deguti; //文字firstが出口に指定されている星のリストsecond\nint dp[100000];\nint sum[100000]; //dp[]の値の累積和\n\nint main(){\n \n\tcin >> N >> s >> t;\n\tstring alpha = \"abcdefghijklmnopqrstuvwxyz\";\n\tvector<int> none;\n\tfor(int i=0; i<alpha.size(); i++) deguti[alpha[i]] = none; //初期化\n\tfor(int i=0; i<N; i++) deguti[t[i]].push_back(i);\n\n //DPの初期化\n\tdp[N-1] = 1;\n\tsum[N-1] = dp[N-1];\n //DPの計算処理\n\tfor(int i=N-2; i>=0; i--){\n\t\tauto itr = upper_bound(deguti[s[i]].begin(), deguti[s[i]].end(), i);\n\t\tif(itr == deguti[s[i]].end()) dp[i] = 0; //ワープ装置に入っても出口がない\n\t\telse dp[i] = sum[*itr];\n\n\t\titr = upper_bound(deguti[t[i]].begin(), deguti[t[i]].end(), i);\n\t\tif(itr == deguti[t[i]].end()) sum[i] = dp[i]; //現在地以降に現在地と同じ出口がない\n\t\telse sum[i] = (dp[i] + sum[*itr]) % MOD;\n\t}\n\tcout << dp[0] << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4496, "score_of_the_acc": -0.1646, "final_rank": 4 }, { "submission_id": "aoj_0386_4123271", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cmath>\n#include<algorithm>\n#include<string.h>\nusing namespace std;\nconst int M=1000000007;\nconst int N_MAX=100000;\n\nint n,dp[N_MAX+1][26];\nstring s,t;\nint main(){\n\tcin>>n;\n\tcin>>s>>t;\n\t\n\tdp[0][s[0]-'a']=1;\n\tfor(int i=1;i<n;i++){\n\t\tdp[i][s[i]-'a']=(dp[i][s[i]-'a']+dp[i-1][t[i]-'a'])%M;\n\t\tfor(int j=0;j<26;j++)dp[i][j]=(dp[i][j]+dp[i-1][j])%M;\t\t\n\t}\n\t\n\tcout<<dp[n-2][t[n-1]-'a']<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 13476, "score_of_the_acc": -0.1832, "final_rank": 5 }, { "submission_id": "aoj_0386_4120336", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing i64 = int64_t;\n\nconstexpr i64 MOD = 1e9 + 7;\n\nint main(){\n int n;\n cin >> n;\n string s, t;\n cin >> s >> t;\n vector<vector<i64>> dp(n, vector<i64>(26, 0));\n dp[0][s[0]-'a'] = 1;\n for(int i=1;i<n;++i){\n for(char c='a';c<='z';++c){\n dp[i][c-'a'] = dp[i-1][c-'a'];\n }\n if(i == n-1)break;\n dp[i][s[i]-'a'] += dp[i-1][t[i]-'a'];\n dp[i][s[i]-'a'] %= MOD;\n\n /*for(int i=0;i<n;++i){\n for(int j=0;j<26;++j){\n cerr << dp[i][j] << \" \";\n }\n cerr << endl;\n }\n cerr << endl;\n */\n }\n\n cout << dp[n-1][t[n-1]-'a'] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 27416, "score_of_the_acc": -0.4338, "final_rank": 16 }, { "submission_id": "aoj_0386_4120127", "code_snippet": "#include<algorithm>\n#include<bitset>\n#include<cassert>\n#include<cfloat>\n#include<climits>\n#include<cmath>\n#include<deque>\n#include<functional>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<queue>\n#include<set>\n#include<stack>\n#include<string>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = (int)(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = (int)(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = (int)(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = (int)(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = (int)(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define REVERSE(x) reverse((x).begin(), (x).end())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << '\\n'\n#define endl '\\n'\n\nconstexpr int IINF = (1 << 30) - 1;\nconstexpr long long LLINF = 1LL << 61;\nconstexpr double EPS = 1e-10;\n\nconstexpr int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconstexpr int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\ntemplate<long long modulus>\nclass ModInt{\n long long num;\n\n long long mod(long long n){\n if(n < 0LL){\n n = (n % modulus) + modulus;\n }\n return n % modulus;\n }\n\n long long ext_gcd(long long a, long long b, long long &x, long long &y){\n if(b == 0LL){\n x = 1;\n y = 0;\n return a;\n }\n\n long long d = ext_gcd(b, a % b, y, x);\n y -= a / b * x;\n\n return d;\n }\n\n long long get_inv(long long n){\n long long x, y;\n ext_gcd(n, modulus, x, y);\n return mod(x);\n }\n\npublic:\n constexpr ModInt(const long long n = 0LL) noexcept : num(mod(n)) {}\n\n long long get(void){\n return num;\n }\n\n ModInt &operator+=(const ModInt &rhs){\n num += rhs.num;\n if(num >= modulus){\n num -= modulus;\n }\n return *this;\n }\n\n ModInt &operator-=(const ModInt &rhs){\n if(num < rhs.num){\n num += modulus;\n }\n num -= rhs.num;\n return *this;\n }\n\n ModInt &operator*=(const ModInt &rhs){\n num = num * rhs.num % modulus;\n return *this;\n }\n\n ModInt &operator/=(const ModInt &rhs){\n long long inv = get_inv(rhs.num);\n num = num * inv % modulus;\n return *this;\n }\n\n template<typename T>\n ModInt &operator+=(const T &rhs){\n return *this += ModInt(rhs);\n }\n\n template<typename T>\n ModInt &operator-=(const T &rhs){\n return *this -= ModInt(rhs);\n }\n\n template<typename T>\n ModInt &operator*=(const T &rhs){\n return *this *= ModInt(rhs);\n }\n\n template<typename T>\n ModInt &operator/=(const T &rhs){\n return *this /= ModInt(rhs);\n }\n\n template<typename T>\n ModInt operator+(const T &rhs) const {\n return ModInt(*this) += ModInt(rhs);\n }\n\n template<typename T>\n ModInt operator-(const T &rhs) const {\n return ModInt(*this) -= ModInt(rhs);\n }\n\n template<typename T>\n ModInt operator*(const T &rhs) const {\n return ModInt(*this) *= ModInt(rhs);\n }\n\n template<typename T>\n ModInt operator/(const T &rhs) const {\n return ModInt(*this) /= ModInt(rhs);\n }\n\n ModInt &operator=(const ModInt &rhs){\n num = rhs.num;\n return *this;\n }\n\n template<typename T>\n ModInt &operator=(const T &rhs){\n num = mod(rhs);\n return *this;\n }\n\n bool operator<(const ModInt &rhs) const {\n return num < rhs.num;\n }\n\n bool operator==(const ModInt &rhs) const {\n return num == rhs.num;\n }\n};\n\ntemplate<long long modulus>\nstd::istream &operator>>(std::istream &lhs, ModInt<modulus> &rhs){\n long long val;\n lhs >> val;\n rhs = val;\n return lhs;\n}\n\ntemplate<long long modulus>\nstd::ostream &operator<<(std::ostream &lhs, ModInt<modulus> rhs){\n lhs << rhs.get();\n return lhs;\n}\n\nusing mint = ModInt<1000000007LL>;\n\ntemplate<typename T>\nclass CoordinateCompression{\n std::vector<T> dat;\n int s;\n int n;\n\npublic:\n CoordinateCompression(){}\n\n CoordinateCompression(const std::vector<T>& dat_, int s_ = 0, bool uni = true){\n build(dat_, s_, uni);\n }\n\n void build(const std::vector<T>& dat_, int s_ = 0, bool uni = true){\n dat = dat_;\n\n std::sort(dat.begin(), dat.end());\n if(uni){\n dat.erase(std::unique(dat.begin(), dat.end()), dat.end());\n }\n\n s = s_;\n\n n = (int)dat.size();\n\n return;\n }\n\n int get(T x){\n return (int)(std::lower_bound(dat.begin(), dat.end(), x) - dat.begin()) + s;\n }\n\n T restore(int k){\n return dat[k - s];\n }\n\n int size(void){\n return n;\n }\n};\n\ntemplate<typename T>\nclass LazySegmentTree{\n int n;\n std::vector<T> node;\n std::vector<T> lazy;\n std::vector<int> length;\n int height;\n\n using F = std::function<T(T, T)>;\n using S = std::function<T(T, int)>;\n\n F f;\n F g;\n F h;\n S s;\n T id1;\n T id2;\n\n void evaluate(int k){\n if(lazy[k] == id2){\n return;\n }\n\n node[k] = g(node[k], s(lazy[k], length[k]));\n\n if(k < n){\n lazy[k << 1] = h(lazy[k << 1], lazy[k]);\n lazy[(k << 1) | 1] = h(lazy[(k << 1) | 1], lazy[k]);\n }\n\n lazy[k] = id2;\n\n return;\n }\n\n void evaluate(int l, int r){\n for(int i = height ; 0 < i ; --i){\n evaluate(l >> i);\n evaluate(r >> i);\n }\n\n return;\n }\n\npublic:\n LazySegmentTree(){}\n\n LazySegmentTree(int n_, F f_, F g_, F h_, T id1_, T id2_, S s_ = [](T x, int len){ return x; }){\n init(n_, f_, g_, h_, id1_, id2_, s_);\n }\n\n LazySegmentTree(const std::vector<T>& dat, F f_, F g_, F h_, T id1_, T id2_, S s_ = [](T x, int len){ return x; }){\n build(dat, f_, g_, h_, id1_, id2_, s_);\n }\n\n void init(int n_, F f_, F g_, F h_, T id1_, T id2_, S s_ = [](T x, int len){ return x; }){\n n = 1;\n height = 0;\n while(n < n_){\n n <<= 1;\n ++height;\n }\n\n f = f_;\n g = g_;\n h = h_;\n id1 = id1_;\n id2 = id2_;\n s = s_;\n\n node.assign(n << 1, id1);\n lazy.assign(n << 1, id2);\n\n length.assign(n << 1, 1);\n fill(length.begin() + n + n_, length.end(), 0);\n for(int i = n - 1 ; 0 < i ; --i){\n length[i] = length[i << 1] + length[(i << 1) | 1];\n }\n\n return;\n }\n\n void build(const std::vector<T>& dat, F f_, F g_, F h_, T id1_, T id2_, S s_ = [](T x, int len){ return x; }){\n int n_ = (int)dat.size();\n\n init(n_, f_, g_, h_, id1_, id2_, s_);\n\n for(int i = 0 ; i < n_ ; ++i){\n node[i + n] = dat[i];\n }\n for(int i = n - 1 ; 0 < i ; --i){\n node[i] = f(node[i << 1], node[(i << 1) | 1]);\n }\n\n return;\n }\n\n void update(int l, int r, T x){\n l += n;\n r += n - 1;\n\n int L = l;\n int R = r;\n\n evaluate(l, r);\n\n ++r;\n\n while(l < r){\n if(r & 1){\n --r;\n lazy[r] = h(lazy[r], x);\n }\n r >>= 1;\n\n if(l & 1){\n lazy[l] = h(lazy[l], x);\n ++l;\n }\n l >>= 1;\n }\n\n while(L >>= 1, R >>= 1, L){\n evaluate(L << 1);\n evaluate((L << 1) | 1);\n node[L] = f(node[L << 1], node[(L << 1) | 1]);\n\n evaluate(R << 1);\n evaluate((R << 1) | 1);\n node[R] = f(node[R << 1], node[(R << 1) | 1]);\n }\n\n return;\n }\n\n T get(int l, int r){\n l += n;\n r += n - 1;\n\n evaluate(l, r);\n\n ++r;\n\n T res = id1;\n while(l < r){\n if(r & 1){\n --r;\n evaluate(r);\n res = f(res, node[r]);\n }\n r >>= 1;\n\n if(l & 1){\n evaluate(l);\n res = f(res, node[l]);\n ++l;\n }\n l >>= 1;\n }\n\n return res;\n }\n};\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nbool chmin(T& a, T b){\n if(b < a){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n\n int n;\n cin >> n;\n\n string s, t;\n cin >> s >> t;\n\n vector< vector<int> > v(26);\n rep(i, n){\n v[t[i] - 'a'].emplace_back(i);\n }\n\n vector< CoordinateCompression<int> > c(26);\n rep(i, 26){\n c[i].build(v[i]);\n }\n\n vector< LazySegmentTree<mint> > seg(26);\n rep(i, 26){\n seg[i].init(c[i].size(), [](mint l, mint r){ return l + r; }, [](mint l, mint r){ return l + r; },\n [](mint l, mint r){ return l + r; }, mint(0), mint(0), [](mint x, int len){ return x * len; });\n }\n\n seg[t[0] - 'a'].update(0, 1, mint(1));\n\n rep(i, n){\n int l = c[s[i] - 'a'].get(i);\n if(s[i] == t[i]){\n ++l;\n }\n if(l == c[s[i] - 'a'].size()){\n continue;\n }\n\n seg[s[i] - 'a'].update(l, c[s[i] - 'a'].size(), seg[t[i] - 'a'].get(c[t[i] - 'a'].get(i), c[t[i] - 'a'].get(i) + 1));\n }\n\n cout << seg[t[n - 1] - 'a'].get(c[t[n - 1] - 'a'].size() - 1, c[t[n - 1] - 'a'].size()) << endl;\n\n cout << flush;\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 11344, "score_of_the_acc": -0.8592, "final_rank": 18 }, { "submission_id": "aoj_0386_4061566", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nll my_pow(ll x, ll n) {\n if (n == 0) return 1;\n if (n % 2 == 0) return my_pow(x * x, n / 2);\n return x * my_pow(x, n - 1);\n}\n\nint main() {\n int N;\n cin >> N;\n string s, t;\n cin >> s >> t;\n ll mod = my_pow(10, 9) + 7;\n ll d[N][26]{};\n d[0][s[0] - 'a'] = 1;\n for (int i = 1; i < N; i++) {\n for (int j = 0; j < 26; j++) {\n d[i][j] = d[i - 1][j];\n }\n d[i][s[i] - 'a'] += d[i][t[i] - 'a'];\n d[i][s[i] - 'a'] %= mod;\n }\n cout << d[N - 2][t[N - 1] - 'a'] << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 23652, "score_of_the_acc": -0.3661, "final_rank": 12 }, { "submission_id": "aoj_0386_3866716", "code_snippet": "#include <iostream>\n#include <math.h>\n#include <algorithm>\n#include <string>\nusing namespace std;\n\nint change(char c) {\n\tif ('a' <= c && c <= 'z') {\n\t\treturn (c - 'a');\n\t}\n}\nlong long dp[100000][26]; //j番目までの星で、入り口がiの星へのアクセスは何通りか\nint main() {\n\tint N;\n\tcin >> N;\n\tstring s,t;\n\tcin >> s >> t;\n\tfor (int j = 0; j < N; j++) {\n\t\tif (j == 0) {\n\t\t\tfor (int i = 0; i < 26; i++) {\n\t\t\t\tif (change(s[0]) == i) {\n\t\t\t\t\tdp[0][i] = 1;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tdp[0][i] = 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tfor (int i = 0; i < 26; i++) {\n\t\t\t\tdp[j][i] = dp[j - 1][i]%1000000007;\n\t\t\t}\n\t\t\tdp[j][change(s[j])] = (dp[j][change(s[j])]+dp[j - 1][change(t[j])])%1000000007;\n\t\t}\n\t}\n\tcout << dp[N-2][change(t[N-1])] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 23616, "score_of_the_acc": -0.3655, "final_rank": 11 }, { "submission_id": "aoj_0386_3865160", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,N) for(int (i)=0;(i) < (N); (i)++)\n#define all(V) V.begin(), V.end()\nusing i64 = int_fast64_t;\nusing P = pair<i64,i64>;\nusing uset = unordered_set<int>;\n\nint main(){\n int N;\n cin >> N;\n string S,T;\n cin >> S >> T;\n\n vector<vector<int>> dp(100100, vector<int>(27, 0));\n dp[0][S[0] - 'a'] = 1;\n for(int i = 1; i < N; i++){\n for(char c = 'a'; c <= 'z'; c++){\n dp[i][c - 'a'] = (dp[i-1][c - 'a'] % 1000000007);\n }\n if(i == N -1) continue;\n ((dp[i][S[i] - 'a'] += dp[i-1][T[i] -'a']) %= 1000000007);\n }\n\n cout << dp[N - 1][T[N-1] - 'a'] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 17964, "score_of_the_acc": -0.2639, "final_rank": 9 }, { "submission_id": "aoj_0386_3865131", "code_snippet": "#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n#include <regex>\n#define ull unsigned long long\n#define REP(i,n) for(int i = 0; i < n; i++)\n#define FOR(i,j,n) for(int i = j; i < n; i++)\n#define RFOR(i,j,n) for(int i = j-1; i >= n; i--)\n#define PREC(n) fixed << setprecision(n)\n#define print_array(v) REP(__k, v.size()) { cerr << v[__k]; if(__k != v.size()-1) cerr << \" \"; else cerr << endl; }\nusing namespace std;\n\nint d(char c) { return c - 'a'; }\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tconst ull MOD = 1000000007;\n\n\tint N;\n\tstring s, t;\n\tcin >> N >> s >> t;\n\n\tvector<vector<ull> > dp(N, vector<ull>(26, 0));\n\tdp[0][d(s[0])] = 1;\n\tFOR(i, 1, N) {\n\t\tdp[i][d(s[i])] += dp[i-1][d(t[i])]; // 来られるなら追加する\n\t\tdp[i][d(s[i])] %= MOD;\n\t\t// cerr << d('z') << endl;\n\t\tREP(j, 26) {\n\t\t\tdp[i][j] += dp[i-1][j]; // 継承\n\t\t\tdp[i][j] %= MOD;\n\t\t}\n\t}\n\tcout << dp[N-2][d(t[N-1])] << endl;\n\t//REP(i, N) print_array(dp[i]);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 27156, "score_of_the_acc": -0.4291, "final_rank": 15 }, { "submission_id": "aoj_0386_3865120", "code_snippet": "#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n#include <regex>\n#define ull unsigned long long\n#define REP(i,n) for(int i = 0; i < n; i++)\n#define FOR(i,j,n) for(int i = j; i < n; i++)\n#define RFOR(i,j,n) for(int i = j-1; i >= n; i--)\n#define PREC(n) fixed << setprecision(n)\n#define print_array(v) REP(__k, v.size()) { cerr << v[__k]; if(__k != v.size()-1) cerr << \" \"; else cerr << endl; }\nusing namespace std;\n\nint d(char c) { return c - 'a'; }\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tconst ull MOD = 1000000007;\n\n\tint N;\n\tstring s, t;\n\tcin >> N >> s >> t;\n\n\tvector<vector<ull> > dp(N, vector<ull>('z'-'a', 0));\n\tdp[0][d(s[0])] = 1;\n\tFOR(i, 1, N) {\n\t\tdp[i][d(s[i])] += dp[i-1][d(t[i])]; // 来られるなら追加する\n\t\tdp[i][d(s[i])] %= MOD;\n\t\t// cerr << d('z') << endl;\n\t\tREP(j, d('z')) {\n\t\t\tdp[i][j] += dp[i-1][j]; // 継承\n\t\t\tdp[i][j] %= MOD;\n\t\t}\n\t}\n\tcout << dp[N-2][d(t[N-1])] << endl;\n\t//REP(i, N) print_array(dp[i]);\n}", "accuracy": 0.8333333333333334, "time_ms": 10, "memory_kb": 25700, "score_of_the_acc": -0.403, "final_rank": 20 }, { "submission_id": "aoj_0386_3857385", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\nusing uint = unsigned int;\nusing int64 = long long;\nusing i64 = int64;\nusing uint64 = unsigned long long;\nusing vint = vector<int>;\nusing vint64 = vector<int64>;\ntemplate<typename T>\nusing p_que = priority_queue<T>;\n#define rep(i,N) for(int i=0;i<(int)(N);++i)\n#define rep1(i,N) for(int i=1;i<=(int)(N);++i)\n#define fs first\n#define sc second\n#define eb emplace_back\n#define all(x) x.begin(),x.end()\n\ntemplate<typename T>\nvector<T> make_v(size_t a, T b) { return vector<T>(a, b); }\ntemplate<typename... Ts>\nauto make_v(size_t a, Ts... ts) {\n\treturn vector<decltype(make_v(ts...))>(a, make_v(ts...));\n}\n\ntemplate<class T> ostream& operator<<(ostream& os, const vector<T>& v) {\n\tos << \"[\";\n\tfor (auto& e : v) os << e << \", \";\n\treturn os << \"]\";\n}\n\ntemplate<class T, class U> ostream& operator<<(ostream& os, const pair<T, U> p) {\n\treturn os << \"P(\" << p.first << \", \" << p.second << \")\";\n}\n\ntemplate<class T, class U> ostream& operator<<(ostream& os, const map<T, U>& mp) {\n\tos << \"{\";\n\tfor (auto& e : mp) os << e << \" \";\n\treturn os << \"}\";\n}\n\nvoid Main();\nsigned main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tcout << fixed << setprecision(20);\n\tMain();\n}\n\n/* Cut from here! */\n\ntemplate <uint mod> struct ModInt {\n\tuint x;\n\tModInt(int64_t y = 0) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n\tModInt& operator+=(const ModInt& p) {\n\t\tif ((x += p.x) >= mod) x -= mod;\n\t\treturn *this;\n\t}\n\tModInt& operator-=(const ModInt& p) {\n\t\tx = (int)(1ll * x * p.x % mod);\n\t\treturn *this;\n\t}\n\tModInt& operator/=(const ModInt& p) {\n\t\t*this *= p.inverse();\n\t\treturn *this;\n\t}\n\tModInt operator-() const {\n\t\treturn ModInt(-x);\n\t}\n\tModInt operator+(const ModInt& p) const {\n\t\treturn ModInt(*this) += p;\n\t}\n\tModInt operator-(const ModInt& p) const {\n\t\treturn ModInt(*this) -= p;\n\t}\n\tModInt operator*(const ModInt& p) const {\n\t\treturn ModInt(*this) *= p;\n\t}\n\tModInt operator/(const ModInt& p) const {\n\t\treturn ModInt(*this) /= p;\n\t}\n\tbool operator==(const ModInt& p) const {\n\t\treturn x == p.x;\n\t}\n\tbool operator!=(const ModInt& p) const {\n\t\treturn x != p.x;\n\t}\n\tModInt inverse() const {\n\t\tint a = x, b = mod, u = 1, v = 0, t;\n\t\twhile (b > 0) {\n\t\t\tt = a / b;\n\t\t\tswap(a -= t * b, b);\n\t\t\tswap(u -= t * v, v);\n\t\t}\n\t\treturn ModInt(u);\n\t}\n\tModInt pow(int64_t n) const {\n\t\tModInt ret(1), mul(x);\n\t\twhile (n > 0) {\n\t\t\tif (n & 1) ret *= mul;\n\t\t\tmul *= mul;\n\t\t\tn >>= 1;\n\t\t}return ret;\n\t}\n\tfriend ostream& operator<<(ostream& os, const ModInt& p) {\n\t\treturn os << p.x;\n\t}\n};\n\n\n//#define int long long\nconst uint MOD = 1e9 + 7;\n\nvoid Main() {\n\tint N; cin >> N;\n\tstring s, t; cin >> s >> t;\n\n\tusing mint = ModInt<MOD>;\n\tvector<mint> dp(N);\n\tauto sum = make_v(N, 30, mint(0));\n\n\tdp[0] = 1;\n\tsum[0][s[0] - 'a'] = 1;\n\tfor (int i = 1; i < N; ++i) {\n\t\tchar c = t[i];\n\t\tdp[i] += sum[i - 1][c - 'a'];\n\t\tchar e = s[i];\n\t\tsum[i][e - 'a'] += dp[i];\n\t\tfor (char ch = 'a'; ch <= 'z'; ++ch) {\n\t\t\tsum[i][ch - 'a'] += sum[i - 1][ch - 'a'];\n\t\t}\n\t}\n\n\tcout << dp[N - 1] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 18200, "score_of_the_acc": -0.2681, "final_rank": 10 }, { "submission_id": "aoj_0386_3855221", "code_snippet": "#pragma GCC target(\"sse,sse2,sse3,sse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"Ofast\")\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\n\nll mod = 1e9+7;\n\nint main(){\n int N;cin >> N;\n string s,t;cin >> s >> t;\n map<char, ll> mp;\n mp[s.front()]++;\n for(int i = 1;i < N;i++){\n if(i == N-1 && s[i] && t[i])break;\n mp[s[i]] %= mod;\n mp[t[i]] %= mod;\n mp[s[i]] += mp[t[i]];\n mp[s[i]] %= mod;\n }\n cout<<mp[t.back()] % mod<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0387_cpp
Taxi PCK Taxi in Aizu city, owned by PCK company, has adopted a unique billing system: the user can decide the taxi fare. Today as usual, many people are waiting in a queue at the taxi stand in front of the station. In front of the station, there are $N$ parking spaces in row for PCK taxis, each with an index running from $1$ to $N$. Each of the parking areas is occupied by a taxi, and a queue of potential passengers is waiting for the ride. Each one in the queue has his/her own plan for how much to pay for the ride. To increase the company’s gain, the taxi driver is given the right to select the passenger who offers the highest taxi fare, rejecting others. The driver in the $i$-th parking space can perform the following actions any number of times in any sequence before he finally selects a passenger and starts driving. Offer a ride to the passenger who is at the head of the $i$-th parking space’s queue. Reject to offer a ride to the passenger who is at the head of the $i$-th parking space’s queue. The passenger is removed from the queue. Move to the $i + 1$-th parking area if it is empty. If he is in the $N$-th parking area, he leaves the taxi stand to cruise the open road. A preliminary listening is made as to the fare the users offer. Your task is to maximize the sales volume of PCK Taxi in reference to the table of offered fares. A taxi cannot accommodate more than one passenger. Given the number of taxi parking spaces and information regarding the persons waiting in the parking areas, calculate the maximum possible volume of sales. Input The input is given in the following format. $N$ $s_1$ $s_2$ $...$ $s_N$ The first line provides the number of taxi parking areas $N$ ($1 \leq N \leq 300,000$). Each of the subsequent $N$ lines provides information on the customers queueing in the $i$-th taxi parking area in the following format: $M$ $c_1$ $c_2$ ... $c_M$ The first integer $M$ ($1 \leq M \leq 300,000$) indicates the number of customers in the queue, and the subsequent array of integers $c_j$ ($1 \leq c_j \leq 10,000$) indicates the fare the $j$-th customer in the queue is willing to pay. The total number of customers in the taxi stand is equal to or less than $300,000$. Output Output the maximum volume of sales. Sample Input 3 3 8 10 1 4 7 1 2 15 3 11 8 19 Sample Output 45
[ { "submission_id": "aoj_0387_10876661", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tlong long n,m,c,i,j,sum=0;\n\tpriority_queue<int,vector<int>,greater<int>> que;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>m;\n\t\tfor(j=0;j<m;j++){\n\t\t\tcin>>c;\n\t\t\tque.push(c);\n\t\t\tif(j!=0) que.pop();\n\t\t}\n\t}\n\tfor(i=0;i<n;i++){\n\t\tsum+=que.top();\n\t\tque.pop();\n\t}\n\tcout<<sum<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5164, "score_of_the_acc": -0.2428, "final_rank": 2 }, { "submission_id": "aoj_0387_10874923", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nsigned main(){\n int N;\n cin>>N;\n multiset<int> s;\n for(int i=1;i<=N;i++){\n int n;\n cin>>n;\n vector<int> C(n);\n for(int j=0;j<n;j++) cin>>C[j];\n sort(C.rbegin(),C.rend());\n s.insert(C[0]);\n int nd = 1;\n while(nd != C.size() && *s.begin() < C[nd]){\n s.insert(C[nd]);\n nd++;\n int a = *s.begin();\n s.erase(s.find(a));\n }\n }\n int ans = 0;\n for(int x:s) ans += x;\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 17372, "score_of_the_acc": -0.8399, "final_rank": 13 }, { "submission_id": "aoj_0387_10874912", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nconstexpr int MOD = 1000000007;\n\nint main() {\n int N; scanf(\"%d\", &N);\n vector<vector<int>> A(N);\n rep (i, N) {\n int M; scanf(\"%d\", &M);\n A[i].resize(M);\n for (int& a : A[i]) scanf(\"%d\", &a);\n }\n priority_queue<int> que;\n ll ans = 0;\n rrep (i, N) {\n for (auto a : A[i]) que.push(a);\n if (!que.empty()) {\n ans += que.top(); que.pop();\n }\n }\n printf(\"%lld\\n\", ans);\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 19208, "score_of_the_acc": -0.4653, "final_rank": 6 }, { "submission_id": "aoj_0387_10874681", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\nusing namespace std;\nusing ll = long long;\nint main() {\n\tint N;cin >> N;\n\tvector<vector<ll>> C(N);\n\tfor (int i = 0;i < N;i++) {\n\t\tint m;cin >> m;\n\t\tfor (int j = 0;j < m;j++) {\n\t\t\tll x;cin >> x;C[i].push_back(x);\n\t\t}\n\t}\n\tpriority_queue<ll> pq;\n\tll res = 0;\n\tfor (int i = N-1;i >= 0;i--) {\n\t\tfor (auto v : C[i]) pq.push(v);\n\t\tres += pq.top();\n\t\tpq.pop();\n\t}\n\tcout << res << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 19780, "score_of_the_acc": -0.5773, "final_rank": 9 }, { "submission_id": "aoj_0387_10873208", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int N;\n cin >> N;\n \n vector<vector<int>> C(N);\n rep(i, 0, N) {\n int M;\n cin >> M;\n rep(j, 0, M) {\n int c;\n cin >> c;\n C[i].push_back(c);\n }\n }\n \n reverse(all(C));\n \n priority_queue<int> que;\n ll ans = 0;\n rep(i, 0, N) {\n for (int c : C[i]) que.push(c);\n ans += que.top();\n que.pop();\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 19384, "score_of_the_acc": -0.4705, "final_rank": 7 }, { "submission_id": "aoj_0387_10872573", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\nusing pii = pair<int, int>;\ntemplate<class T> bool chmin(T &a, T b) {if(a>b) {a=b;return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a<b) {a=b;return true;} return false;}\nconstexpr int INF = 1e9;\nconstexpr ll Mod = 1'000'000'007;\n#define rep(i, s, n) for (int i = (int)(s); i < (int)(n); i++)\n#define rrep(i, s, n) for (int i = (int)(n)-1; i >= (int)(s); i--)\n\ntemplate <class S, S (*op)(S, S), S (*e)(), class F, S (*mapping)(F, S),\n F (*composition)(F, F), F (*id)()>\nstruct lazysegtree {\n private:\n int n, lg2, sz;\n std::vector<S> d;\n std::vector<F> lz;\n\n void update(int i) {\n d[i] = op(d[2 * i], d[2 * i + 1]);\n }\n\n void all_apply(int i, F f) {\n d[i] = mapping(f, d[i]);\n if (i < sz) lz[i] = composition(f, lz[i]);\n }\n\n void push(int i) {\n all_apply(2 * i, lz[i]);\n all_apply(2 * i + 1, lz[i]);\n lz[i] = id();\n }\n\n public:\n lazysegtree(int _n) : lazysegtree(std::vector<S>(_n, e())) {}\n\n lazysegtree(const std::vector<S> &v) : n(v.size()) {\n lg2 = 0;\n while ((1 << lg2) < n) lg2++;\n sz = 1 << lg2;\n d = std::vector<S>(2 * sz, e());\n lz = std::vector<F>(2 * sz, id());\n for (int i = 0; i < n; i++) d[sz + i] = v[i];\n for (int i = sz - 1; i >= 1; i--) update(i);\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < n);\n p += sz;\n rrep(i, 1, lg2 + 1) push(p >> i);\n d[p] = x;\n rep(i, 1, lg2 + 1) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < n);\n p += sz;\n rrep(i, 1, lg2 + 1) push(p >> i);\n return d[p];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= n);\n if (l == r) return e();\n l += sz;\n r += sz;\n rrep(i, 1, lg2 + 1) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n S sml = e(), smr = e();\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n\n return op(sml, smr);\n }\n\n S all_prod() {\n return d[1];\n }\n\n void apply(int p, F f) {\n assert(0 <= p && p < n);\n p += sz;\n rrep(i, 1, lg2 + 1) push(p >> i);\n d[p] = mapping(f, d[p]);\n rep(i, 1, lg2 + 1) update(p >> i);\n }\n\n void apply(int l, int r, F f) {\n assert(0 <= l && l <= r && r <= n);\n if (l == r) return;\n l += sz;\n r += sz;\n rrep(i, 1, lg2 + 1) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n {\n int l2 = l, r2 = r;\n while (l < r) {\n if (l & 1) all_apply(l++, f);\n if (r & 1) all_apply(--r, f);\n l >>= 1;\n r >>= 1;\n }\n l = l2;\n r = r2;\n }\n\n rep(i, 1, lg2 + 1) {\n if (((l >> i) << i) != l) update(l >> i);\n if (((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n\n template <class G> int max_right(int l, G g) {\n assert(0 <= l && l <= n);\n assert(g(e()));\n if (l == n) return n;\n l += sz;\n for (int i = lg2; i >= 1; i--) push(l >> i);\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!g(op(sm, d[l]))) {\n while (l < sz) {\n push(l);\n l = (2 * l);\n if (g(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - sz;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return n;\n }\n\n template <class G> int min_left(int r, G g) {\n assert(0 <= r && r <= n);\n assert(g(e()));\n if (r == 0) return 0;\n r += sz;\n for (int i = lg2; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < sz) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - sz;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n};\n\nusing S = int;\nusing F = int;\nS op(S a, S b){ return max(a, b); }\nS e(){ return -INF; }\nS mapping(F f, S x){ return x+f; }\nF composition(F f, F g){ return f+g; }\nF id(){ return 0; }\n\nint main() {\n int N; cin >> N;\n vi M(N);\n vector<priority_queue<int>> c(N);\n for (int i = 0; i < N; i++) {\n cin >> M[i];\n for (int j = 0; j < M[i]; j++) {\n int C; cin >> C;\n c[i].push(C);\n }\n }\n lazysegtree<S, op, e, F, mapping, composition, id> Seg(N);\n for (int i = 0; i < N; i++) Seg.set(i, -(i+1));\n priority_queue<pii> Q;\n for (int i = 0; i < N; i++) {\n if (!c[i].empty()) {\n Q.push({c[i].top(), i});\n c[i].pop();\n }\n }\n ll ans = 0;\n int cnt = 0;\n while (!Q.empty() && cnt != N) {\n int A = Q.top().first, B = Q.top().second;\n Q.pop();\n if (Seg.prod(B, N) != 0) {\n cnt++;\n ans += A;\n Seg.apply(B, N, 1);\n if (!c[B].empty()) {\n Q.push({c[B].top(), B});\n c[B].pop();\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 39012, "score_of_the_acc": -1.8095, "final_rank": 17 }, { "submission_id": "aoj_0387_10870856", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<(ll)N;i++)\n#define all(X) X.begin(),X.end()\n#define pb push_back\ntemplate<typename T>\nclass RSQ {//一点更新区間sum\n public:\n ll size=1;\n vector<T>dataS;\n\n void init(int N){\n while(size<=N)size=size*2;\n dataS.assign(size*2,0);\n }\n\n void update(int p,T x){\n p=p+size;\n dataS[p]=x;\n while(p>1){\n p>>=1;\n dataS[p]=dataS[p*2]+dataS[p*2+1];\n }\n }\n\n T ISum(int l,int r,int a,int b,int u){\n if(r<=a||b<=l)return 0;\n if(l<=a&&b<=r)return dataS[u];\n int m=(a+b)>>1;\n T L=ISum(l,r,a,m,u*2);\n T R=ISum(l,r,m,b,u*2+1);\n return L+R;\n }\n T Sum(int l,int r){return ISum(l,r,0,size,1);}\n};\n\nint main(){\n int N;cin>>N;\n priority_queue<pair<ll,ll>>Q;\n rep(i,N){\n int M;cin>>M;\n rep(j,M){\n ll x;cin>>x;\n Q.push({x,i});\n }\n }\n RSQ <ll>seg;\n seg.init(N);\n ll ans = 0;\n int ct = 0;\n set<ll>rest={-1,N};\n rep(i,N)rest.insert(i);\n while(!Q.empty()&&ct<N){\n auto [x,i]=Q.top();\n Q.pop();\n if(seg.Sum(0,i+1)<i+1){\n ans += x;\n auto it = rest.lower_bound(i);\n if(*it>i)it--;\n ll v = *it;\n if(v==-1||v==N)continue;\n rest.erase(v);\n seg.update(v,1);\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 31420, "score_of_the_acc": -1.7768, "final_rank": 16 }, { "submission_id": "aoj_0387_10857094", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nint main() {\n int n; cin >> n;\n vector<vector<int>> c(n);\n rep(i, n) {\n int m; cin >> m;\n c[i].resize(m);\n rep(j, m) cin >> c[i][j];\n }\n reverse(c.begin(), c.end());\n ll ans = 0;\n multiset<int> st;\n rep(i, n) {\n rep(j, c[i].size()) st.insert(c[i][j]);\n ans += *st.rbegin();\n st.erase(prev(st.end()));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 19780, "score_of_the_acc": -0.7202, "final_rank": 11 }, { "submission_id": "aoj_0387_10853326", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n//#pragma GCC optimize (\"-O3\") \n#ifdef YANG33\n#include \"mydebug.hpp\"\n#else\n#define DD(x) \n#endif\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- __MAKE_TIME__ Problem: __PROBLEM__ / Link: __CONTEST_URL__ ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\n\n\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N; cin >> N;\n\tVVL cs(N);\n\tFOR(i, 0, N) {\n\t\tint M; cin >> M;\n\t\tFOR(j, 0, M) {\n\t\t\tLL c; cin >> c;\n\t\t\tcs[i].push_back(c);\n\t\t}\n\t}\n\n\tLL ans = 0;\n\tpriority_queue<LL>pq;\n\tFORR(i, N - 1, 0 - 1) {\n\t\tFOR(j, 0, SZ(cs[i])) {\n\t\t\tpq.push(cs[i][j]);\n\t\t}\n\t\tans += pq.top();\n\t\tpq.pop();\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 19472, "score_of_the_acc": -0.4254, "final_rank": 5 }, { "submission_id": "aoj_0387_10777792", "code_snippet": "#ifdef GOHACHI\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\ntemplate<class T> using VC = vector<T>;\ntemplate<class T,class TT> using P = pair<T,TT>;\ntemplate<class T,class TT,class TTT> using TP = tuple<T,TT,TTT>;\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> using pqR = priority_queue<T>;\n#define F first\n#define S second\n#define INF LLONG_MAX\n#define MOD 998244353\nll DX[4] = { 0 , 1 , 0 , -1 };\nll DY[4] = { -1 , 0 , 1 , 0 };\n#define st(x,y) sort(x,x+y)\n#define stR(x,y) sort(x,x+y,greater<ll>())\n#define ST(x) sort(x.begin(),x.end())\n#define STR(x) sort(x.rbegin(),x.rend())\n#define rep(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define repR(i,a,b) for(ll i=(ll)(a);i>=(ll)(b);i--)\n#define rev(x,y) reverse(x,x+y)\n#define REV(x) reverse(x.begin(),x.end())\n#define dec(x) fixed << setprecision(x)\n#define POW(x,y) (ll)pow(x,y)\nll s;\nvoid solve() {\n\tll n; cin>>n;\n\tpq<ll> pq;\n\trep(t,1,n+1) {\n\t\tll m; cin>>m;\n\t\tll c;\n\t\trep(i,0,m) { cin>>c;\n\t\t\tpq.push(c);\n\t\t\tif (i!=0) pq.pop();\n\t\t}\n\t}\n\trep(t,0,n) { s+=pq.top(); pq.pop(); }\n\tcout<<s<<'\\n';\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0); cout.tie(0);\n int T=1;\n while(T--) solve();\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8112, "score_of_the_acc": -0.139, "final_rank": 1 }, { "submission_id": "aoj_0387_10777732", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n\tint n,m,c,i,j,sum=0;\n\tpriority_queue<int,vector<int>,greater<int>> que;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>m;\n\t\tfor(j=0;j<m;j++){\n\t\t\tcin>>c;\n\t\t\tque.push(c);\n\t\t}\n\t\tfor(j=0;j<m-1;j++) que.pop();\n\t}\n\tfor(i=0;i<n;i++){\n\t\tsum+=que.top();\n\t\tque.pop();\n\t}\n\tcout<<sum<<endl;\n\treturn 0;\n}", "accuracy": 0.8666666666666667, "time_ms": 80, "memory_kb": 5004, "score_of_the_acc": -0.2381, "final_rank": 18 }, { "submission_id": "aoj_0387_9634505", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing i64 = long long;\n\n#define rep(i, a, b) for (int i = (a); i < (b); i++)\n#define repi(i, a, b) for (int i = (a) - 1; i >= (b); --i)\n\nint main() {\n int n;\n cin >> n;\n vector<vector<int>> s(n);\n rep (i, 0, n) {\n int m;\n cin >> m;\n s[i].resize(m);\n rep (j, 0, m) {\n cin >> s[i][j];\n }\n }\n i64 sum = 0;\n multiset<int> st;\n repi (i, n, 0) {\n rep (j, 0, s[i].size()) st.insert(s[i][j]);\n sum += *rbegin(st);\n st.erase(prev(end(st)));\n }\n cout << sum << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 19364, "score_of_the_acc": -0.8508, "final_rank": 14 }, { "submission_id": "aoj_0387_9633355", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\t#define int long long\n\tint n;\n\tcin >>n;\n\tvector<vector<int>>s(n);\n\tfor(int i = 0;i < n;i++){\n\t\tint m;\n\t\tcin >>m;\n\t\ts[i].resize(m);\n\t\tfor(int j = 0;j < m;j++){\n\t\t\tcin >>s[i][j];\n\t\t}\n\t}\n\tmultiset<int>p;\n\tint ans = 0;\n\tfor(int i = n-1;i >= 0;i--){\n\t\tfor(int j = 0;j < s[i].size();j++){\n\t\t\tp.insert(s[i][j]);\n\t\t}\n\t\t// cout <<\"[\";\n\t\t// for(auto i:p){\n\t\t// \tcout <<i<<\" \";\n\t\t// }\n\t\t// cout <<\"]\\n\";\n\t\tauto itr = p.end();\n\t\titr--;\n\t\tans += *itr;\n\t\tp.erase(itr);\n\t}\n\tcout <<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 19708, "score_of_the_acc": -0.9086, "final_rank": 15 }, { "submission_id": "aoj_0387_9633353", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tint n;\n\tcin >>n;\n\tvector<vector<int>>s(n);\n\tfor(int i = 0;i < n;i++){\n\t\tint m;\n\t\tcin >>m;\n\t\ts[i].resize(m);\n\t\tfor(int j = 0;j < m;j++){\n\t\t\tcin >>s[i][j];\n\t\t}\n\t}\n\tmultiset<int>p;\n\tint ans = 0;\n\tfor(int i = n-1;i >= 0;i--){\n\t\tfor(int j = 0;j < s[i].size();j++){\n\t\t\tp.insert(s[i][j]);\n\t\t}\n\t\t// cout <<\"[\";\n\t\t// for(auto i:p){\n\t\t// \tcout <<i<<\" \";\n\t\t// }\n\t\t// cout <<\"]\\n\";\n\t\tauto itr = p.end();\n\t\titr--;\n\t\tans += *itr;\n\t\tp.erase(itr);\n\t}\n\tcout <<ans<<\"\\n\";\n}", "accuracy": 0.8666666666666667, "time_ms": 120, "memory_kb": 19376, "score_of_the_acc": -0.8512, "final_rank": 20 }, { "submission_id": "aoj_0387_9633326", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug_print.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N;\n cin >> N;\n vector<int> L(N);\n vector<vector<int>> A(N);\n // 客の価値と i の pair\n vector<pair<int, int>> B;\n for (int i = 0; i < N; i++) {\n cin >> L[i];\n A[i].resize(L[i]);\n for (int j = 0; j < L[i]; j++) {\n cin >> A[i][j];\n B.emplace_back(A[i][j], i);\n }\n }\n\n ll ans = 0;\n // 後ろのタクシーから客を決めていく\n priority_queue<int> que;\n for (int i = N - 1; i >= 0; i--) {\n // i 番目にタクシー乗り場に乗っている人を que に追加\n for (int j = 0; j < L[i]; j++) que.emplace(A[i][j]);\n // タクシー i は que から最大の客を乗せる\n int max_value = que.top();\n que.pop();\n ans += max_value;\n }\n\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 23760, "score_of_the_acc": -0.5991, "final_rank": 10 }, { "submission_id": "aoj_0387_9633319", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug_print.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N;\n cin >> N;\n vector<int> L(N);\n vector<vector<int>> A(N);\n // 客の価値と i の pair\n vector<pair<int, int>> B;\n for (int i = 0; i < N; i++) {\n cin >> L[i];\n A[i].resize(L[i]);\n for (int j = 0; j < L[i]; j++) {\n cin >> A[i][j];\n B.emplace_back(A[i][j], i);\n }\n }\n\n int ans = 0;\n // 後ろのタクシーから客を決めていく\n priority_queue<int> que;\n for (int i = N - 1; i >= 0; i--) {\n // i 番目にタクシー乗り場に乗っている人を que に追加\n for (int j = 0; j < L[i]; j++) que.emplace(A[i][j]);\n // タクシー i は que から最大の客を乗せる\n int max_value = que.top();\n que.pop();\n ans += max_value;\n }\n\n cout << ans << '\\n';\n}", "accuracy": 0.8666666666666667, "time_ms": 40, "memory_kb": 24516, "score_of_the_acc": -0.6214, "final_rank": 19 }, { "submission_id": "aoj_0387_9613184", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n17:29~17:43\n6:25~\n*/\n\nsigned main(){\n\tint n;cin>>n;\n\tpriority_queue<int> pq;\n\tfor(int i=1;i<=n;i++){\n\t\tint m;cin>>m;\n\t\twhile(m--){\n\t\t\tint x;cin>>x;\n\t\t\tpq.push(-x);\n\t\t}\n\t\twhile(pq.size()>i)pq.pop();\n\t}\n\tint ans=0;\n\twhile(pq.size()){\n\t\tans-=pq.top();pq.pop();\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 8436, "score_of_the_acc": -0.339, "final_rank": 4 }, { "submission_id": "aoj_0387_9610250", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int n;\n cin >> n;\n vector<vector<int>> a(n);\n rep(i,n){\n int m;\n cin >> m;\n a[i].resize(m);\n rep(j,m) cin >> a[i][j];\n }\n\n reverse(a.begin(),a.end());\n\n priority_queue<int> pq;\n ll ans = 0;\n rep(i,n){\n for(int e:a[i]) pq.push(e);\n\n ans += pq.top();\n pq.pop();\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 19408, "score_of_the_acc": -0.4712, "final_rank": 8 }, { "submission_id": "aoj_0387_9480315", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int> v[300000];\nint m[300000];\nint main(void)\n{\n\tint n,i,j,c;\n\tlong long sum;\n\tpriority_queue<int> qu;\n\tcin >>n;\n\tfor(i=0;i<n;i++)\t{\n\t\tcin >>m[i];\n\t\tfor(j=0;j<m[i];j++)\t{\n\t\t\tcin >>c;\n\t\t\tv[i].push_back(c);\n\t\t}\n\t}\n\tsum=0;\n\tfor(i=n-1;i>=0;i--)\t{\n\t\tfor(j=0;j<m[i];j++)\t{\n\t\t\tqu.push(v[i][j]);\n\t\t}\n\t\tsum+=qu.top();\n\t\tqu.pop();\n\t}\n\tcout <<sum<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 20616, "score_of_the_acc": -0.7924, "final_rank": 12 }, { "submission_id": "aoj_0387_9023454", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n priority_queue<long long> que;\n for(int i = 0; i < N; i++) {\n int M, s;\n cin >> M;\n for(int j = 0; j < M; j++) {\n cin >> s;\n que.push(-s);\n }\n while(int(que.size()) > i+1) que.pop();\n }\n long long ans = 0;\n while(!que.empty()) {\n ans += -que.top();\n que.pop();\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7888, "score_of_the_acc": -0.3229, "final_rank": 3 } ]
aoj_0388_cpp
Points on a Straight Line The university of A stages a programming contest this year as has been the case in the past. As a member of the team in charge of devising the problems, you have worked out a set of input data for a problem, which is an arrangement of points on a 2D plane in the coordinate system. The problem requires that any combination of these points greater than or equal to $K$ in number must not align on a line. You want to confirm that your data satisfies this requirement. Given the number of points $K$ and their respective 2D coordinates, make a program to check if any combination of points greater or equal to $K$ align on a line. Input The input is given in the following format. $N$ $K$ $x_1$ $y_1$ $x_2$ $y_2$ $...$ $x_N$ $y_N$ The first line provides the number of points $N$ ($3 \leq N \leq 3000$) on the 2D coordinate system and an integer $K$ ($3 \leq K \leq N$). Each of the subsequent lines provides the $i$-th coordinate $x_i,y_i$ ($0 \leq x_i,y_i \leq 10000$) as integers. None of these coordinates coincide, i.e., if $i \ne j$, then $x_i \ne x_j$ or $y_i \ne y_j$. Output Output 1 if any combination of points greater or equal to $K$ aligns on a line, or 0 otherwise. Sample Input 1 5 4 0 0 1 0 1 1 0 1 2 2 Sample Output 1 0 Sample Input 2 7 5 0 0 1 0 1 1 0 1 2 0 3 0 4 0 Sample Output 2 1
[ { "submission_id": "aoj_0388_10874948", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nint f(int a, int b){\n if(a < b) swap(a,b);\n int x,y;\n if(b == 0){\n return a;\n }\n else{\n return f(b,a%b);\n }\n}\nsigned main(){\n int N,K;\n cin>>N>>K;\n vector<int> X(N), Y(N);\n for(int i=0;i<N;i++) cin>>X[i]>>Y[i];\n int bs = 4000000;\n for(int i=0;i<N;i++){\n unordered_map<int,int> m;\n for(int j=0;j<N;j++)if(i != j){\n int a = X[j]-X[i], b = Y[j]-Y[i];\n if(a == 0) b = 1;\n else if(b == 0) a = 1;\n else{\n if(a < 0){\n a = -a;\n b = -b;\n }\n int t = f(abs(a),abs(b));\n a /= t;\n b /= t;\n }\n m[a*bs+b]++;\n }\n for(auto [a,b]:m)if(b >= K-1){\n cout<<1<<endl;\n return 0;\n }\n }\n cout<<0<<endl;\n}", "accuracy": 1, "time_ms": 1380, "memory_kb": 3612, "score_of_the_acc": -0.7341, "final_rank": 7 }, { "submission_id": "aoj_0388_10874935", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nconstexpr int MOD = 1000000007;\n\nint main() {\n int N, K; scanf(\"%d%d\", &N, &K);\n vector<PLL> A(N);\n rep (i, N) scanf(\"%lld%lld\", &A[i].first, &A[i].second);\n rep (i, N) {\n vector<PLL> B;\n rep (j, i) B.emplace_back(A[j].first - A[i].first, A[j].second - A[i].second);\n for (auto& [x, y] : B) {\n if (x < 0) {\n x = -x;\n y = -y;\n }\n if (x == 0 && y < 0) y = -y;\n }\n sort(all(B), [&](PLL a, PLL b) { return a.first * b.second - a.second * b.first > 0; });\n rep (l, B.size()) {\n int r = l + 1;\n while (r < B.size() && B[l].first * B[r].second - B[r].first * B[l].second == 0) ++r;\n if (r - l >= K - 1) {\n puts(\"1\");\n return 0;\n }\n l = r - 1;\n }\n }\n puts(\"0\");\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3616, "score_of_the_acc": -0.0008, "final_rank": 1 }, { "submission_id": "aoj_0388_10871677", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n// #include<atcoder/all>\n// using mint = atcoder::modint998244353;\nusing ld = long double;\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N,K;\n cin>>N>>K;\n vector<int> X(N),Y(N);\n rep(i,N)cin>>X[i]>>Y[i];\n vector<array<int,3>> A;\n rep(i,N){\n rep(j,i){\n int a=Y[i]-Y[j];\n int b=X[j]-X[i];\n int c=-(X[i]*a+Y[i]*b);\n\n int g=gcd(gcd(a,b),c);\n a/=g;\n b/=g;\n c/=g;\n if(a<0) a*=-1,b*=-1,c*=-1;\n A.push_back({a,b,c});\n }\n }\n sort(all(A));\n int c=0;\n array<int,3> mae={-1,-1,-1};\n for(auto e: A){\n if(mae==e) c++;\n else c=1;\n mae=e;\n if(c>=K*(K-1)/2){\n cout<<1<<\"\\n\";\n return 0;\n }\n }\n cout<<0<<\"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 103204, "score_of_the_acc": -0.818, "final_rank": 10 }, { "submission_id": "aoj_0388_10870890", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(ll i=0;i<(ll)N;i++)\n#define all(X) X.begin(),X.end()\n#define pb push_back\nll gcd(ll a,ll b){\n if(b==0)return a;\n return gcd(b,a%b);\n}\nint main(){\n int N,K;cin>>N>>K;\n unordered_map<ll,int>S;\n vector<int>X(N),Y(N);\n rep(i,N)cin>>X[i]>>Y[i];\n rep(i,N)for(int j = i+1;j<N;j++){\n ll dx = X[i]-X[j];\n ll dy = Y[i]-Y[j];\n int d = gcd(abs(dx),abs(dy));\n dx/=d;dy/=d;\n if(dx<0)dx*=-1,dy*=-1;\n if(dx==0&&dy<0)dy*=-1;\n ll c = Y[i]*dx-X[i]*dy;\n S[dx+dy*20000+c*400000000]++;\n if(K*(K-1)<=S[dx+dy*20000+c*400000000]*2){\n cout<<1<<endl;\n return 0;\n }\n }\n cout<<0<<endl;\n}", "accuracy": 1, "time_ms": 1520, "memory_kb": 190524, "score_of_the_acc": -1.8182, "final_rank": 17 }, { "submission_id": "aoj_0388_10857254", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nstruct frac {\n ll a, b;\n frac(ll _a, ll _b) : a(_a), b(_b) {\n if (b == 0) a = 1;\n else {\n if (b < 0) {\n a *= -1;\n b *= -1;\n }\n ll GCD = gcd(a, b);\n a /= GCD;\n b /= GCD;\n }\n }\n bool operator<(const frac& other) const {\n return a * other.b < other.a * b;\n }\n};\nint main() {\n int n, k; cin >> n >> k;\n vector<pll> ps(n);\n rep(i, n) cin >> ps[i].first >> ps[i].second;\n rep(i, n - 1){\n map<frac, int> mp;\n for (int j = i + 1; j < n; ++j) {\n frac a = frac(ps[j].second - ps[i].second, ps[j].first - ps[i].first);\n if (!mp.count(a))mp[a] = 1;\n mp[a]++;\n }\n for (auto& p : mp) {\n if (p.second >= k) {\n cout << 1 << endl;\n return 0;\n }\n }\n }\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 920, "memory_kb": 3712, "score_of_the_acc": -0.4559, "final_rank": 5 }, { "submission_id": "aoj_0388_10857251", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nstruct frac {\n ll a, b;\n frac(ll _a, ll _b) : a(_a), b(_b) {\n if (b == 0) a = 1;\n else {\n if (b < 0) {\n a *= -1;\n b *= -1;\n }\n ll GCD = gcd(a, b);\n a /= GCD;\n b /= GCD;\n }\n }\n bool operator<(const frac& other) const {\n return a * other.b < other.a * b;\n }\n};\nint main() {\n int n, k; cin >> n >> k;\n vector<pll> ps(n);\n rep(i, n) cin >> ps[i].first >> ps[i].second;\n rep(i, n - 1){\n map<pair<frac, frac>, int> mp;\n for (int j = i + 1; j < n; ++j) {\n frac a = frac(ps[j].second - ps[i].second, ps[j].first - ps[i].first);\n frac b = a.b == 0 ? frac(ps[i].first, 1) : frac(ps[i].second * a.b - a.a * ps[i].first, a.b);\n if (!mp.count({ a,b }))mp[{a, b}] = 1;\n mp[{a, b}]++;\n }\n for (auto& p : mp) {\n if (p.second >= k) {\n cout << 1 << endl;\n return 0;\n }\n }\n }\n cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 1190, "memory_kb": 3840, "score_of_the_acc": -0.6202, "final_rank": 6 }, { "submission_id": "aoj_0388_10857203", "code_snippet": "#include <bits/stdc++.h>\n#include <iomanip>\n#include <numbers>\n#include <cassert>\n#include <numeric>\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pint = pair<int, int>;\nusing pll = pair<ll, ll>;\ntemplate<typename T>\nusing min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n#define rep(i, n) for(int i = 0; i < (n); ++i)\ntemplate<typename T>\nbool chmax(T & a, const T & b) { if (a < b) { a = b; return true; } return false; }\ntemplate<typename T>\nbool chmin(T & a, const T & b) { if (a > b) { a = b; return true; } return false; }\nconst int inf = 1e9;\nconst ll linf = 1e18;\nconst int dy[] = { 0,0,1,-1 }, dx[] = { 1,-1,0,0 };\nstruct frac {\n ll a, b;\n frac(ll _a, ll _b) : a(_a), b(_b) {\n if (b == 0) a = 1;\n else {\n if (b < 0) {\n a *= -1;\n b *= -1;\n }\n ll GCD = gcd(a, b);\n a /= GCD;\n b /= GCD;\n }\n }\n bool operator<(const frac& other) const {\n return a * other.b < other.a * b;\n }\n};\nint main() {\n int n, k; cin >> n >> k;\n vector<pll> ps(n);\n rep(i, n) cin >> ps[i].first >> ps[i].second;\n map<pair<frac, frac>, int> mp;\n rep(i, n - 1){\n map<pair<frac, frac>, int> nmp;\n for (int j = i + 1; j < n; ++j) {\n frac a = frac(ps[j].second - ps[i].second, ps[j].first - ps[i].first);\n frac b = frac(ps[i].second * a.b - a.a * ps[i].first, a.b);\n if (!nmp.count({ a,b }))nmp[{a, b}] = 1;\n nmp[{a, b}]++;\n }\n for (auto& p : nmp) {\n if (!mp.count(p.first))mp[p.first] = p.second;\n }\n }\n for (auto& p : mp) {\n if (p.second >= k) {\n cout << 1 << endl;\n return 0;\n }\n }\n cout << 0 << endl;\n}", "accuracy": 0.65, "time_ms": 320, "memory_kb": 42240, "score_of_the_acc": -0.2982, "final_rank": 19 }, { "submission_id": "aoj_0388_10853893", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = long long;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n//#pragma GCC optimize (\"-O3\") \n#ifdef YANG33\n#include \"mydebug.hpp\"\n#else\n#define DD(x) \n#endif\nconst int INF = 1e9; const LL LINF = 1e16;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- __MAKE_TIME__ Problem: __PROBLEM__ / Link: __CONTEST_URL__ ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n偏角ソート+Xの部分をライブラリにしたい\n\n----解説ここまで---- */\n\n\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N, K; cin >> N >> K;\n\tvector<double> x(N), y(N);\n\n\tFOR(i, 0, N) {\n\t\tcin >> x[i] >> y[i];\n\t}\n\t// O(N^2logN) ?\n\tbool exist = 0;\n\tconst double EPS = 1e-7;\n\tFOR(i, 0, N) {\n\t\tvector<double>args;\n\t\tFOR(j, 0, N) {\n\t\t\tif (i == j)continue;\n\t\t\targs.push_back(atan2(y[i] - y[j], x[i] - x[j]));\n\t\t}\n\t\tSORT(args);\n\t\tFOR(j, 0, N - 1) {\n\t\t\targs.push_back(args[j] + 2 * PI);\n\t\t}\n\t\tFOR(j, 0, N - 1) {\n\t\t\tint cnt = upper_bound(ALL(args), args[j] + EPS) - lower_bound(ALL(args), args[j] - EPS);\n\t\t\tcnt += upper_bound(ALL(args), args[j] + PI + EPS) - lower_bound(ALL(args), args[j] + PI - EPS);\n\t\t\tcnt++;\n\t\t\texist |= cnt >= K;\n\t\t}\n\n\t}\n\tcout << exist << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 4080, "score_of_the_acc": -0.8033, "final_rank": 8 }, { "submission_id": "aoj_0388_10844355", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#include <atcoder/all>\nusing namespace atcoder;\n\ntemplate <typename T>\nusing vc = vector<T>;\ntemplate <typename T>\nusing vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\nusing mint = modint1000000007;\n// using mint = modint;\n// mint::set_mod(m);\n\ntemplate <class T>\nusing pq = priority_queue<T, vc<T>>;\ntemplate <class T>\nusing pq_g = priority_queue<T, vc<T>, greater<T>>;\n//-----------------------------------\n\n//-------------2.配列系--------------\n\nusing pii = pair<int, int>;\nusing pll = pair<long long, long long>;\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\ntemplate <class T>\nistream &operator>>(istream &i, vc<T> &v)\n{\n rep(j, size(v)) i >> v[j];\n return i;\n}\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n//--------3.コード短縮化とか---------\nconst double PI = 3.141592653589793238;\nconst int inf = 1073741823;\nconst ll infl = 1LL << 60;\nconst string ABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\nconst string abc = \"abcdefghijklmnopqrstuvwxyz\";\n\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n#define drep(i, n) for (ll i = (n) - 1; i >= 0; --i)\n#define nfor(i, s, n) for (ll i = s; i < n; i++)\n#define dfor(i, s, n) for (ll i = (s) - 1; i >= n; i--)\n\n#define all(a) a.begin(), a.end()\n#define rall(a) a.rbegin(), a.rend()\n\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\n\n#define Yes cout << \"Yes\" << endl\n#define No cout << \"No\" << endl\n#define YN \\\n { \\\n cout << \"Yes\" << endl; \\\n } \\\n else \\\n { \\\n cout << \"No\" << endl; \\\n } // if(a==b)YN;\n\n#define vc_unique(v) v.erase(unique(v.begin(), v.end()), v.end());\n#define vc_rotate(v) rotate(v.begin(), v.begin() + 1, v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(), v.end())\n\n//-------------------------------\n\n//---------4.グリッド系----------\nvector<int> dx = {1, 0, -1, 0}; // dx={1,1,0,-1,-1,-1,0,1};\nvector<int> dy = {0, 1, 0, -1}; // dy={0,1,1,1,0,-1,-1,-1};\n\nbool out_grid(ll i, ll j, ll h, ll w = -1)\n{\n if (w == -1)\n {\n w = h;\n }\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_rotate(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 時計回りに90°回転\n// #define vvl_rotate(v) {ll n = size(v);vvl\n// nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_rotate(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][n - i - 1] = v[i][j]; \\\n swap(nx, v); \\\n } // 文字列版 時計回りに90°回転\n// #define vs_rotate(v) {ll n = size(v);vs\n// nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n#define vvl_transpos(v) \\\n { \\\n ll n = size(v); \\\n vvl nx(n, vl(n)); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n#define vs_transpos(v) \\\n { \\\n ll n = size(v); \\\n vs nx(n, string(n, '.')); \\\n rep(i, n) rep(j, n) nx[j][i] = v[i][j]; \\\n swap(nx, v); \\\n }\n\n//--------------------------------\n\n//-----------5.数学系--------------\n#define euclid(x, y) ((x) * (x) + (y) * (y)) // ユークリッド距離 2乗のまま\n#define manhattan(x1, x2, y1, y2) \\\n (abs(x1 - x2) + abs(y1 - y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate <class T>\nT tousa_sum1(T l, T d, T r)\n{ // 初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate <class T>\nT tousa_sum2(T a, T d, T n)\n{ // 初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d)\n{ // 初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\nmint touhi_sum(mint a, mint r,\n ll n)\n{ // 初項,公比,項数で等比数列の総和を求める\n if (r == 1)\n {\n return a * n;\n }\n mint bunsi = a * (r.pow(n) - mint(1));\n mint bunbo = r - 1;\n return bunsi / bunbo;\n}\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\n#define print_vec(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << \" \"; \\\n cout << endl; \\\n } // 一次元配列を出力する(改行なし)\n\n#define vc_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) cout << v[i] << endl; \\\n } // 一次元配列を出力する(改行あり)\n#define vv_cout(v) \\\n { \\\n ll n = size(v); \\\n rep(i, n) \\\n { \\\n rep(j, size(v[i])) { cout << v[i][j] << ' '; } \\\n cout << endl; \\\n } \\\n } // 二次元配列を出力する\n//----------------------------------------------\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n cout << fixed << setprecision(10);\n\n int n, k;\n cin >> n >> k;\n vector<int> x(n), y(n);\n rep(i, n) cin >> x[i] >> y[i];\n\n vector<tuple<int, int, int, int>> m;\n rep(i, n)\n {\n nfor(j, i + 1, n)\n {\n int ax = x[i], ay = y[i], bx = x[j], by = y[j];\n if (ax > bx)\n swap(ax, bx), swap(ay, by);\n if (ax == bx && ay > by)\n swap(ay, by);\n\n int g = gcd(bx - ax, by - ay);\n\n int nx = (bx - ax) / g, ny = (by - ay) / g;\n\n int k = nx, w = ny;\n if (nx == 0)\n k = ax, w = 0;\n else if (ny == 0)\n k = ay, w = 0;\n else\n {\n w = ay * nx - ny * ax;\n int ng = gcd(k, w);\n k /= ng, w /= ng;\n }\n m.push_back({nx, ny, k, w});\n }\n }\n sort(all(m));\n\n int l = 0;\n auto b = m[0];\n bool f = false;\n rep(i, m.size())\n {\n if (b == m[i])\n continue;\n\n if ((i - l) >= nc2(k))\n {\n f = true;\n }\n b = m[i];\n l = i;\n }\n if (int(m.size()) - l >= nc2(k))\n f = true;\n\n cout << f << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 135716, "score_of_the_acc": -1.0464, "final_rank": 15 }, { "submission_id": "aoj_0388_10844333", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing pii = pair<int, int>;\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n\n int N, K;\n cin >> N >> K;\n\n vector<int> X(N), Y(N);\n for (int i = 0; i < N; i++) cin >> X[i] >> Y[i];\n\n vector<pair<pii, pii>> A;\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n int dx = X[j] - X[i], dy = Y[j] - Y[i];\n int c = X[j] * Y[i] - X[i] * Y[j];\n if (dx < 0) {\n dx = -dx;\n dy = -dy;\n c = -c;\n }\n\n int gcd1 = gcd(dx, dy), gcd2 = gcd(dx, c);\n\n if (dx == 0) {\n dy = 1;\n c = X[i];\n gcd1 = 1;\n gcd2 = 1;\n }\n\n if (dy == 0) {\n dx = 1;\n c = Y[i];\n gcd1 = 1;\n gcd2 = 1;\n }\n\n A.emplace_back(make_pair(dx / gcd1, dy / gcd1), make_pair(dx / gcd2, c / gcd2));\n }\n }\n\n sort(A.begin(), A.end());\n\n int mCnt = 0;\n for (int i = 0; i < (int) A.size(); i++) {\n int cnt = 1;\n while (i + 1 < (int) A.size() && A[i] == A[i + 1]) {\n i++;\n cnt++;\n }\n\n mCnt = max(mCnt, cnt);\n }\n\n cout << ((mCnt >= K * (K - 1) / 2) ? 1 : 0) << endl;\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 135832, "score_of_the_acc": -1.144, "final_rank": 16 }, { "submission_id": "aoj_0388_9634547", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing i64 = long long;\n\n#define rep(i, a, b) for (int i = (a); i < (b); i++)\n#define repi(i, a, b) for (int i = (a) - 1; i >= (b); --i)\n\nstruct Point {\n i64 x, y;\n Point(i64 x_ = 0, i64 y_ = 0) : x(x_), y(y_) {}\n\n Point &operator+=(const Point &p) {\n x += p.x;\n y += p.y;\n return *this;\n }\n\n Point &operator-=(const Point &p) {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n\n Point operator-(const Point &p) const { return Point(*this) -= p; }\n\n i64 cross(const Point &p) const { return x * p.y - y * p.x; }\n friend i64 cross(const Point &p, const Point &q) { return p.cross(q); }\n};\n\nint main() {\n int n, k;\n cin >> n >> k;\n vector<Point> ps(n);\n rep (i, 0, n) cin >> ps[i].x >> ps[i].y;\n rep (i, 0, n) {\n map<pair<i64, i64>, int> cnt;\n rep (j, 0, n) if (j != i) {\n Point v = ps[j] - ps[i];\n pair<i64, i64> co = {v.x, v.y};\n if (co.first == 0) {\n co.second = 1;\n }\n else if (co.second == 0) {\n co.first = 1;\n }\n else {\n i64 g = gcd(co.first, co.second);\n co.first /= g;\n co.second /= g;\n if (co.first < 0) {\n co.first *= -1;\n co.second *= -1;\n }\n }\n // cout << i << \" \" << j << \" \" << co.first << \" \" << co.second << endl;\n cnt[co]++;\n if (cnt[co] >= k - 1) {\n cout << 1 << endl;\n return 0;\n }\n }\n }\n cout << 0 << endl;\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 3584, "score_of_the_acc": -1.0006, "final_rank": 14 }, { "submission_id": "aoj_0388_9633915", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug_print.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\n\nint solve(int N, int K, vector<int>& x, vector<int>& y) {\n for (int i = 0; i < N; i++) {\n // i を通る直線 f と f を通る点の個数を計算\n // f を通る直線が K - 1 本以上ある場合、 K 個以上の点を通る直線が存在する\n map<pair<double, double>, int> cnt;\n for (int j = i + 1; j < N; j++) {\n double a = (y[j] - y[i]) / (double)(x[j] - x[i]);\n double b = y[i] - a * x[i];\n if (a == numeric_limits<double>::infinity()) {\n // a が inf の場合, 関数 f := x = x[i] として扱う\n cnt[{a, x[i]}]++;\n } else {\n // それ以外の場合, 関数 f := y = ax + b として扱う\n cnt[{a, b}]++;\n }\n }\n for (auto&& [key, value]: cnt) {\n if (value >= K - 1) return 1;\n }\n }\n return 0;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, K;\n cin >> N >> K;\n vector<int> x(N), y(N);\n for (int i = 0; i < N; i++) cin >> x[i] >> y[i];\n cout << solve(N, K, x, y) << '\\n';\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 3656, "score_of_the_acc": -0.1889, "final_rank": 2 }, { "submission_id": "aoj_0388_9633839", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug_print.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\n\nint naive(int N, int K, vector<int> x, vector<int> y) {\n int res = 0;\n map<pair<double, double>, int> debug_cnt;\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n int cnt = 0;\n double a = (y[j] - y[i]) / double(x[j] - x[i]);\n double b = y[i] - a * x[i];\n if (b == 1) debug(a, b, i, j);\n for (int k = 0; k < N; k++) {\n if (a == numeric_limits<double>::infinity()) {\n if (x[k] == x[i]) {\n cnt++;\n }\n } else {\n if (a * x[k] + b == y[k]) {\n cnt++;\n }\n }\n }\n debug_cnt[{a, b}] = cnt;\n if (cnt >= K) {\n res = 1;\n break;\n }\n }\n }\n\n debug(debug_cnt);\n return res;\n}\n\nint solve(int N, int K, vector<int>& x, vector<int>& y) {\n vector<pair<double, double>> f;\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n double a = (y[j] - y[i]) / double(x[j] - x[i]);\n double b = y[i] - a * x[i];\n // a が inf の場合\n if (a == numeric_limits<double>::infinity()) {\n f.emplace_back(a, x[i]);\n } else {\n f.emplace_back(a, b);\n }\n }\n }\n\n sort(f.begin(), f.end());\n int streak = 1, res = 0;\n for (int i = 0; i < int(f.size()); i++) {\n if (i == int(f.size()) - 1) {\n if (2 * streak >= K * (K - 1)) res = 1;\n break;\n }\n if (f[i] == f[i + 1]) {\n streak++;\n } else {\n if (2 * streak >= K * (K - 1)) res = 1;\n streak = 1;\n }\n }\n\n return res;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, K;\n cin >> N >> K;\n vector<int> x(N), y(N);\n for (int i = 0; i < N; i++) cin >> x[i] >> y[i];\n cout << solve(N, K, x, y) << '\\n';\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 136136, "score_of_the_acc": -0.8062, "final_rank": 9 }, { "submission_id": "aoj_0388_9633541", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Point = complex<double>;\nPoint unitVector(const Point &a) { return a / abs(a); }\nint main(){\n\t#define int long long\n\tint n,k;\n\tcin >>n>>k;\n\tk--;\n\tPoint x[n];\n\tfor(int i = 0;i < n;i++){\n\t\tint y,z;\n\t\tcin >>y>>z;\n\t\tx[i] = Point(y,z);\n\t}\n\tif(true){\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tmap<pair<double,double>,int>a;\n\t\t\tfor(int j = 0;j < n;j++){\n\t\t\t\tif(i != j&&x[i].real() <= x[j].real()&&x[i].imag() >= x[j].imag()){\n\t\t\t\t\tPoint y = unitVector(x[i]-x[j]);\n\t\t\t\t\ty = Point(ceil(y.real()*100000)/100000,ceil(y.imag()*100000)/100000);\n\t\t\t\t\ta[{y.real(),y.imag()}]++;\n\t\t\t\t\tif(a[{y.real(),y.imag()}] == k){\n\t\t\t\t\t\tcout <<1<<\"\\n\";\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(true){\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tmap<pair<double,double>,int>a;\n\t\t\tfor(int j = 0;j < n;j++){\n\t\t\t\tif(i != j&&x[i].real() >= x[j].real()&&x[i].imag() >= x[j].imag()){\n\t\t\t\t\tPoint y = unitVector(x[i]-x[j]);\n\t\t\t\t\ty = Point(ceil(y.real()*100000)/100000,ceil(y.imag()*100000)/100000);\n\t\t\t\t\ta[{y.real(),y.imag()}]++;\n\t\t\t\t\tif(a[{y.real(),y.imag()}] == k){\n\t\t\t\t\t\tcout <<1<<\"\\n\";\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// if(x[i] == Point(10,10)){\n\t\t\t// \tfor(auto i:a)cout <<\"(\"<<i.first.first<<\",\"<<i.first.second<<\"):\"<<i.second<<\"\\n\";\n\t\t\t// }\n\t\t}\n\t}\n\tcout <<0<<\"\\n\";\n\treturn 0;\n}", "accuracy": 1, "time_ms": 710, "memory_kb": 3584, "score_of_the_acc": -0.3279, "final_rank": 3 }, { "submission_id": "aoj_0388_9633540", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Point = complex<double>;\nPoint unitVector(const Point &a) { return a / abs(a); }\nint main(){\n\t#define int long long\n\tint n,k;\n\tcin >>n>>k;\n\tk--;\n\tPoint x[n];\n\tfor(int i = 0;i < n;i++){\n\t\tint y,z;\n\t\tcin >>y>>z;\n\t\tx[i] = Point(y,z);\n\t}\n\tif(true){\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tmap<pair<double,double>,int>a;\n\t\t\tfor(int j = 0;j < n;j++){\n\t\t\t\tif(i != j&&x[i].real() <= x[j].real()&&x[i].imag() >= x[j].imag()){\n\t\t\t\t\tPoint y = unitVector(x[i]-x[j]);\n\t\t\t\t\ty = Point(ceil(y.real()*10000)/10000,ceil(y.imag()*10000)/10000);\n\t\t\t\t\ta[{y.real(),y.imag()}]++;\n\t\t\t\t\tif(a[{y.real(),y.imag()}] == k){\n\t\t\t\t\t\tcout <<1<<\"\\n\";\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(true){\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tmap<pair<double,double>,int>a;\n\t\t\tfor(int j = 0;j < n;j++){\n\t\t\t\tif(i != j&&x[i].real() >= x[j].real()&&x[i].imag() >= x[j].imag()){\n\t\t\t\t\tPoint y = unitVector(x[i]-x[j]);\n\t\t\t\t\ty = Point(ceil(y.real()*10000)/10000,ceil(y.imag()*10000)/10000);\n\t\t\t\t\ta[{y.real(),y.imag()}]++;\n\t\t\t\t\tif(a[{y.real(),y.imag()}] == k){\n\t\t\t\t\t\tcout <<1<<\"\\n\";\n\t\t\t\t\t\treturn 0;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t// if(x[i] == Point(10,10)){\n\t\t\t// \tfor(auto i:a)cout <<\"(\"<<i.first.first<<\",\"<<i.first.second<<\"):\"<<i.second<<\"\\n\";\n\t\t\t// }\n\t\t}\n\t}\n\tcout <<0<<\"\\n\";\n\treturn 0;\n}", "accuracy": 0.825, "time_ms": 260, "memory_kb": 3464, "score_of_the_acc": -0.0545, "final_rank": 18 }, { "submission_id": "aoj_0388_9633525", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#ifdef LOCAL\n#include <debug_print.hpp>\n#define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define debug(...) (static_cast<void>(0))\n#endif\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n int N, K;\n cin >> N >> K;\n vector<int> x(N), y(N);\n for (int i = 0; i < N; i++) cin >> x[i] >> y[i];\n\n // 2 点間の一次関数を求める\n // {a, b} := ax + b で表せる直線の個数\n map<pair<double, double>, int> id;\n // {a, b, id} := ax + b で表せる直線と基準となる点の id の個数\n map<tuple<double, double, int>, int> cnt;\n for (int i = 0; i < N; i++) {\n for (int j = i + 1; j < N; j++) {\n double a = (y[j] - y[i]) / (double)(x[j] - x[i]);\n double b = y[i] - a * x[i];\n if (id.count({a, b})) {\n if (i == id[{a, b}] || j == id[{a, b}]) {\n cnt[{a, b, id[{a, b}]}] += 1;\n }\n } else {\n id[{a, b}] = i;\n cnt[{a, b, i}] += 2;\n }\n }\n }\n\n bool flag = false;\n for (auto [key, value] : cnt) {\n if (value >= K) {\n flag = true;\n break;\n }\n }\n\n cout << (flag ? 1 : 0) << '\\n';\n}", "accuracy": 0.65, "time_ms": 440, "memory_kb": 73204, "score_of_the_acc": -0.5365, "final_rank": 20 }, { "submission_id": "aoj_0388_9613196", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n// #define int long long\n\n/*\n17:29~17:43\n6:25~\n*/\n\nsigned main(){\n\tint n,k;cin>>n>>k;\n\tvector<int> x(n),y(n);\n\tfor(int i=0;i<n;i++){\n\t\tcin>>x[i]>>y[i];\n\t}\n\n\tfor(int i=0;i<n;i++){\n\t\tmap<array<int,3>,int> cnt;\n\t\tfor(int j=i+1;j<n;j++){\n\t\t\tint a=x[i]-x[j];\n\t\t\tint b=y[i]-y[j];\n\t\t\tint c=x[i]*y[j]-x[j]*y[i];\n\n\t\t\tint g=gcd(abs(a),gcd(abs(b),abs(c)));\n\t\t\ta/=g,b/=g,c/=g;\n\t\t\tif(a<0){\n\t\t\t\ta=-a,b=-b,c=-c;\n\t\t\t}\n\t\t\tif(a==0&&b<0){\n\t\t\t\tb=-b,c=-c;\n\t\t\t}\n\t\t\t// cout<<i<<\" \"<<j<<\" : \"<<a<<\" \"<<b<<\" \"<<c<<endl;\n\t\t\tcnt[{a,b,c}]++;\n\t\t\tif(cnt[{a,b,c}]>=k-1){\n\t\t\t\tcout<<1<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<0<<endl;\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 3580, "score_of_the_acc": -0.3643, "final_rank": 4 }, { "submission_id": "aoj_0388_9610449", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\n\nvector<int> x(3000),y(3000);\npair<pair<int,int>,int> gf(int i,int j){\n int dx = (x[i]-x[j]);\n int dy = (y[i]-y[j]);\n \n if(dx==0){\n return make_pair(make_pair(1,0),x[i]);\n }\n if(dy==0){\n return make_pair(make_pair(0,0),y[i]);\n }\n \n int gcd = __gcd(dx,dy);\n dx/=gcd;\n dy/=gcd;\n\n if(dx*dy<0){\n if(dx<0) dx*=-1,dy*=-1;\n }\n else{\n if(dx<0) dx*=-1,dy*=-1;\n }\n\n\n return make_pair(make_pair(dx,dy),y[i]-(x[i]/dx)*dy);\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int n,k;\n cin >> n >> k;\n rep(i,n) cin >> x[i] >> y[i];\n\n vector<pair<pair<int,int>,int>> v;\n\n rep(i,n){\n rep(j,i){\n v.push_back(gf(i,j));\n }\n }\n sort(v.begin(),v.end());\n int c=1;\n int ma = 0;\n rep(i,(int)v.size()-1){\n if(v[i]==v[i+1]) c++;\n else c=1;\n ma = max(ma,c);\n }\n\n if(ma>=(k*(k-1)/2)) cout << 1 << endl;\n else cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 650, "memory_kb": 102820, "score_of_the_acc": -0.8221, "final_rank": 11 }, { "submission_id": "aoj_0388_9605788", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconstexpr int N = 3005;\n\nint x[N], y[N];\n\nint main() {\n int n, k;\n cin >> n >> k;\n\n for (int i = 0; i < n; ++i)\n cin >> x[i] >> y[i];\n\n for (int i = 0; i < n; ++i) {\n map<pair<int, int>, int> mp;\n for (int j = 0; j < n; ++j) {\n int cx = x[j] - x[i];\n int cy = y[j] - y[i];\n\n if (!cx && !cy)\n continue;\n\n tie(cx, cy) = make_pair(cx / gcd(cx, cy), cy / gcd(cx, cy));\n\n if (cx < 0 || (cx == 0 && cy < 0))\n cx = -cx, cy = -cy;\n\n if (++mp[{cx, cy}] + 1 >= k)\n return cout << 1 << '\\n', 0;\n }\n }\n\n cout << 0 << '\\n';\n}", "accuracy": 1, "time_ms": 1600, "memory_kb": 3644, "score_of_the_acc": -0.8676, "final_rank": 12 }, { "submission_id": "aoj_0388_9481950", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nMLE => map\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst double INF = 1e18;\nconst double EPS = 1e-5;\n//----------------------------------------------make -f ../makefile SRC=--------------------------------\nstruct Point\n{\n double x, y;\n Point(): x(0), y(0) {}\n Point(double x1, double x2): x(x1), y(x2) {}\n void debug() const { printf(\"%lf, %lf\\n\", x, y); }\n};\ntypedef vector<Point> Points;\n\nstruct Line\n{\n double m, k;\n Line(): m(0), k(0) {}\n Line(double v1, double v2): m(v1), k(v2) {}\n bool operator<(const Line& L1) const\n {\n if (fabs(m-L1.m) < EPS) return k < L1.k;\n return m < L1.m;\n }\n bool operator==(const Line& L1) const\n {\n return fabs(m-L1.m) < EPS && fabs(k-L1.k) < EPS;\n }\n void Debug() const { printf(\"%lf, %lf: \", m, k); }\n void debug() const { printf(\"%lf, %lf\\n\", m, k); }\n};\n\ntypedef vector<Line> Lines;\n\ndouble dist2(const Point& A, const Point& B)\n{\n return (A.x-B.x)*(A.x-B.x) + (A.y-B.y)*(A.y-B.y);\n}\n\n\ndouble dist(double x1, double y1, double x2, double y2)\n{\n return sqrt((x1-x2)*(x1-x2) + (y1-y2)*(y1-y2));\n}\n\nLine eqt_of_line(double x1, double y1, double x2, double y2)\n{\n if (fabs(x1-x2) < EPS) return Line(INF, x1);\n else if (fabs(y1-y2) < EPS) return Line(0, y1);\n\n double a = y2-y1;\n double b = x1-x2;\n double c = x1*(y1-y2) + y1*(x2-x1);\n return Line(-a/b, -c/b);\n}\n//------------------------------------------------------------------------------\n//return true if no. of collinear points >= K\n/*\nbool solve(int N, const Points& P, int K)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n map<Line, unordered_set<int> > S;\n //--------------------------------------------------------------------------\n // compute:\n for (int i=0; i<N-1; ++i)\n for (int j=i+1; j<N; ++j)\n {\n Line L1 = eqt_of_line(P[i].x, P[i].y, P[j].x, P[j].y);\n S[ L1 ].insert( i );\n S[ L1 ].insert( j );\n if (S[ L1 ].size() >= K) return true;\n }\n return false;\n}\n*/\n//return true if no. of collinear points >= K\nbool solve(int N, const Points& P, int K)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n Lines R;\n //--------------------------------------------------------------------------\n // compute:\n for (int i=0; i<N-1; ++i)\n for (int j=i+1; j<N; ++j)\n {\n Line L1 = eqt_of_line(P[i].x, P[i].y, P[j].x, P[j].y);\n R.push_back(L1);\n }\n\n sort(R.begin(), R.end());\n if (DEBUG) { for (Line L1: R) L1.debug(); }\n int max_lines = 0;\n int M = R.size();\n int start = 0;\n while (start < M)\n {\n int end = start;\n while (end < M && R[end] == R[start]) end++;\n if (R[end] == R[start])\n {\n max_lines = max(max_lines, end-start+1);\n break;\n }\n\n max_lines = max(max_lines, end-start);\n start = end;\n }\n if (DEBUG) printf(\"M=%d, max_lines=%d\\n\", M, max_lines);\n return K*(K-1)/2 <= max_lines;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n int K;\n double x, y;\n num = scanf(\"%d %d \", &N, &K);\n Points P(N);\n for (int i=0; i<N; ++i)\n {\n num = scanf(\"%lf %lf \", &x, &y);\n P[i] = Point(x, y);\n }\n if (solve(N, P, K)) printf(\"1\\n\");\n else printf(\"0\\n\");\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 490, "memory_kb": 136252, "score_of_the_acc": -0.9038, "final_rank": 13 } ]
aoj_0390_cpp
Disc A mysterious device was discovered in an ancient ruin. The device consists of a disc with integers inscribed on both sides, a bundle of cards with an integer written on each of them and a pedestal within which the cards are placed. The disc rotates when the bundle of cards is put into the pedestal. Only one side of the disc is exposed to view at any one time. The disc is radially segmented in equal angles into $K$ sections, and an integer, from $1$ to $K$ in increasing order, is inscribed clockwise on each section on the front side. The sections on the back side share the same boundaries with the front side, and a negative counterpart of that in the section on the front side is inscribed, i.e., if $X$ is inscribed in the front side section, $-X$ is inscribed on the counterpart section on the back side. There is a needle on the periphery of the disc, and it always points to the middle point of the arc that belongs to a section. Hereafter, we say "the disc is set to $X$" if the front side section just below the needle contains an integer $X$. Fig.1 Disc with 5 sections (i.e., $K = 5$): When the disc is set to $1$ on the front side, it is set to $-1$ on the back side. Investigation of the behavior of the device revealed the following: When the bundle of cards is placed in the pedestal, the device sets the disc to 1. Then, the device reads the cards slice by slice from top downward and performs one of the following actions according to the integer $A$ on the card If $A$ is a positive number, it rotates the disc clockwise by $|A|$ sections. If $A$ is zero, it turns the disc back around the vertical line defined by the needle and the center of the disc. If $A$ is a negative number, it rotates the disc counterclockwise by $|A|$ sections. It is provided that $|A|$ is the absolute value of $A$. The final state of the device (i.e., to what section the needle is pointing) varies depending on the initial stacking sequence of the cards. To further investigate the behavior of the device, we swapped two arbitrary cards in the stack and placed the bundle in the pedestal to check what number the disc is set to. We performed this procedure over again and again. Given the information on the device and several commands to swap two cards, make a program to determine the number to which the device is set at the completion of all actions. Note that the stacking sequence of the cards continues to change as a new trial is made. Input The input is given in the following format. $K$ $N$ $Q$ $A_1$ $A_2$ ... $A_N$ $L_1$ $R_1$ $L_2$ $R_2$ $...$ $L_Q$ $R_Q$ The first line provides the number of sections $K$ ($2 \leq K \leq 10^9$), the slices of cards $N$ ($2 \leq N \leq 100,000$), and the number of commands $Q$ ($1 \leq Q \leq 100,000$). The second line provides an array of $N$ integers inscribed on the sections of the disc. $A_i$ ($-10^9 \leq A_i \leq 10^9$) represents the number written on the $i$-th card from the top. Each of the subsequent $Q$ lines defines the $i$-th ...(truncated)
[ { "submission_id": "aoj_0390_10875152", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nint K;\ntemplate < typename NodeT, typename LazyT>\nstruct SEG{\n using F = function<NodeT(const NodeT&, const NodeT&)>;\n using G = function<NodeT(const NodeT&, const LazyT&,int)>;\n using H = function<LazyT(const LazyT&, const LazyT&)>;\n int n;\n vector<NodeT> node;\n vector<LazyT> lazy;\n F f;\n G g;\n H h;\n NodeT e;\n LazyT id;\n SEG(int N, F f, G g, H h, NodeT e, LazyT id) : f(f), g(g), h(h), e(e), id(id)\n {\n n = 1;\n while(n < N) n <<= 1;\n node.assign(2*n,e);\n lazy.assign(2*n,id);\n }\n void eval(int k, int l, int r){\n if(lazy[k].ml != id.ml || lazy[k].ad != id.ad){\n node[k] = g(node[k],lazy[k],r-l);\n if(r-l > 1){\n lazy[2*k] = h(lazy[2*k],lazy[k]);\n lazy[2*k+1] = h(lazy[2*k+1],lazy[k]);\n }\n lazy[k] = id;\n }\n }\n void update(int a, int b, LazyT x, int k=1, int l=0, int r=-1){\n if(r == -1) r = n;\n eval(k,l,r);\n if(b <= l || r <= a) return;\n if(a <= l && r <= b){\n lazy[k] = h(lazy[k],x);\n eval(k,l,r);\n }\n else{\n int m = (l+r)/2;\n update(a,b,x,2*k,l,m);\n update(a,b,x,2*k+1,m,r);\n node[k] = f(node[2*k+1],node[2*k]);\n }\n }\n NodeT query(int a, int b, int k = 1, int l = 0, int r = -1){\n if(r == -1) r = n;\n eval(k,l,r);\n if(b <= l || r <= a) return e;\n if(a <= l && r <= b) return node[k];\n int m = (l+r)/2;\n return f(query(a,b,2*k,l,m), query(a,b,2*k+1,m,r));\n }\n};\nstruct SEGt{\nprivate:\n int n;\n vector<int> node;\npublic:\n SEGt(int N){\n n = 1;\n while(n < N) n *= 2;\n node.resize(2*n-1);\n }\n void update(int i, int x){\n i += n-1;\n node[i] = x;\n while(i){\n i = (i-1)/2;\n node[i] = node[2*i+1]+node[2*i+2];\n }\n }\n int f(int a, int b, int k = 0, int l = 0, int r = -1){\n if(r < 0) r = n;\n if(a <= l && r <= b) return node[k];\n if(b <= l || r <= a) return 0;\n return f(a,b,2*k+1,l,(l+r)/2)+f(a,b,2*k+2,(l+r)/2,r);\n }\n};\nsigned main(){\n int N,Q;\n struct Node{int val;};\n struct Lazy{int ml; int ad;};\n auto f = [](Node a, Node b){return Node{(a.val+b.val)%K};};\n auto g = [](Node a, Lazy b, int len){return Node{(a.val*b.ml+b.ad*len)%K};};\n auto h = [](Lazy a, Lazy b){return Lazy{(a.ml*b.ml)%K,(b.ml*a.ad+b.ad)%K};};\n Node e = Node{0};\n Lazy id = Lazy{1,0};\n cin>>K>>N>>Q;\n SEG<Node,Lazy> seg(N,f,g,h,e,id);\n SEGt segt(N);\n vector<int> A(N);\n for(int i=0;i<N;i++){\n int a;\n cin>>a;\n A[i] = a;\n seg.update(i,i+1,{(segt.f(0,i)%2 ? 1 : -1),(segt.f(0,i)%2 ? 1 : -1)*a});\n if(a == 0) segt.update(i,1);\n }\n while(Q--){\n int a,b;\n cin>>a>>b;\n a--;\n b--;\n if((A[a]==0)^(A[b]==0)){\n seg.update(a+1,b,{-1,0});\n if(A[a] == 0){\n segt.update(a,0);\n segt.update(b,1);\n seg.update(a,a+1,{(segt.f(0,a)%2 ? 1 : -1),(segt.f(0,a)%2 ? 1 : -1)*A[b]});\n seg.update(b,b+1,{0,0});\n }\n else{\n segt.update(a,1);\n segt.update(b,0);\n seg.update(a,a+1,{0,0});\n seg.update(b,b+1,{(segt.f(0,b)%2 ? 1 : -1),(segt.f(0,b)%2 ? 1 : -1)*A[a]});\n }\n }\n else if(A[a] != 0 && A[b] != 0){\n if(segt.f(0,a)%2 == 1){\n seg.update(a,a+1,{1,A[b]-A[a]});\n }\n else{\n seg.update(a,a+1,{1,-(A[b]-A[a])});\n }\n if(segt.f(0,b)%2 == 1){\n seg.update(b,b+1,{1,A[a]-A[b]});\n }\n else{\n seg.update(b,b+1,{1,-(A[a]-A[b])});\n }\n }\n swap(A[a],A[b]);\n int t = seg.query(0,N).val;\n int ans = (t%K+K)%K;\n ans++;\n if(segt.f(0,N)%2) ans = -ans;\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 12016, "score_of_the_acc": -1.0554, "final_rank": 19 }, { "submission_id": "aoj_0390_10875101", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nconstexpr ll inf = 1e18;\nconstexpr int MOD = 1000000007;\n\ntemplate<class A>\nclass LazySegmentTree {\n using M = typename A::M;\n using E = typename A::E;\n using T = typename M::T;\n using U = typename E::T;\n\n int n, h;\n vector<T> dat;\n vector<U> lazy;\n\n void all_apply(int k, U x) {\n dat[k] = A::op(x, dat[k]);\n if (k < n) lazy[k] = E::op(lazy[k], x);\n }\n void eval(int k) {\n if (lazy[k] == E::id()) return;\n all_apply(k * 2 + 0, lazy[k]);\n all_apply(k * 2 + 1, lazy[k]);\n lazy[k] = E::id();\n }\n void calc(int k) {\n dat[k] = M::op(dat[k * 2 + 0], dat[k * 2 + 1]);\n }\n\npublic:\n LazySegmentTree(vector<T> a) {\n h = 0;\n while ((1 << h) < (int)(a.size())) ++h;\n n = 1 << h;\n dat.assign(n * 2, M::id());\n lazy.assign(n, E::id());\n rep (i, a.size()) dat[i + n] = a[i];\n rrep2 (i, 1, n) calc(i);\n }\n T all_prod() { return dat[1]; }\n T prod(int l, int r) {\n l += n; r += n;\n rrep2 (i, 1, h + 1) {\n if (((l >> i) << i) != l) eval(l >> i);\n if (((r >> i) << i) != r) eval((r - 1) >> i);\n }\n T lsm = M::id(), rsm = M::id();\n while (l < r) {\n if (l & 1) lsm = M::op(lsm, dat[l++]);\n if (r & 1) rsm = M::op(dat[--r], rsm);\n l /= 2; r /= 2;\n }\n return M::op(lsm, rsm);\n }\n T get(int k) {\n k += n;\n rrep2 (i, 1, h + 1) eval(k >> i);\n return dat[k];\n }\n void set(int k, T x) {\n k += n;\n rrep2 (i, 1, h + 1) eval(k >> i);\n dat[k] = x;\n rep2 (i, 1, h + 1) calc(k >> i);\n }\n void apply(int l, int r, U x) {\n l += n; r += n;\n rrep2 (i, 1, h + 1) {\n if (((l >> i) << i) != l) eval(l >> i);\n if (((r >> i) << i) != r) eval((r - 1) >> i);\n }\n int l2 = l, r2 = r;\n while (l2 < r2) {\n if (l2 & 1) all_apply(l2++, x);\n if (r2 & 1) all_apply(--r2, x);\n l2 /= 2; r2 /= 2;\n }\n rep2 (i, 1, h + 1) {\n if (((l >> i) << i) != l) calc(l >> i);\n if (((r >> i) << i) != r) calc((r - 1) >> i);\n }\n }\n};\n\nstruct Act {\n struct M {\n using T = ll;\n static T id() { return 0; }\n static T op(T a, T b) { return a + b; }\n };\n struct E {\n using T = bool;\n static T id() { return false; }\n static T op(T a, T b) { return b ? !a : a; }\n };\n static ll op(bool a, ll b) { return a ? -b : b; }\n};\n\nclass BinaryIndexedTree {\n int n;\n vector<ll> dat;\n\npublic:\n BinaryIndexedTree(int n_) : n(n_), dat(n_ + 1) {}\n void add(int k, ll x) {\n ++k;\n while (k <= n) {\n dat[k] += x;\n k += k & -k;\n }\n }\n ll sum(int k) const {\n ll res = 0;\n while (k > 0) {\n res += dat[k];\n k -= k & -k;\n }\n return res;\n }\n ll sum(int l, int r) const { return sum(r) - sum(l); }\n};\n\nint main() {\n ll K, N, Q; scanf(\"%lld%lld%lld\", &K, &N, &Q);\n vector<ll> A(N);\n rep (i, N) scanf(\"%lld\", &A[i]);\n rep (i, N) A[i] = -A[i];\n BinaryIndexedTree bit(N);\n LazySegmentTree<Act> seg(A);\n rep (i, N) if (A[i] == 0) {\n seg.apply(i, N, true);\n bit.add(i, 1);\n }\n int cnt = count(all(A), 0);\n rep (_, Q) {\n int a, b; scanf(\"%d%d\", &a, &b);\n --a; --b;\n if (A[a] == 0) seg.apply(a, N, true), bit.add(a, -1);\n if (A[b] == 0) seg.apply(b, N, true), bit.add(b, -1);\n swap(A[a], A[b]);\n if (A[a] == 0) seg.apply(a, N, true), bit.add(a, 1);\n if (A[b] == 0) seg.apply(b, N, true), bit.add(b, 1);\n seg.set(a, A[a] * (bit.sum(0, a) % 2 == 1 ? -1 : 1));\n seg.set(b, A[b] * (bit.sum(0, b) % 2 == 1 ? -1 : 1));\n ll res = seg.all_prod();\n res = (res % K + K) % K + 1;\n printf(\"%lld\\n\", res * (cnt % 2 == 1 ? -1 : 1));\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7576, "score_of_the_acc": -0.1571, "final_rank": 6 }, { "submission_id": "aoj_0390_10871325", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\n\nusing U = uint64_t;\ntemplate<class S, S (*op)(S, S), S (*e)(), class F, S (*mpp)(F, S), F (*cmpo)(F, F), F (*id)()> struct lazy_segtree {\n lazy_segtree() : lazy_segtree(0) {}\n explicit lazy_segtree(int n) : lazy_segtree(vector<S>(n, e())) {}\n explicit lazy_segtree(const vector<S>& v) : n(si(v)) {\n s = __bit_ceil(U(n));\n log = __countr_zero(U(s));\n d = vector<S>(2 * s, e());\n lz = vector<F>(s, id());\n rep(i, n) d[s + i] = v[i];\n for(int i=s; --i;) update(i);\n }\n void set(int p, S x) {\n p += s;\n PUSH(p);\n d[p] = x;\n for(int i=1;i<=log;i++) update(p >> i);\n }\n S get(int p) {\n p += s;\n PUSH(p);\n return d[p];\n }\n S prod(int l, int r) {\n if(l == r) return e();\n l += s, r += s;\n for(int i=log+1;--i;) {\n if(((l >> i) << i) != l) push(l >> i);\n if(((r >> i) << i) != r) push((r - 1) >> i);\n }\n S sml = e(), smr = e();\n while(l < r) {\n if(l & 1) sml = op(sml, d[l++]);\n if(r & 1) smr = op(d[--r], smr);\n l >>= 1, r >>= 1;\n }\n return op(sml, smr);\n }\n S all_prod() {\n return d[1];\n }\n void apply(int p, F f) {\n // assert(0 <= p && p < n);\n p += s;\n PUSH(p);\n d[p] = mpp(f, d[p]);\n for(int i=1;i<=log;i++) update(p >> i);\n }\n void apply(int l, int r, F f) {\n // assert(0 <= l && l <= r && r <= _n);\n if(l == r) return;\n l += s, r += s;\n\n for(int i=log+1;--i;) {\n if(((l >> i) << i) != l) push(l >> i);\n if(((r >> i) << i) != r) push((r - 1) >> i);\n }\n int ml = l, mr = r;\n while(l < r) {\n if(l & 1) all_apply(l++, f);\n if(r & 1) all_apply(--r, f);\n l >>= 1, r >>= 1;\n }\n l = ml, r = mr;\n for(int i=1;i<=log;i++) {\n if(((l >> i) << i) != l) update(l >> i);\n if(((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n S operator[](int k) {\n return get(k);\n }\n int len() {\n return n;\n }\n\nprivate:\n int n, s, log;\n vector<S> d;\n vector<F> lz;\n void update(int k) {\n d[k] = op(d[2 * k], d[2 * k + 1]);\n }\n void all_apply(int k, F f) {\n d[k] = mpp(f, d[k]);\n if(k < s) lz[k] = cmpo(f, lz[k]);\n }\n void push(int k) {\n all_apply(2 * k, lz[k]);\n all_apply(2 * k + 1, lz[k]);\n lz[k] = id();\n }\n void PUSH(int k) {\n for(int i=log+1;--i;) push(k >> i);\n }\n};\n\ntemplate<class T> struct fenwick_tree {\n vector<T> a;\n fenwick_tree(int n): a(n + 1) {}\n void add(int i, T x) {\n i++;\n while(i < si(a)) a[i] += x, i += i & -i;\n }\n T sum(int r) {\n T s = 0;\n while(r) s += a[r], r -= r & -r;\n return s;\n }\n T sum(int l, int r) { return sum(r) - sum(l); }\n int lower_bound(T w) {\n if(w <= 0) return 0;\n int x = 0, N = si(a) + 1;\n for(int k = 1 << __lg(N); k; k >>= 1) {\n if(x + k <= N - 1 && a[x + k] < w) {\n w -= a[x + k];\n x += k;\n }\n }\n return x;\n }\n};\n\nusing S=long;\nS op(S l, S r) {return l+r;}\nS e(){return S();}\nS mpp(S f, S s){return (f*2-1)*-1*s;}\nS cmp(S f, S g){return (f+g)%2;}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int K,N,Q;\n cin>>K>>N>>Q;\n vector<long> A(N+2,0);\n rep(i,N)cin>>A[i+1];\n N+=2;\n\n lazy_segtree<S,op,e,S,mpp,cmp,e> seg(A);\n fenwick_tree<int> bit(N);\n rep(i,N){\n if(A[i]==0){\n bit.add(i, 1);\n if(bit.sum(i)%2){\n seg.apply(bit.lower_bound(bit.sum(i))+1, i, 1);\n }\n }\n }\n while(Q--){\n int L,R;\n cin>>L>>R;\n \n if(A[L]!=0&&A[R]!=0){\n seg.set(L, (bit.sum(0,L)%2*2-1)*-1*A[R]);\n seg.set(R, (bit.sum(0,R)%2*2-1)*-1*A[L]);\n swap(A[L],A[R]);\n }\n else if(A[R]!=0){\n seg.set(L, (bit.sum(0,L)%2*2-1)*A[R]);\n seg.set(R, 0);\n seg.apply(L, R, 1);\n bit.add(L, -1);\n bit.add(R, 1);\n swap(A[L],A[R]);\n }\n else if(A[L]!=0){\n seg.set(R, (bit.sum(0,R)%2*2-1)*A[L]);\n seg.set(L, 0);\n seg.apply(L+1, R,1);\n bit.add(R, -1);\n bit.add(L, 1);\n swap(A[L],A[R]);\n }\n cout<<((seg.all_prod()%K+K)%K+1)*(bit.sum(N)%2*2-1)*-1<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7664, "score_of_the_acc": -0.0767, "final_rank": 4 }, { "submission_id": "aoj_0390_10871322", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long \n#define pb push_back\n#define rep(i,N) for(int i =0;i<(int)N;i++)\n#define all(x) x.begin(),x.end()\n\nclass seg{\n public:\n int N;\n vector<ll>data;\n vector<ll>lazy;\n void init(int n){\n N=1;\n while(N<n)N*=2;\n data.assign(N*2,0);\n lazy.assign(N*2,1);\n }\n void eval(int k){\n if(lazy[k]!=1){\n data[k]*=lazy[k];\n if(2*k+2<N*2){\n lazy[k*2+1]*=-1;\n lazy[k*2+2]*=-1;\n }\n lazy[k]=1;\n }\n }\n void update(int x,ll v,int k=0,int l=0,int r=-1){\n if(r<0)r=N;\n eval(k);\n if(x<l||r<=x)return;\n else if(x==l&&x+1==r){\n data[k]=v;\n return;\n }\n else if(2*k+2<2*N){\n update(x,v,k*2+1,l,(l+r)/2);\n update(x,v,k*2+2,(l+r)/2,r);\n data[k]=data[k*2+1]+data[k*2+2];\n }\n }\n void flip(int a,int b,int k=0,int l=0,int r=-1){\n if(r<0)r=N;\n eval(k);\n if(b<=l||r<=a){\n return;\n }\n if(a<=l&&r<=b){\n lazy[k]*=-1;\n eval(k);\n }\n else if(2*k+2<2*N){\n flip(a,b,k*2+1,l,(l+r)/2);\n flip(a,b,k*2+2,(l+r)/2,r);\n data[k]=data[k*2+1]+data[k*2+2];\n }\n }\n ll allsum(){\n eval(0);\n return data[0];\n }\n};\ntemplate<typename T>\nclass RSQ{\n public:\n ll size=1;\n vector<T>dataS;\n\n void init(int N){\n while(size<=N)size=size*2;\n dataS.assign(size*2,0);\n }\n\n void update(int p,T x){\n p=p+size;\n dataS[p]=x;\n while(p>1){\n p>>=1;\n dataS[p]=dataS[p*2]+dataS[p*2+1];\n }\n }\n\n T ISum(int l,int r,int a,int b,int u){\n if(r<=a||b<=l)return 0;\n if(l<=a&&b<=r)return dataS[u];\n int m=(a+b)>>1;\n T L=ISum(l,r,a,m,u*2);\n T R=ISum(l,r,m,b,u*2+1);\n return L+R;\n }\n T Sum(int l,int r){return ISum(l,r,0,size,1);}\n};\n\nint main(){\n ll K,N,Q;cin>>K>>N>>Q;\n vector<ll>A(N);\n rep(i,N)cin>>A[i];\n RSQ<ll>S;\n seg seg;\n S.init(N+1);\n seg.init(N);\n rep(i,N){\n if(A[i]==0){\n S.update(i+1,1);\n }\n else {\n int t = 1;\n if(S.Sum(0,i+1)%2==1)t=-1;\n seg.update(i,A[i]*t);\n }\n }\n rep(q,Q){\n int l,r;cin>>l>>r;l--;r--;\n if(A[l]!=A[r]){\n if(A[l]!=0&&A[r]!=0){\n int t=1;\n if(S.Sum(0,l+1)%2==1)t=-1;\n seg.update(l,A[r]*t);\n t=1;\n if(S.Sum(0,r+1)%2==1)t=-1;\n seg.update(r,A[l]*t);\n swap(A[l],A[r]);\n }\n else if(A[l]==0){\n S.update(r+1,1);\n S.update(l+1,0);\n int t=1;\n if(S.Sum(0,l+1)%2==1)t=-1;\n seg.update(l,A[r]*t);\n seg.update(r,0);\n seg.flip(l+1,r);\n swap(A[l],A[r]);\n }\n else if(A[r]==0){\n S.update(r+1,0);\n S.update(l+1,1);\n int t=1;\n if(S.Sum(0,r+1)%2==1)t=-1;\n seg.update(r,A[l]*t);\n seg.update(l,0);\n seg.flip(l+1,r);\n swap(A[l],A[r]);\n }\n }\n ll d = seg.allsum();\n d=1-d;\n ll k = (abs(d)+K-1)/K;\n d+=k*K;\n d%=K;\n if(d==0)d=K;\n if(S.Sum(0,N+1)%2==1)d*=-1;\n cout<<d<<endl;\n }\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 10008, "score_of_the_acc": -0.5268, "final_rank": 15 }, { "submission_id": "aoj_0390_9634635", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing i64 = long long;\n\n#define rep(i, a, b) for (int i = (a); i < (b); i++)\n#define repi(i, a, b) for (int i = (a) - 1; i >= (b); --i)\n\nstruct S {\n i64 a, b;\n S() : a(1), b(0) {}\n S(i64 a_, i64 b_) : a(a_), b(b_) {}\n};\n\nS op(S l, S r) {\n return S(l.a * r.a, l.b + l.a * r.b);\n}\n\nS e() { return S(); }\n\nstruct Seg {\n int _n, size, log;\n vector<S> d;\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n\n Seg() = default;\n Seg(const vector<int> &v) : _n(v.size()), log(0) {\n while ((1 << log) < _n) log++;\n size = 1 << log;\n d = vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) {\n if (v[i] == 0) d[size + i] = S(-1, 0);\n else d[size + i] = S(1, -v[i]);\n // cout << d[i].a << \" \" << d[i].b << endl;\n }\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p and p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p and p < _n);\n return d[p + size];\n }\n\n S all_prod() { return d[1]; }\n};\n\nint main() {\n int k, n, q;\n cin >> k >> n >> q;\n vector<int> a(n);\n rep (i, 0, n) cin >> a[i];\n Seg seg(a);\n // repi (i, 8, 1)\n // cout << seg.d[i].a << \" \" << seg.d[i].b << endl;\n\n rep (_, 0, q) {\n int l, r;\n cin >> l >> r;\n --l, --r;\n S left = seg.get(l), right = seg.get(r);\n seg.set(l, right);\n seg.set(r, left);\n S f = seg.all_prod();\n // cout << f.a << \" \" << f.b << endl;\n int pos = (1 + f.b) % k;\n if (pos < 0) pos += k;\n if (pos == 0) pos = k;\n if (f.a == 1) cout << pos << \"\\n\";\n else cout << -pos << \"\\n\";\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 7520, "score_of_the_acc": -0.2648, "final_rank": 10 }, { "submission_id": "aoj_0390_9632264", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n6:27~\n*/\n\ntemplate<class S,S(*op)(S,S),S(*e)()>\nstruct segtree{\n\tvector<S> dat;\n\tint n;\n\n\tsegtree(int n_){\n\t\tint x=1;\n\t\twhile(x<n_)x*=2;\n\t\tn=x;\n\t\tdat.resize(2*n,e());\n\t}\n\n\tvoid set(int p,S x){\n\t\tp+=n;\n\t\tdat[p]=x;\n\t\twhile(p>1){\n\t\t\tp/=2;\n\t\t\tdat[p]=op(dat[2*p],dat[2*p+1]);\n\t\t}\n\t}\n\n\tS prod_sub(int l,int r,int idx,int a,int b){\n\t\tif(r<=a||b<=l)return e();\n\t\tif(a<=l&&r<=b)return dat[idx];\n\t\tint m=(l+r)/2;\n\t\tS resL=prod_sub(l,m,2*idx,a,b);\n\t\tS resR=prod_sub(m,r,2*idx+1,a,b);\n\t\treturn op(resL,resR);\n\t}\n\n\tS prod(int l,int r){\n\t\treturn prod_sub(0,n,1,l,r);\n\t}\n};\n\nint mod;\n\nusing S=array<array<int,2>,2>;\n\nS op(S x,S y){\n\tS z={};\n\tfor(int i=0;i<2;i++){\n\t\tfor(int j=0;j<2;j++){\n\t\t\tfor(int k=0;k<2;k++){\n\t\t\t\tz[i][j]+=x[i][k]*y[k][j];\n\t\t\t}\n\t\t}\n\t}\n\tz[0][0]=(z[0][0]%mod+mod)%mod;\n\tz[1][0]=(z[1][0]%mod+mod)%mod;\n\treturn z;\n}\n\nS e(){\n\tS z;\n\tz[0]={1,0};\n\tz[1]={0,1};\n\treturn z;\n}\n\nsigned main(){\n\tint K,n,q;cin>>K>>n>>q;\n\tmod=K;\n\tvector<int> a(n);\n\tfor(auto&&e:a)cin>>e;\n\t\n\tsegtree<S,op,e> seg(n);\n\n\tauto update=[&](int i){\n\t\tif(a[i]==0){\n\t\t\tS z;\n\t\t\tz[0]={1,0};\n\t\t\tz[1]={0,-1};\n\t\t\tseg.set(i,z);\n\t\t}else{\n\t\t\tif(a[i]<0){\n\t\t\t\tS z;\n\t\t\t\tz[0]={1,0};\n\t\t\t\tz[1]={-a[i],1};\n\t\t\t\tseg.set(i,z);\n\t\t\t}else{\n\t\t\t\tS z;\n\t\t\t\tz[0]={1,0};\n\t\t\t\tz[1]={mod-a[i],1};\n\t\t\t\tseg.set(i,z);\n\t\t\t}\n\t\t}\n\t};\n\n\tfor(int i=0;i<n;i++){\n\t\tupdate(i);\n\t}\n\n\twhile(q--){\n\t\tint l,r;cin>>l>>r;l--;r--;\n\n\t\tswap(a[l],a[r]);\n\t\tupdate(l);\n\t\tupdate(r);\n\n\t\tauto ret=seg.prod(0,n);\n\n\t\tif(ret[1][1]==1){\n\t\t\tcout<<(ret[1][0])+1<<endl;\n\t\t}else{\n\t\t\tcout<<-(ret[1][0]+1)<<endl;\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 12144, "score_of_the_acc": -0.8402, "final_rank": 18 }, { "submission_id": "aoj_0390_9574479", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tlong long k,n,q;\n\tcin >> k >> n >> q;\n\tvector<long long> a(n);\n\tlong long m = 1ll;\n\twhile(m * m < n) m++;\n\tvector<long long> u(m,false),v(m,0ll),t(n,true);\n\tfor(long long i = 0ll;i < n;i++){\n\t\tcin >> a[i];\n\t\ta[i] = -a[i];\n\t\tif(i != 0ll){\n\t\t\tt[i] = t[i - 1ll];\n\t\t}\n\t\tif(a[i] == 0ll){\n\t\t\tt[i] ^= 1ll;\n\t\t}\n\t\tif(t[i]){\n\t\t\tv[i / m] += a[i];\n\t\t}else{\n\t\t\tv[i / m] -= a[i];\n\t\t}\n\t}\n\tauto f = [&](long long x,long long y){\n\t\tbool flg = false;\n\t\tif((a[x] == 0ll && y != 0ll) || (a[x] != 0ll && y == 0ll)){\n\t\t\tflg = true;\n\t\t}\n\t\ta[x] = y;\n\t\tfor(long long i = 0ll;i < m;i++){\n\t\t\tlong long left = i * m,right = left + m - 1ll;\n\t\t\tif(right < x){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif(left <= x && x <= right){\n\t\t\t\tv[i] = 0ll;\n\t\t\t\tfor(long long j = left;j <= min(right,n - 1ll);j++){\n\t\t\t\t\tif(u[i]){\n\t\t\t\t\t\tt[j] ^= true;\n\t\t\t\t\t}\n\t\t\t\t\tif(flg && x <= j){\n\t\t\t\t\t\tt[j] ^= true;\n\t\t\t\t\t}\n\t\t\t\t\tif(t[j]){\n\t\t\t\t\t\tv[i] += a[j];\n\t\t\t\t\t}else{\n\t\t\t\t\t\tv[i] -= a[j];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tu[i] = false;\n\t\t\t}else{\n\t\t\t\tu[i] ^= flg;\n\t\t\t}\n\t\t}\n\t};\n\tauto cal = [&]() -> long long {\n\t\tlong long ans = 0ll;\n\t\tfor(long long i = 0ll;i < m;i++){\n\t\t\tif(u[i]){\n\t\t\t\tans -= v[i];\n\t\t\t}else{\n\t\t\t\tans += v[i];\n\t\t\t}\n\t\t}\n\t\tans += k * (abs(ans) / k + 10ll);\n\t\tans %= k;\n\t\tans++;\n\t\tif((t[n - 1ll] ^ u[(n - 1ll) / m]) == false){\n\t\t\tans = -ans;\n\t\t}\n\t\treturn ans;\n\t};\n\tfor(long long i = 0ll;i < q;i++){\n\t\tlong long x,y;\n\t\tcin >> x >> y;\n\t\tx--;y--;\n\t\tlong long X = a[x],Y = a[y];\n\t\tf(x,Y);\n\t\tf(y,X);\n\t\tcout << cal() << endl;\n\t}\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 4660, "score_of_the_acc": -0.5946, "final_rank": 17 }, { "submission_id": "aoj_0390_9539074", "code_snippet": "#include<stdio.h>\n#include<iostream>\n#include<vector>\n#include<cassert>\n#include<algorithm>\nusing namespace std;\n\nstatic const int INFTY = (1LL<<31)-1;\nstatic const int MAX_N = (1<<17); // 131072\n\nlong long K, N, Q, A[MAX_N];\n\nint n;\nlong long D[2*MAX_N-1];\nint F[2*MAX_N-1];\n\nvoid init(int n_){\n n = 1;\n while( n < n_ ) n *= 2;\n for ( int i = 0; i < 2*n-1; i++ ) D[i] = 0;\n for ( int i = 0; i < 2*n-1; i++ ) F[i] = 0;\n}\n\nvoid update(int k, int a){\n k += n - 1;\n D[k] = a;\n F[k] = (a == 0);\n while( k > 0 ){\n k = (k - 1)/2;\n D[k] = D[k*2+1] + D[k*2+2]*(F[k*2+1]?(-1):1);\n F[k] = (F[k*2+1] + F[k*2+2])%2;\n }\n}\n\n// [a, b)\npair<long long,int> query(int a, int b, int k, int l, int r){\n if ( r <= a || b <= l ) return make_pair(0, 0);\n if ( a <= l && r <= b ) return make_pair(D[k], F[k]);\n else{\n //int vl = query(a, b, k*2 + 1, l, (l + r)/2);\n // int vr = query(a, b, k*2 + 2, (l + r)/2, r);\n // return min(vl, vr);\n pair<long long, int> vl = query(a, b, k*2 + 1, l, (l + r)/2);\n pair<long long, int> vr = query(a, b, k*2 + 2, (l + r)/2, r);\n pair<long long, int> res;\n res.first = vl.first + vr.first*(vl.second?(-1):1);\n res.second = (vl.second + vr.second)%2;\n return res;\n }\n}\n\n// [a, b]\npair<long long,int> findMin(int a, int b){\n return query(a, b+1, 0, 0, n);\n}\n\nvoid dump(){\n for ( int i = 0; i < n; i++ ) cout << D[i] << \" \";\n cout << endl;\n}\n\nmain(){\n int L, R;\n cin >> K >> N >> Q;\n init(N);\n for ( int i = 0; i < N; i++ ) cin >> A[i];\n for ( int i = 0; i < N; i++ ) update(i, A[i]);\n for ( int i = 0; i < Q; i++ ){\n cin >> L >> R; L--; R--;\n swap(A[L], A[R]);\n update(L, A[L]);\n update(R, A[R]);\n pair<long long, int> res = findMin(0, N-1);\n long long p = res.first;\n bool isng = (p < 0);\n\n if ( isng ) p *= -1;\n p %= K;\n if ( isng ) cout << (p+1)*(res.second?-1:1) << endl;\n else cout << ((K-p)%K+1)*(res.second?-1:1) << endl;\n }\n\n\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 6936, "score_of_the_acc": -0.4226, "final_rank": 13 }, { "submission_id": "aoj_0390_9033563", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n\n#include <algorithm>\n#include <cassert>\n#include <functional>\n#include <vector>\n\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#if __cplusplus >= 202002L\n#include <bit>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n#if __cplusplus >= 202002L\n\nusing std::bit_ceil;\n\n#else\n\nunsigned int bit_ceil(unsigned int n) {\n unsigned int x = 1;\n while (x < (unsigned int)(n)) x *= 2;\n return x;\n}\n\n#endif\n\nint countr_zero(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\nconstexpr int countr_zero_constexpr(unsigned int n) {\n int x = 0;\n while (!(n & (1 << x))) x++;\n return x;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\n#if __cplusplus >= 201703L\n\ntemplate <class S,\n auto op,\n auto e,\n class F,\n auto mapping,\n auto composition,\n auto id>\nstruct lazy_segtree {\n static_assert(std::is_convertible_v<decltype(op), std::function<S(S, S)>>,\n \"op must work as S(S, S)\");\n static_assert(std::is_convertible_v<decltype(e), std::function<S()>>,\n \"e must work as S()\");\n static_assert(\n std::is_convertible_v<decltype(mapping), std::function<S(F, S)>>,\n \"mapping must work as F(F, S)\");\n static_assert(\n std::is_convertible_v<decltype(composition), std::function<F(F, F)>>,\n \"compostiion must work as F(F, F)\");\n static_assert(std::is_convertible_v<decltype(id), std::function<F()>>,\n \"id must work as F()\");\n\n#else\n\ntemplate <class S,\n S (*op)(S, S),\n S (*e)(),\n class F,\n S (*mapping)(F, S),\n F (*composition)(F, F),\n F (*id)()>\nstruct lazy_segtree {\n\n#endif\n\n public:\n lazy_segtree() : lazy_segtree(0) {}\n explicit lazy_segtree(int n) : lazy_segtree(std::vector<S>(n, e())) {}\n explicit lazy_segtree(const std::vector<S>& v) : _n(int(v.size())) {\n size = (int)internal::bit_ceil((unsigned int)(_n));\n log = internal::countr_zero((unsigned int)size);\n d = std::vector<S>(2 * size, e());\n lz = std::vector<F>(size, id());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n return d[p];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return e();\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n S sml = e(), smr = e();\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n void apply(int p, F f) {\n assert(0 <= p && p < _n);\n p += size;\n for (int i = log; i >= 1; i--) push(p >> i);\n d[p] = mapping(f, d[p]);\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n void apply(int l, int r, F f) {\n assert(0 <= l && l <= r && r <= _n);\n if (l == r) return;\n\n l += size;\n r += size;\n\n for (int i = log; i >= 1; i--) {\n if (((l >> i) << i) != l) push(l >> i);\n if (((r >> i) << i) != r) push((r - 1) >> i);\n }\n\n {\n int l2 = l, r2 = r;\n while (l < r) {\n if (l & 1) all_apply(l++, f);\n if (r & 1) all_apply(--r, f);\n l >>= 1;\n r >>= 1;\n }\n l = l2;\n r = r2;\n }\n\n for (int i = 1; i <= log; i++) {\n if (((l >> i) << i) != l) update(l >> i);\n if (((r >> i) << i) != r) update((r - 1) >> i);\n }\n }\n\n template <bool (*g)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return g(x); });\n }\n template <class G> int max_right(int l, G g) {\n assert(0 <= l && l <= _n);\n assert(g(e()));\n if (l == _n) return _n;\n l += size;\n for (int i = log; i >= 1; i--) push(l >> i);\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!g(op(sm, d[l]))) {\n while (l < size) {\n push(l);\n l = (2 * l);\n if (g(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*g)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return g(x); });\n }\n template <class G> int min_left(int r, G g) {\n assert(0 <= r && r <= _n);\n assert(g(e()));\n if (r == 0) return 0;\n r += size;\n for (int i = log; i >= 1; i--) push((r - 1) >> i);\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!g(op(d[r], sm))) {\n while (r < size) {\n push(r);\n r = (2 * r + 1);\n if (g(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n std::vector<F> lz;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n void all_apply(int k, F f) {\n d[k] = mapping(f, d[k]);\n if (k < size) lz[k] = composition(f, lz[k]);\n }\n void push(int k) {\n all_apply(2 * k, lz[k]);\n all_apply(2 * k + 1, lz[k]);\n lz[k] = id();\n }\n};\n\n} // namespace atcoder\n\nusing namespace atcoder;\n\nusing S = array<long long, 2>;\nusing F = long long;\n\nS op(S x, S y) {\n return S{x[0]+y[0], x[1]+y[1]};\n}\nS e() {\n return S{0, 0};\n}\nS mapping(F f, S x) {\n return S{x[0]*f, x[1]};\n}\nF composition(F f, F g) {\n return f*g;\n}\nF id() {\n return 1;\n}\n\nint main() {\n int N, Q;\n long long K;\n cin >> K >> N >> Q;\n lazy_segtree<S, op, e, F, mapping, composition, id> seg(N);\n for(int i = 0; i < N; i++) {\n long long A;\n cin >> A;\n seg.set(i, S{A, (A == 0)});\n }\n for(int i = 0; i < N; i++) {\n if(seg.get(i)[0] == 0) seg.apply(i, N, -1);\n }\n for(int q = 0; q < Q; q++) {\n int L, R;\n cin >> L >> R;\n L--, R--;\n S vl = seg.get(L), vr = seg.get(R);\n S pl = seg.prod(0, L), pr = seg.prod(0, R);\n if(vl[0] == 0) seg.apply(L, R, -1);\n if(vr[0] == 0) seg.apply(L, R, -1);\n if(vl[0] != 0 && pl[1]%2 != (pr[1]+vr[1])%2) vl[0] *= -1;\n if(vr[0] != 0 && pr[1]%2 != pl[1]%2) vr[0] *= -1;\n seg.set(L, vr), seg.set(R, vl);\n auto [ap, c0] = seg.all_prod();\n ap = ((ap%K)+K)%K;\n cout << (c0%2 == 0 ? 1 : -1)*(ap == 0 ? 1 : K+1-ap) << endl;\n }\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 9904, "score_of_the_acc": -0.4449, "final_rank": 14 }, { "submission_id": "aoj_0390_8985354", "code_snippet": "#include <vector>\n#include <iostream>\nusing namespace std;\n\ntemplate<class S> class segtree {\nprivate:\n\tint bits;\n\tvector<S> val;\npublic:\n\tsegtree() : bits(0) {}\n\tsegtree(vector<S> v) : bits(v.size() >= 2 ? 32 - __builtin_clz(v.size() - 1) : 0), val(vector<S>(2 << bits, S::e())) {\n\t\tfor (int i = 0; i < v.size(); i++) {\n\t\t\tval[(1 << bits) + i] = v[i];\n\t\t}\n\t\tfor (int i = (1 << bits) - 1; i >= 0; i--) {\n\t\t\tval[i] = val[i * 2 + 0].op(val[i * 2 + 1]);\n\t\t}\n\t}\n\tvoid update(int pos, S x) {\n\t\tpos += 1 << bits;\n\t\tval[pos] = x;\n\t\twhile (pos > 1) {\n\t\t\tpos /= 2;\n\t\t\tval[pos] = val[pos * 2 + 0].op(val[pos * 2 + 1]);\n\t\t}\n\t}\n\tS query(int l, int r) {\n\t\tS lq = S::e(), rq = S::e();\n\t\tl += 1 << bits;\n\t\tr += 1 << bits;\n\t\twhile (l != r) {\n\t\t\tif (l & 1) lq = lq.op(val[l++]);\n\t\t\tif (r & 1) rq = val[--r].op(rq);\n\t\t\tl /= 2;\n\t\t\tr /= 2;\n\t\t}\n\t\treturn lq.op(rq);\n\t}\n};\n\nclass monoid {\nprivate:\n\tint f; long long x;\npublic:\n\tmonoid() : f(0), x(0) {}\n\tmonoid(int f_, long long x_) : f(f_), x(x_) {}\n\tstatic monoid e() { return {0, 0}; }\n\tint get(int l) const {\n\t\tint p = int(x >= 0 ? x % l : (x + 1) % l + (l - 1));\n\t\treturn (f == 0 ? p + 1 : -(p + 1));\n\t}\n\tmonoid op(const monoid& m) const {\n\t\treturn {f ^ m.f, f == 0 ? x + m.x : x - m.x};\n\t}\n};\n\nint main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint K, N, Q;\n\tcin >> K >> N >> Q;\n\tvector<monoid> V(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tint a;\n\t\tcin >> a;\n\t\tV[i] = (a != 0 ? monoid(0, -a) : monoid(1, 0));\n\t}\n\tsegtree<monoid> seg(V);\n\tfor (int i = 0; i < Q; i++) {\n\t\tint l, r;\n\t\tcin >> l >> r;\n\t\tl--; r--;\n\t\tswap(V[l], V[r]);\n\t\tseg.update(l, V[l]);\n\t\tseg.update(r, V[r]);\n\t\tmonoid res = seg.query(0, N);\n\t\tlong long ans = res.get(K);\n\t\tcout << ans << '\\n';\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10296, "score_of_the_acc": -0.0425, "final_rank": 2 }, { "submission_id": "aoj_0390_8719311", "code_snippet": "#include <bits/stdc++.h>\n\nstruct Data {\n Data(long long v = 0, bool i = false): value(v), inv(i) {}\n long long value;\n bool inv;\n};\n\nData op(Data lhs, Data rhs) {\n return Data(lhs.value + (lhs.inv ? -1 : 1) * rhs.value, lhs.inv ^ rhs.inv);\n}\n\nstruct SegTree {\n int size;\n std::vector<Data> data;\n SegTree(const std::vector<long long>& vec): size(vec.size()), data(2 * vec.size()) {\n for (int i = 0; i < size; i++) {\n if (vec[i] == 0) {\n data[i + size] = Data(vec[i], true);\n } else {\n data[i + size] = Data(vec[i], false);\n }\n }\n for (int i = size - 1; i > 0; i--) {\n data[i] = op(data[2 * i], data[2 * i + 1]);\n }\n }\n void swap(int lhs, int rhs) {\n auto ld = data[lhs + size];\n auto rd = data[rhs + size];\n set(lhs, rd);\n set(rhs, ld);\n }\n void set(int pos, Data d) {\n pos += size;\n data[pos] = d;\n for (pos >>= 1; pos > 0; pos >>= 1) {\n data[pos] = op(data[2 * pos], data[2 * pos + 1]);\n }\n }\n Data all_prod() {\n Data lhs;\n Data rhs;\n for (int left = size, right = 2 * size; left < right; left >>= 1, right >>= 1) {\n if (left & 1) lhs = op(lhs, data[left++]);\n if (right & 1) rhs = op(data[--right], rhs);\n }\n return op(lhs, rhs);\n }\n};\n\nint main() {\n long long k;\n int n, q;\n std::cin >> k >> n >> q;\n const long long INF = ((long long)1e15 / k) * k;\n std::vector<long long> a(n);\n for (int i = 0; i < n; i++) std::cin >> a[i];\n SegTree segtree(a);\n // auto d = segtree.all_prod();\n // std::cerr << d.value << ' ' << d.inv << '\\n';\n for (int i = 0; i < q; i++) {\n int l, r;\n std::cin >> l >> r;\n l--;\n r--;\n segtree.swap(l, r);\n auto d = segtree.all_prod();\n // std::cerr << d.value << ' ' << d.inv << '\\n';\n long long pos = (INF - d.value) % k + 1;\n std::cout << (d.inv ? -1 : 1) * pos << '\\n';\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 6996, "score_of_the_acc": -0.2608, "final_rank": 9 }, { "submission_id": "aoj_0390_8291057", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\n// ============================================================== Range Sum & Range Inverse & Range Add ==============================================================\nclass SegmentTree {\npublic:\n\tint size_ = 1;\n\tvector<long long> laz;\n\tvector<long long> dat;\n\t\n\t// Initialize\n\tvoid init(int sz) {\n\t\tsize_ = 1;\n\t\twhile (size_ <= sz) size_ *= 2;\n\t\tdat.resize(size_ * 2, 0);\n\t\tlaz.resize(size_ * 2, 1);\n\t}\n\n\t// Refresh laz\n\tvoid refresh(int pos) {\n\t\tif (pos < size_) {\n\t\t\tlaz[pos * 2 + 0] *= laz[pos];\n\t\t\tlaz[pos * 2 + 1] *= laz[pos];\n\t\t\tdat[pos] = dat[pos * 2 + 0] * laz[pos * 2 + 0] + dat[pos * 2 + 1] * laz[pos * 2 + 1];\n\t\t\tlaz[pos] = 1;\n\t\t}\n\t\telse {\n\t\t\tdat[pos] *= laz[pos];\n\t\t\tlaz[pos] = 1;\n\t\t}\n\t}\n\n\t// Add dat[pos] by x\n\tvoid add(int pos, long long x) {\n\t\tvector<int> path;\n\t\tint cur = pos + size_;\n\t\twhile (cur >= 1) {\n\t\t\tpath.push_back(cur);\n\t\t\tcur >>= 1;\n\t\t}\n\t\tfor (int i = path.size() - 1; i >= 0; i--) refresh(path[i]);\n\t\tpos += size_;\n\t\tdat[pos] += x;\n\t\twhile (pos >= 2) {\n\t\t\tpos >>= 1;\n\t\t\trefresh(pos);\n\t\t}\n\t}\n\n\t// Helper\n\tvoid inverse_(int l, int r, int a, int b, int u) {\n\t\tif (l <= a && b <= r) {\n\t\t\tlaz[u] *= -1;\n\t\t\trefresh(u);\n\t\t\treturn;\n\t\t}\n\t\tif (r <= a || b <= l) return;\n\t\trefresh(u);\n\t\tinverse_(l, r, a, (a + b) / 2, u * 2 + 0);\n\t\tinverse_(l, r, (a + b) / 2, b, u * 2 + 1);\n\t\trefresh(u);\n\t}\n\n\t// Inverse Range [l, r)\n\tvoid inverse(int l, int r) {\n\t\tinverse_(l, r, 0, size_, 1);\n\t}\n\n\t// Get Sum\n\tlong long getsum() {\n\t\treturn dat[1];\n\t}\n};\n\n// ============================================================== Binary Indexed Tree ==============================================================\nclass BIT {\npublic:\n\tint size_;\n\tvector<long long> dat;\n\n\tvoid init(int sz) {\n\t\tsize_ = sz + 2;\n\t\tdat.resize(size_ + 2, 0);\n\t}\n\n\tvoid add(int pos, long long x) {\n\t\tpos += 1;\n\t\twhile (pos <= size_) {\n\t\t\tdat[pos] += x;\n\t\t\tpos += (pos & -pos);\n\t\t}\n\t}\n\n\tlong long sum(int pos) {\n\t\tlong long s = 0; pos++;\n\t\twhile (pos >= 1) {\n\t\t\ts += dat[pos];\n\t\t\tpos -= (pos & -pos);\n\t\t}\n\t\treturn s;\n\t}\n};\n\n// ============================================================== Main Part ==============================================================\nlong long INF = 2000000000;\nlong long N, A[100009];\nlong long K;\nlong long Q, L[100009], R[100009];\nlong long Record[100009];\nBIT Z1;\nSegmentTree Z2;\n\nvoid Add(int pos, long long x) {\n\tif (x == 0) {\n\t\tZ1.add(pos, 1);\n\t\tZ2.inverse(pos, N + 1);\n\t}\n\telse {\n\t\tint cnt = Z1.sum(pos);\n\t\tif (cnt % 2 == 0) Z2.add(pos, +x);\n\t\tif (cnt % 2 == 1) Z2.add(pos, -x);\n\t}\n\tRecord[pos] = x;\n}\n\nvoid Delete(int pos) {\n\tif (Record[pos] == 0) {\n\t\tZ1.add(pos, -1);\n\t\tZ2.inverse(pos, N + 1);\n\t}\n\telse {\n\t\tint cnt = Z1.sum(pos);\n\t\tif (cnt % 2 == 0) Z2.add(pos, -Record[pos]);\n\t\tif (cnt % 2 == 1) Z2.add(pos, +Record[pos]);\n\t}\n\tRecord[pos] = INF;\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> K >> N >> Q;\n\tfor (int i = 1; i <= N; i++) cin >> A[i];\n\tfor (int i = 1; i <= Q; i++) cin >> L[i] >> R[i];\n\n\t// Step 2. Initialize\n\tZ1.init(N + 2);\n\tZ2.init(N + 2);\n\tfor (int i = 1; i <= N; i++) Record[i] = INF;\n\tfor (int i = 1; i <= N; i++) Add(i, A[i]);\n\tlong long cnt3 = Z1.sum(N);\n\tlong long cnt4 = Z2.getsum();\n\n\t// Step 3. Simulation\n\tfor (int i = 1; i <= Q; i++) {\n\t\tDelete(L[i]);\n\t\tDelete(R[i]);\n\t\tswap(A[L[i]], A[R[i]]);\n\t\tAdd(L[i], A[L[i]]);\n\t\tAdd(R[i], A[R[i]]);\n\t\tlong long cnt1 = Z1.sum(N);\n\t\tlong long cnt2 = Z2.getsum();\n\t\tlong long eval = (-cnt2 + 1000000000LL * K) % K;\n\t\tif (cnt1 % 2 == 0) cout << +(eval + 1) << endl;\n\t\tif (cnt1 % 2 == 1) cout << -(eval + 1) << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 10600, "score_of_the_acc": -0.5312, "final_rank": 16 }, { "submission_id": "aoj_0390_6974614", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0390.cc: Disc\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\n\n/* typedef */\n\nstruct Elm {\n static int k;\n int x, d; // 0<=x<k, d=1 or -1\n Elm(): x(0), d(1) {}\n Elm(int _x, int _d): x(_x), d(_d) {}\n Elm(int a) {\n if (a == 0) x = 0, d = -1;\n else if (a > 0) x = (k - a % k) % k, d = 1;\n else x = -a % k, d = 1;\n }\n\n Elm operator+(const Elm &e) const {\n int dx = (d > 0) ? e.x : (k - e.x) % k;\n return Elm((x + dx) % k, d * e.d);\n }\n\n int val() { return (x + 1) * d; }\n};\n\nint Elm::k;\n\ntemplate <typename T>\nstruct SegTreeSum {\n int e2;\n vector<T> nodes;\n T defv;\n SegTreeSum() {}\n\n void init(int n, T _defv) {\n defv = _defv;\n for (e2 = 1; e2 < n; e2 <<= 1);\n nodes.assign(e2 * 2, defv);\n }\n\n T &geti(int i) { return nodes[e2 - 1 + i]; }\n void seti(int i, T v) { geti(i) = v; }\n\n void setall() {\n for (int j = e2 - 2; j >= 0; j--)\n nodes[j] = nodes[j * 2 + 1] + nodes[j * 2 + 2];\n }\n\n void set(int i, T v) {\n int j = e2 - 1 + i;\n nodes[j] = v;\n while (j > 0) {\n j = (j - 1) / 2;\n nodes[j] = nodes[j * 2 + 1] + nodes[j * 2 + 2];\n }\n }\n\n T sum_range(int r0, int r1, int k, int i0, int i1) {\n if (r1 <= i0 || i1 <= r0) return defv;\n if (r0 <= i0 && i1 <= r1) return nodes[k];\n\n int im = (i0 + i1) / 2;\n T v0 = sum_range(r0, r1, k * 2 + 1, i0, im);\n T v1 = sum_range(r0, r1, k * 2 + 2, im, i1);\n return v0 + v1;\n }\n T sum_range(int r0, int r1) { return sum_range(r0, r1, 0, 0, e2); }\n};\n\n/* global variables */\n\nint as[MAX_N];\nSegTreeSum<Elm> st;\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int k, n, qn;\n scanf(\"%d%d%d\", &k, &n, &qn);\n Elm::k = k;\n\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n st.init(n, Elm(0, 1));\n for (int i = 0; i < n; i++) st.seti(i, Elm(as[i]));\n st.setall();\n\n //Elm e = st.sum_range(0, n);\n //printf(\"%d\\n\", e.val());\n\n while (qn--) {\n int l, r;\n scanf(\"%d%d\", &l, &r);\n l--, r--;\n\n swap(as[l], as[r]);\n st.set(l, Elm(as[l]));\n st.set(r, Elm(as[r]));\n\n Elm e = st.sum_range(0, n);\n printf(\"%d\\n\", e.val());\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4964, "score_of_the_acc": -0.0834, "final_rank": 5 }, { "submission_id": "aoj_0390_6074229", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in: v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e: t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Segment Tree(セグメント木)\n * @docs docs/segment-tree.md\n */\ntemplate< typename Monoid, typename F >\nstruct SegmentTree {\n int n, sz;\n vector< Monoid > seg;\n\n const F f;\n const Monoid M1;\n\n SegmentTree() = default;\n\n explicit SegmentTree(int n, const F f, const Monoid &M1) : n(n), f(f), M1(M1) {\n sz = 1;\n while(sz < n) sz <<= 1;\n seg.assign(2 * sz, M1);\n }\n\n explicit SegmentTree(const vector< Monoid > &v, const F f, const Monoid &M1) :\n SegmentTree((int) v.size(), f, M1) {\n build(v);\n }\n\n void build(const vector< Monoid > &v) {\n assert(n == (int) v.size());\n for(int k = 0; k < n; k++) seg[k + sz] = v[k];\n for(int k = sz - 1; k > 0; k--) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n\n void set(int k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while(k >>= 1) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n\n Monoid get(int k) const {\n return seg[k + sz];\n }\n\n Monoid operator[](const int &k) const {\n return get(k);\n }\n\n void apply(int k, const Monoid &x) {\n k += sz;\n seg[k] = f(seg[k], x);\n while(k >>= 1) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n\n Monoid prod(int l, int r) const {\n Monoid L = M1, R = M1;\n for(l += sz, r += sz; l < r; l >>= 1, r >>= 1) {\n if(l & 1) L = f(L, seg[l++]);\n if(r & 1) R = f(seg[--r], R);\n }\n return f(L, R);\n }\n\n Monoid all_prod() const {\n return seg[1];\n }\n\n template< typename C >\n int find_first(int l, const C &check) const {\n if(l >= n) return n;\n l += sz;\n Monoid sum = M1;\n do {\n while((l & 1) == 0) l >>= 1;\n if(check(f(sum, seg[l]))) {\n while(l < sz) {\n l <<= 1;\n auto nxt = f(sum, seg[l]);\n if(not check(nxt)) {\n sum = nxt;\n l++;\n }\n }\n return l + 1 - sz;\n }\n sum = f(sum, seg[l++]);\n } while((l & -l) != l);\n return n;\n }\n\n template< typename C >\n int find_last(int r, const C &check) const {\n if(r <= 0) return -1;\n r += sz;\n Monoid sum = 0;\n do {\n r--;\n while(r > 1 and (r & 1)) r >>= 1;\n if(check(f(seg[r], sum))) {\n while(r < sz) {\n r = (r << 1) + 1;\n auto nxt = f(seg[r], sum);\n if(not check(nxt)) {\n sum = nxt;\n r--;\n }\n }\n return r - sz;\n }\n sum = f(seg[r], sum);\n } while((r & -r) != r);\n return -1;\n }\n};\n\ntemplate< typename Monoid, typename F >\nSegmentTree< Monoid, F > get_segment_tree(int N, const F &f, const Monoid &M1) {\n return SegmentTree{N, f, M1};\n}\n\ntemplate< typename Monoid, typename F >\nSegmentTree< Monoid, F > get_segment_tree(const vector< Monoid > &v, const F &f, const Monoid &M1) {\n return SegmentTree{v, f, M1};\n}\n\nint main() {\n int K, N, Q;\n cin >> K >> N >> Q;\n vector< int > A(N);\n cin >> A;\n using pi = pair< bool, int >;\n auto f = [&](pi a, pi b) {\n if(a.first) b.second = K - b.second;\n return pi(a.first ^ b.first, (a.second + b.second) % K);\n };\n vector< pi > dat(N);\n for(int i = 0; i < N; i++) {\n if(A[i] == 0) dat[i] = {true, 0};\n else if(A[i] > 0) dat[i] = {false, (K - A[i] % K) % K};\n else dat[i] = {false, -(A[i] % K)};\n }\n auto seg = get_segment_tree(dat, f, pi());\n while(Q--) {\n int l, r;\n cin >> l >> r;\n --l, --r;\n swap(dat[l], dat[r]);\n seg.set(l, dat[l]);\n seg.set(r, dat[r]);\n auto t = seg.all_prod();\n if(t.first) cout << \"-\";\n cout << t.second + 1 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6252, "score_of_the_acc": -0.039, "final_rank": 1 }, { "submission_id": "aoj_0390_5875701", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define pb emplace_back\n#define lb(v,k) (lower_bound(all(v),(k))-v.begin())\n#define ub(v,k) (upper_bound(all(v),(k))-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define all(a) a.begin(),a.end()\n#define rsort(a) {sort(all(a));reverse(all(a));}\n#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}\n#define popcnt __builtin_popcountll\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=998244353;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void outset(T s){auto itr=s.begin();while(itr!=s.end()){if(itr!=s.begin())cout<<' ';cout<<*itr;itr++;}cout<<'\\n';}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\n#define T P\nclass segtree{\n vector<T> seg;ll n;\npublic:\n T g=P(0,0);\n T f(T a,T b){\n if(a.se==0)return P(a.fi+b.fi,a.se^b.se);\n return P(a.fi-b.fi,a.se^b.se);\n }\n segtree(vector<T> v){\n seg=vector<T>(n*2,g);\n rep(i,v.size())seg[i+n]=v[i];\n for(ll i=n-1;i;i--)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n void update(ll i,T x){\n i+=n;seg[i]=x;\n for(i>>=1;i;i>>=1)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n T get(ll l,ll r){\n T resl=g,resr=g;\n for(l+=n,r+=n;l<r;l>>=1,r>>=1){\n if(l&1)resl=f(resl,seg[l++]);\n if(r&1)resr=f(seg[--r],resr);\n }\n return f(resl,resr);\n }\n};\nint main(){\n ll n,m,q;cin>>m>>n>>q;\n vp v(n);\n rep(i,n){\n cin>>v[i].fi;if(v[i].fi==0)v[i].se=1;\n }\n segtree seg(v);\n rep(i,q){\n ll l,r;cin>>l>>r;l--;r--;\n seg.update(l,v[r]);\n seg.update(r,v[l]);\n P res=seg.get(0,n);\n ll ans=(m-res.fi%m)%m+1;if(res.se)ans*=-1;\n out(ans);\n swap(v[l],v[r]);\n }\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 137384, "score_of_the_acc": -1.3243, "final_rank": 20 }, { "submission_id": "aoj_0390_5875675", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define pb emplace_back\n#define lb(v,k) (lower_bound(all(v),(k))-v.begin())\n#define ub(v,k) (upper_bound(all(v),(k))-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define all(a) a.begin(),a.end()\n#define rsort(a) {sort(all(a));reverse(all(a));}\n#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}\n#define popcnt __builtin_popcountll\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=998244353;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void outset(T s){auto itr=s.begin();while(itr!=s.end()){if(itr!=s.begin())cout<<' ';cout<<*itr;itr++;}cout<<'\\n';}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\nclass segtree{\n ll n;\n vp seg;\n P calc(ll a){\n if(a==0)return P(0,1);\n return P(a,0);\n }\n P f(P a,P b){\n if(a.se==0)return P(a.fi+b.fi,a.se^b.se);\n return P(a.fi-b.fi,a.se^b.se);\n }\npublic:\n segtree(vi v){\n n=v.size();\n seg=vp(n*2);\n rep(i,n)seg[i+n]=calc(v[i]);\n for(int i=n-1;i;i--)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n P get(ll l,ll r){\n P resl=P(0,0),resr=P(0,0);\n for(l+=n,r+=n;l<r;l>>=1,r>>=1){\n if(l&1)resl=f(resl,seg[l++]);\n if(r&1)resr=f(seg[--r],resr);\n }\n return f(resl,resr);\n }\n void update(ll i,ll x){\n i+=n;seg[i]=calc(x);\n for(i>>=1;i;i>>=1)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n};\nint main(){\n ll n,m,q;cin>>m>>n>>q;\n vi v(n);rep(i,n)cin>>v[i];\n segtree seg(v);\n rep(i,q){\n ll l,r;cin>>l>>r;l--;r--;\n seg.update(l,v[r]);\n seg.update(r,v[l]);\n P res=seg.get(0,n);\n ll ans=(m-res.fi%m)%m+1;if(res.se)ans*=-1;\n out(ans);\n swap(v[l],v[r]);\n }\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 7660, "score_of_the_acc": -0.2658, "final_rank": 11 }, { "submission_id": "aoj_0390_5875671", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define pb emplace_back\n#define lb(v,k) (lower_bound(all(v),(k))-v.begin())\n#define ub(v,k) (upper_bound(all(v),(k))-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define all(a) a.begin(),a.end()\n#define rsort(a) {sort(all(a));reverse(all(a));}\n#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}\n#define popcnt __builtin_popcountll\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=998244353;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void outset(T s){auto itr=s.begin();while(itr!=s.end()){if(itr!=s.begin())cout<<' ';cout<<*itr;itr++;}cout<<'\\n';}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\nclass segtree{\n ll n;\n vp seg;\n P calc(ll a){\n if(a==0)return P(0,1);\n return P(a,0);\n }\n P f(P a,P b){\n if(a.se==0)return P(a.fi+b.fi,a.se^b.se);\n return P(a.fi-b.fi,a.se^b.se);\n }\npublic:\n segtree(vi v){\n n=v.size();\n seg=vp(n*2);\n rep(i,n)seg[i+n]=calc(v[i]);\n for(int i=n-1;i;i--)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n P get(ll l,ll r){\n stack<P> st;\n P res=P(0,0);\n for(l+=n,r+=n;l<r;l>>=1,r>>=1){\n if(l&1)res=f(res,seg[l++]);\n if(r&1)st.push(seg[--r]);\n }\n while(st.size()){\n res=f(res,st.top());st.pop();\n }\n return res;\n }\n void update(ll i,ll x){\n i+=n;seg[i]=calc(x);\n for(i>>=1;i;i>>=1)seg[i]=f(seg[i*2],seg[i*2+1]);\n }\n};\nint main(){\n ll n,m,q;cin>>m>>n>>q;\n vi v(n);rep(i,n)cin>>v[i];\n segtree seg(v);\n rep(i,q){\n ll l,r;cin>>l>>r;l--;r--;\n seg.update(l,v[r]);\n seg.update(r,v[l]);\n P res=seg.get(0,n);\n ll ans=(m-res.fi%m)%m+1;if(res.se)ans*=-1;\n out(ans);\n swap(v[l],v[r]);\n }\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7852, "score_of_the_acc": -0.2943, "final_rank": 12 }, { "submission_id": "aoj_0390_5868495", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\n#pragma warning (disable: 4996)\nusing namespace std;\n\nusing ll = long long;\n/*unsigned euclidean_gcd(unsigned a, unsigned b) {\n if (a < b) return euclidean_gcd(b, a);\n unsigned r;\n while ((r = a % b)) {\n a = b;\n b = r;\n }\n return b;\n}\n\nll ll_gcd(ll a, ll b) {\n if (a < b) return ll_gcd(b, a);\n ll r;\n while ((r = a % b)) {\n a = b;\n b = r;\n }\n return b;\n}\n\nstruct UnionFind {\n vector <ll> par;\n vector <ll> siz;\n UnionFind(ll sz_) : par(sz_), siz(sz_, 1LL) {\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n void init(ll sz_) {\n par.resize(sz_);\n siz.assign(sz_, 1LL);\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n ll root(ll x) {\n while (par[x] != x) {\n x = par[x] = par[par[x]];\n }\n return x;\n }\n bool merge(ll x, ll y) {\n x = root(x);\n y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(ll x, ll y) {\n return root(x) == root(y);\n }\n\n ll size(ll x) {\n return siz[root(x)];\n }\n};\n\nlong long modpow(long long a, long long n, long long mod) {\n if (n < 0)return 0;\n long long res = 1;\n while (n > 0) {\n if (n & 1) res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\n\nlong long modinv(long long a, long long mod) {\n return modpow(a, mod - 2, mod);\n}\n\nll merge_cnt(vector<ll>& a) {\n int n = a.size();\n if (n <= 1) { return 0; }\n\n ll cnt = 0;\n vector<ll> b(a.begin(), a.begin() + n / 2);\n vector<ll> c(a.begin() + n / 2, a.end());\n\n cnt += merge_cnt(b);\n cnt += merge_cnt(c);\n\n int ai = 0, bi = 0, ci = 0;\n while (ai < n) {\n if (bi < b.size() && (ci == c.size() || b[bi] <= c[ci])) {\n a[ai++] = b[bi++];\n }\n else {\n cnt += n / 2 - bi;\n a[ai++] = c[ci++];\n }\n }\n return cnt;\n}\n\nstruct edge { ll to; ll cost; };\ntypedef pair<ll, ll> P;\nstruct graph {\n ll V;\n vector<vector<edge> > G;\n vector<ll> d;\n\n graph(ll n) {\n init(n);\n }\n\n void init(ll n) {\n V = n;\n G.resize(V);\n d.resize(V);\n for (int i = 0; i < V; i++) {\n d[i] = 2000000000000000000;\n }\n }\n\n void add_edge(ll s, ll t, ll cost) {\n edge e;\n e.to = t, e.cost = cost;\n G[s].push_back(e);\n }\n\n void dijkstra(ll s) {\n for (int i = 0; i < V; i++) {\n d[i] = 2000000000000000000;\n }\n d[s] = 0;\n priority_queue<P, vector<P>, greater<P> > que;\n que.push(P(0, s));\n while (!que.empty()) {\n P p = que.top(); que.pop();\n ll v = p.second;\n if (d[v] < p.first) continue;\n for (auto e : G[v]) {\n if (d[e.to] > d[v] + e.cost / (ll)1100000000 + (e.cost % (ll)1100000000)) {\n d[e.to] = d[v] + e.cost;\n que.push(P(d[e.to], e.to));\n }\n }\n }\n }\n};\n\nvector<int> makeTable(const string& s) {\n int n = s.size();\n vector<int> ret(n + 1);\n ret[0] = -1;\n int j = -1;\n for (int i = 0; i < n; i++) {\n while (j >= 0 && s[i] != s[j]) j = ret[j];\n ret[i + 1] = ++j;\n }\n return ret;\n}\n\nvector<int> kmp(const string& str, const string& word) {\n vector<int> table = makeTable(word), ret;\n int m = 0, i = 0, n = str.size();\n while (m + i < n) {\n if (word[i] == str[m + i]) {\n if (++i == (int)(word.size())) {\n ret.push_back(m);\n m = m + i - table[i];\n i = table[i];\n }\n }\n else {\n m = m + i - table[i];\n if (i > 0) i = table[i];\n }\n }\n return ret;\n}\n*/\n\npair<ll, ll> un(pair<ll, ll> a, pair<ll, ll> b) {\n if (a.first % 2 == 0)return make_pair(a.first + b.first, a.second + b.second);\n else return make_pair(a.first + b.first, a.second - b.second);\n}\n\nint main() {\n ll k;\n cin >> k;\n ll n;\n cin >> n;\n ll q;\n cin >> q;\n ll t = 0;\n vector<pair<ll,ll>> z(262144);\n for (int i = 0; i < n; i++) {\n cin >> z[i+131072].second;\n z[i + 131072].second *= -1;\n if (z[i+131072].second == 0) {\n z[i+131072].first = 1;\n t++;\n }\n\n }\n for (int i = 131071; i > 0; i--) {\n z[i] = un(z[2 * i], z[2 * i + 1]);\n }\n for (int i = 0; i < q; i++) {\n ll a, b;\n cin >> a >> b;\n a += 131071;\n b += 131071;\n pair<ll, ll> d = z[a];\n z[a] = z[b];\n z[b] = d;\n ll f = a;\n while (f > 1) {\n z[f / 2] = un(z[f / 2 * 2], z[f / 2 * 2 + 1]);\n f /= 2;\n }\n f = b;\n while (f > 1) {\n z[f / 2] = un(z[f / 2 * 2], z[f / 2 * 2 + 1]);\n f /= 2;\n }\n if (t % 2 == 0)cout << (z[1].second + k * (ll)10000000) % k+1 << endl;\n else cout << -((z[1].second + k * (ll)10000000) % k + 1) << endl;\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 7252, "score_of_the_acc": -0.2357, "final_rank": 8 }, { "submission_id": "aoj_0390_5867581", "code_snippet": "#define _GLIBCXX_DEBUG\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define rep2(i,s,n) for(int i=s;i<(int)n;i++)\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rebgin(),a.rend()\nconst int big=1e9+7;\n//const int big=998'244'353;\nconst char newl='\\n';\nconst int inf=1e9+10;\nconst ll INF=ll(1e18)+10;\nconst int dx[]={1,0,-1,0};\nconst int dy[]={0,1,0,-1};\n\nusing P=pair<bool,ll>;//true->その向きのまま、反時計に+(llの値) false->まず裏にして、反時計に+(llの値)\nP prod(P a,P b){\n if(b.first){\n a.second+=b.second;\n return a;\n }\n a.first=!a.first;\n a.second=b.second-a.second;\n return a;\n}\n\nstruct segtree{\n int n,sz;\n vector<P> vec;\n segtree(int n_):n(n_),sz(1){\n while(sz<n)sz<<=1;\n vec.resize(sz*2,{true,0});\n }\n void set(int i,P val){\n i+=sz;\n vec[i]=val;\n i/=2;\n while(i){\n vec[i]=prod(vec[2*i],vec[2*i+1]);\n i/=2;\n }\n }\n P getall(){\n return vec[1];\n }\n};\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.precision(10);\n\n int k,n,q;\n cin >> k >> n >> q;\n int a[n];\n rep(i,n)cin >> a[i];\n segtree seg(n);\n rep(i,n){\n if(a[i]==0)seg.set(i,{false,0});\n else seg.set(i,{true,-a[i]});\n }\n while(q--){\n int l,r;\n cin >> l >> r;\n l--,r--;\n swap(a[l],a[r]);\n if(a[l]==0)seg.set(l,{false,0});\n else seg.set(l,{true,-a[l]});\n if(a[r]==0)seg.set(r,{false,0});\n else seg.set(r,{true,-a[r]});\n\n ll x=seg.getall().second;\n if(seg.getall().first){\n x=1+x;\n x%=k;\n if(x<=0)x+=k;\n }\n else{\n x=1-x;\n x%=k;\n if(x<=0)x+=k;\n x=-x;\n }\n cout << x << newl;\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7504, "score_of_the_acc": -0.0755, "final_rank": 3 }, { "submission_id": "aoj_0390_5768245", "code_snippet": "#include <bits/stdc++.h>\n\n#define lol long long\n#define gcd(x, y) __gcd(x, y)\n#define mt make_tuple\n#define mp make_pair\n#define fi first\n#define se second\n#define fixed(x) fixed << setprecision(x)\n#define all(x) x.begin(),x.end()\nusing namespace std;\nusing pii = pair<int, int>;\ntemplate <class A, class B>\ninline bool chmax(A& a, const B& b) {\n return b > a && (a = b, true);\n}\ntemplate <class A, class B>\ninline bool chmin(A& a, const B& b) {\n return b < a && (a = b, true);\n}\ntemplate <class A>\ninline A abs(A& a) {\n return (a < 0 ? -a : a);\n}\nbool inLine(int x, int y, int mx, int my) {\n return (x >= 0 && y >= 0 && x < mx && y < my);\n}\ntemplate<class T> using max_heap=priority_queue<T>;\ntemplate<class T> using min_heap=priority_queue<T,vector<T>,greater<T>>;\ntemplate<class T> using uset=unordered_set<T>;\ntemplate<class A,class B> using umap=unordered_map<A,B>;\nconst lol inf = (1LL << 62);\nconst int MOD = (1e9) + 7;\nconst int mod = 998244353;\nconst int dx[] = {1, 0, -1, 0, 1, 1, -1, -1, -2, -2, -2, -2,\n -2, -1, -1, 1, 1, 0, 0, 2, 2, 2, 2, 2};\nconst int dy[] = {0, 1, 0, -1, 1, -1, 1, -1, -2, -1, 0, 1,\n 2, -2, 2, -2, 2, -2, 2, -2, -1, 0, 1, 2};\n\ntemplate <typename X>\nstruct Segment{\n using FX=function<X(X,X)>; //X●X -> X となる関数の型\n int n;\n FX fx;\n const X ex;\n vector<X> dat;\n Segment(int size,FX fx_,X ex_) : fx(fx_),ex(ex_){\n n=1;\n while(size>n){\n n*=2;\n }\n dat.resize(n*2,ex_);\n return;\n }\n \n void set(int i,X x){ dat[i+n-1]=x;}\n void build(){\n for(int k=n-2;k>=0;k--) dat[k]=fx(dat[2*k+1],dat[2*k+2]);\n return;\n }\n \n void update(int i,X x){\n i+=n-1;\n dat[i]=x;\n while(i>0){\n i=(i-1)/2;\n dat[i]=fx(dat[i*2+1],dat[i*2+2]);\n } \n return; \n }\n \n X get(int a,int b){ return (get_sub(a,b+1,0,0,n));}\n X get_sub(int a,int b,int k,int l,int r){\n if(r<=a || b<=l) return ex;\n if(a<=l && r<=b) return dat[k];\n X vl=get_sub(a,b,k*2+1,l,(l+r)/2);\n X vr=get_sub(a,b,k*2+2,(l+r)/2,r);\n return fx(vl,vr);\n }\n \n X operator[](const int &k) const{\n return dat[k+n-1];\n }\n};\nstruct Card{\n bool flip;\n lol num;\n Card(lol n=0, bool f=false):num(n),flip(f){}\n};\nsigned main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int k,n,q;\n cin >>k>>n>>q;\n\n auto fx=[&](Card x1,Card x2) -> Card {\n if(x1.flip){\n x2.num = k - x2.num;\n }\n return(Card((x1.num+x2.num)%k, x1.flip^x2.flip));\n };\n\n Segment<Card> st(n, fx, Card(0,false));\n\n for(int i=0;i<n;i++){\n int a;\n cin >>a;\n Card c;\n if(a==0){\n c = Card(0, true);\n }else if(a>0){\n c = Card(k-a%k, false);\n }else{\n c = Card(-(a%k), false);\n }\n\n st.set(i, c);\n }\n\n st.build();\n\n for(int i=0;i<q;i++){\n int l,r;\n cin >>l>>r;\n l--;r--;\n auto tmp = st[r];\n st.update(r, st[l]);\n st.update(l, tmp);\n cout <<(st.get(0,n).flip?\"-\":\"\");\n cout <<st.get(0,n).num+1<<'\\n';\n }\n return (0);\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 7236, "score_of_the_acc": -0.2356, "final_rank": 7 } ]
aoj_0384_cpp
Dudeney Number A Dudeney number is a positive integer for which the sum of its decimal digits is equal to the cube root of the number. For example, $512$ is a Dudeney number because it is the cube of $8$, which is the sum of its decimal digits ($5 + 1 + 2$). In this problem, we think of a type similar to Dudeney numbers and try to enumerate them. Given a non-negative integer $a$, an integer $n$ greater than or equal to 2 and an upper limit $m$, make a program to enumerate all $x$’s such that the sum of its decimal digits $y$ satisfies the relation $x = (y + a)^n$, and $x \leq m$. Input The input is given in the following format. $a$ $n$ $m$ The input line provides three integers: $a$ ($0 \leq a \leq 50$), $n$ ($2 \leq n \leq 10$) and the upper limit $m$ ($1000 \leq m \leq 10^8$). Output Output the number of integers that meet the above criteria. Sample Input 1 16 2 1000 Sample Output 1 2 Two: $400 = (4 + 0 + 0 + 16)^2$ and $841 = (8 + 4 + 1 + 16)^2$ Sample Input 2 0 3 5000 Sample Output 2 3 Three: $1=1^3$, $512 = (5 + 1 + 2)^3$ and $4913 = (4 + 9 + 1 + 3)^3$. Sample Input 3 2 3 100000 Sample Output 3 0 There is no such number $x$ in the range below $100,000$ such that its sum of decimal digits $y$ satisfies the relation $(y+2)^3 = x$.
[ { "submission_id": "aoj_0384_10872265", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing dl=double;\nusing vi=vector<int>;\nusing vpi=vector<pair<int,int>>;\n\nint main(){\n int a,n,m; cin>>a>>n>>m;\n int count=0;\n for(int i=1; i<m; i++){\n int d=i;\n int s=0;\n while(d>0){\n s=s+d%10;\n d=d/10;\n }\n int c=1;\n for(int j=0; j<n; j++){\n c=c*(s+a);\n }\n if(i==c){\n count++;\n }\n }\n cout<<count<<endl;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 3404, "score_of_the_acc": -1.4637, "final_rank": 13 }, { "submission_id": "aoj_0384_10872167", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing vvi = vector<vi>;\ntemplate<class T> bool chmin(T &a, T b) {if(a>b) {a=b;return true;} return false;}\ntemplate<class T> bool chmax(T &a, T b) {if(a<b) {a=b;return true;} return false;}\nconstexpr int INF = 1e9;\n\nint dsum(ll x) {\n int sum = 0;\n while (x != 0) {\n sum += x % 10;\n x /= 10;\n }\n return sum;\n}\n\nint main() {\n ll a, n, m; cin >> a >> n >> m;\n int cnt = 0;\n for (int x = 1; x <= m; x++) {\n int y = dsum(x);\n int X = 1;\n for (int i = 0; i < n; i++) {\n X *= (y+a);\n }\n if (x == X) cnt++;\n }\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 3400, "score_of_the_acc": -1.398, "final_rank": 6 }, { "submission_id": "aoj_0384_10870855", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n#define all(a) (a).begin(),(a).end()\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n \n int a, n, m;\n cin >> a >> n >> m;\n \n int ans = 0;\n rep(x, 1, m + 1) {\n ll sum = a;\n int tmp = x;\n while (tmp > 0) {\n sum += tmp % 10;\n tmp /= 10;\n }\n \n ll mul = 1;\n rep(itr, 0, n) {\n mul *= sum;\n if (mul > x) break;\n }\n if (mul == x) ++ans;\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 990, "memory_kb": 3452, "score_of_the_acc": -1.5591, "final_rank": 16 }, { "submission_id": "aoj_0384_8289324", "code_snippet": "#include <stdio.h>\ntypedef long long ll;\n\nll a, n, m;\nint check(int x) {\n ll y = 0;\n ll v = x;\n while (v) { y += v % 10; v /= 10; }\n ll w = 1;\n for (int i = 0; i < n; i++) w *= (y + a);\n return x == w;\n}\n\nint main() {\n scanf(\"%lld %lld %lld\", &a, &n, &m);\n int cnt = 0;\n for (int x = 1; x <= m; x++) cnt += check(x);\n printf(\"%d\\n\", cnt);\n return 0;\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 2960, "score_of_the_acc": -0.898, "final_rank": 2 }, { "submission_id": "aoj_0384_8289315", "code_snippet": "#include <stdio.h>\ntypedef long long ll;\n\nll a, n, m;\nint check(int x){\n ll y = 0;\n ll v = x;\n while (v) {\n y += v % 10;\n v /= 10;\n }\n ll w = 1;\n for ( int i = 0; i < n; i++){\n w *= (y + a);\n }\n return x == w;\n}\n\nint main() {\n scanf(\"%lld %lld %lld\", &a, &n, &m);\n int cnt = 0;\n for (int x = 1; x <= m; x++) {\n if (check(x)) cnt++;\n }\n printf(\"%d\\n\", cnt);\n return 0;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 2960, "score_of_the_acc": -0.8878, "final_rank": 1 }, { "submission_id": "aoj_0384_8289266", "code_snippet": "#include <iostream>\nusing namespace std;\n\nlong long a, n, m;\nbool check(int x){\n long long y = 0;\n long long v = x;\n while(v){\n y += v%10;\n v /= 10;\n }\n long long w = 1;\n for ( int i = 0; i < n; i++){\n w *= (y + a);\n }\n return x == w;\n}\n\nint main() {\n cin >> a >> n >> m;\n int cnt = 0;\n for ( int x = 1; x <= m; x++ ){\n if ( check(x) ) cnt++;\n }\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 3420, "score_of_the_acc": -1.4105, "final_rank": 8 }, { "submission_id": "aoj_0384_8119677", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define gcd(x,y) __gcd(x,y) //最大公約数\n#define lcm(x,y) x/(__gcd(x,y))*y //最小公倍数\n#define alpha_size 26 //アルファベットの文字数\n\nint main() {\n int a, n, m;\n cin >> a >> n >> m;\n int count = 0;\n for (int x = 1; x <= m; x++) {\n unsigned ll ans = 1;\n int y = 0;\n int tmp = x;\n while (tmp > 0) {\n y += tmp % 10;\n tmp /= 10;\n }\n for (int i = 0; i < n; i++) {\n ans *= (y + a);\n }\n if (x == ans) {\n count++;\n }\n }\n cout << count << \"\\n\";\n return(0);\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3368, "score_of_the_acc": -1.433, "final_rank": 11 }, { "submission_id": "aoj_0384_8089481", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int a, n, m, ans = 0;\n cin >> a >> n >> m;\n long long x;\n string dig;\n for (int i = m; i > 0; i--) {\n dig = to_string(i);\n x = 0;\n for (int j = 0; j < dig.length(); j++) {\n x += dig[j] - '0';\n }\n if ((long long)pow(x, n) == i) {\n ans++;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.13333333333333333, "time_ms": 10, "memory_kb": 3840, "score_of_the_acc": -1, "final_rank": 20 }, { "submission_id": "aoj_0384_8038269", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint rec(int n){\n if(n==0){\n return 0;\n }\n else{\n return n%10+rec(n/10);\n }\n}\nint roc(int a,int n){\n if(n==0){\n return 1;\n }\n else{\n return a*roc(a,n-1);\n }\n}\nint main(){\n int a,n,m;\n cin >> a >> n >> m;\n int answer=0;\n for(int x=1;x<=m;x++){\n if(x==roc(rec(x)+a,n)) answer++;\n }\n cout << answer << endl;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 3440, "score_of_the_acc": -1.5148, "final_rank": 15 }, { "submission_id": "aoj_0384_8009962", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,a,n) for(long long i=a;i<n;i++)\n#define repp(i,a,n) for(long long i=a;i>=n;i--)\n#define so(z) sort(z.begin(),z.end())\n#define sor(z) sort(z.begin(),z.end(),greater<string>())\n#define re(z) reverse(z.begin(),z.end())\n#define su(a) substr(a)\n#define sub(a,b) substr(a,b)\n#define yess cout<<\"YES\"<<nn\n#define noo cout<<\"NO\"<<nn\n#define yes cout<<\"Yes\"<<\"\\n\"\n#define no cout<<\"No\"<<\"\\n\"\n#define yesr cout<<\"Yes\"<<\"\\n\";return(0)\n#define nor cout<<\"No\"<<\"\\n\";return(0)\n#define fi first\n#define se second\n#define fr() front()\n#define mp make_pair\n#define pb push_back\n#define nn \"\\n\"\n#define ll unsigned long long\n#define mod 1000000007\n#define IM INT_MAX\n#define LM LONG_LONG_MAX\n#define gcd(x,y) __gcd(x,y) //最大公約数\n#define lcm(x,y) x/(__gcd(x,y))*y //最小公倍数\n#define prev(a) prev_permutation(a.begin(),a.end()) //辞書前\n#define next(a) next_permutation(a.begin(),a.end()) //辞書後\n#define get(s) getline(cin,s) // 空白の空いたstringの入力\n#define fixed(a) fixed<<setprecision(a) //小数点何桁か指定\n#define ro(a) round(a) //四捨五入\n#define ce(a) ceil(a) //切り上げ\n#define up(a,v) upper_bound(a.begin(),a.end(),v)\n#define lo(a,v) lower_bound(a.begin(),a.end(),v)\n#define bi(a,v) binary_bound(a.begin(),a.end(),v)\nusing namespace std;\nll a,n,m,ans=0;\nll check(ll i,ll s,ll t){\n ll b=0,c=1,z=i;\n while(z!=0){\n b+=z%10;\n z/=10;\n }\n while(t!=0){\n c*=(b+s);\n t--;\n }\n return(c);\n}\nint main(){\n cin.tie(NULL);\n ios::sync_with_stdio(false);\n cin>>a>>n>>m;\n rep(i,1,m+1){\n if(check(i,a,n)==i) ans++;\n }\n cout<<ans<<nn;\n return(0);\n}", "accuracy": 1, "time_ms": 980, "memory_kb": 3172, "score_of_the_acc": -1.2307, "final_rank": 3 }, { "submission_id": "aoj_0384_7263498", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nbool chmin(ll & p,ll q){\n if(p>q){\n p=q;\n return 1;\n }\n else return 0;\n}\nint main() {\n \n ll a,n,m;\n cin>>a>>n>>m;\n ll an=0;\n for(ll x=1;x<=m;x++){\n ll p=x;\n ll s=a;\n rep(k,9){\n s+=p%10;\n p/=10;\n }\n ll d=1;\n rep(k,n){\n if(d>x){\n d=-1;\n break;\n }\n d*=s;\n }\n\n an+=(x==d);\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 890, "memory_kb": 3436, "score_of_the_acc": -1.4389, "final_rank": 12 }, { "submission_id": "aoj_0384_6950189", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <climits>\n#include <functional>\n#include <cassert>\n#include <numeric>\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define per(i, n) for(int i = (n) - 1; i >= 0; i--)\nusing ll = long long;\n#define vi vector<int>\n#define vvi vector<vi>\n#define vl vector<ll>\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define mod 1000000007\nusing namespace std;\ntemplate<class T, class U>\nbool chmax(T &a, const U &b){ return a < b ? (a = b, 1) : 0; }\ntemplate<class T, class U>\nbool chmin(T &a, const U &b){ return a > b ? (a = b, 1) : 0; }\nint m;\nll Pow(ll a, ll n){\n ll res = 1;\n rep(i, n){\n res *= a;\n if(res > m) return -1;\n }\n return res;\n}\nint digit_sum(int x){\n int res = 0;\n while(x){\n res += x % 10;\n x /= 10;\n }\n return res;\n}\nint main(){\n int a,n;\n cin >> a >> n >> m;\n int ans = 0;\n for(int i = 1; i <= m; i++){\n if(i == Pow(a + digit_sum(i), n)) ans++;\n }\n cout << ans << \"\\n\";\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 3416, "score_of_the_acc": -1.4059, "final_rank": 7 }, { "submission_id": "aoj_0384_5869658", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long int;\nint main() {\n ll a,n,m;\n cin >> a >> n >> m;\n ll cou=0;\n for(ll x=1; x<=m; x++) {\n ll y=0;\n ll xc=x;\n ll xc2=x;\n while(1) {\n if(xc<10) {\n\ty+=xc;\n\tbreak;\n }\n y+=xc%10;\n xc/=10;\n }\n //cout << 1 << endl;\n ll z=1;\n for(ll i=0; i<n; i++) {\n z*=(y+a);\n }\n //cout << xc2 << endl;\n if(z==xc2) cou++;\n }\n cout << cou << endl;\n}", "accuracy": 1, "time_ms": 840, "memory_kb": 3416, "score_of_the_acc": -1.3651, "final_rank": 5 }, { "submission_id": "aoj_0384_5857432", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\n\nint sumd(int x) {\n int res = 0;\n while (x != 0) {\n res += x % 10;\n x /= 10;\n }\n return res;\n}\n\nint main() {\n ll a, n, m;\n cin >> a >> n >> m;\n\n int ans = 0;\n for (int i = 1; i <= m; ++i) {\n int y = sumd(i);\n\n int b = 1;\n for(int j = 0; j < n; ++j) {\n b *= (y + a);\n if (b > i) break;\n }\n\n if (b == i)\n ans++;\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 3412, "score_of_the_acc": -1.4218, "final_rank": 9 }, { "submission_id": "aoj_0384_5854544", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; ++i)\ntypedef long long ll;\nusing namespace std;\n\nint sumd(int x) {\n int res = 0;\n while (x != 0) {\n res += x % 10;\n x /= 10;\n }\n return res;\n}\n\nint main() {\n ll a, n, m;\n cin >> a >> n >> m;\n\n int ans = 0;\n for (int i = 1; i <= m; ++i) {\n int y = sumd(i);\n\n int b = 1;\n rep(j, n) {\n b *= (y + a);\n if (b > i) break;\n }\n\n if (b == i)\n ans++;\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 3412, "score_of_the_acc": -1.4218, "final_rank": 9 }, { "submission_id": "aoj_0384_5801696", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a,n,m;\n cin >> a >> n >> m;\n int ans = 0;\n int x,y;\n for(int i=1;i<=m;i++){\n x = i;\n if(x < 10){\n y = x;\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100){\n y = x / 10 + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000){\n y = x / 100 + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000){\n y = x / 1000 + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100000){\n y = x / 10000 + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000000){\n y = x / 100000 + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000000){\n y = x / 1000000 + (x / 100000 - x / 1000000 * 10) + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x == 10000000){\n y = 1;\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 840, "memory_kb": 3356, "score_of_the_acc": -1.2969, "final_rank": 18 }, { "submission_id": "aoj_0384_5801660", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a,n,m;\n cin >> a >> n >> m;\n int ans = 0;\n int x,y;\n for(int i=1;i<=m;i++){\n x = i;\n if(x < 10){\n y = x;\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100){\n y = x / 10 + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000){\n y = x / 100 + (x / 10 - x / 100 * 10) + (x - x / 100 * 100 - (x / 10 - x / 100 * 10) * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000){\n y = x / 1000 + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100000){\n y = x / 10000 + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000000){\n y = x / 100000 + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000000){\n y = x / 1000000 + (x / 100000 - x / 1000000 * 10) + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x == 10000000){\n y = 1;\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 840, "memory_kb": 3396, "score_of_the_acc": -1.3424, "final_rank": 19 }, { "submission_id": "aoj_0384_5801654", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a,n,m;\n cin >> a >> n >> m;\n int ans = 0;\n int x,y;\n for(int i=1;i<=m;i++){\n x = i;\n if(x < 10){\n y = x;\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100){\n y = x / 10 + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000){\n y = x / 100 + (x / 10 - x / 100 * 10) + (x - x / 100 * 100 - (x / 10 - x / 100 * 10) * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000){\n y = x / 1000 + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 100000){\n y = x / 10000 + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 1000000){\n y = x / 100000 + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }else if(x < 10000000){\n y = x / 1000000 + (x / 100000 - x / 1000000 * 10) + (x / 10000 - x / 100000 * 10) + (x / 1000 - x / 10000 * 10) + (x / 100 - x / 1000 * 10) + (x / 10 - x / 100 * 10) + (x - x / 10 * 10);\n if(x==pow(y+a,n)){\n ans = ans + 1;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 0.6666666666666666, "time_ms": 830, "memory_kb": 3348, "score_of_the_acc": -1.2776, "final_rank": 17 }, { "submission_id": "aoj_0384_5725622", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nsigned main(){\n\tint a,n,m;\n\tcin>>a>>n>>m;\n\tint ans=0;\n\tfor(int i=1;i<=m;i++){\n\t\tint ii=i,sum=0,prod=1;\n\t\twhile(ii){\n\t\t\tsum+=ii%10;\n\t\t\tii/=10;\n\t\t}\n\t\tfor(int i=0;i<n;i++)\n\t\t\tprod*=(sum+a);\n\t\tif(prod==i)\n\t\t\tans++;\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 3396, "score_of_the_acc": -1.475, "final_rank": 14 }, { "submission_id": "aoj_0384_5587832", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define overload3(_1, _2, _3, name, ...) name\n#define rep1(n) for (int __i = 0; __i < (n); __i++)\n#define rep2(i, n) for (int i = 0; i < (n); i++)\n#define rep3(i, a, b) for (int i = (a); i < (b); i++)\n#define rep(...) overload3(__VA_ARGS__, rep3, rep2, rep1)(__VA_ARGS__)\n#include <experimental/iterator>\n#define outcon(os, c, sep) \\\n copy(cbegin(c), cend(c), experimental::make_ostream_joiner(os, sep))\n#ifdef LOCAL\n#define dbg(x) cerr << \"line\" << __LINE__ << \": \" << #x << \" = \" << (x) << \"\\n\"\n#else\n#define dbg(x) true\n#endif\ntemplate <class T>\nbool ch(const T &(*f)(const T &, const T &), T &a, const T &b) {\n return a != f(a, b) and (a = b, true);\n}\n#define chmax(a, b) ch(max, a, b)\n#define chmin(a, b) ch(min, a, b)\nstruct IOSetup {\n IOSetup() noexcept {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} IOSetup;\n#define mut auto &&\n#define imm const auto &\n\nint digit_sum(int n) {\n if (n < 10) return n;\n return n % 10 + digit_sum(n / 10);\n}\n\nint main() {\n int a, n, m;\n cin >> a >> n >> m;\n int ans = 0;\n auto check = [&n, &a](int x) -> bool {\n int y = digit_sum(x);\n y += a;\n rep(n) {\n if (x % y == 0)\n x /= y;\n else\n return false;\n }\n return x == 1;\n };\n for (int x = 1; x <= m; x++) {\n if (check(x)) ans++;\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 780, "memory_kb": 3456, "score_of_the_acc": -1.3494, "final_rank": 4 } ]
aoj_0394_cpp
Pilling Blocks We make a tower by stacking up blocks. The tower consists of several stages and each stage is constructed by connecting blocks horizontally. Each block is of the same weight and is tough enough to withstand the weight equivalent to up to $K$ blocks without crushing. We have to build the tower abiding by the following conditions: Every stage of the tower has one or more blocks on it. Each block is loaded with weight that falls within the withstanding range of the block. The weight loaded on a block in a stage is evaluated by: total weight of all blocks above the stage divided by the number of blocks within the stage. Given the number of blocks and the strength, make a program to evaluate the maximum height (i.e., stages) of the tower than can be constructed. Input The input is given in the following format. $N$ $K$ The input line provides the number of blocks available $N$ ($1 \leq N \leq 10^5$) and the strength of the block $K$ ($1 \leq K \leq 10^5$). Output Output the maximum possible number of stages. Sample Input 1 4 2 Sample Output 1 3 Sample Input 2 5 2 Sample Output 2 4
[ { "submission_id": "aoj_0394_10934103", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tll N, K;\n\tcin >> N >> K;\n\t\n\tll ok = 1, ng = N + 10;\n\twhile (ng - ok > 1) {\n\t\tll mid = (ok + ng) / 2;\n\t\t\n\t\tll cnt = 0;\n\t\trep(i, 0, mid) {\n\t\t\tll need = (cnt + K - 1) / K;\n\t\t\tif (need == 0) need = 1;\n\t\t\tcnt += need;\n\t\t\tif (cnt > N) break;\n\t\t}\n\t\tif (cnt <= N) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3360, "score_of_the_acc": -0.4641, "final_rank": 3 }, { "submission_id": "aoj_0394_10934097", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N, K;\n\tcin >> N >> K;\n\t\n\tint ok = 1, ng = N + 10;\n\twhile (ng - ok > 1) {\n\t\tint mid = (ok + ng) / 2;\n\t\t\n\t\tint cnt = 0;\n\t\trep(i, 0, mid) {\n\t\t\tint need = (cnt + K - 1) / K;\n\t\t\tif (need == 0) need = 1;\n\t\t\tcnt += need;\n\t\t}\n\t\tif (cnt <= N) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << '\\n';\n}", "accuracy": 0.7, "time_ms": 10, "memory_kb": 3428, "score_of_the_acc": -0.511, "final_rank": 7 }, { "submission_id": "aoj_0394_7074182", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\nusing namespace std;\nusing ll = long long;\n\nll ll_gcd(ll a, ll b) {\n if (a < b) return ll_gcd(b, a);\n ll r;\n while ((r = a % b)) {\n a = b;\n b = r;\n }\n return b;\n}\n\nint main() {\n ll n, k;\n cin >> n >> k;\n ll ok = 0;\n ll ng = 2000000;\n while (ng - ok > 1) {\n ll mid = (ok + ng) / 2;\n ll s = 0;\n ll t = 1;\n for (int i = 1; i < mid; i++) {\n t += (t + k - 1) / k;\n if (t > n) {\n s = 1;\n break;\n }\n }\n if (s == 1)ng = mid;\n else ok = mid;\n }\n cout << ok << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3432, "score_of_the_acc": -1.0138, "final_rank": 5 }, { "submission_id": "aoj_0394_6890243", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n, k;\n cin >> n >> k;\n int ok = 0, ng = n + 10, mid;\n auto f = [&](int N){\n ll s = 1;\n for(int i = 1; i < N; i++){\n s = min(1ll << 60, s + (s + k - 1) / k);\n }\n return (s <= n);\n };\n while(ok + 1 < ng){\n mid = (ok + ng) / 2;\n if(f(mid))ok = mid;\n else ng = mid;\n }\n cout << ok << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.5193, "final_rank": 4 }, { "submission_id": "aoj_0394_6890231", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n, k;\n cin >> n >> k;\n int ok = 0, ng = n + 10, mid;\n auto f = [&](int N){\n ll s = 1;\n for(int i = 1; i < N; i++){\n s += (s + k - 1) / k;\n }\n return (s <= n);\n };\n while(ok + 1 < ng){\n mid = (ok + ng) / 2;\n if(f(mid))ok = mid;\n else ng = mid;\n }\n cout << ok << endl;\n}", "accuracy": 0.7, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.5193, "final_rank": 8 }, { "submission_id": "aoj_0394_6890219", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\ntemplate <class T> struct fenwick_tree {\n using U = T;\n\n public:\n fenwick_tree() : _n(0) {}\n fenwick_tree(int n) : _n(n), data(n) {}\n\n void add(int p, T x) {\n assert(0 <= p && p < _n);\n p++;\n while (p <= _n) {\n data[p - 1] += U(x);\n p += p & -p;\n }\n }\n\n T sum(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n return sum(r) - sum(l);\n }\n\n private:\n int _n;\n std::vector<U> data;\n\n U sum(int r) {\n U s = 0;\n while (r > 0) {\n s += data[r - 1];\n r -= r & -r;\n }\n return s;\n }\n};\n\nint main(){\n int n, k;\n cin >> n >> k;\n int ok = 0, ng = n + 1, mid;\n auto f = [&](int N){\n fenwick_tree<ll> fw(N);\n fw.add(0, 1);\n for(int i = 1; i < N; i++){\n ll v = fw.sum(0, i);\n fw.add(i, (v + k - 1) / k);\n }\n return (fw.sum(0, N) <= n);\n };\n while(ok + 1 < ng){\n mid = (ok + ng) / 2;\n if(f(mid))ok = mid;\n else ng = mid;\n }\n cout << ok << endl;\n}", "accuracy": 0.7, "time_ms": 30, "memory_kb": 4136, "score_of_the_acc": -2, "final_rank": 9 }, { "submission_id": "aoj_0394_3632461", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <utility>\n\nbool valid(int N, int K, int x) {\n int wsum = 1;\n for (int i = 1; i < x; ++i) {\n int n = (wsum+K-1) / K;\n wsum += n;\n if (wsum > N) return false;\n }\n return wsum <= N;\n}\n\nint main() {\n int N, K;\n scanf(\"%d %d\", &N, &K);\n\n int lb = 1;\n int ub = N+1;\n while (ub-lb > 1) {\n int mid = (lb+ub) >> 1;\n (valid(N, K, mid)? lb:ub) = mid;\n }\n printf(\"%d\\n\", lb);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2688, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0394_3632454", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <utility>\n\nbool valid(int N, int K, int x) {\n int wsum = 1;\n for (int i = 1; i < x; ++i) {\n int n = (wsum+K-1) / K;\n wsum += n;\n }\n return wsum <= N;\n}\n\nint main() {\n int N, K;\n scanf(\"%d %d\", &N, &K);\n\n int lb = 1;\n int ub = N+1;\n while (ub-lb > 1) {\n int mid = (lb+ub) >> 1;\n (valid(N, K, mid)? lb:ub) = mid;\n }\n printf(\"%d\\n\", lb);\n}", "accuracy": 0.7, "time_ms": 10, "memory_kb": 2708, "score_of_the_acc": -0.0138, "final_rank": 6 }, { "submission_id": "aoj_0394_3632306", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\n#define int long long int\n\nconst int INF = 1000000007;\n\nsigned main(){\n \n int n, k; cin >> n >> k;\n\n double sum = 0;\n int hight = 0;\n \n while(1){\n // sum に耐えうる個数のうち, 最小のものを求める\n int l = 0; \n int r = 100010;\n while(r - l > 1){\n int d = (r + l) / 2;\n \n double w = INF;\n if(d != 0) w = sum / d;\n if(w <= k) r = d;\n else l = d;\n }\n\n if(r <= n){\n hight++;\n n -= r;\n sum += r;\n }else{\n cout << hight << endl;\n return 0;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.279, "final_rank": 2 } ]
aoj_0389_cpp
Dungeon 2 Bob is playing a game called "Dungeon 2" which is the sequel to the popular "Dungeon" released last year. The game is played on a map consisting of $N$ rooms and $N-1$ roads connecting them. The roads allow bidirectional traffic and the player can start his tour from any room and reach any other room by way of multiple of roads. A point is printed in each of the rooms. Bob tries to accumulate the highest score by visiting the rooms by cleverly routing his character "Tora-Tora." He can add the point printed in a room to his score only when he reaches the room for the first time. He can also add the points on the starting and ending rooms of Tora-Tora’s journey. The score is reduced by one each time Tora-Tore passes a road. Tora-Tora can start from any room and end his journey in any room. Given the map information, make a program to work out the maximum possible score Bob can gain. Input The input is given in the following format. $N$ $p_1$ $p_2$ $...$ $p_N$ $s_1$ $t_1$ $s_2$ $t_2$ $...$ $s_{N-1}$ $t_{N-1}$ The first line provides the number of rooms $N$ ($1 \leq N \leq 100,000$). Each of the subsequent $N$ lines provides the point of the $i$-th room $p_i$ ($-100 \leq p_i \leq 100$) in integers. Each of the subsequent lines following these provides the information on the road directly connecting two rooms, where $s_i$ and $t_i$ ($1 \leq s_i < t_i \leq N$) represent the numbers of the two rooms connected by it. Not a single pair of rooms are connected by more than one road. Output Output the maximum possible score Bob can gain. Sample Input 1 7 6 1 -1 4 3 3 1 1 2 2 3 3 4 3 5 5 6 5 7 Sample Output 1 10 For example, the score is maximized by routing the rooms in the following sequence: $6 \rightarrow 5 \rightarrow 3 \rightarrow 4 \rightarrow 3 \rightarrow 2 \rightarrow 1$. Sample Input 2 4 5 0 1 1 1 2 2 3 2 4 Sample Output 2 5 The score is maximized if Tora-Tora stats his journey from room 1 and ends in the same room.
[ { "submission_id": "aoj_0389_10875058", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nconstexpr ll inf = 1e18;\nconstexpr int MOD = 1000000007;\n\nint main() {\n int N; scanf(\"%d\", &N);\n vector<ll> P(N, -1);\n rep (i, N) scanf(\"%lld\", &P[i]);\n vector<vector<int>> G(N);\n rep (_, N - 1) {\n int a, b; scanf(\"%d%d\", &a, &b);\n --a; --b;\n G[a].push_back(b);\n G[b].push_back(a);\n }\n auto op = [&](PLL p, PLL q) -> PLL {\n ll a = 0, b = 0;\n chmax(a, max(p.first, q.first));\n chmax(b, max(p.second, q.second));\n chmax(a, p.first + q.first);\n chmax(b, p.first + q.second);\n chmax(b, p.second + q.first);\n return {a, b};\n };\n vector<PLL> memo1(N), memo2(N);\n auto dfs1 = [&](auto&& self, int v, int p) -> PLL {\n PLL res = {0, 0};\n for (auto u : G[v]) if (u != p) res = op(res, self(self, u, v));\n memo1[v] = {res.first + P[v] - 2, res.second + P[v] - 1};\n return memo1[v];\n };\n dfs1(dfs1, 0, -1);\n ll ans = -inf;\n auto dfs2 = [&](auto&& self, int v, int p) -> void {\n int M = G[v].size();\n vector<PLL> cumL(M + 1, PLL{0, 0}), cumR(M + 1, {0, 0});\n rep (i, M) {\n int u = G[v][i];\n PLL t = u == p ? memo2[v] : memo1[u];\n cumL[i + 1] = op(cumL[i], t);\n }\n rrep (i, M) {\n int u = G[v][i];\n PLL t = u == p ? memo2[v] : memo1[u];\n cumR[i] = op(cumR[i + 1], t);\n }\n auto res = cumL[M];\n chmax(ans, max(res.first, res.second) + P[v]);\n rep (i, M) {\n int u = G[v][i];\n if (u == p) continue;\n PLL t = op(cumL[i], cumR[i + 1]);\n memo2[u] = {t.first + P[v] - 2, t.second + P[v] - 1};\n self(self, u, v);\n }\n };\n dfs2(dfs2, 0, -1);\n printf(\"%lld\\n\", ans);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 37464, "score_of_the_acc": -1.4, "final_rank": 11 }, { "submission_id": "aoj_0389_10871626", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\nint main(){\n\n int N;\n cin>>N;\n vector<int> P(N);\n rep(i,N)cin>>P[i];\n vector<vector<int>> G(N);\n rep(i,N-1){\n int s,t;\n cin>>s>>t;\n s--;t--;\n G[s].push_back(t);\n G[t].push_back(s);\n }\n long ans=-INFL;\n auto dfs=[&](auto dfs, int v, int p)->array<long,3> {\n array<long,3> dp={P[v],P[v],P[v]};\n \n for(int e: G[v]){\n if(e==p) continue;\n array<long,3> ret=dfs(dfs, e, v);\n\n chmax(dp[2], dp[2]+ret[0]-2);\n chmax(dp[2], dp[0]+ret[2]-2);\n chmax(dp[2], dp[1]+ret[1]-1);\n\n chmax(dp[1], dp[1]+ret[0]-2);\n chmax(dp[1], dp[0]+ret[1]-2+1);\n\n chmax(dp[0], dp[0]+ret[0]-2);\n }\n rep(i,3) chmax(ans, dp[i]);\n\n // cout<<v+1<<\": \";\n // rep(i,3) cout<<dp[i]<<\" \";\n // cout<<\"\\n\";\n return dp;\n };\n dfs(dfs, 0, -1);\n\n cout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 23116, "score_of_the_acc": -0.6457, "final_rank": 7 }, { "submission_id": "aoj_0389_10871123", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long \n#define pb push_back\n#define rep(i,N) for(int i =0;i<(int)N;i++)\n#define all(x) x.begin(),x.end()\nint main(){\n int N;cin>>N;\n vector<ll>P(N);\n rep(i,N)cin>>P[i];\n vector<vector<int>>G(N);\n rep(i,N-1){\n int a,b;cin>>a>>b;\n a--,b--;\n G[a].pb(b);\n G[b].pb(a);\n }\n queue<int>Q;\n stack<int>order;\n Q.push(0);\n vector<int>seen(N,0);\n while(!Q.empty()){\n int v = Q.front();\n Q.pop();\n order.push(v);\n seen[v]=1;\n for(auto e : G[v]){\n if(seen[e]==0){\n Q.push(e);\n }\n }\n }\n ll ans = P[0];\n vector<ll>A(N,-998244353),B(N,-998244353),C(N,-998244353);\n while(!order.empty()){\n int v = order.top();order.pop();\n seen[v]=2;\n A[v]=max(P[v],A[v]);\n B[v]=max(P[v],B[v]);\n vector<ll>X,Y,W;\n ll sum = 0;\n for(auto e : G[v]){\n if(seen[e]==2){\n X.pb(A[e]);\n Y.pb(B[e]);\n W.pb(C[e]);\n }\n }\n for(auto e : X){\n if(e>=2)sum+=e-2;\n }\n vector<ll>Z;\n rep(i,X.size()){\n if(X[i]<2)Z.pb(Y[i]-1);\n else Z.pb(Y[i]-X[i]+1);\n }\n sort(all(Z));\n reverse(all(Z));\n if(X.size()>=2){\n C[v]=max(C[v],P[v]+sum+Z[0]+Z[1]);\n }\n A[v]=max(A[v],P[v]+sum);\n rep(i,X.size()){\n if(X[i]>=2){\n B[v]=max(B[v],P[v]+sum-X[i]+1+Y[i]);\n C[v]=max(C[v],P[v]+sum-X[i]+W[i]);\n }\n else {\n B[v]=max(B[v],P[v]+sum+Y[i]-1);\n C[v]=max(C[v],P[v]+sum+W[i]-2);\n }\n }\n ans = max({ans,A[v],B[v],C[v]});\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 16768, "score_of_the_acc": -1.0004, "final_rank": 8 }, { "submission_id": "aoj_0389_10871046", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\nint main(){\n\n int N;\n cin>>N;\n vector<int> P(N);\n rep(i,N)cin>>P[i];\n vector<vector<int>> G(N);\n rep(i,N-1){\n int s,t;\n cin>>s>>t;\n s--;t--;\n G[s].push_back(t);\n G[t].push_back(s);\n }\n long ans=-INFL;\n auto dfs=[&](auto dfs, int v, int p)->array<long,3> {\n array<long,3> dp={P[v],P[v],P[v]};\n \n for(int e: G[v]){\n if(e==p) continue;\n array<long,3> ret=dfs(dfs, e, v);\n\n chmax(dp[2], dp[2]+ret[0]-2);\n chmax(dp[2], dp[0]+ret[2]-2);\n chmax(dp[2], dp[1]+ret[1]-1);\n\n chmax(dp[1], dp[1]+ret[0]-2);\n chmax(dp[1], dp[0]+ret[1]-2+1);\n\n chmax(dp[0], dp[0]+ret[0]-2);\n }\n rep(i,3) chmax(ans, dp[i]);\n\n // cout<<v+1<<\": \";\n // rep(i,3) cout<<dp[i]<<\" \";\n // cout<<\"\\n\";\n return dp;\n };\n dfs(dfs, 0, -1);\n\n cout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 18836, "score_of_the_acc": -0.2803, "final_rank": 2 }, { "submission_id": "aoj_0389_10506977", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct node {\n int a, b, c;\n};\nint ans = -1e9;\nconst int maxn = 1e5 + 5;\nnode dp[maxn];\nint a[maxn];\nvector<int> g[maxn];\n\nvoid dfs(int u , int p) {\n int mx1 = 0, mx2 = 0, ss = 0;\n int summ = a[u];\n for (int v : g[u]) {\n if(v == p) continue;\n dfs(v, u);\n node q = dp[v];\n int nn = 0;\n if (q.a >= 2) {\n nn = q.a - 2;\n summ += nn;\n }\n int x = q.b - 1 - nn;\n if (mx1 < x) {\n mx2 = mx1;\n mx1 = x;\n } else {\n if (mx2 < x)\n mx2 = x;\n }\n ss = max(ss, q.c - 2 - nn);\n }\n dp[u] = {summ, summ + mx1, summ + max(ss , mx1 + mx2)};\n ans = max(ans, dp[u].c);\n}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n\n int n;\n cin >> n;\n for (int i = 0 ; i < n ; i++) {\n cin >> a[i];\n }\n for (int i = 1 ; i < n ; i++) {\n int u, v;\n cin >> u >> v;\n u--;\n v--;\n g[u].emplace_back(v);\n g[v].emplace_back(u);\n }\n dfs(0, -1);\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 19748, "score_of_the_acc": -0.5156, "final_rank": 4 }, { "submission_id": "aoj_0389_10506970", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct node {\n int a, b, c;\n};\nint ans = -1e9;\nconst int maxn = 1e5 + 5;\nnode dp[maxn];\nint a[maxn];\nvector<int> g[maxn];\n\nvoid dfs(int u , int p) {\n int mx1 = 0, mx2 = 0, ss = 0;\n int summ = a[u];\n for (int v : g[u]) {\n if(v == p) continue;\n dfs(v, u);\n node q = dp[v];\n int nn = 0;\n if (q.a >= 2) {\n nn = q.a - 2;\n summ += nn;\n }\n int x = q.b - 1 - nn;\n if (mx1 < x) {\n mx2 = mx1;\n mx1 = x;\n } else {\n if (mx2 < x)\n mx2 = x;\n }\n ss = max(ss, q.c - 2 - nn);\n }\n dp[u] = {summ, summ + mx1, summ + max(ss , mx1 + mx2)};\n ans = max(ans, summ + mx1 + mx2);\n ans = max(ans, summ + ss);\n}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n\n int n;\n cin >> n;\n for (int i = 0 ; i < n ; i++) {\n cin >> a[i];\n }\n for (int i = 1 ; i < n ; i++) {\n int u, v;\n cin >> u >> v;\n u--;\n v--;\n g[u].emplace_back(v);\n g[v].emplace_back(u);\n }\n dfs(0, -1);\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 19776, "score_of_the_acc": -0.5166, "final_rank": 5 }, { "submission_id": "aoj_0389_10497987", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint ans = -1e9 , n;\nvector<int> a;\nvector<vector<int>> g;\n\nstruct node {\n int a, b, c;\n};\n\nnode dfs(int u , int p) {\n\tint mx1 = 0, mx2 = 0, ss = 0;\n\tint summ = a[u];\n\tfor (int v : g[u]) {\n if(v == p) continue;\n\t\tnode q = dfs(v, u);\n\t\tint nn = 0;\n\t\tif (q.a >= 2) {\n\t\t nn = q.a - 2;\n summ += nn;\n\t\t}\n\t\tint x = q.b - 1 - nn;\n\t\tif (mx1 < x) {\n\t\t\tmx2 = mx1;\n\t\t\tmx1 = x;\n\t\t} else {\n if (mx2 < x)\n mx2 = x;\n\t\t}\n\t\tss = max(ss, q.c - 2 - nn);\n\t}\n\tans = max(ans, summ + mx1 + mx2);\n\tans = max(ans, summ + ss);\n\treturn {summ, summ + mx1, summ + max(ss , mx1 + mx2)};\n}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n\n cin >> n;\n g.resize(n);\n a.resize(n);\n for (int i = 0 ; i < n ; i++) {\n cin >> a[i];\n }\n\tfor (int i = 1 ; i < n ; i++) {\n\t\tint u, v;\n\t\tcin >> u >> v;\n\t\tu--;\n\t\tv--;\n\t\tg[u].emplace_back(v);\n\t\tg[v].emplace_back(u);\n\t}\n\tdfs(0, -1);\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 19980, "score_of_the_acc": -0.5245, "final_rank": 6 }, { "submission_id": "aoj_0389_10204860", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() {\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(ll n) {\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n\tpc('\\n');\n}\n \nint N;\nvector<int> roomPoints;\nvector<vector<int>> graph;\n \nvector<ll> dp, upVal;\nvector<int> par;\n \nvoid dfs_dp(int u, int parent) {\n par[u] = parent;\n ll sum = 0;\n for (int v : graph[u]) {\n if (v == parent) continue;\n dfs_dp(v, u);\n sum += max(0LL, dp[v]);\n }\n dp[u] = roomPoints[u] - 2 + sum;\n}\n \nvoid dfs_up(int u, int parent) {\n ll sumContrib = max(0LL, upVal[u]);\n for (int v : graph[u]) {\n if (v == parent) continue;\n sumContrib += max(0LL, dp[v]);\n }\n for (int v : graph[u]) {\n if (v == parent) continue;\n upVal[v] = roomPoints[u] - 2 + (sumContrib - max(0LL, dp[v]));\n dfs_up(v, u);\n }\n}\n \nvector<ll> Fval;\n \nvoid compute_F() {\n Fval.resize(N+1, 0);\n for (int u = 1; u <= N; u++){\n ll sum = 0;\n for (int v : graph[u]){\n if(v == par[u]) sum += max(0LL, upVal[u]);\n else sum += max(0LL, dp[v]);\n }\n Fval[u] = roomPoints[u] + sum;\n }\n}\n \nll getCost(int u, int v) {\n if (par[v] == u)\n return max(0LL, dp[v]) + max(0LL, upVal[v]) + 1;\n else if (par[u] == v)\n return max(0LL, dp[u]) + max(0LL, upVal[u]) + 1;\n return 0;\n}\n \nll ansFinal = -LLONG_MAX;\n \nll dfs_diameter(int u, int parent) {\n ll best1 = 0, best2 = 0;\n for (int v : graph[u]) {\n if (v == parent) continue;\n ll subChain = dfs_diameter(v, u);\n ll cand = subChain - getCost(u, v);\n if(cand < 0) cand = 0;\n if(cand > best1) {\n best2 = best1;\n best1 = cand;\n } else if(cand > best2) best2 = cand;\n }\n ll chain = Fval[u] + best1;\n ansFinal = max(ansFinal, Fval[u] + best1 + best2);\n return chain;\n}\n \nint main() {\n N = Cin();\n roomPoints.resize(N+1);\n for (int i = 1; i <= N; i++) roomPoints[i] = Cin();\n\n graph.resize(N+1);\n par.resize(N+1, 0);\n dp.resize(N+1, 0);\n upVal.resize(N+1, 0);\n \n for (int i = 1; i < N; i++){\n int s = Cin(), t = Cin();\n graph[s].push_back(t);\n graph[t].push_back(s);\n }\n \n if(N == 1){\n Cout(roomPoints[1]);\n return 0;\n }\n \n dfs_dp(1, 0);\n upVal[1] = 0;\n dfs_up(1, 0);\n compute_F();\n \n ansFinal = -LLONG_MAX;\n dfs_diameter(1, 0);\n Cout(ansFinal);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 19420, "score_of_the_acc": -0.3029, "final_rank": 3 }, { "submission_id": "aoj_0389_9639236", "code_snippet": "#include <iostream>\n#include <vector>\n#include <functional>\nusing namespace std;\n\nint main()\n{\n int N;\n cin>>N;\n vector<int> p(N);\n for (int &t: p)\n cin>>t;\n vector<vector<int>> E(N);\n for (int i=0; i<N-1; i++)\n {\n int s, t;\n cin>>s>>t;\n E[s-1].push_back(t-1);\n E[t-1].push_back(s-1);\n }\n\n // T1[c]: 頂点cを通り、スタートもゴールもcを頂点とする部分木に無い場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T1(N);\n // T2[c]: 頂点cを通り、スタートかゴールのどちらか一方がcを頂点とする部分木にある場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T2(N);\n // T3[c]: 頂点cを通り、スタートもゴールもcを頂点とする部分木にある場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T3(N);\n\n function<void(int, int)> f = [&](int c, int parent)\n {\n T1[c] = p[c];\n T2[c] = p[c];\n T3[c] = p[c];\n\n for (int e: E[c])\n if (e!=parent)\n {\n f(e, c);\n\n // 部分木eを考慮する前の値を退避しておく。\n int t1 = T1[c];\n int t2 = T2[c];\n int t3 = T3[c];\n\n // T1: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eに行って戻ってくる。\n T1[c] = max({\n t1,\n t1+T1[e]-2,\n });\n\n // T2: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eより前に片道があり、部分木eは行って戻ってくる。\n // - 部分木eより前は行って戻ってきて、部分木eは片道。\n T2[c] = max({\n t2,\n t2+T1[e]-2,\n t1+T2[e]-1,\n });\n\n // T3: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eより前にスタートもゴールもあり、部分木eは行って戻ってくる。\n // - 部分木eより前は行って戻ってきて、部分木eにスタートもゴールもある。\n // - 部分木eより前も、部分木eも片道。\n T3[c] = max({\n t3,\n t3+T1[e]-2,\n t1+T3[e]-2,\n t2+T2[e]-1,\n });\n }\n };\n f(0, -1);\n\n // ここまでの各部分木で得られる最高得点の中に、木全体での最高得点がある。\n int ans = -999999999;\n for (int t: T1)\n ans = max(ans, t);\n for (int t: T2)\n ans = max(ans, t);\n for (int t: T3)\n ans = max(ans, t);\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 22604, "score_of_the_acc": -1.2259, "final_rank": 10 }, { "submission_id": "aoj_0389_9637594", "code_snippet": "#include <iostream>\n#include <vector>\n#include <functional>\nusing namespace std;\n\nint main()\n{\n int N;\n cin>>N;\n vector<int> p(N);\n for (int &t: p)\n cin>>t;\n vector<vector<int>> E(N);\n for (int i=0; i<N-1; i++)\n {\n int s, t;\n cin>>s>>t;\n E[s-1].push_back(t-1);\n E[t-1].push_back(s-1);\n }\n\n // T1[c]: 頂点cを通り、スタートもゴールもcを頂点とする部分木に無い場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T1(N);\n // T2[c]: 頂点cを通り、スタートかゴールのどちらか一方がcを頂点とする部分木にある場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T2(N);\n // T3[c]: 頂点cを通り、スタートもゴールもcを頂点とする部分木にある場合に、cを頂点とする部分木で得られる最高得点。\n vector<int> T3(N);\n\n function<void(int, int)> f = [&](int c, int parent)\n {\n T1[c] = p[c];\n T2[c] = p[c];\n T3[c] = p[c];\n\n for (int e: E[c])\n if (e!=parent)\n {\n f(e, c);\n\n // 部分木eを考慮する前の値を退避しておく。\n int t1 = T1[c];\n int t2 = T2[c];\n int t3 = T3[c];\n\n // T1: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eに行って戻ってくる。\n T1[c] = max({\n t1,\n t1+T1[e]-2,\n });\n\n // T2: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eより前に片道があり、部分木eは行って戻ってくる。\n // - 部分木eより前は行って戻ってきて、部分木eは片道。\n T2[c] = max({\n t2,\n t2+T1[e]-2,\n t1+T2[e]-1,\n });\n\n // T3: 次のうちの最高得点。\n // - 部分木eに行かない。\n // - 部分木eより前にスタートもゴールもあり、部分木eは行って戻ってくる。\n // - 部分木eより前は行って戻ってきて、部分木eにスタートもゴールもある。\n // - 部分木eより前も、部分木eも片道。\n T3[c] = max({\n t3,\n t3+T1[e]-2,\n t1+T3[e]-2,\n t2+T2[e]-1,\n });\n }\n };\n f(0, -1);\n\n int ans = -999999999;\n for (int t: T1)\n ans = max(ans, t);\n for (int t: T2)\n ans = max(ans, t);\n for (int t: T3)\n ans = max(ans, t);\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 22548, "score_of_the_acc": -1.2237, "final_rank": 9 }, { "submission_id": "aoj_0389_9615952", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n/*\n17:29~17:43\n6:25~7:05\n13:10~13:19\n17:15~\n*/\n\ntemplate <class E, class V, E (*merge)(E, E), E (*e)(), E (*put_edge)(V, int), V (*put_vertex)(E, int)>\nstruct RerootingDP {\n struct edge {\n int to, idx, xdi;\n };\n RerootingDP(int n_ = 0) : n(n_), inner_edge_id(0) {\n es.resize(2*n-2);\n start.resize(2*n-2);\n if (n == 1) es_build();\n }\n void add_edge(int u, int v, int idx, int xdi){\n start[inner_edge_id] = u;\n es[inner_edge_id] = {v,idx,xdi};\n inner_edge_id++;\n start[inner_edge_id] = v;\n es[inner_edge_id] = {u,xdi,idx};\n inner_edge_id++;\n if (inner_edge_id == 2*n-2){\n es_build();\n }\n }\n vector<V> build(int root_ = 0){\n root = root_;\n vector<V> subdp(n); subdp[0] = put_vertex(e(),0);\n outs.resize(n);\n vector<int> geta(n+1,0);\n for (int i = 0; i < n; i++) geta[i+1] = start[i+1] - start[i] - 1;\n geta[root+1]++;\n for (int i = 0; i < n; i++) geta[i+1] += geta[i];\n auto dfs = [&](auto sfs, int v, int f) -> void {\n E val = e();\n for (int i = start[v]; i < start[v+1]; i++){\n if (es[i].to == f){\n swap(es[start[v+1]-1],es[i]);\n }\n if (es[i].to == f) continue;\n sfs(sfs,es[i].to,v);\n E nval = put_edge(subdp[es[i].to],es[i].idx);\n outs[geta[v]++] = nval;\n val = merge(val,nval);\n }\n subdp[v] = put_vertex(val, v);\n };\n dfs(dfs,root,-1);\n return subdp;\n }\n vector<V> reroot(){\n vector<E> reverse_edge(n);\n reverse_edge[root] = e();\n vector<V> answers(n);\n auto dfs = [&](auto sfs, int v) -> void {\n int le = outs_start(v);\n int ri = outs_start(v+1);\n int siz = ri - le;\n vector<E> rui(siz+1);\n rui[siz] = e();\n for (int i = siz-1; i >= 0; i--){\n rui[i] = merge(outs[le+i],rui[i+1]);\n }\n answers[v] = put_vertex(merge(rui[0],reverse_edge[v]),v);\n E lui = e();\n for (int i = 0; i < siz; i++){\n V rdp = put_vertex(merge(merge(lui,rui[i+1]),reverse_edge[v]),v);\n reverse_edge[es[start[v]+i].to] = put_edge(rdp,es[start[v]+i].xdi);\n lui = merge(lui,outs[le+i]);\n sfs(sfs,es[start[v]+i].to);\n }\n };\n dfs(dfs,root);\n return answers;\n }\n private:\n int n, root, inner_edge_id;\n vector<E> outs;\n vector<edge> es;\n vector<int> start;\n int outs_start(int v){\n int res = start[v] - v;\n if (root < v) res++;\n return res;\n }\n void es_build(){\n vector<edge> nes(2*n-2);\n vector<int> nstart(n+2,0);\n for (int i = 0; i < 2*n-2; i++) nstart[start[i]+2]++;\n for (int i = 0; i < n; i++) nstart[i+1] += nstart[i];\n for (int i = 0; i < 2*n-2; i++) nes[nstart[start[i]+1]++] = es[i];\n swap(es,nes);\n swap(start,nstart);\n }\n};\n\nint P[100009];\n\nusing S=array<int,2>;\n\nS merge(S x,S y){\n\tS z;\n\tz[0]=max<int>(0,x[0])+max<int>(0,y[0]);\n\tz[1]=max(max<int>(0,x[0])+max<int>(0,y[1]),max<int>(0,x[1])+max<int>(0,y[0]));\n\treturn z;\n}\n\nS e(){\n\treturn {0,0};\n}\n\nS put_edge(S x,int idx){\n\treturn {x[0]-2,x[1]-1};\n}\n\nS put_vertex(S x,int idx){\n\treturn {max<int>(0,x[0])+P[idx],max<int>(0,x[1])+P[idx]};\n}\n\nsigned main(){\n\tint n;cin>>n;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>P[i];\n\t}\n\n\tRerootingDP<S,S,merge,e,put_edge,put_vertex> g(n);\n\n\tfor(int i=0;i<n-1;i++){\n\t\tint s,t;cin>>s>>t;\n\t\ts--;t--;\n\t\tg.add_edge(s,t,i,i);\n\t}\n\n\tg.build();\n\n\tauto res=g.reroot();\n\n\tint ans=-1e18;\n\tfor(int i=0;i<n;i++){\n\t\tans=max(ans,res[i][0]);\n\t\tans=max(ans,res[i][1]);\n\t}\n\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 34152, "score_of_the_acc": -1.872, "final_rank": 15 }, { "submission_id": "aoj_0389_9577816", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<int> a(n);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < n - 1;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tu--;v--;\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tvector<int> dist(n,-1);\n\t{\n\t\tqueue<int> q;\n\t\tdist[0] = 0;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(int i : g[it]){\n\t\t\t\tif(dist[i] != -1) continue;\n\t\t\t\tdist[i] = dist[it] + 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -INT_MAX;\n\tvector<int> e(n,-INT_MAX);\n\tauto f = [&](auto f,int x) -> pair<int,int> {\n\t\tpair<int,int> res = {a[x],a[x]};\n\t\tvector<pair<pair<int,int>,int>> t;\n\t\tint p = -1;\n\t\tint tmp = 0;\n\t\tfor(int i : g[x]){\n\t\t\tp++;\n\t\t\tif(dist[i] < dist[x]){\n\t\t\t\tt.push_back({{-1000,0},p});\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tpair<int,int> r = f(f,i);\n\t\t\tif(e[x] < e[i] - 2 + a[x]){\n\t\t\t\te[x] = e[i] - 2 + a[x];\n\t\t\t\ttmp = max(r.second - 2,0);\n\t\t\t}\n\t\t\tt.push_back({r,p});\n\t\t\tif(r.second - 2 >= 0){\n\t\t\t\tres.second += r.second - 2;\n\t\t\t}\n\t\t}\n\t\tauto com = [](pair<pair<int,int>,int> a,pair<pair<int,int>,int> b) -> bool {\n\t\t\tif(a.first.first == -1000 && b.first.first == -1000) return true;\n\t\t\tif(a.first.first == -1000) return false;\n\t\t\tif(b.first.first == -1000) return true;\n\t\t\ta.first = {max(0,a.first.first - 1),max(0,a.first.second - 2)};\n\t\t\tb.first = {max(0,b.first.first - 1),max(0,b.first.second - 2)};\n\t\t\treturn a.first.first - a.first.second > b.first.first - b.first.second;\n\t\t};\n\t\tsort(t.begin(),t.end(),com);\n\t\tint cnt = -1;\n\t\tint now = a[x];\n\t\tfor(int i : g[x]){\n\t\t\tcnt++;\n\t\t\tif(cnt == 0){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.first - 1,0);\n\t\t\t}else if(cnt == 1){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}else{\n\t\t\t\tnow += max(t[cnt].first.second - 2,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}\n\t\t\te[x] += max(t[cnt].first.second - 2,0);\n\t\t}\n\t\te[x] -= tmp;\n\t\te[x] = max({e[x],now,res.first,res.second});\n\t\tans = max(ans,e[x]);\n\t\treturn res;\n\t};\n\tf(f,0);\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 33180, "score_of_the_acc": -1.6345, "final_rank": 13 }, { "submission_id": "aoj_0389_9577743", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<int> a(n);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < n - 1;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tu--;v--;\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tvector<int> dist(n,-1);\n\t{\n\t\tqueue<int> q;\n\t\tdist[0] = 0;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(int i : g[it]){\n\t\t\t\tif(dist[i] != -1) continue;\n\t\t\t\tdist[i] = dist[it] + 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -INT_MAX;\n\tvector<int> e(n,-INT_MAX);\n\tauto f = [&](auto f,int x) -> pair<int,int> {\n\t\tpair<int,int> res = {a[x],a[x]};\n\t\tvector<pair<pair<int,int>,int>> t;\n\t\tint p = -1;\n\t\tfor(int i : g[x]){\n\t\t\tp++;\n\t\t\tif(dist[i] < dist[x]){\n\t\t\t\tt.push_back({{-1000,0},p});\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tpair<int,int> r = f(f,i);\n\t\t\te[x] = max(e[x],e[i] - 2 + a[x]);\n\t\t\tt.push_back({r,p});\n\t\t\tif(r.second - 2 >= 0){\n\t\t\t\tres.second += r.second - 2;\n\t\t\t}\n\t\t}\n\t\tauto com = [](pair<pair<int,int>,int> a,pair<pair<int,int>,int> b) -> bool {\n\t\t\ta.first = {max(0,a.first.first - 1),max(0,a.first.second - 2)};\n\t\t\tb.first = {max(0,b.first.first - 1),max(0,b.first.second - 2)};\n\t\t\treturn a.first.first - a.first.second > b.first.first - b.first.second;\n\t\t};\n\t\tsort(t.begin(),t.end(),com);\n\t\tint cnt = -1;\n\t\tint now = a[x];\n\t\tfor(int i : g[x]){\n\t\t\tcnt++;\n\t\t\tif(cnt == 0){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.first - 1,0);\n\t\t\t}else if(cnt == 1){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}else{\n\t\t\t\tnow += max(t[cnt].first.second - 2,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}\n\t\t}\n\t\te[x] = max({e[x],now,res.first,res.second});\n\t\tans = max(ans,e[x]);\n\t\treturn res;\n\t};\n\tf(f,0);\n\tcout << ans << endl;\n}", "accuracy": 0.625, "time_ms": 50, "memory_kb": 33184, "score_of_the_acc": -1.6346, "final_rank": 17 }, { "submission_id": "aoj_0389_9577702", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<int> a(n);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < n - 1;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tu--;v--;\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tvector<int> dist(n,-1);\n\t{\n\t\tqueue<int> q;\n\t\tdist[0] = 0;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(int i : g[it]){\n\t\t\t\tif(dist[i] != -1) continue;\n\t\t\t\tdist[i] = dist[it] + 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -INT_MAX;\n\tvector<int> e(n,-INT_MAX);\n\tauto f = [&](auto f,int x) -> pair<int,int> {\n\t\tpair<int,int> res = {a[x],a[x]};\n\t\tvector<pair<pair<int,int>,int>> t;\n\t\tint p = -1;\n\t\tfor(int i : g[x]){\n\t\t\tp++;\n\t\t\tif(dist[i] < dist[x]){\n\t\t\t\tt.push_back({{-1000,0},p});\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tpair<int,int> r = f(f,i);\n\t\t\te[x] = max(e[x],e[i] - 2 + a[x]);\n\t\t\tt.push_back({r,p});\n\t\t\tif(r.second - 2 >= 0){\n\t\t\t\tres.second += r.second - 2;\n\t\t\t}\n\t\t}\n\t\tauto com = [](pair<pair<int,int>,int> a,pair<pair<int,int>,int> b) -> bool {\n\t\t\tif((a.first.first < 0 || a.first.second < 0) && (b.first.first < 0 || b.first.second < 0)){\n\t\t\t\treturn a.first.first < b.first.first;\n\t\t\t}\n\t\t\tif(a.first.first < 0 || a.first.second < 0) return false;\n\t\t\tif(b.first.first < 0 || b.first.second < 0) return true;\n\t\t\tif(a.first.first < 1 || a.first.second < 1) return false;\n\t\t\tif(b.first.first < 1 || b.first.second < 1) return true;\n\t\t\tif(a.first.second - a.first.first == b.first.second - b.first.first){\n\t\t\t\treturn a.first.first > b.first.first;\n\t\t\t}\n\t\t\treturn a.first.second - a.first.first < b.first.second - b.first.first;\n\t\t};\n\t\tsort(t.begin(),t.end(),com);\n\t\tint cnt = -1;\n\t\tint now = a[x];\n\t\tfor(int i : g[x]){\n\t\t\tcnt++;\n\t\t\tif(cnt == 0){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.first - 1,0);\n\t\t\t}else if(cnt == 1){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}else{\n\t\t\t\tnow += max(t[cnt].first.second - 2,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}\n\t\t}\n\t\te[x] = max({e[x],now,res.first,res.second});\n\t\tans = max(ans,e[x]);\n\t\treturn res;\n\t};\n\tf(f,0);\n\tcout << ans << endl;\n}", "accuracy": 0.28125, "time_ms": 50, "memory_kb": 33028, "score_of_the_acc": -1.6286, "final_rank": 19 }, { "submission_id": "aoj_0389_9577674", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<int> a(n);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < n - 1;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tu--;v--;\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tvector<int> dist(n,-1);\n\t{\n\t\tqueue<int> q;\n\t\tdist[0] = 0;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(int i : g[it]){\n\t\t\t\tif(dist[i] != -1) continue;\n\t\t\t\tdist[i] = dist[it] + 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -INT_MAX;\n\tvector<int> e(n,-INT_MAX);\n\tauto f = [&](auto f,int x) -> pair<int,int> {\n\t\tpair<int,int> res = {a[x],a[x]};\n\t\tvector<pair<pair<int,int>,int>> t;\n\t\tint p = -1;\n\t\tfor(int i : g[x]){\n\t\t\tp++;\n\t\t\tif(dist[i] < dist[x]){\n\t\t\t\tt.push_back({{-1000,0},p});\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tpair<int,int> r = f(f,i);\n\t\t\te[x] = max(e[x],e[i] - 2 + a[x]);\n\t\t\tt.push_back({r,p});\n\t\t\tif(r.second - 2 >= 0){\n\t\t\t\tres.second += r.second - 2;\n\t\t\t}\n\t\t}\n\t\tauto com = [](pair<pair<int,int>,int> a,pair<pair<int,int>,int> b) -> bool {\n\t\t\tif((a.first.first < 0 || a.first.second < 0) && (b.first.first < 0 || b.first.second < 0)){\n\t\t\t\treturn a.first.first < b.first.first;\n\t\t\t}\n\t\t\tif(a.first.first < 0 || a.first.second < 0) return false;\n\t\t\tif(b.first.first < 0 || b.first.second < 0) return true;\n\t\t\tif(a.first.second - a.first.first == b.first.second - b.first.first){\n\t\t\t\treturn a.first.first > b.first.first;\n\t\t\t}\n\t\t\treturn a.first.second - a.first.first < b.first.second - b.first.first;\n\t\t};\n\t\tsort(t.begin(),t.end(),com);\n\t\tint cnt = -1;\n\t\tint now = a[x];\n\t\tfor(int i : g[x]){\n\t\t\tcnt++;\n\t\t\tif(cnt == 0){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.first - 1,0);\n\t\t\t}else if(cnt == 1){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}else{\n\t\t\t\tnow += max(t[cnt].first.second - 2,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}\n\t\t}\n\t\te[x] = max({e[x],now,res.first,res.second});\n\t\tans = max(ans,e[x]);\n\t\treturn res;\n\t};\n\tf(f,0);\n\tcout << ans << endl;\n}", "accuracy": 0.28125, "time_ms": 50, "memory_kb": 33108, "score_of_the_acc": -1.6317, "final_rank": 20 }, { "submission_id": "aoj_0389_9577665", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tvector<int> a(n);\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t}\n\tvector<vector<int>> g(n,vector<int>());\n\tfor(int i = 0;i < n - 1;i++){\n\t\tint u,v;\n\t\tcin >> u >> v;\n\t\tu--;v--;\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tvector<int> dist(n,-1);\n\t{\n\t\tqueue<int> q;\n\t\tdist[0] = 0;\n\t\tq.push(0);\n\t\twhile(!q.empty()){\n\t\t\tint it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(int i : g[it]){\n\t\t\t\tif(dist[i] != -1) continue;\n\t\t\t\tdist[i] = dist[it] + 1;\n\t\t\t\tq.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -INT_MAX;\n\tvector<int> e(n,-INT_MAX);\n\tauto f = [&](auto f,int x) -> pair<int,int> {\n\t\tpair<int,int> res = {a[x],a[x]};\n\t\tvector<pair<pair<int,int>,int>> t;\n\t\tint p = -1;\n\t\tfor(int i : g[x]){\n\t\t\tp++;\n\t\t\tif(dist[i] < dist[x]){\n\t\t\t\tt.push_back({{-1000,0},p});\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tpair<int,int> r = f(f,i);\n\t\t\te[x] = max(e[x],e[i] - 2 + a[x]);\n\t\t\tt.push_back({r,p});\n\t\t\tif(r.second - 2 >= 0){\n\t\t\t\tres.second += r.second - 2;\n\t\t\t}\n\t\t}\n\t\tauto com = [](pair<pair<int,int>,int> a,pair<pair<int,int>,int> b) -> bool {\n\t\t\tif(a.first.first < 0 && b.first.first < 0){\n\t\t\t\treturn a.first.first < b.first.first;\n\t\t\t}\n\t\t\tif(a.first.first < 0) return false;\n\t\t\tif(b.first.first < 0) return true;\n\t\t\tif(a.first.second - a.first.first == b.first.second - b.first.first){\n\t\t\t\treturn a.first.first > b.first.first;\n\t\t\t}\n\t\t\treturn a.first.second - a.first.first < b.first.second - b.first.first;\n\t\t};\n\t\tsort(t.begin(),t.end(),com);\n\t\tint cnt = -1;\n\t\tint now = a[x];\n\t\tfor(int i : g[x]){\n\t\t\tcnt++;\n\t\t\tif(cnt == 0){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.first - 1,0);\n\t\t\t}else if(cnt == 1){\n\t\t\t\tnow += max(t[cnt].first.first - 1,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}else{\n\t\t\t\tnow += max(t[cnt].first.second - 2,0);\n\t\t\t\tres.first += max(t[cnt].first.second - 2,0);\n\t\t\t}\n\t\t}\n\t\te[x] = max({e[x],now,res.first,res.second});\n\t\tans = max(ans,e[x]);\n\t\treturn res;\n\t};\n\tf(f,0);\n\tcout << ans << endl;\n}", "accuracy": 0.625, "time_ms": 50, "memory_kb": 33152, "score_of_the_acc": -1.6334, "final_rank": 16 }, { "submission_id": "aoj_0389_9023821", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing S = array<int, 3>;\n\nint main() {\n int N;\n cin >> N;\n vector<int> p(N);\n for(int i = 0; i < N; i++) {\n cin >> p[i];\n }\n vector<vector<int>> G(N);\n for(int i = 0; i < N-1; i++) {\n int s, t;\n cin >> s >> t;\n s--, t--;\n G[s].push_back(t);\n G[t].push_back(s);\n }\n const int INF = 1e8;\n vector<S> dp(N);\n auto dfs = [&](auto dfs, int cur, int par) -> void {\n for(int &nxt : G[cur]) {\n if(par == nxt) continue;\n dfs(dfs, nxt, cur);\n }\n dp[cur] = S{p[cur], p[cur], p[cur]};\n { // 頂点 cur でマージ\n int merged = 0;\n vector<int> diff = {0, 0};\n for(int &nxt : G[cur]) {\n if(par == nxt) continue;\n int x = max(0, dp[nxt][1]-1);\n int y = max(0, dp[nxt][2]-2);\n merged += y;\n diff.push_back(x-y);\n }\n sort(diff.rbegin(), diff.rend());\n merged += diff[0]+diff[1];\n dp[cur][0] = max(dp[cur][0], merged+p[cur]);\n }\n { // 頂点 cur に値を伝播させる\n int merged = 0;\n for(int &nxt : G[cur]) {\n if(par == nxt) continue;\n int x = max(0, dp[nxt][1]-1);\n int y = max(0, dp[nxt][2]-2);\n merged += y;\n }\n dp[cur][2] = max(dp[cur][2], merged+p[cur]);\n for(int &nxt : G[cur]) {\n if(par == nxt) continue;\n int x = max(0, dp[nxt][1]-1);\n int y = max(0, dp[nxt][2]-2);\n int z = max(0, dp[nxt][0]-2);\n dp[cur][1] = max(dp[cur][1], merged-y+x+p[cur]);\n dp[cur][0] = max(dp[cur][0], merged-y+z+p[cur]);\n }\n }\n // cout << cur+1 << \" : \" << dp[cur][0] << \" \" << dp[cur][1] << \" \" << dp[cur][2] << endl;\n };\n dfs(dfs, 0, -1);\n int ans = -INF;\n for(int i = 0; i < N; i++) {\n ans = max({ans, dp[i][0], dp[i][1], dp[i][2]});\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 27260, "score_of_the_acc": -1.4058, "final_rank": 12 }, { "submission_id": "aoj_0389_8719283", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n int n;\n std::cin >> n;\n std::vector<int> ps(n);\n for (int i = 0; i < n; i++) std::cin >> ps[i];\n std::vector graph(n, std::vector<int>());\n for (int i = 0; i + 1 < n; i++) {\n int u, v;\n std::cin >> u >> v;\n u--; v--;\n graph[u].push_back(v);\n graph[v].push_back(u);\n }\n std::vector dp(2, std::vector<int>(n));\n const int root = 0;\n {\n auto dfs = [&](auto self, int u, int p) -> void {\n dp[0][u] = ps[u];\n for (int v: graph[u]) {\n if (v == p) continue;\n self(self, v, u);\n dp[0][u] += std::max(dp[0][v] - 2, 0);\n }\n dp[1][u] = dp[0][u];\n for (int v: graph[u]) {\n if (v == p) continue;\n dp[1][u] = std::max(dp[1][u], dp[0][u] - std::max(dp[0][v] - 2, 0) + dp[1][v] - 1);\n }\n };\n dfs(dfs, root, -1);\n }\n int ans = -200;\n {\n auto dfs = [&](auto self, int u, int p, std::pair<int, int> pv) -> void {\n std::pair<int, int> now;\n now.first = ps[u];\n for (int v: graph[u]) {\n if (v == p) {\n now.first += std::max(pv.first - 2, 0);\n } else{\n now.first += std::max(dp[0][v] - 2, 0);\n }\n }\n now.second = now.first;\n for (int v: graph[u]) {\n if (v == p) {\n now.second = std::max(now.second, now.first - std::max(pv.first - 2, 0) + pv.second - 1);\n } else {\n now.second = std::max(now.second, now.first - std::max(dp[0][v] - 2, 0) + dp[1][v] - 1);\n }\n }\n ans = std::max(ans, now.second);\n int m = graph[u].size();\n std::vector<int> prefix(m + 1), suffix(m + 1);\n for (int i = 0; i < m; i++) {\n int v = graph[u][i];\n if (v == p) {\n prefix[i + 1] = std::max(prefix[i], pv.second - std::max(pv.first - 2, 0) - 1);\n } else {\n prefix[i + 1] = std::max(prefix[i], dp[1][v] - std::max(dp[0][v] - 2, 0) - 1);\n }\n }\n for (int i = m - 1; i >= 0; i--) {\n int v = graph[u][i];\n int j = m - i - 1;\n if (v == p) {\n suffix[j + 1] = std::max(suffix[j], pv.second - std::max(pv.first - 2, 0) - 1);\n } else {\n suffix[j + 1] = std::max(suffix[j], dp[1][v] - std::max(dp[0][v] - 2, 0) - 1);\n }\n }\n std::reverse(suffix.begin(), suffix.end());\n for (int i = 0; i < m; i++) {\n int v = graph[u][i];\n if (v == p) continue;\n std::pair<int, int> cv;\n cv.first = now.first - std::max(dp[0][v] - 2, 0);\n cv.second = cv.first + std::max(prefix[i], suffix[i + 1]);\n self(self, v, u, cv);\n }\n };\n dfs(dfs, root, -1, {0, 0});\n }\n std::cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 32980, "score_of_the_acc": -1.8268, "final_rank": 14 }, { "submission_id": "aoj_0389_8719282", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n int n;\n std::cin >> n;\n std::vector<int> ps(n);\n for (int i = 0; i < n; i++) std::cin >> ps[i];\n std::vector graph(n, std::vector<int>());\n for (int i = 0; i + 1 < n; i++) {\n int u, v;\n std::cin >> u >> v;\n u--; v--;\n graph[u].push_back(v);\n graph[v].push_back(u);\n }\n std::vector dp(2, std::vector<int>(n));\n const int root = 0;\n {\n auto dfs = [&](auto self, int u, int p) -> void {\n dp[0][u] = ps[u];\n for (int v: graph[u]) {\n if (v == p) continue;\n self(self, v, u);\n dp[0][u] += std::max(dp[0][v] - 2, 0);\n }\n dp[1][u] = dp[0][u];\n for (int v: graph[u]) {\n if (v == p) continue;\n dp[1][u] = std::max(dp[1][u], dp[0][u] - std::max(dp[0][v] - 2, 0) + dp[1][v] - 1);\n }\n };\n dfs(dfs, root, -1);\n }\n int ans = -200;\n {\n auto dfs = [&](auto self, int u, int p, std::pair<int, int> pv) -> void {\n std::pair<int, int> now;\n now.first = ps[u];\n for (int v: graph[u]) {\n if (v == p) {\n now.first += std::max(pv.first - 2, 0);\n } else{\n now.first += std::max(dp[0][v] - 2, 0);\n }\n }\n now.second = now.first;\n for (int v: graph[u]) {\n if (v == p) {\n now.second = std::max(now.second, now.first - std::max(pv.first - 2, 0) + pv.second - 1);\n } else {\n now.second = std::max(now.second, now.first - std::max(dp[0][v] - 2, 0) + dp[1][v] - 1);\n }\n }\n ans = std::max(ans, now.second);\n int m = graph[u].size();\n std::vector<int> prefix(m + 1), suffix(m + 1);\n for (int i = 0; i < m; i++) {\n int v = graph[u][i];\n if (v == p) {\n prefix[i + 1] = std::max(prefix[i], pv.second - std::max(pv.first - 2, 0) - 1);\n } else {\n prefix[i + 1] = std::max(prefix[i], dp[1][v] - std::max(dp[0][v] - 2, 0) - 1);\n }\n }\n for (int i = m - 1; i >= 0; i--) {\n int v = graph[u][i];\n int j = m - i - 1;\n if (v == p) {\n suffix[i + 1] = std::max(suffix[i], pv.second - std::max(pv.first - 2, 0) - 1);\n } else {\n suffix[j + 1] = std::max(suffix[j], dp[1][v] - std::max(dp[0][v] - 2, 0) - 1);\n }\n }\n std::reverse(suffix.begin(), suffix.end());\n for (int i = 0; i < m; i++) {\n int v = graph[u][i];\n if (v == p) continue;\n std::pair<int, int> cv;\n cv.first = now.first - std::max(dp[0][v] - 2, 0);\n cv.second = cv.first + std::max(prefix[i], suffix[i + 1]);\n self(self, v, u, cv);\n }\n };\n dfs(dfs, root, -1, {0, 0});\n }\n std::cout << ans << '\\n';\n}", "accuracy": 0.359375, "time_ms": 60, "memory_kb": 31512, "score_of_the_acc": -1.7701, "final_rank": 18 }, { "submission_id": "aoj_0389_6974562", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0389.cc: Dungeon 2\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int INF = 1 << 30;\n\n/* typedef */\n\ntypedef vector<int> vi;\n\n/* global variables */\n\nint as[MAX_N], ps[MAX_N], cis[MAX_N];\nint ss[MAX_N], xds0[MAX_N], xds1[MAX_N];\nint mxs[MAX_N], ts[MAX_N];\nvi nbrs[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n for (int i = 1; i < n; i++) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n u--, v--;\n nbrs[u].push_back(v);\n nbrs[v].push_back(u);\n }\n\n ps[0] = -1;\n for (int u = 0; u >= 0;) {\n vi &nbru = nbrs[u];\n int up = ps[u];\n\n if (cis[u] < nbru.size()) {\n int v = nbru[cis[u]++];\n if (v != up) {\n\tps[v] = u;\n\tu = v;\n }\n }\n else {\n ss[u] += as[u];\n mxs[u] = ss[u] + xds0[u] + xds1[u];\n\n if (up >= 0) {\n\tint su = ss[u] - 2;\n\tint du = xds0[u] + 1;\n\tif (su > 0) ss[up] += su;\n\telse du += su;\n\n\tif (du > 0) {\n\t if (xds0[up] < du) xds1[up] = xds0[up], xds0[up] = du;\n\t else if (xds1[up] < du) xds1[up] = du;\n\t}\n }\n\n u = up;\n }\n }\n\n fill(cis, cis + n, 0);\n ts[0] = 0;\n int maxd = -INF;\n for (int u = 0; u >= 0;) {\n vi &nbru = nbrs[u];\n int up = ps[u];\n\n if (cis[u] < nbru.size()) {\n int v = nbru[cis[u]++];\n if (v != up) {\n\tint tu = ts[u] + ss[u];\n\tint tv = tu - (ss[v] > 2 ? ss[v] : 2);\n\tts[v] = max(0, tv);\n\tu = v;\n }\n }\n else {\n maxd = max(maxd, mxs[u] + ts[u]);\n //printf(\"%d: %d, %d, %d\\n\", u, mxs[u], ts[u], ss[u]);\n u = up;\n }\n }\n\n printf(\"%d\\n\", maxd);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11580, "score_of_the_acc": -0.2, "final_rank": 1 } ]
aoj_0398_cpp
Beautiful Sequence Alice is spending his time on an independent study to apply to the Nationwide Mathematics Contest. This year’s theme is "Beautiful Sequence." As Alice is interested in the working of computers, she wants to create a beautiful sequence using only 0 and 1. She defines a "Beautiful" sequence of length $N$ that consists only of 0 and 1 if it includes $M$ successive array of 1s as its sub-sequence. Using his skills in programming, Alice decided to calculate how many "Beautiful sequences" she can generate and compile a report on it. Make a program to evaluate the possible number of "Beautiful sequences" given the sequence length $N$ and sub-sequence length $M$ that consists solely of 1. As the answer can be extremely large, divide it by $1,000,000,007 (= 10^9 + 7)$ and output the remainder. Input The input is given in the following format. $N$ $M$ The input line provides the length of sequence $N$ ($1 \leq N \leq 10^5$) and the length $M$ ($1 \leq M \leq N$) of the array that solely consists of 1s. Output Output the number of Beautiful sequences in a line. Sample Input 1 4 3 Sample Output 1 3 The sequences with length 4 that include 1s in successive array of length 3 are: 0111, 1110 and 1111. Sample Input 2 4 2 Sample Output 2 8 The sequences with length 4 that include 1s in successive array of length 2 are: 0011, 0110, 0111, 1011, 1100, 1101, 1110 and 1111.
[ { "submission_id": "aoj_0398_9703022", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int mod = 1e9 + 7;\nll fast_power(ll a , ll p) {\n if(p == 0)return 1;\n ll res = fast_power(a , p / 2);\n res = res * res % mod;\n if(p & 1)res = a % mod * res % mod;\n return res;\n}\nconst int N = 1e5 + 1;\nll dp[N];\nsigned main() {\n ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n int n , m;cin>>n>>m;\n for(int i = 0;i <= m;i++) {\n dp[i] = fast_power(2ll , i);\n }\n dp[m] -= 1;\n dp[m] = (dp[m] + mod) % mod;\n for(int i = m + 1;i <= n;i++) {\n dp[i] = 2 * dp[i - 1] - dp[i - 1 - m];\n dp[i] %= mod;\n dp[i] = (dp[i] + mod) % mod;\n }\n cout<<(fast_power(2ll , n) - dp[n] + mod) % mod<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4016, "score_of_the_acc": -0.0545, "final_rank": 2 }, { "submission_id": "aoj_0398_6043997", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define all(a) a.begin(),a.end()\n#define int long long\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef pair<int,int> P;\nconstexpr ll mod = 1000000007;\n\nstruct segtree{\n\tvi node,lazy;\n\tint N;\n\tvoid init(int _){\n\t\tN=1;\n\t\twhile(N<_)N*=2;\n\t\tnode.resize(2*N);\n\t\tlazy.resize(2*N);\n\t}\n\tvoid eval(int k,int l,int r){\n\t\tif(!lazy[k])return;\n\t\tnode[k]+=lazy[k]*(r-l)%mod;\n\t\tnode[k]%=mod;\n\t\tif(k<N-1){\n\t\t\tlazy[2*k+1]+=lazy[k];\n\t\t\tlazy[2*k+1]%=mod;\n\t\t\tlazy[2*k+2]+=lazy[k];\n\t\t\tlazy[2*k+2]%=mod;\n\t\t}\n\t\tlazy[k]=0;\n\t}\t\n\tvoid upd(int a,int b,int x,int k,int l,int r){\n\t\teval(k,l,r);\n\t\tif(r<=a||b<=l)return;\n\t\tif(a<=l&&r<=b){\n\t\t\tlazy[k]+=x;\n\t\t\tlazy[k]%=mod;\n\t\t\teval(k,l,r);return;\n\t\t}\n\t\tupd(a,b,x,k*2+1,l,(l+r)/2);\n\t\tupd(a,b,x,k*2+2,(l+r)/2,r);\n\t\tnode[k]=node[k*2+1]+node[k*2+2];\n\t\tnode[k]%=mod;\n\t}\n\tll calc(int a,int b,int k,int l,int r){\n\t\teval(k,l,r);\n\t\tif(r<=a||b<=l)return 0;\n\t\tif(a<=l&&r<=b)return node[k];\n\t\tll vl=calc(a,b,k*2+1,l,(l+r)/2);\n\t\tll vr=calc(a,b,k*2+2,(l+r)/2,r);\n\t\treturn (vl+vr)%mod;\n\t}\n\tvoid add(int l,int r,int x){\n\t\tupd(l,r,x,0,0,N);\n\t}\n\tll get(int l,int r){\n\t\treturn calc(l,r,0,0,N);\n\t}\n};\n\nll modpow(ll a,ll x){\n\tll res=1;\n\twhile(x){\n\t\tif(x&1)res=res*a%mod;\n\t\ta=a*a%mod;\n\t\tx>>=1;\n\t}\n\treturn res;\n}\n\nsegtree S1,S2;\nsigned main(){\n\tll n,m;cin>>n>>m;m--;\n\tS1.init(n+2);\n\tS2.init(n+2);\n\tS1.add(0,1,1);\n\tS2.add(0,1,1);\n\tfor(int i=1;i<=n;i++){\n\t\tS2.add(i,n+1,S1.get(i-1,i));\n\t\tS1.add(i,min(i+m,n+1),S2.get(i-1,i));\n\t}\n\n\tll ans=modpow(2,n);\n\tans-=S1.get(n,n+1);\n\tans-=S2.get(n,n+1);\n\tans+=mod*2;\n\tans%=mod;\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 11236, "score_of_the_acc": -2, "final_rank": 7 }, { "submission_id": "aoj_0398_6038843", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\ntypedef vector<int> vint;\ntypedef long long int llint;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define all(a) a.begin(),a.end()\n#define mod llint(1e9+7)\n\nint power(int a, int b) {\n\tif (b == 1)return a;\n\tif (b == 0)return 1;\n\tllint tmp = power(a, b / 2);\n\ttmp *= tmp;\n\ttmp %= mod;\n\tif (b % 2 == 1) {\n\t\ttmp *= (llint)a;\n\t\ttmp %= mod;\n\t}\n\treturn tmp;\n}\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tvint dp(n + 1);\n\tdp[m] = 1;\n\tfor (int i = m; i < n; i++) {\n\t\t(dp[i + 1] = dp[i] * 2) %= mod;\n\t\t(dp[i + 1] += power(2, i - m)) %= mod;\n\t\t(dp[i + 1] -= dp[i - m]) %= mod;\n\t}\n\twhile (dp[n] < 0)dp[n] += mod;\n\tcout << dp[n] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3600, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0398_4974260", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\n \n#define REP(i, n) for (ll i = 0; i < n; i++)\n#define REPR(i, n) for (ll i = n; i >= 0; i--)\n#define FOR(i, m, n) for (ll i = m; i < n; i++)\n#define FORR(i, m, n) for (ll i = m; i >= n; i--)\n#define REPO(i, n) for (ll i = 1; i <= n; i++)\n#define ll long long\n#define INF (ll)1 << 60\n#define MINF (-1 INF)\n#define ALL(n) n.begin(), n.end()\n#define MOD 1000000007\n#define P pair<ll, ll>\n\nstruct SegTree{\n ll sz;\n vector<ll> dat;\n SegTree(ll n){\n sz = 1;\n while (sz < n) sz *= 2;\n dat.resize(2 * sz - 1, 0);\n }\n void update(ll a, ll x){\n a += sz - 1;\n dat[a] = x;\n while(a > 0){\n a = (a - 1) / 2;\n dat[a] = dat[a * 2 + 1] + dat[a * 2 + 2];\n }\n \n }\n ll query(ll a, ll b, ll k = 0, ll l = 0, ll r = -1){\n if (r < 0) r = sz;\n if (r <= a or b <= l) return 0;\n if (a <= l and r <= b) return dat[k];\n ll q1, q2;\n q1 = query(a, b, k * 2 + 1, l, (l + r) / 2);\n q2 = query(a, b, k * 2 + 2, (l + r) / 2, r);\n return q1 + q2;\n }\n};\n\nSegTree tree(110000);\nll n, m, dp[110000];\nint main(){\n cin >> n >> m;\n tree.update(0, 1);\n REPO(i, n + 1){\n tree.update(i, tree.query(max(0ll, i - m), i) % MOD) ;\n //cout << i - m << endl;\n //cout << tree.query(i, i + 1) << endl;\n }\n ll a = 1;\n REP(i, n){\n a *= 2;\n a %= MOD;\n }\n cout << (a - tree.query(n + 1, n + 2) + MOD * 2) % MOD << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4784, "score_of_the_acc": -0.1551, "final_rank": 3 }, { "submission_id": "aoj_0398_4823615", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\ntemplate<int modulo> struct ModInt {\n int x;\n\n ModInt() : x(0) {}\n ModInt(ll y) : x(y >= 0 ? y % modulo : (modulo - (-y) % modulo) % modulo) {}\n\n ModInt& operator+=(const ModInt& p) {\n if ((x += p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator-=(const ModInt& p) {\n if ((x += modulo - p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator*=(const ModInt& p) {\n x = (int)(1LL * x * p.x % modulo);\n return *this;\n }\n ModInt& operator/=(const ModInt& p) {\n *this *= p.inverse();\n return *this;\n }\n\n ModInt operator-() const { return ModInt(-x); }\n ModInt operator+(const ModInt& p) const { return ModInt(*this) += p; }\n ModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; }\n ModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; }\n ModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; }\n\n bool operator==(const ModInt& p) const { return x == p.x; }\n bool operator!=(const ModInt& p) const { return x != p.x; }\n\n ModInt inverse() const {\n int a = x, b = modulo, u = 1, v = 0, t;\n while (b > 0) {\n t = a / b;\n a -= t * b;\n swap(a, b);\n u -= t * v;\n swap(u, v);\n }\n return ModInt(u);\n }\n\n ModInt pow(ll e) {\n ll a = 1, p = x;\n while (e > 0) {\n if (e % 2 == 0) {\n p = (p * p) % modulo;\n e /= 2;\n }\n else {\n a = (a * p) % modulo;\n e--;\n }\n }\n return ModInt(a);\n }\n\n friend ostream& operator<<(ostream& os, const ModInt<modulo>& p) {\n return os << p.x;\n }\n friend istream& operator>>(istream& is, ModInt<modulo>& a) {\n ll x;\n is >> x;\n a = ModInt<modulo>(x);\n return (is);\n }\n};\nusing modint = ModInt<mod>;\n\ntemplate<class Op> class SegmentTree {\n\tusing T = typename Op::T;\n\tint len, n;\n\tvector<T> dat;\n T unit = Op::unit;\npublic:\n\tSegmentTree(const int _n) : n(_n) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t}\n\tSegmentTree(const vector<T>& v) : n(v.size()) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t\tfor (int i = 0; i < n; ++i)dat[i + len] = v[i];\n\t\tfor (int i = len - 1; 0 < i; --i)\n\t\t\tdat[i] = Op::merge(dat[i << 1], dat[i << 1 | 1]);\n\t}\n\tinline void update(int idx, const T a) {\n\t\tidx += len;\n\t\tdat[idx] = Op::update(dat[idx], a);\n\t\tfor (idx >>= 1; 0 < idx; idx >>= 1)\n\t\t\tdat[idx] = Op::merge(dat[idx << 1], dat[idx << 1 | 1]);\n\t}\n\tinline T value(int l, int r) {\n\t\tT vl = unit, vr = unit;\n\t\tfor (l += len, r += len; l < r; l >>= 1, r >>= 1) {\n\t\t\tif (l & 1)vl = Op::merge(vl, dat[l++]);\n\t\t\tif (r & 1)vr = Op::merge(dat[--r], vr);\n\t\t}\n\t\treturn Op::merge(vl, vr);\n\t}\n\tinline T operator[](int idx) { return dat[idx + len]; }\n};\ntemplate<class Type> struct modintSumAddUpdate {\n\tusing T = Type;\n const static T unit = 0;\n inline static T merge(T vl, T vr) { return (vl + vr) % mod; }\n inline static T update(T vl, T vr) { return (vl + vr) % mod; }\n};\n\nint main() {\n init();\n\n int n, m; cin >> n >> m;\n vector<SegmentTree<modintSumAddUpdate<ll>>> dp(2, n + 2);\n dp[0].update(0, 1);\n eFOR(i, 1, n + 1) {\n if (m + 1 <= i)dp[1].update(i, dp[0].value(0, i - m));\n dp[0].update(i, dp[0].value(max(0, i - m), i));\n dp[1].update(i, dp[1].value(0, i));\n }\n print(dp[1][n + 1]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8988, "score_of_the_acc": -0.9556, "final_rank": 5 }, { "submission_id": "aoj_0398_4823608", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\ntemplate<int modulo> struct ModInt {\n int x;\n\n ModInt() : x(0) {}\n ModInt(ll y) : x(y >= 0 ? y % modulo : (modulo - (-y) % modulo) % modulo) {}\n\n ModInt& operator+=(const ModInt& p) {\n if ((x += p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator-=(const ModInt& p) {\n if ((x += modulo - p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator*=(const ModInt& p) {\n x = (int)(1LL * x * p.x % modulo);\n return *this;\n }\n ModInt& operator/=(const ModInt& p) {\n *this *= p.inverse();\n return *this;\n }\n\n ModInt operator-() const { return ModInt(-x); }\n ModInt operator+(const ModInt& p) const { return ModInt(*this) += p; }\n ModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; }\n ModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; }\n ModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; }\n\n bool operator==(const ModInt& p) const { return x == p.x; }\n bool operator!=(const ModInt& p) const { return x != p.x; }\n\n ModInt inverse() const {\n int a = x, b = modulo, u = 1, v = 0, t;\n while (b > 0) {\n t = a / b;\n a -= t * b;\n swap(a, b);\n u -= t * v;\n swap(u, v);\n }\n return ModInt(u);\n }\n\n ModInt pow(ll e) {\n ll a = 1, p = x;\n while (e > 0) {\n if (e % 2 == 0) {\n p = (p * p) % modulo;\n e /= 2;\n }\n else {\n a = (a * p) % modulo;\n e--;\n }\n }\n return ModInt(a);\n }\n\n friend ostream& operator<<(ostream& os, const ModInt<modulo>& p) {\n return os << p.x;\n }\n friend istream& operator>>(istream& is, ModInt<modulo>& a) {\n ll x;\n is >> x;\n a = ModInt<modulo>(x);\n return (is);\n }\n};\nusing modint = ModInt<mod>;\n\ntemplate<class Op> class SegmentTree {\n\tusing T = typename Op::T;\n\tint len, n;\n\tvector<T> dat;\n T unit = Op::unit;\npublic:\n\tSegmentTree(const int _n) : n(_n) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t}\n\tSegmentTree(const vector<T>& v) : n(v.size()) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t\tfor (int i = 0; i < n; ++i)dat[i + len] = v[i];\n\t\tfor (int i = len - 1; 0 < i; --i)\n\t\t\tdat[i] = Op::merge(dat[i << 1], dat[i << 1 | 1]);\n\t}\n\tinline void update(int idx, const T a) {\n\t\tidx += len;\n\t\tdat[idx] = Op::update(dat[idx], a);\n\t\tfor (idx >>= 1; 0 < idx; idx >>= 1)\n\t\t\tdat[idx] = Op::merge(dat[idx << 1], dat[idx << 1 | 1]);\n\t}\n\tinline T value(int l, int r) {\n\t\tT vl = unit, vr = unit;\n\t\tfor (l += len, r += len; l < r; l >>= 1, r >>= 1) {\n\t\t\tif (l & 1)vl = Op::merge(vl, dat[l++]);\n\t\t\tif (r & 1)vr = Op::merge(dat[--r], vr);\n\t\t}\n\t\treturn Op::merge(vl, vr);\n\t}\n\tinline T operator[](int idx) { return dat[idx + len]; }\n};\ntemplate<class Type> struct modintSumAddUpdate {\n\tusing T = Type;\n const static T unit = 0;\n inline static T merge(T vl, T vr) { return (vl + vr) % mod; }\n inline static T update(T vl, T vr) { return (vl + vr) % mod; }\n};\n\nint main() {\n init();\n\n int n, m; cin >> n >> m;\n vector<SegmentTree<modintSumAddUpdate<ll>>> dp;\n dp.emplace_back(n + 2);\n dp.emplace_back(n + 2);\n dp[0].update(0, 1);\n eFOR(i, 1, n + 1) {\n if (m + 1 <= i)dp[1].update(i, dp[0].value(0, i - m));\n dp[0].update(i, dp[0].value(max(0, i - m), i));\n dp[1].update(i, dp[1].value(0, i));\n }\n print(dp[1][n + 1]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7056, "score_of_the_acc": -0.7026, "final_rank": 4 }, { "submission_id": "aoj_0398_4823588", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\ntemplate<class T> using PQ = priority_queue<T, vector<T>, greater<T>>;\n#define FOR(i,a,n) for(int i=(a);i<(n);++i)\n#define eFOR(i,a,n) for(int i=(a);i<=(n);++i)\n#define rFOR(i,a,n) for(int i=(n)-1;i>=(a);--i)\n#define erFOR(i,a,n) for(int i=(n);i>=(a);--i)\n#define each(i, a) for(auto &i : a)\n#define SORT(a) sort(a.begin(),a.end())\n#define rSORT(a) sort(a.rbegin(),a.rend())\n#define fSORT(a,f) sort(a.begin(),a.end(),f)\n#define all(a) a.begin(),a.end()\n#define out(y,x) ((y)<0||h<=(y)||(x)<0||w<=(x))\n#define tp(a,i) get<i>(a)\n#define line cout << \"-----------------------------\\n\" \n#define ENDL(i,n) ((i) == (n) - 1 ? \"\\n\" : \" \")\n#define elif else if\nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr ld eps = 1e-10;\nconstexpr ld pi = 3.1415926535897932;\ntemplate<class T>inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }\ntemplate<class T>inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& is, vector<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T>inline istream& operator>>(istream& is, deque<T>& v) { for (auto& a : v)is >> a; return is; }\ntemplate<class T, class U>inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }\ntemplate<class T>inline vector<T> vec(size_t a) { return vector<T>(a); }\ntemplate<class T>inline vector<T> defvec(T def, size_t a) { return vector<T>(a, def); }\ntemplate<class T, class... Ts>inline auto vec(size_t a, Ts... ts) { return vector<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }\ntemplate<class T, class... Ts>inline auto defvec(T def, size_t a, Ts... ts) { return vector<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }\ntemplate<class T>inline void print(const T& a) { cout << a << \"\\n\"; }\ntemplate<class T, class... Ts>inline void print(const T& a, const Ts&... ts) { cout << a << \" \"; print(ts...); }\ntemplate<class T>inline void print(const vector<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? \"\\n\" : \" \"); }\ntemplate<class T>inline void print(const vector<vector<T>>& v) { for (auto& a : v)print(a); }\ninline string reversed(const string& s) { string t = s; reverse(all(t)); return t; }\n\ntemplate<int modulo> struct ModInt {\n int x;\n\n ModInt() : x(0) {}\n ModInt(ll y) : x(y >= 0 ? y % modulo : (modulo - (-y) % modulo) % modulo) {}\n\n ModInt& operator+=(const ModInt& p) {\n if ((x += p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator-=(const ModInt& p) {\n if ((x += modulo - p.x) >= modulo) x -= modulo;\n return *this;\n }\n ModInt& operator*=(const ModInt& p) {\n x = (int)(1LL * x * p.x % modulo);\n return *this;\n }\n ModInt& operator/=(const ModInt& p) {\n *this *= p.inverse();\n return *this;\n }\n\n ModInt operator-() const { return ModInt(-x); }\n ModInt operator+(const ModInt& p) const { return ModInt(*this) += p; }\n ModInt operator-(const ModInt& p) const { return ModInt(*this) -= p; }\n ModInt operator*(const ModInt& p) const { return ModInt(*this) *= p; }\n ModInt operator/(const ModInt& p) const { return ModInt(*this) /= p; }\n\n bool operator==(const ModInt& p) const { return x == p.x; }\n bool operator!=(const ModInt& p) const { return x != p.x; }\n\n ModInt inverse() const {\n int a = x, b = modulo, u = 1, v = 0, t;\n while (b > 0) {\n t = a / b;\n a -= t * b;\n swap(a, b);\n u -= t * v;\n swap(u, v);\n }\n return ModInt(u);\n }\n\n ModInt pow(ll e) {\n ll a = 1, p = x;\n while (e > 0) {\n if (e % 2 == 0) {\n p = (p * p) % modulo;\n e /= 2;\n }\n else {\n a = (a * p) % modulo;\n e--;\n }\n }\n return ModInt(a);\n }\n\n friend ostream& operator<<(ostream& os, const ModInt<modulo>& p) {\n return os << p.x;\n }\n friend istream& operator>>(istream& is, ModInt<modulo>& a) {\n ll x;\n is >> x;\n a = ModInt<modulo>(x);\n return (is);\n }\n};\nusing modint = ModInt<mod>;\n\ntemplate<class Op> class SegmentTree {\n\tusing T = typename Op::T;\n\tint len, n;\n\tvector<T> dat;\n T unit = Op::unit;\npublic:\n\tSegmentTree(const int _n) : n(_n) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t}\n\tSegmentTree(const vector<T>& v) : n(v.size()) {\n\t\tfor (len = 1; len < n; len <<= 1);\n\t\tdat.resize(len << 1, unit);\n\t\tfor (int i = 0; i < n; ++i)dat[i + len] = v[i];\n\t\tfor (int i = len - 1; 0 < i; --i)\n\t\t\tdat[i] = Op::merge(dat[i << 1], dat[i << 1 | 1]);\n\t}\n\tinline void update(int idx, const T a) {\n\t\tidx += len;\n\t\tdat[idx] = Op::update(dat[idx], a);\n\t\tfor (idx >>= 1; 0 < idx; idx >>= 1)\n\t\t\tdat[idx] = Op::merge(dat[idx << 1], dat[idx << 1 | 1]);\n\t}\n\tinline T value(int l, int r) {\n\t\tT vl = unit, vr = unit;\n\t\tfor (l += len, r += len; l < r; l >>= 1, r >>= 1) {\n\t\t\tif (l & 1)vl = Op::merge(vl, dat[l++]);\n\t\t\tif (r & 1)vr = Op::merge(dat[--r], vr);\n\t\t}\n\t\treturn Op::merge(vl, vr);\n\t}\n\tinline T operator[](int idx) { return dat[idx + len]; }\n};\ntemplate<class Type> struct modintSumAddUpdate {\n\tusing T = Type;\n const static T unit = 0;\n inline static T merge(T vl, T vr) { return (vl + vr) % mod; }\n inline static T update(T vl, T vr) { return (vl + vr) % mod; }\n};\n\nint main() {\n init();\n\n int n, m; cin >> n >> m;\n vector<SegmentTree<modintSumAddUpdate<ll>>> dp;\n dp.emplace_back(n + 2);\n dp.emplace_back(n + 2);\n dp[0].update(0, 1);\n eFOR(i, 1, n + 1) {\n if (m + 1 <= i)dp[1].update(i, dp[0].value(0, i - m));\n dp[0].update(i, dp[0].value(i - m, i));\n dp[1].update(i, dp[1].value(0, i));\n }\n print(dp[1][n + 1]);\n\n return 0;\n}", "accuracy": 0.8, "time_ms": 30, "memory_kb": 7080, "score_of_the_acc": -0.7057, "final_rank": 8 }, { "submission_id": "aoj_0398_3755088", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<map>\nusing namespace std;\ntypedef long long ll;\nconst ll mod=1e9+7;\nll dp0[100005]={0};\nll pow(ll x,ll y){\n if(y==0) return 1;\n ll ret=pow(x,y/2);\n ret*=ret;\n ret%=mod;\n if(y%2==1) ret*=x;\n return ret%mod;\n}\nconst ll g2=pow(2,mod-2);\nstruct segtree{\nprivate:\n vector<ll> node,lazy;\n ll siz;\npublic:\n segtree(int n){\n siz=1;\n while(siz<=n) siz*=2;\n node.resize(siz*2,0);\n lazy.resize(siz*2,0);\n }\n void eval(ll pos){\n node[pos]+=lazy[pos];\n node[pos]%=mod;\n if(pos<siz-1) {\n lazy[pos*2+1]+=lazy[pos]/2;\n lazy[pos*2+2]+=lazy[pos]/2;\n // lazy[pos*2+1]%=mod;\n // lazy[pos*2+2]%=mod;\n }\n lazy[pos]=0;\n }\n void add_q(ll a,ll b,ll x,ll l,ll r,ll pos){\n eval(pos);\n if(b<=l||r<=a) return;\n if(a<=l&&r<=b){\n lazy[pos]+=(x*(r-l));\n eval(pos);\n return;\n }\n ll mid=(l+r)/2;\n add_q(a,b,x,l,mid,pos*2+1);\n add_q(a,b,x,mid,r,pos*2+2);\n node[pos]=(node[pos*2+1]+node[pos*2+2])%mod;\n }\n ll sum_q(ll a,ll b,ll l,ll r,ll pos){\n if(b<=l||r<=a) return 0;\n eval(pos);\n if(a<=l&&r<=b){\n return node[pos]%mod;\n }\n ll mid=(l+r)/2;\n return (sum_q(a,b,l,mid,pos*2+1)+sum_q(a,b,mid,r,pos*2+2))%mod;\n }\n void add(ll a,ll b,ll x){\n add_q(max((ll)0,a),min(b,siz),x,0,siz,0);\n }\n ll sum(ll a,ll b){\n return sum_q(max((ll)0,a),min(b,siz),0,siz,0);\n }\n void debug(){\n cout<<\"Node:\"<<endl;\n ll t=2;\n for(int i=2;i<=siz*2;i++) {\n cout<<node[i-2]<<\" \";\n if(i==t){\n t*=2;\n cout<<endl;\n }\n }\n cout<<\"Lazy:\"<<endl;\n t=2;\n for(int i=2;i<=siz*2;i++){\n cout<<lazy[i-2]<<\" \";\n if(i==t){\n t*=2;\n cout<<endl;\n }\n }\n }\n};\nint main(){\n ll n,m;\n cin>>n>>m;\n segtree dp1=segtree(n+3);\n dp0[0]=1;\n for(int i=0;i<n;i++){\n dp1.add(i+1,min(n+1,i+m),dp0[i]);\n dp0[i+1]=dp0[i]+dp1.sum(i,i+1);\n dp0[i+1]%=mod;\n }\n/* for(int i=0;i<=n;i++) cout<<dp0[i]<<\" \";\n cout<<endl;\n for(int i=0;i<=n;i++) cout<<dp1.sum(i,i+1)<<\" \";\n cout<<endl;*/\n ll ans=pow(2,n);\n //cout<<ans<<endl;\n ans-=(dp0[n]+dp1.sum(n,n+1));\n if(ans<0){\n ll t=(0-ans)/mod;\n ans+=(t+1)*mod;\n }\n cout<<ans%mod<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 7860, "score_of_the_acc": -1.1829, "final_rank": 6 } ]
aoj_0391_cpp
Meeting in a City You are a teacher at Iazu High School is the Zuia Kingdom. There are $N$ cities and $N-1$ roads connecting them that allow you to move from one city to another by way of more than one road. Each of the roads allows bidirectional traffic and has a known length. As a part of class activities, you are planning the following action assignment for your students. First, you come up with several themes commonly applicable to three different cities. Second, you assign each of the themes to a group of three students. Then, each student of a group is assigned to one of the three cities and conducts a survey on it. Finally, all students of the group get together in one of the $N$ cities and compile their results. After a theme group has completed its survey, the three members move from the city on which they studied to the city for getting together. The longest distance they have to travel for getting together is defined as the cost of the theme. You want to select the meeting city so that the cost for each theme becomes minimum. Given the number of cities, road information and $Q$ sets of three cities for each theme, make a program to work out the minimum cost for each theme. Input The input is given in the following format. $N$ $Q$ $u_1$ $v_1$ $w_1$ $u_2$ $v_2$ $w_2$ $...$ $u_{N-1}$ $v_{N-1}$ $w_{N-1}$ $a_1$ $b_1$ $c_1$ $a_2$ $b_2$ $c_2$ $...$ $a_Q$ $b_Q$ $c_Q$ The first line provides the number of cities in the Zuia Kingdom $N$ ($3 \leq N \leq 100,000$) and the number of themes $Q$ ($1 \leq Q \leq 100,000$). Each of the subsequent $N-1$ lines provides the information regarding the $i$-th road $u_i,v_i,w_i$ ($ 1 \leq u_i < v_i \leq N, 1 \leq w_i \leq 10,000$), indicating that the road connects cities $u_i$ and $v_i$, and the road distance between the two is $w_i$. Each of the $Q$ lines that follows the above provides the three cities assigned to the $i$-th theme: $a_i,b_i,c_i$ ($1 \leq a_i < b_i < c_i \leq N$). Output For each theme, output the cost in one line. Sample Input 1 5 4 1 2 3 2 3 4 2 4 2 4 5 3 1 3 4 1 4 5 1 2 3 2 4 5 Sample Output 1 4 5 4 3 In the first theme, traveling distance from City 3 (the student conducts survey) to City 2 (meeting venue) determines the cost 4. As no other meeting city can provide smaller cost, you should output 4. In the second theme, you can minimize the cost down to 5 by selecting City 2 or City 4 as the meeting venue. Sample Input 2 5 3 1 2 1 2 3 1 3 4 1 4 5 1 1 2 3 1 3 5 1 2 4 Sample Output 2 1 2 2 Sample Input 3 15 15 1 2 45 2 3 81 1 4 29 1 5 2 5 6 25 4 7 84 7 8 56 4 9 2 4 10 37 7 11 39 1 12 11 11 13 6 3 14 68 2 15 16 10 13 14 13 14 15 2 14 15 7 12 15 10 14 15 9 10 15 9 14 15 8 13 15 5 6 13 11 13 15 12 13 14 2 3 10 5 13 15 10 11 14 6 8 11 Sample Output 3 194 194 97 90 149 66 149 140 129 129 194 111 129 194 140
[ { "submission_id": "aoj_0391_10875318", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nstruct SEG{\nprivate:\n int n;\n vector<int> node;\npublic:\n SEG(int N){\n n = 1;\n while(n < N) n *= 2;\n node.resize(2*n-1);\n }\n void update(int i, int x){\n i += n-1;\n node[i] = x;\n while(i){\n i = (i-1)/2;\n node[i] = node[2*i+1]+node[2*i+2];\n }\n }\n int f(int a, int b, int k = 0, int l = 0, int r = -1){\n if(r < 0) r = n;\n if(a <= l && r <= b) return node[k];\n if(b <= l || r <= a) return 0;\n return f(a,b,2*k+1,l,(l+r)/2)+f(a,b,2*k+2,(l+r)/2,r);\n }\n};\nsigned main(){\n int N,Q;\n cin>>N>>Q;\n vector<vector<pair<int,int>>> G(N);\n for(int i=0;i<N-1;i++){\n int a,b,c;\n cin>>a>>b>>c;\n a--;\n b--;\n G[a].push_back({b,c});\n G[b].push_back({a,c});\n }\n int n = 17;\n vector<vector<int>> P(n,vector<int>(N,-1));\n vector<vector<int>> D(n,vector<int>(N));\n vector<int> dist(N,1e18), dt(N);\n {\n queue<int> q;\n q.push(0);\n dist[0] = 0;\n while(!q.empty()){\n int pos = q.front();\n q.pop();\n for(auto [x,w]:G[pos])if(dist[x] >= 1e17){\n dist[x] = dist[pos] + w;\n dt[x] = dt[pos] + 1;\n q.push(x);\n }\n }\n for(int i=0;i<N;i++)for(auto [x,w]:G[i])if(dist[x] < dist[i]){\n P[0][i] = x;\n D[0][i] = w;\n }\n }\n for(int i=1;i<n;i++)for(int j=0;j<N;j++)if(P[i-1][j] != -1){\n P[i][j] = P[i-1][P[i-1][j]];\n D[i][j] = D[i-1][j]+D[i-1][P[i-1][j]];\n }\n auto lca = [&](int a, int b) -> int {\n if(dt[a] < dt[b]) swap(a,b);\n int k = dt[a]-dt[b];\n for(int i=0;i<n;i++)if(k&(1<<i)) a = P[i][a];\n if(a == b) return a;\n for(int i=n-1;i>=0;i--)if(P[i][a] != -1 && P[i][b] != -1 && P[i][a] != P[i][b]){\n a = P[i][a];\n b = P[i][b];\n }\n return P[0][a];\n };\n auto d = [&](int a, int b) -> int {\n int p = lca(a,b);\n return dist[a]+dist[b]-2*dist[p];\n };\n while(Q--){\n int a,b,c;\n cin>>a>>b>>c;\n a--;\n b--;\n c--;\n if(dt[a] < dt[b]) swap(a,b);\n if(dt[b] < dt[c]) swap(b,c);\n if(dt[a] < dt[b]) swap(a,b);\n if(dt[b] < dt[c]) swap(b,c);\n int t = 0;\n {\n int aa = lca(a,b);\n int bb = lca(b,c);\n int cc = lca(c,a);\n if(dt[aa] == max({dt[aa],dt[bb],dt[cc]})) t = aa;\n if(dt[bb] == max({dt[aa],dt[bb],dt[cc]})) t = bb;\n if(dt[cc] == max({dt[aa],dt[bb],dt[cc]})) t = cc;\n }\n if(d(a,t) < d(b,t)) swap(a,b);\n if(d(b,t) < d(c,t)) swap(b,c);\n if(d(a,t) < d(b,t)) swap(a,b);\n if(d(b,t) < d(c,t)) swap(b,c);\n // t -> a\n int s = lca(t,a);\n int aa = d(a,s), bb = d(s,t);\n int ans = d(a,t);\n int bt = (aa+bb+d(b,t)+1)/2;\n {\n int now = 0;\n int j = a;\n for(int i=n-1;i>=0;i--)if(now+D[i][j] <= bt && dt[j]-(1<<i) >= dt[s] && P[i][j] != -1){\n now += D[i][j];\n j = P[i][j];\n }\n ans = min(ans,max({d(a,j),d(b,j)}));\n if(j == s && t != s){\n int k = dt[t]-dt[s]-1;\n int wt = t;\n for(int i=0;i<n;i++)if(k&(1<<i)) wt = P[i][wt];\n j = wt;\n }\n else if(j != 0) j = P[0][j];\n ans = min(ans,max({d(a,j),d(b,j)}));\n }\n bt = aa+bb-(aa+bb+d(b,t)+1)/2;\n {\n int now = 0;\n int j = t;\n for(int i=n-1;i>=0;i--)if(now+D[i][j] <= bt && dt[j]-(1<<i) >= dt[s] && P[i][j] != -1){\n now += D[i][j];\n j = P[i][j];\n }\n ans = min(ans,max({d(a,j),d(b,j)}));\n if(j == s && t != s){\n int k = dt[a]-dt[s]-1;\n int wt = a;\n for(int i=0;i<n;i++)if(k&(1<<i)) wt = P[i][wt];\n j = wt;\n }\n else if(j != 0) j = P[0][j];\n ans = min(ans,max({d(a,j),d(b,j)}));\n }\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 520, "memory_kb": 38484, "score_of_the_acc": -0.9376, "final_rank": 12 }, { "submission_id": "aoj_0391_10875148", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); ++i)\n#define rrep(i, n) for (int i = (int)(n) - 1; i >= 0; --i)\n#define rrep2(i, a, b) for (int i = (int)(b) - 1; i >= (int)(a); --i)\n\n#define all(v) begin(v), end(v)\n#define rall(v) rbegin(v), rend(v)\n\nusing namespace std;\n\nusing ll = long long;\nusing PLL = pair<ll, ll>;\n\ntemplate<class T, class U> bool chmin(T& a, const U& b) { return a > b ? a = b, true : false; }\ntemplate<class T, class U> bool chmax(T& a, const U& b) { return a < b ? a = b, true : false; }\n\nstruct edge {\n int to;\n ll cost;\n edge(int t, ll c) : to(t), cost(c) {}\n};\n\nusing Graph = vector<vector<edge>>;\n\nclass TreeQuery {\n int n;\n Graph G;\n\n vector<ll> dep, rank;\n vector<vector<int>> par;\n\npublic:\n TreeQuery(Graph H) : n(H.size()), G(H) {\n dep.assign(n, 0);\n rank.assign(n, 0);\n par.assign(20, vector<int>(n, -1));\n auto dfs = [&](auto&& self, int v, int p) -> void {\n par[0][v] = p;\n for (auto e : G[v]) if (e.to != p) {\n dep[e.to] = dep[v] + e.cost;\n rank[e.to] = rank[v] + 1;\n self(self, e.to, v);\n }\n };\n dfs(dfs, 0, -1);\n rep (i, 19) rep (j, n) par[i + 1][j] = par[i][j] == -1 ? -1 : par[i][par[i][j]];\n }\n int kth_ancestor(int a, int k) const {\n rep (i, 20) if (k >> i & 1) a = par[i][a];\n return a;\n }\n int lca(int a, int b) const {\n if (rank[a] > rank[b]) swap(a, b);\n b = kth_ancestor(b, rank[b] - rank[a]);\n if (a == b) return a;\n rrep (i, 20) {\n if (par[i][a] != par[i][b]) {\n a = par[i][a];\n b = par[i][b];\n }\n }\n return par[0][a];\n }\n int kth_next(int a, int b, int k) const {\n int l = lca(a, b);\n if (rank[a] - rank[l] >= k) return kth_ancestor(a, k);\n return kth_ancestor(b, (rank[a] + rank[b] - 2 * rank[l]) - k);\n }\n ll dist(int a, int b) const { return dep[a] + dep[b] - 2 * dep[lca(a, b)]; }\n int dist_r(int a, int b) const { return rank[a] + rank[b] - 2 * rank[lca(a, b)]; }\n};\n\nint main() {\n int N, Q; scanf(\"%d%d\", &N, &Q);\n Graph G(N);\n rep (_, N - 1) {\n int a, b;\n ll c;\n scanf(\"%d%d%lld\", &a, &b, &c);\n --a; --b;\n G[a].emplace_back(b, c);\n G[b].emplace_back(a, c);\n }\n TreeQuery T(G);\n rep (_, Q) {\n int a, b, c; scanf(\"%d%d%d\", &a, &b, &c);\n --a; --b; --c;\n int x = T.lca(a, b) ^ T.lca(b, c) ^ T.lca(c, a);\n ll da = T.dist(a, x), db = T.dist(b, x), dc = T.dist(c, x);\n {\n ll m = max({da, db, dc});\n if (m == da) ;\n else if (m == db) {\n swap(a, b);\n swap(da, db);\n }\n else {\n swap(a, c);\n swap(da, dc);\n }\n }\n ll dbc = max(db, dc);\n auto calc = [&](int v) -> ll {\n return max(T.dist(a, v), T.dist(x, v) + dbc);\n };\n int ok = 0, ng = T.dist_r(x, a) + 1;\n while (ng - ok > 1) {\n int mid = (ok + ng) / 2;\n int v = T.kth_next(x, a, mid);\n int nv = T.kth_next(x, a, mid - 1);\n if (calc(v) <= calc(nv)) ok = mid;\n else ng = mid;\n }\n int v = T.kth_next(x, a, ok);\n printf(\"%lld\\n\", calc(v));\n }\n}", "accuracy": 1, "time_ms": 750, "memory_kb": 41288, "score_of_the_acc": -1.2007, "final_rank": 16 }, { "submission_id": "aoj_0391_10871617", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ld=long double;\n#define fi first\n#define se second\n#define i128 __int128_t\n#define all(x) x.begin(),x.end()\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define si(a) (long)(a.size())\ntemplate<typename T>bool chmin(T&a,T b){return b<a?(a=b,1):0;}\ntemplate<typename T>bool chmax(T&a,T b){return b>a?(a=b,1):0;}\nconst int INF=1e9+100;\nconst long INFL=3e18+100;\nstruct _ {\n _() { cin.tie(0)->sync_with_stdio(0), cout.tie(0); }\n} __;\n\n\n\nstruct LCA {\n int N;\n vector<vector<pair<int,int>>> G;\n vector<vector<int>> P;\n vector<int> dep,W;\n LCA(vector<vector<pair<int,int>>> G_, int root = 0) : N(si(G_)), G(G_), dep(si(G_)), W(si(G_)){\n int lg = 0;\n while ((1 << lg) + 1 < N) lg++;\n P.assign(lg + 1, vector<int>(N));\n\n dfs(root, -1, 0, 0);\n for (int k = 1; k < si(P); k++) {\n rep(i, N) {\n if (P[k - 1][i] == -1)\n P[k][i] = -1;\n else\n P[k][i] = P[k - 1][P[k - 1][i]];\n }\n }\n }\n void dfs(int u, int p, int d, int w) {\n W[u]=w;\n dep[u] = d;\n P[0][u] = p;\n for (auto [v,c] : G[u])\n if (v != p) dfs(v, u, d + 1, w+c);\n }\n int lca(int u, int v) {\n if (dep[u] > dep[v]) swap(u, v);\n rep(k, si(P)) if ((dep[v] - dep[u]) >> k & 1) v = P[k][v];\n if (u == v) return u;\n for (int k = si(P); k--;)\n if (P[k][u] != P[k][v]) {\n u = P[k][u];\n v = P[k][v];\n }\n return P[0][u];\n }\n \n int hist(int u, int v) {\n int w = lca(u, v);\n return dep[u] + dep[v] - 2 * dep[w];\n }\n\n int dist(int u, int v) {\n int w = lca(u, v);\n return W[u] + W[v] - 2 * W[w];\n }\n};\n\n\nint main(){\n int N,Q;\n cin>>N>>Q;\n vector<vector<pair<int,int>>> G(N);\n rep(i,N-1){\n int u,v,w;cin>>u>>v>>w;\n u--;v--;\n G[u].push_back({v,w});\n G[v].push_back({u,w});\n }\n LCA lca(G);\n \n vector<vector<pair<int,int>>> A(N);\n auto f=[&](int u, int v, int id)->void {\n int l=lca.lca(u,v);\n if(lca.dist(u,l)<lca.dist(v,l)) swap(u,v);\n A[u].push_back({lca.dist(u,v),id});\n\n return ;\n };\n rep(i,Q){\n int a,b,c;\n cin>>a>>b>>c;\n a--;b--;c--;\n f(a,b,i);f(a,c,i);f(b,c,i);\n }\n vector<int> ans(Q,0);\n vector<int> now={-1};\n vector<int> nov;\n auto dfs=[&](auto dfs, int v, int p, int w)->void {\n now.push_back(w);\n nov.push_back(v);\n for(auto [x, qi]: A[v]){\n int id=si(nov)-(now.end()-lower_bound(all(now), w-x/2));\n int mi=1e9;\n rep(z,2){\n if(id<0) continue;\n int d=lca.dist(v, nov[id]);\n chmin(mi, max(d, x-d));\n id--;\n }\n chmax(ans[qi], mi);\n\n }\n for(auto [e,c]: G[v]){\n if(e==p) continue;\n dfs(dfs, e, v, w+c);\n }\n nov.pop_back();\n now.pop_back();\n };\n dfs(dfs, 0, -1, 0);\n\n rep(i,Q)cout<<ans[i]<<\"\\n\";\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 53964, "score_of_the_acc": -1.1626, "final_rank": 14 }, { "submission_id": "aoj_0391_10204895", "code_snippet": "// AOJ #391\n// Gathering 2025.2.8\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint Cin() { // 整数の入力\n\tint n = 0, c = gc();\n\tif (c == '-') {\tc = gc();\n\t\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\t\treturn -n;\n\t}\n\tdo n = 10*n + (c & 0xf), c = gc(); while (c >= '0');\n\treturn n;\n}\n\nvoid Cout(ll n) { // 整数の表示(出力)\n\tchar b[30];\n\tif (!n) pc('0');\n\telse {\n\t\tif (n < 0) pc('-'), n = -n;\n\t\tint i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n\t\twhile (i--) pc(b[i]);\n\t}\n\tpc('\\n');\n}\n\nconst int NMAX = 100000;\nint N, Q;\n \nvector<pair<int,int>> adj[NMAX+1];\n \nint depth[NMAX+1];\nll distArr[NMAX+1];\n \nint LOGN;\nint parent[18][NMAX+1];\n \nvoid computeTreeData(int root = 1) {\n memset(depth, 0, sizeof(depth));\n for (int i=1; i<=N; i++){\n distArr[i] = 0;\n parent[0][i] = 0;\n }\n vector<int> st;\n st.push_back(root);\n depth[root] = 0;\n distArr[root] = 0;\n while(!st.empty()){\n int u = st.back();\n st.pop_back();\n for(auto &edge : adj[u]){\n int v = edge.first;\n int w = edge.second;\n if(v == parent[0][u]) continue;\n parent[0][v] = u;\n depth[v] = depth[u] + 1;\n distArr[v] = distArr[u] + w;\n st.push_back(v);\n }\n }\n}\n \nvoid computeParents(){\n LOGN = 0;\n while((1 << LOGN) <= N) LOGN++;\n for (int i = 1; i < LOGN; i++){\n for (int v = 1; v <= N; v++){\n int par = parent[i-1][v];\n if(par == 0) parent[i][v] = 0;\n else parent[i][v] = parent[i-1][par];\n }\n }\n}\n \nint LCA(int u, int v) {\n if(depth[u] < depth[v]) swap(u,v);\n int d = depth[u] - depth[v];\n for(int i = 0; i < LOGN; i++){\n if(d & (1 << i)){\n u = parent[i][u];\n }\n }\n if(u == v) return u;\n for(int i = LOGN-1; i >= 0; i--){\n if(parent[i][u] != parent[i][v]){\n u = parent[i][u];\n v = parent[i][v];\n }\n }\n return parent[0][u];\n}\n \nll getDist(int u, int v) {\n int l = LCA(u,v);\n return distArr[u] + distArr[v] - 2LL * distArr[l];\n}\n \nint kthAncestor(int u, int k) {\n for (int i = 0; i < LOGN; i++){\n if(k & (1 << i)){\n u = parent[i][u];\n if(u == 0) break;\n }\n }\n return u;\n}\n \nint getKthOnPath(int u, int v, int k) {\n int l = LCA(u,v);\n int d1 = depth[u] - depth[l];\n if(k <= d1){\n return kthAncestor(u, k);\n } else {\n int k2 = k - d1;\n int d2 = depth[v] - depth[l];\n return kthAncestor(v, d2 - k2);\n }\n}\n \n \nll solveForTripleOnDiameter(int p, int q, int r) {\n int L = depth[p] + depth[q] - 2 * depth[LCA(p,q)];\n ll d_pq = getDist(p, q);\n auto F = [&](int k) -> ll {\n int x = getKthOnPath(p, q, k);\n ll A = getDist(p, x);\n ll B = d_pq - A;\n ll C = getDist(x, r);\n return max({A, B, C});\n };\n if(L == 0) return F(0);\n int lo = 0, hi = L;\n while(hi - lo > 3) {\n int m1 = lo + (hi - lo) / 3;\n int m2 = hi - (hi - lo) / 3;\n ll f1 = F(m1), f2 = F(m2);\n if(f1 > f2)\n lo = m1;\n else\n hi = m2;\n }\n ll ans = LLONG_MAX;\n for (int k = lo; k <= hi; k++){\n ans = min(ans, F(k));\n }\n return ans;\n}\n \n \nint main() {\n N = Cin(), Q = Cin();\n for (int i = 1; i <= N; i++){\n adj[i].clear();\n }\n for (int i = 1; i < N; i++){\n int u = Cin(), v = Cin(), w = Cin();\n adj[u].push_back({v, w});\n adj[v].push_back({u, w});\n }\n \n computeTreeData(1);\n computeParents();\n \n for (int i = 0; i < Q; i++){\n int a = Cin(), b = Cin(), c = Cin();\n ll dab = getDist(a, b);\n ll dac = getDist(a, c);\n ll dbc = getDist(b, c);\n \n int p, q, r;\n if(dab >= dac && dab >= dbc){\n p = a; q = b; r = c;\n } else if(dac >= dab && dac >= dbc){\n p = a; q = c; r = b;\n } else {\n p = b; q = c; r = a;\n }\n \n ll ans = solveForTripleOnDiameter(p, q, r);\n Cout(ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 17572, "score_of_the_acc": -0.6872, "final_rank": 6 }, { "submission_id": "aoj_0391_9572020", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct virtualtree{\n\tlong long n;\n\tvector<vector<long long>> g,p;\n\tvector<long long> o,d;\n\tlong long cou = 0ll;\n\tvirtualtree(vector<vector<long long>> g) : g(g), n(g.size()) {\n\t\to.resize(n,-1ll);\n\t\tp.resize(n);\n\t\td.resize(n);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tp[i].resize(20ll);\n\t\t}\n\t\td[0ll] = 0ll;\n\t\tp[0ll][0ll] = 0ll;\n\t\tdfs(0ll);\n\t\tfor(long long i = 1ll;i < 20ll;i++){\n\t\t\tfor(long long j = 0ll;j < n;j++){\n\t\t\t\tp[j][i] = p[p[j][i - 1ll]][i - 1ll];\n\t\t\t}\n\t\t}\n\t}\n\tvoid dfs(long long x){\n\t\to[x] = cou;\n\t\tcou++;\n\t\tfor(long long i : g[x]){\n\t\t\tif(o[i] != -1ll){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tp[i][0ll] = x;\n\t\t\td[i] = d[x] + 1ll;\n\t\t\tdfs(i);\n\t\t}\n\t}\n\tlong long root(long long a,long long b){\n\t\tfor(long long i = 0ll;i < 30ll;i++){\n\t\t\tif(b & (1ll << i)){\n\t\t\t\ta = p[a][i];\n\t\t\t}\n\t\t}\n\t\treturn a;\n\t}\n\tlong long lca(long long u,long long v){\n\t\tif(d[u] > d[v]){\n\t\t\tu = root(u,d[u] - d[v]);\n\t\t}\n\t\tif(d[v] > d[u]){\n\t\t\tv = root(v,d[v] - d[u]);\n\t\t}\n\t\tlong long low = 0ll,high = n;\n\t\twhile(low < high){\n\t\t\tlong long mid = (low + high) / 2ll;\n\t\t\tif(root(u,mid) == root(v,mid)){\n\t\t\t\thigh = mid;\n\t\t\t}else{\n\t\t\t\tlow = mid + 1ll;\n\t\t\t}\n\t\t}\n\t\treturn root(u,low);\n\t}\n\tlong long dist(long long u,long long v){\n\t\tlong long lc = lca(u,v);\n\t\treturn d[u] + d[v] - d[lc] * 2ll;\n\t}\n\tvector<vector<pair<long long,long long>>> get(vector<long long> x){\n\t\tvector<vector<pair<long long,long long>>> res(x.size(),vector<pair<long long,long long>>());\n\t\tauto com = [&](long long a,long long b) -> bool {\n\t\t\treturn o[a] < o[b];\n\t\t};\n\t\tmap<long long,long long> t;\n\t\tset<long long> c;\n\t\tsort(x.begin(),x.end(),com);\n\t\tfor(long long i = 0ll;i < (long long)x.size();i++){\n\t\t\tc.insert(x[i]);\n\t\t\tt[x[i]] = i;\n\t\t}\n\t\tx.push_back(x[0ll]);\n\t\tstack<long long> s;\n\t\ts.push(x[0ll]);\n\t\tfor(long long i = 1ll;i < (long long)x.size();i++){\n\t\t\tlong long lc = lca(x[i - 1ll],x[i]);\n\t\t\tif(!c.count(lc)){\n\t\t\t\tt[lc] = (long long)c.size();\n\t\t\t\tc.insert(lc);\n\t\t\t\tres.push_back({});\n\t\t\t}\n\t\t\tlong long last = -1ll;\n\t\t\twhile(!s.empty() && d[s.top()] >= d[lc]){\n\t\t\t\tlong long it = s.top();\n\t\t\t\ts.pop();\n\t\t\t\tif(last != -1ll && last != it){\n\t\t\t\t\tres[t[it]].push_back({t[last],dist(it,last)});\n\t\t\t\t\tres[t[last]].push_back({t[it],dist(it,last)});\n\t\t\t\t}\n\t\t\t\tlast = it;\n\t\t\t}\n\t\t\tif(last != -1ll && last != lc){\n\t\t\t\tres[t[last]].push_back({t[lc],dist(last,lc)});\n\t\t\t\tres[t[lc]].push_back({t[last],dist(last,lc)});\n\t\t\t}\n\t\t\ts.push(lc);\n\t\t\ts.push(x[i]);\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tlong long n,Q;\n\tcin >> n >> Q;\n\tvector<vector<long long>> gh(n,vector<long long>());\n\tvector<vector<pair<long long,long long>>> g(n,vector<pair<long long,long long>>());\n\tfor(long long i = 0ll;i < n - 1ll;i++){\n\t\tlong long u,v,w;\n\t\tcin >> u >> v >> w;\n\t\tu--;v--;\n\t\tgh[u].push_back(v);\n\t\tgh[v].push_back(u);\n\t\tg[u].push_back({v,w});\n\t\tg[v].push_back({u,w});\n\t}\n\tvirtualtree vt(gh);\n\tvector<long long> dist(n,-1ll);\n\t{\n\t\tqueue<long long> q;\n\t\tq.push(0ll);\n\t\tdist[0ll] = 0ll;\n\t\twhile(!q.empty()){\n\t\t\tlong long it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(pair<long long,long long> i : g[it]){\n\t\t\t\tif(dist[i.first] != -1ll) continue;\n\t\t\t\tdist[i.first] = dist[it] + i.second;\n\t\t\t\tq.push(i.first);\n\t\t\t}\n\t\t}\n\t}\n\tauto dis = [&](long long u,long long v) -> long long {\n\t\tlong long lc = vt.lca(u,v);\n\t\treturn dist[u] + dist[v] - dist[lc] * 2ll;\n\t};\n\tfor(long long cnt = 0ll;cnt < Q;cnt++){\n\t\tlong long a,b,c;\n\t\tcin >> a >> b >> c;\n\t\ta--;b--;c--;\n\t\tif(dist[a] < dist[b]) swap(a,b);\n\t\tif(dist[a] < dist[c]) swap(a,c);\n\t\tlong long it = max({dis(a,b),dis(a,c),dis(b,c)});\n\t\tlong long t = it;\n\t\tit = (it + 1ll) / 2ll;\n\t\tlong long low = 0ll,high = n;\n\t\twhile(low < high){\n\t\t\tlong long mid = (low + high) / 2ll;\n\t\t\tif(dist[a] - dist[vt.root(a,mid)] >= it){\n\t\t\t\thigh = mid;\n\t\t\t}else{\n\t\t\t\tlow = mid + 1ll;\n\t\t\t}\n\t\t}\n\t\tlong long ans = dist[a] - dist[vt.root(a,low)]; \n\t\tans = min(ans,t - (dist[a] - dist[vt.root(a,low - 1)]));\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 1150, "memory_kb": 52196, "score_of_the_acc": -1.8219, "final_rank": 19 }, { "submission_id": "aoj_0391_9572016", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct virtualtree{\n\tlong long n;\n\tvector<vector<long long>> g,p;\n\tvector<long long> o,d;\n\tlong long cou = 0ll;\n\tvirtualtree(vector<vector<long long>> g) : g(g), n(g.size()) {\n\t\to.resize(n,-1ll);\n\t\tp.resize(n);\n\t\td.resize(n);\n\t\tfor(long long i = 0ll;i < n;i++){\n\t\t\tp[i].resize(20ll);\n\t\t}\n\t\td[0ll] = 0ll;\n\t\tp[0ll][0ll] = 0ll;\n\t\tdfs(0ll);\n\t\tfor(long long i = 1ll;i < 20ll;i++){\n\t\t\tfor(long long j = 0ll;j < n;j++){\n\t\t\t\tp[j][i] = p[p[j][i - 1ll]][i - 1ll];\n\t\t\t}\n\t\t}\n\t}\n\tvoid dfs(long long x){\n\t\to[x] = cou;\n\t\tcou++;\n\t\tfor(long long i : g[x]){\n\t\t\tif(o[i] != -1ll){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tp[i][0ll] = x;\n\t\t\td[i] = d[x] + 1ll;\n\t\t\tdfs(i);\n\t\t}\n\t}\n\tlong long root(long long a,long long b){\n\t\tfor(long long i = 0ll;i < 30ll;i++){\n\t\t\tif(b & (1ll << i)){\n\t\t\t\ta = p[a][i];\n\t\t\t}\n\t\t}\n\t\treturn a;\n\t}\n\tlong long lca(long long u,long long v){\n\t\tif(d[u] > d[v]){\n\t\t\tu = root(u,d[u] - d[v]);\n\t\t}\n\t\tif(d[v] > d[u]){\n\t\t\tv = root(v,d[v] - d[u]);\n\t\t}\n\t\tlong long low = 0ll,high = n;\n\t\twhile(low < high){\n\t\t\tlong long mid = (low + high) / 2ll;\n\t\t\tif(root(u,mid) == root(v,mid)){\n\t\t\t\thigh = mid;\n\t\t\t}else{\n\t\t\t\tlow = mid + 1ll;\n\t\t\t}\n\t\t}\n\t\treturn root(u,low);\n\t}\n\tlong long dist(long long u,long long v){\n\t\tlong long lc = lca(u,v);\n\t\treturn d[u] + d[v] - d[lc] * 2ll;\n\t}\n\tvector<vector<pair<long long,long long>>> get(vector<long long> x){\n\t\tvector<vector<pair<long long,long long>>> res(x.size(),vector<pair<long long,long long>>());\n\t\tauto com = [&](long long a,long long b) -> bool {\n\t\t\treturn o[a] < o[b];\n\t\t};\n\t\tmap<long long,long long> t;\n\t\tset<long long> c;\n\t\tsort(x.begin(),x.end(),com);\n\t\tfor(long long i = 0ll;i < (long long)x.size();i++){\n\t\t\tc.insert(x[i]);\n\t\t\tt[x[i]] = i;\n\t\t}\n\t\tx.push_back(x[0ll]);\n\t\tstack<long long> s;\n\t\ts.push(x[0ll]);\n\t\tfor(long long i = 1ll;i < (long long)x.size();i++){\n\t\t\tlong long lc = lca(x[i - 1ll],x[i]);\n\t\t\tif(!c.count(lc)){\n\t\t\t\tt[lc] = (long long)c.size();\n\t\t\t\tc.insert(lc);\n\t\t\t\tres.push_back({});\n\t\t\t}\n\t\t\tlong long last = -1ll;\n\t\t\twhile(!s.empty() && d[s.top()] >= d[lc]){\n\t\t\t\tlong long it = s.top();\n\t\t\t\ts.pop();\n\t\t\t\tif(last != -1ll && last != it){\n\t\t\t\t\tres[t[it]].push_back({t[last],dist(it,last)});\n\t\t\t\t\tres[t[last]].push_back({t[it],dist(it,last)});\n\t\t\t\t}\n\t\t\t\tlast = it;\n\t\t\t}\n\t\t\tif(last != -1ll && last != lc){\n\t\t\t\tres[t[last]].push_back({t[lc],dist(last,lc)});\n\t\t\t\tres[t[lc]].push_back({t[last],dist(last,lc)});\n\t\t\t}\n\t\t\ts.push(lc);\n\t\t\ts.push(x[i]);\n\t\t}\n\t\treturn res;\n\t}\n};\nint main()\n{\n\tlong long n,Q;\n\tcin >> n >> Q;\n\tvector<vector<long long>> gh(n,vector<long long>());\n\tvector<vector<pair<long long,long long>>> g(n,vector<pair<long long,long long>>());\n\tfor(long long i = 0ll;i < n - 1ll;i++){\n\t\tlong long u,v,w;\n\t\tcin >> u >> v >> w;\n\t\tu--;v--;\n\t\tgh[u].push_back(v);\n\t\tgh[v].push_back(u);\n\t\tg[u].push_back({v,w});\n\t\tg[v].push_back({u,w});\n\t}\n\tvirtualtree vt(gh);\n\tvector<long long> dist(n,-1ll);\n\t{\n\t\tqueue<long long> q;\n\t\tq.push(0ll);\n\t\tdist[0ll] = 0ll;\n\t\twhile(!q.empty()){\n\t\t\tlong long it = q.front();\n\t\t\tq.pop();\n\t\t\tfor(pair<long long,long long> i : g[it]){\n\t\t\t\tif(dist[i.first] != -1ll) continue;\n\t\t\t\tdist[i.first] = dist[it] + i.second;\n\t\t\t\tq.push(i.first);\n\t\t\t}\n\t\t}\n\t}\n\tauto dis = [&](long long u,long long v) -> long long {\n\t\tlong long lc = vt.lca(u,v);\n\t\treturn dist[u] + dist[v] - dist[lc] * 2ll;\n\t};\n\tfor(long long cnt = 0ll;cnt < Q;cnt++){\n\t\tif(n < 100000){\n\t\tlong long a,b,c;\n\t\tcin >> a >> b >> c;\n\t\ta--;b--;c--;\n\t\tif(dist[a] < dist[b]) swap(a,b);\n\t\tif(dist[a] < dist[c]) swap(a,c);\n\t\tlong long it = max({dis(a,b),dis(a,c),dis(b,c)});\n\t\tlong long t = it;\n\t\tit = (it + 1ll) / 2ll;\n\t\tlong long low = 0ll,high = n;\n\t\twhile(low < high){\n\t\t\tlong long mid = (low + high) / 2ll;\n\t\t\tif(dis(a,vt.root(a,mid)) >= it){\n\t\t\t\thigh = mid;\n\t\t\t}else{\n\t\t\t\tlow = mid + 1ll;\n\t\t\t}\n\t\t}\n\t\tlong long ans = dis(a,vt.root(a,low)); \n\t\tans = min(ans,t - dis(a,vt.root(a,low - 1ll)));\n\t\tcout << ans << endl;\n\t\t}\n\t}\n}", "accuracy": 0.625, "time_ms": 80, "memory_kb": 52392, "score_of_the_acc": -0.9573, "final_rank": 20 }, { "submission_id": "aoj_0391_9033607", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct lca_tree {\n int n, lg;\n vector<vector<int>> to;\n vector<vector<long long>> co;\n vector<int> dep;\n vector<long long> cost;\n vector<vector<int>> dest;\n lca_tree(int n) : n(n), to(n), co(n), dep(n), cost(n) {\n lg = 0;\n while((1<<lg) < n) lg++;\n dest = vector(lg+1, vector<int>(n+1, n));\n }\n void add_edge(int a, int b, long long c) {\n to[a].push_back(b); co[a].push_back(c);\n to[b].push_back(a); co[b].push_back(c);\n }\n void dfs(int v, int p) {\n for(int i = 0; i < int(to[v].size()); i++) {\n int u = to[v][i];\n if(u == p) continue;\n dep[u] = dep[v]+1;\n cost[u] = cost[v]+co[v][i];\n dest[0][u] = v;\n dfs(u, v);\n }\n }\n void build() {\n dfs(0, n);\n for(int k = 0; k < lg; k++) {\n for(int v = 0; v < n; v++) {\n dest[k+1][v] = dest[k][dest[k][v]];\n }\n }\n }\n // LCA\n int up(int v, int d) {\n for(int k = 0; k <= lg; k++) {\n if((d>>k)&1) v = dest[k][v];\n }\n return v;\n }\n int lca(int a, int b) {\n if(dep[a] > dep[b]) swap(a, b);\n b = up(b, dep[b]-dep[a]);\n if(a == b) return a;\n for(int k = lg; k >= 0; k--) {\n if(dest[k][a] != dest[k][b]) {\n a = dest[k][a], b = dest[k][b];\n }\n }\n return dest[0][a];\n }\n int length(int a, int b) {\n int c = lca(a, b);\n return dep[a]+dep[b]-2*dep[c];\n }\n long long dist(int a, int b) {\n int c = lca(a, b);\n return cost[a]+cost[b]-2*cost[c];\n }\n};\n\nint main() {\n int N, Q;\n cin >> N >> Q;\n lca_tree G(N);\n for(int i = 0; i < N-1; i++) {\n int u, v, w;\n cin >> u >> v >> w;\n G.add_edge(u-1, v-1, w);\n }\n G.build();\n auto f = [&](int x, int y) -> long long {\n int z = G.lca(x, y);\n if(G.dist(x, z) < G.dist(y, z)) swap(x, y);\n int ok = 0, ng = G.length(x, z);\n while(ok+1 < ng) {\n int k = (ok+ng)/2;\n int w = G.up(x, k);\n if(G.dist(x, w) < G.dist(y, w)) ok = k;\n else ng = k;\n }\n int wo = G.up(x, ok), wn = G.up(x, ng);\n return min(max(G.dist(x, wo), G.dist(y, wo)), max(G.dist(x, wn), G.dist(y, wn)));\n };\n for(int q = 0; q < Q; q++) {\n int a, b, c;\n cin >> a >> b >> c;\n a--, b--, c--;\n cout << max({f(a, b), f(b, c), f(c, a)}) << endl;\n }\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 29840, "score_of_the_acc": -1.1908, "final_rank": 15 }, { "submission_id": "aoj_0391_8719317", "code_snippet": "#include <bits/stdc++.h>\n\nstruct LCA {\n static constexpr int ROOT = 0;\n static constexpr int LOG = 20;\n std::vector<std::vector<int>> parent;\n std::vector<int> depth;\n std::vector<int> depth_with_weight;\n LCA(const std::vector<std::vector<std::pair<int, int>>>& graph) {\n int n = graph.size();\n parent.assign(n, std::vector<int>(LOG + 1));\n depth.assign(n, 0);\n depth_with_weight.assign(n, 0);\n auto dfs = [&](auto self, int u, int p) -> void {\n parent[u][0] = p;\n for (auto [v, w]: graph[u]) {\n if (v == p) continue;\n depth[v] = depth[u] + 1;\n depth_with_weight[v] = depth_with_weight[u] + w;\n self(self, v, u);\n }\n };\n dfs(dfs, ROOT, ROOT);\n for (int i = 0; i < LOG; i++) {\n for (int j = 0; j < n; j++) {\n parent[j][i + 1] = parent[parent[j][i]][i];\n }\n }\n }\n int lca(int lhs, int rhs) {\n if (depth[lhs] < depth[rhs]) std::swap(lhs, rhs);\n int diff = depth[lhs] - depth[rhs];\n // std::cerr << \"diff = \" << diff << '\\n';\n for (int i = 0; i < LOG; i++) {\n if (diff & (1 << i)) {\n lhs = parent[lhs][i];\n }\n }\n assert(depth[lhs] == depth[rhs]);\n if (lhs == rhs) return lhs;\n for (int i = LOG; i >= 0; i--) {\n if (parent[lhs][i] != parent[rhs][i]) {\n lhs = parent[lhs][i];\n rhs = parent[rhs][i];\n }\n }\n assert(lhs != rhs);\n assert(parent[lhs][0] == parent[rhs][0]);\n return parent[lhs][0];\n }\n int dist(int u, int v) {\n return dist(u, v, lca(u, v));\n }\n int dist(int u, int v, int w) {\n return depth_with_weight[u] + depth_with_weight[v] - 2 * depth_with_weight[w];\n }\n int ancester(int u, int k) {\n for (int i = LOG; i >= 0; i--) {\n if (depth_with_weight[u] - depth_with_weight[parent[u][i]] <= k) {\n k -= depth_with_weight[u] - depth_with_weight[parent[u][i]];\n u = parent[u][i];\n }\n }\n assert(k >= 0);\n return u;\n }\n};\n\nint main() {\n int n, q;\n std::cin >> n >> q;\n std::vector<std::vector<std::pair<int, int>>> graph(n);\n for (int i = 0; i + 1 < n; i++) {\n int u, v, w;\n std::cin >> u >> v >> w;\n u--; v--;\n graph[u].emplace_back(v, w);\n graph[v].emplace_back(u, w);\n }\n LCA lca(graph);\n\n auto query = [&](int u, int v) {\n int w = lca.lca(u, v);\n if (u == w || v == w) {\n if (v == w) std::swap(u, v);\n // root -> u -> v\n int ok = lca.dist(u, v, w);\n int ng = 0;\n while (ok - ng > 1) {\n int key = (ok + ng) / 2;\n int vv = lca.ancester(v, key);\n if (lca.dist(u, vv, w) <= key) {\n ok = key;\n } else {\n ng = key;\n }\n }\n return ok;\n } else {\n int u_dist = lca.dist(u, w, w);\n int v_dist = lca.dist(v, w, w);\n if (u_dist > v_dist) {\n std::swap(u_dist, v_dist);\n std::swap(u, v);\n }\n // root -> w -> u\n // -> ... -> v\n int ok = v_dist;\n int ng = u_dist;\n while (ok - ng > 1) {\n int key = (ok + ng) / 2;\n int vv = lca.ancester(v, key);\n if (lca.dist(u, vv, w) <= key) {\n ok = key;\n } else {\n ng = key;\n }\n }\n return ok;\n }\n };\n\n while (q--) {\n int a, b, c;\n std::cin >> a >> b >> c;\n a--; b--; c--;\n int ans = std::max({query(a, b), query(b, c), query(a, c)});\n std::cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 28772, "score_of_the_acc": -1.0236, "final_rank": 13 }, { "submission_id": "aoj_0391_6974831", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0391.cc: Meeting in a City\n */\n\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<cmath>\n#include<iostream>\n#include<string>\n#include<vector>\n#include<map>\n#include<set>\n#include<stack>\n#include<list>\n#include<queue>\n#include<deque>\n#include<algorithm>\n#include<functional>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int BN = 17;\nconst int INF = 1 << 30;\nconst long long LINF = 1LL << 60;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef queue<int> qi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\n\n/* global variables */\n\nvpii nbrs[MAX_N];\nint ps[MAX_N][BN], ds[MAX_N], dws[MAX_N], cis[MAX_N];\n\n/* subroutines */\n\nint ancestor(int u, int d) {\n for (int i = BN - 1; i >= 0; i--)\n if ((d >> i) & 1) u = ps[u][i];\n return u;\n}\n\nint find_lca(int u, int v) {\n if (ds[u] > ds[v]) swap(u, v);\n\n v = ancestor(v, ds[v] - ds[u]);\n if (u == v) return u;\n\n for(int i = BN - 1; i >= 0; i--)\n if (ps[u][i] != ps[v][i])\n u = ps[u][i], v = ps[v][i];\n\n return ps[u][0];\n}\n\nint pathd(int u, int v) {\n int t = find_lca(u, v);\n return ds[u] + ds[v] - ds[t] * 2;\n}\n\nint pathw(int u, int v) {\n int t = find_lca(u, v);\n return dws[u] + dws[v] - dws[t] * 2;\n}\n\nint check(int a, int b, int c, int t, int x) { // t = lca(a, b)\n int lda = ds[a] + ds[b] - ds[t] * 2;\n int s = (ds[a] - ds[t] >= x) ? ancestor(a, x) : ancestor(b, lda - x);\n return max(pathw(a, s), max(pathw(b, s), pathw(c, s)));\n}\n\n/* main */\n\nint main() {\n int n, qn;\n scanf(\"%d%d\", &n, &qn);\n\n for (int i = 1; i < n; i++) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n u--, v--;\n nbrs[u].push_back(pii(v, w));\n nbrs[v].push_back(pii(u, w));\n }\n\n ps[0][0] = -1, dws[0] = 0, ds[0] = 0;\n for (int u = 0; u >= 0;) {\n vpii &nbru = nbrs[u];\n int up = ps[u][0];\n\n if (cis[u] < nbru.size()) {\n pii vw = nbru[cis[u]++];\n int v = vw.first, w = vw.second;\n if (v != up) {\n\tps[v][0] = u, dws[v] = dws[u] + w, ds[v] = ds[u] + 1;\n\tu = v;\n }\n }\n else {\n u = up;\n }\n }\n\n for (int i = 0; i < BN - 1; i++)\n for (int u = 0; u < n; u++)\n ps[u][i + 1] = (ps[u][i] >= 0) ? ps[ps[u][i]][i] : -1;\n\n while (qn--) {\n int a, b, c;\n scanf(\"%d%d%d\", &a, &b, &c);\n a--, b--, c--;\n\n int dab = pathw(a, b);\n int dbc = pathw(b, c);\n int dca = pathw(c, a);\n\n if (dbc >= dab && dbc >= dca) swap(a, c), swap(dab, dbc);\n else if (dca >= dab && dca >= dbc) swap(b, c), swap(dab, dca);\n //printf(\"%d,%d,%d -> ab=%d,bc=%d,ca=%d\\n\", a, b, c, dab, dbc, dca);\n\n int t = find_lca(a, b);\n int x0 = 0, x1 = ds[a] + ds[b] - ds[t] * 2;\n while (x0 + 2 < x1) {\n int xx0 = (x0 * 2 + x1) / 3;\n int xx1 = (x0 + x1 * 2) / 3;\n int c0 = check(a, b, c, t, xx0);\n int c1 = check(a, b, c, t, xx1);\n if (c0 > c1) x0 = xx0;\n else x1 = xx1;\n }\n\n int minc = INF;\n for (int x = x0; x <= x1; x++)\n minc = min(minc, check(a, b, c, t, x));\n\n printf(\"%d\\n\", minc);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1040, "memory_kb": 17292, "score_of_the_acc": -0.7853, "final_rank": 8 }, { "submission_id": "aoj_0391_5968560", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int LOG = 18;\nstruct lowest_common_ancestor{\n vector<int> d;\n vector<vector<int>> p;\n lowest_common_ancestor(){\n }\n lowest_common_ancestor(vector<int> &P, vector<vector<int>> &c){\n int N = P.size();\n d = vector<int>(N, 0);\n queue<int> Q;\n Q.push(0);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (int w : c[v]){\n d[w] = d[v] + 1;\n Q.push(w);\n }\n }\n p = vector<vector<int>>(LOG, vector<int>(N, -1));\n for (int i = 0; i < N; i++){\n p[0][i] = P[i];\n }\n for (int i = 1; i < LOG; i++){\n for (int j = 0; j < N; j++){\n if (p[i - 1][j] != -1){\n p[i][j] = p[i - 1][p[i - 1][j]];\n }\n }\n }\n }\n int la(int u, int x){\n for (int k = 0; k < LOG; k++){\n if (x >> k & 1){\n u = p[k][u];\n if (u == -1){\n return -1;\n }\n }\n }\n return u;\n }\n int lca(int u, int v){\n if (d[u] > d[v]){\n swap(u, v);\n }\n v = la(v, d[v] - d[u]);\n if (u == v){\n return u;\n }\n for (int k = LOG - 1; k >= 0; k--){\n if (p[k][u] != p[k][v]){\n u = p[k][u];\n v = p[k][v];\n }\n }\n return p[0][u];\n }\n int dist(int u, int v){\n return d[u] + d[v] - 2 * d[lca(u, v)];\n }\n};\nstruct weighted_tree_distance{\n //�d�݂‚��؂�2���_�Ԃ̋��� O(logN)\n lowest_common_ancestor T;\n vector<long long> s;\n weighted_tree_distance(vector<int> &p, vector<vector<pair<int, int>>> &c){\n int N = p.size();\n s = vector<long long>(N, 0);\n vector<vector<int>> c2(N);\n queue<int> Q;\n Q.push(0);\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n for (auto P : c[v]){\n int d = P.first;\n int w = P.second;\n s[w] = s[v] + d;\n c2[v].push_back(w);\n Q.push(w);\n }\n }\n T = lowest_common_ancestor(p, c2);\n }\n int la(int u, int x){\n return T.la(u, x);\n }\n int lca(int u, int v){\n return T.lca(u, v);\n }\n long long dist(int u, int v){\n return s[u] + s[v] - 2 * s[T.lca(u, v)];\n }\n int path_point(int u, int v, int x){\n //u->v�p�X��u���狗��x\n int w = T.lca(u, v);\n int d = T.dist(u, w);\n if (x <= d){\n return T.la(u, x);\n } else {\n return T.la(v, T.dist(u, v) - x);\n }\n }\n};\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int N, Q;\n cin >> N >> Q;\n vector<vector<int>> E1(N);\n vector<vector<pair<int, int>>> E2(N);\n for (int i = 0; i < N - 1; i++){\n int u, v, w;\n cin >> u >> v >> w;\n u--;\n v--;\n E1[u].push_back(v);\n E1[v].push_back(u);\n E2[u].push_back(make_pair(w, v));\n E2[v].push_back(make_pair(w, u));\n }\n vector<int> p(N, -1);\n vector<vector<pair<int, int>>> ch(N);\n queue<int> q;\n q.push(0);\n while (!q.empty()){\n int v = q.front();\n q.pop();\n for (auto P : E2[v]){\n int d = P.first;\n int w = P.second;\n if (w != p[v]){\n p[w] = v;\n ch[v].push_back(make_pair(d, w));\n q.push(w);\n }\n }\n }\n weighted_tree_distance T(p, ch);\n for (int i = 0; i < Q; i++){\n int a, b, c;\n cin >> a >> b >> c;\n a--;\n b--;\n c--;\n int x;\n int ab = T.lca(a, b);\n int bc = T.lca(b, c);\n int ca = T.lca(c, a);\n if (ab == a && ca == a){\n x = bc;\n } else if (bc == b && ab == b){\n x = ca;\n } else if (ca == c && bc == c){\n x = ab;\n } else {\n int abc = T.lca(ab, c);\n if (abc != ab){\n x = ab;\n } else if (abc != bc){\n x = bc;\n } else {\n x = ca;\n }\n }\n long long da = T.dist(x, a);\n long long db = T.dist(x, b);\n long long dc = T.dist(x, c);\n long long ans = max({da, db, dc});\n int A = a, B = b, C = c;\n if (da < db){\n swap(A, B);\n swap(da, db);\n }\n if (max(da, db) < dc){\n swap(A, C);\n swap(da, dc);\n }\n long long p = da;\n long long q = max(db, dc);\n //cout << \"x = \" << x << endl;\n //cout << \"p = \" << p << \", q = \" << q << endl;\n long long t = (p - q) / 2;\n //cout << \"t = \" << t << endl;\n int dist = T.T.dist(A, x);\n //cout << \"x = \" << x << \", A = \" << A << endl;\n ans = min(ans, max(T.dist(A, B), T.dist(A, C)));\n int L = 0;\n int R = dist;\n while (R - L > 1){\n int mid = (L + R) / 2;\n int v = T.path_point(x, A, mid);\n //cout << \"mid = \" << mid << \", v = \" << v << endl;\n long long t2 = T.dist(x, v);\n //cout << \"mid = \" << mid << \", t2 = \" << t2 << endl;\n if (t2 > t){\n R = mid;\n } else {\n L = mid;\n }\n }\n for (int j = L; j <= R; j++){\n int v = T.path_point(x, A, j);\n long long t2 = T.dist(x, v);\n long long dmax = max(p - t2, q + t2);\n ans = min(ans, dmax);\n }\n cout << ans << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 33700, "score_of_the_acc": -0.7753, "final_rank": 7 }, { "submission_id": "aoj_0391_5876859", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define pb emplace_back\n#define lb(v,k) (lower_bound(all(v),(k))-v.begin())\n#define ub(v,k) (upper_bound(all(v),(k))-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\n#define PQ(T) priority_queue<T>\n#define SPQ(T) priority_queue<T,vector<T>,greater<T>>\n#define dame(a) {out(a);return 0;}\n#define decimal cout<<fixed<<setprecision(15);\n#define all(a) a.begin(),a.end()\n#define rsort(a) {sort(all(a));reverse(all(a));}\n#define dupli(a) {sort(all(a));a.erase(unique(all(a)),a.end());}\n#define popcnt __builtin_popcountll\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef tuple<ll,ll,ll,ll> PPP;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nusing vvvvi=vector<vvvi>;\nusing vp=vector<P>;\nusing vvp=vector<vp>;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nconst ll inf=1001001001001001001;\nconst ll INF=1001001001;\nconst ll mod=998244353;\nconst double eps=1e-10;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<'\\n';}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<'\\n';}\ntemplate<class T> void outvp(T v){rep(i,v.size())cout<<'('<<v[i].fi<<','<<v[i].se<<')';cout<<'\\n';}\ntemplate<class T> void outvvp(T v){rep(i,v.size())outvp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<'\\n';}\ntemplate<class T> void outvv(T v){rep(i,v.size())outv(v[i]);}\ntemplate<class T> bool isin(T x,T l,T r){return (l)<=(x)&&(x)<=(r);}\ntemplate<class T> void yesno(T b){if(b)out(\"yes\");else out(\"no\");}\ntemplate<class T> void YesNo(T b){if(b)out(\"Yes\");else out(\"No\");}\ntemplate<class T> void YESNO(T b){if(b)out(\"YES\");else out(\"NO\");}\ntemplate<class T> void outset(T s){auto itr=s.begin();while(itr!=s.end()){if(itr!=s.begin())cout<<' ';cout<<*itr;itr++;}cout<<'\\n';}\nvoid outs(ll a,ll b){if(a>=inf-100)out(b);else out(a);}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll modpow(ll a,ll b){ll res=1;a%=mod;while(b){if(b&1)res=res*a%mod;a=a*a%mod;b>>=1;}return res;}\n\n\nint main(){\n ll n,q;cin>>n>>q;\n vvp g(n);\n rep(i,n-1){\n ll a,b,c;cin>>a>>b>>c;a--;b--;\n g[a].pb(b,c);g[b].pb(a,c);\n }\n vi par(n),dep(n),dep2(n);\n function<void(ll,ll,ll,ll)> dfs=[&](ll i,ll p,ll d,ll d2){\n par[i]=p;dep[i]=d;dep2[i]=d2;\n for(auto x:g[i])if(x.fi!=p)dfs(x.fi,i,d+x.se,d2+1);\n };dfs(0,-1,0,0);\n vvi table(n,vi(20,-1));\n rep(i,n)table[i][0]=par[i];\n rep(i,19)rep(j,n)if(table[j][i]!=-1)table[j][i+1]=table[table[j][i]][i];\n auto lca=[&](ll a,ll b){\n if(dep2[a]>dep2[b])swap(a,b);\n ll dif=dep2[b]-dep2[a];\n rep(i,20)if(dif>>i&1)b=table[b][i];\n if(a==b)return a;\n for(int i=19;i>=0;i--)if(table[a][i]!=table[b][i]){\n a=table[a][i];b=table[b][i];\n }\n return par[a];\n };\n auto dis=[&](ll a,ll b){\n return dep[a]+dep[b]-dep[lca(a,b)]*2;\n };\n rep(qq,q){\n vi v(3);rep(i,3)cin>>v[i];rep(i,3)v[i]--;\n vi al;\n rep(i,3)rep(j,i){\n ll d=dis(v[i],v[j]),l=lca(v[i],v[j]);\n ll cur=v[i];\n for(int k=19;k>=0;k--)if(table[cur][k]!=-1){\n if((dep[v[i]]-dep[table[cur][k]])*2<=d&&dep[l]<dep[table[cur][k]])cur=table[cur][k];\n }\n al.pb(cur);al.pb(par[cur]);\n cur=v[j];\n for(int k=19;k>=0;k--)if(table[cur][k]!=-1){\n if((dep[v[j]]-dep[table[cur][k]])*2<=d&&dep[l]<dep[table[cur][k]])cur=table[cur][k];\n }\n al.pb(cur);al.pb(par[cur]);\n }\n ll ans=inf;\n for(ll x:al)if(x!=-1)chmin(ans,max({dis(v[0],x),dis(v[1],x),dis(v[2],x)}));\n out(ans);\n }\n}", "accuracy": 1, "time_ms": 840, "memory_kb": 42844, "score_of_the_acc": -1.3161, "final_rank": 17 }, { "submission_id": "aoj_0391_5768229", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntemplate<typename Graph>\nstruct Doubling {\npublic:\n int n, lg;\n const Graph g;\n\n vector<int> depth;\n vector<vector<int> > table, dist_table;\n vector<int> dist;\n\n Doubling(Graph &G) : g(G), n(G.size()), depth(G.size()), dist(G.size()) {\n lg = 32 - __builtin_clz(n) + 1;\n table.resize(n, vector(lg, 0));\n dist_table.resize(n, vector(lg, 0));\n dfs(0, -1, 0, 0);\n build();\n }\n\n int lca(int u, int v) {\n if (depth[u] < depth[v]) swap(u, v);\n for (int k = lg - 1; k >= 0; --k) {\n if (depth[u] - depth[v] >> k & 1) u = table[u][k];\n }\n if (u == v) return (u);\n for (int k = lg - 1; k >= 0; --k) {\n if (table[u][k] != table[v][k]) {\n u = table[u][k];\n v = table[v][k];\n }\n }\n return (table[u][0]);\n }\n\n /* u < v */\n int binary_search(int u, int v, int all) {\n int sum = 0;\n for (int k = lg - 1; k >= 0; --k) {\n if (depth[v] - depth[u] >= 1 << k && (sum + dist_table[v][k]) * 2 < all) {\n sum += dist_table[v][k];\n v = table[v][k];\n }\n }\n return (v);\n }\n\n int la(int u, int x) {\n for (int k = lg - 1; k >= 0; --k) {\n if (x >> k & 1) {\n u = table[u][k];\n x >>= 1;\n }\n }\n return (u);\n }\n\n int distance(int u, int v) {\n return (dist[u] + dist[v] - dist[lca(u, v)] * 2);\n }\n\nprivate:\n\n void build() {\n for (int k = 0; k < lg - 1; ++k) {\n for (int i = 0; i < n; ++i) {\n if (table[i][k] != -1) {\n table[i][k + 1] = table[table[i][k]][k];\n dist_table[i][k + 1] = dist_table[i][k] + dist_table[table[i][k]][k];\n }\n }\n }\n }\n\n void dfs(int cur, int par, int dep, int dis) {\n depth[cur] = dep;\n table[cur][0] = par;\n dist[cur] = dis;\n for (auto [to, w] : g[cur]) {\n if (par == to) continue;\n dist_table[to][0] = w;\n dfs(to, cur, dep + 1, dis + w);\n }\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n int n, q;\n cin >> n >> q;\n\n vector<vector<pair<int, int> > > graph(n);\n\n for (int i = 0; i < n - 1; ++i) {\n int u, v, w;\n cin >> u >> v >> w;\n --u, --v;\n graph[u].emplace_back(v, w);\n graph[v].emplace_back(u, w);\n }\n\n Doubling dbl(graph);\n\n for (int i = 0; i < q; ++i) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b, --c;\n\n int dist_ab = dbl.distance(a, b);\n int dist_ac = dbl.distance(a, c);\n int dist_bc = dbl.distance(b, c);\n int max_dist = max({dist_ab, dist_ac, dist_bc});\n\n int u, v;\n if (dist_ab == max_dist) u = a, v = b;\n if (dist_ac == max_dist) u = a, v = c;\n if (dist_bc == max_dist) u = b, v = c;\n\n int lca = dbl.lca(u, v), dist = max_dist;\n if (dbl.depth[u] > dbl.depth[v]) swap(u, v);\n\n if (lca != u) {\n if (dbl.distance(u, lca) > dbl.distance(lca, v)) swap(u, v);\n u = lca;\n }\n\n // cout << u << ' ' << v << ' ' << dist << '\\n';\n int x = dbl.binary_search(u, v, dist);\n int y = max(dbl.la(x, 1), 0);\n // cout << x << ' ' << y << '\\n';\n\n cout << min(max({dbl.distance(a, x), dbl.distance(b, x), dbl.distance(c, x)}),\n max({dbl.distance(a, y), dbl.distance(b, y), dbl.distance(c, y)})) << '\\n';\n }\n\n return (0);\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 42680, "score_of_the_acc": -0.8645, "final_rank": 11 }, { "submission_id": "aoj_0391_4989924", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <set>\n#include <iomanip>\n#include <queue>\n#include <string>\n#include <map>\n#include <fstream>\n#include <cassert>\n#include <stack>\n#include <climits>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <memory>\n#include <functional>\n#include <cfloat>\n#include <numeric>\n#include <random>\n\n\nclass Tree {\n\tstd::vector<std::vector<int>> doubling;\n\tstd::vector<int> depth, distance;\n\tint ancestor_from(int a, int diff) const {\n\t\tfor (auto i = 0; diff != 0; ++i) {\n\t\t\tif (((diff >> i) & 1) == 1) {\n\t\t\t\ta = doubling[a][i];\n\t\t\t\tdiff -= 1 << i;\n\t\t\t}\n\t\t}\n\t\treturn a;\n\t}\n\tint lca(int a, int b) const {\n\t\tif (depth[a] != depth[b]) {\n\t\t\tif (depth[a] < depth[b]) std::swap(a, b);\n\t\t\ta = ancestor_from(a, depth[a] - depth[b]);\n\t\t}\n\t\tif (a == b) return a;\n\t\tif (doubling[a][0] == doubling[b][0]) return doubling[a][0];\n\t\tfor (auto i = 1; i < doubling[a].size(); ++i) {\n\t\t\tif (doubling[a][i] == doubling[b][i]) return lca(doubling[a][i - 1], doubling[b][i - 1]);\n\t\t}\n\t\treturn lca(doubling[a].back(), doubling[b].back());\n\t}\npublic:\n\tTree(const std::vector<std::vector<std::pair<int, int>>>& node) : doubling(node.size()), depth(node.size()), distance(node.size()) {\n\t\tstd::stack<std::pair<int, int>> stack;\n\t\tdepth[0] = 0;\n\t\tdistance[0] = 0;\n\t\tfor (const auto [c, dist] : node[0]) {\n\t\t\tstack.emplace(0, c);\n\t\t\tdepth[c] = depth[0] + 1;\n\t\t\tdistance[c] = distance[0] + dist;\n\t\t}\n\t\twhile (!stack.empty()) {\n\t\t\tconst auto [parent, current] = stack.top(); stack.pop();\n\t\t\tdoubling[current].push_back(parent);\n\t\t\twhile (doubling[doubling[current].back()].size() >= doubling[current].size()) {\n\t\t\t\tdoubling[current].push_back(doubling[doubling[current].back()][doubling[current].size() - 1]);\n\t\t\t}\n\t\t\tfor (const auto [c, dist] : node[current]) {\n\t\t\t\tif (c == parent) continue;\n\t\t\t\tstack.emplace(current, c);\n\t\t\t\tdepth[c] = depth[current] + 1;\n\t\t\t\tdistance[c] = distance[current] + dist;\n\t\t\t}\n\t\t}\n\t}\n\tint distance_between(const int a, const int b) const {\n\t\treturn distance[a] + distance[b] - (distance[lca(a, b)] << 1);\n\t}\n\tint count_between(const int a, const int b) const {\n\t\treturn depth[a] + depth[b] - (depth[lca(a, b)] << 1) + 1;\n\t}\n\tint node(const int from, const int to, const int rank) const {\n\t\tconst auto ancestor = lca(from, to);\n\t\tconst auto left = depth[from] - depth[ancestor] + 1;\n\t\tconst auto right = depth[to] - depth[ancestor];\n\t\tif (rank < left) return ancestor_from(from, rank);\n\t\telse return ancestor_from(to, left + right - 1 - rank);\n\t}\n\tint mid_node(const int a, const int b, const int c) const {\n\t\tconst auto ab = lca(a, b);\n\t\tconst auto bc = lca(b, c);\n\t\tconst auto ca = lca(c, a);\n\t\tconst auto max_depth = std::max({ depth[ab], depth[bc], depth[ca] });\n\t\tif (depth[ab] == max_depth) {\n\t\t\treturn ab;\n\t\t}\n\t\telse if (depth[bc] == max_depth) {\n\t\t\treturn bc;\n\t\t}\n\t\telse {\n\t\t\treturn ca;\n\t\t}\n\t}\n};\n\nint main() {\n\tint n, q; std::cin >> n >> q;\n\tstd::vector<std::vector<std::pair<int, int>>> nodes(n);\n\tfor (auto i = 0; i < n - 1; ++i) {\n\t\tint u, v, w; std::cin >> u >> v >> w; --u; --v;\n\t\tnodes[u].emplace_back(v, w);\n\t\tnodes[v].emplace_back(u, w);\n\t}\n\tTree tree(nodes);\n\tfor (auto i = 0; i < q; ++i) {\n\t\tint a, b, c; std::cin >> a >> b >> c; --a; --b; --c;\n\t\tconst auto center = tree.mid_node(a, b, c);\n\t\tif (tree.distance_between(center, a) < tree.distance_between(center, b)) {\n\t\t\tstd::swap(a, b);\n\t\t}\n\t\tif (tree.distance_between(center, a) < tree.distance_between(center, c)) {\n\t\t\tstd::swap(a, c);\n\t\t}\n\t\tif (tree.distance_between(center, b) < tree.distance_between(center, c)) {\n\t\t\tstd::swap(b, c);\n\t\t}\n\t\tauto min = 0;\n\t\tauto max = tree.count_between(a, b);\n\t\tconst auto dist = tree.distance_between(a, b);\n\t\twhile (min < max) {\n\t\t\tconst auto mid = (min + max) >> 1;\n\t\t\tconst auto node = tree.node(a, b, mid);\n\t\t\tif (tree.distance_between(a, node) << 1 < dist) {\n\t\t\t\tmin = mid + 1;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmax = mid;\n\t\t\t}\n\t\t}\n\t\tconst auto suspect = tree.node(a, b, max);\n\t\tauto min_cost{ std::max({tree.distance_between(a, suspect), tree.distance_between(b, suspect), tree.distance_between(c, suspect)}) };\n\t\tif (max > 0) {\n\t\t\tconst auto suspect = tree.node(a, b, max - 1);\n\t\t\tmin_cost = std::min(min_cost, std::max({ tree.distance_between(a, suspect), tree.distance_between(b, suspect), tree.distance_between(c, suspect) }));\n\t\t}\n\t\tstd::cout << min_cost << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 21764, "score_of_the_acc": -0.6627, "final_rank": 5 }, { "submission_id": "aoj_0391_4962030", "code_snippet": "// verification-helper: PROBLEM http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0391\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define call_from_test\n#ifndef call_from_test\n#include <bits/stdc++.h>\nusing namespace std;\n#endif\n//BEGIN CUT HERE\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n//END CUT HERE\n#ifndef call_from_test\nsigned main(){\n return 0;\n}\n#endif\n\n#ifndef call_from_test\n#include <bits/stdc++.h>\nusing namespace std;\n#endif\n//BEGIN CUT HERE\nstruct LevelAncestor{\n vector<vector<int> > G,par,lad;\n vector<int> dep,nxt,len,pth,ord,hs;\n LevelAncestor(int n):\n G(n),dep(n),nxt(n,-1),len(n),pth(n),ord(n),hs(n+1,0){\n int h=1;\n while((1<<h)<=n) h++;\n par.assign(h,vector<int>(n,-1));\n for(int i=2;i<=n;i++) hs[i]=hs[i>>1]+1;\n }\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n void dfs(int v,int p,int d,int f){\n if(nxt[v]<0){\n par[0][nxt[v]=v]=p;\n len[v]=dep[v]=d;\n for(int u:G[v]){\n if(u==p) continue;\n dfs(u,v,d+1,0);\n if(len[v]<len[u]) nxt[v]=u,len[v]=len[u];\n }\n }\n if(!f) return;\n pth[v]=lad.size();\n lad.emplace_back();\n for(int k=v;;k=nxt[k]){\n lad.back().emplace_back(k);\n pth[k]=pth[v];\n if(k==nxt[k]) break;\n }\n for(;;p=v,v=nxt[v]){\n for(int u:G[v])\n if(u!=p and u!=nxt[v]) dfs(u,v,d+1,1);\n if(v==nxt[v]) break;\n }\n }\n\n void build(int r=0){\n int n=G.size();\n dfs(r,-1,0,1);\n for(int k=0;k+1<(int)par.size();k++){\n for(int v=0;v<n;v++){\n if(par[k][v]<0) par[k+1][v]=-1;\n else par[k+1][v]=par[k][par[k][v]];\n }\n }\n for(int i=0;i<(int)lad.size();i++){\n int v=lad[i][0],p=par[0][v];\n if(~p){\n int k=pth[p],l=min(ord[p]+1,(int)lad[i].size());\n lad[i].resize(l+lad[i].size());\n for(int j=0,m=lad[i].size();j+l<m;j++)\n lad[i][m-(j+1)]=lad[i][m-(j+l+1)];\n for(int j=0;j<l;j++)\n lad[i][j]=lad[k][ord[p]-l+j+1];\n }\n for(int j=0;j<(int)lad[i].size();j++)\n if(pth[lad[i][j]]==i) ord[lad[i][j]]=j;\n }\n }\n\n int lca(int u,int v){\n int h=par.size();\n\n if(dep[u]>dep[v]) swap(u,v);\n for(int k=0;k<h;k++)\n if((dep[v]-dep[u])>>k&1)\n v=par[k][v];\n\n if(u==v) return u;\n for(int k=h-1;k>=0;k--){\n if(par[k][u]==par[k][v]) continue;\n u=par[k][u];\n v=par[k][v];\n }\n return par[0][u];\n }\n\n int distance(int u,int v){\n return dep[u]+dep[v]-dep[lca(u,v)]*2;\n }\n\n int up(int v,int d){\n if(d==0) return v;\n v=par[hs[d]][v];\n d-=1<<hs[d];\n return lad[pth[v]][ord[v]-d];\n }\n\n // from u to v\n int next(int u,int v){\n if(dep[u]>=dep[v]) return par[0][u];\n int l=up(v,dep[v]-dep[u]-1);\n return par[0][l]==u?l:par[0][u];\n }\n};\n//END CUT HERE\n#ifndef call_from_test\n//INSERT ABOVE HERE\nsigned main(){\n return 0;\n}\n#endif\n\n#undef call_from_test\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n const char newl = '\\n';\n\n int n,q;\n cin>>n>>q;\n using P = pair<int, int>;\n vector<vector<P> > G(n);\n LevelAncestor la(n);\n for(int i=1;i<n;i++){\n int u,v,w;\n cin>>u>>v>>w;\n u--;v--;\n la.add_edge(u,v);\n G[u].emplace_back(v,w);\n G[v].emplace_back(u,w);\n }\n\n la.build();\n\n vector<int> dep(n,0);\n {\n queue<P> q;\n q.emplace(0,-1);\n while(!q.empty()){\n int v,p;\n tie(v,p)=q.front();q.pop();\n for(auto e:G[v]){\n int u,c;\n tie(u,c)=e;\n if(u==p) continue;\n dep[u]=dep[v]+c;\n q.emplace(u,v);\n }\n }\n }\n\n auto dist=[&](int u,int v){return dep[u]+dep[v]-2*dep[la.lca(u,v)];};\n auto path=\n [&](int u,int v,int d){\n if(d==0) return u;\n int r=la.lca(u,v);\n int x=la.distance(u,r),y=la.distance(r,v);\n if(d<=x) return la.up(u,d);\n return la.up(v,(x+y)-d);\n };\n\n for(int i=0;i<q;i++){\n int a,b,c;\n cin>>a>>b>>c;\n a--;b--;c--;\n auto calc=\n [&](int v,int u=-1){\n return max({dist(a,v)*(a!=u),\n dist(b,v)*(b!=u),\n dist(c,v)*(c!=u)});\n };\n\n int p=la.lca(a,b),q=la.lca(b,c),r=la.lca(c,a);\n int v=la.dep[p]>la.dep[q]?p:(la.dep[q]>la.dep[r]?q:r);\n\n int ans=min({calc(a),calc(b),calc(c),calc(v)});\n for(int u:{a,b,c}){\n if(calc(v,u)>=ans) continue;\n int l=0,r=la.distance(u,v);\n while(l+1<r){\n int m=(l+r)>>1;\n int x=path(u,v,m);\n if(calc(x,u)<dist(x,u)) r=m;\n else l=m;\n }\n chmin(ans,calc(path(u,v,l)));\n chmin(ans,calc(path(u,v,r)));\n }\n cout<<ans<<newl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1310, "memory_kb": 34788, "score_of_the_acc": -1.4796, "final_rank": 18 }, { "submission_id": "aoj_0391_4869254", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nclass HeavyLightDecomposition {\n void dfs_sz(int v){\n for (auto &&u : G[v]) {\n if(u == par[v]) continue;\n par[u] = v; dep[u] = dep[v] + 1;\n dfs_sz(u);\n sub_size[v] += sub_size[u];\n if(sub_size[u] > sub_size[G[v][0]]) swap(u, G[v][0]);\n }\n }\n\n void dfs_hld(int v, int c, int &pos){\n id[v] = pos++;\n id_inv[id[v]]= v;\n tree_id[v] = c;\n for (auto &&u : G[v]) {\n if(u == par[v]) continue;\n head[u] = (u == G[v][0] ? head[v] : u);\n dfs_hld(u, c, pos);\n }\n }\n\npublic:\n int n;\n vector<vector<int>> G;\n vector<int> par, dep, sub_size, id, id_inv, tree_id, head;\n explicit HeavyLightDecomposition(int n) : n(n), G(n), par(n), dep(n), sub_size(n, 1),\n id(n), id_inv(n), tree_id(n), head(n){}\n explicit HeavyLightDecomposition(vector<vector<int>> &G) :\n G(G), n(G.size()), par(n), dep(n) , sub_size(n, 1), id(n), id_inv(n), tree_id(n), head(n) {}\n\n void add_edge(int u, int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n void build(vector<int> roots = {0}){\n int c = 0, pos = 0;\n for (auto &&i : roots) {\n dfs_sz(i);\n head[i] = i;\n dfs_hld(i, c++, pos);\n }\n }\n\n int ancestor(int v, int k){\n while(true){\n int u = head[v];\n if(id[v] - k >= id[u]) return id_inv[id[v]-k];\n k -= id[v] - id[u] + 1;\n v = par[u];\n }\n }\n\n int lca(int u, int v){\n while(true){\n if(id[u] > id[v]) swap(u, v);\n if(head[u] == head[v]) return u;\n v = par[head[v]];\n }\n }\n\n int distance(int u, int v){\n return dep[u] + dep[v] - 2*dep[lca(u, v)];\n }\n\n\n template<typename F>\n void query(int u, int v, const F &f){\n while(true){\n if(id[u] > id[v]) swap(u, v);\n f(max(id[head[v]], id[u]), id[v]+1);\n if(head[u] == head[v]) break;\n v = par[head[v]];\n }\n }\n\n template<typename F>\n void query_edge(int u, int v, const F &f){\n while(true){\n if(id[u] > id[v]) swap(u, v);\n f(max(id[head[v]], id[u]), id[v]+1);\n if(head[u] == head[v]) {\n if(u == v) break;\n f(id[u], id[v]+1);\n }else {\n v = par[head[v]];\n }\n }\n }\n\n template<typename T, typename Q, typename F>\n T query(int u, int v, const T &e, const Q &q, const F &f){\n T l = e, r = e;\n while(true){\n if(id[u] > id[v]) swap(u, v), swap(l, r);\n l = f(l, q(max(id[head[v]], id[u]), id[v]+1));\n if(head[u] != head[v]) v = par[head[v]];\n else break;\n }\n return f(l, r);\n }\n};\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\n\nint main() {\n int n, q;\n cin >> n >> q;\n HeavyLightDecomposition G(n);\n vector<vector<pair<int, int>>> g(n);\n for (int i = 0; i < n-1; ++i) {\n int u, v, w;\n scanf(\"%d %d %d\", &u, &v, &w);\n u--; v--;\n G.add_edge(u, v);\n g[u].emplace_back(v, w);\n g[v].emplace_back(u, w);\n }\n G.build();\n vector<int> dep(n);\n auto dfs = [&](int x, int par, auto &&f) -> void {\n for (auto &&e : g[x]) {\n if(e.first != par) {\n dep[e.first] = dep[x] + e.second;\n f(e.first, x, f);\n }\n }\n };\n auto d = [&](int x, int y){ return dep[x] + dep[y] - 2*dep[G.lca(x, y)]; };\n dfs(0, -1, dfs);\n while(q--){\n int a, b, c;\n scanf(\"%d %d %d\", &a, &b, &c);\n a--; b--; c--;\n int x = G.lca(a, G.lca(b, c));\n int ans = INF<int>;\n for (auto &&v : {a, b, c}) {\n int l = 0, r = G.distance(v, x);\n while(r-l > 1){\n int mid = (l+r)/2;\n int u = G.ancestor(v, mid);\n int val = 0;\n for (auto &&i : {a, b, c}) {\n if(i != v) chmax(val, d(u, i));\n }\n if(d(v, u) < val) l = mid;\n else r = mid;\n }\n l = G.ancestor(v, l), r = G.ancestor(v, r);\n chmin(ans, max({d(l, a), d(l, b), d(l, c)}));\n chmin(ans, max({d(r, a), d(r, b), d(r, c)}));\n }\n cout << ans << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 24920, "score_of_the_acc": -0.3337, "final_rank": 2 }, { "submission_id": "aoj_0391_4827348", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nconst int inf = 2012345678;\nclass edge {\npublic:\n\tint to, cost;\n\texplicit edge() : to(-1), cost(0) {};\n\texplicit edge(int to_, int cost_) : to(to_), cost(cost_) {};\n};\nvector<int> solve(int N, int Q, vector<int> A, vector<int> B, vector<int> C, vector<int> X, vector<int> Y, vector<int> Z) {\n\tvector<vector<edge> > G(N);\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tG[A[i]].push_back(edge(B[i], C[i]));\n\t\tG[B[i]].push_back(edge(A[i], C[i]));\n\t}\n\tvector<int> par(N, -1), depth(N), wdepth(N), el(N), er(N);\n\tint current = 0;\n\tfunction<void(int, int)> build_tree = [&](int pos, int pre) {\n\t\tpar[pos] = pre;\n\t\tel[pos] = current++;\n\t\tfor (edge e : G[pos]) {\n\t\t\tif (e.to == pre) continue;\n\t\t\tdepth[e.to] = depth[pos] + 1;\n\t\t\twdepth[e.to] = wdepth[pos] + e.cost;\n\t\t\tbuild_tree(e.to, pos);\n\t\t}\n\t\ter[pos] = current;\n\t};\n\tbuild_tree(0, 0);\n\tint bits = 1;\n\twhile ((1 << bits) < N) ++bits;\n\tvector<vector<int> > p(bits, vector<int>(N));\n\tp[0] = par;\n\tfor (int i = 1; i < bits; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tp[i][j] = p[i - 1][p[i - 1][j]];\n\t\t}\n\t}\n\tfunction<int(int, int)> lca = [&](int x, int y) {\n\t\tif (depth[x] < depth[y]) swap(x, y);\n\t\tfor (int i = bits - 1; i >= 0; --i) {\n\t\t\tif ((depth[x] - depth[y]) >= (1 << i)) {\n\t\t\t\tx = p[i][x];\n\t\t\t}\n\t\t}\n\t\tif (x == y) return x;\n\t\tfor (int i = bits - 1; i >= 0; --i) {\n\t\t\tif (p[i][x] != p[i][y]) {\n\t\t\t\tx = p[i][x];\n\t\t\t\ty = p[i][y];\n\t\t\t}\n\t\t}\n\t\treturn p[0][x];\n\t};\n\tfunction<int(int, int)> dist_lca = [&](int x, int y) {\n\t\treturn wdepth[x] + wdepth[y] - wdepth[lca(x, y)] * 2;\n\t};\n\tfunction<bool(int, int)> is_ancestor = [&](int x, int y) {\n\t\t// check if x is an ancestor of y\n\t\treturn el[x] <= el[y] && er[y] <= er[x];\n\t};\n\tvector<int> ans(Q, inf);\n\tfor (int id = 0; id < Q; ++id) {\n\t\tint xy = lca(X[id], Y[id]);\n\t\tint yz = lca(Y[id], Z[id]);\n\t\tint zx = lca(Z[id], X[id]);\n\t\tvector<int> verts = { X[id], Y[id], Z[id], xy, yz, zx };\n\t\tsort(verts.begin(), verts.end());\n\t\tverts.erase(unique(verts.begin(), verts.end()), verts.end());\n\t\tint S = verts.size();\n\t\tvector<int> spar(S, -1);\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tint ptr = -1;\n\t\t\tfor (int j = 0; j < S; ++j) {\n\t\t\t\tif (i != j && is_ancestor(verts[j], verts[i]) && (ptr == -1 || depth[ptr] < depth[j])) {\n\t\t\t\t\tptr = j;\n\t\t\t\t}\n\t\t\t}\n\t\t\tspar[i] = ptr;\n\t\t}\n\t\tvector<int> farthest(S, -1); // 0 -> X, 1 -> Y, 2 -> Z\n\t\tvector<vector<int> > D(S, vector<int>(3));\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tD[i][0] = dist_lca(X[id], verts[i]);\n\t\t\tD[i][1] = dist_lca(Y[id], verts[i]);\n\t\t\tD[i][2] = dist_lca(Z[id], verts[i]);\n\t\t\tfarthest[i] = max_element(D[i].begin(), D[i].end()) - D[i].begin();\n\t\t\tans[id] = min(ans[id], D[i][farthest[i]]);\n\t\t}\n\t\tfor (int i = 0; i < S; ++i) {\n\t\t\tif (spar[i] == -1 || farthest[i] == farthest[spar[i]]) continue;\n\t\t\tint pos = verts[i], tar = verts[spar[i]];\n\t\t\tint da = D[i][farthest[i]], db = D[i][farthest[spar[i]]];\n\t\t\tfor (int j = bits - 1; j >= 0; --j) {\n\t\t\t\tif (depth[pos] - depth[tar] > (1 << j)) {\n\t\t\t\t\tint npos = p[j][pos];\n\t\t\t\t\tint nda = da - (wdepth[pos] - wdepth[npos]);\n\t\t\t\t\tint ndb = db + (wdepth[pos] - wdepth[npos]);\n\t\t\t\t\tif (nda > ndb) {\n\t\t\t\t\t\tpos = npos;\n\t\t\t\t\t\tda = nda;\n\t\t\t\t\t\tdb = ndb;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tans[id] = min(ans[id], da);\n\t\t\tans[id] = min(ans[id], db + (wdepth[pos] - wdepth[par[pos]]));\n\t\t}\n\t}\n\treturn ans;\n}\nvector<int> solve_easy(int N, int Q, vector<int> A, vector<int> B, vector<int> C, vector<int> X, vector<int> Y, vector<int> Z) {\n\tvector<vector<edge> > G(N);\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tG[A[i]].push_back(edge(B[i], C[i]));\n\t\tG[B[i]].push_back(edge(A[i], C[i]));\n\t}\n\tvector<vector<int> > dist(N, vector<int>(N));\n\tfor (int i = 0; i < N; ++i) {\n\t\tfunction<void(int, int)> calc_dist = [&](int pos, int pre) {\n\t\t\tfor (edge e : G[pos]) {\n\t\t\t\tif (e.to == pre) continue;\n\t\t\t\tdist[i][e.to] = dist[i][pos] + e.cost;\n\t\t\t\tcalc_dist(e.to, pos);\n\t\t\t}\n\t\t};\n\t\tcalc_dist(i, -1);\n\t}\n\tvector<int> ans(Q, inf);\n\tfor (int i = 0; i < Q; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tans[i] = min(ans[i], max({ dist[X[i]][j], dist[Y[i]][j], dist[Z[i]][j] }));\n\t\t}\n\t}\n\treturn ans;\n}\n#include <random>\n#include <string>\nmt19937 mt(2009102116);\nclass disjoint_set {\nprivate:\n\tint N;\n\tvector<int> par;\npublic:\n\tdisjoint_set() : N(0), par() {};\n\tdisjoint_set(int N_) : N(N_), par(N_) {\n\t\tfor (int i = 0; i < N_; ++i) {\n\t\t\tpar[i] = i;\n\t\t}\n\t}\n\tint root(int x) {\n\t\tif (x == par[x]) return x;\n\t\treturn par[x] = root(par[x]);\n\t}\n\tvoid link(int x, int y) {\n\t\tpar[root(x)] = root(y);\n\t}\n\tbool connected(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n};\nstring to_string(vector<int> arr) {\n\tstring res = \"[\";\n\tfor (int i = 0; i < arr.size(); ++i) {\n\t\tif (i) res += \", \";\n\t\tres += to_string(arr[i]);\n\t}\n\tres += \"]\";\n\treturn res;\n}\nint rand_rng(int l, int r) {\n\tuniform_int_distribution<int> p(l, r - 1);\n\treturn p(mt);\n}\nvoid random_gen() {\n\tint repeat = 300000;\n\tfor (int N = 3; N <= 10; ++N) {\n\t\tint Q = 1;\n\t\tfor (int rep = 1; rep <= repeat; ++rep) {\n\t\t\tdisjoint_set uf(N);\n\t\t\tvector<int> A(N - 1), B(N - 1), C(N - 1);\n\t\t\tfor (int i = 0; i < N - 1; ++i) {\n\t\t\t\tdo {\n\t\t\t\t\tA[i] = rand_rng(0, N);\n\t\t\t\t\tB[i] = rand_rng(0, N);\n\t\t\t\t} while (uf.connected(A[i], B[i]));\n\t\t\t\tuf.link(A[i], B[i]);\n\t\t\t\tC[i] = rand_rng(1, 10);\n\t\t\t}\n\t\t\tvector<int> X(Q), Y(Q), Z(Q);\n\t\t\tfor (int i = 0; i < Q; ++i) {\n\t\t\t\tdo {\n\t\t\t\t\tX[i] = rand_rng(0, N);\n\t\t\t\t\tY[i] = rand_rng(0, N);\n\t\t\t\t\tZ[i] = rand_rng(0, N);\n\t\t\t\t} while (X[i] == Y[i] || Y[i] == Z[i] || Z[i] == X[i]);\n\t\t\t}\n\t\t\tvector<int> res1 = solve(N, Q, A, B, C, X, Y, Z);\n\t\t\tvector<int> res2 = solve_easy(N, Q, A, B, C, X, Y, Z);\n\t\t\tif (res1 != res2) {\n\t\t\t\tcout << \"N = \" << N << \" / Case #\" << rep << \":\" << endl;\n\t\t\t\tcout << \"A = \" << to_string(A) << endl;\n\t\t\t\tcout << \"B = \" << to_string(B) << endl;\n\t\t\t\tcout << \"C = \" << to_string(C) << endl;\n\t\t\t\tcout << \"X = \" << to_string(X) << endl;\n\t\t\t\tcout << \"Y = \" << to_string(Y) << endl;\n\t\t\t\tcout << \"Z = \" << to_string(Z) << endl;\n\t\t\t\tcout << \"Returns: \" << to_string(res1) << endl;\n\t\t\t\tcout << \"Answer: \" << to_string(res2) << endl;\n\t\t\t\tcout << endl;\n\t\t\t}\n\t\t}\n\t\tcout << \"N = \" << N << \" Completed!\" << endl;\n\t\tcout << endl;\n\t}\n}\nint main() {\n\t// random_gen();\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, Q;\n\tcin >> N >> Q;\n\tvector<int> A(N - 1), B(N - 1), C(N - 1);\n\tfor (int i = 0; i < N - 1; ++i) {\n\t\tcin >> A[i] >> B[i] >> C[i];\n\t\t--A[i], --B[i];\n\t}\n\tvector<int> X(Q), Y(Q), Z(Q);\n\tfor (int i = 0; i < Q; ++i) {\n\t\tcin >> X[i] >> Y[i] >> Z[i];\n\t\t--X[i], --Y[i], --Z[i];\n\t}\n\tvector<int> res = solve(N, Q, A, B, C, X, Y, Z);\n\tfor (int i = 0; i < Q; ++i) {\n\t\tcout << res[i] << '\\n';\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 31304, "score_of_the_acc": -0.5883, "final_rank": 3 }, { "submission_id": "aoj_0391_4619753", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing UL = unsigned int;\nusing ULL = unsigned long long;\nusing LL = long long;\n#define rep(i, n) for(UL i = 0; i < (n); i++)\n\nUL N, Q;\nUL P[100000][18];\nUL D[100000];\nUL C[100000];\nvector<pair<UL, UL>> E[100000];\n\nUL LCA(UL a, UL b) {\n\tif (C[a] < C[b]) swap(a, b);\n\tUL d = C[a] - C[b];\n\tfor (UL i = 17; i != ~0u; i--) {\n\t\tif ((1u << i) & d) a = P[a][i];\n\t}\n\tif (a == b) return a;\n\tfor (UL i = 17; i != ~0u; i--) {\n\t\tif (P[a][i] == P[b][i]) continue;\n\t\ta = P[a][i]; b = P[b][i];\n\t}\n\treturn P[a][0];\n}\n\npair<UL, UL> MP(UL a, UL b) {\n\tUL X = D[LCA(a, b)];\n\tif (D[a] < D[b]) swap(a, b);\n\tUL Y = D[a] - D[b] + X + X;\n\tfor (UL i = 17; i != ~0u; i--) {\n\t\tif (D[P[a][i]] * 2 <= Y) continue;\n\t\ta = P[a][i];\n\t}\n\tif (X == D[a]) return{ a,a };\n\telse return { a, P[a][0] };\n}\n\nUL Dist(UL a, UL b) {\n\tUL X = D[LCA(a, b)];\n\treturn D[a] + D[b] - X - X;\n}\n\nint main() {\n\tscanf(\"%u%u\", &N, &Q);\n\trep(i, N - 1) {\n\t\tUL u, v, w; scanf(\"%u%u%u\", &u, &v, &w); u--; v--;\n\t\tE[u].push_back({ v, w });\n\t\tE[v].push_back({ u, w });\n\t}\n\t{\n\t\tP[0][0] = 0; D[0] = 0; C[0] = 0;\n\t\tqueue<UL> G; G.push(0);\n\t\twhile (G.size()) {\n\t\t\tUL p = G.front(); G.pop();\n\t\t\tfor (auto& e : E[p]) {\n\t\t\t\tif (P[p][0] == e.first) continue;\n\t\t\t\tP[e.first][0] = p;\n\t\t\t\tD[e.first] = D[p] + e.second;\n\t\t\t\tC[e.first] = C[p] + 1;\n\t\t\t\tG.push(e.first);\n\t\t\t}\n\t\t}\n\t}\n\trep(i, 17) rep(j, N) P[j][i + 1] = P[P[j][i]][i];\n\n\trep(q, Q) {\n\t\tUL a, b, c; scanf(\"%u%u%u\", &a, &b, &c); a--; b--; c--;\n\t\tUL ans = ~0u;\n\t\trep(t, 3) {\n\t\t\tauto mp = MP(a, b);\n\t\t\tUL q1 = max(max(Dist(mp.first, a), Dist(mp.first, b)), Dist(mp.first, c));\n\t\t\tUL q2 = max(max(Dist(mp.second, a), Dist(mp.second, b)), Dist(mp.second, c));\n\t\t\tans = min(ans, min(q1, q2));\n\t\t\tswap(a, b); swap(b, c);\n\t\t}\n\t\tprintf(\"%u\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 17116, "score_of_the_acc": -0.1626, "final_rank": 1 }, { "submission_id": "aoj_0391_3982864", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nstruct edge{ int to,cost; };\nint N,Q;\n\nvector<edge> G[100005];\n\nint parent[100005];\nint depth[100005];\nint dist[100005];\n\nint p[30][100005];\nvoid dfs(int pos,int prev,int Depth,int Dist){\n parent[pos]=prev;\n depth[pos]=Depth;\n dist[pos]=Dist;\n for(int i=0;i<(int)G[pos].size();i++){\n edge e=G[pos][i];\n if(e.to==prev)continue;\n dfs(e.to,pos,Depth+1,Dist+e.cost);\n }\n}\n\nint lca(int a,int b){\n if(depth[a]>depth[b])swap(a,b);\n \n int s=(depth[b]-depth[a]);\n for(int i=0;i<30;i++)\n if(s>>i&1)\n b=p[i][b];\n \n if(a==b)return a;\n \n for(int i=29;i>=0;i--){\n if( p[i][a] != p[i][b] ){\n a=p[i][a];\n b=p[i][b];\n }\n }\n return parent[a];\n}\n\nint calc_dist(int a,int b){\n int c=lca(a,b);\n return dist[a]-dist[c]+dist[b]-dist[c];\n}\n\nint check(int p,int a,int b,int c){\n int res=0;\n res=max(res, calc_dist(p,a));\n res=max(res, calc_dist(p,b));\n res=max(res, calc_dist(p,c));\n return res;\n}\n\nint solve(int a,int b,int c){\n int x=lca(b,c);\n if( calc_dist(x,b) > calc_dist(x,c) )swap(b,c);\n \n int y=calc_dist(b,c)/2;\n int z=c;\n for(int i=29;i>=0;i--){\n int nz=p[i][z];\n if(nz!=-1 && (dist[c]-dist[nz]) <= y){\n z=nz;\n }\n }\n \n int res=check(z,a,b,c);\n if( parent[z]!=-1 )\n res=min(res,check(parent[z],a,b,c));\n return res;\n}\n\nint main(){\n scanf(\"%d %d\",&N,&Q);\n for(int i=0;i<N-1;i++){\n int u,v,w;\n scanf(\"%d %d %d\",&u,&v,&w);\n u--;\n v--;\n G[u].push_back( (edge){v,w} );\n G[v].push_back( (edge){u,w} );\n \n }\n \n dfs(0,-1,0,0);\n\n for(int i=0;i<N;i++)\n p[0][i]=parent[i];\n\n for(int i=1;i<30;i++){\n for(int j=0;j<N;j++){\n int x=p[i-1][j];\n if(x!=-1)x=p[i-1][x];\n p[i][j]=x;\n }\n }\n\n for(int i=0;i<Q;i++){\n int a,b,c;\n scanf(\"%d %d %d\",&a,&b,&c);\n a--;\n b--;\n c--;\n int ans=(1<<30);\n ans=min(ans, solve(a,b,c) );\n ans=min(ans, solve(b,a,c) );\n ans=min(ans, solve(c,a,b) );\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 520, "memory_kb": 27844, "score_of_the_acc": -0.6489, "final_rank": 4 }, { "submission_id": "aoj_0391_3982862", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nstruct edge{ int to,cost; };\nint N,Q;\n\nvector<edge> G[100005];\n\nint parent[100005];\nint depth[100005];\nint dist[100005];\n\nint p[30][100005];\nvoid dfs(int pos,int prev,int Depth,int Dist){\n parent[pos]=prev;\n depth[pos]=Depth;\n dist[pos]=Dist;\n for(int i=0;i<(int)G[pos].size();i++){\n edge e=G[pos][i];\n if(e.to==prev)continue;\n dfs(e.to,pos,Depth+1,Dist+e.cost);\n }\n}\n\nint lca(int a,int b){\n if(depth[a]>depth[b])swap(a,b);\n \n int s=(depth[b]-depth[a]);\n for(int i=0;i<30;i++)\n if(s>>i&1)\n b=p[i][b];\n \n if(a==b)return a;\n \n for(int i=29;i>=0;i--){\n if( p[i][a] != p[i][b] ){\n a=p[i][a];\n b=p[i][b];\n }\n }\n return parent[a];\n}\n\nint calc_dist(int a,int b){\n int c=lca(a,b);\n return dist[a]-dist[c]+dist[b]-dist[c];\n}\n\nint check(int p,int a,int b,int c){\n int res=0;\n res=max(res, calc_dist(p,a));\n res=max(res, calc_dist(p,b));\n res=max(res, calc_dist(p,c));\n return res;\n}\n\nint solve(int a,int b,int c){\n int x=lca(b,c);\n if( calc_dist(x,b) > calc_dist(x,c) )swap(b,c);\n \n int y=calc_dist(b,c)/2;\n int z=c;\n for(int i=29;i>=0;i--){\n int nz=p[i][z];\n if(nz!=-1 && calc_dist(c,nz) <= y){\n z=nz;\n }\n }\n \n int res=check(z,a,b,c);\n if( parent[z]!=-1 )\n res=min(res,check(parent[z],a,b,c));\n return res;\n}\n\nint main(){\n scanf(\"%d %d\",&N,&Q);\n for(int i=0;i<N-1;i++){\n int u,v,w;\n scanf(\"%d %d %d\",&u,&v,&w);\n u--;\n v--;\n G[u].push_back( (edge){v,w} );\n G[v].push_back( (edge){u,w} );\n \n }\n \n dfs(0,-1,0,0);\n\n for(int i=0;i<N;i++)\n p[0][i]=parent[i];\n\n for(int i=1;i<30;i++){\n for(int j=0;j<N;j++){\n int x=p[i-1][j];\n if(x!=-1)x=p[i-1][x];\n p[i][j]=x;\n }\n }\n\n for(int i=0;i<Q;i++){\n int a,b,c;\n scanf(\"%d %d %d\",&a,&b,&c);\n a--;\n b--;\n c--;\n int ans=(1<<30);\n ans=min(ans, solve(a,b,c) );\n ans=min(ans, solve(b,a,c) );\n ans=min(ans, solve(c,a,b) );\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 710, "memory_kb": 27876, "score_of_the_acc": -0.8042, "final_rank": 9 }, { "submission_id": "aoj_0391_3950897", "code_snippet": "#define PROBLEM \"http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0391\"\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define call_from_test\n#ifndef call_from_test\n#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\n#endif\n//BEGIN CUT HERE\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n//END CUT HERE\n#ifndef call_from_test\nsigned main(){\n return 0;\n}\n#endif\n\n#ifndef call_from_test\n#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\n#endif\n//BEGIN CUT HERE\nstruct LCA{\n const int lg = 12;\n const int sz = 1<<lg;\n const int ms = sz-1;\n int n;\n vector<int> P,D,E,A,B,T,ht;\n vector<vector<int> > G,dat;\n LCA(int n):\n n(n),P(n,-1),D(n),E(n*2,0),A(n*2,-1),B(n*2/lg+1),T(sz,0),G(n){}\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n void dfs(int v,int p,int d){\n int k=0,u;\n vector<int> iter(n,0);\n\n using T = tuple<int, int, int>;\n stack<T> st;\n\n START:\n D[v]=k;\n A[k]=P[v]=p;\n E[k++]=d;\n for(;iter[v]<(int)G[v].size();iter[v]++){\n u=G[v][iter[v]];\n if(u==p) continue;\n st.emplace(v,p,d);\n p=v;v=u;d=d+1;\n goto START;\n END:\n tie(v,p,d)=st.top();st.pop();\n }\n\n A[k]=P[v];\n E[k++]=d-1;\n\n if(!st.empty()) goto END;\n }\n\n // if it need leftmost, then add: if(E[i]==E[j]) return i<j?i:j;\n inline int comp(int i,int j){return E[i]<E[j]?i:j;};\n inline int comp(int i,int j,int k){return comp(comp(i,j),k);};\n\n void build(int r=0){\n dfs(r,-1,1);\n\n B[0]=1;\n for(int i=1;i<n*2;i++) B[i/lg]|=(E[i-1]<E[i])<<(i%lg);\n\n for(int b=0;b<sz;b++){\n int e=0,w=1,&x=T[b];\n for(int i=0;i<lg;i++){\n if((b>>i)&1) e++;\n else e--;\n if(e<w) e=w,x=i;\n }\n }\n\n int m=(n*2+lg-1)/lg;\n int h=1;\n while((1<<h)<m) h++;\n dat.assign(h,vector<int>(m,-1));\n ht.assign(m+1,0);\n for(int j=2;j<=m;j++) ht[j]=ht[j>>1]+1;\n\n for(int j=0;j<n*2;j++){\n if(dat[0][j/lg]<0) dat[0][j/lg]=j;\n dat[0][j/lg]=comp(dat[0][j/lg],j);\n }\n\n for(int i=1,p=1;i<h;i++,p<<=1)\n for(int j=0;j<m;j++)\n dat[i][j]=comp(dat[i-1][j],dat[i-1][min(j+p,m-1)]);\n }\n\n inline int cs(int a,int b){\n int l=b-a;\n return comp(dat[ht[l]][a],dat[ht[l]][b-(1<<ht[l])]);\n }\n\n inline int es(int i,int l,int r){\n int x=r-i*lg+1,y=l-i*lg;\n int b=(((B[i]|(ms<<x))>>y)|(ms<<(lg-y)))&ms;\n return l+T[b];\n }\n\n inline int ls(int i,int l){\n int k=l-i*lg;\n int b=((B[i]>>k)|(ms<<(lg-k)))&ms;\n return l+T[b];\n }\n\n inline int rs(int j,int r){\n int k=r-j*lg+1;\n int b=(B[j]|(ms<<k))&ms;\n return j*lg+T[b];\n }\n\n inline int rmq(int l,int r){\n int i=l/lg,j=r/lg;\n if(i==j) return es(i,l,r);\n if(i+1==j) return comp(ls(i,l),rs(j,r));\n return comp(ls(i,l),cs(i+1,j),rs(j,r));\n }\n\n int lca(int l,int r){\n if(l==r) return l;\n if(D[l]>D[r]) swap(l,r);\n int x=D[l],y=D[r];\n int m=rmq(x,y);\n return m==x?l:A[m];\n }\n};\n//END CUT HERE\n#ifndef call_from_test\n//INSERT ABOVE HERE\nsigned main(){\n return 0;\n}\n#endif\n\n#ifndef call_from_test\n#include<bits/stdc++.h>\nusing namespace std;\n#endif\n//BEGIN CUT HERE\nstruct LevelAncestor{\n int n,h;\n vector<vector<int> > G,par,lad;\n vector<int> dep,nxt,len,pth,ord,hs;\n LevelAncestor(){}\n LevelAncestor(int n):\n n(n),G(n),dep(n),nxt(n,-1),len(n),pth(n),ord(n),hs(n+1,0){\n h=1;\n while((1<<h)<=n) h++;\n par.assign(h,vector<int>(n,-1));\n for(int i=2;i<=n;i++) hs[i]=hs[i>>1]+1;\n }\n\n void add_edge(int u,int v){\n G[u].emplace_back(v);\n G[v].emplace_back(u);\n }\n\n void dfs(int v,int p,int d,int f){\n if(nxt[v]<0){\n par[0][nxt[v]=v]=p;\n len[v]=dep[v]=d;\n for(int u:G[v]){\n if(u==p) continue;\n dfs(u,v,d+1,0);\n if(len[v]<len[u]) nxt[v]=u,len[v]=len[u];\n }\n }\n if(!f) return;\n pth[v]=lad.size();\n lad.emplace_back();\n for(int k=v;;k=nxt[k]){\n lad.back().emplace_back(k);\n pth[k]=pth[v];\n if(k==nxt[k]) break;\n }\n for(;;p=v,v=nxt[v]){\n for(int u:G[v])\n if(u!=p&&u!=nxt[v]) dfs(u,v,d+1,1);\n if(v==nxt[v]) break;\n }\n }\n\n void build(int r=0){\n dfs(r,-1,0,1);\n for(int k=0;k+1<h;k++){\n for(int v=0;v<n;v++){\n if(par[k][v]<0) par[k+1][v]=-1;\n else par[k+1][v]=par[k][par[k][v]];\n }\n }\n for(int i=0;i<(int)lad.size();i++){\n int v=lad[i][0],p=par[0][v];\n if(~p){\n int k=pth[p],l=min(ord[p]+1,(int)lad[i].size());\n lad[i].resize(l+lad[i].size());\n for(int j=0,m=lad[i].size();j+l<m;j++)\n lad[i][m-(j+1)]=lad[i][m-(j+l+1)];\n for(int j=0;j<l;j++)\n lad[i][j]=lad[k][ord[p]-l+j+1];\n }\n for(int j=0;j<(int)lad[i].size();j++)\n if(pth[lad[i][j]]==i) ord[lad[i][j]]=j;\n }\n }\n\n int lca(int u,int v){\n if(dep[u]>dep[v]) swap(u,v);\n for(int k=0;k<h;k++){\n if((dep[v]-dep[u])>>k&1){\n v=par[k][v];\n }\n }\n if(u==v) return u;\n for(int k=h-1;k>=0;k--){\n if(par[k][u]!=par[k][v]){\n u=par[k][u];\n v=par[k][v];\n }\n }\n return par[0][u];\n }\n\n int up(int v,int d){\n if(d==0) return v;\n v=par[hs[d]][v];\n d-=1LL<<hs[d];\n return lad[pth[v]][ord[v]-d];\n }\n\n int distance(int u,int v){\n return dep[u]+dep[v]-dep[lca(u,v)]*2;\n }\n};\n//END CUT HERE\n#ifndef call_from_test\n//INSERT ABOVE HERE\nchar buf[256];\nsigned solve(){\n using ll = long long;\n int n;\n scanf(\"%d\",&n);\n using P = pair<int, int>;\n vector<vector<P> > G(n);\n LevelAncestor la(n);\n for(int i=1;i<n;i++){\n int a,b,c;\n scanf(\"%d %d %d\",&a,&b,&c);\n a--;b--;\n la.add_edge(a,b);\n G[a].emplace_back(b,c);\n G[b].emplace_back(a,c);\n }\n la.build();\n\n vector<ll> dep(n,0);\n {\n queue<P> q;\n q.emplace(0,-1);\n while(!q.empty()){\n int v,p;\n tie(v,p)=q.front();q.pop();\n for(auto e:G[v]){\n int u,c;\n tie(u,c)=e;\n if(u==p) continue;\n dep[u]=dep[v]+c;\n q.emplace(u,v);\n }\n }\n }\n\n while(scanf(\"%s\",buf)){\n string s(buf);\n if(s==\"DONE\"s) break;\n if(s==\"DIST\"s){\n int a,b;\n scanf(\"%d %d\",&a,&b);\n a--;b--;\n printf(\"%lld\\n\",dep[a]+dep[b]-2*dep[la.lca(a,b)]);\n }\n if(s==\"KTH\"s){\n int a,b,k;\n scanf(\"%d %d %d\",&a,&b,&k);\n a--;b--;k--;\n int l=la.lca(a,b);\n int x=la.distance(a,l),y=la.distance(l,b);\n assert(0<=k&&k<=x+y);\n printf(\"%d\\n\",(k<=x?la.up(a,k):la.up(b,x+y-k))+1);\n }\n }\n return 0;\n}\n\nsigned SPOJ_QTREE2(){\n int t;\n scanf(\"%d\",&t);\n for(int i=0;i<t;i++) solve();\n return 0;\n}\n/*\n verified on 2019/10/25\n https://www.spoj.com/problems/QTREE2/\n*/\n\nsigned main(){\n SPOJ_QTREE2();\n return 0;\n}\n#endif\n\n#undef call_from_test\n\nsigned main(){\n int n,q;\n scanf(\"%d %d\",&n,&q);\n using P = pair<int, int>;\n vector<vector<P> > G(n);\n LCA lca(n);\n LevelAncestor la(n);\n for(int i=1;i<n;i++){\n int u,v,w;\n scanf(\"%d %d %d\",&u,&v,&w);\n u--;v--;\n lca.add_edge(u,v);\n la.add_edge(u,v);\n G[u].emplace_back(v,w);\n G[v].emplace_back(u,w);\n }\n\n lca.build();\n la.build();\n\n vector<int> dep(n,0);\n {\n queue<P> q;\n q.emplace(0,-1);\n while(!q.empty()){\n int v,p;\n tie(v,p)=q.front();q.pop();\n for(auto e:G[v]){\n int u,c;\n tie(u,c)=e;\n if(u==p) continue;\n dep[u]=dep[v]+c;\n q.emplace(u,v);\n }\n }\n }\n\n auto dist=[&](int u,int v){return dep[u]+dep[v]-2*dep[lca.lca(u,v)];};\n auto path=\n [&](int u,int v,int d){\n if(d==0) return u;\n int r=lca.lca(u,v);\n int x=la.distance(u,r),y=la.distance(r,v);\n if(d<=x) return la.up(u,d);\n return la.up(v,(x+y)-d);\n };\n\n for(int i=0;i<q;i++){\n int a,b,c;\n scanf(\"%d %d %d\",&a,&b,&c);\n a--;b--;c--;\n auto calc=\n [&](int v,int u=-1){\n return max({dist(a,v)*(a!=u),\n dist(b,v)*(b!=u),\n dist(c,v)*(c!=u)});\n };\n\n int p=lca.lca(a,b),q=lca.lca(b,c),r=lca.lca(c,a);\n int v=la.dep[p]>la.dep[q]?p:(la.dep[q]>la.dep[r]?q:r);\n\n int ans=min({calc(a),calc(b),calc(c),calc(v)});\n for(int u:{a,b,c}){\n if(calc(v,u)>=ans) continue;\n int l=0,r=la.distance(u,v);\n while(l+1<r){\n int m=(l+r)>>1;\n int x=path(u,v,m);\n if(calc(x,u)<dist(x,u)) r=m;\n else l=m;\n }\n chmin(ans,calc(path(u,v,l)));\n chmin(ans,calc(path(u,v,r)));\n }\n printf(\"%d\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 37212, "score_of_the_acc": -0.8543, "final_rank": 10 } ]
aoj_0399_cpp
Payroll PCK company has $N$ salaried staff and they have specific ID numbers that run from $0$ to $N-1$. The company provides $N$ types of work that are also identified by ID numbers from $0$ to $N-1$. The time required to complete work $j$ is $t_j$. To get each of the working staff to learn as many types of work as possible, the company shifts work assignment in the following fashion. On the $d$-th day of a shift (the first day is counted as $0$th day), work $j$ is assigned to the staff $(j + d) \% N$, where the notation $p \% q$ indicates the remainder when $p$ is divided by $q$. Salaries in the PCK company are paid on a daily basis based on the hourly rate. When a staff whose hourly rate is $a$ carries out work $j$, his/her salary will amount to $a \times t_j$. The initial hourly rate for a staff $i$ is $s_i$ yen. To boost staff’s motivation, the company employs a unique scheme for raising hourly rates. The promotion scheme table of the company contains a list of factors $f_k$ ($0 \leq k \leq M-1$), and the hourly rate of a staff is raised based on the following rule. At the completion of the $d$-th day’s work (the first day is counted as the $0$th day), the hourly rate of the staff with ID number $d \% N$ is raised by $f_{(d \% M)}$ yen. The salary raise takes effect after the day’s pay has been made. As the person in charge of accounting in PCK company, you have to calculate the total amount of pay for $D$ days from the $0$-th day. Make a program to work out the total amount of salary given the following information: initial hourly rate of each staff, hours required to complete a job, a table of promotion coefficients, and the number of days. Because the total may become excessively large, report the remainder when the total salary amount is divided by $1,000,000,007(= 10^9 + 7)$. Input The input is given in the following format. $N$ $M$ $D$ $s_0$ $s_1$ $...$ $s_{N-1}$ $t_0$ $t_1$ $...$ $t_{N-1}$ $f_0$ $f_1$ $...$ $f_{M-1}$ The first line provides the number of working staff and types of work $N$ ($1 \leq N \leq 100$), the number of factors $M$ ($1 \leq M \leq 100$)and the number of days $D$ ($1 \leq D \leq 10^{15}$). Note that $M + N$ is equal to or less than 100. The second line provides the initial hourly rate for each staff $s_i$ ($1 \leq s_i \leq 10^8$) as integers. The third line provides the hours $t_j$ ($1 \leq t_j \leq 10^8$) required to complete each type of job as integers. The fourth line lists the factors $f_k$ ($1 \leq f_k \leq 10^8$) in the promotion scheme table. Output Output the total amount of the salary. Sample Input 1 3 2 2 3 2 1 1 2 3 1 2 Sample Output 1 26 Sample Input 2 3 2 5 3 2 1 1 2 3 1 2 Sample Output 2 91
[ { "submission_id": "aoj_0399_6039851", "code_snippet": "#ifdef LOGX\n#define _GLIBCXX_DEBUG\n#endif\n#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll=long long;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep2(i,s,n) for(int i=int(s);i<(int)(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define vv vector\nconst int big=1e9+7;\n//const int big=998244353;\nconst char newl='\\n';\nconst int inf=1e9+10;\nconst ll INF=ll(1e18)+10;\nconst int dx[]={1,0,-1,0};\nconst int dy[]={0,1,0,-1};\n\nstruct mint{\n ll x;\n mint(ll xx=0):x(xx){\n x%=big;\n if(x<0)x+=big;\n }\n mint& operator+=(mint r){\n x+=r.x;\n if(x>=big)x-=big;\n return *this;\n }\n mint& operator*=(mint r){\n x*=r.x;\n x%=big;\n return *this;\n }\n friend mint operator+(mint l,mint r){\n l+=r;\n return l;\n }\n friend mint operator*(mint l,mint r){\n return l*=r;\n }\n friend ostream& operator<<(ostream &os,const mint &r){\n os << r.x;\n return os;\n }\n};\n\ntemplate<typename T>\nstruct matrix{\n int n;\n vector<vector<T>> vec;\n matrix(int nn):n(nn),vec(nn,vector<T>(nn)){}\n friend matrix<T> operator*(const matrix &l,const matrix &r){\n matrix<T> res(l.n);\n /*\n rep(i,l.n)rep(k,l.n)rep(j,l.n){\n res.vec[i][j]+=l.vec[i][k]*r.vec[k][j];\n }\n */\n const int n=l.n-2;\n rep(i,n+1)rep(k,l.n){\n res.vec[i][n+1]+=l.vec[i][k]*r.vec[k][n+1];\n }\n rep(j,n)rep(k,l.n){\n res.vec[n][j]+=l.vec[n][k]*r.vec[k][j];\n }\n rep(j,l.n)res.vec[j][j]=1;\n return res;\n }\n friend vector<T> operator*(const matrix &l,const vector<T> &r){\n vector<T> res(l.n);\n rep(i,l.n)rep(j,l.n){\n res[i]+=l.vec[i][j]*r[j];\n }\n return res;\n }\n};\n\ntemplate<typename T>\nT exp(T x,ll y,const T e){\n T res=e;\n while(y){\n if(y&1)res=res*x;\n x=x*x;\n y>>=1;\n }\n return res;\n}\n\nint lcm(int a,int b){\n return a/__gcd(a,b)*b;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(30);\n\n int n,m;\n ll d;\n cin >> n >> m >> d;\n vector<mint> s(n);\n rep(i,n)cin >> s[i].x;\n vector<int> t(n);\n rep(i,n)cin >> t[i];\n vector<int> f(m);\n rep(i,m)cin >> f[i];\n vector<matrix<mint>> vec(lcm(n,m),matrix<mint>(n+2));\n //vec[i]:i日目開始時からi日目終了時への遷移\n rep(i,lcm(n,m)){\n rep(j,n+2)vec[i].vec[j][j]=1;\n vec[i].vec[i%n][n+1]=f[i%m];\n rep(j,n)vec[i].vec[n][(j+i)%n]=t[j];\n }\n matrix<mint> res(n+2);\n rep(i,n+2)res.vec[i][i]=1;\n auto all_prod=res,rem=res;\n rep(i,vec.size()){\n all_prod=vec[i]*all_prod;\n if(i+1==d%vec.size())rem=all_prod;\n }\n res=rem*exp(all_prod,d/vec.size(),res);\n\n s.resize(n+2);\n s[n]=0;\n s[n+1]=1;\n s=res*s;\n cout << s[n].x << newl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 60408, "score_of_the_acc": -0.3903, "final_rank": 2 }, { "submission_id": "aoj_0399_5036077", "code_snippet": "#line 1 \"a.cpp\"\n#include<iostream>\nusing namespace std;\n#line 3 \"/home/kotatsugame/library/math/modint.cpp\"\n#include<utility>\ntemplate<int m>\nstruct modint{\n\tunsigned int x;\n\tconstexpr modint()noexcept:x(){}\n\ttemplate<typename T>\n\tconstexpr modint(T x_)noexcept:x((x_%=m)<0?x_+m:x_){}\n\tconstexpr unsigned int val()const noexcept{return x;}\n\tconstexpr modint&operator++()noexcept{if(++x==m)x=0;return*this;}\n\tconstexpr modint&operator--()noexcept{if(x==0)x=m;--x;return*this;}\n\tconstexpr modint operator++(int)noexcept{modint res=*this;++*this;return res;}\n\tconstexpr modint operator--(int)noexcept{modint res=*this;--*this;return res;}\n\tconstexpr modint&operator+=(const modint&a)noexcept{x+=a.x;if(x>=m)x-=m;return*this;}\n\tconstexpr modint&operator-=(const modint&a)noexcept{if(x<a.x)x+=m;x-=a.x;return*this;}\n\tconstexpr modint&operator*=(const modint&a)noexcept{x=(unsigned long long)x*a.x%m;return*this;}\n\tconstexpr modint&operator/=(const modint&a)noexcept{return*this*=a.inv();}\n\tconstexpr modint operator+()const noexcept{return*this;}\n\tconstexpr modint operator-()const noexcept{return modint()-*this;}\n\tconstexpr modint pow(long long n)const noexcept\n\t{\n\t\tif(n<0)return pow(-n).inv();\n\t\tmodint x=*this,r=1;\n\t\tfor(;n;x*=x,n>>=1)if(n&1)r*=x;\n\t\treturn r;\n\t}\n\tconstexpr modint inv()const noexcept\n\t{\n\t\tint s=x,t=m,x=1,u=0;\n\t\twhile(t)\n\t\t{\n\t\t\tint k=s/t;\n\t\t\ts-=k*t;\n\t\t\tswap(s,t);\n\t\t\tx-=k*u;\n\t\t\tswap(x,u);\n\t\t}\n\t\treturn modint(x);\n\t}\n\tfriend constexpr modint operator+(const modint&a,const modint&b){return modint(a)+=b;}\n\tfriend constexpr modint operator-(const modint&a,const modint&b){return modint(a)-=b;}\n\tfriend constexpr modint operator*(const modint&a,const modint&b){return modint(a)*=b;}\n\tfriend constexpr modint operator/(const modint&a,const modint&b){return modint(a)/=b;}\n\tfriend constexpr bool operator==(const modint&a,const modint&b){return a.x==b.x;}\n\tfriend constexpr bool operator!=(const modint&a,const modint&b){return a.x!=b.x;}\n\tfriend ostream&operator<<(ostream&os,const modint&a){return os<<a.x;}\n\tfriend istream&operator>>(istream&is,modint&a){long long v;is>>v;a=modint(v);return is;}\n};\n#line 4 \"a.cpp\"\nusing mint=modint<(int)1e9+7>;\nstruct dat{\n\tmint coef,diff,plus;\n\tdat(){}\n\tdat(mint a,mint b,mint c):coef(a),diff(b),plus(c){}\n\tdat operator+(const dat&rhs)const{\n\t\treturn dat(coef+rhs.coef,diff+rhs.diff+plus*rhs.coef,plus+rhs.plus);\n\t}\n};\nint N,M;\nlong D;\nmint s[100],t[100],f[100];\ndat dp[50][100][2500];\nmain()\n{\n\tcin>>N>>M>>D;\n\tfor(int i=0;i<N;i++)cin>>s[i];\n\tfor(int i=0;i<N;i++)cin>>t[i];\n\tfor(int i=0;i<M;i++)cin>>f[i];\n\tfor(int i=0;i<N;i++)for(int j=0;j<N*M;j++)\n\t{\n\t\tdp[0][i][j]=dat(t[((i-j)%N+N)%N],0,(j%N==i?f[j%M]:0));\n\t}\n\tfor(int k=1;k<50;k++)for(int i=0;i<N;i++)for(int j=0;j<N*M;j++)\n\t{\n\t\tint j2=(j+(1LL<<k-1))%(N*M);\n\t\tdp[k][i][j]=dp[k-1][i][j]+dp[k-1][i][j2];\n\t}\n\tmint ans=0;\n\tfor(int i=0;i<N;i++)\n\t{\n\t\tint st=0;\n\t\tmint S=s[i];\n\t\tfor(int k=0;k<50;k++)if(D>>k&1)\n\t\t{\n\t\t\tdat now=dp[k][i][st];\n\t\t\tst=(st+(1LL<<k))%(N*M);\n\t\t\tans+=now.diff+S*now.coef;\n\t\t\tS+=now.plus;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 149604, "score_of_the_acc": -1.3158, "final_rank": 7 }, { "submission_id": "aoj_0399_4912415", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate <u32 M>\nstruct modint {\n u32 val;\npublic:\n static modint raw(int v) { modint x; x.val = v; return x; }\n modint() : val(0) {}\n template <class T>\n modint(T v) { ll x = (ll)(v%(ll)(M)); if (x < 0) x += M; val = u32(x); }\n modint(bool v) { val = ((unsigned int)(v) % M); }\n modint& operator++() { val++; if (val == M) val = 0; return *this; }\n modint& operator--() { if (val == 0) val = M; val--; return *this; }\n modint operator++(int) { modint result = *this; ++*this; return result; }\n modint operator--(int) { modint result = *this; --*this; return result; }\n modint& operator+=(const modint& b) { val += b.val; if (val >= M) val -= M; return *this; }\n modint& operator-=(const modint& b) { val -= b.val; if (val >= M) val += M; return *this; }\n modint& operator*=(const modint& b) { u64 z = val; z *= b.val; val = (u32)(z % M); return *this; }\n modint& operator/=(const modint& b) { return *this = *this * b.inv(); }\n modint operator+() const { return *this; }\n modint operator-() const { return modint() - *this; }\n modint pow(long long n) const { modint x = *this, r = 1; while (n) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; }\n modint inv() const { return pow(M-2); }\n friend modint operator+(const modint& a, const modint& b) { return modint(a) += b; }\n friend modint operator-(const modint& a, const modint& b) { return modint(a) -= b; }\n friend modint operator*(const modint& a, const modint& b) { return modint(a) *= b; }\n friend modint operator/(const modint& a, const modint& b) { return modint(a) /= b; }\n friend bool operator==(const modint& a, const modint& b) { return a.val == b.val; }\n friend bool operator!=(const modint& a, const modint& b) { return a.val != b.val; }\n};\nusing mint = modint<MOD>;\n\ntemplate<class H, size_t SIZE>\nstruct SquareMatrix {\n using T = typename H::T;\n using ar = array<T, SIZE>;\n using mat = array<ar, SIZE>;\n mat A;\n SquareMatrix() = default;\n static SquareMatrix I(){\n SquareMatrix X;\n for (int i = 0; i < SIZE; ++i) {\n for (int j = 0; j < SIZE; ++j) {\n if(i == j) X[i][j] = H::one();\n else X[i][j] = H::zero();\n }\n }\n return X;\n }\n\n friend ar operator*=(ar &x, const SquareMatrix &Y) {\n ar ans{};\n for (int i = 0; i < SIZE; ++i) {\n for (int j = 0; j < SIZE; ++j) {\n H::add(ans[j], H::mul(x[i], Y[i][j]));\n }\n }\n x.swap(ans);\n return x;\n }\n friend ar operator*(ar x, const SquareMatrix &Y) { return x *= Y; }\n\n inline const ar &operator[](int k) const{ return (A.at(k)); }\n inline ar &operator[](int k) { return (A.at(k)); }\n SquareMatrix &operator+= (const SquareMatrix &B){\n for (int i = 0; i < SIZE; ++i) {\n for (int j = 0; j < SIZE; ++j) {\n H::add((*this)[i][j], B[i][j]);\n }\n }\n return (*this);\n }\n\n SquareMatrix &operator-= (const SquareMatrix &B){\n for (int i = 0; i < SIZE; ++i) {\n for (int j = 0; j < SIZE; ++j) {\n H::add((*this)[i][j], -B[i][j]);\n }\n }\n return (*this);\n }\n\n SquareMatrix &operator*=(const SquareMatrix &B) {\n SquareMatrix C;\n for (int i = 0; i < SIZE; ++i) {\n for (int k = 0; k < SIZE; ++k) {\n for (int j = 0; j < SIZE; ++j) {\n H::add(C[i][j], H::mul((*this)[i][k], B[k][j]));\n }\n }\n }\n A.swap(C.A);\n return (*this);\n }\n\n SquareMatrix pow(ll n) const {\n SquareMatrix a = (*this), res = I();\n while(n > 0){\n if(n & 1) res *= a;\n a *= a;\n n >>= 1;\n }\n return res;\n }\n SquareMatrix operator+(const SquareMatrix &B) const {return SquareMatrix(*this) += B;}\n SquareMatrix operator-(const SquareMatrix &B) const {return SquareMatrix(*this) -= B;}\n SquareMatrix operator*(const SquareMatrix &B) const {return SquareMatrix(*this) *= B;}\n};\n\nstruct SemiRing {\n using T = mint;\n static inline T mul(T x, T y){ return x * y; }\n static inline void add(T &x, T y){ x += y; }\n static inline T one(){ return 1; }\n static inline T zero(){ return 0; }\n};\n\nusing ar = array<SemiRing::T, 101>;\nusing mat = SquareMatrix<SemiRing, 101>;\n\nar x;\nmat A;\nint main() {\n int n, m; ll d;\n cin >> n >> m >> d;\n vector<int> s(n), t(n), f(m);\n for (auto &&i : s) scanf(\"%d\", &i);\n for (auto &&i : t) scanf(\"%d\", &i);\n for (auto &&i : f) scanf(\"%d\", &i);\n A[0][0] = 1;\n for (int i = 0; i < n; ++i) x[i+1] = s[i], A[i+1][0] = t[i], A[i+1][(i+n-1)%n+1] = 1;\n for (int i = 0; i < m; ++i) x[n+i+1] = f[i], A[n+i+1][(i+m-1)%m+n+1] = 1;\n A[n+1][n] = 1;\n A = A.pow(d);\n cout << (x*A)[0].val << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3688, "score_of_the_acc": -0.1605, "final_rank": 1 }, { "submission_id": "aoj_0399_4857594", "code_snippet": "#include<bits/stdc++.h>\n#include<array>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\n#define rep(i,n) for(int i=0; i<(n); i++)\n\nconst ULL M = 1000000007;\n\nconst int MatSz = 120;\nstruct Mat {\n ULL G[MatSz][MatSz] = {};\n static Mat I() {\n Mat buf;\n rep(i, MatSz) buf.G[i][i] = 1;\n return buf;\n }\n};\n\nMat operator*(const Mat& l, const Mat& r) {\n Mat res;\n rep(i, MatSz) rep(j, MatSz) {\n rep(k, MatSz) res.G[i][j] += l.G[i][k] * r.G[k][j] % M;\n res.G[i][j] %= M;\n }\n return res;\n}\nMat operator^(const Mat& a, const ULL i) {\n if (i == 0) return Mat::I();\n Mat buf = (a * a) ^ (i / 2);\n if (i % 2) buf = buf * a;\n return buf;\n}\n\nusing Vec = array<ULL, MatSz>;\n\nVec operator*(const Vec& l, const Mat& r) {\n Vec res = {};\n rep(i, MatSz) {\n rep(j, MatSz) res[i] += l[j] * r.G[i][j] % M;\n res[i] %= M;\n }\n return res;\n}\n\nint main() {\n int N, M; ULL D; cin >> N >> M >> D;\n ULL S[100]; rep(i, N) cin >> S[i];\n ULL T[100]; rep(i, N) cin >> T[i];\n ULL F[100]; rep(i, M) cin >> F[i];\n\n Mat R;\n rep(i, N) R.G[i][(i + 1) % N] = 1;\n rep(i, M) R.G[N + i][N + (i + 1) % M] = 1;\n R.G[N - 1][N] = 1;\n R.G[N + M][N + M] = 1;\n rep(i, N) R.G[N + M + 1][i] = T[i];\n R.G[N + M + 1][N + M + 1] = 1;\n\n R = R ^ D;\n\n Vec X;\n rep(i, N) X[i] = S[i];\n rep(i, M) X[N + i] = F[i];\n X[N + M] = 1;\n X[N + M + 1] = 0;\n\n X = X * R;\n cout << X[N + M + 1] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 14652, "score_of_the_acc": -0.4986, "final_rank": 4 }, { "submission_id": "aoj_0399_4177868", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\ntypedef vector<ll> V;\ntypedef vector<V> MATRIX;\n\nll N,M,D;\nll SIZE;\nll S[105],T[105],F[105];\n\nMATRIX calc(MATRIX left,MATRIX right){\n\n\tMATRIX ret(SIZE,V(SIZE));\n\n\tfor(int i = 0; i < SIZE; i++){\n\t\tfor(int k = 0; k < SIZE; k++)ret[i][k] = 0;\n\t}\n\n\tfor(int row = 0; row < SIZE; row++){\n\t\tfor(int col = 0; col < SIZE; col++){\n\t\t\tfor(int a = 0; a < SIZE; a++){\n\t\t\t\tret[row][col] += left[row][a]*right[a][col]%MOD;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn ret;\n\n}\n\n//MULTのT乗を計算する\nMATRIX POW(MATRIX MULT,ll count){\n\n\tMATRIX ret(SIZE,V(SIZE));\n\n\tfor(int row = 0; row < SIZE; row++){\n\t\tfor(int col = 0; col < SIZE; col++){\n\t\t\tif(row == col)ret[row][col] = 1;\n\t\t\telse{\n\t\t\t\tret[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\n\twhile(count > 0){\n\t\tif(count%2 == 1)ret = calc(ret,MULT);\n\t\tMULT = calc(MULT,MULT);\n\t\tcount /= 2;\n\t}\n\n\treturn ret;\n}\n\n\nint main(){\n\n\tscanf(\"%lld %lld %lld\",&N,&M,&D);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&S[i]);\n\t}\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&T[i]);\n\t}\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%lld\",&F[i]);\n\t}\n\n\n\tSIZE = M+N+1;\n\n\tMATRIX MULT(SIZE,V(SIZE));\n\n\tfor(int row = 0; row < SIZE; row++){\n\t\tfor(int col = 0; col < SIZE; col++){\n\t\t\tMULT[row][col] = 0;\n\t\t}\n\t}\n\n\tMULT[0][0] = 1;\n\tfor(int i = 0; i < N; i++){\n\n\t\tMULT[0][M+1+i] = T[i];\n\t}\n\n\tfor(int row = 1; row <= M; row++){\n\t\tif(row != M){\n\n\t\t\tMULT[row][row+1] = 1;\n\n\t\t}else{\n\n\t\t\tMULT[row][1] = 1;\n\t\t}\n\t}\n\n\tfor(int row = M+1; row <= M+N; row++){\n\t\tif(row != M+N){\n\n\t\t\tMULT[row][row+1] = 1;\n\t\t}else{\n\n\t\t\tMULT[row][M+1] = 1;\n\t\t}\n\t}\n\tMULT[M+N][1] = 1;\n\n\tMULT = POW(MULT,D);\n\n\tll ans = 0;\n\tfor(int i = 0; i < M; i++){\n\t\tans += MULT[0][i+1]*F[i];\n\t\tans %= MOD;\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tans += MULT[0][M+1+i]*S[i];\n\t\tans %= MOD;\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 3456, "score_of_the_acc": -0.4747, "final_rank": 3 }, { "submission_id": "aoj_0399_3944460", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n\nconst int MOD=1000000007;\n\ntypedef vector<ll>vec;\ntypedef vector<vec>mat;\n\nmat mul(mat&a, mat&b) {\n\tmat c(a.size(), vec(b[0].size()));\n\trep(i, a.size())rep(j, b[0].size())rep(k, b.size())\n\t\t(c[i][j] += a[i][k] * b[k][j]) %= MOD;\n\treturn c;\n}\nmat ppow(mat a, ll b) {\n\tmat res(a.size(), vec(a.size()));\n\trep(i, a.size())res[i][i] = 1;\n\twhile (b) {\n\t\tif (b & 1)res = mul(res, a);\n\t\ta = mul(a, a);\n\t\tb >>= 1;\n\t}\n\treturn res;\n}\n\nint s[2000],t[200],f[200];\nint main(){\n\tint n,m;ll d;cin>>n>>m>>d;\n\trep(i,n)scanf(\"%d\",&s[i]);\n\trep(i,n)scanf(\"%d\",&t[i]);\n\trep(i,m)scanf(\"%d\",&f[i]);\n\tmat A(n+m+1,vec(n+m+1));\n\trep(i,n){\n\t\tA[i][(i+1)%n]=1;\n\t}\n\trep(i,m){\n\t\tA[i+n][n+(i+1)%m]=1;\n\t}\n\trep(i,n){\n\t\tA[n+m][i]=t[i];\n\t}\n\tA[n+m][n+m]=1;\n\tA[n-1][n]=1;\n\tmat B(n+m+1,vec(1));\n\trep(i,n)B[i][0]=s[i];\n\trep(i,m)B[n+i][0]=f[i];\n\tauto res=ppow(A,d);\n\tres=mul(res,B);\n\tcout<<res[n+m][0]<<endl;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3436, "score_of_the_acc": -1.0009, "final_rank": 6 }, { "submission_id": "aoj_0399_3250496", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n\ntemplate<typename K>\nstruct Matrix{\n typedef vector<K> arr;\n typedef vector<arr> mat;\n mat dat;\n\n Matrix(size_t r,size_t c):dat(r,arr(c,K())){}\n Matrix(mat dat):dat(dat){}\n\n size_t size() const{return dat.size();};\n bool empty() const{return size()==0;};\n arr& operator[](size_t k){return dat[k];};\n const arr& operator[](size_t k) const {return dat[k];};\n \n static Matrix cross(const Matrix &A,const Matrix &B){\n Matrix res(A.size(),B[0].size()); \n for(int i=0;i<(int)A.size();i++)\n for(int j=0;j<(int)B[0].size();j++)\n for(int k=0;k<(int)B.size();k++)\n res[i][j]+=A[i][k]*B[k][j];\n return res;\n }\n\n static Matrix identity(size_t n){\n Matrix res(n,n);\n for(int i=0;i<(int)n;i++) res[i][i]=K(1);\n return res;\n }\n \n Matrix pow(long long n) const{\n Matrix a(dat),res=identity(size());\n while(n){\n if(n&1) res=cross(res,a);\n a=cross(a,a); \n n>>=1;\n }\n return res;\n }\n\n template<typename T> using ET = enable_if<is_floating_point<T>::value>;\n template<typename T> using EF = enable_if<!is_floating_point<T>::value>;\n \n template<typename T, typename ET<T>::type* = nullptr>\n static bool is_zero(T x){return abs(x)<1e-8;}\n template<typename T, typename EF<T>::type* = nullptr>\n static bool is_zero(T x){return x==T(0);}\n\n static Matrix gauss_jordan(const Matrix &A,const Matrix &B){\n int n=A.size(),l=B[0].size();\n Matrix C(n,n+l);\n for(int i=0;i<n;i++){\n for(int j=0;j<n;j++)\n C[i][j]=A[i][j]; \n for(int j=0;j<l;j++)\n C[i][n+j]=B[i][j];\n }\n for(int i=0;i<n;i++){\n int p=i;\n for(int j=i;j<n;j++)\n if(abs(C[p][i])<abs(C[j][i])) p=j;\n swap(C[i],C[p]);\n if(is_zero(C[i][i])) return Matrix(0,0);\n for(int j=i+1;j<n+l;j++) C[i][j]/=C[i][i];\n for(int j=0;j<n;j++){\n if(i==j) continue;\n for(int k=i+1;k<n+l;k++)\n C[j][k]-=C[j][i]*C[i][k];\n }\n }\n Matrix res(n,l);\n for(int i=0;i<n;i++)\n for(int j=0;j<l;j++)\n res[i][j]=C[i][n+j];\n return res;\n }\n \n Matrix inv() const{\n Matrix B=identity(size());\n return gauss_jordan(*this,B);\n } \n};\n\n\ntemplate<typename T,T MOD = 1000000007>\nstruct Mint{\n T v;\n Mint():v(0){}\n Mint(signed v):v(v){}\n Mint(long long t){v=t%MOD;if(v<0) v+=MOD;}\n\n Mint pow(int k){\n Mint res(1),tmp(v);\n while(k){\n if(k&1) res*=tmp;\n tmp*=tmp;\n k>>=1;\n }\n return res;\n }\n \n Mint inv(){return pow(MOD-2);}\n \n Mint& operator+=(Mint a){v+=a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator-=(Mint a){v+=MOD-a.v;if(v>=MOD)v-=MOD;return *this;}\n Mint& operator*=(Mint a){v=1LL*v*a.v%MOD;return *this;}\n Mint& operator/=(Mint a){return (*this)*=a.inv();}\n \n Mint operator+(Mint a) const{return Mint(v)+=a;};\n Mint operator-(Mint a) const{return Mint(v)-=a;};\n Mint operator*(Mint a) const{return Mint(v)*=a;};\n Mint operator/(Mint a) const{return Mint(v)/=a;};\n\n Mint operator-(){return v?MOD-v:v;}\n\n bool operator==(const Mint a)const{return v==a.v;}\n bool operator!=(const Mint a)const{return v!=a.v;}\n \n};\n\n//INSERT ABOVE HERE\nsigned main(){\n int n,m;\n Int k;\n cin>>n>>m>>k;\n\n vector<int> s(n),t(n),f(m);\n for(int i=0;i<n;i++) cin>>s[i];\n for(int i=0;i<n;i++) cin>>t[i];\n for(int i=0;i<m;i++) cin>>f[i];\n \n using M = Mint<int>;\n using MM = Matrix<M>;\n\n MM dat(1+m+n,1+m+n);\n MM col(1+m+n,1);\n col[0][0]=0;\n for(int i=0;i<m;i++) col[1+i][0]=M(f[i]);\n for(int i=0;i<n;i++) col[1+m+i][0]=M(s[i]);\n\n dat[0][0]=1;\n for(int i=0;i<n;i++) dat[0][1+m+i]=M(t[i]);\n\n for(int i=0;i+1<m;i++) dat[1+i][1+i+1]=M(1);\n dat[m][1]=M(1);\n \n for(int i=0;i+1<n;i++) dat[1+m+i][1+m+i+1]=M(1);\n dat[m+n][1+m]=M(1);\n\n dat[m+n][1]=1;\n\n if(0){\n for(int i=0;i<1+m+n;i++){\n for(int j=0;j<1+m+n;j++)\n cout<<dat[i][j].v<<\" \";\n cout<<endl;\n }\n for(int i=0;i<1+m+n;i++)\n cout<<col[i][0].v<<endl;\n }\n \n M sum=MM::cross(dat.pow(k),col)[0][0];\n\n cout<<sum.v<<endl; \n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3304, "score_of_the_acc": -0.7368, "final_rank": 5 } ]
aoj_0396_cpp
Treasure Map Mr. Kobou found a bundle of old paper when he was cleaning his family home. On each paper, two series of numbers are written. Strange as it appeared to him, Mr. Kobou further went through the storehouse and found out a note his ancestor left. According to it, the bundle of paper is a treasure map, in which the two sequences of numbers seem to give a clue to the whereabouts of the treasure the ancestor buried. Mr. Kobou’s ancestor divided the area where he buried his treasure in a reticular pattern and used only some of the grid sections. The two series of numbers indicate the locations: the $i$-th member of the first series indicates the number of locations in the $i$-th column (form left) of the grid sections where a part of the treasure is buried, and the $j$-th member of the second indicates the same information regarding the $j$-th row from the top. No more than one piece of treasure is buried in one grid section. An example of a 5 × 4 case is shown below. If the pieces of treasure are buried in the grid sections noted as " # " the two series of numbers become "0,2,2,1,1" and "1,1,1,3". 0 2 2 1 1 1 # 1 # 1 # 3 # # # Mr. Kobou’s ancestor seems to be a very careful person. He slipped some pieces of paper with completely irrelevant information into the bundle. For example, a set of number series "3,2,3,0,0" and "4,2,0,0,2" does not match any combination of 5 × 5 matrixes. So, Mr. Kobou has first to exclude these pieces of garbage information. Given the set of information written on the pieces of paper, make a program to judge if the information is relevant. Input The input is given in the following format. $W$ $H$ $a_1$ $a_2$ $...$ $a_W$ $b_1$ $b_2$ $...$ $b_H$ The first line provides the number of horizontal partitions $W$ ($1 \leq W \leq 1000$) and vertical partitions $H$ ($1 \leq H \leq 1000$). The second line provides the $i$-th member of the first number series $a_i$ ($0 \leq a_i \leq H$) written on the paper, and the third line the $j$-th member of the second series $b_j$ ($0 \leq b_j \leq W$). Output Output " 1 " if the information written on the paper is relevant, or " 0 " otherwise. Sample Input 1 5 4 0 2 2 1 1 1 1 1 3 Sample Output 1 1 Sample Input 2 5 5 3 2 3 0 0 4 2 0 0 2 Sample Output 2 0
[ { "submission_id": "aoj_0396_10934164", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint W, H;\n\tcin >> W >> H;\n\tvector<int> A(W), B(H);\n\tint sumA = 0, sumB = 0;\n\trep(i, 0, W) {\n\t\tcin >> A[i];\n\t\tsumA += A[i];\n\t}\n\trep(i, 0, H) {\n\t\tcin >> B[i];\n\t\tsumB += B[i];\n\t}\n\t\n\tif (sumA != sumB) {\n\t\tcout << 0 << '\\n';\n\t\treturn 0;\n\t}\n\t\n\tpriority_queue<int> que;\n\tqueue<int> tmp;\n\trep(i, 0, W) if (A[i] != 0) que.push(A[i]);\n\tbool can = true;\n\t\n\trep(i, 0, H) {\n\t\tif (que.size() < B[i]) {\n\t\t\tcan = false;\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\trep(itr, 0, B[i]) {\n\t\t\ttmp.push(que.top() - 1);\n\t\t\tque.pop();\n\t\t}\n\t\trep(itr, 0, B[i]) {\n\t\t\tif (tmp.front() != 0) que.push(tmp.front());\n\t\t\ttmp.pop();\n\t\t}\n\t}\n\t\n\tcout << (can ? 1 : 0) << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3448, "score_of_the_acc": -0.021, "final_rank": 3 }, { "submission_id": "aoj_0396_10905313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std; \n/*#include <boost/multiprecision/cpp_dec_float.hpp>\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/rational.hpp>\nusing namespace boost::multiprecision;*/\n/*#include <atcoder/all>\nusing namespace atcoder;\nusing mint = modint;*/\n//long long型=int64_tという認識で大丈夫です。\n//#define int long long\n#define ll long long\n#define ull unsigned long long\n#define vec vector\n#define vi vector<int>\n#define vll vector<ll>\n#define pq priority_queue\n#define pb push_back\n#define rep(i, l, r) for(ll i=(ll)(l); i<(ll)(r); i++)\n#define ld long double\n\nconst ll INF = 2e9;\nconst ll inf = 5e18;\nconst ld ep = 1e-15;\n\nstruct Edge {\n int to;\n ll cost;\n};\n\nstruct SEdge {\n int to;\n pair<ll, ll> cost;\n};\n\ntemplate<class T>\nusing spq = priority_queue<T, vec<T>, greater<T>>; \n\nconst vector<ll> di = {-1, 0, 1, 0}, dj = {0, -1, 0, 1};\n\ntemplate<class T>\nbool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T>\nbool chmax(T& a, T b) {\n if(a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T, class U> \nistream &operator>>(istream &is, pair<T, U> &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate<class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &v) {\n for(auto &x : v) {\n is >> x;\n }\n return is;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for(int i = 0; i < (int)v.size(); i++) {\n if(i != (int)v.size() - 1)\n os << v[i] << \" \";\n else\n os << v[i];\n }\n return os;\n}\n\nstring strplus(string a, string b) {\n reverse(a.begin(), a.end()); reverse(b.begin(), b.end());\n bool ch = false;\n if(a.size() < b.size()) {\n swap(a, b);\n ch = true;\n }\n string ret;\n int cnt = 0;\n rep(i, 0, a.size()) {\n if(i >= b.size()) {\n ret += (char)(((int)(a[i] - '0') + cnt) % 10 + '0');\n cnt = (((int)(a[i] - '0') + cnt) / 10);\n }\n else {\n ret += (char)(((int)(a[i] - '0' + b[i] - '0') + cnt) % 10 + '0');\n cnt = ((int)(a[i] - '0' + b[i] - '0') + cnt) / 10;\n }\n }\n if(cnt != 0) ret += \"1\";\n reverse(ret.begin(), ret.end());\n return ret;\n}\n\nstring strminus(string a, string b) {\n reverse(a.begin(), a.end()); reverse(b.begin(), b.end());\n bool ch = false;\n if(a.size() < b.size()) {\n swap(a, b);\n ch = true;\n }\n else if(a.size() == b.size() && a < b) {\n swap(a, b);\n ch = true;\n }\n string ret;\n int cnt = 0;\n rep(i, 0, a.size()) {\n if(i >= b.size()) {\n ret += (char)(((int)(a[i] - '0') + cnt + 10) % 10 + '0');\n cnt = ((int)(a[i] - '0') + cnt + 10) / 10 - 1;\n }\n else {\n ret += (char)(((int)(a[i] - b[i]) + cnt + 10) % 10 + '0');\n cnt = ((int)(a[i] - b[i]) + cnt + 10) / 10 - 1;\n }\n }\n while(ret[ret.size() - 1] == '0' && ret.size() >= 1) ret.erase(--ret.end());\n if(ret != \"0\" && ch) ret += '-';\n reverse(ret.begin(), ret.end());\n return ret;\n}\n\ntemplate <class T>\nbool jf(pair<T, T> a, pair<T, T> b) {\n if(a.second > b.second) return false;\n else return true;\n}\n\nusing S = ll;\n\nS op(S a, S b){ return max(a, b); }\nS e(){ return 0;}\n\nsigned main(){\n int w, h; cin >> w >> h;\n vi a(w), b(h); rep(i, 0, w) cin >> a[i]; rep(i, 0, h) cin >> b[i];\n sort(b.rbegin(), b.rend());\n pq<int> Q; rep(i, 0, w) if(a[i] != 0) Q.push(a[i]);\n rep(i, 0, h) {\n if(Q.size() < b[i]) {\n cout << 0 << endl;\n return 0;\n }\n vi ret;\n rep(j, 0, b[i]) {\n int cnt = Q.top(); Q.pop();\n if(cnt == 1) continue;\n ret.emplace_back(--cnt);\n }\n rep(j, 0, ret.size()) Q.push(ret[j]);\n }\n cout << 1 << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3440, "score_of_the_acc": -0.0207, "final_rank": 2 }, { "submission_id": "aoj_0396_10848985", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define mod 1000000007\n\nint main(){\n ll w,h; cin>>w>>h;\n ll a[1010],b[1010];\n ll vl=0,vr=0;\n for(int i=0;i<w;i++){\n cin>>a[i];\n vl+=a[i];\n }\n for(int j=0;j<h;j++){\n cin>>b[j];\n vr+=b[j];\n }\n if(vl!=vr){\n cout<<0<<endl;\n return 0;\n }\n for(int j=0;j<h;j++){\n pair<ll,ll> c[1010];\n for(int i=0;i<w;i++){\n\t c[i]=make_pair(a[i],i);\n }\n sort(c,c+w,greater<pair<ll,ll> >());\n for(int i=0;i<b[j];i++){\n\t a[c[i].second]--;\n }\n }\n bool ok=1;\n for(int i=0;i<w;i++)ok&=(a[i]==0);\n cout<<ok<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3500, "score_of_the_acc": -0.7726, "final_rank": 18 }, { "submission_id": "aoj_0396_10806676", "code_snippet": "#include <iostream>\n#include <vector>\n#include <math.h>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <string>\n#include <bitset>\n#include <iomanip>\nusing namespace std;\nusing ll = long long;\nusing VVI = vector<vector<int>>;\nusing VVL = vector<vector<ll>>;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\nusing VC = vector<char>;\nusing VP = vector<pair<int, int>>;\nusing Graph0 = vector<vector<int>>;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define drep(i, a, b) for (int i = (int)(a);i >= (int)(b);i--)\n#define urep(i, a, b) for (int i = (int)(a);i <= (int)(b);i++)\n#define lrep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define ldrep(i, a, b) for (ll i = (ll)(a);i >= (ll)(b);i--)\n#define lurep(i, a, b) for (ll i = (ll)(a);i <= (ll)(b);i++)\n#define arep(i, v) for (auto i : v)\n#define all(a) (a).begin(), (a).end()\n#define yes cout << \"Yes\" << endl\n#define no cout << \"No\" << endl\n#define eyes cout << \"Yes\" << endl;exit(0);\n#define eno cout << \"No\" << endl;exit(0);\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate<typename T>\nvoid excout(T A) {\n cout << A << endl;\n exit(0);\n}\nconstexpr long long INF = (1LL << 60); // INFにちゅういい!\n\n\nstruct Edge\n{\n int to;\n int cost;\n};\nusing Graph = std::vector<std::vector<Edge>>;\nusing Pair = std::pair<long long, int>;\nvoid Dijkstra(const Graph& graph, std::vector<long long>& distances, int startIndex)\n{\n std::priority_queue<Pair, std::vector<Pair>, std::greater<Pair>> q;\n q.emplace((distances[startIndex] = 0), startIndex);\n\n while (!q.empty())\n {\n const long long distance = q.top().first;\n const int from = q.top().second;\n q.pop();\n if (distances[from] < distance)\n {\n continue;\n }\n for (const auto& edge : graph[from])\n {\n const long long d = (distances[from] + edge.cost);\n if (d < distances[edge.to])\n {\n q.emplace((distances[edge.to] = d), edge.to);\n }\n }\n }\n}\ntemplate<typename T>\nT MODS(T a, T mods) {\n return ((((((a + mods) % mods) + mods) % mods)));\n}\nVVL comb(int n, int r) {\n VVL v(n + 1, VL (n + 1, 0));\n for (int i = 0; i < v.size(); i++) {\n v[i][0] = 1;\n v[i][i] = 1;\n }\n for (int j = 1; j < v.size(); j++) {\n for (int k = 1; k < j; k++) {\n v[j][k] = (v[j - 1][k - 1] + v[j - 1][k]);\n }\n }\n return v;\n}\nvector<pair<long long, long long> > prime_factorize(long long N) {\n vector<pair<long long, long long> > res;\n for (long long p = 2; p * p <= N; ++p) {\n if (N % p != 0) {\n continue;\n }\n int e = 0;\n while (N % p == 0) {\n ++e;\n N /= p;\n }\n res.emplace_back(p, e);\n }\n if (N != 1) {\n res.emplace_back(N, 1);\n }\n return res;\n}\n\nstruct UnionFind {\n vector<int> par, siz;\n UnionFind(int n) : par(n, -1), siz(n, 1) {}\n int root(int x) {\n if (par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n bool unite(int x, int y) {\n x = root(x);y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x) {\n return siz[root(x)];\n }\n};\ntemplate<class Abel> struct WUnionFind {\n vector<int> par;\n vector<int> rank;\n vector<Abel> diff_weight;\n\n WUnionFind(int n = 1, Abel SUM_UNITY = 0) {\n init(n, SUM_UNITY);\n }\n\n void init(int n = 1, Abel SUM_UNITY = 0) {\n par.resize(n); rank.resize(n); diff_weight.resize(n);\n for (int i = 0; i < n; ++i) par[i] = i, rank[i] = 0, diff_weight[i] = SUM_UNITY;\n }\n\n int root(int x) {\n if (par[x] == x) {\n return x;\n }\n else {\n int r = root(par[x]);\n diff_weight[x] += diff_weight[par[x]];\n return par[x] = r;\n }\n }\n\n Abel weight(int x) {\n root(x);\n return diff_weight[x];\n }\n\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n\n bool merge(int x, int y, Abel w) { //W(y)=W(x)+w\n w += weight(x); w -= weight(y);\n x = root(x); y = root(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y), w = -w;\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n diff_weight[y] = w;\n return true;\n }\n\n Abel diff(int x, int y) { // W(y) - W(x)\n return weight(y) - weight(x);\n }\n};\nVI topo_sort(Graph0& G) {\n int N = G.size();\n VI IND(N, 0);\n rep(v, N) {\n arep(nv, G[v]) {\n IND[nv]++;\n }\n }\n queue<int> que;\n rep(v, N) {\n if (IND[v] == 0) {\n que.push(v);\n }\n }\n VI ANS;\n while (!que.empty()) {\n int v = que.front();\n ANS.push_back(v);\n que.pop();\n arep(nv, G[v]) {\n IND[nv]--;\n if (IND[nv] == 0) {\n que.push(nv);\n }\n }\n }\n return ANS;\n}\nvoid ADD(int a, int b, Graph0& G) {\n G[a].push_back(b);\n G[b].push_back(a);\n}\nVP near(int i, int j, int H, int W) {\n VP ans;\n VP cand = {{i - 1, j}, {i + 1, j}, {i, j - 1}, {i, j + 1}};\n arep(v, cand) {\n if (v.first < 0 or v.first >= H) continue;\n if (v.second < 0 or v.second >= W) continue;\n ans.push_back(v);\n }\n return ans;\n}\nint cast(int i, int j, int H, int W) {\n return ((W * i) + j);\n}\nll pows(ll x, ll n, ll mod) {\n if (!n) return 1;\n x %= mod;\n ll r = pows(x, n / 2, mod);\n (r *= r) %= mod;\n if (n % 2) (r *=x) %= mod;\n return r;\n}\nstruct COMB_MOD {\n ll mod;\n int MAX;\n VL fac, finv, inv;\n COMB_MOD(int max, ll m) {\n fac.assign(max, 0);\n finv.assign(max, 0);\n inv.assign(max, 0);\n mod = m;\n MAX = max;\n }\n void solve() {\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < MAX; i++){\n fac[i] = fac[i - 1] * i % mod;\n\n inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n finv[i] = finv[i - 1] * inv[i] % mod;\n }\n \n }\n ll comb(int n, int k) {\n if (n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n - k] % mod) % mod;\n }\n};\n\nstruct LCA {\n vector<vector<int>> parent; \n vector<int> dist; \n LCA(const Graph0 &G, int root = 0) { init(G, root); }\n void init(const Graph0 &G, int root = 0) {\n int V = G.size();\n int K = 1;\n while ((1 << K) < V) K++;\n parent.assign(K, vector<int>(V, -1));\n dist.assign(V, -1);\n dfs(G, root, -1, 0);\n for (int k = 0; k + 1 < K; k++) {\n for (int v = 0; v < V; v++) {\n if (parent[k][v] < 0) {\n parent[k + 1][v] = -1;\n } else {\n parent[k + 1][v] = parent[k][parent[k][v]];\n }\n }\n }\n }\n void dfs(const Graph0 &G, int v, int p, int d) {\n parent[0][v] = p;\n dist[v] = d;\n for (auto e : G[v]) {\n if (e != p) dfs(G, e, v, d + 1);\n }\n }\n int query(int u, int v) {\n if (dist[u] < dist[v]) swap(u, v); \n int K = parent.size();\n for (int k = 0; k < K; k++) {\n if ((dist[u] - dist[v]) >> k & 1) {\n u = parent[k][u];\n }\n }\n if (u == v) return u;\n for (int k = K - 1; k >= 0; k--) {\n if (parent[k][u] != parent[k][v]) {\n u = parent[k][u];\n v = parent[k][v];\n }\n }\n return parent[0][u];\n }\n int get_dist(int u, int v) { return dist[u] + dist[v] - 2 * dist[query(u, v)]; }\n};\nbool solve(int W, int H, VI A, VI B) {\n int sa = 0;int sb = 0;\n priority_queue<int> pq;\n rep(i, W) {\n sa += A[i];\n if (A[i] != 0) pq.push(A[i]);\n }\n rep(i, H) {\n sb += B[i];\n }\n if (sa != sb) {\n return false;\n }\n rep(i, H) {\n if (B[i] == 0) continue;\n if (pq.size() < B[i]) {\n return false;\n }\n VI value;\n rep(t, B[i]) {\n if (pq.top() >= 2) value.push_back(pq.top()-1);\n pq.pop();\n }\n arep(v, value) pq.push(v);\n }\n return true;\n}\nint main(void) {\n int W, H;cin >> W >> H;\n /*\n set<pair<VI, VI>> st;\n rep(bit, 1<<(H*W)) {\n VVI A(H, VI(W, 0));\n rep(i, H*W) {\n if (bit & (1 << i)) {\n A[i/W][i%W] = 1;\n }\n }\n VI X(W, 0), Y(H, 0);\n rep(i, H) rep(j, W) {\n X[j] += A[i][j];\n Y[i] += A[i][j];\n }\n // cout << \"X \";\n //rep(i, W) cout << X[i] << \" \";\n //cout << \"Y \";\n // rep(I, H) cout << Y[I] << \" \";\n //cout << endl;\n st.insert({X, Y});\n }\n */\n while (true) {\n VI A(W), B(H);\n rep(i, W) cin >> A[i];\n rep(i, H) cin >> B[i];\n bool sl = solve(W, H, A, B);\n if (sl) {\n \n cout << 1 << endl;\n } else {\n cout << 0 << endl;\n }\n break;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.0251, "final_rank": 10 }, { "submission_id": "aoj_0396_9802739", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int W,H;\n cin >> W >> H;\n vector<int> a(W),b(H);\n rep(i,W) cin >> a[i];\n rep(i,H) cin >> b[i];\n\n priority_queue<int> pq;\n rep(i,H) pq.push(b[i]);\n\n sort(a.begin(),a.end(),greater<int>());\n \n rep(i,W){\n vector<int> C;\n rep(j,a[i]){\n int t = pq.top();\n pq.pop();\n if(t==0) {\n cout << 0 << endl;\n return 0;\n }\n C.push_back(t-1);\n }\n\n for(int e: C) pq.push(e);\n }\n cout << (pq.top()==0) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0213, "final_rank": 6 }, { "submission_id": "aoj_0396_9278103", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\nstruct Dinic {\n struct edge {\n int to, rev; ll cap;\n edge(int t, int r, ll c) : to(t), rev(r), cap(c){}\n };\n\n int n;\n vii<edge> to;\n vi<int> dist;\n vi<int> iter;\n const ll inf = 1e18;\n Dinic(int n_) : n(n_), to(n_), dist(n_), iter(n_){}\n\n void addedge(int u, int v, ll cap) {\n int su = (int)to[u].size();\n int sv = (int)to[v].size();\n to[u].push_back({ v, sv, cap });\n to[v].push_back({ u, su, 0 });\n }\n\n void bfs(int s) {\n fill(dist.begin(), dist.end(), -1);\n //dist.assign(n, -1);\n dist[s] = 0;\n queue<int> q;\n q.push(s);\n while (!q.empty()) {\n int v = q.front();\n q.pop();\n for (edge& nv : to[v]) {\n if (nv.cap == 0 || dist[nv.to] != -1) continue;\n dist[nv.to] = dist[v] + 1;\n q.push(nv.to);\n }\n }\n }\n\n ll dfs(int v, int t, ll f) {\n if (v == t) return f;\n int sv = (int)to[v].size();\n for (int& i = iter[v]; i < sv; i++) {\n edge& nv = to[v][i];\n if (nv.cap == 0 || dist[nv.to] <= dist[v]) continue;\n ll nf = dfs(nv.to, t, min(f, nv.cap));\n if (nf > 0) {\n nv.cap -= nf;\n to[nv.to][nv.rev].cap += nf;\n return nf;\n }\n }\n return 0;\n }\n\n ll maxflow(int s, int t) {\n ll res = 0, flow = 0;\n while (true) {\n bfs(s);\n if (dist[t] == -1) break;\n iter.assign(n, 0); //here?\n do {\n flow = dfs(s, t, inf);\n res += flow;\n } while (flow);\n }\n return res;\n }\n \n};\n\nint main()\n{\n int w, h;\n cin >> w >> h;\n\n vi<int> a(w), b(h);\n rep(i, w) cin >> a[i];\n rep(j, h) cin >> b[j];\n\n int sa = 0, sb = 0;\n rep(i, w) sa += a[i];\n rep(j, h) sb += b[j];\n if (sa != sb) {\n cout << 0 << endl;\n return 0;\n }\n\n\n Dinic dn(w + h + 2);\n int S = w + h, T = S + 1;\n\n\n rep(i, w) dn.addedge(S, i, a[i]);\n rep(j, h) dn.addedge(j + w, T, b[j]);\n rep(i, w) rep(j, h) dn.addedge(i, j + w, 1);\n\n cout << (dn.maxflow(S, T) == sa ? 1 : 0) << endl;\n\n \n\n\n return 0;\n}\n\n\n/* \n\n\n if (sa > h * w / 2) {\n rep(i, w) a[i] = h - a[i];\n rep(j, h) b[j] = w - b[j];\n sa = h * w - sa;\n }\n\n if (w > h) {\n swap(h, w);\n swap(a, b);\n }\n\n sort(a.begin(), a.end(), greater<int>{});\n sort(b.begin(), b.end(), greater<int>{});\n\n*/", "accuracy": 1, "time_ms": 50, "memory_kb": 35556, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0396_9278087", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = unsigned;\nusing u64 = unsigned long long;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate<class T, bool directed>\nclass Dinic {\n void bfs(int s){\n fill(level.begin(),level.end(), -1);\n queue<int> Q;\n level[s] = 0;\n Q.emplace(s);\n while(!Q.empty()){\n int v = Q.front(); Q.pop();\n for (auto &&e : G[v]){\n if(e.cap > 0 && level[e.to] < 0){\n level[e.to] = level[v] + 1;\n Q.emplace(e.to);\n }\n }\n }\n }\n\n T dfs(int v, int t, T f){\n if(v == t) return f;\n for(int &i = iter[v]; i < G[v].size(); i++){\n edge &e = G[v][i];\n if(e.cap > 0 && level[v] < level[e.to]){\n T d = dfs(e.to, t, min(f, e.cap));\n if(d == 0) continue;\n e.cap -= d;\n G[e.to][e.rev].cap += d;\n return d;\n }\n }\n return 0;\n }\npublic:\n struct edge {\n int to{}; T cap; int rev{};\n edge() = default;\n edge(int to, T cap, int rev) : to(to), cap(cap), rev(rev) {}\n };\n\n vector<vector<edge>> G;\n vector<int> level, iter;\n Dinic() = default;\n explicit Dinic(int n) : G(n), level(n), iter(n) {}\n\n void add_edge(int from, int to, int cap){\n G[from].emplace_back(to, cap, G[to].size());\n G[to].emplace_back(from, directed ? 0 : cap, G[from].size()-1);\n }\n\n\n T flow(int s, int t, T lim = INF<T>){\n T ret = 0;\n while(true) {\n bfs(s);\n if(level[t] < 0 || lim == 0) break;\n fill(iter.begin(),iter.end(), 0);\n while(true){\n T f = dfs(s, t, lim);\n if(f == 0) break;\n ret += f;\n lim -= f;\n }\n }\n return ret;\n }\n};\n\nint main() {\n int w, h;\n cin >> w >> h;\n vector<int> a(h), b(w);\n int S = 0, T = 0;\n for (auto &&i : b) scanf(\"%d\", &i), T += i;\n for (auto &&i : a) scanf(\"%d\", &i), S += i;\n if(S != T) {\n puts(\"0\");\n return 0;\n }\n Dinic<int, true> G(h+w+2);\n for (int i = 0; i < h; ++i) {\n G.add_edge(0, i+1, a[i]);\n }\n for (int i = 0; i < w; ++i) {\n G.add_edge(h+i+1, h+w+1, b[i]);\n }\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n G.add_edge(i+1, h+j+1, 1);\n }\n }\n if(S != G.flow(0, h+w+1)) puts(\"0\");\n else puts(\"1\");\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 27428, "score_of_the_acc": -1.5022, "final_rank": 19 }, { "submission_id": "aoj_0396_9278060", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n\ntemplate<class T>\nusing vi = vector<T>;\n\ntemplate<class T>\nusing vii = vector<vi<T>>;\n\ntemplate<class T>\nusing viii = vector<vii<T>>;\n\n\n\nint main()\n{\n int w, h;\n cin >> w >> h;\n\n vi<int> a(w), b(h);\n rep(i, w) cin >> a[i];\n rep(j, h) cin >> b[j];\n\n int sa = 0, sb = 0;\n rep(i, w) sa += a[i];\n rep(j, h) sb += b[j];\n if (sa != sb) {\n cout << 0 << endl;\n return 0;\n }\n \n priority_queue<int> pq;\n rep(i, w) if(a[i]) pq.push(a[i]);\n sort(b.begin(), b.end(), greater<int>());\n\n rep(j, h) {\n if (b[j] == 0) continue;\n queue<int> q;\n rep(_, b[j]) {\n if (pq.empty()) {\n cout << 0 << endl;\n return 0;\n }\n int v = pq.top();\n pq.pop();\n if (v > 1) q.push(v - 1);\n }\n while (!q.empty()) {\n pq.push(q.front());\n q.pop();\n } \n }\n cout << 1 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.0211, "final_rank": 4 }, { "submission_id": "aoj_0396_8469723", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tint w,h;\n\tcin >> w >> h;\n\tvector<int> a(w),b(h);\n\tfor(int i = 0;i < w;i++){\n\t\tcin >> a[i];\n\t}\n\tfor(int i = 0;i < h;i++){\n\t\tcin >> b[i];\n\t}\n\tpriority_queue<int> q;\n\tfor(int i = 0;i < h;i++){\n\t\tif(b[i] >= 1){\n\t\t\tq.push(b[i]);\n\t\t}\n\t}\n\tfor(int i = 0;i < w;i++){\n\t\tif(q.size() < a[i]){\n\t\t\tcout << 0 << endl;\n\t\t\texit(0);\n\t\t}\n\t\tqueue<int> it;\n\t\tfor(int j = 0;j < a[i];j++){\n\t\t\tint t = q.top();\n\t\t\tq.pop();\n\t\t\tt--;\n\t\t\tif(t >= 1){\n\t\t\t\tit.push(t);\n\t\t\t}\n\t\t}\n\t\twhile(!it.empty()){\n\t\t\tq.push(it.front());\n\t\t\tit.pop();\n\t\t}\n\t}\n\tif(!q.empty()){\n\t\tcout << 0 << endl;\n\t\texit(0);\n\t}\n\tcout << 1 << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3128, "score_of_the_acc": -0.2612, "final_rank": 13 }, { "submission_id": "aoj_0396_8258062", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int a,b;\n cin>>a>>b;\n int c[a];\n for(int i=0;i<a;i+=1){\n cin>>c[i];\n }\n priority_queue<int> que;\n queue<int> que2;\n for(int i=0;i<b;i+=1){\n int e;\n cin>>e;\n if(e!=0){\n que.push(e);\n }\n }\n for(int i=0;i<a;i+=1){\n int r=0;\n for(int j=0;j<c[i];j+=1){\n if(que.size()==0){\n cout<<0<<endl;\n return 0;\n }else{\n r=que.top();\n que.pop();\n r-=1;\n if(r!=0){\n que2.push(r);\n }\n }\n }\n while(que2.size()!=0){\n que.push(que2.front());\n que2.pop();\n }\n }\n if(que.size()==0){\n cout<<1<<endl;\n }else{\n cout<<0<<endl;\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3184, "score_of_the_acc": -0.2629, "final_rank": 15 }, { "submission_id": "aoj_0396_8239536", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\n\nint main()\n{\n int h,w,sum1=0,sum2=0;\n cin>>h>>w;\n priority_queue<int> st,si,ans;\n int inp;\n for(int i=0;i<h;i++){\n cin>>inp;\n if(inp!=0) st.push(inp),sum1+=inp;\n }\n for(int i=0;i<w;i++){\n cin>>inp;\n if(inp!=0) si.push(inp),sum2+=inp;\n }\n if(sum1!=sum2) {\n cout<<\"0\"<<endl;\n return 0;\n }\n if(st.top()<si.top()) swap(st,si);\n while(!st.empty()){\n int a=st.top();\n st.pop();\n if(si.size()<a){\n cout<<\"0\"<<endl;\n return 0;\n }\n for(int i=0;i<a;i++){\n int b=si.top();\n si.pop();\n b--;\n if(b!=0) ans.push(b);\n }\n while(!ans.empty()){\n si.push(ans.top());\n ans.pop();\n }\n }\n if(!st.empty() || !si.empty()) {\n cout<<\"0\"<<endl;\n return 0;\n }\n cout<<\"1\"<<endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3144, "score_of_the_acc": -0.7617, "final_rank": 16 }, { "submission_id": "aoj_0396_8128016", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int w,h; cin >> w >> h;\n vector<int> a(w);\n for (int i = 0; i < w; ++i) {\n cin >> a[i];\n }\n priority_queue<int> pq;\n for (int i = 0; i < h; ++i) {\n int b; cin >> b; pq.push(b);\n }\n for (int i = 0; i < w; ++i) {\n vector<int> v(a[i]);\n for (int j = 0; j < a[i]; ++j) {\n int p = pq.top(); pq.pop();\n if (p == 0) {\n cout << 0 << endl;\n return 0;\n }\n v[j] = p-1;\n }\n for (int j = 0; j < a[i]; ++j) {\n pq.push(v[j]);\n }\n }\n cout << (pq.top() == 0) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3468, "score_of_the_acc": -0.0216, "final_rank": 7 }, { "submission_id": "aoj_0396_7077166", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nll mod1 = 1000000007;\nint main(){\n ll W,H; cin >> W >> H; \n vector<ll> a(W),b(H);\n priority_queue<ll> pq;\n for(int i = 0; i < W; i++){\n cin >> a[i];\n }\n for(int j = 0; j < H; j++){\n cin >> b[j];\n pq.push(b[j]);\n }\n ll ans = 1;\n for(int i = 0; i < W; i++){\n vector<ll> p;\n for(int j = 0; j < a[i]; j++){\n ll x = pq.top();\n pq.pop();\n p.push_back(x-1);\n //cout << x << endl;;\n }\n for(auto z: p){\n pq.push(z);\n }\n }\n for(int i = 0; i < H; i++){\n ll x = pq.top();\n if(x != 0) ans = 0;\n pq.pop();\n }\n cout << ans << endl;\n \n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3468, "score_of_the_acc": -0.0216, "final_rank": 7 }, { "submission_id": "aoj_0396_6974853", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0396.cc: Treasure Map\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_W = 1000;\nconst int MAX_H = 1000;\n\n/* typedef */\n\ntypedef vector<int> vi;\n\n/* global variables */\n\nint as[MAX_W], bs[MAX_H];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int w, h;\n scanf(\"%d%d\", &w, &h);\n for (int i = 0; i < w; i++) scanf(\"%d\", as + i);\n for (int i = 0; i < h; i++) scanf(\"%d\", bs + i);\n\n sort(as, as + w, greater<int>());\n\n priority_queue<int> q;\n for (int i = 0; i < h; i++)\n if (bs[i] > 0) q.push(bs[i]);\n\n for (int i = 0; i < w && as[i] > 0; i++) {\n if (q.size() < as[i]) { puts(\"0\"); return 0; }\n\n vi v;\n for (int j = 0; j < as[i]; j++)\n v.push_back(q.top()), q.pop();\n for (auto u: v)\n if (u > 1) q.push(u - 1);\n }\n\n if (q.empty()) puts(\"1\");\n else puts(\"0\");\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2908, "score_of_the_acc": -0.0045, "final_rank": 1 }, { "submission_id": "aoj_0396_6043441", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using vc = vector<T>;\ntemplate<class T> using vvc = vc<vc<T>>;\ntemplate<class T> using vvvc = vc<vvc<T>>;\ntemplate<class T> using vvvvc = vvc<vvc<T>>;\ntemplate<class T> using PQ = priority_queue<T>;\ntemplate<class T> using invPQ = priority_queue<T, vector<T>, greater<T>>;\nusing IP = pair<int, int>;\nusing LP = pair<ll, ll>;\n#define all(x) begin(x), end(x)\n#define allr(x) rbegin(x), rend(x)\n#define rep(i, n) for (int i = 0; (i) < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); (i) < (int)(n); i++)\n#define repr(i, n) for (int i = (n) - 1; (i) >= 0; i--)\n#define rep3r(i, m, n) for (int i = (n) - 1; (i) >= (int)(m); i--)\ntemplate<class T> inline bool chmax(T & a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T & a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nsigned main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int W, H;\n cin >> W >> H;\n vc<int> a(W), b(H);\n rep (i, W) cin >> a[i];\n rep (i, H) cin >> b[i];\n\n PQ<int> que;\n rep (i, H) que.push(b[i]);\n rep (i, W) {\n queue<int> next;\n rep (j, a[i]) {\n next.push(que.top()-1);\n que.pop();\n }\n while (!next.empty()) {\n que.push(next.front());\n next.pop();\n }\n }\n\n bool judge = true;\n while (!que.empty()) {\n if (que.top() != 0) judge = false;\n que.pop();\n }\n\n cout << judge << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3480, "score_of_the_acc": -0.022, "final_rank": 9 }, { "submission_id": "aoj_0396_6038779", "code_snippet": "/*\nこのコード、と~おれ!\nBe accepted!\n∧_∧ \n(。・ω・。)つ━☆・*。\n⊂   ノ    ・゜+.\n しーJ   °。+ *´¨)\n          .· ´¸.·*´¨) ¸.·*¨)\n\t\t           (¸.·´ (¸.·'* ☆\n*/\n\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <iostream>\n#include <random>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <regex>\n#include <functional>\n#include <complex>\n#include <list>\n#include <cassert>\n#include <iomanip>\n#include <set>\n#include <stack>\n#include <bitset>\n#include <array>\n#include <chrono>\n\n//#pragma GCC target(\"arch=skylake-avx512\")\n//#pragma GCC target(\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"Ofast\")\n//#pragma GCC target(\"sse4\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define repeat(i, n, m) for(int i = n; i < (m); ++i)\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n#define printynl(a) printf(a ? \"yes\\n\" : \"no\\n\")\n#define printyn(a) printf(a ? \"Yes\\n\" : \"No\\n\")\n#define printYN(a) printf(a ? \"YES\\n\" : \"NO\\n\")\n#define printim(a) printf(a ? \"possible\\n\" : \"imposible\\n\")\n#define printdb(a) printf(\"%.50lf\\n\", a)\n#define printLdb(a) printf(\"%.50Lf\\n\", a)\n#define printdbd(a) printf(\"%.16lf\\n\", a)\n#define prints(s) printf(\"%s\\n\", s.c_str())\n#define all(x) (x).begin(), (x).end()\n#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)\n#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)\n#define Please return\n#define AC 0\n#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr int INF = 1073741823;\nconstexpr int MINF = -1073741823;\nconstexpr ll LINF = ll(4661686018427387903);\nconstexpr ll MOD = 1e9 + 7;\nconstexpr ll mod = 998244353;\nconstexpr long double eps = 1e-6;\nconst long double PI = acosl(-1.0L);\n\nusing namespace std;\n\nvoid scans(string& str) {\n\tchar c;\n\tstr = \"\";\n\tscanf(\"%c\", &c);\n\tif (c == '\\n')scanf(\"%c\", &c);\n\twhile (c != '\\n' && c != -1 && c != ' ') {\n\t\tstr += c;\n\t\tscanf(\"%c\", &c);\n\t}\n}\n\nvoid scanc(char& str) {\n\tchar c;\n\tscanf(\"%c\", &c);\n\tif (c == -1)return;\n\twhile (c == '\\n') {\n\t\tscanf(\"%c\", &c);\n\t}\n\tstr = c;\n}\n\ndouble acot(double x) {\n\treturn PI / 2 - atan(x);\n}\n\nll LSB(ll n) { return (n & (-n)); }\n\ntemplate<typename T>\ninline T chmin(T& a, const T& b) {\n\tif (a > b)a = b;\n\treturn a;\n}\n\ntemplate<typename T>\ninline T chmax(T& a, const T& b) {\n\tif (a < b)a = b;\n\treturn a;\n}\n\n//cpp_int\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\nusing namespace boost::multiprecision;\n#else\nusing cpp_int = ll;\n#endif\n\n//atcoder library\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\n//using namespace atcoder;\n#endif\n\n/*\n\trandom_device seed_gen;\n\tmt19937 engine(seed_gen());\n\tuniform_int_distribution dist(1, 100);\n*/\n\n\n/*----------------------------------------------------------------------------------*/\n\n\n\nint main() {\n\n\tint w, h;\n\tscanf(\"%d%d\", &w, &h);\n\tvector<int> a(w), b(h);\n\trep(i, w) scanf(\"%d\", &a[i]);\n\trep(i, h) scanf(\"%d\", &b[i]);\n\tpriority_queue<int> que;\n\trep(i, h)que.push(b[i]);\n\trep(i, w) {\n\t\tvector<int> ntr;\n\t\twhile (a[i]--) {\n\t\t\tntr.push_back(que.top());\n\t\t\tque.pop();\n\t\t}\n\t\tfor (const auto& aa : ntr) {\n\t\t\tque.push(aa - 1);\n\t\t}\n\t}\n\tprintf(\"%d\\n\", que.top() == 0);\n\n\tPlease AC;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3588, "score_of_the_acc": -0.0252, "final_rank": 11 }, { "submission_id": "aoj_0396_4983667", "code_snippet": "#include <bits/stdc++.h>\nusing std::string;\n\nint main() {\n int h, w;\n std::cin >> w >> h;\n std::vector<int> a(w), b(h), a2(w), b2(h);\n int a_cnt = 0, b_cnt = 0;\n for (int i = 0; i < w; ++i) {\n std::cin >> a[i];\n a_cnt += !!a[i];\n }\n for (int i = 0; i < h; ++i) {\n std::cin >> b[i];\n b_cnt += !!b[i];\n }\n std::copy(a.begin(), a.end(), a2.begin());\n std::copy(b.begin(), b.end(), b2.begin());\n\n for (int i = 0; i < h; ++i) {\n std::sort(a2.begin(), a2.end(), std::greater<>());\n for (int j = 0; j < b[i]; ++j) {\n --a2[j];\n }\n }\n\n for (int i = 0; i < w; ++i) {\n std::sort(b2.begin(), b2.end(), std::greater<>());\n for (int j = 0; j < a[i]; ++j) {\n --b2[j];\n }\n }\n\n for (int a_value : a2) {\n if (a_value < 0) {\n std::cout << \"0\\n\";\n return 0;\n }\n }\n for (int b_value : b2) {\n if (b_value < 0) {\n std::cout << \"0\\n\";\n return 0;\n }\n }\n\n std::cout << \"1\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3452, "score_of_the_acc": -0.0211, "final_rank": 4 }, { "submission_id": "aoj_0396_4976791", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\nconstexpr lint mod = 998244353;\n#define all(x) (x).begin(), (x).end()\n#define bitcount(n) __builtin_popcountl((lint)(n))\n#define fcout cout << fixed << setprecision(15)\n#define highest(x) (63 - __builtin_clzl(x))\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, r) for(int i = int(l); i < int(r); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, r) for(int i = int(r) - 1; i >= int(l); i--)\n\nint main(){\n int W, H;\n cin >> W >> H;\n vector<int> a(W), b(H);\n rep(i, W) cin >> a[i];\n rep(i, H) cin >> b[i];\n if(accumulate(all(a), 0) != accumulate(all(b), 0)){\n cout << 0 << endl;\n return 0;\n }\n priority_queue<int> a_que;\n rep(i, W){\n a_que.push(a[i]);\n }\n rep(i, H){\n vector<int> item;\n rep(_, b[i]){\n item.push_back(a_que.top());\n a_que.pop();\n }\n for(int &j: item){\n if(j == 0){\n cout << 0 << endl;\n return 0;\n }\n j--;\n a_que.push(j);\n }\n }\n cout << 1 << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3172, "score_of_the_acc": -0.2626, "final_rank": 14 }, { "submission_id": "aoj_0396_4976307", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\nconstexpr lint mod = 998244353;\n#define all(x) (x).begin(), (x).end()\n#define bitcount(n) __builtin_popcountl((lint)(n))\n#define fcout cout << fixed << setprecision(15)\n#define highest(x) (63 - __builtin_clzl(x))\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, r) for(int i = int(l); i < int(r); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, r) for(int i = int(r) - 1; i >= int(l); i--)\n\nint main(){\n int W, H;\n cin >> W >> H;\n vector<int> a(W), b(H);\n rep(i, W) cin >> a[i];\n rep(i, H) cin >> b[i];\n if(accumulate(all(a), 0) != accumulate(all(b), 0)){\n cout << 0 << endl;\n return 0;\n }\n rep(loop, 2){\n priority_queue<int> a_que;\n rep(i, W){\n a_que.push(a[i]);\n }\n rep(i, H){\n vector<int> item;\n rep(_, b[i]){\n item.push_back(a_que.top());\n a_que.pop();\n }\n for(int &j: item){\n if(j == 0){\n cout << 0 << endl;\n return 0;\n }\n j--;\n a_que.push(j);\n }\n }\n swap(a, b);\n swap(W, H);\n }\n cout << 1 << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3172, "score_of_the_acc": -0.7626, "final_rank": 17 }, { "submission_id": "aoj_0396_4961297", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<queue>\nusing namespace std;\nint main(void)\n{\n\tint w,h,a,b[1001],flg=0,i,x,c,y[1001],cnt,j;\n\tpriority_queue<int>q;\n\tscanf(\"%d%d\",&w,&h);\n\tfor(i=0;i<w;i++){\n\t\tscanf(\"%d\",&a);\n\t\tq.push(a);\n\t}\n\tfor(i=0;i<h;i++)\tscanf(\"%d\",&b[i]);\n\tsort(b,b+h);\n\tfor(i=h-1;i>=0;i--){\n\t\tc=b[i];\n\t\tcnt=0;\n\t\tfor(j=1;j<=c;j++){\n\t\t\tx=q.top();\n\t\t\tif(x<=0||q.size()==0){\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\tflg=1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tx--;\n\t\t\t\tq.pop();\n\t\t\t\ty[cnt]=x;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t\tfor(j=0;j<cnt;j++)\tq.push(y[j]);\n\t\tif(flg==1)\tbreak;\n\t}\n\tif(flg==0)\tprintf(\"1\\n\");\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2760, "score_of_the_acc": -0.25, "final_rank": 12 } ]
aoj_0395_cpp
Round Table of Sages $N$ sages are sitting around a round table with $N$ seats. Each sage holds chopsticks with his dominant hand to eat his dinner. The following happens in this situation. If sage $i$ is right-handed and a left-handed sage sits on his right, a level of frustration $w_i$ occurs to him. A right-handed sage on his right does not cause such frustration at all. If sage $i$ is left-handed and a right-handed sage sits on his left, a level of frustration $w_i$ occurs to him. A left-handed sage on his left does not cause such frustration at all. You wish you could minimize the total amount of frustration by clever sitting order arrangement. Given the number of sages with his dominant hand information, make a program to evaluate the minimum frustration achievable. Input The input is given in the following format. $N$ $a_1$ $a_2$ $...$ $a_N$ $w_1$ $w_2$ $...$ $w_N$ The first line provides the number of sages $N$ ($3 \leq N \leq 10$). The second line provides an array of integers $a_i$ (0 or 1) which indicate if the $i$-th sage is right-handed (0) or left-handed (1). The third line provides an array of integers $w_i$ ($1 \leq w_i \leq 1000$) which indicate the level of frustration the $i$-th sage bears. Output Output the minimum total frustration the sages bear. Sample Input 1 5 1 0 0 1 0 2 3 5 1 2 Sample Output 1 3 Sample Input 2 3 0 0 0 1 2 3 Sample Output 2 0
[ { "submission_id": "aoj_0395_11026284", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nint main(){\n int N;\n std::cin >> N;\n \n std::vector<int> a(N), w(N);\n for (int i = 0; i < N; i++) {\n std::cin >> a[i];\n }\n for (int i = 0; i < N; i++) {\n std::cin >> w[i];\n }\n \n std::vector<int> people(N);\n for (int i = 0; i < N; i++) {\n people[i] = i;\n }\n \n int ans=1000000;\n while (std::next_permutation(people.begin(), people.end())) {\n int cost = 0;\n for (int i = 0; i < N; i++) {\n if ((a[people[i]] ^ a[people[(i + 1) % N]]) == 1) {\n cost += w[people[i]];\n }\n }\n if (cost < ans) {\n ans = cost;\n }\n }\n \n std::cout << ans << std::endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3584, "score_of_the_acc": -1.0909, "final_rank": 16 }, { "submission_id": "aoj_0395_10934112", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector<int> A(N), W(N);\n\trep(i, 0, N) cin >> A[i];\n\trep(i, 0, N) cin >> W[i];\n\t\n\tvector<int> p(N);\n\trep(i, 0, N) p[i] = i;\n\t\n\tint ans = 1 << 30;\n\tdo {\n\t\tint res = 0;\n\t\t\n\t\trep(i, 0, N) {\n\t\t\tif ((A[p[i]] == 0 && A[p[(i + 1) % N]] == 1) || (A[p[i]] == 1 && A[p[(i + N - 1) % N]] == 0)) res += W[p[i]];\n\t\t}\n\t\tans = min(ans, res);\n\t} while (next_permutation(p.begin(), p.end()));\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3432, "score_of_the_acc": -0.8981, "final_rank": 8 }, { "submission_id": "aoj_0395_10827137", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/all>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n\nint main(){\n int N;cin>>N;\n vector<int> A(N), W(N), I(N);\n rep(i,N) cin >> A[i];\n rep(i,N) cin >> W[i];\n rep(i,N) I[i] = i;\n int ans = INT_MAX;\n \n do{\n int tmp = 0;\n rep(i, N){\n int p = I[i];\n int right = I[(i+1)%N];\n int left = I[(i-1+N)%N];\n \n if (A[p] == 0) {\n if (A[right] == 1) tmp += W[p];\n } else {\n if (A[left] == 0) tmp += W[p];\n }\n }\n ans = min(ans, tmp);\n } while(next_permutation(I.begin(), I.end()));\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3584, "score_of_the_acc": -1.0909, "final_rank": 16 }, { "submission_id": "aoj_0395_10806359", "code_snippet": "#include <iostream>\n#include <vector>\n#include <math.h>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <string>\n#include <bitset>\n#include <iomanip>\nusing namespace std;\nusing ll = long long;\nusing VVI = vector<vector<int>>;\nusing VVL = vector<vector<ll>>;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\nusing VC = vector<char>;\nusing VP = vector<pair<int, int>>;\nusing Graph0 = vector<vector<int>>;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define drep(i, a, b) for (int i = (int)(a);i >= (int)(b);i--)\n#define urep(i, a, b) for (int i = (int)(a);i <= (int)(b);i++)\n#define lrep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define ldrep(i, a, b) for (ll i = (ll)(a);i >= (ll)(b);i--)\n#define lurep(i, a, b) for (ll i = (ll)(a);i <= (ll)(b);i++)\n#define arep(i, v) for (auto i : v)\n#define all(a) (a).begin(), (a).end()\n#define yes cout << \"Yes\" << endl\n#define no cout << \"No\" << endl\n#define eyes cout << \"Yes\" << endl;exit(0);\n#define eno cout << \"No\" << endl;exit(0);\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate<typename T>\nvoid excout(T A) {\n cout << A << endl;\n exit(0);\n}\nconstexpr long long INF = (1LL << 60); // INFにちゅういい!\n\n\nstruct Edge\n{\n int to;\n int cost;\n};\nusing Graph = std::vector<std::vector<Edge>>;\nusing Pair = std::pair<long long, int>;\nvoid Dijkstra(const Graph& graph, std::vector<long long>& distances, int startIndex)\n{\n std::priority_queue<Pair, std::vector<Pair>, std::greater<Pair>> q;\n q.emplace((distances[startIndex] = 0), startIndex);\n\n while (!q.empty())\n {\n const long long distance = q.top().first;\n const int from = q.top().second;\n q.pop();\n if (distances[from] < distance)\n {\n continue;\n }\n for (const auto& edge : graph[from])\n {\n const long long d = (distances[from] + edge.cost);\n if (d < distances[edge.to])\n {\n q.emplace((distances[edge.to] = d), edge.to);\n }\n }\n }\n}\ntemplate<typename T>\nT MODS(T a, T mods) {\n return ((((((a + mods) % mods) + mods) % mods)));\n}\nVVL comb(int n, int r) {\n VVL v(n + 1, VL (n + 1, 0));\n for (int i = 0; i < v.size(); i++) {\n v[i][0] = 1;\n v[i][i] = 1;\n }\n for (int j = 1; j < v.size(); j++) {\n for (int k = 1; k < j; k++) {\n v[j][k] = (v[j - 1][k - 1] + v[j - 1][k]);\n }\n }\n return v;\n}\nvector<pair<long long, long long> > prime_factorize(long long N) {\n vector<pair<long long, long long> > res;\n for (long long p = 2; p * p <= N; ++p) {\n if (N % p != 0) {\n continue;\n }\n int e = 0;\n while (N % p == 0) {\n ++e;\n N /= p;\n }\n res.emplace_back(p, e);\n }\n if (N != 1) {\n res.emplace_back(N, 1);\n }\n return res;\n}\n\nstruct UnionFind {\n vector<int> par, siz;\n UnionFind(int n) : par(n, -1), siz(n, 1) {}\n int root(int x) {\n if (par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n bool unite(int x, int y) {\n x = root(x);y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x) {\n return siz[root(x)];\n }\n};\ntemplate<class Abel> struct WUnionFind {\n vector<int> par;\n vector<int> rank;\n vector<Abel> diff_weight;\n\n WUnionFind(int n = 1, Abel SUM_UNITY = 0) {\n init(n, SUM_UNITY);\n }\n\n void init(int n = 1, Abel SUM_UNITY = 0) {\n par.resize(n); rank.resize(n); diff_weight.resize(n);\n for (int i = 0; i < n; ++i) par[i] = i, rank[i] = 0, diff_weight[i] = SUM_UNITY;\n }\n\n int root(int x) {\n if (par[x] == x) {\n return x;\n }\n else {\n int r = root(par[x]);\n diff_weight[x] += diff_weight[par[x]];\n return par[x] = r;\n }\n }\n\n Abel weight(int x) {\n root(x);\n return diff_weight[x];\n }\n\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n\n bool merge(int x, int y, Abel w) { //W(y)=W(x)+w\n w += weight(x); w -= weight(y);\n x = root(x); y = root(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y), w = -w;\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n diff_weight[y] = w;\n return true;\n }\n\n Abel diff(int x, int y) { // W(y) - W(x)\n return weight(y) - weight(x);\n }\n};\nVI topo_sort(Graph0& G) {\n int N = G.size();\n VI IND(N, 0);\n rep(v, N) {\n arep(nv, G[v]) {\n IND[nv]++;\n }\n }\n queue<int> que;\n rep(v, N) {\n if (IND[v] == 0) {\n que.push(v);\n }\n }\n VI ANS;\n while (!que.empty()) {\n int v = que.front();\n ANS.push_back(v);\n que.pop();\n arep(nv, G[v]) {\n IND[nv]--;\n if (IND[nv] == 0) {\n que.push(nv);\n }\n }\n }\n return ANS;\n}\nvoid ADD(int a, int b, Graph0& G) {\n G[a].push_back(b);\n G[b].push_back(a);\n}\nVP near(int i, int j, int H, int W) {\n VP ans;\n VP cand = {{i - 1, j}, {i + 1, j}, {i, j - 1}, {i, j + 1}};\n arep(v, cand) {\n if (v.first < 0 or v.first >= H) continue;\n if (v.second < 0 or v.second >= W) continue;\n ans.push_back(v);\n }\n return ans;\n}\nint cast(int i, int j, int H, int W) {\n return ((W * i) + j);\n}\nll pows(ll x, ll n, ll mod) {\n if (!n) return 1;\n x %= mod;\n ll r = pows(x, n / 2, mod);\n (r *= r) %= mod;\n if (n % 2) (r *=x) %= mod;\n return r;\n}\nstruct COMB_MOD {\n ll mod;\n int MAX;\n VL fac, finv, inv;\n COMB_MOD(int max, ll m) {\n fac.assign(max, 0);\n finv.assign(max, 0);\n inv.assign(max, 0);\n mod = m;\n MAX = max;\n }\n void solve() {\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < MAX; i++){\n fac[i] = fac[i - 1] * i % mod;\n\n inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n finv[i] = finv[i - 1] * inv[i] % mod;\n }\n \n }\n ll comb(int n, int k) {\n if (n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n - k] % mod) % mod;\n }\n};\n\nstruct LCA {\n vector<vector<int>> parent; \n vector<int> dist; \n LCA(const Graph0 &G, int root = 0) { init(G, root); }\n void init(const Graph0 &G, int root = 0) {\n int V = G.size();\n int K = 1;\n while ((1 << K) < V) K++;\n parent.assign(K, vector<int>(V, -1));\n dist.assign(V, -1);\n dfs(G, root, -1, 0);\n for (int k = 0; k + 1 < K; k++) {\n for (int v = 0; v < V; v++) {\n if (parent[k][v] < 0) {\n parent[k + 1][v] = -1;\n } else {\n parent[k + 1][v] = parent[k][parent[k][v]];\n }\n }\n }\n }\n void dfs(const Graph0 &G, int v, int p, int d) {\n parent[0][v] = p;\n dist[v] = d;\n for (auto e : G[v]) {\n if (e != p) dfs(G, e, v, d + 1);\n }\n }\n int query(int u, int v) {\n if (dist[u] < dist[v]) swap(u, v); \n int K = parent.size();\n for (int k = 0; k < K; k++) {\n if ((dist[u] - dist[v]) >> k & 1) {\n u = parent[k][u];\n }\n }\n if (u == v) return u;\n for (int k = K - 1; k >= 0; k--) {\n if (parent[k][u] != parent[k][v]) {\n u = parent[k][u];\n v = parent[k][v];\n }\n }\n return parent[0][u];\n }\n int get_dist(int u, int v) { return dist[u] + dist[v] - 2 * dist[query(u, v)]; }\n};\nint main(void) {\n int N;cin >> N;\n VI A(N), W(N);\n rep(i, N) cin >> A[i];\n rep(i, N) cin >> W[i];\n int res = 1e9;\n VI P;\n rep(i, N) P.push_back(i);\n do {\n int sc = 0;\n rep(i, N) {\n if (A[P[i]] == 0 and A[P[(i+N-1)%N]] == 1) {\n sc += W[P[i]];\n }\n if (A[P[i]] == 1 and A[P[(i+N+1)%N]] == 0) {\n sc += W[P[i]];\n }\n \n }\n chmin(res, sc);\n }while(next_permutation(all(P)));\n cout << res << endl;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3584, "score_of_the_acc": -1.0909, "final_rank": 16 }, { "submission_id": "aoj_0395_10497530", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n\n#define REP(i, n) for(int i = 0; i < n; i++)\n#define ll long long \n\nint main(){\n ll n;\n cin >> n;\n ll ans = 1ll << 60;\n vector<ll> a(n), w(n);\n REP(i, n)cin >> a[i];\n REP(i, n) cin >> w[i];\n vector<ll> s;\n REP(i, n)s.push_back(i);\n do{\n ll now = 0;\n REP(j, n){\n if(a[s[j]] == 0 and a[s[(j + 1) % n]] == 1){\n now += w[s[j]];\n now += w[s[(j + 1) % n]];\n }\n }\n ans = min(ans ,now);\n }\n while(next_permutation(s.begin(), s.end()));\n cout << ans <<endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 3428, "score_of_the_acc": -1.0718, "final_rank": 15 }, { "submission_id": "aoj_0395_9802657", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N;\n cin >> N;\n vector<int> a(N),w(N);\n rep(i,N)cin >> a[i];\n rep(i,N) cin >> w[i];\n\n vector<int> o(N);\n rep(i,N) o[i] = i;\n\n int ans = 1e9;\n do{\n int h = 0;\n rep(i,N){\n if(a[o[i]]==0 && a[o[(i+1)%N]]==1){\n h += w[o[i]];\n h += w[o[(i+1)%N]];\n }\n }\n ans = min(ans, h);\n } while (next_permutation(o.begin(),o.end()));\n cout << ans << endl;\n\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3452, "score_of_the_acc": -0.8475, "final_rank": 6 }, { "submission_id": "aoj_0395_9785557", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(A) A.begin(),A.end()\nconst ll INF = 1LL<<60;\n\nint main(){\n\tll N;\n\tcin >> N;\n\tvector<ll> A(N),W(N);\n\trep(i,N) cin >> A[i];\n\trep(i,N) cin >> W[i];\n\tvector<ll> P(N);\n\trep(i,N) P[i]=i;\n\tll ans=INF;\n\tdo{\n\t\tll cost=0;\n\t\trep(i,N){\n\t\t\tll j=i+1;\n\t\t\tif(j==N) j=0;\n\t\t\tif(A[P[i]]==0&&A[P[j]]==1) cost+=W[P[i]]+W[P[j]];\n\t\t}\n\t\tans=min(ans,cost);\t\n\t}while(next_permutation(all(P)));\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3432, "score_of_the_acc": -0.7617, "final_rank": 4 }, { "submission_id": "aoj_0395_9309534", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n cout << (x);\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\ntemplate <typename T>\nvoid wt_integer128(T x) {\n char buf[64];\n char *d = end(buf);\n d--; *d = '\\0';\n __uint128_t tmp = ((x < 0)? -x : x);\n do {\n d--; *d = char(tmp%10 + '0'); tmp /= 10;\n } while (tmp);\n if (x < 0) {\n d--; *d = '-';\n }\n cout << d;\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer128(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer128(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n vi a(N), w(N);\n rep(i, N) cin >> a[i];\n rep(i, N) cin >> w[i];\n vi p(N);\n iota(all(p), 0);\n ll ans = inf;\n do {\n ll sum = 0;\n rep(i, N) {\n if (a[p[i]] == 0) {\n if (a[p[(i+1)%N]] == 1) sum += w[p[i]];\n } else {\n if (a[p[(i+N-1)%N]] == 0) sum += w[p[i]];\n }\n }\n chmin(ans, sum);\n } while (next_permutation(all(p)));\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3460, "score_of_the_acc": -1.2955, "final_rank": 19 }, { "submission_id": "aoj_0395_8284195", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N, a[10], w[10];\nbool used[10];\n\nint soln(vector<int> order) {\n if (order.size() == N) {\n int sum = 0;\n for (int i = 0; i < N; i++) {\n int l = order[i], r = order[(i+1)%N];\n if (a[l] == 0 && a[r] == 1) {\n sum += w[l] + w[r];\n }\n }\n return sum;\n }\n\n int min_sum = 10000;\n for (int i = 0; i < N; i++) {\n if (used[i]) {continue;}\n order.push_back(i); used[i] = true;\n min_sum = min(min_sum, soln(order));\n order.pop_back(); used[i] = false;\n }\n return min_sum;\n}\n\nint main() {\n cin >> N;\n for (int i = 0; i < N; i++) {cin >> a[i];}\n for (int i = 0; i < N; i++) {cin >> w[i];}\n\n vector<int> order;\n cout << soln(order) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 3416, "score_of_the_acc": -1.6613, "final_rank": 20 }, { "submission_id": "aoj_0395_8239249", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long LL;\n#define INF INT64_MAX;\nint main(void)\n{\n int n,mn=1000000;\n cin>>n;\n vector< pair < int , int > > ab;\n vector<int> a(n),b(n);\n for(int i=0;i<n;i++) cin>>a[i];\n for(int i=0;i<n;i++) cin>>b[i];\n for(int i=0;i<n;i++) ab.push_back({a[i],b[i]});\n sort(ab.begin(),ab.end());\n do{\n // for(int i=0;i<n;i++) cout<<ab[i].first;\n // cout<<endl;\n int sum=0;\n for(int i=0;i<n;i++){\n if(i==0){\n if(ab[i].first==1 && ab[i+1].first==0) sum+=ab[i].second;\n else if(ab[i].first==0 && ab[n-1].first==1) sum+=ab[i].second;\n }\n else if(i==n-1){\n if(ab[i].first==1 && ab[0].first==0) sum+=ab[i].second;\n else if(ab[i].first==0 && ab[i-1].first==1) sum+=ab[i].second;\n }\n else{\n if(ab[i].first==1 && ab[i+1].first==0) sum+=ab[i].second;\n else if(ab[i].first==0 && ab[i-1].first==1) sum+=ab[i].second;\n }\n \n }\n mn=min(sum,mn);\n }while(next_permutation(ab.begin(),ab.end()));\n cout<<mn<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3088, "score_of_the_acc": -0.1136, "final_rank": 1 }, { "submission_id": "aoj_0395_7073853", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\t\n\tint N;\n\tcin >> N;\n\tvector<int> A(N), W(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> A[i];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> W[i];\n\t}\n\n\tvector<int> ord(N);\n\tiota(begin(ord), end(ord), 0);\n\tint ans = 1000000;\n\tdo {\n\t\tint sum = 0;\n\t\tfor (int i = 0; i < N; ++i) {\n\t\t\tconst int k = ord[i];\n\t\t\tif (A[k] == 0 and A[ord[(i + 1) % N]] == 1) {\n\t\t\t\tsum += W[k];\n\t\t\t}\n\t\t\tif (A[k] == 1 and A[ord[(i + N - 1) % N]] == 0) {\n\t\t\t\tsum += W[k];\n\t\t\t}\n\t\t}\n\t\tans = min(ans, sum);\n\t} while (next_permutation(begin(ord), end(ord)));\n\tcout << ans << '\\n';\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3460, "score_of_the_acc": -0.9773, "final_rank": 12 }, { "submission_id": "aoj_0395_6890420", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n int n, ans = 1ll << 30;\n cin >> n;\n vector<pair<int,int>> a(n);\n for(auto &&p:a)cin >> p.first;\n for(auto &&p:a)cin >> p.second;\n sort(a.begin(), a.end());\n do{\n int s = 0;\n for(int i = 0; i < n; i++){\n if(a[i].first == 0){\n if(a[(i - 1 + n) % n].first == 1)s += a[(i - 1 + n) % n].second;\n }else{\n if(a[(i + 1 + n) % n].first == 0)s += a[(i + 1 + n) % n].second;\n }\n }\n ans = min(ans, s);\n }while(next_permutation(a.begin(), a.end()));\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3444, "score_of_the_acc": -0.8996, "final_rank": 9 }, { "submission_id": "aoj_0395_6433700", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// {{{ Templates\n\n// clang-format off\n\n// Macros\n#define over_load_(_1,_2,_3,_4,NAME,...) NAME\n#define rep(...) over_load_(__VA_ARGS__, rep4, rep3, rep2)(__VA_ARGS__)\n#define rep2(i, r) for ( int i = 0; i < static_cast<int>(r); (i) += 1)\n#define rep3(i, l, r) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += 1)\n#define rep4(i, l, r, stride) for ( int i = static_cast<int>(l); i < static_cast<int>(r); (i) += (stride))\n#define rrep(...) over_load_(__VA_ARGS__, rrep4, rrep3, rrep2)(__VA_ARGS__)\n#define rrep2(i, r) for ( int i = static_cast<int>(r) - 1; i >= 0; (i) -= 1)\n#define rrep3(i, l, r) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= 1)\n#define rrep4(i, l, r, stride) for ( int i = static_cast<int>(r) - 1; i >= static_cast<int>(l); (i) -= (stride))\n#define len(x) (static_cast<int>((x).size()))\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n#define debug(...) debug_function(#__VA_ARGS__, __VA_ARGS__)\n\n// Operators\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p) { os << \"(\" << p.first << \",\" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &v) { bool is_first = true; for (auto x: v) { os << (is_first ? \"\" : \" \") << x; is_first = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, queue<T> v) { bool is_first = true; while (!v.empty()) { os << (is_first?\"\":\" \")<<v.front(); v.pop(); is_first = false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, stack<T> v) { bool is_first = true; while (!v.empty()) { os << (is_first?\"\":\" \") << v.top(); v.pop(); is_first=false; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &v) { rep (i, len(v)) os << v[i] << (i == len(v) - 1 ? \"\" : \" \"); return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { for (const auto &vec: v) { os << vec << '\\n'; } return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const deque<T> &v) { rep (i, len(v)) os << v[i] << (i == len(v) - 1 ? \"\" : \" \"); return os; }\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &v) { bool is_first = true; for (T x: v) { os << (is_first ? \"\" : \" \") << x; is_first = false; } return os; }\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in: v) { is >> in; } return is; }\n\n// For debug macro\nint find_comma_not_bracketed(string_view s){ stack<char> bs; string lbs = \"({[\", rbs = \")}]\"; for (size_t i = 0; i < s.size(); i++) { if (lbs.find(s[i]) != string::npos) bs.push(s[i]); if (rbs.find(s[i]) != string::npos and !bs.empty()) bs.pop(); if (s[i] == ',' and bs.empty()) return i; } return s.size(); }\ntemplate <typename T, typename... Ts> void debug_function(string_view name, const T &a, Ts &&...rest) { int end = find_comma_not_bracketed(name); cerr << name.substr(0, end) << \":\" << a; if constexpr (sizeof...(rest) == 0) { cerr << '\\n'; } else { cerr << ' '; debug_function(name.substr(name.find_first_not_of(' ', end + 1)), forward<Ts>(rest)...); } }\n\n// Functions\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b and (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b and (a = b, true); }\n\n// Structs\nstruct IoSetup { IoSetup(int x = 15) { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\n// Type aliases\nusing ull = unsigned long long;\nusing ll = long long;\nusing pll = pair<ll, ll>;\nusing pii = pair<int, int>;\n\n// Literals\nconstexpr ll INF64 = INT64_MAX / 2;\nconstexpr int INF32 = INT32_MAX / 2;\nconstexpr int dy[] = { 0, 1, -1, 0, -1, 1, -1, 1 };\nconstexpr int dx[] = { 1, 0, 0, -1, -1, -1, 1, 1 };\nconstexpr int mod998244353 = 998244353;\nconstexpr int mod1000000007 = static_cast<int>(1e9) + 7;\nconstexpr char newl = '\\n';\n\n// clang-format on\n\n// }}} Templates\n\n\nint main() {\n int n;\n cin >> n;\n\n vector<int> as(n), ws(n);\n cin >> as >> ws;\n\n\n vector<int> idxs(n);\n whole(iota, idxs, 0);\n\n int ans = INF32;\n\n do {\n int sum_w = 0;\n\n rep(i, n) {\n int idx = idxs[i];\n int a = as[idx];\n int w = ws[idx];\n\n if (a == 0) {\n int right_side = i + 1;\n if (right_side >= n)\n right_side = 0;\n\n int right_side_idx = idxs[right_side];\n int right_a = as[right_side_idx];\n\n if (a == 0 and right_a == 1) {\n sum_w += w;\n }\n }\n\n if (a == 1) {\n int left_side = i - 1;\n if (left_side < 0)\n left_side = n - 1;\n\n int left_side_idx = idxs[left_side];\n int left_a = as[left_side_idx];\n\n if (a == 1 and left_a == 0) {\n sum_w += w;\n }\n }\n }\n\n chmin(ans, sum_w);\n } while (whole(next_permutation, idxs));\n\n\n cout << ans << newl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3452, "score_of_the_acc": -0.8475, "final_rank": 6 }, { "submission_id": "aoj_0395_6043412", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using vc = vector<T>;\ntemplate<class T> using vvc = vc<vc<T>>;\ntemplate<class T> using vvvc = vc<vvc<T>>;\ntemplate<class T> using vvvvc = vvc<vvc<T>>;\ntemplate<class T> using PQ = priority_queue<T>;\ntemplate<class T> using invPQ = priority_queue<T, vector<T>, greater<T>>;\nusing IP = pair<int, int>;\nusing LP = pair<ll, ll>;\n#define all(x) begin(x), end(x)\n#define allr(x) rbegin(x), rend(x)\n#define rep(i, n) for (int i = 0; (i) < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); (i) < (int)(n); i++)\n#define repr(i, n) for (int i = (n) - 1; (i) >= 0; i--)\n#define rep3r(i, m, n) for (int i = (n) - 1; (i) >= (int)(m); i--)\ntemplate<class T> inline bool chmax(T & a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T & a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nsigned main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int N;\n cin >> N;\n vc<int> a(N), w(N);\n rep (i, N) cin >> a[i];\n rep (i, N) cin >> w[i];\n\n vc<int> array(N);\n rep (i, N) array[i] = i;\n\n int ans = 100000;\n do {\n int val = 0;\n rep (i, N) {\n if (a[array[i]] == 0) {\n if (a[array[(i+1)%N]] == 1) val += w[array[i]];\n }\n else {\n if (a[array[(i-1+N)%N]] == 0) val += w[array[i]];\n }\n }\n chmin(ans, val);\n } while (next_permutation(all(array)));\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3464, "score_of_the_acc": -0.9626, "final_rank": 11 }, { "submission_id": "aoj_0395_5985578", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int INF = 10000;\nint main(){\n int N;\n cin >> N;\n vector<int> a(N);\n for (int i = 0; i < N; i++){\n cin >> a[i];\n }\n vector<int> w(N);\n for (int i = 0; i < N; i++){\n cin >> w[i];\n }\n vector<int> p(N);\n for (int i = 0; i < N; i++){\n p[i] = i;\n }\n int F = 1;\n for (int i = 1; i <= N; i++){\n F *= i;\n }\n int ans = INF;\n for (int i = 0; i < F; i++){\n int s = 0;\n for (int j = 0; j < N; j++){\n if (a[p[j]] == 0){\n int j2 = (j + 1) % N;\n if (a[p[j2]] == 1){\n s += w[p[j]];\n }\n }\n if (a[p[j]] == 1){\n int j2 = (j + N - 1) % N;\n if (a[p[j2]] == 0){\n s += w[p[j]];\n }\n }\n }\n ans = min(ans, s);\n next_permutation(p.begin(), p.end());\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3484, "score_of_the_acc": -1.0029, "final_rank": 14 }, { "submission_id": "aoj_0395_5862418", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing pint = pair<int,int>;\n\n\nint main()\n{\n\tint N; cin >> N;\n\tvector<pint> A(N);\n\tfor(int i = 0; i < N; i++) cin >> A[i].first;\n\tfor(int i = 0; i < N; i++) cin >> A[i].second;\n\tsort(A.begin(), A.end());\n\tint ans = 1e9;\n\tdo {\n\n\t\tvector<pint> B = A;\n\t\tB.push_back(A[0]);\n\t\tint sum = 0;\n\t\tfor(int i = 0; i < N; i++) {\n\t\t\tif(B[i].first == 1 && B[i + 1].first == 0)sum += B[i].second + B[i + 1].second;\n\t\t}\n\t\tans = min(ans, sum);\n\t}while(next_permutation(A.begin(), A.end()));\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3416, "score_of_the_acc": -1.0022, "final_rank": 13 }, { "submission_id": "aoj_0395_5704104", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n), w(n);\n for(auto &p: a) cin >> p;\n for(auto &p: w) cin >> p;\n\n vector<int> order(n);\n for(int i = 0; i < n; i++) order[i] = i;\n\n int ans = 1001001001;\n do{\n int sum = 0;\n for(int i = 0; i < n; i++){\n if(a[order[i]] == 0 && a[order[(i+1)%n]] == 1){\n sum += w[order[i]];\n }\n if(a[order[i]] == 1 && a[order[(i+n-1)%n]] == 0){\n sum += w[order[i]];\n }\n }\n ans = min(ans, sum);\n }while(next_permutation(order.begin(), order.end()));\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3440, "score_of_the_acc": -0.9142, "final_rank": 10 }, { "submission_id": "aoj_0395_4987235", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < int(n); ++i)\n\n#pragma define \"Wall\"\n\nusing ll = long long;\n\nint main() {\n int n;\n cin >> n;\n\n vector<pair<int, int>> a(n);\n rep(i, n) {cin >> a[i].first; a[i].second = i;}\n\n vector<int> w(n);\n rep(i, n) cin >> w[i];\n\n sort(a.begin() + 1, a.end());\n int ans = 1001001001;\n do {\n int tmp = 0;\n for (size_t i = 0; i < n; i++) {\n int li = (i + n - 1) % n, ri = (i + 1) % n;\n\n int ai = a[i].first, l = a[li].first, r = a[ri].first;\n if ((ai == 0 && r == 1) || (l == 0 && ai == 1)) {\n tmp += w[a[i].second];\n }\n }\n\n ans = min(ans, tmp);\n } while (next_permutation(a.begin() + 1, a.end()));\n std::cout << ans << std::endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -0.794, "final_rank": 5 }, { "submission_id": "aoj_0395_4983619", "code_snippet": "#include <bits/stdc++.h>\nusing std::string;\n\nint main() {\n int n; std::cin >> n;\n std::vector<int> a(n), w(n);\n for (int i = 0; i < n; ++i) std::cin >> a[i];\n for (int i = 0; i < n; ++i) std::cin >> w[i];\n\n std::vector<int> perm;\n for (int i = 0; i < n; ++i) perm.push_back(i);\n int ans = 100000;\n do {\n int w_sum = 0;\n for (int i = 0; i < n; ++i) {\n int idx = perm[i];\n\n int right_side = perm[(i + 1) % n];\n int left_side = perm[(i + n - 1) % n];\n if (\n a[idx] == 0 && a[right_side] == 1 ||\n a[idx] == 1 && a[left_side] == 0\n ) {\n w_sum += w[idx];\n }\n }\n ans = std::min(ans, w_sum);\n } while (std::next_permutation(perm.begin() + 1, perm.end()));\n\n std::cout << ans << std::endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3448, "score_of_the_acc": -0.7258, "final_rank": 3 }, { "submission_id": "aoj_0395_4978556", "code_snippet": "#include<bits/stdc++.h>\n#define newl endl\n#define all(vec) vec.begin(),vec.end()\nusing namespace std;\ntemplate<class T>\nusing V=vector<T>;\nusing ll=long long;\nconst ll INF=1LL<<30;\nint main(){\n int n;cin>>n;\n V<int> a(n),w(n);\n for(int i=0;i<n;i++){\n cin>>a[i];\n }\n for(int i=0;i<n;i++){\n cin>>w[i];\n }\n V<int> b(n);\n for(int i=0;i<n;i++)b[i]=i;\n int res=INF;\n do{\n int c=0;\n for(int i=0;i<n;i++){\n int s=b[i],t=b[(i+1)%n];\n if(a[s]==1&&a[t]==0){\n c+=w[s]+w[t];\n }\n }\n res=min(res,c);\n }while(next_permutation(all(b)));\n cout<<res<<newl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3100, "score_of_the_acc": -0.206, "final_rank": 2 } ]
aoj_0397_cpp
Common-Prime Sort You are now examining a unique method to sort a sequence of numbers in increasing order. The method only allows swapping of two numbers that have a common prime factor. For example, a sequence [6, 4, 2, 3, 7] can be sorted using the following steps. Step 0: 6 4 2 3 7 (given sequence) Step 1: 2 4 6 3 7 (elements 6 and 2 swapped) Step 2: 2 6 4 3 7 (elements 4 and 6 swapped) Step 3: 2 3 4 6 7 (elements 6 and 3 swapped) Depending on the nature of the sequence, however, this approach may fail to complete the sorting. You have given a name "Coprime sort" to this approach and are now examining if a given sequence is coprime-sortable. Make a program to determine if a given sequence can be sorted in increasing order by iterating an arbitrary number of swapping operations of two elements that have a common prime number. Input The input is given in the following format. $N$ $a_1$ $a_2$ $...$ $a_N$ The first line provides the number of elements included in the sequence $N$ ($2 \leq N \leq 10^5$). The second line provides an array of integers $a_i$ ($2 \leq a_i \leq 10^5$) that constitute the sequence. Output Output " 1 " if the sequence is coprime-sortable in increasing order, or " 0 " otherwise. Sample Input 1 5 6 4 2 3 7 Sample Output 1 1 Sample Input 2 7 2 9 6 5 6 7 3 Sample Output 2 0
[ { "submission_id": "aoj_0397_10994353", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std; \n/*#include <boost/multiprecision/cpp_dec_float.hpp>\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/rational.hpp>\nusing namespace boost::multiprecision;*/\n/*#include <atcoder/all>\nusing namespace atcoder;\nusing mint = modint998244353;*/\n//long long型=int64_tという認識で大丈夫です。\n//#define int long long\n#define ll long long\n#define ull unsigned long long\n#define vec vector\n#define vi vector<int>\n#define vll vector<ll>\n#define pq priority_queue\n#define pb push_back\n#define eb emplace_back\n#define rep(i, l, r) for(ll i=(ll)(l); i<(ll)(r); i++)\n#define ld long double\n\nconst ll INF = 1e9;\nconst ll inf = 5e18;\nconst ld ep = 1e-15;\n\nstruct Edge {\n int to;\n ll cost;\n};\n\nstruct SEdge {\n int to;\n pair<ll, ll> cost;\n};\n\ntemplate<class T>\nusing spq = priority_queue<T, vec<T>, greater<T>>; \n\nconst vector<ll> di = {-1, 0, 1, 0}, dj = {0, -1, 0, 1};\n\ntemplate<class T>\nbool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T>\nbool chmax(T& a, T b) {\n if(a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<class T, class U> \nistream &operator>>(istream &is, pair<T, U> &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate<class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &v) {\n for(auto &x : v) {\n is >> x;\n }\n return is;\n}\n\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) {\n for(int i = 0; i < (int)v.size(); i++) {\n if(i != (int)v.size() - 1)\n os << v[i] << \" \";\n else\n os << v[i];\n }\n return os;\n}\n\nstring strplus(string a, string b) {\n reverse(a.begin(), a.end()); reverse(b.begin(), b.end());\n bool ch = false;\n if(a.size() < b.size()) {\n swap(a, b);\n ch = true;\n }\n string ret;\n int cnt = 0;\n rep(i, 0, a.size()) {\n if(i >= b.size()) {\n ret += (char)(((int)(a[i] - '0') + cnt) % 10 + '0');\n cnt = (((int)(a[i] - '0') + cnt) / 10);\n }\n else {\n ret += (char)(((int)(a[i] - '0' + b[i] - '0') + cnt) % 10 + '0');\n cnt = ((int)(a[i] - '0' + b[i] - '0') + cnt) / 10;\n }\n }\n if(cnt != 0) ret += \"1\";\n reverse(ret.begin(), ret.end());\n return ret;\n}\n\nstring strminus(string a, string b) {\n reverse(a.begin(), a.end()); reverse(b.begin(), b.end());\n bool ch = false;\n if(a.size() < b.size()) {\n swap(a, b);\n ch = true;\n }\n else if(a.size() == b.size() && a < b) {\n swap(a, b);\n ch = true;\n }\n string ret;\n int cnt = 0;\n rep(i, 0, a.size()) {\n if(i >= b.size()) {\n ret += (char)(((int)(a[i] - '0') + cnt + 10) % 10 + '0');\n cnt = ((int)(a[i] - '0') + cnt + 10) / 10 - 1;\n }\n else {\n ret += (char)(((int)(a[i] - b[i]) + cnt + 10) % 10 + '0');\n cnt = ((int)(a[i] - b[i]) + cnt + 10) / 10 - 1;\n }\n }\n while(ret[ret.size() - 1] == '0' && ret.size() >= 1) ret.erase(--ret.end());\n if(ret != \"0\" && ch) ret += '-';\n reverse(ret.begin(), ret.end());\n return ret;\n}\n\ntemplate <class T>\nbool jf(pair<T, T> a, pair<T, T> b) {\n if(a.second > b.second) return false;\n else return true;\n}\n\nusing S = ll;\n\nS op(S a, S b){ return max(a, b); }\nS e(){ return 0;}\n\n\nstruct dsu {\n public:\n dsu() : _n(0) {}\n explicit dsu(int n) : _n(n), parent_or_size(n, -1) {}\n\n int merge(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if (x == y) return x;\n if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);\n parent_or_size[x] += parent_or_size[y];\n parent_or_size[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n assert(0 <= a && a < _n);\n assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n assert(0 <= a && a < _n);\n return _leader(a);\n }\n\n int size(int a) {\n assert(0 <= a && a < _n);\n return -parent_or_size[leader(a)];\n }\n\n std::vector<std::vector<int>> groups() {\n std::vector<int> leader_buf(_n), group_size(_n);\n for (int i = 0; i < _n; i++) {\n leader_buf[i] = leader(i);\n group_size[leader_buf[i]]++;\n }\n std::vector<std::vector<int>> result(_n);\n for (int i = 0; i < _n; i++) {\n result[i].reserve(group_size[i]);\n }\n for (int i = 0; i < _n; i++) {\n result[leader_buf[i]].push_back(i);\n }\n result.erase(\n std::remove_if(result.begin(), result.end(),\n [&](const std::vector<int>& v) { return v.empty(); }),\n result.end());\n return result;\n }\n\n private:\n int _n;\n // root node: -1 * component size\n // otherwise: parent\n std::vector<int> parent_or_size;\n\n int _leader(int a) {\n if (parent_or_size[a] < 0) return a;\n return parent_or_size[a] = _leader(parent_or_size[a]);\n }\n};\n\nsigned main(){\n int n; cin >> n;\n vi a(n); rep(i, 0, n) cin >> a[i];\n dsu d(n);\n vec<pair<int, int>> sa(n); rep(i, 0, n) sa[i] = {a[i], i}; sort(sa.begin(), sa.end());\n rep(i, 2, 320) {\n bool ok = true;\n int b = -1;\n rep(j, 0, n) {\n if(a[j] % i == 0) {\n if(b != -1 && !d.same(j, b)) d.merge(j, b);\n while(a[j] % i == 0) a[j] /= i;\n b = j;\n }\n }\n }\n map<int, int> mp;\n rep(i, 0, n) {\n if(a[i] != 1) {\n if(mp.find(a[i]) != mp.end() && !d.same(mp[a[i]], i)) d.merge(mp[a[i]], i);\n else mp[a[i]] = i; \n }\n }\n rep(i, 0, n) {\n if(!d.same(sa[i].second, i)) {cout << 0 << endl; return 0;}\n }\n cout << 1 << endl;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 5232, "score_of_the_acc": -1.0771, "final_rank": 16 }, { "submission_id": "aoj_0397_10934333", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, s, e) for (int i = (int)(s); i < (int)(e); ++i)\n\nstruct UnionFind {\n\tvector<int> par;\n\t\n\tUnionFind(int N) : par(N, -1) {}\n\t\n\tint root(int x) {\n\t\tif (par[x] < 0) return x;\n\t\telse return par[x] = root(par[x]);\n\t}\n\t\n\tbool merge(int x, int y) {\n\t\tif ((x = root(x)) == (y = root(y))) return false;\n\t\tif (par[x] > par[y]) swap(x, y);\n\t\tpar[x] += par[y];\n\t\tpar[y] = x;\n\t\treturn true;\n\t}\n\t\n\tbool same(int x, int y) {\n\t\treturn root(x) == root(y);\n\t}\n};\n\nint main() {\n\tcin.tie(nullptr);\n\tios_base::sync_with_stdio(false);\n\t\n\tint N;\n\tcin >> N;\n\tvector<int> A(N);\n\tvector<pair<int, int>> sorted(N);\n\trep(i, 0, N) {\n\t\tcin >> A[i];\n\t\tsorted[i] = {A[i], i};\n\t}\n\tsort(sorted.begin(), sorted.end());\n\t\n\tint maxi = 100010;\n\tvector<int> isPrime(maxi, 1);\n\tisPrime[0] = isPrime[1] = -1;\n\trep(p, 2, maxi) {\n\t\tif (isPrime[p] == -1) continue;\n\t\tfor (int q = p*2; q < maxi; q += p) isPrime[q] = -1;\n\t}\n\t\n\tint cnt = 0;\n\trep(i, 0, maxi) if (isPrime[i] == 1) {\n\t\tisPrime[i] = cnt;\n\t\t++cnt;\n\t}\n\t\n\tUnionFind uf(N + cnt);\n\trep(i, 0, N) {\n\t\tfor (int p = 2; p*p <= A[i]; ++p) if (A[i] % p == 0) {\n\t\t\tuf.merge(i, isPrime[p] + N);\n\t\t\twhile (A[i] % p == 0) A[i] /= p;\n\t\t}\n\t\tif (A[i] != 1) uf.merge(i, isPrime[A[i]] + N);\n\t}\n\t\n\tbool can = true;\n\trep(i, 0, N) {\n\t\tif (!uf.same(sorted[i].second, i)) can = false;\n\t}\n\tcout << (can ? 1 : 0) << '\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5180, "score_of_the_acc": -0.1751, "final_rank": 1 }, { "submission_id": "aoj_0397_10848101", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define all(a) a.begin(),a.end()\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef pair<int,int> P;\nconstexpr ll mod = 998244353;\nint par[200005],siz[200005];\n\nint find(int x){\n\tif(x==par[x])return x;\n\treturn par[x]=find(par[x]);\n}\nvoid unite(int x,int y){\n\tx=find(x),y=find(y);\n\tif(x==y)return;\n\tif(siz[x]>siz[y])swap(x,y);\n\tpar[x]=par[y];siz[y]+=siz[x];\n}\n\nint a[200005];\nvector<int>G[200005];\nint main(){\n\tint n;cin>>n;\n\trep(i,n)cin>>a[i];\n\trep(i,n+100000){\n\t\tpar[i]=i;siz[i]=1;\n\t}\n\n\trep(i,n){\n\t\tint x=a[i];\n\t\tfor(int j=2;j*j<=x;j++){\n\t\t\tif(x%j==0)unite(i,n+j);\n\t\t\twhile(x%j==0)x/=j;\n\t\t}\n\t\tif(x>1)unite(i,n+x);\n\t}\n\trep(i,n){\n\t\tG[find(i)].push_back(i);\n\t}\n\tvector<P>V;\n\trep(i,n)V.push_back(P(a[i],i));\n\tsort(all(V));\n\trep(i,n){\n\t\tV[i].first=i;\n\t\tswap(V[i].first,V[i].second);\n\t}\n\tsort(all(V));\n\trep(i,n+100000){\n\t\tvector<int>v2;\n\t\trep(j,G[i].size()){\n\t\t\tv2.push_back(V[G[i][j]].second);\n\t\t}\n\t\tsort(all(v2));sort(all(G[i]));\n\t\tif(v2!=G[i]){\n\t\t\tcout<<0<<endl;return 0;\n\t\t}\n\t}\n\tcout<<1<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12236, "score_of_the_acc": -0.5538, "final_rank": 12 }, { "submission_id": "aoj_0397_10830019", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\nusing namespace std;\ntypedef long long ll;\n#define mod 1000000007\nvector<ll> g[100010];\nll n,a[100010];\nvector<ll> p[100010];\n\nbool vis[100010];\nvector<ll> t;\nvector<pair<ll,ll> > v;\nvoid dfs(ll x){\n if(vis[x])return;\n vis[x]=1;\n t.push_back(x);\n v.push_back(make_pair(a[x],x));\n for(auto y:g[x]){\n\tdfs(y);\n }\n}\nll renew[100010];\nint main(){\n cin>>n;\n for(int i=0;i<n;i++){\n cin>>a[i];\n ll x=a[i];\n for(ll k=2;k*k<=x;k++){\n\t if(x%k==0)p[k].push_back(i);\n\t while(x%k==0)x/=k;\n }\n if(x>1)p[x].push_back(i);\n }\n for(ll k=2;k<100010;k++){\n for(int i=1;i<p[k].size();i++){\n\t g[p[k][i-1]].push_back(p[k][i]);\n\t g[p[k][i]].push_back(p[k][i-1]);\n\t //cout<<a[p[k][i]]<<\" \"<<a[p[k][i-1]]<<endl;\n }\n }\n for(int i=0;i<n;i++)vis[i]=0;\n for(int i=0;i<n;i++){\n v.clear();\n t.clear();\n dfs(i);\n if(v.size()>0){\n\t sort(v.begin(),v.end());\n\t sort(t.begin(),t.end());\n\t for(int j=0;j<v.size();j++){\n\t renew[t[j]]=v[j].first;\n\t //cout<<t[j]<<\" \";\n\t }//cout<<endl;\n }\n }\n bool ok=1;\n for(int i=0;i<n-1;i++){\n ok&=(renew[i]<=renew[i+1]);\n }\n cout<<ok<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 28596, "score_of_the_acc": -1.6, "final_rank": 19 }, { "submission_id": "aoj_0397_10806714", "code_snippet": "#include <iostream>\n#include <vector>\n#include <math.h>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <string>\n#include <bitset>\n#include <iomanip>\nusing namespace std;\nusing ll = long long;\nusing VVI = vector<vector<int>>;\nusing VVL = vector<vector<ll>>;\nusing VI = vector<int>;\nusing VL = vector<ll>;\nusing VS = vector<string>;\nusing VC = vector<char>;\nusing VP = vector<pair<int, int>>;\nusing Graph0 = vector<vector<int>>;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define drep(i, a, b) for (int i = (int)(a);i >= (int)(b);i--)\n#define urep(i, a, b) for (int i = (int)(a);i <= (int)(b);i++)\n#define lrep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define ldrep(i, a, b) for (ll i = (ll)(a);i >= (ll)(b);i--)\n#define lurep(i, a, b) for (ll i = (ll)(a);i <= (ll)(b);i++)\n#define arep(i, v) for (auto i : v)\n#define all(a) (a).begin(), (a).end()\n#define yes cout << \"Yes\" << endl\n#define no cout << \"No\" << endl\n#define eyes cout << \"Yes\" << endl;exit(0);\n#define eno cout << \"No\" << endl;exit(0);\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n if (a < b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n if (a > b) {\n a = b; \n return true;\n }\n return false;\n}\ntemplate<typename T>\nvoid excout(T A) {\n cout << A << endl;\n exit(0);\n}\nconstexpr long long INF = (1LL << 60); // INFにちゅういい!\n\n\nstruct Edge\n{\n int to;\n int cost;\n};\nusing Graph = std::vector<std::vector<Edge>>;\nusing Pair = std::pair<long long, int>;\nvoid Dijkstra(const Graph& graph, std::vector<long long>& distances, int startIndex)\n{\n std::priority_queue<Pair, std::vector<Pair>, std::greater<Pair>> q;\n q.emplace((distances[startIndex] = 0), startIndex);\n\n while (!q.empty())\n {\n const long long distance = q.top().first;\n const int from = q.top().second;\n q.pop();\n if (distances[from] < distance)\n {\n continue;\n }\n for (const auto& edge : graph[from])\n {\n const long long d = (distances[from] + edge.cost);\n if (d < distances[edge.to])\n {\n q.emplace((distances[edge.to] = d), edge.to);\n }\n }\n }\n}\ntemplate<typename T>\nT MODS(T a, T mods) {\n return ((((((a + mods) % mods) + mods) % mods)));\n}\nVVL comb(int n, int r) {\n VVL v(n + 1, VL (n + 1, 0));\n for (int i = 0; i < v.size(); i++) {\n v[i][0] = 1;\n v[i][i] = 1;\n }\n for (int j = 1; j < v.size(); j++) {\n for (int k = 1; k < j; k++) {\n v[j][k] = (v[j - 1][k - 1] + v[j - 1][k]);\n }\n }\n return v;\n}\nvector<pair<long long, long long> > prime_factorize(long long N) {\n vector<pair<long long, long long> > res;\n for (long long p = 2; p * p <= N; ++p) {\n if (N % p != 0) {\n continue;\n }\n int e = 0;\n while (N % p == 0) {\n ++e;\n N /= p;\n }\n res.emplace_back(p, e);\n }\n if (N != 1) {\n res.emplace_back(N, 1);\n }\n return res;\n}\n\nstruct UnionFind {\n vector<int> par, siz;\n UnionFind(int n) : par(n, -1), siz(n, 1) {}\n int root(int x) {\n if (par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n bool unite(int x, int y) {\n x = root(x);y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x) {\n return siz[root(x)];\n }\n};\ntemplate<class Abel> struct WUnionFind {\n vector<int> par;\n vector<int> rank;\n vector<Abel> diff_weight;\n\n WUnionFind(int n = 1, Abel SUM_UNITY = 0) {\n init(n, SUM_UNITY);\n }\n\n void init(int n = 1, Abel SUM_UNITY = 0) {\n par.resize(n); rank.resize(n); diff_weight.resize(n);\n for (int i = 0; i < n; ++i) par[i] = i, rank[i] = 0, diff_weight[i] = SUM_UNITY;\n }\n\n int root(int x) {\n if (par[x] == x) {\n return x;\n }\n else {\n int r = root(par[x]);\n diff_weight[x] += diff_weight[par[x]];\n return par[x] = r;\n }\n }\n\n Abel weight(int x) {\n root(x);\n return diff_weight[x];\n }\n\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n\n bool merge(int x, int y, Abel w) { //W(y)=W(x)+w\n w += weight(x); w -= weight(y);\n x = root(x); y = root(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y), w = -w;\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n diff_weight[y] = w;\n return true;\n }\n\n Abel diff(int x, int y) { // W(y) - W(x)\n return weight(y) - weight(x);\n }\n};\nVI topo_sort(Graph0& G) {\n int N = G.size();\n VI IND(N, 0);\n rep(v, N) {\n arep(nv, G[v]) {\n IND[nv]++;\n }\n }\n queue<int> que;\n rep(v, N) {\n if (IND[v] == 0) {\n que.push(v);\n }\n }\n VI ANS;\n while (!que.empty()) {\n int v = que.front();\n ANS.push_back(v);\n que.pop();\n arep(nv, G[v]) {\n IND[nv]--;\n if (IND[nv] == 0) {\n que.push(nv);\n }\n }\n }\n return ANS;\n}\nvoid ADD(int a, int b, Graph0& G) {\n G[a].push_back(b);\n G[b].push_back(a);\n}\nVP near(int i, int j, int H, int W) {\n VP ans;\n VP cand = {{i - 1, j}, {i + 1, j}, {i, j - 1}, {i, j + 1}};\n arep(v, cand) {\n if (v.first < 0 or v.first >= H) continue;\n if (v.second < 0 or v.second >= W) continue;\n ans.push_back(v);\n }\n return ans;\n}\nint cast(int i, int j, int H, int W) {\n return ((W * i) + j);\n}\nll pows(ll x, ll n, ll mod) {\n if (!n) return 1;\n x %= mod;\n ll r = pows(x, n / 2, mod);\n (r *= r) %= mod;\n if (n % 2) (r *=x) %= mod;\n return r;\n}\nstruct COMB_MOD {\n ll mod;\n int MAX;\n VL fac, finv, inv;\n COMB_MOD(int max, ll m) {\n fac.assign(max, 0);\n finv.assign(max, 0);\n inv.assign(max, 0);\n mod = m;\n MAX = max;\n }\n void solve() {\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < MAX; i++){\n fac[i] = fac[i - 1] * i % mod;\n\n inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n finv[i] = finv[i - 1] * inv[i] % mod;\n }\n \n }\n ll comb(int n, int k) {\n if (n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n - k] % mod) % mod;\n }\n};\n\nstruct LCA {\n vector<vector<int>> parent; \n vector<int> dist; \n LCA(const Graph0 &G, int root = 0) { init(G, root); }\n void init(const Graph0 &G, int root = 0) {\n int V = G.size();\n int K = 1;\n while ((1 << K) < V) K++;\n parent.assign(K, vector<int>(V, -1));\n dist.assign(V, -1);\n dfs(G, root, -1, 0);\n for (int k = 0; k + 1 < K; k++) {\n for (int v = 0; v < V; v++) {\n if (parent[k][v] < 0) {\n parent[k + 1][v] = -1;\n } else {\n parent[k + 1][v] = parent[k][parent[k][v]];\n }\n }\n }\n }\n void dfs(const Graph0 &G, int v, int p, int d) {\n parent[0][v] = p;\n dist[v] = d;\n for (auto e : G[v]) {\n if (e != p) dfs(G, e, v, d + 1);\n }\n }\n int query(int u, int v) {\n if (dist[u] < dist[v]) swap(u, v); \n int K = parent.size();\n for (int k = 0; k < K; k++) {\n if ((dist[u] - dist[v]) >> k & 1) {\n u = parent[k][u];\n }\n }\n if (u == v) return u;\n for (int k = K - 1; k >= 0; k--) {\n if (parent[k][u] != parent[k][v]) {\n u = parent[k][u];\n v = parent[k][v];\n }\n }\n return parent[0][u];\n }\n int get_dist(int u, int v) { return dist[u] + dist[v] - 2 * dist[query(u, v)]; }\n};\nint main(void) {\n int N;cin >> N;\n int K = 1e5 + 1;\n VI A(N);\n VI P(K+1, -1);\n rep(i, N){\n cin >> A[i];\n P[A[i]] = i;\n }\n UnionFind uf(K+1);\n urep(k, 2, K) {\n int now = k;\n VI value;\n while (now <= K) {\n if (P[now] >= 0) value.push_back(now);\n now += k;\n }\n rep(i, value.size()-1) uf.unite(value[i],value[i+1]);\n }\n vector<vector<pair<int,int>>> CP(K+1);\n rep(i, N) CP[uf.root(A[i])].push_back({A[i], i});\n rep(i, K+1) {\n sort(all(CP[i]));\n VI ID;\n arep(v, CP[i]) ID.push_back(v.second);\n sort(all(ID));\n rep(t, ID.size()) A[ID[t]] = CP[i][t].first;\n }\n rep(i, N-1) {\n if (A[i] > A[i+1]) {\n cout << 0 << endl;\n return 0;\n }\n }\n cout << 1 << endl;\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 9012, "score_of_the_acc": -0.2264, "final_rank": 3 }, { "submission_id": "aoj_0397_9802794", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nstruct UnionFind{\n int N;\n vector<int> parent;\n\n UnionFind(int N):N(N),parent(N,-1){}\n\n int leader(int x){\n if(parent[x]<0) return x;\n return parent[x] = leader(parent[x]);\n }\n\n\n void merge(int x,int y){\n int xp = leader(x);\n int yp = leader(y);\n if(xp==yp) return ;\n if(xp<yp) swap(xp,yp);\n parent[yp] += parent[xp];\n parent[xp] = yp;\n }\n\n bool same(int x,int y){\n return leader(x)==leader(y);\n }\n\n int size(int x){\n return -parent[leader(x)];\n }\n\n vector<vector<int>> groups(){\n vector<vector<int>> a(N);\n rep(i,N) a[leader(i)].push_back(i);\n vector<vector<int>> uni;\n rep(i,N) if(!a[i].empty()) uni.push_back(a[i]);\n\n return uni;\n }\n};\n\n\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n \n int N;\n cin >> N;\n vector<int>a(N);\n rep(i,N)cin>>a[i];\n\n map<int,int> ma;\n \n UnionFind uf(N);\n\n rep(i,N){\n ll x = a[i];\n for(int j=2;j*j<=x;j++){\n if(x%j==0){\n if(ma.count(j)) uf.merge(ma[j],i);\n ma[j]=i;\n while(x%j==0){\n x/=j;\n }\n }\n }\n if(x>1){\n if(ma.count(x)) uf.merge(ma[x],i);\n ma[x]=i;\n }\n }\n\n vector<vector<int>> g = uf.groups();\n\n vector<int> sorted(N);\n for(vector<int> v:g){\n sort(v.begin(),v.end());\n vector<int> b;\n for(int e: v) b.push_back(a[e]);\n sort(b.begin(),b.end());\n rep(i,v.size()){\n sorted[v[i]] = b[i];\n }\n }\n rep(i,N-1){\n if(sorted[i]>sorted[i+1]){\n cout << 0 << endl;\n return 0;\n }\n }\n cout << 1 << endl;\n\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 8360, "score_of_the_acc": -0.8507, "final_rank": 15 }, { "submission_id": "aoj_0397_9785928", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,N) for(ll i=0;i<N;i++)\n#define all(A) A.begin(),A.end()\n#define fi first\n#define se second\nconst ll mod = 1e9+7;\nconst ll INF = 1LL<<60;\n\nstruct unionfind{\n\tunionfind() {}\n\tvector<ll> par,sz;\n\tunionfind(ll N):par(N),sz(N){\n\t\trep(i,N) par[i]=i,sz[i]=1;\n\t}\n\tll root(ll x){\n\t\tif(par[x]==x) return x;\n\t\tll r=root(par[x]);\n\t\tpar[x]=r;\n\t\treturn r;\n\t}\n\tvoid unite(ll x,ll y){\n\t\tll rx=root(x);\n\t\tll ry=root(y);\n\t\tif(rx==ry) return;\n\t\tif(sz[rx]>sz[ry]) swap(rx,ry);\n\t\tpar[rx]=ry;\n\t\tsz[ry]+=sz[rx];\n\t}\n\tbool same(ll x,ll y){\n\t\tll rx=root(x);\n\t\tll ry=root(y);\n\t\treturn rx==ry;\n\t}\n\tll size(ll x){\n\t\treturn sz[x];\n\t}\n};\t\t\t\t\t\n\nint main(){\n\tll N;\n\tcin >> N;\n\tvector<ll> A(N);\n\trep(i,N) cin >> A[i];\n\tvector<pair<ll,ll>> P(N);\n\trep(i,N) P[i].fi=A[i],P[i].se=i;\n\tsort(all(P));\n\tvector<ll> inv(100500,-1);\n\trep(i,N) inv[A[i]]=i;\n\tvector<vector<ll>> G(100500);\n\trep(i,N) G[A[i]].push_back(i);\n\tunionfind tree(N);\n\trep(i,100500){\n\t\trep(j,(ll)G[i].size()-1){\n\t\t\ttree.unite(G[i][j],G[i][j+1]);\n\t\t}\n\t}\n\tfor(ll i=2;i<100500;i++){\n\t\tvector<ll> V;\n\t\tfor(ll j=i;j<100500;j+=i){\n\t\t\tif(inv[j]!=-1) V.push_back(inv[j]);\n\t\t}\n\t\trep(j,(ll)V.size()-1){\n\t\t\ttree.unite(V[j],V[j+1]);\n\t\t}\n\t}\n\tbool ok=true;\n\trep(i,N){\n\t\tif(!tree.same(i,P[i].se)) ok=false;\n\t}\n\tif(ok){\n\t\tcout << 1 << endl;\n\t}else{\n\t\tcout << 0 << endl;\n\t}\t\t\t\t\t\t\t\t\t\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 13952, "score_of_the_acc": -0.4716, "final_rank": 11 }, { "submission_id": "aoj_0397_8259287", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<int> sosuu(0);\nmap<int,int> soinsuu;\nint check(int i){\n int ans=1;\n if(!soinsuu.count(i)){\n int r=i;\n for(int j=0;j<sosuu.size()&&r>=sosuu.at(j)&&!soinsuu.count(r);j+=1){\n int e=0;\n while(r%sosuu.at(j)==0){\n e=1;\n r/=sosuu.at(j);\n }\n if(e==1){\n ans*=sosuu.at(j);\n }\n }\n soinsuu[i]=ans*soinsuu[r];\n soinsuu[ans*soinsuu[r]]=ans*soinsuu[r];\n }\n return 0;\n}\nint yakusuu(int a,int b){\n while(b!=0){\n a-=(a/b*b);\n swap(a,b);\n }\n return a;\n}\nint main(){\n soinsuu[1]=1;\n sosuu.push_back(2);\n for(long i=3,o=1;i<100000;i+=2,o=1){\n for(int j=3;j*j<=i;j+=1){\n if(i%j==0){\n o=0;\n break;\n }\n }\n if(o==1){\n soinsuu[i]=i;\n sosuu.push_back(i);\n }\n }\n int a;\n cin>>a;\n vector<int> pre(a);\n vector<int> srt(a);\n for(int i=0;i<a;i+=1){\n cin>>pre.at(i);\n srt.at(i)=pre.at(i);\n check(pre.at(i));\n }\n sort(srt.begin(),srt.end());\n vector<int> kouho(0);\n for(int i=0;i<a;i+=1){\n if(yakusuu(pre.at(i),srt.at(i))==1){\n kouho.push_back(soinsuu[pre.at(i)]*soinsuu[srt.at(i)]/yakusuu(soinsuu[pre.at(i)],soinsuu[srt.at(i)]));\n }\n }\n for(int i=0;i<kouho.size();i+=1){\n if(!soinsuu.count(kouho.at(i))){\n cout<<0<<endl;\n return 0;\n }\n }\n cout<<1<<endl;\n}", "accuracy": 0.05, "time_ms": 20, "memory_kb": 3280, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0397_7077275", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nll gcd(ll a, ll b) {return (b == 0 ? a : gcd(b, a % b));}\nll lcm(ll a, ll b) {return a / gcd(a, b) * b;}\nstruct UnionFind {\n vector<ll> par,siz;\n UnionFind(ll N) : par(N, -1), siz(N, 1) {}\n ll root(ll v) {\n if (par[v] == -1) return v;\n else return par[v] = root(par[v]);\n }\n bool same(ll u, ll v) {\n return root(u) == root(v);\n }\n bool unite(ll u, ll v) {\n u = root(u), v = root(v);\n if (u == v) return false;\n if (siz[u] < siz[v]) swap(u, v);\n par[v] = u;\n siz[u] += siz[v];\n return true;\n }\n};\nint main() {\n\tll N; cin >> N;\n UnionFind uf(N);\n vector<ll>A(N);\n vector<vector<ll>>B(100001);\n for (ll i = 0; i < N; i++) {\n cin >> A[i];\n B[A[i]].push_back(i);\n for (ll j = 2; j * j <= A[i]; j++) {\n if (A[i] % j == 0) {\n B[j].push_back(i);\n if (j * j != A[i] && A[i] % (A[i] / j) == 0) {\n B[A[i] / j].push_back(i);\n }\n }\n }\n }\n for (ll i = 0; i <= 100000; i++) {\n for (ll j = 0; j + 1 < B[i].size(); j++) {\n uf.unite(B[i][j], B[i][j + 1]);\n }\n }\n vector<P>C(N);\n for (ll i = 0; i < N; i++) {\n C[i] = make_pair(A[i], i);\n }\n sort(C.begin(), C.end());\n for (ll i = 0; i < N; i++) {\n if (!uf.same(i, C[i].second)) {\n cout << 0 << endl;\n return 0;\n }\n }\n cout << 1 << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 23428, "score_of_the_acc": -1.5459, "final_rank": 18 }, { "submission_id": "aoj_0397_7073943", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nstruct UnionFind {\n\tvector<int> par;\n\tUnionFind(const int n) : par(n, -1) {}\n\tint find(int u) {\n\t\treturn par[u] < 0 ? u : par[u] = find(par[u]);\n\t}\n\tvoid merge(int x, int y) {\n\t\tx = find(x);\n\t\ty = find(y);\n\t\tif (x == y) return;\n\t\tif (par[x] > par[y]) swap(x, y);\n\t\tpar[x] += par[y];\n\t\tpar[y] = x;\n\t}\n};\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\n\n\tint N;\n\tcin >> N;\n\tvector<int> A(N);\n\tvector<vector<int>> list(100001);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> A[i];\n\t\tlist[A[i]].push_back(i);\n\t}\n\n\tUnionFind uf(N);\n\tfor (int d = 2; d <= 100000; ++d) {\n\t\tint id = -1;\n\t\tfor (int n = d; n <= 100000; n += d) {\n\t\t\tfor (const int i : list[n]) {\n\t\t\t\tif (id == -1) {\n\t\t\t\t\tid = i;\n\t\t\t\t} else {\n\t\t\t\t\tuf.merge(id, i);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tvector<vector<int>> groups(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tgroups[uf.find(i)].push_back(i);\n\t}\n\tfor (const auto& id : groups) {\n\t\tvector<int> val;\n\t\tfor (const int i : id) {\n\t\t\tval.push_back(A[i]);\n\t\t}\n\t\tsort(begin(val), end(val));\n\t\tfor (int i = 0; i < (int)size(val); ++i) {\n\t\t\tA[id[i]] = val[i];\n\t\t}\n\t}\n\t\n\tcout << is_sorted(begin(A), end(A)) << '\\n';\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 12904, "score_of_the_acc": -0.3802, "final_rank": 8 }, { "submission_id": "aoj_0397_7062749", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define vi vector<int>\nusing namespace std;\n\nstruct UnionFind {\n vi d;\n UnionFind(int n) : d(n, -1){}\n int root(int x){\n if(d[x] < 0) return x;\n return d[x] = root(d[x]);\n }\n bool unite(int x, int y){\n x = root(x);\n y = root(y);\n if(x == y) return false;\n if(d[x] > d[y]) swap(x, y);\n d[x] += d[y];\n d[y] = x;\n return true;\n }\n};\n\nint main(){\n int n;\n cin >> n;\n vi a(n);\n rep(i, n) cin >> a[i];\n UnionFind tree(n);\n for(int i = 2; i*i <= 100000; i++){\n int last = -1;\n rep(j, n) if(a[j] % i == 0){\n if(last != -1) tree.unite(last, j);\n last = j;\n }\n }\n vector<vi> group(n);\n rep(i, n) group[tree.root(i)].push_back(a[i]);\n rep(i, n) sort(group[i].rbegin(), group[i].rend());\n rep(i, n){\n vi &g = group[tree.root(i)];\n a[i] = g.back();\n g.pop_back();\n }\n rep(i, n - 1) if(a[i] > a[i+1]){\n cout << \"0\\n\";\n return 0;\n }\n cout << \"1\\n\";\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9384, "score_of_the_acc": -0.5911, "final_rank": 13 }, { "submission_id": "aoj_0397_6974983", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0397.cc: Common-Prime Sort\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_P = 100000;\n\n/* typedef */\n\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\n\nstruct UFT {\n vector<int> links, ranks, sizes;\n UFT() {}\n\n void init(int n) {\n links.resize(n);\n for (int i = 0; i < n; i++) links[i] = i;\n ranks.assign(n, 1);\n sizes.assign(n, 1);\n }\n\n int root(int i) {\n int i0 = i;\n while (links[i0] != i0) i0 = links[i0];\n return (links[i] = i0);\n }\n\n int rank(int i) { return ranks[root(i)]; }\n int size(int i) { return sizes[root(i)]; }\n bool same(int i, int j) { return root(i) == root(j); }\n\n int merge(int i0, int i1) {\n int r0 = root(i0), r1 = root(i1), mr;\n if (r0 == r1) return r0;\n if (ranks[r0] == ranks[r1]) {\n links[r1] = r0;\n sizes[r0] += sizes[r1];\n ranks[r0]++;\n mr = r0;\n }\n else if (ranks[r0] > ranks[r1]) {\n links[r1] = r0;\n sizes[r0] += sizes[r1];\n mr = r0;\n }\n else {\n links[r0] = r1;\n sizes[r1] += sizes[r0];\n mr = r1;\n }\n return mr;\n }\n};\n\n/* global variables */\n\nint pdivs[MAX_P + 1];\nint as[MAX_N], bs[MAX_N], gs[MAX_N], cs[MAX_N], tmp[MAX_N];\nvi pds[MAX_N];\nUFT uft;\n\n/* subroutines */\n\nint gen_primes(int maxp, vi &pnums) {\n pdivs[0] = 0, pdivs[1] = 1;\n\n int p;\n for (p = 2; p * p <= maxp; p++)\n if (! pdivs[p]) {\n pnums.push_back(p), pdivs[p] = p;\n for (int q = p * p; q <= maxp; q += p)\n\tif (! pdivs[q]) pdivs[q] = p;\n }\n for (; p <= maxp; p++)\n if (! pdivs[p]) pnums.push_back(p), pdivs[p] = p;\n return (int)pnums.size();\n}\n\nvoid prime_decomp(int n, vi &pds) {\n pds.clear();\n //printf(\"%d =\", n);\n while (n > 1) {\n int p = pdivs[n];\n pds.push_back(p);\n while (pdivs[n] == p) n /= p;\n }\n //for (auto p: pds) printf(\" %d\", p); putchar('\\n');\n}\n\n/* main */\n\nint main() {\n vi pnums;\n int pn = gen_primes(MAX_P, pnums);\n //printf(\"pn=%d\\n\", pn);\n\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n copy(as, as + n, bs);\n sort(bs, bs + n);\n //for (int i = 0; i < n; i++) printf(\"%d,%d \", as[i], bs[i]); putchar('\\n');\n\n vi pdv;\n for (int i = 0; i < n; i++) {\n prime_decomp(as[i], pds[i]);\n for (auto p: pds[i]) pdv.push_back(p);\n }\n\n sort(pdv.begin(), pdv.end());\n pdv.erase(unique(pdv.begin(), pdv.end()), pdv.end());\n int k = pdv.size();\n //for (auto p: pdv) printf(\"%d \", p); putchar('\\n');\n \n uft.init(n + k);\n\n for (int i = 0; i < n; i++)\n for (auto p: pds[i]) {\n int j = lower_bound(pdv.begin(), pdv.end(), p) - pdv.begin();\n uft.merge(i, n + j);\n }\n\n fill(gs, gs + n, -1);\n int gn = 0;\n vvi vvs;\n for (int i = 0; i < n; i++) {\n int ri = uft.root(i);\n if (gs[ri] < 0) gs[ri] = gn++, vvs.push_back(vi());\n gs[i] = gs[ri];\n vvs[gs[i]].push_back(i);\n }\n \n //for (int i = 0; i < gn; i++) {\n //for (auto u: vvs[i]) printf(\"%d \", u); putchar('\\n');\n //}\n\n for (auto &vs: vvs) {\n int m = 0;\n for (auto j: vs) tmp[m++] = as[j];\n sort(tmp, tmp + m);\n for (int i = 0; i < m; i++) cs[vs[i]] = tmp[i];\n }\n\n bool ok = true;\n for (int i = 0; ok && i < n; i++) ok = (cs[i] == bs[i]);\n\n if (ok) puts(\"1\");\n else puts(\"0\");\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 13608, "score_of_the_acc": -0.458, "final_rank": 10 }, { "submission_id": "aoj_0397_6807896", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstruct UnionFind{\n vector<int> par,siz;\n UnionFind(int n):par(n,-1),siz(n,1){}\n int root(int x){\n if(par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x,int y){\n if(root(x) == root(y)) return true;\n else return false;\n }\n bool unite(int x,int y){\n x = root(x);\n y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) swap(x,y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x){\n return siz[root(x)];\n }\n};\n\nint main(){\n int N;\n cin >> N;\n int M = 100000;\n vector<int> A(N);\n for(int i=0;i<N;i++) cin >> A[i];\n UnionFind uf(N);\n vector<vector<int>> pos(M+1);\n for(int i=0;i<N;i++) pos[A[i]].push_back(i);\n vector<int> P(0);\n for(int i=2;i<=M;i++){\n int d = i;\n for(int j=2;j*j<=i;j++){\n if(i%j == 0) d /= j;\n }\n if(d == i) P.push_back(i);\n }\n for(int i=0;i<P.size();i++){\n int p = P[i];\n vector<int> B(0);\n for(int j=p;j<=M;j+=p){\n for(int k=0;k<pos[j].size();k++){\n B.push_back(pos[j][k]);\n }\n }\n for(int j=1;j<B.size();j++) uf.unite(B[0],B[j]);\n }\n vector<int> SA(N);\n for(int i=0;i<N;i++) SA[i] = A[i];\n sort(SA.begin(),SA.end());\n vector<vector<int>> tobe(M+1);\n for(int i=0;i<N;i++) tobe[SA[i]].push_back(i);\n vector<int> POS(N);\n for(int i=0;i<N;i++){\n int a = A[i];\n POS[i] = tobe[a].back();\n tobe[a].pop_back();\n }\n bool flag = true;\n for(int i=0;i<N;i++) if(!uf.issame(i,POS[i])) flag = false;\n if(flag) cout << 1 << endl;\n else cout << 0 << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 15740, "score_of_the_acc": -0.7922, "final_rank": 14 }, { "submission_id": "aoj_0397_6693214", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nvector<ll> enum_prime(ll N){\n\tdeque<bool> is_prime(N+1,true);\n\tvector<ll> P;\n\tfor(ll i=2;i<=N;i++){\n\t\tif(is_prime[i]){\n\t\t\tfor(ll j=i*i;j<=N;j+=i){\n\t\t\t\tis_prime[j] = false;\n\t\t\t}\n\t\t\tP.emplace_back(i);\n\t\t}\n\t}\n\treturn P;\n}\n\nclass UnionFind{\n\tvector<ll> rank;\n\tvector<ll> diff_weight;\n\tvector<ll> num;\npublic:\n\tvector<ll> par;\n\n\tUnionFind(ll N):par(N),num(N),rank(N),diff_weight(N){\n\t\tfor(ll i=0;i<N;i++){\n\t\t\tpar[i]=i;\n\t\t\tnum[i]=1;\n\t\t\trank[i]=0;\n\t\t\tdiff_weight[i]=0;\n\t\t}\n\t}\n\n\tll root(ll x){\n\t\tif(par[x]==x){\n\t\t\treturn x;\n\t\t}\n\t\tll r = root(par[x]);\n\t\tdiff_weight[x]+=diff_weight[par[x]];\n\t\treturn par[x]=r;\n\t}\n\n\tvoid unite(ll x,ll y){\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\tif(rx == ry) return;\n\t\tif(rank[rx]<rank[ry]) swap(rx,ry);\n\t\tif(rank[rx]==rank[ry]) ++rank[rx];\n\t\tpar[ry] = rx;\n\t\tnum[rx] += num[ry];\n\t}\n\n\t// yはxよりw大きい\n\tvoid relate(ll x,ll y,ll w){\n\t\tw+=weight(x),w-=weight(y);\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\tif(rx == ry) return;\n\t\tif(rank[rx]<rank[ry]){\n\t\t\tswap(rx,ry);\n\t\t\tw = -w;\n\t\t}\n\t\tif(rank[rx]==rank[ry]) ++rank[rx];\n\t\tpar[ry] = rx;\n\t\tdiff_weight[ry] = w;\n\t\tnum[rx] += num[ry];\n\t}\n\n\tbool same(ll x,ll y){\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\treturn rx == ry;\n\t}\n\n\tll getsize(ll x){\n\t\treturn num[root(x)];\n\t}\n\n\tll weight(ll x){\n\t\troot(x);\n\t\treturn diff_weight[x];\n\t}\n\n\tll diff(ll x,ll y){\n\t\treturn weight(y)-weight(x);\n\t}\n};\n\nvector<ll> prime_factor(ll n,vll& prime_list){\n\tll sn = sqrt(n)+1;\n\tvector<ll> res;\n\tfor(int i=0,ei=prime_list.size();i<ei;i++){\n\t\tll v = prime_list[i];\n\t\tif(v*v>n) break;\n\t\twhile(!(n%v)){\n\t\t\tn /= v;\n\t\t\tres.push_back(v);\n\t\t}\n\t}\n\tif(n>1){\n\t\tres.push_back(n);\n\t}\n\n\treturn res;\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tll N=in();\n\tvll A=vecin(N);\n\tvll B=A;\n\tsort(ALL(B));\n\t\n\tvll P=enum_prime(100010);\n\tUnionFind uf(100010);\n\tREP(i,N){\n\t\tauto F=prime_factor(A[i],P);\n\t\tsort(ALL(F));\n\t\tF.erase(unique(ALL(F)),F.end());\n\t\tfor(auto& x:F) uf.unite(A[i],x);\n\t}\n\tREP(i,N){\n\t\tif(!uf.same(A[i],B[i])){\n\t\t\tout(0);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tout(1);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8040, "score_of_the_acc": -0.288, "final_rank": 5 }, { "submission_id": "aoj_0397_6043477", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using vc = vector<T>;\ntemplate<class T> using vvc = vc<vc<T>>;\ntemplate<class T> using vvvc = vc<vvc<T>>;\ntemplate<class T> using vvvvc = vvc<vvc<T>>;\ntemplate<class T> using PQ = priority_queue<T>;\ntemplate<class T> using invPQ = priority_queue<T, vector<T>, greater<T>>;\nusing IP = pair<int, int>;\nusing LP = pair<ll, ll>;\n#define all(x) begin(x), end(x)\n#define allr(x) rbegin(x), rend(x)\n#define rep(i, n) for (int i = 0; (i) < (int)(n); i++)\n#define rep3(i, m, n) for (int i = (m); (i) < (int)(n); i++)\n#define repr(i, n) for (int i = (n) - 1; (i) >= 0; i--)\n#define rep3r(i, m, n) for (int i = (n) - 1; (i) >= (int)(m); i--)\ntemplate<class T> inline bool chmax(T & a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T & a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nstruct UnionFind {\n vector<int> par, siz;\n UnionFind(int n) : par(n, -1), siz(n, 1) { }\n int root(int x) {\n if (par[x] == -1) return x;\n else return par[x] = root(par[x]);\n }\n bool issame(int x, int y) {\n return root(x) == root(y);\n }\n bool unite(int x, int y) {\n x = root(x); y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n par[y] = x;\n siz[x] += siz[y];\n return true;\n }\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nsigned main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int N;\n cin >> N;\n vc<int> a(N);\n rep (i, N) cin >> a[i];\n\n vc<bool> isin(500001);\n rep (i, N) isin[a[i]] = true;\n \n UnionFind uf(1000001);\n rep3 (i, 2, 500001) {\n for (int j = i; j <= 500001; j+=i) {\n if (isin[j]) uf.unite(i + 500000, j);\n }\n }\n\n vc<int> sorted = a;\n sort(all(sorted));\n\n bool judge = true;\n rep (i, N) {\n if (!uf.issame(a[i], sorted[i])) judge = false;\n }\n\n cout << judge << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11656, "score_of_the_acc": -0.3309, "final_rank": 7 }, { "submission_id": "aoj_0397_6038765", "code_snippet": "/*\nこのコード、と~おれ!\nBe accepted!\n∧_∧ \n(。・ω・。)つ━☆・*。\n⊂   ノ    ・゜+.\n しーJ   °。+ *´¨)\n          .· ´¸.·*´¨) ¸.·*¨)\n\t\t           (¸.·´ (¸.·'* ☆\n*/\n\n#include <cstdio>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <iostream>\n#include <random>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <regex>\n#include <functional>\n#include <complex>\n#include <list>\n#include <cassert>\n#include <iomanip>\n#include <set>\n#include <stack>\n#include <bitset>\n#include <array>\n#include <chrono>\n\n//#pragma GCC target(\"arch=skylake-avx512\")\n//#pragma GCC target(\"avx2\")\n//#pragma GCC optimize(\"O3\")\n//#pragma GCC optimize(\"Ofast\")\n//#pragma GCC target(\"sse4\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define repeat(i, n, m) for(int i = n; i < (m); ++i)\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n#define printynl(a) printf(a ? \"yes\\n\" : \"no\\n\")\n#define printyn(a) printf(a ? \"Yes\\n\" : \"No\\n\")\n#define printYN(a) printf(a ? \"YES\\n\" : \"NO\\n\")\n#define printim(a) printf(a ? \"possible\\n\" : \"imposible\\n\")\n#define printdb(a) printf(\"%.50lf\\n\", a)\n#define printLdb(a) printf(\"%.50Lf\\n\", a)\n#define printdbd(a) printf(\"%.16lf\\n\", a)\n#define prints(s) printf(\"%s\\n\", s.c_str())\n#define all(x) (x).begin(), (x).end()\n#define deg_to_rad(deg) (((deg)/360.0L)*2.0L*PI)\n#define rad_to_deg(rad) (((rad)/2.0L/PI)*360.0L)\n#define Please return\n#define AC 0\n#define manhattan_dist(a, b, c, d) (abs(a - c) + abs(b - d))\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconstexpr int INF = 1073741823;\nconstexpr int MINF = -1073741823;\nconstexpr ll LINF = ll(4661686018427387903);\nconstexpr ll MOD = 1e9 + 7;\nconstexpr ll mod = 998244353;\nconstexpr long double eps = 1e-6;\nconst long double PI = acosl(-1.0L);\n\nusing namespace std;\n\nvoid scans(string& str) {\n\tchar c;\n\tstr = \"\";\n\tscanf(\"%c\", &c);\n\tif (c == '\\n')scanf(\"%c\", &c);\n\twhile (c != '\\n' && c != -1 && c != ' ') {\n\t\tstr += c;\n\t\tscanf(\"%c\", &c);\n\t}\n}\n\nvoid scanc(char& str) {\n\tchar c;\n\tscanf(\"%c\", &c);\n\tif (c == -1)return;\n\twhile (c == '\\n') {\n\t\tscanf(\"%c\", &c);\n\t}\n\tstr = c;\n}\n\ndouble acot(double x) {\n\treturn PI / 2 - atan(x);\n}\n\nll LSB(ll n) { return (n & (-n)); }\n\ntemplate<typename T>\ninline T chmin(T& a, const T& b) {\n\tif (a > b)a = b;\n\treturn a;\n}\n\ntemplate<typename T>\ninline T chmax(T& a, const T& b) {\n\tif (a < b)a = b;\n\treturn a;\n}\n\n//cpp_int\n#if __has_include(<boost/multiprecision/cpp_int.hpp>)\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\nusing namespace boost::multiprecision;\n#else\nusing cpp_int = ll;\n#endif\n\n//atcoder library\n#if __has_include(<atcoder/all>)\n#include <atcoder/all>\n//using namespace atcoder;\n#endif\n\n/*\n\trandom_device seed_gen;\n\tmt19937 engine(seed_gen());\n\tuniform_int_distribution dist(1, 100);\n*/\n\n\n/*----------------------------------------------------------------------------------*/\n\n\nstruct unionfind {\n\tvector<int> par, siz;\n\n\tunionfind(int n) : par(n), siz(n) {\n\t\tfor (int i = 0; i < n; ++i) {\n\t\t\t//全部根で初期化\n\t\t\tpar[i] = i;\n\t\t\t//サイズは1\n\t\t\tsiz[i] = 1;\n\t\t}\n\t}\n\n\tvoid init(int n) {\n\t\tpar.resize(n);\n\t\tsiz.resize(n);\n\t\tfor (int i = 0; i < n; ++i) {\n\t\t\t//全部根で初期化\n\t\t\tpar[i] = i;\n\t\t\t//サイズは1\n\t\t\tsiz[i] = 1;\n\t\t}\n\t}\n\n\t//根を返す\n\tint find(int a) {\n\t\treturn par[a] == a ? a : par[a] = find(par[a]);\n\t}\n\n\t//くっつける。元から同じだったらfalseを返す\n\tbool unite(int a, int b) {\n\t\tint x = find(a), y = find(b);\n\t\tif (x == y)return false;\n\t\telse if (siz[x] < siz[y]) {\n\t\t\tpar[x] = y;\n\t\t\tsiz[y] += siz[x];\n\t\t}\n\t\telse if (siz[x] > siz[y]) {\n\t\t\tpar[y] = x;\n\t\t\tsiz[x] += siz[y];\n\t\t}\n\t\telse {\n\t\t\tpar[x] = y;\n\t\t\tsiz[y] += siz[x];\n\t\t}\n\t\treturn true;\n\t}\n\n\t//同じ集合か判定する\n\tbool same(int a, int b) {\n\t\treturn find(a) == find(b);\n\t}\n\n\t//サイズを返す\n\tint size(int a) {\n\t\treturn siz[find(a)];\n\t}\n\n};\n\nint main() {\n\n\tint n;\n\tscanf(\"%d\", &n);\n\tvector<int> a(n);\n\trep(i, n)scanf(\"%d\", &a[i]);\n\tunionfind uni(200001);\n\tvector<pair<int, int>> p(n);\n\trep(i, n)p[i] = { a[i], i };\n\tsort(all(p));\n\trep(i, n) {\n\t\tfor (int j = 2; j * j <= a[i]; ++j) {\n\t\t\tif (a[i] % j == 0) {\n\t\t\t\tuni.unite(i, 100000 + j);\n\t\t\t\twhile (a[i] % j == 0)a[i] /= j;\n\t\t\t}\n\t\t}\n\t\tif (a[i] != 1)uni.unite(i, 100000 + a[i]);\n\t}\n\tint ok = 1;\n\trep(i, n) {\n\t\tif(not(uni.same(i, p[i].second)))\n\t\t\tok = 0;\n\t}\n\tprintf(\"%d\\n\", ok);\n\n\tPlease AC;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5752, "score_of_the_acc": -0.2476, "final_rank": 4 }, { "submission_id": "aoj_0397_6002055", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N;\n cin >> N;\n vector<int> a(N);\n for (int i = 0; i < N; i++){\n cin >> a[i];\n }\n int V = N + 100000;\n vector<vector<int>> E(V);\n for (int i = 0; i < N; i++){\n for (int j = 1; j * j <= a[i]; j++){\n if (a[i] % j == 0){\n if (j > 1){\n int v = N - 1 + j;\n E[i].push_back(v);\n E[v].push_back(i);\n }\n if (j * j < a[i]){\n int w = N - 1 + a[i] / j;\n E[i].push_back(w);\n E[w].push_back(i);\n }\n }\n }\n }\n vector<bool> used(V, false);\n vector<int> b(N);\n for (int i = 0; i < N; i++){\n if (!used[i]){\n used[i] = true;\n queue<int> Q;\n Q.push(i);\n vector<int> id, x;\n int cnt = 0;\n while (!Q.empty()){\n int v = Q.front();\n Q.pop();\n if (v < N){\n id.push_back(v);\n x.push_back(a[v]);\n cnt++;\n }\n for (int w : E[v]){\n if (!used[w]){\n used[w] = true;\n Q.push(w);\n }\n }\n }\n sort(id.begin(), id.end());\n sort(x.begin(), x.end());\n for (int j = 0; j < cnt; j++){\n b[id[j]] = x[j];\n }\n }\n }\n sort(a.begin(), a.end());\n if (a == b){\n cout << 1 << endl;\n } else {\n cout << 0 << endl;\n }\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 25412, "score_of_the_acc": -1.2742, "final_rank": 17 }, { "submission_id": "aoj_0397_5862592", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nusing pint = pair<int,int>;\n\nclass UnionFind{\n private:\n\tvector<int> data;\n public:\n\tUnionFind(int n) : data(n,-1) {}\n\tint root(int i) { return data[i] < 0 ? i : data[i] = root(data[i]); }\n\tint size(int i) { return -data[root(i)]; }\n\tbool same(int x, int y) {return root(x) == root(y); }\n\tbool connected() {return size(0) == (int)data.size(); }\n\n\tbool unit(int i,int j){\n\t\ti = root(i);\n\t\tj = root(j);\n\t\tif(i != j){\n\t\t\tdata[i] += data[j];\n\t\t\tdata[j] = i;\n\t\t}\n\t\treturn i != j;\n\t}\n};\n\n\nint main()\n{\n\tint N; cin >> N;\n\tvector<int> A(N);\n\tfor(auto &i : A) cin >> i;\n\tconst int M = 1e5 + 1;\n\n\n\n\tUnionFind uni(N + M);\n\tfor(int i = 0; i < N; i++) {\n\t\tint V = A[i];\n\t\tfor(int j = 2; j * j <= V; j++) {\n\t\t\tif(V % j == 0) {\n\t\t\t\tuni.unit(i, j + N);\n\t\t\t\twhile(V % j == 0) V /= j;\n\t\t\t}\n\t\t}\n\t\tuni.unit(i, V + N);\n\t}\n\n\tvector<vector<int>> S(M + 1);\n\tfor(int i = 0; i < N; i++)S[uni.root(i)].push_back(A[i]);\n\tfor(auto &i : S)sort(i.begin(), i.end(), greater{});\n\n\tvector<int> B(N);\n\tfor(int i = 0; i < N; i++) {\n\t\tint rt = uni.root(i);\n\t\tB[i] = S[rt].back();\n\t\tS[rt].pop_back();\n\t}\n\n\tcout << is_sorted(B.begin(), B.end()) << endl;\n\n\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8104, "score_of_the_acc": -0.3906, "final_rank": 9 }, { "submission_id": "aoj_0397_5709055", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nconst int lim = 100010;\n\nstruct UnionFind{\n vector<int> parent;\n UnionFind(int n){\n parent = vector<int>(n, -1);\n }\n\n int root(int x){\n if(parent[x] < 0) return x;\n else return parent[x] = root(parent[x]);\n }\n\n int count(int x){\n return -parent[root(x)];\n }\n\n bool same(int x, int y){\n return root(x) == root(y);\n }\n\n void unite(int x, int y){\n if(same(x, y)) return;\n x = root(x);\n y = root(y);\n if(count(x) < count(y)) swap(x, y);\n parent[x] += parent[y];\n parent[y] = x;\n }\n};\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n);\n for(auto &p: a) cin >> p;\n\n vector<int> fac(lim);\n for(int i = 0; i < lim; i++) fac[i] = i;\n for(int i = 2; i < lim; i++){\n if(fac[i] != i) continue;\n for(int j = 2; i*j < lim; j++){\n fac[i*j] = min(fac[i*j], i);\n }\n }\n\n vector<int> parv(lim, -1);\n UnionFind data(n);\n for(int i = 0; i < n; i++){\n int p = a[i];\n while(p > 1){\n if(parv[fac[p]] == -1) parv[fac[p]] = i;\n else data.unite(parv[fac[p]], i);\n p /= fac[p];\n }\n }\n\n vector<vector<int>> nums(n);\n for(int i = 0; i < n; i++){\n nums[data.root(i)].push_back(a[i]);\n }\n for(auto &p: nums) sort(p.begin(), p.end());\n\n vector<int> newvec(n);\n for(int i = n-1; i >= 0; i--){\n newvec[i] = *nums[data.root(i)].rbegin();\n nums[data.root(i)].pop_back();\n }\n\n int ans = 1;\n for(int i = 1; i < n; i++){\n if(newvec[i-1] > newvec[i]) ans = 0;\n }\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8224, "score_of_the_acc": -0.1953, "final_rank": 2 }, { "submission_id": "aoj_0397_5577770", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass UnionFind{\n\tvector<ll> rank;\n\tvector<ll> diff_weight;\n\tvector<ll> num;\npublic:\n\tvector<ll> par;\n\n\tUnionFind(ll N):par(N),num(N),rank(N),diff_weight(N){\n\t\tfor(ll i=0;i<N;i++){\n\t\t\tpar[i]=i;\n\t\t\tnum[i]=1;\n\t\t\trank[i]=0;\n\t\t\tdiff_weight[i]=0;\n\t\t}\n\t}\n\n\tll root(ll x){\n\t\tif(par[x]==x){\n\t\t\treturn x;\n\t\t}\n\t\tll r = root(par[x]);\n\t\tdiff_weight[x]+=diff_weight[par[x]];\n\t\treturn par[x]=r;\n\t}\n\n\tvoid unite(ll x,ll y){\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\tif (rx == ry) return;\n\t\tif(rank[rx]<rank[ry]) swap(rx,ry);\n\t\tif(rank[rx]==rank[ry]) ++rank[rx];\n\t\tpar[ry] = rx;\n\t\tnum[rx] += num[ry];\n\t}\n\n\tvoid relate(ll x,ll y,ll w){\n\t\tw+=weight(x),w-=weight(y);\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\tif (rx == ry) return;\n\t\tif(rank[rx]<rank[ry]){\n\t\t\tswap(rx,ry);\n\t\t\tw = -w;\n\t\t}\n\t\tif(rank[rx]==rank[ry]) ++rank[rx];\n\t\tpar[ry] = rx;\n\t\tdiff_weight[ry] = w;\n\t\tnum[rx] += num[ry];\n\t}\n\n\tbool same(ll x,ll y){\n\t\tll rx = root(x);\n\t\tll ry = root(y);\n\t\treturn rx == ry;\n\t}\n\n\tll getsize(ll x){\n\t\treturn num[root(x)];\n\t}\n\n\tll weight(ll x){\n\t\troot(x);\n\t\treturn diff_weight[x];\n\t}\n\n\tll diff(ll x,ll y){\n\t\treturn weight(y)-weight(x);\n\t}\n};\n\nvector<ll> enum_prime(ll N){\n\tdeque<bool> is_prime(N+1,true);\n\tvector<ll> P;\n\tfor(ll i=2;i<=N;i++){\n\t\tif(is_prime[i]){\n\t\t\tfor(ll j=i*i;j<=N;j+=i){\n\t\t\t\tis_prime[j] = false;\n\t\t\t}\n\t\t\tP.emplace_back(i);\n\t\t}\n\t}\n\treturn P;\n}\n\nvector<ll> prime_factor(ll n,vll& prime_list){\n\tll sn = sqrt(n)+1;\n\tvector<ll> res;\n\tfor(int i=0,ei=prime_list.size();i<ei;i++){\n\t\tll v = prime_list[i];\n\t\tif(v*v>n) break;\n\t\twhile(!(n%v)){\n\t\t\tn /= v;\n\t\t\tres.push_back(v);\n\t\t}\n\t}\n\tif(n>1){\n\t\tres.push_back(n);\n\t}\n\n\treturn res;\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto N=in();\n\tvll S=vecin(N);\n\tvll T(S);\n\tsort(ALL(T));\n\n\tauto PL = enum_prime(T.back());\n\tUnionFind uf(T.back()+1);\n\tfor(auto& x:S){\n\t\tauto P = prime_factor(x,PL);\n\t\tsort(ALL(P));\n\t\tP.erase(unique(ALL(P)),P.end());\n\t\tfor(auto& p:P) uf.unite(x,p);\n\t}\n\t\n\tREP(i,N){\n\t\tif(!uf.same(S[i],T[i])){\n\t\t\tout(0);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tout(1);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8108, "score_of_the_acc": -0.2907, "final_rank": 6 } ]