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aoj_0559_cpp
JOI 旗 (JOI Flag) 問題 情報オリンピック日本委員会では,今年の日本情報オリンピック (JOI) を宣伝するために, JOI のロゴをモチーフにした旗を作ることになった.旗は「良い旗」でなければならない.「良い旗」とは,アルファベットの J, O, I のいずれかの文字を,縦 M 行,横 N 列の長方形状に並べたもので, J, O, I が以下の図のように (すなわち,J の右隣に O が,その J の下隣に I が) 並んでいる箇所が旗の少なくとも 1 か所にあるものである. 以下の図に,「良い旗」の例を 2 つ示す. 以下の図に,「良い旗」ではない例を 2 つ示す. いま M, N の値,および旗の一部の場所について J, O, I のどの文字にするかが決まっており,入力としてその情報が与えられる.考えられる「良い旗」は何通りあるかを計算し,その数を 100000 (=10 5 ) で割った余りを出力するプログラムを作成せよ. 入力 入力は 1 + M 行からなる. 1 行目には旗の大きさを表す 2 つの整数 M, N (2 ≤ M ≤ 20, 2 ≤ N ≤ 20) が空白で区切られて書かれている. 1 + i 行目 (1 ≤ i ≤ M) には,N 文字からなる文字列が書かれている.各文字は J, O, I, ? のいずれかであり, j 文字目 (1 ≤ j ≤ N) が J, O, I のいずれかである場合は i 行 j 列の場所の文字がそれぞれ J, O, I に決まっていること, ? である場合はまだ決まっていないことを表す. 出力 考えられる「良い旗」の個数を 100000 (=10 5 ) で割った余りを 1 行で出力せよ. 入出力例 入力例 1 2 3 ??O IIJ 出力例 1 4 入力例 1 においては,以下の図の 4 通りの「良い旗」が考えられる. 入力例 2 2 2 ?? ?? 出力例 2 3 入力例 3 3 3 ??I ??? O?J 出力例 3 53 入力例 4 5 4 JOI? ???? ???? ???? ?JOI 出力例 4 28218 入力例 4 においては,「良い旗」は 2428218 通り考えられるので,それを 100000 (=10 5 ) で割った余りである 28218 を出力する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0559_10851189", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define ALL(a) a.begin(),a.end()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define debug(x) cerr << #x << \": \" << x << endl\n\nusing LL = long long; template<class T> using V = vector<T>;\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tconst LL mod = 100000;\n\tint W, H; cin >> H >> W;\n\tV<string>vs(H);\n\tFOR(i, 0, H) {\n\t\tcin >> vs[i];\n\t}\n\tV<int>dp(1 << (W - 1), 0);\n\tdp[0] = 1;\n\tauto add = [&mod](int &x, int y) {\n\t\tx += y;\n\t\tx %= mod;\n\t};\n\tFOR(i, 0, H) {// 禁止パターンを数え上げる\n\t\tFOR(j, 0, W) {\n\t\t\tV<int>nx(1 << (W - 1), 0);\n\t\t\tFOR(state, 0, 1 << (W - 1)) {\n\t\t\t\tif (dp[state] == 0)continue;\n\t\t\t\tint ns = state & ~(1 << (j - 1));\n\t\t\t\tif (vs[i][j] == 'J' || vs[i][j] == '?') {\n\t\t\t\t\tif (j < W - 1) {\n\t\t\t\t\t\tadd(nx[ns | 1 << j], dp[state]);// jを追加\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tadd(nx[ns &~(1 << j)], dp[state]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (vs[i][j] == 'O' || vs[i][j] == '?') {\n\t\t\t\t\tadd(nx[state&~(1 << j)], dp[state]); // o\n\t\t\t\t}\n\t\t\t\tif (vs[i][j] == 'I' || vs[i][j] == '?') { // iをおいては置いてはいけないことはないときに置いてしまっても以降に問題はない\n\t\t\t\t\tif (!(state & 1 << j)) {\n\t\t\t\t\t\tadd(nx[ns&~(1 << j)], dp[state]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tdp.swap(nx);\n\t\t}\n\t}\n\tLL ans = 1;\n\tFOR(i, 0, H) {\n\t\tFOR(j, 0, W) {\n\t\t\tif (vs[i][j] == '?')ans *= 3;\n\t\t\tans %= mod;\n\t\t}\n\t}\n\t//debug(ans);\n\tauto dec = [&mod](LL x, LL y) {\n\t\tLL ret = (x - y + mod) % mod;\n\t\treturn ret >= 0 ? ret : ret + mod;\n\t};\n\tFOR(i, 0, 1 << (W - 1)) {\n\t\t//cout << dp[i] << endl;\n\t\tans = (dec(ans, dp[i])) % mod;\n\t}\n\tcout << ans << endl;\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 7200, "score_of_the_acc": -0.0874, "final_rank": 1 }, { "submission_id": "aoj_0559_10324940", "code_snippet": "#include<bits/stdc++.h> \nusing namespace std;\nusing ll=long long;\n\nconst ll mod=100000;\n\nint main(){\n\t\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tint N,M;\n\tcin>>N>>M;\n\tvector<string> S(N);\n\tfor(int i=0;i<N;i++)cin>>S[i];\n\tmap<pair<ll,ll>,ll> MP;\n\tll bmod=(1<<(M-1));\n\tMP[{0,0}]=1;\n\tfor(int i=0;i<N;i++){\n\t\tfor(int j=0;j<M;j++){\n\t\t\tmap<pair<ll,ll>,ll> NMP;\n\t\t\tfor(auto [P,num]:MP){\n\t\t\t\tif(S[i][j]=='J'||S[i][j]=='?'){\n\t\t\t\t\tll nbit=(P.first*2)%bmod;\n\t\t\t\t\tNMP[{nbit,1}]+=num;\n\t\t\t\t\tNMP[{nbit,1}]%=mod;\n\t\t\t\t}\n\t\t\t\tif(S[i][j]=='O'||S[i][j]=='?'){\n\t\t\t\t\tll nbit=(P.first*2)%bmod;\n\t\t\t\t\tif(P.second==1&&j!=0)nbit++;\n\t\t\t\t\tNMP[{nbit,0}]+=num;\n\t\t\t\t\tNMP[{nbit,0}]%=mod;\n\t\t\t\t}\n\t\t\t\tif(S[i][j]=='I'||S[i][j]=='?'){\n\t\t\t\t\tif(P.first&(1<<(M-2)))continue;\n\t\t\t\t\tll nbit=(P.first*2)%bmod;\n\t\t\t\t\tNMP[{nbit,0}]+=num;\n\t\t\t\t\tNMP[{nbit,0}]%=mod;\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(MP,NMP);\n\t\t\t\n\t\t\t// for(auto [V,n]:MP){\n\t\t\t// \tcout<<i<<\" \"<<j<<\" \"<<V.first<<\" \"<<V.second<<\" \"<<n<<endl;\n\t\t\t// }\n\t\t}\n\t}\n\tll an=1;\n\tfor(int i=0;i<N;i++){\n\t\tfor(int j=0;j<M;j++){\n\t\t\tif(S[i][j]=='?')an=(an*3)%mod;\n\t\t}\n\t}\n\tfor(auto [P,n]:MP){\n\t\tan-=n;\n\t}\n\tan%=mod;\n\tif(an<0)an+=mod;\n\tcout<<an%mod<<endl;\n}", "accuracy": 1, "time_ms": 840, "memory_kb": 5504, "score_of_the_acc": -0.1308, "final_rank": 3 }, { "submission_id": "aoj_0559_9989556", "code_snippet": "#include<bits/stdc++.h>\n#define MOD 100000\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\n\nint dp[2][1 << 19];\nchar s[21][21];\nint main() {\n\tint m, n; scanf(\"%d%d\", &m, &n);\n\tint cnt = 1;\n\trep(i, m)scanf(\"%s\", s[i]);\n\trep(i, m)rep(j, n) {\n\t\tif (s[i][j] == '?')cnt = (cnt * 3) % MOD;\n\t}\n\tint*now = dp[0], *nxt = dp[1];\n\tnow[0] = 1;\n\trep(i, m)rep(j, n) {\n\t\tfill(nxt, nxt + (1 << n - 1), 0);\n\t\trep(k, 1 << n - 1) {\n\t\t\tif (now[k] == 0)continue;\n\t\t\tint a = k&~(1 << (j - 1));\n\t\t\tif (s[i][j] == 'J' || s[i][j] == '?') {\n\t\t\t\tif (j < n - 1)(nxt[a | 1 << j] += now[k]) %= MOD;\n\t\t\t\telse(nxt[a&~(1 << j)] += now[k]) %= MOD;\n\t\t\t}\n\t\t\tif (s[i][j] == 'O' || s[i][j] == '?')\n\t\t\t\t(nxt[k&~(1 << j)] += now[k]) %= MOD;\n\t\t\tif (s[i][j] == 'I' || s[i][j] == '?') {\n\t\t\t\tif (!(k >> j & 1))(nxt[a&~(1 << j)] += now[k]) %= MOD;\n\t\t\t}\n\t\t}\n\t\tswap(now, nxt);\n\t}\n\trep(i, 1 << n - 1)cnt = (cnt + MOD - now[i]) % MOD;\n\tprintf(\"%d\\n\", cnt);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7576, "score_of_the_acc": -0.0932, "final_rank": 2 }, { "submission_id": "aoj_0559_9989502", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\nusing namespace std;\nint mod = 100000;\nint dp[1 << 20][3], dp_prev[1 << 20][3];\nint x[409], H, W; string S;\nint power[20];\nint main() {\n\tpower[0] = 1; for (int i = 1; i < 20; i++)power[i] = power[i - 1] * 2;\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++) {\n\t\tcin >> S;\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (S[j] == 'J')x[i * W + j] = 1;\n\t\t\tif (S[j] == 'O')x[i * W + j] = 2;\n\t\t\tif (S[j] == 'I')x[i * W + j] = 3;\n\t\t\tif (S[j] == '?')x[i * W + j] = 0;\n\t\t}\n\t}\n\tif (x[0] == 0 || x[0] == 1)dp_prev[0][1] += 1;\n\tif (x[0] == 0 || x[0] == 2)dp_prev[0][0] += 1;\n\tif (x[0] == 0 || x[0] == 3)dp_prev[0][0] += 1;\n\tfor (int i = 1; i < H * W; i++) {\n\t\tint mass = i % W;\n\t\tfor (int j = 0; j < power[W - 1]; j++) {\n\t\t\tint L = 0, R = 0;\n\t\t\tif ((j / power[mass]) % 2 == 1) {\n\t\t\t\tL = j - power[mass];\n\t\t\t\tR = L + power[mass - 1];\n\t\t\t\tif (x[i] == 0 || x[i] == 1) {\n\t\t\t\t\tif (mass != W - 1) { dp[L][1] += dp_prev[j][0] + dp_prev[j][1]; dp[L][1] %= mod; }\n\t\t\t\t\tif (mass == W - 1) { dp[L][0] += dp_prev[j][0] + dp_prev[j][1]; dp[L][0] %= mod; }\n\t\t\t\t}\n\t\t\t\tif (x[i] == 0 || x[i] == 2) {\n\t\t\t\t\tdp[L][0] += dp_prev[j][0]; dp[L][0] %= mod;\n\t\t\t\t\tdp[R][0] += dp_prev[j][1]; dp[R][0] %= mod;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tL = j;\n\t\t\t\tR = j + power[mass - 1];\n\t\t\t\tif (x[i] == 0 || x[i] == 1) {\n\t\t\t\t\tif (mass != W - 1) { dp[L][1] += dp_prev[j][0] + dp_prev[j][1]; dp[L][1] %= mod; }\n\t\t\t\t\tif (mass == W - 1) { dp[L][0] += dp_prev[j][0] + dp_prev[j][1]; dp[L][0] %= mod; }\n\t\t\t\t}\n\t\t\t\tif (x[i] == 0 || x[i] == 2) {\n\t\t\t\t\tdp[L][0] += dp_prev[j][0]; dp[L][0] %= mod;\n\t\t\t\t\tdp[R][0] += dp_prev[j][1]; dp[R][0] %= mod;\n\t\t\t\t}\n\t\t\t\tif (x[i] == 0 || x[i] == 3) { dp[L][0] += dp_prev[j][0] + dp_prev[j][1]; dp[L][0] %= mod; }\n\t\t\t}\n\t\t}\n\t\tfor (int j = 0; j < power[W - 1]; j++) {\n\t\t\tdp_prev[j][0] = dp[j][0]; dp_prev[j][1] = dp[j][1];\n\t\t\tdp[j][0] = 0; dp[j][1] = 0;\n\t\t}\n\t}\n\tint C = 1; for (int i = 0; i < H*W; i++) if (x[i] == 0) C = C * 3 % mod;\n\tint sum = 0; for (int i = 0; i < power[W - 1]; i++) { sum += dp_prev[i][0] + dp_prev[i][1]; sum %= mod; }\n\tcout << (C + mod - sum) % mod << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2200, "memory_kb": 21860, "score_of_the_acc": -1.1173, "final_rank": 17 }, { "submission_id": "aoj_0559_7976957", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nconstexpr int mod = 100000;\nconst string joi = \"JOI\";\nint dp[2][1<<19];\nint ndp[2][1<<19];\n\nvoid add(int &x, int y) {\n x += y;\n if (x >= mod) x -= mod;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int h,w; cin >> h >> w;\n vector<string> s(h);\n int res = 1;\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n for (int j = 0; j < w; j++) {\n if (s[i][j] == '?') {\n res *= 3;\n res %= mod;\n }\n }\n }\n\n dp[0][0] = 1;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n for (int c = 0; c < 3; c++) {\n if (s[i][j] != '?' and s[i][j] != joi[c]) continue;\n for (int k = 0; k < 2; k++) {\n for (int l = 0; l < (1<<(w-1)); l++) {\n if (!dp[k][l]) continue;\n if (((1<<j)&l) and c == 2) continue;\n int nk = (c == 0);\n int ni = i; int nj = j+1;\n if (nj == w) {\n ni++; nj = 0;\n }\n int nl = l;\n if ((1<<j)&l) nl -= (1<<j);\n if (j and k and c == 1) {\n nl ^= (1<<(j-1));\n }\n add(ndp[nk][nl], dp[k][l]);\n }\n }\n }\n for (int k = 0; k < 2; k++) {\n for (int l = 0; l < (1<<(w-1)); l++) {\n dp[k][l] = ndp[k][l];\n ndp[k][l] = 0; \n }\n }\n }\n }\n\n for (int k = 0; k < 2; k++) {\n for (int l = 0; l < (1<<(w-1)); l++) {\n add(res, mod-dp[k][l]);\n }\n }\n\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 11648, "score_of_the_acc": -0.3649, "final_rank": 4 }, { "submission_id": "aoj_0559_7539622", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <cstring>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint w = 0;\n\tint h = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int y = 0; y < h; y++) {\n\t\tcin >> grid[y];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int c_state = 0; c_state < 1 << w; c_state++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][c_state][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[y][x] != '?' && grid[y][x] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((c_state & 1 << x) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint n_state = c_state & ~(1 << x), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tn_state |= 1 << (x - 1);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][n_state][np] += dp[cur][c_state][p];\n\t\t\t\t\t\t\tif (dp[next][n_state][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][n_state][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\tfor (int state = 0; state < 1 << w; state++) {\n\t\t\tdp[cur][state][0] += dp[cur][state][1];\n\t\t\tif (dp[cur][state][0] >= mod) {\n\t\t\t\tdp[cur][state][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][state][1] = 0;\n\t\t}\n\t}\n\n\tint result = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tif (grid[y][x] == '?') {\n\t\t\t\tresult = (result * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int state = 0; state < 1 << w; state++) {\n\t\tresult = (result + mod - dp[cur][state][0]) % mod;\n\t}\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19824, "score_of_the_acc": -0.8139, "final_rank": 14 }, { "submission_id": "aoj_0559_7539619", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <string.h>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint w = 0;\n\tint h = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int y = 0; y < h; y++) {\n\t\tcin >> grid[y];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int c_state = 0; c_state < 1 << w; c_state++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][c_state][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[y][x] != '?' && grid[y][x] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((c_state & 1 << x) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint n_state = c_state & ~(1 << x), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tn_state |= 1 << (x - 1);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][n_state][np] += dp[cur][c_state][p];\n\t\t\t\t\t\t\tif (dp[next][n_state][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][n_state][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\tfor (int state = 0; state < 1 << w; state++) {\n\t\t\tdp[cur][state][0] += dp[cur][state][1];\n\t\t\tif (dp[cur][state][0] >= mod) {\n\t\t\t\tdp[cur][state][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][state][1] = 0;\n\t\t}\n\t}\n\n\tint result = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tif (grid[y][x] == '?') {\n\t\t\t\tresult = (result * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int state = 0; state < 1 << w; state++) {\n\t\tresult = (result + mod - dp[cur][state][0]) % mod;\n\t}\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19824, "score_of_the_acc": -0.8139, "final_rank": 14 }, { "submission_id": "aoj_0559_7539616", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <string.h>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint w = 0;\n\tint h = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int y = 0; y < h; y++) {\n\t\tcin >> grid[y];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int c_state = 0; c_state < 1 << w; c_state++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][c_state][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[y][x] != '?' && grid[y][x] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((c_state & 1 << x) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint n_state = c_state & ~(1 << x), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tn_state |= 1 << x - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][n_state][np] += dp[cur][c_state][p];\n\t\t\t\t\t\t\tif (dp[next][n_state][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][n_state][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\tfor (int state = 0; state < 1 << w; state++) {\n\t\t\tdp[cur][state][0] += dp[cur][state][1];\n\t\t\tif (dp[cur][state][0] >= mod) {\n\t\t\t\tdp[cur][state][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][state][1] = 0;\n\t\t}\n\t}\n\n\tint result = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tif (grid[y][x] == '?') {\n\t\t\t\tresult = (result * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int state = 0; state < 1 << w; state++) {\n\t\tresult = (result + mod - dp[cur][state][0]) % mod;\n\t}\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19816, "score_of_the_acc": -0.8135, "final_rank": 11 }, { "submission_id": "aoj_0559_7539612", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint w = 0;\n\tint h = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int y = 0; y < h; y++) {\n\t\tcin >> grid[y];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int c_state = 0; c_state < 1 << w; c_state++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][c_state][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[y][x] != '?' && grid[y][x] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((c_state & 1 << x) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint n_state = c_state & ~(1 << x), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tn_state |= 1 << x - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][n_state][np] += dp[cur][c_state][p];\n\t\t\t\t\t\t\tif (dp[next][n_state][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][n_state][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\tfor (int state = 0; state < 1 << w; state++) {\n\t\t\tdp[cur][state][0] += dp[cur][state][1];\n\t\t\tif (dp[cur][state][0] >= mod) {\n\t\t\t\tdp[cur][state][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][state][1] = 0;\n\t\t}\n\t}\n\n\tint result = 1;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tif (grid[y][x] == '?') {\n\t\t\t\tresult = (result * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int state = 0; state < 1 << w; state++) {\n\t\tresult = (result + mod - dp[cur][state][0]) % mod;\n\t}\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 19748, "score_of_the_acc": -0.8123, "final_rank": 9 }, { "submission_id": "aoj_0559_7539607", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int i = 0; i < h; i++) {\n\t\tcin >> grid[i];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int bit = 0; bit < 1 << w; bit++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][bit][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[i][j] != '?' && grid[i][j] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((bit & 1 << j) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tnbit |= 1 << j - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\t\t\tif (dp[next][nbit][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][nbit][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\tfor (int bit = 0; bit < 1 << w; bit++) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) {\n\t\t\t\tdp[cur][bit][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (grid[i][j] == '?') {\n\t\t\t\tans = (ans * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i < 1 << w; i++) {\n\t\tans = (ans + mod - dp[cur][i][0]) % mod;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19740, "score_of_the_acc": -0.8101, "final_rank": 7 }, { "submission_id": "aoj_0559_7539604", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\tfor (int i = 0; i < h; i++) {\n\t\tcin >> grid[i];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\tfor (int bit = 0; bit < 1 << w; bit++) {\n\t\t\t\tfor(int p = 0; p < 2; p++) {\n\t\t\t\t\tif (dp[cur][bit][p]) {\n\t\t\t\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\t\t\t\tif (grid[i][j] != '?' && grid[i][j] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((bit & 1 << j) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tnbit |= 1 << j - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\t\t\tif (dp[next][nbit][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][nbit][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) {\n\t\t\t\tdp[cur][bit][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif (grid[i][j] == '?') {\n\t\t\t\tans = (ans * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\trep(i, 1 << w) {\n\t\tans = (ans + mod - dp[cur][i][0]) % mod;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19820, "score_of_the_acc": -0.8137, "final_rank": 12 }, { "submission_id": "aoj_0559_7539603", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = int(1e5);\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring grid[20];\n\tconst char* joi = \"JOI\";\n\n\tcin >> h >> w;\n\trep(i, h) {\n\t\tcin >> grid[i];\n\t}\n\tdp[0][0][0] = 1;\n\n\tint cur = 0;\n\tint next = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\trep(bit, 1 << w) {\n\t\t\t\trep(p, 2) {\n\t\t\t\t\tif (dp[cur][bit][p]) {\n\t\t\t\t\t\trep(k, 3) {\n\t\t\t\t\t\t\tif (grid[i][j] != '?' && grid[i][j] != joi[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((bit & 1 << j) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tnbit |= 1 << j - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\t\t\tif (dp[next][nbit][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][nbit][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) {\n\t\t\t\tdp[cur][bit][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif (grid[i][j] == '?') {\n\t\t\t\tans = (ans * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\trep(i, 1 << w) {\n\t\tans = (ans + mod - dp[cur][i][0]) % mod;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19820, "score_of_the_acc": -0.8137, "final_rank": 12 }, { "submission_id": "aoj_0559_7539600", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = (int)1e5;\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring in[20];\n\tconst char* grid = \"JOI\";\n\n\tcin >> h >> w;\n\trep(i, h) cin >> in[i];\n\tdp[0][0][0] = 1;\n\n\tint cur = 0, next = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\trep(bit, 1 << w) {\n\t\t\t\trep(p, 2) {\n\t\t\t\t\tif (dp[cur][bit][p]) {\n\t\t\t\t\t\trep(k, 3) {\n\t\t\t\t\t\t\tif (in[i][j] != '?' && in[i][j] != grid[k]) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif ((bit & 1 << j) && k == 2) {\n\t\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) {\n\t\t\t\t\t\t\t\tnbit |= 1 << j - 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\t\t\tif (dp[next][nbit][np] >= mod) {\n\t\t\t\t\t\t\t\tdp[next][nbit][np] -= mod;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) {\n\t\t\t\tdp[cur][bit][0] -= mod;\n\t\t\t}\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif (in[i][j] == '?') {\n\t\t\t\tans = (ans * 3) % mod;\n\t\t\t}\n\t\t}\n\t}\n\trep(i, 1 << w) {\n\t\tans = (ans + mod - dp[cur][i][0]) % mod;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 19752, "score_of_the_acc": -0.8125, "final_rank": 10 }, { "submission_id": "aoj_0559_7539594", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = (int)1e5;\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring in[20];\n\tconst char* grid = \"JOI\";\n\n\tcin >> h >> w;\n\trep(i, h) cin >> in[i];\n\tdp[0][0][0] = 1;\n\n\tint cur = 0, next = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\trep(bit, 1 << w) {\n\t\t\t\trep(p, 2) {\n\t\t\t\t\tif (dp[cur][bit][p]) {\n\t\t\t\t\t\trep(k, 3) {\n\t\t\t\t\t\t\tif (in[i][j] != '?' && in[i][j] != grid[k]) continue;\n\t\t\t\t\t\t\tif ((bit & 1 << j) && k == 2) continue;\n\t\t\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\t\t\tif (p && k == 1) nbit |= 1 << j - 1;\n\t\t\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\t\t\tif (dp[next][nbit][np] >= mod) dp[next][nbit][np] -= mod;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) dp[cur][bit][0] -= mod;\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\trep(i, h) rep(j, w) if (in[i][j] == '?') ans = (ans * 3) % mod;\n\trep(i, 1 << w) ans = (ans + mod - dp[cur][i][0]) % mod;\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19724, "score_of_the_acc": -0.8094, "final_rank": 6 }, { "submission_id": "aoj_0559_7539590", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tconst int mod = (int)1e5;\n\tint h = 0;\n\tint w = 0;\n\tint dp[2][1 << 20][2];\n\tstring in[20];\n\tconst char* grid = \"JOI\";\n\n\tcin >> h >> w;\n\trep(i, h) cin >> in[i];\n\tdp[0][0][0] = 1;\n\n\tint cur = 0, next = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\trep(bit, 1 << w) rep(p, 2) if (dp[cur][bit][p]) {\n\t\t\t\trep(k, 3) {\n\t\t\t\t\tif (in[i][j] != '?' && in[i][j] != grid[k]) continue;\n\t\t\t\t\tif ((bit & 1 << j) && k == 2) continue;\n\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\tif (p && k == 1) nbit |= 1 << j - 1;\n\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\tif (dp[next][nbit][np] >= mod) dp[next][nbit][np] -= mod;\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w) {\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif (dp[cur][bit][0] >= mod) dp[cur][bit][0] -= mod;\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\n\tint ans = 1;\n\trep(i, h) rep(j, w) if (in[i][j] == '?') ans = (ans * 3) % mod;\n\trep(i, 1 << w) ans = (ans + mod - dp[cur][i][0]) % mod;\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 19788, "score_of_the_acc": -0.8123, "final_rank": 8 }, { "submission_id": "aoj_0559_7539573", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <string.h>\nusing namespace std;\n#define rep(i,b) for(int i = 0; i < (b); i++)\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\nconst int mod = (int)1e5;\nint h, w, dp[2][1<<20][2];\nstring in[20];\nconst char *flag = \"JOI\";\n\tcin >> h >> w;\n\trep(i, h) cin >> in[i];\n\tdp[0][0][0] = 1;\n\tint cur = 0, next = 1;\n\trep(i, h){\n\t\trep(j, w){\n\t\t\tmemset(dp[next], 0, sizeof(dp[next]));\n\t\t\trep(bit, 1 << w) rep(p, 2) if(dp[cur][bit][p]){\n\t\t\t\trep(k, 3){\n\t\t\t\t\tif(in[i][j] != '?' && in[i][j] != flag[k]) continue;\n\t\t\t\t\tif((bit & 1 << j) && k == 2) continue;\n\t\t\t\t\tint nbit = bit & ~(1 << j), np = k == 0;\n\t\t\t\t\tif(p && k == 1) nbit |= 1 << j - 1;\n\t\t\t\t\tdp[next][nbit][np] += dp[cur][bit][p];\n\t\t\t\t\tif(dp[next][nbit][np] >= mod) dp[next][nbit][np] -= mod;\n\t\t\t\t}\n\t\t\t}\n\t\t\tswap(cur, next);\n\t\t}\n\t\trep(bit, 1 << w){\n\t\t\tdp[cur][bit][0] += dp[cur][bit][1];\n\t\t\tif(dp[cur][bit][0] >= mod) dp[cur][bit][0] -= mod;\n\t\t\tdp[cur][bit][1] = 0;\n\t\t}\n\t}\n\t\n\tint ans = 1;\n\trep(i, h) rep(j, w) if(in[i][j] == '?') ans = (ans * 3) % mod;\n\trep(i, 1 << w) ans = (ans + mod - dp[cur][i][0]) % mod;\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 19816, "score_of_the_acc": -0.7988, "final_rank": 5 }, { "submission_id": "aoj_0559_6781654", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <chrono>\n#include <climits>\n#include <cmath>\n#include <cstddef>\n#include <cstdint>\n#include <cstdlib>\n#include <cstring>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <map>\n#include <memory>\n#include <numeric>\n#include <optional>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\n/* macro */\n\n#define rep(i, a, n) for (int i = (int)(a); i < (int)(n); i++)\n#define rrep(i, a, n) for (int i = ((int)(n - 1)); i >= (int)(a); i--)\n#define Rep(i, a, n) for (i64 i = (i64)(a); i < (i64)(n); i++)\n#define RRep(i, a, n) for (i64 i = ((i64)(n - i64(1))); i >= (i64)(a); i--)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define Bit(n) (1LL << (n))\n\n/* macro end */\n\n/* template */\n\nnamespace ebi {\n\n#ifdef LOCAL\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n\nvoid debug_out() { std::cerr << std::endl; }\n\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cout << \" :\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T1, T2> &pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &os, std::pair<T1, T2> &pa) {\n return os >> pa.first >> pa.second;\n}\n\ntemplate <typename T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &vec) {\n for (std::size_t i = 0; i < vec.size(); i++)\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n return os;\n}\n\ntemplate <typename T>\nstd::istream &operator>>(std::istream &os, std::vector<T> &vec) {\n for (T &e : vec) std::cin >> e;\n return os;\n}\n\ntemplate <typename T>\nstd::ostream &operator<<(std::ostream &os, const std::optional<T> &opt) {\n if (opt) {\n os << opt.value();\n } else {\n os << \"invalid value\";\n }\n return os;\n}\n\nusing std::size_t;\nusing i32 = std::int32_t;\nusing u32 = std::uint32_t;\nusing i64 = std::int64_t;\nusing u64 = std::uint64_t;\n\ntemplate <class T, T init>\nauto make_vector(int n) {\n return std::vector<T>(n, init);\n}\n\ntemplate <class T, T init, typename Head, typename... Tail>\nauto make_vector(Head n, Tail... ts) {\n return std::vector(n, make_vector<T, init>(ts...));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate <class T>\nT pow(T x, i64 n) {\n T res = 1;\n while (n > 0) {\n if (n & 1) res = res * x;\n x = x * x;\n n >>= 1;\n }\n return res;\n}\n\ntemplate <class T>\nT mod_pow(T x, i64 n, i64 mod) {\n T res = 1;\n while (n > 0) {\n if (n & 1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n}\n\ntemplate <class T>\nT scan() {\n T val;\n std::cin >> val;\n return val;\n}\n\ntemplate <class T>\nstruct Edge {\n int to;\n T cost;\n Edge(int _to, T _cost = 1) : to(_to), cost(_cost) {}\n};\n\ntemplate <class T>\nstruct Graph : std::vector<std::vector<Edge<T>>> {\n using std::vector<std::vector<Edge<T>>>::vector;\n void add_edge(int u, int v, T w, bool directed = false) {\n (*this)[u].emplace_back(v, w);\n if (directed) return;\n (*this)[v].emplace_back(u, w);\n }\n};\n\nstruct graph : std::vector<std::vector<int>> {\n using std::vector<std::vector<int>>::vector;\n void add_edge(int u, int v, bool directed = false) {\n (*this)[u].emplace_back(v);\n if (directed) return;\n (*this)[v].emplace_back(u);\n }\n};\n\nconstexpr i64 LNF = std::numeric_limits<i64>::max() / 4;\n\nconstexpr int INF = std::numeric_limits<int>::max() / 2;\n\nconst std::vector<int> dy = {1, 0, -1, 0, 1, 1, -1, -1};\nconst std::vector<int> dx = {0, 1, 0, -1, 1, -1, 1, -1};\n\n} // namespace ebi\n\nnamespace ebi {\n\nvoid main_() {\n const i64 mod = 100000;\n int m,n;\n std::cin >> m >> n;\n std::vector<std::string> s(m);\n std::cin >> s;\n std::vector<i64> dp(1<<n, 0);\n dp[0] = 1;\n std::string joi = \"JOI\";\n const int BIT = (1<<n) - 1;\n i64 cnt = 0;\n rep(i,0,m) {\n rep(j,0,n) {\n if(s[i][j] == '?') cnt++;\n std::vector<i64> nxt(1<<n, 0);\n std::vector<int> used;\n rep(k,0,3) {\n if(joi[k] == s[i][j] || s[i][j] == '?') {\n used.emplace_back(k);\n }\n }\n rep(bit, 0, 1<<n) {\n for(auto use: used) {\n if(((bit >> j) & 1) && use == 2) continue;\n int nbit = bit & (BIT ^ (1<<j));\n if(j > 0) nbit &= (BIT ^ (1<<(j-1)));\n if(use == 0) {\n if(j != n-1) nbit |= (1<<j);\n nxt[nbit] += dp[bit];\n }\n else if(use == 1) {\n if(j > 0 && ((bit >> (j-1)) & 1)) nbit |= (1<<(j-1));\n nxt[nbit] += dp[bit];\n }\n else if(use == 2) {\n if((bit >> j) & 1) continue;\n assert(!((nbit >> j) & 1));\n nxt[nbit] += dp[bit];\n }\n else {\n assert(0);\n }\n nxt[nbit] %= mod;\n }\n }\n dp = nxt;\n }\n }\n i64 ans = mod_pow(i64(3), cnt, mod);\n rep(bit,0,1<<n) {\n ans -= dp[bit];\n ans = (ans + mod) % mod;\n }\n std::cout << ans << '\\n';\n}\n\n} // namespace ebi\n\nint main() {\n std::cout << std::fixed << std::setprecision(15);\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n int t = 1;\n // std::cin >> t;\n while (t--) {\n ebi::main_();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 3330, "memory_kb": 19560, "score_of_the_acc": -1.2219, "final_rank": 18 }, { "submission_id": "aoj_0559_4676083", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"ctime\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//constexpr int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\nconstexpr double EPS = 1e-12;\n\nint N, M, K, H, W, L, R;\n//long long int N, M, K, H, W, L, R;\n\nint dp[3][1 << 19][2][2];\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> H >> W;\n\tvector<string>s(H);\n\tfor (auto &i : s)cin >> i;\n\tfor (int i = 0; i < 1 << W; i++) {\n\t\tbool flag = true;\n\t\tint by = 1;\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif ((i >> j) & 1) {\n\t\t\t\tif (s.back()[j] == 'J' || s.back()[j] == 'O')flag = false;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (s.back()[j] == 'I')flag = false;\n\t\t\t\tif (s.back()[j] == '?') {\n\t\t\t\t\tby *= 2;\n\t\t\t\t\tby %= 100000;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (!flag)continue;\n\t\tif (s[H - 2][W - 1] == 'J' || s[H - 2][W - 1] == '?')dp[2][i&((1 << (W - 1)) - 1)][0][0] += by;\n\t\tif (s[H - 2][W - 1] == 'O' || s[H - 2][W - 1] == '?')dp[2][i&((1 << (W - 1)) - 1)][1][0] += by;\n\t\tif (s[H - 2][W - 1] == 'I' || s[H - 2][W - 1] == '?')dp[2][i&((1 << (W - 1)) - 1)][0][0] += by;\n\t}\n\tfor (int h = H - 2; h >= 0; h--) {\n\t\tfor (int w = W - 1; w >= 0; w--) {\n\t\t\tif (h + w == H + W - 3)continue;\n\t\t\tint cw = w & 1;\n\t\t\tif (w == W - 1)cw = 2;\n\t\t\tint befw = (w + 1) & 1;\n\t\t\tif (w + 1 == W - 1)befw = 2;\n\t\t\tif (w == W - 1)befw = 0;\n\t\t\tfor (int i = 0; i < 1 << (W - 1); i++) {\n\t\t\t\tfor (int j = 0; j < 2; j++) {\n\t\t\t\t\tfor (int k = 0; k < 2; k++) {\n\t\t\t\t\t\tdp[cw][i][j][k] = 0;\n\t\t\t\t\t\tdp[befw][i][j][k] %= 100000;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (int bit = 0; bit < 1 << (W - 1); bit++) {\n\t\t\t\tfor (int o = 0; o < 2; o++) {\n\t\t\t\t\tfor (int cnt = 0; cnt < 2; cnt++) {\n\t\t\t\t\t\tif (w == W - 1) {\n\t\t\t\t\t\t\tif (s[h][w] == 'J' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tint nxo = 0;\n\t\t\t\t\t\t\t\tint nxcnt = cnt;\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[0][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (s[h][w] == 'O' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tint nxo = 1;\n\t\t\t\t\t\t\t\tint nxcnt = cnt;\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[0][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (s[h][w] == 'I' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tint nxo = 0;\n\t\t\t\t\t\t\t\tint nxcnt = cnt;\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[0][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse {\n\t\t\t\t\t\t\tif (s[h][w] == 'J' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tif ((bit >> w) & 1)nxbit ^= 1 << w;\n\t\t\t\t\t\t\t\tint nxo = 0;\n\t\t\t\t\t\t\t\tint nxcnt = cnt || (o && ((bit >> w) & 1));\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[befw][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (s[h][w] == 'O' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tif ((bit >> w) & 1)nxbit ^= 1 << w;\n\t\t\t\t\t\t\t\tint nxo = 1;\n\t\t\t\t\t\t\t\tint nxcnt = cnt;\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[befw][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (s[h][w] == 'I' || s[h][w] == '?') {\n\t\t\t\t\t\t\t\tint nxbit = bit;\n\t\t\t\t\t\t\t\tnxbit |= 1 << w;\n\t\t\t\t\t\t\t\tint nxo = 0;\n\t\t\t\t\t\t\t\tint nxcnt = cnt;\n\t\t\t\t\t\t\t\tdp[cw][nxbit][nxo][nxcnt] += dp[befw][bit][o][cnt];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 0; i < 1 << (W - 1); i++) {\n\t\tfor (int j = 0; j < 2; j++) {\n\t\t\tans += dp[0][i][j][1];\n\t\t\tans %= 100000;\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 5560, "memory_kb": 27724, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0559_4554003", "code_snippet": "#pragma GCC target (\"avx\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n//#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define C complex<ld>\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define rng(i,s,n) for(int i = (s) ; i < (n) ; i++)\n#define rep(i,n) rng(i, 0, (n))\n#define mkp make_pair\n#define vec vector\n#define vi vec<int>\n#define pb emplace_back\n#define siz(a) (int)(a).size()\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==(int)(n)-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define cyes printf(\"Yes\\n\")\n#define cno printf(\"No\\n\")\n#define cdf(n) int quetimes_=(n);rep(qq123_,quetimes_)\n#define gcj printf(\"Case #%lld: \",qq123_+1)\n#define readv(a,n) a.resize(n,0);rep(i,(n)) a[i]=read()\n//#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr ld EPS = 1e-10;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconstexpr int dx[] = { -1,1,0,0 }, dy[] = { 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; int k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nbool ina(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nbool ina(int t, int l, int r) { return l <= t && t < r; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll popcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\nclass mint {\npublic:long long v;\n\t mint(long long v = 0) { s(v % mod); }\n\t constexpr static int mod = 1e5;\n\t constexpr static int fn_ = 500005;\n\t static mint fact[fn_], comp[fn_];\n\t mint pow(mint x) const {\n\t\t mint b(v), c(1);\n\t\t while (x.v) {\n\t\t\t if (x.v & 1) c *= b;\n\t\t\t b *= b;\n\t\t\t x.v >>= 1;\n\t\t }\n\t\t return c;\n\t }\n\t inline mint& s(int vv) {\n\t\t v = vv < mod ? vv : vv - mod;\n\t\t return *this;\n\t }\n\t inline mint inv()const { return pow(mod - 2); }\n\t inline mint operator-()const { return mint() - *this; }\n\t inline mint& operator+=(const mint b) { return s(v + b.v); }\n\t inline mint& operator-=(const mint b) { return s(v + mod - b.v); }\n\t inline mint& operator*=(const mint b) { v = v * b.v % mod; return *this; }\n\t inline mint& operator/=(const mint b) { return (*this) *= b.inv(); }\n\t inline mint operator+(const mint b) const { return mint(v) += b; }\n\t inline mint operator-(const mint b) const { return mint(v) -= b; }\n\t inline mint operator*(const mint b) const { return mint(v) *= b; }\n\t inline mint operator/(const mint b) const { return mint(v) /= b; }\n\t friend ostream& operator<<(ostream& os, const mint& m) {\n\t\t return os << m.v;\n\t }\n\t friend istream& operator>>(istream& is, mint& m) {\n\t\t int x; is >> x; m = mint(x);\n\t\t return is;\n\t }\n\t bool operator<(const mint& r)const { return v < r.v; }\n\t bool operator>(const mint& r)const { return v > r.v; }\n\t bool operator<=(const mint& r)const { return v <= r.v; }\n\t bool operator>=(const mint& r)const { return v >= r.v; }\n\t bool operator==(const mint& r)const { return v == r.v; }\n\t bool operator!=(const mint& r)const { return v != r.v; }\n\t explicit operator bool()const { return v; }\n\t explicit operator int()const { return v; }\n\t mint comb(mint k) {\n\t\t if (k > * this) return mint();\n\t\t if (!fact[0]) combinit();\n\t\t if (v >= fn_) {\n\t\t\t if (k > * this - k) k = *this - k;\n\t\t\t mint tmp(1);\n\t\t\t for (int i = v; i >= v - k.v + 1; i--) tmp *= mint(i);\n\t\t\t return tmp * comp[k.v];\n\t\t }\n\t\t else return fact[v] * comp[k.v] * comp[v - k.v];\n\t }//nCk\n\t static void combinit() {\n\t\t fact[0] = 1;\n\t\t for (int i = 1; i < fn_; i++) fact[i] = fact[i - 1] * mint(i);\n\t\t comp[fn_ - 1] = fact[fn_ - 1].inv();\n\t\t for (int i = fn_ - 2; i >= 0; i--) comp[i] = comp[i + 1] * mint(i + 1);\n\t }\n}; mint mint::fact[fn_], mint::comp[fn_];\n//--------------------------------------------------------------\nint h, w;\nstring s[30];\n\nsigned main() {\n\tcin >> h >> w;\n\trep(i, h) cin >> s[i];\n\n\n\tmint ans = 1;\n\trep(i, h)rep(j, w)if (s[i][j] == '?') ans *= 3;\n\n\tvec<mint>dp(1 << w, 0);\n\tdp[0] = 1;\n\n\n\trep(i, h)rep(j, w) {\n\n\t\tvec<mint>dp2(1 << w, 0);\n\n\t\tauto F = [&](int k) ->int{\n\t\t\treturn (k & ~(1 << (w - 1)));\n\t\t};\n\n\t\tif (s[i][j] == 'J'||s[i][j]=='?') {\n\t\t\trep(k, 1 << w) {\n\t\t\t\tdp2[(F(k) >> 1) | (1 << (w - 1))] += dp[k];\n\t\t\t}\n\t\t}\n\n\t\tif (s[i][j] == 'O' || s[i][j] == '?') {\n\t\t\trep(k, 1 << w) {\n\t\t\t\tif (j > 0) dp2[k >> 1] += dp[k];\n\t\t\t\telse dp2[F(k) >> 1] += dp[k];\n\t\t\t}\n\t\t}\n\n\t\tif (s[i][j] == 'I' || s[i][j] == '?') {\n\t\t\trep(k, 1 << w) {\n\t\t\t\tif (k & 1) continue;\n\t\t\t\tdp2[F(k) >> 1] += dp[k];\n\t\t\t}\n\t\t}\n\t\tswap(dp, dp2);\n\t}\n\trep(i, 1 << w) ans -= dp[i];\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 2010, "memory_kb": 27200, "score_of_the_acc": -1.3226, "final_rank": 19 }, { "submission_id": "aoj_0559_4476079", "code_snippet": "#include <iostream>\n#include <numeric>\n#include <vector>\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconstexpr int MOD = 100000;\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n int tot = 1;\n const int mask = (1 << (w - 1)) - 1;\n auto dp = vec(3, vec(1 << (w - 1), 0));\n dp[0][0] = 1;\n auto ndp = dp;\n\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n for (auto& v : ndp) std::fill(v.begin(), v.end(), 0);\n\n int id;\n {\n char c;\n std::cin >> c;\n for (id = 0; id < 3; ++id) {\n if (c == \"JOI\"[id]) break;\n }\n }\n\n if (id == 3) (tot *= 3) %= MOD;\n\n for (int p = 0; p < 3; ++p) {\n for (int k = 0; k < 3; ++k) {\n if (id != 3 && k != id) continue;\n\n for (int b = 0; b < (1 << (w - 1)); ++b) {\n if (k == 2 && ((b >> (w - 2)) & 1)) continue;\n\n int nb = ((b << 1) & mask) + (p == 0 && k == 1 && j != 0);\n ndp[k][nb] += dp[p][b];\n if (ndp[k][nb] >= MOD) ndp[k][nb] -= MOD;\n }\n }\n }\n std::swap(dp, ndp);\n }\n }\n\n int out = 0;\n for (const auto& v : dp) {\n for (const auto& x : v) {\n out += x;\n if (out >= MOD) out -= MOD;\n }\n }\n\n std::cout << (tot - out + MOD) % MOD << \"\\n\";\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 3810, "memory_kb": 15132, "score_of_the_acc": -1.111, "final_rank": 16 } ]
aoj_0569_cpp
イルミネーション (Illumination) 問題 JOI 社の建物は図のような 1 辺 1 メートルの正六角形をつなぎ合わせた形である.クリスマスが近づいているので,JOI 社では建物の壁面をイルミネーションで飾り付けることにした.ただし,外から見えない部分にイルミネーションを施すのは無駄なので,イルミネーションは外から建物の中を通らずに行くことのできる壁面にのみ飾り付けることにした. 図: JOI 社の建物の配置の例 上の図は上空から見た JOI 社の建物の配置の例である.正六角形内の数字は座標を表す.灰色の正六角形は建物がある場所を表し,白色の正六角形は建物がない場所を表す.この例では,赤の実線で示される部分がイルミネーションで飾り付けを行う壁面となり,その壁面の長さの合計は 64 メートルとなる. JOI 社の建物の配置を表す地図が与えられたとき,飾り付けを行う壁面の長さの合計を求めるプログラムを作成せよ.ただし,地図の外側は自由に行き来できるものとし,隣接した建物の間は通ることはできないものとする. 入力 入力ファイルの 1 行目には 2 つの整数 W, H (1 ≦ W ≦ 100,1 ≦ H ≦ 100) が空白を区切りとして書かれている.続く H 行には JOI 社の建物の配置が書かれている.i + 1 行目 (1 ≦ i ≦ H) には W 個の整数が空白を区切りとして書かれており,j 個目 (1 ≦ j ≦ W) の整数は座標 (j, i) の正六角形に建物がある時は 1 であり,ない時は 0 である.また,与えられる入力データには建物が必ず 1 つ以上ある. 地図は以下の規則によって記述されている. 地図の最も北の行の最も西の正六角形は座標 (1, 1) である. 座標 (x, y) の正六角形に隣接する東隣の正六角形は座標 (x + 1, y) である. y が奇数の時,座標 (x, y) の正六角形に隣接する南西の正六角形の座標は (x, y + 1) である. y が偶数の時,座標 (x, y) の正六角形に隣接する南東の正六角形の座標は (x, y + 1) である. 出力 イルミネーションで飾り付けを行う壁面の長さの合計を 1 行で出力せよ. 入出力例 入力例 1 8 4 0 1 0 1 0 1 1 1 0 1 1 0 0 1 0 0 1 0 1 0 1 1 1 1 0 1 1 0 1 0 1 0 出力例 1 64 入出力例 1 は問題文中の例に対応しており,イルミネーションで飾り付けを行う壁面の長さの合計は 64 メートルである. 入力例 2 8 5 0 1 1 1 0 1 1 1 0 1 0 0 1 1 0 0 1 0 0 1 1 1 1 1 0 1 0 1 1 0 1 0 0 1 1 0 1 1 0 0 出力例 2 56 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0569_3314220", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\nusing namespace std;\nlong long mmin(long long &a,long long b) {\n\ta = min(a, b);\n\treturn a;\n}\nlong long mmax(long long &a,long long b) {\n\ta = max(a, b);\n\treturn a;\n}\nint nibu(vector<int> &v, int tan) {\n\tint up = v.size()-1;\n\tint lo = 0;\n\tif (tan <= v[0]) {\n\t\treturn 0;\n\t}\n\twhile (up - lo > 1) {\n\t\tint mi = (up + lo) / 2;\n\t\tif (tan <= v[mi]) {\n\t\t\tup = mi;\n\t\t}\n\t\tif (v[mi] < tan) {\n\t\t\tlo = mi;\n\t\t}\n\t}\n\treturn up;\n}\nint ne(int &i, int &j, int k, int ty) {\n\tint di = 0; int dj = 0;\n\tif (k % 3 == 1) {\n\t\tdj = 1;\n\t}\n\telse if (k == 2) {\n\t\tdj = -2;\n\t}\n\telse if (k == 3) {\n\t\tdi = 1;\n\t}\n\telse if (k == 5) {\n\t\tdi = -2;\n\t}\n\telse {\n\t\tdj = -1;\n\t}\n\tif (ty == 1) {\n\t\tdj = -dj;\n\t}\n\ti += di;\n\tj += dj;\n\treturn 0;\n}\nint main() {\n\tint w, h;\n\tcin >> w >> h;\n\tvector<vector<int> > ta(h, vector<int>(w));\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tcin >> ta[i][j];\n\t\t}\n\t}\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (ta[i][j] == 0) {\n\t\t\t\tvector<vector<int> > qt = ta;\n\t\t\t\tqt[i][j] = 1;\n\t\t\t\tvector<int> nei(h*w);\n\t\t\t\tvector<int> nej(h*w);\n\t\t\t\tnei[0] = i;\n\t\t\t\tnej[0] = j;\n\t\t\t\tint up = 1;\n\t\t\t\tint lo = 0;\n\t\t\t\tint da = 0;\n\t\t\t\twhile (up != lo and da == 0) {\n\t\t\t\t\tint qup = up;\n\t\t\t\t\tfor (int in = lo; in < up and da == 0; in++) {\n\t\t\t\t\t\tint pi = nei[in];\n\t\t\t\t\t\tint pj = nej[in];\n\t\t\t\t\t\tif (0 < pi and pi < h - 1) {\n\t\t\t\t\t\t\tif (0 < pj and pj < w - 1) {\n\t\t\t\t\t\t\t\tint ty = (pi+1) % 2;\n\t\t\t\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\t\t\t\tne(pi, pj, k+1, ty);\n\t\t\t\t\t\t\t\t\tif (qt[pi][pj] == 0) {\n\t\t\t\t\t\t\t\t\t\tnei[qup] = pi;\n\t\t\t\t\t\t\t\t\t\tnej[qup] = pj;\n\t\t\t\t\t\t\t\t\t\tqup++;\n\t\t\t\t\t\t\t\t\t\tqt[pi][pj] = 1;\n\t\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\telse {\n\t\t\t\t\t\t\t\tda = 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse {\n\t\t\t\t\t\t\tda = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tlo = up;\n\t\t\t\t\tup = qup;\n\t\t\t\t}\n\t\t\t\tif (da == 0) {\n\t\t\t\t\tta = qt;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tvector<vector<int> > ht(h + 2, vector<int>(w + 2,0));\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tht[i + 1][j + 1] = ta[i][j];\n\t\t}\n\t}\n\th += 2;\n\tw += 2;\n\tint ans = 0;\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (j < w - 1) {\n\t\t\t\tif (ht[i][j] + ht[i][j + 1] == 1) {\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint x = j - 1+i % 2;\n\t\t\tif (x >= 0 and i < h - 1) {\n\t\t\t\tif (ht[i][j] + ht[i + 1][x] == 1) {\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tint y = j + i % 2;\n\t\t\tif (y < w and i < h - 1) {\n\t\t\t\tif (ht[i][j] + ht[i + 1][y] == 1) {\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl; \n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3280, "score_of_the_acc": -0.5555, "final_rank": 17 }, { "submission_id": "aoj_0569_2779097", "code_snippet": "#include <iostream>\n#include <cstring>\n#define MS memset(yet, false, sizeof(yet))\n\nusing namespace std;\n\nint h, w, a[110][110];\nbool yet[110][110];\nbool dfseven (int i, int j);\n\nbool dfsodd (int i, int j)\n{\n yet[i][j]=true;\n if (a[i][j]==1) return false;\n if (i==0 || i==h+1 || j==0 || j==w+1) return true;\n if (a[i][j]==0)\n {\n if (!yet[i-1][j]) { if (dfseven(i-1, j)) return true; }\n if (!yet[i-1][j+1]) { if (dfseven(i-1, j+1)) return true; }\n if (!yet[i][j-1]) { if (dfsodd(i, j-1)) return true; }\n if (!yet[i][j+1]) { if (dfsodd(i, j+1)) return true; }\n if (!yet[i+1][j]) { if (dfseven(i+1, j)) return true; }\n if (!yet[i+1][j+1]) { if (dfseven(i+1, j+1)) return true; }\n }\n return false;\n}\n\nbool dfseven (int i, int j)\n{\n yet[i][j]=true;\n if (a[i][j]==1) return false;\n if (i==0 || i==h+1 || j==0 || j==w+1) return true;\n if (a[i][j]==0)\n {\n if (!yet[i-1][j-1]) { if (dfsodd(i-1, j-1)) return true; }\n if (!yet[i-1][j]) { if (dfsodd(i-1, j)) return true; }\n if (!yet[i][j-1]) { if (dfseven(i, j-1)) return true; }\n if (!yet[i][j+1]) { if (dfseven(i, j+1)) return true; }\n if (!yet[i+1][j-1]) { if (dfsodd(i+1, j-1)) return true; }\n if (!yet[i+1][j]) { if (dfsodd(i+1, j)) return true; }\n }\n return false;\n}\n\nint main()\n{\n int cnt, sum=0;\n bool ok;\n memset(a, 0, sizeof(a));\n cin>>w>>h;\n for (int i=1; i<=h; i++) for (int j=1; j<=w; j++) cin>>a[i][j];\n for (int i=1; i<=h; i++)\n {\n for (int j=1; j<=w; j++)\n {\n ok=false;\n if (i%2==1 && a[i][j]==0)\n {\n if (dfseven(i-1, j)) { MS; ok=true; }\n else if (dfseven(i-1, j+1)) { MS; ok=true; }\n else if (dfsodd(i, j-1)) { MS; ok=true; }\n else if (dfsodd(i, j+1)) { MS; ok=true; }\n else if (dfseven(i+1, j)) { MS; ok=true; }\n else if (dfseven(i+1, j+1)) { MS; ok=true; }\n }\n if (i%2==0 && a[i][j]==0)\n {\n if (dfsodd(i-1, j-1)) { MS; ok=true; }\n else if (dfsodd(i-1, j)) { MS; ok=true; }\n else if (dfseven(i, j-1)) { MS; ok=true; }\n else if (dfseven(i, j+1)) { MS; ok=true; }\n else if (dfsodd(i+1, j-1)) { MS; ok=true; }\n else if (dfsodd(i+1, j)) { MS; ok=true; }\n }\n if (!ok && a[i][j]==0) a[i][j]=1;\n }\n }\n for (int i=1; i<=h; i++)\n {\n for (int j=1; j<=w; j++)\n {\n cnt=6;\n if (i%2==1 && a[i][j])\n {\n if (a[i-1][j]) cnt--;\n if (a[i-1][j+1]) cnt--;\n if (a[i][j-1]) cnt--;\n if (a[i][j+1]) cnt--;\n if (a[i+1][j]) cnt--;\n if (a[i+1][j+1]) cnt--;\n sum+=cnt;\n }\n if (i%2==0 && a[i][j])\n {\n if (a[i-1][j-1]) cnt--;\n if (a[i-1][j]) cnt--;\n if (a[i][j-1]) cnt--;\n if (a[i][j+1]) cnt--;\n if (a[i+1][j-1]) cnt--;\n if (a[i+1][j]) cnt--;\n sum+=cnt;\n }\n }\n }\n cout<<sum<<'\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3484, "score_of_the_acc": -0.5412, "final_rank": 16 }, { "submission_id": "aoj_0569_2622980", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nstruct xy {\n\tint x, y;\n};\n\nxy a[6] = {\n\t{0,-1},\n\t{1,-1},\n\t{-1,0},\n\t{1,0},\n\t{0,1},\n\t{1,1}\n};\n\nxy b[6] = {\n\t{ -1,-1 },\n\t{ 0,-1 },\n\t{ -1,0 },\n\t{ 1,0 },\n\t{ -1,1 },\n\t{ 0,1 }\n};\n\n\nint main() {\n\tint w, h;\n\tcin >> w >> h;\n\n\tvector<vector<int> > map(h+2, vector<int>(w+2, -1));\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tcin >> map[i + 1][j + 1];\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (map[i + 1][j + 1] == 1 || map[i + 1][j + 1] == -1)continue;\n\n\t\t\tbool flag = false;\n\t\t\tvector<vector<bool> > used(h + 2, vector<bool>(w + 2, false));\n\t\t\tused[i + 1][j + 1] = true;\n\t\t\txy pos = { j + 1,i + 1 };\n\t\t\tqueue<xy> q;\n\t\t\tq.push(pos);\n\n\t\t\tvector<xy> root;\n\t\t\twhile (!q.empty()) {\n\t\t\t\txy u = q.front(); q.pop();\n\t\t\t\tif (u.y % 2 == 0) {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + b[k].y][u.x + b[k].x] == 0 && used[u.y + b[k].y][u.x + b[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + b[k].x , u.y + b[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + b[k].y][u.x + b[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + a[k].y][u.x + a[k].x] == 0 && used[u.y + a[k].y][u.x + a[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + a[k].x , u.y + a[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + a[k].y][u.x + a[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\troot.push_back(u);\n\t\t\t}\n\t\tloop:\n\t\t\tif (flag) {\n\t\t\t\tmap[i + 1][j + 1] = -1;\n\t\t\t\tfor (int k = 0; k < root.size(); k++) {\n\t\t\t\t\tmap[root[k].y][root[k].x] = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmap[i + 1][j + 1] = 1;\n\t\t\t\tfor (int k = 0; k < root.size(); k++) {\n\t\t\t\t\tmap[root[k].y][root[k].x] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 1; i < h + 1; i++) {\n\t\tfor (int j = 1; j < w + 1; j++) {\n\t\t\tif (map[i][j] != 1) continue;\n\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\tif (i % 2 == 0) {\n\t\t\t\t\tif (map[i + b[k].y][j + b[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (map[i + a[k].y][j + a[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3212, "score_of_the_acc": -0.4149, "final_rank": 13 }, { "submission_id": "aoj_0569_2622979", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nstruct xy {\n\tint x, y;\n};\n\nxy a[6] = {\n\t{0,-1},\n\t{1,-1},\n\t{-1,0},\n\t{1,0},\n\t{0,1},\n\t{1,1}\n};\n\nxy b[6] = {\n\t{ -1,-1 },\n\t{ 0,-1 },\n\t{ -1,0 },\n\t{ 1,0 },\n\t{ -1,1 },\n\t{ 0,1 }\n};\n\n\nint main() {\n\tint w, h;\n\tcin >> w >> h;\n\n\tvector<vector<int> > map(h+2, vector<int>(w+2, -1));\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tcin >> map[i + 1][j + 1];\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (map[i + 1][j + 1] == 1)continue;\n\n\t\t\tbool flag = false;\n\t\t\tvector<vector<bool> > used(h + 2, vector<bool>(w + 2, false));\n\t\t\tused[i + 1][j + 1] = true;\n\t\t\txy pos = { j + 1,i + 1 };\n\t\t\tqueue<xy> q;\n\t\t\tq.push(pos);\n\n\t\t\tvector<xy> root;\n\t\t\twhile (!q.empty()) {\n\t\t\t\txy u = q.front(); q.pop();\n\t\t\t\tif (u.y % 2 == 0) {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + b[k].y][u.x + b[k].x] == 0 && used[u.y + b[k].y][u.x + b[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + b[k].x , u.y + b[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + b[k].y][u.x + b[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + a[k].y][u.x + a[k].x] == 0 && used[u.y + a[k].y][u.x + a[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + a[k].x , u.y + a[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + a[k].y][u.x + a[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\troot.push_back(u);\n\t\t\t}\n\t\tloop:\n\t\t\tif (flag) {\n\t\t\t\tmap[i + 1][j + 1] = -1;\n\t\t\t\tfor (int k = 0; k < root.size(); k++) {\n\t\t\t\t\tmap[root[k].y][root[k].x] = -1;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmap[i + 1][j + 1] = 1;\n\t\t\t\tfor (int k = 0; k < root.size(); k++) {\n\t\t\t\t\tmap[root[k].y][root[k].x] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 1; i < h + 1; i++) {\n\t\tfor (int j = 1; j < w + 1; j++) {\n\t\t\tif (map[i][j] != 1) continue;\n\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\tif (i % 2 == 0) {\n\t\t\t\t\tif (map[i + b[k].y][j + b[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (map[i + a[k].y][j + a[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3172, "score_of_the_acc": -0.4206, "final_rank": 14 }, { "submission_id": "aoj_0569_2620489", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nstruct xy {\n\tint x, y;\n};\n\nxy a[6] = {\n\t{0,-1},\n\t{1,-1},\n\t{-1,0},\n\t{1,0},\n\t{0,1},\n\t{1,1}\n};\n\nxy b[6] = {\n\t{ -1,-1 },\n\t{ 0,-1 },\n\t{ -1,0 },\n\t{ 1,0 },\n\t{ -1,1 },\n\t{ 0,1 }\n};\n\n\nint main() {\n\tint w, h;\n\tcin >> w >> h;\n\n\tvector<vector<int> > map(h+2, vector<int>(w+2, -1));\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tcin >> map[i + 1][j + 1];\n\t\t}\n\t}\n\n\tint ans = 0;\n\n\tfor (int i = 0; i < h; i++) {\n\t\tfor (int j = 0; j < w; j++) {\n\t\t\tif (map[i + 1][j + 1] == 1)continue;\n\n\t\t\tbool flag = false;\n\t\t\tvector<vector<bool> > used(h + 2, vector<bool>(w + 2, false));\n\t\t\tused[i + 1][j + 1] = true;\n\t\t\txy pos = { j + 1,i + 1 };\n\t\t\tqueue<xy> q;\n\t\t\tq.push(pos);\n\n\t\t\twhile (!q.empty()) {\n\t\t\t\txy u = q.front(); q.pop();\n\t\t\t\tif (u.y % 2 == 0) {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + b[k].y][u.x + b[k].x] == 0 && used[u.y + b[k].y][u.x + b[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + b[k].x , u.y + b[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + b[k].y][u.x + b[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\t\t\tif (map[u.y + a[k].y][u.x + a[k].x] == 0 && used[u.y + a[k].y][u.x + a[k].x] == false) {\n\t\t\t\t\t\t\txy temp = { u.x + a[k].x , u.y + a[k].y };\n\t\t\t\t\t\t\tq.push(temp);\n\t\t\t\t\t\t\tused[temp.y][temp.x] = 1;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[u.y + a[k].y][u.x + a[k].x] == -1) {\n\t\t\t\t\t\t\tflag = true;\n\t\t\t\t\t\t\tgoto loop;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\tloop:\n\t\t\tif (flag) map[i + 1][j + 1] = -1;\n\t\t\telse map[i + 1][j + 1] = 1;\n\t\t}\n\t}\n\n\tfor (int i = 1; i < h + 1; i++) {\n\t\tfor (int j = 1; j < w + 1; j++) {\n\t\t\tif (map[i][j] != 1) continue;\n\t\t\tfor (int k = 0; k < 6; k++) {\n\t\t\t\tif (i % 2 == 0) {\n\t\t\t\t\tif (map[i + b[k].y][j + b[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (map[i + a[k].y][j + a[k].x] == -1) ans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3144, "score_of_the_acc": -0.4106, "final_rank": 12 }, { "submission_id": "aoj_0569_2542254", "code_snippet": "#include <algorithm>\n#include <iostream>\n\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define repr(i, m, n) for (int i = m; i < n; i++)\n#define nbs(y) (y % 2 ? odd_y : even_y)\n\nint builds[102][102];\nint odd_y[][2] = {{0, 1}, {1, 1}, {1, 0}, {1, -1}, {0, -1}, {-1, 0}};\nint even_y[][2] = {{-1, 1}, {0, 1}, {1, 0}, {0, -1}, {-1, -1}, {-1, 0}};\n\nbool in_rng(int x, int y, int w, int h) {\n return x >= 0 && y >= 0 && w + 1 >= x && h + 1 >= y;\n}\nint main() {\n int w, h;\n std::cin >> w >> h;\n\n rep(x, 102) rep(y, 102) builds[x][y] = 0;\n repr(y, 1, h + 1) repr(x, 1, w + 1) {\n int v;\n std::cin >> v, builds[x][y] = v;\n }\n\n bool labeled;\n do {\n labeled = false;\n rep(x, w + 2) rep(y, h + 2) {\n if (x == 0 && y == 0)\n builds[0][0] = 2;\n else if (!builds[x][y] &&\n std::any_of(nbs(y), nbs(y) + 6, [&](int ns[]) {\n int p = x + ns[0], q = y + ns[1];\n return in_rng(p, q, w, h) && builds[p][q] == 2;\n }))\n builds[x][y] = 2, labeled = true;\n }\n } while (labeled);\n\n int count = 0;\n rep(x, w + 2) rep(y, h + 2) rep(i, 3) {\n int p = x + nbs(y)[i][0], q = y + nbs(y)[i][1];\n if (in_rng(p, q, w, h) && ((builds[x][y] == 1 && builds[p][q] == 2) ||\n (builds[x][y] == 2 && builds[p][q] == 1)))\n count++;\n }\n std::cout << count << std::endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3128, "score_of_the_acc": -0.4074, "final_rank": 11 }, { "submission_id": "aoj_0569_2133203", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <vector>\n#include <sstream>\n#include <cmath>\n#include <queue>\n\nusing namespace std;\n\n#define INF 1\n#define MAX_V 50000\n\nstruct edge{\n\tint to;\n\tint cost;\n};\n\ntypedef pair<int, int> P; // first??????????????¢???second??????????????????\n\n// ?????????O(|E|log|V|)\n\nint d[MAX_V];\nvector<edge> G[MAX_V];\n\nvoid shortest_path(int s, int V){ // V???????????°\n\t\n\tpriority_queue<P, vector<P>, greater<P> > que;\n\t\n\tfor(int i = 0; i < V; i++){\n\t\td[i] = INF;\n\t}\n\td[s] = 0;\n\t\n\tque.push(P(0, s));\n\t\n\twhile(!que.empty()){\n\t\t\n\t\tP p = que.top();\n\t\tque.pop();\n\t\t\n\t\tint v = p.second;\n\t\t\n\t\tif(d[v] < p.first){\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t\tfor(int i = 0; i < G[v].size(); i++){\n\t\t\tedge e = G[v][i];\n\t\t\tif(d[e.to] > e.cost + d[v]){\n\t\t\t\td[e.to] = d[v] + e.cost;\n\t\t\t\tque.push(P(d[e.to], e.to));\n\t\t\t}\n\t\t} // ????????????????°???????????????´??°\n\t}\n}\n\nint main(){\n\t\n\tint W, H;\n\t\n\tint map[200][200];\n\t\n\twhile(true){\n\t\tcin >> W >> H;\n\t\t\n\t\tif(cin.eof()){\n\t\t\tbreak;\n\t\t}\n\t\t\n\t\tfor(int i = 0; i < 200; i++){\n\t\t\tfor(int j = 0; j < 200; j++){\n\t\t\t\tmap[i][j] = 0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tfor(int i = 1; i <= H; i++){\n\t\t\tfor(int j = 1; j <= W; j++){\n\t\t\t\tcin >> map[j][i];\n\t\t\t}\n\t\t}\n\t\t\n\t\tfor(int i = 0; i < MAX_V; i++){\n\t\t\tG[i].erase(G[i].begin(), G[i].end());\n\t\t}\n\t\t\n\t\tfor(int i = 0; i < 150; i++){\n\t\t\tfor(int j = 0; j < 150; j++){\n\t\t\t\tif(map[i][j] == map[i + 1][j]){\n\t\t\t\t\tint index1 = i + j * 200;\n\t\t\t\t\tint index2 = i + 1 + j * 200;\n\t\t\t\t\tedge e1, e2;\n\t\t\t\t\te1.cost = 0;\n\t\t\t\t\te2.cost = 0;\n\t\t\t\t\te1.to = index2;\n\t\t\t\t\te2.to = index1;\n\t\t\t\t\tG[index1].push_back(e1);\n\t\t\t\t\tG[index2].push_back(e2);\n\t\t\t\t}\n\t\t\t\tif(map[i][j] == map[i][j + 1]){\n\t\t\t\t\tint index1 = i + j * 200;\n\t\t\t\t\tint index2 = i + (j + 1) * 200;\n\t\t\t\t\tedge e1, e2;\n\t\t\t\t\te1.cost = 0;\n\t\t\t\t\te2.cost = 0;\n\t\t\t\t\te1.to = index2;\n\t\t\t\t\te2.to = index1;\n\t\t\t\t\tG[index1].push_back(e1);\n\t\t\t\t\tG[index2].push_back(e2);\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\tif(j % 2 == 0){\n\t\t\t\t\tif(i >= 1 && map[i][j] == map[i - 1][j + 1]){\n\t\t\t\t\t\tint index1 = i + j * 200;\n\t\t\t\t\t\tint index2 = i - 1 + (j + 1) * 200;\n\t\t\t\t\t\tedge e1, e2;\n\t\t\t\t\t\te1.cost = 0;\n\t\t\t\t\t\te2.cost = 0;\n\t\t\t\t\t\te1.to = index2;\n\t\t\t\t\t\te2.to = index1;\n\t\t\t\t\t\tG[index1].push_back(e1);\n\t\t\t\t\t\tG[index2].push_back(e2);\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tif(map[i][j] == map[i + 1][j + 1]){\n\t\t\t\t\t\tint index1 = i + j * 200;\n\t\t\t\t\t\tint index2 = i + 1 + (j + 1) * 200;\n\t\t\t\t\t\tedge e1, e2;\n\t\t\t\t\t\te1.cost = 0;\n\t\t\t\t\t\te2.cost = 0;\n\t\t\t\t\t\te1.to = index2;\n\t\t\t\t\t\te2.to = index1;\n\t\t\t\t\t\tG[index1].push_back(e1);\n\t\t\t\t\t\tG[index2].push_back(e2);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\n\t\tshortest_path(0, 40000);\n\t\t\n\t\tint ans = 0;\n\t\t\n\t\tfor(int i = 0; i < 150; i++){\n\t\t\tfor(int j = 0; j < 150; j++){\n\t\t\t\tif(d[i + j * 200] != d[i + 1 + j * 200]){\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t\tif(d[i + j * 200] != d[i + (j + 1) * 200]){\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t\t\n\t\t\t\tif(j % 2 == 0){\n\t\t\t\t\tif(i >= 1 && d[i + j * 200] != d[i - 1 + (j + 1) * 200]){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t}else{\n\t\t\t\t\tif(d[i + j * 200] != d[i + 1 + (j + 1) * 200]){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t\n\t\t\t}\n\t\t}\n\t\t\n\t\t/*\n\t\tfor(int i = 0; i <= H + 1; i++){\n\t\t\tfor(int j = 0; j <= W + 1; j++){\n\t\t\t\tcout << d[i * 200 + j] << \" \";\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\t\t*/\n\t\tcout << ans << endl;\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6272, "score_of_the_acc": -1, "final_rank": 18 }, { "submission_id": "aoj_0569_1872034", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint w,h,mp[101][101];\nint dy[6]={-1,-1,0,0,1,1};\nint dx[2][6]={\n {0,1,-1,1,0,1},\n {-1,0,-1,1,-1,0}\n};\n \n \nint used[101][101];\nint mark(int y,int x){\n if(x<0||y<0||x>=w||y>=h)return 0;\n if(mp[y][x]||used[y][x]++)return 1;\n \n int res=1;\n for(int i=0;i<6&&res;i++){\n int nx=x+dx[y%2][i],ny=y+dy[i]; \n res*=mark(ny,nx);\n }\n return res;\n}\n \nint main(){\n cin>>w>>h;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++)cin>>mp[i][j];\n \n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n memset(used,0,sizeof(used));\n if(!mp[i][j])mp[i][j]=mark(i,j);\n } \n \n int ans=0;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n int cnt=6;\n if(!mp[i][j])continue;\n for(int k=0;k<6;k++){\n int nx=j+dx[i%2][k],ny=i+dy[k];\n if(nx<0||ny<0||nx>=w||ny>=h) continue;\n cnt-=mp[ny][nx];\n }\n ans+=cnt;\n }\n cout <<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 1468, "score_of_the_acc": -0.2392, "final_rank": 8 }, { "submission_id": "aoj_0569_1869256", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint w,h,mp[101][101];\nint dy[6]={-1,-1,0,0,1,1};\nint dx[2][6]={\n {0,1,-1,1,0,1},\n {-1,0,-1,1,-1,0}\n};\n\n\nint used[101][101];\nint mark(int y,int x){\n if(x<0||y<0||x>=w||y>=h)return 0;\n if(mp[y][x]||used[y][x]++)return 1;\n\n int res=1;\n for(int i=0;i<6&&res;i++){\n int nx=x+dx[y%2][i],ny=y+dy[i]; \n res*=mark(ny,nx);\n }\n return res;\n}\n\nint main(){\n cin>>w>>h;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++)cin>>mp[i][j];\n \n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n memset(used,0,sizeof(used));\n if(!mp[i][j])mp[i][j]=mark(i,j);\n } \n\n int ans=0;\n for(int i=0;i<h;i++)\n for(int j=0;j<w;j++){\n int cnt=6;\n if(!mp[i][j])continue;\n for(int k=0;k<6;k++){\n\tint nx=j+dx[i%2][k],ny=i+dy[k];\n\tif(nx<0||ny<0||nx>=w||ny>=h) continue;\n\tcnt-=mp[ny][nx];\n }\n ans+=cnt;\n }\n cout <<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 1472, "score_of_the_acc": -0.24, "final_rank": 9 }, { "submission_id": "aoj_0569_1585374", "code_snippet": "#include<iostream>\n#include<cstring>\nusing namespace std;\n \nint main(){\n int n,m,a,b,x[110][110],y[110][110],sum=0;\n memset(x,0,sizeof(x));\n cin>>m>>n;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n cin>>x[i][j];\n }\n }\n memset(y,0,sizeof(y));\n\ta=100;\n\tif(m==100){\n\t\tfor(int i=1;i<=50;i++){\n\t\t\tif(x[2][i]==0){\n\t\t\t\tb++;\n\t\t\t}\n\t\t}\n\t\tif(b==50){\n\t\t\ta=10000;\n\t\t}\n\t}\n for(int i=1;i<=m;i++){\n if(x[1][i]==0){\n y[1][i]=1;\n for(int j=1;j<a;j++){\n for(int k=1;k<=n;k++){\n for(int l=1;l<=m;l++){\n if(x[k][l]==0 && y[k][l]==1){\n if(x[k][l-1]==0){\n y[k][l-1]=1;\n }\n if(x[k-1][l]==0){\n y[k-1][l]=1;\n }\n if(k%2==0){\n if(x[k-1][l-1]==0){\n y[k-1][l-1]=1;\n }\n if(x[k+1][l-1]==0){\n y[k+1][l-1]=1;\n }\n }\n if(x[k][l+1]==0){\n y[k][l+1]=1;\n }\n if(x[k+1][l]==0){\n y[k+1][l]=1;\n }\n if(k%2==1){\n if(x[k+1][l+1]==0){\n y[k+1][l+1]=1;\n }\n if(x[k-1][l+1]==0){\n y[k-1][l+1]=1;\n }\n }\n }\n }\n }\n sum=0;\n }\n }\n }\n for(int i=1;i<=m;i++){\n if(x[n][i]==0){\n y[n][i]=1;\n for(int j=1;j<a;j++){\n for(int k=1;k<=n;k++){\n for(int l=1;l<=m;l++){\n if(x[k][l]==0 && y[k][l]==1){\n if(x[k][l-1]==0){\n y[k][l-1]=1;\n }\n if(x[k-1][l]==0){\n y[k-1][l]=1;\n }\n if(k%2==0){\n if(x[k-1][l-1]==0){\n y[k-1][l-1]=1;\n }\n if(x[k+1][l-1]==0){\n y[k+1][l-1]=1;\n }\n }\n if(x[k][l+1]==0){\n y[k][l+1]=1;\n }\n if(x[k+1][l]==0){\n y[k+1][l]=1;\n }\n if(k%2==1){\n if(x[k+1][l+1]==0){\n y[k+1][l+1]=1;\n }\n if(x[k-1][l+1]==0){\n y[k-1][l+1]=1;\n }\n }\n }\n }\n }\n sum=0;\n }\n }\n }\n for(int i=1;i<=n;i++){\n if(x[i][1]==0){\n y[i][1]=1;\n for(int j=1;j<a;j++){\n for(int k=1;k<=n;k++){\n for(int l=1;l<=m;l++){\n if(x[k][l]==0 && y[k][l]==1){\n if(x[k][l-1]==0){\n y[k][l-1]=1;\n }\n if(x[k-1][l]==0){\n y[k-1][l]=1;\n }\n if(k%2==0){\n if(x[k-1][l-1]==0){\n y[k-1][l-1]=1;\n }\n if(x[k+1][l-1]==0){\n y[k+1][l-1]=1;\n }\n }\n if(x[k][l+1]==0){\n y[k][l+1]=1;\n }\n if(x[k+1][l]==0){\n y[k+1][l]=1;\n }\n if(k%2==1){\n if(x[k+1][l+1]==0){\n y[k+1][l+1]=1;\n }\n if(x[k-1][l+1]==0){\n y[k-1][l+1]=1;\n }\n }\n }\n }\n }\n sum=0;\n }\n }\n }\n for(int i=1;i<=n;i++){\n if(x[i][m]==0){\n y[i][m]=1;\n for(int j=1;j<a;j++){\n for(int k=1;k<=n;k++){\n for(int l=1;l<=m;l++){\n if(x[k][l]==0 && y[k][l]==1){\n if(x[k][l-1]==0){\n y[k][l-1]=1;\n }\n if(x[k-1][l]==0){\n y[k-1][l]=1;\n }\n if(k%2==0){\n if(x[k-1][l-1]==0){\n y[k-1][l-1]=1;\n }\n if(x[k+1][l-1]==0){\n y[k+1][l-1]=1;\n }\n }\n if(x[k][l+1]==0){\n y[k][l+1]=1;\n }\n if(x[k+1][l]==0){\n y[k+1][l]=1;\n }\n if(k%2==1){\n if(x[k+1][l+1]==0){\n y[k+1][l+1]=1;\n }\n if(x[k-1][l+1]==0){\n y[k-1][l+1]=1;\n }\n }\n }\n }\n }\n sum=0;\n }\n }\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(y[i][j]!=1){\n x[i][j]=1;\n }\n }\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(x[i][j]==1){\n if(x[i][j-1]==0){\n sum++;\n }\n if(x[i][j+1]==0){\n sum++;\n }\n if(x[i-1][j]==0){\n sum++;\n }\n if(x[i+1][j]==0){\n sum++;\n }\n if(i%2==0){\n if(x[i-1][j-1]==0){\n sum++;\n }\n if(x[i+1][j-1]==0){\n sum++;\n }\n }\n if(i%2==1){\n if(x[i-1][j+1]==0){\n sum++;\n }\n if(x[i+1][j+1]==0){\n sum++;\n }\n }\n }\n }\n }\n cout<<sum<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1040, "memory_kb": 1268, "score_of_the_acc": -0.4816, "final_rank": 15 }, { "submission_id": "aoj_0569_1585310", "code_snippet": "#include<iostream>\n#include<cstring>\nusing namespace std;\n\nint main(){\n\tint n,m,x[110][110],y[110][110],sum=0;\n\tmemset(x,0,sizeof(x));\n\tcin>>m>>n;\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tcin>>x[i][j];\n\t\t}\n\t}\n\tmemset(y,0,sizeof(y));\n\tfor(int i=1;i<=m;i++){\n\t\tif(x[1][i]==0){\n\t\t\ty[1][i]=1;\n\t\t\tfor(int j=1;j<100;j++){\n\t\t\t\tfor(int k=1;k<=n;k++){\n\t\t\t\t\tfor(int l=1;l<=m;l++){\n\t\t\t\t\t\tif(x[k][l]==0 && y[k][l]==1){\n\t\t\t\t\t\t\tif(x[k][l-1]==0){\n\t\t\t\t\t\t\t\ty[k][l-1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k-1][l]==0){\n\t\t\t\t\t\t\t\ty[k-1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==0){\n\t\t\t\t\t\t\t\tif(x[k-1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k+1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k][l+1]==0){\n\t\t\t\t\t\t\t\ty[k][l+1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k+1][l]==0){\n\t\t\t\t\t\t\t\ty[k+1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==1){\n\t\t\t\t\t\t\t\tif(x[k+1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k-1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsum=0;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=m;i++){\n\t\tif(x[n][i]==0){\n\t\t\ty[n][i]=1;\n\t\t\tfor(int j=1;j<100;j++){\n\t\t\t\tfor(int k=1;k<=n;k++){\n\t\t\t\t\tfor(int l=1;l<=m;l++){\n\t\t\t\t\t\tif(x[k][l]==0 && y[k][l]==1){\n\t\t\t\t\t\t\tif(x[k][l-1]==0){\n\t\t\t\t\t\t\t\ty[k][l-1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k-1][l]==0){\n\t\t\t\t\t\t\t\ty[k-1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==0){\n\t\t\t\t\t\t\t\tif(x[k-1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k+1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k][l+1]==0){\n\t\t\t\t\t\t\t\ty[k][l+1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k+1][l]==0){\n\t\t\t\t\t\t\t\ty[k+1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==1){\n\t\t\t\t\t\t\t\tif(x[k+1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k-1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsum=0;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tif(x[i][1]==0){\n\t\t\ty[i][1]=1;\n\t\t\tfor(int j=1;j<100;j++){\n\t\t\t\tfor(int k=1;k<=n;k++){\n\t\t\t\t\tfor(int l=1;l<=m;l++){\n\t\t\t\t\t\tif(x[k][l]==0 && y[k][l]==1){\n\t\t\t\t\t\t\tif(x[k][l-1]==0){\n\t\t\t\t\t\t\t\ty[k][l-1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k-1][l]==0){\n\t\t\t\t\t\t\t\ty[k-1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==0){\n\t\t\t\t\t\t\t\tif(x[k-1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k+1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k][l+1]==0){\n\t\t\t\t\t\t\t\ty[k][l+1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k+1][l]==0){\n\t\t\t\t\t\t\t\ty[k+1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==1){\n\t\t\t\t\t\t\t\tif(x[k+1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k-1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsum=0;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tif(x[i][m]==0){\n\t\t\ty[i][m]=1;\n\t\t\tfor(int j=1;j<100;j++){\n\t\t\t\tfor(int k=1;k<=n;k++){\n\t\t\t\t\tfor(int l=1;l<=m;l++){\n\t\t\t\t\t\tif(x[k][l]==0 && y[k][l]==1){\n\t\t\t\t\t\t\tif(x[k][l-1]==0){\n\t\t\t\t\t\t\t\ty[k][l-1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k-1][l]==0){\n\t\t\t\t\t\t\t\ty[k-1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==0){\n\t\t\t\t\t\t\t\tif(x[k-1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k+1][l-1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l-1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k][l+1]==0){\n\t\t\t\t\t\t\t\ty[k][l+1]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(x[k+1][l]==0){\n\t\t\t\t\t\t\t\ty[k+1][l]=1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif(k%2==1){\n\t\t\t\t\t\t\t\tif(x[k+1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k+1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\tif(x[k-1][l+1]==0){\n\t\t\t\t\t\t\t\t\ty[k-1][l+1]=1;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tsum=0;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tif(y[i][j]!=1){\n\t\t\t\tx[i][j]=1;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tif(x[i][j]==1){\n\t\t\t\tif(x[i][j-1]==0){\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t\tif(x[i][j+1]==0){\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t\tif(x[i-1][j]==0){\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t\tif(x[i+1][j]==0){\n\t\t\t\t\tsum++;\n\t\t\t\t}\n\t\t\t\tif(i%2==0){\n\t\t\t\t\tif(x[i-1][j-1]==0){\n\t\t\t\t\t\tsum++;\n\t\t\t\t\t}\n\t\t\t\t\tif(x[i+1][j-1]==0){\n\t\t\t\t\t\tsum++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(i%2==1){\n\t\t\t\t\tif(x[i-1][j+1]==0){\n\t\t\t\t\t\tsum++;\n\t\t\t\t\t}\n\t\t\t\t\tif(x[i+1][j+1]==0){\n\t\t\t\t\t\tsum++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<sum<<endl;\n\treturn 0;\n}", "accuracy": 0.8, "time_ms": 1060, "memory_kb": 1264, "score_of_the_acc": -0.4899, "final_rank": 20 }, { "submission_id": "aoj_0569_1447643", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<queue>\n#include<algorithm>\nusing namespace std;\ntypedef pair<int, int> P;\nint W, H;\nint X[102][102];\nint dx1[6] = { -1, 0, 0, 1, 1, 1 };\nint dy1[6] = { 0, -1, 1, -1, 0,1};\nint dx2[6] = { -1, -1, -1, 0, 0, 1 };\nint dy2[6] = { -1, 0, 1, -1, 1, 0 };\nint main()\n{\n\tscanf(\"%d%d\", &W, &H);\n\tfor (int i = 1; i <= H; i++){\n\t\tfor (int j = 1; j <= W; j++){\n\t\t\tscanf(\"%d\", &X[j][i]);\n\t\t}\n\t}\n\t\n\tfor (int j = 1; j <= W; j++){\n\t\tfor (int i = 1; i <= H; i++){\n\t\t\tif (X[j][i] == 0){\n\t\t\t\tbool F[102][102];\n\t\t\t\tfor (int k = 0; k < 102; k++)for (int l = 0; l < 102; l++)F[k][l] = X[k][l]&1;\n\t\t\t\tpriority_queue<P>que;\n\t\t\t\tque.push(make_pair(j,i));\n\t\t\t\twhile (!que.empty()){\n\t\t\t\t\tP p = que.top(); que.pop();\n\t\t\t\t\tif (p.second == 0 || p.second == H + 1 || p.first == 0 || p.first == W + 1)goto aa;\n\t\t\t\t\tif (X[p.first][p.second]||F[p.first][p.second])continue;\n\t\t\t\t\tF[p.first][p.second] = true;\n\t\t\t\t\tif (p.second & 1){\n\t\t\t\t\t\t//if (i == 5 && j == 4)printf(\"%d %d\\n\", p.first, p.second);\n\t\t\t\t\t\tfor (int k = 0; k < 6; k++){\n\t\t\t\t\t\t\t//if (i == 5 && j == 4)printf(\"%d %d %d\\n\", p.first + dx1[k], p.second + dy1[k], F[p.first+dx1[k]][p.second+dy1[k]]);\n\n\n\t\t\t\t\t\t\tif (!F[p.first + dx1[k]][p.second + dy1[k]]){\n\t\t\t\t\t\t\t\tque.push(make_pair(p.first + dx1[k], p.second + dy1[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tfor (int k = 0; k < 6; k++){\n\t\t\t\t\t\t\tif (!F[p.first + dx2[k]][p.second + dy2[k]]){\n\t\t\t\t\t\t\t\t\n\t\t\t\t\t\t\t\tque.push(make_pair(p.first + dx2[k], p.second + dy2[k]));\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\t//if (i == 5 && j == 4)printf(\"%d\\n\", que.size());\n\t\t\t\t}\n\t\t\t\tX[j][i] = 1; aa:;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint ans = 0;\n\tfor (int i = 1; i <= W; i++){\n\t\tfor (int j = 1; j <= H; j++){\n\t\t\tif (X[i][j] == 1){\n\t\t\t\tif (j & 1){\n\t\t\t\t\tfor (int k = 0; k < 6; k++){\n\t\t\t\t\t\tif (!X[i + dx1[k]][j + dy1[k]])ans++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tfor (int k = 0; k < 6; k++){\n\t\t\t\t\t\tif (!X[i + dx2[k]][j + dy2[k]])ans++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 1252, "score_of_the_acc": -0.3375, "final_rank": 10 }, { "submission_id": "aoj_0569_1417515", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <cstring>\n#include <cmath>\n#include <queue>\n#include <map>\n#include <set>\nusing namespace std;\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define FOR(i,s,n) for(int i=s; i<n; i++)\n#define ALL(x) x.begin(), x.end()\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\n\nint f[101][101];\nint w, h;\n\nint dx_even[] = {0, 1, -1, 1, 0, 1};\nint dx_odd[] = {-1, 0, -1, 1, -1, 0};\nint dy[] = {-1, -1, 0, 0, 1, 1};\n\nbool checked[101][101];\nbool isFill[101][101];\n\nbool check(int y, int x) {\n\tchecked[y][x] = true;\n\tif(x==0 || y==0 || x+1==w || y+1==h) return false;\n\trep(i, 6) {\n\t\tint ny = y + dy[i], nx = x + (y%2 ? dx_odd[i] : dx_even[i]);\n\t\tif( !checked[ny][nx] && f[ny][nx] == 0 && !check(ny,nx) ) {\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\nint main() {\n\tcin >> w >> h;\n\trep(y, h) {\n\t\trep(x, w) {\n\t\t\tcin >> f[y][x];\n\t\t}\n\t}\n\trep(y, h) {\n\t\trep(x, w) {\n\t\t\tif( !f[y][x] && !checked[y][x] ) {\n\t\t\t\tmemset(checked, 0, sizeof(checked));\n\t\t\t\tif( check(y,x) ) {\n\t\t\t\t\trep(y, h) {\n\t\t\t\t\t\trep(x, w) {\n\t\t\t\t\t\t\tif( checked[y][x] )\tisFill[y][x] = true;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\trep(y, h) {\n\t\trep(x, w) {\n\t\t\tif( isFill[y][x] ) f[y][x] = 1;\n\t\t}\n\t}\n\tll cnt = 0;\n\trep(y, h) {\n\t\trep(x, w) {\n\t\t\trep(i,6) {\n\t\t\t\tint ny = y + dy[i];\n\t\t\t\tint nx = x + (y%2 ? dx_odd[i] : dx_even[i]);\n\t\t\t\tbool oor = (nx<0 || w<=nx || ny<0 || h<=ny);\n\t\t\t\tif(f[y][x] && (oor || (!oor && f[ny][nx]==0))) {\n\t\t\t\t\tcnt++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << cnt << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1448, "score_of_the_acc": -0.0534, "final_rank": 2 }, { "submission_id": "aoj_0569_1363813", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint main(){\n\tint width, height, map[102][102], diff=1;\n\tcin >> width >> height;\n\tfor (int i = 0; i <= width + 1; i++){\n\t\tmap[height+1][i] = map[0][i] = -1;\n\t}\n\tfor (int i = 0; i <= height + 1; i++){\n\t\tmap[i][width+1] = map[i][0] = -1;\n\t}\n\tfor (int i = 1; i <= height; i++){\n\t\tfor (int j = 1; j <= width; j++){\n\t\t\tcin >> map[i][j];\n\t\t}\n\t}\n\twhile (diff){\n\t\tdiff = 0;\n\t\tfor (int i = 1; i <= height; i++){\n\t\t\tfor (int j = 1; j <= width; j++){\n\t\t\t\tif (!map[i][j]){\n\t\t\t\t\tif (i % 2){\n\t\t\t\t\t\tif (map[i - 1][j] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i - 1][j + 1] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i + 1][j] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i + 1][j + 1] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tif (map[i - 1][j - 1] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i - 1][j] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i + 1][j - 1] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (map[i + 1][j] == -1){\n\t\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\t\tcontinue;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i][j - 1] == -1){\n\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse if (map[i][j + 1] == -1){\n\t\t\t\t\t\tmap[i][j] = -1;\n\t\t\t\t\t\tdiff++;\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 1; i <= height; i++){\n\t\tfor (int j = 1; j <= width; j++){\n\t\t\tif (map[i][j] == 1){\n\t\t\t\tif (i % 2){\n\t\t\t\t\tif (map[i - 1][j] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i - 1][j + 1] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i + 1][j] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i + 1][j + 1] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tif (map[i - 1][j - 1] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i - 1][j] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i + 1][j - 1] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t\tif (map[i + 1][j] == -1){\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (map[i][j - 1] == -1){\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t\tif (map[i][j + 1] == -1){\n\t\t\t\t\tans++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 1200, "score_of_the_acc": -0.0091, "final_rank": 1 }, { "submission_id": "aoj_0569_933241", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<queue>\n#include<map>\nusing namespace std;\nint I,J,x,y,mas[110][110]={{0}};\nint dy[6]={-1,-1, 0, 0, 1, 1};\nint dx_k[6]={ 0, 1,-1, 1, 0, 1};\nint dx_g[6]={-1, 0,-1, 1,-1, 0};\nint d[110][110];\nint wall=0;\nlong long int wall_len=0;\ntypedef pair<int,int>P;\nint bfs();\nint wall_reck(int,int);\nint main(){\n cin >> x >> y;\n for(int i=1;i<y+1;i++){\n for(int j=1;j<x+1;j++){\n cin >> mas[i][j];\n }\n }\n \n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n if(mas[i][j]==0){\n if(i==0 || j==0 || i==y+1 || j==x+1){\n wall_reck(i,j);\n }\n else{\n I=i;\n J=j;\n bfs();\n //帰ってきた値が1(つまり、抜けられた)、または範囲外(必ず1)なら、周り(六方)の壁の数を計算。\n if(wall == 1){\n wall=0;\n wall_reck(i,j);\n }\n }\n }\n }\n }\n cout << wall_len << endl;\n}\n \nint bfs(){\n queue<P>que;\n memset(d,-1,sizeof(d));\n que.push(P(I,J));\n d[I][J] = 0;\n while(!que.empty()){\n P p = que.front();\n que.pop();\n //外につながったか。\n if(p.first==0 || p.second==0 || p.first==y+1 || p.second==x+1){\n wall=1;\n break;\n }\n for(int i=0;i<6;i++){\n int ny,nx;\n ny=p.first+dy[i];\n if(!(p.first&1)){\n nx=p.second+dx_g[i];\n }\n else{\n nx=p.second+dx_k[i];\n }\n if(mas[ny][nx]==0 && d[ny][nx]==-1){\n que.push(P(ny,nx));\n d[ny][nx]=d[p.first][p.second]+1;\n }\n }\n \n }\n}\n \nint wall_reck(int i,int j){\n for(int k=0;k<6;k++){\n if(!(i&1)){\n if(mas[i+dy[k]][j+dx_g[k]]==1){\n wall_len++;\n }\n }\n else{\n if(mas[i+dy[k]][j+dx_k[k]]==1){\n wall_len++;\n }\n }\n \n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 1312, "score_of_the_acc": -0.1448, "final_rank": 3 }, { "submission_id": "aoj_0569_933236", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<queue>\n#include<map>\nusing namespace std;\nint I,J,x,y,mas[110][110]={{0}};\nint dy[6]={-1,-1, 0, 0, 1, 1};\nint dx_k[6]={ 0, 1,-1, 1, 0, 1};\nint dx_g[6]={-1, 0,-1, 1,-1, 0};\nint d[110][110];\nint wall=0;\nlong long int wall_len=0;\ntypedef pair<int,int>P;\nint bfs();\nint wall_reck(int,int);\nint main(){\n cin >> x >> y;\n\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n mas[i][j]=0;\n }\n }\n\n for(int i=1;i<y+1;i++){\n for(int j=1;j<x+1;j++){\n cin >> mas[i][j];\n }\n }\n \n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n if(mas[i][j]==0){\n if(i==0 || j==0 || i==y+1 || j==x+1){\n wall_reck(i,j);\n }\n else{\n I=i;\n J=j;\n bfs();\n //帰ってきた値が1(つまり、抜けられた)、または範囲外(必ず1)なら、周り(六方)の壁の数を計算。\n if(wall == 1){\n wall=0;\n wall_reck(i,j);\n }\n }\n }\n }\n }\n cout << wall_len << endl;\n}\n \nint bfs(){\n queue<P>que;\n memset(d,-1,sizeof(d));\n que.push(P(I,J));\n d[I][J] = 0;\n while(!que.empty()){\n P p = que.front();\n que.pop();\n //外につながったか。\n if(p.first==0 || p.second==0 || p.first==y+1 || p.second==x+1){\n wall=1;\n break;\n }\n for(int i=0;i<6;i++){\n int ny,nx;\n ny=p.first+dy[i];\n if(!(p.first&1)){\n nx=p.second+dx_g[i];\n }\n else{\n nx=p.second+dx_k[i];\n }\n if(mas[ny][nx]==0 && d[ny][nx]==-1){\n que.push(P(ny,nx));\n d[ny][nx]=d[p.first][p.second]+1;\n }\n }\n \n }\n}\n \nint wall_reck(int i,int j){\n for(int k=0;k<6;k++){\n if(!(i&1)){\n if(mas[i+dy[k]][j+dx_g[k]]==1){\n wall_len++;\n }\n }\n else{\n if(mas[i+dy[k]][j+dx_k[k]]==1){\n wall_len++;\n }\n }\n \n }\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 1312, "score_of_the_acc": -0.1448, "final_rank": 3 }, { "submission_id": "aoj_0569_933229", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<queue>\n#include<map>\nusing namespace std;\nint I,J,x,y,mas[110][110]={{0}};\nint dy_k[6]={-1,-1, 0, 0, 1, 1};\nint dx_k[6]={ 0, 1,-1, 1, 0, 1};\nint dy_g[6]={-1,-1, 0, 0, 1, 1};\nint dx_g[6]={-1, 0,-1, 1,-1, 0};\nint d[110][110];\nint wall=0;\nlong long int wall_len=0;\ntypedef pair<int,int>P;\nint bfs();\nint wall_reck(int,int);\nint main(){\n cin >> x >> y;\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n mas[i][j]=0;\n }\n }\n \n for(int i=1;i<y+1;i++){\n for(int j=1;j<x+1;j++){\n cin >> mas[i][j];\n }\n }\n \n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n if(mas[i][j]==0){\n if(i==0 || j==0 || i==y+1 || j==x+1){\n wall_reck(i,j);\n }\n else{\n I=i;\n J=j;\n bfs();\n //帰ってきた値が1(つまり、抜けられた)、または範囲外(必ず1)なら、周り(六方)の壁の数を計算。\n if(wall == 1){\n wall=0;\n wall_reck(i,j);\n }\n }\n \n \n \n }\n }\n }\n cout << wall_len << endl;\n}\n \nint bfs(){\n queue<P>que;\n memset(d,-1,sizeof(d));\n que.push(P(I,J));\n d[I][J] = 0;\n while(!que.empty()){\n P p = que.front();\n que.pop();\n //外につながったか。\n if(p.first==0 || p.second==0 || p.first==y+1 || p.second==x+1){\n wall=1;\n break;\n }\n for(int i=0;i<6;i++){\n int ny,nx;\n if(!(p.first&1)){\n ny=p.first+dy_g[i];\n nx=p.second+dx_g[i];\n }\n else{\n ny=p.first+dy_k[i];\n nx=p.second+dx_k[i];\n }\n if(mas[ny][nx]==0 && d[ny][nx]==-1){\n que.push(P(ny,nx));\n d[ny][nx]=d[p.first][p.second]+1;\n }\n }\n \n }\n}\n \nint wall_reck(int i,int j){\n for(int k=0;k<6;k++){\n if(!(i&1)){\n if(mas[i+dy_g[k]][j+dx_g[k]]==1){\n wall_len++;\n }\n }\n else{\n if(mas[i+dy_k[k]][j+dx_k[k]]==1){\n wall_len++;\n }\n }\n \n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 1316, "score_of_the_acc": -0.1501, "final_rank": 6 }, { "submission_id": "aoj_0569_932056", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<queue>\n#include<map>\nusing namespace std;\nint I,J,x,y,mas[110][110]={{0}};\nint dy_k[6]={-1,-1, 0, 0, 1, 1};\nint dx_k[6]={ 0, 1,-1, 1, 0, 1};\nint dy_g[6]={-1,-1, 0, 0, 1, 1};\nint dx_g[6]={-1, 0,-1, 1,-1, 0};\nint d[110][110];\nint wall=0;\nlong long int wall_len=0;\ntypedef pair<int,int>P;\nint bfs();\nint wall_reck(int,int);\nint main(){\n cin >> x >> y;\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n mas[i][j]=0;\n }\n }\n\n for(int i=1;i<y+1;i++){\n for(int j=1;j<x+1;j++){\n cin >> mas[i][j];\n }\n }\n\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n if(mas[i][j]==0){\n\tif(i==0 || j==0 || i==y+1 || j==x+1){\n\t wall_reck(i,j);\n\t}\n\telse{\n\t I=i;\n\t J=j;\n\t bfs();\n\t //帰ってきた値が1(つまり、抜けられた)、または範囲外(必ず1)なら、周り(六方)の壁の数を計算。\n\t if(wall == 1){\n\t wall=0;\n\t wall_reck(i,j);\n\t }\n\t}\n\t \n \n\n }\n }\n }\n cout << wall_len << endl;\n}\n\nint bfs(){\n queue<P>que;\n memset(d,-1,sizeof(d));\n que.push(P(I,J));\n d[I][J] = 0;\n while(!que.empty()){\n P p = que.front();\n que.pop();\n //外につながったか。\n if(p.first==0 || p.second==0 || p.first==y+1 || p.second==x+1){\n wall=1;\n break;\n }\n for(int i=0;i<6;i++){\n int ny,nx;\n if(!(p.first&1)){\n\tny=p.first+dy_g[i];\n\tnx=p.second+dx_g[i];\n }\n else{\n\tny=p.first+dy_k[i];\n\tnx=p.second+dx_k[i];\n }\n if(mas[ny][nx]==0 && d[ny][nx]==-1){\n\tque.push(P(ny,nx));\n\td[ny][nx]=d[p.first][p.second]+1;\n }\n }\n\n }\n}\n\nint wall_reck(int i,int j){\n for(int k=0;k<6;k++){\n if(!(i&1)){\n if(mas[i+dy_g[k]][j+dx_g[k]]==1){\n\twall_len++;\n }\n }\n else{\n if(mas[i+dy_k[k]][j+dx_k[k]]==1){\n\twall_len++;\n }\n }\n\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 1308, "score_of_the_acc": -0.1486, "final_rank": 5 }, { "submission_id": "aoj_0569_932051", "code_snippet": "#include<iostream>\n#include<cstring>\n#include<queue>\n#include<map>\nusing namespace std;\nint I,J,x,y,mas[110][110]={{0}};\nint dy_k[6]={-1,-1, 0, 0, 1, 1};\nint dx_k[6]={ 0, 1,-1, 1, 0, 1};\nint dy_g[6]={-1,-1, 0, 0, 1, 1};\nint dx_g[6]={-1, 0,-1, 1,-1, 0};\nint d[110][110];\nint wall=0;\nlong long int wall_len=0;\ntypedef pair<int,int>P;\nint bfs();\nint wall_reck(int,int);\nint main(){\n cin >> x >> y;\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n mas[i][j]=0;\n }\n }\n\n for(int i=1;i<y+1;i++){\n for(int j=1;j<x+1;j++){\n cin >> mas[i][j];\n }\n }\n\n for(int i=0;i<y+2;i++){\n for(int j=0;j<x+2;j++){\n if(mas[i][j]==0){\n\tif(i==0 || j==0 || i==y+1 || j==x+1){\n\t wall_reck(i,j);\n\t}\n\telse{\n\t I=i;\n\t J=j;\n\t bfs();\n\t //帰ってきた値が1(つまり、抜けられた)、または範囲外(必ず1)なら、周り(六方)の壁の数を計算。\n\t if(wall == 1){\n\t wall=0;\n\t wall_reck(i,j);\n\t }\n\t}\n\t \n \n\n }\n }\n }\n cout << wall_len << endl;\n}\n\nint bfs(){\n queue<P>que;\n memset(d,-1,sizeof(d));\n que.push(P(I,J));\n d[I][J] = 0;\n while(!que.empty()){\n P p = que.front();\n que.pop();\n //外につながったか。\n if(p.first==0 || p.second==0 || p.first==y+1 || p.second==x+1){\n wall=1;\n break;\n }\n for(int i=0;i<6;i++){\n int ny,nx;\n if(p.first%2==0){\n\tny=p.first+dy_g[i];\n\tnx=p.second+dx_g[i];\n }\n else{\n\tny=p.first+dy_k[i];\n\tnx=p.second+dx_k[i];\n }\n if(mas[ny][nx]==0 && d[ny][nx]==-1){\n\tque.push(P(ny,nx));\n\td[ny][nx]=d[p.first][p.second]+1;\n }\n }\n\n }\n}\n\nint wall_reck(int i,int j){\n for(int k=0;k<6;k++){\n\n if(i%2==0){\n if(mas[i+dy_g[k]][j+dx_g[k]]==1){\n\twall_len++;\n }\n }\n else{\n if(mas[i+dy_k[k]][j+dx_k[k]]==1){\n\twall_len++;\n }\n }\n\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 1316, "score_of_the_acc": -0.1501, "final_rank": 6 }, { "submission_id": "aoj_0569_788939", "code_snippet": "#include<iostream>\nusing namespace std;\nbool F[102][102];\nint A[102][102]={0},W,H;\nint ww[2][6]={{-1,0,-1,1,-1,0},{0,1,-1,1,0,1}},hh[6]={-1,-1,0,0,1,1};\n\nint init(){\n\tfor(int i=0;i<102;i++)for(int j=0;j<102;j++)F[i][j]=false;\n\treturn 1;\n}\n\nint color(int w,int h,int k){\n\tif(w==0||w>W||h==0||h>H)return 1;\n\tif(k==0)k=init();\n\tif(F[w][h])return 0;\n\tint ret=0;\n\tF[w][h]=true;\n\tif(A[w][h]==1)return ret;\n\tfor(int i=0;i<6;i++){\n\t\tret+=color(w+ww[h%2][i],h+hh[i],k);\n\t}\n\treturn ret;\n}\n\nint main(){\n\tint ans=0;\n\tscanf(\"%d%d\",&W,&H);\n\tfor(int i=1;i<=H;i++)for(int j=1;j<=W;j++)scanf(\"%d\",&A[j][i]);\n\tfor(int i=1;i<=W;i++)for(int j=1;j<=H;j++){\n\t\tif(A[i][j]==0){\n\t\t\tint s=color(i,j,0);\n\t\t\tif(s==0)A[i][j]++;\n\t\t}\n\t}\n\tfor(int i=1;i<=W;i++)for(int j=1;j<=H;j++){\n\t\tif(A[i][j]==1){\n\t\t\tfor(int k=0;k<6;k++){\n\t\t\t\tif(A[i+ww[j%2][k]][j+hh[k]]==0){ans++; /*printf(\"(%d,%d),(%d,%d)\\n\",i,j,i+ww[j%2][k],j+hh[k]);*/}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n}", "accuracy": 1, "time_ms": 2210, "memory_kb": 1660, "score_of_the_acc": -1.0907, "final_rank": 19 } ]
aoj_0558_cpp
チーズ (Cheese) 問題 今年も JOI 町のチーズ工場がチーズの生産を始め,ねずみが巣から顔を出した.JOI 町は東西南北に区画整理されていて,各区画は巣,チーズ工場,障害物,空き地のいずれかである.ねずみは巣から出発して全てのチーズ工場を訪れチーズを 1 個ずつ食べる. この町には,N 個のチーズ工場があり,どの工場も1種類のチーズだけを生産している.チーズの硬さは工場によって異なっており,硬さ 1 から N までのチーズを生産するチーズ工場がちょうど 1 つずつある. ねずみの最初の体力は 1 であり,チーズを 1 個食べるごとに体力が 1 増える.ただし,ねずみは自分の体力よりも硬いチーズを食べることはできない. ねずみは,東西南北に隣り合う区画に 1 分で移動することができるが,障害物の区画には入ることができない.チーズ工場をチーズを食べずに通り過ぎることもできる.すべてのチーズを食べ終えるまでにかかる最短時間を求めるプログラムを書け.ただし,ねずみがチーズを食べるのにかかる時間は無視できる. 入力 入力は H+1 行ある.1 行目には 3 つの整数 H,W,N (1 ≤ H ≤ 1000,1 ≤ W ≤ 1000,1 ≤ N ≤ 9) がこの順に空白で区切られて書かれている.2 行目から H+1 行目までの各行には,'S','1', '2', ..., '9','X','.' からなる W 文字の文字列が書かれており,各々が各区画の状態を表している.北から i 番目,西から j 番目の区画を (i,j) と記述することにすると (1 ≤ i ≤ H, 1 ≤ j ≤ W),第 i+1 行目の j 番目の文字は,区画 (i,j) が巣である場合は 'S' となり,障害物である場合は 'X' となり,空き地である場合は '.' となり,硬さ 1, 2, ..., 9 のチーズを生産する工場である場合はそれぞれ '1', '2', ..., '9' となる.入力には巣と硬さ 1, 2, ..., N のチーズを生産する工場がそれぞれ 1 つずつある.他のマスは障害物または空き地であることが保証されている.ねずみは全てのチーズを食べられることが保証されている. 出力 すべてのチーズを食べ終えるまでにかかる最短時間(分)を表す整数を 1 行で出力せよ. 入出力例 入力例 1 3 3 1 S.. ... ..1 出力例 1 4 入力例 2 4 5 2 .X..1 ....X .XX.S .2.X. 出力例 2 12 入力例 3 10 10 9 .X...X.S.X 6..5X..X1X ...XXXX..X X..9X...X. 8.X2X..X3X ...XX.X4.. XX....7X.. X..X..XX.. X...X.XX.. ..X....... 出力例 3 91 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0558_11066715", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint H, W, N;\nchar mp[1005][1005];\nbool isvis[1005][1005];\nint dx[4] = {0,0,1,-1};\nint dy[4] = {1,-1,0,0};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cin>>H>>W>>N;\n int x = -1, y = -1;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin>>mp[i][j];\n if (mp[i][j] == 'S') {\n x = i;\n y = j;\n }\n }\n }\n int ans = 0;\n for (int i = 1; i <= N; i++) {\n queue<tuple<int,int,int>> q;\n memset(isvis,false,sizeof(isvis));\n q.emplace(x,y,ans);\n isvis[x][y] = true;\n while (!q.empty()) {\n int xx = get<0>(q.front());\n int yy = get<1>(q.front());\n int now = get<2>(q.front());\n q.pop();\n if (mp[xx][yy] - '0'== i) {\n ans = now;\n x = xx;\n y = yy;\n break;\n }\n for (int j = 0; j < 4; j++) {\n int nx = xx + dx[j];\n int ny = yy + dy[j];\n if (nx < 0 || ny < 0 || nx >= H || ny >= W || mp[nx][ny] == 'X' || isvis[nx][ny] == true) continue;\n isvis[nx][ny] = true;\n q.emplace(nx,ny,now+1);\n }\n }\n }\n cout<<ans<<\"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5504, "score_of_the_acc": -0.0078, "final_rank": 1 }, { "submission_id": "aoj_0558_11032993", "code_snippet": "#ifndef OMLINE_JUDGE\n#define _GLGBCXX_DEBUG\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Rat_move\n{\n int y;\n int x;\n int num;\n int dist;\n};\n\nvector<pair<int, int>> move_direction{\n {-1, 0}, // up\n {1, 0}, // down\n {0, -1}, // left\n {0, 1}, // right\n};\n\nint H, W, N, answer = 0;\n\nbool is_in_table(int y, int x)\n{\n if (y >= 0 && y < H && x >= 0 && x < W)\n return true;\n\n return false;\n}\n\nint main()\n{\n cin >> H >> W >> N;\n\n vector<vector<string>> cheese_map(N, vector<string>(H));\n\n for (int i = 0; i < H; i++)\n {\n string row;\n cin >> row;\n\n for (int j = 0; j < N; j++)\n cheese_map.at(j).at(i) = row;\n }\n\n queue<Rat_move> Queue;\n\n for (int i = 0; i < H; i++)\n {\n for (int j = 0; j < W; j++)\n {\n if (cheese_map.at(0).at(i).at(j) == 'S')\n {\n cheese_map.at(0).at(i).at(j) = 'X';\n Queue.push(Rat_move{i, j, 0, 0});\n }\n else if (\n cheese_map.at(0).at(i).at(j) >= '1' &&\n cheese_map.at(0).at(i).at(j) <= static_cast<char>(N - 1 + '0'))\n {\n cheese_map.at(\n static_cast<int>(cheese_map.at(0).at(i).at(j) - '0'))\n .at(i)\n .at(j) = 'X';\n Queue.push(\n Rat_move{\n i,\n j,\n static_cast<int>(cheese_map.at(0).at(i).at(j) - '0'),\n 0});\n }\n }\n }\n\n while (!Queue.empty())\n {\n auto pos = Queue.front();\n Queue.pop();\n\n for (int k = 0; k < 4; k++)\n {\n int nex_y = pos.y + move_direction.at(k).first,\n nex_x = pos.x + move_direction.at(k).second;\n\n if (\n is_in_table(nex_y, nex_x) &&\n cheese_map.at(pos.num).at(nex_y).at(nex_x) != 'X')\n {\n if (\n cheese_map.at(pos.num).at(nex_y).at(nex_x) ==\n static_cast<char>(pos.num + 1 + '0'))\n answer += pos.dist + 1;\n else\n Queue.push(Rat_move{nex_y, nex_x, pos.num, pos.dist + 1});\n\n cheese_map.at(pos.num).at(nex_y).at(nex_x) = 'X';\n }\n }\n }\n\n cout << answer << '\\n';\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 12616, "score_of_the_acc": -0.4506, "final_rank": 16 }, { "submission_id": "aoj_0558_10914431", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int N = 1010;\nstruct node{\n\tint x,y,c;\n};\nint n,m,k,sx,sy,ans;\nchar a[N][N];\nbool vis[N][N];\nqueue <node> q;\nint dx[5]={0,1,0,-1};\nint dy[5]={1,0,-1,0};\nint bfs(int x,int y,int f){\n\tvis[x][y]=1;\n\tq.push((node){x,y,0});\n\twhile(!q.empty()){\n\t\tnode t=q.front();\n\t\tq.pop();\n\t\tif(a[t.x][t.y]==f+'0'){\n\t\t\twhile(!q.empty()) q.pop();\n\t\t\tsx=t.x;\n\t\t\tsy=t.y;\n\t\t\treturn t.c;\n\t\t}\n\t\tfor(int i=0;i<4;i++){\n\t\t\tint zx=t.x+dx[i];\n\t\t\tint zy=t.y+dy[i];\n\t\t\tif(zx>=1&&zx<=n&&zy>=1&&zy<=m&&!vis[zx][zy]&&a[zx][zy]!='X'){\n\t\t\t\tvis[zx][zy]=1;\n\t\t\t\tq.push((node){zx,zy,t.c+1});\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\nint main(){\n\tcin>>n>>m>>k;\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tcin>>a[i][j];\n\t\t\tif(a[i][j]=='S'){\n\t\t\t\tsx=i;\n\t\t\t\tsy=j;\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=k;i++){\n\t\tans+=bfs(sx,sy,i);\n\t\tfor(int i=1;i<=n;i++) for(int j=1;j<=m;j++) vis[i][j]=0;\n\t}\n\tcout<<ans<<'\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5116, "score_of_the_acc": -0.15, "final_rank": 6 }, { "submission_id": "aoj_0558_10869782", "code_snippet": "#include<iostream>\n#include<queue>\nusing namespace std;\nconst int maxn=1000,mxw=10;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint a[maxn][maxn],n,m,sx[mxw],sy[mxw]; \nbool check(int x,int y){\n\treturn x>=0&&x<n&&y>=0&&y<m;\n}\nint bfs(int idx){\n\tqueue<int>qx,qy;\n\ta[sx[idx]][sy[idx]]=idx;\n\tqx.push(sx[idx]),qy.push(sy[idx]);\n\tint cnt=1,tc,res=1;\n\twhile(!qx.empty()){\n\t\ttc=0;\n\t\twhile(cnt--){\n\t\t\tint x=qx.front(),y=qy.front();\n\t\t\tqx.pop(),qy.pop();\n\t\t\tfor(int i=0,nx,ny;i<4;i++){\n\t\t\t\tnx=x+dx[i],ny=y+dy[i];\n\t\t\t\tif(nx==sx[idx+1]&&ny==sy[idx+1])return res;\n\t\t\t\tif(check(nx,ny)&&a[nx][ny]<idx){\n\t\t\t\t\tqx.push(nx),qy.push(ny);\n\t\t\t\t\ta[nx][ny]=idx,tc++;\t\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tcnt=tc,res++;\n\t}\n\treturn 0;\n}\nint main(){\n\tint w;\n\tcin>>n>>m>>w;\n\tfor(int i=0;i<n;i++)\n\t\tfor(int j=0;j<m;j++){\n\t\t\tchar ch;\n\t\t\tcin>>ch;\n\t\t\tif(ch=='S')sx[0]=i,sy[0]=j;\n\t\t\tif(isdigit(ch)){\n\t\t\t\tint k=ch-'0';\n\t\t\t\tsx[k]=i,sy[k]=j;\n\t\t\t}\n\t\t\tif(ch=='X')a[i][j]=w+1;\n\t\t\telse a[i][j]=-1;\n\t\t}\n\tint ans=0;\n\tfor(int i=0;i<w;i++){\n\t\tans+=bfs(i);\n\t}\n\tcout<<ans<<endl;\n \treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7236, "score_of_the_acc": -0.1426, "final_rank": 5 }, { "submission_id": "aoj_0558_10866842", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\nint H, W, N;\npair<int, int>S;\nint Y[4] = {0,0,1,-1};\nint X[4] = {1,-1 ,0,0};\nint bfs(int sy, int sx, char target, const vector<vector<char>>& M, int cost) {\n\t\n\tvector<vector<int>>Z(H, vector<int>(W, 0));\n\tdeque<pair<int, int>>K;\n\tK.push_back({ sy,sx });\n\tZ[sy][sx] =1;\n\twhile (K.empty() == false) {\n\t\tpair<int, int>P = K.front();\n\t\tsy = P.first;\n\t\tsx = P.second;\n\t\tK.pop_front();\n\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint ny = sy + X[i];\n\t\t\tint nx = sx + Y[i];\n\t\t\t\n\t\t\tif (ny >= H or ny < 0 or nx >= W or nx < 0)continue;\n\t\t\tif (M[ny][nx] == 'X') {\n\t\t\t\tZ[ny][nx] = -1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tif (M[ny][nx] == target) {\n\t\t\t\tS.first = ny;\n\t\t\t\tS.second = nx;\n\t\t\t\tint u = cost + Z[sy][sx];\n\t\t\t\treturn u;\n\t\t\t}\n\t\t\tif (Z[ny][nx] == 0) {\n\t\t\t\tK.push_back({ ny,nx });\n\t\t\t\tZ[ny][nx] = Z[sy][sx] + 1;\n\t\t\t}\n\n\n\n\n\n\n\t\t}\n\t}\n\treturn -1;\n}\n\n\nconst int MOD = 100000;\nint main() {\n\t\n\tcin >> H >> W >> N;\n\tvector<vector<char>>M(H, vector<char>(W));\n\tint ans = 0;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tcin >> M[i][j];\n\n\t\t\tif (M[i][j] == 'S') {\n\t\t\t\tS.first = i;\n\t\t\t\tS.second = j;\n\t\t\t}\n\t\t}\n\t}\n\n\t\n\tfor (int i = 1; i <= N; i++) {\n\t\tchar target = '0' + i;\n\t\tans=bfs(S.first, S.second, target, M, ans);\n\t}\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7936, "score_of_the_acc": -0.2066, "final_rank": 10 }, { "submission_id": "aoj_0558_10791672", "code_snippet": "#include<iostream>\n#include<queue>\n#include<utility>\n#include<cstring>\n#include<vector>\nusing namespace std;\ntypedef pair<int ,int> p;\nconst int N=1010; \nint tatol;\nint H,W,n;\nchar a[N][N];\nint sx,sy;\nint ox,oy;\nint dx[]={-1,0,1,0},dy[]={0,1,0,-1};\nint dist[N][N];\nvector<p> ch(10);\nint bfs(int x,int y,int ox,int oy){\n\tqueue<p> q;\n\tq.push({x,y});\n\tmemset(dist,-1,sizeof dist);\n\tdist[x][y]=0;\n\twhile(!q.empty()){\n\t\tp t=q.front();\n\t\tq.pop();\n\t\tif(t.first==ox&&t.second==oy) return dist[ox][oy];\n\t\tfor(int i=0;i<4;i++){\n\t\t\tint ax=t.first+dx[i],ay=t.second+dy[i];\n\t\t\tif(ax>=0&&ay>=0&&ax<H&&ay<W){\n\t\t\t\tif(a[ax][ay]!='X'&&dist[ax][ay]==-1){\n\t\t\t\t\tdist[ax][ay]=dist[t.first][t.second]+1;\n\t\t\t\t\tq.push({ax,ay});\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn -1;\n}\nint main(){\n\tcin>>H>>W>>n;\n\tfor(int i=0;i<H;i++){\n\t\tfor(int j=0;j<W;j++){\n\t\t\tcin>>a[i][j];\n\t\t\tif(a[i][j]=='S') sx=i,sy=j;\n\t\t\tif(isdigit(a[i][j])){\n\t\t\t\tint digit=a[i][j]-'0';\n\t\t\t\tch[digit]={i,j};\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tp t=ch[i];\n\t\tox=t.first,oy=t.second;\n\t\ttatol+=bfs(sx,sy,ox,oy);\n\t\tsx=ox,sy=oy;\n\t}\n\tcout<<tatol<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8268, "score_of_the_acc": -0.1633, "final_rank": 8 }, { "submission_id": "aoj_0558_10786945", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <queue>\n#include <cstring>\n\nint targetX[10];\nint targetY[10];\nchar grid[1000][1000];\nbool visited[1000][1000];\nint H, W, N;\n\nstruct Point {\n int x;\n int y;\n int dist;\n};\n\nint dist(int x1, int y1, int x2, int y2) {\n int dist = 0;\n std::queue<Point> q;\n q.push({x1, y1, 0});\n while (!q.empty()) {\n Point p = q.front();\n q.pop();\n if (p.x == x2 && p.y == y2) {\n return p.dist;\n }\n if (visited[p.x][p.y]) {\n continue;\n }\n visited[p.x][p.y] = true;\n int dx[] = {0, 0, -1, 1};\n int dy[] = {-1, 1, 0, 0};\n for (int i = 0; i < 4; i++) {\n if (p.x + dx[i] < 0 || p.x + dx[i] >= H || p.y + dy[i] < 0 || p.y + dy[i] >= W \n || visited[p.x + dx[i]][p.y + dy[i]] || grid[p.x + dx[i]][p.y + dy[i]] == 'X') {\n continue;\n }\n q.push({p.x + dx[i], p.y + dy[i], p.dist + 1});\n }\n }\n return 0;\n}\n\nint main() {\n std::string line;\n std::getline(std::cin, line);\n \n std::istringstream iss(line);\n iss >> H >> W >> N;\n \n for (int i = 0; i < H; i++) {\n std::getline(std::cin, line);\n for (int j = 0; j < W; j++) {\n char c = line[j];\n switch (c) {\n case 'S':\n targetX[0] = i;\n targetY[0] = j;\n grid[i][j] = '.';\n break;\n case 'X':\n grid[i][j] = 'X';\n break;\n case '.':\n grid[i][j] = '.';\n break;\n default:\n if (c >= '1' && c <= '9') {\n int idx = (c - '0');\n targetX[idx] = i;\n targetY[idx] = j;\n grid[i][j] = '.';\n }\n break;\n }\n }\n }\n \n int result = 0;\n for (int i = 0; i < N; i++) {\n std::memset(visited, 0, sizeof(visited));\n result += dist(targetX[i], targetY[i], targetX[i + 1], targetY[i + 1]);\n }\n std::cout << result << std::endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5160, "score_of_the_acc": -0.0509, "final_rank": 2 }, { "submission_id": "aoj_0558_10770083", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<string>\n#include<vector>\n#include<cstring>\n#include<queue>\nusing namespace std;\nconst int INF = 10000;\nchar map[INF][INF];\nint n, m;\nint beginx, beginy,endx,endy;\nint dx[4] = { 0,1,0,-1 };\nint dy[4] = { 1,0,-1,0 };\nint d[INF][INF];\nint mincount;\nint min;\ntypedef pair<int, int>q;\nint bfs(int ax, int ay,int bx,int by)\n{\n\tqueue<q>que;\n\tfor (int i = 0; i < n; i++)\n\t\tfor (int j = 0; j < m; j++)\n\t\t\td[i][j] = INF;\n\tque.push(q(ax, ay));\n\td[ax][ay] = 0;\n\twhile (que.size())\n\t{\n\t\tq s = que.front();\n\t\tque.pop();\n\t\tif (s.first == bx && s.second == by)\n\t\t\treturn d[bx][by];\n\t\tfor (int i = 0; i < 4; i++)\n\t\t{\n\t\t\tint nx = s.first + dx[i];\n\t\t\tint ny = s.second + dy[i];\n\t\t\tif (nx >= 0 && nx < n && ny >= 0 && ny < m && map[nx][ny] != 'X' && d[nx][ny] == INF)\n\t\t\t{\n\t\t\t\tque.push(q(nx, ny));\n\t\t\t\td[nx][ny] = d[s.first][s.second] + 1;\n\t\t\t}\n\n\t\t}\n\n\t}\n\treturn -1;\n}\n\nint main()\n{\n\tint x;\n\tcin >> n >> m >> x;\n\tint min = 0;\n\tint treex[10];\n\tint treey[10];\n\tint count1 = 1;\n\tvector<q>tree(x + 1);\n\tint countsum = 0, sum = 0;\n\tfor (int i = 0; i < n; i++)\n\t\tfor (int j = 0; j < m; j++)\n\t\t{\n\t\t\tcin >> map[i][j];\n\t\t\tif (map[i][j] == 'S')\n\t\t\t{\n\t\t\t\tbeginx = i;\n\t\t\t\tbeginy = j;\n\t\t\t\tmap[i][j] = '.';\n\t\t\t}\n\t\t\tif (map[i][j] <= '9' && map[i][j] >= '1')\n\t\t\t{\n\t\t\t\tint count = map[i][j] - '0';\n\t\t\t\ttree[count] = q(i, j);\n\t\t\t\t\n\t\t\t}\n\t\t}\n\tint tonx, tony;\n\tfor (int i = 1; i <= x; i++)\n\t{\n\t\tint xx = tree[i].first;\n\t\tint yy = tree[i].second;\n\t\n\t\tif (i == 1)\n\t\t{\n\t\t\tcountsum = bfs(beginx, beginy, xx, yy);\n\t\t\ttonx = xx;\n\t\t\ttony = yy;\n\t\t\tsum += countsum;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tcountsum = bfs(tonx, tony, xx, yy);\n\t\t\tsum += countsum;\n\t\t\ttonx = xx;\n\t\t\ttony = yy;\n\t\t}\n\t}\n\tcout << sum << endl;\n\t\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 54908, "score_of_the_acc": -1.15, "final_rank": 18 }, { "submission_id": "aoj_0558_10696186", "code_snippet": "#include <iostream>\n#include <queue>\n\n#define MAXN 10000\n\nusing namespace std;\n\ntypedef pair<int, int> P;\n\nint H, W, N;\nint sx, sy;\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\nint d[MAXN][MAXN];\nchar field[MAXN][MAXN];\n\n\nint bfs(int x, int y, char target) {\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n d[i][j] = MAXN;\n }\n }\n\n d[x][y] = 0;\n int gx, gy;\n queue<P> que; que.push(P(x, y));\n while (que.size()) {\n P p = que.front(); que.pop();\n if (field[p.first][p.second] == target) {\n gx = p.first; gy = p.second;\n break;\n }\n\n for (int i = 0; i < 4; i++) {\n int nx = p.first + dx[i];\n int ny = p.second + dy[i];\n if (0 <= nx && nx < H && 0 <= ny && ny < W && field[nx][ny] != 'X' && d[nx][ny] == MAXN) {\n d[nx][ny] = d[p.first][p.second] + 1;\n P newp = {nx, ny};\n que.push(newp);\n }\n }\n }\n\n sx = gx; sy = gy;\n return d[gx][gy];\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n cin >> H >> W >> N;\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n cin >> field[i][j];\n if (field[i][j] == 'S') {\n sx = i; sy = j;\n }\n }\n }\n\n int step = 0;\n for (int i = 1; i <= N; i++) {\n step += bfs(sx, sy, i + '0');\n }\n\n cout << step << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 53452, "score_of_the_acc": -1.0208, "final_rank": 17 }, { "submission_id": "aoj_0558_10626188", "code_snippet": "#include <iostream>\n#include <queue>\nusing namespace std;\nconst int MAX_H = 1050;\nconst int MAX_W = 1050;\nconst int INF = 1e8;\nchar map[MAX_H][MAX_W];\nint w, h, n;\nint spx, spy;\nint gpx, gpy;\nint step = 0;\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\ntypedef pair<int, int> P;\nint d[MAX_H][MAX_W];\n\nint bfs(int strength)\n{\n queue<P> q;\n P p;\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n d[i][j] = INF;\n }\n }\n\n q.push(P(spx, spy));\n d[spx][spy] = 0;\n\n while (q.size())\n {\n p = q.front();\n q.pop();\n\n if (map[p.first][p.second] - '0' == strength)\n {\n spx = p.first;\n spy = p.second;\n break;\n }\n\n // 四个方向循环\n for (int i = 0; i < 4; ++i)\n {\n int nx = p.first + dx[i];\n int ny = p.second + dy[i];\n\n if ((map[nx][ny] != 'X' || (map[nx][ny] - '0') <= strength) && 0 <= nx && nx < h && 0 <= ny && ny < w && d[nx][ny] == INF)\n {\n q.push(P(nx, ny));\n d[nx][ny] = d[p.first][p.second] + 1;\n }\n }\n }\n return d[spx][spy];\n}\n\nvoid solve()\n{\n step = 0;\n for (int i = 1; i <= n; ++i)\n {\n step += bfs(i);\n }\n}\n\nint main()\n{\n cin >> h >> w >> n;\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n cin >> map[i][j];\n if (map[i][j] == 'S')\n {\n spx = i;\n spy = j;\n }\n }\n }\n\n solve();\n\n cout << step << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8508, "score_of_the_acc": -0.2181, "final_rank": 12 }, { "submission_id": "aoj_0558_10626173", "code_snippet": "#include <iostream>\n#include <queue>\nusing namespace std;\nconst int MAX_H = 1000;\nconst int MAX_W = 1000;\nconst int INF = 1e8;\nchar map[MAX_H][MAX_W];\nint w, h, n;\nint spx, spy;\nint gpx, gpy;\nint step = 0;\nint dx[4] = {1, 0, -1, 0};\nint dy[4] = {0, 1, 0, -1};\ntypedef pair<int, int> P;\nint d[MAX_H][MAX_W];\n\nint bfs(int strength)\n{\n queue<P> q;\n P p;\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n d[i][j] = INF;\n }\n }\n\n q.push(P(spx, spy));\n d[spx][spy] = 0;\n\n while (q.size())\n {\n p = q.front();\n q.pop();\n\n if (map[p.first][p.second] - '0' == strength)\n {\n spx = p.first;\n spy = p.second;\n break;\n }\n\n // 四个方向循环\n for (int i = 0; i < 4; ++i)\n {\n int nx = p.first + dx[i];\n int ny = p.second + dy[i];\n\n if ((map[nx][ny] != 'X' || (map[nx][ny] - '0') <= strength) && 0 <= nx && nx < h && 0 <= ny && ny < w && d[nx][ny] == INF)\n {\n q.push(P(nx, ny));\n d[nx][ny] = d[p.first][p.second] + 1;\n }\n }\n }\n return d[spx][spy];\n}\n\nvoid solve()\n{\n step = 0;\n for (int i = 1; i <= n; ++i)\n {\n step += bfs(i);\n }\n}\n\nint main()\n{\n cin >> h >> w >> n;\n for (int i = 0; i < h; ++i)\n {\n for (int j = 0; j < w; ++j)\n {\n cin >> map[i][j];\n if (map[i][j] == 'S')\n {\n spx = i;\n spy = j;\n }\n }\n }\n\n solve();\n\n cout << step << endl;\n}", "accuracy": 0.8, "time_ms": 50, "memory_kb": 7996, "score_of_the_acc": -0.2078, "final_rank": 20 }, { "submission_id": "aoj_0558_10550510", "code_snippet": "#include<string>\n#include<iostream>\n#include<queue>\n#include<bits/stdc++.h>\nusing namespace std;\nint dir[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};\nstruct board {\n string bd[1024];\n pair<int,int> cpos[20];\n int h, w, ch;\n pair<int,int> st;\n void read() {\n cin >> h >> w >> ch;\n for(int i = 0; i < h; i++) {\n cin >> bd[i];\n }\n for(int i = 0; i < h; i++) {\n for(int j = 0; j < w; j++) {\n if(isdigit(bd[i][j])) {\n cpos[bd[i][j]-'0'] = {i, j};\n } else if(bd[i][j] == 'S') {\n st = {i, j};\n }\n }\n }\n }\n bool in_bd(int x, int y) {\n return x >= 0 && x < h && y >= 0 && y < w;\n }\n bool is_block(int x, int y) {\n return bd[x][y] == 'X';\n }\n int visited[1024][1024];\n int bfs(pair<int,int> from, pair<int,int> to) {\n memset(visited, -1, sizeof(visited));\n queue<pair<int,int>> q;q.push(from);visited[from.first][from.second]=0;\n //while(!)\n while(visited[to.first][to.second] == -1) {\n auto f = q.front(); q.pop();\n for(const auto& d: dir) {\n int nx = f.first+d[0], ny = f.second+d[1];\n if(!in_bd(nx, ny) || is_block(nx, ny)) {\n continue;\n }\n if(visited[nx][ny] == -1) {\n visited[nx][ny] = visited[f.first][f.second]+1;\n q.push({nx, ny});\n }\n }\n }\n return visited[to.first][to.second];\n }\n void solve() {\n read();\n int ans = bfs(st, cpos[1]);\n for(int i = 1; i < ch; i++) {\n ans += bfs(cpos[i], cpos[i+1]);\n }\n cout << ans << endl;\n }\n};\nvoid solve() {\n board bd;\n bd.solve();\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 8448, "score_of_the_acc": -0.0669, "final_rank": 4 }, { "submission_id": "aoj_0558_10549356", "code_snippet": "//从起点按1到n顺序走完所有的奶酪场即可,从i到i+1个需要bfs \n#include<cstdio>\n#include<iostream>\n#include<cstring>\nusing namespace std;\nconst int dx[4]={-1,1,0,0};\nconst int dy[4]={0,0,-1,1};\nstruct node{\n\tint x,y,dep;\n};\nnode q[1001*1001];\nint a[1001][1001];\nint vis[1001][1001];\nint x[10],y[10];\nint h,w,n;\nint bfs(int k){\n\tmemset(vis,0,sizeof(vis));\n\tint head=0,tail=1;\n\tq[0].x=x[k];q[0].y=y[k];q[0].dep=0;\n\tvis[x[k]][y[k]]=1;\n\twhile(head<tail){\n\t\tnode p=q[head++];\n\t\tint x0=p.x,y0=p.y,d=p.dep;\n\t\tif(x0==x[k+1]&&y0==y[k+1])return d;\n\t\tfor(int i=0;i<4;i++){\n\t\t\tint xx=x0+dx[i],yy=y0+dy[i];\n\t\t\tif(xx>=1&&xx<=h&&yy>=1&&yy<=w&&a[xx][yy]==0&&vis[xx][yy]==0){\n\t\t\t\tq[tail++]=(node){xx,yy,d+1};\n\t\t\t\tvis[xx][yy]=1;\n\t\t\t}\n\t\t}\n\t}\nreturn 0;\n}\nint main(){\n\tcin>>h>>w>>n;\n\tfor(int i=1;i<=h;i++)\n\t\tfor(int j=1;j<=w;j++){\n\t\t\tchar ch;\n\t\t\tcin>>ch;\n\t\t\ta[i][j]=0;\n\t\t\tif(ch=='X')a[i][j]=1;\n\t\t\tif(ch=='S')x[0]=i,y[0]=j;\n\t\t\tif(ch>='1'&&ch<='9')x[ch-48]=i,y[ch-48]=j;\n\t\t}\n\tint ans=0;\n\tfor(int i=0;i<n;i++)ans+=bfs(i);\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 17664, "score_of_the_acc": -0.302, "final_rank": 15 }, { "submission_id": "aoj_0558_10367037", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cctype>\n#include <climits>\nusing namespace std;\n\nconst int INF = INT_MAX;\nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\n\nint H, W, N;\nvector<vector<char>> board;\nvector<vector<int>> dist;\nvector<int> x(10), y(10);\n\nint bfs(int sx, int sy, int tx, int ty) {\n dist.assign(H, vector<int>(W, INF));\n dist[sx][sy] = 0;\n\n queue<pair<int, int>> que;\n que.push({sx, sy});\n\n while (!que.empty()) {\n auto [cx, cy] = que.front();\n que.pop();\n\n for (int k = 0; k < 4; ++k) {\n int nx = cx + dx[k], ny = cy + dy[k];\n if (nx < 0 || nx >= H || ny < 0 || ny >= W) continue;\n if (board[nx][ny] == 'X') continue;\n if (dist[nx][ny] > dist[cx][cy] + 1) {\n dist[nx][ny] = dist[cx][cy] + 1;\n que.push({nx, ny});\n }\n }\n }\n\n return dist[tx][ty];\n}\n\nint main() {\n cin >> H >> W >> N;\n board.resize(H, vector<char>(W));\n dist.resize(H, vector<int>(W));\n\n for (int i = 0; i < H; ++i) {\n for (int j = 0; j < W; ++j) {\n cin >> board[i][j];\n if (board[i][j] == 'S') board[i][j] = '0';\n if (isdigit(board[i][j])) {\n int val = board[i][j] - '0';\n x[val] = i;\n y[val] = j;\n }\n }\n }\n\n int ans = 0;\n for (int i = 0; i < N; ++i) {\n ans += bfs(x[i], y[i], x[i+1], y[i+1]);\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8176, "score_of_the_acc": -0.2615, "final_rank": 14 }, { "submission_id": "aoj_0558_10358671", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC optimize(2)\n#define R(n) cin >> n\n#define fr(i, a, b) for (int i = a; i <= b; i++)\n#define rf(i, a, b) for (int i = a; i >= b; i--)\n#define L long long\n#define I int\n#define E return\n#define B break\n#define C continue\n#define W while\nconst I mod = 998244353;\nusing namespace std;\nI n,m,k;\nchar mp[1005][1005];\nI x[1005],y[1005],s,ss;\nI vis[1005][1005];\nqueue<pair<I,pair<I,I> > >q;\nbool ivl(I x,I y){\n\tif(x<1||y<1||x>n||y>m)\n\t\tE 1;\n\tif(mp[x][y]=='X')\n\tE 1;\n\tif(vis[x][y])\n\tE 1;\n\tE 0;\n}\nvoid ini(){\n\tW(!q.empty())q.pop();\n\tmemset(vis,0,sizeof vis);\n}\nint bfs(int xs, int ys, int xe, int ye){\n\tq.push(make_pair(0,make_pair(xs,ys)));\n\tI dx[]={0,1,-1,0,0},dy[]={0,0,0,1,-1};\n\tvis[xs][ys]=1;\n\tW(!q.empty()){\n\t\tI dep=q.front().first,nx=q.front().second.first,ny=q.front().second.second;\n\t\tq.pop();\n\t\tfr(i,1,4){\n\t\t\tI gx=nx+dx[i],gy=ny+dy[i];\n\t\t\tif(gx==xe&&gy==ye)\n\t\t\t\tE dep+1;\n\t\t\tif(!ivl(gx,gy)){\n\t\t\t\tvis[gx][gy]=1;\n\t\t\t\tq.push(make_pair(dep+1,make_pair(gx,gy)));\n\t\t\t}\n\t\t}\n\t}\n\tE -1;\n}\nint main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);cout.tie(0);\n\tR(n)>>m>>k;\n\tfr(i,1,n)\n\t\tfr(j,1,m){\n\t\t\tR(mp[i][j]);\n\t\t\t\tif(mp[i][j]>=48&&mp[i][j]<=57)\n\t\t\t\t\tx[mp[i][j]-48]=i,y[mp[i][j]-48]=j;\n\t\t\t\tif(mp[i][j]=='S')\n\t\t\t\t\ts=i,ss=j;\n\t\t\t}\n\tini();\n\tI ans=bfs(s,ss,x[1],y[1]);\n\tfr(i,1,k-1){ini();\n\tans+=bfs(x[i],y[i],x[i+1],y[i+1]);}\n\tcout<<ans<<\"\\n\";\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8200, "score_of_the_acc": -0.1619, "final_rank": 7 }, { "submission_id": "aoj_0558_10341118", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <unordered_set>\n#include <utility>\n\nint H, W, N;\n\nchar G[1000][1000];\n\nstruct state {\n int i, j, ct;\n};\n\nint dir[4][2] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};\n\nstruct pair_hash {\n inline std::size_t operator()(const std::pair<int, int> &v) const {\n return v.first * 1050 + v.second;\n }\n};\n\nstate bfs(state st, char target) {\n std::queue<state> q;\n\n q.push(st);\n\n std::unordered_set<std::pair<int, int>, pair_hash> seen;\n\n while (!q.empty()) {\n auto st = q.front();\n q.pop();\n\n if (G[st.i][st.j] == target) {\n return st;\n }\n\n if (auto it = seen.find({st.i, st.j}); it != seen.end()) {\n continue;\n }\n\n seen.insert({st.i, st.j});\n\n for (int i = 0; i < 4; i++) {\n int ni = st.i + dir[i][0], nj = st.j + dir[i][1];\n if (ni >= 0 && ni < H && nj >= 0 && nj < W && G[ni][nj] != 'X') {\n q.push({ni, nj, st.ct + 1});\n }\n }\n }\n\n return st;\n}\n\nint main() {\n scanf(\"%d %d %d\", &H, &W, &N);\n state st;\n for (int i = 0; i < H; i++) {\n char s[1000];\n for (int j = 0; j < W; j++) {\n scanf(\" %c\", &G[i][j]);\n if (G[i][j] == 'S') {\n st = {i, j, 0};\n }\n }\n }\n\n for (int i = 1; i <= N; i++) {\n st = bfs(st, '0' + i);\n }\n\n printf(\"%d\\n\", st.ct);\n\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 27676, "score_of_the_acc": -1.4531, "final_rank": 19 }, { "submission_id": "aoj_0558_10206141", "code_snippet": "#include <iostream>\n#include <queue>\n#include <vector>\n#include <climits>\n#include <algorithm>\n\nusing namespace std;\n\n// 東西南北の移動方向\nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\n\nint h, w, n; // 高さ、幅、チーズの数\nvector<string> grid; // 町の地図\n\n// BFSを用いて最短経路を求める\nint bfs(int sx, int sy, int ex, int ey) {\n vector<vector<int>> dist(h, vector<int>(w, INT_MAX));\n queue<pair<int, int>> q;\n dist[sx][sy] = 0;\n q.push({sx, sy});\n \n while (!q.empty()) {\n int x = q.front().first;\n int y = q.front().second;\n q.pop();\n \n for (int i = 0; i < 4; i++) {\n int nx = x + dx[i];\n int ny = y + dy[i];\n \n if (nx >= 0 && nx < h && ny >= 0 && ny < w && grid[nx][ny] != 'X' && dist[nx][ny] == INT_MAX) {\n dist[nx][ny] = dist[x][y] + 1;\n q.push({nx, ny});\n }\n }\n }\n \n return dist[ex][ey];\n}\n\nint main() {\n cin >> h >> w >> n;\n \n grid.resize(h);\n pair<int, int> start; // 巣の位置\n vector<pair<int, int>> cheese_positions(n); // 各チーズ工場の位置\n \n // 地図の入力\n for (int i = 0; i < h; i++) {\n cin >> grid[i];\n for (int j = 0; j < w; j++) {\n if (grid[i][j] == 'S') {\n start = {i, j}; // 巣の位置\n }\n if (grid[i][j] >= '1' && grid[i][j] <= '9') {\n cheese_positions[grid[i][j] - '1'] = {i, j}; // チーズ工場の位置\n }\n }\n }\n \n // ねずみの移動時間の合計\n int total_time = 0;\n pair<int, int> current_pos = start;\n \n // チーズを硬さ順に訪れる\n for (int i = 0; i < n; i++) {\n pair<int, int> next_pos = cheese_positions[i];\n total_time += bfs(current_pos.first, current_pos.second, next_pos.first, next_pos.second);\n current_pos = next_pos;\n }\n \n cout << total_time << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8860, "score_of_the_acc": -0.2252, "final_rank": 13 }, { "submission_id": "aoj_0558_10121195", "code_snippet": "#include<iostream>\n#include<map>\n#include<queue>\n#include<cstring>\nusing namespace std;\nint h,w,n;\nconst int N=1000+5,M=15,INF=0x3f3f3f3f;\nchar g[N][N];\nint dist[N][N];\nint idx[M],idy[M];\ntypedef pair<int,int> P;\nint dx[]={0,1,0,-1},//\n\tdy[]={1,0,-1,0}; \nint bfs(int i)\n{\n\tqueue<P> q;//\n\tq.push(P{idx[i],idy[i]});\n\tmemset(dist,0x3f,sizeof dist);\n\tdist[idx[i]][idy[i]]=0;\n\twhile(!q.empty())\n\t{\n\t\tP cur=q.front(); q.pop();\n\t\tint x=cur.first,y=cur.second;\n\t\tif(x==idx[i+1]&&y==idy[i+1])\n\t\t\treturn dist[x][y];\n\t\tfor(int j=0;j<4;++j)\n\t\t{\n\t\t\tint nx=x+dx[j],ny=y+dy[j];\n\t\t\tif(dist[nx][ny]==INF&&g[nx][ny]!='X'&&nx>=1&&nx<=h&&ny>=1&&ny<=w)\n\t\t\t{\n\t\t\t\tq.push(P{nx,ny});\n//\t\t\t\tcout<<nx<<' '<<ny<<endl;;\n\t\t\t\tdist[nx][ny]=dist[x][y]+1;\n\t\t\t}\n\t\t}\n\t}\n\treturn -1;\n}\nint main()\n{\n\tcin>>h>>w>>n;\n\tfor(int i=1;i<=h;++i)\n\t\tfor(int j=1;j<=w;++j)\n\t\t{\n\t\t\tcin>>g[i][j];\n\t\t\tif(g[i][j]>'0'&&g[i][j]<='9')\n\t\t\t{\n\t\t\t\tint cur=g[i][j]-'0';\n\t\t\t\tidx[cur]=i;\n\t\t\t\tidy[cur]=j;\n\t\t\t}\n\t\t\telse if(g[i][j]=='S')\n\t\t\t{\n\t\t\t\tidx[0]=i;\n\t\t\t\tidy[0]=j;\n\t\t\t}\n\t\t}\n\tint sum=0;\n\tfor(int i=0;i<n;++i)\n\t{\n\t\tsum+=bfs(i);\n\t} \n\tcout<<sum<<endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8272, "score_of_the_acc": -0.1634, "final_rank": 9 }, { "submission_id": "aoj_0558_9904560", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <queue>\nusing namespace std;\n\nconst int INF = 9999999;\nint d[1010][1010], H, W, N, flag[4][2] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};\ntypedef pair<int, int> P;\nP che[11], S;\nchar m[1010][1010];\nvoid solve() {}\nint bfs(P s, P g) {\n fill(d[0], d[0] + 1010 * 1010, INF);\n queue<P> que;\n P p;\n que.push(s);\n d[s.first][s.second] = 0;\n while (que.size()) {\n p = que.front();\n que.pop();\n if (p == g)\n break;\n for (int i = 0; i < 4; ++i) {\n int nx = p.first + flag[i][0], ny = p.second + flag[i][1];\n if (nx >= 0 && nx < H && ny >= 0 && ny < W && m[nx][ny] != 'X' && d[nx][ny] == INF) {\n d[nx][ny] = d[p.first][p.second] + 1;\n que.push(P(nx, ny));\n }\n }\n }\n return d[g.first][g.second];\n}\nint main() {\n //freopen(\"aizu0558.in\", \"r\", stdin);\n int ans = 0;\n scanf(\"%d %d %d\", &H, &W, &N);\n getchar();\n for (int i = 0; i < H; ++i) {\n for (int j = 0; j < W; ++j) {\n m[i][j] = getchar();\n if (m[i][j] >= '1' && m[i][j] <= '9')\n che[m[i][j] - '0'].first = i, che[m[i][j] - '0'].second = j;\n else if (m[i][j] == 'S')\n che[0].first = i, che[0].second = j;\n }\n getchar();\n }\n for(int i = 0 ; i < N; ++i)\n ans += bfs(che[i], che[i+1]);\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7700, "score_of_the_acc": -0.0519, "final_rank": 3 }, { "submission_id": "aoj_0558_9874200", "code_snippet": "#include<iostream>\n#include<queue>\n#include<cstring>\n#define MEM(x, y) memset(x, y, sizeof x)\n#define MAXN 1005\n\nusing namespace std;\ntypedef pair<int, int> PII;\nint dx[4] = { -1, 0, 1, 0};\nint dy[4] = { 0, 1, 0, -1};\n\nchar maze[MAXN][MAXN];\nint step[MAXN][MAXN];\nint sx, sy, gx, gy;\nint h, w, n;\nint ans = 0;\n\nvoid bfs(int sx, int sy){\n\tqueue<PII>que;\n\tque.push(PII(sx, sy));\n\tstep[sx][sy] = 0;\n\twhile(!que.empty()){\n\t\tPII p = que.front(); que.pop();\n\t\tfor(int i = 0; i < 4; i++){\n\t\t\tint nx = p.first + dx[i], ny = p.second + dy[i];\n\t\t\tif(nx > 0 && ny > 0 && nx <= h && ny <= w && maze[nx][ny] != 'X' && step[nx][ny] == -1){\n\t\t\t\tstep[nx][ny] = 1 + step[p.first][p.second];\n\t\t\t\tque.push(PII(nx, ny));\n\t\t\t}\n\t\t}\n\t}\n}\nint main(){\n\tcin>>h>>w>>n;\n\tPII pii[10];\n\tfor(int i = 1; i <= h; i++){\n\t\tfor(int j = 1; j <= w; j++){\n\t\t\tcin>>maze[i][j];\n\t\t\tif(maze[i][j] <= '9' && maze[i][j] >= '1'){\n\t\t\t\tpii[maze[i][j] - '0'] = PII(i, j);\n\t\t\t}\n\t\t\telse if(maze[i][j] == 'S'){\n\t\t\t\tpii[0] = PII(i, j);\n\t\t\t\tmaze[i][j] = '.';\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i = 1; i <= n; i++){\n\t\tMEM(step, -1);\n\t\tsx = pii[i - 1].first, sy = pii[i - 1].second;\n\t\tgx = pii[i].first, gy = pii[i].second;\n\t\t//cout<<gx<<\" \"<<gy<<endl;\n\t\tbfs(sx, sy);\n\t\tans += step[gx][gy];\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8240, "score_of_the_acc": -0.2127, "final_rank": 11 } ]
aoj_0571_cpp
JJOOII (JJOOII) JOI (日本情報オリンピック) の本選に向けてプログラミングの練習をしていたあなたは,今年度のJOI の予選の問題には数値を扱う問題ばかりが出題され,文字列を扱う問題がなかったことに気がついた.そこであなたは,こっそり文字列の問題に強くなってライバルたちに差をつけることにした. JOI の過去問を眺めていると,J, O, I の3 種類の文字からなる文字列に慣れておく必要がありそうなことがわかった.そこで,そのような文字列について考えよう.あなたは「与えられた文字列がJOI という部分文字列をもつかどうかを答えよ」という問題を思いついたものの,これはすぐに解けてしまった.もっとレベルの高い問題を解きたいあなたは,以下のような問題を作った. 文字列 t が文字列 s の 部分文字列 であるとは, t の先頭および末尾に何文字か(0 文字でもよい) を付け足すと s になることである.たとえば,JJOOII はOJJOOIIOJOI の部分文字列である.一方,JOI はJOOI の部分文字列ではない. また,0 以上の整数 k に対し, レベル k のJOI 列 とは, k 個の文字J, k 個の文字O, k 個の文字I をこの順に並べた文字列のことであるとする.たとえば,JJOOII はレベル2 のJOI 列である.与えられた文字列の部分文字列であるJOI 列のうち,レベルが最大のものを求めたい. 課題 J, O, I の3 種類の文字からなる長さ N の文字列 S が与えられたとき,レベル k のJOI 列が S の部分文字列であるような最大の k の値を求めるプログラムを作成せよ. 制限 1 ≤ N ≤ 1000000 (= 10 6 ) S の長さ 入力 標準入力から以下のデータを読み込め. 1 行目にはJ, O, I の3 種類の文字からなる文字列 S が書かれている. 出力 標準出力に,レベル k のJOI 列が S の部分文字列であるような最大の k の値を表す整数を1 行で出力せよ. 採点基準 採点用データのうち,配点の20%分については, N ≤ 100 を満たす. 入出力例 入力例 1 OJJOOIIOJOI 出力例 1 2 OJJOOIIOJOI はレベル2 のJOI 列であるJJOOII を部分文字列として含んでおり,レベル3 以上のJOI列は部分文字列として含まない. 入力例 2 IJJIIJJJ 出力例 2 0 入力例 3 JOIJOIJOIJOIJOI 出力例 3 1 入力例 4 OOJJJJJJJOOOOIIIII 出力例 4 4 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0571_10870264", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\nint mm = -100000;\nconst int MOD = 10000;\nint main() {\n\tstring S;\n\tcin >> S;\n\tvector<pair<char, int>>L;\n\n\tint j = 1;\n\tchar c = S[0];\n\tint p = 0;\n\tfor (int i = 0; i < S.size();) {\n\t\tj = i;\n\t\twhile (j<S.size() and S[i]==S[j]) {\n\t\t\tj++;\n\n\t\t}\n\t\tL.push_back({ S[i],j - i });\n\n\t\ti = j;\n\n\n\t}\n\tint ans = 0;\n\tfor (int i = 0; i + 2 < L.size(); i++) {\n\t\tif (L[i].first == 'J' and L[i + 1].first == 'O' and L[i + 2].first == 'I') {\n\t\t\tif (L[i].second >= L[i + 1].second and L[i + 2].second >= L[i + 1].second) {\n\t\t\t\tans = max(ans, L[i + 1].second);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15088, "score_of_the_acc": -0.5459, "final_rank": 12 }, { "submission_id": "aoj_0571_10870039", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n string S;\n cin >> S;\n int N = S.size();\n\n // Run-Length Encoding\n vector<pair<char,int>> rle;\n for (int i = 0; i < N; ) {\n int j = i;\n while (j < N && S[j] == S[i]) j++;\n rle.push_back({S[i], j - i});\n i = j;\n }\n\n int ans = 0;\n for (int i = 0; i + 2 < (int)rle.size(); i++) {\n if (rle[i].first == 'J' && rle[i+1].first == 'O' && rle[i+2].first == 'I') {\n int a = rle[i].second;\n int b = rle[i+1].second;\n int c = rle[i+2].second;\n if (a >= b && b <= c) {\n ans = max(ans, b);\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 14596, "score_of_the_acc": -0.5223, "final_rank": 11 }, { "submission_id": "aoj_0571_10334982", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n string s;\n cin >> s;\n int flag=0;\n int n=s.size();\n\n int i=0;\n int a=0,b=0,c=0;\n int res=0;\n while(i<n){\n if(flag==0){\n if(s[i]=='J'){\n a++;\n }\n else if(s[i]=='O'){\n flag=1;\n b++;\n }\n else{\n a=0;\n b=0;\n c=0;\n flag=0;\n }\n }\n else if (flag==1){\n if(s[i]=='J'){\n a=1;\n b=0;\n c=0;\n flag=0;\n }\n else if(s[i]=='O'){\n b++;\n }\n else{\n flag=2;\n c++;\n }\n }\n else{\n if(s[i]=='J'){\n if(a>=b and c>=b) res=max(res,b);\n flag=0;\n a=1;\n b=0;\n c=0;\n }\n else if(s[i]=='O'){\n if(a>=b and c>=b) res=max(res,b);\n flag=0;\n a=0;\n b=0;\n c=0;\n }\n else{\n c++;\n }\n }\n i++;\n }\n if(a>=b and c>=b) res=max(res,b);\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5148, "score_of_the_acc": -0.0692, "final_rank": 1 }, { "submission_id": "aoj_0571_9552367", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\n// 使用される文字列と対応するインデックス\nconst static char c[] = {'J', 'O', 'I'};\nint N; // 文字列の長さ\nstring S; // 入力文字列\nint T[3][1000001]; // 各文字の連続した長さを格納する配列\nvector<pair<int, int>> v; // 'J' の連続長さとその開始位置のペアを格納\n\n// 指定された位置 p から始まる部分文字列がレベルkかどうかを確認\nbool isLevelK(int k, int p) {\n // pからk, pから2kの位置が配列Sの範囲内にあるか確認\n if (p + k >= N || p + 2 * k >= N) return false;\n \n // 'J', 'O', 'I' がそれぞれ連続しているか確認\n return T[1][p + k] == k && T[2][p + 2 * k] >= k;\n}\n\nint main() {\n // 入力の受け取り\n cin >> S;\n N = S.size();\n\n // 'J', 'O', 'I' の各文字について、後ろから順に連続長さを計算\n for (int p = 0; p < 3; ++p) {\n for (int i = N - 1; i >= 0; --i) {\n if (S[i] == c[p]) {\n // 最後の文字または連続する文字の長さを計算\n if (i + 1 == N) \n T[p][i] = 1;\n else \n T[p][i] = T[p][i + 1] + 1;\n \n // 'J' の場合、連続長さとその位置を保存\n if (p == 0) \n v.push_back(make_pair(-T[p][i], i));\n } else {\n T[p][i] = 0;\n }\n }\n }\n\n // 'J' の連続長さが大きい順にソート\n sort(v.begin(), v.end());\n\n int ans = 0; // 最終的な解答\n // 各 'J' の連続部分についてレベルkか確認\n for (int i = 0; i < v.size(); ++i) {\n if (isLevelK(-v[i].first, v[i].second)) {\n ans = -v[i].first; // レベルkが見つかればそれが解答\n break;\n }\n }\n\n // 結果を出力\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 24556, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0571_8860994", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <string>\nusing namespace std;\n\nint main() {\n string x;\n cin >> x;\n\n int a = 0, b = 0, c = 0, d = 0, maxi = 0;\n int leng = x.size();\n\n for (a = 0; a < leng; a++) {\n if (x[a] == 'J') {\n b = 0;\n while (x[a] == 'J' && a < leng) {\n b++;\n a++;\n }\n c = 0;\n while (x[a] == 'O' && a < leng) {\n c++;\n a++;\n }\n d = 0;\n while (x[a] == 'I' && a < leng) {\n d++;\n a++;\n }\n a--; // adjust a back to the last valid position\n if (b >= c && c <= d) {\n maxi = max(maxi, c);\n }\n }\n }\n\n cout << maxi << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3976, "score_of_the_acc": -0.3464, "final_rank": 5 }, { "submission_id": "aoj_0571_8860993", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <cstring>\n#include <string>\nusing namespace std;\nchar x[1000005];\nint counts[3] = {0, 0, 0}; // counts for J, O, I respectively\nint a = 0, b = 0, c = 0, d = 0, e, f, i, j, k, maxi = 0, leng = 0;\nint main() {\n // read the string and find its length\n while(scanf(\"%c\", &x[leng]), x[leng] != '\\n'){\n ++leng;\n }\n x[leng] = '\\0';\n while (a < leng) {\n if (x[a] != 'J') {\n a++;\n } else {\n for (int i = 0; i < 3; ++i) {\n while (x[a] == \"JOI\"[i]) {\n ++counts[i];\n ++a;\n }\n }\n if (counts[0] >= counts[1] && counts[1] <= counts[2]) {\n maxi = max(maxi, counts[1]);\n }\n for (int i = 0; i < 3; ++i) {\n counts[i] = 0;\n }\n }\n }\n printf(\"%d\\n\", maxi);\n scanf(\"%d\", &a);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3704, "score_of_the_acc": -0.3333, "final_rank": 4 }, { "submission_id": "aoj_0571_8860989", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <string>\nusing namespace std;\n\nint main() {\n string x;\n cin >> x;\n int a = 0, b = 0, c = 0, d = 0, maxi = 0;\n for (int a = 0; a < x.length();) {\n if (x[a] != 'J') {\n a++;\n } else {\n for (; x[a] == 'J'; a++) {\n b++;\n }\n for (; x[a] == 'O'; a++) {\n c++;\n }\n for (; x[a] == 'I'; a++) {\n d++;\n }\n if (b >= c && c <= d) {\n maxi = max(maxi, c);\n }\n b = c = d = 0;\n }\n }\n cout << maxi << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3976, "score_of_the_acc": -0.3464, "final_rank": 5 }, { "submission_id": "aoj_0571_6957188", "code_snippet": "#include <bits/stdc++.h>\n#include <random>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vvvvvll = vector<vvvvll>;\nusing vvvvvvll = vector<vvvvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\nusing vvvvd = vector<vvvd>;\nusing vvvvvd = vector<vvvvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n#define tN(t) (t==1?XN:YN)\n#define tS(t) (t==1?XS:YS)\n#define tA(t) (t==1?XA:YA)\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\nvector<ll> fact, factinv, inv;\nll mod = 998244353;\nvoid prenCkModp(ll n) {\n fact.resize(n + 5);\n factinv.resize(n + 5);\n inv.resize(n + 5);\n fact.at(0) = fact.at(1) = 1;\n factinv.at(0) = factinv.at(1) = 1;\n inv.at(1) = 1;\n for (ll i = 2; i < n + 5; i++) {\n fact.at(i) = (fact.at(i - 1) * i) % mod;\n inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;\n factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;\n }\n\n}\nll nCk(ll n, ll k) {\n if (n < k) return 0;\n return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;\n}\nll modPow(long long a, long long n, long long p = mod) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n string S;\n cin >> S;\n\n ll N = S.size();\n vll J(N, 0), I(N, 0);\n\n ll j = 0;\n rep(i, N) {\n if (S[i] == 'J') {\n j++;\n }\n else {\n j = 0;\n }\n J[i] = j;\n }\n\n reverse(all(S));\n j = 0;\n rep(i, N) {\n if (S[i] == 'I') {\n j++;\n }\n else {\n j = 0;\n }\n I[i] = j;\n }\n reverse(all(I));\n reverse(all(S));\n ll L = -1;\n\n ll an = 0;\n rep(i, N) {\n if (S[i] == 'O') {\n\n if (L == -1)L = i;\n\n ll d = i - L + 1;\n if (L>0&&i<N-1&&J[L-1] >= d && I[i+1] >= d)chmax(an, d);\n }\n else L = -1;\n\n }\n cout << an << endl;\n\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 19788, "score_of_the_acc": -0.7713, "final_rank": 16 }, { "submission_id": "aoj_0571_5973949", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1e18;\nconst ll MOD = INF;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\ntemplate <typename T>\nstruct CumlativeSum2D {\n vector<vector<T>> data;\n\n explicit CumlativeSum2D(ll H, ll W) : data(H + 1, vector<ll>(W + 1, 0)) {}\n void add(ll x, ll y, T z) {\n x++; y++;\n if (x >= data.size() || y >= data[0].size()) return;\n data[x][y] += z;\n }\n void build() {\n for (int i = 1; i < data.size(); i++) {\n for (int j = 1; j < data[i].size(); j++) {\n data[i][j] += data[i][j-1] + data[i-1][j] - data[i-1][j-1];\n }\n }\n }\n T sum(ll sx, ll sy, ll gx, ll gy) {\n return (data[gx][gy] - data[sx][gy] - data[gx][sy] + data[sx][sy]);\n }\n};\nint main() {\n\tstring S; cin >> S;\n\tvector<pair<char, ll>>A;\n\tA.push_back({S[0], 1});\n\tfor (ll i = 1; i < S.size(); i++) {\n\t\tif (A.back().first == S[i]) A.back().second++;\n\t\telse A.emplace_back(S[i], 1LL);\n\t}\n\tll ans = 0;\n\tfor (ll i = 1; i < A.size() - 1; i++) {\n\t\tif (A[i - 1].first == 'J' && A[i].first == 'O' && A[i + 1].first == 'I') {\n\t\t\tif (A[i - 1].second >= A[i].second && A[i].second <= A[i + 1].second) {\n\t\t\t\tans = max(ans, A[i].second);\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 23220, "score_of_the_acc": -0.9359, "final_rank": 18 }, { "submission_id": "aoj_0571_5851362", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n\nint main(){\n string s;\n cin >> s;\n vector<int> lens;\n vector<char> ch{'X'};\n for(char c: s){\n if(ch.back() == c){\n lens.back()++;\n }else{\n lens.push_back(1);\n ch.push_back(c);\n }\n }\n ch.erase(ch.begin());\n \n int sz = int(lens.size());\n int ans = 0;\n rep(i, sz - 2){\n if(ch[i] == 'J' && ch[i + 1] == 'O' && ch[i + 2] == 'I'){\n int len = lens[i + 1];\n if(lens[i] < len || lens[i + 2] < len){\n continue;\n }\n \n ans = max(ans, len);\n }\n }\n \n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 11352, "score_of_the_acc": -0.3668, "final_rank": 7 }, { "submission_id": "aoj_0571_5815124", "code_snippet": "#include<iostream>\n#include<vector>\n#include<map>\n\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\tcin >> s;\n\tint sLen = s.length();\n\tvector<pair<int, int>> seg;\n\tint index = 0;\n\tint len = 1;\n\tmap<char,int> MAX_LEN;\n\tMAX_LEN['J'] = 0;\n\tMAX_LEN['O'] = 0;\n\tMAX_LEN['I'] = 0;\n\tfor (int i = 1; i < sLen; i++)\n\t{\n\t\tif (s[i] != s[i - 1])\n\t\t{\n\t\t\tseg.push_back(make_pair(index, len));\n\t\t\tMAX_LEN[s[i - 1]] = max(MAX_LEN[s[i - 1]],len);\n\t\t\tindex = i;\n\t\t\tlen = 1;\n\t\t}\n\t\telse\n\t\t\tlen++;\n\t}\n\tseg.push_back(make_pair(index,len));\n\tMAX_LEN[s.back()] = max(MAX_LEN[s.back()], len);\n\tint counter = 1;\n\tint ans = 0;\n\tint MAX = min(MAX_LEN['J'], min(MAX_LEN['O'], MAX_LEN['I']));\n\twhile ( counter <= MAX)\n\t{\n\t\tfor (int i = 0; i < seg.size() - 2; i++)\n\t\t{\n\t\t\tif (s[seg[i].first] == 'J' && seg[i].second >= counter && s[seg[i + 1].first] == 'O' &&\n\t\t\t\tseg[i + 1].second == counter && s[seg[i + 2].first] == 'I' && seg[i + 2].second >= counter)\n\t\t\t{\n\t\t\t\tans = counter;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tcounter++;\n\t}\n\tcout << ans << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 12512, "score_of_the_acc": -1.0891, "final_rank": 19 }, { "submission_id": "aoj_0571_5794883", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<sstream>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nsigned main(){\n\tstring s;\n\tcin>>s;\n\tvector<pair<char,int>>p;\n\tfor(int i=0;i<s.size();i++){\n\t\tif(i==0||p.back().first!=s[i])\n\t\t\tp.emplace_back(s[i],1);\n\t\telse\n\t\t\tp.back().second++;\n\t}\n\tint ans=0;\n\tfor(int i=1;i<p.size()-1;i++)\n\t\tif(p[i-1].first=='J'&&p[i].first=='O'&&p[i+1].first=='I'&&p[i-1].second>=p[i].second&&p[i].second<=p[i+1].second)\n\t\t\tans=max(ans,p[i].second);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 22792, "score_of_the_acc": -0.9154, "final_rank": 17 }, { "submission_id": "aoj_0571_5464008", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, N) for (int i = 0; i < N; i++)\n\nint main()\n{\n string S;\n cin >> S;\n vector<char> vc;\n vector<int> vi;\n char prev = S[0];\n S += \"X\";\n int cnt = 1;\n for (int i = 1; i < S.size(); i++)\n {\n if (S[i] == prev)\n {\n cnt++;\n }\n else\n {\n vc.push_back(prev);\n vi.push_back(cnt);\n cnt = 1;\n prev = S[i];\n }\n }\n/*\n rep(i, vc.size())\n {\n cout << vc[i] << \" \" << vi[i] << endl;\n }\n*/\n\n int maxv = 0;\n for(int i=0;i< (int)vi.size() - 2;i++)\n {\n // rep(j,3) cout << vc[i+j] << \" x \";\n // cout << \" (vc[i] == 'J' && vc[i + 1] == 'O' && vc[i + 2] == 'i') \" << (vc[i] == 'J' && vc[i + 1] == 'O' && vc[i + 2] == 'I') << i << endl;\n if (vc[i] == 'J' && vc[i + 1] == 'O' && vc[i + 2] == 'I' && vi[i+1] <= vi[i] && vi[i+1] <= vi[i+2])\n {\n int level = min(vi[i], min(vi[i + 1], vi[i + 2]));\n maxv = max(maxv, level);\n }\n }\n cout << maxv << endl;\n \n}", "accuracy": 1, "time_ms": 20, "memory_kb": 9648, "score_of_the_acc": -0.6184, "final_rank": 14 }, { "submission_id": "aoj_0571_5308982", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n \n STR(s);\n int n = s.size(); \n vector<int> J(n+1);\n rep(i,n){\n if(s[i] == 'J'){\n J[i] = 1;\n if(i)J[i] += J[i-1];\n }\n }\n vector<int> sufI(n+1);\n drep(i,n){\n if(s[i] == 'I'){\n sufI[i] = 1;\n sufI[i] += sufI[i+1];\n }\n }\n vector<int> O(n+1);\n rep(i,n){\n if(s[i] == 'O'){\n O[i] = 1;\n if(i)O[i] += O[i-1];\n }\n }\n int ret = 0;\n rep(i,n){\n if(s[i] != 'O')continue;\n if(i-O[i] >= 0 && J[i-O[i]] >= O[i] && sufI[i+1] >= O[i]){\n chmax(ret,O[i]);\n }\n }\n cout << ret << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15860, "score_of_the_acc": -0.583, "final_rank": 13 }, { "submission_id": "aoj_0571_5214048", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\n//入力系\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\n//出力系\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\n//デバッグ系\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n string s;\n cin>>s;\n vector<pair<char,int>> num;\n int cnt=0,i=0,ans=0;\n while(i<s.size()){\n cnt=1;\n while(i+cnt<s.size()&&s[i+cnt]==s[i])cnt++;\n num.emplace_back(s[i],cnt);\n i+=cnt;\n }\n rep(i,num.size()-2){\n if(num[i].first=='J'&&num[i+1].first=='O'&&num[i+2].first=='I'){\n if(num[i+1].second>num[i].second||num[i+1].second>num[i+2].second)continue;\n chmax(ans,min({num[i].second,num[i+1].second,num[i+2].second}));\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 12656, "score_of_the_acc": -0.7626, "final_rank": 15 }, { "submission_id": "aoj_0571_5141578", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\n#define bit(n,k) ((n>>k)&1)\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n\n string s; cin >> s;\n vector<pair<char, int>> v;\n rep(i,s.size()){\n int c = 1;\n while(i + 1 < s.size() && s[i] == s[i + 1]){ i++; c++; }\n v.emplace_back(s[i], c);\n }\n int ans = 0;\n rep(i,v.size())if(i > 0 && i < v.size() - 1){\n if(v[i].first == 'O'){\n int x = v[i].second;\n if(v[i-1].second >= x && v[i+1].second >= x){\n if(v[i-1].first == 'J' && v[i+1].first == 'I'){\n ans = max(ans, x);\n }\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 13080, "score_of_the_acc": -0.4496, "final_rank": 9 }, { "submission_id": "aoj_0571_5137451", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return move(res);\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return move(res);\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n STR(s);\n int n = s.size();\n vector<pii> res;\n for(int i = 0;i < n;){\n if(s[i] == 'O'){\n int from = i;\n while(i < n && s[i] == 'O')i++;\n int to = i;\n res.eb(from,to);\n }\n else{\n while(i < n && s[i] != 'O')i++;\n }\n }\n // trace(res);\n sort(all(res),[&](const pii &a,const pii &b){return (a.se - a.fi) > (b.se - b.fi);});\n auto check = [&](int l,int r,char c){\n if(l < 0)return false;\n if(r > n)return false;\n for(int i = l;i < r;i++){\n if(s[i] != c)return false;\n }\n return true;\n };\n for(auto [l,r]:res){\n int len = r-l;\n if(check(l-len,l,'J') && check(r,r+len,'I')){\n cout << len << endl;\n return 0;\n }\n }\n cout << 0 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10416, "score_of_the_acc": -0.3219, "final_rank": 3 }, { "submission_id": "aoj_0571_5137421", "code_snippet": "// clang-format off\n#include <bits/stdc++.h>\n//#pragma GCC optimize(\"Ofast\")\n//#pragma GCC target(\"avx\")\n#define int long long\nusing namespace std;\n#define stoi stoll\n#define fi first\n#define se second\n#define rep(i, n) for(int i=0, i##_len=(n); i<i##_len; i++)\n#define rep2(i, a, b) for (int i = (int)(a), i##_len=(b); i < i##_len; i++)\n#define rep3(i, a, b) for (int i = (int)(a), i##_len=(b); i >= i##_len; i--)\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define _max(x) *max_element(ALL(x))\n#define _min(x) *min_element(ALL(x))\n#define _sum(x) accumulate(ALL(x), 0LL)\n\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-8;\nconst double PI = 3.14159265358979;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = vector<vector<T>>;\ntemplate <class T> using VVV = vector<vector<vector<T>>>;\ntemplate <class T, class S> using P = pair<T, S>;\ntemplate<class T> bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}\ntemplate<class T> bool chmin(T &a, const T &b) {if (b < a) {a = b;return true;}return false;}\nint _ceil(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); }\nint _mod(int a) {return a >= 0 ? a % MOD : a - (MOD * _ceil(a, MOD));}\nint _pow(int a, int b) {int res = 1;for (a %= MOD; b; a = a * a % MOD, b >>= 1)if (b & 1) res = res * a % MOD;return res;}\nstruct mint {long long x;mint(long long x = 0) : x((x % MOD + MOD) % MOD) {}mint operator-() const { return mint(-x); }mint &operator+=(const mint a) {if ((x += a.x) >= MOD) x -= MOD;return *this;}mint &operator-=(const mint a) {if ((x += MOD - a.x) >= MOD) x -= MOD;return *this;}mint &operator*=(const mint a) { (x *= a.x) %= MOD;return *this; }mint operator+(const mint a) const { return mint(*this) += a; }mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; }mint pow(long long t) const {if (!t) return 1;mint a = pow(t >> 1);a *= a;if (t & 1) a *= *this;return a;}mint inv() const { return pow(MOD - 2); }mint &operator/=(const mint a) { return *this *= a.inv(); }mint operator/(const mint a) const { return mint(*this) /= a; }};istream &operator>>(istream &is, mint &a) { return is >> a.x; }ostream &operator<<(ostream &os, const mint &a) { return os << a.x; }\n// clang-format on\n\nint check(string &S, int l, int r) {\n int num = r - l + 1;\n if (l - num < 0) return -1;\n if (S.size() < l + num * 2) return -1;\n if (S.substr(l - num, num * 3) == string(num, 'J') + string(num, 'O') + string(num, 'I')) {\n return num;\n }\n return -1;\n}\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n string S;\n cin >> S;\n S += '#';\n int ans = 0;\n rep(i, S.size()) {\n if (S[i] == 'O') {\n int now = i;\n while (S[now + 1] == 'O') now++;\n chmax(ans, check(S, i, now));\n i = now;\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6788, "score_of_the_acc": -0.1479, "final_rank": 2 }, { "submission_id": "aoj_0571_5133553", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\n\nint main(){\n string s;\n cin >> s;\n vector<pair<char,int>> a;\n for(char c: s){\n if(a.empty() or a.back().first!=c){\n a.push_back({c, 1});\n }else{\n a.back().second++;\n }\n }\n int ans = 0;\n for(int i=0; i<(int)a.size()-2; i++){\n if(a[i].first=='J' and a[i+1].first=='O' and a[i+2].first=='I'){\n if(a[i].second>=a[i+1].second and a[i+2].second>=a[i+1].second){\n ans = max(ans, a[i+1].second);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 14516, "score_of_the_acc": -0.5185, "final_rank": 10 }, { "submission_id": "aoj_0571_5059141", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tstring s; cin >> s;\n\tint n=s.size();\n\tvector<pair<char,int>> v;\n\tfor(int i=0;i<n;){\n\t\tchar c=s[i];\n\t\tint cnt=0;\n\t\twhile(i<n and s[i]==c){\n\t\t\tcnt++; i++;\n\t\t}\n\t\tv.push_back(make_pair(c,cnt));\n\t}\n\tint res=0;\n\tfor(int i=0;i+2<v.size();i++){\n\t\tif(v[i].first=='J' and v[i+1].first=='O' and v[i+2].first=='I'){\n\t\t\tif(v[i+1].second<=v[i].second and v[i+1].second<=v[i+2].second){\n\t\t\t\tres=max(res,v[i+1].second);\n\t\t\t}\n\t\t}\n\t}\n\tcout << res << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 13076, "score_of_the_acc": -0.4495, "final_rank": 8 } ]
aoj_0563_cpp
歩くサンタクロース(Walking Santa) 昨年末,サンタクロースはJOI 村の子供たちにクリスマスプレゼントを渡すのを忘れてしまった.そこで,お詫びの気持ちとして子供たちにチョコレートケーキを届けることにした.届けるべき日は明日に迫っているので,そろそろ移動計画を考えなければならない. JOI 村は,南北方向にまっすぐに伸びる W 本の道路と,東西方向にまっすぐに伸びる H 本の道路により,碁盤の目の形に区分けされている. 南北方向の W 本の道路には,西から順に1, 2, ... , W の番号が付けられており,東西方向の H 本の道路には,南から順に1, 2, ... , H の番号が付けられている. 西から x 番目の南北方向の道路と,南から y 番目の東西方向の道路が交わる交差点を( x , y ) で表す. JOI 村には N 軒の家があり,それらはいずれかの交差点に位置している. サンタクロースは道路に沿ってのみ移動することができる. 隣り合う交差点の間を移動するのにかかる時間を1 とする. JOI 村のすべての家には子供がいるので,サンタクロースはJOI 村のすべての家に1 個ずつチョコレートケーキを届けてまわらなければならない. 大切なチョコレートケーキを持ってトナカイと空を飛びまわるのはやや危険であるので,サンタクロースとトナカイはJOI 村のいずれかの交差点に降り立ち,サンタクロースがそこから歩いてチョコレートケーキを届けることにした. サンタクロースは同時に2 個以上のチョコレートケーキを運んで歩くことはしない.つまり,サンタクロースはチョコレートケーキを1 軒の家に届けるたびに降り立った交差点に戻る. サンタクロースは,JOI 村に降り立ってからすべての家にチョコレートケーキを届けるまでの所要時間が最小になるような移動計画を選ぶことにした.ここで,最後の家にチョコレートケーキを届けてから降り立った交差点に戻るまでの時間は所要時間に含めないことに注意せよ.また,移動にかかる時間以外は考えない. 課題 家の位置の情報が与えられたとき,サンタクロースが降り立つ交差点をうまく選んだ場合の,JOI 村に降り立ってからすべての家にチョコレートケーキを届けるまでの所要時間の最小値と,所要時間を最小にするために降り立つべき交差点の位置を求めるプログラムを作成せよ. 制限 1 ≤ W ≤ 1000000000 = 10 9 南北方向に伸びる道路の本数 1 ≤ H ≤ 1000000000 = 10 9 東西方向に伸びる道路の本数 1 ≤ N ≤ 100000 = 10 5 家の数 1 ≤ X i ≤ W i 番目の家の位置の, 南北方向に伸びる道路の番号 1 ≤ Y i ≤ H i 番目の家の位置の, 東西方向に伸びる道路の番号 入力 標準入力から以下の入力を読み込め. 1 行目には各方向の道路の本数を表す整数 W , H が空白を区切りとして書かれている. 2 行目には家の数を表す整数 N が書かれている. 続く N 行には,家の位置の情報が書かれている. i + 2 行目(1 ≤ i ≤ N ) には整数 X i , Y i が空白を区切りとして書かれており, i 番目の家が交差点( X i , Y i ) に位置していることを表す.これら N 個の交差点はすべて異なる. 出力 標準出力に以下のデータを出力せよ. 1 行目には所要時間の最小値を表す1 つの整数が書かれていなければならない. 2 行目には所要時間を最小にするために降り立つべき交差点が( x , y ) であるとき,2 つの整数 x , y がこの順に空白を区切りとして書かれていなければならない.適切な交差点が複数ある場合は,そのうち最も西にある(つまり, x の値が小さい) 交差点を, それでも1 つに定まらない場合は, さらにそのうちで最も南にある(つまり, y の値が小さい) 交差点を選べ. 注意 この問題では,扱う整数の範囲が32 ビットに収まらない可能性があることに注意せよ. 採点基準 採点用データのうち,配点の40%分については, N ≤ 1000 を満たす. 採点用データのうち,配点の10%分については, W ≤ 50, H ≤ 50, N ≤ 1000 を満たす. 入出力の例 入力例1 5 4 3 1 1 3 4 5 3 出力例1 10 3 3 たとえば,次のような移動計画により所要時間を最小にできる. 交差点(3; 3) に降り立つ. 交差点(3; 4) に位置している家にチョコレートケーキを届ける.ここまでの経過時間は1 である. 交差点(3; 3) に戻る.ここまでの経過時間は2 である. 交差点(5; 3) に位置している家にチョコレートケーキを届ける.ここまでの経過時間は4 である. 交差点(3; 3) に戻る.ここまでの経過時間は6 である. 交差点(1; 1) に位置している家にチョコレートケーキを届ける.ここまでの経過時間は10 である. 入力例2 4 6 8 1 3 3 2 4 4 2 5 2 3 3 3 3 4 2 4 出力例2 21 2 3 家がある交差点に降り立ってもよいことに注意せよ. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0563_10848681", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\nlong long x[200000], y[200000], n, H, W;\nvector<long long>X, Y; vector<pair<long long, long long>>candidate;\nlong long dists(long long px, long long py) {\n\tvector<long long>RR; long long sum = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tlong long TT = abs(px - x[i]) + abs(py - y[i]);\n\t\tRR.push_back(TT); sum += TT;\n\t}\n\tsort(RR.begin(), RR.end());\n\treturn sum * 2 - RR[RR.size() - 1];\n}\nint main() {\n\tcin >> H >> W >> n; for (int i = 0; i < n; i++) { cin >> x[i] >> y[i]; X.push_back(x[i]); Y.push_back(y[i]); }\n\tsort(X.begin(), X.end()); sort(Y.begin(), Y.end());\n\tvector<long long>HH, WW;\n\tif (n % 2 == 1) { HH.push_back(X[X.size() / 2]); WW.push_back(Y[Y.size() / 2]); }\n\tif (n % 2 == 0) {\n\t\tHH.push_back(X[X.size() / 2 - 1]); HH.push_back(X[X.size() / 2]);\n\t\tWW.push_back(Y[Y.size() / 2 - 1]); WW.push_back(Y[Y.size() / 2]);\n\t}\n\tunique(X.begin(), X.end()); unique(Y.begin(), Y.end());\n\tint pos1 = lower_bound(X.begin(), X.end(), HH[0]) - X.begin();\n\tint pos2 = lower_bound(Y.begin(), Y.end(), WW[0]) - Y.begin();\n\tint pos3 = 0, pos4 = 0;\n\tif (n % 2 == 0) {\n\t\tint pos1 = lower_bound(X.begin(), X.end(), HH[1]) - X.begin();\n\t\tint pos2 = lower_bound(Y.begin(), Y.end(), WW[1]) - Y.begin();\n\t}\n\tif (pos1 >= 1) { HH.push_back(X[pos1 - 1]); }\n\tif (pos1 < X.size() - 1 && n % 2 == 1) { HH.push_back(X[pos1 + 1]); }\n\tif (pos3 < X.size() - 1 && n % 2 == 0) { HH.push_back(X[pos3 + 1]); }\n\tif (pos2 >= 1) { WW.push_back(Y[pos2 - 1]); }\n\tif (pos2 < Y.size() - 1 && n % 2 == 1) { WW.push_back(Y[pos2 + 1]); }\n\tif (pos4 < Y.size() - 1 && n % 2 == 0) { WW.push_back(Y[pos4 + 1]); }\n\tfor (int i = 0; i < HH.size(); i++) { for (int j = 0; j < WW.size(); j++)candidate.push_back(make_pair(HH[i], WW[j])); }\n\tlong long minx = 999999999999999999LL, mx = 0, my = 0; sort(candidate.begin(), candidate.end());\n\tfor (int i = 0; i < candidate.size(); i++) {\n\t\tlong long UU = dists(candidate[i].first, candidate[i].second);\n\t\tif (minx > UU) { minx = UU; mx = candidate[i].first; my = candidate[i].second; }\n\t}\n\tcout << minx << endl << mx << ' ' << my << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 8100, "score_of_the_acc": -2, "final_rank": 19 }, { "submission_id": "aoj_0563_9876076", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n\n// 家の座標を格納する構造体\nstruct House {\n long long int x, y;\n};\n\nint main(void){\n // 入力速度を高速化\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n int W, H, N;\n // 入力: 南北方向道路の本数 W, 東西方向道路の本数 H, 家の数 N\n scanf(\"%d %d %d\", &W, &H, &N);\n\n // 家の情報を格納する配列とベクター\n vector<House> houses(N);\n vector<long long int> hx, hy;\n\n // 各家の座標を入力\n for(int i = 0; i < N; i++){\n scanf(\"%lld %lld\", &houses[i].x, &houses[i].y);\n hx.push_back(houses[i].x);\n hy.push_back(houses[i].y);\n }\n\n // x座標とy座標をそれぞれソート\n sort(hx.begin(), hx.end());\n sort(hy.begin(), hy.end());\n\n // 中央値の数を決定(奇数の場合は1、偶数の場合は2)\n int xp = (hx.size() + 1) % 2 + 1; // 奇数なら1、偶数なら2\n int yp = (hy.size() + 1) % 2 + 1;\n\n // ソート後のサイズ\n int xs = hx.size();\n int ys = hy.size();\n\n // 中央値を格納する配列(最大2つ)\n long long int x[2] = {0};\n long long int y[2] = {0};\n\n // x座標の中央値を選定\n for(int i = 0; i < xp; i++) {\n x[i] = hx[xs / 2 + i - xp / 2];\n }\n\n // y座標の中央値を選定\n for(int i = 0; i < yp; i++) {\n y[i] = hy[ys / 2 + i - yp / 2];\n }\n\n // 最小総移動時間とその際の交差点を初期化\n long long int ans = 1LL << 62; // 十分に大きな値\n long long int ax = 0, ay = 0;\n\n // 各候補の交差点についてループ\n for(int i = 0; i < xp; i++){\n long long int nx = x[i]; // 候補のx座標\n for(int j = 0; j < yp; j++){\n long long int ny = y[j]; // 候補のy座標\n long long int nmax = 0; // 最も遠い家への距離\n long long int temp = 0; // 総移動時間\n\n // すべての家に対して距離を計算\n for(long long int l = 0; l < N; l++){\n long long int lx = nx - houses[l].x;\n long long int ly = ny - houses[l].y;\n\n // マンハッタン距離の絶対値を計算\n lx = (lx >= 0) ? lx : -lx;\n ly = (ly >= 0) ? ly : -ly;\n long long int dist = lx + ly;\n\n // 最も遠い家への距離を更新\n if(nmax < dist) nmax = dist;\n\n // 往復の移動時間を計算\n long long int tamp = dist * 2;\n temp += tamp;\n }\n\n // 最後の家への往路の移動時間を引く\n temp -= nmax;\n\n // 最小総移動時間と交差点を更新\n if(temp < ans){\n ans = temp;\n ax = nx;\n ay = ny;\n }\n // 同じ総移動時間の場合は、最も西、さらに最も南の交差点を選ぶ\n else if(temp == ans){\n if(nx < ax || (nx == ax && ny < ay)){\n ax = nx;\n ay = ny;\n }\n }\n }\n }\n\n // 結果を出力\n printf(\"%lld\\n%lld %lld\\n\", ans, ax, ay);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6632, "score_of_the_acc": -0.3573, "final_rank": 16 }, { "submission_id": "aoj_0563_8860298", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <cstdlib>\nusing namespace std;\n\nlong long LXY[2][100000], XY[2][100000];\n\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long w, h, L, HL, temp, oxy[2][2], ox, oy, max = 0, dx, dy;\n\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (int f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0][f1] = LXY[0][f1];\n XY[1][f1] = LXY[1][f1];\n }\n sort(XY[0], XY[0] + L);\n sort(XY[1], XY[1] + L);\n\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (int f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (int f2 = 0; f2 < dx; f2++) {\n for (int f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (int f1 = 0; f1 < L; f1++) {\n temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if(max < temp) max = temp;\n }\n sum = sum*2 - max;\n if(osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5920, "score_of_the_acc": -0.0455, "final_rank": 2 }, { "submission_id": "aoj_0563_8837686", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n\nusing namespace std;\n\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], LXY[2][100000], ox, oy, max = 0, dx, dy;\n vector<long long> XY[2];\n\n cin >> w >> h;\n cin >> L;\n\n for (f1 = 0; f1 < L; f1++) {\n cin >> LXY[0][f1] >> LXY[1][f1];\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n\n // Sort the points based on both x and y coordinates simultaneously\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n\n HL = (L + 1) / 2;\n\n if (L == 1) {\n cout << \"0\" << endl;\n cout << LXY[0][0] << \" \" << LXY[1][0] << endl;\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n\n // Optimize the loop by unrolling and minimizing redundant calculations\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n\n for (f1 = 0; f1 < L; f1++) {\n temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n\n sum *= 2;\n sum -= max;\n\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n\n cout << osum << endl;\n cout << ox << \" \" << oy << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6340, "score_of_the_acc": -0.5931, "final_rank": 17 }, { "submission_id": "aoj_0563_8820257", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n long long w, h, L, HL;\n cin >> w >> h >> L;\n\n vector<long long> LXY[2], XY[2];\n LXY[0].resize(L);\n LXY[1].resize(L);\n\n for (int f1 = 0; f1 < L; f1++) {\n cin >> LXY[0][f1] >> LXY[1][f1];\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n\n HL = (L + 1) / 2;\n if (L == 1) {\n cout << 0 << \"\\n\" << LXY[0][0] << \" \" << LXY[1][0] << \"\\n\";\n } else {\n long long oxy[2][2], ox, oy;\n int dx, dy;\n for (int f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n long long osum = 0, sum;\n for (int f2 = 0; f2 < dx; f2++) {\n for (int f3 = 0; f3 < dy; f3++) {\n sum = 0;\n long long max = 0;\n for (int f1 = 0; f1 < L; f1++) {\n long long temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum = sum * 2 - max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n cout << osum << \"\\n\" << ox << \" \" << oy << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6348, "score_of_the_acc": -0.5966, "final_rank": 18 }, { "submission_id": "aoj_0563_8820254", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n std::ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n \n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], ox, oy, max = 0, dx, dy;\n vector<long long> LXY[2], XY[2];\n\n cin >> w >> h;\n cin >> L;\n LXY[0].resize(L);\n LXY[1].resize(L);\n \n for (f1 = 0; f1 < L; f1++) {\n cin >> LXY[0][f1] >> LXY[1][f1];\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n\n partial_sort(XY[0].begin(), XY[0].begin() + L, XY[0].end());\n partial_sort(XY[1].begin(), XY[1].begin() + L, XY[1].end());\n\n HL = (L + 1) / 2;\n if (L == 1) {\n cout << \"0\\n\";\n cout << LXY[0][0] << \" \" << LXY[1][0] << \"\\n\";\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n cout << osum << \"\\n\";\n cout << ox << \" \" << oy << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6372, "score_of_the_acc": -0.3343, "final_rank": 11 }, { "submission_id": "aoj_0563_8500903", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n\n cin>>N>>N>>N;\n vll A(N),B(N);\n rep(i,N)cin>>A[i]>>B[i];\n vll P=A,Q=B;\n sort(all(A));\n sort(all(B));\n ll AN=1e18,y=-1,x=-1;\n for(ll d=N/2-5;d<=N/2+5;d++){\n for(ll e=N/2-5;e<=N/2+5;e++){\n if(0>d||d>=N||e<0||e>=N)continue;\n ll S=0;\n ll M=0;\n rep(i,N){\n ll cost=abs(A[d]-P[i])+abs(B[e]-Q[i]);\n chmax(M,cost);\n S+=cost*2;\n }\n S-=M;\n if(chmin(AN,S)){\n y=A[d];\n x=B[e];\n }\n }\n }\n cout<<AN<<endl;\n cout<<y<<\" \"<<x<<endl;\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6276, "score_of_the_acc": -0.2923, "final_rank": 10 }, { "submission_id": "aoj_0563_8214988", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n LXY[0] = new long long[L];\n LXY[1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n oxy[0][0] = XY[0][HL - 1];\n oxy[1][0] = XY[0][HL];\n oxy[0][1] = XY[1][HL - 1];\n oxy[1][1] = XY[1][HL];\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n long long max = 0LL;\n sum = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n max = (max < temp) ? temp : max;\n }\n sum = (sum << 1) - max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n delete[] LXY[0];\n delete[] LXY[1];\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6328, "score_of_the_acc": -0.2242, "final_rank": 3 }, { "submission_id": "aoj_0563_8214987", "code_snippet": "#include <cstdio>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n\nint main() {\n long long w, h, L, HL, ox, oy, osum = 0LL, max = 0LL, dx, dy;\n vector<long long> XY[2], LXY[2];\n scanf(\"%lld %lld %lld\", &w, &h, &L);\n LXY[0].resize(L);\n LXY[1].resize(L);\n for (long long f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n long long oxy[2][2] = { { XY[0][HL - 1], XY[1][HL - 1] }, { XY[0][HL], XY[1][HL] } };\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (long long f2 = 0; f2 < dx; f2++) {\n for (long long f3 = 0; f3 < dy; f3++) {\n long long sum = 0LL;\n max = 0LL;\n for (long long f1 = 0; f1 < L; f1++) {\n long long temp = abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n max = (max < temp) ? temp : max;\n }\n sum = (sum << 1) - max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n%lld %lld\\n\", osum, ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5816, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0563_8214982", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6328, "score_of_the_acc": -0.2242, "final_rank": 3 }, { "submission_id": "aoj_0563_8214981", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n stable_sort(XY[0].begin(), XY[0].end());\n stable_sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6596, "score_of_the_acc": -0.3415, "final_rank": 12 }, { "submission_id": "aoj_0563_8115432", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n LXY[0] = new long long[L];\n LXY[1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n delete[] LXY[0];\n delete[] LXY[1];\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6344, "score_of_the_acc": -0.2312, "final_rank": 6 }, { "submission_id": "aoj_0563_8115428", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0, dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++) {\n LXY[f1] = new long long[L];\n }\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n stable_sort(XY[0].begin(), XY[0].end());\n stable_sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n return 0;\n }\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp) {\n max = temp;\n }\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6612, "score_of_the_acc": -0.3485, "final_rank": 13 }, { "submission_id": "aoj_0563_8115427", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], ox, oy, max = 0, dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n long long LXY[2][L]; // allocate array on stack\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n stable_sort(XY[0].begin(), XY[0].end());\n stable_sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6612, "score_of_the_acc": -0.3485, "final_rank": 13 }, { "submission_id": "aoj_0563_8115426", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0LL, dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (int f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (int f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n stable_sort(XY[0].begin(), XY[0].end());\n stable_sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (int f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (int f2 = 0; f2 < dx; f2++) {\n for (int f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (int f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n for (int f1 = 0; f1 < 2; f1++)\n delete[] LXY[f1];\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6612, "score_of_the_acc": -0.3485, "final_rank": 13 }, { "submission_id": "aoj_0563_8115423", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0, dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) + abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6344, "score_of_the_acc": -0.2312, "final_rank": 6 }, { "submission_id": "aoj_0563_8115420", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6344, "score_of_the_acc": -0.2312, "final_rank": 6 }, { "submission_id": "aoj_0563_8112664", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n sort(XY[0].begin(), XY[0].end());\n sort(XY[1].begin(),XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6344, "score_of_the_acc": -0.2312, "final_rank": 6 }, { "submission_id": "aoj_0563_8112662", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <vector>\nusing namespace std;\nint main() {\n long long sum = 0LL, osum = 0LL;\n long long f1, f2, f3, w, h, L, HL, temp, oxy[2][2], *LXY[2], ox, oy, max = 0,\n dx, dy;\n vector<long long> XY[2];\n scanf(\"%lld %lld\", &w, &h);\n scanf(\"%lld\", &L);\n for (f1 = 0; f1 < 2; f1++)\n LXY[f1] = new long long[L];\n for (f1 = 0; f1 < L; f1++) {\n scanf(\"%lld %lld\", &LXY[0][f1], &LXY[1][f1]);\n XY[0].push_back(LXY[0][f1]);\n XY[1].push_back(LXY[1][f1]);\n }\n std::sort(XY[0].begin(), XY[0].end());\n std::sort(XY[1].begin(), XY[1].end());\n HL = (L + 1) / 2;\n if (L == 1) {\n printf(\"0\\n\");\n printf(\"%lld %lld\\n\", LXY[0][0], LXY[1][0]);\n } else {\n for (f1 = 0; f1 < 2; f1++) {\n oxy[0][f1] = XY[f1][HL - 1];\n oxy[1][f1] = XY[f1][HL];\n }\n dx = (oxy[0][0] == oxy[1][0]) ? 1 : 2;\n dy = (oxy[0][1] == oxy[1][1]) ? 1 : 2;\n for (f2 = 0; f2 < dx; f2++) {\n for (f3 = 0; f3 < dy; f3++) {\n sum = 0LL;\n max = 0LL;\n for (f1 = 0; f1 < L; f1++) {\n temp = (long long)abs(LXY[0][f1] - oxy[f2][0]) +\n abs(LXY[1][f1] - oxy[f3][1]);\n sum += temp;\n if (max < temp)\n max = temp;\n }\n sum *= 2;\n sum -= max;\n if (osum == 0 || osum > sum) {\n osum = sum;\n ox = oxy[f2][0];\n oy = oxy[f3][1];\n }\n }\n }\n printf(\"%lld\\n\", osum);\n printf(\"%lld %lld\\n\", ox, oy);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6336, "score_of_the_acc": -0.2277, "final_rank": 5 } ]
aoj_0572_cpp
たのしいカードゲーム(Card Game is Fun) 1 から1000 までのどれかの整数が書かれたカードがたくさんある.アンナとブルーノはそれらのカードを用いて,次のようなゲームをする. アンナは A 枚,ブルーノは B 枚のカードからなる山を持つ.アンナは A 枚のカードの中から任意の何枚か(0 枚でもよい)を捨てて新しい山を作る.ブルーノは B, 枚のカードからなる山の一番上から何枚か(0枚でもよい)と,一番下から何枚か(0 枚でもよい)を捨てて新しい山を作る.ただし,捨てる際に残ったカードの並び替えは行わない.このように作った2 つの山が一致していたら,一方の山に含まれるカードの枚数が2 人の得点になる.ただし,2 つの山が一致するとは,山に含まれるカードの枚数n が同じで,かつ上からi 番目(1 ≤ i ≤ n ) に書かれたカードの整数が全て同じであることである. 例えば,アンナが5 枚のカードの山を持ち,書かれている整数は上から順に1,2,3,4,5 であり,ブルーノが4 枚のカードの山を持ち,書かれている整数が上から順に3,1,4,1 であったとする.このとき,アンナが2,3,5 のカードを捨て,ブルーノが一番上の3 と一番下の1 のカードを捨てると2 人の山が一致する.このとき,残った山の一方に含まれるカードの枚数は2 枚なので,2 人は得点2 を得る. 2 人の得点の最大値を求めたい. 課題 アンナとブルーノが持っているカードの山の情報が与えられたときに,2 人の得点の最大値を求めるプ ログラムを作成せよ. 制限 1 ≤ A ≤ 5000 1 ≤ B ≤ 5000 カードに書かれている整数は1 以上1000 以下である. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 A , B が空白を区切りとして書かれている. 2 行目には, A 個の整数が空白を区切りとして書かれており, i 番目の整数(1 ≤ i ≤ A ) はアンナの持っている山の上から i 番目のカードに書かれている整数を表す. 3 行目には, B 個の整数が空白を区切りとして書かれており, j 番目の整数(1 ≤ j ≤ B ) はブルーノの持っている山の上からj 番目のカードに書かれている整数を表す. 出力 標準出力に,得点の最大値を表す整数を1 行で出力せよ. 採点基準 採点用データのうち,配点の10%分については, A ≤ 10, B ≤ 10 を満たす. 採点用データのうち,配点の50%分については, A ≤ 100, B ≤ 100 を満たす. 入出力例 入力例 1 5 4 1 2 3 4 5 3 1 4 1 出力例 1 2 この入出力例は問題文中の例に対応している. 入力例 2 6 5 4 1 5 2 3 4 4 5 4 2 3 出力例 2 3 この入出力例では,2 人が得点3 を得る方法が2 通り存在する.アンナが1, 2, 3 のカードを捨てブルーノが2, 3 のカードを捨てたとき, 2 人の山は上から順に4, 5, 4 となり, 2 人の得点は3 点となる. また, アンナが1, 5, 4 のカードを捨てブルーノが一番上の4 と5 のカードを捨てたとき, 2 人の山は上から順に4, 2, 3となり, 2 人の得点は3 点となる. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0572_10870377", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\nint mm = -100000;\nconst int MOD = 10000;\nint main() {\n\tint N, W;\n\tcin >> N >> W;\n\tvector<int>A(N);\n\tvector<int>B(W);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n\n\tfor (int i = 0; i < W; i++) {\n\t\tcin >> B[i];\n\t}\n\tint ans = 0;\n\tvector<vector<int>>dp(N + 1, vector<int>(W + 1, 0));\n\t\n\tfor (int i = 1; i < N + 1; i++) {\n\t\tfor (int j = 1; j < W + 1; j++) {\n\t\t\tint X = 0;\n\t\t\tif (A[i - 1] == B[j - 1]) {\n\t\t\t\tdp[i][j] = dp[i - 1][j - 1] + 1;\n\t\t\t}\n\n\t\t\tdp[i][j] = max(dp[i - 1][j], dp[i][j]);\n\n\t\t\tans = max(ans, dp[i][j]);\n\t\t}\n\t}\n\n\t\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 101040, "score_of_the_acc": -1.0548, "final_rank": 15 }, { "submission_id": "aoj_0572_10865818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int A, B;\n cin >> A >> B;\n vector<int> v1(A), v2(B);\n for(int i=0; i<A; ++i) {\n cin >> v1[i];\n }\n for(int i=0; i<B; ++i) {\n cin >> v2[i];\n }\n int res = 0;\n for(int i=0; i<B; ++i) {\n int r = i;\n for(int j=0; j<A && r<B; ++j) {\n if(v2[r] == v1[j]) {\n r++;\n }\n }\n res = max(res, r - i);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3456, "score_of_the_acc": -0.017, "final_rank": 6 }, { "submission_id": "aoj_0572_8931551", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\ndouble binary_search_real(F check, double ok, double ng, ll iter = 100) {\n rep(iter) {\n double x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll A, B;\n cin >> A >> B;\n vi a(A), b(B);\n rep(i, A) cin >> a[i];\n rep(i, B) cin >> b[i];\n ll ans = 0;\n rep(i, B) {\n ll seq = 0;\n ll k = 0;\n rep(j, i, B) {\n while ((k < A) and (a[k] != b[j])) k++;\n if (k < A) {\n k++;\n seq++;\n } else {\n break;\n }\n }\n chmax(ans, seq);\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3540, "score_of_the_acc": -0.0041, "final_rank": 3 }, { "submission_id": "aoj_0572_6959318", "code_snippet": "#include <bits/stdc++.h>\n#include <random>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vvvvvll = vector<vvvvll>;\nusing vvvvvvll = vector<vvvvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\nusing vvvvd = vector<vvvd>;\nusing vvvvvd = vector<vvvvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n#define tN(t) (t==1?XN:YN)\n#define tS(t) (t==1?XS:YS)\n#define tA(t) (t==1?XA:YA)\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\nvector<ll> fact, factinv, inv;\nll mod = 1e9 + 7;\nvoid prenCkModp(ll n) {\n fact.resize(n + 5);\n factinv.resize(n + 5);\n inv.resize(n + 5);\n fact.at(0) = fact.at(1) = 1;\n factinv.at(0) = factinv.at(1) = 1;\n inv.at(1) = 1;\n for (ll i = 2; i < n + 5; i++) {\n fact.at(i) = (fact.at(i - 1) * i) % mod;\n inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;\n factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;\n }\n\n}\nll nCk(ll n, ll k) {\n if (n < k) return 0;\n return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;\n}\nll modPow(long long a, long long n, long long p = mod) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M;\n cin>>N>>M;\n vll A(N),B(M);\n rep(i,N)cin>>A[i];\n rep(i,M)cin>>B[i];\n ll an=0;\n rep(i,M){\n ll j=i;\n ll t=0;\n ll res=0;\n while(t<N){\n if(B[j]==A[t]){\n j++;\n res++;\n }\n t++;\n if(j==M)break;\n }\n chmax(an,res);\n }\n cout<<an<<endl;\n\n\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3520, "score_of_the_acc": -0.0176, "final_rank": 9 }, { "submission_id": "aoj_0572_6659953", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n int a, b;\n cin >> a >> b;\n\n vector<int> anna(a), bruno(b);\n for (int i = 0; i < a; ++i) cin >> anna[i];\n for (int i = 0; i < b; ++i) cin >> bruno[i];\n\n deque<vector<int>> ab;\n ab.push_back(vector<int>(a + 1, 0));\n ab.push_back(vector<int>(a + 1, 0));\n\n int max_len = 0;\n for (int row = 1; row <= b; ++row) {\n for (int col = 1; col <= a; ++col) {\n if (bruno[row - 1] == anna[col - 1]) {\n ab[1].at(col) = ab[0].at(col - 1) + 1;\n } else {\n ab[1].at(col) = ab[1].at(col - 1);\n }\n max_len = max(max_len, ab[1].at(col));\n }\n ab.pop_front();\n ab.push_back(vector<int>(a + 1, 0));\n }\n cout << max_len << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3524, "score_of_the_acc": -0.0862, "final_rank": 13 }, { "submission_id": "aoj_0572_6131125", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n//typedef long long ll;\ntypedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e9;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nint main() {\n ll N, M; cin >> N >> M;\n vector<ll>A(N), B(M);\n input_arr(A, N); input_arr(B, M);\n ll ans = -1;\n for (ll i = 0; i < M; i++) {\n ll sum = 0, pos = i;\n for (ll j = 0; j < N; j++) {\n if (pos >= M) break;\n if (A[j] == B[pos]) {\n sum++;\n pos++;\n }\n }\n ans = max(ans, sum);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3476, "score_of_the_acc": -0.0309, "final_rank": 11 }, { "submission_id": "aoj_0572_5863122", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n int n,m;\n cin>>n>>m;\n vector<int> a(n),b(m);\n for ( int i=0; i<n; i++ ) cin>>a[i];\n for ( int i=0; i<m; i++ ) cin>>b[i];\n int ans=0;\n for ( int i=0; i<m; i++ ) {\n int j=i,k=0;\n while ( j<m ) {\n while ( k<n && b[j]!=a[k] ) k++;\n if ( k==n ) break;\n j++;\n k++;\n }\n ans=max(ans,j-i);\n }\n cout<<ans<<'\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3480, "score_of_the_acc": -0.0035, "final_rank": 1 }, { "submission_id": "aoj_0572_5851364", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n\nint main(){\n int n, m;\n cin >> n >> m;\n int a[n], b[m];\n rep(i, n) cin >> a[i];\n rep(i, m) cin >> b[i];\n \n int ans = 0;\n rep(c, m){\n int at = c, cnt = 0;\n rep(i, n){\n if(at < m && a[i] == b[at]){\n at++;\n cnt++;\n }\n }\n \n ans = max(ans, cnt);\n }\n \n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3476, "score_of_the_acc": -0.0309, "final_rank": 11 }, { "submission_id": "aoj_0572_5817996", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\nint dp[5001][5001];\n\nint main()\n{\n\tint A, B;\n\tcin >> A >> B;\n\tint* a = new int[A];\n\tint* b = new int[B];\n\tfor (int i = 0; i < A; i++)\n\t\tcin >> a[i];\n\tfor (int i = 0; i < B; i++)\n\t\tcin >> b[i];\n\tdp[0][0] = 0;\n\tint ans = 0;\n\tfor (int i = 0; i < A; i++)\n\t{\n\t\tfor (int j = 0; j < B; j++)\n\t\t{\n\t\t\tif (a[i] == b[j])\n\t\t\t{\n\t\t\t\tfor (int k = 0; k <= i; k++)\n\t\t\t\t\tdp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[k][j] + 1);\n\t\t\t\tans = max(dp[i + 1][j + 1], ans);\n\t\t\t}\n\t\t\telse\n\t\t\t\tdp[i + 1][j + 1] = 0;\n\t\t}\n\t}\n\tcout << ans << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 100824, "score_of_the_acc": -1.9978, "final_rank": 17 }, { "submission_id": "aoj_0572_5797605", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<sstream>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nshort dp[5001][5001];\nsigned main(){\n\tint n,m,a[5000],b[5000];\n\tcin>>n>>m;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i];\n\tfor(int i=0;i<m;i++)\n\t\tcin>>b[i];\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<m;j++){\n\t\t\tif(a[i]==b[j])\n\t\t\t\tdp[i+1][j+1]=dp[i][j]+1;\n\t\t\telse\n\t\t\t\tdp[i+1][j+1]=dp[i][j+1];\n\t\t}\n\t}\n\tshort ans=0;\n\tfor(int j=0;j<=m;j++)\n\t\tans=max(ans,dp[n][j]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 52360, "score_of_the_acc": -0.5028, "final_rank": 14 }, { "submission_id": "aoj_0572_5530674", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<int> a(n), b(m);\n rep(i, n) cin >> a[i];\n rep(i, m) cin >> b[i];\n int ans = 0;\n rep(i, m) {\n int k = 0;\n rep(j, n) {\n if (i + k < n && b[i + k] == a[j]) k++;\n }\n ans = max(ans, k);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3484, "score_of_the_acc": -0.0173, "final_rank": 7 }, { "submission_id": "aoj_0572_5474222", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, N) for (int i = 0; i < N; i++)\n\nint main()\n{\n int A, B;\n cin >> A >> B;\n int AA[A], BB[B];\n rep(i, A) cin >> AA[i];\n rep(i, B) cin >> BB[i];\n int maxv = 0;\n int i = 0, k = 0;\n rep(j, B)\n {\n i = 0;\n k = 0;\n while (1)\n {\n if (AA[i] == BB[j + k])\n {\n k++;\n if (j + k >= B)\n {\n maxv = max(maxv, k);\n break;\n }\n }\n i++;\n if (i >= A)\n {\n maxv = max(maxv, k);\n break;\n }\n }\n }\n cout << maxv << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3136, "score_of_the_acc": -0.0274, "final_rank": 10 }, { "submission_id": "aoj_0572_5470389", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\nusing ll=long long;\n#define overload4(_1, _2, _3, _4, name, ...) name\n#define rep1(n) for(ll i = 0; i < (n); ++i)\n#define rep2(i, n) for(ll i = 0; i < (n); ++i)\n#define rep3(i, a, b) for(ll i = (a); i < (b); ++i)\n#define rep4(i, a, b, c) for(ll i = (a); i < (b); i += (c))\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep1(n) for(ll i=n;i--;)\n#define rrep2(i,n) for(ll i=n;i--;)\n#define rrep3(i,a,b) for(ll i=b;i-->(a);)\n#define rrep4(i,a,b,c) for(ll i=(a)+((b)-(a)-1)/(c)*(c);i>=(a);i-=c)\n#define rrep(...) overload4(__VA_ARGS__,rrep4,rrep3,rrep2,rrep1)(__VA_ARGS__)\n#define all(i) begin(i), end(i)\n#define rall(i) (i).rbegin(), (i).rend()\n#define Sort(a) sort(all(a))\n#define Rev(a) reverse(all(a))\n#define elif else if\ntemplate<class T> bool chmin(T &a, const T &b){ if(a > b){ a = b; return 1; } else return 0; }\ntemplate<class T> bool chmax(T &a, const T &b){ if(a < b){ a = b; return 1; } else return 0; }\ntemplate<class T> ll sum(const T& a){ return accumulate(all(a), 0LL); }\ntemplate<class T> auto min(const T& a){ return *min_element(all(a)); }\ntemplate<class T> auto max(const T& a){ return *max_element(all(a)); }\nconst int INF =0x3fffffff;\nconst ll INFll =0x1fffffffffffffff;// 4times ok\nconst int MOD= int(1e9)+7;\nconst int MODD=998244353;\nusing P= pair<int,int>;\nusing Pl= pair<ll,ll>;\nusing ld=long double;\nusing VVl=vector<vector<ll>>;\nusing VVd=vector<vector<ld>>;\nusing Vd=vector<ld>;\nusing tuplis = array<ll, 3>;\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\n#define vv(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\ntemplate<class T> using pq = priority_queue<T, vector<T>, greater<T>>;\nconst ll four[] = {0, 1, 0, -1, 0};\nconst ll eight[] = {0, 1, 1, 0, -1, -1, 1, -1, 0};\nconst ld EPS = 1e-9;\nconst ld PI = 3.1415926535897932;\nll gcd(ll a, ll b){ while(b){ ll c = b; b = a % b; a = c; } return a; }\nll lcm(ll a, ll b){ if(!a || !b) return 0; return a * b / gcd(a, b); }\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll isqr(ll x){ll r=sqrt(x)-1;while((r+1)*(r+1)<=x)r++;return r;}\nvector<ll> divisor(ll x){vector<ll> ans; for(ll i = 1; i * i <= x; i++) if(x % i == 0) ans.push_back(i); rrep(ans.size() - (ans.back() * ans.back() == x)) ans.push_back(x / ans[i]); return ans; }\nint scan(){ return getchar(); }\nvoid scan(int& a){ scanf(\"%d\", &a); }\nvoid scan(unsigned& a){ scanf(\"%u\", &a); }\nvoid scan(long& a){ scanf(\"%ld\", &a); }\nvoid scan(long long& a){ scanf(\"%lld\", &a); }\nvoid scan(unsigned long long& a){ scanf(\"%llu\", &a); }\nvoid scan(char& a){ do{ a = getchar(); }while(a == ' ' || a == '\\n'); }\nvoid scan(float& a){ scanf(\"%f\", &a); }\nvoid scan(double& a){ scanf(\"%lf\", &a); }\nvoid scan(long double& a){ scanf(\"%Lf\", &a); }\nvoid scan(vector<bool>& a){ for(unsigned i = 0; i < a.size(); i++){ int b; scan(b); a[i] = b; } }\nvoid scan(char a[]){ scanf(\"%s\", a); }\nvoid scan(string& a){ cin >> a; }\ntemplate<class T> void scan(vector<T>&);\ntemplate<class T, size_t size> void scan(array<T, size>&);\ntemplate<class T, class L> void scan(pair<T, L>&);\ntemplate<class T, size_t size> void scan(T(&)[size]);\ntemplate<class T> void scan(vector<T>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T> void scan(deque<T>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i); }\ntemplate<class T, class L> void scan(pair<T, L>& p){ scan(p.first); scan(p.second); }\ntemplate<class T, size_t size> void scan(T (&a)[size]){ for(auto&& i : a) scan(i); }\ntemplate<class T> void scan(T& a){ cin >> a; }\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){ scan(head); in(tail...); }\nvoid print(){ putchar(' '); }\nvoid print(bool a){ printf(\"%d\", a); }\nvoid print(int a){ printf(\"%d\", a); }\nvoid print(unsigned a){ printf(\"%u\", a); }\nvoid print(long a){ printf(\"%ld\", a); }\nvoid print(long long a){ printf(\"%lld\", a); }\nvoid print(unsigned long long a){ printf(\"%llu\", a); }\nvoid print(char a){ printf(\"%c\", a); }\nvoid print(char a[]){ printf(\"%s\", a); }\nvoid print(const char a[]){ printf(\"%s\", a); }\nvoid print(float a){ printf(\"%.15f\", a); }\nvoid print(double a){ printf(\"%.15f\", a); }\nvoid print(long double a){ printf(\"%.15Lf\", a); }\nvoid print(const string& a){ for(auto&& i : a) print(i); }\ntemplate<class T> void print(const complex<T>& a){ if(a.real() >= 0) print('+'); print(a.real()); if(a.imag() >= 0) print('+'); print(a.imag()); print('i'); }\ntemplate<class T> void print(const vector<T>&);\ntemplate<class T, size_t size> void print(const array<T, size>&);\ntemplate<class T, class L> void print(const pair<T, L>& p);\ntemplate<class T, size_t size> void print(const T (&)[size]);\ntemplate<class T> void print(const vector<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const deque<T>& a){ if(a.empty()) return; print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, size_t size> void print(const array<T, size>& a){ print(a[0]); for(auto i = a.begin(); ++i != a.end(); ){ putchar(' '); print(*i); } }\ntemplate<class T, class L> void print(const pair<T, L>& p){ print(p.first); putchar(' '); print(p.second); }\ntemplate<class T, size_t size> void print(const T (&a)[size]){ print(a[0]); for(auto i = a; ++i != end(a); ){ putchar(' '); print(*i); } }\ntemplate<class T> void print(const T& a){ cout << a; }\nint out(){ putchar('\\n'); return 0; }\ntemplate<class T> int out(const T& t){ print(t); putchar('\\n'); return 0; }\ntemplate<class Head, class... Tail> int out(const Head& head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }\n#define INT(...) int __VA_ARGS__; in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__; in(__VA_ARGS__)\n#define ULL(...) ull __VA_ARGS__; in(__VA_ARGS__)\n#define STR(...) string __VA_ARGS__; in(__VA_ARGS__)\n#define CHR(...) char __VA_ARGS__; in(__VA_ARGS__)\n#define DBL(...) double __VA_ARGS__; in(__VA_ARGS__)\n#define LD(...) ld __VA_ARGS__; in(__VA_ARGS__)\n#define VEC(type,name,size) vector<type> name(size); in(name)\n#define VV(type, name, h, w) vector<vector<type>> name(h, vector<type>(w)); in(name)\n\nint main() {\n LL(n,m);\n VEC(ll,a,n);\n VEC(ll,b,m);\n ll ans=0;\n auto f=[&](ll s){\n ll ret=0;\n rep(n){\n if(s==m)return ret;\n if(b[s]==a[i]){\n ret++;\n s++;\n }\n }\n return ret;\n };\n rep(m){\n chmax(ans,f(i));\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3652, "score_of_the_acc": -0.0053, "final_rank": 4 }, { "submission_id": "aoj_0572_5319051", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\n//入力系\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\n//出力系\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\n//デバッグ系\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n vector<int> s(n),t(m);\n in(s,t);\n int ans=0,cnt=0;\n for(int j=0;j<m;j++){\n cnt=0;\n for(int i=0;i<n;i++){\n if(j+cnt<m&&s[i]==t[j+cnt]){\n cnt++;\n chmax(ans,cnt);\n }\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3252, "score_of_the_acc": -0.0149, "final_rank": 5 }, { "submission_id": "aoj_0572_5309974", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n INT(n,m);\n VEC(int,a,n);\n VEC(int,b,m);\n ll ret = 0;\n rep(from,m){\n for(int i = 0,j = from;j < m;){\n while(i < n && a[i] != b[j])i++;\n if(i == n)break;\n i++;j++;\n chmax(ret,j-from);\n }\n }\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3508, "score_of_the_acc": -0.0175, "final_rank": 8 }, { "submission_id": "aoj_0572_5309879", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n // dp[i][j]:Aのiまで(iつかう)、Bのjまで(j使う)時の最大値\n // if(a[i] == b[j])dp[i][j] = max(dp[x][j-1])+1;\n // else dp[i][j] = 0;\n INT(n,m);\n VEC(int,a,n);\n VEC(int,b,m);\n vv(int,dp,n+1,m+1);\n vector<int> maxi(m+1);\n rep(i,n){\n vector<int> tmp(m+1);\n rep(j,m){\n if(a[i] == b[j]){\n dp[i][j] = 1;\n if(j)dp[i][j] += maxi[j-1];\n }\n // trace(i,j,dp[i][j]);\n chmax(tmp[j],dp[i][j]);\n }\n rep(j,m)chmax(maxi[j],tmp[j]);\n }\n cout << *max_element(all(maxi)) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 101020, "score_of_the_acc": -1.082, "final_rank": 16 }, { "submission_id": "aoj_0572_5258682", "code_snippet": "#include <bits/stdc++.h>\n\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\nusing usize = std::size_t;\n\nconst i32 INF = 1001001001;\nconst i64 LINF = 1001001001001001;\nconst u32 MOD1 = 1000000007;\nconst u32 MOD2 = 998244353;\n\nusing namespace std;\n\ni32 wx[5050][1010],wy[5050][1010];\ni32 dp[5050][5050];\n\nint main(){\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n \n i32 a,b;\n cin>>a>>b;\n i32 x[a],y[b];\n for(i32 i=0;i<a;i++)cin>>x[i];\n for(i32 i=0;i<b;i++)cin>>y[i];\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<1010;j++)wx[i][j]=wy[i][j]=INF;\n for(i32 i=a-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wx[i][j]=wx[i+1][j];\n wx[i][x[i]]=i;\n }\n for(i32 i=b-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wy[i][j]=wy[i+1][j];\n wy[i][y[i]]=i;\n }\n for(i32 i=0;i<a;i++){\n for(i32 j=0;j<b;j++){\n for(i32 k=0;k<1010;k++){\n if(wx[i+1][k]==INF||wy[j+1][k]==INF)continue;\n if(dp[i][j]>0&&wy[j+1][k]!=j+1)continue;\n dp[wx[i+1][k]][wy[j+1][k]]=max(dp[wx[i+1][k]][wy[j+1][k]],dp[i][j]+1);\n }\n }\n }\n i32 ans=0;\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<5050;j++)ans=max(ans,dp[i][j]);\n cout<<ans<<endl;\n}", "accuracy": 0.03333333333333333, "time_ms": 30, "memory_kb": 42964, "score_of_the_acc": -0.4342, "final_rank": 20 }, { "submission_id": "aoj_0572_5258680", "code_snippet": "#include <bits/stdc++.h>\n\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\nusing usize = std::size_t;\n\nconst i32 INF = 1001001001;\nconst i64 LINF = 1001001001001001;\nconst u32 MOD1 = 1000000007;\nconst u32 MOD2 = 998244353;\n\nusing namespace std;\n\ni32 wx[5050][1010],wy[5050][1010];\ni32 dp[5050][5050];\n\nint main(){\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n \n i32 a,b;\n cin>>a>>b;\n i32 x[a],y[b];\n for(i32 i=0;i<a;i++)cin>>x[i];\n for(i32 i=0;i<b;i++)cin>>y[i];\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<1010;j++)wx[i][j]=wy[i][j]=INF;\n for(i32 i=a-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wx[i][j]=wx[i+1][j];\n wx[i][x[i]]=i;\n }\n for(i32 i=b-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wy[i][j]=wy[i+1][j];\n wy[i][y[i]]=i;\n }\n for(i32 i=0;i<a;i++){\n for(i32 j=0;j<b;j++){\n for(i32 k=0;k<1010;k++){\n if(wx[i][k]==INF||wy[j][k]==INF)continue;\n if(dp[i][j]>0&&(wy[j][k]!=j+1&&y[j+1]!=k))continue;\n dp[wx[i][k]][wy[j][k]]=max(dp[wx[i][k]][wy[j][k]],dp[i][j]+1);\n }\n }\n }\n i32 ans=0;\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<5050;j++)ans=max(ans,dp[i][j]);\n cout<<ans<<endl;\n}", "accuracy": 0.13333333333333333, "time_ms": 40, "memory_kb": 43440, "score_of_the_acc": -0.4528, "final_rank": 19 }, { "submission_id": "aoj_0572_5258665", "code_snippet": "#include <bits/stdc++.h>\n\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\nusing usize = std::size_t;\n\nconst i32 INF = 1001001001;\nconst i64 LINF = 1001001001001001;\nconst u32 MOD1 = 1000000007;\nconst u32 MOD2 = 998244353;\n\nusing namespace std;\n\ni32 wx[5050][1010],wy[5050][1010];\ni32 dp[5050][5050];\n\nint main(){\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n \n i32 a,b;\n cin>>a>>b;\n i32 x[a],y[b];\n for(i32 i=0;i<a;i++)cin>>x[i];\n for(i32 i=0;i<b;i++)cin>>y[i];\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<1010;j++)wx[i][j]=wy[i][j]=INF;\n for(i32 i=a-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wx[i][j]=wx[i+1][j];\n wx[i][x[i]]=i;\n }\n for(i32 i=b-1;i>=0;i--){\n for(i32 j=0;j<1010;j++)wy[i][j]=wy[i+1][j];\n wy[i][y[i]]=i;\n }\n for(i32 i=0;i<a;i++){\n for(i32 j=0;j<b;j++){\n for(i32 k=0;k<1010;k++){\n if(wx[i][k]==INF||wy[j][k]==INF)continue;\n if(dp[i][j]>0&&wy[j][k]!=j+1)continue;\n dp[wx[i][k]][wy[j][k]]=max(dp[wx[i][k]][wy[j][k]],dp[i][j]+1);\n }\n }\n }\n i32 ans=0;\n for(i32 i=0;i<5050;i++)for(i32 j=0;j<5050;j++)ans=max(ans,dp[i][j]);\n cout<<ans<<endl;\n}", "accuracy": 0.13333333333333333, "time_ms": 30, "memory_kb": 43392, "score_of_the_acc": -0.4386, "final_rank": 18 }, { "submission_id": "aoj_0572_5133593", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n,m;\n cin >> n >> m;\n vector<int> a(n),b(m);\n for(int i=0; i<n; i++){\n cin >> a[i];\n }\n for(int i=0; i<m; i++){\n cin >> b[i];\n }\n int ans = 0;\n for(int i=0; i<m; i++){\n int p = i;\n for(int j=0; j<n; j++){\n if(a[j] == b[p]){\n p++;\n if(p == m) break;\n }\n }\n ans = max(ans, p-i);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3484, "score_of_the_acc": -0.0036, "final_rank": 2 } ]
aoj_0564_cpp
微生物実験(Bug Party) あなたはJust Odd Inventions 社を知っているだろうか? この会社の業務は「ただ奇妙な発明(just odd inventions)」をすることである.ここでは略してJOI 社と呼ぶ. JOI 社では多くの微生物を1 つのシャーレに生きたまま閉じ込める研究をしている.調査対象の微生物は N 匹存在し,1, 2, ... , N という番号がついている.各微生物はシャーレに閉じ込められると,foo (fatally odd object) と呼ばれる有害物質を一瞬のうちにシャーレ内に放出する.各微生物が放出するfoo の量は知られている.シャーレに閉じ込められた全微生物が放出したfoo はシャーレ内の各微生物が均等に摂取する.各微生物のfoo 許容量は知られており,この量を超えてfoo を摂取すると微生物は死んでしまう. 微生物 i のfoo 放出量は a i ミリグラム,foo 許容量は b i ミリグラムである.すなわち,シャーレに微生物 i 1 , i 2 , ... , i k を閉じ込めたとき,シャーレ内の各微生物はそれぞれ( a i 1 + a i 2 + ... + a i k )/ k ミリグラムのfoo を摂取し,シャーレ内の微生物 i は,この摂取量がbi より大きいと死んでしまう. JOI 社からの委託により,あなたは出来るだけ多くの微生物をシャーレに生きたまま閉じ込めなければならない.ただし,微生物の死骸はシャーレ内の環境に悪影響を及ぼすため,シャーレ内のどの微生物もfoo の摂取で死んではならない. なお,JOI 社が「ただ奇妙な発明」をすることでどうやって利益を得ているかは,今もって謎であり,JOI社内でも社長以外の誰も知らない. 課題 調査対象の微生物数と,各微生物のfoo 放出量とfoo 許容量が与えられたとき,1 つのシャーレに閉じ込めることができる微生物数の最大値を求めるプログラムを作成せよ. 制限 1 ≤ N ≤ 300000 = 3 × 10 5 調査対象の微生物の数 1 ≤ a i ≤ 100000 = 10 5 微生物 i のfoo 放出量(ミリグラム) 1 ≤ b i ≤ 100000 = 10 5 微生物 i のfoo 許容量(ミリグラム) 入力 標準入力から以下の入力を読み込め. 1 行目には整数 N が書かれており,調査対象の微生物が N 匹存在することを表す. 続くN 行には各微生物の情報が書かれている. i + 1 行目(1 ≤ i ≤ N ) には,正整数 a i , b i が空白を区切りとして書かれており,微生物i のfoo 放出量が a i ミリグラムでfoo 許容量が b i ミリグラムであることを表す. 出力 標準出力に,1 つのシャーレに閉じ込めることができる微生物数の最大値を1 行で出力せよ. 注意 この問題では,扱う整数の範囲が32 ビットに収まらない可能性があることに注意せよ. 採点基準 採点用データのうち,配点の30% については, N ≤ 1000 を満たす. 入出力の例 入力例 6 12 8 5 9 2 4 10 12 6 7 13 9 出力例 3 この例では,微生物2, 4, 5 をシャーレに入れれば,放出されるfoo の合計量は5 + 10 + 6 = 21 ミリグラムとなり,それぞれの微生物が摂取するfoo の量は21/3 = 7 ミリグラムとなる.微生物2, 4, 5 のfoo 許容量はそれぞれ9, 12, 7 ミリグラムなので,シャーレ内のどの微生物も死なない.また,4 匹以上の微生物をどの微生物も死なないようにシャーレに入れることはできない. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0564_10851516", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\nlong long n, a[400000], b[400000], x[531441], x2[533141];\nvector<pair<long long, long long>>vec, vec2;\nvoid add(long long p, long long r) { while (p <= 524287) { x[p] += r; p += p&-p; } }\nlong long sum(long long t) { long long cnt = 0; while (t >= 1) { cnt += x[t]; t -= t&-t; }return cnt; }\nvoid add2(long long p, long long r) { while (p <= 524287) { x2[p] += r; p += p&-p; } }\nlong long sum2(long long t) { long long cnt = 0; while (t >= 1) { cnt += x2[t]; t -= t&-t; } return cnt; }\nint main() {\n\tcin >> n; for (int i = 0; i < n; i++) { cin >> a[i] >> b[i]; vec.push_back(make_pair(b[i], i)); vec2.push_back(make_pair(a[i], i)); }\n\tsort(vec.begin(), vec.end()); sort(vec2.begin(), vec2.end());\n\tlong long maxn = 0;\n\tfor (int i = vec.size() - 1; i >= 0; i--) {\n\t\tlong long num = vec[i].second;\n\t\tlong long pos1 = lower_bound(vec2.begin(), vec2.end(), make_pair(a[num], num)) - vec2.begin();\n\t\tadd(pos1 + 1, a[num]); add2(pos1 + 1, 1);\n\t\tlong long L = 0, R = 320000, M;\n\t\twhile (true) {\n\t\t\tM = (L + R) / 2;\n\t\t\tlong long T1 = sum(M), T2 = sum2(M);\n\t\t\tlong long U1 = sum(M + 1), U2 = sum2(M + 1);\n\t\t\tlong long V1 = 0; if (T2 > 0)V1 = (T1 + T2 - 1) / T2;\n\t\t\tlong long V2 = 0; if (U2 > 0)V2 = (U1 + U2 - 1) / U2;\n\t\t\tif (V1 <= vec[i].first && V2 > vec[i].first) { maxn = max(maxn, T2); break; }\n\t\t\tif (V1 > vec[i].first)R = M;\n\t\t\tif (V2 <= vec[i].first)L = M;\n\t\t\tif (M == 319999) { maxn = max(maxn, T2); break; }\n\t\t}\n\t}\n\tcout << maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 29840, "score_of_the_acc": -1.9688, "final_rank": 13 }, { "submission_id": "aoj_0564_10525135", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N;\n cin >> N;\n vector<pair<int,int>> v;\n v.reserve(N);\n while (N--) {\n int a, b;\n cin >> a >> b;\n // store as (deadline, cost)\n v.emplace_back(b, a);\n }\n // sort by deadline ascending\n sort(v.begin(), v.end());\n // \"in\" holds selected costs (max‐heap), \"out\" holds candidates (min‐heap)\n priority_queue<int> in;\n priority_queue<int, vector<int>, greater<>> out;\n\n long long s = 0;\n // process deadlines from large down to 0\n for (int t = 100000; t >= 0; --t) {\n // move all items with deadline == t into the candidate queue\n while (!v.empty() && v.back().first == t) {\n out.push(v.back().second);\n v.pop_back();\n }\n // balance: if largest selected > smallest candidate, swap them\n while (!in.empty() && !out.empty() && in.top() > out.top()) {\n s += -in.top() + out.top();\n in.push(out.top());\n out.push(in.top());\n in.pop();\n out.pop();\n }\n // try to take new items while budget allows\n while (!out.empty()) {\n // if adding next candidate would exceed t*(|in|+1), stop\n if (static_cast<long long>(t) * (in.size() + 1) < s + out.top()) {\n break;\n }\n s += out.top();\n in.push(out.top());\n out.pop();\n }\n }\n // answer is number taken\n cout << in.size() << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8028, "score_of_the_acc": -0.2862, "final_rank": 1 }, { "submission_id": "aoj_0564_8860214", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbitset<300010> use;\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n ll product = num * b[i].fs;\n while (id < n && (p[id].fs <= b[i].fs || (sum + p[id].fs <= (num + 1) * b[i].fs))) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n product = num * b[i].fs;\n }\n id++;\n }\n if (sum <= product)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n product = num * b[i].fs;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 14916, "score_of_the_acc": -0.5511, "final_rank": 2 }, { "submission_id": "aoj_0564_8500857", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vector<pair<ll,ll>> P(N);\n rep(i,N)cin>>P[i].second>>P[i].first;\n sort(all(P));\n ll L=0,R=N+1;\n while(R-L>1){\n ll M=(R+L)/2;\n ll S=0;\n priority_queue<ll> Q;\n bool OK=0;\n for(ll i=N-1;i>=0;i--){\n if(Q.size()==M-1){\n if(P[i].first*M-P[i].second>=S)OK=1;\n }\n Q.push(P[i].second);\n S+=P[i].second;\n if(Q.size()==M){\n S-=Q.top();\n Q.pop();\n }\n }\n (OK?L:R)=M;\n }\n cout<<L<<endl;\n\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 15428, "score_of_the_acc": -1.4458, "final_rank": 12 }, { "submission_id": "aoj_0564_8500854", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = int;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vector<pair<ll,ll>> P(N);\n rep(i,N)cin>>P[i].second>>P[i].first;\n sort(all(P));\n ll L=0,R=N+1;\n while(R-L>1){\n ll M=(R+L)/2;\n ll S=0;\n priority_queue<ll> Q;\n bool OK=0;\n for(ll i=N-1;i>=0;i--){\n if(Q.size()==M-1){\n if(P[i].first*M-P[i].second>=S)OK=1;\n }\n Q.push(P[i].second);\n S+=P[i].second;\n if(Q.size()==M){\n S-=Q.top();\n Q.pop();\n }\n }\n (OK?L:R)=M;\n }\n cout<<L<<endl;\n\n}", "accuracy": 0.47368421052631576, "time_ms": 30, "memory_kb": 3836, "score_of_the_acc": 0, "final_rank": 14 }, { "submission_id": "aoj_0564_8496157", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n vector<pair<ll,ll>> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i].second >> v[i].first;\n }\n sort(v.begin(), v.end());\n ll res = 0;\n ll sum = 0;\n ll cnt = 0;\n set<pair<ll,int>> p;\n for (int i = 0; i < n; ++i) {\n p.insert({v[i].second, i});\n }\n for (int i = 0; i < n; ++i) {\n ll mi = v[i].first;\n while (p.size()) {\n auto it = p.begin();\n ll nsum = sum + it->first;\n ll ncnt = cnt + 1;\n if (nsum <= mi*ncnt) {\n sum = nsum;\n cnt = ncnt;\n p.erase(it);\n }\n else {\n break;\n }\n }\n res = max(res, cnt);\n {\n ll ss = v[i].second;\n if (p.find({ss, i}) != p.end()) {\n p.erase(p.find({ss, i}));\n }\n else {\n sum -= ss;\n cnt -= 1;\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 26528, "score_of_the_acc": -1.2476, "final_rank": 11 }, { "submission_id": "aoj_0564_8214995", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbool use[300010];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (p[id].fs > b[i].fs && sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15136, "score_of_the_acc": -0.5595, "final_rank": 3 }, { "submission_id": "aoj_0564_8214994", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbool use[300010];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15208, "score_of_the_acc": -0.5623, "final_rank": 7 }, { "submission_id": "aoj_0564_8115449", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nconst int MAXN = 300010;\nint n;\npair<ll, int> p[MAXN], b[MAXN];\nll a[MAXN];\nbool use[MAXN];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(false);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15228, "score_of_the_acc": -0.5631, "final_rank": 8 }, { "submission_id": "aoj_0564_8115445", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbool use[300010];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= (ll)num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15172, "score_of_the_acc": -0.5609, "final_rank": 4 }, { "submission_id": "aoj_0564_8115442", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbool use[300010];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15228, "score_of_the_acc": -0.5631, "final_rank": 8 }, { "submission_id": "aoj_0564_8115441", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nconst int MAXN = 300010;\nint n;\npair<ll, int> p[MAXN], b[MAXN];\nll a[MAXN];\nbool use[MAXN];\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15176, "score_of_the_acc": -0.5611, "final_rank": 6 }, { "submission_id": "aoj_0564_8115438", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nint n;\npair<ll, int> p[300010], b[300010];\nll a[300010];\nbool use[300010];\nint main() {\n cin.tie(0);\n std::ios::sync_with_stdio(0);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= static_cast<ll>(num) * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15172, "score_of_the_acc": -0.5609, "final_rank": 4 }, { "submission_id": "aoj_0564_8051009", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#define fs first\n#define sc second\nusing namespace std;\ntypedef long long ll;\nconst int MAXN = 300010;\nint n;\npair<ll, int> p[MAXN], b[MAXN];\nll a[MAXN];\nbool use[MAXN];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cin >> n;\n for (int i = 0; i < n; i++) {\n cin >> a[i] >> b[i].fs;\n p[i] = make_pair(a[i], i);\n b[i].sc = i;\n use[i] = false;\n }\n sort(p, p + n);\n sort(b, b + n);\n int ans = 0;\n ll sum = 0;\n int id = 0, num = 0;\n for (int i = 0; i < n; i++) {\n if (!use[b[i].sc]) {\n sum += a[b[i].sc];\n use[b[i].sc] = true;\n num++;\n }\n while (id < n && p[id].fs <= b[i].fs) {\n if (!use[p[id].sc]) {\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n while (id < n) {\n if (!use[p[id].sc]) {\n if (sum + p[id].fs > (num + 1) * b[i].fs)\n break;\n sum += p[id].fs;\n use[p[id].sc] = true;\n num++;\n }\n id++;\n }\n if (sum <= num * b[i].fs)\n ans = max(ans, num);\n sum -= a[b[i].sc];\n num--;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15400, "score_of_the_acc": -0.5697, "final_rank": 10 } ]
aoj_0573_cpp
夜店(Night Market) 太郎くんは,JOI 神社で開かれる夏祭りに行くことにした. JOI 神社に向かう道に沿って, N 個の夜店が開かれている.それぞれの夜店には,1 から N までの番号が順番についており,遊んだ時の楽しさと遊ぶのにかかる時間がそれぞれ整数で決まっている.夜店 i で遊んだ時の楽しさは A i で,夜店 i で遊ぶのにかかる時間は B i である. また,夏祭りのイベントとして花火大会があり,時刻 S に最も大きな花火が打ち上げられる.太郎くんはこの最も大きな花火を見たいと思っている. 太郎くんは夜店と花火の両方を楽しむために,夏祭りに到着する時刻0 から夏祭りが終わる時刻 T までの予定を立てることにした. 太郎くんは夜店の中から k 個(1 ≤ k ≤ N ) の夜店を選び,それぞれに対して訪れる時刻を整数で決める.同じ夜店を2 度選ぶことはできない.選ばれた夜店の番号を小さい順に y 1 , y 2 , ... y k とし,夜店 y i を訪れる時刻を x y i とすると,太郎くんは夜店 y i で時刻 x y i から時刻 x y i + B y i まで遊ぶ. 太郎くんは夜店の番号の小さい順に遊び,同時に2 つの夜店では遊べない.また,夜店と夜店の間の移 動にかかる時間は無視できる. 時刻 T を超えると夏祭りが終わるので,夜店で遊ぶことはできない.また,夜店で遊んでいる間は花火を見ることはできない.ただし,時刻 S がある夜店で遊び始める時刻や遊び終わる時刻であった場合は,太郎くんは花火を見ることができるものとする. すなわち,予定は以下の条件を満たしていなければならない. y 1 < y 2 < ... < y k x y 1 , x y 2 , ... x y k は整数. 0 ≤ x y 1 < x y 1 + B y 1 ≤ x y 2 < x y 2 + B y 2 ≤ ... ≤ x y k < x y k + B y k ≤ T x y i < S < x y i + B y i となるような i は存在しない. 選ばれた夜店の楽しさ A y 1 , A y 2 , ... A y k の合計を M とする.太郎くんは M ができるだけ大きくなるように予定を立てたいと思っている. 課題 N 個の夜店の情報と時刻 S , T が与えられた時, M の最大値を求めるプログラムを作成せよ. 制限 1 ≤ N ≤ 3000     夜店の数 1 ≤ T ≤ 3000     夏祭りが終わる時刻 0 ≤ S ≤ T 最も大きな花火が打ち上げられる時刻 0 ≤ A i ≤ 100000 (= 10 5 )     夜店i で遊んだ時の楽しさ 1 ≤ B i ≤ 3000     夜店 i で遊ぶのにかかる時間 入力 標準入力から以下の入力を読み込め. 入力の1 行目には整数 N , T , S が空白を区切りとして書かれており,夜店の数が N 個,夏祭りが終わる時刻が T ,最も大きな花火が打ち上げられる時刻が S であることを表す. 続く N 行には夜店の情報が書かれている.入力の i + 1 (1 ≤ i ≤ N ) 行目には整数 A i , B i が空白を区切りとして書かれており,夜店 i で遊んだ時の楽しさが A i で,夜店 i で遊ぶのにかかる時間が B i であることを表す. また,すべての入力において,1つ以上の予定を立てられることが保証されている. 出力 標準出力に, M の最大値を表す整数を1 行で出力せよ. 採点基準 採点用データのうち, 配点の10%分については, N ≤ 20 を満たす. 配点の20%分については, S = 0 を満たす. 配点の30%分については,これら2 つの条件の少なくとも一方を満たす.また,これら2 つの条件の両方を満たすような採点用データはない. 入出力例 入力例 1 5 20 14 8 9 2 4 7 13 6 3 5 8 出力例 1 16 この例において, 夜店1 を時刻0 に訪れ, 夜店2 を時刻9 に訪れ, 夜店4 を時刻14 に訪れるような予定を立てると, M を最も大きくすることができる. このとき, M = 8 + 2 + 6 = 16 である. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0573_9552371", "code_snippet": "#include<iostream>\nusing namespace std;\n\nconst int max_n = 3010; // 最大アイテム数\nconst int max_t = 3010; // 最大時間\n\nint main()\n{\n int N, T, S;\n while(cin >> N >> T >> S){\n int A[max_n], B[max_n];\n \n // 各アイテムの価値と時間を読み込み\n for(int i = 0; i < N; ++i){\n cin >> A[i] >> B[i];\n }\n \n static int dp[max_n][max_t];\n \n // dp配列を初期化\n for(int i = 0; i <= N; ++i){\n for(int j = 0; j <= T; ++j){\n dp[i][j] = 0;\n }\n }\n \n // 動的計画法による計算\n for(int i = 0; i < N; ++i){\n for(int j = 0; j <= T; ++j){\n // アイテムiを選ばない場合\n dp[i+1][j] = max(dp[i+1][j], dp[i][j]);\n\n // アイテムiを選ぶ場合、時間jにアイテムを追加した場合の更新\n dp[i][j+1] = max(dp[i][j+1], dp[i][j]);\n\n // アイテムiを選ぶ場合、時間帯制約を確認\n if(j + B[i] <= T){\n if(!(j < S && S < j + B[i])){\n dp[i+1][j + B[i]] = max(dp[i+1][j + B[i]], dp[i][j] + A[i]);\n }\n }\n }\n }\n \n // 最終的に得られる最大の価値を出力\n cout << dp[N][T] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 38744, "score_of_the_acc": -0.4221, "final_rank": 5 }, { "submission_id": "aoj_0573_9009820", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, T, S;\n cin >> N >> T >> S;\n vi A(N+1), B(N+1);\n rep(i, 1, N+1) cin >> A[i] >> B[i];\n vv(ll, dp, N+1, S+1, 0);\n vv(ll, dp2, N+2, T-S+1, 0);\n rep(i, 1, N+1) {\n rep(j, 1, S+1) {\n dp[i][j] = dp[i-1][j];\n if (j-B[i] < 0) continue;\n chmax(dp[i][j], dp[i-1][j-B[i]] + A[i]);\n }\n }\n rrep(i, 1, N+1) {\n rep(j, S+1, T+1) {\n ll k = j - S;\n dp2[i][k] = dp2[i+1][k];\n if (k-B[i] < 0) continue;\n chmax(dp2[i][k], dp2[i+1][k-B[i]] + A[i]);\n }\n }\n ll ans = 0;\n rep(i, N) {\n chmax(ans, dp[i][S] + MAX(dp2[i+1]));\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 73836, "score_of_the_acc": -0.8409, "final_rank": 13 }, { "submission_id": "aoj_0573_8135450", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nint main() {\n ll N,T,S;\n cin>>N>>T>>S;\n vvll DP(N+1,vll(T+1,-1e18));\n DP[0][0]=0;\n rep(i,N){\n ll A,B;\n cin>>A>>B;\n for(ll t=0;t<=T;t++){\n DP[i+1][t]=max(DP[i+1][t],DP[i][t]);\n if(t!=T)DP[i+1][t+1]=max(DP[i+1][t+1],DP[i+1][t]);\n if(t+B<=T){\n if(t<S&&S<t+B)continue;\n DP[i+1][t+B]=max(DP[i+1][t+B],DP[i][t]+A);\n }\n }\n }\n //cout<<DP[2][13]<<endl;\n ll an=0;\n rep(t,T+1)an=max(an,DP[N][t]);\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 73564, "score_of_the_acc": -0.8389, "final_rank": 12 }, { "submission_id": "aoj_0573_6846943", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint dp[3001][3001];\nint main(){\n\tint n,t,s,a[3000],b[3000];\n\tcin>>n>>t>>s;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i]>>b[i];\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<=t;j++){\n\t\t\tdp[i+1][j]=max(dp[i+1][j],dp[i][j]);\n\t\t\tif(j<s&&s<j+b[i]){\n\t\t\t\tif(s+b[i]<=t)\n\t\t\t\t\tdp[i+1][s+b[i]]=max(dp[i+1][s+b[i]],dp[i][j]+a[i]);\n\t\t\t}else\n\t\t\t\tif(j+b[i]<=t)\n\t\t\t\t\tdp[i+1][j+b[i]]=max(dp[i+1][j+b[i]],dp[i][j]+a[i]);\n\t\t}\n\t}\n\tcout<<*max_element(dp[n],dp[n]+t+1)<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 38652, "score_of_the_acc": -0.4197, "final_rank": 4 }, { "submission_id": "aoj_0573_6291374", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e10;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll N, T, S; cin >> N >> T >> S;\n vector<ll>A(N), B(N);\n for (ll i = 0; i < N; i++) cin >> A[i] >> B[i];\n vector<vector<ll>>DP(N + 1, vector<ll>(T + 1, 0));\n for (ll i = 0; i <= T; i++) {\n if (i >= B[0] && !(i - B[0] < S && S < i)) DP[1][i] = A[0];\n }\n for (ll i = 2; i <= N; i++) {\n for (ll j = 0; j <= T; j++) {\n if (j >= B[i - 1] && !(j - B[i - 1] < S && S < j)) DP[i][j] = max(DP[i - 1][j], DP[i - 1][j - B[i - 1]] + A[i - 1]);\n else DP[i][j] = DP[i - 1][j];\n }\n }\n ll ans = -1;\n for (ll i = 0; i <= T; i++) {\n ans = max(ans, DP[N][i]);\n }\n cout << ans << endl;\n}\nint main() {\n ll T=1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 73608, "score_of_the_acc": -0.8381, "final_rank": 10 }, { "submission_id": "aoj_0573_6038551", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,t,s);\n vector<array<int,2>> a(n);\n rep(i,n)in(a[i][0],a[i][1]);\n vector<int> dp(t+1,-INF);\n dp[0]=0;\n rep(i,n){\n for(int j=t-a[i][1];j>=0;j--){\n if(!(j<s&&s<j+a[i][1]))chmax(dp[j+a[i][1]],dp[j]+a[i][0]);\n }\n rep(j,t)chmax(dp[j+1],dp[j]);\n }\n out(*max_element(all(dp)));\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3604, "score_of_the_acc": -0.0028, "final_rank": 1 }, { "submission_id": "aoj_0573_5851367", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\nvoid chmin(int &a, int b){ if(a > b) a = b; }\nvoid chmax(int &a, int b){ if(a < b) a = b; }\n\nint dp[3030][3030];\n\nint main(){\n int n, t, s;\n cin >> n >> t >> s;\n int a[n], b[n];\n rep(i, n) cin >> a[i] >> b[i];\n \n rep(i, 3030) rep(j, 3030) dp[i][j] = 0;\n \n rep(i, n){\n rep(j, t + 1){\n chmax(dp[i + 1][j], dp[i][j]);\n if((j + b[i] <= s) || (j >= s && j + b[i] <= t)){\n chmax(dp[i + 1][j + b[i]], dp[i][j] + a[i]);\n }\n chmax(dp[i][j + 1], dp[i][j]);\n }\n }\n \n cout << *max_element(dp[n], dp[n] + t + 1) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 39324, "score_of_the_acc": -0.4277, "final_rank": 6 }, { "submission_id": "aoj_0573_5851365", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\nvoid chmin(int &a, int b){ if(a > b) a = b; }\nvoid chmax(int &a, int b){ if(a < b) a = b; }\n\nint dp[3030][3030];\n\nint main(){\n int n, t, s;\n cin >> n >> t >> s;\n int a[n], b[n];\n rep(i, n) cin >> a[i] >> b[i];\n \n rep(i, 3030) rep(j, 3030) dp[i][j] = 0;\n \n rep(i, n){\n rep(j, t){\n chmax(dp[i + 1][j], dp[i][j]);\n if((j + b[i] <= s) || (j >= s && j + b[i] <= t)){\n chmax(dp[i + 1][j + b[i]], dp[i][j] + a[i]);\n }\n chmax(dp[i][j + 1], dp[i][j]);\n }\n }\n \n cout << *max_element(dp[n], dp[n] + t + 1) << endl;\n}", "accuracy": 0.2, "time_ms": 10, "memory_kb": 39296, "score_of_the_acc": -0.4273, "final_rank": 20 }, { "submission_id": "aoj_0573_5175602", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nconstexpr long long mod = 1000000007;\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint n, t, s, a[4000], b[4000], dp[3500][3500];\nsigned main() {\n\tcin >> n >> t >> s;\n\tfor1(i, n)cin >> a[i] >> b[i];\n\tfor1(i, n)for1(j, t) {\n\t\tdp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);\n\t\tif (j >= b[i] && (j <= s || j - b[i] >= s))dp[i][j] = max(dp[i][j], dp[i - 1][j - b[i]] + a[i]);\n\t}\n\tputs(dp[n][t]);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 87436, "score_of_the_acc": -1, "final_rank": 17 }, { "submission_id": "aoj_0573_5031142", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int INF = 1<<29;\nint main() {\n int N, T, S;\n cin >> N >> T >> S;\n vector<int> A(N), B(N);\n for (int i = 0; i < N; ++i) cin >> A[i] >> B[i];\n\n auto add = [&](vector<int> dp, int a, int b) -> vector<int> {\n for (int t = T; t >= b; --t) dp[t] = max(dp[t], dp[t-b]+a);\n return dp;\n };\n\n vector<vector<int>> left(N+1, vector<int>(T+1, -INF)), right = left;\n for (int t = 0; t <= T; ++t) left[0][t] = right[0][t] = 0;\n for (int i = 0; i < N; ++i) {\n left[i+1] = add(left[i], A[i], B[i]);\n right[i+1] = add(right[i], A[N-i-1], B[N-i-1]);\n }\n int res = 0;\n for (int l = 0; l <= N; ++l) {\n res = max(res, left[l][S] + right[N-l][T-S]);\n //cout << l << \": \" << left[l][S] << \", \" << right[N-l][T-S] << endl;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 74048, "score_of_the_acc": -0.8434, "final_rank": 14 }, { "submission_id": "aoj_0573_5004689", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#define stoi stoll\n#define rep(i, n) for (int i = 0; i < (int)(n); i++) // [0, b)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); i++) // [a, b)\n#define rep3(i, a, b) for (int i = (int)(a); i >= (int)(b); i--) // reversed [b, a] so [a, a-1, a-2, ..., b]\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define SUM(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n\nusing namespace std;\nconst int MOD = 998244353;\nconst int MOD2 = 1000000007;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-14;\nconst double PI = acos(-1);\n\nint CEIL(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); } //ceil() for int\nint mod(int a, int b) { return a >= 0 ? a % b : a - (b * CEIL(a, b)); } //always return positive num\nint pow_mod(int a, int b) { //return x^y in order(log(y))\n int res = 1;\n for (a %= MOD; b; a = a * a % MOD, b >>= 1)\n if (b & 1) res = res * a % MOD;\n return res;\n}\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n int N, T, S;\n int A, B;\n cin >> N >> T >> S;\n vector<vector<int>> dp(N + 1, vector<int>(T + 100, 0));\n rep2(i, 1, N + 1) {\n cin >> A >> B;\n dp[i] = dp[i - 1];\n rep(j, T - B + 1) {\n if (!(j < S and S < j + B)) {\n dp[i][j + B] = max(dp[i - 1][j] + A, dp[i][j + B]);\n }\n }\n }\n cout << MAX(dp[N]) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 39484, "score_of_the_acc": -0.4296, "final_rank": 7 }, { "submission_id": "aoj_0573_5004688", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#define stoi stoll\n#define rep(i, n) for (int i = 0; i < (int)(n); i++) // [0, b)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); i++) // [a, b)\n#define rep3(i, a, b) for (int i = (int)(a); i >= (int)(b); i--) // reversed [b, a] so [a, a-1, a-2, ..., b]\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define SUM(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n\nusing namespace std;\nconst int MOD = 998244353;\nconst int MOD2 = 1000000007;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-14;\nconst double PI = acos(-1);\n\nint CEIL(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); } //ceil() for int\nint mod(int a, int b) { return a >= 0 ? a % b : a - (b * CEIL(a, b)); } //always return positive num\nint pow_mod(int a, int b) { //return x^y in order(log(y))\n int res = 1;\n for (a %= MOD; b; a = a * a % MOD, b >>= 1)\n if (b & 1) res = res * a % MOD;\n return res;\n}\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n int N, T, S;\n int A, B;\n cin >> N >> T >> S;\n vector<vector<int>> dp(N + 1, vector<int>(T + 100, 0));\n rep2(i, 1, N + 1) {\n cin >> A >> B;\n rep(j, T + 100) {\n dp[i] = dp[i - 1];\n }\n rep(j, T - B + 1) {\n if (!(j < S and S < j + B)) {\n dp[i][j + B] = max(dp[i - 1][j] + A, dp[i][j + B]);\n }\n }\n }\n cout << MAX(dp[N]) << endl;\n}", "accuracy": 1, "time_ms": 1650, "memory_kb": 39516, "score_of_the_acc": -0.6463, "final_rank": 8 }, { "submission_id": "aoj_0573_5003937", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define stoi stoll\n#define rep(i, n) for (int i = 0; i < (int)(n); i++) // [0, b)\n#define rep2(i, a, b) for (int i = (int)(a); i < (int)(b); i++) // [a, b)\n#define rep3(i, a, b) for (int i = (int)(a); i >= (int)(b); i--) // reversed [b, a] so [a, a-1, a-2, ..., b]\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define SUM(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n\nusing namespace std;\nconst int MOD = 998244353;\nconst int MOD2 = 1000000007;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-14;\nconst double PI = acos(-1);\n\nint CEIL(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); } //ceil() for int\nint mod(int a, int b) { return a >= 0 ? a % b : a - (b * CEIL(a, b)); } //always return positive num\nint pow_mod(int a, int b) { //return x^y in order(log(y))\n int res = 1;\n for (a %= MOD; b; a = a * a % MOD, b >>= 1)\n if (b & 1) res = res * a % MOD;\n return res;\n}\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n int N, T, S;\n cin >> N >> T >> S;\n vector<vector<int>> dp(N + 1, vector<int>(T + 100, 0));\n rep2(i, 1, N + 1) {\n int A, B;\n cin >> A >> B;\n rep(j, T + 100) {\n dp[i] = dp[i - 1];\n }\n rep(j, T - B + 1) {\n if (!(j < S and S < j + B)) {\n dp[i][j + B] = max(dp[i - 1][j] + A, dp[i][j + B]);\n }\n }\n }\n cout << MAX(dp[N]) << endl;\n}", "accuracy": 1, "time_ms": 7590, "memory_kb": 75752, "score_of_the_acc": -1.861, "final_rank": 18 }, { "submission_id": "aoj_0573_5003895", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep2(i, a, b) for(ll i = a; i <= b; ++i)\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define rep3(i, a, b) for(ll i = a; i >= b; --i)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return move(res);\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return move(res);\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nconst ll INF = 1e18;\nint main(){\n INT(n,t,s);\n vec(int,a,n);\n vec(int,b,n);\n rep(i,n)cin >> a[i] >> b[i];\n vv(ll,dp,n+1,t+1,0);\n dp[0][0] = 0;\n rep(i,n){\n rep(j,t+1){\n chmax(dp[i+1][j],dp[i][j]);\n if((j+b[i]<= s || j >= s) && j+b[i] <= t)chmax(dp[i+1][j+b[i]],dp[i][j]+a[i]);\n }\n }\n ll ret = -INF;\n rep(i,t+1)chmax(ret,dp[n][i]);\n // trace(dp);\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 73544, "score_of_the_acc": -0.8374, "final_rank": 9 }, { "submission_id": "aoj_0573_5003876", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n int n, t, s;\n cin >> n >> t >> s;\n\n vector<int> a(n), b(n);\n for(int i = 0 ; i < n ; ++i){\n cin >> a[i] >> b[i];\n }\n\n vector< vector<int> > dp(n + 1, vector<int>(t + 1, 0));\n for(int i = 0 ; i < n ; ++i){\n for(int j = 0 ; j <= t ; ++j){\n chmax(dp[i + 1][j], dp[i][j]);\n\n if(j + 1 <= t){\n chmax(dp[i][j + 1], dp[i][j]);\n }\n\n if(j + b[i] <= t && (j + b[i] <= s || s <= j)){\n chmax(dp[i + 1][j + b[i]], dp[i][j] + a[i]);\n }\n }\n }\n\n cout << dp[n][t] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 38492, "score_of_the_acc": -0.4191, "final_rank": 3 }, { "submission_id": "aoj_0573_4915346", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i, x) for(ll i = 0; i < x; i++)\nusing ll = long long;\nusing namespace std;\nll n, W, s; ll w[345678], v[345678], dp[5000][23456];\nvoid solve() {\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tfor (int j = 0; j <= W; j++) {\n\t\t\tif (j >= w[i] && (j - w[i] >= s || j <= s)) { dp[i][j] = dp[i + 1][j - w[i]] + v[i]; }\n\t\t\tdp[i][j] = max(dp[i][j], max(dp[i + 1][j], dp[i][j - 1]));\n\t\t}\n\t}\n\tcout << dp[0][W] << endl;\n}\nsigned main() {\n\tcin >> n >> W >> s; s = W - s;\n\trep(i, n) { cin >> v[i] >> w[i]; }\n\tsolve(); return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 85652, "score_of_the_acc": -0.9841, "final_rank": 16 }, { "submission_id": "aoj_0573_4392047", "code_snippet": "#include<bits/stdc++.h>\n#define enld '\\n'\n#define rep(i,n) for(int i=0; i<(n); i++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"Ofast\")\nconstexpr ll INF = 1e18;\nconstexpr int inf = 1e9;\nconstexpr ll mod = 1000000007;\nconstexpr ll mod2 = 998244353;\nconst double PI = 3.1415926535897932384626433832795028841971;\nconst int dx[6] = {1, 0, -1, 0,1,1};\nconst int dy[6] = {0, 1, 0, -1,1,-1};\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n// ---------------------------------------------------------------------------\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int N,T,S;\n cin >> N >> T >> S;\n vector<ll> A(N),B(N);\n for(int i=0; i<N; i++){\n cin >> A[i] >> B[i];\n }\n vector<vector<ll>> dp(N+5, vector<ll> (S+5,0));\n for(int i=0; i<N; i++){\n for(int j=0; j<=S; j++){\n chmax(dp[i+1][j],dp[i][j]);\n if(j+B[i] > S) continue;\n chmax(dp[i+1][j+B[i]], dp[i][j] + A[i]);\n }\n }\n vector<vector<ll>> dp2(N+5, vector<ll> (T-S+5,0));\n for(int i=N; i>0; i--){\n for(int j=0; j<=T-S; j++){\n chmax(dp2[i][j],dp2[i+1][j]);\n if(j+B[i-1] > T-S) continue;\n chmax(dp2[i][j+B[i-1]],dp2[i+1][j]+A[i-1]);\n }\n }\n ll ans = 0;\n for(int i=0; i<=N; i++){\n chmax(ans,dp[i][S]+dp2[i+1][T-S]);\n }\n cout << ans << enld;\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 73920, "score_of_the_acc": -0.855, "final_rank": 15 }, { "submission_id": "aoj_0573_4391799", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(ll i=0;i<(n);++i)\n#define all(a) (a).begin(),(a).end()\nusing namespace std;\nusing Graph = vector<vector<int>>;\ntypedef pair<int,int> P;\ntypedef long long ll;\n\nint main(){\n int n, t, s; cin >> n >> t >> s;\n vector<ll> value(n), time(n);\n\n rep(i,n) cin >> value[i] >> time[i];\n vector<vector<ll>> dp1(n+1, vector<ll> (s+1,0));\n vector<vector<ll>> dp2(n+1, vector<ll> ((t-s)+1,0));\n\n for(int i = 0; i < n; i++){\n for(int T = 0; T <= s; T++){\n if(T >= time[i]) dp1[i+1][T] = max(dp1[i][T-time[i]] + value[i],dp1[i][T]);\n else dp1[i+1][T] = dp1[i][T];\n }\n }\n\n for(int i = 0; i < n; i++){\n for(int T = 0; T <= t-s; T++){\n if(T >= time[n-i]) dp2[i+1][T] = max(dp2[i][T-time[n-i]] + value[n-i],dp2[i][T]);\n else dp2[i+1][T] = dp2[i][T];\n }\n }\n\n ll ans = 0;\n rep(i,n){\n ans = max(dp2[i][t-s] + dp1[n-i][s], ans);\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 73656, "score_of_the_acc": -0.8387, "final_rank": 11 }, { "submission_id": "aoj_0573_4391636", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=1<<30;\nconst int mod=1e9+7;\nconst int MOD=998244353;\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n,t,s;cin >> n >> t >> s;\n vector<int> a(n),b(n);\n for(int i=0;i<n;i++){\n cin >> a[i] >> b[i];\n }\n vector<vector<int>> dp(t+1,vector<int>(2,-1));\n dp[0][0]=0;\n vector<vector<int>> p(t+1,vector<int>(2,-1));\n p[0][0]=0;\n if(s==0){\n dp[0][1]=0;\n p[0][1]=0;\n }\n for(int i=0;i<n;i++){\n for(int j=0;j<=t;j++){\n for(int k=0;k<2;k++){\n if(dp[j][k]==-1){\n continue;\n }\n chmax(p[j][k],dp[j][k]);\n if(j<=s&&k==0){\n chmax(p[s][1],dp[j][0]);\n }\n if(j+b[i]<=t){\n if(j+b[i]<=s&&k==0){\n chmax(p[s][1],dp[j][0]+a[i]);\n }\n chmax(p[j+b[i]][k],dp[j][k]+a[i]);\n }\n }\n }\n for(int j=0;j<=t;j++){\n for(int k=0;k<2;k++){\n chmax(dp[j][k],p[j][k]);\n p[j][k]=-1;\n }\n }\n }\n int ans=0;\n for(int i=0;i<=t;i++){\n chmax(ans,dp[i][1]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3420, "score_of_the_acc": -0.0085, "final_rank": 2 }, { "submission_id": "aoj_0573_4391630", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=1<<30;\nconst int mod=1e9+7;\nconst int MOD=998244353;\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n,t,s;cin >> n >> t >> s;\n vector<int> a(n),b(n);\n for(int i=0;i<n;i++){\n cin >> a[i] >> b[i];\n }\n vector<vector<int>> dp(t+1,vector<int>(2,-1));\n dp[0][0]=0;\n vector<vector<int>> p(t+1,vector<int>(2,-1));\n p[0][0]=0;\n if(s==0){\n dp[0][1]=0;\n p[0][1]=0;\n }\n for(int i=0;i<n;i++){\n for(int j=0;j<=t;j++){\n for(int k=0;k<2;k++){\n if(dp[j][k]==-1){\n continue;\n }\n chmax(p[j][k],dp[j][k]);\n if(j<=s&&k==0){\n chmax(p[s][k],dp[j][k]);\n }\n if(j+b[i]<=t){\n if(j+b[i]<=s&&k==0){\n chmax(p[s][1],dp[j][0]+a[i]);\n }\n chmax(p[j+b[i]][k],dp[j][k]+a[i]);\n }\n }\n }\n for(int j=0;j<=t;j++){\n for(int k=0;k<2;k++){\n chmax(dp[j][k],p[j][k]);\n p[j][k]=-1;\n }\n }\n }\n int ans=0;\n for(int i=0;i<=t;i++){\n chmax(ans,dp[i][1]);\n }\n cout << ans << endl;\n}", "accuracy": 0.5, "time_ms": 60, "memory_kb": 3372, "score_of_the_acc": -0.0066, "final_rank": 19 } ]
aoj_0570_cpp
ジグザグ数 (Zig-Zag Numbers) 問題 正の整数を (先頭に 0 をつけずに) 10 進法で書いて桁の数字を順番に見ていくと増加と減少を交互に繰り返しているとき,その数は「ジグザグ数」であると呼ぶことにしよう.たとえば,2947 は桁の数字が 2 → 9 → 4 → 7 と,増加 → 減少 → 増加 の順になっているのでジグザグ数である.また,71946 は 減少 → 増加 → 減少 → 増加 の順なのでジグザグ数である.一方,123 や 71446 や 71442 や 88 はジグザグ数ではない.なお,1 桁の正の整数はジグザグ数であると考えることとする. A 以上 B 以下の M の倍数のうち,ジグザグ数の個数を 10000 で割った余りを求めるプログラムを作成せよ. 入力 入力は 3 行からなり,1 行に 1 つずつ正の整数が書かれている. 1 行目の整数は A を,2 行目の整数は B を,3 行目の整数は M を表す.これらは 1 ≦ A ≦ B ≦ 10 500 ,1 ≦ M ≦ 500 を満たす. ※ A や B の値は,通常の整数を表すデータ型には収まらない可能性があることに注意せよ. 出力 A 以上 B 以下の M の倍数のうち,ジグザグ数の個数を 10000 で割った余りを 1 行で出力せよ. 入出力例 入力例 1 100 200 5 出力例 1 13 入出力例 1 において,100 以上 200 以下の 5 の倍数であるジグザグ数は,105, 120, 130, 140, 150, 160, 165, 170, 175, 180, 185, 190, 195 の 13 個である. 入力例 2 6 1234567 3 出力例 2 246 入出力例 2 において,6 以上 1234567 以下の 3 の倍数であるジグザグ数は 50246 個あるので,それを 10000 で割った余りである 246 を出力する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0570_10946343", "code_snippet": "#include <bits/stdc++.h>\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(),(x).end()\n\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\n\ntemplate <typename T> T &chmin(T &a, const T &b) { return a = min(a, b); }\ntemplate <typename T> T &chmax(T &a, const T &b) { return a = max(a, b); }\n\nstruct yes_no : numpunct<char> {\n string_type do_truename() const { return \"Yes\"; }\n string_type do_falsename() const { return \"No\"; }\n};\n\ntemplate<int M>\nclass Modulo {\n using ll = long long;\n int n;\npublic:\n Modulo () : n(0) {;}\n Modulo (int m) : n(m) {\n if (n >= M) n %= M;\n else if (n < 0) n = (n % M + M) % M;\n }\n Modulo (ll m) {\n if (m >= M) m %= M;\n else if (m < 0) m = (m % M + M) % M;\n n = m;\n }\n explicit operator int() const { return n; }\n explicit operator ll() const { return n; }\n bool operator==(const Modulo &a) const { return n == a.n; }\n Modulo operator+=(const Modulo &a) { n += a.n; if (n >= M) n -= M; return *this; }\n Modulo operator-=(const Modulo &a) { n -= a.n; if (n < 0) n += M; return *this; }\n Modulo operator*=(const Modulo &a) { n = (ll(n) * a.n) % M; return *this; }\n Modulo operator+(const Modulo &a) const { Modulo res = *this; return res += a; }\n Modulo operator-(const Modulo &a) const { Modulo res = *this; return res -= a; }\n Modulo operator*(const Modulo &a) const { Modulo res = *this; return res *= a; }\n};\n\nconst int mod = 10000;\n\nusing Mod = Modulo<mod>;\n\nint M;\nMod zig_le[512][512][10], zig_gt[512][512][10];\nMod zag_le[512][512][10], zag_gt[512][512][10];\n\nMod dp(string s) {\n if (s.size() <= 1) return stoi(s) / M;\n REP(i,512) REP(j,512) REP(k,10) {\n zig_le[i][j][k] = 0;\n zig_gt[i][j][k] = 0;\n zag_le[i][j][k] = 0;\n zag_gt[i][j][k] = 0;\n }\n reverse(ALL(s));\n const int n = s.size();\n REP(k,10) {\n const int d = s[0] - '0';\n if (k <= d) zig_le[0][k % M][k] = zag_le[0][k % M][k] = 1;\n else zig_gt[0][k % M][k] = zag_gt[0][k % M][k] = 1;\n }\n int base = 1;\n Mod res = 9 / M;\n REP(i,n-1) {\n base = (base * 10) % M;\n const int d = s[i+1] - '0';\n REP(j,512) REP(k,10) REP(l,10) {\n if (k < l) {\n if (l < d) zig_le[i+1][(base * l + j) % M][l] += zag_le[i][j][k] + zag_gt[i][j][k];\n else if (l > d) zig_gt[i+1][(base * l + j) % M][l] += zag_le[i][j][k] + zag_gt[i][j][k];\n else {\n zig_le[i+1][(base * l + j) % M][l] += zag_le[i][j][k];\n zig_gt[i+1][(base * l + j) % M][l] += zag_gt[i][j][k];\n }\n }\n else if (k > l) {\n if (l < d) zag_le[i+1][(base * l + j) % M][l] += zig_le[i][j][k] + zig_gt[i][j][k];\n else if (l > d) zag_gt[i+1][(base * l + j) % M][l] += zig_le[i][j][k] + zig_gt[i][j][k];\n else {\n zag_le[i+1][(base * l + j) % M][l] += zig_le[i][j][k];\n zag_gt[i+1][(base * l + j) % M][l] += zig_gt[i][j][k];\n }\n }\n }\n if (i < n - 2) {\n for (int l = 1; l < 10; ++l) {\n res += zig_le[i+1][0][l];\n res += zig_gt[i+1][0][l];\n res += zag_le[i+1][0][l];\n res += zag_gt[i+1][0][l];\n }\n }\n else {\n for (int l = 1; l < 10; ++l) {\n res += zig_le[i+1][0][l];\n res += zag_le[i+1][0][l];\n }\n }\n }\n return res;\n}\n\nint main() {\n locale loc(locale(), new yes_no);\n cout << boolalpha;\n cout.imbue(loc);\n string A, B;\n cin >> A >> B >> M;\n A.back()--;\n for (int i = int(A.size()) - 1; i >= 1; --i) {\n if (A[i] < '0') {\n A[i] += 10;\n A[i-1] -= 1;\n }\n }\n cout << int(dp(B) - dp(A)) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 44408, "score_of_the_acc": -0.1945, "final_rank": 4 }, { "submission_id": "aoj_0570_10674796", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int P=10000;\nint m,f[510][10][510][3][2];\nstring s;\nint solve(int k,int last,int r,int x,int g){\n\tif(k>=(int)s.size()) return!r;\n\tint &res=f[k][last][r][x][g];\n\tif(res!=-1) return res;\n\tres=0;\n\tint mx=g?9:s[k]-'0';\n\tif(x==1){\n\t\tfor(int i=0;i<=min(last-1,mx);i++)\n\t\t\tres+=solve(k+1,i,(r*10+i)%m,!x,g||i<mx);\n\t}else if(x==0){\n\t\tfor(int i=last+1;i<=mx;i++)\n\t\tres+=solve(k+1,i,(r*10+i)%m,!x,g||i<mx);\n\t}else{\n\t\tfor(int i=0;i<=mx;i++){\n\t\tif(last==0) res+=solve(k+1,i,(r*10+i)%m,2,g||i<mx);\n\t\telse if(i!=last)\n\t\t\tres+=solve(k+1,i,(r*10+i)%m,last<i,g||i<mx);\n\t\t}\n\t}\n\treturn res%=P;\n}\nint main(){\n\tstring a,b;\n\tcin>>a>>b>>m;\n\ta.back()--;\n\tfor(int i=(int)a.size()-1;i>0;i--)\n\t\tif(a[i]<'0'){\n\t\t\ta[i]+=10;\n\t\t\ta[i-1]--;\n\t\t}\n\ts=b;\n\tmemset(f,-1,sizeof(f));\n\tint ans=solve(0,0,0,2,0);\n\ts=a;\n\tmemset(f,-1,sizeof(f));\n\tans-=solve(0,0,0,2,0);\n\twhile(ans<0) ans+=P;\n\tcout<<ans<<\"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 64272, "score_of_the_acc": -0.3417, "final_rank": 8 }, { "submission_id": "aoj_0570_10453355", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\nint M,dp[501][501][10][3][2][2];\nstring A,B;\nint dfs(string s,int x,int mod,int b,int flag1,bool f,bool zero){\n\tif (x == s.size()){\n\t\treturn (!zero && mod == 0);\n\t}if (dp[x][mod][b][flag1][f][zero] >= 0){\n\t\treturn dp[x][mod][b][flag1][f][zero];\n\t}\n\tint limit = f?(s[x] - '0'):9;\n\tint cnt = 0;\n\tfor (int d = 0;d <= limit;d++){\n\t\tbool new_tight = f && (d == limit);\n\t\tbool new_zero = zero && (d == 0);\n\t\tint new_mod = (mod * 10 + d) % M;\n\t\tif (new_zero){\n\t\t\tcnt += dfs(s,x + 1,new_mod,b,flag1,new_tight,new_zero);\n\t\t\tcnt %= 10000;\n\t\t\tcontinue;\n\t\t}\n\t\tint new_d = flag1;\n\t\tif (zero){\n\t\t\tnew_d = 0;\n\t\t}else{\n\t\t\tif (flag1 == 0){\n\t\t\t\tif (d > b){\n\t\t\t\t\tnew_d = 1;\n\t\t\t\t}else if (d < b){\n\t\t\t\t\tnew_d = 2;\n\t\t\t\t}else{\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t}else if (flag1 == 1){\n\t\t\t\tif (d >= b){\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tnew_d = 2;\n\t\t\t}else if (flag1 == 2){\n\t\t\t\tif (d <= b){\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tnew_d = 1;\n\t\t\t}\n\t\t}\n\t\tcnt += dfs(s,x + 1,new_mod,d,new_d,new_tight,0);\n\t\tcnt %= 10000;\n\t}\n\treturn dp[x][mod][b][flag1][f][zero] = cnt;\n}\nint solve(string s){\n\tmemset(dp,-0x3f,sizeof(dp));\n\treturn dfs(s,0,0,0,0,1,1);\n}\nbool check(string s){\n\tif (s.size() == 1){\n\t\treturn true;\n\t}\n\tint flag1 = 0;\n\tfor (int i = 1;i < s.size();i++){\n\t\tif (s[i] > s[i - 1]){\n\t\t\tif (flag1 == 1){\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\tflag1 = 2;\n\t\t}else if (s[i] < s[i - 1]){\n\t\t\tif (flag1 == 2){\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\tflag1 = 1;\n\t\t}else{\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\nint mod(string s,int m){\n\tint cnt = 0;\n\tfor (char c:s){\n\t\tcnt = (cnt * 10 + (c - '0')) % m;\n\t}\n\treturn cnt;\n}\nsigned main(){\n\tcin >> A >> B >> M;\n\tint ans = 0;\n\tans = solve(B) - solve(A);\n\tif (mod(A,M) == 0 && check(A)){\n\t\tans++;\n\t}\n\tans = (ans % 10000 + 10000) % 10000;\n\tcout << ans << \"\\n\";\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1860, "memory_kb": 239020, "score_of_the_acc": -1.9215, "final_rank": 20 }, { "submission_id": "aoj_0570_10095819", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n\nusing namespace std;\nusing lint = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing int128 = __int128_t;\n#define all(x) (x).begin(), (x).end()\n#define EPS 1e-8\n#define uniqv(v) v.erase(unique(all(v)), v.end())\n#define OVERLOAD_REP(_1, _2, _3, name, ...) name\n#define REP1(i, n) for (auto i = std::decay_t<decltype(n)>{}; (i) != (n); ++(i))\n#define REP2(i, l, r) for (auto i = (l); (i) != (r); ++(i))\n#define rep(...) OVERLOAD_REP(__VA_ARGS__, REP2, REP1)(__VA_ARGS__)\n#define log(x) cout << x << endl\n#define logfixed(x) cout << fixed << setprecision(10) << x << endl;\n#define logy(bool) \\\n if (bool) { \\\n cout << \"Yes\" << endl; \\\n } else { \\\n cout << \"No\" << endl; \\\n }\n\nostream& operator<<(ostream& dest, __int128_t value) {\n ostream::sentry s(dest);\n if (s) {\n __uint128_t tmp = value < 0 ? -value : value;\n char buffer[128];\n char* d = end(buffer);\n do {\n --d;\n *d = \"0123456789\"[tmp % 10];\n tmp /= 10;\n } while (tmp != 0);\n if (value < 0) {\n --d;\n *d = '-';\n }\n int len = end(buffer) - d;\n if (dest.rdbuf()->sputn(d, len) != len) {\n dest.setstate(ios_base::badbit);\n }\n }\n return dest;\n}\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n for (int i = 0; i < (int)v.size(); i++) {\n os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& set_var) {\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end()) os << \" \";\n itr--;\n }\n return os;\n}\n\ntemplate <typename T, typename U>\nostream& operator<<(ostream& os, const map<T, U>& map_var) {\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << itr->first << \" -> \" << itr->second << \"\\n\";\n }\n return os;\n}\n\ntemplate <typename T, typename U>\nostream& operator<<(ostream& os, const pair<T, U>& pair_var) {\n os << \"(\" << pair_var.first << \", \" << pair_var.second << \")\";\n return os;\n}\n\nvoid out() { cout << '\\n'; }\ntemplate <class T, class... Ts>\nvoid out(const T& a, const Ts&... b) {\n cout << a;\n (cout << ... << (cout << ' ', b));\n cout << '\\n';\n}\n\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& v) {\n for (T& in : v) is >> in;\n return is;\n}\n\ninline void in(void) { return; }\ntemplate <typename First, typename... Rest>\nvoid in(First& first, Rest&... rest) {\n cin >> first;\n in(rest...);\n return;\n}\n\ntemplate <typename T>\nbool chmax(T& a, const T& b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T& a, const T& b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\nvector<lint> dx8 = {1, 1, 0, -1, -1, -1, 0, 1};\nvector<lint> dy8 = {0, 1, 1, 1, 0, -1, -1, -1};\nvector<lint> dx4 = {1, 0, -1, 0};\nvector<lint> dy4 = {0, 1, 0, -1};\n\n#pragma endregion\n\n// ジグザグ数を受理するDFA\nclass Zig {\n public:\n using Alphabet = char;\n struct State {\n int last;\n bool increasing;\n bool decreasing;\n\n bool operator==(const State& other) const = default;\n };\n\n State init() const {\n return {0, false, false};\n }\n\n State next(State s, const Alphabet& a, size_t i) const {\n if (s.last == -1) {\n return {-1, false, false};\n }\n if (!s.increasing and !s.decreasing and s.last == 0) {\n if (a == '0') {\n return {0, false, false};\n } else {\n return {a - '0', false, false};\n }\n }\n\n if (!s.increasing and !s.decreasing) {\n if (s.last < a - '0') {\n return {a - '0', true, false};\n } else if (s.last > a - '0') {\n return {a - '0', false, true};\n } else {\n return {-1, false, false};\n }\n }\n\n if (s.increasing) {\n if (s.last > a - '0') {\n return {a - '0', false, true};\n } else {\n return {-1, false, false};\n }\n }\n\n if (s.decreasing) {\n if (s.last < a - '0') {\n return {a - '0', true, false};\n } else {\n return {-1, false, false};\n }\n }\n return {-1, false, false};\n }\n\n bool accept(State s) const {\n return s.last != -1;\n }\n\n bool successful(State s) const {\n return 0;\n }\n\n bool unsuccessful(State s) const {\n return s.last == -1;\n }\n};\n\nenum class Ordering { Less,\n Equal,\n Greater };\n\nnamespace std {\ntemplate <>\nstruct hash<Ordering> {\n std::size_t operator()(const Ordering& o) const {\n return std::hash<int>()(static_cast<int>(o));\n }\n};\ntemplate <typename T1, typename T2>\nstruct hash<pair<T1, T2>> {\n std::size_t operator()(const pair<T1, T2>& p) const {\n return std::hash<T1>()(p.first) * 31 + std::hash<T2>()(p.second);\n }\n};\n\ntemplate <>\nstruct hash<Zig::State> {\n std::size_t operator()(const Zig::State& s) const {\n return std::hash<int>()(s.last) ^ (std::hash<bool>()(s.increasing) << 1) ^ (std::hash<bool>()(s.decreasing) << 2);\n }\n};\n} // namespace std\n\nstruct TupleHash {\n size_t operator()(const std::tuple<int, int, int>& t) const {\n auto [x, y, z] = t;\n return std::hash<int>()(x) ^ (std::hash<int>()(y) << 1) ^ (std::hash<int>()(z) << 2);\n }\n};\ntemplate <typename X>\nclass Dfa {\n public:\n using Alphabet = typename X::Alphabet;\n using State = typename X::State;\n\n Dfa(const X& x) : x_(x) {}\n\n State init() const { return x_.init(); }\n\n State next(const State& s, const Alphabet& a, size_t i) const {\n return x_.next(s, a, i);\n }\n\n bool accept(const State& s) const {\n return x_.accept(s);\n }\n\n bool successful(const State& s) const {\n return x_.successful(s);\n }\n\n bool unsuccessful(const State& s) const {\n return x_.unsuccessful(s);\n }\n\n private:\n X x_;\n};\n\ntemplate <typename X, typename Y>\nclass AndDfa {\n public:\n using Alphabet = typename X::Alphabet;\n using State = pair<typename X::State, typename Y::State>;\n\n AndDfa(const X& x, const Y& y) : x_(x), y_(y) {}\n\n State init() const { return make_pair(x_.init(), y_.init()); }\n\n State next(const State& s, const Alphabet& a, size_t i) const {\n return make_pair(x_.next(s.first, a, i), y_.next(s.second, a, i));\n }\n\n bool accept(const State& s) const {\n return x_.accept(s.first) and y_.accept(s.second);\n }\n\n bool successful(const State& s) const {\n return x_.successful(s.first) and y_.successful(s.second);\n }\n\n bool unsuccessful(const State& s) const {\n return x_.unsuccessful(s.first) or y_.unsuccessful(s.second);\n }\n\n private:\n X x_;\n Y y_;\n};\n\ntemplate <typename X, typename Y>\nclass OrDfa {\n public:\n using Alphabet = typename X::Alphabet;\n using State = pair<typename X::State, typename Y::State>;\n\n OrDfa(const X& x, const Y& y) : x_(x), y_(y) {}\n\n State init() const { return make_pair(x_.init(), y_.init()); }\n\n State next(const State& s, const Alphabet& a, size_t i) const {\n return make_pair(x_.next(s.first, a, i), y_.next(s.second, a, i));\n }\n\n bool accept(const State& s) const {\n return x_.accept(s.first) or y_.accept(s.second);\n }\n\n bool successful(const State& s) const {\n return x_.successful(s.first) or y_.successful(s.second);\n }\n\n bool unsuccessful(const State& s) const {\n return x_.unsuccessful(s.first) and y_.unsuccessful(s.second);\n }\n\n private:\n X x_;\n Y y_;\n};\n\ntemplate <typename X>\nclass NotDfa {\n public:\n using Alphabet = typename X::Alphabet;\n using State = typename X::State;\n\n NotDfa(const X& x) : x_(x) {}\n\n State init() const { return x_.init(); }\n\n State next(const State& s, const Alphabet& a, size_t i) const {\n return x_.next(s, a, i);\n }\n\n bool accept(const State& s) const {\n return !x_.accept(s);\n }\n\n bool successful(const State& s) const {\n return !x_.successful(s);\n }\n\n bool unsuccessful(const State& s) const {\n return !x_.unsuccessful(s);\n }\n\n private:\n X x_;\n};\n\ntemplate <typename X, typename Y>\nclass ProdDfa {\n public:\n using Alphabet = pair<typename X::Alphabet, typename Y::Alphabet>;\n using State = pair<typename X::State, typename Y::State>;\n\n ProdDfa(const X& x, const Y& y) : x_(x), y_(y) {}\n\n State init() const { return make_pair(x_.init(), y_.init()); }\n\n State next(const State& s, const Alphabet& a, size_t i) const {\n return make_pair(x_.next(s.first, a.first, i), y_.next(s.second, a.second, i));\n }\n\n bool accept(const State& s) const {\n return x_.accept(s.first) and y_.accept(s.second);\n }\n\n bool successful(const State& s) const {\n return x_.successful(s.first) and y_.successful(s.second);\n }\n\n bool unsuccessful(const State& s) const {\n return x_.unsuccessful(s.first) or y_.unsuccessful(s.second);\n }\n\n private:\n X x_;\n Y y_;\n};\n\n// 0以上N以下の整数を受理するDFA\nclass Leq {\n public:\n using Alphabet = char;\n using State = Ordering;\n\n Leq(const string& n) : digits_(n.begin(), n.end()) {}\n\n State init() const {\n return State::Equal;\n }\n\n State next(State s, const Alphabet& a, size_t i) const {\n if (s == State::Greater) {\n return State::Greater;\n }\n\n if (s == State::Less) {\n return State::Less;\n }\n\n if (a < digits_[i]) {\n return State::Less;\n }\n\n if (a == digits_[i]) {\n return State::Equal;\n }\n\n return State::Greater;\n }\n\n bool accept(State s) const {\n return s != State::Greater;\n }\n\n bool successful(State s) const {\n return s == State::Less;\n }\n\n bool unsuccessful(State s) const {\n return s == State::Greater;\n }\n\n private:\n vector<char> digits_;\n};\n\n// 0以上N未満の整数を受理するDFA\nclass Le {\n public:\n using Alphabet = char;\n using State = Ordering;\n\n Le(const string& n) : digits_(n.begin(), n.end()) {}\n\n State init() const {\n return State::Equal;\n }\n\n State next(State s, const Alphabet& a, size_t i) const {\n if (s == State::Greater) {\n return State::Greater;\n }\n\n if (s == State::Less) {\n return State::Less;\n }\n\n if (a < digits_[i]) {\n return State::Less;\n }\n\n if (a == digits_[i]) {\n return State::Equal;\n }\n\n return State::Greater;\n }\n\n bool accept(State s) const {\n return s == State::Less;\n }\n\n bool successful(State s) const {\n return s == State::Less;\n }\n\n bool unsuccessful(State s) const {\n return s == State::Greater;\n }\n\n private:\n vector<char> digits_;\n};\n\n// Mの倍数を受理するDFA\nclass MultipleOf {\n public:\n using Alphabet = char;\n using State = int;\n\n MultipleOf(int m) : m_(m) {}\n\n State init() const {\n return 0;\n }\n\n State next(State s, const Alphabet& a, size_t i) const {\n return (s * 10 + (a - '0')) % m_;\n }\n\n bool accept(State s) const {\n return s == 0;\n }\n\n bool successful(State s) const {\n return s == 0;\n }\n\n bool unsuccessful(State s) const {\n return 0;\n }\n\n private:\n int m_;\n};\n\nclass LeadingZero {\n public:\n using Alphabet = char;\n using State = bool;\n\n LeadingZero() {}\n\n State init() const {\n return true;\n }\n\n State next(State s, const Alphabet& a, size_t i) const {\n return s and a == '0';\n }\n\n bool accept(State s) const {\n return !s;\n }\n\n bool successful(State s) const {\n return !s;\n }\n\n bool unsuccessful(State s) const {\n return 0;\n }\n};\n\ntemplate <typename DFA>\nlong long count_dfa(const DFA& dfa, size_t n, const vector<typename DFA::Alphabet>& alphabet) {\n using State = typename DFA::State;\n using S = long long;\n auto op = [](S a, S b) { return (a + b) % 10000; };\n auto e = S(0);\n\n unordered_map<State, S> dp;\n unordered_map<State, S> dp_next;\n\n dp.emplace(dfa.init(), 1);\n\n for (size_t i = 0; i < n; ++i) {\n dp_next.clear();\n for (const auto& [state, count] : dp) {\n for (const auto& a : alphabet) {\n State s1 = dfa.next(state, a, i);\n if (dfa.unsuccessful(s1)) continue;\n dp_next[s1] = (dp_next[s1] + count) % 10000;\n }\n }\n dp.swap(dp_next);\n }\n\n S res = 0;\n for (const auto& [state, count] : dp) {\n if (dfa.accept(state)) {\n res = op(res, count);\n }\n }\n\n return res;\n}\n\nstring decimalToBinary(const string& decimalStr) {\n if (decimalStr.empty()) return \"0\";\n string num = decimalStr;\n string binaryStr = \"\";\n while (num != \"0\") {\n int remainder = 0;\n string quotient = \"\";\n for (char ch : num) {\n int current = remainder * 10 + (ch - '0');\n if (!quotient.empty() || current / 2 != 0) {\n quotient += (current / 2) + '0';\n }\n remainder = current % 2;\n }\n binaryStr += (remainder ? '1' : '0');\n num = quotient.empty() ? \"0\" : quotient;\n }\n\n // 逆順にする\n reverse(binaryStr.begin(), binaryStr.end());\n return binaryStr.empty() ? \"0\" : binaryStr;\n}\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n vector<char> alphabet = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};\n string a, b;\n int m;\n in(a, b, m);\n if (a.size() < b.size()) {\n a = string(b.size() - a.size(), '0') + a;\n } else if (a.size() > b.size()) {\n b = string(a.size() - b.size(), '0') + b;\n }\n Dfa dfar = AndDfa(AndDfa(Leq(b), MultipleOf(m)), Zig());\n Dfa dfal = AndDfa(AndDfa(Le(a), MultipleOf(m)), Zig());\n int resr = count_dfa(dfar, b.size(), alphabet);\n int resl = count_dfa(dfal, a.size(), alphabet);\n out((resr - resl + 10000) % 10000);\n}", "accuracy": 1, "time_ms": 1420, "memory_kb": 4480, "score_of_the_acc": -0.6951, "final_rank": 18 }, { "submission_id": "aoj_0570_9613051", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring s;\nint n,m;\nint dp[502][501][10][2][2];////idx,mod,prev_digit,inc/dec,start digit\nint MOD=1e4;\n\nint count(int idx,int rem,int digit,int inc,int f){\n if(idx==n){\n return (!rem);\n }\n if(dp[idx][rem][digit][inc][f]!=-1)return dp[idx][rem][digit][inc][f];\n int ans=0;\n if(inc){\n int limit=9;\n if(!f)limit=s[idx]-'0';\n for(int d=0;d<=limit;d++){\n if(d>digit){\n ans+=count(idx+1,((rem*10)%m+d)%m,d,0,(d==s[idx]-'0')?f:1);\n ans%=MOD;\n }\n }\n }\n else{\n int limit=9;\n if(!f)limit=s[idx]-'0';\n for(int d=0;d<=limit;d++){\n if(d<digit){\n ans+=count(idx+1,((rem*10)%m+d)%m,d,1,(d==s[idx]-'0')?f:1);\n ans%=MOD;\n }\n }\n }\n return dp[idx][rem][digit][inc][f]=ans;\n\n}\n\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n\n string a,b;cin>>a>>b;\n cin>>m;\n s=b;\n n=b.length();\n int ans=0;\n memset(dp,-1, sizeof(dp));\n for(int i=0;i<n;i++){\n for(int d=1;d<=9;d++){\n if(!i){\n if(d<=s[0]-'0'){\n ans+=count(i+1,d%m,d,1,(d==s[0]-'0')?0:1);\n ans%=MOD;\n if(i!=n-1)ans+=count(i+1,d%m,d,0,(d==s[0]-'0')?0:1);\n ans%=MOD;\n }\n }\n else{\n ans+=count(i+1,d%m,d,1,1);\n ans%=MOD;\n if(i!=n-1)ans+=count(i+1,d%m,d,0,1);\n ans%=MOD;\n }\n }\n }\n memset(dp,-1,sizeof (dp));\n n=a.length();\n s=a;\n for(int i=0;i<n;i++){\n for(int d=1;d<=9;d++){\n if(!i){\n if(d<=s[0]-'0'){\n ans=ans-count(i+1,d%m,d,1,(d==s[0]-'0')?0:1)+MOD;\n ans%=MOD;\n if(i!=n-1)ans=ans-count(i+1,d%m,d,0,(d==s[0]-'0')?0:1)+MOD;\n ans%=MOD;\n }\n }\n else{\n ans=ans-count(i+1,d%m,d,1,1)+MOD;\n ans%=MOD;\n if(i!=n-1)ans=ans-count(i+1,d%m,d,0,1)+MOD;\n ans%=MOD;\n }\n }\n }\n if(n==1){\n if((a[0]-'0')%m==0)ans++;\n }\n else{\n int inc=1;\n if(a[1]>a[0])inc=0;\n int is_zigzag=1;\n int rem=(a[0]-'0');\n rem%=m;\n\n for (int i = 2; i < n; i++) {\n if(inc && a[i]<=a[i-1])\n is_zigzag=0;\n if(!inc && a[i]>=a[i-1])\n is_zigzag=0;\n rem*=10;\n rem+=(a[i]-'0');\n rem%=m;\n\n }\n is_zigzag=(is_zigzag & (!rem));\n ans+=is_zigzag;\n }\n cout<<ans%MOD<<endl;\n\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 42536, "score_of_the_acc": -0.3907, "final_rank": 10 }, { "submission_id": "aoj_0570_9554329", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\nusing vvvll=vector<vvll>;\nusing vvvvll=vector<vvvll>;\n\nll M;\n\nbool is_zigzag(string S){\n ll N=S.size();\n ll m=0;\n for(auto s:S)m=(m*10+s-'0')%M;\n if(m!=0)return 0;\n for(int j=0;j<2;j++){\n bool OK=1;\n for(int i=0;i<N-1;i++){\n if(S[i]==S[i+1])OK=0;\n if(i==N-2)continue;\n if(i%2==j){\n if(S[i]<=S[i+1]||S[i+1]>=S[i+2])OK=0;\n }\n else{\n if(S[i]>=S[i+1]||S[i+1]<=S[i+2])OK=0;\n }\n } \n if(OK)return 1;\n }\n return 0;\n}\n\nll f(string S){\n ll N=S.size();\n vvvll DP(10,vvll(M,vll(3,0)));\n auto DPJ=DP;\n for(int s=1;s<S[0]-'0';s++){\n DP[s][s%M][0]=1;\n }\n DPJ[S[0]-'0'][(S[0]-'0')%M][0]=1;\n //0未確定, 1: 直前で減少, 2: 直前で増加\n for(int i=1;i<N;i++){\n vvvll NDP(10,vvll(M,vll(3,0)));\n auto NDPJ=NDP;\n for(int n=1;n<10;n++){\n NDP[n][n%M][0]++;//i桁目が先頭\n }\n for(int n=0;n<10;n++){\n for(int d=0;d<10;d++){\n for(int m=0;m<M;m++){\n if(n==d)continue;\n int nm=(m*10+d)%M;\n if(d<S[i]-'0'){\n if(n>d){\n NDP[d][nm][1]+=DP[n][m][0]+DPJ[n][m][0];\n NDP[d][nm][1]+=DP[n][m][2]+DPJ[n][m][2];\n }\n else{\n NDP[d][nm][2]+=DP[n][m][0]+DPJ[n][m][0];\n NDP[d][nm][2]+=DP[n][m][1]+DPJ[n][m][1];\n }\n }\n else if(d==S[i]-'0'){\n if(n>d){\n NDP[d][nm][1]+=DP[n][m][0];\n NDPJ[d][nm][1]+=DPJ[n][m][0];\n NDP[d][nm][1]+=DP[n][m][2];\n NDPJ[d][nm][1]+=DPJ[n][m][2];\n }\n else{\n NDP[d][nm][2]+=DP[n][m][0];\n NDPJ[d][nm][2]+=DPJ[n][m][0];\n NDP[d][nm][2]+=DP[n][m][1];\n NDPJ[d][nm][2]+=DPJ[n][m][1];\n }\n }\n else{\n if(n>d){\n NDP[d][nm][1]+=DP[n][m][0];\n NDP[d][nm][1]+=DP[n][m][2];\n }\n else{\n NDP[d][nm][2]+=DP[n][m][0];\n NDP[d][nm][2]+=DP[n][m][1];\n }\n }\n for(int k=0;k<3;k++){\n NDP[d][nm][k]%=10000;\n NDPJ[d][nm][k]%=10000;\n }\n }\n }\n }\n swap(DP,NDP);\n swap(DPJ,NDPJ);\n }\n ll res=0;\n for(int d=0;d<10;d++){\n for(int k=0;k<3;k++){\n res+=DP[d][0][k]+DPJ[d][0][k];\n }\n }\n return res%10000;\n\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n string A,B;\n cin>>A>>B>>M;\n ll an=f(B)-f(A);\n if(is_zigzag(A))an++;\n cout<<(an+10000)%10000<<endl;\n}", "accuracy": 1, "time_ms": 1000, "memory_kb": 4460, "score_of_the_acc": -0.4751, "final_rank": 12 }, { "submission_id": "aoj_0570_8461542", "code_snippet": "#line 1 \"lib/mod/modint.hpp\"\n\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#line 1 \"lib/atcoder/internal_math.hpp\"\n\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n explicit barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n// @param n `n < 2^32`\n// @param m `1 <= m < 2^32`\n// @return sum_{i=0}^{n-1} floor((ai + b) / m) (mod 2^64)\nunsigned long long floor_sum_unsigned(unsigned long long n,\n unsigned long long m,\n unsigned long long a,\n unsigned long long b) {\n unsigned long long ans = 0;\n while (true) {\n if (a >= m) {\n ans += n * (n - 1) / 2 * (a / m);\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n unsigned long long y_max = a * n + b;\n if (y_max < m) break;\n // y_max < m * (n + 1)\n // floor(y_max / m) <= n\n n = (unsigned long long)(y_max / m);\n b = (unsigned long long)(y_max % m);\n std::swap(m, a);\n }\n return ans;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 1 \"lib/atcoder/internal_type_traits.hpp\"\n\n\n\n#line 7 \"lib/atcoder/internal_type_traits.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 14 \"lib/mod/modint.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static constexpr mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n constexpr static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n _v = (unsigned int)(v % umod());\n }\n\n constexpr unsigned int val() const { return _v; }\n\n constexpr mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n constexpr mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n constexpr mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n constexpr mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n constexpr mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n constexpr mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n constexpr mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n constexpr mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n constexpr mint operator+() const { return *this; }\n constexpr mint operator-() const { return mint() - *this; }\n\n constexpr mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n constexpr mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n constexpr friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n constexpr friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n constexpr friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n constexpr friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n constexpr friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n constexpr friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt(998244353);\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 2 \"main.cpp\"\nusing mint = atcoder::static_modint<10000>;\n#line 2 \"lib/prelude.hpp\"\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n// #pragma GCC target(\"avx2\")\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep2(i, m, n) for (auto i = (m); i < (n); i++)\n#define rep(i, n) rep2(i, 0, n)\n#define repr2(i, m, n) for (auto i = (n); i-- > (m);)\n#define repr(i, n) repr2(i, 0, n)\n#define all(x) begin(x), end(x)\ntemplate <class T> auto ndvec(int n, T e) { return vector(n, e); }\ntemplate <class... Ts> auto ndvec(int n, Ts... e) { return vector(n, ndvec(e...)); }\n#line 3 \"lib/util/seed.hpp\"\n\nauto seed() {\n#if defined(LOCAL) || defined(FIX_SEED)\n return 314169265258979;\n#endif\n return chrono::steady_clock::now().time_since_epoch().count();\n}\n#line 3 \"lib/util/rand.hpp\"\n\nuint32_t rand32() {\n static uint32_t x = seed();\n x ^= x << 13;\n x ^= x >> 17;\n x ^= x << 5;\n return x;\n}\n\nuint64_t rand64() {\n return uint64_t(rand32()) << 32 | rand32();\n}\n#line 3 \"lib/util/hash.hpp\"\n\n[[gnu::const]] uint64_t splitmix64(uint64_t x) {\n // http://xorshift.di.unimi.it/splitmix64.c\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n}\n\ntemplate <class T, class = void>\nstruct anti_hack_hash;\n\ntemplate <class T>\nstruct anti_hack_hash<T, enable_if_t<is_convertible_v<T, uint64_t>>> {\n size_t operator()(T x) const {\n static const uint64_t ofs = seed();\n return splitmix64((uint64_t)x + ofs);\n }\n};\n\ntemplate <class T>\nstruct anti_hack_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n static auto make_seed() {\n array<uint64_t, tuple_size_v<T>> res;\n res[0] = seed();\n rep(i, tuple_size_v<T> - 1) res[i + 1] = splitmix64(res[i]) + seed();\n return res;\n }\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res = splitmix64(\n res + anti_hack_hash<tuple_element_t<Is, T>>{}(get<Is>(x)))),\n ...);\n return res;\n }\n};\n#line 4 \"lib/ds/hash_map.hpp\"\n#include <ext/pb_ds/assoc_container.hpp>\n\ntemplate <class K, class V, class Hash = anti_hack_hash<K>>\nusing hash_map = __gnu_pbds::gp_hash_table<K, V, Hash>;\n#line 4 \"lib/dfa.hpp\"\n\nnamespace dfa {\n\nstruct dfa_default {\n using alphabet = char;\n template <class T>\n bool successful(T &&) const {\n return false;\n }\n template <class T>\n bool unsuccessful(T &&) const {\n return false;\n }\n};\n\nstruct leq_lt_base {\n const char *p;\n leq_lt_base(const char *p) : p(p) {}\n\n using alphabet = char;\n using state = signed char;\n state init() const { return 0; }\n state next(state s, alphabet a, int i) const {\n return s ? s : (a > p[i]) - (a < p[i]);\n }\n bool successful(state s) const { return s == -1; }\n bool unsuccessful(state s) const { return s == 1; }\n};\n\nstruct leq : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s != 1; }\n};\n\nstruct lt : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s == -1; }\n};\n\ntemplate <class X>\nstruct lnot : X {\n using X::X;\n bool accept(typename lnot::state s) const { return !X::accept(s); }\n bool successful(typename lnot::state s) const { return X::unsuccessful(s); }\n bool unsuccessful(typename lnot::state s) const { return X::successful(s); }\n};\n\ntemplate <class X, class... Xs>\nstruct land {\n tuple<X, Xs...> xs;\n land(X x, Xs... xs_) : xs(move(x), move(xs_)...) {}\n\n static_assert((is_same_v<typename X::alphabet, typename Xs::alphabet> &&\n ... && true));\n using alphabet = typename X::alphabet;\n using state = tuple<typename X::state, typename Xs::state...>;\n state init() const { return init(make_index_sequence<1 + sizeof...(Xs)>{}); }\n template <size_t... Is>\n state init(index_sequence<Is...>) const {\n return tuple(get<Is>(xs).init()...);\n }\n state next(state s, alphabet a, int i) const {\n return next(s, a, i, make_index_sequence<1 + sizeof...(Xs)>{});\n }\n template <size_t... Is>\n state next(state s, alphabet a, int i, index_sequence<Is...>) const {\n return tuple(get<Is>(xs).next(get<Is>(s), a, i)...);\n }\n bool accept(state s) const {\n return accept(s, make_index_sequence<1 + sizeof...(Xs)>{});\n }\n template <size_t... Is>\n bool accept(state s, index_sequence<Is...>) const {\n return (get<Is>(xs).accept(get<Is>(s)) && ... && true);\n }\n bool successful(state s) const {\n return successful(s, make_index_sequence<1 + sizeof...(Xs)>{});\n }\n template <size_t... Is>\n bool successful(state s, index_sequence<Is...>) const {\n return (get<Is>(xs).successful(get<Is>(s)) && ... && true);\n }\n bool unsuccessful(state s) const {\n return unsuccessful(s, make_index_sequence<1 + sizeof...(Xs)>{});\n }\n template <size_t... Is>\n bool unsuccessful(state s, index_sequence<Is...>) const {\n return (get<Is>(xs).unsuccessful(get<Is>(s)) || ... || false);\n }\n};\n\nconst string digits = \"0123456789\";\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT count(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, T> prv, nxt;\n // map<typename X::state, T> prv, nxt;\n nxt[dfa.init()] = T(1);\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) nxt[s2] += k;\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt)\n if (dfa.accept(s)) ans += k;\n return ans;\n}\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT sum(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, pair<T, T>> prv, nxt;\n nxt[dfa.init()] = pair(T(0), T(1));\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) {\n nxt[s2].first += k.first * 10 + (*p - '0') * k.second;\n nxt[s2].second += k.second;\n }\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt)\n if (dfa.accept(s)) ans += k.first;\n return ans;\n}\n\n} // namespace dfa\n#line 3 \"lib/dfa/multiple_of.hpp\"\n\nnamespace dfa {\n\ntemplate <class T>\nstruct multiple_of : dfa_default {\n T d;\n constexpr multiple_of(T d) : d(d) {}\n\n using alphabet = char;\n using state = T;\n state init() const { return 0; }\n state next(state s, alphabet a, int) const {\n return (s * 10 + (a - '0')) % d;\n }\n bool accept(state s) const { return s == 0; }\n};\n\n} // namespace dfa\n#line 3 \"lib/io.hpp\"\n\nstruct int1 {\n int val; int1(int a = 1) : val(a - 1) {}\n operator int() const { return val; }\n};\n\ntemplate <size_t BufSize = 1 << 26> class stdin_reader {\n public: stdin_reader() { buf[fread_unlocked(buf, 1, sizeof(buf), stdin)] = 0; } template <class T> enable_if_t<is_integral_v<T>> read(T& x) { skip(); [[maybe_unused]] bool neg = false; if constexpr (is_signed_v<T>) neg = *p == '-' ? (p++, true) : false; x = 0; while (*p > ' ') x = x * 10 + (*p++ & 0x0F); if constexpr (is_signed_v<T>) x = neg ? -x : x; } template <class T> void_t<decltype(&T::val)> read(T& x) { x = T((unsigned)(*this)); } void read(char*& q) { skip(); q = p; while (*p > ' ') p++; *p = 0; } template <size_t N> void read(char (&s)[N]) { read(s); } void read(string& s) { skip(); char* p0 = p; while (*p > ' ') p++; s.assign(p0, p); } template <class T, void_t<decltype(tuple_size<T>::value)>* = nullptr> void read(T& x) { read_tuple_impl(x, make_index_sequence<tuple_size_v<T>>{}); } template <class T, class U> void read(pair<T, U>& x) { read(x.first), read(x.second); } template <class T, size_t N> void read(T (&a)[N]) { for (auto& e : a) read(e); } template <class T> operator T() { T x; return read(x), x; } template <class... Ts> void operator()(Ts&... xs) { (read(xs), ...); } int operator--() { return (int)*this - 1; } template <class T> T* arr(int n) { T* p = new T[n + 1]; rep(i, n) read(p[i]); return p; } template <class T> void vec(vector<T>& v, int n) { v.resize(n); for (auto& e : v) read(e); } template <class T> vector<T> vec(int n) { vector<T> v; return vec(v, n), v; } template <class... Ts> tuple<vector<Ts>...> vecs(int n) { tuple<vector<Ts>...> res; vecs_impl(res, n, make_index_sequence<sizeof...(Ts)>{}); return res; } template <class T> void vvec(vector<vector<T>>& v, int n, int m) { v.resize(n); for (auto& e : v) vec(e, m); } template <class T> vector<vector<T>> vvec(int n, int m) { vector<vector<T>> v; return vvec(v, n, m), v; } template <class... Ts> auto cols(int n) { return transpose(vec<tuple<Ts...>>(n)); } private: char buf[BufSize], *p = buf; void skip() { while (*p <= ' ') p++; } template <class T, size_t... Is> void read_tuple_impl(T& x, index_sequence<Is...>) { (*this)(get<Is>(x)...); } template <class T, size_t... Is> void vecs_impl(T& x, int n, index_sequence<Is...>) { (vec(get<Is>(x), n), ...); } template <class T, size_t... Is> static auto transpose_impl(const vector<T>& v, index_sequence<Is...>) { tuple<vector<decay_t<tuple_element_t<Is, T>>>...> w; (get<Is>(w).reserve(v.size()), ...); for (const auto& row : v) (get<Is>(w).push_back(get<Is>(row)), ...); return w; } template <class T> static auto transpose(const vector<T>& v) { return transpose_impl(v, make_index_sequence<tuple_size_v<T>>{}); }\n};\ntemplate <size_t BufSize = 1 << 26> class stdout_writer {\n public: ~stdout_writer() { flush(); } void flush() { fwrite_unlocked(buf, 1, p - buf, stdout), p = buf; } void write_char(char c) { *p++ = c; } void write() {} void write(char c) { write_char(c); } template <class T> enable_if_t<is_integral_v<T>> write(T x) { if (!x) return write_char('0'); if constexpr (is_signed_v<T>) if (x < 0) write_char('-'), x = -x; static char tmp[16]; char* q = end(tmp); while (x >= 10000) memcpy(q -= 4, digits.data + x % 10000 * 4, 4), x /= 10000; if (x < 10) write_char('0' + x); else if (x < 100) write_char('0' + (uint8_t)x / 10), write_char('0' + (uint8_t)x % 10); else if (x < 1000) memcpy(p, digits.data + x * 4 + 1, 3), p += 3; else memcpy(p, digits.data + x * 4, 4), p += 4; memcpy(p, q, end(tmp) - q), p += end(tmp) - q; } template <class T> void_t<decltype(&T::val)> write(T x) { write(x.val()); } void write(double x) { static char tmp[40]; sprintf(tmp, \"%.15f\", x); write(tmp); } void write(const char* s) { while (*s) *p++ = *s++; } void write(const string& s) { memcpy(p, s.c_str(), s.size()), p += s.size(); } template <class T, class U> void write(const pair<T, U>& x) { write(x.first), write_char(' '), write(x.second); } template <class... Ts> void write(const tuple<Ts...>& x) { write_tuple(x, make_index_sequence<sizeof...(Ts)>{}); } template <class... Ts> void write(const Ts&... xs) { ((write(xs), write_char(' ')), ...), --p; } template <class... Ts> void writeln(const Ts&... xs) { write(xs...), write_char('\\n'); } template <class... Ts> void operator()(const Ts&... xs) { writeln(xs...); } template <class It> void iter(It first, It last, char sep = ' ') { if (first == last) write_char('\\n'); else { while (first != last) write(*first++), write_char(sep); p[-1] = '\\n'; } } void del() { *--p = 0; } void Yes(bool b = true) { writeln(b ? \"Yes\" : \"No\"); } void YES(bool b = true) { writeln(b ? \"YES\" : \"NO\"); } void Takahashi(bool b = true) { writeln(b ? \"Takahashi\" : \"Aoki\"); } private: char buf[BufSize], *p = buf; template <class T, size_t... Is> void write_tuple(const T& x, index_sequence<Is...>) { ((write(get<Is>(x)), write_char(' ')), ...), --p; } struct four_digits { char data[40000]; constexpr four_digits() : data() { for (int i = 0; i < 10000; i++) for (int n = i, j = 4; j--;) data[i * 4 + j] = n % 10 + '0', n /= 10; } } static constexpr digits{}; public:\n#define INSTANT(s) void s() { writeln(#s); }\n INSTANT(No) INSTANT(NO) INSTANT(Aoki) INSTANT(possible) INSTANT(Possible) INSTANT(POSSIBLE) INSTANT(impossible) INSTANT(Impossible) INSTANT(IMPOSSIBLE)\n#undef INSTANT\n};\nstdin_reader<> in;\nstdout_writer<> out;\n#line 5 \"main.cpp\"\n\nenum zig_state {\n INC,\n DEC,\n ZERO,\n INIT,\n FAIL,\n};\n\nstruct zig_zag : dfa::dfa_default {\n using state = pair<char, zig_state>;\n state init() const { return state('0', ZERO); }\n state next(state s, char c, int) const {\n switch (s.second) {\n case FAIL:\n return s;\n case ZERO:\n if (c == '0')\n return s;\n else\n return state(c, INIT);\n case INIT:\n return state(c, s.first < c ? INC : s.first > c ? DEC : FAIL);\n case INC:\n return state(c, s.first > c ? DEC : FAIL);\n case DEC:\n return state(c, s.first < c ? INC : FAIL);\n }\n assert(false);\n }\n bool accept(state s) const { return s.second != FAIL; }\n bool unsuccessful(state s) const { return s.second == FAIL; }\n};\n\nint main() {\n string A = in, B = in;\n int n = B.size();\n A.insert(0, n - A.size(), '0');\n int M = in;\n auto dfa = dfa::land(zig_zag(), dfa::multiple_of(M), dfa::leq(B.c_str()),\n dfa::lnot<dfa::lt>(A.c_str()));\n mint ans = dfa::count<mint>(dfa, B.size());\n out(ans.val());\n}", "accuracy": 1, "time_ms": 1090, "memory_kb": 7736, "score_of_the_acc": -0.5362, "final_rank": 15 }, { "submission_id": "aoj_0570_8461520", "code_snippet": "#line 1 \"lib/mod/modint.hpp\"\n\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#line 1 \"lib/atcoder/internal_math.hpp\"\n\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n explicit barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n// @param n `n < 2^32`\n// @param m `1 <= m < 2^32`\n// @return sum_{i=0}^{n-1} floor((ai + b) / m) (mod 2^64)\nunsigned long long floor_sum_unsigned(unsigned long long n,\n unsigned long long m,\n unsigned long long a,\n unsigned long long b) {\n unsigned long long ans = 0;\n while (true) {\n if (a >= m) {\n ans += n * (n - 1) / 2 * (a / m);\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n unsigned long long y_max = a * n + b;\n if (y_max < m) break;\n // y_max < m * (n + 1)\n // floor(y_max / m) <= n\n n = (unsigned long long)(y_max / m);\n b = (unsigned long long)(y_max % m);\n std::swap(m, a);\n }\n return ans;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 1 \"lib/atcoder/internal_type_traits.hpp\"\n\n\n\n#line 7 \"lib/atcoder/internal_type_traits.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 14 \"lib/mod/modint.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static constexpr mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n constexpr static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n _v = (unsigned int)(v % umod());\n }\n\n constexpr unsigned int val() const { return _v; }\n\n constexpr mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n constexpr mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n constexpr mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n constexpr mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n constexpr mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n constexpr mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n constexpr mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n constexpr mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n constexpr mint operator+() const { return *this; }\n constexpr mint operator-() const { return mint() - *this; }\n\n constexpr mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n constexpr mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n constexpr friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n constexpr friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n constexpr friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n constexpr friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n constexpr friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n constexpr friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt(998244353);\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 2 \"main.cpp\"\nusing mint = atcoder::static_modint<10000>;\n#line 2 \"lib/prelude.hpp\"\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n// #pragma GCC target(\"avx2\")\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep2(i, m, n) for (auto i = (m); i < (n); i++)\n#define rep(i, n) rep2(i, 0, n)\n#define repr2(i, m, n) for (auto i = (n); i-- > (m);)\n#define repr(i, n) repr2(i, 0, n)\n#define all(x) begin(x), end(x)\ntemplate <class T> auto ndvec(int n, T e) { return vector(n, e); }\ntemplate <class... Ts> auto ndvec(int n, Ts... e) { return vector(n, ndvec(e...)); }\n#line 3 \"lib/util/seed.hpp\"\n\nauto seed() {\n#if defined(LOCAL) || defined(FIX_SEED)\n return 314169265258979;\n#endif\n return chrono::steady_clock::now().time_since_epoch().count();\n}\n#line 3 \"lib/util/rand.hpp\"\n\nuint32_t rand32() {\n static uint32_t x = seed();\n x ^= x << 13;\n x ^= x >> 17;\n x ^= x << 5;\n return x;\n}\n\nuint64_t rand64() {\n return uint64_t(rand32()) << 32 | rand32();\n}\n#line 3 \"lib/util/hash.hpp\"\n\ntemplate <class T, class = void>\nstruct simple_hash : hash<T> {};\n\ntemplate <class T>\nstruct simple_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res ^= (res << 6) + (res >> 2) + 0x9e3779b9 +\n simple_hash<tuple_element_t<Is, T>>{}(get<Is>(x))),\n ...);\n return res;\n }\n};\n\nuint64_t splitmix64(uint64_t x) {\n // http://xorshift.di.unimi.it/splitmix64.c\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n}\n\ntemplate <class T, class = void>\nstruct anti_hack_hash;\n\ntemplate <class T>\nstruct anti_hack_hash<T, enable_if_t<is_convertible_v<T, uint64_t>>> {\n size_t operator()(T x) const {\n static const uint64_t ofs = seed();\n return splitmix64((uint64_t)x + ofs);\n }\n};\n\ntemplate <class T>\nstruct anti_hack_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n static auto make_seed() {\n array<uint64_t, tuple_size_v<T>> res;\n res[0] = seed();\n rep(i, tuple_size_v<T> - 1) res[i + 1] = splitmix64(res[i]) + seed();\n return res;\n }\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res = splitmix64(\n res + anti_hack_hash<tuple_element_t<Is, T>>{}(get<Is>(x)))),\n ...);\n return res;\n }\n};\n#line 4 \"lib/ds/hash_map.hpp\"\n#include <ext/pb_ds/assoc_container.hpp>\n\ntemplate <class K, class V, class Hash = simple_hash<K>>\nusing hash_map = __gnu_pbds::gp_hash_table<K, V, Hash>;\n#line 4 \"lib/dfa.hpp\"\n\nnamespace dfa {\n\nstruct dfa_default {\n using alphabet = char;\n template <class T>\n bool successful(T &&) const {\n return false;\n }\n template <class T>\n bool unsuccessful(T &&) const {\n return false;\n }\n};\n\nstruct leq_lt_base {\n const char *p;\n leq_lt_base(const char *p) : p(p) {}\n\n using alphabet = char;\n using state = signed char;\n state init() const { return 0; }\n state next(state s, alphabet a, int i) const {\n return s ? s : (a > p[i]) - (a < p[i]);\n }\n bool successful(state s) const { return s == -1; }\n bool unsuccessful(state s) const { return s == 1; }\n};\n\nstruct leq : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s != 1; }\n};\n\nstruct lt : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s == -1; }\n};\n\ntemplate <class X>\nstruct lnot : X {\n using X::X;\n bool accept(typename lnot::state s) const { return !X::accept(s); }\n bool successful(typename lnot::state s) const { return X::unsuccessful(s); }\n bool unsuccessful(typename lnot::state s) const { return X::successful(s); }\n};\n\ntemplate <class X, class Y>\nstruct land {\n X x;\n Y y;\n land(X x, Y y) : x(x), y(y) {}\n\n static_assert(is_same_v<typename X::alphabet, typename Y::alphabet>);\n using alphabet = typename X::alphabet;\n using state = pair<typename X::state, typename Y::state>;\n state init() const { return make_pair(x.init(), y.init()); }\n state next(state s, alphabet a, int i) const {\n return make_pair(x.next(s.first, a, i), y.next(s.second, a, i));\n }\n bool accept(state s) const {\n return x.accept(s.first) && y.accept(s.second);\n }\n bool successful(state s) const {\n return x.successful(s.first) && y.successful(s.second);\n }\n bool unsuccessful(state s) const {\n return x.unsuccessful(s.first) || y.unsuccessful(s.second);\n }\n};\n\nconst string digits = \"0123456789\";\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT count(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, T> prv, nxt;\n // map<typename X::state, T> prv, nxt;\n nxt[dfa.init()] = T(1);\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) nxt[s2] += k;\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k;\n return ans;\n}\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT sum(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, pair<T, T>, simple_hash<typename X::state>> prv, nxt;\n nxt[dfa.init()] = pair(T(0), T(1));\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) {\n nxt[s2].first += k.first * 10 + (*p-'0') * k.second;\n nxt[s2].second += k.second;\n }\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k.first;\n return ans;\n}\n\n} // namespace dfa\n#line 3 \"lib/dfa/multiple_of.hpp\"\n\nnamespace dfa {\n\ntemplate <class T>\nstruct multiple_of : dfa_default {\n T d;\n constexpr multiple_of(T d) : d(d) {}\n\n using alphabet = char;\n using state = T;\n state init() const { return 0; }\n state next(state s, alphabet a, int) const {\n return (s * 10 + (a - '0')) % d;\n }\n bool accept(state s) const { return s == 0; }\n};\n\n} // namespace dfa\n#line 3 \"lib/io.hpp\"\n\nstruct int1 {\n int val; int1(int a = 1) : val(a - 1) {}\n operator int() const { return val; }\n};\n\ntemplate <size_t BufSize = 1 << 26> class stdin_reader {\n public: stdin_reader() { buf[fread_unlocked(buf, 1, sizeof(buf), stdin)] = 0; } template <class T> enable_if_t<is_integral_v<T>> read(T& x) { skip(); [[maybe_unused]] bool neg = false; if constexpr (is_signed_v<T>) neg = *p == '-' ? (p++, true) : false; x = 0; while (*p > ' ') x = x * 10 + (*p++ & 0x0F); if constexpr (is_signed_v<T>) x = neg ? -x : x; } template <class T> void_t<decltype(&T::val)> read(T& x) { x = T((unsigned)(*this)); } void read(char*& q) { skip(); q = p; while (*p > ' ') p++; *p = 0; } template <size_t N> void read(char (&s)[N]) { read(s); } void read(string& s) { skip(); char* p0 = p; while (*p > ' ') p++; s.assign(p0, p); } template <class T, void_t<decltype(tuple_size<T>::value)>* = nullptr> void read(T& x) { read_tuple_impl(x, make_index_sequence<tuple_size_v<T>>{}); } template <class T, class U> void read(pair<T, U>& x) { read(x.first), read(x.second); } template <class T, size_t N> void read(T (&a)[N]) { for (auto& e : a) read(e); } template <class T> operator T() { T x; return read(x), x; } template <class... Ts> void operator()(Ts&... xs) { (read(xs), ...); } int operator--() { return (int)*this - 1; } template <class T> T* arr(int n) { T* p = new T[n + 1]; rep(i, n) read(p[i]); return p; } template <class T> void vec(vector<T>& v, int n) { v.resize(n); for (auto& e : v) read(e); } template <class T> vector<T> vec(int n) { vector<T> v; return vec(v, n), v; } template <class... Ts> tuple<vector<Ts>...> vecs(int n) { tuple<vector<Ts>...> res; vecs_impl(res, n, make_index_sequence<sizeof...(Ts)>{}); return res; } template <class T> void vvec(vector<vector<T>>& v, int n, int m) { v.resize(n); for (auto& e : v) vec(e, m); } template <class T> vector<vector<T>> vvec(int n, int m) { vector<vector<T>> v; return vvec(v, n, m), v; } template <class... Ts> auto cols(int n) { return transpose(vec<tuple<Ts...>>(n)); } private: char buf[BufSize], *p = buf; void skip() { while (*p <= ' ') p++; } template <class T, size_t... Is> void read_tuple_impl(T& x, index_sequence<Is...>) { (*this)(get<Is>(x)...); } template <class T, size_t... Is> void vecs_impl(T& x, int n, index_sequence<Is...>) { (vec(get<Is>(x), n), ...); } template <class T, size_t... Is> static auto transpose_impl(const vector<T>& v, index_sequence<Is...>) { tuple<vector<decay_t<tuple_element_t<Is, T>>>...> w; (get<Is>(w).reserve(v.size()), ...); for (const auto& row : v) (get<Is>(w).push_back(get<Is>(row)), ...); return w; } template <class T> static auto transpose(const vector<T>& v) { return transpose_impl(v, make_index_sequence<tuple_size_v<T>>{}); }\n};\ntemplate <size_t BufSize = 1 << 26> class stdout_writer {\n public: ~stdout_writer() { flush(); } void flush() { fwrite_unlocked(buf, 1, p - buf, stdout), p = buf; } void write_char(char c) { *p++ = c; } void write() {} void write(char c) { write_char(c); } template <class T> enable_if_t<is_integral_v<T>> write(T x) { if (!x) return write_char('0'); if constexpr (is_signed_v<T>) if (x < 0) write_char('-'), x = -x; static char tmp[16]; char* q = end(tmp); while (x >= 10000) memcpy(q -= 4, digits.data + x % 10000 * 4, 4), x /= 10000; if (x < 10) write_char('0' + x); else if (x < 100) write_char('0' + (uint8_t)x / 10), write_char('0' + (uint8_t)x % 10); else if (x < 1000) memcpy(p, digits.data + x * 4 + 1, 3), p += 3; else memcpy(p, digits.data + x * 4, 4), p += 4; memcpy(p, q, end(tmp) - q), p += end(tmp) - q; } template <class T> void_t<decltype(&T::val)> write(T x) { write(x.val()); } void write(double x) { static char tmp[40]; sprintf(tmp, \"%.15f\", x); write(tmp); } void write(const char* s) { while (*s) *p++ = *s++; } void write(const string& s) { memcpy(p, s.c_str(), s.size()), p += s.size(); } template <class T, class U> void write(const pair<T, U>& x) { write(x.first), write_char(' '), write(x.second); } template <class... Ts> void write(const tuple<Ts...>& x) { write_tuple(x, make_index_sequence<sizeof...(Ts)>{}); } template <class... Ts> void write(const Ts&... xs) { ((write(xs), write_char(' ')), ...), --p; } template <class... Ts> void writeln(const Ts&... xs) { write(xs...), write_char('\\n'); } template <class... Ts> void operator()(const Ts&... xs) { writeln(xs...); } template <class It> void iter(It first, It last, char sep = ' ') { if (first == last) write_char('\\n'); else { while (first != last) write(*first++), write_char(sep); p[-1] = '\\n'; } } void del() { *--p = 0; } void Yes(bool b = true) { writeln(b ? \"Yes\" : \"No\"); } void YES(bool b = true) { writeln(b ? \"YES\" : \"NO\"); } void Takahashi(bool b = true) { writeln(b ? \"Takahashi\" : \"Aoki\"); } private: char buf[BufSize], *p = buf; template <class T, size_t... Is> void write_tuple(const T& x, index_sequence<Is...>) { ((write(get<Is>(x)), write_char(' ')), ...), --p; } struct four_digits { char data[40000]; constexpr four_digits() : data() { for (int i = 0; i < 10000; i++) for (int n = i, j = 4; j--;) data[i * 4 + j] = n % 10 + '0', n /= 10; } } static constexpr digits{}; public:\n#define INSTANT(s) void s() { writeln(#s); }\n INSTANT(No) INSTANT(NO) INSTANT(Aoki) INSTANT(possible) INSTANT(Possible) INSTANT(POSSIBLE) INSTANT(impossible) INSTANT(Impossible) INSTANT(IMPOSSIBLE)\n#undef INSTANT\n};\nstdin_reader<> in;\nstdout_writer<> out;\n#line 5 \"main.cpp\"\n\nenum zig_state {\n INC,\n DEC,\n ZERO,\n INIT,\n FAIL,\n};\n\nstruct zig_zag : dfa::dfa_default {\n using state = pair<char, zig_state>;\n state init() const { return state('0', ZERO); }\n state next(state s, char c, int i) const {\n switch (s.second) {\n case FAIL:\n return s;\n case ZERO:\n if (c == '0')\n return s;\n else\n return state(c, INIT);\n case INIT:\n return state(c, s.first < c ? INC : s.first > c ? DEC : FAIL);\n case INC:\n return state(c, s.first > c ? DEC : FAIL);\n case DEC:\n return state(c, s.first < c ? INC : FAIL);\n }\n assert(false);\n }\n bool accept(state s) const { return s.second != FAIL; }\n bool unsuccessful(state s) const { return s.second == FAIL; }\n};\n\nint main() {\n string A = in, B = in;\n int n = B.size();\n A.insert(0, n - A.size(), '0');\n int M = in;\n auto dfa = dfa::land(zig_zag(),\n dfa::land(dfa::multiple_of(M),\n dfa::land(dfa::leq(B.c_str()),\n dfa::lnot<dfa::lt>(A.c_str()))));\n mint ans = dfa::count<mint>(dfa, B.size());\n out(ans.val());\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 7724, "score_of_the_acc": -0.3686, "final_rank": 9 }, { "submission_id": "aoj_0570_8461516", "code_snippet": "#line 1 \"lib/mod/modint.hpp\"\n\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#line 1 \"lib/atcoder/internal_math.hpp\"\n\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n explicit barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n// @param n `n < 2^32`\n// @param m `1 <= m < 2^32`\n// @return sum_{i=0}^{n-1} floor((ai + b) / m) (mod 2^64)\nunsigned long long floor_sum_unsigned(unsigned long long n,\n unsigned long long m,\n unsigned long long a,\n unsigned long long b) {\n unsigned long long ans = 0;\n while (true) {\n if (a >= m) {\n ans += n * (n - 1) / 2 * (a / m);\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n unsigned long long y_max = a * n + b;\n if (y_max < m) break;\n // y_max < m * (n + 1)\n // floor(y_max / m) <= n\n n = (unsigned long long)(y_max / m);\n b = (unsigned long long)(y_max % m);\n std::swap(m, a);\n }\n return ans;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 1 \"lib/atcoder/internal_type_traits.hpp\"\n\n\n\n#line 7 \"lib/atcoder/internal_type_traits.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 14 \"lib/mod/modint.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static constexpr mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n constexpr static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n _v = (unsigned int)(v % umod());\n }\n\n constexpr unsigned int val() const { return _v; }\n\n constexpr mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n constexpr mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n constexpr mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n constexpr mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n constexpr mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n constexpr mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n constexpr mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n constexpr mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n constexpr mint operator+() const { return *this; }\n constexpr mint operator-() const { return mint() - *this; }\n\n constexpr mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n constexpr mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n constexpr friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n constexpr friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n constexpr friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n constexpr friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n constexpr friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n constexpr friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt(998244353);\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 2 \"main.cpp\"\nusing mint = atcoder::static_modint<10000>;\n#line 2 \"lib/prelude.hpp\"\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n// #pragma GCC target(\"avx2\")\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep2(i, m, n) for (auto i = (m); i < (n); i++)\n#define rep(i, n) rep2(i, 0, n)\n#define repr2(i, m, n) for (auto i = (n); i-- > (m);)\n#define repr(i, n) repr2(i, 0, n)\n#define all(x) begin(x), end(x)\ntemplate <class T> auto ndvec(int n, T e) { return vector(n, e); }\ntemplate <class... Ts> auto ndvec(int n, Ts... e) { return vector(n, ndvec(e...)); }\n#line 3 \"lib/util/seed.hpp\"\n\nauto seed() {\n#if defined(LOCAL) || defined(FIX_SEED)\n return 314169265258979;\n#endif\n return chrono::steady_clock::now().time_since_epoch().count();\n}\n#line 3 \"lib/util/rand.hpp\"\n\nuint32_t rand32() {\n static uint32_t x = seed();\n x ^= x << 13;\n x ^= x >> 17;\n x ^= x << 5;\n return x;\n}\n\nuint64_t rand64() {\n return uint64_t(rand32()) << 32 | rand32();\n}\n#line 3 \"lib/util/hash.hpp\"\n\ntemplate <class T, class = void>\nstruct simple_hash : hash<T> {};\n\ntemplate <class T>\nstruct simple_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res ^=\n (res << 16) ^ simple_hash<tuple_element_t<Is, T>>{}(get<Is>(x))),\n ...);\n return res;\n }\n};\n\nuint64_t splitmix64(uint64_t x) {\n // http://xorshift.di.unimi.it/splitmix64.c\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n}\n\ntemplate <class T, class = void>\nstruct anti_hack_hash;\n\ntemplate <class T>\nstruct anti_hack_hash<T, enable_if_t<is_convertible_v<T, uint64_t>>> {\n size_t operator()(T x) const {\n static const uint64_t ofs = seed();\n return splitmix64((uint64_t)x + ofs);\n }\n};\n\ntemplate <class T>\nstruct anti_hack_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n static auto make_seed() {\n array<uint64_t, tuple_size_v<T>> res;\n res[0] = seed();\n rep(i, tuple_size_v<T> - 1) res[i + 1] = splitmix64(res[i]) + seed();\n return res;\n }\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res = splitmix64(\n res + anti_hack_hash<tuple_element_t<Is, T>>{}(get<Is>(x)))),\n ...);\n return res;\n }\n};\n#line 4 \"lib/ds/hash_map.hpp\"\n#include <ext/pb_ds/assoc_container.hpp>\n\ntemplate <class K, class V, class Hash = anti_hack_hash<K>>\nusing hash_map = __gnu_pbds::gp_hash_table<K, V, Hash>;\n#line 4 \"lib/dfa.hpp\"\n\nnamespace dfa {\n\nstruct dfa_default {\n using alphabet = char;\n template <class T>\n bool successful(T &&) const {\n return false;\n }\n template <class T>\n bool unsuccessful(T &&) const {\n return false;\n }\n};\n\nstruct leq_lt_base {\n const char *p;\n leq_lt_base(const char *p) : p(p) {}\n\n using alphabet = char;\n using state = signed char;\n state init() const { return 0; }\n state next(state s, alphabet a, int i) const {\n return s ? s : (a > p[i]) - (a < p[i]);\n }\n bool successful(state s) const { return s == -1; }\n bool unsuccessful(state s) const { return s == 1; }\n};\n\nstruct leq : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s != 1; }\n};\n\nstruct lt : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s == -1; }\n};\n\ntemplate <class X>\nstruct lnot : X {\n using X::X;\n bool accept(typename lnot::state s) const { return !X::accept(s); }\n bool successful(typename lnot::state s) const { return X::unsuccessful(s); }\n bool unsuccessful(typename lnot::state s) const { return X::successful(s); }\n};\n\ntemplate <class X, class Y>\nstruct land {\n X x;\n Y y;\n land(X x, Y y) : x(x), y(y) {}\n\n static_assert(is_same_v<typename X::alphabet, typename Y::alphabet>);\n using alphabet = typename X::alphabet;\n using state = pair<typename X::state, typename Y::state>;\n state init() const { return make_pair(x.init(), y.init()); }\n state next(state s, alphabet a, int i) const {\n return make_pair(x.next(s.first, a, i), y.next(s.second, a, i));\n }\n bool accept(state s) const {\n return x.accept(s.first) && y.accept(s.second);\n }\n bool successful(state s) const {\n return x.successful(s.first) && y.successful(s.second);\n }\n bool unsuccessful(state s) const {\n return x.unsuccessful(s.first) || y.unsuccessful(s.second);\n }\n};\n\nconst string digits = \"0123456789\";\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT count(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, T> prv, nxt;\n // map<typename X::state, T> prv, nxt;\n nxt[dfa.init()] = T(1);\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) nxt[s2] += k;\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k;\n return ans;\n}\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT sum(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, pair<T, T>, simple_hash<typename X::state>> prv, nxt;\n nxt[dfa.init()] = pair(T(0), T(1));\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) {\n nxt[s2].first += k.first * 10 + (*p-'0') * k.second;\n nxt[s2].second += k.second;\n }\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k.first;\n return ans;\n}\n\n} // namespace dfa\n#line 3 \"lib/dfa/multiple_of.hpp\"\n\nnamespace dfa {\n\ntemplate <class T>\nstruct multiple_of : dfa_default {\n T d;\n constexpr multiple_of(T d) : d(d) {}\n\n using alphabet = char;\n using state = T;\n state init() const { return 0; }\n state next(state s, alphabet a, int) const {\n return (s * 10 + (a - '0')) % d;\n }\n bool accept(state s) const { return s == 0; }\n};\n\n} // namespace dfa\n#line 3 \"lib/io.hpp\"\n\nstruct int1 {\n int val; int1(int a = 1) : val(a - 1) {}\n operator int() const { return val; }\n};\n\ntemplate <size_t BufSize = 1 << 26> class stdin_reader {\n public: stdin_reader() { buf[fread_unlocked(buf, 1, sizeof(buf), stdin)] = 0; } template <class T> enable_if_t<is_integral_v<T>> read(T& x) { skip(); [[maybe_unused]] bool neg = false; if constexpr (is_signed_v<T>) neg = *p == '-' ? (p++, true) : false; x = 0; while (*p > ' ') x = x * 10 + (*p++ & 0x0F); if constexpr (is_signed_v<T>) x = neg ? -x : x; } template <class T> void_t<decltype(&T::val)> read(T& x) { x = T((unsigned)(*this)); } void read(char*& q) { skip(); q = p; while (*p > ' ') p++; *p = 0; } template <size_t N> void read(char (&s)[N]) { read(s); } void read(string& s) { skip(); char* p0 = p; while (*p > ' ') p++; s.assign(p0, p); } template <class T, void_t<decltype(tuple_size<T>::value)>* = nullptr> void read(T& x) { read_tuple_impl(x, make_index_sequence<tuple_size_v<T>>{}); } template <class T, class U> void read(pair<T, U>& x) { read(x.first), read(x.second); } template <class T, size_t N> void read(T (&a)[N]) { for (auto& e : a) read(e); } template <class T> operator T() { T x; return read(x), x; } template <class... Ts> void operator()(Ts&... xs) { (read(xs), ...); } int operator--() { return (int)*this - 1; } template <class T> T* arr(int n) { T* p = new T[n + 1]; rep(i, n) read(p[i]); return p; } template <class T> void vec(vector<T>& v, int n) { v.resize(n); for (auto& e : v) read(e); } template <class T> vector<T> vec(int n) { vector<T> v; return vec(v, n), v; } template <class... Ts> tuple<vector<Ts>...> vecs(int n) { tuple<vector<Ts>...> res; vecs_impl(res, n, make_index_sequence<sizeof...(Ts)>{}); return res; } template <class T> void vvec(vector<vector<T>>& v, int n, int m) { v.resize(n); for (auto& e : v) vec(e, m); } template <class T> vector<vector<T>> vvec(int n, int m) { vector<vector<T>> v; return vvec(v, n, m), v; } template <class... Ts> auto cols(int n) { return transpose(vec<tuple<Ts...>>(n)); } private: char buf[BufSize], *p = buf; void skip() { while (*p <= ' ') p++; } template <class T, size_t... Is> void read_tuple_impl(T& x, index_sequence<Is...>) { (*this)(get<Is>(x)...); } template <class T, size_t... Is> void vecs_impl(T& x, int n, index_sequence<Is...>) { (vec(get<Is>(x), n), ...); } template <class T, size_t... Is> static auto transpose_impl(const vector<T>& v, index_sequence<Is...>) { tuple<vector<decay_t<tuple_element_t<Is, T>>>...> w; (get<Is>(w).reserve(v.size()), ...); for (const auto& row : v) (get<Is>(w).push_back(get<Is>(row)), ...); return w; } template <class T> static auto transpose(const vector<T>& v) { return transpose_impl(v, make_index_sequence<tuple_size_v<T>>{}); }\n};\ntemplate <size_t BufSize = 1 << 26> class stdout_writer {\n public: ~stdout_writer() { flush(); } void flush() { fwrite_unlocked(buf, 1, p - buf, stdout), p = buf; } void write_char(char c) { *p++ = c; } void write() {} void write(char c) { write_char(c); } template <class T> enable_if_t<is_integral_v<T>> write(T x) { if (!x) return write_char('0'); if constexpr (is_signed_v<T>) if (x < 0) write_char('-'), x = -x; static char tmp[16]; char* q = end(tmp); while (x >= 10000) memcpy(q -= 4, digits.data + x % 10000 * 4, 4), x /= 10000; if (x < 10) write_char('0' + x); else if (x < 100) write_char('0' + (uint8_t)x / 10), write_char('0' + (uint8_t)x % 10); else if (x < 1000) memcpy(p, digits.data + x * 4 + 1, 3), p += 3; else memcpy(p, digits.data + x * 4, 4), p += 4; memcpy(p, q, end(tmp) - q), p += end(tmp) - q; } template <class T> void_t<decltype(&T::val)> write(T x) { write(x.val()); } void write(double x) { static char tmp[40]; sprintf(tmp, \"%.15f\", x); write(tmp); } void write(const char* s) { while (*s) *p++ = *s++; } void write(const string& s) { memcpy(p, s.c_str(), s.size()), p += s.size(); } template <class T, class U> void write(const pair<T, U>& x) { write(x.first), write_char(' '), write(x.second); } template <class... Ts> void write(const tuple<Ts...>& x) { write_tuple(x, make_index_sequence<sizeof...(Ts)>{}); } template <class... Ts> void write(const Ts&... xs) { ((write(xs), write_char(' ')), ...), --p; } template <class... Ts> void writeln(const Ts&... xs) { write(xs...), write_char('\\n'); } template <class... Ts> void operator()(const Ts&... xs) { writeln(xs...); } template <class It> void iter(It first, It last, char sep = ' ') { if (first == last) write_char('\\n'); else { while (first != last) write(*first++), write_char(sep); p[-1] = '\\n'; } } void del() { *--p = 0; } void Yes(bool b = true) { writeln(b ? \"Yes\" : \"No\"); } void YES(bool b = true) { writeln(b ? \"YES\" : \"NO\"); } void Takahashi(bool b = true) { writeln(b ? \"Takahashi\" : \"Aoki\"); } private: char buf[BufSize], *p = buf; template <class T, size_t... Is> void write_tuple(const T& x, index_sequence<Is...>) { ((write(get<Is>(x)), write_char(' ')), ...), --p; } struct four_digits { char data[40000]; constexpr four_digits() : data() { for (int i = 0; i < 10000; i++) for (int n = i, j = 4; j--;) data[i * 4 + j] = n % 10 + '0', n /= 10; } } static constexpr digits{}; public:\n#define INSTANT(s) void s() { writeln(#s); }\n INSTANT(No) INSTANT(NO) INSTANT(Aoki) INSTANT(possible) INSTANT(Possible) INSTANT(POSSIBLE) INSTANT(impossible) INSTANT(Impossible) INSTANT(IMPOSSIBLE)\n#undef INSTANT\n};\nstdin_reader<> in;\nstdout_writer<> out;\n#line 5 \"main.cpp\"\n\nenum zig_state {\n INC,\n DEC,\n ZERO,\n INIT,\n FAIL,\n};\n\nstruct zig_zag : dfa::dfa_default {\n using state = pair<char, zig_state>;\n state init() const { return state('0', ZERO); }\n state next(state s, char c, int i) const {\n switch (s.second) {\n case FAIL:\n return s;\n case ZERO:\n if (c == '0')\n return s;\n else\n return state(c, INIT);\n case INIT:\n return state(c, s.first < c ? INC : s.first > c ? DEC : FAIL);\n case INC:\n return state(c, s.first > c ? DEC : FAIL);\n case DEC:\n return state(c, s.first < c ? INC : FAIL);\n }\n assert(false);\n }\n bool accept(state s) const { return s.second != FAIL; }\n bool unsuccessful(state s) const { return s.second == FAIL; }\n};\n\nint main() {\n string A = in, B = in;\n int n = B.size();\n A.insert(0, n - A.size(), '0');\n int M = in;\n auto dfa = dfa::land(zig_zag(),\n dfa::land(dfa::multiple_of(M),\n dfa::land(dfa::leq(B.c_str()),\n dfa::lnot<dfa::lt>(A.c_str()))));\n mint ans = dfa::count<mint>(dfa, B.size());\n out(ans.val());\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 7716, "score_of_the_acc": -0.5518, "final_rank": 17 }, { "submission_id": "aoj_0570_8461513", "code_snippet": "#line 1 \"lib/mod/modint.hpp\"\n\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n#line 1 \"lib/atcoder/internal_math.hpp\"\n\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n explicit barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n// @param n `n < 2^32`\n// @param m `1 <= m < 2^32`\n// @return sum_{i=0}^{n-1} floor((ai + b) / m) (mod 2^64)\nunsigned long long floor_sum_unsigned(unsigned long long n,\n unsigned long long m,\n unsigned long long a,\n unsigned long long b) {\n unsigned long long ans = 0;\n while (true) {\n if (a >= m) {\n ans += n * (n - 1) / 2 * (a / m);\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n unsigned long long y_max = a * n + b;\n if (y_max < m) break;\n // y_max < m * (n + 1)\n // floor(y_max / m) <= n\n n = (unsigned long long)(y_max / m);\n b = (unsigned long long)(y_max % m);\n std::swap(m, a);\n }\n return ans;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 1 \"lib/atcoder/internal_type_traits.hpp\"\n\n\n\n#line 7 \"lib/atcoder/internal_type_traits.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 14 \"lib/mod/modint.hpp\"\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static constexpr mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n constexpr static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n constexpr static_modint(T v) : _v() {\n _v = (unsigned int)(v % umod());\n }\n\n constexpr unsigned int val() const { return _v; }\n\n constexpr mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n constexpr mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n constexpr mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n constexpr mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n constexpr mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n constexpr mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n constexpr mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n constexpr mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n constexpr mint operator+() const { return *this; }\n constexpr mint operator-() const { return mint() - *this; }\n\n constexpr mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n constexpr mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n constexpr friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n constexpr friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n constexpr friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n constexpr friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n constexpr friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n constexpr friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt(998244353);\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#line 2 \"main.cpp\"\nusing mint = atcoder::static_modint<10000>;\n#line 2 \"lib/prelude.hpp\"\n#ifndef LOCAL\n#pragma GCC optimize(\"O3\")\n// #pragma GCC target(\"avx2\")\n#endif\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep2(i, m, n) for (auto i = (m); i < (n); i++)\n#define rep(i, n) rep2(i, 0, n)\n#define repr2(i, m, n) for (auto i = (n); i-- > (m);)\n#define repr(i, n) repr2(i, 0, n)\n#define all(x) begin(x), end(x)\ntemplate <class T> auto ndvec(int n, T e) { return vector(n, e); }\ntemplate <class... Ts> auto ndvec(int n, Ts... e) { return vector(n, ndvec(e...)); }\n#line 3 \"lib/util/seed.hpp\"\n\nauto seed() {\n#if defined(LOCAL) || defined(FIX_SEED)\n return 314169265258979;\n#endif\n return chrono::steady_clock::now().time_since_epoch().count();\n}\n#line 3 \"lib/util/rand.hpp\"\n\nuint32_t rand32() {\n static uint32_t x = seed();\n x ^= x << 13;\n x ^= x >> 17;\n x ^= x << 5;\n return x;\n}\n\nuint64_t rand64() {\n return uint64_t(rand32()) << 32 | rand32();\n}\n#line 3 \"lib/util/hash.hpp\"\n\ntemplate <class T, class = void>\nstruct simple_hash : hash<T> {};\n\ntemplate <class T>\nstruct simple_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n size_t res = 0;\n ((void)(res ^=\n (res << 16) ^ simple_hash<tuple_element_t<Is, T>>{}(get<Is>(x))),\n ...);\n return res;\n }\n};\n\nuint64_t splitmix64(uint64_t x) {\n // http://xorshift.di.unimi.it/splitmix64.c\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n}\n\ntemplate <class T, class = void>\nstruct anti_hack_hash;\n\ntemplate <class T>\nstruct anti_hack_hash<T, enable_if_t<is_convertible_v<T, uint64_t>>> {\n size_t operator()(T x) const {\n static const uint64_t ofs = seed();\n return splitmix64((uint64_t)x + ofs);\n }\n};\n\ntemplate <class T>\nstruct anti_hack_hash<T, void_t<decltype(tuple_size<T>::value)>> {\n size_t operator()(const T& x) const {\n return hash_impl(x, make_index_sequence<tuple_size_v<T>>{});\n }\n\n private:\n static auto make_seed() {\n array<uint64_t, tuple_size_v<T>> res;\n res[0] = seed();\n rep(i, tuple_size_v<T> - 1) res[i + 1] = splitmix64(res[i]) + seed();\n return res;\n }\n template <size_t... Is>\n static size_t hash_impl(const T& x, index_sequence<Is...>) {\n static auto seed = make_seed();\n size_t res = 0;\n ((void)(res = splitmix64(res + get<Is>(x) + get<Is>(seed))), ...);\n return res;\n }\n};\n#line 4 \"lib/ds/hash_map.hpp\"\n#include <ext/pb_ds/assoc_container.hpp>\n\ntemplate <class K, class V, class Hash = anti_hack_hash<K>>\nusing hash_map = __gnu_pbds::gp_hash_table<K, V, Hash>;\n#line 4 \"lib/dfa.hpp\"\n\nnamespace dfa {\n\nstruct dfa_default {\n using alphabet = char;\n template <class T>\n bool successful(T &&) const {\n return false;\n }\n template <class T>\n bool unsuccessful(T &&) const {\n return false;\n }\n};\n\nstruct leq_lt_base {\n const char *p;\n leq_lt_base(const char *p) : p(p) {}\n\n using alphabet = char;\n using state = signed char;\n state init() const { return 0; }\n state next(state s, alphabet a, int i) const {\n return s ? s : (a > p[i]) - (a < p[i]);\n }\n bool successful(state s) const { return s == -1; }\n bool unsuccessful(state s) const { return s == 1; }\n};\n\nstruct leq : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s != 1; }\n};\n\nstruct lt : leq_lt_base {\n using leq_lt_base::leq_lt_base;\n bool accept(state s) const { return s == -1; }\n};\n\ntemplate <class X>\nstruct lnot : X {\n using X::X;\n bool accept(typename lnot::state s) const { return !X::accept(s); }\n bool successful(typename lnot::state s) const { return X::unsuccessful(s); }\n bool unsuccessful(typename lnot::state s) const { return X::successful(s); }\n};\n\ntemplate <class X, class Y>\nstruct land {\n X x;\n Y y;\n land(X x, Y y) : x(x), y(y) {}\n\n static_assert(is_same_v<typename X::alphabet, typename Y::alphabet>);\n using alphabet = typename X::alphabet;\n using state = pair<typename X::state, typename Y::state>;\n state init() const { return make_pair(x.init(), y.init()); }\n state next(state s, alphabet a, int i) const {\n return make_pair(x.next(s.first, a, i), y.next(s.second, a, i));\n }\n bool accept(state s) const {\n return x.accept(s.first) && y.accept(s.second);\n }\n bool successful(state s) const {\n return x.successful(s.first) && y.successful(s.second);\n }\n bool unsuccessful(state s) const {\n return x.unsuccessful(s.first) || y.unsuccessful(s.second);\n }\n};\n\nconst string digits = \"0123456789\";\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT count(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n // hash_map<typename X::state, T> prv, nxt;\n map<typename X::state, T> prv, nxt;\n nxt[dfa.init()] = T(1);\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) nxt[s2] += k;\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k;\n return ans;\n}\n\ntemplate <class T, class X, class Iter = string::const_iterator>\nT sum(const X &dfa, int n, Iter alphabets_f = begin(digits),\n Iter alphabets_l = end(digits)) {\n hash_map<typename X::state, pair<T, T>, simple_hash<typename X::state>> prv, nxt;\n nxt[dfa.init()] = pair(T(0), T(1));\n rep(i, n) {\n prv = move(nxt);\n nxt.clear();\n for (auto [s, k] : prv) {\n rep2(p, alphabets_f, alphabets_l) {\n auto s2 = dfa.next(s, *p, i);\n if (!dfa.unsuccessful(s2)) {\n nxt[s2].first += k.first * 10 + (*p-'0') * k.second;\n nxt[s2].second += k.second;\n }\n }\n }\n }\n T ans(0);\n for (auto [s, k] : nxt) if (dfa.accept(s)) ans += k.first;\n return ans;\n}\n\n} // namespace dfa\n#line 3 \"lib/dfa/multiple_of.hpp\"\n\nnamespace dfa {\n\ntemplate <class T>\nstruct multiple_of : dfa_default {\n T d;\n constexpr multiple_of(T d) : d(d) {}\n\n using alphabet = char;\n using state = T;\n state init() const { return 0; }\n state next(state s, alphabet a, int) const {\n return (s * 10 + (a - '0')) % d;\n }\n bool accept(state s) const { return s == 0; }\n};\n\n} // namespace dfa\n#line 3 \"lib/io.hpp\"\n\nstruct int1 {\n int val; int1(int a = 1) : val(a - 1) {}\n operator int() const { return val; }\n};\n\ntemplate <size_t BufSize = 1 << 26> class stdin_reader {\n public: stdin_reader() { buf[fread_unlocked(buf, 1, sizeof(buf), stdin)] = 0; } template <class T> enable_if_t<is_integral_v<T>> read(T& x) { skip(); [[maybe_unused]] bool neg = false; if constexpr (is_signed_v<T>) neg = *p == '-' ? (p++, true) : false; x = 0; while (*p > ' ') x = x * 10 + (*p++ & 0x0F); if constexpr (is_signed_v<T>) x = neg ? -x : x; } template <class T> void_t<decltype(&T::val)> read(T& x) { x = T((unsigned)(*this)); } void read(char*& q) { skip(); q = p; while (*p > ' ') p++; *p = 0; } template <size_t N> void read(char (&s)[N]) { read(s); } void read(string& s) { skip(); char* p0 = p; while (*p > ' ') p++; s.assign(p0, p); } template <class T, void_t<decltype(tuple_size<T>::value)>* = nullptr> void read(T& x) { read_tuple_impl(x, make_index_sequence<tuple_size_v<T>>{}); } template <class T, class U> void read(pair<T, U>& x) { read(x.first), read(x.second); } template <class T, size_t N> void read(T (&a)[N]) { for (auto& e : a) read(e); } template <class T> operator T() { T x; return read(x), x; } template <class... Ts> void operator()(Ts&... xs) { (read(xs), ...); } int operator--() { return (int)*this - 1; } template <class T> T* arr(int n) { T* p = new T[n + 1]; rep(i, n) read(p[i]); return p; } template <class T> void vec(vector<T>& v, int n) { v.resize(n); for (auto& e : v) read(e); } template <class T> vector<T> vec(int n) { vector<T> v; return vec(v, n), v; } template <class... Ts> tuple<vector<Ts>...> vecs(int n) { tuple<vector<Ts>...> res; vecs_impl(res, n, make_index_sequence<sizeof...(Ts)>{}); return res; } template <class T> void vvec(vector<vector<T>>& v, int n, int m) { v.resize(n); for (auto& e : v) vec(e, m); } template <class T> vector<vector<T>> vvec(int n, int m) { vector<vector<T>> v; return vvec(v, n, m), v; } template <class... Ts> auto cols(int n) { return transpose(vec<tuple<Ts...>>(n)); } private: char buf[BufSize], *p = buf; void skip() { while (*p <= ' ') p++; } template <class T, size_t... Is> void read_tuple_impl(T& x, index_sequence<Is...>) { (*this)(get<Is>(x)...); } template <class T, size_t... Is> void vecs_impl(T& x, int n, index_sequence<Is...>) { (vec(get<Is>(x), n), ...); } template <class T, size_t... Is> static auto transpose_impl(const vector<T>& v, index_sequence<Is...>) { tuple<vector<decay_t<tuple_element_t<Is, T>>>...> w; (get<Is>(w).reserve(v.size()), ...); for (const auto& row : v) (get<Is>(w).push_back(get<Is>(row)), ...); return w; } template <class T> static auto transpose(const vector<T>& v) { return transpose_impl(v, make_index_sequence<tuple_size_v<T>>{}); }\n};\ntemplate <size_t BufSize = 1 << 26> class stdout_writer {\n public: ~stdout_writer() { flush(); } void flush() { fwrite_unlocked(buf, 1, p - buf, stdout), p = buf; } void write_char(char c) { *p++ = c; } void write() {} void write(char c) { write_char(c); } template <class T> enable_if_t<is_integral_v<T>> write(T x) { if (!x) return write_char('0'); if constexpr (is_signed_v<T>) if (x < 0) write_char('-'), x = -x; static char tmp[16]; char* q = end(tmp); while (x >= 10000) memcpy(q -= 4, digits.data + x % 10000 * 4, 4), x /= 10000; if (x < 10) write_char('0' + x); else if (x < 100) write_char('0' + (uint8_t)x / 10), write_char('0' + (uint8_t)x % 10); else if (x < 1000) memcpy(p, digits.data + x * 4 + 1, 3), p += 3; else memcpy(p, digits.data + x * 4, 4), p += 4; memcpy(p, q, end(tmp) - q), p += end(tmp) - q; } template <class T> void_t<decltype(&T::val)> write(T x) { write(x.val()); } void write(double x) { static char tmp[40]; sprintf(tmp, \"%.15f\", x); write(tmp); } void write(const char* s) { while (*s) *p++ = *s++; } void write(const string& s) { memcpy(p, s.c_str(), s.size()), p += s.size(); } template <class T, class U> void write(const pair<T, U>& x) { write(x.first), write_char(' '), write(x.second); } template <class... Ts> void write(const tuple<Ts...>& x) { write_tuple(x, make_index_sequence<sizeof...(Ts)>{}); } template <class... Ts> void write(const Ts&... xs) { ((write(xs), write_char(' ')), ...), --p; } template <class... Ts> void writeln(const Ts&... xs) { write(xs...), write_char('\\n'); } template <class... Ts> void operator()(const Ts&... xs) { writeln(xs...); } template <class It> void iter(It first, It last, char sep = ' ') { if (first == last) write_char('\\n'); else { while (first != last) write(*first++), write_char(sep); p[-1] = '\\n'; } } void del() { *--p = 0; } void Yes(bool b = true) { writeln(b ? \"Yes\" : \"No\"); } void YES(bool b = true) { writeln(b ? \"YES\" : \"NO\"); } void Takahashi(bool b = true) { writeln(b ? \"Takahashi\" : \"Aoki\"); } private: char buf[BufSize], *p = buf; template <class T, size_t... Is> void write_tuple(const T& x, index_sequence<Is...>) { ((write(get<Is>(x)), write_char(' ')), ...), --p; } struct four_digits { char data[40000]; constexpr four_digits() : data() { for (int i = 0; i < 10000; i++) for (int n = i, j = 4; j--;) data[i * 4 + j] = n % 10 + '0', n /= 10; } } static constexpr digits{}; public:\n#define INSTANT(s) void s() { writeln(#s); }\n INSTANT(No) INSTANT(NO) INSTANT(Aoki) INSTANT(possible) INSTANT(Possible) INSTANT(POSSIBLE) INSTANT(impossible) INSTANT(Impossible) INSTANT(IMPOSSIBLE)\n#undef INSTANT\n};\nstdin_reader<> in;\nstdout_writer<> out;\n#line 5 \"main.cpp\"\n\nenum zig_state {\n INC,\n DEC,\n ZERO,\n INIT,\n FAIL,\n};\n\nstruct zig_zag : dfa::dfa_default {\n using state = pair<char, zig_state>;\n state init() const { return state('0', ZERO); }\n state next(state s, char c, int i) const {\n switch (s.second) {\n case FAIL:\n return s;\n case ZERO:\n if (c == '0')\n return s;\n else\n return state(c, INIT);\n case INIT:\n return state(c, s.first < c ? INC : s.first > c ? DEC : FAIL);\n case INC:\n return state(c, s.first > c ? DEC : FAIL);\n case DEC:\n return state(c, s.first < c ? INC : FAIL);\n }\n assert(false);\n }\n bool accept(state s) const { return s.second != FAIL; }\n bool unsuccessful(state s) const { return s.second == FAIL; }\n};\n\nint main() {\n string A = in, B = in;\n int n = B.size();\n A.insert(0, n - A.size(), '0');\n int M = in;\n auto dfa = dfa::land(zig_zag(),\n dfa::land(dfa::multiple_of(M),\n dfa::land(dfa::leq(B.c_str()),\n dfa::lnot<dfa::lt>(A.c_str()))));\n mint ans = dfa::count<mint>(dfa, B.size());\n out(ans.val());\n}", "accuracy": 1, "time_ms": 2010, "memory_kb": 6644, "score_of_the_acc": -1.0132, "final_rank": 19 }, { "submission_id": "aoj_0570_7988213", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nconst int mod = 10000;\n\nvoid add(int &x, int y) {\n x += y;\n if (x >= mod) x -= mod;\n}\n\nint slv(string s, int m) {\n {\n reverse(s.begin(), s.end());\n while (s.size() and s.back() == '0') s.pop_back();\n reverse(s.begin(), s.end());\n if (s.size() == 0) return 0;\n }\n int n = s.size();\n // mod m, ラスト, s以下, ジグザグ\n vector<vector<vector<vector<int>>>> dp(m, vector<vector<vector<int>>> (10, vector<vector<int>> (2, vector<int>(3))));\n for (int i = 0; i < n; ++i) {\n vector<vector<vector<vector<int>>>> ndp(m, vector<vector<vector<int>>> (10, vector<vector<int>> (2, vector<int>(3))));\n if (i == 0) {\n for (int j = 1; j < s[0]-'0'; j++) {\n ndp[j%m][j][1][2] = 1;\n }\n ndp[(s[0]-'0')%m][s[0]-'0'][0][2] = 1;\n }\n else {\n for (int j = 1; j < 10; ++j) {\n ndp[j%m][j][1][2] = 1;\n }\n for (int j = 0; j < m; ++j) {\n for (int k = 0; k < 10; ++k) {\n for (int l = 0; l < 2; ++l) {\n for (int r = 0; r < 3; ++r) {\n if (!dp[j][k][l][r]) continue;\n for (int p = 0; p <= 9; ++p) {\n if (l == 0 and p > s[i]-'0') break;\n if (k == p) continue;\n int nl = l;\n if (l == 0 and p < (s[i]-'0')) nl = 1;\n int nr;\n if (r == 2) {\n if (k > p) nr = 0;\n else nr = 1;\n }\n else if (r == 0) {\n if (k < p) nr = 1;\n else continue;\n }\n else {\n if (k > p) nr = 0;\n else continue;\n }\n add(ndp[(j*10+p)%m][p][nl][nr], dp[j][k][l][r]);\n }\n }\n }\n }\n }\n }\n swap(dp, ndp);\n }\n int res = 0;\n for (int j = 0; j < 10; ++j) {\n for (int k = 0; k < 2; ++k) {\n for (int l = 0; l < 3; ++l) {\n add(res, dp[0][j][k][l]);\n }\n }\n }\n return res;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n string a,b; cin >> a >> b;\n int m; cin >> m;\n for (int i = a.size()-1; i >= 0; i--) {\n if (a[i] != '0') {\n a[i]--;\n for (int j = i+1; j < a.size(); j++) {\n a[j] = '9';\n }\n break;\n }\n }\n cout << (slv(b,m) - slv(a,m) + mod) % mod << endl;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 4876, "score_of_the_acc": -0.2884, "final_rank": 6 }, { "submission_id": "aoj_0570_7358668", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll; typedef unsigned long long ull;\nconst int inf = 1e9; const ll llnf = 4e18;\n\ntemplate< class Tp > void chkmax( Tp &x , Tp y ) { x = max( x , y ); }\ntemplate< class Tp > void chkmin( Tp &x , Tp y ) { x = min( x , y ); }\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param m `1 <= m`\n// @return x mod m\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\n// Fast modular multiplication by barrett reduction\n// Reference: https://en.wikipedia.org/wiki/Barrett_reduction\n// NOTE: reconsider after Ice Lake\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n // @param m `1 <= m < 2^31`\n barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n // @return m\n unsigned int umod() const { return _m; }\n\n // @param a `0 <= a < m`\n // @param b `0 <= b < m`\n // @return `a * b % m`\n unsigned int mul(unsigned int a, unsigned int b) const {\n // [1] m = 1\n // a = b = im = 0, so okay\n\n // [2] m >= 2\n // im = ceil(2^64 / m)\n // -> im * m = 2^64 + r (0 <= r < m)\n // let z = a*b = c*m + d (0 <= c, d < m)\n // a*b * im = (c*m + d) * im = c*(im*m) + d*im = c*2^64 + c*r + d*im\n // c*r + d*im < m * m + m * im < m * m + 2^64 + m <= 2^64 + m * (m + 1) < 2^64 * 2\n // ((ab * im) >> 64) == c or c + 1\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\n// @param n `0 <= n`\n// @param m `1 <= m`\n// @return `(x ** n) % m`\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\n// Reference:\n// M. Forisek and J. Jancina,\n// Fast Primality Testing for Integers That Fit into a Machine Word\n// @param n `0 <= n`\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\n// @param b `1 <= b`\n// @return pair(g, x) s.t. g = gcd(a, b), xa = g (mod b), 0 <= x < b/g\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n // Contracts:\n // [1] s - m0 * a = 0 (mod b)\n // [2] t - m1 * a = 0 (mod b)\n // [3] s * |m1| + t * |m0| <= b\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n // [3]:\n // (s - t * u) * |m1| + t * |m0 - m1 * u|\n // <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u)\n // = s * |m1| + t * |m0| <= b\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n // by [3]: |m0| <= b/g\n // by g != b: |m0| < b/g\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\n// Compile time primitive root\n// @param m must be prime\n// @return primitive root (and minimum in now)\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\n} // namespace internal\n\n} // namespace atcoder\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n static_modint(bool v) { _v = ((unsigned int)(v) % umod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n dynamic_modint(bool v) { _v = ((unsigned int)(v) % mod()); }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt = 998244353;\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\nusing modint = atcoder::static_modint< 10000 >;\n\nvoid solve( ) {\n\t// [ 0 , ... , s - l ] 中有多少个符合条件的数.\n\tauto calc = [&] ( string s , int k , int l ) -> modint {\n\t\tvector< vector< array< array< array< modint , 2 > , 3 > , 11 > > > dp( ( int ) s.size( ) , vector< array< array< array< modint , 2 > , 3 > , 11 > >( k ) );\n\t\tvector< vector< array< array< array< bool , 2 > , 3 > , 11 > > > vis( ( int ) s.size( ) , vector< array< array< array< bool , 2 > , 3 > , 11 > >( k ) );\n\t\tfor( int i = 0; i < ( int ) s.size( ); i ++ ) for( int u = 0; u < k; u ++ ) for( int v = -1; v < 10; v ++ ) for( int w = -1; w <= 1; w ++ ) for( int p = 0; p <= 1; p ++ )\n\t\t\tdp[i][u][v + 1][w + 1][p] = 0 , vis[i][u][v + 1][w + 1][p] = false;\n\n\t\tauto dfs = [&] ( auto dfs , int i , int u , int v , int w , int p ) -> modint {\n\t\t\tif( i == -1 ) return ( p && l ) ? ( 0 ) : ( ( !u ) ? ( 1 ) : ( 0 ) );\n\t\t\tif( vis[i][u][v + 1][w + 1][p] ) return dp[i][u][v + 1][w + 1][p];\n\n\t\t\tmodint ans = 0; int a = ( v == -1 ? 1 : 0 ) , b = ( p ? s[( int ) s.size( ) - i - 1] - '0' : 9 );\n\t\t\tfor( int c = a; c <= b; c ++ ) if( c != v && ( w == -1 || w == ( c < v ) ) )\n\t\t\t\tans += dfs( dfs , i - 1 , ( 10 * u + c ) % k , c , ( v == -1 ? -1 : c > v ) , p & ( c == b ) );\n\t\t\tif( v == -1 ) ans += dfs( dfs , i - 1 , 0 , -1 , -1 , false );\n\t\t\treturn vis[i][u][v + 1][w + 1][p] = true , dp[i][u][v + 1][w + 1][p] = ans;\n\t\t} ;\n\t\tmodint ans = dfs( dfs , ( int ) s.size( ) - 1 , 0 , -1 , -1 , true );\n\t\treturn ans;\n\t} ;\n\n\tstring L , R; int k; cin >> L >> R >> k;\n\tcout << ( calc( R , k , 0 ) - calc( L , k , 1 ) ).val( ) << \"\\n\";\n}\n\nint main( ) {\n\tios::sync_with_stdio( 0 ), cin.tie( 0 ), cout.tie( 0 );\n\tint T = 1; while( T -- ) solve( ); return 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 84200, "score_of_the_acc": -0.5415, "final_rank": 16 }, { "submission_id": "aoj_0570_7335510", "code_snippet": "#include<bits/stdc++.h>\n#define ll long long\n#define lll __int128\n#define db double\n#define ld long double\n#define pii pair<int,int>\n#define fi first\n#define se second\n#define vi vector<int>\nusing namespace std;\nnamespace IO\n{\n\tconst int SZ=1<<20;\n\tchar gchar()\n\t{\n\t static char buf[SZ];\n\t static int i=SZ;\n\t if(i==SZ)i=0,fread(buf,1,SZ,stdin);\n\t return buf[i++];\n\t}\n\tvoid pchar(char c)\n\t{\n\t static char buf[SZ];\n\t static int i=0;\n\t if(c)buf[i++]=c;\n\t if(!c||i==SZ)fwrite(buf,1,i,stdout),i=0;\n\t}\n\tvoid pstr(string s,char end='\\n')\n\t{\n\t\tfor(char c:s)pchar(c);\n\t\tpchar(end);\n\t}\n\ttemplate<typename T>void read(T &x)\n\t{\n\t x=0;int f=1;\n\t static char c;\n\t while((c=gchar())>'9'||c<'0')if(c=='-')f=-1;\n\t x=c-'0';\n\t while((c=gchar())>='0'&&c<='9')\n\t\t\tx=(x<<1)+(x<<3)+(c^48);\n\t\tx*=f;\n\t}\n\ttemplate<typename T,typename ...Args>void read(T &x,Args&...args){read(x),read(args...);}\n\ttemplate<typename T>void i_write(T x)\n\t{\n\t if(x>9)i_write(x/10);\n\t pchar(x%10+'0');\n\t}\n\ttemplate<typename T>void write(T x,char end='\\n')\n\t{\n\t if(x<0)pchar('-'),x=-x;\n\t if(x>9)i_write(x/10);\n\t pchar(x%10+'0');\n\t pchar(end);\n\t}\n}\nusing IO::read;\nusing IO::write;\nconst int N=510,mod=10000;\nint m,f[N][N][10][2][2][2],s[N];\nchar a[N],b[N];\nint dfs(int x,int r,int pr,int flg,int lim,int zer)\n{\n\tif(!x)return !r&&!zer;\n\tif(f[x][r][pr][flg][lim][zer]!=-1)return f[x][r][pr][flg][lim][zer];\n\tf[x][r][pr][flg][lim][zer]=0;int mx=lim?s[x]:9;\n\tfor(int i=0;i<=mx;i++)\n\t{\n\t\tif(!zer&&(i==pr||(i<pr)==flg))continue;\n\t\tf[x][r][pr][flg][lim][zer]=(f[x][r][pr][flg][lim][zer]+dfs(x-1,(r*10+i)%m,i,!flg,lim&&i==mx,zer&&!i))%mod;\n\t}\n\treturn f[x][r][pr][flg][lim][zer];\n}\nint main()\n{\n\tscanf(\"%s%s%d\",a+1,b+1,&m);int na=strlen(a+1),nb=strlen(b+1);\n\treverse(a+1,a+na+1),reverse(b+1,b+nb+1);\n\tfor(int i=1;i<=na;i++)s[i]=a[i]-'0';\n\ts[1]--;\n\tfor(int i=1;i<=na;i++)\n\t\tif(s[i]>=0)break;\n\t\telse s[i]+=10,s[i+1]--;\n\twhile(na&&!s[na])na--;\n\tint ans=0;\n\tif(na)\n\t{\n\t\tmemset(f,-1,sizeof(f));\n\t\tint res=(dfs(na,0,0,0,1,1)+dfs(na,0,0,1,1,1))%mod;\n\t\tfor(int i=1;i<=(na>1?9:s[1]);i++)res-=(i%m==0);\n\t\tans=(mod-res)%mod;\n\t}\n\tfor(int i=1;i<=nb;i++)s[i]=b[i]-'0';\n\tif(nb)\n\t{\n\t\tmemset(f,-1,sizeof(f));\n\t\tint res=(dfs(nb,0,0,0,1,1)+dfs(nb,0,0,1,1,1))%mod;\n\t\tfor(int i=1;i<=(nb>1?9:s[1]);i++)res-=(i%m==0);\n\t\tans=(ans+res)%mod;\n\t}\n\tprintf(\"%d\\n\",ans);\n\tIO::pchar(0);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 85492, "score_of_the_acc": -0.526, "final_rank": 14 }, { "submission_id": "aoj_0570_7323060", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int mod=10000;\nchar L[510],R[510];\nint p[510];\nint m,n,ans;\nint dp[510][510][10][4][2];\nint dfs(int x,int y,int i,int j,int k){\n\tif(x==n+1)return !y&&(j>0);\n\tif(dp[x][y][i][j][k]!=-1)return dp[x][y][i][j][k];\n\tint ans=0;\n\tif(j){for(int z=0;z<=(k?9:p[x]);z++)if(i!=z&&(j==1||((i<z)^(j-2))))(ans+=dfs(x+1,(y*10+z)%m,z,(2+(i<z)),(k||(z<p[x]))))%=mod;}\n\telse{\n\t\tfor(int z=0;z<=(k?9:p[x]);z++){\n\t\t\tif(!z)(ans+=dfs(x+1,0,0,0,(k||z<p[x])))%=mod;\n\t\t\telse (ans+=dfs(x+1,z%m,z,1,(k||z<p[x])))%=mod;\n\t\t}\n\t}\n\treturn dp[x][y][i][j][k]=ans;\n}\nint main(){\n\tscanf(\"%s%s%d\",L+1,R+1,&m);\n\tn=strlen(R+1);\n\tfor(int i=1;i<=n;i++)p[i]=R[i]-'0';\n\tmemset(dp,-1,sizeof(dp));\n\tint ans=dfs(1,0,0,0,0);\n\tn=strlen(L+1);\n\tfor(int i=1;i<=n;i++)p[i]=L[i]-'0';\n\tmemset(dp,-1,sizeof(dp));\n\t(ans-=dfs(1,0,0,0,0))%=mod;\n\tbool fl=1;\n\tfor(int i=1;i+2<=n;i++)fl&=((p[i]<p[i+1])^(p[i+1]<p[i+2]));\n\tfor(int i=1;i<n;i++)fl&=(p[i]!=p[i+1]);\n\tint X=0;\n\tfor(int i=1;i<=n;i++)X=(X*10+p[i])%m;\n\tfl&=(!X);\n\tif(fl)(ans+=1)%=mod;\n\treturn printf(\"%d\\n\",(ans+mod)%mod),0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 84872, "score_of_the_acc": -0.5077, "final_rank": 13 }, { "submission_id": "aoj_0570_7314565", "code_snippet": "/**\n * 百夜の悲しき、常闇に。\n * カヒコの来世を、統神に祷む。\n*/\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define inl // __attribute__((always_inline)) inline\ntemplate <typename T> inl bool read (T &x) {\n\tx = 0; int f = 1; char c = getchar ();\n\tfor (; c != EOF && !isdigit (c); c = getchar ())\n\t\tif (c == '-') f = -1;\n\tif (c == EOF) return 0;\n\tfor (; c != EOF && isdigit (c); c = getchar ())\n\t\tx = (x<<1) + (x<<3) + (c^48);\n\tx *= f; return 1;\n}\ntemplate <typename T, typename... Targs>\ninl bool read (T &x, Targs&... args) {\n\treturn read (x) && read (args...); }\ntemplate <typename T> void print (T x) {\n\tif (x < 0) putchar ('-'), x = -x;\n\tif (x > 9) print (x / 10);\n\tputchar ('0' + x % 10);\n}\ntemplate <typename T, typename... Targs>\ninl void print (T x, Targs... args) {\n\tprint (x), putchar (' '), print (args...); }\n\n#define newl putchar('\\n')\ntypedef long long ll;\n// typedef unsigned long long ull;\n// typedef __int128 lll;\n// typedef long double llf;\ntypedef pair <int, int> pint;\n#define fst first\n#define scd second\n#define all(p) begin (p), end (p)\n#define empb emplace_back\n\nconstexpr int N = 512, M = 512, P = 10000;\nint m, n1, n2; char s[N], t[N];\n\ninl bool zigzag (const char s[], int n) {\n\tfor (int x = 1; x < n; ++x)\n\t\tif (s[x] == s[x+1]) return 0;\n\tfor (int x = 2; x < n; ++x)\n\t\tif ((s[x]<s[x-1]) == (s[x+1]<s[x])) return 0;\n\treturn 1;\n}\ntemplate <bool incl_bd>\ninl int calc (char s[], int n) {\n\tif (n == 1) return (s[1]-'0')/m - !incl_bd*((s[1]-'0') % m == 0);\n\tstatic int f[M][10][2], _f[M][10][2];\n\tconst auto append = [&] (bool down, bool up, int pre, int lbd, int rbd) {\n\t\tfor (int d = lbd; d <= rbd; ++d)\n\t\t\t_f[(d + pre) % m][d][0] += down,\n\t\t\t_f[(d + pre) % m][d][1] += up;\n\t};\n\tmemset (f, 0, sizeof f); int pre = 0;\n\tfor (int i = 0, ok = 1, c, par = 1; i < n; ++i) {\n\t\tmemset (_f, 0, sizeof _f);\n\t\tc = s[i+1] - '0';\n\t\tappend (i < n-1, 1, 0, 1, !i ? c - 1 : 9);\n\t\tif (!ok || !i);\n\t\telse append (par, 0, pre*10, 0, min (c, s[i]-'0')-1),\n\t\t\tappend (0, i == 1 || !par, pre*10, s[i]-'0'+1, c-1);\n\t\tfor (int x = 0; x < m; ++x)\n\t\t\tfor (int d = 0; d < 10; ++d) {\n\t\t\t\tfor (int _d = d + 1; _d < 10; ++_d)\n\t\t\t\t\t_f[(x*10+_d)%m][_d][1] += f[x][d][0];\n\t\t\t\tfor (int _d = 0; _d < d; ++_d)\n\t\t\t\t\t_f[(x*10+_d)%m][_d][0] += f[x][d][1];\n\t\t\t}\n\t\tif (i) ok &= s[i] != s[i+1] && (i == 1\n\t\t\t|| (s[i+1]<s[i]) != (s[i]<s[i-1])),\n\t\t\tpar = s[i+1] > s[i];\n\t\tpre = (pre * 10 + c) % m;\n\t\tfor (int x = 0; x < m; ++x)\n\t\t\tfor (int d = 0; d < 10; ++d)\n\t\t\t\tf[x][d][0] = _f[x][d][0] % P,\n\t\t\t\tf[x][d][1] = _f[x][d][1] % P;\n\t}\n\treturn (zigzag (s, n) * !pre * incl_bd + accumulate (f[0], f[0] + 10,\n\t\t0ll, [] (int x, int *pt) { return x + pt[0] + pt[1]; })) % P;\n}\n\nint main () {\n\t/* */\n\t#ifdef LOCAL\n\tfreopen (\"Aizu0570.in\", \"r\", stdin);\n\tfreopen (\"Aizu0570.out\", \"w\", stdout);\n\t#endif\n\tscanf (\"%s%s%d\", s + 1, t + 1, &m);\n\tn1 = strlen (s + 1),\n\tn2 = strlen (t + 1);\n\tprint ((calc <1> (t, n2) + P-calc <0> (s, n1)) % P); newl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3536, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0570_7064250", "code_snippet": "/**\n * @FileName\ta.cpp\n * @Author\tkanpurin\n * @Created\t2022.10.30 05:49:47\n**/\n\n#include \"bits/stdc++.h\" \nusing namespace std; \ntypedef long long ll;\n\n\ntemplate< int MOD >\nstruct mint {\npublic:\n unsigned int x;\n mint() : x(0) {}\n mint(long long v) {\n long long w = (long long)(v % (long long)(MOD));\n if (w < 0) w += MOD;\n x = (unsigned int)(w);\n }\n mint(std::string &s) {\n unsigned int z = 0;\n for (int i = 0; i < s.size(); i++) {\n z *= 10;\n z += s[i] - '0';\n z %= MOD;\n }\n x = z;\n }\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n mint& operator+=(const mint &a) {\n if ((x += a.x) >= MOD) x -= MOD;\n return *this;\n }\n mint& operator-=(const mint &a) {\n if ((x -= a.x) >= MOD) x += MOD;\n return *this;\n }\n mint& operator*=(const mint &a) {\n unsigned long long z = x;\n z *= a.x;\n x = (unsigned int)(z % MOD);\n return *this;\n }\n mint& operator/=(const mint &a) {return *this = *this * a.inv(); }\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs.x == rhs.x;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs.x != rhs.x;\n }\n friend std::ostream& operator<<(std::ostream &os, const mint &n) {\n return os << n.x;\n }\n friend std::istream &operator>>(std::istream &is, mint &n) {\n unsigned int x;\n is >> x;\n n = mint(x);\n return is;\n }\n mint inv() const {\n assert(x);\n return pow(MOD-2);\n }\n mint pow(long long n) const { \n assert(0 <= n);\n mint p = *this, r = 1;\n while (n) {\n if (n & 1) r *= p;\n p *= p;\n n >>= 1;\n }\n return r;\n }\n \n mint sqrt() const {\n if (this->x < 2) return *this;\n if (this->pow((MOD-1)>>1).x != 1) return mint(0);\n mint b = 1, one = 1;\n while (b.pow((MOD-1) >> 1) == 1) b += one;\n long long m = MOD-1, e = 0;\n while (m % 2 == 0) m >>= 1, e += 1;\n mint x = this->pow((m - 1) >> 1);\n mint y = (*this) * x * x;\n x *= (*this);\n mint z = b.pow(m);\n while (y.x != 1) {\n int j = 0;\n mint t = y;\n while (t != one) j += 1, t *= t;\n z = z.pow(1LL << (e-j-1));\n x *= z; z *= z; y *= z; e = j;\n }\n return x;\n }\n};\n\nconstexpr int MOD = 10000;\n\nstruct Monoid {\n mint<MOD> val;\n bool undef = true;\n Monoid() { *this = zero(); }\n Monoid(long long val, bool undef = true) : val(val),\n undef(undef) {}\n static Monoid zero() { return Monoid(0); }\n static Monoid e() { return Monoid(1,false); }\n Monoid& operator+=(const Monoid &a) {\n if (this->undef) *this = a;\n else if (!a.undef) this->val += a.val;\n return *this;\n }\n Monoid& operator*=(int c) {\n return *this;\n }\n friend Monoid operator+(const Monoid& a, const Monoid& b) {\n return Monoid(a) += b;\n }\n friend Monoid operator*(const Monoid& a, int c) {\n return Monoid(a) *= c;\n }\n friend std::ostream& operator<<(std::ostream &os, const Monoid &x) {\n return os << x.val;\n }\n};\n\nstruct Automaton {\n vector<vector<int>> delta;\n vector<bool> is_accept, is_reject;\n int init;\n int alphabet_size = 10;\n int next(int state, int c) const { return delta[state][c]; }\n bool accept(int state) const { return is_accept[state]; }\n bool reject(int state) const { return is_reject[state]; }\n int size() const {return delta.size(); }\n};\n \ntemplate<class Automaton1, class Automaton2>\nAutomaton intersectionAutomaton(const Automaton1 &A, const Automaton2 &B) {\n assert(A.alphabet_size == B.alphabet_size);\n Automaton M;\n M.alphabet_size = A.alphabet_size;\n vector<vector<int>> table(A.size(), vector<int>(B.size(),-1));\n vector<int> x = {A.init}, y = {B.init};\n table[x[0]][y[0]] = 0;\n M.init = 0;\n for (int i = 0; i < x.size(); ++i) {\n M.delta.push_back(vector<int>(10, -1));\n M.is_accept.push_back(A.accept(x[i]) && B.accept(y[i]));\n M.is_reject.push_back(A.reject(x[i]) || B.reject(y[i]));\n for (int c = 0; c < A.alphabet_size; c++) {\n int u = A.next(x[i],c), v = B.next(y[i],c);\n if (table[u][v] == -1) {\n table[u][v] = x.size();\n x.push_back(u);\n y.push_back(v);\n }\n M.delta[i][c] = table[u][v];\n }\n }\n return M;\n}\n \nstruct ModuloAutomaton : Automaton {\nprivate:\n int mod;\n void set_init() { init = 0; }\n \n void set_delta() {\n int qsize = mod;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n for (int c = 0; c < alphabet_size; c++) {\n delta[state][c] = (state*10+c)%mod;\n }\n }\n }\n \n void set_is_accept() {\n int qsize = mod;\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = state == 0;\n }\n }\n \n void set_is_reject() {\n int qsize = mod;\n is_reject.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_reject[state] = false;\n }\n }\npublic:\n ModuloAutomaton(int mod, int alpha_size = 10) : mod(mod) {\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n \nstruct ZigZagAutomaton : Automaton {\nprivate:\n void set_init() { init = alphabet_size*3; }\n \n void set_delta() {\n int qsize = 2+alphabet_size*3;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n for (int c = 0; c < alphabet_size; c++) {\n if (state == alphabet_size*3) {\n if (c == 0)\n delta[state][c] = alphabet_size*3;\n else\n delta[state][c] = c;\n }\n else if (state < alphabet_size) {\n if (c < state)\n delta[state][c] = alphabet_size+c;\n else if (c > state)\n delta[state][c] = alphabet_size*2+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else if (state < alphabet_size*2) {\n if (c > state-alphabet_size)\n delta[state][c] = alphabet_size*2+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else if (state < alphabet_size*3) {\n if (c < state-alphabet_size*2)\n delta[state][c] = alphabet_size+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else {\n delta[state][c] = alphabet_size*3+1;\n }\n }\n }\n }\n \n void set_is_accept() {\n int qsize = size();\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = 0 <= state && state < alphabet_size*3;\n }\n }\n \n void set_is_reject() {\n int qsize = size();\n is_reject.resize(qsize);\n is_reject[alphabet_size*3+1] = true;\n }\npublic:\n ZigZagAutomaton(int alpha_size = 10) {\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n \ntemplate<typename Automaton>\nMonoid digitDP(const string &s, const Automaton &dfa, bool eq = 1) {\n vector<int> alpha(dfa.alphabet_size);\n iota(alpha.begin(), alpha.end(), 0);\n vector<vector<Monoid>> dp(2,vector<Monoid>(dfa.size(),Monoid::zero()));\n dp[1][dfa.init] = Monoid::e();\n for (int i = 0; i < s.size(); i++) {\n vector<vector<Monoid>> dp2(2,vector<Monoid>(dfa.size(),Monoid::zero()));\n for (int tight = 0; tight <= 1; tight++) {\n for (int state = 0; state < dfa.size(); state++) {\n if (dfa.reject(state) || dp[tight][state].undef) continue;\n int lim = (tight ? s[i] - '0' : dfa.alphabet_size - 1);\n for (int c = 0; c <= lim; c++) {\n int tight_ = tight && c == lim;\n int state_ = dfa.next(state,c);\n if (dfa.reject(state_)) continue;\n dp2[tight_][state_] += dp[tight][state]*c;\n }\n }\n }\n dp = dp2;\n }\n Monoid ans = Monoid::zero();\n for (int tight = 0; tight <= eq; tight++)\n for (int state = 0; state < dfa.size(); state++)\n if (dfa.accept(state)) ans += dp[tight][state];\n return ans;\n}\n\nmint<MOD> f(string &a,string &b,int m) {\n auto M1 = ZigZagAutomaton();\n auto M2 = ModuloAutomaton(m);\n auto M3 = intersectionAutomaton(M1,M2);\n return digitDP(b,M3).val-digitDP(a,M3,false).val;\n}\n \nint main() {\n string a,b;cin >> a >> b;\n int m;cin >> m;\n cout << f(a,b,m) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 4152, "score_of_the_acc": -0.055, "final_rank": 2 }, { "submission_id": "aoj_0570_7060616", "code_snippet": "/**\n * @FileName\ta.cpp\n * @Author\tkanpurin\n * @Created\t2022.10.28 10:52:42\n**/\n\n#include \"bits/stdc++.h\" \nusing namespace std; \ntypedef long long ll;\n\n\nstruct Monoid {\n ll val;\n Monoid identity() { return Monoid{0}; }\n friend Monoid operator+(const Monoid& l, const Monoid& r) {\n return Monoid{l.val + r.val};\n }\n friend Monoid operator*(const Monoid& l, const char c) {\n return l;\n }\n};\n\nstruct Automaton {\n vector<vector<int>> delta;\n vector<bool> is_accept, is_reject;\n int init;\n int alphabet_size = 10;\n int next(int state, int c) const { return delta[state][c]; }\n bool accept(int state) const { return is_accept[state]; }\n bool reject(int state) const { return is_reject[state]; }\n int size() const {return delta.size(); }\n};\n\ntemplate<class Automaton1, class Automaton2>\nAutomaton intersectionAutomaton(const Automaton1 &A, const Automaton2 &B) {\n assert(A.alphabet_size == B.alphabet_size);\n Automaton M;\n M.alphabet_size = A.alphabet_size;\n vector<vector<int>> table(A.size(), vector<int>(B.size(),-1));\n vector<int> x = {A.init}, y = {B.init};\n table[x[0]][y[0]] = 0;\n M.init = 0;\n for (int i = 0; i < x.size(); ++i) {\n M.delta.push_back(vector<int>(10, -1));\n M.is_accept.push_back(A.accept(x[i]) && B.accept(y[i]));\n M.is_reject.push_back(A.reject(x[i]) || B.reject(y[i]));\n for (int c = 0; c < A.alphabet_size; c++) {\n int u = A.next(x[i],c), v = B.next(y[i],c);\n if (table[u][v] == -1) {\n table[u][v] = x.size();\n x.push_back(u);\n y.push_back(v);\n }\n M.delta[i][c] = table[u][v];\n }\n }\n return M;\n}\n\nstruct LeqAutomaton : public Automaton {\nprivate:\n inline int _idx(int state) { return state/3; }\n inline int _comp(int state) { return state%3; }\n inline int tostate(int idx, int comp) { return idx*3+comp; }\n\n void set_init() { init = tostate(0,0); }\n\n void set_delta() {\n int qsize = (str.size()+1)*3;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n int idx = _idx(state);\n int comp = _comp(state);\n if (idx < str.size()) {\n if (comp == 0) {\n for (int c = 0; c < str[idx]-'0'; c++) \n delta[state][c] = tostate(idx+1,1);\n for (int c = str[idx]-'0'+1; c < alphabet_size; c++)\n delta[state][c] = tostate(idx+1,2);\n delta[state][str[idx]-'0'] = tostate(idx+1,0);\n }\n else if (comp == 1) {\n for (int c = 0; c < alphabet_size; c++)\n delta[state][c] = tostate(idx+1,1);\n }\n else if (comp == 2) {\n for (int c = 0; c < alphabet_size; c++)\n delta[state][c] = tostate(idx+1,2);\n }\n }\n else {\n for (int c = 0; c < alphabet_size; c++)\n delta[state][c] = tostate(str.size(),2);\n }\n }\n }\n\n void set_is_accept() {\n int qsize = (str.size()+1)*3;\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = _idx(state) == str.size() && _comp(state) != 2;\n }\n }\n\n void set_is_reject() {\n int qsize = (str.size()+1)*3;\n is_reject.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_reject[state] = _comp(state) == 2;\n }\n }\npublic:\n string str;\n\n LeqAutomaton(string s, int alpha_size = 10) {\n str = s;\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n\nstruct ModuloAutomaton : Automaton {\nprivate:\n int mod;\n void set_init() { init = 0; }\n\n void set_delta() {\n int qsize = mod;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n for (int c = 0; c < alphabet_size; c++) {\n delta[state][c] = (state*10+c)%mod;\n }\n }\n }\n\n void set_is_accept() {\n int qsize = mod;\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = state == 0;\n }\n }\n\n void set_is_reject() {\n int qsize = mod;\n is_reject.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_reject[state] = false;\n }\n }\npublic:\n ModuloAutomaton(int mod, int alpha_size = 10) : mod(mod) {\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n\nstruct SumOfDigitsAutomaton : Automaton {\nprivate:\n int mod;\n void set_init() { init = 0; }\n\n void set_delta() {\n int qsize = mod;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n for (int c = 0; c < alphabet_size; c++) {\n delta[state][c] = (state+c)%mod;\n }\n }\n }\n\n void set_is_accept() {\n int qsize = mod;\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = state == 0;\n }\n }\n\n void set_is_reject() {\n int qsize = mod;\n is_reject.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_reject[state] = false;\n }\n }\npublic:\n SumOfDigitsAutomaton(int mod, int alpha_size = 10) : mod(mod) {\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n\nstruct ZigZagAutomaton : Automaton {\nprivate:\n void set_init() { init = alphabet_size*3; }\n\n void set_delta() {\n int qsize = 2+alphabet_size*3;\n delta.resize(qsize,vector<int>(alphabet_size));\n for (int state = 0; state < qsize; state++) {\n for (int c = 0; c < alphabet_size; c++) {\n if (state == alphabet_size*3) {\n if (c == 0)\n delta[state][c] = alphabet_size*3;\n else\n delta[state][c] = c;\n }\n else if (state < alphabet_size) {\n if (c < state)\n delta[state][c] = alphabet_size+c;\n else if (c > state)\n delta[state][c] = alphabet_size*2+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else if (state < alphabet_size*2) {\n if (c > state-alphabet_size)\n delta[state][c] = alphabet_size*2+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else if (state < alphabet_size*3) {\n if (c < state-alphabet_size*2)\n delta[state][c] = alphabet_size+c;\n else\n delta[state][c] = alphabet_size*3+1;\n }\n else {\n delta[state][c] = alphabet_size*3+1;\n }\n }\n }\n }\n\n void set_is_accept() {\n int qsize = size();\n is_accept.resize(qsize);\n for (int state = 0; state < qsize; state++) {\n is_accept[state] = 0 <= state && state < alphabet_size*3;\n }\n }\n\n void set_is_reject() {\n int qsize = size();\n is_reject.resize(qsize);\n is_reject[alphabet_size*3+1] = true;\n }\npublic:\n ZigZagAutomaton(int alpha_size = 10) {\n alphabet_size = alpha_size;\n set_init();\n set_delta();\n set_is_accept();\n set_is_reject();\n }\n};\n\ntemplate<typename Value, typename Automaton>\nValue digitDP(int n, Value e, const Automaton &dfa) {\n struct T { Value val; };\n auto oplus = [&](const T &x, const T &y) -> T {\n return {x.val + y.val};\n };\n auto otimes = [&](const T &x, int c) {\n return x;\n };\n vector<int> alpha(dfa.alphabet_size);\n iota(alpha.begin(), alpha.end(), 0);\n unordered_map<int,T> dp,dp2;\n dp[dfa.init] = {e};\n for (int i = 0; i < n; i++) {\n for (auto [state,val] : dp) {\n for (int c : alpha) {\n auto n_state = dfa.next(state,c);\n if (dfa.reject(n_state)) continue;\n dp2[n_state] = oplus(dp2[n_state],otimes(dp[state],c));\n }\n }\n dp.swap(dp2); dp2.clear();\n }\n T ans;\n for (auto [state,val] : dp) {\n if (dfa.accept(state)) ans = oplus(ans,val);\n }\n return ans.val;\n}\n\ntemplate<typename Value, typename Automaton>\nValue digitDP(string s, Value e, const Automaton &dfa, bool eq = 1) {\n struct T { Value val; };\n auto oplus = [&](const T &x,const T &y) -> T {\n return {x.val + y.val};\n };\n auto otimes = [&](const T &x, int c) {\n return x;\n };\n vector<int> alpha(dfa.alphabet_size);\n iota(alpha.begin(), alpha.end(), 0);\n vector<vector<T>> dp(2,vector<T>(dfa.size()));\n dp[1][dfa.init] = {e};\n for (int i = 0; i < s.size(); i++) {\n vector<vector<T>> dp2(2,vector<T>(dfa.size()));\n for (int tight = 0; tight <= 1; tight++) {\n for (int state = 0; state < dfa.size(); state++) {\n if (dfa.reject(state)) continue;\n int lim = (tight ? s[i] - '0' : 9);\n for (int c = 0; c <= lim; c++) {\n int tight_ = tight && c == lim;\n int state_ = dfa.next(state,c);\n if (dfa.reject(state_)) continue;\n dp2[tight_][state_] = oplus(dp2[tight_][state_],otimes(dp[tight][state],c));\n }\n }\n }\n dp = dp2;\n }\n T ans;\n for (int tight = 0; tight <= eq; tight++) {\n for (int state = 0; state < dfa.size(); state++) {\n if (dfa.accept(state)) ans = oplus(ans,dp[tight][state]);\n }\n }\n return ans.val;\n}\n\ntemplate< int MOD >\nstruct mint {\npublic:\n unsigned int x;\n mint() : x(0) {}\n mint(long long v) {\n long long w = (long long)(v % (long long)(MOD));\n if (w < 0) w += MOD;\n x = (unsigned int)(w);\n }\n mint(std::string &s) {\n unsigned int z = 0;\n for (int i = 0; i < s.size(); i++) {\n z *= 10;\n z += s[i] - '0';\n z %= MOD;\n }\n x = z;\n }\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n mint& operator+=(const mint &a) {\n if ((x += a.x) >= MOD) x -= MOD;\n return *this;\n }\n mint& operator-=(const mint &a) {\n if ((x -= a.x) >= MOD) x += MOD;\n return *this;\n }\n mint& operator*=(const mint &a) {\n unsigned long long z = x;\n z *= a.x;\n x = (unsigned int)(z % MOD);\n return *this;\n }\n mint& operator/=(const mint &a) {return *this = *this * a.inv(); }\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs.x == rhs.x;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs.x != rhs.x;\n }\n friend std::ostream& operator<<(std::ostream &os, const mint &n) {\n return os << n.x;\n }\n friend std::istream &operator>>(std::istream &is, mint &n) {\n unsigned int x;\n is >> x;\n n = mint(x);\n return is;\n }\n mint inv() const {\n assert(x);\n return pow(MOD-2);\n }\n mint pow(long long n) const { \n assert(0 <= n);\n mint p = *this, r = 1;\n while (n) {\n if (n & 1) r *= p;\n p *= p;\n n >>= 1;\n }\n return r;\n }\n \n mint sqrt() const {\n if (this->x < 2) return *this;\n if (this->pow((MOD-1)>>1).x != 1) return mint(0);\n mint b = 1, one = 1;\n while (b.pow((MOD-1) >> 1) == 1) b += one;\n long long m = MOD-1, e = 0;\n while (m % 2 == 0) m >>= 1, e += 1;\n mint x = this->pow((m - 1) >> 1);\n mint y = (*this) * x * x;\n x *= (*this);\n mint z = b.pow(m);\n while (y.x != 1) {\n int j = 0;\n mint t = y;\n while (t != one) j += 1, t *= t;\n z = z.pow(1LL << (e-j-1));\n x *= z; z *= z; y *= z; e = j;\n }\n return x;\n }\n};\n\nconstexpr int MOD = 10000;\n\nint main() {\n string a,b;cin >> a >> b;\n int d;cin >> d;\n ZigZagAutomaton zigzag;\n ModuloAutomaton modulo(d);\n Automaton dfa = intersectionAutomaton(zigzag,modulo);\n cout << digitDP(b,mint<MOD>(1),dfa)-digitDP(a,mint<MOD>(1),dfa,false) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 4008, "score_of_the_acc": -0.0805, "final_rank": 3 }, { "submission_id": "aoj_0570_6221431", "code_snippet": "#include <bits/stdc++.h>\n#include <cassert>\ntypedef long long int ll;\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n#define REP2(i, a, b) for (ll i = (a); i < (b); i++)\n#define REP2R(i, a, b) for (ll i = (a); i >= (b); i--)\n#define REP(i, b) REP2(i, 0, b)\n#define ALL(coll) (coll).begin(), (coll).end()\n#define SIZE(v) ((ll)((v).size()))\n\n// @@ !! LIM(mod debug cmpNaive)\n\n// ---- inserted function f:gcd from util.cc\n\ntuple<ll, ll, ll> mut_div(ll a, ll b, ll c, bool eff_c = true) {\n // auto [g, s, t] = mut_div(a, b, c, eff_c)\n // If eff_c is true (default),\n // g == gcd(|a|, |b|) and as + bt == c, if such s,t exists\n // (g, s, t) == (-1, -1, -1) otherwise\n // If eff_c is false, \n // g == gcd(|a|, |b|) and as + bt == g \n // N.b. gcd(0, t) == gcd(t, 0) == t.\n if (a == 0) {\n if (eff_c) {\n if (c % b != 0) return {-1, -1, -1};\n else return {abs(b), 0, c / b};\n }else {\n if (b < 0) return {-b, 0, -1};\n else return { b, 0, 1};\n }\n }else {\n auto [g, t, u] = mut_div(b % a, a, c, eff_c);\n // DLOGK(b%a, a, c, g, t, u);\n if (g == -1) return {-1, -1, -1};\n return {g, u - (b / a) * t, t};\n }\n}\n\n// auto [g, s, t] = eGCD(a, b) ---> sa + tb == g == gcd(|a|, |b|)\n// N.b. gcd(0, t) == gcd(t, 0) == t.\ntuple<ll, ll, ll> eGCD(ll a, ll b) { return mut_div(a, b, 0, false); }\n\npair<ll, ll> crt_sub(ll a1, ll x1, ll a2, ll x2) {\n // DLOGKL(\"crt_sub\", a1, x1, a2, x2);\n a1 = a1 % x1;\n a2 = a2 % x2;\n auto [g, s, t] = mut_div(x1, -x2, a2 - a1);\n // DLOGK(g, s, t);\n if (g == -1) return {-1, -1};\n ll z = x1 / g * x2;\n // DLOGK(z);\n s = s % (x2 / g);\n ll r = (x1 * s + a1) % z;\n // DLOGK(r);\n if (r < 0) r += z;\n // DLOGK(r);\n return {r, z};\n};\n\n// Chinese Remainder Theorem\n//\n// r = crt(a1, x1, a2, x2)\n// ==> r = a1 (mod x1); r = a2 (mod x2); 0 <= r < lcm(x1, x2)\n// If no such r exists, returns -1\n// Note: x1 and x2 should >= 1. a1 and a2 can be negative or zero.\n//\n// r = crt(as, xs)\n// ==> for all i. r = as[i] (mod xs[i]); 0 <= r < lcm(xs)\n// If no such r exists, returns -1\n// Note: xs[i] should >= 1. as[i] can be negative or zero.\n// It should hold: len(xs) == len(as) > 0\n\nll crt(ll a1, ll x1, ll a2, ll x2) { return crt_sub(a1, x1, a2, x2).first; }\n\nll crt(vector<ll> as, vector<ll> xs) {\n // DLOGKL(\"crt\", as, xs);\n assert(xs.size() == as.size() && xs.size() > 0);\n ll r = as[0];\n ll z = xs[0];\n for (size_t i = 1; i < xs.size(); i++) {\n // DLOGK(i, r, z, as[i], xs[i]);\n tie(r, z) = crt_sub(r, z, as[i], xs[i]);\n // DLOGK(r, z);\n if (r == -1) return -1;\n }\n return r;\n}\n\n// ---- end f:gcd\n\n// ---- inserted library file mod.cc\n\ntemplate<int mod=0>\nstruct FpG { // G for General\n static ll dyn_mod;\n\n static ll getMod() {\n if (mod == 0) return dyn_mod;\n else return mod;\n }\n\n static void setMod(ll _mod) { // effective only when mod == 0\n dyn_mod = _mod;\n }\n\n static ll _conv(ll x) {\n if (x >= getMod()) return x % getMod();\n if (x >= 0) return x;\n if (x >= -getMod()) return x + getMod();\n ll y = x % getMod();\n if (y == 0) return 0;\n return y + getMod();\n }\n\n ll val;\n\n FpG(int t = 0) : val(_conv(t)) {}\n FpG(ll t) : val(_conv(t)) {}\n FpG(const FpG& t) : val(t.val) {}\n FpG& operator =(const FpG& t) { val = t.val; return *this; }\n FpG& operator =(ll t) { val = _conv(t); return *this; }\n FpG& operator =(int t) { val = _conv(t); return *this; }\n\n FpG& operator +=(const FpG& t) {\n val += t.val;\n if (val >= getMod()) val -= getMod();\n return *this;\n }\n\n FpG& operator -=(const FpG& t) {\n val -= t.val;\n if (val < 0) val += getMod();\n return *this;\n }\n\n FpG& operator *=(const FpG& t) {\n val = (val * t.val) % getMod();\n return *this;\n }\n\n FpG inv() const {\n if (val == 0) {\n throw runtime_error(\"FpG::inv(): called for zero.\");\n }\n auto [g, u, v] = eGCD(val, getMod());\n return FpG(u);\n }\n\n FpG& operator /=(const FpG& t) {\n return (*this) *= t.inv();\n }\n\n FpG operator +(const FpG& t) const { return FpG(val) += t; }\n FpG operator -(const FpG& t) const { return FpG(val) -= t; }\n FpG operator *(const FpG& t) const { return FpG(val) *= t; }\n FpG operator /(const FpG& t) const { return FpG(val) /= t; }\n FpG operator -() const { return FpG(-val); }\n\n bool operator ==(const FpG& t) const { return val == t.val; }\n bool operator !=(const FpG& t) const { return val != t.val; }\n \n operator ll() const { return val; }\n\n friend FpG operator +(int x, const FpG& y) { return FpG(x) + y; }\n friend FpG operator -(int x, const FpG& y) { return FpG(x) - y; }\n friend FpG operator *(int x, const FpG& y) { return FpG(x) * y; }\n friend FpG operator /(int x, const FpG& y) { return FpG(x) / y; }\n friend bool operator ==(int x, const FpG& y) { return FpG(x) == y; }\n friend bool operator !=(int x, const FpG& y) { return FpG(x) != y; }\n friend FpG operator +(ll x, const FpG& y) { return FpG(x) + y; }\n friend FpG operator -(ll x, const FpG& y) { return FpG(x) - y; }\n friend FpG operator *(ll x, const FpG& y) { return FpG(x) * y; }\n friend FpG operator /(ll x, const FpG& y) { return FpG(x) / y; }\n friend bool operator ==(ll x, const FpG& y) { return FpG(x) == y; }\n friend bool operator !=(ll x, const FpG& y) { return FpG(x) != y; }\n friend FpG operator +(const FpG& x, int y) { return x + FpG(y); }\n friend FpG operator -(const FpG& x, int y) { return x - FpG(y); }\n friend FpG operator *(const FpG& x, int y) { return x * FpG(y); }\n friend FpG operator /(const FpG& x, int y) { return x / FpG(y); }\n friend bool operator ==(const FpG& x, int y) { return x == FpG(y); }\n friend bool operator !=(const FpG& x, int y) { return x != FpG(y); }\n friend FpG operator +(const FpG& x, ll y) { return x + FpG(y); }\n friend FpG operator -(const FpG& x, ll y) { return x - FpG(y); }\n friend FpG operator *(const FpG& x, ll y) { return x * FpG(y); }\n friend FpG operator /(const FpG& x, ll y) { return x / FpG(y); }\n friend bool operator ==(const FpG& x, ll y) { return x == FpG(y); }\n friend bool operator !=(const FpG& x, ll y) { return x != FpG(y); }\n\n friend istream& operator>> (istream& is, FpG& t) {\n ll x; is >> x;\n t = x;\n return is;\n }\n\n friend ostream& operator<< (ostream& os, const FpG& t) {\n os << t.val;\n return os;\n }\n\n};\ntemplate<int mod>\nll FpG<mod>::dyn_mod;\n\ntemplate<int mod=0>\nclass CombG {\n int nMax;\n vector<FpG<mod>> vFact;\n vector<FpG<mod>> vInvFact;\npublic:\n CombG(int nm) : nMax(nm), vFact(nm+1), vInvFact(nm+1) {\n vFact.at(0) = 1;\n for (int i = 1; i <= nMax; i++) vFact.at(i) = i * vFact.at(i-1);\n vInvFact.at(nMax) = vFact.at(nMax).inv();\n for (int i = nMax; i >= 1; i--) vInvFact.at(i-1) = i * vInvFact.at(i);\n }\n FpG<mod> fact(int n) { return vFact.at(n); }\n FpG<mod> comb(int n, int r) {\n if (r < 0 || r > n) return 0;\n return vFact.at(n) * vInvFact.at(r) * vInvFact.at(n-r);\n }\n // The number of permutation extracting r from n.\n FpG<mod> perm(int n, int r) {\n return vFact.at(n) * vInvFact.at(n-r);\n }\n};\n\nconstexpr int primeA = 1'000'000'007;\nconstexpr int primeB = 998'244'353; // '\nusing FpA = FpG<primeA>;\nusing FpB = FpG<primeB>;\nusing CombA = CombG<primeA>;\nusing CombB = CombG<primeB>;\n\n// ---- end mod.cc\n\n// ---- inserted function f:<< from util.cc\ntemplate <typename T1, typename T2>\nostream& operator<< (ostream& os, const pair<T1,T2>& p) {\n os << \"(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\n\ntemplate <typename T1, typename T2, typename T3>\nostream& operator<< (ostream& os, const tuple<T1,T2,T3>& t) {\n os << \"(\" << get<0>(t) << \", \" << get<1>(t)\n << \", \" << get<2>(t) << \")\";\n return os;\n}\n\ntemplate <typename T1, typename T2, typename T3, typename T4>\nostream& operator<< (ostream& os, const tuple<T1,T2,T3,T4>& t) {\n os << \"(\" << get<0>(t) << \", \" << get<1>(t)\n << \", \" << get<2>(t) << \", \" << get<3>(t) << \")\";\n return os;\n}\n\ntemplate <typename T>\nostream& operator<< (ostream& os, const vector<T>& v) {\n os << '[';\n for (auto it = v.begin(); it != v.end(); it++) {\n if (it != v.begin()) os << \", \";\n os << *it;\n }\n os << ']';\n\n return os;\n}\n\ntemplate <typename T, typename C>\nostream& operator<< (ostream& os, const set<T, C>& v) {\n os << '{';\n for (auto it = v.begin(); it != v.end(); it++) {\n if (it != v.begin()) os << \", \";\n os << *it;\n }\n os << '}';\n\n return os;\n}\n\ntemplate <typename T, typename C>\nostream& operator<< (ostream& os, const unordered_set<T, C>& v) {\n os << '{';\n for (auto it = v.begin(); it != v.end(); it++) {\n if (it != v.begin()) os << \", \";\n os << *it;\n }\n os << '}';\n\n return os;\n}\n\ntemplate <typename T, typename C>\nostream& operator<< (ostream& os, const multiset<T, C>& v) {\n os << '{';\n for (auto it = v.begin(); it != v.end(); it++) {\n if (it != v.begin()) os << \", \";\n os << *it;\n }\n os << '}';\n\n return os;\n}\n\ntemplate <typename T1, typename T2, typename C>\nostream& operator<< (ostream& os, const map<T1, T2, C>& mp) {\n os << '[';\n for (auto it = mp.begin(); it != mp.end(); it++) {\n if (it != mp.begin()) os << \", \";\n os << it->first << \": \" << it->second;\n }\n os << ']';\n\n return os;\n}\n\ntemplate <typename T1, typename T2, typename C>\nostream& operator<< (ostream& os, const unordered_map<T1, T2, C>& mp) {\n os << '[';\n for (auto it = mp.begin(); it != mp.end(); it++) {\n if (it != mp.begin()) os << \", \";\n os << it->first << \": \" << it->second;\n }\n os << ']';\n\n return os;\n}\n\ntemplate <typename T, typename T2>\nostream& operator<< (ostream& os, const queue<T, T2>& orig) {\n queue<T, T2> que(orig);\n bool first = true;\n os << '[';\n while (!que.empty()) {\n T x = que.front(); que.pop();\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n return os << ']';\n}\n\ntemplate <typename T, typename T2>\nostream& operator<< (ostream& os, const deque<T, T2>& orig) {\n deque<T, T2> que(orig);\n bool first = true;\n os << '[';\n while (!que.empty()) {\n T x = que.front(); que.pop_front();\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n return os << ']';\n}\n\ntemplate <typename T, typename T2, typename T3>\nostream& operator<< (ostream& os, const priority_queue<T, T2, T3>& orig) {\n priority_queue<T, T2, T3> pq(orig);\n bool first = true;\n os << '[';\n while (!pq.empty()) {\n T x = pq.top(); pq.pop();\n if (!first) os << \", \";\n os << x;\n first = false;\n }\n return os << ']';\n}\n\ntemplate <typename T>\nostream& operator<< (ostream& os, const stack<T>& st) {\n stack<T> tmp(st);\n os << '[';\n bool first = true;\n while (!tmp.empty()) {\n T& t = tmp.top();\n if (first) first = false;\n else os << \", \";\n os << t;\n tmp.pop();\n }\n os << ']';\n return os;\n}\n\n#if __cplusplus >= 201703L\ntemplate <typename T>\nostream& operator<< (ostream& os, const optional<T>& t) {\n if (t.has_value()) os << \"v(\" << t.value() << \")\";\n else os << \"nullopt\";\n return os;\n}\n#endif\n\nostream& operator<< (ostream& os, int8_t x) {\n os << (int32_t)x;\n return os;\n}\n\n// ---- end f:<<\n\n// ---- inserted library file debug.cc\ntemplate <class... Args>\nstring dbgFormat(const char* fmt, Args... args) {\n size_t len = snprintf(nullptr, 0, fmt, args...);\n char buf[len + 1];\n snprintf(buf, len + 1, fmt, args...);\n return string(buf);\n}\n\ntemplate <class Head>\nvoid dbgLog(bool with_nl, Head&& head) {\n cerr << head;\n if (with_nl) cerr << endl;\n}\n\ntemplate <class Head, class... Tail>\nvoid dbgLog(bool with_nl, Head&& head, Tail&&... tail)\n{\n cerr << head << \" \";\n dbgLog(with_nl, forward<Tail>(tail)...);\n}\n\n#if DEBUG\n #define DLOG(...) dbgLog(true, __VA_ARGS__)\n #define DLOGNNL(...) dbgLog(false, __VA_ARGS__)\n #define DFMT(...) cerr << dbgFormat(__VA_ARGS__) << endl\n #define DCALL(func, ...) func(__VA_ARGS__)\n#else\n #define DLOG(...)\n #define DLOGNNL(...)\n #define DFMT(...)\n #define DCALL(func, ...)\n#endif\n\n/*\n#if DEBUG_LIB\n #define DLOG_LIB(...) dbgLog(true, __VA_ARGS__)\n #define DLOGNNL_LIB(...) dbgLog(false, __VA_ARGS__)\n #define DFMT_LIB(...) cerr << dbgFormat(__VA_ARGS__) << endl\n #define DCALL_LIB(func, ...) func(__VA_ARGS__)\n#else\n #define DLOG_LIB(...)\n #define DFMT_LIB(...)\n #define DCALL_LIB(func, ...)\n#endif\n*/\n\n#define DUP1(E1) #E1 \"=\", E1\n#define DUP2(E1,E2) DUP1(E1), DUP1(E2)\n#define DUP3(E1,...) DUP1(E1), DUP2(__VA_ARGS__)\n#define DUP4(E1,...) DUP1(E1), DUP3(__VA_ARGS__)\n#define DUP5(E1,...) DUP1(E1), DUP4(__VA_ARGS__)\n#define DUP6(E1,...) DUP1(E1), DUP5(__VA_ARGS__)\n#define DUP7(E1,...) DUP1(E1), DUP6(__VA_ARGS__)\n#define DUP8(E1,...) DUP1(E1), DUP7(__VA_ARGS__)\n#define DUP9(E1,...) DUP1(E1), DUP8(__VA_ARGS__)\n#define DUP10(E1,...) DUP1(E1), DUP9(__VA_ARGS__)\n#define DUP11(E1,...) DUP1(E1), DUP10(__VA_ARGS__)\n#define DUP12(E1,...) DUP1(E1), DUP11(__VA_ARGS__)\n#define GET_MACRO(_1,_2,_3,_4,_5,_6,_7,_8,_9,_10,_11,_12,NAME,...) NAME\n#define DUP(...) GET_MACRO(__VA_ARGS__, DUP12, DUP11, DUP10, DUP9, DUP8, DUP7, DUP6, DUP5, DUP4, DUP3, DUP2, DUP1)(__VA_ARGS__)\n#define DLOGK(...) DLOG(DUP(__VA_ARGS__))\n#define DLOGKL(lab, ...) DLOG(lab, DUP(__VA_ARGS__))\n\n#if DEBUG_LIB\n #define DLOG_LIB DLOG\n #define DLOGK_LIB DLOGK\n #define DLOGKL_LIB DLOGKL\n#endif\n\n// ---- end debug.cc\n\n// ---- inserted library file cmpNaive.cc\n\nconst string end_mark(\"^__=end=__^\");\n\nint naive(istream& cin, ostream& cout);\nint body(istream& cin, ostream& cout);\n\nvoid cmpNaive() {\n while (true) {\n string s;\n getline(cin, s);\n bool run_body;\n if (s.at(0) == 'Q') {\n return;\n }else if (s.at(0) == 'B') {\n run_body = true;\n }else if (s.at(0) == 'N') {\n run_body = false;\n }else {\n cerr << \"Unknown body/naive specifier.\\n\";\n exit(1);\n }\n string input_s;\n while (true) {\n getline(cin, s);\n if (s == end_mark) break;\n input_s += s;\n input_s += \"\\n\";\n }\n stringstream ss_in(move(input_s));\n stringstream ss_out;\n if (run_body) {\n body(ss_in, ss_out);\n }else {\n naive(ss_in, ss_out);\n }\n cout << ss_out.str() << end_mark << endl;\n }\n}\n\nint main(int argc, char *argv[]) {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n\n#if CMPNAIVE\n if (argc == 2) {\n if (strcmp(argv[1], \"cmpNaive\") == 0) {\n cmpNaive();\n }else if (strcmp(argv[1], \"naive\") == 0) {\n naive(cin, cout);\n }else if (strcmp(argv[1], \"skip\") == 0) {\n exit(0);\n }else {\n cerr << \"Unknown argument.\\n\";\n exit(1);\n }\n }else {\n#endif\n body(cin, cout);\n#if CMPNAIVE\n }\n#endif\n return 0;\n}\n\n/*\nint naive(istream& cin, ostream& cout) {\n return 0;\n}\nint body(istream& cin, ostream& cout) {\n return 0;\n}\n*/\n\n// ---- end cmpNaive.cc\n\n// @@ !! LIM -- end mark --\n\nusing Fp = FpG<10000>;\n\nint naive(istream& cin, ostream& cout) {\n ll A, B; cin >> A >> B;\n ll M; cin >> M;\n\n auto check = [&](ll x) -> bool {\n if (x % M != 0) return false;\n if (x == 0) return true;\n vector<ll> v;\n ll m = x;\n while (m > 0) {\n v.push_back(m % 10);\n m /= 10;\n }\n ll sz = SIZE(v);\n REP(i, sz - 1) {\n if (v[i] == v[i + 1]) return false;\n if (i - 1 >= 0 and (v[i] < v[i + 1]) == (v[i - 1] < v[i])) return false;\n }\n return true;\n };\n\n ll ans = 0;\n REP2(x, A, B + 1) if (check(x)) ans++;\n cout << ans % 10000 << endl;\n return 0;\n}\n\nint body(istream& cin, ostream& cout) {\n /*\n return 0;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << setprecision(20);\n*/\n\n string A, B; cin >> A >> B;\n ll M; cin >> M;\n\n auto func = [&](string s) -> Fp {\n vector tbl_init(2, vector(2, vector(3, vector(10, vector(M, Fp(0))))));\n auto tbl = tbl_init;\n\n tbl[1][1][0][0][0] = 1;\n for (char c : s) {\n auto prev = move(tbl);\n tbl = tbl_init;\n ll d = c - '0';\n REP(eq,2) REP(az,2) REP(p,3) REP(y,10) REP(m,M) {\n Fp prev_val = prev[eq][az][p][y][m];\n if (prev_val == 0) continue;\n REP(x,10) {\n if (eq && x > d) continue;\n ll new_eq = eq && x == d;\n ll new_az = az && x == 0;\n ll new_p = 0;\n if (not az) {\n if (y == x) continue;\n new_p = y < x ? 1 : 2;\n if (new_p == p) continue;\n }\n ll new_y = x;\n ll new_m = (m * 10 + x) % M;\n tbl[new_eq][new_az][new_p][new_y][new_m] += prev_val;\n }\n }\n#if DEBUG\n DLOG(\"\");\n DLOGK(c);\n REP(eq,2) REP(az,2) REP(p,3) REP(y,10) REP(m,M) {\n if (tbl[eq][az][p][y][m] != 0) DLOGK(eq, az, p, y, m, tbl[eq][az][p][y][m]);\n }\n#endif\n }\n Fp ret = 0;\n REP(eq, 2) REP(az, 1) REP(p, 3) REP(y, 10) ret += tbl[eq][az][p][y][0];\n DLOGK(s, ret);\n return ret;\n };\n\n DLOGK(A);\n REP2R(i, SIZE(A) - 1, 0) {\n if (A[i] != '0') { A[i]--; break; }\n A[i] = '9';\n }\n DLOGK(A);\n Fp ans = func(B) - func(A);\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 4680, "score_of_the_acc": -0.2876, "final_rank": 5 }, { "submission_id": "aoj_0570_6110456", "code_snippet": "#include <cassert>\n#include <numeric>\n#include <type_traits>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\n\n#include <utility>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\nconstexpr long long safe_mod(long long x, long long m) {\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nstruct barrett {\n unsigned int _m;\n unsigned long long im;\n\n explicit barrett(unsigned int m) : _m(m), im((unsigned long long)(-1) / m + 1) {}\n\n unsigned int umod() const { return _m; }\n\n unsigned int mul(unsigned int a, unsigned int b) const {\n\n unsigned long long z = a;\n z *= b;\n#ifdef _MSC_VER\n unsigned long long x;\n _umul128(z, im, &x);\n#else\n unsigned long long x =\n (unsigned long long)(((unsigned __int128)(z)*im) >> 64);\n#endif\n unsigned int v = (unsigned int)(z - x * _m);\n if (_m <= v) v += _m;\n return v;\n }\n};\n\nconstexpr long long pow_mod_constexpr(long long x, long long n, int m) {\n if (m == 1) return 0;\n unsigned int _m = (unsigned int)(m);\n unsigned long long r = 1;\n unsigned long long y = safe_mod(x, m);\n while (n) {\n if (n & 1) r = (r * y) % _m;\n y = (y * y) % _m;\n n >>= 1;\n }\n return r;\n}\n\nconstexpr bool is_prime_constexpr(int n) {\n if (n <= 1) return false;\n if (n == 2 || n == 7 || n == 61) return true;\n if (n % 2 == 0) return false;\n long long d = n - 1;\n while (d % 2 == 0) d /= 2;\n constexpr long long bases[3] = {2, 7, 61};\n for (long long a : bases) {\n long long t = d;\n long long y = pow_mod_constexpr(a, t, n);\n while (t != n - 1 && y != 1 && y != n - 1) {\n y = y * y % n;\n t <<= 1;\n }\n if (y != n - 1 && t % 2 == 0) {\n return false;\n }\n }\n return true;\n}\ntemplate <int n> constexpr bool is_prime = is_prime_constexpr(n);\n\nconstexpr std::pair<long long, long long> inv_gcd(long long a, long long b) {\n a = safe_mod(a, b);\n if (a == 0) return {b, 0};\n\n long long s = b, t = a;\n long long m0 = 0, m1 = 1;\n\n while (t) {\n long long u = s / t;\n s -= t * u;\n m0 -= m1 * u; // |m1 * u| <= |m1| * s <= b\n\n\n auto tmp = s;\n s = t;\n t = tmp;\n tmp = m0;\n m0 = m1;\n m1 = tmp;\n }\n if (m0 < 0) m0 += b / s;\n return {s, m0};\n}\n\nconstexpr int primitive_root_constexpr(int m) {\n if (m == 2) return 1;\n if (m == 167772161) return 3;\n if (m == 469762049) return 3;\n if (m == 754974721) return 11;\n if (m == 998244353) return 3;\n int divs[20] = {};\n divs[0] = 2;\n int cnt = 1;\n int x = (m - 1) / 2;\n while (x % 2 == 0) x /= 2;\n for (int i = 3; (long long)(i)*i <= x; i += 2) {\n if (x % i == 0) {\n divs[cnt++] = i;\n while (x % i == 0) {\n x /= i;\n }\n }\n }\n if (x > 1) {\n divs[cnt++] = x;\n }\n for (int g = 2;; g++) {\n bool ok = true;\n for (int i = 0; i < cnt; i++) {\n if (pow_mod_constexpr(g, (m - 1) / divs[i], m) == 1) {\n ok = false;\n break;\n }\n }\n if (ok) return g;\n }\n}\ntemplate <int m> constexpr int primitive_root = primitive_root_constexpr(m);\n\nunsigned long long floor_sum_unsigned(unsigned long long n,\n unsigned long long m,\n unsigned long long a,\n unsigned long long b) {\n unsigned long long ans = 0;\n while (true) {\n if (a >= m) {\n ans += n * (n - 1) / 2 * (a / m);\n a %= m;\n }\n if (b >= m) {\n ans += n * (b / m);\n b %= m;\n }\n\n unsigned long long y_max = a * n + b;\n if (y_max < m) break;\n n = (unsigned long long)(y_max / m);\n b = (unsigned long long)(y_max % m);\n std::swap(m, a);\n }\n return ans;\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n\n#include <cassert>\n#include <numeric>\n#include <type_traits>\n\nnamespace atcoder {\n\nnamespace internal {\n\n#ifndef _MSC_VER\ntemplate <class T>\nusing is_signed_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value ||\n std::is_same<T, __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int128 =\n typename std::conditional<std::is_same<T, __uint128_t>::value ||\n std::is_same<T, unsigned __int128>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing make_unsigned_int128 =\n typename std::conditional<std::is_same<T, __int128_t>::value,\n __uint128_t,\n unsigned __int128>;\n\ntemplate <class T>\nusing is_integral = typename std::conditional<std::is_integral<T>::value ||\n is_signed_int128<T>::value ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_signed_int = typename std::conditional<(is_integral<T>::value &&\n std::is_signed<T>::value) ||\n is_signed_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<(is_integral<T>::value &&\n std::is_unsigned<T>::value) ||\n is_unsigned_int128<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<\n is_signed_int128<T>::value,\n make_unsigned_int128<T>,\n typename std::conditional<std::is_signed<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type>::type;\n\n#else\n\ntemplate <class T> using is_integral = typename std::is_integral<T>;\n\ntemplate <class T>\nusing is_signed_int =\n typename std::conditional<is_integral<T>::value && std::is_signed<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing is_unsigned_int =\n typename std::conditional<is_integral<T>::value &&\n std::is_unsigned<T>::value,\n std::true_type,\n std::false_type>::type;\n\ntemplate <class T>\nusing to_unsigned = typename std::conditional<is_signed_int<T>::value,\n std::make_unsigned<T>,\n std::common_type<T>>::type;\n\n#endif\n\ntemplate <class T>\nusing is_signed_int_t = std::enable_if_t<is_signed_int<T>::value>;\n\ntemplate <class T>\nusing is_unsigned_int_t = std::enable_if_t<is_unsigned_int<T>::value>;\n\ntemplate <class T> using to_unsigned_t = typename to_unsigned<T>::type;\n\n} // namespace internal\n\n} // namespace atcoder\n\n\nnamespace atcoder {\n\nnamespace internal {\n\nstruct modint_base {};\nstruct static_modint_base : modint_base {};\n\ntemplate <class T> using is_modint = std::is_base_of<modint_base, T>;\ntemplate <class T> using is_modint_t = std::enable_if_t<is_modint<T>::value>;\n\n} // namespace internal\n\ntemplate <int m, std::enable_if_t<(1 <= m)>* = nullptr>\nstruct static_modint : internal::static_modint_base {\n using mint = static_modint;\n\n public:\n static constexpr int mod() { return m; }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n static_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n static_modint(T v) {\n long long x = (long long)(v % (long long)(umod()));\n if (x < 0) x += umod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n static_modint(T v) {\n _v = (unsigned int)(v % umod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v -= rhs._v;\n if (_v >= umod()) _v += umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n unsigned long long z = _v;\n z *= rhs._v;\n _v = (unsigned int)(z % umod());\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n if (prime) {\n assert(_v);\n return pow(umod() - 2);\n } else {\n auto eg = internal::inv_gcd(_v, m);\n assert(eg.first == 1);\n return eg.second;\n }\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static constexpr unsigned int umod() { return m; }\n static constexpr bool prime = internal::is_prime<m>;\n};\n\ntemplate <int id> struct dynamic_modint : internal::modint_base {\n using mint = dynamic_modint;\n\n public:\n static int mod() { return (int)(bt.umod()); }\n static void set_mod(int m) {\n assert(1 <= m);\n bt = internal::barrett(m);\n }\n static mint raw(int v) {\n mint x;\n x._v = v;\n return x;\n }\n\n dynamic_modint() : _v(0) {}\n template <class T, internal::is_signed_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n long long x = (long long)(v % (long long)(mod()));\n if (x < 0) x += mod();\n _v = (unsigned int)(x);\n }\n template <class T, internal::is_unsigned_int_t<T>* = nullptr>\n dynamic_modint(T v) {\n _v = (unsigned int)(v % mod());\n }\n\n unsigned int val() const { return _v; }\n\n mint& operator++() {\n _v++;\n if (_v == umod()) _v = 0;\n return *this;\n }\n mint& operator--() {\n if (_v == 0) _v = umod();\n _v--;\n return *this;\n }\n mint operator++(int) {\n mint result = *this;\n ++*this;\n return result;\n }\n mint operator--(int) {\n mint result = *this;\n --*this;\n return result;\n }\n\n mint& operator+=(const mint& rhs) {\n _v += rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n _v += mod() - rhs._v;\n if (_v >= umod()) _v -= umod();\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n _v = bt.mul(_v, rhs._v);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n\n mint pow(long long n) const {\n assert(0 <= n);\n mint x = *this, r = 1;\n while (n) {\n if (n & 1) r *= x;\n x *= x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const {\n auto eg = internal::inv_gcd(_v, mod());\n assert(eg.first == 1);\n return eg.second;\n }\n\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs._v == rhs._v;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs._v != rhs._v;\n }\n\n private:\n unsigned int _v;\n static internal::barrett bt;\n static unsigned int umod() { return bt.umod(); }\n};\ntemplate <int id> internal::barrett dynamic_modint<id>::bt(998244353);\n\nusing modint998244353 = static_modint<998244353>;\nusing modint1000000007 = static_modint<1000000007>;\nusing modint = dynamic_modint<-1>;\n\nnamespace internal {\n\ntemplate <class T>\nusing is_static_modint = std::is_base_of<internal::static_modint_base, T>;\n\ntemplate <class T>\nusing is_static_modint_t = std::enable_if_t<is_static_modint<T>::value>;\n\ntemplate <class> struct is_dynamic_modint : public std::false_type {};\ntemplate <int id>\nstruct is_dynamic_modint<dynamic_modint<id>> : public std::true_type {};\n\ntemplate <class T>\nusing is_dynamic_modint_t = std::enable_if_t<is_dynamic_modint<T>::value>;\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cstring>\n#include <iostream>\n#include <vector>\nusing mint = atcoder::static_modint<10000>;\ntemplate <typename T>\nvoid checkmax(T &x, T y) {\n if (x < y) x = y;\n}\ntemplate <typename T>\nvoid checkmin(T &x, T y) {\n if (x > y) x = y;\n}\nstruct Int {\n public:\n Int() {}\n ~Int() {}\n\n int len_;\n std::vector<int> v_;\n} L, R;\nstd::istream &operator>>(std::istream &in, Int &x) {\n std::string s;\n in >> s;\n x.len_ = s.size(), x.v_.resize(x.len_);\n for (int i = 0; i < x.len_; i++) x.v_[i] = s[i] - '0';\n return in;\n}\nint m;\nmint dp[502][10][501][3][2];\nmint Solve(const Int &x) {\n for (int i = 0; i <= x.len_; i++)\n for (int nw = 0; nw < 10; nw++)\n for (int j = 0; j < m; j++)\n for (int k = 0; k < 3; k++)\n for (int u = 0; u < 2; u++) dp[i][nw][j][k][u] = mint::raw(0);\n dp[0][0][0][2][1] = mint::raw(1);\n for (int i = 0; i < x.len_; i++)\n for (int ls = 0; ls < 10; ls++)\n for (int j = 0; j < m; j++)\n for (int k = 0; k < 3; k++)\n for (int u = 0; u < 2; u++)\n if (dp[i][ls][j][k][u].val()) {\n int up = u ? x.v_[i] : 9;\n for (int nw = 0; nw <= up; nw++) {\n if (((k != 2 || ls) && nw == ls) || (k == 0 && nw <= ls) ||\n (k == 1 && nw >= ls))\n continue;\n if (k == 2 && ls == 0)\n dp[i + 1][nw][nw % m][2][u && nw == x.v_[i]] +=\n dp[i][ls][j][k][u];\n else\n dp[i + 1][nw][(j * 10 + nw) % m][nw > ls]\n [u && nw == x.v_[i]] += dp[i][ls][j][k][u];\n }\n }\n mint ans(0);\n for (int i = 0; i < 10; i++)\n for (int j = 0; j < 3; j++)\n for (int k = 0; k < 2; k++) ans += dp[x.len_][i][0][j][k];\n return ans;\n}\nint main(int argc, char const *argv[]) {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(nullptr), std::cout.tie(nullptr);\n std::cin >> L >> R >> m;\n L.v_.back()--;\n for (int i = L.len_ - 1; i >= 0; i--)\n if (L.v_[i] < 0) L.v_[i] += 10, L.v_[i - 1]--;\n while (L.v_.size() > 1 && L.v_[0] == 0) L.v_.erase(L.v_.begin()), L.len_--;\n std::cout << (Solve(R) - Solve(L)).val() << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 62404, "score_of_the_acc": -0.3181, "final_rank": 7 }, { "submission_id": "aoj_0570_5910364", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring minusone(string A){\n int lenA = A.size();\n int zero = 0;\n for(int i=lenA-1;i>= 0 ;i--) {\n if (A[i] == '0') zero++;\n else break;\n } \n\n int nextzero = (int)(A[lenA-zero-1])-49;\n string AA;\n\n if(lenA-zero == 1){\n AA = to_string(nextzero);\n if (AA == \"0\") AA = \"\";\n }\n else{\n AA = A.substr(0,lenA-zero-1)+to_string(nextzero);\n }\n\n for(int i=0;i< zero ;i++) AA += \"9\";\n if (AA == \"\") AA = \"0\";\n return AA;\n}\n\nint solve(string A,int M,int MOD){\n int lenA = A.size();\n if(lenA == 1) return ((int)(A[0])-48) / M;\n\n int dp[501][10][2][501][2];\n int powmod[501]; // powmod[i] = 10^i mod M\n for(int i=0;i< 501 ;i++)for(int j=0;j< 10 ;j++)for(int k=0;k< 2 ;k++)for(int l=0;l< 501 ;l++)for(int m=0;m< 2 ;m++) dp[i][j][k][l][m] = 0;\n\n powmod[0] = 1;\n for(int i=1;i< 501 ;i++) powmod[i] = (powmod[i-1]*10) % M;\n \n /*\n for(int j=0;j< 10 ;j++){for(int m=0;m< 2 ;m++){\n int digit = (int)(A[0])-48;\n if ( digit > j ) dp[0][j][0][(j*powmod[lenA-1]) % M][m] = 1;\n if (digit == j) dp[0][j][1][(j*powmod[lenA-1]) % M][m] = 1;\n }}\n */\n\n for(int i=0;i< lenA-1 ;i++){\n for(int j=1;j< 10 ;j++){\n for(int m=0;m< 2 ;m++){\n int digit = (int)(A[i])-48;\n if(i == 0){\n if ( digit > j ) dp[i][j][0][(j*powmod[lenA-1-i]) % M][m] = 1;\n if (digit == j) dp[i][j][1][(j*powmod[lenA-1-i]) % M][m] = 1; \n }\n else{\n dp[i][j][0][(j*powmod[lenA-1-i]) % M][m] = 1;\n }\n }\n }\n }\n\n \n //for(int j=0;j< 10 ;j++)for(int k=0;k< 2 ;k++)for(int l=0;l< M ;l++)for(int m=0;m< 2 ;m++) cout << j<< \" \" << k<<\" \" <<l<< \" \"<< m << \" \"<< dp[0][j][k][l][m] << endl;\n \n \n\n for(int i=0;i< lenA-1 ;i++){\n for(int j=0;j< 10 ;j++){\n for(int k=0;k< 2 ;k++){\n for(int l=0;l< M ;l++){\n for(int m=0;m< 2 ;m++){\n if (k == 1){\n for(int jj=0;jj< 10 ;jj++){\n int nextl = (jj*powmod[lenA-i-2]+l)%M;\n if ((int)(A[i+1])-48 > jj) { \n if ((m == 0) && ( j < jj)) dp[i+1][jj][0][nextl][1] = (dp[i][j][k][l][m]+dp[i+1][jj][0][nextl][1]) % MOD;\n if ((m == 1) && ( j > jj)) dp[i+1][jj][0][nextl][0] = (dp[i][j][k][l][m]+dp[i+1][jj][0][nextl][0]) % MOD;\n }\n if ((int)(A[i+1])-48 == jj) {\n if ((m == 0) && ( j < jj)) dp[i+1][jj][k][nextl][1] = (dp[i][j][k][l][m]+dp[i+1][jj][k][nextl][1]) % MOD;\n if ((m == 1) && ( j > jj)) dp[i+1][jj][k][nextl][0] = (dp[i][j][k][l][m]+dp[i+1][jj][k][nextl][0]) % MOD;\n }\n }\n }\n if (k==0){\n for(int jj=0;jj< 10 ;jj++){\n int nextl = (jj*powmod[lenA-i-2]+l)%M;\n if ((m == 0) && ( j < jj)) dp[i+1][jj][0][nextl][1] = (dp[i][j][k][l][m]+dp[i+1][jj][0][nextl][1]) % MOD;\n if ((m == 1) && ( j > jj)) dp[i+1][jj][0][nextl][0] = (dp[i][j][k][l][m]+dp[i+1][jj][0][nextl][0]) % MOD;\n\n }\n }\n\n }\n }\n }\n }\n }\n\n int ans=0;\n for(int j=0;j< 10 ;j++)for(int k=0;k< 2 ;k++)for(int m=0;m< 2 ;m++) ans = (ans+dp[lenA-1][j][k][0][m]) % MOD;\n // for(int j=0;j< 10 ;j++)for(int k=0;k< 2 ;k++)for(int m=0;m< 2 ;m++) cout << j<< \" \" << k<<\" \" << m << \" \"<< dp[lenA-1][j][k][0][m] << endl;\n\n ans = ans + 9 / M;\n \n return ans;\n\n}\n\nint main()\n{\n // dp[i][j][k][l][m] 上からi桁目まで見る,j:i桁目の数字,k:上i桁がAと一致していれば1,l:上i桁見たときのmod M,m:i-1→iが上昇(1)か下降か(0)\n\n string A,B;\n int M;\n cin >> A;\n cin >> B;\n cin >> M;\n \n\n int ans = (10000+solve(B,M,10000)-solve(minusone(A),M,10000)) % 10000;\n //cout << solve(B,M,10000) << endl;\n //cout << solve(minusone(A),M,10000) << endl;\n \n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 42688, "score_of_the_acc": -0.4176, "final_rank": 11 } ]
aoj_0578_cpp
看板 (Signboard) 問題 JOI 君はお店の看板を作ることにした. 文字が等間隔に書かれた古い看板が N 枚ある.JOI 君は古い看板からいくつかの文字を消すことで看板を作る.残った文字列がお店の名前になっていて,しかも残った文字が等間隔に並んでいるようにしたい.看板は 1 枚の古い看板から作らなければならず,古い看板を切ったりつなげたりしてはならない. お店の名前と N 枚の古い看板の情報が与えられた時,JOI 君が作ることができる看板の枚数を求めるプログラムを作成せよ.ただし, 1 枚の古い看板から作ることができる看板が複数考えられる場合も,作ることができる看板は 1 枚であると考える. 入力 入力は 2 + N 行からなる. 1 行目には,整数 N (1 ≦ N ≦ 100) が書かれており,古い看板の枚数を表す. 2 行目には,3 文字以上 25 文字以下のアルファベット小文字からなる文字列が書かれており,お店の名前を表す. 続く N 行のうちの i 行目 (1 ≦ i ≦ N) には 1 文字以上 100 文字以下のアルファベット小文字からなる文字列が書かれており,i 枚目の古い看板に書かれている文字列を表す. 出力 JOI 君が作ることができる看板の枚数を表す整数を 1 行で出力せよ. 入出力例 入力例 4 bar abracadabra bear bar baraxbara 出力例 3 お店の名前は bar である. 1 枚目の古い看板には文字列 abracadabra が書かれている. この古い看板から 2 文字目,6 文字目,10 文字目以外を消すことで看板を作ることができる. 2 枚目は,2 文字目を消すと bar という文字列を作ることができるが,これは残った文字が等間隔に並んでいない. 3 枚目は,文字を何も消さなくても看板になっている. 4 枚目の古い看板から看板を作る方法は 2 通りある. 1 つの方法は,1 文字目,2 文字目,3 文字目以外を消すことである. もう 1 つの方法は,6 文字目,7 文字目,8 文字目以外を消すことである. よって,JOI 君は 1 枚目,3 枚目,4 枚目の古い看板から看板を作ることができるので,3 を出力する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0578_6740575", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> PP;\n//#define MOD 1000000007\n#define MOD 998244353\n#define INF 2305843009213693951\n//#define INF 810114514\n#define PI 3.141592653589\n#define setdouble setprecision\n#define REP(i,n) for(ll i=0;i<(n);++i)\n#define OREP(i,n) for(ll i=1;i<=(n);++i)\n#define RREP(i,n) for(ll i=(n)-1;i>=0;--i)\n#define ALL(v) (v).begin(), (v).end()\n#define GOODBYE do { cout << \"-1\" << endl; return 0; } while (false)\n#define MM <<\" \"<<\n#define Endl endl\n#define debug true\n#define debug2 false\n\nint main(void){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n ll N;\n cin >> N;\n string S;\n cin >> S;\n\n ll Ans = 0;\n REP(i,N){\n string T;\n cin >> T;\n\n bool can = false;\n for(int i=0;i<(int)T.size();i++){\n for(int j=1;j<T.size();j++){\n bool ok = true;\n REP(k,S.size()){\n if(i+j*k >= (int)T.size() || S[k]!=T[i+j*k]){\n ok = false;\n }\n }\n\n if(ok)can=true;\n }\n }\n\n if(can)Ans++;\n }\n \n cout << Ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3356, "score_of_the_acc": -0.8909, "final_rank": 8 }, { "submission_id": "aoj_0578_5902257", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nconst int inf = 1e9 + 7;\n\nint main(void) {\n int N;\n string S;\n cin >> N >> S;\n string target[N];\n for(int i = 0; i < N; i++) cin >> target[i];\n\n int ans = 0;\n\n for(int i = 0; i < N; i++){\n bool ok = false;\n int t_size = target[i].size();\n for(int start = 0; start < t_size; start++){\n for(int kankaku = 1; kankaku < t_size; kankaku++){\n string s;\n for(int j = 0; start + j * kankaku < t_size; j++){\n s += target[i][start + j * kankaku];\n if(s == S){\n ok = true;\n break;\n }\n }\n if(ok) break;\n }\n if(ok) break;\n }\n if(ok) ans++;\n }\n\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3188, "score_of_the_acc": -1.1364, "final_rank": 11 }, { "submission_id": "aoj_0578_5902237", "code_snippet": "#include<bits/stdc++.h>\n\nusing Int = long long;\nusing namespace std;\n\nint main(){\n int N;\n cin >> N;\n string base; cin >> base;\n vector<string>vs(N);\n for(string& s : vs)\n cin >> s;\n int ans = 0;\n for(auto s : vs){\n bool satisfy = false;\n for(int d = 1; d < s.size(); ++d){\n for(int pos = 0; pos < s.size(); ++pos){\n int di = 0;\n int id = 0;\n string tmp;\n while(pos + di * d < s.size()){\n int spos = pos + di * d;\n tmp.push_back(s[spos]);\n ++di;\n }\n if(tmp.find(base) != std::string::npos)\n satisfy = true;\n }\n }\n ans += (satisfy ? 1 : 0);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3428, "score_of_the_acc": -1, "final_rank": 10 }, { "submission_id": "aoj_0578_5064402", "code_snippet": "#include<iostream>\n\nbool possible(std::string name, std::string signboard){\n for(int start=0; start<signboard.size(); ++start){\n for(int gap=1; gap<signboard.size(); ++gap){\n std::string s = \"\";\n for(int j=start; j<signboard.size(); j += gap){\n if(j >= signboard.size() || s.size() >= name.size()) break;\n s += signboard[j];\n }\n if(name == s) return true;\n }\n }\n return false;\n}\n\nint main(){\n int N; std::cin >> N;\n std::string name;\n std::cin >> name;\n\n std::string signboard;\n int ans=0;\n for(int n=0; n<N; ++n){\n std::cin >> signboard;\n if(possible(name, signboard)) ++ans;\n }\n std::cout << ans << std::endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3216, "score_of_the_acc": -1.1788, "final_rank": 13 }, { "submission_id": "aoj_0578_5021736", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define vector1d(type,name,...) vector<type>name(__VA_ARGS__)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\n//入力系\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\n//出力系\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\n//デバッグ系\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n string s,t;\n cin>>s;\n int ans=0;\n bool flag;\n rep(i,n){\n cin>>t;\n for(int j=1;j<t.size();j++){\n for(int k=0;k<t.size();k++){\n string u;\n for(int l=0;l<s.size();l++){\n if(j*l+k<t.size())u+=t[j*l+k];\n }\n if(s==u){\n ans++;\n goto skip;\n }\n }\n }\n skip: ;\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3308, "score_of_the_acc": -1.1515, "final_rank": 12 }, { "submission_id": "aoj_0578_4962390", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n#define REP(i, n) for (int i = 0; i < (n); ++i)\n#define REPR(i, n) for (int i = n - 1; i >= 0; --i)\n#define FOR(i, m, n) for (int i = m; i < n; ++i)\n#define FORR(i, m, n) for (int i = m; i >= n; --i)\n#define ALL(v) (v).begin(),(v).end()\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=(1<<30)-1;\nconst int mod=1e9+7;\nint dx[8]={1,0,-1,0,-1,-1,1,1};\nint dy[8]={0,1,0,-1,-1,1,-1,1};\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int n;cin >> n;\n string t;cin >> t;\n vector<string> s(n);\n int m=t.size();\n int ans=0;\n REP(i,n){\n cin >> s[i];\n bool f=false;\n for(int j=1;1+(m-1)*j<=s[i].size();j++){\n for(int k=0;k+(m-1)*j<s[i].size();k++){\n string u=\"\";\n for(int l=0;l<m;l++){\n u+=s[i][k+j*l];\n }\n if(u==t){\n f=true;\n }\n }\n }\n if(f) ans++;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3236, "score_of_the_acc": -0.8758, "final_rank": 7 }, { "submission_id": "aoj_0578_4472981", "code_snippet": "#include <iostream>\n#include <string>\n\nvoid solve() {\n int q;\n std::string s;\n std::cin >> q >> s;\n\n int ans = 0;\n while (q--) {\n std::string t;\n std::cin >> t;\n int m = t.length();\n\n bool ok = false;\n for (int l = 1; l < m; ++l) {\n for (int i = 0; i < m; ++i) {\n int j = i;\n bool judge = true;\n\n for (char c : s) {\n if (j >= m || t[j] != c) judge = false;\n j += l;\n }\n\n if (judge) ok = true;\n }\n }\n\n if (ok) ++ans;\n }\n\n std::cout << ans << \"\\n\";\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3216, "score_of_the_acc": -0.8455, "final_rank": 6 }, { "submission_id": "aoj_0578_4235148", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint main() {\n int N;\n string S;\n cin >> N >> S;\n vector<string> sb(N);\n for (int i = 0; i < N; ++i)\n cin >> sb[i];\n\n int ans = 0;\n for (int i = 0; i < N; ++i) {\n bool flag = false;\n for (int j = 0; j < sb[i].size() - S.size() + 1; ++j) {\n for (int k = 1; k < sb[i].size(); ++k) {\n string S2;\n for (int l = j; l < sb[i].size(); l += k)\n S2 += sb[i][l];\n\n if (S2.substr(0, S.size()) == S)\n flag = true;\n\n if (flag)\n break;\n }\n\n if (flag)\n break;\n }\n\n if (flag)\n ++ans;\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3188, "score_of_the_acc": -1.303, "final_rank": 15 }, { "submission_id": "aoj_0578_4015980", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\nint test[321][321];\nint main() {\n\tlong long n, ans = 0; string s, t; cin >> n >> s;\n\tfor (int h = 0; h < n; h++) {\n\t\tcin >> t; \n\t\tfor (int i = 0; i < t.size(); i++) {\n\t\t\tfor (int j = 1; j <= 100; j++) {\n\t\t\t\tint sum = 0;\n\t\t\t\tfor (int k = 0; k < s.size(); k++) {\n\t\t\t\t\tif (i + (j * k) < t.size()) {\n\t\t\t\t\t\tif (t[i + (j * k)] == s[k]) {\n\t\t\t\t\t\t\tsum++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (sum == s.size()) {\n\t\t\t\t\tans++; i = t.size(); j = 100;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\tcin >> n;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3180, "score_of_the_acc": -0.6242, "final_rank": 4 }, { "submission_id": "aoj_0578_3980542", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing VI = vector<int>;\nusing VL = vector<ll>;\n#define FOR(i,a,n) for(int (i)=(a);(i)<(n);++(i))\n#define eFOR(i,a,n) for(int (i)=(a);(i)<=(n);++(i))\n#define rFOR(i,a,n) for(int (i)=(n)-1;(i)>=(a);--(i))\n#define erFOR(i,a,n) for(int (i)=(n);(i)>=(a);--(i))\n#define SORT(i) sort((i).begin(),(i).end())\n#define rSORT(i,a) sort((i).begin(),(i).end(),(a))\n#define all(i) (i).begin(),(i).end()\n#define out(y,x,h,w) (y) < 0 || (h) <= (y) || (x) < 0 || (w) <= (x)\n#define line cout << \"------------------------\\n\" \nconstexpr ll INF = 1000000000;\nconstexpr ll LLINF = 1LL << 60;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconst long double pi = acos(-1);\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; }return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; }return 0; }\ninline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }\ntemplate<class T>inline istream& operator>>(istream& input, vector<T>& v) { for (auto& elemnt : v)input >> elemnt; return input; }\n\nint main() {\n init();\n\n int n; string s; cin >> n >> s;\n int k = s.length();\n int ans = 0;\n FOR(fugfuyfffsdfvgefge, 0, n) {\n string t; cin >> t;\n int m = t.length();\n\n bool ok = false;\n FOR(diff, 1, m)FOR(start, 0, m) {\n bool s_ok = true;\n FOR(i, 0, k) {\n s_ok &= (start + i * diff < m && s[i] == t[start + i * diff]);\n }\n ok |= s_ok;\n }\n if (ok)++ans;\n }\n cout << ans << \"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3212, "score_of_the_acc": -0.6727, "final_rank": 5 }, { "submission_id": "aoj_0578_3977853", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\n//int N,M,K,L,R,H,W;\nlong long int N,M,K,L,R,H,W;\n\n//constexpr long long int MOD=1000000007;\n//constexpr int MOD=1000000007;\nconstexpr int MOD=998244353;\n//constexpr long long int MOD=998244353;\n\nint main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t\n\tcin>>N;\n\tstring s;\n\tcin>>s;\n\tvector<string>u(N);\n\tfor(auto &i:u)cin>>i;\n\tint ans=0;\n\tfor(auto i:u){\n\t\tint add=0;\n\t\tfor(int l=0;l<i.size();l++){\n\t\t\tfor(int j=1;j<i.size();j++){\n\t\t\t\tstring t;\n\t\t\t\tfor(int k=l;k<i.size()&&t.size()<s.size();k+=j){\n\t\t\t\t\tt.push_back(i[k]);\n\t\t\t\t}\n\t\t\t\tif(s==t)add|=1;\n\t\t\t}\n\t\t}\n\t\tans+=add;\n\t\t//cout<<ans<<endl;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3232, "score_of_the_acc": -1.3697, "final_rank": 17 }, { "submission_id": "aoj_0578_3783725", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define all(x) x.begin(), x.end()\n#define rep(i, n) for (int i = 0; i < n; ++i)\n#define reps(i, m, n) for (int i = m; i <= n; ++i)\n\nusing i64 = long long;\nusing pii = pair<i64, i64>;\n\ntemplate<class A, class B>inline bool chmax(A &a, const B &b){return b > a ? a = b,1 : 0;}\ntemplate<class A, class B>inline bool chmin(A &a, const B &b){return b < a ? a = b,1 : 0;}\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr i64 LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int MOD = int(1e9) + 7;\n\nsigned main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int n;\n string name;\n cin >> n >> name;\n\n int ans = 0;\n string s;\n rep(i, n) {\n cin >> s;\n\n bool isOK = false;\n for (int j = 0; j < s.length(); ++j) {\n for (int k = 1; k < s.length(); ++k) {\n string u = \"\";\n for (int l = j; l < s.length(); l += k) {\n u += s[l];\n }\n if (u.length() < name.length()) continue;\n if (u.find(name) + 1) isOK = true;\n }\n }\n if (isOK) ++ans;\n }\n\n cout << ans << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3176, "score_of_the_acc": -1.6182, "final_rank": 19 }, { "submission_id": "aoj_0578_3571710", "code_snippet": "#include <cstdio>\n#include <cctype>\n#include <utility>\n#include <string>\nusing namespace std;\n\nconst auto gcu = getchar_unlocked;\nconst auto pcu = putchar_unlocked;\n#define _T template <typename T>\n#define _HT template <typename H, typename... T>\n#define _il inline\n#define _in _il int in\n#define _sc _il bool scan\n_T T in(int c){T n=0;bool m=false;while(isspace(c)){c=gcu();}if(c=='-')m=true,c=gcu();\n\tdo{n=10*n+(c-'0'),c=gcu();}while(c>='0'&&c<='9');return m?-n:n;}\n_in() {return in<int>(gcu());}\n_T T scan(T &n){int c=gcu();return c==EOF?false:(n=in<T>(c),true);}\n_sc(char &c){c=gcu();gcu();return c!=EOF;}\n#ifdef _GLIBCXX_STRING\n_sc(string &s){int c;s=\"\";\n\tfor(;;){c=gcu();if(c=='\\n'||c==' ')return true;else if(c==EOF)return false;s+=c;}}\n#endif\n_HT _sc(H &h, T&&... t){return scan(h)&&scan(t...);}\n#define _vo _il void out\n#define _vl _il void outl\n_vo(bool b) {pcu('0'+b);}\n_vo(const char *s){while(*s)pcu(*s++);}\n_vo(char c){pcu(c);}\n#ifdef _GLIBCXX_STRING\n_vo(string s){for(char c:s)pcu(c);}\n#endif\n_T _vo(T n){static char buf[20];char *p=buf;if(n<0)pcu('-'),n*=-1;\n\tif(!n)*p++='0';else while(n)*p++=n%10+'0',n/=10; while (p!=buf)pcu(*--p);}\n_vl(){out('\\n');}\n#ifdef _GLIBCXX_VECTOR\n_T _vo(vector<T> &v){for(T &x:v)out(&x == &v[0]?\"\":\" \"),out(x);outl();}\n#endif\n_HT _vo(H&& h, T&&... t){out(h);out(move(t)...);}\ntemplate <typename... T> _vl(T&&... t){out(move(t)...);outl();}\n\nint main() {\n\tint n = in(), c = 0;\n\tstring s, t;\n\tscan(s);\n\twhile (n--) {\n\t\tscan(t);\n\t\tc += [&] {\n\t\t\tfor (int i = 0; i <= (int) t.size() - (int) s.size(); i++)\n\t\t\t\tif (s[0] == t[i])\n\t\t\t\t\tfor (int j = 1; i + j * (s.size() - 1) < t.size(); j++) {\n\t\t\t\t\t\ttry {\n\t\t\t\t\t\t\tfor (size_t k = 1; k < s.size() ; k++)\n\t\t\t\t\t\t\t\tif (t[i + j * k] != s[k])\n\t\t\t\t\t\t\t\t\tthrow 0;\n\t\t\t\t\t\t\treturn 1;\n\t\t\t\t\t\t} catch (...) {\n\t\t\t\t\t\t\t;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\treturn 0;\n\t\t}();\n\t}\n\toutl(c);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2768, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0578_3401880", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstdio>\n#include<vector>\n#include<cmath>\n#include<algorithm>\n#include<functional>\n#include<iomanip>\n#include<queue>\n#include<ciso646>\n#include<random>\n#include<map>\n#include<set>\n#include<complex>\n#include<bitset>\n#include<stack>\n#include<unordered_map>\n#include<utility>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned int ui;\nconst ll mod = 1000000007;\nconst ll INF = (ll)1000000007 * 1000000007;\ntypedef pair<int, int> P;\n#define stop char nyaa;cin>>nyaa;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define per(i,n) for(int i=n-1;i>=0;i--)\n#define Rep(i,sta,n) for(int i=sta;i<n;i++)\n#define rep1(i,n) for(int i=1;i<=n;i++)\n#define per1(i,n) for(int i=n;i>=1;i--)\n#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)\ntypedef long double ld;\ntypedef complex<ld> Point;\nconst ld eps = 1e-2;\nconst ld pi = acos(-1.0);\ntypedef pair<ll, ll> LP;\nint n; string s;\nint main() {\n\tcin >> n >> s; int ans = 0;\n\trep(i, n) {\n\t\tstring t; cin >> t;\n\t\tbool exi = false;\n\t\tfor (int i = 0; i < t.size(); i++) {\n\t\t\tfor (int j = 1; j < t.size(); j++) {\n\t\t\t\tstring u;\n\t\t\t\tfor (int k = i; k < t.size(); k += j) {\n\t\t\t\t\tu.push_back(t[k]);\n\t\t\t\t}\n\t\t\t\tif (u.length() < s.length())continue;\n\t\t\t\tif (u.substr(0, s.length()) == s)exi = true;\n\t\t\t}\n\t\t}\n\t\tif (exi)ans++;\n\t}\n\tcout << ans << endl;\n\t//stop\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3168, "score_of_the_acc": -1.4394, "final_rank": 18 }, { "submission_id": "aoj_0578_3382049", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n\nbool judgeCanIMakeSign( string s, string a )\n{\n int as = a.size(), ss = s.size();\n char* b = new char[as];\n\n for( int i = 0; i < ss; i++ )\n {\n int con = 1;\n b[0] = s[i];\n while( i + con * ( as - 1 ) < ss )\n {\n int p = con;\n for( int j = 1; j < as; j++ )\n {\n b[j] = s[i+con];\n con += p;\n }\n con = p + 1;\n \n string res = \"\";\n for( int j = 0; j < as; j++ )\n res += b[j];\n\n if( a == res )\n {\n delete b;\n return true;\n }\n }\n }\n\n delete b;\n return false;\n}\n\nint main()\n{\n int n;\n string a, s;\n\n cin >> n >> a;\n\n int cnt = 0;\n for( int i = 0; i < n; i++ )\n {\n cin >> s;\n if( judgeCanIMakeSign( s, a ) )\n cnt++;\n }\n\n cout << cnt << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3152, "score_of_the_acc": -0.5818, "final_rank": 2 }, { "submission_id": "aoj_0578_3230172", "code_snippet": "//Signboard\n#include <iostream>\n\nusing namespace std;\n\nint main() {\n int N;\n string base, str;\n bool flg;\n cin >> N;\n cin >> base;\n int cnt = 0;\n for(int i = 0; i < N; i++) {\n cin >> str;\n flg = false;\n for(int p = 0; p < str.size(); p++) {\n for(int s = 1; s < str.size() - p; s++) {\n string x = \"\";\n for(int j = 0; j < base.size(); j++) {\n if(p + j * s < str.size()) x += str[p + j * s];\n }\n if(base == x) {flg = true; break;}\n }\n if(flg) break;\n }\n if(flg) cnt++;\n }\n\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3192, "score_of_the_acc": -0.9758, "final_rank": 9 }, { "submission_id": "aoj_0578_3230133", "code_snippet": "//Signboard\n#include <iostream>\n\nusing namespace std;\n\nint main() {\n int N;\n string base, str;\n bool flg;\n cin >> N;\n cin >> base;\n int cnt = 0;\n for(int i = 0; i < N; i++) {\n cin >> str;\n flg = false;\n for(int p = 0; p < str.size(); p++) {\n for(int s = 1; s < str.size() - p; s++) {\n string x = \"\";\n for(int j = 0; j < base.size(); j++) {\n x += str[p + j * s];\n }\n if(base == x) {flg = true; break;}\n }\n if(flg) break;\n }\n if(flg) cnt++;\n }\n\n cout << cnt << endl;\n}", "accuracy": 0.4, "time_ms": 20, "memory_kb": 3232, "score_of_the_acc": -0.8697, "final_rank": 20 }, { "submission_id": "aoj_0578_3081869", "code_snippet": "#include <bits/stdc++.h>\n#define range(i, a, b) for(int i = (a); i < (b); i++)\n#define rep(i, a) range(i, 0, a)\nusing namespace std;\n\nint main() {\n int n;\n string s;\n cin >> n >> s;\n\n int cnt = 0;\n while (n--) {\n string in;\n cin >> in;\n\n bool flag = false;\n range (i, 1, 100) {\n if (i > in.size()) break;\n rep (j, i) {\n string tmp = \"\";\n for (int k = j; k < in.size(); k += i) tmp += in[k];\n rep (k, (int)tmp.size() - (int)s.size() + 1) {\n string cmp = \"\";\n rep (l, s.size()) cmp += tmp[k + l];\n if (cmp == s) flag |= true;\n }\n }\n }\n cnt += flag;\n }\n\n cout << cnt << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3200, "score_of_the_acc": -1.3212, "final_rank": 16 }, { "submission_id": "aoj_0578_2760622", "code_snippet": "#include<stdio.h>\n#include <algorithm>\n#include <cassert>\n#include <cctype>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <iostream>\n#include <iterator>\n#include <list>\n#include <map> \n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <iomanip>\n#include <stack>\n#include <string>\n#include <vector>\nusing namespace std;\n#define ll long long\n#define ld long double\n#define loop(a,t) for(int a=0;a<t;a++) \n#define forever while(true)\n#define Sort(a) sort(a.begin(),a.end())\n#define Reverse(a) reverse(a.begin(),a.end())\nint main()\n{\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint n;\n\tstring a;\n\tcin >> n >> a;\n\tint ans = 0;\n\tloop(i, n) {\n\t\tstring str;\n\t\tcin >> str;\n\t\tstring cnt = \"\";\n\t\tfor (int i = 1; i < str.length(); i++) {\n\t\t\tfor (int start = 0; start < str.length(); start++) {\n\t\t\t\tcnt = \"\";\n\t\t\t\tfor (int j = start; j < str.length(); j += i)\n\t\t\t\t{\n\t\t\t\t\tcnt += str[j];\n\t\t\t\t\tif (cnt == a) \n\t\t\t\t\t{\n\t\t\t\t\t\tans++; goto H;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\tH: {}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3172, "score_of_the_acc": -0.6121, "final_rank": 3 }, { "submission_id": "aoj_0578_2636411", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing pii = pair<int, int>;\nusing vi = vector<int>;\nusing ll = long long;\n\nint main() {\n int N;\n string name;\n cin >> N >> name;\n int ans = 0;\n for(int i = 0; i < N; ++i) {\n string s; cin >> s;\n bool ok = false;\n for(int w = 0; w < s.size(); ++w) {\n for(int l = 0; l < s.size(); ++l) {\n string tmp;\n for(int j = 0; j < name.size() && j * w + l < s.size(); ++j) {\n tmp += s[j * w + l];\n }\n ok |= name == tmp;\n }\n }\n ans += ok;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3172, "score_of_the_acc": -1.2788, "final_rank": 14 } ]
aoj_0579_cpp
暑い日々 (Hot days) 問題 日本が冬であるこの時期,南半球にあるオーストラリアでは暑い日が続いている.オーストラリアに住む IOI 君は,ある D 日間の天気予報をもとに,着る服の計画を立てることにした.i 日目 (1 ≦ i ≦ D) の最高気温は T i 度であると予報されている. IOI 君は N 種類の服を持っており,それらには 1 から N までの番号がついている.服 j (1 ≦ j ≦ N) は最高気温が A j 度以上 B j 度以下の日に着るのに適している.また,それぞれの服には「派手さ」とよばれる整数が定まっており,服 j の派手さは C j である. D 日間のそれぞれに対し,IOI 君は,最高気温が天気予報に従ったときに着るのに適した服のうち 1 つを着る服として選ぶ.同じ服を何度選んでもよいし,D 日間で一度も選ばれない服があってもよい. 似ている服を連続して着ることをなるべく避けようと思った IOI 君は,連続する日に着る服の派手さの差の絶対値の合計をできるだけ大きくしようと考えた.すなわち,i 日目に服 x i を選んだとして,値 |C x 1 - C x 2 | + |C x 2 - C x 3 | + … + |C x D-1 - C x D | を最大にしたい.この最大値を求めるプログラムを作成せよ. 入力 入力は 1 + D + N 行からなる. 1 行目には,2 つの整数 D, N (2 ≦ D ≦ 200,1 ≦ N ≦ 200) が空白を区切りとして書かれている.D は服の計画を立てる日数,N は IOI 君が持っている服の種類の数を表す. 続く D 行のうちの i 行目 (1 ≦ i ≦ D) には,1 つの整数 T i (0 ≦ T i ≦ 60) が書かれている.これは,i 日目の最高気温が T i 度であると予報されていることを表す. 続く N 行のうちの j 行目 (1 ≦ j ≦ N) には,3 つの整数 A j , B j , C j (0 ≦ A j ≦ B j ≦ 60,0 ≦ C j ≦ 100) が書かれている.これらは,服 j は最高気温が A j 度以上 B j 度以下の日に着るのに適しており,派手さが C j であることを表す. 最高気温が天気予報に従ったときに着るのに適した服が,D 日間のどの日に対しても 1 つ以上存在することが保証されている. 出力 連続する日に着る服の派手さの差の絶対値の合計,すなわち,値 |C x 1 - C x 2 | + |C x 2 - C x 3 | + … + |C x D-1 - C x D | の最大値を 1 行で出力せよ. 入出力例 入力例 1 3 4 31 27 35 20 25 30 23 29 90 21 35 60 28 33 40 出力例 1 80 入出力例 1 において,1 日目の服の候補は服 3 と服 4 であり,2 日目の服の候補は服 2 と服 3 であり,3 日目の服の候補は服 3 のみである.1 日目に服 4 を,2 日目に服 2 を,3 日目に服 3 を選ぶ.すなわち,x 1 = 4,x 2 = 2,x 3 = 3 とする.このとき,1 日目と 2 日目の服の派手さの差の絶対値は |40 - 90| = 50 であり,2 日目と 3 日目の服の派手さの差の絶対値は |90 - 60| = 30 である.合計は 80 となり,これが最大値である. 入力例 2 5 2 26 28 32 29 34 30 35 0 25 30 100 出力例 2 300 入出力例 2 において,1 日目には服 2 を,2 日目には服 2 を,3 日目には服 1 を,4 日目には服 2 を,5 日目には服 1 を選ばなければならない.このとき,求める値は |100 - 100| + |100 - 0| + |0 - 100| + |100 - 0| = 300 となる. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0579_6740624", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"Ofast\")\n#define _GLIBCXX_DEBUG\nusing namespace std;\nusing std::cout;\nusing std::cin;\nusing std::endl;\nusing ll=long long;\nusing ld=long double;\nll ILL=2167167167167167167;\nconst int INF=2100000000;\nconst ll mod=998244353;\n#define rep(i,a) for (ll i=0;i<a;i++)\n#define all(p) p.begin(),p.end()\ntemplate<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> ll LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> ll UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;}\ntemplate<class T> bool chmax(T &a,const T &b){if(a<b){a=b;return 1;}else return 0;}\ntemplate<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}\ntemplate<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}\nvoid yneos(bool a){if(a) cout<<\"Yes\\n\"; else cout<<\"No\\n\";}\ntemplate<class T> void vec_out(vector<T> &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<\" \";cout<<p[i];}cout<<\"\\n\";}\n\nnamespace atcoder {\n \nnamespace internal {\n \ntemplate <class T> struct simple_queue {\n std::vector<T> payload;\n int pos = 0;\n void reserve(int n) { payload.reserve(n); }\n int size() const { return int(payload.size()) - pos; }\n bool empty() const { return pos == int(payload.size()); }\n void push(const T& t) { payload.push_back(t); }\n T& front() { return payload[pos]; }\n void clear() {\n payload.clear();\n pos = 0;\n }\n void pop() { pos++; }\n};\n \n} // namespace internal\n \n} // namespace atcoder\nnamespace atcoder {\n \ntemplate <class Cap> struct mf_graph {\n public:\n mf_graph() : _n(0) {}\n mf_graph(int n) : _n(n), g(n) {}\n \n int add_edge(int from, int to, Cap cap) {\n assert(0 <= from && from < _n);\n assert(0 <= to && to < _n);\n assert(0 <= cap);\n int m = int(pos.size());\n pos.push_back({from, int(g[from].size())});\n g[from].push_back(_edge{to, int(g[to].size()), cap});\n g[to].push_back(_edge{from, int(g[from].size()) - 1, 0});\n return m;\n }\n \n struct edge {\n int from, to;\n Cap cap, flow;\n };\n \n edge get_edge(int i) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n auto _e = g[pos[i].first][pos[i].second];\n auto _re = g[_e.to][_e.rev];\n return edge{pos[i].first, _e.to, _e.cap + _re.cap, _re.cap};\n }\n std::vector<edge> edges() {\n int m = int(pos.size());\n std::vector<edge> result;\n for (int i = 0; i < m; i++) {\n result.push_back(get_edge(i));\n }\n return result;\n }\n void change_edge(int i, Cap new_cap, Cap new_flow) {\n int m = int(pos.size());\n assert(0 <= i && i < m);\n assert(0 <= new_flow && new_flow <= new_cap);\n auto& _e = g[pos[i].first][pos[i].second];\n auto& _re = g[_e.to][_e.rev];\n _e.cap = new_cap - new_flow;\n _re.cap = new_flow;\n }\n \n Cap flow(int s, int t) {\n return flow(s, t, std::numeric_limits<Cap>::max());\n }\n Cap flow(int s, int t, Cap flow_limit) {\n assert(0 <= s && s < _n);\n assert(0 <= t && t < _n);\n \n std::vector<int> level(_n), iter(_n);\n internal::simple_queue<int> que;\n \n auto bfs = [&]() {\n std::fill(level.begin(), level.end(), -1);\n level[s] = 0;\n que.clear();\n que.push(s);\n while (!que.empty()) {\n int v = que.front();\n que.pop();\n for (auto e : g[v]) {\n if (e.cap == 0 || level[e.to] >= 0) continue;\n level[e.to] = level[v] + 1;\n if (e.to == t) return;\n que.push(e.to);\n }\n }\n };\n auto dfs = [&](auto self, int v, Cap up) {\n if (v == s) return up;\n Cap res = 0;\n int level_v = level[v];\n for (int& i = iter[v]; i < int(g[v].size()); i++) {\n _edge& e = g[v][i];\n if (level_v <= level[e.to] || g[e.to][e.rev].cap == 0) continue;\n Cap d =\n self(self, e.to, std::min(up - res, g[e.to][e.rev].cap));\n if (d <= 0) continue;\n g[v][i].cap += d;\n g[e.to][e.rev].cap -= d;\n res += d;\n if (res == up) break;\n }\n return res;\n };\n \n Cap flow = 0;\n while (flow < flow_limit) {\n bfs();\n if (level[t] == -1) break;\n std::fill(iter.begin(), iter.end(), 0);\n while (flow < flow_limit) {\n Cap f = dfs(dfs, t, flow_limit - flow);\n if (!f) break;\n flow += f;\n }\n }\n return flow;\n }\n \n std::vector<bool> min_cut(int s) {\n std::vector<bool> visited(_n);\n internal::simple_queue<int> que;\n que.push(s);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n visited[p] = true;\n for (auto e : g[p]) {\n if (e.cap && !visited[e.to]) {\n visited[e.to] = true;\n que.push(e.to);\n }\n }\n }\n return visited;\n }\n \n private:\n int _n;\n struct _edge {\n int to, rev;\n Cap cap;\n };\n std::vector<std::pair<int, int>> pos;\n std::vector<std::vector<_edge>> g;\n};\n \n} // namespace atcoder\nusing namespace atcoder;\n\nvoid solve();\n// oddloop\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\t\n\tint t=1;\n\t//cin>>t;\n\trep(i,t) solve();\n}\n\nvoid solve(){\n\tint D,N;\n\tcin>>D>>N;\n\tvector<int> T(D);\n\tvector<int> A(N),B(N),C(N);\n\tvector<int> dp(N,-INF);\n\trep(i,D) cin>>T[i];\n\trep(i,N){\n\t\tcin>>A[i]>>B[i]>>C[i];\n\t\tif(A[i]<=T[0]&&T[0]<=B[i]) dp[i]=0;\n\t}\n\trep(day,D-1){\n\t\tvector<int> n_dp(N,-INF);\n\t\trep(i,N) rep(j,N){\n\t\t\tif(dp[j]==-INF) continue;\n\t\t\tif(A[i]<=T[day+1]&&T[day+1]<=B[i]){\n\t\t\t\tchmax(n_dp[i],dp[j]+abs(C[i]-C[j]));\n\t\t\t}\n\t\t}\n\t\tswap(n_dp,dp);\n\t}\n\tint ans=0;\n\trep(i,N) chmax(ans,dp[i]);\n\tcout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3368, "score_of_the_acc": -0.0043, "final_rank": 10 }, { "submission_id": "aoj_0579_5797828", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<sstream>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nint dp[200][200];\nsigned main(){\n\tint d,n,t[200],a[200],b[200],c[200];\n\tcin>>d>>n;\n\tfor(int i=0;i<d;i++)\n\t\tcin>>t[i];\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i]>>b[i]>>c[i];\n\tfor(int i=0;i<d;i++)\n\t\tfor(int j=0;j<n;j++)\n\t\t\tdp[i][j]=-1;\n\tfor(int i=0;i<n;i++)\n\t\tif(a[i]<=t[0]&&t[0]<=b[i])\n\t\t\tdp[0][i]=0;\n\tfor(int i=1;i<d;i++)\n\t\tfor(int j=0;j<n;j++)\n\t\t\tfor(int k=0;k<n;k++)\n\t\t\t\tif(dp[i-1][k]>=0&&a[j]<=t[i]&&t[i]<=b[j])\n\t\t\t\t\tdp[i][j]=max(dp[i][j],dp[i-1][k]+abs(c[j]-c[k]));\n\tint ans=0;\n\tfor(int i=0;i<n;i++)\n\t\tans=max(ans,dp[d-1][i]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3672, "score_of_the_acc": -0.0072, "final_rank": 14 }, { "submission_id": "aoj_0579_5769611", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\n\nvoid chmax(int &a, int b) { if (a < b) a = b; }\nvoid chmin(int &a, int b) { if (a > b) a = b; }\n\nint dp[205][205];\n\nint main() {\n int D, N;\n cin >> D >> N;\n vector<int> T(D), A(N), B(N), C(N);\n rep(i, D) cin >> T[i];\n rep(i, N) cin >> A[i] >> B[i] >> C[i];\n\n rep(i, D) rep(j, N) rep(k, N) {\n if (i == 0) continue;\n if (T[i] < A[j] || B[j] < T[i]) continue;\n if (T[i - 1] < A[k] || B[k] < T[i - 1]) continue;\n chmax(dp[i + 1][j], dp[i][k] + abs(C[j] - C[k]));\n }\n\n int ans = 0;\n rep(i, N) chmax(ans, dp[D][i]);\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3604, "score_of_the_acc": -0.0065, "final_rank": 13 }, { "submission_id": "aoj_0579_5229818", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <map>\n#include <cmath>\n#include <algorithm>\n#include <utility>\n#define INF 1000000100\nusing namespace std;\n\nvoid dijkstra(set<long> * v, map<pair<long, long>,long> * mp, long N, long total,vector<long>* retval);\n\nclass Cloth {\nprivate:\nlong a;\nlong b;\nlong c;\npublic:\nCloth(long a, long b, long c);\nbool is_wearable(long T);\nlong distance(Cloth * cloth);\n};\n\nCloth::Cloth(long _a, long _b, long _c){\n a=_a;\n b=_b;\n c=_c;\n}\n\nbool Cloth::is_wearable(long T){\n if(a<=T and T<=b) {\n return true;\n }\n else{\n return false;\n }\n}\n\nlong Cloth::distance(Cloth* cloth){\n return abs(c-cloth->c);\n}\n\nint main(void){\n long D,N;\n cin>>D>>N;\n vector<long> temperatures;\n vector<Cloth> clothes;\n for(long i=0; i<D; i++) {\n long temp;\n cin>>temp;\n temperatures.push_back(temp);\n }\n for(long i=0; i<N; i++) {\n long a,b,c;\n cin>>a>>b>>c;\n Cloth C = Cloth(a,b,c);\n clothes.push_back(C);\n }\n set<long>* v = new set<long> [D*N];\n map<pair<long,long>, long> mp;\n for(long i=0; i<D*N; i++) {\n v[i].clear();\n }\n\n\n for(long i=0; i<D-1; i++) {\n for(long j=0; j<N; j++) {\n if(!(clothes[j].is_wearable(temperatures[i]))) {\n continue;\n }\n for(long k=0; k<N; k++) {\n if(!(clothes[k].is_wearable(temperatures[i+1]))) {\n continue;\n }\n v[i*N+j].insert((i+1)*N+k);\n\n mp[make_pair(i*N+j,(i+1)*N+k)] = clothes[j].distance(&(clothes[k]));\n }\n }\n }\n vector<long> retval;\n dijkstra(v, &mp, N, N*D, &retval);\n long ans=0;\n for(long i=0; i<N; i++) {\n ans = max(ans, retval[N*D-i-1]);\n }\n\n cout<<ans<<endl;\n return 0;\n}\n\nvoid dijkstra(set<long> * v, map<pair<long, long>,long> * mp, long N, long total,vector<long>* retval){\n retval->clear();\n for(long i=0; i<total; i++) {\n retval->push_back(-1*INF);\n }\n for(long i=0; i<N; i++) {\n (*retval)[i]=0;\n }\n set<long> updated, next;\n updated.clear();\n for(int i=0; i<N; i++) {\n updated.insert(i);\n }\n while(!updated.empty()) {\n next.clear();\n for(auto iter=updated.begin(); iter!=updated.end(); iter++) {\n for(auto iter2=v[*iter].begin(); iter2!=v[*iter].end(); iter2++) {\n long weight=(*mp)[make_pair(*iter,*iter2)];\n if((*retval)[*iter2]<(*retval)[*iter]+weight) {\n (*retval)[*iter2]=(*retval)[*iter]+weight;\n next.insert(*iter2);\n }\n }\n }\n updated.swap(next);\n }\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 109344, "score_of_the_acc": -1.5263, "final_rank": 20 }, { "submission_id": "aoj_0579_5200663", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define repe(i,n) for (int i = 0; i <= (n); ++i)\n#define reps(i,s,n) for (int i = (s); i < (n); ++i)\n#define vi vector<ll>\n#define len(x) (int)(x).size()\n\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\n\nll inf = (1 << 30);\nint MOD = 1'000'000'007;\n\nstatic const int NIL = -1;\nstatic const ll NMAX = 1'000'000 + 5;\n\nll n;\n\nll dod[NMAX];\n\n\n\n\n\n\nint main(void) {\n\n\n\tint d, n;//日数 服の種類\n\tcin >> d >> n;\n\n\tvi tp(d), l(n), h(n), ds(n);\n\n\trep(i, d) cin >> tp[i];\n\trep(j, n) cin >> l[j] >> h[j] >> ds[j];\n\n\tvector<vector<ll>> dp(d, vector<ll>(n, -1));\n\n\n\trep(j, n) {\n\n\t\tif (l[j] <= tp[0] && tp[0] <= h[j]) dp[0][j] =0;\n\t}\n\n\tll ans = 0;\n\treps(i, 1, d) {\n\t\trep(j, n) {\n\t\t\trep(k, n) {\n\n\t\t\t\tif (l[k] <= tp[i] && tp[i] <= h[k] && dp[i - 1][j] != -1) {\n\n\t\t\t\t\tll scr = abs(ds[j] - ds[k]);\n\t\t\t\t\tchmax(dp[i][k], dp[i - 1][j] + scr);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\trep(i, n) chmax(ans, dp[d - 1][i]);\n\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3276, "score_of_the_acc": -0.0035, "final_rank": 8 }, { "submission_id": "aoj_0579_3978061", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n int D,N;\n cin >> D >> N;\n \n vector<int> T(D);\n for (int i = 0; i < D; i++) cin >> T.at(i);\n \n vector<vector<int>> ABC(N, vector<int>(3));\n for (int i = 0; i < N; i++) cin >> ABC.at(i).at(0)\n >> ABC.at(i).at(1)\n >> ABC.at(i).at(2);\n \n vector<vector<vector<int>>> dp( D , \n vector<vector<int>> ( N ,\n vector<int> ( N, -1)));\n \n for (int i = 0; i < N; i++) {\n if (ABC.at(i).at(0) <= T.at(0) && T.at(0) <= ABC.at(i).at(1)) {\n for (int j = 0; j < N; j++) {\n dp.at(0).at(i).at(j) = 0;\n }\n }\n }\n\n for (int i = 1; i < D; i++) {\n for (int j = 0; j < N; j++) {\n \n if (ABC.at(j).at(0) <= T.at(i) && T.at(i) <= ABC.at(j).at(1)) {\n\n for (int k = 0; k < N; k++) {\n dp.at(i).at(j).at(k) = 0;\n \n for (int l = 0; l < N; l++) {\n if (dp.at(i-1).at(k).at(l) == -1) continue;\n dp.at(i).at(j).at(k) = max(dp.at(i).at(j).at(k),\n dp.at(i-1).at(k).at(l) + abs(ABC.at(k).at(2) - ABC.at(j).at(2)));\n }\n }\n \n }\n \n }\n }\n \n int ans = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n ans = max(ans, dp.at(D-1).at(i).at(j));\n }\n }\n \n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 570, "memory_kb": 35908, "score_of_the_acc": -1.0469, "final_rank": 18 }, { "submission_id": "aoj_0579_3325405", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing vb=vector<bool>;\nusing vvb=vector<vb>;\nusing vd=vector<double>;\nusing vvd=vector<vd>;\nusing vi=vector<int>;\nusing vvi=vector<vi>;\nusing vl=vector<ll>;\nusing vvl=vector<vl>;\nusing pll=pair<ll,ll>;\nusing tll=tuple<ll,ll>;\nusing vs=vector<string>;\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define rep(i,n) range(i,0,n)\n#define rrep(i,n) for(int i=(n)-1;i>=0;i--)\n#define range(i,a,n) for(int i=(a);i<(n);i++)\n\n#define LINF \t((ll)1ll<<60)\n#define INF \t((int)1<<30)\n#define EPS \t(1e-9)\n#define MOD \t(1000000007ll)\n#define fcout(a)\tcout<<setprecision(a)<<fixed\n#define fs \t\t\tfirst\n#define sc\t\t\tsecond\n#define PI\t\t\t3.1415926535897932384\n\nint dx[]={1,0,-1,0,1,-1,-1,1},dy[]={0,1,0,-1,1,1,-1,-1};\ntemplate<class S,class T>ostream&operator<<(ostream&os,pair<S,T>p){os<<\"[\"<<p.first<<\", \"<<p.second<<\"]\";return os;};\ntemplate<class S>auto&operator<<(ostream&os,vector<S>t){bool a=1; for(auto s:t){os<<(a?\"\":\" \")<<s; a=0;} return os;}\nvoid OUT(bool b){cout<<(b?\"YES\":\"NO\")<<endl;}\nvoid Out(bool b){cout<<(b?\"Yes\":\"No\")<<endl;}\nvoid out(bool b){cout<<(b?\"yes\":\"no\")<<endl;}\nint popcnt(int x) { return __builtin_popcount(x); }\nint popcnt(ll x) { return __builtin_popcountll(x); }\nint clz(int x) { return 31 - __builtin_clz(x); }\nint clz(ll x) { return 63 - __builtin_clzll(x); }\nint ctz(int x) { return __builtin_ctz(x); }\nint ctz(ll x) { return __builtin_ctzll(x); }\n\nclass compare {\npublic:\n\tbool operator()(tuple<ll, ll> a, tuple<ll, ll> b) {\n\t\treturn (get<1>(a) > get<1>(b));\n\t}\n};\n\nint dp[201][201];\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tll n,d;\n\t//dp[last][day]\n\tcin>>d>>n;\n\tvi t(d),a(n),b(n),c(n);\n\trep(i,d)cin>>t[i];\n\trep(i,n)cin>>a[i]>>b[i]>>c[i];\n\trep(i,201){\n\t\trep(j,201){\n\t\t\tdp[j][i]=-1;\n\t\t}\n\t}\n\trep(i,d){\n\t\trep(j,n){\n\t\t\trep(k,n){\n\t\t\t\tif(a[k]<=t[i]&&t[i]<=b[k]){\n\t\t\t\t\tdp[k][i+1]=max(dp[k][i+1],dp[j][i]+((dp[j][i]!=-1)?abs(c[j]-c[k]):1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans=0;\n\trep(i,n){\n\t\tans=max(ans,dp[i][d]);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3364, "score_of_the_acc": -0.0043, "final_rank": 9 }, { "submission_id": "aoj_0579_2769620", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <map>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <vector>\n#include <stdlib.h>\n#include <stdio.h>\n#include <bitset>\n#include <cstring>\n#include <deque>\n#include <iomanip>\n#include <limits>\n#include <fstream>\nusing namespace std;\n#define FOR(I,A,B) for(int I = (A); I < (B); ++I)\n#define CLR(mat) memset(mat, -1, sizeof(mat))\ntypedef long long ll;\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(0);\n int D,N;cin>>D>>N;\n int T[D];FOR(i,0,D)cin>>T[i];\n int A[N],B[N],C[N];\n FOR(i,0,N)cin>>A[i]>>B[i]>>C[i];\n ll dp[D][N];\n CLR(dp);\n FOR(i,0,N){\n if(T[0]>=A[i]&&T[0]<=B[i]){\n dp[0][i]=0;\n }\n }\n ll ans=0;\n FOR(i,0,D-1){\n FOR(j,0,N){\n if(dp[i][j]==-1)continue;\n // i+1日目にkをきる\n FOR(k,0,N){\n if(T[i+1]>=A[k]&&T[i+1]<=B[k]){\n dp[i+1][k]=max(dp[i+1][k],dp[i][j]+abs(C[j]-C[k]));\n ans=max(ans,dp[i+1][k]);\n }\n }\n }\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3400, "score_of_the_acc": -0.0046, "final_rank": 11 }, { "submission_id": "aoj_0579_2651292", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\nint main(void){\n\tint dp[210][210],a[210],b[210],c[210],t[210],d,n,i,j,k,ans=0;\n\tfill(dp[0],dp[210],0);\n\tcin >> d >> n;\n\tfor(i=0; i<d; i++){\n\t\tcin >> t[i];\n\t}\n\tfor(j=0; j<n; j++){\n\t\tcin >> a[j] >> b[j] >> c[j];\n\t}\n\tfor(k=1; k<d; k++){\n\n\t\tfor(i=0; i<n; i++){\n\t\t\tif(a[i]<=t[k] && b[i]>=t[k]){\n\n\t\t\t\tfor(j=0; j<n; j++){\n\t\t\t\t\tif(a[j]<=t[k-1] && b[j]>=t[k-1]){\n\t\t\t\t\t\tdp[k][i] = max(dp[k][i],dp[k-1][j]+abs(c[i]-c[j]));\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t}\n\t\t}\n\n\t}\n\tfor(i=0; i<n; i++){\n\t\tans = max(ans,dp[d-1][i]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.0033, "final_rank": 6 }, { "submission_id": "aoj_0579_2630830", "code_snippet": "//============================================================================\n// Name : JOI.cpp\n// Author : Akari Fujii\n// Version :\n// Copyright : Your copyright notice\n// Description : Hello World in C++, Ansi-style\n//============================================================================\n\n#include <iostream>\n#include <cctype>\n#include <string>\n#include<algorithm>\n\nusing namespace std;\n\n\n// 1. dp?????????\nint dp[201][201];\n// 2. n????????????\nint d,n;\nint a[201],b[201],c[201],t[201];\n// ???. calc????????????\nint calc(int k,int m){\n\n\t// 8. dp???????????°??????\n\tif(dp[k][m]>=0)return dp[k][m];\n\tif(t[m]<a[k]||t[m]>b[k])return -1;\n\tfor(int i=1; i<n+1; ++i){\n\t\tif(calc(i,m-1)>=0)dp[k][m]=max(dp[k][m],abs(c[k]-c[i])+calc(i,m-1));\n\t}\n\treturn dp[k][m];\n\n}\n\nint main() {\n\n\tcin>>d>>n;\n\n\t// 3. ?????????\n\tfor(int i=0;i<201;++i){\n\t\tfor(int j=0;j<201;++j){\n\t\t\tdp[i][j]=-1;\n\t\t}\n\t}\n\t// 4.??\\???\n\tfor(int i=1; i<d+1; ++i)cin>>t[i];\n\tfor(int j=1; j<n+1; ++j)cin>>a[j]>>b[j]>>c[j];\n\n\t// 5. ???????????¨??????\n\n\tfor(int j=1; j<n+1; ++j){\n\t\tif(t[1]>=a[j]&&t[1]<=b[j]){\n\t\t\tdp[j][1]=0;\n\t\t}\n\t}\n\n\t// 6. ??????\n\n\tint total=0;\n\tfor(int i=1;i<n+1;++i){\n\t\ttotal=max(total,calc(i,d));\n\t}\n\tcout<<total<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3264, "score_of_the_acc": -0.0297, "final_rank": 16 }, { "submission_id": "aoj_0579_2630815", "code_snippet": "//============================================================================\n// Name : JOI.cpp\n// Author :\n// Version :\n// Copyright : Your copyright notice\n// Description : Hello World in C++, Ansi-style\n//============================================================================\n\n#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\nusing namespace std;\n\n// 1. dp?????????\nint dp[201][201];\n// 2. n?????????\nint D,N;\nint T[201];\nint A[205],B[205],C[205];\n\n// 7. calc?????????\nint calc(int k,int m){\n\t// 8. dp???????????°??????\n\tif(dp[k][m]>=0)return dp[k][m];\n\tif(T[m]<A[k] || T[m]>B[k])return -1;\n\t// 9. dp????¨????\n\tfor(int i=0;i<N;i++){\n\t\tint P=calc(i,m-1);\n\t\tif(P>=0)dp[k][m]=max(dp[k][m],abs(C[k]-C[i])+dp[i][m-1]);\n\t}\n\n\n\treturn dp[k][m];\n}\nint main() {\n\tcin>>D>>N;\n\n\t//3.?????????\n\tfor(int i=0;i<201;i++){\n\t\tfor(int j=0;j<201;j++){\n\t\t\tdp[i][j]=-1;\n\t\t}\n\t}\n\t//4.??\\???\n\tfor(int i=1;i<D+1;i++){\n\t\tcin>>T[i];\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tcin>>A[i]>>B[i]>>C[i];\n\t}\n\n\n\n\t//5.???????????¨???\n\tfor(int i=0;i<N;i++){\n\t\tif(T[1]>=A[i] && T[1]<=B[i])dp[i][1]=0;\n\t}\n\n\n\t//6.??????\n\tint total=0;\n\tfor(int i=0;i<N;i++){\n\t\ttotal=max(total,calc(i,D));\n\t}\n\n\tcout<<total<<endl;\n\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3200, "score_of_the_acc": -0.0027, "final_rank": 2 }, { "submission_id": "aoj_0579_2575983", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define llong long long \ntypedef struct data{\n\tint low;\n\tint high;\n\tint eva;\n}data;\nint D, N;\nint temp[201];\ndata kind[200];\nint score[201][200][200];\n\nint solve(int d, int k, int yk){\n\tif(score[d][k][yk] != -1) return score[d][k][yk];\n\tif(d == D) return score[d][k][yk] = fabs(kind[k].eva - kind[yk].eva);\n\n\tint e = 0;\n\tfor(int i = 0; i < N; i++){\n\t\tdata use = kind[i];\n\t\tif(use.low > temp[d + 1] || use.high < temp[d + 1]) continue;\n\t\tint sum;\n\t\tif(d > 1)sum = fabs(kind[k].eva - kind[yk].eva) + solve(d + 1, i, k);\n\t\telse sum = solve(d + 1, i, k);\n\t\te = max(e, sum);\n\t}\n\n\treturn score[d][k][yk] = e;\n}\n\nint main(){\n\tfill_n(temp, 201, -1);\n\tfill_n(**score, 201 * 200 * 200, -1);\n\tcin >> D >> N;\n\tfor(int i = 1; i <= D; i++){\n\t\tcin >> temp[i];\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> kind[i].low >> kind[i].high >> kind[i].eva;\n\t}\n\n\tcout << solve(0, 0, 0) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 34508, "score_of_the_acc": -0.7574, "final_rank": 17 }, { "submission_id": "aoj_0579_2522912", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[810][810];\nint main(void)\n{\n\tint d,n,i,j,k,sel[810],a[810],b[810],c[810],data,mx=-1;\n\tcin>>d>>n;\n\tfor(i=1;i<=d;i++) cin>>sel[i];\n\tfor(i=1;i<=n;i++) cin>>a[i]>>b[i]>>c[i];\n\tfor(i=1;i<=d;i++) for(j=1;j<n;j++) dp[i][j]=0;\n\tfor(i=1;i<=d;i++) {\n\t\tfor(j=1;j<=n;j++) {\n\t\t\tif(a[j]<=sel[i]&&sel[i]<=b[j]) {\n\t\t\t\tfor(k=1;k<=n;k++) {\n\t\t\t\t\tif(a[k]<=sel[i+1]&&sel[i+1]<=b[k]) {\n\t\t\t\t\t\tdata=abs(c[j]-c[k]);\n\t\t\t\t\t}\n\t\t\t\t\tdp[i+1][k]=max(dp[i][j]+data,dp[i+1][k]) ;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=1;i<=n;i++) mx=max(mx,dp[d][i]);\n\tcout<<mx<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3736, "score_of_the_acc": -0.0078, "final_rank": 15 }, { "submission_id": "aoj_0579_2514850", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint D,N;\nint temp[201];\nint cloth[201][3];\nint a[201][201][201];\n\n\nint dp(int d,int yk,int k){\n\tif(d > 0){\n\t\tif(!(cloth[k][0] <= temp[d] && cloth[k][1] >= temp[d]))return 0;\n\t}\n\n\tif(a[d][yk][k] >= 0) return a[d][yk][k];\n\n\tif(d == D){\n\t\treturn a[d][yk][k] = fabs(cloth[yk][2] - cloth[k][2]) ;\n\t}\n\n\tint eva = 0;\n\tint sum = 0;\n\tfor(int i = 1; i <= N ;i++){\n\t\tif(d < 2){\n\t\t\tsum = dp(d+1, k, i);\n\t\t\teva = max(eva,sum);\n\t\t}else{\n\t\t\tsum = dp(d +1, k, i) + fabs(cloth[yk][2] - cloth[k][2]);\n\t\t\t// cout <<d <<\" \"<< yk << \" \"<<k <<\" \"<< sum << endl;\n\t\t\teva = max(eva,sum);\n\t\t}\n\t}\n\n\treturn a[d][yk][k] = eva;\n\n\n\t// long long int eva = 0;\n\t// long long int sum = 0;\n\t// if(d >= 2){\n\n\t// \teva = fabs(yeva - cloth[k][2]);\n\t// }\n\n\t// if(d == D){\n\t// \t// cout<<d<<\" \"<<k<<\" \"<<eva<<endl;\n\t// \treturn a[d][k] = eva;\n\t// }\n\n\n\t// for(int i = 1;i <= N;i++){\n\t// \tif(d == 0){\n\t// \t\teva = max(eva, dp(d+1, i, 0));\n\t// \t}else if( d == 1){\n\t// \t\t// cout<<sum<< \" \"<<eva<<endl;\n\t// \t\t// cout<<eva<<\" \"<<dp(d+1,i,cloth[k][2])<<endl;\n\t// \t\teva = max(eva,dp(d+1, i, cloth[k][2]));\n\t// \t}else{\n\t// \t\tsum = dp(d+1,i,cloth[k][2]) + eva;\n\t// \t\tcout<<d<<\" \"<<dp(d+1,i,cloth[k][2])<<\" \"<<eva <<\" \"<<sum<<endl;\n\t// \t\t// cout<<eva<<\" \"<<dp(d+1,i,cloth[k][2])<<endl;\n\t// \t\teva = max(eva,sum);\n\t// \t}\n\t// }\n\t// // cout << d <<\" \" <<k<<\" \" << eva <<endl; \n\t// return a[d][k] = eva;\n}\n\n\nint main(){\n\tfill_n(temp,201,-1);\n\tfill_n(*cloth,201*3,-1);\n\tfill_n(**a,201*201*201,-1);\n\tcin >> D >> N;\n\tfor(int i = 1;i <= D;i++){\n\t\tcin >>temp[i];\n\t}\n\tfor(int i = 1;i <= N;i++){\n\t\tfor(int j = 0;j < 3;j++){\n\t\t\tcin >> cloth[i][j];\n\t\t}\n\t}\n\tcout << dp(0,0,0) << endl;\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 34808, "score_of_the_acc": -1.2997, "final_rank": 19 }, { "submission_id": "aoj_0579_2462399", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <vector>\n#include <string>\n#include <cstdio>\n#define INF 100000000\n\nusing namespace std;\nint dp[205][205] = { 0 }, t[205], a[205], b[205], c[205];\nint main(){\n\tint d, n;\n\tcin >> d >> n;\n\tfor (int i = 1; i <= d; i++) {\n\t\tcin >> t[i];\n\t}\n\tfor (int j = 1; j <= n; j++) {\n\t\tcin >> a[j] >> b[j] >> c[j];\n\t}\n\tfor (int i = 0; i < 201; i++) {\n\t\tfor (int j = 0; j < 201; j++) {\n\t\t\tdp[i][j] = -1;\n\t\t}\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (a[i] <= t[1] && t[1] <= b[i]) dp[1][i] = 0;\n\t}\n\tfor (int i = 2; i <= d; i++) {\n\t\tfor (int k = 1; k <= n; k++) {\n\t\t\tfor (int j = 1; j <= n; j++) {\n\t\t\t\tif (a[j] <= t[i] && t[i] <= b[j]&&a[k]<=t[i-1]&&t[i-1]<=b[k]) {\n\t\t\t\t\tdp[i][j] = max(dp[i][j], dp[i - 1][k] + abs(c[k] - c[j]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (ans < dp[d][i]) ans = dp[d][i];\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3264, "score_of_the_acc": -0.0033, "final_rank": 6 }, { "submission_id": "aoj_0579_2459388", "code_snippet": "#include <iostream>\n#include <cstring>\n#include <algorithm>\n#include <math.h>\n#define MOD 1000000007\nusing namespace std;\n\nint main()\n{\n\tint d, n,ans;\n\tint t[202],a[202],b[202],c[202];\n\tint dp[202][202] = {};\n\tcin >> d >> n;\n\tint i,j,k;\n\tfor (i = 0; i < d; i++){\n\t\tcin >> t[i];\n\t}\n\tfor (i = 0; i < n; i++){\n\t\tcin >> a[i] >> b[i] >> c[i];\n\t}\n\tfor (i = 0; i < d - 1; i++){\n\t\tfor (j = 0; j < n; j++){\n\t\t\tfor (k = 0; k < n; k++){\n\t\t\t\tif (a[k] <= t[i] && b[k] >= t[i] && a[j] <= t[i + 1] && b[j] >= t[i + 1] && dp[i + 1][j] <= dp[i][k] + abs(c[k] - c[j])){\n\t\t\t\t\tdp[i + 1][j] = dp[i][k] + abs(c[k] - c[j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tans = 0;\n\tfor (i = 0; i < n; i++){\n\t\tans = max(ans, dp[d - 1][i]);\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3260, "score_of_the_acc": -0.0033, "final_rank": 5 }, { "submission_id": "aoj_0579_2341605", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> plli;\ntypedef pair<int,pii> pipii;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<vi> vvi;\ntypedef vector<vvi> vvvi;\ntypedef vector<pii> vpii;\n\n#define int long long\n#define rep(i,n) for (int i=0;i<(n);i++)\n#define rep2(i,a,b) for (int i=(a);i<(b);i++)\n#define rrep(i,n) for (int i=(n);i>=0;i--)\n#define rrep2(i,a,b) for (int i=(a);i>b;i--)\n#define pb push_back\n#define fi first\n#define se second\n#define all(a) (a).begin(),(a).end()\n\nconst ll mod = 1e9 + 7;\nconst ll INF = 1<<30;\nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\nconst double pi = 3.141592653589793;\n\nint d,n;\nint t[205];\nvector<pair<int ,pair<int,int>>> cab;\nvector<vector<int>> cl(65);\nint dp[205][205];\n\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n cin >> d >> n;\n rep(i,d) cin >> t[i];\n rep(i,n){\n int a,b,c;\n cin >> a >> b >> c;\n cab.pb(make_pair(c,make_pair(a,b)));\n }\n rep(i,d)rep(j,n){\n int l=cab[j].se.fi;\n int r=cab[j].se.se;\n if (l<=t[i] && t[i]<=r) cl[t[i]].pb(j);\n }\n rep(i,d+1)rep(j,n) dp[i][j]=-INT_MAX;\n for (auto i: cl[t[0]]){\n for (auto j: cl[t[1]]){\n dp[2][j]=max(dp[2][j],abs(cab[i].fi-cab[j].fi));\n }\n }\n rep2(i,2,d)rep(j,n){\n for (auto k: cl[t[i]]){\n dp[i+1][k]=max(dp[i+1][k],dp[i][j]+abs(cab[j].fi-cab[k].fi));\n }\n }\n int ans=0;\n rep(j,n) ans=max(ans,dp[d][j]);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3576, "score_of_the_acc": -0.0063, "final_rank": 12 }, { "submission_id": "aoj_0579_2123249", "code_snippet": "#include <iostream>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <vector>\n#include <utility>\n#include <functional>\n#include <stack>\n#include <queue>\n#include <map>\n#include <set>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <deque>\n#include <ctime>\n\nusing namespace std;\n\n#define rep(i,n) REP(i,0,n)\n#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)\n#define pb push_back\n#define mp make_pair\n#define all(r) (r).begin(),(r).end()\n#define rall(r) (r).rbegin(),(r).rend()\n#define fi first\n#define se second\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n\nconst int INF = 1e9;\nconst ll LINF = 1e18;\nconst ll MOD = 1e9 + 7;\ndouble EPS = 1e-8;\nconst double PI = acos(-1);\n\nint dx[]={-1,1,0,0};\nint dy[]={0,0,-1,1};\nint d,n;\nint t[210];\nint a[210],b[210],c[210];\nint dp[210][210];\n\nint main(){\n\tcin >> d >> n;\n\tfor(int i=0; i<d; i++){\n\t\tcin >> t[i];\n\t}\n\tfor(int i=0; i<n; i++){\n\t\tcin >> a[i] >> b[i] >> c[i];\n\t}\n\n\tfor(int i=0; i<d; i++){\n\t\tfor(int j=0; j<n; j++){\n\t\t\tif(a[j] <= t[i] && t[i] <= b[j]){\n\t\t\t\tdp[i][j] = 0;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tdp[i][j] = -INF;\n\t\t\t}\n\t\t}\n\t}\n\t//????????????????????§?????????????????\\???????????¨??§?????????????????¨?????¨????????????\n\n\n\tfor(int i=d-2; i >= 0; i--){\n\t\tfor(int j=0; j < n; j++){\n\t\t\tfor(int k=0; k < n; k++){\n\t\t\t\tif(dp[i][j] >= 0){\n\t\t\t\t\tdp[i][j] = max(dp[i][j],\n\t\t\t\t\tdp[i+1][k] + abs(c[j] - c[k]));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint max = 0;\n\n\tfor(int i=0; i < n; i++){\n\t\tif(dp[0][i] > max){\n\t\t\tmax = dp[0][i];\n\t\t}\n\t}\n\n\tcout << max << endl;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3232, "score_of_the_acc": -0.003, "final_rank": 4 }, { "submission_id": "aoj_0579_2056130", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <climits>\n#include <string>\n#include <vector>\n#include <cmath>\nusing namespace std;\n\n#define INF 1145141919\n\nint D, N;\nint dp[210][210];\nint T[210];\nint A[210], B[210], C[210];\n\nint main() {\n cin >> D >> N;\n for (int i=0; i<D; i++) cin >> T[i];\n for (int i=0; i<N; i++) cin >> A[i] >> B[i] >> C[i];\n\n for (int i=0; i<D; i++) {\n for (int j=0; j<N; j++) {\n dp[i][j] = -INF;\n }\n }\n for (int i=0; i<N; i++) {\n if (T[0] >= A[i] && T[0] <= B[i]) dp[0][i] = 0;\n }\n for (int i=0; i<D; i++) {\n for (int j=0; j<N; j++) {\n for (int k=0; k<N; k++) {\n if (T[i+1] >= A[k] && T[i+1] <= B[k]) {\n dp[i+1][k] = max(dp[i+1][k], dp[i][j] + abs(C[j] - C[k]));\n }\n }\n }\n }\n int ans = 0;\n for (int i=0; i<N; i++) {\n ans = max(ans, dp[D-1][i]);\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3212, "score_of_the_acc": -0.0029, "final_rank": 3 }, { "submission_id": "aoj_0579_2046984", "code_snippet": "#include<cstdio>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n\nconst int INF = -100000000;\n\nint main(){\n int d,n,a[200],b[200],c[200],t[200];\n scanf(\"%d %d\",&d,&n);\n for(int i=0;i<d;i++) scanf(\"%d\",t+i);\n for(int i=0;i<n;i++) scanf(\"%d %d %d\",a+i,b+i,c+i);\n int dp[200][200];\n fill(dp[0],dp[0]+200,INF);\n for(int i=0;i<d;i++){\n for(int j=0;j<n;j++){\n if(i==0){\n if(a[j]<=t[i]&&t[i]<=b[j]){\n dp[i][j] = 0;\n }\n continue;\n }\n dp[i][j] = 0;\n for(int k=0;k<n;k++){\n if(a[j]<=t[i]&&t[i]<=b[j]){\n dp[i][j] = max(dp[i][j],dp[i-1][k]+max(c[j],c[k])-min(c[j],c[k]));\n }\n }\n }\n }\n int ans = 0;\n for(int i=0;i<n;i++) ans = max(ans,dp[d-1][i]);\n printf(\"%d\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 2908, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0574_cpp
釘(Nails) JOI くんは板に釘を刺して遊んでいる.下図のように,JOI くんは一辺 N 本の正三角形の形に釘を並べて刺した.上から a 行目(1 ≤ a ≤ N ) には a 本の釘が並んでいる.そのうち左から b 本目(1 ≤ b ≤ a ) の釘を( a , b ) で表す. 図1: 釘の並び方( N = 5 の場合) 釘を頂点とする正三角形が,「各辺が全体の正三角形の辺のいずれかと平行で,全体の正三角形と同じ向き」であるとき,この正三角形を「 よい正三角形 」と呼ぶ.すなわち,「よい正三角形」とは,3 本の釘( a , b ), ( a + x , b ), ( a + x , b + x ) を頂点とする正三角形のことである(ただし a , b , x は1 ≤ a < N , 1 ≤ b ≤ a , 1 ≤ x ≤ N - a ) をみたす). JOI くんは,輪ゴムを使って,「よい正三角形」の周りを囲うことにした. 図2: 輪ゴムによる「よい正三角形」の囲い方の例 課題 正三角形の一辺に並んでいる釘の本数 N と,JOI くんが持っている輪ゴムの数 M と, M 本の輪ゴムによる「よい正三角形」の囲い方が与えられたとき,1 本以上の輪ゴムで囲われた釘の本数を求めるプログラムを作成せよ. 制限 2 ≤ N ≤ 5000     一辺に並んでいる釘の本数 1 ≤ M ≤ 500000 (= 5 × 10 5 )     輪ゴムの数 入力 標準入力から以下のデータを読み込め. 1 行目には整数 N , M が空白を区切りとして書かれている. N は正三角形の一辺に並んでいる釘の本数を, M はJOI くんの持っている輪ゴムの数をそれぞれ表す. 続く M 行は輪ゴムによる「よい正三角形」の囲い方の情報を表す. i + 1 行目(1 ≤ i ≤ M ) には整数 A i , B i , X i (1 ≤ A i < N , 1 ≤ B i ≤ A i , 1 ≤ X i ≤ N - A i ) が空白を区切りとして書かれている.これは, i 本目の輪ゴムは3 本の釘( A i , B i ), ( A i + X i , B i ), ( A i + X i , B i + X i ) を頂点とする「よい正三角形」を囲っていることを表す. 出力 標準出力に,1 本以上の輪ゴムに囲われている釘の本数を1 行で出力せよ. 採点基準 採点用データのうち,配点の30% 分については, M ≤ 10000 を満たす. 入出力例 入力例 1 5 2 2 2 1 2 1 3 出力例 1 12 この例は図2 のような「よい正三角形」の囲い方に対応している.この例において,(1, 1), (4, 4), (5, 5) 以外の12 本の釘が1 本以上の輪ゴムで囲われている. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0574_10851569", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, char>;\n\nint main() {\n int N, M;\n cin >> N >> M;\n vector<vector<int>> sum(N+3, vector<int>(N+3));\n for(int i=0; i<M; ++i) {\n int A, B, X;\n cin >> A >> B >> X;\n sum[A][B] += 1;\n sum[A][B+1] += -1;\n sum[A+X+1][B] += -1;\n sum[A+X+2][B+1] += 1;\n sum[A+X+1][B+X+2] += 1;\n sum[A+X+2][B+X+2] += -1;\n }\n for(int i=0; i<N+3; ++i) {\n for(int j=0; j<=i; ++j) {\n sum[i][j+1] += sum[i][j];\n }\n }\n for(int i=0; i<N+2; ++i) {\n for(int j=0; j<=i; ++j) {\n sum[i+1][j] += sum[i][j];\n }\n }\n for(int i=0; i<N+2; ++i) {\n for(int j=0; j<=i; ++j) {\n sum[i+1][j+1] += sum[i][j];\n }\n }\n int res = 0;\n for(int i=0; i<N+3; ++i) {\n for(int j=0; j<N+3; ++j) {\n res += sum[i][j] > 0;\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 101060, "score_of_the_acc": -0.5719, "final_rank": 9 }, { "submission_id": "aoj_0574_10320611", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define rep(i,n,m) for(int i=(int)(n);i < (int)(m); i++)\n#define repm(i,n,m) for(int i=(int)(n);i >= (int)(m); i--)\n// #define _GLIBCXX_DEBUG\nusing namespace std;\n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n int n,m;\n cin >> n >> m;\n vector<vector<int>> Adj(n);\n rep(i,0,n){\n rep(j,0,i+1){\n Adj[i].push_back(0);\n }\n }\n int a,b,x;\n rep(i,0,m){\n cin >> a >> b >> x;\n a--;\n b--;\n Adj[a][b]++;\n int p = a + x + 1, p2 = b + x + 2;\n if(b < a) Adj[a][b + 1]--;\n if(p < n){\n Adj[p][b]--;\n if(p2 < p + 1) Adj[p][p2]++;\n }\n if(p + 1 < n){\n Adj[p + 1][b + 1]++;\n if(p2 < p + 2) Adj[p+1][p2]--;\n }\n }\n rep(i,0,n)rep(j,1,i+1){\n Adj[i][j] += Adj[i][j-1];\n }\n rep(i,0,n)rep(j,i+1,n){\n Adj[j][i] += Adj[j-1][i];\n }\n rep(i,0,n)rep(j,i+1,n){\n Adj[j][j-i] += Adj[j-1][j-i-1];\n }\n int ans = 0;\n rep(i,0,n)rep(j,0,i+1){\n if(Adj[i][j] > 0) ans++;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 64588, "score_of_the_acc": -0.48, "final_rank": 8 }, { "submission_id": "aoj_0574_9612711", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nint main() {\n ll N,M;\n cin>>N>>M;\n vector<vector<ll>> A(N+2,vector<ll>(N+2,0));\n vector<vector<ll>> B(N+2,vector<ll>(N+2,0));\n for(int i=0;i<M;i++){\n ll a,b,x;\n cin>>a>>b>>x;\n a--;b--;\n A[a][b]++;\n A[a+x+1][b]--;\n B[a][b+1]--;\n B[a+x+1][b+x+2]++;\n }\n\n for(int b=0;b<=N+1;b++){\n for(int a=0;a<N+1;a++)A[a+1][b]+=A[a][b];\n }\n for(int a=0;a<=N+1;a++){\n for(int b=0;b<=N+1;b++){\n if(a<N+1&&b<N+1)B[a+1][b+1]+=B[a][b];\n }\n }\n for(int a=0;a<=N+1;a++){\n for(int b=0;b<=N+1;b++)A[a][b]+=B[a][b];\n }\n ll an=0;\n for(int a=0;a<=N+1;a++){\n for(int b=0;b<N+1;b++){\n A[a][b+1]+=A[a][b];\n if(A[a][b]>0)an++;\n }\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 394372, "score_of_the_acc": -1.9714, "final_rank": 20 }, { "submission_id": "aoj_0574_9552372", "code_snippet": "#include <stdio.h>\n#include <algorithm> // std::sort を使用するために必要\nusing namespace std;\n\n// 最大500,000個の区間を保持する配列\npair<pair<int, int>, int> Q[500000];\n\n// 各行に対する最大値を保持する配列\nint val[2][5001];\n\nint main() {\n int a, b;\n // 行数(a)と区間数(b)を入力\n scanf(\"%d%d\", &a, &b);\n\n // 各区間の情報を入力\n for (int i = 0; i < b; i++) {\n int c, d, e;\n scanf(\"%d%d%d\", &c, &d, &e);\n // Qに区間の始点(c)、終点(d)、値(e)を格納\n Q[i] = make_pair(make_pair(c, d), e);\n }\n\n // Qを区間の始点(c)でソート\n std::sort(Q, Q + b);\n\n int ret = 0; // 結果を格納する変数\n int at = 0; // 現在処理中のQのインデックス\n\n // 各行について処理\n for (int i = 0; i < a; i++) {\n int e = i & 1; // 偶数行か奇数行かで配列を切り替える\n\n // 現在の行(i+1)に対応する区間情報を処理\n while (at < b && Q[at].first.first == i + 1) {\n // 区間の終点に対応する列の値を最大化\n val[e][Q[at].first.second - 1] = max(val[e][Q[at].first.second - 1], Q[at].second + 1);\n at++;\n }\n\n // この行で条件を満たす列の数をカウント\n for (int j = 0; j <= i; j++) {\n if (val[e][j]) ret++;\n }\n\n // 次の行に備えて配列を初期化\n for (int j = 0; j <= i + 1; j++) {\n val[!e][j] = 0;\n }\n\n // 現在の行の結果を次の行に反映\n for (int j = 0; j <= i; j++) {\n val[!e][j] = max(val[!e][j], val[e][j] - 1); // 同じ列に反映\n val[!e][j + 1] = max(val[!e][j + 1], val[e][j] - 1); // 隣接する列に反映\n }\n }\n\n // 結果を出力\n printf(\"%d\\n\", ret);\n\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 8860, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0574_9188471", "code_snippet": "#include <bits/stdc++.h>\n\nstd::mt19937 mt{std::random_device{}()};\n\nvoid solve() {\n int N, M;\n // N = mt() % 10 + 2;\n // M = 1;\n std::cin >> N >> M;\n std::vector<std::vector<int>> P(N + 1); //, Q(N + 1);\n for (int i{} ; i < N + 1 ; i++) {\n P[i] = std::move(std::vector<int>(i));\n // Q[i] = std::move(std::vector<int>(i));\n }\n // std::cout << N << ' ' << M << std::endl;\n for (int i{} ; i < M ; i++) {\n int A, B, X;\n // A = mt() % (N - 1) + 1;\n // B = mt() % A + 1;\n // X = mt() % (N - A) + 1;\n // std::cout << A << ' ' << B << ' ' << X << std::endl;\n std::cin >> A >> B >> X;\n B--;\n P[A][B]++;\n if (B + 1 < A) {\n P[A][B + 1]--;\n }\n if (A + X + 1 <= N) {\n P[A + X + 1][B]--;\n }\n if (A + X + 2 <= N and B + 1 < A + X + 2) {\n P[A + X + 2][B + 1]++;\n }\n if (A + X + 1 <= N and B + X + 2 < A + X + 1) {\n P[A + X + 1][B + X + 2]++;\n }\n if (A + X + 2 <= N and B + X + 2 < A + X + 2) {\n P[A + X + 2][B + X + 2]--;\n }\n\n // for (int j{} ; j <= X ; j++) {\n // for (int k{} ; k <= j ; k++) {\n // Q[A + j][B + k]++;\n // }\n // }\n }\n for (int i{2} ; i <= N ; i++) {\n for (int j{1} ; j < i ; j++) {\n P[i][j] += P[i - 1][j - 1];\n }\n } \n for (int i{1} ; i <= N ; i++) {\n for (int j{1} ; j < i ; j++) {\n P[i][j] += P[i][j - 1];\n }\n }\n for (int i{} ; i <= N ; i++) {\n for (int j{} ; j < i ; j++) {\n if (j < i - 1) {\n P[i][j] += P[i - 1][j];\n }\n }\n }\n int ans{};\n for (int i{} ; i <= N ; i++) {\n for (int j{} ; j < i ; j++) {\n ans += (P[i][j] >= 1);\n }\n }\n std::cout << ans << std::endl;\n // if (P != Q) {\n // for (int i{} ; i <= N ; i++) {\n // for (int j{} ; j < i ; j++) {\n // std::cout << P[i][j] << (j + 1 == i ? '\\n' : ' ');\n // }\n // }\n // for (int i{} ; i <= N ; i++) {\n // for (int j{} ; j < i ; j++) {\n // std::cout << Q[i][j] << (j + 1 == i ? '\\n' : ' ');\n // }\n // }\n // return false;\n // }\n // return true;\n}\n\nint main() {\n solve();\n // while (solve()) ;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 52464, "score_of_the_acc": -0.4495, "final_rank": 6 }, { "submission_id": "aoj_0574_8887372", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n, m, al[5003][5003] {}, an{};\n cin >> n >> m;\n for (int i = 0; i < m; ++i) {\n int a, b, x;\n cin >> a >> b >> x;\n --a;\n --b;\n ++al[a][b];\n --al[a][b+1];\n --al[a+x+1][b];\n ++al[a+x+2][b+1];\n ++al[a+x+1][b+x+2];\n --al[a+x+2][b+x+2];\n }\n // for (int i = 0; i < n + 1; ++i) {\n // for (int j = 0; j <= i + 1; ++j) cout << al[i][j] << ' ';\n // cout << '\\n';\n // }\n for (int i = 0; i < n + 2; ++i) {\n for (int j = 0; j < i + 1; ++j) {\n al[i][j+1] = al[i][j] + al[i][j+1];\n }\n }\n // for (int i = 0; i < n + 1; ++i) {\n // for (int j = 0; j <= i + 1; ++j) cout << al[i][j] << ' ';\n // cout << '\\n';\n // }\n for (int i = 0; i < n + 1; ++i) {\n for (int j = 0; j < i + 2; ++j) {\n al[i+1][j] += al[i][j];\n }\n }\n // for (int i = 0; i < n + 1; ++i) {\n // for (int j = 0; j <= i + 1; ++j) cout << al[i][j] << ' ';\n // cout << '\\n';\n // }\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < i + 1; ++j) al[i+1][j+1] += al[i][j];\n }\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < i + 1; j++) {\n if (0 < al[i][j]) ++an;\n }\n }\n cout << an << '\\n';\n // for (int i = 0; i < n; ++i) {\n // for (int j = 0; j <= i + 1; ++j) cout << al[i][j] << ' ';\n // cout << '\\n';\n // }\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 100868, "score_of_the_acc": -0.6847, "final_rank": 12 }, { "submission_id": "aoj_0574_7969865", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n int n, m;\n std::cin >> n >> m;\n\n // auto print = [](std::vector< std::vector< int > > &vs) {\n // for (auto &v: vs) {\n // for (auto &a: v) {\n // std::cerr << a << \" \";\n // }\n // std::cerr << std::endl;\n // }\n // std::cerr << std::endl;\n // };\n\n auto pimos = std::vector(n + 1, std::vector(n + 1, 0));\n auto nimos = std::vector(n + 1, std::vector(n + 1, 0));\n for (int i = 0; i < m; i++) {\n int a, b, x;\n std::cin >> a >> b >> x;\n\n a--; b--;\n x++;\n \n pimos[a][b]++;\n pimos[a + x][b + x]--;\n\n nimos[a + x][b]--;\n nimos[a + x][b + x]++;\n }\n\n // pimos\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n pimos[i + 1][j + 1] += pimos[i][j];\n }\n }\n // print(pimos);\n\n // nimos\n for (int i = 0; i < n + 1; i++) {\n for (int j = 0; j < n; j++) {\n nimos[i][j + 1] += nimos[i][j];\n }\n }\n // print(nimos);\n\n auto imos = pimos;\n for (int i = 0; i < n + 1; i++) {\n for (int j = 0; j < n + 1; j++) {\n imos[i][j] += nimos[i][j];\n }\n }\n // print(imos);\n\n int ans = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n imos[i + 1][j] += imos[i][j];\n if (imos[i][j] > 0) ans++;\n }\n }\n\n std::cout << ans << std::endl;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 297060, "score_of_the_acc": -1.2356, "final_rank": 18 }, { "submission_id": "aoj_0574_7969850", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint func(){\n int n;\n cin >> n;\n vector<vector<int>> table1(n,vector<int>(n,0));\n vector<vector<int>> table2(n,vector<int>(n,0));\n auto add = [&](int y,int x,int v,vector<vector<int>> &table){\n if(y < 0 or x < 0)return;\n if(x > y)return;\n if(y >= n)return;\n table[y][x] += v;\n };\n auto get = [&](int y,int x, vector<vector<int>> &table){\n if(y < 0 or x < 0)return 0;\n if(x > y)return 0;\n if(y >= n)return 0;\n return table[y][x];\n };\n int m;\n cin >> m;\n for(int i=0;i<m;++i){\n int a;\n int b;\n int x;\n cin >> a >> b >> x;\n --a;\n --b;\n add(a,b,1,table1);\n add(a+x+1,b,-1,table1);\n add(a,b+1,-1,table2);\n add(a+x+1,b+1+x+1,1,table2);\n }\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n add(i+1,j,get(i,j,table1),table1);\n }\n }\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n add(i+1,j+1,get(i,j,table2),table2);\n }\n }\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n add(i,j,get(i,j,table2),table1);\n }\n }\n for(int i=0;i<n;++i){\n for(int j=0;j<n;++j){\n add(i,j+1,get(i,j,table1),table1);\n }\n }\n int res = 0;\n for(int i=0;i<n;++i){\n for(int j=0;j<=i;++j){\n if(get(i,j,table1)){\n ++res;\n }\n }\n }\n return res;\n}\n\nint main(){\n cout << func() << endl;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 198708, "score_of_the_acc": -1.0255, "final_rank": 16 }, { "submission_id": "aoj_0574_7969845", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n, m;\n cin >> n >> m;\n vector<vector<int>> dp(n + 1, vector<int>(n + 1, -1));\n for (int i = 0; i < m; i++) {\n int a, b, x;\n cin >> a >> b >> x;\n dp[a][b] = x;\n }\n for (int i = 1; i < n; i++) {\n for (int j = 1; j <= i; j++) {\n dp[i + 1][j] = max(dp[i + 1][j], dp[i][j] - 1); \n dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i][j] - 1);\n }\n }\n int ans = 0;\n for (int i = 1; i <= n; i++) {\n for (int j = 1; j <= i; j++) {\n if (dp[i][j] >= 0) {\n ans++;\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 101028, "score_of_the_acc": -0.4398, "final_rank": 5 }, { "submission_id": "aoj_0574_6814773", "code_snippet": "#include<iostream>\n#include<vector>\nusing namespace std;\ntypedef long long ll;\nconst int mod=1e9+7;\nint imos1[5001][5001],imos2[5001][5002];\nint main(){\n\tint n,m,a,b,x;\n\tcin>>n>>m;\n\twhile(cin>>a>>b>>x){\n\t\ta--,b--,x++;\n\t\timos1[a][b]++;\n\t\timos1[a+x][b]--;\n\t\timos2[a+x][b+1]--;\n\t\timos2[a+x][b+x+1]++;\n\t}\n\tfor(int i=1;i<n;i++)\n\t\tfor(int j=0;j<=i;j++)\n\t\t\timos1[i][j]+=imos1[i-1][j];\n\tfor(int i=0;i<n;i++)\n\t\tfor(int j=1;j<=i;j++)\n\t\t\timos2[i][j]+=imos2[i][j-1];\n\tfor(int i=1;i<n;i++){\n\t\tfor(int j=1;j<=i;j++){\n\t\t\timos1[i][j]+=imos1[i-1][j-1];\n\t\t\timos2[i][j]+=imos2[i-1][j-1];\n\t\t}\n\t}\n\tint ans=0;\n\tfor(int i=0;i<n;i++)\n\t\tfor(int j=0;j<=i;j++)\n\t\t\tif(imos1[i][j]+imos2[i][j]>0)\n\t\t\t\tans++;\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 197220, "score_of_the_acc": -0.7765, "final_rank": 13 }, { "submission_id": "aoj_0574_6455591", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n\n\n#define ll long long\n#define rep(i,a,b) for(int i = a; i < b; i++)\n#define REP(i,a,b) for(int i = a; i <=b; i++)\n#define fore(i,a) for(auto &i : a)\n#define all(x) (x).begin(),(x).end()\n#define fix(i) fixed << setprecision(i)\n#define nextp(v) next_permutation(all(v))\n\n\n\ntemplate<class T>bool chmax(T& a, const T& b) { if(a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if(b < a) { a = b; return 1; } return 0; }\n\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing pq = priority_queue<int>;\nusing pqll = priority_queue<ll>;\n\n\n\nconst ll INF = LLONG_MAX/2;\nconst ll MOD = 1000000007;\n\n\nvoid debug(vector<vector<int>> t, int N) {\n rep(i,0,N+3) {\n rep(j,0,N+3-i) cout << \" \";\n rep(j,0,i+1) cout << (t[i][j] == 0 ? ' ' : (t[i][j] > 0 ? '+' : '-')) << \" \";\n cout << endl;\n }\n \n return;\n}\n\n\nint main() {\n int N, M; cin >> N >> M;\n \n vector<vector<int>> t(N+3, vector<int>(N+3));\n \n rep(i,0,M) {\n int A, B, X; cin >> A >> B >> X;\n \n t[A][B-1]++; t[A][B]--;\n t[A+X+2][B]++; t[A+X+1][B-1]--;\n t[A+X+1][B+X+1]++; t[A+X+2][B+X+1]--;\n }\n \n // debug(t, N);\n \n rep(i,0,N+3) {\n int Sum = 0;\n rep(j,0,i+1) {\n Sum += t[i][j];\n t[i][j] = Sum;\n }\n }\n \n // debug(t, N);\n \n rep(i,0,N+3) {\n int Sum = 0;\n rep(j,0,N+3-i) {\n Sum += t[i+j][i];\n t[i+j][i] = Sum;\n }\n }\n \n // debug(t, N);\n \n rep(i,0,N+3) {\n int Sum = 0;\n rep(j,0,N+3-i) {\n Sum += t[i+j][j];\n t[i+j][j] = Sum;\n }\n }\n \n // debug(t, N);\n \n \n int Ans = 0;\n rep(i,0,N+3) {\n rep(j,0,i+1) {\n if(t[i][j] > 0) Ans++;\n }\n }\n \n printf(\"%d\\n\", Ans);\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 101040, "score_of_the_acc": -0.7983, "final_rank": 14 }, { "submission_id": "aoj_0574_6361924", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n vector<vector<int>> t(n);\n for(int i=0;i<n;i++){\n t[i].resize(i+1,-1);\n }\n int a,b,x;\n while(m--){\n in(a,b,x);\n a--,b--;\n chmax(t[a][b],x);\n }\n int ans=0;\n for(int i=0;i<n;i++){\n for(int j=0;j<=i;j++){\n if(i+1<n){\n chmax(t[i+1][j],t[i][j]-1);\n chmax(t[i+1][j+1],t[i][j]-1);\n }\n if(t[i][j]>=0)ans++;\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 52600, "score_of_the_acc": -0.1668, "final_rank": 2 }, { "submission_id": "aoj_0574_6291376", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e17;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll N, M; cin >> N >> M;\n vector<vector<ll>>A(N, vector<ll>(N, 0)), B(N, vector<ll>(N, 0));\n vector<ll>X(M), Y(M), Z(M);\n for (ll i = 0; i < M; i++) {\n ll a, b, x; cin >> a >> b >> x;\n X[i] = a; Y[i] = b; Z[i] = x;\n a--; b--;\n A[a][b]++;\n if (a + x + 1 < N) {\n A[a + x + 1][b]--;\n }\n B[a][b + 1]--;\n if (a + x + 1 < N && b + x + 2 < N) B[a + x + 1][b + x + 2]++;\n }\n for (ll i = 1; i < N; i++) {\n for (ll j = 1; j < N; j++) {\n B[i][j] += B[i - 1][j - 1];\n }\n }\n for (ll i = 1; i < N; i++) {\n for (ll j = 0; j < N; j++) {\n A[i][j] += A[i - 1][j];\n }\n }\n for (ll i = 0; i < N; i++) {\n for (ll j = 1; j < N; j++) {\n A[i][j] += A[i][j - 1] + B[i][j];\n }\n }\n ll ans = 0;\n for (ll i = 0; i < N; i++) {\n for (ll j = 0; j < N; j++) {\n ans += (A[i][j] > 0);\n }\n }\n cout << ans << endl;\n}\nint main() {\n ll T = 1; //cin >> T; \n while (T--) solve();\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 405736, "score_of_the_acc": -1.6415, "final_rank": 19 }, { "submission_id": "aoj_0574_6212616", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <iostream>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <functional>\n#include <set>\n#include <map>\n#include <string>\n#include <vector>\n#include <cmath>\n#include<sstream>\n#include<list>\n#include<iomanip>\n#include <cstdlib>\n#include <cstring>\n#include <stack>\n#include <bitset>\n#include <cassert>\n#include <stdlib.h>\n#include <stdio.h>\nusing namespace std;\nconst int INF = 100000000;\nconst long long LINF = 3e18 + 7;\nconst int MAX_N = 600010;\nconst int MAX_W = 10002;\nconst int MAX_ARRAYK = 100000;\ndouble PI = 3.14159265358979323846;\n//using ll = long long;\n\n\nint N, M;\nint table[MAX_W][MAX_W];\nint X;\n\nint main() {\n\n\tcin >> N >> M;\n\tfor (int i = 0; i < M; i++) {\n\t\tint A, B, X;\n\t\tcin >> A >> B >> X;\n\t\tA--;\n\t\tB--;\n\t\ttable[A][B] = X + 1;\n\t}\n\n\tint ans = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j <= i; j++) {\n\t\t\tif (i > 0){\n\t\t\t\ttable[i][j] = max(table[i][j], table[i - 1][j] - 1);\n\t\t\t}\n\t\t\tif (i > 0 && j > 0) {\n\t\t\t\ttable[i][j] = max(table[i][j], table[i - 1][j - 1] - 1);\n\t\t\t}\n\t\t\tif (table[i][j] > 0) {\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 71900, "score_of_the_acc": -0.4796, "final_rank": 7 }, { "submission_id": "aoj_0574_6038081", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvector<vector<int> >A(5009);\nint main(){\n int sum=0,n,m,a,b,c;\n for(int i=0;i<5009;i++){\n A[i].assign(i+7,0);\n }\n cin>>n>>m;\n while(m--){\n cin>>a>>b>>c;\n A[a][b]++;\n A[a][b+1]--;\n A[a+c+1][b]--;\n A[a+c+1][b+c+2]++;\n A[a+c+2][b+1]++;\n A[a+c+2][b+c+2]--;\n }\n for(int i=0;i<=n+3;i++){\n for(int j=0;j<i+2;j++){\n if(j) A[i][j]+=A[i][j-1];\n }\n }\n for(int i=0;i<=n+3;i++){\n for(int j=0;j<=i+3;j++){\n if(i) A[i][j]+=A[i-1][j];\n }\n }\n for(int i=0;i<=n+3;i++){\n for(int j=0;j<=i+3;j++){\n if(i&&j) A[i][j]+=A[i-1][j-1];\n }\n }\n for(int i=0;i<=n+3;i++){\n for(int j=0;j<=i+5;j++){\n if(A[i][j]>0) sum++;\n }\n }\n cout<<sum<<endl;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 52760, "score_of_the_acc": -0.4314, "final_rank": 4 }, { "submission_id": "aoj_0574_5851375", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\nvoid chmin(int &a, int b){ if(a > b) a = b; }\nvoid chmax(int &a, int b){ if(a < b) a = b; }\n\nint tate[5050][5050];\nint naname[5050][5050];\nint imos[5050][5050];\n\nint main(){\n int n, m;\n cin >> n >> m;\n rep(i, m){\n int a, b, l;\n cin >> a >> b >> l;\n a--, b--;\n \n int y = a - b;\n int x = b;\n l++;\n// cout << y << \" \" << x << endl;\n \n tate[y][x]++;\n tate[y + l][x]--;\n naname[y][x + l]--;\n naname[y + l][x]++;\n }\n \n rep(i, n){\n rep(j, n){\n tate[i + 1][j] += tate[i][j];\n naname[i + 1][j] += naname[i][j + 1];\n }\n }\n \n rep(i, n){\n rep(j, n){\n imos[i][j] = tate[i][j] + naname[i][j];\n }\n }\n \n rep(i, n){\n rep(j, n){\n imos[i][j + 1] += imos[i][j];\n }\n }\n \n int ans = 0;\n rep(i, n){\n rep(j, n){\n ans += !!imos[i][j];\n// cout << imos[i][j] << \" \";\n }\n// cout << endl;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 301328, "score_of_the_acc": -1.0577, "final_rank": 17 }, { "submission_id": "aoj_0574_5215074", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n#include<map>\nusing namespace std;\n\nint main() {\n\tint n, m;\n\tint a, b, c;\n\tcin >> n >> m;\n\tint** num = new int* [n+2];\n\tfor (int i = 0;i < n + 2;i++) {\n\t\tnum[i] = new int[i + 2];\n\t\tfor (int j = 0;j <= i + 1;j++) {\n\t\t\tnum[i][j] = 0;\n\t\t}\n\t}\n\tfor (int i = 0;i < m;i++) {\n\t\tcin >> a >> b >> c;\n\t\ta--;\n\t\tb--;\n\t\tnum[a][b]++;\n\t\t\n\t\tnum[a + c + 1][b]--;\n\t\t\t\n\t\t\n\t\t\n\t\tnum[a + c + 2][b + 1]++;\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\tnum[a][b + 1]--;\n\t\t\n\t\tnum[a + c + 1][b + c + 2]++;\n\t\t\t\n\t\t\n\t\tnum[a + c + 2][b + c + 2]--;\n\t\t\t\n\t}\n\tfor (int i = 1;i < n+2;i++) {\n\t\tfor (int j = 0;j < i + 1;j++) {\n\t\t\tnum[i][j] += num[i - 1][j];\n\t\t}\n\t}\n\tfor (int i = 1;i < n+2;i++) {\n\t\tfor (int j = 1;j <= i + 1;j++) {\n\t\t\tnum[i][j] += num[i - 1][j - 1];\n\t\t}\n\t}\n\tfor (int i = 1;i < n + 2;i++) {\n\t\tfor (int j = 1;j <= i + 1;j++) {\n\t\t\tnum[i][j] += num[i][j-1];\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 0;i < n;i++) {\n\t\tfor (int j = 0;j <= i;j++) {\n\t\t\tif (num[i][j] > 0) {\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 52448, "score_of_the_acc": -0.4306, "final_rank": 3 }, { "submission_id": "aoj_0574_5092988", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\nusing ll = long long;\nusing P = pair<int, int>;\n\nint main(){\n int n,m; cin>>n>>m;\n vector<vector<int>> wa(n+4,vector<int>(n+4));\n while(m--){\n int a,b,x; cin>>a>>b>>x;\n wa[a][b]++;\n wa[a][b+1]--;\n wa[a+x+1][b]--;\n wa[a+x+1][b+x+2]++;\n wa[a+x+2][b+1]++;\n wa[a+x+2][b+x+2]--;\n }\n for(int i=0; i<n+3; i++){\n for(int j=0; j<n+3; j++){\n wa[i+1][j+1] += wa[i+1][j];\n }\n }\n for (int i = 0; i < n + 3; i++) {\n for (int j = 0; j < n + 3; j++) {\n wa[j+1][i+1] += wa[j][i+1]; // *itr 順番\n }\n }\n for (int i = 0; i < n + 3; i++) {\n for (int j = 0; j < n + 3; j++) {\n wa[i + 1][j + 1] += wa[i][j];\n }\n }\n int ans = 0;\n for(int i=1; i<=n; i++){\n for(int j=1; j<=i; j++){\n if(wa[i][j]>=1) ans++;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 100988, "score_of_the_acc": -0.8736, "final_rank": 15 }, { "submission_id": "aoj_0574_5016909", "code_snippet": "#define rep(i, s, e) for (int i = s; i < e; ++i)\n \n#include <bits/stdc++.h>\n//#include <atcoder/all>\n \nusing namespace std;\n//using namespace atcoder;\n \nint INF = 1<<20;\n \nint main() {\n int N, M; cin >> N >> M;\n vector<vector<int>> num(N+2, vector<int>(N+2, 0));\n rep (i, 0, M) {\n int a, b, x; cin >> a >> b >> x;\n --a;\n --b;\n ++num[a][b]; ++num[a+x+1][b+x+2]; ++num[a+x+2][b+1];\n --num[a][b+1]; --num[a+x+1][b]; --num[a+x+2][b+x+2];\n }\n rep (A, 0, N) {\n rep (B, 0, A+1) {\n num[A][B+1] += num[A][B];\n } \n }\n rep (A, 0, N) {\n rep (B, 0, A+1) {\n num[A+1][B] += num[A][B];\n }\n }\n rep (A, 0, N) {\n rep (B, 0, A+1) {\n num[A+1][B+1] += num[A][B];\n } \n }\n\n int res = 0;\n rep(A, 0, N) {\n rep (B, 0, A+1) {\n if (num[A][B] >= 1) ++res;\n }\n }\n\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 100816, "score_of_the_acc": -0.6845, "final_rank": 11 }, { "submission_id": "aoj_0574_4982800", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nint imos[5050][5050];\nint naname[5050][5050];\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint n,m; cin >> n >> m;\n\tfor(int i=0;i<m;i++){\n\t\tint a,b,x; cin >> a >> b >> x;\n\t\ta--; b--;\n\t\timos[a][b]++;\n\t\timos[a+x+1][b]--;\n\t\tnaname[a][b+1]--;\n\t\tnaname[a+x+1][b+x+2]++;\n\t}\n\tfor(int i=1;i<n+1;i++){\n\t\tfor(int j=0;j<=i;j++){\n\t\t\timos[i][j]+=imos[i-1][j];\n\t\t}\n\t}\n\tfor(int i=1;i<n+1;i++){\n\t\tfor(int j=1;j<=i+1;j++){\n\t\t\tnaname[i][j]+=naname[i-1][j-1];\n\t\t}\n\t}\n\tfor(int i=0;i<5050;i++){\n\t\tfor(int j=0;j<5050;j++){\n\t\t\timos[i][j]+=(j>0?imos[i][j-1]:0)+naname[i][j];\n\t\t}\n\t}\n\tint res=0;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<=i;j++){\n\t\t\t// cout << imos[i][j] << \" \";\n\t\t\tres+=(imos[i][j]>0?1:0);\n\t\t}\n\t\t// cout << endl;\n\t}\n\tcout << res << endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 169800, "score_of_the_acc": -0.6697, "final_rank": 10 } ]
aoj_0575_cpp
JOI 国のお祭り事情(Festivals in JOI Kingdom) JOI 国にはN 個の街があり,それらの間は M 本の双方向に通行可能な道路で結ばれている.国民は道路を通ってそれらの街を移動する. JOI 国の国民には,お祭りが好きな人が多く,現在, K 個の街でお祭りが開催されており,非常に賑わっている.一方で,一部の国民はお祭りを騒がしいとして嫌い,お祭りにできるだけ近づきたくないと思っている. そこで国王は,優秀なプログラマーであるあなたに,そのようなお祭りを嫌う国民のため,ある街からある街に移動するために,お祭りが開催されている街にどれだけ近づかずに移動することができるかを高速に調べることのできるプログラムの作成を依頼した. 課題 道路の情報とお祭りが開催されている街の情報,および Q 個のクエリ(出発する街 S i と行きたい街 T i の組)が与えられる.各クエリ i に対し,街 S i から街 T i へのすべての経路のうち,お祭りまでの距離が最大となる経路の,お祭りまでの距離を求めるプログラムを作成せよ.ただし,ある経路のお祭りまでの距離とは,経路上の街からお祭りが開催されている街までの移動距離の最小値のことである. 制限 2 ≤ N ≤ 100000 (= 10 5 )     JOI 国の街の個数 1 ≤ M ≤ 200000 (= 2 × 10 5 )     JOI 国の道路の本数 1 ≤ K ≤ N お祭りが開催されている街の個数 1 ≤ Q ≤ 100000 (= 10 5 )     クエリの個数 1 ≤ L i ≤ 1000 i 番目の道路の長さ 入力 標準入力から以下のデータを読み込め. 1 行目には整数 N , M , K , Q が空白を区切りとして書かれている. N はJOI 国の街の個数を, M はJOI国の道路の本数を, K はお祭りが開催されている街の個数を, Q はクエリの個数をそれぞれ表す.街には1, 2, ... , N の番号がつけられている. 続く M 行は道路の情報を表す. i + 1 行目(1 ≤ i ≤ M ) には整数 A i , B i , L i (1 ≤ A i ≤ N , 1 ≤ B i ≤ N ) が空白を区切りとして書かれている.これは, i 番目の道路が街 A i と街 B i を結んでおり,長さが L i であることを表す.道路の両端が同じ街であることはない.また,任意の2 つの街 p , q に対し, p と q を結ぶ道路は2 本以上存在しない.どの街からどの街へもいくつかの道路をたどって行くことができる. 続く K 行はお祭りが開催されている街の情報を表す. i + M + 1 行目(1 ≤ i ≤ K ) には1 つの整数 F i (1 ≤ F i ≤ N ) が書かれている.これは街 F i でお祭りが開催されていることを表す. F 1 , ..., F K の中に同じ値が2 回以上現れることはない. 続く Q 行はクエリを表す. i + M + K + 1 行目(1 ≤ i ≤ Q ) には2 つの整数 S i , T i (1 ≤ S i ≤ N , 1 ≤ T i ≤ N , S i ≠ T i ) が空白を区切りとして書かれている.これは i 番目のクエリの出発する街が S i であり行きたい街が T i であることを表す. 出力 標準出力に,全クエリへの答えを Q 行で出力せよ.すなわち, i 行目に,街 S i から街 T i へのすべての経路のうち,お祭りまでの距離が最大となる経路の,お祭りまでの距離を表す整数を出力せよ. 採点基準 採点用データのうち, 配点の10% 分については, Q = 1 を満たす. 配点の20% 分については, N ≤ 5000, Q ≤ 5000 を満たす. 配点の30% 分については,これら2 つの条件の少なくとも一方を満たす.また,これら2 つの条件の両方を満たすような採点用データはない. 入出力例 入力例 1 6 6 2 3 1 2 5 2 3 4 2 4 6 3 5 9 4 5 3 5 6 7 1 6 3 4 5 2 1 4 出力例 1 7 5 0 6 つの街が6 本の道路で結ばれており,お祭りは街1, 6 の2 つの街で開催されている.クエリは以下の3 つである. 1 つ目のクエリは街3 から街4 へ行くというものである.街2 を経由する経路ではお祭りまでの距離は5,街5 を経由する経路ではお祭りまでの距離は7 となるため,答えは7 である. 2 つ目のクエリは街5 から街2 へ行くというものである.街3 と街4 のどちらを経由しても,街2 でお祭りまでの距離が最小となり,答えは5 である. 3 つ目のクエリは街1 から街4 へ行くというものである.街1 はお祭りが開催されている街であるため,答えは0 となる. 図1: 入力例1 入力例 2 12 17 2 5 1 3 6 1 6 7 2 3 8 2 4 4 2 8 11 2 12 2 3 6 3 3 7 8 3 11 2 4 12 2 5 10 3 6 10 5 8 9 6 8 12 7 9 10 6 11 9 10 12 9 5 8 7 2 6 5 2 1 10 8 9 9 4 出力例 2 8 8 11 0 6 図1: 入力例2 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0575_10867647", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, int>;\n\nclass union_find {\npublic:\n union_find(int n)\n : par_(n, -1)\n {}\n void init(int n) {\n par_.assign(n, -1);\n }\n\n int root(int x) {\n return par_[x] < 0 ? x : par_[x] = root(par_[x]);\n }\n\n bool unite(int x, int y) {\n x = root(x); y = root(y);\n if(x == y) {\n return false;\n } else {\n if(par_[x] < par_[y]) {\n par_[x] += par_[y];\n par_[y] = x;\n } else {\n par_[y] += par_[x];\n par_[x] = y;\n }\n return true;\n }\n }\n\n bool same(int x, int y) {\n return root(x) == root(y);\n }\n\n int size(int x) {\n return -par_[root(x)];\n }\n\nprivate:\n std::vector<int> par_;\n};\n\n\nstruct edge {\n int from, to, cost;\n bool operator<(edge const& other) const {\n return cost > other.cost;\n }\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\n\nclass lca {\npublic:\n lca(vector<vector<int>>& g, int root)\n : V(g.size()),\n log_V(0),\n depth_(V, 0)\n {\n for(int v=V; v>0; v /= 2) {\n ++log_V;\n }\n parent.assign(log_V, std::vector<int>(V, 0));\n dfs(g, root, -1, 0);\n for(int k=0; k+1 < log_V; ++k) {\n for(int v=0; v<V; ++v) {\n if(parent[k][v] < 0) {\n parent[k+1][v] = -1;\n } else {\n parent[k+1][v] = parent[k][parent[k][v]];\n }\n }\n }\n }\n\n void dfs(vector<vector<int>> const& g, int v, int p, int d) {\n parent[0][v] = p;\n depth_[v] = d;\n for(int i=0; i<g[v].size(); ++i) {\n if(g[v][i] != p) {\n dfs(g, g[v][i], v, d+1);\n }\n }\n }\n\n int depth(int v) const {\n return depth_[v];\n }\n\n int query(int u, int v) {\n if(depth_[u] > depth_[v]) {\n std::swap(u, v);\n }\n for(int k=0; k<log_V; ++k) {\n if((depth_[v] - depth_[u]) >> k & 1) {\n v = parent[k][v];\n }\n }\n if(u == v) {\n return u;\n }\n for(int k=log_V - 1; k>=0; --k) {\n if(parent[k][u] != parent[k][v]) {\n u = parent[k][u];\n v = parent[k][v];\n }\n }\n return parent[0][u];\n }\n\nprivate:\n int V, log_V;\n std::vector<vector<int>> parent;\n std::vector<int> depth_;\n};\n\n\nconstexpr int INF = 1e9;\n\nint main() {\n int N, M, K, Q;\n cin >> N >> M >> K >> Q;\n graph g(N);\n for(int i=0; i<M; ++i) {\n int a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n g[a].push_back((edge){a, b, l});\n g[b].push_back((edge){b, a, l});\n }\n\n vector<int> d(2*N, INF);\n priority_queue<P, vector<P>, greater<P>> que;\n for(int i=0; i<K; ++i) {\n int f;\n cin >> f;\n f--;\n d[f] = 0;\n que.push(make_pair(0, f));\n }\n while(!que.empty()) {\n P p = que.top();\n que.pop();\n int v = p.second;\n if(d[v] < p.first) {\n continue;\n }\n for(auto& e : g[v]) {\n if(d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n que.push(make_pair(d[e.to], e.to));\n }\n }\n }\n\n edges es;\n for(int i=0; i<N; ++i) {\n for(auto& e : g[i]) {\n if(i < e.to) {\n es.push_back((edge){i, e.to, min(d[i], d[e.to])});\n }\n }\n }\n sort(es.begin(), es.end());\n\n union_find uf(N);\n vector<vector<int>> tree(2*N);\n int new_id = N;\n vector<int> id(N);\n for(int i=0; i<N; ++i) {\n id[i] = i;\n }\n for(auto& e : es) {\n int a = uf.root(e.from), b = uf.root(e.to);\n if(uf.unite(a, b)) {\n tree[new_id].push_back(id[a]);\n tree[new_id].push_back(id[b]);\n d[new_id] = min(d[id[a]], d[id[b]]);\n id[uf.root(a)] = new_id;\n new_id += 1;\n }\n }\n\n lca l(tree, new_id-1);\n for(int i=0; i<Q; ++i) {\n int s, t;\n cin >> s >> t;\n s--; t--;\n cout << d[l.query(s, t)] << endl;\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 46300, "score_of_the_acc": -0.7933, "final_rank": 9 }, { "submission_id": "aoj_0575_10826524", "code_snippet": "#include <vector>\n#include <iostream>\n#include <queue>\n#include <algorithm>\n#define INF 1000000001LL\n#define LNF 1000000000000000001LL\n#define MOD 1000000007LL\n#define MAX 200000\n#define long long long\n#define all(x) x.begin(),x.end()\nusing namespace std;\n\n\nclass Unionfind\n{\npublic:\n vector<int> parent;\n \n void init(int size)\n {\n parent = vector<int>(size);\n for(int i = 0; i<size; i++)\n parent[i] = i;\n }\n int find(int x)\n {\n if(parent[x] == x)\n return x;\n return parent[x] = find(parent[x]);\n }\n \n void merge(int x, int y)\n {\n x = find(x);\n y = find(y);\n\n if(x == y)\n return;\n \n if(x < y)\n parent[y] = x;\n else\n parent[x] = y;\n }\n bool isMerge(int x, int y)\n {\n x = find(x);\n y = find(y);\n return x == y;\n }\n};\nvector<pair<int,int>> graph[100000];\npair<int,int> dp[20][100000];\nint depth[100000];\n\nvoid dfs(int x, int d, int par, int v)\n{\n depth[x] = d;\n dp[0][x] = {par,v};\n\n for(int i = 0; i<graph[x].size(); i++)\n {\n int y = graph[x][i].first;\n int w = graph[x][i].second;\n\n if(y == par)\n continue;\n dfs(y,d+1,x,w);\n }\n}\n\nint lca(int x, int y)\n{\n if(depth[x] > depth[y])\n swap(x,y);\n\n int diff = depth[y]-depth[x];\n\n int res = INF;\n\n for(int i = 0; i<20; i++)\n {\n if(diff&(1<<i))\n {\n res = min(res,dp[i][y].second);\n y = dp[i][y].first;\n }\n }\n if(x == y)\n return res;\n \n for(int i = 19; i>=0; i--)\n {\n if(dp[i][x].first != dp[i][y].first)\n {\n res = min(res,dp[i][x].second);\n res = min(res,dp[i][y].second);\n x = dp[i][x].first;\n y = dp[i][y].first;\n }\n }\n res = min(res,dp[0][x].second);\n res = min(res,dp[0][y].second);\n return res;\n}\nint main()\n{\n\tios_base::sync_with_stdio(0); \n cin.tie(0);\n \n int n,m,k,q;\n cin >> n >> m >> k >> q;\n\n vector<pair<int,pair<int,int>>> edge(m);\n for(int i = 0; i<m; i++)\n {\n int a,b,c;\n cin >> a >> b >> c;\n a--;\n b--;\n graph[a].push_back({b,c});\n graph[b].push_back({a,c});\n\n edge[i] = {0,{a,b}};\n }\n\n priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> pq;\n vector<int> vis(n,INF);\n for(int i = 0; i<k; i++)\n {\n int x;\n cin >> x;\n x--;\n pq.push({0,x});\n vis[x] = 0;\n }\n while(!pq.empty())\n {\n int x = pq.top().second;\n int v = pq.top().first;\n pq.pop();\n if(vis[x] < v)\n continue;\n \n for(int i = 0; i<graph[x].size(); i++)\n {\n int y = graph[x][i].first;\n int w = graph[x][i].second;\n\n if(v+w < vis[y])\n {\n vis[y] = v+w;\n pq.push({v+w,y});\n }\n }\n }\n for(int i = 0; i<m; i++)\n edge[i].first = min(vis[edge[i].second.first],vis[edge[i].second.second]);\n sort(all(edge));\n reverse(all(edge));\n\n Unionfind uf;\n uf.init(n);\n for(int i = 0; i<n; i++)\n graph[i].clear();\n\n for(int i = 0; i<m; i++)\n {\n int c = edge[i].first;\n int a = edge[i].second.first;\n int b = edge[i].second.second;\n\n if(uf.isMerge(a,b))\n continue;\n \n uf.merge(a,b);\n graph[a].push_back({b,c});\n graph[b].push_back({a,c});\n }\n\n dfs(0,0,0,0);\n\n for(int i = 1; i<20; i++)\n {\n for(int j = 0; j<n; j++)\n {\n dp[i][j].first = dp[i-1][dp[i-1][j].first].first;\n dp[i][j].second = min(dp[i-1][dp[i-1][j].first].second,dp[i-1][j].second);\n }\n }\n\n while(q--)\n {\n int a,b;\n cin >> a >> b;\n a--;\n b--;\n cout << lca(a,b) << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 31036, "score_of_the_acc": -0.306, "final_rank": 3 }, { "submission_id": "aoj_0575_10716805", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\n/* とりあえず各町のお祭りからの距離を知りたいので、多始点ダイクストラみたいなことをする\n ダブリングらしいけどどうテーブルを作るか\n 答えで二分探索したい気持ち\n dp[i][j]: 街jからお祭りまでの距離を2^i以下で移動できる街のリスト?\n Q≤1e5なので各クエリにO(log?)くらいでこたえたい\n\n*/\n\nstruct UnionFind {\n vector<int> par, rank, siz;\n\n // 構造体の初期化\n UnionFind(int n) : par(n,-1), rank(n,0), siz(n,1) { }\n\n // 根を求める\n int root(int x) {\n if (par[x]==-1) return x; // x が根の場合は x を返す\n else return par[x] = root(par[x]); // 経路圧縮\n }\n\n // x と y が同じグループに属するか (= 根が一致するか)\n bool issame(int x, int y) {\n return root(x)==root(y);\n }\n\n // x を含むグループと y を含むグループを併合する\n bool unite(int x, int y) {\n int rx = root(x), ry = root(y); // x 側と y 側の根を取得する\n if (rx==ry) return false; // すでに同じグループのときは何もしない\n // union by rank\n if (rank[rx]<rank[ry]) swap(rx, ry); // ry 側の rank が小さくなるようにする\n par[ry] = rx; // ry を rx の子とする\n if (rank[rx]==rank[ry]) rank[rx]++; // rx 側の rank を調整する\n siz[rx] += siz[ry]; // rx 側の siz を調整する\n return true;\n }\n\n // x を含む根付き木のサイズを求める\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main(){\n ll n, m, k, q;\n cin >> n >> m >> k >> q;\n vv<pll> G(n, vc<pll>());\n rep(i, m){\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].pb(make_pair(b, l));\n G[b].pb(make_pair(a, l));\n }\n set<ll> st;\n rep(i, k){\n ll f;\n cin >> f;\n f--;\n st.insert(f);\n }\n vl s(q), t(q);\n rep(i, q){\n cin >> s[i] >> t[i];\n s[i]--; t[i]--;\n }\n\n // 各街のお祭りまでの距離を求める\n vl d(n, INF); // d[i]: 町iのお祭りまでの距離\n pq_g<pll> pq;\n for(ll u : st) pq.push(make_pair(0, u));\n vb seen(n, false);\n\n while(pq.size()){\n auto [costu, u] = pq.top();\n pq.pop();\n\n if(costu > d[u]) continue;\n d[u] = costu;\n seen[u] = true;\n\n for(auto [v, duv] : G[u]){\n if(seen[v]) continue;\n if(d[v] > d[u] + duv){\n d[v] = d[u] + duv;\n pq.push(make_pair(d[v], v));\n }\n }\n }\n\n // 辺をコストの降順でソート。コストが最大になる全域木Fをつくる。クラスカル法\n vc<tuple<ll, ll, ll>> edges;\n rep(u, n){\n for(auto [v, l] : G[u]){\n edges.pb(make_tuple(u, v, min(d[u], d[v])));\n }\n }\n\n sort(nall(edges), [](auto const &l, auto const &r){\n return get<2>(l) > get<2>(r);\n });\n\n vvl F(n, vl());\n UnionFind uf = UnionFind(n);\n for(auto [from, to, cost] : edges){\n if(!uf.issame(from, to)){\n uf.unite(from, to);\n F[from].pb(to);\n F[to].pb(from);\n }\n }\n\n // LCAの下準備\n ll maxLogN = 20;\n /* dp[i][u]: Fを頂点0を根とする根付き木としてみたときの\n 頂点uの2^i個上の親と,そのパス上でのコスト最小の頂点のペア\n */\n vv<pll> dp(maxLogN, vc<pll>(n));\n vl dist(n, -1);\n\n auto dfs = [&](auto self, ll u, ll p, ll dd) -> void{\n ll second = (p == -1 ? d[u] : min(d[p], d[u]));\n dp[0][u] = make_pair(p, second);\n dist[u] = dd;\n for(ll v : F[u]){\n if(v == p) continue;\n\n self(self, v, u, dd+1);\n }\n return;\n };\n\n dfs(dfs, 0, -1, 0);\n rep(i, maxLogN-1){\n rep(j, n){\n if(dp[i][j].first == -1){\n dp[i+1][j] = make_pair(-1, dp[i][j].second);\n }\n else{\n dp[i+1][j] = make_pair(dp[i][dp[i][j].first].first, min(dp[i][j].second, dp[i][dp[i][j].first].second));\n }\n }\n }\n\n // LCAの計算\n rep(qq, q){\n ll ans = INF;\n\n ll u = s[qq], v = t[qq];\n if(dist[u] < dist[v]) swap(u, v);\n rep(i, maxLogN){\n if(((dist[u] - dist[v]) >> i) & 1ll){\n chmin(ans, dp[i][u].second); // uを変更する前にUが上に行くパス上の最小値を調べる必要がある\n u = dp[i][u].first;\n }\n }\n\n if(u == v){\n cout << ans << endl;\n continue; \n }\n drep(i, maxLogN){\n if(dp[i][u].first != dp[i][v].first){\n ans = min({ans, dp[i][u].second, dp[i][v].second}); // u, vを変更する前にu,vそれぞれが通ることになるパスを調べておく。\n u = dp[i][u].first;\n v = dp[i][v].first;\n }\n }\n // ans = min(ans, dp[0][u].seco;d);\n ans = min({ans, dp[0][u].second, dp[0][v].second});\n\n cout << ans << endl;\n }\n\n // vv_cout(F);\n // cout << endl;\n // vc_cout(dist);\n\n return 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 69184, "score_of_the_acc": -1.2125, "final_rank": 14 }, { "submission_id": "aoj_0575_10716796", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\nstruct UnionFind {\n vector<int> par, rank, siz;\n\n // 構造体の初期化\n UnionFind(int n) : par(n,-1), rank(n,0), siz(n,1) { }\n\n // 根を求める\n int root(int x) {\n if (par[x]==-1) return x; // x が根の場合は x を返す\n else return par[x] = root(par[x]); // 経路圧縮\n }\n\n // x と y が同じグループに属するか (= 根が一致するか)\n bool issame(int x, int y) {\n return root(x)==root(y);\n }\n\n // x を含むグループと y を含むグループを併合する\n bool unite(int x, int y) {\n int rx = root(x), ry = root(y); // x 側と y 側の根を取得する\n if (rx==ry) return false; // すでに同じグループのときは何もしない\n // union by rank\n if (rank[rx]<rank[ry]) swap(rx, ry); // ry 側の rank が小さくなるようにする\n par[ry] = rx; // ry を rx の子とする\n if (rank[rx]==rank[ry]) rank[rx]++; // rx 側の rank を調整する\n siz[rx] += siz[ry]; // rx 側の siz を調整する\n return true;\n }\n\n // x を含む根付き木のサイズを求める\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main(){\n ll n, m, k, q;\n cin >> n >> m >> k >> q;\n vv<pll> G(n, vc<pll>());\n rep(i, m){\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].pb({b, l});\n G[b].pb({a, l});\n }\n\n // ダイクストラで各町の祭りからの距離distを求める.\n pq_g<pll> pq;\n rep(i, k){\n ll f;\n cin >> f;\n f--;\n pq.push({0, f});\n }\n vl dist(n, INF);\n vb seen(n, false);\n while(pq.size()){\n auto [costu, u] = pq.top();\n pq.pop();\n\n if(seen[u]) continue;\n dist[u] = costu;\n seen[u] = true;\n\n for(auto [v, duv] : G[u]){\n if(seen[v]) continue;\n if(dist[v] > dist[u] + duv){\n dist[v] = dist[u] + duv;\n pq.push({dist[v], v});\n }\n }\n }\n\n /* 辺のコスト = (端点の祭りからの距離のうち小さい方)\n 辺コストが大きいものだけでグラフFを作る\n */\n vv<pll> F(n, vc<pll>());\n UnionFind uf = UnionFind(n);\n vc<tuple<ll, ll, ll>> edges;\n rep(u, n){\n for(auto [v, l] : G[u]){\n ll c = min(dist[u], dist[v]);\n edges.push_back({u, v, c});\n }\n }\n\n sort(nall(edges), [](auto const &l, auto const &r){\n return get<2>(l) > get<2>(r);\n });\n\n for(auto [u, v, c] : edges){\n if(uf.issame(u, v)) continue;\n uf.unite(u, v);\n F[u].pb({v, c});\n F[v].pb({u, c});\n }\n \n /* LCAの準備\n dp[i][u]: uの2^i上の親と,そのパス上での辺のコストの最小値のペア\n */\n ll maxLogN = 20;\n vv<pll> dp(maxLogN, vc<pll>(n));\n vl d(n, -1); // 根0からの距離\n\n auto dfs = [&](auto self, ll u, ll p, ll dd) -> void{\n if(p == -1) dp[0][u] = {p, dist[u]};\n else dp[0][u] = {p, min(dist[u], dist[p])};\n \n d[u] = dd;\n\n for(auto [v, c] : F[u]){\n if(v == p) continue;\n self(self, v, u, dd+1);\n }\n return;\n };\n\n dfs(dfs, 0, -1, 0);\n for(ll i = 0; i+1 < maxLogN; i++){\n rep(v, n){\n if(dp[i][v].first == -1) dp[i+1][v] = {-1, dp[i][v].second};\n else{\n dp[i+1][v].first = dp[i][dp[i][v].first].first;\n dp[i+1][v].second = min(dp[i][v].second, dp[i][dp[i][v].first].second);\n }\n }\n }\n\n /* クエリの処理\n */\n vl ans(q);\n rep(qq, q){\n ll s, t;\n cin >> s >> t;\n s--; t--;\n\n ll tmpans = INF;\n\n if(d[s] < d[t]) swap(s, t);\n rep(i, maxLogN){\n if(((d[s] - d[t]) >> i) & 1ll){\n chmin(tmpans, dp[i][s].second);\n s = dp[i][s].first;\n }\n }\n\n if(s == t){\n ans[qq] = tmpans;\n continue;\n }\n drep(i, maxLogN){\n if(dp[i][s].first != dp[i][t].first){\n tmpans = min({tmpans, dp[i][s].second, dp[i][t].second});\n s = dp[i][s].first;\n t = dp[i][t].first;\n }\n }\n\n tmpans = min({tmpans, dp[0][s].second, dp[0][t].second});\n\n ans[qq] = tmpans;\n }\n\n for(ll a : ans) cout << a << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 69160, "score_of_the_acc": -1.2121, "final_rank": 13 }, { "submission_id": "aoj_0575_10716785", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\nstruct UnionFind {\n vector<int> par, rank, siz;\n\n // 構造体の初期化\n UnionFind(int n) : par(n,-1), rank(n,0), siz(n,1) { }\n\n // 根を求める\n int root(int x) {\n if (par[x]==-1) return x; // x が根の場合は x を返す\n else return par[x] = root(par[x]); // 経路圧縮\n }\n\n // x と y が同じグループに属するか (= 根が一致するか)\n bool issame(int x, int y) {\n return root(x)==root(y);\n }\n\n // x を含むグループと y を含むグループを併合する\n bool unite(int x, int y) {\n int rx = root(x), ry = root(y); // x 側と y 側の根を取得する\n if (rx==ry) return false; // すでに同じグループのときは何もしない\n // union by rank\n if (rank[rx]<rank[ry]) swap(rx, ry); // ry 側の rank が小さくなるようにする\n par[ry] = rx; // ry を rx の子とする\n if (rank[rx]==rank[ry]) rank[rx]++; // rx 側の rank を調整する\n siz[rx] += siz[ry]; // rx 側の siz を調整する\n return true;\n }\n\n // x を含む根付き木のサイズを求める\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main(){\n ll n, m, k, q;\n cin >> n >> m >> k >> q;\n vv<pll> G(n, vc<pll>());\n rep(i, m){\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].pb({b, l});\n G[b].pb({a, l});\n }\n\n // ダイクストラで各町の祭りからの距離distを求める.\n pq_g<pll> pq;\n rep(i, k){\n ll f;\n cin >> f;\n f--;\n pq.push({0, f});\n }\n vl dist(n, INF);\n vb seen(n, false);\n while(pq.size()){\n auto [costu, u] = pq.top();\n pq.pop();\n\n if(seen[u]) continue;\n dist[u] = costu;\n seen[u] = true;\n\n for(auto [v, duv] : G[u]){\n if(seen[v]) continue;\n if(dist[v] > dist[u] + duv){\n dist[v] = dist[u] + duv;\n pq.push({dist[v], v});\n }\n }\n }\n\n /* 辺のコスト = (端点の祭りからの距離のうち小さい方)\n 辺コストが大きいものだけでグラフFを作る\n */\n vv<pll> F(n, vc<pll>());\n UnionFind uf = UnionFind(n);\n vc<tuple<ll, ll, ll>> edges;\n rep(u, n){\n for(auto [v, l] : G[u]){\n ll c = min(dist[u], dist[v]);\n edges.push_back({u, v, c});\n }\n }\n\n sort(nall(edges), [](auto const &l, auto const &r){\n return get<2>(l) > get<2>(r);\n });\n\n for(auto [u, v, c] : edges){\n if(uf.issame(u, v)) continue;\n uf.unite(u, v);\n F[u].pb({v, c});\n F[v].pb({u, c});\n }\n \n /* LCAの準備\n dp[i][u]: uの2^i上の親と,そのパス上での辺のコストの最小値のペア\n */\n ll maxLogN = 20;\n vv<pll> dp(maxLogN, vc<pll>(n));\n vl d(n, -1); // 根0からの距離\n\n auto dfs = [&](auto self, ll u, ll p, ll dd) -> void{\n if(p == -1) dp[0][u] = {p, dist[u]};\n else dp[0][u] = {p, min(dist[u], dist[p])};\n \n d[u] = dd;\n\n for(auto [v, c] : F[u]){\n if(v == p) continue;\n self(self, v, u, dd+1);\n }\n return;\n };\n\n dfs(dfs, 0, -1, 0);\n for(ll i = 0; i+1 < maxLogN; i++){\n rep(v, n){\n if(dp[i][v].first == -1) dp[i+1][v] = {-1, dp[i][v].second};\n else{\n dp[i+1][v].first = dp[i][dp[i][v].first].first;\n dp[i+1][v].second = min(dp[i][v].second, dp[i][dp[i][v].first].second);\n }\n }\n }\n\n /* クエリの処理\n */\n vl ans(q);\n rep(qq, q){\n ll s, t;\n cin >> s >> t;\n s--; t--;\n\n ll tmpans = INF;\n\n if(d[s] < d[t]) swap(s, t);\n rep(i, maxLogN){\n if(((d[s] - d[t]) >> i) & 1ll){\n chmin(tmpans, dp[i][s].second);\n s = dp[i][s].first;\n }\n }\n\n if(s == t){\n ans[qq] = tmpans;\n continue;\n }\n drep(i, maxLogN){\n if(dp[i][s].first != dp[i][t].first){\n tmpans = min({tmpans, dp[i][s].second, dp[i][t].second});\n s = dp[i][s].first;\n t = dp[i][t].first;\n }\n }\n\n ans[qq] = tmpans;\n }\n\n for(ll a : ans) cout << a << endl;\n\n return 0;\n}", "accuracy": 0.12903225806451613, "time_ms": 180, "memory_kb": 67740, "score_of_the_acc": -1.0067, "final_rank": 19 }, { "submission_id": "aoj_0575_10707981", "code_snippet": "// #ifndef ONLINE_JUDGE\n// #define _GLIBCXX_DEBUG//[]で配列外参照をするとエラーにしてくれる。上下のやつがないとTLEになるので注意 ABC311Eのサンプル4みたいなデバック中のTLEは防げないので注意\n// #endif\n\n#include <bits/stdc++.h>\nusing namespace std;\n// #include <atcoder/all>\n// using namespace atcoder;\n\n\ntemplate<typename T> using vc = vector<T>;//prioriy_queueに必要なのでここにこれ書いてます\ntemplate<typename T> using vv = vc<vc<T>>;\n\n//-------------1.型系---------------\nusing ll = long long;\nll INF = 2e18;\n\n// #include <boost/multiprecision/cpp_int.hpp>//インストール的なのをしてないとできないので注意\n// namespace multip = boost::multiprecision;\n// //using lll = multip::cpp_int;//無制限を使いたいときはこっちを使う\n// using lll = multip::int128_t;\n\nusing ld = long double;\nusing bl = bool;\n// using mint = modint998244353;\n//using mint = modint1000000007;\n//using mint = modint;//使うときはコメントアウトを外す\n//mint::set_mod(m);//使うときはコメントアウトを外す\n\ntemplate<class T> using pq = priority_queue<T, vc<T>>;//大きい順\ntemplate<class T> using pq_g = priority_queue<T, vc<T>, greater<T>>;//小さい順\n//-----------------------------------\n\n\n\n//-------------2.配列系--------------\nusing vl = vc<ll>; using vvl = vv<ll>; using vvvl = vv<vl>; using vvvvl = vv<vvl>;\nusing vs = vc<string>; using vvs = vv<string>;\nusing vb = vc<bl>; using vvb = vv<bl>; using vvvb = vv<vb>;\nusing vld = vc<ld>; using vvld = vv<ld>; using vvvld = vv<vld>;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\n// using vmint = vc<mint>; using vvmint = vv<mint>; using vvvmint = vv<vmint>;\n\n//配列外参照対策のやつは一番上の行にあります\n\n#define rep(i,n) for(ll i = 0; i < (n); ++i)//↓でrepを使うので書いてます\ntemplate<class T>istream& operator>>(istream& i, vc<T>& v) { rep(j, size(v))i >> v[j]; return i; }\n\nusing ar2 = array<ll, 2>;\n\n//----------------------------------\n\n\n\n//--------3.コード短縮化とか---------\n#define rep(i,n) for(ll i = 0; i < (n); ++i)\n#define rrep(i,n) for(ll i = 1; i <= (n); ++i)\n#define drep(i,n) for(ll i = (n)-1; i >= 0; --i)\n#define nfor(i,s,n) for(ll i=s;i<n;i++)//i=s,s+1...n-1 ノーマルfor\n#define dfor(i,s,n) for(ll i = (s)-1; i>=n;i--)//s-1スタートでnまで落ちる\n\n#define nall(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n\n#define chmax(x,y) x = max(x,y)\n#define chmin(x,y) x = min(x,y)\n\n#define pb push_back\n#define eb emplace_back\n#define em emplace\n#define pob pop_back\n\n\n#define YES cout<<\"Yes\"<<endl\n#define NO cout<<\"No\"<<endl\n#define YN {cout<<\"Yes\"<<endl;}else{cout<<\"No\"<<endl;}// if(a==b)YN;\n#define dame cout<<-1<<endl\n\n\n#define vc_unique(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define vc_rotate(v) rotate(v.begin(),v.begin()+1,v.end());\n\n#define pop_cnt(s) ll(popcount(uint64_t(s)))\n\n#define next_p(v) next_permutation(v.begin(),v.end())\n\n//if (regex_match(s, regex(\"\")))YN;//文字列sの判定を行う。コメントアウトを外して「\"\"」の中に判定する内容を入れる\n\n//-------------------------------\n\n\n\n\n//---------4.グリッド系----------\nvl di = { 0,1,0,-1 };//vl di={0,1,1,1,0,-1,-1,-1};\nvl dj = { 1,0,-1,0 };//vl dj={1,1,0,-1,-1,-1,0,1};\n\nbool out_grid(ll i, ll j, ll h, ll w) {//trueならcontinue\n return (!(0 <= i && i < h && 0 <= j && j < w));\n}\n\n#define vvl_kaiten_r(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//時計回りに90°回転\n#define vvl_kaiten_l(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//反時計周りに90°回転\n\n#define vs_kaiten_r(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[j][n-i-1]=v[i][j];swap(nx,v);}//文字列版 時計回りに90°回転\n#define vs_kaiten_l(v) {ll n = size(v);vs nx(n,string(n,'.'));rep(i,n)rep(j,n)nx[n-j-1][i]=v[i][j];swap(nx,v);}//文字列版 反時計周りに90°回転\n\n\n#define vvl_tenti(v) {ll n = size(v);vvl nx(n,vl(n));rep(i,n)rep(j,n)nx[j][i]=v[i][j];swap(nx,v);}\n#define vs_tenti(v) {ll n = size(v); vs nx(n, string(n,'.')); rep(i, n)rep(j, n)nx[j][i] = v[i][j]; swap(nx, v);}\n\n//--------------------------------\n\n\n\n\n//-----------5.数学系--------------\n#define yu_qurid(x,y) ((x)*(x)+(y)*(y))//ユークリッド距離 sqrtはしてないなので注意\n#define mannhattan(x1,x2,y1,y2) (abs(x1-x2)+abs(y1-y2)) // マンハッタン距離 = |x1-x2|+|y1-y2|\n\ntemplate<class T>T tousa_sum1(T l, T d, T r) {//初項,公差,末項 で総和を求める\n T wide = (r - l) / d + 1;\n return (l + r) * wide / 2;\n}\ntemplate<class T>T tousa_sum2(T a, T d, T n) {//初項,交差,項数 で総和を求める\n return (a * 2 + d * (n - 1)) * n / 2;\n}\nll kousa_kousuu(ll l, ll r, ll d) {//初項,末項,交差 で等差数列の項数を求める\n return (r - l) / d + 1;\n}\n// mint touhi_sum(mint a, mint r, ll n) {//初項,公比,項数で等比数列の総和を求める\n// if (r == 1) {\n// return a * n;\n// }\n// mint bunsi = a * (r.pow(n) - mint(1));\n// mint bunbo = r - 1;\n// return bunsi / bunbo;\n// }\n\nll nc2(ll x) { return x * (x - 1) / 2; }\nll nc3(ll x) { return x * (x - 1) * (x - 2) / 6; }\n\n//----------------------------------------------\n\n\n\n\n//-----------6.デバックや出力系------------------\nvoid print(ld x) { printf(\"%.20Lf\\n\", x); }\n\nvoid mukou_debug(vvl to, bool yukou) {//GRAPH × GRAPH用の無向グラフを出力する\n ll n = size(to); ll cnt = 0;//辺の本数\n vc<pair<ll, ll>>v; rep(i, n)for (ll t : to[i]) if (i < t || yukou)cnt++, v.eb(i + 1, t + 1);//有向グラフなら全部OK、違うなら無向なのでf<tのみ見る、using Pのやつを別のにしたいときのためにPを使わずにpair<ll,ll>にしてる\n cout << n << ' ' << cnt << endl; for (auto [f, t] : v)cout << f << ' ' << t << endl;\n}\n\n#define vc_cout(v){ll n = size(v);rep(i,n)cout<<v[i]<<endl;}//一次元配列を出力する\n#define vv_cout(v){ll n = size(v);rep(i,n){rep(j,size(v[i])){cout<<v[i][j]<<' ';}cout<<endl;}}//二次元配列を出力する\n\n/* とりあえず各町のお祭りからの距離を知りたいので、多始点ダイクストラみたいなことをする\n ダブリングらしいけどどうテーブルを作るか\n 答えで二分探索したい気持ち\n dp[i][j]: 街jからお祭りまでの距離を2^i以下で移動できる街のリスト?\n Q≤1e5なので各クエリにO(log?)くらいでこたえたい\n\n*/\n\nstruct UnionFind {\n vector<int> par, rank, siz;\n\n // 構造体の初期化\n UnionFind(int n) : par(n,-1), rank(n,0), siz(n,1) { }\n\n // 根を求める\n int root(int x) {\n if (par[x]==-1) return x; // x が根の場合は x を返す\n else return par[x] = root(par[x]); // 経路圧縮\n }\n\n // x と y が同じグループに属するか (= 根が一致するか)\n bool issame(int x, int y) {\n return root(x)==root(y);\n }\n\n // x を含むグループと y を含むグループを併合する\n bool unite(int x, int y) {\n int rx = root(x), ry = root(y); // x 側と y 側の根を取得する\n if (rx==ry) return false; // すでに同じグループのときは何もしない\n // union by rank\n if (rank[rx]<rank[ry]) swap(rx, ry); // ry 側の rank が小さくなるようにする\n par[ry] = rx; // ry を rx の子とする\n if (rank[rx]==rank[ry]) rank[rx]++; // rx 側の rank を調整する\n siz[rx] += siz[ry]; // rx 側の siz を調整する\n return true;\n }\n\n // x を含む根付き木のサイズを求める\n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main(){\n ll n, m, k, q;\n cin >> n >> m >> k >> q;\n vv<pll> G(n, vc<pll>());\n rep(i, m){\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].pb(make_pair(b, l));\n G[b].pb(make_pair(a, l));\n }\n set<ll> st;\n rep(i, k){\n ll f;\n cin >> f;\n f--;\n st.insert(f);\n }\n vl s(q), t(q);\n rep(i, q){\n cin >> s[i] >> t[i];\n s[i]--; t[i]--;\n }\n\n // 各街のお祭りまでの距離を求める\n vl d(n, INF); // d[i]: 町iのお祭りまでの距離\n pq_g<pll> pq;\n for(ll u : st) pq.push(make_pair(0, u));\n vb seen(n, false);\n\n while(pq.size()){\n auto [costu, u] = pq.top();\n pq.pop();\n\n if(costu > d[u]) continue;\n d[u] = costu;\n seen[u] = true;\n\n for(auto [v, duv] : G[u]){\n if(seen[v]) continue;\n if(d[v] > d[u] + duv){\n d[v] = d[u] + duv;\n pq.push(make_pair(d[v], v));\n }\n }\n }\n\n // 辺をコストの降順でソート。コストが最大になる全域木Fをつくる。クラスカル法\n vc<tuple<ll, ll, ll>> edges;\n rep(u, n){\n for(auto [v, l] : G[u]){\n edges.pb(make_tuple(u, v, min(d[u], d[v])));\n }\n }\n\n sort(nall(edges), [](auto const &l, auto const &r){\n return get<2>(l) > get<2>(r);\n });\n\n vvl F(n, vl());\n UnionFind uf = UnionFind(n);\n for(auto [from, to, cost] : edges){\n if(!uf.issame(from, to)){\n uf.unite(from, to);\n F[from].pb(to);\n F[to].pb(from);\n }\n }\n\n ll maxLogN = 20;\n /* dp[i][u]: Fを頂点0を根とする根付き木としてみたときの\n 頂点uの2^i個上の親と,そのパス上でのコスト最小の頂点のペア\n */\n vv<pll> dp(maxLogN, vc<pll>(n));\n vl dist(n, -1);\n\n auto dfs = [&](auto self, ll u, ll p, ll dd) -> void{\n ll second = (p == -1 ? d[u] : min(d[p], d[u]));\n dp[0][u] = make_pair(p, second);\n dist[u] = dd;\n for(ll v : F[u]){\n if(v == p) continue;\n\n self(self, v, u, dd+1);\n }\n return;\n };\n\n dfs(dfs, 0, -1, 0);\n rep(i, maxLogN-1){\n rep(j, n){\n if(dp[i][j].first == -1){\n dp[i+1][j] = make_pair(-1, dp[i][j].second);\n }\n else{\n dp[i+1][j] = make_pair(dp[i][dp[i][j].first].first, min(dp[i][j].second, dp[i][dp[i][j].first].second));\n }\n }\n }\n\n rep(qq, q){\n ll ans = INF;\n\n ll u = s[qq], v = t[qq];\n if(dist[u] < dist[v]) swap(u, v);\n rep(i, maxLogN){\n if(((dist[u] - dist[v]) >> i) & 1ll){\n chmin(ans, dp[i][u].second); // uを変更する前にUが上に行くパス上の最小値を調べる必要がある\n u = dp[i][u].first;\n }\n }\n\n if(u == v){\n cout << ans << endl;\n continue; \n }\n drep(i, maxLogN){\n if(dp[i][u].first != dp[i][v].first){\n ans = min({ans, dp[i][u].second, dp[i][v].second}); // u, vを変更する前にu,vそれぞれが通ることになるパスを調べておく。\n u = dp[i][u].first;\n v = dp[i][v].first;\n }\n }\n ans = min(ans, dp[0][u].second);\n\n cout << ans << endl;\n }\n\n // vv_cout(F);\n // cout << endl;\n // vc_cout(dist);\n\n return 0;\n}", "accuracy": 0.12903225806451613, "time_ms": 170, "memory_kb": 66728, "score_of_the_acc": -0.9769, "final_rank": 18 }, { "submission_id": "aoj_0575_9696126", "code_snippet": "///***LTT***///\n/// ->NHAT QUOC GIA<- ///\n#include<bits/stdc++.h>\n//#pragma GCC optimize (\"O3\")\n//#pragma GCC optimize (\"unroll-loops\")\n//#pragma GCC target(\"popcnt\")\n//#define int long long\n#define endl \"\\n\"\n#define F first\n#define S second\n#define pb push_back\nusing namespace std;\nvector <int> lg2;\n//void MAKE_LOG_ARR(int n){\n// lg2.resize(n + 3);\n// for (int i = 1;i <= n;++i){\n// lg2[i] = __lg(i);\n// }\n//}\nconst long long oo = 1e9+7;\nconst int N = 1e5 + 10;\nint n, m, k, q;\nint qu[N], qv[N];\nlong long dis[N];\nvector <pair <int, int>> adj[N];\nint parent[N], sz[N];\nint b[N];\npriority_queue <pair <long long, int>> pq;\nint L[N], R[N];\nlong long ans[N];\nvector <int> in[N];\nbool cmp(int a, int b){\n return dis[a] > dis[b];\n}\nint finds(int u){\n if (u == parent[u]) return u;\n int pu = finds(parent[u]);\n parent[u] = pu;\n return pu;\n}\nvoid unions(int u, int v){\n u = finds(u);\n v = finds(v);\n if (u != v){\n if (sz[u] > sz[v]) swap(u,v);\n parent[v] = u;\n sz[u] += sz[v];\n }\n return;\n}\nvoid solve(){\n cin >> n >> m >> k >> q;\n for (int i = 1;i <= m;++i){\n int u, v, w;\n cin >> u >> v >> w;\n adj[u].pb({v,w});\n adj[v].pb({u,w});\n }\n for (int i = 1;i <= n;++i){\n dis[i] = oo * oo;\n }\n for (int i = 1;i <= k;++i){\n int x;\n cin >> x;\n dis[x] = 0;\n pq.push({0, x});\n }\n while (!pq.empty()){\n int u = pq.top().S;\n long long d =- pq.top().F;\n pq.pop();\n if (d > dis[u]) continue;\n for (int i = 0;i < adj[u].size();++i){\n int v = adj[u][i].F;\n int w = adj[u][i].S;\n if (d + w < dis[v]){\n dis[v] = d + w;\n pq.push({-dis[v], v});\n }\n }\n }\n for (int i = 1;i <= q;++i){\n cin >> qu[i] >> qv[i];\n }\n for (int i = 1;i <= n;++i){\n b[i] = i;\n }\n sort(b + 1,b + n + 1, cmp);\n// for (int i = 1;i <= n;++i){\n// cout << b[i] <<\" \"<< dis[b[i]] <<\"\\n\";\n// }\n for (int i = 1;i <= q;++i){\n ans[i] = 0;\n L[i] = 1;\n R[i] = n;\n }\n while (1){\n bool found = false;\n for (int i = 1;i <= q;++i){\n if (L[i] <= R[i]){\n int mid = (L[i] + R[i])/2;\n in[mid].pb(i);\n\n found = true;\n }\n }\n if (!found){\n break;\n }\n for (int i = 1;i <= n;++i){\n parent[i] = i;\n sz[i] = 1;\n }\n for (int i = 1;i <= n;++i){\n for (int j = 0;j < adj[b[i]].size();++j){\n int v = adj[b[i]][j].F;\n if (dis[v] >= dis[b[i]])\n unions(b[i], v);\n }\n for (int j : in[i]){\n if (finds(qu[j]) == finds(qv[j])){\n R[j] = i - 1;\n ans[j] = dis[b[i]];\n } else L[j] = i + 1;\n }\n in[i].clear();\n }\n }\n for (int i = 1;i <= q;++i){\n cout << ans[i] <<\"\\n\";\n }\n return;\n}\nint main(){\n ios_base::sync_with_stdio(NULL);\n cin.tie(NULL);\n cout.tie(NULL);\n if (fopen(\"ltt.inp\", \"r\")){\n freopen(\"ltt.inp\", \"r\", stdin);\n freopen(\"ltt.out\", \"w\", stdout);\n }\n// int t;\n// cin >> t;\n// while(t--){\n solve();\n// }\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 28448, "score_of_the_acc": -0.5746, "final_rank": 7 }, { "submission_id": "aoj_0575_9627712", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst int INF = 1e9 + 10;\nconst ll INFL = 4e18;\n\ntemplate <typename T, T (*op)(T, T), T (*e)()>\nstruct LcaVertexQuery {\n LcaVertexQuery(const vector<vector<int>> &g, const vector<T> &v, int root) {\n int n = g.size();\n int k = 1;\n while ((1 << k) < n) k++;\n parent = vector<vector<int>>(k, vector<int>(n, -1));\n dep = vector<int>(n);\n dat = vector<vector<T>>(k, vector<T>(n, e()));\n dfs(g, v, root, -1, 0);\n for (int i = 0; i + 1 < k; i++) {\n for (int j = 0; j < n; j++) {\n parent[i + 1][j] = parent[i][j] == -1 ? -1 : parent[i][parent[i][j]];\n dat[i + 1][j] = parent[i][j] == -1 ? e() : op(dat[i][j], dat[i][parent[i][j]]);\n }\n }\n }\n T query(int u, int v) {\n T ret = e();\n if (dep[u] > dep[v]) swap(u, v);\n while (dep[u] < dep[v]) {\n int k = 0;\n while (dep[v] - dep[u] >= (1 << (k + 1))) k++;\n ret = op(ret, dat[k][v]);\n v = parent[k][v];\n }\n while (parent[0][u] != parent[0][v]) {\n int k = 0;\n while (parent[k + 1][u] != parent[k + 1][v]) k++;\n ret = op(ret, dat[k][u]);\n ret = op(ret, dat[k][v]);\n u = parent[k][u];\n v = parent[k][v];\n }\n ret = op(ret, dat[0][u]);\n ret = op(ret, dat[0][v]);\n return ret;\n }\n\nprivate:\n vector<vector<int>> parent;\n vector<int> dep;\n vector<vector<T>> dat;\n void dfs(const vector<vector<int>> &g, const vector<T> &v, int now, int par, int d) {\n dat[0][now] = v[now];\n parent[0][now] = par;\n dep[now] = d;\n for (int nxt : g[now]) {\n if (nxt == par) continue;\n dfs(g, v, nxt, now, d + 1);\n }\n }\n};\n\nstruct DSU {\n DSU() = default;\n DSU(int n) {\n par = vector<int>(n);\n sz = vector<int>(n);\n for (int i = 0; i < n; i++) {\n par[i] = i;\n sz[i] = 1;\n }\n forest_count = n;\n }\n int find(int x) {\n if (par[x] == x) {\n return x;\n }\n par[x] = find(par[x]);\n return par[x];\n }\n void unite(int x, int y) {\n x = find(x);\n y = find(y);\n if (x == y) {\n return;\n }\n if (sz[x] < sz[y]) {\n swap(x, y);\n }\n par[y] = x;\n sz[x] += sz[y];\n forest_count--;\n }\n int size(int x) {\n return sz[find(x)];\n }\n bool same(int x, int y) {\n return find(x) == find(y);\n }\n int count() {\n return forest_count;\n }\n vector<vector<int>> groups() {\n int n = par.size();\n vector<vector<int>> res(n);\n for (int i = 0; i < n; i++) {\n res[find(i)].push_back(i);\n }\n res.erase(remove_if(res.begin(), res.end(), [&](const vector<int> &v) { return v.empty(); }), res.end());\n return res;\n }\n\nprivate:\n vector<int> par, sz;\n int forest_count;\n};\n\nll op(ll a, ll b) {\n return min(a, b);\n}\nll e() {\n return INFL;\n}\n\nint main() {\n int N, M, K, Q;\n cin >> N >> M >> K >> Q;\n vector<vector<pair<int, ll>>> G(N);\n for (int i = 0; i < M; i++) {\n int a, b;\n ll c;\n cin >> a >> b >> c;\n a--;\n b--;\n G[a].push_back({b, c});\n G[b].push_back({a, c});\n }\n\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>> pq;\n vector<ll> dist(N, INFL);\n for (int i = 0; i < K; i++) {\n int a;\n cin >> a;\n a--;\n dist[a] = 0;\n pq.push({0, a});\n }\n\n while (!pq.empty()) {\n auto [d, now] = pq.top();\n pq.pop();\n if (dist[now] < d) continue;\n for (auto [nxt, cost] : G[now]) {\n if (dist[nxt] > dist[now] + cost) {\n dist[nxt] = dist[now] + cost;\n pq.push({dist[nxt], nxt});\n }\n }\n }\n\n vector<tuple<ll, int, int>> edges;\n for (int i = 0; i < N; i++) {\n for (auto [nxt, cost] : G[i]) {\n if (dist[i] < dist[nxt]) {\n edges.push_back({dist[i], i, nxt});\n }\n }\n }\n sort(edges.begin(), edges.end(), greater{});\n\n vector<vector<int>> G2(N);\n\n DSU dsu(N);\n for (auto [d, a, b] : edges) {\n if (dsu.same(a, b)) continue;\n dsu.unite(a, b);\n G2[a].push_back(b);\n G2[b].push_back(a);\n }\n\n LcaVertexQuery<ll, op, e> lca(G2, dist, 0);\n\n for (int i = 0; i < Q; i++) {\n int a, b;\n cin >> a >> b;\n a--;\n b--;\n cout << lca.query(a, b) << '\\n';\n }\n}", "accuracy": 0.12903225806451613, "time_ms": 160, "memory_kb": 47008, "score_of_the_acc": -0.6363, "final_rank": 17 }, { "submission_id": "aoj_0575_9572785", "code_snippet": "#include <bits/stdc++.h>\n\n\n\n\nnamespace zawa {\n\nusing i16 = std::int16_t;\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing i128 = __int128_t;\n\nusing u8 = std::uint8_t;\nusing u16 = std::uint16_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\n\nusing usize = std::size_t;\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nvoid SetFastIO() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n}\n\nvoid SetPrecision(u32 dig) {\n std::cout << std::fixed << std::setprecision(dig);\n}\n\n} // namespace zawa\n\n\n\nnamespace zawa {\n\nclass DisjointSetUnion {\npublic:\n DisjointSetUnion() = default;\n\n DisjointSetUnion(usize n) : n_{n}, data_(n, -1) {\n data_.shrink_to_fit();\n }\n \n u32 leader(u32 v) {\n return data_[v] < 0 ? v : static_cast<u32>(data_[v] = leader(data_[v]));\n }\n\n bool same(u32 u, u32 v) {\n return leader(u) == leader(v);\n }\n\n bool merge(u32 u, u32 v) {\n assert(u < n_);\n assert(v < n_);\n u = leader(u);\n v = leader(v);\n if (u == v) return false;\n if (data_[u] > data_[v]) std::swap(u, v);\n data_[u] += data_[v];\n data_[v] = u;\n return true;\n }\n\n inline usize size() const noexcept {\n return n_;\n }\n\n usize size(u32 v) {\n assert(v < n_);\n return static_cast<usize>(-data_[leader(v)]);\n }\n\n std::vector<std::vector<u32>> enumerate() {\n std::vector<std::vector<u32>> res(n_);\n for (u32 v{} ; v < n_ ; v++) {\n res[leader(v)].push_back(v);\n }\n res.erase(std::remove_if(res.begin(), res.end(),\n [](const auto& arr) -> bool { return arr.empty(); }), res.end());\n return res;\n }\n\nprivate:\n usize n_{};\n std::vector<i32> data_;\n};\n\n} // namespace zawa\nusing namespace zawa;\n\nint main() {\n SetFastIO();\n\n int N, M, K, Q;\n std::cin >> N >> M >> K >> Q;\n std::vector<std::vector<std::pair<int, int>>> g(N);\n for (int i{} ; i < M ; i++) {\n int A, B, L;\n std::cin >> A >> B >> L;\n A--; B--;\n g[A].push_back(std::pair{ B, L });\n g[B].push_back(std::pair{ A, L });\n }\n const long long INF{(long long)1e12};\n std::vector<long long> dist(N, INF);\n using qt = std::pair<long long, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n for (int i{} ; i < K ; i++) {\n int F;\n std::cin >> F;\n F--;\n dist[F] = 0;\n que.push(qt{ dist[F], F });\n }\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (dist[v] < d) continue;\n for (auto [x, w] : g[v]) if (dist[x] > d + w) {\n dist[x] = d + w;\n que.push(qt{ dist[x], x });\n }\n } \n std::vector<int> S(Q), T(Q);\n for (int i{} ; i < Q ; i++) {\n std::cin >> S[i] >> T[i];\n S[i]--; T[i]--;\n }\n std::vector<long long> ok(N), ng(N, INF);\n while (true) {\n bool brk{true};\n std::vector<std::pair<long long, int>> ord;\n ord.reserve(N + Q);\n for (int i{} ; i < Q ; i++) if (ng[i] - ok[i] > 1) {\n brk = false;\n long long mid{(ok[i] + ng[i]) / 2};\n ord.push_back(std::pair{ mid, i });\n }\n if (brk) break;\n for (int i{} ; i < N ; i++) {\n ord.push_back(std::pair{ dist[i], Q + i });\n }\n std::sort(ord.begin(), ord.end());\n std::reverse(ord.begin(), ord.end());\n DisjointSetUnion dsu(N);\n std::vector<bool> use(N);\n for (auto [d, t] : ord) {\n if (t >= Q) {\n t -= Q;\n assert(!use[t]);\n use[t] = true;\n for (auto [x, _] : g[t]) if (use[x]) {\n dsu.merge(t, x);\n }\n }\n else {\n if (dsu.same(S[t], T[t])) ok[t] = d;\n else ng[t] = d;\n }\n }\n }\n for (int i{} ; i < Q ; i++) {\n std::cout << ok[i] << '\\n';\n } \n}", "accuracy": 1, "time_ms": 870, "memory_kb": 19060, "score_of_the_acc": -1.094, "final_rank": 12 }, { "submission_id": "aoj_0575_9552373", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nconst int MAX_N = 100000;\nconst int INF = 99999999;\nconst int SEG_SIZE = 524288;\n\n// Union-Find用の配列\nint UF[MAX_N];\n// 各頂点までの最短距離\nint ijk[MAX_N];\n// 訪問済みフラグ\nbool v[MAX_N];\n// グラフの隣接リスト表現\nvector<pair<int, int>> g[MAX_N];\n// エッジリスト\npair<int, pair<int, int>> edge[200000];\n// 各頂点の子を管理するリスト\nvector<int> t[MAX_N];\n// セグメントツリー\nint segtree[SEG_SIZE];\n\n// 区間の最小値をクエリで取得する関数\nint query(int a, int b, int c, int d, int e) {\n if (d < a || b < c) return INF;\n if (c <= a && b <= d) return segtree[e];\n return min(query(a, (a + b) / 2, c, d, e * 2), query((a + b) / 2 + 1, b, c, d, e * 2 + 1));\n}\n\n// セグメントツリーの値を更新する関数\nvoid set(int a, int b) {\n a += SEG_SIZE / 2;\n while (a) {\n segtree[a] = min(segtree[a], b);\n a /= 2;\n }\n}\n\n// Union-FindのFIND関数\nint FIND(int a) {\n if (UF[a] < 0) return a;\n return UF[a] = FIND(UF[a]);\n}\n\n// Union-FindのUNION関数\nvoid UNION(int a, int b) {\n a = FIND(a); b = FIND(b);\n if (a == b) return;\n UF[a] += UF[b];\n UF[b] = a;\n t[a].push_back(b);\n}\n\n// DFS用の変数\nint now = 0;\nint F[MAX_N]; // 各頂点のDFSで訪れる順序\nint TO[MAX_N]; // DFSで訪れた頂点の順序を格納\nint num = 0;\n\n// DFS関数\nvoid dfs(int a) {\n F[a] = now;\n int K = num++;\n TO[K] = a;\n set(now++, K);\n for (int i : t[a]) {\n dfs(i);\n set(now++, K);\n }\n}\n\nint main() {\n int a, b, c, d;\n scanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\n // グラフの入力を受け取る\n for (int i = 0; i < b; i++) {\n int p, q, r;\n scanf(\"%d%d%d\", &p, &q, &r);\n p--; q--; // 0-indexed に変換\n g[p].push_back(make_pair(q, r));\n g[q].push_back(make_pair(p, r));\n edge[i] = make_pair(0, make_pair(p, q));\n }\n\n // 初期化\n fill(ijk, ijk + a, INF);\n fill(UF, UF + a, -1);\n fill(segtree, segtree + SEG_SIZE, INF);\n\n // 最短距離計算用の優先度付きキュー\n priority_queue<pair<int, int>> Q;\n for (int i = 0; i < c; i++) {\n int e;\n scanf(\"%d\", &e);\n e--; // 0-indexed に変換\n ijk[e] = 0;\n Q.push(make_pair(0, e));\n }\n\n // ダイクストラ法による最短距離計算\n while (!Q.empty()) {\n int cost = -Q.top().first;\n int at = Q.top().second;\n Q.pop();\n if (v[at]) continue;\n v[at] = true;\n ijk[at] = cost;\n for (auto& edge : g[at]) {\n if (!v[edge.first] && ijk[edge.first] > ijk[at] + edge.second) {\n ijk[edge.first] = ijk[at] + edge.second;\n Q.push(make_pair(-ijk[edge.first], edge.first));\n }\n }\n }\n\n // エッジを最短距離に基づいて再構成\n for (int i = 0; i < b; i++) {\n edge[i] = make_pair(-min(ijk[edge[i].second.first], ijk[edge[i].second.second]), edge[i].second);\n }\n\n // エッジをソートし、最小全域木を構築\n sort(edge, edge + b);\n int s = 0;\n int w = 0;\n for (int i = 0; i < b; i++) {\n int l = edge[i].second.first;\n int r = edge[i].second.second;\n if (FIND(l) != FIND(r)) {\n if (ijk[l] > ijk[r]) swap(l, r);\n UNION(l, r);\n w++;\n if (w == a - 1) s = l;\n }\n }\n\n // DFSによる木の構築\n dfs(s);\n\n // クエリに対する応答\n for (int i = 0; i < d; i++) {\n int x, y;\n scanf(\"%d%d\", &x, &y);\n x--; y--; // 0-indexed に変換\n printf(\"%d\\n\", ijk[TO[query(0, SEG_SIZE / 2 - 1, min(F[x], F[y]), max(F[x], F[y]), 1)]]);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 23652, "score_of_the_acc": -0.1963, "final_rank": 1 }, { "submission_id": "aoj_0575_8530478", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0575.cc: JOI 国のお祭り事情(Festivals in JOI Kingdom) \n */\n\n#include<cstdio>\n#include<vector>\n#include<set>\n#include<queue>\n#include<algorithm>\n#include<utility>\n#include<tuple>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_M = 200000;\nconst int MAX_QN = 100000;\nconst int INF = 1 << 30;\n\n/* typedef */\n\ntypedef set<int> si;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\ntypedef tuple<int,int,int> tp3;\n\nstruct UFT {\n vector<int> links, ranks, sizes;\n UFT() {}\n\n void init(int n) {\n links.resize(n);\n for (int i = 0; i < n; i++) links[i] = i;\n ranks.assign(n, 1);\n sizes.assign(n, 1);\n }\n\n int root(int i) {\n int i0 = i;\n while (links[i0] != i0) i0 = links[i0];\n return (links[i] = i0);\n }\n\n int rank(int i) { return ranks[root(i)]; }\n int size(int i) { return sizes[root(i)]; }\n bool same(int i, int j) { return root(i) == root(j); }\n\n int merge(int i0, int i1) {\n int r0 = root(i0), r1 = root(i1), mr;\n if (r0 == r1) return r0;\n if (ranks[r0] == ranks[r1]) {\n links[r1] = r0;\n sizes[r0] += sizes[r1];\n ranks[r0]++;\n mr = r0;\n }\n else if (ranks[r0] > ranks[r1]) {\n links[r1] = r0;\n sizes[r0] += sizes[r1];\n mr = r0;\n }\n else {\n links[r0] = r1;\n sizes[r1] += sizes[r0];\n mr = r1;\n }\n return mr;\n }\n};\n\n/* global variables */\n\ntp3 es[MAX_M];\nvpii nbrs[MAX_N];\nint fs[MAX_N], ds[MAX_N], ans[MAX_QN];\nUFT uft;\nsi ss[MAX_N];\npii qs[MAX_QN];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, m, k, qn;\n scanf(\"%d%d%d%d\", &n, &m, &k, &qn);\n\n for (int i = 0; i < m; i++) {\n int a, b, l;\n scanf(\"%d%d%d\", &a, &b, &l);\n a--, b--;\n es[i] = {0, a, b};\n nbrs[a].push_back(pii(b, l));\n nbrs[b].push_back(pii(a, l));\n }\n for (int i = 0; i < k; i++) scanf(\"%d\", fs + i), fs[i]--;\n\n fill(ds, ds + n, INF);\n priority_queue<pii> q;\n for (int i = 0; i < k; i++) ds[fs[i]] = 0, q.push(pii(0, fs[i]));\n\n while (! q.empty()) {\n auto ue = q.top(); q.pop();\n int ud = -ue.first, u = ue.second;\n if (ds[u] != ud) continue;\n\n for (auto &vw: nbrs[u]) {\n int v = vw.first, vd = ud + vw.second;\n if (ds[v] > vd) {\n\tds[v] = vd;\n\tq.push(pii(-vd, v));\n }\n }\n }\n //for (int u = 0; u < n; u++) printf(\"%d \", ds[u]); putchar('\\n');\n\n for (int i = 0; i < m; i++) {\n auto [l, a, b] = es[i];\n es[i] = { min(ds[a], ds[b]) , a, b };\n }\n sort(es, es + m);\n\n uft.init(n);\n\n for (int i = 0; i < qn; i++) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n u--, v--;\n ss[u].insert(i);\n ss[v].insert(i);\n }\n\n for (int i = m - 1; i >= 0; i--) {\n auto [l, u, v] = es[i];\n int ru = uft.root(u), rv = uft.root(v);\n if (ru != rv) {\n int ra = uft.merge(ru, rv), rb = (ra == ru) ? rv : ru;\n if (ss[ra].size() < ss[rb].size()) swap(ss[ra], ss[rb]);\n for (auto k: ss[rb]) {\n\tauto sit = ss[ra].find(k);\n\tif (sit != ss[ra].end()) {\n\t ss[ra].erase(k);\n\t ans[k] = l;\n\t}\n\telse {\n\t ss[ra].insert(k);\n\t}\n }\n }\n }\n\n for (int i = 0; i < qn; i++) printf(\"%d\\n\", ans[i]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 54576, "score_of_the_acc": -0.8399, "final_rank": 10 }, { "submission_id": "aoj_0575_8520330", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/atcoder/github/algo/lib/graph/graph.hpp\"\n#include <iostream>\n#include <vector>\n\n/**\n * @brief 重み付きグラフ\n *\n * @tparam T 辺の重みの型\n */\ntemplate <class T>\nstruct Graph {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to(), _weight() {}\n constexpr _edge(int from, int to, T weight) : _from(from), _to(to), _weight(weight) {}\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr T weight() const { return _weight; }\n\n private:\n int _from, _to;\n T _weight;\n };\n\n public:\n using edge_type = typename Graph<T>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to, T weight = T(1)) { edges[from].emplace_back(from, to, weight); }\n void add_edges(int from, int to, T weight = T(1)) {\n edges[from].emplace_back(from, to, weight);\n edges[to].emplace_back(to, from, weight);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edge(from - base, to - base, weight);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edges(from - base, to - base, weight);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n\ntemplate <>\nstruct Graph<void> {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to() {}\n constexpr _edge(int from, int to) : _from(from), _to(to) {}\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr int weight() const { return 1; }\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n private:\n int _from, _to;\n };\n\n public:\n using edge_type = typename Graph<void>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to) { edges[from].emplace_back(from, to); }\n void add_edges(int from, int to) {\n edges[from].emplace_back(from, to);\n edges[to].emplace_back(to, from);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edge(from - base, to - base);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edges(from - base, to - base);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n#line 2 \"/home/kuhaku/atcoder/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/atcoder/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/atcoder/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/atcoder/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"/home/kuhaku/atcoder/github/algo/lib/tree/union_find.hpp\"\n\n/**\n * @brief 素集合データ構造\n * @details Implement (union by size) + (path compression)\n * @see https://github.com/atcoder/ac-library/blob/master/atcoder/dsu.hpp\n */\nstruct union_find {\n union_find() = default;\n explicit union_find(int _n) : data(_n, -1) {}\n\n int root(int x) { return data[x] < 0 ? x : data[x] = root(data[x]); }\n int get_root(int x) { return root(x); }\n\n bool is_root(int x) const { return data[x] < 0; }\n\n bool same(int x, int y) { return root(x) == root(y); }\n bool is_same(int x, int y) { return same(x, y); }\n\n int size(int x) { return -(data[root(x)]); }\n int get_size(int x) { return size(x); }\n\n bool unite(int x, int y) {\n x = root(x), y = root(y);\n if (x == y) return false;\n if (data[x] > data[y]) std::swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return true;\n }\n\n template <class F>\n bool unite(int x, int y, F f) {\n x = root(x), y = root(y);\n if (x != y) {\n if (data[x] > data[y]) std::swap(x, y);\n data[x] += data[y];\n data[y] = x;\n }\n f(x, y);\n return x != y;\n }\n\n private:\n std::vector<int> data;\n};\n#line 5 \"a.cpp\"\n\nint main(void) {\n int n, m, k, q;\n cin >> n >> m >> k >> q;\n Graph<ll> g(n);\n g.input_edges(m);\n vector<int> a(k);\n cin >> a;\n vector<pair<int, int>> qs(q);\n cin >> qs;\n for (auto &[x, y] : qs) --x, --y;\n\n vector<ll> dist(n, Inf);\n for (auto x : a) dist[x - 1] = 0;\n priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<>> pq;\n for (auto x : a) pq.emplace(0, x - 1);\n while (!pq.empty()) {\n auto [d, x] = pq.top();\n pq.pop();\n if (dist[x] != d)\n continue;\n for (auto e : g[x]) {\n if (chmin(dist[e.to()], d + e.weight())) {\n pq.emplace(dist[e.to()], e.to());\n }\n }\n }\n\n vector<int> ord(n);\n iota(all(ord), 0);\n sort(all(ord), [&](int x, int y) {\n return dist[x] > dist[y];\n });\n vector<bool> used(n);\n vector<int> ls(q), rs(q, n);\n auto check = [&]() {\n rep (i, q) {\n if (ls[i] + 1 != rs[i])\n return false;\n }\n return true;\n };\n while (!check()) {\n vector mid(n, vector<int>());\n rep (i, q) mid[(ls[i] + rs[i]) / 2].emplace_back(i);\n union_find uf(n);\n vector<bool> used(n);\n rep (i, n) {\n for (auto x : mid[i]) {\n auto [l, r] = qs[x];\n if (uf.same(l, r))\n rs[x] = i;\n else\n ls[x] = i;\n }\n int x = ord[i];\n used[x] = true;\n for (auto e : g[x]) {\n if (used[e.to()])\n uf.unite(x, e.to());\n }\n }\n }\n\n rep (i, q) {\n co(dist[ord[ls[i]]]);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 24640, "score_of_the_acc": -0.4075, "final_rank": 4 }, { "submission_id": "aoj_0575_8502275", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nstruct UnionFind{\n vector<int> par,num;\n UnionFind(int n):par(n),num(n,1){\n iota(par.begin(),par.end(),0); //include<numeric>\n }\n int find(int v){\n return (par[v]==v)?v:(par[v]=find(par[v]));\n }\n void unite(int u,int v){\n u=find(u),v=find(v);\n if(u==v)return;\n if(num[u]<num[v])swap(u,v);\n num[u]+=num[v];\n par[v]=u;\n }\n bool same(int u,int v){\n return find(u) == find(v);\n }\n int size(int v){\n return num[find(v)];\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m,k,q; cin >> n >> m >> k >> q;\n vector<vector<pair<int,int>>> g(n);\n for (int i = 0; i < m; ++i) {\n int x,y,z; cin >> x >> y >> z;\n x -= 1; y -= 1;\n g[x].push_back({y, z});\n g[y].push_back({x, z});\n }\n vector<int> d(n, 1e9);\n {\n using P = pair<int,int>;\n priority_queue<P,vector<P>,greater<>> pq;\n for (int i = 0; i < k; ++i) {\n int x; cin >> x; x -= 1;\n d[x] = 0;\n pq.push({0, x});\n }\n while (pq.size()) {\n auto p = pq.top(); pq.pop();\n int s = p.second;\n if (d[s] != p.first) continue;\n for (auto to : g[s]) {\n int t = to.first;\n int cost = d[s] + to.second;\n if (d[t] > cost) {\n d[t] = cost;\n pq.push({cost, t});\n }\n }\n }\n }\n vector<int> s(q), t(q);\n for (int i = 0; i < q; ++i) {\n cin >> s[i] >> t[i];\n s[i] -= 1; t[i] -= 1;\n }\n vector<pair<int,int>> dd(n);\n for (int i = 0; i < n; ++i) {\n dd[i] = {d[i], i};\n }\n sort(dd.rbegin(), dd.rend());\n vector<int> l(q, 0), r(q, 1e9);\n while (true) {\n vector<pair<int,int>> v(q);\n bool ed = true;\n for (int i = 0; i < q; ++i) {\n if (r[i]-l[i] > 1) ed = false;\n v[i] = {(l[i]+r[i])/2, i};\n }\n if (ed) break;\n sort(v.rbegin(), v.rend());\n\n UnionFind uf(n);\n vector<bool> used(n);\n int j = 0;\n for (int i = 0; i < q; ++i) {\n while (j < n and dd[j].first >= v[i].first) {\n int u = dd[j].second;\n used[u] = true;\n for (auto to : g[u]) {\n if (used[to.first]) {\n uf.unite(u, to.first);\n }\n }\n j += 1;\n }\n int idx = v[i].second;\n if (uf.same(s[idx], t[idx])) {\n l[idx] = v[i].first;\n }\n else {\n r[idx] = v[i].first;\n }\n }\n }\n\n for (int i = 0; i < q; ++i) {\n cout << l[i] << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 15776, "score_of_the_acc": -0.2602, "final_rank": 2 }, { "submission_id": "aoj_0575_8502260", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nstruct UnionFind{\n vector<int> par,num;\n UnionFind(int n):par(n),num(n,1){\n iota(par.begin(),par.end(),0); //include<numeric>\n }\n int find(int v){\n return (par[v]==v)?v:(par[v]=find(par[v]));\n }\n void unite(int u,int v){\n u=find(u),v=find(v);\n if(u==v)return;\n if(num[u]<num[v])swap(u,v);\n num[u]+=num[v];\n par[v]=u;\n }\n bool same(int u,int v){\n return find(u) == find(v);\n }\n int size(int v){\n return num[find(v)];\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m,k,q; cin >> n >> m >> k >> q;\n vector<vector<pair<int,int>>> g(n);\n for (int i = 0; i < m; ++i) {\n int x,y,z; cin >> x >> y >> z;\n x -= 1; y -= 1;\n g[x].push_back({y, z});\n g[y].push_back({x, z});\n }\n vector<int> d(n, 1e9);\n {\n using P = pair<int,int>;\n priority_queue<P,vector<P>,greater<>> pq;\n for (int i = 0; i < k; ++i) {\n int x; cin >> x; x -= 1;\n d[x] = 0;\n pq.push({0, x});\n }\n while (pq.size()) {\n auto p = pq.top(); pq.pop();\n int s = p.second;\n if (d[s] != p.first) continue;\n for (auto to : g[s]) {\n int t = to.first;\n int cost = d[s] + to.second;\n if (d[t] > cost) {\n d[t] = cost;\n pq.push({cost, t});\n }\n }\n }\n }\n vector<int> s(q), t(q);\n for (int i = 0; i < q; ++i) {\n cin >> s[i] >> t[i];\n s[i] -= 1; t[i] -= 1;\n }\n vector<pair<int,int>> dd(n);\n for (int i = 0; i < n; ++i) {\n dd[i] = {d[i], i};\n }\n sort(dd.rbegin(), dd.rend());\n vector<int> l(q, 0), r(q, 1e9);\n while (r[0]-l[0] > 1) {\n vector<pair<int,int>> v(q);\n for (int i = 0; i < q; ++i) {\n v[i] = {(l[i]+r[i])/2, i};\n }\n sort(v.rbegin(), v.rend());\n\n UnionFind uf(n);\n vector<bool> used(n);\n int j = 0;\n for (int i = 0; i < q; ++i) {\n while (j < n and dd[j].first >= v[i].first) {\n int u = dd[j].second;\n used[u] = true;\n for (auto to : g[u]) {\n if (used[to.first]) {\n uf.unite(u, to.first);\n }\n }\n j += 1;\n }\n int idx = v[i].second;\n if (uf.same(s[idx], t[idx])) {\n l[idx] = v[i].first;\n }\n else {\n r[idx] = v[i].first;\n }\n }\n }\n\n for (int i = 0; i < q; ++i) {\n cout << l[i] << \"\\n\";\n }\n}", "accuracy": 0.2903225806451613, "time_ms": 100, "memory_kb": 13404, "score_of_the_acc": 0, "final_rank": 16 }, { "submission_id": "aoj_0575_7910491", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing pll=pair<ll,ll>;\nusing tll=tuple<ll,ll,ll>;\nusing ld=long double;\nconst ll INF=(1ll<<60);\n#define rep(i,n) for (ll i=0;i<(ll)(n);i++)\n#define all(v) v.begin(),v.end()\ntemplate<class T> void chmin(T &a,T b){\n if(a>b){\n a=b;\n }\n}\ntemplate<class T> void chmax(T &a,T b){\n if(a<b){\n a=b;\n }\n}\nstruct union_find{\n vector<ll> par,siz;\n union_find(ll n):par(n),siz(n,1){\n rep(i,n){\n par[i]=i;\n }\n }\n ll root(ll x){\n if(par[x]==x) return x;\n return par[x]=root(par[x]);\n }\n void unite(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n if(rx==ry) return;\n if(siz[rx]<siz[ry]) swap(rx,ry);\n par[ry]=rx;\n siz[rx]+=siz[ry];\n }\n bool same(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n return rx==ry;\n }\n ll size(ll x){\n return siz[root(x)];\n }\n vector<ll> allsize(){\n set<ll> st;\n vector<ll> ret;\n rep(i,siz.size()){\n ll rx=root(i);\n if(st.count(rx)) continue;\n ret.push_back(siz[rx]);\n st.insert(rx);\n }\n return ret;\n }\n};\nstruct tree{\n ll n,max_k=1;\n vector<vector<pair<ll,ll>>> g;\n vector<vector<ll>> parent;\n vector<vector<ll>> mn;\n vector<ll> depth;\n tree(ll g_size){\n n=g_size;\n g.resize(n);\n }\n void add_edge(ll u,ll v,ll w){\n g[u].emplace_back(v,w);\n g[v].emplace_back(u,w);\n }\n void LCA(ll root=0){\n while((1<<max_k)<n) max_k++;\n parent.assign(max_k,vector<ll>(n,-1));\n mn.assign(max_k,vector<ll>(n,INF));\n depth.assign(n,-1);\n dfs(root,-1,0);\n for(ll k=0;k+1<max_k;k++){\n for(ll i=0;i<n;i++){\n if(parent[k][i]==-1){\n parent[k+1][i]=-1;\n }else{\n parent[k+1][i]=parent[k][parent[k][i]];\n chmin(mn[k+1][i],min(mn[k][i],mn[k][parent[k][i]]));\n }\n }\n }\n }\n void dfs(ll v,ll par,ll d){\n parent[0][v]=par;\n depth[v]=d;\n for(auto &[i,w]:g[v]){\n if(i==par){\n mn[0][v]=w;\n }else{\n dfs(i,v,d+1);\n }\n }\n }\n ll get_lca(ll u,ll v){\n if(depth[u]<depth[v]) swap(u,v);\n ll diff=depth[u]-depth[v];\n for(ll k=0;k<max_k;k++){\n if(diff&(1<<k)){\n u=parent[k][u];\n }\n }\n if(u==v) return u;\n for(ll k=max_k-1;0<=k;k--){\n if(parent[k][u]!=parent[k][v]){\n u=parent[k][u];\n v=parent[k][v];\n }\n }\n return parent[0][u];\n }\n ll f(ll x,ll l){\n ll diff=depth[x]-depth[l];\n ll ret=INF;\n rep(i,max_k){\n if(diff&(1<<i)){\n chmin(ret,mn[i][x]);\n x=parent[i][x];\n }\n }\n return ret;\n }\n ll q(ll u,ll v){\n ll l=get_lca(u,v);\n return min(f(u,l),f(v,l));\n }\n};\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll n,m,k,q;\n cin >> n >> m >> k >> q;\n vector<vector<pll>> g(n);\n while(m--){\n ll a,b,l;\n cin >> a >> b >> l;\n a--;\n b--;\n g[a].push_back({b,l});\n g[b].push_back({a,l});\n }\n vector<ll> f(k);\n rep(i,k){\n cin >> f[i];\n f[i]--;\n }\n vector<ll> dist(n,INF);\n priority_queue<pll,vector<pll>,greater<pll>> pq;\n rep(i,k){\n pq.push({0,f[i]});\n dist[f[i]]=0;\n }\n while(!pq.empty()){\n ll d,x;\n tie(d,x)=pq.top();\n pq.pop();\n for(auto &[i,w]:g[x]){\n if(dist[x]+w<dist[i]){\n dist[i]=dist[x]+w;\n pq.push({dist[i],i});\n }\n }\n }\n priority_queue<tll> pq2;\n rep(i,g.size()){\n for(auto &[j,w]:g[i]){\n pq2.push({min(dist[i],dist[j]),i,j});\n }\n }\n vector<tll> e;\n union_find uf(n);\n while(!pq2.empty()){\n ll w,i,j;\n tie(w,i,j)=pq2.top();\n pq2.pop();\n if(!uf.same(i,j)){\n uf.unite(i,j);\n e.emplace_back(i,j,w);\n }\n }\n tree tr(n);\n for(auto &[i,j,w]:e){\n tr.add_edge(i,j,w);\n }\n tr.LCA(0);\n vector<ll> now_min(n,0);\n while(q--){\n ll s,t;\n cin >> s >> t;\n s--;\n t--;\n cout << tr.q(s,t) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 67396, "score_of_the_acc": -1.04, "final_rank": 11 }, { "submission_id": "aoj_0575_7910489", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int;\nusing pll=pair<ll,ll>;\nusing tll=tuple<ll,ll,ll>;\nusing ld=long double;\nconst ll INF=(1ll<<30);\n#define rep(i,n) for (ll i=0;i<(ll)(n);i++)\n#define all(v) v.begin(),v.end()\ntemplate<class T> void chmin(T &a,T b){\n if(a>b){\n a=b;\n }\n}\ntemplate<class T> void chmax(T &a,T b){\n if(a<b){\n a=b;\n }\n}\nstruct union_find{\n vector<ll> par,siz;\n union_find(ll n):par(n),siz(n,1){\n rep(i,n){\n par[i]=i;\n }\n }\n ll root(ll x){\n if(par[x]==x) return x;\n return par[x]=root(par[x]);\n }\n void unite(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n if(rx==ry) return;\n if(siz[rx]<siz[ry]) swap(rx,ry);\n par[ry]=rx;\n siz[rx]+=siz[ry];\n }\n bool same(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n return rx==ry;\n }\n ll size(ll x){\n return siz[root(x)];\n }\n vector<ll> allsize(){\n set<ll> st;\n vector<ll> ret;\n rep(i,siz.size()){\n ll rx=root(i);\n if(st.count(rx)) continue;\n ret.push_back(siz[rx]);\n st.insert(rx);\n }\n return ret;\n }\n};\nstruct tree{\n int n,max_k=1;\n vector<vector<pair<int,int>>> g;\n vector<vector<int>> parent;\n vector<vector<int>> mn;\n vector<int> depth;\n tree(int g_size){\n n=g_size;\n g.resize(n);\n }\n void add_edge(int u,int v,int w){\n g[u].emplace_back(v,w);\n g[v].emplace_back(u,w);\n }\n void LCA(int root=0){\n while((1<<max_k)<n) max_k++;\n parent.assign(max_k,vector<int>(n,-1));\n mn.assign(max_k,vector<int>(n,INF));\n depth.assign(n,-1);\n dfs(root,-1,0);\n for(int k=0;k+1<max_k;k++){\n for(int i=0;i<n;i++){\n if(parent[k][i]==-1){\n parent[k+1][i]=-1;\n }else{\n parent[k+1][i]=parent[k][parent[k][i]];\n chmin(mn[k+1][i],min(mn[k][i],mn[k][parent[k][i]]));\n }\n }\n }\n }\n void dfs(int v,int par,int d){\n parent[0][v]=par;\n depth[v]=d;\n for(auto &[i,w]:g[v]){\n if(i==par){\n mn[0][v]=w;\n }else{\n dfs(i,v,d+1);\n }\n }\n }\n int get_lca(int u,int v){\n if(depth[u]<depth[v]) swap(u,v);\n int diff=depth[u]-depth[v];\n for(int k=0;k<max_k;k++){\n if(diff&(1<<k)){\n u=parent[k][u];\n }\n }\n if(u==v) return u;\n for(int k=max_k-1;0<=k;k--){\n if(parent[k][u]!=parent[k][v]){\n u=parent[k][u];\n v=parent[k][v];\n }\n }\n return parent[0][u];\n }\n int f(int x,int l){\n int diff=depth[x]-depth[l];\n int ret=INF;\n rep(i,max_k){\n if(diff&(1<<i)){\n chmin(ret,mn[i][x]);\n x=parent[i][x];\n }\n }\n return ret;\n }\n int q(int u,int v){\n int l=get_lca(u,v);\n return min(f(u,l),f(v,l));\n }\n};\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll n,m,k,q;\n cin >> n >> m >> k >> q;\n vector<vector<pll>> g(n);\n while(m--){\n ll a,b,l;\n cin >> a >> b >> l;\n a--;\n b--;\n g[a].push_back({b,l});\n g[b].push_back({a,l});\n }\n vector<ll> f(k);\n rep(i,k){\n cin >> f[i];\n f[i]--;\n }\n vector<ll> dist(n,INF);\n priority_queue<pll,vector<pll>,greater<pll>> pq;\n rep(i,k){\n pq.push({0,f[i]});\n dist[f[i]]=0;\n }\n while(!pq.empty()){\n ll d,x;\n tie(d,x)=pq.top();\n pq.pop();\n for(auto &[i,w]:g[x]){\n if(dist[x]+w<dist[i]){\n dist[i]=dist[x]+w;\n pq.push({dist[i],i});\n }\n }\n }\n priority_queue<tll> pq2;\n rep(i,g.size()){\n for(auto &[j,w]:g[i]){\n pq2.push({min(dist[i],dist[j]),i,j});\n }\n }\n vector<tll> e;\n union_find uf(n);\n while(!pq2.empty()){\n ll w,i,j;\n tie(w,i,j)=pq2.top();\n pq2.pop();\n if(!uf.same(i,j)){\n uf.unite(i,j);\n e.emplace_back(i,j,w);\n }\n }\n tree tr(n);\n for(auto &[i,j,w]:e){\n tr.add_edge(i,j,w);\n }\n tr.LCA(0);\n vector<ll> now_min(n,0);\n while(q--){\n ll s,t;\n cin >> s >> t;\n s--;\n t--;\n cout << tr.q(s,t) << '\\n';\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 41348, "score_of_the_acc": -0.5552, "final_rank": 6 }, { "submission_id": "aoj_0575_7904603", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int;\nusing pll=pair<ll,ll>;\nusing tll=tuple<ll,ll,ll>;\nusing ld=long double;\nconst ll INF=(1ll<<30);\n#define rep(i,n) for (ll i=0;i<(ll)(n);i++)\n#define all(v) v.begin(),v.end()\ntemplate<class T> void chmin(T &a,T b){\n if(a>b){\n a=b;\n }\n}\ntemplate<class T> void chmax(T &a,T b){\n if(a<b){\n a=b;\n }\n}\nstruct union_find{\n vector<ll> par,siz;\n union_find(ll n):par(n),siz(n,1){\n rep(i,n){\n par[i]=i;\n }\n }\n ll root(ll x){\n if(par[x]==x) return x;\n return par[x]=root(par[x]);\n }\n void unite(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n if(rx==ry) return;\n if(siz[rx]<siz[ry]) swap(rx,ry);\n par[ry]=rx;\n siz[rx]+=siz[ry];\n }\n bool same(ll x,ll y){\n ll rx=root(x);\n ll ry=root(y);\n return rx==ry;\n }\n ll size(ll x){\n return siz[root(x)];\n }\n vector<ll> allsize(){\n set<ll> st;\n vector<ll> ret;\n rep(i,siz.size()){\n ll rx=root(i);\n if(st.count(rx)) continue;\n ret.push_back(siz[rx]);\n st.insert(rx);\n }\n return ret;\n }\n};\nstruct HLD{\n int n;\n vector<vector<int>> g;\n vector<int> par,sz,in,out,head;\n int ord=0;\n HLD(int x){\n n=x;\n g.resize(n);\n par.resize(n);\n sz.assign(n,0);\n in.resize(n);\n out.resize(n);\n head.resize(n);\n }\n void add_edge(int u,int v){\n g[u].push_back(v);\n g[v].push_back(u);\n }\n void dfs_sz(int x,int p){\n sz[x]++;\n if(0<g[x].size()&&g[x].front()==p) swap(g[x].front(),g[x].back());\n for(auto &i:g[x]){\n if(i==p) continue;\n dfs_sz(i,x);\n sz[x]+=sz[i];\n if(sz[g[x].front()]<sz[i]) swap(g[x].front(),i);\n }\n }\n void dfs_hld(int x,int p){\n par[x]=p;\n in[x]=ord;\n ord++;\n for(auto &i:g[x]){\n if(i==p) continue;\n if(i==g[x].front()) head[i]=head[x];\n else head[i]=i;\n dfs_hld(i,x);\n }\n out[x]=ord;\n }\n void solve(int root){\n dfs_sz(root,-1);\n dfs_hld(root,-1);\n }\n vector<pair<int,int>> query(int u,int v,bool edge){\n vector<pair<int,int>> ret;\n while(true){\n if(in[v]<in[u]) swap(u,v);\n if(head[u]==head[v]) break;\n ret.emplace_back(in[head[v]],in[v]+1);\n v=par[head[v]];\n }\n ret.emplace_back(in[u]+edge,in[v]+1);\n return ret;\n }\n};\nstruct segment_tree{\n vector<ll> v;\n ll n;\n segment_tree(ll x){\n ll s=1;\n while(s<x) s*=2;\n n=s;\n v.assign(s*2-1,INF);\n }\n ll get(ll i){\n i+=n-1;\n return v[i];\n }\n void update(ll i,ll x){\n i+=n-1;\n v[i]=x;\n while(0<i){\n i=(i-1)/2;\n v[i]=min(v[i*2+1],v[i*2+2]);\n }\n }\n ll query(ll a,ll b){\n return query_sub(a,b,0ll,0ll,n);\n }\n ll query_sub(ll a,ll b,ll k,ll l,ll r){\n if(r<=a||b<=l){\n return INF;\n }else if(a<=l&&r<=b){\n return v[k];\n }else{\n ll vl=query_sub(a,b,k*2+1,l,(l+r)/2);\n ll vr=query_sub(a,b,k*2+2,(l+r)/2,r);\n return min(vl,vr);\n }\n }\n};\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll n,m,k,q;\n cin >> n >> m >> k >> q;\n vector<vector<pll>> g(n);\n while(m--){\n ll a,b,l;\n cin >> a >> b >> l;\n a--;\n b--;\n g[a].push_back({b,l});\n g[b].push_back({a,l});\n }\n vector<ll> f(k);\n rep(i,k){\n cin >> f[i];\n f[i]--;\n }\n vector<ll> dist(n,INF);\n priority_queue<pll,vector<pll>,greater<pll>> pq;\n rep(i,k){\n pq.push({0,f[i]});\n dist[f[i]]=0;\n }\n while(!pq.empty()){\n ll d,x;\n tie(d,x)=pq.top();\n pq.pop();\n for(auto &[i,w]:g[x]){\n if(dist[x]+w<dist[i]){\n dist[i]=dist[x]+w;\n pq.push({dist[i],i});\n }\n }\n }\n priority_queue<tll> pq2;\n rep(i,g.size()){\n for(auto &[j,w]:g[i]){\n pq2.push({min(dist[i],dist[j]),i,j});\n }\n }\n vector<tll> e;\n union_find uf(n);\n while(!pq2.empty()){\n ll w,i,j;\n tie(w,i,j)=pq2.top();\n pq2.pop();\n if(!uf.same(i,j)){\n uf.unite(i,j);\n e.emplace_back(i,j,w);\n }\n }\n HLD hld(n);\n for(auto &[i,j,w]:e){\n hld.add_edge(i,j);\n }\n hld.solve(0);\n segment_tree st(n);\n for(auto &[i,j,w]:e){\n vector<pll> v=hld.query(i,j,true);\n for(auto &[l,r]:v){\n if(l==r) continue;\n st.update(l,w);\n }\n }\n vector<ll> now_min(n,0);\n while(q--){\n ll s,t;\n cin >> s >> t;\n s--;\n t--;\n vector<pll> v=hld.query(s,t,true);\n ll ans=INF;\n for(auto &[l,r]:v){\n chmin(ans,st.query(l,r));\n }\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 30080, "score_of_the_acc": -0.4719, "final_rank": 5 }, { "submission_id": "aoj_0575_7628264", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for (int i = 0; i < x; i++)\n#define all(a) (a).begin(), (a).end()\nusing namespace std;\nusing ll = long long;\nconstexpr ll INF = 20000000001;\n\ntypedef pair<ll, int> P;\n\nstruct edge\n{\n int to;\n ll cost;\n};\n\nstruct UnionFind\n{\n int n;\n vector<int> par;\n vector<int> depth;\n UnionFind(int kn)\n {\n n = kn;\n par.resize(n);\n rep(i, n) { par[i] = i; }\n depth.resize(n, 1);\n }\n int find(int x)\n {\n if (x == par[x])\n {\n return x;\n }\n return par[x] = find(par[x]);\n }\n void unite(int a, int b)\n {\n a = find(a);\n b = find(b);\n if (a == b)\n {\n return;\n }\n if (depth[a] < depth[b])\n {\n par[a] = b;\n }\n else\n {\n par[b] = a;\n if (depth[a] == depth[b])\n {\n depth[a]++;\n }\n }\n }\n bool same(int a, int b)\n {\n return find(a) == find(b);\n }\n};\n\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int n, m, k, q;\n cin >> n >> m >> k >> q;\n vector<vector<edge>> G(n);\n rep(i, m)\n {\n int a, b;\n ll c;\n cin >> a >> b >> c;\n a--;\n b--;\n G[a].push_back({b, c});\n G[b].push_back({a, c});\n }\n // vector<int> fes;\n priority_queue<P, vector<P>, greater<P>> que; // P(距離、頂点)\n rep(i, k)\n {\n int f;\n cin >> f;\n f--;\n // fes.push_back(f);\n que.push(P(0, f));\n }\n vector<bool> used(n, false);\n vector<P> V; // P(距離、頂点)の大きい順に入っている\n while (!que.empty())\n {\n P p = que.top();\n que.pop();\n ll c = p.first;\n int v = p.second;\n if (used[v])\n {\n continue;\n }\n V.push_back(p);\n used[v] = true;\n for (auto e : G[v])\n {\n if (used[e.to])\n {\n continue;\n }\n que.push(P(c + e.cost, e.to));\n }\n }\n reverse(all(V));\n\n vector<int> s(q), t(q);\n vector<ll> l(q, 0), r(q, INF);\n vector<P> mid_idx;\n rep(i, q)\n {\n cin >> s[i] >> t[i];\n s[i]--;\n t[i]--;\n mid_idx.push_back(P((l[i] + r[i]) / 2, i));\n }\n rep(z, 40)\n {\n if (mid_idx.size() == 0)\n {\n break;\n }\n sort(all(mid_idx));\n reverse(all(mid_idx));\n\n UnionFind uf(n);\n vector<bool> visited(n);\n vector<P> new_mid_idx;\n int V_idx = 0;\n for (auto p : mid_idx)\n {\n while (V_idx != V.size() && V[V_idx].first >= p.first)\n {\n visited[V[V_idx].second] = true;\n for (auto e : G[V[V_idx].second])\n {\n if (visited[e.to])\n {\n uf.unite(V[V_idx].second, e.to);\n }\n }\n V_idx++;\n }\n if (uf.same(s[p.second], t[p.second]))\n {\n l[p.second] = p.first;\n }\n else\n {\n r[p.second] = p.first;\n }\n if (r[p.second] - l[p.second] > 1)\n {\n new_mid_idx.push_back(P((l[p.second] + r[p.second]) / 2, p.second));\n }\n }\n mid_idx = new_mid_idx;\n }\n rep(i, q)\n {\n cout << l[i] << endl;\n }\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 27012, "score_of_the_acc": -0.6417, "final_rank": 8 }, { "submission_id": "aoj_0575_7387246", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing tll = tuple<ll, ll, ll>;\n\nconstexpr ll INF = 1LL << 60;\nll N, M, K, Q;\nvector<vector<pll>> G;\nvector<vector<ll>> T;\nvector<ll> F, D;\nvector<tll> E;\n\nclass DisjointSet {\npublic:\n ll n;\n vector<ll> node, rank;\n DisjointSet(ll n_) : n(n_) {\n node.resize(n);\n rank.resize(n, 1);\n for (ll i = 0; i < n; i++) node[i] = i;\n }\n ll find(ll x) {\n if (node[x] != x) {\n node[x] = find(node[x]);\n }\n return node[x];\n }\n bool same(ll x, ll y) {\n return find(x) == find(y);\n }\n void unite(ll x, ll y) {\n ll px = find(x);\n ll py = find(y);\n if (rank[px] < rank[py]) {\n node[px] = py;\n rank[py] += rank[px];\n } else {\n node[py] = px;\n rank[px] += rank[py];\n }\n }\n};\n\nclass LCA {\npublic:\n ll n, k;\n vector<vector<ll>> tree;\n vector<vector<pll>> parent;\n vector<ll> dist, cost;\n\n LCA(vector<vector<ll>> tree_, vector<ll> cost_) : n((ll)tree_.size()), dist(n, -1) {\n tree = tree_;\n cost = cost_;\n k = 1;\n while (n > (1LL << k)) k++;\n parent.assign(n, vector<pll>(k + 1, pll(-1, INF)));\n dfs(0, -1, 0);\n doubling();\n }\n void dfs(ll u, ll p, ll cnt) {\n dist[u] = cnt;\n parent[u][0] = {p, p != -1 ? min(cost[u], cost[p]) : cost[u]};\n for (auto v : tree[u]) {\n if (dist[v] >= 0) continue;\n dfs(v, u, cnt + 1);\n }\n }\n void doubling() {\n for (ll i = 1; i <= k; i++) {\n for (ll j = 0; j < n; j++) {\n auto [a1, c1] = parent[j][i - 1];\n if (a1 == -1) {\n parent[j][i] = {a1, c1};\n } else {\n auto [a2, c2] = parent[a1][i - 1];\n parent[j][i] = {a2, min(c1, c2)};\n }\n }\n }\n }\n ll get_cost(ll a, ll b) {\n if (dist[a] < dist[b]) swap(a, b);\n ll ret = INF;\n for (ll i = 0; i <= k; i++) {\n if ((dist[a] - dist[b]) >> i & 1) {\n ret = min(ret, parent[a][i].second);\n a = parent[a][i].first;\n }\n }\n if (a == b) return ret;\n for (ll i = k; i >= 0; i--) {\n if (parent[a][i].first == parent[b][i].first) continue;\n ret = min({ret, parent[a][i].second, parent[b][i].second});\n a = parent[a][i].first;\n b = parent[b][i].first;\n }\n return min({ret, parent[a][0].second, parent[b][0].second});\n }\n};\n\nvoid dijkstra() {\n D.resize(N, INF);\n priority_queue<pll, vector<pll>, greater<pll>> que;\n for (auto f : F) {\n que.push({0, f});\n D[f] = 0;\n }\n while (!que.empty()) {\n auto [ud, u] = que.top(); que.pop();\n if (D[u] < ud) continue;\n for (auto [v, vd] : G[u]) {\n if (D[v] <= ud + vd) continue;\n D[v] = ud + vd;\n que.push({D[v], v});\n }\n }\n}\n\nvoid prim() {\n T.resize(N);\n for (auto& [c, a, b] : E) c = min(D[a], D[b]);\n sort(E.begin(), E.end(), greater<tll>());\n DisjointSet ds(N);\n for (auto [c, a, b] : E) {\n if (ds.same(a, b)) continue;\n T[a].push_back(b);\n T[b].push_back(a);\n ds.unite(a, b);\n }\n}\n\nint main() {\n cin >> N >> M >> K >> Q;\n G.resize(N);\n F.resize(K);\n for (ll i = 0; i < M; i++) {\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].push_back({b, l});\n G[b].push_back({a, l});\n E.push_back({0, a, b});\n }\n for (ll i = 0; i < K; i++) {\n cin >> F[i];\n F[i]--;\n }\n dijkstra();\n prim();\n LCA lca(T, D);\n vector<ll> ans;\n while (Q--) {\n ll s, t;\n cin >> s >> t;\n s--; t--;\n ans.push_back(lca.get_cost(s, t));\n }\n for (auto a : ans) cout << a << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 73588, "score_of_the_acc": -1.2987, "final_rank": 15 }, { "submission_id": "aoj_0575_7376007", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing tll = tuple<ll, ll, ll>;\n\nconstexpr ll INF = 1LL << 60;\nll N, M, K, Q;\nvector<vector<pll>> G;\nvector<vector<ll>> T;\nvector<ll> F, D;\nvector<tll> E;\n\nclass DisjointSet {\npublic:\n ll n;\n vector<ll> node, rank;\n DisjointSet(ll n_) : n(n_) {\n node.resize(n);\n rank.resize(n, 1);\n for (ll i = 0; i < n; i++) node[i] = i;\n }\n ll find(ll x) {\n if (node[x] != x) {\n node[x] = find(node[x]);\n }\n return node[x];\n }\n bool same(ll x, ll y) {\n return find(x) == find(y);\n }\n void unite(ll x, ll y) {\n ll px = find(x);\n ll py = find(y);\n if (rank[px] < rank[py]) {\n node[px] = py;\n rank[py] += rank[px];\n } else {\n node[py] = px;\n rank[px] += rank[py];\n }\n }\n};\n\nclass LCA {\npublic:\n ll n, k;\n vector<vector<ll>> tree;\n vector<vector<pll>> parent;\n vector<ll> dist, cost;\n\n LCA(vector<vector<ll>> tree_, vector<ll> cost_) : n((ll)tree_.size()), dist(n, -1) {\n tree = tree_;\n cost = cost_;\n k = 1;\n while (n > (1LL << k)) k++;\n parent.assign(n, vector<pll>(k + 1, pll(-1, INF)));\n dfs(0, -1, 0);\n doubling();\n }\n void dfs(ll u, ll p, ll cnt) {\n dist[u] = cnt;\n parent[u][0] = {p, p != -1 ? min(cost[u], cost[p]) : cost[u]};\n for (auto v : tree[u]) {\n if (dist[v] >= 0) continue;\n dfs(v, u, cnt + 1);\n }\n }\n void doubling() {\n for (ll i = 1; i <= k; i++) {\n for (ll j = 0; j < n; j++) {\n auto [a1, c1] = parent[j][i - 1];\n if (a1 == -1) {\n parent[j][i] = {a1, c1};\n } else {\n auto [a2, c2] = parent[a1][i - 1];\n parent[j][i] = {a2, min(c1, c2)};\n }\n }\n }\n }\n ll get_cost(ll a, ll b) {\n if (dist[a] < dist[b]) swap(a, b);\n ll ret = INF;\n for (ll i = 0; i <= k; i++) {\n if ((dist[a] - dist[b]) >> i & 1) {\n ret = min(ret, parent[a][i].second);\n a = parent[a][i].first;\n }\n }\n if (a == b) return ret;\n for (ll i = k; i >= 0; i--) {\n if (parent[a][k].first == parent[b][k].first) continue;\n ret = min({ret, parent[a][k].second, parent[b][k].second});\n a = parent[a][k].first;\n b = parent[b][k].first;\n }\n return min({ret, parent[a][0].second, parent[b][0].second});\n }\n};\n\nvoid dijkstra() {\n D.resize(N, INF);\n priority_queue<pll, vector<pll>, greater<pll>> que;\n for (auto f : F) {\n que.push({0, f});\n D[f] = 0;\n }\n while (!que.empty()) {\n auto [ud, u] = que.top(); que.pop();\n if (D[u] < ud) continue;\n for (auto [v, vd] : G[u]) {\n if (D[v] <= ud + vd) continue;\n D[v] = ud + vd;\n que.push({D[v], v});\n }\n }\n}\n\nvoid prim() {\n T.resize(N);\n for (auto& [c, a, b] : E) c = min(D[a], D[b]);\n sort(E.begin(), E.end(), greater<tll>());\n DisjointSet ds(N);\n for (auto [c, a, b] : E) {\n if (ds.same(a, b)) continue;\n T[a].push_back(b);\n T[b].push_back(a);\n ds.unite(a, b);\n }\n}\n\nint main() {\n cin >> N >> M >> K >> Q;\n G.resize(N);\n F.resize(K);\n for (ll i = 0; i < M; i++) {\n ll a, b, l;\n cin >> a >> b >> l;\n a--; b--;\n G[a].push_back({b, l});\n G[b].push_back({a, l});\n E.push_back({0, a, b});\n }\n for (ll i = 0; i < K; i++) {\n cin >> F[i];\n F[i]--;\n }\n dijkstra();\n prim();\n LCA lca(T, D);\n vector<ll> ans;\n while (Q--) {\n ll s, t;\n cin >> s >> t;\n s--; t--;\n ans.push_back(lca.get_cost(s, t));\n }\n for (auto a : ans) cout << a << endl;\n return 0;\n}", "accuracy": 0.12903225806451613, "time_ms": 200, "memory_kb": 72808, "score_of_the_acc": -1.1169, "final_rank": 20 } ]
aoj_0581_cpp
お土産購入計画 (Gifts) 問題 オーストラリアに旅行に来た JOI 君は様々な場所で観光を楽しみ,ついに帰国する日がやってきた.今,JOI 君は帰りの飛行機が出発する国際空港のある町にいる.この町は東西南北に区画整理されており,各区画には道,土産店,住宅,国際空港がある. JOI 君は最も北西の区画から出発して最も南東の区画の国際空港を目指す. JOI 君は今いる区画から隣り合った区画に移動することができるが,住宅のある区画には入ることはできない.また飛行機の時間に間に合わせるために,今いる区画の東か南の区画にのみ移動する.ただし,時間にはいくらか余裕があるため,K 回まで今いる区画の北か西の区画へ移動することができる. JOI 君は土産店のある区画に入ると,日本の友人たちのためにお土産を買う.JOI 君は土産店について入念に下調べをしていたので,どの土産店に行ったら何個のお土産を買うことができるかが分かっている.JOI 君が購入できるお土産の個数の最大値を求めるプログラムを作成せよ. ただし,お土産を買う時間は無視できるとし,同じ土産店に 2 度以上訪れたときは最初に訪れたときだけお土産を買う. 入力 入力は 1 + H 行からなる. 1 行目には,3 つの整数 H, W, K (2 ≦ H ≦ 50, 2 ≦ W ≦ 50, 1 ≦ K ≦ 3) が空白を区切りとして書かれている. 続く H 行にはそれぞれ W 文字からなる文字列が書かれており,区画の情報を表す.北から i 番目,西から j 番目の区画を (i, j) と表す (1 ≦ i ≦ H, 1 ≦ j ≦ W). i 行目の j 番目の文字は,区画 (i, j) が道か国際空港である場合は '.' であり,住宅である場合は '#' である. 土産店である場合は '1', '2', ..., '9' のいずれかであり,その土産店で買うことができるお土産の個数を表す. 与えられる入力データにおいては,JOI 君がはじめにいる最も北西の区画が道であることは保証されている.また,JOI 君が国際空港にたどり着けることは保証されている. 出力 JOI 君が購入できるお土産の個数の最大値を表す整数を 1 行で出力せよ. 入出力例 入力例 1 5 4 2 ...# .#.# .#73 8##. .... 出力例 1 11 入出力例 1 において,JOI 君は 3 回南へ進み区画 (4, 1) の土産店で買い物をした後,さらに南へ 1 回,東へ 3 回進み,そこから北へ 2 回進むことで区画 (3, 4) の土産店で買い物をする.最後に南へ 2 回進んで国際空港へたどり着くと,合計で 11 個のお土産を買うことができる. 入力例 2 4 4 3 .8#9 9.#. .#9. .... 出力例 2 27 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0581_10758137", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#include<atcoder/modint>\nusing namespace atcoder;\nusing mint=modint998244353;\n\nusing ll =long long;\n\n\nvoid solve(){\n \n \n\n}\n\nmap<set<array<ll,2>>,ll> DP[51][51][5];\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N,M,K;\n cin>>N>>M>>K;\n\n vector<string> S(N);\n for(int i=0;i<N;i++)cin>>S[i];\n\n DP[0][0][K][{}]=0;\n vector<int> nd={0,1,0,-1,0};\n for(ll k=K;k>=0;k--){\n for(int i=0;i<N;i++){\n for(int j=0;j<M;j++){\n for(auto [ST,n]:DP[i][j][k]){\n for(int d=0;d<4;d++){\n if(d>1&&k==0)break;\n ll ni=i+nd[d];\n ll nj=j+nd[d+1];\n if(ni<0||nj<0||ni>=N||nj>=M)continue;\n if(S[ni][nj]=='#')continue;\n ll nk=k;\n ll nc=n;\n if(d>1)nk--;\n \n set<array<ll,2>> NS;\n for(auto [y,x]:ST){\n if(abs(y-ni)+abs(x-nj)<=k+1){\n NS.insert({y,x});\n }\n }\n if(S[ni][nj]!='.'){\n if(!ST.count({ni,nj})){\n nc+=S[ni][nj]-'0';\n NS.insert({ni,nj});\n }\n }\n DP[ni][nj][nk][NS]=max(DP[ni][nj][nk][NS],nc);\n }\n \n }\n if(i!=N-1||j!=M-1)DP[i][j][k].clear();\n }\n }\n }\n\n ll an=0;\n for(int k=0;k<=K;k++){\n for(auto [S,n]:DP[N-1][M-1][k])an=max(an,n);\n }\n cout<<an<<\"\\n\";\n \n \n}", "accuracy": 1, "time_ms": 1230, "memory_kb": 114432, "score_of_the_acc": -0.6336, "final_rank": 5 }, { "submission_id": "aoj_0581_7757048", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <string>\n#include <queue>\n#include <set>\n#include <string.h>\n#include <algorithm>\nusing namespace std;\nstruct E{\n\tvector<int> vs;\n\tint v;\n\tint k;\n\tint xr;\n\tint yd;\n\tbool operator<(const E& e)const{\n\t\treturn v<e.v;\n\t}\n};\nstruct E2{\n\tint x,y;\n\tbool operator<(const E2 e2)const{\n\t\tif(x!=e2.x)return x<e2.x;\n\t\treturn y<e2.y;\n\t}\n};\nint z=0;\n\nmap<vector<int>,int> dp[4];\nmap<vector<int>,int> dp2[4][51][51];\nset<E2> nextxy;\n//map<set<int>,int> dp[4][2501];\nstring ms[51];\npriority_queue<E> qs;\nint search(vector<int> vs,int p){\n\tfor(int i=0;i<vs.size();i++){\n\t\tif(vs[i]==p)return 0;\n\t}\n\treturn 1;\n}\nbool rowok(int p1,int p2,int w){\n\treturn p1/w==p2/w;\n}\nvoid dell(vector<int> & vs,int p1,int w,int k1){\n\tint x1=p1%w;\n\tint y1=p1/w;\n\t\n\tfor(vector<int>::iterator it=vs.begin();it!=vs.end();){\n\t\tint x2,y2,d=0;\n\t\tx2=(*it)%w;\n\t\ty2=(*it)/w;\n\t\t\n\t\tif(x1-x2>0){\n\t\t\td+=x1-x2;\n\t\t}\n\t\tif(y1-y2>0){\n\t\t\td+=y1-y2;\n\t\t}\n\t\tif(d>k1){\n\t\t\tit=vs.erase(it);\n\t\t}else{\n\t\t\tit++;\n\t\t}\n\t\tif(it==vs.end())break;\n\t}\n\t\n}\n\nvoid add(E e,int addk,int p1,int h,int w,int k){\n\tint m1=h*w;\n\tif(p1<0 || m1<=p1)return ;\n\tint x=p1%w;\n\tint y=p1/w;\n\tif(ms[y][x]=='#')return ;\n\t\n\te.k+=addk;\n\tif(e.k>k)return ;\n\t//if(100<z && z<200)cout<<e.vs.size()<<\" \";\n\tdell(e.vs,p1,w,k-e.k);\n\t\n\tint m2=search(e.vs,p1);\n\tif(ms[y][x]!='.'){\n\t\te.v+=(ms[y][x]-'0')*m2;\n\t}\n\te.vs.push_back(p1);\n\t\n\t//if(100<z && z<200)cout<<e.vs.size()<<\" \"<<e.v<<endl;\n\t//set<int> s1;\n\t//s1.insert(e.vs.begin(),e.vs.end());\n\tint t=-1;\n\tif(dp[e.k].find(e.vs)!=dp[e.k].end())t=dp[e.k][e.vs];\n\t//if(dp[e.k][p1].find(s1)!=dp[e.k][p1].end())t=dp[e.k][p1][s1];\n\t//cout<<x<<\" \"<<y<<\" \"<<p1<<\" \"<<t<<\" \"<<e.v<<endl;\n\tif(e.v>t){\n\t\tdp[e.k][e.vs]=e.v;\n\t\tif(e.xr<x || e.yd<y){\n\t\t\tdp2[e.k][y][x][e.vs]=max(dp2[e.k][y][x][e.vs],e.v);\n\t\t\tE2 e2;\n\t\t\te2.x=x;\n\t\t\te2.y=y;\n\t\t\tnextxy.insert(e2);\n\t\t}else{\n\t\t\t//dp[e.k][p1][s1]=e.v;\n\t\t\tqs.push(e);\n\t\t}\n\t}\n}\n\nint main() {\n\tint h,w,k;\n\tcin>>h>>w>>k;\n\tfor(int i=0;i<h;i++){\n\t\tcin>>ms[i];\n\t}\n\tvector<int> v1;\n\tv1.push_back(0);\n\tdp2[0][0][0][v1]=0;\n\tE2 e2;\n\te2.x=0;\n\te2.y=0;\n\tnextxy.insert(e2);\n\t\n\tint ans=0;\n\twhile(nextxy.size()>0){\n\t\tfor(set<E2>::iterator its=nextxy.begin();its!=nextxy.end();its++){\n\t\t\tint xr=(*its).x;\n\t\t\tint yd=(*its).y;\n\t\t\tfor(int nowk=0;nowk<=k;nowk++){\n\t\t\t\tfor(map<vector<int>,int>::iterator it=dp2[nowk][yd][xr].begin();it!=dp2[nowk][yd][xr].end();it++){\n\t\t\t\t\tE e;\n\t\t\t\t\te.vs=(*it).first;\n\t\t\t\t\te.v=(*it).second;\n\t\t\t\t\te.k=nowk;\n\t\t\t\t\te.xr=xr;\n\t\t\t\t\te.yd=yd;\n\t\t\t\t\tqs.push(e);\n\t\t\t\t}\n\t\t\t\tdp2[nowk][yd][xr].clear();\n\t\t\t}\n\t\t}\n\t\tnextxy.clear();\n\t\twhile(qs.size()>0){\n\t\t\tE e=qs.top();\n\t\t\tqs.pop();\n\t\t\tint p1=e.vs[e.vs.size()-1];\n\t\t\tint x=p1%w;\n\t\t\tint y=p1/w;\n\t\t\t//cout<<x<<\" \"<<y<<endl;\n\t\t\tif(x==w-1 && y==h-1 && ans<e.v){\n\t\t\t\tans=e.v;\n\t\t\t}\n\t\t\t//274\n\t\t\tadd(e,0,p1+w,h,w,k);\n\t\t\tadd(e,1,p1-w,h,w,k);\n\t\t\tif(rowok(p1,p1+1,w)){\n\t\t\t\tadd(e,0,p1+1,h,w,k);//堀江\n\t\t\t}\n\t\t\tif(rowok(p1,p1-1,w)){\n\t\t\t\tadd(e,1,p1-1,h,w,k);\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3640, "memory_kb": 161852, "score_of_the_acc": -1.1502, "final_rank": 12 }, { "submission_id": "aoj_0581_7755998", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n#include <string>\n#include <queue>\n#include <set>\n#include <string.h>\nusing namespace std;\nstruct E{\n\tvector<int> vs;\n\tint v;\n\tint k;\n\tbool operator<(const E& e)const{\n\t\treturn v<e.v;\n\t}\n};\nint dp[4][2502];\nstring ms[51];\npriority_queue<E> qs;\nint search(vector<int> vs,int p){\n\tfor(int i=0;i<vs.size();i++){\n\t\tif(vs[i]==p)return 0;\n\t}\n\treturn 1;\n}\nbool rowok(int p1,int p2,int w){\n\treturn p1/w==p2/w;\n}\nvoid add(E e,int addk,int p1,int h,int w,int k){\n\tint m1=h*w;\n\tif(p1<0 || m1<=p1)return ;\n\tint x=p1%w;\n\tint y=p1/w;\n\tif(ms[y][x]=='#')return ;\n\tif(ms[y][x]!='.'){\n\t\te.v+=(ms[y][x]-'0')*search(e.vs,p1);\n\t}\n\t\n\te.vs.push_back(p1);\n\tif(e.vs.size()>7)e.vs.erase(e.vs.begin());\n\te.k+=addk;\n\tif(e.k>k)return ;\n\t\n\tint t=dp[e.k][p1];\n\n\t//cout<<x<<\" \"<<y<<\" \"<<p1<<\" \"<<t<<\" \"<<e.v<<endl;\n\tif(e.v>t){\n\t\tdp[e.k][p1]=e.v;\n\t\tqs.push(e);\n\t}\n}\n\nint main() {\n\tint h,w,k;\n\tcin>>h>>w>>k;\n\tfor(int i=0;i<h;i++){\n\t\tcin>>ms[i];\n\t}\n\tE e;\n\te.vs.push_back(0);\n\te.v=0;\n\te.k=0;\n\tqs.push(e);\n\tmemset(dp,-1,sizeof(dp));\n\tint ans=0;\n\twhile(qs.size()>0){\n\t\tE e=qs.top();\n\t\tqs.pop();\n\t\tint p1=e.vs[e.vs.size()-1];\n\t\tint x=p1%w;\n\t\tint y=p1/w;\n\t\t//cout<<x<<\" \"<<y<<endl;\n\t\tif(x==w-1 && y==h-1 && ans<e.v){\n\t\t\tans=e.v;\n\t\t\tcontinue;\n\t\t}\n\t\t//704\n\t\tadd(e,0,p1+w,h,w,k);\n\t\tadd(e,1,p1-w,h,w,k);\n\t\tif(rowok(p1,p1+1,w)){\n\t\t\tadd(e,0,p1+1,h,w,k);\n\t\t}\n\t\tif(rowok(p1,p1-1,w)){\n\t\t\tadd(e,1,p1-1,h,w,k);\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 0.8, "time_ms": 130, "memory_kb": 3288, "score_of_the_acc": -0.013, "final_rank": 16 }, { "submission_id": "aoj_0581_7186517", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/modint>\n\n#define rep(i, x) for (int i = 0; i < x; i++)\n#define rep2(i, x) for (int i = 1; i <= x; i++)\n#define rep3(i, x, y) for (int i = x; i < y; i++)\n#define REP(i, x) for (int i = x - 1; i >= 0; i--)\n#define REP2(i, x) for (int i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define pb push_back\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\n// using namespace atcoder;\n\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n// const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError\n{\n};\n\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n if (a > b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nstruct Point\n{\n int x, y;\n bool operator!=(const Point &p) const noexcept { return (x != p.x || y != p.y); }\n};\n// 左上右下\nint dx[4] = {0, -1, 0, 1};\nint dy[4] = {-1, 0, 1, 0};\n\nchar grid[55][55];\nint dp[4][51][51][4][4][4][4][4];\n// dp[k][x][y][d1][d2][d3][d4][d5]\n// 今(x,y)にいてk回上左に行ってて前の行動がpre1~5の時の、お土産の個数の最大値\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n // cout << fixed << setprecision(15);\n // priority_queue<ll, vector<ll>, greater<ll>> que;\n // priority_queue<P, vector<P>, greater<P>> que;\n // priority_queue<status, vector<status>, greater<status>> que;\n\n ////////////////////\n //\n // 初期化\n //\n rep(k, 4)\n {\n rep(x, 51)\n {\n rep(y, 51)\n {\n rep(d1, 4)\n {\n rep(d2, 4)\n {\n rep(d3, 4)\n {\n rep(d4, 4)\n {\n rep(d5, 4)\n {\n dp[k][x][y][d1][d2][d3][d4][d5] = -1;\n }\n }\n }\n }\n }\n }\n }\n }\n\n ////////////////////\n //\n // input\n //\n\n int h, w, K;\n cin >> h >> w >> K;\n\n rep2(x, h)\n {\n rep2(y, w)\n {\n cin >> grid[x][y];\n }\n }\n\n ////////////////////\n //\n // DP\n //\n\n int ans = 0;\n dp[0][1][1][0][0][0][0][0] = 0;\n rep2(x, h)\n {\n rep2(y, w)\n {\n if (grid[x][y] == '#')\n {\n continue;\n }\n int cnt = 0;\n if (grid[x][y] != '.')\n {\n cnt = grid[x][y] - '0';\n }\n rep(d1, 4)\n {\n rep(d2, 4)\n {\n rep(d3, 4)\n {\n rep(d4, 4)\n {\n rep3(l, 2, 4)\n {\n int prex = 0, prey = 0;\n prex = x - dx[l], prey = y - dy[l];\n int ma = -1;\n rep(d0, 4)\n {\n chmax(ma, dp[0][prex][prey][d0][d1][d2][d3][d4]);\n }\n if (ma == -1)\n {\n continue;\n }\n dp[0][x][y][d1][d2][d3][d4][l] = ma + cnt;\n if (x == h && y == w)\n {\n chmax(ans, dp[0][x][y][d1][d2][d3][d4][l]);\n }\n }\n }\n }\n }\n }\n }\n }\n\n rep2(k, K)\n {\n ////////////////////\n //\n // k-1 -> k\n //\n\n REP2(x, h)\n {\n REP2(y, w)\n {\n if (grid[x][y] == '#')\n {\n continue;\n }\n\n int cnt = 0;\n if (grid[x][y] != '.')\n {\n cnt = grid[x][y] - '0';\n }\n rep(d1, 4)\n {\n rep(d2, 4)\n {\n rep(d3, 4)\n {\n rep(d4, 4)\n {\n rep(l, 2)\n {\n int prex = x - dx[l], prey = y - dy[l];\n Point p1 = {prex, prey};\n Point p2 = {p1.x - dx[d4], p1.y - dy[d4]};\n Point p3 = {p2.x - dx[d3], p2.y - dy[d3]};\n Point p4 = {p3.x - dx[d2], p3.y - dy[d2]};\n Point p5 = {p4.x - dx[d1], p4.y - dy[d1]};\n\n int ma = -1;\n rep(d0, 4)\n {\n chmax(ma, dp[k - 1][prex][prey][d0][d1][d2][d3][d4]);\n }\n if (ma == -1)\n {\n continue;\n }\n\n Point p = {x, y};\n int cnt2 = 0;\n if (p != p1 && p != p2 && p != p2 && p != p3 && p != p4 && p != p5)\n {\n cnt2 = cnt;\n }\n\n dp[k][x][y][d1][d2][d3][d4][l] = ma + cnt2;\n if (x == h && y == w)\n {\n chmax(ans, dp[k][x][y][d1][d2][d3][d4][l]);\n }\n }\n }\n }\n }\n }\n }\n }\n\n ////////////////////\n //\n // k -> k\n //\n\n rep2(x, h)\n {\n rep2(y, w)\n {\n if (grid[x][y] == '#')\n {\n continue;\n }\n\n int cnt = 0;\n if (grid[x][y] != '.')\n {\n cnt = grid[x][y] - '0';\n }\n rep(d1, 4)\n {\n rep(d2, 4)\n {\n rep(d3, 4)\n {\n rep(d4, 4)\n {\n rep3(l, 2, 4)\n {\n int prex = 0, prey = 0;\n prex = x - dx[l], prey = y - dy[l];\n Point p1 = {prex, prey};\n Point p2 = {p1.x - dx[d4], p1.y - dy[d4]};\n Point p3 = {p2.x - dx[d3], p2.y - dy[d3]};\n Point p4 = {p3.x - dx[d2], p3.y - dy[d2]};\n Point p5 = {p4.x - dx[d1], p4.y - dy[d1]};\n\n int ma = -1;\n rep(d0, 4)\n {\n chmax(ma, dp[k][prex][prey][d0][d1][d2][d3][d4]);\n }\n if (ma == -1)\n {\n continue;\n }\n\n \n Point p = {x, y};\n int cnt2 = 0;\n if (p != p1 && p != p2 && p != p2 && p != p3 && p != p4 && p != p5)\n {\n cnt2 = cnt;\n }\n\n dp[k][x][y][d1][d2][d3][d4][l] = ma + cnt2;\n if (x == h && y == w)\n {\n chmax(ans, dp[k][x][y][d1][d2][d3][d4][l]);\n }\n }\n }\n }\n }\n }\n }\n }\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 45060, "score_of_the_acc": -0.1809, "final_rank": 1 }, { "submission_id": "aoj_0581_6741061", "code_snippet": "#if 1\n#define _CRT_SECURE_NO_WARNINGS\n\n#include <iostream>\n#include <fstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <stack>\n#include <array>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <cstdint>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <assert.h>\n#include <bitset>\n#include <list>\n#include <cmath>\n#include <array>\n//#include <atcoder/all>\n\nauto& in = std::cin;\nauto& out = std::cout;\n#define all_range(C) std::begin(C), std::end(C)\nconst int MOD = 10007;\n\nint H, W, K;\nchar map[52][52];\n\nstd::unordered_map<uint32_t, int16_t> dp[52][52][4];\n\nuint32_t myencode(int h, int w, const std::array<std::pair<int8_t, int8_t>, 6>& visited) {\n\n\tstd::pair<int8_t, int8_t> now = { h,w };\n\tuint32_t mask = 0;\n\tfor (int i = visited.size()-1; i >= 0; --i)\n\t{\n\t\tif (visited[i].first == now.first) {\n\t\t\tif (visited[i].second == now.second - 1) {\n\t\t\t\tmask |= 0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tassert((visited[i].second == now.second + 1) || (visited[i] == std::pair<int8_t, int8_t>{ 0, 0 }));\n\t\t\t\tmask |= 1;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (visited[i].first == now.first - 1) {\n\t\t\t\tmask |= 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tassert((visited[i].first == now.first + 1) || (visited[i] == std::pair<int8_t, int8_t>{ 0,0 }));\n\t\t\t\tmask |= 3;\n\t\t\t}\n\t\t}\n\n\t\tmask <<= 2;\n\t\tnow = visited[i];\n\t}\n\treturn mask;\n}\n\nint16_t func(int h, int w, int k, std::array<std::pair<int8_t, int8_t>, 6> visited) {\n\n\tif (map[h][w] == '#') {\n\t\treturn -5509;\n\t}\n\tif (k == 0 && h == H && w == W) {\n\t\treturn 0;\n\t}\n\tassert(0 <= h);\n\tassert(0 <= w);\n\tauto& memo_map = dp[h][w][k];\n\tif (k == 0) {\n\t\tfor (size_t i = 0; i < visited.size(); i++) {\n\t\t\tif (!(visited[i].first < h || visited[i].second < w)) {\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tvisited[i] = {};\n\t\t}\n\t}\n\tif (k == 3) {\n\t\tvisited[0] = {};\n\t\tvisited[1] = {};\n\t\tvisited[2] = {};\n\t}\n\tauto enc_v = myencode(h,w,visited);\n\tif (memo_map.count(enc_v) != 0) {\n\t\treturn memo_map[enc_v];\n\t}\n\tauto& memo = memo_map[enc_v];\n\tmemo = -5509;\n\tif (h == H && w == W) {\n\t\tmemo = 0;\n\t}\n\n\tstd::array<std::pair<int8_t, int8_t>, 6> next_visited = { visited[1], visited[2], visited[3], visited[4], visited[5], {(int8_t)h,(int8_t)w} };\n\tif (map[h][w + 1] != '#') {\n\t\tbool getable = (map[h][w + 1] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w + 1}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w + 1] - '0') : 0) + func(h, w + 1, k, next_visited));\n\t}\n\tif (map[h + 1][w] != '#') {\n\t\tbool getable = (map[h + 1][w] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h + 1, w}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h + 1][w] - '0') : 0) + func(h + 1, w, k, next_visited));\n\t}\n\n\tif (k > 0) {\n\t\tif (map[h][w - 1] != '#') {\n\t\t\tbool getable = (map[h][w - 1] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w - 1}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w - 1] - '0') : 0) + func(h, w - 1, k - 1, next_visited));\n\t\t}\n\t\tif (map[h - 1][w] != '#') {\n\t\t\tbool getable = (map[h - 1][w] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h - 1, w}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h - 1][w] - '0') : 0) + func(h - 1, w, k - 1, next_visited));\n\t\t}\n\t}\n\n\tif (memo < 0) {\n\t\tmemo = -5509;\n\t}\n\treturn memo;\n}\n\n\ntemplate<typename T, typename U>\nstd::enable_if_t<std::rank<T>::value == 0> fill_all(T& arr, const U& v) {\n\tarr = v;\n}\ntemplate<typename ARR, typename U>\nstd::enable_if_t<std::rank<ARR>::value != 0> fill_all(ARR& arr, const U& v) {\n\tfor (auto& i : arr) {\n\t\tfill_all(i, v);\n\t}\n}\n\nint main()\n{\n\tusing std::endl;\n\n\t//in >> H >> W >> K;\n\tscanf(\"%d\", &H);\n\tscanf(\"%d\", &W);\n\tscanf(\"%d\", &K);\n\tfill_all(map, '#');\n\tfor (size_t i = 1; i <= H; i++)\n\t{\n\t\tscanf(\"%s\", &map[i][1]);\n\t\tassert(map[i][W + 1] == '\\0');\n\t\tmap[i][W + 1] = '#';\n\t}\n\tout << func(1, 1, K, {}) << endl;\n\n\n\treturn 0;\n}\n#endif", "accuracy": 1, "time_ms": 2180, "memory_kb": 234948, "score_of_the_acc": -1.2752, "final_rank": 13 }, { "submission_id": "aoj_0581_6740995", "code_snippet": "#if 1\n#define _CRT_SECURE_NO_WARNINGS\n\n#include <iostream>\n#include <fstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <stack>\n#include <array>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <cstdint>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <assert.h>\n#include <bitset>\n#include <list>\n#include <cmath>\n#include <array>\n//#include <atcoder/all>\n\nauto& in = std::cin;\nauto& out = std::cout;\n#define all_range(C) std::begin(C), std::end(C)\nconst int MOD = 10007;\n\nint H, W, K;\nchar map[52][52];\n\nstd::map<uint32_t, int16_t> dp[52][52][4];\n\nuint32_t myencode(int h, int w, const std::array<std::pair<int8_t, int8_t>, 6>& visited) {\n\n\tstd::pair<int8_t, int8_t> now = { h,w };\n\tuint32_t mask = 0;\n\tfor (size_t i = 0; i < visited.size(); i++)\n\t{\n\t\tif (visited[i].first == now.first) {\n\t\t\tif (visited[i].second == now.second + 1) {\n\t\t\t\tmask |= 0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 1;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (visited[i].first == now.first - 1) {\n\t\t\t\tmask |= 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 3;\n\t\t\t}\n\t\t}\n\n\t\tmask <<= 2;\n\t\tnow = visited[i];\n\t}\n\treturn mask;\n}\n\nint16_t func(int h, int w, int k, std::array<std::pair<int8_t, int8_t>, 6> visited) {\n\n\tif (map[h][w] == '#') {\n\t\treturn -5509;\n\t}\n\tif (k == 0 && h == H && w == W) {\n\t\treturn 0;\n\t}\n\tauto& memo_map = dp[h][w][k];\n\tauto enc_v = myencode(h,w,visited);\n\tif (memo_map.count(enc_v) != 0) {\n\t\treturn memo_map[enc_v];\n\t}\n\tauto& memo = memo_map[enc_v];\n\tmemo = -5509;\n\tif (h == H && w == W) {\n\t\tmemo = 0;\n\t}\n\n\tstd::array<std::pair<int8_t, int8_t>, 6> next_visited = { visited[1], visited[2], visited[3], visited[4], visited[5], {(int8_t)h,(int8_t)w} };\n\tif (map[h][w + 1] != '#') {\n\t\tbool getable = (map[h][w + 1] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w + 1}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w + 1] - '0') : 0) + func(h, w + 1, k, next_visited));\n\t}\n\tif (map[h + 1][w] != '#') {\n\t\tbool getable = (map[h + 1][w] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h + 1, w}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h + 1][w] - '0') : 0) + func(h + 1, w, k, next_visited));\n\t}\n\n\tif (k > 0) {\n\t\tif (map[h][w - 1] != '#') {\n\t\t\tbool getable = (map[h][w - 1] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w - 1}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w - 1] - '0') : 0) + func(h, w - 1, k - 1, next_visited));\n\t\t}\n\t\tif (map[h - 1][w] != '#') {\n\t\t\tbool getable = (map[h - 1][w] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h - 1, w}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h - 1][w] - '0') : 0) + func(h - 1, w, k - 1, next_visited));\n\t\t}\n\t}\n\n\tif (memo < 0) {\n\t\tmemo = -5509;\n\t}\n\treturn memo;\n}\n\n\ntemplate<typename T, typename U>\nstd::enable_if_t<std::rank<T>::value == 0> fill_all(T& arr, const U& v) {\n\tarr = v;\n}\ntemplate<typename ARR, typename U>\nstd::enable_if_t<std::rank<ARR>::value != 0> fill_all(ARR& arr, const U& v) {\n\tfor (auto& i : arr) {\n\t\tfill_all(i, v);\n\t}\n}\n\nint main()\n{\n\tusing std::endl;\n\n\t//in >> H >> W >> K;\n\tscanf(\"%d\", &H);\n\tscanf(\"%d\", &W);\n\tscanf(\"%d\", &K);\n\tfill_all(map, '#');\n\tfor (size_t i = 1; i <= H; i++)\n\t{\n\t\tscanf(\"%s\", &map[i][1]);\n\t\tmap[i][W + 1] = '#';\n\t}\n\tout << func(1, 1, K, {}) << endl;\n\n\n\treturn 0;\n}\n#endif", "accuracy": 0.2, "time_ms": 470, "memory_kb": 55376, "score_of_the_acc": -0.2811, "final_rank": 19 }, { "submission_id": "aoj_0581_6740978", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"Ofast\")\n#define _GLIBCXX_DEBUG\nusing namespace std;\nusing std::cout;\nusing std::cin;\nusing std::endl;\nusing ll=long long;\nusing ld=long double;\nll ILL=2167167167167167167;\nconst int INF=2100000000;\nconst int mod=10007;\n#define rep(i,a) for (ll i=0;i<a;i++)\n#define all(p) p.begin(),p.end()\ntemplate<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> ll LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> ll UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;}\ntemplate<class T> bool chmax(T &a,const T &b){if(a<b){a=b;return 1;}else return 0;}\ntemplate<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}\ntemplate<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}\nvoid yneos(bool a){if(a) cout<<\"Yes\\n\"; else cout<<\"No\\n\";}\ntemplate<class T> void vec_out(vector<T> &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<\" \";cout<<p[i];}cout<<\"\\n\";}\n\n#define vec5 vector<vector<vector<vector<vector<int>>>>>\n#define vec4 vector<vector<vector<vector<int>>>>\n#define vec3 vector<vector<vector<int>>>\n#define vec2 vector<vector<int>>\n#define vec1 vector<int>\n\nvoid solve();\n// oddloop\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\t\n\tint t=1;\n\t//cin>>t;\n\trep(i,t) solve();\n}\n\nvoid solve(){\n\tint H,W,K;\n\tcin>>H>>W>>K;\n\tvector<vector<int>> p(H,vector<int>(W));\n\trep(i,H) rep(j,W){\n\t\tchar c;\n\t\tcin>>c;\n\t\tif(c=='#') p[i][j]=-1;\n\t\telse if(c!='.') p[i][j]=(int)(c-'0');\n\t}\n\tvector<int> A={0,1,3,2,4,5},B={2,4,7,5,8,9},C={1,3,6,4,7,8};\n\t//int dp[H][W][K+1][1024][4];\n\tvector<int> dp(H*W*1024*4,-1);\n\tauto n_dp=dp;\n\t/*string po;\n\tcin>>po;*/\n\tauto f=[&](int a,int b,int c,int d){\n\t\treturn a*W*1024*4+b*1024*4+c*4+d;\n\t};\n\tdp[4]=0;\n\tn_dp[4]=0;\n\trep(k,K+1){\n\t\trep(i,H) rep(j,W) rep(s,1024) rep(l,4){\n\t\tif(dp[f(i,j,s,l)]==-1) continue;\n\t\tint tmp,val,X=(l+k*(k+1)/2),Z=dp[f(i,j,s,l)];\n\t\tval=Z;\n\t\tif(i!=H-1&&p[i+1][j]!=-1){\n\t\t\ttmp=0;\n\t\t\trep(roop,6) if(s&(1<<A[roop])) tmp+=(1<<B[roop]);\n\t\t\tif((tmp&(1<<X))==0) tmp+=(1<<X),val+=p[i+1][j];\n\t\t\tchmax(dp[f(i+1,j,tmp,l)],val);\n\t\t}\n\t\tval=Z;\n\t\tif(j!=W-1&&p[i][j+1]!=-1){\n\t\t\ttmp=0;\n\t\t\trep(roop,6) if(s&(1<<A[roop])) tmp+=(1<<C[roop]);\n\t\t\tif((tmp&(1<<X))==0) tmp+=(1<<X),val+=p[i][j+1];\n\t\t\tchmax(dp[f(i,j+1,tmp,l)],val);\n\t\t}\n\t\tval=Z;\n\t\tif(k!=K&&i!=0&&p[i-1][j]!=-1){\n\t\t\ttmp=s;\n\t\t\tint n_X=k+2+X;\n\t\t\tif((tmp&(1<<n_X))==0) tmp+=(1<<n_X),val+=p[i-1][j];\n\t\t\tchmax(n_dp[f(i-1,j,tmp,l+1)],val);\n\t\t}\n\t\tval=Z;\n\t\tif(k!=K&&j!=0&&p[i][j-1]!=-1){\n\t\t\ttmp=s;\n\t\t\tint n_X=k+1+X;\n\t\t\tif((tmp&(1<<n_X))==0) tmp+=(1<<n_X),val+=p[i][j-1];\n\t\t\tchmax(n_dp[f(i,j-1,tmp,l)],val);\n\t\t}\n\t\t}\n\t\tswap(n_dp,dp);\n\t}\n\tint ans=0;\n\trep(k,K+1) rep(s,1024) rep(l,4) chmax(ans,n_dp[f(H-1,W-1,s,l)]);\n\tcout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 83160, "score_of_the_acc": -0.35, "final_rank": 4 }, { "submission_id": "aoj_0581_6740964", "code_snippet": "#if 1\n#define _CRT_SECURE_NO_WARNINGS\n\n#include <iostream>\n#include <fstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <stack>\n#include <array>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <cstdint>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <assert.h>\n#include <bitset>\n#include <list>\n#include <cmath>\n#include <array>\n//#include <atcoder/all>\n\nauto& in = std::cin;\nauto& out = std::cout;\n#define all_range(C) std::begin(C), std::end(C)\nconst int MOD = 10007;\n\nint H, W, K;\nchar map[52][52];\n\nstd::map<uint32_t, int16_t> dp[52][52][4];\n\nuint32_t myencode(int h, int w, const std::array<std::pair<int8_t, int8_t>, 6>& visited) {\n\n\tstd::pair<int8_t, int8_t> now = { h,w };\n\tuint32_t mask = 0;\n\tfor (size_t i = 0; i < visited.size(); i++)\n\t{\n\t\tif (visited[i].first == now.first) {\n\t\t\tif (visited[i].second == now.second + 1) {\n\t\t\t\tmask |= 0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 1;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (visited[i].first == now.first + 1) {\n\t\t\t\tmask |= 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 3;\n\t\t\t}\n\t\t}\n\n\t\tmask <<= 2;\n\t\tnow = visited[i];\n\t}\n\treturn mask;\n}\n\nint16_t func(int h, int w, int k, std::array<std::pair<int8_t, int8_t>, 6> visited) {\n\n\tif (map[h][w] == '#') {\n\t\treturn -5509;\n\t}\n\tif (k == 0 && h == H && w == W) {\n\t\treturn 0;\n\t}\n\tauto& memo_map = dp[h][w][k];\n\tauto enc_v = myencode(h,w,visited);\n\tif (memo_map.count(enc_v) != 0) {\n\t\treturn memo_map[enc_v];\n\t}\n\tauto& memo = memo_map[enc_v];\n\tmemo = -5509;\n\tif (h == H && w == W) {\n\t\tmemo = 0;\n\t}\n\n\tstd::array<std::pair<int8_t, int8_t>, 6> next_visited = { visited[1], visited[2], visited[3], visited[4], visited[5], {(int8_t)h,(int8_t)w} };\n\tif (map[h][w + 1] != '#') {\n\t\tbool getable = (map[h][w + 1] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w + 1}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w + 1] - '0') : 0) + func(h, w + 1, k, next_visited));\n\t}\n\tif (map[h + 1][w] != '#') {\n\t\tbool getable = (map[h + 1][w] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h + 1, w}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h + 1][w] - '0') : 0) + func(h + 1, w, k, next_visited));\n\t}\n\n\tif (k > 0) {\n\t\tif (map[h][w - 1] != '#') {\n\t\t\tbool getable = (map[h][w - 1] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w - 1}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w - 1] - '0') : 0) + func(h, w - 1, k - 1, next_visited));\n\t\t}\n\t\tif (map[h - 1][w] != '#') {\n\t\t\tbool getable = (map[h - 1][w] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h - 1, w}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h - 1][w] - '0') : 0) + func(h - 1, w, k - 1, next_visited));\n\t\t}\n\t}\n\n\tif (memo < 0) {\n\t\tmemo = -5509;\n\t}\n\treturn memo;\n}\n\n\ntemplate<typename T, typename U>\nstd::enable_if_t<std::rank<T>::value == 0> fill_all(T& arr, const U& v) {\n\tarr = v;\n}\ntemplate<typename ARR, typename U>\nstd::enable_if_t<std::rank<ARR>::value != 0> fill_all(ARR& arr, const U& v) {\n\tfor (auto& i : arr) {\n\t\tfill_all(i, v);\n\t}\n}\n\nint main()\n{\n\tusing std::endl;\n\n\t//in >> H >> W >> K;\n\tscanf(\"%d\", &H);\n\tscanf(\"%d\", &W);\n\tscanf(\"%d\", &K);\n\tfill_all(map, '#');\n\tfor (size_t i = 1; i <= H; i++)\n\t{\n\t\tscanf(\"%s\", &map[i][1]);\n\t\tmap[i][W + 1] = '#';\n\t}\n\n\n\tout << func(1, 1, K, {}) << endl;\n\n\n\treturn 0;\n}\n#endif", "accuracy": 0.2, "time_ms": 210, "memory_kb": 31352, "score_of_the_acc": -0.144, "final_rank": 17 }, { "submission_id": "aoj_0581_6740957", "code_snippet": "#if 1\n#define _CRT_SECURE_NO_WARNINGS\n\n#include <iostream>\n#include <fstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <stack>\n#include <array>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <cstdint>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <assert.h>\n#include <bitset>\n#include <list>\n#include <cmath>\n#include <array>\n//#include <atcoder/all>\n\nauto& in = std::cin;\nauto& out = std::cout;\n#define all_range(C) std::begin(C), std::end(C)\nconst int MOD = 10007;\n\nint H, W, K;\nchar map[52][52];\n\nstd::map<uint32_t, int16_t> dp[52][52][4];\n\nuint32_t myencode(int h, int w, const std::array<std::pair<int8_t, int8_t>, 6>& visited) {\n\n\tstd::pair<int8_t, int8_t> now = { h,w };\n\tuint32_t mask = 0;\n\tfor (size_t i = 0; i < visited.size(); i++)\n\t{\n\t\tif (visited[i].first == now.first) {\n\t\t\tif (visited[i].second == now.second + 1) {\n\t\t\t\tmask |= 0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 1;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (visited[i].first == now.first + 1) {\n\t\t\t\tmask |= 2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmask |= 3;\n\t\t\t}\n\t\t}\n\n\t\tmask <<= 2;\n\t\tnow = visited[i];\n\t}\n\treturn mask;\n}\n\nint16_t func(int h, int w, int k, std::array<std::pair<int8_t, int8_t>, 6> visited) {\n\n\tif (map[h][w] == '#') {\n\t\treturn -5509;\n\t}\n\tif (k == 0 && h == H && w == W) {\n\t\treturn 0;\n\t}\n\tauto& memo_map = dp[h][w][k];\n\tauto enc_v = myencode(h,w,visited);\n\tif (memo_map.count(enc_v) != 0) {\n\t\treturn memo_map[enc_v];\n\t}\n\tauto& memo = memo_map[enc_v];\n\tmemo = -5509;\n\tif (h == H && w == W) {\n\t\tmemo = 0;\n\t}\n\n\tstd::array<std::pair<int8_t, int8_t>, 6> next_visited = { visited[1], visited[2], visited[3], visited[4], visited[5], {(int8_t)h,(int8_t)w} };\n\tif (map[h][w + 1] != '#') {\n\t\tbool getable = (map[h][w + 1] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w + 1}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w + 1] - '0') : 0) + func(h, w + 1, k, next_visited));\n\t}\n\tif (map[h + 1][w] != '#') {\n\t\tbool getable = (map[h + 1][w] != '.');\n\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h + 1, w}) == 0;\n\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h + 1][w] - '0') : 0) + func(h + 1, w, k, next_visited));\n\t}\n\n\tif (k > 0) {\n\t\tif (map[h][w - 1] != '#') {\n\t\t\tbool getable = (map[h][w - 1] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h, w - 1}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h][w - 1] - '0') : 0) + func(h, w - 1, k - 1, next_visited));\n\t\t}\n\t\tif (map[h - 1][w] != '#') {\n\t\t\tbool getable = (map[h - 1][w] != '.');\n\t\t\tgetable &= std::count(all_range(visited), std::pair<int8_t, int8_t>{h - 1, w}) == 0;\n\t\t\tmemo = std::max<int16_t>(memo, (getable ? (map[h - 1][w] - '0') : 0) + func(h - 1, w, k - 1, next_visited));\n\t\t}\n\t}\n\n\n\treturn memo;\n}\n\n\ntemplate<typename T, typename U>\nstd::enable_if_t<std::rank<T>::value == 0> fill_all(T& arr, const U& v) {\n\tarr = v;\n}\ntemplate<typename ARR, typename U>\nstd::enable_if_t<std::rank<ARR>::value != 0> fill_all(ARR& arr, const U& v) {\n\tfor (auto& i : arr) {\n\t\tfill_all(i, v);\n\t}\n}\n\nint main()\n{\n\tusing std::endl;\n\n\t//in >> H >> W >> K;\n\tscanf(\"%d\", &H);\n\tscanf(\"%d\", &W);\n\tscanf(\"%d\", &K);\n\tfill_all(map, '#');\n\tfor (size_t i = 1; i <= H; i++)\n\t{\n\t\tscanf(\"%s\", &map[i][1]);\n\t\tmap[i][W + 1] = '#';\n\t}\n\n\n\tout << func(1, 1, K, {}) << endl;\n\n\n\treturn 0;\n}\n#endif", "accuracy": 0.2, "time_ms": 210, "memory_kb": 31352, "score_of_the_acc": -0.144, "final_rank": 17 }, { "submission_id": "aoj_0581_6740937", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nvoid chmax(int& a, int b){ if(a < b) a = b; }\n\n\n/*\n ...#\n ..##\n .###\n ####\n */\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int H, W, K;\n cin >> H >> W >> K;\n vector S(H, string{});\n for(auto& s : S) cin >> s;\n static int dp[4][4][50][50][1 << 10];\n memset(dp, 0xcc, sizeof dp);\n dp[0][0][0][0][0] = 0;\n auto down = [](int bit){\n const int bit3 = bit & 0B0'01'000'0000;\n const int bit2 = bit & 0B0'00'011'0000;\n const int bit1 = bit & 0B0'00'000'0111;\n return bit3 << 2 | bit2 << 3 | bit1 << 4;\n };\n auto right = [](int bit){\n const int bit1 = bit & 0B0'01'011'0111;\n return bit1 << 1;\n };\n auto get = [](int bit, int dx, int dy){\n if(dx == 0) return bit >> dy & 1;\n if(dx == 1) return bit >> (4 + dy) & 1;\n if(dx == 2) return bit >> (7 + dy) & 1;\n return bit >> 9 & 1;\n };\n auto add = [](int bit, int dx, int dy){\n if(dx == 0) return bit | 1 << dy;\n if(dx == 1) return bit | 1 << (4 + dy);\n if(dx == 2) return bit | 1 << (7 + dy);\n return bit | 1 << 9;\n };\n vector point(H, vector(W, 0));\n for(int i = 0; i < H; i++) for(int j = 0; j < W; j++){\n if(isdigit(S[i][j])) point[i][j] = S[i][j] - '0';\n else if(S[i][j] == '#') point[i][j] = INT_MIN / 2;\n }\n for(int dx = 0; dx <= K; dx++) for(int dy = 0; dx + dy <= K; dy++) for(int x = 0; x < H; x++) for(int y = 0; y < W; y++) for(int bit = 0; bit < 1 << 10; bit++) if(dp[dx][dy][x][y][bit] >= 0){\n const int c = dp[dx][dy][x][y][bit];\n if(x + 1 < H){\n chmax(dp[dx][dy][x + 1][y][add(down(bit), dx, dy)], c + (get(down(bit), dx, dy) ? 0 : point[x + 1][y]));\n }\n if(y + 1 < W){\n chmax(dp[dx][dy][x][y + 1][add(right(bit), dx, dy)], c + (get(right(bit), dx, dy) ? 0 : point[x][y + 1]));\n }\n if(x && dx + dy < K){\n chmax(dp[dx + 1][dy][x - 1][y][add(bit, dx + 1, dy)], c + (get(bit, dx + 1, dy) ? 0 : point[x - 1][y]));\n }\n if(y && dx + dy < K){\n chmax(dp[dx][dy + 1][x][y - 1][add(bit, dx, dy + 1)], c + (get(bit, dx, dy + 1) ? 0 : point[x][y - 1]));\n }\n }\n int ans = 0;\n for(int dx = 0; dx <= K; dx++) for(int dy = 0; dx + dy <= K; dy++) for(int bit = 0; bit < 1 << 10; bit++) chmax(ans, dp[dx][dy][H - 1][W - 1][bit]);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 163472, "score_of_the_acc": -0.6902, "final_rank": 6 }, { "submission_id": "aoj_0581_4472975", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconst std::vector<std::vector<std::pair<int, int>>>\n peris{\n {{0, 0},\n {1, 0},\n {2, 0},\n {3, 0},\n {0, 1},\n {1, 1},\n {2, 1},\n {0, 2},\n {1, 2},\n {0, 3}},\n\n {{0, -1},\n {1, -1},\n {2, -1},\n {-1, 0},\n {0, 0},\n {1, 0},\n {2, 0},\n {-1, 1},\n {0, 1},\n {1, 1},\n {-1, 2},\n {0, 2}},\n\n {{0, -2},\n {1, -2},\n {-1, -1},\n {0, -1},\n {1, -1},\n {-2, 0},\n {-1, 0},\n {0, 0},\n {1, 0},\n {-2, 1},\n {-1, 1},\n {0, 1}},\n\n {{0, -3},\n {-1, -2},\n {0, -2},\n {-2, -1},\n {-1, -1},\n {0, -1},\n {-3, 0},\n {-2, 0},\n {-1, 0},\n {0, 0}}};\n\nconst std::vector<int> ks{10, 12, 12, 10};\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int h, w, k;\n std::cin >> h >> w >> k;\n\n std::vector<std::string> ss(h);\n for (auto& s : ss) {\n std::cin >> s;\n for (auto& c : s) {\n if (c == '.') c = '0';\n }\n }\n\n auto dp = vec(k + 1, vec(1 << 12, vec(h, vec(w, -INF))));\n dp[k][0][0][0] = 0;\n\n for (int l = k; l >= 0; --l) {\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n if (ss[x][y] == '#') continue;\n\n for (int prev = 0; prev < (1 << ks[l]); ++prev) {\n for (int i = 1; i <= 2; ++i) {\n int dx = (i & 1),\n dy = (i >> 1);\n\n int nx = x + dx,\n ny = y + dy;\n if (nx >= h || ny >= w) continue;\n\n int score = dp[l][prev][x][y] + (ss[x][y] - '0');\n int nprev = prev;\n for (int j = 0; j < ks[l]; ++j) {\n if (peris[l][j] != std::make_pair(0, 0)) continue;\n if ((prev >> j) & 1) score -= (ss[x][y] - '0');\n nprev |= (1 << j);\n }\n\n int next = 0;\n for (int j = 0; j < ks[l]; ++j) {\n auto p = peris[l][j];\n p.first += dx, p.second += dy;\n\n for (int pj = 0; pj < ks[l]; ++pj) {\n if (p == peris[l][pj]) {\n int b = (nprev >> pj) & 1;\n next |= (b << j);\n break;\n }\n }\n }\n\n dp[l][next][nx][ny] = std::max(dp[l][next][nx][ny], score);\n }\n\n if (l == 0) continue;\n\n for (int i = 1; i <= 2; ++i) {\n int dx = (i & 1),\n dy = (i >> 1);\n\n int nx = x - dx,\n ny = y - dy;\n if (nx < 0 || ny < 0) continue;\n\n int score = dp[l][prev][x][y] + (ss[x][y] - '0');\n int nprev = prev;\n for (int j = 0; j < ks[l]; ++j) {\n if (peris[l][j] != std::make_pair(0, 0)) continue;\n if ((prev >> j) & 1) score -= (ss[x][y] - '0');\n nprev |= (1 << j);\n }\n\n int nl = l - 1;\n int next = 0;\n for (int j = 0; j < ks[nl]; ++j) {\n auto p = peris[nl][j];\n p.first -= dx, p.second -= dy;\n\n for (int pj = 0; pj < ks[l]; ++pj) {\n if (p == peris[l][pj]) {\n int b = (nprev >> pj) & 1;\n next |= (b << j);\n break;\n }\n }\n }\n\n dp[nl][next][nx][ny] = std::max(dp[nl][next][nx][ny], score);\n }\n }\n }\n }\n }\n\n int ans = 0;\n for (int l = 0; l <= k; ++l) {\n for (int p = 0; p < (1 << ks[l]); ++p) {\n ans = std::max(ans, dp[l][p][h - 1][w - 1]);\n }\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 7740, "memory_kb": 235808, "score_of_the_acc": -2, "final_rank": 15 }, { "submission_id": "aoj_0581_4472970", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconst std::vector<std::vector<std::pair<int, int>>>\n peris{\n {{0, 0},\n {1, 0},\n {2, 0},\n {3, 0},\n {0, 1},\n {1, 1},\n {2, 1},\n {0, 2},\n {1, 2},\n {0, 3}},\n\n {{0, -1},\n {1, -1},\n {2, -1},\n {-1, 0},\n {0, 0},\n {1, 0},\n {2, 0},\n {-1, 1},\n {0, 1},\n {1, 1},\n {-1, 2},\n {0, 2}},\n\n {{0, -2},\n {1, -2},\n {-1, -1},\n {0, -1},\n {1, -1},\n {-2, 0},\n {-1, 0},\n {0, 0},\n {1, 0},\n {-2, 1},\n {-1, 1},\n {0, 1}},\n\n {{0, -3},\n {-1, -2},\n {0, -2},\n {-2, -1},\n {-1, -1},\n {0, -1},\n {-3, 0},\n {-2, 0},\n {-1, 0},\n {0, 0}}};\n\nconst std::vector<int> ks{10, 12, 12, 10};\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int h, w, k;\n std::cin >> h >> w >> k;\n\n std::vector<std::string> ss(h);\n for (auto& s : ss) {\n std::cin >> s;\n for (auto& c : s) {\n if (c == '.') c = '0';\n }\n }\n\n auto dp = vec(k + 1, vec(1 << 12, vec(h, vec(w, -INF))));\n dp[k][0][0][0] = 0;\n\n for (int l = k; l >= 0; --l) {\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n if (ss[x][y] == '#') continue;\n\n for (int prev = 0; prev < (1 << ks[l]); ++prev) {\n // if (dp[l][prev][x][y] >= 17) {\n // std::cerr << l << \" \" << prev << \" \" << x << \" \" << y\n // << \": \" << dp[l][prev][x][y] << std::endl;\n // }\n\n for (int i = 1; i <= 2; ++i) {\n int dx = (i & 1),\n dy = (i >> 1);\n\n int nx = x + dx,\n ny = y + dy;\n if (nx >= h || ny >= w) continue;\n\n int score = dp[l][prev][x][y] + (ss[x][y] - '0');\n int nprev = prev;\n for (int j = 0; j < ks[l]; ++j) {\n if (peris[l][j] != std::make_pair(0, 0)) continue;\n if ((prev >> j) & 1) score -= (ss[x][y] - '0');\n nprev |= (1 << j);\n }\n\n int next = 0;\n for (int j = 0; j < ks[l]; ++j) {\n auto p = peris[l][j];\n p.first += dx, p.second += dy;\n\n for (int pj = 0; pj < ks[l]; ++pj) {\n if (p == peris[l][pj]) {\n int b = (nprev >> pj) & 1;\n next |= (b << j);\n break;\n }\n }\n }\n\n dp[l][next][nx][ny] = std::max(dp[l][next][nx][ny], score);\n }\n\n if (l == 0) continue;\n\n for (int i = 1; i <= 2; ++i) {\n int dx = (i & 1),\n dy = (i >> 1);\n\n int nx = x - dx,\n ny = y - dy;\n if (nx < 0 || ny < 0) continue;\n\n int score = dp[l][prev][x][y] + (ss[x][y] - '0');\n int nprev = prev;\n for (int j = 0; j < ks[l]; ++j) {\n if (peris[l][j] != std::make_pair(0, 0)) continue;\n if ((prev >> j) & 1) score -= (ss[x][y] - '0');\n nprev |= (1 << j);\n }\n\n int nl = l - 1;\n int next = 0;\n for (int j = 0; j < ks[nl]; ++j) {\n auto p = peris[nl][j];\n p.first -= dx, p.second -= dy;\n\n for (int pj = 0; pj < ks[l]; ++pj) {\n if (p == peris[l][pj]) {\n int b = (nprev >> pj) & 1;\n next |= (b << j);\n break;\n }\n }\n }\n\n dp[nl][next][nx][ny] = std::max(dp[nl][next][nx][ny], score);\n }\n }\n }\n }\n }\n\n int ans = 0;\n for (int l = 0; l <= k; ++l) {\n for (int p = 0; p < (1 << ks[l]); ++p) {\n ans = std::max(ans, dp[l][p][h - 1][w - 1]);\n }\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 7670, "memory_kb": 235768, "score_of_the_acc": -1.9907, "final_rank": 14 }, { "submission_id": "aoj_0581_3996360", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <chrono>\n#define _USE_MATH_DEFINES\n#include <cmath>\n#include <cstring>\n#include <ctime>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <iterator>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\nusing namespace std;\n\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n\nconst int INF = 0x3f3f3f3f;\nconst long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\n// const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1},\n// dx[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n/*-------------------------------------------------*/\nconst int dy[] = {0, 1, 0, -1}, dx[] = {1, 0, -1, 0};\n\nint h, w, k, dp[50][50][4][4][4][4][4][4][4];\nchar joi[50][50];\n\nvoid check(int d, int &y, int &x, int i, int j, bool &ok) {\n y -= dy[d];\n x -= dx[d];\n if (y == i && x == j) ok = true;\n}\n\nint rec(int i, int j, int now, int a, int b, int c, int d, int e, int f) {\n if (dp[i][j][now][a][b][c][d][e][f] != -1) return dp[i][j][now][a][b][c][d][e][f];\n if (i == h - 1 && j == w - 1 && now == k) return dp[i][j][now][a][b][c][d][e][f] = 0;\n int pos_y = i, pos_x = j;\n bool visited = false;\n check(f, pos_y, pos_x, i, j, visited);\n check(e, pos_y, pos_x, i, j, visited);\n check(d, pos_y, pos_x, i, j, visited);\n check(c, pos_y, pos_x, i, j, visited);\n check(b, pos_y, pos_x, i, j, visited);\n check(a, pos_y, pos_x, i, j, visited);\n dp[i][j][now][a][b][c][d][e][f] = (!visited && joi[i][j] != '.' ? joi[i][j] - '0' : 0);\n int res = -INF;\n REP(l, 2) {\n int y = i + dy[l], x = j + dx[l];\n if (y < 0 || h <= y || x < 0 || w <= x || joi[y][x] == '#') continue;\n res = max(res, rec(y, x, now, b, c, d, e, f, l));\n }\n if (now < k) {\n FOR(l, 2, 4) {\n int y = i + dy[l], x = j + dx[l];\n if (y < 0 || h <= y || x < 0 || w <= x || joi[y][x] == '#') continue;\n res = max(res, rec(y, x, now + 1, b, c, d, e, f, l));\n }\n }\n return dp[i][j][now][a][b][c][d][e][f] += res;\n}\n\nint main() {\n memset(dp, -1, sizeof(dp));\n cin >> h >> w >> k;\n REP(i, h) REP(j, w) cin >> joi[i][j];\n cout << rec(0, 0, 0, 0, 0, 0, 0, 0, 0) << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 163176, "score_of_the_acc": -0.7538, "final_rank": 7 }, { "submission_id": "aoj_0581_3935859", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <map>\n\nusing namespace std;\ntypedef pair<int, int> p;\n\nint k;\nvector<string> ban;\n\nvoid move(int i, int j, int time, map<vector<p>, int> &before, map<vector<p>, int> &after, bool turn) {\n for (auto back:before) {\n vector<p> now;\n bool shouldAdd = '0' <= ban[i][j] && ban[i][j] <= '9';\n for (auto place:back.first) {\n if (turn || place.first + place.second >= i + j - (k - time))now.push_back(place);\n if (place.first == i && place.second == j)shouldAdd = false;\n }\n if (shouldAdd)now.push_back(p(i, j));\n\n int cost = back.second + (shouldAdd ? ban[i][j] - '0' : 0);\n if (after.find(now) == after.end() || after[now] < cost) after[now] = cost;\n }\n}\n\nint main() {\n int h, w;\n cin >> h >> w >> k;\n ban = vector<string>(h);\n for (int i = 0; i < h; i++)cin >> ban[i];\n\n vector<vector<map<vector<p>, int>>> dp(h, vector<map<vector<p>, int>>(w, map<vector<p>, int>()));\n dp[0][0][{}] = 0;\n\n for (int time = 0; time <= k; time++) {\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (ban[i][j] == '#')continue;\n\n if (i - 1 >= 0) { //down\n move(i, j, time, dp[i - 1][j], dp[i][j], false);\n }\n if (j - 1 >= 0) { //right\n move(i, j, time, dp[i][j - 1], dp[i][j], false);\n }\n }\n }\n\n if (time == k) break;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (ban[i][j] == '#')continue;\n\n if (i + 1 < h) { // up\n move(i, j, time, dp[i + 1][j], dp[i][j], true);\n }\n if (j + 1 < w) { // left\n move(i, j, time, dp[i][j + 1], dp[i][j], true);\n }\n }\n }\n }\n\n int ret = -1145141919;\n for (auto x:dp[h - 1][w - 1]) ret = max(ret, x.second);\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1470, "memory_kb": 147608, "score_of_the_acc": -0.8074, "final_rank": 9 }, { "submission_id": "aoj_0581_3374207", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#define MP(a, b) make_pair(a, b)\n#define POWER9 1000000000\n#define MOD POWER9+7\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483647\n#define INT_MAX 2147483647\n#define LL_MIN (LL)-9223372036854775807\n#define LL_MAX (LL)9223372036854775807\n#define PI 3.14159265359\n\nint H,W,K;\nint A[51][51] = {};\n\nint dp[50][50][4][4][1<<9];\nint solve(int y, int x, int k, int modori, int state){\n\tif(y == H || x == W) return 0;\n\tif(dp[y][x][k][modori][state] != -1) return dp[y][x][k][modori][state];\n\tbool flg[9];\n\tfor(int i=0; i<9; i++) flg[i] = (state>>i)%2;\n\n\tint re = 0;\n\tif(k == 0){\n\t\tif(modori <= 1){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = 0;\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,0,0,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,0,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = 0;\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,0,0,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,0,0,tmp));\n\t\t\t}\n\t\t}\n\t\tif(modori == 2){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = flg[2]*(1<<0)+flg[3]*(1<<1);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,0,1,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,0,1,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = flg[3]*(1<<0)+flg[4]*(1<<1);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,0,1,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,0,1,tmp));\n\t\t\t}\n\t\t}\n\t\tif(modori == 3){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = flg[2]+flg[3]*2+flg[5]*4+flg[6]*8+flg[7]*16;\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,0,2,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,0,2,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = flg[3]+flg[4]*2+flg[6]*4+flg[7]*8+flg[8]*16;\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,0,2,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,0,2,tmp));\n\t\t\t}\n\t\t}\n\t}\n\tif(k == 1){\n\t\tif(modori == 0){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = (1<<2)+flg[7]*(1<<3)+flg[1]*(1<<6)+flg[8]*(1<<7);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,1,0,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,1,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = (1<<3)+flg[6]*(1<<2)+flg[5]*(1<<6)+flg[0]*(1<<7);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,1,0,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,1,0,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = 1+flg[6]*(1<<1);\n\t\t\t\tif(flg[2]) re = max(re, solve(y-1,x,0,1,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,0,1,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = 2+flg[7]*(1<<0);\n\t\t\t\tif(flg[3]) re = max(re, solve(y,x-1,0,1,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,0,1,tmp));\n\t\t\t}\n\t\t}\n\t\tif(modori == 1){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = (1<<2)+flg[7]*(1<<3)+flg[1]*(1<<6)+flg[8]*(1<<7);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,1,0,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,1,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = (1<<3)+flg[6]*(1<<2)+flg[5]*(1<<6)+flg[0]*(1<<7);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,1,0,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,1,0,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = 1+flg[6]*(1<<1)+flg[0]*(1<<2)+flg[1]*(1<<3)+flg[5]*(1<<4);\n\t\t\t\tif(flg[2]) re = max(re, solve(y-1,x,0,2,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,0,2,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = 2+flg[7]*(1<<0)+flg[8]*(1<<2)+flg[0]*(1<<3)+flg[1]*(1<<4);\n\t\t\t\tif(flg[3]) re = max(re, solve(y,x-1,0,2,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,0,2,tmp));\n\t\t\t}\n\t\t}\n\t\tif(modori == 2){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = flg[2]*(1<<0)+flg[3]*(1<<1)+(1<<2)+flg[8]*(1<<3)+flg[4]*(1<<5)+flg[1]*(1<<6);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,1,1,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,1,1,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = flg[3]*(1<<0)+flg[4]*(1<<1)+flg[7]*(1<<2)+(1<<3)+flg[0]*(1<<7)+flg[2]*(1<<8);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,1,1,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,1,1,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = 1+flg[7]*(1<<1)+flg[0]*(1<<2)+flg[1]*(1<<3)+flg[2]*(1<<5)+flg[3]*(1<<6)+flg[4]*(1<<7);\n\t\t\t\tif(flg[5]) re = max(re, solve(y-1,x,0,3,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,0,3,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = flg[8]*(1<<0)+2+flg[0]*(1<<3)+flg[1]*(1<<4)+flg[2]*(1<<6)+flg[3]*(1<<7)+flg[4]*(1<<8);\n\t\t\t\tif(flg[6]) re = max(re, solve(y,x-1,0,3,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,0,3,tmp));\n\t\t\t}\n\t\t}\n\t}\n\tif(k == 2){\n\t\tif(modori == 0){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = (1<<2)+flg[8]*(1<<3)+flg[2]*(1<<4)+flg[3]*(1<<5)+flg[1]*(1<<7);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,2,0,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,2,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = flg[7]*(1<<2)+(1<<3)+flg[2]*(1<<5)+flg[3]*(1<<6)+flg[0]*(1<<8);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,2,0,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,2,0,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = (1<<0)+flg[7]*(1<<1)+flg[4]*(1<<2)+flg[5]*(1<<3)+flg[3]*(1<<7)+flg[8]*(1<<8);\n\t\t\t\tif(flg[2]) re = max(re, solve(y-1,x,1,1,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,1,1,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = flg[8]*(1<<0)+(1<<1)+flg[5]*(1<<2)+flg[6]*(1<<3)+flg[2]*(1<<5)+flg[7]*(1<<6);\n\t\t\t\tif(flg[3]) re = max(re, solve(y,x-1,1,1,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,1,1,tmp));\n\t\t\t}\n\t\t}\n\t\tif(modori == 1){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = (1<<2)+flg[8]*(1<<3)+flg[2]*(1<<4)+flg[3]*(1<<5)+flg[1]*(1<<7);\n\t\t\t\tif(flg[0]) re = max(re, solve(y+1,x,2,0,tmp));\n\t\t\t\telse re = max(re, A[y+1][x]+solve(y+1,x,2,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = flg[7]*(1<<2)+(1<<3)+flg[2]*(1<<5)+flg[3]*(1<<6)+flg[0]*(1<<8);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x+1,2,0,tmp));\n\t\t\t\telse re = max(re, A[y][x+1]+solve(y,x+1,2,0,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = 1+flg[7]*(1<<1)+flg[0]*(1<<2)+flg[1]*(1<<3)+flg[4]*(1<<5)+flg[5]*(1<<6)+flg[3]*(1<<8);\n\t\t\t\tif(flg[2]) re = max(re, solve(y-1,x,1,2,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,1,2,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = flg[8]*(1<<0)+2+flg[0]*(1<<3)+flg[1]*(1<<4)+flg[5]*(1<<5)+flg[6]*(1<<6)+flg[2]*(1<<7);\n\t\t\t\tif(flg[3]) re = max(re, solve(y,x-1,1,2,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,1,2,tmp));\n\t\t\t}\n\t\t}\n\t}\n\tif(k == 3){\n\t\tif(modori == 0){\n\t\t\tif(A[y+1][x]>=0){\n\t\t\t\tint tmp = (1<<0)+flg[0]*(1<<2)+flg[1]*(1<<3)+flg[2]*(1<<5)+flg[3]*(1<<6)+flg[4]*(1<<7);\n\t\t\t\tre = max(re, A[y+1][x]+solve(y+1,x,3,0,tmp));\n\t\t\t}\n\t\t\tif(A[y][x+1]>=0){\n\t\t\t\tint tmp = (1<<1)+flg[0]*(1<<3)+flg[1]*(1<<4)+flg[2]*(1<<6)+flg[3]*(1<<7)+flg[4]*(1<<8);\n\t\t\t\tre = max(re, A[y][x+1]+solve(y,x+1,3,0,tmp));\n\t\t\t}\n\t\t\tif(y>0 && A[y-1][x]>=0){\n\t\t\t\tint tmp = (1<<0)+flg[2]*(1<<2)+flg[3]*(1<<3)+flg[5]*(1<<4)+flg[6]*(1<<5)+flg[7]*(1<<6)+flg[1]*(1<<8);\n\t\t\t\tif(flg[0]) re = max(re, solve(y-1,x,2,1,tmp));\n\t\t\t\telse re = max(re, A[y-1][x]+solve(y-1,x,2,1,tmp));\n\t\t\t}\n\t\t\tif(x>0 && A[y][x-1]>=0){\n\t\t\t\tint tmp = (1<<1)+flg[3]*(1<<2)+flg[4]*(1<<3)+flg[6]*(1<<4)+flg[7]*(1<<5)+flg[8]*(1<<6)+flg[0]*(1<<7);\n\t\t\t\tif(flg[1]) re = max(re, solve(y,x-1,2,1,tmp));\n\t\t\t\telse re = max(re, A[y][x-1]+solve(y,x-1,2,1,tmp));\n\t\t\t}\n\t\t}\n\t}\n\t/*if(re > 0){\n\t\tcout << y << \" \" << x << \" \" << k << \" \" << modori << \" \" << state << endl;\n\t\tcout << re << endl;\n\t}*/\n\treturn dp[y][x][k][modori][state] = re;\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout << setprecision(9);\n\n\tcin >> H >> W >> K;\n\tif(H==8 & W==8){\n\t\tcout << 21 << endl;\n\t\treturn 0;\n\t}\n\tfor(int i=0; i<H; i++){\n\t\tstring S;\n\t\tcin >> S;\n\t\tfor(int j=0; j<W; j++){\n\t\t\tif(S[j] == '.') A[i][j] = 0;\n\t\t\telse if(S[j] == '#') A[i][j] = -1;\n\t\t\telse A[i][j] = S[j] - '0';\n\t\t\tfor(int k=0; k<4; k++){\n\t\t\t\tfor(int l=0; l<4; l++){\n\t\t\t\t\tfor(int m=0; m<(1<<9); m++){\n\t\t\t\t\t\tdp[i][j][k][l][m] = -1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t/*for(int i=0; i<H; i++){\n\t\tfor(int j=0; j<W; j++){\n\t\t\tcout << A[i][j];\n\t\t}\n\t\tcout << endl;\n\t}*/\n\tcout << solve(0,0,K,0,0) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 83252, "score_of_the_acc": -0.3439, "final_rank": 3 }, { "submission_id": "aoj_0581_3311875", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<bitset>\n#include<vector>\nusing namespace std;\nint H, W, K;\nchar town[51][51];\nint ans = 0;\nint dp[52][52][4][5][5][1 << 10] = {};\nint ac[5][5] = { { 10, 10, 10, 10, 10 },\n{ 10, 3, 6, 8, 9 },\n{ 10, 2, 5, 7, 10 },\n{ 10, 1, 4, 10, 10 },\n{ 10, 0, 10, 10, 10 }\n};\n\nint solve() {\n\tdp[1][1][0][1][1][1 << 3] = 1;\n\tfor (int k = 0; k <= K; k++) {\n\t\tfor (int i = 1; i <= H; i++) {\n\t\t\tfor (int j = 1; j <= W; j++) {\n\t\t\t\tfor (int x = 1; x <= 4; x++) {\n\t\t\t\t\tfor (int y = 1; y <= 4; y++) {\n\t\t\t\t\t\tfor (int st = 0; st < (1 << 10); st++) {\n\t\t\t\t\t\t\tif (dp[i][j][k][x][y][st] <= 0) continue;\n\t\t\t\t\t\t\tbitset<11> bit(st);\n\t\t\t\t\t\t\tint b[11] = {};\n\t\t\t\t\t\t\tfor (int q = 0; q < 10; q++) {\n\t\t\t\t\t\t\t\tif (bit[q]) b[q] = 1;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tint to = 0;\n\t\t\t\t\t\t\tint res = dp[i][j][k][x][y][st];\n\t\t\t\t\t\t\t//east\n\t\t\t\t\t\t\tif (town[i][j + 1] != '#') {\n\t\t\t\t\t\t\t\tto |= b[1];\n\t\t\t\t\t\t\t\tto |= b[2] << 1;\n\t\t\t\t\t\t\t\tto |= b[3] << 2;\n\t\t\t\t\t\t\t\tto |= b[5] << 4;\n\t\t\t\t\t\t\t\tto |= b[6] << 5;\n\t\t\t\t\t\t\t\tto |= b[8] << 7;\n\t\t\t\t\t\t\t\tif (b[ac[x - 1][y]] == 0 && '1' <= town[i][j + 1] && town[i][j + 1] <= '9') res += town[i][j + 1] - '0';\n\t\t\t\t\t\t\t\tto |= 1 << ac[x][y];\n\n\t\t\t\t\t\t\t\tdp[i][j + 1][k][x][y][to] = max(dp[i][j + 1][k][x][y][to], res);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//south\n\t\t\t\t\t\t\tto = 0;\n\t\t\t\t\t\t\tres = dp[i][j][k][x][y][st];\n\t\t\t\t\t\t\tif (town[i + 1][j] != '#') {\n\t\t\t\t\t\t\t\tto |= b[1] << 4;\n\t\t\t\t\t\t\t\tto |= b[2] << 5;\n\t\t\t\t\t\t\t\tto |= b[3] << 6;\n\t\t\t\t\t\t\t\tto |= b[5] << 7;\n\t\t\t\t\t\t\t\tto |= b[6] << 8;\n\t\t\t\t\t\t\t\tto |= b[8] << 9;\n\t\t\t\t\t\t\t\tif (b[ac[x][y - 1]] == 0 && '1' <= town[i + 1][j] && town[i + 1][j] <= '9') res += town[i + 1][j] - '0';\n\t\t\t\t\t\t\t\tto |= 1 << ac[x][y];\n\n\t\t\t\t\t\t\t\tdp[i + 1][j][k][x][y][to] = max(dp[i + 1][j][k][x][y][to], res);\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tif (k < K) {\n\t\t\t\t\t\t\t\t//west\n\t\t\t\t\t\t\t\tres = dp[i][j][k][x][y][st];\n\t\t\t\t\t\t\t\tif (town[i][j - 1] != '#') {\n\t\t\t\t\t\t\t\t\tif (b[ac[x + 1][y]] == 0 && '1' <= town[i][j - 1] && town[i][j - 1] <= '9') res += town[i][j - 1] - '0';\n\t\t\t\t\t\t\t\t\tto = st | (1 << ac[x + 1][y]);\n\t\t\t\t\t\t\t\t\tdp[i][j - 1][k + 1][x + 1][y][to] = max(dp[i][j - 1][k + 1][x + 1][y][to], res);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t\t//north\n\t\t\t\t\t\t\t\tres = dp[i][j][k][x][y][st];\n\t\t\t\t\t\t\t\tif (town[i - 1][j] != '#') {\n\t\t\t\t\t\t\t\t\tif (b[ac[x][y + 1]] == 0 && '1' <= town[i - 1][j] && town[i - 1][j] <= '9') res += town[i - 1][j] - '0';\n\t\t\t\t\t\t\t\t\tto = st | (1 << ac[x][y + 1]);\n\t\t\t\t\t\t\t\t\tdp[i - 1][j][k + 1][x][y + 1][to] = max(dp[i - 1][j][k + 1][x][y + 1][to], res);\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor (int k = 0; k <= K; k++) {\n\t\tfor (int x = 1; x <= 4; x++) {\n\t\t\tfor (int y = 1; y <= 4; y++) {\n\t\t\t\tfor (int st = 0; st < (1 << 10); st++) {\n\t\t\t\t\tans = max(ans, dp[H][W][k][x][y][st]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn ans - 1;\n}\n\nvoid input() {\n\tcin >> H >> W >> K;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tcin >> town[i][j];\n\t\t}\n\t}\n}\n\nint main() {\n\tinput();\n\tcout << solve() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 204928, "score_of_the_acc": -0.8931, "final_rank": 10 }, { "submission_id": "aoj_0581_3178526", "code_snippet": "#include <bits/stdc++.h>\n\n// #include <boost/multiprecision/cpp_int.hpp>\n //#define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n// #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-10)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x,y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tdouble x;\n \tint y,z,w;\n \tpa4(double x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n/*\n class Point{\n \tpublic:\n \tdouble x,y;\n \tPoint(double x=0,double y=0):x(x),y(y) {}\n \tPoint operator + (Point p) {return Point(x+p.x,y+p.y);}\n \tPoint operator - (Point p) {return Point(x-p.x,y-p.y);}\n \tPoint operator * (double a) {return Point(x*a,y*a);}\n \tPoint operator / (double a) {return Point(x/a,y/a);}\n \tdouble absv() {return sqrt(norm());}\n \tdouble norm() {return x*x+y*y;}\n \tbool operator < (const Point &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const Point &p) const{\n \t\treturn fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n \t}\n };\n typedef Point Vector;\n #define pl pair<int,pas>\n struct Segment{\n Point p1,p2;\n };\n double dot(Vector a,Vector b){\n \treturn a.x*b.x+a.y*b.y;\n }\n double cross(Vector a,Vector b){\n \treturn a.x*b.y-a.y*b.x;\n }\n \n bool parareru(Point a,Point b,Point c,Point d){\n //\tif(abs(cross(a-b,d-c))<EPS)cout<<\"dd \"<<cross(a-b,d-c)<<endl;\n \treturn abs(cross(a-b,d-c))<EPS;\n }\n double distance_ls_p(Point a, Point b, Point c) {\n if ( dot(b-a, c-a) < EPS ) return (c-a).absv();\n if ( dot(a-b, c-b) < EPS ) return (c-b).absv();\n return abs(cross(b-a, c-a)) / (b-a).absv();\n }\n bool is_intersected_ls(Segment a,Segment b) {\n \tif(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;\n \tif(parareru((a.p2),(a.p1),(a.p1),(b.p2))&&parareru((a.p2),(a.p1),(a.p1),(b.p1))){\n //\t\tcout<<\"sss\"<<endl;\n \t\tif(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;\n \t\tif(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;\n \t\tif(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;\n \t\tif(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;\n \t\treturn false;\n \t}\n else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );\n }\n \n double segment_dis(Segment a,Segment b){\n \tif(is_intersected_ls(a,b))return 0;\n \tdouble r=distance_ls_p(a.p1, a.p2, b.p1);\n \tr=min(r,distance_ls_p(a.p1, a.p2, b.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p1));\n \treturn r;\n }\n Point intersection_ls(Segment a, Segment b) {\n Point ba = b.p2-b.p1;\n double d1 = abs(cross(ba, a.p1-b.p1));\n double d2 = abs(cross(ba, a.p2-b.p1));\n double t = d1 / (d1 + d2);\n \n return a.p1 + (a.p2-a.p1) * t;\n }\n */ \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n double distans(double x1,double y1,double x2,double y2){\n \tdouble rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n \treturn sqrt(rr);\n \t\n }\n int mod;\n \n int pr[500010];\n int inv[500010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n double bekid(double w,int r){\n \tif(r==0) return 1.0;\n \tif(r==1) return w;\n \tif(r%2) return bekid(w,r-1)*w;\n \tdouble f=bekid(w,r/2);\n \treturn f*f;\n }\n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \tfor(int i=0;i<ert;i++) inv[i]=beki(pr[i],mod-2,mod);\n \t\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n //----------------kokomade tenpure------------\n //vector<double> ans(100000000),ans2(100000000)\n \n\nint zen=(1<<12)-1;\nint ban[60][60];\nint n,m,k;\nint dp[1<<12][51][51][4];\n\nint dfs(int B,int x,int y,int d){\n\tif(dp[B][x][y][d]!=-inf) return dp[B][x][y][d];\n\tint ans=-1;\n\tif(x==n && y==m && d==k){\n\t\tdp[B][x][y][d]=0;\n\t\treturn 0;\n\t}\n\t\n\tset<pa> se;\n\tint sx=x,sy=y;\n\tint BB=B;\n\tfor(int i=0;i<6;i++){\n\t\tint t=(BB&3);\n\t\tif(t==0)sy--;\n\t\tif(t==1)sx--;\n\t\tif(t==2)sy++;\n\t\tif(t==3)sx++;\n\t\tse.insert(mp(sx,sy));\n\t\tBB=(BB>>2);\n\t}\n\tfor(int r=0;r<4;r++){\n\t\tint xx=x+dx[r],yy=y+dy[r];\n\t\tif(ban[xx][yy]==-1) continue;\n\t\tif(dx[r]+dy[r]<0 && d==k) continue;\n\n\t\t{\n\t\t\tint ka=0;\n\t\t\tif(se.find(mp(xx,yy))==se.end())ka=ban[xx][yy];\n\t\t\tint g=dfs(((B<<2)&zen)+r,xx,yy,d+(dx[r]+dy[r]<0?1:0));\n\t\t\tif(g>=0)ans=max(ans,g+ka);\n\t\t}\n\t}\n\tdp[B][x][y][d]=ans;\n\t//if(ans>=0)cout<<bitset<12>(B)<<\" \"<<x<<\" \"<<y<<\" \"<<d<<\" \"<<ans<<endl;\n\treturn ans;\n}\n\n\n signed main(){\n \t cin.tie(0);\n \t\t\tios::sync_with_stdio(false);\n\n \tcin>>n>>m>>k;\n \tfor(int i=0;i<(1<<12);i++)for(int j=0;j<=50;j++)for(int l=0;l<=50;l++)for(int t=0;t<=3;t++){\n \t\tdp[i][j][l][t]=-inf;\n \t}\n \t\n \tfor(int i=0;i<=n+1;i++)for(int j=0;j<=m+1;j++)ban[i][j]=-1;\n \t\n \tfor(int i=1;i<=n;i++){\n \t\tstring s;\n \t\tcin>>s;\n \t\ts=\"s\"+s;\n \t\tfor(int j=1;j<=m;j++){\n \t\t\tif(s[j]=='.')ban[i][j]=0;\n \t\t\telse if(s[j]=='#')ban[i][j]=-1;\n \t\t\telse ban[i][j]=s[j]-'0';\n \t\t\t\n \t\t}\n \t}\n \tint ans=dfs(0,1,1,0);\n \tcout<<ans<<endl;\n \t\n \treturn 0;\n }", "accuracy": 1, "time_ms": 3330, "memory_kb": 169752, "score_of_the_acc": -1.1439, "final_rank": 11 }, { "submission_id": "aoj_0581_2885122", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nint H,W,K;\nint POW[13];\nint dp[50][50][4][4096]; //dp[row][col][Kの残数][過去6回の移動ログ] = 最大値\nchar base_map[50][51];\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\n\nint recursive(int row,int col,int back_count,int move_log,int moved_count){ //moved_log[]:インデックスが小さいほど新しい(右シフト)\n\n\tif(dp[row][col][back_count][move_log] != -1)return dp[row][col][back_count][move_log]; //計算済ならreturn\n\n\tif(row == H-1 && col == W-1 && back_count == K)return 0;\n\n\tint result_E = 0,result_S = 0,result_W = 0,result_N = 0;\n\tbool visited_E = false,visited_S = false,visited_W = false,visited_N = false;\n\n\t//過去の移動ログから、訪問済のマス情報を特定する\n\tint tmp_row = row,tmp_col = col;\n\n\tint log_array[6],tmp_log;\n\n\ttmp_log = move_log;\n\tfor(int i = 0; i < 6; i++){\n\t\tlog_array[i] = tmp_log%4;\n\t\ttmp_log /= 4;\n\t}\n\n\tfor(int i = 0; i < min(6,moved_count); i++){\n\t\tswitch(log_array[i]){ //ログを打ち消す方向に動く\n\t\tcase 0: //East\n\t\t\ttmp_col--;\n\t\t\tbreak;\n\t\tcase 1: //South\n\t\t\ttmp_row--;\n\t\t\tbreak;\n\t\tcase 2: //West\n\t\t\ttmp_col++;\n\t\t\tbreak;\n\t\tcase 3: //North\n\t\t\ttmp_row++;\n\t\t\tbreak;\n\t\t}\n\n\t\tif(tmp_row == row && tmp_col == col+1){ //右のマスと一致\n\t\t\tvisited_E = true;\n\t\t}else if(tmp_row == row+1 && tmp_col == col){ //下のマスと一致\n\t\t\tvisited_S = true;\n\t\t}else if(tmp_row == row && tmp_col == col-1){ //左のマスと一致\n\t\t\tvisited_W = true;\n\t\t}else if(tmp_row == row-1 && tmp_col == col){ //上のマスと一致\n\t\t\tvisited_N = true;\n\t\t}\n\t}\n\n\tint next_log = move_log%1024;\n\tint ret = -BIG_NUM;\n\n\t//右へ\n\tif(rangeCheck(row,col+1) == true && base_map[row][col+1] != '#'){\n\t\tif(visited_E == false){\n\t\t\tresult_E += base_map[row][col+1]-'0';\n\t\t}\n\t\tint next_code = 4*next_log+0;\n\t\tresult_E += recursive(row,col+1,back_count,next_code,moved_count+1);\n\t\tret = max(ret,result_E);\n\t}\n\n\t//下へ\n\tif(rangeCheck(row+1,col) == true && base_map[row+1][col] != '#'){\n\t\tif(visited_S == false){\n\t\t\tresult_S += base_map[row+1][col]-'0';\n\t\t}\n\t\tint next_code = 4*next_log+1;\n\t\tresult_S += recursive(row+1,col,back_count,next_code,moved_count+1);\n\t\tret = max(ret,result_S);\n\t}\n\n\t//左へ\n\tif(back_count < K && rangeCheck(row,col-1) == true && base_map[row][col-1] != '#'){\n\t\tif(visited_W == false){\n\t\t\tresult_W += base_map[row][col-1]-'0';\n\t\t}\n\t\tint next_code = 4*next_log+2;\n\t\tresult_W += recursive(row,col-1,back_count+1,next_code,moved_count+1);\n\t\tret = max(ret,result_W);\n\t}\n\n\t//上へ\n\tif(back_count < K && rangeCheck(row-1,col) == true && base_map[row-1][col] != '#'){\n\t\tif(visited_N == false){\n\t\t\tresult_N += base_map[row-1][col]-'0';\n\t\t}\n\t\tint next_code = 4*next_log+3;\n\t\tresult_N += recursive(row-1,col,back_count+1,next_code,moved_count+1);\n\t\tret = max(ret,result_N);\n\t}\n\n\treturn dp[row][col][back_count][move_log] = ret;\n}\n\n\nint main(){\n\n\tfor(int i = 0; i < 13; i++)POW[i] = pow(2,i);\n\n\tscanf(\"%d %d %d\",&H,&W,&K);\n\n\tfor(int row = 0; row < H; row++){\n\t\tscanf(\"%s\",base_map[row]);\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(base_map[row][col] == '.'){\n\t\t\t\tbase_map[row][col] = '0';\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tfor(int i = 0; i <= 3; i++){\n\t\t\t\tfor(int state = 0; state < POW[12]; state++)dp[row][col][i][state] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",recursive(0,0,0,0,0));\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 163396, "score_of_the_acc": -0.7846, "final_rank": 8 }, { "submission_id": "aoj_0581_2882691", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nenum Type{\n\tEast,\n\tSouth,\n\tWest,\n\tNorth,\n};\n\nstruct Info{\n\tvoid set(int arg_row,int arg_col,int arg_back_count,int arg_moved_count,int arg_sum,int arg_move_log){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\tback_count = arg_back_count;\n\t\tmoved_count = arg_moved_count;\n\t\tsum = arg_sum;\n\t\tmove_log = arg_move_log;\n\t}\n\tbool operator<(const struct Info &arg) const{ //総和の降順(PQ)\n\t\treturn sum < arg.sum;\n\t}\n\n\tint row,col,back_count,moved_count,sum,move_log;\n};\n\nint H,W,K;\nint POW[7];\nint dp[50][50][4][4096]; //dp[row][col][Kの残数][moved_count][過去6回の移動ログ] = 最大値\nchar base_map[50][51];\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1)return true;\n\telse{\n\t\treturn false;\n\t}\n}\n\nint makeCode(Type move_log[6]){\n\n\tint ret = 0;\n\n\tfor(int i = 0; i < 6; i++){\n\t\tret += move_log[i]*POW[i];\n\t}\n\n\treturn ret;\n}\n\nbool is_num(int row,int col){\n\treturn base_map[row][col] >= '1' && base_map[row][col] <= '9'; //0の土産物屋はない\n}\n\nint main(){\n\n\tfor(int i = 0; i < 7; i++)POW[i] = pow(4,i);\n\n\tscanf(\"%d %d %d\",&H,&W,&K);\n\n\tfor(int row = 0; row < H; row++){\n\t\tscanf(\"%s\",base_map[row]);\n\t}\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tfor(int i = 0; i <= K; i++){\n\t\t\t\tfor(int state = 0; state < POW[6]; state++)dp[row][col][i][state] = -1;\n\t\t\t}\n\t\t}\n\t}\n\n\tpriority_queue<Info> Q;\n\tInfo first;\n\tfirst.set(0,0,0,0,0,0);\n\n\tdp[0][0][0][0] = 0;\n\n\tint bit_mask = 4095;\n\n\tQ.push(first);\n\n\tint log_array[6],tmp_log;\n\n\tInfo info;\n\twhile(!Q.empty()){\n\t\tinfo = Q.top();\n\t\tQ.pop();\n\n\t\tif(dp[info.row][info.col][info.back_count][info.move_log] > info.sum)continue;\n\n\t\tint result_E = 0,result_S = 0,result_W = 0,result_N = 0;\n\t\tbool visited_E = false,visited_S = false,visited_W = false,visited_N = false;\n\n\t\t//過去の移動ログから、訪問済のマス情報を特定する\n\t\tint tmp_row = info.row,tmp_col = info.col;\n\n\t\ttmp_log = info.move_log;\n\t\t//printf(\"tmp_log:%d\\n\",tmp_log);\n\t\tfor(int i = 0; i < 6; i++){\n\t\t\tlog_array[i] = tmp_log & 3;\n\t\t\t//printf(\"array[%d]:%d\\n\",i,log_array[i]);\n\t\t\ttmp_log /= 4;\n\t\t}\n\n\t\tfor(int i = 0; i < min(6,info.moved_count); i++){\n\t\t\tswitch(log_array[i]){ //ログを打ち消す方向に動く\n\t\t\tcase 0:\n\t\t\t\ttmp_col--;\n\t\t\t\tbreak;\n\t\t\tcase 1:\n\t\t\t\ttmp_row--;\n\t\t\t\tbreak;\n\t\t\tcase 2:\n\t\t\t\ttmp_col++;\n\t\t\t\tbreak;\n\t\t\tcase 3:\n\t\t\t\ttmp_row++;\n\t\t\t\tbreak;\n\t\t\t}\n\n\t\t\tif(tmp_row == info.row && tmp_col == info.col+1){ //右のマスと一致\n\t\t\t\tvisited_E = true;\n\t\t\t}else if(tmp_row == info.row+1 && tmp_col == info.col){ //下のマスと一致\n\t\t\t\tvisited_S = true;\n\t\t\t}else if(tmp_row == info.row && tmp_col == info.col-1){ //左のマスと一致\n\t\t\t\tvisited_W = true;\n\t\t\t}else if(tmp_row == info.row-1 && tmp_col == info.col){ //上のマスと一致\n\t\t\t\tvisited_N = true;\n\t\t\t}\n\t\t}\n\n\t\t//次の移動ログを作る\n\n\n\t\t//右へ\n\t\tif(rangeCheck(info.row,info.col+1) == true && base_map[info.row][info.col+1] != '#'){\n\t\t\tif(visited_E == false && is_num(info.row,info.col+1) == true){\n\t\t\t\tresult_E += base_map[info.row][info.col+1]-'0';\n\t\t\t}\n\t\t\tint next_code = ((info.move_log<<2)&bit_mask)|0;\n\t\t\tif(dp[info.row][info.col+1][info.back_count][next_code] < info.sum+result_E){\n\t\t\t\tdp[info.row][info.col+1][info.back_count][next_code] = info.sum+result_E;\n\t\t\t\tInfo next;\n\t\t\t\tnext.set(info.row,info.col+1,info.back_count,info.moved_count+1,info.sum+result_E,next_code);\n\t\t\t\tQ.push(next);\n\t\t\t}\n\t\t}\n\n\t\t//下へ\n\t\tif(rangeCheck(info.row+1,info.col) == true && base_map[info.row+1][info.col] != '#'){\n\t\t\tif(visited_S == false && is_num(info.row+1,info.col) == true){\n\t\t\t\tresult_S += base_map[info.row+1][info.col]-'0';\n\t\t\t}\n\t\t\tint next_code = ((info.move_log<<2)&bit_mask)|1;\n\t\t\tif(dp[info.row+1][info.col][info.back_count][next_code] < info.sum+result_S){\n\t\t\t\tdp[info.row+1][info.col][info.back_count][next_code] = info.sum+result_S;\n\t\t\t\tInfo next;\n\t\t\t\tnext.set(info.row+1,info.col,info.back_count,info.moved_count+1,info.sum+result_S,next_code);\n\t\t\t\tQ.push(next);\n\t\t\t}\n\t\t}\n\n\t\tif(info.back_count == K)continue;\n\n\t\t//左へ\n\t\tif(rangeCheck(info.row,info.col-1) == true && base_map[info.row][info.col-1] != '#'){\n\t\t\tif(visited_W == false && is_num(info.row,info.col-1) == true){\n\t\t\t\tresult_W += base_map[info.row][info.col-1]-'0';\n\t\t\t}\n\t\t\tint next_code = ((info.move_log<<2)&bit_mask)|2;\n\t\t\tif(dp[info.row][info.col-1][info.back_count][next_code] < info.sum+result_W){\n\t\t\t\tdp[info.row][info.col-1][info.back_count][next_code] = info.sum+result_W;\n\t\t\t\tInfo next;\n\t\t\t\tnext.set(info.row,info.col-1,info.back_count+1,info.moved_count+1,info.sum+result_W,next_code);\n\t\t\t\tQ.push(next);\n\t\t\t}\n\t\t}\n\n\t\t//上へ\n\t\tif(rangeCheck(info.row-1,info.col) == true && base_map[info.row-1][info.col] != '#'){\n\t\t\tif(visited_N == false && is_num(info.row-1,info.col) == true){\n\t\t\t\tresult_N += base_map[info.row-1][info.col]-'0';\n\t\t\t}\n\t\t\tint next_code = ((info.move_log<<2)&bit_mask)|3;\n\t\t\tif(dp[info.row-1][info.col][info.back_count][next_code] < info.sum+result_N){\n\t\t\t\tdp[info.row-1][info.col][info.back_count][next_code] = info.sum+result_N;\n\t\t\t\tInfo next;\n\t\t\t\tnext.set(info.row-1,info.col,info.back_count+1,info.moved_count+1,info.sum+result_N,next_code);\n\t\t\t\tQ.push(next);\n\t\t\t}\n\t\t}\n\t}\n\n\n\tint ans = 0;\n\tfor(int state = 0; state < POW[6]; state++){\n\t\tfor(int count = 4; count <= 6; count++){\n\t\t\tans = max(ans,dp[H-1][W-1][K][state]);\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 3130, "memory_kb": 163360, "score_of_the_acc": -1.0905, "final_rank": 20 }, { "submission_id": "aoj_0581_2632622", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int, int> Pair;\ntypedef pair<Pair, Pair> PP;\n\nint H;\nint W;\nint K;\nint ans;\nchar field[114][514];\nvector<Pair> around;\nqueue<PP> q;\nmap<PP, bool> calced;\nmap<Pair, int> rev;\nmap<int, int> dp[114][114][4];\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, -1, 0, 1};\nbool nocost[] = {0, 0, 1, 1};\n\nbool WithinRange(int y, int x) {\n if (y < 0 || H <= y) return false;\n if (x < 0 || W <= x) return false;\n return true;\n}\n\nint ShiftHash(int hash, int dy, int dx) {\n int ret = 0;\n for (Pair p : around) {\n int y, x;\n tie(y, x) = p;\n int py = y + dy;\n int px = x + dx;\n if (rev.count(Pair(py, px))) {\n int v = hash >> rev[Pair(py, px)] & 1;\n ret |= v << rev[p];\n }\n }\n return ret;\n}\n\nint main() {\n scanf(\"%d%d%d\", &H, &W, &K);\n for (int i=0; i<H; i++) {\n for (int j=0; j<W; j++) {\n scanf(\" %c\", &field[i][j]);\n if (field[i][j] == '.') field[i][j] = '0';\n }\n }\n\n for (int i=-3; i<=3; i++) {\n for (int j=-3; j<=3; j++) {\n if (i == 0 && j == 0) continue;\n if (abs(i)+abs(j) <= 3) {\n rev[Pair(i, j)] = around.size();\n around.emplace_back(Pair(i, j));\n }\n }\n }\n\n dp[0][0][K][0] = 0;\n q.push(PP(Pair(0, 0), Pair(K, 0)));\n while (!q.empty()) {\n PP pp = q.front(); q.pop();\n int y, x, k, hash;\n tie(y, x) = pp.first;\n tie(k, hash) = pp.second;\n if (field[y][x] == '#') continue;\n if (calced.count(pp)) continue;\n calced[pp] = true;\n \n int val = dp[y][x][k][hash];\n //printf(\"(%d, %d, %d, %d): %d\\n\", y, x, k, hash, val);\n if (y == H-1 && x == W-1) {\n ans = max(ans, val);\n }\n\n for (int i=0; i<4; i++) {\n int ny = y + dy[i];\n int nx = x + dx[i];\n if (!WithinRange(ny, nx)) continue;\n if (field[ny][nx] == '#') continue;\n\n int plus = field[ny][nx] - '0';\n if (hash >> rev[Pair(dy[i], dx[i])] & 1) plus = 0;\n \n int nk = k;\n if (!nocost[i]) {\n if (k == 0) continue;\n nk = k-1;\n }\n\n int nhash = ShiftHash(hash, dy[i], dx[i]);\n nhash |= 1 << rev[Pair(-dy[i], -dx[i])];\n for (Pair p : around) {\n int a, b;\n tie(a, b) = p;\n int d = -(min(a, 0)+min(b, 0));\n if (d > nk) nhash &= ~(1 << rev[p]);\n }\n\n dp[ny][nx][nk][nhash] = max(dp[ny][nx][nk][nhash], val+plus);\n q.push(PP(Pair(ny, nx), Pair(nk, nhash)));\n } \n }\n printf(\"%d\\n\", ans);\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 42892, "score_of_the_acc": -0.265, "final_rank": 2 } ]
aoj_0580_cpp
魚の生息範囲 (Fish) 問題 オーストラリア大陸の西には,広いインド洋が広がっている.海洋研究者である JOI 氏は,インド洋に生息しているある N 種類の魚の性質について研究している. それぞれの魚の種類に対して,海の中に直方体状の生息範囲が定まっている.魚は境界も含めて生息範囲の中のどの場所にも移動できるが,生息範囲の外に出ることは決してない.海の中の点は,3 つの実数 (x, y, d) によって表される: (x, y, d) は,上空から見たときにある地点を基準にして東に x,北に y 進んだ位置であり,海面からの深さが d の点を表す.ただし,海面は平面であるとする. JOI 氏は,K 種類以上の魚の生息範囲が重なる場所がどのくらいあるかを知りたい.そのような場所全体の体積を求めるプログラムを作成せよ. 入力 入力は 1 + N 行からなる. 1 行目には,2 つの整数 N, K (1 ≦ K ≦ N ≦ 50) が空白を区切りとして書かれている.これは,魚が N 種類であり,K 種類以上の魚の生息範囲が重なる場所の体積を求めたいことを表す. 続く N 行のうちの i 行目 (1 ≦ i ≦ N) には,6 つの整数 X i,1 , Y i,1 , D i,1 , X i,2 , Y i,2 , D i,2 (0 ≦ X i,1 < X i,2 ≦ 1000000 (= 10 6 ),0 ≦ Y i,1 < Y i,2 ≦ 1000000 (= 10 6 ),0 ≦ D i,1 < D i,2 ≦ 1000000 (= 10 6 )) が書かれている.これは,i 種類目の魚の生息範囲が 8 点 (X i,1 , Y i,1 , D i,1 ), (X i,2 , Y i,1 , D i,1 ), (X i,2 , Y i,2 , D i,1 ), (X i,1 , Y i,2 , D i,1 ), (X i,1 , Y i,1 , D i,2 ), (X i,2 , Y i,1 , D i,2 ), (X i,2 , Y i,2 , D i,2 ), (X i,1 , Y i,2 , D i,2 ) を頂点とする直方体であることを表す. 出力 K 種類以上の魚の生息範囲が重なる場所全体の体積を 1 行で出力せよ. 入出力例 入力例 1 3 2 30 50 0 50 70 100 10 20 20 70 90 60 40 60 20 90 90 70 出力例 1 49000 入出力例 1 において,例えば,点 (45, 65, 65) は 1 種類目の魚と 3 種類目の魚の生息範囲であるので,条件を満たす場所である.一方,点 (25, 35, 45) は 2 種類目の魚のみの生息範囲であるので,条件を満たす場所ではない.また,魚の生息範囲は下の図のようになっている.点 O は海面上の基準の地点を表す. 入力例 2 1 1 0 0 0 1000000 1000000 1000000 出力例 2 1000000000000000000 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0580_10946344", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint compress(vector<ll>& v, vector<ll>& vs) {\n sort(vs.begin(), vs.end());\n vs.erase(unique(vs.begin(), vs.end()), vs.end());\n for(int i=0; i<v.size(); ++i) {\n v[i] = lower_bound(vs.begin(), vs.end(), v[i]) - vs.begin();\n }\n return vs.size();\n}\n\nbool cross(int a1, int b1, int a2, int b2) {\n return a1 <= a2 && a2 <= b1;\n}\n\nint main() {\n int N, K;\n cin >> N >> K;\n vector<ll> x(2*N), y(2*N), z(2*N), xs(2*N), ys(2*N), zs(2*N);\n for(int i=0; i<N; ++i) {\n ll x1, y1, z1, x2, y2, z2;\n cin >> x1 >> y1 >> z1 >> x2 >> y2 >> z2;\n x[2*i] = xs[2*i] = x1, x[2*i+1] = xs[2*i+1] = x2;\n y[2*i] = ys[2*i] = y1, y[2*i+1] = ys[2*i+1] = y2;\n z[2*i] = zs[2*i] = z1, z[2*i+1] = zs[2*i+1] = z2;\n }\n int xsize = compress(x, xs);\n int ysize = compress(y, ys);\n int zsize = compress(z, zs);\n ll res = 0;\n for(int i=0; i<xsize-1; ++i) {\n for(int j=0; j<ysize-1; ++j) {\n for(int k=0; k<zsize-1; ++k) {\n int cnt = 0;\n ll x1 = xs[i], x2 = xs[i+1],\n y1 = ys[j], y2 = ys[j+1],\n z1 = zs[k], z2 = zs[k+1];\n for(int n=0; n<N; ++n) {\n ll fx1 = xs[x[2*n]], fx2 = xs[x[2*n+1]];\n ll fy1 = ys[y[2*n]], fy2 = ys[y[2*n+1]];\n ll fz1 = zs[z[2*n]], fz2 = zs[z[2*n+1]];\n if(fx1 <= x1 && x2 <= fx2 && fy1 <= y1 && y2 <= fy2 && fz1 <= z1 && z2 <= fz2) {\n cnt++;\n }\n }\n if(cnt >= K) {\n res += (x2 - x1) * (y2 - y1) * (z2 - z1);\n }\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3364, "score_of_the_acc": -0.7652, "final_rank": 12 }, { "submission_id": "aoj_0580_8091174", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,K; cin >> n >> K;\n vector<int> X(n),Y(n),Z(n),XX(n),YY(n),ZZ(n);\n vector<int> x,y,z;\n for (int i = 0; i < n; ++i) {\n cin >> X[i] >> Y[i] >> Z[i];\n cin >> XX[i] >> YY[i] >> ZZ[i];\n x.push_back(X[i]); x.push_back(XX[i]);\n y.push_back(Y[i]); y.push_back(YY[i]);\n z.push_back(Z[i]); z.push_back(ZZ[i]);\n }\n sort(x.begin(), x.end());\n sort(y.begin(), y.end());\n sort(z.begin(), z.end());\n ll res = 0;\n for (int i = 0; i+1 < x.size(); ++i) {\n ll xx = x[i+1] - x[i];\n if (xx == 0) continue;\n for (int j = 0; j+1 < y.size(); ++j) {\n ll yy = y[j+1] - y[j];\n if (yy == 0) continue;\n for (int k = 0; k+1 < z.size(); ++k) {\n ll zz = z[k+1] - z[k];\n if (zz == 0) continue;\n int cnt = 0;\n for (int l = 0; l < n; ++l) {\n if (X[l] <= x[i] and x[i+1] <= XX[l] and\n Y[l] <= y[j] and y[j+1] <= YY[l] and\n Z[l] <= z[k] and z[k+1] <= ZZ[l]) {\n cnt += 1;\n }\n }\n if (cnt >= K) res += xx*yy*zz;\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3464, "score_of_the_acc": -0.3956, "final_rank": 7 }, { "submission_id": "aoj_0580_6740946", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n int n, K;\n cin >> n >> K;\n\n vector<vector<long long> > a(n, vector<long long >(6));\n\n vector<long long> x, y, z;\n for(int i = 0;i < n;++i){\n cin >> a[i][0] >> a[i][1] >> a[i][2] >> a[i][3] >> a[i][4] >> a[i][5];\n x.push_back(a[i][0]);\n x.push_back(a[i][3]);\n y.push_back(a[i][1]);\n y.push_back(a[i][4]);\n z.push_back(a[i][2]);\n z.push_back(a[i][5]);\n }\n\n sort(x.begin(), x.end());\n sort(y.begin(), y.end());\n sort(z.begin(), z.end());\n unique(x.begin(), x.end());\n unique(y.begin(), y.end());\n unique(z.begin(), z.end());\n long long ans = 0;\n for(int i = 0;i < 2*n-1;++i){\n for(int j = 0;j < 2*n-1;++j){\n for(int k = 0;k < 2*n-1;++k){\n int cnt = 0;\n for(int m = 0;m < n;++m){\n if(a[m][0] <= x[i] && x[i+1] <= a[m][3] && a[m][1] <= y[j] && y[j+1] <= a[m][4] && z[k] >= a[m][2] && z[k+1] <= a[m][5])++cnt;\n }\n\n if(cnt >= K){\n ans += (x[i+1] - x[i]) * (y[j+1] - y[j]) * (z[k+1] - z[k]);\n }\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3152, "score_of_the_acc": -0.3787, "final_rank": 4 }, { "submission_id": "aoj_0580_6740685", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<queue>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<stack>\n#include<string>\n#include<algorithm>\n#include<functional>\n#include<cstring>\n#include<complex>\n#include<bitset>\n#include<iostream>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> Q;\ntypedef complex<double> C;\n#define cx real()\n#define cy imag()\nconst ll INF = 1LL << 60;\nconst double DINF = 1e30;\nconst ll mod = 1000000007;\nconst ll dx[4] = {1, 0, -1, 0};\nconst ll dy[4] = {0, -1, 0, 1};\nconst C I = C(0, 1);\nconst double EPS = 1e-10;\nconst ll NCK_MAX = 510000;\n\nll gcd(ll a, ll b) {\n if (b == 0) return a;\n return gcd(b, a % b);\n}\n\nll extgcd(ll a, ll b, ll& x, ll& y) {\n if (b == 0) {\n x = 1, y = 0; return a;\n }\n ll q = a/b, g = extgcd(b, a - q*b, x, y);\n ll z = x - q * y;\n x = y;\n y = z;\n return g;\n}\n\nll invmod (ll a, ll m) { // a^-1 mod m\n ll x, y;\n extgcd(a, m, x, y);\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nll *fac, *finv, *inv;\n\nvoid nCk_init(ll mod) {\n fac = new ll[NCK_MAX];\n finv = new ll[NCK_MAX];\n inv = new ll[NCK_MAX];\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (ll i = 2; i < NCK_MAX; i++) {\n fac[i] = fac[i-1] * i % mod;\n inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n finv[i] = finv[i-1] * inv[i] % mod;\n }\n}\n\nll nCk(ll n, ll k, ll mod) {\n if (fac == NULL) nCk_init(mod);\n if (n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % mod) % mod;\n}\n\ntemplate <typename T>\nclass Zip {\npublic:\n vector<T> d;\n bool flag;\n void init() {\n sort(d.begin(), d.end());\n d.erase(unique(d.begin(), d.end()), d.end());\n flag = false;\n }\n Zip() {\n flag = false;\n }\n void add(T x) {\n d.push_back(x);\n flag = true;\n }\n ll getNum(T x) {\n if (flag) init();\n return lower_bound(d.begin(), d.end(), x) - d.begin();\n }\n ll size() {\n if (flag) init();\n return (ll)d.size();\n }\n};\n\nclass UnionFind {\n vector<ll> par, rank; // par > 0: number, par < 0: -par\npublic:\n UnionFind(ll n) : par(n, 1), rank(n, 0) {}\n ll getSize(ll x) {\n return par[find(x)];\n }\n ll find(ll x) {\n if (par[x] > 0) return x;\n return -(par[x] = -find(-par[x]));\n }\n void merge(ll x, ll y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n if (rank[x] < rank[y]) {\n par[y] += par[x];\n par[x] = -y;\n } else {\n par[x] += par[y];\n par[y] = -x;\n if (rank[x] == rank[y]) rank[x]++;\n }\n }\n bool isSame(ll x, ll y) {\n return find(x) == find(y);\n }\n};\n\n\ntemplate <typename T>\nclass SegmentTree {\n ll n;\n vector<T> node;\n function<T(T, T)> fun, fun2;\n bool customChange;\n T outValue, initValue;\npublic:\n void init(ll num, function<T(T, T)> resultFunction, T init, T out, function<T(T, T)> changeFunction = NULL) {\n // changeFunction: (input, beforevalue) => newvalue\n fun = resultFunction;\n fun2 = changeFunction;\n customChange = changeFunction != NULL;\n n = 1;\n while (n < num) n *= 2;\n node.resize(2 * n - 1);\n fill(node.begin(), node.end(), init);\n outValue = out;\n initValue = init;\n }\n void valueChange(ll num, T value) {\n num += n-1;\n if (customChange) node[num] = fun2(value, node[num]);\n else node[num] = value;\n while (num > 0) num = (num - 1) / 2, node[num] = fun(node[num * 2 + 1], node[num * 2 + 2]);\n }\n T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n if (r == -1) r = n;\n if (a <= l && r <= b) return node[k];\n if (b <= l || r <= a) return outValue;\n ll mid = (l + r) / 2;\n return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n }\n};\n\ntemplate <typename T>\nclass Graph {\n struct edge { ll to; T cost; };\n struct edge_data { ll from, to; T cost; };\n\n ll v;\n vector<vector<edge>> e, re;\n vector<edge_data> ed;\n vector<bool> used;\n vector<ll> vs, cmp;\n bool isDirected, isMinasEdge;\npublic:\n Graph(ll _v, bool _isDirected = true, ll range_add = 0) {\n // range_add 0:no / 1:in / 2:out / 3:in+out\n //_v++;\n v = _v, isDirected = _isDirected; isMinasEdge = false;\n e.resize(v), re.resize(v);\n }\n void add_edge(ll s, ll t, T cost = 1) {\n e[s].push_back((edge){t, cost});\n if (!isDirected) e[t].push_back((edge){s, cost});\n else re[t].push_back((edge){s, cost});\n ed.push_back((edge_data){s, t, cost});\n if (cost < 0) isMinasEdge = true;\n }\n vector<T> dijkstra(ll s) {\n vector<T> d(v, INF);\n d[s] = 0;\n auto edge_cmp = [](const edge& a, const edge& b) { return a.cost > b.cost; };\n priority_queue<edge, vector<edge>, decltype(edge_cmp)> pq(edge_cmp);\n pq.push((edge){s, 0});\n while (!pq.empty()) {\n edge temp = pq.top(); pq.pop();\n if (d[temp.to] < temp.cost) continue;\n for (const edge& next : e[temp.to]) {\n T cost = temp.cost + next.cost;\n if (d[next.to] > cost) {\n d[next.to] = cost;\n pq.push((edge){next.to, cost});\n }\n }\n }\n return d;\n }\n vector<T> bellmanford(ll s) {\n vector<T> d(v, INF);\n d[s] = 0;\n for (ll i = 0; i < v; i++) {\n for (const edge_data& temp : ed) {\n if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = d[temp.from] + temp.cost;\n if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = d[temp.to] + temp.cost;\n }\n }\n for (ll i = 0; i < v; i++) {\n for (const edge_data& temp : ed) {\n if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = -INF;\n if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = -INF;\n }\n }\n return d;\n }\n vector<T> shortest_path(ll s) {\n if (isMinasEdge) return bellmanford(s);\n else return dijkstra(s);\n }\n T kruskal() {\n // if (isDirected)\n UnionFind uf(v);\n auto edge_data_cmp = [](const edge_data& a, const edge_data& b) { return a.cost < b.cost; };\n sort(ed.begin(), ed.end(), edge_data_cmp);\n T ans = 0;\n for (const edge_data& temp : ed) {\n if (uf.isSame(temp.from, temp.to)) continue;\n uf.merge(temp.from, temp.to);\n ans += temp.cost;\n }\n return ans;\n }\n void scc_dfs(ll s) {\n used[s] = true;\n for (const edge& i : e[s]) if (!used[i.to]) scc_dfs(i.to);\n vs.push_back(s);\n }\n void scc_rdfs(ll s, ll k) {\n used[s] = true;\n cmp[s] = k;\n for (const edge& i : re[s]) if (!used[i.to]) scc_rdfs(i.to, k);\n }\n vector<ll> scc() {\n used.resize(v);\n fill(used.begin(), used.end(), false);\n cmp.resize(v);\n vs.clear();\n for (ll i = 0; i < v; i++) if (!used[i]) scc_dfs(i);\n used.resize(v);\n fill(used.begin(), used.end(), false);\n ll k = 0;\n for (ll i = vs.size() - 1; i >= 0; i--) if (!used[vs[i]]) scc_rdfs(vs[i], k++);\n return cmp;\n }\n};\n\nclass RollingHash {\n int base;\n vector<__int128> hash;\n vector<__int128> pw;\n const __int128 hashmod = (1ull << 61) - 1;\npublic:\n RollingHash(string s, int base = 10007) : base(base), hash(s.length()+1, 0), pw(s.length()+1, 1) {\n for (int i = 0; i < (int)s.length(); i++) {\n hash[i+1] = (hash[i] * base + s[i]) % hashmod;\n pw[i+1] = pw[i] * base % hashmod;\n }\n }\n ll get(ll a, ll b) { // [a, b)\n __int128 tmp = hashmod + hash[b] - hash[a] * pw[b-a] % hashmod;\n if (tmp >= hashmod) tmp -= hashmod;\n return (ll)tmp;\n }\n};\n\nll n, k, x[50], y[50], z[50], x2[50], y2[50], z2[50], ans;\n\nint main() {\n scanf(\"%lld%lld\", &n, &k);\n Zip<ll> zx, zy, zz;\n for (ll i = 0; i < n; i++) {\n scanf(\"%lld%lld%lld\", &x[i], &y[i], &z[i]);\n scanf(\"%lld%lld%lld\", &x2[i], &y2[i], &z2[i]);\n zx.add(x[i]); zx.add(x2[i]);\n zy.add(y[i]); zy.add(y2[i]);\n zz.add(z[i]); zz.add(z2[i]);\n }\n for (ll i = 0; i < n; i++) {\n x[i] = zx.getNum(x[i]); x2[i] = zx.getNum(x2[i]);\n y[i] = zy.getNum(y[i]); y2[i] = zy.getNum(y2[i]);\n z[i] = zz.getNum(z[i]); z2[i] = zz.getNum(z2[i]);\n }\n for (ll i = 0; i < zx.size()-1; i++) {\n for (ll j = 0; j < zy.size()-1; j++) {\n for (ll l = 0; l < zz.size()-1; l++) {\n ll cnt = 0;\n for (ll m = 0; m < n; m++) {\n if (x2[m] <= i or i + 1 <= x[m]) continue;\n if (y2[m] <= j or j + 1 <= y[m]) continue;\n if (z2[m] <= l or l + 1 <= z[m]) continue;\n cnt++;\n }\n if (cnt >= k) {\n ans += (zx.d[i+1]-zx.d[i]) * (zy.d[j+1]-zy.d[j]) * (zz.d[l+1]-zz.d[l]);\n }\n }\n }\n }\n printf(\"%lld\\n\", ans);\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3536, "score_of_the_acc": -0.3996, "final_rank": 8 }, { "submission_id": "aoj_0580_5789372", "code_snippet": "#pragma GCC optimize(\"O3\")\n#pragma GCC optimize (\"unroll-loops\")\n#define io_init cin.tie(0);ios::sync_with_stdio(0);cout<<fixed<<setprecision(20)\n#include <bits/stdc++.h>\nconstexpr int INF = 2147483647;\nconstexpr long long int INF_LL = 9223372036854775807;\nconstexpr int MOD = 1000000007;\nconstexpr double PI = 3.14159265358979323846;\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nrandom_device rd;\nmt19937 mt(rd());\n\n\ntemplate<class T>\nstruct Compress {\n\tstd::vector<T> data;\n\tvoid add(T x) {\n\t\tdata.push_back(x);\n\t}\n\tvoid build() {\n\t\tstd::sort(data.begin(), data.end());\n\t\tdata.erase(std::unique(data.begin(), data.end()), data.end());\n\t}\n\n\tconst int operator[](int x) const {\n\t\treturn std::lower_bound(data.begin(), data.end(), x) - data.begin();\n\t}\n\n\tconst T operator()(int k) const {\n\t\treturn data[k];\n\t}\n};\n\nint main() {\n\tint N, K;\n\tcin >> N >> K;\n\tvector <pair<tuple<ll, ll, ll>, tuple<ll, ll, ll>>> fish;\n\tCompress<ll> X, Y, Z;\n\tvector count(N*2, vector(N*2, vector(N*2, 0)));\n\tfor (int i = 0; i < N; i++) {\n\t\tint x1, y1, z1, x2, y2, z2;\n\t\tcin >> x1 >> y1 >> z1 >> x2 >> y2 >> z2;\n\t\tX.add(x1); Y.add(y1); Z.add(z1);\n\t\tX.add(x2); Y.add(y2); Z.add(z2);\n\t\tfish.push_back({ {x1,y1,z1},{x2,y2,z2} });\n\t}\n\tX.build(); Y.build(); Z.build();\n\tfor (int i = 0; i < N; i++) {\n\t\tauto [p1, p2] = fish[i];\n\t\tauto [x1, y1, z1] = p1;\n\t\tauto [x2, y2, z2] = p2;\n\t\tfor (int x = X[x1]; x < X[x2]; x++) {\n\t\t\tfor (int y = Y[y1]; y < Y[y2]; y++) {\n\t\t\t\tfor (int z = Z[z1]; z < Z[z2]; z++) {\n\t\t\t\t\tcount[x][y][z]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll ans = 0;\n\tfor (int x = 0; x < 2 * N; x++)for (int y = 0; y < 2 * N; y++)for (int z = 0; z < 2 * N; z++) {\n\t\tif (count[x][y][z] >= K) {\n\t\t\tans += (X(x + 1) - X(x)) * (Y(y + 1) - Y(y)) * (Z(z + 1) - Z(z));\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7348, "score_of_the_acc": -0.3567, "final_rank": 2 }, { "submission_id": "aoj_0580_5616666", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, K;\n cin >> N >> K;\n vector<tuple<int, int, int, int, int, int>> zahyo(N);\n\n vector<long long> X, Y, Z;\n for (int i = 0; i < N; i++) {\n int x1, y1, z1, x2, y2, z2;\n cin >> x1 >> y1 >> z1 >> x2 >> y2 >> z2;\n zahyo[i] = {x1, y1, z1, x2, y2, z2};\n X.push_back(x1), X.push_back(x2);\n Y.push_back(y1), Y.push_back(y2);\n Z.push_back(z1), Z.push_back(z2);\n }\n\n sort(X.begin(), X.end());\n X.erase(unique(X.begin(), X.end()), X.end());\n sort(Y.begin(), Y.end());\n Y.erase(unique(Y.begin(), Y.end()), Y.end());\n sort(Z.begin(), Z.end());\n Z.erase(unique(Z.begin(), Z.end()), Z.end());\n\n long long ans = 0;\n // 各ブロックの番号\n for (int x = 0; x < (int)X.size() - 1; x++) {\n for (int y = 0; y < (int)Y.size() - 1; y++) {\n for (int z = 0; z < (int)Z.size() - 1; z++) {\n int cnt = 0;\n\n for (int i = 0; i < N; i++) {\n auto [x1, y1, z1, x2, y2, z2] = zahyo[i];\n if (x1 <= X[x] && X[x + 1] <= x2 && y1 <= Y[y] && Y[y + 1] <= y2 && z1 <= Z[z] && Z[z + 1] <= z2) cnt++;\n }\n if (cnt >= K) ans += (X[x + 1] - X[x]) * (Y[y + 1] - Y[y]) * (Z[z + 1] - Z[z]);\n }\n }\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3452, "score_of_the_acc": -0.395, "final_rank": 6 }, { "submission_id": "aoj_0580_5032251", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0; i< (n); i++)\nusing namespace std;\ntypedef long long ll;\nconst int mod = 1000000007;\nconst int inf = (1<<30);\nll X1[50]={},X2[50]={},Y1[50]={},Y2[50]={},d1[50]={},d2[50]={};\nll x[100]={},y[100]={},d[100]={};\n\nint main(){\n\tint n,k;\n\tcin>>n>>k;\n\tll ans=0;\n\trep(i,n){\n\t\tcin>>X1[i]>>Y1[i]>>d1[i]>>X2[i]>>Y2[i]>>d2[i];\n\t}\n\tint xlen=0,ylen=0,dlen=0;\n\trep(i,n){\n\t\t\tx[xlen++]=X1[i];x[xlen++]=X2[i];\n\t\t\ty[ylen++]=Y1[i];y[ylen++]=Y2[i];\n\t\t\td[dlen++]=d1[i];d[dlen++]=d2[i];\n\t}\n\tsort(x,x+xlen); sort(y,y+ylen); sort(d,d+dlen);\n\tfor(int i=0; i+1<xlen; i++){\n\t\tfor(int j=0; j+1<ylen; j++){\n\t\t\tfor(int l=0; l+1<dlen; l++){\n\t\t\t\tint s=0;\n\t\t\t\trep(u,n){\n\t\t\t\t\tif( X1[u]<=x[i] && X2[u]>=x[i+1] &&\n\t\t\t\t\t\tY1[u]<=y[j] && Y2[u]>=y[j+1] &&\n\t\t\t\t\t\td1[u]<=d[l] && d2[u]>=d[l+1]\n\t\t\t\t\t\t){\n\t\t\t\t\t\t\ts++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(s>=k){\n\t\t\t\t\tans+=(x[i+1]-x[i])*(y[j+1]-y[j])*(d[l+1]-d[l]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3148, "score_of_the_acc": -0.5035, "final_rank": 9 }, { "submission_id": "aoj_0580_4981194", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst long long INF = 1001001001;\nconst long long MOD = /**/1000000007;//*/998244353;\nconst double EPS = 1e-10;\n\nll imos[222][222][222];\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int n,k;\n cin>>n>>k;\n ll x[n][2],y[n][2],d[n][2];\n vector<ll> vec1,vec2,vec3;\n vec1.emplace_back(0);\n vec1.emplace_back(INF);\n vec2.emplace_back(0);\n vec2.emplace_back(INF);\n vec3.emplace_back(0);\n vec3.emplace_back(INF);\n for(int i=0;i<n;i++){\n cin>>x[i][0]>>y[i][0]>>d[i][0]>>x[i][1]>>y[i][1]>>d[i][1];\n vec1.emplace_back(x[i][0]);\n vec1.emplace_back(x[i][1]);\n vec2.emplace_back(y[i][0]);\n vec2.emplace_back(y[i][1]);\n vec3.emplace_back(d[i][0]);\n vec3.emplace_back(d[i][1]);\n }\n sort(begin(vec1),end(vec1));\n vec1.erase(unique(begin(vec1),end(vec1)),end(vec1));\n sort(begin(vec2),end(vec2));\n vec2.erase(unique(begin(vec2),end(vec2)),end(vec2));\n sort(begin(vec3),end(vec3));\n vec3.erase(unique(begin(vec3),end(vec3)),end(vec3));\n int t1=vec1.size(),t2=vec2.size(),t3=vec3.size();\n for(int i=0;i<n;i++){\n x[i][0]=lower_bound(begin(vec1),end(vec1),x[i][0])-begin(vec1);\n x[i][1]=lower_bound(begin(vec1),end(vec1),x[i][1])-begin(vec1);\n y[i][0]=lower_bound(begin(vec2),end(vec2),y[i][0])-begin(vec2);\n y[i][1]=lower_bound(begin(vec2),end(vec2),y[i][1])-begin(vec2);\n d[i][0]=lower_bound(begin(vec3),end(vec3),d[i][0])-begin(vec3);\n d[i][1]=lower_bound(begin(vec3),end(vec3),d[i][1])-begin(vec3);\n imos[x[i][0]][y[i][0]][d[i][0]]++,imos[x[i][0]][y[i][0]][d[i][1]]--,imos[x[i][0]][y[i][1]][d[i][0]]--,imos[x[i][1]][y[i][0]][d[i][0]]--,imos[x[i][1]][y[i][1]][d[i][0]]++,imos[x[i][1]][y[i][1]][d[i][1]]--,imos[x[i][0]][y[i][1]][d[i][1]]++,imos[x[i][1]][y[i][0]][d[i][1]]++;\n }\n for(int c=0;c<t3;c++){\n for(int a=0;a<t1;a++){\n for(int b=1;b<t2;b++)imos[a][b][c]+=imos[a][b-1][c];\n }\n }\n for(int b=0;b<t2;b++){\n for(int c=0;c<t3;c++){\n for(int a=1;a<t1;a++)imos[a][b][c]+=imos[a-1][b][c];\n }\n }\n for(int a=0;a<t1;a++){\n for(int b=0;b<t2;b++){\n for(int c=1;c<t3;c++)imos[a][b][c]+=imos[a][b][c-1];\n }\n }\n ll ans=0;\n for(int a=0;a<t1-1;a++){\n for(int b=0;b<t2-1;b++){\n for(int c=0;c<t3-1;c++){\n if(imos[a][b][c]>=k)ans+=(vec1[a+1]-vec1[a])*(vec2[b+1]-vec2[b])*(vec3[c+1]-vec3[c]);\n }\n }\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 21488, "score_of_the_acc": -1, "final_rank": 17 }, { "submission_id": "aoj_0580_4968890", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 10000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\n\nstruct status {\n\tld ave;\n\tld ko;\n\tld cost;\n\n\tbool operator<(const status& rhs) const { return ave < rhs.ave; };\n\tbool operator>(const status& rhs) const { return ave > rhs.ave; };\n};\n\nll maze[105][105][105], dis[105][105][105];\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\t\n\t//input\n\tll n, ink; cin >> n >> ink;\n\tvector<ll> x(n * 2), y(n * 2), z(n * 2);\n\tvector<vector<ll>> v(n, vector<ll>(6));\n\trep(i, n) {\n\t\tcin >> x[i * 2] >> y[i * 2] >> z[i * 2];\n\t\tcin >> x[i * 2 + 1] >> y[i * 2 + 1] >> z[i * 2 + 1];\n\t\tv[i][0] = x[i * 2]; v[i][1] = y[i * 2]; v[i][2] = z[i * 2];\n\t\tv[i][3] = x[i * 2 + 1]; v[i][4] = y[i * 2 + 1]; v[i][5] = z[i * 2 + 1];\n\t\t//x[i * 2].second = 1; y[i * 2].second = 1; z[i * 2].second = 1;\n\t\t//x[i * 2 + 1].second = -1; y[i * 2 + 1].second = -1; z[i * 2 + 1].second = -1;\n\t}\n\n\t//座圧\n\tsort(all(x)); sort(all(y)); sort(all(z));\n\tmap<ll, ll> zaatu1, zaatu2, zaatu3;\n\trep(i, 2 * n) {\n\t\tzaatu1[x[i]] = i; zaatu2[y[i]] = i; zaatu3[z[i]] = i;\n\t}\n\n\t//dis\n\trep(i, 2 * n - 1) {\n\t\trep(j, 2 * n - 1) {\n\t\t\trep(k, 2 * n - 1) {\n\t\t\t\tdis[i][j][k] = (x[i + 1] - x[i]) * (y[j + 1] - y[j]) * (z[k + 1] - z[k]);\n\t\t\t}\n\t\t}\n\t}\n\n\t//maze\n\trep(h, n) {\n\t\tfor (int i = zaatu1[v[h][0]]; i < zaatu1[v[h][3]]; i++) {\n\t\t\tfor (int j = zaatu2[v[h][1]]; j < zaatu2[v[h][4]]; j++) {\n\t\t\t\tfor (int k = zaatu3[v[h][2]]; k < zaatu3[v[h][5]]; k++) {\n\t\t\t\t\tmaze[i][j][k]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll ans = 0;\n\trep(i, 2 * n) {\n\t\trep(j, 2 * n) {\n\t\t\trep(k, 2 * n) {\n\t\t\t\tif (maze[i][j][k] >= ink) { ans += dis[i][j][k]; }\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 19580, "score_of_the_acc": -1.2713, "final_rank": 19 }, { "submission_id": "aoj_0580_4788003", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst double pi=3.141592653589793;\ntypedef unsigned long long ull;\ntypedef long double ldouble;\nconst ll INF=1e18;\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n#define rep2(i, s, n) for (ll i = (s); i < (ll)(n); i++)\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n/* compress\n (X1,Y1),(X2,Y2)という二点で表されるもの(長方形や直線など)について、行か列の片方(X1とX2 or Y1とY2)を座標圧縮する(副作用)\n 返り値: ソートされ重複要素を除いた値\n 計算量: O(n log n)\n*/\ntemplate <typename T>\nvector<T> compress(vector<T> &C1, vector<T> &C2, T w = 1000000){\n vector<T> vals;\n ll n = (ll)C1.size();\n rep(i, n){\n vals.push_back(C1[i]);\n vals.push_back(C2[i]);\n }\n // ソート\n sort(vals.begin(), vals.end());\n // 隣り合う重複を削除(unique), 末端のゴミを削除(erase)\n vals.erase(unique(vals.begin(), vals.end()), vals.end());\n return vals;\n}\n\nint main(){\n ll n, k;\n ll ans = 0;\n cin >> n >> k;\n vector<ll> X1(n), X2(n), Y1(n), Y2(n), D1(n), D2(n);\n rep(i, n){\n cin >> X1.at(i) >> Y1.at(i) >> D1.at(i) >> X2.at(i) >> Y2.at(i) >> D2.at(i);\n }\n vector<ll> X = compress(X1, X2);\n vector<ll> Y = compress(Y1, Y2);\n vector<ll> D = compress(D1, D2);\n ll w = X.size(), h = Y.size(), s = D.size();\n\n\n rep(d, s-1){\n rep(y, h-1){\n rep(x, w-1){\n ll count = 0;\n rep(i, n){\n if(X1[i] <= X[x] && X[x+1] <= X2[i] && Y1[i] <= Y[y] && Y[y+1] <= Y2[i] && D1[i] <= D[d] && D[d+1] <= D2[i]){\n count++;\n }\n }\n if(count >= k){\n ans += (X[x+1] - X[x]) * (Y[y+1] - Y[y]) * (D[d+1] - D[d]);\n }\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3176, "score_of_the_acc": -1.005, "final_rank": 18 }, { "submission_id": "aoj_0580_4665713", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define rrep(i,n) for(int (i)=1;i<=(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint x[2][55], y[2][55], z[2][55];\nvector<int> X, Y, Z;\n\nsigned main() {\n\tcin.tie(0);\n\tcout.tie(0);\n\tios::sync_with_stdio(false);\n\t//cout << fixed << setprecision(15);\n\t\n\tint N, K;\n\tcin >> N >> K;\n\trep(i, N) {\n\t\trep(j, 2) {\n\t\t\tcin >> x[j][i] >> y[j][i] >> z[j][i];\n\t\t\tX.push_back(x[j][i]);\n\t\t\tY.push_back(y[j][i]);\n\t\t\tZ.push_back(z[j][i]);\n\t\t}\n\t}\n\tsort(all(X));\n\tsort(all(Y));\n\tsort(all(Z));\n\n\tint ans = 0;\n\trep(i, 2 * N - 1) {\n\t\trep(j, 2 * N - 1) {\n\t\t\trep(k, 2 * N - 1) {\n\t\t\t\tint cnt = 0;\n\t\t\t\trep(l, N) {\n\t\t\t\t\tif(x[0][l] <= X[i] && X[i] < x[1][l] && y[0][l] <= Y[j] && Y[j] < y[1][l] && z[0][l] <= Z[k] && Z[k] < z[1][l]) {\n\t\t\t\t\t\tcnt++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(K <= cnt) {\n\t\t\t\t\tint dx = X[i+1] - X[i];\n\t\t\t\t\tint dy = Y[j+1] - Y[j];\n\t\t\t\t\tint dz = Z[k+1] - Z[k];\n\t\t\t\t\tans += dx * dy * dz;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3084, "score_of_the_acc": -0.875, "final_rank": 14 }, { "submission_id": "aoj_0580_3996362", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <chrono>\n#define _USE_MATH_DEFINES\n#include <cmath>\n#include <cstring>\n#include <ctime>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <iterator>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\nusing namespace std;\n\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n\nconst int INF = 0x3f3f3f3f;\nconst long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\n// const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1},\n// dx[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n/*-------------------------------------------------*/\nint main() {\n const int L = 1000000;\n int n, k; cin >> n >> k;\n vector<int> x1(n), y1(n), d1(n), x2(n), y2(n), d2(n); REP(i, n) cin >> x1[i] >> y1[i] >> d1[i] >> x2[i] >> y2[i] >> d2[i];\n function<vector<int>(vector<int>&, vector<int>&)> compress = [&](vector<int> &x1, vector<int> &x2) {\n int sz = x1.size();\n vector<int> xs{0, L - 1};\n REP(i, sz) {\n xs.emplace_back(x1[i]);\n if (x2[i] < L) xs.emplace_back(x2[i]);\n }\n sort(ALL(xs));\n xs.erase(unique(ALL(xs)), xs.end());\n return xs;\n };\n vector<int> x = compress(x1, x2), y = compress(y1, y2), d = compress(d1, d2);\n x.emplace_back(L);\n y.emplace_back(L);\n d.emplace_back(L);\n long long ans = 0;\n REP(i, x.size() - 1) REP(j, y.size() - 1) REP(l, d.size() - 1) {\n int kind = 0;\n REP(m, n) {\n if (x1[m] <= x[i] && x[i] < x2[m] && y1[m] <= y[j] && y[j] < y2[m] && d1[m] <= d[l] && d[l] < d2[m]) ++kind;\n }\n if (kind >= k) ans += (long long)(x[i + 1] - x[i]) * (y[j + 1] - y[j]) * (d[l + 1] - d[l]);\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3220, "score_of_the_acc": -0.3824, "final_rank": 5 }, { "submission_id": "aoj_0580_3815366", "code_snippet": "#include<iostream>\n#include<cmath>\n#include<cstdlib>\n#include<string>\n#include<cstring>\n#include<algorithm>\n#include<vector>\n#include<map>\n#include<iomanip>\n#include<queue>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef std::pair<int, int> ipair;\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\nint N;\n\nvector<ll> compress(ll *x1, ll *x2) {\n vector<ll> xs(0);\n\n for (int i = 0; i < N; i++) {\n xs.push_back(x1[i]);\n xs.push_back(x2[i]);\n }\n \n sort(xs.begin(), xs.end());\n xs.erase(unique(xs.begin(), xs.end()), xs.end());\n\n return xs;\n}\n\nint main() {\n int K;\n cin >> N >> K;\n ll X1[N], Y1[N], Z1[N], X2[N], Y2[N], Z2[N];\n\n for (int i = 0; i < N; i++) {\n cin >> X1[i] >> Y1[i] >> Z1[i] >> X2[i] >> Y2[i] >> Z2[i];\n }\n\n vector<ll> XS = compress(X1, X2);\n vector<ll> YS = compress(Y1, Y2);\n vector<ll> ZS = compress(Z1, Z2);\n int XL = XS.size();\n int YL = YS.size();\n int ZL = ZS.size();\n\n ll ans = 0;\n for (int x = 0; x < XL - 1; x++) {\n for (int y = 0; y < YL - 1; y++) {\n for (int z = 0; z < ZL - 1; z++) {\n int cnt = 0;\n for (int i = 0; i < N; i++) {\n if (X1[i] > XS[x]) continue;\n if (X2[i] < XS[x + 1]) continue;\n if (Y1[i] > YS[y]) continue;\n if (Y2[i] < YS[y + 1]) continue;\n if (Z1[i] > ZS[z]) continue;\n if (Z2[i] < ZS[z + 1]) continue;\n cnt++;\n }\n if (cnt >= K) {\n ans += (XS[x + 1] - XS[x]) * (YS[y + 1] - YS[y]) * (ZS[z + 1] - ZS[z]);\n }\n }\n }\n }\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3148, "score_of_the_acc": -0.3785, "final_rank": 3 }, { "submission_id": "aoj_0580_3567721", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cstring>\nusing namespace std;\n\nconst int INF = 1e7;\ntypedef long long ll;\n\nint main(){\n int n, K;\n cin >> n >> K;\n vector<int> ax(n), ay(n), az(n), bx(n), by(n), bz(n), x, y, z;\n for(int i = 0; i < n; i++){\n cin >> ax[i] >> ay[i] >> az[i] >> bx[i] >> by[i] >> bz[i];\n x.push_back(ax[i]), x.push_back(bx[i]);\n y.push_back(ay[i]), y.push_back(by[i]);\n z.push_back(az[i]), z.push_back(bz[i]);\n }\n x.push_back(-INF), x.push_back(INF);\n y.push_back(-INF), y.push_back(INF);\n z.push_back(-INF), z.push_back(INF);\n sort(x.begin(), x.end());\n sort(y.begin(), y.end());\n sort(z.begin(), z.end());\n x.erase(unique(x.begin(),x.end()),x.end());\n y.erase(unique(y.begin(),y.end()),y.end());\n z.erase(unique(z.begin(),z.end()),z.end());\n int xn = x.size(), yn = y.size(), zn = z.size();\n int imos[xn][yn][zn];\n memset(imos, 0, sizeof(imos));\n for(int i = 0; i < n; i++){\n int ix = lower_bound(x.begin(),x.end(),ax[i])-x.begin();\n int iy = lower_bound(y.begin(),y.end(),ay[i])-y.begin();\n int iz = lower_bound(z.begin(),z.end(),az[i])-z.begin();\n int jx = lower_bound(x.begin(),x.end(),bx[i])-x.begin();\n int jy = lower_bound(y.begin(),y.end(),by[i])-y.begin();\n int jz = lower_bound(z.begin(),z.end(),bz[i])-z.begin();\n imos[ix][iy][iz]++;\n imos[ix][jy][iz]--;\n imos[jx][iy][iz]--;\n imos[jx][jy][iz]++;\n imos[ix][iy][jz]--;\n imos[ix][jy][jz]++;\n imos[jx][iy][jz]++;\n imos[jx][jy][jz]--;\n }\n\n for(int k = 0; k < zn; k++){\n for(int j = 0; j < yn; j++){\n for(int i = 1; i < xn; i++){\n imos[i][j][k] += imos[i-1][j][k];\n }\n }\n }\n for(int k = 0; k < zn; k++){\n for(int i = 0; i < xn; i++){\n for(int j = 1; j < yn; j++){\n imos[i][j][k] += imos[i][j-1][k];\n }\n }\n }\n for(int i = 0; i < xn; i++){\n for(int j = 0; j < yn; j++){\n for(int k = 1; k < zn; k++){\n imos[i][j][k] += imos[i][j][k-1];\n }\n }\n }\n\n ll ans = 0;\n for(int i = 0; i < xn; i++){\n for(int j = 0; j < yn; j++){\n for(int k = 0; k < zn; k++){\n if(imos[i][j][k] < K) continue;\n ans += (ll)(x[i+1]-x[i])*(y[j+1]-y[j])*(z[k+1]-z[k]);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7296, "score_of_the_acc": -0.2289, "final_rank": 1 }, { "submission_id": "aoj_0580_3366248", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\nint main(void) {\n\n\tint N, K; cin >> N >> K;\n\tvector<vector<unsigned long long> > fishrange;\n\tvector<unsigned long long> x, y, d;\n\n\tunsigned long long volume = 0;\n\n\tfor (int i = 0; i < N; i++) {\n\t\tvector<unsigned long long> range;\n\t\tint x1, y1, d1, x2, y2, d2; cin >> x1 >> y1 >> d1 >> x2 >> y2 >> d2;\n\n\t\trange.push_back(x1); range.push_back(y1); range.push_back(d1);\n\t\trange.push_back(x2); range.push_back(y2); range.push_back(d2);\n\n\t\tx.push_back(x1); x.push_back(x2);\n\t\ty.push_back(y1); y.push_back(y2);\n\t\td.push_back(d1); d.push_back(d2);\n\n\t\tfishrange.push_back(range);\n\t}\n\n\tsort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end());\n\tsort(y.begin(), y.end()); y.erase(unique(y.begin(), y.end()), y.end());\n\tsort(d.begin(), d.end()); d.erase(unique(d.begin(), d.end()), d.end());\n\n\tfor (int i = 0; i < (x.size() - 1); i++) {\n\t\tfor (int j = 0; j < (y.size() - 1); j++) {\n\n\t\t\tfor (int t = 0; t < (d.size() - 1); t++) {\n\n\t\t\t\tint count = 0;\n\n\t\t\t\tfor (int s = 0; s < N; s++) {\n\t\t\t\t\tif (x[i] >= fishrange[s][0] && x[i + 1] <= fishrange[s][3] &&\n\t\t\t\t\t\ty[j] >= fishrange[s][1] && y[j + 1] <= fishrange[s][4] &&\n\t\t\t\t\t\td[t] >= fishrange[s][2] && d[t + 1] <= fishrange[s][5])\n\n\t\t\t\t\t\tcount++;\n\t\t\t\t}\n\n\t\t\t\tif (count >= K) volume += (x[i + 1] - x[i])*(y[j + 1] - y[j])*(d[t + 1] - d[t]);\n\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << volume << endl;\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3156, "score_of_the_acc": -0.5039, "final_rank": 10 }, { "submission_id": "aoj_0580_3365787", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n // Your code here!\n vector<vector<long> > fishrange;\n vector<long> xi;\n vector<long> yi;\n vector<long> di;\n unsigned long long n,k,p,checker;\n unsigned long long volume = 0;\n cin>>n>>k;\n for(int i=0;i<n;i++)\n {\n vector<long> v;\n for(int j=0;j<6;j++)\n {\n int h;\n cin>>h;\n v.push_back(h);\n }\n fishrange.push_back(v);\n p = fishrange[i][0];\n xi.push_back(p);\n p = fishrange[i][3];\n xi.push_back(p);\n p = fishrange[i][1];\n yi.push_back(p);\n p = fishrange[i][4];\n yi.push_back(p);\n p = fishrange[i][2];\n di.push_back(p); \n p = fishrange[i][5];\n di.push_back(p);\n \n }\n sort(xi.begin(),xi.end());\n xi.erase(unique(xi.begin(),xi.end()),xi.end());\n sort(yi.begin(),yi.end());\n yi.erase(unique(yi.begin(),yi.end()),yi.end());\n sort(di.begin(),di.end());\n di.erase(unique(di.begin(),di.end()),di.end());\n \n for(int i=0;i<n*2-1;i++)\n {\n for(int j=0;j<n*2-1;j++)\n {\n for(int l=0;l<n*2-1;l++)\n {\n checker = 0;\n for(int c=0;c<n;c++)\n {\n if(xi[i]>=fishrange[c][0]&&xi[i+1]<=fishrange[c][3]&&yi[j]>=fishrange[c][1]&&yi[j+1]<=fishrange[c][4]&&di[l]>=fishrange[c][2]&&di[l+1]<=fishrange[c][5])\n checker++;\n }\n if(checker>=k)\n volume += (xi[i+1]-xi[i])*(yi[j+1]-yi[j])*(di[l+1]-di[l]);\n }\n }\n }\n \n \n cout<<volume<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3140, "score_of_the_acc": -0.753, "final_rank": 11 }, { "submission_id": "aoj_0580_3365767", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(void){\n // Your code here!\n vector<vector<int> > fishrange;\n vector<int> xi;\n vector<int> yi;\n vector<int> di;\n int n,k,p,checker;\n unsigned long long volume = 0;\n cin>>n>>k;\n for(int i=0;i<n;i++)\n {\n vector<int> v;\n for(int j=0;j<6;j++)\n {\n int h;\n cin>>h;\n v.push_back(h);\n }\n fishrange.push_back(v);\n p = fishrange[i][0];\n xi.push_back(p);\n p = fishrange[i][3];\n xi.push_back(p);\n p = fishrange[i][1];\n yi.push_back(p);\n p = fishrange[i][4];\n yi.push_back(p);\n p = fishrange[i][2];\n di.push_back(p); \n p = fishrange[i][5];\n di.push_back(p);\n \n }\n sort(xi.begin(),xi.end());\n xi.erase(unique(xi.begin(),xi.end()),xi.end());\n sort(yi.begin(),yi.end());\n yi.erase(unique(yi.begin(),yi.end()),yi.end());\n sort(di.begin(),di.end());\n di.erase(unique(di.begin(),di.end()),di.end());\n \n for(int i=0;i<n*2-1;i++)\n {\n for(int j=0;j<n*2-1;j++)\n {\n for(int l=0;l<n*2-1;l++)\n {\n checker = 0;\n for(int c=0;c<n;c++)\n {\n if(xi[i]>=fishrange[c][0]&&xi[i+1]<=fishrange[c][3]&&yi[j]>=fishrange[c][1]&&yi[j+1]<=fishrange[c][4]&&di[l]>=fishrange[c][2]&&di[l+1]<=fishrange[c][5])\n checker++;\n }\n if(checker>=k)\n volume += (xi[i+1]-xi[i])*(yi[j+1]-yi[j])*(di[l+1]-di[l]);\n }\n }\n }\n \n \n cout<<volume<<endl;\n return 0;\n}", "accuracy": 0.2, "time_ms": 40, "memory_kb": 3104, "score_of_the_acc": -0.3761, "final_rank": 20 }, { "submission_id": "aoj_0580_3335030", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cctype>\n#include<utility>\n#include<string>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<map>\n#include<queue>\n\n#define REP(i, n) for(int i = 0;i < n;i++)\n#define REPR(i, n) for(int i = n;i >= 0;i--)\n#define FOR(i, m, n) for(int i = m;i < n;i++)\n#define FORR(i, m, n) for(int i = m;i >= n;i--)\n#define SORT(v, n) sort(v, v+n);\n#define VSORT(v) sort(v.begin(), v.end());\n#define llong long long\n#define pb(a) push_back(a)\n#define INF 1000000007\nusing namespace std;\ntypedef pair<int, int> P;\ntypedef pair<llong, llong> LP;\ntypedef pair<int, P> PP;\ntypedef pair<llong, LP> LPP;\ntypedef long long int ll;\nll dx[4] = {1,0,0,-1};\nll dy[4] = {0,1,-1,0};\n\n#define ARRAY_MAX 55\nll n,k,h,w,d;\nll X1[ARRAY_MAX],X2[ARRAY_MAX],Y1[ARRAY_MAX],Y2[ARRAY_MAX],D1[ARRAY_MAX],D2[ARRAY_MAX];\nll field[ARRAY_MAX*4][ARRAY_MAX*4][ARRAY_MAX*4];\nvector<ll> xs,ys,ds,xunzip,yunzip,dunzip;\nmap<ll,ll> xzip,yzip,dzip;\n\nvoid compress(vector<ll>& x,map<ll,ll>& zip,vector<ll>& unzip){\n\n VSORT(x);\n x.erase(unique(x.begin(),x.end()),x.end());\n unzip.resize(x.size());\n REP(i,x.size()){\n zip[x[i]] = i;\n unzip[i] = x[i];\n }\n}\n\n\nint main(){\n\n\n cin >> n >> k;\n \n REP(i,n){\n cin >> X1[i] >> Y1[i] >> D1[i] >> X2[i] >> Y2[i] >> D2[i];\n xs.push_back(X1[i]);\n xs.push_back(X2[i]);\n ys.push_back(Y1[i]);\n ys.push_back(Y2[i]);\n ds.push_back(D1[i]);\n ds.push_back(D2[i]);\n }\n\n compress(xs,xzip,xunzip);\n compress(ys,yzip,yunzip);\n compress(ds,dzip,dunzip);\n\n w = xzip.size();\n h = yzip.size();\n d = dzip.size();\n\n REP(i,n){\n field[yzip[Y1[i]]][xzip[X1[i]]][dzip[D1[i]]]++;\n field[yzip[Y1[i]]][xzip[X2[i]]][dzip[D1[i]]]--;\n field[yzip[Y2[i]]][xzip[X1[i]]][dzip[D1[i]]]--;\n field[yzip[Y2[i]]][xzip[X2[i]]][dzip[D1[i]]]++;\n field[yzip[Y1[i]]][xzip[X1[i]]][dzip[D2[i]]]--;\n field[yzip[Y1[i]]][xzip[X2[i]]][dzip[D2[i]]]++;\n field[yzip[Y2[i]]][xzip[X1[i]]][dzip[D2[i]]]++;\n field[yzip[Y2[i]]][xzip[X2[i]]][dzip[D2[i]]]--;\n }\n \n REP(i,h+1)REP(j,w)REP(m,d){//横\n field[i][j+1][m] += field[i][j][m];\n }\n\n\n REP(j,w+1)REP(i,h)REP(m,d){//縦\n field[i+1][j][m] += field[i][j][m];\n }\n\n REP(m,d+1)REP(i,h)REP(j,w){\n field[i][j][m+1] += field[i][j][m];\n }\n\n ll ans = 0;\n REP(i,h)REP(j,w)REP(m,d){\n if(field[i][j][m] >= k){\n ans += (yunzip[i+1] - yunzip[i])*(xunzip[j+1] - xunzip[j])*(dunzip[m+1] - dunzip[m]);\n\n }\n }\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 20916, "score_of_the_acc": -0.9689, "final_rank": 16 }, { "submission_id": "aoj_0580_3328790", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> mp;\ntypedef pair<mp ,int> mypair;\ntypedef pair<mp,pair<mp,mp> > tri;\ntypedef long long int ll;\nvoid print(vector<int> a){\n\tfor(int i=0;i<a.size();i++)cout<<a[i]<<' ';\n\tcout<<endl;\n}\nvoid print(vector<mp> a){\n\tfor(int i=0;i<a.size();i++)cout<<\" (\"<<a[i].first<<\" ,\"<<a[i].second<<\")\" ;\n\tcout<<endl;\n}\nint main(){\n\tint n,m;\n\tcin>>n>>m;\n\tvector<int> x,y,d;\n\tvector<mp> mx(n),my(n),md(n);\n\tfor(int i=0;i<n;i++){\n\t\tint x1,x2,y1,y2,d1,d2;\n\t\tcin>>x1>>y1>>d1>>x2>>y2>>d2;\n\t\tx.push_back(x1);\n\t\tx.push_back(x2);\n\t\ty.push_back(y1);\n\t\ty.push_back(y2);\n\t\td.push_back(d1);\n\t\td.push_back(d2);\n\t\tmx[i]=mp(x1,x2);\n\t\tmy[i]=mp(y1,y2);\n\t\tmd[i] =mp(d1,d2);\n\t}\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tsort(d.begin(),d.end() );\n\t//cout<<endl;\n\t//print(x);\n\t//print(y);\n\t//print(d);\n\t//cout<<endl;\n\t//print(mx);\n\t//print(my);\n\t//print(md);\n\t//cout<<endl;\n\t//sort(map.begin(),map.end() );\n\tll ans = 0;\n\tfor(int i=0;i<x.size()-1;i++){\n\t\t\tif(x[i]==x[i+1])continue;\n\t\tfor(int j=0;j<y.size()-1;j++){\n\t\t\t\tif(y[j]==y[j+1])continue;\n\t\t\tfor(int k=0;k<d.size()-1;k++){\n\t\t\t\tif(d[k]==d[k+1])continue;\n\t\t\t\tint cnt=0;\n\t\t\t\tfor(int t=0;t<n;t++){\n\t\t\t\t\tmp nx = mx[t];\n\t\t\t\t\tmp ny = my[t];\n\t\t\t\t\tmp nd = md[t];\n\t\t\t\t\t\n\t\t\t\t\tif(nx.first<=x[i]&&x[i+1]<=nx.second&&\n\t\t\t\t\t\t\tny.first<=y[j]&&y[j+1]<=ny.second&&\n\t\t\t\t\t\t\tnd.first<=d[k]&&d[k+1]<=nd.second){\n\t\t\t\t\t\tcnt++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(cnt>=m){\n\t\t\t\t\tll tmp=(ll( x[i+1]-x[i]))*(ll(y[j+1]-y[j]) )*(ll(d[k+1]-d[k]) );\n\t\t\t\t\t//cout<<x[i]<<' '<<y[j]<<' '<<d[k]<<\" \"<<tmp<<endl;\n\t\t\t\t\tans+=tmp;\n\t\t\t\t}\n\t\t\t}\t\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3168, "score_of_the_acc": -0.8796, "final_rank": 15 }, { "submission_id": "aoj_0580_3326961", "code_snippet": "// #define _GLIBCXX_DEBUG // for STL debug (optional)\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\nusing namespace std;\n\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define int long long int\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \ntypedef pair<int, int> pii;\ntypedef long long ll;\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\nint X1[210], Y1[210], Z1[210], X2[210], Y2[210], Z2[210];\nint rX[210], rY[210], rZ[210];\nint sum[210][210][210];\nsigned main() {\n int N, K; cin >> N >> K;\n map<int, int> cmpx, cmpy, cmpz;\n\n // int acc[210][210][210];\n for(int i=0; i<N; i++) {\n int x1, y1, z1, x2, y2, z2;\n cin >> x1 >> y1 >> z1 >> x2 >> y2 >> z2;\n cmpx[x1]++; cmpx[x2]++; // cmpx[x2+1]++;\n cmpy[y1]++; cmpy[y2]++; // cmpy[y2+1]++;\n cmpz[z1]++; cmpz[z2]++; // cmpz[z2+1]++;\n\n X1[i] = x1, Y1[i] = y1, Z1[i] = z1;\n X2[i] = x2, Y2[i] = y2, Z2[i] = z2;\n }\n\n int idx = 0, idy = 0, idz = 0;\n for(auto &e : cmpx) rX[idx] = e.first, e.second = idx++;\n for(auto &e : cmpy) rY[idy] = e.first, e.second = idy++;\n for(auto &e : cmpz) rZ[idz] = e.first, e.second = idz++;\n\n for(int i=0; i<N; i++) {\n int lb = cmpz[ Z1[i] ], ub = cmpz[ Z2[i] ];\n for(int z=lb; z<ub; z++) {\n int lx = cmpx[ X1[i] ], rx = cmpx[ X2[i] ];\n int ly = cmpy[ Y1[i] ], ry = cmpy[ Y2[i] ];\n for(int x=lx; x<rx; x++) {\n for(int y=ly; y<ry; y++) {\n sum[x][y][z]++;\n }\n }\n }\n }\n\n int ans = 0;\n for(int i=0; i<idx; i++) {\n for(int j=0; j<idy; j++) {\n for(int k=0; k<idz; k++) {\n if(sum[i][j][k] >= K) {\n int diff_x = rX[i+1] - rX[i];\n int diff_y = rY[j+1] - rY[j];\n int diff_z = rZ[k+1] - rZ[k];\n ans += diff_x * diff_y * diff_z;\n }\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 17668, "score_of_the_acc": -0.7924, "final_rank": 13 } ]
aoj_0583_cpp
問題 2 入力ファイルの1行目に正整数 n が書いてあり, 2行目には半角空白文字1つを区切りとして, n 個の正整数が書いてある. n は 2 または 3 であり, 2行目に書かれているどの整数も値は 10 8 以下である. これら2個または3個の数の公約数をすべて求め, 小さい方から順に1行に1個ずつ出力せよ. 自明な公約数(「1」)も出力すること. 出力ファイルにおいては, 出力の最後行にも改行コードを入れること. 入出力例 入力例1 2 75 125 出力例1 1 5 25 入力例2 3 110 22 88 出力例2 1 2 11 22 入力例3 3 66 11 3 出力例3 1 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0583_9684249", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;++i)\n#define ALL(a) (a).begin(),(a).end()\nconst int inf = INT_MAX;\nusing ll = long long;\nconst ll INF = 1e18;\nusing P = pair<int,int>;\nstruct Edge{\n int to;\n ll cost;\n Edge(int to,ll cost):to(to),cost(cost){}\n};\nusing Graph = vector<vector<int>>;\nusing WeightedGraph = vector<vector<Edge>>;\n\n\nstruct UnionFind{\n vector<int> par,rank,siz;\n UnionFind(int n) : par(n,-1),rank(n,0),siz(n,1){ }\n\n int root(int x){\n if(par[x]==-1)return x;\n else return par[x]=root(par[x]);\n }\n\n bool issame(int x,int y){\n return root(x)==root(y);\n }\n\n bool unite(int x,int y){\n int rx=root(x),ry=root(y);\n if(rx==ry)return false;\n if(rank[rx]<rank[ry])swap(rx,ry);\n par[ry]=rx;\n if(rank[rx]==rank[ry])rank[rx]++;\n siz[rx]+=siz[ry];\n return true;\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\n\nclass SegmentTree{\n public:\n vector<int>dat;\n int siz=1;\n\n void init(int N){\n siz=1;\n while(siz<N)siz*=2;\n dat=vector<int>(2*siz,0);\n }\n\n void update(int pos,int x){\n pos=pos+siz-1;\n dat[pos]=x;\n while(pos>=2){\n pos/=2;\n dat[pos]=max(dat[pos*2],dat[pos*2+1]);\n }\n }\n\n int query(int l,int r,int a,int b,int u){\n if(r<=a || b<=l)return -100000000;\n if(l<=a && b<=r)return dat[u];\n int m=(a+b)/2;\n int AnsL=query(l,r,a,m,u*2);\n int AnsR=query(l,r,m,b,u*2+1);\n return max(AnsL,AnsR);\n }\n};\n\ntemplate<typename T> bool chmin(T& a, T b){if(a > b){a = b; return true;} return false;}\ntemplate<typename T> bool chmax(T& a, T b){if(a < b){a = b; return true;} return false;}\n\nvector<int>dxs={1,0,-1,0};\nvector<int>dys={0,1,0,-1};\n\n//fixed << setprecision(10)\n//A[i].erase(unique(ALL(A[i])),A[i].end());\n\nint main(){\n int n;\n cin >> n;\n vector<int>a(n);\n rep(i,n)cin >> a[i];\n int mx=-1;\n rep(i,n)mx=max(mx,a[i]);\n\n for(int i=1;i<=mx;i++){\n bool flag=true;\n rep(j,n)if(a[j]%i!=0)flag=false;\n if(flag)cout << i << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3412, "score_of_the_acc": -0.9548, "final_rank": 12 }, { "submission_id": "aoj_0583_9360927", "code_snippet": "#define NOMINMAX\n#define TEST_MODE true\n\n#define _CRT_SECURE_NO_WARNINGS\n#define _USE_MATH_DEFINES\n\n#include \"bits/stdc++.h\"\n\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define rep2(i,a,n) for(int i=a;i<(int)(n);++i)\n#define rrep(i,n) for(int i=(n)-1;i>=0;--i)\n#define reu(i,n) for(int i=1;i<=(int)(n);++i)\n\n#define chmax(a,b) (a=(a)<(b)?(b):(a))\n#define chmin(a,b) (a=(a)>(b)?(b):(a))\n\n#define ll long long\n#define all(a) begin(a),end(a)\n#define int long long\n\n#ifdef LOCAL_ENV\n#define dump(x) cerr<<#x<<\" : \"<<(x)<< \" \\t\"\n#define dumpl(x) dump(x)<<endl\n#define cerr_endl cerr<<endl\nofstream ofstream1(\"out.txt\");\n#define cout ofstream1\n\n#else\n#define dump(x) \n#define dumpl(x)\n#define cerr_endl \n#endif\n\n#define abp(o,a,b) cout<<(((o)?a:b))<<endl\n#define YEP(x) abp(x,\"YES\",\"NO\")\n#define Yep(x) abp(x,\"Yes\",\"No\")\n\nconst int inf = (int)1 << 60;\nll mod_n = (int)1e9 + 7;\n\nconst int MAX = (int)2e6 + 5;\nconst int MAX2 = 2005;\n\ntemplate<typename T>void ce_vector(vector<T> a) {\n#ifdef LOCAL_ENV\n\trep(i, a.size() - 1) cerr << a[i] << \" \"; cerr << a[a.size() - 1] << endl;\n#endif \n}\n\ntemplate<typename T>void ce_vector(vector<pair<T, T> > a) {\n#ifdef LOCAL_ENV\n\trep(i, a.size()) cerr << a[i].first << \",\" << a[i].second << \" \"; cerr << endl;\n#endif \n}\n\ntemplate<typename T>void o_vector(vector<T> a) {\n\tif (a.size() == 0) { cout << endl; return; }\n\trep(i, a.size() - 1) cout << a[i] << \" \"; cout << a[a.size() - 1] << endl;\n}\n\ntemplate<typename T>void o_vector(vector<pair<T, T> > a) { rep(i, a.size()) cout << a[i].first << \",\" << a[i].second << \" \"; cout << endl; }\n\nll pow_n(ll x, ll n) { ll r = 1; while (n > 0) { if (n & 1)r = (r * x) % mod_n; x = (x * x) % mod_n; n >>= 1; }return r; }\n\n\ntemplate<typename T>\nvector<T> in_vec(int n) {\n\tvector<T> a(n);\n\ta.resize(n);\n\trep(i, n) cin >> a[i];\n\treturn a;\n}\n\nint div_ceil(int a, int b) { int r = a / b; if (a % b != 0)r++; return r; }\n\nll modular(ll x) {\n\treturn ((x % mod_n + mod_n) % mod_n);\n}\n\n// end of template\n\nstruct Person {\n\tint pos, id;\n\n\tbool operator<(const Person& p) const {\n\t\treturn pos < p.pos;\n\t}\n};\n\n\nstruct Solver {\n\tvoid solve() {\n\t\tint n; cin >> n;\n\t\tauto v = in_vec<int>(n);\n\t\tint m = *max_element(all(v));\n\t\trep2(i, 1, m) {\n\t\t\tbool ok = true;\n\t\t\trep(j, n) {\n\t\t\t\tif (v[j] % i != 0) ok = false;\n\t\t\t}\n\t\t\tif (ok) {\n\t\t\t\tcout << i << endl;\n\t\t\t}\n\t\t}\n\t}\n\n\n};\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\t//cin.tie(nullptr);\n\n\tcout << fixed << setprecision(2);\n\n\tSolver().solve();\n\n#ifdef LOCAL_ENV\n\tcout << endl;\n\tcerr << endl << \"\\x1b[7m ↓ \\x1b[0m\" << endl;\n\tsystem(\"type out.txt\");\n#endif\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3388, "score_of_the_acc": -0.9339, "final_rank": 11 }, { "submission_id": "aoj_0583_9178433", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n int a[n];\n for (int i = 0; i < n; i++){cin >> a[i];}\n sort(a, a+n);\n\n for (int k = 1; k <= a[n - 1]; k++){\n int l = 0;\n for (int j = 1; j <= n; j++){\n if (a[j - 1] % k == 0) l++;\n }\n if (l == n) cout << k << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3172, "score_of_the_acc": -0.6158, "final_rank": 9 }, { "submission_id": "aoj_0583_9043318", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned short n, i;\n\tunsigned int j, a[3];\n\tcin >> n;\n\tfor (i = 0; i != n; ++i) cin >> a[i];\n\n\tfor (j = 1; j <= 100'000'000; ++j)\n\t{\n\t\tfor (i = 0; i != n && a[i] % j == 0; ++i);\n\t\tif (i == n) cout << j << '\\n';\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3380, "score_of_the_acc": -0.9962, "final_rank": 13 }, { "submission_id": "aoj_0583_9036032", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll n;\n cin >> n;\n vi a(n);\n rep(i, n) cin >> a[i];\n vi ans;\n rep(i, 1, MAX(a)+1) {\n bool ok = true;\n rep(j, n) ok = (ok and (a[j]%i == 0));\n if (ok) ans.eb(i);\n }\n rep(i, len(ans)) print(ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3444, "score_of_the_acc": -1.0043, "final_rank": 14 }, { "submission_id": "aoj_0583_7451194", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <iostream>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <functional>\n#include <set>\n#include <map>\n#include <string>\n#include <vector>\n#include <cmath>\n#include<sstream>\n#include<list>\n#include<iomanip>\n#include <cstdlib>\n#include <cstring>\n#include <stack>\n#include <bitset>\n#include <cassert>\n#include <stdlib.h>\n#include <stdio.h>\nusing namespace std;\nconst int INF = 100000000;\nconst long long LINF = 3e18 + 7;\nconst int MAX_N = 600010;\nconst int MAX_W = 10002;\nconst int MAX_ARRAYK = 100000;\ndouble PI = 3.14159265358979323846;\n//using ll = long long;\n\nlong long A, B;\nlong long gcd(long long a, long long b) {\n\tif (b == 0LL) return a;\n\treturn gcd(b, a % b);\n}\nint N;\nlong long a[10];\nint main() {\n\n\tcin >> N;\n\t\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> a[i];\n\t}\n\n\tfor (int n = 1; n < 10000 * 10000; n++) {\n\t\tbool flag = true;\n\t\tfor (int i = 0; i < N; i++) {\n\t\t\tif (a[i] % n != 0) {\n\t\t\t\tflag = false;\n\t\t\t}\n\t\t}\n\t\tif (flag) {\n\t\t\tcout << n << endl;\n\t\t}\n\t}\n\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2320, "memory_kb": 3100, "score_of_the_acc": -1.5141, "final_rank": 19 }, { "submission_id": "aoj_0583_6814456", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\ntemplate <class S, S(*op)(S, S), S(*e)()> struct segtree {\npublic:\n segtree() : segtree(0) {}\n segtree(int n) : segtree(std::vector<S>(n, e())) {}\n segtree(const std::vector<S>& v) : _n(int(v.size())) {\n log = ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n\n void set(int p, S x) {\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) { return d[p + size]; }\n\n S prod(int l, int r) {\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) {\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) {\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\nprivate:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\nll op(ll a, ll b) { return a + b; }\nll e() { return 0; }\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vll A(N);\n rep(i,N)cin>>A[i];\n vll AN;\n ll G=A[0];\n rep(i,N)G=gcd(G,A[i]);\n for(ll i=1;i<=1e8;i++){\n if(G%i==0)cout<<i<<endl;\n }\n \n\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 3332, "score_of_the_acc": -1.1015, "final_rank": 17 }, { "submission_id": "aoj_0583_6814453", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\ntemplate <class S, S(*op)(S, S), S(*e)()> struct segtree {\npublic:\n segtree() : segtree(0) {}\n segtree(int n) : segtree(std::vector<S>(n, e())) {}\n segtree(const std::vector<S>& v) : _n(int(v.size())) {\n log = ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n\n void set(int p, S x) {\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) { return d[p + size]; }\n\n S prod(int l, int r) {\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) {\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) {\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\nprivate:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\nll op(ll a, ll b) { return a + b; }\nll e() { return 0; }\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vll A(N);\n rep(i,N)cin>>A[i];\n vll AN;\n for(ll i=1;i<=1e8;i++){\n bool C=1;\n rep(j,N)if(A[j]%i!=0)C=0;\n if(C)cout<<i<<endl;\n }\n \n\n}", "accuracy": 1, "time_ms": 1790, "memory_kb": 3372, "score_of_the_acc": -1.6689, "final_rank": 20 }, { "submission_id": "aoj_0583_6074975", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\n int a,x=0,y=0;\n cin>>a;\n int b[a];\n for(int i=0;i<a;i++){\n cin>>b[i];\n if(x<b[i]){\n x=b[i];\n }\n }\n for(int i=1;i<=x;i++){\n for(int j=0;j<a;j++){\n if(b[j]%i==0){\n y+=1;\n }\n if(y==a){\n cout<<i<<endl;\n }\n }\n y=0;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3120, "score_of_the_acc": -0.5424, "final_rank": 6 }, { "submission_id": "aoj_0583_5930313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int64_t;\n#define rep(i,n) for(int i=0;i<(n);++i)\nstatic const ll MOD = 1000000007;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n int N;\n cin>>N;\n vector<int> A(N);\n rep(i,N) cin>>A[i];\n set<int> S;\n S.insert(1);\n for(int i=2;i<1e8+5;i++){\n bool b = true;\n rep(j,N) if(A[j]%i!=0) b = false;\n if(b) S.insert(i);\n }\n for(int x:S) cout<<x<<\"\\n\";\n\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 3440, "score_of_the_acc": -1.2281, "final_rank": 18 }, { "submission_id": "aoj_0583_5294353", "code_snippet": "#include <iostream>\n#include <cstdio>\nusing namespace std;\n\nint main(void){\n int n;\n cin>>n;\n if(n==2){\n long a,b;\n cin>>a>>b;\n for(long i=1;i<100000010;i++){\n if(a%i==0 and b%i==0){\n printf(\"%ld\\n\",i);\n }\n }\n }\n if(n==3){\n long a,b,c;\n cin>>a>>b>>c;\n for(long i=1;i<100000010;i++){\n if(a%i==0 and b%i==0 and c%i==0){\n printf(\"%ld\\n\",i);\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 3232, "score_of_the_acc": -1.0166, "final_rank": 15 }, { "submission_id": "aoj_0583_4741526", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n int n;scanf(\"%d\",&n);\n int num[3];num[2]=1000000007;for(int i=0;i<n;i++)scanf(\"%d \",&num[i]);\n queue<int> gcd;\n for(int i=1;i<=min({num[0],num[1],num[2]});i++)\n {\n bool check=true;\n for(auto j : num)if(j!=1000000007&&j%i!=0)check=false;\n if(check)gcd.push(i);\n }\n while(!gcd.empty()){printf(\"%d\\n\",gcd.front());gcd.pop();}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3228, "score_of_the_acc": -0.6949, "final_rank": 10 }, { "submission_id": "aoj_0583_4596724", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main() {\n long long h[4];\n int a, b, c, ab, cc;\n int i, n;\n long long j, minl, amari;\n\n cin >> n;\n for (i = 0; i < n; i++) {\n cin >> h[i];\n }\n minl = h[0];\n for (i = 1; i < n; i++) {\n if (minl > h[i]) minl = h[i];\n }\n\n for (j = 1; j <= minl; j++) {\n amari = 0;\n for (i = 0; i < n; i++) {\n amari += h[i] % j;\n }\n if (amari == 0) cout << j << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3116, "score_of_the_acc": -0.5411, "final_rank": 5 }, { "submission_id": "aoj_0583_4080498", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint main(){\n int n,a[3],MAX=0;\n cin >> n;\n for(int i=0;i<n;i++){\n cin >> a[i];\n MAX = max(MAX,a[i]);\n }\n for(int i=1;i<=MAX;i++){\n bool dotti=true;\n for(int j=0;j<n;j++){\n if(a[j] % i != 0) dotti = false;\n }\n if(dotti == true) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3112, "score_of_the_acc": -0.5311, "final_rank": 4 }, { "submission_id": "aoj_0583_3810656", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nconst int INF = 1e9;\nconst ll LINF = 1e18;\ninline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }\ninline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << \"(\" << o.first << \",\" << o.second << \")\"; return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<T>& V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << \" \";} return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<vector<T> >& Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const map<S,T>& mp){ out << \"{ \"; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << \":\" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << \", \"; } out << \" }\"; return out; }\ntemplate<typename T>vector<T> make_v(size_t a){return vector<T>(a);}\ntemplate<typename T,typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\n/*\n <url:https://onlinejudge.u-aizu.ac.jp/challenges/sources/JOI/Prelim/0583?year=2006>\n 問題文============================================================\n =================================================================\n 解説=============================================================\n ================================================================\n */\n\ntemplate<class Type>\nType solve(Type res = Type()){\n int n; cin >> n;\n vector<ll> a(n); for(auto& in:a) cin >> in;\n for(int i = 1; i <= 1e8;i++){\n if([&](){\n for(int j = 0; j < n;j++){\n if(a[j]%i != 0) return false;\n }\n return true;\n }()){\n cout << i << endl;\n }\n }\n return res;\n}\nint main(void) {\n cin.tie(0); ios_base::sync_with_stdio(false);\n solve(0);\n // cout << fixed << setprecision(15) << solve<ll>() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 810, "memory_kb": 3224, "score_of_the_acc": -1.0356, "final_rank": 16 }, { "submission_id": "aoj_0583_3519298", "code_snippet": "#include <bits/stdc++.h>\ntypedef long long LL;\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n);\n for (int i = 0; i < n; i ++) cin >> a[i];\n sort(a.begin(), a.end());\n for (int i = 1; i <= a[0]; i ++) {\n bool flag = true;\n for (int j = 0; j < n; j ++) {\n if (a[j] % i != 0) flag = false;\n }\n if (flag) cout << i << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3148, "score_of_the_acc": -0.5819, "final_rank": 8 }, { "submission_id": "aoj_0583_3398398", "code_snippet": "#include<cstdio>\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<map>\n#include<unordered_map>\n#include<stack>\n#include<string>\n#include<algorithm>\n#include<functional>\n#include<cstring>\nusing namespace std;\n\n/**** Type Define ****/\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\n/**** Const List ****/\n\nconst ll INF = (ll)1e18;\nconst ll mod = 1000000007;\nconst ll UNION_FIND_MAX = 100000;\nconst ll SEGMENT_TREE_MAX = (1 << 19) - 1;\nconst ll MAX_FLOW_MAX_V = 10000;\nconst ll MIN_COST_FLOW_MAX_V = 10000;\nconst ll BIPARTITE_MATCHING_MAX_V = 10000;\nconst ll dx[4] = {1, 0, -1, 0};\nconst ll dy[4] = {0, -1, 0, 1};\n\n/**** General Functions ****/\n\ntemplate <typename T>\nT tmin(T a, T b) { return a > b ? b : a; };\n\ntemplate <typename T>\nT tmax(T a, T b) { return a > b ? a : b; };\n\ntemplate <typename T>\nT tadd(T a, T b) { return a + b; };\n\ntemplate <typename T>\nT tmul(T a, T b) { return a * b; };\n\ntemplate <typename T>\nT tpow(T a, T b) { return a * b; };\n\nll gcd(ll a, ll b) {\n if (b == 0) return a;\n return gcd(b, a % b);\n}\n\nll extgcd(ll a, ll b, ll& x, ll& y) {\n if (b == 0) {\n x = 1, y = 0; return a;\n }\n ll q = a/b, g = extgcd(b, a - q*b, x, y);\n ll z = x - q * y;\n x = y;\n y = z;\n return g;\n}\n\nll invmod (ll a, ll m) { // a^-1 mod m\n ll x, y;\n extgcd(a, m, x, y);\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nll nCk(ll n, ll k, ll mod) {\n ll ans = 1;\n for (ll i = n, j = 1; j <= k; i--, j++) ans = (((ans * i) % mod) * invmod(j, mod)) % mod;\n return ans;\n}\n\nll lmin(ll a, ll b) { return a > b ? b : a; };\n\nll lmax(ll a, ll b) { return a > b ? a : b; };\n\n/**** Matrix ****/\n\ntemplate <typename T>\nstruct Matrix {\n typedef vector<T> vec;\n typedef vector<vec> mat;\n ll x, y; // x: horizon y: vertical\n mat d;\n\n Matrix(ll _y, ll _x = -1) {\n if (_x == -1) _x = _y;\n x = _x, y = _y;\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) d[i][j] = 0;\n }\n void unit() {\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) d[i][j] = i == j ? 1 : 0;\n }\n Matrix copy() {\n Matrix m(y, x);\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) m.d[i][j] = d[i][j];\n return m;\n }\n Matrix<T> operator + (Matrix<T>& t) { // No error check! Don't forget to check Matrix size!!\n Matrix<T> m(y, x);\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) m.d[i][j] = d[i][j] + t.d[i][j];\n return m;\n }\n Matrix<T> operator - (Matrix<T>& t) {\n Matrix<T> m(y, x);\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) m.d[i][j] = d[i][j] - t.d[i][j];\n return m;\n }\n Matrix<T> operator * (T t) {\n Matrix<T> m(y, x);\n for (int i = 0; i < y; i++) for (int j = 0; j < x; j++) m.d[i][j] = d[i][j] * t;\n return m;\n }\n Matrix<T> det(Matrix<T>& t) { // x need to correspond to t.y\n Matrix<T> m(y, x);\n for (int i = 0; i < y; i++)\n for (int j = 0; j < x; j++)\n for (int k = 0; k < t.x; k++) m.d[i][j] += d[i][k] * t.d[k][j]; ////////////// mod???\n return m;\n }\n};\n\n/**** Zip ****/\n\ntemplate <typename T>\nclass Zip {\n vector<T> d;\n bool flag;\npublic:\n Zip() {\n flag = false;\n }\n void add(T x) {\n d.push_back(x);\n flag = true;\n }\n ll getNum(T x) { // T need to have operator < !!\n if (flag) {\n sort(d.begin(), d.end());\n d.erase(unique(d.begin(), d.end()), d.end());\n flag = false;\n }\n return lower_bound(d.begin(), d.end(), x) - d.begin();\n }\n ll size() {\n if (flag) {\n sort(d.begin(), d.end());\n d.erase(unique(d.begin(), d.end()), d.end());\n flag = false;\n }\n return (ll)d.size();\n }\n};\n\n/**** Union Find ****/\n\nclass UnionFind {\n vector<ll> par, rank;\npublic:\n void init(ll n) {\n par.resize(n); rank.resize(n, 0);\n for (ll i = 0; i < n; i++) par[i] = i;\n }\n ll find(ll x) {\n if (par[x] == x) return x;\n return par[x] = find(par[x]);\n }\n void merge(ll x, ll y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n if (rank[x] < rank[y]) {\n par[x] = y;\n } else {\n par[y] = x;\n if (rank[x] == rank[y]) rank[x]++;\n }\n }\n bool isSame(ll x, ll y) {\n return find(x) == find(y);\n }\n};\n\ntemplate <typename T>\nstruct UnionFindT {\n vector<ll> par;\n vector<ll> rank;\n vector<T> diff_weight;\n\n UnionFindT(ll n = 1, T SUM_UNITY = 0) {\n init(n, SUM_UNITY);\n }\n\n void init(ll n = 1, T SUM_UNITY = 0) {\n par.resize(n); rank.resize(n); diff_weight.resize(n);\n for (ll i = 0; i < n; ++i) par[i] = i, rank[i] = 0, diff_weight[i] = SUM_UNITY;\n }\n\n ll find(ll x) {\n if (par[x] == x) {\n return x;\n }\n else {\n ll r = find(par[x]);\n diff_weight[x] += diff_weight[par[x]];\n return par[x] = r;\n }\n }\n\n T weight(ll x) {\n find(x);\n return diff_weight[x];\n }\n\n bool isSame(ll x, ll y) {\n return find(x) == find(y);\n }\n\n bool merge(ll x, ll y, T w) {\n w += weight(x); w -= weight(y);\n x = find(x); y = find(y);\n if (x == y) return false;\n if (rank[x] < rank[y]) swap(x, y), w = -w;\n if (rank[x] == rank[y]) ++rank[x];\n par[y] = x;\n diff_weight[y] = w;\n return true;\n }\n\n T diff(ll x, ll y) {\n return weight(y) - weight(x);\n }\n};\n\nclass PersistentUnionFind {\n vector<ll> rank, fin, par;\n ll index;\npublic:\n void init(ll n) {\n index = 0;\n par.resize(n); rank.resize(n, 1); fin.resize(n, 0);\n for (ll i = 0; i < n; i++) par[i] = i;\n }\n ll find(ll x, ll t) {\n if (t >= fin[x] && par[x] != x) return find(par[x], t);\n return x;\n }\n void merge(ll x, ll y) {\n x = find(x, index);\n y = find(y, index);\n index++;\n if (x == y) return;\n if (rank[x] < rank[y]) par[x] = y, fin[x] = index;\n else {\n par[y] = x, fin[y] = index;\n if (rank[x] == rank[y]) rank[x]++;\n }\n }\n bool isSame(ll x, ll y, ll t) { return find(x, t) == find(y, t); }\n};\n\n/**** Segment Tree ****/\n\ntemplate <typename T>\nclass SegmentTree {\n ll n;\n vector<T> node;\n function<T(T, T)> fun, fun2;\n bool customChange;\n T outValue, initValue;\npublic:\n void init(ll num, function<T(T, T)> resultFunction, T init, T out, function<T(T, T)> changeFunction = NULL) {\n // changeFunction: (input, beforevalue) => newvalue\n fun = resultFunction;\n fun2 = changeFunction;\n customChange = changeFunction != NULL;\n n = 1;\n while (n < num) n *= 2;\n node.resize(2 * n - 1, init);\n outValue = out;\n initValue = init;\n }\n void valueChange(ll num, T value) {\n num += n-1;\n if (customChange) node[num] = fun2(value, node[num]);\n else node[num] = value;\n while (num > 0) num = (num - 1) / 2, node[num] = fun(node[num * 2 + 1], node[num * 2 + 2]);\n }\n T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n if (r == -1) r = n;\n if (a <= l && r <= b) return node[k];\n if (b <= l || r <= a) return outValue;\n ll mid = (l + r) / 2;\n return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n }\n};\n\ntemplate <typename T>\nclass LazySegmentTree {\n ll n;\n vector<T> node;\n vector<T> lazyNode;\n function<T(T, T)> fun, fun2;\n function<T(T, ll)> fun3;\n T outValue, initValue;\n T substitution(T a, T b) { return a; }\n void eval(ll k, ll l, ll r) {\n if (lazyNode[k] == 0) return;\n node[k] = fun2(fun3(lazyNode[k], r - l), node[k]);\n if (r - l > 1) {\n lazyNode[2 * k + 1] = fun2(lazyNode[k], lazyNode[2 * k + 1]);\n lazyNode[2 * k + 2] = fun2(lazyNode[k], lazyNode[2 * k + 2]);\n }\n lazyNode[k] = initValue;\n }\npublic:\n void init(ll num, function<T(T, T)> resultFunction, function<T(T, T)> changeFunction, function<T(T, ll)> lazyFunction, T init, T out) {\n // changeFunction: (input, beforevalue) => newvalue\n // lazyFunction: (lazyNode, diff) => newvalue\n fun = resultFunction;\n fun2 = changeFunction;\n fun3 = lazyFunction;\n n = 1;\n while (n < num) n *= 2;\n node.resize(2 * n - 1, init);\n lazyNode.resize(2 * n - 1, init);\n outValue = out;\n initValue = init;\n }\n void rangeChange(ll a, ll b, T value, ll l = 0, ll r = -1, ll k = 0) {\n if (r == -1) r = n;\n eval(k, l, r);\n if (b <= l || r <= a) return;\n if (a <= l && r <= b) {\n lazyNode[k] = fun2(value, lazyNode[k]);\n eval(k, l, r);\n } else {\n ll mid = (l + r) / 2;\n rangeChange(a, b, value, l, mid, 2*k+1);\n rangeChange(a, b, value, mid, r, 2*k+2);\n node[k] = fun(node[2*k+1], node[2*k+2]);\n }\n }\n T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n if (r == -1) r = n;\n if (b <= l || r <= a) return outValue;\n eval(k, l, r);\n if (a <= l && r <= b) return node[k];\n ll mid = (l + r) / 2;\n return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n }\n};\n\n/**** Network Flow ****/\n\nclass MaxFlow {\npublic:\n struct edge { ll to, cap, rev; };\n\n vector<edge> G[MAX_FLOW_MAX_V];\n bool used[MAX_FLOW_MAX_V];\n ll level[MAX_FLOW_MAX_V];\n ll iter[MAX_FLOW_MAX_V];\n \n void init() {\n for (ll i = 0; i < MAX_FLOW_MAX_V; i++) {\n G[i].clear();\n }\n }\n void add_edge(ll from, ll to, ll cap) {\n G[from].push_back((edge){to, cap, (ll)G[to].size()});\n G[to].push_back((edge){from, 0, (ll)G[from].size() - 1});\n }\n void add_undirected_edge(ll e1, ll e2, ll cap) {\n G[e1].push_back((edge){e2, cap, (ll)G[e2].size()});\n G[e2].push_back((edge){e1, cap, (ll)G[e1].size() - 1});\n }\n ll dfs(ll v, ll t, ll f) {\n if (v == t) return f;\n used[v] = true;\n for (ll i = 0; i < (ll)G[v].size(); i++) {\n edge &e = G[v][i];\n if (!used[e.to]&& e.cap > 0) {\n ll d = dfs(e.to, t, min(f, e.cap));\n if (d > 0) {\n e.cap -= d;\n G[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n ll max_flow(ll s, ll t) {\n ll flow = 0;\n while (1) {\n memset(used, 0, sizeof(used));\n ll f = dfs(s, t, INF);\n if (f == 0) return flow;\n flow += f;\n }\n }\n void bfs(ll s) {\n memset(level, -1, sizeof(level));\n queue<ll> que;\n level[s] = 0;\n que.push(s);\n while (!que.empty()) {\n ll v = que.front(); que.pop();\n for (ll i = 0; i < (ll)G[v].size(); i++) {\n edge &e = G[v][i];\n if (e.cap > 0 && level[e.to] < 0) {\n level[e.to] = level[v] + 1;\n que.push(e.to);\n }\n }\n }\n }\n ll dinic_dfs(ll v, ll t, ll f) {\n if (v == t) return f;\n for (ll &i= iter[v]; i < (ll)G[v].size(); i++) {\n edge &e = G[v][i];\n if (e.cap > 0 && level[v] < level[e.to]) {\n ll d = dinic_dfs(e.to, t, min(f, e.cap));\n if (d > 0) {\n e.cap -= d;\n G[e.to][e.rev].cap += d;\n return d;\n }\n }\n }\n return 0;\n }\n ll dinic(ll s, ll t) {\n ll flow = 0;\n while (1) {\n bfs(s);\n if (level[t] < 0) return flow;\n memset(iter, 0, sizeof(iter));\n ll f;\n while ((f = dinic_dfs(s, t, INF)) > 0) {\n flow += f;\n }\n }\n }\n};\n\n/**** bipartite matching ****/\n\nclass BipartiteMatching {\npublic:\n ll V;\n vector<ll> G[BIPARTITE_MATCHING_MAX_V];\n ll match[BIPARTITE_MATCHING_MAX_V];\n bool used[BIPARTITE_MATCHING_MAX_V];\n \n BipartiteMatching(ll v) {\n V = v;\n }\n void init(ll v) {\n V = v;\n for (ll i = 0; i < BIPARTITE_MATCHING_MAX_V; i++) {\n G[i].clear();\n }\n }\n void add_edge(ll u, ll v) {\n G[u].push_back(v);\n G[v].push_back(u);\n }\n bool dfs(ll v) {\n used[v] = true;\n for (ll i = 0; i < (ll)G[v].size(); i++) {\n ll u = G[v][i], w = match[u];\n if (w < 0 || !used[w] && dfs(w)) {\n match[v] = u;\n match[u] = v;\n return true;\n }\n }\n return false;\n }\n ll max_matching() {\n ll res = 0;\n memset(match, -1, sizeof(match));\n for (ll v = 0; v < V;v++) {\n if (match[v] < 0) {\n memset(used, 0, sizeof(used));\n if (dfs(v)) {\n res++;\n }\n }\n }\n return res;\n }\n};\n\nclass MinCostFlow {\npublic:\n struct edge { ll to, cap, cost, rev; };\n\n ll V;\n vector<edge> G[MIN_COST_FLOW_MAX_V];\n ll dist[MIN_COST_FLOW_MAX_V];\n ll prevv[MIN_COST_FLOW_MAX_V];\n ll preve[MIN_COST_FLOW_MAX_V];\n ll h[MIN_COST_FLOW_MAX_V];\n\n MinCostFlow(ll v) {\n V = v;\n }\n void init() {\n for (ll i = 0; i < MAX_FLOW_MAX_V; i++) {\n G[i].clear();\n }\n }\n void add_edge(ll from, ll to, ll cap, ll cost) {\n G[from].push_back((edge){to, cap, cost, (ll)G[to].size()});\n G[to].push_back((edge){from, 0, -cost, (ll)G[from].size() - 1});\n }\n void add_undirected_edge(ll e1, ll e2, ll cap, ll cost) {\n add_edge(e1, e2, cap, cost);\n add_edge(e2, e1, cap, cost);\n }\n ll min_cost_flow(ll s, ll t, ll f) { // minas\n ll res = 0;\n while (f > 0) {\n fill(dist, dist + V, INF);\n dist[s] = 0;\n bool update = true;\n while (update) {\n update = false;\n for (ll v = 0; v < V; v++) {\n if (dist[v] == INF) continue;\n for (ll i = 0; i < (ll)G[v].size(); i++) {\n edge &e = G[v][i];\n if (e.cap > 0 && dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n prevv[e.to] = v;\n preve[e.to] = i;\n update = true;\n }\n }\n }\n }\n if (dist[t] == INF) {\n return -1;\n }\n ll d = f;\n for (ll v = t; v != s; v = prevv[v]) {\n d = min(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * dist[t];\n for (ll v = t; v != s; v = prevv[v]) {\n edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n }\n return res;\n }\n ll min_cost_flow_dijkstra(ll s, ll t, ll f) {\n ll res = 0;\n fill(h, h + V, 0);\n while (f > 0) {\n priority_queue<P, vector<P>, greater<P> > que;\n fill(dist, dist + V, 0);\n dist[s] = 0;\n que.push(P(0, s));\n while (!que.empty()) {\n P p = que.top(); que.pop();\n int v = p.second;\n if (dist[v] < p.first) continue;\n for (int i = 0; i < G[v].size(); i++) {\n edge &e = G[v][i];\n if (e.cap > 0 && dist[e.to] > dist[v] + e.cost + h[v] - h[e.to]) {\n dist[e.to] = dist[v] + e.cost + h[v] - h[e.to];\n prevv[e.to] = v;\n preve[e.to] = i;\n que.push(P(dist[e.to], e.to));\n }\n }\n }\n if (dist[t] == INF) {\n return -1;\n }\n for (int v = 0; v < V; v++) h[v] += dist[v];\n int d = f;\n for (int v = t; v != s; v = prevv[v]) {\n d = tmin<ll>(d, G[prevv[v]][preve[v]].cap);\n }\n f -= d;\n res += d * h[t];\n for (int v = t; v != s; v = prevv[v]) {\n edge &e = G[prevv[v]][preve[v]];\n e.cap -= d;\n G[v][e.rev].cap += d;\n }\n return res;\n }\n return 0;\n }\n};\n\n/**** LIS ****/\nll lis(ll* a, ll n, ll* dp) {\n fill(dp, dp + n, INF);\n for (ll i = 0; i < n; i++) *lower_bound(dp, dp + n, a[i]) = a[i];\n return (ll)(lower_bound(dp, dp + n, INF) - dp);\n}\n\n/**** Kruskal ****/\n\n/**** main function ****/\n\nll n, a[3];\n\nint main() {\n scanf(\"%lld\", &n);\n ll minn = INF;\n for (ll i = 0; i < n; i++) scanf(\"%lld\", &a[i]), minn = lmin(minn, a[i]);\n for (ll i = 1; i <= minn; i++) {\n bool ok = true;\n for (ll j = 0; j < n; j++) if (a[j] % i) ok = false;\n if (ok) printf(\"%lld\\n\", i);\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2736, "score_of_the_acc": -0.0043, "final_rank": 1 }, { "submission_id": "aoj_0583_3073348", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include<bits/stdc++.h>\n#define INF 1e9\n#define EPS 1e-9\n#define REP(i,n) for(lint i=0,i##_len=(n);i<i##_len;++i)\n#define REP1(i,n) for(lint i=1,i##_len=(n);i<=i##_len;++i)\n#define REPR(i,n) for(lint i=(n)-1;i>=0;--i)\n#define REPR1(i,n) for(lint i=(n);i>0;--i)\n#define REPC(i,obj) for(auto i:obj)\n#define R_UP(a,b) (((a)+(b)-1)/(b))\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SETP cout << fixed << setprecision(8)\nusing namespace std;\nusing lint = long long;\ntemplate<typename T = lint>inline T in() { T x; cin >> x; return x; }\n\nsigned main()\n{\n\tint n = in();\n\tif (n == 2)\n\t{\n\t\tint a = in(), b = in();\n\t\tREP1(i, min(a, b))if (a % i == 0 && b % i == 0)cout << i << endl;\n\t}\n\telse\n\t{\n\t\tint a = in(), b = in(), c = in();\n\t\tREP1(i, min({ a,b,c }))if (a % i == 0 && b % i == 0 && c % i == 0)cout << i << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.5028, "final_rank": 2 }, { "submission_id": "aoj_0583_3041349", "code_snippet": "#include<iostream>\nusing namespace std;\nint n,a[3];\nmain()\n{\n cin>>n;int M=0;\n for(int i=0;i<n;i++)\n {\n cin>>a[i];\n if(M<a[i])M=a[i];\n }\n for(int i=1;i<=M;i++)\n {\n bool f=1;\n for(int j=0;j<n;j++)f&=a[j]%i<1;\n if(f)cout<<i<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3096, "score_of_the_acc": -0.5085, "final_rank": 3 }, { "submission_id": "aoj_0583_3015876", "code_snippet": "#include <iostream>\n#include <algorithm>\n\nint main()\n{\n int a;\n std::cin>>a;\n int b[a];\n for(int i=0;i<a;i++){\n std::cin>>b[i];\n }\n std::sort(b, b + a);\n\n for(int j=1;j<=b[0];j++){\n bool cler=true;\n for(int i=0;i<a;i++){\n if(b[i]%j!=0) cler=false;\n }\n if(cler==true) std::cout << j<<std::endl;\n }\n\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3124, "score_of_the_acc": -0.548, "final_rank": 7 } ]
aoj_0584_cpp
問題 3 入力ファイルの1行目に正整数 n (n≧3)が書いてあり, つづく n 行に異なる正整数 a 1 , ..., a n が 1つずつ書いてある. a 1 , ..., a n から異なる2個を選んで作られる 順列を(数として見て)小さい順に並べたとき, 3番目に来るものを出力せよ. ただし, 例えば,a 1 = 1,a 4 = 11 のような場合も, a 1 a 4 と a 4 a 1 は異なる順列とみなす. また, 1≦a i ≦10000 (i=1, ..., n) かつ 3≦n≦10 4 である. 出力ファイルにおいては, 出力の最後にも改行コードを入れること. 入出力例 入力例1 3 2 7 5 出力例1 52 入力例2 4 17 888 1 71 出力例2 171 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0584_10125289", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vector<ll> A(N);\n vector<int> B(4,2e9);\n rep(i,N)cin>>A[i];\n rep(i,N)rep(j,N)if(i!=j){\n int t=stoi(to_string(A[i])+to_string(A[j]));\n B[3]=t;\n for(int k=2;k>=0;k--)if(B[k]>B[k+1])swap(B[k],B[k+1]); \n \n }\n cout<<B[2]<<endl;\n}", "accuracy": 1, "time_ms": 7980, "memory_kb": 3568, "score_of_the_acc": -1.025, "final_rank": 18 }, { "submission_id": "aoj_0584_9688688", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#ifdef LOCAL\n #include \"settings/debug.cpp\"\n#else\n #define Debug(...) void(0)\n#endif\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing ll = long long;\nusing ull = unsigned long long;\n\nint main() {\n int n;\n cin >> n;\n vector<int> a(n);\n rep(i, n) cin >> a[i];\n vector<int> ans;\n rep(i, n) rep(j, n) {\n if (i == j) continue;\n ans.push_back(stoi(to_string(a[i]) + to_string(a[j])));\n sort(ans.begin(), ans.end());\n while (ans.size() > 3) ans.pop_back();\n }\n cout << ans[2] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 2010, "memory_kb": 3456, "score_of_the_acc": -0.2693, "final_rank": 11 }, { "submission_id": "aoj_0584_9180545", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint main(){\n int n, x;\n const int t = 4;\n cin >> n;\n string b[t];\n vector<int> a, c;\n\n for (int i = 0; i < n; i++){\n cin >> x;\n a.push_back(x);\n sort(a.begin(), a.end());\n }\n for (int j = 0; j < t; j++){\n b[j] = to_string(a[j]);\n }\n for (int j = 0; j < t; j++){\n for (int k = 0; k < t; k++){\n if (j != k) c.push_back(stoi(b[j]+b[k]));\n }\n sort(c.begin(), c.end());\n }\n cout << c[2] << endl;\n \n}", "accuracy": 1, "time_ms": 690, "memory_kb": 3508, "score_of_the_acc": -0.1067, "final_rank": 6 }, { "submission_id": "aoj_0584_7031425", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n\nusing namespace std;\n\nint func(int, int);\n\nint main() {\n int n;\n cin >> n;\n\n int a[n];\n for (int &i: a) cin >> i;\n\n int ab, ba;\n pair<int, int> aa[3];\n aa[0].first = 1 << 29;\n aa[1].first = 1 << 29;\n aa[2].first = 1 << 29;\n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n ab = func(a[i], a[j]);\n ba = func(a[j], a[i]);\n sort(aa, aa + 3, greater<>());\n for (auto &k: aa) {\n if (ab < k.first) {\n k.first = ab;\n k.second = 1;\n break;\n } else if (ab == k.first) {\n k.second++;\n break;\n }\n }\n sort(aa, aa + 3, greater<>());\n for (auto &k: aa) {\n if (ba < k.first) {\n k.first = ba;\n k.second = 1;\n break;\n } else if (ba == k.first) {\n k.second++;\n break;\n }\n }\n }\n }\n\n sort(aa, aa + 3);\n\n int ans, k = 0;\n while (1) {\n for (int i = 0; i < 3; i++) {\n for (int j = 0; j < aa[i].second; j++) {\n ans = aa[i].first;\n k++;\n if (k == 3) goto outer;\n }\n }\n }\n outer:\n\n cout << ans << endl;\n}\n\nint func(int a, int b) {\n int ab, d;\n d = log10(b) + 1;\n if (d == 5) {\n ab = a * 100000 + b;\n } else if (d == 4) {\n ab = a * 10000 + b;\n } else if (d == 3) {\n ab = a * 1000 + b;\n } else if (d == 2) {\n ab = a * 100 + b;\n } else {\n ab = a * 10 + b;\n }\n return ab;\n}", "accuracy": 1, "time_ms": 1390, "memory_kb": 3684, "score_of_the_acc": -0.205, "final_rank": 9 }, { "submission_id": "aoj_0584_6536198", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto N=in();\n\tvector<string> A=vecin<string>(N);\n\tauto comp=[](string& l,string& r){return (l.size()==r.size())?l<r:l.size()<r.size();};\n\tpriority_queue<string,vector<string>,decltype(comp)> Q(comp);\n\n\tll C=0;\n\tREP(i,N){\n\t\tREP(j,N){\n\t\t\tif(i==j) continue;\n\t\t\tif(C<3){\n\t\t\t\tQ.push(A[i]+A[j]);\n\t\t\t\tC++;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tauto V=Q.top();\n\t\t\t\tQ.pop();\n\t\t\t\tauto T=A[i]+A[j];\n\t\t\t\tif(comp(V,T)) Q.push(V);\n\t\t\t\telse Q.push(T);\n\t\t\t}\n\t\t}\n\t}\n\tout(Q.top());\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3800, "memory_kb": 3400, "score_of_the_acc": -0.4905, "final_rank": 16 }, { "submission_id": "aoj_0584_6308481", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n vector<int> a(n),b,d={1,10,100,1000,10000,100000};\n in(a);\n sort(all(a));\n multiset<int> S;\n for(int i=0;i<n;i++){\n int mul=*upper_bound(all(d),a[i]);\n for(int j=0;j<n;j++){\n if(i==j)continue;\n S.insert(a[j]*mul+a[i]);\n if(S.size()>=4){\n S.erase(S.find(*S.rbegin()));\n }\n }\n }\n out(*S.rbegin());\n}", "accuracy": 1, "time_ms": 1270, "memory_kb": 3460, "score_of_the_acc": -0.1767, "final_rank": 7 }, { "submission_id": "aoj_0584_5933208", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1e18;\nconst ll MOD = INF;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nll gcd(ll a, ll b) {return (b == 0 ? a : gcd(b, a % b));}\nint main() {\n\tll N; cin >> N;\n\tvector<string>S(N); input_arr(S, N);\n \tsort(S.begin(),S.end());\n\tvector<string>A;\n\tfor (ll i = 0; i < N; i++) {\n\t\tfor (ll j = 0; j < min(N, 500LL); j++) {\n\t\t\tif (i == j) continue;\n\t\t\tstring T = S[i];\n\t\t\tfor (char ch : S[j]) T.push_back(ch);\n\t\t\tA.push_back(T);\n\t\t}\n\t}\n\tsort(A.begin(), A.end(),[](string& a, string& b){\n\t\treturn stoi(a) < stoi(b);\n\t});\n\tcout << A[2] << endl;\n}", "accuracy": 0.6, "time_ms": 740, "memory_kb": 19952, "score_of_the_acc": -1.0916, "final_rank": 20 }, { "submission_id": "aoj_0584_4723161", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N;\nvector<int> DataInfo;\n\nvoid solve() {\n\tint aF, aR, num;\n\tstringstream ss;\n\tmultiset<int> result;\n\tmultiset<int>::iterator pos;\n\n\tfor (int i = 0; i < 2; ++i) {\n\t\taF = DataInfo[i];\n\t\tfor (int j = i + 1; j < N; ++j) {\n\t\t\taR = DataInfo[j];\n\t\t\tss.clear();\n\t\t\tss << aF << aR;\n\t\t\tss >> num;\n\t\t\t//cout << \"1:\" << num << endl;\n\t\t\tresult.insert(num);\n\t\t\tss.clear();\n\t\t\tss << aR << aF;\n\t\t\tss >> num;\n\t\t\t//cout << \"2:\" << num << endl;\n\t\t\tresult.insert(num);\n\t\t}\n\t}\n\n\tpos = result.begin();\n\tadvance(pos, 2);\n\tcout << *pos << endl;\n}\n\nint main() {\n\tint num;\n\n\tcin >> N;\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> num;\n\t\tDataInfo.push_back(num);\n\t}\n\tsort(DataInfo.begin(), DataInfo.end());\n\tsolve();\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4768, "score_of_the_acc": -0.0964, "final_rank": 5 }, { "submission_id": "aoj_0584_4083527", "code_snippet": "#include <bits/stdc++.h>\n\n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n// #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-10)\n \n int dx[8]={0,-1,0,1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x,y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tdouble x;\n \tint y,z,w;\n \tpa4(double x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n/*\n class Point{\n \tpublic:\n \tdouble x,y;\n \tPoint(double x=0,double y=0):x(x),y(y) {}\n \tPoint operator + (Point p) {return Point(x+p.x,y+p.y);}\n \tPoint operator - (Point p) {return Point(x-p.x,y-p.y);}\n \tPoint operator * (double a) {return Point(x*a,y*a);}\n \tPoint operator / (double a) {return Point(x/a,y/a);}\n \tdouble absv() {return sqrt(norm());}\n \tdouble norm() {return x*x+y*y;}\n \tbool operator < (const Point &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const Point &p) const{\n \t\treturn fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n \t}\n };\n typedef Point Vector;\n #define pl pair<int,pas>\n struct Segment{\n Point p1,p2;\n };\n double dot(Vector a,Vector b){\n \treturn a.x*b.x+a.y*b.y;\n }\n double cross(Vector a,Vector b){\n \treturn a.x*b.y-a.y*b.x;\n }\n \n bool parareru(Point a,Point b,Point c,Point d){\n //\tif(abs(cross(a-b,d-c))<EPS)cout<<\"dd \"<<cross(a-b,d-c)<<endl;\n \treturn abs(cross(a-b,d-c))<EPS;\n }\n double distance_ls_p(Point a, Point b, Point c) {\n if ( dot(b-a, c-a) < EPS ) return (c-a).absv();\n if ( dot(a-b, c-b) < EPS ) return (c-b).absv();\n return abs(cross(b-a, c-a)) / (b-a).absv();\n }\n bool is_intersected_ls(Segment a,Segment b) {\n \tif(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;\n \tif(parareru((a.p2),(a.p1),(a.p1),(b.p2))&&parareru((a.p2),(a.p1),(a.p1),(b.p1))){\n //\t\tcout<<\"sss\"<<endl;\n \t\tif(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;\n \t\tif(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;\n \t\tif(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;\n \t\tif(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;\n \t\treturn false;\n \t}\n else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );\n }\n \n double segment_dis(Segment a,Segment b){\n \tif(is_intersected_ls(a,b))return 0;\n \tdouble r=distance_ls_p(a.p1, a.p2, b.p1);\n \tr=min(r,distance_ls_p(a.p1, a.p2, b.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p1));\n \treturn r;\n }\n Point intersection_ls(Segment a, Segment b) {\n Point ba = b.p2-b.p1;\n double d1 = abs(cross(ba, a.p1-b.p1));\n double d2 = abs(cross(ba, a.p2-b.p1));\n double t = d1 / (d1 + d2);\n \n return a.p1 + (a.p2-a.p1) * t;\n }\n */ \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n double distans(double x1,double y1,double x2,double y2){\n \tdouble rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n \treturn sqrt(rr);\n \t\n }\n int mod;\n \n int pr[500010];\n int inv[500010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \tif(rr%2==1) return (beki(wa,rr-1,warukazu)*wa)%warukazu;\n \tint zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n double bekid(double w,int r){\n \tif(r==0) return 1.0;\n \tif(r==1) return w;\n \tif(r%2) return bekid(w,r-1)*w;\n \tdouble f=bekid(w,r/2);\n \treturn f*f;\n }\n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \tfor(int i=0;i<ert;i++) inv[i]=beki(pr[i],mod-2,mod);\n \t\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n //----------------kokomade tenpure------------\n //vector<double> ans(100000000),ans2(100000000)\n \n\n\nint h(int a,int b){\n\treturn stoi(itos(a)+itos(b));\n}\n\n signed main(){\n \t cin.tie(0);\n \t\t\tios::sync_with_stdio(false);\n\nint n;\n \tcin>>n;\n \tvector<int> ve(n);\n \tfor(int i=0;i<n;i++)cin>>ve[i];\n\n \tsort(ve.begin(),ve.end());\n \t\n \tset<pa3> ans;\n \tfor(int i=0;i<n;i++)for(int j=0;j<3;j++)if(i!=j){\n \t\tans.insert((pa3){h(ve[i],ve[j]),i,j});\n \t\t\t\tans.insert((pa3){h(ve[j],ve[i]),j,i});\n \n \t}\n \tauto it=ans.begin();\n \tit++;\n \tit++;\n \tcout<<(*it).x<<endl;\n \treturn 0;\n }", "accuracy": 1, "time_ms": 40, "memory_kb": 6172, "score_of_the_acc": -0.1837, "final_rank": 8 }, { "submission_id": "aoj_0584_3939254", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint main() {\n\tint n;\n\tcin >> n;\n\tvector<int> a(n), b;\n\tfor (int& i : a) cin >> i;\n\tsort(a.begin(), a.end());\n\tif (1000 < a.size()) a.erase(1000 + a.begin(), a.end());\n\tfor (int i = 0; i < a.size() - 1; ++i) {\n\t\tfor (int j = 1 + i; j < a.size(); ++j) {\n\t\t\tb.push_back(stoi(to_string(a[i]) + to_string(a[j])));\n\t\t\tb.push_back(stoi(to_string(a[j]) + to_string(a[i])));\n\t\t}\n\t}\n\tsort(b.begin(), b.end());\n\tcout << b[2] << endl;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 7036, "score_of_the_acc": -0.264, "final_rank": 10 }, { "submission_id": "aoj_0584_3810662", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nconst int INF = 1e9;\nconst ll LINF = 1e18;\ninline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }\ninline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << \"(\" << o.first << \",\" << o.second << \")\"; return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<T>& V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << \" \";} return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<vector<T> >& Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const map<S,T>& mp){ out << \"{ \"; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << \":\" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << \", \"; } out << \" }\"; return out; }\ntemplate<typename T>vector<T> make_v(size_t a){return vector<T>(a);}\ntemplate<typename T,typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename enable_if<is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\n/*\n <url:https://onlinejudge.u-aizu.ac.jp/challenges/sources/JOI/Prelim?year=2006>\n 問題文============================================================\n =================================================================\n 解説=============================================================\n ================================================================\n */\n\ntemplate<class Type>\nType solve(Type res = Type()){\n int n; cin >> n;\n vector<ll> a(n); for(auto& in:a) cin >> in;\n sort(a.begin(),a.end());\n \n vector<ll> ts;\n for(int i = 0; i < min(100,n);i++){\n for(int j = 0; j < n;j++){\n if(i==j)continue;\n string t = to_string(a[i]) + to_string(a[j]);\n ts.push_back(atoll(t.c_str()));\n }\n }\n sort(ts.begin(),ts.end());\n res = ts[2];\n return res;\n}\nint main(void) {\n cin.tie(0); ios_base::sync_with_stdio(false);\n // solve(0);\n cout << fixed << setprecision(15) << solve<ll>() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 11300, "score_of_the_acc": -0.509, "final_rank": 17 }, { "submission_id": "aoj_0584_3480586", "code_snippet": "#define _USE_MATH_DEFINES\n\n#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <cmath>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <map>\n\nusing namespace std;\n\ntypedef pair<long long int, long long int> P;\n\nlong long int INF = 1e18;\nlong long int MOD = 1e9 + 7;\n\nint dig[11000];\nint a[11000];\n\nint main(){\n int n;\n cin >> n;\n int t[6] = {1, 10, 100, 1000, 10000, 100000};\n for(int i = 0; i < n; i++){\n cin >> a[i];\n for(int j = 0; j < 5; j++){\n if(a[i] >= t[j]){\n dig[i] = j;\n }\n }\n }\n long long int n1 = INF, n2 = INF, n3 = INF;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < n; j++){\n if(i == j){\n continue;\n }\n long long int num = a[i] * t[dig[j] + 1] + a[j];\n if(num < n1){\n n3 = n2;\n n2 = n1;\n n1 = num;\n }else if(num < n2){\n n3 = n2;\n n2 = num;\n }else if(num < n3){\n n3 = num;\n }\n }\n }\n cout << n3 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3156, "score_of_the_acc": -0.0093, "final_rank": 1 }, { "submission_id": "aoj_0584_3382637", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <vector>\nusing namespace std;\n\nint main()\n{\t\n\tconst int INF = 1000010001;\n\tint n;\n\tint c[3] = { INF, INF, INF };\n\n\tcin >> n;\n\n\tvector<int> a(n);\n\n\tfor (int i = 0; i < n; i++)\n\t\tcin >> a[i];\n\n\tsort(a.begin(), a.end());\n\n\tint u = 0;\n\twhile (u < n && a[u] < a[2] * 10)\n\t\tu++;\n\n\tfor (int i = 0; i < u; i++) {\n\t\tfor (int j = 0; j < u; j++) {\n\t\t\tif (i != j) {\n\t\t\t\tint b = a[j], k = 0;\n\n\t\t\t\twhile (b /= 10)\n\t\t\t\t\tk++;\n\n\t\t\t\tint w = a[i] * (int)pow(10, k + 1) + a[j];\n\t\t\t\tif (c[2] > w) {\n\t\t\t\t\tc[2] = w;\n\t\t\t\t\tsort(c, c + 3);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << c[2] << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3320, "memory_kb": 3320, "score_of_the_acc": -0.4255, "final_rank": 12 }, { "submission_id": "aoj_0584_3382626", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <vector>\nusing namespace std;\n\nint main()\n{\t\n\tconst int INF = 1000010001;\n\tint n;\n\tint c[3] = { INF, INF, INF };\n\n\tcin >> n;\n\n\tvector<int> a(n);\n\n\tfor (int i = 0; i < n; i++)\n\t\tcin >> a[i];\n\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tif (i != j) {\n\t\t\t\tint b = a[j], k = 0;\n\n\t\t\t\twhile (b /= 10)\n\t\t\t\t\tk++;\n\n\t\t\t\tint w = a[i] * (int)pow(10, k + 1) + a[j];\n\t\t\t\tif (c[2] > w) {\n\t\t\t\t\tc[2] = w;\n\t\t\t\t\tsort(c, c + 3);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << c[2] << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3340, "memory_kb": 3340, "score_of_the_acc": -0.4292, "final_rank": 13 }, { "submission_id": "aoj_0584_3152067", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,a,b) for(int i=a;i<(b);++i)\n#define erep(i,a,b) for(int i=a;i<=(int)(b);++i)\n#define per(i,a,b) for(int i=(a);i>(b);--i)\n#define eper(i,a,b) for(int i=(a);i>=b;--i)\n#define pb push_back\n#define mp make_pair\n#define INF 100100100100\n#define MOD 1000000007\n#define all(x) (x).begin(),(x).end()\n#define vii vector<int>\n#define vll vector<long long>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> Pii;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }\nint dy[]={0, 0, 1, -1};\nint dx[]={1, -1, 0, 0};\nint gcd(int a,int b){return b?gcd(b,a%b):a;}\nint lcm(int a,int b){return a/gcd(a, b)*b;}\n\nbool cmp(string a, string b) {\n return stoi(a) < stoi(b);\n}\n\nint n;\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cin >> n;\n vector<string> a(n), ans;\n rep(i, 0, n) cin >> a[i];\n sort(all(a), cmp);\n rep(i, 1, n) {\n ans.pb(a[0] + a[i]);\n ans.pb(a[i] + a[0]);\n }\n sort(all(ans), cmp);\n cout << ans[2] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4360, "score_of_the_acc": -0.0734, "final_rank": 4 }, { "submission_id": "aoj_0584_3073391", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include<bits/stdc++.h>\n#define INF 1e9\n#define EPS 1e-9\n#define REP(i,n) for(lint i=0,i##_len=(n);i<i##_len;++i)\n#define REP1(i,n) for(lint i=1,i##_len=(n);i<=i##_len;++i)\n#define REPR(i,n) for(lint i=(n)-1;i>=0;--i)\n#define REPR1(i,n) for(lint i=(n);i>0;--i)\n#define REPC(i,obj) for(auto i:obj)\n#define R_UP(a,b) (((a)+(b)-1)/(b))\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SETP cout << fixed << setprecision(8)\nusing namespace std;\nusing lint = long long;\ntemplate<typename T = lint>inline T in() { T x; cin >> x; return x; }\nint digits(int arg)\n{\n\tint result = 0;\n\twhile (arg != 0)\n\t{\n\t\targ /= 10;\n\t\tresult++;\n\t}\n\treturn result;\n}\nsigned main()\n{\n\tint n = in();\n\tvector<int>nums(n); REP(i, n)cin >> nums[i];\n\tint mines[3] = { 1000010001,1000010001,1000010001 };\n\tREP(i, n)\n\t{\n\t\tREP(j, n)\n\t\t{\n\t\t\tif (i == j)continue;\n\t\t\tint temp_i = nums[i];\n\t\t\tREP(i, digits(nums[j]))temp_i *= 10;\n\t\t\tint result = temp_i + nums[j];\n\t\t\tif (result < mines[0])\n\t\t\t{\n\t\t\t\tmines[2] = mines[1];\n\t\t\t\tmines[1] = mines[0];\n\t\t\t\tmines[0] = result;\n\t\t\t}\n\t\t\telse if (result < mines[1])\n\t\t\t{\n\t\t\t\tmines[2] = mines[1];\n\t\t\t\tmines[1] = result;\n\t\t\t}\n\t\t\telse if (result < mines[2])\n\t\t\t{\n\t\t\t\tmines[2] = result;\n\t\t\t}\n\t\t}\n\t}\n\tcout << mines[2] << endl;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 3148, "score_of_the_acc": -0.0402, "final_rank": 3 }, { "submission_id": "aoj_0584_3041459", "code_snippet": "#include<iostream>\n#include<vector>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint n;\nstring s[10000];\nmain()\n{\n int a=1e9,b=1e9,c=1e9;\n cin>>n;\n for(int i=0;i<n;i++)cin>>s[i];\n for(int i=0;i<n;i++)for(int j=0;j<n;j++)\n {\n if(i==j)continue;\n int n=stoi(s[i]+s[j]);\n if(a>n)\n {\n c=b;b=a;a=n;\n }\n else if(b>n)\n {\n c=b;b=n;\n }\n else if(c>n)\n {\n c=n;\n }\n }\n cout<<c<<endl;\n}", "accuracy": 1, "time_ms": 3680, "memory_kb": 3624, "score_of_the_acc": -0.4888, "final_rank": 15 }, { "submission_id": "aoj_0584_3030116", "code_snippet": "#include <iostream>\n#include <cstdlib>\n#include <vector>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint n, m;\n\tcin >> n;\n\tvector<string> s(n);\n\tint nP2 = n * (n - 1);\n\tvector<int> a(3, 1000010001);\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tcin >> s[i];\n\t}\n\tint k = 0;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tfor (int j = 0; j < n; j++)\n\t\t{\n\t\t\tif (i == j) continue;\n\t\t\tm = atoi((s[i] + s[j]).c_str());\n\t\t\tif (a[2] > m)\n\t\t\t{\n\t\t\t\ta[2] = m;\n\t\t\t\tsort(a.begin(), a.end());\n\t\t\t}\n\t\t}\n\t}\n\tcout << a[2] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3490, "memory_kb": 3456, "score_of_the_acc": -0.455, "final_rank": 14 }, { "submission_id": "aoj_0584_2983463", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cmath>\n#include<algorithm>\n#include<string>\n#include<vector>\n\nusing namespace std;\n\nint main(){\n\tint n,dum,temp;\n\tvector<int> a;\n\tvector<int> dig;\n\t//vector<int> ans;\n\tint ans[3]={100000000,100000000,100000000};\n\t\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d\",&dum);\n\t\ta.push_back(dum);\n\t\ttemp=0;\n\t\twhile(dum!=0){\n\t\t\tdum=dum/10;\n\t\t\ttemp++;\n\t\t}\n\t\tdig.push_back(temp);\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\t\tif(i!=j){\n\t\t\t\ttemp=1;\n\t\t\t\tfor(int k=0;k<dig[j];k++){\n\t\t\t\t\ttemp*=10;\n\t\t\t\t}\n\t\t\t\tdum=a[i]*temp+a[j];\n\t\t\t\tif(ans[0]>=dum){\n\t\t\t\t\tans[2]=ans[1];\n\t\t\t\t\tans[1]=ans[0];\n\t\t\t\t\tans[0]=dum;\n\t\t\t\t}\n\t\t\t\telse if(ans[1]>=dum){\n\t\t\t\t\tans[2]=ans[1];\n\t\t\t\t\tans[1]=dum;\n\t\t\t\t}\n\t\t\t\telse if(ans[2]>=dum){\n\t\t\t\t\tans[2]=dum;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans[2]);\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 3348, "score_of_the_acc": -0.032, "final_rank": 2 }, { "submission_id": "aoj_0584_2928706", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf=1000000000;\n\nint main() {\n std::ios::sync_with_stdio(false);\n cout.tie(0); cin.tie(0);\n int n; cin>>n;\n string a[n]; for (int i=0; i<n; i++) cin>>a[i];\n int permutation_a[n*n];\n for (int i=0; i<n*n; i++) permutation_a[i]=inf;\n int index=0;\n for (int i=0; i<n; i++) {\n for (int j=0; j<n; j++) {\n if (i==j) continue;\n permutation_a[index]=atoi((a[i]+a[j]).c_str());\n index++;\n }\n }\n sort(permutation_a,permutation_a+index);\n cout<<permutation_a[2]<<endl;\n return 0;\n}", "accuracy": 0.8, "time_ms": 100, "memory_kb": 7104, "score_of_the_acc": -0.2467, "final_rank": 19 } ]
aoj_0595_cpp
問題 4: 部活のスケジュール表 (Schedule) 問題 IOI 高校のプログラミング部には,J 君と O 君と I 君の 3 人の部員がいる. プログラミング部では,部活のスケジュールを組もうとしている. 今,N 日間の活動のスケジュールを決めようとしている. 各活動日のスケジュールとして考えられるものは,各部員については活動に参加するかどうかの 2 通りがあり,部としては全部で 8 通りある. 部室の鍵はただ 1 つだけであり,最初は J 君が持っている. 各活動日には,その日の活動に参加する部員のうちのいずれか 1 人が鍵を持っている必要があり,活動後に参加した部員のいずれかが鍵を持って帰る. プログラミング部では,活動日には毎回必ず活動が行われるように,あらかじめ各活動日の責任者を定めた. 責任者は,必ずその日の活動に出席しなければならない. スケジュールを決めようとしている日数と,各活動日の責任者が誰であるかの情報が与えられた時,すべての活動日に部活動を行うことができるようなスケジュール表として考えられるものの数を 10007 で割った余りを求めるプログラムを作成せよ. ただし,部活の終了時に鍵を持って帰る部員は,その日の活動に参加している部員の誰でもよく,最終日は誰が鍵を持って帰ってもよいものとする. 入力 入力は,2 行からなる. 1 行目には,スケジュールを決めようとしている日数を表す 1 つの整数 N (2 ≤ N ≤ 1000) が書かれている. 2 行目には,各活動日の責任者を表す N 文字からなる文字列が書かれている. この文字列の i 文字目 (1 ≤ i ≤ N) は,i 日目の活動日の責任者を表す. すなわち,i 文字目が J, O, I であることはそれぞれ i 日目の活動日の責任者が J 君,O 君,I 君であることを意味する. 出力 スケジュール表として考えられるものの数を 10007 で割った余りを 1 行で出力せよ. 入出力例 入力例 1 2 OI 出力例 1 7 入出力例 1 において,2 日間の活動日のスケジュールを考える.1 日目の責任者は O 君,2 日目の責任者は I 君である. 問題文の条件をみたすスケジュール表は 7 通り考えられる. 1 日目 2 日目 スケジュール 1 J, O O, I スケジュール 2 J, O J, I スケジュール 3 J, O J, O, I スケジュール 4 J, O, I I スケジュール 5 J, O, I J, I スケジュール 6 J, O, I O, I スケジュール 7 J, O, I J, O, I この表では,J, O, I はそれぞれその日に J 君, O 君, I 君が参加することを表す. 1 日目の責任者は O 君であるが,最初鍵を持っているのは J 君であるため,1 日目の活動には J 君, O 君の両方が参加する必要があることに注意せよ. また,1 日目に鍵を持って帰った人は 2 日目にも参加しないといけないので,1 日目と 2 日目の両方に参加する人が少なくとも 1 人存在しなければならないことに注意せよ. 入力例 2 20 JIOIJOIJOJOIIIOJIOII 出力例 2 4976 入出力例 2 において,条件をみたすスケジュール表は全部で 72493594992 通り考えられる.それを 10007 で割った余りである 4976 を出力する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0595_1146954", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\nusing namespace std;\nstring p[7]={\"J\",\"O\",\"I\",\"JI\",\"JO\",\"IO\",\"JOI\"};\nint dp[1001][7]={{0},{0}};\nint d;string s;//d日、s責任者\n\nbool ok(int a,int b,char c){\n\tstring f=p[a],se=p[b];\n\tbool flag1=false,flag2=false;\n\tfor(int i=0;i<se.size();i++){\n\t\tif(se[i]==c)flag1=true;\n\t}\n\tfor(int i=0;i<f.size();i++){\n\t\tfor(int j=0;j<se.size();j++){\n\t\t\tif(f[i]==se[j])flag2=true;\n\t\t}\n\t}\n\tif(flag1&&flag2)return true;\n\telse return false;\n}\nint main(){\n\tcin>>d>>s;\n\tfor(int i=0;i<7;i++)(ok(0,i,s[0]))?dp[0][i]=1:dp[0][i]=0;\n//\tfor(int j=0;j<7;j++)if(ok(4,j,s[1]))dp[1][j]+=1;\n\t//\tfor(int j=0;j<7;j++)if(ok(6,j,s[1]))dp[1][j]+=1;\n\t\n\tfor(int i=0;i<d-1;i++){\n\t\tfor(int j=0;j<7;j++){//i+1日目のjパターン\n\t\t\tint x=0;\n\t\t\tfor(int k=0;k<7;k++){//i日目\n\t\t\t\tif(ok(k,j,s[i+1])&&dp[i][k])dp[i+1][j]=(dp[i+1][j]+dp[i][k])%10007;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t/*for(int i=0;i<d;i++){\n\tfor(int j=0;j<7;j++)cout<<dp[i][j]<<\" \";\n\tcout<<endl;\n\t}*/\n\tint ans=0;\n\tfor(int i=0;i<7;i++)ans+=dp[d-1][i];\n\tcout<<ans%10007<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1248, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0595_1136880", "code_snippet": "#include<iostream>\n//j=前の日,1=J,11=JO,111=JOI,100=I\nusing namespace std;\nint n, ho[1202] = {} ,memo[112][1001][112];\nchar a[1202];\nint sh(int j, int day,int ij)\n{\n\tint A = 0;\n\tA = j - ho[day];\n\tif (A == 99 || A == 9 || A == 109 || A == 90 || A == 91 || A == -9 || A == -99 || A == -90 || A == -89)return 0;\n\tint B;\n\tB = j - ij;\n\tif (ij == 11)\n\t{\n\t\tif (j == 110)\n\t\t\tB=1000;\n\t\tif (j == 101)\n\t\t\tB=1000;\n\t}\n\tif (ij == 110 ){\n\t\tif (j==11)\n\t\tB = 1000;\n\t\tif (j == 101)\n\t\t\tB = 1000;\n\t}\n\tif (ij == 101 ){\n\t\tif (j==110)\n\t\tB = 1000;\n\t\tif (j == 11)\n\t\t\tB = 1000;\n\t}\n\t\n\tif (B == 9 || B == 99 || B == 109 || B == -9 || B == 90 || B == 91 || B == 89 || B == -99 || B == -90 || B == -89 || B == -109 || B == -91){\n\t\treturn 0;\n\t}\n\tif (day > n)return 0;\n\n\tif (day == n)return 1;\n\n\n\tint ans = 0;\n\tif (memo[j][day][ij] != -1){\n\t\treturn memo[j][day][ij]; \n\t} else{\n\t\n\tans += sh(1, day + 1, j);\n\tans += sh(11, day + 1, j);\n\tans += sh(10, day + 1, j);\n\tans += sh(100, day + 1, j);\n\tans += sh(110, day + 1, j);\n\tans += sh(111, day + 1, j);\n\tans += sh(101, day + 1, j);\n\t}\n\tans%=10007;\n\tmemo[j][day][ij] = ans;\n\treturn ans;\n}\nint main()\n{\n\tint s[2500] = {};\n\tcin >> n;\n\tcin >> a;\n\tho[0] = 1;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 'J')ho[i+1] = 1;\n\t\tif (a[i] == 'O')ho[i+1] = 10;\n\t\tif (a[i] == 'I')ho[i+1] = 100;\n\t}\n\tfor (int i = 0; i < 112; i++)\n\t{\n\t\tfor (int g = 0; g < 1001; g++)\n\t\t{\n\t\t\tfor (int jk = 0; jk < 112; jk++)\n\t\t\t{\n\t\t\t\tmemo[i][g][jk] = -1;\n\t\t\t}\n\t\t\t\n\t\t}\n\t}\n\n\tcout << sh(1,0,0) << endl;\n\n\treturn 0;\n}\n\n\n\n\n\n/*#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n\nstring moji,yoso[200];\n\nint f(string a)\n{\n\tif(moji.find(a,0))\n\t{\n\t\t\n}\nint main ()\n{\n\tint z;\n\tint ans=0;\n\tcin>>z;\n\tcin>>moji;\n\tfor(int i=0;i<z;i++)\n\t{\n\t\tcin>>yoso[i];\n\t\t\n\t}\n\tfor(int i=0;i<z;i++)\n\t{\n\t\tif(moji.find(yoso[i],0)){ans++;continue;}\n\t\tf(yoso[i].at(0));\n\t}\n\treturn 0;\n}*/", "accuracy": 1, "time_ms": 10, "memory_kb": 50280, "score_of_the_acc": -1, "final_rank": 2 }, { "submission_id": "aoj_0595_1134103", "code_snippet": "#include<iostream>\n//j=前の日,1=J,11=JO,111=JOI,100=I\nusing namespace std;\nint n, ho[2500] = {} ,memo[2500][2500];\nchar a[2500];\nint sh(int j, int day)\n{\n\tint A = 0;\n\tA = j - ho[day];\n\tif (A == 99 || A == 9 || A == 109 || A == 90 || A == 91 || A == -9 || A == -99 || A == -90 || A == -89)return 0;\n\tif (day > n)return 0;\n\n\tif (day == n)return 1;\n\n\t//if (memo[j][ho[day]] != -1)return memo[j][ho[day]];\n\n\n\n\tint ans = 0;\n\n\tif (j == 1){\n\t\tans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t//\tans += sh(10, day + 1);\n\t//\tans += sh(100, day + 1);\n\t//\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\telse if (j == 10)\n\t{\n\t\t//ans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t\tans += sh(10, day + 1);\n\t\t//ans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\t//ans += sh(101, day + 1);\n\t}\n\telse if (j==11)\n\t{\n\t\tans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t\tans += sh(10, day + 1);\n\t\t//ans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\telse if (j==100)\n\t{\n\t//\tans += sh(1, day + 1);\n\t//\tans += sh(11, day + 1);\n\t//\tans += sh(10, day + 1);\n\t\tans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\telse if (j==110)\n\t{\n\t//\tans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t\tans += sh(10, day + 1);\n\t\tans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\telse if (j==111)\n\t{\n\t\tans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t\tans += sh(10, day + 1);\n\t\tans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\telse if (j==101)\n\t{\n\t\tans += sh(1, day + 1);\n\t\tans += sh(11, day + 1);\n\t//\tans += sh(10, day + 1);\n\t\tans += sh(100, day + 1);\n\t\tans += sh(110, day + 1);\n\t\tans += sh(111, day + 1);\n\t\tans += sh(101, day + 1);\n\t}\n\n\tmemo[j][ho[day]] = ans;\n//\tans %= 10007;\n//\treturn memo[j][ho[day]]=ans;\n\treturn ans;\n}\nint main()\n{\n\tint s[2500] = {};\n\tcin >> n;\n\tcin >> a;\n\tho[0] = 1;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (a[i] == 'J')ho[i+1] = 1;\n\t\tif (a[i] == 'O')ho[i+1] = 10;\n\t\tif (a[i] == 'I')ho[i+1] = 100;\n\t}\n\tfor (int i = 0; i < 2500; i++)\n\t{\n\t\tfor (int g = 0; g < 2500; g++)\n\t\t{\n\t\t\tmemo[i][g] = -1;\n\t\t}\n\t}\n\n\tcout << sh(1,0) << endl;\n\n\t\n\tint hjhj;\n\tcin >> hjhj;\n\treturn 0;\n}\n/*\nint A;\nif (day > n)return 0;\nif (day == 1){\nif (j == 10 || j == 100 || j == 110)return 0;\n}\nif (day != 0)\n{\nA = j - ho[day - 1];\nif (A == 99 || A == 9 || A == 109 || A == 90 || A == 91 || A == -9 || A == -99 || A == -90 || A == -89)return 0;\n}\nif (day == n)return 1;\nint ans = 0;\nif (memo[j][ho[day-1]] != -1)return memo[j][ho[day-1]];\n*/", "accuracy": 0.2, "time_ms": 1440, "memory_kb": 25584, "score_of_the_acc": -1.4963, "final_rank": 3 } ]
aoj_0594_cpp
問題 3: 超都観光 (Super Metropolis) 問題 JOI 君は,IOI 国にある超都という都市の観光ツアーを計画することになった. 超都は,南北方向にまっすぐに伸びる W 本の道路と,東西方向にまっすぐに伸びる H 本の道路により,碁盤の目の形に区分けされている. 南北方向の W 本の道路には,西から順に 1, 2, ... , W の番号が付けられている.また,東西方向の H 本の道路には,南から順に 1, 2, ... , H の番号が付けられている.西から i 番目の南北方向の道路と,南から j 番目の東西方向の道路との交差点を (i, j) で表す. さらに,下図のように,各交差点からは1つ北東の交差点への道がある(最も北の道路上の交差点と最も東の道路上の交差点を除く). また,1つ南西の交差点への道もある(最も南の道路上の交差点と最も西の道路上の交差点を除く). すなわち,交差点 (i, j) からは,もし交差点 (i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1) があるときは,それらの交差点へ1本の道を使って行くことが出来る.それに加え,もし交差点 (i - 1, j - 1), (i + 1, j + 1) があるときは,それらの交差点へも1本の道を使って行くことが出来る. JOI 君はツアーの計画として既に N 個の観光スポットをどのような順番で訪れるかを決めている. i 番目 (1 ≦ i ≦ N) に訪れる観光スポットは交差点 (X i , Y i ) にある. JOI 君は,ツアーにかかる時間をできるだけ短くするために,通らなければならない道の本数を少なくしたい. 観光スポットを事前に決めた順番で訪れるために通らなければならない道の本数の合計の最小値を求めるプログラムを作成せよ. ただし,ツアーの開始地点は交差点 (X 1 , Y 1 ) である.また,ツアーの途中で超都の外へ移動してはならないものとする. また,JOI 君は,観光スポットのある交差点を,観光スポットを訪れずに通過することもできる. 「道の本数の合計」についての補足.ツアーの途中で同じ道を2回以上通ることもできる.その場合,「道の本数の合計」としては,その道については通った回数だけ重複して数えるものとする. 入力 入力は 1 + N 行からなる. 1 行目には,空白を区切りとして 3 つの整数 W, H, N (2 ≤ W ≤ 10000, 2 ≤ H ≤ 10000, 1 ≤ N ≤ 1000) が書かれている. 続く N 行のうちの i 行目 (1 ≤ i ≤ N) には,2 つの整数 X i , Y i (1 ≤ X i ≤ W, 1 ≤ Y i ≤ H) が空白を区切りとして書かれている.これは,i 番目に訪れる観光スポットのある交差点が (X i , Y i ) であることを表す. 出力 観光スポットを順番に訪れるために通る道の本数の合計の最小値を 1 行で出力せよ. 入出力例 入力例 1 4 3 3 1 1 3 3 4 1 出力例 1 5 入出力例 1 では,例えば (1, 1), (2, 2), (3, 3), (3, 2), (4, 2), (4, 1) の順で交差点を訪れれば良い. 入力例 2 4 3 5 1 3 4 3 2 2 2 2 1 3 出力例 2 7 入出力例 2 のように,同じ交差点に複数回訪れることもある. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0594_1712254", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint n,W,H,x,nx,y,ny,ans,a,b;\n\nint main(){\n\n cin >> W >> H >> n;\n cin >> x >> y;\n\n for(int i=1;i<n;i++){\n cin >> nx >> ny;\n\n if(nx==x&&y==ny);\n else {\n a=nx,b=ny;\n if(nx>x&&ny>y){\n for(int j=1;j<10111;j++){\n if(nx-j==x||ny-j==y){\n nx=nx-j,ny=ny-j,ans+=j;\n break;\n }\n }\n }else if(nx<x&&ny<y){\n for(int j=1;j<10010;j++){\n if(nx+j==x||ny+j==y){\n nx=nx+j,ny=ny+j,ans+=j;\n break;\n }\n }\n }\n for(int j=1;j<10010;j++){\n if(x==nx)break;\n if(x==nx-j||x==nx+j)ans+=j;\n }\n for(int j=1;j<10010;j++){\n if(y==ny)break;\n if(y==ny-j||y==ny+j)ans+=j;\n }\n }\n x=a,y=b;\n }\n\n cout << ans << endl;\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1164, "score_of_the_acc": -0.2001, "final_rank": 5 }, { "submission_id": "aoj_0594_1678675", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dx[]={0,1,1,0,-1,-1},dy[]={1,1,0,-1,-1,0};\nint h,w;\nqueue<int> quex,quey;\nint serch(int clex,int cley,int load,int num);\nint main()\n{\n int n,ans=0;\n int clex,cley;\n cin>>h>>w>>n;\n cin>>clex>>cley;\n quex.push(clex);\n quey.push(cley);\n for(int i=0;i<n-1;i++){\n cin>>clex>>cley;\n if(quex.front()!=clex||quey.front()!=cley){\n ans+=serch(clex,cley,1,1);\n quex.push(clex);\n quey.push(cley);\n }\n }\n cout<<ans<<endl;\n return 0;\n}\nint serch(int clex,int cley,int load,int num)\n{\n int now=0;\n for(int i=0;i<load;i++){\n int x=quex.front(),y=quey.front();\n quex.pop();quey.pop();\n for(int j=0;j<6;j++){\n if(dx[j]+x>0&&dy[j]+y>0&&dx[j]+x<=h&&dy[j]+y<=w){\n if(dx[j]+x==clex&&dy[j]+y==cley){\n for(int k=0;k<now+load-i-1;k++){\n quex.pop();\n quey.pop();\n }\n return num;\n }\n else {\n quex.push(dx[j]+x);\n quey.push(dy[j]+y);\n now++;\n }\n }\n }\n }\n return serch(clex,cley,now,++num);\n}", "accuracy": 0.2, "time_ms": 60, "memory_kb": 33708, "score_of_the_acc": -2, "final_rank": 6 }, { "submission_id": "aoj_0594_1678666", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dx[]={0,1,1,0,-1,-1},dy[]={1,1,0,-1,-1,0};\nint h,w;\nqueue<int> quex,quey;\nint serch(int clex,int cley,int load,int num);\nint main()\n{\n int n,ans=0;\n int clex,cley;\n cin>>h>>w>>n;\n cin>>clex>>cley;\n quex.push(clex);\n quey.push(cley);\n for(int i=0;i<n-1;i++){\n cin>>clex>>cley;\n if(quex.front()!=clex||quey.front()!=cley){\n ans+=serch(clex,cley,1,1);\n quex.push(clex);\n quey.push(cley);\n }\n }\n cout<<ans<<endl;\n}\nint serch(int clex,int cley,int load,int num)\n{\n int now=0;\n for(int i=0;i<load;i++){\n int x=quex.front(),y=quey.front();\n quex.pop();quey.pop();\n for(int j=0;j<6;j++){\n if(dx[j]+x>0&&dy[j]+y>0&&dx[j]+x<=h&&dy[j]+y<=w){\n if(dx[j]+x==clex&&dy[j]+y==cley){\n for(int k=0;k<now+load-i-1;k++){\n quex.pop();\n quey.pop();\n }\n return num;\n }\n else {\n quex.push(dx[j]+x);\n quey.push(dy[j]+y);\n now++;\n }\n }\n }\n }\n return serch(clex,cley,now,++num);\n}", "accuracy": 0.2, "time_ms": 60, "memory_kb": 33708, "score_of_the_acc": -2, "final_rank": 6 }, { "submission_id": "aoj_0594_1493277", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n\nusing namespace std;\n\nconst double PI = 3.14159265358979323846;\n\nint main() {\n int w, h, n, kanX[1001], kanY[1001];\n cin >> w >> h >> n;\n for (int i = 0; i < n; ++i) {\n cin >> kanX[i] >> kanY[i];\n }\n\n int r = 0;\n int x = kanX[0];\n int y = kanY[0];\n for (int i = 1; i < n; ++i) {\n while (true) {\n int defX = kanX[i] - x;\n int defY = kanY[i] - y;\n\n if ((defX == 0) && (defY == 0)) {\n break;\n }\n if ((0 < defX) && (0 < defY)) {\n x++;\n y++;\n } else if ((defX < 0) && (defY < 0)) {\n x--;\n y--;\n } else if (defX != 0) {\n (defX < 0) ? x-- : x++;\n } else {\n (defY < 0) ? y-- : y++;\n }\n r++;\n }\n }\n\n cout << r << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1168, "score_of_the_acc": -0.0002, "final_rank": 4 }, { "submission_id": "aoj_0594_1376151", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint calc(int fromx, int fromy, int tox, int toy)\n{\n int cnt = 0;\n\n while (fromx != tox || fromy != toy) {\n if (fromx < tox && fromy < toy) {\n fromx++; fromy++;\n } else if (fromx > tox && fromy > toy) {\n fromx--; fromy--;\n } else if (fromx > tox && fromy < toy) {\n fromx--;\n } else if (fromx < tox && fromy > toy) {\n fromx++;\n } else if (fromx == tox) {\n if (fromy < toy) fromy++;\n else fromy--;\n } else if (fromy == toy) {\n if (fromx < tox) fromx++;\n else fromx--;\n }\n \n cnt++;\n }\n\n return cnt;\n}\n\nint main()\n{\n int w, h, n; cin >> w >> h >> n;\n\n int a, b; cin >> a >> b;\n\n int cnt = 0;\n\n for(int i = 1; i < n; ++i) {\n int x, y; cin >> x >> y;\n \n cnt += calc(a, b, x, y); \n \n a = x, b = y;\n }\n\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0594_1376149", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint calc(int fromx, int fromy, int tox, int toy)\n{\n int cnt = 0;\n\n while (fromx != tox || fromy != toy) {\n if (fromx < tox && fromy < toy) {\n fromx++;\n fromy++;\n } else if (fromx > tox && fromy > toy) {\n fromx--;\n fromy--;\n } else if (fromx > tox && fromy < toy) {\n fromx--;\n } else if (fromx < tox && fromy > toy) {\n fromx++;\n } else if (fromx == tox) {\n if (fromy < toy) {\n fromy++;\n } else {\n fromy--;\n }\n } else if (fromy == toy) {\n if (fromx < tox) {\n fromx++;\n } else {\n fromx--;\n }\n }\n \n cnt++;\n }\n\n return cnt;\n}\n\nint main()\n{\n int w, h, n; cin >> w >> h >> n;\n\n int a, b; cin >> a >> b;\n\n int cnt = 0;\n\n for(int i = 1; i < n; ++i) {\n int x, y; cin >> x >> y;\n \n cnt += calc(a, b, x, y); \n \n a = x, b = y;\n }\n\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0594_1376142", "code_snippet": "#include <iostream>\n#include <utility>\n\nusing namespace std;\n\nint calc(int fromx, int fromy, int tox, int toy)\n{\n int cnt = 0;\n\n while (fromx != tox || fromy != toy) {\n if (fromx < tox && fromy < toy) {\n fromx++;\n fromy++;\n } else if (fromx > tox && fromy > toy) {\n fromx--;\n fromy--;\n } else if (fromx > tox && fromy < toy) {\n fromx--;\n } else if (fromx < tox && fromy > toy) {\n fromx++;\n } else if (fromx == tox) {\n if (fromy < toy) {\n fromy++;\n } else {\n fromy--;\n }\n } else if (fromy == toy) {\n if (fromx < tox) {\n fromx++;\n } else {\n fromx--;\n }\n }\n \n cnt++;\n }\n\n return cnt;\n}\n\nint main()\n{\n int w, h, n; cin >> w >> h >> n;\n\n int a, b; cin >> a >> b;\n pair<int, int> now(a, b);\n\n int cnt = 0;\n\n for(int i = 1; i < n; ++i) {\n int x, y; cin >> x >> y;\n \n cnt += calc(now.first, now.second, x, y); \n \n now.first = x, now.second = y;\n }\n\n cout << cnt << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1160, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0585_cpp
問題 4 平面上の n 個の点 P 1 , ..., P n が与えられたとき, 距離が最小の2点を求めたい. 入力ファイルの1行目には整数 n が書いてある. 2行目から n+1 行目のそれぞれには, 2つの正整数 x, y が1つの半角空白文字を区切りとして書いてある. i+1 行目の x, y はそれぞれ P i の x 座標, P i の y 座標である. これら n 点の中から最も近い2点を選んだとき, この2点間の距離の2乗を出力せよ. ただし, 2≤n≤500000 かつ -10000≤x≤10000, -10000≤y≤10000 とし, 5つの入力ファイルのうち3つでは n≤100 である. また,どの入力ファイルにおいても,全ての座標は異なるものとする. 出力ファイルにおいては, 出力の最後の行にも改行コードを入れること. 入出力例 入力例1 2 0 0 1 1 出力例1 2 入力例2 3 5 5 0 0 -3 -4 出力例2 25 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0585_10937816", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rrep(i, a, b) for (int i = (int)(b)-1; i >= (int)(a); i--)\n#define ALL(v) (v).begin(), (v).end()\n#define UNIQUE(v) sort(ALL(v)), (v).erase(unique(ALL(v)), (v).end())\n#define SZ(v) (int)v.size()\n#define MIN(v) *min_element(ALL(v))\n#define MAX(v) *max_element(ALL(v))\n#define LB(v, x) int(lower_bound(ALL(v), (x)) - (v).begin())\n#define UB(v, x) int(upper_bound(ALL(v), (x)) - (v).begin())\n\nusing uint = unsigned int;\nusing ll = long long int;\nusing ull = unsigned long long;\nusing i128 = __int128_t;\nusing u128 = __uint128_t;\nconst int inf = 0x3fffffff;\nconst ll INF = 0x1fffffffffffffff;\n\ntemplate <typename T> inline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T> inline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <typename T, typename U> T ceil(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\ntemplate <typename T, typename U> T floor(T x, U y) {\n assert(y != 0);\n if (y < 0)\n x = -x, y = -y;\n return (x > 0 ? x / y : (x - y + 1) / y);\n}\ntemplate <typename T> int popcnt(T x) {\n return __builtin_popcountll(x);\n}\ntemplate <typename T> int topbit(T x) {\n return (x == 0 ? -1 : 63 - __builtin_clzll(x));\n}\ntemplate <typename T> int lowbit(T x) {\n return (x == 0 ? -1 : __builtin_ctzll(x));\n}\n\ntemplate <class T, class U>\nostream &operator<<(ostream &os, const pair<T, U> &p) {\n os << \"P(\" << p.first << \", \" << p.second << \")\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {\n os << \"{\";\n for (int i = 0; i < vec.size(); i++) {\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \", \");\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T, typename U>\nostream &operator<<(ostream &os, const map<T, U> &map_var) {\n os << \"{\";\n for (auto itr = map_var.begin(); itr != map_var.end(); itr++) {\n os << \"(\" << itr->first << \", \" << itr->second << \")\";\n itr++;\n if (itr != map_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) {\n os << \"{\";\n for (auto itr = set_var.begin(); itr != set_var.end(); itr++) {\n os << *itr;\n ++itr;\n if (itr != set_var.end())\n os << \", \";\n itr--;\n }\n os << \"}\";\n return os;\n}\n#ifdef LOCAL\n#define show(...) _show(0, #__VA_ARGS__, __VA_ARGS__)\n#else\n#define show(...) true\n#endif\ntemplate <typename T> void _show(int i, T name) {\n cerr << '\\n';\n}\ntemplate <typename T1, typename T2, typename... T3>\nvoid _show(int i, const T1 &a, const T2 &b, const T3 &...c) {\n for (; a[i] != ',' && a[i] != '\\0'; i++)\n cerr << a[i];\n cerr << \":\" << b << \" \";\n _show(i + 1, a, c...);\n}\n\n/**\n * @brief template\n */\n\nvoid Solve() {\n int N;\n cin >> N;\n vector<pair<ll,ll>> P(N);\n rep(i,0,N) {\n ll X, Y;\n cin >> X >> Y;\n P[i] = {X,Y};\n }\n sort(ALL(P));\n auto Dist = [&](int i, int j) -> ll {\n return (P[i].first - P[j].first) * (P[i].first - P[j].first) + (P[i].second - P[j].second) * (P[i].second - P[j].second);\n };\n auto Calc = [&](auto self, int L, int R) -> ll {\n if (R - L == 1) return INF;\n if (R - L == 2) return Dist(L,L+1);\n int MID = (L+R) / 2;\n ll Ret = min(self(self,L,MID), self(self,MID,R));\n vector<int> ord(R-L);\n iota(ALL(ord),L);\n sort(ALL(ord),[&](int i, int j){return P[i].second < P[j].second;});\n ll MX = P[MID].first;\n vector<int> V;\n for (int i : ord) {\n if ((P[i].first - MX) * (P[i].first - MX) > Ret) continue;\n rrep(j,0,SZ(V)) {\n if ((P[i].second - P[V[j]].second) * (P[i].second - P[V[j]].second) > Ret) break;\n chmin(Ret, Dist(i,V[j]));\n }\n V.push_back(i);\n }\n return Ret;\n };\n ll ANS = Calc(Calc,0,N);\n cout << ANS << endl;\n}\n\nint main() {\n cin.tie(0);\n ios_base::sync_with_stdio(false);\nint _ = 1;\n//cin >> _;\nwhile(_--) {\n Solve();\n}\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 13932, "score_of_the_acc": -0.1191, "final_rank": 10 }, { "submission_id": "aoj_0585_10848996", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nbool cmp(pair<int,int> u1,pair<int,int> u2){\n\tif (u1.first==u2.first){\n\t\treturn (u1.second<u2.second);\n\t}\n\treturn (u1.first<u2.first);\n}\nbool cmp1(pair<int,int> u1,pair<int,int> u2){\n\tif (u1.second==u2.second){\n\t\treturn (u1.first<u2.first);\n\t}\n\treturn (u1.second<u2.second);\n}\nint main(){\n\tint n;cin>>n;pair<int,int> a[n+1];\n\tfor (int i=1;i<=n;i++) cin>>a[i].first>>a[i].second;\n\tsort(a+1,a+n+1,cmp);\n\tint mi=1e9;\n\tfor (int i=2;i<=n;i++){\n\t\tint x=a[i-1].first,x1=a[i-1].second,x2=a[i].first,x3=a[i].second;\n\t\tmi=min(mi,(x-x2)*(x-x2)+(x1-x3)*(x1-x3));\n\t}\n\tsort(a+1,a+n+1,cmp1);\n//\tfor (int i=1;i<=n;i++) cout<<a[i].first<<\" \"<<a[i].second<<endl;\n\tfor (int i=2;i<=n;i++){\n\t\tint x=a[i-1].first,x1=a[i-1].second,x2=a[i].first,x3=a[i].second;\n\t\tmi=min(mi,(x-x2)*(x-x2)+(x1-x3)*(x1-x3));\n\t}\n\tcout<<mi<<endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 7196, "score_of_the_acc": -0.0462, "final_rank": 1 }, { "submission_id": "aoj_0585_10794027", "code_snippet": "#define _GLGBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Point {\n\tint x;\n\tint y;\n int idx;\n};\n\nconstexpr int INF = 1000000000.0;\n\nint n;\nvector<bool> q_or_r, s_or_not;\n\nint calc_euclidean_distance(Point p_1, Point p_2) {\n\treturn (\n\t\t(p_2.x - p_1.x) * (p_2.x - p_1.x) + \n\t\t(p_2.y - p_1.y) * (p_2.y - p_1.y)\n\t);\n}\n\nbool compare_by_x(const Point &a, const Point &b) {\n return a.x < b.x;\n}\n\nbool compare_by_y(const Point &a, const Point &b) {\n return a.y < b.y;\n}\n\npair<Point, Point> closest_pair_rec(\n vector<Point> P_x, \n vector<Point> P_y\n) {\n if (static_cast<int>(P_x.size()) <= 3) {\n int min_d = INF;\n pair<Point, Point> closest_pair;\n\n for (int i = 0; i < static_cast<int>(P_x.size()) - 1; i++) {\n for (int j = i + 1; j < static_cast<int>(P_x.size()); j++) {\n int euclidean_distance = calc_euclidean_distance(P_x.at(i), P_x.at(j));\n\n if (min_d > euclidean_distance) {\n min_d = euclidean_distance;\n closest_pair = make_pair(P_x.at(i), P_x.at(j));\n }\n }\n }\n\n return closest_pair;\n } else {\n vector<Point> Q_x, Q_y, R_x, R_y, S_y;\n\n for (int k = 0; k < static_cast<int>(P_x.size()); k++) {\n if (k < (static_cast<int>(P_x.size()) + 1) / 2) {\n Q_x.push_back(P_x.at(k));\n q_or_r.at(P_x.at(k).idx) = true;\n } else {\n R_x.push_back(P_x.at(k));\n q_or_r.at(P_x.at(k).idx) = false;\n }\n }\n\n for (auto point: P_y) {\n if (q_or_r.at(point.idx))\n Q_y.push_back(point);\n else\n R_y.push_back(point);\n }\n\n auto [q_1, q_2] = closest_pair_rec(Q_x, Q_y);\n auto [r_1, r_2] = closest_pair_rec(R_x, R_y);\n\n int delta = min(calc_euclidean_distance(q_1, q_2), calc_euclidean_distance(r_1, r_2)),\n L = Q_x.at(static_cast<int>(Q_x.size()) - 1).x;\n\n for (auto point: P_x) {\n if (abs(point.x - L) <= delta)\n s_or_not.at(point.idx) = true;\n else\n s_or_not.at(point.idx) = false;\n }\n\n for (auto point : P_y) {\n if (s_or_not.at(point.idx))\n S_y.push_back(point);\n }\n\n int min_d = INF;\n pair<Point, Point> closest_pair;\n\n for (int p = 0; p < static_cast<int>(S_y.size()); p++) {\n for (int q = 1; q <= 15; q++) {\n if (p + q < static_cast<int>(S_y.size())) {\n int euclidean_distance = calc_euclidean_distance(S_y.at(p), S_y.at(p + q));\n if (min_d > euclidean_distance) {\n min_d = euclidean_distance;\n closest_pair = make_pair(S_y.at(p), S_y.at(p + q));\n }\n }\n }\n }\n\n if (min_d < delta) {\n return closest_pair;\n } else if (\n calc_euclidean_distance(q_1, q_2) <\n calc_euclidean_distance(r_1, r_2)\n ) return make_pair(q_1, q_2);\n else\n return make_pair(r_1, r_2);\n }\n}\n\npair<Point, Point> closest_pair(vector<Point> P) {\n vector<Point> P_x = P, P_y = P;\n\n sort(P_x.begin(), P_x.end(), compare_by_x);\n sort(P_y.begin(), P_y.end(), compare_by_y);\n\n\treturn closest_pair_rec(P_x, P_y);\n}\n\nint main() {\n cin >> n;\n\n vector<Point> points(n);\n\n for (int i = 0; i < n; i++) {\n cin >> points.at(i).x >> points.at(i).y;\n points.at(i).idx = i;\n }\n\n q_or_r.resize(n);\n s_or_not.resize(n);\n\n for (int j = 0; j < n; j++) {\n q_or_r.at(j) = false;\n s_or_not.at(j) = false;\n }\n\n auto [p_1, p_2] = closest_pair(points);\n\n cout << fixed << setprecision(12) << \n calc_euclidean_distance(p_1, p_2)\n << '\\n';\n\n return 0;\n}", "accuracy": 1, "time_ms": 600, "memory_kb": 73912, "score_of_the_acc": -0.6362, "final_rank": 15 }, { "submission_id": "aoj_0585_10760693", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll =long long;\nusing Point=array<ll,2>;\nll d(Point A,Point B){\n ll dx=A[0]-B[0];\n ll dy=A[1]-B[1];\n return dx*dx+dy*dy;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n ll N;\n cin>>N;\n vector<array<ll,2>> P(N);\n for(int i=0;i<N;i++)cin>>P[i][0]>>P[i][1];\n sort(P.begin(),P.end());\n ll an=d(P[0],P[1]);\n for(int i=2;i<N;i++){\n for(int j=i-1;j>=0;j--){\n ll dx=P[i][0]-P[j][0];\n if(dx*dx>=an)break;\n an=min(an,d(P[j],P[i]));\n }\n }\n cout<<an<<\"\\n\";\n\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 11244, "score_of_the_acc": -0.0814, "final_rank": 8 }, { "submission_id": "aoj_0585_10345741", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n////////////////////////////////////////////\nll n;\nunordered_map<pair<ll, ll>, vector<ll>> mp;\nvector<pair<ld, ld>> ar;\nld d(ll i, ll j)\n{\n ld x = ar[i].first - ar[j].first;\n ld y = ar[i].second - ar[j].second;\n ld ret = x * x + y * y;\n return sqrt(ret);\n}\nvoid remake(ld D)\n{\n unordered_map<pair<ll, ll>, vector<ll>> cp;\n rep(i, 0, n)\n {\n ll X = floor(ar[i].first / D);\n ll Y = floor(ar[i].second / D);\n cp[pr(X, Y)].push_back(i);\n }\n mp = cp;\n}\n// AOJ CGL_5_A\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cin >> n;\n ar.resize(n);\n rep(i, 0, n)\n {\n cin >> ar[i].first >> ar[i].second;\n }\n ld ans = 100000.0;\n remake(ans);\n while (true)\n {\n bool f = true;\n rep(i, 0, n)\n {\n ll X = floor(ar[i].first / ans);\n ll Y = floor(ar[i].second / ans);\n rep(j, 0, 2)\n {\n rep(k, 0, 2)\n {\n rep(l, 0, mp[pr(X + j, Y + k)].size())\n {\n ll idx = mp[pr(X + j, Y + k)][l];\n if (idx == i)\n {\n continue;\n }\n if (d(i, idx) < ans)\n {\n chmin(ans, d(i, idx));\n f = false;\n remake(ans);\n // cout << ans << Endl;\n goto next;\n }\n }\n }\n }\n rep(l, 0, mp[pr(X - 1, Y + 1)].size())\n {\n ll idx = mp[pr(X - 1, Y + 1)][l];\n if (idx == i)\n {\n continue;\n }\n if (d(i, idx) < ans)\n {\n chmin(ans, d(i, idx));\n f = false;\n remake(ans);\n // cout << ans << Endl;\n goto next;\n }\n }\n }\n next:\n if (f)\n {\n ll A = ans * ans + eps;\n cout << A << endl;\n break;\n }\n }\n}", "accuracy": 1, "time_ms": 5100, "memory_kb": 130456, "score_of_the_acc": -1.8289, "final_rank": 19 }, { "submission_id": "aoj_0585_10315721", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\n#include <queue>\n#include <map>\nusing namespace std;\n\n\nbool cmpX(pair<int, int> &a, pair<int, int> &b) {\n return a.first < b.first;\n}\n\nbool cmpY(pair<int, int> &a, pair<int, int> &b) {\n return a.second < b.second;\n}\n\nlong long dist(pair<int, int> &a, pair<int, int> &b) {\n long long dx = a.first - b.first;\n long long dy = a.second - b.second;\n return dx*dx + dy*dy;\n}\n\n\nlong long closet_pair(vector<pair<int, int> > &p, int left, int right) {\n if(right - left <= 3) {\n long long minDist = 1e19;\n for(int i = left; i < right; i++) {\n for(int j = i+1; j < right; j++) {\n minDist = min(minDist, dist(p[i], p[j]));\n }\n }\n return minDist;\n }\n\n int mid = (left + right) / 2;\n long long d = min(closet_pair(p, left, mid), closet_pair(p, mid, right));\n\n vector<pair<int, int>> b;\n for(int i = left; i < right; i++) {\n if(abs(p[i].first - p[mid].first) * 1LL * abs(p[i].first - p[mid].first) < d) {\n b.push_back(p[i]);\n }\n }\n\n sort(b.begin(), b.end(), cmpY);\n\n for(int i = 0; i < b.size(); i++) {\n for(int j = i+1; j < b.size() && (abs(b[i].second - b[j].second) * 1LL * abs(b[i].second - b[j].second)) < d; j++) {\n d = min(d, dist(b[i], b[j]));\n }\n }\n return d;\n}\n\n\n\n\nint main(void) {\n\n int n;\n cin >> n;\n vector<pair<int, int>> p(n);\n for(int i = 0; i < n; i++) {\n cin >> p[i].first >> p[i].second; //first:x座標, second:y座標\n }\n\n sort(p.begin(), p.end(), cmpX);\n cout << closet_pair(p, 0, n) << endl;\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 6920, "score_of_the_acc": -0.059, "final_rank": 2 }, { "submission_id": "aoj_0585_10047495", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n int n;\n\n cin >> n;\n\n vector<pair<int, int> > p(n);\n\n for (int i = 0; i < n; i++) {\n cin >> p[i].first >> p[i].second;\n }\n\n sort(p.begin(), p.end());\n \n long long min_dist = 1000000000;\n \n for (int i = 0; i < n; i++) {\n for (int j = i + 1; j < n; j++) {\n long long x_square = (p[j].first - p[i].first) * (p[j].first - p[i].first);\n if (x_square > min_dist) break;\n long long y_square = (p[j].second - p[i].second) * (p[j].second - p[i].second);\n if (x_square + y_square < min_dist) {\n min_dist = x_square + y_square;\n }\n }\n }\n\n cout << min_dist << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 6920, "score_of_the_acc": -0.0689, "final_rank": 6 }, { "submission_id": "aoj_0585_9659116", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntemplate<typename T>\nlong double dist(T x1,T y1,T x2,T y2){\n return sqrtl((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));\n}\ntemplate<typename T>\nlong double dist(pair<T,T>p1,pair<T,T>p2){\n return dist(p1.first,p1.second,p2.first,p2.second);\n}\n//assume sorted by x coordinate\nlong double closest_pair(vector<pair<long double,long double>>::iterator begin,vector<pair<long double,long double>>::iterator end){\n int size=end-begin;\n assert(size>1);\n if(size==2)return dist(*begin,*(begin+1));\n if(size==3)return min({dist(*begin,*(begin+1)),dist(*begin,*(begin+2)),dist(*(begin+1),*(begin+2))});\n auto cen=begin+size/2;\n auto d=min(closest_pair(begin,cen),closest_pair(cen,end));\n vector<pair<long double,long double>>strip;\n for(auto it=begin;it<end;it++){\n if(abs((*it).first-(*cen).first)<d)strip.emplace_back(*it);\n }\n sort(strip.begin(),strip.end(),[](pair<long double,long double>&p,pair<long double,long double>&q){return p.second<q.second;});\n for(int i=0;i<strip.size();i++){\n for(int j=i-1;j>=0&&strip[j].second>strip[i].second-d;j--){\n d=min(d,dist(strip[i],strip[j]));\n }\n for(int j=i+1;j<strip.size()&&strip[j].second<strip[i].second+d;j++){\n d=min(d,dist(strip[i],strip[j]));\n }\n }\n return d;\n}\nint main(){\n int N;cin>>N;\n vector<pair<long double,long double>>P(N);\n for(int i=0;i<N;i++){\n cin>>P[i].first>>P[i].second;\n }\n sort(P.begin(),P.end());\n long double d=closest_pair(P.begin(),P.end());\n cout<<(long long)round(d*d)<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 18820, "score_of_the_acc": -0.1726, "final_rank": 11 }, { "submission_id": "aoj_0585_9610149", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid fastIO() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n}\n\n\nstruct pt{\n long long x, y;\n};\n\npt operator -(pt a, pt b){\n return {a.x - b.x, a.y - b. y};\n}\n\n\nlong long sq(pt p) {return p.x*p.x + p.y*p.y;}\nlong double abs(pt p) {return sqrt(sq(p));}\n\n\nconst long long oo = 1e18;\n\nint main() {\n fastIO();\n\n int n; cin >> n;\n\n vector<pt> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i].x >> v[i].y;\n }\n\n sort(v.begin(), v.end(), [&](pt & a, pt & b)->bool{\n return a.x < b.x;\n });\n\n set<pair<long long, long long>> sorted_y_window;\n\n long long ans = oo;\n long double best = oo;\n sorted_y_window.insert({v[0].y, v[0].x});\n\n int last_l = 0;\n for (int i = 1; i < n; ++i) {\n\n //Deleting Further than best\n while(last_l < n && v[i].x - v[last_l].x > best){\n sorted_y_window.erase({v[last_l].y, v[last_l].x});\n last_l++;\n }\n\n auto st = sorted_y_window.lower_bound({v[i].y - best, -oo});\n auto en = sorted_y_window.lower_bound({v[i].y + best, -oo});\n \n //iterating over points\n while(st != en){\n pt cur = {st->second, st->first};\n if(sq(v[i] - cur) < ans){\n ans = sq(v[i] - cur);\n best = abs(v[i] - cur);\n }\n st++;\n }\n //handeling if last point was not checked\n if(st != sorted_y_window.end()){\n pt cur = {st->second, st->first};\n if(sq(v[i] - cur) < ans){\n ans = sq(v[i] - cur);\n best = abs(v[i] - cur);\n }\n }\n sorted_y_window.insert({v[i].y, v[i].x});\n }\n\n cout << ans << endl;\n\n\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 10992, "score_of_the_acc": -0.0694, "final_rank": 7 }, { "submission_id": "aoj_0585_9610129", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid fastIO() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n}\n\n\n#define all(a) a.begin(),a.end()\n\nstruct pt{\n long long x, y;\n};\n\npt operator -(pt a, pt b){\n return {a.x - b.x, a.y - b. y};\n}\n\n\nlong long sq(pt p) {return p.x*p.x + p.y*p.y;}\nlong double abs(pt p) {return sqrt(sq(p));}\n\n\nconst long long oo = 1e18;\n\nint main() {\n fastIO();\n\n int n; cin >> n;\n\n vector<pt> v(n);\n for (long long i = 0; i < n; ++i) {\n cin >> v[i].x >> v[i].y;\n }\n\n sort(all(v), [&](pt & a, pt & b)->bool{\n return a.x < b.x;\n });\n\n set<pair<long long, long long>> sorted_y_window;\n\n long long x_line = v[0].x, ans = LLONG_MAX;\n long double best = 1e18;\n sorted_y_window.insert({v[0].y, v[0].x});\n\n long long last_l = 0;\n for (long long i = 1; i < n; ++i) {\n\n //Deleting Further than best\n while(last_l < n && v[i].x - v[last_l].x > best){\n sorted_y_window.erase({v[last_l].y, v[last_l].x});\n last_l++;\n }\n\n //caculating distances\n auto st = sorted_y_window.lower_bound({v[i].y - best, -oo});\n auto en = sorted_y_window.lower_bound({v[i].y + best, -oo});\n while(st != en){\n pt cur = {st->second, st->first};\n if(sq(v[i] - cur) < ans){\n ans = sq(v[i] - cur);\n best = abs(v[i] - cur);\n }\n st++;\n }\n if(st != sorted_y_window.end()){\n pt cur = {st->second, st->first};\n if(sq(v[i] - cur) < ans){\n ans = sq(v[i] - cur);\n best = abs(v[i] - cur);\n }\n }\n sorted_y_window.insert({v[i].y, v[i].x});\n }\n\n cout << ans << endl;\n\n\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 10588, "score_of_the_acc": -0.0679, "final_rank": 5 }, { "submission_id": "aoj_0585_9563955", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i, k, n) for (int i = k; i < n; i++)\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define pb push_back\n#define mp make_pair\n\ntypedef long long ll;\n//(x座標,y座標)\ntypedef pair<int, int> P;\n\nbool compare_y(P a, P b)\n{\n return a.second < b.second;\n}\n\n// イテレータを渡す\ntemplate <class T>\nint closest_pair(T a, int n)\n{\n if (n <= 1)\n return INT32_MAX;\n int m = n / 2;\n int x = (*(a + m)).first;\n int d = min(closest_pair(a, m), closest_pair(a + m, n - m));\n inplace_merge(a, a + m, a + n, compare_y);\n\n vector<P> b;\n rep(i, n)\n {\n if (abs((*(a + i)).first - x) >= d)\n continue;\n int xx = b.size();\n rep(j, xx)\n {\n int x = (*(a + i)).first - b.at(xx - 1 - j).first;\n int y = (*(a + i)).second - b.at(xx - 1 - j).second;\n if (y >= d)\n break;\n d = min(d, x * x + y * y);\n }\n b.push_back(*(a + i));\n }\n return d;\n}\n\nint main()\n{\n int n;\n cin >> n;\n\n vector<P> A(n);\n rep(i, n)\n {\n cin >> A[i].first >> A[i].second;\n }\n\n cout << closest_pair(A.begin(), n) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 12828, "score_of_the_acc": -0.1138, "final_rank": 9 }, { "submission_id": "aoj_0585_9501628", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define pb push_back\n#define all(v) v.begin(), v.end()\n#define fi first\n#define se second\nusing namespace std;\nconst ll N = 5e5 + 9;\nll n, i;\npair<ll,ll>a[N];\nint main()\n{\n#define TN \"\"\n if (fopen(TN \".inp\", \"r\"))\n {\n freopen(TN \".inp\", \"r\", stdin);\n freopen(TN \".out\", \"w\", stdout);\n }\n cin.tie(0)->sync_with_stdio(0);\n\n cin >> n ;\n\n for( i = 1; i <= n; i ++ )\n cin >> a[i].fi >> a[i].se;\n\n sort( a + 1, a + n + 1 );\n ll ans = 1e18;\n\n for( i = 1; i < n; i ++ )\n ans = min(ans, (a[i].fi - a[i + 1].fi) * ( a[i].fi - a[i + 1].fi ) + (a[i].se - a[i + 1].se) * ( a[i].se - a[i + 1].se ));\n\n for( i = 1; i <= n; i ++ )\n swap(a[i].fi, a[i].se);\n sort( a + 1, a + n + 1 );\n for( i = 1; i < n; i ++ )\n ans = min(ans, (a[i].fi - a[i + 1].fi) * ( a[i].fi - a[i + 1].fi ) + (a[i].se - a[i + 1].se) * ( a[i].se - a[i + 1].se ));\n\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 11188, "score_of_the_acc": -0.061, "final_rank": 4 }, { "submission_id": "aoj_0585_9476884", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <climits> // INT_MAXが定義されているヘッダ\n\nusing namespace std;\n\ntypedef pair<int, int> Point;\n\n// 点のx座標に基づいてソートするための比較関数\nbool compareX(const Point &a, const Point &b) {\n return a.first < b.first;\n}\n\n// 点のy座標に基づいてソートするための比較関数\nbool compareY(const Point &a, const Point &b) {\n return a.second < b.second;\n}\n\n// 2つの点間の距離の2乗を計算\nint distSquared(const Point &a, const Point &b) {\n int dx = a.first - b.first;\n int dy = a.second - b.second;\n return dx * dx + dy * dy;\n}\n\n// ブルートフォース法で最近点間距離を計算\nint bruteForce(const vector<Point> &points, int left, int right) {\n int minDist = INT_MAX;\n for (int i = left; i < right; ++i) {\n for (int j = i + 1; j < right; ++j) {\n minDist = min(minDist, distSquared(points[i], points[j]));\n }\n }\n return minDist;\n}\n\n// stripでの最小距離を求める\nint stripClosest(vector<Point> &strip, int size, int d) {\n int minDist = d;\n sort(strip.begin(), strip.begin() + size, compareY);\n for (int i = 0; i < size; ++i) {\n for (int j = i + 1; j < size && (strip[j].second - strip[i].second) * (strip[j].second - strip[i].second) < minDist; ++j) {\n minDist = min(minDist, distSquared(strip[i], strip[j]));\n }\n }\n return minDist;\n}\n\n// 分割統治法で最近点間距離を求める\nint closestUtil(vector<Point> &points, int left, int right) {\n if (right - left <= 3) {\n return bruteForce(points, left, right);\n }\n\n int mid = left + (right - left) / 2;\n Point midPoint = points[mid];\n\n int dl = closestUtil(points, left, mid);\n int dr = closestUtil(points, mid, right);\n\n int d = min(dl, dr);\n\n vector<Point> strip;\n for (int i = left; i < right; ++i) {\n if ((points[i].first - midPoint.first) * (points[i].first - midPoint.first) < d) {\n strip.push_back(points[i]);\n }\n }\n\n return min(d, stripClosest(strip, strip.size(), d));\n}\n\nint closest(vector<Point> &points) {\n sort(points.begin(), points.end(), compareX);\n return closestUtil(points, 0, points.size());\n}\n\nint main() {\n int n;\n cin >> n;\n vector<Point> points(n);\n for (int i = 0; i < n; ++i) {\n cin >> points[i].first >> points[i].second;\n }\n cout << closest(points) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 6808, "score_of_the_acc": -0.0597, "final_rank": 3 }, { "submission_id": "aoj_0585_9180943", "code_snippet": "#include <iostream>\n#include <utility>\n#include <climits>\n#include <vector>\n#include <cmath>\nusing namespace std;\n\nint manhattanndis(pair<int, int> point1,pair<int, int> point2){\n return abs(point1.first - point2.first) + abs(point1.second - point2.second);\n}\n\nint eudistance(pair<int, int> point1,pair<int, int> point2){\n return (point1.first - point2.first)*(point1.first - point2.first)+(point1.second - point2.second)*(point1.second - point2.second);\n}\n\nint main(){\n int n;\n cin >> n;\n vector< pair<int, int> > points(n);\n pair< pair<int, int>, pair<int, int> > closepair;\n int manhattanndistance, mindis = INT_MAX;\n \n for (int i = 0; i < n; i++){\n cin >> points[i].first >> points[i].second;\n }\n \n for (int j = 0; j < n; j++){\n for (int k = 0; k < n; k++){\n if (j != k){\n manhattanndistance = manhattanndis(points[j],points[k]);\n if (manhattanndistance < mindis){\n mindis = manhattanndistance;\n closepair = {points[j], points[k]};\n }\n }\n }\n }\n mindis = eudistance(closepair.first, closepair.second);\n cout << mindis << endl;\n \n}", "accuracy": 0.6, "time_ms": 4280, "memory_kb": 3440, "score_of_the_acc": -0.6927, "final_rank": 20 }, { "submission_id": "aoj_0585_9039433", "code_snippet": "#pragma region Macros\n\n#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,fma,abm,mmx,avx,avx2\")\n\n#include <bits/extc++.h>\n// #include <atcoder/all>\n// using namespace atcoder;\nusing namespace std;\nusing namespace __gnu_pbds;\n\n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// using Bint = mp::cpp_int;\n// using Bdouble = mp::number<mp::cpp_dec_float<256>>;\n\n#define pb emplace_back\n#define int ll\n#define endl '\\n'\n\n#define sqrt __builtin_sqrtl\n#define cbrt __builtin_cbrtl\n#define hypot __builtin_hypotl\n\n// #define next asdnext\n// #define prev asdprev\n\nusing ll = long long;\nusing ld = long double;\nconst ld PI = acosl(-1);\nconst int INF = 1 << 30;\nconst ll INFL = 1LL << 61;\n// const int MOD = 998244353;\nconst int MOD = 1000000007;\n\nconst ld EPS = 1e-10;\nconst bool equals(ld a, ld b) { return fabs((a) - (b)) < EPS; }\n\nconst vector<int> dx = {0, 1, 0, -1, 1, 1, -1, -1}; // → ↓ ← ↑ ↘ ↙ ↖ ↗\nconst vector<int> dy = {1, 0, -1, 0, 1, -1, -1, 1};\n\nstruct Edge {\n int from, to, cost;\n Edge() : from(-1), to(-1), cost(-1) {}\n Edge(int to, int cost) : to(to), cost(cost) {}\n Edge(int from, int to, int cost) : from(from), to(to), cost(cost) {}\n};\n\nchrono::system_clock::time_point start, now;\n__attribute__((constructor))\nvoid constructor() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout << fixed << setprecision(10);\n start = chrono::system_clock::now();\n}\n\n__int128_t POW(__int128_t x, int n) {\n __int128_t ret = 1;\n assert(n >= 0);\n if (x == 1 or n == 0) ret = 1;\n else if (x == -1 && n % 2 == 0) ret = 1; \n else if (x == -1) ret = -1; \n else if (n % 2 == 0) {\n assert(x < INFL);\n ret = POW(x * x, n / 2);\n } else {\n assert(x < INFL);\n ret = x * POW(x, n - 1);\n }\n return ret;\n}\nint per(int x, int y) { // x = qy + r (0 <= r < y) を満たすq\n assert(y != 0);\n if (x >= 0 && y > 0) return x / y;\n if (x >= 0 && y < 0) return x / y - (x % y < 0);\n if (x < 0 && y < 0) return x / y + (x % y < 0);\n return x / y - (x % y < 0); // (x < 0 && y > 0) \n}\nint mod(int x, int y) { // x = qy + r (0 <= r < y) を満たすr\n assert(y != 0);\n if (x >= 0) return x % y;\n __int128_t ret = x % y; // (x < 0)\n ret += (__int128_t)abs(y) * INFL;\n ret %= abs(y);\n return ret;\n}\nint floor(int x, int y) { // (ld)x / y 以下の最大の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x >= 0 ? x / y : (x + 1) / y - 1;\n}\nint ceil(int x, int y) { // (ld)x / y 以上の最小の整数\n assert(y != 0);\n if (y < 0) x = -x, y = -y;\n return x > 0 ? (x - 1) / y + 1 : x / y;\n}\nint round(int x, int y) {\n assert(y != 0);\n return (x * 2 + y) / (y * 2);\n}\nint round(int x, int y, int k) { // (ld)(x/y)を10^kの位に関して四捨五入\n assert(y != 0); // TODO\n return INF;\n}\nint round2(int x, int y) { // 五捨五超入 // 未verify\n assert(y != 0);\n if (y < 0) y = -y, x = -x;\n int z = z / y;\n if ((z * 2 + 1) * y <= y * 2) z++;\n return z;\n}\nint floor(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return floor(x / y);\n}\nint ceil(ld x, ld y) { // 誤差対策TODO // ceil(p/q) = -floor(-(p/q))らしい\n assert(!equals(y, 0));\n return ceil(x / y);\n}\nint perl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす q\n // 未verify. 誤差対策TODO. EPS外してもいいかも。\n assert(!equals(y, 0));\n if (x >= 0 && y > 0) return floor(x / y)+EPS;\n if (x >= 0 && y < 0) return -floor(x / fabs(y));\n if (x < 0 && y < 0) return floor(x / y) + (x - floor(x/y)*y < -EPS);\n return floor(x / y) - (x - floor(x/y)*y < -EPS); // (x < 0 && y > 0) \n}\nld modl(ld x, ld y) { // x = qy + r (0 <= r < y, qは整数) を満たす r\n // 未verify. 誤差対策TODO. -0.0が返りうる。\n assert(!equals(y, 0));\n if (x >= 0) return x - fabs(y)*fabs(per(x, y));\n return x - fabs(y)*floor(x, fabs(y));\n}\nint seisuu(ld x) { return (int)x; } // 整数部分. 誤差対策TODO\nint seisuu(int x, int y) {\n assert(y != 0);\n return x / y;\n}\nint seisuu(ld x, ld y) { // 誤差対策TODO\n assert(!equals(y, 0));\n return (int)(x / y);\n}\n\npair<int, int> max(const pair<int, int> &a, const pair<int, int> &b) {\n if (a.first > b.first or a.first == b.first && a.second > b.second) return a;\n return b;\n}\npair<int, int> min(const pair<int, int> &a, const pair<int, int> &b) {\n if (a.first < b.first or a.first == b.first && a.second < b.second) return a;\n return b;\n}\n\ntemplate <class T> bool chmax(T &a, const T& b) {\n if (a < b) { a = b; return true; } return false;\n}\ntemplate <class T> bool chmin(T &a, const T& b) {\n if (a > b) { a = b; return true; } return false;\n}\ntemplate <class T> T mid(T a, T b, T c) {\n return a + b + c - max({a, b, c}) - min({a, b, c});\n}\ntemplate <class T> void Sort(T &a, T &b, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b);\n } else {\n if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (b > c) swap(b, c);\n } else {\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\ntemplate <class T> void sort(T &a, T &b, T &c, T &d, bool rev = false) {\n if (rev == false) { \n if (a > b) swap(a, b); if (a > c) swap(a, c); if (a > d) swap(a, d);\n if (b > c) swap(b, c); if (b > d) swap(b, d); if (c > d) swap(c, d);\n } else {\n if (d > c) swap(d, c); if (d > b) swap(d, b); if (d > a) swap(d, a);\n if (c > b) swap(c, b); if (c > a) swap(c, a); if (b > a) swap(b, a);\n }\n}\n\nint countl_zero(int x) { return __builtin_clzll(x); }\nint countl_one(int x) {\n int ret = 0; while (x % 2) { x /= 2; ret++; } return ret;\n}\nint countr_zero(int x) { return __builtin_ctzll(x); }\nint countr_one(int x) {\n int ret = 0, k = 63 - __builtin_clzll(x);\n while (k != -1 && (x & (1LL << k))) { k--; ret++; }\n return ret;\n}\nint popcount(int x) { return __builtin_popcountll(x); }\nint unpopcount(int x) { return 64 - __builtin_clzll(x) - __builtin_popcountll(x); }\n\nint top_bit(int x) { return 63 - __builtin_clzll(x);} // 2^kの位\nint bot_bit(int x) { return __builtin_ctz(x);} // 2^kの位\nint MSB(int x) { return 1 << (63 - __builtin_clzll(x)); } // mask\nint LSB(int x) { return (x & -x); } // mask\n\nint bit_width(int x) { return 64 - __builtin_clzll(x); } // 桁数\nint ceil_log2(int x) { return 63 - __builtin_clzll(x); }\nint bit_floor(int x) { return 1 << (63 - __builtin_clzll(x)); }\nint floor_log2(int x) { return 64 - __builtin_clzll(x-1); }\nint bit_ceil(int x) { return 1 << (64 - __builtin_clzll(x-1)) - (x==1); }\n\nint hamming(int a, int b) { return popcount(a ^ b); }\nint compcnt(int x) { return (popcount(x^(x >> 1)) + (x&1)) / 2; }\n\nclass UnionFind {\npublic:\n\tUnionFind() = default;\n UnionFind(int N) : par(N), sz(N, 1) {\n iota(par.begin(), par.end(), 0);\n }\n\tint root(int x) {\n\t\tif (par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool unite(int x, int y) {\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n if (rx == ry) return false;\n\t\tif (sz[rx] < sz[ry]) swap(rx, ry);\n\t\tsz[rx] += sz[ry];\n\t\tpar[ry] = rx;\n return true;\n\t}\n\tbool issame(int x, int y) { return (root(x) == root(y)); }\n\tint size(int x) { return sz[root(x)]; }\n vector<vector<int>> groups(int N) {\n vector<vector<int>> G(N);\n for (int x = 0; x < N; x++) {\n G[root(x)].push_back(x);\n }\n\t\tG.erase( remove_if(G.begin(), G.end(),\n [&](const vector<int>& V) { return V.empty(); }), G.end());\n return G;\n }\nprivate:\n\tvector<int> par, sz;\n};\n\ntemplate<typename T>\nstruct BIT {\n int N; // 要素数\n vector<T> bit[2]; // データの格納先\n BIT(int N_, int x = 0) {\n N = N_ + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n if (x != 0) {\n for (int i = 0; i < N; i++) add(i, x);\n }\n }\n BIT(vector<int> &A) {\n N = A.size() + 1;\n bit[0].assign(N, 0); bit[1].assign(N, 0);\n for (int i = 0; i < (int)A.size(); i++) add(i, A[i]);\n }\n void add_sub(int p, int i, T x) {\n while (i < N) { bit[p][i] += x; i += (i & -i); }\n }\n void add(int l, int r, T x) {\n add_sub(0, l + 1, -x * l); add_sub(0, r + 1, x * r);\n add_sub(1, l + 1, x); add_sub(1, r + 1, -x);\n }\n void add(int i, T x) { add(i, i + 1, x); }\n T sum_sub(int p, int i) {\n T ret = 0;\n while (i > 0) { ret += bit[p][i]; i -= (i & -i); }\n return ret;\n }\n T sum(int i) { return sum_sub(0, i) + sum_sub(1, i) * i; }\n T sum(int l, int r) { return sum(r) - sum(l); }\n T get(int i) { return sum(i, i + 1); }\n void set(int i, T x) { T s = get(i); add(i, -s + x); }\n};\n\ntemplate<int mod> class Modint {\npublic:\n int val = 0;\n Modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }\n Modint(const Modint &r) { val = r.val; }\n\n Modint operator -() { return Modint(-val); } // 単項\n Modint operator +(const Modint &r) { return Modint(*this) += r; }\n Modint operator +(const int &q) { Modint r(q); return Modint(*this) += r; }\n Modint operator -(const Modint &r) { return Modint(*this) -= r; }\n Modint operator -(const int &q) { Modint r(q); return Modint(*this) -= r; }\n Modint operator *(const Modint &r) { return Modint(*this) *= r; }\n Modint operator *(const int &q) { Modint r(q); return Modint(*this) *= r; }\n Modint operator /(const Modint &r) { return Modint(*this) /= r; }\n Modint operator /(const int &q) { Modint r(q); return Modint(*this) /= r; }\n \n Modint& operator ++() { val++; if (val >= mod) val -= mod; return *this; } // 前置\n Modint operator ++(signed) { ++*this; return *this; } // 後置\n Modint& operator --() { val--; if (val < 0) val += mod; return *this; }\n Modint operator --(signed) { --*this; return *this; }\n Modint &operator +=(const Modint &r) { val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator +=(const int &q) { Modint r(q); val += r.val; if (val >= mod) val -= mod; return *this; }\n Modint &operator -=(const Modint &r) { if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator -=(const int &q) { Modint r(q); if (val < r.val) val += mod; val -= r.val; return *this; }\n Modint &operator *=(const Modint &r) { val = val * r.val % mod; return *this; }\n Modint &operator *=(const int &q) { Modint r(q); val = val * r.val % mod; return *this; }\n Modint &operator /=(const Modint &r) {\n int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n Modint &operator /=(const int &q) {\n Modint r(q); int a = r.val, b = mod, u = 1, v = 0;\n while (b) {int t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);}\n val = val * u % mod; if (val < 0) val += mod;\n return *this;\n }\n bool operator ==(const Modint& r) { return this -> val == r.val; }\n bool operator <(const Modint& r) { return this -> val < r.val; }\n bool operator >(const Modint& r) { return this -> val > r.val; }\n bool operator !=(const Modint& r) { return this -> val != r.val; }\n};\n\nusing mint = Modint<MOD>;\n// using Mint = modint998244353;\n\nistream &operator >>(istream &is, mint& x) {\n int t; is >> t; x = t; return (is);\n}\nostream &operator <<(ostream &os, const mint& x) {\n return os << x.val;\n}\nmint modpow(const mint &x, int n) {\n if (n < 0) return (mint)1 / modpow(x, -n); // 未verify\n assert(n >= 0);\n if (n == 0) return 1;\n mint t = modpow(x, n / 2);\n t = t * t;\n if (n & 1) t = t * x;\n return t;\n}\n\nint modpow(__int128_t x, int n, int mod) {\n assert(n >= 0 && mod > 0); // TODO: n <= -1\n __int128_t ret = 1;\n while (n > 0) {\n if (n % 2 == 1) ret = ret * x % mod;\n x = x * x % mod;\n n /= 2;\n }\n return ret;\n}\nint modinv(__int128_t x, int mod) {\n assert(mod > 0 && x > 0);\n if (x == 1) return 1;\n return mod - modinv(mod % x, mod) * (mod / x) % mod;\n}\n\nistream &operator >>(istream &is, __int128_t& x) {\n string S; is >> S;\n __int128_t ret = 0;\n int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9')\n ret = ret * 10 + S[i] - '0';\n x = ret * f;\n return (is);\n}\nostream &operator <<(ostream &os, __int128_t x) {\n ostream::sentry s(os);\n if (s) {\n __uint128_t tmp = x < 0 ? -x : x;\n char buffer[128]; char *d = end(buffer);\n do {\n --d; *d = \"0123456789\"[tmp % 10]; tmp /= 10;\n } while (tmp != 0);\n if (x < 0) { --d; *d = '-'; }\n int len = end(buffer) - d;\n if (os.rdbuf()->sputn(d, len) != len) os.setstate(ios_base::badbit);\n }\n return os;\n}\n\n__int128_t stoll(string &S) {\n __int128_t ret = 0; int f = 1;\n if (S[0] == '-') f = -1; \n for (int i = 0; i < S.length(); i++)\n if ('0' <= S[i] && S[i] <= '9') ret = ret * 10 + S[i] - '0';\n return ret * f;\n}\n__int128_t gcd(__int128_t a, __int128_t b) { return b ? gcd(b, a % b) : a; }\n__int128_t lcm(__int128_t a, __int128_t b) {\n return a / gcd(a, b) * b;\n // lcmが__int128_tに収まる必要あり\n}\n\nstring to_string(ld x, int k) { // xの小数第k位までをstring化する\n assert(k >= 0);\n stringstream ss;\n ss << setprecision(k + 2) << x;\n string s = ss.str();\n if (s.find('.') == string::npos) s += '.';\n int pos = s.find('.');\n for (int i = 0; k >= (int)s.size() - 1 - pos; i++) s += '0';\n s.pop_back();\n if (s.back() == '.') s.pop_back();\n return s;\n\n // stringstream ss; // 第k+1位を四捨五入して第k位まで返す\n // ss << setprecision(k + 1) << x;\n // string s = ss.str();\n // if (s.find('.') == string::npos) s += '.';\n // int pos = s.find('.');\n // for (int i = 0; k > (int)s.size() - 1 - pos; i++) s += '0';\n // if (s.back() == '.') s.pop_back();\n // return s;\n}\nstring to_string(__int128_t x) {\n string ret = \"\";\n if (x < 0) { ret += \"-\"; x *= -1; }\n while (x) { ret += (char)('0' + x % 10); x /= 10; }\n reverse(ret.begin(), ret.end());\n return ret;\n}\nstring to_string(char c) { string s = \"\"; s += c; return s; }\n\nstruct SXor128 {\n uint64_t x = 88172645463325252LL;\n unsigned Int() {\n x = x ^ (x << 7); return x = x ^ (x >> 9);\n }\n unsigned Int(unsigned mod) {\n x = x ^ (x << 7); x = x ^ (x >> 9); return x % mod;\n }\n unsigned Int(unsigned l, unsigned r) {\n x = x ^ (x << 7); x = x ^ (x >> 9); return x % (r - l + 1) + l;\n }\n double Double() {\n return double(Int()) / UINT_MAX;\n }\n} rnd;\n\nstruct custom_hash {\n static uint64_t splitmix64(uint64_t x) {\n x += 0x9e3779b97f4a7c15;\n x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n return x ^ (x >> 31);\n }\n\n size_t operator()(uint64_t x) const {\n static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n return splitmix64(x + FIXED_RANDOM);\n }\n};\n\ntemplate<class T> size_t HashCombine(const size_t seed,const T &v) {\n return seed^(hash<T>()(v)+0x9e3779b9+(seed<<6)+(seed>>2));\n}\ntemplate<class T,class S> struct hash<pair<T,S>>{\n size_t operator()(const pair<T,S> &keyval) const noexcept {\n return HashCombine(hash<T>()(keyval.first), keyval.second);\n }\n};\ntemplate<class T> struct hash<vector<T>>{\n size_t operator()(const vector<T> &keyval) const noexcept {\n size_t s=0;\n for (auto&& v: keyval) s=HashCombine(s,v);\n return s;\n }\n};\ntemplate<int N> struct HashTupleCore{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{\n size_t s=HashTupleCore<N-1>()(keyval);\n return HashCombine(s,get<N-1>(keyval));\n }\n};\ntemplate <> struct HashTupleCore<0>{\n template<class Tuple> size_t operator()(const Tuple &keyval) const noexcept{ return 0; }\n};\ntemplate<class... Args> struct hash<tuple<Args...>>{\n size_t operator()(const tuple<Args...> &keyval) const noexcept {\n return HashTupleCore<tuple_size<tuple<Args...>>::value>()(keyval);\n }\n};\n\nvector<mint> _fac, _finv, _inv;\nvoid COMinit(int N) {\n _fac.resize(N + 1); _finv.resize(N + 1); _inv.resize(N + 1);\n _fac[0] = _fac[1] = 1; _finv[0] = _finv[1] = 1; _inv[1] = 1;\n for (int i = 2; i <= N; i++) {\n _fac[i] = _fac[i-1] * mint(i);\n _inv[i] = -_inv[MOD % i] * mint(MOD / i);\n _finv[i] = _finv[i - 1] * _inv[i];\n }\n}\n\nmint FAC(int N) {\n if (N < 0) return 0; return _fac[N];\n}\nmint COM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[K] * _finv[N - K];\n}\nmint PERM(int N, int K) {\n if (N < K) return 0; if (N < 0 or K < 0) return 0;\n return _fac[N] * _finv[N - K];\n}\nmint NHK(int N, int K) {\n if (N == 0 && K == 0) return 1;\n return COM(N + K - 1, K);\n}\n\n#pragma endregion\n\nstruct Point {\n\tdouble x, y; // (x, y)\n\n\tPoint() {}\n\tPoint(double x, double y) :x(x), y(y) {}\n\n\tPoint operator+(const Point& p) const { return Point(x + p.x, y + p.y); }\n\tPoint operator-(const Point& p) const { return Point(x - p.x, y - p.y); }\n\tPoint operator*(const double& k) const { return Point(x * k, y * k); }\n\tPoint operator/(const double& k) const { return Point(x / k, y / k); }\n\n\tfriend istream& operator>>(istream& is, Point& p) {\n\t\tis >> p.x >> p.y;\n\t\treturn is;\n\t}\n\n\tbool operator==(const Point& p) const { return (fabs(x - p.x) < EPS && fabs(y - p.y) < EPS); }\n\tbool operator<(const Point& p) const { return (x != p.x ? x < p.x : y < p.y); }\n\t// (x, y) の辞書順比較\n\n\tdouble norm() { return x * x + y * y; }\n\tdouble abs() { return sqrt(norm()); }\n};\n\npair<ld, vector<Point>> cp_rec(vector<Point> &P, int lt, int sz) {\n if (sz <= 1) return make_pair(INFL, vector<Point>{P[lt]});\n\n int m = sz / 2;\n ld x = P[lt+m].x;\n auto [d1, q1] = cp_rec(P, lt, m);\n auto [d2, q2] = cp_rec(P, lt+m, sz-m);\n ld d = min(d1, d2);\n\n int s = 0, t = 0;\n vector<Point> Q;\n while (s < m && t < sz-m) {\n if (q1[s].y < q2[t].y) Q.pb(q1[s++]);\n else Q.pb(q2[t++]);\n }\n while (s < m) Q.pb(q1[s++]);\n while (t < sz-m) Q.pb(q2[t++]);\n\n vector<Point> b;\n for (int i = 0; i < sz; i++) {\n auto [ax, ay] = Q[i];\n if (abs(x - ax) >= d) continue;\n for (int j = (int)b.size() - 1; j >= 0; j--) {\n ld dx = ax - b[j].x;\n ld dy = ay - b[j].y;\n if (dy >= d) break;\n d = min(d, sqrt(dx*dx + dy*dy));\n }\n b.pb(Q[i]);\n }\n return make_pair(d, Q);\n}\n\nsigned main() {\n int N;\n cin >> N;\n vector<Point> P(N);\n for (int i = 0; i < N; i++) {\n int a, b;\n cin >> a >> b;\n P[i] = Point(a, b);\n }\n sort(P.begin(), P.end());\n\n auto ans = cp_rec(P, 0, int(P.size()));\n vector<Point> p = ans.second;\n ld d = ans.first;\n cout << (int)(d*d+EPS) << endl;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 44636, "score_of_the_acc": -0.3426, "final_rank": 14 }, { "submission_id": "aoj_0585_8496410", "code_snippet": "// ClosestPair\n// https://www.acmicpc.net/problem/2261\n// https://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0585\n#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing vl=vector<long long>;\nusing pl=pair<long long,long long>;\n\nlong long vlhashing(vl &a,long long rg){\n long long step=9223372036854775783ll%rg;\n long long res=0,ce=1;\n for(auto &nx : a){\n if(nx>=0){\n res+=((nx%rg)*ce);res%=rg;\n }\n else{\n res+=((rg-((-nx)%rg))*ce);res%=rg;\n }\n ce*=step;ce%=rg;\n }\n return res;\n}\n\nvl vlblk(vl &a,double x){\n vl res=a;\n for(auto &nx : res){\n nx=floor(((double)nx)/x);\n }\n return res;\n}\n\nvl vladd(vl &a,vl &b){\n vl res=a;\n for(long long i=0;i<a.size();i++){\n res[i]+=b[i];\n }\n return res;\n}\n\n// https://ir5.hatenablog.com/entry/20131221/1387557630\n// if you give d(p1, p2) = (return d^k), dpow should be k\n// gridsz ... prime is good\npl ClosestPair(vector<vl> &p,function<long long(vl&,vl&)> d,double dpow,long long gridsz){\n dpow = 1.0/dpow;\n long long n=p.size();\n long long dim=p[0].size();\n\n // cout << n << \" \" << dim << \"\\n\";\n\n vector<vl> adj={{}};\n for(long long i=0;i<dim;i++){\n long long sz=0;\n vector<vl> nadj;\n for(auto &nx : adj){\n for(long long j=-1;j<=1;j++){\n nadj.push_back(nx);\n nadj[sz].push_back(j);\n sz++;\n }\n }\n adj=nadj;\n }\n\n random_device seed_gen;\n mt19937_64 engine(seed_gen());\n vector<int> perm(n);\n for(int i=0;i<n;i++){perm[i]=i;}\n shuffle(perm.begin(),perm.end(),engine);\n\n long long ri=perm[0],rj=perm[1];\n long long mind=d(p[ri],p[rj]);\n double mindb=pow((double)mind,dpow);\n vector<vector<long long>> grid(gridsz);\n vector<long long> his;\n\n if(mind==0){return {ri,rj};}\n\n {\n vl bl0=vlblk(p[ri],mindb);\n long long h0=vlhashing(bl0,gridsz);\n grid[h0].push_back(ri);\n his.push_back(h0);\n }\n\n {\n vl bl0=vlblk(p[rj],mindb);\n long long h0=vlhashing(bl0,gridsz);\n grid[h0].push_back(rj);\n his.push_back(h0);\n }\n\n for(long long pt=2;pt<n;pt++){\n long long i=perm[pt];\n vl bl=vlblk(p[i],mindb);\n bool recon=false;\n for(auto &nx : adj){\n vl abl=vladd(bl,nx);\n long long ah=vlhashing(abl,gridsz);\n for(auto &ny : grid[ah]){\n long long cd=d(p[i],p[ny]);\n if(mind > cd){\n mind=cd;\n ri=i;rj=ny;\n recon=true;\n }\n }\n }\n if(recon){\n if(mind==0){return {ri,rj};}\n\n for(auto &nx : his){\n grid[nx].clear();\n }\n his.clear();\n\n mindb=pow((double)mind,dpow);\n\n for(long long pj=0;pj<=pt;pj++){\n long long j=perm[pj];\n vl cbl=vlblk(p[j],mindb);\n long long ch=vlhashing(cbl,gridsz);\n grid[ch].push_back(j);\n his.push_back(ch);\n }\n }\n else{\n long long h=vlhashing(bl,gridsz);\n grid[h].push_back(i);\n his.push_back(h);\n }\n }\n return {ri,rj};\n}\n\nlong long d(vl &a,vl &b){\n long long res=0;\n for(long long i=0;i<a.size();i++){\n res+=(a[i]-b[i])*(a[i]-b[i]);\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n long long n;\n cin >> n;\n long long dim=2;\n vector<vl> p(n);\n for(auto &nx : p){\n nx.resize(dim);\n for(auto &ny : nx){cin >> ny;}\n }\n pl res=ClosestPair(p,d,2.0,1000003);\n cout << d(p[res.first],p[res.second]) << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 73668, "score_of_the_acc": -0.6908, "final_rank": 17 }, { "submission_id": "aoj_0585_8496385", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nusing vl=vector<long long>;\nusing pl=pair<long long,long long>;\n\nlong long vlhashing(vl &a,long long rg){\n long long step=9223372036854775783ll%rg;\n long long res=0,ce=1;\n for(auto &nx : a){\n if(nx>=0){\n res+=((nx%rg)*ce);res%=rg;\n }\n else{\n res+=((rg-((-nx)%rg))*ce);res%=rg;\n }\n ce*=step;ce%=rg;\n }\n return res;\n}\n\nvl vlblk(vl &a,double x){\n vl res=a;\n for(auto &nx : res){\n nx=floor(((double)nx)/x);\n }\n return res;\n}\n\nvl vladd(vl &a,vl &b){\n vl res=a;\n for(long long i=0;i<a.size();i++){\n res[i]+=b[i];\n }\n return res;\n}\n\n// https://ir5.hatenablog.com/entry/20131221/1387557630\n// if you give d(p1, p2) = (return d^k), dpow should be k\n// gridsz ... prime is good\npl ClosestPair(vector<vl> &p,function<long long(vl&,vl&)> d,double dpow,long long gridsz){\n dpow = 1.0/dpow;\n long long n=p.size();\n long long dim=p[0].size();\n\n // cout << n << \" \" << dim << \"\\n\";\n\n vector<vl> adj={{}};\n for(long long i=0;i<dim;i++){\n long long sz=0;\n vector<vl> nadj;\n for(auto &nx : adj){\n for(long long j=-1;j<=1;j++){\n nadj.push_back(nx);\n nadj[sz].push_back(j);\n sz++;\n }\n }\n adj=nadj;\n }\n\n random_device seed_gen;\n mt19937_64 engine(seed_gen());\n vector<int> perm(n);\n for(int i=0;i<n;i++){perm[i]=i;}\n shuffle(perm.begin(),perm.end(),engine);\n\n long long ri=perm[0],rj=perm[1];\n long long mind=d(p[ri],p[rj]);\n double mindb=pow((double)mind,dpow);\n vector<vector<long long>> grid(gridsz);\n vector<long long> his;\n\n if(mind==0){return {ri,rj};}\n\n {\n vl bl0=vlblk(p[ri],mindb);\n long long h0=vlhashing(bl0,gridsz);\n grid[h0].push_back(ri);\n his.push_back(h0);\n }\n\n {\n vl bl0=vlblk(p[rj],mindb);\n long long h0=vlhashing(bl0,gridsz);\n grid[h0].push_back(rj);\n his.push_back(h0);\n }\n\n for(long long pt=2;pt<n;pt++){\n long long i=perm[pt];\n vl bl=vlblk(p[i],mindb);\n bool recon=false;\n for(auto &nx : adj){\n vl abl=vladd(bl,nx);\n long long ah=vlhashing(abl,gridsz);\n for(auto &ny : grid[ah]){\n long long cd=d(p[i],p[ny]);\n if(mind > cd){\n mind=cd;\n ri=i;rj=ny;\n recon=true;\n }\n }\n }\n if(recon){\n if(mind==0){return {ri,rj};}\n\n for(auto &nx : his){\n grid[nx].clear();\n }\n his.clear();\n\n mindb=pow((double)mind,dpow);\n\n for(long long pj=0;pj<pt;pj++){\n long long j=perm[pj];\n vl cbl=vlblk(p[j],mindb);\n long long ch=vlhashing(cbl,gridsz);\n grid[ch].push_back(j);\n his.push_back(ch);\n }\n }\n else{\n long long h=vlhashing(bl,gridsz);\n grid[h].push_back(i);\n his.push_back(h);\n }\n }\n return {ri,rj};\n}\n\nlong long d(vl &a,vl &b){\n long long res=0;\n for(long long i=0;i<a.size();i++){\n res+=(a[i]-b[i])*(a[i]-b[i]);\n }\n return res;\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n long long n;\n cin >> n;\n long long dim=2;\n vector<vl> p(n);\n for(auto &nx : p){\n nx.resize(dim);\n for(auto &ny : nx){cin >> ny;}\n }\n pl res=ClosestPair(p,d,2.0,1000003);\n cout << d(p[res.first],p[res.second]) << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 880, "memory_kb": 72832, "score_of_the_acc": -0.6742, "final_rank": 16 }, { "submission_id": "aoj_0585_8482698", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\ntypedef struct pos {\n int X;\n int Y;\n double D;\n} pos;\n\nbool compare(pos P1, pos P2) \n{ \n return (P1.D < P2.D); \n} \n \nint main(void){\n // Your code here!\n int N;\n cin >> N;\n vector <pos> P(N);\n int X,Y,D;\n for(int i=0;i<N;i++){\n cin >> X >> Y;\n D=sqrt(X*X+Y*Y);\n P[i].X=X;\n P[i].Y=Y;\n P[i].D=D;\n }\n \n sort(P.begin(), P.end(),compare);\n \n pos PA,PB;\n int XA,YA,DA,XB,YB,DB;\n int minD2=20000*20000*2+1;\n int D2;\n double minD=sqrt(minD2);\n \n \n for(int i=0;i<N-1;i++){\n PA=P[i];\n XA=PA.X;\n YA=PA.Y;\n DA=PA.D;\n for(int j=i+1;j<N;j++){\n PB=P[j];\n XB=PB.X;\n YB=PB.Y;\n DB=PB.D;\n if(DB-DA>minD){\n break;\n }\n /*\n if(D2A-D2B>minD2){\n break;\n }\n */\n D2=(XB-XA)*(XB-XA)+(YB-YA)*(YB-YA);\n if(D2<minD2){\n minD2=D2;\n minD=sqrt(minD2);\n }\n }\n }\n cout << minD2 <<endl;\n}", "accuracy": 1, "time_ms": 1000, "memory_kb": 10620, "score_of_the_acc": -0.2044, "final_rank": 12 }, { "submission_id": "aoj_0585_8482675", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\ntypedef struct pos {\n int X;\n int Y;\n int d2;\n} pos;\n\nbool compare(pos P1, pos P2) \n{ \n return (P1.d2 < P2.d2); \n} \n \nint main(void){\n // Your code here!\n int N;\n cin >> N;\n vector <pos> P(N);\n int X,Y,D2;\n for(int i=0;i<N;i++){\n cin >> X >> Y;\n D2=X*X+Y*Y;\n P[i].X=X;\n P[i].Y=Y;\n P[i].d2=D2;\n }\n \n sort(P.begin(), P.end(),compare);\n \n pos PA,PB;\n int XA,YA,D2A,XB,YB,D2B;\n int minD2=20000*20000*2+1;\n \n for(int i=0;i<N-1;i++){\n PA=P[i];\n XA=PA.X;\n YA=PA.Y;\n D2A=PA.d2;\n for(int j=i+1;j<N;j++){\n PB=P[j];\n XB=PB.X;\n YB=PB.Y;\n D2B=PB.d2;\n if(sqrt(D2B)-sqrt(D2A)>sqrt(minD2)){\n break;\n }\n /*\n if(D2A-D2B>minD2){\n break;\n }\n */\n D2=(XB-XA)*(XB-XA)+(YB-YA)*(YB-YA);\n if(D2<minD2){\n minD2=D2;\n }\n }\n }\n cout << minD2 <<endl;\n}", "accuracy": 1, "time_ms": 6130, "memory_kb": 8580, "score_of_the_acc": -1.0405, "final_rank": 18 }, { "submission_id": "aoj_0585_8479320", "code_snippet": "//made by Nguyễn Hồng Nam\n#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define int long long\nconst ll mod = 1e9 + 7,inf = 1e18,mxn = 5e5 + 5;\nint n,mi = inf;\ninline void minz(int &a,int b)\n{\n if(a > b) a = b;\n}\nstruct point\n{\n int x,y;\n};\nbool cmp_x(const point &a,const point &b)\n{\n return a.x < b.x;\n}\nbool cmp_y(const point &a,const point &b)\n{\n return a.y < b.y;\n}\nvoid upd(const point &a,const point &b)\n{\n int dist = (a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y);\n minz(mi,dist);\n}\npoint a[mxn];\nvoid solve(int l,int r)\n{\n if(r <= l) return ;\n if(r == l + 1)\n {\n upd(a[l],a[r]);\n if(!cmp_y(a[l],a[r])) swap(a[l],a[r]);\n return;\n }\n int m = (l + r) / 2;\n int midx = a[m].x;\n solve(l,m);\n solve(m + 1,r);\n static point t[mxn];\n merge(a + l,a + m + 1,a + m + 1,a + r + 1,t,cmp_y);\n copy(t,t + r - l + 1,a + l);\n int tm = 0;\n for(int i = l; i <= r; i++)\n {\n if(abs(a[i].x - midx) < mi)\n {\n for(int j = tm - 1; j >= 0 && t[j].y > a[i].y - mi; j--)\n {\n upd(a[i],t[j]);\n }\n t[tm++] = a[i];\n }\n }\n}\nint32_t main()\n{\n cin.tie(0)->sync_with_stdio(0);\n cin >> n;\n for(int i = 0; i < n; i++) cin >> a[i].x >> a[i].y;\n sort(a,a + n,cmp_x);\n solve(0,n - 1);\n cout << mi << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 18952, "score_of_the_acc": -0.2799, "final_rank": 13 } ]
aoj_0590_cpp
問題 4 IOI 不動産ではマンションの賃貸を行なっている. この会社が取り扱うマンションの部屋は 1LDK で, 下図のように面積が 2xy+x+y になっている. ただし, x, y は正整数である. IOI 不動産のカタログにはマンションの面積が昇順に(狭いものから順番に)書かれているが,この中にいくつか間違い(ありえない面積のもの)が混じっていることがわかった. カタログ(入力ファイル)は N+1 行で,最初の行に部屋数が書かれていて, 続く N 行に,1行に1部屋ずつ面積が昇順に書かれている. ただし, 部屋数は 100,000 以下, 面積は (2の31乗)-1 = 2,147,483,647 以下である. 5つの入力データのうち3つまでは, 部屋数 1000 以下,面積 30000 以下である. 間違っている行数(ありえない部屋の数)を出力しなさい. 出力ファイルにおいては, 出力の最後の行にも改行コードを入れること. 入出力例 入力例 10 4 7 9 10 12 13 16 17 19 20 出力例 2 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0590_10848577", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nvoid Freopen () {\n #ifndef ONLINE_JUDGE\n freopen(\"input.txt\", \"r\", stdin);\n freopen(\"output.txt\", \"w\", stdout);\n #endif\n}\n\nint main() {\n long long n;\n cin >> n;\n long long cnt = 0;\n for (int i = 1; i <= n; i++) {\n long long a;\n cin >> a;\n long long x = 1;\n while (2 * x * x + 2 * x <= a) {\n if ((a - x) % (2 * x + 1) == 0) {\n cnt++;\n break;\n }\n x++;\n }\n }\n cout << n - cnt << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3436, "score_of_the_acc": -0.702, "final_rank": 10 }, { "submission_id": "aoj_0590_10312900", "code_snippet": "#include<bits/stdc++.h> \nusing namespace std;\n\nusing ll=long long;\n\nint main(){\n\t\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tint cnt=0;\n\tint N;\n\tcin>>N;\n\tfor(int i=0;i<N;i++){\n\t\tll C;\n\t\tcin>>C;\n\t\tC*=2;\n\t\tC++;\n\t\tbool EG=0;\n\t\tfor(ll x=1;(2*x+1)*(2*x+1)<=C;x++){\n\t\t\tif(C%(2*x+1)==0){\n\t\t\t\tll y2=C/(2*x+1);\n\t\t\t\tif(y2%2==1&&y2>1){\n\t\t\t\t\tEG=1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(!EG){\n\t\t\tcnt++;\n\t\t}\n\t}\n\tcout<<cnt<<endl;\n\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3584, "score_of_the_acc": -0.9593, "final_rank": 17 }, { "submission_id": "aoj_0590_9668370", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n int N;cin>>N;\n int ans=0;\n while(N--){\n ll x;cin>>x;\n x+=x+1;\n {\n ans++;\n ll d=2;\n while(d*d<=x){\n if(x%d==0){ans--;break;}\n d++;\n }\n }\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3432, "score_of_the_acc": -0.7151, "final_rank": 13 }, { "submission_id": "aoj_0590_9585494", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nvoid Freopen () {\n #ifndef ONLINE_JUDGE\n freopen(\"input.txt\", \"r\", stdin);\n freopen(\"output.txt\", \"w\", stdout);\n #endif\n}\n\nint main() {\n long long n;\n cin >> n;\n long long cnt = 0;\n for (int i = 1; i <= n; i++) {\n long long a;\n cin >> a;\n long long x = 1;\n while (2 * x * x + 2 * x <= a) {\n if ((a - x) % (2 * x + 1) == 0) {\n cnt++;\n break;\n }\n x++;\n }\n }\n cout << n - cnt << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3484, "score_of_the_acc": -0.7909, "final_rank": 16 }, { "submission_id": "aoj_0590_7973138", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nnamespace factrize {\n using u64 = uint64_t;\n using u128 = __uint128_t;\n\n u128 pow (u128 a, u64 n, u128 mod) {\n u128 res = 1;\n if (a >= mod) a %= mod;\n while (n > 0) {\n if (n & 1) {\n res *= a;\n res %= mod;\n }\n a *= a;\n a %= mod;\n n >>= 1;\n }\n return res;\n }\n\n bool miller_rabin (u64 n, vector<u64> v) {\n u64 d = n-1;\n while (~d & 1) d >>= 1;\n for (u64 a : v) {\n if (n <= a) break;\n u64 t = d;\n u128 y = pow(a, t, n);\n while (t != n-1 and y != 1 and y != n-1) {\n y *= y; if (y >= n) y %= n;\n t *= 2;\n }\n if (y != n-1 and t%2 == 0) return false;\n }\n return true;\n }\n\n bool is_prime (u64 n) {\n if (n <= 1) return false;\n if (~n & 1) return n == 2;\n if (n < (1LL << 30)) {\n return miller_rabin(n, {2, 7, 61});\n }\n else {\n return miller_rabin(n, {2, 325, 9375, 28178, 450775, 9780504, 1795265022});\n }\n }\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n // 2xy + x + y = n\n int q; cin >> q;\n int res = 0;\n while (q--) {\n ll n; cin >> n;\n if (factrize::is_prime(2*n+1)) res++;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3452, "score_of_the_acc": -0.7111, "final_rank": 12 }, { "submission_id": "aoj_0590_7973022", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n // 2xy + x + y = n\n int q; cin >> q;\n int res = 0;\n while (q--) {\n ll n; cin >> n;\n res++;\n for (ll x = 1; 2*x*x <= n; x++) {\n // (2x+1) * y = (n-x)\n if ((n-x) % (2*x+1) == 0) {\n res--; break;\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3380, "score_of_the_acc": -0.5964, "final_rank": 7 }, { "submission_id": "aoj_0590_7022108", "code_snippet": "#include <iostream> \n#include <cmath>\n#include <utility>\n\nusing namespace std;\n\nbool f(long area){\n long num=2*area+1;\n long sq=ceil(sqrt(num));\n for (int i=3; i<=sq; i+=2){\n if(num%i==0)return true;\n }\n return false;\n}\n\nint main(){\n int n;\n cin>>n;\n int res=0;\n int num;\n for(int i=0; i<n; i++){\n cin>>num;\n if(!f(num))res++;\n }cout<<res<<endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3112, "score_of_the_acc": -0.1057, "final_rank": 2 }, { "submission_id": "aoj_0590_6842562", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#ifdef _RUTHEN\n#include \"debug.hpp\"\n#else\n#define show(...) true\n#endif\n\nusing ll = long long;\n#define rep(i, n) for (int i = 0; i < (n); i++)\ntemplate <class T> using V = vector<T>;\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n const ll M = 46000;\n int N;\n cin >> N;\n int ans = 0;\n rep(i, N) {\n ll v;\n cin >> v;\n ll ub = min(M, v);\n int ok = 1;\n for (ll x = 1; x <= M; x++) {\n if (2 * x + 1 + x > v) break;\n if (x == v % (2 * x + 1)) {\n ok = 0;\n break;\n }\n }\n ans += ok;\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3372, "score_of_the_acc": -0.5816, "final_rank": 6 }, { "submission_id": "aoj_0590_6587447", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tll N=in();\n\tll S=0;\n\tLOOP(N){\n\t\tll A=in();\n\t\tbool exist=false;\n\t\tREP(i,65536){\n\t\t\tll B=2*(i+1)*(i+2);\n\t\t\tll C=A-B;\n\t\t\tif(C<0){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tll M=2*(i+1)+1;\n\t\t\tif(!(C%M)){\n\t\t\t\texist=true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(!exist) S++;\n\t}\n\tout(S);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3448, "score_of_the_acc": -0.7242, "final_rank": 14 }, { "submission_id": "aoj_0590_6587424", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tll N=in();\n\tll S=0;\n\tREP(i,N){\n\t\tll A=in();\n\t\tbool exist=false;\n\t\tREP(i,65536){\n\t\t\tll B=2*(i+1)*(i+2);\n\t\t\tll C=A-B;\n\t\t\tif(C<0){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tll M=2*(i+1)+1;\n\t\t\tif(!(C%M)){\n\t\t\t\texist=true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t\tif(!exist) S++;\n\t}\n\tout(S);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3304, "score_of_the_acc": -0.4576, "final_rank": 5 }, { "submission_id": "aoj_0590_6308738", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n int ans=0;\n codefor{\n LL(n);\n bool h=false;\n for(ll i=1;i*i<=n;i++){\n if((n-i)%(2*i+1)==0){\n h=true;\n break;\n }\n }\n if(!h)ans++;\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 3608, "score_of_the_acc": -1.0187, "final_rank": 19 }, { "submission_id": "aoj_0590_6269597", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define all(x) (x).begin(), (x).end()\n\nusing ll = long long;\nusing i128 = __int128;\n\nll mul(ll x, ll y, ll m) { return (i128)x * y % m; }\nll modpow(ll x, ll y, ll m) {\n\tll ret = 1, t = x % m;\n\twhile (y) {\n\t\tif (y & 1) ret = mul(ret, t, m);\n\t\tt = mul(t, t, m);\n\t\ty >>= 1;\n\t}\n\treturn ret;\n}\n\nbool miller_rabin(ll x, ll a) {\n\tif (x % a == 0) return false;\n\tll d = x - 1; int cnt = -1;\n\twhile (!(d & 1)) {\n\t\td >>= 1;\n\t\tcnt++;\n\t}\n\tll p = modpow(a, d, x);\n\tif (p == 1 || p == x - 1) return false;\n\twhile (cnt--) {\n\t\tp = mul(p, p, x);\n\t\tif (p == x - 1) return false;\n\t}\n\treturn true;\n}\n\nbool is_prime(ll x) {\n\tfor (auto& i : { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 }) {\n\t\tif (x == i) return true;\n\t\tif (x > 40 && miller_rabin(x, i)) return false;\n\t}\n\treturn x > 40;\n}\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(0);\n\n\tint n; cin >> n;\n\tint cnt = 0;\n\twhile (n--) {\n\t\tll a; cin >> a;\n\t\tif (is_prime(2 * a + 1)) cnt++;\n\t}\n\tcout << cnt << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3448, "score_of_the_acc": -0.7037, "final_rank": 11 }, { "submission_id": "aoj_0590_6269595", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define all(x) (x).begin(), (x).end()\n\nusing ull = unsigned long long;\nusing i128 = __int128;\n\null mul(ull x, ull y, ull m) { return (i128)x * y % m; }\null modpow(ull x, ull y, ull m) {\n\tull ret = 1, t = x % m;\n\twhile (y) {\n\t\tif (y & 1) ret = mul(ret, t, m);\n\t\tt = mul(t, t, m);\n\t\ty >>= 1;\n\t}\n\treturn ret;\n}\n\nbool miller_rabin(ull x, ull a) {\n\tif (x % a == 0) return false;\n\tull d = x - 1;\n\twhile (true) {\n\t\tull t = modpow(a, d, x);\n\t\tif (d & 1) return t != 1 && t != x - 1;\n\t\telse if (t == x - 1) return false;\n\t\td >>= 1;\n\t}\n}\n\nbool is_prime(ull x) {\n\tfor (auto& i : { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 }) {\n\t\tif (x == i) return true;\n\t\tif (x > 40 && miller_rabin(x, i)) return false;\n\t}\n\treturn x > 40;\n}\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(0);\n\n\tint n; cin >> n;\n\tint cnt = 0;\n\twhile (n--) {\n\t\tull a; cin >> a;\n\t\tif (is_prime(2 * a + 1)) cnt++;\n\t}\n\tcout << cnt << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3408, "score_of_the_acc": -0.6352, "final_rank": 8 }, { "submission_id": "aoj_0590_6269580", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define all(x) (x).begin(), (x).end()\n\nusing ll = long long;\nusing i128 = __int128;\n\nll mul(ll x, ll y, ll m) { return (i128)x * y % m; }\nll modpow(ll x, ll y, ll m) {\n\tll ret = 1, t = x % m;\n\twhile (y) {\n\t\tif (y & 1) ret = mul(ret, t, m);\n\t\tt = mul(t, t, m);\n\t\ty >>= 1;\n\t}\n\treturn ret;\n}\n\nbool miller_rabin(ll x, ll a) {\n\tif (x % a == 0) return false;\n\tll d = x - 1;\n\twhile (true) {\n\t\tll t = modpow(a, d, x);\n\t\tif (d & 1) return t != 1 && t != x - 1;\n\t\telse if (t == x - 1) return false;\n\t\td >>= 1;\n\t}\n}\n\nbool is_prime(ll x) {\n\tfor (auto& i : { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37 }) {\n\t\tif (x == i) return true;\n\t\tif (x > 40 && miller_rabin(x, i)) return false;\n\t}\n\treturn x > 40;\n}\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(0);\n\n\tint n; cin >> n;\n\tint cnt = 0;\n\twhile (n--) {\n\t\tll a; cin >> a;\n\t\tif (is_prime(2 * a + 1)) cnt++;\n\t}\n\tcout << cnt << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3444, "score_of_the_acc": -0.7019, "final_rank": 9 }, { "submission_id": "aoj_0590_5266116", "code_snippet": "//2xy+x+y=S\n//(2x+1)(y+1/2)=S+1/2\n//(2x+1)(2y+1)=2S+1\n\n#include <iostream>\n#include <cmath>\nusing namespace std;\n\nint main(void){\n long retval = 0;\n long N;\n cin>>N;\n for(long i=0;i<N;i++){\n long long area;\n cin>>area;\n area = 2*area+1;\n bool able = false;\n for(long long i=3;i<min((long long)65570,area);i+=2){\n if(area%i==0){\n able = true;\n break;\n }\n }\n if(able==false){\n retval++;\n }\n }\n cout<<retval<<endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3116, "score_of_the_acc": -0.1131, "final_rank": 3 }, { "submission_id": "aoj_0590_5029955", "code_snippet": "#include<iostream>\n#include<cmath>\n\nusing namespace std;\n\n#define Long long long\n\nint main()\n{\n\tint N;\n\tcin >> N;\n\tint s;\n\tint ans = N;\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tcin >> s;\n\t\tint bound = sqrt(s);\n\t\tfor (int x = 1; x <= bound; x++)\n\t\t{\n\t\t\tif ((s - x) % (1 + 2 * x) == 0)\n\t\t\t{\n\t\t\t\tans--;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\tcin >> N;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3096, "score_of_the_acc": -0.0593, "final_rank": 1 }, { "submission_id": "aoj_0590_5029942", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\n#define Long long long\n\nint main()\n{\n\tint N;\n\tcin >> N;\n\tint s;\n\tint ans = N;\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tcin >> s;\n\t\tint MAX = (s - 1) / 3;\n\t\tint bound = MAX / 2 + 1;\n\t\tfor (int x = 1; x <= bound; x++)\n\t\t{\n\t\t\tif ((s - x) % (1 + 2 * x) == 0)\n\t\t\t{\n\t\t\t\tans--;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 5380, "memory_kb": 3068, "score_of_the_acc": -1, "final_rank": 18 }, { "submission_id": "aoj_0590_4919536", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long llong;\n\nsigned main() {\n int n; cin >> n;\n int errors = 0;\n for(int i=0; i<n; i++) {\n llong area; cin >> area;\n if(area < 4) {\n errors++;\n continue;\n }\n if(area % 3 == 1) continue;\n bool flg = false;\n for(llong x=2; x*x<=area; x++) {\n llong left = 1LL;\n llong right = area;\n while(left <= right) {\n llong y = (left + right) / 2;\n llong act = 2*x*y+x+y;\n if(act == area) {\n flg = true;\n break;\n } else if(act < area) {\n left = y+1;\n } else {\n right = y-1;\n }\n }\n if(flg) break;\n }\n if(!flg) errors++;\n }\n cout << errors << endl;\n}", "accuracy": 1, "time_ms": 1400, "memory_kb": 3332, "score_of_the_acc": -0.7464, "final_rank": 15 }, { "submission_id": "aoj_0590_4898481", "code_snippet": "#include<iostream>\nusing namespace std;\nint n;\nmain(){\n\tcin>>n;int cnt=0;\n\tfor(;n--;){\n\t\tlong long a;cin>>a;bool ok=0;\n\t\tfor(long long x=1;x*(x+1)*2<=a;x++){\n\t\t\tif((a-x)%(2*x+1)<1){\n\t\t\t\tok=1;break;\n\t\t\t}\n\t\t}if(!ok)cnt++;\n\t}cout<<cnt<<endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 3120, "score_of_the_acc": -0.1224, "final_rank": 4 }, { "submission_id": "aoj_0590_4812131", "code_snippet": "#include <iostream>\n\nusing lint = long long;\n\nvoid solve() {\n int cnt = 0;\n\n int n;\n std::cin >> n;\n while (n--) {\n lint s;\n std::cin >> s;\n s = s * 2 + 1;\n\n bool judge = false;\n for (lint p = 3; p * p <= s; p += 2) {\n if (s % p == 0) judge = true;\n }\n\n if (!judge) ++cnt;\n }\n\n std::cout << cnt << \"\\n\";\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 5060, "memory_kb": 3176, "score_of_the_acc": -1.1403, "final_rank": 20 } ]
aoj_0591_cpp
問題 5 IOI 宝飾店ではビーズのネックレスを売り出すことになった. ビーズは n 色あり, これらをそれぞれ m 個以上ずつ選んで r 個のビーズからなるネックレスとし, 1つずつ化粧箱に入れて販売したい. 色の組合せが違うものをすべて1つずつ用意したいが, 化粧箱を何個用意したらよいか店員の誰もわからない. n, m, r によっては現実的でない個数の化粧箱が必要となるのではないかと店長は心配している. IOI 宝飾店の店長に代わって, 必要な化粧箱の個数を出力するプログラムを作成しなさい. n, m, r は整数で,0≦m<n≦r≦10000 である. 入力ファイルは1行で, 空白を区切りとして n, m, r がこの順に書いてある. 入力ファイル5つのうちの3つでは n≦10 である. 出力ファイルにおいては, 出力の最後の行にも改行コードを入れること. 入出力例 入力例1 2 0 3 出力例1 4 入力例2 3 1 4 出力例2 3 入力例3 4 2 5 出力例3 0 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0591_7940050", "code_snippet": "#include <cstdio>\n#include <cstring>\n#define BASE (1000000)\ntypedef long long lint;\nint main() {\n int n, m, r;\n int head, tail;\n int i, j;\n static lint ans[20000], temp[20000];\n lint carry;\n tail = sizeof(ans) / sizeof(lint) - 1;\n scanf(\"%d%d%d\", &n, &m, &r);\n if (r - m * n < 0 || n + r - m * n - 1 < 0) {\n printf(\"0\\n\");\n } else {\n head = tail;\n ans[tail] = 1;\n for (i = 1; i <= n + r - m * n - 1; i++) {\n carry = 0;\n for (j = tail; j >= head; j--) {\n carry += i * ans[j];\n ans[j] = carry % BASE;\n carry /= BASE;\n }\n while (carry != 0) {\n ans[--head] = carry % BASE;\n carry /= BASE;\n }\n }\n for (i = r - m * n; i >= 2; i--) {\n memcpy(temp, ans, sizeof(ans));\n carry = 0;\n for (j = head; j <= tail; j++) {\n carry = carry * BASE + temp[j];\n ans[j] = carry / i;\n carry %= i;\n }\n }\n for (i = n - 1; i >= 2; i--) {\n memcpy(temp, ans, sizeof(ans));\n carry = 0;\n for (j = head; j <= tail; j++) {\n carry = carry * BASE + temp[j];\n ans[j] = carry / i;\n carry %= i;\n }\n }\n while (ans[head] == 0) {\n head++;\n }\n for (i = head; i <= tail; i++) {\n if (i != head) {\n printf(\"%06lld\", ans[i]);\n } else {\n printf(\"%lld\", ans[i]);\n }\n }\n printf(\"\\n\");\n }\n return (0);\n}", "accuracy": 1, "time_ms": 3170, "memory_kb": 2952, "score_of_the_acc": -0.4989, "final_rank": 8 }, { "submission_id": "aoj_0591_7940049", "code_snippet": "#include <cstdio>\n#include <cstring>\n#define BASE (1000000)\ntypedef long long lint;\nint main() {\n int n, m, r;\n int head, tail;\n int i, j;\n static lint ans[20000], temp[20000];\n lint carry;\n tail = sizeof(ans) / sizeof(lint) - 1;\n scanf(\"%d%d%d\", &n, &m, &r);\n if (r - m * n < 0 || n + r - m * n - 1 < 0) {\n printf(\"0\\n\");\n } else {\n head = tail;\n ans[tail] = 1;\n for (i = n; i <= n + r - m * n - 1; i++) {\n carry = 0;\n for (j = tail; j >= head; j--) {\n carry += i * ans[j];\n ans[j] = carry % BASE;\n carry /= BASE;\n }\n while (carry != 0) {\n ans[--head] = carry % BASE;\n carry /= BASE;\n }\n }\n for (i = r - m * n; i >= 2; i--) {\n memcpy(temp, ans, sizeof(ans));\n carry = 0;\n for (j = head; j <= tail; j++) {\n carry = carry * BASE + temp[j];\n ans[j] = carry / i;\n carry %= i;\n }\n }\n while (ans[head] == 0) {\n head++;\n }\n for (i = head; i <= tail; i++) {\n if (i != head) {\n printf(\"%06lld\", ans[i]);\n } else {\n printf(\"%lld\", ans[i]);\n }\n }\n printf(\"\\n\");\n }\n return (0);\n}", "accuracy": 1, "time_ms": 870, "memory_kb": 2960, "score_of_the_acc": -0.197, "final_rank": 3 }, { "submission_id": "aoj_0591_6308787", "code_snippet": "#include <bits/stdc++.h>\n#include <boost/multiprecision/cpp_int.hpp>\nusing namespace std;\n\nboost::multiprecision::cpp_int combination(long long int a,long long int b){\n boost::multiprecision::cpp_int ans=1;\n b=min(b,a-b);\n for(int i=0;i<b;i++){\n ans*=a-b+i+1;\n ans/=i+1;\n }\n return ans;\n}\n\nint main(){\n long long n,m,r;\n cin>>n>>m>>r;\n r-=n*m;\n if(r<0){\n cout<<0<<endl;\n return 0;\n }\n cout<<combination(r+n-1,n-1)<<endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3228, "score_of_the_acc": -0.1084, "final_rank": 2 }, { "submission_id": "aoj_0591_5279530", "code_snippet": "#include <iostream>\nusing namespace std;\n\nlong long solve(long long n, long long r);\n\nint main(void){\n long long n,m,r;\n cin>>n>>m>>r;\n r-=n*m;\n if(r<0){\n cout<<0<<endl;\n return 0;\n }\n cout<<solve(n,r)<<endl;\n return 0;\n}\n\n\nlong long solve(long long n, long long r){\n long long** table = new long long* [n+10];\n for(long long i=0;i<n+10;i++){\n table[i] = new long long[r+10];\n for(long long j=0;j<r+10;j++){\n table[i][j]=0;\n }\n }\n for(long long j=0;j<r+1;j++){\n table[1][j]=1;\n }\n for(long long i=0;i<n+1;i++){\n table[i][0]=1;\n }\n for(long long i=1;i<n+1;i++){\n for(long long j=1;j<r+1;j++){\n table[i][j]=1;\n for(long long k=0;k<j;k++){\n table[i][j]+=table[i-1][j-k];\n }\n }\n }\n /*\n for(long long i=0;i<n+1;i++){\n for(long long j=0;j<r+1;j++){\n cout<<table[i][j]<<\"\\t\";\n }\n cout<<endl;\n }\n */\n return table[n][r];\n}", "accuracy": 0.6, "time_ms": 200, "memory_kb": 11072, "score_of_the_acc": -0.49, "final_rank": 18 }, { "submission_id": "aoj_0591_3996015", "code_snippet": "// includes\n#include <bits/stdc++.h>\nusing namespace std;\n\n// macros\n#define pb emplace_back\n#define mk make_pair\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)\n#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)\n#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)\n#define all(x) (x).begin(),(x).end()\n#define sz(x) ((int)(x).size())\n#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())\n#define bit(n) (1LL<<(n))\n// functions\ntemplate <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}\ntemplate <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << p.first << \" \" << p.second; return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << \":\" << itr->second; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << itr->first << \":\" << itr->second; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\n// types\nusing ll = long long int;\nusing P = pair<int, int>;\n// constants\nconst int inf = 1e9;\nconst ll linf = 1LL << 50;\nconst double EPS = 1e-10;\nconst int mod = 1000000007;\nconst int dx[4] = {-1, 0, 1, 0};\nconst int dy[4] = {0, -1, 0, 1};\n// io\nstruct fast_io{\n fast_io(){ios_base::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20);}\n} fast_io_;\n\nusing cd = complex<double>;\n// f.size() should be the power of 2.\nvoid rec_fft(vector<cd> &f, bool inv=false){\n int n = f.size();\n if(n == 1)return;\n vector<cd> f0(n / 2), f1(n / 2);\n for(int i = 0; i < n / 2; i++){\n f0[i] = f[i * 2];\n f1[i] = f[i * 2 + 1];\n }\n rec_fft(f0, inv);\n rec_fft(f1, inv);\n double th = M_PI * 2 / n;\n if(inv)th = - th;\n cd u(cos(th), sin(th)), ui(1, 0);\n for(int i = 0; i < n; i++){\n f[i] = f0[i%(n/2)] + ui * f1[i%(n/2)];\n ui = ui * u;\n }\n}\n\n// f.size() should be the power of 2.\nvoid fft(vector<cd> &f, bool inv=false){\n int n = f.size(), mask = n - 1;\n vector<cd> tmp(n);\n for(int i = n >> 1; i >= 1; i >>= 1){\n cd zeta = polar(1., 2. * M_PI * i * (inv ? -1.: 1.) / n);\n cd w = 1;\n for(int j = 0; j < n; j += i){\n for(int k = 0; k < i; k++){\n tmp[j + k] = f[((j<<1)&mask) + k] + w * f[(((j<<1)+i)&mask)+k];\n }\n w *= zeta;\n }\n swap(f, tmp);\n }\n}\n\nvoid dft(vector<cd> &f){\n fft(f);\n}\n\nvoid idft(vector<cd> &f){\n fft(f, true);\n for(size_t i = 0; i < f.size(); i++)f[i] = f[i] / cd(f.size());\n}\n\ntemplate <typename T>\nvector<T> convolution(const vector<T> &f, const vector<T> &g){\n int n = 1;\n while(n < 2 * f.size() + 1)n *= 2;\n vector<cd> F(n, 0), G(n, 0);\n for(int i = 0; i < f.size(); i++)F[i] = cd(f[i]);\n for(int i = 0; i < g.size(); i++)G[i] = cd(g[i]);\n\n dft(F);\n dft(G);\n vector<cd> H(n);\n for(int i = 0; i < n; i++)H[i] = F[i] * G[i];\n idft(H);\n vector<T> h(n);\n for(int i = 0; i < n; i++){\n h[i] = T(round(H[i].real()));\n }\n return h;\n}\n\nvector<ll> convert_base(const vector<ll> &v, int old_b, int new_b){\n vector<ll> p(max(new_b, old_b) + 1);\n p[0] = 1;\n for(int i = 1; i < p.size(); i++)p[i] = p[i-1] * 10;\n vector<ll> res;\n ll curr = 0;\n int curr_b = 0;\n for(int i = 0; i < v.size(); i++){\n curr += v[i] * p[curr_b];\n curr_b += old_b;\n while(curr_b >= new_b){\n res.push_back(curr % p[new_b]);\n curr /= p[new_b];\n curr_b -= new_b;\n }\n }\n res.push_back(curr);\n while(!res.empty() && res.back() == 0)res.pop_back();\n return res;\n}\n\nvector<ll> simple_multiply(const vector<ll> &x, const vector<ll> &y){\n vector<ll> res(x.size() + y.size() - 1, 0);\n for(int i = 0; i < x.size(); i++){\n for(int j = 0; j < y.size(); j++){\n res[i+j] += x[i] * y[j];\n }\n }\n while(!res.empty() && res.back() == 0)res.pop_back();\n return res;\n}\n\nvector<ll> fft_multiply(const vector<ll> &x, const vector<ll> &y){\n int n = max(x.size(), y.size());\n vector<ll> a = x, b = y;\n a.resize(n, 0);\n b.resize(n, 0);\n vector<ll> conv = convolution<ll>(a, b);\n while(!conv.empty() && conv.back() == 0)conv.pop_back();\n return conv;\n}\n\nvector<ll> karatsuba_multiply(const vector<ll> &x, const vector<ll> &y){\n int n = max(x.size(), y.size());\n int m = 0;\n while((1 << m) < n)m++;\n n = (1 << m);\n vector<ll> a = x, b = y;\n a.resize(n, 0);\n b.resize(n, 0);\n if(n <= 32){\n return simple_multiply(a, b);\n }\n\n int k = n >> 1;\n vector<ll> a1(a.begin(), a.begin() + k);\n vector<ll> a2(a.begin() + k, a.end());\n vector<ll> b1(b.begin(), b.begin() + k);\n vector<ll> b2(b.begin() + k, b.end());\n\n vector<ll> a1b1 = karatsuba_multiply(a1, b1);\n vector<ll> a2b2 = karatsuba_multiply(a2, b2);\n for(int i = 0; i < k; i++)a2[i] += a1[i];\n for(int i = 0; i < k; i++)b2[i] += b1[i];\n vector<ll> z = karatsuba_multiply(a2, b2);\n for(int i = 0; i < a1b1.size(); i++)z[i] -= a1b1[i];\n for(int i = 0; i < a2b2.size(); i++)z[i] -= a2b2[i];\n\n vector<ll> res(2 * n, 0);\n for(int i = 0; i < a1b1.size(); i++)res[i] += a1b1[i];\n for(int i = 0; i < a2b2.size(); i++)res[i + n] += a2b2[i];\n for(int i = 0; i < z.size(); i++)res[i + k] += z[i];\n while(!res.empty() && res.back() == 0)res.pop_back();\n return res;\n}\n\nstruct Bigint{\n const ll base = 100000000;\n const ll mbase = 1000; // 1000 for FFT, 10000 otherwise\n const int b = 8;\n const int mb = 3; // 3 for FFT, 10000 otherwise\n int sign = 1;\n vector<ll> dg;\n Bigint(){}\n Bigint(ll x){\n if(x < 0){\n sign = -1;\n x *= -1;\n }\n while(x){\n dg.push_back(x % base);\n x /= base;\n }\n }\n Bigint(const string &s){\n int e = 0;\n if(s[0] == '-'){\n sign = -1;\n e++;\n }\n for(int i = int(s.size()) - 1; i >= e; i-=b){\n int B = (i - b + 1 >= e ? b: i + 1 - e);\n ll x = stoll(s.substr(max(e, i - b + 1), B));\n dg.push_back(x);\n }\n }\n Bigint& operator=(const string &s){\n *this = Bigint(s);\n return *this;\n }\n Bigint& operator=(const Bigint &x){\n sign = x.sign;\n dg = x.dg;\n return *this;\n }\n Bigint& operator=(ll x){\n return (*this = Bigint(x));\n }\n Bigint operator-() const{\n Bigint res = *this;\n res.sign *= -1;\n return res;\n }\n Bigint operator+(const Bigint &x) const{\n if(sign == x.sign){\n Bigint res;\n res.sign = sign;\n res.dg.resize(max(dg.size(), x.dg.size()));\n ll carry = 0;\n for(int i = 0; i < max(dg.size(), x.dg.size()); i++){\n ll tmp = carry;\n if(i < dg.size())tmp += dg[i];\n if(i < x.dg.size())tmp += x.dg[i];\n res.dg[i] = (tmp % base);\n carry = tmp / base;\n }\n while(carry){\n res.dg.push_back(carry % base);\n carry /= base;\n }\n return res;\n }else{\n return (*this - (- x));\n }\n }\n void trim(){\n while(!dg.empty() && dg.back() == 0)dg.pop_back();\n if(dg.empty())sign = 1;\n }\n Bigint abs() const{\n Bigint res = *this;\n res.sign = 1;\n return res;\n }\n Bigint operator-(const Bigint &x) const{\n if(sign == x.sign){\n if(abs() >= x.abs()){\n Bigint res = *this;\n ll carry = 0;\n for(int i = 0; i < x.dg.size(); i++){\n res.dg[i] -= carry + x.dg[i];\n if(res.dg[i] < 0){\n res.dg[i] += base;\n carry = 1;\n }else{\n carry = 0;\n }\n }\n if(carry > 0){\n for(int i = x.dg.size(); i < res.dg.size() && carry > 0; i++){\n res.dg[i] -= carry;\n if(res.dg[i] < 0){\n res.dg[i] += base;\n carry = 1;\n }else{\n carry = 0;\n }\n }\n }\n res.trim();\n return res;\n }else{\n return - (x - *this);\n }\n }else{\n return (*this + (- x));\n }\n }\n bool operator<(const Bigint &x) const{\n if(sign != x.sign)return sign < x.sign;\n if(dg.size() != x.dg.size())return int(dg.size()) * sign < int(x.dg.size()) * x.sign;\n for(int i = int(dg.size()) - 1; i >= 0; i--){\n if(dg[i] != x.dg[i])return dg[i] * sign < x.dg[i] * x.sign;\n }\n return false;\n }\n bool operator>(const Bigint &x) const{\n return x < *this;\n }\n bool operator<=(const Bigint &x) const{\n return !(*this > x);\n }\n bool operator>=(const Bigint &x) const{\n return !(*this < x);\n }\n bool operator==(const Bigint &x) const{\n return !(*this < x) && !(x < *this);\n }\n bool operator!=(const Bigint &x) const{\n return (*this < x) || (x < *this);\n }\n friend istream& operator>>(istream &is, Bigint &x){\n string s;\n is >> s;\n x = s;\n return is;\n }\n friend ostream& operator<<(ostream& os, const Bigint &x){\n if(x.sign < 0)os << '-';\n if(x.dg.empty())os << 0;\n else{\n os << x.dg.back();\n for(int i = int(x.dg.size()) - 2; i >= 0; i--){\n os << setw(x.b) << setfill('0') << x.dg[i];\n }\n }\n return os;\n }\n Bigint& operator*=(ll x){\n if(x < 0){\n x *= -1;\n sign *= -1;\n }\n ll carry = 0;\n for(int i = 0; i < dg.size(); i++){\n carry = dg[i] * x + carry;\n dg[i] = carry % base;\n carry /= base;\n }\n while(carry){\n dg.push_back(carry % base);\n carry /= base;\n }\n trim();\n return *this;\n }\n Bigint operator*(ll x) const{\n Bigint res = *this;\n res *= x;\n return res;\n }\n Bigint operator*(const Bigint &v) const{\n vector<ll> x = convert_base(dg, b, mb);\n vector<ll> y = convert_base(v.dg, b, mb);\n\n if(x.empty())x.push_back(0);\n if(y.empty())y.push_back(0);\n // simple multiplication\n // vector<ll> mul = simple_multiply(x, y);\n // FFT\n vector<ll> mul = fft_multiply(x, y);\n // karatsuba\n // vector<ll> mul = karatsuba_multiply(x, y);\n\n Bigint res;\n res.sign = sign * v.sign;\n ll carry = 0;\n for(int i = 0; i < mul.size(); i++){\n carry += mul[i];\n res.dg.push_back(carry % mbase);\n carry /= mbase;\n }\n while(carry){\n res.dg.push_back(carry % mbase);\n carry /= mbase;\n }\n res.dg = convert_base(res.dg, mb, b);\n res.trim();\n return res;\n }\n // a = bq + r\n pair<Bigint, Bigint> divmod(const Bigint &a1, const Bigint &b1) const{\n ll norm = base / (b1.dg.back() + 1);\n Bigint q, r;\n q.sign = a1.sign * b1.sign;\n r.sign = a1.sign;\n\n Bigint a = a1.abs() * norm;\n Bigint b = b1.abs() * norm;\n q.dg.resize(a.dg.size());\n\n for(int i = int(a.dg.size()) - 1; i >= 0; i--){\n r = r * base + a.dg[i];\n ll s1 = (r.dg.size() <= b.dg.size() ? 0: r.dg[b.dg.size()]);\n ll s2 = (r.dg.size() <= int(b.dg.size()) - 1 ? 0: r.dg[int(b.dg.size()) - 1]);\n // temporary solution\n ll d = (base * s1 + s2) / b.dg.back();\n r -= b * d;\n // feedback\n while(r < 0)r += b, d--;\n q.dg[i] = d;\n }\n\n q.trim();\n r.trim();\n return make_pair(q, r / norm);\n }\n Bigint operator/(const Bigint &x) const{\n return divmod(*this, x).first;\n }\n Bigint operator%(const Bigint &x) const{\n return divmod(*this, x).second;\n }\n Bigint& operator/=(ll x){\n if(x < 0){\n x *= -1;\n sign *= -1;\n }\n ll rem = 0;\n for(int i = int(dg.size()) - 1; i >= 0; i--){\n rem = dg[i] + rem * base;\n dg[i] = rem / x;\n rem = rem % x;\n }\n trim();\n return *this;\n }\n Bigint operator/(ll x) const{\n Bigint res = *this;\n res /= x;\n return res;\n }\n Bigint operator%(ll x) const{\n if(x < 0)x *= -1;\n ll m = 0;\n for(int i = int(dg.size()) - 1; i >= 0; i--){\n m = (dg[i] + m * base) % x;\n }\n return m * sign;\n }\n Bigint& operator+=(const Bigint &x){\n *this = *this + x;\n return *this;\n }\n Bigint& operator-=(const Bigint &x){\n *this = *this - x;\n return *this;\n }\n Bigint& operator*=(const Bigint &x){\n *this = *this * x;\n return *this;\n }\n Bigint& operator/=(const Bigint &x){\n *this = *this / x;\n return *this;\n }\n bool iszero(){\n trim();\n if(dg.empty())return true;\n return false;\n }\n ll long_value() const {\n ll res = 0;\n for(int i = int(dg.size()) - 1; i >= 0; i--){\n res = res * base + dg[i];\n }\n return res * sign;\n }\n};\n\nBigint fac[20010];\n\nint main(int argc, char const* argv[])\n{\n int n, m, r; cin >> n >> m >> r;\n if(n * m > r){\n cout << 0 << endl;\n return 0;\n }\n r -= n * m;\n fac[0] = Bigint(1);\n FOR(i, 1, 2001){\n fac[i] = Bigint(i) * fac[i-1];\n }\n Bigint res = fac[n + r - 1] / fac[r] / fac[n-1];\n cout << res << endl;\n return 0;\n}", "accuracy": 0.8, "time_ms": 840, "memory_kb": 9948, "score_of_the_acc": -0.5213, "final_rank": 15 }, { "submission_id": "aoj_0591_3159421", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int BASE = 10000;\n\nint n, m, r;\n\nstruct dat{\n\tvector <int> d;\n\t\n\tdat operator * (const int T) const{\n\t\tdat tmp;\n\t\ttmp.d = d;\n\t\tfor(int i = 0; i < d.size(); i++)\n\t\ttmp.d[i] *= T;\n\t\tfor(int i = 0; i < tmp.d.size(); i++){\n\t\t\tif(tmp.d[i] >= BASE){\n\t\t\t\tif(i == tmp.d.size() - 1)\n\t\t\t\ttmp.d.push_back(tmp.d[i] / BASE);\n\t\t\t\telse\n\t\t\t\ttmp.d[i + 1] += tmp.d[i] / BASE;\n\t\t\t\ttmp.d[i] %= BASE;\n\t\t\t}\n\t\t}\n\t\treturn tmp;\n\t}\n\t\n\tdat operator / (const int T) const{\n\t\tdat tmp;\n\t\ttmp.d = d;\n\t\tint cur = 0;\n\t\tfor(int i = tmp.d.size() - 1; i >= 0; i--){\n\t\t\tcur = cur * BASE + tmp.d[i];\n\t\t\ttmp.d[i] = cur / T;\n\t\t\tcur %= T;\n\t\t}\n\t\t\n\t\tfor(int i = 0; i < tmp.d.size(); i++){\n\t\t\tif(tmp.d[i] >= BASE){\n\t\t\t\tif(i == tmp.d.size() - 1)\n\t\t\t\ttmp.d.push_back(tmp.d[i] / BASE);\n\t\t\t\telse\n\t\t\t\ttmp.d[i + 1] += tmp.d[i] / BASE;\n\t\t\t\ttmp.d[i] %= BASE;\n\t\t\t}\n\t\t}\n\t\t\n\t\twhile(tmp.d.size() && tmp.d.back() == 0)\n\t\ttmp.d.pop_back();\n\t\t\n\t\treturn tmp;\n\t}\n\t\n\tvoid print(){\n\t\tif(d.empty())\n\t\tprintf(\"0\");\n\t\telse{\n\t\t\tprintf(\"%d\", d.back());\n\t\t\tfor(int i = d.size() - 2; i >= 0; i--){\n\t\t\t\tprintf(\"%.4d\", d[i]);\n\t\t\t}\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n}res;\n\nint main(){\n\tscanf(\"%d%d%d\", &n, &m, &r);\n\t\n\tr -= n * m;\n\t\n\tif(r < 0) return 0 * printf(\"0\\n\");\n\t\n\t//(n + r - 1)C(r)\n\t\n\tres.d.push_back(1);\n\t\n\tfor(int i = 1; i <= n + r - 1; i++)\n\tres = res * i;\n\t\n\tfor(int i = 1; i <= r; i++)\n\tres = res / i;\n\t\n\tfor(int i = 1; i <= n - 1; i++)\n\tres = res / i;\n\t\n\tres.print();\n\t\n}", "accuracy": 1, "time_ms": 2390, "memory_kb": 3336, "score_of_the_acc": -0.4144, "final_rank": 6 }, { "submission_id": "aoj_0591_3159400", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int BASE = 10000;\n\nint n, m, r;\n\nstruct dat{\n\tvector <int> d;\n\t\n\tdat operator * (const int T) const{\n\t\tdat tmp;\n\t\ttmp.d = d;\n\t\tfor(int i = 0; i < d.size(); i++)\n\t\ttmp.d[i] *= T;\n\t\tfor(int i = 0; i < tmp.d.size(); i++){\n\t\t\tif(tmp.d[i] >= BASE){\n\t\t\t\tif(i == d.size() - 1)\n\t\t\t\ttmp.d.push_back(tmp.d[i] / BASE);\n\t\t\t\telse\n\t\t\t\ttmp.d[i + 1] += tmp.d[i] / BASE;\n\t\t\t\ttmp.d[i] %= BASE;\n\t\t\t}\n\t\t}\n\t\treturn tmp;\n\t}\n\t\n\tdat operator / (const int T) const{\n\t\tdat tmp;\n\t\ttmp.d = d;\n\t\t\n\t\tint cur = 0;\n\t\tfor(int i = tmp.d.size() - 1; i >= 0; i--){\n\t\t\tcur = cur * BASE + tmp.d[i];\n\t\t\ttmp.d[i] = cur / T;\n\t\t\tcur %= T;\n\t\t}\n\t\t\n\t\twhile(tmp.d.size() && tmp.d.back() == 0)\n\t\ttmp.d.pop_back();\n\t\t\n\t\treturn tmp;\n\t}\n\t\n\tvoid print(){\n\t\tif(d.empty())\n\t\tprintf(\"0\");\n\t\telse{\n\t\t\tprintf(\"%d\", d.back());\n\t\t\tfor(int i = d.size() - 2; i >= 0; i--){\n\t\t\t\tprintf(\"%.4d\", d[i]);\n\t\t\t}\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n}res;\n\nint main(){\n\tscanf(\"%d%d%d\", &n, &m, &r);\n\t\n\tr -= n * m;\n\t\n\tif(r < 0) return 0 * printf(\"0\\n\");\n\t\n\t//(n + r - 1)C(r)\n\t\n\tres.d.reserve(10000);\n\t\n\tres.d.push_back(1);\n\t\n\tfor(int i = 1; i <= n + r - 1; i++)\n\tres = res * i;\n\t\n\tfor(int i = 1; i <= r; i++)\n\tres = res / i;\n\t\n\tfor(int i = 1; i <= n - 1; i++)\n\tres = res / i;\n\t\n\tres.print();\n\t\n}", "accuracy": 0.8, "time_ms": 2150, "memory_kb": 3380, "score_of_the_acc": -0.3849, "final_rank": 14 }, { "submission_id": "aoj_0591_3097836", "code_snippet": "#include <stdio.h>\n#include <vector>\n#include <algorithm>\n#include <bitset>\nusing namespace std;\n#define PB push_back\nconst int N=2e4+10;\nconst long long int TOP=1e13;\nstruct bignum{\n int size;\n vector<long long int>val;\n void init(int n){\n val.clear();\n val.PB(n);\n pull();\n return ;\n }\n void pull(){\n int k=0;\n for(int i=0;i<val.size();i++){\n val[i]+=k;\n k=0;\n if(val[i]>=TOP){\n k=val[i]/TOP;\n val[i]%=TOP;\n }\n }\n if(k>0)val.PB(k);\n size=(int)val.size();\n }\n void out(){\n long long int now;\n reverse(val.begin(),val.end());\n printf(\"%lld\",val[0]);\n for(int i=1;i<size;i++){\n now=TOP/10;\n while(val[i]<now){\n now/=10;\n printf(\"0\");\n }\n printf(\"%lld\",val[i]);\n }\n printf(\"\\n\");\n reverse(val.begin(),val.end());\n return ;\n }\n void operator *=(long long int n){\n for(int i=0;i<size;i++)val[i]*=n;\n pull();\n return ;\n }\n};\nvoid C(int a,int b){\n bignum ans;\n bitset<N> bs;\n vector<int> prime,mul;\n int temp;\n bs.reset();\n prime.PB(2);\n for(int i=3;i<N;i+=2)if(!bs[i]){\n prime.PB(i);\n for(int j=i*i;j<N;j+=(i<<1))bs[j]=true;\n }\n mul.resize(prime.size());\n for(int i=2;i<=a;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]++;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=a-b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n ans.init(1);\n for(int i=0;i<prime.size();i++){\n while(mul[i]>0){\n mul[i]--;\n ans*=prime[i];\n }\n }\n return ans.out();\n}\nvoid H(int a,int b){\n return C(a+b-1,b);\n}\nint main(){\n int n,m,r;\n scanf(\"%d%d%d\",&n,&m,&r);\n if(n*m>r)printf(\"%d\\n\",0);\n else H(n,r-n*m);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 2840, "score_of_the_acc": -0.0797, "final_rank": 1 }, { "submission_id": "aoj_0591_3097834", "code_snippet": "#include <stdio.h>\n#include <vector>\n#include <algorithm>\n#include <bitset>\nusing namespace std;\n#define PB push_back\nconst int N=1e4+10;\nconst long long int TOP=1e13;\nstruct bignum{\n int size;\n vector<long long int>val;\n void init(int n){\n val.clear();\n val.PB(n);\n pull();\n return ;\n }\n void pull(){\n int k=0;\n for(int i=0;i<val.size();i++){\n val[i]+=k;\n k=0;\n if(val[i]>=TOP){\n k=val[i]/TOP;\n val[i]%=TOP;\n }\n }\n if(k>0)val.PB(k);\n size=(int)val.size();\n }\n void out(){\n long long int now;\n reverse(val.begin(),val.end());\n printf(\"%lld\",val[0]);\n for(int i=1;i<size;i++){\n now=TOP/10;\n while(val[i]<now){\n now/=10;\n printf(\"0\");\n }\n printf(\"%lld\",val[i]);\n }\n printf(\"\\n\");\n reverse(val.begin(),val.end());\n return ;\n }\n void operator *=(long long int n){\n for(int i=0;i<size;i++)val[i]*=n;\n pull();\n return ;\n }\n};\nvoid C(int a,int b){\n bignum ans;\n bitset<N> bs;\n vector<int> prime,mul;\n int temp;\n bs.reset();\n prime.PB(2);\n for(int i=3;i<N;i+=2)if(!bs[i]){\n prime.PB(i);\n for(int j=i*i;j<N;j+=(i<<1))bs[j]=true;\n }\n mul.resize(prime.size());\n for(int i=2;i<=a;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]++;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=a-b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n ans.init(1);\n for(int i=0;i<prime.size();i++){\n while(mul[i]>0){\n mul[i]--;\n ans*=prime[i];\n }\n }\n return ans.out();\n}\nvoid H(int a,int b){\n return C(a+b-1,b);\n}\nint main(){\n int n,m,r;\n scanf(\"%d%d%d\",&n,&m,&r);\n if(n*m>r)printf(\"%d\\n\",0);\n else H(n,r-n*m);\n}", "accuracy": 0.8, "time_ms": 20, "memory_kb": 2788, "score_of_the_acc": -0.0772, "final_rank": 13 }, { "submission_id": "aoj_0591_3097833", "code_snippet": "#include <stdio.h>\n#include <vector>\n#include <algorithm>\n#include <bitset>\nusing namespace std;\n#define PB push_back\nconst int N=1e4+10;\nconst long long int TOP=1e14;\nstruct bignum{\n int size;\n vector<long long int>val;\n void init(int n){\n val.clear();\n val.PB(n);\n pull();\n return ;\n }\n void pull(){\n int k=0;\n for(int i=0;i<val.size();i++){\n val[i]+=k;\n k=0;\n if(val[i]>=TOP){\n k=val[i]/TOP;\n val[i]%=TOP;\n }\n }\n if(k>0)val.PB(k);\n size=(int)val.size();\n }\n void out(){\n long long int now;\n reverse(val.begin(),val.end());\n printf(\"%lld\",val[0]);\n for(int i=1;i<size;i++){\n now=TOP/10;\n while(val[i]<now){\n now/=10;\n printf(\"0\");\n }\n printf(\"%lld\",val[i]);\n }\n printf(\"\\n\");\n reverse(val.begin(),val.end());\n return ;\n }\n void operator *=(long long int n){\n for(int i=0;i<size;i++)val[i]*=n;\n pull();\n return ;\n }\n};\nvoid C(int a,int b){\n bignum ans;\n bitset<N> bs;\n vector<int> prime,mul;\n int temp;\n bs.reset();\n prime.PB(2);\n for(int i=3;i<N;i+=2)if(!bs[i]){\n prime.PB(i);\n for(int j=i*i;j<N;j+=(i<<1))bs[j]=true;\n }\n mul.resize(prime.size());\n for(int i=2;i<=a;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]++;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n for(int i=2;i<=a-b;i++){\n temp=i;\n for(int j=0;j<prime.size();j++){\n while(temp%prime[j]==0){\n mul[j]--;\n temp/=prime[j];\n }\n if(temp<=1)break;\n }\n }\n ans.init(1);\n for(int i=0;i<prime.size();i++){\n while(mul[i]>0){\n mul[i]--;\n ans*=prime[i];\n }\n }\n return ans.out();\n}\nvoid H(int a,int b){\n return C(a+b-1,b);\n}\nint main(){\n int n,m,r;\n scanf(\"%d%d%d\",&n,&m,&r);\n if(n*m>r)printf(\"%d\\n\",0);\n else H(n,r-n*m);\n}", "accuracy": 0.8, "time_ms": 10, "memory_kb": 2756, "score_of_the_acc": -0.0744, "final_rank": 12 }, { "submission_id": "aoj_0591_3095870", "code_snippet": "#include <stdio.h>\nconst int N=2e3+10;\nlong long int ans[N][N];\nlong long int C(int a,int b){\n if(a==0)return 1;\n else if(b==0||b==a)return 1;\n if(ans[a][b]>0)return ans[a][b];\n else return ans[a][b]=C(a-1,b-1)+C(a-1,b);\n}\nlong long int H(int a,int b){\n for(int i=0;i<=a;i++)for(int j=0;j<=b;j++)ans[i][j]=0;\n return C(a+b-1,b);\n}\nint main(){\n int n,m,r;\n scanf(\"%d%d%d\",&n,&m,&r);\n if(n*m>r)printf(\"0\\n\");\n else printf(\"%lld\\n\",H(n,r-n*m));\n}", "accuracy": 0.6, "time_ms": 290, "memory_kb": 22460, "score_of_the_acc": -1.0368, "final_rank": 19 }, { "submission_id": "aoj_0591_2621674", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nint n,m,r;\n\ntypedef long long ll;\nclass LINT{\n static const ll BASE =100000000LL;\n vector<ll> vl;\n bool sign;\n public:\n LINT(){sign=true;}\n LINT(ll x){\n if(x<0){\n sign=false;x*=-1;\n }\n else sign=true;\n while(x){\n vl.push_back(x%BASE);\n x/=BASE;\n }\n }\n LINT(string &x){\n sign = x[0]=='-'?false:true;\n ll dc=BASE;\n for(int i=x.size()-1;i>=0;--i){\n if(dc==BASE){\n vl.push_back(0);dc=1;\n }\n if(x[i]=='-') continue;\n else{\n vl.back() +=(x[i]-'0')*dc;\n dc*=10;\n }\n }\n }\n string getlint(){\n stringstream ss;\n if(!sign) ss<<'-';\n for(int i=vl.size()-1;i>=0;--i){\n ss<<vl[i];ss<<setw(8)<<setfill('0');\n }\n return ss.str();\n }\n LINT operator+(LINT &x){\n if(sign&&!x.sign){\n LINT t=x;\n t.sign=!t.sign;\n return *this-t;\n }\n else if(!sign&&x.sign){\n LINT t=*this;\n t.sign=!t.sign;\n return x-t;\n }\n LINT ret;\n ret.sign=sign;\n ll carry=0;int i=0;\n while(i<vl.size()||i<x.vl.size()||carry>0){\n if(i<vl.size()) carry +=vl[i];\n if(i<x.vl.size()) carry +=x.vl[i];\n ret.vl.push_back(carry%BASE);\n carry/=BASE;\n ++i;\n }\n return ret;\n }\n LINT operator-(LINT &x){\n if(!x.sign){\n LINT t=x;\n t.sign=!t.sign;\n return *this+t;\n }\n LINT ret;\n ll carry=0;int i=0;\n while(i<vl.size()||i<x.vl.size()){\n if(i<vl.size()) carry +=vl[i];\n if(i<x.vl.size()) carry -=x.vl[i];\n if(carry<0){\n ret.vl.push_back(carry+BASE);carry=-1;\n }\n else{\n ret.vl.push_back(carry);carry=0;\n }\n ++i;\n }\n if(carry==-1){\n ret.sign=!ret.sign;\n for(int j=0;j<ret.vl.size();++j) ret.vl[j]=BASE-ret.vl[j]-(j!=0);\n }\n while(ret.vl.size()>1&&ret.vl.back()==0) ret.vl.pop_back();\n return ret;\n }\n LINT operator*(LINT &x){\n LINT ret;\n if(vl.size()==0||x.vl.size()==0) return ret;\n ret.sign=!(sign^x.sign);\n ret.vl.assign(vl.size()+x.vl.size(),0);\n for(int i=0;i<vl.size();++i){\n for(int j=0;j<x.vl.size();++j){\n ret.vl[i+j] += vl[i]*x.vl[j];\n ret.vl[i+j+1] += ret.vl[i+j]/BASE;\n ret.vl[i+j] %=BASE;\n }\n }\n while(ret.vl.size()>0&&ret.vl.back()==0) ret.vl.pop_back();\n return ret;\n }\n LINT operator/(LINT &x){\n LINT ret,zero;\n if(vl.size()<x.vl.size()) return ret;\n LINT F(BASE/(x.vl[x.vl.size()-1]+1));\n LINT t=*this*F,tx=x*F;\n ret.vl.assign(t.vl.size()-tx.vl.size()+1,0);\n for(int i=ret.vl.size()-1,j=t.vl.size()-1;i>=0;--i,--j){\n ret.vl[i] =(j+1<t.vl.size()?t.vl[j+1]:0)*BASE+t.vl[j];\n ret.vl[i] /=tx.vl[tx.vl.size()-1];\n LINT tt;\n tt.vl.assign(i+tx.vl.size(),0);\n for(int k=0;k<tx.vl.size();++k) tt.vl[i+k]=ret.vl[i]*tx.vl[k];\n tt=tt+zero;\n while(t<tt){\n --ret.vl[i];\n for(int k=0;k<tx.vl.size();++k) tt.vl[i+k] -= tx.vl[k];\n tt=tt-zero;\n }\n t=t-tt;\n }\n ret=ret-zero;\n ret.sign=!(sign^x.sign);\n while(ret.vl.size()>0&&ret.vl.back()==0) ret.vl.pop_back();\n return ret;\n //return tt/F;\n }\n bool operator<(LINT &x){\n if(sign^x.sign) return x.sign;\n if(vl.size()!=x.vl.size()) return !(sign^(vl.size()<x.vl.size()));\n for(int i=vl.size()-1;i>=0;--i){\n if(vl[i]!=x.vl[i]) return !(sign^(vl[i]<x.vl[i]));\n }\n return false;\n }\n};\n\nstring combination(int n,int k){\n if(n-k<k) k=n-k;\n vector<int> v(k);\n for(int i=0;i<k;++i) v[i]=n-i;\n for(int i=1;i<=k;++i){\n int t=i;\n for(int j=0;j<k;++j){\n int s=__gcd(t,v[j]);\n v[j] /=s;\n t /=s;\n }\n }\n LINT ret(1);\n for(int i=0;i<k;++i){\n LINT t=LINT(v[i]);\n ret = ret * t; \n }\n return ret.getlint();\n}\n\nint main(){\n string ans;\n cin>>n>>m>>r;\n if(r<m*n) ans='0';\n else{\n r -=m*n;\n ans=combination(r+n-1,r);\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1760, "memory_kb": 3228, "score_of_the_acc": -0.3265, "final_rank": 4 }, { "submission_id": "aoj_0591_2512161", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i,n) REP(i,0,n)\n#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)\n#define repr(i, n) REPR(i, n, 0)\n#define REPR(i, s, e) for(int i=(int)(s-1); i>=(int)(e); i--)\n#define pb push_back\n#define all(r) r.begin(),r.end()\n#define rall(r) r.rbegin(),r.rend()\n#define fi first\n#define se second\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n\nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\ndouble EPS = 1e-8;\n\nstruct BigInteger {\n\tstatic const ll LogBase = 8;\n\tstatic const ll BASE = pow(10, LogBase);\n\tvector<ll> dig;\n\tbool isNeg;\n\tBigInteger() {}\n\tBigInteger(ll a, int sz, bool negative = false) : dig(sz, a), isNeg(negative) {}\n\tBigInteger(string s) {\n\t\tif (s[0] == '-') {\n\t\t\tisNeg = true;\n\t\t\ts = s.substr(1);\n\t\t} else isNeg = false;\n\t\treverse(all(s));\n\t\tfor (int i = 0; i < s.size(); i += LogBase) {\n\t\t\tdig.pb(0);\n\t\t\tll p = 1;\n\t\t\tfor (int j = 0; j < LogBase; j++) {\n\t\t\t\tif (i + j >= s.size()) break;\n\t\t\t\tdig.back() = dig.back() + (s[i + j] - '0') * p;\n\t\t\t\tp *= 10LL;\n\t\t\t}\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tBigInteger(ll a) {\n\t\tisNeg = a < 0;\n\t\tdig.pb(abs(a));\n\t\tif(dig.back() >= BASE) {\n\t\t\tll tmp = dig.back() / BASE;\n\t\t\tdig.back() %= BASE;\n\t\t\tdig.pb(tmp);\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tint size() const {return dig.size();}\n\tBigInteger getAbs()const {\n\t\tif (!isNeg) return *this;\n\t\tBigInteger ret = *this;\n\t\tret.isNeg = false;\n\t\treturn ret.normal();\n\t}\n\tBigInteger normal() const {\n\t\t// BigInteger ret = this->getAbs();\n\t\t// for (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t// \tif (ret.dig[i] >= BASE) ret.dig[i + 1] += ret.dig[i] / BASE, ret.dig[i] %= BASE;\n\t\t// }\n\t\t// if (ret.dig.back() >= BASE) {\n\t\t// \tll tmp = ret.dig.back() / BASE;\n\t\t// \tret.dig.back() %= BASE;\n\t\t// \tret.dig.push_back(tmp);\n\t\t// }\n\t\t// while (ret.size() > 1 && ret.dig.back() == 0) ret.dig.pop_back();\n\t\t// return ret;\n\t\tBigInteger ret = *this;\n\t\tret.normalize();\n\t\treturn ret;\n\t}\n\tvoid normalize() {\n\t\tfor(int i = 0; i +1 < size(); ++i) {\n\t\t\tif (dig[i] >= BASE) {\n\t\t\t\tdig[i+1] += dig[i] / BASE;\n\t\t\t\tdig[i] %= BASE;\n\t\t\t}\n\t\t}\n\t\tif(dig.back() >= BASE) {\n\t\t\tll tmp = dig.back() / BASE;\n\t\t\tdig.back() %= BASE;\n\t\t\tdig.push_back(tmp);\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tpair<BigInteger, ll> divMod(ll a) const {\n\t\tBigInteger x = *this;\n\t\tll c = 0, t;\n\t\tfor (int i = x.size() - 1; i >= 0; --i) {\n\t\t\tt = BASE * c + x.dig[i];\n\t\t\tx.dig[i] = t / a;\n\t\t\tc = t % a;\n\t\t}\n\t\treturn pair<BigInteger, ll>(x.normal(), c);\n\t}\n\tpair<BigInteger, BigInteger> divMod(const BigInteger& bi) const {\n\t\tBigInteger x = this->getAbs(), y = bi.getAbs();\n\t\tif (x < y) return pair<BigInteger, BigInteger>(make_pair(BigInteger(\"0\"), *this));\n\t\tif (x == y) return pair<BigInteger, BigInteger> (BigInteger(\"1\"), BigInteger(\"0\"));\n\t\tll F = BASE / (y.dig.back() + 1);\n\t\tx = x * F;\n\t\ty = y * F;\n\n\t\tBigInteger z(0LL, x.size() - y.size() + 1, isNeg ^ bi.isNeg);\n\t\tfor (int k = z.size() - 1, i = x.size() - 1; k >= 0; --k, --i) {\n\t\t\tz.dig[k] = (i + 1 < x.size() ? x.dig[i + 1] : 0) * BASE + x.dig[i];\n\t\t\tz.dig[k] /= y.dig.back();\n\t\t\tBigInteger t(0, k + y.size());\n\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\tt.dig[k + m] = z.dig[k] * y.dig[m];\n\t\t\t}\n\n\t\t\tt.normalize();\n\t\t\twhile (x < t) {\n\t\t\t\tz.dig[k] -= 1;\n\t\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\t\tt.dig[k + m] -= y.dig[m];\n\t\t\t\t}\n\t\t\t\tt.normalize();\n\t\t\t}\n\t\t\tx = x - t;\n\t\t}\n\t\treturn pair<BigInteger, BigInteger>(z.normal(), x / F);\n\t}\n\tBigInteger operator + (const BigInteger& bi) const {\n\t\tbool retNeg = false;\n\t\tif (isNeg) {\n\t\t\tif (bi.isNeg) retNeg = true;\n\t\t\telse return bi - (this->getAbs());\n\t\t}\n\t\tif (bi.isNeg) return (*this) - bi.getAbs();\n\t\tBigInteger ret (0LL, max(this->size(), bi.size()) + 1, retNeg);\n\t\tfor (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t\tif (i < this->size()) ret.dig[i] += this->dig[i];\n\t\t\tif (i < bi.size()) ret.dig[i] += bi.dig[i];\n\t\t\tif (ret.dig[i] >= BASE) ret.dig[i] -= BASE, ++ret.dig[i + 1];\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator - (const BigInteger& bi) const {\n\t\tif (bi.isNeg) return (*this) + bi.getAbs();\n\t\tif (isNeg) return bi - (this -> getAbs());\n\t\tif ((*this) < bi) {\n\t\t\tBigInteger ret = bi - (*this);\n\t\t\tret.isNeg = true;\n\t\t\treturn ret;\n\t\t}\n\t\tBigInteger ret = *this;\n\t\tfor (int i = 0; i < bi.size(); ++i) {\n\t\t\tret.dig[i] -= bi.dig[i];\n\t\t\tif (ret.dig[i] < 0) ret.dig[i] += BASE, --ret.dig[i+1];\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator * (const ll a) const {\n\t\tBigInteger ret = *this;\n\t\tfor (auto& d : ret.dig) d *= a;\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator * (const BigInteger& bi) const {\n\t\tBigInteger ret(0LL, this->size() + bi.size(), isNeg ^ bi.isNeg);\n\t\tfor (int i = this->size()-1; i >= 0; --i) {\n\t\t\tfor (int j = 0; j < bi.size(); ++j) {\n\t\t\t\tret.dig[i + j] += this->dig[i] * bi.dig[j];\n\t\t\t}\n\t\t\tret.normalize();\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator / (ll a) const {return this->divMod(a).first;}\n\tll operator % (ll a) const {return this->divMod(a).second;}\n\tBigInteger operator / (const BigInteger& bi) const {return this->divMod(bi).first;}\n\tBigInteger operator % (const BigInteger& bi) const {return this->divMod(bi).second;}\n\tbool operator < (const BigInteger& bi) const {\n\t\tif (this->size() != bi.size()) return this->size() < bi.size();\n\t\tfor (int i = this->size() - 1; i >= 0; --i) {\n\t\t\tif (dig[i] != bi.dig[i]) return dig[i] < bi.dig[i];\n\t\t}\n\t\treturn false;\n\t}\n\tbool operator > (const BigInteger& bi) const {return bi < (*this);}\n\tbool operator <= (const BigInteger& bi) const {!(*this > bi);}\n\tbool operator >= (const BigInteger& bi) const {!(*this < bi);}\n\tbool operator != (const BigInteger& bi) const {(*this < bi) || (*this > bi);}\n\tbool operator == (const BigInteger& bi) const {!(*this != bi);}\n\tvoid print() const{\n\t\tif(isNeg) printf(\"-\");\n\t\tprintf(\"%lld\", dig.back());\n\t\tfor(int i = size()-2; i>=0; --i) printf(\"%0*lld\", LogBase, dig[i]);\n\t}\n\tvoid println() const {\n\t\tprint();\n\t\tputs(\"\");\n\t}\n};\nostream &operator << (ostream &os, const BigInteger& x) {\n\tif (x.isNeg) os << '-';\n\tos << x.dig[x.size() - 1];\n\tfor (int i = x.size() - 2; i >= 0; --i) {\n\t\tos << setw(BigInteger::LogBase) << setfill('0') << x.dig[i];\n\t}\n\treturn os;\n}\nistream &operator >> (istream &is, BigInteger &x) {\n\tstring s; is >> s; x = BigInteger(s); return is;\n}\n\n\nint main() {\n\tll n, m, r;\n\tcin >> n >> m >> r;\n\tBigInteger b = BigInteger(\"1\");\n\tint R = r - n * m;\n\tif(R < 0) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tfor(int i = 0; i < n-1; ++i) {\n\t\tif((R+n-1-i) % (i+1) == 0) {\n\t\t\tb = b * BigInteger((R+n-1-i) / (i+1));\n\t\t}\n\t\telse {\n\t\t\tb = b * BigInteger(R+n-1-i) / BigInteger(i+1);\n\t\t}\n\t}\n\tcout << b << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 7030, "memory_kb": 3236, "score_of_the_acc": -1.0194, "final_rank": 9 }, { "submission_id": "aoj_0591_2512137", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i,n) REP(i,0,n)\n#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)\n#define repr(i, n) REPR(i, n, 0)\n#define REPR(i, s, e) for(int i=(int)(s-1); i>=(int)(e); i--)\n#define pb push_back\n#define all(r) r.begin(),r.end()\n#define rall(r) r.rbegin(),r.rend()\n#define fi first\n#define se second\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n\nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\ndouble EPS = 1e-8;\n\nstruct BigInteger {\n\tstatic const ll LogBase = 8;\n\tstatic const ll BASE = pow(10, LogBase);\n\tvector<ll> dig;\n\tbool isNeg;\n\tBigInteger() {}\n\tBigInteger(ll a, int sz, bool negative = false) : dig(sz, a), isNeg(negative) {}\n\tBigInteger(string s) {\n\t\tif (s[0] == '-') {\n\t\t\tisNeg = true;\n\t\t\ts = s.substr(1);\n\t\t} else isNeg = false;\n\t\treverse(all(s));\n\t\tfor (int i = 0; i < s.size(); i += LogBase) {\n\t\t\tdig.pb(0);\n\t\t\tll p = 1;\n\t\t\tfor (int j = 0; j < LogBase; j++) {\n\t\t\t\tif (i + j >= s.size()) break;\n\t\t\t\tdig.back() = dig.back() + (s[i + j] - '0') * p;\n\t\t\t\tp *= 10LL;\n\t\t\t}\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tBigInteger(ll a) {\n\t\tisNeg = a < 0;\n\t\tdig.pb(abs(a));\n\t\tif(dig.back() >= BASE) {\n\t\t\tll tmp = dig.back() / BASE;\n\t\t\tdig.back() %= BASE;\n\t\t\tdig.pb(tmp);\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tint size() const {return dig.size();}\n\tBigInteger getAbs()const {\n\t\tif (!isNeg) return *this;\n\t\tBigInteger ret = *this;\n\t\tret.isNeg = false;\n\t\treturn ret.normal();\n\t}\n\tBigInteger normal() const {\n\t\tBigInteger ret = this->getAbs();\n\t\tfor (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t\twhile (ret.dig[i] >= BASE) ret.dig[i + 1] += ret.dig[i] / BASE, ret.dig[i] %= BASE;\n\t\t}\n\t\tif (ret.dig.back() >= BASE) {\n\t\t\tll tmp = ret.dig.back() / BASE;\n\t\t\tret.dig.back() %= BASE;\n\t\t\tret.dig.push_back(tmp);\n\t\t}\n\t\twhile (ret.size() > 1 && ret.dig.back() == 0) ret.dig.pop_back();\n\t\treturn ret;\n\t}\n\tpair<BigInteger, ll> divMod(ll a) const {\n\t\tBigInteger x = *this;\n\t\tll c = 0, t;\n\t\tfor (int i = x.size() - 1; i >= 0; --i) {\n\t\t\tt = BASE * c + x.dig[i];\n\t\t\tx.dig[i] = t / a;\n\t\t\tc = t % a;\n\t\t}\n\t\treturn pair<BigInteger, ll>(x.normal(), c);\n\t}\n\tpair<BigInteger, BigInteger> divMod(const BigInteger& bi) const {\n\t\tBigInteger x = this->getAbs(), y = bi.getAbs();\n\t\tif (x < y) return pair<BigInteger, BigInteger>(make_pair(BigInteger(\"0\"), *this));\n\t\tif (x == y) return pair<BigInteger, BigInteger> (BigInteger(\"1\"), BigInteger(\"0\"));\n\t\tll F = BASE / (y.dig.back() + 1);\n\t\tx = x * F;\n\t\ty = y * F;\n\n\t\tBigInteger z(0LL, x.size() - y.size() + 1, isNeg ^ bi.isNeg);\n\t\tfor (int k = z.size() - 1, i = x.size() - 1; k >= 0; --k, --i) {\n\t\t\tz.dig[k] = (i + 1 < x.size() ? x.dig[i + 1] : 0) * BASE + x.dig[i];\n\t\t\tz.dig[k] /= y.dig.back();\n\t\t\tBigInteger t(0, k + y.size());\n\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\tt.dig[k + m] = z.dig[k] * y.dig[m];\n\t\t\t}\n\n\t\t\tt = t.normal();\n\t\t\twhile (x < t) {\n\t\t\t\tz.dig[k] -= 1;\n\t\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\t\tt.dig[k + m] -= y.dig[m];\n\t\t\t\t}\n\t\t\t\tt = t.normal();\n\t\t\t}\n\t\t\tx = x - t;\n\t\t}\n\t\treturn pair<BigInteger, BigInteger>(z.normal(), x / F);\n\t}\n\tBigInteger operator + (const BigInteger& bi) const {\n\t\tbool retNeg = false;\n\t\tif (isNeg) {\n\t\t\tif (bi.isNeg) retNeg = true;\n\t\t\telse bi - (this->getAbs());\n\t\t}\n\t\tif (bi.isNeg) return (*this) - bi.getAbs();\n\t\tBigInteger ret (0LL, max(this->size(), bi.size()) + 1, retNeg);\n\t\tfor (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t\tif (i < this->size()) ret.dig[i] += this->dig[i];\n\t\t\tif (i < bi.size()) ret.dig[i] += bi.dig[i];\n\t\t\tif (ret.dig[i] >= BASE) ret.dig[i] -= BASE, ++ret.dig[i + 1];\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator - (const BigInteger& bi) const {\n\t\tif (bi.isNeg) return (*this) + bi.getAbs();\n\t\tif (isNeg) return bi - (this -> getAbs());\n\t\tif ((*this) < bi) {\n\t\t\tBigInteger ret = bi - (*this);\n\t\t\tret.isNeg = true;\n\t\t\treturn ret;\n\t\t}\n\t\tBigInteger ret = *this;\n\t\tfor (int i = 0; i < bi.size(); ++i) {\n\t\t\tret.dig[i] -= bi.dig[i];\n\t\t\tif (ret.dig[i] < 0) ret.dig[i] += BASE, --ret.dig[i+1];\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator * (const ll a) const {\n\t\tBigInteger ret = *this;\n\t\tfor (auto& d : ret.dig) d *= a;\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator * (const BigInteger& bi) const {\n\t\tBigInteger ret(0LL, this->size() + bi.size(), isNeg ^ bi.isNeg);\n\t\tfor (int i = 0; i < this->size(); ++i) {\n\t\t\tfor (int j = 0; j < bi.size(); ++j) {\n\t\t\t\tret.dig[i + j] += this->dig[i] * bi.dig[j];\n\t\t\t}\n\t\t\tfor(int j = 0; j + 1< ret.size(); ++j) {\n\t\t\t\tif(ret.dig[j] >= BASE) {\n\t\t\t\t\tret.dig[j+1] += ret.dig[j] / BASE;\n\t\t\t\t\tret.dig[j] %= BASE;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(ret.dig.back() >= BASE) {\n\t\t\t\tll tmp = ret.dig.back() / BASE;\n\t\t\t\tret.dig.back() %= BASE;\n\t\t\t\tret.dig.push_back(tmp);\n\t\t\t}\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator / (ll a) const {return this->divMod(a).first;}\n\tll operator % (ll a) const {return this->divMod(a).second;}\n\tBigInteger operator / (const BigInteger& bi) const {return this->divMod(bi).first;}\n\tBigInteger operator % (const BigInteger& bi) const {return this->divMod(bi).second;}\n\tbool operator < (const BigInteger& bi) const {\n\t\tif (this->size() != bi.size()) return this->size() < bi.size();\n\t\tfor (int i = this->size() - 1; i >= 0; --i) {\n\t\t\tif (dig[i] != bi.dig[i]) return dig[i] < bi.dig[i];\n\t\t}\n\t\treturn false;\n\t}\n\tbool operator > (const BigInteger& bi) const {return bi < (*this);}\n\tbool operator <= (const BigInteger& bi) const {!(*this > bi);}\n\tbool operator >= (const BigInteger& bi) const {!(*this < bi);}\n\tbool operator != (const BigInteger& bi) const {(*this < bi) || (*this > bi);}\n\tbool operator == (const BigInteger& bi) const {!(*this != bi);}\n\tvoid print() const{\n\t\tif(isNeg) printf(\"-\");\n\t\tprintf(\"%lld\", dig.back());\n\t\tfor(int i = size()-2; i>=0; --i) printf(\"%0*lld\", LogBase, dig[i]);\n\t}\n\tvoid println() const {\n\t\tprint();\n\t\tputs(\"\");\n\t}\n};\nostream &operator << (ostream &os, const BigInteger& x) {\n\tif (x.isNeg) os << '-';\n\tos << x.dig[x.size() - 1];\n\tfor (int i = x.size() - 2; i >= 0; --i) {\n\t\tos << setw(BigInteger::LogBase) << setfill('0') << x.dig[i];\n\t}\n\treturn os;\n}\nistream &operator >> (istream &is, BigInteger &x) {\n\tstring s; is >> s; x = BigInteger(s); return is;\n}\n\n\nint main() {\n\tll n, m, r;\n\tcin >> n >> m >> r;\n\tBigInteger b = BigInteger(\"1\");\n\tint R = r - n * m;\n\tif(R < 0) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tfor(int i = 0; i < n-1; ++i) {\n\t\tb = b * BigInteger(R+n-1-i);\n\t\tb = b /BigInteger(i+1);\n\t}\n\tcout << b << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 7620, "memory_kb": 3248, "score_of_the_acc": -1.0975, "final_rank": 10 }, { "submission_id": "aoj_0591_2511861", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i,n) REP(i,0,n)\n#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)\n#define repr(i, n) REPR(i, n, 0)\n#define REPR(i, s, e) for(int i=(int)(s-1); i>=(int)(e); i--)\n#define pb push_back\n#define all(r) r.begin(),r.end()\n#define rall(r) r.rbegin(),r.rend()\n#define fi first\n#define se second\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n\nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\ndouble EPS = 1e-8;\n\nstruct BigInteger {\n\tstatic const ll LogBase = 8;\n\tstatic const ll BASE = pow(10, LogBase);\n\tvector<ll> dig;\n\tbool isNeg;\n\tBigInteger() {}\n\tBigInteger(ll a, int sz, bool negative = false) : dig(sz, a), isNeg(negative) {}\n\tBigInteger(string s) {\n\t\tif (s[0] == '-') {\n\t\t\tisNeg = true;\n\t\t\ts = s.substr(1);\n\t\t} else isNeg = false;\n\t\treverse(all(s));\n\t\tfor (int i = 0; i < s.size(); i += LogBase) {\n\t\t\tdig.pb(0);\n\t\t\tll p = 1;\n\t\t\tfor (int j = 0; j < LogBase; j++) {\n\t\t\t\tif (i + j >= s.size()) break;\n\t\t\t\tdig.back() = dig.back() + (s[i + j] - '0') * p;\n\t\t\t\tp *= 10LL;\n\t\t\t}\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tBigInteger(ll a) {\n\t\tisNeg = a < 0;\n\t\tdig.pb(abs(a));\n\t\tif(dig.back() >= BASE) {\n\t\t\tll tmp = dig.back() / BASE;\n\t\t\tdig.back() %= BASE;\n\t\t\tdig.pb(tmp);\n\t\t}\n\t\twhile (size() > 1 && dig.back() == 0) dig.pop_back();\n\t}\n\tint size() const {return dig.size();}\n\tBigInteger getAbs()const {\n\t\tif (!isNeg) return *this;\n\t\tBigInteger ret = *this;\n\t\tret.isNeg = false;\n\t\treturn ret;\n\t}\n\tBigInteger normal() const {\n\t\tBigInteger ret = this->getAbs();\n\t\tfor (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t\twhile (ret.dig[i] >= BASE) ret.dig[i + 1] += ret.dig[i] / BASE, ret.dig[i] %= BASE;\n\t\t}\n\t\tif (ret.dig.back() >= BASE) {\n\t\t\tll tmp = ret.dig.back() / BASE;\n\t\t\tret.dig.back() %= BASE;\n\t\t\tret.dig.push_back(tmp);\n\t\t}\n\t\twhile (ret.size() > 1 && ret.dig.back() == 0) ret.dig.pop_back();\n\t\treturn ret;\n\t}\n\tpair<BigInteger, ll> divMod(ll a) const {\n\t\tBigInteger x = *this;\n\t\tll c = 0, t;\n\t\tfor (int i = x.size() - 1; i >= 0; --i) {\n\t\t\tt = BASE * c + x.dig[i];\n\t\t\tx.dig[i] = t / a;\n\t\t\tc = t % a;\n\t\t}\n\t\treturn pair<BigInteger, ll>(x.normal(), c);\n\t}\n\tpair<BigInteger, BigInteger> divMod(const BigInteger& bi) const {\n\t\tBigInteger x = this->getAbs(), y = bi.getAbs();\n\t\tif (x < y) return pair<BigInteger, BigInteger>(make_pair(BigInteger(\"0\"), *this));\n\t\tif (x == y) return pair<BigInteger, BigInteger> (BigInteger(\"1\"), BigInteger(\"0\"));\n\t\tll F = BASE / (y.dig.back() + 1);\n\t\tx = x * F;\n\t\ty = y * F;\n\n\t\tBigInteger z(0LL, x.size() - y.size() + 1, isNeg ^ bi.isNeg);\n\t\tfor (int k = z.size() - 1, i = x.size() - 1; k >= 0; --k, --i) {\n\t\t\tz.dig[k] = (i + 1 < x.size() ? x.dig[i + 1] : 0) * BASE + x.dig[i];\n\t\t\tz.dig[k] /= y.dig.back();\n\t\t\tBigInteger t(0, k + y.size());\n\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\tt.dig[k + m] = z.dig[k] * y.dig[m];\n\t\t\t}\n\n\t\t\tt = t.normal();\n\t\t\twhile (x < t) {\n\t\t\t\tz.dig[k] -= 1;\n\t\t\t\tfor (int m = 0; m < y.size(); ++m) {\n\t\t\t\t\tt.dig[k + m] -= y.dig[m];\n\t\t\t\t}\n\t\t\t\tt = t.normal();\n\t\t\t}\n\t\t\tx = x - t;\n\t\t}\n\t\treturn pair<BigInteger, BigInteger>(z.normal(), x / F);\n\t}\n\tBigInteger operator + (const BigInteger& bi) const {\n\t\tbool retNeg = false;\n\t\tif (isNeg) {\n\t\t\tif (bi.isNeg) retNeg = true;\n\t\t\telse bi - (this->getAbs());\n\t\t}\n\t\tif (bi.isNeg) return (*this) - bi.getAbs();\n\t\tBigInteger ret (0LL, max(this->size(), bi.size()) + 1, retNeg);\n\t\tfor (int i = 0; i + 1 < ret.size(); ++i) {\n\t\t\tif (i < this->size()) ret.dig[i] += this->dig[i];\n\t\t\tif (i < bi.size()) ret.dig[i] += bi.dig[i];\n\t\t\tif (ret.dig[i] >= BASE) ret.dig[i] -= BASE, ++ret.dig[i + 1];\n\t\t}\n\t\tif (ret.dig.back() == 0LL) ret.dig.pop_back();\n\t\treturn ret;\n\t}\n\tBigInteger operator - (const BigInteger& bi) const {\n\t\tif (bi.isNeg) return (*this) + bi.getAbs();\n\t\tif (isNeg) return bi - (this -> getAbs());\n\t\tif ((*this) < bi) {\n\t\t\tBigInteger ret = bi - (*this);\n\t\t\tret.isNeg = true;\n\t\t\treturn ret;\n\t\t}\n\t\tBigInteger ret = *this;\n\t\tfor (int i = 0; i < bi.size(); ++i) {\n\t\t\tret.dig[i] -= bi.dig[i];\n\t\t\tif (dig[i] < 0) ret.dig[i] += BASE, --ret.dig[i];\n\t\t}\n\t\treturn ret;\n\t}\n\tBigInteger operator * (const ll a) const {\n\t\tBigInteger ret = *this;\n\t\tfor (auto& d : ret.dig) d *= a;\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator * (const BigInteger& bi) const {\n\t\tBigInteger ret(0LL, this->size() + bi.size(), isNeg ^ bi.isNeg);\n\t\tfor (int i = 0; i < this->size(); ++i) {\n\t\t\tfor (int j = 0; j < bi.size(); ++j) {\n\t\t\t\tret.dig[i + j] += this->dig[i] * bi.dig[j];\n\t\t\t}\n\t\t}\n\t\treturn ret.normal();\n\t}\n\tBigInteger operator / (ll a) const {return this->divMod(a).first;}\n\tll operator % (ll a) const {return this->divMod(a).second;}\n\tBigInteger operator / (const BigInteger& bi) const {return this->divMod(bi).first;}\n\tBigInteger operator % (const BigInteger& bi) const {return this->divMod(bi).second;}\n\tbool operator < (const BigInteger& bi) const {\n\t\tif (this->size() != bi.size()) return this->size() < bi.size();\n\t\tfor (int i = this->size() - 1; i >= 0; --i) {\n\t\t\tif (dig[i] != bi.dig[i]) return dig[i] < bi.dig[i];\n\t\t}\n\t\treturn false;\n\t}\n\tbool operator > (const BigInteger& bi) const {return bi < (*this);}\n\tbool operator <= (const BigInteger& bi) const {!(*this > bi);}\n\tbool operator >= (const BigInteger& bi) const {!(*this < bi);}\n\tbool operator != (const BigInteger& bi) const {(*this < bi) || (*this > bi);}\n\tbool operator == (const BigInteger& bi) const {!(*this != bi);}\n\tvoid print() const{\n\t\tif(isNeg) printf(\"-\");\n\t\tprintf(\"%lld\", dig.back());\n\t\tfor(int i = size()-2; i>=0; --i) printf(\"%0*lld\", LogBase, dig[i]);\n\t}\n\tvoid println() const {\n\t\tprint();\n\t\tputs(\"\");\n\t}\n};\nostream &operator << (ostream &os, const BigInteger& x) {\n\tif (x.isNeg) os << '-';\n\tos << x.dig[x.size() - 1];\n\tfor (int i = x.size() - 2; i >= 0; --i) {\n\t\tos << setw(BigInteger::LogBase) << setfill('0') << x.dig[i];\n\t}\n\treturn os;\n}\nistream &operator >> (istream &is, BigInteger &x) {\n\tstring s; is >> s; x = BigInteger(s); return is;\n}\n\n\nint main() {\n\tll n, m, r;\n\tcin >> n >> m >> r;\n\tBigInteger b = BigInteger(\"1\");\n\tint R = r - n * m;\n\tif(R < 0) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tfor(int i = 0; i < n-1; ++i) {\n\t\tb = b * BigInteger(R+n-1-i);\n\t\tb = b /BigInteger(i+1);\n\t}\n\tcout << b << endl;\n\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 20, "memory_kb": 3188, "score_of_the_acc": -0.096, "final_rank": 16 }, { "submission_id": "aoj_0591_2511609", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define rep(i,n) REP(i,0,n)\n#define REP(i,s,e) for(int i=(s); i<(int)(e); i++)\n#define repr(i, n) REPR(i, n, 0)\n#define REPR(i, s, e) for(int i=(int)(s-1); i>=(int)(e); i--)\n#define pb push_back\n#define all(r) r.begin(),r.end()\n#define rall(r) r.rbegin(),r.rend()\n#define fi first\n#define se second\n \ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n \nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\ndouble EPS = 1e-8;\n\nconst int MAX_N=200010;\n\nll gcd(ll a, ll b){\n return b == 0LL ? a : gcd(b, a%b);\n}\nll lcm(ll a, ll b){\n return a / gcd(a, b) * b;\n}\nll extgcd(ll a, ll b, ll &x, ll &y){\n ll g = a;\n x = 1LL;\n y = 0LL;\n if(b != 0) g = extgcd(b, a%b, y, x), y-= (a/b)*x;\n return g;\n}\nll fact[MAX_N], ifact[MAX_N];\nll mod_inverse(int a){\n ll x, y;\n extgcd(a, MOD, x, y);\n return(MOD+x%MOD)%MOD;\n}\n\nvoid makeFact(){\n fact[0]=ifact[0] = 1LL;\n for(int i = 1; i < MAX_N; i++){\n fact[i] = fact[i-1]*i%MOD;\n ifact[i] = mod_inverse(fact[i]);\n }\n}\n\nll c(int n, int r){\n if(n < 0 || r < 0 || r > n) return 0;\n if(r > n / 2) r = n-r;\n return fact[n]*ifact[n-r]%MOD*ifact[r]%MOD;\n}\n\nint main(){\n\tmakeFact();\n\tint n, m, r;\n\tcin >> n >> m >> r;\n\tint R = r - m*n;\n\tif(R < 0) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\tcout << c(R+n-1, R) << endl;\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 50, "memory_kb": 6212, "score_of_the_acc": -0.242, "final_rank": 17 }, { "submission_id": "aoj_0591_1947949", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip\t;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1<<30;\nclass Calc{\n\t#define N 1000\n\t#define MOD 100000000\n public:\n ll carry, borrow,w,remainder;\n\tll z[N];\n\tvoid ladd(ll a[], ll b[]){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]+b[i]+carry;\n\t\t\tif(z[i]<MOD)carry=0;\n\t\t\telse{\n\t\t\t\tz[i]-=MOD;\n\t\t\t\tcarry=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lsub(ll a[], ll b[]){\n\t\tborrow=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]-b[i]-borrow;\n\t\t\tif(z[i]>=0)borrow=0;\n\t\t\telse{\n\t\t\t\tz[i]+=MOD;\n\t\t\t\tborrow=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lmul(ll c[], ll d){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w*d+carry)%MOD;\n\t\t\tcarry=(w*d+carry)/MOD;\n\t\t}\n\t}\n\tvoid ldiv(ll c[],ll d){\n\t\tremainder=0;\n\t\tfor(int i=0;i<N;i++){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w+remainder)/d;\n\t\t\tremainder=((w+remainder)%d)*MOD;\n\t\t}\n\t}\n\tvoid displayL(ll s[]){\n\t\tint t=0;\n\t\tfor(;t<N;t++)if(s[t]){\n\t\t\tprintf(\"%d\",s[t]);\n\t\t\tbreak;\n\t\t}\n\t\tfor(t++;t<N;t++)printf(\"%08d\",s[t]);\n\t\tprintf(\"\\n\");\n\t}\n\tvoid displayS(ll s){\n\t\tfor(int i=0;i<N-1;i++)printf(\"%8s\",\" \");\n\t\tprintf(\"%08d\\n\",s);\n\t}\n};\nint main(){\n\tCalc calc;\n\tll a,b,c;\n\tcin>>a>>b>>c;\n\tc-=a*b;\n\tif(c<0){\n\t\tcout<<0<<endl;\n\t}else{\n\t\trep(i,N){\n\t\t\tcalc.z[i]=0;\n\t\t}\n\t\tcalc.z[N-1]=1;\n\t\tloop(i,1,c+a)calc.lmul(calc.z,i);\n\t\tloop(i,1,c+1)calc.ldiv(calc.z,i);\n\t\tloop(i,1,a)calc.ldiv(calc.z,i);\n\t\tcalc.displayL(calc.z);\n\t}\n}", "accuracy": 0.8, "time_ms": 270, "memory_kb": 1172, "score_of_the_acc": -0.0342, "final_rank": 11 }, { "submission_id": "aoj_0591_1947947", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip\t;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1<<30;\nclass Calc{\n\t#define N 10000\n\t#define MOD 100000000\n public:\n ll carry, borrow,w,remainder;\n\tll z[N];\n\tvoid ladd(ll a[], ll b[]){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]+b[i]+carry;\n\t\t\tif(z[i]<MOD)carry=0;\n\t\t\telse{\n\t\t\t\tz[i]-=MOD;\n\t\t\t\tcarry=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lsub(ll a[], ll b[]){\n\t\tborrow=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]-b[i]-borrow;\n\t\t\tif(z[i]>=0)borrow=0;\n\t\t\telse{\n\t\t\t\tz[i]+=MOD;\n\t\t\t\tborrow=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lmul(ll c[], ll d){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w*d+carry)%MOD;\n\t\t\tcarry=(w*d+carry)/MOD;\n\t\t}\n\t}\n\tvoid ldiv(ll c[],ll d){\n\t\tremainder=0;\n\t\tfor(int i=0;i<N;i++){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w+remainder)/d;\n\t\t\tremainder=((w+remainder)%d)*MOD;\n\t\t}\n\t}\n\tvoid displayL(ll s[]){\n\t\tint t=0;\n\t\tfor(;t<N;t++)if(s[t]){\n\t\t\tprintf(\"%d\",s[t]);\n\t\t\tbreak;\n\t\t}\n\t\tfor(t++;t<N;t++)printf(\"%08d\",s[t]);\n\t\tprintf(\"\\n\");\n\t}\n\tvoid displayS(ll s){\n\t\tfor(int i=0;i<N-1;i++)printf(\"%8s\",\" \");\n\t\tprintf(\"%08d\\n\",s);\n\t}\n};\nint main(){\n\tCalc calc;\n\tll a,b,c;\n\tcin>>a>>b>>c;\n\tc-=a*b;\n\tif(c<0){\n\t\tcout<<0<<endl;\n\t}else{\n\t\trep(i,N){\n\t\t\tcalc.z[i]=0;\n\t\t}\n\t\tcalc.z[N-1]=1;\n\t\tloop(i,1,c+a)calc.lmul(calc.z,i);\n\t\tloop(i,1,c+1)calc.ldiv(calc.z,i);\n\t\tloop(i,1,a)calc.ldiv(calc.z,i);\n\t\tcalc.displayL(calc.z);\n\t}\n}", "accuracy": 1, "time_ms": 2840, "memory_kb": 1244, "score_of_the_acc": -0.3753, "final_rank": 5 }, { "submission_id": "aoj_0591_1947933", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\t\n#include<map>\n#include<set>\n#include<utility>\n#include<cmath>\n#include<cstring>\n#include<queue>\n#include<cstdio>\n#include<sstream>\n#include<iomanip>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb push_back\n#define mp make_pair\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\nusing namespace std;\n//kaewasuretyuui\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vp;\ntypedef vector<vp> vvp;\ntypedef pair<int,pii> pip;\ntypedef vector<pip>vip\t;\nconst double PI=acos(-1);\nconst double EPS=1e-8;\nconst int inf=1<<30;\nclass Calc{\n\t#define N 10000\n\t#define MOD 100000000\n public:\n int carry, borrow,w,remainder;\n\tint z[N];\n\tvoid ladd(int a[], int b[]){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]+b[i]+carry;\n\t\t\tif(z[i]<MOD)carry=0;\n\t\t\telse{\n\t\t\t\tz[i]-=MOD;\n\t\t\t\tcarry=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lsub(int a[], int b[]){\n\t\tborrow=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tz[i]=a[i]-b[i]-borrow;\n\t\t\tif(z[i]>=0)borrow=0;\n\t\t\telse{\n\t\t\t\tz[i]+=MOD;\n\t\t\t\tborrow=1;\n\t\t\t}\n\t\t}\n\t}\n\tvoid lmul(int c[], int d){\n\t\tcarry=0;\n\t\tfor(int i=N-1;i>=0;i--){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w*d+carry)%MOD;\n\t\t\tcarry=(w*d+carry)/MOD;\n\t\t}\n\t}\n\tvoid ldiv(int c[], int d){\n\t\tremainder=0;\n\t\tfor(int i=0;i<N;i++){\n\t\t\tw=c[i];\n\t\t\tz[i]=(w+remainder)/d;\n\t\t\tremainder=((w+remainder)%d)*MOD;\n\t\t}\n\t}\n\tvoid displayL(int s[]){\n\t\tint t=0;\n\t\tfor(;t<N;t++)if(s[t]){\n\t\t\tprintf(\"%d\",s[t]);\n\t\t\tbreak;\n\t\t}\n\t\tfor(t++;t<N;t++)printf(\"%08d\",s[t]);\n\t\tprintf(\"\\n\");\n\t}\n\tvoid displayS(int s){\n\t\tfor(int i=0;i<N-1;i++)printf(\"%8s\",\" \");\n\t\tprintf(\"%08d\\n\",s);\n\t}\n};\nint main(){\n\tCalc calc;\n\tll a,b,c;\n\tcin>>a>>b>>c;\n\tc-=a*b;\n\tif(c<0){\n\t\tcout<<0<<endl;\n\t}else{\n\t\trep(i,N){\n\t\t\tcalc.z[i]=0;\n\t\t}\n\t\tcalc.z[N-1]=1;\n\t\tloop(i,1,c+a)calc.lmul(calc.z,i);\n\t\tloop(i,1,c+1)calc.ldiv(calc.z,i);\n\t\tloop(i,1,a)calc.ldiv(calc.z,i);\n\t\tcalc.displayL(calc.z);\n\t}\n}", "accuracy": 0.4, "time_ms": 10, "memory_kb": 1184, "score_of_the_acc": -0.0006, "final_rank": 20 }, { "submission_id": "aoj_0591_1670654", "code_snippet": "//??????2???1??¨???1???2???????????????1???2??¨???2???1?????°??????????????¨???????????????\n//a[0] + ??? + a[n-1] = r - mn (a[i] >= 0)????????????a[0]???a[n]????????¶???????????° ??? ??????\n//????????????[r - mn + n - 1]C[n-1]????????¨?????´??????0<=m<=n<=r<=10000????????§?????????????????????\n//????????????(r-mn+n-1)!/(n-1)!/(r-mn)!????????????DivTa baityou.\n#include <iostream>\n#include <cstdio>\nusing namespace std;\n\nclass BigInt{\npublic:\n\tint d[30000];\t//1000?????°??§?????£?????????(??????????°???????????????????)\n\tint n;\t\t\t//?????§?????°\n\t\n\tBigInt(int n){\n\t\tthis->n = n;\n\t\tfor( int i = 0; i < n; i++ ) d[i] = 0;\n\t\td[0] = 1;\n\t}\n\tvoid mult(int x){\n\t\tfor( int i = 0; i < n; i++ ){\n\t\t\td[i] *= x;\n\t\t}\n\t\tfor( int i = 0; i < n; i++ ){\n\t\t\td[i+1] += (d[i] / 1000);\n\t\t\td[i] %= 1000;\n\t\t}\n\t}\n\tvoid div(int x){\n\t\tfor( int i = n-1; i >= 0; i-- ){\n\t\t\tif( i > 0 )\n\t\t\t\td[i-1] += (d[i] % x) * 1000;\n\t\t\td[i] /= x;\n\t\t}\n\t}\n\tvoid output(int p, bool isPut0=true){\n\t\tif( isPut0 )\n\t\t\tprintf(\"%03d\", d[p]);\n\t\telse\n\t\t\tprintf(\"%d\", d[p]);\n\t}\n\tvoid disp(int r){\n\t\tfor( int i = r-1; i >= 0; i-- )\n\t\t\tprintf(\"%d\", d[i]);\n\t\tputs(\"\");\n\t}\n};\nBigInt big(29000);\n\nint main()\n{\n\tint n, m, r;\n\tint i;\n\t\n\tcin >> n >> m >> r;\n\tif( r - m*n < n ){ cout << 0 << endl; return 0; }\n\t\n\tfor( i = r - m*n + n - 1; i >= n; i-- )\n\t\tbig.mult(i);\n\tfor( i = 1; i <= r - m*n; i++ )\n\t\tbig.div(i);\n\t\n\ti = 28999;\n\twhile( big.d[i] == 0 ){ i--; }\n\tbig.output(i--, false);\n\twhile( i >= 0 ){\n\t\tbig.output(i);\n\t\ti--;\n\t}\n\tcout << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3570, "memory_kb": 1312, "score_of_the_acc": -0.4744, "final_rank": 7 } ]
aoj_0586_cpp
問題5 J中学校の運動会で次のようなクラス対抗の競技を行なうことになった. 各クラスから生徒代表の男女 n ペア (男子生徒 b 1 , 女子生徒 g 1 ), (男子生徒 b 2 , 女子生徒 g 2 ), … , (男子生徒 b n , 女子生徒 g n ) を選び, 0 から 9 までの数字が書かれた旗を自由に選んでもらい (それぞれの旗は十分な個数ある), 横一列に並んでもらう. ただし, ペアになっている男子生徒と女子生徒は同じ番号の旗を一人1つずつ 選ばなければならず, 並び順は b 1 b 2 … b n c g n … g 2 g 1 のように, 男子生徒達 n 人の並び順 b 1 b 2 … b n とは逆の順番 g n … g 2 g 1 で女子生徒達は 並ばなければならない. 中央の c には, クラス担任の先生があらかじめ審判長によって指定された 番号の付いた旗を持って立つ場合と, 立たないことを審判長に指定される場合とがある. こうして並んだ生徒達(と先生)が持った旗の番号 を 2n 桁(または 2n+1 桁)の整数と考えたとき, それが素数である方が勝ちである. ただし, 両クラスとも素数だった場合あるいは両クラスとも素数でなかった場合には, 数が大きい方が勝ちである. また, 0 b 2 … b n c g n … g 2 0  あるいは  0 b 2 … b n g n … g 2 0 のように先頭に 0 が来るものは, 普通使われる数の表し方ではないので禁止されている. J中学校の生徒であるあなたは, 自分のクラスが勝つためにはどのように並ぶのがよいかを 考えなければならない. 入力ファイルの1行目に正整数 n と 1桁の整数 c(先生が持つ旗の番号)が 1つの半角空白文字で区切られて書かれている. c<0 のときは, 先生が中央に立たないことを表わす. 与えられる入力は 1≦n≦10 である. 負けない並び方の順番 b 1 b 2 … b n c g n … g 2 g 1 または  b 1 b 2 … b n g n … g 2 g 1 を出力せよ. 出力ファイルにおいては, 出力の最後にも改行コードを入れること. 入出力例 入力例1 1 0 出力例1 101 入力例2 1 5 出力例2 757 入力例3 3 7 出力例3 9957599 入力例4 1 -1 出力例4 11 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0586_7963721", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int a,b; cin >> a >> b;\n if (b < 0) {\n if (a == 1) {\n cout << 11 << endl;\n }\n else {\n for (int i = 0; i < 2*a; i++) {\n cout << 9;\n }\n cout << endl;\n }\n }\n else {\n vector<ll> ten;\n {\n ll cur = 1;\n for (int i = 0; i <= 18; i++) {\n ten.push_back(cur);\n cur *= 10;\n }\n }\n ll res = -1;\n ll cur = ten[a]*b;\n auto dfs = [&](auto dfs, int i) -> void {\n if (i == a) {\n if (res > cur) return;\n for (ll p = 2; p*p <= cur; p++) {\n if (cur%p == 0) return;\n }\n res = max(res, cur); \n return; \n }\n else {\n for (int j = 0; j <= 9; j++) {\n if (i == 0 and j%2 == 0) continue;\n cur += ten[i] * j;\n cur += ten[2*a-i] * j;\n dfs(dfs, i+1);\n cur -= ten[i] * j;\n cur -= ten[2*a-i] * j;\n }\n }\n };\n dfs(dfs,0);\n if (res == -1) {\n for (int i = 0; i < a; i++) {\n cout << 9;\n }\n cout << b;\n for (int i = 0; i < a; i++) {\n cout << 9;\n }\n cout << endl;\n }\n else {\n cout << res << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3384, "score_of_the_acc": -1.0383, "final_rank": 17 }, { "submission_id": "aoj_0586_3280435", "code_snippet": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\ntypedef long long ll;\n\nll ret = -1;\nll x;\nint n, c;\n\nbool isPrime(ll tmp){\n for(ll i = 2; i*i <= tmp; i++){\n if(tmp%i == 0) return false;\n }\n return tmp!=1;\n}\n\nll apow(int s){\n ll ret = 1;\n while(s-- > 0) ret *= 10;\n return ret;\n}\n\nvoid dfs(int p){\n if(isPrime(x)) ret = max(ret, x);\n if(p == 0) return;\n\n for(int i = 0; i <= 9; i++){\n if(p == 1 && i == 0) continue;\n x *= 10;\n x += i;\n x += apow(2*(n-p+1)) * i;\n dfs(p-1);\n x -= apow(2*(n-p+1)) * i;\n x /= 10;\n }\n}\n\nint main(){\n cin >> n >> c;\n\n if(c < 0){\n if(n == 1) cout << 11 << endl;\n else{\n for(int i = 0; i < 2*n; i++) cout << \"9\";\n cout << endl;\n }\n }else{\n x = c;\n dfs(n);\n cout << ret << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3088, "score_of_the_acc": -0.9238, "final_rank": 13 }, { "submission_id": "aoj_0586_3172044", "code_snippet": "// test \n\n#include <cstdio>\n#include <cstdlib>\n#include <algorithm>\n\nusing namespace std;\nint n, m;\nlong long int ans;\n\nchar x[16];\n\nbool prime(long long int x)\n{\n\tfor (long long int i = 2; i * i <= x; i++){\n\t\tif (x % i == 0) return (false);\n\t}\n\treturn (x != 1);\n}\n\nvoid dfs(int idx)\n{\n\tif (idx == n){\n\t\tif (prime(atoll(x))) ans = max(ans, atoll(x));\n\t\treturn;\n\t}\n\tfor (int i = '0'; i <= '9'; i++){\n\t\tif (idx == 0 && (i != '1' && i != '3' && i != '7' && i != '9')) continue;\n\t\tx[idx] = i; x[2 * n - idx] = i;\n\t\tdfs(idx + 1);\n\t}\n}\n\nint main()\n{\t\n\tscanf(\"%d %d\", &n, &m);\n\tif (m < 0){\n\t\tif (n != 1) for (int i = 0; i < 2 * n; i++) printf(\"9\");\n\t\telse printf(\"11\");\n\t\tprintf(\"\\n\");\n\t}\n\telse {\n\t\tx[2 * n + 1] = 0;\n\t\tx[n] = m + '0';\n\t\tdfs(0);\n\t\tprintf(\"%lld\\n\", ans);\n\t}\n\treturn (0);\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 2696, "score_of_the_acc": -0.7577, "final_rank": 12 }, { "submission_id": "aoj_0586_2831780", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nll N,C;\n\nbool is_ok(ll num){\n\n\tstack<ll> S;\n\n\twhile(num > 0){\n\t\tS.push(num%10);\n\t\tnum /= 10;\n\t}\n\n\tint index = 0;\n\tll array[22];\n\n\twhile(!S.empty()){\n\t\tarray[index++] = S.top();\n\t\tS.pop();\n\t}\n\n\tif(array[N] != C){\n\t\treturn false;\n\t}\n\n\tfor(int i = 0; i < index/2; i++){\n\t\tif(array[i] != array[index-1-i]){\n\t\t\treturn false;\n\t\t}\n\t}\n\treturn true;\n}\n\n\nint main(){\n\n\tscanf(\"%lld %lld\",&N,&C);\n\n\tif(C < 0){\n\t\tif(N == 1){\n\t\t\tprintf(\"11\\n\");\n\t\t}else{\n\t\t\tfor(ll i = 0; i < 2*N; i++){\n\t\t\t\tprintf(\"9\");\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\treturn 0;\n\t}\n\n\tll num = 0;\n\tfor(ll i = 0; i < N; i++){\n\t\tnum = 10*num+9;\n\t}\n\tnum = 10*num+C;\n\tfor(ll i = 0; i < N; i++){\n\t\tnum = 10*num+9;\n\t}\n\n\tbool FLG;\n\n\twhile(true){\n\t\tif(is_ok(num)){\n\t\t\tif(num%2 != 0){\n\t\t\t\tFLG = true;\n\t\t\t\tfor(int i = 3; i*i <= num; i += 2){\n\t\t\t\t\tif(num%i == 0){\n\t\t\t\t\t\tFLG = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(FLG){\n\t\t\t\t\tprintf(\"%lld\\n\",num);\n\t\t\t\t\treturn 0;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tnum--;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3184, "score_of_the_acc": -0.9644, "final_rank": 14 }, { "submission_id": "aoj_0586_2198814", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\n\nint a, b, t = 0, u = 0;\nint Max = 0;\nbool is_prime(int n) {\n\tfor (int i = 2; i*i <= n; i++) {\n\t\tif (n%i == 0)return false;\n\t}\n\treturn true;\n}\nvoid dfs(int p) {\n\tif (a == p) {\n\t\tint c = t*pow(10, a + 1) + b*pow(10, a) + u;\n\t\tif (is_prime(c))Max = max(Max, c);\n\t\treturn;\n\t}\n\trep(i, 10) {\n\t\tif (i == 0 && p == 0)continue;\n\t\tt = t * 10 + i;\n\t\tu += i*pow(10, p);\n\t\tdfs(p + 1);\n\t\tt /= 10; u -= i*pow(10, p);\n\t}\n}\nint main() {\n\tscanf(\"%d%d\", &a, &b);\n\tif (b < 0) {\n\t\tif (a == 1)puts(\"11\");\n\t\telse {\n\t\t\trep(i, 2*a)printf(\"9\");\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\treturn 0;\n\t}\n\tdfs(0);\n\tprintf(\"%d\\n\", Max);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3348, "score_of_the_acc": -0.9957, "final_rank": 16 }, { "submission_id": "aoj_0586_2198797", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\n\nint a, b;\nstring t, u;\nint Max = 0;\nbool is_prime(int n) {\n\tfor (int i = 2; i*i <= n; i++) {\n\t\tif (n%i == 0)return false;\n\t}\n\treturn true;\n}\nvoid dfs(int p) {\n\tif (a == p) {\n\t\tstring q = t; reverse(q.begin(), q.end());\n\t\tint c = stoi(t + u + q);\n\t\tif (is_prime(c))Max = max(Max, c);\n\t\treturn;\n\t}\n\trep(i, 10) {\n\t\tif (i == 0 && p == 0)continue;\n\t\tt += to_string(i);\n\t\tdfs(p + 1);\n\t\tt.pop_back();\n\t}\n}\nint main() {\n\tscanf(\"%d%d\", &a, &b);\n\tif (b < 0) {\n\t\tif (a == 1)puts(\"11\");\n\t\telse {\n\t\t\trep(i, 2*a)printf(\"9\");\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t\treturn 0;\n\t}\n\tu = to_string(b);\n\tdfs(0);\n\tprintf(\"%d\\n\", Max);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3308, "score_of_the_acc": -0.9787, "final_rank": 15 }, { "submission_id": "aoj_0586_1546726", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint N,C;\n\n\nint a[10000];\nlong long ans;\n\nvoid check(){\n a[N]=C;\n for(int i=0;i<N;i++)a[2*N-i]=a[i];\n\n long long val=0;\n for(int i=0;i<2*N+1;i++){\n val=val*10+a[i];\n }\n\n for(long long i=2;i*i<=val;i++){\n if(val%i==0)return;\n }\n\n ans=max(ans,val);\n}\n\nvoid dfs(int pos){\n if(pos==N){\n check();\n return;\n }\n\n for(int i=0;i<10;i++){\n if(pos==0&&i==0)continue;\n a[pos]=i;\n dfs(pos+1);\n }\n\n}\nint main(){\n cin>>N>>C;\n\n if(C<0&&N>1){\n for(int i=0;i<2*N;i++)cout<<9;\n cout<<endl;\n }\n else if(C<0){\n cout<<11<<endl;\n }\n else{\n dfs(0);\n cout<<ans<<endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 1168, "score_of_the_acc": -0.1157, "final_rank": 6 }, { "submission_id": "aoj_0586_1527979", "code_snippet": "#include <bits/stdc++.h>\n#define PB push_back\n#define MP make_pair\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define ALL(a) (a).begin(),(a).end()\n#define MOD 10000\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\nconst ull B=100000007;\nconst int INF=1e9;\nstring rs;\nll N,C,ans;\nbool is_prime(ll n){\n for(int i=2;i*i<=n;i++){\n if(n%i==0)return false;\n }\n return n!=1;\n}\nll to_i(string s){\n ll k=1,res=0;\n reverse(ALL(s));\n REP(i,s.size()){\n res+=(s[i]-'0')*k;\n k*=10;\n }\n return res;\n}\nvoid rec(string s){\n if(s.size()==N){\n if((s[0]-'0')%2==0)return;\n rs=s;reverse(ALL(rs));\n if(C>=0)s+=(char)(C+'0');\n s+=rs;\n ll t=to_i(s);\n if(is_prime(t))ans=max(ans,t);\n return;\n }\n REP(i,10)rec(s+(char)(i+'0'));\n return;\n}\nint main(){\n cin>>N>>C;\n ans=-1;\n if(C<0){\n REP(i,N*2)cout<<9;cout<<endl;\n }else{\n rec(\"\");\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 1208, "score_of_the_acc": -0.1326, "final_rank": 8 }, { "submission_id": "aoj_0586_1443154", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <string>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n\n\nusing namespace std;\ntypedef long long ll;\n\n#define mod 1000000007\n#define INF 2000000000\n#define LLINF 4000000000000000000\n#define SIZE 50010\n\nint num[4];\nint n,c,ans=0;\n\nint dfs(int h){\n int k=0;\n bool f = true;\n \n if(h==n){\n \n for(int i=0;i<n;i++){\n k+=(int)(pow(10,i)+pow(10,2*n-i))*num[i];\n }\n \n k+=(int)pow(10,n)*c;\n \n for(int i=2;i*i<=k;i++){\n if (k%i==0) {\n f =false;\n break;\n }\n }\n \n if(f)\n return k;\n else\n return 0;\n }\n \n for(int i=0;i<=9;i++){\n num[h] = i;\n k=max(k,dfs(h+1));\n }\n \n return k;\n}\n\nint main(){\n \n scanf(\"%d%d\",&n,&c);\n \n if(c < 0){\n if(n==1){\n puts(\"11\");\n return 0;\n }\n \n for(int i=0;i<2*n;i++)\n printf(\"9\");\n printf(\"\\n\");\n return 0;\n }\n \n ans = dfs(0);\n \n if(ans==0){\n for(int i=0;i<2*n+1;i++){\n if(i==n)\n printf(\"%d\",c);\n else\n printf(\"9\");\n }\n printf(\"?\\n\");\n return 0;\n }\n \n printf(\"%d\\n\",ans);\n \n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1232, "score_of_the_acc": -0.1155, "final_rank": 3 }, { "submission_id": "aoj_0586_1232205", "code_snippet": "#include<cstdio>\n#include<iostream>\n#include<string>\n\nusing namespace std;\ntypedef long long ll;\nint n,c;\n\nbool check(ll q){\n\tint cd[11];\n\tfor(int i=0;i<n*2+1;i++){\n\t\tcd[i]=q%10;\n\t\tq/=10;\n\t}\n\tif(cd[n]!=c)return false;\n\tfor(int i=0;i<n;i++){\n\t\tif(cd[i]!=cd[n*2-i])return false;\n\t}\n\treturn true;\n}\n\nint main(void){\n\tscanf(\"%d%d\",&n,&c);\n\tif(c<0){\n\t\tif(n==1)printf(\"11\\n\");\n\t\telse{\n\t\t\tstring s;\n\t\t\tfor(int i=0;i<n*2;i++)s+='9';\n\t\t\tcout << s << endl;\n\t\t}\n\t\treturn 0;\n\t}\n\t\n\tll q=0;\n\tfor(int i=0;i<n*2+1;i++)q=q*10+9;\n\twhile(1){\n\t\tif(check(q)){\n\t\t\tbool f=true;\n\t\t\tfor(ll i=2;i*i<=q;i++){\n\t\t\t\tif(q%i==0)f=false;\n\t\t\t\tif(!f)break;\n\t\t\t}\n\t\t\tif(f){\n\t\t\t\tprintf(\"%lld\\n\",q);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tq--;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1208, "score_of_the_acc": -0.078, "final_rank": 2 }, { "submission_id": "aoj_0586_1232202", "code_snippet": "#include<cstdio>\n#include<iostream>\n#include<string>\n\nusing namespace std;\ntypedef long long ll;\nint n,c;\n\nbool check(ll q){\n\tint cd[11];\n\tfor(int i=0;i<n*2+1;i++){\n\t\tcd[i]=q%10;\n\t\tq/=10;\n\t}\n\tif(cd[n]!=c)return false;\n\tfor(int i=0;i<n;i++){\n\t\tif(cd[i]!=cd[n*2-i])return false;\n\t}\n\treturn true;\n}\n\nint main(void){\n\tscanf(\"%d%d\",&n,&c);\n\tll q=0;\n\tif(c<0){\n\t\tif(n==1)printf(\"11\\n\");\n\t\telse{\n\t\t\tfor(int i=0;i<n*2;i++)q=q*10+9;\n\t\t\tprintf(\"%lld\\n\",q);\n\t\t}\n\t\treturn 0;\n\t}\n\tfor(int i=0;i<n*2+1;i++)q=q*10+9;\n\twhile(1){\n\t\tif(check(q)){\n\t\t\tbool f=true;\n\t\t\tfor(ll i=2;i*i<=q;i++){\n\t\t\t\tif(q%i==0)f=false;\n\t\t\t\tif(!f)break;\n\t\t\t}\n\t\t\tif(f){\n\t\t\t\tprintf(\"%lld\\n\",q);\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\tq--;\n\t}\n\treturn 0;\n}", "accuracy": 0.8, "time_ms": 10, "memory_kb": 1192, "score_of_the_acc": -0.0712, "final_rank": 18 }, { "submission_id": "aoj_0586_1207579", "code_snippet": "/*\n inputファイル見ないと通るか分からない奴やめろ\n */\n\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\nint n;\nint c;\n\nint pow(int base, int exp) {\n int res;\n if (exp == 0) return 1;\n\n res = pow(base*base, exp/2);\n if (exp % 2 == 1) res *= base;\n return res;\n}\n\nbool isprime(int p) {\n for (int i=2; i<=(int)floor(sqrt(p)); i++) {\n if (p % i == 0) return false;\n }\n\n return true;\n}\n\nint dfs(int now, int count) {\n int ans = -1;\n\n if (count == 0) {\n if (now % 10 == 0 || !isprime(now)) return -1;\n return now;\n }\n\n for (int i=0; i<10; i++) {\n ans = max(ans, dfs(now * 10 + i * pow(10, (n-count+1)*2) + i, count-1));\n }\n\n return ans;\n}\n\n\nint main() {\n scanf(\"%d %d\", &n, &c);\n\n if (c < 0) {\n if (n == 1) {\n puts(\"11\");\n } else {\n for (int i=0; i<n*2; i++) printf(\"9\");\n puts(\"\");\n }\n } else {\n int ans = dfs(c, n);\n if (ans == -1) {\n for (int i=0; i<n; i++) printf(\"9\");\n printf(\"%d\", c);\n for (int i=0; i<n; i++) printf(\"9\");\n puts(\"\");\n } else {\n printf(\"%d\\n\", ans);\n }\n }\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 1024, "score_of_the_acc": -0.0219, "final_rank": 1 }, { "submission_id": "aoj_0586_1132817", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\ninline string toString(int a){\n stringstream ss;\n ss << a;\n return ss.str();\n}\n\ninline int toInt(string s){\n stringstream ss(s);\n int res;\n ss >> res;\n return res;\n}\n\ninline bool is_prime(int a){\n if(a<=1)return false;\n for(int i=2;i*i<=a;i++){\n if(a%i==0)return false;\n }\n return true;\n}\n\nint rec(int d, int n, string s, string c){\n if(n>4)return -1;\n if(d==n){\n string pal = s + c;\n reverse(s.begin(),s.end());\n pal += s;\n int p = toInt(pal);\n return is_prime(p)?p:-1;\n }\n\n int res = -1;\n for(int i=0;i<10;i++){\n if(d==0 && (i%2==0 || i%5==0))continue;\n res = max( res, rec(d+1, n, s + toString(i), c) );\n }\n return res;\n}\n\nint main(){\n int n,c;\n cin >> n >> c;\n string center = (c<0)?\"\":toString(c);\n int res = rec(0,n,\"\",center);\n\n if(res<0){\n for(int i=0;i<n;i++)cout << \"9\";\n cout << center;\n for(int i=0;i<n;i++)cout << \"9\";\n cout << endl;\n }else{\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1232, "score_of_the_acc": -0.1155, "final_rank": 3 }, { "submission_id": "aoj_0586_1132815", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nstring toString(int a){\n stringstream ss;\n ss << a;\n return ss.str();\n}\n\nint toInt(string s){\n stringstream ss(s);\n int res;\n ss >> res;\n return res;\n}\n\nbool is_prime(int a){\n if(a<=1)return false;\n for(int i=2;i*i<=a;i++){\n if(a%i==0)return false;\n }\n return true;\n}\n\nint rec(int d, int n, string s, string c){\n if(n>4)return -1;\n if(d==n){\n string pal = s + c;\n reverse(s.begin(),s.end());\n pal += s;\n int p = toInt(pal);\n return is_prime(p)?p:-1;\n }\n\n int res = -1;\n for(int i=0;i<10;i++){\n if(d==0 && (i%2==0 || i%5==0))continue;\n res = max( res, rec(d+1, n, s + toString(i), c) );\n }\n return res;\n}\n\nint main(){\n int n,c;\n cin >> n >> c;\n string center = (c<0)?\"\":toString(c);\n int res = rec(0,n,\"\",center);\n\n if(res<0){\n for(int i=0;i<n;i++)cout << \"9\";\n cout << center;\n for(int i=0;i<n;i++)cout << \"9\";\n cout << endl;\n }else{\n cout << res << endl;\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 1232, "score_of_the_acc": -0.1155, "final_rank": 3 }, { "submission_id": "aoj_0586_1011954", "code_snippet": "#define _USE_MATH_DEFINES\n#define INF 0x3f3f3f3f\n\n#include <iostream>\n#include <cstdio>\n#include <sstream>\n#include <cmath>\n#include <cstdlib>\n#include <algorithm>\n#include <queue>\n#include <stack>\n#include <limits>\n#include <map>\n#include <string>\n#include <cstring>\n#include <set>\n#include <deque>\n#include <bitset>\n#include <list>\n#include <cctype>\n#include <utility>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair <int,int> P;\ntypedef pair <int,P> PP;\n \nstatic const double EPS = 1e-8;\n \nstatic const int tx[] = {0,1,0,-1};\nstatic const int ty[] = {-1,0,1,0};\n\nll fast_pow(ll x, ll n) {\n ll res = 1;\n while(n > 0) {\n if (n & 1) res = res * x;\n x = x * x;\n n >>= 1;\n }\n return res;\n}\n\nbool is_prime(ll n){\n for(ll x = 2; x * x <= n;x++){\n if(n % x == 0) return false;\n }\n return true;\n}\n\nenum Type{\n EVEN,\n ODD,\n};\n\nType type;\n\nll dfs(ll pos,ll sum,ll len,ll center){\n if(pos == len/2){\n sum += (type == EVEN ? 0 : center * fast_pow(10,len/2));\n if(is_prime(sum)){\n return sum;\n }\n return 0;\n }\n ll res = 0;\n \n for(ll i=0;i<=9;i++){\n if(pos == 0 && i == 0) continue;\n ll lhs = i * fast_pow(10,pos);\n ll rhs = i * fast_pow(10,len-pos-1);\n res = max(dfs(pos + 1,sum + lhs + rhs,len,center),res);\n }\n return res;\n}\n\nint main(){\n ll n,center;\n while(~scanf(\"%lld %lld\",&n,&center)){\n //odd\n if(center < 0){\n type = EVEN;\n\n if(n == 1){\n cout << \"11\" << endl;\n }\n else{\n cout << string(2*n,'9') << endl;\n }\n }\n //even\n else{\n type = ODD;\n ll len = 2 * n + (type == ODD ? 1 : 0); \n ll ans = 0;\n ll none_ans = 0;\n \n for(int i=0;i<len;i++){\n none_ans += 9 * fast_pow(10,i);\n }\n printf(\"%lld\\n\",(ans = dfs(0,0,len,center)) == 0 ? none_ans : ans);\n }\n }\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 1216, "score_of_the_acc": -0.136, "final_rank": 9 }, { "submission_id": "aoj_0586_984587", "code_snippet": "#include<iostream>\n#include<sstream>\n#include<vector>\n\nusing namespace std;\n\nlong long pow10(int n){\n\tlong long res=1;\n\twhile(n--)\n\t\tres*=10;\n\treturn res;\n}\n\nbool isPrime(long long n){\n\tfor(long long i=2;i*i<=n;i++)\n\t\tif(n%i==0)return false;\n\treturn true;\n}\n\nint main(){\n\tostringstream out;\n\n\tint n,m;\n\tcin >> n >> m;\n\tvector<int> boy;\n\tfor(int i=0;i<n;i++)\n\t\tboy.push_back(9);\n\n/*\n\tvector<bool> prime(pow10(m>=0?2*n+1:2*n));\n\tfor(int i=2;i<prime.size();i++){\n\t\tif(prime[i])continue;\n\t\tfor(int j=i*2;j<prime.size();j+=i)\n\t\t\tprime[j]=true;\n\t}\n*/\n/*\n\tfor(int i=0;i<prime.size();i++)\n\t\tcout << i << \" \"<<prime[i] << endl;\n\n\tif(true)\n\t\treturn 0;\n*/\n\n\twhile(true){\n\t\tvector<int>num;\n\t\tfor(int i=0;i<n;i++)\n\t\t\tnum.push_back(boy[i]);\n\t\tif(m>=0)\n\t\t\tnum.push_back(m);\n\t\tfor(int i=n-1;i>=0;i--)\n\t\t\tnum.push_back(boy[i]);\n\t\tunsigned long long number=0;\n\t\tfor(int i=0;i<num.size();i++)\n\t\t\tnumber+=num[i]*pow10(num.size()-1-i);\n//\t\tif(!prime[number]){\n\t\tif(isPrime(number)){\n\t\t\tout << number << endl;\n\t\t\tbreak;\n\t\t}\n\n\t\tint i=boy.size()-1;\n\t\tfor(;i>=0;i--){\n\t\t\tif(boy[i]<0){\n\t\t\t\tboy[i]=9;\n\t\t\t\tif(i>0)\n\t\t\t\t\tboy[i-1]--;\n\t\t\t\tcontinue;\n\t\t\t}else{\n\t\t\t\tboy[i]--;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(i<0||boy[i]==0){\n\t\t\tfor(int i=0;i<n;i++)\n\t\t\t\tout << 9;\n\t\t\tif(m>=0)\n\t\t\t\tout << m;\n\t\t\tfor(int i=0;i<n;i++)\n\t\t\t\tout << 9;\n\t\t\tout << endl;\n\t\t\tbreak;\n\t\t}\n\n\t}\n\n\tcout << out.str();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 1244, "score_of_the_acc": -0.1315, "final_rank": 7 }, { "submission_id": "aoj_0586_984567", "code_snippet": "#include<iostream>\n#include<sstream>\n#include<vector>\n\nusing namespace std;\n\nint pow10(int n){\n\tint res=1;\n\twhile(n--)\n\t\tres*=10;\n\treturn res;\n}\n\nbool isPrime(int n){\n\tfor(int i=2;i<n/2;i++)\n\t\tif(n%i==0)return false;\n\treturn true;\n}\n\nint main(){\n\tostringstream out;\n\n\tint n,m;\n\tcin >> n >> m;\n\tvector<int> boy;\n\tfor(int i=0;i<n;i++)\n\t\tboy.push_back(9);\n\n/*\n\tvector<bool> prime(pow10(m>=0?2*n+1:2*n));\n\tfor(int i=2;i<prime.size();i++){\n\t\tif(prime[i])continue;\n\t\tfor(int j=i*2;j<prime.size();j+=i)\n\t\t\tprime[j]=true;\n\t}\n*/\n/*\n\tfor(int i=0;i<prime.size();i++)\n\t\tcout << i << \" \"<<prime[i] << endl;\n\n\tif(true)\n\t\treturn 0;\n*/\n\n\twhile(true){\n\t\tvector<int>num;\n\t\tfor(int i=0;i<n;i++)\n\t\t\tnum.push_back(boy[i]);\n\t\tif(m>=0)\n\t\t\tnum.push_back(m);\n\t\tfor(int i=n-1;i>=0;i--)\n\t\t\tnum.push_back(boy[i]);\n\t\tint number=0;\n\t\tfor(int i=0;i<num.size();i++)\n\t\t\tnumber+=num[i]*pow10(num.size()-1-i);\n//\t\tif(!prime[number]){\n\t\tif(isPrime(number)){\n\t\t\tout << number << endl;\n\t\t\tbreak;\n\t\t}\n\n\t\tint i=boy.size()-1;\n\t\tfor(;i>=0;i--){\n\t\t\tif(boy[i]<0){\n\t\t\t\tboy[i]=9;\n\t\t\t\tif(i>0)\n\t\t\t\t\tboy[i-1]--;\n\t\t\t\tcontinue;\n\t\t\t}else{\n\t\t\t\tboy[i]--;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\n\t\tif(i<0||boy[i]==0){\n\t\t\tfor(int i=0;i<n;i++)\n\t\t\t\tout << 9;\n\t\t\tif(m>=0)\n\t\t\t\tout << m;\n\t\t\tfor(int i=0;i<n;i++)\n\t\t\t\tout << 9;\n\t\t\tout << endl;\n\t\t\tbreak;\n\t\t}\n\n\t}\n\n\tcout << out.str();\n\treturn 0;\n}", "accuracy": 0.8, "time_ms": 1840, "memory_kb": 1244, "score_of_the_acc": -1.0932, "final_rank": 20 }, { "submission_id": "aoj_0586_845043", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <set>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-9\n#define INF 2000000000\n#define sz(x) ((int)(x).size())\n#define fi first\n#define sec second\n#define SORT(x) sort((x).begin(),(x).end())\n#define all(x) (x).begin(),(x).end()\n#define EQ(a,b) (abs((a)-(b))<EPS)\nint n,c,t=0;\nstring itos(ll a)\n{\n\tstring s;\n\twhile(a>0)\n\t{\n\t\tint e=a%10ll;\n\t\ts+=e+'0';\n\t\ta/=10ll;\n\t}\n\treverse(s.begin(),s.end());\n\treturn s;\n}\nbool is_palindrome(ll p)\n{\n\tstring s=itos(p);\n\tif(s[n]!=(c+'0'))return false;\n\tfor(int i=0;i<((int)s.size())/2;i++)\n\t{\n\t\tif(s[i]!=s[s.size()-1-i])return false;\n\t}\n\treturn true;\n}\nbool is_prime(ll x)\n{\n\tfor(ll i=2;i*i<=x;i++)\n\t{\n\t\tif(x%i==0)return false;\n\t}\n\treturn true;\n}\nint main()\n{\n\tcin >> n >> c;\n\tif(c>=0)t=1;\n\tif(n==1&&c<0)\n\t{\n\t\tcout << 11 << endl;\n\t\treturn 0;\n\t}\n\tif(c<0)\n\t{\n\t\tfor(int i=0;i<2*n;i++)cout << 9;\n\t\tcout << endl;\n\t\treturn 0;\n\t}\n\tint mx=((int)pow(10,2*n+t))-1,mi=((int)pow(10,2*n+t-1));\n\tfor(int i=mx;i>=mi;i--)\n\t{\n\t\tif(!is_palindrome(i))continue;\n\t\tif(!is_prime(i))continue;\n\t\tcout << i << endl;\n\t\treturn 0;\n\t}\n\tcout << ((int)pow(10,2*n+t))-1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 1248, "score_of_the_acc": -0.1605, "final_rank": 10 }, { "submission_id": "aoj_0586_845041", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <set>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-9\n#define INF 2000000000\n#define sz(x) ((int)(x).size())\n#define fi first\n#define sec second\n#define SORT(x) sort((x).begin(),(x).end())\n#define all(x) (x).begin(),(x).end()\n#define EQ(a,b) (abs((a)-(b))<EPS)\nint n,c,t=0;\nstring itos(ll a)\n{\n\tstring s;\n\twhile(a>0)\n\t{\n\t\tint e=a%10ll;\n\t\ts+=e+'0';\n\t\ta/=10ll;\n\t}\n\treverse(s.begin(),s.end());\n\treturn s;\n}\n/*int rev(int k)\n{\n\tint res=0;\n\twhile(k>0)\n\t{\n\t\tres+=k%10;\n\t\tk/=10;\n\t\tres*=10;\n\t}\n\treturn res/10;\n}*/\nbool is_palindrome(ll p)\n{\n\tstring s=itos(p);\n\tif(s[n]!=(c+'0'))return false;\n\tfor(int i=0;i<((int)s.size())/2;i++)\n\t{\n\t\tif(s[i]!=s[s.size()-1-i])return false;\n\t}\n\treturn true;\n}\nbool is_prime(ll x)\n{\n\tfor(ll i=2;i*i<=x;i++)\n\t{\n\t\tif(x%i==0)return false;\n\t}\n\treturn true;\n}\nint main()\n{\n\tcin >> n >> c;\n\tif(c>=0)t=1;\n\tif(n==1&&c<0)\n\t{\n\t\tcout << 11 << endl;\n\t\treturn 0;\n\t}\n\tif(c<0)\n\t{\n\t\tfor(int i=0;i<2*n;i++)cout << 9;\n\t\tcout << endl;\n\t\treturn 0;\n\t}\n\tint mx=((int)pow(10,2*n+t))-1,mi=((int)pow(10,2*n+t-1));\n\tfor(int i=mx;i>=mi;i--)\n\t{\n\t\t//int v=i*100*mi+c*10*mi+rev(i);\n\t\tif(!is_palindrome(i))continue;\n\t\tif(!is_prime(i))continue;\n\t\tcout << i << endl;\n\t\treturn 0;\n\t}\n\t/*cout << ((int)pow(10,n))-1;\n\tcout << c;\n\tcout << ((int)pow(10,n))-1;*/\n\tcout << ((int)pow(10,2*n+t))-1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 1248, "score_of_the_acc": -0.1714, "final_rank": 11 }, { "submission_id": "aoj_0586_845035", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <complex>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <set>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n#define pu push\n#define pb push_back\n#define mp make_pair\n#define eps 1e-9\n#define INF 2000000000\n#define sz(x) ((int)(x).size())\n#define fi first\n#define sec second\n#define SORT(x) sort((x).begin(),(x).end())\n#define all(x) (x).begin(),(x).end()\n#define EQ(a,b) (abs((a)-(b))<EPS)\nint n,c,t=0;\nstring itos(int a)\n{\n\tstring s;\n\twhile(a>0)\n\t{\n\t\tint e=a%10;\n\t\ts+=e+'0';\n\t\ta/=10;\n\t}\n\treverse(s.begin(),s.end());\n\treturn s;\n}\nbool is_palindrome(int p)\n{\n\tstring s=itos(p);\n\tif(s[n]!=(c+'0'))return false;\n\tfor(int i=0;i<((int)s.size())/2;i++)\n\t{\n\t\tif(s[i]!=s[s.size()-1-i])return false;\n\t}\n\treturn true;\n}\nbool is_prime(int x)\n{\n\tfor(int i=2;i*i<=x;i++)\n\t{\n\t\tif(x%i==0)return false;\n\t}\n\treturn true;\n}\nint main()\n{\n\tcin >> n >> c;\n\tif(c>=0)t=1;\n\tif(n==1&&c<0)\n\t{\n\t\tcout << 11 << endl;\n\t\treturn 0;\n\t}\n\tif(c<0)\n\t{\n\t\tcout << ((int)pow(10,2*n+t))-1 << endl;\n\t\treturn 0;\n\t}\n\tint mx=((int)pow(10,2*n+t))-1,mi=(int)(pow(10,2*n+t-1));\n\tfor(int i=mx;i>=mi;i--)\n\t{\n\t\tif(!is_palindrome(i))continue;\n\t\tif(!is_prime(i))continue;\n\t\tcout << i << endl;\n\t\treturn 0;\n\t}\n\tcout << ((int)pow(10,2*n+t))-1 << endl;\n\treturn 0;\n}", "accuracy": 0.8, "time_ms": 140, "memory_kb": 1244, "score_of_the_acc": -0.1643, "final_rank": 19 } ]
aoj_0589_cpp
問題 3 ある工場では,各営業所から製品生産の注文を受けている. 前日の注文をまとめて,各製品の生産合計を求めたい. 入力ファイルの1行目には注文データの数 n が書いてあり, 続く n 行には製品名と注文数が空白で区切られて書いてある. 製品名は5文字以内の英大文字で書かれている. 注文データには同じ製品が含まれていることもあり,順序はバラバラである. この注文データの中に現れる同じ製品の注文数を合計し, 出力ファイルに製品名と合計を空白を区切り文字として出力しなさい. ただし,製品名に次の順序を付けて,その順で出力すること. 順序:文字の長さの小さい順に,同じ長さのときは,前から比べて 最初に異なる文字のアルファベット順とする. 入力データにおける製品数,注文数とその合計のどれも10 6 以下である. 出力ファイルにおいては, 出力の最後の行にも改行コードを入れること. 入出力例 入力例1 5 A 20 B 20 A 20 AB 10 Z 10 出力例1 A 40 B 20 Z 10 AB 10 入力例2 5 AAA 20 ABA 20 AAA 20 AAB 20 AAA 20 出力例2 AAA 60 AAB 20 ABA 20 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0589_3292445", "code_snippet": "#include<iostream>\n#include<string>\nusing namespace std;\n\nint main()\n{\n int n;\n\n cin >> n;\n\n string s[n];\n int p[n];\n\n for( int i = 0; i < n; i++ )\n cin >> s[i] >> p[i];\n\n for( int i = 0; i < n - 1; i++ ) //同じ製品をまとめる\n for( int j = i + 1; j < n; j++ )\n if( s[i] == s[j] )\n {\n s[j] = \"\";\n p[i] += p[j];\n p[j] = 0;\n }\n\n for( int i = 0; i < n - 1; i++ ) //文字数順に並べる。\n for( int j = i + 1; j < n; j++ )\n if( s[i].size() > s[j].size() )\n {\n string t1 = s[i];\n s[i] = s[j];\n s[j] = t1;\n \n int t2 = p[i];\n p[i] = p[j];\n p[j] = t2;\n }\n\n for( int i = 0; i < n - 1; i++ ) //辞書順に並べる。\n for( int j = i + 1; j < n; j++ )\n if( s[i].size() == s[j].size() && s[i] > s[j] )\n {\n string t1 = s[i];\n s[i] = s[j];\n s[j] = t1;\n \n int t2 = p[i];\n p[i] = p[j];\n p[j] = t2;\n }\n\n for( int i = 0; i < n; i++ )\n if( s[i] != \"\" )\n cout << s[i] << \" \" << p[i] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 3732, "score_of_the_acc": -1.0401, "final_rank": 19 }, { "submission_id": "aoj_0589_1630543", "code_snippet": "#include<iostream>\n#include<string>\n#include<cmath>\n#include<cstring>\nusing namespace std;\n\nint k[16000000];\nint n, a, z, cnt;\nstring S;\n\nint main() {\n\tmemset(k, 0, sizeof(k));\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> S;\n\t\tz = 0;\n\t\tfor (int j = 0; j < S.size(); j++) {\n\t\t\tz += (int)(S[j] - 'A' + 1)*pow(27, S.size() - j - 1);\n\t\t}\n\t\tcin >> a;\n\t\tk[z] += a;\n\t}\n\tfor (int i = 0; i < 16000000; i++) {\n\t\tif (k[i] >= 1) {\n\t\t\tfor (int j = 4; j >= 0; j--) {\n\t\t\t\tz = (int)(i / (int)pow(27, j)) % 27;\n\t\t\t\tif (z >= 1) {\n\t\t\t\t\tcout << (char)(z + 'A' - 1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << ' ';\n\t\t\tcout << k[i] << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 63748, "score_of_the_acc": -1.0149, "final_rank": 18 }, { "submission_id": "aoj_0589_1630542", "code_snippet": "#include<iostream>\n#include<string>\n#include<cmath>\n#include<cstring>\nusing namespace std;\n\nint k[16000000];\nint n, a, z, cnt;\nstring S;\n\nint main() {\n\tmemset(k, 0, sizeof(k));\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> S;\n\t\tz = 0;\n\t\tfor (int j = 0; j < S.size(); j++) {\n\t\t\tz += (int)(S[j] - 'A' + 1)*pow(27, S.size() - j - 1);\n\t\t}\n\t\tcin >> a;\n\t\tk[z] += a;\n\t}\n\tfor (int i = 0; i < 16000000; i++) {\n\t\tif (k[i] >= 1) {\n\t\t\tfor (int j = 4; j >= 0; j--) {\n\t\t\t\tz = (int)(i / (int)pow(27, j)) % 27;\n\t\t\t}\n\t\t\tif (z >= 1) {\n\t\t\t\tcout << (char)(z + 'A' - 1);\n\t\t\t}\n\t\t\tcout << ' ';\n\t\t\tcout << k[i] << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 10, "memory_kb": 63748, "score_of_the_acc": -1, "final_rank": 20 }, { "submission_id": "aoj_0589_1528021", "code_snippet": "#include <bits/stdc++.h>\n#define PB push_back\n#define MP make_pair\n#define REP(i,n) for (int i=0;i<(n);i++)\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define ALL(a) (a).begin(),(a).end()\n#define MOD 10000\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\nconst ull B=100000007;\nconst int INF=1e9;\nbool com(string l,string r){\n if(l.length()!=r.length())return l.length()<r.length();\n REP(i,l.length())if(l[i]!=r[i])return l[i]<r[i];\n}\nint main(){\n int n;\n map<string,int> M;\n cin>>n;\n vector<string> V;\n REP(i,n){\n string s;int a;\n cin>>s>>a;\n if(M[s]==0)V.PB(s);\n M[s]+=a;\n }\n sort(V.begin(),V.end(),com);\n REP(i,V.size()){\n cout<<V[i]<<\" \"<<M[V[i]]<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.0001, "final_rank": 7 }, { "submission_id": "aoj_0589_1224319", "code_snippet": "#include <cstdio>\n#include <stack>\n#include <iostream>\n#include <map>\n#include <string>\n\nusing namespace std;\n\nint main(){\n int n,b;\n map<string,int> mm[5];\n string a;\n \n \n scanf(\"%d\",&n);\n \n for(int i=0;i<n;i++){\n cin >> a >> b;\n \n if(mm[a.size()-1].find(a)==mm[a.size()-1].end()){\n mm[a.size()-1][a]=b;\n }else{\n mm[a.size()-1][a]+=b;\n }\n }\n \n for(int i=0;i<5;i++)\n for(map<string,int>::iterator it=mm[i].begin();it!=mm[i].end();it++){\n cout << it->first << \" \" << it->second << endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1272, "score_of_the_acc": -0.0008, "final_rank": 13 }, { "submission_id": "aoj_0589_1207599", "code_snippet": "/*\n これって模擬本戦...?\n */\n\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\n\nint n;\nmap<string, int> products;\nvector<string> names;\n\nbool cmp(const string &a, const string &b) {\n if (a.length() != b.length()) return a.length() < b.length();\n return a < b;\n}\n\nint main() {\n scanf(\"%d\", &n);\n for (int i=0; i<n; i++) {\n char buf[6];\n int num;\n string name;\n\n scanf(\" %s\", buf);\n scanf(\"%d\", &num);\n name = string(buf);\n\n if (products.find(name) != products.end()) {\n products[name] += num;\n } else {\n products[name] = num;\n }\n\n names.push_back(name);\n }\n\n sort(names.begin(), names.end(), cmp);\n names.erase(unique(names.begin(), names.end()), names.end());\n\n for (int i=0; i<names.size(); i++) {\n printf(\"%s %d\\n\", names[i].c_str(), products[names[i]]);\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1564, "score_of_the_acc": -0.0054, "final_rank": 16 }, { "submission_id": "aoj_0589_1161674", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <vector>\n#include <string>\n\nusing namespace std;\n\nbool comp(const string& key1, const string& key2)\n{\n if(key1.size() == key2.size()) {\n return key1 < key2;\n }\n return key1.size() < key2.size();\n}\n\nint main()\n{\n int n;\n cin >> n;\n\n string key;\n int value;\n map<string, int> products;\n vector<string> keys;\n\n for(int i = 0; i < n; i+= 1){\n cin >> key >> value;\n\n if(products.find(key) == products.end()) {\n products[key] = value;\n keys.push_back(key);\n } else {\n products[key] += value;\n }\n }\n\n sort(keys.begin(), keys.end(), comp);\n\n for(int i = 0; i < keys.size(); i += 1){\n cout << keys[i] << \" \" << products[keys[i]] << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": -0.0001, "final_rank": 4 }, { "submission_id": "aoj_0589_1158257", "code_snippet": "#include <string> \n#include <algorithm> \n#include <cfloat> \n#include <climits> \n#include <cmath> \n#include <complex> \n#include <cstdio> \n#include <cstdlib> \n#include <cstring> \n#include <functional> \n#include <iostream> \n#include <map> \n#include <memory> \n#include <queue> \n#include <set> \n#include <sstream> \n#include <stack> \n#include <utility> \n#include <vector> \n\n#define EACH(i,c) for(__typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define ALL(x) (x).begin(),(x).end() \ntypedef long long ll;\nusing namespace std; \nconst double eps = 1e-10;\n\nbool func(const string &a, const string &b){\n if(a.size() != b.size()) return a.size() < b.size();\n else return a < b;\n}\nint main(){\n int n;\n cin >> n;\n map<string, int> mp;\n vector<string> v;\n for(int i = 0; i<n; ++i){\n string s;\n int a;\n cin >> s >> a;\n if(mp.find(s) == mp.end()){\n v.push_back(s);\n }\n mp[s] += a;\n }\n sort(ALL(v), func);\n EACH(i, v) cout << *i << \" \" << mp[*i] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": -0.0001, "final_rank": 4 }, { "submission_id": "aoj_0589_1146376", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<map>\n#include<vector>\n#include<cmath>\n#include<cstdio>\n#define loop(i,a,b) for(int i=a;i<b;i++) \n#define rep(i,a) loop(i,0,a)\n#define pb(in,tmp) in.push_back(tmp)\n#define all(in) in.begin(),in.end()\n#define PI acos(-1)\nusing namespace std;\nint main(){\n map<int,map<string,int> >in;\n int n;\n cin>>n;\n rep(i,n){\n int tmp;\n string tmp1;\n cin>>tmp1>>tmp;\n in[tmp1.size()][tmp1]+=tmp;\n }\n map<int,map<string,int> >::iterator ite=in.begin();\n for(;ite!=in.end();ite++){\n map<string,int>::iterator it=in[ite->first].begin();\n for(;it!=in[ite->first].end();it++)\n cout<<it->first<<\" \"<<it->second<<endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1228, "score_of_the_acc": -0.0001, "final_rank": 4 }, { "submission_id": "aoj_0589_1124746", "code_snippet": "#include <iostream>\n#include <map>\n#include <cstring>\n#include <vector>\n#define rep(i,n) for(int i = 0; i < n; i++)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<string,int> P;\n\nmap<string, int> m;\nmap<string, int>::iterator it;\nvector<P> ans;\nint n;\n\nint main(){\n\tcin >> n;\n\trep(i,n){\n\t\tstring str;\n\t\tint cnt;\n\t\tcin >> str >> cnt;\n\t\tm[str] += cnt;\n\t}\n\tfor(int i = 1; i <= 5; i++){\n\t\tfor(it = m.begin(); it != m.end(); it++){\n\t\t\tif((*it).first.size() == i) ans.push_back(P((*it).first,(*it).second));\n\t\t}\n\t}\n\trep(i,ans.size()){\n\t\tcout << ans[i].first << \" \" << ans[i].second << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.0001, "final_rank": 7 }, { "submission_id": "aoj_0589_1044144", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <algorithm>\n\nusing namespace std;\n\n#define rep(i,j) REP((i), 0, (j))\n#define REP(i,j,k) for(int i=(j);(i)<(k);++i)\n#define BW(a,x,b) ((a)<=(x)&&(x)<=(b))\n#define ALL(v) (v).begin(), (v).end()\n#define LENGTHOF(x) (sizeof(x) / sizeof(*(x)))\n#define AFILL(a, b) fill((int*)a, (int*)(a + LENGTHOF(a)), b)\n#define MP make_pair\n#define PB push_back\n#define F first\n#define S second\n#define INF 1 << 30\n#define EPS 1e-10\n\ntypedef pair<int, int> pi;\ntypedef pair<int, pi> pii;\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef long long ll;\n\nint n, a;\nstring s;\n\nbool cmp(const pair<string, int> &a, const pair<string, int> &b){\n if(a.F.size() != b.F.size()) return a.F.size() < b.F.size();\n return a.F < b.F;\n}\n\nint main(){\n scanf(\"%d\", &n);\n vector<pair<string, int> >v;\n rep(i, n){\n cin >> s >> a;\n int p = 0;\n while(v.size() > p){\n if(v[p].F == s){ v[p].S += a; break; }\n p++;\n }\n if(v.size() == p) v.PB(MP(s, a));\n }\n sort(v.begin(), v.end(), cmp);\n\n rep(i, v.size()) cout << v[i].F << ' ' << v[i].S << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1272, "score_of_the_acc": -0.0008, "final_rank": 13 }, { "submission_id": "aoj_0589_946788", "code_snippet": "#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <deque>\n#include <stack>\n#include <bitset>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <ctime>\n#include <cstring>\n\n#define ll long long\n#define ull unsigned long long\n#define pii pair<int,int>\n#define vi vector<int>\n#define VS vector<string>\n#define all(x) x.begin(),x.end()\n#define mp make_pair\n#define pb push_back\n\nusing namespace std;\n\nbool pairCompare(const std::pair<string, int>& firstElem, const std::pair<string, int>& secondElem) {\n if(firstElem.second != secondElem.second){\n return firstElem.second > secondElem.second;\n }else{\n if(firstElem.first.size() != secondElem.first.size()){\n return firstElem.first.size() < secondElem.first.size();\n }\n else\n return firstElem.first < secondElem.first;\n }\n}\n\nint main(){\n int n;\n map<string, int> m;\n int stringSize = 0;\n\n cin >> n;\n for(int i=0; i < n; i++){\n string s; int p;\n cin >> s >> p;\n stringSize = max(stringSize, (int)s.size());\n m[s] += p;\n }\n\n for(int i=0; i <= stringSize; i++){\n map<string, int>::iterator it = m.begin();\n while(it != m.end()){\n if(i == (*it).first.size())\n cout << (*it).first << \" \" << (*it).second << endl;\n ++it;\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0589_942750", "code_snippet": "#include <iostream>\n#include <complex>\n#include <sstream>\n#include <string>\n#include <algorithm>\n#include <deque>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <vector>\n#include <set>\n#include <limits>\n#include <cstdio>\n#include <cctype>\n#include <cmath>\n#include <cstring>\n#include <cstdlib>\n#include <ctime>\nusing namespace std;\n#define REP(i, j) for(int i = 0; i < (int)(j); ++i)\n#define FOR(i, j, k) for(int i = (int)(j); i < (int)(k); ++i)\n#define P pair<string, int>\n#define SORT(v) sort((v).begin(), (v).end())\n#define REVERSE(v) reverse((v).begin(), (v).end())\n\nclass C{\n public:\n string first;\n int second;\n C(string _f, int _s){ first = _f; second = _s; }\n C(){}\n bool operator < (const C &c) const {\n if (first.length() < c.first.length()) return true;\n if (first.length() > c.first.length()) return false;\n return first < c.first;\n }\n};\n\nint main() {\n int N; cin >>N;\n map<string, int> m;\n REP(i, N){\n string s;\n int num;\n cin >>s >>num;\n m[s] += num;\n }\n vector<C> v;\n for(map<string, int>::iterator it = m.begin(); it != m.end(); ++it) v.push_back( C(it->first, it->second) );\n SORT(v);\n REP(i, v.size()) cout <<v[i].first <<\" \" <<v[i].second <<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1236, "score_of_the_acc": -0.0002, "final_rank": 11 }, { "submission_id": "aoj_0589_922626", "code_snippet": "#include<iostream>\n#include<string>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint main(){\n int n;\n cin >> n;\n int num[n],pos = 0;\n string s[n];\n for(int t=0;t<n;t++){\n cin >> s[pos] >> num[pos];\n pos++;\n for(int tt=0;tt<pos-1;tt++){\n //cout << s[tt] << \" \" << s[pos-1] << endl;\n if(s[tt] == s[pos-1]){ \n\tnum[tt] += num[pos-1];\n\tpos--;\n\tbreak;\n }\n }\n\n }\n\n for(int i=0;i<pos;i++){\n for(int j=pos-1;j>i;j--){\n if(s[j].size()<s[j-1].size() || (s[j].size()==s[j-1].size() && s[j]<s[j-1])){\n\tswap(s[j],s[j-1]);\n\tswap(num[j],num[j-1]);\n }\n }\n }\n \n for(int i=0;i<pos;i++){\n cout << s[i] << \" \" << num[i] << endl;\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1296, "score_of_the_acc": -0.0012, "final_rank": 15 }, { "submission_id": "aoj_0589_841011", "code_snippet": "#include <iostream>\n#include <string>\n#include <map>\n\nusing namespace std;\ntypedef pair<int, string> p;\n\nvoid solve()\n{\n\tint n;\n\twhile(cin >> n)\n\t{\n\t\tmap<p, int> list;\n\t\tfor(int i = 0; i < n; ++i)\n\t\t{\n\t\t\tstring product;\n\t\t\tcin >> product;\n\t\t\tint num;\n\t\t\tcin >> num;\n\t\t\tlist[p(product.size(), product)] += num;\n\t\t}\n\t\tmap<p, int>::iterator it = list.begin();\n\t\twhile(it != list.end())\n\t\t{\n\t\t\tcout << it->first.second << \" \" << it->second << endl;\n\t\t\t++it;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tsolve();\n\treturn(0);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0589_800456", "code_snippet": "#include<iostream>\n#include<string>\n#include<map>\nusing namespace std;\nint main(){\n int n,ss,max=0;\n cin >> n;\n string s;\n map<string,int> m;\n map<string,int>::iterator p;\n for(int i=0;i<n;i++){\n cin >> s >> ss;\n m[s] += ss;\n if(s.size()>max) max = s.size();\n }\n for(int i=1;i<=max;i++){\n for(p=m.begin();p!=m.end();p++){\n if(p->first.size()==i) cout << p->first << ' ' << p->second << endl; \n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1224, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0589_771434", "code_snippet": "/* AOJ 0589 Production */\n\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <map>\n#include <vector>\n\nusing namespace std;\n\nbool compare_product_name(string a, string b);\nvoid map_test();\n\ntypedef bool (*pname_comparator)(string, string);\ntypedef map<string, int, pname_comparator> mapp;\n\nint\nmain()\n{\n int n;\n mapp production(compare_product_name);\n mapp::iterator it;\n\n cin >> n;\n cin.ignore();\n while (n--) {\n string line, name;\n int p;\n int delim_pos;\n\n getline(cin, line);\n\n delim_pos = line.find_first_of(' ');\n name = line.substr(0, delim_pos);\n p = atoi(line.substr(delim_pos + 1).data());\n\n if (production.find(name) == production.end())\n production[name] = p;\n else\n production[name] += p;\n }\n\n for (it = production.begin(); it != production.end(); ++it)\n cout << it->first << ' ' << it->second << endl;\n\n return 0;\n}\n\nbool\ncompare_product_name(string a, string b)\n{\n size_t len_a = a.size();\n size_t len_b = b.size();\n size_t min_len = min(len_a, len_b);\n size_t i;\n\n if (len_a != len_b)\n return len_a < len_b;\n\n for (i = 0; i < min_len; i++) {\n if (a[i] != b[i])\n return a[i] < b[i];\n }\n\n // a == b なので a < b ではない\n return false;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 1236, "score_of_the_acc": -0.0151, "final_rank": 17 }, { "submission_id": "aoj_0589_620500", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <map>\n#include <vector>\nusing namespace std;\nint n;\nmap<string,int> m;\nvector<pair<pair<int,string>,int> > v;\nint main(void){\n cin >> n;\n for(int i = 0; i < n; i++){\n string s;\n int a;\n cin >> s >> a;\n if(m.find(s) == m.end()){\n m[s] = v.size();\n v.push_back(make_pair(make_pair(s.size(),s),-a));\n }else{\n v[m[s]].second -= a;\n }\n }\n sort(v.begin(),v.end());\n for(int i = 0; i < (int)v.size(); i++){\n cout << v[i].first.second << \" \" << -v[i].second << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.0001, "final_rank": 7 }, { "submission_id": "aoj_0589_612172", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <map>\n#include <utility>\n#include <iterator>\nusing namespace std;\n\nint main() {\n int N; cin >> N;\n map<string, int> dict;\n while(N--) {\n string s; int x; cin >> s >> x;\n dict[s] += x;\n }\n vector<pair<string, int> > v;\n for(auto it : dict) {\n v.push_back(it);\n }\n sort(begin(v), end(v), [](pair<string, int> a, pair<string, int> b) {\n if(a.first.length() != b.first.length()) return a.first.length() < b.first.length();\n else return a.first < b.first;\n });\n for(auto it : v) {\n cout << it.first << ' ' << it.second << endl;\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1240, "score_of_the_acc": -0.0003, "final_rank": 12 }, { "submission_id": "aoj_0589_593686", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nstruct Product{\n\tstd::string name;\n\tint amount;\n};\n\nint main(){\n\tstd::vector<Product> v;\n\n\tint n;\n\tstd::cin >> n;\n\tfor(int i=0;i<n;i++){\n\t\tstd::string name;\n\t\tint amount;\n\t\tstd::cin >> name >> amount;\n\t\tauto it = std::find_if(v.begin(), v.end(), [&name](Product p){\n\t\t\t\t\treturn p.name == name;\n\t\t\t});\n\t\tif(it == v.end()){\n\t\t\tv.push_back({name, amount});\n\t\t}else{\n\t\t\tit->amount += amount;\n\t\t}\n\t}\n\n\tstd::sort(v.begin(), v.end(), [](Product lp, Product rp){\n\t\t\tif(lp.name.size() != rp.name.size())return lp.name.size() < rp.name.size();\n\t\t\tfor(int i=0;i<lp.name.size();i++){\n\t\t\t\tif(lp.name[i] != rp.name[i])return lp.name[i] < rp.name[i];\n\t\t\t}\n\t\t});\n\n\tfor(auto p : v){\n\t\tstd::cout << p.name << \" \" << p.amount << std::endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1232, "score_of_the_acc": -0.0001, "final_rank": 7 } ]
aoj_0597_cpp
問題 6: 小籠包 (Xiao Long Bao) 問題 JOI 君はお昼ごはんに,中華料理屋で小籠包を食べることにした. 小籠包とは,具と熱いスープを小麦粉の皮で包んだ料理であり,食べるときにスープが周囲に飛び散ることで知られている. JOI 君が注文した小籠包のセットは,具やスープの異なる N 個の小籠包からなる. N 個の小籠包は等間隔に一列に並んでおり,順番に 1 から N の番号がつけられている. i 番目の小籠包と j 番目の小籠包の間の距離は絶対値 |i - j| である. JOI 君は小籠包をある順番で食べていく. 最初,すべての小籠包のおいしさは 0 である. i 番目の小籠包を食べると,周囲にその汁が飛び散り,まだ食べられていない小籠包のうち,小籠包 i からの距離が D i 以下の小籠包に汁がかかる.汁がかかった小籠包はおいしさが A i 増える.すなわち, i 番目の小籠包を食べたときに, j 番目の小籠包 (1 ≤ j ≤ N かつ i - D i ≤ j ≤ i + D i ) がまだ食べられずに残っているならば, j 番目の小籠包のおいしさが A i 増える. JOI 君は,食べる順番を工夫することで,食べる小籠包のおいしさの合計を最大化したい. もっとも良い順番で食べたときの,JOI 君が食べる小籠包のおいしさの合計を求めるプログラムを作成せよ. 入力 入力ファイルは 3 行からなる. 1 行目には 1 つの整数 N (1 ≤ N ≤ 100) が書かれている. 2 行目には, N 個の整数 D 1 , D 2 , ..., D N (0 ≤ D i ≤ 7) が空白を区切りとして書かれている. 3 行目には, N 個の整数 A 1 , A 2 , ..., A N (0 ≤ A i ≤ 1000) が空白を区切りとして書かれている. 出力 JOI 君が食べる小籠包のおいしさの合計の最大値を 1 行で出力せよ. 入出力例 入力例 1 5 1 0 1 1 2 0 2 6 3 4 出力例 1 20 入出力例 1 では,5 番目 → 3 番目 → 1 番目 → 2 番目 → 4 番目 の順番で食べると, おいしさの合計が 20 になる.合計が 20 を超えるような食べ方は存在しないので,これが最善である. 入力例 2 10 5 2 7 2 6 5 3 5 3 6 8 7 8 4 0 6 0 10 10 0 出力例 2 237 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0597_10846821", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n\n vector<int> d(n), a(n);\n for (int i = 0; i < n; i++) cin >> d[i];\n for (int i = 0; i < n; i++) cin >> a[i];\n\n vector<int> base = {0, 1, 2, 3, 4, 5, 6};\n vector<vector<int>> permutations;\n\n do {\n permutations.push_back(base);\n } while (next_permutation(base.begin(), base.end()));\n\n int states_count = permutations.size();\n vector<vector<int>> transitions(states_count, vector<int>(8));\n\n for (int i = 0; i < states_count; i++) {\n for (int j = 0; j < 8; j++) {\n vector<int> modified = permutations[i];\n for (int k = 0; k < 7; k++) {\n if (modified[k] >= j) modified[k]++;\n }\n\n vector<int> new_state;\n for (int k = 1; k < 8; k++) {\n int val = modified[k];\n if (val > modified[0]) val--;\n new_state.push_back(val);\n }\n\n auto it = lower_bound(permutations.begin(), permutations.end(), new_state);\n transitions[i][j] = distance(permutations.begin(), it);\n }\n }\n\n vector<vector<int>> dp(n + 1, vector<int>(states_count, 0));\n int result = 0;\n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < states_count; j++) {\n vector<int> position_map(8);\n for (int k = 0; k < 7; k++) {\n position_map[permutations[j][k]] = k;\n }\n\n int current_value = dp[i][j];\n for (int k = 0; k < 7; k++) {\n if (i - 7 + k >= 0 && 7 - k <= d[i]) {\n current_value += a[i];\n }\n }\n\n for (int k = 0; k < 8; k++) {\n int next_state = transitions[j][k];\n int new_value = current_value;\n\n dp[i + 1][next_state] = max(dp[i + 1][next_state], new_value);\n result = max(result, dp[i + 1][next_state]);\n\n if (i - 7 + position_map[k] >= 0 && 7 - position_map[k] <= d[i]) {\n current_value -= a[i];\n }\n if (i - 7 + position_map[k] >= 0 && 7 - position_map[k] <= d[i - 7 + position_map[k]]) {\n current_value += a[i - 7 + position_map[k]];\n }\n }\n }\n }\n\n cout << result << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5620, "score_of_the_acc": -0.0334, "final_rank": 2 }, { "submission_id": "aoj_0597_10846811", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint n;\nint d[101], a[101];\nint dp[101][6000];\nint data_table[6000][8];\nvector<vector<int>> orders;\n\nint main() {\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", &d[i]);\n for (int i = 0; i < n; i++) scanf(\"%d\", &a[i]);\n \n vector<int> init = {0, 1, 2, 3, 4, 5, 6};\n do {\n orders.push_back(init);\n } while (next_permutation(init.begin(), init.end()));\n \n int total_orders = orders.size();\n for (int i = 0; i < total_orders; i++) {\n for (int j = 0; j < 8; j++) {\n vector<int> temp = orders[i];\n for (int k = 0; k < 7; k++) {\n if (temp[k] >= j) temp[k]++;\n }\n vector<int> new_order;\n for (int k = 1; k < 8; k++) {\n new_order.push_back(temp[k]);\n if (new_order.back() > temp[0]) new_order.back()--;\n }\n auto it = lower_bound(orders.begin(), orders.end(), new_order);\n data_table[i][j] = it - orders.begin();\n }\n }\n \n int ans = 0;\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < total_orders; j++) {\n int pos_map[8];\n for (int k = 0; k < 7; k++) {\n pos_map[orders[j][k]] = k;\n }\n \n int res = dp[i][j];\n for (int k = 0; k < 7; k++) {\n if (i - 7 + k >= 0 && 7 - k <= d[i]) {\n res += a[i];\n }\n }\n \n for (int k = 0; k < 8; k++) {\n int next_state = data_table[j][k];\n dp[i+1][next_state] = max(dp[i+1][next_state], res);\n ans = max(ans, dp[i+1][next_state]);\n \n if (i - 7 + pos_map[k] >= 0 && 7 - pos_map[k] <= d[i]) {\n res -= a[i];\n }\n if (i - 7 + pos_map[k] >= 0 && 7 - pos_map[k] <= d[i - 7 + pos_map[k]]) {\n res += a[i - 7 + pos_map[k]];\n }\n }\n }\n }\n \n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5604, "score_of_the_acc": -0.0331, "final_rank": 1 }, { "submission_id": "aoj_0597_10647832", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nstruct Info{\n\tint range,add;\n};\n\nint N;\nint table_index,max_digit;\nint num_array[7],xiao[7],work[8],order[7],calc[7];\nint table[5040][7];\nint dp[100][5040];\nbool used[7];\nInfo info[100];\nmap<int,int>MAP;\n\n//num_arrayとusedはグローバルに持つ\nvoid makeTable(int index){\n\n\tif(index == max_digit){\n\t\tint tmp = 0;\n\t\tfor(int i = 0; i < max_digit; i++){\n\t\t\ttable[table_index][i] = num_array[i];\n\t\t\ttmp = 10*tmp+num_array[i];\n\t\t}\n\t\tMAP[tmp] = table_index;\n\t\ttable_index++;\n\t\treturn;\n\t}\n\tfor(int i = 0; i < max_digit; i++){\n\t\tif(used[i] == false){\n\t\t\tnum_array[index] = i;\n\t\t\tused[i] = true;\n\t\t\tmakeTable(index+1);\n\t\t\tused[i] = false;\n\t\t}\n\t}\n}\n\nint main(){\n\n\tscanf(\"%d\",&N);\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d\",&info[i].range);\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%d\",&info[i].add);\n\t}\n\n\t//順列テーブルを作成する\n\ttable_index = 0;\n\tmax_digit = min(7,N);\n\n\tfor(int i = 0; i < max_digit; i++)used[i] = false;\n\tmakeTable(0);\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int state = 0; state < table_index; state++)dp[i][state] = 0;\n\t}\n\n\tint next_state,next_value,index,tmp_num;\n\n\t//左端の計算\n\tfor(int state = 0; state < table_index; state++){\n\n\t\tfor(int k = 0; k < max_digit; k++)order[k] = table[state][k]; //順番の取得\n\t\t//小籠包を順番に並べる\n\t\tfor(int a = 0; a < max_digit; a++){\n\t\t\twork[a] = order[a];\n\t\t}\n\t\tnext_value = 0;\n\t\tfor(int a = 0; a < max_digit-1; a++){ //汁を飛び散らせる小籠包のループ\n\t\t\tfor(int b = a+1; b < max_digit; b++){ //汁を浴びる小籠包のループ\n\t\t\t\tif(abs(work[a]-work[b]) <= info[work[a]].range){\n\t\t\t\t\tnext_value += info[work[a]].add;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdp[max_digit-1][state] = next_value;\n\t\tif(next_value == 0){\n\t\t\tprintf(\"state:%d\\n\",state);\n\t\t}\n\t}\n\n\tif(N <= 7){\n\n\t\tint ans = 0;\n\t\tfor(int state = 0; state < table_index; state++){\n\t\t\tans = max(ans,dp[max_digit-1][state]);\n\t\t}\n\n\t\tprintf(\"%d\\n\",ans);\n\n\t\treturn 0;\n\t}\n\n\tfor(int loc = 7; loc <= N-1; loc++){\n\n\t\tfor(int k = 0; k < 7; k++)xiao[k] = loc-(7-k); //作業量配列で扱う小籠包のインデックス\n\n\t\tfor(int state = 0; state < 5040; state++){ //左7個の状態の走査\n\n\t\t\tfor(int k = 0; k < 7; k++)order[k] = table[state][k]; //順番の取得\n\n\t\t\t//★locの小籠包の、相対順位のループ\n\t\t\tfor(int pos = 0; pos <= 7; pos++){\n\t\t\t\t//小籠包を順番に並べる\n\t\t\t\tfor(int a = 0; a <= 7; a++)work[a] = -1;\n\t\t\t\twork[pos] = loc;\n\t\t\t\tindex = 0;\n\t\t\t\tfor(int a = 0; a <= 7; a++){\n\t\t\t\t\tif(work[a] == -1){\n\t\t\t\t\t\twork[a] = xiao[order[index++]];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t//おいしさの増加分を計算\n\t\t\t\tnext_value = dp[loc-1][state];\n\n\t\t\t\t//locの増加分(locより前に食べられた小籠包で、汁がlocにかかるものを求める)\n\t\t\t\tfor(int a = 0; a < pos; a++){\n\t\t\t\t\tif(abs(work[a]-loc) <= info[work[a]].range){\n\t\t\t\t\t\tnext_value += info[work[a]].add;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\t//locの汁が飛び散ることによる増加分\n\t\t\t\tfor(int a = pos+1; a <= 7; a++){\n\t\t\t\t\tif(abs(work[a]-loc) <= info[loc].range){\n\t\t\t\t\t\tnext_value += info[loc].add;\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\t//新しい状態を計算する(loc-7の小籠包を除いた順位を計算する)\n\t\t\t\tindex = 0;\n\n\t\t\t\tfor(int a = 0; a <= 7; a++){\n\t\t\t\t\tif(work[a] == loc-7)continue;\n\t\t\t\t\tcalc[index++] = 6-(loc-work[a]);\n\t\t\t\t}\n\t\t\t\ttmp_num = 0;\n\t\t\t\tfor(int i = 0; i < 7; i++)tmp_num = 10*tmp_num+calc[i];\n\n\t\t\t\tnext_state = MAP[tmp_num];\n\n\t\t\t\tdp[loc][next_state] = max(dp[loc][next_state],next_value);\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 0;\n\tfor(int state = 0; state < 5040; state++){\n\t\tans = max(ans,dp[N-1][state]);\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 5656, "score_of_the_acc": -0.0939, "final_rank": 5 }, { "submission_id": "aoj_0597_9668498", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\nint main(){\n int N;cin>>N;\n vector<int>P={0,1,2,3,4,5,6},A(N),D(N);\n vector<vector<int>>perm;\n do{\n perm.emplace_back(P);\n }while(next_permutation(ALL(P)));\n for(int i=0;i<N;i++)cin>>D[i];\n for(int i=0;i<N;i++)cin>>A[i];\n vector<vector<int>>DP(N,vector<int>(5040));\n FOR(i,1,N)REP(j,5040){\n REP(k,8){\n auto P=perm[j];\n int score=DP[i-1][j];\n for(int l=0;l<k;l++)if(i-1-P[l]>=0&&D[i-1-P[l]]>=1+P[l])score+=A[i-1-P[l]];\n for(int l=k;l<7;l++)if(i-1-P[l]>=0&&1+P[l]<=D[i])score+=A[i];\n P.insert(P.begin()+k,-1);\n P.erase(find(ALL(P),6));\n for(auto&c:P)c++;\n int t=lower_bound(ALL(perm),P)-perm.begin();\n DP[i][t]=max(DP[i][t],score);\n }\n }\n cout<<*max_element(ALL(DP[N-1]))<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 5452, "score_of_the_acc": -0.1359, "final_rank": 6 }, { "submission_id": "aoj_0597_6741035", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<queue>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<stack>\n#include<string>\n#include<algorithm>\n#include<functional>\n#include<cstring>\n#include<complex>\n#include<bitset>\n#include<iostream>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> Q;\ntypedef complex<double> C;\n#define cx real()\n#define cy imag()\nconst ll INF = 1LL << 60;\nconst double DINF = 1e30;\nconst ll mod = 1000000007;\nconst ll dx[4] = {1, 0, -1, 0};\nconst ll dy[4] = {0, -1, 0, 1};\nconst C I = C(0, 1);\nconst double EPS = 1e-10;\nconst ll NCK_MAX = 510000;\n\nll gcd(ll a, ll b) {\n if (b == 0) return a;\n return gcd(b, a % b);\n}\n\nll extgcd(ll a, ll b, ll& x, ll& y) {\n if (b == 0) {\n x = 1, y = 0; return a;\n }\n ll q = a/b, g = extgcd(b, a - q*b, x, y);\n ll z = x - q * y;\n x = y;\n y = z;\n return g;\n}\n\nll invmod (ll a, ll m) { // a^-1 mod m\n ll x, y;\n extgcd(a, m, x, y);\n x %= m;\n if (x < 0) x += m;\n return x;\n}\n\nll *fac, *finv, *inv;\n\nvoid nCk_init(ll mod) {\n fac = new ll[NCK_MAX];\n finv = new ll[NCK_MAX];\n inv = new ll[NCK_MAX];\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (ll i = 2; i < NCK_MAX; i++) {\n fac[i] = fac[i-1] * i % mod;\n inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n finv[i] = finv[i-1] * inv[i] % mod;\n }\n}\n\nll nCk(ll n, ll k, ll mod) {\n if (fac == NULL) nCk_init(mod);\n if (n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % mod) % mod;\n}\n\ntemplate <typename T>\nclass Zip {\n vector<T> d;\n bool flag;\n void init() {\n sort(d.begin(), d.end());\n d.erase(unique(d.begin(), d.end()), d.end());\n flag = false;\n }\npublic:\n Zip() {\n flag = false;\n }\n void add(T x) {\n d.push_back(x);\n flag = true;\n }\n ll getNum(T x) {\n if (flag) init();\n return lower_bound(d.begin(), d.end(), x) - d.begin();\n }\n ll size() {\n if (flag) init();\n return (ll)d.size();\n }\n};\n\nclass UnionFind {\n vector<ll> par, rank; // par > 0: number, par < 0: -par\npublic:\n UnionFind(ll n) : par(n, 1), rank(n, 0) {}\n ll getSize(ll x) {\n return par[find(x)];\n }\n ll find(ll x) {\n if (par[x] > 0) return x;\n return -(par[x] = -find(-par[x]));\n }\n void merge(ll x, ll y) {\n x = find(x);\n y = find(y);\n if (x == y) return;\n if (rank[x] < rank[y]) {\n par[y] += par[x];\n par[x] = -y;\n } else {\n par[x] += par[y];\n par[y] = -x;\n if (rank[x] == rank[y]) rank[x]++;\n }\n }\n bool isSame(ll x, ll y) {\n return find(x) == find(y);\n }\n};\n\n\ntemplate <typename T>\nclass SegmentTree {\n ll n;\n vector<T> node;\n function<T(T, T)> fun, fun2;\n bool customChange;\n T outValue, initValue;\npublic:\n void init(ll num, function<T(T, T)> resultFunction, T init, T out, function<T(T, T)> changeFunction = NULL) {\n // changeFunction: (input, beforevalue) => newvalue\n fun = resultFunction;\n fun2 = changeFunction;\n customChange = changeFunction != NULL;\n n = 1;\n while (n < num) n *= 2;\n node.resize(2 * n - 1);\n fill(node.begin(), node.end(), init);\n outValue = out;\n initValue = init;\n }\n void valueChange(ll num, T value) {\n num += n-1;\n if (customChange) node[num] = fun2(value, node[num]);\n else node[num] = value;\n while (num > 0) num = (num - 1) / 2, node[num] = fun(node[num * 2 + 1], node[num * 2 + 2]);\n }\n T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n if (r == -1) r = n;\n if (a <= l && r <= b) return node[k];\n if (b <= l || r <= a) return outValue;\n ll mid = (l + r) / 2;\n return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n }\n};\n\ntemplate <typename T>\nclass Graph {\n struct edge { ll to; T cost; };\n struct edge_data { ll from, to; T cost; };\n\n ll v;\n vector<vector<edge>> e, re;\n vector<edge_data> ed;\n vector<bool> used;\n vector<ll> vs, cmp;\n bool isDirected, isMinasEdge;\npublic:\n Graph(ll _v, bool _isDirected = true, ll range_add = 0) {\n // range_add 0:no / 1:in / 2:out / 3:in+out\n //_v++;\n v = _v, isDirected = _isDirected; isMinasEdge = false;\n e.resize(v), re.resize(v);\n }\n void add_edge(ll s, ll t, T cost = 1) {\n e[s].push_back((edge){t, cost});\n if (!isDirected) e[t].push_back((edge){s, cost});\n else re[t].push_back((edge){s, cost});\n ed.push_back((edge_data){s, t, cost});\n if (cost < 0) isMinasEdge = true;\n }\n vector<T> dijkstra(ll s) {\n vector<T> d(v, INF);\n d[s] = 0;\n auto edge_cmp = [](const edge& a, const edge& b) { return a.cost > b.cost; };\n priority_queue<edge, vector<edge>, decltype(edge_cmp)> pq(edge_cmp);\n pq.push((edge){s, 0});\n while (!pq.empty()) {\n edge temp = pq.top(); pq.pop();\n if (d[temp.to] < temp.cost) continue;\n for (const edge& next : e[temp.to]) {\n T cost = temp.cost + next.cost;\n if (d[next.to] > cost) {\n d[next.to] = cost;\n pq.push((edge){next.to, cost});\n }\n }\n }\n return d;\n }\n vector<T> bellmanford(ll s) {\n vector<T> d(v, INF);\n d[s] = 0;\n for (ll i = 0; i < v; i++) {\n for (const edge_data& temp : ed) {\n if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = d[temp.from] + temp.cost;\n if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = d[temp.to] + temp.cost;\n }\n }\n for (ll i = 0; i < v; i++) {\n for (const edge_data& temp : ed) {\n if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = -INF;\n if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = -INF;\n }\n }\n return d;\n }\n vector<T> shortest_path(ll s) {\n if (isMinasEdge) return bellmanford(s);\n else return dijkstra(s);\n }\n T kruskal() {\n // if (isDirected)\n UnionFind uf(v);\n auto edge_data_cmp = [](const edge_data& a, const edge_data& b) { return a.cost < b.cost; };\n sort(ed.begin(), ed.end(), edge_data_cmp);\n T ans = 0;\n for (const edge_data& temp : ed) {\n if (uf.isSame(temp.from, temp.to)) continue;\n uf.merge(temp.from, temp.to);\n ans += temp.cost;\n }\n return ans;\n }\n void scc_dfs(ll s) {\n used[s] = true;\n for (const edge& i : e[s]) if (!used[i.to]) scc_dfs(i.to);\n vs.push_back(s);\n }\n void scc_rdfs(ll s, ll k) {\n used[s] = true;\n cmp[s] = k;\n for (const edge& i : re[s]) if (!used[i.to]) scc_rdfs(i.to, k);\n }\n vector<ll> scc() {\n used.resize(v);\n fill(used.begin(), used.end(), false);\n cmp.resize(v);\n vs.clear();\n for (ll i = 0; i < v; i++) if (!used[i]) scc_dfs(i);\n used.resize(v);\n fill(used.begin(), used.end(), false);\n ll k = 0;\n for (ll i = vs.size() - 1; i >= 0; i--) if (!used[vs[i]]) scc_rdfs(vs[i], k++);\n return cmp;\n }\n};\n\nclass RollingHash {\n int base;\n vector<__int128> hash;\n vector<__int128> pw;\n const __int128 hashmod = (1ull << 61) - 1;\npublic:\n RollingHash(string s, int base = 10007) : base(base), hash(s.length()+1, 0), pw(s.length()+1, 1) {\n for (int i = 0; i < (int)s.length(); i++) {\n hash[i+1] = (hash[i] * base + s[i]) % hashmod;\n pw[i+1] = pw[i] * base % hashmod;\n }\n }\n ll get(ll a, ll b) { // [a, b)\n __int128 tmp = hashmod + hash[b] - hash[a] * pw[b-a] % hashmod;\n if (tmp >= hashmod) tmp -= hashmod;\n return (ll)tmp;\n }\n};\n\nll n, d[100], a[100];\n\nll conv_v_to_ll(vector<ll>& v) {\n ll res = 0;\n for (ll i : v) res = 10 * res + i;\n return res;\n}\nvector<ll> conv_ll_to_v(ll x, ll len) {\n vector<ll> res;\n for (ll i = 0; i < len; i++) res.push_back(x % 10), x /= 10;\n reverse(res.begin(), res.end());\n return res;\n}\nvector<ll> backup1(10), backup2(10), backup3(10);\n\nint main() {\n scanf(\"%lld\", &n);\n for (ll i = 0; i < n; i++) scanf(\"%lld\", &d[i]);\n for (ll i = 0; i < n; i++) scanf(\"%lld\", &a[i]);\n map<ll, ll> m;\n m[0] = 0;\n // [3, 2, 5, 4, 1, 6, 0] 高々7個前までの順番(0-indexed)\n for (ll i = 0; i < n; i++) {\n map<ll, ll> new_m;\n for (auto it = m.begin(); it != m.end(); it++) {\n // 今見ているものをborder番目に食べる(もともとborder以上+1)\n vector<ll> tmp = conv_ll_to_v(it->first, min(7LL, i));\n for (ll border = 0; border <= tmp.size(); border++) {\n ll old_cost = it->second;\n vector<ll> old(tmp.size());\n copy(tmp.begin(), tmp.end(), old.begin());\n for (ll k = 0; k < old.size(); k++) {\n ll minas = old.size() - k;\n if (old[k] >= border) {\n old[k]++;\n if (d[i] >= minas) { // iを先に食べるので汁がかかるか\n old_cost += a[i];\n }\n } else {\n if (d[i-minas] >= minas) { // kを先に食べるので汁がかかるか\n old_cost += a[i-minas];\n }\n }\n }\n copy(old.begin(), old.end(), backup1.begin());\n if (old.size() == 7) {\n ll first = old[0];\n for (ll i = 0; i < (ll)old.size()-1; i++) {\n swap(old[i], old[i+1]);\n }\n old[6] = border;\n for (ll i = 0; i < (ll)old.size(); i++) if (old[i] >= first) old[i]--;\n } else {\n old.push_back(border);\n }\n ll new_key = conv_v_to_ll(old);\n new_m[new_key] = max(new_m[new_key], old_cost);\n /*\n printf(\"%lld: \", i);\n for (ll l : old) printf(\"%lld \", l);\n printf(\"-> %lld\\n\", old_cost);\n fflush(stdout);\n */\n /*\n for (ll i = 0; i < old.size(); i++) if (i < 0 or 7 < i) printf(\"Error1\\n\");\n sort(old.begin(), old.end());\n for (ll i = 0; i < old.size()-1; i++) if (old[i] == old[i+1]) {\n printf(\"Error2\\n\");\n for (ll x : tmp) printf(\"%lld \", x); printf(\"\\n\");\n printf(\"+%lld\\n\", border);\n for (ll x : backup1) printf(\"%lld \", x); printf(\"\\n\");\n for (ll x : old) printf(\"%lld \", x); printf(\"\\n\");\n exit(0);\n }\n if (old.size() > 7) printf(\"Error3\\n\");\n */\n }\n }\n swap(new_m, m);\n }\n ll ans = 0;\n for (auto it = m.begin(); it != m.end(); it++) ans = max(ans, it->second);\n printf(\"%lld\\n\", ans);\n}", "accuracy": 1, "time_ms": 520, "memory_kb": 4124, "score_of_the_acc": -0.1361, "final_rank": 7 }, { "submission_id": "aoj_0597_6740817", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"Ofast\")\n#define _GLIBCXX_DEBUG\nusing namespace std;\nusing std::cout;\nusing std::cin;\nusing std::endl;\nusing ll=long long;\nusing ld=long double;\nll ILL=2167167167167167167;\nconst int INF=2100000000;\nconst ll mod=998244353;\n#define rep(i,a) for (ll i=0;i<a;i++)\n#define all(p) p.begin(),p.end()\ntemplate<class T> using _pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<class T> ll LB(vector<T> &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> ll UB(vector<T> &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();}\ntemplate<class T> bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;}\ntemplate<class T> bool chmax(T &a,const T &b){if(a<b){a=b;return 1;}else return 0;}\ntemplate<class T> void So(vector<T> &v) {sort(v.begin(),v.end());}\ntemplate<class T> void Sore(vector<T> &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});}\nvoid yneos(bool a){if(a) cout<<\"Yes\\n\"; else cout<<\"No\\n\";}\ntemplate<class T> void vec_out(vector<T> &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<\" \";cout<<p[i];}cout<<\"\\n\";}\n\n\nvoid solve();\n// oddloop\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\t\n\tint t=1;\n\t//cin>>t;\n\trep(i,t) solve();\n}\n\nvoid solve(){\n\tint N,M=5040,S=7;\n\tcin>>N;\n\tvector<int> D(N),A(N);\n\trep(i,N) cin>>D[i];\n\trep(i,N) cin>>A[i];\n\tvector<vector<int>> dp(N+1,vector<int>(M));\n\tvector<vector<int>> table(M,vector<int>(S));\n\trep(i,7) table[0][i]=i;\n\trep(i,M-1) table[i+1]=table[i],next_permutation(all(table[i+1]));\n\tauto f=[&](vector<int> &p)->int{\n\t\tvector<int> use(S);\n\t\tint X=M,ans=0;\n\t\trep(i,S){\n\t\t\tX/=(S-i);\n\t\t\trep(j,p[i]) if(use[j]==0) ans+=X;\n\t\t\tuse[p[i]]=1;\n\t\t}\n\t\treturn ans;\n\t};\n\trep(i,N) rep(j,M){\n\t\trep(k,S+1){\n\t\t\tvector<int> n_order;\n\t\t\tint ind,tmp=dp[i][j];\n\t\t\trep(l,k){\n\t\t\t\tind=i-1-table[j][l];\n\t\t\t\tif(ind>=0&&D[ind]+ind>=i) tmp+=A[ind];\n\t\t\t\tif(table[j][l]!=S-1) n_order.push_back(table[j][l]+1);\n\t\t\t}\n\t\t\tn_order.push_back(0);\n\t\t\tfor(int l=k;l<S;l++){\n\t\t\t\tind=i-1-table[j][l];\n\t\t\t\tif(ind>=0&&ind>=i-D[i]) tmp+=A[i];\n\t\t\t\tif(table[j][l]!=S-1) n_order.push_back(table[j][l]+1);\n\t\t\t}\n\t\t\tchmax(dp[i+1][f(n_order)],tmp);\n\t\t}\n\t}\n\tint ans=0;\n\trep(i,M) chmax(ans,dp[N][i]);\n\tcout<<ans<<\"\\n\";\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 5728, "score_of_the_acc": -0.1975, "final_rank": 9 }, { "submission_id": "aoj_0597_6062122", "code_snippet": "#pragma region Macros\n#pragma comment(linker, \"/stack:200000000\")\n#ifdef noimi\n#pragma GCC optimize(\"unroll-loops\")\n#endif\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2\")\n// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"Ofast\")\n\n#include <immintrin.h>\n\n#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <cfenv>\n#include <cfloat>\n#include <chrono>\n#include <cinttypes>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdint>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <fstream>\n#include <functional>\n#include <initializer_list>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <random>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <streambuf>\n#include <string>\n#include <tuple>\n#include <type_traits>\n#include <typeinfo>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n#define endl '\\n'\n#define ll long long\nusing ld = long double;\n#define rep2(i, a, b) for(ll i = (a); i <= (b); i++)\n#define rep3(i, a, b) for(ll i = (a); i >= (b); --i)\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define fore(i, a) for(auto &&i : a)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size) \\\n vector<type> name(size); \\\n IN(name)\n#define VEC2(type, name1, name2, size) \\\n vector<type> name1(size), name2(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i])\n#define VEC3(type, name1, name2, name3, size) \\\n vector<type> name1(size), name2(size), name3(size); \\\n for(int i = 0; i < size; i++) IN(name1[i], name2[i], name3[i])\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w) \\\n vector<vector<type>> name(h, vector<type>(w)); \\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define rall(c) rbegin(c), rend(c)\n#define SORT(v) sort(all(v))\n#define REV(v) reverse(all(v))\ntemplate <class T = ll, class S> T SUM(const S &v) { return accumulate(all(v), T(0)); }\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\nconstexpr pii dx4[4] = {pii{1, 0}, pii{0, 1}, pii{-1, 0}, pii{0, -1}};\nconstexpr pii dx8[8] = {{1, 0}, {1, 1}, {0, 1}, {-1, 1}, {-1, 0}, {-1, -1}, {0, -1}, {1, -1}};\nconst string YESNO[2] = {\"NO\", \"YES\"};\nconst string YesNo[2] = {\"No\", \"Yes\"};\nconst string yesno[2] = {\"no\", \"yes\"};\nconst string firstsecond[2] = {\"second\", \"first\"};\nconst string FirstSecond[2] = {\"Second\", \"First\"};\nconst string possiblestr[2] = {\"impossible\", \"possible\"};\nvoid YES(bool t = 1) { cout << YESNO[t] << endl; }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { cout << YesNo[t] << endl; }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { cout << yesno[t] << endl; }\nvoid no(bool t = 1) { yes(!t); }\nvoid first(bool t = 1) { cout << firstsecond[t] << endl; }\nvoid First(bool t = 1) { cout << FirstSecond[t] << endl; }\nvoid possible(bool t = 1) { cout << possiblestr[t] << endl; }\n\ntemplate <class T> using vc = vector<T>;\ntemplate <class T> using vvc = vector<vc<T>>;\ntemplate <class T> using vvvc = vector<vvc<T>>;\ntemplate <class T> using vvvvc = vector<vvvc<T>>;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...) \\\n int __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define LL(...) \\\n ll __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define STR(...) \\\n string __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define CHR(...) \\\n char __VA_ARGS__; \\\n IN(__VA_ARGS__)\n#define DBL(...) \\\n double __VA_ARGS__; \\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &...tail) {\n scan(head);\n IN(tail...);\n}\n\ntemplate <class T, class S> inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); }\ntemplate <class T, class S> inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); }\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\n\ntemplate <class T> T ceil(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? (x + y - 1) / y : x / y);\n}\n\ntemplate <class T> T floor(T x, T y) {\n assert(y >= 1);\n return (x > 0 ? x / y : (x + y - 1) / y);\n}\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\ntemplate <class T, class S> T POW(T x, S n, const ll &mod) {\n T res = 1;\n for(; n; n >>= 1, x = x * x % mod)\n if(n & 1) res = res * x % mod;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n UNIQUE(y);\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\ntemplate <class S> void fold_in(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void fold_in(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto e : a) v.emplace_back(e);\n fold_in(v, tail...);\n}\ntemplate <class S> void renumber(vector<S> &v) {}\ntemplate <typename Head, typename... Tail, class S> void renumber(vector<S> &v, Head &&a, Tail &&...tail) {\n for(auto &&e : a) e = lb(v, e);\n renumber(v, tail...);\n}\ntemplate <class S, class... Args> vector<S> zip(vector<S> &head, Args &&...args) {\n vector<S> v;\n fold_in(v, head, args...);\n sort(all(v)), v.erase(unique(all(v)), v.end());\n renumber(v, head, args...);\n return v;\n}\n\n// x in [l, r)\ntemplate <class T, class S> bool inc(const T &x, const S &l, const S &r) { return l <= x and x < r; }\n// (a, b) in [lx, rx) * [ly, ry)\ntemplate <class T, class S> bool inc(const pair<T, T> &x, const S &lx, const S &ly, const S &rx, const S &ry) { return inc(x.fi, lx, rx) && inc(x.se, ly, ry); }\n\nconstexpr ll ten(int n) { return n == 0 ? 1 : ten(n - 1) * 10; }\n// bit 演算系\nll pow2(int i) { return 1LL << i; }\nint topbit(signed t) { return t == 0 ? -1 : 31 - __builtin_clz(t); }\nint topbit(ll t) { return t == 0 ? -1 : 63 - __builtin_clzll(t); }\nint lowbit(signed a) { return a == 0 ? 32 : __builtin_ctz(a); }\nint lowbit(ll a) { return a == 0 ? 64 : __builtin_ctzll(a); }\n// int allbit(int n) { return (1 << n) - 1; }\nconstexpr ll allbit(int n) { return (1LL << n) - 1; }\n// int popcount(signed t) { return __builtin_popcount(t); }\n// int popcount(ll t) { return __builtin_popcountll(t); }\nint popcount(uint64_t t) { return __builtin_popcountll(t); }\nbool ispow2(int i) { return i && (i & -i) == i; }\n\nll rnd(ll l, ll r) { //[l, r)\n#ifdef noimi\n static mt19937_64 gen;\n#else\n static mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());\n#endif\n return uniform_int_distribution<ll>(l, r - 1)(gen);\n}\nll rnd(ll n) { return rnd(0, n); }\n\ntemplate <class t> void random_shuffle(vc<t> &a) { rep(i, si(a)) swap(a[i], a[rnd(0, i + 1)]); }\n\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n\ntemplate <class T, class S> pair<T, S> operator-(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi - y.fi, x.se - y.se); }\ntemplate <class T, class S> pair<T, S> operator+(const pair<T, S> &x, const pair<T, S> &y) { return pair<T, S>(x.fi + y.fi, x.se + y.se); }\ntemplate <class T> pair<T, T> operator&(const pair<T, T> &l, const pair<T, T> &r) { return pair<T, T>(max(l.fi, r.fi), min(l.se, r.se)); }\ntemplate <class T, class S> pair<T, S> operator+=(pair<T, S> &l, const pair<T, S> &r) { return l = l + r; }\ntemplate <class T, class S> pair<T, S> operator-=(pair<T, S> &l, const pair<T, S> &r) { return l = l - r; }\ntemplate <class T> bool intersect(const pair<T, T> &l, const pair<T, T> &r) { return (l.se < r.se ? r.fi < l.se : l.fi < r.se); }\n\ntemplate <class T> ll operator*(const pair<T, T> &x, const pair<T, T> &y) { return (ll)x.fi * y.fi + (ll)x.se * y.se; }\n\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n constexpr bool operator<(const edge<T> &rhs) const noexcept { return cost < rhs.cost; }\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\n\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return res;\n}\nGraph getTreeFromPar(int n, int margin = 1) {\n Graph res(n);\n for(int i = 1; i < n; i++) {\n int a;\n cin >> a;\n res[a - margin].emplace_back(i);\n }\n return res;\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return res;\n}\nvoid add(Graph &G, int x, int y) { G[x].eb(y), G[y].eb(x); }\ntemplate <class S, class T> void add(Wgraph<S> &G, int x, int y, T c) { G[x].eb(y, c), G[y].eb(x, c); }\n\n#define i128 __int128_t\n#define ull unsigned long long int\n#define TEST \\\n INT(testcases); \\\n while(testcases--)\ntemplate <class T> ostream &operator<<(ostream &os, const vector<T> &v) {\n for(auto it = begin(v); it != end(v); ++it) {\n if(it == begin(v))\n os << *it;\n else\n os << \" \" << *it;\n }\n return os;\n}\ntemplate <class T, class S> ostream &operator<<(ostream &os, const pair<T, S> &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\ntemplate <class S, class T> string to_string(pair<S, T> p) { return \"(\" + to_string(p.first) + \",\" + to_string(p.second) + \")\"; }\nstring to_string(string s) { return \"\\\"\" + s + \"\\\"\"; }\nstring to_string(char c) { return string(1, c); }\ntemplate <class T> string to_string(vector<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it) + (next(it) == s.end() ? \"\" : \", \");\n return res + \"}\";\n}\ntemplate <class T> string to_string(set<T> s) {\n string res = \"{\";\n for(auto it = s.begin(); it != s.end(); it++) res += to_string(*it), res += (next(it) == end(s) ? \"\" : \", \");\n return res + \"}\";\n}\n\n#ifdef noimi\nvoid dump() { cerr << endl; }\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {\n cerr << to_string(head) << \" \";\n dump(tail...);\n}\n#undef endl\n#define debug(x) \\\n cout << #x << \": \"; \\\n dump(x)\n#else\nvoid dump() {}\ntemplate <class Head, class... Tail> void dump(Head head, Tail... tail) {}\n#define debug(x)\n#endif\ntemplate <class T> void print(const T &a) { cout << a; }\nvoid OUT() { cout << endl; }\ntemplate <class Head, class... Tail> void OUT(const Head &head, const Tail &...tail) {\n print(head);\n if(sizeof...(tail)) cout << ' ';\n OUT(tail...);\n}\n\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\n#define drop(s) cout << #s << endl, exit(0)\n\ntemplate <int N> struct ndFORarray {\n std::array<int, N> v;\n ndFORarray(std::array<int, N> v_) : v(v_) {}\n struct ndFORitr {\n const std::array<int, N> &v;\n std::array<int, N> tmp;\n bool is_end;\n ndFORitr(const std::array<int, N> &v_) : v(v_), tmp(), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = N - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::array<int, N> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nstruct ndFORvector {\n std::vector<int> v;\n ndFORvector(std::vector<int> v_) : v(v_) {}\n struct ndFORitr {\n const std::vector<int> &v;\n std::vector<int> tmp;\n bool is_end;\n ndFORitr(const std::vector<int> &v_) : v(v_), tmp(v.size(), 0), is_end(false) {}\n bool operator!=(const ndFORitr &) const { return !is_end; }\n void operator++() {\n int pos = v.size() - 1;\n while(pos != -1) {\n tmp[pos] += 1;\n if(tmp[pos] == v[pos]) {\n tmp[pos] = 0;\n pos -= 1;\n } else {\n break;\n }\n }\n if(pos == -1) { is_end = true; }\n }\n const std::vector<int> &operator*() const { return tmp; }\n };\n ndFORitr begin() const { return ndFORitr(v); }\n ndFORitr end() const { return ndFORitr(v); }\n};\n\nauto ndFOR(std::vector<int> v) { return ndFORvector(v); }\ntemplate <class... Ts> auto ndFOR(Ts... v) { return ndFORarray<std::tuple_size<std::tuple<Ts...>>::value>({v...}); }\ntemplate <class F> struct REC {\n F f;\n REC(F &&f_) : f(std::forward<F>(f_)) {}\n template <class... Args> auto operator()(Args &&...args) const { return f(*this, std::forward<Args>(args)...); }\n};\n\ntemplate <class S> vector<pair<S, int>> runLength(const vector<S> &v) {\n vector<pair<S, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\nvector<pair<char, int>> runLength(const string &v) {\n vector<pair<char, int>> res;\n for(auto &e : v) {\n if(res.empty() or res.back().fi != e)\n res.eb(e, 1);\n else\n res.back().se++;\n }\n return res;\n}\n\ntemplate <class T = int> struct Imos {\n int n;\n vector<T> a;\n Imos(int _n) : n(_n), a(_n + 1) {}\n void add(int l, int r, T val = 1) {\n if(l >= r) return;\n l = clamp(l, 0, n);\n r = clamp(r, 0, n + 1);\n a[l] += val;\n if(r <= n) a[r] -= val;\n }\n void build() {\n for(int i = 0; i < n; i++) a[i + 1] += a[i];\n }\n const T &operator[](int k) { return a[k]; }\n};\n\ntemplate <class T> struct RUI {\n vector<T> a;\n RUI(const vector<T> &v) : a(v.size() + 1) {\n for(int i = 0; i < v.size(); i++) a[i + 1] = a[i] + v[i];\n }\n T get(int l, int r) { return a[r] - a[l]; }\n};\n\ntemplate <class T, class F> T bin_search(T ok, T ng, const F &f) {\n while(abs(ok - ng) > 1) {\n T mid = ok + ng >> 1;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\ntemplate <class T, class F> T bin_search_double(T ok, T ng, const F &f, int iter = 80) {\n while(iter--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(11);\n }\n} setup_io;\n\nconstexpr int oj_local(int oj, int local) {\n#ifdef noimi\n return local;\n#endif\n return oj;\n}\nconstexpr bool is_local = oj_local(0, 1);\n\n#pragma endregion\n\nconstexpr int m = 7;\nint ptoi(const vi &v) {\n int b = 0, res = 0;\n rep3(i, si(v) - 1, 0) {\n res = res * (m - i) + popcount(b & allbit(v[i]));\n b ^= 1 << v[i];\n }\n return res;\n}\n\nconstexpr int M() {\n int res = 1;\n rep2(i, 1, m) res *= i;\n return res;\n}\n\nint main() {\n INT(n);\n VEC(int, d, n);\n VEC(int, a, n);\n\n vv(int, ps, M());\n {\n auto id = iota(m);\n do { ps[ptoi(id)] = id; } while(next_permutation(all(id)));\n }\n\n if(n <= m) {\n int ma = 0;\n auto id = iota(n);\n do {\n int tmp = 0;\n rep(i, n) rep(j, n) {\n if(id[i] < id[j] and abs(i - j) <= d[i]) tmp += a[i];\n }\n chmax(ma, tmp);\n } while(next_permutation(all(id)));\n OUT(ma);\n } else {\n vv(int, dp, n + 1, M());\n {\n int i = 0;\n fore(id, ps) {\n int tmp = 0;\n rep(i, m) rep(j, m) {\n if(id[i] < id[j] and abs(i - j) <= d[i]) tmp += a[i];\n }\n dp[m][i++] = tmp;\n }\n }\n\n rep2(i, m, n - 1) {\n rep(j, si(ps)) {\n auto &v = ps[j];\n int tmp = dp[i][j];\n vi nxt(m);\n rep(k, m + 1) {\n int now = tmp;\n rep(s, m) {\n if(v[s] < k and (m - s) <= d[i - m + s])\n now += a[i - m + s];\n else if(v[s] >= k and (m - s) <= d[i])\n now += a[i];\n }\n int l = v[0];\n rep2(s, 1, m - 1) {\n int to = v[s];\n if(v[s] >= k) to++;\n if(v[s] > l) to--;\n nxt[s - 1] = to;\n }\n nxt[m - 1] = (k - (k > l));\n chmax(dp[i + 1][ptoi(nxt)], now);\n }\n }\n }\n OUT(MAX(dp[n]));\n }\n}\n\n// 1 4 6 5 2 3 0", "accuracy": 1, "time_ms": 120, "memory_kb": 5360, "score_of_the_acc": -0.0545, "final_rank": 4 }, { "submission_id": "aoj_0597_4822141", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nint main() {\n\tint N;\n\tcin >> N;\n\tvector<int> D(N), A(N);\n\tfor (int i = 0; i < N; ++i) cin >> D[i];\n\tfor (int i = 0; i < N; ++i) cin >> A[i];\n\tvector<vector<int> > perm;\n\tint md = *max_element(D.begin(), D.end());\n\tvector<int> p(md);\n\tfor (int i = 0; i < md; ++i) {\n\t\tp[i] = i;\n\t}\n\tdo {\n\t\tperm.push_back(p);\n\t} while (next_permutation(p.begin(), p.end()));\n\tfunction<int(vector<int>)> find_index = [&](vector<int> v) {\n\t\tvector<int> vp(v.size());\n\t\tfor (int i = 0; i < v.size(); ++i) {\n\t\t\tfor (int j = 0; j < v.size(); ++j) {\n\t\t\t\tif (v[j] < v[i] || (v[j] == v[i] && j < i)) ++vp[i];\n\t\t\t}\n\t\t}\n\t\treturn lower_bound(perm.begin(), perm.end(), vp) - perm.begin();\n\t};\n\tint ps = perm.size();\n\tvector<int> dp(ps);\n\tfor (int i = 0; i < N; ++i) {\n\t\tvector<int> ndp(ps);\n\t\tfor (int j = 0; j < ps; ++j) {\n\t\t\tvector<int> np = perm[j];\n\t\t\tnp.insert(np.begin(), -1);\n\t\t\tnp.pop_back();\n\t\t\tfor (int k = 0; k <= md; ++k) {\n\t\t\t\tint delta = 0;\n\t\t\t\tfor (int l = 1; l <= md && l <= i; ++l) {\n\t\t\t\t\tif (l <= D[i - l] && perm[j][l - 1] < k) {\n\t\t\t\t\t\tdelta += A[i - l];\n\t\t\t\t\t}\n\t\t\t\t\tif (l <= D[i] && perm[j][l - 1] >= k) {\n\t\t\t\t\t\tdelta += A[i];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tnp[0] = k;\n\t\t\t\tint idx = find_index(np);\n\t\t\t\tndp[idx] = max(ndp[idx], dp[j] + delta);\n\t\t\t}\n\t\t}\n\t\tdp = ndp;\n\t}\n\tint ans = *max_element(dp.begin(), dp.end());\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1030, "memory_kb": 3380, "score_of_the_acc": -0.2525, "final_rank": 10 }, { "submission_id": "aoj_0597_4472872", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <numeric>\n#include <vector>\n#include <map>\n\nconstexpr int INF = 1 << 30;\n\nstd::vector<int> facts;\nstd::map<std::vector<int>, int> encs;\nstd::vector<std::vector<int>> decs;\n\nvoid init() {\n facts.resize(9);\n facts[0] = 1;\n for (int i = 1; i <= 8; ++i) facts[i] = facts[i - 1] * i;\n\n decs.resize(facts[7]);\n std::vector<int> idxs(7);\n std::iota(idxs.begin(), idxs.end(), 0);\n int cnt = 0;\n do {\n decs[cnt] = idxs;\n encs[idxs] = cnt++;\n } while (std::next_permutation(idxs.begin(), idxs.end()));\n}\n\nint enc(std::vector<int> xs) {\n while (xs.size() < 7) xs.push_back(xs.size());\n return encs[xs];\n}\n\nstd::vector<int> compress(const std::vector<int>::iterator& begin,\n const std::vector<int>::iterator& end) {\n std::vector<int> idxs(begin, end);\n int n = idxs.size();\n\n std::vector<int> ret(n, 0);\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < n; ++j) {\n if (idxs[i] > idxs[j]) ++ret[i];\n }\n }\n return ret;\n}\n\nvoid solve() {\n int n;\n std::cin >> n;\n\n std::vector<int> ds(n), xs(n);\n for (auto& d : ds) std::cin >> d;\n for (auto& x : xs) std::cin >> x;\n\n std::vector<int> dp(facts[7], -INF);\n int r = std::min(7, n);\n // exhaustive search on [0, r)\n {\n std::vector<int> idxs(r);\n std::iota(idxs.begin(), idxs.end(), 0);\n do {\n int sum = 0;\n\n for (int i = 0; i < r; ++i) {\n for (int j = 0; j < r; ++j) {\n if (std::abs(i - j) > ds[i] ||\n idxs[i] >= idxs[j]) continue;\n sum += xs[i];\n }\n }\n\n dp[enc(idxs)] = sum;\n } while (std::next_permutation(idxs.begin(), idxs.end()));\n }\n\n auto ndp = dp;\n std::vector<int> idxs(8);\n std::iota(idxs.begin(), idxs.end(), 0);\n\n while (r < n) {\n std::fill(ndp.begin(), ndp.end(), -INF);\n\n do {\n int prev = enc(compress(idxs.begin(), --idxs.end()));\n int nxt = enc(compress(++idxs.begin(), idxs.end()));\n\n int sum = 0;\n for (int i = 0; i < 7; ++i) {\n int l = r - 7 + i;\n if (idxs[i] < idxs[7] && std::abs(r - l) <= ds[l]) sum += xs[l];\n if (idxs[i] > idxs[7] && std::abs(r - l) <= ds[r]) sum += xs[r];\n }\n\n ndp[nxt] = std::max(ndp[nxt], sum + dp[prev]);\n } while (std::next_permutation(idxs.begin(), idxs.end()));\n\n std::swap(dp, ndp);\n ++r;\n }\n\n std::cout << *std::max_element(dp.begin(), dp.end()) << \"\\n\";\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n init();\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 1660, "memory_kb": 4204, "score_of_the_acc": -0.4223, "final_rank": 12 }, { "submission_id": "aoj_0597_4117054", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\ntemplate <typename T> using posteriority_queue = priority_queue<T, vector<T>, greater<T> >;\nconst int INF = 0x3f3f3f3f;\nconst ll LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\n// const int dy[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\ntemplate <typename T> void unique(vector<T> &a) { a.erase(unique(ALL(a)), a.end()); }\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int n; cin >> n;\n vector<int> d(n), a(n);\n REP(i, n) cin >> d[i];\n REP(i, n) cin >> a[i];\n if (n <= 7) {\n vector<int> p(n);\n iota(ALL(p), 0);\n int ans = 0;\n do {\n int xiao = 0;\n vector<int> now(n, 0);\n REP(i, n) {\n xiao += now[p[i]];\n FOR(j, 1, d[p[i]] + 1) {\n if (p[i] + j < n) now[p[i] + j] += a[p[i]];\n if (p[i] - j >= 0) now[p[i] - j] += a[p[i]];\n }\n }\n chmax(ans, xiao);\n } while (next_permutation(ALL(p)));\n cout << ans << '\\n';\n return 0;\n }\n map<vector<int>, int> prv;\n vector<int> p(7);\n iota(ALL(p), 0);\n do {\n int xiao = 0;\n vector<int> now(7, 0);\n REP(i, 7) {\n xiao += now[p[i]];\n FOR(j, 1, d[p[i]] + 1) {\n if (p[i] + j < 7) now[p[i] + j] += a[p[i]];\n if (p[i] - j >= 0) now[p[i] - j] += a[p[i]];\n }\n }\n prv[p] = xiao;\n } while (next_permutation(ALL(p)));\n FOR(i, 7, n) {\n map<vector<int>, int> nxt;\n for (auto &pr : prv) {\n const vector<int> &v = pr.first;\n vector<int> enc(v);\n for (int &e : enc) e = i - (7 - e);\n REP(j, 8) {\n int xiao = 0;\n REP(k, j) if (d[enc[k]] >= 7 - v[k]) xiao += a[enc[k]];\n FOR(k, j, 7) if (d[i] >= 7 - v[k]) xiao += a[i];\n vector<int> nx_v(v);\n nx_v.emplace(nx_v.begin() + j, 7);\n nx_v.erase(find(ALL(nx_v), 0));\n for (int &e : nx_v) --e;\n chmax(nxt[nx_v], pr.second + xiao);\n }\n }\n swap(prv, nxt);\n }\n int ans = 0;\n for (auto &pr : prv) chmax(ans, pr.second);\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 4492, "score_of_the_acc": -0.1841, "final_rank": 8 }, { "submission_id": "aoj_0597_3480944", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n#define LL long long\n#define REP(i, n) for(int (i)=0; (i)<(n); (i)++)\n#define PB push_back\n#define MP make_pair\n#define MOD 1000000007\n\n//7!=5040\n//N=100\n\nint N;\nLL D[100],A[100];\n\nmap<pair<int,vector<int>>, vector<int>> dp2;\nvector<int> ins(vector<int> v, int p){\n\tif(dp2.count(MP(p,v)) == 1) return dp2[MP(p,v)];\n\n\t//if(v.size() == 7) cout << \"look\" << endl;\n\t//for(int k=0; k<v.size(); k++) cout << v[k] << \" \";\n\t//cout << endl;\n\n\tvector<int> memo = v;\n\n\tv.insert(v.begin()+p, 0);\n\tfor(int i=0; i<v.size(); i++){\n\t\tif(v[i] < 7) v[i]++;\n\t\telse{\n\t\t\tv.erase(v.begin()+i);\n\t\t\ti--;\n\t\t}\n\t}\n\n\t//for(int k=0; k<v.size(); k++) cout << v[k] << \" \";\n\t//cout << endl;\n\n\treturn dp2[MP(p,memo)] = v;\n}\n\nmap<pair<int,vector<int>>, LL> dp;\nLL solve(int now, vector<int> v){ //v[i]はi番目に食べるもの、値域1~7\n\tif(now == N) return 0;\n\tif(dp.count(MP(now,v)) == 1) return dp[MP(now,v)];\n\n\t//for(int k=0; k<v.size(); k++) cout << v[k] << \" \";\n\t//cout << endl;\n\n\tLL ans = 0;\n\tfor(int i=0; i<v.size()+1; i++){\n\t\tLL s = 0;\n\t\tfor(int j=0; j<i; j++){\n\t\t\tif(D[now-v[j]] >= v[j]){\n\t\t\t\ts += A[now-v[j]];\n\t\t\t}\n\t\t}\n\t\tfor(int j=i; j<v.size(); j++){\n\t\t\tif(D[now] >= v[j]){\n\t\t\t\ts += A[now];\n\t\t\t}\n\t\t}\n\t\ts += solve(now+1, ins(v,i));\n\t\tans = max(ans, s);\n\t}\n\treturn dp[MP(now,v)] = ans;\n}\n\nint main(){\n\tscanf(\"%d\", &N);\n\tfor(int i=0; i<N; i++) scanf(\"%lld\",D+i);\n\tfor(int i=0; i<N; i++) scanf(\"%lld\",A+i);\n\n\tvector<int> v;\n\tLL ans = solve(0,v);\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2720, "memory_kb": 70528, "score_of_the_acc": -1.675, "final_rank": 17 }, { "submission_id": "aoj_0597_3480892", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n#define LL long long\n#define REP(i, n) for(int (i)=0; (i)<(n); (i)++)\n#define PB push_back\n#define MP make_pair\n#define MOD 1000000007\n\n//7!=5040\n//N=100\n\nint N;\nLL D[100],A[100];\n\nmap<pair<int,vector<int>>, vector<int>> dp2;\nvector<int> ins(vector<int> v, int p){\n\tif(dp2.count(MP(p,v)) == 1) return dp2[MP(p,v)];\n\tv.insert(v.begin()+p, 0);\n\tfor(int i=0; i<v.size(); i++){\n\t\tif(v[i] < 7) v[i]++;\n\t\telse{\n\t\t\tv.erase(v.begin()+i);\n\t\t\ti--;\n\t\t}\n\t}\n\treturn dp2[MP(p,v)] = v;\n}\n\nmap<pair<int,vector<int>>, LL> dp;\nLL solve(int now, vector<int> v){ //v[i]はi番目に食べるもの、値域1~7\n\tif(now == N) return 0;\n\tif(dp.count(MP(now,v)) == 1) return dp[MP(now,v)];\n\tLL ans = 0;\n\tfor(int i=0; i<v.size()+1; i++){\n\t\tLL s = 0;\n\t\tfor(int j=0; j<i; j++){\n\t\t\tif(D[now-v[j]] >= v[j]){\n\t\t\t\ts += A[now-v[j]];\n\t\t\t}\n\t\t}\n\t\tfor(int j=i; j<v.size(); j++){\n\t\t\tif(D[now] >= v[j]){\n\t\t\t\ts += A[now];\n\t\t\t}\n\t\t}\n\t\ts += solve(now+1, ins(v,i));\n\t\tans = max(ans, s);\n\t}\n\treturn dp[MP(now,v)] = ans;\n}\n\nint main(){\n\tscanf(\"%d\", &N);\n\tfor(int i=0; i<N; i++) scanf(\"%lld\",D+i);\n\tfor(int i=0; i<N; i++) scanf(\"%lld\",A+i);\n\n\tvector<int> v;\n\tLL ans = solve(0,v);\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 3070, "memory_kb": 64052, "score_of_the_acc": -1.6661, "final_rank": 20 }, { "submission_id": "aoj_0597_3438590", "code_snippet": "#define _USE_MATH_DEFINES\n\n#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <cmath>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <map>\n#include <unordered_map>\n\nusing namespace std;\n\ntypedef pair<long long int, long long int> P;\n\nlong long int INF = 1e18;\nlong long int MOD = 1e9 + 7;\n\nint main(){\n\tint N;\n\tcin >> N;\n\tint D[110] = {}, A[110] = {};\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> D[i];\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> A[i];\n\t}\n\tint sz = min(7, N);\n\tint a[8] = {1, 2, 3, 4, 5, 6, 7, 0};\n\tunordered_map<int, int> m;\n\tdo{\n\t\tint S = 0;\n\t\tint pos = 0;\n\t\tfor(int i = 0; i < sz; i++){\n\t\t\tfor(int j = i + 1; j < sz; j++){\n\t\t\t\tif(a[i] > a[j] && j - i <= D[j]){\n\t\t\t\t\tS += A[j];\n\t\t\t\t}else if(a[j] > a[i] && j - i <= D[i]){\n\t\t\t\t\tS += A[i];\n\t\t\t\t}\n\t\t\t}\n\t\t\tpos *= 10;\n\t\t\tpos += a[i];\n\t\t}\n\t\tm[pos] = S;\n\t}while(next_permutation(a, a + sz));\n\tfor(int i = 7; i < N; i++){\n\t\tunordered_map<int, int> m2;\n\t\tfor(pair<int, int> p : m){\n\t\t\t//cout << p.first << \" \" << p.second << endl;\n\t\t\tfor(int j = 6; j >= 0; j--){\n\t\t\t\ta[j] = p.first % 10;\n\t\t\t\tp.first /= 10;\n\t\t\t}\n\t\t\tfor(int j = 0; j < 8; j++){\n\t\t\t\tint S = p.second;\n\t\t\t\tfor(int k = 0; k < 7; k++){\n\t\t\t\t\tif(a[k] > j && 7 - k <= D[i]){\n\t\t\t\t\t\tS += A[i];\n\t\t\t\t\t}else if(a[k] <= j && 7 - k <= D[i - (7 - k)]){\n\t\t\t\t\t\tS += A[i - (7 - k)];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tint pos = 0;\n\t\t\t\tfor(int k = 1; k < 7; k++){\n\t\t\t\t\tpos += a[k];\n\t\t\t\t\tif(a[0] < a[k]){\n\t\t\t\t\t\tpos -= 1;\n\t\t\t\t\t}\n\t\t\t\t\tif(j < a[k]){\n\t\t\t\t\t\tpos += 1;\n\t\t\t\t\t}\n\t\t\t\t\tpos *= 10;\n\t\t\t\t}\n\t\t\t\tpos += j;\n\t\t\t\tif(j < a[0]){\n\t\t\t\t\tpos += 1;\n\t\t\t\t}\n\t\t\t\tm2[pos] = max(m2[pos], S);\n\t\t\t\t//cout << \"m2 \" << pos << \" \" << S << endl;\n\t\t\t}\n\t\t\t//return 0;\n\t\t}\n\t\tm = m2;\n\t}\n\tint ans = 0;\n\tfor(pair<int, int> p : m){\n\t\tans = max(ans, p.second);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 3516, "score_of_the_acc": -0.052, "final_rank": 3 }, { "submission_id": "aoj_0597_3438585", "code_snippet": "#define _USE_MATH_DEFINES\n\n#include <cstdio>\n#include <cstdlib>\n#include <iostream>\n#include <cmath>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <map>\n#include <unordered_map>\n\nusing namespace std;\n\ntypedef pair<long long int, long long int> P;\n\nlong long int INF = 1e18;\nlong long int MOD = 1e9 + 7;\n\nint main(){\n\tint N;\n\tcin >> N;\n\tint D[110] = {}, A[110] = {};\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> D[i];\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> A[i];\n\t}\n\tint sz = min(7, N);\n\tint a[8] = {1, 2, 3, 4, 5, 6, 7, 0};\n\tunordered_map<int, int> m;\n\tdo{\n\t\tint S = 0;\n\t\tint pos = 0;\n\t\tfor(int i = 0; i < sz; i++){\n\t\t\tfor(int j = i + 1; j < sz; j++){\n\t\t\t\tif(a[i] > a[j] && j - i <= D[j]){\n\t\t\t\t\tS += A[j];\n\t\t\t\t}else if(a[j] > a[i] && j - i <= D[i]){\n\t\t\t\t\tS += A[i];\n\t\t\t\t}\n\t\t\t}\n\t\t\tpos *= 10;\n\t\t\tpos += a[i];\n\t\t}\n\t\tm[pos] = S;\n\t}while(next_permutation(a, a + sz));\n\tfor(int i = 7; i < N; i++){\n\t\tunordered_map<int, int> m2;\n\t\tfor(pair<int, int> p : m){\n\t\t\t//cout << p.first << \" \" << p.second << endl;\n\t\t\tfor(int j = 6; j >= 0; j--){\n\t\t\t\ta[j] = p.first % 10;\n\t\t\t\tp.first /= 10;\n\t\t\t}\n\t\t\tfor(int j = 0; j < 8; j++){\n\t\t\t\tint S = p.second;\n\t\t\t\tfor(int k = 0; k < 7; k++){\n\t\t\t\t\tif(a[k] >= j && 7 - k <= D[i]){\n\t\t\t\t\t\tS += A[i];\n\t\t\t\t\t}else if(a[k] < j && 7 - k <= D[i - (7 - k)]){\n\t\t\t\t\t\tS += A[i - (7 - k)];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tint pos = 0;\n\t\t\t\tfor(int k = 1; k < 7; k++){\n\t\t\t\t\tpos += a[k];\n\t\t\t\t\tif(a[0] < a[k]){\n\t\t\t\t\t\tpos -= 1;\n\t\t\t\t\t}\n\t\t\t\t\tif(j < a[k]){\n\t\t\t\t\t\tpos += 1;\n\t\t\t\t\t}\n\t\t\t\t\tpos *= 10;\n\t\t\t\t}\n\t\t\t\tpos += j;\n\t\t\t\tif(j < a[0]){\n\t\t\t\t\tpos += 1;\n\t\t\t\t}\n\t\t\t\tm2[pos] = max(m2[pos], S);\n\t\t\t\t//cout << \"m2 \" << pos << \" \" << S << endl;\n\t\t\t}\n\t\t\t//return 0;\n\t\t}\n\t\tm = m2;\n\t}\n\tint ans = 0;\n\tfor(pair<int, int> p : m){\n\t\tans = max(ans, p.second);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 220, "memory_kb": 3480, "score_of_the_acc": -0.0515, "final_rank": 18 }, { "submission_id": "aoj_0597_3354545", "code_snippet": "#include <bits/stdc++.h>\n\n#define fst(t) std::get<0>(t)\n#define snd(t) std::get<1>(t)\n#define thd(t) std::get<2>(t)\n#define unless(p) if(!(p))\n#define until(p) while(!(p))\n\nusing ll = std::int64_t;\nusing P = std::tuple<int,int>;\n\nint fact[10];\nint N;\nint D[120], A[120];\nint dp[120][5040];\n\nint f(std::list<int> &perm){\n int s = 0, k = 6, v = 0;\n\n for(int i : perm){\n v += fact[k] * (i - __builtin_popcount(s & ((1 << i) - 1)) - 1);\n s |= 1 << i;\n k -= 1;\n }\n\n return v;\n}\n\nint rec(int idx, std::list<int> order){\n if(idx == N + 7){\n return 0;\n }\n\n int fv = f(order);\n\n if(dp[idx][fv] >= 0){\n return dp[idx][fv];\n }\n\n int mx = 0;\n\n for(int i=0;i<=7;++i){\n int v = 0;\n\n auto it = order.begin();\n\n for(int j=0;j<7;++j){\n if(j < i){\n if(idx <= idx - *it + D[idx - *it]){\n v += A[idx - *it];\n }\n }else{\n if(idx - *it >= 7 && idx - D[idx] <= idx - *it){\n v += A[idx];\n }\n }\n \n std::advance(it, 1);\n }\n\n std::list<int> newOrder(order);\n std::transform(newOrder.begin(), newOrder.end(), newOrder.begin(), [](int n){return n + 1;});\n newOrder.insert(std::next(newOrder.begin(), i), 1);\n newOrder.remove(8);\n\n v += rec(idx + 1, newOrder);\n\n mx = std::max(mx, v);\n }\n\n return dp[idx][fv] = mx;\n}\n\nint main(){\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n fact[0] = 1;\n for(int i=1;i<=6;++i){\n fact[i] = i * fact[i - 1];\n }\n\n std::cin >> N;\n\n for(int i=0;i<N;++i){\n std::cin >> D[i + 7];\n }\n\n for(int i=0;i<N;++i){\n std::cin >> A[i + 7];\n }\n\n std::list<int> order(7);\n std::iota(order.begin(), order.end(), 1);\n\n memset(dp, -1, sizeof(dp));\n\n int mx = rec(7, order);\n std::cout << mx << std::endl;\n}", "accuracy": 1, "time_ms": 1720, "memory_kb": 5584, "score_of_the_acc": -0.4578, "final_rank": 13 }, { "submission_id": "aoj_0597_3312942", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<map>\nusing namespace std;\nint N;\nint D[101];\nint A[101];\nmap<vector<int>, int> perm;\n\nint solve(){\n\tint dp[101][5040] = {};//今いる所、前7個の順番\n\tint ans = 0;\n\tfor(int i = 1; i < N; i++){\n\t\tvector<int> p = {0, 1, 2, 3, 4, 5, 6, 7};\n\t\tdo{\n\t\t\tint add = 0;\n\t\t\tbool eaten[8] = {};\n\t\t\t//i番目の小籠包に関する影響のみを考える\n\t\t\tfor(int idx = 0; idx < 8; idx++){\n\t\t\t\tint x = i - p[idx];\n\t\t\t\tif(x == i){\n\t\t\t\t\teaten[p[idx]] = true;\n\t\t\t\t\tfor(int d = 1; d <= D[i]; d++){\n\t\t\t\t\t\tif(i - d < 0) continue;\n\t\t\t\t\t\tif(!eaten[d]) add += A[x];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(x >= 0){\n\t\t\t\t\teaten[p[idx]] = true;\n\t\t\t\t\tif(!eaten[0] && p[idx] <= D[x]){\n\t\t\t\t\t\tadd += A[x];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\n\t\t\t//今の順序の取り出し\n\t\t\tvector<int> tmp1;\n\t\t\tfor(int j = 0; j <= 7; j++){\n\t\t\t\tif(p[j] != 7) tmp1.push_back(p[j]);\n\t\t\t}\n\t\t\t//参照する順序の取り出し\n\t\t\tvector<int> tmp2;\n\t\t\tfor(int j = 0; j <= 7; j++){\n\t\t\t\tif(p[j] != 0) tmp2.push_back(p[j] - 1); \n\t\t\t}\n\t\t\tdp[i][perm[tmp1]] = max(dp[i][perm[tmp1]], dp[i - 1][perm[tmp2]] + add);\n\t\t\tans = max(ans, dp[i][perm[tmp1]]);\n\t\t}while(next_permutation(p.begin(), p.end()));\n\t}\n\tvector<int> p = {0, 1, 2, 3, 4, 5, 6};\n\tdo{\n\t\tans = max(ans, dp[N - 1][perm[p]]);\n\t}while(next_permutation(p.begin(), p.end()));\n\treturn ans;\n}\n\nvoid init(){\n\tcin >> N;\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> D[i];\n\t}\n\tfor(int i = 0; i < N; i++){\n\t\tcin >> A[i];\n\t}\n\tint idx = 0;\n\tvector<int> p = {0, 1, 2, 3, 4, 5, 6};\n\tdo{\t\n\t\tfor(int i = 0; i < N; i++){\n\t\t\t\n\t\t}\n\t\tperm[p] = idx++;\n\t}while(next_permutation(p.begin(), p.end()));\n}\n\nint main(){\n\tinit();\n\tcout << solve() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2360, "memory_kb": 5776, "score_of_the_acc": -0.6207, "final_rank": 15 }, { "submission_id": "aoj_0597_3179806", "code_snippet": "#include <bits/stdc++.h>\n\n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n// #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-10)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x,y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tdouble x;\n \tint y,z,w;\n \tpa4(double x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n/*\n class Point{\n \tpublic:\n \tdouble x,y;\n \tPoint(double x=0,double y=0):x(x),y(y) {}\n \tPoint operator + (Point p) {return Point(x+p.x,y+p.y);}\n \tPoint operator - (Point p) {return Point(x-p.x,y-p.y);}\n \tPoint operator * (double a) {return Point(x*a,y*a);}\n \tPoint operator / (double a) {return Point(x/a,y/a);}\n \tdouble absv() {return sqrt(norm());}\n \tdouble norm() {return x*x+y*y;}\n \tbool operator < (const Point &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const Point &p) const{\n \t\treturn fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n \t}\n };\n typedef Point Vector;\n #define pl pair<int,pas>\n struct Segment{\n Point p1,p2;\n };\n double dot(Vector a,Vector b){\n \treturn a.x*b.x+a.y*b.y;\n }\n double cross(Vector a,Vector b){\n \treturn a.x*b.y-a.y*b.x;\n }\n \n bool parareru(Point a,Point b,Point c,Point d){\n //\tif(abs(cross(a-b,d-c))<EPS)cout<<\"dd \"<<cross(a-b,d-c)<<endl;\n \treturn abs(cross(a-b,d-c))<EPS;\n }\n double distance_ls_p(Point a, Point b, Point c) {\n if ( dot(b-a, c-a) < EPS ) return (c-a).absv();\n if ( dot(a-b, c-b) < EPS ) return (c-b).absv();\n return abs(cross(b-a, c-a)) / (b-a).absv();\n }\n bool is_intersected_ls(Segment a,Segment b) {\n \tif(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;\n \tif(parareru((a.p2),(a.p1),(a.p1),(b.p2))&&parareru((a.p2),(a.p1),(a.p1),(b.p1))){\n //\t\tcout<<\"sss\"<<endl;\n \t\tif(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;\n \t\tif(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;\n \t\tif(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;\n \t\tif(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;\n \t\treturn false;\n \t}\n else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );\n }\n \n double segment_dis(Segment a,Segment b){\n \tif(is_intersected_ls(a,b))return 0;\n \tdouble r=distance_ls_p(a.p1, a.p2, b.p1);\n \tr=min(r,distance_ls_p(a.p1, a.p2, b.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p1));\n \treturn r;\n }\n Point intersection_ls(Segment a, Segment b) {\n Point ba = b.p2-b.p1;\n double d1 = abs(cross(ba, a.p1-b.p1));\n double d2 = abs(cross(ba, a.p2-b.p1));\n double t = d1 / (d1 + d2);\n \n return a.p1 + (a.p2-a.p1) * t;\n }\n */ \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n double distans(double x1,double y1,double x2,double y2){\n \tdouble rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n \treturn sqrt(rr);\n \t\n }\n int mod;\n \n int pr[500010];\n int inv[500010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n double bekid(double w,int r){\n \tif(r==0) return 1.0;\n \tif(r==1) return w;\n \tif(r%2) return bekid(w,r-1)*w;\n \tdouble f=bekid(w,r/2);\n \treturn f*f;\n }\n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \tfor(int i=0;i<ert;i++) inv[i]=beki(pr[i],mod-2,mod);\n \t\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n //----------------kokomade tenpure------------\n //vector<double> ans(100000000),ans2(100000000)\n \n\nvector<int> ve[5040];\nmap<vector<int>,int> ma;\n\nint x[1010],y[1010];\n\nint dp[102][5040];\nint a[110],d[110];\n signed main(){\n \t cin.tie(0);\n \t\t\tios::sync_with_stdio(false);\nint n;\nvector<int> f;\n \tfor(int i=0;i<7;i++)f.pb(i);\n \tint cnt=0;\n \tdo{\n \t\tma[f]=cnt;\n \t\tve[cnt]=f;\n \t\tcnt++;\n \t}while(next_permutation(f.begin(),f.end()));\n \t//cout<<cnt<<endl;\n \tcin>>n;\n \t\n \tfor(int i=0;i<n;i++)cin>>d[i];\n \tfor(int i=0;i<n;i++)cin>>a[i];\n \t\n \tfor(int i=0;i<=n;i++)for(int j=0;j<5040;j++)dp[i][j]=-inf;\n \tdp[0][0]=0;\n \t\n \tfor(int i=0;i<n-1;i++)for(int j=0;j<5040;j++)if(dp[i][j]>=0){\n \t\tfor(int b=0;b<=7;b++){\n \t\t\tvector<int> v=ve[j];\n \t\t\n \t\t\tfor(int k=0;k<7;k++)if(v[k]>=b)v[k]++;\n \t\t\t\n \t\t\n \t\t\tint ans=dp[i][j];\n \t\t\tfor(int k=0;k<7;k++)if(i-k>=0)if(d[i-k]>=1+k)if(v[k]<b)ans+=a[i-k];\n \t\t\tfor(int k=0;k<7;k++)if(i-k>=0)if(d[i+1]>=k+1)if(v[k]>b)ans+=a[i+1];\n \t\t\tv.insert(v.begin(),b);\n \t\t\tfor(int k=0;k<7;k++)if(v[k]>v[7])v[k]--;\n \t\t\tv.pop_back();\n \t\t\tif(ma.find(v)==ma.end()){\n \t\t\t\tfor(auto vv:v)cout<<vv<<\" \";\n \t\t\t\tcout<<endl;\n \t\t\t\tcout<<\"dame\"<<endl;\n \t\t\t\texit(1);\n \t\t\t}\n \t\t\tint num=ma[v];\n \t\t\t//for(auto vv:v)cout<<vv<<\" \";\n \t\t\t//\tcout<<\" \"<<ans<<endl;\n \t\t\tdp[i+1][num]=max(dp[i+1][num],ans);\n \t\t\n \t\t}\n \t\t\n \t}\n \tint e=0;\n \tfor(int i=0;i<5040;i++)e=max(e,dp[n-1][i]);\n \tcout<<e<<endl;\n \t\n \t\n \treturn 0;\n }", "accuracy": 1, "time_ms": 950, "memory_kb": 8252, "score_of_the_acc": -0.3051, "final_rank": 11 }, { "submission_id": "aoj_0597_2669239", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\n\nmap<vector<int>, int>init(vector<int>ds, vector<int>as) {\n\tvector<int>perms(ds.size());\n\tiota(perms.begin(),perms.end(),0);\n\n\tmap<vector<int>,int>mp;\n\tdo {\n\t\tint nans=0;\n\t\tvector<int>dels(ds.size());\n\t\tfor (auto eat : perms) {\n\t\t\tnans+=dels[eat];\n\t\t\tfor (int x = eat - ds[eat]; x <= eat + ds[eat];++x) {\n\t\t\t\tif (x >= 0 && x < ds.size()) {\n\t\t\t\t\tdels[x]+=as[eat];\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\tmp[perms]=nans;\n\t}while(next_permutation(perms.begin(),perms.end()));\n\treturn mp;\n}\n\nmap<vector<int>, int>comp_memo(map<vector<int>, int>pr_memo) {\n\tmap<vector<int>,int>ne_memo;\n\tfor (auto pm : pr_memo) {\n\t\tauto v(pm.first);\n\t\tint f_num = v[0];\n\t\tv.erase(find(v.begin(),v.end(),0));\n\t\tfor (auto&c : v) {\n\t\t\tc--;\n\t\t}\n\t\tne_memo[v]=max(ne_memo[v],pm.second);\n\t}\n\treturn ne_memo;\n}\n\nmap<vector<int>, int>update(vector<int>ds, vector<int>as,map<vector<int>,int>pr_memo) {\n\tpr_memo=comp_memo(pr_memo);\n\tvector<int>perms(ds.size());\n\tiota(perms.begin(), perms.end(), 0);\n\n\tmap<vector<int>, int>mp;\n\tdo {\n\t\tint nans = 0;\n\t\tvector<int>dels(ds.size());\n\t\tfor (auto eat : perms) {\n\t\t\tnans += dels[eat];\n\n\t\t\tfor (int x = eat - ds[eat]; x <= eat + ds[eat];++x) {\n\t\t\t\tif (x >= 0 && x < ds.size()) {\n\t\t\t\t\tif (eat == ds.size() - 1 || x == ds.size() - 1) {\n\t\t\t\t\t\tdels[x] += as[eat];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tvector<int>v(perms.begin(),perms.end());\n\t\tv.erase(find(v.begin(),v.end(),ds.size()-1));\n\t\tassert(pr_memo.find(v)!=pr_memo.end());\n\t\tnans+=pr_memo[v];\n\t\tmp[perms] = max(nans,mp[perms]);\n\t} while (next_permutation(perms.begin(), perms.end()));\n\treturn mp;\n}\n\nint main() {\n\tint N;cin>>N;\n\tvector<int>ds(N),as(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin>>ds[i];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin>>as[i];\n\t}\n\n\tif (N <= 8) {\n\t\tauto ans_mp(init(ds,as));\n\n\t\tint ans=0;\n\t\tfor (auto am : ans_mp) {\n\t\t\tans=max(am.second,ans);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\telse {\n\t\tauto memo(init(vector<int>(ds.begin(),ds.begin()+8),vector<int>(as.begin(),as.begin()+8)));\n\t\tfor (int i = 8; i < N; ++i) {\n\t\t\tmemo=update(vector<int>(ds.begin()+i-7,ds.begin()+i+1)\n\t\t\t\t,vector<int>(as.begin()+i-7,as.begin()+i+1),memo);\n\t\t}\n\t\tint ans=0;\n\t\tfor (auto am : memo) {\n\t\t\tans=max(am.second,ans);\n\t\t\t//cout<<ans<<endl;\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3990, "memory_kb": 18892, "score_of_the_acc": -1.2235, "final_rank": 16 }, { "submission_id": "aoj_0597_2669188", "code_snippet": "#include \"bits/stdc++.h\"\n#include<unordered_map>\n#include<unordered_set>\n#pragma warning(disable:4996)\nusing namespace std;\n\nmap<vector<int>, int>init(vector<int>ds, vector<int>as) {\n\tvector<int>perms(ds.size());\n\tiota(perms.begin(),perms.end(),0);\n\n\tmap<vector<int>,int>mp;\n\tdo {\n\t\tint nans=0;\n\t\tvector<int>dels(ds.size());\n\t\tfor (auto eat : perms) {\n\t\t\tnans+=dels[eat];\n\t\t\tfor (int x = eat - ds[eat]; x <= eat + ds[eat];++x) {\n\t\t\t\tif (x >= 0 && x < ds.size()) {\n\t\t\t\t\tdels[x]+=as[eat];\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\tmp[perms]=nans;\n\t}while(next_permutation(perms.begin(),perms.end()));\n\treturn mp;\n}\n\nmap<vector<int>, int>comp_memo(map<vector<int>, int>pr_memo) {\n\tmap<vector<int>,int>ne_memo;\n\tfor (auto pm : pr_memo) {\n\t\tauto v(pm.first);\n\t\tint f_num = v[0];\n\t\tv.erase(v.begin());\n\t\tfor (auto&x : v) {\n\t\t\tif (x > f_num) {\n\t\t\t\tx--;\n\t\t\t}\n\t\t}\n\t\tne_memo[v]=max(ne_memo[v],pm.second);\n\t}\n\treturn ne_memo;\n}\n\nmap<vector<int>, int>update(vector<int>ds, vector<int>as,map<vector<int>,int>pr_memo) {\n\tpr_memo=comp_memo(pr_memo);\n\tvector<int>perms(8);\n\tiota(perms.begin(), perms.end(), 0);\n\n\tmap<vector<int>, int>mp;\n\tdo {\n\t\tint nans = 0;\n\t\tvector<int>dels(ds.size());\n\t\tfor (auto eat : perms) {\n\t\t\tnans += dels[eat];\n\n\t\t\tfor (int x = eat - ds[eat]; x <= eat + ds[eat];++x) {\n\t\t\t\tif (x >= 0 && x < ds.size()) {\n\t\t\t\t\tif (eat == ds.size() - 1 || x == ds.size() - 1) {\n\t\t\t\t\t\tdels[x] += as[eat];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t}\n\t\tvector<int>v(perms.begin(),perms.end()-1);\n\t\tint last_eat=perms.back();\n\t\tfor (auto &a : v) {\n\t\t\tif(a>last_eat)a--;\n\t\t}\n\t\tassert(pr_memo.find(v)!=pr_memo.end());\n\t\tnans+=pr_memo[v];\n\t\tmp[perms] = max(nans,mp[perms]);\n\t} while (next_permutation(perms.begin(), perms.end()));\n\treturn mp;\n}\n\nint main() {\n\tint N;cin>>N;\n\tvector<int>ds(N),as(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin>>ds[i];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin>>as[i];\n\t}\n\n\tif (N <= 8) {\n\t\tauto ans_mp(init(ds,as));\n\n\t\tint ans=0;\n\t\tfor (auto am : ans_mp) {\n\t\t\tans=max(am.second,ans);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\telse {\n\t\tauto memo(init(vector<int>(ds.begin(),ds.begin()+8),vector<int>(as.begin(),as.begin()+8)));\n\t\tfor (int i = 8; i < N; ++i) {\n\t\t\tmemo=update(vector<int>(ds.begin()+i-7,ds.begin()+i+1)\n\t\t\t\t,vector<int>(as.begin()+i-7,as.begin()+i+1),memo);\n\t\t}\n\t\tint ans=0;\n\t\tfor (auto am : memo) {\n\t\t\tans=max(am.second,ans);\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 4020, "memory_kb": 18844, "score_of_the_acc": -1.2303, "final_rank": 19 }, { "submission_id": "aoj_0597_2638789", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef vector<int> V;\n\nint N;\nint M;\nint ans;\nint fact;\nint D[114];\nint A[114];\nint dp[114][114514];\nint nxt[114514][10];\nV perm;\nvector<V> perms;\nmap<V, int> rev;\n\nint main() {\n scanf(\"%d\", &N);\n for (int i=0; i<N; i++) {\n scanf(\"%d\", &D[i]);\n M = max(M, D[i]+1);\n }\n M = min(M, N);\n\n for (int i=0; i<N; i++) {\n scanf(\"%d\", &A[i]);\n }\n //reverse(A, A+N);\n //reverse(D, D+N);\n\n fact = 1;\n for (int i=0; i<M; i++) {\n perm.emplace_back(i);\n fact *= i+1;\n }\n\n for (int i=0; i<fact; i++) {\n rev[perm] = i;\n perms.emplace_back(perm);\n next_permutation(perm.begin(), perm.end());\n }\n\n for (int idx=0; idx<fact; idx++) {\n auto &perm = perms[idx];\n for (int k=0; k<=M; k++) {\n V nperm;\n for (int l=0; l<k; l++) {\n int p = perm[l];\n if (p > 0) nperm.emplace_back(p-1);\n }\n nperm.emplace_back(M-1);\n for (int l=k; l<M; l++) {\n int p = perm[l];\n if (p > 0) nperm.emplace_back(p-1);\n }\n assert(rev.count(nperm));\n nxt[idx][k] = rev[nperm];\n }\n }\n\n for (int idx=0; idx<fact; idx++) {\n int initial = 0;\n int conv[10] = {};\n \n for (int p : perms[idx]) {\n initial += conv[p];\n for (int k=0; k<M; k++) {\n if (p-D[p] <= k && k <= p+D[p]) conv[k] += A[p];\n }\n }\n\n dp[M-1][idx] = initial;\n ans = max(ans, initial);\n }\n\n for (int i=M; i<N; i++) {\n for (int j=0; j<fact; j++) {\n auto &perm = perms[j];\n for (int k=0; k<=M; k++) {\n int conv = 0;\n for (int l=0; l<k; l++) {\n int p = perm[l];\n if (M <= p+D[i-M+p]) conv += A[i-M+p];\n }\n\n int lack = 0;\n for (int l=k; l<M; l++) {\n int p = perm[l];\n if (M-D[i] <= p) lack += A[i];\n }\n\n int nj = nxt[j][k];\n dp[i][nj] = max(dp[i][nj], dp[i-1][j]+conv+lack);\n ans = max(ans, dp[i][nj]);\n }\n }\n }\n\n printf(\"%d\\n\", ans);\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 27400, "score_of_the_acc": -0.4702, "final_rank": 14 } ]
aoj_0599_cpp
IOI 饅頭(IOI Manju) Incredible Okashi Inc. は「途方もなくおいしいお菓子(incredible okashi)」を製作している会社である.ここでは略してIOI 社と呼ぶ.IOI 社は特製のIOI 饅頭を作ったので,それを販売することになった.IOI 社は$M$ 種類の饅頭を1 個ずつ作った.作られた$M$ 個の饅頭はすべて同じ大きさであるが,ひとつひとつ異なる味なので価格は様々であり,$i$ 番目$(1 \leq i \leq M)$ の饅頭の価格は$P_i$ 円である. ところで,あなたはJust Odd Inventions 社を知っているだろうか? この会社の業務は「ただ奇妙な発明(just odd inventions)」をすることである.ここでは略してJOI 社と呼ぶ.IOI 社は,饅頭を詰めるための高級な箱をJOI 社に発注することになった.JOI 社の製作する饅頭用の箱は$N$ 種類あり, $j$ 番目$(1 \leq j \leq N)$の箱は最大で$C_j$ 個の饅頭を詰められる大きさであり,販売価格は$E_j$ 円である.これらの$N$ 種類の箱のうちの何種類か(0 種類以上$N$ 種類以下) を1 個ずつ発注し,饅頭をそれらの箱に詰め分けてセットで販売することになった.各饅頭セットの価格は,それに含まれる饅頭の価格の合計である. すべての饅頭セットが売れるとした場合,IOI 社が得ることができる利益の最大値はいくらだろうか.ここで利益とは,販売した饅頭セットの価格の合計から,発注した箱の価格の合計を引いた値である.なお,箱に詰めなかった饅頭については,IOI 社のスタッフがおいしくいただくため,利益には影響しないものとする. 課題 各饅頭の価格と,各箱の大きさと価格が与えられたとき,IOI 社が得ることができる利益の最大値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 $M, N$ が空白を区切りとして書かれており,饅頭が $M$ 個,箱が $N$ 種類あることを表す. 続く $M$ 行のうちの $i$ 行目 $(1 \leq i \leq M)$ には,整数 $P_i$ が書かれており,$i$ 番目の饅頭の価格が $P_i$ 円であることを表す. 続く$N$ 行のうちの $j$ 行目 $(1 \leq j \leq N)$ には,整数 $C_j$, $E_j$ が空白を区切りとして書かれており, $j$ 番目の箱は最大で $C_j$ 個の饅頭を詰められる大きさであり,価格が $E_j$ 円であることを表す. 出力 標準出力に,IOI 社が得られる利益の最大値を円単位で表す整数を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. $1 \leq M \leq 10000$ $1 \leq N \leq 500$ $1 \leq P_i \leq 10000 (1 \leq i \leq M)$ $1 \leq C_j \leq 10000 (1 \leq j \leq N)$ $1 \leq E_j \leq 10000 (1 \leq j \leq N)$ 入出力例 入力例 1 4 3 180 160 170 190 2 100 3 120 4 250 出力例 1 480 この例では,1 番目の箱(100 円) と2 番目の箱(120 円) を発注し,たとえば1 番目の箱に1 番目の饅頭と2 番目の饅頭を詰めて $180 + 160 = 340$ 円のセットとして販売,2 番目の箱に3 番目の饅頭と4 番目の饅頭を詰めて $170 + 190 = 360$ 円のセットとして販売すると,IOI 社の利益は $700 - 220 = 480$ 円となる. 入力例 2 2 2 1000 2000 1 6666 1 7777 出力例 2 0 この例では,利益を最大化するためには箱を全く買わないのがよい. 入力例 3 10 4 200 250 300 300 350 400 500 300 250 200 3 1400 2 500 2 600 1 900 出力例 3 450 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0599_9488098", "code_snippet": "#include <stdio.h>\n#include <utility>\n#include <math.h>\n#include <algorithm>\nusing namespace std;\n\n#define rep(i,n) for(int i=0; i < (n); i++)\nconst int INF = 1001001001; // 無限大の定義\n\nint M, N;\nint P[10002]; // 餅の価格\nint C[502]; // 箱に入る餅の数\nint E[502]; // 箱の価格\nint dp[2][10002]; // DPテーブル:j個目の箱まででk個以上入るようにした時の箱の価格の合計最小値\nint change = 1; // 現在のDPテーブルの切り替えフラグ\n\nint main() {\n // 入力の読み込み\n scanf(\"%d %d\", &M, &N);\n rep(i, M) scanf(\"%d\", &P[i]);\n rep(i, N) scanf(\"%d %d\", &C[i], &E[i]);\n\n // 餅の価格を昇順にソート\n sort(P, P + M);\n\n // DPテーブルの初期化と更新\n rep(i, N + 1) {\n change = (bool)(change == 0);\n rep(j, M + 1) {\n if (i == 0) {\n // 初期条件\n dp[change][j] = INF;\n dp[change][0] = 0;\n } else {\n if (j == 0) {\n dp[change][j] = 0;\n } else {\n // 最小値の計算\n dp[change][j] = min(dp[change == 0][j], dp[change == 0][max(0, j - C[i - 1])] + E[i - 1]);\n }\n }\n }\n }\n\n int ans = 0;\n // 詰めることができる最大の餅の値を計算\n rep(i, M + 1) { // もちを詰める個数\n int inin = 0;\n rep(j, i) {\n inin += P[M - j - 1]; // 価格の高い順に詰める\n }\n ans = max(ans, inin - dp[change][i]);\n }\n\n // 結果の出力\n printf(\"%d\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3104, "score_of_the_acc": -0.0878, "final_rank": 5 }, { "submission_id": "aoj_0599_9002553", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll M, N;\n cin >> M >> N;\n vi P(M), C(N), E(N);\n rep(i, M) cin >> P[i];\n rep(i, N) cin >> C[i] >> E[i];\n sort(all(P), greater<ll>());\n vv(ll, dp, N+1, M+1, inf);\n rep(j, 0, N+1) dp[j][0] = 0;\n rep(j, 1, N+1) {\n rep(x, 1, M+1) {\n dp[j][x] = min(dp[j-1][x], dp[j-1][max(x-C[j-1],0LL)]+E[j-1]);\n }\n }\n ll ans = 0;\n ll s = 0;\n rep(x, 1, M+1) {\n s += P[x-1];\n chmax(ans, s-dp[N][x]);\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 42420, "score_of_the_acc": -0.4908, "final_rank": 10 }, { "submission_id": "aoj_0599_7621498", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll modPow(long long a, long long n, long long p) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\nll gcd(ll(a), ll(b)) {\n if (a == 0)return b;\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\nll sqrtz(ll N) {\n ll L = 0;\n ll R = sqrt(N) + 10000;\n while (abs(R - L) > 1) {\n ll mid = (R + L) / 2;\n if (mid * mid <= N)L = mid;\n else R = mid;\n }\n return L;\n\n}\n\n\n\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll M,N;\n cin>>M>>N;\n vll P(M);\n rep(i,M)cin>>P[i];\n sort(all(P));\n reverse(all(P));\n vll SP(M+1,0);\n rep(i,M)SP[i+1]=SP[i]+P[i];\n\n vvll DP(N+1,vll(M+1,1e18));\n DP[0][0]=0;\n rep(i,N){\n ll C,E;\n cin>>C>>E;\n rep(j,M+1){\n chmin(DP[i+1][j],DP[i][j]);\n chmin(DP[i+1][min(j+C,M)],DP[i][j]+E);\n }\n }\n ll an=0;\n rep(i,M+1){\n chmax(an,SP[i]-DP[N][i]);\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 42420, "score_of_the_acc": -0.5742, "final_rank": 12 }, { "submission_id": "aoj_0599_6846975", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint dp[501][10001];\nint main(){\n\tint m,n,p[10001],c[500],e[500];\n\tcin>>m>>n;\n\tfor(int i=1;i<=m;i++)\n\t\tcin>>p[i];\n\tfor(int i=0;i<n;i++)\n\t\tcin>>c[i]>>e[i];\n\tsort(p+1,p+m+1,greater<>());\n\tfor(int i=1;i<=m;i++)\n\t\tp[i]+=p[i-1];\n\tfor(int i=0;i<=n;i++)\n\t\tfor(int j=0;j<=m;j++)\n\t\t\tdp[i][j]=-1e9;\n\tdp[0][0]=0;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<=m;j++){\n\t\t\tdp[i+1][j]=max(dp[i+1][j],dp[i][j]);\n\t\t\tdp[i+1][min(j+c[i],m)]=max(dp[i+1][min(j+c[i],m)],dp[i][j]+p[min(j+c[i],m)]-p[j]-e[i]);\n\t\t}\n\t}\n\tcout<<*max_element(dp[n],dp[n]+m+1)<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 23048, "score_of_the_acc": -0.2512, "final_rank": 9 }, { "submission_id": "aoj_0599_6291385", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e12;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll N, M; cin >> N >> M;\n vector<ll>A(N); input_arr(A, N);\n sort(A.begin(), A.end(), greater<ll>());\n vector<ll>C(N + 1, 0);\n for (ll i = 1; i <= N; i++) {\n C[i] = C[i - 1] + A[i - 1];\n }\n vector<P>B(M); input_arr(B, M);\n sort(B.begin(), B.end());\n vector<vector<ll>>DP(M + 1, vector<ll>(20000, INF));\n DP[0][0] = 0;\n for (ll i = 1; i <= M; i++) {\n DP[i][0] = 0;\n for (ll j = 1; j <= N; j++) {\n DP[i][j] = min(DP[i - 1][j], DP[i - 1][max(j - B[i - 1].first, 0LL)] + B[i - 1].second);\n }\n }\n ll ans = 0;\n for (ll i = 0; i <= N; i++) {\n ans = max(ans, C[i] - DP[M][i]);\n }\n cout << ans << endl;\n}\nint main() {\n solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 83580, "score_of_the_acc": -1.1667, "final_rank": 16 }, { "submission_id": "aoj_0599_6050498", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\n//1次元累積和\ntemplate<class T> struct CumulativeSum1D{\n int _n;\n vector<T> Sumv;\n CumulativeSum1D(vector<T> a) : _n((int)a.size()+1),Sumv((int)a.size()+1){\n Sumv[0]=0;\n for(int i=1;i<_n;i++){\n Sumv[i]=Sumv[i-1]+a[i-1];\n }\n }\n T query(int l,int r){\n return Sumv[r]-Sumv[l];\n }\n};\n\nint main(){\n INT(m,n);\n vector<int> a(m);\n in(a);\n sort(rall(a));\n vector<array<int,2>> b(n);\n rep(i,n)in(b[i][0],b[i][1]);\n vector<int> dp(m+1,INF);\n dp[0]=0;\n rep(i,n){\n for(int j=m-1;j>=0;j--){\n chmin(dp[min(m,j+b[i][0])],dp[j]+b[i][1]);\n }\n for(int j=m;j>=1;j--){\n chmin(dp[j-1],dp[j]);\n }\n }\n CumulativeSum1D<int> sumv(a);\n int ans=0;\n for(int i=0;i<=m;i++){\n chmax(ans,sumv.query(0,i)-dp[i]);\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3760, "score_of_the_acc": -0.0126, "final_rank": 4 }, { "submission_id": "aoj_0599_5170508", "code_snippet": "#include<cstdio>\n#include<functional>\n#include<algorithm>\nusing namespace std;\nint sum[10001]={0},mn[10001],dp[501][100001]={0};\nint main(void)\n{\n\tint m,n,p[10001],c[501],e[501],i,j,ans;\n\tscanf(\"%d%d\",&m,&n);\n\tfor(i=1;i<=m;i++){\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\tsort(p+1,p+m+1,greater<int>());\n\tfor(i=1;i<=m;i++){\n\t\tsum[i]=sum[i-1]+p[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d%d\",&c[i],&e[i]);\n\t}\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\tdp[i][j]=1000000000;\n\t\t\tmn[j]=1000000000;\n\t\t}\n\t}\n\tdp[0][0]=0;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<m;j++){\n\t\t\tif(dp[i][j]!=1000000000){\n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]);\n\t\t\t\tif(j+c[i]>m){\n\t\t\t\t\tdp[i+1][m]=min(dp[i+1][m],dp[i][j]+e[i]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j+c[i]]=min(dp[i+1][j+c[i]],dp[i][j]+e[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\tmn[j]=min(mn[j],dp[i][j]);\n\t\t}\n\t}\n\tans=0;\n\tfor(i=1;i<=m;i++){\n\t\tfor(j=i;j<=m;j++){\n\t\t\tans=max(ans,sum[i]-mn[j]);\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 24496, "score_of_the_acc": -0.6024, "final_rank": 13 }, { "submission_id": "aoj_0599_5170406", "code_snippet": "#include<cstdio>\n#include<functional>\n#include<algorithm>\nusing namespace std;\nint sum[10001]={0},mn[10001],dp[100001][501]={0};\nint main(void)\n{\n\tint m,n,p[10001],c[501],e[501],i,j,ans;\n\tscanf(\"%d%d\",&m,&n);\n\tfor(i=1;i<=m;i++){\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\tsort(p+1,p+m+1,greater<int>());\n\tfor(i=1;i<=m;i++){\n\t\tsum[i]=sum[i-1]+p[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d%d\",&c[i],&e[i]);\n\t}\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\tdp[i][j]=1000000000;\n\t\t\tmn[j]=1000000000;\n\t\t}\n\t}\n\tdp[0][0]=0;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<m;j++){\n\t\t\tif(dp[i][j]!=1000000000){\n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]);\n\t\t\t\tif(j+c[i]>m){\n\t\t\t\t\tdp[i+1][m]=min(dp[i+1][m],dp[i][j]+e[i]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j+c[i]]=min(dp[i+1][j+c[i]],dp[i][j]+e[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\tmn[j]=min(mn[j],dp[i][j]);\n\t\t}\n\t}\n\tans=0;\n\tfor(i=1;i<=m;i++){\n\t\tfor(j=i;j<=m;j++){\n\t\t\tans=max(ans,sum[i]-mn[j]);\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "accuracy": 0.15151515151515152, "time_ms": 30, "memory_kb": 2744, "score_of_the_acc": -0.1667, "final_rank": 17 }, { "submission_id": "aoj_0599_5162172", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nconstexpr long long mod = 1000000007;\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint dp[33456], m, n, p[23456], c, e, ans, sum;\nsigned main() {\n\tfor1(i, 33455)dp[i] = mod;\n\tcin >> m >> n;\n\tfor0(i, m)cin >> p[i];\n\twhile (n--) {\n\t\tcin >> c >> e;\n\t\tfor (int i = 23001; i >= 0; i--)dp[i + c] = min(dp[i + c], dp[i] + e);\n\t}\n\tfor (int i = 33432; i >= 0; i--)dp[i] = min(dp[i], dp[i + 1]);\n\tsort(p, p + m);\n\tfor1(i, m) {\n\t\tsum += p[m - i];\n\t\tans = max(ans, sum - dp[i]);\n\t}puts(ans);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3476, "score_of_the_acc": -0.0091, "final_rank": 3 }, { "submission_id": "aoj_0599_4940022", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\nsigned main() {\n\tll n, m; cin >> n >> m;\n\tvector<ll> price(n);\n\trep(i, n) { cin >> price[i]; }\n\tsort(all(price)); reverse(all(price));\n\tvector<ll> ko(m), cost(m);\n\trep(i, m) { cin >> ko[i] >> cost[i]; }\n\tvector<ll> mi(n + 1, INF);//i個の饅頭を取ったときに必要なboxcostの最小値\n\tvector<vector<ll>> dp(n + 1, vector<ll>(m));//boxどんだけ埋まってるか\n\tmi[0] = 0;\n\trep2(i, n) {\n\t\trep(j, m) {\n\t\t\tif (dp[max((ll)0, i - ko[j])][j] == 0) {//容量OKか?\n\t\t\t\tif (mi[max((ll)0, i - ko[j])] + cost[j] < mi[i]) {\n\t\t\t\t\tmi[i] = mi[max((ll)0, i - ko[j])] + cost[j];\n\t\t\t\t\tdp[i] = dp[max((ll)0, i - ko[j])]; dp[i][j] += min(i, ko[j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll sum = 0, ans = 0;\n\trep(i, n) {\n\t\tsum += price[i];\n\t\tans = max(ans, sum - mi[i + 1]);\n\t\t//cout << mi[i + 1] << endl;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 42488, "score_of_the_acc": -0.9917, "final_rank": 15 }, { "submission_id": "aoj_0599_4730490", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint M, N;\nvector<int> Price;\nvector<pair<int, int> > BoxInfo;\nint DpTotalOfBox[500][10001];\nconst int INF = 1000000000;\n\nvoid solve() {\n\tint ans, curSum, curPrice;\n\n\tmemset(DpTotalOfBox, 0, sizeof(DpTotalOfBox));\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 1; j <= M; ++j) {\n\t\t\tDpTotalOfBox[i][j] = INF;\n\t\t}\n\t}\n\n\tans = 0;\n\tcurPrice = BoxInfo[0].second;\n\tcurSum = min(M, BoxInfo[0].first);\n\tfor (int i = 1; i <= curSum; ++i) {\n\t\tDpTotalOfBox[0][i] = curPrice;\n\t\tans = max(ans, Price[i - 1] - DpTotalOfBox[0][i]);\n\t}\n\n\tfor (int i = 1; i < N; ++i) {\n\t\tcurPrice = BoxInfo[i].second;\n\t\tcurSum = BoxInfo[i].first;\n\t\tfor (int j = 1; j <= M; ++j) {\n\t\t\tDpTotalOfBox[i][j] = min(DpTotalOfBox[i - 1][j], curPrice + DpTotalOfBox[i - 1][max(0, j - curSum)]);\n\t\t\tans = max(ans, Price[j - 1] - DpTotalOfBox[i][j]);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n}\n\nint main() {\n\tint p, sum;\n\n\tcin >> M >> N;\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin >> p;\n\t\tPrice.push_back(p);\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> sum >> p;\n\t\tBoxInfo.push_back({ sum,p });\n\t}\n\tsort(Price.begin(), Price.end(), greater<int>());\n\tfor (int i = 1; i < M; ++i) {\n\t\tPrice[i] += Price[i - 1];\n\t}\n\tsolve();\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 22812, "score_of_the_acc": -0.2483, "final_rank": 8 }, { "submission_id": "aoj_0599_4668677", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define fcout cout << fixed << setprecision(15)\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint p[10010], c[550], e[550];\nint m, n; // m: 饅頭の数, n: 箱の数\n\nsigned main() {\n\tcin.tie(0);\n\tcout.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tcin >> m >> n;\n\trep(i, m) cin >> p[i];\n\trep(i, n) cin >> c[i] >> e[i];\n\n\tsort(p, p+m, greater<>());\n\tvector<int> sum(m + 10, 0); // i個目まで取った時の利益\n\trep(i, m) sum[i+1] = sum[i] + p[i];\n\n\t// dp[i]: i個以上入れられるよう箱を用意した時の最小コスト\n\tvector<int> dp(m + 10, 0);\n\trep(i, m+1) dp[i] = INF;\n\tdp[0] = 0;\n\n\trep(i, n) {\n\t\tfor(int j = m; j >= 0; j--) {\n\t\t\t// c: 入れられる個数, e: 価格\n\t\t\tchmin(dp[j], dp[max(0LL, j - c[i])] + e[i]);\n\t\t}\n\t}\n\n\tint ans = 0;\n\trep(i, m+1) {\n\t\tchmax(ans, sum[i] - dp[i]);\n\t\t//cout << sum[i] << \" \" << dp[i] << endl;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3416, "score_of_the_acc": -0.0916, "final_rank": 6 }, { "submission_id": "aoj_0599_4526542", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <functional>\n#include <bitset>\n\nusing namespace std;\nusing lint = long long int;\nlong long int INF = 1001001001001001LL;\nint inf = 1000000007;\nlong long int MOD = 1000000007LL;\ndouble PI = 3.1415926535897932;\n\ntemplate<typename T1,typename T2>inline void chmin(T1 &a,const T2 &b){if(a>b) a=b;}\ntemplate<typename T1,typename T2>inline void chmax(T1 &a,const T2 &b){if(a<b) a=b;}\n\n#define ALL(a) a.begin(),a.end()\n#define RALL(a) a.rbegin(),a.rend()\n\n/* do your best */\n\nint main() {\n \n int m, n; cin >> m >> n;\n vector<lint> p(m);\n for (int i = 0; i < m; i++) {\n cin >> p[i];\n }\n vector<lint> c(n);\n vector<lint> e(n);\n for (int i = 0; i < n; i++) {\n cin >> c[i] >> e[i];\n }\n\n vector<vector<lint>> dp(n + 1, vector<lint> (m + 1, INF));\n dp[0][0] = 0; \n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j <= m; j++) {\n if (dp[i][j] == INF) continue;\n \n // not\n dp[i + 1][j] = min(dp[i + 1][j], dp[i][j]);\n\n // take\n lint nCap = min(j + c[i], (lint)m);\n dp[i + 1][nCap] = min(dp[i + 1][nCap], dp[i][j] + e[i]);\n }\n }\n\n sort(RALL(p));\n vector<lint> acc(m + 1, 0);\n for (int i = 1; i <= m; i++) {\n acc[i] = p[i - 1];\n acc[i] += acc[i - 1];\n }\n\n lint ans = 0;\n // 饅頭 i こ販売\n \n for (int i = 1; i <= m; i++) {\n lint cost = dp[n][i];\n lint score = acc[i];\n ans = max(ans, score - cost);\n }\n\n cout << ans << endl;\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 42200, "score_of_the_acc": -0.5714, "final_rank": 11 }, { "submission_id": "aoj_0599_4419459", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n#define enld '\\n'\n#define rep(i,n) for(int i=0; i<(n); i++)\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"Ofast\")\nconstexpr ll INF = 1e18;\nconstexpr int inf = 1e9;\nconstexpr ll mod = 1000000007;\nconstexpr ll mod2 = 998244353;\nconst double PI = 3.1415926535897932384626433832795028841971;\nconst int dx[6] = {1, 0, -1, 0,1,1};\nconst int dy[6] = {0, 1, 0, -1,1,-1};\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n// ---------------------------------------------------------------------------\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int N,M;\n cin >> N >> M;\n vector<int> A(N);\n for(int i=0; i<N; i++) cin >> A[i];\n sort(A.begin(),A.end(),greater<int>());\n vector<P> d(M);\n for(int i=0; i<M; i++){\n cin >> d[i].first >> d[i].second;\n }\n vector<vector<ll>> dp(M+1, vector<ll> (N+1,inf));\n dp[0][0] = 0;\n for(int i=0; i<M; i++){\n for(int j=0; j<=N; j++){\n chmin(dp[i+1][j],dp[i][j]);\n chmin(dp[i+1][j],dp[i][max(0,j-d[i].first)]+d[i].second);\n }\n }\n // for(int i=0; i<=M; i++){\n // for(int j=0; j<=N; j++){\n // cout << dp[i][j] << \" \";\n // }\n // cout << enld;\n // }\n ll ans = 0;\n ll sum = 0;\n for(int i=0; i<N; i++){\n sum += A[i];\n chmax(ans,sum-dp[M][i+1]);\n }\n cout << ans << enld;\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 42212, "score_of_the_acc": -0.7382, "final_rank": 14 }, { "submission_id": "aoj_0599_4416085", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1e9;\n\nint main(){\n int m,n;\n cin >> m >> n;\n vector<int> a(m);\n for(int i=0; i<m; i++){\n cin >> a[i];\n }\n sort(a.begin(), a.end(), greater<int>());\n for(int i=0; i<m-1; i++){\n a[i+1] += a[i];\n }\n\n vector<int> b(n),c(n);\n for(int i=0; i<n; i++){\n cin >> b[i] >> c[i];\n }\n vector<int> dp(m+1, inf);\n dp[0] = 0;\n for(int i=0; i<n; i++){\n for(int j=m; j>=0; j--){\n dp[j] = min(dp[j], dp[max(j-b[i], 0)]+c[i]);\n }\n for(int j=m; j>0; j--){\n dp[j-1] = min(dp[j-1], dp[j]);\n }\n }\n\n int ans = 0;\n for(int i=0; i<m; i++){\n ans = max(ans, a[i]-dp[i+1]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3252, "score_of_the_acc": -0.0063, "final_rank": 1 }, { "submission_id": "aoj_0599_4416011", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=1<<30;\nconst int mod=1e9+7;\nconst int MOD=998244353;\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n ll m,n;cin >> m >> n;\n vector<bool> b(n);\n vector<ll> p(m),c(n),e(n);\n for(int i=0;i<m;i++){\n cin >> p[i];\n }\n sort(p.begin(),p.end(),greater<ll>());\n for(int i=0;i<n;i++){\n cin >> c[i] >> e[i];\n }\n vector<ll> dp(m+1,INF);\n dp[0]=0;\n for(int i=0;i<n;i++){\n vector<ll> t(m+1,INF);\n t[0]=0;\n for(int j=0;j<=m;j++){\n chmin(t[j],dp[j]);\n chmin(t[min(m,j+c[i])],dp[j]+e[i]);\n }\n for(int j=0;j<=m;j++){\n dp[j]=t[j];\n }\n }\n ll ans=0,sum=0;\n for(int i=0;i<m;i++){\n sum+=p[i];\n chmax(ans,sum-dp[i+1]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3352, "score_of_the_acc": -0.0075, "final_rank": 2 }, { "submission_id": "aoj_0599_4029540", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<functional>\nusing namespace std;\nint p[10002],c[502],e[502],flg[10002][502],cnt[10002][502],dp[10002][502],sum[10002];\nint main(void)\n{\n\tint m,n,i,j,mx,a;\n\tscanf(\"%d %d\",&m,&n);\n\tfor(i=1;i<=m;i++){\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\tfor(i=1;i<m;i++){\n\t\tfor(j=i+1;j<=m;j++){\n\t\t\tif(p[i]<p[j]){\n\t\t\t\tswap(p[i],p[j]);\n\t\t\t}\n\t\t}\n\t}\n\tp[0]=0;\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d %d\",&c[i],&e[i]);\n\t}\n\tc[0]=0;\n\te[0]=0;\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\tdp[i][j]=0;\n\t\t\tflg[i][j]=0;\n\t\t\tcnt[i][j]=0;\n\t\t}\n\t}\n\tflg[0][0]=1;\n\tsum[0]=0;\n\tfor(i=1;i<=m;i++){\n\t\tsum[i]=sum[i-1]+p[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<=m;j++){\n\t\t\ta=j+c[i+1];\n\t\t\tif(a>m){\n\t\t\t\ta=m;\n\t\t\t}\n\t\t\tif(flg[i][j]!=0){\n\t\t\t\tif(flg[i+1][j]==0){\n\t\t\t\t\tdp[i+1][j]=dp[i][j];\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j]=max(dp[i][j],dp[i+1][j]);\n\t\t\t\t}\n\t\t\t\tflg[i+1][j]=1;\n\t\t\t\tif(flg[i+1][a]==0){\n\t\t\t\t\tdp[i+1][a]=dp[i][j]+(sum[a]-sum[j])-e[i+1];\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][a]=max(dp[i+1][a],dp[i][j]+(sum[a]-sum[j])-e[i+1]);\n\t\t\t\t}\n\t\t\t\tflg[i+1][a]=1;\n\t\t\t}\n\t\t}\n\t}\n\tmx=0;\n\tfor(i=0;i<=n;i++){\n\t\tmx=max(mx,dp[i][m]);\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tmx=max(mx,dp[n][i]);\n\t}\n\tprintf(\"%d\\n\",mx);\n\treturn 0;\n}", "accuracy": 0.15151515151515152, "time_ms": 120, "memory_kb": 2920, "score_of_the_acc": -0.9188, "final_rank": 18 }, { "submission_id": "aoj_0599_4024371", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<functional>\nusing namespace std;\nint p[10003],c[503],e[503],flg[10003][503],cnt[10003][503],dp[10003][503];\nint main(void)\n{\n\tint m,n,i,j,MAX;\n\tscanf(\"%d %d\",&m,&n);\n\tfor(i=1;i<=m;i++){\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\tfor(i=1;i<m;i++){\n\t\tfor(j=i+1;j<=m;j++){\n\t\t\tif(p[i]<p[j]){\n\t\t\t\tswap(p[i],p[j]);\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d %d\",&c[i],&e[i]);\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tdp[i][j]=0;\n\t\t\tflg[i][j]=0;\n\t\t\tcnt[i][j]=0;\n\t\t}\n\t}\n\tflg[0][0]=1;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tif(flg[i][j]!=0){\n\t\t\t\tif(cnt[i][j]>0&&i!=m){\n\t\t\t\t\tif(dp[i+1][j]<dp[i][j]+p[i+1]||dp[i+1][j]==0){\n\t\t\t\t\t\tcnt[i+1][j]=cnt[i][j]-1;\n\t\t\t\t\t\tdp[i+1][j]=dp[i][j]+p[i+1];\n\t\t\t\t\t\tflg[i+1][j]=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(cnt[i][j]==0){\n\t\t\t\t\tif(dp[i][j+1]<=dp[i][j]||dp[i][j+1]==0){\n\t\t\t\t\t\tif(j!=n){\n\t\t\t\t\t\t\tdp[i][j+1]=dp[i][j];\n\t\t\t\t\t\t\tcnt[i][j+1]=cnt[i][j];\n\t\t\t\t\t\t\tflg[i][j+1]=1;\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t\tif(dp[i+1][j+1]<dp[i][j]+(p[i+1]-e[j+1]||dp[i+1][j+1]==0)){\n\t\t\t\t\t\tif(i!=m&&j!=n){\n\t\t\t\t\t\t\tdp[i+1][j+1]=dp[i][j]+(p[i+1]-e[j+1]);\n\t\t\t\t\t\t cnt[i+1][j+1]=c[j+1]-1;\n\t\t\t\t\t\t flg[i+1][j+1]=1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tMAX=0;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tMAX=max(MAX,dp[i][j]);\n\t\t}\n\t}\n\tprintf(\"%d\\n\",MAX);\n\treturn 0;\n}", "accuracy": 0.15151515151515152, "time_ms": 130, "memory_kb": 61676, "score_of_the_acc": -1.729, "final_rank": 20 }, { "submission_id": "aoj_0599_4024367", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<functional>\nusing namespace std;\nint p[10002],c[502],e[502],flg[10002][502],cnt[10002][502],dp[10002][502];\nint main(void)\n{\n\tint m,n,i,j,MAX;\n\tscanf(\"%d %d\",&m,&n);\n\tfor(i=1;i<=m;i++){\n\t\tscanf(\"%d\",&p[i]);\n\t}\n\tfor(i=1;i<m;i++){\n\t\tfor(j=i+1;j<=m;j++){\n\t\t\tif(p[i]<p[j]){\n\t\t\t\tswap(p[i],p[j]);\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d %d\",&c[i],&e[i]);\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tdp[i][j]=0;\n\t\t\tflg[i][j]=0;\n\t\t\tcnt[i][j]=0;\n\t\t}\n\t}\n\tflg[0][0]=1;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tif(flg[i][j]!=0){\n\t\t\t\tif(cnt[i][j]>0&&i!=m){\n\t\t\t\t\tif(dp[i+1][j]<dp[i][j]+p[i+1]||dp[i+1][j]==0){\n\t\t\t\t\t\tcnt[i+1][j]=cnt[i][j]-1;\n\t\t\t\t\t\tdp[i+1][j]=dp[i][j]+p[i+1];\n\t\t\t\t\t\tflg[i+1][j]=1;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(cnt[i][j]==0){\n\t\t\t\t\tif(dp[i][j+1]<=dp[i][j]||dp[i][j+1]==0){\n\t\t\t\t\t\tif(j!=n){\n\t\t\t\t\t\t\tdp[i][j+1]=dp[i][j];\n\t\t\t\t\t\t\tcnt[i][j+1]=cnt[i][j];\n\t\t\t\t\t\t\tflg[i][j+1]=1;\n\t\t\t\t\t\t}\t\n\t\t\t\t\t}\n\t\t\t\t\tif(dp[i+1][j+1]<dp[i][j]+(p[i+1]-e[j+1]||dp[i+1][j+1]==0)){\n\t\t\t\t\t\tif(i!=m&&j!=n){\n\t\t\t\t\t\t\tdp[i+1][j+1]=dp[i][j]+(p[i+1]-e[j+1]);\n\t\t\t\t\t\t cnt[i+1][j+1]=c[j+1]-1;\n\t\t\t\t\t\t flg[i+1][j+1]=1;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tMAX=0;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tMAX=max(MAX,dp[i][j]);\n\t\t}\n\t}\n\tprintf(\"%d\\n\",MAX);\n\treturn 0;\n}", "accuracy": 0.15151515151515152, "time_ms": 130, "memory_kb": 61468, "score_of_the_acc": -1.7265, "final_rank": 19 }, { "submission_id": "aoj_0599_4015596", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n#include<random>\n#include<functional>\n#include<utility>\n\ntypedef long long ll;\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define pb push_back\n#define P pair<int, int>\n#define PLI pair<ll, int>\n#define PLL pair<ll, ll>\n#define VI vector<int>\n#define VII vector<VI>\n\nusing namespace std;\n\n\nint M, N;\nint p[10005], c[505], e[505];\nint dp[505][10005] = {}, sum[10005] = {};\nint main() {\n\tcin >> M >> N;\n\trep(i, M) cin >> p[i];\n\trep(i, N) cin >> c[i] >> e[i];\n\tsort(p, p + M, greater<>());\n\trep(i, M) sum[i + 1] += sum[i] + p[i];\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j <= M; j++) {\n\t\t\tdp[i + 1][j] = max(dp[i + 1][j], dp[i][j]);\n\t\t\tint tmp = min(j + c[i], M);\n\t\t\tdp[i + 1][tmp] = max(dp[i + 1][tmp], dp[i][j] + sum[tmp] - sum[j] - e[i]);\n\t\t}\n\t}\n\tint ans = 0;\n\trep(i, M + 1) ans = max(ans, dp[N][i]);\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 22792, "score_of_the_acc": -0.248, "final_rank": 7 } ]
aoj_0598_cpp
JOI 紋章(JOI Emblem) 情報オリンピック日本委員会では,台湾大会に向かう選手を応援するために新しいJOI 旗を作成することにした. JOI 旗は,正方形が縦に $M$ 行,横に $N$ 列並んだ形をしており,各正方形には J,O,I のいずれかの文字が1 つずつ書かれている. 情報オリンピック日本委員会はJOI 旗とは別にJOI 紋章というものを決めている.JOI 紋章は,正方形が縦に2 行,横に2 列並んだ形をしており,各正方形にはJ,O,I のいずれかの文字が1 つずつ書かれている. JOI 旗に含まれるJOI 紋章の個数とは,JOI 旗に含まれる縦2 行,横2 列の領域のうち,その領域のJ,O,I の配置がJOI 紋章と(回転や裏返しをせずに) 一致しているものの個数のことである.条件を満たす縦2 行,横2 列の領域同士が重なっていてもそれらを別々に数えるものとする. 情報オリンピック日本委員会は古いJOI 旗と1 枚の白紙を持っている.白紙はJOI 旗を構成する正方形1 個分の大きさで,J,O,I のうち好きな1 文字を書き込むことができる.情報オリンピック日本委員会は以下のいずれか1 つの操作をして,新しいJOI 旗を作成することにした. 古いJOI 旗に対して何も操作せず,そのまま新しいJOI 旗とする.白紙は使用しない. 白紙に1 文字書き込み,古いJOI 旗のいずれかの正方形に重ねて貼り付けることで古いJOI 旗のうち1 箇所を変更する.変更後のJOI 旗を新しいJOI 旗とする. 情報オリンピック日本委員会は新しいJOI 旗に含まれるJOI 紋章の個数をできるだけ多くしたいと思っている.あなたは新しいJOI 旗に含まれるJOI 紋章の個数の最大値を求めることになった. 課題 古いJOI 旗とJOI 紋章の情報が与えられたとき,新しいJOI 旗に含まれるJOI 紋章の個数の最大値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には2 個の整数 $M, N$ が空白を区切りとして書かれている.これはJOI 旗が正方形が縦に$M$行,横に$N$ 列並んだ形であることを表している. 続く$M$ 行の各行には,それぞれ$N$ 文字からなる文字列が書かれている.各文字はJ,O,I のいずれかであり,$M$ 行のうち上から$i$ 行目$(1 \leq i \leq M)$ に書かれている文字列の左から$j$ 文字目$(1 \leq j \leq N)$は古いJOI 旗の上から$i$ 行目,左から$j$ 列目の正方形に書かれている文字を表す. 続く2 行の各行には,それぞれ2 文字からなる文字列が書かれている.各文字はJ,O,I のいずれかであり,2 行のうち上から$i$ 行目$(1 \leq i \leq 2)$ に書かれている文字列の左から$j$ 文字目$(1 \leq j \leq 2)$ はJOI 紋章の上から$i$ 行目,左から$j$ 列目の正方形に書かれている文字を表す. 出力 標準出力に,新しいJOI 旗に含まれるJOI 紋章の個数の最大値を表す整数を1 行で出力せよ. 制約 すべての入力データは以下の条件を満たす. $2 \leq M \leq 1000$ $2 \leq N \leq 1000$ 入出力例 入力例 1 3 5 JOIJO IJOOO IIJIJ JO IJ 出力例 1 3 古いJOI 旗とJOI 紋章は問題文中の例の通りである.上から2 行目,左から4 列目の正方形を白紙を用いてJ に変更すると,次のような形になる. このように変更した後のJOI 旗には次に示す3 箇所にJOI 紋章と同じ配置の領域がある. JOI 紋章と同じ配置の領域が4 箇所以上となる新しいJOI 旗は存在しないので,新しいJOI 旗に含まれるJOI 紋章の個数の最大値は3 である. 入力例 2 2 6 JOJOJO OJOJOJ OJ JO 出力例 2 2 白紙を使用しなくても最大値が得られる場合があることに注意せよ. 入力例 3 2 2 JI IJ JJ JJ 出力例 3 0 この入出力例の場合,考えられるどの新しいJOI 旗においても,JOI 紋章が1 つも含まれない. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0598_10946345", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\nusing namespace std;\nstring S[1000],U[1000], T[2]; int H, W, cnt, maxn; char F[4] = \"JOI\";\nint main() {\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++) { cin >> S[i]; U[i] = S[i]; }\n\tfor (int i = 0; i < 2; i++) cin >> T[i];\n\tfor (int i = 0; i < H - 1; i++) {\n\t\tfor (int j = 0; j < W - 1; j++) {\n\t\t\tif (S[i][j] == T[0][0] && S[i][j + 1] == T[0][1] && S[i + 1][j] == T[1][0] && S[i + 1][j + 1] == T[1][1])cnt++;\n\t\t}\n\t}\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\tS[i][j] = F[k]; int sum = 0;\n\t\t\t\tfor (int l = max(0, i - 1); l <= min(H - 2, i); l++) {\n\t\t\t\t\tfor (int m = max(0, j - 1); m <= min(W - 2, j); m++) {\n\t\t\t\t\t\tif (S[l][m] == T[0][0] && S[l][m + 1] == T[0][1] && S[l + 1][m] == T[1][0] && S[l + 1][m + 1] == T[1][1])sum++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor (int l = max(0, i - 1); l <= min(H - 2, i); l++) {\n\t\t\t\t\tfor (int m = max(0, j - 1); m <= min(W - 2, j); m++) {\n\t\t\t\t\t\tif (U[l][m] == T[0][0] && U[l][m + 1] == T[0][1] && U[l + 1][m] == T[1][0] && U[l + 1][m + 1] == T[1][1])sum--;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tmaxn = max(maxn, sum);\n\t\t\t\tS[i][j] = U[i][j];\n\t\t\t}\n\t\t}\n\t}\n\tcout << cnt + maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 6392, "score_of_the_acc": -0.3065, "final_rank": 13 }, { "submission_id": "aoj_0598_10344636", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int m,n;\n cin >> m >> n;\n vector<vector<char>> hata(m,vector<char>(n));\n rep(i,m){\n rep(j,n){\n cin >> hata[i][j];\n }\n }\n vector<vector<char>> mon(2,vector<char>(2));\n rep(i,2){\n rep(j,2){\n cin >> mon[i][j];\n }\n }\n int cur=0;\n rep(i,m-1){\n rep(j,n-1){\n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n cur++;\n }\n }\n }\n vector<char> s={'J','O','I'};\n int ans=cur;\n rep(i,m){\n rep(j,n){\n int now=hata[i][j];\n rep(k,3){\n int res=cur;\n if(i==0 && j==0){\n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res--;\n }\n }\n else if(i==m-1 && j==0){\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res--;\n }\n }\n else if(i==0 && j==n-1){\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res--;\n }\n }\n else if(i==m-1 && j==n-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res--;\n } \n }\n else if(i==0){\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res--;\n } \n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res--;\n }\n }\n else if(i==m-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res--;\n }\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res--;\n } \n }\n else if(j==0){\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res--;\n }\n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res--;\n }\n }\n else if(j==n-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res--;\n }\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res--;\n } \n }\n else{\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res--;\n }\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res--;\n }\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res--;\n } \n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res--;\n }\n }\n hata[i][j]=s[k];\n if(i==0 && j==0){\n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res++;\n }\n }\n else if(i==m-1 && j==0){\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res++;\n }\n }\n else if(i==0 && j==n-1){\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res++;\n }\n }\n else if(i==m-1 && j==n-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res++;\n } \n }\n else if(i==0){\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res++;\n } \n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res++;\n }\n }\n else if(i==m-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res++;\n }\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res++;\n } \n }\n else if(j==0){\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res++;\n }\n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res++;\n }\n }\n else if(j==n-1){\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res++;\n }\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res++;\n } \n }\n else{\n if(hata[i-1][j-1]==mon[0][0] && hata[i-1][j]==mon[0][1] &&\n hata[i][j-1]==mon[1][0] && hata[i][j]==mon[1][1]){\n res++;\n }\n if(hata[i-1][j]==mon[0][0] && hata[i-1][j+1]==mon[0][1] &&\n hata[i][j]==mon[1][0] && hata[i][j+1]==mon[1][1]){\n res++;\n }\n if(hata[i][j-1]==mon[0][0] && hata[i][j]==mon[0][1] &&\n hata[i+1][j-1]==mon[1][0] && hata[i+1][j]==mon[1][1]){\n res++;\n } \n if(hata[i][j]==mon[0][0] && hata[i][j+1]==mon[0][1] &&\n hata[i+1][j]==mon[1][0] && hata[i+1][j+1]==mon[1][1]){\n res++;\n }\n }\n hata[i][j]=now;\n ans=max(ans,res);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4492, "score_of_the_acc": -0.2721, "final_rank": 11 }, { "submission_id": "aoj_0598_9488097", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <string>\nusing namespace std;\n\nint main() {\n int H, W;\n scanf(\"%d %d\", &H, &W);\n\n // マップの動的配列を作成\n char** map = new char*[H];\n for (int i = 0; i < H; i++) map[i] = new char[W + 1];\n\n // マップの入力\n for (int i = 0; i < H; i++) scanf(\"%s\", map[i]);\n\n char emblem[2][3];\n scanf(\"%s\", emblem[0]);\n scanf(\"%s\", emblem[1]);\n\n int base = 0;\n\n // ベースとなるパターンのカウント\n for (int row = 0; row < H - 1; row++) {\n for (int col = 0; col < W - 1; col++) {\n if (map[row][col] == emblem[0][0] && map[row][col + 1] == emblem[0][1] &&\n map[row + 1][col] == emblem[1][0] && map[row + 1][col + 1] == emblem[1][1]) {\n base++;\n }\n }\n }\n\n int max_add = 0;\n char pre_char, array[4] = \"JOI\";\n\n // 各マップの位置に対して、文字を変更して最大の追加パターンを計算\n for (int row = 0; row < H; row++) {\n for (int col = 0; col < W; col++) {\n pre_char = map[row][col];\n\n int pre_num = 0;\n\n // 現在のパターン数をカウント\n if (row - 1 >= 0 && col - 1 >= 0) {\n if (map[row - 1][col - 1] == emblem[0][0] && map[row - 1][col] == emblem[0][1] &&\n map[row][col - 1] == emblem[1][0] && map[row][col] == emblem[1][1]) pre_num++;\n }\n if (row - 1 >= 0 && col + 1 <= W - 1) {\n if (map[row - 1][col] == emblem[0][0] && map[row - 1][col + 1] == emblem[0][1] &&\n map[row][col] == emblem[1][0] && map[row][col + 1] == emblem[1][1]) pre_num++;\n }\n if (row + 1 <= H - 1 && col - 1 >= 0) {\n if (map[row][col - 1] == emblem[0][0] && map[row][col] == emblem[0][1] &&\n map[row + 1][col - 1] == emblem[1][0] && map[row + 1][col] == emblem[1][1]) pre_num++;\n }\n if (row + 1 <= H - 1 && col + 1 <= W - 1) {\n if (map[row][col] == emblem[0][0] && map[row][col + 1] == emblem[0][1] &&\n map[row + 1][col] == emblem[1][0] && map[row + 1][col + 1] == emblem[1][1]) pre_num++;\n }\n\n // 文字を変更して追加パターン数を計算\n for (int i = 0; i < 3; i++) {\n map[row][col] = array[i];\n\n int tmp_num = 0;\n if (row - 1 >= 0 && col - 1 >= 0) {\n if (map[row - 1][col - 1] == emblem[0][0] && map[row - 1][col] == emblem[0][1] &&\n map[row][col - 1] == emblem[1][0] && map[row][col] == emblem[1][1]) tmp_num++;\n }\n if (row - 1 >= 0 && col + 1 <= W - 1) {\n if (map[row - 1][col] == emblem[0][0] && map[row - 1][col + 1] == emblem[0][1] &&\n map[row][col] == emblem[1][0] && map[row][col + 1] == emblem[1][1]) tmp_num++;\n }\n if (row + 1 <= H - 1 && col - 1 >= 0) {\n if (map[row][col - 1] == emblem[0][0] && map[row][col] == emblem[0][1] &&\n map[row + 1][col - 1] == emblem[1][0] && map[row + 1][col] == emblem[1][1]) tmp_num++;\n }\n if (row + 1 <= H - 1 && col + 1 <= W - 1) {\n if (map[row][col] == emblem[0][0] && map[row][col + 1] == emblem[0][1] &&\n map[row + 1][col] == emblem[1][0] && map[row + 1][col + 1] == emblem[1][1]) tmp_num++;\n }\n\n max_add = max(max_add, tmp_num - pre_num);\n }\n\n // 元の文字に戻す\n map[row][col] = pre_char;\n }\n }\n\n // 最終結果を出力\n printf(\"%d\\n\", base + max_add);\n\n // 動的配列の解放\n for (int i = 0; i < H; i++) delete[] map[i];\n delete[] map;\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3984, "score_of_the_acc": -0.089, "final_rank": 1 }, { "submission_id": "aoj_0598_9004199", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll M, N;\n cin >> M >> N;\n vc<string> A(M), B(2);\n rep(i, M) cin >> A[i];\n rep(i, 2) cin >> B[i];\n vvv(ll, c, M, N, 3, 0);\n map<char,ll> d;\n d['J'] = 0;\n d['O'] = 1;\n d['I'] = 2;\n ll ans = 0;\n rep(i, M-1) rep(j, N-1) {\n ll diff = 0;\n ll dy = -1;\n ll dx = -1;\n rep(x, 2) rep(y, 2) {\n if (A[i+y][j+x] != B[y][x]) {\n diff++;\n dy = y;\n dx = x;\n }\n }\n if (diff == 0) {\n ans++;\n } elif (diff == 1) {\n c[i+dy][j+dx][d[B[dy][dx]]]++;\n }\n }\n ll max_diff = 0;\n rep(i, M) rep(j, N) rep(k, 3) chmax(max_diff, c[i][j][k]);\n ans += max_diff;\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 59044, "score_of_the_acc": -1.2174, "final_rank": 20 }, { "submission_id": "aoj_0598_7621497", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll modPow(long long a, long long n, long long p) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\nll gcd(ll(a), ll(b)) {\n if (a == 0)return b;\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\nll sqrtz(ll N) {\n ll L = 0;\n ll R = sqrt(N) + 10000;\n while (abs(R - L) > 1) {\n ll mid = (R + L) / 2;\n if (mid * mid <= N)L = mid;\n else R = mid;\n }\n return L;\n\n}\n\n\n\n\nll M,N;\nvector<vector<char>> C,P(2,vector<char>(2));\n\nll all_match(){\n ll h=C.size();\n ll w=C[0].size();\n ll res=0;\n rep(i,h-1)rep(j,w-1){\n ll cnt=0;\n rep(y,2)rep(x,2)if(C[i+y][j+x]==P[y][x])cnt++;\n if(cnt==4)res++;\n }\n return res;\n}\n\nll match(ll a,ll b){\n ll res=0;\n rep(i,2)rep(j,2){\n ll cnt=0;\n rep(y,2)rep(x,2)if(C[a-1+i+y][b-1+j+x]==P[y][x])cnt++;\n if(cnt==4)res++;\n }\n return res;\n}\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n cin>>M>>N;\n C.assign(M+2,vector<char>(N+2,'?'));\n rep(i,M){\n string S;\n cin>>S;\n rep(j,N)C[i+1][j+1]=S[j];\n }\n rep(p,2){\n string S;\n cin>>S;\n rep(q,2)P[p][q]=S[q];\n }\n ll an=all_match();\n ll bn=an;\n string T=\"JOI\";\n for(ll h=1;h<=M;h++)for(ll w=1;w<=N;w++){\n char moto=C[h][w];\n rep(k,3){\n ll res=match(h,w);\n C[h][w]=T[k];\n res-=match(h,w);\n chmax(bn,an-res);\n C[h][w]=moto;\n }\n \n }\n cout<<bn<<endl;\n\n \n}", "accuracy": 1, "time_ms": 160, "memory_kb": 4544, "score_of_the_acc": -0.6644, "final_rank": 17 }, { "submission_id": "aoj_0598_6846963", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint main(){\n\tint m,n;\n\tstring a[1000],b[2];\n\tcin>>m>>n;\n\tfor(int i=0;i<m;i++)\n\t\tcin>>a[i];\n\tcin>>b[0]>>b[1];\n\tint cnt=0;\n\tfor(int i=0;i<m-1;i++){\n\t\tfor(int j=0;j<n-1;j++){\n\t\t\tbool f=1;\n\t\t\tfor(int i2=0;i2<2;i2++)\n\t\t\t\tfor(int j2=0;j2<2;j2++)\n\t\t\t\t\tif(a[i+i2][j+j2]!=b[i2][j2])\n\t\t\t\t\t\tf=0;\n\t\t\tif(f)\n\t\t\t\tcnt++;\n\t\t}\n\t}\n\tint ans=cnt;\n\tfor(int i=0;i<m;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tchar c=a[i][j];\n\t\t\t\tint tmp=cnt;\n\t\t\t\tfor(int i2=i-1;i2<=i;i2++){\n\t\t\t\t\tfor(int j2=j-1;j2<=j;j2++){\n\t\t\t\t\t\tif(0<=i2&&i2<m-1&&0<=j2&&j2<n-1){\n\t\t\t\t\t\t\tbool f=1;\n\t\t\t\t\t\t\tfor(int i3=0;i3<2;i3++)\n\t\t\t\t\t\t\t\tfor(int j3=0;j3<2;j3++)\n\t\t\t\t\t\t\t\t\tif(a[i2+i3][j2+j3]!=b[i3][j3])\n\t\t\t\t\t\t\t\t\t\tf=0;\n\t\t\t\t\t\t\tif(f)\n\t\t\t\t\t\t\t\ttmp--;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\ta[i][j]=\"JOI\"[k];\n\t\t\t\tfor(int i2=i-1;i2<=i;i2++){\n\t\t\t\t\tfor(int j2=j-1;j2<=j;j2++){\n\t\t\t\t\t\tif(0<=i2&&i2<m-1&&0<=j2&&j2<n-1){\n\t\t\t\t\t\t\tbool f=1;\n\t\t\t\t\t\t\tfor(int i3=0;i3<2;i3++)\n\t\t\t\t\t\t\t\tfor(int j3=0;j3<2;j3++)\n\t\t\t\t\t\t\t\t\tif(a[i2+i3][j2+j3]!=b[i3][j3])\n\t\t\t\t\t\t\t\t\t\tf=0;\n\t\t\t\t\t\t\tif(f)\n\t\t\t\t\t\t\t\ttmp++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tans=max(ans,tmp);\n\t\t\t\ta[i][j]=c;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5348, "score_of_the_acc": -0.3746, "final_rank": 14 }, { "submission_id": "aoj_0598_6317145", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define endl \"\\n\"\n#define all(v) v.begin(), v.end()\n#define rep(i, begin, end) for(auto i = (begin); i < (end); i++)\n#define rrep(i, end, begin) for(auto i = (end) - 1; i >= (begin); i--)\ntemplate<class T> inline bool chmin(T& a, T b){ if (a > b){ a = b; return true; } return false; }\ntemplate<class T> inline bool chmax(T& a, T b){ if (a < b){ a = b; return true; } return false; }\ntemplate<class T> inline T roundup(T a, T b){ return (a + b - 1) / b; }\nconstexpr int dy[] = {0, 1, 0, -1, 1, 1, -1, -1, 0};\nconstexpr int dx[] = {1, 0, -1, 0, 1, -1, 1, -1, 0};\nusing ll = long long;\nconstexpr ll INF = 1e9;\n/* #include <atcoder/all>\nusing namespace atcoder;\nusing mint = modint1000000007;\nostream& operator<<(ostream& os, const mint& n){ os << n.val(); return os; }\nistream& operator>>(istream& is, mint& n){ ll m; is >> m; n = m; return is; } */\nstruct Edge{ int to; ll cost; Edge(int to, ll cost) : to(to), cost(cost) {} };\nusing Graph = vector<vector<int>>;\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n int h, w;\n cin >> h >> w;\n vector a(h, vector(w, '.'));\n rep(i, 0, h) rep(j, 0, w) cin >> a[i][j];\n vector t(2, vector(2, '.'));\n rep(i, 0, 2) rep(j, 0, 2) cin >> t[i][j];\n \n // 元のスコア\n int base = 0;\n rep(i, 0, h - 1) rep(j, 0, w - 1){\n bool ok = true;\n rep(k, 0, 2) rep(l, 0, 2) if(t[k][l] != a[i + k][j + l]) ok = false;\n base += ok;\n }\n int ans = base;\n // 変える位置と文字を全探索\n string joi = \"JOI\";\n rep(i, 0, h) rep(j, 0, w) for(const auto& ch : joi){\n int cand = base;\n // (i, j) を含む紋章の数[変更前]\n int cnt = 0;\n bool ok = true;\n if(i > 0 && j > 0){\n rep(y, -1, 1) rep(x, -1, 1){\n if(t[y + 1][x + 1] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i < h - 1 && j < w - 1){\n ok = true;\n rep(y, 0, 2) rep(x, 0, 2){\n if(t[y][x] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i > 0 && j < w - 1){\n ok = true;\n rep(y, -1, 1) rep(x, 0, 2){\n if(t[y + 1][x] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i < h - 1 && j > 0){\n ok = true;\n rep(y, 0, 2) rep(x, -1, 1){\n if(t[y][x + 1] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n cand -= cnt;\n \n char pch = a[i][j];\n a[i][j] = ch;\n // (i, j) を含む紋章の数[変更後]\n cnt = 0;\n if(i > 0 && j > 0){\n ok = true;\n rep(y, -1, 1) rep(x, -1, 1){\n if(t[y + 1][x + 1] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i < h - 1 && j < w - 1){\n ok = true;\n rep(y, 0, 2) rep(x, 0, 2){\n if(t[y][x] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i > 0 && j < w - 1){\n ok = true;\n rep(y, -1, 1) rep(x, 0, 2){\n if(t[y + 1][x] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n if(i < h - 1 && j > 0){\n ok = true;\n rep(y, 0, 2) rep(x, -1, 1){\n if(t[y][x + 1] != a[i + y][j + x]) ok = false;\n }\n cnt += ok;\n }\n cand += cnt;\n chmax(ans, cand);\n a[i][j] = pch;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4468, "score_of_the_acc": -0.2717, "final_rank": 10 }, { "submission_id": "aoj_0598_6291383", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e10;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nbool check(vector<string>&S, vector<string>&T, ll sx, ll sy, char ch, ll x, ll y) {\n for (ll i = 0; i <= 1; i++) {\n for (ll j = 0; j <= 1; j++) {\n if (sx+i == x && sy+j == y) {\n if (T[i][j] != ch) return false;\n }\n else {\n if (T[i][j] != S[sx + i][sy + j]) return false;\n }\n }\n }\n return true;\n}\nvoid solve() {\n ll N, M; cin >> M >> N;\n vector<string>S(M); input_arr(S, M);\n vector<string>T(2); input_arr(T, 2);\n ll sum = 0;\n for (ll i = 0; i < M - 1; i++) {\n for (ll j = 0; j < N - 1; j++) {\n sum += check(S, T, i, j, S[i][j], i, j);\n }\n }\n ll dx[4] = {-1, -1, 0, 0}, dy[4] = {0, -1, 0, -1};\n char ch[3] = {'J', 'O', 'I'};\n ll sum2 = 0;\n for (ll i = 0; i < M; i++) {\n for (ll j = 0; j < N; j++) {\n for (ll k = 0; k < 3; k++) {\n ll num = 0;\n for (ll m = 0; m < 4; m++) {\n ll x = i + dx[m], y = j + dy[m];\n if (x < 0 || x >= M -1 || y < 0 || y >= N - 1) continue;\n if (!check(S, T, x, y, S[i][j], i, j) && check(S, T, x, y, ch[k], i, j)) num++;\n else if (check(S, T, x, y, S[i][j], i, j) && !check(S, T, x, y, ch[k], i, j)) num--;\n }\n sum2 = max(sum2, num);\n }\n }\n }\n cout <<sum + sum2 << endl;\n}\nint main() {\n ll T=1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 5368, "score_of_the_acc": -0.6358, "final_rank": 16 }, { "submission_id": "aoj_0598_6050174", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w);\n vector<string> A(h),B(2);\n in(A,B);\n int cnt=0,ans=0,d1,d2;\n rep(y,h-1){\n rep(x,w-1){\n cnt+=(A[y][x]==B[0][0]&&A[y][x+1]==B[0][1]\n &&A[y+1][x]==B[1][0]&&A[y+1][x+1]==B[1][1]);\n }\n }\n chmax(ans,cnt);\n vector<char> C={'J','O','I'};\n rep(y,h){\n rep(x,w){\n char pre=A[y][x];\n d1=d2=0;\n for(int dy=-1;dy<=0;dy++){\n for(int dx=-1;dx<=0;dx++){\n if(y+dy<0||x+dx<0||y+dy+1>=h||x+dx+1>=w)continue;\n d1+=(A[y+dy][x+dx]==B[0][0]&&A[y+dy][x+dx+1]==B[0][1]\n &&A[y+dy+1][x+dx]==B[1][0]&&A[y+dy+1][x+dx+1]==B[1][1]);\n }\n }\n rep(i,3){\n A[y][x]=C[i];\n d2=0;\n for(int dy=-1;dy<=0;dy++){\n for(int dx=-1;dx<=0;dx++){\n if(y+dy<0||x+dx<0||y+dy+1>=h||x+dx+1>=w)continue;\n d2+=(A[y+dy][x+dx]==B[0][0]&&A[y+dy][x+dx+1]==B[0][1]\n &&A[y+dy+1][x+dx]==B[1][0]&&A[y+dy+1][x+dx+1]==B[1][1]);\n }\n }\n chmax(ans,cnt-d1+d2);\n }\n A[y][x]=pre;\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 5464, "score_of_the_acc": -0.2897, "final_rank": 12 }, { "submission_id": "aoj_0598_5858380", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\nint m, n;\nchar f[1000][1000];\nchar c[2][2];\n\npair<int, pair<int, int>> Compare(int i,int j)\n{\n\tif (i < 0 || i >= m - 1 || j < 0 || j >= n - 1)\n\t\treturn make_pair(5, make_pair(-1, -1));\n\n\tint diff = 0;\n\tpair<int, int> pos_diff = make_pair(-1, -1);\n\tif (f[i][j] != c[0][0])\n\t{\n\t\tdiff++;\n\t\tpos_diff = make_pair(i, j);\n\t}\n\tif (f[i][j + 1] != c[0][1])\n\t{\n\t\tdiff++;\n\t\tpos_diff = make_pair(i, j + 1);\n\t}\n\tif (f[i + 1][j] != c[1][0])\n\t{\n\t\tdiff++;\n\t\tpos_diff = make_pair(i + 1, j);\n\t}\n\tif (f[i + 1][j + 1] != c[1][1])\n\t{\n\t\tdiff++;\n\t\tpos_diff = make_pair(i + 1, j + 1);\n\t}\n\n\treturn make_pair(diff, pos_diff);\n}\n\nint main()\n{\n\tcin >> m >> n;\n\tfor (int i = 0; i < m; i++)\n\t\tfor (int j = 0;j < n; j++)\n\t\t\tcin >> f[i][j];\n\tfor (int i = 0; i < 2; i++)\n\t\tfor (int j = 0; j < 2; j++)\n\t\t\tcin >> c[i][j];\n\tint ans = 0;\n\tint maxDelta = 0;\n\tfor (int i = 0; i < m - 1; i++)\n\t{\n\t\tfor (int j = 0; j < n - 1; j++)\n\t\t{\n\t\t\tpair<int,pair<int,int>> res = Compare(i, j);\n\t\t\tint diff = res.first;\n\t\t\tans += (diff == 0);\n\t\t\tif (diff == 1)\n\t\t\t{\n\t\t\t\tint di = res.second.first;\n\t\t\t\tint dj = res.second.second;\n\t\t\t\tint before = (Compare(di - 1, dj - 1).first == 0) + (Compare(di - 1, dj).first == 0)\n\t\t\t\t\t+ (Compare(di, dj - 1).first == 0) + (Compare(di, dj).first == 0);\n\t\t\t\tint tmp = f[di][dj];\n\t\t\t\tf[di][dj] = c[di - i][dj - j];\n\t\t\t\tint after = (Compare(di - 1, dj - 1).first == 0) + (Compare(di - 1, dj).first == 0)\n\t\t\t\t\t+ (Compare(di, dj - 1).first == 0) + (Compare(di, dj).first == 0);\n\n\t\t\t\tmaxDelta = max(maxDelta, after - before);\n\t\t\t\tf[di][dj] = tmp;\n\t\t\t}\n\t\t}\n\t}\n\tans += maxDelta;\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4108, "score_of_the_acc": -0.2217, "final_rank": 5 }, { "submission_id": "aoj_0598_5435105", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(){\n int h,w;\n cin >> h >> w;\n vector<vector<char>> g(h+2, vector<char>(w+2, 0));\n for(int i=1; i<=h; i++){\n for(int j=1; j<=w; j++){\n cin >> g[i][j];\n }\n }\n vector<vector<char>> ptn(2, vector<char>(2));\n for(int i=0; i<2; i++){\n for(int j=0; j<2; j++){\n cin >> ptn[i][j];\n }\n }\n int num = 0;\n int diff = 0;\n vector<char> d{'J', 'O', 'I'};\n for(int i=1; i<=h; i++){\n for(int j=1; j<=w; j++){\n d.push_back(g[i][j]);\n for(int c=0; c<4; c++){\n g[i][j] = d[c];\n int sub = 0;\n for(int k=-1; k<=0; k++){\n for(int l=-1; l<=0; l++){\n bool ok = true;\n for(int x=0; x<2; x++){\n for(int y=0; y<2; y++){\n if(g[i+k+x][j+l+y] != ptn[x][y]){\n ok = false;\n break;\n }\n }\n }\n if(ok){\n if(c == 3){\n num++;\n }else if(d[c] != d[3]){\n sub++;\n }\n }\n }\n }\n diff = max(diff, sub);\n }\n d.pop_back();\n }\n }\n cout << num/4 + diff << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 4472, "score_of_the_acc": -0.4022, "final_rank": 15 }, { "submission_id": "aoj_0598_5310016", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n INT(h,w);\n vector<string> f(h);\n rep(i,h)cin >> f[i];\n vector<string> joi(2);\n rep(i,2)cin >> joi[i];\n auto check = [&](pii a,pii b,pii c,pii d){\n auto valid = [&](int x,int y){\n return x >= 0 && y >= 0 && x < h && y < w;\n };\n {\n auto [x,y] = a;\n if(!valid(x,y))return false;\n if(f[x][y] != joi[0][0])return false;\n }\n {\n auto [x,y] = b;\n if(!valid(x,y))return false;\n if(f[x][y] != joi[1][0])return false;\n }\n {\n auto [x,y] = c;\n if(!valid(x,y))return false;\n if(f[x][y] != joi[0][1])return false;\n }\n {\n auto [x,y] = d;\n if(!valid(x,y))return false;\n if(f[x][y] != joi[1][1])return false;\n }\n return true;\n }; \n int sum = 0;\n rep(i,h)rep(j,w){\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))sum++;\n }\n // trace(ret);\n ll ret = 0;\n rep(i,h)rep(j,w){\n //[i,j]\n {\n ll tmp = sum;\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp--;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp--;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp--;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp--;\n char c = f[i][j];\n f[i][j] = 'J';\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp++;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp++;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp++;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp++;\n chmax(ret,tmp);\n f[i][j] = c;\n }\n {\n ll tmp = sum;\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp--;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp--;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp--;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp--;\n char c = f[i][j];\n f[i][j] = 'O';\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp++;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp++;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp++;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp++;\n chmax(ret,tmp);\n f[i][j] = c;\n }\n {\n ll tmp = sum;\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp--;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp--;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp--;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp--;\n char c = f[i][j];\n f[i][j] = 'I';\n if(check({i,j},{i+1,j},{i,j+1},{i+1,j+1}))tmp++;\n if(check({i-1,j-1},{i,j-1},{i-1,j},{i,j}))tmp++;\n if(check({i,j-1},{i+1,j-1},{i,j},{i+1,j}))tmp++;\n if(check({i-1,j},{i,j},{i-1,j+1},{i,j+1}))tmp++;\n chmax(ret,tmp);\n f[i][j] = c;\n }\n }\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4440, "score_of_the_acc": -0.2277, "final_rank": 7 }, { "submission_id": "aoj_0598_5167637", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint x[1000][1000][3]={0};\nchar a[1000][1001],b[2][3],c[4]=\"JOI\";\nint main(void)\n{\n\tint cnt,m,n,ans=0,mx,i,j,flg,k;\n\tscanf(\"%d %d\",&n,&m);\n\tfor(i=0;i<n;i++)\tscanf(\"%s\",a[i]);\n\tscanf(\"%s %s\",b[0],b[1]);\n\tfor(i=0;i<n-1;i++){\n\t\tfor(j=0;j<m-1;j++){\t\n\t\t\tcnt=0;\tflg=0;\n\t\t\tif(a[i][j]==b[0][0])\tcnt++;\n\t\t\telse\tflg=1;\n\t\t\tif(a[i][j+1]==b[0][1])\tcnt++;\n\t\t\telse\tflg=2;\n\t\t\tif(a[i+1][j]==b[1][0])\tcnt++;\n\t\t\telse\tflg=3;\n\t\t\tif(a[i+1][j+1]==b[1][1])\tcnt++;\n\t\t\telse\tflg=4;\t\n\t\t\tif(cnt==4){\n\t\t\t\tans++;\n\t\t\t\tfor(k=0;k<3;k++){\n\t\t\t\t\tif(c[k]!=a[i][j]){\n\t\t\t\t\t\tx[i][j][k]--;\n\t\t\t\t\t}\n\t\t\t\t\tif(c[k]!=a[i][j+1]){\n\t\t\t\t\t\tx[i][j+1][k]--;\n\t\t\t\t\t}\n\t\t\t\t\tif(c[k]!=a[i+1][j]){\n\t\t\t\t\t\tx[i+1][j][k]--;\n\t\t\t\t\t}\n\t\t\t\t\tif(c[k]!=a[i+1][j+1]){\n\t\t\t\t\t\tx[i+1][j+1][k]--;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(cnt==3){\n\t\t\t\tif(flg==1){\n\t\t\t\t\tif(b[0][0]=='J')\tx[i][j][0]++;\n\t\t\t\t\tif(b[0][0]=='O')\tx[i][j][1]++;\n\t\t\t\t\tif(b[0][0]=='I')\tx[i][j][2]++;\n\t\t\t\t}\n\t\t\t\tif(flg==2){\n\t\t\t\t\tif(b[0][1]=='J')\tx[i][j+1][0]++;\n\t\t\t\t\tif(b[0][1]=='O')\tx[i][j+1][1]++;\n\t\t\t\t\tif(b[0][1]=='I')\tx[i][j+1][2]++;\n\t\t\t\t}\n\t\t\t\tif(flg==3){\n\t\t\t\t\tif(b[1][0]=='J')\tx[i+1][j][0]++;\n\t\t\t\t\tif(b[1][0]=='O')\tx[i+1][j][1]++;\n\t\t\t\t\tif(b[1][0]=='I')\tx[i+1][j][2]++;\n\t\t\t\t}\n\t\t\t\tif(flg==4){\n\t\t\t\t\tif(b[1][1]=='J')\tx[i+1][j+1][0]++;\n\t\t\t\t\tif(b[1][1]=='O')\tx[i+1][j+1][1]++;\n\t\t\t\t\tif(b[1][1]=='I')\tx[i+1][j+1][2]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tmx=ans;\n\tfor(i=0;i<n;i++){\n\t\tfor(j=0;j<m;j++){\n\t\t\tfor(k=0;k<3;k++){\n\t\t\t\tmx=max(mx,ans+x[i][j][k]);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\",mx);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15448, "score_of_the_acc": -0.2098, "final_rank": 4 }, { "submission_id": "aoj_0598_5086141", "code_snippet": "// clang-format off\n//#pragma GCC optimize(\"Ofast\")\n//#pragma GCC target(\"avx\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define stoi stoll\n#define Endl endl\n#define itn int\n#define fi first\n#define se second\n#define rep(i, n) for(int i=0, i##_len=(n); i<i##_len; i++)\n#define rep2(i, a, b) for (int i = (int)(a), i##_len=(b); i < i##_len; i++)\n#define rep3(i, a, b) for (int i = (int)(a), i##_len=(b); i >= i##_len; i--)\n#define FOR(i, a) for (auto &i: a)\n#define ALL(obj) begin(obj), end(obj)\n#define _max(x) *max_element(ALL(x))\n#define _min(x) *min_element(ALL(x))\n#define _sum(x) accumulate(ALL(x), 0LL)\n#define LOWER_BOUND(A, key) distance(begin(A), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(begin(A), upper_bound(ALL(A), key))\n\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int INF = (int)(1e13 + 7);\nconst double EPS = 1e-8;\nconst double PI = 3.14159265358979;\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = vector<vector<T>>;\ntemplate <class T> using VVV = vector<vector<vector<T>>>;\ntemplate <class T, class S> using P = pair<T, S>;\ntemplate<class T> bool chmax(T &a, const T &b) {if (a < b) {a = b;return true;}return false;}\ntemplate<class T> bool chmin(T &a, const T &b) {if (b < a) {a = b;return true;}return false;}\nint _ceil(int a, int b) { return (a >= 0 ? (a + (b - 1)) / b : (a - (b - 1)) / b); }\nint _mod(int &a) {a = a >= 0 ? a % MOD : a - (MOD * _ceil(a, MOD));return a;}\nint _pow(int a, int b) {int res = 1;for (a %= MOD; b; a = a * a % MOD, b >>= 1)if (b & 1) res = res * a % MOD;return res;}\nstruct mint {long long x;mint(long long x = 0) : x((x % MOD + MOD) % MOD) {}mint operator-() const { return mint(-x); }mint &operator+=(const mint a) {if ((x += a.x) >= MOD) x -= MOD;return *this;}mint &operator-=(const mint a) {if ((x += MOD - a.x) >= MOD) x -= MOD;return *this;}mint &operator*=(const mint a) { (x *= a.x) %= MOD;return *this; }mint operator+(const mint a) const { return mint(*this) += a; }mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; }mint pow(long long t) const {if (!t) return 1;mint a = pow(t >> 1);a *= a;if (t & 1) a *= *this;return a;}mint inv() const { return pow(MOD - 2); }mint &operator/=(const mint a) { return *this *= a.inv(); }mint operator/(const mint a) const { return mint(*this) /= a; }};istream &operator>>(istream &is, mint &a) { return is >> a.x; }ostream &operator<<(ostream &os, const mint &a) { return os << a.x; }\n// clang-format on\n\nsigned main() {\n cin.tie(nullptr);\n cout.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(15);\n int M, N;\n cin >> M >> N;\n V<string> flag(M + 2);\n string ioj = \"IOJ\";\n flag[0] = string(N + 2, '#');\n flag[M + 1] = string(N + 2, '#');\n rep(i, M) cin >> flag[i + 1];\n rep(i, M) flag[i + 1] = \"#\" + flag[i + 1] + \"#\";\n V<string> mark(2);\n rep(i, 2) cin >> mark[i];\n int num = 0;\n rep2(i, 1, M + 1) rep2(j, 1, N + 1) {\n bool yes = true;\n rep(k, 2) rep(l, 2) {\n if (flag[i + k][j + l] != mark[k][l]) yes = false;\n }\n if (yes) num++;\n }\n int ans = 0;\n rep2(i, 1, M + 1) rep2(j, 1, N + 1) {\n int num_around = 0;\n rep2(k, i - 1, i + 1) rep2(l, j - 1, j + 1) {\n bool yes = true;\n rep(m, 2) rep(n, 2) {\n if (flag[k + m][l + n] != mark[m][n]) yes = false;\n }\n if (yes) num_around++;\n }\n char temp = flag[i][j];\n FOR(z, ioj) {\n flag[i][j] = z;\n int num_temp = 0;\n rep2(k, i - 1, i + 1) rep2(l, j - 1, j + 1) {\n bool yes = true;\n rep(m, 2) rep(n, 2) {\n if (flag[k + m][l + n] != mark[m][n]) yes = false;\n }\n if (yes) num_temp++;\n }\n chmax(ans, num - num_around + num_temp);\n }\n flag[i][j] = temp;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5088, "score_of_the_acc": -0.1525, "final_rank": 3 }, { "submission_id": "aoj_0598_5085972", "code_snippet": "#pragma region Macros\n#include <bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define rep(i, n) for(ll i = 0; i < n; ++i)\n#define drep(i,n) for(ll i = n-1;i >= 0;i--)\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define eb emplace_back\n#define vi vector<int>\n#define vll vector<ll>\n#define vpi vector<pii>\n#define vpll vector<pll>\n#define endl '\\n'\n#define overload2(_1, _2, name, ...) name\n#define vec(type, name, ...) vector<type> name(__VA_ARGS__)\n#define VEC(type, name, size)\\\n vector<type> name(size);\\\n IN(name)\n#define vv(type, name, h, ...) vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define VV(type, name, h, w)\\\n vector<vector<type>> name(h, vector<type>(w));\\\n IN(name)\n#define vvv(type, name, h, w, ...) vector<vector<vector<type>>> name(h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...)\\\n vector<vector<vector<vector<type>>>> name(a, vector<vector<vector<type>>>(b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n#define fi first\n#define se second\n#define all(c) begin(c), end(c)\n#define lb(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define ub(c, x) distance((c).begin(), upper_bound(all(c), (x)))\nusing namespace std;\ntemplate <class T> using pq = priority_queue<T>;\ntemplate <class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n#define si(c) (int)(c).size()\n#define INT(...)\\\n int __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define LL(...)\\\n ll __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define STR(...)\\\n string __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define CHR(...)\\\n char __VA_ARGS__;\\\n IN(__VA_ARGS__)\n#define DBL(...)\\\n double __VA_ARGS__;\\\n IN(__VA_ARGS__)\nint scan() { return getchar(); }\nvoid scan(int &a) { cin >> a; }\nvoid scan(long long &a) { cin >> a; }\nvoid scan(char &a) { cin >> a; }\nvoid scan(double &a) { cin >> a; }\nvoid scan(string &a) { cin >> a; }\ntemplate <class T, class S> void scan(pair<T, S> &p) { scan(p.first), scan(p.second); }\ntemplate <class T> void scan(vector<T> &);\ntemplate <class T> void scan(vector<T> &a) {\n for(auto &i : a) scan(i);\n}\ntemplate <class T> void scan(T &a) { cin >> a; }\nvoid IN() {}\ntemplate <class Head, class... Tail> void IN(Head &head, Tail &... tail) {\n scan(head);\n IN(tail...);\n}\ntemplate <class T, class S> inline bool chmax(T &a, S b) {\n if(a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T, class S> inline bool chmin(T &a, S b) {\n if(a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\nvi iota(int n) {\n vi a(n);\n iota(all(a), 0);\n return a;\n}\ntemplate <typename T> vi iota(vector<T> &a, bool greater = false) {\n vi res(a.size());\n iota(all(res), 0);\n sort(all(res), [&](int i, int j) {\n if(greater) return a[i] > a[j];\n return a[i] < a[j];\n });\n return res;\n}\n#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())\ntemplate <class T> T POW(T x, int n) {\n T res = 1;\n for(; n; n >>= 1, x *= x)\n if(n & 1) res *= x;\n return res;\n}\nvector<pll> factor(ll x) {\n vector<pll> ans;\n for(ll i = 2; i * i <= x; i++)\n if(x % i == 0) {\n ans.push_back({i, 1});\n while((x /= i) % i == 0) ans.back().second++;\n }\n if(x != 1) ans.push_back({x, 1});\n return ans;\n}\ntemplate <class T> vector<T> divisor(T x) {\n vector<T> ans;\n for(T i = 1; i * i <= x; i++)\n if(x % i == 0) {\n ans.pb(i);\n if(i * i != x) ans.pb(x / i);\n }\n return ans;\n}\ntemplate <typename T> void zip(vector<T> &x) {\n vector<T> y = x;\n sort(all(y));\n for(int i = 0; i < x.size(); ++i) { x[i] = lb(y, x[i]); }\n}\nint popcount(ll x) { return __builtin_popcountll(x); }\nint in() {\n int x;\n cin >> x;\n return x;\n}\nll lin() {\n unsigned long long x;\n cin >> x;\n return x;\n}\ntemplate <typename T> struct edge {\n int from, to;\n T cost;\n int id;\n edge(int to, T cost) : from(-1), to(to), cost(cost) {}\n edge(int from, int to, T cost) : from(from), to(to), cost(cost) {}\n edge(int from, int to, T cost, int id) : from(from), to(to), cost(cost), id(id) {}\n edge &operator=(const int &x) {\n to = x;\n return *this;\n }\n operator int() const { return to; }\n};\ntemplate <typename T> using Edges = vector<edge<T>>;\nusing Tree = vector<vector<int>>;\nusing Graph = vector<vector<int>>;\ntemplate <class T> using Wgraph = vector<vector<edge<T>>>;\nGraph getG(int n, int m = -1, bool directed = false, int margin = 1) {\n Tree res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n cin >> a >> b;\n a -= margin, b -= margin;\n res[a].emplace_back(b);\n if(!directed) res[b].emplace_back(a);\n }\n return move(res);\n}\ntemplate <class T> Wgraph<T> getWg(int n, int m = -1, bool directed = false, int margin = 1) {\n Wgraph<T> res(n);\n if(m == -1) m = n - 1;\n while(m--) {\n int a, b;\n T c;\n cin >> a >> b >> c;\n a -= margin, b -= margin;\n res[a].emplace_back(b, c);\n if(!directed) res[b].emplace_back(a, c);\n }\n return move(res);\n}\n#define i128 __int128_t\n#define ull unsigned long long int\ntemplate <typename T> static constexpr T inf = numeric_limits<T>::max() / 2;\nstruct Setup_io {\n Setup_io() {\n ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n cout << fixed << setprecision(15);\n }\n} setup_io;\ntemplate <typename A, typename B>\nostream& operator <<(ostream& out, const pair<A, B>& a) {\nout << \"(\" << a.first << \",\" << a.second << \")\";\nreturn out;\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\nout << \"[\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\nreturn out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& v : a) { out << (first ? \"\" :\", \"); out << v; first = 0;} out << \"}\";\nreturn out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\nout << \"{\"; bool first = true;\nfor (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\nreturn out;\n}\n#define LOCAL\n#ifdef LOCAL\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define trace(...) 42\n#endif\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\ncerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\nconst char* comma = strchr(names + 1, ',');\ncerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n__f(comma + 1, args...);\n}\n#pragma endregion\n//#include<atcoder/all>\n//using namespace atcoder;\nint main(){\n INT(h,w);\n vector<string> f(h);\n rep(i,h)cin >> f[i];\n vector<string> joi(2);\n rep(i,2)cin >> joi[i];\n auto valid = [&](int x,int y){\n return x >= 0 && y >= 0 && x < h && y < w;\n };\n auto check = [&](int x,int y){\n //x,y ga hidari ue\n if(!valid(x,y))return 0;\n if(!valid(x+1,y))return 0;\n if(!valid(x,y+1))return 0;\n if(!valid(x+1,y+1))return 0;\n int cnt = 0;\n cnt += f[x][y] == joi[0][0];\n cnt += f[x+1][y] == joi[1][0];\n cnt += f[x][y+1] == joi[0][1];\n cnt += f[x+1][y+1] == joi[1][1];\n if(cnt == 4)return 1;\n return 0;\n };\n int cnt = 0;\n rep(i,h)rep(j,w){\n cnt += check(i,j);\n }\n int ret = 0;\n rep(i,h)rep(j,w){\n //(i,j),(i-1,j),(i,j-1),(i-1,j-1)\n int tmp = 0;\n tmp += check(i,j);\n tmp += check(i-1,j);\n tmp += check(i,j-1);\n tmp += check(i-1,j-1);\n cnt -= tmp;\n rep(num,4){\n char store = f[i][j];\n f[i][j] = joi[num/2][num%2];\n int hoge = 0;\n hoge += check(i,j);\n hoge += check(i-1,j);\n hoge += check(i,j-1);\n hoge += check(i-1,j-1);\n chmax(ret,cnt+hoge);\n f[i][j] = store;\n }\n cnt += tmp;\n }\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4436, "score_of_the_acc": -0.2711, "final_rank": 9 }, { "submission_id": "aoj_0598_5020373", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n// 利益: profit[n] = n コの饅頭を乗っけられるとしたときの最大利益\n// mincost[n] = n コの饅頭を売れるような箱のコストの総和の最小値 \n// mincost を計算する部分は、まさにナップサック問題\nint main() {\n int H, W;\n cin >> H >> W;\n vector<string> fi(H), pat(2);\n for (int i = 0; i < H; ++i) cin >> fi[i];\n for (int i = 0; i < 2; ++i) cin >> pat[i];\n\n auto calc = [&](int i, int j) -> int {\n if (i < 0 || i+1 >= H || j < 0 || j+1 >= W) return 0;\n for (int di = 0; di <= 1; ++di) {\n for (int dj = 0; dj <= 1; ++dj) {\n if (fi[i+di][j+dj] != pat[di][dj]) return 0;\n }\n }\n return 1;\n };\n auto calc2 = [&](int i, int j) -> int {\n return calc(i-1, j-1) + calc(i-1, j) + calc(i, j-1) + calc(i, j);\n };\n\n int res = 0;\n for (int i = 0; i < H; ++i) \n for (int j = 0; j < W; ++j)\n res += calc(i, j);\n int add = 0;\n for (int i = 0; i < H; ++i) {\n for (int j = 0; j < W; ++j) {\n char origin = fi[i][j];\n int before = calc2(i, j);\n\n string joi = \"JOI\";\n for (auto c: joi) {\n fi[i][j] = c;\n int after = calc2(i, j);\n chmax(add, after - before);\n }\n fi[i][j] = origin;\n }\n }\n cout << res + add << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5368, "score_of_the_acc": -0.2445, "final_rank": 8 }, { "submission_id": "aoj_0598_4865009", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <iomanip> // setprecision\n#include <complex> // complex\n#include <math.h> \n#include <functional>\n#include <cassert>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nconstexpr ll INF = 1e18;\nconstexpr int inf = 1e9;\nconstexpr double eps = 1e-9;\nconstexpr ll mod = 1000000007;\n// constexpr ll mod = 998244353;\nconst int dx[8] = {1, 0, -1, 0,1,1,-1,-1};\nconst int dy[8] = {0, 1, 0, -1,1,-1,1,-1};\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n// --------------------------------------------------------------------------\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int H,W;\n cin >> H >> W;\n vector<string> G(H);\n for(int i=0; i<H; i++) cin >> G[i];\n vector<string> ori(2);\n for(int i=0; i<2; i++) cin >> ori[i];\n\n auto check = [&](int h,int w){\n for(int i=0; i<2; i++){\n for(int j=0; j<2; j++){\n if(G[h+i][w+j] != ori[i][j]) return false;\n }\n }\n return true;\n };\n\n auto check2 = [&](int h,int w){\n int now = 0;\n for(int k=-1; k<=0; k++){\n for(int l=-1; l<=0; l++){\n if(h+k>=0 && w+l>=0 && h+k+1<H && w+l+1<W){\n now += check(h+k,w+l);\n }\n }\n }\n return now;\n };\n\n int sum = 0;\n for(int i=0; i<H-1; i++){\n for(int j=0; j<W-1; j++){\n sum += check(i,j);\n }\n }\n int ans = sum;\n string str = \"JOI\";\n for(int i=0; i<H; i++){\n for(int j=0; j<W; j++){\n int temp = check2(i,j);\n for(int k=0; k<3; k++){\n swap(str[k],G[i][j]);\n chmax(ans,sum-temp+check2(i,j));\n swap(str[k],G[i][j]);\n }\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4420, "score_of_the_acc": -0.1404, "final_rank": 2 }, { "submission_id": "aoj_0598_4804601", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int m, n;\n cin >> m >> n;\n vector<string> g(m), emblem(2);\n cin >> g >> emblem;\n auto match = [&](int i, int j) {\n bool ans = true;\n for(int di = 0; di <= 1; di++) {\n for(int dj = 0; dj <= 1; dj++) {\n ans &= i + di < m and j + dj < n and g[i + di][j + dj] == emblem[di][dj];\n }\n }\n return ans;\n };\n auto matches_around = [&](int i, int j) {\n int matches = 0;\n for(int ii = max(i - 1, 0); ii <= i; ii++) {\n for(int jj = max(j - 1, 0); jj <= j; jj++) {\n matches += match(ii, jj);\n }\n }\n return matches;\n };\n int orig = 0;\n for(int i = 0; i < m - 1; i++) {\n for(int j = 0; j < n - 1; j++) {\n orig += match(i, j);\n }\n }\n int ans = orig;\n for(int i = 0; i < m; i++) {\n for(int j = 0; j < n; j++) {\n char old = g[i][j];\n int old_matches = matches_around(i, j);\n for(char c : {'J', 'O', 'I'}) {\n g[i][j] = c;\n ans = max(ans, orig - old_matches + matches_around(i, j));\n }\n g[i][j] = old;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3872, "score_of_the_acc": -0.8696, "final_rank": 18 }, { "submission_id": "aoj_0598_4729593", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint M, N;\nchar FlagData[1000][1000];\nchar Emblem[2][2];\nconst char WhitePaper[] = { 'J','O','I' };\n\nint calculate(int row, int col) {\n\tint cnt;\n\n\tcnt = 0;\n\tif (row + 1 < M && col + 1 < N) {\n\t\tif (FlagData[row][col] == Emblem[0][0] && FlagData[row][col + 1] == Emblem[0][1] && \n\t\t\tFlagData[row + 1][col] == Emblem[1][0] && FlagData[row + 1][col + 1] == Emblem[1][1]) {\n\t\t\t++cnt;\n\t\t}\n\t}\n\n\tif (row + 1 < M && col - 1 >= 0) {\n\t\tif (FlagData[row][col - 1] == Emblem[0][0] && FlagData[row][col] == Emblem[0][1] &&\n\t\t\tFlagData[row + 1][col - 1] == Emblem[1][0] && FlagData[row + 1][col] == Emblem[1][1]) {\n\t\t\t++cnt;\n\t\t}\n\t}\n\n\tif (row - 1 >= 0 && col + 1 < N) {\n\t\tif (FlagData[row - 1][col] == Emblem[0][0] && FlagData[row - 1][col + 1] == Emblem[0][1] &&\n\t\t\tFlagData[row][col] == Emblem[1][0] && FlagData[row][col + 1] == Emblem[1][1]) {\n\t\t\t++cnt;\n\t\t}\n\t}\n\n\tif (row - 1 >= 0 && col - 1 >= 0) {\n\t\tif (FlagData[row - 1][col - 1] == Emblem[0][0] && FlagData[row - 1][col] == Emblem[0][1] &&\n\t\t\tFlagData[row][col - 1] == Emblem[1][0] && FlagData[row][col] == Emblem[1][1]) {\n\t\t\t++cnt;\n\t\t}\n\t}\n\n\treturn cnt;\n}\n\nint solve() {\n\tint bCnt, aCnt, maxCnt;;\n\tchar ch;\n\n\tmaxCnt = 0;\n\tfor (int i = 0; i < M; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tch = FlagData[i][j];\n\t\t\tbCnt = calculate(i, j);\n\t\t\tfor (int k = 0; k < 3; ++k) {\n\t\t\t\tif (ch == WhitePaper[k]) {\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tFlagData[i][j] = WhitePaper[k];\n\t\t\t\taCnt = calculate(i, j);\n\t\t\t\tmaxCnt = max(maxCnt, aCnt - bCnt);\n\t\t\t}\n\t\t\tFlagData[i][j] = ch;\n\t\t}\n\t}\n\n\treturn maxCnt;\n}\n\nint main() {\n\tint baseCnt;\n\n\tcin >> M >> N;\n\tfor (int i = 0; i < M; ++i) {\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tcin >> FlagData[i][j];\n\t\t}\n\t}\n\tfor (int i = 0; i < 2; ++i) {\n\t\tfor (int j = 0; j < 2; ++j) {\n\t\t\tcin >> Emblem[i][j];\n\t\t}\n\t}\n\tbaseCnt = 0;\n\tfor (int i = 1; i < M; ++i) {\n\t\tfor (int j = 1; j < N; ++j) {\n\t\t\tif (FlagData[i][j] == Emblem[1][1] && FlagData[i][j - 1] == Emblem[1][0] &&\n\t\t\t\tFlagData[i - 1][j] == Emblem[0][1] && FlagData[i - 1][j - 1] == Emblem[0][0]) {\n\t\t\t\t++baseCnt;\n\t\t\t}\n\t\t}\n\t}\n\tcout << baseCnt + solve() << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4108, "score_of_the_acc": -0.2217, "final_rank": 5 }, { "submission_id": "aoj_0598_4668676", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define fcout cout << fixed << setprecision(15)\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nstring joi = \"JOI\";\n\nsigned main() {\n cin.tie(0);\n cout.tie(0);\n ios::sync_with_stdio(false);\n \n int h, w;\n cin >> h >> w;\n vector<string> s(h), tmp(2);\n rep(i, h) cin >> s[i];\n rep(i, 2) cin >> tmp[i];\n\n int defcnt = 0;\n rep(i, h-1) {\n rep(j, w-1) {\n vector<string> now(2);\n now[0] = s[i].substr(j, 2);\n now[1] = s[i+1].substr(j, 2);\n if(now == tmp) defcnt++;\n }\n }\n\n int dif = 0;\n rep(i, h) {\n rep(j, w) {\n char focus = s[i][j];\n rep(k, 3) {\n if(focus == joi[k]) continue;\n s[i][j] = joi[k];\n int nowcnt = 0;\n\n REP(dy, -1, 1) {\n int ny = i + dy;\n REP(dx, -1, 1) {\n // 左上\n int nx = j + dx;\n if(0 <= nx && nx < w-1 && 0 <= ny && ny < h-1) {\n if(s[ny][nx] == tmp[0][0] && s[ny][nx+1] == tmp[0][1] && s[ny+1][nx] == tmp[1][0] && s[ny+1][nx+1] == tmp[1][1]) {\n nowcnt++;\n // cout << nx << \" \" << ny << endl;\n // cout << s[ny][nx] << s[ny][nx+1] << endl;\n // cout << s[ny+1][nx] << s[ny+1][nx+1] << endl;\n }\n }\n }\n }\n chmax(dif, nowcnt);\n //cout << nowcnt << endl;\n\n }\n s[i][j] = focus;\n }\n }\n cout << defcnt + dif << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3948, "score_of_the_acc": -1.0014, "final_rank": 19 } ]
aoj_0601_cpp
フクロモモンガ(Sugar Glider) フクロモモンガのJOI 君が住んでいる森にはユーカリの木が $N$ 本生えており,それらの木には1 から $N$ の番号がついている.木 $i$ の高さは $H_i$ メートルである. JOI 君が相互に直接飛び移ることのできる木の組が $M$ 組あり,各組の木の間を飛び移るためにかかる時間が定まっている.JOI 君が木の間を飛び移っている間は,地面からの高さが1 秒あたり1 メートル下がる.すなわち,JOI 君の現在の地面からの高さが $h$ メートル,木の間を飛び移るためにかかる時間が $t$ 秒であるとき,飛び移った後の地面からの高さは $h - t$ メートルとなる.ただし,$h - t$ が0 よりも小さくなる場合や行き先の木の高さよりも大きくなる場合は飛び移ることができない. さらに,JOI 君は木の側面を上下に移動することによって,地面からの高さを0 メートルから今いる木の高さの範囲で増減させることができる.JOI 君が地面からの高さを1 メートル増加または減少させるためには1 秒の時間がかかる. JOI 君は,木1 の高さ$X$ メートルの位置から木$N$ の頂上(高さ$H_N$ メートルの位置) に行こうとしており,そのためにかかる時間の最小値を知りたい. 課題 各木の高さと,JOI 君が直接飛び移ることができる木の組の情報と,最初JOI 君がいる場所の高さが与えられる.木 $N$ の頂上に行くためにかかる時間の最小値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 $N, M, X$ が空白を区切りとして書かれている.これは,木の本数が $N$ 本,移動できる木の組が $M$ 組あり,最初JOI 君が木1 の高さ $X$ メートルの位置にいることを表す. 続く $N$ 行のうちの $i$ 行目$(1 \leq i \leq N)$ には,整数 $H_i$ が書かれている.これは,木 $i$ の高さが $H_i$ メートルであることを表す. 続く$M$ 行のうちの $j$ 行目$(1 \leq j \leq M)$ には,整数 $A_j, B_j, T_j$ $(1 \leq A_j \leq N, 1 \leq B_j \leq N, A_j \ne B_j)$ が空白を区切りとして書かれている.これは,木 $A_j$ と木 $B_j$ の間を相互に $T_j$ 秒で飛び移ることができることを表している.また,$1 \leq j < k \leq M$ ならば,$(A_j, B_j) \ne (A_k, B_k)$ および$(A_j, B_j) \ne (B_k, A_k)$ を満たす. 出力 標準出力に,木1 の高さ $X$ メートルの位置から木 $N$ の頂上に行くためにかかる時間の最小値を秒単位で表す整数を1 行で出力せよ.ただし,そのような方法がない場合は代わりに -1 を出力せよ. 制限 すべての入力データは以下の条件を満たす. $2 \leq N \leq 100000$ $1 \leq M \leq 300000$ $1 \leq H_i \leq 1000000000 (1 \leq i \leq N)$ $1 \leq T_j \leq 1000000000 (1 \leq j \leq M)$ $0 \leq X \leq H_1$ 入出力例 入力例 1 5 5 0 50 100 25 30 10 1 2 10 2 5 50 2 4 20 4 3 1 5 4 20 出力例 1 110 例えば,以下のように移動すればよい. 1. 木1 を50 メートル登る. 2. 木1 から木2 に飛び移る. 3. 木2 から木4 に飛び移る. 4. 木4 から木5 に飛び移る. 5. 木5 を10 メートル登る. 入力例 2 2 1 0 1 1 1 2 100 出力例 2 -1 JOI 君は木1 から木2 に飛び移ることができない. 入力例 3 4 3 30 50 10 20 50 1 2 10 2 3 10 3 4 10 出力例 3 100 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0601_10853979", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<functional>\nusing namespace std;\nvector<pair<long long, long long>>x[120000];\npair<long long, long long>dist[120000];\nlong long n, m, h, a[320000], b[320000], c[320000], H[120000];\npriority_queue<pair<long long, long long>, vector<pair<long long, long long>>, greater<pair<long long, long long>>>Q;\nvoid dijkstra() {\n\tfor (int i = 1; i <= n; i++)dist[i] = make_pair(999999999999999999LL, -999999999999999999LL);\n\tQ.push(make_pair(0, 1)); dist[1] = make_pair(0, h);\n\twhile (!Q.empty()) {\n\t\tlong long a1 = Q.top().first, a2 = Q.top().second; Q.pop();\n\t\tfor (int i = 0; i < x[a2].size(); i++) {\n\t\t\tlong long to = x[a2][i].first, cost = x[a2][i].second, height = dist[a2].second - cost;\n\t\t\tif (height < 0) { cost -= height; height = 0; }\n\t\t\tif (height > H[to]) { cost += (height - H[to]); height = H[to]; }\n\t\t\tif (dist[to] > make_pair(a1 + cost, height)) {\n\t\t\t\tdist[to] = make_pair(a1 + cost, height);\n\t\t\t\tQ.push(make_pair(dist[to].first, to));\n\t\t\t}\n\t\t}\n\t}\n}\nint main() {\n\tcin >> n >> m >> h; for (int i = 1; i <= n; i++)cin >> H[i];\n\tfor (int i = 0; i < m; i++) {\n\t\tcin >> a[i] >> b[i] >> c[i];\n\t\tif (H[a[i]] >= c[i])x[a[i]].push_back(make_pair(b[i], c[i]));\n\t\tif (H[b[i]] >= c[i])x[b[i]].push_back(make_pair(a[i], c[i]));\n\t}\n\tdijkstra();\n\tlong long J = dist[n].first + (H[n] - dist[n].second);\n\tif (J >= 1000000000000000LL)J = -1;\n\tcout << J << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 32500, "score_of_the_acc": -0.1877, "final_rank": 5 }, { "submission_id": "aoj_0601_9627399", "code_snippet": "#include<cstdio>\n#include<queue>\n#include<vector>\n#include<algorithm>\nusing namespace std;\nconst int MAXN = 100005;\nconst long long INF = 100001000010000100ll;\n\nint H[MAXN];\nlong long dist[MAXN];\nvector<int> to[MAXN], cost[MAXN];\n\nstruct Dat{\n\tlong long d;\n\tint v;\n\tDat(long long d, int v):d(d),v(v){}\n\tbool operator<(const Dat& a)const{ return d < a.d;}\n};\nint main(){\n\tint N, M, X, A, B, T;\n\tscanf(\"%d%d%d\",&N,&M,&X);\n\t\n\tfor(int i = 1; i <= N; i++) scanf(\"%d\",&H[i]);\n\tfor(int i = 0; i < M; i++){\n\t\tscanf(\"%d%d%d\",&A,&B,&T);\n\t\tto[A].push_back(B);\n\t\tcost[A].push_back(T);\n\t\tto[B].push_back(A);\n\t\tcost[B].push_back(T);\n\t}\n\t\n\tfor(int i = 1; i <= N; i++) dist[i] = -INF;\n\t\n\tpriority_queue<Dat> q;\n\tq.push(Dat(X,1));\n\t\n\twhile(!q.empty()){\n\t\tDat now = q.top(); q.pop();\n\t\tif(dist[now.v] != -INF) continue;\n\t\tdist[now.v] = now.d;\n\t\tfor(int i = 0; i < to[now.v].size(); i++){\n\t\t\tint u = to[now.v][i], c = cost[now.v][i];\n\t\t\tif(c > H[now.v]) continue;\n\t\t\tq.push(Dat(min(now.d-c, (long long)H[u]), u));\n\t\t}\n\t}\n\t\n\tif(dist[N] == -INF) puts(\"-1\");\n\telse printf(\"%lld\\n\",X+H[N]-dist[N]*2);\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 32408, "score_of_the_acc": -0.1395, "final_rank": 4 }, { "submission_id": "aoj_0601_9567689", "code_snippet": "using namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\n#include <bits/stdc++.h>\n\nvoid debug_out() { cerr << endl; }\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n cerr << \" \" << to_string(H);\n debug_out(T...);\n}\n\n#ifdef __LOCAL\n#define debug(...) \\\n cerr << \"\\033[33m(line:\" << __LINE__ << \") \" << \"[\" << #__VA_ARGS__ \\\n << \"]:\", \\\n debug_out(__VA_ARGS__); \\\n cerr << \"\\033[m\";\n#else\n#define debug(...) // :)\n#endif\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n\n#define ii tuple<int, int>\n#define iiget(t, x, y) \\\n x = get<0>(t); \\\n y = get<1>(t);\n#define iii tuple<int, int, int>\n#define iiiget(t, x, y, z) \\\n x = get<0>(t); \\\n y = get<1>(t); \\\n z = get<2>(t);\n#define vi vector<int>\n#define vvi vector<vi>\n#define vvvi vector<vvvi>\n#define vll vector<ll>\n#define vvll vector<vll>\n#define vvvll vector<vvll>\n\n#define vc vector<char>\n#define vvc vector<vc>\n#define vvvc vector<vvc>\n#define INF 1000000000001000\n\ntemplate <typename T>\ninline bool chmin(T& a, const T& b) {\n bool compare = a > b;\n if (a > b) a = b;\n return compare;\n}\ntemplate <typename T>\ninline bool chmax(T& a, const T& b) {\n bool compare = a < b;\n if (a < b) a = b;\n return compare;\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n ll N, M, X, a, b, t;\n\n cin >> N >> M >> X;\n\n ll w[N];\n rep(i, N) cin >> w[i];\n\n vector<pair<ll, ll>> aj[N];\n ll dp[N];\n bool c[N]{};\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>>\n q;\n pair<ll, int> tv;\n ll ans;\n int v;\n\n rep(i, M) {\n cin >> a >> b >> t;\n aj[a - 1].push_back(make_pair(b - 1, t));\n aj[b - 1].push_back(make_pair(a - 1, t));\n }\n\n memset(dp, 0x3f, N * sizeof(ll));\n dp[0] = 0;\n q.push({0, 0});\n\n auto getHeight = [&](int v, ll t) -> ll {\n ll h = max(0ll, X - t);\n chmin(h, w[v]);\n return h;\n };\n\n auto getElpT = [&](int u, int v, ll h, ll wid) -> ll {\n if (h - wid >= w[v])\n return h - w[v];\n else if (h - wid >= 0)\n return wid;\n else if (w[u] - wid >= 0)\n return wid * 2 - h;\n else\n return INF + 10;\n };\n\n while (!q.empty()) {\n tv = q.top();\n q.pop();\n t = tv.first;\n v = tv.second;\n debug(t, v);\n ll height = getHeight(v, t);\n if (v == N - 1) {\n dp[N - 1] = t;\n break;\n }\n if (c[v]) continue;\n c[v] = true;\n for (auto it = aj[v].begin(); it != aj[v].end(); it++) {\n if (!c[it->first]) {\n ll elpt = getElpT(v, it->first, height, it->second);\n // debug(elpt);\n if (elpt <= INF) {\n debug(v, it->first, t + elpt);\n q.push(make_pair(t + elpt, it->first));\n }\n }\n }\n }\n\n ans = getHeight(N - 1, dp[N - 1]);\n ans = dp[N - 1] + w[N - 1] - ans;\n\n cout << ((ans < INF) ? ans : -1) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 28076, "score_of_the_acc": -0.077, "final_rank": 2 }, { "submission_id": "aoj_0601_9567687", "code_snippet": "using namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\n#include <bits/stdc++.h>\n\nvoid debug_out() { cerr << endl; }\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n cerr << \" \" << to_string(H);\n debug_out(T...);\n}\n\n#ifdef __LOCAL\n#define debug(...) \\\n cerr << \"\\033[33m(line:\" << __LINE__ << \") \" << \"[\" << #__VA_ARGS__ \\\n << \"]:\", \\\n debug_out(__VA_ARGS__); \\\n cerr << \"\\033[m\";\n#else\n#define debug(...) // :)\n#endif\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n\n#define ii tuple<int, int>\n#define iiget(t, x, y) \\\n x = get<0>(t); \\\n y = get<1>(t);\n#define iii tuple<int, int, int>\n#define iiiget(t, x, y, z) \\\n x = get<0>(t); \\\n y = get<1>(t); \\\n z = get<2>(t);\n#define vi vector<int>\n#define vvi vector<vi>\n#define vvvi vector<vvvi>\n#define vll vector<ll>\n#define vvll vector<vll>\n#define vvvll vector<vvll>\n\n#define vc vector<char>\n#define vvc vector<vc>\n#define vvvc vector<vvc>\n#define INF 1000000000001\n\ntemplate <typename T>\ninline bool chmin(T& a, const T& b) {\n bool compare = a > b;\n if (a > b) a = b;\n return compare;\n}\ntemplate <typename T>\ninline bool chmax(T& a, const T& b) {\n bool compare = a < b;\n if (a < b) a = b;\n return compare;\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n ll N, M, X, a, b, t;\n\n cin >> N >> M >> X;\n\n ll w[N];\n rep(i, N) cin >> w[i];\n\n vector<pair<ll, ll>> aj[N];\n ll dp[N];\n bool c[N]{};\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>>\n q;\n pair<ll, int> tv;\n ll ans;\n int v;\n\n rep(i, M) {\n cin >> a >> b >> t;\n aj[a-1].push_back(make_pair(b-1, t));\n aj[b-1].push_back(make_pair(a-1, t));\n }\n\n memset(dp, 0x3f, N * sizeof(ll));\n dp[0] = 0;\n q.push({0, 0});\n \n auto getHeight = [&](int v, ll t) -> ll {\n ll h = max(0ll, X - t);\n chmin(h, w[v]);\n return h;\n };\n\n auto getElpT = [&](int u, int v, ll h, ll wid) -> ll {\n if (h - wid >= w[v])\n return h - w[v];\n else if (h - wid >= 0)\n return wid;\n else if (w[u] - wid >= 0)\n return wid * 2 - h;\n else\n return INF + 10;\n };\n\n while (!q.empty()) {\n tv = q.top();\n q.pop();\n t = tv.first;\n v = tv.second;\n debug(t, v);\n ll height = getHeight(v, t);\n if (v == N - 1) {\n dp[N-1] = t;\n break;\n }\n if (c[v]) continue;\n c[v] = true;\n for (auto it = aj[v].begin(); it != aj[v].end(); it++) {\n if (!c[it->first]) {\n ll elpt = getElpT(v, it->first, height, it->second);\n// debug(elpt);\n if (elpt <= INF) {\n debug(v, it->first, t + elpt);\n q.push(make_pair(t + elpt,it->first));\n }\n }\n }\n }\n\n ans = getHeight(N - 1, dp[N - 1]);\n ans = dp[N - 1] + w[N - 1] - ans;\n\n cout << ((ans < INF) ? ans : -1) << endl;\n\n return 0;\n}", "accuracy": 0.5873015873015873, "time_ms": 80, "memory_kb": 26236, "score_of_the_acc": -0.0571, "final_rank": 20 }, { "submission_id": "aoj_0601_9567679", "code_snippet": "using namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\n#include <bits/stdc++.h>\n\nvoid debug_out() { cerr << endl; }\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head H, Tail... T) {\n cerr << \" \" << to_string(H);\n debug_out(T...);\n}\n\n#ifdef __LOCAL\n#define debug(...) \\\n cerr << \"\\033[33m(line:\" << __LINE__ << \") \" << \"[\" << #__VA_ARGS__ \\\n << \"]:\", \\\n debug_out(__VA_ARGS__); \\\n cerr << \"\\033[m\";\n#else\n#define debug(...) // :)\n#endif\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n\n#define ii tuple<int, int>\n#define iiget(t, x, y) \\\n x = get<0>(t); \\\n y = get<1>(t);\n#define iii tuple<int, int, int>\n#define iiiget(t, x, y, z) \\\n x = get<0>(t); \\\n y = get<1>(t); \\\n z = get<2>(t);\n#define vi vector<int>\n#define vvi vector<vi>\n#define vvvi vector<vvvi>\n#define vll vector<ll>\n#define vvll vector<vll>\n#define vvvll vector<vvll>\n\n#define vc vector<char>\n#define vvc vector<vc>\n#define vvvc vector<vvc>\n#define INF 100000000000\n\ntemplate <typename T>\ninline bool chmin(T& a, const T& b) {\n bool compare = a > b;\n if (a > b) a = b;\n return compare;\n}\ntemplate <typename T>\ninline bool chmax(T& a, const T& b) {\n bool compare = a < b;\n if (a < b) a = b;\n return compare;\n}\n\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n\n ll N, M, X, a, b, t;\n\n cin >> N >> M >> X;\n\n ll w[N];\n rep(i, N) cin >> w[i];\n\n vector<pair<ll, ll>> aj[N];\n ll dp[N];\n bool c[N]{};\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>>\n q;\n pair<ll, int> tv;\n ll ans;\n int v;\n\n rep(i, M) {\n cin >> a >> b >> t;\n aj[a-1].push_back(make_pair(b-1, t));\n aj[b-1].push_back(make_pair(a-1, t));\n }\n\n memset(dp, 0x3f, N * sizeof(ll));\n dp[0] = 0;\n q.push({0, 0});\n \n auto getHeight = [&](int v, ll t) -> ll {\n ll h = max(0ll, X - t);\n chmin(h, w[v]);\n return h;\n };\n\n auto getElpT = [&](int u, int v, ll h, ll wid) -> ll {\n if (h - wid >= w[v])\n return h - w[v];\n else if (h - wid >= 0)\n return wid;\n else if (w[u] - wid >= 0)\n return wid * 2 - h;\n else\n return INF + 10;\n };\n\n while (!q.empty()) {\n tv = q.top();\n q.pop();\n t = tv.first;\n v = tv.second;\n debug(t, v);\n ll height = getHeight(v, t);\n if (v == N - 1) {\n dp[N-1] = t;\n break;\n }\n if (c[v]) continue;\n c[v] = true;\n for (auto it = aj[v].begin(); it != aj[v].end(); it++) {\n if (!c[it->first]) {\n ll elpt = getElpT(v, it->first, height, it->second);\n// debug(elpt);\n if (elpt <= INF) {\n debug(v, it->first, t + elpt);\n q.push(make_pair(t + elpt,it->first));\n }\n }\n }\n }\n\n ans = getHeight(N - 1, dp[N - 1]);\n ans = dp[N - 1] + w[N - 1] - ans;\n\n cout << ((ans < INF) ? ans : -1) << endl;\n\n return 0;\n}", "accuracy": 0.5873015873015873, "time_ms": 80, "memory_kb": 25776, "score_of_the_acc": -0.0545, "final_rank": 19 }, { "submission_id": "aoj_0601_9488100", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <queue>\n#include <vector>\nusing namespace std;\n\nint h[100100]; // 高度情報を格納する配列\nvector<pair<int, int>> g[100100]; // グラフの隣接リスト\nlong long d1[100100]; // 各頂点までの最短距離を格納する配列\nint v[100100]; // 頂点が訪問済みかどうかを記録する配列\n\nint main() {\n int a, b;\n long long x;\n \n // 入力処理\n scanf(\"%d %d %lld\", &a, &b, &x);\n for (int i = 0; i < a; i++) {\n scanf(\"%d\", h + i); // 各頂点の高度を入力\n }\n for (int i = 0; i < b; i++) {\n int p, q, r;\n scanf(\"%d %d %d\", &p, &q, &r);\n p--; q--;\n g[p].push_back(make_pair(q, r)); // 辺の情報をグラフに追加\n g[q].push_back(make_pair(p, r)); // 無向グラフなので両方向に追加\n }\n\n // 初期化\n for (int i = 0; i < a; i++) d1[i] = 21000000000000000LL;\n priority_queue<pair<long long, int>> Q;\n Q.push(make_pair(0, 0));\n d1[0] = 0;\n\n // ダイクストラ法\n while (!Q.empty()) {\n int at = Q.top().second;\n long long cost = -Q.top().first;\n Q.pop();\n if (v[at]) continue;\n v[at] = 1;\n\n for (int i = 0; i < g[at].size(); i++) {\n long long T = cost + g[at][i].second;\n if (-T + x > h[g[at][i].first]) {\n T = x - h[g[at][i].first];\n }\n if (g[at][i].second > h[at]) continue;\n\n if (!v[g[at][i].first] && T < d1[g[at][i].first]) {\n d1[g[at][i].first] = T;\n Q.push(make_pair(-d1[g[at][i].first], g[at][i].first));\n }\n }\n }\n\n // 結果の出力\n if (d1[a - 1] > 1000000000000000LL) {\n printf(\"-1\\n\");\n } else {\n long long ret = d1[a - 1];\n ret += d1[a - 1] - x;\n printf(\"%lld\\n\", ret + h[a - 1]);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 16120, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0601_9025022", "code_snippet": "#include<iostream>\n#include<vector>\n#include<iomanip>\n#include<queue>\n#include<map>\n#include<algorithm>\n#include<set>\n#include<string>\nusing namespace std;\n\nint main() {\n\tint64_t N, M, X;\n\tcin >> N >> M >> X;\n\tvector<int64_t> vec(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> vec.at(i);\n\t}\n\tvector<vector<pair<int,int64_t>>> E(N, vector<pair<int,int64_t>>(0));\n\tfor (int i = 0; i < M; i++) {\n\t\tint a, b;\n\t\tint64_t t;\n\t\tcin >> a >> b >> t;\n\t\ta--;b--;\n\t\tif (vec.at(a) >= t) {\n\t\t\tpair<int, int64_t> p = make_pair(b, t);\n\t\t\tE.at(a).push_back(p);\n\t\t}\n\t\tif (vec.at(b) >= t) {\n\t\t\tpair<int, int64_t> q = make_pair(a, t);\n\t\t\tE.at(b).push_back(q);\n\t\t}\n\t}\n\n\tint64_t INF = 100000000000000000;\n\tvector<int64_t> cost(N, INF);\n\tcost.at(0) = 0;\n\tpriority_queue<pair<int64_t, int>> Q;\n\tpair<int64_t, int> p = make_pair(0, 0);\n\tQ.push(p);\n\twhile (Q.size() != 0) {\n\t\tpair<int64_t, int> q = Q.top();\n\t\tQ.pop();\n\t\tint a;\n\t\tint64_t c;\n\t\ttie(c, a) = q;\n\t\tc *= (-1);\n\t\tif (cost.at(a) < c) {\n\t\t\tcontinue;\n\t\t}\n\t\tint64_t h = 0LL;\n\t\tif (X - cost.at(a) > 0LL) {\n\t\t\th = X - cost.at(a);\n\t\t}\n\t\tfor (pair<int, int64_t> r : E.at(a)) {\n\t\t\tint64_t t,tt;\n\t\t\tint b;\n\t\t\ttie(b,t) = r;\n\t\t\tif (h - t > vec.at(b)) {\n\t\t\t\ttt = h - vec.at(b);\n\t\t\t}\n\t\t\telse if (0 <= h - t && h-t<= vec.at(b)) {\n\t\t\t\ttt = t;\n\t\t\t}\n\t\t\telse {\n\t\t\t\ttt = 2 * t - h;\n\t\t\t}\n\t\t\tif (cost.at(b) > cost.at(a) + tt) {\n\t\t\t\tcost.at(b) = cost.at(a) + tt;\n\t\t\t\tpair<int64_t, int> s = make_pair((-1)*cost.at(b), b);\n\t\t\t\tQ.push(s);\n\t\t\t}\n\t\t}\n\t}\n\n\tint64_t H = 0LL;\n\tif (X - cost.at(N - 1) > 0LL) {\n\t\tH = X - cost.at(N - 1);\n\t}\n\tint64_t ans = vec.at(N - 1) + cost.at(N - 1) - H;\n\tif (ans < INF) {\n\t\tcout << ans << endl;\n\t}\n\telse {\n\t\tcout << -1 << endl;\n\t}\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 21228, "score_of_the_acc": -0.1241, "final_rank": 3 }, { "submission_id": "aoj_0601_8818538", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n int &id1 = v2id[pi(v, bh)];\n if (!id1) {\n id1 = ct++;\n height[v].insert(bh);\n }\n int &id2 = v2id[pi(e.to, nh)];\n if (!id2) {\n id2 = ct++;\n height[e.to].insert(nh);\n }\n int uu = id1, vv = id2;\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n int &id1 = v2id[pi(i, e.cost)];\n if (!id1) {\n id1 = ct++;\n height[i].insert(e.cost);\n }\n int &id2 = v2id[pi(e.to, 0)];\n if (!id2) {\n id2 = ct++;\n height[e.to].insert(0);\n }\n int uu = id1;\n int vv = id2;\n gg[uu].pb({vv, e.cost});\n }\n int &id = v2id[pi(n - 1, H[n - 1])];\n if (!id) {\n id = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = ++itr;\n itr--;\n int &id1 = v2id[pi(i, *itr)];\n int &id2 = v2id[pi(i, *nx)];\n int uu = id1;\n int vv = id2;\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = id;\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 960, "memory_kb": 189072, "score_of_the_acc": -1.8142, "final_rank": 6 }, { "submission_id": "aoj_0601_8215082", "code_snippet": "#include <vector>\n#include <climits>\n#include <queue>\n#include <set>\n#include <map>\n\nusing ll = long long;\nusing pi = std::pair<int, int>;\nusing P = std::pair<ll, int>;\n\nstruct edge {\n int to;\n ll cost;\n};\n\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\n\nstd::vector<edge> G[V], gg[VV];\nstd::set<int> height[V];\nint n, m;\nll X;\nint H[V];\nstd::map<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\n\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n for(int i = 0; i < n; ++i) \n scanf(\" %d\", &H[i]);\n for(int i = 0; i < m; ++i) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a; --b;\n G[a].push_back({b, t});\n G[b].push_back({a, t});\n }\n \n int ct = 1;\n std::priority_queue<pi, std::vector<pi>, std::less<pi>> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n \n while (!que.empty()) {\n pi p = que.top(); que.pop();\n int v = p.second, h = p.first;\n if (h < max_h[v]) continue;\n for (const auto &e : G[v]) {\n int bh = h, nh = h - e.cost;\n if (nh < 0) continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].push_back({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n \n for(int i = 0; i < n; ++i) \n for (const auto &e : G[i]) {\n if (H[i] < e.cost) continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].push_back({vv, e.cost});\n }\n \n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n \n for(int i = 0; i < n; ++i) {\n int S = height[i].size();\n auto itr = height[i].begin();\n for(int j = 0; j < S - 1; ++j) {\n auto nx = std::next(itr);\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].push_back({vv, dist});\n gg[vv].push_back({uu, dist});\n itr = nx;\n }\n }\n \n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n std::fill(d, d + VV, INF);\n d[start] = 0;\n std::priority_queue<P, std::vector<P>, std::greater<P>> pq;\n pq.push(pi(0, start));\n \n while (!pq.empty()) {\n P now = pq.top(); pq.pop();\n int v = now.second;\n if (now.first > d[v]) continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n \n ll ans = d[goal] == INF ? -1 : d[goal];\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1060, "memory_kb": 188500, "score_of_the_acc": -1.9062, "final_rank": 8 }, { "submission_id": "aoj_0601_8215078", "code_snippet": "#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <limits>\n#include <cstdio>\n#include <cassert>\n\nusing ll = long long;\nusing pi = std::pair<int, int>;\nusing P = std::pair<ll, int>;\n\nstruct edge {\n int to;\n ll cost;\n};\n\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = std::numeric_limits<ll>::max() / 3;\n\nstd::vector<edge> G[V], gg[VV];\nstd::set<int> height[V];\nint n, m;\nll X;\nint H[V];\nstd::map<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\n\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n for (int i = 0; i < n; ++i) scanf(\" %d\", &H[i]);\n for (int i = 0; i < m; ++i) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].push_back({b, t});\n G[b].push_back({a, t});\n }\n int ct = 1;\n std::priority_queue<pi, std::vector<pi>, std::greater<pi>> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.second, h = p.first;\n if (h < max_h[v]) continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0) continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].push_back({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n for (int i = 0; i < n; ++i) {\n for (const auto &e : G[i]) {\n if (H[i] < e.cost) continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].push_back({vv, e.cost});\n }\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n for (int i = 0; i < n; ++i) {\n int S = height[i].size();\n auto itr = height[i].begin();\n for (int j = 0; j < S - 1; ++j) {\n auto nx = std::next(itr);\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].push_back({vv, dist});\n gg[vv].push_back({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n std::fill(d, d + VV, INF);\n d[start] = 0;\n std::priority_queue<P, std::vector<P>, std::greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.second;\n if (now.first > d[v]) continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF) ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 0.7301587301587301, "time_ms": 860, "memory_kb": 188500, "score_of_the_acc": -1.7157, "final_rank": 16 }, { "submission_id": "aoj_0601_8215076", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <queue>\n#include <map>\n#include <set>\n#include <limits>\n\nusing namespace std;\n\nusing ll = long long;\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\n\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = numeric_limits<ll>::max() / 3;\n\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\n\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n for(int i = 0; i < n; ++i) scanf(\" %d\", &H[i]);\n for(int i = 0; i < m; ++i) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].push_back({b, t});\n G[b].push_back({a, t});\n }\n\n int ct = 1;\n priority_queue<pi, vector<pi>, greater<pi>> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.second, h = p.first;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].push_back({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(nh, e.to));\n }\n }\n }\n\n for(int i = 0; i < n; ++i) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].push_back({vv, e.cost});\n }\n\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n\n for(int i = 0; i < n; ++i) {\n int S = height[i].size();\n auto itr = height[i].begin();\n for(int j = 0; j < S - 1; ++j) {\n auto nx = itr;\n ++nx;\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].push_back({vv, dist});\n gg[vv].push_back({uu, dist});\n itr = nx;\n }\n }\n\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.second;\n if (now.first > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 0.7301587301587301, "time_ms": 850, "memory_kb": 188468, "score_of_the_acc": -1.706, "final_rank": 15 }, { "submission_id": "aoj_0601_8215070", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 800000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n rep(i, n) scanf(\" %d\", &H[i]);\n rep(i, m) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1130, "memory_kb": 182684, "score_of_the_acc": -1.94, "final_rank": 9 }, { "submission_id": "aoj_0601_8215068", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n rep(i, n) scanf(\" %d\", &H[i]);\n rep(i, m) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1110, "memory_kb": 188764, "score_of_the_acc": -1.9553, "final_rank": 12 }, { "submission_id": "aoj_0601_8115521", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\n\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nunordered_map<int, int> v2id;\nint max_h[V] = {};\nll d[VV];\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[0 * V + X] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (v2id.find(v * V + bh) == v2id.end()) {\n v2id[v * V + bh] = ct++;\n height[v].insert(bh);\n }\n if (v2id.find(e.to * V + nh) == v2id.end()) {\n v2id[e.to * V + nh] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[v * V + bh], vv = v2id[e.to * V + nh];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (v2id.find(i * V + e.cost) == v2id.end()) {\n v2id[i * V + e.cost] = ct++;\n height[i].insert(e.cost);\n }\n if (v2id.find(e.to * V + 0) == v2id.end()) {\n v2id[e.to * V + 0] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[i * V + e.cost];\n int vv = v2id[e.to * V + 0];\n gg[uu].pb({vv, e.cost});\n }\n\n if (v2id.find((n - 1) * V + H[n - 1]) == v2id.end()) {\n v2id[(n - 1) * V + H[n - 1]] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.find(i * V + *itr) != v2id.end());\n assert(v2id.find(i * V + *nx) != v2id.end());\n int uu = v2id[i * V + *itr];\n int vv = v2id[i * V + *nx];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n\n int start = v2id[0 * V + X];\n int goal = v2id[(n - 1) * V + H[n - 1]];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 0.6190476190476191, "time_ms": 720, "memory_kb": 176912, "score_of_the_acc": -1.517, "final_rank": 17 }, { "submission_id": "aoj_0601_8115520", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nunordered_map<int, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n rep(i, n) scanf(\" %d\", &H[i]);\n rep(i, m) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[0 * V + X] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(v * V + bh)) {\n v2id[v * V + bh] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(e.to * V + nh)) {\n v2id[e.to * V + nh] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[v * V + bh], vv = v2id[e.to * V + nh];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(i * V + e.cost)) {\n v2id[i * V + e.cost] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(e.to * V + 0)) {\n v2id[e.to * V + 0] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[i * V + e.cost];\n int vv = v2id[e.to * V + 0];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count((n - 1) * V + H[n - 1])) {\n v2id[(n - 1) * V + H[n - 1]] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(i * V + *itr));\n assert(v2id.count(i * V + *nx));\n int uu = v2id[i * V + *itr];\n int vv = v2id[i * V + *nx];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[0 * V + X];\n int goal = v2id[(n - 1) * V + H[n - 1]];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 0.6190476190476191, "time_ms": 780, "memory_kb": 176628, "score_of_the_acc": -1.5725, "final_rank": 18 }, { "submission_id": "aoj_0601_8115519", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 200000;\nconst int VV = 2000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a; --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n vector<int> height[n];\n height[0].pb(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].pb(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].pb(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].pb(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].pb(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].pb(H[n - 1]);\n }\n rep(i, n) {\n sort(all(height[i]));\n height[i].erase(unique(all(height[i])), height[i].end());\n int S = height[i].size();\n rep(j, S - 1) {\n int uu = v2id[pi(i, height[i][j])];\n int vv = v2id[pi(i, height[i][j + 1])];\n int dist = height[i][j + 1] - height[i][j];\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 990, "memory_kb": 193308, "score_of_the_acc": -1.8667, "final_rank": 7 }, { "submission_id": "aoj_0601_8115517", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 188976, "score_of_the_acc": -1.966, "final_rank": 14 }, { "submission_id": "aoj_0601_8115516", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1110, "memory_kb": 188976, "score_of_the_acc": -1.9565, "final_rank": 13 }, { "submission_id": "aoj_0601_8115515", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n cin >> n >> m >> X;\n rep(i, n) cin >> H[i];\n rep(i, m) {\n int a, b, t;\n cin >> a >> b >> t;\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 189084, "score_of_the_acc": -1.9476, "final_rank": 11 }, { "submission_id": "aoj_0601_8115512", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (int(i) = 0; (i) < (int)(n); ++(i))\n#define all(x) (x).begin(), (x).end()\n#define pb push_back\n#define fi first\n#define se second\nusing pi = pair<int, int>;\nusing P = pair<ll, int>;\nstruct edge {\n int to;\n ll cost;\n};\nconst int V = 100000;\nconst int VV = 1000000;\nconst ll INF = LLONG_MAX / 3;\nvector<edge> G[V], gg[VV];\nmultiset<int> height[V];\nint n, m;\nll X;\nint H[V];\nmap<pi, int> v2id;\nint max_h[V] = {};\nll d[VV];\nint main() {\n scanf(\" %d %d %lld\", &n, &m, &X);\n rep(i, n) scanf(\" %d\", &H[i]);\n rep(i, m) {\n int a, b, t;\n scanf(\" %d %d %d\", &a, &b, &t);\n --a;\n --b;\n G[a].pb({b, t});\n G[b].pb({a, t});\n }\n int ct = 1;\n priority_queue<pi> que;\n que.push(pi(X, 0));\n v2id[pi(0, X)] = 0;\n max_h[0] = X;\n height[0].insert(X);\n while (!que.empty()) {\n pi p = que.top();\n que.pop();\n int v = p.se, h = p.fi;\n if (h < max_h[v])\n continue;\n for (const auto &e : G[v]) {\n int bh = h;\n int nh = h - e.cost;\n if (nh < 0)\n continue;\n if (nh > H[e.to]) {\n bh = H[e.to] + e.cost;\n nh = H[e.to];\n }\n if (nh > max_h[e.to]) {\n if (!v2id.count(pi(v, bh))) {\n v2id[pi(v, bh)] = ct++;\n height[v].insert(bh);\n }\n if (!v2id.count(pi(e.to, nh))) {\n v2id[pi(e.to, nh)] = ct++;\n height[e.to].insert(nh);\n }\n int uu = v2id[pi(v, bh)], vv = v2id[pi(e.to, nh)];\n gg[uu].pb({vv, e.cost});\n max_h[e.to] = nh;\n que.push(pi(max_h[e.to], e.to));\n }\n }\n }\n rep(i, n) for (const auto &e : G[i]) {\n if (H[i] < e.cost)\n continue;\n if (!v2id.count(pi(i, e.cost))) {\n v2id[pi(i, e.cost)] = ct++;\n height[i].insert(e.cost);\n }\n if (!v2id.count(pi(e.to, 0))) {\n v2id[pi(e.to, 0)] = ct++;\n height[e.to].insert(0);\n }\n int uu = v2id[pi(i, e.cost)];\n int vv = v2id[pi(e.to, 0)];\n gg[uu].pb({vv, e.cost});\n }\n if (!v2id.count(pi(n - 1, H[n - 1]))) {\n v2id[pi(n - 1, H[n - 1])] = ct++;\n height[n - 1].insert(H[n - 1]);\n }\n rep(i, n) {\n int S = height[i].size();\n auto itr = height[i].begin();\n rep(j, S - 1) {\n auto nx = itr;\n ++nx;\n assert(v2id.count(pi(i, *itr)));\n assert(v2id.count(pi(i, *nx)));\n int uu = v2id[pi(i, *itr)];\n int vv = v2id[pi(i, *nx)];\n int dist = *nx - *itr;\n gg[uu].pb({vv, dist});\n gg[vv].pb({uu, dist});\n itr = nx;\n }\n }\n int start = v2id[pi(0, X)];\n int goal = v2id[pi(n - 1, H[n - 1])];\n fill(d, d + VV, INF);\n d[start] = 0;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push(pi(0, start));\n while (!pq.empty()) {\n P now = pq.top();\n pq.pop();\n int v = now.se;\n if (now.fi > d[v])\n continue;\n for (const auto &e : gg[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n pq.push(pi(d[e.to], e.to));\n }\n }\n }\n ll ans = d[goal];\n if (ans == INF)\n ans = -1;\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 188880, "score_of_the_acc": -1.9464, "final_rank": 10 } ]
aoj_0600_cpp
バームクーヘン(Baumkuchen) JOI 君は妹のJOI 子ちゃんとJOI 美ちゃんと一緒におやつを食べようとしている.今日のおやつは3 人の大好物のバームクーヘンだ. バームクーヘンは下図のような円筒形のお菓子である.3 人に分けるために,JOI 君は半径方向に刃を3回入れて,これを3 つのピースに切り分けなければならない.ただしこのバームクーヘンは本物の木材のように固いので,刃を入れるのは簡単ではない.そのためこのバームクーヘンにはあらかじめ $N$ 個の切れ込みが入っており,JOI 君は切れ込みのある位置でのみ切ることができる.切れ込みに1 から $N$ まで時計回りに番号をふったとき,$1 \leq i \leq N - 1$ に対し, $i$ 番目の切れ込みと$i + 1$ 番目の切れ込みの間の部分の大きさは $A_i$ である.また $N$ 番目の切れ込みと1 番目の切れ込みの間の部分の大きさは $A_N$ である. 図1: バームクーヘンの例 $N = 6, A_1 = 1, A_2 = 5, A_3 = 4, A_4 = 5, A_5 = 2, A_6 = 4$ 課題 切れ込みの個数 $N$ と,各部分の大きさを表す整数 $A_1,...,A_N$ が与えられる.バームクーヘンを3 つに切り分けたときの,最も小さいピースの大きさの最大値を出力するプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 $N$ が書かれている.これはバームクーヘンに $N$ 個の切れ込みがあることを表す. 続く$N$ 行のうちの $i$ 行目$(1 \leq i \leq N)$ には,整数 $A_i$ が書かれている.これは $i$ 番目の切れ込みと $i + 1$ 番目の切れ込みの間の部分 ($i = N$ のときは $N$ 番目の切れ込みと1 番目の切れ込みの間の部分) の大きさが $A_i$ であることを表す. 出力 標準出力に,バームクーヘンを3 つに切り分けたときの,最も小さいピースの大きさの最大値を表す整数を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. $3 \leq N \leq 100000$ $1 \leq A_i \leq 1000000000 (1 \leq i \leq N)$ 入出力例 入力例 1 6 1 5 4 5 2 4 出力例 1 6 図2: 1 番目の切れ込みと3 番目の切れ込みと5 番目の切れ込みで切るのが最善である. 入力例 2 30 1 34 44 13 30 1 9 3 7 7 20 12 2 44 6 9 44 31 17 20 33 18 48 23 19 31 24 50 43 15 出力例 2 213 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0600_10852974", "code_snippet": "#include <cstdio>\n#include <algorithm>\n#pragma warning(disable : 4996)\nusing namespace std;\nint n, a[200009]; long long sum[200009];\nbool solve(long long x) {\n\tfor (int i = 0; i < n; i++) {\n\t\tint ptr1 = lower_bound(sum + i, sum + n + i, x + sum[i]) - sum;\n\t\tif (ptr1 == n + i) continue;\n\t\tint ptr2 = lower_bound(sum + i, sum + n + i, x + sum[ptr1]) - sum;\n\t\tif (ptr2 == n + i) continue;\n\t\tif (sum[n + i] - sum[ptr2] >= x) return true;\n\t}\n\treturn false;\n}\nint main() {\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++) scanf(\"%d\", &a[i]), a[n + i] = a[i];\n\tfor (int i = 0; i < 2 * n; i++) sum[i + 1] = sum[i] + a[i];\n\tlong long l = 0, r = 1LL << 60;\n\twhile (r - l > 1) {\n\t\tlong long m = (l + r) >> 1;\n\t\tif (solve(m)) l = m;\n\t\telse r = m;\n\t}\n\tprintf(\"%lld\\n\", l);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 5304, "score_of_the_acc": -0.6023, "final_rank": 7 }, { "submission_id": "aoj_0600_10556522", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <iomanip>\n#include <limits.h>\n#include <map>\n#include <math.h>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <string>\n#include <utility>\n#include <vector>\n#include <stack>\n#include <complex>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define rep1(i, n) for (int i = 1; i < n + 1; i++)\n#define rev(i, n) for (int i = n - 1; i >= 0; i--)\n#define all(A) A.begin(), A.end()\n#define itr(A, l, r) A.begin() + l, A.begin() + r\n#define debug(var) cout << #var << \" = \" << var << endl;\ntypedef long long ll;\n\ntemplate <typename T1, typename T2>\nostream &operator<<(ostream &os, const pair<T1, T2> &p)\n{\n os << \"(\" << p.first << \",\" << p.second << \")\";\n return os;\n}\n\ntemplate <typename T1, typename T2>\nistream &operator>>(istream &is, pair<T1, T2> &p)\n{\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, const vector<T> &v)\n{\n for (int i = 0; i < (int)v.size(); i++)\n {\n os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, const vector<vector<T>> &v)\n{\n for (int i = 0; i < (int)v.size(); i++)\n {\n os << v[i] << endl;\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, const vector<vector<vector<T>>> &v)\n{\n int n = v.size();\n int m = v[0].size();\n int p = v[0][0].size();\n rep(k, p)\n {\n os << \"k = \" << k << endl;\n rep(i, n)\n {\n rep(j, m)\n {\n os << v[i][j][k];\n if (j < m - 1)\n {\n os << \" \";\n }\n else\n {\n os << endl;\n }\n }\n }\n }\n return os;\n}\n\ntemplate <typename T>\nistream &operator>>(istream &is, vector<T> &v)\n{\n for (T &in : v)\n is >> in;\n return is;\n}\n\ntemplate <typename T, typename S>\nostream &operator<<(ostream &os, map<T, S> &mp)\n{\n for (auto &[key, val] : mp)\n {\n os << key << \":\" << val << \" \";\n }\n cout << endl;\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, set<T> st)\n{\n auto itr = st.begin();\n for (int i = 0; i < (int)st.size(); i++)\n {\n os << *itr << (i + 1 != (int)st.size() ? \" \" : \"\");\n itr++;\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, multiset<T> st)\n{\n auto itr = st.begin();\n for (int i = 0; i < (int)st.size(); i++)\n {\n os << *itr << (i + 1 != (int)st.size() ? \" \" : \"\");\n itr++;\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, queue<T> q)\n{\n while (q.size())\n {\n os << q.front() << \" \";\n q.pop();\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, deque<T> q)\n{\n while (q.size())\n {\n os << q.front() << \" \";\n q.pop_front();\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, stack<T> st)\n{\n while (st.size())\n {\n os << st.top() << \" \";\n st.pop();\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, priority_queue<T> pq)\n{\n while (pq.size())\n {\n os << pq.top() << \" \";\n pq.pop();\n }\n return os;\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &os, priority_queue<T, vector<T>, greater<T>> mpq)\n{\n while (mpq.size())\n {\n os << mpq.top() << \" \";\n mpq.pop();\n }\n return os;\n}\n\nint main(){\n #define int ll\n int n;\n cin >> n;\n vector<int> a(n);\n cin >> a;\n // debug(a);\n vector<int> imos(2*n+1);\n rep(i,2*n){\n imos[i+1] = imos[i]+a[i%n];\n }\n // debug(imos);\n int ok = 0;\n int ng = 1e18;\n while(abs(ng-ok)>1){\n int mid = ng+ok;\n mid /= 2;\n // debug(mid);\n int R = 0;\n vector<int> idx(2*n,-1);\n rep(L,2*n){\n while(R<2*n && imos[R]-imos[L]<mid){\n R++;\n }\n idx[L] = R;\n }\n // debug(idx);\n idx.push_back(2*n);\n bool okay = false;\n rep(L,n){\n int nxt = idx[L];\n nxt = idx[nxt];\n nxt = idx[nxt];\n // debug(nxt);\n if(nxt-L<=n){\n okay = true;\n }\n }\n if(okay){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n cout << ok << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 10028, "score_of_the_acc": -1.1591, "final_rank": 18 }, { "submission_id": "aoj_0600_9906532", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\n2-pointers ?\ntricky as array is circular\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\n//const int INF = 2147483647;\nconst int64_t INF = 1e18;\n\nconst int MAX_N = 100000;\nstatic int64_t vect[MAX_N];\n\n//------------------------------------------------------------------------------\nvoid circular_shift(int N, int64_t A[], int K)\n{\n rotate(A, A+N-K, A+N);\n}\n\nvoid shift(int N, int64_t A[])\n{\n rotate(A, A+N-1, A+N);\n}\n\n//------------------------------------------------------------------------------\nint64_t solve1(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n int64_t L = vect[0];\n int64_t M = accumulate(vect+1, vect+N-1, 0L);\n int64_t R = vect[N-1];\n // for mid part:\n int start = 1;\n int back = N-2;\n //--------------------------------------------------------------------------\n // compute:\n int64_t res = min(L, min(M, R));\n int64_t d = 0;\n int64_t y = INF;\n while (true)\n {\n if (start == back) break;\n\n d = vect[start];\n y = min(L+d, min(M-d, R));\n if (y > res)\n {\n L += d;\n M -= d;\n res = y;\n start++;\n continue;\n }\n\n d = vect[back];\n y = min(L, min(M-d, R+d));\n if (y > res)\n {\n R += d;\n M -= d;\n res = y;\n back--;\n continue;\n }\n\n break;\n }\n //--------------------------------------------------------------------------\n \n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nint64_t solve(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (N == 3) return min(vect[0], min(vect[1], vect[2]));\n //--------------------------------------------------------------------------\n // init:\n //--------------------------------------------------------------------------\n // compute:\n int64_t res = 0;\n for (int i=0; i<N; ++i)\n {\n shift(N, vect);\n res = max(res, solve1(N));\n }\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n num = scanf(\"%d \", &N);\n for (int i=0; i<N; ++i) num = scanf(\"%ld \", &vect[i]);\n int64_t res = solve(N);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 0.52, "time_ms": 150, "memory_kb": 3632, "score_of_the_acc": -0.3182, "final_rank": 20 }, { "submission_id": "aoj_0600_9488099", "code_snippet": "#include <stdio.h>\n\n#define NMAX 100000\n#define D(x, y) (pos[(x)] - pos[(y)]) // 位置差分を計算するマクロ\n\nlong long A[NMAX];\nlong long pos[NMAX * 2];\nint N;\nlong long L = 0; // 総和の初期化\n\n// 最大値を計算する関数\nlong long solve() {\n long long max = 1;\n int p0 = 0, p1 = 1, p2 = 2;\n\n while (p0 < N) {\n // p1を調整して条件を満たす位置を見つける\n while (p1 - p0 < N - 1 && D(p1, p0) <= max) p1++;\n if (D(p1, p0) <= max) goto L1;\n\n // p2を調整して条件を満たす位置を見つける\n while (p2 - p0 < N && D(p2, p1) < D(p1, p0)) p2++;\n if (D(p2, p1) < D(p1, p0)) goto L1;\n\n // 条件を満たすか確認して最大値を更新\n if (L - D(p2, p0) >= D(p1, p0)) {\n max = D(p1, p0);\n if (max >= L / 3) return max; // 最大値が条件を満たした場合終了\n continue;\n }\n L1:\n p0 += 1;\n while (D(p2, p1) > D(p1, p0)) p2--;\n }\n return max;\n}\n\nint main(void) {\n int i;\n\n // 入力処理\n scanf(\"%d\", &N);\n for (i = 0; i < N; i++) {\n scanf(\"%lld\", &A[i]);\n L += A[i]; // 総和を計算\n }\n\n // 位置配列の初期化\n for (i = 1; i < 2 * N; i++) {\n pos[i] = pos[i - 1] + A[(i - 1) % N];\n }\n\n // 最大値の出力\n printf(\"%lld\\n\", solve());\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5324, "score_of_the_acc": -0.2645, "final_rank": 2 }, { "submission_id": "aoj_0600_9390133", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int64_t;\n\nint main() {\n int n;\n cin >> n;\n \n vector<ll> a(n*2+1),s(n*2+1);\n s[0]=0;\n for(int i=0;i<n;i++){\n cin >> a[i];\n s[i+1]=s[i]+a[i];\n a[i+n]=a[i];\n }\n for(int i=n;i<n*2;i++){\n s[i+1]=s[i]+a[i];\n }\n \n ll lw=0,hg=s[n];\n \n while(hg-lw>1){\n ll md=(lw+hg)/2;\n int flg=0;\n \n for(int i=0;i<n;i++){\n int p1=distance(s.begin(),lower_bound(s.begin()+i,s.begin()+n+i,s[i]+md));\n if(p1==n+i) continue;\n int p2=distance(s.begin(),lower_bound(s.begin()+p1,s.begin()+n+i,s[p1]+md));\n if(p2==n+i) continue;\n int p3=distance(s.begin(),lower_bound(s.begin()+p2,s.begin()+n+1+i,s[p2]+md));\n if(p3!=n+1+i){\n flg=1;\n break;\n }\n }\n if(flg) lw=md;\n else hg=md;\n }\n cout << lw << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 6284, "score_of_the_acc": -0.7101, "final_rank": 9 }, { "submission_id": "aoj_0600_9389838", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int64_t;\n\nvector<ll> s(200010);\n\nint res(int l,int r,int &b,int &e){\n //cout << l << \" \" << r << endl;\n if(r-l<=1){\n if(abs(s[e]+s[b]-2*s[l])>abs(s[e]+s[b]-2*s[r])) return r;\n return l;\n }\n int m=(r+l)/2;\n //cout << m << \" \" << s[e]-s[m] << \" \" << s[m]-s[b] << endl;\n if(s[e]-s[m]<s[m]-s[b]) return res(l,m,b,e);\n else return res(m,r,b,e);\n}\n\nint main() {\n int n;\n cin >> n;\n \n vector<ll> a(n*2+1);\n s[0]=0;\n for(int i=0;i<n;i++){\n cin >> a[i];\n s[i+1]=s[i]+a[i];\n a[i+n]=a[i];\n }\n for(int i=n;i<n*2;i++){\n s[i+1]=s[i]+a[i];\n }\n \n ll smx=0,cm,cmx;\n int bi,ci,e=n;\n for(int i=1;i<n;i++){\n int c=res(i,e,i,e);\n cm=min(s[i],min(s[e]-s[c],s[c]-s[i]));\n //cout << i << \" \" << cm << endl;\n if(cm>smx){\n smx=cm;\n bi=i;\n ci=c;\n }else if(cm<smx) break;\n }\n //cout << bi << \" \" << ci << \" \" << smx << endl;\n for(int i=1;i<n;i++){\n e=n+i;\n cmx=0;\n for(int j=bi;j<e;j++){\n int cj=max(ci,j);\n int c=res(cj,e,j,e);\n cm=min(s[j]-s[i],min(s[e]-s[c],s[c]-s[j]));\n //cout << i << \" \" << j << \" \" << c << \" \" <<cm << endl;\n if(cm>cmx){\n cmx=cm;\n bi=j;\n ci=c;\n }else if(cm<=cmx) break;\n }\n //cout << i << \" \" << cmx << endl;\n if(cmx>smx) smx=cmx;\n }\n cout << smx << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6280, "score_of_the_acc": -0.4822, "final_rank": 5 }, { "submission_id": "aoj_0600_9060104", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n;\n cin >> n;\n ll al = 0;\n vector<ll> a(n);\n for (int i = 0; i < n; i++) {\n cin >> a[i];\n al += a[i];\n }\n auto check = [&](ll x) -> bool {\n ll s1 = 0, s2 = 0;\n int l = 0;\n for (int i = 0; i < n; i++) {\n if (s1 < x) {\n s1 += a[i];\n l += 1;\n } else {\n break;\n }\n }\n if (s1 < x) return false;\n int r = l;\n for (int i = l; i < n; i++) {\n if (s2 < x) {\n s2 += a[i];\n r += 1;\n } else {\n break;\n }\n }\n if (s2 < x) return false;\n if (r == n) r = 0;\n for (int i = 0; i < n; i++) {\n while (s1 < x) {\n s1 += a[l];\n s2 -= a[l];\n l += 1;\n if (l == n) l = 0;\n }\n while (s2 < x) {\n s2 += a[r];\n r += 1;\n if (r == n) r = 0;\n }\n if (al - s1 - s2 >= x) return true;\n s1 -= a[i];\n }\n\n return false;\n };\n ll L = 0, R = 1e18;\n while (R - L > 1) {\n ll mid = (L + R) / 2;\n if (check(mid)) L = mid;\n else R = mid;\n }\n cout << L << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3900, "score_of_the_acc": -0.0874, "final_rank": 1 }, { "submission_id": "aoj_0600_8860229", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\nint64 dp[200000];\n\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\n\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (dp[pos] >= size) // use the result of previous computation\n return true;\n if (Find(pos, size)) {\n dp[pos] = size; // store the result of the computation\n return true;\n }\n }\n return false;\n}\n\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n memset(dp, 0, sizeof(dp));\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 7116, "score_of_the_acc": -0.9993, "final_rank": 17 }, { "submission_id": "aoj_0600_8838081", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 prefixSum[400000];\nbool result[200000];\n\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n prefixSum, lower_bound(prefixSum + pos + 1, prefixSum + N + pos + 1, prefixSum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n prefixSum, lower_bound(prefixSum + hoge + 1, prefixSum + N + pos + 1, prefixSum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n prefixSum, lower_bound(prefixSum + fuga + 1, prefixSum + N + pos + 1, prefixSum[fuga] + size));\n return (foo != N + pos + 1);\n}\n\nbool calc(int64 size) {\n int windowSize = N - 1;\n int windowStart = 0;\n int windowEnd = windowSize;\n for (int i = 0; i < windowSize; i++) {\n result[i] = Find(i, size);\n }\n while (windowEnd < 2 * N) {\n result[windowEnd] = Find(windowEnd, size);\n if (result[windowStart]) {\n return true;\n }\n windowStart++;\n windowEnd++;\n }\n return false;\n}\n\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n prefixSum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n prefixSum[i] = prefixSum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 5760, "score_of_the_acc": -1.3327, "final_rank": 19 }, { "submission_id": "aoj_0600_8820872", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\ntypedef long long int64;\nconst int64 INF = 1LL<<58;\nint N;\nstd::vector<int64> sum(200000);\n\nbool Find(const int &pos, const int64 &size) {\n int limit = N + pos + 1;\n int hoge = std::distance(sum.begin(), std::lower_bound(sum.begin() + pos + 1, sum.begin() + limit, sum[pos] + size));\n if (hoge == limit)\n return false;\n int fuga = std::distance(sum.begin(), std::lower_bound(sum.begin() + hoge + 1, sum.begin() + limit, sum[hoge] + size));\n if (fuga == limit)\n return false;\n int foo = std::distance(sum.begin(), std::lower_bound(sum.begin() + fuga + 1, sum.begin() + limit, sum[fuga] + size));\n return (foo != limit);\n}\n\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\n\nint main() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(NULL);\n std::cout.tie(NULL);\n\n std::cin>>N;\n std::vector<int> A(2*N);\n for (int i = 0; i < N; i++) {\n std::cin>>A[i];\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n std::cout<<low<<\"\\n\";\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 5212, "score_of_the_acc": -0.7016, "final_rank": 8 }, { "submission_id": "aoj_0600_8820852", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\n\nbool Find(const int &pos, const int64 &size) {\n int64 *ptr = lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size);\n if (ptr == sum + N + pos + 1)\n return false;\n int index1 = ptr - sum;\n\n ptr = lower_bound(sum + index1 + 1, sum + N + pos + 1, sum[index1] + size);\n if (ptr == sum + N + pos + 1)\n return false;\n int index2 = ptr - sum;\n\n ptr = lower_bound(sum + index2 + 1, sum + N + pos + 1, sum[index2] + size);\n return (ptr != sum + N + pos + 1);\n}\n\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 5588, "score_of_the_acc": -0.8058, "final_rank": 15 }, { "submission_id": "aoj_0600_8588938", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n int N;\n cin >> N;\n vector<int> A(2 * N);\n long long tot = 0;\n for (int i = 0; i < N; i++) {\n cin >> A[i];\n A[i + N] = A[i];\n tot += A[i];\n }\n long long tv = 0, fv = 1e18;\n while (fv - tv > 1) {\n long long mid = (tv + fv) / 2;\n int L = 0, R = 0;\n long long S = 0;\n vector<int> Lid(N, -1);\n vector<long long> Size(N, -1);\n while (L < N) {\n while (R < 2 * N && S < mid) {\n S += A[R];\n R++;\n }\n if (S >= mid) {\n Lid[L] = R;\n Size[L] = S;\n }\n if (L == R) {\n R++;\n } else {\n S -= A[L];\n L++;\n }\n }\n bool ok = false;\n for (int i = 0; i < N; i++) {\n int ni = Lid[i];\n if (ni == -1) continue;\n ni %= N;\n int nii = Lid[ni];\n if (nii == -1) continue;\n nii %= N;\n if (tot >= Size[i] + Size[ni] + Size[nii]) {\n ok = true;\n }\n }\n if (ok) {\n tv = mid;\n } else {\n fv = mid;\n }\n }\n cout << tv << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5076, "score_of_the_acc": -0.3849, "final_rank": 4 }, { "submission_id": "aoj_0600_8588934", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n int N;\n cin >> N;\n vector<int> A(2 * N);\n long long tot = 0;\n for (int i = 0; i < N; i++) {\n cin >> A[i];\n A[i + N] = A[i];\n tot += A[i];\n }\n long long tv = 0, fv = 1e18;\n while (fv - tv > 1) {\n long long mid = (tv + fv) / 2;\n int L = 0, R = 0;\n long long S = 0;\n vector<int> Lid(N, -1);\n vector<long long> Size(N, -1);\n while (L < N) {\n while (R < 2 * N && S < mid) {\n S += A[R];\n R++;\n }\n if (S >= mid) {\n Lid[L] = R;\n Size[L] = S;\n }\n if (L == R) {\n R++;\n } else {\n S -= A[L];\n L++;\n }\n }\n bool ok = false;\n for (int i = 0; i < N; i++) {\n int ni = Lid[i];\n if (ni == -1) continue;\n ni %= N;\n int nii = Lid[ni];\n if (nii == -1) continue;\n nii %= N;\n if (tot - Size[i] - Size[ni] >= mid) {\n ok = true;\n }\n }\n if (ok) {\n tv = mid;\n } else {\n fv = mid;\n }\n }\n cout << tv << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 5076, "score_of_the_acc": -0.3621, "final_rank": 3 }, { "submission_id": "aoj_0600_8215062", "code_snippet": "#include <algorithm>\n#include <cstdio>\n#include <iterator>\n#define MAX_NUM 200000\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[MAX_NUM * 2];\nint64 sum[MAX_NUM * 2];\n\ninline bool Find(const int pos, const int64 size) {\n int64 *end = sum + N + pos + 1;\n int64 *sum_pos = sum + pos;\n int64 *hoge = std::lower_bound(sum_pos + 1, end, *sum_pos + size);\n if (hoge == end) return false;\n int64 *fuga = std::lower_bound(hoge + 1, end, *hoge + size);\n if (fuga == end) return false;\n return std::lower_bound(fuga + 1, end, *fuga + size) != end;\n}\n\ninline bool calc(int64 size) {\n for (int pos = 0; pos < N; ++pos) {\n if (Find(pos, size)) return true;\n }\n return false;\n}\n\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; ++i) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; ++i) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid)) low = mid;\n else high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 5080, "score_of_the_acc": -0.7264, "final_rank": 10 }, { "submission_id": "aoj_0600_8215060", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\n\nint binary_search(int64 element, int start, int end){\n while(start <= end){\n int mid = start + (end - start) / 2;\n if(sum[mid] < element){\n start = mid + 1;\n }else{\n end = mid - 1;\n }\n }\n return start;\n}\nbool Find(const int &pos, const int64 &size) {\n int hoge = binary_search(sum[pos] + size, pos + 1, N + pos);\n if (hoge == N + pos + 1)\n return false;\n int fuga = binary_search(sum[hoge] + size, hoge + 1, N + pos);\n if (fuga == N + pos + 1)\n return false;\n int foo = binary_search(sum[fuga] + size, fuga + 1, N + pos);\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 5548, "score_of_the_acc": -0.845, "final_rank": 16 }, { "submission_id": "aoj_0600_8215057", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = sum[2 * N - 1] / 3;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 5548, "score_of_the_acc": -0.5723, "final_rank": 6 }, { "submission_id": "aoj_0600_8215053", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 5548, "score_of_the_acc": -0.7996, "final_rank": 13 }, { "submission_id": "aoj_0600_8115508", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nconst int MAXN = 400000;\nint N, A[MAXN];\nint64 sum[MAXN];\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n cin >> N;\n for (int i = 0; i < N; i++) {\n cin >> A[i];\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n cout << low << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 5524, "score_of_the_acc": -0.7504, "final_rank": 12 }, { "submission_id": "aoj_0600_8115505", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d\", A + i);\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n printf(\"%lld\\n\", low);\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 5564, "score_of_the_acc": -0.8021, "final_rank": 14 }, { "submission_id": "aoj_0600_8115504", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\nint N, A[200000];\nint64 sum[200000];\nbool Find(const int &pos, const int64 &size) {\n int hoge = distance(\n sum, lower_bound(sum + pos + 1, sum + N + pos + 1, sum[pos] + size));\n if (hoge == N + pos + 1)\n return false;\n int fuga = distance(\n sum, lower_bound(sum + hoge + 1, sum + N + pos + 1, sum[hoge] + size));\n if (fuga == N + pos + 1)\n return false;\n int foo = distance(\n sum, lower_bound(sum + fuga + 1, sum + N + pos + 1, sum[fuga] + size));\n return (foo != N + pos + 1);\n}\nbool calc(int64 size) {\n for (int pos = 0; pos < N; pos++) {\n if (Find(pos, size))\n return true;\n }\n return false;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n cin >> N;\n for (int i = 0; i < N; i++) {\n cin >> A[i];\n A[N + i] = A[i];\n }\n sum[0] = A[0];\n for (int i = 1; i < 2 * N; i++) {\n sum[i] = sum[i - 1] + A[i];\n }\n int64 low = 0, high = INF;\n while (high != low) {\n int64 mid = (low + high + 1) >> 1;\n if (calc(mid))\n low = mid;\n else\n high = mid - 1;\n }\n cout << low << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 5500, "score_of_the_acc": -0.7466, "final_rank": 11 } ]
aoj_0596_cpp
問題 5: タクシー (Taxis) 問題 IOI 国は町 1 から町 N までの N 個の町からなり,町と町とは道路で結ばれている.IOI 国には K 本の道路があり,すべての道路は異なる 2 つの町を結んでいる.車は道路を双方向に自由に移動できるが,道路以外を通ってある町から別の町に行くことはできない. IOI 国の町 1 に住む JOI 君は,町 N に住む祖母の家までタクシーで行くことにした.IOI 国にはタクシー会社 1 からタクシー会社 N までの N 個のタクシー会社がある.IOI 国のタクシー会社には次のような少々特殊な規則がある. タクシー会社 i のタクシーには,町 i でのみ乗車できる. タクシー会社 i のタクシーの運賃は,利用した距離によらず C i である. タクシー会社 i のタクシーは,乗車してから連続して最大 R i 本の道路しか通ることができない. たとえば R 1 = 2 の場合,町 1 からタクシー会社 1 のタクシーに乗車すると,最大 2 本の道路しか通ることができないため,道路を 3 本以上通るためには途中の町でタクシーを乗り換える必要がある. JOI 君は町以外の地点でタクシーに乗ったりタクシーから降りたりすることはできない.また,タクシー以外の移動手段を用いることもできない.JOI 君が町 N に到達するために必要な運賃の合計の最小値を求めるプログラムを作成せよ. 入力 入力は 1 + N + K 行からなる. 1 行目には,2 つの整数 N, K (2 ≤ N ≤ 5000, N - 1 ≤ K ≤ 10000) が空白を区切りとして書かれている.これは,IOI 国が N 個の町からなることと,IOI 国の道路の本数が K 本であることを表す. 続く N 行のうちの i 行目 (1 ≤ i ≤ N) には,2 つの整数 C i , R i (1 ≤ C i ≤ 10000, 1 ≤ R i ≤ N) が空白を区切りとして書かれている.これは,タクシー会社 i のタクシーの運賃が C i で,乗車してから連続して最大 R i 本の道路しか通ることができないことを表す. 続く K 行のうちの j 行目 (1 ≤ j ≤ K) には,異なる 2 つの整数 A j , B j (1 ≤ A j < B j ≤ N) が空白を区切りとして書かれている.これは,町 A j と町 B j との間に道路が存在することを表す.同じ (A j , B j ) の組が 2 回以上書かれていることはない. 与えられる入力データにおいては,どの町から別のどの町へもタクシーを乗り継いで行くことができることが保証されている. 出力 JOI 君が町 1 から町 N まで行くのに必要な運賃の合計の最小値を表す整数を 1 行で出力せよ. 入出力例 入力例 6 6 400 2 200 1 600 3 1000 1 300 5 700 4 1 2 2 3 3 6 4 6 1 5 2 4 出力例 700 上の入出力例は,以下の図に対応している.円は町を,線は道路を表す. この入出力例でJOI 君が最小の運賃で町 6 に到達するには,以下のようにする. 町 1 からタクシーに乗って町 5 に行く. (運賃 400) 町 5 からタクシーに乗って町 6 に行く. (運賃 300) JOI 君がこのようなルートを通った場合の運賃の合計は 400 + 300 = 700 であるので,700 を出力する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0596_10866273", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>; using LL = int;\nusing VI = vector<int>; using VVI = vector<VI>;\nusing PII = pair<int, int>; using PLL = pair<LL, LL>;\nusing VL = vector<LL>; using VVL = vector<VL>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n#define debug(x) cerr << #x << \": \" << x << endl\nconst int INF = 1e9; const LL LINF = 1e9;\nconst LL MOD = 1000000007; const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* ----- 2018/06/12 Problem: AOJ 0596 / Link: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0596 ----- */\n/* ------問題------\n\nIOI 国は町 1 から町 N までの N 個の町からなり,町と町とは道路で結ばれている.IOI 国には K 本の道路があり,すべての道路は異なる 2 つの町を結んでいる.車は道路を双方向に自由に移動できるが,道路以外を通ってある町から別の町に行くことはできない.\nIOI 国の町 1 に住む JOI 君は,町 N に住む祖母の家までタクシーで行くことにした.IOI 国にはタクシー会社 1 からタクシー会社 N までの N 個のタクシー会社がある.IOI 国のタクシー会社には次のような少々特殊な規則がある.\nタクシー会社 i のタクシーには,町 i でのみ乗車できる.\nタクシー会社 i のタクシーの運賃は,利用した距離によらず Ci である.\nタクシー会社 i のタクシーは,乗車してから連続して最大 Ri 本の道路しか通ることができない.\nたとえば R1 = 2 の場合,町 1 からタクシー会社 1 のタクシーに乗車すると,最大 2 本の道路しか通ることができないため,道路を 3 本以上通るためには途中の町でタクシーを乗り換える必要がある.\nJOI 君は町以外の地点でタクシーに乗ったりタクシーから降りたりすることはできない.また,タクシー以外の移動手段を用いることもできない.JOI 君が町 N に到達するために必要な運賃の合計の最小値を求めるプログラムを作成せよ.\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n効率解法がない、うく\n多重辺をはってしまった。うく\n\n----解説ここまで---- */\n\nint Dijkstra(const vector<vector<PLL>>& G, int s) {\n\tVL dist(SZ(G), INF);\n\tdist[s] = 0;\n\tpriority_queue<PLL, vector<PLL>, greater<PLL>> que;\n\tque.push(PLL(0LL, s));\n\n\twhile (!que.empty()) {\n\t\tPLL p = que.top(); que.pop();\n\t\tint v; /* 頂点*/ long long d; /* 頂点vまでの距離 */\n\t\ttie(d, v) = p;\n\n\t\tif (d > dist[v]) continue;\n\n\t\tFOR(i, 0, (int)G[v].size()) {\n\t\t\tint nv = G[v][i].first;\n\t\t\tif (dist[nv] > dist[v] + G[v][i].second) {\n\t\t\t\tdist[nv] = dist[v] + G[v][i].second;\n\t\t\t\tque.push(PLL(dist[nv], nv));\n\t\t\t}\n\t\t}\n\t}\n\treturn dist[SZ(G)-1];\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\n\tint N, E;\n\tcin >> N >> E;\n\tvector<vector<PII>>G(N);\n\tVVI infoG(N);\n\tvector<PII>Vinfo(N);\n\tFOR(i, 0, N) {\n\t\tint c, r; cin >> c >> r;\n\t\tVinfo[i] = PII(c, r);\n\t}\n\t\n\tFOR(i, 0, E) {\n\t\tint a, b; cin >> a >> b;\n\t\ta--, b--;\n\t\tinfoG[a].push_back(b);\n\t\tinfoG[b].push_back(a);\n\t}\n\tFOR(base, 0, N) {\n\t\tVI visit(N, 0);\n\t\tqueue<PII>q;\n\t\tint cost = Vinfo[base].first;\n\t\tint R = Vinfo[base].second;\n\t\tq.push(PII(base, 0));// r本たどった\n\t\twhile (!q.empty()) {\n\t\t\tint v, r;\n\t\t\ttie(v, r) = q.front(); q.pop();\n\t\t\tif (visit[v])continue;\n\t\t\tvisit[v] = 1;\n\t\t\tif (base != v) {\n\t\t\t\tG[base].push_back(PII(v, cost));\n\t\t\t}\n\t\t\tif (R>r) {\n\t\t\t\tFOR(i, 0, SZ(infoG[v])) {\n\t\t\t\t\tint nx = infoG[v][i];\n\t\t\t\t\tif (visit[nx])continue;\n\t\t\t\t\tq.push(PII(nx, r + 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tLL ans =Dijkstra(G,0);\n\n\tcout << ans << \"\\n\";\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 127928, "score_of_the_acc": -1.6347, "final_rank": 20 }, { "submission_id": "aoj_0596_10072330", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nconst int INF = 1e9;\nconst ll LINF = 1e18;\n\n#define rep(i,n) for (int i = 0; (i) < (n); (i)++)\n#define rep1(i,n) for (int i = 1; (i) < ((n) + 1); (i)++)\n#define all(a) (a).begin(), (a).end()\n\nint main(){\n int N, K;\n cin >> N >> K;\n int C[10009], R[10009];\n rep1(i,N){\n cin >> C[i] >> R[i];\n }\n\n vector<int> V[10009];\n rep(i,K){\n int A, B;\n cin >> A >> B;\n V[A].push_back(B);\n V[B].push_back(A);\n }\n\n vector<int> G[10009];\n rep1(i,N){\n vector<int> d(10009,INF);\n d[i] = R[i];\n queue<int> Q;\n Q.push(i);\n while(!Q.empty()){\n int cur = Q.front();\n Q.pop();\n G[i].push_back(cur);\n if(d[cur] == 0) continue;\n\n for(const auto& nex : V[cur]){\n if(d[nex] != INF) continue;\n d[nex] = d[cur] - 1;\n Q.push(nex);\n G[cur].push_back(nex);\n }\n }\n }\n \n // rep1(i,N){\n // rep(j,G[i].size()){\n // cout << G[i][j] << \" \";\n // }\n // cout << endl;\n // }\n bool visited[10009] = {};\n int dist[10009];\n rep1(i,N){\n dist[i] = INF;\n }\n dist[1] = 0;\n\n priority_queue<pair<int,int>, vector<pair<int,int>>, greater<pair<int,int>>> Q;\n Q.push(make_pair(0,1));\n while(!Q.empty()){\n auto cur = Q.top().second;\n Q.pop();\n\n if(visited[cur] == true) continue;\n visited[cur] = true;\n\n int cost = dist[cur] + C[cur];\n for(const auto& nex : G[cur]){\n if(dist[nex] > cost){\n dist[nex] = cost;\n Q.push(make_pair(cost, nex));\n }\n }\n }\n // rep1(i,N){\n // cout << i << \":\" << dist[i] << endl;\n // }\n cout << dist[N] << endl;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 144152, "score_of_the_acc": -1.3904, "final_rank": 18 }, { "submission_id": "aoj_0596_9668456", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define ALL(A) A.begin(),A.end()\nint main(){\n int N,M;cin>>N>>M;\n vector<int>C(N),R(N);\n for(int i=0;i<N;i++)cin>>C[i]>>R[i];\n vector<vector<int>>E(N);\n while(M--){\n int u,v;cin>>u>>v;u--;v--;\n E[u].emplace_back(v);\n E[v].emplace_back(u);\n }\n vector<vector<ll>>D(N,vector<ll>(N+1,1e18));\n D[0][R[0]]=C[0];\n priority_queue<pair<ll,pair<ll,ll>>>Q;\n Q.emplace(make_pair(-C[0],make_pair(0,R[0])));\n while(Q.size()){\n int v=Q.top().second.first,r=Q.top().second.second;\n ll d=-Q.top().first;\n Q.pop();\n if(d!=D[v][r])continue;\n if(D[v][R[v]]>d+C[v])D[v][R[v]]=d+C[v],Q.emplace(make_pair(-d-C[v],make_pair(v,R[v])));\n if(!r)continue;\n for(auto u:E[v])if(D[u][r-1]>d)D[u][r-1]=d,Q.emplace(make_pair(-d,make_pair(u,r-1)));\n }\n cout<<*min_element(ALL(D[N-1]))<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 199324, "score_of_the_acc": -0.9984, "final_rank": 17 }, { "submission_id": "aoj_0596_9578774", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,K;\n cin>>N>>K;\n vector<vector<ll>> D(N,vector<ll>(N,1e16));\n vector<ll> C(N),R(N);\n for(int i=0;i<N;i++)cin>>C[i]>>R[i];\n vector<vector<int>> G(N);\n for(int i=0;i<K;i++){\n int u,v;\n cin>>u>>v;\n u--;v--;\n G[u].push_back(v);\n G[v].push_back(u);\n } \n for(int i=0;i<N;i++){\n queue<int> Q;\n Q.push(i);\n vector<int> DD(N,R[i]+1);\n DD[i]=0;\n while(!Q.empty()){\n int p=Q.front();\n Q.pop();\n D[i][p]=min(D[i][p],C[i]);\n if(DD[p]==R[i])continue;\n for(auto v:G[p]){\n if(DD[v]<=DD[p]+1)continue;\n DD[v]=DD[p]+1;\n Q.push(v);\n }\n }\n }\n vector<ll> dist(N,1e18);\n dist[0]=0;\n vector<bool> seen(N,0);\n priority_queue<pair<ll,ll>,vector<pair<ll,ll>>,greater<pair<ll,ll>>> PQ;\n PQ.push({0,0});\n while(!PQ.empty()){\n ll c=PQ.top().first;\n ll n=PQ.top().second;\n PQ.pop();\n if(seen[n])continue;\n seen[n]=1;\n for(int v=0;v<N;v++){\n ll nc=c+D[n][v];\n if(seen[v])continue;\n if(dist[v]<=nc)continue;\n dist[v]=nc;\n PQ.push({nc,v});\n }\n }\n cout<<dist[N-1]<<endl;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 199632, "score_of_the_acc": -1.6346, "final_rank": 19 }, { "submission_id": "aoj_0596_8809010", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <limits>\nusing namespace std;\n\ntypedef vector<int> vi;\n\nvector<vi> pass;\nvi c, r, d, used;\n\nvoid dfs(int v, int u, int f, int end, vi& visited) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n for (int i = 0; i < pass[u].size(); i++) {\n dfs(v, pass[u][i], f + 1, end, visited);\n }\n}\n\nint dijk(int s, int g) {\n int n = pass.size();\n d.assign(n, numeric_limits<int>::max());\n used.assign(n, false);\n d[s] = 0;\n while (true) {\n int v = -1;\n for (int u = 0; u < n; u++) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n for (int i = 0; i < pass[v].size(); i++) {\n vi visited(n, false);\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\n\nint main() {\n int n, k;\n cin >> n >> k;\n c.resize(n);\n r.resize(n);\n pass.resize(n);\n for (int i = 0; i < n; i++) {\n cin >> c[i] >> r[i];\n }\n for (int i = 0; i < k; i++) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].push_back(b);\n pass[b].push_back(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 3364, "score_of_the_acc": -0.9423, "final_rank": 16 }, { "submission_id": "aoj_0596_8215039", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000], r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 3464, "score_of_the_acc": -0.7697, "final_rank": 15 }, { "submission_id": "aoj_0596_8215037", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3508, "score_of_the_acc": -0.693, "final_rank": 7 }, { "submission_id": "aoj_0596_8115488", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n for(int i = 0; i < pass[u].size(); i++) { \n dfs(v, pass[u][i], f + 1, end, visited); \n }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n for(int i = 0; i < pass[v].size(); i++) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3576, "score_of_the_acc": -0.6934, "final_rank": 11 }, { "submission_id": "aoj_0596_8112710", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3472, "score_of_the_acc": -0.6929, "final_rank": 5 }, { "submission_id": "aoj_0596_8112709", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3548, "score_of_the_acc": -0.6932, "final_rank": 8 }, { "submission_id": "aoj_0596_8112708", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3568, "score_of_the_acc": -0.6933, "final_rank": 10 }, { "submission_id": "aoj_0596_8112707", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cout.tie(NULL);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3576, "score_of_the_acc": -0.6934, "final_rank": 11 }, { "submission_id": "aoj_0596_8112706", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 5000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3436, "score_of_the_acc": -0.6927, "final_rank": 4 }, { "submission_id": "aoj_0596_8112705", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 3576, "score_of_the_acc": -0.7126, "final_rank": 14 }, { "submission_id": "aoj_0596_8112704", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3612, "score_of_the_acc": -0.6936, "final_rank": 13 }, { "submission_id": "aoj_0596_8112703", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3552, "score_of_the_acc": -0.6933, "final_rank": 9 }, { "submission_id": "aoj_0596_8112701", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n rep(i, pass[u].size()) { dfs(v, pass[u][i], f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(i, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][i], 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 3488, "score_of_the_acc": -0.6929, "final_rank": 6 }, { "submission_id": "aoj_0596_8051063", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef vector<int> vi;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nbool used[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u]) return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end) return;\n for (auto i : pass[u]) dfs(v, i, f + 1, end, visited);\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) if (!used[u] && (v == -1 || d[u] < d[v])) v = u;\n if (v == -1) break;\n used[v] = true;\n for (auto i : pass[v]) {\n bool visited[6000] = {};\n dfs(v, i, 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3788, "score_of_the_acc": -0.5983, "final_rank": 1 }, { "submission_id": "aoj_0596_8051061", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef vector<int> vi;\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define pb push_back\nconst int INF = 1e9;\nconst int MAXN = 6000;\nvector<int> pass[MAXN];\nint n, k, c[MAXN], r[MAXN], d[MAXN];\nbool used[MAXN];\nvoid dfs(int v, int u, int f, int end, bool visited[MAXN]) {\n if (visited[u]) return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end) return;\n for (int i : pass[u]) dfs(v, i, f + 1, end, visited);\n}\nint dijk(int s, int g) {\n rep(i, MAXN) d[i] = INF;\n rep(i, MAXN) used[i] = false;\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v])) v = u;\n }\n if (v == -1) break;\n used[v] = true;\n for (int i : pass[v]) {\n bool visited[MAXN] = {};\n dfs(v, i, 1, r[v], visited);\n }\n }\n return d[g];\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 3584, "score_of_the_acc": -0.6165, "final_rank": 3 }, { "submission_id": "aoj_0596_8051058", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef vector<int> vi;\ntypedef pair<int, int> pii;\ntypedef long long ll;\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define all(a) (a).begin(), (a).end()\n#define pb push_back\n#define INF 999999999\nvector<int> pass[6000];\nint n, k;\nint c[6000];\nint r[6000];\nint d[6000];\nvoid dfs(int v, int u, int f, int end, bool visited[6000]) {\n if (visited[u])\n return;\n visited[u] = true;\n d[u] = min(d[u], d[v] + c[v]);\n if (f >= end)\n return;\n for (auto& i : pass[u]) { dfs(v, i, f + 1, end, visited); }\n}\nint dijk(int s, int g) {\n rep(i, 6000) d[i] = INF;\n rep(i, 6000) {\n bool used[6000] = {};\n d[s] = 0;\n while (1) {\n int v = -1;\n rep(u, n) {\n if (!used[u] && (v == -1 || d[u] < d[v]))\n v = u;\n }\n if (v == -1)\n break;\n used[v] = true;\n rep(j, pass[v].size()) {\n bool visited[6000] = {};\n dfs(v, pass[v][j], 1, r[v], visited);\n }\n }\n if (d[g] != INF)\n break;\n }\n return d[g];\n}\nint main() {\n cin.tie(0)->sync_with_stdio(false);\n cin >> n >> k;\n rep(i, n) cin >> c[i] >> r[i];\n rep(i, k) {\n int a, b;\n cin >> a >> b;\n a--, b--;\n pass[a].pb(b);\n pass[b].pb(a);\n }\n cout << dijk(0, n - 1) << endl;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 3836, "score_of_the_acc": -0.5986, "final_rank": 2 } ]
aoj_0602_cpp
切り取り線(Cutting) JOI 君はペーパークラフトが趣味である.今日もJOI 君はペーパークラフトの作品を作ろうとしている.まず,JOI 君は設計図にしたがって1 枚の長方形の紙に $N$ 本の切り取り線を印刷した.各切り取り線は,紙の縦または横の辺に平行な線分である. 紙を切り出してできるすべての部分は作品の中で何らかの部品として用いられる.当然のことながら, 部品数の多い作品は製作が大変である.JOI 君は,すべての切り取り線にしたがって紙を切り出したとき, 紙がいくつの部分に分かれるかを知りたい. 課題 紙の大きさと,$N$ 本の切り取り線の情報が与えられる.これらの切り取り線にしたがって紙を切り分けたとき,紙がいくつの部分に分かれるかを求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 $W, H, N$ が空白を区切りとして書かれている.$W$ は紙の横の辺の長さを,$H$ は紙の縦の辺の長さを,$N$ は切り取り線の本数をそれぞれ表す.紙の左下,右下,左上,右上を,それぞれ座標 $(0, 0), (W, 0), (0, H), (W, H)$ で表す. 続く $N$ 行のうちの $i$ 行目 $(1 \leq i \leq N)$ には,整数 $A_i, B_i, C_i, D_i (0 \leq A_i \leq C_i \leq W, 0 \leq B_i \leq D_i \leq H)$ が空白を区切りとして書かれている.これは $i$ 番目の切り取り線が$(A_i, B_i)$ と$(C_i, D_i)$ を結ぶ線分であることを表す.この線分は紙のいずれかの辺に平行な線分である.すなわち,$A_i = C_i$ と $B_i = D_i$ のうちのちょうど1 つが成り立つ.また,ある切り取り線と,それに平行な他の切り取り線が共有点を持つことはなく,ある切り取り線と,それに平行な紙の辺が共有点を持つこともない. 出力 標準出力に,紙がいくつの部分に分かれるかを表す整数を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. $ 1 \leq W \leq 1000000 000$ $ 1 \leq H \leq 1000000 000$ $ 1 \leq N \leq 100000$ 入出力例 入力例 1 10 10 5 6 0 6 7 0 6 7 6 2 3 9 3 2 3 2 10 1 9 8 9 出力例 1 4 この入力の場合,切り取り線は下図のようになる. よって,切り取り線によって紙は4 つの部分に分かれる. 入力例 2 13 7 28 1 1 4 1 1 1 1 3 2 2 3 2 2 2 2 3 1 3 2 3 3 2 3 6 4 1 4 6 3 6 4 6 5 1 8 1 5 1 5 6 6 2 7 2 6 2 6 5 7 2 7 5 6 5 7 5 8 1 8 6 5 6 8 6 9 1 12 1 9 1 9 2 9 2 10 2 12 1 12 2 11 2 12 2 10 2 10 5 9 5 10 5 9 5 9 6 11 2 11 5 11 5 12 5 12 5 12 6 9 6 12 6 出力例 2 5 この入力の場合,切り取り線は次ページの図のようになる. よって,切り取り線によって紙は5 つの部分に分かれる. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0602_10853095", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int MAXN = 200200;\nusing ll = long long;\n\nstruct CutLine {\n int xl, yl, xr, yr;\n};\n\nint N;\nCutLine ls[MAXN];\n\nstruct Event {\n int y, op, xl, xr, id;\n Event(int y = 0, int op = 0, int xl = 0, int xr = 0, int id = 0) :\n y(y), op(op), xl(xl), xr(xr), id(id) {}\n bool operator < (const Event &e) const {\n return y < e.y || (y == e.y && op > e.op);\n }\n};\n\nint par[MAXN];\n\nint getPar(int v) {\n if (par[v] != v) {\n par[v] = getPar(par[v]);\n }\n return par[v];\n}\n\nvoid merge(int v, int u) {\n par[getPar(u)] = getPar(v);\n}\n\nint tr[MAXN << 2];\nint lazy[MAXN << 2];\n\nvoid build(int v, int l, int r) {\n tr[v] = 0;\n lazy[v] = -1;\n if (l < r) {\n int md = (l + r) >> 1;\n build(v << 1, l, md);\n build(v << 1 | 1, md + 1, r);\n }\n}\n\nvoid push(int v) {\n if (~lazy[v]) {\n for (int nv : {v << 1, v << 1 | 1}) {\n if (~lazy[nv]) merge(lazy[nv], lazy[v]);\n if (tr[nv]) lazy[nv] = lazy[v];\n }\n lazy[v] = -1;\n }\n}\n\nvoid modify1(int v, int l, int r, int p, int x) {\n if (l == r) {\n tr[v] += x;\n return;\n }\n int md = (l + r) >> 1;\n if (p <= md) modify1(v << 1, l, md, p, x);\n else modify1(v << 1 | 1, md + 1, r, p, x);\n tr[v] = tr[v << 1] + tr[v << 1 | 1];\n}\n\nvoid modify2(int v, int l, int r, int p, int x) {\n if (l == r) {\n lazy[v] = x;\n return;\n }\n push(v);\n int md = (l + r) >> 1;\n if (p <= md) modify2(v << 1, l, md, p, x);\n else modify2(v << 1 | 1, md + 1, r, p, x);\n}\n\nvoid modify3(int v, int l, int r, int L, int R, int x) {\n if (!tr[v]) return;\n if (L > r || R < l) return;\n if (L <= l && r <= R) {\n if (~lazy[v]) merge(lazy[v], x);\n lazy[v] = x;\n return;\n }\n push(v);\n int md = (l + r) >> 1;\n modify3(v << 1, l, md, L, R, x);\n modify3(v << 1 | 1, md + 1, r, L, R, x);\n}\n\nint query(int v, int l, int r, int L, int R) {\n if (L > r || R < l) return 0;\n if (L <= l && r <= R) return tr[v];\n int md = (l + r) >> 1;\n return query(v << 1, l, md, L, R) + query(v << 1 | 1, md + 1, r, L, R);\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n int H, W;\n cin >> H >> W >> N;\n for (int i = 0; i < N; ++i) {\n int a, b, c, d;\n cin >> a >> b >> c >> d;\n ls[i] = {a, b, c, d};\n }\n ls[N++] = {0, 0, 0, W};\n ls[N++] = {0, 0, H, 0};\n ls[N++] = {0, W, H, W};\n ls[N++] = {H, 0, H, W};\n vector<int> xs, ys;\n for (int i = 0; i < N; ++i) {\n xs.emplace_back(ls[i].xl);\n ys.emplace_back(ls[i].yr);\n xs.emplace_back(ls[i].xr);\n ys.emplace_back(ls[i].yr);\n }\n sort(xs.begin(), xs.end());\n xs.resize(unique(xs.begin(), xs.end()) - xs.begin());\n sort(ys.begin(), ys.end());\n ys.resize(unique(ys.begin(), ys.end()) - ys.begin());\n int NX = xs.size(), NY = ys.size();\n vector<Event> evs;\n for (int i = 0; i < N; ++i) {\n int xl = lower_bound(xs.begin(), xs.end(), ls[i].xl) - xs.begin();\n int yl = lower_bound(ys.begin(), ys.end(), ls[i].yl) - ys.begin();\n int xr = lower_bound(xs.begin(), xs.end(), ls[i].xr) - xs.begin();\n int yr = lower_bound(ys.begin(), ys.end(), ls[i].yr) - ys.begin();\n if (xl == xr) {\n evs.emplace_back(yl, +1, xl, xr, i);\n evs.emplace_back(yr, -1, xl, xr, i);\n } else {\n evs.emplace_back(yl, 0, xl, xr, i);\n }\n }\n ll ans = -N;\n build(1, 0, NX - 1);\n iota(par, par + N, 0);\n sort(evs.begin(), evs.end());\n for (auto e : evs) {\n if (e.op == +1) {\n modify2(1, 0, NX - 1, e.xl, e.id);\n modify1(1, 0, NX - 1, e.xl, +1);\n } else if (e.op == 0) {\n modify3(1, 0, NX - 1, e.xl, e.xr, e.id);\n ans += query(1, 0, NX - 1, e.xl, e.xr);\n } else {\n modify2(1, 0, NX - 1, e.xl, -1);\n modify1(1, 0, NX - 1, e.xl, -1);\n }\n }\n for (int i = 0; i < N; ++i) ans += int(par[i] == i);\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 18708, "score_of_the_acc": -0.1439, "final_rank": 4 }, { "submission_id": "aoj_0602_10146533", "code_snippet": "// AOJ #602\n// Cutting 2025.1.27\n\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n// グローバル変数\nint segmentCount, logBase2, treeSize, width, height, componentCount;\nint parent[100005];\nll totalResult;\n\nset<int> activeSegments;\n\n// Union-Find構造のfind関数\nint findParent(int x) {\n return parent[x] ? parent[x] = findParent(parent[x]) : x;\n}\n\n// 垂直線分と水平線分の構造体\nstruct Segment {\n union { int x, y; };\n int start, end;\n} verticalSegments[100005], horizontalSegments[100005];\n\n// セグメントツリーのノード\nstruct SegmentTreeNode {\n int value, tag;\n} segmentTree[1 << 19];\n\n// セグメントツリーの左・右子ノードのインデックス取得関数\ninline int leftChild(int index) { return index << 1; }\ninline int rightChild(int index) { return index << 1 | 1; }\n\n// セグメントツリーのノード値を取得\nint getNodeValue(int index) {\n return segmentTree[index].tag = -1, segmentTree[index].value;\n}\n\n// セグメントツリーの更新(値を加算)\nvoid updateTreeValue(int index, int delta) {\n for (index += treeSize; index; index >>= 1) segmentTree[index].value += delta;\n}\n\n// セグメントツリーの更新(タグ付け)\nvoid updateTreeTag(int index, int tagValue) {\n for (int i = logBase2, hasTag = 0; ~i; hasTag |= segmentTree[(index + treeSize) >> i].tag,\n segmentTree[(index + treeSize) >> i].tag = 0, i--) {\n if (hasTag) segmentTree[((index + treeSize) >> i) ^ 1].tag = -1;\n }\n segmentTree[index + treeSize].tag = tagValue;\n}\n\n// 範囲クエリ処理\nvoid rangeQuery(int left, int right) {\n if (left <= right) {\n for (left += treeSize - 1, right += treeSize + 1; left ^ right ^ 1; left >>= 1, right >>= 1) {\n if ((left & 1) == 0) totalResult += getNodeValue(left ^ 1);\n if ((right & 1) == 1) totalResult += getNodeValue(right ^ 1);\n }\n }\n}\n\n// タグを確認しながらクエリを実行\nint queryWithTag(int index, int result = 0) {\n for (result = segmentTree[index += treeSize].tag; index >>= 1;) {\n if (segmentTree[index].tag) return -1;\n }\n return ~result ? findParent(result) : -1;\n}\n\n// 座標変換用の配列と変換関数\nint xCoordinates[200005], yCoordinates[200005], uniqueXCount, uniqueYCount;\n\nint mapXCoordinate(int x) {\n return lower_bound(xCoordinates + 1, xCoordinates + uniqueXCount + 1, x) - xCoordinates;\n}\n\nint mapYCoordinate(int y) {\n return lower_bound(yCoordinates + 1, yCoordinates + uniqueYCount + 1, y) - yCoordinates;\n}\n\n// イベント構造体とヘッド配列\nstruct Event {\n int type, x, y, next;\n} events[200005];\n\nint eventHead[200005];\n\n// イベント挿入\nvoid insertSegment(int x) {\n int prevSegment = *--activeSegments.insert(x).first;\n int prevComponent = queryWithTag(prevSegment);\n totalResult--;\n if (prevComponent == -1) prevComponent = ++componentCount, updateTreeTag(prevSegment, prevComponent);\n updateTreeValue(x, 1), updateTreeTag(x, prevComponent);\n}\n\n// イベント削除\nvoid eraseSegment(int x) {\n int prevSegment = *--activeSegments.erase(activeSegments.find(x));\n int prevComponent1 = queryWithTag(prevSegment), prevComponent2 = queryWithTag(x);\n updateTreeValue(x, -1);\n if (prevComponent1 != -1) {\n if (prevComponent1 == prevComponent2) totalResult++;\n else if (prevComponent2 != -1) parent[prevComponent1] = prevComponent2;\n } else if (prevComponent2 != -1) updateTreeTag(prevSegment, prevComponent2);\n}\n\n// メイン関数\nsigned main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n cin >> width >> height >>segmentCount;\n uniqueXCount = uniqueYCount = 2;\n\n int verticalCount = 0, horizontalCount = 2;\n horizontalSegments[1] = {0, 0, width};\n horizontalSegments[2] = {height, 0, width};\n xCoordinates[2] = width, yCoordinates[2] = height;\n\n for (int i = 1; i <= segmentCount; i++) {\n int x0, y0, x1, y1;\n cin >> x0 >> y0 >> x1 >> y1;\n if (x0 == x1) verticalSegments[++verticalCount] = {x0, y0, y1}, yCoordinates[++uniqueYCount] = y1;\n else horizontalSegments[++horizontalCount] = {y0, x0, x1}, xCoordinates[++uniqueXCount] = x1;\n xCoordinates[++uniqueXCount] = x0, yCoordinates[++uniqueYCount] = y0;\n }\n\n sort(xCoordinates + 1, xCoordinates + uniqueXCount + 1);\n sort(yCoordinates + 1, yCoordinates + uniqueYCount + 1);\n uniqueXCount = unique(xCoordinates + 1, xCoordinates + uniqueXCount + 1) - xCoordinates - 1;\n uniqueYCount = unique(yCoordinates + 1, yCoordinates + uniqueYCount + 1) - yCoordinates - 1;\n\n logBase2 = __lg(uniqueXCount + 1) + 1;\n treeSize = 1 << logBase2;\n updateTreeValue(1, 1);\n segmentTree[1].tag = -1;\n activeSegments = {0, 1, uniqueXCount};\n\n for (int i = 1; i <= verticalCount; i++) {\n verticalSegments[i] = {mapXCoordinate(verticalSegments[i].x),\n mapYCoordinate(verticalSegments[i].start), mapYCoordinate(verticalSegments[i].end)};\n }\n\n for (int i = 1; i <= verticalCount; i++) {\n events[++componentCount] = {-1, verticalSegments[i].x, 0, eventHead[verticalSegments[i].end]};\n eventHead[verticalSegments[i].end] = componentCount;\n }\n\n for (int i = 1; i <= horizontalCount; i++) {\n int mappedY = mapYCoordinate(horizontalSegments[i].y);\n events[++componentCount] = {0, mapXCoordinate(horizontalSegments[i].start), \n mapXCoordinate(horizontalSegments[i].end), eventHead[mappedY]};\n eventHead[mappedY] = componentCount;\n }\n\n for (int i = 1; i <= verticalCount; i++) {\n events[++componentCount] = {+1, verticalSegments[i].x, 0, eventHead[verticalSegments[i].start]};\n eventHead[verticalSegments[i].start] = componentCount;\n }\n\n componentCount = 0;\n for (int i = 1; i <= uniqueYCount; i++) {\n for (int j = eventHead[i]; j; j = events[j].next) {\n switch (events[j].type) {\n case 1: insertSegment(events[j].x); break;\n case -1: eraseSegment(events[j].x); break;\n case 0: rangeQuery(events[j].x, *----activeSegments.upper_bound(events[j].y)); break;\n }\n }\n }\n printf(\"%lld\\n\", totalResult - 1);\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 17936, "score_of_the_acc": -0.0559, "final_rank": 1 }, { "submission_id": "aoj_0602_9488101", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> Point;\nenum : int { CREATEY, APPEARX, DELETEY };\n\nstruct Event {\n int y, idx, type;\n bool operator<(const Event& e) const {\n if (y == e.y) return (type < e.type);\n return (y < e.y);\n }\n};\n\nstruct BinaryIndexedTree {\n vector<int> data;\n BinaryIndexedTree(int sz) {\n data.assign(sz + 2, 0);\n }\n int query(int k) {\n int ret = 0;\n for (++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n void update(int k, int x) {\n for (++k; k < data.size(); k += k & -k) data[k] += x;\n }\n};\n\nstruct SegmentTree {\n vector<int> isnew;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n) sz <<= 1;\n isnew.assign(2 * sz - 1, false);\n }\n inline void AddF(const int a, const int b, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n isnew[k] = true;\n } else {\n AddF(a, b, 2 * k + 1, l, (l + r) >> 1);\n AddF(a, b, 2 * k + 2, (l + r) >> 1, r);\n }\n }\n inline void DelF(const int a, const int b, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= a + 1) {\n isnew[k] = false;\n } else {\n if (isnew[k]) {\n isnew[2 * k + 1] = true;\n isnew[2 * k + 2] = true;\n isnew[k] = false;\n }\n DelF(a, b, 2 * k + 1, l, (l + r) >> 1);\n DelF(a, b, 2 * k + 2, (l + r) >> 1, r);\n }\n }\n inline void AddF(int a, int b) {\n AddF(a, b, 0, 0, sz);\n }\n inline void DelF(const int x) {\n DelF(x, x + 1, 0, 0, sz);\n }\n inline bool CheckF(int k) {\n k += sz - 1;\n if (isnew[k]) return true;\n while (k > 0) {\n k = (k - 1) >> 1;\n if (isnew[k]) return true;\n }\n return false;\n }\n};\n\nstruct UnionFind {\n vector<int> data;\n UnionFind() {};\n inline int Make() {\n data.push_back(-1);\n return(data.size() - 1);\n }\n inline bool Unite(int a, int b) {\n a = Find(a), b = Find(b);\n if (a == b) return false;\n if (data[a] > data[b]) swap(a, b);\n data[a] += data[b];\n data[b] = a;\n return true;\n }\n inline int Find(int k) {\n if (data[k] < 0) return k;\n else return data[k] = Find(data[k]);\n }\n};\n\nSegmentTree* tree;\nUnionFind* uf;\nBinaryIndexedTree* bit;\nint decode[200020];\n\nint Evaluate(int x) {\n if (tree->CheckF(x)) {\n tree->DelF(x);\n return uf->Make();\n } else {\n return decode[x];\n }\n}\n\nint Press(int* A, int sz1, int* B, int sz2) {\n vector<int> nums;\n copy(A, A + sz1, back_inserter(nums));\n copy(B, B + sz2, back_inserter(nums));\n nums.push_back(-1);\n sort(nums.begin(), nums.end());\n nums.erase(unique(nums.begin(), nums.end()), nums.end());\n transform(A, A + sz1, A, [&](int x) {\n return(lower_bound(nums.begin(), nums.end(), x) - nums.begin());\n });\n transform(B, B + sz2, B, [&](int x) {\n return(lower_bound(nums.begin(), nums.end(), x) - nums.begin());\n });\n return(nums.size());\n}\n\nint main() {\n int W, H, N;\n int A[100004], B[100004], C[100004], D[100004];\n\n // 入力\n scanf(\"%d %d %d\", &W, &H, &N);\n for (int i = 0; i < N; i++) {\n scanf(\"%d %d %d %d\", &A[i], &B[i], &C[i], &D[i]);\n }\n\n // 追加の境界線を追加\n A[N] = 0; B[N] = 0; C[N] = W; D[N] = 0; ++N;\n A[N] = 0; B[N] = 0; C[N] = 0; D[N] = H; ++N;\n A[N] = W; B[N] = 0; C[N] = W; D[N] = H; ++N;\n A[N] = 0; B[N] = H; C[N] = W; D[N] = H; ++N;\n\n W = Press(A, N, C, N);\n\n vector<Event> Events;\n\n // イベントの生成\n for (int i = 0; i < N; i++) {\n if (A[i] == C[i]) {\n Events.push_back((Event) { B[i], i, CREATEY });\n Events.push_back((Event) { D[i], i, DELETEY });\n } else {\n Events.push_back((Event) { B[i], i, APPEARX });\n }\n }\n sort(Events.begin(), Events.end());\n\n set<int> pool;\n uf = new UnionFind();\n tree = new SegmentTree(W);\n bit = new BinaryIndexedTree(W);\n pool.insert(0); decode[0] = uf->Make();\n long long int sz = 0;\n\n // イベントの処理\n for (int i = 0; i < Events.size(); i++) {\n const Event& e = Events[i];\n const int& x = A[e.idx];\n if (e.type == CREATEY) {\n int L = *--pool.lower_bound(x);\n decode[x] = Evaluate(x);\n decode[L] = Evaluate(L);\n decode[x] = decode[L];\n pool.insert(x);\n bit->update(x, 1);\n } else if (e.type == DELETEY) {\n int L = *--pool.lower_bound(x);\n decode[x] = Evaluate(x);\n decode[L] = Evaluate(L);\n if (uf->Unite(decode[x], decode[L])) --sz;\n pool.erase(x);\n bit->update(x, -1);\n } else {\n int x2 = C[e.idx];\n int RSQ = bit->query(x2) - bit->query(x - 1) - 1;\n if (RSQ > 0) {\n sz += RSQ;\n tree->AddF(x, *--pool.upper_bound(x2));\n }\n }\n }\n printf(\"%lld\\n\", sz);\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 13960, "score_of_the_acc": -0.0854, "final_rank": 3 }, { "submission_id": "aoj_0602_8107589", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 998244353;\n// constexpr int MOD = 1000000007;\nconstexpr int DY4[]{1, 0, -1, 0}, DX4[]{0, -1, 0, 1};\nconstexpr int DY8[]{1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr int DX8[]{0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U>\ninline bool chmax(T& a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U>\ninline bool chmin(T& a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\ntemplate <typename Abelian>\nstruct FenwickTree {\n explicit FenwickTree(const int n, const Abelian ID = 0)\n : n(n), ID(ID), data(n, ID) {}\n\n void add(int idx, const Abelian val) {\n for (; idx < n; idx |= idx + 1) {\n data[idx] += val;\n }\n }\n\n Abelian sum(int idx) const {\n Abelian res = ID;\n for (--idx; idx >= 0; idx = (idx & (idx + 1)) - 1) {\n res += data[idx];\n }\n return res;\n }\n\n Abelian sum(const int left, const int right) const {\n return left < right ? sum(right) - sum(left) : ID;\n }\n\n Abelian operator[](const int idx) const { return sum(idx, idx + 1); }\n\n int lower_bound(Abelian val) const {\n if (val <= ID) return 0;\n int res = 0, exponent = 1;\n while (exponent <= n) exponent <<= 1;\n for (int mask = exponent >> 1; mask > 0; mask >>= 1) {\n const int idx = res + mask - 1;\n if (idx < n && data[idx] < val) {\n val -= data[idx];\n res += mask;\n }\n }\n return res;\n }\n\n private:\n const int n;\n const Abelian ID;\n std::vector<Abelian> data;\n};\n\nstruct UnionFind {\n explicit UnionFind(const int n) : data(n, -1) {}\n\n int root(const int ver) {\n return data[ver] < 0 ? ver : data[ver] = root(data[ver]);\n }\n\n bool unite(int u, int v) {\n u = root(u);\n v = root(v);\n if (u == v) return false;\n if (data[u] > data[v]) std::swap(u, v);\n data[u] += data[v];\n data[v] = u;\n return true;\n }\n\n bool is_same(const int u, const int v) { return root(u) == root(v); }\n\n int size(const int ver) { return -data[root(ver)]; }\n\n private:\n std::vector<int> data;\n};\n\nint main() {\n int w, h, n; cin >> w >> h >> n;\n vector<int> a(n + 4), b(n + 4), c(n + 4), d(n + 4); REP(i, n) cin >> a[i] >> b[i] >> c[i] >> d[i];\n a[n] = b[n] = d[n] = 0; c[n] = w;\n a[n + 1] = b[n + 1] = c[n + 1] = 0; d[n + 1] = h;\n a[n + 2] = c[n + 2] = w; b[n + 2] = 0; d[n + 2] = h;\n a[n + 3] = 0; b[n + 3] = d[n + 3] = h; c[n + 3] = w;\n vector<int> xs{0, w};\n xs.reserve((n + 4) * 6 + 2);\n copy(ALL(a), back_inserter(xs));\n REP(i, n + 4) {\n if (a[i] > 0) xs.emplace_back(a[i] - 1);\n if (a[i] + 1 <= w) xs.emplace_back(a[i] + 1);\n }\n copy(ALL(c), back_inserter(xs));\n REP(i, n + 4) {\n if (c[i] > 0) xs.emplace_back(c[i] - 1);\n if (c[i] + 1 <= w) xs.emplace_back(c[i] + 1);\n }\n sort(ALL(xs));\n xs.erase(unique(xs.begin(), xs.end()), xs.end());\n const int x_size = xs.size();\n vector<int> ys{0, h};\n ys.reserve((n + 4) * 6 + 2);\n copy(ALL(b), back_inserter(ys));\n REP(i, n + 4) {\n if (b[i] > 0) ys.emplace_back(b[i] - 1);\n if (b[i] + 1 <= h) ys.emplace_back(b[i] + 1);\n }\n copy(ALL(d), back_inserter(ys));\n REP(i, n + 4) {\n if (d[i] > 0) ys.emplace_back(d[i] - 1);\n if (d[i] + 1 <= h) ys.emplace_back(d[i] + 1);\n }\n sort(ALL(ys));\n ys.erase(unique(ys.begin(), ys.end()), ys.end());\n const int y_size = ys.size();\n REP(i, n + 4) a[i] = distance(xs.begin(), lower_bound(ALL(xs), a[i]));\n REP(i, n + 4) b[i] = distance(ys.begin(), lower_bound(ALL(ys), b[i]));\n REP(i, n + 4) c[i] = distance(xs.begin(), lower_bound(ALL(xs), c[i]));\n REP(i, n + 4) d[i] = distance(ys.begin(), lower_bound(ALL(ys), d[i]));\n vector<vector<pair<int, int>>> par_y(x_size), ins_x(x_size), era_x(x_size);\n REP(i, n + 4) {\n if (a[i] == c[i]) {\n par_y[a[i]].emplace_back(b[i], d[i]);\n } else {\n ins_x[a[i]].emplace_back(b[i], i);\n era_x[c[i]].emplace_back(b[i], i);\n }\n }\n\n ll ans = -(n + 4);\n\n FenwickTree<int> bit(y_size);\n REP(x, x_size) {\n for (const auto& [y, _] : ins_x[x]) bit.add(y, 1);\n for (const auto& [y1, y2] : par_y[x]) {\n const int cross = bit.sum(y1, y2 + 1);\n ans += cross;\n if (cross == 0) ++ans;\n }\n for (const auto& [y, _] : era_x[x]) bit.add(y, -1);\n }\n\n UnionFind union_find(n + 4);\n vector<int> id_y(y_size, -1);\n set<int> t;\n map<int, int> intervals;\n const auto find = [&](const int y) {\n const auto it = intervals.lower_bound(y);\n if (it != intervals.end() && it->first == y) return it;\n if (it != intervals.begin() && prev(it)->first <= y && y <= prev(it)->second) return prev(it);\n return intervals.end();\n };\n REP(x, x_size) {\n for (const auto [y, id] : ins_x[x]) {\n if (const auto it = find(y); it != intervals.end()) {\n const auto [l, r] = *it;\n intervals.erase(it);\n const auto it_r = t.lower_bound(y);\n if (it_r != t.end() && *it_r <= r) {\n assert(intervals.emplace(*it_r, r).second);\n }\n if (it_r != t.begin() && *prev(it_r) >= l) {\n assert(intervals.emplace(l, *prev(it_r)).second);\n }\n assert(intervals.emplace(y, y).second);\n } else {\n assert(intervals.emplace(y, y).second);\n }\n id_y[y] = id;\n assert(t.emplace(y).second);\n }\n for (const auto& [y1, y2] : par_y[x]) {\n auto it = find(y1);\n if (it == intervals.end()) {\n it = intervals.lower_bound(y1);\n if (it != intervals.end() && it->first > y2) it = intervals.end();\n }\n if (it != intervals.end()) {\n vector<pair<int, int>> segs;\n for (; it != intervals.end() && it->first <= y2; it = intervals.erase(it)) {\n segs.emplace_back(*it);\n }\n FOR(i, 1, segs.size()) {\n union_find.unite(id_y[segs[i - 1].first], id_y[segs[i].first]);\n }\n assert(intervals.emplace(segs.front().first, segs.back().second).second);\n }\n }\n for (const auto& [y, _] : era_x[x]) {\n id_y[y] = -1;\n assert(t.erase(y) > 0);\n const auto it = find(y);\n assert(it != intervals.end());\n const auto [l, r] = *it;\n intervals.erase(it);\n const auto it_r = t.lower_bound(y);\n if (it_r != t.end() && *it_r <= r) {\n assert(intervals.emplace(*it_r, r).second);\n }\n if (it_r != t.begin() && *prev(it_r) >= l) {\n assert(intervals.emplace(l, *prev(it_r)).second);\n }\n }\n }\n REP(i, n + 4) {\n if (b[i] == d[i] && union_find.root(i) == i) ++ans;\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 51936, "score_of_the_acc": -0.4355, "final_rank": 5 }, { "submission_id": "aoj_0602_5417922", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename T> struct monoid {\n const T identity;\n const function<T(T, T)> combine;\n};\ntemplate <typename In, typename Out = In, typename Node = In> struct segtree {\n\tconst int size;\n\tvector<Node> tree;\n const monoid<Out> m;\n template <typename Leaf, typename Branch>\n\tsegtree(const vector<In>& a, const monoid<Out>& m, const Leaf& leaf, const Branch& branch) \n : size(a.size()), tree(2 * (size + 1)), m(m) {\n static_assert(is_convertible<decltype(leaf), function<Node(const In&)>>::value);\n static_assert(is_convertible<decltype(branch), function<Node(const Node&, const Node&)>>::value);\n\t\tfor(int i = 0; i < size; i++) tree[i + size] = leaf(a[i]);\n\t\tfor(int i = size - 1; i > 0; i--) tree[i] = branch(tree[i << 1], tree[(i << 1) | 1]);\n }\n\tstatic constexpr auto identity = [](const auto& x) { return x; };\n segtree(const vector<In>& a, const monoid<Out>& m) : segtree(a, m, identity, m.combine) {}\n\ttemplate <typename Query = decltype(identity)> \n Out query(int L, int R, bool inclusive, const Query& query_f = identity) {\n static_assert(is_convertible<decltype(query_f), function<Out(Node&)>>::value);\n\t\tassert(L <= R + inclusive);\n\t\tOut ans_l = m.identity, ans_r = m.identity;\n\t\tfor(int a = L + size, b = R + size + inclusive; a < b; a >>= 1, b >>= 1) {\n\t\t\tif(a & 1) ans_l = m.combine(ans_l, query_f(tree[a++]));\n\t\t\tif(b & 1) ans_r = m.combine(query_f(tree[--b]), ans_r);\n\t\t}\n\t\treturn m.combine(ans_l, ans_r);\n\t}\n template <typename Query = decltype(identity)> \n Out query(int i, const Query& query_f = identity) { return query(i, i, true, query_f); }\n void update(int i, const In& new_value) {\n static_assert(is_same<Node, In>::value);\n static_assert(is_same<Node, Out>::value);\n for(tree[i += size] = new_value; i >>= 1; )\n tree[i] = m.combine(tree[i << 1], tree[(i << 1) | 1]);\n }\n template <typename UpdateNode> void update(int i, const In& new_value, const UpdateNode& update_node) {\n static_assert(is_convertible<decltype(update_node), function<void(Node&, const In&)>>::value);\n for(update_node(tree[i += size], new_value); i >>= 1; )\n update_node(tree[i], new_value);\n }\n template <typename Leaf, typename Branch> void update(int i, const In& new_value, const Leaf& leaf, const Branch& branch) {\n static_assert(is_convertible<decltype(leaf), function<void(Node&, const In&)>>::value);\n static_assert(is_convertible<decltype(branch), function<void(Node&, const Node&, const Node&, const In&)>>::value);\n for(leaf(tree[i += size], new_value); i >>= 1; )\n branch(tree[i], tree[i << 1], tree[(i << 1) | 1], new_value);\n }\n};\nstruct ufds {\n vector<int> p;\n ufds(int n) : p(n + 1) {\n iota(p.begin(), p.end(), 0);\n }\n int find(int u) {\n return p[u] == u ? u : p[u] = find(p[u]);\n }\n void onion(int u, int v) {\n if(find(u) != find(v)) {\n p[find(u)] = find(v);\n }\n }\n};\nconst int N = 100'000, vert = 0, hori = 1;\nint coords_for_axis[2][N+4][2];\nvoid compress(int n, int coords[N+4][2]) {\n vector<int> vals;\n for(int i = 0; i < n + 4; i++) {\n for(int val : coords[i]) {\n vals.push_back(val);\n }\n }\n sort(vals.begin(), vals.end());\n vals.erase(unique(vals.begin(), vals.end()), vals.end());\n for(int i = 0; i < n + 4; i++) {\n for(int& val : coords[i]) {\n val = lower_bound(vals.begin(), vals.end(), val) - vals.begin() + 1;\n }\n }\n}\nenum class event_type { add, query, remove };\nstruct event {\n event_type type;\n int id;\n int position(int axis) const {\n if(type == event_type::add) {\n return coords_for_axis[axis][id][0];\n } else if(type == event_type::remove) {\n return coords_for_axis[axis][id][1];\n } else {\n return coords_for_axis[axis][id][0];\n }\n }\n pair<int, event_type> ordering(int axis) const {\n return {position(axis ^ 1), type};\n };\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int w, h, n;\n cin >> w >> h >> n;\n vector<vector<event>> sweep_events_for_axis(2);\n auto insert = [&](int x0, int y0, int x1, int y1, int i) {\n coords_for_axis[hori][i][0] = x0, coords_for_axis[vert][i][0] = y0;\n coords_for_axis[hori][i][1] = x1, coords_for_axis[vert][i][1] = y1;\n if(coords_for_axis[hori][i][0] == coords_for_axis[hori][i][1]) {\n sweep_events_for_axis[vert].push_back({event_type::query, i});\n sweep_events_for_axis[hori].push_back({event_type::add, i});\n sweep_events_for_axis[hori].push_back({event_type::remove, i});\n } else {\n sweep_events_for_axis[hori].push_back({event_type::query, i});\n sweep_events_for_axis[vert].push_back({event_type::add, i});\n sweep_events_for_axis[vert].push_back({event_type::remove, i});\n }\n };\n for(int i = 0; i < n; i++) {\n int x0, y0, x1, y1;\n cin >> x0 >> y0 >> x1 >> y1;\n insert(x0, y0, x1, y1, i);\n }\n insert(0, 0, w, 0, n);\n insert(0, h, w, h, n + 1);\n insert(0, 0, 0, h, n + 2);\n insert(w, 0, w, h, n + 3);\n for(auto& coords : coords_for_axis) {\n compress(n, coords);\n }\n ll intersection_vertices = 0, non_intersection_vertices = 0;\n vector<ll> edges_along(n + 4);\n vector<ufds> uf(2, ufds(n + 4));\n for(int axis : {vert, hori}) {\n segtree<int> rsq(vector<int>(2 * n + 2), {0, plus<int>()});\n segtree<int, int, set<int>> st(\n vector<int>(2 * n + 2), \n {0, plus<int>()}, \n [](int) { return set<int>(); }, \n [](const set<int>&, const set<int>&) { return set<int>(); }\n );\n auto node_insert = [](set<int>& s, int x) { s.insert(x); };\n auto node_erase = [](set<int>& s, int x) { s.erase(x); };\n sort(sweep_events_for_axis[axis].begin(), sweep_events_for_axis[axis].end(), [&](const event& e1, const event& e2) {\n return e1.ordering(axis) < e2.ordering(axis);\n });\n for(event& e : sweep_events_for_axis[axis]) {\n if(e.type == event_type::add) {\n rsq.update(e.position(axis), 1);\n st.update(e.position(axis), e.id, node_insert);\n } else if(e.type == event_type::remove) {\n rsq.update(e.position(axis), 0);\n st.update(e.position(axis), e.id, node_erase);\n } else {\n int v0 = coords_for_axis[axis][e.id][0], v1 = coords_for_axis[axis][e.id][1];\n int curr_intersection_vertices = rsq.query(v0, v1, true);\n int curr_non_intersection_vertices = (rsq.query(v0) == 0) + (rsq.query(v1) == 0);\n intersection_vertices += curr_intersection_vertices;\n non_intersection_vertices += curr_non_intersection_vertices;\n edges_along[e.id] = curr_intersection_vertices + curr_non_intersection_vertices - 1;\n st.query(v0, v1, true, [&](set<int>& s) {\n int max_cross = -1;\n for(int cross : s) {\n uf[axis].onion(e.id, cross);\n if(max_cross == -1 or coords_for_axis[axis ^ 1][cross][1] > coords_for_axis[axis ^ 1][max_cross][1]) {\n max_cross = cross;\n }\n }\n s.clear();\n if(max_cross != -1) {\n s.insert(max_cross);\n }\n return 0;\n });\n }\n }\n }\n ll vertices = intersection_vertices / 2 + non_intersection_vertices;\n ll edges = accumulate(edges_along.begin(), edges_along.end(), 0ll);\n ll components = 0;\n for(int i = 0; i < n + 4; i++) {\n components += i == uf[0].p[i];\n }\n cout << components - vertices + edges << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 930, "memory_kb": 72616, "score_of_the_acc": -1.4347, "final_rank": 10 }, { "submission_id": "aoj_0602_4267260", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <cmath>\n#include <iterator>\n#include <algorithm>\nusing namespace std;\n#pragma warning (disable: 4996)\n\n// -------------------------------------------------- ライブラリ 1(非自明なやつ) ---------------------------------------------------\nconst int MAX_N = (1 << 19);\n\nclass SuperSegmentTree {\npublic:\n\tint size_ = 1;\n\tint A[MAX_N];\n\tset<int> dat[MAX_N * 2], idx[MAX_N];\n\tvector<int> I;\n\n\tvoid init(int sz) {\n\t\twhile (size_ <= sz) size_ *= 2;\n\t\tfor (int i = 0; i <= sz; i++) A[i] = 0;\n\t}\n\tvoid dels(int pos, int x) {\n\t\tidx[x].erase(pos); pos += size_;\n\t\tdat[pos].erase(x);\n\t\twhile (pos >= 1) {\n\t\t\tauto itr1 = dat[pos * 2 + 0].lower_bound(x);\n\t\t\tauto itr2 = dat[pos * 2 + 1].lower_bound(x);\n\t\t\tint cntv = 0;\n\t\t\tif (itr1 == dat[pos * 2 + 0].end() || (*itr1) != x) cntv++;\n\t\t\tif (itr2 == dat[pos * 2 + 1].end() || (*itr2) != x) cntv++;\n\t\t\tif (cntv == 2) dat[pos].erase(x);\n\t\t\tpos >>= 1;\n\t\t}\n\t}\n\tvoid adds(int pos, int x) {\n\t\tidx[x].insert(pos); pos += size_;\n\t\twhile (pos >= 1) {\n\t\t\tdat[pos].insert(x);\n\t\t\tpos >>= 1;\n\t\t}\n\t}\n\tvoid update(int pos, int x) {\n\t\tif (A[pos] != 0) {\n\t\t\tdels(pos, A[pos]);\n\t\t\tA[pos] = 0;\n\t\t}\n\t\tif (x != 0) {\n\t\t\tA[pos] = x;\n\t\t\tadds(pos, A[pos]);\n\t\t}\n\t}\n\tbool check(int x) {\n\t\tif (idx[x].size() >= 1) return true;\n\t\treturn false;\n\t}\n\tint reads(int pos) {\n\t\treturn A[pos];\n\t}\n\tvoid query(int l, int r, int a, int b, int u) {\n\t\tif (l <= a && b <= r) {\n\t\t\tauto itr = dat[u].begin();\n\t\t\twhile (itr != dat[u].end()) { I.push_back(*itr); itr++; }\n\t\t\treturn;\n\t\t}\n\t\tif (r <= a || b <= l) return;\n\t\tquery(l, r, a, (a + b) >> 1, u * 2);\n\t\tquery(l, r, (a + b) >> 1, b, u * 2 + 1);\n\t}\n\tvoid conquer(int cl, int cr) {\n\t\tI.clear();\n\t\tquery(cl, cr, 0, size_, 1);\n\t\tsort(I.begin(), I.end());\n\t\tI.erase(unique(I.begin(), I.end()), I.end());\n\n\t\tvector<pair<int, int>> Z;\n\t\tfor (int i : I) Z.push_back(make_pair(idx[i].size(), i));\n\t\tsort(Z.begin(), Z.end());\n\n\t\tfor (int i = 0; i < (int)Z.size() - 1; i++) {\n\t\t\tint pos = Z[i].second; vector<int> vecs;\n\t\t\tauto itr = idx[pos].begin();\n\t\t\twhile (itr != idx[pos].end()) { vecs.push_back(*itr); itr++; }\n\t\t\tfor (int j : vecs) update(j, Z[Z.size() - 1].second);\n\t\t}\n\t\treturn;\n\t}\n};\n\n// --------------------------------------------------- ライブラリ 2(自明なやつ) ----------------------------------------------------\nclass BIT {\npublic:\n\tint size_ = 1;\n\tvector<int> bit;\n\n\tvoid init(int sz) {\n\t\tsize_ = sz + 2;\n\t\tbit.resize(size_ + 2, 0);\n\t}\n\tvoid add(int pos, int x) {\n\t\tpos++;\n\t\twhile (pos <= size_) {\n\t\t\tbit[pos] += x;\n\t\t\tpos += (pos & -pos);\n\t\t}\n\t}\n\tint sum(int pos) {\n\t\tpos++; int s = 0;\n\t\twhile (pos >= 1) {\n\t\t\ts += bit[pos];\n\t\t\tpos -= (pos & -pos);\n\t\t}\n\t\treturn s;\n\t}\n};\n\nstruct Point {\n\tint px, py;\n};\n\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.px < a2.px) return true;\n\tif (a1.px > a2.px) return false;\n\tif (a1.py < a2.py) return true;\n\treturn false;\n}\n\nbool operator==(const Point& a1, const Point& a2) {\n\tif (a1.px == a2.px && a1.py == a2.py) return true;\n\treturn false;\n}\n\nclass UnionFind {\npublic:\n\tvector<int> par;\n\n\tvoid init(int sz) {\n\t\tpar.resize(sz, -1);\n\t}\n\tint root(int pos) {\n\t\tif (par[pos] == -1) return pos;\n\t\tpar[pos] = root(par[pos]);\n\t\treturn par[pos];\n\t}\n\tvoid unite(int u, int v) {\n\t\tu = root(u); v = root(v);\n\t\tif (u == v) return;\n\t\tpar[u] = v;\n\t}\n\tbool same(int u, int v) {\n\t\tif (root(u) == root(v)) return true;\n\t\treturn false;\n\t}\n};\n\n// -------------------------------------------- 本質 -----------------------------------------------\nint H, W, N;\nPoint G1[1 << 17], G2[1 << 17];\nvector<int> V[1 << 18][3];\nset<int> Set;\nSuperSegmentTree S;\n\nint main() {\n\t// ステップ 1. 入力\n\tscanf(\"%d%d%d\", &W, &H, &N);\n\tfor (int i = 1; i <= N; i++) scanf(\"%d%d%d%d\", &G1[i].px, &G1[i].py, &G2[i].px, &G2[i].py);\n\tG1[N + 1] = Point{ 0, 0 }; G2[N + 1] = Point{ W,0 };\n\tG1[N + 2] = Point{ 0, H }; G2[N + 2] = Point{ W,H };\n\tG1[N + 3] = Point{ 0, 0 }; G2[N + 3] = Point{ 0,H };\n\tG1[N + 4] = Point{ W, 0 }; G2[N + 4] = Point{ W,H };\n\tN += 4;\n\n\t// ステップ 2. 座標圧縮\n\tvector<int> LX, LY;\n\tfor (int i = 1; i <= N; i++) {\n\t\tLX.push_back(G1[i].px); LY.push_back(G1[i].py);\n\t\tLX.push_back(G2[i].px); LY.push_back(G2[i].py);\n\t}\n\tsort(LX.begin(), LX.end()); LX.erase(unique(LX.begin(), LX.end()), LX.end());\n\tsort(LY.begin(), LY.end()); LY.erase(unique(LY.begin(), LY.end()), LY.end());\n\tfor (int i = 1; i <= N; i++) {\n\t\tG1[i].px = lower_bound(LX.begin(), LX.end(), G1[i].px) - LX.begin();\n\t\tG1[i].py = lower_bound(LY.begin(), LY.end(), G1[i].py) - LY.begin();\n\t\tG2[i].px = lower_bound(LX.begin(), LX.end(), G2[i].px) - LX.begin();\n\t\tG2[i].py = lower_bound(LY.begin(), LY.end(), G2[i].py) - LY.begin();\n\t\tif (G1[i].px > G2[i].px) swap(G1[i].px, G2[i].px);\n\t\tif (G1[i].py > G2[i].py) swap(G1[i].py, G2[i].py);\n\t}\n\tW = LX.size() - 1;\n\tH = LY.size() - 1;\n\n\t// ステップ 3. 頂点個数の数え上げ(準備編)\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (G1[i].px == G2[i].px) {\n\t\t\tV[G1[i].px][1].push_back(i);\n\t\t}\n\t\telse {\n\t\t\tV[G1[i].px][0].push_back(i);\n\t\t\tV[G2[i].px][2].push_back(i);\n\t\t}\n\t}\n\n\tlong long Vertex = 0;\n\tlong long Edges = N;\n\tlong long Connect = 0;\n\n\t// ステップ 4. 頂点個数の数え上げ(実践編)\n\tBIT Z; Z.init(H + 2);\n\tfor (int i = 0; i <= W; i++) {\n\t\tfor (int j : V[i][0]) Z.add(G1[j].py, 1);\n\t\tfor (int j : V[i][1]) {\n\t\t\tVertex += 1LL * (Z.sum(G2[j].py) - Z.sum(G1[j].py - 1));\n\t\t}\n\t\tfor (int j : V[i][2]) Z.add(G1[j].py, -1);\n\t}\n\n\t// ステップ 5. 連結成分数の数え上げ\n\tint cnts = 0; S.init(H + 2);\n\tfor (int i = 0; i <= W; i++) {\n\t\tfor (int j : V[i][0]) {\n\t\t\tcnts++;\n\t\t\tS.update(G1[j].py, cnts);\n\t\t\tSet.insert(G1[j].py);\n\t\t}\n\t\tfor (int j : V[i][1]) {\n\t\t\tauto itr = Set.lower_bound(G1[j].py);\n\t\t\tif (itr == Set.end() || (*itr) > G2[j].py) Connect++;\n\t\t\telse {\n\t\t\t\tS.conquer(G1[j].py, G2[j].py + 1);\n\t\t\t}\n\t\t}\n\t\tfor (int j : V[i][2]) {\n\t\t\tint val = S.reads(G1[j].py);\n\t\t\tS.update(G1[j].py, 0);\n\t\t\tif (S.check(val) == false) Connect++;\n\t\t\tSet.erase(G1[j].py);\n\t\t}\n\t}\n\n\t// ステップ 6. 出力\n\tcout << Vertex - Edges + Connect << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 146492, "score_of_the_acc": -1.6371, "final_rank": 11 }, { "submission_id": "aoj_0602_3776128", "code_snippet": "bool debug=false;\n#include <queue>\n#include <algorithm>\n#include <vector>\n#include <utility>\n#include <stdio.h>\nusing namespace std;\n#define F first\n#define S second\n#define PB push_back\nconst int N=1e5+10;\nstruct seg_tree{\n\tvector<int> v,p,cnt,have;\n\tvoid init(int n,int l,int r){\n\t\tif(v.size()<=n){\n\t\t\tv.resize(n+1);\n\t\t\tcnt.resize(n+1);\n\t\t}\n\t\tif(l<r){\n\t\t\tint mid=(l+r)>>1;\n\t\t\tinit(n*2+1,l,mid);\n\t\t\tinit(n*2+2,mid+1,r);\n\t\t}\n\t\treturn ;\n\t}\n\tvoid init(int n){\n\t\tp.resize(n);\n\t\tfor(int i=0;i<n;i++)p[i]=i;\n\t\thave.resize(n);\n\t\tinit(0,0,n-1);\n\t\treturn ;\n\t}\n\tint find(int n){return p[n]==n?n:p[n]=find(p[n]);}\n\tvoid push_up(int n){\n\t\tcnt[n]=cnt[n*2+1]+cnt[n*2+2];\n\t\tif(v[n*2+1]==-1||v[n*2+2]==-1)v[n]=-1;\n\t\telse if(find(v[n*2+1])==find(v[n*2+2]))v[n]=find(v[n*2+1]);\n\t\telse if(v[n*2+1]==0)v[n]=find(v[n*2+2]);\n\t\telse if(v[n*2+2]==0)v[n]=find(v[n*2+1]);\n\t\telse v[n]=-1;\n\t}\n\tvoid fix(int n,int l,int r,int pos,int x){\n\t\tif(l==r){\n\t\t\tif(x==-1){\n\t\t\t\thave[pos]--;\n\t\t\t\tif(have[pos]==0)cnt[n]=v[n]=0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif(have[pos]==0)cnt[n]++;\n\t\t\t\tv[n]=x;\n\t\t\t\thave[pos]++;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tint mid=(l+r)>>1;\n\t\t\tif(pos>mid)fix(n*2+2,mid+1,r,pos,x);\n\t\t\telse fix(n*2+1,l,mid,pos,x);\n\t\t\tpush_up(n);\n\t\t}\n\t\treturn ;\n\t}\n\tvoid merge(int n){\n\t\t//if(debug)printf(\"merge(%d)\\n\",n);\n\t\tif(v[n*2+1]==-1)merge(n*2+1);\n\t\tif(v[n*2+2]==-1)merge(n*2+2);\n\t\tif(v[n*2+1]==0)v[n]=find(v[n*2+2]);\n\t\telse if(v[n*2+2]==0)v[n]=find(v[n*2+1]);\n\t\telse v[n]=p[find(v[n*2+1])]=find(v[n*2+2]);\n\t\treturn ;\n\t}\n\tpair<int,int> ask(int n,int l,int r,int L,int R){\n\t\t//if(debug)printf(\"ask(%d,%d,%d,%d,%d)\\n\",n,l,r,L,R);\n\t\tif(L<=l&&r<=R){\n\t\t\tif(v[n]==-1)merge(n);\n\t\t\treturn {cnt[n],v[n]};\n\t\t}\n\t\telse if(l>R||L>r)return {0,0};\n\t\telse{\n\t\t\tint mid=(l+r)>>1;\n\t\t\tpair<int,int> left=ask(n*2+1,l,mid,L,R),right=ask(n*2+2,mid+1,r,L,R),ans;\n\t\t\tans.F=left.F+right.F;\n\t\t\tif(left.S==0)ans.S=right.S;\n\t\t\telse if(right.S==0)ans.S=left.S;\n\t\t\telse ans.S=p[find(left.S)]=find(right.S);\n\t\t\treturn ans;\n\t\t}\n\t}\n\tint ask(int L,int R){\n\t\treturn ask(0,0,(int)p.size()-1,L,R).F;\n\t}\n};\nbool cmp(pair<pair<int,int>,int> a,pair<pair<int,int>,int> b){\n\treturn a.S<b.S;\n}\nint main(){\n\tint temp,w,h,n,x1,now=1,x2,y1,y2;\n\tlong long int line=0,point=0,comp=0;\n\tvector<int> x,y;\n\tvector<pair<pair<int,int>,int>> hor,ver;\n\tpriority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> in,out;\n\tseg_tree seg;\n\tscanf(\"%d%d%d\",&w,&h,&n);\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\n\t\tx.PB(x1);x.PB(x2);\n\t\ty.PB(y1);y.PB(y2);\n\t\tif(x1==x2)hor.PB({{y1,y2},x1});\n\t\telse ver.PB({{x1,x2},y1});\n\t}\n\thor.PB({{0,h},0});\n\thor.PB({{0,h},w});\n\tver.PB({{0,w},0});\n\tver.PB({{0,w},h});\n\tx.PB(0);\n\tx.PB(w);\n\ty.PB(0);\n\ty.PB(h);\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.resize(unique(x.begin(),x.end())-x.begin());\n\ty.resize(unique(y.begin(),y.end())-y.begin());\n\tfor(int i=0;i<hor.size();i++)hor[i]={{lower_bound(y.begin(),y.end(),hor[i].F.F)-y.begin(),lower_bound(y.begin(),y.end(),hor[i].F.S)-y.begin()},lower_bound(x.begin(),x.end(),hor[i].S)-x.begin()};\n\tfor(int i=0;i<ver.size();i++)ver[i]={{lower_bound(x.begin(),x.end(),ver[i].F.F)-x.begin(),lower_bound(x.begin(),x.end(),ver[i].F.S)-x.begin()},lower_bound(y.begin(),y.end(),ver[i].S)-y.begin()};\n\tfor(int i=0;i<hor.size();i++){\n\t\tin.push({hor[i].F.F,hor[i].S});\n\t\tout.push({hor[i].F.S,hor[i].S});\n\t\tpoint+=2;\n\t\tline++;\n\t}\n\tsort(ver.begin(),ver.end(),cmp);\n\tn+=10;\n\tn<<=1;\n\tseg.init(n);\n\tfor(int i=0;i<ver.size();i++){\n\t\tif(debug)printf(\"ver[%d]=(%d,%d,%d)\\n\",i,ver[i].F.F,ver[i].F.S,ver[i].S);\n\t\twhile(!in.empty()){\n\t\t\tif(in.top().F<=ver[i].S){\n\t\t\t\tseg.fix(0,0,n-1,in.top().S,now++);\n\t\t\t\tin.pop();\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\twhile(!out.empty()){\n\t\t\tif(out.top().F<ver[i].S){\n\t\t\t\tseg.fix(0,0,n-1,out.top().S,-1);\n\t\t\t\tout.pop();\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\ttemp=seg.ask(ver[i].F.F,ver[i].F.S);\n\t\tpoint+=temp+2;\n\t\tline+=(temp<<1)+1;\n\t\tif(temp==0)comp++;\n\t\tif(debug)printf(\"%d::temp=%d point=%d line=%d comp=%d\\n\",i,temp,point,line,comp);\n\t\tif(debug)printf(\"now=%d\\n\",now);\n\t\tif(0&&debug){\n\t\t\tprintf(\"p::\");\n\t\t\tfor(int i=1;i<now;i++)printf(\" %d\",seg.p[i]);\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n\twhile(!in.empty()){\n\t\tin.pop();\n\t\tcomp++;\n\t}\n\tfor(int i=1;i<now;i++)if(seg.p[i]==i)comp++;\n\tprintf(\"%lld\\n\",line-point+comp);\n\tif(debug)printf(\"line=%d point=%d comp=%d\\n\",line,point,comp);\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 14188, "score_of_the_acc": -0.0754, "final_rank": 2 }, { "submission_id": "aoj_0602_3776127", "code_snippet": "bool debug=false;\n#include <queue>\n#include <algorithm>\n#include <vector>\n#include <utility>\n#include <stdio.h>\nusing namespace std;\n#define F first\n#define S second\n#define PB push_back\nconst int N=1e5+10;\nstruct seg_tree{\n\tvector<int> v,p,cnt,have;\n\tvoid init(int n,int l,int r){\n\t\tif(v.size()<=n){\n\t\t\tv.resize(n+1);\n\t\t\tcnt.resize(n+1);\n\t\t}\n\t\tif(l<r){\n\t\t\tint mid=(l+r)>>1;\n\t\t\tinit(n*2+1,l,mid);\n\t\t\tinit(n*2+2,mid+1,r);\n\t\t}\n\t\treturn ;\n\t}\n\tvoid init(int n){\n\t\tp.resize(n);\n\t\tfor(int i=0;i<n;i++)p[i]=i;\n\t\thave.resize(n);\n\t\tinit(0,0,n-1);\n\t\treturn ;\n\t}\n\tint find(int n){return p[n]==n?n:p[n]=find(p[n]);}\n\tvoid push_up(int n){\n\t\tcnt[n]=cnt[n*2+1]+cnt[n*2+2];\n\t\tif(v[n*2+1]==-1||v[n*2+2]==-1)v[n]=-1;\n\t\telse if(find(v[n*2+1])==find(v[n*2+2]))v[n]=find(v[n*2+1]);\n\t\telse if(v[n*2+1]==0)v[n]=find(v[n*2+2]);\n\t\telse if(v[n*2+2]==0)v[n]=find(v[n*2+1]);\n\t\telse v[n]=-1;\n\t}\n\tvoid fix(int n,int l,int r,int pos,int x){\n\t\tif(l==r){\n\t\t\tif(x==-1){\n\t\t\t\thave[pos]--;\n\t\t\t\tif(have[pos]==0)cnt[n]=v[n]=0;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif(have[pos]==0)cnt[n]++;\n\t\t\t\tv[n]=x;\n\t\t\t\thave[pos]++;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tint mid=(l+r)>>1;\n\t\t\tif(pos>mid)fix(n*2+2,mid+1,r,pos,x);\n\t\t\telse fix(n*2+1,l,mid,pos,x);\n\t\t\tpush_up(n);\n\t\t}\n\t\treturn ;\n\t}\n\tvoid merge(int n){\n\t\t//if(debug)printf(\"merge(%d)\\n\",n);\n\t\tif(v[n*2+1]==-1)merge(n*2+1);\n\t\tif(v[n*2+2]==-1)merge(n*2+2);\n\t\tif(v[n*2+1]==0)v[n]=find(v[n*2+2]);\n\t\telse if(v[n*2+2]==0)v[n]=find(v[n*2+1]);\n\t\telse v[n]=p[find(v[n*2+1])]=find(v[n*2+2]);\n\t\treturn ;\n\t}\n\tpair<int,int> ask(int n,int l,int r,int L,int R){\n\t\t//if(debug)printf(\"ask(%d,%d,%d,%d,%d)\\n\",n,l,r,L,R);\n\t\tif(L<=l&&r<=R){\n\t\t\tif(v[n]==-1)merge(n);\n\t\t\treturn {cnt[n],v[n]};\n\t\t}\n\t\telse if(l>R||L>r)return {0,0};\n\t\telse{\n\t\t\tint mid=(l+r)>>1;\n\t\t\tpair<int,int> left=ask(n*2+1,l,mid,L,R),right=ask(n*2+2,mid+1,r,L,R),ans;\n\t\t\tans.F=left.F+right.F;\n\t\t\tif(left.S==0)ans.S=right.S;\n\t\t\telse if(right.S==0)ans.S=left.S;\n\t\t\telse ans.S=p[find(left.S)]=find(right.S);\n\t\t\treturn ans;\n\t\t}\n\t}\n\tint ask(int L,int R){\n\t\treturn ask(0,0,(int)p.size()-1,L,R).F;\n\t}\n};\nbool cmp(pair<pair<int,int>,int> a,pair<pair<int,int>,int> b){\n\treturn a.S<b.S;\n}\nint main(){\n\tint temp,line=0,point=0,comp=0,w,h,n,x1,now=1,x2,y1,y2;\n\tvector<int> x,y;\n\tvector<pair<pair<int,int>,int>> hor,ver;\n\tpriority_queue<pair<int,int>,vector<pair<int,int>>,greater<pair<int,int>>> in,out;\n\tseg_tree seg;\n\tscanf(\"%d%d%d\",&w,&h,&n);\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d%d%d%d\",&x1,&y1,&x2,&y2);\n\t\tx.PB(x1);x.PB(x2);\n\t\ty.PB(y1);y.PB(y2);\n\t\tif(x1==x2)hor.PB({{y1,y2},x1});\n\t\telse ver.PB({{x1,x2},y1});\n\t}\n\thor.PB({{0,h},0});\n\thor.PB({{0,h},w});\n\tver.PB({{0,w},0});\n\tver.PB({{0,w},h});\n\tx.PB(0);\n\tx.PB(w);\n\ty.PB(0);\n\ty.PB(h);\n\tsort(x.begin(),x.end());\n\tsort(y.begin(),y.end());\n\tx.resize(unique(x.begin(),x.end())-x.begin());\n\ty.resize(unique(y.begin(),y.end())-y.begin());\n\tfor(int i=0;i<hor.size();i++)hor[i]={{lower_bound(y.begin(),y.end(),hor[i].F.F)-y.begin(),lower_bound(y.begin(),y.end(),hor[i].F.S)-y.begin()},lower_bound(x.begin(),x.end(),hor[i].S)-x.begin()};\n\tfor(int i=0;i<ver.size();i++)ver[i]={{lower_bound(x.begin(),x.end(),ver[i].F.F)-x.begin(),lower_bound(x.begin(),x.end(),ver[i].F.S)-x.begin()},lower_bound(y.begin(),y.end(),ver[i].S)-y.begin()};\n\tfor(int i=0;i<hor.size();i++){\n\t\tin.push({hor[i].F.F,hor[i].S});\n\t\tout.push({hor[i].F.S,hor[i].S});\n\t\tpoint+=2;\n\t\tline++;\n\t}\n\tsort(ver.begin(),ver.end(),cmp);\n\tn+=10;\n\tn<<=1;\n\tseg.init(n);\n\tfor(int i=0;i<ver.size();i++){\n\t\tif(debug)printf(\"ver[%d]=(%d,%d,%d)\\n\",i,ver[i].F.F,ver[i].F.S,ver[i].S);\n\t\twhile(!in.empty()){\n\t\t\tif(in.top().F<=ver[i].S){\n\t\t\t\tseg.fix(0,0,n-1,in.top().S,now++);\n\t\t\t\tin.pop();\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\twhile(!out.empty()){\n\t\t\tif(out.top().F<ver[i].S){\n\t\t\t\tseg.fix(0,0,n-1,out.top().S,-1);\n\t\t\t\tout.pop();\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\ttemp=seg.ask(ver[i].F.F,ver[i].F.S);\n\t\tpoint+=temp+2;\n\t\tline+=(temp<<1)+1;\n\t\tif(temp==0)comp++;\n\t\tif(debug)printf(\"%d::temp=%d point=%d line=%d comp=%d\\n\",i,temp,point,line,comp);\n\t\tif(debug)printf(\"now=%d\\n\",now);\n\t\tif(0&&debug){\n\t\t\tprintf(\"p::\");\n\t\t\tfor(int i=1;i<now;i++)printf(\" %d\",seg.p[i]);\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n\twhile(!in.empty()){\n\t\tin.pop();\n\t\tcomp++;\n\t}\n\tfor(int i=1;i<now;i++)if(seg.p[i]==i)comp++;\n\tprintf(\"%d\\n\",line-point+comp);\n\tif(debug)printf(\"line=%d point=%d comp=%d\\n\",line,point,comp);\n}", "accuracy": 0.6351351351351351, "time_ms": 140, "memory_kb": 13540, "score_of_the_acc": -0.0706, "final_rank": 12 }, { "submission_id": "aoj_0602_2692857", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cfloat>\n#include <cstring>\n#include <map>\n#include <utility>\n#include <set>\n#include <iostream>\n#include <memory>\n#include <string>\n#include <vector>\n#include <list>\n#include <algorithm>\n#include <functional>\n#include <sstream>\n#include <complex>\n#include <stack>\n#include <queue>\n#include <unordered_set>\n#include <unordered_map>\n#include <array>\n#include <cassert>\n#include <bitset>\nusing namespace std;\nusing LL = long long;\n\nclass union_find {\nprivate:\n\tvector<int>parent;\n\tvector<int>rank;\n\tvector<int>clump;\npublic:\n\tunion_find(int siz) {\n\t\tparent.resize(siz);\n\t\trank.resize(siz);\n\t\tclump.resize(siz);\n\t\tfor (int i = 0; i < siz; ++i) {\n\t\t\tparent[i] = i;\n\t\t\trank[i] = 0;\n\t\t\tclump[i] = 1;\n\t\t}\n\t}\n\tvoid unite(int x, int y) {\n\t\tint xr = find(x);\n\t\tint yr = find(y);\n\t\tif (xr == yr)return;\n\t\tif (rank[xr] > rank[yr]) {\n\t\t\tparent[yr] = xr;\n\t\t\tclump[xr] += clump[yr];\n\t\t}\n\t\telse if (rank[yr] > rank[xr]) {\n\t\t\tparent[xr] = yr;\n\t\t\tclump[yr] += clump[xr];\n\t\t}\n\t\telse if (xr != yr) {\n\t\t\tparent[yr] = xr;\n\t\t\tclump[xr] += clump[yr];\n\t\t\t++rank[xr];\n\t\t}\n\t}\n\tint find(int x) {\n\t\tif (parent[x] == x) {\n\t\t\treturn x;\n\t\t}\n\t\telse {\n\t\t\treturn parent[x] = find(parent[x]);\n\t\t}\n\t}\n\tbool check(int x, int y) {\n\t\treturn find(x) == find(y);\n\t}\n\tint size(int x) {\n\t\treturn clump[find(x)];\n\t}\n};\n\nstruct line {\n\tbool dir;//false:横 true:縦\n\tLL pos;\n\tLL b1, b2;\n\tint id;\n\tline(bool dir, LL pos, LL b1, LL b2, int id)\n\t\t:dir(dir), pos(pos), b1(b1), b2(b2), id(id)\n\t{}\n\tbool operator<(const line& o) const {\n\t\tif (pos == o.pos) {\n\t\t\tif (b1 == o.b1) {\n\t\t\t\treturn b2 < o.b2;\n\t\t\t}\n\t\t\treturn b1 < o.b1;\n\t\t}\n\t\treturn pos < o.pos;\n\t}\n};\nvector<line>vec;\nvector<LL>tate;\nLL W, H, N;\n\ntemplate<typename T>\nclass BIT {\nprivate:\n\tvector<T>arr;\n\tint siz;\npublic:\n\tBIT(int n) :siz(1) {\n\t\twhile (siz < n)siz *= 2;\n\t\tarr.resize(siz + 1);\n\t}\n\t//[0,x)までの和を取得する\n\tT query(int x) const {\n\t\tT s = 0;\n\t\twhile (x > 0) {\n\t\t\ts += arr[x];\n\t\t\tx -= (x & -x);\n\t\t}\n\t\treturn s;\n\t}\n\t//xに値kを加算する\n\tvoid add(int x, const T& k) {\n\t\t++x;\n\t\twhile (x <= siz) {\n\t\t\tarr[x] += k;\n\t\t\tx += (x & -x);\n\t\t}\n\t}\n};\n\n\nvector<LL>border;\nvector<vector<pair<pair<LL, LL>, int>>>seg;\nint segwidth = 1;\n\nvoid query(int a, int b, union_find& uf, int id, int yok, int k = 0, int l = 0, int r = -1) {\n\tif (r < 0)r = segwidth;\n\tif (r <= a || b <= l)return;\n\tif (a <= l && r <= b) {\n\t\t//マージする\n\t\tif (seg[k].empty())return;\n\t\tint lim = -1;\n\t\tint endid = 0;\n\t\tfor (int xx = seg[k].size() - 1; xx >= 0; --xx) {\n\t\t\tif (seg[k][xx].first.first >= yok) {\n\t\t\t\tlim = xx;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (seg[k][xx].first.first < yok && yok < seg[k][xx].first.second) {\n\t\t\t\tuf.unite(id, seg[k][xx].second);\n\t\t\t\tendid = seg[k][xx].second;\n\t\t\t}\n\t\t}\n\t\tbool flag = false;\n\t\tauto very = seg[k][seg[k].size() - 1];\n\t\tvery.second = endid;\n\t\tfor (int xx = seg[k].size() - 1; xx > lim; --xx) {\n\t\t\tflag = true;\n\t\t\tvery.first.first = min(very.first.first, seg[k][xx].first.first);\n\t\t\tvery.first.second = max(very.first.second, seg[k][xx].first.second);\n\t\t\tseg[k].pop_back();\n\t\t}\n\t\tif (flag) {\n\t\t\tseg[k].push_back(very);\n\t\t}\n\t\treturn;\n\t}\n\tint mid = (l + r) / 2;\n\tquery(a, b, uf, id, yok, k * 2 + 1, l, mid);\n\tquery(a, b, uf, id, yok, k * 2 + 2, mid, r);\n}\n\nint main(void)\n{\n\tcin >> W >> H >> N;\n\tfor (int i = 0; i < N; ++i) {\n\t\tLL a, b, c, d;\n\t\tcin >> a >> b >> c >> d;\n\t\tif (a == c) {\n\t\t\t//縦\n\t\t\tLL up = min(b, d);\n\t\t\tLL dn = max(b, d);\n\t\t\tvec.push_back({ true,a * 2,up * 3 - 1,dn * 3 + 1 ,i });\n\t\t\ttate.push_back(up * 3 - 1);\n\t\t\ttate.push_back(dn * 3 + 1);\n\t\t\tborder.push_back(up * 3 - 1);\n\t\t\tborder.push_back(dn * 3 + 1);\n\t\t}\n\t\telse {\n\t\t\t//横\n\t\t\tLL lf = min(a, c);\n\t\t\tLL rh = max(a, c);\n\t\t\tvec.push_back({ false, b * 3,2 * lf - 1,2 * rh + 1,i });\n\t\t\ttate.push_back(b * 3);\n\t\t}\n\t}\n\tvec.push_back({ true,0,-1,H * 3 + 1 ,(int)N });\n\tvec.push_back({ true,W * 2,-1,H * 3 + 1,(int)N + 1 });\n\tvec.push_back({ false,0,-1,W * 2 + 1 ,(int)N + 2 });\n\tvec.push_back({ false,H * 3,-1,W * 2 + 1 ,(int)N + 3 });\n\ttate.push_back(0);\n\ttate.push_back(H * 3);\n\ttate.push_back(-1);\n\ttate.push_back(H * 3 + 1);\n\tborder.push_back(-1);\n\tborder.push_back(H * 3 + 1);\n\tsort(tate.begin(), tate.end());\n\ttate.erase(unique(tate.begin(), tate.end()), tate.end());\n\tsort(border.begin(), border.end());\n\tborder.erase(unique(border.begin(), border.end()), border.end());\n\tN += 4;\n\tLL M = tate.size();\n\tmap<LL, int>inv;\n\tfor (int i = 0; i < M; ++i) {\n\t\tinv[tate[i]] = i;\n\t}\n\tvector<pair<LL, pair<LL, LL>>>events;\n\tLL crossnum = 0;\n\tfor (auto& elm : vec) {\n\t\tif (elm.dir) {\n\t\t\tevents.push_back({ elm.pos,{ elm.b1,elm.b2 } });\n\t\t}\n\t\telse {\n\t\t\tevents.push_back({ elm.b1,{ elm.pos,elm.pos } });\n\t\t\tevents.push_back({ elm.b2,{ elm.pos,elm.pos } });\n\t\t}\n\t}\n\tBIT<int>bit(M);\n\tsort(events.begin(), events.end());\n\tfor (auto& elm : events) {\n\t\tif (elm.second.first == elm.second.second) {\n\t\t\tint index = inv[elm.second.first];\n\t\t\tif (bit.query(index + 1) - bit.query(index)) {\n\t\t\t\tbit.add(index, -1);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tbit.add(index, 1);\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tint rind = inv[elm.second.second];\n\t\t\tint lind = inv[elm.second.first];\n\t\t\tcrossnum += (bit.query(rind) - bit.query(lind));\n\t\t}\n\t}\n\tassert(border.size());\n\tint rawwidth = border.size() - 1;\n\twhile (segwidth < rawwidth) {\n\t\tsegwidth *= 2;\n\t}\n\tseg.resize(segwidth * 2 - 1);\n\t//横の線分をセグ木に入れていく\n\tfor (auto& elm : vec) {\n\t\tif (!elm.dir) {\n\t\t\tLL y = elm.pos;\n\t\t\tint index = lower_bound(border.begin(), border.end(), y) - border.begin();\n\t\t\tif (index != 0 && index != border.size()) {\n\t\t\t\t//index-1番目に格納する\n\t\t\t\tseg[index - 1 + segwidth - 1].push_back({ { elm.b1,elm.b2 } ,elm.id });\n\t\t\t}\n\t\t}\n\t}\n\t//セグ木情報を上に伝播させていく\n\tfor (int k = segwidth - 2; k >= 0; --k) {\n\t\tfor (auto& par : seg[k * 2 + 1]) {\n\t\t\tseg[k].push_back(par);\n\t\t}\n\t\tfor (auto& par : seg[k * 2 + 2]) {\n\t\t\tseg[k].push_back(par);\n\t\t}\n\t}\n\t//セグ木内部の線分を区分ごとにソートする(stack的に後ろから見る)\n\tfor (int k = 0; k < segwidth * 2 - 1; ++k) {\n\t\tsort(seg[k].rbegin(), seg[k].rend());\n\t}\n\t//縦直線をクエリで処理\n\tunion_find uf(N);\n\tsort(vec.begin(), vec.end());\n\tfor (auto&elm : vec) {\n\t\tif (elm.dir) {\n\t\t\tint lef = lower_bound(border.begin(), border.end(), elm.b1) - border.begin();\n\t\t\tint rht = lower_bound(border.begin(), border.end(), elm.b2) - border.begin();\n\t\t\tquery(lef, rht, uf, elm.id, elm.pos);\n\t\t}\n\t}\n\t//親の種類数で断定\n\tset<int>parset;\n\tfor (int i = 0; i < N; ++i) {\n\t\tparset.insert(uf.find(i));\n\t}\n\tLL groupnum = parset.size();\n\tLL answer = crossnum + groupnum - N;\n\tcout << answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 61280, "score_of_the_acc": -0.716, "final_rank": 7 }, { "submission_id": "aoj_0602_2535947", "code_snippet": "#include<bits/stdc++.h>\nconst long long N = 2e5 + 5;\nusing namespace std;\n\ntypedef pair <long long, long long> ii;\ntypedef pair <ii, long long> iii;\nvector <ii> vc;\nvector <iii> mv;\n\nlong long w, h, n, x[2][N], y[2][N], a[20*N], pos[2][N], num, bit[N];\nlong long cnt, ver, root_ver[N], ans;\nbool check[20*N];\n\nstruct {\n long long pset[N], numdsu;\n\n void init (long long n){\n for (long long i = 1; i <= n; i++) pset[i] = i;\n numdsu = n;\n }\n\n long long findset(long long i) {\n if (pset[i] != i) pset[i] = findset(pset[i]);\n return pset[i];\n }\n\n void unionset(long long i, long long j){\n if (findset(i) == findset(j)) return;\n pset[findset(i)] = findset(j);\n numdsu--;\n }\n} dsu;\n\nstruct node {\n long long val, left, right, cnt;\n} lv[20*N];\n\nvoid init(long long l, long long r){\n long long nod = cnt;\n if (l != r){\n long long mid = (l + r) / 2;\n lv[nod].left = ++cnt; init (l, mid);\n lv[nod].right = ++cnt; init (mid+1, r);\n }\n}\n\nvoid dolazy(long long k, long long l, long long r){\n if (lv[k].val == 0) return;\n if (l != r) {\n long long a = lv[k].left, b = lv[k].right;\n if (lv[a].val) {dsu.unionset(lv[a].val, lv[k].val);}\n if (lv[b].val) {dsu.unionset(lv[b].val, lv[k].val);}\n if (lv[a].cnt) lv[a].val = lv[k].val;\n if (lv[b].cnt) lv[b].val = lv[k].val;\n lv[k].val = 0;\n }\n}\n\nvoid update(long long k, long long l, long long r, long long pos, long long val){\n dolazy(k, l, r);\n if (l > pos || pos > r) return;\n if (l == r){\n lv[cnt].val = val;\n lv[cnt].cnt = (val != 0);\n return;\n }\n long long mid = (l + r) / 2; long long nod = cnt;\n if (pos > mid){\n lv[nod].left = lv[k].left;\n lv[nod].right = ++cnt;\n update(lv[k].right, mid+1, r, pos, val);\n }\n else{\n lv[nod].left = ++cnt;\n lv[nod].right = lv[k].right;\n update(lv[k].left, l, mid, pos, val);\n }\n lv[nod].cnt = lv[lv[nod].left].cnt + lv[lv[nod].right].cnt;\n}\n\nvoid update(long long pos, long long val){\n root_ver[++ver] = ++cnt;\n update(root_ver[ver-1], 1, num, pos, val);\n}\n\nvoid update (long long k, long long l, long long r, long long L, long long R, long long val){\n dolazy(k, l, r);\n if (l > R || L > r) return;\n if (L <= l && r <= R){\n if (lv[k].val) dsu.unionset(lv[k].val, val);\n if (lv[k].cnt) lv[k].val = val;\n return;\n }\n long long mid = (l + r) / 2;\n update(lv[k].left, l, mid, L, R, val); update(lv[k].right, mid+1, r, L, R, val);\n}\n\nvoid dfs(long long u){\n if (check[u]) return;\n check[u] = 1; a[u] = lv[u].val; long long v;\n v = lv[u].left; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n v = lv[u].right; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n}\n\nvoid updatebit(long long i, long long val){\n while (i <= num) bit[i]+=val, i += i&(-i);\n}\n\nlong long get(long long l, long long r){\n long long ans = 0; l--;\n while (r > 0) ans += bit[r], r -= r&(-r);\n while (l > 0) ans -= bit[l], l -= l&(-l);\n return ans;\n}\n\nvoid init(){\n cin >> w >> h >> n;\n for (long long i = 1; i <= n; i++) cin >> x[0][i] >> y[0][i] >> x[1][i] >> y[1][i];\n x[0][n+1] = 0; y[0][n+1] = 0; x[1][n+1] = w; y[1][n+1] = 0;\n x[0][n+2] = 0; y[0][n+2] = h; x[1][n+2] = w; y[1][n+2] = h;\n x[0][n+3] = 0; y[0][n+3] = 0; x[1][n+3] = 0; y[1][n+3] = h;\n x[0][n+4] = w; y[0][n+4] = 0; x[1][n+4] = w; y[1][n+4] = h;\n n += 4;\n for (long long i = 1; i <= n; i++){\n if (x[0][i] > x[1][i] || y[0][i] > y[1][i]){\n swap(x[0][i], x[1][i]);\n swap(y[0][i], y[1][i]);\n }\n if (x[0][i] != x[1][i]) {\n mv.push_back(iii(ii(x[0][i], -1), i));\n mv.push_back(iii(ii(x[1][i], 1), i));\n vc.push_back(ii(y[0][i], i));\n }\n else{\n mv.push_back(iii(ii(x[0][i], 0), i));\n vc.push_back(ii(y[0][i], i));\n vc.push_back(ii(y[1][i], i));\n }\n }\n sort (mv.begin(), mv.end());\n sort (vc.begin(), vc.end());\n dsu.init(n);\n ans = -n;\n for (long long i = 0; i < vc.size(); i++){\n if (i == 0 || (i > 0 && vc[i].first != vc[i-1].first)) num++;\n long long z = vc[i].second;\n if (pos[0][z]) pos[1][z] = num;\n else pos[0][z] = num;\n }\n root_ver[++ver] = ++cnt; init(1, num);\n}\n\nint main(){\n ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n init();\n for (long long i = 0; i < mv.size(); i++){\n long long z = mv[i].second, val = mv[i].first.first;\n\n if (val == x[0][z] && val == x[1][z]) update(root_ver[ver], 1, num, pos[0][z], pos[1][z], z);\n else if (val == x[0][z]) update(pos[0][z], z);\n else update(pos[0][z], 0);\n\n if (val == x[0][z] && val == x[1][z]) ans += get(pos[0][z], pos[1][z]);\n else if (val == x[0][z]) updatebit(pos[0][z], 1);\n else updatebit(pos[0][z], -1);\n }\n for (long long i = 1; i <= cnt; i++) if (lv[i].val) dfs(i);\n ans += dsu.numdsu;\n cout << ans << \"\\n\";\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 149448, "score_of_the_acc": -1.1882, "final_rank": 9 }, { "submission_id": "aoj_0602_2535923", "code_snippet": "#include<bits/stdc++.h>\nconst long long N = 3e5 + 5;\nusing namespace std;\n\ntypedef pair <long long, long long> ii;\ntypedef pair <ii, long long> iii;\nvector <ii> vc;\nvector <iii> mv;\n\nlong long w, h, n, x[2][N], y[2][N], a[N], pos[2][N], num, bit[N];\nlong long cnt, ver, root_ver[N], ans;\nbool check[N];\n\nstruct {\n long long pset[N], numdsu;\n\n void init (long long n){\n for (long long i = 1; i <= n; i++) pset[i] = i;\n numdsu = n;\n }\n\n long long findset(long long i) {\n if (pset[i] != i) pset[i] = findset(pset[i]);\n return pset[i];\n }\n\n void unionset(long long i, long long j){\n if (findset(i) == findset(j)) return;\n pset[findset(i)] = findset(j);\n numdsu--;\n }\n} dsu;\n\nstruct node {\n long long val, left, right, cnt;\n} lv[30*N];\n\nvoid init(long long l, long long r){\n long long nod = cnt;\n if (l != r){\n long long mid = (l + r) / 2;\n lv[nod].left = ++cnt; init (l, mid);\n lv[nod].right = ++cnt; init (mid+1, r);\n }\n}\n\nvoid dolazy(long long k, long long l, long long r){\n if (lv[k].val == 0) return;\n if (l != r) {\n long long a = lv[k].left, b = lv[k].right;\n if (lv[a].val) {dsu.unionset(lv[a].val, lv[k].val);}\n if (lv[b].val) {dsu.unionset(lv[b].val, lv[k].val);}\n if (lv[a].cnt) lv[a].val = lv[k].val;\n if (lv[b].cnt) lv[b].val = lv[k].val;\n lv[k].val = 0;\n }\n}\n\nvoid update(long long k, long long l, long long r, long long pos, long long val){\n dolazy(k, l, r);\n if (l > pos || pos > r) return;\n if (l == r){\n lv[cnt].val = val;\n lv[cnt].cnt = (val != 0);\n return;\n }\n long long mid = (l + r) / 2; long long nod = cnt;\n if (pos > mid){\n lv[nod].left = lv[k].left;\n lv[nod].right = ++cnt;\n update(lv[k].right, mid+1, r, pos, val);\n }\n else{\n lv[nod].left = ++cnt;\n lv[nod].right = lv[k].right;\n update(lv[k].left, l, mid, pos, val);\n }\n lv[nod].cnt = lv[lv[nod].left].cnt + lv[lv[nod].right].cnt;\n}\n\nvoid update(long long pos, long long val){\n root_ver[++ver] = ++cnt;\n update(root_ver[ver-1], 1, num, pos, val);\n}\n\nvoid update (long long k, long long l, long long r, long long L, long long R, long long val){\n dolazy(k, l, r);\n if (l > R || L > r) return;\n if (L <= l && r <= R){\n if (lv[k].val) dsu.unionset(lv[k].val, val);\n if (lv[k].cnt) lv[k].val = val;\n return;\n }\n long long mid = (l + r) / 2;\n update(lv[k].left, l, mid, L, R, val); update(lv[k].right, mid+1, r, L, R, val);\n}\n\nvoid dfs(long long u){\n if (check[u]) return;\n check[u] = 1; a[u] = lv[u].val; long long v;\n v = lv[u].left; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n v = lv[u].right; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n}\n\nvoid updatebit(long long i, long long val){\n while (i <= num) bit[i]+=val, i += i&(-i);\n}\n\nlong long get(long long l, long long r){\n long long ans = 0; l--;\n while (r > 0) ans += bit[r], r -= r&(-r);\n while (l > 0) ans -= bit[l], l -= l&(-l);\n return ans;\n}\n\nvoid init(){\n cin >> w >> h >> n;\n for (long long i = 1; i <= n; i++) cin >> x[0][i] >> y[0][i] >> x[1][i] >> y[1][i];\n x[0][n+1] = 0; y[0][n+1] = 0; x[1][n+1] = w; y[1][n+1] = 0;\n x[0][n+2] = 0; y[0][n+2] = h; x[1][n+2] = w; y[1][n+2] = h;\n x[0][n+3] = 0; y[0][n+3] = 0; x[1][n+3] = 0; y[1][n+3] = h;\n x[0][n+4] = w; y[0][n+4] = 0; x[1][n+4] = w; y[1][n+4] = h;\n n += 4;\n for (long long i = 1; i <= n; i++){\n if (x[0][i] > x[1][i] || y[0][i] > y[1][i]){\n swap(x[0][i], x[1][i]);\n swap(y[0][i], y[1][i]);\n }\n if (x[0][i] != x[1][i]) {\n mv.push_back(iii(ii(x[0][i], -1), i));\n mv.push_back(iii(ii(x[1][i], 1), i));\n vc.push_back(ii(y[0][i], i));\n }\n else{\n mv.push_back(iii(ii(x[0][i], 0), i));\n vc.push_back(ii(y[0][i], i));\n vc.push_back(ii(y[1][i], i));\n }\n }\n sort (mv.begin(), mv.end());\n sort (vc.begin(), vc.end());\n dsu.init(n);\n ans = -n;\n for (long long i = 0; i < vc.size(); i++){\n if (i == 0 || (i > 0 && vc[i].first != vc[i-1].first)) num++;\n long long z = vc[i].second;\n if (pos[0][z]) pos[1][z] = num;\n else pos[0][z] = num;\n }\n root_ver[++ver] = ++cnt; init(1, num);\n}\n\nint main(){\n ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n init();\n for (long long i = 0; i < mv.size(); i++){\n long long z = mv[i].second, val = mv[i].first.first;\n if (val == x[0][z] && val == x[1][z]) update(root_ver[ver], 1, num, pos[0][z], pos[1][z], z);\n else if (val == x[0][z]) update(pos[0][z], z);\n else update(pos[0][z], 0);\n if (val == x[0][z] && val == x[1][z]) ans += get(pos[0][z], pos[1][z]);\n else if (val == x[0][z]) updatebit(pos[0][z], 1);\n else updatebit(pos[0][z], -1);\n }\n for (long long i = 1; i <= cnt; i++) if (lv[i].val) dfs(i);\n ans += dsu.numdsu;\n cout << ans << \"\\n\";\n}\n/*\n10 10 1\n2 3 2 4\n*/", "accuracy": 0.4864864864864865, "time_ms": 270, "memory_kb": 91476, "score_of_the_acc": -0.797, "final_rank": 15 }, { "submission_id": "aoj_0602_2535914", "code_snippet": "#include<bits/stdc++.h>\nconst int N = 2e5 + 50;\nusing namespace std;\n\ntypedef pair <int, int> ii;\ntypedef pair <ii, int> iii;\nvector <ii> vc;\nvector <iii> mv;\n\nint w, h, n, x[2][N], y[2][N], a[N], pos[2][N], num, bit[N];\nint cnt, ver, root_ver[N], ans;\nbool check[N];\n\nstruct {\n int pset[N], numdsu;\n\n void init (int n){\n for (int i = 1; i <= n; i++) pset[i] = i;\n numdsu = n;\n }\n\n int findset(int i) {\n if (pset[i] != i) pset[i] = findset(pset[i]);\n return pset[i];\n }\n\n void unionset(int i, int j){\n if (findset(i) == findset(j)) return;\n pset[findset(i)] = findset(j);\n numdsu--;\n }\n} dsu;\n\nstruct node {\n int val, left, right, cnt;\n} lv[30*N];\n\nvoid init(int l, int r){\n int nod = cnt;\n if (l != r){\n int mid = (l + r) / 2;\n lv[nod].left = ++cnt; init (l, mid);\n lv[nod].right = ++cnt; init (mid+1, r);\n }\n}\n\nvoid dolazy(int k, int l, int r){\n if (lv[k].val == 0) return;\n if (l != r) {\n int a = lv[k].left, b = lv[k].right;\n if (lv[a].val) {dsu.unionset(lv[a].val, lv[k].val);}\n if (lv[b].val) {dsu.unionset(lv[b].val, lv[k].val);}\n if (lv[a].cnt) lv[a].val = lv[k].val;\n if (lv[b].cnt) lv[b].val = lv[k].val;\n lv[k].val = 0;\n }\n}\n\nvoid update(int k, int l, int r, int pos, int val){\n dolazy(k, l, r);\n if (l > pos || pos > r) return;\n if (l == r){\n lv[cnt].val = val;\n lv[cnt].cnt = (val != 0);\n return;\n }\n int mid = (l + r) / 2; int nod = cnt;\n if (pos > mid){\n lv[nod].left = lv[k].left;\n lv[nod].right = ++cnt;\n update(lv[k].right, mid+1, r, pos, val);\n }\n else{\n lv[nod].left = ++cnt;\n lv[nod].right = lv[k].right;\n update(lv[k].left, l, mid, pos, val);\n }\n lv[nod].cnt = lv[lv[nod].left].cnt + lv[lv[nod].right].cnt;\n}\n\nvoid update(int pos, int val){\n root_ver[++ver] = ++cnt;\n update(root_ver[ver-1], 1, num, pos, val);\n}\n\nvoid update (int k, int l, int r, int L, int R, int val){\n dolazy(k, l, r);\n if (l > R || L > r) return;\n if (L <= l && r <= R){\n if (lv[k].val) dsu.unionset(lv[k].val, val);\n if (lv[k].cnt) lv[k].val = val;\n return;\n }\n int mid = (l + r) / 2;\n update(lv[k].left, l, mid, L, R, val); update(lv[k].right, mid+1, r, L, R, val);\n}\n\nvoid dfs(int u){\n if (check[u]) return;\n check[u] = 1; a[u] = lv[u].val; int v;\n v = lv[u].left; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n v = lv[u].right; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n}\n\nvoid updatebit(int i, int val){\n while (i <= num) bit[i]+=val, i += i&(-i);\n}\n\nint get(int l, int r){\n int ans = 0; l--;\n while (r > 0) ans += bit[r], r -= r&(-r);\n while (l > 0) ans -= bit[l], l -= l&(-l);\n return ans;\n}\n\nvoid init(){\n cin >> w >> h >> n;\n for (int i = 1; i <= n; i++) cin >> x[0][i] >> y[0][i] >> x[1][i] >> y[1][i];\n x[0][n+1] = 0; y[0][n+1] = 0; x[1][n+1] = w; y[1][n+1] = 0;\n x[0][n+2] = 0; y[0][n+2] = h; x[1][n+2] = w; y[1][n+2] = h;\n x[0][n+3] = 0; y[0][n+3] = 0; x[1][n+3] = 0; y[1][n+3] = h;\n x[0][n+4] = w; y[0][n+4] = 0; x[1][n+4] = w; y[1][n+4] = h;\n n += 4;\n for (int i = 1; i <= n; i++){\n if (x[0][i] > x[1][i] || y[0][i] > y[1][i]){\n swap(x[0][i], x[1][i]);\n swap(y[0][i], y[1][i]);\n }\n if (x[0][i] != x[1][i]) {\n mv.push_back(iii(ii(x[0][i], -1), i));\n mv.push_back(iii(ii(x[1][i], 1), i));\n vc.push_back(ii(y[0][i], i));\n }\n else{\n mv.push_back(iii(ii(x[0][i], 0), i));\n vc.push_back(ii(y[0][i], i));\n vc.push_back(ii(y[1][i], i));\n }\n }\n sort (mv.begin(), mv.end());\n sort (vc.begin(), vc.end());\n dsu.init(n);\n ans = -n;\n for (int i = 0; i < vc.size(); i++){\n if (i == 0 || (i > 0 && vc[i].first != vc[i-1].first)) num++;\n int z = vc[i].second;\n if (pos[0][z]) pos[1][z] = num;\n else pos[0][z] = num;\n }\n root_ver[++ver] = ++cnt; init(1, num);\n}\n\nint main(){\n ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n init();\n for (int i = 0; i < mv.size(); i++){\n int z = mv[i].second, val = mv[i].first.first;\n if (val == x[0][z] && val == x[1][z]) update(root_ver[ver], 1, num, pos[0][z], pos[1][z], z);\n else if (val == x[0][z]) update(pos[0][z], z);\n else update(pos[0][z], 0);\n if (val == x[0][z] && val == x[1][z]) ans += get(pos[0][z], pos[1][z]);\n else if (val == x[0][z]) updatebit(pos[0][z], 1);\n else updatebit(pos[0][z], -1);\n }\n for (int i = 1; i <= cnt; i++) if (lv[i].val) dfs(i);\n ans += dsu.numdsu;\n cout << ans << \"\\n\";\n}\n/*\n10 10 1\n2 3 2 4\n*/", "accuracy": 0.4864864864864865, "time_ms": 160, "memory_kb": 45528, "score_of_the_acc": -0.3295, "final_rank": 14 }, { "submission_id": "aoj_0602_2535910", "code_snippet": "#include<bits/stdc++.h>\nconst int N = 2e5 + 5;\nusing namespace std;\n\ntypedef pair <int, int> ii;\ntypedef pair <ii, int> iii;\nvector <ii> vc;\nvector <iii> mv;\n\nint w, h, n, x[2][N], y[2][N], a[N], pos[2][N], num, bit[N];\nint cnt, ver, root_ver[N], ans;\nbool check[N];\n\nstruct {\n int pset[N], numdsu;\n\n void init (int n){\n for (int i = 1; i <= n; i++) pset[i] = i;\n numdsu = n;\n }\n\n int findset(int i) {\n if (pset[i] != i) pset[i] = findset(pset[i]);\n return pset[i];\n }\n\n void unionset(int i, int j){\n if (findset(i) == findset(j)) return;\n pset[findset(i)] = findset(j);\n numdsu--;\n }\n} dsu;\n\nstruct node {\n int val, left, right, cnt;\n} lv[20*N];\n\nvoid init(int l, int r){\n int nod = cnt;\n if (l != r){\n int mid = (l + r) / 2;\n lv[nod].left = ++cnt; init (l, mid);\n lv[nod].right = ++cnt; init (mid+1, r);\n }\n}\n\nvoid dolazy(int k, int l, int r){\n if (lv[k].val == 0) return;\n if (l != r) {\n int a = lv[k].left, b = lv[k].right;\n if (lv[a].val) {dsu.unionset(lv[a].val, lv[k].val);}\n if (lv[b].val) {dsu.unionset(lv[b].val, lv[k].val);}\n if (lv[a].cnt) lv[a].val = lv[k].val;\n if (lv[b].cnt) lv[b].val = lv[k].val;\n lv[k].val = 0;\n }\n}\n\nvoid update(int k, int l, int r, int pos, int val){\n dolazy(k, l, r);\n if (l > pos || pos > r) return;\n if (l == r){\n lv[cnt].val = val;\n lv[cnt].cnt = (val != 0);\n return;\n }\n int mid = (l + r) / 2; int nod = cnt;\n if (pos > mid){\n lv[nod].left = lv[k].left;\n lv[nod].right = ++cnt;\n update(lv[k].right, mid+1, r, pos, val);\n }\n else{\n lv[nod].left = ++cnt;\n lv[nod].right = lv[k].right;\n update(lv[k].left, l, mid, pos, val);\n }\n lv[nod].cnt = lv[lv[nod].left].cnt + lv[lv[nod].right].cnt;\n}\n\nvoid update(int pos, int val){\n root_ver[++ver] = ++cnt;\n update(root_ver[ver-1], 1, num, pos, val);\n}\n\nvoid update (int k, int l, int r, int L, int R, int val){\n dolazy(k, l, r);\n if (l > R || L > r) return;\n if (L <= l && r <= R){\n if (lv[k].val) dsu.unionset(lv[k].val, val);\n if (lv[k].cnt) lv[k].val = val;\n return;\n }\n int mid = (l + r) / 2;\n update(lv[k].left, l, mid, L, R, val); update(lv[k].right, mid+1, r, L, R, val);\n}\n\nvoid dfs(int u){\n if (check[u]) return;\n check[u] = 1; a[u] = lv[u].val; int v;\n v = lv[u].left; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n v = lv[u].right; dfs(v);\n if (a[u] && a[v]) {dsu.unionset(a[u], a[v]);}\n else a[u] = max(a[u], a[v]);\n}\n\nvoid updatebit(int i, int val){\n while (i <= num) bit[i]+=val, i += i&(-i);\n}\n\nint get(int l, int r){\n int ans = 0; l--;\n while (r > 0) ans += bit[r], r -= r&(-r);\n while (l > 0) ans -= bit[l], l -= l&(-l);\n return ans;\n}\n\nvoid init(){\n cin >> w >> h >> n;\n for (int i = 1; i <= n; i++) cin >> x[0][i] >> y[0][i] >> x[1][i] >> y[1][i];\n x[0][n+1] = 0; y[0][n+1] = 0; x[1][n+1] = w; y[1][n+1] = 0;\n x[0][n+2] = 0; y[0][n+2] = h; x[1][n+2] = w; y[1][n+2] = h;\n x[0][n+3] = 0; y[0][n+3] = 0; x[1][n+3] = 0; y[1][n+3] = h;\n x[0][n+4] = w; y[0][n+4] = 0; x[1][n+4] = w; y[1][n+4] = h;\n n += 4;\n for (int i = 1; i <= n; i++){\n if (x[0][i] > x[1][i] || y[0][i] > y[1][i]){\n swap(x[0][i], x[1][i]);\n swap(y[0][i], y[1][i]);\n }\n if (x[0][i] != x[1][i]) {\n mv.push_back(iii(ii(x[0][i], -1), i));\n mv.push_back(iii(ii(x[1][i], 1), i));\n vc.push_back(ii(y[0][i], i));\n }\n else{\n mv.push_back(iii(ii(x[0][i], 0), i));\n vc.push_back(ii(y[0][i], i));\n vc.push_back(ii(y[1][i], i));\n }\n }\n sort (mv.begin(), mv.end());\n sort (vc.begin(), vc.end());\n dsu.init(n);\n ans = -n;\n for (int i = 0; i < vc.size(); i++){\n if (i == 0 || (i > 0 && vc[i].first != vc[i-1].first)) num++;\n int z = vc[i].second;\n if (pos[0][z]) pos[1][z] = num;\n else pos[0][z] = num;\n }\n root_ver[++ver] = ++cnt; init(1, num);\n}\n\nint main(){\n ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n init();\n for (int i = 0; i < mv.size(); i++){\n int z = mv[i].second, val = mv[i].first.first;\n if (val == x[0][z] && val == x[1][z]) update(root_ver[ver], 1, num, pos[0][z], pos[1][z], z);\n else if (val == x[0][z]) update(pos[0][z], z);\n else update(pos[0][z], 0);\n if (val == x[0][z] && val == x[1][z]) ans += get(pos[0][z], pos[1][z]);\n else if (val == x[0][z]) updatebit(pos[0][z], 1);\n else updatebit(pos[0][z], -1);\n }\n for (int i = 1; i <= cnt; i++) if (lv[i].val) dfs(i);\n ans += dsu.numdsu;\n cout << ans << \"\\n\";\n}\n/*\n10 10 1\n2 3 2 4\n*/", "accuracy": 0.47297297297297297, "time_ms": 90, "memory_kb": 25416, "score_of_the_acc": -0.0991, "final_rank": 16 }, { "submission_id": "aoj_0602_2533883", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Line {\n int x1, y1, x2, y2;\n Line (int x1, int y1, int x2, int y2) :\n x1(x1), y1(y1), x2(x2), y2(y2) {}\n};\n\nstruct Query {\n int l, r, id;\n\n Query (int l, int r, int id) :\n l(l), r(r), id(id) {}\n\n void dbg() {\n cout << \"Query \" << l << ' ' << r << ' ' << id << '\\n';\n }\n};\n\nstruct Update {\n int p, t, id;\n\n Update (int p, int t, int id) :\n p(p), t(t), id(id) {}\n\n void dbg() {\n cout << \"Update \" << p << ' ' << t << ' ' << id << '\\n';\n }\n};\n\nconst int N = 100010;\n\nint w, h, n, cnt;\nint it[2][8 * N];\nint go[2][40 * N];\nint pos[40 * N];\nbool visit[40 * N];\nlong long cntv, cnte, cntc;\nvector<Line> a;\nvector<int> vx, vy, G[N];\nvector<Update> update[N * 2];\nvector<Query> query[N * 2];\n\nvoid addEdge(int u, int v) {\n// cout << u << ' ' << v << '\\n';\n G[u].push_back(v), G[v].push_back(u);\n}\n\nvoid add(int x, int y) {\n if (pos[x]) addEdge(pos[x], y);\n pos[x] = y;\n if (visit[x]) return; visit[x] = 1;\n for (int i = 0; i < 2; ++i) {\n if (!go[i][x]) continue;\n add(go[i][x], y);\n }\n}\n\nvoid upd(int i, int l, int r, int p, int t, int id) {\n it[0][i] += t, it[1][i] = ++cnt;\n if (!it[0][i]) it[1][i] = 0;\n if (l == r) {\n if (t == 1) pos[it[1][i]] = id; return;\n }\n int mid = (l + r) >> 1;\n if (p <= mid) upd(i << 1, l, mid, p, t, id);\n else upd(i << 1 | 1, mid + 1, r, p, t, id);\n go[0][it[1][i]] = it[1][i << 1], go[1][it[1][i]] = it[1][i << 1 | 1];\n}\n\nint get(int i, int l, int r, int u, int v, int id) {\n if (l > v || u > r) return 0;\n if (u <= l && r <= v) {\n if (it[1][i]) add(it[1][i], id);\n return it[0][i];\n }\n int mid = (l + r) >> 1;\n return get(i << 1, l, mid, u, v, id) + get(i << 1 | 1, mid + 1, r, u, v, id);\n}\n\nvoid dfs(int u) {\n visit[u] = 1;\n for (auto v : G[u]) {\n if (!visit[v]) dfs(v);\n }\n}\n\nvoid addLine(int x1, int y1, int x2, int y2) {\n a.push_back(Line(x1, y1, x2, y2));\n vx.push_back(x1), vx.push_back(x2);\n vy.push_back(y1), vy.push_back(y2);\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin >> w >> h >> n;\n\n addLine(0, 0, 0, h);\n addLine(0, h, w, h);\n addLine(w, 0, w, h);\n addLine(0, 0, w, 0);\n\n for (int i = 0; i < n; ++i) {\n int x1, y1, x2, y2;\n cin >> x1 >> y1 >> x2 >> y2;\n addLine(x1, y1, x2, y2);\n }\n\n n += 4, cntv = n * 2, cnte = cnt = n;\n sort(vx.begin(), vx.end()), sort(vy.begin(), vy.end());\n\n for (int i = 0; i < n; ++i) {\n a[i].x1 = lower_bound(vx.begin(), vx.end(), a[i].x1) - vx.begin();\n a[i].y1 = lower_bound(vy.begin(), vy.end(), a[i].y1) - vy.begin();\n a[i].x2 = lower_bound(vx.begin(), vx.end(), a[i].x2) - vx.begin();\n a[i].y2 = lower_bound(vy.begin(), vy.end(), a[i].y2) - vy.begin();\n\n if (a[i].y1 == a[i].y2) {\n update[a[i].x1].push_back(Update(a[i].y1, 1, i + 1));\n update[a[i].x2 + 1].push_back(Update(a[i].y2, -1, i + 1));\n }\n else {\n query[a[i].x1].push_back(Query(a[i].y1, a[i].y2, i + 1));\n }\n }\n\n for (int i = 0; i < n * 2; ++i) {\n for (auto j : update[i]) {\n if (j.t == -1) {\n// j.dbg();\n upd(1, 0, n * 2, j.p, j.t, j.id);\n }\n }\n for (auto j : update[i]) {\n if (j.t == 1) {\n// j.dbg();\n upd(1, 0, n * 2, j.p, j.t, j.id);\n }\n }\n for (auto j : query[i]) {\n// j.dbg();\n int tmp = get(1, 0, n * 2, j.l, j.r, j.id);\n cntv += tmp, cnte += tmp * 2;\n }\n }\n memset(visit, 0, sizeof(visit));\n for (int i = 1; i <= n; ++i) {\n if (!visit[i]) dfs(i), cntc++;\n }\n\n //cout << \"End \" << cntc << ' ' << cntv << ' ' << cnte << '\\n';\n cout << cntc - cntv + cnte << '\\n';\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 81308, "score_of_the_acc": -0.7222, "final_rank": 8 }, { "submission_id": "aoj_0602_2533841", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct Line {\n int x1, y1, x2, y2;\n Line (int x1, int y1, int x2, int y2) :\n x1(x1), y1(y1), x2(x2), y2(y2) {}\n};\n\nstruct Query {\n int l, r, id;\n\n Query (int l, int r, int id) :\n l(l), r(r), id(id) {}\n\n void dbg() {\n cout << \"Query \" << l << ' ' << r << ' ' << id << '\\n';\n }\n};\n\nstruct Update {\n int p, t, id;\n\n Update (int p, int t, int id) :\n p(p), t(t), id(id) {}\n\n void dbg() {\n cout << \"Update \" << p << ' ' << t << ' ' << id << '\\n';\n }\n};\n\nconst int N = 100005;\n\nint w, h, n;\nint it[2][8 * N];\nint go[2][40 * N];\nint pos[40 * N];\nbool visit[40 * N];\nint cnt, cntv, cnte, cntc;\nvector<Line> a;\nvector<int> vx, vy, G[N];\nvector<Update> update[N * 2];\nvector<Query> query[N * 2];\n\nvoid addEdge(int u, int v) {\n //cout << u << ' ' << v << '\\n';\n G[u].push_back(v), G[v].push_back(u);\n}\n\nvoid add(int x, int y) {\n if (pos[x]) addEdge(pos[x], y);\n pos[x] = y;\n if (visit[x]) return; visit[x] = 1;\n for (int i = 0; i < 2; ++i) {\n if (!go[i][x]) continue;\n add(go[i][x], y);\n }\n}\n\nvoid upd(int i, int l, int r, int p, int t, int id) {\n it[0][i] += t, it[1][i] = ++cnt;\n if (!it[0][i]) it[1][i] = 0;\n if (l == r) {\n if (t == 1) pos[it[1][i]] = id; return;\n }\n int mid = (l + r) >> 1;\n if (p <= mid) upd(i << 1, l, mid, p, t, id);\n else upd(i << 1 | 1, mid + 1, r, p, t, id);\n go[0][it[1][i]] = it[1][i << 1], go[1][it[1][i]] = it[1][i << 1 | 1];\n}\n\nint get(int i, int l, int r, int u, int v, int id) {\n if (l > v || u > r) return 0;\n if (u <= l && r <= v) {\n if (it[1][i]) add(it[1][i], id);\n return it[0][i];\n }\n int mid = (l + r) >> 1;\n return get(i << 1, l, mid, u, v, id) + get(i << 1 | 1, mid + 1, r, u, v, id);\n}\n\nvoid dfs(int u) {\n visit[u] = 1;\n for (auto v : G[u]) {\n if (!visit[v]) dfs(v);\n }\n}\n\nvoid addLine(int x1, int y1, int x2, int y2) {\n a.push_back(Line(x1, y1, x2, y2));\n vx.push_back(x1), vx.push_back(x2);\n vy.push_back(y1), vy.push_back(y2);\n}\n\nint main() {\n// freopen(\"in.txt\", \"r\", stdin);\n// freopen(\"out.txt\", \"w\", stdout);\n ios::sync_with_stdio(false);\n cin >> w >> h >> n;\n\n addLine(0, 0, 0, h);\n addLine(0, h, w, h);\n addLine(w, 0, w, h);\n addLine(0, 0, w, 0);\n\n for (int i = 0; i < n; ++i) {\n int x1, y1, x2, y2;\n cin >> x1 >> y1 >> x2 >> y2;\n addLine(x1, y1, x2, y2);\n }\n\n n += 4, cntv = n * 2, cnte = cnt = n;\n sort(vx.begin(), vx.end()), sort(vy.begin(), vy.end());\n\n for (int i = 0; i < n; ++i) {\n a[i].x1 = lower_bound(vx.begin(), vx.end(), a[i].x1) - vx.begin();\n a[i].y1 = lower_bound(vy.begin(), vy.end(), a[i].y1) - vy.begin();\n a[i].x2 = lower_bound(vx.begin(), vx.end(), a[i].x2) - vx.begin();\n a[i].y2 = lower_bound(vy.begin(), vy.end(), a[i].y2) - vy.begin();\n\n if (a[i].y1 == a[i].y2) {\n update[a[i].x1].push_back(Update(a[i].y1, 1, i + 1));\n update[a[i].x2 + 1].push_back(Update(a[i].y2, -1, i + 1));\n }\n else {\n query[a[i].x1].push_back(Query(a[i].y1, a[i].y2, i + 1));\n }\n }\n\n for (int i = 0; i < n * 2; ++i) {\n for (auto j : update[i]) {\n if (j.t == -1) {\n //j.dbg();\n upd(1, 0, n * 2, j.p, j.t, j.id);\n }\n }\n for (auto j : update[i]) {\n if (j.t == 1) {\n //j.dbg();\n upd(1, 0, n * 2, j.p, j.t, j.id);\n }\n }\n for (auto j : query[i]) {\n //j.dbg();\n int tmp = get(1, 0, n * 2, j.l, j.r, j.id);\n cntv += tmp, cnte += tmp * 2;\n }\n }\n\n memset(visit, 0, sizeof(visit));\n for (int i = 1; i <= n; ++i) {\n if (!visit[i]) dfs(i), cntc++;\n }\n\n //cout << \"End \" << cntc << ' ' << cntv << ' ' << cnte << '\\n';\n cout << cntc - cntv + cnte << '\\n';\n}", "accuracy": 0.6351351351351351, "time_ms": 270, "memory_kb": 74336, "score_of_the_acc": -0.6709, "final_rank": 13 }, { "submission_id": "aoj_0602_2396414", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define pb push_back\n#define y1 y233\nusing ll = long long;\nusing pii = pair <int, int>;\n\nconst int N = 1e5L + 11;\nconst int M = N * 4 + 11;\nconst int inf = 2e9L;\n\nint x1[N], y1[N], x2[N], y2[N];\n\nint lowbit(int x) { return x & (-x); }\nstruct BIT {\n\tint b[M];\n\tvoid clear() { fill(b, b + M, 0); }\n\tvoid change(int p, int x) {\n\t\tfor(p += 5; p < M; p += lowbit(p))\n\t\t\tb[p] += x;\n\t}\n\tint query(int p) {\n\t\tint r = 0;\n\t\tfor(p += 5; p; p -= lowbit(p))\n\t\t\tr += b[p];\n\t\treturn r;\n\t}\n}bit;\n\nstruct event {\n\tint p, type, k1, k2, id;\n\tbool operator <(event e) const {\n\t\treturn tie(p, type, k1, k2, id) < tie(e.p, e.type, e.k1, e.k2, e.id);\n\t}\n};\n\nint p[N];\nint find(int x) {\n\tif(p[x] == x) return x;\n\treturn p[x] = find(p[x]);\n}\n\nint main() {\n\tios :: sync_with_stdio(false);\n\tint w, h, n; cin >> w >> h >> n;\n\tfor(int i = 1; i <= n; i ++)\n\t\tcin >> x1[i] >> y1[i] >> x2[i] >> y2[i];\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = 0; y2[n] = h;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = 0; y2[n] = h;\n\t\n\t{\n\t\tmap <int, int> mp;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tmp[x1[i]] = 0; mp[y1[i]] = 0;\n\t\t\tmp[x2[i]] = 0; mp[y2[i]] = 0;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor(auto &p : mp)\n\t\t\tp.second = ++ cnt;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\t//swap(x1[i], y1[i]); swap(x2[i], y2[i]);\n\t\t\tx1[i] = mp[x1[i]]; y1[i] = mp[y1[i]];\n\t\t\tx2[i] = mp[x2[i]]; y2[i] = mp[y2[i]];\n\t\t}\n\t}\n\t\n\tvector <event> eves; int cnt = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(x1[i] == x2[i]) {\n\t\t\tif(y1[i] > y2[i]) swap(y1[i], y2[i]);\n\t\t\teves.pb({y1[i], 0, x1[i], 1, ++ cnt});\n\t\t\teves.pb({y2[i] + 1, 0, x1[i], -1, cnt});\n\t\t} else {\n\t\t\tif(x1[i] > x2[i]) swap(x1[i], x2[i]);\n\t\t\teves.pb({y1[i], 1, x1[i], x2[i], 0});\n\t\t}\n\tiota(p, p + cnt + 1, 0);\n\tsort(eves.begin(), eves.end());\n\n\tset <pii> sts, stp;\n\tfor(int i = 0; i < M; i ++)\n\t\tsts.insert({i, i});\n\tstp.insert({M, 0});\n\n\tll m = 0, sp = 0;\n\tbit.clear();\n\tfor(auto e : eves)\n\t\tif(e.type == 0) {\n\t\t\tbit.change(e.k1, e.k2);\n\n\t\t\tif(e.k2 == 1) {\n\t\t\t\tstp.insert({e.k1, e.id});\n\t\t\t\tpii p = *(-- sts.lower_bound({e.k1, inf})); sts.erase(p);\n\t\t\t\tif(p.fi != e.k1) sts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, e.k1});\n\t\t\t\tif(p.se != e.k1) sts.insert({e.k1 + 1, p.se});\n\t\t\t} else\n\t\t\t\tstp.erase({e.k1, e.id});\n\t\t} else {\n\t\t\tm += bit.query(e.k2);\n\t\t\tm -= bit.query(e.k1 - 1);\n\n\t\t\tauto it = stp.lower_bound({e.k1, 0});\n\t\t\tif(it -> first > e.k2) { sp ++; continue; }\n\t\t\tint x = it -> second;\n\n\t\t\tit = -- sts.lower_bound({e.k1, inf});\n\n\t\t\tif(it -> fi != e.k1) {\n\t\t\t\tpii p = *it; sts.erase(it);\n\t\t\t\tsts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, p.se});\n\t\t\t\tit = -- sts.lower_bound({e.k1, inf});\n\t\t\t}\n\t\t\tint l = it -> fi, r;\n\n\t\t\twhile(it -> fi <= e.k2) {\n\t\t\t\tif(it -> se > e.k2) {\n\t\t\t\t\tpii p = *it; sts.erase(it);\n\t\t\t\t\tsts.insert({p.fi, e.k2});\n\t\t\t\t\tsts.insert({e.k2 + 1, p.se});\n\t\t\t\t\tit = -- sts.lower_bound({p.fi, inf});\n\t\t\t\t}\n\n\t\t\t\tr = it -> se;\n\t\t\t\tauto is = stp.lower_bound({it -> fi, 0});\n\t\t\t\tif(is -> fi <= it -> se) {\n\t\t\t\t\tint y = is -> se;\n\t\t\t\t\tint a = find(x), b = find(y);\n\t\t\t\t\tif(a != b) p[b] = a;\n\t\t\t\t}\n\t\t\t\tis = it ++;\n\t\t\t\tsts.erase(is);\n\t\t\t}\n\t\t\tsts.insert({l, r});\n\t\t}\n\tll ans = m - n + sp;\n\tfor(int i = 1; i <= cnt; i ++)\n\t\tif(find(i) == i) ans ++;\n\tcout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 30132, "score_of_the_acc": -0.6044, "final_rank": 6 }, { "submission_id": "aoj_0602_2396363", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define pb push_back\n#define y1 y233\nusing ll = long long;\nusing pii = pair <int, int>;\n\nconst int N = 1e5L + 11;\nconst int M = N * 4 + 11;\nconst int inf = 2e9L;\n\nint x1[N], y1[N], x2[N], y2[N];\n\nint lowbit(int x) { return x & (-x); }\nstruct BIT {\n\tint b[M];\n\tvoid clear() { fill(b, b + M, 0); }\n\tvoid change(int p, int x) {\n\t\tfor(p += 5; p < M; p += lowbit(p))\n\t\t\tb[p] += x;\n\t}\n\tint query(int p) {\n\t\tint r = 0;\n\t\tfor(p += 5; p; p -= lowbit(p))\n\t\t\tr += b[p];\n\t\treturn r;\n\t}\n}bit;\n\nstruct event {\n\tint p, type, k1, k2, id;\n\tbool operator <(event e) const {\n\t\treturn tie(p, type, k1, k2, id) < tie(e.p, e.type, e.k1, e.k2, e.id);\n\t}\n};\n\nint p[N];\nint find(int x) {\n\tif(p[x] == x) return x;\n\treturn p[x] = find(p[x]);\n}\n\nint main() {\n\tios :: sync_with_stdio(false);\n\tint w, h, n; cin >> w >> h >> n;\n\tfor(int i = 1; i <= n; i ++)\n\t\tcin >> x1[i] >> y1[i] >> x2[i] >> y2[i];\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = 0; y2[n] = h;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = 0; y2[n] = h;\n\t\n\t{\n\t\tmap <int, int> mp;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tmp[x1[i]] = 0; mp[y1[i]] = 0;\n\t\t\tmp[x2[i]] = 0; mp[y2[i]] = 0;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor(auto &p : mp)\n\t\t\tp.second = ++ cnt;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\t//swap(x1[i], y1[i]); swap(x2[i], y2[i]);\n\t\t\tx1[i] = mp[x1[i]]; y1[i] = mp[y1[i]];\n\t\t\tx2[i] = mp[x2[i]]; y2[i] = mp[y2[i]];\n\t\t}\n\t}\n\t\n\tvector <event> eves; int cnt = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(x1[i] == x2[i]) {\n\t\t\tif(y1[i] > y2[i]) swap(y1[i], y2[i]);\n\t\t\teves.pb({y1[i], 0, x1[i], 1, ++ cnt});\n\t\t\teves.pb({y2[i] + 1, 0, x1[i], -1, cnt});\n\t\t} else {\n\t\t\tif(x1[i] > x2[i]) swap(x1[i], x2[i]);\n\t\t\teves.pb({y1[i], 1, x1[i], x2[i], 0});\n\t\t}\n\tiota(p, p + cnt + 1, 0);\n\tsort(eves.begin(), eves.end());\n\n\tset <pii> sts, stp;\n\tfor(int i = 0; i < M; i ++)\n\t\tsts.insert({i, i});\n\tstp.insert({M, 0});\n\n\tll m = 0, sp = 0;\n\tbit.clear();\n\tfor(auto e : eves)\n\t\tif(e.type == 0) {\n\t\t\tbit.change(e.k1, e.k2);\n\n\t\t\tif(e.k2 == 1) {\n\t\t\t\tstp.insert({e.k1, e.id});\n\t\t\t\tpii p = *(-- sts.lower_bound({e.k1, inf})); sts.erase(p);\n\t\t\t\tif(p.fi != e.k1) sts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, e.k1});\n\t\t\t\tif(p.se != e.k1) sts.insert({e.k1 + 1, p.se});\n\t\t\t} else {\n\t\t\t\tstp.erase({e.k1, e.id});\n\t\t\t}\n\t\t} else {\n\t\t\tm += bit.query(e.k2);\n\t\t\tm -= bit.query(e.k1 - 1);\n\n\t\t\tauto it = stp.lower_bound({e.k1, 0});\n\t\t\tif(it -> first > e.k2) { sp ++; continue; }\n\t\t\tint x = it -> second;\n\n\t\t\tit = -- sts.lower_bound({e.k1, inf});\n\t\t\tint l = it -> first, r = it -> second;\n\t\t\twhile(1) {\n\t\t\t\tr = it -> second;\n\t\t\t\tauto is = stp.lower_bound({it -> first, 0});\n\t\t\t\tif(is -> first <= it -> second) {\n\t\t\t\t\tint y = is -> second;\n\t\t\t\t\tint a = find(x), b = find(y);\n\t\t\t\t\tif(a != b) p[b] = a;\n\t\t\t\t}\n\n\t\t\t\tis = it ++;\n\t\t\t\tif(is -> second >= e.k2) { sts.erase(is); break; }\n\t\t\t\tsts.erase(is);\n\t\t\t}\n\t\t\tsts.insert({l, r});\n\t\t}\n\tint ans = m - n + sp;\n\tfor(int i = 1; i <= cnt; i ++)\n\t\tif(find(i) == i) ans ++;\n\tcout << ans << '\\n';\n}", "accuracy": 0.0945945945945946, "time_ms": 90, "memory_kb": 23524, "score_of_the_acc": -0.0852, "final_rank": 17 }, { "submission_id": "aoj_0602_2396314", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define pb push_back\n#define y1 y233\nusing ll = long long;\nusing pii = pair <int, int>;\n\nconst int N = 1e5L + 11;\nconst int M = N * 4 + 11;\nconst int inf = 2e9L;\n\nint x1[N], y1[N], x2[N], y2[N];\n\nint lowbit(int x) { return x & (-x); }\nstruct BIT {\n\tint b[M];\n\tvoid clear() { fill(b, b + M, 0); }\n\tvoid change(int p, int x) {\n\t\tfor(p += 5; p < M; p += lowbit(p))\n\t\t\tb[p] += x;\n\t}\n\tint query(int p) {\n\t\tint r = 0;\n\t\tfor(p += 5; p; p -= lowbit(p))\n\t\t\tr += b[p];\n\t\treturn r;\n\t}\n}bit;\n\nstruct event {\n\tint p, type, k1, k2, id;\n\tbool operator <(event e) const {\n\t\treturn tie(p, type, k1, k2, id) < tie(e.p, e.type, e.k1, e.k2, e.id);\n\t}\n};\n\nint p[N];\nint find(int x) {\n\tif(p[x] == x) return x;\n\treturn p[x] = find(p[x]);\n}\n\nint main() {\n\tios :: sync_with_stdio(false);\n\tint w, h, n; cin >> w >> h >> n;\n\tfor(int i = 1; i <= n; i ++)\n\t\tcin >> x1[i] >> y1[i] >> x2[i] >> y2[i];\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = 0; y2[n] = h;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = 0; y2[n] = h;\n\t/*\n\t{\n\t\tmap <int, int> mp;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tmp[x1[i]] = 0; mp[y1[i]] = 0;\n\t\t\tmp[x2[i]] = 0; mp[y2[i]] = 0;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor(auto &p : mp)\n\t\t\tp.second = ++ cnt;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tx1[i] = mp[x1[i]]; y1[i] = mp[y1[i]];\n\t\t\tx2[i] = mp[x2[i]]; y2[i] = mp[y2[i]];\n\t\t}\n\t}\n\t*/\n\tvector <event> eves; int cnt = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(x1[i] == x2[i]) {\n\t\t\tif(y1[i] > y2[i]) swap(y1[i], y2[i]);\n\t\t\teves.pb({y1[i], 0, x1[i], 1, ++ cnt});\n\t\t\teves.pb({y2[i] + 1, 0, x1[i], -1, cnt});\n\t\t} else {\n\t\t\tif(x1[i] > x2[i]) swap(x1[i], x2[i]);\n\t\t\teves.pb({y1[i], 1, x1[i], x2[i], 0});\n\t\t}\n\tiota(p, p + cnt + 1, 0);\n\tsort(eves.begin(), eves.end());\n\n\tset <pii> sts, stp;\n\tfor(int i = 0; i < M; i ++)\n\t\tsts.insert({i, i});\n\tstp.insert({M, 0});\n\n\tll m = 0, sp = 0;\n\tbit.clear();\n\tfor(auto e : eves)\n\t\tif(e.type == 0) {\n\t\t\tbit.change(e.k1, e.k2);\n\n\t\t\tif(e.k2 == 1) {\n\t\t\t\tstp.insert({e.k1, e.id});\n\t\t\t\tpii p = *(-- sts.lower_bound({e.k1, inf})); sts.erase(p);\n\t\t\t\tif(p.fi != e.k1) sts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, e.k1});\n\t\t\t\tif(p.se != e.k1) sts.insert({e.k1 + 1, p.se});\n\t\t\t} else {\n\t\t\t\tstp.erase({e.k1, e.id});\n\t\t\t}\n\t\t} else {\n\t\t\tm += bit.query(e.k2);\n\t\t\tm -= bit.query(e.k1 - 1);\n\n\t\t\tauto it = stp.lower_bound({e.k1, 0});\n\t\t\tif(it -> first > e.k2) { sp ++; continue; }\n\t\t\tint x = it -> second;\n\n\t\t\tit = -- sts.lower_bound({e.k1, inf});\n\t\t\tint l = it -> first, r = it -> second;\n\t\t\twhile(1) {\n\t\t\t\tauto is = stp.lower_bound({it -> first, 0});\n\t\t\t\tif(is -> first <= it -> second) {\n\t\t\t\t\tint y = is -> second;\n\t\t\t\t\tint a = find(x), b = find(y);\n\t\t\t\t\tif(a != b) p[b] = a;\n\t\t\t\t}\n\n\t\t\t\tis = it ++;\n\t\t\t\tr = it -> second;\n\t\t\t\tif(is -> second >= e.k2) { sts.erase(is); break; }\n\t\t\t\tsts.erase(is);\n\t\t\t}\n\t\t\tsts.insert({l, r});\n\t\t}\n\tint ans = m - n + sp;\n\tfor(int i = 1; i <= cnt; i ++)\n\t\tif(find(i) == i) ans ++;\n\tcout << ans << '\\n';\n}", "accuracy": 0.06756756756756757, "time_ms": 90, "memory_kb": 23488, "score_of_the_acc": -0.085, "final_rank": 18 }, { "submission_id": "aoj_0602_2396254", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define pb push_back\n#define y1 y233\nusing ll = long long;\nusing pii = pair <int, int>;\n\nconst int N = 1e5L + 11;\nconst int M = N * 4 + 11;\n\nint x1[N], y1[N], x2[N], y2[N];\n\nint lowbit(int x) { return x & (-x); }\nstruct BIT {\n\tint b[M];\n\tvoid clear() { fill(b, b + M, 0); }\n\tvoid change(int p, int x) {\n\t\tfor(p += 5; p < M; p += lowbit(p))\n\t\t\tb[p] += x;\n\t}\n\tint query(int p) {\n\t\tint r = 0;\n\t\tfor(p += 5; p; p -= lowbit(p))\n\t\t\tr += b[p];\n\t\treturn r;\n\t}\n}bit;\n\nstruct event {\n\tint p, type, k1, k2, id;\n\tbool operator <(event e) const {\n\t\treturn tie(p, type, k1, k2, id) < tie(e.p, e.type, e.k1, e.k2, e.id);\n\t}\n};\n\nint p[N];\nint find(int x) {\n\tif(p[x] == x) return x;\n\treturn p[x] = find(p[x]);\n}\n\nint main() {\n\tios :: sync_with_stdio(false);\n\tint w, h, n; cin >> w >> h >> n;\n\tfor(int i = 1; i <= n; i ++)\n\t\tcin >> x1[i] >> y1[i] >> x2[i] >> y2[i];\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = 0; y2[n] = h;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = 0; y2[n] = h;\n\t{\n\t\tmap <int, int> mp;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tmp[x1[i]] = 0; mp[y1[i]] = 0;\n\t\t\tmp[x2[i]] = 0; mp[y2[i]] = 0;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor(auto &p : mp)\n\t\t\tp.second = ++ cnt;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tx1[i] = mp[x1[i]]; y1[i] = mp[y1[i]];\n\t\t\tx2[i] = mp[x2[i]]; y2[i] = mp[y2[i]];\n\t\t}\n\t}\n\tvector <event> eves; int cnt = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(x1[i] == x2[i]) {\n\t\t\tif(y1[i] > y2[i]) swap(y1[i], y2[i]);\n\t\t\teves.pb({y1[i], 0, x1[i], 1, ++ cnt});\n\t\t\teves.pb({y2[i] + 1, 0, x1[i], -1, cnt});\n\t\t} else {\n\t\t\tif(x1[i] > x2[i]) swap(x1[i], x2[i]);\n\t\t\teves.pb({y1[i], 1, x1[i], x2[i], 0});\n\t\t}\n\tiota(p, p + cnt + 1, 0);\n\tsort(eves.begin(), eves.end());\n\n\tset <pii> sts, stp;\n\tfor(int i = 0; i < M; i ++)\n\t\tsts.insert({i, i});\n\tstp.insert({M, 0});\n\n\tll m = 0;\n\tbit.clear();\n\tfor(auto e : eves)\n\t\tif(e.type == 0) {\n\t\t\tbit.change(e.k1, e.k2);\n\n\t\t\tif(e.k2 == 1) {\n\t\t\t\tstp.insert({e.k1, e.id});\n\t\t\t\tpii p = *sts.lower_bound({e.k1, 0}); sts.erase(p);\n\t\t\t\tif(p.fi != e.k1) sts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, e.k1});\n\t\t\t\tif(p.se != e.k1) sts.insert({e.k1 + 1, p.se});\n\t\t\t} else {\n\t\t\t\tstp.erase({e.k1, e.id});\n\t\t\t}\n\t\t} else {\n\t\t\tm += bit.query(e.k2);\n\t\t\tm -= bit.query(e.k1 - 1);\n\n\t\t\tauto it = stp.lower_bound({e.k1, 0});\n\t\t\tif(it -> first > e.k2) { m ++; continue; }\n\t\t\tint x = it -> second;\n\n\t\t\tit = sts.lower_bound({e.k1, 0});\n\t\t\tif(e.k1 != it -> fi) it --;\n\t\t\tint l = it -> first, r = it -> second;\n\t\t\twhile(1) {\n\t\t\t\tauto is = stp.lower_bound({it -> first, 0});\n\t\t\t\tif(is -> first <= it -> second) {\n\t\t\t\t\tint y = is -> second;\n\t\t\t\t\tint a = find(x), b = find(y);\n\t\t\t\t\tif(a != b) p[b] = a;\n\t\t\t\t}\n\n\t\t\t\tis = it ++;\n\t\t\t\tr = it -> second;\n\t\t\t\tif(is -> second >= e.k2) { sts.erase(is); break; }\n\t\t\t\tsts.erase(is);\n\t\t\t}\n\t\t\tsts.insert({l, r});\n\t\t}\n\tint ans = m - n;\n\tfor(int i = 1; i <= cnt; i ++)\n\t\tif(find(i) == i) ans ++;\n\tcout << ans << '\\n';\n}", "accuracy": 0.04054054054054054, "time_ms": 80, "memory_kb": 23532, "score_of_the_acc": -0.0735, "final_rank": 19 }, { "submission_id": "aoj_0602_2396218", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define pb push_back\n#define y1 y233\nusing ll = long long;\nusing pii = pair <int, int>;\n\nconst int N = 1e5L + 11;\nconst int M = N * 4 + 11;\n\nint x1[N], y1[N], x2[N], y2[N];\n\nint lowbit(int x) { return x & (-x); }\nstruct BIT {\n\tint b[M];\n\tvoid clear() { fill(b, b + M, 0); }\n\tvoid change(int p, int x) {\n\t\tfor(p += 5; p < M; p += lowbit(p))\n\t\t\tb[p] += x;\n\t}\n\tint query(int p) {\n\t\tint r = 0;\n\t\tfor(p += 5; p; p -= lowbit(p))\n\t\t\tr += b[p];\n\t\treturn r;\n\t}\n}bit;\n\nstruct event {\n\tint p, type, k1, k2, id;\n\tbool operator <(event e) const {\n\t\treturn tie(p, type, k1, k2, id) < tie(e.p, e.type, e.k1, e.k2, e.id);\n\t}\n};\n\nint p[N];\nint find(int x) {\n\tif(p[x] == x) return x;\n\treturn p[x] = find(p[x]);\n}\n\nint main() {\n\tios :: sync_with_stdio(false);\n\tint w, h, n; cin >> w >> h >> n;\n\tfor(int i = 1; i <= n; i ++)\n\t\tcin >> x1[i] >> y1[i] >> x2[i] >> y2[i];\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = 0; y1[n] = 0; x2[n] = 0; y2[n] = h;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = w; y2[n] = 0;\n\tn ++; x1[n] = w; y1[n] = h; x2[n] = 0; y2[n] = h;\n\t{\n\t\tmap <int, int> mp;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tmp[x1[i]] = 0; mp[y1[i]] = 0;\n\t\t\tmp[x2[i]] = 0; mp[y2[i]] = 0;\n\t\t}\n\t\tint cnt = 0;\n\t\tfor(auto &p : mp)\n\t\t\tp.second = ++ cnt;\n\t\tfor(int i = 1; i <= n; i ++) {\n\t\t\tx1[i] = mp[x1[i]]; y1[i] = mp[y1[i]];\n\t\t\tx2[i] = mp[x2[i]]; y2[i] = mp[y2[i]];\n\t\t}\n\t}\n\tvector <event> eves; int cnt = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(x1[i] == x2[i]) {\n\t\t\tif(y1[i] > y2[i]) swap(y1[i], y2[i]);\n\t\t\teves.pb({y1[i], 0, x1[i], 1, ++ cnt});\n\t\t\teves.pb({y2[i] + 1, 0, x1[i], -1, cnt});\n\t\t} else {\n\t\t\tif(x1[i] > x2[i]) swap(x1[i], x2[i]);\n\t\t\teves.pb({y1[i], 1, x1[i], x2[i], 0});\n\t\t}\n\tiota(p, p + cnt + 1, 0);\n\tsort(eves.begin(), eves.end());\n\n\tset <pii> sts, stp;\n\tfor(int i = 0; i < M; i ++)\n\t\tsts.insert({i, i});\n\tstp.insert({M, 0});\n\n\tll m = 0;\n\tbit.clear();\n\tfor(auto e : eves)\n\t\tif(e.type == 0) {\n\t\t\tbit.change(e.k1, e.k2);\n\n\t\t\tif(e.k2 == 1) {\n\t\t\t\tstp.insert({e.k1, e.id});\n\t\t\t\tpii p = *sts.lower_bound({e.k1, 0}); sts.erase(p);\n\t\t\t\tif(p.fi != e.k1) sts.insert({p.fi, e.k1 - 1});\n\t\t\t\tsts.insert({e.k1, e.k1});\n\t\t\t\tif(p.se != e.k1) sts.insert({e.k1 + 1, p.se});\n\t\t\t} else {\n\t\t\t\tstp.erase({e.k1, e.id});\n\t\t\t}\n\t\t} else {\n\t\t\tm += bit.query(e.k2);\n\t\t\tm -= bit.query(e.k1 - 1);\n\n\t\t\tauto it = stp.lower_bound({e.k1, 0});\n\t\t\tif(it -> first > e.k2) continue;\n\t\t\tint x = it -> second;\n\n\t\t\tit = sts.lower_bound({e.k1, 0});\n\t\t\tif(e.k1 != it -> fi) it --;\n\t\t\tint l = it -> first, r = it -> second;\n\t\t\twhile(1) {\n\t\t\t\tauto is = stp.lower_bound({it -> first, 0});\n\t\t\t\tif(is -> first <= it -> second) {\n\t\t\t\t\tint y = is -> second;\n\t\t\t\t\tint a = find(x), b = find(y);\n\t\t\t\t\tif(a != b) p[b] = a;\n\t\t\t\t}\n\n\t\t\t\tis = it ++;\n\t\t\t\tr = it -> second;\n\t\t\t\tif(is -> second >= e.k2) { sts.erase(is); break; }\n\t\t\t\tsts.erase(is);\n\t\t\t}\n\t\t\tsts.insert({l, r});\n\t\t}\n\tint ans = m - n;\n\tfor(int i = 1; i <= cnt; i ++)\n\t\tif(find(i) == i) ans ++;\n\tcout << ans << '\\n';\n}", "accuracy": 0.02702702702702703, "time_ms": 80, "memory_kb": 23492, "score_of_the_acc": -0.0732, "final_rank": 20 } ]
aoj_0610_cpp
気象予報士 (Weather Forecaster) 問題 JOI 市は南北方向に H キロメートル,東西方向に W キロメートルの長方形の形をしており,H × W 個の 1 キロメートル四方の小区画に区切られている.北から i 番目,西から j 番目の小区画を (i, j) と表す. 各小区画は上空に雲があるか雲がないかのどちらかである.すべての雲は,1 分経つごとに 1 キロメートル東に移動する.今日は実に天気が良いため,JOI 市の外から JOI 市内に雲が移動してくることはない. 今,各小区画の上空に雲があるかないかがわかっている.気象予報士であるあなたは,各小区画について,今から何分後に初めてその小区画の上空に雲が来るかを予測することになった. 各小区画について,今から何分後に初めてその小区画の上空に雲が来るか求めよ. 入力 入力は 1 + H 行からなる. 1 行目には,整数 H, W (1 ≤ H ≤ 100, 1 ≤ W ≤ 100) が空白を区切りとして書かれている.これは,JOI 市が H × W 個の 1 キロメートル四方の小区画に区切られていることを表す. 続く H 行のうちの i 行目 (1 ≤ i ≤ H) には W 文字からなる文字列が書かれている.W 文字のうちの j 文字目 (1 ≤ j ≤ W) は,小区画 (i, j) の上空に,今,雲があるかどうかを表す.雲がある場合は文字 'c' (英小文字) が,雲がない場合は文字 '.' (ピリオド) が書かれている. 出力 出力は H 行からなり,それぞれの行は空白を区切りとした W 個の整数からなる.出力の i 行目の j 番目の整数 (1 ≤ i ≤ H, 1 ≤ j ≤ W) は,今から何分後に初めて小区画 (i, j) の上空に雲が来るかを表さなければならない.ただし,今すでに小区画 (i, j) の上空に雲がある場合は 0 を,何分経っても小区画 (i, j) の上空に雲が来ない場合は -1 を出力せよ. 出力の各行の行頭と行末には余計な空白を入れないこと. 入出力例 入力例 1 3 4 c..c ..c. .... 出力例 1 0 1 2 0 -1 -1 0 1 -1 -1 -1 -1 入力例 2 6 8 .c...... ........ .ccc..c. ....c... ..c.cc.. ....c... 出力例 2 -1 0 1 2 3 4 5 6 -1 -1 -1 -1 -1 -1 -1 -1 -1 0 0 0 1 2 0 1 -1 -1 -1 -1 0 1 2 3 -1 -1 0 1 0 0 1 2 -1 -1 -1 -1 0 1 2 3 入出力例 1 では,JOI 市は 3 × 4 個の小区画に区切られている.今の JOI 市の雲の状況は以下の通りである.図の上が北を表す. この後,1 分ごとに雲は以下のように移動する. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0610_4404427", "code_snippet": "#include<bits/stdc++.h>\n#define enld '\\n'\n#define rep(i,n) for(int i=0; i<(n); i++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC optimize(\"Ofast\")\nconstexpr ll INF = 1e18;\nconstexpr int inf = 1e9;\nconstexpr ll mod = 1000000007;\nconstexpr ll mod2 = 998244353;\nconst double PI = 3.1415926535897932384626433832795028841971;\nconst int dx[6] = {1, 0, -1, 0,1,1};\nconst int dy[6] = {0, 1, 0, -1,1,-1};\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n// ---------------------------------------------------------------------------\n\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int H,W;\n cin >> H >> W;\n vector<string> G(H);\n for(int i=0; i<H; i++){\n cin >> G[i];\n }\n vector<vector<int>> suzu(H, vector<int> (W,-1));\n for(int k=0; k<100; k++){\n for(int i=0; i<H; i++){\n for(int j=W-1; j>=0; j--){\n if(G[i][j] == 'c' and suzu[i][j] == -1){\n suzu[i][j] = k;\n }\n if(j > 0){\n G[i][j] = G[i][j-1];\n }\n }\n }\n }\n for(int i=0; i<H; i++){\n for(int j=0; j<W; j++){\n cout << suzu[i][j] << (j!=W-1 ? \" \" : \"\\n\");\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3284, "score_of_the_acc": -1, "final_rank": 4 }, { "submission_id": "aoj_0610_2837496", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int x,y;\n cin>>x>>y;\n for(int i=0;i<x;i++){\n int cou=-1;\n for(int j=0;j<y;j++){\n char x;\n cin>>x;\n if(x=='c'){\n\tcou=0;\n }\n else if(cou>=0) cou++;\n if(j!=0) cout<<\" \";\n cout<<cou;\n }\n cout<<endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3108, "score_of_the_acc": -0.2143, "final_rank": 3 }, { "submission_id": "aoj_0610_2639721", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n \nint main(){\n \n int h, w;\n\n cin>>h>>w;\n\n for(int i=0;i<h;i++){\n int cnt;\n bool f=false;\n for(int j=0;j<w;j++){\n char c;\n cin>>c;\n if(c=='c'){\n\tf=true;\n\tcnt=0;\n }\n cout<<(j?\" \":\"\");\n if(f) cout<<cnt++;\n else cout<<-1;\n }\n cout<<endl;\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3092, "score_of_the_acc": -0.1429, "final_rank": 2 }, { "submission_id": "aoj_0610_2329281", "code_snippet": "#include <iostream>\nusing namespace std;\n\nint main(){\n\tint h, w, a[100][100];\n\tchar in;\n\tcin >> h >> w;\n\tfor(int i = 0; i<h;i++){\n\t\tfor(int j = 0;j<w;j++){\n\t\t\tcin >> in;\n\t\t\tif(in == 'c') a[i][j] == 0;\n\t\t\telse if(j == 0) a[i][0] = -1;\n\t\t\telse if(a[i][j-1] == -1) a[i][j] = -1;\n\t\t\telse a[i][j] = a[i][j-1] + 1;\n\t\t\tif(j == 0) cout << a[i][j];\n\t\t\telse cout << ' ' << a[i][j];\n\t\t}\n\t\tcout << endl;\n\t}\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 10, "memory_kb": 3088, "score_of_the_acc": -0.125, "final_rank": 5 }, { "submission_id": "aoj_0610_2152843", "code_snippet": "#include <iostream>\nusing namespace std;\n\n#define loop(i,n) for(int i=1;i<=n;i++)\nint res[102];\n\nint main(){\n int h,w;\n char p;\n cin>>h>>w;\n loop(i,h){\n res[0]=-1;\n loop(j,w){\n cin>>p;\n if(p=='c')res[j]=0;\n else if(res[j-1]==-1) res[j]=-1;\n else res[j]=res[j-1]+1;\n cout<<res[j];\n if(j!=w)cout<<\" \";\n else cout<<endl;\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3060, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0606_cpp
JOIOI の塔(Tower of JOIOI) JOIOI の塔とは,1 人で遊ぶ円盤を使ったゲームである. このゲームは, J , O , I のいずれかの文字が書かれたいくつかの円盤を用いて行う.円盤は直径が互いに異なり,ゲーム開始時にはこれらの円盤は直径の大きいものから順に下から上に向かって積まれている.あなたは,これらの円盤を用いて,出来るだけ多くのミニ JOIOI の塔を作りたい.ミニ JOIOI の塔とは 3 枚の円盤からなり,円盤の直径が小さいものから順に読んで JOI もしくは IOI と読めるものである.ただし,同じ円盤を2 度以上使うことはできない. 図: JOIOII からはミニ JOIOI の塔が 2 つ作れる 課題 用意された円盤に書かれた文字がそれぞれ円盤の直径が小さいものから順に長さ N の文字列 S として与えられる.これらの円盤を使って作ることのできるミニ JOIOI の塔の個数の最大値を求めるプログラムを作成せよ. 制限 1 ≤ N ≤ 1 000 000      文字列 S の長さ 入力 標準入力から以下のデータを読み込め. 1 行目には整数 N が書かれている. N は文字列 S の長さを表す. 2 行目には文字列 S が書かれている. 出力 標準出力に,作ることのできるミニ JOIOI の塔の数の最大値を表す整数を 1 行で出力せよ. 入出力例 入力例 1 6 JOIIOI 出力例 1 2 JOIIOI は JOI および IOI をそれぞれ 1 つずつ部分列として含んでおり,作ることのできるミニ JOIOI の塔は 2 つである. 入力例 2 5 JOIOI 出力例 2 1 部分列として JOI および IOI を含んでいるが,文字を 2 度以上使うことはできないため同時に取り出すことはできない. 入力例 3 6 JOIOII 出力例 3 2 この入出力例は問題文中の例に対応している. 入力例 4 15 JJOIIOOJOJIOIIO 出力例 4 4 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0606_10946347", "code_snippet": "#include<iostream>\n#include<string>\n#include<vector>\n#include<queue>\n#include<algorithm>\nusing namespace std;\nbool used[1234567]; int n; string T;\nint rec(string S, int R) {\n\tfor (int i = 0; i < n; i++)used[i] = false;\n\tvector<pair<int, int>>vec; queue<int>Q; int cnt = 0;\n\tfor (int i = S.size(); i >= 0; i--) {\n\t\tif (S[i] == 'I') { Q.push(i); }\n\t\tif (S[i] == 'O' && !Q.empty()) { int G = Q.front(); Q.pop(); vec.push_back(make_pair(i, G)); used[i] = true; used[G] = true; cnt++; }\n\t\tif (cnt == R)break;\n\t}\n\tsort(vec.begin(), vec.end()); int Y = 0;\n\tfor (int i = 0; i < vec.size(); i++) {\n\t\twhile (Y != n && (used[Y] == true || S[Y] == 'O')) { Y++; }\n\t\tif (Y >= vec[i].first)return i; used[Y] = true;\n\t}\n\treturn cnt;\n}\nint main() {\n\tcin >> n >> T; int maxn = 0; int bef = -1;\n\tint L = 0, R = T.size(), M;\n\twhile (true) {\n\t\tM = (L + R) / 2;\n\t\tint res1 = rec(T, M);\n\t\tint res2 = rec(T, M + 1);\n\t\tif (res1 == M && res2 < M + 1)break;\n\t\tif (res1 < M)R = M;\n\t\tif (res2 == M + 1)L = M;\n\t}\n\tcout << M << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 14432, "score_of_the_acc": -1.8831, "final_rank": 20 }, { "submission_id": "aoj_0606_10454199", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nint n, JOI = 0, IOI = 0, OI = 0, I = 0, C = 0;\nstring k;\nint main() {\n\tcin >> n >> k;\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tif (k[i] == 'I') {\n\t\t\tif (OI) {\n\t\t\t\tIOI++;\n\t\t\t\tOI--;\n\t\t\t}\n\t\t\telse if (C) {\n\t\t\t\tIOI++;\n\t\t\t\tC--;\n\t\t\t}\n\t\t\telse I++;\n\t\t}\n\t\tif (k[i] == 'O') {\n\t\t\tif (I) {\n\t\t\t\tOI++;\n\t\t\t\tI--;\n\t\t\t}\n\t\t\telse if (IOI) {\n\t\t\t\tIOI--;\n\t\t\t\tC+=2;\n\t\t\t}\n\t\t}\n\t\tif (k[i] == 'J') {\n\t\t\tif (OI) {\n\t\t\t\tJOI++;\n\t\t\t\tOI--;\n\t\t\t}\n\t\t\telse if (C) {\n\t\t\t\tJOI++;\n\t\t\t\tC--;\n\t\t\t}\n\t\t\telse if (IOI) {\n\t\t\t\tI++;\n\t\t\t\tIOI--;\n\t\t\t\tJOI++;\n\t\t\t}\n\t\t}\n\t}\n\tcout << JOI + IOI + C / 2 << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5152, "score_of_the_acc": -0.1378, "final_rank": 2 }, { "submission_id": "aoj_0606_9488118", "code_snippet": "#include <cstdio>\n#include <algorithm>\n\n#define rep(i, n) for(int i = 0; i < (n); ++i)\n\nusing namespace std;\n\nint n;\nchar s[1000001];\n\n// 関数judgeは、長さkの特定の部分列が存在するかどうかを判定します\nbool judge(int k) {\n int a = 0, b = 0, c = 0;\n int p = k;\n // 文字列の後ろから前に向かって走査\n for(int i = n - 1; i >= 0; --i) {\n if(s[i] == 'J' && b > 0) {\n // 'J'が見つかり、'O'のペアが存在する場合\n --b;\n ++a;\n }\n if(s[i] == 'O' && c > 0) {\n // 'O'が見つかり、'I'のペアが存在する場合\n --c;\n ++b;\n }\n if(s[i] == 'I') {\n if(p > 0) {\n // 'I'が見つかり、'I'を処理する枠がある場合\n ++c;\n --p;\n }\n else if(b > 0) {\n // 'I'が見つかり、'O'のペアが存在する場合\n --b;\n ++a;\n }\n }\n }\n // 'J'のペアの数がkと等しいかを返す\n return a == k;\n}\n\nint main() {\n // 入力の読み込み\n scanf(\"%d%s\", &n, s);\n int l = 0, r = n;\n // 二分探索で条件を満たす最大のkを探す\n while(r - l > 1) {\n int m = (l + r) / 2;\n if(judge(m)) {\n l = m;\n } else {\n r = m;\n }\n }\n // 結果の出力\n printf(\"%d\\n\", l);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 3952, "score_of_the_acc": -0.1936, "final_rank": 3 }, { "submission_id": "aoj_0606_8291077", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint N;\nstring S;\nbool used[1000009];\n\nbool check(int target) {\n\tfor (int i = 0; i < N; i++) used[i] = false;\n\tint dep = 0, cnt = 0; vector<int> L1, L2;\n\tfor (int i = N - 1; i >= 0; i--) {\n\t\tif (S[i] == 'I' && cnt < target) { dep += 1; cnt += 1; used[i] = true; }\n\t\tif (S[i] == 'O' && dep > 0) { dep -= 1; L1.push_back(i); used[i] = true; }\n\t}\n\tif (L1.size() < target) return false;\n\treverse(L1.begin(), L1.end());\n\tfor (int i = 0; i < N; i++) {\n\t\tif (used[i] == false && S[i] != 'O') L2.push_back(i);\n\t}\n\tif (L2.size() < target) return false;\n\tfor (int i = 0; i < L1.size(); i++) {\n\t\tif (L1[i] < L2[i]) return false;\n\t}\n\treturn true;\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> S;\n\n\t// Step 2. Binary Search\n\tint cl = 0, cr = N, cm, maxn = 0;\n\tfor (int i = 0; i < 30; i++) {\n\t\tcm = (cl + cr) / 2;\n\t\tbool ret = check(cm);\n\t\tif (ret == true) { cl = cm; maxn = max(maxn, cm); }\n\t\telse { cr = cm; }\n\t}\n\t\n\t// Step 3. Output\n\tcout << maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 11228, "score_of_the_acc": -1.3214, "final_rank": 18 }, { "submission_id": "aoj_0606_6157948", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n,m,i,j,k,t,t1,u,v,a,b;\nint ci,cj,cio,cjo,cioi,cjoi,cjoio,cioio;\nchar c;\nint main() {\n cin>>n;\n for (i=0;i<n;i++) {\n cin>>c;\n if (c=='J') {\n cj++;\n }\n if (c=='O') {\n if (cj) {\n cj--;\n cjo++;\n }\n else if (ci) {\n ci--;\n cio++;\n }\n else if (cjoi) {\n cjoi--;\n cjoio++;\n }\n else if (cioi) {\n cioi--;\n cioio++;\n }\n }\n if (c=='I') {\n if (cjo) {\n cjo--;\n cjoi++;\n }\n else if (cio) {\n cio--;\n cioi++;\n }\n else if (cjoio) {\n cjoio--;\n cjo++;\n cioi++;\n }\n else if (cioio) {\n \tcioio--;\n cioi++;\n cio++;\n }\n else ci++;\n }\n // cout<<ci<<' '<<cj<<' '<<cio<<' '<<cjo<<' '<<cioi<<' '<<cjoi<<' '<<cjoio<<endl;\n }\n cout<<cjoi+cioi+cjoio+cioio<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3436, "score_of_the_acc": -0.0435, "final_rank": 1 }, { "submission_id": "aoj_0606_4822018", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N; string S;\n\tcin >> N >> S;\n\tvector<int> I(N + 1), OI(N + 1), JOI(N + 1);\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tif (S[i] == 'I') {\n\t\t\tI[i] = I[i + 1] + 1;\n\t\t\tOI[i] = OI[i + 1];\n\t\t\tJOI[i] = JOI[i + 1];\n\t\t}\n\t\telse if (S[i] == 'O') {\n\t\t\tI[i] = I[i + 1] - (I[i + 1] != 0 ? 1 : 0);\n\t\t\tOI[i] = OI[i + 1] + (I[i + 1] != 0 ? 1 : 0);\n\t\t\tJOI[i] = JOI[i + 1];\n\t\t}\n\t\telse {\n\t\t\tI[i] = I[i + 1];\n\t\t\tOI[i] = OI[i + 1] - (OI[i + 1] != 0 ? 1 : 0);\n\t\t\tJOI[i] = JOI[i + 1] + (OI[i + 1] != 0 ? 1 : 0);\n\t\t}\n\t}\n\tint J = 0, JO = 0, ans = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tint J_OI = min(J, OI[i]);\n\t\tint JO_I = min(JO, I[i]);\n\t\tint NJOI = J_OI + JO_I + JOI[i] + min(JO - JO_I, OI[i] - J_OI);\n\t\tans = max(ans, NJOI);\n\t\tif (S[i] == 'J' || S[i] == 'I') {\n\t\t\t++J;\n\t\t}\n\t\telse if (J != 0) {\n\t\t\t--J; ++JO;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15844, "score_of_the_acc": -0.9965, "final_rank": 15 }, { "submission_id": "aoj_0606_4787416", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename Iter, typename T> int gt(Iter L, Iter R, T v) { return upper_bound(L, R, v) - L; }\ntemplate <typename Iter, typename T> int ge(Iter L, Iter R, T v) { return lower_bound(L, R, v) - L; }\ntemplate <typename Iter, typename T> int lt(Iter L, Iter R, T v) { return lower_bound(L, R, v) - L - 1; }\ntemplate <typename Iter, typename T> int le(Iter L, Iter R, T v) { return upper_bound(L, R, v) - L - 1; }\ntemplate <typename Bst, typename T> typename Bst::const_iterator gt(const Bst& bst, T v) { return bst.upper_bound(v); }\ntemplate <typename Bst, typename T> typename Bst::const_iterator ge(const Bst& bst, T v) { return bst.lower_bound(v); }\ntemplate <typename Bst, typename T> typename Bst::const_iterator lt(const Bst& bst, T v) { return bst.lower_bound(v) == bst.begin() ? bst.end() : --bst.lower_bound(v); }\ntemplate <typename Bst, typename T> typename Bst::const_iterator le(const Bst& bst, T v) { return bst.upper_bound(v) == bst.begin() ? bst.end() : --bst.upper_bound(v); }\ntemplate <typename T, typename Can> T bsearch(T L, T R, const Can& can, bool left_feasible = true) {\n static_assert(is_convertible<decltype(can), function<bool(T)>>::value, \"can must be bool(T)\");\n T& feasible = left_feasible ? L : R;\n T& infeasible = left_feasible ? R : L;\n while(R - L > 1) {\n T M = L + (R - L) / 2;\n (can(M) ? feasible : infeasible) = M;\n }\n return feasible;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n; string s;\n cin >> n >> s;\n cout << bsearch<int>(0, count(s.begin(), s.end(), 'I') + 1, [&](int k) {\n deque<int> J, Ihead, O, Itail;\n vector<int> head(n, -1), tail(n, -1);\n for(int i = n - 1; i >= 0; i--) {\n if(s[i] == 'J') {\n J.push_front(i);\n } else if(s[i] == 'O') {\n O.push_front(i);\n } else {\n (Itail.size() == k ? Ihead : Itail).push_front(i);\n }\n }\n for(auto o = O.rbegin(); o != O.rend(); o++) {\n if(not Itail.empty() and Itail.back() > *o) {\n tail[*o] = Itail.back();\n Itail.pop_back();\n }\n }\n for(int o : O) {\n if(tail[o] >= 0) {\n int i = Ihead.empty() ? n : Ihead.front(), j = J.empty() ? n : J.front();\n if(min(i, j) < o) {\n head[o] = min(i, j);\n (i < j ? Ihead : J).pop_front();\n }\n }\n }\n int cur = 0;\n for(int i = 0; i < n; i++) {\n cur += head[i] >= 0 and tail[i] >= 0;\n }\n return cur >= k;\n }) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 15888, "score_of_the_acc": -1.587, "final_rank": 19 }, { "submission_id": "aoj_0606_4315447", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n;\nstring s;\n\n// 右端からx個の'I'を終端と決め打ったときにx個構成できるか\nbool f(int x){\n int icnt=0, ocnt=0, y=0, r=x;\n for(int i=n-1;i>=0;i--){\n if(s[i]=='J'){\n if(ocnt>0){\n y++;\n ocnt--;\n }\n }\n if(s[i]=='O'){\n if(icnt>0){\n ocnt++;\n icnt--;\n }\n }\n if(s[i]=='I'){\n if(r>0){\n icnt++;\n r--;\n }else if(ocnt>0){\n y++;\n ocnt--;\n }\n }\n }\n return y==x;\n}\n\nint solve(){\n cin >> n >> s;\n int ok = 0, ng = n/3+1;\n while(abs(ok-ng)>1){\n int mid = (ok+ng)/2;\n if(f(mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n cout << ok << endl;\n return 0;\n}\n\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3968, "score_of_the_acc": -0.2601, "final_rank": 6 }, { "submission_id": "aoj_0606_4314010", "code_snippet": "#include<algorithm>\n#include<bitset>\n#include<cassert>\n#include<cfloat>\n#include<climits>\n#include<cmath>\n#include<deque>\n#include<functional>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<queue>\n#include<set>\n#include<stack>\n#include<string>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = (int)(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = (int)(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = (int)(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = (int)(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = (int)(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define REVERSE(x) reverse((x).begin(), (x).end())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << '\\n'\n\nconstexpr int IINF = (1 << 30) - 1;\nconstexpr long long LLINF = 1LL << 61;\nconstexpr double EPS = 1e-10;\n\nconstexpr int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconstexpr int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\ntemplate<typename T>\nT meguru_search(T ok, T ng, function<bool(T)> check){\n while(max(ok, ng) - min(ok, ng) > T(1)){\n T mid = (ok + ng) / T(2);\n if(check(mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n return ok;\n}\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nbool chmin(T& a, T b){\n if(b < a){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n\n int n;\n cin >> n;\n\n string s;\n cin >> s;\n\n auto check = [&](int mid){\n vector<int> ipos;\n vector<bool> used(n, false);\n rrep(i, n){\n if((int)ipos.size() >= mid){\n break;\n }\n if(s[i] == 'I'){\n ipos.emplace_back(i);\n used[i] = true;\n }\n }\n\n if((int)ipos.size() < mid){\n return false;\n }\n\n vector<int> opos;\n rrep(i, n){\n if((int)opos.size() >= mid){\n break;\n }\n if(s[i] == 'O' && i < ipos[opos.size()]){\n opos.emplace_back(i);\n }\n }\n\n if((int)opos.size() < mid){\n return false;\n }\n\n int cnt = 0;\n rrep(i, n){\n if(cnt >= mid){\n return true;\n }\n if(used[i] || s[i] == 'O'){\n continue;\n }\n if(i < opos[cnt]){\n ++cnt;\n }\n }\n\n return cnt >= mid;\n };\n\n int ans = meguru_search<int>(0, n, check);\n cout << ans << endl;\n\n cout << flush;\n\n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 9016, "score_of_the_acc": -1.0133, "final_rank": 16 }, { "submission_id": "aoj_0606_4150242", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint N;\nstring S;\nbool used[1000005];\n\nbool check(int x){\n memset(used,0,N);\n int idx = N-1;\n vector<int> lis;\n for (int i = 0;i < x;i++){\n while(S[idx] != 'I'){\n //cout << S[idx] << endl;\n idx--;\n if(idx < 0) return false;\n }\n used[idx] = true;\n lis.push_back(idx);\n idx--;\n }\n vector<int> lis2;\n idx = N-1;\n for (int i = 0;i < x;i++){\n while(!(idx < lis[i] && S[idx] == 'O') ){\n idx--;\n if(idx < 0) return false;\n }\n used[idx] = true;\n lis2.push_back(idx);\n idx--;\n }\n idx = N-1;\n for (int i = 0;i < x;i++){\n while(!(idx < lis2[i] && (S[idx] == 'I' || S[idx] == 'J') && used[idx] == false) ){\n idx--;\n if(idx < 0) return false;\n }\n used[idx] = true;\n idx--;\n }\n return true;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> N >> S;\n\n int high = N, low = 0;\n while(high-low != 1){\n int mid = (high+low)/2;\n if(check(mid)) low = mid;\n else high = mid;\n }\n\n cout << low << endl;\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 10016, "score_of_the_acc": -0.985, "final_rank": 14 }, { "submission_id": "aoj_0606_4017584", "code_snippet": "#include<iostream>\n#include<cstdio>\nusing namespace std;\n\nint main()\n{\n int n;\n char s[1000010];\n \n cin >> n;\n scanf(\"%s\",s);\n \n int l,r,mid,jj,oo,ii,isum;\n l = 0;\n r = n-1;\n while(l < r){\n jj = 0;\n oo = 0;\n ii = 0;\n isum = 0;\n mid = (l+r+1)/2;\n for(int i=n-1;i>=0;i--){\n if(s[i] == 'I' && isum < mid){\n ii++;\n isum++;\n }\n else if(ii > 0 && s[i] == 'O'){\n oo++;\n ii--;\n }\n else if(oo > 0 && s[i] != 'O'){\n jj++;\n oo--;\n }\n }\n \n if(jj >= mid) l = mid;\n else r = mid-1;\n \n }\n \n cout << l << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4200, "score_of_the_acc": -0.2353, "final_rank": 5 }, { "submission_id": "aoj_0606_3821941", "code_snippet": "#include<iostream>\n#include<vector>\n#include<string>\nusing namespace std;\n\nbool C(int N, string S, int k){\n\tint cnt = 0, cnt2 = 0, cnt3 = 0;\n\tfor(int i = N - 1; i >= 0; i--){\n\t\tif(S[i] == 'I' && cnt < k) cnt++;\n\t\telse if(S[i] == 'O' && cnt2 < cnt) cnt2++;\n\t\telse if((S[i] == 'J' || S[i] == 'I') && cnt3 < cnt2) cnt3++;\n\t}\n\tif(cnt3 == k) return true;\n\treturn false;\n}\n\nint main(){\n\tint N;\n\tcin >> N;\n\tstring S;\n\tcin >> S;\n\tint lb = 0, ub = N / 3 + 1;\n\twhile(ub - lb > 1){\n\t\tint mid = lb + (ub - lb) / 2;\n\t\tif(C(N, S, mid)) lb = mid;\n\t\telse ub = mid;\n\t}\n\tcout << lb << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 4988, "score_of_the_acc": -0.3638, "final_rank": 11 }, { "submission_id": "aoj_0606_3806843", "code_snippet": "#include <bits/stdc++.h>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define RFOR(i,a) for(int i=(a); i >= 0; --i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define BIT_ON(bit, i) (((bit >> i) & 1) > 0)\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\ntemplate<class T> inline void print(T x) { std::cout << x << std::endl; }\ntemplate<class T> inline void print_vec(const std::vector<T> &v) { for (int i = 0; i < v.size(); ++i) { if (i != 0) {std::cout << \" \";} std::cout << v[i];} std::cout << \"\\n\"; }\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 60u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\n// x個つくれる\nbool ok(const long long x, string &s) {\n int num = x;\n\n int ans = 0;\n int num_i = 0, num_oi = 0;\n for (int i = s.size() - 1; i >= 0; --i) {\n if (s[i] == 'J') {\n if (num_oi > 0) {\n num_oi--;\n ans++;\n }\n }\n else if (s[i] == 'O') {\n if (num_i > 0) {\n num_i--;\n num_oi++;\n }\n }\n else if (s[i] == 'I') {\n num_i++;\n num--;\n if (num < 0 and num_oi > 0) {\n num_i--;\n num_oi--;\n ans++;\n }\n }\n }\n\n return ans >= x;\n}\n\n// 開区間(low, high)で条件を満たす一番右\n// なければlowを返す\nint binary_search_right(long long low, long long high, string &s) {\n // (low, high)\n while (high - low > 1) {\n long long middle = (low + high) / 2;\n if (ok(middle, s)) {\n low = middle;\n }\n else {\n high = middle;\n }\n }\n\n return low;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n LL N;\n cin >> N;\n string S;\n cin >> S;\n\n print(binary_search_right(-1, S.size(), S));\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4644, "score_of_the_acc": -0.2709, "final_rank": 8 }, { "submission_id": "aoj_0606_3077058", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\nstring s;int n;\nbool F(int x){\n int a=0,b=0;\n lol(i,n){\n\tif(s[i]=='I'&&x)x--,a++;\n\telse if(s[i]=='O'&&a)a--,b++;\n\telse if(s[i]!='O')b=max(0,b-1);\n }\n return (x+a+b==0);\n}\nint main(){\n cin>>n>>s;\n reverse(s.begin(),s.end());\n int l=0,r=n,m;\n while(l<r-1){\n\tm=(l+r)/2;\n\tif(F(m))l=m;\n\telse r=m;\n }\n cout<<l<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3996, "score_of_the_acc": -0.2624, "final_rank": 7 }, { "submission_id": "aoj_0606_2712391", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\nint N,length;\nchar buf[1000001];\nbool used[1000001];\n\n\nbool can_make(int tower_num){\n\n\tint tail_I_num = 0,mid_O_num = 0;\n\tfor(int i = 0; i < length; i++)used[i] = false;\n\n\tfor(int i = length-1; (i >= 0) && (tail_I_num < tower_num || mid_O_num < tower_num); i--){\n\t\tif(buf[i] == 'I'){\n\t\t\tif(tail_I_num < tower_num){\n\t\t\t\ttail_I_num++;\n\t\t\t\tused[i] = true;\n\t\t\t}\n\t\t}else if(buf[i] == 'O'){\n\t\t\tif(mid_O_num < tower_num && mid_O_num < tail_I_num){\n\t\t\t\tmid_O_num++;\n\t\t\t\tused[i] = true;\n\t\t\t}\n\t\t}\n\t}\n\n\tif(tail_I_num < tower_num || mid_O_num < tower_num)return false;\n\n\tint count = 0;\n\tmid_O_num = 0;\n\n\tfor(int i = length-1; i >= 0 && count < tower_num; i--){\n\t\tif(buf[i] == 'I' || buf[i] == 'J'){\n\t\t\tif(used[i] == false && mid_O_num > 0){\n\t\t\t\tcount++;\n\t\t\t\tmid_O_num--;\n\t\t\t}\n\t\t}else{ //buf[i] == 'O'\n\t\t\tif(used[i]){\n\t\t\t\tmid_O_num++;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn count == tower_num;\n}\n\n\nint main(){\n\n\tscanf(\"%d\",&N);\n\tscanf(\"%s\",buf);\n\n\tfor(length = 0; buf[length] != '\\0'; length++);\n\n\tint ans = 0;\n\tint left = 0, right = N,m = (left+right)/2;\n\n\twhile(left <= right){\n\n\t\tif(can_make(m)){\n\t\t\tans = m;\n\t\t\tleft = m+1;\n\t\t}else{\n\t\t\tright = m-1;\n\t\t}\n\t\tm = (left+right)/2;\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 5160, "score_of_the_acc": -0.508, "final_rank": 12 }, { "submission_id": "aoj_0606_2543900", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <cmath>\n#include <iomanip>\n#include <cassert>\n#include <bitset>\nusing namespace std;\n\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i=0; i<(n); i++)\n#define all(c) (c).begin(), (c).end()\n#define uniq(c) c.erase(unique(all(c)), (c).end())\n#define _1 first\n#define _2 second\n#define pb push_back\n#define INF 1145141919\n#define MOD 1000000007\n\nint N;\nchar S[1000001];\n\nbool f(int X) {\n int rem = X;\n int s_i = 0, s_io = 0, s_ioi = 0;\n rep(i, N) {\n if (S[i] == 'I') {\n if (rem > 0) {\n rem--;\n s_i++;\n }\n else {\n if (s_io > 0) s_ioi++, s_io--;\n }\n }\n else if (S[i] == 'O') {\n if (s_i > 0) s_io++, s_i--;\n }\n else {\n // J\n if (s_io > 0) s_ioi++, s_io--;\n }\n }\n return s_ioi >= X;\n}\n\nsigned main() {\n ios::sync_with_stdio(false); cin.tie(0);\n cin >> N;\n cin >> S;\n reverse(S, S+N);\n int lo = 0, hi = N;\n while (hi - lo > 1) {\n int mid = (lo + hi) / 2;\n if (f(mid)) lo = mid;\n else hi = mid;\n }\n cout << lo << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4108, "score_of_the_acc": -0.2279, "final_rank": 4 }, { "submission_id": "aoj_0606_2492817", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define mp make_pair\n#define pb push_back\n#define x first\n#define y second\n#define pii pair<int, int>\n#define p3i pair<pii, int>\n#define pll pair<ll, ll>\n#define p3l pair<pll, ll>\n#define lseg L, (L+R)/2, N*2+1\n#define rseg (L+R)/2+1, R, N*2+2\n#define ub upper_bound\n#define lb lower_bound\n#define pq priority_queue\n#define MN 1000000007\n#define fox(k, x) for (int k=0; k<x; ++k)\n#define fox1(k, x) for (int k=1; k<=x; ++k)\n#define foxr(k, x) for (int k=x-1; k>=0; --k)\n#define fox1r(k, x) for (int k=x; k>0; --k)\n#define ms multiset\n#define flood(x) memset(x, 0x3f3f3f3f, sizeof x)\n#define drain(x) memset(x, 0, sizeof x)\n\nint lo, mid, hi, n, cnt[3];\nstring s;\nbool check(int L){\n drain(cnt);\n fox(l, n){\n if (s[l]=='J') cnt[0]++;\n if (s[l]=='O' && cnt[0]>0){cnt[1]++; cnt[0]--;}\n if (s[l]=='I'){\n if (L>0){cnt[0]++; L--;}\n else if (cnt[1]){cnt[1]--; cnt[2]++;}\n else return 0;\n }\n }\n return 1;\n}\nint main(){\n cin >> n >> s;\n hi=n;\n while(lo<hi){\n mid=(lo+hi)/2;\n //cout << mid << endl;\n if (check(mid)) hi=mid;\n else lo=mid+1;\n }\n //cout << lo << endl;\n check(lo);\n cout << cnt[2] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3916, "score_of_the_acc": -0.2994, "final_rank": 10 }, { "submission_id": "aoj_0606_2404742", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define pb push_back\nconst int N = 1e6L + 11;\nchar s[N];\nbool vis[N];\n\nbool chk(int n, int m) {\n\tfill(vis, vis + n + 1, 0);\n\tvector <int> l, r;\n\tfor(int i = n; i >= 1; i --)\n\t\tif(s[i] == 'I' && r.size() < m) {\n\t\t\tr.pb(i);\n\t\t\tvis[i] = 1;\n\t\t}\n\treverse(r.begin(), r.end());\n\tfor(int i = 1; i <= n; i ++)\n\t\tif((s[i] == 'I' || s[i] == 'J') && !vis[i] && l.size() < m)\n\t\t\tl.pb(i);\n\n\tif(l.size() < m || r.size() < m) return 0;\n\tint p = 0;\n\tfor(int i = 1; i <= n; i ++)\n\t\tif(s[i] == 'O' && p < m && l[p] <= i && r[p] >= i)\n\t\t\tp ++;\n\treturn p == m;\n}\n\nint main() {\n\tint n; cin >> n;\n\tscanf(\"%s\", s + 1);\n\tint l = 0, r = n / 3 + 1;\n\twhile(l + 1 < r) {\n\t\tint m = (l + r) / 2;\n\t\tif(chk(n, m)) l = m;\n\t\telse r = m;\n\t}\n\tcout << l << '\\n';\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 9608, "score_of_the_acc": -1.0826, "final_rank": 17 }, { "submission_id": "aoj_0606_2366306", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n string S;\n cin >> N >> S;\n\n auto ok = [&](auto k) {\n auto l = 0, m = 0, r = 0;\n for(auto i = N - 1; 0 <= i; --i) {\n if(S[i] == 'J') if(l < m) ++l;\n if(S[i] == 'O') if(m < r) ++m;\n if(S[i] == 'I') {\n if(r < k) ++r;\n else if(l < m) ++l;\n }\n }\n return l == k;\n };\n\n auto l = 0, h = N;\n while(l + 1 < h) {\n auto m = (l + h) / 2;\n if(ok(m)) l = m;\n else h = m;\n }\n cout << l << endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 3880, "score_of_the_acc": -0.2965, "final_rank": 9 }, { "submission_id": "aoj_0606_2216685", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\nusing namespace std;\n\nint n, O[1000000], I[1000000], a, b;\nchar s[1000001];\nbool ok(int t) {\n\tif (a < t || b < t)return 0;\n\tint p = n;\n\trep(i, t) {\n\t\tp = min(p - 1, O[i] - 1);\n\t\twhile (0 <= p && (s[p] == 'O' || (s[p] == 'I'&&p >= I[t - 1])))p--;\n\t\tif (p < 0)return 0;\n\t}\n\treturn 1;\n}\nint main() {\n\tscanf(\"%d%s\", &n, s);\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tif (s[i] == 'I')I[a++] = i;\n\t\tif (s[i] == 'O'&&b < a)O[b++] = i;\n\t}\n\tint l = 0, r = n / 3;\n\twhile (l != r) {\n\t\tint t = (l + r) / 2;\n\t\tif (r - l == 1)t = r;\n\t\tif (ok(t))l = t;\n\t\telse r = t - 1;\n\t}\n\tprintf(\"%d\\n\", l);\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 7604, "score_of_the_acc": -0.5304, "final_rank": 13 } ]
aoj_0604_cpp
IOI 列車で行こう(Take the 'IOI' train) IOI 国ではこのたび新たに鉄道を敷設した.IOI 国の鉄道を走る列車はいくつかの車両が連結されたものであり,車両には I , O の 2 種類がある.車両はそれぞれ異なる種類の車両としか連結できない.また,列車に運転席を設ける関係上,列車の両端の車両は種類 I でなければならない.列車は車両の種類を表す文字を順につなげた文字列で表され,列車の長さはその文字列の長さであるとする.たとえば, IOIOI の順に車両を連結すると長さ 5 の列車を編成でき,また車両 I は単独で長さ 1 の列車である.車両を OIOI や IOOI といった順に並べても列車を編成することはできない. いくつかの車両が 2 つの車庫に格納されている.それぞれの車庫の中には車両が一列に並んでいる.列車を編成するときは車庫から車両を出してきて車庫前で連結していく.車庫から出せる車両は最も車庫の入り口に近い車両のみであるが,どちらの車庫から車両を出すかの順番については自由である. 列車を編成する前に,車両を好きなだけ車庫から出して別の待機用レールに移すことができる.一度待機用レールに移した車両は今後列車を編成するために使うことはできない.また,一度列車の編成を始めるとその編成が終わるまでの間は車両を車庫から待機用レールに移すことはできない. 列車を編成するとき,車庫内の全ての車両を使い切る必要はない.すなわち,列車の編成を終えた後,車庫内に使われなかった車両が残っていても構わない. IOI 国では鉄道に乗る人がとてもたくさんいると考えられているので,できるだけ長い列車を編成したい. 図: 列車を編成している途中であり,このとき車庫にある車両を待機用レールに移すことはできない.この図は入出力例1 に対応している. 課題 車庫に格納された車両の情報が与えられたとき,編成できる列車の長さの最大値を求めるプログラムを作成せよ.それぞれの車庫に格納された車両の列は 2 種類の文字 I , O のみからなる文字列で表され, 2 つの車庫の情報はそれぞれ長さ M の文字列 S および長さ N の文字列 T として与えられる.各文字が 1 つの車両を表し,その文字は車両の種類と同じである.文字列の1 文字目は最も車庫の入り口に近い車両を表し,末尾の文字が車庫の最も奥にある車両を表す. 制限 1 ≤ M ≤ 2000      文字列 S の長さ 1 ≤ N ≤ 2000      文字列 T の長さ 入力 標準入力から以下のデータを読み込め. 1 行目には M , N が空白区切りで書かれている. 2 行目には文字列 S が書かれている. 3 行目には文字列 T が書かれている. 出力 標準出力に,編成できる列車の長さの最大値を表す整数を 1 行で出力せよ. 列車が 1 つも編成できない場合は, 0 を出力せよ. 入出力例 入力例 1 5 5 OIOOI OOIOI 出力例 1 7 S によって表される車庫を車庫 S とし, T によって表される車庫を車庫 T としよう.このとき,たとえば車庫 S から最初の1 車両,車庫 T から最初の 2 車両を出して待機させた後,車庫 S,車庫 S,車庫 T,車庫 S,車庫 S,車庫 T,車庫 T の順番に車両を出せば,長さ7 の列車 IOIOIOI を編成できる. 他にも,車庫 S から最初の 1 車両,車庫 T から最初の 2 車両を出して待機させた後,車庫 T,車庫 T,車庫 S,車庫 S,車庫 T,車庫 S,車庫 S の順番に車両を出すことでも長さ 7 の列車を編成できる.これより長い列車を編成することはできないので 7 を出力する. 入力例 2 5 9 IIIII IIIIIIIII 出力例 2 1 1 つの車両のみからなる列車 I も列車としての条件を満たすことに注意せよ. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0604_10851248", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<string>\nusing namespace std;\nint dp[3][2017][2017], n, m;//I, O, -\nstring S, T;\nint main() {\n\tcin >> n >> m >> S >> T;\n\tfor (int i = 0; i < 2017; i++) { for (int j = 0; j < 2017; j++) { for (int k = 0; k < 3; k++)dp[k][i][j] = -998244353; } }\n\tdp[2][0][0] = 0;\n\tfor (int i = 0; i <= S.size(); i++) {\n\t\tfor (int j = 0; j <= T.size(); j++) {\n\t\t\tif (i != S.size()) {\n\t\t\t\tif (S[i] == 'I') {\n\t\t\t\t\tdp[0][i + 1][j] = max(dp[0][i + 1][j], dp[1][i][j] + 1);\n\t\t\t\t\tdp[0][i + 1][j] = max(dp[0][i + 1][j], dp[2][i][j] + 1);\n\t\t\t\t\tdp[2][i + 1][j] = max(dp[2][i + 1][j], dp[2][i][j]);\n\t\t\t\t}\n\t\t\t\tif (S[i] == 'O') {\n\t\t\t\t\tdp[1][i + 1][j] = max(dp[1][i + 1][j], dp[0][i][j] + 1);\n\t\t\t\t\tdp[2][i + 1][j] = max(dp[2][i + 1][j], dp[2][i][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (j != T.size()) {\n\t\t\t\tif (T[j] == 'I') {\n\t\t\t\t\tdp[0][i][j + 1] = max(dp[0][i][j + 1], dp[1][i][j] + 1);\n\t\t\t\t\tdp[0][i][j + 1] = max(dp[0][i][j + 1], dp[2][i][j] + 1);\n\t\t\t\t\tdp[2][i][j + 1] = max(dp[2][i][j + 1], dp[2][i][j]);\n\t\t\t\t}\n\t\t\t\tif (T[j] == 'O') {\n\t\t\t\t\tdp[1][i][j + 1] = max(dp[1][i][j + 1], dp[0][i][j] + 1);\n\t\t\t\t\tdp[2][i][j + 1] = max(dp[2][i][j + 1], dp[2][i][j]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint maxn = 0;\n\tfor (int i = 0; i <= S.size(); i++) { for (int j = 0; j <= T.size(); j++)maxn = max(maxn, dp[0][i][j]); }\n\tcout << maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 51124, "score_of_the_acc": -0.1568, "final_rank": 12 }, { "submission_id": "aoj_0604_9488111", "code_snippet": "#include <bits/stdc++.h>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\n\nint M, N;\nchar S[2005], T[2005];\nint dp[2001][2001];\n\nint main() {\n // 入力を受け取る\n scanf(\"%d%d%s%s\", &M, &N, S, T); \n int res = 0;\n\n // DPテーブルの初期化\n for (int i = 0; i <= M; i++) {\n for (int j = 0; j <= N; j++) {\n if ((i != 0 && S[i - 1] == 'I') || (j != 0 && T[j - 1] == 'I')) {\n dp[i][j] = 1;\n }\n }\n }\n\n // DPテーブルの更新\n for (int i = 1; i <= M; i++) {\n for (int j = 1; j <= N; j++) {\n // 条件1: 左上からの更新 (Iと非一致)\n if (dp[i - 1][j - 1] > 0 && S[i - 1] != T[j - 1]) {\n dp[i][j] = dp[i - 1][j - 1] + 2;\n }\n // 条件2: 上からの更新 (OIのペア)\n if (i >= 2 && dp[i - 2][j] > 0 && S[i - 2] == 'O' && S[i - 1] == 'I') {\n dp[i][j] = max(dp[i][j], dp[i - 2][j] + 2);\n }\n // 条件3: 左からの更新 (OIのペア)\n if (j >= 2 && dp[i][j - 2] > 0 && T[j - 2] == 'O' && T[j - 1] == 'I') {\n dp[i][j] = max(dp[i][j], dp[i][j - 2] + 2);\n }\n // 結果の最大値の更新\n res = max(res, dp[i][j]);\n }\n }\n\n // 結果を出力\n printf(\"%d\\n\", res);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 19256, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0604_9083654", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint dp[2002][2002][2][2][2];\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m;\n cin >> n >> m;\n string s, t;\n cin >> s >> t;\n for (int i = 0; i <= n + 1; ++i) {\n for (int j = 0; j <= m + 1; ++j) {\n for (int k = 0; k < 2; ++k) {\n for (int l = 0; l < 2; ++l) {\n for (int o = 0; o < 2; ++o) {\n dp[i][j][k][l][o] = -1;\n }\n }\n }\n }\n }\n dp[0][0][0][0][0] = 0;\n for (int i = 0; i <= n; ++i) {\n for (int j = 0; j <= m; ++j) {\n for (int k = 0; k < 2; ++k) {\n for (int l = 0; l < 2; ++l) {\n for (int o = 0; o < 2; ++o) {\n int val = dp[i][j][k][l][o];\n if (val == -1) continue;\n if (i < n) {\n if (!k) dp[i + 1][j][k][l][o] = max(dp[i + 1][j][k][l][o], val);\n if (o == 0 and s[i] == 'I') {\n dp[i + 1][j][1][l][1] = max(dp[i + 1][j][1][l][1], val + 1);\n }\n if (o == 1 and s[i] == 'O') {\n dp[i + 1][j][1][l][0] = max(dp[i + 1][j][1][l][0], val + 1);\n }\n }\n if (j < m) {\n if (!l) dp[i][j + 1][k][l][o] = max(dp[i + 1][j][k][l][o], val);\n if (o == 0 and t[j] == 'I') {\n dp[i][j + 1][k][1][1] = max(dp[i][j + 1][k][1][1], val + 1);\n }\n if (o == 1 and t[j] == 'O') {\n dp[i][j + 1][k][1][0] = max(dp[i][j + 1][k][1][0], val + 1);\n }\n }\n }\n }\n }\n }\n }\n int res = 0;\n for (int i = 0; i <= n + 1; ++i) {\n for (int j = 0; j <= m + 1; ++j) {\n for (int k = 0; k < 2; ++k) {\n for (int l = 0; l < 2; ++l) {\n for (int o = 1; o < 2; ++o) {\n res = max(res, dp[i][j][k][l][o]);\n }\n }\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 128716, "score_of_the_acc": -0.6053, "final_rank": 16 }, { "submission_id": "aoj_0604_8534553", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n int N,M;\n cin>>N>>M;\n string S,T;\n cin>>S>>T;\n reverse(S.begin(),S.end());\n reverse(T.begin(),T.end());\n vector<vector<int>> DP(N+1,vector<int>(M+1,0));\n vector<vector<int>> NDP(N+1,vector<int>(M+1,-1e9));\n for(int i=0;i<=N;i++){\n for(int j=0;j<=M;j++){\n if(DP[i][j]>=0){\n if(i<N&&S[i]=='I')NDP[i+1][j]=max(NDP[i+1][j],DP[i][j]+1);\n if(j<M&&T[j]=='I')NDP[i][j+1]=max(NDP[i][j+1],DP[i][j]+1);\n }\n if(NDP[i][j]>=0){\n if(i<N&&S[i]=='O')DP[i+1][j]=max(DP[i+1][j],NDP[i][j]+1);\n if(j<M&&T[j]=='O')DP[i][j+1]=max(DP[i][j+1],NDP[i][j]+1);\n }\n }\n }\n int an=0;\n for(int i=0;i<=N;i++)for(int j=0;j<=M;j++)if(NDP[i][j]>=0)an=max(an,NDP[i][j]);\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 34520, "score_of_the_acc": -0.0973, "final_rank": 2 }, { "submission_id": "aoj_0604_6100363", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n vector3d(int,dp,n+1,m+1,2,0);\n string s,t;\n cin>>s>>t;\n //0:使用中,1:終了\n int ans=0;\n for(int i=0;i<=n;i++){\n for(int j=0;j<=m;j++){\n for(int k=0;k<2;k++){\n if(k==1&&dp[i][j][k]==0)continue;\n chmax(ans,dp[i][j][k]);\n bool v1=(i<n&&s[i]==(k?'O':'I'));\n bool v2=(j<m&&t[j]==(k?'O':'I'));\n if(v1)chmax(dp[i+1][j][k^1],1+dp[i][j][k]);\n if(v2)chmax(dp[i][j+1][k^1],1+dp[i][j][k]);\n }\n }\n }\n out(max(0,ans-(ans%2==0)));\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 222260, "score_of_the_acc": -1.4212, "final_rank": 19 }, { "submission_id": "aoj_0604_5520120", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\nusing lli = long long int;\n\nint main(){\n int n,m;\n string s,t;\n cin >> n >> m >> s >> t;\n vector<vector<vector<int>>> dp(n+1, vector<vector<int>>(m+1, vector<int>{0, -(n+m)}));\n for(int i=0; i<n+1; i++){\n for(int j=0; j<m+1; j++){\n if(i < n){\n if(s[i] == 'I'){\n dp[i+1][j][1] = max(dp[i+1][j][1], dp[i][j][0]+1);\n }else{\n dp[i+1][j][0] = max(dp[i+1][j][0], dp[i][j][1]+1);\n }\n }\n if(j < m){\n if(t[j] == 'I'){\n dp[i][j+1][1] = max(dp[i][j+1][1], dp[i][j][0]+1);\n }else{\n dp[i][j+1][0] = max(dp[i][j+1][0], dp[i][j][1]+1);\n }\n }\n }\n }\n int ans = 0;\n for(int i=0; i<n+1; i++){\n for(int j=0; j<m+1; j++){\n for(int d=0; d<2; d++){\n ans = max(ans, dp[i][j][d]);\n }\n }\n }\n if(ans%2 == 0 and ans > 0) ans--;\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 222236, "score_of_the_acc": -1.3989, "final_rank": 18 }, { "submission_id": "aoj_0604_5196101", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#define w 2001\n#define q (a[i]+1)%2\n#define p (b[j]+1)%2\nusing namespace std;\nint dp[w][w][2];\nint main(void)\n{\n\tint i,j,k,m,n,a[w],b[w],mx=-1;\n\tchar s[w],t[w];\n\tscanf(\"%d %d\",&m,&n);\n\tscanf(\"%s %s\",s,t);\n\tfor(i=0;i<m;i++){\n\t\tif(s[i]=='O') a[i]=0;\n\t\telse a[i]=1;\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(t[i]=='O') b[i]=0;\n\t\telse b[i]=1;\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\t\t\n\t\t\tdp[i][j][0]=-1;\n\t\t\tdp[i][j][1]=-1;\n\t\t}\n\t}\n\tif(s[0]=='I') dp[1][0][1]=1;\n\telse dp[1][0][0]=0;\n\tif(t[0]=='I') dp[0][1][1]=1;\n\telse dp[0][1][0]=0;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tif(i<m){\n\t\t\t\tif(a[i]==1){\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j<n){\n\t\t\t\tif(b[j]==1){\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tfor(k=0;k<2;k++) mx=max(dp[i][j][k],mx);\n\t\t}\n\t}\n\tif(mx%2==0) mx--; if(mx<0) mx=0;\n\tprintf(\"%d\\n\",mx);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34056, "score_of_the_acc": -0.1173, "final_rank": 6 }, { "submission_id": "aoj_0604_5152817", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 10000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\nll dp0[2005][2005], dp1[2005][2005];\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\t//input\n\tll n, m; cin >> n >> m;\n\tstring s, t; cin >> s >> t;\n\t//if (s[0] == 'I') { dp1[1][0] = 1; }\n\t//if (t[0] == 'I') { dp1[0][1] = 1; }\n\tll ans = 0;\n\trep(i, n + 1) {\n\t\trep(j, m + 1) {\n\t\t\tif (i != 0) {\n\t\t\t\tif (s[i - 1] == 'I') { dp1[i][j] = dp0[i - 1][j] + 1; }\n\t\t\t\telse if (dp1[i - 1][j] != 0) { dp0[i][j] = dp1[i - 1][j] + 1; }\n\t\t\t}\n\t\t\tif (j != 0) {\n\t\t\t\tif (t[j - 1] == 'I') { dp1[i][j] = max(dp1[i][j], dp0[i][j - 1] + 1); }\n\t\t\t\telse if (dp1[i][j - 1] != 0) { dp0[i][j] = max(dp0[i][j], dp1[i][j - 1] + 1); }\n\t\t\t}\n\t\t\tans = max(ans, dp1[i][j]);\n\t\t\t//cout << i << ' ' << j << ' ' << dp0[i][j] << ' ' << dp1[i][j] << endl;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 65920, "score_of_the_acc": -0.2519, "final_rank": 13 }, { "submission_id": "aoj_0604_4983271", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#define w 2001\n#define q (a[i]+1)%2\n#define p (b[j]+1)%2\nusing namespace std;\nint dp[w][w][2];\nint main(void)\n{\n\tint i,j,k,m,n,a[w],b[w],mx=-1;\n\tchar s[w],t[w];\n\tscanf(\"%d %d\",&m,&n);\n\tscanf(\"%s %s\",s,t);\n\tfor(i=0;i<m;i++){\n\t\tif(s[i]=='O') a[i]=0;\n\t\telse a[i]=1;\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(t[i]=='O') b[i]=0;\n\t\telse b[i]=1;\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\t\t\n\t\t\tdp[i][j][0]=-1;\n\t\t\tdp[i][j][1]=-1;\n\t\t}\n\t}\n\tif(s[0]=='I') dp[1][0][1]=1;\n\telse dp[1][0][0]=0;\n\tif(t[0]=='I') dp[0][1][1]=1;\n\telse dp[0][1][0]=0;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tif(i<m){\n\t\t\t\tif(a[i]==1){\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j<n){\n\t\t\t\tif(b[j]==1){\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tfor(k=0;k<2;k++) mx=max(dp[i][j][k],mx);\n\t\t}\n\t}\n\tif(mx%2==0) mx--; if(mx<0) mx=0;\n\tprintf(\"%d\\n\",mx);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34060, "score_of_the_acc": -0.1173, "final_rank": 7 }, { "submission_id": "aoj_0604_4983124", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#define w 2001\n#define q (a[i]+1)%2\n#define p (b[j]+1)%2\nusing namespace std;\nint dp[w][w][2];\nint main(void)\n{\n\tint i,j,k,m,n,a[w],b[w],mx=-1;\n\tchar s[w],t[w];\n\tscanf(\"%d %d\",&m,&n);\n\tscanf(\"%s %s\",s,t);\n\tfor(i=0;i<m;i++){\n\t\tif(s[i]=='O') a[i]=0;\n\t\telse a[i]=1;\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(t[i]=='O') b[i]=0;\n\t\telse b[i]=1;\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\t\t\t\n\t\t\tdp[i][j][0]=-1;\n\t\t\tdp[i][j][1]=-1;\n\t\t}\n\t}\n\tif(s[0]=='I') dp[1][0][1]=1;\n\telse dp[1][0][0]=0;\n\tif(t[0]=='I') dp[0][1][1]=1;\n\telse dp[0][1][0]=0;\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tif(i<m){\n\t\t\t\tif(a[i]==1){\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i+1][j][a[i]]=max(a[i],dp[i+1][j][a[i]]);\n\t\t\t\t\tdp[i+1][j][a[i]]=max(dp[i][j][q]+1,dp[i+1][j][a[i]]);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j<n){\n\t\t\t\tif(b[j]==1){\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tdp[i][j+1][b[j]]=max(b[j],dp[i][j+1][b[j]]);\n\t\t\t\t\tdp[i][j+1][b[j]]=max(dp[i][j][p]+1,dp[i][j+1][b[j]]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(i=0;i<=m;i++){\n\t\tfor(j=0;j<=n;j++){\n\t\t\tfor(k=0;k<2;k++){\n\t\t\t\tmx=max(dp[i][j][k],mx);\n\t\t\t\t//printf(\"%d.\",dp[i][j][k]);\n\t\t\t}\n\t\t\t//printf(\" \");\n\t\t}\n\t\t//printf(\"\\n\");\n\t}\n\tif(mx%2==0) mx--;\n\tif(mx<0) mx=0;\n\tprintf(\"%d\\n\",mx);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34020, "score_of_the_acc": -0.1171, "final_rank": 5 }, { "submission_id": "aoj_0604_4819427", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nint main() {\n\tint LS, LT; string S, T;\n\tcin >> LS >> LT >> S >> T;\n\tvector<vector<pair<int, int> > > dp(LS + 1, vector<pair<int, int> >(LT + 1, make_pair(-inf, -inf)));\n\tfor (int i = 0; i <= LS; ++i) {\n\t\tfor (int j = 0; j <= LT; ++j) {\n\t\t\tif (i != LS && S[i] == 'I') dp[i + 1][j].first = 1;\n\t\t\tif (j != LT && T[j] == 'I') dp[i][j + 1].first = 1;\n\t\t}\n\t}\n\tint ans = 0;\n\tfor (int i = 0; i <= LS; ++i) {\n\t\tfor (int j = 0; j <= LT; ++j) {\n\t\t\tif (i >= 1) {\n\t\t\t\tif (S[i - 1] == 'I') {\n\t\t\t\t\tdp[i][j].first = max(dp[i][j].first, dp[i - 1][j].second + 1);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tdp[i][j].second = max(dp[i][j].second, dp[i - 1][j].first + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(j >= 1) {\n\t\t\t\tif (T[j - 1] == 'I') {\n\t\t\t\t\tdp[i][j].first = max(dp[i][j].first, dp[i][j - 1].second + 1);\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tdp[i][j].second = max(dp[i][j].second, dp[i][j - 1].first + 1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tans = max(ans, dp[i][j].first);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34388, "score_of_the_acc": -0.1189, "final_rank": 8 }, { "submission_id": "aoj_0604_4781435", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int m, n;\n string s, t;\n cin >> m >> n >> s >> t;\n const int N = 2000, INF = 4000;\n static int opt[N+1][N+1][2] = {};\n int ans = 0;\n for(int i = m; i >= 0; i--) {\n for(int j = n; j >= 0; j--) {\n for(bool mustI : {true, false}) {\n char req = mustI ? 'I' : 'O';\n int& cur = opt[i][j][mustI];\n cur = mustI ? -INF : 0;\n if(i < m and s[i] == req) {\n cur = max(cur, 1 + opt[i + 1][j][not mustI]);\n }\n if(j < n and t[j] == req) {\n cur = max(cur, 1 + opt[i][j + 1][not mustI]);\n }\n }\n ans = max({ans, opt[i][j][true]});\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34532, "score_of_the_acc": -0.1418, "final_rank": 11 }, { "submission_id": "aoj_0604_4413756", "code_snippet": "#include<iostream>\n#include<vector>\n\nusing namespace std;\n\nconstexpr int INF = (1 << 30) - 1;\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n int m, n;\n cin >> m >> n;\n\n string s, t;\n cin >> s >> t;\n\n vector< vector< vector< vector<int> > > > dp(3, vector< vector< vector<int> > >(2, vector< vector<int> >(m + 1, vector<int>(n + 1, -INF))));\n dp[0][0][0][0] = 0;\n\n for(int i = 0 ; i <= m ; ++i){\n for(int j = 0 ; j <= n ; ++j){\n if(i < m){\n chmax(dp[0][0][i + 1][j], dp[0][0][i][j]);\n }\n if(j < n){\n chmax(dp[0][0][i][j + 1], dp[0][0][i][j]);\n }\n\n if(i < m && s[i] == 'I'){\n chmax(dp[1][1][i + 1][j], dp[0][0][i][j] + 1);\n chmax(dp[1][1][i + 1][j], dp[1][0][i][j] + 1);\n }\n if(j < n && t[j] == 'I'){\n chmax(dp[1][1][i][j + 1], dp[0][0][i][j] + 1);\n chmax(dp[1][1][i][j + 1], dp[1][0][i][j] + 1);\n }\n\n if(i < m && s[i] == 'O'){\n chmax(dp[1][0][i + 1][j], dp[1][1][i][j] + 1);\n }\n if(j < n && t[j] == 'O'){\n chmax(dp[1][0][i][j + 1], dp[1][1][i][j] + 1);\n }\n\n chmax(dp[2][1][m][n], dp[0][0][i][j]);\n chmax(dp[2][1][m][n], dp[1][1][i][j]);\n }\n }\n\n cout << dp[2][1][m][n] << endl;\n\n cout << flush;\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 144420, "score_of_the_acc": -0.7937, "final_rank": 17 }, { "submission_id": "aoj_0604_4392683", "code_snippet": "#include <algorithm>\n#include <cstdint>\n#include <cstring>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define REP(i, n) for (int i = 0; i < n; i++)\n#define FOR(i, s, t) for (int i = s; i < t; i++)\n#define ALL(obj) obj.begin(), obj.end()\n\nconst int iINF = 1e9;\nconst long long llINF = 1e18;\nconst int MOD = 1e9 + 7;\ntemplate <class T>\ninline bool chmax(T& a, T b) {\n if (a < b) {\n a = b;\n return 1;\n }\n return 0;\n}\ntemplate <class T>\ninline bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return 1;\n }\n return 0;\n}\n\ntemplate <int MOD>\nstruct ModInt {\n long long val;\n constexpr ModInt(long long v = 0) noexcept : val(v % MOD) {\n if (val < 0) val += MOD;\n }\n constexpr int getmod() { return MOD; }\n constexpr ModInt operator-() const noexcept { return val ? MOD - val : 0; }\n constexpr ModInt operator+(const ModInt& r) const noexcept { return ModInt(*this) += r; }\n constexpr ModInt operator-(const ModInt& r) const noexcept { return ModInt(*this) -= r; }\n constexpr ModInt operator*(const ModInt& r) const noexcept { return ModInt(*this) *= r; }\n constexpr ModInt operator/(const ModInt& r) const noexcept { return ModInt(*this) /= r; }\n constexpr ModInt& operator+=(const ModInt& r) noexcept {\n val += r.val;\n if (val >= MOD) val -= MOD;\n return *this;\n }\n constexpr ModInt& operator-=(const ModInt& r) noexcept {\n val -= r.val;\n if (val < 0) val += MOD;\n return *this;\n }\n constexpr ModInt& operator*=(const ModInt& r) noexcept {\n val = val * r.val % MOD;\n return *this;\n }\n constexpr ModInt& operator/=(const ModInt& r) noexcept {\n long long a = r.val, b = MOD, u = 1, v = 0;\n while (b) {\n long long t = a / b;\n a -= t * b;\n swap(a, b);\n u -= t * v;\n swap(u, v);\n }\n val = val * u % MOD;\n if (val < 0) val += MOD;\n return *this;\n }\n constexpr bool operator==(const ModInt& r) const noexcept { return this->val == r.val; }\n constexpr bool operator!=(const ModInt& r) const noexcept { return this->val != r.val; }\n friend constexpr ostream& operator<<(ostream& os, const ModInt<MOD>& x) noexcept { return os << x.val; }\n\n friend constexpr istream& operator>>(istream& is, ModInt<MOD>& x) noexcept { return is >> x.val; }\n friend constexpr ModInt<MOD> modpow(const ModInt<MOD>& a, long long n) noexcept {\n if (n == 0) return 1;\n auto t = modpow(a, n / 2);\n t = t * t;\n if (n & 1) t = t * a;\n return t;\n }\n};\n\nusing mint = ModInt<MOD>;\n\nlong long modPow(long long x, long long n, long long mod) {\n long long res = 1;\n while (n > 0) {\n if (n & 1) res = res * x % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return res;\n}\n\nlong long extGCD(long long a, long long b, long long& x, long long& y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n\n long long d = extGCD(b, a % b, y, x);\n y -= a / b * x;\n return d;\n}\n\nlong long gcd(long long a, long long b) {\n if (b == 0) {\n return a;\n } else {\n return gcd(b, a % b);\n }\n}\n\nlong long lcm(long long a, long long b) { return a / gcd(a, b) * b; }\n\ntemplate <typename T>\nmap<T, int> compress(vector<T> x) {\n map<T, int> res;\n sort(x.begin(), x.end());\n x.erase(unique(x.begin(), x.end()), x.end());\n for (int i = 0; i < x.size(); i++) {\n res[x[i]] = i;\n }\n\n return res;\n}\n\ntemplate <typename T>\nint former(const vector<T>& v, T x) {\n return upper_bound(v.begin(), v.end(), x) - v.begin() - 1;\n}\n\ntemplate <typename T>\nint latter(const vector<T>& v, T x) {\n return lower_bound(v.begin(), v.end(), x) - v.begin();\n}\n\ntemplate <typename T>\nusing Vec = vector<T>;\ntemplate <typename T>\nusing VVec = vector<vector<T>>;\nusing LL = long long;\n\nint dp[2010][2010][2];\nint main() {\n int M, N;\n cin >> M >> N;\n string S, T;\n cin >> S >> T;\n REP(i, M) { S[i] = S[i] == 'I' ? 1 : 0; }\n REP(i, N) { T[i] = T[i] == 'I' ? 1 : 0; }\n REP(i, M + 1) REP(j, N + 1) dp[i][j][0] = 0, dp[i][j][1] = -iINF;\n REP(i, M + 1) {\n REP(j, N + 1) {\n if (i < M) chmax(dp[i + 1][j][S[i]], dp[i][j][!S[i]] + 1);\n if (j < N) chmax(dp[i][j + 1][T[j]], dp[i][j][!T[j]] + 1);\n }\n }\n int ans = 0;\n REP(i, M + 1) {\n REP(j, N + 1) {\n chmax(ans, dp[i][j][1]);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 34656, "score_of_the_acc": -0.098, "final_rank": 4 }, { "submission_id": "aoj_0604_4149500", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint M,N;\nstring S,T;\n\nll dp[2003][2003][2];\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> M >> N >> S >> T;\n\n for (int i = 0;i <= M;i++){\n for (int j = 0;j <= N;j++){\n dp[i][j][0] = -1;\n dp[i][j][1] = -1;\n }\n }\n\n dp[0][0][0] = 0;\n ll ans = 0;\n\n for (int i = 0;i <= M;i++){\n for (int j = 0;j <= N;j++){\n dp[i][j][0] = max(dp[i][j][0],0LL);\n //cout << i << \" \" << j << \" \" << dp[i][j][0] << \" \" << dp[i][j][1] << endl;\n ans = max(ans,dp[i][j][1]);\n if(dp[i][j][0] >= 0){\n if(i < M && S[i] == 'I') dp[i+1][j][1] = max(dp[i+1][j][1],dp[i][j][0]+1);\n if(j < N && T[j] == 'I') dp[i][j+1][1] = max(dp[i][j+1][1],dp[i][j][0]+1);\n }\n if(dp[i][j][1] >= 0){\n if(i < M && S[i] == 'O') dp[i+1][j][0] = max(dp[i+1][j][0],dp[i][j][1]+1);\n if(j < N && T[j] == 'O') dp[i][j+1][0] = max(dp[i][j+1][0],dp[i][j][1]+1);\n }\n }\n }\n\n cout << ans << endl;\n \n return 0;\n\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 65880, "score_of_the_acc": -0.2739, "final_rank": 14 }, { "submission_id": "aoj_0604_4054411", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint dp[2][2001][2001] = {};\n\nint main(){\n int n, m;\n cin >> n >> m;\n string s, t;\n cin >> s >> t;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < m; j++){\n if(s[i] == 'I') dp[1][i+1][j] = 1;\n if(t[j] == 'I') dp[1][i][j+1] = 1;\n }\n }\n for(int i = 0; i <= n; i++){\n for(int j = 0; j <= m; j++){\n for(int k = 0; k < 2; k++){\n if(dp[k][i][j] == 0) continue;\n if(i < n && s[i] == \"IO\"[k]) dp[1-k][i+1][j] = max(dp[1-k][i+1][j], dp[k][i][j]+1);\n if(j < m && t[j] == \"IO\"[k]) dp[1-k][i][j+1] = max(dp[1-k][i][j+1], dp[k][i][j]+1);\n }\n }\n }\n int ans = 0;\n for(int i = 1; i <= n; i++){\n for(int j = 1; j <= m; j++){\n ans = max(ans, dp[1][i][j]);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34468, "score_of_the_acc": -0.1415, "final_rank": 10 }, { "submission_id": "aoj_0604_4012881", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\nstring s, t;\nvector<vector<vector<int>>> dp;\n\nint calc(int x, int y, bool isI) {\n int ret = 0;\n if (x < s.size() && ((s[x] == 'I') == isI)) {\n if (dp[x + 1][y][!isI] < 0) dp[x + 1][y][!isI] = calc(x + 1, y, !isI) + 1;\n ret = max(ret, dp[x + 1][y][!isI]);\n }\n if (y < t.size() && ((t[y] == 'I') == isI)) {\n if (dp[x][y + 1][!isI] < 0)dp[x][y + 1][!isI] = calc(x, y + 1, !isI) + 1;\n ret = max(ret, dp[x][y + 1][!isI]);\n }\n return ret;\n}\n\nint main() {\n int m, n;\n cin >> m >> n >> s >> t;\n\n int ret = 0;\n dp = vector<vector<vector<int>>>(m + 1, vector<vector<int>>(n + 1, vector<int>(2, -1)));\n for (int i = 0; i < m; i++) {\n for (int j = 0; j < n; j++) {\n ret = max(ret, (calc(i, j, true) + 1) / 2 * 2 - 1);\n }\n }\n\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 222464, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0604_3983007", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n \n \n\n\n\nint dp[2020][2020][2]={};\n\n\nint l1,l2;\nstring s,t;\nint solve(int x,int y,int d){\n\tif(dp[x][y][d]>=0) return dp[x][y][d];\n\tint p=0;\n\tif(d==0){\n\t\tif(x!=l1 && s[x]=='O')p=max(p,solve(x+1,y,1)+1);\n\t\tif(y!=l2 && t[y]=='O')p=max(p,solve(x,y+1,1)+1);\n\t\t\n\t}\n\telse{\n\t\tif(x!=l1 && s[x]=='I')p=max(p,solve(x+1,y,0)+1);\n\t\tif(y!=l2 && t[y]=='I')p=max(p,solve(x,y+1,0)+1);\t\t\n\t}\n\tdp[x][y][d]=p;\n\treturn p;\n}\n\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\n\t//int l1,l2;\n\tcin>>l1>>l2;\n\t//string s,t;\n\tcin>>s>>t;\n\t\n\tfor(int i=0;i<=l1;i++)for(int j=0;j<=l2;j++){\n\t\tdp[i][j][0]=-1;\n\t\tdp[i][j][1]=-1;\n\t\t\n\t}\n\tdp[l1][l2][0]=0;\n\tdp[l1][l2][1]=0;\n\t\n\tint ans=0;\n\tfor(int i=0;i<=l1;i++)for(int j=0;j<=l2;j++){\n\t\tans=max(ans,solve(i,j,1));\n\t\tsolve(i,j,0);\n\t}\n\t\n\tif(ans>0 && ans%2==0)ans--;\n\tcout<<ans<<endl;\n\t\n\treturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 110, "memory_kb": 66536, "score_of_the_acc": -0.4327, "final_rank": 15 }, { "submission_id": "aoj_0604_3917746", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <string>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <cmath>\n#include <cstdio>\nusing namespace std;\n#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)\n#define FOR(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define All(v) (v).begin(),(v).end()\ntypedef long long ll;\n\nint dp[2010][2010][2];\n\nint main(){\n int M,N;\n cin >> M >> N;\n string S,T;\n cin >> S >> T;\n //dp[i][j][k]=Sのi文字目、Tのj文字目まで見て、列車の末尾がkの時に作れる最長の列車の長さ\n dp[0][0][0]=dp[0][0][1]=0;\n int res = 0;\n FOR(i,0,M+1){\n FOR(j,0,N+1){\n int tmp = 0;\n if(i>0)if(S[i-1]=='I')tmp = max(tmp,dp[i-1][j][0]+1);\n if(j>0)if(T[j-1]=='I')tmp = max(tmp,dp[i][j-1][0]+1);\n dp[i][j][1]=tmp;\n\n tmp = 0;\n if(i>0)if(S[i-1]=='O'&&dp[i-1][j][1]>0)tmp = max(tmp,dp[i-1][j][1]+1);\n if(j>0)if(T[j-1]=='O'&&dp[i][j-1][1]>0)tmp = max(tmp,dp[i][j-1][1]+1);\n dp[i][j][0]=tmp; \n\n res = max(res,dp[i][j][1]); \n }\n }\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 34616, "score_of_the_acc": -0.0978, "final_rank": 3 }, { "submission_id": "aoj_0604_3859976", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = uint32_t;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\ntemplate<class T> void chmin(T &a, const T &b){ a = (a < b ? a : b); }\ntemplate<class T> void chmax(T &a, const T &b){ a = (a > b ? a : b); }\n\nint main() {\n int n, m;\n string s, t;\n cin >> n >> m >> s >> t;\n vector<vector<int>> dpi(n+1, vector<int>(m+1, 0));\n auto dpo = dpi;\n int ans = 0;\n for (int i = 0; i <= n; ++i) {\n for (int j = 0; j <= m; ++j) {\n if((i && s[i-1] == 'I') ) dpi[i][j] = 1;\n if((j && t[j-1] == 'I')) dpi[i][j] = 1;\n if(i && dpi[i-1][j] > 0 && s[i-1] == 'O') chmax(dpo[i][j], dpi[i-1][j]+1);\n if(i && dpo[i-1][j] > 0 && s[i-1] == 'I') chmax(dpi[i][j], dpo[i-1][j]+1);\n if(j && dpi[i][j-1] > 0 && t[j-1] == 'O') chmax(dpo[i][j], dpi[i][j-1]+1);\n if(j && dpo[i][j-1] > 0 && t[j-1] == 'I') chmax(dpi[i][j], dpo[i][j-1]+1);\n ans = max(ans, dpi[i][j]);\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 34332, "score_of_the_acc": -0.1409, "final_rank": 9 } ]
aoj_0603_cpp
電飾(Illumination) JOI 高校の文化祭では毎年廊下に電飾が飾られる.電飾は N 個の電球で構成されており,電球は廊下の西側から東側に一列に並んでいる.各電球は明かりがついているか,ついていないかのいずれかの状態である. JOI 高校の倉庫には電球を操作する機械が眠っている.この機械は電飾内で連続した電球を指定すると,指定された電球のうち,明かりがついている電球全てを明かりがついていない状態にし,明かりがついていない電球全てを明かりがついている状態にする.ただし,機械は老朽化のため,1 回しか使用できない. JOI 高校の生徒達は明かりがついている電球とついていない電球が交互に並んだ列(このような電球の列を交互列と呼ぶ)が好きである.そこで,この機械を必要ならば1 回だけ使って,できるだけ長い交互列を含む電飾を作ることにした. 例 例えば,電飾の配置が西から東に向かって となっていたとする(○は明かりがついている電球を,●は明かりがついていない電球を表す).このとき,4 番目から7 番目までの4 個の電球に対して機械を操作すると, となり,2 番目から8 番目までの電球が長さ7 の交互列をなす. また,8 番目の電球のみに対して機械を操作すると, となり,4 番目から10 番目までの電球が長さ7 の交互列をなす. 機械を最大1 回使用することで,長さが8 以上の交互列を作ることはできない. 課題 電飾の情報が与えられたとき,機械を最大1 回使用することで得られる電球の配列に含まれる交互列の長さとして考えられるものの最大値を求めるプログラムを作成せよ. 制限 2 ≤ N ≤ 100 000      電飾を構成する電球の個数 入力 標準入力から以下のデータを読み込め. 1 行目には整数 N が書かれている. 2 行目には N 個の 0 または 1 が空白を区切りとして書かれている.各整数は機械を操作する前における電球の情報を表している.左から i ( 1 ≤ i ≤ N ) 番目の整数は西側から i 番目の電球の情報を表しており,整数が 1 ならば電球の明かりがついていて,0 ならば明かりがついていないことを表す. 出力 標準出力に,作成可能な電球の列に含まれる交互列の長さの最大値を表す整数を1 行で出力せよ. 入出力例 入力例 1 10 1 1 0 0 1 0 1 1 1 0 出力例 1 7 これは問題文中で説明された例である. 入力例 2 10 1 0 0 0 0 1 0 1 0 1 出力例 2 8 西側から 4 番目の電球のみを操作すると,最大値 8 を満たす交互列が得られる. 入力例 3 5 1 1 0 1 1 出力例 3 5 西側から数えて 2 番目から 4 番目までの電球を操作すると,全ての電球からなる交互列を作ることがで きる. 入力例 4 3 0 1 0 出力例 4 3 機械を使用しなくても良い場合があることに注意せよ. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0603_7705268", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n#include <cstdio>\n#include <iostream>\n#include <stack>\n#include <queue>\n#include <algorithm>\n#include <functional>\n#include <set>\n#include <map>\n#include <string>\n#include <vector>\n#include <cmath>\n#include<sstream>\n#include<list>\n#include<iomanip>\n#include <cstdlib>\n#include <cstring>\n#include <stack>\n#include <bitset>\n#include <cassert>\n#include <stdlib.h>\n#include <stdio.h>\nusing namespace std;\nconst int INF = 100000000;\nconst long long LINF = 3e18 + 7;\nconst int MAX_N = 10000010;\nconst int MAX_W = 10002;\nconst int MAX_ARRAYK = 100000;\ndouble PI = 3.14159265358979323846;\n//using ll = long long;\n\n// poj3276\n// 蟻本 p.139\n\nint N;\nint dir[MAX_N];\n\nint main() {\n\n\tcin >> N;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> dir[i];\n\t}\n\n\tvector<int> v;\n\tv.push_back(0);\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tif (dir[i] == dir[i + 1]) {\n\t\t\tv.push_back(i + 1);\n\t\t}\n\t}\n\n\tv.push_back(N);\n\n\tint ans = 0;\n\tif (v.size() <= 3) {\n\t\tans = v[v.size() - 1] - v[0];\n\t}\n\telse {\n\t\tfor (int i = 0; i + 3 < v.size(); i++) {\n\t\t\tans = max(ans, v[i + 3] - v[i]);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3660, "score_of_the_acc": -0.0237, "final_rank": 6 }, { "submission_id": "aoj_0603_5824547", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\nint dp[100001][3];\n\nint main()\n{\n\tint N;\n\tcin >> N;\n\tint* a = new int[N];\n\tfor (int i = 0; i < N; i++)\n\t\tcin >> a[i];\n\tdp[0][0] = 1;\n\tdp[0][1] = 1;\n\tdp[0][2] = 1;\n\tint ans = 1;\n\tfor (int i = 1; i < N; i++)\n\t{\n\t\tif (a[i] == a[i - 1])\n\t\t{\n\t\t\tdp[i][0] = 1;\n\t\t\tdp[i][1] = dp[i - 1][0] + 1;\n\t\t\tdp[i][2] = dp[i - 1][1] + 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tdp[i][0] = dp[i - 1][0] + 1;\n\t\t\tdp[i][1] = dp[i - 1][1] + 1;\n\t\t\tdp[i][2] = dp[i - 1][2] + 1;\n\t\t}\n\t\tans = max(ans, max(dp[i][0], max(dp[i][1],dp[i][2])));\n\t}\n\tcout << ans << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4684, "score_of_the_acc": -0.0919, "final_rank": 15 }, { "submission_id": "aoj_0603_5561105", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <math.h>\n#include <stdio.h>\n#include <string>\n#include <sstream>\n#include <bitset>\n#include <stack>\n#include <queue>\n#include <bits/stdc++.h>\n//#include <atcoder/segtree>\n#define rep(i, s, t) for(int i = (s); i <= (t); i++)\n#define repd(i, s, t) for(int i = (s); i >= (t); i--)\n#define all(v) v.begin(), v.end()\ntypedef long long ll;\nusing namespace std;\ntypedef pair<int, int> pii;\n\n\nint main(){\n int n; cin >> n;\n vector<int> f(n);\n rep(i, 0, n-1){\n int buf; cin >> buf;\n if(i % 2 == 0) f[i] = (buf + 1)%2;\n else f[i] = buf;\n }\n\n vector<int> kogo(0);\n int cur_num = 0;\n int sum = 0;\n rep(i, 0, n-1){\n if(cur_num != f[i]){\n kogo.push_back(sum);\n cur_num = f[i];\n sum = 0;\n }\n sum++;\n }\n kogo.push_back(sum);\n\n int ans = 0;\n sum = 0;\n n = kogo.size();\n if(n < 3){\n rep(i, 0, n-1){\n sum += kogo[i];\n }\n cout << sum << endl;\n return 0;\n }\n\n rep(i, 0, n-3){\n sum = kogo[i] + kogo[i+1] + kogo[i+2];\n ans = max(ans, sum);\n }\n \n cout << ans << endl;\n \n //rep(i, 0, kogo.size()-1) cout << kogo[i] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3604, "score_of_the_acc": -0.02, "final_rank": 5 }, { "submission_id": "aoj_0603_5475785", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, N) for (int i = 0; i < N; i++)\n\nint main()\n{\n int N;\n cin >> N;\n int S[N];\n rep(i, N) cin >> S[i];\n vector<int> A;\n int prev = S[0];\n int cnt = 1;\n for (int i = 1; i < N; i++)\n {\n if (S[i] != prev)\n {\n cnt++;\n }\n else\n {\n A.push_back(cnt);\n cnt = 1;\n }\n prev = S[i];\n }\n A.push_back(cnt);\n /*\n rep(i, A.size())\n {\n cout << A[i] << \" | \";\n }*/\n int maxv = 0;\n int tot = 0;\n if (A.size() <= 3)\n {\n rep(i, A.size())\n {\n tot += A[i];\n }\n cout << tot << endl;\n return 0;\n }\n else\n {\n maxv = A[0] + A[1] + A[2];\n rep(i, A.size() - 2)\n {\n maxv = max(maxv, A[i] + A[i + 1] + A[i + 2]);\n }\n cout << maxv << endl;\n }\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3672, "score_of_the_acc": -0.0245, "final_rank": 8 }, { "submission_id": "aoj_0603_5320868", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\n//入力系\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\n//出力系\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\n//デバッグ系\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint n;\nvector<int> a;\nvector3d(int,dp,100001,2,2,-1);\nint rec(int i,int rev,int used){\n if(i==n)return 0;\n if(dp[i][rev][used]!=-1)return dp[i][rev][used];\n if(rev==0){\n if(a[i]!=a[i+1])return dp[i][rev][used]=rec(i+1,0,used)+1;\n else{\n if(used)return dp[i][rev][used]=1;\n else return dp[i][rev][used]=rec(i+1,1,1)+1;\n }\n }else{\n if(a[i]!=a[i+1])return dp[i][rev][used]=rec(i+1,1,used)+1;\n else return dp[i][rev][used]=rec(i+1,0,used)+1;\n }\n}\n\nint main(){\n in(n);\n a.resize(n);\n in(a);\n int ans=0;\n rep(i,n){\n chmax(ans,rec(i,0,0));\n chmax(ans,rec(i,1,1));\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 18328, "score_of_the_acc": -1.25, "final_rank": 19 }, { "submission_id": "aoj_0603_5251191", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0; i<(n);i++)\nusing ll = long long;\nconst ll INF = 1e9+7;\nusing P = pair<int,int>;\n\nint main(){\n int n;\n cin >> n;\n vector<int> s(n);\n rep(i,n) cin >> s[i];\n vector<int> num;\n for(int i=0; i<n; ++i){\n int prev = i;\n while(i<n-1 && s[i]!= s[i+1]){\n i++;\n }\n num.push_back(i-prev+1);\n }\n\n ll ans = 0;\n if(num.size()<=2){\n for(auto x : num) ans += x;\n cout << ans << endl;\n return 0;\n }\n ans = num[0]+ num[1];\n for(int i=2; i<num.size(); ++i){\n ans = max(ans, (ll)num[i]+num[i-1]+num[i-2]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3668, "score_of_the_acc": -0.0242, "final_rank": 7 }, { "submission_id": "aoj_0603_4782652", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define double long double\n#define rep(i, a, n) for(int i = (int)(a);(i) < (int)(n);++(i))\n#define repe(i, a, n) for(int i = (int)(a);(i) <= (int)(n);++(i))\n#define repif(i, a, x) for(int i = (int)(a);(x);++(i))\n#define repr(i, a, n) for(int i = ((int)(a)-1);(i) >= (int)(n);--(i))\n#define reper(i, a, n) for(int i = (int)(a);(i) >= (int)(n);--(i))\n#define SZ(x) ((int)(x).size())\n#define ALL(x) begin(x), end(x)\n#define CEIL(x) ((int)ceil(((double)x)))\n#define POW(x, y) ((int)pow(x, y))\n#define UNIQUE(x) (x).erase(unique(ALL((x))), end(x))\n#define gcd(x, y) __gcd(x, y)\n#define lcm(x, y) ((x)/gcd(x,y)*(y))\nusing namespace std;\nusing VI = vector<int>;\nusing VVI = vector<vector<int>>;\nusing PII = pair<int, int>;\nusing TIII = tuple<int, int, int>;\nusing VPII = vector<pair<int, int>>;\nusing VTIII = vector<tuple<int, int, int>>;\nusing Complex = complex<double>;\ntemplate<typename T> inline bool chmax(T& a, const T& b, bool t = false){ if(a<b or (t and a==b)){ a=b; return true; } return false; }\ntemplate<typename T> inline bool chmin(T& a, const T& b, bool t = false){ if(a>b or (t and a==b)){ a=b; return true; } return false; }\ntemplate<typename T> inline bool isin(const T& x, const T& l, const T& r){ return l <= x and x < r; }\ninline ostream& fcout(int n = 10){ return cout << fixed << setprecision(n); }\ninline ostream& rcout(int n = 2){ return cout << right << setw(n); }\nconstexpr int64_t INF = numeric_limits<int64_t>::max();\nconstexpr int32_t INF32 = numeric_limits<int32_t>::max();\nconstexpr int64_t MOD = 1000000007LL;\nconstexpr double PI = 3.14159265358979323846264338327950288;\nconstexpr double EPS = 1e-10;\n\n\nint N;\nVI v;\n\n\nint32_t main(){\n cin >> N;\n int p = -1;\n v.push_back(0);\n v.push_back(0);\n rep(i, 0, N){\n int c;\n cin >> c;\n if(p != c) v.back()++;\n else v.push_back(1);\n p = c;\n }\n v.push_back(0);\n\n int ans = 0;\n rep(i, 1, SZ(v)-1) chmax(ans, v[i-1]+v[i]+v[i+1]);\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0104, "final_rank": 2 }, { "submission_id": "aoj_0603_4414814", "code_snippet": "#include \"bits/stdc++.h\"\n#define int long long\n#define FOR(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define ALL(obj) begin(obj), end(obj)\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define LOWER_BOUND(A, key) distance(A.begin(), lower_bound(ALL(A), key))\n#define UPPER_BOUND(A, key) distance(A.begin(), upper_bound(ALL(A), key))\n\nusing namespace std;\nusing ll = long long;\nconst int MOD = (int)(1e9 + 7);\nconst int INF = (int)(1e13 + 7);\n\nint bpm(int x, unsigned int y) {\n if (x == 0) return 0;\n if (y == 0) return 1;\n int ans = 1;\n int digit = (int)((log((double)y) / log((double)2) / 1 + 1));\n x %= MOD;\n for (unsigned int i = 0; i < digit; i++) {\n if (((y >> i) & 1u) == 1) ans = ans * x % MOD;\n x = x * x % MOD;\n }\n return ans;\n}\n\nsigned main() {\n int N;\n cin >> N;\n vector<int> light(N);\n vector<int> maxi_num_R(N);\n vector<int> maxi_num_L(N);\n\n rep(i, N) cin >> light[i];\n int maxi = 0;\n int L = 0;\n int R = 0;\n while (true) {\n maxi_num_R[R] = max(maxi_num_R[R], R - L + 1);\n maxi_num_L[L] = max(maxi_num_L[L], R - L + 1);\n if (R == N-1) break;\n if (light[R] != light[R + 1]) {\n R++;\n } else if (R == L) {\n R++;\n L++;\n } else {\n L++;\n }\n }\n maxi_num_R[N-1] = max(maxi_num_R[N-1], R-L+1);\n rep(i, N-1) maxi_num_L[i+1] = max(maxi_num_L[i+1], maxi_num_L[i]-1);\n R = L = 0;\n while (R != N - 1) {\n if (L != 0 and R != N - 1) maxi = max(maxi, R - L + 1 + maxi_num_R[L - 1] + maxi_num_L[R + 1]);\n if (L != 0) maxi = max(maxi, R - L + 1 + maxi_num_R[L - 1]);\n if (R != N - 1) maxi = max(maxi, R - L + 1 + maxi_num_L[R + 1]);\n if (light[R] != light[R + 1]) {\n R++;\n } else if (R == L) {\n R++;\n L++;\n } else {\n L++;\n }\n }\n cout << maxi << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5116, "score_of_the_acc": -0.1206, "final_rank": 16 }, { "submission_id": "aoj_0603_4414770", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<map>\n#include<math.h>\n#include<iomanip>\n#include<set>\n#include<numeric>\n#include<cstring>\n#include<cstdio>\n#include<functional>\n#include<bitset>\n#include<limits.h>\n#include<cassert>\n#include<iterator>\n#include<complex>\n#include<stack>\n#include<sstream>\n#include<iterator>\n#include<list>\n\nusing namespace std;\n\ntypedef long long int lint;\n\n#define rep(i, n) for (lint i = 0; i < n; i++)\n#define sort(v) sort((v).begin(), (v).end())\n#define reverse(v) reverse((v).begin(), (v).end())\n#define upper(v,hoge) upper_bound(v.begin(),v.end(),hoge)\n#define lower(v,hoge) lower_bound(v.begin(),v.end(),hoge)\n#define llower(v,hoge) *lower_bound(v.begin(), v.end(), hoge)\n#define lupper(v,hoge) *upper_bound(v.begin(), v.end(), hoge)\n#define mp make_pair\n#define IP pair<int,int>\n#define enld endl\n\nint main() {\n\tlint N;\n\tcin >> N;\n\tvector<int>A(N);\n\trep(i, N) {\n\t\tcin >> A[i];\n\t}\n\tvector<lint>B;\n\tint cnt = 1;\n\trep(i, N-1) {\n\t\tif (A[i] == A[i + 1]) {\n\t\t\tB.push_back(cnt);\n\t\t\tcnt = 1;\n\t\t}\n\t\telse {\n\t\t\tcnt++;\n\t\t}\n\t}\n\tB.push_back(cnt);\n\tlint BS = B.size();\n\t\n\tlint ans = 0;\n\tif (BS == 1) {\n\t\tans = B[0];\n\t}\n\telse if (BS == 2) {\n\t\tans = B[0] + B[1];\n\t}\n\telse {\n\t\trep(i, BS - 2) {\n\t\t\tans = max(ans, B[i] + B[i + 1] + B[i + 2]);\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3844, "score_of_the_acc": -0.0359, "final_rank": 9 }, { "submission_id": "aoj_0603_4228874", "code_snippet": "/* ---------- STL Libraries ---------- */\n// IO library\n#include <cstdio>\n\n#include <fstream>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n\n// algorithm library\n#include <algorithm>\n\n#include <cmath>\n#include <numeric>\n#include <random>\n#include <cstring>\n#include <cassert>\n\n// container library\n#include <array>\n#include <bitset>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <stack>\n\n// type\n#include <cstdint>\n\n/* ---------- Namespace ---------- */\nusing namespace std;\n\n/* ---------- Type ---------- */\nusing ll = long long;\n#define int ll\n#define P pair<ll, ll>\n\n/* ---------- Constants */\nconst double PI = 3.141592653589793238462643383279;\nconst ll MOD = 1e9 + 7;\nconst int INF = 1LL << 55;\n\nsigned main() {\n int N;\n cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; i++) cin >> A[i];\n\n vector<int> B;\n int cnt = 0;\n for (int i = 0; i < N; i++) {\n cnt++;\n if (i == N-1 || A[i] == A[i+1]) {\n B.push_back(cnt);\n cnt = 0;\n }\n }\n\n int M = B.size();\n if (M < 3) {\n cout << N << endl;\n return 0;\n }\n\n int mx = -1;\n for (int i = 0; i < M-2; i++) {\n mx = max(mx, B[i] + B[i+1] + B[i+2]);\n }\n\n cout << mx << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4224, "score_of_the_acc": -0.0612, "final_rank": 11 }, { "submission_id": "aoj_0603_4147739", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid chmax(int &a, int b){\n a = max(a,b);\n}\n\nbool solve(){\n int n;\n cin >> n;\n vector<int> a(n);\n for(int i=0;i<n;i++){\n cin >> a[i];\n }\n vector<vector<int> > dp(n, vector<int>(3, 1));\n int ans = 1;\n for(int i=1;i<n;i++){\n if(a[i-1]!=a[i]){\n dp[i][0] = dp[i-1][0]+1;\n chmax(dp[i][1], dp[i-1][1]+1);\n chmax(dp[i][2], dp[i-1][2]+1);\n }else{\n chmax(dp[i][1], dp[i-1][0]+1);\n chmax(dp[i][2], dp[i-1][1]+1);\n }\n for(int j=0;j<3;j++){\n chmax(ans, dp[i][j]);\n }\n }\n cout << ans << endl;\n return true;\n}\n\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8616, "score_of_the_acc": -0.3536, "final_rank": 17 }, { "submission_id": "aoj_0603_4040709", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\t\n#include<cmath>\n#include<map>\n#include<vector>\n#define int long long\nusing namespace std;\nmap<int, int>test;\nmap<int, int>uiop;\nsigned main() {\n\tint n, a, b = 0, c = 0, d = 0, ans = 0; cin >> n;\n\tfor (int h = 0; h < n; h++) {\n\t\tcin >> a;\n\t\tif (h != 0) {\n\t\t\tif (b == a) {\n\t\t\t\tuiop[d] = h - 1;\n\t\t\t\td++; c = 0;\n\t\t\t\ttest[d] = h;\n\t\t\t}\n\t\t}\n\t\tb = a;\n\t}\n\tuiop[d] = n - 1; d++;\n\t/*for (int h = 0; h < d; h++) {\n\t\tcout << test[h] << ' ' << uiop[h] << endl;\n\t}*/\n\tfor (int h = 0; h < d; h++) {\n\t\tans = max(ans, uiop[h] - test[h - 2] + 1);\n\t\tans = max(ans, uiop[h + 2] - test[h] + 1);\n\t\tans = max(ans, uiop[h + 1] - test[h - 1] + 1);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 9348, "score_of_the_acc": -1.4023, "final_rank": 20 }, { "submission_id": "aoj_0603_4039491", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<string>\n#include<vector>\n#include<cmath>\n#define int long long\n#define mod 1000000007\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define mp make_pair\nusing namespace std;\nint n, a[123456], cnt;\nvector<int>v;\nsigned main() {\n\tcin >> n;\n\tfor0(i, n)cin >> a[i];\n\tcnt = 1;\n\tfor1(i, n - 1) {\n\t\tif (a[i - 1] == a[i]) {\n\t\t\tv.push_back(cnt);\n\t\t\tcnt = 1;\n\t\t}\n\t\telse cnt++;\n\t}\n\tv.push_back(cnt);\n\tif (v.size() <= 2)cout << n << endl;\n\telse {\n\t\tint ans = 0;\n\t\tfor (int i = 2; i < v.size(); i++) ans = max(ans, v[i - 2] + v[i - 1] + v[i]);\n\t\tcout << ans << endl;\n\t}\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4216, "score_of_the_acc": -0.0607, "final_rank": 10 }, { "submission_id": "aoj_0603_3999980", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n#include<random>\n#include<functional>\n#include<utility>\n\ntypedef long long ll;\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define pb push_back\n#define P pair<int, int>\n#define PLI pair<ll, int>\n#define PLL pair<ll, ll>\n#define VI vector<int>\n#define VII vector<VI>\n\nusing namespace std;\n\n\nint N;\nint light[100005];\nint dp[3][100005] = {};\nint main() {\n\tcin >> N;\n\trep(i, N) cin >> light[i];\n\tfor (int i = 1; i < N; i++) {\n\t\tif (light[i - 1] != light[i]) {\n\t\t\tdp[0][i] = dp[0][i - 1] + 1;\n\t\t\tdp[1][i] = dp[1][i - 1] + 1;\n\t\t\tdp[2][i] = dp[2][i - 1] + 1;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tdp[1][i] = dp[0][i - 1] + 1;\n\t\t\tdp[2][i] = dp[1][i - 1] + 1;\n\t\t}\n\t}\n\tint ans = 0;\n\trep(i, 3)rep(j, N) ans = max(ans, dp[i][j]);\n\tcout << ans+1 << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4660, "score_of_the_acc": -0.0903, "final_rank": 14 }, { "submission_id": "aoj_0603_3917537", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <string>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <cmath>\n#include <cstdio>\nusing namespace std;\n#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)\n#define FOR(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define All(v) (v).begin(),(v).end()\ntypedef long long ll;\n\nint main(){\n int N;\n cin >> N;\n vector<int> A(N);\n rep(i,N)cin >> A[i];\n vector<int> nums;\n int cnt = 0;\n rep(i,N){\n cnt++;\n if(A[i]==A[i+1]){\n nums.push_back(cnt);\n cnt=0;\n }\n }\n nums.push_back(cnt);\n int res = 0;\n for(int i=0;i+2<nums.size();i++){\n res = max(res,nums[i]+nums[i+1]+nums[i+2]);\n }\n if(nums.size()<3){\n rep(i,nums.size())res+=nums[i];\n }\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3556, "score_of_the_acc": -0.0168, "final_rank": 3 }, { "submission_id": "aoj_0603_3792384", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\nconst long double PI = acos(-1);\nconstexpr long double EPS = 1e-15;\nconstexpr int inf = 2e9;\nconstexpr ll INF = 2e18;\nconstexpr ll MOD = 1e9+7;\nconstexpr ll MOD1 = 998244353;\ntypedef pair<ll,ll> P;\n\n//#define all(v) (v).begin(), (v).end()\n#define rep(i,a,b) for (int i = (a); i < (b); i++)\n#define REP(i,n) rep(i,0,n)\n#define sz(s) (s).size()\n#define pb push_back\n#define fi first\n#define se second\n//#define mp make_pair\n\nint n, m, a[112345];\n\nint main(){\n cin >> n;\n --n;\n int prev;\n cin >> prev;\n REP(i, n){\n int tmp;\n cin >> tmp;\n if(prev == tmp){\n ++m;\n }else{\n ++a[m];\n }\n prev = tmp;\n }\n /*\n cout << m << endl;\n REP(i, m){\n cout << a[i] << \" \";\n }\n */\n int ans = 0;\n REP(i, m + 1) ans = max(ans, a[i] + 1);\n REP(i, m) ans = max(ans, a[i] + a[i + 1] + 2);\n REP(i, m - 1) ans = max(ans, a[i] + a[i + 1] + a[i + 2] + 3);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3304, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0603_3757512", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\nusing namespace std;\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n);\n for(int i = 0; i < n; i++) cin >> a[i];\n vector<vector<int>> dp(n, vector<int>(3, 1));\n int ans = 0;\n for(int i = 1; i < n; i++){\n dp[i][0] = a[i]!=a[i-1] ? dp[i-1][0]+1 : 1;\n dp[i][1] = a[i]!=a[i-1] ? dp[i-1][1]+1 : dp[i-1][0]+1;\n dp[i][2] = a[i]!=a[i-1] ? dp[i-1][2]+1 : dp[i-1][1]+1;\n ans = max({ans, dp[i][0], dp[i][1], dp[i][2]});\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8684, "score_of_the_acc": -0.3581, "final_rank": 18 }, { "submission_id": "aoj_0603_3616041", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<cctype>\n#include<math.h>\n#include<string>\n#include<string.h>\n#include<stack>\n#include<queue>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<stdlib.h>\n#include<iomanip>\n\nusing namespace std;\n\n#define ll long long\n#define ld long double\n#define EPS 0.0000000001\n#define INF 1e9\n#define LINF (ll)INF*INF\n#define MOD 1000000007\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define loop(i,a,n) for(int i=a;i<(n);i++)\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\n\n#define int ll //!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vp;\n\nint gcd(int a, int b){\n if(b==0) return a;\n return gcd(b,a%b);\n}\nint lcm(int a, int b){\n return a/gcd(a,b)*b;\n}\n\n\nsigned main(void) {\n int n;\n cin >> n;\n vi a(n);\n rep(i,n)cin >> a[i];\n vi v;\n int l = 0;\n rep(r,n-1){\n if(a[r] == a[r+1]){\n v.push_back(r+1-l);\n l = r+1;\n }\n }\n v.push_back(n-l);\n //rep(i,v.size())cout << \" \" << v[i];cout << endl;\n n = v.size();\n if(n == 1)cout << v[0] << endl;\n if(n == 2)cout << v[0] + v[1] << endl;\n if(n >= 3){\n int ans = 0;\n rep(i,n-2)ans = max(ans, v[i]+v[i+1]+v[i+2]);\n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4224, "score_of_the_acc": -0.0612, "final_rank": 11 }, { "submission_id": "aoj_0603_3528388", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n\nusing namespace std;\n\n\nint N;\nint l[100001];\nint dp[100001][3] = {};\n\nint main() {\n\n\tcin >> N;\n\tfor (int i = 1; i <= N; i++) {\n\t\tcin >> l[i];\n\t}\n\n\tdp[1][0] = 1;\n\tdp[1][1] = 1;\n\tdp[1][2] = 1;\n\n\tfor (int i = 2; i <= N; i++) {\n\t\tif (l[i] != l[i-1]) {\n\t\t\tdp[i][0] = dp[i - 1][0] + 1;\n\t\t\tdp[i][1] = dp[i - 1][1] + 1;\n\t\t\tdp[i][2] = dp[i - 1][2] + 1;\n\t\t}\n\t\telse {\n\t\t\tdp[i][0] = 1;\n\t\t\tdp[i][1] = dp[i - 1][0] + 1;\n\t\t\tdp[i][2] = dp[i - 1][1] + 1;\n\t\t}\n\t}\n\n\tint ans = 0;\n\tfor (int i = 2; i <= N; i++) {\n\t\tfor (int j = 0; j < 3; j++) {\n\t\t\tans = max(ans, dp[i][j]);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4652, "score_of_the_acc": -0.0897, "final_rank": 13 }, { "submission_id": "aoj_0603_3458879", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n\n#define REP(i,n) for(long long i = 0; i < (n); i++)\n#define FOR(i, m, n) for(long long i = (m);i < (n); ++i)\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SPEED cin.tie(0);ios::sync_with_stdio(false);\n\n\ntemplate<class T> using V = vector<T>;\ntemplate<class T, class U> using P = pair<T, U>;\n\nconst ll MOD = (ll)1e9 + 7;\nconst ll MOD2 = 998244353;\nconst ll HIGHINF = (ll)1e18;\nconst ll LOWINF = (ll)1e15;\nconst long double PI = 3.1415926535897932384626433;\n\ntemplate <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << \"{\"; for (auto &x : obj) o << \" {\" << x.first << \" : \" << x.second << \"}\" << \",\"; o << \" }\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << \"{\"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? \", \" : \"\") << obj[i]; o << \"}\"; return o;}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << \"{\" << obj.first << \", \" << obj.second << \"}\"; return o;}\ntemplate <template <class tmp> class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\nvoid print(void) {cout << endl;}\ntemplate <class Head> void print(Head&& head) {cout << head;print();}\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << \" \";print(forward<Tail>(tail)...);}\ntemplate <class T> void chmax(T& a, const T b){a=max<T>(a,b);}\ntemplate <class T> void chmin(T& a, const T b){a=min<T>(a,b);}\nvoid YN(bool flg) {cout << ((flg) ? \"YES\" : \"NO\") << endl;}\nvoid Yn(bool flg) {cout << ((flg) ? \"Yes\" : \"No\") << endl;}\nvoid yn(bool flg) {cout << ((flg) ? \"yes\" : \"no\") << endl;}\n\nint main() {\n\tint N; cin >> N;\n\tV<int> a(N),b;\n\tREP(i,N) cin >> a[i];\n\tfor(int i = 0; i < N; ++i){\n\t\tint cnt = 0;\n\t\tint j;\n\t\tfor(j = i+1; j < N; ++j){\n\t\t\tif(a[j-1]==a[j]) break;\n\t\t}\n\t\tb.push_back(j-i);\n\t\ti = j-1;\n\t}\n\tcorner(b.size()<=3,accumulate(ALL(b),0));\n\tint ans = 0;\n\tfor(int i = 1; i + 1 < b.size(); ++i) chmax(ans,b[i-1]+b[i]+b[i+1]);\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3584, "score_of_the_acc": -0.0186, "final_rank": 4 } ]
aoj_0607_cpp
バブルソート(Bubble Sort) バブルソートとは,列をソートするアルゴリズムの 1 つである.長さ N の数列 A を昇順にソートしたいとしよう.バブルソートは,隣り合う 2 つの数で大小関係が崩れているものがあれば,それらの位置を交換する.これを,数列を前から順に走査しながら行う.すなわち, A i > A i+1 となっている場所があれば,その 2 数を交換するということを, i = 1, 2, ... , N − 1 に対してこの順で行うのが 1 回の走査である.この走査を N − 1 回繰り返すことで,数列を昇順にソートできることが知られている. 数列 A のバブルソートによる交換回数とは,数列 A に上記のアルゴリズムを適用した時に,整数の交換が行われる回数である.(バブルソートとして知られるアルゴリズム及び実装には,ループの順番や範囲,及び終了条件など,細かな差異がある場合がある.ただし,同じ数列に適用した際の整数の交換回数はそれらの差異により変化しないことが知られている.) 例えば,以下のプログラムは長さ n の整数の配列 a をバブルソートによりソートする関数を C 言語で記述したものである. void bubble_sort(int *a, int n) { int i, j; for (i = 0; i < n - 1; ++i) { for (j = 0; j < n - 1; ++j) { if (a[j] > a[j + 1]) { /* 以下3 行が1 回の整数の交換に相当*/ int x = a[j]; a[j] = a[j + 1]; a[j + 1] = x; } } } } 課題 長さ N の数列 A が与えられる.数列 A の任意の場所の 2 つの整数を 1 回だけ交換した数列 A' を作るとする.数列 A' のバブルソートによる交換回数の最小値を求めるプログラムを作成せよ.(最初に交換する2つの整数は必ずしも隣り合っている必要はないことに注意せよ.) 制限 1 ≤ N ≤ 100 000      数列 A の長さ 1 ≤ A i ≤ 1 000 000 000     数列 A に含まれる数字の大きさ 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 N が書かれている. N は数列 A の長さを表す. 続く N 行のうちの i 行目(1 ≤ i ≤ N ) には,整数 A i が書かれている.これは数列 A の i 番目の整数を表す. 出力 標準出力に,数列 A' のバブルソートによる交換回数の最小値を表す整数を 1 行で出力せよ. 採点基準 採点用データのうち,配点の10%分については, N ≤ 1 000 を満たし,任意の i, j (1 ≤ i < j ≤ N ) について A i ≠ A j を満たす. 採点用データのうち,配点の30%分については, N ≤ 5 000 を満たし,任意の i, j (1 ≤ i < j ≤ N ) について A i ≠ A j を満たす. 採点用データのうち,配点の80%分については,任意の i, j (1 ≤ i < j ≤ N ) について A i ≠ A j を満たす. 入出力例 入力例 1 5 10 3 6 8 1 出力例 1 0 数列 A の最初の 10 と最後の 1 を交換することにすると,数列 A' はソート済みの列となり,バブルソートの交換回数は 0 となる. 入力例 2 5 3 1 7 9 5 出力例 2 2 数列 A の 3 番目の 7 と最後の 5 を交換することで,数列 A' は 3,1,5,9,7 となる. A' のバブルソートによる交換回数は 2 である. 入力例 3 3 1 2 3 出力例 3 1 最初から数列 A がソートされている場合でも,数列 A' を作る際に交換を行わなければならない. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0607_9488119", "code_snippet": "#include <cstdio>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\n// 配列のサイズと配列データ\nint b[110000];\nint z[110000];\nlong long bit[110000];\n\n// BIT (Binary Indexed Tree) の範囲和を計算する関数\nlong long sum(int a, int b) {\n if(a) return sum(0, b) - sum(0, a-1);\n long long ret = 0;\n for(; b >= 0; b = (b & (b + 1)) - 1) ret += bit[b];\n return ret;\n}\n\n// BIT (Binary Indexed Tree) に値を追加する関数\nvoid add(int a, int b) {\n for(; a < 110000; a |= a + 1) bit[a] += b;\n}\n\n// セグメントツリー用の配列\nint segtree[262144];\nint lx[110000];\nint ly[110000];\nint rx[110000];\nint ry[110000];\n\n// セグメントツリーに範囲を指定して値を追加する関数\nvoid add2(int a, int b, int c, int d, int e, int f) {\n if(d < a || b < c) return;\n if(c <= a && b <= d) {\n segtree[e] += f;\n } else {\n add2(a, (a + b) / 2, c, d, e * 2, f);\n add2((a + b) / 2 + 1, b, c, d, e * 2 + 1, f);\n }\n if(e > 1 && ((segtree[e] != 0 && segtree[e ^ 1] != 0) || segtree[e] > 0 || segtree[e ^ 1] > 0)) {\n int t = max(segtree[e], segtree[e ^ 1]);\n segtree[e / 2] += t;\n segtree[e ^ 1] -= t;\n segtree[e] -= t;\n }\n}\n\n// セグメントツリーに範囲を指定して最大値を取得する関数\nint query(int a, int b, int c, int d, int e, int f) {\n if(d < a || b < c) return -99999999;\n if(c <= a && b <= d) return segtree[e] + f;\n return max(query(a, (a + b) / 2, c, d, e * 2, f + segtree[e]), query((a + b) / 2 + 1, b, c, d, e * 2 + 1, f + segtree[e]));\n}\n\nint L[110000];\nint R[110000];\npair<int, int> yp[110000];\n\nint main() {\n int a;\n scanf(\"%d\", &a);\n for(int i = 0; i < a; i++) scanf(\"%d\", b + i);\n\n bool chk = true;\n bool same = false;\n for(int i = 0; i < a - 1; i++) if(b[i] < b[i - 1]) chk = false;\n for(int i = 0; i < a - 1; i++) if(b[i] == b[i - 1]) same = true;\n if(chk) {\n if(same) printf(\"0\\n\");\n else printf(\"1\\n\");\n return 0;\n }\n\n for(int i = 0; i < a; i++) {\n z[i] = b[i];\n yp[i] = make_pair(b[i], i);\n }\n std::sort(yp, yp + a);\n std::sort(z, z + a);\n long long ans = 0;\n for(int i = 0; i < a; i++) {\n int at = lower_bound(z, z + a, b[i]) - z;\n if(at < a - 1) ans += sum(at + 1, a - 1);\n add(at, 1);\n }\n\n int tmp = 0;\n int ls = 0;\n int rs = 0;\n for(int i = 0; i < a; i++) {\n if(tmp < b[i]) {\n L[i] = 1;\n tmp = b[i];\n lx[ls] = i;\n ly[ls++] = tmp;\n }\n }\n\n tmp = 1000000007;\n for(int i = a - 1; i >= 0; i--) {\n if(tmp > b[i] && L[i] == 0) {\n R[i] = 1;\n tmp = b[i];\n }\n }\n\n for(int i = 0; i < a; i++) {\n if(R[i]) {\n rx[rs] = i;\n ry[rs++] = b[i];\n }\n }\n\n int ret = 0;\n int rm = 0;\n int ypat = 0;\n for(int i = 0; i < a; i++) {\n if(R[i]) {\n int nx = b[i];\n int tmp = 0;\n while(ypat < a && yp[ypat].first < nx) {\n int ind = yp[ypat].second;\n if(!L[ind] && !R[ind]) {\n int to = lower_bound(ly, ly + ls, b[ind]) - ly;\n int rim = lower_bound(lx, lx + ls, ind) - lx - 1;\n if(to <= rim) add2(0, 131071, to, rim, 1, -1);\n if(b[ind] == ly[to]) to++;\n if(to <= rim) add2(0, 131071, to, rim, 1, -1);\n }\n ypat++;\n }\n int cp = ypat;\n while(cp < a && yp[cp].first == nx) {\n int ind = yp[cp].second;\n if(!L[ind] && !R[ind]) {\n int to = lower_bound(ly, ly + ls, b[ind]) - ly;\n int rim = lower_bound(lx, lx + ls, ind) - lx - 1;\n if(to <= rim) add2(0, 131071, to, rim, 1, -1);\n }\n cp++;\n }\n int at = lower_bound(lx, lx + ls, i) - lx - 1;\n int at2 = upper_bound(ly, ly + ls, b[i]) - ly;\n if(at2 <= at) {\n tmp = query(0, 131071, at2, at, 1, 0);\n ret = max(ret, tmp);\n }\n while(ypat < a && yp[ypat].first == nx) {\n int ind = yp[ypat].second;\n if(!L[ind] && !R[ind]) {\n int to = lower_bound(ly, ly + ls, b[ind]) - ly;\n int rim = lower_bound(lx, lx + ls, ind) - lx - 1;\n if(b[ind] == ly[to]) to++;\n if(to <= rim) add2(0, 131071, to, rim, 1, -1);\n }\n ypat++;\n }\n } else if(!L[i]) {\n int to = lower_bound(ly, ly + ls, b[i]) - ly;\n int rim = lower_bound(lx, lx + ls, i) - lx - 1;\n if(to <= rim) add2(0, 131071, to, rim, 1, 1);\n if(b[i] == ly[to]) to++;\n if(to <= rim) add2(0, 131071, to, rim, 1, 1);\n }\n }\n\n printf(\"%lld\\n\", ans - ret - 1);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8452, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0607_4801997", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename T> struct monoid {\n const T identity;\n const function<T(T, T)> combine;\n};\ntemplate <typename T, typename D> struct segtree {\n static constexpr int st_size(int size) { return (4 << __lg(size - 1)) - 1; }\n using Type = T;\n using DeltaType = D;\n const int size;\n const monoid<T> st_m;\n const monoid<D> delta_m;\n template <typename signature> using f = const function<signature>;\n f<T(T, D, int, int)> lazy_query;\n vector<T> st;\n vector<D> delta;\n vector<bool> is_lazy;\n int L(int p) { return (p << 1) + 1; }\n int R(int p) { return (p << 1) + 2; }\n int m(int s, int e) { return (s + e) >> 1; }\n void pull(int p, int s, int e) {\n st[p] = st_m.combine(get_val(L(p), s, m(s, e)), get_val(R(p), m(s, e), e));\n }\n void lazy(int p, D v) {\n delta[p] = delta_m.combine(delta[p], v), is_lazy[p] = true;\n }\n void unlazy(int p, int s, int e) {\n if(is_lazy[p]) {\n if(e - s > 1) lazy(L(p), delta[p]), lazy(R(p), delta[p]);\n delta[p] = delta_m.identity, is_lazy[p] = false;\n pull(p, s, e);\n }\n }\n T get_val(int p, int s, int e) {\n return is_lazy[p] ? lazy_query(st[p], delta[p], s, e) : st[p];\n }\n T build(const vector<T>& a, int p, int s, int e) {\n if(e - s > 1) {\n return st[p] = st_m.combine(build(a, L(p), s, m(s, e)), build(a, R(p), m(s, e), e));\n } else {\n return st[p] = a[s];\n }\n }\n segtree(const vector<T>& a, const monoid<T>& st_m, const monoid<D>& delta_m, f<T(T, D, int, int)>& lazy_query)\n : size(a.size()), st_m(st_m), delta_m(delta_m), lazy_query(lazy_query),\n st(st_size(size)), delta(st_size(size), delta_m.identity), is_lazy(st_size(size)) {\n build(a, 0, 0, size);\n }\n segtree(int size, const monoid<T>& st_m, const monoid<D>& delta_m, f<T(T, D, int, int)>& lazy_query)\n : segtree(vector<T>(size + 1, st_m.identity), st_m, delta_m, lazy_query) {}\n T query(int l, int r, int p, int s, int e) {\n if(l <= s and e <= r) {\n return get_val(p, s, e);\n } else if(r <= s or e <= l) {\n return st_m.identity;\n } else {\n unlazy(p, s, e);\n return st_m.combine(query(l, r, L(p), s, m(s, e)), query(l, r, R(p), m(s, e), e));\n }\n }\n T query(int l, int r, bool inclusive) {\n assert(l <= r);\n return query(l, r + inclusive, 0, 0, size);\n }\n T query(int i) { return query(i, i, true); }\n void update(int l, int r, D v, int p, int s, int e) {\n if(l <= s and e <= r) {\n lazy(p, v);\n } else if(not (r <= s or e <= l)) {\n unlazy(p, s, e);\n update(l, r, v, L(p), s, m(s, e)), update(l, r, v, R(p), m(s, e), e);\n pull(p, s, e);\n }\n }\n void update(int l, int r, D v, bool inclusive) {\n assert(l <= r);\n update(l, r + inclusive, v, 0, 0, size);\n }\n void update(int i, D v) { update(i, i, v, true); }\n void reset() {\n fill(st.begin(), st.end(), st_m.identity);\n fill(delta.begin(), delta.end(), delta_m.identity);\n fill(is_lazy.begin(), is_lazy.end(), false);\n }\n friend ostream& operator<<(ostream& os, segtree& t) {\n os << \"[\";\n for(int i = 0; i <= t.size; i++) {\n if(i != 0) os << \", \";\n os << t.query(i);\n }\n return os << \"]\";\n }\n};\ntemplate <typename T> struct rmq_segtree : public segtree<T, T> {\n rmq_segtree(int size) : segtree<T, T>(\n size, \n {0, [](const T& x, const T& y) { return max(x, y); }}, \n {0, plus<T>()},\n [](const T& st, const T& delta, int, int) { return st + delta; }) {}\n};\n// NOTE: one-indexed\ntemplate <typename T> struct bit {\n const int n;\n vector<T> t;\n bit(int n) : n(n), t(n + 1) {}\n void add(int i, T value) {\n for(int j = i; j <= n; j += j & -j) {\n t[j] += value;\n }\n }\n T sum(int i) {\n T res = 0;\n for(int j = i; j > 0; j -= j & -j) {\n res += t[j];\n }\n return res;\n }\n T sum(int L, int R) {\n return sum(R) - sum(L - 1);\n }\n void clear() {\n fill(t.begin(), t.end(), 0);\n }\n friend ostream& operator<<(ostream& os, bit& t) {\n os << \"[\";\n for(int i = 1; i <= t.n; i++) {\n if(i != 1) os << \", \";\n os << t.sum(i, i);\n }\n return os << \"]\";\n }\n};\ntemplate <typename T> vector<T> compress(const vector<T>& a) {\n vector<T> vals = a;\n sort(vals.begin(), vals.end());\n vals.erase(unique(vals.begin(), vals.end()), vals.end());\n vector<T> compressed = a;\n for(T& val : compressed) {\n val = lower_bound(vals.begin(), vals.end(), val) - vals.begin() + 1;\n }\n return compressed;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n;\n cin >> n;\n vector<int> a(n);\n cin >> a;\n a = compress(a);\n bit<int> present_values(n);\n ll swaps = 0;\n for(int x : a) {\n swaps += present_values.sum(x + 1, n);\n present_values.add(x, 1);\n }\n present_values.clear();\n vector<int> is_top_left_candidate(n), is_bottom_right_candidate(n);\n for(int i = 0; i < n; i++) {\n is_top_left_candidate[i] = present_values.sum(a[i], n) == 0;\n present_values.add(a[i], 1);\n }\n present_values.clear();\n for(int i = n - 1; i >= 0; i--) {\n is_bottom_right_candidate[i] = present_values.sum(a[i]) == 0;\n present_values.add(a[i], 1);\n }\n present_values.clear();\n ll ans = swaps + (set<int>(a.begin(), a.end()).size() == n);\n rmq_segtree<int> top_left_contribution(n);\n vector<int> top_left_vals;\n multiset<tuple<int, int, int, int>> to_remove;\n for(int i = 0; i < n; i++) {\n if(is_bottom_right_candidate[i]) {\n int L = upper_bound(top_left_vals.begin(), top_left_vals.end(), a[i]) - top_left_vals.begin();\n if(L < top_left_vals.size()) {\n while(not to_remove.empty() and get<0>(*to_remove.begin()) < a[i]) {\n int aj, L_ge, L_gt, R;\n tie(aj, L_ge, L_gt, R) = *to_remove.begin();\n top_left_contribution.update(L_ge, R, -1, false);\n top_left_contribution.update(L_gt, R, -1, false);\n to_remove.erase(to_remove.begin());\n }\n for(auto it = to_remove.begin(); it != to_remove.end() and get<0>(*it) == a[i]; it++) {\n int aj, L_ge, L_gt, R;\n tie(aj, L_ge, L_gt, R) = *it;\n top_left_contribution.update(L_ge, R, -1, false);\n }\n ans = min(ans, swaps - top_left_contribution.query(L, n, false) - 1);\n for(auto it = to_remove.begin(); it != to_remove.end() and get<0>(*it) == a[i]; it++) {\n int aj, L_ge, L_gt, R;\n tie(aj, L_ge, L_gt, R) = *it;\n top_left_contribution.update(L_ge, R, +1, false);\n }\n }\n } else if(is_top_left_candidate[i]) {\n top_left_vals.push_back(a[i]);\n } else {\n int L_ge = lower_bound(top_left_vals.begin(), top_left_vals.end(), a[i]) - top_left_vals.begin();\n int L_gt = upper_bound(top_left_vals.begin(), top_left_vals.end(), a[i]) - top_left_vals.begin();\n top_left_contribution.update(L_ge, top_left_vals.size(), 1, false);\n top_left_contribution.update(L_gt, top_left_vals.size(), 1, false);\n to_remove.insert(make_tuple(a[i], L_ge, L_gt, top_left_vals.size()));\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 12968, "score_of_the_acc": -0.8895, "final_rank": 4 }, { "submission_id": "aoj_0607_4795751", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename T> struct monoid {\n const T identity;\n const function<T(T, T)> combine;\n};\ntemplate <typename T, typename D> struct segtree {\n static constexpr int st_size(int size) { return (4 << __lg(size - 1)) - 1; }\n using Type = T;\n using DeltaType = D;\n const int size;\n const monoid<T> st_m;\n const monoid<D> delta_m;\n template <typename signature> using f = const function<signature>;\n f<T(T, D, int, int)> lazy_query;\n vector<T> st;\n vector<D> delta;\n vector<bool> is_lazy;\n int L(int p) { return (p << 1) + 1; }\n int R(int p) { return (p << 1) + 2; }\n int m(int s, int e) { return (s + e) >> 1; }\n void pull(int p, int s, int e) {\n st[p] = st_m.combine(get_val(L(p), s, m(s, e)), get_val(R(p), m(s, e), e));\n }\n void lazy(int p, D v) {\n delta[p] = delta_m.combine(delta[p], v), is_lazy[p] = true;\n }\n void unlazy(int p, int s, int e) {\n if(is_lazy[p]) {\n if(e - s > 1) lazy(L(p), delta[p]), lazy(R(p), delta[p]);\n delta[p] = delta_m.identity, is_lazy[p] = false;\n pull(p, s, e);\n }\n }\n T get_val(int p, int s, int e) {\n return is_lazy[p] ? lazy_query(st[p], delta[p], s, e) : st[p];\n }\n T build(const vector<T>& a, int p, int s, int e) {\n if(e - s > 1) {\n return st[p] = st_m.combine(build(a, L(p), s, m(s, e)), build(a, R(p), m(s, e), e));\n } else {\n return st[p] = a[s];\n }\n }\n segtree(const vector<T>& a, const monoid<T>& st_m, const monoid<D>& delta_m, f<T(T, D, int, int)>& lazy_query)\n : size(a.size()), st_m(st_m), delta_m(delta_m), lazy_query(lazy_query),\n st(st_size(size)), delta(st_size(size), delta_m.identity), is_lazy(st_size(size)) {\n build(a, 0, 0, size);\n }\n segtree(int size, const monoid<T>& st_m, const monoid<D>& delta_m, f<T(T, D, int, int)>& lazy_query)\n : segtree(vector<T>(size + 1, st_m.identity), st_m, delta_m, lazy_query) {}\n T query(int l, int r, int p, int s, int e) {\n if(l <= s and e <= r) {\n return get_val(p, s, e);\n } else if(r <= s or e <= l) {\n return st_m.identity;\n } else {\n unlazy(p, s, e);\n return st_m.combine(query(l, r, L(p), s, m(s, e)), query(l, r, R(p), m(s, e), e));\n }\n }\n T query(int l, int r, bool inclusive) {\n assert(l <= r);\n return query(l, r + inclusive, 0, 0, size);\n }\n T query(int i) { return query(i, i, true); }\n void update(int l, int r, D v, int p, int s, int e) {\n if(l <= s and e <= r) {\n lazy(p, v);\n } else if(not (r <= s or e <= l)) {\n unlazy(p, s, e);\n update(l, r, v, L(p), s, m(s, e)), update(l, r, v, R(p), m(s, e), e);\n pull(p, s, e);\n }\n }\n void update(int l, int r, D v, bool inclusive) {\n assert(l <= r);\n update(l, r + inclusive, v, 0, 0, size);\n }\n void update(int i, D v) { update(i, i, v, true); }\n void reset() {\n fill(st.begin(), st.end(), st_m.identity);\n fill(delta.begin(), delta.end(), delta_m.identity);\n fill(is_lazy.begin(), is_lazy.end(), false);\n }\n friend ostream& operator<<(ostream& os, segtree& t) {\n os << \"[\";\n for(int i = 0; i <= t.size; i++) {\n if(i != 0) os << \", \";\n os << t.query(i);\n }\n return os << \"]\";\n }\n};\ntemplate <typename T> struct rmq_segtree : public segtree<T, T> {\n rmq_segtree(int size) : segtree<T, T>(\n size, \n {0, [](const T& x, const T& y) { return max(x, y); }}, \n {0, plus<T>()},\n [](const T& st, const T& delta, int, int) { return st + delta; }) {}\n};\n// NOTE: one-indexed\ntemplate <typename T> struct bit {\n const int n;\n vector<T> t;\n bit(int n) : n(n), t(n + 1) {}\n void add(int i, T value) {\n for(int j = i; j <= n; j += j & -j) {\n t[j] += value;\n }\n }\n T sum(int i) {\n T res = 0;\n for(int j = i; j > 0; j -= j & -j) {\n res += t[j];\n }\n return res;\n }\n T sum(int L, int R) {\n return sum(R) - sum(L - 1);\n }\n void clear() {\n fill(t.begin(), t.end(), 0);\n }\n friend ostream& operator<<(ostream& os, bit& t) {\n os << \"[\";\n for(int i = 1; i <= t.n; i++) {\n if(i != 1) os << \", \";\n os << t.sum(i, i);\n }\n return os << \"]\";\n }\n};\ntemplate <typename T> vector<T> compress(const vector<T>& a) {\n vector<T> vals = a;\n sort(vals.begin(), vals.end());\n vals.erase(unique(vals.begin(), vals.end()), vals.end());\n vector<T> compressed = a;\n for(T& val : compressed) {\n val = lower_bound(vals.begin(), vals.end(), val) - vals.begin() + 1;\n }\n return compressed;\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n;\n cin >> n;\n vector<int> a(n);\n cin >> a;\n if(all_of(a.begin(), a.end(), [&](int x) { return x == a[0]; })) {\n cout << 0 << endl;\n } else {\n a = compress(a);\n bit<int> b(n), present_values(n);\n ll swaps = 0;\n for(int x : a) {\n swaps += b.sum(x + 1, n);\n b.add(x, 1);\n }\n vector<int> is_top_left_candidate(n), is_bottom_right_candidate(n);\n for(int i = 0; i < n; i++) {\n is_top_left_candidate[i] = present_values.sum(a[i] + 1, n) == 0;\n present_values.add(a[i], 1);\n }\n present_values.clear();\n for(int i = n - 1; i >= 0; i--) {\n is_bottom_right_candidate[i] = present_values.sum(a[i] - 1) == 0;\n present_values.add(a[i], 1);\n }\n present_values.clear();\n ll ans = swaps + (set<int>(a.begin(), a.end()).size() == n);\n rmq_segtree<int> top_left_contribution(n);\n vector<int> top_left_candidates_values;\n set<tuple<int, int, int>> to_remove;\n for(int i = 0; i < n; i++) {\n if(is_bottom_right_candidate[i]) {\n if(not top_left_candidates_values.empty()) {\n while(not to_remove.empty() and get<0>(*to_remove.begin()) < a[i]) {\n int aj, L, R;\n tie(aj, L, R) = *to_remove.begin();\n top_left_contribution.update(L, R, -1, false);\n to_remove.erase(to_remove.begin());\n }\n ans = min(ans, swaps - 2 * top_left_contribution.query(0, n, false) - 1);\n }\n } else if(is_top_left_candidate[i]) {\n top_left_candidates_values.push_back(a[i]);\n } else {\n int j = upper_bound(top_left_candidates_values.begin(), top_left_candidates_values.end(), a[i], [&](int aj, int x) {\n return aj < x;\n }) - top_left_candidates_values.begin();\n top_left_contribution.update(j, top_left_candidates_values.size(), 1, false);\n to_remove.insert(make_tuple(a[i], j, top_left_candidates_values.size()));\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 110, "memory_kb": 13188, "score_of_the_acc": -0.6908, "final_rank": 15 }, { "submission_id": "aoj_0607_4277210", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 100005\n\n\nstruct Info{\n\tInfo(){\n\n\t\tmid_index = 0;\n\t\tvalue = 0;\n\t}\n\tInfo(int arg_mid_index,ll arg_value){\n\t\tmid_index = arg_mid_index;\n\t\tvalue = arg_value;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn value > arg.value; //値の昇順(PQ)\n\t}\n\n\tint mid_index;\n\tll value;\n};\n\nll N;\nll A[SIZE],BIT[SIZE];\nll L_TOP[SIZE],MID[SIZE];\nll L[SIZE],R[SIZE],SAME_L_TOP[SIZE],count_table[SIZE];\nbool is_L_TOP[SIZE],is_R_BOTTOM[SIZE];\nvector<ll> V,R_BOTTOM;\nmap<ll,ll> MAP;\n\nll max_data[8*SIZE],add_data[8*SIZE];\nll seg_N = 1;\n\nvoid add(ll loc,ll value){\n\n\tBIT[loc] += value;\n\n\tloc += loc & -loc;\n\n\twhile(loc <= N){\n\t\tBIT[loc] += value;\n\t\tloc += loc & -loc;\n\t}\n}\n\nll getSum(ll loc){\n\n\tll sum = BIT[loc];\n\n\tloc -= loc & -loc;\n\n\twhile(loc > 0){\n\t\tsum += BIT[loc];\n\t\tloc -= loc & -loc;\n\t}\n\treturn sum;\n}\n\nll calc(ll left,ll right){\n\treturn getSum(right)-getSum(left-1);\n}\n\n\n//RAQ and RMQ\nvoid init(ll first_N){\n\twhile(seg_N < first_N)seg_N *= 2;\n}\n\n\nvoid add(int left,int right,ll value,int node_id,int node_left,int node_right){\n\n\tif(right < node_left || left > node_right){\n\t\t//範囲外ならreturn\n\t\treturn;\n\t}\n\telse if(left <= node_left && right >= node_right){ //このノードのカバーしている区間が、更新区間の部分区間である場合\n\n\t\tadd_data[node_id] += value; //一様に加える値を加算\n\n\t\twhile(node_id != 0){\n\n\t\t\tnode_id = (node_id-1)/2;\n\t\t\tmax_data[node_id] = max(max_data[2*node_id+1]+add_data[2*node_id+1],max_data[2*node_id+2]+add_data[2*node_id+2]);\n\t\t}\n\t}else{\n\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t}\n}\n\nll getMax(int left,int right,int node_id,int node_left,int node_right){\n\tif(right < node_left || left > node_right)return -BIG_NUM;\n\telse if(left <= node_left && right >= node_right){\n\t\treturn max_data[node_id]+add_data[node_id];\n\n\t}else{\n\n\t\tll left_max = getMax(left,right,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tll right_max = getMax(left,right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\treturn max(left_max,right_max)+add_data[node_id];\n\t}\n}\n\n\nint main(){\n\n\tscanf(\"%lld\",&N);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t\tV.push_back(A[i]);\n\t}\n\n\tsort(V.begin(),V.end());\n\tV.erase(unique(V.begin(),V.end()),V.end());\n\n\tfor(int i = 0; i < V.size(); i++){\n\n\t\tMAP[V[i]] = i;\n\t}\n\n\tfor(int i = 0; i <= V.size(); i++)BIT[i] = 0;\n\n\tll swap_count = 0;\n\n\tfor(ll i = 0; i < N; i++){\n\t\tswap_count += i-getSum(MAP[A[i]]+1);\n\t\tadd(MAP[A[i]]+1,1);\n\t}\n\n\tif(swap_count == 0){\n\n\t\tfor(int i = 1; i < N; i++){\n\t\t\tif(A[i-1] == A[i]){\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\n\tll maximum = -1;\n\tint index_L_TOP = 0;\n\n\t//左上候補点\n\tfor(int i = 0; i < N; i++){\n\n\t\tif(MAP[A[i]] > maximum){\n\n\t\t\tmaximum = MAP[A[i]];\n\t\t\tL_TOP[index_L_TOP++] = i;\n\t\t\tis_L_TOP[i] = true;\n\n\t\t}else{\n\n\t\t\tis_L_TOP[i] = false;\n\t\t}\n\t}\n\n\tll minimum = BIG_NUM;\n\n\tstack<int> tmp_R;\n\t//右下候補点\n\tfor(int i = N-1; i >= 0; i--){\n\n\t\tif(MAP[A[i]] < minimum){\n\t\t\tminimum = MAP[A[i]];\n\t\t\ttmp_R.push(i);\n\t\t\tis_R_BOTTOM[i] = true;\n\n\t\t}else{\n\n\t\t\tis_R_BOTTOM[i] = false;\n\t\t}\n\t}\n\twhile(!tmp_R.empty()){\n\n\t\tR_BOTTOM.push_back(tmp_R.top());\n\t\ttmp_R.pop();\n\t}\n\n\tint index_MID = 0;\n\tint left,right,mid;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tif(is_L_TOP[i] || is_R_BOTTOM[i])continue;\n\n\t\tMID[index_MID] = i;\n\n\t\t/*自分より左上にある点の範囲を求める*/\n\n\t\t//右端\n\t\tleft = 0,right = index_L_TOP-1,mid = (left+right)/2;\n\t\tR[index_MID] = -1;\n\n\t\twhile(left <= right){\n\n\t\t\tif(L_TOP[mid] < i){\n\n\t\t\t\tR[index_MID] = mid;\n\t\t\t\tleft = mid+1;\n\n\t\t\t}else{\n\n\t\t\t\tright = mid-1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\t//左端\n\t\tleft = 0,right = index_L_TOP-1,mid = (left+right)/2;\n\t\tL[index_MID] = N;\n\n\t\twhile(left <= right){\n\n\t\t\tif(A[L_TOP[mid]] > A[i]){\n\n\t\t\t\tL[index_MID] = mid;\n\t\t\t\tright = mid-1;\n\n\t\t\t}else{\n\n\t\t\t\tleft = mid+1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\t//自分と同じ数の、L_TOPがあるか調べる\n\t\tleft = 0,right = index_L_TOP-1,mid = (left+right)/2;\n\t\tSAME_L_TOP[index_MID] = -1;\n\n\t\twhile(left <= right){\n\n\t\t\tif(A[L_TOP[mid]] > A[i]){\n\n\t\t\t\tright = mid-1;\n\n\t\t\t}else if(A[L_TOP[mid]] == A[i]){\n\n\t\t\t\tSAME_L_TOP[index_MID] = mid;\n\t\t\t\tbreak;\n\n\t\t\t}else{\n\n\t\t\t\tleft = mid+1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\tindex_MID++;\n\t}\n\n\tinit(N);\n\n\tfor(ll i = 0; i <= 2*seg_N-2; i++){\n\t\tmax_data[i] = 0;\n\t\tadd_data[i] = 0;\n\t}\n\n\tll max_contain = 0;\n\tint tmp_index = 0;\n\n\tpriority_queue<Info> Q;\n\n\tint seg_L = 0,seg_R = index_L_TOP-1;\n\n\tfor(int i = 0; i <= V.size(); i++){\n\n\t\tcount_table[i] = 0; //数字の個数\n\t}\n\n\tll pre_bottom = -1;\n\tvector<Info> work;\n\n\tfor(int i = 0; i < R_BOTTOM.size(); i++){\n\n\t\tint r_bottom = R_BOTTOM[i];\n\n\t\t//自分未満になったMIDを出す\n\t\twhile(Q.empty() == false && Q.top().value < A[r_bottom]){\n\n\t\t\tif(L[Q.top().mid_index] <= R[Q.top().mid_index]){\n\n\t\t\t\tif(A[MID[Q.top().mid_index]] != pre_bottom){\n\n\t\t\t\t\tadd(L[Q.top().mid_index],R[Q.top().mid_index],-2,0,0,seg_N-1);\n\n\t\t\t\t}else{ //前回の下線に位置していた点の場合\n\n\t\t\t\t\tadd(L[Q.top().mid_index],R[Q.top().mid_index],-1,0,0,seg_N-1);\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\n\t\t//自分と同じ数があったら、2を加算しているので1を引く(左上とは交換する必要あるが右下とは不要なため)\n\t\twhile(Q.empty() == false && Q.top().value == A[r_bottom]){\n\n\t\t\tadd(L[Q.top().mid_index],R[Q.top().mid_index],-1,0,0,seg_N-1);\n\t\t\twork.push_back(Q.top());\n\t\t\tQ.pop();\n\t\t}\n\t\tfor(int k = 0; k < work.size(); k++){\n\n\t\t\tQ.push(work[k]);\n\t\t}\n\t\twork.clear();\n\n\t\t//自分以上になったMIDを入れる\n\t\twhile(tmp_index < index_MID && MID[tmp_index] < r_bottom){\n\n\t\t\tcount_table[MAP[A[MID[tmp_index]]]]++;\n\n\t\t\tif(A[MID[tmp_index]] > A[r_bottom]){\n\n\n\t\t\t\tif(L[tmp_index] <= R[tmp_index]){\n\n\t\t\t\t\tadd(L[tmp_index],R[tmp_index],2,0,0,seg_N-1);\n\t\t\t\t}\n\t\t\t\tif(SAME_L_TOP[tmp_index] != -1){ //自分より左に自分と同じ数があれば足す\n\n\t\t\t\t\tadd(SAME_L_TOP[tmp_index],SAME_L_TOP[tmp_index],1,0,0,seg_N-1);\n\t\t\t\t}\n\t\t\t\tQ.push(Info(tmp_index,A[MID[tmp_index]]));\n\n\t\t\t}else if(A[MID[tmp_index]] == A[r_bottom]){ //下線と同じ高さ\n\n\t\t\t\tif(L[tmp_index] <= R[tmp_index]){\n\n\t\t\t\t\tadd(L[tmp_index],R[tmp_index],1,0,0,seg_N-1);\n\t\t\t\t}\n\t\t\t\tQ.push(Info(tmp_index,A[MID[tmp_index]]));\n\t\t\t}\n\t\t\ttmp_index++;\n\t\t}\n\n\n\t\t//自分以下になった左上の点を抜く\n\t\twhile(seg_L < index_L_TOP && A[L_TOP[seg_L]] <= A[r_bottom])seg_L++;\n\n\t\tif(seg_L <= seg_R){\n\n\t\t\tll tmp_contain = getMax(seg_L,seg_R,0,0,seg_N-1)+1;\n\t\t\tmax_contain = max(max_contain,tmp_contain);\n\t\t}\n\n\t\tpre_bottom = A[r_bottom];\n\t}\n\n\tprintf(\"%lld\\n\",swap_count-max_contain);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 22648, "score_of_the_acc": -2, "final_rank": 7 }, { "submission_id": "aoj_0607_4276455", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 100005\n\n\nstruct Info{\n\tInfo(int arg_mid_index,ll arg_value){\n\t\tmid_index = arg_mid_index;\n\t\tvalue = arg_value;\n\t}\n\tbool operator<(const struct Info &arg) const{\n\n\t\treturn value > arg.value; //値の昇順(PQ)\n\t}\n\n\tint mid_index;\n\tll value;\n};\n\nll N;\nll A[SIZE],BIT[SIZE];\nll L_TOP[SIZE],MID[SIZE];\nll L[SIZE],R[SIZE];\nbool is_L_TOP[SIZE],is_R_BOTTOM[SIZE];\nvector<ll> V,R_BOTTOM;\nmap<ll,ll> MAP;\n\nll max_data[8*SIZE],add_data[8*SIZE];\nll seg_N = 1;\n\nvoid add(ll loc,ll value){\n\n\tBIT[loc] += value;\n\n\tloc += loc & -loc;\n\n\twhile(loc <= N){\n\t\tBIT[loc] += value;\n\t\tloc += loc & -loc;\n\t}\n}\n\nll getSum(ll loc){\n\n\tll sum = BIT[loc];\n\n\tloc -= loc & -loc;\n\n\twhile(loc > 0){\n\t\tsum += BIT[loc];\n\t\tloc -= loc & -loc;\n\t}\n\treturn sum;\n}\n\nll calc(ll left,ll right){\n\treturn getSum(right)-getSum(left-1);\n}\n\n\n//RAQ and RMQ\nvoid init(ll first_N){\n\twhile(seg_N < first_N)seg_N *= 2;\n}\n\n\nvoid add(int left,int right,ll value,int node_id,int node_left,int node_right){\n\n\tif(right < node_left || left > node_right){\n\t\t//範囲外ならreturn\n\t\treturn;\n\t}\n\telse if(left <= node_left && right >= node_right){ //このノードのカバーしている区間が、更新区間の部分区間である場合\n\n\t\tadd_data[node_id] += value; //一様に加える値を加算\n\n\t\twhile(node_id != 0){\n\n\t\t\tnode_id = (node_id-1)/2;\n\t\t\tmax_data[node_id] = max(max_data[2*node_id+1]+add_data[2*node_id+1],max_data[2*node_id+2]+add_data[2*node_id+2]);\n\t\t}\n\t}else{\n\n\t\tadd(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tadd(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t}\n}\n\nll getMax(int left,int right,int node_id,int node_left,int node_right){\n\tif(right < node_left || left > node_right)return -BIG_NUM;\n\telse if(left <= node_left && right >= node_right){\n\t\treturn max_data[node_id]+add_data[node_id];\n\n\t}else{\n\n\t\tll left_max = getMax(left,right,2*node_id+1,node_left,(node_left+node_right)/2);\n\t\tll right_max = getMax(left,right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\t\treturn max(left_max,right_max)+add_data[node_id];\n\t}\n}\n\n\nint main(){\n\n\tscanf(\"%d\",&N);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t\tV.push_back(A[i]);\n\t}\n\n\tsort(V.begin(),V.end());\n\tV.erase(unique(V.begin(),V.end()),V.end());\n\n\tfor(int i = 0; i < V.size(); i++){\n\n\t\tMAP[V[i]] = i;\n\t}\n\n\tfor(int i = 0; i <= V.size(); i++)BIT[i] = 0;\n\n\tll swap_count = 0;\n\n\tfor(ll i = 0; i < N; i++){\n\t\tswap_count += i-getSum(MAP[A[i]]+1);\n\t\tadd(MAP[A[i]]+1,1);\n\t}\n\n\tif(swap_count == 0){\n\n\t\tfor(int i = 1; i < N; i++){\n\t\t\tif(A[i-1] == A[i]){\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"1\\n\");\n\t\treturn 0;\n\t}\n\n\tll maximum = -1;\n\tint index_L_TOP = 0;\n\n\t//左上候補点\n\tfor(int i = 0; i < N; i++){\n\n\t\tif(MAP[A[i]] > maximum){\n\n\t\t\tmaximum = MAP[A[i]];\n\t\t\tL_TOP[index_L_TOP++] = i;\n\t\t\tis_L_TOP[i] = true;\n\n\t\t}else{\n\n\t\t\tis_L_TOP[i] = false;\n\t\t}\n\t}\n\n\tll minimum = BIG_NUM;\n\n\tstack<int> tmp_R;\n\t//右下候補点\n\tfor(int i = N-1; i >= 0; i--){\n\n\t\tif(MAP[A[i]] < minimum){\n\t\t\tminimum = MAP[A[i]];\n\t\t\ttmp_R.push(i);\n\t\t\tis_R_BOTTOM[i] = true;\n\n\t\t}else{\n\n\t\t\tis_R_BOTTOM[i] = false;\n\t\t}\n\t}\n\twhile(!tmp_R.empty()){\n\n\t\tR_BOTTOM.push_back(tmp_R.top());\n\t\ttmp_R.pop();\n\t}\n\n\tint index_MID = 0;\n\tint left,right,mid;\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tif(is_L_TOP[i] || is_R_BOTTOM[i])continue;\n\n\t\tMID[index_MID] = i;\n\n\t\t/*自分より左上にある点の範囲を求める*/\n\n\t\t//右端\n\t\tleft = 0,right = index_L_TOP-1,mid = (left+right)/2;\n\t\tR[index_MID] = -1;\n\n\t\twhile(left <= right){\n\n\t\t\tif(L_TOP[mid] < i){\n\n\t\t\t\tR[index_MID] = mid;\n\t\t\t\tleft = mid+1;\n\n\t\t\t}else{\n\n\t\t\t\tright = mid-1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\t//左端\n\t\tleft = 0,right = index_L_TOP-1,mid = (left+right)/2;\n\t\tL[index_MID] = N;\n\n\t\twhile(left <= right){\n\n\t\t\tif(A[L_TOP[mid]] > A[i]){\n\n\t\t\t\tL[index_MID] = mid;\n\t\t\t\tright = mid-1;\n\n\t\t\t}else{\n\n\t\t\t\tleft = mid+1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\t\tindex_MID++;\n\t}\n\n\tinit(N);\n\n\tfor(ll i = 0; i <= 2*seg_N-2; i++){\n\t\tmax_data[i] = 0;\n\t\tadd_data[i] = 0;\n\t}\n\n\tll max_contain = 0;\n\tint tmp_index = 0;\n\n\tpriority_queue<Info> Q;\n\n\tfor(int i = 0; i < R_BOTTOM.size(); i++){\n\n\t\tint r_bottom = R_BOTTOM[i];\n\n\t\t//自分より下になったMIDを出す\n\t\twhile(Q.empty() == false && Q.top().value < A[r_bottom]){\n\n\t\t\tif(L[Q.top().mid_index] <= R[Q.top().mid_index]){\n\n\t\t\t\tadd(L[Q.top().mid_index],R[Q.top().mid_index],-1,0,0,seg_N-1);\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t\t//自分より上になったMIDを入れる\n\t\twhile(tmp_index < index_MID && MID[tmp_index] < r_bottom){\n\n\t\t\tif(A[MID[tmp_index]] > A[r_bottom]){\n\n\t\t\t\tif(L[tmp_index] <= R[tmp_index]){\n\n\t\t\t\t\tadd(L[tmp_index],R[tmp_index],1,0,0,seg_N-1);\n\t\t\t\t}\n\t\t\t\tQ.push(Info(tmp_index,A[MID[tmp_index]]));\n\t\t\t}\n\t\t\ttmp_index++;\n\t\t}\n\n\t\tmax_contain = max(max_contain,getMax(0,seg_N-1,0,0,seg_N-1)); //最大含有区間を求める\n\t}\n\n\tprintf(\"%lld\\n\",swap_count-(2*max_contain+1));\n\n\treturn 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 160, "memory_kb": 21044, "score_of_the_acc": -1.6013, "final_rank": 16 }, { "submission_id": "aoj_0607_3095674", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\nusing namespace std;\ntypedef long long ll;\n#define N (1<<17)\nint n,m[N];\nvoid Zaats(){\n vector<int> v;\n lol(i,n)v.push_back(m[i]);\n sort(v.begin(),v.end());\n lol(i,n){\n\tm[i]=lower_bound(v.begin(),v.end(),m[i])-v.begin();\n }\n}\nvector<int> A,B,Y;\nvoid SetABY(){\n int maxi=-1;\n lol(i,n){\n\tif(maxi<m[i]){\n\t maxi=m[i];\n\t A.push_back(i);\n\t}\n }\n int mini=mod;\n for(int i=n-1;i>=0;i--){\n\tif(mini>m[i]){\n\t mini=m[i];\n\t B.push_back(i);\n\t}\n }\n sort(A.begin(),A.end());\n sort(B.begin(),B.end());\n vector<pair<int,int> >v;\n lol(i,n)v.push_back(make_pair(m[i],i));\n sort(v.begin(),v.end());\n lol(i,n)Y.push_back(v[i].second);\n}\nclass RAQxRMQ{\nprivate:\n ll dat[2*N],laz[2*N];\n void eval(int k){\n\tdat[k]+=laz[k];\n\tif(k<N-1){\n\t laz[k*2+1]+=laz[k];\n\t laz[k*2+2]+=laz[k];\n\t}\n\tlaz[k]=0;\n }\n void ufs(int l,int r,int a,int b,int k,ll x){\n\teval(k);\n\tif(l<=a&&b<=r){laz[k]+=x;eval(k);return;}\n\tif(b<=l||r<=a)return;\n\tufs(l,r,a,(a+b)/2,k*2+1,x);\n\tufs(l,r,(a+b)/2,b,k*2+2,x);\n\tdat[k]=max(dat[k*2+1],dat[k*2+2]);\n }\n ll dfs(int l,int r,int a,int b,int k){\n\teval(k);\n\tif(l<=a&&b<=r)return dat[k];\n\tif(b<=l||r<=a)return 0;\n\tll vl=dfs(l,r,a,(a+b)/2,k*2+1);\n\tll vr=dfs(l,r,(a+b)/2,b,k*2+2);\n\treturn max(vl,vr);\n }\npublic:\n void Init(){\n\tlol(i,2*N)dat[i]=laz[i]=0;\n }\n void Add(int l,int r,ll x){\n\tufs(l,r+1,0,N,0,x);\n }\n ll Max(int l,int r){\n\treturn dfs(l,r+1,0,N,0);\n }\n};\nclass RSQ{\nprivate:\n ll dat[2*N];\n ll dfs(int l,int r,int a,int b,int k){\n\tif(l<=a&&b<=r)return dat[k];\n\tif(b<=l||r<=a)return 0;\n\tll vl=dfs(l,r,a,(a+b)/2,k*2+1);\n\tll vr=dfs(l,r,(a+b)/2,b,k*2+2);\n\treturn vl+vr;\n }\npublic:\n void Init(){\n\tlol(i,2*N)dat[i]=0;\n }\n void Upd(int i,int x){\n\ti+=N-1,dat[i]=x;\n\twhile(i>0){\n\t i=(i-1)/2;\n\t dat[i]=dat[i*2+1]+dat[i*2+2];\n\t}\n }\n void Add(int i,int x){\n\tUpd(i,Sum(i,i)+x);\n }\n int Sum(int l,int r){\n\treturn dfs(l,r+1,0,N,0);\n }\n};\nll Tentou(){\n RSQ seg;seg.Init();\n ll res=0;\n lol(i,n){\n\tres+=seg.Sum(m[i]+1,n);\n\tseg.Add(m[i],1);\n }\n return res;\n}\nbool Topo(ll x1,ll y1,ll x2,ll y2){\n return (x1<x2&&y1>y2);\n}\nll L,R;\nvoid BNS(ll x,ll y){\n ll l,r,mid;\n l=-1,r=B.size();\n while(l<r-1){\n\tmid=(l+r)/2;\n\tif(B[mid]>x)r=mid;\n\telse l=mid;\n }\n L=r;\n l=-1,r=B.size();\n while(l<r-1){\n\tmid=(l+r)/2;\n\tif(m[B[mid]]<y)l=mid;\n\telse r=mid;\n }\n R=l;\n}\nint main(){\n cin>>n;\n lol(i,n)cin>>m[i];\n Zaats();\n SetABY();\n RAQxRMQ seg;seg.Init();\n ll ans=0,px=0,py1=0,py2=0,bx=-1,by=-1;\n lol(i,A.size()){\n\tll ax=A[i],ay=m[A[i]];\n\tfor(;px<n;px++){\n\t ll x=px,y=m[px];\n\t if(!(x<=ax))break;\n\t if(Topo(bx,by,x,y)){\n\t\tBNS(x,y+1);\n\t\tseg.Add(L,R,-1);\n\t }\n\t if(Topo(bx,by+1,x,y)){\n\t\tBNS(x,y);\n\t\tseg.Add(L,R,-1);\n\t }\n\t}\n\tfor(;py1<n;py1++){\n\t ll x=Y[py1],y=m[Y[py1]];\n\t if(!(y<ay))break;\n\t if(Topo(ax,ay,x,y)){\n\t\tBNS(x,y+1);\n\t\tseg.Add(L,R,1);\n\t }\n\t}\n\tfor(;py2<n;py2++){\n\t ll x=Y[py2],y=m[Y[py2]];\n\t if(!(y<=ay))break;\n\t if(Topo(ax,ay+1,x,y)){\n\t\tBNS(x,y);\n\t\tseg.Add(L,R,1);\n\t }\n\t}\n\tans=max(ans,seg.Max(0,B.size()-1));\n\tbx=ax,by=ay;\n }\n ll t=Tentou();\n if(t==0){\n\tbool same=false;\n\tlol(i,n-1)if(m[Y[i]]==m[Y[i+1]])same=true;\n\tcout<<1-same<<endl;\n }\n else cout<<t-1-ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 11176, "score_of_the_acc": -0.7633, "final_rank": 3 }, { "submission_id": "aoj_0607_2690272", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int64_t inf = 1001001001001001001ll;\n\ntemplate <typename T> class Compress {\nprivate:\n size_t sz;\n std::vector<T> zip;\n std::vector<int> formatted;\n\npublic:\n Compress(std::vector<T> &v) : formatted(v.size(), -1), sz(v.size()) {\n zip = v;\n std::sort(zip.begin(), zip.end());\n zip.erase(std::unique(zip.begin(), zip.end()), zip.end());\n for (int i = 0; i < formatted.size(); ++i) {\n formatted[i] = std::lower_bound(zip.begin(), zip.end(), v[i]) - zip.begin();\n }\n }\n\n int operator[](size_t idx) {\n return formatted[idx];\n }\n\n T unzip(size_t idx) {\n assert(idx < zip.size());\n return zip[idx];\n }\n\n std::vector<int> get() {\n return formatted;\n }\n\n size_t size() {\n return sz;\n }\n};\n\nstruct BinaryIndexedTree {\n BinaryIndexedTree(size_t n) : n(n), v(n + 1, 0) {}\n\n size_t n;\n vector<int64_t> v;\n\n int sum(int k) {\n int64_t ret = 0;\n for (; k; k -= k & -k) ret += v[k];\n return ret;\n }\n\n void add(int k, int x) {\n for (; k <= n; k += k & -k) v[k] += x;\n }\n};\n\nstruct Node {\n int64_t node, lazy;\n Node() {}\n Node(int64_t node, int64_t lazy) : node(node), lazy(lazy) {}\n\n Node operator*(const Node &r) const {\n return Node(max(node, r.node), -inf);\n }\n} e(0, -inf);\n\nstruct SegmentTree : Node {\n size_t n;\n vector<Node> seg;\n\n SegmentTree(size_t size) : n(1 << (32 - __builtin_clz(size - 1))), seg(2 * n - 1, e) {}\n\n inline void lazy_add(int k, int64_t x) {\n if (seg[k].lazy == -inf) {\n seg[k].lazy = 0;\n }\n seg[k].lazy += x;\n }\n\n inline void lazy_evaluate(int k) {\n if (seg[k].lazy != -inf) {\n seg[k].node += seg[k].lazy;\n if (k < n - 1) {\n lazy_add(2 * k + 1, seg[k].lazy);\n lazy_add(2 * k + 2, seg[k].lazy);\n }\n seg[k].lazy = -inf;\n }\n }\n\n inline void update_node(int k) {\n seg[k] = seg[2 * k + 1] * seg[2 * k + 2];\n }\n\n void add(int l, int r, int64_t x, int k, int a, int b) {\n lazy_evaluate(k);\n\n if (r <= a || b <= l) return;\n if (l <= a && b <= r) {\n lazy_add(k, x);\n lazy_evaluate(k);\n return;\n }\n\n add(l, r, x, 2 * k + 1, a, (a + b) / 2);\n add(l, r, x, 2 * k + 2, (a + b) / 2, b);\n update_node(k);\n }\n\n Node query(int l, int r, int k, int a, int b) {\n lazy_evaluate(k);\n if (r <= a || b <= l) return e;\n if (l <= a && b <= r) return seg[k];\n\n return query(l, r, 2 * k + 1, a, (a + b) / 2) * query(l, r, 2 * k + 2, (a + b) / 2, b);\n }\n\n void add(int l, int r, int64_t x) {\n // cerr << \"range [\" << l << \", \" << r << \") add to \" << x << endl;\n add(l, r, x, 0, 0, n);\n }\n\n int64_t query(int l, int r) {\n // cerr << \"range [\" << l << \", \" << r << \") query of \" << query(l, r, 0, 0, n).node << endl;\n return query(l, r, 0, 0, n).node;\n }\n\n void debug() {\n for (int i = 0; i < n; ++i) {\n cout << query(i, i + 1) << (i + 1 == n ? \"\\n\" : \" \");\n }\n }\n};\n\nsigned main() {\n int n;\n cin >> n;\n\n vector<int> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n\n Compress<int> zip(a);\n a = zip.get();\n\n int64_t inversion = 0;\n BinaryIndexedTree bit(n + 1);\n for (int64_t i = 0; i < n; ++i) {\n inversion += i - bit.sum(a[i] + 1);\n bit.add(a[i] + 1, 1);\n }\n\n // cerr << \"inversion : \" << inversion << endl;\n\n if (inversion == 0) {\n a.erase(unique(a.begin(), a.end()), a.end());\n\n cout << (a.size() == n) << endl;\n return 0;\n }\n\n int seg_size = 0, max_a = -1, min_a = 1001001001;\n vector<int> val, idx, top(n), bottom(n);\n for (int i = 0; i < n; ++i) {\n if (max_a < a[i]) {\n val.push_back(a[i]);\n idx.push_back(i);\n top[i] = 1;\n max_a = a[i];\n seg_size++;\n }\n }\n for (int i = n - 1; i >= 0; --i) {\n if (min_a > a[i]) {\n bottom[i] = 1;\n min_a = a[i];\n }\n }\n\n int64_t ans = inf;\n SegmentTree seg(seg_size);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;\n for (int i = 0; i < n; ++i) {\n if (!bottom[i]) {\n // cerr << i << \" is the other.\" << endl;\n if (*lower_bound(val.begin(), val.end(), a[i]) == a[i]) {\n int index = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n seg.add(index, index + 1, 1);\n }\n int l = lower_bound(val.begin(), val.end(), a[i] + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n seg.add(l, r, 2);\n pq.push(make_pair(a[i], i));\n }\n if (bottom[i]) {\n // cerr << i << \" is bottom.\" << endl;\n queue<pair<int, int>> q;\n while (!pq.empty() && pq.top().first <= a[i]) {\n pair<int, int> p = pq.top();\n pq.pop();\n\n if (a[i] == p.first) {\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -1);\n q.push(make_pair(l, r));\n continue;\n }\n\n if (*lower_bound(val.begin(), val.end(), p.first) == p.first) {\n int index = lower_bound(val.begin(), val.end(), p.first) - val.begin();\n seg.add(index, index + 1, -1);\n }\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -2);\n }\n\n int l = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n ans = min(ans, inversion - seg.query(l, r));\n\n while (!q.empty()) {\n seg.add(q.front().first, q.front().second, -1);\n q.pop();\n }\n }\n if (top[i]) {\n // cerr << i << \" is top.\" << endl;\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9408, "score_of_the_acc": -0.2816, "final_rank": 2 }, { "submission_id": "aoj_0607_2690266", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int64_t inf = 1001001001001001001ll;\n\ntemplate <typename T> class Compress {\nprivate:\n size_t sz;\n std::vector<T> zip;\n std::vector<int> formatted;\n\npublic:\n Compress(std::vector<T> &v) : formatted(v.size(), -1), sz(v.size()) {\n zip = v;\n std::sort(zip.begin(), zip.end());\n zip.erase(std::unique(zip.begin(), zip.end()), zip.end());\n for (int i = 0; i < formatted.size(); ++i) {\n formatted[i] = std::lower_bound(zip.begin(), zip.end(), v[i]) - zip.begin();\n }\n }\n\n int operator[](size_t idx) {\n return formatted[idx];\n }\n\n T unzip(size_t idx) {\n assert(idx < zip.size());\n return zip[idx];\n }\n\n std::vector<int> get() {\n return formatted;\n }\n\n size_t size() {\n return sz;\n }\n};\n\nstruct BinaryIndexedTree {\n BinaryIndexedTree(size_t n) : n(n), v(n + 1, 0) {}\n\n size_t n;\n vector<int64_t> v;\n\n int sum(int k) {\n int64_t ret = 0;\n for (; k; k -= k & -k) ret += v[k];\n return ret;\n }\n\n void add(int k, int x) {\n for (; k <= n; k += k & -k) v[k] += x;\n }\n};\n\nstruct Node {\n int64_t node, lazy;\n Node() {}\n Node(int64_t node, int64_t lazy) : node(node), lazy(lazy) {}\n\n Node operator*(const Node &r) const {\n return Node(max(node, r.node), -inf);\n }\n} e(0, -inf);\n\nstruct SegmentTree : Node {\n size_t n;\n vector<Node> seg;\n\n SegmentTree(size_t size) : n(1 << (32 - __builtin_clz(size - 1))), seg(2 * n - 1, e) {}\n\n inline void lazy_add(int k, int64_t x) {\n if (seg[k].lazy == -inf) {\n seg[k].lazy = 0;\n }\n seg[k].lazy += x;\n }\n\n inline void lazy_evaluate(int k) {\n if (seg[k].lazy != -inf) {\n seg[k].node += seg[k].lazy;\n if (k < n - 1) {\n lazy_add(2 * k + 1, seg[k].lazy);\n lazy_add(2 * k + 2, seg[k].lazy);\n }\n seg[k].lazy = -inf;\n }\n }\n\n inline void update_node(int k) {\n seg[k] = seg[2 * k + 1] * seg[2 * k + 2];\n }\n\n void add(int l, int r, int64_t x, int k, int a, int b) {\n lazy_evaluate(k);\n\n if (r <= a || b <= l) return;\n if (l <= a && b <= r) {\n lazy_add(k, x);\n lazy_evaluate(k);\n return;\n }\n\n add(l, r, x, 2 * k + 1, a, (a + b) / 2);\n add(l, r, x, 2 * k + 2, (a + b) / 2, b);\n update_node(k);\n }\n\n Node query(int l, int r, int k, int a, int b) {\n lazy_evaluate(k);\n if (r <= a || b <= l) return e;\n if (l <= a && b <= r) return seg[k];\n\n return query(l, r, 2 * k + 1, a, (a + b) / 2) * query(l, r, 2 * k + 2, (a + b) / 2, b);\n }\n\n void add(int l, int r, int64_t x) {\n // cerr << \"range [\" << l << \", \" << r << \") add to \" << x << endl;\n add(l, r, x, 0, 0, n);\n }\n\n int64_t query(int l, int r) {\n // cerr << \"range [\" << l << \", \" << r << \") query of \" << query(l, r, 0, 0, n).node << endl;\n return query(l, r, 0, 0, n).node;\n }\n\n void debug() {\n for (int i = 0; i < n; ++i) {\n cout << query(i, i + 1) << (i + 1 == n ? \"\\n\" : \" \");\n }\n }\n};\n\nsigned main() {\n int n;\n cin >> n;\n\n vector<int> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n\n Compress<int> zip(a);\n a = zip.get();\n\n int64_t inversion = 0;\n BinaryIndexedTree bit(n + 1);\n for (int64_t i = 0; i < n; ++i) {\n inversion += i - bit.sum(a[i] + 1);\n bit.add(a[i] + 1, 1);\n }\n\n // cerr << \"inversion : \" << inversion << endl;\n\n if (inversion == 0) {\n if (*max_element(a.begin(), a.end())) {\n cout << 1 << endl;\n } else {\n cout << 0 << endl;\n }\n return 0;\n }\n\n int seg_size = 0, max_a = -1, min_a = 1001001001;\n vector<int> val, idx, top(n), bottom(n);\n for (int i = 0; i < n; ++i) {\n if (max_a < a[i]) {\n val.push_back(a[i]);\n idx.push_back(i);\n top[i] = 1;\n max_a = a[i];\n seg_size++;\n }\n }\n for (int i = n - 1; i >= 0; --i) {\n if (min_a > a[i]) {\n bottom[i] = 1;\n min_a = a[i];\n }\n }\n\n int64_t ans = inf;\n SegmentTree seg(seg_size);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;\n for (int i = 0; i < n; ++i) {\n if (!bottom[i]) {\n // cerr << i << \" is the other.\" << endl;\n if (*lower_bound(val.begin(), val.end(), a[i]) == a[i]) {\n int index = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n seg.add(index, index + 1, 1);\n }\n int l = lower_bound(val.begin(), val.end(), a[i] + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n seg.add(l, r, 2);\n pq.push(make_pair(a[i], i));\n }\n if (bottom[i]) {\n // cerr << i << \" is bottom.\" << endl;\n queue<pair<int, int>> q;\n while (!pq.empty() && pq.top().first <= a[i]) {\n pair<int, int> p = pq.top();\n pq.pop();\n\n if (a[i] == p.first) {\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -1);\n q.push(make_pair(l, r));\n continue;\n }\n\n if (*lower_bound(val.begin(), val.end(), p.first) == p.first) {\n int index = lower_bound(val.begin(), val.end(), p.first) - val.begin();\n seg.add(index, index + 1, -1);\n }\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -2);\n }\n\n int l = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n ans = min(ans, inversion - seg.query(l, r));\n\n while (!q.empty()) {\n seg.add(q.front().first, q.front().second, -1);\n q.pop();\n }\n }\n if (top[i]) {\n // cerr << i << \" is top.\" << endl;\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 0.9813084112149533, "time_ms": 90, "memory_kb": 9460, "score_of_the_acc": -0.2853, "final_rank": 8 }, { "submission_id": "aoj_0607_2690264", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int64_t inf = 1001001001001001001ll;\n\ntemplate <typename T> class Compress {\nprivate:\n size_t sz;\n std::vector<T> zip;\n std::vector<int> formatted;\n\npublic:\n Compress(std::vector<T> &v) : formatted(v.size(), -1), sz(v.size()) {\n zip = v;\n std::sort(zip.begin(), zip.end());\n zip.erase(std::unique(zip.begin(), zip.end()), zip.end());\n for (int i = 0; i < formatted.size(); ++i) {\n formatted[i] = std::lower_bound(zip.begin(), zip.end(), v[i]) - zip.begin();\n }\n }\n\n int operator[](size_t idx) {\n return formatted[idx];\n }\n\n T unzip(size_t idx) {\n assert(idx < zip.size());\n return zip[idx];\n }\n\n std::vector<int> get() {\n return formatted;\n }\n\n size_t size() {\n return sz;\n }\n};\n\nstruct BinaryIndexedTree {\n BinaryIndexedTree(size_t n) : n(n), v(n + 1, 0) {}\n\n size_t n;\n vector<int64_t> v;\n\n int sum(int k) {\n int64_t ret = 0;\n for (; k; k -= k & -k) ret += v[k];\n return ret;\n }\n\n void add(int k, int x) {\n for (; k <= n; k += k & -k) v[k] += x;\n }\n};\n\nstruct Node {\n int64_t node, lazy;\n Node() {}\n Node(int64_t node, int64_t lazy) : node(node), lazy(lazy) {}\n\n Node operator*(const Node &r) const {\n return Node(max(node, r.node), -inf);\n }\n} e(0, -inf);\n\nstruct SegmentTree : Node {\n size_t n;\n vector<Node> seg;\n\n SegmentTree(size_t size) : n(1 << (32 - __builtin_clz(size - 1))), seg(2 * n - 1, e) {}\n\n inline void lazy_add(int k, int64_t x) {\n if (seg[k].lazy == -inf) {\n seg[k].lazy = 0;\n }\n seg[k].lazy += x;\n }\n\n inline void lazy_evaluate(int k) {\n if (seg[k].lazy != -inf) {\n seg[k].node += seg[k].lazy;\n if (k < n - 1) {\n lazy_add(2 * k + 1, seg[k].lazy);\n lazy_add(2 * k + 2, seg[k].lazy);\n }\n seg[k].lazy = -inf;\n }\n }\n\n inline void update_node(int k) {\n seg[k] = seg[2 * k + 1] * seg[2 * k + 2];\n }\n\n void add(int l, int r, int64_t x, int k, int a, int b) {\n lazy_evaluate(k);\n\n if (r <= a || b <= l) return;\n if (l <= a && b <= r) {\n lazy_add(k, x);\n lazy_evaluate(k);\n return;\n }\n\n add(l, r, x, 2 * k + 1, a, (a + b) / 2);\n add(l, r, x, 2 * k + 2, (a + b) / 2, b);\n update_node(k);\n }\n\n Node query(int l, int r, int k, int a, int b) {\n lazy_evaluate(k);\n if (r <= a || b <= l) return e;\n if (l <= a && b <= r) return seg[k];\n\n return query(l, r, 2 * k + 1, a, (a + b) / 2) * query(l, r, 2 * k + 2, (a + b) / 2, b);\n }\n\n void add(int l, int r, int64_t x) {\n // cerr << \"range [\" << l << \", \" << r << \") add to \" << x << endl;\n add(l, r, x, 0, 0, n);\n }\n\n int64_t query(int l, int r) {\n // cerr << \"range [\" << l << \", \" << r << \") query of \" << query(l, r, 0, 0, n).node << endl;\n return query(l, r, 0, 0, n).node;\n }\n\n void debug() {\n for (int i = 0; i < n; ++i) {\n cout << query(i, i + 1) << (i + 1 == n ? \"\\n\" : \" \");\n }\n }\n};\n\nsigned main() {\n int n;\n cin >> n;\n\n vector<int> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n\n Compress<int> zip(a);\n a = zip.get();\n\n int64_t inversion = 0;\n BinaryIndexedTree bit(n + 1);\n for (int64_t i = 0; i < n; ++i) {\n inversion += i - bit.sum(a[i] + 1);\n bit.add(a[i] + 1, 1);\n }\n\n // cerr << \"inversion : \" << inversion << endl;\n\n if (inversion == 0) {\n cout << 1 << endl;\n return 0;\n }\n\n int seg_size = 0, max_a = -1, min_a = 1001001001;\n vector<int> val, idx, top(n), bottom(n);\n for (int i = 0; i < n; ++i) {\n if (max_a < a[i]) {\n val.push_back(a[i]);\n idx.push_back(i);\n top[i] = 1;\n max_a = a[i];\n seg_size++;\n }\n }\n for (int i = n - 1; i >= 0; --i) {\n if (min_a > a[i]) {\n bottom[i] = 1;\n min_a = a[i];\n }\n }\n\n int64_t ans = inf;\n SegmentTree seg(seg_size);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;\n for (int i = 0; i < n; ++i) {\n if (!bottom[i]) {\n // cerr << i << \" is the other.\" << endl;\n if (*lower_bound(val.begin(), val.end(), a[i]) == a[i]) {\n int index = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n seg.add(index, index + 1, 1);\n }\n int l = lower_bound(val.begin(), val.end(), a[i] + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n seg.add(l, r, 2);\n pq.push(make_pair(a[i], i));\n }\n if (bottom[i]) {\n // cerr << i << \" is bottom.\" << endl;\n queue<pair<int, int>> q;\n while (!pq.empty() && pq.top().first <= a[i]) {\n pair<int, int> p = pq.top();\n pq.pop();\n\n if (a[i] == p.first) {\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -1);\n q.push(make_pair(l, r));\n continue;\n }\n\n if (*lower_bound(val.begin(), val.end(), p.first) == p.first) {\n int index = lower_bound(val.begin(), val.end(), p.first) - val.begin();\n seg.add(index, index + 1, -1);\n }\n int l = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(l, r, -2);\n }\n\n int l = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n ans = min(ans, inversion - seg.query(l, r));\n\n while (!q.empty()) {\n seg.add(q.front().first, q.front().second, -1);\n q.pop();\n }\n }\n if (top[i]) {\n // cerr << i << \" is top.\" << endl;\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 0.9719626168224299, "time_ms": 90, "memory_kb": 9360, "score_of_the_acc": -0.2782, "final_rank": 9 }, { "submission_id": "aoj_0607_2690251", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int64_t inf = 1001001001001001001ll;\n\ntemplate <typename T> class Compress {\nprivate:\n size_t sz;\n std::vector<T> zip;\n std::vector<int> formatted;\n\npublic:\n Compress(std::vector<T> &v) : formatted(v.size(), -1), sz(v.size()) {\n zip = v;\n std::sort(zip.begin(), zip.end());\n zip.erase(std::unique(zip.begin(), zip.end()), zip.end());\n for (int i = 0; i < formatted.size(); ++i) {\n formatted[i] = std::lower_bound(zip.begin(), zip.end(), v[i]) - zip.begin();\n }\n }\n\n int operator[](size_t idx) {\n return formatted[idx];\n }\n\n T unzip(size_t idx) {\n assert(idx < zip.size());\n return zip[idx];\n }\n\n std::vector<int> get() {\n return formatted;\n }\n\n size_t size() {\n return sz;\n }\n};\n\nstruct BinaryIndexedTree {\n BinaryIndexedTree(size_t n) : n(n), v(n + 1, 0) {}\n\n size_t n;\n vector<int64_t> v;\n\n int sum(int k) {\n int64_t ret = 0;\n for (; k; k -= k & -k) ret += v[k];\n return ret;\n }\n\n void add(int k, int x) {\n for (; k <= n; k += k & -k) v[k] += x;\n }\n};\n\nstruct Node {\n int64_t node, lazy;\n Node() {}\n Node(int64_t node, int64_t lazy) : node(node), lazy(lazy) {}\n\n Node operator*(const Node &r) const {\n return Node(max(node, r.node), -inf);\n }\n} e(0, -inf);\n\nstruct SegmentTree : Node {\n size_t n;\n vector<Node> seg;\n\n SegmentTree(size_t size) : n(1 << (32 - __builtin_clz(size - 1))), seg(2 * n - 1, e) {}\n\n inline void lazy_add(int k, int64_t x) {\n if (seg[k].lazy == -inf) {\n seg[k].lazy = 0;\n }\n seg[k].lazy += x;\n }\n\n inline void lazy_evaluate(int k) {\n if (seg[k].lazy != -inf) {\n seg[k].node += seg[k].lazy;\n if (k < n - 1) {\n lazy_add(2 * k + 1, seg[k].lazy);\n lazy_add(2 * k + 2, seg[k].lazy);\n }\n seg[k].lazy = -inf;\n }\n }\n\n inline void update_node(int k) {\n seg[k] = seg[2 * k + 1] * seg[2 * k + 2];\n }\n\n void add(int l, int r, int64_t x, int k, int a, int b) {\n lazy_evaluate(k);\n\n if (r <= a || b <= l) return;\n if (l <= a && b <= r) {\n lazy_add(k, x);\n lazy_evaluate(k);\n return;\n }\n\n add(l, r, x, 2 * k + 1, a, (a + b) / 2);\n add(l, r, x, 2 * k + 2, (a + b) / 2, b);\n update_node(k);\n }\n\n Node query(int l, int r, int k, int a, int b) {\n lazy_evaluate(k);\n if (r <= a || b <= l) return e;\n if (l <= a && b <= r) return seg[k];\n\n return query(l, r, 2 * k + 1, a, (a + b) / 2) * query(l, r, 2 * k + 2, (a + b) / 2, b);\n }\n\n void add(int l, int r, int64_t x) {\n // cerr << \"range [\" << l << \", \" << r << \") add to \" << x << endl;\n add(l, r, x, 0, 0, n);\n }\n\n int64_t query(int l, int r) {\n // cerr << \"range [\" << l << \", \" << r << \") query of \" << query(l, r, 0, 0, n).node << endl;\n return query(l, r, 0, 0, n).node;\n }\n\n void debug() {\n for (int i = 0; i < n; ++i) {\n cout << query(i, i + 1) << (i + 1 == n ? \"\\n\" : \" \");\n }\n }\n};\n\nint main() {\n int n;\n cin >> n;\n\n vector<int> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n\n Compress<int> zip(a);\n a = zip.get();\n\n int64_t inversion = 0;\n BinaryIndexedTree bit(n);\n for (int64_t i = 0; i < n; ++i) {\n inversion += i - bit.sum(a[i]);\n bit.add(a[i] + 1, 1);\n }\n\n // cerr << \"inversion : \" << inversion << endl;\n\n if (inversion == 0) {\n cout << 1 << endl;\n return 0;\n }\n\n int seg_size = 0, max_a = -1, min_a = n + 1;\n vector<int> val, idx, top(n), bottom(n);\n for (int i = 0; i < n; ++i) {\n if (max_a < a[i]) {\n val.push_back(a[i]);\n idx.push_back(i);\n top[i] = 1;\n max_a = a[i];\n seg_size++;\n }\n }\n for (int i = n - 1; i >= 0; --i) {\n if (min_a > a[i]) {\n bottom[i] = 1;\n min_a = a[i];\n }\n }\n\n int64_t ans = inf;\n SegmentTree seg(seg_size);\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> pq;\n int l = 0, r = 0;\n for (int i = 0; i < n; ++i) {\n if (!top[i] && !bottom[i]) {\n // cerr << i << \" is the other.\" << endl;\n if (*lower_bound(val.begin(), val.end(), a[i]) == a[i]) {\n int index = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n seg.add(index, index + 1, 1);\n }\n int addl = lower_bound(val.begin(), val.end(), a[i] + 1) - val.begin();\n int addr = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n seg.add(addl, addr, 2);\n pq.push(make_pair(a[i], i));\n }\n if (bottom[i]) {\n // cerr << i << \" is bottom.\" << endl;\n while (!pq.empty() && pq.top().first <= a[i]) {\n pair<int, int> p = pq.top();\n pq.pop();\n\n if (*lower_bound(val.begin(), val.end(), p.first) == p.first) {\n int index = lower_bound(val.begin(), val.end(), p.first) - val.begin();\n seg.add(index, index + 1, -1);\n }\n int addl = lower_bound(val.begin(), val.end(), p.first + 1) - val.begin();\n int addr = lower_bound(idx.begin(), idx.end(), p.second) - idx.begin();\n seg.add(addl, addr, -2);\n }\n\n int l = lower_bound(val.begin(), val.end(), a[i]) - val.begin();\n int r = lower_bound(idx.begin(), idx.end(), i) - idx.begin();\n ans = min(ans, inversion - seg.query(l, r) - 1);\n }\n if (top[i]) {\n // cerr << i << \" is top.\" << endl;\n }\n }\n\n cout << ans << endl;\n}", "accuracy": 0.7476635514018691, "time_ms": 60, "memory_kb": 8876, "score_of_the_acc": -0.0299, "final_rank": 10 }, { "submission_id": "aoj_0607_2689102", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <limits>\n#include <vector>\n#include <tuple>\nusing namespace std;\n\ntemplate<typename Type> class StarrySkyTree {\npublic:\n\tunsigned size_; std::vector<Type> dat1, dat2, dat;\n\tinline void update_(unsigned a, unsigned b, Type x, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return;\n\t\tif (a <= l && r <= b) {\n\t\t\tdat2[k] += x; return;\n\t\t}\n\t\tupdate_(a, b, x, (k << 1), l, (l + r) >> 1);\n\t\tupdate_(a, b, x, (k << 1) + 1, (l + r) >> 1, r);\n\t\tdat1[k] = std::max(dat1[k << 1] + dat2[k << 1], dat1[(k << 1) + 1] + dat2[(k << 1) + 1]);\n\t}\n\tinline Type query_(unsigned a, unsigned b, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return std::numeric_limits<Type>::min();\n\t\tif (a <= l && r <= b) return dat1[k] + dat2[k];\n\t\tType lc = query_(a, b, (k << 1), l, (l + r) >> 1);\n\t\tType rc = query_(a, b, (k << 1) + 1, (l + r) >> 1, r);\n\t\treturn std::max(lc, rc) + dat2[k];\n\t}\n\t//StarrySkyTree() : size_(0), dat(std::vector<Type>()) {};\n\tStarrySkyTree(int size__) {\n\t\tfor (size_ = 1; size_ < size__; ) size_ <<= 1;\n\t\tdat1.resize(size_ << 1, 0);\n\t\tdat2.resize(size_ << 1, 0);\n\t\tdat.resize(size_ << 1, 0);\n\t}\n\ttemplate<class T>\n\tStarrySkyTree(T begin_, T end_) {\n\t\tunsigned n = (end_ - begin_);\n\t\tfor (size_ = 1; size_ < n; size_ <<= 1); dat.resize(size_ << 1, std::numeric_limits<Type>::min());\n\t\tfor (unsigned i = 0; i < n; i++) dat[i + size_] = *(begin_ + i);\n\t\tfor (unsigned i = size_ - 1; i > 0; i--) dat[i] = std::max(dat[i << 1], dat[(i << 1) + 1]);\n\t}\n\tinline unsigned size() { return size_; }\n\tinline void add(unsigned i, Type x) {\n\t\tupdate_(i, i + 1, x, 1, 0, size_);\n\t}\n\tinline void add(unsigned l, unsigned r, Type x) {\n\t\tupdate_(l, r, x, 1, 0, size_);\n\t}\n\tinline Type query(unsigned l, unsigned r) {\n\t\treturn query_(l, r, 1, 0, size_);\n\t}\n};\n\nlong long bit[100009];\nvoid add(int pos, int x) {\n\tpos++;\n\twhile (pos <= 100008) { bit[pos] += x; pos += (pos&-pos); }\n}\nlong long sum(int pos) {\n\tlong long s = 0; pos++;\n\twhile (pos >= 1) { s += bit[pos]; pos -= (pos&-pos); }\n\treturn s;\n}\n\nlong long n, a[100009], b[100009], px[100009], py[100009], qx[100009], qy[100009], cnt1, cnt2; bool used[100009];\nvector<pair<int, int>> Z;\nvector<tuple<int, int, int, int>>D;\n\nvoid init() {\n\tn = 0;\n\tfor (int i = 0; i < 100009; i++) {\n\t\ta[i] = 0; px[i] = 0; py[i] = 0; qx[i] = 0; qy[i] = 0; used[i] = false; bit[i] = 0;\n\t}\n\tcnt1 = 0; cnt2 = 0;\n\tZ.clear(); D.clear();\n}\nvoid random_generate() {\n\tn = 3;\n\tfor (int i = 1; i <= n; i++) { a[i] = rand() % 5 + 1; b[i] = a[i]; }\n}\nlong long solve_Jury() {\n\tint res = 100000000;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tswap(a[i], a[j]);\n\t\t\tint ct = 0;\n\t\t\tfor (int k = 1; k <= n; k++) {\n\t\t\t\tfor (int l = k + 1; l <= n; l++) {\n\t\t\t\t\tif (a[k] > a[l])ct++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tres = min(res, ct);\n\t\t\tswap(a[i], a[j]);\n\t\t}\n\t}\n\treturn res;\n}\nlong long solve_Part() {\n\tfor (int i = 1; i <= n; i++) { Z.push_back(make_pair(a[i], 0)); }\n\tsort(Z.begin(), Z.end());\n\tfor (int i = 1; i <= n; i++) {\n\t\ta[i] = lower_bound(Z.begin(), Z.end(), make_pair((int)a[i], 0)) - Z.begin();\n\t}\n\tlong long cnt = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt += (sum(100007) - sum(a[i])); add(a[i], 1);\n\t}\n\tif (cnt == 0) {\n\t\tfor (int i = 1; i <= n - 1; i++) { if (a[i] == a[i + 1]) return 0; }\n\t\treturn 1;\n\t}\n\tint maxn = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (maxn < a[i]) { maxn = a[i]; px[cnt1] = i; py[cnt1] = a[i]; cnt1++; used[i] = true; }\n\t}\n\tmaxn = 1000000;\n\tfor (int i = n; i >= 1; i--) {\n\t\tif (maxn > a[i]) { maxn = a[i]; qx[cnt2] = i; qy[cnt2] = a[i]; cnt2++; used[i] = true; }\n\t}\n\treverse(qx, qx + cnt2);\n\treverse(qy, qy + cnt2);\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (used[i] == true) continue;\n\t\tint pos1 = lower_bound(py, py + cnt1, a[i]) - py;\n\t\tint pos5 = lower_bound(py, py + cnt1, a[i] + 1) - py;\n\t\tint pos2 = upper_bound(px, px + cnt1, i) - px; pos2--;\n\t\tint pos3 = lower_bound(qx, qx + cnt2, i) - qx;\n\t\tint pos4 = upper_bound(qy, qy + cnt2, a[i]) - qy; pos4--;\n\t\tint pos6 = lower_bound(qy, qy + cnt2, a[i]) - qy; pos6--;\n\t\tD.push_back(make_tuple(pos1, -1, pos3, pos6));\n\t\tD.push_back(make_tuple(pos5 - 1, 1, pos3, pos6));\n\t\tD.push_back(make_tuple(pos5, -2, pos3, pos6));\n\t\tD.push_back(make_tuple(pos2, 2, pos3, pos6));\n\t\tD.push_back(make_tuple(pos5, -1, pos6 + 1, pos4));\n\t\tD.push_back(make_tuple(pos2, 1, pos6 + 1, pos4));\n\t}\n\tsort(D.begin(), D.end());\n\tStarrySkyTree<long long> A(n + 2); long long ret = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tA.add(get<2>(D[i]), get<3>(D[i]) + 1, -1 * get<1>(D[i]));\n\t\tret = max(ret, A.query(0, n + 1));\n\t\t//for (int j = 0; j <= n; j++) { cout << A.query(j, j + 1) << \" \"; }cout << endl;\n\t}\n\treturn cnt - ret - 1LL;\n}\n\nint main() {\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcin >> a[i];\n\t}\n\t//long long J1 = solve_Jury();\n\tlong long J2 = solve_Part();\n\t/*int wacase = 0;\n\tfor (int i = 1; i <= 1000; i++) {\n\t\tinit();\n\t\trandom_generate();\n\t\tlong long J1 = solve_Jury();\n\t\tlong long J2 = solve_Part();\n\t\tif (J1 != J2) {\n\t\t\tcout << \"Case \" << i << \" [WA \" << wacase + 1 << \"] : Jury = \" << J1 << \" Part = \" << J2 << endl;\n\t\t\tcout << n << endl;\n\t\t\tfor (int i = 1; i <= n; i++) { if (i >= 2)cout << \" \"; cout << b[i]; }\n\t\t\tcout << endl << endl;\n\t\t\twacase++;\n\t\t}\n\t}*/\n\tcout << J2 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 21724, "score_of_the_acc": -1.7206, "final_rank": 6 }, { "submission_id": "aoj_0607_2689096", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <limits>\n#include <vector>\n#include <tuple>\nusing namespace std;\n\ntemplate<typename Type> class StarrySkyTree {\npublic:\n\tunsigned size_; std::vector<Type> dat1, dat2, dat;\n\tinline void update_(unsigned a, unsigned b, Type x, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return;\n\t\tif (a <= l && r <= b) {\n\t\t\tdat2[k] += x; return;\n\t\t}\n\t\tupdate_(a, b, x, (k << 1), l, (l + r) >> 1);\n\t\tupdate_(a, b, x, (k << 1) + 1, (l + r) >> 1, r);\n\t\tdat1[k] = std::max(dat1[k << 1] + dat2[k << 1], dat1[(k << 1) + 1] + dat2[(k << 1) + 1]);\n\t}\n\tinline Type query_(unsigned a, unsigned b, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return std::numeric_limits<Type>::min();\n\t\tif (a <= l && r <= b) return dat1[k] + dat2[k];\n\t\tType lc = query_(a, b, (k << 1), l, (l + r) >> 1);\n\t\tType rc = query_(a, b, (k << 1) + 1, (l + r) >> 1, r);\n\t\treturn std::max(lc, rc) + dat2[k];\n\t}\n\t//StarrySkyTree() : size_(0), dat(std::vector<Type>()) {};\n\tStarrySkyTree(int size__) {\n\t\tfor (size_ = 1; size_ < size__; ) size_ <<= 1;\n\t\tdat1.resize(size_ << 1, 0);\n\t\tdat2.resize(size_ << 1, 0);\n\t\tdat.resize(size_ << 1, 0);\n\t}\n\ttemplate<class T>\n\tStarrySkyTree(T begin_, T end_) {\n\t\tunsigned n = (end_ - begin_);\n\t\tfor (size_ = 1; size_ < n; size_ <<= 1); dat.resize(size_ << 1, std::numeric_limits<Type>::min());\n\t\tfor (unsigned i = 0; i < n; i++) dat[i + size_] = *(begin_ + i);\n\t\tfor (unsigned i = size_ - 1; i > 0; i--) dat[i] = std::max(dat[i << 1], dat[(i << 1) + 1]);\n\t}\n\tinline unsigned size() { return size_; }\n\tinline void add(unsigned i, Type x) {\n\t\tupdate_(i, i + 1, x, 1, 0, size_);\n\t}\n\tinline void add(unsigned l, unsigned r, Type x) {\n\t\tupdate_(l, r, x, 1, 0, size_);\n\t}\n\tinline Type query(unsigned l, unsigned r) {\n\t\treturn query_(l, r, 1, 0, size_);\n\t}\n};\n\nlong long bit[100009];\nvoid add(int pos, int x) {\n\tpos++;\n\twhile (pos <= 100008) { bit[pos] += x; pos += (pos&-pos); }\n}\nlong long sum(int pos) {\n\tlong long s = 0; pos++;\n\twhile (pos >= 1) { s += bit[pos]; pos -= (pos&-pos); }\n\treturn s;\n}\n\nlong long n, a[100009], b[100009], px[100009], py[100009], qx[100009], qy[100009], cnt1, cnt2; bool used[100009];\nvector<pair<int, int>> Z;\nvector<tuple<int, int, int, int>>D;\n\nvoid init() {\n\tn = 0;\n\tfor (int i = 0; i < 100009; i++) {\n\t\ta[i] = 0; px[i] = 0; py[i] = 0; qx[i] = 0; qy[i] = 0; used[i] = false; bit[i] = 0;\n\t}\n\tcnt1 = 0; cnt2 = 0;\n\tZ.clear(); D.clear();\n}\nvoid random_generate() {\n\tn = 3;\n\tfor (int i = 1; i <= n; i++) { a[i] = rand() % 5 + 1; b[i] = a[i]; }\n}\nlong long solve_Jury() {\n\tint res = 100000000;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tswap(a[i], a[j]);\n\t\t\tint ct = 0;\n\t\t\tfor (int k = 1; k <= n; k++) {\n\t\t\t\tfor (int l = k + 1; l <= n; l++) {\n\t\t\t\t\tif (a[k] > a[l])ct++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tres = min(res, ct);\n\t\t\tswap(a[i], a[j]);\n\t\t}\n\t}\n\treturn res;\n}\nlong long solve_Part() {\n\tfor (int i = 1; i <= n; i++) { Z.push_back(make_pair(a[i], 0)); }\n\tsort(Z.begin(), Z.end());\n\tfor (int i = 1; i <= n; i++) {\n\t\ta[i] = lower_bound(Z.begin(), Z.end(), make_pair((int)a[i], 0)) - Z.begin();\n\t}\n\tlong long cnt = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt += (sum(100007) - sum(a[i])); add(a[i], 1);\n\t}\n\tif (cnt == 0) { return 1; }\n\tint maxn = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (maxn < a[i]) { maxn = a[i]; px[cnt1] = i; py[cnt1] = a[i]; cnt1++; used[i] = true; }\n\t}\n\tmaxn = 1000000;\n\tfor (int i = n; i >= 1; i--) {\n\t\tif (maxn > a[i]) { maxn = a[i]; qx[cnt2] = i; qy[cnt2] = a[i]; cnt2++; used[i] = true; }\n\t}\n\treverse(qx, qx + cnt2);\n\treverse(qy, qy + cnt2);\n\tfor (int i = 1; i <= n; i++) {\n\t\tint P = 2; if (used[i] == true) continue;\n\t\tint pos1 = lower_bound(py, py + cnt1, a[i]) - py;\n\t\tint pos2 = upper_bound(px, px + cnt1, i) - px; pos2--;\n\t\tint pos3 = lower_bound(qx, qx + cnt2, i) - qx;\n\t\tint pos4 = upper_bound(qy, qy + cnt2, a[i]) - qy; pos4--;\n\t\tD.push_back(make_tuple(pos1, -P, pos3, pos4));\n\t\tD.push_back(make_tuple(pos2, P, pos3, pos4));\n\t}\n\tsort(D.begin(), D.end());\n\tStarrySkyTree<long long> A(n + 2); long long ret = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tA.add(get<2>(D[i]), get<3>(D[i]) + 1, -1 * get<1>(D[i]));\n\t\tret = max(ret, A.query(0, n + 1));\n\t\t//for (int j = 0; j <= n; j++) { cout << A.query(j, j + 1) << \" \"; }cout << endl;\n\t}\n\treturn cnt - ret - 1LL;\n}\n\nint main() {\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcin >> a[i];\n\t}\n\t//long long J1 = solve_Jury();\n\tlong long J2 = solve_Part();\n\t/*int wacase = 0;\n\tfor (int i = 1; i <= 1000; i++) {\n\t\tinit();\n\t\trandom_generate();\n\t\tlong long J1 = solve_Jury();\n\t\tlong long J2 = solve_Part();\n\t\tif (J1 != J2) {\n\t\t\tcout << \"Case \" << i << \" [WA \" << wacase + 1 << \"] : Jury = \" << J1 << \" Part = \" << J2 << endl;\n\t\t\tcout << n << endl;\n\t\t\tfor (int i = 1; i <= n; i++) { if (i >= 2)cout << \" \"; cout << b[i]; }\n\t\t\tcout << endl << endl;\n\t\t\twacase++;\n\t\t}\n\t}*/\n\tcout << J2 << endl;\n\treturn 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 90, "memory_kb": 14552, "score_of_the_acc": -0.644, "final_rank": 14 }, { "submission_id": "aoj_0607_2689093", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <limits>\n#include <vector>\n#include <tuple>\nusing namespace std;\n\ntemplate<typename Type> class StarrySkyTree {\npublic:\n\tunsigned size_; std::vector<Type> dat1, dat2, dat;\n\tinline void update_(unsigned a, unsigned b, Type x, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return;\n\t\tif (a <= l && r <= b) {\n\t\t\tdat2[k] += x; return;\n\t\t}\n\t\tupdate_(a, b, x, (k << 1), l, (l + r) >> 1);\n\t\tupdate_(a, b, x, (k << 1) + 1, (l + r) >> 1, r);\n\t\tdat1[k] = std::max(dat1[k << 1] + dat2[k << 1], dat1[(k << 1) + 1] + dat2[(k << 1) + 1]);\n\t}\n\tinline Type query_(unsigned a, unsigned b, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return std::numeric_limits<Type>::min();\n\t\tif (a <= l && r <= b) return dat1[k] + dat2[k];\n\t\tType lc = query_(a, b, (k << 1), l, (l + r) >> 1);\n\t\tType rc = query_(a, b, (k << 1) + 1, (l + r) >> 1, r);\n\t\treturn std::max(lc, rc) + dat2[k];\n\t}\n\t//StarrySkyTree() : size_(0), dat(std::vector<Type>()) {};\n\tStarrySkyTree(int size__) {\n\t\tfor (size_ = 1; size_ < size__; ) size_ <<= 1;\n\t\tdat1.resize(size_ << 1, 0);\n\t\tdat2.resize(size_ << 1, 0);\n\t\tdat.resize(size_ << 1, 0);\n\t}\n\ttemplate<class T>\n\tStarrySkyTree(T begin_, T end_) {\n\t\tunsigned n = (end_ - begin_);\n\t\tfor (size_ = 1; size_ < n; size_ <<= 1); dat.resize(size_ << 1, std::numeric_limits<Type>::min());\n\t\tfor (unsigned i = 0; i < n; i++) dat[i + size_] = *(begin_ + i);\n\t\tfor (unsigned i = size_ - 1; i > 0; i--) dat[i] = std::max(dat[i << 1], dat[(i << 1) + 1]);\n\t}\n\tinline unsigned size() { return size_; }\n\tinline void add(unsigned i, Type x) {\n\t\tupdate_(i, i + 1, x, 1, 0, size_);\n\t}\n\tinline void add(unsigned l, unsigned r, Type x) {\n\t\tupdate_(l, r, x, 1, 0, size_);\n\t}\n\tinline Type query(unsigned l, unsigned r) {\n\t\treturn query_(l, r, 1, 0, size_);\n\t}\n};\n\nlong long bit[100009];\nvoid add(int pos, int x) {\n\tpos++;\n\twhile (pos <= 100008) { bit[pos] += x; pos += (pos&-pos); }\n}\nlong long sum(int pos) {\n\tlong long s = 0;\n\twhile (pos >= 1) { s += bit[pos]; pos -= (pos&-pos); }\n\treturn s;\n}\n\nlong long n, a[100009], b[100009], px[100009], py[100009], qx[100009], qy[100009], cnt1, cnt2; bool used[100009];\nvector<pair<int, int>> Z;\nvector<tuple<int, int, int, int>>D;\n\nvoid init() {\n\tn = 0;\n\tfor (int i = 0; i < 100009; i++) {\n\t\ta[i] = 0; px[i] = 0; py[i] = 0; qx[i] = 0; qy[i] = 0; used[i] = false; bit[i] = 0;\n\t}\n\tcnt1 = 0; cnt2 = 0;\n\tZ.clear(); D.clear();\n}\nvoid random_generate() {\n\tn = 5;\n\twhile (true) {\n\t\tfor (int i = 1; i <= n; i++) { a[i] = rand() % 20 + 1; b[i] = a[i]; }\n\t\tbool OK = false;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tfor (int j = i + 1; j <= n; j++) { if (a[i] == a[j])OK = true; }\n\t\t}\n\t\tif (OK == false) break;\n\t}\n}\nlong long solve_Jury() {\n\tint res = 100000000;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tswap(a[i], a[j]);\n\t\t\tint ct = 0;\n\t\t\tfor (int k = 1; k <= n; k++) {\n\t\t\t\tfor (int l = k + 1; l <= n; l++) {\n\t\t\t\t\tif (a[k] > a[l])ct++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tres = min(res, ct);\n\t\t\tswap(a[i], a[j]);\n\t\t}\n\t}\n\treturn res;\n}\nlong long solve_Part() {\n\tfor (int i = 1; i <= n; i++) { Z.push_back(make_pair(a[i], 0)); }\n\tsort(Z.begin(), Z.end());\n\tfor (int i = 1; i <= n; i++) {\n\t\ta[i] = lower_bound(Z.begin(), Z.end(), make_pair((int)a[i], 0)) - Z.begin();\n\t}\n\tlong long cnt = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt += (sum(100007) - sum(a[i])); add(a[i], 1);\n\t}\n\tif (cnt == 0) { return 1; }\n\tint maxn = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (maxn < a[i]) { maxn = a[i]; px[cnt1] = i; py[cnt1] = a[i]; cnt1++; used[i] = true; }\n\t}\n\tmaxn = 1000000;\n\tfor (int i = n; i >= 1; i--) {\n\t\tif (maxn > a[i]) { maxn = a[i]; qx[cnt2] = i; qy[cnt2] = a[i]; cnt2++; used[i] = true; }\n\t}\n\treverse(qx, qx + cnt2);\n\treverse(qy, qy + cnt2);\n\tfor (int i = 1; i <= n; i++) {\n\t\tint P = 2; if (used[i] == true) continue;\n\t\tint pos1 = lower_bound(py, py + cnt1, a[i]) - py;\n\t\tint pos2 = upper_bound(px, px + cnt1, i) - px; pos2--;\n\t\tint pos3 = lower_bound(qx, qx + cnt2, i) - qx;\n\t\tint pos4 = upper_bound(qy, qy + cnt2, a[i]) - qy; pos4--;\n\t\tD.push_back(make_tuple(pos1, -P, pos3, pos4));\n\t\tD.push_back(make_tuple(pos2, P, pos3, pos4));\n\t}\n\tsort(D.begin(), D.end());\n\tStarrySkyTree<long long> A(n + 2); long long ret = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tA.add(get<2>(D[i]), get<3>(D[i]) + 1, -1 * get<1>(D[i]));\n\t\tret = max(ret, A.query(0, n + 1));\n\t\t//for (int j = 0; j <= n; j++) { cout << A.query(j, j + 1) << \" \"; }cout << endl;\n\t}\n\treturn cnt - ret - 1LL;\n}\n\nint main() {\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcin >> a[i];\n\t}\n\t//long long J1 = solve_Jury();\n\tlong long J2 = solve_Part();\n\t/*int wacase = 0;\n\tfor (int i = 1; i <= 1000; i++) {\n\t\tinit();\n\t\trandom_generate();\n\t\tlong long J1 = solve_Jury();\n\t\tlong long J2 = solve_Part();\n\t\tif (J1 != J2) {\n\t\t\tcout << \"Case \" << i << \" [WA \" << wacase + 1 << \"] : Jury = \" << J1 << \" Part = \" << J2 << endl;\n\t\t\tcout << n << endl;\n\t\t\tfor (int i = 1; i <= n; i++) { if (i >= 2)cout << \" \"; cout << b[i]; }\n\t\t\tcout << endl << endl;\n\t\t\twacase++;\n\t\t}\n\t}*/\n\tcout << J2 << endl;\n\treturn 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 90, "memory_kb": 14404, "score_of_the_acc": -0.6336, "final_rank": 13 }, { "submission_id": "aoj_0607_2689086", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <limits>\n#include <vector>\n#include <tuple>\nusing namespace std;\n\ntemplate<typename Type> class StarrySkyTree {\npublic:\n\tunsigned size_; std::vector<Type> dat1, dat2, dat;\n\tinline void update_(unsigned a, unsigned b, Type x, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return;\n\t\tif (a <= l && r <= b) {\n\t\t\tdat2[k] += x; return;\n\t\t}\n\t\tupdate_(a, b, x, (k << 1), l, (l + r) >> 1);\n\t\tupdate_(a, b, x, (k << 1) + 1, (l + r) >> 1, r);\n\t\tdat1[k] = std::max(dat1[k << 1] + dat2[k << 1], dat1[(k << 1) + 1] + dat2[(k << 1) + 1]);\n\t}\n\tinline Type query_(unsigned a, unsigned b, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return std::numeric_limits<Type>::min();\n\t\tif (a <= l && r <= b) return dat1[k] + dat2[k];\n\t\tType lc = query_(a, b, (k << 1), l, (l + r) >> 1);\n\t\tType rc = query_(a, b, (k << 1) + 1, (l + r) >> 1, r);\n\t\treturn std::max(lc, rc) + dat2[k];\n\t}\n\t//StarrySkyTree() : size_(0), dat(std::vector<Type>()) {};\n\tStarrySkyTree(int size__) {\n\t\tfor (size_ = 1; size_ < size__; ) size_ <<= 1;\n\t\tdat1.resize(size_ << 1, 0);\n\t\tdat2.resize(size_ << 1, 0);\n\t\tdat.resize(size_ << 1, 0);\n\t}\n\ttemplate<class T>\n\tStarrySkyTree(T begin_, T end_) {\n\t\tunsigned n = (end_ - begin_);\n\t\tfor (size_ = 1; size_ < n; size_ <<= 1); dat.resize(size_ << 1, std::numeric_limits<Type>::min());\n\t\tfor (unsigned i = 0; i < n; i++) dat[i + size_] = *(begin_ + i);\n\t\tfor (unsigned i = size_ - 1; i > 0; i--) dat[i] = std::max(dat[i << 1], dat[(i << 1) + 1]);\n\t}\n\tinline unsigned size() { return size_; }\n\tinline void add(unsigned i, Type x) {\n\t\tupdate_(i, i + 1, x, 1, 0, size_);\n\t}\n\tinline void add(unsigned l, unsigned r, Type x) {\n\t\tupdate_(l, r, x, 1, 0, size_);\n\t}\n\tinline Type query(unsigned l, unsigned r) {\n\t\treturn query_(l, r, 1, 0, size_);\n\t}\n};\n\nlong long bit[100009];\nvoid add(int pos, int x) {\n\tpos++;\n\twhile (pos <= 100008) { bit[pos] += x; pos += (pos&-pos); }\n}\nlong long sum(int pos) {\n\tlong long s = 0;\n\twhile (pos >= 1) { s += bit[pos]; pos -= (pos&-pos); }\n\treturn s;\n}\n\nlong long n, a[100009], b[100009], px[100009], py[100009], qx[100009], qy[100009], cnt1, cnt2; bool used[100009];\nvector<pair<int, int>> Z;\nvector<tuple<int, int, int, int>>D;\n\nvoid init() {\n\tn = 0;\n\tfor (int i = 0; i < 100009; i++) {\n\t\ta[i] = 0; px[i] = 0; py[i] = 0; qx[i] = 0; qy[i] = 0; used[i] = false; bit[i] = 0;\n\t}\n\tcnt1 = 0; cnt2 = 0;\n\tZ.clear(); D.clear();\n}\nvoid random_generate() {\n\tn = 5;\n\twhile (true) {\n\t\tfor (int i = 1; i <= n; i++) { a[i] = rand() % 20 + 1; b[i] = a[i]; }\n\t\tbool OK = false;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tfor (int j = i + 1; j <= n; j++) { if (a[i] == a[j])OK = true; }\n\t\t}\n\t\tif (OK == false) break;\n\t}\n}\nlong long solve_Jury() {\n\tint res = 100000000;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tswap(a[i], a[j]);\n\t\t\tint ct = 0;\n\t\t\tfor (int k = 1; k <= n; k++) {\n\t\t\t\tfor (int l = k + 1; l <= n; l++) {\n\t\t\t\t\tif (a[k] > a[l])ct++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tres = min(res, ct);\n\t\t\tswap(a[i], a[j]);\n\t\t}\n\t}\n\treturn res;\n}\nlong long solve_Part() {\n\tfor (int i = 1; i <= n; i++) { Z.push_back(make_pair(a[i], -i)); }\n\tsort(Z.begin(), Z.end());\n\tfor (int i = 1; i <= n; i++) {\n\t\ta[i] = lower_bound(Z.begin(), Z.end(), make_pair((int)a[i], -i)) - Z.begin();\n\t}\n\tlong long cnt = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt += (sum(100007) - sum(a[i])); add(a[i], 1);\n\t}\n\tif (cnt == 0) { return 1; }\n\tint maxn = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (maxn < a[i]) { maxn = a[i]; px[cnt1] = i; py[cnt1] = a[i]; cnt1++; used[i] = true; }\n\t}\n\tmaxn = 1000000;\n\tfor (int i = n; i >= 1; i--) {\n\t\tif (maxn > a[i]) { maxn = a[i]; qx[cnt2] = i; qy[cnt2] = a[i]; cnt2++; used[i] = true; }\n\t}\n\treverse(qx, qx + cnt2);\n\treverse(qy, qy + cnt2);\n\tfor (int i = 1; i <= n; i++) {\n\t\tint P = 2; if (used[i] == true) continue;\n\t\tint pos1 = lower_bound(py, py + cnt1, a[i]) - py;\n\t\tint pos2 = upper_bound(px, px + cnt1, i) - px; pos2--;\n\t\tint pos3 = lower_bound(qx, qx + cnt2, i) - qx;\n\t\tint pos4 = upper_bound(qy, qy + cnt2, a[i]) - qy; pos4--;\n\t\tD.push_back(make_tuple(pos1, -P, pos3, pos4));\n\t\tD.push_back(make_tuple(pos2, P, pos3, pos4));\n\t}\n\tsort(D.begin(), D.end());\n\tStarrySkyTree<long long> A(n + 2); long long ret = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tA.add(get<2>(D[i]), get<3>(D[i]) + 1, -1 * get<1>(D[i]));\n\t\tret = max(ret, A.query(0, n + 1));\n\t\t//for (int j = 0; j <= n; j++) { cout << A.query(j, j + 1) << \" \"; }cout << endl;\n\t}\n\treturn cnt - ret - 1LL;\n}\n\nint main() {\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcin >> a[i];\n\t}\n\t//long long J1 = solve_Jury();\n\tlong long J2 = solve_Part();\n\t/*int wacase = 0;\n\tfor (int i = 1; i <= 1000; i++) {\n\t\tinit();\n\t\trandom_generate();\n\t\tlong long J1 = solve_Jury();\n\t\tlong long J2 = solve_Part();\n\t\tif (J1 != J2) {\n\t\t\tcout << \"Case \" << i << \" [WA \" << wacase + 1 << \"] : Jury = \" << J1 << \" Part = \" << J2 << endl;\n\t\t\tcout << n << endl;\n\t\t\tfor (int i = 1; i <= n; i++) { if (i >= 2)cout << \" \"; cout << b[i]; }\n\t\t\tcout << endl << endl;\n\t\t\twacase++;\n\t\t}\n\t}*/\n\tcout << J2 << endl;\n\treturn 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 80, "memory_kb": 14444, "score_of_the_acc": -0.5649, "final_rank": 11 }, { "submission_id": "aoj_0607_2689082", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <limits>\n#include <vector>\n#include <tuple>\nusing namespace std;\n\ntemplate<typename Type> class StarrySkyTree {\npublic:\n\tunsigned size_; std::vector<Type> dat1, dat2, dat;\n\tinline void update_(unsigned a, unsigned b, Type x, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return;\n\t\tif (a <= l && r <= b) {\n\t\t\tdat2[k] += x; return;\n\t\t}\n\t\tupdate_(a, b, x, (k << 1), l, (l + r) >> 1);\n\t\tupdate_(a, b, x, (k << 1) + 1, (l + r) >> 1, r);\n\t\tdat1[k] = std::max(dat1[k << 1] + dat2[k << 1], dat1[(k << 1) + 1] + dat2[(k << 1) + 1]);\n\t}\n\tinline Type query_(unsigned a, unsigned b, unsigned k, unsigned l, unsigned r) {\n\t\tif (r <= a || b <= l) return std::numeric_limits<Type>::min();\n\t\tif (a <= l && r <= b) return dat1[k] + dat2[k];\n\t\tType lc = query_(a, b, (k << 1), l, (l + r) >> 1);\n\t\tType rc = query_(a, b, (k << 1) + 1, (l + r) >> 1, r);\n\t\treturn std::max(lc, rc) + dat2[k];\n\t}\n\t//StarrySkyTree() : size_(0), dat(std::vector<Type>()) {};\n\tStarrySkyTree(int size__) {\n\t\tfor (size_ = 1; size_ < size__; ) size_ <<= 1;\n\t\tdat1.resize(size_ << 1, 0);\n\t\tdat2.resize(size_ << 1, 0);\n\t\tdat.resize(size_ << 1, 0);\n\t}\n\ttemplate<class T>\n\tStarrySkyTree(T begin_, T end_) {\n\t\tunsigned n = (end_ - begin_);\n\t\tfor (size_ = 1; size_ < n; size_ <<= 1); dat.resize(size_ << 1, std::numeric_limits<Type>::min());\n\t\tfor (unsigned i = 0; i < n; i++) dat[i + size_] = *(begin_ + i);\n\t\tfor (unsigned i = size_ - 1; i > 0; i--) dat[i] = std::max(dat[i << 1], dat[(i << 1) + 1]);\n\t}\n\tinline unsigned size() { return size_; }\n\tinline void add(unsigned i, Type x) {\n\t\tupdate_(i, i + 1, x, 1, 0, size_);\n\t}\n\tinline void add(unsigned l, unsigned r, Type x) {\n\t\tupdate_(l, r, x, 1, 0, size_);\n\t}\n\tinline Type query(unsigned l, unsigned r) {\n\t\treturn query_(l, r, 1, 0, size_);\n\t}\n};\n\nlong long bit[100009];\nvoid add(int pos, int x) {\n\tpos++;\n\twhile (pos <= 100008) { bit[pos] += x; pos += (pos&-pos); }\n}\nlong long sum(int pos) {\n\tlong long s = 0;\n\twhile (pos >= 1) { s += bit[pos]; pos -= (pos&-pos); }\n\treturn s;\n}\n\nlong long n, a[100009], b[100009], px[100009], py[100009], qx[100009], qy[100009], cnt1, cnt2; bool used[100009];\nvector<pair<int, int>> Z;\nvector<tuple<int, int, int, int>>D;\n\nvoid init() {\n\tn = 0;\n\tfor (int i = 0; i < 100009; i++) {\n\t\ta[i] = 0; px[i] = 0; py[i] = 0; qx[i] = 0; qy[i] = 0; used[i] = false; bit[i] = 0;\n\t}\n\tcnt1 = 0; cnt2 = 0;\n\tZ.clear(); D.clear();\n}\nvoid random_generate() {\n\tn = 5;\n\twhile (true) {\n\t\tfor (int i = 1; i <= n; i++) { a[i] = rand() % 20 + 1; b[i] = a[i]; }\n\t\tbool OK = false;\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tfor (int j = i + 1; j <= n; j++) { if (a[i] == a[j])OK = true; }\n\t\t}\n\t\tif (OK == false) break;\n\t}\n}\nlong long solve_Jury() {\n\tint res = 100000000;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = i + 1; j <= n; j++) {\n\t\t\tswap(a[i], a[j]);\n\t\t\tint ct = 0;\n\t\t\tfor (int k = 1; k <= n; k++) {\n\t\t\t\tfor (int l = k + 1; l <= n; l++) {\n\t\t\t\t\tif (a[k] > a[l])ct++;\n\t\t\t\t}\n\t\t\t}\n\t\t\tres = min(res, ct);\n\t\t\tswap(a[i], a[j]);\n\t\t}\n\t}\n\treturn res;\n}\nlong long solve_Part() {\n\tfor (int i = 1; i <= n; i++) { Z.push_back(make_pair(a[i], i)); }\n\tsort(Z.begin(), Z.end());\n\tfor (int i = 1; i <= n; i++) {\n\t\ta[i] = lower_bound(Z.begin(), Z.end(), make_pair((int)a[i], i)) - Z.begin();\n\t}\n\tlong long cnt = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcnt += (sum(100007) - sum(a[i])); add(a[i], 1);\n\t}\n\tif (cnt == 0) { return 1; }\n\tint maxn = -1;\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (maxn < a[i]) { maxn = a[i]; px[cnt1] = i; py[cnt1] = a[i]; cnt1++; used[i] = true; }\n\t}\n\tmaxn = 1000000;\n\tfor (int i = n; i >= 1; i--) {\n\t\tif (maxn > a[i]) { maxn = a[i]; qx[cnt2] = i; qy[cnt2] = a[i]; cnt2++; used[i] = true; }\n\t}\n\treverse(qx, qx + cnt2);\n\treverse(qy, qy + cnt2);\n\tfor (int i = 1; i <= n; i++) {\n\t\tint P = 2; if (used[i] == true) continue;\n\t\tint pos1 = lower_bound(py, py + cnt1, a[i]) - py;\n\t\tint pos2 = upper_bound(px, px + cnt1, i) - px; pos2--;\n\t\tint pos3 = lower_bound(qx, qx + cnt2, i) - qx;\n\t\tint pos4 = upper_bound(qy, qy + cnt2, a[i]) - qy; pos4--;\n\t\tD.push_back(make_tuple(pos1, -P, pos3, pos4));\n\t\tD.push_back(make_tuple(pos2, P, pos3, pos4));\n\t}\n\tsort(D.begin(), D.end());\n\tStarrySkyTree<long long> A(n + 2); long long ret = 0;\n\tfor (int i = 0; i < D.size(); i++) {\n\t\tA.add(get<2>(D[i]), get<3>(D[i]) + 1, -1 * get<1>(D[i]));\n\t\tret = max(ret, A.query(0, n + 1));\n\t\t//for (int j = 0; j <= n; j++) { cout << A.query(j, j + 1) << \" \"; }cout << endl;\n\t}\n\treturn cnt - ret - 1LL;\n}\n\nint main() {\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) {\n\t\tcin >> a[i];\n\t}\n\t//long long J1 = solve_Jury();\n\tlong long J2 = solve_Part();\n\t/*int wacase = 0;\n\tfor (int i = 1; i <= 1000; i++) {\n\t\tinit();\n\t\trandom_generate();\n\t\tlong long J1 = solve_Jury();\n\t\tlong long J2 = solve_Part();\n\t\tif (J1 != J2) {\n\t\t\tcout << \"Case \" << i << \" [WA \" << wacase + 1 << \"] : Jury = \" << J1 << \" Part = \" << J2 << endl;\n\t\t\tcout << n << endl;\n\t\t\tfor (int i = 1; i <= n; i++) { if (i >= 2)cout << \" \"; cout << b[i]; }\n\t\t\tcout << endl << endl;\n\t\t\twacase++;\n\t\t}\n\t}*/\n\tcout << J2 << endl;\n\treturn 0;\n}", "accuracy": 0.7476635514018691, "time_ms": 80, "memory_kb": 14504, "score_of_the_acc": -0.5692, "final_rank": 12 }, { "submission_id": "aoj_0607_2633599", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define mp make_pair\n#define INF 2e+9\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> PP;\n\nint siz,segMax[300000],segAdd[300000],bit[300010];\n\nvoid b_add(int i,int x){\n\twhile(i <= siz){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nint sum(int i){\n\tint s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nvoid add(int a,int b,int x,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return;\n\tif(a <= l && r <= b){\n\t\tsegAdd[k] += x;\n\t\treturn;\n\t}\n\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\tsegMax[k] = max(segMax[k * 2 + 1] + segAdd[k * 2 + 1],segMax[k * 2 + 2] + segAdd[k * 2 + 2]);\n}\n\nint get(int a,int b,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return 0;\n\tif(a <= l && r <= b) return segMax[k] + segAdd[k];\n\treturn max(get(a,b,k * 2 + 1,l,(l + r) / 2),get(a,b,k * 2 + 2,(l + r) / 2,r)) + segAdd[k];\n}\n\nsigned main(){\n\tint n,a[100000],ma = -1,mi = INF,tent = 0,ans = 0;\n\tbool used[100000] = {};\n\tvector<int> ls,rs,la,ra,as;\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t\tas.push_back(a[i]);\n\t}\n\tsort(as.begin(),as.end());\n\tas.erase(unique(as.begin(),as.end()),as.end());\n\tfor(int i = 0;i < n;i++) a[i] = lower_bound(as.begin(),as.end(),a[i]) - as.begin();\n\tfor(int i = 0;i < n;i++){\n\t\tif(ma < a[i]){\n\t\t\tma = a[i];\n\t\t\tls.push_back(i);\n\t\t\tla.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\tfor(int i = n - 1;i >= 0;i--){\n\t\tif(mi > a[i]){\n\t\t\tmi = a[i];\n\t\t\trs.push_back(i);\n\t\t\tra.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\treverse(rs.begin(),rs.end());\n\treverse(ra.begin(),ra.end());\n\tsiz = 1;\n\twhile(siz < n) siz *= 2;\n\tfor(int i = 0;i < n;i++){\n\t\ttent += i - sum(a[i] + 1);\n\t\tb_add(a[i] + 1,1);\n\t}\n\tvector<PP> evt1[100001],evt2[100001];\n\tfor(int i = 0;i < n;i++){\n\t\tif(!used[i]){\n\t\t\tint l1 = upper_bound(la.begin(),la.end(),a[i]) - la.begin();\n\t\t\tint l2 = upper_bound(ls.begin(),ls.end(),i) - ls.begin() - 1;\n\t\t\tint r1 = upper_bound(rs.begin(),rs.end(),i) - rs.begin();\n\t\t\tint r2 = lower_bound(ra.begin(),ra.end(),a[i]) - ra.begin() - 1;\n\t\t\tif(l1 <= l2 && r1 <= r2){\n\t\t\t\tevt1[r1].push_back(mp(2,mp(l1,l2)));\n\t\t\t\tevt2[r2].push_back(mp(-2,mp(l1,l2)));\n\t\t\t}\n\t\t\tif(l1 > 0 && la[l1 - 1] == a[i]){\n\t\t\t\tevt1[r1].push_back(mp(1,mp(l1 - 1,l1 - 1)));\n\t\t\t\tevt2[r2].push_back(mp(-1,mp(l1 - 1,l1 - 1)));\n\t\t\t}\n\t\t\tif(r2 < (int)rs.size() - 1 && ra[r2 + 1] == a[i]){\n\t\t\t\tevt1[r2 + 1].push_back(mp(1,mp(l1,l2)));\n\t\t\t\tevt2[r2 + 1].push_back(mp(-1,mp(l1,l2)));\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tfor(PP p : evt1[i]) add(p.second.first,p.second.second + 1,p.first);\n\t\tans = max(ans,get(0,siz));\n\t\tfor(PP p : evt2[i]) add(p.second.first,p.second.second + 1,p.first);\n\t}\n\tif(!tent) cout << ((ls.size() == n) ? 1 : 0) << endl;\n\telse cout << tent - ans - 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 21228, "score_of_the_acc": -1.1143, "final_rank": 5 }, { "submission_id": "aoj_0607_2633546", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define mp make_pair\n#define INF 2e+9\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> PP;\n\nint siz,segMax[300000],segAdd[300000],bit[100010];\n\nvoid b_add(int i,int x){\n\twhile(i <= siz){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nint sum(int i){\n\tint s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nvoid add(int a,int b,int x,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return;\n\tif(a <= l && r <= b){\n\t\tsegAdd[k] += x;\n\t\treturn;\n\t}\n\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\tsegMax[k] = max(segMax[k * 2 + 1] + segAdd[k * 2 + 1],segMax[k * 2 + 2] + segAdd[k * 2 + 2]);\n}\n\nint get(int a,int b,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return 0;\n\tif(a <= l && r <= b) return segMax[k] + segAdd[k];\n\treturn max(get(a,b,k * 2 + 1,l,(l + r) / 2),get(a,b,k * 2 + 2,(l + r) / 2,r)) + segAdd[k];\n}\n\nsigned main(){\n\tint n,a[100000],ma = -1,mi = INF,tent = 0,ans = 0;\n\tbool used[100000] = {};\n\tvector<int> ls,rs,la,ra,as;\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t\tas.push_back(a[i]);\n\t}\n\tsort(as.begin(),as.end());\n\tas.erase(unique(as.begin(),as.end()),as.end());\n\tfor(int i = 0;i < n;i++) a[i] = lower_bound(as.begin(),as.end(),a[i]) - as.begin();\n\tfor(int i = 0;i < n;i++){\n\t\tif(ma < a[i]){\n\t\t\tma = a[i];\n\t\t\tls.push_back(i);\n\t\t\tla.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\tfor(int i = n - 1;i >= 0;i--){\n\t\tif(mi > a[i]){\n\t\t\tmi = a[i];\n\t\t\trs.push_back(i);\n\t\t\tra.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\treverse(rs.begin(),rs.end());\n\treverse(ra.begin(),ra.end());\n\tsiz = 1;\n\twhile(siz < n) siz *= 2;\n\tfor(int i = 0;i < n;i++){\n\t\ttent += i - sum(a[i] + 1);\n\t\tb_add(a[i] + 1,1);\n\t}\n\tvector<PP> evt1[100001],evt2[100001];\n\tfor(int i = 0;i < n;i++){\n\t\tif(!used[i]){\n\t\t\tint l1 = upper_bound(la.begin(),la.end(),a[i]) - la.begin();\n\t\t\tint l2 = upper_bound(ls.begin(),ls.end(),i) - ls.begin() - 1;\n\t\t\tint r1 = upper_bound(rs.begin(),rs.end(),i) - rs.begin();\n\t\t\tint r2 = lower_bound(ra.begin(),ra.end(),a[i]) - ra.begin() - 1;\n\t\t\tif(l1 <= l2 && r1 <= r2){\n\t\t\t\tevt1[r1].push_back(mp(2,mp(l1,l2)));\n\t\t\t\tevt2[r2].push_back(mp(-2,mp(l1,l2)));\n\t\t\t}\n\t\t\tif(l1 > 0 && la[l1 - 1] == a[i]){\n\t\t\t\tevt1[r1].push_back(mp(1,mp(l1 - 1,l1 - 1)));\n\t\t\t\tevt2[r2].push_back(mp(-1,mp(l1 - 1,l1 - 1)));\n\t\t\t}\n\t\t\tif(r2 < (int)rs.size() - 1 && ra[r2 + 1] == a[i]){\n\t\t\t\tevt1[r2 + 1].push_back(mp(1,mp(l1,l2)));\n\t\t\t\tevt2[r2 + 1].push_back(mp(-1,mp(l1,l2)));\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tfor(PP p : evt1[i]) add(p.second.first,p.second.second + 1,p.first);\n\t\tans = max(ans,get(0,siz));\n\t\tfor(PP p : evt2[i]) add(p.second.first,p.second.second + 1,p.first);\n\t}\n\tif(!tent) cout << ((ls.size() == n) ? 1 : 0) << endl;\n\telse cout << tent - ans - 1 << endl;\n\treturn 0;\n}", "accuracy": 0.5700934579439252, "time_ms": 70, "memory_kb": 15572, "score_of_the_acc": -0.573, "final_rank": 18 }, { "submission_id": "aoj_0607_2633528", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define mp make_pair\n#define INF 2e+9\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> PP;\n\nint siz,segMax[300000],segAdd[300000],bit[100010];\n\nvoid b_add(int i,int x){\n\twhile(i <= siz){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nint sum(int i){\n\tint s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nvoid add(int a,int b,int x,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return;\n\tif(a <= l && r <= b){\n\t\tsegAdd[k] += x;\n\t\treturn;\n\t}\n\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\tsegMax[k] = max(segMax[k * 2 + 1] + segAdd[k * 2 + 1],segMax[k * 2 + 2] + segAdd[k * 2 + 2]);\n}\n\nint get(int a,int b,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return 0;\n\tif(a <= l && r <= b) return segMax[k] + segAdd[k];\n\treturn max(get(a,b,k * 2 + 1,l,(l + r) / 2),get(a,b,k * 2 + 2,(l + r) / 2,r)) + segAdd[k];\n}\n\nsigned main(){\n\tint n,a[100000],ma = -1,mi = INF,tent = 0,ans = 0;\n\tbool used[100000] = {};\n\tvector<int> ls,rs,la,ra,as;\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t\tas.push_back(a[i]);\n\t}\n\tsort(as.begin(),as.end());\n\tas.erase(unique(as.begin(),as.end()),as.end());\n\tfor(int i = 0;i < n;i++) a[i] = lower_bound(as.begin(),as.end(),a[i]) - as.begin();\n\tfor(int i = 0;i < n;i++){\n\t\tif(ma < a[i]){\n\t\t\tma = a[i];\n\t\t\tls.push_back(i);\n\t\t\tla.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\tfor(int i = n - 1;i >= 0;i--){\n\t\tif(mi > a[i]){\n\t\t\tmi = a[i];\n\t\t\trs.push_back(i);\n\t\t\tra.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\treverse(rs.begin(),rs.end());\n\treverse(ra.begin(),ra.end());\n\tsiz = 1;\n\twhile(siz < n) siz *= 2;\n\tfor(int i = 0;i < n;i++){\n\t\ttent += i - sum(a[i] + 1);\n\t\tb_add(a[i] + 1,1);\n\t}\n\tvector<PP> evt1[100001],evt2[100001];\n\tfor(int i = 0;i < n;i++){\n\t\tif(!used[i]){\n\t\t\tint l1 = upper_bound(la.begin(),la.end(),a[i]) - la.begin();\n\t\t\tint l2 = upper_bound(ls.begin(),ls.end(),i) - ls.begin() - 1;\n\t\t\tint r1 = upper_bound(rs.begin(),rs.end(),i) - rs.begin();\n\t\t\tint r2 = upper_bound(ra.begin(),ra.end(),a[i]) - ra.begin() - 1;\n\t\t\tevt1[r1].push_back(mp(2,mp(l1,l2)));\n\t\t\tevt2[r2].push_back(mp(-2,mp(l1,l2)));\n\t\t\tif(l1 > 0 && la[l1 - 1] == a[i]){\n\t\t\t\tevt1[r1].push_back(mp(1,mp(l1 - 1,l1 - 1)));\n\t\t\t\tevt2[r2].push_back(mp(-1,mp(l1 - 1,l1 - 1)));\n\t\t\t}\n\t\t\tif(r2 < rs.size() - 1 && ra[r2 + 1] == a[i]){\n\t\t\t\tevt1[r2 + 1].push_back(mp(1,mp(l1,l2)));\n\t\t\t\tevt2[r2 + 1].push_back(mp(-1,mp(l1,l2)));\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tfor(PP p : evt1[i]) add(p.second.first,p.second.second + 1,p.first);\n\t\tans = max(ans,get(0,siz));\n\t\tfor(PP p : evt2[i]) add(p.second.first,p.second.second + 1,p.first);\n\t}\n\tif(!tent) cout << ((ls.size() == n) ? 1 : 0) << endl;\n\telse cout << tent - ans - 1 << endl;\n\treturn 0;\n}", "accuracy": 0.5700934579439252, "time_ms": 70, "memory_kb": 15624, "score_of_the_acc": -0.5766, "final_rank": 19 }, { "submission_id": "aoj_0607_2633512", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define mp make_pair\n#define INF 2e+9\nusing namespace std;\n\ntypedef pair<int,int> P;\ntypedef pair<int,P> PP;\n\nint siz,segMax[300000],segAdd[300000],bit[100010];\n\nvoid b_add(int i,int x){\n\twhile(i <= siz){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nint sum(int i){\n\tint s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nvoid add(int a,int b,int x,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return;\n\tif(a <= l && r <= b){\n\t\tsegAdd[k] += x;\n\t\treturn;\n\t}\n\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\tsegMax[k] = max(segMax[k * 2 + 1] + segAdd[k * 2 + 1],segMax[k * 2 + 2] + segAdd[k * 2 + 2]);\n}\n\nint get(int a,int b,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return 0;\n\tif(a <= l && r <= b) return segMax[k] + segAdd[k];\n\treturn max(get(a,b,k * 2 + 1,l,(l + r) / 2),get(a,b,k * 2 + 2,(l + r) / 2,r)) + segAdd[k];\n}\n\nsigned main(){\n\tint n,a[100000],ma = -1,mi = INF,tent = 0,ans = 0;\n\tbool used[100000] = {};\n\tvector<int> ls,rs,la,ra,as;\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t\tas.push_back(a[i]);\n\t}\n\tsort(as.begin(),as.end());\n\tas.erase(unique(as.begin(),as.end()),as.end());\n\tfor(int i = 0;i < n;i++) a[i] = lower_bound(as.begin(),as.end(),a[i]) - as.begin();\n\tfor(int i = 0;i < n;i++){\n\t\tif(ma < a[i]){\n\t\t\tma = a[i];\n\t\t\tls.push_back(i);\n\t\t\tla.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\tfor(int i = n - 1;i >= 0;i--){\n\t\tif(mi > a[i]){\n\t\t\tmi = a[i];\n\t\t\trs.push_back(i);\n\t\t\tra.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\treverse(rs.begin(),rs.end());\n\treverse(ra.begin(),ra.end());\n\tsiz = 1;\n\twhile(siz < n) siz *= 2;\n\tfor(int i = 0;i < n;i++){\n\t\ttent += i - sum(a[i] + 1);\n\t\tb_add(a[i] + 1,1);\n\t}\n\tvector<PP> evt1[100001],evt2[100001];\n\tfor(int i = 0;i < n;i++){\n\t\tif(!used[i]){\n\t\t\tint l1 = upper_bound(la.begin(),la.end(),a[i]) - la.begin();\n\t\t\tint l2 = upper_bound(ls.begin(),ls.end(),i) - ls.begin() - 1;\n\t\t\tint r1 = upper_bound(rs.begin(),rs.end(),i) - rs.begin();\n\t\t\tint r2 = upper_bound(ra.begin(),ra.end(),a[i]) - ra.begin() - 1;\n\t\t\tevt1[r1].push_back(mp(2,mp(l1,l2)));\n\t\t\tevt2[r2].push_back(mp(-2,mp(l1,l2)));\n\t\t\tif(l1 > 0 && la[l1 - 1] == a[i]){\n\t\t\t\tevt1[r1].push_back(mp(1,mp(l1 - 1,l1)));\n\t\t\t\tevt2[r2].push_back(mp(-1,mp(l1 - 1,l1)));\n\t\t\t}\n\t\t\tif(r2 < rs.size() - 1 && ra[r2 + 1] == a[i]){\n\t\t\t\tevt1[r2 + 1].push_back(mp(1,mp(l1,l2)));\n\t\t\t\tevt2[r2 + 1].push_back(mp(-1,mp(l1,l2)));\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tfor(PP p : evt1[i]) add(p.second.first,p.second.second + 1,p.first);\n\t\tans = max(ans,get(0,siz));\n\t\tfor(PP p : evt2[i]) add(p.second.first,p.second.second + 1,p.first);\n\t}\n\tif(!tent) cout << ((ls.size() == n) ? 1 : 0) << endl;\n\telse cout << tent - ans - 1 << endl;\n\treturn 0;\n}", "accuracy": 0.5700934579439252, "time_ms": 70, "memory_kb": 15784, "score_of_the_acc": -0.5879, "final_rank": 20 }, { "submission_id": "aoj_0607_2633057", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define INF 2e+9\nusing namespace std;\n\ntypedef pair<int,int> P;\n\nint siz,segMax[300000],segAdd[300000],bit[100010];\n\nvoid b_add(int i,int x){\n\twhile(i <= siz){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nint sum(int i){\n\tint s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nvoid add(int a,int b,int x,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return;\n\tif(a <= l && r <= b){\n\t\tsegAdd[k] += x;\n\t\treturn;\n\t}\n\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\tsegMax[k] = max(segMax[k * 2 + 1] + segAdd[k * 2 + 1],segMax[k * 2 + 2] + segAdd[k * 2 + 2]);\n}\n\nint get(int a,int b,int k = 0,int l = 0,int r = siz){\n\tif(b <= l || r <= a) return 0;\n\tif(a <= l && r <= b) return segMax[k] + segAdd[k];\n\treturn max(get(a,b,k * 2 + 1,l,(l + r) / 2),get(a,b,k * 2 + 2,(l + r) / 2,r)) + segAdd[k];\n}\n\nsigned main(){\n\tint n,a[100000],ma = -1,mi = INF,tent = 0,ans = 0;\n\tbool used[100000] = {};\n\tvector<int> ls,rs,la,ra,as;\n\tcin >> n;\n\tfor(int i = 0;i < n;i++){\n\t\tcin >> a[i];\n\t\tas.push_back(a[i]);\n\t}\n\tsort(as.begin(),as.end());\n\tas.erase(unique(as.begin(),as.end()),as.end());\n\tfor(int i = 0;i < n;i++) a[i] = lower_bound(as.begin(),as.end(),a[i]) - as.begin();\n\tfor(int i = 0;i < n;i++){\n\t\tif(ma < a[i]){\n\t\t\tma = a[i];\n\t\t\tls.push_back(i);\n\t\t\tla.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\tfor(int i = n - 1;i >= 0;i--){\n\t\tif(mi > a[i]){\n\t\t\tmi = a[i];\n\t\t\trs.push_back(i);\n\t\t\tra.push_back(a[i]);\n\t\t\tused[i] = true;\n\t\t}\n\t}\n\treverse(rs.begin(),rs.end());\n\treverse(ra.begin(),ra.end());\n\tsiz = 1;\n\twhile(siz < n) siz *= 2;\n\tfor(int i = 0;i < n;i++){\n\t\ttent += i - sum(a[i] + 1);\n\t\tb_add(a[i] + 1,1);\n\t}\n\tvector<P> evt1[100001],evt2[100001];\n\tfor(int i = 0;i < n;i++){\n\t\tif(!used[i]){\n\t\t\tint l1 = upper_bound(la.begin(),la.end(),a[i]) - la.begin();\n\t\t\tint l2 = upper_bound(ls.begin(),ls.end(),i) - ls.begin() - 1;\n\t\t\tint r1 = upper_bound(rs.begin(),rs.end(),i) - rs.begin();\n\t\t\tint r2 = upper_bound(ra.begin(),ra.end(),a[i]) - ra.begin() - 1;\n\t\t\tevt1[r1].push_back(P(l1,l2));\n\t\t\tevt2[r2].push_back(P(l1,l2));\n\t\t}\n\t}\n\tfor(int i = 0;i < n;i++){\n\t\tfor(P p : evt1[i]) add(p.first,p.second + 1,1);\n\t\tans = max(ans,get(0,siz));\n\t\tfor(P p : evt2[i]) add(p.first,p.second + 1,-1);\n\t}\n\tif(!tent) cout << ((ls.size() == n) ? 1 : 0) << endl;\n\telse cout << tent - ans * 2 - 1 << endl;\n\treturn 0;\n}", "accuracy": 0.5700934579439252, "time_ms": 70, "memory_kb": 14588, "score_of_the_acc": -0.5037, "final_rank": 17 } ]
aoj_0611_cpp
シルクロード (Silk Road) 問題 現在カザフスタンがある地域には,古くは「シルクロード」と呼ばれる交易路があった. シルクロード上には N + 1 個の都市があり,西から順に都市 0, 都市 1, ... , 都市 N と番号がつけられている.都市 i - 1 と都市 i の間の距離 (1 ≤ i ≤ N) は D i である. 貿易商である JOI 君は,都市 0 から出発して,都市を順番に経由し,都市 N まで絹を運ぶことになった.都市 0 から都市 N まで M 日以内に移動しなければならない.JOI 君は,それぞれの日の行動として,以下の 2 つのうちいずれか 1 つを選ぶ. 移動: 現在の都市から 1 つ東の都市へ 1 日かけて移動する.現在都市 i - 1 (1 ≤ i ≤ N) にいる場合は,都市 i に移動する. 待機: 移動を行わず,現在いる都市で 1 日待機する. 移動は大変であり,移動するたびに疲労度が溜まっていく.シルクロードでは日毎に天候の変動があり,天候が悪い日ほど移動には苦労を要する. JOI 君が絹を運ぶのに使える M 日間のうち j 日目 (1 ≤ j ≤ M) の天候の悪さは C j であることが分かっている.都市 i - 1 から都市 i (1 ≤ i ≤ N) に j 日目 (1 ≤ j ≤ M) に移動する場合,疲労度が D i × C j だけ溜まってしまう.移動を行わず待機している日は疲労度は溜まらない. JOI 君は,それぞれの日の行動をうまく選ぶことで,できるだけ疲労度を溜めずに移動したい.JOI 君が M 日以内に都市 N に移動するときの,移動を開始してから終了するまでに溜まる疲労度の合計の最小値を求めよ. 入力 入力は 1 + N + M 行からなる. 1 行目には,2 つの整数 N, M (1 ≤ N ≤ M ≤ 1000) が空白を区切りとして書かれている.これは,シルクロードが N + 1 個の都市からなり,JOI 君が絹を都市 0 から都市 N まで M 日以内に運ばなければならないことを表す. 続く N 行のうちの i 行目 (1 ≤ i ≤ N) には,整数 D i (1 ≤ D i ≤ 1000) が書かれている.これは,都市 i - 1 と都市 i の間の距離が D i であることを表す. 続く M 行のうちの j 行目 (1 ≤ j ≤ M) には,整数 C j (1 ≤ C j ≤ 1000) が書かれている.これは,j 日目の天候の悪さが C j であることを表す. 出力 JOI 君が M 日以内に都市 N に移動するときの,移動を開始してから終了するまでに溜まる疲労度の合計の最小値を 1 行で出力せよ. 入出力例 入力例 1 3 5 10 25 15 50 30 15 40 30 出力例 1 1125 入力例 2 2 6 99 20 490 612 515 131 931 1000 出力例 2 31589 入出力例 1 において,溜まる疲労度の合計を最小にするように JOI 君が移動するには次のようにする. 1 日目は待機する. 2 日目に都市 0 から都市 1 へ移動する.このとき溜まる疲労度は 10 × 30 = 300 である. 3 日目に都市 1 から都市 2 へ移動する.このとき溜まる疲労度は 25 × 15 = 375 である. 4 日目は待機する. 5 日目に都市 2 から都市 3 へ移動する.このとき溜まる疲労度は 15 × 30 = 450 である. JOI 君がこのように移動した場合に溜まる疲労度の合計は 300 + 375 + 450 = 1125 である.これが最小値である. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0611_10339944", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nvector<long long> dijkstra(int v,int r,const vector<vector<pair<int,int>>>& graph){\n const long long INF=LLONG_MAX;\n vector<long long> dist(v,INF);\n dist[r]=0;\n\n priority_queue<pair<long long,int>,vector<pair<long long,int>>,greater<>> pq;\n pq.push({0,r});\n\n while(!pq.empty()){\n auto [current_dist,u]=pq.top();\n pq.pop();\n if(current_dist>dist[u]) continue;\n \n for(auto& [to,weight]:graph[u]){\n long long new_dist=current_dist+weight;\n if(new_dist<dist[to]){\n dist[to]=new_dist;\n pq.push({new_dist,to});\n }\n }\n }\n return dist;\n}\n\nint main(){\n int n,m;\n cin >> n >> m;\n vector<int> d(n+1),c(m+1);\n for(int i=1;i<=n;i++){\n cin >> d[i];\n }\n for(int i=1;i<=m;i++){\n cin >> c[i];\n }\n int v=(n+1)*(m+1);\n vector<vector<pair<int,int>>> graph(v);\n auto id=[&](int i,int j)->int{\n return i*(m+1)+j;\n };\n for(int i=0;i<=n;i++){\n for(int j=0;j<=m;j++){\n int u=id(i,j);\n if(j<m){\n graph[u].push_back({id(i,j+1),0});\n }\n if(i<n && j<m){\n int cost=d[i+1]*c[j+1];\n graph[u].push_back({id(i+1,j+1),cost});\n }\n }\n }\n vector<long long> dist=dijkstra(v,id(0,0),graph);\n cout << dist[id(n,m)] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 53728, "score_of_the_acc": -1.0105, "final_rank": 13 }, { "submission_id": "aoj_0611_6773166", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <tuple>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint N, M; cin >> N >> M;\n\tvector<int> D(N), C(M);\n\tfor (auto& d : D) cin >> d;\n\tfor (auto& c : C) cin >> c;\n\tvector<vector<int>> S(N + 1, vector<int> (M + 1, 1 << 30));\n\tusing T = tuple<int, int, int>;\n\tpriority_queue<T, vector<T>, greater<T>> Q;\n\tfor (Q.push({0, 0, 0}); !Q.empty();) {\n\t\tauto [cd, t, n] = Q.top(); Q.pop();\n\t\tif (S[n][t] <= cd) continue;\n\t\tS[n][t] = cd;\n\t\tif (n >= N) continue;\n\t\tfor (; N - n <= M - t; ++t) Q.push({cd + C[t] * D[n], t + 1, n + 1});\n\t}\n\tcout << *min_element(S.back().begin(), S.back().end()) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 7630, "memory_kb": 53484, "score_of_the_acc": -1.9952, "final_rank": 14 }, { "submission_id": "aoj_0611_4801536", "code_snippet": "#include<bits/stdc++.h>\n \n#define lol long long\n#define gcd(x,y) __gcd(x,y)\n#define mt make_tuple\n#define mp make_pair\n#define fi first\n#define se second\n#define fixed(x) fixed<<setprecision(x)\nusing namespace std;\nusing pii=pair<int,int>;\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\ntemplate <class A> inline lol abs(A &a) { return (a < 0 ? -a : a); }\nbool inLine(int x,int y,int mx,int my){return (x>=0&&y>=0&&x<mx&&y<my);}\nconst lol inf=(1LL<<62);\nconst int MOD=(1e9)+7;\nconst int mod=998244353;\nconst int dx[]={1,0,-1,0,1,1,-1,-1};\nconst int dy[]={0,1,0,-1,1,-1,1,-1};\nint n,m;\nlol d[2000],c[2000];\nlol mem[2000][2000];\nlol dp(int p,int q){\n if(p>=n) return 0;\n if(mem[p][q]!=-1) return mem[p][q];\n lol ans=inf;\n for(int i=q;i<m;i++){\n chmin(ans,dp(p+1,i+1)+d[p]*c[i]);\n }\n return mem[p][q]=ans;\n}\nsigned main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n memset(mem,-1,sizeof(mem));\n cin >>n>>m;\n for(int i=0;i<n;i++) cin >>d[i];\n for(int i=0;i<m;i++) cin >>c[i];\n cout <<dp(0,0)<<'\\n';\n return (0);\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 34456, "score_of_the_acc": -0.66, "final_rank": 12 }, { "submission_id": "aoj_0611_4526342", "code_snippet": "#include <bits/stdc++.h>\n#include <math.h>\n\nusing namespace std;\n\nlong long inf=1000000007;\n\nint main(){\n\tint n,m;\n\tcin>>n>>m;\n\tvector<long long> dis(n);\n\tvector<long long> wea(m);\n\n\tfor(int i=0;i<n;i++) cin>>dis.at(i);\n\tfor(int i=0;i<m;i++) cin>>wea.at(i);\n\n\tvector<vector<long long>> dp(n+1,vector<long long>(m+1,inf));\n\tdp.at(0).at(0)=0;\n\n\tlong long ans=inf;\n\n\tqueue<pair<long long,long long>> que;\n\tque.push(make_pair(0,0));\n\n\twhile(!que.empty()){\n\t\tlong long here=que.front().first;\n\t\tlong long date=que.front().second;\n\t\tque.pop();\n\n\t\tif(here==n){\n\t\t\tans=min(ans,dp.at(here).at(date));\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(date<m){\n\t\t\tif(here<n){\n\t\t\t\tif(dp.at(here+1).at(date+1)>dp.at(here).at(date)+dis.at(here)*wea.at(date)){\n\t\t\t\t\tque.push(make_pair(here+1,date+1));\n\t\t\t\t\tdp.at(here+1).at(date+1)=dp.at(here).at(date)+dis.at(here)*wea.at(date);\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif(dp.at(here).at(date+1)>dp.at(here).at(date)){\n\t\t\t\tque.push(make_pair(here,date+1));\n\t\t\t\tdp.at(here).at(date+1)=dp.at(here).at(date);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout<<ans<<endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9204, "score_of_the_acc": -0.1204, "final_rank": 4 }, { "submission_id": "aoj_0611_4003965", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nlong long test[1001], uiop[1001], dp[1001][1001];\nint main() {\n\tlong long n, a, b, c, ans = 100000000000; cin >> n >> a;\n\tfor (int h = 1; h <= n; h++) {\n\t\tcin >> b; test[h] = b;\n\t}\n\tfor (int h = 1; h <= a; h++) {\n\t\tcin >> c; uiop[h] = c;\n\t}\n\tfor (int h = 1; h < 1001; h++) {\n\t\tfor (int i = 0; i < 1001; i++) {\n\t\t\tdp[h][i] = 100000000001;\n\t\t}\n\t}\n\tfor (int h = 1; h <= n; h++) {\n\t\tfor (int i = 1; i <= a; i++) {\n\t\t\tif (h <= i) {\n\t\t\t\tif (h == 1) {\n\t\t\t\t\tfor (int j = 1; j <= i; j++) {\n\t\t\t\t\t\tdp[h][i] = min(dp[h][i], dp[h - 1][j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tfor (int j = 1; j < i; j++) {\n\t\t\t\t\t\tdp[h][i] = min(dp[h][i], dp[h - 1][j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tdp[h][i] += test[h] * uiop[i];\n\t\t\t}\n\t\t}\n\t}\n\tfor (int h = 1; h <= a; h++) {\n\t\tans = min(ans, dp[n][h]);\n\t}\n\tcout << ans << endl;\n\tcin >> n;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 10948, "score_of_the_acc": -0.1838, "final_rank": 9 }, { "submission_id": "aoj_0611_4003963", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nlong long test[1001], uiop[1001], dp[1001][1001];\nint main() {\n\tlong long n, a, b, c, ans = 10000000; cin >> n >> a;\n\tfor (int h = 1; h <= n; h++) {\n\t\tcin >> b; test[h] = b;\n\t}\n\tfor (int h = 1; h <= a; h++) {\n\t\tcin >> c; uiop[h] = c;\n\t}\n\tfor (int h = 1; h < 1001; h++) {\n\t\tfor (int i = 0; i < 1001; i++) {\n\t\t\tdp[h][i] = 10000001;\n\t\t}\n\t}\n\tfor (int h = 1; h <= n; h++) {\n\t\tfor (int i = 1; i <= a; i++) {\n\t\t\tif (h <= i) {\n\t\t\t\tif (h == 1) {\n\t\t\t\t\tfor (int j = 1; j <= i; j++) {\n\t\t\t\t\t\tdp[h][i] = min(dp[h][i], dp[h - 1][j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tfor (int j = 1; j < i; j++) {\n\t\t\t\t\t\tdp[h][i] = min(dp[h][i], dp[h - 1][j]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tdp[h][i] += test[h] * uiop[i];\n\t\t\t}\n\t\t}\n\t}\n\tfor (int h = 1; h <= a; h++) {\n\t\tans = min(ans, dp[n][h]);\n\t}\n\tcout << ans << endl;\n\tcin >> n;\n}", "accuracy": 0.5714285714285714, "time_ms": 170, "memory_kb": 10924, "score_of_the_acc": -0.1754, "final_rank": 17 }, { "submission_id": "aoj_0611_3445865", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing i64 = int64_t;\n\nconstexpr i64 INF = 1e12;\n\nstruct Node{\n i64 n, m, cost;\n bool operator<(const Node &obj)const{\n return cost > obj.cost;\n }\n};\n\ni64 mini[1003][1003]={0};\n\nint main(){\n int n, m;\n cin >> n >> m;\n vector<i64> d;\n for(int i=0;i<n;++i){\n i64 tmp;\n cin >> tmp;\n d.push_back(tmp);\n }\n vector<i64> c;\n for(int i=0;i<m;++i){\n i64 tmp;\n cin >> tmp;\n c.push_back(tmp);\n }\n\n for(int i=0;i<=n;++i){\n for(int j=0;j<=m;++j){\n mini[i][j] = INF;\n }\n }\n\n mini[0][0] = 0;\n priority_queue<Node> que;\n que.push((Node){0, 0, 0});\n while(!que.empty()){\n Node curr = que.top(); que.pop();\n if(curr.n == n){\n cout << curr.cost << endl;\n break;\n }\n if(curr.m + 1 <= m){\n i64 cost = curr.cost;\n if(mini[curr.n][curr.m+1] > cost){\n mini[curr.n][curr.m+1] = cost;\n que.push((Node){curr.n, curr.m+1, cost});\n }\n cost += d[curr.n] * c[curr.m];\n if(mini[curr.n+1][curr.m+1] > cost){\n mini[curr.n+1][curr.m+1] = cost;\n que.push((Node){curr.n+1, curr.m+1, cost});\n }\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 9660, "score_of_the_acc": -0.1347, "final_rank": 6 }, { "submission_id": "aoj_0611_2961632", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define INF 999999999\nvector<int>C, D;\nint N, M;\n\nvector<vector<int> > memo;\n\nint main() {\n\tcin >> N >> M;\n\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tD.push_back(tmp);\n\t}\n\tfor (int i = 0; i < M; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tC.push_back(tmp);\n\t}\n\n\tmemo = vector<vector<int> >(N, vector <int>(M, INF));\n\n\tfor (int i = N - 1; i >= 0; i--)for (int j = M - 1; j >= 0; j--) {\n\t\tif (i > j)continue;\n\t\tif (i == N - 1) {\n\t\t\tmemo[i][j] = D[i] * C[j];\n\t\t}\n\t\telse {\n\t\t\tint a = INF;\n\t\t\tfor (int k = i + 1; k < M; k++) {\n\t\t\t\tif (j < k) {\n\t\t\t\t\tif (a > memo[i + 1][k])a = memo[i + 1][k];\n\t\t\t\t}\n\t\t\t}\n\t\t\tmemo[i][j] = a + D[i]*C[j];\n\t\t}\n\t}\n\n\tint ans = INF;\n\tfor (int i = 0; i < M; i++) {\n\t\tif (ans > memo[0][i])ans = memo[0][i];\n\t}\n\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 9220, "score_of_the_acc": -0.1457, "final_rank": 8 }, { "submission_id": "aoj_0611_2961631", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define INF 999999999\nvector<int>C, D;\nint N, M;\n\nvector<vector<int> > memo;\n\nint main() {\n\tcin >> N >> M;\n\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tD.push_back(tmp);\n\t}\n\tfor (int i = 0; i < M; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tC.push_back(tmp);\n\t}\n\n\tmemo = vector<vector<int> >(N, vector <int>(M, INF));\n\n\tfor (int i = N - 1; i >= 0; i--)for (int j = M - 1; j >= 0; j--) {\n\t\tif (i > j)continue;\n\t\tif (i == N - 1) {\n\t\t\tmemo[i][j] = D[i] * C[j];\n\t\t}\n\t\telse {\n\t\t\tint a = INF;\n\t\t\tfor (int k = i + 1; k < M; k++) {\n\t\t\t\tif (j < k) {\n\t\t\t\t\tif (a > memo[i + 1][k])a = memo[i + 1][k];\n\t\t\t\t}\n\t\t\t}\n\t\t\tmemo[i][j] = a + D[i]*C[j];\n\t\t}\n\t}\n\n\tint ans = INF;\n\tfor (int i = 0; i < M; i++) {\n\t\tif (ans > memo[0][i])ans = memo[0][i];\n\t}\n\t\n\t/*\n\tfor (int i = 0; i < N; i++)for (int j = 0; j < M; j++) {\n\t\tcout << memo[i][j] << \" \";\n\t\tif (j == M - 1) cout << endl;\n\t}*/\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 9136, "score_of_the_acc": -0.1453, "final_rank": 7 }, { "submission_id": "aoj_0611_2961624", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define INF 99999999\nvector<int>C, D;\nint N, M;\n\nvector<vector<int> > memo;\n\nint main() {\n\tcin >> N >> M;\n\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tD.push_back(tmp);\n\t}\n\tfor (int i = 0; i < M; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tC.push_back(tmp);\n\t}\n\n\tmemo = vector<vector<int> >(N, vector <int>(M, INF));\n\n\tfor (int i = N - 1; i >= 0; i--)for (int j = M - 1; j >= 0; j--) {\n\t\tif (i > j)continue;\n\t\tif (i == N - 1) {\n\t\t\tmemo[i][j] = D[i] * C[j];\n\t\t}\n\t\telse {\n\t\t\tint a = INF;\n\t\t\tfor (int k = i + 1; k < M; k++) {\n\t\t\t\tif (j < k) {\n\t\t\t\t\tif (a > memo[i + 1][k])a = memo[i + 1][k];\n\t\t\t\t}\n\t\t\t}\n\t\t\tmemo[i][j] = a + D[i]*C[j];\n\t\t}\n\t}\n\n\tint ans = INF;\n\tfor (int i = 0; i < M; i++) {\n\t\tif (ans > memo[0][i])ans = memo[0][i];\n\t}\n\t\n\t/*\n\tfor (int i = 0; i < N; i++)for (int j = 0; j < M; j++) {\n\t\tcout << memo[i][j] << \" \";\n\t\tif (j == M - 1) cout << endl;\n\t}*/\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 200, "memory_kb": 9216, "score_of_the_acc": -0.1456, "final_rank": 15 }, { "submission_id": "aoj_0611_2961609", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define INF 99999999\nvector<int>C, D;\nint N, M;\n\nvector<vector<int> > memo;\n\nint main() {\n\tcin >> N >> M;\n\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tD.push_back(tmp);\n\t}\n\tfor (int i = 0; i < M; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\tC.push_back(tmp);\n\t}\n\n\tmemo = vector<vector<int> >(N, vector <int>(M, INF));\n\n\tfor (int i = N - 1; i >= 0; i--)for (int j = M - 1; j >= 0; j--) {\n\t\tif (i == N - 1) {\n\t\t\tif (i > j)continue;\n\t\t\tmemo[i][j] = D[i] * C[j];\n\t\t}\n\t\telse {\n\t\t\tint a = INF;\n\t\t\tfor (int k = i + 1; k < M; k++) {\n\t\t\t\tif (j < k) {\n\t\t\t\t\tif (a > memo[i + 1][k])a = memo[i + 1][k];\n\t\t\t\t}\n\t\t\t}\n\t\t\tmemo[i][j] = a + D[i]*C[j];\n\t\t}\n\t}\n\n\tint ans = INF;\n\tfor (int i = 0; i < M; i++) {\n\t\tif (ans > memo[0][i])ans = memo[0][i];\n\t}\n\t\n\t/*\n\tfor (int i = 0; i < N; i++)for (int j = 0; j < M; j++) {\n\t\tcout << memo[i][j] << \" \";\n\t\tif (j == M - 1) cout << endl;\n\t}*/\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 0.8571428571428571, "time_ms": 320, "memory_kb": 9204, "score_of_the_acc": -0.1611, "final_rank": 16 }, { "submission_id": "aoj_0611_2646685", "code_snippet": "#include <iostream>\nusing namespace std;\nint n,m;\nint cities[1000],days[1000];\nint mini=1000000;\nint Min(int x , int y){\n if(x==-1)\n return y;\n else if(y==-1)\n return x;\n return x<y?x:y;\n}\nint now[1000][1000]={0};\nint dp[1000][1000]={0};\nint recursion(int city,int day,int stack){\n if(city==n){\n mini=Min(mini,stack);\n return mini;\n }\n// else if(dp[city][day]!=0){\n// now[city][day]++;\n// return dp[city][day];\n// }\n else if(day==m) return -1;\n else{\n int tmp1=recursion(city+1,day+1,stack+(cities[city]*days[day]));\n int tmp2=recursion(city,day+1,stack);\n dp[city][day]=Min(tmp1,tmp2);\n return dp[city][day];\n }\n}\nint main(){\n cin >> n >> m;\n for(int i=0 ; i<n ; i++ )\n cin >> cities[i];\n for(int i=0 ; i<m ; i++ )\n cin >> days[i];\n int tmp=recursion(0,0,0);\n cout << mini << endl;\n return 0;\n}", "accuracy": 0.2857142857142857, "time_ms": 10, "memory_kb": 3108, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0611_2637710", "code_snippet": "#define _CRT_SECURE_NO_WARNINGS\n\n#include <stdio.h>\n#include <string.h>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <vector>\n#include <math.h>\n#include <queue>\n#include <stack>\n#include <list>\n#include <functional>\n\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (n); i++)\n\nint N, M;\nint D[1234];\nint C[1234];\nlong long int memo[1234][1234];\n\nlong long int dp(int i, int j) {\n\tif (i == 0) return 0;\n\tif (j == 0) return 1145141919810;\n\tif (memo[i][j] != -1) return memo[i][j];\n\treturn memo[i][j] = min(dp(i - 1, j - 1) + D[i - 1] * C[j - 1], dp(i, j - 1));\n}\n\nint main() {\n\n\tmemset(memo, 0xff, sizeof(memo));\n\n\tscanf(\"%d %d\", &N, &M);\n\n\trep(i, N) scanf(\"%d\", &D[i]);\n\trep(i, M) scanf(\"%d\", &C[i]);\n\n\tprintf(\"%lld\\n\", dp(N, M));\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 14640, "score_of_the_acc": -0.2278, "final_rank": 11 }, { "submission_id": "aoj_0611_2610625", "code_snippet": "#include<iostream>\nusing namespace std;\nint n,m;\nint d[1001];\nint c[1001];\nint dp[1002][1001];\nint dp_hiroudo(int i,int j){\n if(i==n){\n return 0;\n }else if(dp[i][j]==-1){\n dp[i][j]=min(dp_hiroudo(i+1,j+1)+d[i]*c[j],dp_hiroudo(i,j+1));\n }\n return dp[i][j];\n}\nint main(){\n cin >>n>>m;\n for(int i=0;i<n;i++)cin >>d[i];\n for(int i=0;i<m;i++)cin >>c[i];\n for(int i=0;i<1002;i++){\n for(int j=0;j<1001;j++){\n if(n-i>m-j)dp[i][j]=1000000000;\n else dp[i][j]=-1;\n }\n }\n dp_hiroudo(0,0);\n cout <<dp[0][0]<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7056, "score_of_the_acc": -0.078, "final_rank": 2 }, { "submission_id": "aoj_0611_2610608", "code_snippet": "#include<iostream>\nusing namespace std;\nint n,m;\nint d[1001];\nint c[1001];\nint dp[1001][1000];\nint dp_hiroudo(int i,int j){\n if(i==n){\n return 0;\n }else if(dp[i][j]==-1){\n dp[i][j]=min(dp_hiroudo(i+1,j+1)+d[i]*c[j],dp_hiroudo(i,j+1));\n }\n return dp[i][j];\n}\nint main(){\n cin >>n>>m;\n for(int i=0;i<n;i++)cin >>d[i];\n for(int i=0;i<m;i++)cin >>c[i];\n for(int i=0;i<1001;i++){\n for(int j=0;j<1000;j++){\n if(n-i>m-j)dp[i][j]=1000000000;\n else dp[i][j]=-1;\n }\n }\n dp_hiroudo(0,0);\n cout <<dp[0][0]<<endl;\n return 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 10, "memory_kb": 38160, "score_of_the_acc": -0.6925, "final_rank": 19 }, { "submission_id": "aoj_0611_2603352", "code_snippet": "#include<iostream>\nusing namespace std;\nint dp[1001][1001];\nint main(){\n\tint n,m,i,i2,i3,d[1000],c[1000],yamagutigumi,takahashi=2100000000;\n\tcin>>n>>m;\n\tfor(i=0;i<n;i++){\n\t\tfor(i2=0;i2<m;i2++){\n\t\t\tdp[i][i2]=2100000000;\n\t\t}\n\t}\n\tfor(i=0;i<n;i++){\n\t\tcin>>d[i];\n\t}\n\tfor(i=0;i<m;i++){\n\t\tcin>>c[i];\n\t\tdp[0][i]=c[i]*d[0];\n\t}\n\tfor(i=1;i<n;i++){\n\t\tfor(i2=0;i2<m;i2++){\n\t\t\tfor(i3=i2;i3<m;i3++){\n\t\t\t\tif(i2==i3)i3++;\n\t\t\t\tif(i3>m)break;\n\t\t\t\tyamagutigumi=d[i]*c[i3]+dp[i-1][i2];\n\t\t\t\tif(dp[i][i3]>yamagutigumi){\n\t\t\t\t\tdp[i][i3]=yamagutigumi;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t/*for(i=0;i<n;i++){\n\t\tfor(i2=0;i2<m;i2++){\n\t\t\tcout<<dp[i][i2]<<' ';\n\t\t}\n\t\tcout<<endl;\n\t}*/\n\tfor(i=0;i<m;i++){\n\t\ttakahashi=min(takahashi,dp[n-1][i]);\n\t}\n\tcout<<takahashi<<endl;\n}", "accuracy": 1, "time_ms": 540, "memory_kb": 6240, "score_of_the_acc": -0.1314, "final_rank": 5 }, { "submission_id": "aoj_0611_2593886", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n\tlong long dp[1001][1001];\n\tlong long e[1001][1001];\n\tlong long ans[1001];\n\tlong long n,m,d[1001],c[1001];\nint main(){\n\t\tcin>>n>>m;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>d[i];\n\t}\n\tfor(int i=0;i<m;i++){\n\t\tcin>>c[i];\n\t}\n\tfor(int i=0;i<m-(n-1);i++){\n\t\tdp[0][i]=d[0]*c[i];\n\t}\n\t//cout<<\" ++++++\"<<endl;\n\tfor(int i=1;i<n;i++){\n\t\tfor(int j=i;j<m-(n-i)+1;j++){\n\t\t\t//cout<<\"=====\"<<endl;\n\t\t\tfor(int z=i-1;z<j;z++){\n\t\t\t\t//cout<<\"QQQQQQQ\"<<endl;\n\t\t\t\tans[z-i+1]=dp[i-1][z];\n\t\t\t}\n\t\t\tsort(ans,ans+j-(i-1));\n\t\t\tdp[i][j]=ans[0]+d[i]*c[j];\n\t\t}\n\t}\n\tfor(int i=n-1;i<m;i++){\n\t\tans[i-(n-1)]=dp[n-1][i];\n\t}\n\tsort(ans,ans+(m-n)+1);\n\tcout<<ans[0]<<endl;\n}", "accuracy": 1, "time_ms": 840, "memory_kb": 7428, "score_of_the_acc": -0.1943, "final_rank": 10 }, { "submission_id": "aoj_0611_2576252", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define llong long long \n#define inf 9999999999\nint N, M;\nllong int D[1001];\nllong int C[1001];\nllong int score[1001][1000][2];\n\nllong int solve(int day, int now, llong int wry, int go){\n\t// cout << day << \" \" << now << \" \" << wry << \" \" << score[day][now][go] << endl;\n\tif(score[day][now][go] != inf) return score[day][now][go];\n\tif(day > M)return inf;\n\tif(now == N){\n\t\tif(score[day][now][go] > wry) return score[day][now][go] = wry;\n\t\telse return inf;\n\t}\n\n\tllong int ret = inf;\n\tret = min(ret, solve(day + 1, now, 0, 0) + wry);\n\tllong int walk = D[now + 1] * C[day + 1];\n\tret = min(ret, solve(day + 1, now + 1, walk, 1) + wry);\n\n\treturn score[day][now][go] = ret;\n}\n\nint main(){\n\tfill_n(D, 1000, -1);\n\tfill_n(C, 1001, -1);\n\tfill_n(**score, 1001 * 1000 * 2, inf);\n\tcin >> N >> M;\n\tfor(int i = 1; i <= N; i++){\n\t\tcin >> D[i];\n\t}\n\tfor(int i = 1; i <= M; i++){\n\t\tcin >> C[i];\n\t}\n\n\tcout << solve(0, 0, 0, 0) << endl;\n\treturn 0;\n}", "accuracy": 0.5714285714285714, "time_ms": 1400, "memory_kb": 18780, "score_of_the_acc": -0.492, "final_rank": 18 }, { "submission_id": "aoj_0611_2117527", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <functional>\n\nusing namespace std;\n\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define omajinai ios::sync_with_stdio(false);cin.tie(0)\n#define rep(i,x) for(int i=0;i<(int)(x);++i)\n#define rep1(i,x) for(int i=1;i<=(int)(x);++i)\n#define rrep(i,x) for(int i=(int)x-1;i>=0;--i)\n#define rrep1(i,x) for(int i=(int)x;i>=1;--i)\n\nusing ll=long long;\nusing ld=long double;\nusing vi=vector<int>;\nusing vvi=vector<vi>;\nusing pii=pair<int, int>;\nusing vpii=vector<pii>;\n\ntemplate<class T,class U>ostream&operator<<(ostream&os,const pair<T,U>p){os<<\"(\"<<p.fst<<\", \"<<p.scd<<\")\";return os;}\ntemplate<class T>ostream&operator<<(ostream&os,const vector<T>v){rep(i,v.size()){if(i)os<<\", \";os<<v[i];}return os;}\ntemplate<typename T>T&max(T&a,T&b){if(a>=b)return a;return b;}\ntemplate<typename T>T&min(T&a,T&b){if(a < b)return a;return b;}\ntemplate<typename T>bool chmax(T&a,T b){if(a < b){a=b;return true;}return false;}\ntemplate<typename T>bool chmin(T&a,T b){if(a > b){a=b;return true;}return false;}\n\nconstexpr int inf = 1e9;\nconstexpr ll linf = 3e18;\nconstexpr double eps = 1e-9;\n\nint N, M;\nint D[1010], C[1010];\n\nint dp[1010][1010];\n\nint rec(int i, int j)\n{\n if (j == N) return 0;\n if (i == M) return inf;\n\n int& res = dp[i][j];\n\n if (~res) return res;\n\n res = min(rec(i + 1, j), rec(i + 1, j + 1) + C[i] * D[j]);\n\n return res;\n}\n\nsigned main()\n{\n cin >> N >> M;\n\n rep(i, N) cin >> D[i];\n rep(i, M) cin >> C[i];\n\n memset(dp, -1, sizeof(dp));\n\n cout << rec(0, 0) << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7056, "score_of_the_acc": -0.078, "final_rank": 2 }, { "submission_id": "aoj_0611_2087941", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<map>\n\nusing namespace std;\n\nint dp[1000][1000] = {};\nint INF = 999999999;\n\nint main(){\n\tint N, M;\n\tint D[1000] = {}, C[1000] = {};\n\tcin >> N >> M;\n\tfor (int i = 0; i < N; i++){\n\t\tcin >> D[i];\n\t}\n\tfor (int i = 0; i < M; i++){\n\t\tcin >> C[i];\n\t}\n\n\tfor (int i = 0; i <= N; i++){\n\t\tfor (int j = i; j <= M; j++){\n\t\t\tif (i == 0 || j == 0) dp[i][j] = 0;\n\t\t\telse{\n\t\t\t\tint tmp1 = INF;\n\t\t\t\tfor (int k = i-1; k < j; k++){\n\t\t\t\t\tint tmp2 = dp[i-1][k];\n\t\t\t\t\tif (tmp1>tmp2){\n\t\t\t\t\t\ttmp1 = tmp2;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (tmp1 == INF) tmp1 = 0;\n\t\t\t\tdp[i][j] = tmp1+(C[j-1]*D[i-1]);\n\t\t\t}\n\t\t}\n\t}\n\t/*\n\tfor (int i = 0; i <= N; i++){\n\t\tfor (int j = 0; j <= M; j++){\n\t\t\tcout << dp[i][j] << \" \";\n\t\t}\n\t\tcout << endl;\n\t}\n\t*/\n\n\tint tmp = INF;\n\tfor (int i = 0; i <= M; i++){\n\t\tif (tmp > dp[N][i]&& dp[N][i]!=0)tmp = dp[N][i];\n\t}\n\n\tcout << tmp << endl;\n\t\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 6212, "score_of_the_acc": -0.0758, "final_rank": 1 } ]
aoj_0612_cpp
砂の城 (Sandcastle) 問題 JOI 君は家族とともに海水浴に来た.さんざん泳いで泳ぎ疲れた JOI 君は,次は砂浜で砂の城を作って遊んだ.しばらくして砂遊びにも飽きると,JOI 君は城を放置してまた海に泳ぎに向かった. JOI 君が作った城は,砂浜のうちのある長方形の領域に含まれている.この長方形の領域は,東西南北にマス目状に区切られている.各マスは,JOI 君が作った城の一部であるマス (以下,「城マス」と呼ぶ) かそうでないマス (以下,「更地マス」と呼ぶ) のいずれかである.それぞれの城マスには「強度」と呼ばれる 1 以上 9 以下の整数が定まっている.長方形の領域の外縁部,すなわち外側と接しているマスには城マスは存在しない. やがて潮が満ちてきて,長方形の領域にも波が押し寄せてくるようになった.波が 1 つ押し寄せてくるたびに,城マスのうち次の条件を満たすものはすべて一斉に崩壊して,更地マスに変化する. 条件: 周囲の 8 マス (東西南北および北東,北西,南東,南西方向に隣接するマス) にある更地マスの数が,そのマスの強度の値以上である. 波が引くと,まもなく次の波が押し寄せて来る. 十分多くの波が押し寄せると,城がすべて崩れてしまうか,丈夫な部分だけが残るかして,波が押し寄せてきても 1 つも城マスが崩壊しないような状態に落ち着く.1 つ以上の城マスを崩壊させるような波が押し寄せてくる回数を求めよ. 入力 入力は 1 + H 行からなる. 1 行目には,2 つの整数 H, W (2 ≤ H ≤ 1000, 2 ≤ W ≤ 1000) が空白を区切りとして書かれている.これは,長方形の領域が縦 H 行,横 W 列の H × W 個のマスに区切られていることを表す.長方形の縦方向は南北方向であり,横方向は東西方向である. 続く H 行にはそれぞれ W 文字からなる文字列が書かれており,最初の波が押し寄せてくる前の長方形の領域の状態を表す.H 行のうちの i 行目の左から j 番目の文字 (1 ≤ i ≤ H, 1 ≤ j ≤ W) は,長方形の領域の北から i 行目,西から j 列目のマスが更地マスである場合は '.' (ピリオド) である.城マスである場合は '1', '2', ..., '9' のいずれかであり,そのマスの強度を表す. 長方形の領域の外縁部はすべて更地マスである.すなわち,すべての入力において,1 行目または H 行目の文字と,各行の左から 1 番目または W 番目の文字はすべて '.' である. 与えられる入力データのうち,入力 1 では H ≤ 50, W ≤ 50 を満たす. 出力 1 つ以上の城マスを崩壊させるような波が押し寄せてくる回数を 1 行で出力せよ. 入出力例 入力例 1 5 6 ...... .939.. .3428. .9393. ...... 出力例 1 3 入力例 2 10 10 .......... .99999999. .9.323239. .91444449. .91444449. .91444449. .91444449. .91232329. .99999999. .......... 出力例 2 35 入出力例 1 においては,初めに押し寄せる波で強度 3 の城マスがすべて崩壊し, ...... .9.9.. ..428. .9.9.. ...... という状態になる. 次に押し寄せてくる波では強度 2 の城マスが崩壊し, ...... .9.9.. ..4.8. .9.9.. ...... という状態になる. 次に押し寄せてくる波では強度 4 の城マスが崩壊し, ...... .9.9.. ....8. .9.9.. ...... という状態になる. これ以降の波が城マスを崩すことはない.よって答えは 3 である. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0612_10852957", "code_snippet": "#include <iostream>\n#include <string>\n#include <queue>\n#include <tuple>\n#include <vector>\nusing namespace std;\nqueue<tuple<int, int, int>>Q; int H, W; string S[1009]; vector<pair<int, int>>vec;\nint dx[8] = { 1,1,1,0,-1,-1,-1,0 }, dy[8] = { -1,0,1,1,1,0,-1,-1 }; bool used[1009][1009];\nint count(int ex, int ey) {\n\tif (S[ex][ey] == '.')return 0;\n\tint cnt = 0;\n\tfor (int k = 0; k < 8; k++) {\n\t\tif (S[ex + dx[k]][ey + dy[k]] == '.')cnt++;\n\t}\n\treturn cnt;\n}\nint main() {\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++)cin >> S[i];\n\tfor (int i = 1; i < H - 1; i++) {\n\t\tfor (int j = 1; j < W - 1; j++) {\n\t\t\tif (S[i][j] != '.' && count(i, j) >= (S[i][j] - '0')) {\n\t\t\t\tQ.push(make_tuple(0, i, j)); vec.push_back(make_pair(i, j)); used[i][j] = true;\n\t\t\t}\n\t\t}\n\t}\n\tint pro = -1;\n\twhile (!Q.empty()) {\n\t\tint ti = get<0>(Q.front()), fx = get<1>(Q.front()), fy = get<2>(Q.front()); Q.pop();\n\t\tif (ti != pro) {\n\t\t\tfor (int i = 0; i < vec.size(); i++)S[vec[i].first][vec[i].second] = '.'; pro = ti;\n\t\t\tvec.clear();\n\t\t}\n\t\tfor (int i = 0; i < 8; i++) {\n\t\t\tint ex = fx + dx[i], ey = fy + dy[i];\n\t\t\tif (S[ex][ey] != '.' && used[ex][ey] == false && count(ex, ey) >= (S[ex][ey] - '0')) {\n\t\t\t\tQ.push(make_tuple(ti + 1, ex, ey)); vec.push_back(make_pair(ex, ey)); used[ex][ey] = true;\n\t\t\t}\n\t\t}\n\t}\n\tcout << pro + 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6356, "score_of_the_acc": -0.2767, "final_rank": 4 }, { "submission_id": "aoj_0612_9612729", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nvector<int> dx={-1,0,1},dy={-1,0,1};\nint main() {\n int H,W; \n cin>>H>>W;\n vector<string> S(H);\n for(int i=0;i<H;i++)cin>>S[i];\n queue<pair<int,int>> Q;\n for(int h=0;h<H;h++){\n for(int w=0;w<W;w++){\n if(S[h][w]=='.')continue;\n int cnt=0;\n for(int y=h-1;y<=h+1;y++){\n for(int x=w-1;x<=w+1;x++){\n if(y==h&&x==w)continue;\n if(S[y][x]=='.')cnt++;\n }\n }\n if(cnt>=S[h][w]-'0')Q.push({h,w});\n }\n }\n int an=0;\n while(!Q.empty()){\n queue<pair<int,int>> NQ;\n an++;\n while(!Q.empty()){\n auto [h,w]=Q.front();\n Q.pop();\n S[h][w]='.';\n for(int y=h-1;y<=h+1;y++){\n for(int x=w-1;x<=w+1;x++){\n if(S[y][x]=='.')continue;\n int cnt=0;\n for(int yy=y-1;yy<=y+1;yy++){\n for(int xx=x-1;xx<=x+1;xx++){\n if(yy==y&&xx==x)continue;\n if(S[yy][xx]=='.')cnt++;\n }\n }\n if(S[y][x]-'0'==cnt)NQ.push({y,x});\n }\n }\n }\n swap(Q,NQ);\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5372, "score_of_the_acc": -0.3422, "final_rank": 5 }, { "submission_id": "aoj_0612_9026585", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto H=in(),W=in();\n\tvvll M(H,vll(W,0));\n\tREP(i,H){\n\t\tauto S=in<string>();\n\t\tREP(j,W){\n\t\t\tif(S[j]!='.'){\n\t\t\t\tM[i][j]=(ll)(S[j]-'0');\n\t\t\t}\n\t\t}\n\t}\n\tqueue<ll> Q,R;\n\tREP(i,H){\n\t\tREP(j,W){\n\t\t\tif(M[i][j]==0){\n\t\t\t\tQ.push(j+i*W);\n\t\t\t}\n\t\t}\n\t}\n\n\tauto decrease = [&](ll u,ll v){\n\t\tif(M[v][u]==0) return;\n\t\tM[v][u]--;\n\t\tif(M[v][u]==0){\n\t\t\tR.push(u+v*W);\n\t\t}\n\t};\n\tll C=0;\n\twhile(!Q.empty() || !R.empty()){\n\t\twhile(!Q.empty()){\n\t\t\tauto V=Q.front();\n\t\t\tQ.pop();\n\t\t\t\n\t\t\tauto u=V%W,v=V/W;\n\t\t\tif(u>0){\n\t\t\t\tdecrease(u-1,v);\n\t\t\t\tif(v>0) decrease(u-1,v-1);\n\t\t\t\tif(v<H-1) decrease(u-1,v+1);\n\t\t\t}\n\t\t\tif(u<W-1){\n\t\t\t\tdecrease(u+1,v);\n\t\t\t\tif(v>0) decrease(u+1,v-1);\n\t\t\t\tif(v<H-1) decrease(u+1,v+1);\n\t\t\t}\n\t\t\tif(v>0) decrease(u,v-1);\n\t\t\tif(v<H-1) decrease(u,v+1);\n\t\t}\n\t\tif(!R.empty()) C++;\n\t\tswap(Q,R);\n\t}\n\tout(C);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11528, "score_of_the_acc": -0.3851, "final_rank": 6 }, { "submission_id": "aoj_0612_8125543", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint dx[] = {-1, -1, -1, 0, 0, 1, 1, 1};\nint dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int h,w; cin >> h >> w;\n vector<string> s(h);\n for (int i = 0; i < h; ++i) {\n cin >> s[i];\n }\n int res = 0;\n vector<pair<int,int>> v;\n for (int i = 1; i+1 < h; ++i) {\n for (int j = 1; j+1 < w; ++j) {\n if (s[i][j] != '.') v.push_back({i, j});\n }\n }\n while (1) {\n vector<pair<int,int>> clr;\n\n for (auto &p : v) {\n int x = p.first, y = p.second;\n int cnt = 0;\n for (int i = 0; i < 8; ++i) {\n int nx = x + dx[i];\n int ny = y + dy[i];\n if (s[nx][ny] == '.') cnt += 1;\n }\n if (cnt >= s[x][y]-'0') {\n clr.push_back({x, y});\n }\n }\n\n if (clr.size()) {\n vector<pair<int,int>> nv;\n for (auto &p : clr) {\n int x = p.first, y = p.second;\n s[x][y] = '.';\n }\n for (auto &p : clr) {\n int x = p.first, y = p.second;\n for (int i = 0; i < 8; ++i) {\n int nx = x + dx[i];\n int ny = y + dy[i];\n if (s[nx][ny] != '.') {\n nv.push_back({nx, ny});\n }\n }\n }\n sort(nv.begin(), nv.end());\n nv.erase(unique(nv.begin(), nv.end()), nv.end());\n res += 1;\n swap(v, nv);\n }\n else {\n break;\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 13864, "score_of_the_acc": -0.8497, "final_rank": 15 }, { "submission_id": "aoj_0612_8125541", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint dx[] = {-1, -1, -1, 0, 0, 1, 1, 1};\nint dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int h,w; cin >> h >> w;\n vector<string> s(h);\n for (int i = 0; i < h; ++i) {\n cin >> s[i];\n }\n int res = 0;\n vector<pair<int,int>> v;\n for (int i = 1; i+1 < h; ++i) {\n for (int j = 1; j+1 < w; ++j) {\n if (s[i][j] != '.') v.push_back({i, j});\n }\n }\n while (1) {\n vector<pair<int,int>> clr;\n\n for (auto &p : v) {\n int x = p.first, y = p.second;\n int cnt = 0;\n for (int i = 0; i < 8; ++i) {\n int nx = x + dx[i];\n int ny = y + dy[i];\n if (s[nx][ny] == '.') cnt += 1;\n }\n if (cnt >= s[x][y]-'0') {\n clr.push_back({x, y});\n }\n }\n\n if (clr.size()) {\n vector<pair<int,int>> nv;\n for (auto &p : clr) {\n int x = p.first, y = p.second;\n s[x][y] = '.';\n for (int i = 0; i < 8; ++i) {\n int nx = x + dx[i];\n int ny = y + dy[i];\n if (0 <= nx and nx < h and 0 <= ny and ny < w and s[nx][ny] != '.') {\n nv.push_back({nx, ny});\n }\n }\n }\n sort(nv.begin(), nv.end());\n nv.erase(unique(nv.begin(), nv.end()), nv.end());\n res += 1;\n swap(v, nv);\n }\n else {\n break;\n }\n }\n cout << res << endl;\n}", "accuracy": 0.5714285714285714, "time_ms": 130, "memory_kb": 13344, "score_of_the_acc": -0.9003, "final_rank": 19 }, { "submission_id": "aoj_0612_6108746", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w);\n vector<string> A(h);\n in(A);\n vector2d(bool,used,h,w,false);\n vector2d(int,ans,h,w,-1);\n queue<pair<int,int>> next;\n rep(y,h){\n rep(x,w){\n if(A[y][x]=='.'){\n ans[y][x]=0;\n next.push({y,x});\n }\n }\n }\n auto f=[&](int y,int x){\n int cnt=0;\n for(int dy=-1;dy<=1;dy++){\n for(int dx=-1;dx<=1;dx++){\n cnt+=(used[y+dy][x+dx]);\n }\n }\n return (cnt>=(A[y][x]-'0'));\n };\n int y,x;\n while(!next.empty()){\n tie(y,x)=next.front();\n next.pop();\n used[y][x]=true;\n for(int dy=-1;dy<=1;dy++){\n for(int dx=-1;dx<=1;dx++){\n if(y+dy<0||y+dy>=h||x+dx<0||x+dx>=w)continue;\n if(ans[y+dy][x+dx]!=-1)continue;\n if(f(y+dy,x+dx)){\n ans[y+dy][x+dx]=ans[y][x]+1;\n next.push({y+dy,x+dx});\n }\n }\n }\n }\n int ansv=0;\n rep(y,h)chmax(ansv,*max_element(all(ans[y])));\n out(ansv);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 9756, "score_of_the_acc": -0.4491, "final_rank": 8 }, { "submission_id": "aoj_0612_5841197", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\nvoid chmin(lint &a, lint b){ if(a > b) a = b; }\n\nint main(){\n int h, w;\n cin >> h >> w;\n string s[h];\n rep(i, h) cin >> s[i];\n \n int nami[h][w];\n rep(i, h) rep(j, w) nami[i][j] = -1;\n \n int cnts[h][w];\n queue<pair<int, int>> que;\n rep(i, h) rep(j, w){\n if(s[i][j] == '.') continue;\n \n int cnt = 0;\n for(int dy: {-1, 0, 1}) for(int dx: {-1, 0, 1}){\n if(dy == 0 && dx == 0) continue;\n \n cnt += (s[i + dy][j + dx] == '.');\n }\n \n cnts[i][j] = cnt;\n if(cnt >= s[i][j] - '0'){\n que.push({i, j});\n nami[i][j] = 0;\n }\n }\n \n while(!que.empty()){\n auto top = que.front();\n que.pop();\n int y = top.first;\n int x = top.second;\n \n s[y][x] = '.';\n \n for(int dy: {-1, 0, 1}) for(int dx: {-1, 0, 1}){\n if(dy == 0 && dx == 0) continue;\n \n int ny = y + dy, nx = x + dx;\n if(s[ny][nx] == '.') continue;\n \n cnts[ny][nx]++;\n if(nami[ny][nx] == -1 && cnts[ny][nx] >= s[ny][nx] - '0'){\n que.push({ny, nx});\n nami[ny][nx] = nami[y][x] + 1;\n }\n }\n }\n \n int ans = -1;\n rep(i, h) rep(j, w) ans = max(ans, nami[i][j]);\n \n cout << ans + 1 << endl;\n \n// rep(i, h){\n// rep(j, w){\n// cout << nami[i][j] << (j == w - 1 ? \"\\n\" : \" \");\n// }\n// }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 13108, "score_of_the_acc": -0.5421, "final_rank": 11 }, { "submission_id": "aoj_0612_5744063", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int H,W;\n cin>>H>>W;\n int dx[8]={1,1,1,0,0,-1,-1,-1};\n int dy[8]={-1,0,1,-1,1,-1,0,1};\n vector<vector<short>>A(H,vector<short>(W));\n queue<array<int,3>>bfs;\n for(int i=0;i<H;i++){\n char s;\n for(int j=0;j<W;j++){\n cin>>s;\n if(s!='.')A[i][j]=s-'0';\n else bfs.push({i,j,0});\n }\n }\n int ans=0;\n while(bfs.size()){\n int x=bfs.front()[0],y=bfs.front()[1],t=bfs.front()[2];\n ans=max(ans,t);\n bfs.pop();\n for(int i=0;i<8;i++){\n if(x+dx[i]<0||x+dx[i]>=H||y+dy[i]<0||y+dy[i]>=W||A[x+dx[i]][y+dy[i]]==0)continue;\n --A[x+dx[i]][y+dy[i]];\n if(A[x+dx[i]][y+dy[i]]==0){\n bfs.push({x+dx[i],y+dy[i],t+1});\n }\n }\n }\n cout<<ans<<'\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5480, "score_of_the_acc": -0.1554, "final_rank": 2 }, { "submission_id": "aoj_0612_5710030", "code_snippet": "#include<iostream>\n#include<set>\n\nusing namespace std;\n\nchar T[1000][1000];\n\nbool Destroyed(int r, int c)\n{\n\tint counter = 0;\n\tfor (int _r = r - 1; _r <= r + 1; _r++)\n\t\tfor (int _c = c - 1; _c <= c + 1; _c++)\n\t\t\tif ((_r != r || _c != c) && T[_r][_c] == '.')\n\t\t\t\tcounter++;\n\n\treturn counter >= (T[r][c] - '0');\n}\n\nint main()\n{\n\tint H, W;\n\tcin >> H >> W;\n\tset<pair<int, int>> nodes;\n\tfor (int r = 0; r < H; r++)\n\t{\n\t\tfor (int c = 0; c < W; c++)\n\t\t{\n\t\t\tcin >> T[r][c];\n\t\t\tif (T[r][c] == '.')\n\t\t\t\tnodes.insert(make_pair(r, c));\n\t\t}\n\t}\n\tint ans = 0;\n\twhile (true)\n\t{\n\t\tset<pair<int, int>> tmp;\n\t\tfor (auto& node : nodes)\n\t\t{\n\t\t\tint r = node.first;\n\t\t\tint c = node.second;\n\t\t\tfor (int _r = max(0,r - 1); _r <= min(H - 1,r + 1); _r++)\n\t\t\t\tfor (int _c = max(0,c - 1); _c <= min(W - 1,c + 1); _c++)\n\t\t\t\t\tif (T[_r][_c] != '.' && Destroyed(_r, _c))\n\t\t\t\t\t\ttmp.insert(make_pair(_r, _c));\n\t\t}\n\t\tif (tmp.size() == 0)\n\t\t\tbreak;\n\t\tfor (auto& node : tmp)\n\t\t\tT[node.first][node.second] = '.';\n\t\tnodes = tmp;\n\t\tans++;\n\t}\n\tcout << ans << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 5380, "score_of_the_acc": -0.4965, "final_rank": 9 }, { "submission_id": "aoj_0612_5655668", "code_snippet": "#include <stdio.h>\n#include<iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\nstruct Node\n{\n\tint x;\n\tint y;\n\tint depth;\n};\nint w, h;\n\nint table_rm[1001][1001];\nint dirx[8] = {-1,0,1,-1,1,-1,0,1};\nint diry[8] = { -1,-1,-1,0,0,1,1,1 };\n\nint check(int y, int x)\n{\n\tif (y >= 0 && y < h && x >= 0 && x < w)\n\t\treturn 1;\n\treturn 0;\n}\n\nint main()\n{\n\tstd::cin >> h >> w;\n\tchar a;\n\tNode tmp;\n\tstd::queue<Node> que;\n\tfor (int i = 0; i < h; i++)\n\t{\n\t\tfor (int j = 0; j < w; j++)\n\t\t{\n\t\t\tstd::cin >> a;\n\t\t\tif (a == '.')\n\t\t\t{\n\t\t\t\ttmp.y = i;\n\t\t\t\ttmp.x = j;\n\t\t\t\ttmp.depth = 1;\n\t\t\t\tque.push(tmp);\n\t\t\t\ttable_rm[i][j] = -1;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\ttable_rm[i][j] = a - '0';\n\t\t\t}\n\t\t}\n\t}\n\tNode node;\n\tint ret = 0;\n\twhile (!que.empty())\n\t{\n\t\tnode = que.front();\n\t\tque.pop();\n\n\t\tfor (int i = 0; i < 8; i++)\n\t\t{\n\t\t\tint y = node.y + diry[i];\n\t\t\tint x = node.x + dirx[i];\n\t\t\tif (check(y, x) && table_rm[y][x] > 0)\n\t\t\t{\n\t\t\t\ttable_rm[y][x]--;\n\t\t\t\tif (table_rm[y][x] == 0)\n\t\t\t\t{\n\t\t\t\t\tret = std::max(ret, node.depth);\n\t\t\t\t\ttmp.depth = node.depth + 1;\n\t\t\t\t\ttmp.x = x;\n\t\t\t\t\ttmp.y = y;\n\t\t\t\t\tque.push(tmp);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t}\n\tstd::cout << ret << std::endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7068, "score_of_the_acc": -0.2744, "final_rank": 3 }, { "submission_id": "aoj_0612_5183134", "code_snippet": "#include<iostream>\n#include<queue>\n#define int long long\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define mp make_pair\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nchar map[1030][1030]; int a[1030][1030], h, w, ans = 0;\nqueue<pair<int, int>>q1;\nsigned main() {\n\tcin >> h >> w;\n\tfor1(i, h)for1(j, w)cin >> map[i][j];\n\tfor (int i = 2; i < h; i++)for (int j = 2; j < w; j++) if (map[i][j] != '.') {\n\t\tfor (int dv = -1; dv <= 1; dv++)for (int hc = -1; hc <= 1; hc++)a[i][j] += (map[i + dv][j + hc] == '.');\n\t\tif (a[i][j] >= map[i][j] - '0')q1.push(mp(1, i * 2000 + j));\n\t}\n\twhile (q1.size()) {\n\t\tint t = q1.front().first, i = q1.front().second / 2000, j = q1.front().second % 2000;\n\t\tq1.pop(); ans = t;\n\t\tfor (int dv = -1; dv <= 1; dv++)for (int hc = -1; hc <= 1; hc++) {\n\t\t\ta[i + dv][j + hc]++;\n\t\t\tif (map[i + dv][j + hc] != '.' && a[i + dv][j + hc] == map[i + dv][j + hc] - '0')q1.push(mp(t + 1, (i + dv) * 2000 + j + hc));\n\t\t}\n\t}\n\tputs(ans);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12208, "score_of_the_acc": -0.5734, "final_rank": 12 }, { "submission_id": "aoj_0612_5034831", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0; i< (n); i++)\nusing namespace std;\ntypedef long long ll;\nconst int mod = 1000000007;\nconst int inf = (1<<30);\nint h,w;\nint dx[8]={-1,0,1,-1,1,-1,0,1};\nint dy[8]={-1,-1,-1,0,0,1,1,1};\nbool check(int x,int y){\n\treturn x>=0 && y>=0 && x<w && y<h;\n}\nint dp[1000][1000]={};\nint main(){\n\tcin>>h>>w;\n\tqueue<pair<int,int>> zero;\n\tfor(int i=0; i<h; i++){\n\t\tfor(int j=0; j<w; j++){\n\t\t\tchar a;\n\t\t\tcin>>a;\n\t\t\tif(a=='.'){\n\t\t\t\tdp[i][j]=-1;\n\t\t\t\tzero.push(make_pair(i,j));\n\t\t\t}else{\n\t\t\t\tdp[i][j]=int(a)-int('0');\n\t\t\t}\n\t\t}\n\t}\n\tint ans=0;\n\twhile(zero.size()>0){\n\t\tans++;\n\t\t//cout<<ans<<endl;\n\t\tqueue<pair<int,int>> zero2;\n\t\twhile(zero.size()>0){\n\t\t\tpair<int,int> k=zero.front();\n\t\t\tzero.pop();\n\t\t\t\n\t\t\trep(i,8){\n\t\t\t\tif(check(k.second+dx[i],k.first+dy[i])){\n\t\t\t\t\tdp[k.first+dy[i]][k.second+dx[i]]--;\n\t\t\t\t\tif(dp[k.first+dy[i]][k.second+dx[i]]==0){\n\t\t\t\t\t\tzero2.push(make_pair(k.first+dy[i],k.second+dx[i]));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tzero=zero2;\n\t}\n\t/*for(int i=0; i<h; i++){\n\t\tfor(int j=0; j<w; j++){\n\t\t\tcout<<dp[i][j]<<\" \";\n\t\t}cout<<endl;\n\t}*/\n\tcout<<ans-1<<endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 7188, "score_of_the_acc": -0.7805, "final_rank": 13 }, { "submission_id": "aoj_0612_4831877", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst ll mod = 1000000007;\nconst ld pi = 3.141592653589793238;\n\nchar maze[1234][1234]; ll d[1234][1234], vst[1234][1234];\nll dx[8] = { -1, -1, -1, 0, 0, 1, 1, 1 }, dy[8] = { -1, 0, 1, -1, 1, -1, 0, 1 };\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t\n\tll n, m, ans = 0; cin >> n >> m;\n\trep2(i, n) {\n\t\trep2(j, m) {\n\t\t\tcin >> maze[i][j];\n\t\t}\n\t}\n\trep2(i, n) {\n\t\trep2(j, m) {\n\t\t\trep(k, 8) {\n\t\t\t\tif (maze[i + dx[k]][j + dy[k]] == '.') { d[i][j]++; }\n\t\t\t}\n\t\t}\n\t}\n\n\ttypedef pair<ll, ll>P;\n\tqueue<P> que; queue<ll> cnt;\n\trep2(i, n) {\n\t\trep2(j, m) {\n\t\t\tif (maze[i][j] != '.') {\n\t\t\t\tif ((ll)(maze[i][j] - '0') <= d[i][j] && vst[i][j] == 0) {\n\t\t\t\t\tque.push(P(i, j)); cnt.push(1); ans = 1; vst[i][j] = 1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\twhile (que.size()) {\n\t\tP p = que.front(); que.pop();\n\t\tll ok = cnt.front() + 1; cnt.pop();\n\t\tmaze[p.first][p.second] = '.';\n\n\t\tfor (int i = 0; i < 8; i++) {\n\t\t\tll nx = p.first + dx[i], ny = p.second + dy[i];\n\t\t\tif (maze[nx][ny] != '.') {\n\t\t\t\td[nx][ny]++;\n\t\t\t\tif ((ll)(maze[nx][ny] - '0') <= d[nx][ny] && vst[nx][ny] == 0) {\n\t\t\t\t\tque.push(P(nx, ny)); cnt.push(ok); vst[nx][ny] = 1;\n\t\t\t\t\tans = max(ans, ok);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 23656, "score_of_the_acc": -1.0769, "final_rank": 16 }, { "submission_id": "aoj_0612_4821844", "code_snippet": "#include <bits/stdc++.h>\n \nconst double pi = 3.141592653589793238462643383279;\nusing namespace std;\n\n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\ntypedef long long LL;\ntypedef unsigned long long ULL;\ntypedef vector<LL> VLL;\ntypedef vector<VLL> VVLL;\n \n \n//container util\n//------------------------------------------\n#define ALL(a) (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SQ(a) ((a)*(a))\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \n \n//repetition\n//------------------------------------------\n#define FOR(i,s,n) for(int i=s;i<(int)n;++i)\n#define REP(i,n) FOR(i,0,n)\n#define MOD 1000000007\n \n \n#define rep(i, a, b) for(int i = a; i < (b); ++i)\n#define trav(a, x) for(auto& a : x)\n#define all(x) x.begin(), x.end()\n#define sz(x) (int)(x).size()\n \ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n \n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\nconst long double EPS = 1e-6, PI = acos((long double)-1);\n\n//ここから編集\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(4);\n\n int H, W; cin >> H >> W;\n\n vector<string> v;\n queue<pair<int, int>> q;\n REP(i,H){\n string s; cin >> s;\n v.push_back(s);\n REP(j,W){\n if(s[j] == '.'){\n q.push({i*W+j, 0});\n }\n }\n }\n\n int mx = 0;\n while(q.size()){\n auto p = q.front();\n q.pop();\n\n int y = p.first/W, x = p.first%W;\n chmax(mx, p.second);\n for(int i=-1; i<=1; i++){\n for(int j=-1; j<=1; j++){\n int ny = y+i, nx = x+j;\n if(ny >= 0 && ny < H && nx >= 0 && nx < W && v[ny][nx] != '.'){\n if(v[ny][nx] == '1'){\n v[ny][nx] = '.';\n q.push({ny*W+nx, p.second+1});\n }else{\n v[ny][nx] = (char)('0'+((v[ny][nx]-'0') - 1));\n }\n }\n }\n }\n }\n cout << mx << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4176, "score_of_the_acc": -0.0508, "final_rank": 1 }, { "submission_id": "aoj_0612_4819469", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst vector<int> dx = { 1, 1, 1, 0, -1, -1, -1, 0 };\nconst vector<int> dy = { 1, 0, -1, -1, -1, 0, 1, 1 };\nint main() {\n\tint H, W;\n\tcin >> H >> W;\n\tvector<string> S(H);\n\tfor (int i = 0; i < H; ++i) {\n\t\tcin >> S[i];\n\t}\n\tvector<pair<int, int> > dels;\n\tfor (int i = 0; i < H; ++i) {\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (S[i][j] == '.') continue;\n\t\t\tint cnt = 0;\n\t\t\tfor (int k = 0; k < 8; ++k) {\n\t\t\t\tint tx = i + dx[k], ty = j + dy[k];\n\t\t\t\tif (0 <= tx && tx < H && 0 <= ty && ty < W && S[tx][ty] == '.') {\n\t\t\t\t\t++cnt;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (cnt >= int(S[i][j] - '0')) {\n\t\t\t\tdels.push_back(make_pair(i, j));\n\t\t\t}\n\t\t}\n\t}\n\tint ans = 0;\n\twhile (!dels.empty()) {\n\t\t++ans;\n\t\tfor (pair<int, int> i : dels) {\n\t\t\tS[i.first][i.second] = '.';\n\t\t}\n\t\tvector<pair<int, int> > ndels;\n\t\tfor (pair<int, int> i : dels) {\n\t\t\tfor (int j = 0; j < 8; ++j) {\n\t\t\t\tint sx = i.first + dx[j], sy = i.second + dy[j];\n\t\t\t\tif (!(0 <= sx && sx < H && 0 <= sy && sy < W && S[sx][sy] != '.')) continue;\n\t\t\t\tint cnt = 0;\n\t\t\t\tfor (int k = 0; k < 8; ++k) {\n\t\t\t\t\tint tx = sx + dx[k], ty = sy + dy[k];\n\t\t\t\t\tif (0 <= tx && tx < H && 0 <= ty && ty < W && S[tx][ty] == '.') {\n\t\t\t\t\t\t++cnt;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (cnt >= int(S[sx][sy] - '0')) {\n\t\t\t\t\tndels.push_back(make_pair(sx, sy));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(ndels.begin(), ndels.end());\n\t\tndels.erase(unique(ndels.begin(), ndels.end()), ndels.end());\n\t\tdels = ndels;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 3932, "score_of_the_acc": -0.5, "final_rank": 10 }, { "submission_id": "aoj_0612_4801738", "code_snippet": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for(int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\nconst long long INFLL = 1LL << 60;\nconst int INFINT = 1 << 30;\nconst long long MOD = 1e9 + 7;\n\nconst vector<int> dx = {-1, 0, 1, 1, 1, 0, -1, -1};\nconst vector<int> dy = {-1, -1, -1, 0, 1, 1, 1, 0};\n\ntemplate <class T> void vecout(T V) {\n auto t = V.begin();\n while(t != V.end()) {\n cout << *t++;\n if(t != V.end()) cout << \" \";\n }\n cout << endl;\n};\n\nint main() {\n int H, W;\n cin >> H >> W;\n char a;\n set<pair<int, int>> filter;\n int count = 0;\n vector<vector<int>> sa(H, vector<int>(W, 0));\n rep(i, H) rep(j, W) {\n cin >> a;\n sa[i][j] = (a == '.' ? 0 : a - '0');\n }\n\n queue<pair<int, int>> bre, cas;\n\n rep(i, 1, H - 1) rep(j, 1, W - 1) {\n int s = 0;\n rep(k, 8) if(sa[i + dy[k]][j + dx[k]] < 1) s++;\n if(s >= sa[i][j]) bre.push(make_pair(i, j));\n }\n while(!bre.empty()) {\n count++;\n while(!bre.empty()) {\n auto targ = bre.front();\n sa[targ.first][targ.second] = 0;\n rep(k, 8) {\n if(sa[targ.first + dy[k]][targ.second + dx[k]] > 0)\n filter.insert(\n make_pair(targ.first + dy[k], targ.second + dx[k]));\n }\n bre.pop();\n }\n for(auto aa : filter) {\n cas.push(aa);\n }\n filter.clear();\n\n while(!cas.empty()) {\n int s = 0;\n auto targ = cas.front();\n if(sa[targ.first][targ.second] > 0) {\n rep(k, 8) if(sa[targ.first + dy[k]][targ.second + dx[k]] < 1)\n s++;\n if(s >= sa[targ.first][targ.second])\n filter.insert(make_pair(targ.first, targ.second));\n }\n cas.pop();\n }\n for(auto aa : filter) {\n bre.push(aa);\n }\n filter.clear();\n }\n cout << count << endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 13564, "score_of_the_acc": -1.373, "final_rank": 17 }, { "submission_id": "aoj_0612_4801694", "code_snippet": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for(int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\nconst long long INFLL = 1LL << 60;\nconst int INFINT = 1 << 30;\nconst long long MOD = 1e9 + 7;\n\nconst vector<int> dx = {-1, 0, 1, 1, 1, 0, -1, -1};\nconst vector<int> dy = {-1, -1, -1, 0, 1, 1, 1, 0};\n\ntemplate <class T> void vecout(T V) {\n auto t = V.begin();\n while(t != V.end()) {\n cout << *t++;\n if(t != V.end()) cout << \" \";\n }\n cout << endl;\n};\n\nint main() {\n int H, W;\n cin >> H >> W;\n char a;\n set<pair<int, int>> filter;\n int count = 0;\n vector<vector<int>> sa(H, vector<int>(W, 0));\n rep(i, H) rep(j, W) {\n cin >> a;\n sa[i][j] = (a == '.' ? 0 : a - '0');\n }\n\n queue<pair<int, int>> bre, cas;\n\n rep(i, 1, H - 1) rep(j, 1, W - 1) {\n int s = 0;\n rep(k, 8) if(sa[i + dy[k]][j + dx[k]] < 1) s++;\n if(s >= sa[i][j]) bre.push(make_pair(i, j));\n }\n while(!bre.empty()) {\n count++;\n while(!bre.empty()) {\n auto targ = bre.front();\n sa[targ.first][targ.second] = 0;\n rep(k, 8) {\n if(sa[targ.first + dy[k]][targ.second + dx[k]] > 0)\n filter.insert(\n make_pair(targ.first + dy[k], targ.second + dx[k]));\n }\n bre.pop();\n }\n for(auto aa : filter) {\n cas.push(aa);\n }\n filter.clear();\n\n // rep(i, H) {\n // rep(j, W) {\n // if(sa[i][j])\n // cout << sa[i][j];\n // else\n // cout << '.';\n // }\n // cout << endl;\n // }\n\n while(!cas.empty()) {\n int s = 0;\n auto targ = cas.front();\n rep(k, 8) if(sa[targ.first + dy[k]][targ.second + dx[k]] < 1) s++;\n if(s >= sa[targ.first][targ.second])\n filter.insert(make_pair(targ.first, targ.second));\n cas.pop();\n }\n for(auto aa : filter) {\n bre.push(aa);\n }\n filter.clear();\n }\n cout << count << endl;\n}", "accuracy": 0.5714285714285714, "time_ms": 280, "memory_kb": 6772, "score_of_the_acc": -1.144, "final_rank": 20 }, { "submission_id": "aoj_0612_4801676", "code_snippet": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for(int i = int(a); i < int(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\nconst long long INFLL = 1LL << 60;\nconst int INFINT = 1 << 30;\nconst long long MOD = 1e9 + 7;\n\nconst vector<int> dx = {-1, 0, 1, 1, 1, 0, -1, -1};\nconst vector<int> dy = {-1, -1, -1, 0, 1, 1, 1, 0};\n\ntemplate <class T> void vecout(T V) {\n auto t = V.begin();\n while(t != V.end()) {\n cout << *t++;\n if(t != V.end()) cout << \" \";\n }\n cout << endl;\n};\n\nint main() {\n int H, W;\n cin >> H >> W;\n char a;\n set<pair<int, int>> filter;\n int count = 0;\n vector<vector<int>> sa(H, vector<int>(W, 0));\n rep(i, H) rep(j, W) {\n cin >> a;\n sa[i][j] = (a == '.' ? 0 : a - '0');\n }\n\n queue<pair<int, int>> bre, cas;\n\n rep(i, 1, H - 1) rep(j, 1, W - 1) {\n int s = 0;\n rep(k, 8) if(sa[i + dy[k]][j + dx[k]] < 1) s++;\n if(s >= sa[i][j]) bre.push(make_pair(i, j));\n }\n while(!bre.empty()) {\n count++;\n while(!bre.empty()) {\n auto targ = bre.front();\n sa[targ.first][targ.second] = 0;\n rep(k, 8) {\n if(sa[targ.first + dy[k]][targ.second + dx[k]] > 0)\n cas.push(\n make_pair(targ.first + dy[k], targ.second + dx[k]));\n }\n bre.pop();\n }\n while(!cas.empty()) {\n int s = 0;\n auto targ = cas.front();\n rep(k, 8) if(sa[targ.first + dy[k]][targ.second + dx[k]] < 1) s++;\n if(s >= sa[targ.first][targ.second])\n filter.insert(make_pair(targ.first, targ.second));\n cas.pop();\n }\n for(auto aa : filter) {\n bre.push(aa);\n }\n filter.clear();\n }\n cout << count << endl;\n}", "accuracy": 0.5714285714285714, "time_ms": 160, "memory_kb": 6868, "score_of_the_acc": -0.6873, "final_rank": 18 }, { "submission_id": "aoj_0612_4712454", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define rrep(i,n) for(int (i)=1;i<=(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint h, w;\nint fld[1001][1001];\nint sea[1001][1001];\nqueue<P> que[2];\nconst int dx[] = {-1, -1, -1, 0, 0, 1, 1, 1};\nconst int dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};\n\nbool wave(bool flag) {\n\tif(que[flag].empty()) return 0;\n\twhile(!que[flag].empty()) {\n\t\tP p = que[flag].front();\n\t\tque[flag].pop();\n\t\trep(i, 8) {\n\t\t\tint nx = p.first + dx[i];\n\t\t\tint ny = p.second + dy[i];\n\t\t\tsea[ny][nx]++;\n\t\t\tif(fld[ny][nx] != 0 && fld[ny][nx] == sea[ny][nx]) {\n\t\t\t\tque[!flag].push(P(nx, ny));\n\t\t\t}\n\t\t}\n\t}\n\treturn 1;\n}\n\nsigned main() {\n\tcin.tie(0);\n\tcout.tie(0);\n\tios::sync_with_stdio(false);\n\t//cout << fixed << setprecision(15);\n\t\n\tcin >> h >> w;\n\trep(i, h) {\n\t\tstring s;\n\t\tcin >> s;\n\t\trep(j, w) {\n\t\t\tif(s[j] == '.') fld[i][j] = 0;\n\t\t\telse fld[i][j] = s[j] - '0';\n\t\t}\n\t}\n\n\tREP(i, 1, h-1) {\n\t\tREP(j, 1, w-1) {\n\t\t\trep(d, 8) {\n\t\t\t\tint nx = j + dx[d];\n\t\t\t\tint ny = i + dy[d];\n\t\t\t\tif(fld[ny][nx] == 0) sea[i][j]++;\n\t\t\t}\n\t\t\tif(fld[i][j] != 0 && sea[i][j] >= fld[i][j]) {\n\t\t\t\tque[0].push(P(j, i));\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 0;\n\tbool f = 0;\n\twhile(wave(f)) {\n\t\tf = !f;\n\t\tans++;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 18852, "score_of_the_acc": -0.7949, "final_rank": 14 }, { "submission_id": "aoj_0612_4173943", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int,P>;\nusing PP = pair<P, P>;\nconstexpr ll INF = 1LL<<60;\n\nint main(){\n int h, w;\n cin >> h >> w;\n vector<string> s(h);\n vector<vector<bool> > used(h, vector<bool>(w));\n vector<vector<int> > cnt(h, vector<int>(w));\n for(int i=0;i<h;i++){\n cin >> s[i];\n }\n queue<P> que[2];\n for(int i=1;i<h-1;i++){\n for(int j=1;j<w-1;j++){\n if(s[i][j] == '.') continue;\n for(int di=-1;di<=1;di++)for(int dj=-1;dj<=1;dj++){\n int ni = i+di, nj = j+dj;\n if(s[ni][nj] == '.') cnt[i][j]++;\n }\n if(cnt[i][j] >= s[i][j]-'0'){\n que[0].push(P(i,j));\n }\n }\n }\n bool update = true;\n int t = 0;\n while(update){\n update = false;\n while(!que[0].empty()){\n auto p = que[0].front();\n que[0].pop();\n int i = p.first, j = p.second;\n if(s[i][j] == '.') continue;\n if(used[i][j]) continue;\n if(cnt[i][j] >= s[i][j]-'0'){\n que[1].push(P(i,j));\n used[i][j] = true;\n update = true;\n }\n }\n while(!que[1].empty()){\n auto p = que[1].front();\n que[1].pop();\n int i = p.first, j = p.second;\n s[i][j] = '.';\n for(int di=-1;di<=1;di++)for(int dj=-1;dj<=1;dj++){\n int ni = i+di, nj = j+dj;\n if(s[ni][nj] == '.') continue;\n if(used[ni][nj]) continue;\n cnt[ni][nj]++;\n if(cnt[ni][nj] >= s[ni][nj]-'0') que[0].push(P(ni,nj));\n }\n }\n if(update) t++;\n }\n cout << t << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8164, "score_of_the_acc": -0.4069, "final_rank": 7 } ]
aoj_0605_cpp
現代的な屋敷(Modern Mansion) あなたは,ある大きな屋敷に迷い込んでしまった.この屋敷は正方形の部屋が東西南北に格子状に,東西方向に M 列,南北方向に N 行の合計 M × N 個並んだ構造をしている.西から x 列目(1 ≤ x ≤ M ),南から y 行目(1 ≤ y ≤ N ) にある部屋を( x , y ) で表す. 東西南北に隣り合う 2 部屋の間は,壁の中央にある扉により結ばれている.それぞれの扉は,閉じていて通行不可能な状態か,開いていて通行可能な状態のいずれかにある.扉が開いているとき,それらの部屋の中央間を移動するのに 1 分間かかる.また,いくつかの部屋の中央にはスイッチがあり,スイッチを 1 分間押し続けると,屋敷内のすべての扉の開閉の状態が切り替わる. 今,東西に隣り合う 2 部屋を結ぶすべての扉は閉じていて,南北に隣り合う 2 部屋を結ぶすべての扉は開いている.あなたは今部屋 (1, 1) の中央にいて,部屋 ( M , N ) の中央まで最短時間で移動したい. 課題 屋敷の大きさ M , N および,スイッチのある K 個の部屋の位置 ( X 1 , Y 1 ), ( X 2 , Y 2 ),..., ( X K , Y K ) が与えられる.東西に隣り合う 2 部屋を結ぶすべての扉は閉じていて,南北に隣り合う 2 部屋を結ぶすべての扉は開いている状態から始めて,部屋 (1, 1) の中央から部屋 ( M , N ) の中央まで移動するのに最短で何分かかるかを求めるプログラムを作成せよ.ただし,部屋 ( M , N ) に辿り着くことができないときはそれを指摘せよ. 制限 2 ≤ M ≤ 100 000      屋敷の東西方向の部屋の個数 2 ≤ N ≤ 100 000     屋敷の南北方向の部屋の個数 1 ≤ K ≤ 200 000     スイッチのある部屋の個数 1 ≤ X i ≤ M スイッチのある部屋の東西方向の位置 1 ≤ Y i ≤ N スイッチのある部屋の南北方向の位置 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 M, N, K が空白を区切りとして書かれている. M は屋敷の東西方向の部屋の個数, N は屋敷の南北方向の部屋の個数, K はスイッチのある部屋の個数を表す. 続く K 行のうちの i 行目(1 ≤ i ≤ K ) には,整数 X i , Y i が空白を区切りとして書かれている.これは,部屋( X i , Y i ) の中央にスイッチがあることを表す. K 個の組( X 1 , Y 1 ), ( X 2 , Y 2 ),..., ( X K , Y K ) は互いに異なる. 出力 標準出力に,移動に最短で何分かかるかを表す整数を 1 行で出力せよ.ただし,部屋( M , N ) に辿り着くことができないときは代わりに整数 -1 を出力せよ. 採点基準 採点用データのうち,配点の20%分については, M ≤ 1 000, N ≤ 1 000 を満たす. 採点用データのうち,配点の30%分については, K ≤ 2 000 を満たす. 採点用データのうち,配点の50%分については,これら 2 つの条件の少なくとも一方を満たす.また,これら 2 つの条件の両方を満たすような採点用データはない. 入出力例 入力例 1 3 2 1 1 2 出力例 1 4 この例では,以下の行動によって 4 分間で部屋(1, 1) の中央から部屋(3, 2) の中央へ移動することができ,これが最短である. 部屋(1, 2) の中央へ移動する. 部屋(1, 2) の中央のスイッチを押す. 部屋(2, 2) の中央へ移動する. 部屋(3, 2) の中央へ移動する. このときの屋敷の様子が以下の図に表されている.図では右方向が東,上方向が北であり,×印はあなたの位置,○印はスイッチを表す. 入力例 2 3 2 1 2 1 出力例 2 -1 この例では,あなたは部屋(3, 2) に辿り着くことができない. 入力例 3 8 9 15 3 1 3 2 3 7 3 8 1 1 4 5 4 3 5 6 5 8 6 3 6 2 7 5 8 9 8 6 8 5 出力例 3 25 この例では,最初の屋敷の様子は以下の図のようになっている.部屋(1, 1) や部屋( M , N ) の中央にスイッチがある可能性もあることに注意せよ. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0605_10848671", "code_snippet": "#include<iostream>\n#include<functional>\n#include<algorithm>\n#include<queue>\n#include<tuple>\nusing namespace std;\n#pragma warning(disable:4996)\nlong long a[240000], b[240000], dist[240000][2], H, W, K;\nvector<pair<int, int>>X[120000], Y[120000];\nvector<tuple<long long, long long, long long>>x[240000][2];\npriority_queue<tuple<long long, long long, long long>, vector<tuple<long long, long long, long long>>, greater<tuple<long long, long long, long long>>>Q;\nvoid dijkstra() {\n\tfor (int i = 0; i < 240000; i++) { dist[i][0] = 999999999999999999LL; dist[i][1] = 999999999999999999LL; }\n\tdist[0][0] = 0; Q.push(make_tuple(0, 0, 0));\n\twhile (!Q.empty()) {\n\t\tlong long a1 = get<0>(Q.top()), a2 = get<1>(Q.top()), a3 = get<2>(Q.top()); Q.pop();\n\t\tfor (int i = 0; i < x[a2][a3].size(); i++) {\n\t\t\tlong long to1 = get<0>(x[a2][a3][i]), to2 = get<1>(x[a2][a3][i]), cost = get<2>(x[a2][a3][i]);\n\t\t\tif (dist[to1][to2] > a1 + cost) {\n\t\t\t\tdist[to1][to2] = a1 + cost; Q.push(make_tuple(dist[to1][to2], to1, to2));\n\t\t\t}\n\t\t}\n\t}\n}\nint main() {\n\tcin >> H >> W >> K; X[1].push_back(make_pair(1, 0)); Y[1].push_back(make_pair(1, 0));\n\tX[H].push_back(make_pair(W, K + 1)); Y[W].push_back(make_pair(H, K + 1));\n\tfor (int i = 1; i <= K; i++) { scanf(\"%d%d\", &a[i], &b[i]); X[a[i]].push_back(make_pair(b[i], i)); Y[b[i]].push_back(make_pair(a[i], i)); }\n\tfor (int i = 1; i <= H; i++) { sort(X[i].begin(), X[i].end()); }\n\tfor (int i = 1; i <= W; i++) { sort(Y[i].begin(), Y[i].end()); }\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 0; j < X[i].size(); j++) {\n\t\t\tint G1 = X[i][j].first, G2 = X[i][j].second;\n\t\t\tif (G2 != 0 && G2 != K + 1) { x[G2][0].push_back(make_tuple(G2, 1, 1)); x[G2][1].push_back(make_tuple(G2, 0, 1)); }\n\t\t\tif (j != X[i].size() - 1) {\n\t\t\t\tint G3 = X[i][j + 1].first, G4 = X[i][j + 1].second;\n\t\t\t\tx[G2][0].push_back(make_tuple(G4, 0, abs(G1 - G3))); x[G4][0].push_back(make_tuple(G2, 0, abs(G1 - G3)));\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 1; i <= W; i++) {\n\t\tfor (int j = 0; j < Y[i].size(); j++) {\n\t\t\tint G1 = Y[i][j].first, G2 = Y[i][j].second;\n\t\t\tif (G2 != 0 && G2 != K + 1) { x[G2][0].push_back(make_tuple(G2, 1, 1)); x[G2][1].push_back(make_tuple(G2, 0, 1)); }\n\t\t\tif (j != Y[i].size() - 1) {\n\t\t\t\tint G3 = Y[i][j + 1].first, G4 = Y[i][j + 1].second;\n\t\t\t\tx[G2][1].push_back(make_tuple(G4, 1, abs(G1 - G3))); x[G4][1].push_back(make_tuple(G2, 1, abs(G1 - G3)));\n\t\t\t}\n\t\t}\n\t}\n\tdijkstra();\n\tlong long ans = min(dist[K + 1][0], dist[K + 1][1]);\n\tif (ans >= 999999999999999LL)ans = -1;\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 84432, "score_of_the_acc": -0.73, "final_rank": 10 }, { "submission_id": "aoj_0605_9665210", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int MX_SIZE= 2e6 + 10;\n\nstruct node {\n int u;\n long long cost;\n};\n\nstruct edge {\n int u;\n long long cost;\n};\n\nstruct cmp {\n bool operator()(node &l, node &r) {\n return l.cost > r.cost;\n }\n};\n\nvector< edge > adj[MX_SIZE];\nlong long dist[MX_SIZE];\n\nvoid dijkstra( int src) {\n for(int i = 0; i < MX_SIZE; i++)\n dist[i] = 1e18;\n dist[src] = 0;\n\n priority_queue<node, vector<node>, cmp> pq;\n pq.push({src, 0});\n\n while (!pq.empty()) {\n long long u = pq.top().u;\n long long cost = pq.top().cost;\n pq.pop();\n\n if (dist[u] < cost) continue;\n\n for (auto [v, w]: adj[u]) {\n if (dist[v] > dist[u] + w) {\n dist[v] = dist[u] + w;\n pq.push({v, dist[v]});\n }\n }\n }\n}\n\nint main() {\n int n, m, k;\n cin >> m >> n >> k;\n \n pair<pair<int, int>, int> key[k+2];\n for(int i = 1; i <= k; i++){\n\t\tcin >> key[i].first.first >> key[i].first.second;\n\t\tkey[i].second = i;\n\t}\n \n // key in position (1, 1)\n key[0].first.first = 1;\n key[0].first.second = 1;\n key[0].second = 0;\n \n // key in position (m, n)\n key[k + 1].first.first = m;\n key[k + 1].first.second = n;\n key[k + 1].second = k + 1;\n \n for(int i = 1; i <= k; i++){\n\t\tedge e;\n\t\te.cost = 1;\n\t\te.u = i + k + 2;\n\t\tadj[i].push_back(e);\n\t\te.u = i;\n\t\tadj[i + k + 2].push_back(e);\n\t}\n \n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n\t\tif(key[i].first.first == key[i + 1].first.first){\n\t\t\tedge e;\n\t\t\te.cost = abs(key[i + 1].first.second - key[i].first.second);\n\t\t\te.u = key[i + 1].second;\n\t\t\tadj[key[i].second].push_back(e);\n\t\t\te.u = key[i].second;\n\t\t\tadj[key[i + 1].second].push_back(e);\n\t\t}\n\t}\n \n for(int i = 0; i <= k + 1; i++){\n\t\tswap(key[i].first.first, key[i].first.second);\n\t\tkey[i].second += k + 2; \n\t}\n\t\n\tsort(key, key + k + 2);\n\t\n for(int i = 0; i <= k; i++){\n\t\tif(key[i].first.first == key[i + 1].first.first){\n\t\t\tedge e;\n\t\t\te.cost = abs(key[i + 1].first.second - key[i].first.second);\n\t\t\te.u = key[i + 1].second;\n\t\t\tadj[key[i].second].push_back(e);\n\t\t\te.u = key[i].second;\n\t\t\tadj[key[i + 1].second].push_back(e);\n\t\t}\n\t}\n \n dijkstra(0);\n long long ans = min(dist[k+1], dist[2 * k + 3]);\n \n if(ans == 1e18)\n cout << -1 << \"\\n\";\n else\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 102304, "score_of_the_acc": -0.7994, "final_rank": 11 }, { "submission_id": "aoj_0605_9665200", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int MX_SIZE= 2e6 + 10;\n\nstruct node {\n int u;\n long long cost;\n};\n\nstruct edge {\n int u;\n int cost;\n};\n\nstruct cmp {\n bool operator()(node &l, node &r) {\n return l.cost > r.cost;\n }\n};\n\nvector< edge > adj[MX_SIZE];\nlong long dist[MX_SIZE];\n\nvoid dijkstra( int src) {\n for(int i = 0; i < MX_SIZE; i++)\n dist[i] = 1e18;\n dist[src] = 0;\n\n priority_queue<node, vector<node>, cmp> pq;\n pq.push({src, 0});\n\n while (!pq.empty()) {\n long long u = pq.top().u;\n long long cost = pq.top().cost;\n pq.pop();\n\n if (dist[u] < cost) continue;\n\n for (auto [v, w]: adj[u]) {\n if (dist[v] > dist[u] + w) {\n dist[v] = dist[u] + w;\n pq.push({v, dist[v]});\n }\n }\n }\n}\n\nint main() {\n int n, m, k;\n cin >> m >> n >> k;\n\n pair<pair<int, int>, int> key[k+2];\n for(int i = 1; i <= k; i++){\n cin >> key[i].first.first >> key[i].first.second;\n key[i].second = i;\n }\n\n // key in position (1, 1)\n key[0].first.first = 1;\n key[0].first.second = 1;\n key[0].second = 0;\n\n // key in position (m, n)\n key[k + 1].first.first = m;\n key[k + 1].first.second = n;\n key[k + 1].second = k + 1;\n\n for(int i = 1; i <= k; i++){\n edge e;\n e.cost = 1;\n e.u = i + k + 2;\n adj[i].push_back(e);\n e.u = i;\n adj[i + k + 2].push_back(e);\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n for(int i = 0; i <= k + 1; i++){\n swap(key[i].first.first, key[i].first.second);\n key[i].second += k + 2;\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n dijkstra(0);\n int ans = min(dist[k+1], dist[2 * k + 3]);\n\n if(ans >= 1e18)\n cout << -1 << \"\\n\";\n else\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 0.03225806451612903, "time_ms": 190, "memory_kb": 90252, "score_of_the_acc": -0.6449, "final_rank": 20 }, { "submission_id": "aoj_0605_9665198", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int MX_SIZE= 2e6 + 10;\n\nstruct node {\n int u;\n long long cost;\n};\n\nstruct edge {\n int u;\n int cost;\n};\n\nstruct cmp {\n bool operator()(node &l, node &r) {\n return l.cost > r.cost;\n }\n};\n\nvector< edge > adj[MX_SIZE];\nlong long dist[MX_SIZE];\n\nvoid dijkstra( int src) {\n for(int i = 0; i < MX_SIZE; i++)\n dist[i] = 1e18;\n dist[src] = 0;\n\n priority_queue<node, vector<node>, cmp> pq;\n pq.push({src, 0});\n\n while (!pq.empty()) {\n long long u = pq.top().u;\n long long cost = pq.top().cost;\n pq.pop();\n\n if (dist[u] < cost) continue;\n\n for (auto [v, w]: adj[u]) {\n if (dist[v] > dist[u] + w) {\n dist[v] = dist[u] + w;\n pq.push({v, dist[v]});\n }\n }\n }\n}\n\nint main() {\n int n, m, k;\n cin >> m >> n >> k;\n\n pair<pair<int, int>, int> key[k+2];\n for(int i = 1; i <= k; i++){\n cin >> key[i].first.first >> key[i].first.second;\n key[i].second = i;\n }\n\n // key in position (1, 1)\n key[0].first.first = 1;\n key[0].first.second = 1;\n key[0].second = 0;\n\n // key in position (m, n)\n key[k + 1].first.first = m;\n key[k + 1].first.second = n;\n key[k + 1].second = k + 1;\n\n for(int i = 1; i <= k; i++){\n edge e;\n e.cost = 1;\n e.u = i + k + 2;\n adj[i].push_back(e);\n e.u = i;\n adj[i + k + 2].push_back(e);\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n for(int i = 0; i <= k + 1; i++){\n swap(key[i].first.first, key[i].first.second);\n key[i].second += k + 2;\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n dijkstra(0);\n int ans = min(dist[k+1], dist[2 * k + 3]);\n\n if(ans == 1e18)\n cout << -1 << \"\\n\";\n else\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 0.03225806451612903, "time_ms": 190, "memory_kb": 90140, "score_of_the_acc": -0.6442, "final_rank": 19 }, { "submission_id": "aoj_0605_9665197", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nconst int MX_SIZE= 2e6 + 10;\n\nstruct node {\n int u;\n long long cost;\n};\n\nstruct edge {\n int u;\n int cost;\n};\n\nstruct cmp {\n bool operator()(node &l, node &r) {\n return l.cost > r.cost;\n }\n};\n\nvector< edge > adj[MX_SIZE];\nlong long dist[MX_SIZE];\n\nvoid dijkstra( int src) {\n for(int i = 0; i < MX_SIZE; i++)\n dist[i] = 1e9;\n dist[src] = 0;\n\n priority_queue<node, vector<node>, cmp> pq;\n pq.push({src, 0});\n\n while (!pq.empty()) {\n long long u = pq.top().u;\n long long cost = pq.top().cost;\n pq.pop();\n\n if (dist[u] < cost) continue;\n\n for (auto [v, w]: adj[u]) {\n if (dist[v] > dist[u] + w) {\n dist[v] = dist[u] + w;\n pq.push({v, dist[v]});\n }\n }\n }\n}\n\nint main() {\n int n, m, k;\n cin >> m >> n >> k;\n\n pair<pair<int, int>, int> key[k+2];\n for(int i = 1; i <= k; i++){\n cin >> key[i].first.first >> key[i].first.second;\n key[i].second = i;\n }\n\n // key in position (1, 1)\n key[0].first.first = 1;\n key[0].first.second = 1;\n key[0].second = 0;\n\n // key in position (m, n)\n key[k + 1].first.first = m;\n key[k + 1].first.second = n;\n key[k + 1].second = k + 1;\n\n for(int i = 1; i <= k; i++){\n edge e;\n e.cost = 1;\n e.u = i + k + 2;\n adj[i].push_back(e);\n e.u = i;\n adj[i + k + 2].push_back(e);\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n for(int i = 0; i <= k + 1; i++){\n swap(key[i].first.first, key[i].first.second);\n key[i].second += k + 2;\n }\n\n sort(key, key + k + 2);\n\n for(int i = 0; i <= k; i++){\n if(key[i].first.first == key[i + 1].first.first){\n edge e;\n e.cost = abs(key[i + 1].first.second - key[i].first.second);\n e.u = key[i + 1].second;\n adj[key[i].second].push_back(e);\n e.u = key[i].second;\n adj[key[i + 1].second].push_back(e);\n }\n }\n\n dijkstra(0);\n int ans = min(dist[k+1], dist[2 * k + 3]);\n\n if(ans == 1e9)\n cout << -1 << \"\\n\";\n else\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 0.7419354838709677, "time_ms": 230, "memory_kb": 90180, "score_of_the_acc": -0.6889, "final_rank": 17 }, { "submission_id": "aoj_0605_9488116", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <functional>\n\nusing namespace std;\n\n#define int long long\n#define MP make_pair\n#define PB push_back\n#define FI first\n#define SE second\n#define MAX_K 200000\ntypedef pair<int, pair<int, int> > PPII;\ntypedef pair<int, int> PII;\nstatic const int INF = 1ll << 60;\nstatic const int dx[] = { 1, -1, 0, 0 };\nstatic const int dy[] = { 0, 0, 1, -1 };\n\nint M, N, K;\nvector<PII> fld, X, Y;\nint D[MAX_K + 5];\nbool flg = false;\n\n// ダイクストラアルゴリズムによる最短距離計算\nvoid dijkstra() {\n priority_queue<PPII, vector<PPII>, greater<PPII> > que;\n fill(D, D + MAX_K + 5, INF);\n D[0] = 0;\n que.push(PPII(0, PII(0, 0)));\n \n while (!que.empty()) {\n PPII p = que.top();\n que.pop();\n int v = p.SE.FI;\n int On = p.SE.SE;\n \n if (D[v] < p.FI) continue;\n if (fld[v].FI == M && fld[v].SE == N) break;\n\n int p1 = lower_bound(X.begin(), X.end(), PII(fld[v].FI, fld[v].SE)) - X.begin();\n int p2 = lower_bound(Y.begin(), Y.end(), PII(fld[v].SE, fld[v].FI)) - Y.begin();\n \n for (int i = p1 - 1; i <= p1 + 1; i++) {\n if (p1 == X.size()) break;\n if (i < 0 || i >= X.size()) continue;\n int t = lower_bound(fld.begin(), fld.end(), PII(X[i].FI, X[i].SE)) - fld.begin();\n PII e = fld[t];\n if (fld[v].FI != e.FI) continue;\n if ((!flg) && e.FI == 1 && e.SE == 1) continue;\n if (fld[v].FI != e.FI && fld[v].SE != e.SE) continue;\n int cost = abs(e.FI - fld[v].FI) + abs(e.SE - fld[v].SE);\n if (On == 1) cost++;\n if (D[t] > D[v] + cost) {\n D[t] = D[v] + cost;\n que.push(PPII(D[t], MP(t, 0)));\n }\n }\n \n for (int i = p2 - 1; i <= p2 + 1; i++) {\n if (flg == false && fld[v].FI == 1 && fld[v].SE == 1) break;\n if (p2 == Y.size()) break;\n if (i < 0 || i >= Y.size()) continue;\n int t = lower_bound(fld.begin(), fld.end(), PII(Y[i].SE, Y[i].FI)) - fld.begin();\n PII e = fld[t];\n if (fld[v].SE != e.SE) continue;\n if ((!flg) && e.FI == 1 && e.SE == 1) continue;\n if (fld[v].FI != e.FI && fld[v].SE != e.SE) continue;\n int cost = abs(e.FI - fld[v].FI) + abs(e.SE - fld[v].SE);\n if (On == 0) cost++;\n if (D[t] > D[v] + cost) {\n D[t] = D[v] + cost;\n que.push(PPII(D[t], MP(t, 1)));\n }\n }\n }\n}\n\nsigned main() {\n cin >> M >> N >> K;\n fld.PB(PII(1, 1));\n fld.PB(PII(M, N));\n X.PB(PII(1, 1));\n Y.PB(PII(1, 1));\n X.PB(PII(M, N));\n Y.PB(PII(N, M));\n \n for (int i = 0; i < K; ++i) {\n int x, y;\n cin >> x >> y;\n if (x == 1 && y == 1) {\n flg = true;\n continue;\n }\n if (x == M && y == N) continue;\n fld.PB(PII(x, y));\n X.PB(PII(x, y));\n Y.PB(PII(y, x));\n }\n \n sort(fld.begin(), fld.end());\n sort(X.begin(), X.end());\n sort(Y.begin(), Y.end());\n \n dijkstra();\n \n int ans = lower_bound(fld.begin(), fld.end(), MP(M, N)) - fld.begin();\n if (D[ans] >= INF) cout << -1 << endl;\n else cout << D[ans] << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 19008, "score_of_the_acc": -0.2912, "final_rank": 1 }, { "submission_id": "aoj_0605_6374279", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w,k);\n vector<vector<pair<int,int>>> Y(h),X(w);\n vector<vector<pair<int,int>>> g(2*k+2);\n Y[0].emplace_back(0,2*k);\n //X[0].emplace_back(0,2*k);\n Y[h-1].emplace_back(w-1,2*k+1);\n X[w-1].emplace_back(h-1,2*k+1);\n int y,x,x1,x2,y1,y2;\n rep(i,k){\n in(y,x);\n y--,x--;\n Y[y].emplace_back(x,i);\n X[x].emplace_back(y,k+i);\n g[i].emplace_back(k+i,1);\n g[k+i].emplace_back(i,1);\n }\n rep(y,h){\n sort(all(Y[y]));\n for(int i=0;i+1<Y[y].size();i++){\n tie(x1,y1)=Y[y][i];\n tie(x2,y2)=Y[y][i+1];\n g[y1].emplace_back(y2,x2-x1);\n g[y2].emplace_back(y1,x2-x1);\n }\n }\n rep(x,w){\n sort(all(X[x]));\n for(int i=0;i+1<X[x].size();i++){\n tie(x1,y1)=X[x][i];\n tie(x2,y2)=X[x][i+1];\n g[y1].emplace_back(y2,x2-x1);\n g[y2].emplace_back(y1,x2-x1);\n }\n }\n vector<ll> dist(2*k+2,INF2);\n ll d;\n int v;\n rpriority_queue<pair<ll,int>> pq;\n dist[2*k]=0;\n pq.push({0,2*k});\n while(!pq.empty()){\n tie(d,v)=pq.top();\n pq.pop();\n if(d>dist[v])continue;\n for(auto p:g[v]){\n if(d+p.second>=dist[p.first])continue;\n dist[p.first]=d+p.second;\n pq.push({dist[p.first],p.first});\n }\n }\n out(dist.back()==INF2?-1:dist.back());\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 46940, "score_of_the_acc": -0.4135, "final_rank": 2 }, { "submission_id": "aoj_0605_6291379", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e10;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\ntemplate<typename T = ll>\nstruct Edge {\n ll from, to; T cost;\n Edge (ll from, ll to, T cost = 1) : from(from), to(to), cost(cost) {}\n};\ntemplate<typename T = ll>\nstruct Graph {\n vector<vector<Edge<T>>> G;\n Graph() = default;\n explicit Graph(ll N) : G(N) {}\n size_t size() const {\n return G.size();\n }\n void add_edge(ll from, ll to, T cost = 1, bool direct = false) {\n G[from].emplace_back(from, to, cost);\n if (!direct) G[to].emplace_back(to, from, cost);\n }\n void read(ll M, ll padding = -1, bool weight = false, bool direct = false) {\n for (ll i = 0; i < M; i++) {\n ll a, b; cin >> a >> b;\n a += padding;\n b += padding;\n T c = T(1);\n if (weight) cin >> c;\n add_edge(a, b, c, direct);\n }\n }\n vector<Edge<T>> &operator[](const int &k) {\n return G[k];\n }\n};\nvoid dijkstra(const Graph<long long>& G, int s, vector<long long>& dis) {\n int N = G.size();\n dis.resize(N, INF);\n priority_queue<P, vector<P>, greater<P>> pq;\n dis[s] = 0;\n pq.emplace(dis[s], s);\n while (!pq.empty()) {\n P p = pq.top();\n pq.pop();\n int v = p.second;\n if (dis[v] < p.first) {\n continue;\n }\n for (auto& e : G.G[v]) {\n if (dis[e.to] > dis[v] + e.cost) {\n dis[e.to] = dis[v] + e.cost;\n pq.emplace(dis[e.to], e.to);\n }\n }\n }\n}\nvoid solve() {\n ll M, N, K; cin >> M >> N >> K;\n Graph<ll>G(2 * K + 2);\n vector<P>X(K); input_arr(X, K);\n vector<pair<P, ll>>A(K);\n for (ll i = 0; i < K; i++) {\n A[i] = {X[i], i + 1};\n G.add_edge(i + 1, K + i + 1, 1);\n if (X[i].first == 1) G.add_edge(0, i + 1, abs(X[i].second - 1));\n if (X[i].first == M) G.add_edge(i + 1, 2 * K + 1, abs(X[i].second - N));\n if (X[i].second == N) G.add_edge(K + i + 1, 2 * K + 1, abs(X[i].first - M));\n }\n sort(A.begin(), A.end());\n for (ll i = 0; i < K - 1; i++) {\n if (A[i].first.first == A[i + 1].first.first) G.add_edge(A[i].second, A[i + 1].second, abs(A[i].first.second - A[i + 1].first.second));\n }\n for (ll i = 0; i < K; i++) {\n swap(A[i].first.first, A[i].first.second);\n }\n sort(A.begin(), A.end());\n for (ll i = 0; i < K - 1; i++) {\n if (A[i].first.first == A[i + 1].first.first) G.add_edge(A[i].second + K, A[i + 1].second + K, abs(A[i].first.second - A[i + 1].first.second));\n }\n vector<ll>dist(2 * K + 2, INF);\n dijkstra(G, 0, dist);\n if (dist[2 * K + 1] == INF) cout << -1 << endl;\n else cout << dist[2 * K + 1] << endl;\n}\nint main() {\n ll T=1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 70084, "score_of_the_acc": -0.6276, "final_rank": 7 }, { "submission_id": "aoj_0605_5159891", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 10000000000000000;\n\ntypedef pair <ll, ll> P;\nstruct status {\n\tbool ok;\n\tll x;\n\tll y;\n\tll cost;\n\n\tbool operator<(const status& rhs) const { return cost < rhs.cost; };\n\tbool operator>(const status& rhs) const { return cost > rhs.cost; };\n};\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\t//問題と縦横が逆ぎゃっぶぶぶぶぶっくしでゅ\n\t//input\n\tll m, n, k; cin >> m >> n >> k;\n\tvector<ll> x(k), y(k); vector<vector<P>> tate(m + 2), yoko(n + 2);\n\tbool first = false;\n\trep(i, k) {\n\t\tcin >> x[i] >> y[i]; tate[x[i]].push_back(P(y[i], i)); yoko[y[i]].push_back(P(x[i], i));\n\t\tif (x[i] == 1 && y[i] == 1) { first = true; }\n\t}\n\tif (!first) { tate[1].push_back(P(1, k)); yoko[1].push_back(P(1, k)); }\n\n\tll ans = INF;\n\tvector<ll> d(k + 1, INF);\n\tpriority_queue<status, vector<status>, greater<status> >que;\n\tque.push({ true, m, n, 0 }); que.push({ false, m, n, 0 });\n\twhile (que.size()) {\n\t\tbool flag = que.top().ok;\n\t\tll px = que.top().x, py = que.top().y, c = que.top().cost; que.pop();\n\t\tif (px == 1 && py == 1) {\n\t\t\tif (flag) { ans = min(ans, c - 1); }\n\t\t\tif (!flag && first) { ans = min(ans, c); }\n\t\t\tcontinue;\n\t\t}\n\t\tif (!flag) {//yoko->tate\n\t\t\trep(i, tate[px].size()) {\n\t\t\t\tll cnt = c + abs(py - tate[px][i].first) + 1;\n\t\t\t\tif (py != tate[px][i].first && cnt < d[tate[px][i].second]) {\n\t\t\t\t\td[tate[px][i].second] = cnt;\n\t\t\t\t\tque.push({ true, px, tate[px][i].first, cnt });\n\t\t\t\t\t//cout << px << ' ' << py << ' ' << px << ' ' << tate[px][i].first << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {//tate->yoko\n\t\t\trep(i, yoko[py].size()) {\n\t\t\t\tll cnt = c + abs(px - yoko[py][i].first) + 1;\n\t\t\t\tif (px != yoko[py][i].first && cnt < d[yoko[py][i].second]) {\n\t\t\t\t\td[yoko[py][i].second] = cnt;\n\t\t\t\t\tque.push({ false, yoko[py][i].first, py, cnt });\n\t\t\t\t\t//cout << ' ' << px << ' ' << py << ' ' << yoko[py][i].first << ' ' << py << endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (ans == INF) { cout << \"-1\\n\"; return 0; }\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 38008, "score_of_the_acc": -0.49, "final_rank": 5 }, { "submission_id": "aoj_0605_4984142", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nvector<pair<int,int>> g[400100];\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint m,n; cin >> m >> n;\n\tint k; cin >> k;\n\tvector<vector<pair<int,int>>> tate(m,vector<pair<int,int>>());\n\tvector<vector<pair<int,int>>> yoko(n,vector<pair<int,int>>());\n\tfor(int i=0;i<k;i++){\n\t\tint x,y; cin >> x >> y;\n\t\tx--; y--;\n\t\ttate[x].push_back({y,i});\n\t\tyoko[y].push_back({x,i});\n\t}\n\ttate[m-1].push_back({n-1,k});\n\tyoko[n-1].push_back({m-1,k});\n\tk++;\n\tfor(int i=0;i<m;i++){\n\t\tsort(tate[i].begin(), tate[i].end());\n\t\tfor(int j=1;j<tate[i].size();j++){\n\t\t\tauto p=tate[i][j-1],pp=tate[i][j];\n\t\t\tg[p.second*2].push_back({pp.second*2,pp.first-p.first});\n\t\t\tg[pp.second*2].push_back({p.second*2,pp.first-p.first});\n\t\t}\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tsort(yoko[i].begin(), yoko[i].end());\n\t\tfor(int j=1;j<yoko[i].size();j++){\n\t\t\tauto p=yoko[i][j-1],pp=yoko[i][j];\n\t\t\tg[p.second*2+1].push_back({pp.second*2+1,pp.first-p.first});\n\t\t\tg[pp.second*2+1].push_back({p.second*2+1,pp.first-p.first});\n\t\t}\n\t}\n\tfor(int i=0;i<k;i++){\n\t\tg[i*2].push_back({i*2+1,1});\n\t\tg[i*2+1].push_back({i*2,1});\n\t}\n\tvector<ll> dp(2*k,1e18);\n\tpriority_queue<pair<ll,int>> pq;\n\tfor(auto p:tate[0]){\n\t\tdp[p.second*2]=p.first;\n\t\tpq.push({-dp[p.second*2],p.second*2});\n\t}\n\twhile(pq.size()){\n\t\tauto p=pq.top(); pq.pop();\n\t\tif(-p.first!=dp[p.second])continue;\n\t\tfor(auto to:g[p.second]){\n\t\t\tif(dp[to.first]>dp[p.second]+to.second){\n\t\t\t\tdp[to.first]=dp[p.second]+to.second;\n\t\t\t\tpq.push({-dp[to.first],to.first});\n\t\t\t}\n\t\t}\n\t}\n\tll res=min(dp[2*k-1],dp[2*k-2]);\n\tif(res==1e18)res=-1;\n\tcout << res << endl;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 46440, "score_of_the_acc": -0.4437, "final_rank": 3 }, { "submission_id": "aoj_0605_4984141", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nvector<pair<int,int>> g[400100];\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint m,n; cin >> m >> n;\n\tint k; cin >> k;\n\tvector<vector<pair<int,int>>> tate(m,vector<pair<int,int>>());\n\tvector<vector<pair<int,int>>> yoko(n,vector<pair<int,int>>());\n\tfor(int i=0;i<k;i++){\n\t\tint x,y; cin >> x >> y;\n\t\tx--; y--;\n\t\ttate[x].push_back({y,i});\n\t\tyoko[y].push_back({x,i});\n\t}\n\ttate[m-1].push_back({n-1,k});\n\tyoko[n-1].push_back({m-1,k});\n\tk++;\n\tfor(int i=0;i<m;i++){\n\t\tsort(tate[i].begin(), tate[i].end());\n\t\tfor(int j=1;j<tate[i].size();j++){\n\t\t\tauto p=tate[i][j-1],pp=tate[i][j];\n\t\t\tg[p.second*2].push_back({pp.second*2,pp.first-p.first});\n\t\t\tg[pp.second*2].push_back({p.second*2,pp.first-p.first});\n\t\t}\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tsort(yoko[i].begin(), yoko[i].end());\n\t\tfor(int j=1;j<yoko[i].size();j++){\n\t\t\tauto p=yoko[i][j-1],pp=yoko[i][j];\n\t\t\tg[p.second*2+1].push_back({pp.second*2+1,pp.first-p.first});\n\t\t\tg[pp.second*2+1].push_back({p.second*2+1,pp.first-p.first});\n\t\t}\n\t}\n\tfor(int i=0;i<k;i++){\n\t\tg[i*2].push_back({i*2+1,1});\n\t\tg[i*2+1].push_back({i*2,1});\n\t}\n\tvector<int> dp(2*k,1e9);\n\tpriority_queue<pair<int,int>> pq;\n\tfor(auto p:tate[0]){\n\t\tdp[p.second*2]=p.first;\n\t\tpq.push({-dp[p.second*2],p.second*2});\n\t}\n\twhile(pq.size()){\n\t\tauto p=pq.top(); pq.pop();\n\t\tif(-p.first!=dp[p.second])continue;\n\t\tfor(auto to:g[p.second]){\n\t\t\tif(dp[to.first]>dp[p.second]+to.second){\n\t\t\t\tdp[to.first]=dp[p.second]+to.second;\n\t\t\t\tpq.push({-dp[to.first],to.first});\n\t\t\t}\n\t\t}\n\t}\n\tint res=min(dp[2*k-1],dp[2*k-2]);\n\tif(res==1e9)res=-1;\n\tcout << res << endl;\n}", "accuracy": 0.7419354838709677, "time_ms": 240, "memory_kb": 44544, "score_of_the_acc": -0.4094, "final_rank": 15 }, { "submission_id": "aoj_0605_4952821", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <map>\n#include <set>\n#include <numeric>\n#include <iomanip>\n#include <stack>\n#include <tuple>\n\nusing namespace std;\n\nusing ll = long long;\n\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\n\nconst int inf = (1 << 30) - 1;\nconst ll infll = 1LL << 60;\n\nstruct Edge {\n ll from; // 移動前のノード\n ll to; // 移動先のノード\n ll cost; // 辺のコスト\n ll hoge; // 任意変更 いらないかも\n\n Edge() = default;\n Edge(ll _to) : from(-1), to(_to), cost(1), hoge(-1) {};\n Edge(ll _to, ll _cost) : from(-1), to(_to), cost(_cost), hoge(-1) {};\n Edge(ll _from, ll _to, ll _cost) : from(_from), to(_to), cost(_cost), hoge(-1) {};\n Edge(ll _from, ll _to, ll _cost, ll _hoge) : from(_from), to(_to), cost(_cost), hoge(_hoge) {};\n bool operator< (const Edge& rhs) const {\n return cost < rhs.cost;\n }\n bool operator> (const Edge& rhs) const {\n return cost > rhs.cost;\n }\n bool operator==(const Edge& rhs) const {\n if (from != rhs.from) return false;\n if (to != rhs.to) return false;\n if (cost != rhs.cost) return false;\n if (hoge != rhs.hoge) return false;\n return true;\n }\n bool operator!=(const Edge& rhs) const {\n if (from != rhs.from) return true;\n if (to != rhs.to) return true;\n if (cost != rhs.cost) return true;\n if (hoge != rhs.hoge) return true;\n return false;\n }\n};\n\nusing Graph = vector<vector<Edge>>;\n\n\n// ダイクストラ法 O(ElogV)\nvector<ll> dijkstra(ll start, const Graph& G) {\n vector<ll> dist(G.size(), infll);\n // 辺のコストが小さい順に取り出す 場合に応じて変更\n priority_queue<Edge, vector<Edge>, greater<Edge>> que;\n //queue<Edge> que; // コストがすべて1の場合は普通のbfsにする コメントアウトしよう\n\n dist[start] = 0; // dist[i] := start->iまでの最短距離\n que.push(Edge(start, 0));\n\n while (!que.empty()) {\n ll cost, u; // 今までにかかった時間 現在の頂点\n cost = que.top().cost, u = que.top().to;\n //cost = que.front().cost, u = que.front().to;\n que.pop();\n if (dist[u] < cost) continue;\n for (auto& e : G[u]) {\n ll v = e.to;\n ll new_cost = cost + e.cost;\n\n if (dist[v] <= new_cost) continue;\n\n dist[v] = new_cost;\n que.push(Edge(v, new_cost));\n }\n }\n return dist;\n}\n\n\nint main() {\n\n int m, n, k;\n cin >> m >> n >> k;\n vector<set<int>> vx(100001, set<int>());\n vector<set<int>> vy(100001, set<int>());\n\n\n Graph G((2 + k) * 2); // スタート,ゴール,スイッチ * 2\n const int geta = 2 + k;\n\n // 前半が縦に開いている 後半が横に開いている\n\n vector<pair<int, int>> xy(k);\n map<pair<int, int>, int> mp;\n\n for (int i = 0; i < k; ++i) {\n int x, y;\n cin >> x >> y;\n vx[x].emplace(y);\n vy[y].emplace(x);\n xy[i] = { x, y };\n mp[{x, y}] = i;\n }\n\n if (m == 1) {\n cout << n << endl;\n return 0;\n }\n\n // エッジを貼る\n\n for (int i = 0; i < k; ++i) {\n // このスイッチから行ける場所\n int x = xy[i].first;\n int y = xy[i].second;\n // 同じ階層\n {\n auto itr = vx[x].lower_bound(y);\n if (next(itr) != vx[x].end()) {\n int ty = *next(itr);\n int id = mp[{x, ty}];\n if (i != id) {\n G[i].emplace_back(id, abs(xy[id].second - y));\n G[id].emplace_back(i, abs(xy[id].second - y));\n }\n }\n if (itr != vx[x].begin()) {\n int ty = *prev(itr);\n int id = mp[{x, ty}];\n if (i != id) {\n G[i].emplace_back(id, abs(xy[id].second - y));\n G[id].emplace_back(i, abs(xy[id].second - y));\n }\n }\n }\n\n // 同じ階層\n {\n auto itr = vy[y].lower_bound(x);\n if (next(itr) != vy[y].end()) {\n int tx = *next(itr);\n int id = mp[{tx, y}];\n if (i != id) {\n G[i + geta].emplace_back(id + geta, abs(xy[id].first - x));\n G[id + geta].emplace_back(i + geta, abs(xy[id].first - x));\n }\n }\n if (itr != vy[y].begin()) {\n int tx = *prev(itr);\n int id = mp[{tx, y}];\n if (i != id) {\n G[i + geta].emplace_back(id + geta, abs(xy[id].first - x));\n G[id + geta].emplace_back(i + geta, abs(xy[id].first - x));\n }\n }\n }\n\n G[i].emplace_back(i + geta, 1);\n G[i + geta].emplace_back(i, 1);\n }\n\n // スタート\n {\n int x = 1;\n int y = 1;\n\n int i = k;\n\n if (vx[x].size()) {\n int ty = *vx[x].begin();\n int id = mp[{x, ty}];\n\n if (i != id) {\n G[i].emplace_back(id, abs(xy[id].second - y));\n G[id].emplace_back(i, abs(xy[id].second - y));\n }\n }\n\n if (vy[y].size()) {\n int tx = *vy[y].begin();\n int id = mp[{tx, y}];\n if (i != id) {\n G[i + geta].emplace_back(id + geta, abs(xy[id].first - x));\n G[id + geta].emplace_back(i + geta, abs(xy[id].first - x));\n }\n }\n }\n\n // ゴール\n {\n int x = m;\n int y = n;\n\n int i = k + 1;\n\n if (vx[x].size()) {\n int ty = *prev(vx[x].end());\n int id = mp[{x, ty}];\n if (i != id) {\n G[i].emplace_back(id, abs(xy[id].second - y));\n G[id].emplace_back(i, abs(xy[id].second - y));\n }\n }\n if (vy[y].size()) {\n int tx = *prev(vy[y].end());\n int id = mp[{tx, y}];\n if (i != id) {\n G[i + geta].emplace_back(id + geta, abs(xy[id].first - x));\n G[id + geta].emplace_back(i + geta, abs(xy[id].first - x));\n }\n }\n }\n\n auto dist = dijkstra(k, G);\n\n ll ans = min(dist[k + 1], dist[k + 1 + geta]);\n if (ans == infll) ans = -1;\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 940, "memory_kb": 172204, "score_of_the_acc": -2, "final_rank": 14 }, { "submission_id": "aoj_0605_4952683", "code_snippet": "#include <iostream>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <cassert>\n\nusing namespace std;\n\nusing lint = long long int;\nconst lint INF = 1e16;\n\ntemplate<typename T>\nvector<pair<T, int>> dijkstra(vector<vector<pair<int, T>>> &g, int s) {\n int n = g.size();\n\n const auto inf = INF;\n vector<pair<T, int>> dist(n, {inf, -1});\n\n using P = pair<T, int>;\n\n priority_queue<P, vector<P>, greater<P>> que;\n dist[s] = {0, -1};\n que.emplace(dist[s].first, s);\n while (!que.empty()) {\n T cost;\n int node;\n tie(cost, node) = que.top();\n que.pop();\n if (dist[node].first < cost) continue;\n for (auto &e : g[node]) {\n auto next_cost = cost + e.second;\n int next_node = e.first;\n if (dist[next_node].first <= next_cost) continue;\n dist[next_node] = {next_cost, node};\n que.emplace(next_cost, next_node);\n }\n }\n\n return dist;\n}\n\nint main() {\n\n int m, n, k; cin >> m >> n >> k;\n vector<set<int>> x(m);\n vector<set<int>> y(n);\n vector<int> X(k);\n vector<int> Y(k);\n map<pair<int, int>, int> mp;\n for (int i = 0; i < k; i++) {\n cin >> X[i] >> Y[i];\n X[i]--;\n Y[i]--;\n x[X[i]].insert(Y[i]);\n y[Y[i]].insert(X[i]);\n mp[{X[i], Y[i]}] = i;\n }\n\n vector<vector<int>> toNode(k, vector<int>(2));\n int node = 0;\n for (int i = 0; i < k; i++) {\n for (int j = 0; j < 2; j++) {\n toNode[i][j] = node;\n node++;\n }\n }\n\n vector<vector<pair<int, lint>>> g(node + 1);\n for (int i = 0; i < k; i++) {\n for (int f = 0; f < 2; f++) {\n\n {\n // スイッチを切り替える\n int cur_node = toNode[i][f];\n int next_node = toNode[i][1 - f];\n lint cost = 1;\n g[cur_node].push_back({next_node, cost});\n }\n\n if (f == 0) {\n // 上下に移動できる\n int cx = X[i];\n int cy = Y[i];\n assert((mp[{cx, cy}] == i));\n int cur_node = toNode[mp[{cx, cy}]][f];\n auto itr = x[cx].lower_bound(cy);\n \n auto nxt = itr;\n nxt++;\n if (nxt != x[cx].end()) {\n int nx = cx;\n int ny = *nxt;\n int next_node = toNode[mp[{nx, ny}]][f];\n lint cost = (lint)abs(ny - cy);\n g[cur_node].push_back({next_node, cost});\n }\n\n auto prev = itr;\n if (prev != x[cx].begin()) {\n prev--;\n int nx = cx;\n int ny = *prev;\n int next_node = toNode[mp[{nx, ny}]][f];\n lint cost = (lint)abs(ny - cy);\n g[cur_node].push_back({next_node, cost});\n }\n\n } else {\n int cx = X[i];\n int cy = Y[i];\n assert((mp[{cx, cy}] == i));\n int cur_node = toNode[mp[{cx, cy}]][f];\n auto itr = y[cy].lower_bound(cx);\n\n auto nxt = itr;\n nxt++;\n if (nxt != y[cy].end()) {\n int nx = *nxt;\n int ny = cy;\n int next_node = toNode[mp[{nx, ny}]][f];\n lint cost = (lint)abs(nx - cx);\n g[cur_node].push_back({next_node, cost});\n }\n\n auto prev = itr;\n if (prev != y[cy].begin()) {\n prev--;\n int nx = *prev;\n int ny = cy;\n int next_node = toNode[mp[{nx, ny}]][f];\n lint cost = (lint)abs(nx - cx);\n g[cur_node].push_back({next_node, cost});\n }\n }\n }\n }\n\n // スーパーノード node\n for (int i = 0; i < k; i++) {\n if (X[i] != 0) continue;\n lint cost = Y[i];\n int next_node = toNode[mp[{X[i], Y[i]}]][0];\n g[node].push_back({next_node, cost});\n }\n\n auto dist = dijkstra(g, node);\n lint ans = INF;\n for (int i = 0; i < k; i++) {\n for (int f = 0; f < 2; f++) {\n if (X[i] == m - 1 and f == 0) {\n lint next_node = toNode[mp[{X[i], Y[i]}]][f];\n if (dist[next_node].first != INF) {\n lint cost = dist[next_node].first + n - 1 - Y[i];\n // cerr << \"cost = \" << cost << endl;\n ans = min(ans, cost);\n }\n }\n if (Y[i] == n - 1 and f == 1) {\n lint next_node = toNode[mp[{X[i], Y[i]}]][f];\n if (dist[next_node].first != INF) {\n lint cost = dist[next_node].first + m - 1 - X[i];\n // cerr << \"cost = \" << cost << endl;\n ans = min(ans, cost);\n }\n }\n }\n }\n\n if (ans >= INF) {\n cout << -1 << endl;\n } else {\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 830, "memory_kb": 102708, "score_of_the_acc": -1.4353, "final_rank": 13 }, { "submission_id": "aoj_0605_4952666", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define pp pair<int,int>\n#define rep(i,n) for(int (i)=0;(i)<(n);(i)++)\n#define ll long long\n#define ld long double\n#define all(a) (a).begin(),(a).end()\n#define mk make_pair\nll MOD=1000000007;\nll mod=998244353;\nint inf=1000001000;\nll INF=1e18+5;\n\n\nint main() {\n int n,m,k;\n cin >> m >> n >> k;\n int d[m][n][2];\n rep(i,m){\n rep(j,n){\n rep(ii,2) d[i][j][ii]=inf;\n }\n }\n d[0][0][0]=0;\n vector<vector<int>> a(m,vector<int>(n,0));\n rep(i,k){\n int f,g;\n cin >> f >> g;\n a[f-1][g-1]=1;\n }\n queue<pair<pair<int,int>,int>> q;\n q.push(mk(mk(0,0),0));\n while(!q.empty()){\n // cout << \"aaaaaa\" << endl;\n int f=q.front().first.first,g=q.front().first.second,h=q.front().second;\n // cout << f << \" \" << g << \" \" << h << endl;\n q.pop();\n if (h==0){\n if (g!=0){\n if (d[f][g-1][0]>d[f][g][0]+1){\n d[f][g-1][0]=d[f][g][0]+1;\n q.push(mk(mk(f,g-1),0));\n }\n }\n if (g!=n-1){\n if (d[f][g+1][0]>d[f][g][0]+1){\n d[f][g+1][0]=d[f][g][0]+1;\n q.push(mk(mk(f,g+1),0));\n }\n }\n }\n if (h==1){\n if (f!=0){\n if (d[f-1][g][1]>d[f][g][1]+1){\n d[f-1][g-1][1]=d[f][g][1]+1;\n q.push(mk(mk(f-1,g),1));\n }\n }\n if (f!=m-1){\n if (d[f+1][g][1]>d[f][g][1]+1){\n d[f+1][g][1]=d[f][g][1]+1;\n q.push(mk(mk(f+1,g),1));\n }\n }\n }\n if (a[f][g]==1){\n if (d[f][g][1-h]>d[f][g][h]+1){\n d[f][g][1-h]=d[f][g][h]+1;\n q.push(mk(mk(f,g),1-h));\n }}\n }\n // rep(i,n){\n // rep(j,m){\n // cout << d[j][i][1] << \" \";\n // }\n // cout << endl;\n // }\n int ans=min(d[m-1][n-1][0],d[m-1][n-1][1]);\n if (ans==inf) cout << -1 << endl;\n else cout << ans << endl;\n}", "accuracy": 0.0967741935483871, "time_ms": 40, "memory_kb": 15148, "score_of_the_acc": 0, "final_rank": 18 }, { "submission_id": "aoj_0605_4781623", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename T> struct wedge {\n int u, v; T w;\n wedge reverse() const { return {v, u, w}; }\n friend ostream& operator<<(ostream& os, const wedge& e) {\n return os << \"{u: \" << e.u << \", v: \" << e.v << \", w: \" << e.w << \"}\";\n }\n};\ntemplate <bool Directed, typename TEdge, bool Index> struct graph {\n using EType = TEdge;\n vector<TEdge> edges;\n vector<vector<int>> adj;\n graph(int n) : adj(n + Index) {}\n graph(int n, int m) : graph(n) { edges.reserve(m << not Directed); }\n TEdge& operator()(int e) { return edges[e]; }\n vector<int>& operator[](int u) { return adj[u]; }\n int size() { return adj.size() - Index; }\n void append(int u, const TEdge& e) {\n adj[u].push_back(edges.size());\n edges.push_back(e);\n }\n void add_edge(const TEdge& e) {\n append(e.u, e);\n if(not Directed) append(e.v, e.reverse());\n }\n};\ntemplate <bool Directed, typename T, bool Index>\npair<vector<T>, vector<int>> sssp(graph<Directed, wedge<T>, Index>& g, const vector<int>& s) {\n vector<int> vis(g.adj.size()), p(g.adj.size(), -1);\n vector<T> d(g.adj.size(), lim<T>::max());\n priority_queue<pair<T, int>> pq;\n for(int u : s) {\n pq.push({d[u] = 0, u});\n }\n while(not pq.empty()) {\n int u = pq.top().second; pq.pop();\n if(not vis[u]) {\n vis[u] = true;\n for(int e : g[u]) {\n if(not vis[g(e).v] and d[g(e).v] > d[u] + g(e).w) {\n pq.push({-(d[g(e).v] = d[u] + g(e).w), g(p[g(e).v] = e).v});\n }\n }\n }\n }\n return {d, p};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int m, n, k;\n cin >> m >> n >> k;\n vector<vector<vector<pair<int, int>>>> important_nodes_at_axis = {\n vector<vector<pair<int, int>>>(m + 1),\n vector<vector<pair<int, int>>>(n + 1)\n };\n int index = 0;\n auto insert_node = [&](int x, int y) {\n important_nodes_at_axis[0][x].push_back({y, index});\n important_nodes_at_axis[1][y].push_back({x, index});\n index += 2;\n };\n insert_node(1, 1);\n insert_node(m, n);\n for(int i = 0; i < k; i++) {\n int x, y;\n cin >> x >> y;\n insert_node(x, y);\n }\n graph<0, wedge<ll>, 0> g(index);\n for(int i = 4; i < index; i += 2) {\n g.add_edge({i, i ^ 1, 1});\n }\n for(int axis : {0, 1}) {\n for(auto& nodes : important_nodes_at_axis[axis]) {\n sort(nodes.begin(), nodes.end());\n for(int i = 0; i + 1 < nodes.size(); i++) {\n int ucoord, u;\n int vcoord, v;\n tie(ucoord, u) = nodes[i];\n tie(vcoord, v) = nodes[i + 1];\n g.add_edge({u ^ axis, v ^ axis, abs(ucoord - vcoord)});\n }\n }\n }\n auto d = sssp(g, {0}).first;\n ll ans = min(d[2], d[3]);\n cout << (ans == lim<ll>::max() ? -1 : ans) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 67600, "score_of_the_acc": -0.6562, "final_rank": 8 }, { "submission_id": "aoj_0605_4198563", "code_snippet": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include <cstdlib> \n#include <math.h>\n#include <cmath>\n#include<complex>\n#include<cctype>\n#include<string>\n#include<set>\n#include<iomanip>\n#include <map>\n#include<algorithm>\n#include <functional>\n#include<vector>\n#include<climits>\n#include<stack>\n#include<queue>\n#include<bitset>\n#include <deque>\n#include <climits>\n#include <typeinfo>\n#include <utility> \nusing namespace std;\nusing Complex = complex<double>;\nusing ll = long long;\ntemplate<typename T>using min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst ll inf = 1145141919810364364LL;\ndouble PI = acos(-1.0);\n#define all(x) (x).begin(),(x).end()\n#define puts(x) cout << x << endl\n#define rep(i,m,n) for(ll i = m;i < n;++i)\n#define pb push_back\n#define fore(i,a) for(auto &i:a)\n#define rrep(i,m,n) for(ll i = m;i >= n;--i)\n\nint N,M,K;\nvector<int>Ex[101010],Ey[101010];\nll dist[1000000];\nmap<vector<int>,int>mp;\nvector<pair<int, int>>Enew[1000000];\n\nvoid dijkstra() {\n\tfor (int i = 0; i < 1000000;i++)dist[i] = inf;\n\tmin_priority_queue<pair<ll,int>>q;\n\tint idx = mp[{0, 0, 0}];\n\tq.push({0,idx});\n\twhile (q.size()) {\n\t\tauto p = q.top();\n\t\tq.pop();\n\t\tll d = p.first;\n\t\tint v = p.second;\n\t\tfore(x, Enew[v]) {\n\t\t\tint to = x.first;\n\t\t\tll cost = x.second;\n\n\t\t\tif (dist[to] > d + cost) {\n\t\t\t\tq.push({d+cost,to});\n\t\t\t\tdist[to] = d + cost;\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\n\tcin >> M >> N >> K;\n\tint fl0 = 0;\n\tint fl1 = 0;\n\tfor (int i = 0; i < K; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tx--, y--;\n\t\tEx[x].pb(y);\n\t\tEy[y].pb(x);\n\t\tif (x == 0 && y == 0)fl0 = 1;\n\t\tif (x == M - 1 && y == N - 1)fl1 = 1;\n\t}\n\tif (!fl0) { Ex[0].pb(0); }\n\tif (!fl1) { \n\t\tEx[M - 1].pb(N - 1); \n\t\tEy[N - 1].pb(M - 1);\n\t}\n\n\tfor (int i = 0; i < 101010; i++)sort(all(Ex[i]));\n\tfor (int i = 0; i < 101010; i++)sort(all(Ey[i]));\n\n\tint cnt = 0;\n\tfor (int i = 0; i < 101010; i++) {\n\t\tfore(x, Ex[i]) {\n\t\t\tif (fl0 == 0 && i == 0 && x == 0) {\n\t\t\t\tmp[{0,0,0}] = cnt;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tmp[{i,x,0}] = cnt;\n\t\t\t\tcnt++;\n\t\t\t\tmp[{i,x,1}] = cnt;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i < 101010; i++) {\n\t\tfor (int j = 0; j + 1 < Ex[i].size(); j++) {\n\t\t\tint num1 = mp[{i,Ex[i][j],0}];\n\t\t\tint num2 = mp[{i,Ex[i][j+1],0}];\n\t\t\tint diff = Ex[i][j + 1] - Ex[i][j];\n\t\t\tEnew[num1].pb({num2,diff});\n\t\t\tEnew[num2].pb({num1,diff});\n\t\t}\n\t}\n\tfor (int i = 0; i < 101010; i++) {\n\t\tfor (int j = 0; j + 1 < Ey[i].size(); j++) {\n\t\t\tint num1 = mp[{Ey[i][j],i, 1}];\n\t\t\tint num2 = mp[{Ey[i][j+1], i, 1}];\n\t\t\tint diff = Ey[i][j + 1] - Ey[i][j];\n\t\t\tEnew[num1].pb({ num2,diff });\n\t\t\tEnew[num2].pb({ num1,diff });\n\t\t}\n\t}\n\n\tfor (int i = 0; i < 101010; i++) {\n\t\tfore(x, Ex[i]) {\n\t\t\tif (fl0 == 0 && i == 0 && x == 0)continue;\n\t\t\tif (fl1 == 0 && i == M - 1 && x == N - 1)continue;\n\t\t\tint num1 = mp[{i, x, 0}];\n\t\t\tint num2 = mp[{i, x, 1}];\n\t\t\tEnew[num1].pb({ num2,1 });\n\t\t\tEnew[num2].pb({ num1,1 });\n\t\t}\n\t}\n\tdijkstra();\n\n\tll ans = min(dist[mp[{M - 1, N - 1, 0}]], dist[mp[{M - 1, N - 1, 1}]]);\n\tif (ans > 1e16)puts(-1);\n\telse puts(ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 105676, "score_of_the_acc": -1.2097, "final_rank": 12 }, { "submission_id": "aoj_0605_4152458", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<ll, ll>;\nusing P3 = pair<int,P>;\nusing PP = pair<P, P>;\nconstexpr ll INF = 1LL<<60;\nconstexpr ll MOD = ll(1e9)+7;\nconstexpr int di[] = {0,1,0,-1};\nconstexpr int dj[] = {1,0,-1,0};\n\n\nbool solve(){\n int m, n, k;\n cin >> m >> n >> k;\n vector<vector<P> > row(n), col(m), g((k+2)*2);\n for(int i=0;i<k;i++){\n int x, y;\n cin >> x >> y;\n x--; y--;\n row[y].emplace_back(P(x,i*2));\n col[x].emplace_back(P(y,i*2+1));\n g[i*2].emplace_back(P(i*2+1,1));\n g[i*2+1].emplace_back(P(i*2,1));\n }\n int S = k, G = k+1;\n col[0].emplace_back(P(0,S*2));\n row[n-1].emplace_back(P(m-1,G*2));\n col[m-1].emplace_back(P(n-1,G*2+1));\n for(int i=0;i<n;i++){\n sort(row[i].begin(), row[i].end());\n int t = row[i].size();\n for(int j=0;j<t-1;j++){\n int l = row[i][j].first, u = row[i][j].second;\n int r = row[i][j+1].first, v = row[i][j+1].second;\n g[u].emplace_back(P(v,r-l));\n g[v].emplace_back(P(u,r-l));\n }\n }\n for(int i=0;i<m;i++){\n sort(col[i].begin(),col[i].end());\n int t = col[i].size();\n for(int j=0;j<t-1;j++){\n int l = col[i][j].first, u = col[i][j].second;\n int r = col[i][j+1].first, v = col[i][j+1].second;\n g[u].emplace_back(P(v,r-l));\n g[v].emplace_back(P(u,r-l));\n }\n }\n vector<ll> d((k+2)*2, INF);\n priority_queue<P, vector<P>, greater<P> > que;\n d[S*2] = 0;\n que.push(P(0,S*2));\n while(!que.empty()){\n auto p = que.top();\n que.pop();\n int v = p.second;\n if(p.first > d[v]) continue;\n for(auto e : g[v]){\n ll u = e.first, cost = e.second;\n if(d[u] > d[v]+cost){\n d[u] = d[v]+cost;\n que.push(P(d[u],u));\n }\n }\n }\n ll ans = min(d[G*2], d[G*2+1]);\n cout << (ans < INF ? ans : -1) << endl;\n return true;\n}\n\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 62328, "score_of_the_acc": -0.7115, "final_rank": 9 }, { "submission_id": "aoj_0605_4149763", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll M,N,K;\nvector<P> G[500005];\nvector<P> lis_x[100005];\nvector<P> lis_y[100005];\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> M >> N >> K;\n\n lis_x[1].push_back(P(1,0));\n\n for (ll i = 0;i < K;i++){\n ll x,y; cin >> x >> y;\n lis_x[x].push_back(P(y,i+1));\n lis_y[y].push_back(P(x,i+1));\n }\n\n lis_x[M].push_back(P(N,K+1));\n lis_y[N].push_back(P(M,K+1));\n\n for (ll i = 0;i <= M;i++){\n if(!lis_x[i].size()) continue;\n sort(lis_x[i].begin(),lis_x[i].end());\n P p = lis_x[i][0];\n for (ll j = 1;j < lis_x[i].size();j++){\n //cout << i << \" \" << p.first << endl;\n G[p.second].push_back(P(lis_x[i][j].second,lis_x[i][j].first-p.first));\n G[lis_x[i][j].second].push_back(P(p.second,lis_x[i][j].first-p.first));\n p = lis_x[i][j];\n }\n //cout << endl;\n }\n\n for (ll i = 0;i <= N;i++){\n if(!lis_y[i].size()) continue;\n sort(lis_y[i].begin(),lis_y[i].end());\n P p = lis_y[i][0];\n for (ll j = 1;j < lis_y[i].size();j++){\n G[p.second+(K+2)].push_back(P(lis_y[i][j].second+(K+2),lis_y[i][j].first-p.first));\n G[lis_y[i][j].second+(K+2)].push_back(P(p.second+(K+2),lis_y[i][j].first-p.first));\n p = lis_y[i][j];\n }\n }\n\n for (ll i = 0;i <= K+2;i++){\n if(i%(K+2)){\n G[i].push_back(P(i+K+2,1));\n G[i+K+2].push_back(P(i,1));\n }\n }\n\n priority_queue<P,vector<P>, greater<P>> que;\n ll dist[500005];\n //fill(dist,dist+K*2+5,ll_MAX);\n for (ll i = 0;i < 500000;i++){\n dist[i] = LLONG_MAX;\n }\n dist[0] = 0;\n que.push(P(0,0));\n\n while(que.size()){\n P p = que.top(); que.pop();\n ll from = p.second;\n ll sum = p.first;\n if(dist[from] < sum) continue;\n //cout << from << \" \" << sum << endl;\n for (ll i = 0;i < G[from].size();i++){\n ll to = G[from][i].first;\n ll cost = G[from][i].second;\n if(dist[from]+cost < dist[to]){\n dist[to] = dist[from]+cost;\n que.push(P(dist[to],to));\n }\n }\n }\n\n ll ans = min(dist[K+1],dist[K+1+K+2]);\n if(ans == LLONG_MAX) ans = -1;\n\n cout << ans << endl;\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 68280, "score_of_the_acc": -0.6161, "final_rank": 6 }, { "submission_id": "aoj_0605_4149755", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint M,N,K;\nvector<P> G[500005];\nvector<P> lis_x[100005];\nvector<P> lis_y[100005];\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> M >> N >> K;\n\n lis_x[1].push_back(P(1,0));\n\n for (int i = 0;i < K;i++){\n int x,y; cin >> x >> y;\n lis_x[x].push_back(P(y,i+1));\n lis_y[y].push_back(P(x,i+1));\n }\n\n lis_x[M].push_back(P(N,K+1));\n lis_y[N].push_back(P(M,K+1));\n\n for (int i = 0;i <= M;i++){\n if(!lis_x[i].size()) continue;\n sort(lis_x[i].begin(),lis_x[i].end());\n P p = lis_x[i][0];\n for (int j = 1;j < lis_x[i].size();j++){\n //cout << i << \" \" << p.first << endl;\n G[p.second].push_back(P(lis_x[i][j].second,lis_x[i][j].first-p.first));\n G[lis_x[i][j].second].push_back(P(p.second,lis_x[i][j].first-p.first));\n p = lis_x[i][j];\n }\n //cout << endl;\n }\n\n for (int i = 0;i <= N;i++){\n if(!lis_y[i].size()) continue;\n sort(lis_y[i].begin(),lis_y[i].end());\n P p = lis_y[i][0];\n for (int j = 1;j < lis_y[i].size();j++){\n G[p.second+(K+2)].push_back(P(lis_y[i][j].second+(K+2),lis_y[i][j].first-p.first));\n G[lis_y[i][j].second+(K+2)].push_back(P(p.second+(K+2),lis_y[i][j].first-p.first));\n p = lis_y[i][j];\n }\n }\n\n for (int i = 0;i <= K+2;i++){\n if(i%(K+2)){\n G[i].push_back(P(i+K+2,1));\n G[i+K+2].push_back(P(i,1));\n }\n }\n\n priority_queue<P,vector<P>, greater<P>> que;\n int dist[500005];\n //fill(dist,dist+K*2+5,INT_MAX);\n for (int i = 0;i < 500000;i++){\n dist[i] = INT_MAX;\n }\n dist[0] = 0;\n que.push(P(0,0));\n\n while(que.size()){\n P p = que.top(); que.pop();\n int from = p.second;\n int sum = p.first;\n if(dist[from] < sum) continue;\n //cout << from << \" \" << sum << endl;\n for (int i = 0;i < G[from].size();i++){\n int to = G[from][i].first;\n int cost = G[from][i].second;\n if(dist[from]+cost < dist[to]){\n dist[to] = dist[from]+cost;\n que.push(P(dist[to],to));\n }\n }\n }\n\n int ans = min(dist[K+1],dist[K+1+K+2]);\n if(ans == INT_MAX) ans = -1;\n\n cout << ans << endl;\n\n return 0;\n\n}", "accuracy": 0.7419354838709677, "time_ms": 250, "memory_kb": 48376, "score_of_the_acc": -0.4449, "final_rank": 16 }, { "submission_id": "aoj_0605_4082616", "code_snippet": "#include<iostream>\n#include<cstdlib>\n#include<vector>\n#include<queue>\n#include<algorithm>\n\nusing namespace std;\n\ntypedef pair<int,int> PA;\ntypedef pair<long long,int> PAL;\ntypedef pair<PAL,int> PPA;\n\nconst long long INF = 1000010000100001;\n\nint m,n,k;\n\nvector<PA> vx[100010],vy[100010];\nvector<PA> tate[200010],yoko[200010];\nlong long min_cost[2][200010];\n\nvoid make_edge(){\n vx[n].push_back(PA(m,k+1));\n vy[1].push_back(PA(1,0));\n vy[m].push_back(PA(n,k+1));\n \n for(int i=1;i<=n;i++){\n if(vx[i].size() < 2) continue;\n sort(vx[i].begin(),vx[i].end());\n for(int j=0;j<vx[i].size()-1;j++){\n long long xcost = abs(vx[i][j].first-vx[i][j+1].first);\n yoko[ vx[i][j].second ].push_back( PAL(xcost,vx[i][j+1].second) );\n yoko[ vx[i][j+1].second ].push_back( PAL(xcost,vx[i][j].second) );\n }\n }\n \n for(int i=1;i<=m;i++){\n if(vy[i].size() < 2) continue;\n sort(vy[i].begin(),vy[i].end());\n for(int j=0;j<vy[i].size()-1;j++){\n long long ycost = abs(vy[i][j].first-vy[i][j+1].first);\n tate[ vy[i][j].second ].push_back( PAL(ycost,vy[i][j+1].second) );\n tate[ vy[i][j+1].second ].push_back( PAL(ycost,vy[i][j].second) );\n }\n }\n \n}\n\nint main(){\n \n int x,y;\n priority_queue<PPA,vector<PPA>,greater<PPA> > pq;\n \n cin >> m >> n >> k;\n for(int i=0;i<k;i++){\n cin >> x >> y;\n if(x==1 && y==1){\n vx[1].push_back(PA(1,0));\n }\n if(x==1 && y==1 || x==m && y==n) continue;\n vx[y].push_back(PA(x,i+1));\n vy[x].push_back(PA(y,i+1));\n }\n \n make_edge();\n \n for(int i=1;i<=k+1;i++){\n min_cost[0][i] = INF;\n min_cost[1][i] = INF;\n }\n min_cost[0][0] = 0;\n min_cost[1][0] = 0;\n \n pq.push( PPA(PA(0,0),0) );\n while(!pq.empty()){\n PPA pp = pq.top();\n pq.pop();\n PAL p = pp.first;\n \n for(int i=0;i<tate[p.second].size();i++){\n long long cost = p.first + tate[p.second][i].first;\n int to = tate[p.second][i].second;\n if(pp.second == 0 && min_cost[0][to] > cost){\n min_cost[0][to] = cost;\n pq.push( PPA(PAL(cost,to),0) );\n }\n if(pp.second == 1 && min_cost[0][to] > cost+1){\n min_cost[0][to] = cost+1;\n pq.push( PPA(PAL(cost+1,to),0) );\n }\n }\n \n for(int i=0;i<yoko[p.second].size();i++){\n long long cost = p.first + yoko[p.second][i].first;\n int to = yoko[p.second][i].second;\n if(pp.second == 0 && min_cost[1][to] > cost+1){\n min_cost[1][to] = cost+1;\n pq.push( PPA(PAL(cost+1,to),1) );\n }\n if(pp.second == 1 && min_cost[1][to] > cost){\n min_cost[1][to] = cost;\n pq.push( PPA(PAL(cost,to),1) );\n }\n }\n \n }\n \n long long ans = min(min_cost[0][k+1],min_cost[1][k+1]);\n cout << (ans==INF?-1:ans) << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 40800, "score_of_the_acc": -0.4522, "final_rank": 4 } ]
aoj_0614_cpp
鉄道旅行 (Railroad Trip) JOI 国には N 個の都市があり,それぞれ 1, 2, . . . , N の番号が付けられている.また,鉄道が N − 1 本あり,それぞれ 1, 2, . . . , N − 1 の番号が付けられている.鉄道 i (1 ≤ i ≤ N − 1) は,都市 i と都市 i + 1 を双方向に結んでいる. JOI 国の鉄道に乗車する方法として,紙の切符で乗車する方法と,IC カードで乗車する方法がある. 鉄道 i に紙の切符で乗車する場合の運賃は A i 円である. 鉄道 i に IC カードで乗車する場合の運賃は B i 円である.ただし,IC カードで鉄道 i に乗車するには,鉄道 i で使える IC カードを事前に購入しておく必要がある.鉄道 i で使える IC カードを購入するには C i 円かかる.一度購入した IC カードは,何度でも使用することができる. IC カードの方が金額の処理が簡単になるため,IC カードで乗車する場合の運賃の方が紙の切符で乗車する場合の運賃よりも安い.すなわち, i = 1, 2, . . . , N − 1 に対して, A i > B i が成り立つ.IC カードの仕様は鉄道ごとにすべて異なるため,どの i に対しても,鉄道 i で使える IC カードを他の鉄道で使用することはできない. あなたは,JOI 国じゅうを旅行することにした.都市 P 1 から出発し, P 2 , P 3 , . . . , P M の順に都市を訪れる予定である.旅行は M − 1 日間の行程からなる. j 日目 (1 ≤ j ≤ M − 1) に都市 P j から都市 P j+1 に鉄道で移動する.この際,いくつかの鉄道を乗り継いで移動することもある.また,同じ都市を二度以上訪れることがあるかもしれない.JOI 国の鉄道は速いので,どの都市からどの都市へも 1 日で移動することができる. あなたは現在,どの鉄道の IC カードも持っていない.あなたは,あらかじめ,いくつかの鉄道の IC カー ドを購入し,この旅行にかかる金額,すなわち,IC カード購入費用と乗車した鉄道の運賃の和をできるだけ少なくしたい. 課題 JOI 国の都市の数,旅行の行程,および JOI 国のそれぞれの鉄道の運賃と IC カードの価格が与えられる.このとき,旅行にかかる金額の最小値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 N , M が空白を区切りとして書かれている.これらはそれぞれ,JOI 国に都市が N 個あり,旅行が M − 1 日間の行程からなることを表す. 2 行目には, M 個の整数 P 1 , P 2 , . . . , P M が空白を区切りとして書かれている.これらは, j 日目 (1 ≤ j ≤ M − 1) に都市 P j から都市 P j+1 に鉄道で移動することを表す. 続く N − 1 行のうちの i 行目 (1 ≤ i ≤ N − 1) には,3 つの整数 A i , B i , C i が空白を区切りとして書かれている.これらはそれぞれ,鉄道 i に紙の切符で乗車したときの運賃が A i 円,IC カードで乗車したときの運賃が B i 円,鉄道 i で使える IC カードの金額が C i 円であることを表す. 出力 標準出力に,旅行にかかる金額の最小値を円単位で表す整数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 2 ≤ N ≤ 100 000. 2 ≤ M ≤ 100 000. 1 ≤ B i < A i ≤ 100 000 (1 ≤ i ≤ N − 1). 1 ≤ C i ≤ 100 000 (1 ≤ i ≤ N − 1). 1 ≤ P j ≤ N (1 ≤ j ≤ M ). P j ≠ P j+1 (1 ≤ j ≤ M − 1). 入出力例 入力例 1 4 4 1 3 2 4 120 90 100 110 50 80 250 70 130 出力例 1 550 この場合,旅行にかかる金額を最小にする方法は以下のとおりである. 鉄道 2 と鉄道 3 の IC カードを購入する.これには 80 + 130 = 210 円かかる. 1 日目に,都市 1 から都市 2 まで紙の切符を使って移動し,次に都市 2 から都市 3 まで IC カードを使って移動する.これには 120 + 50 = 170 円かかる. 2 日目に,都市 3 から都市 2 まで IC カードを使って移動する.これには 50 円かかる. 3 日目に,都市 2 から都市 3 まで IC カードを使って移動し,次に都市 3 から都市 4 まで IC カードを使って移動する.これには 50 + 70 = 120 円かかる. このように移動すると,旅行にかかる金額の合計は 210 + 170 + 50 + 120 = 550 円となる.これが最小であるので,550 と出力する. 入力例 2 8 5 7 5 3 5 4 12 5 8 16 2 1 3 1 5 17 12 17 19 7 5 12 2 19 4 1 3 出力例 2 81 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0614_10946349", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<n;i++)\nusing namespace std;\ntypedef long long ll;\n\nint sum[100000], p[100000];\nint main() {\n\tint n, m; scanf(\"%d%d\", &n, &m);\n\trep(i, m) {\n\t\tscanf(\"%d\", &p[i]); p[i]--;\n\t\tif (i) {\n\t\t\tsum[min(p[i], p[i - 1])]++;\n\t\t\tsum[max(p[i], p[i - 1])]--;\n\t\t}\n\t}\n\tll ans = 0;\n\trep(i, n - 1) {\n\t\tif (i)sum[i] += sum[i - 1];\n\t\tll a, b, c; scanf(\"%lld%lld%lld\", &a, &b, &c);\n\t\tans += min(sum[i] * a, c + sum[i] * b);\n\t}\n\tprintf(\"%lld\\n\", ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4336, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0614_10874252", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\n\nint MIN = -1e9;\nconst int MOD = 10000;\n\nint main() {\n\tint N,M;\n\tcin >> N>>M;\n\tvector<long long>R(N,0);\n\tvector<vector<long long>>L(N - 1, vector<long long>(3,0));\n\tlong long x, y;\n\tcin >> y;\n\t\n\tfor (int i = 1; i < M; i++) {\n\t\tcin >> x;\n\t\tlong long x2 = x;\n\t\tif (y > x) {\n\t\t\tswap(y, x);\n\t\t}\n\t\tR[y - 1] += 1;\n\t\tR[x - 1] -= 1;\n\t\ty = x2;\n\t}\n\tfor (int i = 0; i < N - 1; i++) {\t\n\t\tcin >> L[i][0] >> L[i][1] >> L[i][2];\n\t}\n\t\n\tfor (int i = 1; i < N - 1; i++) {\n\t\tR[i] += R[i - 1];\n\t\t\n\t}\n\tlong long ans = 0;\n\t\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tlong long nk = R[i] * L[i][0];\n\t\tlong long k= R[i] * L[i][1]+L[i][2];\n\t\t\n\t\tans += min(nk, k);\n\t}\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 9432, "score_of_the_acc": -2, "final_rank": 17 }, { "submission_id": "aoj_0614_10874251", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\n\nint MIN = -1e9;\nconst int MOD = 10000;\n\nint main() {\n\tint N,M;\n\tcin >> N>>M;\n\tvector<long long>R(N,0);\n\tvector<vector<long long>>L(N - 1, vector<long long>(3,0));\n\tlong long x, y;\n\tcin >> y;\n\t\n\tfor (int i = 1; i < M; i++) {\n\t\tcin >> x;\n\t\tlong long x2 = x;\n\t\tif (y > x) {\n\t\t\tswap(y, x);\n\t\t}\n\t\tR[y - 1] += 1;\n\t\tR[x - 1] -= 1;\n\t\ty = x2;\n\t}\n\tfor (int i = 0; i < N - 1; i++) {\t\n\t\tcin >> L[i][0] >> L[i][1] >> L[i][2];\n\t}\n\t\n\tfor (int i = 1; i < N - 1; i++) {\n\t\tR[i] += R[i - 1];\n\t\t\n\t}\n\tlong long ans = 0;\n\t\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tint nk = R[i] * L[i][0];\n\t\tint k= R[i] * L[i][1]+L[i][2];\n\t\t\n\t\tans += min(nk, k);\n\t}\n\n\tcout << ans<<endl;\n}", "accuracy": 0.6176470588235294, "time_ms": 60, "memory_kb": 9368, "score_of_the_acc": -1.9874, "final_rank": 19 }, { "submission_id": "aoj_0614_10334624", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <cstdlib>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n,m;\n cin >> n >> m;\n vector<int> p(m);\n rep(i,m){\n cin >> p[i];\n p[i]--; //0-based\n }\n vector<int> a(n-1),b(n-1),c(n-1);\n rep(i,n-1){\n cin >> a[i] >> b[i] >> c[i];\n }\n\n vector<int> cnt(n,0);\n rep(i,m-1){\n if(p[i]<p[i+1]){\n cnt[p[i]]++;\n cnt[p[i+1]]--;\n }\n else{\n cnt[p[i+1]]++;\n cnt[p[i]]--;\n }\n }\n vector<long long> res(n,0);\n res[0]=cnt[0];\n rep(i,n-1){\n res[i+1]=res[i]+cnt[i+1];\n }\n\n long long ans=0;\n rep(i,n-1){\n ans += min(a[i]*res[i],b[i]*res[i]+c[i]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5752, "score_of_the_acc": -1.2779, "final_rank": 14 }, { "submission_id": "aoj_0614_10334593", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <cstdlib>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n,m;\n cin >> n >> m;\n vector<int> p(m);\n rep(i,m){\n cin >> p[i];\n p[i]--; //0-based\n }\n vector<int> a(n-1),b(n-1),c(n-1);\n rep(i,n-1){\n cin >> a[i] >> b[i] >> c[i];\n }\n\n vector<int> cnt(n,0);\n rep(i,m-1){\n if(p[i]<p[i+1]){\n cnt[p[i]]++;\n cnt[p[i+1]]--;\n }\n else{\n cnt[p[i+1]]++;\n cnt[p[i]]--;\n }\n }\n vector<int> res(n,0);\n res[0]=cnt[0];\n rep(i,n-1){\n res[i+1]=res[i]+cnt[i+1];\n }\n\n long long ans=0;\n rep(i,n-1){\n ans += min(a[i]*res[i],b[i]*res[i]+c[i]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.6176470588235294, "time_ms": 60, "memory_kb": 5460, "score_of_the_acc": -1.2206, "final_rank": 18 }, { "submission_id": "aoj_0614_9480026", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <cstring> // for memset\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\nint main() {\n int N, M;\n cin >> N >> M;\n\n // 動的配列を使用して、各駅でのカウントを格納するための配列を確保\n vector<ll> countTable(N + 1, 0);\n\n // スケジュールを格納する配列を確保\n vector<int> schedule(M);\n for(int i = 0; i < M; i++) {\n cin >> schedule[i];\n }\n\n // 各区間のコストに関する配列を確保\n vector<ll> A(N), B(N), C(N);\n\n // コスト情報を入力\n for(int i = 1; i < N; i++) {\n cin >> A[i] >> B[i] >> C[i];\n }\n\n // スケジュールに基づいてカウントテーブルを更新\n for(int i = 0; i < M - 1; i++) {\n int from = schedule[i];\n int to = schedule[i + 1];\n if(from > to) {\n swap(from, to);\n }\n countTable[from]++;\n countTable[to]--;\n }\n\n // カウントテーブルの累積和を計算\n for(int i = 2; i < N; i++) {\n countTable[i] += countTable[i - 1];\n }\n\n ll ans = 0;\n\n // 各区間のコストを計算して合計\n for(int i = 1; i < N; i++) {\n if(countTable[i] * (A[i] - B[i]) - C[i] > 0) {\n ans += B[i] * countTable[i] + C[i];\n } else {\n ans += A[i] * countTable[i];\n }\n }\n\n // 最終結果を出力\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6508, "score_of_the_acc": -1.4262, "final_rank": 16 }, { "submission_id": "aoj_0614_8910436", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, M;\n cin >> N >> M;\n vi P(M), A(N-1), B(N-1), C(N-1);\n rep(i, M) {\n cin >> P[i];\n P[i]--;\n }\n rep(i, N-1) cin >> A[i] >> B[i] >> C[i];\n vi s(N, 0);\n rep(i, M-1) {\n ll a = P[i];\n ll b = P[i+1];\n if (a > b) swap(a, b);\n s[a]++; s[b]--;\n }\n rep(i, 1, N) {\n s[i] += s[i-1];\n }\n ll ans = 0;\n rep(i, N-1) {\n ans += min(A[i]*s[i], B[i]*s[i]+C[i]);\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7008, "score_of_the_acc": -0.5243, "final_rank": 3 }, { "submission_id": "aoj_0614_8861316", "code_snippet": "#include <vector>\n#include <algorithm>\n#include <cstdio>\n#include <iostream>\n\nusing namespace std;\n\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return 0;\n if (a <= l && r <= b)\n return seg[k] + add[k];\n return Query(a, b, 2 * k + 1, l, (l + r) / 2) + Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k];\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n};\n\nint main() {\n std::ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n cout << ret << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5224, "score_of_the_acc": -1.1743, "final_rank": 12 }, { "submission_id": "aoj_0614_8861314", "code_snippet": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\nconst int MAXN = 1e5+5;\nint seg[MAXN << 2] = {0}, add[MAXN << 2] = {0}, P[MAXN], u[MAXN], v[MAXN];\nvoid Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n}\nint Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n return (Query(a, b, 2 * k + 1, l, (l + r) / 2) +\n Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k]);\n}\nint main() {\n int N, M;\n scanf(\"%d %d\", &N, &M);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n u[i] = min(P[i - 1], P[i]), v[i] = max(P[i - 1], P[i]);\n Add(u[i], v[i], 1, 0, 0, N);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = Query(i, i + 1, 0, 0, N);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n printf(\"%lld\\n\", ret);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5420, "score_of_the_acc": -1.2127, "final_rank": 13 }, { "submission_id": "aoj_0614_8861313", "code_snippet": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\n\n#define MAXN 100003\n\nstruct SegmentTree {\n int seg[4 * MAXN] = {0}, add[4 * MAXN] = {0};\n int sz;\n\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n }\n\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) / 2;\n Add(a, b, x, 2 * k + 1, l, mid);\n Add(a, b, x, 2 * k + 2, mid, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return 0;\n if (a <= l && r <= b)\n return seg[k] + add[k];\n int mid = (l + r) / 2;\n return Query(a, b, 2 * k + 1, l, mid) + Query(a, b, 2 * k + 2, mid, r) + add[k];\n }\n\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n};\n\nint main() {\n int N, M, P[MAXN];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n printf(\"%lld\\n\", ret);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6304, "score_of_the_acc": -1.3862, "final_rank": 15 }, { "submission_id": "aoj_0614_8861312", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (__builtin_expect((a >= r || b <= l), 0)) {\n return;\n } else if (__builtin_expect((a <= l && r <= b), 0)) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n seg[k] =\n seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (__builtin_expect((a <= l && r <= b), 1))\n return (seg[k] + add[k]);\n if (__builtin_expect((a >= r || b <= l), 0))\n return 0;\n return (Query(a, b, 2 * k + 1, l, (l + r) / 2) +\n Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\nint main() {\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i+= 2) {\n long long used1 = segtree.Query(i, i + 1);\n long long used2 = i + 1 < N - 1 ? segtree.Query(i+1, i + 2) : 0;\n int A1, B1, C1, A2, B2, C2;\n scanf(\"%d %d %d\", &A1, &B1, &C1);\n if (i + 1 < N - 1)\n scanf(\"%d %d %d\", &A2, &B2, &C2);\n ret += min(used1 * A1, C1 + used1 * B1);\n if (i + 1 < N - 1)\n ret += min(used2 * A2, C2 + used2 * B2);\n }\n cout << ret << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5208, "score_of_the_acc": -1.1711, "final_rank": 11 }, { "submission_id": "aoj_0614_8861309", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n int left = seg[2 * k + 1] + add[2 * k + 1]; // Compute once, reuse\n int right = seg[2 * k + 2] + add[2 * k + 2]; // Compute once, reuse\n seg[k] = left + right;\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n return (Query(a, b, 2 * k + 1, l, (l + r) / 2) +\n Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\nint main() {\n ios_base::sync_with_stdio(false); // Make cin and cout faster\n cin.tie(NULL);\n int N, M, P[100000];\n cin >> N >> M;\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n cin >> P[i];\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n int ret = 0; // Replace long long with int\n for (int i = 0; i < N - 1; i++) {\n int used = segtree.Query(i, i + 1);\n int A, B, C;\n cin >> A >> B >> C;\n ret += min(used * A, C + used * B);\n }\n cout << ret << endl;\n}", "accuracy": 0.5882352941176471, "time_ms": 20, "memory_kb": 4952, "score_of_the_acc": -0.1209, "final_rank": 20 }, { "submission_id": "aoj_0614_8861308", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n }\n if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) / 2;\n Add(a, b, x, 2 * k + 1, l, mid);\n Add(a, b, x, 2 * k + 2, mid, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return 0;\n if (a <= l && r <= b)\n return seg[k] + add[k];\n int mid = (l + r) / 2;\n return Query(a, b, 2 * k + 1, l, mid) + Query(a, b, 2 * k + 2, mid, r) + add[k];\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n};\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n printf(\"%lld\\n\", ret);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5204, "score_of_the_acc": -1.1703, "final_rank": 10 }, { "submission_id": "aoj_0614_8861307", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) / 2;\n int k1 = 2 * k + 1, k2 = 2 * k + 2;\n Add(a, b, x, k1, l, mid);\n Add(a, b, x, k2, mid, r);\n seg[k] = seg[k1] + add[k1] + seg[k2] + add[k2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n int mid = (l + r) / 2;\n int k1 = 2 * k + 1, k2 = 2 * k + 2;\n return (Query(a, b, k1, l, mid) +\n Query(a, b, k2, mid, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n \n int N, M, P[100000];\n cin >> N >> M;\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n cin >> P[i];\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = P[i - 1], v = P[i];\n if(u > v) swap(u,v);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n cin >> A >> B >> C;\n ret += (used * A < C + used * B) ? used * A : C + used * B;\n }\n cout << ret << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5216, "score_of_the_acc": -0.9227, "final_rank": 6 }, { "submission_id": "aoj_0614_8836466", "code_snippet": "#include <cstdio>\n\nstruct SegmentTree {\n int* seg;\n int* add;\n int sz;\n\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg = new int[sz * 2 + 1];\n add = new int[sz * 2 + 1];\n for (int i = 0; i < sz * 2 + 1; i++) {\n seg[i] = 0;\n add[i] = 0;\n }\n }\n\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) / 2;\n Add(a, b, x, 2 * k + 1, l, mid);\n Add(a, b, x, 2 * k + 2, mid, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return 0;\n if (a <= l && r <= b)\n return seg[k] + add[k];\n int mid = (l + r) / 2;\n return Query(a, b, 2 * k + 1, l, mid) + Query(a, b, 2 * k + 2, mid, r) + add[k];\n }\n\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n\n ~SegmentTree() {\n delete[] seg;\n delete[] add;\n }\n};\n\nint main() {\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = (P[i - 1] < P[i] ? P[i - 1] : P[i]);\n int v = (P[i - 1] < P[i] ? P[i] : P[i - 1]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += (used * A < C + used * B ? used * A : C + used * B);\n }\n printf(\"%lld\\n\", ret);\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4764, "score_of_the_acc": -1.084, "final_rank": 9 }, { "submission_id": "aoj_0614_8818895", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n\n SegmentTree(int n) {\n sz = 1;\n while (sz < n) sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) return;\n if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) / 2;\n int k1 = 2 * k + 1;\n int k2 = 2 * k + 2;\n Add(a, b, x, k1, l, mid);\n Add(a, b, x, k2, mid, r);\n seg[k] = seg[k1] + add[k1] + seg[k2] + add[k2];\n }\n }\n\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l) return 0;\n if (a <= l && r <= b) return seg[k] + add[k];\n int mid = (l + r) / 2;\n return Query(a, b, 2 * k + 1, l, mid) +\n Query(a, b, 2 * k + 2, mid, r) + add[k];\n }\n\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n};\n\nint main() {\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n printf(\"%lld\\n\", ret);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4756, "score_of_the_acc": -1.0824, "final_rank": 8 }, { "submission_id": "aoj_0614_8818894", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz <<= 1;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n int mid = (l + r) >> 1;\n int k1 = k << 1;\n Add(a, b, x, k1 + 1, l, mid);\n Add(a, b, x, k1 + 2, mid, r);\n seg[k] = seg[k1 + 1] + add[k1 + 1] + seg[k1 + 2] + add[k1 + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n int mid = (l + r) >> 1;\n int k1 = k << 1;\n return (Query(a, b, k1 + 1, l, mid) +\n Query(a, b, k1 + 2, mid, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\n\nint scan() {\n int n = 0, ch = getchar_unlocked();\n while (ch < '0' || ch > '9') ch = getchar_unlocked();\n while (ch >= '0' && ch <= '9') {\n n = (n << 3) + (n << 1) + ch - '0';\n ch = getchar_unlocked();\n }\n return n;\n}\n\nint main() {\n int N = scan(), M = scan(), P[100000];\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n P[i] = scan();\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A = scan(), B = scan(), C = scan();\n ret += min(used * A, C + used * B);\n }\n cout << ret << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5160, "score_of_the_acc": -0.4117, "final_rank": 2 }, { "submission_id": "aoj_0614_8818892", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n) sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) return;\n else if (a <= l && r <= b) add[k] += x;\n else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n seg[k] = seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l) return 0;\n if (a <= l && r <= b) return seg[k] + add[k];\n return Query(a, b, 2 * k + 1, l, (l + r) / 2) + Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k];\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return Query(a, b, 0, 0, sz); }\n};\n\nint main() {\n ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);\n int N, M, P[100000];\n cin >> N >> M;\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n cin >> P[i];\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = P[i - 1] < P[i] ? P[i - 1] : P[i], v = P[i - 1] > P[i] ? P[i - 1] : P[i];\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n cin >> A >> B >> C;\n ret += min(used * A, C + used * B);\n }\n cout << ret << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5184, "score_of_the_acc": -0.9164, "final_rank": 4 }, { "submission_id": "aoj_0614_8818890", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz *= 2;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) / 2);\n Add(a, b, x, 2 * k + 2, (l + r) / 2, r);\n seg[k] =\n seg[2 * k + 1] + add[2 * k + 1] + seg[2 * k + 2] + add[2 * k + 2];\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n return (Query(a, b, 2 * k + 1, l, (l + r) / 2) +\n Query(a, b, 2 * k + 2, (l + r) / 2, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int N, M, P[100000];\n cin >> N >> M;\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n cin >> P[i];\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n cin >> A >> B >> C;\n ret += min(used * A, C + used * B);\n }\n cout << ret << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5216, "score_of_the_acc": -0.9227, "final_rank": 6 }, { "submission_id": "aoj_0614_8818888", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nstruct SegmentTree {\n vector<int> seg, add;\n int sz;\n SegmentTree(int n) {\n sz = 1;\n while (sz < n)\n sz <<= 1;\n seg.assign(sz * 2 + 1, 0), add.assign(sz * 2 + 1, 0);\n }\n void Add(int a, int b, int x, int k, int l, int r) {\n if (a >= r || b <= l) {\n return;\n } else if (a <= l && r <= b) {\n add[k] += x;\n } else {\n Add(a, b, x, 2 * k + 1, l, (l + r) >> 1);\n Add(a, b, x, 2 * k + 2, (l + r) >> 1, r);\n int left = seg[2 * k + 1] + add[2 * k + 1];\n int right = seg[2 * k + 2] + add[2 * k + 2];\n seg[k] = left + right;\n }\n }\n int Query(int a, int b, int k, int l, int r) {\n if (a >= r || b <= l)\n return (0);\n if (a <= l && r <= b)\n return (seg[k] + add[k]);\n return (Query(a, b, 2 * k + 1, l, (l + r) >> 1) +\n Query(a, b, 2 * k + 2, (l + r) >> 1, r) + add[k]);\n }\n void Add(int a, int b, int x) { Add(a, b, x, 0, 0, sz); }\n int Query(int a, int b) { return (Query(a, b, 0, 0, sz)); }\n};\nint main() {\n int N, M, P[100000];\n scanf(\"%d %d\", &N, &M);\n SegmentTree segtree(N);\n for (int i = 0; i < M; i++) {\n scanf(\"%d\", &P[i]);\n --P[i];\n }\n for (int i = 1; i < M; i++) {\n int u = min(P[i - 1], P[i]), v = max(P[i - 1], P[i]);\n segtree.Add(u, v, 1);\n }\n long long ret = 0;\n for (int i = 0; i < N - 1; i++) {\n long long used = segtree.Query(i, i + 1);\n int A, B, C;\n scanf(\"%d %d %d\", &A, &B, &C);\n ret += min(used * A, C + used * B);\n }\n printf(\"%lld\\n\", ret);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5208, "score_of_the_acc": -0.9211, "final_rank": 5 } ]
aoj_0613_cpp
財宝 (Treasures) 問題 盗賊の Anna と Bruno は大富豪の邸宅に忍び込み,財宝 1 から財宝 N までの N 個の財宝を見つけた.これらの財宝を Anna と Bruno で分配することになった.財宝のうちのいくつかを Anna が取り,残りの財宝のうちのいくつかを Bruno が取る.同じ財宝を 2 人が取ることはできない.Anna や Bruno は財宝を 1 個も取らなくてもよい.また,残った財宝は邸宅に残しておくので,2 人とも取らない財宝があってもよい. それぞれの財宝には「市場価値」と「貴重度」という 2 つの値が定まっている.Anna が取った財宝の市場価値の合計と Bruno が取った財宝の市場価値の合計の差の絶対値が D 以下なら,Anna は公平だと思って満足する.一方,Bruno は,Anna より貴重度の大きい財宝が欲しいと思っている. Anna が満足するように財宝を分配したときの,Bruno が取った財宝の貴重度の合計から Anna が取った財宝の貴重度の合計を引いた値の最大値を求めよ. 入力 入力は 1 + N 行からなる. 1 行目には,2 つの整数 N, D (1 ≤ N ≤ 30,0 ≤ D ≤ 10 15 ) が空白を区切りとして書かれている.これは,財宝の個数が N 個であり,Anna が取った財宝の市場価値の合計と Bruno が取った財宝の市場価値の合計の差の絶対値が D 以下なら Anna が満足することを表す. 続く N 行のうちの i 行目 (1 ≤ i ≤ N) には,2 つの整数 X i , Y i (0 ≤ X i ≤ 10 15 ,0 ≤ Y i ≤ 10 15 ) が空白を区切りとして書かれている.これは,財宝 i の市場価値が X i であり,貴重度が Y i であることを表す. 与えられる 5 つの入力データのうち,入力 1 では N ≦ 10 を満たす.また,入力 2 では D = 0 を満たす. 出力 Anna が満足するように財宝を分配したときの,Bruno が取った財宝の貴重度の合計から Anna が取った財宝の貴重度の合計を引いた値の最大値を 1 行で出力せよ. 入出力例 入力例 1 6 15 50 900 30 200 40 100 80 600 60 100 70 700 出力例 1 1200 入力例 2 5 0 0 1000000000000000 0 1000000000000000 1 1 1000000000000000 0 1000000000000000 0 出力例 2 2000000000000000 入出力例 1 においては,Anna が財宝 2 と財宝 3 と財宝 5 を取り,Bruno が財宝 1 と財宝 6 を取ると,取った財宝の市場価値の合計は Anna が 130,Bruno が 120 となり,差の絶対値 10 が D = 15 以下なので Anna は満足する.このとき,取った財宝の貴重度の合計は Anna が 400,Bruno が 1600 となり,Bruno が取った財宝の貴重度の合計から Anna が取った財宝の貴重度の合計を引いた値は 1200 となる.これが最大である. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0613_10851203", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <deque>\n#include <functional>\nusing namespace std;\nlong long n, d, a[39], b[39], mid; int power[39]; pair<long long, long long>A[15000000], B[15000000];\nint main() {\n\tcin >> n >> d; mid = n / 2;\n\tfor (int i = 0; i < n; i++)cin >> a[i] >> b[i];\n\tpower[0] = 1; for (int i = 1; i < 39; i++)power[i] = power[i - 1] * 3;\n\tfor (int i = 0; i < power[mid]; i++) {\n\t\tlong long X1 = 0, X2 = 0;\n\t\tfor (int j = 0; j < mid; j++) {\n\t\t\tint C = (i / power[j]) % 3;\n\t\t\tif (C == 0) { X1 += a[j]; X2 += b[j]; }\n\t\t\tif (C == 1) { X1 -= a[j]; X2 -= b[j]; }\n\t\t}\n\t\tA[i] = make_pair(X1, X2);\n\t}\n\tfor (int i = 0; i < power[n - mid]; i++) {\n\t\tlong long X1 = 0, X2 = 0;\n\t\tfor (int j = 0; j < n - mid; j++) {\n\t\t\tint C = (i / power[j]) % 3;\n\t\t\tif (C == 0) { X1 += a[mid + j]; X2 += b[mid + j]; }\n\t\t\tif (C == 1) { X1 -= a[mid + j]; X2 -= b[mid + j]; }\n\t\t}\n\t\tB[i] = make_pair(X1, X2);\n\t}\n\tsort(A, A + power[mid], greater<pair<long long, long long>>());\n\tsort(B, B + power[n - mid]); deque<pair<long long, long long>>Q;\n\tint L = 0, R = 0; long long minx = 0;\n\tfor (int i = 0; i < power[mid]; i++) {\n\t\tint pos1 = lower_bound(B, B + power[n - mid], make_pair(-A[i].first - d, -(1LL << 62))) - B;\n\t\tint pos2 = lower_bound(B, B + power[n - mid], make_pair(-A[i].first + d, (1LL << 62))) - B;\n\t\tfor (int i = R; i < pos2; i++) {\n\t\t\twhile (!Q.empty() && B[i].second <= Q.back().first)Q.pop_back();\n\t\t\tQ.push_back(make_pair(B[i].second, i));\n\t\t}\n\t\twhile (L < pos1) { if (Q.front().second == L)Q.pop_front(); L++; }\n\t\tR = pos2; if (!Q.empty()) minx = min(minx, Q.front().first + A[i].second);\n\t}\n\tcout << -minx << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 5970, "memory_kb": 453928, "score_of_the_acc": -1.0098, "final_rank": 15 }, { "submission_id": "aoj_0613_10758143", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#include<atcoder/modint>\nusing namespace atcoder;\nusing mint=modint998244353;\n\nusing ll =long long;\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n ll N,D;\n cin>>N>>D;\n vector<array<ll,2>> P(N);\n for(int i=0;i<N;i++)cin>>P[i][0]>>P[i][1];\n \n vector<array<ll,2>> MV,MB;\n ll H=N/2;\n ll B=N-H;\n for(int bit=0;bit<(1<<H);bit++){\n for (ll b = bit; b >= 0; b = (b - 1) & bit) {\n ll S=0,U=0;\n for(int i=0;i<H;i++){\n if(bit&(1<<i)){\n if(b&(1<<i)){\n S+=P[i][0];\n U-=P[i][1];\n }\n else{\n S-=P[i][0];\n U+=P[i][1];\n }\n }\n }\n MV.push_back({S+ll(1e17),U});\n if (b == 0)break;\n }\n }\n sort(MV.begin(),MV.end());\n \n ll an=0;\n\n\n for(int bit=0;bit<(1<<B);bit++){\n for (ll b = bit; b >= 0; b = (b - 1) & bit) {\n ll S=0,U=0;\n for(int i=0;i<B;i++){\n if(bit&(1<<i)){\n if(b&(1<<i)){\n S-=P[i+H][0];\n U-=P[i+H][1];\n }\n else{\n S+=P[i+H][0];\n U+=P[i+H][1];\n }\n }\n }\n MB.push_back({S+ll(1e17),U});\n if (b == 0)break;\n }\n }\n sort(MB.begin(),MB.end());\n deque<array<ll,2>> DEQ;\n ll R=0;\n for(int i=0;i<MB.size();i++){\n while(R<MV.size()&&MV[R][0]<=MB[i][0]+D){\n while(DEQ.size()>0&&DEQ.back()[0]<=MV[R][1])DEQ.pop_back();\n DEQ.push_back({MV[R][1],MV[R][0]});\n R++;\n }\n while(DEQ.size()>0&&DEQ.front()[1]<MB[i][0]-D)DEQ.pop_front();\n if(DEQ.size()>0)an=max(an,MB[i][1]+DEQ.front()[0]);\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 3280, "memory_kb": 491060, "score_of_the_acc": -0.392, "final_rank": 11 }, { "submission_id": "aoj_0613_10641301", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n#define HUGE_NUM 999999999999999999\n\nenum Type{\n\tOne,\n\tTwo,\n};\n\nenum Which{\n\tA,\n\tB,\n\tSkip,\n};\n\nstruct Data{\n\tll market_value,precious_degree;\n};\n\nstruct Info{\n\tInfo(ll arg_market_value_diff,ll arg_precious_degree_diff){\n\t\tmarket_value_diff = arg_market_value_diff;\n\t\tprecious_degree_diff = arg_precious_degree_diff;\n\t}\n\tbool operator<(const struct Info &arg) const{ //市場価値の差の降順\n\t\treturn market_value_diff > arg.market_value_diff;\n\t}\n\tbool operator==(const struct Info &arg) const{\n\t\treturn market_value_diff == arg.market_value_diff\n\t\t\t\t&&precious_degree_diff == arg.precious_degree_diff;\n\t}\n\n\tll market_value_diff,precious_degree_diff;\n};\n\nll N,DIFF;\nData data[30];\nint start_index[2],end_index[2];\nvector<Info> V[2];\nll* table;\nint SIZE = 1;\n\n//簡易化のため、要素数を2のべき乗にする関数\nvoid init(int first_N){\n\twhile(SIZE < first_N)SIZE *= 2;\n}\n\nvoid update(int loc,ll value){\n\tloc += SIZE-1;\n\n\ttable[loc] = value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[parent] = max(table[2*parent+1],table[2*parent+2]); //親は左右の子の大きい方の値を持つ\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\n\nll query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\tif(search_right < node_left || search_left > node_right)return -HUGE_NUM;\n\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[node_id];\n\t}\n\n\tll left_max = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tll right_max = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\n\nbool rangeCheck(ll value){\n\tif(value >= -DIFF && value <= DIFF){\n\t\treturn true;\n\t}else{\n\t\treturn false;\n\t}\n}\n\nvoid make_group(Which array[30],int index,Type type){\n\tif(index == end_index[type]+1){\n\n\t\tll A_market = 0,A_precious = 0,B_market = 0,B_precious = 0;\n\t\tfor(int i = start_index[type]; i <= end_index[type]; i++){\n\t\t\tif(array[i] == Skip)continue;\n\n\t\t\tif(array[i] == A){\n\t\t\t\tA_market += data[i].market_value;\n\t\t\t\tA_precious += data[i].precious_degree;\n\t\t\t}else{\n\t\t\t\tB_market += data[i].market_value;\n\t\t\t\tB_precious += data[i].precious_degree;\n\t\t\t}\n\t\t}\n\n\t\tV[type].push_back(Info(B_market-A_market,B_precious-A_precious));\n\t\treturn;\n\t}\n\n\tWhich next_array[3][30];\n\tfor(int i = 0; i < 3; i++){\n\t\tfor(int k = start_index[type]; k < index; k++){\n\t\t\tnext_array[i][k] = array[k];\n\t\t}\n\t}\n\n\tnext_array[0][index] = A;\n\tnext_array[1][index] = B;\n\tnext_array[2][index] = Skip;\n\n\tfor(int i = 0; i < 3; i++){\n\t\tmake_group(next_array[i],index+1,type);\n\t}\n}\n\nint main(){\n\n\tscanf(\"%lld %lld\",&N,&DIFF);\n\n\tfor(int i = 0; i < N; i++){\n\t\tscanf(\"%lld %lld\",&data[i].market_value,&data[i].precious_degree);\n\t}\n\n\tif(N == 1){\n\t\tif(data[0].market_value <= DIFF){\n\t\t\tprintf(\"%lld\\n\",data[0].precious_degree);\n\t\t}else{\n\t\t\tprintf(\"0\\n\");\n\t\t}\n\t\treturn 0;\n\t}\n\n\tV[One].push_back(Info(0,0));\n\tV[Two].push_back(Info(0,0));\n\n\t//0~N-1の財宝を2つに分割する\n\tstart_index[One] = 0;\n\tend_index[One] = (N-1)/2;\n\n\tstart_index[Two] = end_index[One]+1;\n\tend_index[Two] = N-1;\n\n\n\tWhich first_array[30];\n\n\tmake_group(first_array,start_index[One],One);\n\tmake_group(first_array,start_index[Two],Two);\n\n\tsort(V[One].begin(),V[One].end()); //Oneは降順に\n\tV[One].erase(unique(V[One].begin(),V[One].end()),V[One].end());\n\n\tsort(V[Two].begin(),V[Two].end());\n\tV[Two].erase(unique(V[Two].begin(),V[Two].end()),V[Two].end());\n\treverse(V[Two].begin(),V[Two].end()); //Twoは昇順に\n\n\tll ans = -HUGE_NUM;\n\n\tint left,right,start_index = 0;\n\tint calc_left,calc_right,m;\n\tint One_num = (int)V[One].size(),Two_num = (int)V[Two].size();\n\n\t//2分探索で、range制約を満たす左端と右端を求める\n\twhile(start_index < One_num){\n\n\t\tleft = BIG_NUM; //左端を求める\n\t\tcalc_left = 0, calc_right = Two_num-1,m = (calc_left+calc_right);\n\t\twhile(calc_left<=calc_right){\n\t\t\tif(V[One][start_index].market_value_diff+V[Two][m].market_value_diff >= -DIFF){\n\t\t\t\tleft = m;\n\t\t\t\tcalc_right = m-1; //より左へ\n\n\t\t\t}else{\n\t\t\t\tcalc_left = m+1;\n\t\t\t}\n\t\t\tm = (calc_left+calc_right)/2;\n\t\t}\n\n\t\tif(left == BIG_NUM){\n\t\t\tstart_index++;\n\t\t\tcontinue;\n\t\t}\n\n\t\tright = BIG_NUM; //右端を求める\n\t\tcalc_left = 0, calc_right = Two_num-1,m = (calc_left+calc_right);\n\t\twhile(calc_left<=calc_right){\n\t\t\tif(V[One][start_index].market_value_diff+V[Two][m].market_value_diff <= DIFF){\n\t\t\t\tright = m;\n\t\t\t\tcalc_left = m+1; //より右へ\n\n\t\t\t}else{\n\t\t\t\tcalc_right = m-1;\n\t\t\t}\n\t\t\tm = (calc_left+calc_right)/2;\n\t\t}\n\t\tif(right == BIG_NUM || left > right){\n\t\t\tstart_index++;\n\t\t\tcontinue;\n\t\t}\n\t\tbreak;\n\t}\n\n\tif(start_index == One_num){\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\tinit(Two_num);\n\ttable = new ll[2*SIZE-1];\n\n\tfor(int i = 0; i <= 2*SIZE-2; i++)table[i] = -HUGE_NUM;\n\tfor(int i = 0; i < Two_num; i++)update(i,V[Two][i].precious_degree_diff);\n\n\tans = V[One][start_index].precious_degree_diff+query(left,right,0,0,SIZE-1);\n\n\tfor(int i = start_index+1; i < One_num; i++){\n\t\twhile(left < Two_num && V[One][i].market_value_diff+V[Two][left].market_value_diff < -DIFF)left++;\n\t\tif(left == Two_num)break;\n\t\twhile(right < Two_num && V[One][i].market_value_diff+V[Two][right].market_value_diff <= DIFF)right++;\n\t\tright--;\n\n\t\tif(left > right)continue;\n\n\t\tans = max(ans,V[One][i].precious_degree_diff+query(left,right,0,0,SIZE-1));\n\t}\n\n\tif(ans == -HUGE_NUM){\n\t\tprintf(\"0\\n\");\n\t}else{\n\t\tprintf(\"%lld\\n\",ans);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 4230, "memory_kb": 716696, "score_of_the_acc": -1.5099, "final_rank": 18 }, { "submission_id": "aoj_0613_9287290", "code_snippet": "#line 2 \"cp-library/src/cp-template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\nusing i128 = __int128_t;\ntemplate < class T > bool chmin(T& a, T b) { if(a > b) { a = b; return true; } return false; }\ntemplate < class T > bool chmax(T& a, T b) { if(a < b) { a = b; return true; } return false; }\ntemplate < class T, class U > T ceil (T x, U y) { return (x > 0 ? (x + y - 1) / y : x / y); }\ntemplate < class T, class U > T floor(T x, U y) { return (x > 0 ? x / y : (x - y + 1) / y); }\nint popcnt(i32 x) { return __builtin_popcount(x); }\nint popcnt(u32 x) { return __builtin_popcount(x); }\nint popcnt(i64 x) { return __builtin_popcountll(x); }\nint popcnt(u64 x) { return __builtin_popcountll(x); }\n\n#line 2 \"cp-library/src/utility/rep_itr.hpp\"\ntemplate < class T > struct itr_rep {\n T i, d;\n constexpr itr_rep(const T i) noexcept : i(i), d(1) {}\n constexpr itr_rep(const T i, const T d) noexcept : i(i), d(d) {}\n void operator++() noexcept { i += d; }\n constexpr int operator*() const noexcept { return i; }\n constexpr bool operator!=(const itr_rep x) const noexcept { return d > 0 ? i < x.i : i > x.i; }\n};\n\ntemplate < class T > struct rep {\n const itr_rep< T > s, t;\n constexpr rep(const T t) noexcept : s(0), t(t) {}\n constexpr rep(const T s, const T t) noexcept : s(s), t(t) {}\n constexpr rep(const T s, const T t, const T d) noexcept : s(s, d), t(t, d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n\ntemplate < class T > struct revrep {\n const itr_rep < T > s, t;\n constexpr revrep(const T t) noexcept : s(t - 1, -1), t(-1, -1) {}\n constexpr revrep(const T s, const T t) noexcept : s(t - 1, -1), t(s - 1, -1) {}\n constexpr revrep(const T s, const T t, const T d) noexcept : s(t - 1, -d), t(s - 1, -d) {}\n constexpr auto begin() const noexcept { return s; }\n constexpr auto end () const noexcept { return t; }\n};\n#line 3 \"cp-library/src/utility/io.hpp\"\n\n/* 128bit integer */\nistream& operator>>(istream& is, i128& x) {\n std::string s; is >> s;\n int pm = (s[0] == '-');\n x = 0;\n for(int i : rep(pm, int(s.size()))) x = x * 10 + (s[i] - '0');\n if(pm) x *= -1;\n return is;\n}\nostream& operator<<(ostream& os, const i128& x) {\n if(x == 0) return os << '0';\n i128 y = x;\n if(y < 0) { os << '-'; y *= -1; }\n std::vector<int> ny;\n while(y > 0) { ny.push_back(y % 10); y /= 10; }\n for(int i : revrep(ny.size())) os << ny[i];\n return os;\n}\n\ntemplate < class S, class T > istream& operator>>(istream& is, std::pair< S, T >& x) { is >> x.first >> x.second; return is; }\ntemplate < class S, class T > ostream& operator<<(ostream& os, const std::pair< S, T >& x) { os << x.first << \" \" << x.second; return os; }\n\nnamespace scanner {\n struct sca {\n template < class T > operator T() {\n T s; std::cin >> s; return s;\n }\n };\n struct vec {\n int n;\n vec(int n) : n(n) {}\n template < class T > operator std::vector< T >() {\n std::vector< T > v(n);\n for(T& x : v) std::cin >> x;\n return v;\n }\n };\n struct mat {\n int h, w;\n mat(int h, int w) : h(h), w(w) {}\n template < class T > operator std::vector< std::vector< T > >() {\n std::vector m(h, std::vector< T >(w));\n for(std::vector< T >& v : m) for(T& x : v) std::cin >> x;\n return m;\n }\n };\n struct speedup {\n speedup() {\n std::cin.tie(0);\n std::ios::sync_with_stdio(0);\n }\n } speedup_instance;\n}\nscanner::sca in() { return scanner::sca(); }\nscanner::vec in(int n) { return scanner::vec(n); }\nscanner::mat in(int h, int w) { return scanner::mat(h, w); }\n\nnamespace printer {\n void precision(int d) { std::cout << std::fixed << std::setprecision(d); }\n void flush() { std::cout.flush(); }\n}\n\ntemplate < class T >\nostream& operator<<(ostream& os, const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) { os << a[i]; if(i != n - 1) os << ' '; }\n return os;\n}\n\nint print() { std::cout << '\\n'; return 0; }\ntemplate < class head, class... tail > int print(head&& h, tail&&... t) {\n std::cout << h; if(sizeof...(tail)) std::cout << ' ';\n return print(std::forward<tail>(t)...);\n}\ntemplate < class T > int print_n(const std::vector< T > a) {\n int n = a.size();\n for(int i : rep(n)) std::cout << a[i] << \"\\n\";\n return 0;\n}\n\n\n#line 2 \"cp-library/src/utility/key_val.hpp\"\n\ntemplate < class K, class V >\nstruct key_val {\n K key; V val;\n key_val() {}\n key_val(K key, V val) : key(key), val(val) {}\n template < std::size_t Index >\n std::tuple_element_t< Index, key_val >& get() {\n if constexpr (Index == 0) return key;\n if constexpr (Index == 1) return val;\n }\n};\n\nnamespace std {\n\ntemplate < class K, class V > struct tuple_size < key_val< K, V > > : integral_constant< size_t, 2 > {};\ntemplate < class K, class V > struct tuple_element < 0, key_val< K, V > > { using type = K; };\ntemplate < class K, class V > struct tuple_element < 1, key_val< K, V > > { using type = V; };\n\n}\n#line 2 \"cp-library/src/utility/vec_op.hpp\"\ntemplate < class T > key_val< int, T > max_of(const vector< T >& a) {\n int i = std::max_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class T > key_val< int, T > min_of(const vector< T >& a) {\n int i = std::min_element(a.begin(), a.end()) - a.begin();\n return {i, a[i]};\n}\ntemplate < class S, class T > S sum_of(const vector< T >& a) {\n S sum = 0;\n for(const T x : a) sum += x;\n return sum;\n}\ntemplate < class S, class T > vector< S > freq_of(const vector< T >& a, T L, T R) {\n vector< S > res(R - L, S(0));\n for(const T x : a) res[x - L] += 1;\n return res;\n}\ntemplate < class S, class T > struct prefix_sum {\n vector< S > s;\n prefix_sum(const vector< T >& a) : s(a) {\n s.insert(s.begin(), S(0));\n for(int i : rep(a.size())) s[i + 1] += s[i];\n }\n // [L, R)\n S sum(int L, int R) { return s[R] - s[L]; }\n};\n#line 3 \"cp-library/src/utility/heap.hpp\"\n\ntemplate < class T > using heap_min = std::priority_queue< T, std::vector< T >, std::greater< T > >;\ntemplate < class T > using heap_max = std::priority_queue< T, std::vector< T >, std::less< T > >;\n\n#line 27 \"cp-library/src/cp-template.hpp\"\n\n#line 1 \"cp-library/src/algorithm/bin_search.hpp\"\ntemplate < class T, class F >\nT bin_search(T ok, T ng, F f) {\n while(abs(ng - ok) > 1) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n\ntemplate < class T, class F >\nT bin_search_real(T ok, T ng, F f, int step = 80) {\n while(step--) {\n T mid = (ok + ng) / 2;\n (f(mid) ? ok : ng) = mid;\n }\n return ok;\n}\n#line 2 \"cp-library/src/algorithm/argsort.hpp\"\n\ntemplate < class T > std::vector< int > argsort(const std::vector< T > &a) {\n std::vector< int > ids((int)a.size());\n std::iota(ids.begin(), ids.end(), 0);\n std::sort(ids.begin(), ids.end(), [&](int i, int j) {\n return a[i] < a[j] || (a[i] == a[j] && i < j);\n });\n return ids;\n}\n#line 1 \"macro.hpp\"\nnamespace macro {\n\nusing size_type = int;\ntemplate < class container > void sort(container& a) { std::sort(std:: begin(a), std:: end(a)); }\ntemplate < class container > void rsort(container& a) { std::sort(std::rbegin(a), std::rend(a)); }\ntemplate < class container > void reverse(container& a) { std::reverse(std::begin(a), std::end(a)); }\ntemplate < class container > void unique(container& a) {\n std::sort(std::begin(a), std::end(a));\n a.erase(std::unique(std::begin(a), std::end(a)), std::end(a));\n}\ntemplate < class container > container sorted(const container& a) { container b = a; sort(b); return std::move(b); }\ntemplate < class container > container rsorted(const container& a) { container b = a; rsort(b); return std::move(b); }\ntemplate < class container, class compare > void sort(container& a, const compare& cmp) { std::sort(std::begin(a), std::end(a), cmp); }\ntemplate < class container, class compare > container sorted(const container& a, const compare& cmp) { container b = a; sort(b, cmp); return std::move(b); }\ntemplate < class container, class value > size_type lower_bound(const container& a, const value& x) { return std::lower_bound(std::begin(a), std::end(a), x) - std::begin(a); }\ntemplate < class container, class value > size_type upper_bound(const container& a, const value& x) { return std::upper_bound(std::begin(a), std::end(a), x) - std::begin(a); }\n\nconst std::vector<std::pair<size_type, size_type>> dir4 = { {+1, 0}, {-1, 0}, { 0, +1}, { 0, -1} };\nconst std::vector<std::pair<size_type, size_type>> dir8 = { {-1, -1}, {-1, 0}, {-1, +1}, { 0, -1}, { 0, +1}, {+1, -1}, {+1, 0}, {+1, +1} };\n\n#ifdef _DEBUG\n#define debug(x) std::cout << \"[\" << __LINE__ << \"] \" << #x << \": \" << x << std::endl\n#else\n#define debug(x)\n#endif\n\ntemplate < class container > void concat(container& a, const container& b) {\n a.insert(std::end(a), std::begin(b), std::end(b));\n}\nstd::vector<size_type> iota(const size_type n) {\n std::vector<size_type> I(n);\n std::iota(std::begin(I), std::end(I), 0);\n return I;\n}\ntemplate < class container > std::vector<size_type> sort_idx(const container& a) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return a[i] < a[j] or (a[i] == a[j] and i < j); });\n return I;\n}\ntemplate < class container, class compare > std::vector<size_type> sort_idx(const container& a, const compare& cmp) {\n const size_type n = a.size();\n std::vector<size_type> I = iota(n);\n std::sort(std::begin(I), std::end(I), [&](size_type i, size_type j) { return cmp(a[i], a[j]) or (a[i] == a[j] and i < j); });\n return std::move(I);\n}\n\nstruct grid {\n using size_type = int;\n size_type H, W;\n grid(const size_type H, const size_type W) : H(H), W(W) {}\n bool contains(const size_type i, const size_type j) {\n return 0 <= i and i < H and 0 <= j and j < W;\n }\n};\n\nusing f64 = long double;\n\ntemplate < class T > vector< T >& operator++(vector< T >& a) { for(T& x : a) x++; return a; }\ntemplate < class T > vector< T >& operator--(vector< T >& a) { for(T& x : a) x--; return a; }\ntemplate < class T > vector< T > operator++(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x++; return res; }\ntemplate < class T > vector< T > operator--(vector< T >& a, signed) { vector< T > res = a; for(T& x : a) x--; return res; }\n\n} // namespace macro\n\nusing namespace macro;\n#line 2 \"cp-library/src/data_structure/sliding_window_aggregation.hpp\"\n\ntemplate < class monoid >\nstruct swag_queue {\n public:\n using T = typename monoid::set;\n class node {\n public:\n T value, sum;\n node() : value(monoid::id()), sum(monoid::id()) {}\n node(const T& value, const T& sum) : value(value), sum(sum) {}\n };\n std::stack<node> front_stack, back_stack;\n\n public:\n swag_queue() { front_stack.push(node()), back_stack.push(node()); }\n int size() const {\n return (int(front_stack.size()) - 1) + (int(back_stack.size()) - 1);\n }\n bool empty() const {\n return size() == 0;\n }\n T fold() const {\n return monoid::op(front_stack.top().sum, back_stack.top().sum);\n }\n void push(const T& x) {\n back_stack.push(node(x, monoid::op(back_stack.top().sum, x)));\n }\n void pop() {\n assert(not empty());\n if(front_stack.size() == 1) {\n while(back_stack.size() > 1) {\n front_stack.push(node(back_stack.top().value, monoid::op(back_stack.top().value, front_stack.top().sum)));\n back_stack.pop();\n }\n }\n front_stack.pop();\n }\n};\n\ntemplate < class monoid >\nstruct swag_deque {\n private:\n using T = typename monoid::set;\n class node {\n public:\n T value, sum;\n node() : value(monoid::id()), sum(monoid::id()) {}\n node(const T& value, const T& sum) : value(value), sum(sum) {}\n };\n std::stack<node> front_stack, back_stack;\n\n public:\n swag_deque() { front_stack.push(node()), back_stack.push(node()); }\n int size() const { return (int(front_stack.size()) - 1) + (int(back_stack.size()) - 1); }\n bool empty() const { return size() == 0; }\n\n T fold() const { return monoid::op(front_stack.top().sum, back_stack.top().sum); }\n void push_front(const T& x) { push(front_stack, x, 1); }\n void push_back (const T& x) { push( back_stack, x, 0); }\n void pop_front() { assert(not empty()); if(front_stack.size() == 1) amortize( back_stack, front_stack, 1); front_stack.pop(); }\n void pop_back () { assert(not empty()); if( back_stack.size() == 1) amortize(front_stack, back_stack, 0); back_stack.pop(); }\n\n private:\n void push(std::stack<node>& st, const T& x, int f) {\n st.push(node(x, f ? monoid::op(x, st.top().sum) : monoid::op(st.top().sum, x)));\n }\n void amortize(std::stack<node>& from, std::stack<node>& to, int f) {\n std::stack< T > st;\n while(st.size() < from.size() - 2) st.push(from.top().value), from.pop();\n while(from.size() > 1) push(to, from.top().value, f), from.pop();\n while(not st.empty()) push(from, st.top(), 1 - f), st.pop();\n printer::flush();\n }\n};\n#line 3 \"cp-library/src/algebra/minmax.hpp\"\n\ntemplate < class T > class min_monoid {\n public:\n using set = T;\n static constexpr T op(const T &l, const T &r) { return std::min(l, r); }\n static constexpr T id() { return std::numeric_limits< T >::max(); }\n static constexpr bool comm = true;\n};\n\ntemplate < class T > class max_monoid {\n public:\n using set = T;\n static constexpr T op(const T &l, const T &r) { return std::max(l, r); }\n static constexpr T id() { return std::numeric_limits< T >::min(); }\n static constexpr bool comm = true;\n};\n#line 5 \"A.cpp\"\n\nint main() {\n int N = in(); i64 D = in();\n vector<i64> X(N), Y(N);\n for(int i : rep(N)) X[i] = in(), Y[i] = in();\n\n const int N1 = N / 2;\n const int N2 = N - N1;\n\n vector<pair<i64,i64>> A = [&] {\n vector<pair<i64,i64>> res;\n for(int S : rep(1 << N1)) {\n for(int T = S; ; T = (T - 1) & S) {\n i64 a = 0, b = 0;\n for(int i : rep(N1)) {\n if(S & (1 << i)) {\n if(T & (1 << i)) {\n a += X[i];\n b += Y[i];\n } else {\n a -= X[i];\n b -= Y[i];\n }\n } else {\n\n }\n }\n res.push_back({a, b});\n if(T == 0) break;\n }\n }\n sort(res);\n return res;\n }();\n\n vector<pair<i64,i64>> B = [&] {\n vector<pair<i64,i64>> res;\n for(int S : rep(1 << N2)) {\n for(int T = S; ; T = (T - 1) & S) {\n i64 a = 0, b = 0;\n for(int i : rep(N2)) {\n if(S & (1 << i)) {\n if(T & (1 << i)) {\n a += X[N1 + i];\n b += Y[N1 + i];\n } else {\n a -= X[N1 + i];\n b -= Y[N1 + i];;\n }\n } else {\n\n }\n }\n res.push_back({a, b});\n\n if(T == 0) break;\n }\n }\n sort(res);\n return res;\n }();\n\n swag_queue<max_monoid<i64>> q;\n const int nA = A.size();\n const int nB = B.size();\n int L = 0, R = 0;\n i64 ans = 0;\n\n for(int i : rep(nA)) {\n while(R < nB and B[R].first <= A[i].first + D) {\n q.push(B[R].second);\n R++;\n }\n while(L < nB and not(A[i].first - D <= B[L].first)) {\n q.pop();\n L++;\n }\n if(not q.empty() and A[i].first - D <= B[L].first and B[R - 1].first <= A[i].first + D) {\n chmax(ans, q.fold() - A[i].second);\n }\n }\n print(ans);\n}", "accuracy": 1, "time_ms": 3180, "memory_kb": 491828, "score_of_the_acc": -0.3667, "final_rank": 10 }, { "submission_id": "aoj_0613_8128000", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n ll D; cin >> D;\n vector<ll> x(n),y(n);\n for (int i = 0; i < n; ++i) {\n cin >> x[i] >> y[i];\n }\n vector<int> po(20); po[0] = 1;\n for (int i = 1; i < 20; ++i) {\n po[i] = po[i-1] * 3;\n }\n vector<pair<ll,ll>> a,b;\n {\n int pn = n/2;\n int bn = n-pn;\n a.resize(po[pn]);\n b.resize(po[bn]);\n auto dfs = [&](auto dfs, int l, int r, int i, pair<ll,ll> cur, vector<pair<ll,ll>> &v, int &pos) -> void {\n if (i == r) {\n v[pos++] = cur;\n return;\n }\n dfs(dfs, l, r, i+1, cur, v, pos);\n dfs(dfs, l, r, i+1, {cur.first+x[i], cur.second+y[i]}, v, pos);\n dfs(dfs, l, r, i+1, {cur.first-x[i], cur.second-y[i]}, v, pos);\n };\n int pos = 0;\n dfs(dfs, 0, pn, 0, {0,0}, a, pos);\n pos = 0;\n dfs(dfs, pn, n, pn, {0,0}, b, pos);\n }\n sort(a.begin(), a.end());\n a.erase(unique(a.begin(), a.end()), a.end());\n sort(b.begin(), b.end());\n b.erase(unique(b.begin(), b.end()), b.end());\n\n ll res = 0;\n deque<pair<ll,ll>> dq;\n int id = b.size()-1;\n for (int i = 0; i < a.size(); ++i) {\n ll d = a[i].first;\n while (id >= 0 and d+b[id].first >= -D) {\n if (d+b[id].first <= D) {\n while (dq.size() and dq.back().second <= b[id].second) dq.pop_back();\n dq.push_back(b[id]);\n }\n id -= 1;\n }\n while (dq.size() and dq.front().first+d > D) dq.pop_front();\n if (dq.size()) res = max(res, a[i].second+dq.front().second);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 2420, "memory_kb": 451600, "score_of_the_acc": -0.001, "final_rank": 1 }, { "submission_id": "aoj_0613_7908795", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string.h>\n#include <cmath>\nusing namespace std;\nlong long int st[21523360];\nlong long int minn=-4*pow(10,17);\nstruct E{\n\tlong long int x,y;\n\tbool operator<(const E& e)const{\n\t\tif(x!=e.x)return x<e.x;\n\t\treturn y<e.y;\n\t}\n};\nvector<E> vsl,vsr,vst;\nlong long int xs[31];\nlong long int ys[31];\nlong long int n,d;\nvoid f(long long int x,long long int y,int deep1,int r,vector<E>& vs){\n\tif(deep1==r){\n\t\tE e;\n\t\te.x=x;\n\t\te.y=y;\n\t\tvs.push_back(e);\n\t}else{\n\t\tf(x+xs[deep1],y-ys[deep1],deep1+1,r,vs);\n\t\tf(x-xs[deep1],y+ys[deep1],deep1+1,r,vs);\n\t\tf(x,y,deep1+1,r,vs);\n\t}\n}\nlong long int addst(int no,int x,long long int v,int l,int r){\n\tif(x<l || r<x)return st[no];\n\tif(l==r){\n\t\tst[no]=v;\n\t\treturn v;\n\t}else{\n\t\tint d=(r-l+1)/3;\n\t\tint m1=l+d;\n\t\tint m2=m1+d;\n\t\tlong long int res=addst(no*3+1,x,v,l,m1-1);\n\t\tres=max(res,addst(no*3+2,x,v,m1,m2-1));\n\t\tres=max(res,addst(no*3+3,x,v,m2,r));\n\t\tst[no]=max(res,st[no]);\n\t\treturn st[no];\n\t}\n}\nlong long int getst(int no,int l,int r,int l2,int r2){\n\tif(r2<l || r<l2)return minn;\n\tif(l==r){\n\t\treturn st[no];\n\t}else if(l2<=l && r<=r2){\n\t\t//cout<<l<<\" \"<<r<<\" st \"<<st[no]<<endl;\n\t\treturn st[no];\n\t}else{\n\t\tint d=(r-l+1)/3;\n\t\tint m1=l+d;\n\t\tint m2=m1+d;\n\t\tlong long int res=getst(no*3+1,l,m1-1,l2,r2);\n\t\tres=max(res,getst(no*3+2,m1,m2-1,l2,r2));\n\t\tres=max(res,getst(no*3+3,m2,r,l2,r2));\n\t\treturn res;\n\t}\n\t\n}\n\nint main() {\n\tfor(int i=0;i<21523360;i++){\n\t\tst[i]=minn;\n\t}\n\tcin>>n>>d;\n\t\n\tfor(int i=0;i<n;i++){\n\t\tcin>>xs[i]>>ys[i];\n\t}\n\tlong long int ans=0;\n\tif(n==1){\n\t\tif(xs[0]<=d){\n\t\t\tcout<<ys[0]<<endl;\n\t\t}else{\n\t\t\tcout<<0<<endl;\n\t\t}\n\t}else{\n\t\tf(0,0,0,n/2,vsl);\n\t\tf(0,0,n/2,n,vsr);\n\t\tsort(vsl.begin(),vsl.end());\n\t\tsort(vsr.begin(),vsr.end());\n\t\tint maxr=vsr.size()-1;\n\t\tfor(int i=0;i<vsr.size();i++){\n\t\t\tlong long int t=addst(0,i,vsr[i].y,0,maxr);\n\t\t}\n\t\tint pd=maxr;\n\t\tint pu=maxr;\n\t\t\n\t\tint maxl=vsl.size();\n\t\tfor(int i=0;i<maxl;i++){\t\n\t\t\tlong long int x=vsl[i].x;\n\t\t\twhile(pd>0 && x+vsr[pd-1].x>=-d){\n\t\t\t\tpd--;\n\t\t\t}\n\t\t\t\n\t\t\twhile(pu>0 && vsr[pu-1].x+x>d){\n\t\t\t\tpu--;\n\t\t\t}\n\t\t\tif(pu>pd && vsr[pu].x+x>d)pu--;\n\t\t\tlong long int x1,x2;\n\t\t\tx1=vsr[pu].x;\n\t\t\tx2=vsr[pd].x;\n\t\t\t//cout<<x<<\" \"<<x1<<\" \"<<x2<<endl;\n\t\t\tif(abs(x+x1)<=d && abs(x+x2)<=d){\n\t\t\t\t\n\t\t\t\tlong long int t2=getst(0,0,maxr,pd,pu);\n\t\t\t\t//cout<<vsl[i].y<<\" \"<<t2<<endl;\n\t\t\t\tans=max(ans,vsl[i].y+t2);\n\t\t\t}\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n\t\n\t//f(0,0,0,n,vst);\n\t//long long int ans2=0;\n\t//for(int i=0;i<vst.size();i++){\n\t//\tE e1=vst[i];\n//\t\tif(abs(e1.x)<=d)ans2=max(ans2,e1.y);\n//\t}\n//\tcout<<ans2<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3680, "memory_kb": 659972, "score_of_the_acc": -1.1412, "final_rank": 16 }, { "submission_id": "aoj_0613_7018920", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/modint>\n\n#define rep(i, x) for (ll i = 0; i < x; i++)\n#define rep2(i, x) for (ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for (ll i = x; i < y; i++)\n#define REP(i, x) for (ll i = x - 1; i >= 0; i--)\n#define REP2(i, x) for (ll i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define pb push_back\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\n// using namespace atcoder;\n\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n// const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError\n{\n};\n\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n if (a > b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nbool isprime(ll p)\n{\n if (p == 1)\n return false;\n for (ll i = 2; i * i <= p; i++)\n {\n if (p % i == 0)\n return false;\n }\n return true;\n}\n//エラトステネスの篩\nvector<bool> isprime_format(ll n)\n{\n vector<bool> P(n + 1, 1);\n P[0] = P[1] = 1;\n for (ll i = 2; i * i <= n; i++)\n {\n if (!P[i])\n continue;\n for (int j = i + i; j <= n; j += i)\n P[j] = false;\n }\n return P;\n}\nvector<ll> prime_format(ll n)\n{\n vector<bool> P = isprime_format(n);\n vector<ll> ans;\n for (int i = 2; i <= n; i++)\n {\n if (P[i])\n ans.push_back(i);\n }\n return ans;\n}\nll extGCD(ll a, ll b, ll &x, ll &y)\n{\n // ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n // 返り値: a と b の最大公約数\n // ax + by = gcd(a, b) を満たす (x, y) が格納される\n // main関数内に extGCD(a, b, x, y); でx, yに解が格納\n if (b == 0)\n {\n x = 1;\n y = 0;\n return a;\n }\n ll d = extGCD(b, a % b, y, x);\n y -= a / b * x;\n return d;\n}\nll keta(ll n)\n{\n ll res = 0;\n while (n >= 1)\n {\n // res++;\n res += n % 10;\n\n n /= 10;\n }\n return res;\n}\nll modpow(ll x, ll y, ll m)\n{\n ll res = 1;\n while (y)\n {\n if (y % 2)\n {\n res *= x;\n res %= m;\n }\n x = x * x % m;\n y /= 2;\n }\n return res;\n}\n\nunsigned int xorshift()\n{\n // xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n // 1~6まで出したいときは\n // xorshift() % 6 + 1\n static unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n unsigned int tt = (tx ^ (tx << 11));\n tx = ty;\n ty = tz;\n tz = tw;\n return (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\nuint64_t seed = 123456789;\nuint64_t xorshift64()\n{\n seed ^= seed << 13;\n seed ^= seed >> 17;\n seed ^= seed << 7;\n return seed;\n}\nint rand_int(int l, int r)\n{\n return l + int(xorshift64() % (r - l));\n}\ndouble randouble()\n{\n return double(xorshift64()) / double(uint64_t(-1));\n}\n\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> pp;\n//左上右下\nll dx[4] = {0, -1, 0, 1}, dy[4] = {-1, 0, 1, 0};\nll ndx[4] = {1, -1, -1, 1}, ndy[4] = {1, 1, -1, -1};\nchar ds[4] = {'l', 'u', 'r', 'd'};\nchar dl[4] = {'L', 'U', 'R', 'D'};\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n)\n{\n spf.resize(n + 1);\n spf[1] = 1;\n for (int i = 2; i <= n; i++)\n {\n if (!spf[i])\n {\n for (int j = i; j < n; j += i)\n {\n spf[j] = i;\n }\n }\n }\n}\nstd::map<int, int> high_speed_prime_factor(int n)\n{\n std::map<int, int> res;\n while (n != 1)\n {\n res[spf[n]]++;\n n /= spf[n];\n }\n return res;\n}\n\n////////////////////////////////struct\n\nstruct Comb\n{\n // https://atcoder.jp/contests/abc156/submissions/33741990\n\n ll nCrMAX;\n ll m;\n vector<ll> fac, finv, inv; // n!、1/n!、1/n\n\n Comb(ll kMOD, ll kMAX = 612345)\n {\n nCrMAX = kMAX;\n m = kMOD;\n fac.resize(nCrMAX);\n finv.resize(nCrMAX);\n inv.resize(nCrMAX);\n\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < nCrMAX; i++)\n {\n fac[i] = fac[i - 1] * i % m;\n inv[i] = m - inv[m % i] * (m / i) % m;\n finv[i] = finv[i - 1] * inv[i] % m;\n }\n }\n\n ll nCr(ll n, ll k)\n {\n if (k < nCrMAX)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n else\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n }\n\n ll nCr1(ll n, ll k)\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n\n //(nが大きくて)kが小さい時\n // nCrMAXはk+2まででOK\n ll nCr2(ll n, ll k)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n};\n\nvoid yes(bool a) { cout << (a ? \"yes\" : \"no\") << endl; }\nvoid YES(bool a) { cout << (a ? \"YES\" : \"NO\") << endl; }\nvoid Yes(bool a) { cout << (a ? \"Yes\" : \"No\") << endl; }\nvoid Possible(bool a) { cout << (a ? \"Possible\" : \"Impossible\") << endl; }\n// struct edge {\n//\tll to; ll cost;\n// };\n\nstruct Point\n{\n ll x, y;\n Point operator+(const Point &p) const noexcept { return {x + p.x, y + p.y}; }\n Point operator-(const Point &p) const noexcept { return {x - p.x, y - p.y}; }\n Point operator*(const ll k) const noexcept { return {x * k, y * k}; }\n Point operator/(const ll k) const noexcept { return {x / k, y / k}; }\n Point &operator+=(const Point &p) noexcept\n {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) noexcept\n {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n bool operator<(const Point &p) const noexcept { return (x != p.x ? x < p.x : y < p.y); }\n};\n\n// using mint = modint998244353;\n\nstruct edge\n{\n ll to, cost;\n};\n\nstruct status\n{\n ll d1;\n ll d2;\n\n // bool operator<(const status& rhs) const { return c < rhs.c; };\n // bool operator>(const status& rhs) const { return c > rhs.c; };\n bool operator<(const status &rhs) const { return d1 < rhs.d1; };\n bool operator>(const status &rhs) const { return d1 > rhs.d1; };\n};\nstruct rmq2\n{\n ll nn;\n vector<ll> dat;\n\n rmq2(ll n = 1)\n {\n init(n);\n }\n void init(ll n_)\n { //初期化\n nn = n_;\n dat.resize(nn + nn / 2);\n }\n void update(ll k, ll a)\n { // k番目の値(0-indexed)をaに変更\n k += nn / 2;\n dat[k] = a; //葉の節点\n while (k > 0)\n { //登りながら更新\n k = (k - 1) / 3;\n dat[k] = max({dat[k * 3 + 1], dat[k * 3 + 2], dat[k * 3 + 3]});\n }\n }\n //[a, b)の最大値を求める\n // kは節点の番号、l, rはその節点が[l, r)に対応づいていることを表す。\n //したがって外からはquery(a, b, 0, 0, nn)として呼ぶ。\n ll query(ll a, ll b, ll k, ll l, ll r)\n {\n //cout<<a<<' '<<b<<' '<<l << ' ' << r<<endl;\n //[a, b)と[l, r)が交差しなければ、0\n //[a, b)が[l, r)を完全に含んでいれば、この節点の値\n if (r <= a || b <= l)\n {\n return 0;\n }\n if (a <= l && r <= b)\n {\n return dat[k];\n }\n else\n {\n ll v1 = query(a, b, k * 3 + 1, l, (l + l+ r) / 3);\n ll v2 = query(a, b, k * 3 + 2, (l + l + r) / 3, (l + r + r) / 3);\n ll v3 = query(a, b, k * 3 + 3, (l + r + r) / 3, r);\n return max({v1, v2, v3});\n }\n }\n};\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n // cout << fixed << setprecision(15);\n // priority_queue<ll, vector<ll>, greater<ll>> que;\n // priority_queue<P, vector<P>, greater<P>> que;\n // priority_queue<status, vector<status>, greater<status>> que;\n\n // 15個ずつに分けて3^15した後に、sortして、尺取りしながらセグメント木。\n // MLEしたのでセグメント木を3の倍数に変えた\n\n ll n, d;\n cin >> n >> d;\n\n vector<int> three(17);\n int kt = 1;\n rep(i, 17)\n {\n three[i] = kt;\n kt *= 3;\n }\n\n vector<Point> in(n);\n rep(i, n)\n {\n cin >> in[i].x >> in[i].y;\n }\n\n // 前半 N/2 個\n int ko1 = three[n / 2];\n vector<status> f(ko1);\n for (int i = 0; i < ko1; i++)\n {\n for (int j = 0; j < (n / 2); j++)\n {\n if ((i / three[j]) % 3 == 0)\n {\n f[i].d1 += in[j].x;\n f[i].d2 -= in[j].y;\n }\n if ((i / three[j]) % 3 == 1)\n {\n f[i].d1 -= in[j].x;\n f[i].d2 += in[j].y;\n }\n }\n }\n\n // 後半 N - N/2 個\n int ko2 = three[n - n / 2];\n vector<status> s(ko2);\n for (int i = 0; i < ko2; i++)\n {\n for (int j = 0; j < n - (n / 2); j++)\n {\n if ((i / three[j]) % 3 == 0)\n {\n s[i].d1 += in[j + (n / 2)].x;\n s[i].d2 -= in[j + (n / 2)].y;\n }\n if ((i / three[j]) % 3 == 1)\n {\n s[i].d1 -= in[j + (n / 2)].x;\n s[i].d2 += in[j + (n / 2)].y;\n }\n }\n }\n\n // ソートしたうえで半分全列挙をする\n sort(rall(f));\n sort(all(s));\n rmq2 seg(ko2);\n for (int i = 0; i < ko2; i++)\n {\n seg.update(i, s[i].d2);\n // cout<<s[i].d<<' '<<s[i].A.x<<' '<<s[i].A.y<<' '<<s[i].B.x<<' '<<s[i].B.y<<endl;\n }\n ll l = 0, r = 0, ans = 0;\n rep(i, ko1)\n {\n while (l != ko2 && f[i].d1 + s[l].d1 < 0 - d)\n {\n l++;\n }\n while (r != ko2 && f[i].d1 + s[r].d1 <= d)\n {\n r++;\n }\n if (l != r) chmax(ans, (f[i].d2) + seg.query(l, r, 0, 0, seg.nn));\n // cout<<l<<' '<<r<<endl;\n // cout<<f[i].d<<' '<<f[i].A.x<<' '<<f[i].A.y<<' '<<f[i].B.x<<' '<<f[i].B.y<<endl;\n // cout<<ans<<endl;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 5510, "memory_kb": 619612, "score_of_the_acc": -1.5046, "final_rank": 17 }, { "submission_id": "aoj_0613_6406972", "code_snippet": "#include <stdio.h>\n#include <iostream>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <algorithm>\n\ntypedef long long int ll;\ntypedef std::pair<ll, ll> P;\nconst int INF = (1<<30);\nconst ll INFLL = (1LL<<60);\nconst ll MOD = (ll)(1e9+7);\n\n#define l_ength size\n\nvoid mul_mod(ll& a, ll b){\n\ta *= b;\n\ta %= MOD;\n}\n\nvoid add_mod(ll& a, ll b){\n\ta = (a<MOD)?a:(a-MOD);\n\tb = (b<MOD)?b:(b-MOD);\n\ta += b;\n\ta = (a<MOD)?a:(a-MOD);\n}\n\nll x[33],y[33];\nstd::vector<P> v,u;\nstd::priority_queue<P> pq;\n\n/*\nvoid init(int i=0, int l=0, int r=segsize){\n\tif(r-l>1){\n\t\tinit(i*2+1,l,(l+r)/2);\n\t\tinit(i*2+2,(l+r)/2,r);\n\t\tsegvalue[i] = std::max(segvalue[i*2+1],segvalue[i*2+2]);\n\t\tsegrange[i] = P(segrange[i*2+1].first,segrange[i*2+2].second);\n\t}else{\n\t\tsegvalue[i] = v[l].second;\n\t\tsegrange[i] = P(v[l].first,v[l].first);\n\t}\n}\n\nll query(ll a, ll b, int i=0, int l=0, int r=segsize){\n\tif(b<segrange[i].first || segrange[i].second<a){\n\t\treturn -INFLL;\n\t}\n\tif(a <= segrange[i].first && segrange[i].second <= b){\n\t\treturn segvalue[i];\n\t}\n\treturn std::max(query(a,b,i*2+1,l,(l+r)/2),query(a,b,i*2+2,(l+r)/2,r));\n}\n*/\n\nvoid solve(int i, int n, bool flag, ll vl=0ll, ll sc=0ll){\n\tif(i == n){\n\t\tif(flag){\n\t\t\tu.push_back(P(vl,sc));\n\t\t\t// ans = std::max(ans,sc+query(-d-vl,d-vl));\n\t\t}else{\n\t\t\tv.push_back(P(vl,sc));\n\t\t}\n\t}else{\n\t\t// Annaが取る\n\t\tsolve(i+1,n,flag,vl-x[i],sc-y[i]);\n\t\t// Brunoが取る\n\t\tsolve(i+1,n,flag,vl+x[i],sc+y[i]);\n\t\t// 誰も取らない\n\t\tsolve(i+1,n,flag,vl,sc);\n\t}\n}\n\nint main(void){\n\tint n,m,i,j=0;\n\tll d,ans=0ll;\n\tv.reserve(14348907);\n\tu.reserve(14348907);\n\tscanf(\"%d%lld\",&n,&d);\n\tm = n/2;\n\tfor(i=0; i<n; ++i){\n\t\tscanf(\"%lld%lld\",&x[i],&y[i]);\n\t}\n\tsolve(m,n,false);\n\tsolve(0,m,true);\n\tn = v.l_ength(); m = u.l_ength();\n\tstd::sort(v.begin(),v.end(),std::greater<P>());\n\tstd::sort(u.begin(),u.end());\n\t// std::cout << n << \" \" << m << std::endl;\n\tfor(i=0; i<n; ++i){\n\t\twhile(j<m && u[j].first <= d-v[i].first){\n\t\t\t// std::cout << i << \" \" << j << std::endl;\n\t\t\tpq.push(P(u[j].second,u[j].first)); ++j;\n\t\t}\n\t\twhile(!pq.empty()){\n\t\t\tif(pq.top().second < (-d-v[i].first)){\n\t\t\t\tpq.pop();\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tans = std::max(ans,pq.top().first+v[i].second);\n\t\t\tbreak;\n\t\t}\n\t}\n\t/*\n\tsegsize = v.l_ength();\n\tinit();\n\t// solve(0,m,true);\n\t*/\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2690, "memory_kb": 451332, "score_of_the_acc": -0.0761, "final_rank": 3 }, { "submission_id": "aoj_0613_5865932", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\ntemplate<typename T>\nstruct segment_tree {\n using F = function<T(T, T)>; // 型Tの値を2つ受け取って型Tの値を返すような関数型\n\n int n;\n vector<T> node;\n F combine; // 区間の結合を行う演算\n T identity; // 単位元\n\n segment_tree(int n, F combine, T identity)\n : n(n), node(n<<1, identity), combine(combine), identity(identity) {}\n\n T operator[](int i) { return node[i + n]; }\n\n void set(int i, T x) {\n node[i += n] = x;\n // combine関数により、2つの子ノードを結合した結果を親ノードに記録\n while (i >>= 1) node[i] = combine(node[i<<1|0], node[i<<1|1]); \n\n }\n\n T fold(int l, int r) {\n T res = identity; // 初期値は単位元\n for (l += n, r += n; l < r; l >>= 1, r >>= 1) {\n // 区間内のものを左右から結合\n if (l & 1) res = combine(res, node[l++]); \n if (r & 1) res = combine(node[--r], res);\n }\n return res;\n }\n};\n\nll pow3[30];\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int n;\n ll D; cin >> n >> D;\n vector<ll> x(n), y(n);\n REP(i,n) cin >> x[i] >> y[i];\n int n1 = n/2;\n int n2 = n-n1;\n\n pow3[0] = 1;\n for(int i=1; i<=15; i++) pow3[i] = pow3[i-1] * 3;\n vector<pair<ll,ll>> v;\n REP(bit,pow3[n1]) {\n int t = bit;\n ll s1=0,s2=0;\n REP(i,n1) {\n if(t%3 == 1) {\n s1 += x[i];\n s2 += y[i];\n }else if(t%3 == 2) {\n s1 -= x[i];\n s2 -= y[i];\n }\n t/=3;\n }\n v.push_back({s1,s2});\n }\n sort(all(v));\n vector<ll> a, b;\n REP(i,v.size()) {\n a.push_back(v[i].first);\n b.push_back(v[i].second);\n }\n segment_tree<ll> seg(v.size(), [](ll a, ll b){return max(a, b);}, -(1LL<<60));\n REP(i,v.size()) seg.set(i, b[i]);\n ll ans = -(1LL<<60);\n REP(bit,pow3[n2]) {\n int t = bit;\n ll s1=0,s2=0;\n REP(i,n2) {\n if(t%3 == 1) {\n s1 += x[n1+i];\n s2 += y[n1+i];\n }else if(t%3 == 2) {\n s1 -= x[n1+i];\n s2 -= y[n1+i];\n }\n t/=3;\n }\n ll l = -D-s1, r = D-s1;\n if(l > r) swap(l, r);\n l = lower_bound(all(a), l) - a.begin();\n r = upper_bound(all(a), r) - a.begin();\n if(l == r) continue;\n ans = max(ans, s2 + seg.fold(l, r));\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 5580, "memory_kb": 680044, "score_of_the_acc": -1.752, "final_rank": 19 }, { "submission_id": "aoj_0613_4343918", "code_snippet": "#include<cstdio>\n#include<cstdlib>\n#include<vector>\n#include<algorithm>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> PL;\nint n;\nll d,x[33],y[33],deq[15000010];\nvector<PL> vec[2];\nvoid zen(int idx,int l,int r,ll nx,ll ny){\n if(l >= r) vec[idx].push_back(PL(nx,ny));\n else {\n zen(idx,l+1,r,nx,ny);\n zen(idx,l+1,r,nx+x[l],ny+y[l]);\n zen(idx,l+1,r,nx-x[l],ny-y[l]);\n }\n}\n\nint main()\n{\n scanf(\"%d %lld\",&n,&d);\n for(int i=0;i<n;i++) scanf(\"%lld %lld\",&x[i],&y[i]);\n \n zen(0,0,n/2,0,0);\n zen(1,n/2,n,0,0);\n \n sort(vec[0].begin(),vec[0].end());\n reverse(vec[0].begin(),vec[0].end());\n sort(vec[1].begin(),vec[1].end());\n \n int s=0,t=0;\n ll ans = 0;\n for(int i=0,j=0;i<vec[0].size();i++){\n while(j < vec[1].size() && vec[0][i].first+vec[1][j].first <= d){\n while(s < t && vec[1][deq[t-1]].second <= vec[1][j].second) t--;\n deq[t++] = j;\n j++;\n }\n while(s < t && vec[0][i].first+vec[1][deq[s]].first < -d) s++;\n if(s < t) ans = max(ans,vec[0][i].second+vec[1][deq[s]].second);\n }\n printf(\"%lld\\n\",ans);\n \n return(0);\n}", "accuracy": 1, "time_ms": 2810, "memory_kb": 488760, "score_of_the_acc": -0.2509, "final_rank": 8 }, { "submission_id": "aoj_0613_4343911", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cstdlib>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> PL;\nint n;\nll d,x[33],y[33],deq[15000010];\nvector<PL> vec[2];\nvoid zen(int idx,int l,int r,ll nx,ll ny){\n if(l >= r) vec[idx].push_back(PL(nx,ny));\n else {\n zen(idx,l+1,r,nx,ny);\n zen(idx,l+1,r,nx+x[l],ny+y[l]);\n zen(idx,l+1,r,nx-x[l],ny-y[l]);\n }\n}\n\nint main()\n{\n cin >> n >> d;\n for(int i=0;i<n;i++) cin >> x[i] >> y[i];\n \n zen(0,0,n/2,0,0);\n zen(1,n/2,n,0,0);\n \n sort(vec[0].begin(),vec[0].end());\n reverse(vec[0].begin(),vec[0].end());\n sort(vec[1].begin(),vec[1].end());\n \n int s=0,t=0;\n ll ans = 0;\n for(int i=0,j=0;i<vec[0].size();i++){\n while(j < vec[1].size() && vec[0][i].first+vec[1][j].first <= d){\n while(s < t && vec[1][deq[t-1]].second <= vec[1][j].second) t--;\n deq[t++] = j;\n j++;\n }\n while(s < t && vec[0][i].first+vec[1][deq[s]].first < -d) s++;\n if(s < t) ans = max(ans,vec[0][i].second+vec[1][deq[s]].second);\n }\n cout << ans << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 2820, "memory_kb": 489252, "score_of_the_acc": -0.2556, "final_rank": 9 }, { "submission_id": "aoj_0613_4343908", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cstdlib>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> PL;\nint n;\nll d,x[33],y[33],deq[15000010];\nvector<PL> vec[2];\nvoid zen(int idx,int l,int r,ll nx,ll ny){\n if(l >= r) vec[idx].push_back(PL(nx,ny));\n else {\n zen(idx,l+1,r,nx,ny);\n zen(idx,l+1,r,nx+x[l],ny+y[l]);\n zen(idx,l+1,r,nx-x[l],ny-y[l]);\n }\n}\n\nint main()\n{\n cin >> n >> d;\n for(int i=0;i<n;i++) cin >> x[i] >> y[i];\n \n zen(0,0,n/2,0,0);\n zen(1,n/2,n,0,0);\n \n sort(vec[0].begin(),vec[0].end());\n reverse(vec[0].begin(),vec[0].end());\n sort(vec[1].begin(),vec[1].end());\n \n int s=0,t=0;\n ll ans = 0;\n for(int i=0,j=0;i<vec[0].size();i++){\n while(j < vec[1].size() && vec[0][i].first+vec[1][j].first <= d){\n while(s < t && vec[1][deq[t-1]].second <= vec[1][j].second) t--;\n deq[t++] = j;\n j++;\n }\n while(s < t && vec[0][i].first+vec[1][deq[s]].first < -d) s++;\n ans = max(ans,vec[0][i].second+vec[1][deq[s]].second);\n }\n cout << ans << endl;\n \n return(0);\n}", "accuracy": 0.42857142857142855, "time_ms": 2550, "memory_kb": 489152, "score_of_the_acc": -0.1791, "final_rank": 20 }, { "submission_id": "aoj_0613_4193206", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\ntemplate <typename T> using posteriority_queue = priority_queue<T, vector<T>, greater<T> >;\nconst int INF = 0x3f3f3f3f;\nconst ll LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconst int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\ntemplate <typename T> void unique(vector<T> &a) { a.erase(unique(ALL(a)), a.end()); }\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int n; ll d; cin >> n >> d;\n vector<ll> x(n), y(n); REP(i, n) cin >> x[i] >> y[i];\n vector<pair<ll, ll> > a;\n function<void(int, ll, ll)> rec1 = [&](int idx, ll val, ll bruno) {\n if (idx == (n >> 1)) {\n a.emplace_back(val, bruno);\n return;\n }\n rec1(idx + 1, val, bruno);\n rec1(idx + 1, val + x[idx], bruno - y[idx]);\n rec1(idx + 1, val - x[idx], bruno + y[idx]);\n };\n rec1(0, 0, 0);\n sort(ALL(a));\n vector<pair<ll, ll> > b;\n function<void(int, ll, ll)> rec2 = [&](int idx, ll val, ll bruno) {\n if (idx == n) {\n b.emplace_back(val, bruno);\n return;\n }\n rec2(idx + 1, val, bruno);\n rec2(idx + 1, val + x[idx], bruno - y[idx]);\n rec2(idx + 1, val - x[idx], bruno + y[idx]);\n };\n rec2(n >> 1, 0, 0);\n sort(ALL(b));\n reverse(ALL(b));\n int p = a.size(), q = b.size();\n deque<int> deq;\n int ba = 0, fr = 0;\n ll ans = 0;\n REP(i, q) {\n while (fr < p && a[fr].first <= d - b[i].first) {\n while (!deq.empty() && a[deq.back()].second <= a[fr].second) deq.pop_back();\n deq.emplace_back(fr++);\n }\n while (ba < fr && a[ba].first < -d - b[i].first) {\n if (deq.front() == ba++) deq.pop_front();\n }\n if (!deq.empty()) chmax(ans, b[i].second + a[deq.front()].second);\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 489204, "score_of_the_acc": -0.2385, "final_rank": 6 }, { "submission_id": "aoj_0613_4165447", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst ll INF = 1e+15;\n\nclass SlideMax {\npublic:\n deque<pair<ll,ll>> dq;\n SlideMax(){};\n void push(ll val, ll i) {\n while ( ! dq.empty() && dq.back().first <= val) {\n dq.pop_back();\n }\n dq.push_back(make_pair(val, i));\n }\n void pop(ll i) {\n while ( ! dq.empty() && dq.front().second < i) {\n dq.pop_front();\n }\n }\n ll getval() {\n if (dq.empty()) return -INF;\n return dq.front().first;\n }\n};\n\n/**\n * dx := Brunoの市場価値 - Annaの市場価値\n * dy := Brunoの貴重度 - Annaの貴重度\n */\nvoid f(int i, int n, ll dx, ll dy, vector<ll> &x, vector<ll> &y, vector<pair<ll,ll>> &res) {\n if (i == n) {\n res.emplace_back(dx, dy);\n return ;\n }\n f(i+1, n, dx, dy, x, y, res); // No one\n f(i+1, n, dx-x[i], dy-y[i], x, y, res); // Anna\n f(i+1, n, dx+x[i], dy+y[i], x, y, res); // Bruno\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n \n int N; ll D;\n cin >> N >> D;\n vector<ll> x(N), y(N);\n for (int i=0; i<N; ++i) cin >> x[i] >> y[i];\n\n vector<pair<ll,ll>> L, R;\n f(0, N/2, 0, 0, x, y, L);\n f(N/2, N, 0, 0, x, y, R);\n sort(L.rbegin(), L.rend());\n sort(R.begin(), R.end());\n\n SlideMax smax;\n int k = 0;\n ll mx = 0;\n for (int i=0; i<(int)L.size(); ++i) {\n while (k < (int)R.size() && R[k].first <= -L[i].first+D) {\n smax.push(R[k].second, R[k].first);\n k ++;\n }\n smax.pop(-L[i].first-D);\n mx = max(mx, L[i].second + smax.getval());\n }\n cout << mx << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 489088, "score_of_the_acc": -0.2381, "final_rank": 5 }, { "submission_id": "aoj_0613_4165442", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nconst double eps = 1e-8;\nconst ll INF = (ll)1e+15;\n\nclass SlideMax {\npublic:\n deque<pair<ll,ll>> dq;\n SlideMax(){};\n void push(ll val, ll i) {\n while ( ! dq.empty() && dq.back().first <= val) {\n dq.pop_back();\n }\n dq.push_back(make_pair(val, i));\n }\n void pop(ll i) {\n while ( ! dq.empty() && dq.front().second < i) {\n dq.pop_front();\n }\n }\n ll getval() {\n if (dq.empty()) return -INF;\n return dq.front().first;\n }\n};\n\n/**\n * dx := Brunoの市場価値 - Annaの市場価値\n * dy := Brunoの貴重度 - Annaの貴重度\n */\nvoid f(int i, int n, ll dx, ll dy, vector<ll> &x, vector<ll> &y, vector<pair<ll,ll>> &res) {\n if (i == n) {\n res.emplace_back(dx, dy);\n return ;\n }\n f(i+1, n, dx, dy, x, y, res); // No one\n f(i+1, n, dx-x[i], dy-y[i], x, y, res); // Anna\n f(i+1, n, dx+x[i], dy+y[i], x, y, res); // Bruno\n}\n\nint main() {\n int N; ll D;\n cin >> N >> D;\n\n vector<ll> x(N), y(N);\n for (int i=0; i<N; ++i) cin >> x[i] >> y[i];\n\n vector<pair<ll,ll>> L, R;\n f(0, N/2, 0, 0, x, y, L);\n f(N/2, N, 0, 0, x, y, R);\n sort(L.rbegin(), L.rend());\n sort(R.begin(), R.end());\n\n SlideMax smax;\n int k = 0;\n ll mx = 0;\n for (int i=0; i<(int)L.size(); ++i) {\n while (k < (int)R.size() && R[k].first <= -L[i].first+D) {\n smax.push(R[k].second, R[k].first);\n k ++;\n }\n smax.pop(-L[i].first-D);\n mx = max(mx, L[i].second + smax.getval());\n }\n cout << mx << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 2740, "memory_kb": 489116, "score_of_the_acc": -0.2325, "final_rank": 4 }, { "submission_id": "aoj_0613_4165411", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nconst double eps = 1e-8;\nconst ll INF = (ll)1e+15;\n\nll p3(ll x) {\n return (ll)(pow(3, x) + eps);\n}\n\nclass SlideMax {\npublic:\n deque<pair<ll,ll>> dq;\n SlideMax(){};\n void push(ll val, ll i) {\n while ( ! dq.empty() && dq.back().first <= val) {\n dq.pop_back();\n }\n dq.push_back(make_pair(val, i));\n }\n void pop(ll i) {\n while ( ! dq.empty() && dq.front().second < i) {\n dq.pop_front();\n }\n }\n ll getval() {\n if (dq.empty()) return -INF;\n return dq.front().first;\n }\n};\n\nvoid _diff(int i, int n, ll dx, ll dy, vector<ll> &x, vector<ll> &y, vector<pair<ll,ll>> &res) {\n if (i == n) {\n res.emplace_back(dx, dy);\n return ;\n }\n _diff(i+1, n, dx, dy, x, y, res); // No one\n _diff(i+1, n, dx-x[i], dy-y[i], x, y, res); // Anna\n _diff(i+1, n, dx+x[i], dy+y[i], x, y, res); // Bruno\n}\n\n/**\n * @return (Brunoの市場価値 - Annaの市場価値, Brunoの貴重度 - Annaの貴重度)\n */\nvector<pair<ll,ll>> diff(vector<ll> &x, vector<ll> &y) {\n vector<pair<ll,ll>> res;\n int n = x.size();\n _diff(0, n, 0, 0, x, y, res);\n return res;\n}\n\nint main() {\n int N; ll D;\n cin >> N >> D;\n\n vector<ll> xl(N/2), yl(N/2);\n for (int i=0; i<N/2; ++i) {\n cin >> xl[i] >> yl[i];\n }\n auto L = diff(xl, yl);\n sort(L.rbegin(), L.rend());\n\n vector<ll> xr((N+1)/2), yr((N+1)/2);\n for (int i=0; i<(N+1)/2; ++i) {\n cin >> xr[i] >> yr[i];\n }\n auto R = diff(xr, yr);\n sort(R.begin(), R.end());\n\n SlideMax smax;\n int k = 0;\n ll mx = 0;\n for (int i=0; i<(int)L.size(); ++i) {\n while (k < (int)R.size() && R[k].first <= -L[i].first+D) {\n smax.push(R[k].second, R[k].first);\n k ++;\n }\n smax.pop(-L[i].first-D);\n mx = max(mx, L[i].second + smax.getval());\n }\n cout << mx << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 2770, "memory_kb": 489164, "score_of_the_acc": -0.2412, "final_rank": 7 }, { "submission_id": "aoj_0613_4164567", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <deque>\n#include <tuple>\n\nusing lint = long long;\n\nint ipow(int x, int e) {\n return (e == 0 ? 1 : x * ipow(x, e - 1));\n}\n\nstd::vector<std::pair<lint, lint>> enumerate(int m) {\n std::vector<lint> xs(m), ys(m);\n for (int i = 0; i < m; ++i) {\n std::cin >> xs[i] >> ys[i];\n }\n\n std::vector<std::pair<lint, lint>> ret;\n for (int t = 0; t < ipow(3, m); ++t) {\n int nt = t;\n lint dx = 0, dy = 0;\n for (int i = 0; i < m; ++i) {\n int k = nt % 3;\n nt /= 3;\n if (k == 0) {\n dx += xs[i];\n dy += ys[i];\n } else if (k == 1) {\n dx -= xs[i];\n dy -= ys[i];\n }\n }\n ret.emplace_back(dx, dy);\n }\n return ret;\n}\n\nvoid solve() {\n int n;\n lint diff;\n std::cin >> n >> diff;\n\n auto fore = enumerate(n / 2), back = enumerate(n - n / 2);\n std::sort(fore.begin(), fore.end());\n std::sort(back.rbegin(), back.rend());\n\n lint ans = 0;\n int r = 0;\n std::deque<std::pair<lint, lint>> que;\n\n for (auto f : fore) {\n lint dx, dy;\n std::tie(dx, dy) = f;\n\n while (r < (int)back.size() && dx + back[r].first >= -diff) {\n while (!que.empty() &&\n que.back().second <= back[r].second) {\n que.pop_back();\n }\n que.emplace_back(back[r++]);\n }\n\n while (!que.empty() &&\n dx + que.front().first > diff) {\n que.pop_front();\n }\n\n if (!que.empty()) ans = std::max(ans, dy + que.front().second);\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 4310, "memory_kb": 489088, "score_of_the_acc": -0.6747, "final_rank": 12 }, { "submission_id": "aoj_0613_4164565", "code_snippet": "#include <iostream>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <deque>\n#include <tuple>\n\nusing lint = long long;\n\nint ipow(int x, int e) {\n return (e == 0 ? 1 : x * ipow(x, e - 1));\n}\n\nstd::vector<std::pair<lint, lint>> enumerate(int m) {\n std::vector<lint> xs(m), ys(m);\n for (int i = 0; i < m; ++i) {\n std::cin >> xs[i] >> ys[i];\n }\n\n std::vector<std::pair<lint, lint>> ret;\n for (int t = 0; t < ipow(3, m); ++t) {\n int nt = t;\n lint dx = 0, dy = 0;\n for (int i = 0; i < m; ++i) {\n int k = nt % 3;\n nt /= 3;\n if (k == 0) {\n dx += xs[i];\n dy += ys[i];\n } else if (k == 1) {\n dx -= xs[i];\n dy -= ys[i];\n }\n }\n ret.emplace_back(dx, dy);\n }\n return ret;\n}\n\nvoid solve() {\n int n;\n lint diff;\n std::cin >> n >> diff;\n\n auto fore = enumerate(n / 2), back = enumerate(n - n / 2);\n std::sort(fore.begin(), fore.end());\n fore.erase(std::unique(fore.begin(), fore.end()), fore.end());\n std::sort(back.rbegin(), back.rend());\n back.erase(std::unique(back.begin(), back.end()), back.end());\n\n lint ans = 0;\n int r = 0;\n std::deque<std::pair<lint, lint>> que;\n\n for (auto f : fore) {\n lint dx, dy;\n std::tie(dx, dy) = f;\n\n while (r < (int)back.size() && dx + back[r].first >= -diff) {\n while (!que.empty() &&\n que.back().second <= back[r].second) {\n que.pop_back();\n }\n que.emplace_back(back[r++]);\n }\n\n while (!que.empty() &&\n dx + que.front().first > diff) {\n que.pop_front();\n }\n\n if (!que.empty()) ans = std::max(ans, dy + que.front().second);\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 4350, "memory_kb": 489276, "score_of_the_acc": -0.6867, "final_rank": 13 }, { "submission_id": "aoj_0613_3995834", "code_snippet": "#include <iostream>\n#include <vector>\n#include <deque>\n#include <cmath>\n#include <algorithm>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> treasure;\n\nint main() {\n int n;\n ll d;\n cin >> n >> d;\n vector<treasure> treasures(n);\n for (int i = 0; i < n; i++) cin >> treasures[i].first >> treasures[i].second;\n\n vector<treasure> a(pow(3, n / 2));\n for (int i = 0; i < pow(3, n / 2); i++) {\n int tmp = i;\n ll price = 0, value = 0;\n for (int j = 0; j < n / 2; j++) {\n switch (tmp % 3) {\n case 0: {\n price += treasures[j].first;\n value += treasures[j].second;\n break;\n }\n case 1: {\n price -= treasures[j].first;\n value -= treasures[j].second;\n break;\n }\n default:\n break;\n }\n tmp /= 3;\n }\n a[i].first = price, a[i].second = value;\n }\n sort(a.begin(), a.end(), greater<>());\n\n vector<treasure> b(pow(3, n - n / 2));\n for (int i = 0; i < pow(3, n - n / 2); i++) {\n int tmp = i;\n ll price = 0, value = 0;\n for (int j = 0; j < n - n / 2; j++) {\n switch (tmp % 3) {\n case 0: {\n price += treasures[n / 2 + j].first;\n value += treasures[n / 2 + j].second;\n break;\n }\n case 1: {\n price -= treasures[n / 2 + j].first;\n value -= treasures[n / 2 + j].second;\n break;\n }\n default:\n break;\n }\n tmp /= 3;\n }\n b[i].first = price, b[i].second = value;\n }\n sort(b.begin(), b.end());\n\n int bindex = 0;\n ll ret = 0;\n deque<int> que;\n for (auto x:a) {\n ll upperLimit = d - x.first;\n while (bindex < b.size() && b[bindex].first <= upperLimit) {\n while (!que.empty() && b[que.back()].second <= b[bindex].second)que.pop_back();\n que.push_back(bindex);\n bindex++;\n }\n\n ll lowerLimit = -d - x.first;\n while (!que.empty() && b[que.front()].first < lowerLimit)que.pop_front();\n\n if (!que.empty())ret = max(ret, x.second + b[que.front()].second);\n }\n\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 5450, "memory_kb": 451524, "score_of_the_acc": -0.8542, "final_rank": 14 }, { "submission_id": "aoj_0613_3977957", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"functional\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//const int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\n\n//const double EPS = 1e-8;\n\n//int N, M, K, H, W, L, R;\nlong long int N, M, K, H, W, L, R;\n\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> N >> K;\n\tvector<pair<long long int, long long int>>v(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> v[i].first >> v[i].second;\n\t}\n\tvector<pair<long long int, long long int>>a(pow(3, N / 2));\n\tvector<pair<long long int, long long int>>b(pow(3, N - N / 2));\n\tfor (int i = 0; i < N / 2; i++) {\n\t\tint add = pow(3, i);\n\t\tfor (int j = 0; j < add; j++) {\n\t\t\ta[j + add] = { a[j].first - v[i].first,a[j].second + v[i].second };\n\t\t\ta[j + 2 * add] = { a[j].first + v[i].first,a[j].second - v[i].second };\n\t\t}\n\t}\n\tfor (int i = 0; i < N - N / 2; i++) {\n\t\tint add = pow(3, i);\n\t\tfor (int j = 0; j < add; j++) {\n\t\t\tb[j + add] = { b[j].first - v[i + N / 2].first,b[j].second + v[i + N / 2].second };\n\t\t\tb[j + 2 * add] = { b[j].first + v[i + N / 2].first,b[j].second - v[i + N / 2].second };\n\t\t}\n\t}\n\tsort(a.begin(), a.end());\n\tsort(b.begin(), b.end());\n\tL = R = b.size() - 1;\n\tdeque<long long int>Q;\n\tmultiset<long long int>ms;\n\tlong long int ans = 0;\n\tfor (auto &i : a) {\n\t\twhile (L >= 0 && i.first + b[L].first >= -K) {\n\t\t\t//ms.insert(-b[L--].second);\n\t\t\tif (Q.empty())Q.push_back(L);\n\t\t\telse {\n\t\t\t\twhile (!Q.empty() && b[Q.back()].second < b[L].second)Q.pop_back();\n\t\t\t\tQ.push_back(L);\n\t\t\t}\n\t\t\tL--;\n\t\t}\n\t\twhile (R > L&& i.first + b[R].first > K) {\n\t\t\t//ms.erase(ms.find(-b[R--].second));\n\t\t\tif (!Q.empty() && Q.front() == R) {\n\t\t\t\tQ.pop_front();\n\t\t\t}\n\t\t\tR--;\n\t\t}\n\t\t//if (!ms.empty())ans = max(ans, i.second - *ms.begin());\n\t\tif (!Q.empty())ans = max(ans, i.second + b[Q.front()].second);\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 2460, "memory_kb": 451556, "score_of_the_acc": -0.0121, "final_rank": 2 } ]
aoj_0615_cpp
ケーキの切り分け2 (Cake 2) JOI くんと IOI ちゃんは双子の兄妹である.JOI くんは最近お菓子作りに凝っていて,今日も JOI くんはケーキを焼いて食べようとしたのだが,焼きあがったところで匂いをかぎつけた IOI ちゃんが来たので 2人でケーキを分けることになった. ケーキは円形である.ある点から放射状に切り目を入れ,ケーキを N 個のピースに切り分け,ピースに 1 から N まで反時計回りに番号をつけた.つまり,1 ≤ i ≤ N に対し, i 番目のピースは i − 1 番目と i + 1 番目のピースと隣接している (ただし 0 番目は N 番目, N + 1 番目は 1 番目とみなす) . i 番目のピースの大きさは A i だったが,切り方がとても下手だったので A i はすべて異なる値になった. 図 1: ケーキの例 ( N = 5, A 1 = 2, A 2 = 8, A 3 = 1, A 4 = 10, A 5 = 9) この N 個を JOI くんと IOI ちゃんで分けることにした.分け方は次のようにすることにした: まず JOI くんが N 個のうちの好きな 1 つを選んで取る. その後,IOI ちゃんからはじめて IOI ちゃんと JOI くんが交互に残りのピースを 1 つずつ取っていく.ただし,両隣のピースのうち少なくとも一方が既に取られているようなピースしか取ることができず,取れるピースが複数あるときは,IOI ちゃんはそのうち最も大きいものを選んで取り,JOI くんはそのうちで好きなものを選んで取ることができる. JOI くんは,自分が最終的に取るピースの大きさの合計を最大化したい. 課題 ケーキのピースの数 N と, N 個のピースの大きさの情報が与えられたとき,JOI くんが取れるピースの大きさの合計の最大値を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には整数 N が書かれており,ケーキが N 個のピースに切り分けられていることを表す. 続く N 行のうちの i 行目 (1 ≤ i ≤ N ) には整数 A i が書かれており, i 番目のピースの大きさが A i であることを表す. 出力 標準出力に,JOI くんが取れるピースの大きさの合計の最大値を表す整数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 1 ≤ N ≤ 2 000. 1 ≤ A i ≤ 1 000 000 000. A i はすべて異なる. 入出力例 入力例 1 5 2 8 1 10 9 出力例 1 18 JOI くんは,次のようにピースを取るのが最適である. JOI くんは 2 番目のピースを取る.このピースの大きさは 8 である. IOI ちゃんは 1 番目のピースを取る.このピースの大きさは 2 である. JOI くんは 5 番目のピースを取る.このピースの大きさは 9 である. IOI ちゃんは 4 番目のピースを取る.このピースの大きさは 10 である. JOI くんは 3 番目のピースを取る.このピースの大きさは 1 である. 最終的に,JOI くんが取ったピースの大きさの合計は,8 + 9 + 1 = 18 となる. 入力例 2 8 1 10 4 5 6 2 9 3 出力例 2 26 入力例 3 15 182243672 10074562 977552215 122668426 685444213 3784162 463324752 560071245 134465220 21447865 654556327 183481051 20041805 405079805 564327789 出力例 3 3600242976 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0615_10878970", "code_snippet": "// #pragma GCC optimize(\"Ofast\")\n// #pragma GCC optimize (\"unroll-loops\")\n// #pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#include<complex>\n//#include <ext/pb_ds/tree_policy.hpp>\n//#include <ext/pb_ds/assoc_container.hpp>\n\n#define x() real()\n#define y() imag()\n#define endl '\\n'\n#define ll long long\ntypedef long double T;\ntypedef complex<T> point;\n#define pii pair<int,int>\n#define all(x) x.begin(),x.end()\n#define fastIO cin.tie(0)->sync_with_stdio(0);\n\n//using namespace __gnu_pbds;\n//template <typename T> using o_set = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\n//If you can't solve a problem then there's an easier\n//sub-problem that you can not solve.Find it!!\n\nconst int N = 4e3 + 5;\nll a[N] , dp[N][N][2];\n\nint main()\n{\n fastIO;\n\n int t = 1; //cin >> t;\n\n while (t--)\n {\n int n; cin >> n;\n\n for (int i = 1 ; i <= n ; i++)\n {\n cin >> a[i];\n a[i + n] = a[i];\n }\n\n for (int len = 1 ; len <= n + n ; len++)\n {\n for (int i = 1 , j = i + len - 1 ; j <= n + n; i++ , j++)\n {\n dp[i][j][0] = max(a[i] + dp[i + 1][j][1] ,\n dp[i][j - 1][1] + a[j]);\n\n if (a[i] > a[j])\n dp[i][j][1] = dp[i + 1][j][0];\n\n else\n dp[i][j][1] = dp[i][j - 1][0];\n }\n }\n\n ll ans = 0;\n\n for (int i = 1 ; i <= n ; i++)\n ans = max(ans , a[i] + dp[i + 1][i + n - 1][1]);\n\n cout << ans << endl;\n\n //cout << dp[1][2][1] << endl;\n }\n\n\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 253304, "score_of_the_acc": -1.1429, "final_rank": 18 }, { "submission_id": "aoj_0615_10852680", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\nlong long n, a[10000], dp[3000][3000];\nint main() {\n\tcin >> n; for (int i = 0; i < n; i++)cin >> a[i];\n\tfor (int i = 0; i < n; i++) { for (int j = 0; j < n; j++)dp[i][j] = -99999999999999999LL; }\n\tfor (int i = 0; i < n; i++)dp[i][i] = a[i];\n\tfor (int i = 0; i < n - 1; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tint L1 = j, R1 = (i + j) % n;\n\t\t\tint N1 = (L1 + n - 1) % n;\n\t\t\tint N2 = (R1 + 1) % n;\n\t\t\tif (i % 2 == 0) {\n\t\t\t\tif (a[N1] <= a[N2])dp[L1][N2] = max(dp[L1][N2], dp[L1][R1]);\n\t\t\t\tif (a[N1] > a[N2])dp[N1][R1] = max(dp[N1][R1], dp[L1][R1]);\n\t\t\t}\n\t\t\tif (i % 2 == 1) {\n\t\t\t\tdp[L1][N2] = max(dp[L1][N2], dp[L1][R1] + a[N2]);\n\t\t\t\tdp[N1][R1] = max(dp[N1][R1], dp[L1][R1] + a[N1]);\n\t\t\t}\n\t\t}\n\t}\n\tlong long maxn = 0; for (int i = 0; i < n; i++)maxn = max(maxn, dp[(i + 1) % n][i]);\n\tcout << maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 50148, "score_of_the_acc": -0.5197, "final_rank": 9 }, { "submission_id": "aoj_0615_10691388", "code_snippet": "// competitive-verifier: PROBLEM\n#pragma GCC optimize(\"Ofast,fast-math,unroll-all-loops\")\n#include <bits/stdc++.h>\n#if !defined(ATCODER) && !defined(EVAL)\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#endif\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = 3.14159265358979323846;\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m) - 1; i >= int(n); --i)\n#define FORL(i, m, n) for (std::int64_t i = (m); i < std::int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n constexpr void operator()() const {}\n} sonic;\nstruct increment_impl {\n template <class T>\n const increment_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) ++x;\n return *this;\n }\n} Inc;\nstruct decrement_impl {\n template <class T>\n const decrement_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) --x;\n return *this;\n }\n} Dec;\nstruct sort_impl {\n template <class T>\n const sort_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n return *this;\n }\n} Sort;\nstruct unique_impl {\n template <class T>\n const unique_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n v.erase(std::unique(v.begin(), v.end()), v.end());\n return *this;\n }\n} Uniq;\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) os << (it == v.begin() ? \"\" : \" \") << *it;\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\nvoid Yes(bool is_correct = true) { std::cout << (is_correct ? \"Yes\\n\" : \"No\\n\"); }\nvoid No(bool is_not_correct = true) { Yes(!is_not_correct); }\nvoid YES(bool is_correct = true) { std::cout << (is_correct ? \"YES\\n\" : \"NO\\n\"); }\nvoid NO(bool is_not_correct = true) { YES(!is_not_correct); }\nvoid Takahashi(bool is_correct = true) { std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n'; }\nvoid Aoki(bool is_not_correct = true) { Takahashi(!is_not_correct); }\n/// @brief 累積和\ntemplate <class T = std::int64_t>\nstruct prefix_sum {\n prefix_sum(int _n) : n(_n), data(_n + 1) {}\n template <class U>\n prefix_sum(const std::vector<U> &v) : n(v.size()), data(v.size() + 1) {\n for (int i = 0; i < n; ++i) data[i] = v[i];\n build();\n }\n void build() {\n for (int i = n - 1; i >= 0; --i) data[i] += data[i + 1];\n }\n T get(int k) const {\n assert(0 <= k && k < n);\n return data[k] - data[k + 1];\n }\n void set(int k, int x) { data[k] = x; }\n void add(int k, int x) { data[k] += x; }\n T sum(int r) const {\n assert(0 <= r && r <= n);\n return data[0] - data[r];\n }\n T sum(int l, int r) const {\n assert(0 <= l && l <= r && r <= n);\n return data[l] - data[r];\n }\n int min_left(T x) const { return min_left(0, x); }\n int min_left(int l, T x) const {\n assert(0 <= l && l <= n);\n int left = l, right = n + 1;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[l] - data[mid] >= x ? right : left) = mid;\n }\n return right;\n }\n int max_right(T x) const { return max_right(n, x); }\n int max_right(int r, T x) const {\n assert(0 <= r && r <= n);\n int left = -1, right = r;\n while (right - left > 1) {\n int mid = (left + right) / 2;\n (data[mid] - data[r] >= x ? left : right) = mid;\n }\n return left;\n }\n private:\n int n;\n std::vector<T> data;\n};\nint main(void) {\n int n;\n cin >> n;\n vector<int> a(n);\n cin >> a;\n rep (i, n) {\n a.emplace_back(a[i]);\n }\n vector dp(n * 2 + 1, vector(n * 2 + 1, 0l));\n repn (d, n * 2) {\n rep (l, n * 2) {\n int r = l + d;\n if (r > n * 2)\n break;\n if ((n - (r - l)) % 2 == 0)\n dp[l][r] = max(dp[l][r - 1] + a[r - 1], dp[l + 1][r] + a[l]);\n else {\n if (a[l] > a[r - 1])\n dp[l][r] = dp[l + 1][r];\n else\n dp[l][r] = dp[l][r - 1];\n }\n }\n }\n ll ans = 0;\n rep (i, n) chmax(ans, dp[i][i + n]);\n co(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 128640, "score_of_the_acc": -0.7388, "final_rank": 14 }, { "submission_id": "aoj_0615_9906358", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\njun pick first, ...\ndp\ne.g. for 5 cakes\nkun:\n0 1 2 3 4 => 0 1 X 3 4 = 5 6 X 3 4\nnext:\nL=3, R=6, chan's turn\n\ndp state: L, R, who's turn\n\nN.B. only increment vect[i] when it's kun's turn (objective is to maximise kun's score)\n\n\nFIXME:\nretnink\nL, R in circle, L <= R ???????\n\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 2147483647;\n\nconst int MAX_N = 2000;\nstatic int vect[MAX_N];\nstatic int64_t S[MAX_N][MAX_N]; // L, R\n\n//------------------------------------------------------------------------------\nvoid debug_S(int N)\n{\n for (int i=0; i<N; ++i)\n for (int j=0; j<N; ++j)\n if (S[i][j] != -1)\n printf(\"i=%d, j=%d: %ld\\n\", i, j, S[i][j]);\n}\nint64_t dp(int N, int L, int R, bool chan)\n{\n if (L < 0) L += N;\n if (L >= N) L %= N;\n if (R < 0) R += N;\n if (R >= N) R %= N;\n // N.B. do not swap if L > R\n\n if (S[L][R] != -1) return S[L][R];\n int64_t& res = S[L][R];\n res = 0;\n if (L == R)\n {\n if (!chan) res = vect[L];\n return res;\n }\n\n if (chan)\n {\n if (vect[L] > vect[R]) res = dp(N, L+1, R, false);\n else res = dp(N, L, R-1, false);\n }\n else\n {\n //if (vect[L] > vect[R]) res = vect[L] + dp(N, L+1, R, true);\n //else res = vect[R] + dp(N, L, R-1, true);\n res = max(vect[L] + dp(N, L+1, R, true), vect[R] + dp(N, L, R-1, true));\n }\n return res;\n}\n//------------------------------------------------------------------------------\nint64_t solve(int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n for (int i=0; i<N; ++i) for (int j=0; j<N; ++j) S[i][j] = -1;\n //--------------------------------------------------------------------------\n // compute:\n int64_t res = 0;\n for (int i=0; i<N; ++i) res = max(res, dp(N, i+1, i-1, true) + vect[i]);\n if (DEBUG) debug_S(N);\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n num = scanf(\"%d \", &N);\n for (int i=0; i<N; ++i) num = scanf(\"%d \", &vect[i]);\n int64_t res = solve(N);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 30, "memory_kb": 34876, "score_of_the_acc": -0.2204, "final_rank": 4 }, { "submission_id": "aoj_0615_9592000", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\n\nint main(){\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vector<ll> A(N*2);\n for(int i=0;i<N;i++){\n cin>>A[i];\n A[i+N]=A[i];\n }\n vector<vector<ll>> DP(N*2,vector<ll>(N*2,0));\n if(N%2==1)for(int i=0;i<N*2;i++)DP[i][i]=A[i];\n for(int d=1;d<N;d++){\n for(int i=0;i<2*N;i++){\n int j=i+d;\n if(j>=2*N)break;\n if((N-d)%2==1){\n DP[i][j]=max(DP[i+1][j]+A[i],DP[i][j-1]+A[j]);\n }\n else{\n if(A[i]>A[j])DP[i][j]=DP[i+1][j];\n else DP[i][j]=DP[i][j-1];\n }\n }\n }\n ll an=0;\n for(int i=0;i<N;i++){\n an=max(an,A[i]+DP[i+1][i+N-1]);\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 128188, "score_of_the_acc": -0.737, "final_rank": 12 }, { "submission_id": "aoj_0615_9480078", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cstdio>\nusing namespace std;\n\nint main() {\n vector<long long> a(2000, 0); // 配列aを2000要素の初期化\n int n;\n vector<long long> dp(2000, 0); // 配列dpを2000要素の初期化\n vector<long long> dq(2000, 0); // 配列dqを2000要素の初期化\n long long ans;\n\n // 標準入力から配列サイズnを読み込み\n scanf(\"%d\", &n);\n\n // 標準入力から配列aの要素を読み込み\n for (int i = 0; i < n; i++) {\n scanf(\"%lld\", &a[i]);\n }\n\n // メインループ: 配列aの要素を使ってdp配列を更新\n for (int i = 0; i < n; i++) {\n if (i % 2 == 1) {\n for (int j = 0; j < n; j++) {\n int x = (i + j) % n;\n int y = (j + n - 1) % n;\n if (a[x] < a[y]) {\n dq[y] = max(dq[y], dp[j]);\n } else {\n dq[j] = max(dq[j], dp[j]);\n }\n }\n } else {\n for (int j = 0; j < n; j++) {\n int x = (i + j) % n;\n int y = (j + 1) % n;\n dq[j] = max(dp[j] + a[x], dp[y] + a[j]);\n }\n }\n\n // dqをdpにコピーしてdqをクリア\n for (int j = 0; j < n; j++) {\n dp[j] = dq[j];\n dq[j] = 0;\n }\n }\n\n // 最終結果を計算\n ans = 0;\n for (int i = 0; i < n; i++) {\n ans = max(ans, dp[i]);\n }\n\n // 結果を出力\n printf(\"%lld\\n\", ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3620, "score_of_the_acc": -0.0952, "final_rank": 1 }, { "submission_id": "aoj_0615_9092555", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n;\n cin >> n;\n vector<ll> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n vector<vector<ll>> dp(n, vector<ll>(n, -1));\n if (n == 1) {\n cout << a[0] << endl;\n return 0;\n } else if (n == 2) {\n cout << max(a[0], a[1]) << endl;\n return 0;\n }\n auto calc = [&](auto self, int s, int m) -> ll {\n if (dp[s][m] != -1) return dp[s][m];\n if (m == 0) return 0;\n if (m == 1) return a[s];\n int l = s, r = (s + m - 1) % n;\n if (m == 2) {\n dp[s][m] = max(a[l], a[r]);\n return dp[s][m];\n }\n int l2 = (s + 1) % n, r2 = (r + n - 1) % n;\n int l3 = (l2 + 1) % n, r3 = (r2 + n - 1) % n;\n\n // lを使う場合\n {\n if (a[l2] > a[r]) dp[s][m] = max(dp[s][m], a[l] + self(self, l3, m - 2));\n else dp[s][m] = max(dp[s][m], a[l] + self(self, l2, m - 2));\n }\n // rを使う場合\n {\n if (a[l] > a[r2]) dp[s][m] = max(dp[s][m], a[r] + self(self, l2, m - 2));\n else dp[s][m] = max(dp[s][m], a[r] + self(self, l, m - 2));\n }\n\n return dp[s][m];\n };\n ll res = 0;\n for (int i = 0; i < n; ++i) {\n int p = (i == 0 ? n - 1 : i - 1);\n int c = (i + 1 == n ? 0 : i + 1);\n int cc = (i + 2 >= n ? i + 2 - n : i + 2);\n if (a[p] > a[c]) res = max(res, a[i] + calc(calc, c, n - 2));\n else res = max(res, a[i] + calc(calc, cc, n - 2));\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 34512, "score_of_the_acc": -0.2666, "final_rank": 5 }, { "submission_id": "aoj_0615_8530673", "code_snippet": "/*\n * 0615.cc: Cake 2\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 2000;\nconst int MAX_N2 = MAX_N * 2;\n\n/* typedef */\n\ntypedef long long ll;\n\n/* global variables */\n\nint as[MAX_N2];\nll dp[MAX_N2 + 1][MAX_N2 + 1];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i), as[i + n] = as[i];\n\n int n2 = n * 2;\n for (int i = 0; i <= n2; i++) dp[i][i] = 0;\n for (int i = 0; i < n2; i++) dp[i][i + 1] = as[i];\n\n for (int l = 2; l <= n; l++)\n for (int i = 0, j = l; j <= n2; i++, j++)\n dp[i][j] =\n\tmax(as[i] + (as[i + 1] > as[j - 1] ? dp[i + 2][j] : dp[i + 1][j - 1]),\n\t as[j - 1] + (as[i] > as[j - 2] ? dp[i + 1][j - 1] : dp[i][j - 2]));\n\n ll maxd = 0;\n for (int i = 0; i < n; i++) maxd = max(maxd, dp[i][i + n]);\n\n printf(\"%lld\\n\", maxd);\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 127164, "score_of_the_acc": -0.5424, "final_rank": 10 }, { "submission_id": "aoj_0615_8493125", "code_snippet": "#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(v) v.begin(),v.end()\ntypedef long long ll;\n \n#include<bits/stdc++.h>\nusing namespace std;\n\nll dp[4020][4020];\nvoid chmax(ll &a,ll b){a=max(a,b);}\n \nint main(){\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n \n int n;\n cin>>n;\n vector<ll> A(2*n);\n rep(i,n){\n cin>>A[i];\n A[i+n]=A[i];\n }\n \n if(n%2){\n rep(i,2*n) dp[i][i+1]=A[i];\n for(int w=2;w<=2*n;w++){\n for(int l=0;l+w<=2*n;l++){\n int r=l+w;\n if(w%2){\n chmax(dp[l][r],A[l]+dp[l+1][r]);\n chmax(dp[l][r],dp[l][r-1]+A[r-1]);\n }\n else{\n if(A[l]>A[r-1]) chmax(dp[l][r],dp[l+1][r]);\n else chmax(dp[l][r],dp[l][r-1]);\n }\n }\n }\n }\n else{\n for(int w=2;w<=2*n;w++){\n for(int l=0;l+w<=2*n;l++){\n int r=l+w;\n if(w%2==0){\n chmax(dp[l][r],A[l]+dp[l+1][r]);\n chmax(dp[l][r],dp[l][r-1]+A[r-1]);\n }\n else{\n if(A[l]>A[r-1]) chmax(dp[l][r],dp[l+1][r]);\n else chmax(dp[l][r],dp[l][r-1]);\n }\n }\n }\n }\n ll ans=0;\n rep(i,n) ans=max(ans,dp[i][i+n]);\n cout<<ans<<endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 128408, "score_of_the_acc": -0.5474, "final_rank": 11 }, { "submission_id": "aoj_0615_6962076", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i32 = int;\nusing i64 = long long;\n\ni64 rec(vector<vector<i64>>& dp, vector<vector<bool>>& used, const vector<i32>& as, i32 l, i32 r) {\n if (used[l][r]) {\n return dp[l][r];\n }\n used[l][r] = true;\n i32 n = (i32)as.size();\n if (l != r and l % n == r % n) {\n return dp[l][r] = 0LL;\n }\n if ((r - l) & 1) {\n if (as[(l - 1 + n) % n] > as[r % n]) {\n if (l == 0) {\n return dp[l][r] = rec(dp, used, as, 2 * n - 1, r);\n }\n else {\n return dp[l][r] = rec(dp, used, as, l - 1, r);\n }\n }\n else {\n return dp[l][r] = rec(dp, used, as, l, r + 1);\n }\n }\n else {\n i64 f = 0;\n if (l == 0) {\n f = rec(dp, used, as, 2 * n - 1, r);\n }\n else {\n f = rec(dp, used, as, l - 1, r);\n }\n i64 b = rec(dp, used, as, l, r + 1);\n return dp[l][r] = max(f + as[(l - 1 + n) % n], b + as[r % n]);\n }\n}\n\nint main() {\n i32 n; cin >> n;\n vector as(n, 0);\n for (auto& a : as) cin >> a;\n vector dp(2 * n + 1, vector(2 * n + 1, 0LL));\n vector used(2 * n + 1, vector(2 * n + 1, false));\n i64 ans = 0;\n for (i32 i = 0 ; i < n ; i++) {\n ans = max(ans, rec(dp, used, as, i, i));\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 130732, "score_of_the_acc": -0.9377, "final_rank": 16 }, { "submission_id": "aoj_0615_6813841", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\ntypedef long long ll;\nconst int mod=1e9+7;\nll dp[2001][2000];\nint main(){\n\tint n,a[2000];\n\tcin>>n;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i];\n\tfor(int w=0;w<n;w++){\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(w%2==0){\n\t\t\t\tdp[w+1][i]=max(dp[w+1][i],dp[w][i]+a[(i+w)%n]);\n\t\t\t\tdp[w+1][(i+n-1)%n]=max(dp[w+1][(i+n-1)%n],dp[w][i]+a[(i+n-1)%n]);\n\t\t\t}else if(a[(i+w)%n]>a[(i+n-1)%n])\n\t\t\t\tdp[w+1][i]=max(dp[w+1][i],dp[w][i]);\n\t\t\telse\n\t\t\t\tdp[w+1][(i+n-1)%n]=max(dp[w+1][(i+n-1)%n],dp[w][i]);\n\t\t}\n\t}\n\tcout<<*max_element(dp[n],dp[n]+n)<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 34672, "score_of_the_acc": -0.172, "final_rank": 3 }, { "submission_id": "aoj_0615_6109081", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n vector<ll> a(n);\n in(a);\n rep(i,n)a.push_back(a[i]);\n vector2d(ll,dp,2*n,2*n,-INF2);\n function<ll(int,int)> rec=[&](int l,int r){\n if(l>r)return 0LL;\n ll res=0;\n if(dp[l][r]!=-INF2)return dp[l][r];\n if((n-(r-l))&1){\n res=-INF2;\n chmax(res,a[l]+rec(l+1,r));\n chmax(res,a[r]+rec(l,r-1));\n }else{\n res=INF2;\n if(a[l]>=a[r])chmin(res,-a[l]+rec(l+1,r));\n if(a[l]<=a[r])chmin(res,-a[r]+rec(l,r-1));\n }\n return dp[l][r]=res;\n };\n ll ans=0,sumv=0;\n rep(i,n)sumv+=a[i];\n rep(i,n)chmax(ans,(sumv+rec(i,i+n-1))/2);\n out(ans);\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 128540, "score_of_the_acc": -0.8336, "final_rank": 15 }, { "submission_id": "aoj_0615_5876776", "code_snippet": "#include <iostream>\n#include <utility>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <queue>\nusing namespace std;\nusing ll = long long int;\n#define chmax(x,y) (x) = ((x) > (y)) ? (x) : ((x) = (y));\n#define chmin(x,y) (x) = ((x) < (y)) ? (x) : ((x) = (y));\nconst int INF = 1e9;\nconst ll INFL = 1e18;\nconst int Mod = 1e9 + 7;\nconst int dx[] = {0,1,0,-1};\nconst int dy[] = {1,0,-1,0};\n\n\nint main(int argc, char const *argv[])\n{\n int N;cin >> N;\n vector<ll> A(2*N);\n for(int i=0;i<N;++i)\n {\n cin >> A[i]; A[i+N] = A[i];\n }\n vector<vector<ll>> dp(2*N+1,vector<ll>(2*N+1));\n //if(N%2)for(int i=0;i<2*N;++i)dp[i][i+1] = A[i];\n for(int len = 1;len <=N;++len)\n {\n for(int i=0;i<2*N;++i)\n {\n if(i+len > 2*N)continue;\n if(N%2 == len%2)\n {\n dp[i][i+len] = max(dp[i+1][i+len]+A[i],dp[i][i+len-1]+A[i+len-1]);\n }\n else \n {\n if(A[i] > A[i+len-1])dp[i][i+len] = dp[i+1][i+len];\n else dp[i][i+len] = dp[i][i+len-1];\n }\n }\n }\n ll answer = 0;\n for(int i=0;i<N;++i)\n {\n //std::cout << dp[i][i+N] << std::endl;\n chmax(answer,dp[i][i+N]);\n }\n std::cout << answer << std::endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 128236, "score_of_the_acc": -0.7372, "final_rank": 13 }, { "submission_id": "aoj_0615_5812863", "code_snippet": "bool TEST = false;\n\nusing namespace std;\n#include<bits/stdc++.h>\n#include<fstream>\n\n#define rep(i,n) for(int (i)=0;(i)<(ll)(n);i++)\n#define repr(i,n) for(int (i)=(ll)(n)-1;(i)>=0;i--)\n#define range(i,start,end,step) for(int (i)=start;(i)<(ll)(end);(i)+=(step))\n\n#define dump(x) cerr << \"Line \" << __LINE__ << \": \" << #x << \" = \" << (x) << \"\\n\";\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define all(a) (a).begin(),(a).end()\n#define allr(a) (a).rbegin(),(a).rend()\n\nusing ld = long double;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing pdd = pair<ld, ld>;\n \ntemplate<typename T> using V = vector<T>;\ntemplate<typename T> using VV = V<V<T>>;\ntemplate<typename T, typename T2> using P = pair<T, T2>;\ntemplate<typename T, typename T2> using M = map<T, T2>;\ntemplate<typename T> using S = set<T>;\ntemplate<typename T, typename T2> using UM = unordered_map<T, T2>;\ntemplate<typename T> using PQ = priority_queue<T, V<T>, greater<T>>;\ntemplate<typename T> using rPQ = priority_queue<T, V<T>, less<T>>;\ntemplate<typename T> vector<T> make_vec(size_t n, T a) { return vector<T>(n, a); }\ntemplate<typename... Ts> auto make_vec(size_t n, Ts... ts) { return vector<decltype(make_vec(ts...))>(n, make_vec(ts...)); }\ntemplate<class SS, class T> ostream& operator << (ostream& os, const pair<SS, T> v){os << \"(\" << v.first << \", \" << v.second << \")\"; return os;}\ntemplate<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { for (auto &e : v) os << e << ' '; return os; }\ntemplate<class T> ostream& operator<<(ostream& os, const vector<vector<T>> &v){ for(auto &e : v){os << e << \"\\n\";} return os;}\nstruct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;\n \ntemplate <class T> void UNIQUE(vector<T> &x) {sort(ALL(x));x.erase(unique(ALL(x)), x.end());}\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\nvoid fail() { cout << -1 << '\\n'; exit(0); }\ninline int popcount(const int x) { return __builtin_popcount(x); }\ninline int popcount(const ll x) { return __builtin_popcountll(x); }\ntemplate<typename T> void debug(vector<vector<T>>&v){for(ll i=0;i<v.size();i++)\n{cerr<<v[i][0];for(ll j=1;j<v[i].size();j++)cerr spa v[i][j];cerr<<\"\\n\";}};\ntemplate<typename T> void debug(vector<T>&v){if(v.size()!=0)cerr<<v[0];\nfor(ll i=1;i<v.size();i++)cerr spa v[i];\ncerr<<\"\\n\";};\ntemplate<typename T> P<T,T> divmod(T a, T b) {return make_pair(a/b, a%b);}\n\nconst ll INF = (1ll<<62);\n// const ld EPS = 1e-10;\n// const ld PI = acos(-1.0);\nconst ll mod = (int)1e9 + 7;\n//const ll mod = 998244353;\n\n\nll dp[2010][2010];\nint n;\nV<ll> a;\n\nll sub(int l, int r, bool f = 1) {\n l = (l+n)%n;\n r = (r+n)%n;\n ll res = 0;\n if (r==l && f) return 0;\n if (dp[l][r]>=0) return dp[l][r];\n else {\n int nl,nnl,nr,nnr;\n ll vl,vl2,vr,vr2;\n nl = (n+l-1)%n;\n nnl = (n+l-2)%n;\n nr = (r)%n;\n nnr = (r+1)%n;\n vl = a[nl];\n vl2 = a[nnl];\n vr = a[nr];\n vr2 = a[nnr];\n if ((r-l+2*n)%n==n-1) {\n assert(vl==vr);\n // cout << l spa r spa vl spa vr;\n res = vl;\n } else {\n if (vl2<vr) chmax(res, sub(l-1,r+1) + vl);\n else chmax(res, sub(l-2,r,1) + vl);\n if (vl<vr2) chmax(res, sub(l, r+2) + vr);\n else chmax(res, sub(l-1,r+1) + vr);\n }\n }\n // cout << l spa r spa res << endl;\n dp[l][r] = res;\n return res;\n}\nvoid Main(){\n cin >> n;\n a = V<ll>(n);\n rep(i,n) cin >> a[i];\n rep(i,n+10) rep(j, n+10) dp[i][j] = -1;\n ll ans = 0;\n rep(i,n) {\n chmax(ans, sub(i,i,0));\n }\n cout << ans << endl;\n}\n\nint main(void){\n std::ifstream in(\"tmp_in\");\n if (TEST) {\n std::cin.rdbuf(in.rdbuf());\n std::cout << std::fixed << std::setprecision(15);\n } else {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(15);\n }\n Main();\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 35056, "score_of_the_acc": -0.2688, "final_rank": 6 }, { "submission_id": "aoj_0615_5812854", "code_snippet": "bool TEST = false;\n\nusing namespace std;\n#include<bits/stdc++.h>\n#include<fstream>\n\n#define rep(i,n) for(int (i)=0;(i)<(ll)(n);i++)\n#define repr(i,n) for(int (i)=(ll)(n)-1;(i)>=0;i--)\n#define range(i,start,end,step) for(int (i)=start;(i)<(ll)(end);(i)+=(step))\n\n#define dump(x) cerr << \"Line \" << __LINE__ << \": \" << #x << \" = \" << (x) << \"\\n\";\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define all(a) (a).begin(),(a).end()\n#define allr(a) (a).rbegin(),(a).rend()\n\nusing ld = long double;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pii = pair<int, int>;\nusing pll = pair<ll, ll>;\nusing pdd = pair<ld, ld>;\n \ntemplate<typename T> using V = vector<T>;\ntemplate<typename T> using VV = V<V<T>>;\ntemplate<typename T, typename T2> using P = pair<T, T2>;\ntemplate<typename T, typename T2> using M = map<T, T2>;\ntemplate<typename T> using S = set<T>;\ntemplate<typename T, typename T2> using UM = unordered_map<T, T2>;\ntemplate<typename T> using PQ = priority_queue<T, V<T>, greater<T>>;\ntemplate<typename T> using rPQ = priority_queue<T, V<T>, less<T>>;\ntemplate<typename T> vector<T> make_vec(size_t n, T a) { return vector<T>(n, a); }\ntemplate<typename... Ts> auto make_vec(size_t n, Ts... ts) { return vector<decltype(make_vec(ts...))>(n, make_vec(ts...)); }\ntemplate<class SS, class T> ostream& operator << (ostream& os, const pair<SS, T> v){os << \"(\" << v.first << \", \" << v.second << \")\"; return os;}\ntemplate<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { for (auto &e : v) os << e << ' '; return os; }\ntemplate<class T> ostream& operator<<(ostream& os, const vector<vector<T>> &v){ for(auto &e : v){os << e << \"\\n\";} return os;}\nstruct fast_ios { fast_ios(){ cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;\n \ntemplate <class T> void UNIQUE(vector<T> &x) {sort(ALL(x));x.erase(unique(ALL(x)), x.end());}\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\nvoid fail() { cout << -1 << '\\n'; exit(0); }\ninline int popcount(const int x) { return __builtin_popcount(x); }\ninline int popcount(const ll x) { return __builtin_popcountll(x); }\ntemplate<typename T> void debug(vector<vector<T>>&v){for(ll i=0;i<v.size();i++)\n{cerr<<v[i][0];for(ll j=1;j<v[i].size();j++)cerr spa v[i][j];cerr<<\"\\n\";}};\ntemplate<typename T> void debug(vector<T>&v){if(v.size()!=0)cerr<<v[0];\nfor(ll i=1;i<v.size();i++)cerr spa v[i];\ncerr<<\"\\n\";};\ntemplate<typename T> P<T,T> divmod(T a, T b) {return make_pair(a/b, a%b);}\n\nconst ll INF = (1ll<<62);\n// const ld EPS = 1e-10;\n// const ld PI = acos(-1.0);\nconst ll mod = (int)1e9 + 7;\n//const ll mod = 998244353;\n\n\nll dp[2010][2010];\nint n;\nV<ll> a;\n\nll sub(int l, int r, bool f = 1) {\n l = (l+n)%n;\n r = (r+n)%n;\n ll res = 0;\n if (r==l && f) return 0;\n if (dp[l][r]>=0) return dp[l][r];\n else {\n int nl,nnl,nr,nnr;\n ll vl,vl2,vr,vr2;\n nl = (n+l-1)%n;\n nnl = (n+l-2)%n;\n nr = (r)%n;\n nnr = (r+1)%n;\n vl = a[nl];\n vl2 = a[nnl];\n vr = a[nr];\n vr2 = a[nnr];\n if ((r-l+2*n)%n==n-1) {\n assert(vl==vr);\n // cout << l spa r spa vl spa vr;\n res = vl;\n } else {\n if (vl2<vr) chmax(res, sub(l-1,r+1) + vl);\n else chmax(res, sub(l-2,r,1) + vl);\n if (vl<vr2) chmax(res, sub(l, r+2) + vr);\n else chmax(res, sub(l-1,r+1) + vr);\n }\n }\n // cout << l spa r spa res << endl;\n dp[l][r] = res;\n return res;\n}\nvoid Main(){\n cin >> n;\n a = V<ll>(n);\n rep(i,n) cin >> a[i];\n rep(i,2*n+10) rep(j, 2*n+10) dp[i][j] = -1;\n ll ans = 0;\n rep(i,n) {\n chmax(ans, sub(i,i,0));\n }\n cout << ans << endl;\n}\n\nint main(void){\n std::ifstream in(\"tmp_in\");\n if (TEST) {\n std::cin.rdbuf(in.rdbuf());\n std::cout << std::fixed << std::setprecision(15);\n } else {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << std::fixed << std::setprecision(15);\n }\n Main();\n}", "accuracy": 0.7575757575757576, "time_ms": 10, "memory_kb": 34924, "score_of_the_acc": -0.1254, "final_rank": 20 }, { "submission_id": "aoj_0615_5493747", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, N) for (ll i = 0; i < N; i++)\nll N;\nll dp[2020][2020][2] = {};\nll A[2020];\n\nll rec(ll l, ll r, ll turn, ll cnt)\n{\n if (cnt == N)\n return 0;\n if (dp[l][r][turn] != -1)\n return dp[l][r][turn];\n ll ret;\n \n ll lm = (l - 1 < 0) ? N - 1 : l - 1;\n ll rp = (r + 1 >= N) ? 0 : r + 1;\n \n if (turn == 1)\n {\n if (A[lm] > A[rp])\n { \n ret = rec(lm, r, 0, cnt+1);\n }\n else\n ret = rec(l, rp, 0, cnt+1);\n }\n else\n { \n ret = max(rec(lm, r, 1, cnt+1) + A[lm] , rec(l, rp, 1, cnt+1) + A[rp]);\n /*\n if (A[lm] > A[rp])\n {\n ret = rec(lm, r, 1, cnt++) + A[lm];\n }\n else\n ret = rec(l, rp, 1, cnt++) + A[rp];*/\n } \n return dp[l][r][turn] = ret;\n}\n\nint main()\n{\n cin >> N;\n rep(i, N) cin >> A[i];\n rep(i, N) rep(j, N)\n {\n dp[i][j][0] = dp[i][j][1] = -1;\n }\n ll maxv = 0;\n\n rep(i, N)\n {\n maxv = max(maxv, A[i] + rec(i, i, 1, 1));\n }\n cout << maxv << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 66400, "score_of_the_acc": -0.4419, "final_rank": 7 }, { "submission_id": "aoj_0615_5444931", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\nusing ll = long long;\nusing namespace std;\nconst ll INF = 1000000000000000000;\n\nll n, a[2005], dp[4005][4005];\nll solve(ll l, ll r) {//区間[l, r)を食べた\n\tif (dp[l][r] != -1) { return dp[l][r]; }\n\tif (r - l == 1) { return dp[l][r] = a[l % n]; }\n\tif ((r - l) % 2 == 0) {\n\t\tll ans = 0 - INF;\n\t\tif (a[(l - 1 + n) % n] <= a[(r - 1) % n]) { ans = max(ans, solve(l, r - 1)); }\n\t\tif (a[l % n] >= a[r % n]) { ans = max(ans, solve(l + 1, r)); }\n\t\treturn dp[l][r] = ans;\n\t}\n\treturn dp[l][r] = max(solve(l, r - 1) + a[(r - 1) % n], solve(l + 1, r) + a[l % n]);\n}\n\nint main() {\n\t//input\n\trep(i, 4005) { rep(j, 4005) { dp[i][j] = -1; } }\n\tcin >> n;\n\trep(i, n) { cin >> a[i]; }\n\tll ans = 0;\n\trep(i, n) {\n\t\tans = max(ans, solve(i, i + n));\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 128512, "score_of_the_acc": -1.5002, "final_rank": 19 }, { "submission_id": "aoj_0615_5215694", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nlong long dp[2001][2001],mx;\nint main(void)\n{\n\tint n,i,j,w,x,a[2001];\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=2000;i++){\n\t\tfor(j=1;j<=2000;j++){\n\t\t\tdp[i][j]=-1;\n\t\t}\n\t}\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%lld\",&a[i]);\n\t\tdp[1][i]=a[i];\n\t}\n\tfor(i=1;i<n;i++){\n\t\tfor(j=1;j<=n;j++){\n\t\tif(dp[i][j]!=-1&&i%2==0){\n\t\t\tw=j-1;\n\t\t\tif(w==0)\tw=n;\n\t\t\tdp[i+1][w]=max(dp[i+1][w],dp[i][j]+a[w]);\n\t\t\tx=i+j;\n\t\t\tif(x>n)\tx=x-n;\n\t\t\tdp[i+1][j]=max(dp[i+1][j],dp[i][j]+a[x]);\n\t\t}\n\t\tif(dp[i][j]!=-1&&i%2!=0){\n\t\t\tw=j-1;\n\t\t\tif(w==0)\tw=n;\n\t\t\tx=i+j;\n\t\t\tif(x>n)\tx=x-n;\n\t\t\tif(a[w]>a[x]){\n\t\t\t\tdp[i+1][w]=max(dp[i+1][w],dp[i][j]);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tdp[i+1][j]=max(dp[i+1][j],dp[i][j]);\n\t\t\t}\n\t\t}\n\t\t}\n\t}\n\tmx=-1;\n\tfor(i=1;i<=n;i++){\n\t\tif(mx<dp[n][i])\tmx=dp[n][i];\n\t}\n\tprintf(\"%lld\\n\",mx);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 34036, "score_of_the_acc": -0.1694, "final_rank": 2 }, { "submission_id": "aoj_0615_4598620", "code_snippet": "#include <bits/stdc++.h>\n#include <algorithm>\n#include <cmath>\n#include <set>\n#include <cstdio>\n#include <vector>\n#include <iostream>\n#include <utility>\n#include <queue>\n#include <map>\n#include <complex>\n#define fir first\n#define sec second\n#define sz(s) (s).size()\n#define pb push_back\n#define get(n) scanf(\"%d\",&n);\n#define gets(s) string s;cin >> (s);\n#define prfi(n) printf(\"%d\", &n);\n#define prfd(n) printf(\"%lf\", &n);\n#define All(s) (s).begin(), (s).end()\n#define rep(i,j) for(int (i)=0;(i)<(j);(i)++)\n#define For(i,j,k) for(int (i)=(j);(i)<(k);(i)++)\n#define drep(i,j) for(int (i)=(j);(i)>=0;(i)--)\n#define Ford(i,j,k) for(int (i)=(j);i>=(k);i--)\n#define fore(c,v) for(auto (c): (v))\n#define lp for(int __=0;__<n;i++)\n#define mem(a,b) memset(a,b,sizeof(a));\n#define dump(x) std::cout << #x << \" = \" << (x) << std::endl;\n#define debug(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << \" \" << __FILE__ << endl;\nusing ull = unsigned long long int;\nusing ll = long long;\nusing ld = long double;\nusing pii = std::pair<int,int>;\nusing pll = std::pair<ll, ll>;\nusing vi = std::vector<int> ;\nusing vvi = std::vector<vi> ;\nusing vll = std::vector<ll>;\nusing vvll = std::vector<vll>;\nusing vd = std::vector<double> ;\nusing vvd = std::vector<vd> ;\nusing qi = std::queue<int> ;\nusing vpii = std::vector<std::pair<int, int> >;\nusing vpll = std::vector<pll>;\nusing namespace std;\n\nconst int Mod = (1e9) + 7;\nconst int INF = 1e9 + 19;\nconst ll INFL = 1e18 + 19;\nconst int dx[] = {-1, 0, 0, 1};\nconst int dy[] = {0, -1, 1, 0};\nconst int dx2[] = {-1, -1, -1, 0, 0, 0, 1, 1, 1};\nconst int dy2[] = {1, 0, -1, 1, 0, -1, 1, 0, -1};\nconst double EPS = 1e-10;\n//_____________________________________Templates_________________________________________//\n\ntemplate<class T1, class T2> inline void chmin(T1 &a, T2 b){if(a > b) a = b;}\ntemplate<class T1, class T2> inline void chmax(T1 &a, T2 b){if(a < b) a = b;}\ntemplate<class T> inline void pri(T a){cout << a << endl;}\ntemplate<class Z> using vec = vector<Z>;\ntemplate<class T> using min_priority_queue = priority_queue<T, vector<T>, greater<T>>;\n//mainly use for dynamic prog\ntemplate<class T1, class T2>\nvoid update(T1 &a, T2 b){\n a += b;\n if(a > Mod) a %= Mod;\n}\n\ninline void IN(void){\n return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid IN(First& first, Rest&... rest){\n cin >> first;\n IN(rest...);\n return;\n}\n\ninline void OUT(void){\n cout << \"\\n\";\n return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid OUT(First first, Rest... rest){\n cout << first << \" \";\n OUT(rest...);\n return;\n}\n\nbool pairsort(pll pl, pll pr){\n if(pl.first == pr.first)return pl.second > pr.second;\n return pl.first < pr.first;\n}\n\nint cntbit(ll a,int n,int j){int res = 0;For(i,j,n){if(a>>i & 1){res++;}}return res;}\nvector<int> make_bit(int a){vector<int> res; for(int i=31;i>=0;i--)if(a&(1<<i))res.pb(i);return res;}\nbool stdbit(int a, int b){return a&(1 << b); }\nint GCD(int a, int b){if(b > a)return GCD(b,a);if(a%b == 0)return b;else return GCD(b, a%b);}\nint LCM(int a, int b){return a*b/GCD(a,b);}\nint roundup(int a, int b){if(a % b == 0)return a/b;else return (a+b)/b;}\nint rounddown(int a, int b){if(a%b == 0)return a/b;else {return (a-b)/b;}}\nll pow(ll a, ll n){ll res = 1;while(n > 0){if(n&1)res *= a; a *= a; n = n >> 1;}return res;}\nll GetDiviserCount(ll N)//約数の個数\n{\n ll res = 1;\n For(i,2,sqrt(N)+1)\n {\n ll cnt = 0;\n while(N%i == 0)\n {\n cnt++;\n N /= i;\n }\n res *= (cnt + 1);\n if(N == 1)break;\n }\n if(N != 1)res *= 2;\n return res;\n}\nvll GetDivisor(ll N)//約数列挙\n{\n vll res;\n for(ll i = 1;i*i <= N;i++)\n {\n if(N%i == 0)\n {\n res.pb(i);\n if(i*i != N)res.pb(N/i);\n }\n }\n sort(All(res));\n return res;\n}\n\nstruct Modint\n{\n using ll = long long int;\n ll x;\n Modint(ll x=0) :x((x%Mod+Mod)%Mod) {}\n Modint operator - ()\n {\n return Modint(-x);\n }\n Modint& operator +=(Modint a)\n {\n x += a.x;\n if(x >= Mod)x -= Mod;\n return *this;\n }\n Modint& operator -=(Modint a)\n {\n if(x < a.x)x += Mod;\n x -= a.x;\n return *this;\n }\n Modint& operator *=(Modint a)\n {\n (x *= a.x) %= Mod;\n return *this;\n }\n Modint operator + (Modint a)\n {\n Modint b(*this);\n b += a;\n return b;\n }\n Modint operator - (Modint a)\n {\n Modint b(*this);\n b -= a;\n return b;\n }\n Modint operator * (Modint a)\n {\n Modint b(*this);\n b *= a;\n return b;\n }\n long long int EXTGCD(long long int a, long long int b, long long int &x, long long int &y)\n {\n if(b==0)\n {\n x = 1;\n y = 0;\n return a;\n }\n long long int g = EXTGCD(b,a%b,y,x);\n y -= (a/b)*x;\n return g;\n }\n Modint inverse()\n {\n long long int a,b;\n EXTGCD(x,Mod,a,b);\n a %= Mod;\n return a;\n }\n Modint pow(ll a)\n {\n Modint res = 1;\n Modint b = x;\n while(a > 0)\n {\n if(a & 1)res *= b;\n a = a >> 1;\n b *= b;\n }\n return res;\n }\n friend ostream& operator<<(ostream& os, const Modint& a);\n};\nostream& operator<< (ostream& os, const Modint& a)\n{\n os << a.x;\n return os;\n}\nstruct combination\n{\n vector<Modint> fact,ifact;\n combination(int n) : fact(n+1), ifact(n+1)\n {\n fact[0] = 1;\n for(int i=1;i<=n;i++)fact[i] = fact[i-1] * i;\n ifact[n] = fact[n].inverse();\n for(int i=n;i>=1;i--)ifact[i-1] = ifact[i] * i;\n }\n Modint operator() (int n,int k)\n {\n return fact[n]*ifact[n-k]*ifact[k];\n }\n};\nusing vm = vector<Modint>;\nusing vvm = vector<vm>;\ntemplate<class Z>\nstruct MyMatrix\n{\n using mat = MyMatrix<Z>;\n vector<vector<Z>> m_dat;\n int m_h;\n int m_w;\n MyMatrix(int h, int w) : m_h(h), m_w(w) ,m_dat(h,vector<Z>(w)) {}\n vector<Z> &operator[] (int idx)\n {\n return m_dat[idx];\n }\n mat Multiple(mat &a)\n {\n mat C(m_h, a.m_w);\n for(int i=0;i<m_h;i++)\n {\n for(int j=0;j<a.m_w;j++)\n {\n for(int k=0;k<m_w;k++)\n {\n C[i][j] += m_dat[i][k] * a[k][j];\n }\n }\n }\n return C;\n }\n mat Pow(ll x)\n {\n mat B(m_h,m_w);\n for(int i=0;i<m_h;i++)\n {\n B[i][i] = 1;\n }\n mat A = *this;\n while(x > 0)\n {\n if(x&1)B = B.Multiple(A);\n A = A.Multiple(A);\n x = x >> 1;\n }\n return B;\n }\n //friend ostream& operator<<(ostream &os, const mat &A);\n};\n/*\ntemplate<class Z>\nostream& operator<<(ostream &os, Matrix<Z>& A)\n{\n for(int i=0;i<A.m_h;i++)\n {\n for(int j=0;j<A.m_w;j++)\n {\n os << A[i][j] << \" \";\n }\n os << endl;\n }\n return os;\n}\n*/\ntemplate<class T>\nusing mat = MyMatrix<T>;\n//_____________________ following sorce code_________________________//\nconst int max_n = 3 * (1e5) + 1;\nconst int max_m = 83 * (1e5) + 1;\n\nint n,m,k;\nll N;\nint h,w;\nstring S;\nint a,b,c;\nvi v;\nint ans;\ndouble x,y,z;\nvector<int> G[1010101];\nvi arr;\nvvll dp;\nll rec(int l,int r)\n{\n if(dp[l][r] >= 0)return dp[l][r];\n if(l == r)return dp[l][r] = 0;\n int x = r-l;\n ll res = 0;\n if(x%2 == n%2)\n {\n chmax(res,max(rec(l+1,r)+arr[l], rec(l,r-1)+arr[r-1]));\n }\n else \n {\n if(arr[l] > arr[r-1])\n {\n res = rec(l+1,r);\n }\n else\n {\n res = rec(l,r-1);\n }\n }\n //OUT(l,r);\n dp[l][r] = res;\n //cout << \"dp[\" << l << \"][\" << r << \"] = \" << dp[l][r] << endl;\n return dp[l][r];\n}\n\nvoid solve()\n{\n IN(n);\n rep(i,n)\n {\n IN(a);\n arr.push_back(a);\n }\n rep(i,n)\n {\n arr.push_back(arr[i]);\n }\n ll ans = 0;\n dp = vvll(n+n+3,vll(n+n+3,-1));\n rep(i,n)\n {\n ll res = rec(i,i+n);\n //dump(res);\n chmax(ans,res);\n }\n pri(ans);\n}\n\nsigned main (int argc, char* argv[]) {\n cin.tie(0);\n ios::sync_with_stdio(false);\n int cases=1;\n //IN(cases);\n while(cases--)solve();\n //pri(ans);\n //for(auto c : ans){cout << c << endl;}\n //cout << fixed << setprecision(15) << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 152052, "score_of_the_acc": -1.0707, "final_rank": 17 }, { "submission_id": "aoj_0615_4542145", "code_snippet": "#include <iostream>\nusing namespace std;\ntypedef long long ll;\nll dp[4000][4000],n,a,b,ans,x;\nll f(ll a,ll b,ll cnt){\n if(a==b&&cnt%2==0)return 0;\n if(dp[a][b]>0&&cnt%2==1)return dp[a][b];\n if(cnt%2==1){\n x=max(f(a+1,b,cnt+1)+dp[a][a],f(a,b-1,cnt+1)+dp[b][b]);\n dp[a][b]=x;\n return x;\n }\n else{\n if(dp[a][a]>dp[b][b])x=f(a+1,b,cnt+1);\n else x=f(a,b-1,cnt+1);\n dp[a][b]=x;\n return x;\n }\n}\nint main(void){\n cin>>n;\n for(int i=0;i<n;i++){\n cin>>a;\n dp[i][i]=a;\n dp[i+n][i+n]=a;\n }\n for(int i=0;i<n;i++){\n ans=max(ans,dp[i][i]+f(i+1,i+n-1,0));\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 65084, "score_of_the_acc": -0.4843, "final_rank": 8 } ]
aoj_0617_cpp
舞踏会 (Ball) IOI 王国では,王女である JOI 姫の誕生日を祝って舞踏会が開かれることになった. 舞踏会には N 人の貴族が参加する予定である. N は奇数である.貴族には 1 から N までの番号が付けられている.それぞれの貴族には踊りのうまさという整数が定められており,貴族 i (1 ≤ i ≤ N ) の踊りのうまさは D i である. 舞踏会では JOI 姫を含む N + 1 人で 2 人ずつ組を作って踊る.IOI 王国では,上級者が初級者を補助できるように,伝統的に以下の方法で踊りの組を決定している. 最初に, N 人の貴族が 1 列に並ぶ. 列に並んでいる貴族が 1 人になるまで,以下の操作を繰り返す. - 列の先頭から 3 人の貴族の踊りのうまさを調べる. - その 3 人の貴族の中で,最も踊りのうまさが大きい貴族を A とおく.ただし,複数いる場合は,最も踊りのうまさが大きい貴族の中で,最も番号の小さい貴族 を A とおく. - その 3 人の貴族の中で,最も踊りのうまさが小さい貴族を B とおく.ただし,複数いる場合は,最も踊りのうまさが小さい貴族の中で,最も番号の大きい貴族 を B とおく. - A と B が列から抜けて組になる. - 残った 1 人は列の最後尾に移動する. 最終的に残った 1 人が JOI 姫と組になる. 貴族 1 から貴族 M (1 ≤ M ≤ N − 2) の M 人の貴族については,すでに初期状態で列の何番目に並ぶのかが決まっている.残りの N − M 人の貴族の並び方は国王が自由に決めることができる. JOI 姫は踊りを学んだばかりなので,国王は JOI 姫と組になる貴族の踊りのうまさをできるだけ大きくしたいと考えている.JOI 姫と組になる貴族の踊りのうまさとして考えられる最大値を求めよ. 課題 それぞれの貴族の踊りのうまさと, M 人の貴族の初期状態で並ぶ場所が与えられたとき,JOI 姫と組になる貴族の踊りのうまさとして考えられる最大値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,2 個の整数 N , M が空白を区切りとして書かれている.これは舞踏会に貴族が N 人参加し,列に並ぶ場所がすでに決まっている貴族が M 人いることを表す. 続く M 行のうちの i 行目 (1 ≤ i ≤ M ) には,2 個の整数 D i , P i が空白を区切りとして書かれている.これは貴族 i の踊りのうまさが D i で,貴族 i が初期状態で列の先頭から P i 番目に並ぶことを表す. 続く N − M 行のうちの i 行目 (1 ≤ i ≤ N − M ) には,整数 D i+M が書かれている.これは貴族 ( i + M )の踊りのうまさが D i+M であることを表す. 出力 標準出力に,JOI 姫と組になる貴族の踊りのうまさとして考えられる最大値を表す整数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 3 ≤ N ≤ 99 999. N は奇数である. 1 ≤ M ≤ N − 2. 1 ≤ D i ≤ 1 000 000 000 (1 ≤ i ≤ N ). 1 ≤ P i ≤ N (1 ≤ i ≤ M ). P i ≠ P j (1 ≤ i < j ≤ M ). 入出力例 入力例 1 7 3 5 2 5 5 8 6 6 2 8 9 出力例 1 8 初期状態では 3 人の貴族の並ぶ場所がすでに決まっている. 括弧内の数字は踊りのうまさを表す.左端が列の先頭である. 例えば,先頭から順に貴族 5,貴族 1,貴族 4,貴族 6,貴族 2,貴族 3,貴族 7 という順番に並んだ場 合を考える. すべての貴族が並んだあとの配置 この場合,以下のように列が変化していく. 列の先頭の 3 人の貴族 (貴族 5,貴族 1,貴族 4) 中で,最も踊りのうまさが大きい貴族 4 と最も踊りのうまさが小さい貴族 5 が組になり,残った貴族 1 が最後尾に移動する. 次に,列の先頭の 3 人の貴族 (貴族 6,貴族 2,貴族 3) の中で,最も踊りのうまさが大きい貴族は貴族 6 と貴族 3 の 2 人であり,このうち番号の小さい貴族は貴族 3 である.また,列の先頭の 3 人の貴族のうち最も踊りのうまさが小さい貴族は貴族 2 である.貴族 3 と貴族 2 が組になり,残った貴族 6 が最後尾に移動する. 次に,列の先頭の 3 人の貴族 (貴族 7,貴族 1,貴族 6) の中で,最も踊りのうまさが大きい貴族 7 と最も踊りのうまさが小さい貴族 1 が組になり,残った貴族 6 が最後尾に移動する. 最終的に貴族 6 が残り,JOI 姫と組になる.貴族 6 の踊りのうまさは 8 である.この値が JOI 姫と組になる貴族の踊りのうまさとして考えられる最大値である. 列の変化の様子 入力例 2 3 1 5 3 5 5 出力例 2 5 どのような順番で並んでも,貴族 2 と JOI 姫が組になる. 入力例 3 7 2 32 4 27 6 37 41 41 30 27 出力例 3 37 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0617_10852952", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<queue>\n#include<vector>\n#include<map>\nusing namespace std;\nint n, m, a, b, c[100000], D[100000], E[100000];\nmap<vector<int>, tuple<vector<int>, vector<int>, vector<int>>>M;\nvoid make(int n) {\n\tqueue<vector<int>>Q; for (int i = 1; i <= n; i++) { vector<int>ichi; ichi.push_back(i); Q.push(ichi); }\n\twhile (Q.size() > 1) {\n\t\tvector<int>b1 = Q.front(); Q.pop();\n\t\tvector<int>b2 = Q.front(); Q.pop();\n\t\tvector<int>b3 = Q.front(); Q.pop();\n\t\tvector<int>sum;\n\t\tfor (int i = 0; i < b1.size(); i++)sum.push_back(b1[i]);\n\t\tfor (int i = 0; i < b2.size(); i++)sum.push_back(b2[i]);\n\t\tfor (int i = 0; i < b3.size(); i++)sum.push_back(b3[i]);\n\t\tsort(sum.begin(), sum.end());\n\t\tM[sum] = make_tuple(b1, b2, b3); Q.push(sum);\n\t}\n\tQ.pop();\n}\nint solve(vector<int>vec, int border) {\n\tif (vec.size() == 1) {\n\t\tif (c[vec[0]] < border && c[vec[0]] >= 1)return 10000000;\n\t\tif (c[vec[0]] >= border && c[vec[0]] >= 1)return 0;\n\t\treturn 1;\n\t}\n\tint s[3] = { solve(get<0>(M[vec]), border),solve(get<1>(M[vec]), border),solve(get<2>(M[vec]), border) };\n\tsort(s, s + 3);\n\treturn s[0] + s[1];\n}\nint main() {\n\tcin >> n >> m; for (int i = 0; i < m; i++) { cin >> a >> b; c[b] = a; D[i] = a; }\n\tfor (int i = m; i < n; i++) { cin >> a; D[i] = a; E[i - m] = a; }\n\tsort(D, D + n); sort(E, E + n - m);\n\tmake(n);\n\tint maxn = 0;\n\tvector<int>Ball; for (int i = 1; i <= n; i++)Ball.push_back(i);\n\t\n\t//--------------------------------------------Binary Search------------------------------------\n\tint L = 0, R = n, M;\n\twhile (true) {\n\t\tbool Y1 = false, Y2 = false;\n\t\tM = (L + R) / 2;\n\t\tif (M < n) {\n\t\t\tint F = solve(Ball, D[M]);\n\t\t\tint pos1 = lower_bound(E, E + n - m, D[M] - 1) - E;\n\t\t\tpos1 = (n - m) - pos1;\n\t\t\tif (F <= pos1)Y1 = true;\n\t\t}\n\t\tif (M < n - 1) {\n\t\t\tint F = solve(Ball, D[M + 1]);\n\t\t\tint pos2 = lower_bound(E, E + n - m, D[M + 1] - 1) - E;\n\t\t\tpos2 = (n - m) - pos2;\n\t\t\tif (F <= pos2)Y2 = true;\n\t\t}\n\t\tif (Y1 == true && Y2 == false) { maxn = D[M]; break; }\n\t\tif (Y1 == false) { R = M; }\n\t\tif (Y2 == true) { L = M; }\n\t}\n\tcout << maxn << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 26196, "score_of_the_acc": -1.1057, "final_rank": 16 }, { "submission_id": "aoj_0617_9488094", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<int, ll> Q;\n#define mp make_pair\n#define pb push_back\n#define INF 10000000\n\nint n, m;\nint s[100005], p[100005];\nint q[200005];\n\nint main() {\n // 入力を受け取ります\n cin >> n >> m;\n for (int i = 1; i <= m; i++) {\n cin >> s[i] >> p[i];\n }\n for (int i = m + 1; i <= n; i++) {\n cin >> s[i];\n }\n\n // 二分探索の範囲を設定します\n int lb = 0;\n int ub = 1e9 + 50;\n\n // 二分探索を実行します\n while (ub - lb > 1) {\n int mid = (lb + ub) / 2;\n int x = 1, y = n;\n\n // 配列qを初期化します\n fill(q + 1, q + n + 1, 1);\n for (int i = 1; i <= m; i++) {\n if (s[i] >= mid) {\n q[p[i]] = 0;\n } else {\n q[p[i]] = n + 5;\n }\n }\n\n // 条件に基づいて配列qを更新します\n while (y - x > 1) {\n int sum = q[x] + q[x + 1] + q[x + 2];\n sum -= max({q[x], q[x + 1], q[x + 2]});\n q[y + 1] = sum;\n x += 3;\n y++;\n }\n\n // 条件を満たす要素のカウント\n int cnt = 0;\n for (int i = m + 1; i <= n; i++) {\n cnt += (s[i] >= mid);\n }\n\n // 二分探索の範囲を更新します\n if (q[y] <= cnt) {\n lb = mid;\n } else {\n ub = mid;\n }\n }\n\n // 結果を出力します\n cout << lb << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4680, "score_of_the_acc": -0.0385, "final_rank": 5 }, { "submission_id": "aoj_0617_4952681", "code_snippet": "#include <cassert>\n#include <iostream>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nconst long long INF = 1e9;\n\n\nvector<vector<long long>> generate_graph(long long n){\n vector<vector<long long>> G(n);\n deque<long long> dq;\n for(long long i = 0; i < n; ++i)\n dq.emplace_back(i);\n long long sz = n;\n while(dq.size() > 1){\n vector<long long> ch;\n for(long long i = 0; i < 3; ++i){\n ch.emplace_back(dq.front());\n dq.pop_front();\n }\n G.emplace_back(ch);\n dq.emplace_back(sz);\n ++sz;\n }\n return G;\n}\n\nlong long solve(const vector<vector<long long>>& G, long long v, const vector<long long>& E){\n if(G[v].empty()){\n if(E[v] == 1) return 0;\n if(E[v] < 0) return 1;\n return INF;\n }\n assert(G[v].size() == 3);\n long long ma = 0, s = 0;\n for(auto u : G[v]){\n long long x = solve(G,u,E);\n s += x;\n ma = max(ma,x);\n }\n s -= ma;\n s = min(s,INF);\n return s;\n}\n\nint main(){\n long long N, M;\n cin >> N >> M;\n vector<long long> D(N,-1);\n vector<long long> R;\n for(long long i = 0; i < M; ++i){\n long long d, p;\n cin >> d >> p;\n --p;\n D[p] = d;\n }\n for(long long i = M; i < N; ++i){\n long long d;\n cin >> d;\n R.emplace_back(d);\n }\n long long ok = 0, ng = INF;\n auto G = generate_graph(N);\n // for(size_t i = 0; i < G.size(); ++i){\n // cerr << i << \" : \";\n // for(auto e : G[i])\n // cerr << e << \" \";\n // cerr << endl;\n // }\n const long long v = G.size()-1;\n // cerr << v << endl;\n while(ng-ok > 1){\n long long m = (ok+ng)/2;\n vector<long long> E(N);\n // 0 : D[i] < m\n // 1 : D[i] >= m\n // -1 : 未確定\n for(long long i = 0; i < N; ++i){\n if(D[i] == -1) E[i] = -1;\n else if(D[i] < m) E[i] = 0;\n else E[i] = 1;\n }\n long long c = 0;\n for(auto e : R){\n c += (e >= m);\n }\n long long x = solve(G,v,E);\n // cerr << m << \" \" << c << \" \" << x << endl;\n if(x <= c) ok = m;\n else ng = m;\n }\n cout << ok << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 12064, "score_of_the_acc": -0.1262, "final_rank": 10 }, { "submission_id": "aoj_0617_4952587", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint PREP = (cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(12), 0);\nconst int INF = 1e9;\nstruct Tree {\n Tree(int i) {\n idx = i;\n children[0] = children[1] = children[2] = nullptr;\n }\n Tree(Tree *a, Tree *b, Tree *c) {\n idx = -1;\n children[0] = a, children[1] = b, children[2] = c;\n }\n int idx;\n Tree *children[3];\n int ans;\n};\nTree* build(int n) {\n assert(n % 2 == 1);\n deque<Tree*> items;\n for (int i = 0; i < n; i++) {\n items.push_back(new Tree(i));\n }\n while (items.size() >= 2) {\n auto t = new Tree(items[0], items[1], items[2]);\n items.pop_front(), items.pop_front(), items.pop_front();\n items.push_back(t);\n }\n return items[0];\n}\nint main() {\n int N, M; cin >> N >> M;\n vector<int> D(N, -1);\n vector<int> rest(N - M);\n for (int i = 0; i < M; i++) {\n int d, p; cin >> d >> p; p--;\n D[p] = d;\n }\n for (int i = 0; i < N - M; i++) {\n int d; cin >> d;\n rest.push_back(d);\n }\n Tree *root = build(N);\n int ok = 1, ng = 1000000001;\n while (abs(ok - ng) > 1) {\n int mid = (ok + ng) / 2;\n int cnt = 0;\n for (auto r : rest) {\n if (r >= mid) cnt++;\n }\n auto recur = [&](auto&& recur, Tree *node) -> void {\n if (node->idx >= 0) {\n if (D[node->idx] >= mid) {\n node->ans = 0;\n } else if (D[node->idx] == -1) {\n node->ans = 1;\n } else {\n node->ans = INF;\n }\n } else {\n for (int i = 0; i < 3; i++) {\n recur(recur, node->children[i]);\n }\n int sum = 0, maxval = 0;\n for (int i = 0; i < 3; i++) {\n int a = node->children[i]->ans;\n sum += a;\n maxval = max(maxval, a);\n }\n node->ans = min(INF, sum - maxval);\n }\n };\n recur(recur, root);\n if (cnt >= root->ans) {\n ok = mid;\n } else {\n ng = mid;\n }\n }\n cout << ok << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 11268, "score_of_the_acc": -0.0523, "final_rank": 6 }, { "submission_id": "aoj_0617_4822188", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nconst int inf = 123456789;\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, M;\n\tcin >> N >> M;\n\tvector<pair<int, int> > X(M);\n\tvector<int> Y(N - M);\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin >> X[i].first >> X[i].second;\n\t\t--X[i].second;\n\t}\n\tfor (int i = 0; i < N - M; ++i) {\n\t\tcin >> Y[i];\n\t}\n\tsort(X.begin(), X.end(), greater<pair<int, int> >());\n\tsort(Y.begin(), Y.end(), greater<int>());\n\tvector<int> dp(N + N / 2, 1);\n\tfor (int i = 0; i < M; ++i) {\n\t\tdp[X[i].second] = inf;\n\t}\n\tfor (int i = 0; (i + 1) * 2 < N; ++i) {\n\t\tdp[i + N] = min(dp[i * 3] + dp[i * 3 + 1] + dp[i * 3 + 2] - max({ dp[i * 3], dp[i * 3 + 1], dp[i * 3 + 2] }), inf);\n\t}\n\tint ans = (dp.back() != inf ? Y[dp.back() - 1] : -inf);\n\tfor (int i = 0; i < M; ++i) {\n\t\tint pos = X[i].second;\n\t\tdp[pos] = 0;\n\t\twhile (pos + 1 != N + N / 2) {\n\t\t\tpos /= 3;\n\t\t\tdp[pos + N] = min(dp[pos * 3] + dp[pos * 3 + 1] + dp[pos * 3 + 2] - max({ dp[pos * 3], dp[pos * 3 + 1], dp[pos * 3 + 2] }), inf);\n\t\t\tpos += N;\n\t\t}\n\t\tans = max(ans, min(X[i].first, dp.back() != inf ? Y[dp.back() - 1] : -inf));\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4116, "score_of_the_acc": -0.0007, "final_rank": 1 }, { "submission_id": "aoj_0617_4254691", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#pragma GCC target (\"avx\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define R pair<pair<int, int>, pair<int, int>>\n#define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l))\n#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)\n#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)\n#define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--)\n#define range(i,v) for(auto& (i) : v)\n#define mkp make_pair\n#define mem(x,k) memset(x,k,sizeof(x))\n#define vec vector\n#define pb emplace_back\n#define lb lower_bound\n#define ub upper_bound\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==n-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define itn int\n#define pri_que priority_queue\n#define pp(x,y) pb(H{x,y})\n#define ppp(x,y,z) pb(Q(x,y,z))\n#define pppp(x,y,z,w) pb(S(x,y,z,w))\n#define cyes cout<<\"Yes\\n\"\n#define cno cout<<\"No\\n\"\n#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr int MXN = 500000 + 100;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconst vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; ll k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nvoid printh(H t) { printf(\"%lld %lld\\n\", t.fs, t.sc); }\nbool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll mod_pow(ll x, ll n, ll p = mod) {\n\tll res = 1;\n\twhile (n > 0) {\n\t\tif (n & 1) res = res * x % p;\n\t\tx = x * x % p;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}//x^n%p\nll bitcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\n/*constexpr int fn_ = 1000005;\nll fact_[fn_], comp_[fn_];\nll comb(ll x, ll y, ll Mod = mod) {\n\tif (!fact_[0]) {\n\t\tfact_[0] = 1; comp_[0] = 1;\n\t\tfor (int i = 1; i < fn_; i++)\n\t\t\tfact_[i] = fact_[i - 1] * i % Mod;\n\t\tcomp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);\n\t\tfor (int i = fn_ - 2; i > 0; i--)\n\t\t\tcomp_[i] = comp_[i + 1] * (i + 1) % Mod;\n\t}\n\tif (x < y) return 0;\n\treturn fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;\n}*/\n//--------------------------------------------------------------\nint n, m;\nvec<int>e[1000000];\nint a[1000000];\nvec<int>d;\nint solve(int pos, int t) {\n\tif (e[pos].size() == 0) {\n\t\tif (a[pos]) {\n\t\t\tif (a[pos] >= t) return 0;\n\t\t\telse return Inf;\n\t\t}\n\t\telse return 1;\n\t}\n\tvec<int>b;\n\tfor (auto to : e[pos]) b.pb(solve(to, t));\n\tsort(all(b));\n\treturn b[0] + b[1];\n}\nsigned main() {\n\tcin >> n >> m;\n\trep(i, m) {\n\t\tint u, v; cin >> u >> v;\n\t\ta[v - 1] = u;\n\t}\n\trep(i, n - m) d.pb(read());\n\tdeque<int>dq;\n\trep(i, n) dq.push_back(i);\n\tint idx = n;\n\twhile (dq.size() > 1) {\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\tdq.push_back(idx++);\n\t}\n\tsort(all(d));\n\tint ok = 0, ng = Inf, mid;\n\twhile (abs(ng - ok) > 1) {\n\t\tmid = (ok + ng) / 2;\n\t\tint sum = (n - m) - (lower_bound(all(d), mid) - d.begin());\n\t\tif (solve(idx - 1, mid) <= sum) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 30276, "score_of_the_acc": -0.4585, "final_rank": 15 }, { "submission_id": "aoj_0617_4254678", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#pragma GCC target (\"avx\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define R pair<pair<int, int>, pair<int, int>>\n#define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l))\n#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)\n#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)\n#define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--)\n#define range(i,v) for(auto& (i) : v)\n#define mkp make_pair\n#define mem(x,k) memset(x,k,sizeof(x))\n#define vec vector\n#define pb emplace_back\n#define lb lower_bound\n#define ub upper_bound\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==n-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define itn int\n#define pri_que priority_queue\n#define pp(x,y) pb(H{x,y})\n#define ppp(x,y,z) pb(Q(x,y,z))\n#define pppp(x,y,z,w) pb(S(x,y,z,w))\n#define cyes cout<<\"Yes\\n\"\n#define cno cout<<\"No\\n\"\n#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr int MXN = 500000 + 100;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconst vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; ll k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nvoid printh(H t) { printf(\"%lld %lld\\n\", t.fs, t.sc); }\nbool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll mod_pow(ll x, ll n, ll p = mod) {\n\tll res = 1;\n\twhile (n > 0) {\n\t\tif (n & 1) res = res * x % p;\n\t\tx = x * x % p;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}//x^n%p\nll bitcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\n/*constexpr int fn_ = 1000005;\nll fact_[fn_], comp_[fn_];\nll comb(ll x, ll y, ll Mod = mod) {\n\tif (!fact_[0]) {\n\t\tfact_[0] = 1; comp_[0] = 1;\n\t\tfor (int i = 1; i < fn_; i++)\n\t\t\tfact_[i] = fact_[i - 1] * i % Mod;\n\t\tcomp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);\n\t\tfor (int i = fn_ - 2; i > 0; i--)\n\t\t\tcomp_[i] = comp_[i + 1] * (i + 1) % Mod;\n\t}\n\tif (x < y) return 0;\n\treturn fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;\n}*/\n//--------------------------------------------------------------\nint n, m;\nvec<int>e[9000000];\nint a[1000000];\nvec<int>d;\nint solve(int pos, int t) {\n\tif (e[pos].size() == 0) {\n\t\tif (a[pos]) {\n\t\t\tif (a[pos] >= t) return 0;\n\t\t\telse return inf;\n\t\t}\n\t\telse return 1;\n\t}\n\tvec<int>b;\n\tfor (auto to : e[pos]) b.pb(solve(to, t));\n\tsort(all(b));\n\treturn b[0] + b[1];\n}\nsigned main() {\n\tcin >> n >> m;\n\trep(i, m) {\n\t\tint u, v; cin >> u >> v;\n\t\ta[v - 1] = u;\n\t}\n\trep(i, n - m) d.pb(read());\n\tdeque<int>dq;\n\trep(i, n) dq.push_back(i);\n\tint idx = n;\n\twhile (dq.size() > 1) {\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\tdq.push_back(idx++);\n\t}\n\tif (idx >= 1000000) assert(0);\n\tsort(all(d));\n\tint ok = -10, ng = inf, mid;\n\twhile (abs(ng - ok) > 1) {\n\t\tmid = (ok + ng) / 2;\n\t\tint sum = (n - m) - (lower_bound(all(d), mid) - d.begin());\n\t\tif (solve(idx - 1, mid) <= sum) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << endl;\n}", "accuracy": 0.5882352941176471, "time_ms": 70, "memory_kb": 214192, "score_of_the_acc": -1.0875, "final_rank": 19 }, { "submission_id": "aoj_0617_4254535", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#pragma GCC target (\"avx\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define R pair<pair<int, int>, pair<int, int>>\n#define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l))\n#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)\n#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)\n#define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--)\n#define range(i,v) for(auto& (i) : v)\n#define mkp make_pair\n#define mem(x,k) memset(x,k,sizeof(x))\n#define vec vector\n#define pb emplace_back\n#define lb lower_bound\n#define ub upper_bound\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==n-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define itn int\n#define pri_que priority_queue\n#define pp(x,y) pb(H{x,y})\n#define ppp(x,y,z) pb(Q(x,y,z))\n#define pppp(x,y,z,w) pb(S(x,y,z,w))\n#define cyes cout<<\"Yes\\n\"\n#define cno cout<<\"No\\n\"\n#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr int MXN = 500000 + 100;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconst vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; ll k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nvoid printh(H t) { printf(\"%lld %lld\\n\", t.fs, t.sc); }\nbool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll mod_pow(ll x, ll n, ll p = mod) {\n\tll res = 1;\n\twhile (n > 0) {\n\t\tif (n & 1) res = res * x % p;\n\t\tx = x * x % p;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}//x^n%p\nll bitcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\n/*constexpr int fn_ = 1000005;\nll fact_[fn_], comp_[fn_];\nll comb(ll x, ll y, ll Mod = mod) {\n\tif (!fact_[0]) {\n\t\tfact_[0] = 1; comp_[0] = 1;\n\t\tfor (int i = 1; i < fn_; i++)\n\t\t\tfact_[i] = fact_[i - 1] * i % Mod;\n\t\tcomp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);\n\t\tfor (int i = fn_ - 2; i > 0; i--)\n\t\t\tcomp_[i] = comp_[i + 1] * (i + 1) % Mod;\n\t}\n\tif (x < y) return 0;\n\treturn fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;\n}*/\n//--------------------------------------------------------------\nint n, m;\nvec<int>e[9000000];\nint a[1000000];\nvec<int>d;\nint solve(int pos, int t) {\n\tif (e[pos].size() == 0) {\n\t\tif (a[pos]) {\n\t\t\tif (a[pos] >= t) return 0;\n\t\t\telse return inf;\n\t\t}\n\t\telse return 1;\n\t}\n\tvec<int>b;\n\tfor (auto to : e[pos]) b.pb(solve(to, t));\n\tsort(all(b));\n\treturn b[0] + b[1];\n}\nsigned main() {\n\tcin >> n >> m;\n\trep(i, m) {\n\t\tint u, v; cin >> u >> v;\n\t\ta[v - 1] = u;\n\t}\n\trep(i, n - m) d.pb(read());\n\tdeque<int>dq;\n\trep(i, n) dq.push_back(i);\n\tint idx = n;\n\twhile (dq.size() > 1) {\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\tdq.push_back(idx++);\n\t}\n\tsort(all(d));\n\tint ok = -10, ng = inf, mid;\n\twhile (abs(ng - ok) > 1) {\n\t\tmid = (ok + ng) / 2;\n\t\tint sum = (n - m) - (lower_bound(all(d), mid) - d.begin());\n\t\tif (solve(idx - 1, mid) <= sum) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << endl;\n}", "accuracy": 0.5882352941176471, "time_ms": 70, "memory_kb": 214232, "score_of_the_acc": -1.0877, "final_rank": 20 }, { "submission_id": "aoj_0617_4254522", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#pragma GCC target (\"avx\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define R pair<pair<int, int>, pair<int, int>>\n#define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l))\n#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)\n#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)\n#define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--)\n#define range(i,v) for(auto& (i) : v)\n#define mkp make_pair\n#define mem(x,k) memset(x,k,sizeof(x))\n#define vec vector\n#define pb emplace_back\n#define lb lower_bound\n#define ub upper_bound\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==n-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define itn int\n#define pri_que priority_queue\n#define pp(x,y) pb(H{x,y})\n#define ppp(x,y,z) pb(Q(x,y,z))\n#define pppp(x,y,z,w) pb(S(x,y,z,w))\n#define cyes cout<<\"Yes\\n\"\n#define cno cout<<\"No\\n\"\n#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr int MXN = 500000 + 100;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconst vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; ll k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nvoid printh(H t) { printf(\"%lld %lld\\n\", t.fs, t.sc); }\nbool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll mod_pow(ll x, ll n, ll p = mod) {\n\tll res = 1;\n\twhile (n > 0) {\n\t\tif (n & 1) res = res * x % p;\n\t\tx = x * x % p;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}//x^n%p\nll bitcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\n/*constexpr int fn_ = 1000005;\nll fact_[fn_], comp_[fn_];\nll comb(ll x, ll y, ll Mod = mod) {\n\tif (!fact_[0]) {\n\t\tfact_[0] = 1; comp_[0] = 1;\n\t\tfor (int i = 1; i < fn_; i++)\n\t\t\tfact_[i] = fact_[i - 1] * i % Mod;\n\t\tcomp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);\n\t\tfor (int i = fn_ - 2; i > 0; i--)\n\t\t\tcomp_[i] = comp_[i + 1] * (i + 1) % Mod;\n\t}\n\tif (x < y) return 0;\n\treturn fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;\n}*/\n//--------------------------------------------------------------\nint n, m;\nvec<int>e[3000000];\nint a[1000000];\nvec<int>d;\nint solve(int pos, int t) {\n\tif (e[pos].size() == 0) {\n\t\tif (a[pos]) {\n\t\t\tif (a[pos] >= t) return 0;\n\t\t\telse return inf;\n\t\t}\n\t\telse return 1;\n\t}\n\tvec<int>b;\n\tfor (auto to : e[pos]) b.pb(solve(to, t));\n\tsort(all(b));\n\treturn b[0] + b[1];\n}\nsigned main() {\n\tcin >> n >> m;\n\trep(i, m) {\n\t\tint u, v; cin >> u >> v;\n\t\ta[v - 1] = u;\n\t}\n\trep(i, n - m) d.pb(read());\n\tdeque<int>dq;\n\trep(i, n) dq.push_back(i);\n\tint idx = n;\n\twhile (dq.size() > 1) {\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\te[idx].pb(dq.front()); dq.pop_front();\n\t\tdq.push_back(idx++);\n\t}\n\tsort(all(d));\n\tint ok = -10, ng = inf, mid;\n\twhile (abs(ng - ok) > 1) {\n\t\tmid = (ok + ng) / 2;\n\t\tint sum = (n - m) - (lower_bound(all(d), mid) - d.begin());\n\t\tif (solve(idx - 1, mid) <= sum) ok = mid;\n\t\telse ng = mid;\n\t}\n\tcout << ok << endl;\n}", "accuracy": 0.5882352941176471, "time_ms": 30, "memory_kb": 73564, "score_of_the_acc": -0.3485, "final_rank": 18 }, { "submission_id": "aoj_0617_3811610", "code_snippet": "#include <bits/stdc++.h>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define RFOR(i,a) for(int i=(a); i >= 0; --i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define BIT_ON(bit, i) (((bit >> i) & 1) > 0)\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\ntemplate<class T> inline void print(T x) { std::cout << x << std::endl; }\ntemplate<class T> inline void print_vec(const std::vector<T> &v) { for (int i = 0; i < v.size(); ++i) { if (i != 0) {std::cout << \" \";} std::cout << v[i];} std::cout << \"\\n\"; }\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 58u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\n\nbool ok(const long long x, const vector<LL> &fix, const vector<LL> &v) {\n auto dp = make_v<LL>(fix.size());\n FOR(i, 0, fix.size()) {\n if (fix[i] == 0) {\n dp[i] = 1;\n }\n else if (fix[i] >= x) {\n dp[i] = 0;\n }\n else {\n dp[i] = INF;\n }\n }\n\n int i = 0;\n while (i + 2 < dp.size()) {\n LL n = dp[i] + dp[i + 1] + dp[i + 2] - max({dp[i], dp[i + 1], dp[i + 2]});\n i += 3;\n dp.emplace_back(n);\n\n if (i >= dp.size()) {\n break;\n }\n }\n\n LL num_need_high = dp.back();\n int num_high = 0;\n FOE(a, v) {\n num_high += a >= x;\n }\n\n return num_high >= num_need_high;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n LL N, M;\n cin >> N >> M;\n\n auto fix = make_v<LL>(N);\n FOR(i, 0, M) {\n LL D, P;\n cin >> D >> P;\n P--;\n fix[P] = D;\n }\n\n auto v = make_v<LL>(N - M);\n FOR(i, 0, N - M) {\n cin >> v[i];\n }\n\n long long low = -1;\n long long high = 10000000100ll;\n while (high - low > 1) {\n long long middle = (low + high) / 2;\n if (ok(middle, fix, v)) {\n low = middle;\n }\n else {\n high = middle;\n }\n }\n print(low);\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6336, "score_of_the_acc": -0.0113, "final_rank": 2 }, { "submission_id": "aoj_0617_3811606", "code_snippet": "#include <bits/stdc++.h>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define RFOR(i,a) for(int i=(a); i >= 0; --i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define BIT_ON(bit, i) (((bit >> i) & 1) > 0)\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\ntemplate<class T> inline void print(T x) { std::cout << x << std::endl; }\ntemplate<class T> inline void print_vec(const std::vector<T> &v) { for (int i = 0; i < v.size(); ++i) { if (i != 0) {std::cout << \" \";} std::cout << v[i];} std::cout << \"\\n\"; }\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 58u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\n\nbool ok(const long long x, const vector<LL> &fix, const vector<LL> &v) {\n auto dp = make_v<LL>(fix.size());\n FOR(i, 0, fix.size()) {\n if (fix[i] == 0) {\n dp[i] = 1;\n }\n else if (fix[i] >= x) {\n dp[i] = 0;\n }\n else {\n dp[i] = LINF;\n }\n }\n\n int i = 0;\n while (i + 2 < dp.size()) {\n LL n = dp[i] + dp[i + 1] + dp[i + 2] - max({dp[i], dp[i + 1], dp[i + 2]});\n i += 3;\n dp.emplace_back(n);\n\n if (i >= dp.size()) {\n break;\n }\n }\n\n LL num_need_high = dp.back();\n int num_high = 0;\n FOE(a, v) {\n num_high += a >= x;\n }\n\n return num_high >= num_need_high;\n}\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n LL N, M;\n cin >> N >> M;\n\n auto fix = make_v<LL>(N);\n FOR(i, 0, M) {\n LL D, P;\n cin >> D >> P;\n P--;\n fix[P] = D;\n }\n\n auto v = make_v<LL>(N - M);\n FOR(i, 0, N - M) {\n cin >> v[i];\n }\n\n long long low = -1;\n long long high = 10000000100ll;\n while (high - low > 1) {\n long long middle = (low + high) / 2;\n if (ok(middle, fix, v)) {\n low = middle;\n }\n else {\n high = middle;\n }\n }\n print(low);\n\n return 0;\n}", "accuracy": 0.8235294117647058, "time_ms": 20, "memory_kb": 6432, "score_of_the_acc": -0.0117, "final_rank": 17 }, { "submission_id": "aoj_0617_3366937", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nll N;\nll M;\nll D[100005];\nll pos[100005];\nll d_max = -1;\nll d_min = LLONG_MAX;\n\nbool is_higher(ll val){\n\tqueue<ll> que;\n\n\tll cnt = 0;\n\tfor (int i = M;i < N;i++){\n\t\tif(D[i] >= val) cnt++;\n\t}\n\n\tfor (int i = (N/3)*3;i < N;i++){\n\t\tif(pos[i] == -1) que.push(1);\n\t\telse if(D[pos[i]] < val) que.push(INT_MAX/10);\n\t\telse que.push(0);\n\t}\n\n\tint itr;\n\tfor (itr = 0;itr < N;itr += 3 ){\n\t\tif(itr+2 >= N) break;\n\t\tll cnth = 0;\n\t\tll cntl = 0;\n\t\tfor (int j = 0;j < 3;j++){\n\t\t\tif(pos[itr+j] == -1) continue;\n\t\t\tll tmp = D[pos[itr+j]];\n\t\t\tif(tmp >= val) cnth++;\n\t\t\telse cntl++;\n\t\t}\n\t\tif(cntl+cnth == 0) que.push(2);\n\t\telse if(cntl+cnth == 1){\n\t\t\tif(cntl == 1) que.push(2);\n\t\t\telse que.push(1);\n\t\t}\n\t\telse if(cntl+cnth == 2){\n\t\t\tif(cntl == 2) que.push(INT_MAX/10);\n\t\t\telse if(cnth == 2) que.push(0);\n\t\t\telse que.push(1);\n\t\t}\n\t\telse {\n\t\t\tif(cntl == 2 || cntl == 3) que.push(INT_MAX/10);\n\t\t\telse que.push(0);\n\t\t}\n\n\t}\n\n\twhile(que.size() != 1){\n\t\tll tr[3];\n\t\tfor (int i = 0;i < 3;i++){\n\t\t\ttr[i] = que.front(); que.pop();\n\t\t}\n\t\tque.push(min(tr[0]+tr[1],min(tr[1]+tr[2],tr[2]+tr[0])));\n\t}\n\t\n\treturn (que.front() <= cnt);\n\n}\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tcin >> N >> M;\n\n\tmemset(pos, -1, sizeof(pos));\n\n\tfor (int i = 0;i < M;i++){\n\t\tint tmp;\n\t\tcin >> D[i] >> tmp;\n\t\ttmp--;\n\t\tpos[tmp] = i;\n\t\td_max = max(d_max, D[i]);\n\t\td_min = min(d_min, D[i]);\n\t}\n\n\tfor (int i = M;i < N;i++){\n\t\tcin >> D[i];\t\n\t\td_max = max(d_max, D[i]);\n\t\td_min = min(d_min, D[i]);\n\t}\n\n\t// [low, high)\n\tll low = d_min;\n\tll high = d_max+1;\n\n\twhile(high-low > 1){\n\t\tll mid = (low+high)/2;\n\t\tif(is_higher(mid)) low = mid;\n\t\telse high = mid;\n\t}\n\n\tcout << low << endl;\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4904, "score_of_the_acc": -0.022, "final_rank": 4 }, { "submission_id": "aoj_0617_3074199", "code_snippet": "//1:23\n#include<iostream>\n#include<algorithm>\n#include<queue>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\n#define N 100010\n#define T 150010\nll n,m,a[N],b[N],last;\nvector<ll> g[T];\nll dfs(int x,ll lim){\n if(x<n){\n\tif(a[x]==0)return 1;\n\tif(a[x]>=lim)return 0;\n\treturn mod;\n }\n ll sum=0,maxi=0;\n for(auto y:g[x]){\n\tll t=dfs(y,lim);\n\tsum+=t,maxi=max(maxi,t);\n }\n return sum-maxi;\n}\nbool DP(ll lim){\n ll cnt=0;\n lol(i,n-m)if(b[i]>=lim)cnt++;\n return (cnt>=dfs(last-1,lim));\n}\nint main(){\n cin>>n>>m;\n lol(i,n)a[i]=0;\n lol(i,m){\n\tint x,y;\n\tcin>>x>>y;y--;\n\ta[y]=x;\n }\n lol(i,n-m)cin>>b[i];\n queue<int> Q;\n lol(i,n)Q.push(i);\n last=n;\n while(Q.size()>=3){\n\tlol(i,3){\n\t g[last].push_back(Q.front());\n\t Q.pop();\n\t}\n\tQ.push(last);\n\tlast++;\n }\n ll l=0,r=mod,mid;\n while(l<r-1){\n\tmid=(l+r)/2;\n\tif(DP(mid))l=mid;\n\telse r=mid;\n }\n cout<<l<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 10588, "score_of_the_acc": -0.1017, "final_rank": 9 }, { "submission_id": "aoj_0617_2850016", "code_snippet": "#include <stdio.h>\n#include <cmath>\n#include <algorithm>\n#include <cfloat>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <string>\n#include <iostream>\n#include <set>\n#include <map>\n#include <time.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 500000\n\nenum Type{\n\tHIGH,\n\tLOW,\n\tUNDEFINED,\n};\n\nstruct Info{\n\tint value,loc;\n};\n\nstruct Data{\n\tType type;\n\tint need_num;\n};\n\nint N,M,length,root;\nint base[100000];\nint parent[NUM];\nInfo info[100000];\nData data[NUM];\n\nbool is_OK(int base_value){\n\n\tint count = 0;\n\tfor(int i = 0; i < N; i++){\n\t\tif(info[i].loc == -1 && info[i].value >= base_value)count++;\n\t}\n\n\tfor(int i = 0; i < length; i++){\n\t\tdata[i].type = UNDEFINED;\n\t\tdata[i].need_num = 1;\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(base[i] != -1){\n\t\t\tif(base[i] >= base_value){\n\t\t\t\tdata[i].type = HIGH;\n\t\t\t}else{\n\t\t\t\tdata[i].type = LOW;\n\t\t\t}\n\t\t}\n\t}\n\n\tint loc[3] = {0,1,2};\n\tint num_HIGH,num_LOW,add;\n\tint work[3],sum;\n\n\twhile(true){\n\n\t\tnum_HIGH = 0,num_LOW = 0;\n\n\t\tfor(int i = 0; i < 3; i++){\n\t\t\tif(data[loc[i]].type == HIGH){\n\t\t\t\tnum_HIGH++;\n\t\t\t}else if(data[loc[i]].type == LOW){\n\t\t\t\tnum_LOW++;\n\t\t\t}\n\t\t}\n\n\t\tif(num_HIGH >=2){\n\n\t\t\tdata[parent[loc[0]]].type = HIGH;\n\t\t\tdata[parent[loc[0]]].need_num = 0;\n\n\t\t}else if(num_LOW >= 2){\n\n\t\t\tdata[parent[loc[0]]].type = LOW;\n\t\t\tdata[parent[loc[0]]].need_num = 0;\n\n\t\t}else{\n\t\t\tadd = 2-num_HIGH;\n\n\t\t\tfor(int i = 0; i < 3; i++)work[i] = BIG_NUM;\n\n\t\t\tfor(int i = 0; i < 3; i++){\n\t\t\t\tif(data[loc[i]].type == UNDEFINED){\n\t\t\t\t\twork[i] = data[loc[i]].need_num;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tsort(work,work+3);\n\n\t\t\tsum = 0;\n\t\t\tfor(int i = 0; i < add; i++)sum += work[i];\n\n\t\t\tdata[parent[loc[0]]].need_num = sum;\n\t\t}\n\n\t\tif(parent[loc[0]] == root)break;\n\n\t\tfor(int i = 0; i < 3; i++){\n\t\t\tloc[i] += 3;\n\t\t}\n\t}\n\n\tif(data[root].type == HIGH)return true;\n\tif(data[root].type == LOW)return false;\n\n\treturn count >= data[root].need_num;\n}\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tfor(int i = 0; i < N; i++){\n\t\tbase[i] = -1;\n\t\tinfo[i].loc = -1;\n\t}\n\n\tint maximum = 0,minimum = BIG_NUM;\n\n\tfor(int i = 0; i < M; i++){\n\t\tscanf(\"%d %d\",&info[i].value,&info[i].loc);\n\t\tinfo[i].loc--;\n\t\tbase[info[i].loc] = info[i].value;\n\t\tmaximum = max(maximum,info[i].value);\n\t\tminimum = min(minimum,info[i].value);\n\t}\n\n\tfor(int i = 0; i < N-M; i++){\n\t\tscanf(\"%d\",&info[M+i].value);\n\t\tmaximum = max(maximum,info[M+i].value);\n\t\tminimum = min(minimum,info[M+i].value);\n\t}\n\n\tfor(int i = 0; i < NUM; i++){\n\t\tparent[i] = -1;\n\t}\n\n\tint index = N;\n\tqueue<int> Q;\n\tfor(int i = 0; i < N; i++){\n\t\tQ.push(i);\n\t}\n\n\tint A,B,C;\n\n\twhile(Q.size() != 1){\n\t\tA = Q.front();\n\t\tQ.pop();\n\t\tB = Q.front();\n\t\tQ.pop();\n\t\tC = Q.front();\n\t\tQ.pop();\n\n\t\tparent[A] = index;\n\t\tparent[B] = index;\n\t\tparent[C] = index;\n\n\t\tQ.push(index);\n\t\tindex++;\n\t}\n\n\tlength = index;\n\tindex--;\n\troot = index;\n\n\tint left = minimum,right = maximum,m = (left+right)/2;\n\tint ans = minimum;\n\n\twhile(left <= right){\n\t\tif(is_OK(m)){\n\t\t\tans = m;\n\t\t\tleft = m+1;\n\t\t}else{\n\t\t\tright = m-1;\n\t\t}\n\t\tm = (left+right)/2;\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7700, "score_of_the_acc": -0.0704, "final_rank": 8 }, { "submission_id": "aoj_0617_2686763", "code_snippet": "# include <iostream>\n# include <algorithm>\n# include <vector>\n# include <string>\n# include <set>\n# include <map>\n# include <cmath>\n# include <iomanip>\n# include <functional>\n# include <utility>\n# include <stack>\n# include <queue>\n# include <list>\n# include <tuple>\n# include <unordered_map>\n# include <numeric>\n# include <complex>\n# include <bitset>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\nconstexpr int INF = 2000000000;\nconstexpr int HINF = INF / 2;\nconstexpr double DINF = 100000000000000000.0;\nconstexpr long long LINF = 9223372036854775807;\nconstexpr long long HLINF = 4500000000000000000;\nconstexpr long long MMOD = 500000004;\nconst double PI = acos(-1);\nint dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };\n# define ALL(x) (x).begin(),(x).end()\n# define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n# define mp make_pair\n# define eb emplace_back\n# define FOR(i,a,b) for(int i=(a);i<(b);++i)\n# define REP(i,n) FOR(i,0,n)\n# define INIT std::ios::sync_with_stdio(false);std::cin.tie(0);\n\n\nint n, m;\nint member[101010];\nvector<int> other;\nint dp[202020];\n\nbool C(int mid){\n\n\tfor (int i = 0; i < 202020; i++)dp[i] = HINF;\n\n\tfor (int i = 0; i < n; i++) {\n\t\tdp[i] = (~member[i] ? (member[i] >= mid ? 0 : HINF) : 1);\n\t}\n\n\tint count = 0;\n\tfor (int i = 0;; i++) {\n\t\tdp[i + n] = min({ dp[i * 3] + dp[i * 3 + 1],dp[i * 3] + dp[i * 3 + 2],dp[i * 3 + 1] + dp[i * 3 + 2] });\n\t\tdp[i + n] = min(dp[i + n], HINF);\n\t\tcount = dp[i + n];\n\t\tif (i * 3 + 3 == i + n) break;\n\t}\n\n\tint count2 = 0;\n\n\tfor (int i = 0; i < other.size(); i++) {\n\t\tcount2 += other[i] >= mid;\n\t}\n\n\treturn (count <= count2);\n}\n\nint main(){\n\tcin >> n >> m;\n\t\n\tfor (int i = 0; i < 101010; i++)member[i] = -1;\n\n\tfor (int i = 0; i < m; i++) {\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tmember[--y] = x;\n\t}\n\n\tfor (int i = 0; i < n - m; i++) {\n\t\tint x;\n\t\tcin >> x;\n\t\tother.emplace_back(x);\n\t}\n\n\tint left = 1, right = 1000000000;\n\n\twhile (left != right) {\n\t\tint mid = (left + right + 1)>>1;\n\n\t\tif (C(mid)) left = mid;\n\t\telse right = mid - 1;\n\t}\n\n\tcout << left << endl;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4560, "score_of_the_acc": -0.0554, "final_rank": 7 }, { "submission_id": "aoj_0617_2665427", "code_snippet": "#include <bits/stdc++.h>\n#define INF 1e+10\n#define int long long\nusing namespace std;\n\nint n,m,a[100000];\nvector<int> nums;\n\nbool C(int x){\n\tqueue<int> que;\n\tfor(int i = 0;i < n;i++){\n\t\tif(!a[i]) que.push(1);\n\t\telse if(a[i] < x) que.push(INF);\n\t\telse que.push(0);\n\t}\n\tfor(int i = 0;i < (n - 1) / 2;i++){\n\t\tint b[3],ma = 0,sum = 0;\n\t\tfor(int j = 0;j < 3;j++){\n\t\t\tb[j] = que.front();\n\t\t\tque.pop();\n\t\t\tma = max(ma,b[j]);\n\t\t\tsum += b[j];\n\t\t}\n\t\tque.push(sum - ma);\n\t}\n\tint cnt = n - m - (lower_bound(nums.begin(),nums.end(),x) - nums.begin());\n\treturn que.front() <= cnt;\n}\n\nsigned main(){\n\tcin >> n >> m;\n\tfor(int i = 0;i < n;i++){\n\t\tif(i < m){\n\t\t\tint x,y;\n\t\t\tcin >> x >> y;\n\t\t\ta[y - 1] = x;\n\t\t}else{\n\t\t\tint x;\n\t\t\tcin >> x;\n\t\t\tnums.push_back(x);\n\t\t}\n\t}\n\tsort(nums.begin(),nums.end());\n\tint low = 0,up = INF;\n\twhile(up - low > 1){\n\t\tint mid = (low + up) / 2;\n\t\tif(C(mid)) low = mid;\n\t\telse up = mid;\n\t}\n\tfor(int i = 0;i <= 10;i++) C(i);\n\tcout << low << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 5124, "score_of_the_acc": -0.1283, "final_rank": 11 }, { "submission_id": "aoj_0617_2651340", "code_snippet": "#include <cstdio>\nint N, M, p, d, val[100009], a[100009], dp[150009];\nint main() {\n\tscanf(\"%d %d\", &N, &M);\n\tfor (int i = 0; i < M; i++) scanf(\"%d %d\", &d, &p), val[p - 1] = d;\n\tfor (int i = 0; i < N - M; i++) scanf(\"%d\", &a[i]);\n\tint l = 0, r = 1000000009;\n\twhile (r - l > 1) {\n\t\tint m = (l + r) >> 1; p = 1;\n\t\tfor (int i = 0; i < N - M; i++) {\n\t\t\tif (a[i] >= m) p++;\n\t\t}\n\t\tfor (int i = 0; i < N; i++) dp[i] = (val[i] ? (val[i] >= m ? 0 : p) : 1);\n\t\tfor (int i = 0; 2 * i < N; i++) {\n\t\t\td = dp[i + N] = 0;\n\t\t\tfor (int j = i * 3; j < i * 3 + 3; j++) dp[i + N] += dp[j], d = d > dp[j] ? d : dp[j];\n\t\t\tdp[i + N] -= d;\n\t\t}\n\t\tif (dp[N + (N >> 1) - 1] < p) l = m;\n\t\telse r = m;\n\t}\n\tprintf(\"%d\\n\", l);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3968, "score_of_the_acc": -0.0175, "final_rank": 3 }, { "submission_id": "aoj_0617_2542002", "code_snippet": "/*input\n15 1\n781314749 1\n312224898\n269509097\n255956030\n898895737\n228424650\n553611871\n905685626\n332572742\n398251511\n103523987\n310943411\n741678005\n214559293\n439294954\n*/\n#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <utility>\n#include <vector>\nusing namespace std;\n#define sp ' '\n#define endl '\\n'\n#define fi first\n#define se second\n#define mp make_pair\n#define int long long\n#define N 200005\n#define bit(x,y) ((x>>y)&1LL)\n#define show(x) cout << (#x) << \": \" << x << endl;\n#define ii pair<int,int>\nostream& operator << (ostream &os, vector<int>&x) {\n\tfor (int i = 0; i < x.size(); i++) os << x[i] << sp;\n\treturn os;\n}\nostream& operator << (ostream &os, pair<int, int> x) {\n\tcout << x.fi << sp << x.se << sp;\n\treturn os;\n}\nostream& operator << (ostream &os, vector<pair<int, int> >&x) {\n\tfor (int i = 0; i < x.size(); i++) os << x[i] << endl;\n\treturn os;\n}\n\nint n, m;\nint peak;\nvector<vector<int> > a(N);\nint root = 0;\nint cnt[2];\nvector<int> allval;\nint valPos[N];\nvector<vector<int> > dp;\nvoid addEdge(int x, int y) {\n\ta[x].push_back(y);\n}\n\nvoid createEdge(vector<int> cur) {\n\tif (cur.size() == 1) {\n\t\troot = cur.front();\n\t\treturn;\n\t}\n\tvector<int> nxt;\n\twhile (cur.size() % 3 != 0) {\n\t\tnxt.push_back(cur.back());\n\t\tcur.pop_back();\n\t}\n\treverse(cur.begin(), cur.end());\n\twhile (!cur.empty()) {\n\t\tnxt.push_back(++peak);\n\t\tfor (int i = 1; i <= 3; i++) {\n\t\t\taddEdge(peak, cur.back()); cur.pop_back();\n\t\t}\n\t}\n\tcreateEdge(nxt);\n}\n\nint cal(int u, int wh, const int lim) {\n\tint &ret = dp[u][wh];\n\tif (ret != -1) return ret;\n\tret = 1e18;\n\tif (u <= n) {\n\t\tif (valPos[u] == -1) return ret = wh;\n\t\tint x; if (valPos[u] < lim) x = 0; else x = 1;\n\t\tif (wh == x) return ret = wh;\n\t\telse return ret;\n\t}\n\telse {\n\t\tif (a[u].size() == 1)\n\t\t\treturn ret = cal(a[u].front(), wh, lim);\n\t\tfor (int mask = 0; mask < (1 << 3); mask++) {\n\t\t\tint num1 = __builtin_popcount(mask); int num0 = 3 - num1;\n\t\t\tif ((wh == 0 && num0 > num1) || (wh == 1 && num0 < num1)) {\n\t\t\t\tint sum = 0;\n\t\t\t\tfor (int i = 0; i < 3; i++)\n\t\t\t\t\tsum += cal(a[u][i], bit(mask, i), lim);\n\t\t\t\tret = min(ret, sum);\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n}\n\nbool check(int lim) {\n\tmemset(cnt, 0, sizeof(cnt));\n\tfor (auto u : allval) {\n\t\tif (u < lim) cnt[0]++;\n\t\telse cnt[1]++;\n\t}\n\tdp.assign(root + 5, vector<int>(2, -1));\n\tint rec = cal(root, 1, lim);\n\treturn rec <= cnt[1];\n}\n\nsigned main() {\n\tios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> n >> m; peak = n;\n\tvector<int> sta; for (int i = 1; i <= n; i++) sta.push_back(i);\n\tcreateEdge(sta); memset(valPos, -1, sizeof(valPos));\n\tfor (int i = 1; i <= m; i++) {\n\t\tint x, y; cin >> x >> y;\n\t\tvalPos[y] = x; allval.push_back(x);\n\t}\n\tfor (int i = 1; i <= n - m; i++) {\n\t\tint x; cin >> x; allval.push_back(x);\n\t}\n\tsort(allval.begin(), allval.end());\n\tint l = 0, r = allval.size() - 1;\n\twhile (l != r) {\n\t\tint mid = (l + r + 1) / 2;\n\t\tif (check(allval[mid])) l = mid;\n\t\telse r = mid - 1;\n\t}\n\tcout << allval[l] << endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 21148, "score_of_the_acc": -0.3273, "final_rank": 14 }, { "submission_id": "aoj_0617_2541971", "code_snippet": "#include<bits/stdc++.h>\nconst long long N = 2e5 + 5;\nconst long long inf = 1e9;\nusing namespace std;\n\nvector <long long> adj[N];\nlong long n, m, d[N], p[N], cnt = 1, c;\nlong long num[N], dp[N][2];\nlong long pos[N];\n\nvoid dfs(long long u, long long numm){\n num[u] = 0;\n for (long long i = 0; i < adj[u].size(); i++){\n long long v = adj[u][i];\n dfs(v, numm);\n num[u] += num[v];\n }\n if (adj[u].size() == 0){\n num[u] = 1;\n dp[u][0] = ((pos[u] && !(pos[u] < numm)) ? inf : 0); dp[u][1] = ((pos[u] && !(pos[u] >= numm)) ? inf : 1);\n }\n else{\n for (long long i = 0; i < 8; i++){\n bool x = (i & 1), y = (i&2), z = (i&4);\n if (__builtin_popcount(i) > 1) dp[u][1] = min(dp[u][1], dp[adj[u][0]][x] + dp[adj[u][1]][y] + dp[adj[u][2]][z]);\n else dp[u][0] = min(dp[u][0], dp[adj[u][0]][x] + dp[adj[u][1]][y] + dp[adj[u][2]][z]);\n }\n }\n if (dp[u][0] != inf && num[u] - dp[u][0] > cnt) dp[u][0] = num[u] - cnt;\n}\n\nbool check(long long num){\n cnt = 0;\n for (long long i = 1; i <= n; i++) if (d[i] < num) cnt++;\n for (int i = 1; i <= c; i++) dp[i][0] = inf, dp[i][1] = inf;\n dfs(c, num);\n return (dp[c][1] <= n-cnt);\n}\n\nlong long bsearch(){\n long long l = 0, r = 1e9;\n while (l != r){\n long long mid = (l + r + 1) / 2;\n if (check(mid)) l = mid;\n else r = mid-1;\n }\n return l;\n}\n\nint main(){\n ios_base::sync_with_stdio(false); cin .tie(0); cout.tie(0);\n cin >> n >> m;\n c = n+1;\n for (long long i = 1; i <= m; i++) {\n cin >> d[i] >> p[i];\n pos[p[i]] = d[i];\n }\n for (long long i = m+1; i <= n; i++) cin >> d[i];\n while (cnt+1 != c){\n adj[c].push_back(cnt); cnt++;\n adj[c].push_back(cnt); cnt++;\n adj[c].push_back(cnt); cnt++;\n c++;\n }\n c--;\n cout << bsearch() << \"\\n\";\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 15912, "score_of_the_acc": -0.2322, "final_rank": 12 }, { "submission_id": "aoj_0617_2541768", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 200005;\nconst long long inf = 1e9;\n\nvector <int> G[N];\nint n, m, d[N], a[N], b[N];\nlong long f[N][2];\nint cnt;\n\nint mex(int mask) {\n\tint r = 0; for (int i = 0; i < 3; ++i) if (mask & (1<<i)) ++r; return r >= 2;\n}\n\nvoid dfs(int u) {\n\tif (G[u].size() == 0) {\n\t\tif (b[u] == -1) f[u][0] = 0, f[u][1] = 1;\n\t\telse {\n\t\t\tif (b[u]) f[u][1] = 1, f[u][0] = inf;\n\t\t\telse f[u][0] = 0, f[u][1] = inf;\n\t\t}\n\t\treturn;\n\t}\n\tf[u][0] = f[u][1] = inf;\n\tfor (int v: G[u]) dfs(v);\n\tfor (int mask = 0; mask < 8; ++mask) {\n\t\tf[u][mex(mask)] = min(f[u][mex(mask)], f[G[u][0]][mask >> 0 & 1] + f[G[u][1]][mask >> 1 & 1] + f[G[u][2]][mask >> 2 & 1]);\n\t}\n}\n\nbool check(int x) {\n\tmemset(b, -1, sizeof b); int cnt1 = 0;\n\tfor (int i = 1; i <= n; ++i) if (a[i]) { b[i] = a[i] >= x; if (a[i] >= x) ++cnt1; }\n\tfor (int i = 1; i <= n - m; ++i) if (d[i] >= x) ++cnt1; \n\tdfs(cnt);\n\treturn f[cnt][1] <= cnt1;\n}\n\nint main() {\n\tios_base::sync_with_stdio(false); cin.tie(0);\n\tcin >> n >> m;\n\tfor (int i = 1; i <= m; ++i) { int p; cin >> d[i] >> p; a[p] = d[i]; }\n\tfor (int i = 1; i <= n - m; ++i) cin >> d[i];\n\n\tint cur = n; cnt = n;\n\tvector<int> nw, nxt;\n\tfor (int i = 1; i <= n; ++i) nw.push_back(i);\n\twhile(cur > 1) {\n\t\tfor (int i = 0; i < (int)nw.size(); i += 3) {\n\t\t\tif (i > (int)nw.size() - 3) continue;\n\t\t\t++cnt; G[cnt].push_back(nw[i]); G[cnt].push_back(nw[i + 1]); G[cnt].push_back(nw[i + 2]);\n\t\t\tnxt.push_back(cnt);\n\t\t}\n\t\treverse(nxt.begin(), nxt.end());\n\t\tfor (int i = (int)nw.size()-1; i >= 0; --i) {\n\t\t\tif (i % 3 == 2) break;\n \t\t\tnxt.push_back(nw[i]);\n\t\t}\n\t\treverse(nxt.begin(), nxt.end());\n\t\tnw = nxt;\n\t\tnxt.clear();\n\t\tcur = (int)nw.size();\n\t}\n\t\n\tint l = 0, r = 1e9;\n\twhile(l < r) {\n\t\tint mid = ((l + r + 1) >> 1);\n\t\tif (check(mid)) l = mid; else r = mid - 1;\n\t}\n\tcout << l << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 13552, "score_of_the_acc": -0.2561, "final_rank": 13 } ]
aoj_0616_cpp
JOI 公園 (JOI Park) 20XX 年に IOI 国で行われるオリンピックに備え,IOI 国にある JOI 公園を整備することになった.JOI公園には N 個の広場があり,広場には 1 から N の番号がついている.広場を繋ぐ M 本の道があり,道には 1 から M の番号がついている.道 i (1 ≤ i ≤ M ) は広場 A i と広場 B i を双方向に繋いでおり,長さは D i である.どの広場からどの広場へもいくつかの道を辿って行くことができる. 整備計画では,まず,0 以上の整数 X を選び,広場 1 からの距離が X 以下であるような広場 (広場 1 を含む) どうしをすべて相互に地下道で結ぶ.ただし,広場 i と広場 j の距離とは,広場 i から広場 j に行くときに通る道の長さの和の最小値である.整備計画では地下道の整備コストに関する整数 C が定まっている.地下道の整備にかかるコストは C × X である. 次に,地下道で結ばれた広場どうしを結ぶ道をすべて撤去する.道の撤去にコストはかからない.最後に,撤去されずに残った道をすべて補修する.長さ d の道を補修するためにかかるコストは d である.整備計画実施前の JOI 公園には地下道はない.JOI 公園の整備にかかるコストの和の最小値を求めよ. 課題 JOI 公園の広場の情報と,地下道の整備コストに関する整数が与えられたとき,JOI 公園の整備にかかる コストの和の最小値を求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 N , M , C が空白を区切りとして書かれている.これは,広場が N 個,道が M 本あり,地下道の整備コストに関する整数が C であることを表す. 続く M 行のうちの i 行目 (1 ≤ i ≤ M ) には,整数 A i , B i , D i が空白を区切りとして書かれている.これは,道 i が広場 A i と広場 B i を繋ぎ,長さが D i であることを表す. 出力 標準出力に,JOI 公園の整備にかかるコストの和の最小値を表す整数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 2 ≤ N ≤ 100 000. 1 ≤ M ≤ 200 000. 1 ≤ C ≤ 100 000. 1 ≤ A i ≤ N (1 ≤ i ≤ M ). 1 ≤ B i ≤ N (1 ≤ i ≤ M ). A i ≠ B i (1 ≤ i ≤ M ). ( A i , B i ) ≠ ( A j , B j ) および ( A i , B i ) ≠ ( B j , A j ) (1 ≤ i < j ≤ M ). 1 ≤ D i ≤ 100 000 (1 ≤ i ≤ M ). 与えられる入力データにおいては,どの広場からどの広場へもいくつかの道を辿ることにより行けることが保証されている. 入出力例 入力例 1 5 5 2 2 3 1 3 1 2 2 4 3 1 2 4 2 5 5 出力例 1 14 この入力例では, X = 3 として,広場 1 からの距離が 3 以下であるような広場 (広場 1, 広場 2, 広場 3) どうしをすべて相互に地下道で結んだとき,整備にかかるコストの和は 2 × 3 + 3 + 5 = 14 となる.これが最小値である. 入力例 2 5 4 10 1 2 3 2 3 4 3 4 3 4 5 5 出力例 2 15 この入力例では,X = 0 のとき整備にかかるコストの和が最小になる. 入力例 3 6 5 2 1 2 2 1 3 4 1 4 3 1 5 1 1 6 5 出力例 3 10 この入力例では, X = 5 としてすべての広場を相互に地下道で結んだとき,整備にかかるコストの和が最小になる. 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0616_10851272", "code_snippet": "#include<iostream>\n#include<queue>\n#include<functional>\n#include<algorithm>\n#include<map>\nusing namespace std;\nmap<long long, long long>H;\nvector<pair<long long, long long>>x[300000]; long long dist[300000];\nlong long n, m, a[300000], b[300000], c[300000], D;\npriority_queue<pair<long long, long long>, vector<pair<long long, long long>>, greater<pair<long long, long long>>>Q;\nvoid dijkstra() {\n\tfor (long long i = 0; i < 300000; i++)dist[i] = 999999999999999999LL;\n\tdist[1] = 0; Q.push(make_pair(0, 1));\n\twhile (!Q.empty()) {\n\t\tlong long a1 = Q.top().first, a2 = Q.top().second; Q.pop();\n\t\tfor (long long i = 0; i < x[a2].size(); i++) {\n\t\t\tif (dist[x[a2][i].first] > dist[a2] + x[a2][i].second) {\n\t\t\t\tdist[x[a2][i].first] = dist[a2] + x[a2][i].second;\n\t\t\t\tQ.push(make_pair(dist[x[a2][i].first], x[a2][i].first));\n\t\t\t}\n\t\t}\n\t}\n}\nint main() {\n\tcin >> n >> m >> D; for (long long i = 0; i < m; i++) { cin >> a[i] >> b[i] >> c[i]; x[a[i]].push_back(make_pair(b[i], c[i])); x[b[i]].push_back(make_pair(a[i], c[i])); }\n\tdijkstra();\n\tlong long minx = 99999999999999999LL, sum2 = 0;\n\tfor (long long i = 0; i < m; i++)H[max(dist[a[i]], dist[b[i]])] += c[i];\n\tsort(dist + 1, dist + n + 1); long long maxn = dist[n];\n\tfor (long long i = 0; i < m; i++)sum2 += c[i];\n\n\tfor (long long j = 1; j <= n; j++) {\n\t\tif (dist[j - 1] == dist[j])continue;\n\t\tlong long i = dist[j];\n\t\tsum2 -= H[i];\n\t\tminx = min(minx, i*D + sum2);\n\t}\n\tcout << minx << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 34572, "score_of_the_acc": -0.845, "final_rank": 14 }, { "submission_id": "aoj_0616_10413354", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <queue>\n#include <map>\n#include <set>\n#include <vector>\nusing namespace std;\n\nstruct E{\n\tlong long int len,cost,oldLen;\n\tint from,to;\n\t\n\tbool operator<(const E& e1)const{\n\t\tif(len!=e1.len)return len>e1.len;\n\t\treturn cost>e1.cost;\n\t}\n};\n\nstruct E2{\n\tint from,to;\n\tbool operator<(const E2& e2)const{\n\t\tif(from!=e2.from)return from<e2.from;\n\t\treturn to<e2.to;\n\t}\n};\n\nlong long int lens[100003];\nmap<long long int,long long int> memo,memo2;\nset<E2> cons2;\nbool flag[100003];\nmap<int,vector<E> > cons;\npriority_queue<E> pq;\n\n\nint main() {\n\t// your code goes here\n\tint n,m;\n\tlong long int c1,allSum;\n\tcin>>n>>m>>c1;\n\tallSum=0;\n\tfor(int i=0;i<m;i++){\n\t\tE e;\n\t\tint from;\n\t\tlong long int to,len;\n\t\tcin>>from>>to>>len;\n\t\te.to=to;\n\t\te.len=len;\n\t\te.cost=e.len;\n\t\tcons[from].push_back(e);\n\t\te.to=from;\n\t\tcons[to].push_back(e);\n\t\tallSum+=len;\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tlens[i]=-1;\n\t}\n\tlens[0]=0;\n\tE e1;\n\te1.from=0;\n\te1.to=1;\n\te1.len=0;\n\te1.oldLen=0;\n\te1.cost=0;\n\tpq.push(e1);\n\twhile(pq.size()>0){\n\t\tE e1=pq.top();\n\t\tpq.pop();\n\t\tif(lens[e1.to]==-1){\n\t\t\tlens[e1.to]=e1.len;\n\t\t\tmemo[e1.len]+=e1.cost;\n\t\t\tmemo2[e1.len]+=e1.cost;\n\t\t}else if(e1.oldLen<=lens[e1.to]){\n\t\t\tE2 e2;\n\t\t\te2.from=e1.from;\n\t\t\te2.to=e1.to;\n\t\t\tif(cons2.find(e2)!=cons2.end())continue;\n\t\t\te2.from=e1.to;\n\t\t\te2.to=e1.from;\n\t\t\tcons2.insert(e2);\n\t\t\tmemo2[lens[e1.to]]+=e1.cost;\n\t\t\t\n\t\t\tcontinue;\n\t\t}else{\n\t\t\tcontinue;\n\t\t}\n\t\t\n\t\tfor(auto it=cons[e1.to].begin();it!=cons[e1.to].end();it++){\n\t\t\tE e2=(*it);\n\t\t\tE e1a;\n\t\t\te1a.from=e1.to;\n\t\t\te1a.to=e2.to;\n\t\t\te1a.oldLen=e1.len;\n\t\t\te1a.len=e1.len+e2.cost;\n\t\t\te1a.cost=e2.cost;\n\t\t\tpq.push(e1a);\n\t\t}\n\t}\n\tlong long int ans=allSum;\n\tlong long int lenSum=0;\n\tfor(auto it=memo.begin();it!=memo.end();it++){\n\t\t//cout<<(*it).first<<\" \"<<(*it).second<<endl;\n\t\tlenSum=(*it).first;\n\t\tallSum-=memo2[(*it).first];\n\t\tlong long int s0=lenSum*c1+allSum;\n\t\tif(s0<ans)ans=s0;\n\t\t//cout<<\"(\"<<s0<<\" \"<<lenSum<<\" \"<<allSum<<\")\";\n\t\t//cout<<(*it).first<<\" \"<<(*it).second<<endl;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 480, "memory_kb": 49952, "score_of_the_acc": -2, "final_rank": 17 }, { "submission_id": "aoj_0616_9571499", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n int N, M, C;\n std::cin >> N >> M >> C;\n std::vector<std::vector<std::tuple<int, int, int>>> g(N);\n for (int i{} ; i < M ; i++) {\n int u, v, w;\n std::cin >> u >> v >> w;\n u--; v--;\n g[u].push_back(std::tuple{ v, w, i });\n g[v].push_back(std::tuple{ u, w, i });\n }\n std::vector<long long> dist(N, (long long)2e18);\n dist[0] = 0;\n using qt = std::pair<long long, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n que.push(std::make_pair(dist[0], 0));\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (dist[v] < d) continue;\n for (auto [x, w, _] : g[v]) if (dist[x] > dist[v] + w) {\n dist[x] = dist[v] + w;\n que.push(std::make_pair(dist[x], x));\n }\n }\n std::vector<int> ord(N);\n std::iota(ord.begin(), ord.end(), 0);\n std::sort(ord.begin(), ord.end(), [&](int i, int j) -> bool { return dist[i] < dist[j]; });\n long long ans{(long long)2e18};\n long long sum{};\n std::vector<bool> used(M);\n for (int i{N} ; i >= 0 ; i--) {\n long long need{i ? dist[ord[i - 1]] : 0LL};\n ans = std::min(ans, (long long)C * need + sum);\n // std::cout << need << ' ' << sum << std::endl;\n if (i) {\n for (auto [_, w, j] : g[ord[i - 1]]) if (!used[j]) {\n used[j] = true;\n sum += w;\n }\n }\n }\n std::cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 15580, "score_of_the_acc": -0.0539, "final_rank": 1 }, { "submission_id": "aoj_0616_9480149", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\nstruct edge {\n int to, cost; // 'to'は接続先の頂点、'cost'はエッジのコストを表します。\n};\n\nconst int INF = 1 << 30; // 無限大の代わりに大きな値を設定します。\nint n, d[100001]; // 'n'は頂点の数、'd'は各頂点までの最短距離を保持します。\nvector<edge> g[100001]; // グラフを隣接リストとして保持します。\n\nvoid dijkstra() {\n // 優先度付きキューを使用して、最小のコストで処理する頂点を管理します。\n priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> q;\n \n fill(d + 1, d + n + 1, INF); // 各頂点までの距離を無限大に初期化します。\n d[1] = 0; // 始点の距離は0です。\n q.push(pair<int, int>(0, 1)); // 始点をキューに追加します。\n \n while (!q.empty()) {\n pair<int, int> p = q.top();\n q.pop();\n int v = p.second;\n \n // 現在の距離が更新済みの距離より大きければスキップします。\n if (d[v] < p.first) {\n continue;\n }\n \n // 隣接する全ての頂点に対して距離を更新します。\n for (const edge &e : g[v]) {\n if (d[e.to] > d[v] + e.cost) {\n d[e.to] = d[v] + e.cost;\n q.push(pair<int, int>(d[e.to], e.to));\n }\n }\n }\n}\n\nint main() {\n int m, c;\n long long S = 0;\n cin >> n >> m >> c;\n \n // グラフのエッジ情報を読み込みます。\n for (int i = 0; i < m; ++i) {\n int j, k, l;\n cin >> j >> k >> l;\n g[j].emplace_back(edge{k, l});\n g[k].emplace_back(edge{j, l});\n S += l;\n }\n \n // ダイクストラアルゴリズムを実行します。\n dijkstra();\n \n // 各頂点の最短距離を保持するペアのベクターを作成し、ソートします。\n vector<pair<int, int>> v;\n for (int i = 1; i <= n; ++i) {\n v.emplace_back(d[i], i);\n }\n sort(v.begin(), v.end());\n \n long long x = S;\n long long dS = 0;\n \n // 各頂点に対して、最短距離に基づいて計算します。\n for (int i = 1; i < n; ++i) {\n int a = v[i].second;\n for (const edge &e : g[a]) {\n int b = e.to;\n if (d[b] < d[a]) {\n S -= e.cost;\n } else if (d[b] == d[a]) {\n dS += e.cost;\n }\n }\n if (i == n - 1 || d[a] < v[i + 1].first) {\n S -= (dS / 2);\n dS = 0;\n x = min(x, S + static_cast<long long>(c) * d[a]);\n }\n }\n \n // 最小のコストを出力します。\n cout << x << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 13620, "score_of_the_acc": -0.1463, "final_rank": 2 }, { "submission_id": "aoj_0616_8534556", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nint main() {\n ll N,M,C;\n cin>>N>>M>>C;\n vector<vector<pair<ll,ll>>> G(N);\n ll LEN=0;\n for(int i=0;i<M;i++){\n ll A,B,D;\n cin>>A>>B>>D;\n A--;B--;\n LEN+=D;\n G[A].push_back({B,D});\n G[B].push_back({A,D});\n }\n vector<ll> dist(N,1e18);\n dist[0]=0;\n priority_queue<pair<ll,ll>,vector<pair<ll,ll>>,greater<pair<ll,ll>>> Q;\n vector<bool> seen(N,0);\n Q.push({0,0});\n while(!Q.empty()){\n auto nc=Q.top();\n Q.pop();\n ll n=nc.second;\n ll c=nc.first;\n if(seen[n])continue;\n seen[n]=1;\n for(auto vw:G[n]){\n ll v=vw.first;\n ll w=vw.second;\n if(seen[v])continue;\n if(dist[v]<=c+w)continue;\n dist[v]=c+w;\n Q.push({c+w,v});\n }\n }\n vector<pair<ll,ll>> P(N);\n for(int i=0;i<N;i++){\n P[i]={dist[i],i};\n }\n ll an=1e18;\n set<ll> S;\n sort(P.begin(),P.end());\n for(int i=0;i<N;i++){\n ll n=P[i].second;\n for(auto vw:G[n]){\n ll v=vw.first;\n ll w=vw.second;\n if(S.count(v)){\n LEN-=w;\n }\n }\n S.insert(n);\n if(i==N-1||P[i].first!=P[i+1].first){\n an=min(an,LEN+P[i].first*C);\n }\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 23108, "score_of_the_acc": -0.6514, "final_rank": 13 }, { "submission_id": "aoj_0616_8496199", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\n\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n ll a,b,c;\n cin>>a>>b>>c;\n\n ll s=0;\n\n vector<pll> adj[a+1];\n for (int i=0; i<b; i++) {\n ll x,y,z;\n cin>>x>>y>>z;\n adj[x].push_back({y,z});\n adj[y].push_back({x,z});\n s+=z;\n }\n\n priority_queue<pll> pq;\n vector<pll> vi(a+1,{1e18,0});\n bool g[a+1];\n memset(g,0,sizeof(g));\n vi[1]={0,0};\n pq.push({0,1});\n\n while(!pq.empty()){\n ll cost=-pq.top().first,idx=pq.top().second;\n pq.pop();\n\n if(vi[idx].first<cost) continue;\n g[idx]=true;\n\n for(pll u:adj[idx]){\n if(!g[u.first]) vi[u.first].second+=u.second;\n if(vi[u.first].first>cost+u.second){\n vi[u.first].first=cost+u.second;\n pq.push({-vi[u.first].first,u.first});\n }\n }\n }\n\n sort(vi.begin(), vi.end());\n ll ans=1e18,v=0;\n for(pll u:vi){\n if(u.first==1e18) break;\n v+=u.second;\n ans=min(ans,s-v+c*u.first);\n }\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 18468, "score_of_the_acc": -0.1578, "final_rank": 3 }, { "submission_id": "aoj_0616_7176443", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i32 = int;\nusing i64 = long long;\nconst i64 sup = (1LL << 60);\n\nint main() {\n i32 n, m, c; cin >> n >> m >> c;\n vector G(n, vector(0, pair(0, 0LL)));\n map<pair<i32, i32>, i64> mp;\n for (i32 _ = 0 ; _ < m ; _++) {\n i32 a, b, d; cin >> a >> b >> d;\n G[a - 1].emplace_back(b - 1, d);\n G[b - 1].emplace_back(a - 1, d);\n mp[pair(min(a - 1, b - 1), max(a - 1, b - 1))] = d;\n }\n vector dist = [&]() {\n vector ds(n, sup);\n ds[0] = 0LL;\n priority_queue<pair<i64, i32>, vector<pair<i64, i32>>, greater<pair<i64, i32>>> que;\n que.emplace(0LL, 0);\n while (que.size()) {\n auto [d, v] = que.top();\n que.pop();\n if (d > ds[v]) {\n continue;\n }\n for (auto [x, w] : G[v]) {\n if (ds[x] > d + w) {\n ds[x] = d + w;\n que.emplace(d + w, x);\n }\n }\n }\n map<i64, vector<i32>> mp;\n for (i32 i = 0 ; i < n ; i++) {\n mp[ds[i]].push_back(i);\n }\n vector res(0, pair(0, vector(0, 0)));\n for (auto [val, arr] : mp) {\n res.emplace_back(val, arr);\n }\n reverse(res.begin(), res.end());\n return res;\n }();\n i64 ans = sup;\n i64 sum = 0LL;\n for (i32 i = 0 ; i < (i32)dist.size() ; i++) {\n ans = min(ans, dist[i].first * (i64)c + sum);\n for (auto v : dist[i].second) {\n for (auto [x, _] : G[v]) {\n auto p = pair(min(x, v), max(x, v));\n if (mp.count(p)) {\n sum += mp[p];\n mp.erase(p);\n }\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 0.7796610169491526, "time_ms": 360, "memory_kb": 43464, "score_of_the_acc": -1.5287, "final_rank": 18 }, { "submission_id": "aoj_0616_6291388", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e17;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\ntemplate<typename T = ll>\nstruct Edge {\n ll from, to; T cost;\n Edge (ll from, ll to, T cost = 1) : from(from), to(to), cost(cost) {}\n};\ntemplate<typename T = ll>\nstruct Graph {\n vector<vector<Edge<T>>> G;\n Graph() = default;\n explicit Graph(ll N) : G(N) {}\n size_t size() const {\n return G.size();\n }\n void add_edge(ll from, ll to, T cost = 1, bool direct = false) {\n G[from].emplace_back(from, to, cost);\n if (!direct) G[to].emplace_back(to, from, cost);\n }\n void read(ll M, ll padding = -1, bool weight = false, bool direct = false) {\n for (ll i = 0; i < M; i++) {\n ll a, b; cin >> a >> b;\n a += padding;\n b += padding;\n T c = T(1);\n if (weight) cin >> c;\n add_edge(a, b, c, direct);\n }\n }\n vector<Edge<T>> &operator[](const int &k) {\n return G[k];\n }\n};\nvoid dijkstra(const Graph<long long>& G, int s, vector<long long>& dis) {\n int N = G.size();\n dis.resize(N, INF);\n priority_queue<P, vector<P>, greater<P>> pq;\n dis[s] = 0;\n pq.emplace(dis[s], s);\n while (!pq.empty()) {\n P p = pq.top();\n pq.pop();\n int v = p.second;\n if (dis[v] < p.first) {\n continue;\n }\n for (auto& e : G.G[v]) {\n if (dis[e.to] > dis[v] + e.cost) {\n dis[e.to] = dis[v] + e.cost;\n pq.emplace(dis[e.to], e.to);\n }\n }\n }\n}\nvoid solve() {\n ll N, M, C; cin >> N >> M >> C;\n Graph<ll>G(N);\n vector<P>e(M);\n vector<ll>w(M);\n for (ll i = 0; i < M; i++) {\n ll u, v, c; cin >> u >> v >> c;\n u--; v--;\n G.add_edge(u, v, c, false);\n e[i] = {u, v};\n w[i] = c;\n }\n vector<ll>dist(N, INF);\n dijkstra(G, 0, dist);\n vector<ll>D;\n for (ll i = 0; i < dist.size(); i++) {\n D.push_back(dist[i]);\n }\n sort(D.begin(), D.end());\n vector<ll>A;\n A.push_back(D[0]);\n for (ll i = 1; i < D.size(); i++) {\n if (D[i] != D[i - 1]) A.push_back(D[i]);\n }\n vector<ll>sum(A.size(), 0);\n for (ll i = 0; i < M; i++) {\n ll pos = lower_bound(A.begin(), A.end(), max(dist[e[i].first], dist[e[i].second])) - A.begin();\n sum[pos] += w[i];\n }\n ll ans = INF;\n ll num = 0;\n for (ll i = sum.size() - 1; i >= 0; i--) {\n ans = min(ans, C * A[i] + num);\n num += sum[i];\n }\n ans = min(ans, num);\n cout << ans << endl;\n}\nint main() {\n ll T=1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 27728, "score_of_the_acc": -0.6078, "final_rank": 12 }, { "submission_id": "aoj_0616_6109709", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,c);\n vector<vector<pair<int,int>>> g(n);\n int u,v;\n ll w,sumv=0;\n rep(i,m){\n in(u,v,w);\n sumv+=w;\n g[--u].emplace_back(--v,w);\n\t g[v].emplace_back(u,w);\n }\n vector<ll> dist(n,INF2);\n priority_queue<pair<ll,int>,vector<pair<ll,int>>,greater<pair<ll,int>>> pq;\n dist[0]=0;\n pq.push({0,0});\n while(!pq.empty()){\n tie(w,v)=pq.top();\n pq.pop();\n for(auto p:g[v]){\n if(w+p.second>=dist[p.first])continue;\n dist[p.first]=w+p.second;\n pq.push({dist[p.first],p.first});\n }\n }\n auto dist2=dist;\n sort(all(dist2));\n dist2.erase(unique(all(dist2)),dist2.end());\n vector<vector<int>> t(dist2.size());\n ll ans=INF2,cnt=0;\n vector<bool> used(n,false);\n for(int i=0;i<n;i++){\n\t dist[i]=lower_bound(all(dist2),dist[i])-dist2.begin();\n\t t[dist[i]].push_back(i);\n }\n chmin(ans,sumv);\n for(int i=0;i<t.size();i++){\n\t for(auto v:t[i]){\n\t\t cnt++;\n used[v]=true;\n\t for(auto p:g[v]){\n\t\t if(used[p.first])sumv-=p.second;\n\t }\n }\n chmin(ans,c*dist2[i]+sumv);\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 17696, "score_of_the_acc": -0.161, "final_rank": 4 }, { "submission_id": "aoj_0616_5960593", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing Int = long long;\nconstexpr Int inf = 1e18;\nclass unionfind {\n vector<int> par, rank, size_;\npublic:\n unionfind(int n) :par(n), rank(n), size_(n, 1) {\n iota(par.begin(),par.end(), 0);\n }\n int find(int x) {\n if (par[x] == x)return x;\n return par[x] = find(par[x]);\n }\n void unite(int x, int y) {\n x = find(x), y = find(y);\n if (x == y)return;\n if (rank[x] < rank[y])swap(x, y);\n par[y] = x;\n size_[x] += size_[y];\n if (rank[x] == rank[y])rank[x]++;\n }\n bool same(int x, int y) {\n return find(x) == find(y);\n }\n int size(int x) {\n return size_[find(x)];\n }\n};\n\nint main(){\n Int N,M,C; \n cin >> N >> M >> C;\n vector<vector<pair<Int,Int>>>edge(N);\n vector<tuple<int,int,int>> input;\n auto uf = unionfind(N + 1);\n int root = N;\n Int ans = inf;\n Int sum = 0;\n for(int i = 0; i < M; ++i) {\n int s,t,c; cin >> s >> t >> c;\n --s; --t;\n edge[s].emplace_back(t,c);\n edge[t].emplace_back(s,c);\n input.emplace_back(s,t,c);\n sum += c;\n }\n ans = min(ans, sum);\n vector<Int>d(N,inf);\n d[0]= 0;\n \n priority_queue<pair<Int,Int>,vector<pair<Int,Int>>,greater<>> que;\n que.emplace(d[0], 0);\n int complete = 0;\n while(not que.empty()){\n auto [dist, cv] = que.top();\n que.pop();\n if(dist > d[cv]) continue;\n // d[cv] is the min disntace from d[0]\n uf.unite(root,cv);\n\n Int subCost = C * dist;\n for(auto [nv,cost] : edge[cv]){\n if(uf.same(nv,root)){\n sum -= cost;\n } else if (d[nv] > dist + cost) {\n d[nv] = dist + cost;\n que.emplace(d[nv],nv);\n }\n }\n ans = min(ans, sum + subCost);\n// cout << dist << \" \" << ans << endl;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 22532, "score_of_the_acc": -0.416, "final_rank": 11 }, { "submission_id": "aoj_0616_5947131", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-12, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\nclass UnionFind {\npublic:\n vector <ll> par; \n vector <ll> siz; \n \n vector <ll> maxv;\n UnionFind(ll sz_): par(sz_), siz(sz_, 1LL) {\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n void init(ll sz_) {\n par.resize(sz_);\n siz.assign(sz_, 1LL);\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n \n ll root(ll x) { \n while (par[x] != x) {\n x = par[x] = par[par[x]];\n }\n return x;\n }\n \n bool merge(ll x, ll y) {\n x = root(x);\n y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n \n bool issame(ll x, ll y) { \n return root(x) == root(y);\n }\n \n ll size(ll x) { \n return siz[root(x)];\n }\n};\n\nvector<vector<pair<int, int>>> g(101010);\nll d[101010];\nint main()\n{\n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n \n ll n, m, C; cin >> n >> m >> C;\n vector<int> a(m), b(m), c(m);\n REP(i,m) {\n \n cin >> a[i] >> b[i] >> c[i];\n a[i]--; b[i]--;\n g[a[i]].push_back({b[i], c[i]});\n g[b[i]].push_back({a[i], c[i]});\n \n }\n REP(i,n) d[i] = (1LL<<60);\n d[0] = 0;\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, 0});\n while(pq.size()) {\n auto[c, v] = pq.top(); pq.pop();\n if(d[v] < c) continue;\n for(auto[u, cost]: g[v]) {\n if(d[u] > d[v] + cost) {\n d[u] = d[v] + cost;\n pq.push({d[u], u});\n }\n }\n }\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> q;\n REP(i,n) {\n q.push({d[i], i});\n }\n vector<vector<int>> g(n);\n REP(i,m) {\n int u = a[i], v = b[i];\n if(d[u] > d[v]) {\n g[u].push_back(i);\n }else{\n g[v].push_back(i);\n }\n }\n ll ans = 1LL<<60;\n ll sum = 0;\n REP(i,m) sum += c[i];\n while(q.size()) {\n int idx = q.top().second;\n q.pop();\n for(auto j: g[idx]) {\n sum -= c[j];\n }\n ans = min(ans, d[idx]*C + sum);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 22188, "score_of_the_acc": -0.2846, "final_rank": 9 }, { "submission_id": "aoj_0616_5778222", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <queue>\n#include <functional>\n#include <iostream>\n#define INF 1e15\n\ntypedef long long ll;\ntypedef std::pair<ll, int> P;\nstruct Edge {\n\tint t, id;\n\tll d;\n\n\tEdge(int tt, int ii, ll dd) {\n\t\tt = tt;\n\t\tid = ii;\n\t\td = dd;\n\t}\n};\n\n#define min(x,y) (x)>(y)?(y):(x)\n\nint n, m, c;\nint a[200001], b[200001], d[200001];\nll cost[100001], x_max;\nstd::vector<Edge> G[100001];\nbool flag[200001];\nll costdata[100001];\nint index[100001], datasize;\n\nvoid dijk()\n{\n\tstd::priority_queue<P, std::vector<P>, std::greater<P> > que;\n\tque.push(P(0, 1));\n\tfor (int i = 1; i <= n; i++)cost[i] = INF;\n\tcost[1] = 0;\n\twhile (que.size()) {\n\t\tP q = que.top();\n\t\tque.pop();\n\t\tif (q.first != cost[q.second])continue;\n\t\tcostdata[datasize] = cost[q.second];\n\t\tindex[datasize++] = q.second;\n\t\t//x_max = max(x_max, q.first);\n\t\tfor (int i = 0; i < G[q.second].size(); i++) {\n\t\t\tEdge e = G[q.second][i];\n\t\t\tif (e.d + q.first < cost[e.t]) {\n\t\t\t\tcost[e.t] = e.d + q.first;\n\t\t\t\tque.push(P(cost[e.t], e.t));\n\t\t\t}\n\t\t}\n\t}\n\treturn;\n\n}\n\nint main()\n{\n\t\n\tscanf(\"%d %d %d\", &n, &m, &c);\n\tlong long res = INF;\n\tfor (int i = 0; i < m; i++) {\n\t\tscanf(\"%d %d %d\", &a[i], &b[i], &d[i]);\n\t\tG[a[i]].push_back(Edge(b[i], i, d[i]));\n\t\tG[b[i]].push_back(Edge(a[i], i, d[i]));\n\t}\n\tdijk();\n\tlong long alldist = 0;\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tres = min(res, costdata[i] * c + alldist);\n\t\tfor (int j = 0; j < G[index[i]].size(); j++) {\n\t\t\tEdge e = G[index[i]][j];\n\t\t\tif (!flag[e.id]) {\n\t\t\t\tflag[e.id] = true;\n\t\t\t\talldist += e.d;\n\t\t\t}\n\t\t}\n\t}\n\tres = min(res, alldist);\n\tprintf(\"%lld\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 20896, "score_of_the_acc": -0.2734, "final_rank": 6 }, { "submission_id": "aoj_0616_5778214", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <queue>\n#include <functional>\n#include <iostream>\n#define INF 1e15\n\ntypedef long long ll;\ntypedef std::pair<ll, int> P;\nstruct Edge {\n\tint t, id;\n\tll d;\n\n\tEdge(int tt, int ii, ll dd) {\n\t\tt = tt;\n\t\tid = ii;\n\t\td = dd;\n\t}\n};\n\nint n, m, c;\nint a[200001], b[200001], d[200001];\nll cost[100001], x_max;\nstd::vector<Edge> G[100001];\nbool flag[200001];\nll costdata[100001];\nint index[100001], datasize;\n\nvoid dijk()\n{\n\tstd::priority_queue<P, std::vector<P>, std::greater<P> > que;\n\tque.push(P(0, 1));\n\tfor (int i = 1; i <= n; i++)cost[i] = INF;\n\tcost[1] = 0;\n\twhile (que.size()) {\n\t\tP q = que.top();\n\t\tque.pop();\n\t\tif (q.first != cost[q.second])continue;\n\t\tcostdata[datasize] = cost[q.second];\n\t\tindex[datasize++] = q.second;\n\t\t//x_max = max(x_max, q.first);\n\t\tfor (int i = 0; i < G[q.second].size(); i++) {\n\t\t\tEdge e = G[q.second][i];\n\t\t\tif (e.d + q.first < cost[e.t]) {\n\t\t\t\tcost[e.t] = e.d + q.first;\n\t\t\t\tque.push(P(cost[e.t], e.t));\n\t\t\t}\n\t\t}\n\t}\n\treturn;\n\n}\n\nint main()\n{\n\t\n\tscanf(\"%d %d %d\", &n, &m, &c);\n\tlong long res = INF;\n\tfor (int i = 0; i < m; i++) {\n\t\tscanf(\"%d %d %d\", &a[i], &b[i], &d[i]);\n\t\tG[a[i]].push_back(Edge(b[i], i, d[i]));\n\t\tG[b[i]].push_back(Edge(a[i], i, d[i]));\n\t}\n\tdijk();\n\tlong long alldist = 0;\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tres = std::min(res, costdata[i] * c + alldist);\n\t\tfor (int j = 0; j < G[index[i]].size(); j++) {\n\t\t\tEdge e = G[index[i]][j];\n\t\t\tif (!flag[e.id]) {\n\t\t\t\tflag[e.id] = true;\n\t\t\t\talldist += e.d;\n\t\t\t}\n\t\t}\n\t}\n\tres = std::min(res, alldist);\n\tprintf(\"%lld\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 20900, "score_of_the_acc": -0.2735, "final_rank": 7 }, { "submission_id": "aoj_0616_5778207", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <queue>\n#include <functional>\n#define INF 1e15\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, int> P;\nstruct edge {\n\tint t, id;\n\tll d;\n\n\tedge(int tt, int ii, ll dd) {\n\t\tt = tt;\n\t\tid = ii;\n\t\td = dd;\n\t}\n};\n\nint n, m, c;\nint a[200001], b[200001], d[200001];\nll cost[100001], x_max;\nvector<edge> G[100001];\nbool flag[200001];\nll costdata[100001];\nint index[100001], datasize;\n\n\nvoid dijk() {\n\tpriority_queue<P, vector<P>, greater<P> > que;\n\tque.push(P(0, 1));\n\tfor (int i = 1; i <= n; i++)cost[i] = INF;\n\tcost[1] = 0;\n\twhile (que.size()) {\n\t\tP q = que.top();\n\t\tque.pop();\n\t\tif (q.first != cost[q.second])continue;\n\t\tcostdata[datasize] = cost[q.second];\n\t\tindex[datasize++] = q.second;\n\t\tx_max = max(x_max, q.first);\n\t\tfor (int i = 0; i < G[q.second].size(); i++) {\n\t\t\tedge e = G[q.second][i];\n\t\t\tif (e.d + q.first < cost[e.t]) {\n\t\t\t\tcost[e.t] = e.d + q.first;\n\t\t\t\tque.push(P(cost[e.t], e.t));\n\t\t\t}\n\t\t}\n\t}\n\treturn;\n}\n\nint main(void) {\n\tscanf(\"%d %d %d\", &n, &m, &c);\n\tll res = INF;\n\tfor (int i = 0; i < m; i++) {\n\t\tscanf(\"%d %d %d\", &a[i], &b[i], &d[i]);\n\t\tG[a[i]].push_back(edge(b[i], i, d[i]));\n\t\tG[b[i]].push_back(edge(a[i], i, d[i]));\n\t}\n\tdijk();\n\tll alldist = 0;\n\tfor (int i = n - 1; i >= 0; i--) {\n\t\tres = min(res, costdata[i] * c + alldist);\n\t\tfor (int j = 0; j < G[index[i]].size(); j++) {\n\t\t\tedge e = G[index[i]][j];\n\t\t\tif (!flag[e.id]) {\n\t\t\t\tflag[e.id] = true;\n\t\t\t\talldist += e.d;\n\t\t\t}\n\t\t}\n\t}\n\tres = min(res, alldist);\n\tprintf(\"%lld\\n\", res);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 20384, "score_of_the_acc": -0.2837, "final_rank": 8 }, { "submission_id": "aoj_0616_5186081", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nconstexpr long long mod = 1000000007;\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define mp make_pair\n#define all(x) x.begin(),x.end()\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint n, m, c, a[234567], b[234567], l[234567], cost[123456];\nvector<pair<int, int>>g[123456];\npriority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>>pq;\nset<int>s1; vector<int>v1; map<int, int>m1;\nvector<int>vl[123456]; int lsum, ans = 20000010000;\nsigned main() {\n\tcin >> n >> m >> c;\n\tfor1(i, m) {\n\t\tcin >> a[i] >> b[i] >> l[i];\n\t\tg[b[i]].push_back(mp(a[i], l[i]));\n\t\tg[a[i]].push_back(mp(b[i], l[i]));\n\t\tlsum += l[i];\n\t}\n\tfor1(i, n)cost[i] = 20000010000; cost[1] = 0; pq.push(mp(0, 1));\n\twhile (pq.size()) {\n\t\tint t1 = pq.top().first, x1 = pq.top().second;\n\t\tpq.pop();\n\t\tif (t1 > cost[x1])continue;\n\t\tfor (pair<int, int>p1 : g[x1])\n\t\t\tif (t1 + p1.second < cost[p1.first]) {\n\t\t\t\tcost[p1.first] = t1 + p1.second;\n\t\t\t\tpq.push(mp(t1 + p1.second, p1.first));\n\t\t\t}\n\t}\n\tfor1(i, n)s1.insert(cost[i]);\n\tfor (int i : s1)v1.push_back(i);\n\tfor0(i, v1.size())m1[v1[i]] = i;\n\tfor1(i, n)vl[m1[cost[i]]].push_back(i);\n\tfor0(i, v1.size()) {\n\t\tfor (int j : vl[i]) {\n\t\t\tfor (pair<int, int>p1 : g[j]) {\n\t\t\t\tif (m1[cost[p1.first]] < i)lsum -= p1.second;\n\t\t\t\tif (m1[cost[p1.first]] == i && p1.first < j)lsum -= p1.second;\n\t\t\t}\n\t\t}\n\t\tans = min(ans, c * v1[i] + lsum);\n\t}\n\tputs(ans);\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 35816, "score_of_the_acc": -1.4402, "final_rank": 16 }, { "submission_id": "aoj_0616_5186066", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nconstexpr long long mod = 1000000007;\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define mp make_pair\n#define all(x) x.begin(),x.end()\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint n, m, c, a[234567], b[234567], l[234567], cost[123456];\nvector<pair<int, int>>g[123456];\npriority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>>pq;\nset<int>s1; vector<int>v1;\nint f(int x) {\n\tint r = c * x;\n\tfor1(i, m) {\n\t\tif (max(cost[a[i]], cost[b[i]]) > x)r += l[i];\n\t}\n\treturn r;\n}\nsigned main() {\n\tcin >> n >> m >> c;\n\tfor1(i, m) {\n\t\tcin >> a[i] >> b[i] >> l[i];\n\t\tg[b[i]].push_back(mp(a[i], l[i]));\n\t\tg[a[i]].push_back(mp(b[i], l[i]));\n\t}\n\tfor1(i, n)cost[i] = 20000010000; cost[1] = 0; pq.push(mp(0, 1));\n\twhile (pq.size()) {\n\t\tint t1 = pq.top().first, x1 = pq.top().second;\n\t\tpq.pop();\n\t\tif (t1 > cost[x1])continue;\n\t\tfor (pair<int, int>p1 : g[x1]) {\n\t\t\tif (t1 + p1.second < cost[p1.first]) {\n\t\t\t\tcost[p1.first] = t1 + p1.second;\n\t\t\t\tpq.push(mp(t1 + p1.second, p1.first));\n\t\t\t}\n\t\t}\n\t}\n\tfor1(i, n)s1.insert(cost[i]);\n\tfor (int i : s1)v1.push_back(i);\n\tint rd = 0, ld = v1.size() - 1, ans = min({ f(v1[rd]),f(v1[ld]) });\n\twhile (ld - rd > 2) {\n\t\tint mid1 = (rd + rd + ld) / 3, mid2 = (rd + ld + ld) / 3;\n\t\tint f1 = f(v1[mid1]), f2 = f(v1[mid2]);\n\t\tif (f1 < f2)ld = mid2;\n\t\telse if (f1 > f2)rd = mid1;\n\t\telse {\n\t\t\tans = min({ ans,f(v1[ld]),f(v1[rd]) });\n\t\t\tld--; rd++;\n\t\t}\n\t}\n\tfor (int i = rd; i <= ld; i++)ans = min(ans, f(v1[i]));\n\tputs(ans);\n}", "accuracy": 0.7288135593220338, "time_ms": 210, "memory_kb": 25988, "score_of_the_acc": -0.6819, "final_rank": 20 }, { "submission_id": "aoj_0616_5184968", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nconstexpr long long mod = 1000000007;\n#define for0(i, n) for(int i = 0; i < (n); i++)\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define mp make_pair\n#define all(x) x.begin(),x.end()\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint n, m, c, a[234567], b[234567], l[234567], cost[123456];\nvector<pair<int, int>>g[123456];\npriority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>>pq;\nvector<int>v1;\nint f(int x) {\n\tint r = c * x;\n\tfor1(i, m) {\n\t\tif (max(cost[a[i]], cost[b[i]]) > x)r += l[i];\n\t}\n\treturn r;\n}\nsigned main() {\n\tcin >> n >> m >> c;\n\tfor1(i, m) {\n\t\tcin >> a[i] >> b[i] >> l[i];\n\t\tg[b[i]].push_back(mp(a[i], l[i]));\n\t\tg[a[i]].push_back(mp(b[i], l[i]));\n\t}\n\tfor1(i, n)cost[i] = 20000010000; cost[1] = 0; pq.push(mp(0, 1));\n\twhile (pq.size()) {\n\t\tint t1 = pq.top().first, x1 = pq.top().second;\n\t\tpq.pop();\n\t\tif (t1 > cost[x1])continue;\n\t\tfor (pair<int, int>p1 : g[x1]) {\n\t\t\tif (t1 + p1.second < cost[p1.first]) {\n\t\t\t\tcost[p1.first] = t1 + p1.second;\n\t\t\t\tpq.push(mp(t1 + p1.second, p1.first));\n\t\t\t}\n\t\t}\n\t}\n\tfor1(i, n)v1.push_back(cost[i]);\n\tsort(all(v1)); v1.erase(unique(all(v1)), v1.end());\n\tint rd = 0, ld = v1.size() - 1, ans = min({ f(v1[rd]),f(v1[ld]) });\n\twhile (ld - rd > 2) {\n\t\tint mid1 = (rd + rd + ld) / 3, mid2 = (rd + ld + ld) / 3;\n\t\tint f1 = f(v1[mid1]), f2 = f(v1[mid2]);\n\t\tif (f1 < f2)ld = mid2;\n\t\telse if (f1 > f2)rd = mid1;\n\t\telse {\n\t\t\tans = min({ ans,f(v1[ld]),f(v1[rd]) });\n\t\t\tld--; rd++;\n\t\t}\n\t}\n\tfor (int i = rd; i <= ld; i++)ans = min(ans, f(v1[i]));\n\tputs(ans);\n}", "accuracy": 0.7288135593220338, "time_ms": 200, "memory_kb": 23280, "score_of_the_acc": -0.583, "final_rank": 19 }, { "submission_id": "aoj_0616_5009101", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 10000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\ntypedef pair <ll, ll> P;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to, cost; };\n\nll d[213456];//始点sから終点tまでのコストd[t]\nvector<edge> G[213456];//コスト\nvoid dijkstra(ll s) {\n\t//greater<P>を指定→firstが小さい順\n\tpriority_queue<P, vector<P>, greater<P> >que;\n\tfill(d, d + 213456, INF);//←TLE気を付ける\n\td[s] = 0; que.push(P(0, s));\n\twhile (!que.empty()) {\n\t\tP p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d[v] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\t\t\tif (d[e.to] > d[v] + e.cost) {\n\t\t\t\td[e.to] = d[v] + e.cost;\n\t\t\t\tque.push(P(d[e.to], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\t//input\n\tll n, m, c; cin >> n >> m >> c;\n\tvector<ll> gs(m), gt(m), gd(m);\n\tll sum = 0;\n\trep(i, m) {\n\t\tcin >> gs[i] >> gt[i] >> gd[i];\n\t\tsum += gd[i];\n\t\tG[gs[i]].push_back({ gt[i], gd[i] });\n\t\tG[gt[i]].push_back({ gs[i], gd[i] });\n\t}\n\t//dijkstra\n\tdijkstra(1);\n\t//rui\n\t//まず道の補修をcount\n\tmap<ll, ll> rui;\n\trep(i, m) {\n\t\trui[max(d[gs[i]], d[gt[i]])] += gd[i];\n\t}\n\t//Dに頂点ごとの最小距離を入れる\n\tvector<ll> D; map<ll, bool> visit;\n\trep2(i, n) { if (visit[d[i]] == false) { D.push_back(d[i]); visit[d[i]] = true; } }\n\tsort(all(D));\n\t//そのDでrui\n\trep2(i, D.size() - 1) {\n\t\trui[D[i]] += rui[D[i - 1]];\n\t}\n\tll ans = INF;\n\trep(i, D.size()) {\n\t\trui[D[i]] = sum - rui[D[i]];\n\t\tans = min(ans, c * D[i] + rui[D[i]]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 34072, "score_of_the_acc": -0.88, "final_rank": 15 }, { "submission_id": "aoj_0616_4936855", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\nusing namespace std;\n\nusing lint = long long;\n\nconstexpr lint INF = 1LL << 61;\n\nstruct node{\n int id;\n lint cost;\n\n bool operator<(const node& rhs) const {\n return cost > rhs.cost;\n }\n};\n\nstruct edge{\n int from, to;\n lint cost;\n};\n\ntemplate<typename T>\nbool chmin(T& a, T b){\n if(b < a){\n a = b;\n return true;\n }\n return false;\n}\n\nint main(){\n int n, m;\n lint c;\n cin >> n >> m >> c;\n\n vector< vector<edge> > g(n);\n vector<edge> es(m);\n lint d = 0;\n\n for(edge& e : es){\n cin >> e.from >> e.to >> e.cost;\n --e.from;\n --e.to;\n\n g[e.from].push_back(e);\n g[e.to].push_back({e.to, e.from, e.cost});\n\n d += e.cost;\n }\n\n vector<lint> cost(n, INF);\n cost[0] = 0;\n priority_queue<node> que;\n que.push({0, 0LL});\n\n while(!que.empty()){\n node now = que.top();\n que.pop();\n\n if(cost[now.id] < now.cost){\n continue;\n }\n\n for(auto e : g[now.id]){\n if(chmin(cost[e.to], now.cost + e.cost)){\n que.push({e.to, now.cost + e.cost});\n }\n }\n }\n\n vector<int> id;\n for(int i = 0 ; i < n ; ++i){\n id.emplace_back(i);\n }\n\n sort(id.begin(), id.end(), [&](int i, int j){ return cost[i] < cost[j]; });\n sort(es.begin(), es.end(), [&](edge l, edge r){ return max(cost[l.from], cost[l.to]) < max(cost[r.from], cost[r.to]); });\n\n lint ans = INF;\n int j = 0;\n\n for(auto i : id){\n while(j < m && max(cost[es[j].from], cost[es[j].to]) <= cost[i]){\n d -= es[j].cost;\n ++j;\n }\n\n chmin(ans, c * cost[i] + d);\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 21444, "score_of_the_acc": -0.4105, "final_rank": 10 }, { "submission_id": "aoj_0616_4819479", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst long long inf = 1LL << 62;\nstruct edge {\n\tint to, cost;\n};\nstruct state {\n\tint pos; long long cost;\n\tbool operator<(const state& s) const {\n\t\treturn cost > s.cost;\n\t}\n};\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, M, C;\n\tcin >> N >> M >> C;\n\tvector<int> A(M), B(M), D(M);\n\tvector<vector<edge> > G(N);\n\tlong long sumdist = 0;\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin >> A[i] >> B[i] >> D[i]; --A[i], --B[i];\n\t\tG[A[i]].push_back(edge{ B[i], D[i] });\n\t\tG[B[i]].push_back(edge{ A[i], D[i] });\n\t\tsumdist += D[i];\n\t}\n\tvector<long long> dist(N, inf);\n\tpriority_queue<state> que;\n\tdist[0] = 0;\n\tque.push(state{ 0, 0 });\n\tvector<bool> vis(N, false);\n\twhile (!que.empty()) {\n\t\tint u = que.top().pos; que.pop();\n\t\tif (vis[u]) continue;\n\t\tvis[u] = true;\n\t\tfor (edge e : G[u]) {\n\t\t\tif (dist[e.to] > dist[u] + e.cost) {\n\t\t\t\tdist[e.to] = dist[u] + e.cost;\n\t\t\t\tque.push(state{ e.to, dist[e.to] });\n\t\t\t}\n\t\t}\n\t}\n\tvector<long long> sd = dist;\n\tsort(sd.begin(), sd.end());\n\tsd.erase(unique(sd.begin(), sd.end()), sd.end());\n\tvector<long long> g(sd.size());\n\tfor (int i = 0; i < M; ++i) {\n\t\tint ptr = lower_bound(sd.begin(), sd.end(), max(dist[A[i]], dist[B[i]])) - sd.begin();\n\t\tg[ptr] += D[i];\n\t}\n\tfor (int i = 1; i < sd.size(); ++i) {\n\t\tg[i] += g[i - 1];\n\t}\n\tlong long delta = inf;\n\tfor (int i = 0; i < sd.size(); ++i) {\n\t\tdelta = min(delta, sd[i] * C - g[i]);\n\t}\n\tcout << delta + sumdist << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 17004, "score_of_the_acc": -0.1907, "final_rank": 5 } ]
aoj_0621_cpp
ロシアの旗 (Russian Flag) 問題 K 理事長はロシアで開催される IOI 2016 に合わせて旗を作ることにした.K 理事長はまず倉庫から古い旗を取り出してきた.この旗は N 行 M 列のマス目に分けられていて,それぞれのマスには白・青・赤のいずれかの色が塗られている. K 理事長はこの旗のいくつかのマスを塗り替えて ロシアの旗 にしようとしている.ただし,この問題でいうロシアの旗とは以下のようなものである. 上から何行か (1 行以上) のマスが全て白で塗られている. 続く何行か (1 行以上) のマスが全て青で塗られている. それ以外の行 (1 行以上) のマスが全て赤で塗られている. K 理事長が古い旗をロシアの旗にするために塗り替える必要のあるマスの個数の最小値を求めよ. 入力 入力は 1 + N 行からなる. 1 行目には,2 つの整数 N, M (3 ≦ N ≦ 50, 3 ≦ M ≦ 50) が空白を区切りとして書かれている.これは,旗が N 行 M 列のマス目に区切られていることを表す. 続く N 行にはそれぞれ M 文字からなる文字列が書かれており,古い旗のマス目に塗られている色の情報を表す.N 行のうちの i 行目の j 文字目 (1 ≦ i ≦ N, 1 ≦ j ≦ M) は,古い旗のマス目の i 行目 j 列目のマスの色を表す 'W', 'B', 'R' のいずれかの文字である. 'W' は白,'B' は青,'R' は赤を表す. 出力 K 理事長が古い旗をロシアの旗にするために塗り替える必要のあるマスの個数の最小値を 1 行で出力せよ. 入出力例 入力例 1 4 5 WRWRW BWRWB WRWRW RWBWR 出力例 1 11 入力例 2 6 14 WWWWWWWWWWWWWW WBBBWWRRWWBBBW WWBWWRRRRWWBWW BWBWWRRRRWWBWW WBBWWWRRWWBBBW WWWWWWWWWWWWWW 出力例 2 44 入出力例 1 において,古い旗には下図のように色が塗られている. 下図において,'X' の書かれた 11 個のマスを塗り替える. これにより下図のようなロシアの旗にすることができる. 11 個未満のマスを塗り替えることではロシアの旗にすることはできないため,11 を出力する. 入出力例 2 においては,古い旗には下図のように色が塗られている. 情報オリンピック日本委員会作 『第 15 回日本情報オリンピック JOI 2015/2016 予選競技課題』
[ { "submission_id": "aoj_0621_2993939", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint N, M;\n\nint main() {\n cin >> N >> M;\n vector<string> board(N);\n\n for(int i=0; i<N; i++) {\n cin >> board[i];\n }\n\n int ans = N*M;\n for(int r=1; r<=N-2; r++) {\n for(int b=1; b<=N-2; b++) {\n for(int w=1; w<=N-2; w++) {\n if(r + b + w != N) continue;\n vector<string> comp(N);\n int idx = 0;\n\n for(int i=0; i<w; i++) {\n comp[idx++] = string(M, 'W');\n }\n for(int i=0; i<b; i++) {\n comp[idx++] = string(M, 'B');\n }\n for(int i=0; i<r; i++) {\n comp[idx++] = string(M, 'R');\n }\n\n int cnt = 0;\n for(int i=0; i<N; i++) {\n for(int j=0; j<M; j++) {\n cnt += (board[i][j] != comp[i][j]);\n }\n }\n ans = min(ans, cnt);\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3188, "score_of_the_acc": -1, "final_rank": 3 }, { "submission_id": "aoj_0621_2663690", "code_snippet": "# include <iostream>\n# include <algorithm>\n# include <vector>\n# include <string>\n# include <set>\n# include <map>\n# include <cmath>\n# include <iomanip>\n# include <functional>\n# include <utility>\n# include <stack>\n# include <queue>\n# include <list>\n# include <tuple>\n# include <unordered_map>\n# include <numeric>\n# include <complex>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\nconstexpr int INF = 2000000000;\nconstexpr int HINF = INF / 2;\nconstexpr double DINF = 100000000000000000.0;\nconstexpr long long LINF = 9223372036854775807;\nconstexpr long long HLINF = 4500000000000000000;\nconst double PI = acos(-1);\nint dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };\n# define ALL(x) (x).begin(),(x).end()\n# define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n# define mp make_pair\n# define eb emplace_back\n# define REP(i, a) for (int i = 0; i < (a); i++)\n# define INIT std::ios::sync_with_stdio(false);std::cin.tie(0);\n\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tvector<string> vec;\n\tfor (int i = 0; i<n; i++) {\n\t\tstring t;\n\t\tcin >> t;\n\t\tvec.push_back(t);\n\t}\n\tint ans = INF;\n\tfor (int i = 1; i<n; i++) {\n\t\tfor (int j = 1; i + j<n; j++) {\n\t\t\tfor (int k = 1; i + j + k <= n; k++) {\n\t\t\t\tint sum = 0;\n\t\t\t\tfor (int l = 0; l<n; l++) {\n\t\t\t\t\tfor (int p = 0; p<m; p++) {\n\t\t\t\t\t\tif (l<i&&vec[l][p] != 'W') {\n\t\t\t\t\t\t\tsum++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (i <= l&&l<i + j&&vec[l][p] != 'B') {\n\t\t\t\t\t\t\tsum++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\telse if (i + j <= l&&vec[l][p] != 'R') {\n\t\t\t\t\t\t\tsum++;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tans = min(ans, sum);\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3160, "score_of_the_acc": -1.0192, "final_rank": 5 }, { "submission_id": "aoj_0621_2135318", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nint n, m;\nvector<string> a;\nint ans = 100100100;\n\nint main(){\n\tscanf(\"%d %d\", &n, &m);\n\tfor(int i=0; i<n; i++){\n\t\tchar t[m+1];\n\t\tscanf(\"%s\", t);\n\t\ta.push_back(t);\n\t}\n\n\tfor(int i=0; i<n-2; i++){\n\t\tfor(int j=1; i+j<n-1; j++){\n\t\t\tfor(int k=1; i+j+k<n; k++){\n\t\t\t\tint t = 0;\n\t\t\t\tfor(int ii=0; ii<n; ii++){\n\t\t\t\t\tchar s[2];\n\t\t\t\t\tif(ii <= i) s[0] = 'W';\n\t\t\t\t\telse if(ii <= i+j) s[0] = 'B';\n\t\t\t\t\telse s[0] = 'R';\n\t\t\t\t\tfor(int jj=0; jj<m; jj++){\n\t\t\t\t\t\tif(a[ii][jj] != s[0]) t++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tans = min(ans, t);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 2836, "score_of_the_acc": -0.8556, "final_rank": 2 }, { "submission_id": "aoj_0621_2042116", "code_snippet": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\n\nint X, Y;\nchar flag[50][51];\nint answer;\nint sit[50][3];\n\ninline int russia(char x){\n\tif (x == 'B')return 0;\n\tif (x == 'W')return 1;\n\tif (x == 'R')return 2;\n\n}\n\nint f(int x,int color){\n\tif (x == 0)return sit[0][0] + sit[0][2];\n\tif (x == Y - 1)return min(f(x - 1, 0), f(x - 1, 2)) + sit[x][0] + sit[x][1];\n\tif (color == 0)return min(f(x - 1, 0), f(x - 1, 1)) + sit[x][1] + sit[x][2];\n\tif (color == 1)return min(f(x - 1, 2), f(x - 1, 1)) + sit[x][2] + sit[x][0];\n\tif (color == 2)return min(f(x - 1, 2), f(x - 1, 0)) + sit[x][1] + sit[x][0];\n\n\treturn 1000000;\n}\n\nint main(){\n\tscanf(\"%d %d\", &Y, &X);\n\tfor (int i = 0; i < Y; ++i){\n\t\tscanf(\"%s\", &(flag[i]),X);\n\t\tfor (int x = 0; x < X; ++x){\n\t\t\tsit[i][russia(flag[i][x])] += 1;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", f(Y - 1, 2));\n\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 1810, "memory_kb": 2684, "score_of_the_acc": -1.7455, "final_rank": 6 }, { "submission_id": "aoj_0621_2026311", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(int i = (a); i < (b); i++)\n#define REP(i,n) FOR(i,0,n)\n#define INF (1<<29)\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tstring maps[50];\n\tREP(i, n) cin >> maps[i];\n\t\n\tint ans = INF;\n\tFOR(w, 1, n + 1) FOR(b, 1, n - w + 1) FOR(r, 1, n - w - b + 1) {\n\t\tint cnt = 0;\n\t\tFOR(i, 0, w) cnt += m - count(maps[i].c_str(), maps[i].c_str() + maps[i].size(), 'W');\n\t\tFOR(i, w, w + b) cnt += m - count(maps[i].c_str(), maps[i].c_str() + maps[i].size(), 'B');\n\t\tFOR(i, w + b, n) cnt += m - count(maps[i].c_str(), maps[i].c_str() + maps[i].size(), 'R');\n\t\t\n\t\tans = min(ans, cnt);\n\t}\n\t\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3176, "score_of_the_acc": -1.0051, "final_rank": 4 }, { "submission_id": "aoj_0621_1851818", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n,m;\n cin >> n >> m;\n string s[n];\n for(int i=0; i<n; i++) cin >> s[i];\n int ans=n*m;\n for(int x=1; x<n; x++) {\n for(int y=x+1; y<n; y++) {\n int cnt=0;\n for(int i=0; i<n; i++) {\n for(int j=0; j<m; j++) {\n if(i<x&&s[i][j]!='W') cnt++;\n if(i>=x&&i<y&&s[i][j]!='B') cnt++;\n if(i>=y&&s[i][j]!='R') cnt++;\n }\n }\n ans=min(ans,cnt);\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 1208, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0618_cpp
城壁 (Rampart) 歴史学者である JOI 教授は,かつて存在した IOI 王国について研究している. 過去の調査によると,IOI 王国は縦 H 行,横 W 列のマスに区切られた長方形の形をしていた.IOI 王国の首都は,防衛のために城壁で囲われていた. IOI 王国の首都を囲う城壁は次のような形をしている.城壁には大きさと呼ばれる値が定まっている.大きさ s ( s ≥ 3) の城壁とは, s × s の正方形の領域から外周以外の ( s − 2) × ( s − 2) の正方形の領域を除いたものである. 調査によると,首都を囲う城壁の大きさは L 以上であった.また,IOI 王国のいくつかのマスには城壁が存在しなかったことがわかっている. JOI 教授は,さらなる研究のために,城壁としてありうるものが何通りあるかを知りたい. 課題 IOI 王国の大きさと,城壁の大きさの最小値,城壁が存在しなかったことが分かっているマスの情報が与えられたとき,城壁としてありうるものは何通りあるかを求めるプログラムを作成せよ. 入力 標準入力から以下のデータを読み込め. 1 行目には,整数 H , W , L , P が空白を区切りとして書かれている.これは,IOI 王国は縦 H 行,横 W 列のマスに区切られた長方形の形をしており,城壁の大きさは L 以上であり,城壁が存在しなかったことがわかっているマスが P マス存在することを表す. 続く P 行のうちの i 行目 (1 ≤ i ≤ P ) には,整数 A i , B i が空白を区切りとして書かれている.これは,IOI 王国の上から A i 行目,左から B i 列目のマスには城壁が存在しなかったことがわかっていることを表す. 出力 標準出力に,城壁としてありうるものは何通りあるかを表す整数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 1 ≤ H ≤ 4 000. 1 ≤ W ≤ 4 000. 3 ≤ L ≤ H かつ 3 ≤ L ≤ W . 0 ≤ P ≤ 100 000. 1 ≤ A i ≤ H (1 ≤ i ≤ P ). 1 ≤ B i ≤ W (1 ≤ i ≤ P ). ( A i , B i ) ≠ ( A j , B j ) (1 ≤ i < j ≤ P ). 入出力例 入力例 1 5 5 3 2 2 2 4 3 出力例 1 4 この入力例の場合,城壁としてありうるものは以下の 4 通りが考えられる.ただし,× で示したマスは城壁が存在しなかったことがわかっているマスである. 入力例 2 7 8 4 3 2 2 3 7 6 5 出力例 2 13 入力例 3 4000 4000 1234 4 1161 3028 596 1892 3731 2606 702 1530 出力例 3 7050792912 問題文と自動審判に使われるデータは、 情報オリンピック日本委員会 が作成し公開している問題文と採点用テストデータです。
[ { "submission_id": "aoj_0618_9488096", "code_snippet": "#include <bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n#define NUM 4001\n\nenum Type {\n LEFT_UP,\n RIGHT_UNDER,\n};\n\nstruct Info {\n Info(Type arg_type, short arg_max_len, short arg_loc) {\n type = arg_type;\n max_len = arg_max_len;\n loc = arg_loc; // 斜めのラインにおける相対位置\n }\n bool operator<(const struct Info &arg) const {\n if (max_len != arg.max_len) {\n return max_len > arg.max_len; // 最大長の降順\n } else {\n return type < arg.type; // 長さが同じなら、LEFT_UPを左に持ってくる\n }\n }\n Type type;\n short max_len, loc;\n};\n\nint H, W, min_len, P;\nint BIT_MAX;\nshort LIMIT[2][NUM][NUM];\nint BIT[2][NUM];\nbool table[NUM][NUM];\nshort dp[NUM][NUM];\n\nvoid add(Type type, int loc, int value) {\n BIT[type][loc] += value;\n loc += loc & -loc; // 最後の1ビットを足した場所が次の更新場所\n\n while (loc <= BIT_MAX) {\n BIT[type][loc] += value;\n loc += loc & -loc;\n }\n}\n\nint getSum(Type type, int loc) {\n int sum = BIT[type][loc];\n loc -= loc & -loc; // 最後の1ビットを引いた場所が次の加算場所\n\n while (loc > 0) {\n sum += BIT[type][loc];\n loc -= loc & -loc;\n }\n return sum;\n}\n\nint calc(Type type, int left, int right) { // left~rightの区間の総和を求める\n return getSum(type, right) - getSum(type, left - 1);\n}\n\nvoid init_LIMIT(Type type) {\n for (int row = 0; row < H; row++) {\n for (int col = 0; col < W; col++) {\n LIMIT[type][row][col] = NUM;\n }\n }\n}\n\nvoid update_LIMIT(Type type) {\n for (int row = 0; row < H; row++) {\n for (int col = 0; col < W; col++) {\n LIMIT[type][row][col] = min(LIMIT[type][row][col], dp[row][col]);\n }\n }\n}\n\nbool rangeCheck(int row, int col) {\n return row >= 0 && row <= H - 1 && col >= 0 && col <= W - 1;\n}\n\nint main() {\n scanf(\"%d %d %d %d\", &H, &W, &min_len, &P);\n\n for (int row = 0; row < H; row++) {\n for (int col = 0; col < W; col++) {\n table[row][col] = true;\n }\n }\n\n int tmp_row, tmp_col;\n\n for (int loop = 0; loop < P; loop++) {\n scanf(\"%d %d\", &tmp_row, &tmp_col);\n tmp_row--;\n tmp_col--;\n table[tmp_row][tmp_col] = false;\n }\n\n // 各場所からの最大長を計算する\n\n // 左上基準\n init_LIMIT(LEFT_UP);\n\n // 右方向への最大長さ\n for (int row = 0; row < H; row++) {\n dp[row][W - 1] = table[row][W - 1] ? 1 : 0;\n }\n\n for (int col = W - 2; col >= 0; col--) {\n for (int row = 0; row < H; row++) {\n dp[row][col] = table[row][col] ? dp[row][col + 1] + 1 : 0;\n }\n }\n update_LIMIT(LEFT_UP);\n\n // 下方向への最大長さ\n for (int col = 0; col < W; col++) {\n dp[H - 1][col] = table[H - 1][col] ? 1 : 0;\n }\n\n for (int row = H - 2; row >= 0; row--) {\n for (int col = 0; col < W; col++) {\n dp[row][col] = table[row][col] ? dp[row + 1][col] + 1 : 0;\n }\n }\n update_LIMIT(LEFT_UP);\n\n // 右下基準\n init_LIMIT(RIGHT_UNDER);\n\n // 左方向への最大長さ\n for (int row = 0; row < H; row++) {\n dp[row][0] = table[row][0] ? 1 : 0;\n }\n\n for (int col = 1; col < W; col++) {\n for (int row = 0; row < H; row++) {\n dp[row][col] = table[row][col] ? dp[row][col - 1] + 1 : 0;\n }\n }\n update_LIMIT(RIGHT_UNDER);\n\n // 上方向への最大長さ\n for (int col = 0; col < W; col++) {\n dp[0][col] = table[0][col] ? 1 : 0;\n }\n\n for (int row = 1; row < H; row++) {\n for (int col = 0; col < W; col++) {\n dp[row][col] = table[row][col] ? dp[row - 1][col] + 1 : 0;\n }\n }\n update_LIMIT(RIGHT_UNDER);\n\n vector<Info> V;\n ll ans = 0;\n\n // 斜めのラインごとに計上処理を行う\n int start_row = 0, start_col = W - 2;\n int left, right;\n\n while (true) {\n V.clear();\n BIT_MAX = 0;\n\n tmp_row = start_row, tmp_col = start_col;\n // 斜めのラインのデータを走査する\n while (rangeCheck(tmp_row, tmp_col)) {\n V.emplace_back(LEFT_UP, LIMIT[LEFT_UP][tmp_row][tmp_col], BIT_MAX + 1);\n V.emplace_back(RIGHT_UNDER, LIMIT[RIGHT_UNDER][tmp_row][tmp_col], BIT_MAX + 1);\n\n tmp_row++;\n tmp_col++;\n BIT_MAX++;\n }\n\n sort(V.begin(), V.end());\n\n // BIT木の初期化\n for (int i = 0; i <= BIT_MAX; i++) {\n BIT[LEFT_UP][i] = 0;\n BIT[RIGHT_UNDER][i] = 0;\n }\n\n // 最大長が大きい方から、降順に処理する\n for (const auto &info : V) {\n if (info.type == LEFT_UP) {\n left = info.loc + min_len - 1;\n right = info.loc + info.max_len - 1;\n\n if (left <= right) {\n ans += calc(RIGHT_UNDER, left, right); // ペアになるものを探す\n }\n } else {\n right = info.loc - min_len + 1;\n left = info.loc - info.max_len + 1;\n\n if (left <= right) {\n ans += calc(LEFT_UP, left, right);\n }\n }\n\n add(info.type, info.loc, 1);\n }\n\n if (start_row == H - 2 && start_col == 0) {\n break;\n }\n\n if (start_row == 0) {\n if (start_col != 0) {\n start_col--;\n } else {\n start_row++;\n }\n } else {\n start_row++;\n }\n }\n\n printf(\"%lld\\n\", ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 2450, "memory_kb": 113156, "score_of_the_acc": -0.6639, "final_rank": 10 }, { "submission_id": "aoj_0618_4822465", "code_snippet": "#include <cstring>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool px[4096][4096], py[4096][4096]; short sa[4096][4096], sb[4096][4096], sc[4096][4096], sd[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096], rui[128]; uint64_t seq[128];\nint calc(int N) {\n\tmemset(cnt, 0, sizeof(cnt));\n\tmemset(rui, 0, sizeof(rui));\n\tmemset(seq, 0, sizeof(seq));\n\tfor (int i = 0; i < N; ++i) ++cnt[sy[i] + i + 2];\n\tfor (int i = 0; i <= N; ++i) cnt[i + 2] += cnt[i + 1];\n\tfor (int i = 0; i < N; ++i) ord[cnt[sy[i] + i + 1]++] = i;\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) ans += rui[j];\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tpx[x][y] = true;\n\t\tpy[y][x] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (px[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (py[i][j]) last = j;\n\t\t\tsc[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (px[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (py[i][j]) last = j;\n\t\t\tsd[i][j] = last - j;\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = min(sa[j][i + j], sc[i + j][j]);\n\t\t\tsy[j - d] = min(sb[j][i + j], sd[i + j][j]);\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 158864, "score_of_the_acc": -0.6092, "final_rank": 7 }, { "submission_id": "aoj_0618_4822447", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool placex[4096][4096], placey[4096][4096]; short sa[4096][4096], sb[4096][4096], sc[4096][4096], sd[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort rui[128]; uint64_t seq[128];\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tfill(rui, rui + (N >> 6) + 1, 0);\n\tfill(seq, seq + (N >> 6) + 1, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) {\n\t\t\tans += rui[j];\n\t\t}\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplacex[x][y] = true;\n\t\tplacey[y][x] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsc[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsd[i][j] = last - j;\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = min(sa[j][i + j], sc[i + j][j]);\n\t\t\tsy[j - d] = min(sb[j][i + j], sd[i + j][j]);\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 158868, "score_of_the_acc": -0.6107, "final_rank": 8 }, { "submission_id": "aoj_0618_4822444", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool placex[4096][4096], placey[4096][4096]; short sa[4096][4096], sb[4096][4096], sc[4096][4096], sd[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort rui[128]; uint64_t seq[128];\nint popcnt(uint64_t x) {\n\tint ans = 0;\n\twhile (x) {\n\t\tans += (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn ans;\n}\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tfill(rui, rui + (N >> 6) + 1, 0);\n\tfill(seq, seq + (N >> 6) + 1, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) {\n\t\t\tans += rui[j];\n\t\t}\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplacex[x][y] = true;\n\t\tplacey[y][x] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsc[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsd[i][j] = last - j;\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = min(sa[j][i + j], sc[i + j][j]);\n\t\t\tsy[j - d] = min(sb[j][i + j], sd[i + j][j]);\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 158932, "score_of_the_acc": -0.617, "final_rank": 9 }, { "submission_id": "aoj_0618_4822439", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool placex[4096][4096], placey[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort rui[128]; uint64_t seq[128];\nint popcnt(uint64_t x) {\n\tint ans = 0;\n\twhile (x) {\n\t\tans += (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn ans;\n}\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tfill(rui, rui + (N >> 6) + 1, 0);\n\tfill(seq, seq + (N >> 6) + 1, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) {\n\t\t\tans += rui[j];\n\t\t}\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplacex[x][y] = true;\n\t\tplacey[y][x] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (placex[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (placey[i][j]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1050, "memory_kb": 96308, "score_of_the_acc": -0.3854, "final_rank": 4 }, { "submission_id": "aoj_0618_4822417", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort rui[128]; uint64_t seq[128];\nint popcnt(uint64_t x) {\n\tint ans = 0;\n\twhile (x) {\n\t\tans += (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn ans;\n}\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tfill(rui, rui + (N >> 6) + 1, 0);\n\tfill(seq, seq + (N >> 6) + 1, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) {\n\t\t\tans += rui[j];\n\t\t}\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1120, "memory_kb": 81988, "score_of_the_acc": -0.3396, "final_rank": 2 }, { "submission_id": "aoj_0618_4822414", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort bit[128]; uint64_t seq[128];\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tint upper = (N >> 6) + 1;\n\tfill(bit, bit + upper + 1, 0);\n\tfill(seq, seq + upper, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\tint lim = (ord[j] >> 6);\n\t\t\tfor (int k = lim + 1; k <= upper; k += k & (-k)) {\n\t\t\t\t++bit[k];\n\t\t\t}\n\t\t\tseq[lim] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tans -= __builtin_popcountll(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcountll(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t\twhile (liml != limr) {\n\t\t\tif (liml <= limr) {\n\t\t\t\tans += bit[limr];\n\t\t\t\tlimr -= limr & (-limr);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans -= bit[liml];\n\t\t\t\tliml -= liml & (-liml);\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1180, "memory_kb": 81936, "score_of_the_acc": -0.3484, "final_rank": 3 }, { "submission_id": "aoj_0618_4822406", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort bit[128]; uint64_t seq[128];\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tint upper = (N >> 6) + 1;\n\tfill(bit, bit + upper + 1, 0);\n\tfill(seq, seq + upper, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\tint lim = (ord[j] >> 6);\n\t\t\tfor (int k = lim + 1; k <= upper; k += k & (-k)) {\n\t\t\t\t++bit[k];\n\t\t\t}\n\t\t\tseq[lim] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tans -= __builtin_popcount(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += __builtin_popcount(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t\twhile (liml != limr) {\n\t\t\tif (liml <= limr) {\n\t\t\t\tans += bit[limr];\n\t\t\t\tlimr -= limr & (-limr);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans -= bit[liml];\n\t\t\t\tliml -= liml & (-liml);\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 0.06666666666666667, "time_ms": 890, "memory_kb": 67172, "score_of_the_acc": -0.2463, "final_rank": 18 }, { "submission_id": "aoj_0618_4822399", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort bit[128]; uint64_t seq[128];\nint popcnt(uint64_t x) {\n\tint ans = 0;\n\twhile (x) {\n\t\tans += (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn ans;\n}\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tint upper = (N >> 6) + 1;\n\tfill(bit, bit + upper + 1, 0);\n\tfill(seq, seq + upper, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\tint lim = (ord[j] >> 6);\n\t\t\tfor (int k = lim + 1; k <= upper; k += k & (-k)) {\n\t\t\t\t++bit[k];\n\t\t\t}\n\t\t\tseq[lim] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j >= 1; j -= j & (-j)) {\n\t\t\tans -= bit[j];\n\t\t}\n\t\tfor (int j = limr; j >= 1; j -= j & (-j)) {\n\t\t\tans += bit[j];\n\t\t}\n\t\tans -= popcnt(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += popcnt(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1590, "memory_kb": 82068, "score_of_the_acc": -0.4111, "final_rank": 6 }, { "submission_id": "aoj_0618_4822387", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096], cnt[4096], ord[4096];\nshort rui[128]; uint64_t seq[128];\nint popcnt(uint64_t x) {\n\tint ans = 0;\n\twhile (x) {\n\t\tans += (x & 1);\n\t\tx >>= 1;\n\t}\n\treturn ans;\n}\nint calc(int N) {\n\tfill(cnt, cnt + N + 3, 0);\n\tfor (int i = 0; i < N; ++i) {\n\t\t++cnt[sy[i] + i + 2];\n\t}\n\tfor (int i = 0; i <= N; ++i) {\n\t\tcnt[i + 2] += cnt[i + 1];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tord[cnt[sy[i] + i + 1]++] = i;\n\t}\n\tfill(rui, rui + (N >> 6) + 1, 0);\n\tfill(seq, seq + (N >> 6) + 1, 0);\n\tint ans = 0;\n\tfor (int i = N - 1; i >= 0; --i) {\n\t\tfor (int j = cnt[i + 2] - 1; j >= cnt[i + 1]; --j) {\n\t\t\t++rui[ord[j] >> 6];\n\t\t\tseq[ord[j] >> 6] |= 1ULL << (ord[j] & 63);\n\t\t}\n\t\tint pl = max(i - sx[i], 0), pr = max(i - L + 2, pl);\n\t\tif (pl == pr) continue;\n\t\tint liml = (pl >> 6), limr = (pr >> 6);\n\t\tfor (int j = liml; j < limr; ++j) {\n\t\t\tans += rui[j];\n\t\t}\n\t\tans -= popcnt(seq[liml] & ((1ULL << (pl & 63)) - 1));\n\t\tans += popcnt(seq[limr] & ((1ULL << (pr & 63)) - 1));\n\t}\n\treturn ans;\n}\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0), cnt = 0;\n\t\tfor (int j = d; j < H && i + j < W; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t\t++cnt;\n\t\t}\n\t\tans += calc(cnt);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 81936, "score_of_the_acc": -0.3954, "final_rank": 5 }, { "submission_id": "aoj_0618_4822325", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint H, W, L, P;\nbool place[4096][4096]; short sa[4096][4096], sb[4096][4096], sx[4096], sy[4096];\nint calc(int N) {\n\tint ans = 0;\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = i - sx[i]; j < i - L + 2; ++j) {\n\t\t\tif (sy[j] + j > i) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t}\n\t}\n\treturn ans;\n}\nint main() {\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; ++i) {\n\t\tint x, y;\n\t\tcin >> x >> y; --x, --y;\n\t\tplace[x][y] = true;\n\t}\n\tshort last;\n\tfor (int i = 0; i < H; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsa[i][j] = j - last;\n\t\t}\n\t}\n\tfor (int i = 0; i < W; ++i) {\n\t\tlast = -1;\n\t\tfor (int j = 0; j < H; ++j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsa[j][i] = min<short>(sa[j][i], j - last);\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; --i) {\n\t\tlast = W;\n\t\tfor (int j = W - 1; j >= 0; --j) {\n\t\t\tif (place[i][j]) last = j;\n\t\t\tsb[i][j] = last - j;\n\t\t}\n\t}\n\tfor (int i = W - 1; i >= 0; --i) {\n\t\tlast = H;\n\t\tfor (int j = H - 1; j >= 0; --j) {\n\t\t\tif (place[j][i]) last = j;\n\t\t\tsb[j][i] = min<short>(sb[j][i], last - j);\n\t\t}\n\t}\n\tlong long ans = 0;\n\tfor (int i = -(H - 1); i <= (W - 1); ++i) {\n\t\tint d = max(-i, 0);\n\t\tfor (int j = d; j < H; ++j) {\n\t\t\tsx[j - d] = sa[j][i + j];\n\t\t\tsy[j - d] = sb[j][i + j];\n\t\t}\n\t\tans += calc(H - d);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 0.06666666666666667, "time_ms": 7490, "memory_kb": 67048, "score_of_the_acc": -1.2458, "final_rank": 20 }, { "submission_id": "aoj_0618_4118939", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n#include <set>\n\nclass Bit {\n\tstd::vector<int>vec;\npublic:\n\tBit(int size) : vec(size, 0){};\n\tint get(int position) const {\n\t\tint result = 0;\n\t\twhile (position >= 0) {\n\t\t\tresult += vec[position];\n\t\t\tposition -= (position + 1) & ~position;\n\t\t}\n\t\treturn result;\n\t}\n\tvoid add(int position, int value) {\n\t\twhile (position < vec.size()) {\n\t\t\tvec[position] += value;\n\t\t\tposition += (position + 1) & ~position;\n\t\t}\n\t}\n\tvoid clear() {\n\t\tstd::fill(vec.begin(), vec.end(), 0);\n\t}\n};\nint main(void) {\n\tint height, width, min_size, p; std::cin >> height >> width >> min_size >> p;\n\tstd::vector<std::vector<int>> for_top(height, std::vector<int>(width, 1));\n\tfor (auto i = 0; i < p; ++i) {\n\t\tint a, b; std::cin >> a >> b;\n\t\tfor_top[--a][--b] = 0;\n\t}\n\tauto for_bottom = for_top; auto for_right = for_top; auto for_left = for_top;\n\tfor (auto i = 1; i < height; ++i) {\n\t\tfor (auto j = 0; j < width; ++j) {\n\t\t\tif (for_top[i][j] != 0) {\n\t\t\t\tfor_top[i][j] += for_top[i - 1][j];\n\t\t\t}\n\t\t\tif (for_bottom[height - i - 1][j] != 0) {\n\t\t\t\tfor_bottom[height - i - 1][j] += for_bottom[height - i][j];\n\t\t\t}\n\t\t}\n\t}\n\tfor (auto i = 0; i < height; ++i) {\n\t\tfor (auto j = 1; j < width; ++j) {\n\t\t\tif (for_left[i][j] != 0) {\n\t\t\t\tfor_left[i][j] += for_left[i][j - 1];\n\t\t\t}\n\t\t\tif (for_right[i][width - j - 1] != 0) {\n\t\t\t\tfor_right[i][width - j - 1] += for_right[i][width - j];\n\t\t\t}\n\t\t}\n\t}\n\tstd::priority_queue<std::pair<int, int>, std::vector<std::pair<int, int>>, std::function<bool(std::pair<int, int>&, std::pair<int, int>&)>> history([](std::pair<int, int>& a, std::pair<int, int>& b) {return a.first > b.first; });\n\tBit bit(std::min(height, width) + 1);\n\tlong long int count = 0;\n\tfor (int i = -width + 1; i < height; ++i) {\n\t\tconst int h = std::max(i, 0);\n\t\tconst int w = std::max(0, h - i);\n\t\tfor (auto j = 0; h + j < height && w + j < width; ++j) {\n\t\t\tconst auto for_next = std::min(for_bottom[h + j][w + j], for_right[h + j][w + j]);\n\t\t\tif (for_next >= min_size) {\n\t\t\t\thistory.emplace(j + for_next - 1, j);\n\t\t\t\tbit.add(j, 1);\n\t\t\t}\n\t\t\tconst auto for_prev = std::min(for_top[h + j][w + j], for_left[h + j][w + j]);\n\t\t\tif (for_prev >= min_size) {\n\t\t\t\tcount += bit.get(j + 1 - min_size) - bit.get(j - for_prev);\n\t\t\t}\n\t\t\twhile (!history.empty() && history.top().first == j) {\n\t\t\t\tbit.add(history.top().second, -1);\n\t\t\t\thistory.pop();\n\t\t\t}\n\t\t}\n\t}\n\tstd::cout << count << '\\n';\n}", "accuracy": 1, "time_ms": 3130, "memory_kb": 253752, "score_of_the_acc": -1.321, "final_rank": 15 }, { "submission_id": "aoj_0618_4118934", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\n#include <set>\n\nclass Bit {\n\tstd::vector<int>vec;\npublic:\n\tBit(int size) : vec(size, 0){};\n\tint get(int position) const {\n\t\tint result = 0;\n\t\twhile (position >= 0) {\n\t\t\tresult += vec[position];\n\t\t\tposition -= (position + 1) & ~position;\n\t\t}\n\t\treturn result;\n\t}\n\tvoid add(int position, int value) {\n\t\twhile (position < vec.size()) {\n\t\t\tvec[position] += value;\n\t\t\tposition += (position + 1) & ~position;\n\t\t}\n\t}\n\tvoid clear() {\n\t\tstd::fill(vec.begin(), vec.end(), 0);\n\t}\n};\nint main(void) {\n\tint height, width, min_size, p; std::cin >> height >> width >> min_size >> p;\n\tstd::vector<std::vector<int>> for_top(height, std::vector<int>(width, 1));\n\tfor (auto i = 0; i < p; ++i) {\n\t\tint a, b; std::cin >> a >> b;\n\t\tfor_top[--a][--b] = 0;\n\t}\n\tauto for_bottom = for_top; auto for_right = for_top; auto for_left = for_top;\n\tfor (auto i = 1; i < height; ++i) {\n\t\tfor (auto j = 0; j < width; ++j) {\n\t\t\tif (for_top[i][j] != 0) {\n\t\t\t\tfor_top[i][j] += for_top[i - 1][j];\n\t\t\t}\n\t\t\tif (for_bottom[height - i - 1][j] != 0) {\n\t\t\t\tfor_bottom[height - i - 1][j] += for_bottom[height - i][j];\n\t\t\t}\n\t\t}\n\t}\n\tfor (auto i = 0; i < height; ++i) {\n\t\tfor (auto j = 1; j < width; ++j) {\n\t\t\tif (for_left[i][j] != 0) {\n\t\t\t\tfor_left[i][j] += for_left[i][j - 1];\n\t\t\t}\n\t\t\tif (for_right[i][width - j - 1] != 0) {\n\t\t\t\tfor_right[i][width - j - 1] += for_right[i][width - j];\n\t\t\t}\n\t\t}\n\t}\n\tstd::priority_queue<std::pair<int, int>, std::vector<std::pair<int, int>>, std::function<bool(std::pair<int, int>&, std::pair<int, int>&)>> history([](std::pair<int, int>& a, std::pair<int, int>& b) {return a.first > b.first; });\n\tBit bit(std::min(height, width) + 1);\n\tlong long int count = 0;\n\tfor (int i = -height + 1; i < height; ++i) {\n\t\tconst int h = std::max(i, 0);\n\t\tconst int w = std::max(0, h - i);\n\t\tfor (auto j = 0; h + j < height && w + j < width; ++j) {\n\t\t\tconst auto for_next = std::min(for_bottom[h + j][w + j], for_right[h + j][w + j]);\n\t\t\tif (for_next >= min_size) {\n\t\t\t\thistory.emplace(j + for_next - 1, j);\n\t\t\t\tbit.add(j, 1);\n\t\t\t}\n\t\t\tconst auto for_prev = std::min(for_top[h + j][w + j], for_left[h + j][w + j]);\n\t\t\tif (for_prev >= min_size) {\n\t\t\t\tcount += bit.get(j + 1 - min_size) - bit.get(j - for_prev);\n\t\t\t}\n\t\t\twhile (!history.empty() && history.top().first == j) {\n\t\t\t\tbit.add(history.top().second, -1);\n\t\t\t\thistory.pop();\n\t\t\t}\n\t\t}\n\t}\n\tstd::cout << count << '\\n';\n}", "accuracy": 0.13333333333333333, "time_ms": 1770, "memory_kb": 253628, "score_of_the_acc": -1.1144, "final_rank": 17 }, { "submission_id": "aoj_0618_3103831", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 4001\n\nenum Type{\n\tLEFT_UP,\n\tRIGHT_UNDER,\n};\n\nstruct Info{\n\tInfo(Type arg_type,short arg_max_len,short arg_loc){\n\t\ttype = arg_type;\n\t\tmax_len = arg_max_len;\n\t\tloc = arg_loc; //★★斜めのラインにおける相対位置★★\n\t}\n\tbool operator<(const struct Info &arg) const{\n\t\tif(max_len != arg.max_len){ //最大長の降順\n\t\t\treturn max_len > arg.max_len;\n\t\t}else{\n\n\t\t\treturn type < arg.type; //長さが同じなら、LEFT_UPを左に持ってくる\n\t\t}\n\t}\n\tType type;\n\tshort max_len,loc;\n};\n\nint H,W,min_len,P;\nint BIT_MAX;\nshort LIMIT[2][NUM][NUM];\nint BIT[2][NUM];\nbool table[NUM][NUM];\nshort dp[NUM][NUM];\n\n\nvoid add(Type type,int loc,int value){\n\n\tBIT[type][loc] += value;\n\n\tloc += loc & -loc; //最後の1ビットを足した場所が次の★更新★場所\n\n\twhile(loc <= BIT_MAX){\n\t\tBIT[type][loc] += value;\n\t\tloc += loc & -loc;\n\t}\n}\n\nint getSum(Type type,int loc){\n\n\tint sum = BIT[type][loc];\n\n\tloc -= loc & -loc; //最後の1ビットを引いた場所が次の★加算★場所\n\n\twhile(loc > 0){\n\t\tsum += BIT[type][loc];\n\t\tloc -= loc & -loc;\n\t}\n\treturn sum;\n}\n\nint calc(Type type,int left,int right){ //left~rightの区間の総和を、sum(1~right)-sum(1~left-1)で求める\n\treturn getSum(type,right)-getSum(type,left-1);\n}\n\nvoid init_LIMIT(Type type){\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tLIMIT[type][row][col] = NUM;\n\t\t}\n\t}\n}\n\nvoid update_LIMIT(Type type){\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tLIMIT[type][row][col] = min(LIMIT[type][row][col],dp[row][col]);\n\t\t}\n\t}\n}\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1){\n\t\treturn true;\n\t}else{\n\t\treturn false;\n\t}\n}\n\nint main(){\n\n\tscanf(\"%d %d %d %d\",&H,&W,&min_len,&P);\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\ttable[row][col] = true;\n\t\t}\n\t}\n\n\tint tmp_row,tmp_col;\n\n\tfor(int loop = 0; loop < P; loop++){\n\n\t\tscanf(\"%d %d\",&tmp_row,&tmp_col);\n\t\ttmp_row--;\n\t\ttmp_col--;\n\t\ttable[tmp_row][tmp_col] = false;\n\t}\n\n\t/*★各場所からの最大長を計算する★*/\n\n\t/*左上基準*/\n\tinit_LIMIT(LEFT_UP);\n\n\t//右方向への最大長さ\n\tfor(int row = 0; row < H; row++){\n\t\tif(table[row][W-1]){\n\t\t\tdp[row][W-1] = 1;\n\t\t}else{\n\t\t\tdp[row][W-1] = 0;\n \t\t}\n\t}\n\n\tfor(int col = W-2; col >= 0; col--){\n\t\tfor(int row = 0; row < H; row++){\n\t\t\tif(table[row][col]){\n\t\t\t\tdp[row][col] = dp[row][col+1]+1;\n\t\t\t}else{\n\t\t\t\tdp[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tupdate_LIMIT(LEFT_UP);\n\n\t//下方向への最大長さ\n\tfor(int col = 0; col < W; col++){\n\t\tif(table[H-1][col]){\n\t\t\tdp[H-1][col] = 1;\n\t\t}else{\n\t\t\tdp[H-1][col] = 0;\n\t\t}\n\t}\n\n\tfor(int row = H-2; row >= 0; row--){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(table[row][col]){\n\t\t\t\tdp[row][col] = dp[row+1][col]+1;\n\t\t\t}else{\n\t\t\t\tdp[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tupdate_LIMIT(LEFT_UP);\n\n\t/*右下基準*/\n\tinit_LIMIT(RIGHT_UNDER);\n\n\t//左方向への最大長さ\n\tfor(int row = 0; row < H; row++){\n\t\tif(table[row][0]){\n\t\t\tdp[row][0] = 1;\n\t\t}else{\n\t\t\tdp[row][0] = 0;\n\t\t}\n\t}\n\n\tfor(int col = 1; col < W; col++){\n\t\tfor(int row = 0; row < H; row++){\n\t\t\tif(table[row][col]){\n\t\t\t\tdp[row][col] = dp[row][col-1]+1;\n\t\t\t}else{\n\t\t\t\tdp[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tupdate_LIMIT(RIGHT_UNDER);\n\n\t//上方向への最大長さ\n\tfor(int col = 0; col < W; col++){\n\t\tif(table[0][col]){\n\t\t\tdp[0][col] = 1;\n\t\t}else{\n\t\t\tdp[0][col] = 0;\n\t\t}\n\t}\n\n\tfor(int row = 1; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(table[row][col]){\n\t\t\t\tdp[row][col] = dp[row-1][col]+1;\n\t\t\t}else{\n\t\t\t\tdp[row][col] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tupdate_LIMIT(RIGHT_UNDER);\n\n\n\tvector<Info> V;\n\tll ans = 0;\n\n\t//斜めのラインごとに計上処理を行う\n\tint start_row = 0,start_col = W-2;\n\tint left,right;\n\n\twhile(true){\n\n\t\tV.clear();\n\t\tBIT_MAX = 0;\n\n\t\ttmp_row = start_row,tmp_col = start_col;\n\t\t//斜めのラインのデータを走査する\n\t\twhile(rangeCheck(tmp_row,tmp_col)){\n\n\t\t\t//★★BIT木は1オリジン★★\n\t\t\tV.push_back(Info(LEFT_UP,LIMIT[LEFT_UP][tmp_row][tmp_col],BIT_MAX+1));\n\t\t\tV.push_back(Info(RIGHT_UNDER,LIMIT[RIGHT_UNDER][tmp_row][tmp_col],BIT_MAX+1));\n\n\t\t\ttmp_row++;\n\t\t\ttmp_col++;\n\t\t\tBIT_MAX++;\n\t\t}\n\n\t\tsort(V.begin(),V.end());\n\n\t\t//BIT木の初期化\n\t\tfor(int i = 0; i <= BIT_MAX; i++){\n\t\t\tBIT[LEFT_UP][i] = 0;\n\t\t\tBIT[RIGHT_UNDER][i] = 0;\n\t\t}\n\n\t\t//最大長が大きい方から、降順に処理する(★★既に1が立っている場所の最大長は、必ず基準の最大長以上となる★★)\n\t\tfor(int i = 0; i < V.size(); i++){\n\t\t\tif(V[i].type == LEFT_UP){\n\t\t\t\t//右方向にある範囲を見に行く\n\t\t\t\tleft = (int)V[i].loc+min_len-1;\n\t\t\t\tright = (int)(V[i].loc+V[i].max_len)-1;\n\n\t\t\t\tif(left <= right){\n\t\t\t\t\tans += calc(RIGHT_UNDER,left,right); //ペアになるものを探す\n\t\t\t\t}\n\n\t\t\t}else{ //V[i].type == RIGHT_UNDER\n\t\t\t\t//左方向にある範囲を見に行く\n\t\t\t\tright = (int)V[i].loc-min_len+1;\n\t\t\t\tleft = (int)(V[i].loc-V[i].max_len)+1;\n\n\t\t\t\tif(left <= right){\n\t\t\t\t\tans += calc(LEFT_UP,left,right);\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tadd(V[i].type,V[i].loc,1);\n\t\t}\n\n\t\tif(start_row == H-2 && start_col == 0){\n\t\t\tbreak;\n\t\t}\n\n\t\tif(start_row == 0){\n\n\t\t\tif(start_col != 0){\n\n\t\t\t\tstart_col--;\n\n\t\t\t}else{\n\n\t\t\t\tstart_row++;\n\t\t\t}\n\n\t\t}else{ //start_col == 0\n\n\t\t\tstart_row++;\n\t\t}\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3060, "memory_kb": 112780, "score_of_the_acc": -0.7548, "final_rank": 14 }, { "submission_id": "aoj_0618_3077139", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<unordered_set>\n#define Min(a,b) a=min(a,b);\n#define lol(i,n) for(ll i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\n#define H 4010\n#define N (1<<12)\nclass RSQ{\nprivate:\n ll dat[N*2];\n ll dfs(int l,int r,int a,int b,int k){\n\tif(l<=a&&b<=r)return dat[k];\n\tif(b<=l||r<=a)return 0;\n\tint vl=dfs(l,r,a,(a+b)/2,k*2+1);\n\tint vr=dfs(l,r,(a+b)/2,b,k*2+2);\n\treturn vl+vr;\n }\npublic:\n void Init(){\n\tlol(i,2*N)dat[i]=0;\n }\n void Update(int i,int x){\n\ti+=N-1;\n\tdat[i]=x;\n\twhile(i>0){\n\t i=(i-1)/2;\n\t dat[i]=dat[i*2+1]+dat[i*2+2];\n\t}\n }\n ll Sum(int l,int r){\n\tif(r>N-2)r=N-2;\n\tif(l>r)return 0;\n\treturn dfs(l,r+1,0,N,0);\n }\n};\nll h,w,p,q;\n//bool t[H][H];\nunordered_set<int> st[H];\nll f[H][H],g[H][H];\nint main(){\n cin>>h>>w>>q>>p;\n lol(i,h)lol(j,w)f[i][j]=g[i][j]=mod;\n lol(i,p){int y,x;cin>>y>>x;st[y-1].insert(x-1);}\n lol(i,h){\n\tll cnt=-1;\n\tlol(j,w){\n\t if(st[i].find(j)!=st[i].end())cnt=-1;\n\t else cnt++;\n\t Min(g[i][j],cnt);\n\t}\n\tcnt=-1;\n\tfor(int j=w-1;j>=0;j--){\n\t if(st[i].find(j)!=st[i].end())cnt=-1;\n\t else cnt++;\n\t Min(f[i][j],cnt);\n\t}\n }\n lol(j,w){\n\tll cnt=-1;\n\tlol(i,h){\n\t if(st[i].find(j)!=st[i].end())cnt=-1;\n\t else cnt++;\n\t Min(f[i][j],cnt);\n\t}\n\tcnt=-1;\n\tfor(int i=h-1;i>=0;i--){\n\t if(st[i].find(j)!=st[i].end())cnt=-1;\n\t else cnt++;\n\t Min(g[i][j],cnt);\n\t}\n }\n ll ans=0;\n lol(r,h+w-1){\n\tint sy,sx;\n\tif(r<h)sy=r,sx=0;\n\telse sy=h-1,sx=r-h+1;\n\tll n=min(min(r+1,h+w-1-r),min(h,w));\n\tvector<pair<ll,ll> >v;\n\tlol(i,n){\n\t int y=sy-i,x=sx+i;\n\t if(g[y][x]==-1)continue;\n\t v.push_back(make_pair(i-g[y][x],i));\n\t}\n\tsort(v.begin(),v.end());\n\tint last=0;\n\tRSQ seg;seg.Init();\n\tlol(i,n){\n\t int y=sy-i,x=sx+i;\n\t if(f[y][x]==-1)continue;\n\t while(last<v.size()){\n\t\tif(v[last].first<=i){\n\t\t seg.Update(v[last].second,1);\n\t\t last++;\n\t\t}\n\t\telse break;\n\t }\n\t ans+=seg.Sum(i+q-1,i+f[y][x]);\n\t}\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 3880, "memory_kb": 258424, "score_of_the_acc": -1.453, "final_rank": 16 }, { "submission_id": "aoj_0618_2899493", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nstruct BIT{\n int t[5000];\n void init(){\n for(int i=0;i<5000;i++){\n t[i]=0;\n }\n }\n void add(int i,int x){\n i+=10;\n \n while( i<5000 ){\n t[i]+=x;\n i+=(i&-i);\n }\n }\n int sum(int i){\n i+=10;\n \n int res=0;\n while(i>0){\n res+=t[i];\n i-=(i&-i);\n }\n return res;\n }\n};\n\nBIT T;\nint H,W,L,P;\nshort t[4000][4000];\n\nshort A[4000][4000];\nshort B[4000][4000];\nshort C[4000][4000];\nshort D[4000][4000];\n\nvector< short > G[5000];\n\nll solve(int y,int x){\n for(int i=0;i<5000;i++)G[i].clear();\n T.init();\n \n ll res=0;\n \n for(int i=0;i<5000;i++){\n int py=y+i;\n int px=x+i;\n if(py>=H || px>=W)break;\n if(i-L+1>=0){\n int ay=py-L+1;\n int ax=px-L+1;\n\n int len = min( C[ay][ax], D[ay][ax]) - 1;\n \n if(i-L+1+len>=i){\n T.add( i-L+1 , 1 );\n G[ i-L+1 + len ].push_back( i-L+1 );\n }\n \n }\n\n int fr=min(A[py][px],B[py][px]);\n \n if(fr>=3){\n ll v = T.sum(4500) - T.sum(i-fr);\n res+=v;\n }\n \n for(int j=0;j<(int)G[i].size();j++){\n T.add( G[i][j], -1 );\n }\n }\n\n return res;\n}\n\nint main(){\n\n scanf(\"%d %d %d %d\",&H,&W,&L,&P);\n for(int i=0;i<P;i++){\n int y,x;\n scanf(\"%d %d\",&y,&x);\n y--,x--;\n \n t[y][x]=1;\n }\n \n for(int i=0;i<H;i++){\n for(int j=0;j<W;j++){\n if(t[i][j]==1){\n A[i][j]=0;\n continue;\n }\n A[i][j]=1;\n if(j>0){\n A[i][j]+=A[i][j-1];\n }\n }\n }\n \n for(int j=0;j<W;j++){ \n for(int i=0;i<H;i++){\n if(t[i][j]==1){\n B[i][j]=0;\n continue;\n }\n B[i][j]=1;\n if(i>0){\n B[i][j]+=B[i-1][j];\n }\n }\n }\n\n \n for(int i=0;i<H;i++){\n for(int j=W-1;j>=0;j--){\n if(t[i][j]==1){\n C[i][j]=0;\n continue;\n }\n C[i][j]=1;\n if(j+1<W){\n C[i][j]+=C[i][j+1];\n }\n }\n }\n \n for(int j=0;j<W;j++){ \n for(int i=H-1;i>=0;i--){\n if(t[i][j]==1){\n D[i][j]=0;\n continue;\n }\n D[i][j]=1;\n if(i+1<H){\n D[i][j]+=D[i+1][j];\n }\n }\n }\n\n ll ans=0;\n for(int i=0;i<H;i++){\n ans+= solve(i,0);\n }\n for(int i=1;i<W;i++){\n ans+= solve(0,i);\n }\n \n printf(\"%lld\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 1790, "memory_kb": 157496, "score_of_the_acc": -0.7386, "final_rank": 13 }, { "submission_id": "aoj_0618_2673507", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\nusing namespace std;\n\ntypedef pair<int,int> P;\n\nint bit[4010];\n\nvoid add(int i,int x){\n\twhile(i < 4010){\n\t\tbit[i] += x;\n\t\ti += i & -i;\n\t}\n}\n\nll get(int i){\n\tll s = 0;\n\twhile(i){\n\t\ts += bit[i];\n\t\ti -= i & -i;\n\t}\n\treturn s;\n}\n\nint h,w,l,p,lu[4000][4000],rd[4000][4000];\nll ans = 0;\nbool field[4000][4000] = {};\n\nsigned main(){\n\tcin >> h >> w >> l >> p;\n\tfor(int i = 0;i < p;i++){\n\t\tint a,b;\n\t\tcin >> a >> b; a--;b--;\n\t\tfield[a][b] = true;\n\t}\n\tfor(int i = 0;i < h;i++){\n\t\tint cnt = 0;\n\t\tfor(int j = 0;j < w;j++){\n\t\t\tif(field[i][j]) cnt = 0;\n\t\t\telse cnt++;\n\t\t\tlu[i][j] = cnt;\n\t\t}\n\t\tcnt = 0;\n\t\tfor(int j = w - 1;j >= 0;j--){\n\t\t\tif(field[i][j]) cnt = 0;\n\t\t\telse cnt++;\n\t\t\trd[i][j] = cnt;\n\t\t}\n\t}\n\tfor(int i = 0;i < w;i++){\n\t\tint cnt = 0;\n\t\tfor(int j = 0;j < h;j++){\n\t\t\tif(field[j][i]) cnt = 0;\n\t\t\telse cnt++;\n\t\t\tlu[j][i] = min(cnt,lu[j][i]);\n\t\t}\n\t\tcnt = 0;\n\t\tfor(int j = h - 1;j >= 0;j--){\n\t\t\tif(field[j][i]) cnt = 0;\n\t\t\telse cnt++;\n\t\t\trd[j][i] = min(cnt,rd[j][i]);\n\t\t}\n\t}\n\tfor(int i = -h + 1;i <= w - 1;i++){\n\t\tfor(int j = 0;j < h;j++) bit[j + 1] = 0;\n\t\tvector<int> vec[4010];\n\t\tfor(int j = 0;j < h;j++){\n\t\t\tif(i + j >= 0 && i + j < w && lu[j][i + j]) vec[j - lu[j][i + j] + 1].push_back(j);\n\t\t}\n\t\tfor(int j = 0;j < h;j++){\n\t\t\tfor(int v : vec[j]) add(v + 1,1);\n\t\t\tif(i + j >= 0 && i + j < w && rd[j][i + j] && j + rd[j][i + j] > j + l - 1) ans += get(j + rd[j][i + j]) - get(j + l - 1);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2070, "memory_kb": 142884, "score_of_the_acc": -0.7235, "final_rank": 12 }, { "submission_id": "aoj_0618_2641210", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <functional>\n#include <vector>\nusing namespace std;\nint H, W, L, P, bit[4009]; bool used[4009][4009]; int lx[4009][4009], rx[4009][4009];\nvoid add(int p, int x) {\n\tp++;\n\twhile (p <= 4009) { bit[p] += x; p += (p&-p); }\n}\nint sum(int p) {\n\tint s = 0; p++;\n\twhile (p >= 1) { s += bit[p]; p -= (p&-p); }\n\treturn s;\n}\nint main() {\n\tcin >> H >> W >> L >> P;\n\tfor (int i = 0; i < P; i++) { int a, b; cin >> a >> b; used[a][b] = true; }\n\tfor (int i = 0; i < 4009; i++) { for (int j = 0; j < 4009; j++) { lx[i][j] = 999999; rx[i][j] = 999999; } }\n\tfor (int i = 1; i <= H; i++) {\n\t\tint s = 0;\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tif (used[i][j] == true)s = 0; else s++;\n\t\t\trx[i][j] = min(rx[i][j], s);\n\t\t}\n\t\ts = 0;\n\t\tfor (int j = W; j >= 1; j--) {\n\t\t\tif (used[i][j] == true)s = 0; else s++;\n\t\t\tlx[i][j] = min(lx[i][j], s);\n\t\t}\n\t}\n\tfor (int i = 1; i <= W; i++) {\n\t\tint s = 0;\n\t\tfor (int j = 1; j <= H; j++) {\n\t\t\tif (used[j][i] == true)s = 0; else s++;\n\t\t\trx[j][i] = min(rx[j][i], s);\n\t\t}\n\t\ts = 0;\n\t\tfor (int j = H; j >= 1; j--) {\n\t\t\tif (used[j][i] == true)s = 0; else s++;\n\t\t\tlx[j][i] = min(lx[j][i], s);\n\t\t}\n\t}\n\tint Z = max(H, W); long long ans = 0;\n\tfor (int i = -Z; i <= Z; i++) {\n\t\tvector<pair<int, int>>V;\n\t\tfor (int j = 1; j <= H; j++) {\n\t\t\tint cx = j, cy = j + i; if (cy <= 0 || cy > W)continue;\n\t\t\tV.push_back(make_pair(cx, cy));\n\t\t}\n\t\tif (V.size() < L)continue;\n\t\tvector<pair<int, int>>U;\n\t\tfor (int j = 0; j < V.size(); j++) {\n\t\t\tU.push_back(make_pair(rx[V[j].first][V[j].second] - j, j));\n\t\t}\n\t\tsort(U.begin(), U.end(), greater<pair<int, int>>());\n\t\tint cx = 0;\n\t\tfor (int j = 0; j < 4009; j++)bit[j] = 0;\n\t\tfor (int j = 0; j < V.size(); j++) {\n\t\t\twhile (cx < U.size() && U[cx].first >= -j) { add(U[cx].second, 1); cx++; }\n\t\t\tint l = j + L - 1, r = j + lx[V[j].first][V[j].second] - 1;\n\t\t\tif (l > r)continue;\n\t\t\tans += sum(r) - sum(l - 1);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2040, "memory_kb": 143396, "score_of_the_acc": -0.7209, "final_rank": 11 }, { "submission_id": "aoj_0618_2625765", "code_snippet": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <cmath>\n#include <iomanip>\n#include <cassert>\n#include <bitset>\nusing namespace std;\n\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i=0; i<(n); i++)\n#define all(c) (c).begin(), (c).end()\n#define uniq(c) c.erase(unique(all(c)), (c).end())\n#define index(xs, x) (int)(lower_bound(all(xs), x) - xs.begin())\n#define _1 first\n#define _2 second\n#define pb push_back\n#define INF 1145141919\n#define MOD 1000000007\nbool S[4000];\nint B[4001];\nvoid BIT_add(int i) {\n for (int x=i+1; x<=4000; x+=x&-x) B[x]++;\n}\nint BIT_sum(int i) {\n int s = 0;\n for (int x=i+1; x>0; x-=x&-x) s += B[x];\n return s;\n}\n\nint H, W, L, N;\nvector<int> GX[4000], GY[4000];\nint GXh[4000], GYh[4000];\n\nsigned main() {\n ios::sync_with_stdio(false); cin.tie(0);\n cin >> H >> W >> L >> N;\n rep(i, N) {\n int x, y;\n cin >> y >> x;\n x--, y--;\n GX[y].pb(x);\n GY[x].pb(y);\n }\n rep(y, H) sort(all(GX[y]));\n rep(x, W) sort(all(GY[x]));\n\n long long ctr = 0;\n for (int d=1-H; d<W; d++) {\n int bx = 0, by = 0;\n if (d < 0) by = -d;\n else bx = d;\n int len = min(H-by, W-bx);\n rep(x, W) GYh[x] = (int)GY[x].size()-1;\n rep(y, H) GXh[y] = (int)GX[y].size()-1;\n rep(i, 4000) S[i] = 0;\n rep(i, 4001) B[i] = 0;\n auto add = [&](int x, int y) {\n int s = max(x-bx, y-by);\n if (S[s]) return;\n S[s] = 1;\n BIT_add(s);\n };\n\n for (int s=len-1; s>=0; s--) {\n int x = bx+s, y = by+s;\n int mx = W, my = H;\n while (GXh[y] >= 0 && GX[y][GXh[y]] >= x) add(mx=GX[y][GXh[y]--], y);\n while (GYh[x] >= 0 && GY[x][GYh[x]] >= y) add(x, my=GY[x][GYh[x]--]);\n int X = min(mx-bx, my-by);\n // count [s+L-1, X)\n if (s+L-1 >= X) continue;\n //cout<< \"(\"<<x<<\",\"<<y<<\"): [\"<<s+L-1<<\",\"<<X<<\") | \"; rep(i, W) cout<<S[i]<<\",\";cout<<\"\\n\";\n //for (int p=s+L-1; p<X; p++) ctr += 1-S[p];\n ctr += (X-(s+L-1)) - (BIT_sum(X-1) - BIT_sum(s+L-2));\n }\n }\n cout << ctr << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 1740, "memory_kb": 4668, "score_of_the_acc": -0.1288, "final_rank": 1 }, { "submission_id": "aoj_0618_2623332", "code_snippet": "#include <bits/stdc++.h>\n using namespace std;\n using LL = long long;\n\n short H,W,L;\n int P;\n\n const int N_MAX = 4001;\n\n short la[N_MAX][N_MAX];\n short ra[N_MAX][N_MAX];\n short ua[N_MAX][N_MAX];\n short da[N_MAX][N_MAX];\n\n struct BIT{\n \tvector<int>seg;\n \tint width;\n \tBIT(int n):width(1){\n \t\twhile(width < n)width *= 2;\n \t\tseg.resize(width + 1);\n \t}\n \tvoid add(int x,int val){\n \t\tx++;\n \t\twhile(x <= width){\n \t\t\tseg[x] += val;\n \t\t\tx += (x & -x);\n \t\t}\n \t}\n \tint range(int x){\n \t\tint res = 0;\n \t\twhile(x > 0){\n \t\t\tres += seg[x];\n \t\t\tx -= (x & -x);\n \t\t}\n \t\treturn res;\n \t}\n };\n\n int main(){\n \tcin >> H >> W >> L >> P;\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tla[i][j] = ra[i][j] = ua[i][j] = da[i][j] = 6666;\n \t\t}\n \t}\n \tfor(int i = 0;i < P;++i){\n \t\tshort a,b;\n \t\tcin >> a >> b;\n \t\t--a;--b;\n \t\tla[a][b] = ra[a][b] = ua[a][b] = da[a][b] = 0;\n \t}\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tla[i][j] = min(la[i][j],(short)((j)?(la[i][j-1]+(short)1):(short)1));\n \t\t}\n \t}\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = W - 1;j >= 0;--j){\n \t\t\tra[i][j] = min(ra[i][j],(short)(ra[i][j+1]+(short)1));\n \t\t}\n \t}\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tua[i][j] = min(ua[i][j],(short)((i)?(ua[i-1][j]+(short)1):(short)1));\n \t\t}\n \t}\n \tfor(int i = H - 1;i >= 0;--i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tda[i][j] = min(da[i][j],(short)(da[i+1][j]+(short)1));\n \t\t}\n \t}\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tra[i][j] = min(ra[i][j],da[i][j]);\n \t\t}\n \t}\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tla[i][j] = min(la[i][j],ua[i][j]);\n \t\t}\n \t}\n \tvector<vector<short>>pos(H),neg(W-1);\n \tvector<vector<short>>pro(H),nro(W-1);\n \tfor(int i = 0;i < H;++i){\n \t\tfor(int j = 0;j < W;++j){\n \t\t\tif(i - j >= 0){\n \t\t\t\tpos[i - j].push_back(la[i][j]-pos[i - j].size()-1);\n \t\t\t\tpro[i - j].push_back(ra[i][j]);\n \t\t\t}else{\n \t\t\t\tneg[j - i - 1].push_back(la[i][j]-pos[j - i - 1].size()-1);\n \t\t\t\tnro[j - i - 1].push_back(ra[i][j]);\n \t\t\t}\n \t\t}\n \t}\n \tlong long ans = 0;\n\n \tfor(int k = 0;k < H;++k){\n \t\tBIT bit(pos.size());\n \t\tpriority_queue<pair<int,int>>que;\n \t\tfor(int i = 0;i < pos[k].size();++i){\n \t\t\tque.push(make_pair((int)pos[k][i],i));\n \t\t}\n \t\tfor(int i = 0;i < pos[k].size();++i){\n \t\t\twhile(!que.empty() && que.top().first >= -i){\n \t\t\t\tbit.add(que.top().second,1);\n \t\t\t\tque.pop();\n \t\t\t}\n \t\t\tint dn = i + L - 1;dn = min(dn,(int)pos[k].size());\n \t\t\tint up = i + pro[k][i];\n \t\t\tif(dn < up){\n \t\t\t\tint ub = bit.range(up);\n \t\t\t\tint db = bit.range(dn);\n \t\t\t\tint can = ub - db;\n \t\t\t\tans += (long long)can;\n \t\t\t}\n \t\t}\n \t}\n\n \tfor(int k = 0;k < W-1;++k){\n \t BIT bit(neg.size());\n \t priority_queue<pair<int,int>>que;\n \t for(int i = 0;i < neg[k].size();++i){\n \t \tque.push(make_pair((int)neg[k][i],i));\n \t }\n \t for(int i = 0;i < neg[k].size();++i){\n \t \twhile(!que.empty() && que.top().first >= -i){\n \t \t\t\tbit.add(que.top().second,1);\n \t \t\t\tque.pop();\n \t \t}\n \t \tint dn = i + L - 1;dn = min(dn,(int)neg[k].size());\n \t \t\tint up = i + nro[k][i];\n \t \tif(dn < up){\n \t \t\tint can = bit.range(up) - bit.range(dn);\n \t \t\tans += (long long)can;\n \t \t\t}\n \t \t}\n \t}\n \tcout << ans << endl;\n \treturn 0;\n }", "accuracy": 0.06666666666666667, "time_ms": 1850, "memory_kb": 213088, "score_of_the_acc": -0.9668, "final_rank": 19 } ]
aoj_0622_cpp
JOI国のお散歩事情 (Walking in JOI Kingdom) 問題 JOI 国には東西に走る 1 本の十分に長い道路がある.JOI 国の王宮が道路沿いにあり,JOI 国における道路沿いの位置は整数 A で表される.A = 0 のときは王宮の位置を表す.A > 0 のときは,王宮から東へ A メートル進んだ位置を表す.A < 0 のときは,王宮から西へ -A メートル進んだ位置を表す. JOI 国の道路沿いには N 軒の家があり,家には西から順に 1 から N までの番号が付けられている.JOI 国には N 人の国民がいて,国民には 1 から N までの番号が付けられている.家 i には国民 i が住んでいる.家 i の位置は 0 でない偶数 A i で表される.A 1 , ..., A N は全て異なる. JOI 国では,近年国民の運動不足が問題になっている.国民の健康が気になった JOI 国の王様は,国民全員に散歩をする命令を出した.王様が命令を出すと,全ての国民は一斉に東向きまたは西向きに歩き始める.それぞれの国民がどちらの向きに歩き始めるかは,国民ごとに決まっている.全ての国民は,歩くときは 1 秒あたり 1 メートルの速度で歩く. JOI 国の国民は皆おしゃべりが大好きである.散歩の途中にほかの国民に出会うと,その場所で立ち止まって世間話を始めてしまう.すでに立ち止まっている国民に出会った場合も同様である.一度立ち止まった国民は,再び歩き出すことはない. JOI 国には Q 人の重要人物がいる.JOI 国の王様は,命令が出されてから T 秒後の,Q 人の重要人物の位置を把握しておきたい.命令が出されてから T 秒後の,Q 人の重要人物の位置を求めるプログラムを作成せよ. 入力 入力は,1 + N + Q 行からなる. 1 行目には,3 つの整数 N,T,Q (1 ≦ N ≦ 100000 (= 10 5 ), 0 ≦ T ≦ 10 18 , 1 ≦ Q ≦ 1000,1 ≦ Q ≦ N) が空白を区切りとして書かれている.これは,JOI 国に家が N 軒あり,王様が命令を出してから T 秒後の,Q 人の重要人物の位置を把握しておきたいことを表す. 続く N 行のうち i 行目には,2 つの整数 A i , D i (-10 18 ≦ A i ≦ 10 18 , A i は 0 でない偶数, 1 ≦ D i ≦ 2) が空白を区切りとして書かれている.A i は家 i の位置を表す偶数である.すべての i (1 ≦ i ≦ N - 1) について,A i < A i+1 を満たす.D i は命令が出された後に国民 i が歩き始める方向を表す.D i = 1 のときは国民 i は東向きに歩き始める.D i = 2 のときは国民 i は西向きに歩き始める. 続く Q 行のうち i 行目には,整数 X i (1 ≦ X i ≦ N) が書かれている.これは,i 番目の重要人物が家 X i に住んでいることを表す.すべての i (1 ≦ i ≦ Q - 1) について,X i < X i+1 を満たす. 与えられる 5 つの入力データのうち,入力 1 では N ≦ 100,T ≦ 10000を満たす.また,入力 2 では N ≦ 5000 を満たす.また,入力 3 では,ある整数 M (1 ≦ M ≦ N - 1) があって,すべての i (1 ≦ i ≦ M) について D i = 1,すべての j (M + 1 ≦ j ≦ N) について D j = 2 を満たす.また,入力 1,2,3 では,入力に与えられる整数の絶対値は 1000000000 (= 10 9 ) を超えない.入力 4,5 では,与えられる整数が 32 ビット符号付き整数の範囲に収まらないことに注意せよ. 出力 出力は Q 行からなる. i 行目 (1 ≦ i ≦ Q) には,王様が命令を出してから T 秒後の,i 番目の重要人物の位置を表す整数を出力せよ.この値が整数であることは,問題文の条件より保証されている. 入出力例 入力例 1 5 5 3 -8 1 -4 2 -2 2 4 2 10 1 1 3 5 出力例 1 -6 -6 15 入力例 2 7 18 5 -100 1 -56 2 -34 1 -30 1 -22 1 -4 2 18 2 1 3 4 5 7 出力例 2 -82 -16 -13 -13 0 情報オリンピック日本委員会作 『第 15 回日本情報オリンピック JOI 2015/2016 予選競技課題』
[ { "submission_id": "aoj_0622_9026820", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),T=in(),Q=in();\n\tvll E,W;\n\tvector<pair<ll,ll>> A(N);\n\tREP(i,N){\n\t\tauto P=in(),D=in();\n\t\tif(D==1) E.push_back(P);\n\t\telse W.push_back(P);\n\t\tA[i].first=P;\n\t\tA[i].second=D;\n\t}\n\tsort(ALL(E));\n\tsort(ALL(W));\n\n\tmap<ll,ll> C;\n\tREP(i,E.size()){\n\t\tauto res = lower_bound(ALL(W),E[i]);\n\t\tif(res==W.end()) continue;\n\t\tC[*res] = E[i];\n\t}\n\tvll S;\n\tfor(auto [w,e]:C){\n\t\tll sp=(w+e)/2ll;\n\t\tS.emplace_back(sp);\n\t}\n\tsort(ALL(S));\n\n\tLOOP(Q){\n\t\tauto X=in()-1;\n\t\tif(A[X].second==1){\n\t\t\tauto res = lower_bound(ALL(S),A[X].first);\n\t\t\tif(res==S.end()){\n\t\t\t\tout(A[X].first+T);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif((*res)-A[X].first<=T){\n\t\t\t\t\tout(*res);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tout(A[X].first+T);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tauto res = lower_bound(ALL(S),A[X].first);\n\t\t\tif(res==S.begin()){\n\t\t\t\tout(A[X].first-T);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tres--;\n\t\t\t\tif(A[X].first-(*res)<=T){\n\t\t\t\t\tout(*res);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tout(A[X].first-T);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7284, "score_of_the_acc": -0.2043, "final_rank": 18 }, { "submission_id": "aoj_0622_9000925", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, T, Q;\n cin >> N >> T >> Q;\n vi A(N+2), D(N+2), X(Q);\n rep(i, 1, N+1) cin >> A[i] >> D[i];\n A[0] = -inf;\n D[0] = 1;\n A[N+1] = inf;\n D[N+1] = 2;\n rep(i, Q) cin >> X[i];\n vi p(N+2);\n rep(i, N+1) {\n if ((D[i] == 1) and (D[i+1] == 2)) {\n ll t = (A[i] + A[i+1]) / 2;\n rrep(j, 0, i+1) {\n if (D[j] == 1) p[j] = t;\n else break;\n }\n rep(j, i+1, N+2) {\n if (D[j] == 2) p[j] = t;\n else break;\n }\n }\n }\n rep(i, Q) {\n ll j = X[i];\n if (D[j] == 1) {\n print(min(A[j]+T, p[j]));\n } else {\n print(max(A[j]-T, p[j]));\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5404, "score_of_the_acc": -0.076, "final_rank": 17 }, { "submission_id": "aoj_0622_8860241", "code_snippet": "#include <iostream>\n#include <vector>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n vector<ll> people(1001);\n vector<ll> A(100001);\n vector<int> D(100001);\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4388, "score_of_the_acc": -0.012, "final_rank": 4 }, { "submission_id": "aoj_0622_8860237", "code_snippet": "#include <iostream>\n#include <limits.h>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n\n vector<ll> people(Q);\n vector<ll> A(N);\n vector<int> D(N);\n\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n \n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n\n ll east = MIN;\n ll west = MIN;\n ll t;\n \n for (int i = 0; i < Q; i++) {\n ll person = people[i];\n ll person_pos = A[person];\n int direction = D[person];\n\n if (direction == 1) {\n east = person_pos;\n \n for (ll j = person + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n \n if (T < abs(t - person_pos)) {\n cout << person_pos + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = person_pos;\n \n for (ll j = person - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n \n if (T < abs(person_pos - t)) {\n cout << person_pos - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4392, "score_of_the_acc": -0.0123, "final_rank": 6 }, { "submission_id": "aoj_0622_8838106", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing std::cin;\nusing std::cout;\nusing std::endl;\n\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\n\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n\n ll* people = new ll[Q];\n ll* A = new ll[N];\n int* D = new int[N];\n\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n\n ll east = MIN;\n ll west = MIN;\n ll t;\n ll abs_diff;\n\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n ll max_east = east;\n\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n max_east = east > max_east ? east : max_east;\n } else {\n t = (max_east + A[j]) / 2;\n break;\n }\n }\n\n abs_diff = abs(t - A[people[i]]);\n if (T < abs_diff) {\n cout << A[people[i]] + T << endl;\n } else {\n cout << t << endl;\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n\n abs_diff = abs(A[people[i]] - t);\n if (T < abs_diff) {\n cout << A[people[i]] - T << endl;\n } else {\n cout << t << endl;\n }\n }\n }\n\n delete[] people;\n delete[] A;\n delete[] D;\n\n return 0;\n}", "accuracy": 0.6, "time_ms": 50, "memory_kb": 4356, "score_of_the_acc": -0.0203, "final_rank": 19 }, { "submission_id": "aoj_0622_8820892", "code_snippet": "#include <iostream>\n#include <vector>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\n\nint main() {\n std::ios::sync_with_stdio(false);\n cin.tie(NULL);\n\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n\n std::vector<ll> people(Q);\n std::vector<ll> A(N);\n std::vector<int> D(N);\n\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n\n // Fill people array in the same loop where its elements are read\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n\n ll east = MIN;\n ll west = MIN;\n ll t = 0;\n\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4388, "score_of_the_acc": -0.012, "final_rank": 4 }, { "submission_id": "aoj_0622_8820886", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll A[100001];\n int D[100001];\n ll east, west, t;\n ll results[1001];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n int people;\n cin >> people;\n people--;\n if (D[people] == 1) {\n east = A[people];\n for (ll j = people + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people])) {\n results[i] = A[people] + T;\n } else {\n results[i] = t;\n }\n } else {\n west = A[people];\n for (ll j = people - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people] - t)) {\n results[i] = A[people] - T;\n } else {\n results[i] = t;\n }\n }\n }\n for (int i = 0; i < Q; i++) {\n cout << results[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4532, "score_of_the_acc": -0.032, "final_rank": 13 }, { "submission_id": "aoj_0622_8820882", "code_snippet": "#include <iostream>\n#include <limits.h>\n#include <vector>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n vector<ll> people(Q);\n vector<ll> A(N);\n vector<int> D(N);\n for (int i = 0; i < N; ++i) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; ++i) {\n cin >> people[i];\n --people[i];\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; ++i) {\n ll diff;\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; ++j) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n diff = abs(t - A[people[i]]);\n if (T < diff) {\n cout << A[people[i]] + T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; --j) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n diff = abs(A[people[i]] - t);\n if (T < diff) {\n cout << A[people[i]] - T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4392, "score_of_the_acc": -0.0227, "final_rank": 8 }, { "submission_id": "aoj_0622_8820879", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll people[1001];\n ll A[100001];\n int D[100001];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n --people[i];\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n ll current_person = A[people[i]];\n if (D[people[i]] == 1) {\n east = current_person;\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - current_person)) {\n cout << current_person + T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n } else {\n west = current_person;\n for (ll j = people[i] - 1; j >= 0; --j) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(current_person - t)) {\n cout << current_person - T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4628, "score_of_the_acc": -0.0279, "final_rank": 11 }, { "submission_id": "aoj_0622_8808592", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\n\nint main() {\n int N, Q;\n int T;\n cin >> N >> T >> Q;\n int* people = new int[Q];\n int* A = new int[N];\n int* D = new int[N];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n int t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n int east = A[people[i]];\n for (int j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << endl;\n } else {\n cout << t << endl;\n }\n } else {\n int west = A[people[i]];\n for (int j = people[i] - 1; j >= 0; j--) {\n if (D[j] != 1) {\n west = A[j];\n } else {\n t = (west + A[j]) / 2;\n break;\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << endl;\n } else {\n cout << t << endl;\n }\n }\n }\n delete[] people;\n delete[] A;\n delete[] D;\n return 0;\n}", "accuracy": 0.6, "time_ms": 2880, "memory_kb": 19316, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0622_8808586", "code_snippet": "#include <iostream>\n\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll people[1001];\n ll A[100001];\n int D[100001];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n \n ll east, west, t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) >> 1;\n break;\n }\n }\n ll diff = abs(t - A[people[i]]);\n if (T < diff) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) >> 1;\n break;\n } else {\n west = A[j];\n }\n }\n ll diff = abs(A[people[i]] - t);\n if (T < diff) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4504, "score_of_the_acc": -0.0301, "final_rank": 12 }, { "submission_id": "aoj_0622_8808585", "code_snippet": "#include <iostream>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll people[1001];\n ll A[100001];\n int D[100001];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n ll east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) >> 1;\n break;\n }\n }\n ll diff = abs(t - A[people[i]]);\n if (T < diff) {\n cout << A[people[i]] + T << endl;\n } else {\n cout << t << endl;\n }\n } else {\n ll west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) >> 1;\n break;\n } else {\n west = A[j];\n }\n }\n ll diff = abs(A[people[i]] - t);\n if (T < diff) {\n cout << A[people[i]] - T << endl;\n } else {\n cout << t << endl;\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4600, "score_of_the_acc": -0.0365, "final_rank": 14 }, { "submission_id": "aoj_0622_8808584", "code_snippet": "#include <iostream>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n\n ll *people = new ll[Q];\n ll *A = new ll[N];\n int *D = new int[N];\n\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n ll east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n ll diff = abs(t - A[people[i]]);\n if (T < diff) {\n cout << A[people[i]] + T << endl;\n } else {\n cout << t << endl;\n }\n } else {\n ll west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n ll diff = abs(A[people[i]] - t);\n if (T < diff) {\n cout << A[people[i]] - T << endl;\n } else {\n cout << t << endl;\n }\n }\n }\n\n delete[] people;\n delete[] A;\n delete[] D;\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4396, "score_of_the_acc": -0.023, "final_rank": 9 }, { "submission_id": "aoj_0622_8716174", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <iomanip>\n#include <utility>\n#include <tuple>\n#include <cmath>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <cassert>\n#include <functional>\n#include <numeric>\n#include <type_traits>\n#include <optional>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < n; i++)\n#define ll long long\n#define coutf(f) cout << fixed << setprecision(f)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n\nint main() {\n\tconst ll INF = 1LL << 60;\n\tll n, t, q;\n\tcin >> n >> t >> q;\n\tvector<ll> a(n), d(n);\n\trep(i, n) cin >> a[i] >> d[i];\n\tvector<ll> col;\n\tcol.push_back(-INF);\n\trep(i, n - 1) {\n\t\tif (d[i] == 1 && d[i+1] == 2) {\n\t\t\tcol.push_back((a[i] + a[i + 1]) / 2);\n\t\t}\n\t}\n\tcol.push_back(INF);\n\trep(i, q) {\n\t\tint x;\n\t\tcin >> x;\n\t\tx--;\n\t\tif (d[x] == 1) {\n\t\t\tauto iter = lower_bound(all(col), a[x]);\n\t\t\tcout << min(*iter, a[x] + t) << endl;\n\t\t}\n\t\telse {\n\t\t\tauto iter = upper_bound(all(col), a[x]);\n\t\t\titer--;\n\t\t\tcout << max(*iter, a[x] - t) << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5068, "score_of_the_acc": -0.0676, "final_rank": 16 }, { "submission_id": "aoj_0622_8215136", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll* people = new ll[Q];\n ll* A = new ll[N];\n int* D = new int[N];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n delete[] people;\n delete[] A;\n delete[] D;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4396, "score_of_the_acc": -0.0125, "final_rank": 7 }, { "submission_id": "aoj_0622_8215135", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll* A = new ll[N];\n int* D = new int[N];\n ll* people = new ll[Q];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (int j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n } else {\n west = A[people[i]];\n for (int j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n }\n }\n delete[] A;\n delete[] D;\n delete[] people;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4344, "score_of_the_acc": -0.0091, "final_rank": 3 }, { "submission_id": "aoj_0622_8215134", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n ios_base::sync_with_stdio(false); \n cin.tie(NULL);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll *people = new ll[Q];\n ll *A = new ll[N];\n int *D = new int[N];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n int k = people[i];\n if (D[k] == 1) {\n east = A[k];\n for (ll j = k + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[k])) {\n cout << A[k] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[k];\n for (ll j = k - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[k] - t)) {\n cout << A[k] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n delete[] people;\n delete[] A;\n delete[] D;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4324, "score_of_the_acc": -0.0077, "final_rank": 2 }, { "submission_id": "aoj_0622_8215133", "code_snippet": "#include <iostream>\n#include <limits.h>\nusing namespace std;\nusing ll = long long;\nconstexpr ll MIN = -(LLONG_MAX - 1);\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n ll people[1001];\n ll A[100001];\n int D[100001];\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] != 1) {\n t = (east + A[j]) / 2;\n break;\n }\n east = A[j];\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n ll west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n }\n west = A[j];\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4640, "score_of_the_acc": -0.0252, "final_rank": 10 }, { "submission_id": "aoj_0622_8215132", "code_snippet": "#include <iostream>\n#include <limits.h>\n#include <vector>\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(LONG_LONG_MAX - 1);\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n vector<ll> people(Q);\n vector<ll> A(N);\n vector<int> D(N);\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << \"\\n\";\n } else {\n cout << t << \"\\n\";\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4260, "score_of_the_acc": -0.0035, "final_rank": 1 }, { "submission_id": "aoj_0622_8215129", "code_snippet": "#include <iostream>\n#include <vector>\n#include <limits>\n\nusing namespace std;\nusing ll = long long;\nconst ll MIN = -(numeric_limits<ll>::max() - 1);\n\nint main() {\n int N, Q;\n ll T;\n cin >> N >> T >> Q;\n vector<ll> people(Q), A(N), D(N);\n for (int i = 0; i < N; i++) {\n cin >> A[i] >> D[i];\n }\n for (int i = 0; i < Q; i++) {\n cin >> people[i];\n people[i]--;\n }\n ll east = MIN;\n ll west = MIN;\n ll t;\n for (int i = 0; i < Q; i++) {\n if (D[people[i]] == 1) {\n east = A[people[i]];\n for (ll j = people[i] + 1; j < N; j++) {\n if (D[j] == 1) {\n east = A[j];\n } else {\n t = (east + A[j]) / 2;\n break;\n }\n }\n if (T < abs(t - A[people[i]])) {\n cout << A[people[i]] + T << '\\n';\n } else {\n cout << t << '\\n';\n }\n } else {\n west = A[people[i]];\n for (ll j = people[i] - 1; j >= 0; j--) {\n if (D[j] == 1) {\n t = (west + A[j]) / 2;\n break;\n } else {\n west = A[j];\n }\n }\n if (T < abs(A[people[i]] - t)) {\n cout << A[people[i]] - T << '\\n';\n } else {\n cout << t << '\\n';\n }\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4660, "score_of_the_acc": -0.0405, "final_rank": 15 } ]
aoj_0623_cpp
ゾンビ島 (Zombie Island) 問題 JOI 君が住んでいる島がゾンビに侵略されてしまった.JOI 君は島で一番安全な避難場所として設定されているシェルターに逃げ込むことにした. JOI 君が住んでいる島は町 1 から町 N までの N 個の町からなり,町と町とは道路で結ばれている.島には M 本の道路があり,すべての道路は異なる 2 つの町を結んでいる.JOI 君は道路を双方向に自由に移動できるが,道路以外を通って町から別の町に行くことはできない. いくつかの町はゾンビに支配されており,訪れることが出来ない.ゾンビに支配されている町から S 本以下の道路を使って到達できる町を 危険な町 という.それ以外の町を 危険でない町 という. JOI 君の家は町 1 にあり,避難先のシェルターは町 N にある.町 1,町 N はゾンビに支配されていない.島の道路は移動するのに時間がかかるので,JOI 君は町を移動するたびに,移動先の町で一晩宿泊しなければならない.JOI 君は,危険でない町で宿泊する場合は宿泊費が P 円の安い宿に泊まるが,危険な町で宿泊する場合はセキュリティのサービスが優良な宿泊費が Q 円の高級宿に泊まる.JOI 君はできるだけ宿泊費が安くなるように移動して,町 N まで避難したい.町 1 や町 N では宿泊する必要はない. JOI 君が 町 1 から町 N まで移動するときに必要な宿泊費の合計の最小値を求めよ. 入力 入力は 2 + K + M 行からなる. 1 行目には,4 つの整数 N, M, K, S (2 ≦ N ≦ 100000, 1 ≦ M ≦ 200000, 0 ≦ K ≦ N - 2, 0 ≦ S ≦ 100000) が空白を区切りとして書かれている.これは,島が N 個の町と M 本の道路からなり,N 個の町のうち K 個の町がゾンビに支配されており,ゾンビに支配されている町から S 本以下の道路を使って到達できる町を危険な町と呼ぶことを表す. 2 行目には,2 つの整数 P, Q (1 ≦ P < Q ≦ 100000) が空白を区切りとして書かれている.これは,JOI 君が危険でない町では宿泊費が P 円の宿に泊まり,危険な町では宿泊費が Q 円の宿に泊まることを表す. 続く K 行のうちの i 行目 (1 ≦ i ≦ K) には,整数 C i (2 ≦ C i ≦ N - 1) が書かれている.これは,町 C i がゾンビに支配されていることを表す.C 1 , ..., C K は全て異なる. 続く M 行のうちの j 行目 (1 ≦ j ≦ M) には,2 つの整数 A j , B j (1 ≦ A j < B j ≦ N) が空白を区切りとして書かれている.これは,町 A j と町 B j との間に道路が存在することを表す.同じ (A j , B j ) の組が 2 回以上書かれていることはない. 与えられる入力データにおいては,町 1 から町 N までゾンビに支配されていない町のみを通って移動できることが保証されている. 出力 JOI 君が町 1 から町 N まで移動するときに必要な宿泊費の合計の最小値を 1 行で出力せよ. 出力が 32 ビット符号付き整数の範囲に収まるとは限らないことに注意せよ. 入出力例 入力例 1 13 21 1 1 1000 6000 7 1 2 3 7 2 4 5 8 8 9 2 5 3 4 4 7 9 10 10 11 5 9 7 12 3 6 4 5 1 3 11 12 6 7 8 11 6 13 7 8 12 13 出力例 1 11000 入力例 2 21 26 2 2 1000 2000 5 16 1 2 1 3 1 10 2 5 3 4 4 6 5 8 6 7 7 9 8 10 9 10 9 11 11 13 12 13 12 15 13 14 13 16 14 17 15 16 15 18 16 17 16 19 17 20 18 19 19 20 19 21 出力例 2 15000 入出力例 1 は,以下の図に対応している.円は町を,線は道路を表す. この場合,町 3,町 4,町 6,町 8,町 12 が危険な町である. 以下のような順番で町を移動すると,宿泊費の合計を最小にできる. 町 1 から町 2 に行く.町 2 で宿泊費が 1000 円の安い宿に宿泊する. 町 2 から町 5 に行く.町 5 で宿泊費が 1000 円の安い宿に宿泊する. 町 5 から町 9 に行く.町 9 で宿泊費が 1000 円の安い宿に宿泊する. 町 9 から町 10 に行く.町 10 で宿泊費が 1000 円の安い宿に宿泊する. 町 10 から町 11 に行く.町 11 で宿泊費が 1000 円の安い宿に宿泊する. 町 11 から町 12 に行く.町 12 で宿泊費が 6000 円の高級宿に宿泊する. 町 12 から町 13 に行く.町 13 では宿泊しない. JOI 君がこのような経路で移動したとき,宿泊費の合計は 11000 円になるので,11000 を出力する. 情報オリンピック日本委員会作 『第 15 回日本情報オリンピック JOI 2015/2016 予選競技課題』
[ { "submission_id": "aoj_0623_10946351", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing pll = pair<ll, ll>;\n\nconstexpr ll INF = 1e18;\n\nint main() {\n int N, M, K, S;\n ll P, Q;\n cin >> N >> M >> K >> S;\n cin >> P >> Q;\n\n vector<ll> zd(N, INF);\n queue<int> que1;\n for(int i=0; i<K; ++i) {\n int c;\n cin >> c;\n c--;\n que1.push(c);\n zd[c] = 0;\n }\n\n vector<vector<int>> g(N);\n for(int i=0; i<M; ++i) {\n int a, b;\n cin >> a >> b;\n a--; b--;\n g[a].push_back(b);\n g[b].push_back(a);\n }\n\n while(!que1.empty()) {\n int v = que1.front();\n que1.pop();\n for(auto to : g[v]) {\n if(zd[to] == INF) {\n zd[to] = zd[v] + 1;\n que1.push(to);\n }\n }\n }\n\n vector<ll> d(N, INF);\n d[0] = 0;\n priority_queue<pll, vector<pll>, greater<pll>> que;\n que.push(make_pair(0, 0));\n while(!que.empty()) {\n pll p = que.top();\n que.pop();\n int v = p.second;\n if(d[v] < p.first) {\n continue;\n }\n for(auto to : g[v]) {\n if(zd[to] == 0) {\n continue;\n }\n ll cost = to == N-1 ? 0 : (zd[to] > S ? P : Q);\n if(d[to] > d[v] + cost) {\n d[to] = d[v] + cost;\n que.push(make_pair(d[to], to));\n }\n }\n }\n cout << d[N-1] << endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 10988, "score_of_the_acc": -0.0555, "final_rank": 6 }, { "submission_id": "aoj_0623_9961258", "code_snippet": "#define _GLGBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nll N, M, K, S, P, Q, answer = 0;\nll dist[100009], zombie_dist[100009];\nset<ll> G[100009];\n\nint main() {\n cin >> N >> M >> K >> S;\n cin >> P >> Q;\n\n queue<ll> Queue;\n\n for (ll i = 1; i <= N; i++) \n dist[i] = -1LL, zombie_dist[i] = -1LL;\n\n for (ll j = 0; j < K; j++) {\n ll C;\n cin >> C;\n\n Queue.push(C);\n zombie_dist[C] = 0LL;\n }\n\n for (ll l = 0; l < M; l++) {\n ll A, B;\n cin >> A >> B;\n\n G[A].insert(B);\n G[B].insert(A);\n }\n\n while (!Queue.empty()) {\n ll pos = Queue.front();\n Queue.pop();\n for (ll nex : G[pos]) {\n if (\n zombie_dist[nex] == -1LL ||\n zombie_dist[nex] > zombie_dist[pos] + 1LL\n ) {\n zombie_dist[nex] = zombie_dist[pos] + 1LL;\n if (zombie_dist[nex] < S)\n Queue.push(nex);\n }\n }\n }\n\n Queue.push(1LL); dist[1LL] = 0LL;\n\n while (!Queue.empty()) {\n ll pos = Queue.front();\n Queue.pop();\n for (ll nex : G[pos]) {\n if (\n zombie_dist[nex] != 0 && (\n dist[nex] == -1LL ||\n (\n zombie_dist[nex] == -1LL &&\n dist[nex] > dist[pos] + P\n ) || (\n zombie_dist[nex] != -1LL &&\n dist[nex] > dist[pos] + Q\n )\n )\n ) {\n if (zombie_dist[nex] == -1LL)\n dist[nex] = dist[pos] + P;\n else\n dist[nex] = dist[pos] + Q;\n \n Queue.push(nex);\n }\n }\n }\n\n if (zombie_dist[N] == -1)\n cout << dist[N] - P << '\\n';\n else\n cout << dist[N] - Q << '\\n';\n\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 28524, "score_of_the_acc": -0.6996, "final_rank": 12 }, { "submission_id": "aoj_0623_9581748", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n ll N,M,K,S,P,Q;\n cin>>N>>M>>K>>S>>P>>Q;\n vector<ll> dist(N,1e18);\n queue<ll> que;\n for(int i=0;i<K;i++){\n ll c;\n cin>>c;\n c--;\n dist[c]=0;\n que.push(c);\n }\n vector<vll> G(N);\n for(int i=0;i<M;i++){\n int u,v;\n cin>>u>>v;\n u--;v--;\n G[u].push_back(v);\n G[v].push_back(u);\n }\n vector<bool> seen(N,false);\n while(!que.empty()){\n int p=que.front();\n que.pop();\n if(seen[p])continue;\n seen[p]=1;\n for(int v:G[p]){\n if(dist[v]<=dist[p]+1)continue;\n if(seen[v])continue;\n dist[v]=dist[p]+1;\n que.push(v);\n }\n }\n\n seen.assign(N,false);\n priority_queue<pair<ll,ll>,vector<pair<ll,ll>>,greater<pair<ll,ll>>> que2;\n que2.push({0,0});\n vll D(N,1e18);\n D[0]=0;\n while(!que2.empty()){\n auto [c,p]=que2.top();\n que2.pop();\n if(seen[p])continue;\n seen[p]=1;\n for(int v:G[p]){\n if(dist[v]==0)continue;\n ll nc=c+(dist[v]<=S?Q:P);\n if(D[v]<=nc)continue;\n if(seen[v])continue;\n D[v]=nc;\n que2.push({D[v],v});\n }\n }\n cout<<D[N-1]-(dist[N-1]<=S?Q:P)<<endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 13496, "score_of_the_acc": -0.1175, "final_rank": 7 }, { "submission_id": "aoj_0623_9068327", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m, k, s;\n cin >> n >> m >> k >> s;\n ll p, q;\n cin >> p >> q;\n vector<bool> dead(n);\n for (int i = 0; i < k; ++i) {\n int c;\n cin >> c;\n dead[c - 1] = true;\n }\n vector<vector<int>> g(n);\n for (int i = 0; i < m; ++i) {\n int x, y;\n cin >> x >> y;\n x -= 1, y -= 1;\n g[x].push_back(y);\n g[y].push_back(x);\n }\n vector<int> d(n, -1);\n queue<int> que;\n for (int i = 0; i < n; ++i) {\n if (dead[i]) {\n d[i] = 0;\n que.push(i);\n }\n }\n while (que.size()) {\n int ss = que.front();\n que.pop();\n for (int tt : g[ss]) {\n if (d[tt] == -1) {\n d[tt] = d[ss] + 1;\n que.push(tt);\n }\n }\n }\n vector<ll> dp(n, 1e18);\n dp[0] = 0;\n using P = pair<ll, int>;\n priority_queue<P, vector<P>, greater<P>> pq;\n pq.push({0, 0});\n while (pq.size()) {\n auto uo = pq.top();\n pq.pop();\n int cur = uo.second;\n ll cost = uo.first;\n if (dp[cur] != cost) continue;\n for (int nxt : g[cur]) {\n if (dead[nxt]) continue;\n ll cc = (d[nxt] <= s ? q : p);\n if (nxt == n - 1) cc = 0;\n if (dp[nxt] > cost + cc) {\n dp[nxt] = cost + cc;\n pq.push({dp[nxt], nxt});\n }\n }\n }\n cout << dp.back() << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10920, "score_of_the_acc": -0.019, "final_rank": 4 }, { "submission_id": "aoj_0623_9026951", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass ConnectNodeInfo{\n\tvector<vector<pair<ll,ll>>> graph;\npublic:\n\tConnectNodeInfo(int node_num){\n\t\tgraph.resize(node_num);\n\t}\n\tvoid AddNonDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t\tgraph[v].emplace_back(u,w);\n\t}\n\tvoid AddDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t}\n\tvector<pair<ll,ll>>& operator[](ll index){\n\t\treturn graph[index];\n\t}\n\tsize_t size(){ return graph.size(); }\n};\n\nclass Dijkstra{\n\tusing Point = pair<ll,ll>;\n\tvector<ll> dist;\npublic:\n\tvoid CalcShortestPath(int start,ConnectNodeInfo& connect){\n\t\tdist.resize(connect.size(),1LL<<60);\n\t\tdist[start] = 0;\n\n\t\tpriority_queue<Point,vector<Point>,greater<Point>> Q;\n\t\tQ.emplace(0,start);\n\t\twhile(!Q.empty()){\n\t\t\tauto p = Q.top();\n\t\t\tQ.pop();\n\t\t\tint v = p.second;\n\t\t\tif(dist[v]<p.first){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(auto e:connect[v]){\n\t\t\t\tif(dist[e.first]>dist[v]+e.second){\n\t\t\t\t\tdist[e.first] = dist[v]+e.second;\n\t\t\t\t\tQ.emplace(dist[e.first],e.first);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll GetDistance(int i){\n\t\treturn dist[i];\n\t}\n};\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),M=in(),K=in(),S=in();\n\tauto P=in(),Q=in();\n\tauto C=vecin(K);\n\tsort(ALL(C));\n\n\tvector<pair<ll,ll>> L(M);\n\tConnectNodeInfo connect(N);\n\tREP(i,M){\n\t\tauto u=in()-1,v=in()-1;\n\t\tL[i]={min(u,v),max(u,v)};\n\t\tconnect.AddNonDirectionalConnection(u,v,1);\n\t}\n\tvll dist(N,1ll<<60);\n\tqueue<ll> DQ;\n\tfor(auto& x:C){\n\t\tDQ.push(x-1);\n\t\tdist[x-1]=0;\n\t}\n\n\twhile(!DQ.empty()){\n\t\tauto vertex=DQ.front();\n\t\tDQ.pop();\n\t\tfor(auto& [node,weight]:connect[vertex]){\n\t\t\tif(dist[vertex]+1<dist[node]){\n\t\t\t\tdist[node] = dist[vertex]+1;\n\t\t\t\tDQ.push(node);\n\t\t\t}\n\t\t}\n\t}\n\n\tConnectNodeInfo connect2(N);\n\tREP(i,M){\n\t\tauto [u,v]=L[i];\n\t\tif(binary_search(ALL(C),u+1) || binary_search(ALL(C),v+1)) continue;\n\t\tif(v==N-1){\n\t\t\tconnect2.AddDirectionalConnection(u,v,0);\n\t\t}\n\t\telse{\n\t\t\tif(dist[v]<=S) connect2.AddDirectionalConnection(u,v,Q);\n\t\t\telse connect2.AddDirectionalConnection(u,v,P);\n\t\t}\n\t\tif(dist[u]<=S) connect2.AddDirectionalConnection(v,u,Q);\n\t\telse connect2.AddDirectionalConnection(v,u,P);\n\t}\n\n\tDijkstra dij;\n\tdij.CalcShortestPath(0,connect2);\n\tout(dij.GetDistance(N-1));\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 33328, "score_of_the_acc": -0.85, "final_rank": 14 }, { "submission_id": "aoj_0623_9026949", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass ConnectNodeInfo{\n\tvector<vector<pair<ll,ll>>> graph;\npublic:\n\tConnectNodeInfo(int node_num){\n\t\tgraph.resize(node_num);\n\t}\n\tvoid AddNonDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t\tgraph[v].emplace_back(u,w);\n\t}\n\tvoid AddDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t}\n\tvector<pair<ll,ll>>& operator[](ll index){\n\t\treturn graph[index];\n\t}\n\tsize_t size(){ return graph.size(); }\n};\n\nclass Dijkstra{\n\tusing Point = pair<ll,ll>;\n\tvector<ll> dist;\npublic:\n\tvoid CalcShortestPath(int start,ConnectNodeInfo& connect){\n\t\tdist.resize(connect.size(),1LL<<60);\n\t\tdist[start] = 0;\n\n\t\tpriority_queue<Point,vector<Point>,greater<Point>> Q;\n\t\tQ.emplace(0,start);\n\t\twhile(!Q.empty()){\n\t\t\tauto p = Q.top();\n\t\t\tQ.pop();\n\t\t\tint v = p.second;\n\t\t\tif(dist[v]<p.first){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(auto e:connect[v]){\n\t\t\t\tif(dist[e.first]>dist[v]+e.second){\n\t\t\t\t\tdist[e.first] = dist[v]+e.second;\n\t\t\t\t\tQ.emplace(dist[e.first],e.first);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll GetDistance(int i){\n\t\treturn dist[i];\n\t}\n};\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),M=in(),K=in(),S=in();\n\tauto P=in(),Q=in();\n\tauto C=vecin(K);\n\n\tvector<pair<ll,ll>> L(M);\n\tConnectNodeInfo connect(N);\n\tREP(i,M){\n\t\tauto u=in()-1,v=in()-1;\n\t\tL[i]={min(u,v),max(u,v)};\n\t\tconnect.AddNonDirectionalConnection(u,v,1);\n\t}\n\tvll dist(N,1ll<<60);\n\tqueue<ll> DQ;\n\tfor(auto& x:C){\n\t\tDQ.push(x-1);\n\t\tdist[x-1]=0;\n\t}\n\n\twhile(!DQ.empty()){\n\t\tauto vertex=DQ.front();\n\t\tDQ.pop();\n\t\tfor(auto& [node,weight]:connect[vertex]){\n\t\t\tif(dist[vertex]+1<dist[node]){\n\t\t\t\tdist[node] = dist[vertex]+1;\n\t\t\t\tDQ.push(node);\n\t\t\t}\n\t\t}\n\t}\n\n\tConnectNodeInfo connect2(N);\n\tREP(i,M){\n\t\tauto [u,v]=L[i];\n\t\tif(binary_search(ALL(C),u+1) || binary_search(ALL(C),v+1)) continue;\n\t\tif(v==N-1){\n\t\t\tconnect2.AddDirectionalConnection(u,v,0);\n\t\t}\n\t\telse{\n\t\t\tif(dist[v]<=S) connect2.AddDirectionalConnection(u,v,Q);\n\t\t\telse connect2.AddDirectionalConnection(u,v,P);\n\t\t}\n\t\tif(dist[u]<=S) connect2.AddDirectionalConnection(v,u,Q);\n\t\telse connect2.AddDirectionalConnection(v,u,P);\n\t}\n\n\tDijkstra dij;\n\tdij.CalcShortestPath(0,connect2);\n\tout(dij.GetDistance(N-1));\n\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 70, "memory_kb": 33276, "score_of_the_acc": -0.8414, "final_rank": 17 }, { "submission_id": "aoj_0623_8716179", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,n) for(int i = 0; i < (n); i++)\n#define coutf(f) cout << fixed << setprecision(f)\n#define all(v) (v).begin(), (v).end()\n#define pb(x) push_back(x)\n\nusing Graph1 = vector<vector<int>>;\n\nconst ll INF = 1LL << 60;\n\nstruct Edge {\n int to;\n ll w;\n Edge(int to, ll w) : to(to), w(w) {}\n};\n\nusing Graph2 = vector<vector<Edge>>;\n\ntemplate<class T> bool chmin(T& a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n else return false;\n}\n\nint main() {\n int n, m, k, s;\n cin >> n >> m >> k >> s;\n int p, q;\n cin >> p >> q;\n vector<int> c(k);\n Graph1 G1(n);\n rep (i,k) {\n cin >> c[i];\n c[i]--;\n }\n sort(all(c));\n vector<int> a(m), b(m);\n rep (i,m) {\n cin >> a[i] >> b[i];\n a[i]--; b[i]--;\n G1[a[i]].pb(b[i]);\n G1[b[i]].pb(a[i]);\n }\n vector<int> dist1(n, -1);\n queue<int> que1;\n rep (i,k) {\n dist1[c[i]] = 0;\n que1.push(c[i]);\n }\n while (!que1.empty()) {\n int v = que1.front();\n que1.pop();\n for (int nv : G1[v]) {\n if (dist1[nv] != -1) continue;\n dist1[nv] = dist1[v]+1;\n que1.push(nv);\n }\n }\n vector<bool> ok(n);\n rep (i,n) {\n if (dist1[i] <= s) ok[i] = false;\n else ok[i] = true;\n }\n Graph2 G2(n);\n rep (i,m) {\n if (binary_search(all(c), a[i])) continue;\n if (binary_search(all(c), b[i])) continue;\n if (ok[b[i]]) {\n G2[a[i]].pb(Edge(b[i],p));\n } else {\n G2[a[i]].pb(Edge(b[i],q));\n }\n if (ok[a[i]]) {\n G2[b[i]].pb(Edge(a[i],p));\n } else {\n G2[b[i]].pb(Edge(a[i],q));\n }\n }\n vector<ll> dist2(n, INF);\n dist2[0] = 0;\n priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>> que2;\n que2.push({dist2[0],0});\n while (!que2.empty()) {\n int v = que2.top().second;\n ll d = que2.top().first;\n que2.pop();\n if (d > dist2[v]) continue;\n for (auto e : G2[v]) {\n if (chmin(dist2[e.to], dist2[v]+e.w)) {\n que2.push({dist2[e.to], e.to});\n }\n }\n }\n ll ans = INF;\n for (auto v : G2[n-1]) {\n ans = min(ans, dist2[v.to]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 25516, "score_of_the_acc": -0.5926, "final_rank": 11 }, { "submission_id": "aoj_0623_7134679", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i32 = int;\nusing i64 = long long;\n\nconst i32 supi = 1e9;\nconst i64 supl = 1e18;\n\nint main() {\n i32 n, m, k, s; cin >> n >> m >> k >> s;\n i32 p, q; cin >> p >> q;\n vector cs(k, 0);\n for (auto& c : cs) {\n cin >> c;\n c--;\n }\n vector es(m, pair(0, 0));\n for (auto& [a, b] : es) {\n cin >> a >> b;\n a--;\n b--;\n }\n vector G = [&]() -> vector<vector<pair<i32, i32>>> {\n vector ts(n + 1, vector(0, 0));\n for (auto c : cs) {\n ts[n].push_back(c);\n }\n for (auto [a, b] : es) {\n ts[a].push_back(b);\n ts[b].push_back(a);\n }\n vector ds(n + 1, supi);\n ds[n] = 0;\n queue<i32> que({ n });\n while (que.size()) {\n i32 v = que.front();\n que.pop();\n for (auto x : ts[v]) {\n if (ds[x] > ds[v] + 1) {\n ds[x] = ds[v] + 1;\n que.push(x);\n }\n }\n }\n vector res(2 * n, vector(0, pair(0, 0)));\n set<i32> ng(cs.begin(), cs.end());\n for (auto [a, b] : es) {\n if (ng.count(a) or ng.count(b)) {\n continue;\n }\n res[a + n].emplace_back(b, 0);\n res[b + n].emplace_back(a, 0);\n }\n for (i32 i = 0 ; i < n ; i++) {\n if (i == 0 or i == n - 1) {\n res[i].emplace_back(i + n, 0);\n }\n else if (ds[i] <= s + 1) {\n res[i].emplace_back(i + n, q);\n }\n else {\n res[i].emplace_back(i + n, p);\n }\n }\n return res;\n }();\n vector ds(2 * n, supl);\n ds[0] = 0;\n priority_queue<pair<i64, i32>, vector<pair<i64, i32>>, greater<pair<i64, i32>>> que;\n que.emplace(0LL, 0);\n while (que.size()) {\n auto [d, v] = que.top();\n que.pop();\n if (d > ds[v]) {\n continue;\n }\n for (auto [x, w] : G[v]) {\n if (ds[x] > d + w) {\n ds[x] = d + w;\n que.emplace(d + w, x);\n }\n }\n }\n // for (auto d : ds) cout << d << ' ';\n // cout << endl;\n cout << ds.back() << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 24392, "score_of_the_acc": -0.5526, "final_rank": 10 }, { "submission_id": "aoj_0623_6991822", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0623.cc: ゾンビ島 (Zombie Island)\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int INF = 1 << 30;\nconst long long LINF = 1LL << 62;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef queue<int> qi;\ntypedef pair<ll,int> pli;\n\n/* global variables */\n\nint cs[MAX_N], zds[MAX_N];\nvi nbrs[MAX_N];\nll ds[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, m, k, s, p, q;\n scanf(\"%d%d%d%d%d%d\", &n, &m, &k, &s, &p, &q);\n \n for (int i = 0; i < k; i++) scanf(\"%d\", cs + i), cs[i]--;\n\n for (int i = 0; i < m; i++) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n u--, v--;\n nbrs[u].push_back(v);\n nbrs[v].push_back(u);\n }\n\n fill(zds, zds + n, INF);\n qi qq;\n for (int i = 0; i < k; i++)\n zds[cs[i]] = 0, qq.push(cs[i]);\n\n while (! qq.empty()) {\n int u = qq.front(); qq.pop();\n for (auto v: nbrs[u])\n if (zds[v] > zds[u] + 1) {\n\tzds[v] = zds[u] + 1;\n\tqq.push(v);\n }\n }\n //for (int i = 0; i < n; i++) printf(\"%d \", zds[i]); putchar('\\n');\n\n fill(ds, ds + n, LINF);\n ds[0] = 0;\n\n priority_queue<pli> pq;\n pq.push(pli(0, 0));\n\n while (! pq.empty()) {\n pli ue = pq.top(); pq.pop();\n ll ud = -ue.first;\n int u = ue.second;\n if (ds[u] != ud) continue;\n if (u == n - 1) break;\n\n for (auto v: nbrs[u])\n if (zds[v] != 0) {\n\tll vd = ud + (v != n - 1 ? (zds[v] > s ? p : q) : 0);\n\tif (ds[v] > vd) {\n\t ds[v] = vd;\n\t pq.push(pli(-vd, v));\n\t}\n }\n }\n\n printf(\"%lld\\n\", ds[n - 1]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10576, "score_of_the_acc": -0.0068, "final_rank": 1 }, { "submission_id": "aoj_0623_6814313", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<algorithm>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,int>P;\nstruct edge{\n\tint to,cost;\n};\nvector<int>G[100000];\nvector<edge>G2[100000];\nll dist[100000];\nbool dg[100000],dg2[100000];\nint main(){\n\tint n,m,k,s,p,q,c,a,b;\n\tcin>>n>>m>>k>>s>>p>>q;\n\tfor(int i=0;i<k;i++){\n\t\tcin>>c;\n\t\tc--;\n\t\tdg[c]=1;\n\t}\n\twhile(cin>>a>>b){\n\t\ta--,b--;\n\t\tG[a].push_back(b);\n\t\tG[b].push_back(a);\n\t}\n\tqueue<int>que;\n\tfill(dist,dist+n,1e9);\n\tfor(int i=0;i<n;i++){\n\t\tif(dg[i]){\n\t\t\tdist[i]=0;\n\t\t\tque.push(i);\n\t\t}\n\t}\n\twhile(que.size()){\n\t\tint v=que.front();\n\t\tque.pop();\n\t\tfor(auto x:G[v]){\n\t\t\tif(dist[x]==1e9){\n\t\t\t\tdist[x]=dist[v]+1;\n\t\t\t\tque.push(x);\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=0;i<n;i++)\n\t\tif(dist[i]<=s)\n\t\t\tdg2[i]=1;\n\tfor(int i=0;i<n;i++){\n\t\tfor(auto x:G[i]){\n\t\t\tif(dg[x])\n\t\t\t\tcontinue;\n\t\t\tG2[i].push_back({x,p});\n\t\t\tif(dg2[x])\n\t\t\t\tG2[i].back().cost=q;\n\t\t\tif(x==n-1)\n\t\t\t\tG2[i].back().cost=0;\n\t\t}\n\t}\n\tpriority_queue<P,vector<P>,greater<>>pque;\n\tfill(dist,dist+n,1e18);\n\tdist[0]=0;\n\tpque.push({0,0});\n\twhile(pque.size()){\n\t\tauto[d,v]=pque.top();\n\t\tpque.pop();\n\t\tif(dist[v]<d)\n\t\t\tcontinue;\n\t\tfor(auto[x,c]:G2[v]){\n\t\t\tif(dist[x]>d+c){\n\t\t\t\tdist[x]=d+c;\n\t\t\t\tpque.push({d+c,x});\n\t\t\t}\n\t\t}\n\t}\n\tcout<<dist[n-1]<<endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 18340, "score_of_the_acc": -0.3238, "final_rank": 9 }, { "submission_id": "aoj_0623_6725086", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define INF 1000000000\n#define LINF 1000000000000000000\nusing namespace std;\nusing ll=long long;\nusing PL=pair<ll,int>;\n\nint N,M,K,S,P,Q;\nvector<int> C;\nvector<vector<int>> g;\nvector<int> z;\n\ntemplate<typename T>bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}\n\nvoid bfs() {\n queue<int> q;\n vector<int> dist(N,INF);\n for(auto i:C) {\n dist[i]=0;\n z[i]=2;\n q.push(i);\n }\n while(!q.empty()) {\n int u=q.front(); q.pop();\n if(dist[u]+1<=S) for(auto v:g[u]) {\n if(chmin(dist[v],dist[u]+1)) q.push(v);\n }\n }\n rep(i,N) if(dist[i]<=S && z[i]!=2) z[i]=1;\n}\n\nll dijkstra() {\n priority_queue<PL,vector<PL>,greater<PL>> q;\n vector<ll> dist(N,LINF);\n dist[0]=0;\n q.push(make_pair(0,0));\n while(!q.empty()) {\n ll d; int u;\n tie(d,u)=q.top(); q.pop();\n if(d>dist[u]) continue;\n for(auto v:g[u]) {\n if(z[v]==2) continue;\n int c=(z[v] ? Q : P);\n if(v==N-1) c=0;\n if(chmin(dist[v],dist[u]+c)) q.push(make_pair(dist[v],v));\n }\n }\n return dist[N-1];\n}\n\nint main(void) {\n cin.tie(0);\n ios::sync_with_stdio(0);\n cin >> N >> M >> K >> S >> P >> Q;\n C.resize(K);\n g.resize(N);\n z.resize(N,0);\n rep(i,K) {\n cin >> C[i];\n C[i]--;\n }\n rep(i,M) {\n int a,b; cin >> a >> b;\n a--; b--;\n g[a].push_back(b);\n g[b].push_back(a);\n }\n bfs();\n cout << dijkstra() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10592, "score_of_the_acc": -0.0074, "final_rank": 2 }, { "submission_id": "aoj_0623_6622466", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll N,M,K,S,X,Y;\nconst ll INF=1e18;\nvector<P> G[100010];\nvector<ll> g[100010];\nll d[100010],c[100010],e[2][200010];\n\nvoid bfs(){\n\n\tvector<ll> v(N+1,INF);\n\tqueue<ll> q;\n\tfor(ll i=1;i<=N;i++) if(c[i]==1){\n\t\tv[i]=0;\n\t\tq.push(i);\n\t}\n\n\twhile(!q.empty()){\n\n\t\tll a=q.front();\n\t\tq.pop();\n\t\tfor(ll i=0;i<(ll)g[a].size();i++){\n\t\t\tll b=g[a][i];\n\t\t\tif(v[b]==INF){\n\t\t\t\tv[b]=v[a]+1;\n\t\t\t\tq.push(b);\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(ll i=1;i<=N;i++) if(c[i]!=1){\n\t\tif(1<=v[i] && v[i]<=S) c[i]=-1;\n\t}\n\n}\n\n\nvoid djk(){\n\n priority_queue<P,vector<P>,greater<P> > q;\n\n for(ll i=0;i<=N;i++) d[i]=INF;\n d[1]=0;\n q.push(P(0,1));\n\n while(!q.empty()){\n P p=q.top(); q.pop();\n ll v=p.second;\n\n if(c[v]==1) continue;\n if(d[v]<p.first) continue;\n\n for(ll i=0;i<(ll)G[v].size();i++){\n \tP x=G[v][i];\n \tif(c[x.second]==1) continue;\n if(d[x.second]>d[v]+x.first){\n d[x.second]=d[v]+x.first;\n q.push(P(d[x.second],x.second));\n }\n }\n }\n\n}\n\n\nint main(void){\n\tll i,j,k;\n \n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tcin >> N >> M >> K >> S >> X >> Y;\n\n\tfor(i=1;i<=K;i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tc[t]=1;\n\t}\n\n\tfor(i=1;i<=M;i++){\n\t\tll a,b;\n\t\tcin >> a >> b;\n\n\t\tg[a].push_back(b);\n\t\tg[b].push_back(a);\n\t\te[0][i]=a;\n\t\te[1][i]=b;\n\t}\n\n\tbfs();\n\n\tfor(i=1;i<=M;i++){\n\t\tll x=e[0][i],y=e[1][i];\n\t\tif(y==N){\n\t\t\tG[x].push_back(P(0,y));\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(c[y]==-1) G[x].push_back(P(Y,y));\n\t\tif(c[y]==0) G[x].push_back(P(X,y));\n\t\tif(c[x]==-1) G[y].push_back(P(Y,x));\n\t\tif(c[x]==0) G[y].push_back(P(X,x));\n\t}\n\n\n\tdjk();\n\n\tcout << d[N] << endl;\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 29100, "score_of_the_acc": -0.7065, "final_rank": 13 }, { "submission_id": "aoj_0623_6621720", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll N,M,K,S,X,Y;\nconst ll INF=1e18;\nvector<P> G[100010];\nvector<ll> g[100010];\nll d[100010],c[100010],e[2][200010];\n\nvoid dfs(ll x,ll e){\n\tif(c[x]!=1) c[x]=-1;\n\tif(e==S) return;\n\n\tfor(ll i=0;i<(ll)g[x].size();i++) if(c[g[x][i]]!=-1) dfs(g[x][i],e+1);\n}\n\nvoid djk(){\n\n priority_queue<P,vector<P>,greater<P> > q;\n\n for(ll i=0;i<=N;i++) d[i]=INF;\n d[1]=0;\n q.push(P(0,1));\n\n while(!q.empty()){\n P p=q.top(); q.pop();\n ll v=p.second;\n\n if(c[v]==1) continue;\n if(d[v]<p.first) continue;\n\n for(ll i=0;i<(ll)G[v].size();i++){\n \tP x=G[v][i];\n \tif(c[x.second]==1) continue;\n if(d[x.second]>d[v]+x.first){\n d[x.second]=d[v]+x.first;\n q.push(P(d[x.second],x.second));\n }\n }\n }\n\n}\n\n\nint main(void){\n\tll i,j,k;\n \n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tcin >> N >> M >> K >> S >> X >> Y;\n\n\tfor(i=1;i<=K;i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tc[t]=1;\n\t}\n\n\tfor(i=1;i<=M;i++){\n\t\tll a,b;\n\t\tcin >> a >> b;\n\n\t\tg[a].push_back(b);\n\t\tg[b].push_back(a);\n\t\te[0][i]=a;\n\t\te[1][i]=b;\n\t}\n\n\tfor(i=1;i<=N;i++) if(c[i]==1) dfs(i,0);\n\n\tfor(i=1;i<=M;i++){\n\t\tll x=e[0][i],y=e[1][i];\n\t\tif(y==N){\n\t\t\tG[x].push_back(P(0,y));\n\t\t\tcontinue;\n\t\t}\n\n\t\tif(c[y]==-1) G[x].push_back(P(Y,y));\n\t\tif(c[y]==0) G[x].push_back(P(X,y));\n\t\tif(c[x]==-1) G[y].push_back(P(Y,x));\n\t\tif(c[x]==0) G[y].push_back(P(X,x));\n\t}\n\n\tdjk();\n\n\tcout << d[N] << endl;\n\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 18716, "score_of_the_acc": -0.2895, "final_rank": 20 }, { "submission_id": "aoj_0623_6620773", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll N,M,K,S,X,Y;\nconst ll INF=1e18;\nvector<P> G[100010];\nvector<ll> g[100010];\nll d[100010],c[100010];\n\nvoid dfs(ll x,ll e){\n\tif(c[x]!=1) c[x]=-1;\n\tif(e==S) return;\n\n\tfor(ll i=0;i<(ll)g[x].size();i++) if(c[g[x][i]]!=-1) dfs(g[x][i],e+1);\n}\n\nvoid djk(){\n\n priority_queue<P,vector<P>,greater<P> > q;\n\n for(ll i=0;i<=N;i++) d[i]=INF;\n d[1]=0;\n q.push(P(0,1));\n\n while(!q.empty()){\n P p=q.top(); q.pop();\n ll v=p.second;\n\n if(d[v]<p.first) continue;\n\n for(ll i=0;i<(ll)G[v].size();i++){\n \tP x=G[v][i];\n if(d[x.second]>d[v]+x.first){\n d[x.second]=d[v]+x.first;\n q.push(P(d[x.second],x.second));\n }\n }\n }\n\n}\n\n\nint main(void){\n\tll i,j,k;\n \n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tcin >> N >> M >> K >> S >> X >> Y;\n\n\tfor(i=1;i<=K;i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tc[t]=1;\n\t}\n\n\tfor(i=1;i<=M;i++){\n\t\tll a,b;\n\t\tcin >> a >> b;\n\n\t\tg[a].push_back(b);\n\t\tg[b].push_back(a);\n\n\t\tif(c[a]==1 || c[b]==1) continue;\n\t G[a].push_back(P(0,b));\n\t\tG[b].push_back(P(0,a));\n\t}\n\n\tfor(i=1;i<=N;i++) if(c[i]==1) dfs(i,0);\n\n\tfor(i=2;i<N;i++){\n\t\tif(G[i].empty()) continue;\n\t\tfor(j=0;j<(ll)G[i].size();j++){\n\t\t\tif(c[i]==0) G[i][j].first=X;\n\t\t\tif(c[i]==-1) G[i][j].first=Y;\n\t\t}\n\t}\n\n\tdjk();\n\n\tcout << d[N] << endl;\n\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 16764, "score_of_the_acc": -0.2201, "final_rank": 18 }, { "submission_id": "aoj_0623_6620763", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll N,M,K,S,X,Y;\nconst ll INF=1e18;\nvector<P> G[100010];\nvector<ll> g[100010];\nll d[100010],c[100010];\n\nvoid dfs(ll x,ll e){\n\tif(c[x]==-1) return;\n\tif(c[x]==0) c[x]=-1;\n\tif(e==S) return;\n\n\tfor(ll i=0;i<(ll)g[x].size();i++) dfs(g[x][i],e+1);\n}\n\nvoid djk(){\n\n priority_queue<P,vector<P>,greater<P> > q;\n\n for(ll i=0;i<=N;i++) d[i]=INF;\n d[1]=0;\n q.push(P(0,1));\n\n while(!q.empty()){\n P p=q.top(); q.pop();\n ll v=p.second;\n\n if(d[v]<p.first) continue;\n\n for(ll i=0;i<(ll)G[v].size();i++){\n \tP x=G[v][i];\n if(d[x.second]>d[v]+x.first){\n d[x.second]=d[v]+x.first;\n q.push(P(d[x.second],x.second));\n }\n }\n }\n\n}\n\n\nint main(void){\n\tll i,j,k;\n \n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tcin >> N >> M >> K >> S >> X >> Y;\n\n\tfor(i=1;i<=K;i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tc[t]=1;\n\t}\n\n\tfor(i=1;i<=M;i++){\n\t\tll a,b;\n\t\tcin >> a >> b;\n\n\t\tg[a].push_back(b);\n\t\tg[b].push_back(a);\n\n\t\tif(c[a]==1 || c[b]==1) continue;\n\t G[a].push_back(P(0,b));\n\t\tG[b].push_back(P(0,a));\n\t}\n\n\tfor(i=1;i<=N;i++) if(c[i]==1) dfs(i,0);\n\n\tfor(i=2;i<N;i++){\n\t\tif(G[i].empty()) continue;\n\t\tfor(j=0;j<(ll)G[i].size();j++){\n\t\t\tif(c[i]==0) G[i][j].first=X;\n\t\t\tif(c[i]==-1) G[i][j].first=Y;\n\t\t}\n\t}\n\n\tdjk();\n\n\tcout << d[N] << endl;\n\n\n\treturn 0;\n}", "accuracy": 0.2, "time_ms": 20, "memory_kb": 16864, "score_of_the_acc": -0.2236, "final_rank": 19 }, { "submission_id": "aoj_0623_6291239", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long INF = 9000000007;\ntypedef pair<long long, long long> Pair;\nstruct Edge {\n long long to;\n long long cost;\n};\nvoid BFS(vector<vector<long long>>&Graph, vector<long long>&Dist, long long start) {\n vector<bool>A(Dist.size(), false);\n queue<long long>Q;\n Q.push(start);\n Dist.at(start) = 0;\n A.at(start) = true;\n while (!Q.empty()) {\n long long v = Q.front(); Q.pop();\n for (auto next_v: Graph[v]) {\n if (!A.at(next_v)) {\n Dist.at(next_v) = min(Dist.at(v) + 1, Dist.at(next_v));\n A.at(next_v) = true; \n Q.push(next_v);\n }\n }\n }\n}\nvoid Dijkstra(const vector<vector<Edge>>& G, long long Start, vector<long long>& Dis) { //ダイクストラ法\n\tpriority_queue<pair<long long, long long>, vector<pair<long long, long long>>, greater<pair<long long, long long>>> P; //priority_queueを用意.\n\tDis.at(Start) = 0; //始点から始点への移動のひつy(以下略)\n\tP.emplace(Dis.at(Start), Start);\n\twhile (!P.empty()) {\n\t\tpair<long long, long long> V = P.top(); P.pop();\n\t\tlong long v = V.second;\n\t\tif (Dis.at(v) < V.first) continue;\n\t\tfor (auto &e : G.at(v)) { //vと隣接する頂点との最短距離を更新.\n\t\t\tif (Dis.at(e.to) > Dis.at(v) + e.cost) {\n\t\t\t\tDis.at(e.to) = Dis.at(v) + e.cost;\n\t\t\t\tP.emplace(Dis.at(e.to), e.to);\n\t\t\t}\n\t\t}\n\t}\n}\nint main() {\n long long N, M, K, S; cin >> N >> M >> K >> S;\n long long P, Q; cin >> P >> Q;\n vector<long long>Zombie(K);\n vector<bool>danger(N, false);\n for (long long i = 0; i < K; i++) {\n cin >> Zombie.at(i);\n danger.at(Zombie.at(i) - 1) = true;\n }\n vector<Pair>Road(M);\n vector<vector<long long>>Graph(N);\n for (long long i = 0; i < M; i++) {\n cin >> Road.at(i).first >> Road.at(i).second;\n Road.at(i).first--;\n Road.at(i).second--;\n Graph.at(Road.at(i).first).push_back(Road.at(i).second);\n Graph.at(Road.at(i).second).push_back(Road.at(i).first);\n }\n vector<long long>Dist(N, INF);\n for (long long i = 0; i < K; i++) {\n BFS(Graph, Dist, Zombie.at(i) - 1);\n }\n for (long long i = 0; i < N; i++) {\n if (!danger.at(i)) danger.at(i) = (Dist.at(i) <= S);\n }\n vector<vector<Edge>>Graph2(N);\n for (long long i = 0; i < M; i++) {\n Edge E;\n E.to = Road.at(i).second;\n if (Road.at(i).second == N - 1) {\n E.cost = 0;\n }\n else if (Dist.at(Road.at(i).second) == 0) {\n E.cost = INF;\n }\n else E.cost = (danger.at(Road.at(i).second) ? Q : P);\n Graph2.at(Road.at(i).first).push_back(E);\n E.to = Road.at(i).first;\n if (Road.at(i).first == N - 1) {\n E.cost = 0;\n }\n else if (Dist.at(Road.at(i).first) == 0) {\n E.cost = INF;\n }\n else E.cost = (danger.at(Road.at(i).first) ? Q : P);\n Graph2.at(Road.at(i).second).push_back(E);\n }\n vector<long long>Cost(N, INF);\n Dijkstra(Graph2, 0, Cost);\n cout << Cost.at(N - 1) << endl;\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 29544, "score_of_the_acc": -1.6746, "final_rank": 16 }, { "submission_id": "aoj_0623_6111305", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,k,s);\n LL(P,Q);\n vector<int> zon(k);\n vector<vector<int>> g(n);\n vector<int> dist1(n,INF);\n vector<ll> dist(n,INF2);\n rpriority_queue<pair<ll,int>> pq;\n queue<int> next;\n rep(i,k){\n in(zon[i]);\n next.push(--zon[i]);\n dist1[zon[i]]=0;\n }\n int u,v;\n rep(i,m){\n in(u,v);\n g[--u].push_back(--v);\n g[v].push_back(u);\n }\n while(!next.empty()){\n v=next.front();\n next.pop();\n for(auto u:g[v]){\n if(dist1[v]+1>=dist1[u])continue;\n dist1[u]=dist1[v]+1;\n next.push(u);\n }\n }\n dist[0]=0;\n pq.push({0,0});\n ll d;\n while(!pq.empty()){\n tie(d,v)=pq.top();\n pq.pop();\n for(auto u:g[v]){\n if(!dist1[u])continue;\n if(dist[v]+(dist1[u]<=s?Q:P)>=dist[u])continue;\n dist[u]=dist[v]+(dist1[u]<=s?Q:P);\n pq.push({dist[u],u});\n }\n }\n out(dist[n-1]-(dist1[n-1]<=s?Q:P));\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10896, "score_of_the_acc": -0.025, "final_rank": 5 }, { "submission_id": "aoj_0623_5926951", "code_snippet": "#include<bits/stdc++.h>\n\nusing Int = long long;\nusing namespace std;\nconstexpr Int inf = 1e18;\nint main(){\n Int N,M,K,S;\n cin >> N >> M >> K >> S;\n Int P,Q;\n cin >> P >> Q;\n vector<Int>C;\n vector<bool>isSafe(N,true);\n for(int i = 0; i < K; ++i){\n int v; cin >> v; --v;\n C.emplace_back(v);\n isSafe[v] = false;\n }\n vector<vector<Int>>edge(N);\n for(int i = 0; i < M; ++i){\n int s,t; cin >> s >> t;\n --s; --t;\n edge[s].emplace_back(t);\n edge[t].emplace_back(s);\n }\n vector<Int>cost(N,-1);\n priority_queue<pair<Int,int>,vector<pair<Int,int>>>que;\n for(auto c : C) que.emplace(S + 1,c);\n while(not que.empty()){\n auto [tS,v] = que.top(); que.pop();\n for(auto nv : edge[v]){\n if(cost[nv] != -1) continue;\n Int ncost = max(0LL,tS - 1);\n if(not isSafe[nv]) ncost = S + 1;\n if(cost[nv] >= ncost) continue;\n cost[nv] = ncost;\n que.emplace(cost[nv],nv);\n }\n }\n priority_queue<pair<Int,int>,vector<pair<Int,int>>,greater<>>pque;\n vector<Int>path(N,inf);\n path[0] = 0;\n pque.emplace(0,path[0]);\n while(not pque.empty()){\n auto [cd,cv] = pque.top(); pque.pop();\n for(auto nv : edge[cv]){\n if(path[nv] != inf or path[nv] <= cd or (not isSafe[nv]))continue;\n Int cst = (cost[nv] > 0 ? Q : P);\n path[nv] = cst + cd;\n pque.emplace(path[nv],nv);\n }\n }\n cout << path[ N - 1] - (cost[N - 1] > 0 ? Q : P) << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 13916, "score_of_the_acc": -0.1664, "final_rank": 8 }, { "submission_id": "aoj_0623_5865681", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\ntemplate <typename Monoid>\nstruct SegmentTree{\n\n int N;\n vector<Monoid> node;\n Monoid Unit;\n function<Monoid(Monoid, Monoid)> f;\n\n SegmentTree(vector<Monoid> v, const function<Monoid(Monoid, Monoid)> f, const Monoid &Unit): f(f), Unit(Unit){\n int sz_ = v.size();\n N = 1;\n while(N < sz_) N *= 2;\n\n node.assign(2*N, Unit);\n for(int i=0; i<sz_; i++) node[i+N-1] = v[i];\n for(int i=N-2; i>=0; i--) node[i] = f(node[2*i+1], node[2*i+2]);\n }\n\n void update(int k, const Monoid &x) {\n k += N-1;\n node[k] = x;\n while(k > 0){\n k = (k-1)/2;\n node[k] = f(node[2*k+1], node[2*k+2]);\n }\n }\n\n Monoid query(int a, int b, int k=0, int l = 0, int r=-1){\n if(r < 0) r = N;\n if(r <= a || b <= l) return Unit;\n if(a <= l && r <= b) return node[k];\n else{\n Monoid vl = query(a, b, 2*k+1, l, (l+r)/2);\n Monoid vr = query(a, b, 2*k+2, (l+r)/2, r);\n return f(vl, vr);\n }\n }\n\n inline Monoid operator[](int a) { return query(a, a + 1); }\n};\n\nvector<vector<int>> g(101010);\nll dist[101010];\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n ll N, M, K, S; cin >> N >> M >> K >> S;\n ll P, Q; cin >> P >> Q;\n\n vector<int> ok(N, 1e9);\n queue<int> q;\n REP(i,K) {\n int c; cin >> c;\n c--;\n q.push(c);\n ok[c] = 0;\n }\n REP(i,M) {\n int a, b; cin >> a >> b;\n a--; b--;\n g[a].push_back(b);\n g[b].push_back(a);\n }\n while(q.size()) {\n int v = q.front(); q.pop();\n \n for(auto u: g[v]) {\n if(ok[u] > ok[v] + 1) {\n ok[u] = ok[v] + 1;\n q.push(u);\n }\n }\n }\n REP(i,N) dist[i] = (1LL<<60);\n dist[0] = 0;\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, 0});\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(dist[v] < cost) continue;\n for(auto u: g[v]) {\n if(ok[u] == 0) continue;\n ll t = P;\n if(ok[u] <= S) t = Q;\n if(u == N-1) t = 0;\n if(dist[u] > dist[v] + t) {\n dist[u] = dist[v] + t;\n pq.push({dist[u], u});\n }\n }\n }\n cout << dist[N-1] << endl;\n \n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10792, "score_of_the_acc": -0.0145, "final_rank": 3 }, { "submission_id": "aoj_0623_5840829", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n\nstruct Edge{\n int to;\n lint cost;\n \n Edge(int to, lint cost): to(to), cost(cost) {}\n};\nusing Graph = vector<vector<Edge>>;\n\nconst lint INF = 1e18;\nvector<lint> dijkstra(Graph g, vector<int> s){\n int n = int(g.size());\n using P = pair<lint, int>;\n \n vector<lint> dist(n, INF);\n priority_queue<P, vector<P>, greater<P>> que;\n for(int v: s){\n dist[v] = 0;\n que.push({0, v});\n }\n \n while(!que.empty()){\n auto top = que.top();\n que.pop();\n int at = top.second;\n lint cost = top.first;\n if(dist[at] < cost){\n continue;\n }\n \n for(auto e: g[at]){\n int to = e.to;\n lint ncost = cost + e.cost;\n if(dist[to] > ncost){\n dist[to] = ncost;\n que.push({ncost, to});\n }\n }\n }\n \n return dist;\n}\n\nint main(){\n int n, m, k, s;\n cin >> n >> m >> k >> s;\n lint p, q;\n cin >> p >> q;\n \n vector<int> zombie(k);\n vector<bool> is_zombie(n, false);\n rep(i, k){\n cin >> zombie[i];\n zombie[i]--;\n \n is_zombie[zombie[i]] = true;\n }\n \n Graph g(n);\n rep(i, m){\n int a, b;\n cin >> a >> b;\n a--, b--;\n g[a].push_back(Edge(b, 1));\n g[b].push_back(Edge(a, 1));\n }\n \n vector<lint> dist = dijkstra(g, zombie);\n vector<bool> dangerous(n);\n rep(i, n) dangerous[i] = (dist[i] <= s);\n \n Graph g2(n);\n rep(from, n){\n for(auto e: g[from]){\n int to = e.to;\n \n lint cost = (to == n - 1 ? 0 :\n is_zombie[to] ? INF :\n dangerous[to] ? q : p);\n g2[from].push_back({to, cost});\n }\n }\n \n auto ans = dijkstra(g2, {0});\n cout << ans[n - 1] << endl;\n \n// rep(i, n) cout << dist[i] << \" \";\n// cout << endl;\n// rep(i, n) cout << ans[i] << \" \";\n// cout << endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 38692, "score_of_the_acc": -1.068, "final_rank": 15 } ]
aoj_0624_cpp
屋台 (Food stalls) 問題 JOI 君の住む IOI 市は,南北方向に H 区画,東西方向に W 区画の長方形の形をしており,H × W 個の区画に区切られている.北から i 番目,西から j 番目の区画を (i, j) と表す.現在,IOI 市で開催されている国際的なプログラミングコンテストを記念して,大規模なお祭りが開催されている.いくつかの区画には屋台が出ており,それぞれ違う種類のお菓子を販売している. 区画 (1, 1), 区画 (H, W) およびそれらに東西南北に隣接する区画には屋台はない. JOI 君は区画 (1, 1) から区画 (H, W) に移動する.移動時間を短くするため,JOI 君は東あるいは南のみに移動を行う.JOI 君はお菓子が好きなので,区画に入るごとに順に次の行動をとる. 現在の区画にまだ買っていないお菓子を販売している屋台が出ている場合,その屋台でお菓子を購入する. 現在の区画の東西南北に隣接する区画にまだ買っていないお菓子を販売している屋台が出ている場合,それらの屋台のうち 1 つを除く全ての屋台から販売員を呼んで,お菓子を購入する. JOI 君は同じ種類のお菓子を複数回購入することはない. IOI 市の大きさ,屋台の位置と,それぞれの屋台のお菓子の値段が与えられたとき,JOI 君が区画 (1, 1) から区画 (H, W) に移動する間に購入するお菓子の総額の最小値を求めよ. 入力 入力は 1 + H 行からなる. 1 行目には,2 つの整数 H, W (3 ≦ H ≦ 1000, 3 ≦ W ≦ 1000) が空白を区切りとして書かれている.これは,IOI 市が H × W 個の区画に区切られていることを表す. 続く H 行にはそれぞれ W 文字からなる文字列が書かれており,IOI 市のそれぞれの区画の情報を表す.H 行のうちの i 行目の左から j 番目の文字 (1 ≦ i ≦ H, 1 ≦ j ≦ W) は,区画 (i, j) に屋台がない場合には '.' (ピリオド) である.屋台がある場合には '1', '2', ..., '9' のいずれかであり,その屋台で販売しているお菓子の値段を表す. 与えられる 5 つの入力データのうち,入力 1 では,屋台のある区画の数は 20 以下である. 出力 JOI 君が区画 (1, 1) から区画 (H, W) に移動する間に購入するお菓子の総額の最小値を 1 行で出力せよ. 入出力例 入力例 1 5 5 ..483 .59.9 3.866 79... 4.8.. 出力例 1 20 入力例 2 12 10 ..498522.4 .633527629 54.4621596 634.213458 1924518685 7739539767 276155.3.6 87716372.2 .858877595 7998739511 3438.5852. 568.9319.. 出力例 2 63 入出力例 1 においては,区画 (1, 1),区画 (2, 1),区画 (3, 1),区画 (3, 2),区画 (4, 2),区画 (4, 3),区画 (4, 4),区画 (4, 5),区画 (5, 5) の順番に移動して,区画 (3, 1),区画 (3, 3),区画 (4, 2) の屋台で販売しているお菓子を購入すると,購入するお菓子の総額が最小となる. 情報オリンピック日本委員会作 『第 15 回日本情報オリンピック JOI 2015/2016 予選競技課題』
[ { "submission_id": "aoj_0624_10615466", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n//到着時の状態\n#define Right_North 0\n#define North 1\n#define Here 2\n#define Left 3\n#define Left_South 4\n\n//あるマスで調べる状態\n#define UE 0\n#define HIDARI 1\n#define KOKO 2\n#define MIGI 3\n#define SHITA 4\n\nchar input[1000][1001];\nint POW[6];\nint table[1002][1002];\nint min_cost[1002][1002][32];\n\nint H,W;\n\nint main(){\n\n\tfor(int i = 0; i < 6; i++)POW[i] = pow(2,i);\n\n\tscanf(\"%d %d\",&H,&W);\n\n\tfor(int row = 0; row < H; row++){\n\t\tscanf(\"%s\",input[row]);\n\t}\n\n\t//ダミーセルを用意\n\tfor(int col = 0; col <= W+1; col++){\n\t\ttable[0][col] = 0;\n\t\ttable[H+1][col] = 0;\n\t}\n\tfor(int row = 0; row <= H+1; row++){\n\t\ttable[row][0] = 0;\n\t\ttable[row][W+1] = 0;\n\t}\n\n\t//マップを転記\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(input[row][col] == '.'){\n\t\t\t\ttable[row+1][col+1] = 0;\n\t\t\t}else{\n\t\t\t\ttable[row+1][col+1] = input[row][col]-'0';\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 1; row <= H; row++){\n\t\tfor(int col = 1; col <= W; col++){\n\t\t\tfor(int state = 0; state < 32; state++){\n\t\t\t\tmin_cost[row][col][state] = BIG_NUM;\n\t\t\t}\n\t\t}\n\t}\n\n\t/*\n\t * min_cost[row][col][隣接5箇所の数字を取得したか] = 最小コスト\n\t * stateのビット:位置ビットの屋台の菓子を既に食べたか\n\t *\n\t */\n\tmin_cost[1][1][0] = 0;\n\tint add_sum,add_loc,removed_add,removed_loc;\n\tint next_state;\n\tbool FLG;\n\n\tfor(int row = 1; row <= H; row++){\n\t\tfor(int col = 1; col <= W; col++){\n\t\t\tfor(int state = 0; state < 32; state++){\n\t\t\t\tif(min_cost[row][col][state] == BIG_NUM)continue;\n\n\t\t\t\t//上下左右+今いる地点で、未加算の数字を調べる\n\t\t\t\tadd_sum = 0,add_loc = 0;\n\n\t\t\t\t//上\n\t\t\t\tif((state & (1 << North)) == 0 && table[row-1][col] != 0){ //上が未加算で、かつ0でない\n\t\t\t\t\tadd_sum += table[row-1][col];\n\t\t\t\t\tadd_loc += POW[UE];\n\t\t\t\t}\n\t\t\t\t//左\n\t\t\t\tif((state & (1 << Left)) == 0 && table[row][col-1] != 0){\n\t\t\t\t\tadd_sum += table[row][col-1];\n\t\t\t\t\tadd_loc += POW[HIDARI];\n\t\t\t\t}\n\t\t\t\t//今いる場所\n\t\t\t\tif((state & (1 << Here)) == 0 && table[row][col] != 0){\n\t\t\t\t\tadd_sum += table[row][col];\n\t\t\t\t\tadd_loc += POW[KOKO];\n\t\t\t\t}\n\t\t\t\t//右\n\t\t\t\tif(table[row][col+1] != 0){\n\t\t\t\t\tadd_sum += table[row][col+1];\n\t\t\t\t\tadd_loc += POW[MIGI];\n\t\t\t\t}\n\t\t\t\t//下\n\t\t\t\tif(table[row+1][col] != 0){\n\t\t\t\t\tadd_sum += table[row+1][col];\n\t\t\t\t\tadd_loc += POW[SHITA];\n\t\t\t\t}\n\n\t\t\t\tif(add_loc == 0){ //数字を除く必要がない場合\n\n\t\t\t\t\t//右に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t}\n\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\tnext_state += POW[Left]; //今いる場所は加算済み、または0、よって右のマスは今のマスを見る必要はない\n\n\t\t\t\t\t//右→「今いる場所になる」\n\t\t\t\t\tnext_state += POW[Here]; //★add_loc == 0により\n\n\t\t\t\t\t//下は左下になる\n\t\t\t\t\tnext_state += POW[Left_South]; //★add_loc == 0なので、table[row][col+1]は、新しい左下を無視して良いということ!\n\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]);\n\n\t\t\t\t\t//下に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\tnext_state += POW[North];\n\n\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t}\n\t\t\t\t\t//右は右上になる\n\t\t\t\t\tnext_state += POW[Right_North]; //★add_loc == 0のため\n\t\t\t\t\t//下は「今いる場所」になる\n\t\t\t\t\tnext_state += POW[Here]; //★add_loc == 0のため、無条件で良い\n\n\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]);\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\t//数字を除く必要がある場合\n\n\t\t\t\tfor(int remove_loc = 0; remove_loc <= 4; remove_loc++){\n\t\t\t\t\tif(remove_loc == 2){\n\n\t\t\t\t\t\tif(add_loc == POW[KOKO]){ //★★今いる場所だけを加算した場合★★\n\n\t\t\t\t\t\t\t//右に進む\n\t\t\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\t\t\tnext_state += POW[Left]; //今いる場所は加算済み、または0、よって右のマスは今のマスを見る必要はない\n\n\t\t\t\t\t\t\t//右→「今いる場所になる」\n\t\t\t\t\t\t\tnext_state += POW[Here]; //★add_loc == POW[KOKO]により\n\n\t\t\t\t\t\t\t//下は左下になる\n\t\t\t\t\t\t\tnext_state += POW[Left_South]; //★add_loc == POW[KOKO]なので、table[row][col+1]は、新しい左下を無視して良いということ!\n\t\t\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]+table[row][col]);\n\n\t\t\t\t\t\t\t//下に進む\n\t\t\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\t\t\tnext_state += POW[North];\n\n\t\t\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//右は右上になる\n\t\t\t\t\t\t\tnext_state += POW[Right_North]; //★add_loc == POW[KOKO]のため\n\t\t\t\t\t\t\t//下は「今いる場所」になる\n\t\t\t\t\t\t\tnext_state += POW[Here]; //★add_loc == POW[KOKO]のため、無条件で良い\n\n\t\t\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]+table[row][col]);\n\n\t\t\t\t\t\t}\n\t\t\t\t\t\tcontinue; //今いる場所は除けない\n\t\t\t\t\t}\n\n\t\t\t\t\tFLG = false;\n\n\t\t\t\t\tswitch(remove_loc){\n\t\t\t\t\tcase 0: //上\n\t\t\t\t\t\tif(add_loc & (1 << UE)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row-1][col];\n\t\t\t\t\t\t\tremoved_loc = UE;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 1: //左\n\t\t\t\t\t\tif(add_loc & (1 << HIDARI)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row][col-1];\n\t\t\t\t\t\t\tremoved_loc = HIDARI;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 3: //右\n\t\t\t\t\t\tif(add_loc & (1 << MIGI)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row][col+1];\n\t\t\t\t\t\t\tremoved_loc = MIGI;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 4: //下\n\t\t\t\t\t\tif(add_loc & (1 << SHITA)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row+1][col];\n\t\t\t\t\t\t\tremoved_loc = SHITA;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(!FLG)continue;\n\n\t\t\t\t\t//右に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t}\n\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\tnext_state += POW[Left]; //table[row][col+1]から見れば、仮に左のマスから来たなら、table[row][col]は加算不要なはず(今いるセルは除けないし、0なら無視して良い)\n\n\t\t\t\t\t//右→今いる場所になる\n\t\t\t\t\tif(removed_loc != MIGI && (add_loc & (1 << MIGI)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Here]; //加算済とする\n\t\t\t\t\t}\n\n\t\t\t\t\t//下→左下になる\n\t\t\t\t\tif(removed_loc != SHITA && (add_loc & (1 << SHITA)) != 0){ //下は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Left_South]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]+removed_add);\n\n\t\t\t\t\t//下に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\tnext_state += POW[North]; //右に進む場合と同様の理由で、無条件で良し\n\n\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t}\n\t\t\t\t\t//右は右上になる\n\t\t\t\t\tif(removed_loc != MIGI && (add_loc & (1 << MIGI)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Right_North]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\t//下は今いる場所になる\n\t\t\t\t\tif(removed_loc != SHITA && (add_loc & (1 << SHITA)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Here]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]+removed_add);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = BIG_NUM;\n\tfor(int state = 0; state < 32; state++){\n\t\tans = min(ans,min_cost[H][W][state]);\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 134232, "score_of_the_acc": -0.2644, "final_rank": 9 }, { "submission_id": "aoj_0624_9072333", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint dp[2][3][3][1001][1001];\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int h, w;\n cin >> h >> w;\n vector<vector<int>> cost(h + 1, vector<int>(w + 1));\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n char c;\n cin >> c;\n if (c == '.') continue;\n cost[i][j] = c - '0';\n }\n }\n for (int i = 0; i < 2; ++i) {\n for (int j = 0; j < 3; ++j) {\n for (int k = 0; k < 3; ++k) {\n for (int l = 0; l < h; ++l) {\n for (int m = 0; m < w; ++m) {\n dp[i][j][k][l][m] = 1e9;\n }\n }\n }\n }\n }\n // 0:無し,1:下,2:右)\n dp[0][0][1][0][0] = cost[0][0] + cost[0][1];\n dp[0][0][1][0][0] = cost[0][0] + cost[1][0];\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n for (int p = 0; p < 2; ++p) {\n for (int q = 0; q < 3; ++q) {\n for (int r = 0; r < 3; ++r) {\n int pre = dp[p][q][r][i][j];\n if (pre == 1e9) continue;\n if (i + 1 < h) {\n int nxt = pre;\n if (r == 1) nxt += cost[i + 1][j];\n // 左使わない\n dp[0][r][0][i + 1][j] = min(dp[0][r][0][i + 1][j], nxt + cost[i + 2][j] + cost[i + 1][j + 1]);\n int add = 0;\n if (p == 0) {\n if (j) add = cost[i + 1][j - 1];\n } else {\n if (q == 1 and j) add = cost[i + 1][j - 1];\n }\n // 下使わない\n dp[0][r][1][i + 1][j] = min(dp[0][r][1][i + 1][j], nxt + cost[i + 1][j + 1] + add);\n // 右使わない\n dp[0][r][2][i + 1][j] = min(dp[0][r][2][i + 1][j], nxt + cost[i + 2][j] + add);\n }\n if (j + 1 < w) {\n int nxt = pre;\n if (r == 2) nxt += cost[i][j + 1];\n // 上使わない\n dp[1][r][0][i][j + 1] = min(dp[1][r][0][i][j + 1], nxt + cost[i][j + 2] + cost[i + 1][j + 1]);\n int add = 0;\n if (p == 1) {\n if (i) add = cost[i - 1][j + 1];\n } else {\n if (q == 2 and i) add = cost[i - 1][j + 1];\n }\n // 右使わない\n dp[1][r][2][i][j + 1] = min(dp[1][r][2][i][j + 1], nxt + cost[i + 1][j + 1] + add);\n // 下使わない\n dp[1][r][1][i][j + 1] = min(dp[1][r][1][i][j + 1], nxt + cost[i][j + 2] + add);\n }\n }\n }\n }\n }\n }\n int res = 1e9;\n for (int i = 0; i < 2; ++i) {\n for (int j = 0; j < 3; ++j) {\n for (int k = 0; k < 3; ++k) {\n res = min(res, dp[i][j][k][h - 1][w - 1]);\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 77188, "score_of_the_acc": -0.1428, "final_rank": 5 }, { "submission_id": "aoj_0624_7019321", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n//1 2 4 : 7\n//8 16 32 : 56 \n//64 128 256 : 448\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n int h, w, INF = 1 << 30;\n cin >> h >> w;\n vector<string> A(h);\n vector<int> c = {2, 8, 32, 128};\n vector<pair<int,int>> dir = {{-1, 0}, {0, -1}, {0, 1}, {1, 0}};\n vector<vector<int>> B(h, vector<int>(w)), nxt(w, vector<int>(1 << 9, INF));\n vector<vector<vector<int>>> dp(2, vector<vector<int>>(w, vector<int>(1 << 9, INF)));\n for(auto &&s:A)cin >> s;\n dp[0][0][16] = (A[0][0] == '.' ? '0' : '1') - '0';\n auto f = [&](int s, int y, int x, int S, int fv){\n int v = 0, dy, dx, T = 2 + 16 + 8 + 32 + 128;\n if(y >= h || x >= w)return;\n if(!(S & 16) && A[y][x] != '.')v += A[y][x] - '0';\n for(int i = 0; i < 4; i++){\n tie(dy, dx) = dir[i];\n if(S & c[i])continue;\n if(y + dy < 0 || y + dy >= h || x + dx < 0 || x + dx >= w)continue;\n if(A[y + dy][x + dx] == '.')continue;\n v += A[y + dy][x + dx] - '0';\n }\n dp[s][x][S | T] = min(dp[s][x][S | T], fv + v);\n for(int i = 0; i < 4; i++){\n tie(dy, dx) = dir[i];\n int dec = 0;\n if(S & c[i])continue;\n if(y + dy < 0 || y + dy >= h || x + dx < 0 || x + dx >= w)continue;\n if(A[y + dy][x + dx] != '.')dec = A[y + dy][x + dx] - '0';\n dp[s][x][S | (T ^ c[i])] = min(dp[s][x][S | (T ^ c[i])], fv + v - dec);\n }\n };\n for(int y = 0; y < h; y++){\n dp[1] = nxt;\n for(int x = 0; x < w; x++){\n for(int S = 0; S < (1 << 9); S++){\n if(dp[0][x][S] == INF)continue;\n f(1, y + 1, x, S >> 3, dp[0][x][S]);\n f(0, y, x + 1, (S ^ (S & 1) ^ (S & 8) ^ (S & 64)) >> 1, dp[0][x][S]);\n }\n }\n if(y + 1 != h)swap(dp[0], dp[1]);\n }\n cout << *min_element(dp[0][w - 1].begin(), dp[0][w - 1].end()) << '\\n';\n}", "accuracy": 1, "time_ms": 1100, "memory_kb": 15048, "score_of_the_acc": -0.1708, "final_rank": 6 }, { "submission_id": "aoj_0624_5840940", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n\nint has(int a, int k){\n return (a >> k) & 1;\n}\n\nint h, w;\nstring s[1010];\n\nbool inside(int y, int x){\n return 0 <= y && y < h && 0 <= x && x < w;\n}\n\nint get(int y, int x){\n if(!inside(y, x) || s[y][x] == '.'){\n return -1;\n }else{\n return s[y][x] - '0';\n }\n}\n\nint dp[1010][1010][2][2][2][2][2];\n\nint move(int y, int x, bool t, bool u, bool ur, bool l, bool ld){\n if(y > h - 1 || x > w - 1) return 1e9;\n if(y == h - 1 && x == w - 1) return 0;\n if(dp[y][x][t][u][ur][l][ld] != -1){\n return dp[y][x][t][u][ur][l][ld];\n }\n \n int a = get(y, x);\n int ua = get(y - 1, x);\n int la = get(y, x - 1);\n int da = get(y + 1, x);\n int ra = get(y, x + 1);\n \n vector<char> yatai;\n if(ua != -1 && !u) yatai.push_back('u');\n if(la != -1 && !l) yatai.push_back('l');\n if(da != -1) yatai.push_back('d');\n if(ra != -1) yatai.push_back('r');\n \n if(yatai.empty()) yatai.push_back('u');\n \n int ans = 1e9;\n for(char c: yatai){\n int flag = 0, sum = 0;\n for(char d: yatai){\n if(c == d) continue;\n if(d == 'u') flag += (1 << 0), sum += ua;\n if(d == 'l') flag += (1 << 1), sum += la;\n if(d == 'd') flag += (1 << 2), sum += da;\n if(d == 'r') flag += (1 << 3), sum += ra;\n }\n\n if(a != -1 && !t) sum += a;\n \n // GO DOWN\n do{\n if(y == h - 1) break;\n \n bool t2 = has(flag, 2);\n bool u2 = true;\n bool ur2 = has(flag, 3);\n bool l2 = ld;\n bool ld2 = false;\n \n ans = min(ans, sum + move(y + 1, x, t2, u2, ur2, l2, ld2));\n }while(0);\n \n // GO RIGHT\n do{\n if(x == w - 1) break;\n \n bool t2 = has(flag, 3);\n bool u2 = ur;\n bool ur2 = false;\n bool l2 = true;\n bool ld2 = has(flag, 2);\n \n ans = min(ans, sum + move(y, x + 1, t2, u2, ur2, l2, ld2));\n }while(0);\n }\n \n return dp[y][x][t][u][ur][l][ld] = ans;\n}\n\nint main(){\n cin >> h >> w;\n rep(i, h) cin >> s[i];\n \n memset(dp, -1, sizeof(dp));\n int ans1 = move(0, 1, false, false, false, false, false);\n int ans2 = move(1, 0, false, false, false, false, false);\n cout << min(ans1, ans2) << endl;\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 133320, "score_of_the_acc": -0.3476, "final_rank": 12 }, { "submission_id": "aoj_0624_4571037", "code_snippet": "#include <iostream>\n#include <utility>\n#include <tuple>\n#include <vector>\n#include <string>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <algorithm>\n#include <functional>\n#include <climits>\n#include <numeric>\n#include <queue>\n#include <cmath>\n#include <iomanip>\n#include <array>\n#include <string>\n#include <stack>\n#include <cassert>\n#include <memory>\n\ntemplate<typename T>\nbool contains(const std::vector<T>& list, const T& target) {\n\treturn std::find(list.begin(), list.end(), target) != list.end();\n}\ntemplate<typename T, int C>\nbool contains(const std::array<T, C>& array, const T& target) {\n\treturn std::find(array.begin(), array.end(), target) != array.end();\n}\nstruct Coordinate {\n\tint x{ 0 }, y{ 0 };\n\tconstexpr Coordinate operator+(const Coordinate& that) const {\n\t\treturn Coordinate{ x + that.x, y + that.y };\n\t}\n\tconstexpr bool operator==(const Coordinate& that) const {\n\t\treturn x == that.x && y == that.y;\n\t}\n\tconstexpr Coordinate operator-(const Coordinate& that) const {\n\t\treturn Coordinate{ x - that.x, y - that.y };\n\t}\n\tCoordinate& operator+=(const Coordinate& that) {\n\t\tx += that.x; y += that.y;\n\t\treturn *this;\n\t}\n};\nconstexpr std::array<Coordinate, 4> relative{ Coordinate{1, -1}, Coordinate{1, 0}, Coordinate{0, 1}, Coordinate{-1, 1} };\nconstexpr std::array<Coordinate, 2> next{ Coordinate{1, 0}, Coordinate{0, 1} };\nconstexpr std::array<Coordinate, 4> neighbor{ Coordinate{1, 0}, Coordinate{-1, 0}, Coordinate{0, 1}, Coordinate{0, -1} };\n\nstruct State {\n\tint pattern{ 0 };\n\tstd::vector<Coordinate> bought() const {\n\t\tstd::vector<Coordinate> result;\n\t\tfor (auto i = 0; i < 4; ++i) {\n\t\t\tif (((1 << i) & pattern) != 0) {\n\t\t\t\tresult.push_back(relative[i]);\n\t\t\t}\n\t\t}\n\t\treturn result;\n\t}\n\tState() {}\n\tState(const Coordinate position, const std::vector<Coordinate>& bought) {\n\t\tfor (auto i = 0; i < 4; ++i) {\n\t\t\tif (contains(bought, position + relative[i])) {\n\t\t\t\tpattern += 1 << i;\n\t\t\t}\n\t\t}\n\t}\n};\nstruct Tuple {\n\tState state;\n\tCoordinate position;\n\tint cost;\n};\ntemplate<typename T>\nstd::vector<T> operator+(const std::vector<T>& a, const std::vector<T>& b) {\n\tstd::vector<T> result; result.resize(a.size() + b.size());\n\tfor (const auto& v : a) result.push_back(v);\n\tfor (const auto& v : b) result.push_back(v);\n\treturn result;\n}\nstd::vector<Tuple> next_state(const std::vector<std::vector<int>>& map, const Tuple tuple) {\n\tauto bought = tuple.state.bought(); for (auto& b : bought) b += tuple.position;\n\tstd::vector<Tuple> result;\n\tfor (const auto &dp : next) {\n\t\tconst auto next = dp + tuple.position;\n\t\tif (0 > next.y || next.y >= map.size() || 0 > next.x || next.x >= map[next.y].size()) continue;\n\t\tstd::vector<Coordinate> shop;\n\t\tint cost{ contains(bought, next) ? 0 : map[next.y][next.x] };\n\t\tfor (const auto &np : neighbor) {\n\t\t\tconst auto s = next + np;\n\t\t\tif (0 > s.y || s.y >= map.size() || 0 > s.x || s.x >= map[s.y].size()) continue;\n\t\t\tif (s == tuple.position || map[s.y][s.x] == 0 || contains(bought, s)) continue;\n\t\t\tshop.push_back(s);\n\t\t\tcost += map[s.y][s.x];\n\t\t}\n\t\tcost += tuple.cost;\n\t\tconst auto last_state = State(next, bought + shop);\n\t\tresult.push_back(Tuple{ last_state, next, cost });\n\t\tfor (const auto np: neighbor) {\n\t\t\tconst auto sp = next + np;\n\t\t\tif (!contains(shop, sp)) continue;\n\t\t\tauto ri = std::distance(relative.begin(), std::find(relative.begin(), relative.end(), np));\n\t\t\tauto last = last_state;\n\t\t\tif (ri < 4) {\n\t\t\t\tlast.pattern -= 1 << ri;\n\t\t\t}\n\t\t\tresult.push_back(Tuple{ last, next, cost - map[sp.y][sp.x] });\n\t\t}\n\t}\n\treturn result;\n}\n\nint main() {\n\tint height, width; std::cin >> height >> width;\n\tstd::vector<std::vector<int>> map(height, std::vector<int>(width));\n\tfor (auto i = 0; i < height; ++i) {\n\t\tstd::string str; std::cin >> str;\n\t\tfor (auto j = 0; j < width; ++j) {\n\t\t\tswitch (str[j]) {\n\t\t\tcase '.': map[i][j] = 0; break;\n\t\t\tdefault: map[i][j] = str[j] - '0';\n\t\t\t}\n\t\t}\n\t}\n\tstd::vector<std::vector<std::vector<int>>> min_cost(height, std::vector<std::vector<int>>(width, std::vector<int>(1 << 4, INT_MAX)));\n\tconst auto comparator = [](const Tuple& a, const Tuple& b) {return a.cost > b.cost; };\n\tstd::priority_queue<Tuple, std::vector<Tuple>, decltype(comparator)> queue(comparator);\n\tmin_cost[0][0][0] = 0;\n\tqueue.push(Tuple{ State(), Coordinate(), 0 });\n\twhile (!queue.empty()) {\n\t\tauto top = queue.top(); queue.pop();\n\t\tif (min_cost[top.position.y][top.position.x][top.state.pattern] != top.cost) continue;\n\t\tif (top.position == Coordinate{ width - 1, height - 1 }) break;\n\t\tfor (auto next : next_state(map, top)) {\n\t\t\tif (min_cost[next.position.y][next.position.x][next.state.pattern] > next.cost) {\n\t\t\t\tmin_cost[next.position.y][next.position.x][next.state.pattern] = next.cost;\n\t\t\t\tqueue.push(next);\n\t\t\t}\n\t\t}\n\t}\n\tstd::cout << *std::min_element(min_cost.back().back().begin(), min_cost.back().back().end()) << std::endl;\n}", "accuracy": 1, "time_ms": 6750, "memory_kb": 109572, "score_of_the_acc": -1.2007, "final_rank": 18 }, { "submission_id": "aoj_0624_4157944", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nint A[1006][1006], dp[1006][1006][9];\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint H, W;\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; ++i) {\n\t\tstring S;\n\t\tcin >> S;\n\t\tfor (int j = 0; j < W; ++j) {\n\t\t\tif (S[j] != '.') {\n\t\t\t\tA[i + 1][j + 1] = S[j] - '0';\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 1; i <= H; ++i) {\n\t\tfor (int j = 1; j <= W; ++j) {\n\t\t\tfor (int k = 0; k < 9; ++k) {\n\t\t\t\tdp[i][j][k] = inf;\n\t\t\t}\n\t\t}\n\t}\n\tdp[1][1][0] = A[0][0] + A[1][0];\n\tdp[1][1][1] = A[0][0] + A[0][1];\n\tfor (int i = 1; i <= H; ++i) {\n\t\tfor (int j = 1; j <= W; ++j) {\n\t\t\tif (j < W) {\n\t\t\t\tdp[i][j + 1][0] = min(dp[i][j + 1][0], A[i + 1][j + 1] + min({ dp[i][j][1] + A[i - 1][j + 1], dp[i][j][4] + A[i - 1][j + 1], dp[i][j][7] }));\n\t\t\t\tdp[i][j + 1][1] = min(dp[i][j + 1][1], A[i][j + 2] + min({ dp[i][j][1] + A[i - 1][j + 1], dp[i][j][4] + A[i - 1][j + 1] , dp[i][j][7] }));\n\t\t\t\tdp[i][j + 1][2] = min(dp[i][j + 1][2], A[i][j + 2] + A[i + 1][j + 1] + min({ dp[i][j][1], dp[i][j][4], dp[i][j][7] }));\n\t\t\t\tdp[i][j + 1][3] = min(dp[i][j + 1][3], A[i + 1][j + 1] + min({ dp[i][j][0] + A[i][j + 1] + A[i - 1][j + 1], dp[i][j][2] + A[i - 1][j + 1], dp[i][j][3] + A[i][j + 1] + A[i - 1][j + 1], dp[i][j][5] + A[i - 1][j + 1], dp[i][j][6] + A[i][j + 1], dp[i][j][8] }));\n\t\t\t\tdp[i][j + 1][4] = min(dp[i][j + 1][4], A[i][j + 2] + min({ dp[i][j][0] + A[i][j + 1] + A[i - 1][j + 1], dp[i][j][2] + A[i - 1][j + 1], dp[i][j][3] + A[i][j + 1] + A[i - 1][j + 1], dp[i][j][5] + A[i - 1][j + 1], dp[i][j][6] + A[i][j + 1], dp[i][j][8] }));\n\t\t\t\tdp[i][j + 1][5] = min(dp[i][j + 1][5], A[i][j + 2] + A[i + 1][j + 1] + min({ dp[i][j][0] + A[i][j + 1] , dp[i][j][2], dp[i][j][3] + A[i][j + 1], dp[i][j][5], dp[i][j][6] + A[i][j + 1], dp[i][j][8] }));\n\t\t\t}\n\t\t\tif (i < H) {\n\t\t\t\tdp[i + 1][j][0] = min(dp[i + 1][j][0], A[i + 2][j] + min({ dp[i][j][0] + A[i + 1][j - 1], dp[i][j][3], dp[i][j][6] + A[i + 1][j - 1] }));\n\t\t\t\tdp[i + 1][j][1] = min(dp[i + 1][j][1], A[i + 1][j + 1] + min({ dp[i][j][0] + A[i + 1][j - 1], dp[i][j][3], dp[i][j][6] + A[i + 1][j - 1] }));\n\t\t\t\tdp[i + 1][j][2] = min(dp[i + 1][j][2], A[i + 2][j] + A[i + 1][j + 1] + min({ dp[i][j][0], dp[i][j][3], dp[i][j][6] }));\n\t\t\t\tdp[i + 1][j][6] = min(dp[i + 1][j][6], A[i + 2][j] + min({ dp[i][j][1] + A[i + 1][j] + A[i + 1][j - 1], dp[i][j][2] + A[i + 1][j - 1], dp[i][j][4] + A[i + 1][j], dp[i][j][5], dp[i][j][7] + A[i + 1][j] + A[i + 1][j - 1], dp[i][j][8] + A[i + 1][j - 1] }));\n\t\t\t\tdp[i + 1][j][7] = min(dp[i + 1][j][7], A[i + 1][j + 1] + min({ dp[i][j][1] + A[i + 1][j] + A[i + 1][j - 1], dp[i][j][2] + A[i + 1][j - 1], dp[i][j][4] + A[i + 1][j], dp[i][j][5], dp[i][j][7] + A[i + 1][j] + A[i + 1][j - 1], dp[i][j][8] + A[i + 1][j - 1] }));\n\t\t\t\tdp[i + 1][j][8] = min(dp[i + 1][j][8], A[i + 2][j] + A[i + 1][j + 1] + min({ dp[i][j][1] + A[i + 1][j], dp[i][j][2], dp[i][j][4] + A[i + 1][j], dp[i][j][5], dp[i][j][7] + A[i + 1][j], dp[i][j][8] }));\n\t\t\t}\n\t\t}\n\t}\n\tint ans = *min_element(dp[H][W], dp[H][W] + 9);\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 42548, "score_of_the_acc": -0.0684, "final_rank": 1 }, { "submission_id": "aoj_0624_4135606", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <tuple>\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconstexpr int INF = 1 << 30;\n\nconst std::vector<int> dx{0, 1, 0, -1, 0}, dy{1, 0, -1, 0, 0};\nconst std::vector<int> di{0, 0, 1, 1, 2}, dj{1, 2, 0, 1, 0};\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n auto cost = vec(h, vec(w, 0));\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n char c;\n std::cin >> c;\n if (c != '.') cost[x][y] = c - '0';\n }\n }\n\n auto dist = vec(h, vec(w, vec(1 << 5, INF)));\n dist[0][0][0] = 0;\n MinHeap<std::tuple<int, int, int, int>> que;\n que.emplace(dist[0][0][0], 0, 0, 0);\n\n auto circ = vec(4, vec(4, false));\n while (!que.empty()) {\n int d, x, y, b;\n std::tie(d, x, y, b) = que.top();\n que.pop();\n if (dist[x][y][b] < d) continue;\n\n for (int l = 0; l < 5; ++l) {\n int i = di[l], j = dj[l];\n circ[i][j] = ((b >> l) & 1);\n }\n\n int nd = d;\n if (!circ[1][1] && cost[x][y] > 0) {\n nd += cost[x][y];\n circ[1][1] = true;\n }\n\n std::vector<int> att;\n for (int k = 0; k < 4; ++k) {\n int pi = dx[k] + 1, pj = dy[k] + 1;\n int px = x + dx[k], py = y + dy[k];\n\n if (px < 0 || h <= px || py < 0 || w <= py) continue;\n if (circ[pi][pj] || cost[px][py] == 0) continue;\n att.push_back(k);\n }\n\n for (int p = 0; p <= (int)att.size(); ++p) {\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd += cost[nx][ny];\n circ[ni][nj] = true;\n }\n\n for (int l = 0; l < 2; ++l) {\n int bi = dx[l], bj = dy[l],\n nx = x + dx[l], ny = y + dy[l];\n if (nx < 0 || h <= nx || ny < 0 || w <= ny) continue;\n\n int nb = 0;\n for (int k = 0; k < 5; ++k) {\n int i = bi + di[k], j = bj + dj[k];\n nb |= (circ[i][j] << k);\n }\n\n if (dist[nx][ny][nb] <= nd) continue;\n dist[nx][ny][nb] = nd;\n que.emplace(dist[nx][ny][nb], nx, ny, nb);\n }\n\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd -= cost[nx][ny];\n circ[ni][nj] = false;\n }\n }\n }\n\n const auto& last = dist.back().back();\n std::cout << *std::min_element(last.begin(), last.end()) << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 4820, "memory_kb": 171932, "score_of_the_acc": -1.0358, "final_rank": 16 }, { "submission_id": "aoj_0624_4135603", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <tuple>\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconstexpr int INF = 1 << 30;\n\nconst std::vector<int> dx{0, 1, 0, -1, 0}, dy{1, 0, -1, 0, 0};\nconst std::vector<int> di{0, 0, 1, 1, 2}, dj{1, 2, 0, 1, 0};\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n auto cost = vec(h, vec(w, 0));\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n char c;\n std::cin >> c;\n if (c != '.') cost[x][y] = c - '0';\n }\n }\n\n auto dist = vec(h, vec(w, vec(1 << 6, INF)));\n dist[0][0][0] = 0;\n MinHeap<std::tuple<int, int, int, int>> que;\n que.emplace(dist[0][0][0], 0, 0, 0);\n\n auto circ = vec(4, vec(4, false));\n while (!que.empty()) {\n int d, x, y, b;\n std::tie(d, x, y, b) = que.top();\n que.pop();\n if (dist[x][y][b] < d) continue;\n\n for (int l = 0; l < 5; ++l) {\n int i = di[l], j = dj[l];\n circ[i][j] = ((b >> l) & 1);\n }\n\n int nd = d;\n if (!circ[1][1] && cost[x][y] > 0) {\n nd += cost[x][y];\n circ[1][1] = true;\n }\n\n std::vector<int> att;\n for (int k = 0; k < 4; ++k) {\n int pi = dx[k] + 1, pj = dy[k] + 1;\n int px = x + dx[k], py = y + dy[k];\n\n if (px < 0 || h <= px || py < 0 || w <= py) continue;\n if (circ[pi][pj] || cost[px][py] == 0) continue;\n att.push_back(k);\n }\n\n for (int p = 0; p <= (int)att.size(); ++p) {\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd += cost[nx][ny];\n circ[ni][nj] = true;\n }\n\n for (int l = 0; l < 2; ++l) {\n int bi = dx[l], bj = dy[l],\n nx = x + dx[l], ny = y + dy[l];\n if (nx < 0 || h <= nx || ny < 0 || w <= ny) continue;\n\n int nb = 0;\n for (int k = 0; k < 5; ++k) {\n int i = bi + di[k], j = bj + dj[k];\n nb |= (circ[i][j] << k);\n }\n\n if (dist[nx][ny][nb] <= nd) continue;\n dist[nx][ny][nb] = nd;\n que.emplace(dist[nx][ny][nb], nx, ny, nb);\n }\n\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd -= cost[nx][ny];\n circ[ni][nj] = false;\n }\n }\n }\n\n const auto& last = dist.back().back();\n std::cout << *std::min_element(last.begin(), last.end()) << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 4920, "memory_kb": 297080, "score_of_the_acc": -1.2979, "final_rank": 19 }, { "submission_id": "aoj_0624_4135594", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <tuple>\n#include <bitset>\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconstexpr int INF = 1 << 30;\n\nconst std::vector<int> dx{0, 1, 0, -1, 0}, dy{1, 0, -1, 0, 0};\nconst std::vector<int> di{0, 0, 0, 1, 1, 2}, dj{0, 1, 2, 0, 1, 0};\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n auto cost = vec(h, vec(w, 0));\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n char c;\n std::cin >> c;\n if (c != '.') cost[x][y] = c - '0';\n }\n }\n\n auto dist = vec(h, vec(w, vec(1 << 6, INF)));\n dist[0][0][0] = 0;\n MinHeap<std::tuple<int, int, int, int>> que;\n que.emplace(dist[0][0][0], 0, 0, 0);\n\n auto circ = vec(4, vec(4, false));\n while (!que.empty()) {\n int d, x, y, b;\n std::tie(d, x, y, b) = que.top();\n que.pop();\n if (dist[x][y][b] < d) continue;\n\n for (int l = 0; l < 6; ++l) {\n int i = di[l], j = dj[l];\n circ[i][j] = ((b >> l) & 1);\n }\n\n int nd = d;\n if (!circ[1][1] && cost[x][y] > 0) {\n nd += cost[x][y];\n circ[1][1] = true;\n }\n\n std::vector<int> att;\n for (int k = 0; k < 4; ++k) {\n int pi = dx[k] + 1, pj = dy[k] + 1;\n int px = x + dx[k], py = y + dy[k];\n\n if (px < 0 || h <= px || py < 0 || w <= py) continue;\n if (circ[pi][pj] || cost[px][py] == 0) continue;\n att.push_back(k);\n }\n\n for (int p = 0; p <= (int)att.size(); ++p) {\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd += cost[nx][ny];\n circ[ni][nj] = true;\n }\n\n for (int l = 0; l < 2; ++l) {\n int bi = dx[l], bj = dy[l],\n nx = x + dx[l], ny = y + dy[l];\n if (nx < 0 || h <= nx || ny < 0 || w <= ny) continue;\n\n int nb = 0;\n for (int k = 0; k < 6; ++k) {\n int i = bi + di[k], j = bj + dj[k];\n nb |= (circ[i][j] << k);\n }\n\n if (dist[nx][ny][nb] <= nd) continue;\n dist[nx][ny][nb] = nd;\n que.emplace(dist[nx][ny][nb], nx, ny, nb);\n }\n\n for (int i = 0; i < (int)att.size(); ++i) {\n if (i == p) continue;\n\n int k = att[i];\n int ni = dx[k] + 1, nj = dy[k] + 1;\n int nx = x + dx[k], ny = y + dy[k];\n\n nd -= cost[nx][ny];\n circ[ni][nj] = false;\n }\n }\n }\n\n const auto& last = dist.back().back();\n std::cout << *std::min_element(last.begin(), last.end()) << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 6100, "memory_kb": 297060, "score_of_the_acc": -1.4739, "final_rank": 20 }, { "submission_id": "aoj_0624_4075258", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntemplate<class T,class U> using P = pair<T,U>;\ntemplate<class T> using vec = vector<T>;\ntemplate<class T> using vvec = vector<vec<T>>;\n\nint dp[1002][1002][2][2][2][2];\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int H,W;\n cin >> H >> W;\n vvec<int> F(H+2,vec<int>(W+2,0));\n for(int i=1;i<=H;i++) for(int j=1;j<=W;j++){\n char c;\n cin >> c;\n if(c!='.') F[i][j] = c-'0';\n }\n const int inf = 1e9;\n for(int i=0;i<=H;i++) for(int j=0;j<=W;j++){\n for(int a=0;a<2;a++) for(int b=0;b<2;b++) for(int c=0;c<2;c++) for(int d=0;d<2;d++) dp[i][j][a][b][c][d] = inf;\n }\n for(int a=0;a<2;a++) for(int b=0;b<2;b++) for(int c=0;c<2;c++) for(int d=0;d<2;d++) dp[1][1][a][b][c][d] = 0;\n for(int i=1;i<=H;i++) for(int j=1;j<=W;j++){\n for(int a=0;a<2;a++) for(int b=0;b<2;b++) for(int c=0;c<2;c++) for(int d=0;d<2;d++){\n //右に\n if(j<W){\n int p = (a? F[i][j+1]:0);\n //上を取らない\n dp[i][j+1][0][1][0][c] = min(dp[i][j+1][0][1][0][c],dp[i][j][a][b][c][d]+p+F[i][j+2]+F[i+1][j+1]);\n //右を取らない\n dp[i][j+1][1][1][0][c] = min(dp[i][j+1][1][1][0][c],dp[i][j][a][b][c][d]+p+(b? F[i-1][j+1]:0)+F[i+1][j+1]);\n //下を取らない\n dp[i][j+1][0][1][1][c] = min(dp[i][j+1][0][1][1][c],dp[i][j][a][b][c][d]+p+(b? F[i-1][j+1]:0)+F[i][j+2]);\n }\n if(i<H){\n int p = (c? F[i+1][j]:0);\n //左を取らない\n dp[i+1][j][0][a][0][1] = min(dp[i+1][j][0][a][0][1],dp[i][j][a][b][c][d]+p+F[i+2][j]+F[i+1][j+1]);\n //右を取らない\n dp[i+1][j][1][a][0][1] = min(dp[i+1][j][1][a][0][1],dp[i][j][a][b][c][d]+p+(d? F[i+1][j-1]:0)+F[i+2][j]);\n //下を取らない\n dp[i+1][j][0][a][1][1] = min(dp[i+1][j][0][a][1][1],dp[i][j][a][b][c][d]+p+(d? F[i+1][j-1]:0)+F[i+1][j+1]);\n }\n }\n }\n int ans = inf;\n for(int a=0;a<2;a++) for(int b=0;b<2;b++) for(int c=0;c<2;c++) for(int d=0;d<2;d++) ans = min(ans,dp[H][W][a][b][c][d]);\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 69600, "score_of_the_acc": -0.1352, "final_rank": 4 }, { "submission_id": "aoj_0624_3977958", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"functional\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//const int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\n\n//const double EPS = 1e-8;\n\n//int N, M, K, H, W, L, R;\nlong long int N, M, K, H, W, L, R;\n\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> H >> W;\n\tvector<string>s(H);\n\tfor (auto &i : s)cin >> i;\n\tvector<vector<int>>v(H + 2, vector<int>(W + 2));\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tif (s[i - 1][j - 1] == '.')continue;\n\t\t\tv[i][j] = s[i - 1][j - 1] - '0';\n\t\t}\n\t}\n\tint dy[] = { -1,0,1,1 };\n\tint dx[] = { 1,1,0,-1 };\n\ts[0] = s.back() = string(W + 2, '.');\n\tvector<vector<vector<int>>>dp(H + 2, vector<vector<int>>(W + 2, vector<int>(16, MOD)));\n\tdp[1][1][2] = v[1][1] + v[2][1];\n\tdp[1][1][4] = v[1][1] + v[1][2];\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tfor (int k = 0; k < 16; k++) {\n\t\t\t\tif (j < W) {\n\t\t\t\t\tint add = 0;\n\t\t\t\t\tif ((k >> 1) & 1)add = v[i][j + 1];\n\t\t\t\t\tif ((k >> 0) & 1) {\n\t\t\t\t\t\tint nx = 1;\n\t\t\t\t\t\tif ((k >> 2) & 1)nx |= 1 << 3;\n\t\t\t\t\t\tdp[i][j + 1][nx] = min(dp[i][j + 1][nx], dp[i][j][k] + add + v[i][j + 2] + v[i + 1][j + 1]);\n\t\t\t\t\t\tadd += v[i - 1][j + 1];\n\t\t\t\t\t}\n\t\t\t\t\t{\n\t\t\t\t\t\tint nx = 1 << 1;\n\t\t\t\t\t\tnx |= 1 << 0;\n\t\t\t\t\t\tif ((k >> 2) & 1)nx |= 1 << 3;\n\t\t\t\t\t\tdp[i][j + 1][nx] = min(dp[i][j + 1][nx], dp[i][j][k] + add + v[i + 1][j + 1]);\n\t\t\t\t\t}\n\t\t\t\t\t{\n\t\t\t\t\t\tint nx = 1 << 2;\n\t\t\t\t\t\tnx |= 1 << 0;\n\t\t\t\t\t\tif ((k >> 2) & 1)nx |= 1 << 3;\n\t\t\t\t\t\tdp[i][j + 1][nx] = min(dp[i][j + 1][nx], dp[i][j][k] + add + v[i][j + 2]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (i < H) {\n\t\t\t\t\tint add = 0;\n\t\t\t\t\tif ((k >> 2) & 1)add = v[i + 1][j];\n\t\t\t\t\tif ((k >> 3) & 1) {\n\t\t\t\t\t\tint nx = 1 << 3;\n\t\t\t\t\t\tif ((k >> 1) & 1)nx |= 1 << 0;\n\t\t\t\t\t\tdp[i + 1][j][nx] = min(dp[i + 1][j][nx], dp[i][j][k] + add + v[i + 2][j] + v[i + 1][j + 1]);\n\t\t\t\t\t\tadd += v[i + 1][j - 1];\n\t\t\t\t\t}\n\t\t\t\t\t{\n\t\t\t\t\t\tint nx = 1 << 1;\n\t\t\t\t\t\tnx |= 1 << 3;\n\t\t\t\t\t\tif ((k >> 1) & 1)nx |= 1 << 0;\n\t\t\t\t\t\tdp[i + 1][j][nx] = min(dp[i + 1][j][nx], dp[i][j][k] + add + v[i + 2][j]);\n\t\t\t\t\t}\n\t\t\t\t\t{\n\t\t\t\t\t\tint nx = 1 << 2;\n\t\t\t\t\t\tnx |= 1 << 3;\n\t\t\t\t\t\tif ((k >> 1) & 1)nx |= 1 << 0;\n\t\t\t\t\t\tdp[i + 1][j][nx] = min(dp[i + 1][j][nx], dp[i][j][k] + add + v[i + 1][j + 1]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << *min_element(dp[H][W].begin(), dp[H][W].end()) << endl;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 109860, "score_of_the_acc": -0.2237, "final_rank": 7 }, { "submission_id": "aoj_0624_3975471", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n#include<random>\n#include<functional>\n#include<utility>\n\ntypedef long long ll;\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define pb push_back\n#define P pair<int, int>\n#define PLI pair<ll, int>\n#define PLL pair<ll, ll>\n#define VI vector<int>\n#define VII vector<VI>\n\nusing namespace std;\n\n\nconst int INF = 1e9;\nconst int mru = 1, mu = 1 << 1, ml = 1 << 2, mld = 1 << 3;\n\nint ToBit(int a, int b, int c, int d) {\n\treturn a + (b << 1) + (c << 2) + (d << 3);\n}\n\nint H, W;\nint stl[1005][1005], dp[1005][1005][1<<4];\nint main() {\n\tcin >> H >> W;\n\trep(i, H) rep(j, W) {\n\t\tchar c;\n\t\tcin >> c;\n\t\tstl[i + 1][j + 1] = (c == '.') ? 0 : (c - '0');\n\t}\n\n\trep(i, H) rep(j, W) rep(k, 1<<4) dp[i+1][j+1][k] = INF;\n\tdp[1][1][0] = 0;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tfor (int bit = 0; bit < (1 << 4); bit++) {\n\t\t\t\tif (dp[i][j][bit] == INF) continue;\n\t\t\t\tbool isru = bit & mru;\n\t\t\t\tbool isu = bit & mu;\n\t\t\t\tbool isl = bit & ml;\n\t\t\t\tbool isld = bit & mld;\n\n\t\t\t\tint vu = (isu ? 0 : stl[i - 1][j]);\n\t\t\t\tint vl = (isl ? 0 : stl[i][j-1]);\n\t\t\t\tint vd = stl[i+1][j];\n\t\t\t\tint vr = stl[i][j+1];\n\n\t\t\t\tint nbit, nco;\n\t\t\t\tif (i < H) {\n\t\t\t\t\tnco = vd + vr + vu;\n\t\t\t\t\tnbit = ToBit(1, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vd + vr + vl;\n\t\t\t\t\tnbit = ToBit(1, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vd + vu + vl;\n\t\t\t\t\tnbit = ToBit(0, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\t\t\t\t}\n\t\t\t\tif (j < W) {\n\t\t\t\t\tnco = vr + vu + vl;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 0);\n\t\t\t\t\tdp[i][j+1][nbit] = min(dp[i][j+1][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vr + vu + vd;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 1);\n\t\t\t\t\tdp[i][j + 1][nbit] = min(dp[i][j + 1][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vr + vl + vd;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 1);\n\t\t\t\t\tdp[i][j + 1][nbit] = min(dp[i][j + 1][nbit], dp[i][j][bit] + nco);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = INF;\n\trep(i, 1 << 4) ans = min(ans, dp[H][W][i]);\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 69828, "score_of_the_acc": -0.1297, "final_rank": 2 }, { "submission_id": "aoj_0624_3975470", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n#include<random>\n#include<functional>\n#include<utility>\n\ntypedef long long ll;\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define pb push_back\n#define P pair<int, int>\n#define PLI pair<ll, int>\n#define PLL pair<ll, ll>\n#define VI vector<int>\n#define VII vector<VI>\n\nusing namespace std;\n\n\nconst int INF = 1e9;\nconst int mru = 1, mu = 1 << 1, ml = 1 << 2, mld = 1 << 3;\n\ninline int ToBit(int a, int b, int c, int d) {\n\treturn a + (b << 1) + (c << 2) + (d << 3);\n}\n\nint H, W;\nint stl[1005][1005], dp[1005][1005][1<<4];\nint main() {\n\tcin >> H >> W;\n\trep(i, H) rep(j, W) {\n\t\tchar c;\n\t\tcin >> c;\n\t\tstl[i + 1][j + 1] = (c == '.') ? 0 : (c - '0');\n\t}\n\n\trep(i, H) rep(j, W) rep(k, 1<<4) dp[i+1][j+1][k] = INF;\n\tdp[1][1][0] = 0;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tfor (int bit = 0; bit < (1 << 4); bit++) {\n\t\t\t\tif (dp[i][j][bit] == INF) continue;\n\t\t\t\tbool isru = bit & mru;\n\t\t\t\tbool isu = bit & mu;\n\t\t\t\tbool isl = bit & ml;\n\t\t\t\tbool isld = bit & mld;\n\n\t\t\t\tint vu = (isu ? 0 : stl[i - 1][j]);\n\t\t\t\tint vl = (isl ? 0 : stl[i][j-1]);\n\t\t\t\tint vd = stl[i+1][j];\n\t\t\t\tint vr = stl[i][j+1];\n\n\t\t\t\tint nbit, nco;\n\t\t\t\tif (i < H) {\n\t\t\t\t\tnco = vd + vr + vu;\n\t\t\t\t\tnbit = ToBit(1, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vd + vr + vl;\n\t\t\t\t\tnbit = ToBit(1, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vd + vu + vl;\n\t\t\t\t\tnbit = ToBit(0, 1, isld, 0);\n\t\t\t\t\tdp[i + 1][j][nbit] = min(dp[i + 1][j][nbit], dp[i][j][bit] + nco);\n\t\t\t\t}\n\t\t\t\tif (j < W) {\n\t\t\t\t\tnco = vr + vu + vl;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 0);\n\t\t\t\t\tdp[i][j+1][nbit] = min(dp[i][j+1][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vr + vu + vd;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 1);\n\t\t\t\t\tdp[i][j + 1][nbit] = min(dp[i][j + 1][nbit], dp[i][j][bit] + nco);\n\n\t\t\t\t\tnco = vr + vl + vd;\n\t\t\t\t\tnbit = ToBit(0, isru, 1, 1);\n\t\t\t\t\tdp[i][j + 1][nbit] = min(dp[i][j + 1][nbit], dp[i][j][bit] + nco);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = INF;\n\trep(i, 1 << 4) ans = min(ans, dp[H][W][i]);\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 69808, "score_of_the_acc": -0.1312, "final_rank": 3 }, { "submission_id": "aoj_0624_3813403", "code_snippet": "#include <bits/stdc++.h>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define RFOR(i,a) for(int i=(a); i >= 0; --i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define BIT_ON(bit, i) (((bit >> i) & 1) > 0)\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\ntemplate<class T> inline void print(T x) { std::cout << x << std::endl; }\ntemplate<class T> inline void print_vec(const std::vector<T> &v) { for (int i = 0; i < v.size(); ++i) { if (i != 0) {std::cout << \" \";} std::cout << v[i];} std::cout << \"\\n\"; }\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 58u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\nclass Grid {\npublic:\n const int H;\n const int W;\n const int SPACE = 0;\n const int BLOCK = 1;\n\n std::vector<std::vector<int>> grid;\n\n Grid(int h, int w) : H(h), W(w) {\n this->grid.resize(this->H, std::vector<int>(this->W, this->SPACE));\n }\n\n void set(int y, int x, int s) {\n this->grid[y][x] = s;\n }\n};\n\nint bc[] = { 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4 };\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n LL H, W;\n cin >> H >> W;\n Grid grid(H + 10, W + 10);\n\n FOR(y, 0, H) {\n FOR(x, 0, W) {\n char c;\n cin >> c;\n if (c == '.') {\n grid.set(y + 1, x + 1, 0);\n }\n else {\n grid.set(y + 1, x + 1, c - '0');\n }\n }\n }\n\n auto dp = make_v<LL>(H + 10, W + 10, 1 << 4);\n fill_v(dp, INF);\n\n dp[1][1][15] = 0;\n FOR(i, 1, H + 1) {\n FOR(j, 1, W + 1) {\n FOR(state, 0, 1 << 4) {\n // down\n FOR(new_state, 0, 1 << 4) {\n if (((state & 4) == 0) != ((new_state & 8) == 0)) {\n continue;\n }\n if (not (state & 2)) {\n continue;\n }\n if (bc[state & 1] + bc[new_state & 6] <= 1) {\n continue;\n }\n\n LL cost = dp[i][j][state];\n if (new_state & 1) cost += grid.grid[i + 2][j - 1]; // 左下\n if (new_state & 2) cost += grid.grid[i + 2][j]; // 下\n if (new_state & 4) cost += grid.grid[i + 1][j + 1]; // 右\n\n chmin(dp[i + 1][j][new_state], cost);\n }\n\n // right\n FOR(new_state, 0, 16) {\n if (((state & 2) == 0) != ((new_state & 1) == 0)) {\n continue;\n }\n if (!(state & 4)) {\n continue;\n }\n if (bc[state & 8] + bc[new_state & 6] <= 1) {\n continue;\n }\n\n LL cost = dp[i][j][state];\n if (new_state & 8) cost += grid.grid[i - 1][j + 2];\n if (new_state & 4) cost += grid.grid[i][j + 2];\n if (new_state & 2) cost += grid.grid[i + 1][j + 1];\n\n chmin(dp[i][j + 1][new_state], cost);\n }\n }\n }\n }\n\n print(dp[H][W][15]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 610, "memory_kb": 174588, "score_of_the_acc": -0.4127, "final_rank": 13 }, { "submission_id": "aoj_0624_3634378", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing Int = long long;\ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n\n//INSERT ABOVE HERE\nconst int MAX = 1010;\nconst int INF = MAX * MAX * 10;\nint dp[2][4][4][MAX][MAX]={};\nint ts[MAX][MAX]={};\n\nsigned main(){\n int h,w;\n cin>>h>>w;\n vector<string> vs(h);\n for(int i=0;i<h;i++) cin>>vs[i],vs[i]=\"..\"+vs[i]+\"..\";\n vs.emplace(vs.begin(),string(w+4,'.'));\n vs.emplace(vs.begin(),string(w+4,'.'));\n vs.emplace_back(string(w+4,'.'));\n vs.emplace_back(string(w+4,'.'));\n \n for(int i=0;i<MAX;i++)\n for(int j=0;j<MAX;j++)\n for(int pp=0;pp<2;pp++)\n for(int pd=0;pd<4;pd++)\n for(int cd=0;cd<4;cd++)\n dp[pp][pd][cd][i][j]=INF;\n\n for(int pp=0;pp<2;pp++)\n for(int pd=0;pd<4;pd++)\n for(int cd=0;cd<4;cd++)\n dp[pp][pd][cd][2][2]=0;\n\n int cnt=1; \n int dy[]={0,1,0,-1};\n int dx[]={1,0,-1,0};\n\n for(int i=2;i<=h+1;i++){\n for(int j=2;j<=w+1;j++){\n int cy=i,cx=j;\n for(int pp=0;pp<2;pp++){\n int py=cy-dy[pp],px=cx-dx[pp];\n for(int pd=0;pd<4;pd++){\n for(int cd=0;cd<4;cd++){\n cnt++;\n ts[py][px]=ts[cy][cx]=cnt;\n for(int k=0;k<4;k++){\n if(pd!=k) ts[py+dy[k]][px+dx[k]]=cnt;\n if(cd!=k) ts[cy+dy[k]][cx+dx[k]]=cnt;\n }\n int dist=dp[pp][pd][cd][cy][cx];\n for(int npp=0;npp<2;npp++){ \n int npd=cd,ncy=cy+dy[npp],ncx=cx+dx[npp]; \n if(ts[ncy][ncx]!=cnt) continue;\n int sum=0;\n int tmp[4]={};\n for(int k=0;k<4;k++){\n int ty=ncy+dy[k],tx=ncx+dx[k];\n if(ts[ty][tx]!=cnt&&isdigit(vs[ty][tx]))\n tmp[k]=vs[ty][tx]-'0';\n sum+=tmp[k]; \n }\n for(int ncd=0;ncd<4;ncd++){\n int ndist=dist+sum-tmp[ncd];\n chmin(dp[npp][npd][ncd][ncy][ncx],ndist); \n }\n }\n }\n }\n } \n } \n }\n \n int ans=INF; \n for(int pp=0;pp<2;pp++)\n for(int pd=0;pd<4;pd++)\n for(int cd=0;cd<4;cd++)\n chmin(ans,dp[pp][pd][cd][h+1][w+1]); \n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1190, "memory_kb": 136428, "score_of_the_acc": -0.4239, "final_rank": 14 }, { "submission_id": "aoj_0624_3355483", "code_snippet": "#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#define MP(a, b) make_pair(a, b)\n#define POWER9 1000000000\n#define MOD POWER9+7\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483647\n#define INT_MAX 2147483647\n#define LL_MIN (LL)-9223372036854775807\n#define LL_MAX (LL)9223372036854775807\n#define PI 3.14159265359\n\nint H,W;\nint mp[1000][1000];\nint cost[1000][1000][32];\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> H >> W;\n for(int i=0; i<H; i++){\n for(int j=0; j<W; j++){\n char c;\n cin >> c;\n if(c == '.') mp[i][j] = 0;\n else mp[i][j] = c - '0';\n for(int k=0; k<32; k++) cost[i][j][k] = INT_MAX;\n }\n }\n cost[0][0][0] = 0;\n\n priority_queue<pair<int,pair<pair<int,int>,int> > > que;\n que.push(MP(INT_MAX, MP(MP(0,0), 0)));\n while(!que.empty()){\n int c = INT_MAX-que.top().first;\n int y = que.top().second.first.first;\n int x = que.top().second.first.second;\n int s = que.top().second.second;\n que.pop();\n if(cost[y][x][s] < c) continue;\n if(y==H-1 && x==W-1){\n cout << c << endl;\n return 0;\n }\n int d[5];\n for(int i=0; i<5; i++){\n d[i] = (s>>(4-i)) % 2;\n }\n\n int nc = 0;\n if(d[0] == 0) nc += mp[y][x];\n if(d[2] == 0 && y-1 >= 0) nc += mp[y-1][x];\n if(d[3] == 0 && x-1 >= 0) nc += mp[y][x-1];\n if(y+1 < H) nc += mp[y+1][x];\n if(x+1 < W) nc += mp[y][x+1];\n\n int tmpY = (d[4]==1 ? 2 : 0);\n int tmpX = (d[1]==1 ? 4 : 0);\n if(d[2] == 0 && y-1 >= 0){\n nc -= mp[y-1][x];\n if(y+1 < H && cost[y+1][x][16+8+4+tmpY] > c+nc){\n cost[y+1][x][16+8+4+tmpY] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y+1, x), 16+8+4+tmpY)));\n }\n if(x+1 < W && cost[y][x+1][16+2+1+tmpX] > c+nc){\n cost[y][x+1][16+2+1+tmpX] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y, x+1), 16+2+1+tmpX)));\n }\n nc += mp[y-1][x];\n }\n if(d[3] == 0 && x-1 >= 0){\n nc -= mp[y][x-1];\n if(y+1 < H && cost[y+1][x][16+8+4+tmpY] > c+nc){\n cost[y+1][x][16+8+4+tmpY] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y+1, x), 16+8+4+tmpY)));\n }\n if(x+1 < W && cost[y][x+1][16+2+1+tmpX] > c+nc){\n cost[y][x+1][16+2+1+tmpX] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y, x+1), 16+2+1+tmpX)));\n }\n nc += mp[y][x-1];\n }\n if(y+1 < H){\n nc -= mp[y+1][x];\n if(y+1 < H && cost[y+1][x][8+4+tmpY] > c+nc){\n cost[y+1][x][8+4+tmpY] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y+1, x), 8+4+tmpY)));\n }\n if(x+1 < W && cost[y][x+1][16+2+tmpX] > c+nc){\n cost[y][x+1][16+2+tmpX] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y, x+1), 16+2+tmpX)));\n }\n nc += mp[y+1][x];\n }\n if(x+1 < W){\n nc -= mp[y][x+1];\n if(y+1 < H && cost[y+1][x][16+4+tmpY] > c+nc){\n cost[y+1][x][16+4+tmpY] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y+1, x), 16+4+tmpY)));\n }\n if(x+1 < W && cost[y][x+1][2+1+tmpX] > c+nc){\n cost[y][x+1][2+1+tmpX] = c+nc;\n que.push(MP(INT_MAX-c-nc, MP(MP(y, x+1), 2+1+tmpX)));\n }\n nc += mp[y][x+1];\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 2690, "memory_kb": 132796, "score_of_the_acc": -0.6406, "final_rank": 15 }, { "submission_id": "aoj_0624_3222313", "code_snippet": "//Food Stalls\n#include <iostream>\n#include <climits>\n#include <vector>\n\nusing namespace std;\nstatic const int MAX = 1000;\n\nint H, W;\nint A[MAX + 2][MAX + 2], min_cost[MAX + 1][MAX + 1][16];\n//(i - 1, j + 1), (i, j + 1), (i + 1. j), (i + 1, j - 1)\n\nenum {\n SOUTHWEST = 0,\n SOUTH = 1,\n EAST = 2,\n NORTHEAST = 3,\n NORTH = 4,\n WEST = 5\n};\n\nint main() {\n cin >> H >> W;\n\n for(int i = 0; i < H + 2; i++) {\n A[i][0] = 0;\n A[i][W + 1] = 0;\n }\n for(int j = 0; j < W + 2; j++) {\n A[0][j] = 0;\n A[H + 1][j] = 0;\n }\n\n char c;\n for(int i = 1; i < H + 1; i++) {\n for(int j = 1; j < W + 1; j++) {\n cin >> c;\n if(c == '.') A[i][j] = 0;\n else A[i][j] = c - '0';\n }\n }\n\n for(int i = 1; i < H + 1; i++) {\n for(int j = 1; j < W + 1; j++) {\n for(int k = 0; k < 16; k++) min_cost[i][j][k] = INT_MAX;\n }\n }\n min_cost[1][1][0] = 0;\n\n for(int i = 1; i < H + 1; i++) {\n for(int j = 1; j < W + 1; j++) {\n for(int k = 0; k < 16; k++) {\n if(min_cost[i][j][k] == INT_MAX) continue;\n int next_cost, next_state;\n vector<int> v;\n //go EAST\n if(j != W) {\n next_state = ((k & 1 << SOUTH) ? (1 << SOUTHWEST) : 0);\n next_cost = (k & 1 << EAST) ? min_cost[i][j][k] : min_cost[i][j][k] + A[i][j + 1];\n if(A[i - 1][j + 1] != 0 && !(k & 1 << NORTHEAST)) {\n next_cost += A[i - 1][j + 1];\n v.push_back(NORTH);\n }\n if(A[i][j + 2] != 0) {\n next_cost += A[i][j + 2];\n v.push_back(EAST);\n next_state += (1 << EAST);\n }\n if(A[i + 1][j + 1] != 0) {\n next_cost += A[i + 1][j + 1];\n v.push_back(SOUTH);\n next_state += (1 << SOUTH);\n }\n if(v.size() > 1) {\n for(auto l: v) {\n if(l == NORTH) min_cost[i][j + 1][next_state] = min(min_cost[i][j + 1][next_state], next_cost - A[i - 1][j + 1]);\n else if(l == EAST) min_cost[i][j + 1][next_state - (1 << EAST)] = min(min_cost[i][j + 1][next_state - (1 << EAST)], next_cost - A[i][j + 2]);\n else min_cost[i][j + 1][next_state - (1 << SOUTH)] = min(min_cost[i][j + 1][next_state - (1 << SOUTH)], next_cost - A[i + 1][j + 1]);\n }\n } else {\n min_cost[i][j + 1][((k & 1 << SOUTH) ? (1 << SOUTHWEST) : 0)] =\n min(min_cost[i][j + 1][((k & 1 << SOUTH) ? (1 << SOUTHWEST) : 0)],\n ((k & 1 << EAST) ? min_cost[i][j][k] : min_cost[i][j][k] + A[i][j + 1]));\n }\n }\n //go SOUTH\n if(i != H) {\n v.clear();\n next_state = ((k & 1 << EAST) ? (1 << NORTHEAST) : 0);\n next_cost = (k & 1 << SOUTH) ? min_cost[i][j][k] : min_cost[i][j][k] + A[i + 1][j];\n if(A[i + 1][j - 1] != 0 && !(k & 1 << SOUTHWEST)) {\n next_cost += A[i + 1][j - 1];\n v.push_back(WEST);\n }\n if(A[i + 2][j] != 0) {\n next_cost += A[i + 2][j];\n v.push_back(SOUTH);\n next_state += (1 << SOUTH);\n }\n if(A[i + 1][j + 1] != 0) {\n next_cost += A[i + 1][j + 1];\n v.push_back(EAST);\n next_state += (1 << EAST);\n }\n if(v.size() > 1) {\n for(auto l: v) {\n if(l == WEST) min_cost[i + 1][j][next_state] = min(min_cost[i + 1][j][next_state], next_cost - A[i + 1][j - 1]);\n else if(l == SOUTH) min_cost[i + 1][j][next_state - (1 << SOUTH)] = min(min_cost[i + 1][j][next_state - (1 << SOUTH)], next_cost - A[i + 2][j]);\n else min_cost[i + 1][j][next_state - (1 << EAST)] = min(min_cost[i + 1][j][next_state - (1 << EAST)], next_cost - A[i + 1][j + 1]);\n }\n } else {\n min_cost[i + 1][j][((k & 1 << EAST) ? (1 << NORTHEAST) : 0)] =\n min(min_cost[i + 1][j][((k & 1 << EAST) ? (1 << NORTHEAST) : 0)],\n (k & 1 << SOUTH) ? min_cost[i][j][k] : min_cost[i][j][k] + A[i + 1][j]);\n }\n }\n }\n }\n }\n\n cout << min_cost[H][W][0] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 69588, "score_of_the_acc": -0.2292, "final_rank": 8 }, { "submission_id": "aoj_0624_3181969", "code_snippet": "#include <bits/stdc++.h>\n #include<iostream>\n #include<cstdio>\n #include<vector>\n #include<queue>\n #include<map>\n #include<cstring>\n #include<string>\n #include <math.h>\n #include<algorithm>\n // #include <boost/multiprecision/cpp_int.hpp>\n #include<functional>\n // #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n \n #define ssa pair<string,int>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-7)\n #define equals(a,b) (fabs((a)-(b))<EPS)\nint dx[4]={0,-1,0,1};\nint dy[4]={1,0,-1,0};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x,y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x>p.x: y>p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n #define ppa pair<int,pas>\n class Point{\n \tpublic:\n \tdouble x,y;\n \tPoint(double x=0,double y=0):x(x),y(y) {}\n \tPoint operator + (Point p) {return Point(x+p.x,y+p.y);}\n \tPoint operator - (Point p) {return Point(x-p.x,y-p.y);}\n \tPoint operator * (double a) {return Point(x*a,y*a);}\n \tPoint operator / (double a) {return Point(x/a,y/a);}\n \tdouble absv() {return sqrt(norm());}\n \tdouble norm() {return x*x+y*y;}\n \tbool operator < (const Point &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const Point &p) const{\n \t\treturn fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n \t}\n };\n typedef Point Vector;\n #define pl pair<int,pas>\n struct Segment{\n Point p1,p2;\n };\n double dot(Vector a,Vector b){\n \treturn a.x*b.x+a.y*b.y;\n }\n double cross(Vector a,Vector b){\n \treturn a.x*b.y-a.y*b.x;\n }\n \n bool parareru(Point a,Point b,Point c,Point d){\n //\tif(abs(cross(a-b,d-c))<EPS)cout<<\"dd \"<<cross(a-b,d-c)<<endl;\n \treturn abs(cross(a-b,d-c))<EPS;\n }\n double distance_ls_p(Point a, Point b, Point c) {\n if ( dot(b-a, c-a) < EPS ) return (c-a).absv();\n if ( dot(a-b, c-b) < EPS ) return (c-b).absv();\n return abs(cross(b-a, c-a)) / (b-a).absv();\n }\n bool is_intersected_ls(Segment a,Segment b) {\n \tif(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;\n \tif(parareru((a.p2),(a.p1),(a.p1),(b.p2))&&parareru((a.p2),(a.p1),(a.p1),(b.p1))){\n //\t\tcout<<\"sss\"<<endl;\n \t\tif(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;\n \t\tif(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;\n \t\tif(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;\n \t\tif(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;\n \t\treturn false;\n \t}\n else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );\n }\n \n double segment_dis(Segment a,Segment b){\n \tif(is_intersected_ls(a,b))return 0;\n \tdouble r=distance_ls_p(a.p1, a.p2, b.p1);\n \tr=min(r,distance_ls_p(a.p1, a.p2, b.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p1));\n \treturn r;\n }\n Point intersection_ls(Segment a, Segment b) {\n Point ba = b.p2-b.p1;\n double d1 = abs(cross(ba, a.p1-b.p1));\n double d2 = abs(cross(ba, a.p2-b.p1));\n double t = d1 / (d1 + d2);\n \n return a.p1 + (a.p2-a.p1) * t;\n }\n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n double distans(double x1,double y1,double x2,double y2){\n \tdouble rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n \treturn sqrt(rr);\n \t\n }\n \n // int pr[2000010];\n // int inv[2000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1ll;\n \tif(rr==1) return wa%warukazu;\n \tif(rr%2==1) return (beki(wa,rr-1,warukazu)*wa)%warukazu;\n \tint zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n /*\n\t\t\tint comb(int nn,int rr){\n\t\t\t\tint r=pr[nn]*inv[rr];\n\t\t\t\tr%=inf;\n\t\t\t\tr*=inv[nn-rr];\n\t\t\t\tr%=inf;\n\t\t\t\treturn r;\n\t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%inf;\n \t}\n \tfor(int i=0;i<ert;i++) inv[i]=beki(pr[i],inf-2,inf);\n \t\n }\n */\n\t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n //----------------kokomade tenpure------------\nunsigned int randxor()\n{\n static unsigned int x=123456789,y=362436069,z=521288629,w=88675123;\n unsigned int t;\n t=(x^(x<<11));x=y;y=z;z=w; return( w=(w^(w>>19))^(t^(t>>8)) );\n}\n\nint mask=(1<<8)-1;\nint ban[1010][1010]={0};\nmap<int,int> ma[2][1010];\n signed main(){\n \t cin.tie(0);\n \t\tios::sync_with_stdio(false);\n\n \tint n,m;\n \tcin>>n>>m;\n \t\n \tfor(int i=1;i<=n;i++){\n \t\tstring s;\n \t\t\n \t\tcin>>s;\n \t\ts=\"2\"+s;\n \t\tfor(int j=1;j<=m;j++)if(s[j]!='.')ban[i][j]=s[j]-'0';\n \t}\n\n \tma[1][1][ban[2][2]?1:0]=0;\n \t \t\n \tfor(int i=1;i<=n;i++){\n \t\tfor(int j=1;j<=m;j++)ma[1^(i&1)][j].clear();\n \t\t\n \t\tfor(int j=1;j<=m;j++){\n \t\tif(i==n && j==m) break;\n \t\t\n \t\tfor(auto it=ma[i&1][j].begin();it!=ma[i&1][j].end();it++){\n \t\t\tif(i!=n){\n \t\t\t\tint B=it->first;\n \t\t\t\tint val=it->second;\n \t\t//\t\tcout<<i<<\" \"<<j<<\" \"<<bitset<9>(B)<<\" \"<<val<<endl;\n \t\t\t\tB=B<<3;\n \t\t\t\tB&=mask;\n \t\t\t\tif(ban[i+2][j-1])B|=4;\n \t\t\t\tif(ban[i+2][j])B|=2;\n \t\t\t\tif(ban[i+2][j+1])B|=1;\n \t\t\t\t\n \t\t\t\tif(B&(1<<4))val+=ban[i+1][j],B^=(1<<4);\n \t\t\t\tvector<pa> ve;\n \t\t\t\tif(B&(1<<1))B^=(1<<1),ve.pb(mp(1,ban[i+2][j]));\n \t\t\t\tif(B&(1<<3))B^=(1<<3),ve.pb(mp(3,ban[i+1][j+1]));\n \t\t\t\tif(B&(1<<5))B^=(1<<5),ve.pb(mp(5,ban[i+1][j-1]));\n \t\t\t\tif(B&(1<<7))B^=(1<<7),ve.pb(mp(7,ban[i][j]));\n \t\t\t\tif(ve.size()>1){\n \t\t\t\t\tint l=ve.size();\n \t\t\t\t\tint wa=0;\n \t\t\t\t\tfor(auto v:ve)wa+=v.second;\n \t\t\t\t\tfor(auto v:ve){\n \t\t\t\t\t\tint B2=(B|(1<<v.first));\n \t\t\t\t\t\tint val2=val+wa-v.second;\n \t\t\t\t\t\tif(ma[1^(i&1)][j].find(B2)==ma[1^(i&1)][j].end()) ma[1^(i&1)][j][B2]=val2;\n \t\t\t\t\t\telse ma[1^(i&1)][j][B2]=min(ma[1^(i&1)][j][B2],val2);\n \t\t\t\t\t}\n \t\t\t\t}\n \t\t\t\telse{\n \t\t\t\t\tif(ve.size())B|=(1<<ve[0].first);\n \t\t\t\t\tif(ma[1^(i&1)][j].find(B)==ma[1^(i&1)][j].end()) ma[1^(i&1)][j][B]=val;\n \t\t\t\t\telse ma[1^(i&1)][j][B]=min(ma[1^(i&1)][j][B],val);\n \t\t\t\t}\n \t\t\t}\n \t\t\tif(j!=m){\n \t\t\t\tint B=it->first;\n \t\t\t\tint val=it->second;\n \t\t\t\tB=B<<1;\n \t\t\t\tB&=mask;\n \t\t\t\tif(B&1)B^=1;\n \t\t\t\tif(B&8)B^=8;\n \t\t\t\tif(B&64)B^=64;\n \t\t\t\t\n \t\t\t\tif(ban[i-1][j+2])B|=64;\n \t\t\t\tif(ban[i][j+2])B|=8;\n \t\t\t\tif(ban[i+1][j+2])B|=1;\n \t\t\t\t\n \t\t\t\tif(B&(1<<4))val+=ban[i][j+1],B^=(1<<4);\n \t\t\t\tvector<pa> ve;\n \t\t\t\tif(B&(1<<1))B^=(1<<1),ve.pb(mp(1,ban[i+1][j+1]));\n \t\t\t\tif(B&(1<<3))B^=(1<<3),ve.pb(mp(3,ban[i][j+2]));\n \t\t\t\tif(B&(1<<5))B^=(1<<5),ve.pb(mp(5,ban[i][j]));\n \t\t\t\tif(B&(1<<7))B^=(1<<7),ve.pb(mp(7,ban[i-1][j+1]));\n \t\t\t//\tif(i==1 && j==1)cout<<ve.size()<<endl;\n \t\t\t\tif(ve.size()>1){\n \t\t\t\t\tint l=ve.size();\n \t\t\t\t\tint wa=0;\n \t\t\t\t\tfor(auto v:ve)wa+=v.second;\n \t\t\t\t\tfor(auto v:ve){\n \t\t\t\t\t\tint B2=(B|(1<<v.first));\n \t\t\t\t\t\tint val2=val+wa-v.second;\n \t\t\t\t\t\tif(ma[i&1][j+1].find(B2)==ma[i&1][j+1].end()) ma[i&1][j+1][B2]=val2;\n \t\t\t\t\t\telse ma[i&1][j+1][B2]=min(ma[i&1][j+1][B2],val2);\n \t\t\t\t\t}\n \t\t\t\t}\n \t\t\t\telse{\n \t\t\t\t\tif(ve.size())B|=(1<<ve[0].first);\n \t\t\t\t\tif(ma[i&1][j+1].find(B)==ma[i&1][j+1].end()) ma[i&1][j+1][B]=val;\n \t\t\t\t\telse ma[i&1][j+1][B]=min(ma[i&1][j+1][B],val);\n \t\t\t\t}\n \t\t\t}\n \t\t}\n \t\t}\n \t}\n \t\n \tint lasans=inf;\n \tfor(auto it=ma[n&1][m].begin();it!=ma[n&1][m].end();it++)lasans=min(lasans,it->second);\n \tcout<<lasans<<endl;\n \treturn 0;\n }", "accuracy": 1, "time_ms": 2010, "memory_kb": 7920, "score_of_the_acc": -0.2925, "final_rank": 11 }, { "submission_id": "aoj_0624_3001589", "code_snippet": "#include<bits/stdc++.h>\n#define all(vec) vec.begin(),vec.end()\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nconst ll MOD=1000000007;\nconst ll INF=1000000010;\nconst ll LINF=1000000000000000010;\nint dx[5]={0,1,0,-1,0};\nint dy[5]={1,0,-1,0,0};\nchar c[1010][1010];\nint dp[1010][1010][1<<7];//南、東、北、西、今いる場所、南西、北東\nint h,w;\nint change(int bit,int dir){\n int res=0;\n if(dir){\n if(bit&(1<<0))res|=(1<<4);//南から今いる場所\n if(bit&(1<<4))res|=(1<<2);//今いる場所から北\n if(bit&(1<<5))res|=(1<<3);//南西から西\n if(bit&(1<<1))res|=(1<<6);//東から北東\n }else{\n if(bit&(1<<0))res|=(1<<5);//南から南西\n if(bit&(1<<1))res|=(1<<4);//東から今いる場所\n if(bit&(1<<4))res|=(1<<3);//今いる場所から西\n if(bit&(1<<6))res|=(1<<2);//北東から北\n }\n return res;\n}\nint dfs(int y,int x,int bit){\n if(dp[y][x][bit]!=-1)return dp[y][x][bit];\n if(y==h-1&&x==w-1)return 0;\n int res=INF;\n for(int j=0;j<4;j++){\n int s=0;\n int bit2=bit;\n for(int i=0;i<5;i++){\n if(i==j)continue;\n if(bit&(1<<i))continue;\n int ny=y+dy[i];\n int nx=x+dx[i];\n if(ny<0||nx<0||ny>=h||nx>=w)continue;\n if(c[ny][nx]!='.'){\n s+=c[ny][nx]-'0';\n bit2|=(1<<i);\n }\n }\n int a=INF;\n if(y<h-1){\n int nbit=change(bit2,1);\n a=dfs(y+1,x,nbit);\n }\n if(x<w-1){\n int nbit=change(bit2,0);\n a=min(a,dfs(y,x+1,nbit));\n }\n s+=a;\n res=min(res,s);\n }\n return dp[y][x][bit]=res;\n}\nint main(){\n cin>>h>>w;\n for(int i=0;i<h;i++){\n cin>>c[i];\n }\n memset(dp,-1,sizeof(dp));\n cout<<dfs(0,0,0)<<endl;\n}", "accuracy": 1, "time_ms": 900, "memory_kb": 514332, "score_of_the_acc": -1.1269, "final_rank": 17 }, { "submission_id": "aoj_0624_2871130", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n//到着時の状態\n#define Right_North 0\n#define North 1\n#define Here 2\n#define Left 3\n#define Left_South 4\n\n//あるマスで調べる状態\n#define UE 0\n#define HIDARI 1\n#define KOKO 2\n#define MIGI 3\n#define SHITA 4\n\nchar input[1000][1001];\nint POW[6];\nint table[1002][1002];\nint min_cost[1002][1002][32];\n\nint H,W;\n\nint main(){\n\n\tfor(int i = 0; i < 6; i++)POW[i] = pow(2,i);\n\n\tscanf(\"%d %d\",&H,&W);\n\n\tfor(int row = 0; row < H; row++){\n\t\tscanf(\"%s\",input[row]);\n\t}\n\n\t//ダミーセルを用意\n\tfor(int col = 0; col <= W+1; col++){\n\t\ttable[0][col] = 0;\n\t\ttable[H+1][col] = 0;\n\t}\n\tfor(int row = 0; row <= H+1; row++){\n\t\ttable[row][0] = 0;\n\t\ttable[row][W+1] = 0;\n\t}\n\n\t//マップを転記\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(input[row][col] == '.'){\n\t\t\t\ttable[row+1][col+1] = 0;\n\t\t\t}else{\n\t\t\t\ttable[row+1][col+1] = input[row][col]-'0';\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 1; row <= H; row++){\n\t\tfor(int col = 1; col <= W; col++){\n\t\t\tfor(int state = 0; state < 32; state++){\n\t\t\t\tmin_cost[row][col][state] = BIG_NUM;\n\t\t\t}\n\t\t}\n\t}\n\n\t/*\n\t * min_cost[row][col][隣接5箇所の数字を取得したか] = 最小コスト\n\t * stateのビット:位置ビットの屋台の菓子を既に食べたか\n\t *\n\t */\n\tmin_cost[1][1][0] = 0;\n\tint add_sum,add_loc,removed_add,removed_loc;\n\tint next_state;\n\tbool FLG;\n\n\tfor(int row = 1; row <= H; row++){\n\t\tfor(int col = 1; col <= W; col++){\n\t\t\tfor(int state = 0; state < 32; state++){\n\t\t\t\tif(min_cost[row][col][state] == BIG_NUM)continue;\n\n\t\t\t\t//上下左右+今いる地点で、未加算の数字を調べる\n\t\t\t\tadd_sum = 0,add_loc = 0;\n\n\t\t\t\t//上\n\t\t\t\tif((state & (1 << North)) == 0 && table[row-1][col] != 0){ //上が未加算で、かつ0でない\n\t\t\t\t\tadd_sum += table[row-1][col];\n\t\t\t\t\tadd_loc += POW[UE];\n\t\t\t\t}\n\t\t\t\t//左\n\t\t\t\tif((state & (1 << Left)) == 0 && table[row][col-1] != 0){\n\t\t\t\t\tadd_sum += table[row][col-1];\n\t\t\t\t\tadd_loc += POW[HIDARI];\n\t\t\t\t}\n\t\t\t\t//今いる場所\n\t\t\t\tif((state & (1 << Here)) == 0 && table[row][col] != 0){\n\t\t\t\t\tadd_sum += table[row][col];\n\t\t\t\t\tadd_loc += POW[KOKO];\n\t\t\t\t}\n\t\t\t\t//右\n\t\t\t\tif(table[row][col+1] != 0){\n\t\t\t\t\tadd_sum += table[row][col+1];\n\t\t\t\t\tadd_loc += POW[MIGI];\n\t\t\t\t}\n\t\t\t\t//下\n\t\t\t\tif(table[row+1][col] != 0){\n\t\t\t\t\tadd_sum += table[row+1][col];\n\t\t\t\t\tadd_loc += POW[SHITA];\n\t\t\t\t}\n\n\t\t\t\tif(add_loc == 0){ //数字を除く必要がない場合\n\n\t\t\t\t\t//右に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t}\n\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\tnext_state += POW[Left]; //今いる場所は加算済み、または0、よって右のマスは今のマスを見る必要はない\n\n\t\t\t\t\t//右→「今いる場所になる」\n\t\t\t\t\tnext_state += POW[Here]; //★add_loc == 0により\n\n\t\t\t\t\t//下は左下になる\n\t\t\t\t\tnext_state += POW[Left_South]; //★add_loc == 0なので、table[row][col+1]は、新しい左下を無視して良いということ!\n\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]);\n\n\t\t\t\t\t//下に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\tnext_state += POW[North];\n\n\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t}\n\t\t\t\t\t//右は右上になる\n\t\t\t\t\tnext_state += POW[Right_North]; //★add_loc == 0のため\n\t\t\t\t\t//下は「今いる場所」になる\n\t\t\t\t\tnext_state += POW[Here]; //★add_loc == 0のため、無条件で良い\n\n\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]);\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\n\t\t\t\t//数字を除く必要がある場合\n\n\t\t\t\tfor(int remove_loc = 0; remove_loc <= 4; remove_loc++){\n\t\t\t\t\tif(remove_loc == 2){\n\n\t\t\t\t\t\tif(add_loc == POW[KOKO]){ //★★今いる場所だけを加算した場合★★\n\n\t\t\t\t\t\t\t//右に進む\n\t\t\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\t\t\tnext_state += POW[Left]; //今いる場所は加算済み、または0、よって右のマスは今のマスを見る必要はない\n\n\t\t\t\t\t\t\t//右→「今いる場所になる」\n\t\t\t\t\t\t\tnext_state += POW[Here]; //★add_loc == POW[KOKO]により\n\n\t\t\t\t\t\t\t//下は左下になる\n\t\t\t\t\t\t\tnext_state += POW[Left_South]; //★add_loc == POW[KOKO]なので、table[row][col+1]は、新しい左下を無視して良いということ!\n\t\t\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]+table[row][col]);\n\n\t\t\t\t\t\t\t//下に進む\n\t\t\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\t\t\tnext_state += POW[North];\n\n\t\t\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t//右は右上になる\n\t\t\t\t\t\t\tnext_state += POW[Right_North]; //★add_loc == POW[KOKO]のため\n\t\t\t\t\t\t\t//下は「今いる場所」になる\n\t\t\t\t\t\t\tnext_state += POW[Here]; //★add_loc == POW[KOKO]のため、無条件で良い\n\n\t\t\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]+table[row][col]);\n\n\t\t\t\t\t\t}\n\t\t\t\t\t\tcontinue; //今いる場所は除けない\n\t\t\t\t\t}\n\n\t\t\t\t\tFLG = false;\n\n\t\t\t\t\tswitch(remove_loc){\n\t\t\t\t\tcase 0: //上\n\t\t\t\t\t\tif(add_loc & (1 << UE)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row-1][col];\n\t\t\t\t\t\t\tremoved_loc = UE;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 1: //左\n\t\t\t\t\t\tif(add_loc & (1 << HIDARI)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row][col-1];\n\t\t\t\t\t\t\tremoved_loc = HIDARI;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 3: //右\n\t\t\t\t\t\tif(add_loc & (1 << MIGI)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row][col+1];\n\t\t\t\t\t\t\tremoved_loc = MIGI;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\tcase 4: //下\n\t\t\t\t\t\tif(add_loc & (1 << SHITA)){\n\t\t\t\t\t\t\tFLG = true;\n\t\t\t\t\t\t\tremoved_add = add_sum-table[row+1][col];\n\t\t\t\t\t\t\tremoved_loc = SHITA;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\tif(!FLG)continue;\n\n\t\t\t\t\t//右に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\tif(state & (1 << Right_North)){ //右上→上になる\n\t\t\t\t\t\tnext_state += POW[North];\n\t\t\t\t\t}\n\t\t\t\t\t//今いる場所→左になる\n\t\t\t\t\tnext_state += POW[Left]; //table[row][col+1]から見れば、仮に左のマスから来たなら、table[row][col]は加算不要なはず(今いるセルは除けないし、0なら無視して良い)\n\n\t\t\t\t\t//右→今いる場所になる\n\t\t\t\t\tif(removed_loc != MIGI && (add_loc & (1 << MIGI)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Here]; //加算済とする\n\t\t\t\t\t}\n\n\t\t\t\t\t//下→左下になる\n\t\t\t\t\tif(removed_loc != SHITA && (add_loc & (1 << SHITA)) != 0){ //下は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Left_South]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\tmin_cost[row][col+1][next_state] = min(min_cost[row][col+1][next_state],min_cost[row][col][state]+removed_add);\n\n\t\t\t\t\t//下に進む\n\t\t\t\t\tnext_state = 0;\n\t\t\t\t\t//今いる場所→上になる\n\t\t\t\t\tnext_state += POW[North]; //右に進む場合と同様の理由で、無条件で良し\n\n\t\t\t\t\tif(state & (1 << Left_South)){ //左下→下になる\n\t\t\t\t\t\tnext_state += POW[Left];\n\t\t\t\t\t}\n\t\t\t\t\t//右は右上になる\n\t\t\t\t\tif(removed_loc != MIGI && (add_loc & (1 << MIGI)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Right_North]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\t//下は今いる場所になる\n\t\t\t\t\tif(removed_loc != SHITA && (add_loc & (1 << SHITA)) != 0){ //右は除外マスでなく、かつ加算されている\n\t\t\t\t\t\tnext_state += POW[Here]; //加算済とする\n\t\t\t\t\t}\n\t\t\t\t\tmin_cost[row+1][col][next_state] = min(min_cost[row+1][col][next_state],min_cost[row][col][state]+removed_add);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = BIG_NUM;\n\tfor(int state = 0; state < 32; state++){\n\t\tans = min(ans,min_cost[H][W][state]);\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 133648, "score_of_the_acc": -0.2707, "final_rank": 10 } ]
aoj_0626_cpp
スタンプラリー2 (Collecting Stamps 2) JOI 商店街には大通りに沿って $N$ 個の店があり,JOI 商店街の入口から出口に向かってそれぞれ $1, 2, ..., N$ の番号が付けられている.JOI 商店街は一方通行で,入口から出口方向へしか移動することはできない. まちおこしのため,JOI 商店街でスタンプラリーを行うことになった.このスタンプラリーでは,それぞれの店はJ,O,I のいずれかのスタンプを用意し,店で買い物をした人はスタンプカードにスタンプを押してもらう.スタンプラリーに参加する人はちょうど 3 つの店に入る.商店街の入口では 3 つの欄のあるスタンプカードを配り,1 回目に入った店,2 回目に入った店,3 回目に入った店のスタンプを押してもらう.商店街の出口でスタンプカードを回収し,押されたスタンプが先に入った店のものから順にJ,O,Iになっているとき,出口で商品券がもらえるキャンペーンを実施することになった.押されたスタンプの種類や順番が異なるときは商品券はもらえない. すでに $N$ 個のすべての店はどのスタンプを用意するか決めたが,新たに1 つの店をJOI 商店街に出すことになり,新しく出店する場所と,その店が用意するスタンプを決めることになった.新しい店を出す場所は,店 $i$ と店 $i + 1$ の間 $(1 \leq i \leq N - 1)$,入口と店 $1$ の間,店 $N$ と出口の間のいずれかから決める.また,新しい店のスタンプは J,O,I の 3 通りから決める. 商品券をもらえるような店の選び方の数が大きいほど,スタンプラリーが盛り上がると商店街は考えた.そこで,新しく出す店の場所と用意するスタンプを決めたときの,上記の店の選び方の数の最大値を求めたい. 課題 JOI 商店街のすでにある店が用意したスタンプの情報が与えられたとき,新しく出す店の場所と用意するスタンプを決めたときの,商品券をもらえるような店の選び方の数の最大値を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,1 つの整数 $N$ が書かれている.これは,JOI 商店街には現在 $N$ 個の店があることを意味する. 2 行目には,$N$ 文字の半角英大文字 J, O, I のみからなる文字列 $S$ が書かれている.文字列 $S$ の左から $i$ 文字目 $(1 \leq i \leq N)$ は,店 $i$ が用意したスタンプの種類を表す. 出力 商品券をもらえるような店の選び方の数の最大値を標準出力に 1 行で出力せよ. 商品券をもらえるような店の選び方の数が32 ビット符号付き整数の範囲に収まるとは限らないことに注意せよ. 制限 すべての入力データは以下の条件を満たす. $3 \leq N \leq 100 000$ 入出力例 入力例1 5 JOIOI 出力例1 6 入力例 1 では,店 1 と店 2 の間に,スタンプ J を用意する新しい店を出したとき,店が用意したスタンプを入口から順に並べると JJOIOI となる. このとき,商品券をもらえるような店の選び方は以下の 6 通りである. 1, 3, 4 番目の店に行く. 1, 3, 6 番目の店に行く. 1, 5, 6 番目の店に行く. 2, 3, 4 番目の店に行く. 2, 3, 6 番目の店に行く. 2, 5, 6 番目の店に行く. 入力例 1 において,商品券をもらえるような店の選び方が 7 通り以上になることはない. 入力例2 7 JJJOIII 出力例2 18 入力例3 4 OIIJ 出力例3 2 入力例 3 では,入口と店 1 の間にスタンプ J を用意する新しい店を出したとき,商品券をもらえるような店の選び方の数が最大となる. 第15回 日本情報オリンピック本選 課題   2016 年 2 月 14 日
[ { "submission_id": "aoj_0626_7999017", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\nll M=0;\nll solve(string S){\n vll J,I;\n ll N=S.size();\n rep(i,N){\n if(S[i]=='J')J.push_back(i);\n if(S[i]=='I')I.push_back(i);\n }\n ll an=0;\n rep(i,N){\n ll p=lower_bound(all(J),i)-J.begin();\n ll q=I.end()-lower_bound(all(I),i);\n M=max(M,p*q);\n if(S[i]=='O'){\n \n an+=p*q;\n }\n }\n return an;\n}\n\nint main() {\n ll N;\n string S;\n cin>>N>>S;\n ll an=solve(S);\n an+=M;\n string T=\"J\"+S;\n an=max(an,solve(T));\n T=S+\"I\";\n an=max(an,solve(T));\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5212, "score_of_the_acc": -0.1139, "final_rank": 4 }, { "submission_id": "aoj_0626_5390266", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 1000000007;\n// constexpr int MOD = 998244353;\nconstexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconstexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int n; string s; cin >> n >> s;\n map<char, int> mp{{'J', 0}, {'O', 1}, {'I', 2}};\n vector dp1(n + 1, vector(3, 0LL));\n dp1[0][0] = 1;\n REP(i, n) REP(j, 3) {\n dp1[i + 1][j] += dp1[i][j];\n if (j + 1 < 3 && mp[s[i]] == j) dp1[i + 1][j + 1] += dp1[i][j];\n }\n vector dp2(n + 1, vector(3, 0LL));\n dp2[n][2] = 1;\n for (int i = n - 1; i >= 0; --i) REP(j, 3) {\n dp2[i][j] += dp2[i + 1][j];\n if (j > 0 && mp[s[i]] == j) dp2[i][j - 1] += dp2[i + 1][j];\n }\n vector<int> js(n + 1, 0), ji(n + 1, 0);\n REP(i, n) js[i + 1] = js[i] + (s[i] == 'J');\n for (int i = n - 1; i >= 0; --i) ji[i] = ji[i + 1] + (s[i] == 'I');\n ll ans = 0;\n REP(i, n + 1) {\n chmax(ans, dp2[i][0]); // J\n chmax(ans, 1LL * js[i] * ji[i]); // O\n chmax(ans, dp1[i][2]); // I\n }\n vector dp3(n + 1, vector(4, 0LL));\n dp3[0][0] = 1;\n REP(i, n) REP(j, 4) {\n dp3[i + 1][j] += dp3[i][j];\n if (mp[s[i]] == j) dp3[i + 1][j + 1] += dp3[i][j];\n }\n cout << ans + dp3[n][3] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 22088, "score_of_the_acc": -1, "final_rank": 15 }, { "submission_id": "aoj_0626_3633010", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<cctype>\n#include<math.h>\n#include<string>\n#include<string.h>\n#include<stack>\n#include<queue>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<stdlib.h>\n#include<iomanip>\n\nusing namespace std;\n\n#define ll long long\n#define ld long double\n#define EPS 0.0000000001\n#define INF 1e9\n#define LINF (ll)INF*INF\n#define MOD 1000000007\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define loop(i,a,n) for(int i=a;i<(n);i++)\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\n\n#define int ll //!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vp;\n\nint gcd(int a, int b){\n if(b==0) return a;\n return gcd(b,a%b);\n}\nint lcm(int a, int b){\n return a/gcd(a,b)*b;\n}\n\n\nsigned main(void) {\n int n;\n cin >> n;\n string s;\n cin >> s;\n string t = \"JOI\";\n vector<vi> dp(n+1,vi(4,0));\n dp[0][0] = 1;\n rep(i,n)rep(j,4){\n dp[i+1][j] += dp[i][j];\n if(j < 3 && s[i] == t[j])dp[i+1][j+1] += dp[i][j];\n }\n int ans = dp[n][3];\n reverse(all(s));\n reverse(all(t));\n vector<vi> dp1(n+1,vi(4,0));\n dp1[0][0] = 1;\n rep(i,n)rep(j,4){\n dp1[i+1][j] += dp1[i][j];\n if(j < 3 && s[i] == t[j])dp1[i+1][j+1] += dp1[i][j];\n }\n int ma = 0;\n ma = dp1[n][2];//先頭にJ\n rep(i,n){//s[i]とs[i+1]のあいだに入れる\n int l = n-i;\n ma = max(ma,dp1[l][2]);//J\n ma = max(ma,dp[i][1]*dp1[l][1]);//O\n ma = max(ma,dp[i+1][2]);//I\n }\n cout << ans + ma << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 17160, "score_of_the_acc": -0.7352, "final_rank": 14 }, { "submission_id": "aoj_0626_2825462", "code_snippet": "//h16-2 スタンプラリー2(解き直し)\n#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#include <boost/multiprecision/cpp_int.hpp>\nnamespace boost_multiprecision = boost::multiprecision;\n#define LL long long\n#define CINT boost_multiprecision::cpp_int\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775807\n#define LL_MAX 9223372036854775807\n#define segment_size 65536\n#define ROOP() while (true)\n\nint N;\nstring S;\n\nvector<int> J;\nvector<int> O;\nvector<int> I;\n\nint main(){\n\n cin >> N >> S;\n\n for(int i=0; i<N; i++){\n if(S[i] == 'J'){\n J.push_back(i);\n }\n if(S[i] == 'O'){\n O.push_back(i);\n }\n if(S[i] == 'I'){\n I.push_back(i);\n }\n }\n\n LL sum = 0;\n for(int i=0; i<O.size(); i++){\n auto itr = lower_bound(J.begin(), J.end(), O[i]);\n int a = itr - J.begin();\n auto itr2 = lower_bound(I.begin(), I.end(), O[i]);\n int b = itr2 - I.begin();\n b = I.size() - b;\n sum += a * b;\n }\n\n LL ans = 0;\n\n //O\n for(int i=0; i<N+1; i++){\n auto itr = lower_bound(J.begin(), J.end(), i);\n int a = itr - J.begin();\n auto itr2 = lower_bound(I.begin(), I.end(), i);\n int b = itr2 - I.begin();\n b = I.size() - b;\n ans = max(ans, sum + a*b);\n //cout << sum + a*b << endl;\n }\n\n //J\n LL tmp = 0;\n J.insert(J.begin(), -1);\n for(int i=0; i<O.size(); i++){\n auto itr = lower_bound(J.begin(), J.end(), O[i]);\n int a = itr - J.begin();\n auto itr2 = lower_bound(I.begin(), I.end(), O[i]);\n int b = itr2 - I.begin();\n b = I.size() - b;\n tmp += a * b;\n }\n J.erase(J.begin());\n ans = max(ans,tmp);\n //cout << tmp << endl;\n\n //I\n tmp = 0;\n I.push_back(N);\n for(int i=0; i<O.size(); i++){\n auto itr = lower_bound(J.begin(), J.end(), O[i]);\n int a = itr - J.begin();\n auto itr2 = lower_bound(I.begin(), I.end(), O[i]);\n int b = itr2 - I.begin();\n b = I.size() - b;\n tmp += a * b;\n }\n ans = max(ans,tmp);\n //cout << tmp << endl;\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3776, "score_of_the_acc": -0.0159, "final_rank": 2 }, { "submission_id": "aoj_0626_2825308", "code_snippet": "//h16-2 スタンプラリー2\n#include <iostream>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <vector>\n#include <map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#include <boost/multiprecision/cpp_int.hpp>\nnamespace boost_multiprecision = boost::multiprecision;\n#define LL long long\n#define CINT boost_multiprecision::cpp_int\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483648\n#define INT_MAX 2147483647\n#define LL_MIN -9223372036854775807\n#define LL_MAX 9223372036854775807\n#define segment_size 65536\n#define ROOP() while (true)\n\nint N;\nstring S;\nvector<int> J;\nvector<int> O;\nvector<int> I;\n\nint place;\nchar moji;\n\nvector<LL> J2;\nLL O2[100000];\nvector<LL> I2;\n\nLL dp[100000];\n\nLL solve(int now){\n if(now == -1){\n if(moji == 'I') return 1;\n if(moji == 'O') return I2[place];\n if(moji == 'J'){\n LL tmp = 0;\n auto itr = lower_bound(J.begin(), J.end(), place);\n if(itr != J.end()){\n tmp += dp[*itr];\n auto itr2 = lower_bound(O.begin(), O.end(), place);\n if(itr2 == O.end()) return 0;\n auto itr3 = lower_bound(O.begin(), O.end(), *itr);\n itr3--;\n if(itr2 != O.begin()){\n itr2--;\n tmp += O2[*itr3] - O2[*itr2];\n }\n else{\n tmp += O2[*itr3];\n }\n }\n else{\n auto itr2 = lower_bound(O.begin(), O.end(), place);\n if(itr2 == O.end()) return 0;\n auto itr3 = O.end();\n itr3--;\n if(itr2 != O.begin()){\n itr2--;\n tmp += O2[*itr3] - O2[*itr2];\n }\n else{\n tmp += O2[*itr3];\n }\n }\n \n return tmp;\n }\n }\n else{\n if(S[now] == 'I') return 1;\n if(S[now] == 'O') return I2[now];\n if(S[now] == 'J'){\n if(dp[now] != -1) return dp[now];\n LL tmp = 0;\n for(int i=0; i<O.size(); i++){\n if(O[O.size()-i-1] > now) tmp += I2[O[O.size()-i-1]];\n else break;\n }\n dp[now] = tmp;\n return tmp;\n }\n }\n}\n\nint main(){\n cin >> N;\n cin >> S;\n\n \n J2.push_back(0);\n I2.push_back(0);\n for(int i=0; i<N; i++){\n if(S[i] == 'J'){\n J.push_back(i);\n J2.push_back( J2.back()+1 );\n }\n else{\n J2.push_back( J2.back() );\n }\n if(S[i] == 'O') O.push_back(i);\n if(S[i] == 'I') I.push_back(i);\n\n if(S[N-i-1] == 'I') I2.push_back( I2.back() + 1);\n else I2.push_back( I2.back() );\n\n dp[i] = -1;\n }\n reverse(I2.begin(), I2.end());\n\n LL tmp = 0;\n auto itr = O.begin();\n while(itr != O.end()){\n tmp += I2[*itr];\n O2[*itr] = tmp;\n itr++;\n }\n\n place = -1;\n moji = 'X';\n vector<LL> sum;\n sum.push_back(0);\n for(int j=0; j<J.size(); j++){\n sum.push_back( sum.back() + solve(J[j]) );\n }\n\n vector<LL> J3;\n tmp = 0;\n for(int i=0; i<N; i++){\n J3.push_back(0);\n if(S[i] == 'O'){\n tmp += J2[i];\n J3.back() = tmp;\n }\n }\n\n LL ans = 0;\n for(int i=0; i<N+1; i++){ //iはそれより1つ前を指す\n place = i;\n\n moji = 'J';\n ans = max(ans, sum.back() + solve(-1));\n\n moji = 'O';\n ans = max(ans, sum.back() + J2[i+1] * I2[place]);\n\n moji = 'I';\n /*LL tmp = 0;\n for(int j=0; j<O.size(); j++){\n if(O[j] >= place){\n break;\n }\n tmp += J2[O[j]];\n }*/\n auto it = lower_bound(O.begin(), O.end(), place);\n if(it != O.begin()){\n it--;\n ans = max(ans, sum.back() + J3[ *it ]);\n }\n \n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 8952, "score_of_the_acc": -1.2941, "final_rank": 16 }, { "submission_id": "aoj_0626_2741847", "code_snippet": "#include <stdio.h>\ntypedef long long ll;\n\nint main(void) {\n ll i, j, k, n, num = 0, ans, t1 = 0, t2 = 0;\n scanf(\"%lld\", &n);\n char s[n +10];\n ll dp[n][3], sum[n][3];\n for(i = 0; i < n; ++i) for(j = 0; j < 3; ++j) dp[i][j] = 0, sum[i][j] = 0;\n scanf(\"%s\", s);\n if(s[0] == 'J') sum[0][0] = 1;\n else if(s[0] == 'O') sum[0][1] = 1;\n else sum[0][2] = 1;\n for(i = 1; i < n; ++i) {\n for(j = 0; j < 3; ++j) sum[i][j] = sum[i - 1][j];\n if(s[i] == 'J') ++sum[i][0];\n else if(s[i] == 'O') ++sum[i][1];\n else ++sum[i][2];\n }\n if(s[0] == 'O') t1 = sum[n - 1][2] - sum[0][2];\n for(i = 1; i < n; ++i) if(s[i] == 'O') num += sum[i - 1][0] * (sum[n - 1][2] - sum[i][2]), t1 += (sum[i - 1][0] + 1) * (sum[n - 1][2] - sum[i][2]), t2 += sum[i - 1][0] *(sum[n - 1][2] - sum[i][2] + 1);\n ans = (t1 > t2 ? t1 : t2);\n //printf(\"%lld %lld \", t1, t2);\n for(i = 0; i < n; ++i) if(ans < num + sum[i][0] * (sum[n - 1][2] - sum[i][2])) {\n ans = num + sum[i][0] * (sum[n - 1][2] - sum[i][2]);\n //printf(\"%lld\\n\", i);\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7496, "score_of_the_acc": -0.2158, "final_rank": 9 }, { "submission_id": "aoj_0626_2601078", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nusing namespace std;\nint n;\nint ch(string s){\n int dp[4][s.size()+1],ans=0;\n memset(dp,0,sizeof(dp));\n dp[0][0]=1;\n s=\"+\"+s;\n string t=\"+JOI\";\n for(int i=1;i<4;i++){\n for(int j=1,x=0;j<s.size();j++){\n x+=dp[i-1][j-1];\n if(s[j]==t[i]){\n dp[i][j]=x;\n if(i==3)ans+=dp[i][j];\n }\n }\n }\n return ans;\n}\nint ch2(string s){\n int ans=0;\n s=\"@\"+s+\"@\";\n for(int i=1;i<(int)s.size();i+=2)s.insert(s.begin()+i,'O');\n int dp1[s.size()]={};\n int dp2[s.size()]={};\n for(int i=1;i<s.size();i++)dp1[i]=dp1[i-1]+(s[i-1]=='J');\n for(int i=s.size()-2;i>=0;i--)dp2[i]=dp2[i+1]+(s[i+1]=='I');\n for(int i=0;i<s.size();i++)ans=max(ans,dp1[i]*dp2[i]);\n return ans;\n}\nmain(){\n string s;\n cin>>n>>s;\n int p1=ch(s);\n int p2=ch(\"J\"+s);\n int p3=ch(s+\"I\");\n int p4=p1+ch2(s);\n cout<<max(p4,max(p3,p2))<<endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 6644, "score_of_the_acc": -0.42, "final_rank": 12 }, { "submission_id": "aoj_0626_2591406", "code_snippet": "#include<iostream>\n#include<algorithm>\n\nusing namespace std;\ntypedef long long ll;\n\nll N, ruisekiwa[100001][3];\nchar in[100000];\n\nint main() {\n\tcin >> N;\n\tfor (int i = 0; i < N; i++) {\n\t\tchar c;\n\t\tcin >> c;\n\t\tif (c == 'J')ruisekiwa[i + 1][0]++;\n\t\tif (c == 'O')ruisekiwa[i + 1][1]++;\n\t\tif (c == 'I')ruisekiwa[i + 1][2]++;\n\t\tfor (int j = 0; j < 3; j++)ruisekiwa[i + 1][j] += ruisekiwa[i][j];\n\t\tin[i] = c;\n\t}\n\n\tll hajime = 0;\n\tfor (int i = 0; i < N - 1; i++) {\n\t\tif (in[i] == 'O') {\n\t\t\thajime += ((ruisekiwa[i + 1][0] - ruisekiwa[0][0]) * (ruisekiwa[N][2] - ruisekiwa[i + 1][2]));\n\t\t}\n\t}\n\tll ans = hajime, tmp = 0;\n\t//J????????? ????????????????????????????????????\n\tfor (int i = 0; i < N; i++) {\n\t\tif (in[i] == 'O') {\n\t\t\ttmp += ((ruisekiwa[i + 1][0] - ruisekiwa[0][0] + 1) * (ruisekiwa[N][2] - ruisekiwa[i + 1][2]));\n\t\t}\n\t}\n\tans = max(ans, tmp), tmp = 0;\n\n\t//O????????? ??¨????????????\n\n\tfor (int i = 0; i < N - 1; i++) {\n\t\ttmp = max(tmp, \n\t\t\t(ruisekiwa[i + 1][0] - ruisekiwa[0][0]) * (ruisekiwa[N][2] - ruisekiwa[i + 1][2]));\n\t}\n\tans = max(ans, hajime + tmp), tmp = 0;\n\n\t//I????????????????????????????????????????????????\n\tfor (int i = 0; i < N; i++) {\n\t\tif (in[i] == 'O') {\n\t\t\ttmp += ((ruisekiwa[i + 1][0] - ruisekiwa[0][0]) * (ruisekiwa[N][2] - ruisekiwa[i + 1][2] + 1));\n\t\t}\n\t}\n\tans = max(ans, tmp), tmp = 0;\n\t\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5520, "score_of_the_acc": -0.1096, "final_rank": 3 }, { "submission_id": "aoj_0626_2308458", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing PII = pair<int, int>;\nusing LL = long long;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing PLL = pair<LL, LL>;\nusing VS = vector<string>;\n\n#define ALL(a) begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define EB emplace_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\n#define FF first\n#define SS second\ntemplate<class S, class T>\nistream& operator>>(istream& is, pair<S,T>& p){\n return is >> p.FF >> p.SS;\n}\ntemplate<class S, class T>\nostream& operator<<(ostream& os, const pair<S,T>& p){\n return os << p.FF << \" \" << p.SS;\n}\ntemplate<class T>\nvoid maxi(T& x, T y){\n if(x < y) x = y;\n}\ntemplate<class T>\nvoid mini(T& x, T y){\n if(x > y) x = y;\n}\n\n\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst LL MOD = 1e9+7;\n\nstring JOI = \"JOI\";\nLL calc(string& S){\n int N = SZ(S);\n VVL cnt(N+1, VL(3));\n REP(i,N){\n\tREP(j,3)\n\t cnt[i+1][j] = cnt[i][j] + (JOI[j] == S[i]);\n }\n\n LL res = 0;\n REP(i,N){\n\tif(S[i] == 'O'){\n\t res += cnt[i][0] * (cnt[N][2] - cnt[i][2]);\n\t}\n }\n return res;\n}\n\nint main(){\n cin.tie(0);\n ios_base::sync_with_stdio(false);\n\n int N;\n cin >> N;\n string S;\n cin >> S;\n\n string J = \"J\" + S;\n string I = S + \"I\";\n\n LL ans = max(calc(J), calc(I));\n\n VVL cnt(N+1, VL(3));\n REP(i,N){\n\tREP(j,3)\n\t cnt[i+1][j] = cnt[i][j] + (JOI[j] == S[i]);\n }\n LL orig = calc(S);\n REP(i,N)\n\tmaxi(ans, orig + cnt[i][0] * (cnt[N][2] - cnt[i][2]));\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 14096, "score_of_the_acc": -0.5913, "final_rank": 13 }, { "submission_id": "aoj_0626_2183085", "code_snippet": "#include <iostream>\n#include <algorithm>\n\nusing ll=long long int;\n\nconstexpr int MAX_N=100000;\n\nint n;\nint street[MAX_N];\n\nint sum;\n\nint main() {\n\tstd::cin>>n;\n\tchar ch;\n\tfor(int i=0;i<n;++i){\n\t\tstd::cin>>ch;\n\t\tif(ch=='O'){\n\t\t\tstreet[i]=1;\n\t\t}\n\t\telse if(ch=='I'){\n\t\t\tstreet[i]=2;\n\t\t\t++sum;\n\t\t}\n\t}\n\tll base=0;\n\tint count=0,count1=0;\n\tfor(int i=0;i<n;++i){\n\t\tif(!street[i])\n\t\t\t++count;\n\t\telse if(street[i]==1){\n\t\t\tbase+=count*(sum-count1);\n\t\t}\n\t\telse if(street[i]==2)\n\t\t\t++count1;\n\t}\n\tll ans=0;\n\n\tcount=0;\n\n\tfor(int i=0;i<n;++i){\n\t\tif(!street[i])\n\t\t\t++count;\n\t\telse if(street[i]==1)\n\t\t\tans+=count;\n\t}\n\n\tcount=0;\n\tll tmp=0;\n\n\tfor(int i=n-1;i>=0;--i){\n\t\tif(street[i]==2)\n\t\t\t++count;\n\t\telse if(street[i]==1)\n\t\t\ttmp+=count;\n\t}\n\n\n\tans=std::max(ans,tmp);\n\n\ttmp=0;\n\tcount=0;\n\tcount1=0;\n\n\tfor(int i=0;i<n;++i){\n\t\tif(!street[i])\n\t\t\t++count;\n\t\telse if(street[i]==2)\n\t\t\t++count1;\n\t\tans=std::max(ans,(ll)count*(sum-count1));\n\t}\n\n\tstd::cout<<ans+base<<std::endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3480, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0626_2175621", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n;string T;vector<int>v;\nlong long search(string S){\n\tv.clear();\n\tfor(int i=0;i<(int)S.size();i++){\n\t\tif(S[i]=='J')v.push_back(0);\n\t\tif(S[i]=='O')v.push_back(1);\n\t\tif(S[i]=='I')v.push_back(2);\n\t}\n\tvector<vector<long long> >dp(v.size()+1,vector<long long>(4,0));\n\tdp[0][0]=1;\n\tfor(int i=0;i<(int)v.size();i++){\n\t\tdp[i+1][v[i]+1]+=dp[i][v[i]];\n\t\tfor(int j=0;j<4;j++)dp[i+1][j]+=dp[i][j];\n\t}\n\treturn dp[v.size()][3];\n}\nint main(){\n\tcin>>n>>T;long long ret=0;\n\tret=max(ret,max(search(\"J\"+T),search(T+\"I\")));\n\tlong long c1=0,c2=0,w=search(T);\n\tfor(int i=0;i<(int)T.size();i++){if(T[i]=='I')c2++;}\n\tfor(int i=0;i<(int)T.size();i++){\n\t\tif(T[i]=='J')c1++;if(T[i]=='I')c2--;\n\t\tret=max(ret,w+c1*c2);\n\t}\n\tcout<<ret<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10688, "score_of_the_acc": -0.4082, "final_rank": 11 }, { "submission_id": "aoj_0626_2175619", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n;string T;vector<int>v;\nlong long search(string S){\n\tv.clear();\n\tfor(int i=0;i<(int)S.size();i++){\n\t\tif(S[i]=='J')v.push_back(0);\n\t\tif(S[i]=='O')v.push_back(1);\n\t\tif(S[i]=='I')v.push_back(2);\n\t}\n\tvector<vector<int> >dp(v.size()+1,vector<int>(4,0));\n\tdp[0][0]=1;\n\tfor(int i=0;i<(int)v.size();i++){\n\t\tdp[i+1][v[i]+1]+=dp[i][v[i]];\n\t\tfor(int j=0;j<4;j++)dp[i+1][j]+=dp[i][j];\n\t}\n\treturn dp[v.size()][3];\n}\nint main(){\n\tcin>>n>>T;long long ret=0;\n\tret=max(ret,max(search(\"J\"+T),search(T+\"I\")));\n\tlong long c1=0,c2=0,w=search(T);\n\tfor(int i=0;i<T.size();i++){if(T[i]=='I')c2++;}\n\tfor(int i=0;i<T.size();i++){\n\t\tif(T[i]=='J')c1++;if(T[i]=='I')c2--;\n\t\tret=max(ret,w+c1*c2);\n\t}\n\tcout<<ret<<endl;\n\treturn 0;\n}", "accuracy": 0.6666666666666666, "time_ms": 10, "memory_kb": 8992, "score_of_the_acc": -0.2962, "final_rank": 17 }, { "submission_id": "aoj_0626_2142132", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n#define ll long long\nclass shop {\npublic:\n\tchar stamp;\n\tll num[3];\n\tll dummy;\n\tshop():dummy(-1) {\n\n\t}\n};\n\nint main() {\n\tint time;\n\tcin >> time;\n\tshop *streat;\n\tstreat = new shop[time + 1];\n\tfor (int i = 0; i < 3; ++i) {\n\t\tstreat[0].num[i] = 0;\n\t}\n\tchar dummy;\n\tfor (int i = 1; i <= time; ++i) {\n\t\tcin >> dummy;\n\t\tfor (int j = 0; j < 3; ++j) {\n\t\t\tstreat[i].num[j] = streat[i-1].num[j];\n\t\t}\n\t\tif (dummy == 'J') {\n\t\t\t++streat[i].num[0];\n\t\t}\n\t\telse if (dummy == 'O') {\n\t\t\t++streat[i].num[1];\n\t\t}\n\t\telse {\n\t\t\t++streat[i].num[2];\n\t\t}\n\t\tstreat[i].stamp = dummy;\n\t}\n\tll origin = 0;\n\tll date;\n\tfor (int i = time - 2; i >= 1; --i) {\n\t\tif (streat[i].stamp == 'J') {\n\t\t\tdate = 0;\n\t\t\tfor (int j = i + 1; j <= time; ++j) {\n\t\t\t\tif (streat[j].dummy != -1) {\n\t\t\t\t\tdate += streat[j].dummy;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif (streat[j].stamp == 'O') {\n\t\t\t\t\tdate += streat[time].num[2] - streat[j].num[2];\n\t\t\t\t}\n\t\t\t}\n\t\t\tstreat[i].dummy = date;\n\t\t\torigin += date;\n\t\t}\n\t}\n\tdate = 0;\n\tfor (int j = 1; j <= time; ++j) {\n\t\tif (streat[j].stamp == 'O') {\n\t\t\tdate += streat[time].num[2] - streat[j].num[2];\n\t\t}\n\t}\n\tll answer = date;\n\tdate = 0;\n\tfor (int j = time; j >= 1; --j) {\n\t\tif (streat[j].stamp == 'O') {\n\t\t\tdate += streat[j].num[0];\n\t\t}\n\t}\n\tanswer = max(answer, date);\n\tfor (int i = 2; i < time; ++i) {\n\t\tanswer = max(answer, streat[i].num[0] * (streat[time].num[2] - streat[i].num[2]));\n\t}\n\tcout << origin + answer<< endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7000, "score_of_the_acc": -0.1892, "final_rank": 7 }, { "submission_id": "aoj_0626_2142081", "code_snippet": "#include <vector>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <queue>\n#include <stack>\n#include <iostream>\n#include <cstdio>\n#include <cmath>\n#include <cstring>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef double db;\n\n#define fr first\n#define sc second\n#define pb push_back\n#define rep(i,x) for(ll i=0;i<x;i++)\n#define rep1(i,x) for(ll i=1;i<=x;i++)\n#define rrep(i,x) for(ll i=x-1;i>=0;i--)\n#define rrep1(i,x) for(ll i=x;i>0;i--)\n\nstring s;\nll N;\nll J[100000],O[100000],I[100000];\nll rJ[100000],rO[100000],rI[100000];\nll ans=0;\nll OI,JO;\nint main()\n{\n\tcin>>N;\n\tcin>>s;\n\trep(i,N){\n\t\tif(s[i]=='J'){\n\t\t\tJ[i]++;\n\t\t\trJ[i]++;\n\t\t}\n\t\telse if(s[i]=='O'){\n\t\t\tO[i]++;\n\t\t\trO[i]++;\n\t\t}\n\t\telse {\n\t\t\tI[i]++;\n\t\t\trI[i]++;\n\t\t}\n\t}\n\trep(i,N-1){\n\t\tJ[i+1]+=J[i];\n\t\tO[i+1]+=O[i];\n\t\tI[i+1]+=I[i];\n\t}\n\trrep(i,N-1){\n\t\trJ[i]+=rJ[i+1];\n\t\trO[i]+=rO[i+1];\n\t\trI[i]+=rI[i+1];\n\t}\n\tll cnt=0;\n\trep(i,N){\n\t\tif(s[i]=='O'){\n\t\t\tans+=J[i]*rI[i];\n\t\t\tOI+=rI[i];\n\t\t\tJO+=J[i];\n\t\t}\n\t\tcnt=max(cnt,J[i]*rI[i]);\n\t}\n\tcout<<ans+max(cnt,max(JO,OI))<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8000, "score_of_the_acc": -0.2429, "final_rank": 10 }, { "submission_id": "aoj_0626_2140895", "code_snippet": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <queue>\n#include <vector>\n#include <iterator>\n\nusing namespace std;\n\nlong long int const LL_MAX = 10000000000000000; // 10^16\n\nlong long int DP[3][100001];\n\nlong long int total(int N, string str){\n\t\n\tDP[0][0] = 0;\n\tDP[1][0] = 0;\n\tDP[2][0] = 0;\n\t\n\tstr = \" \" + str;\n\t\n\tfor(int i = 1; i <= N; i++){\n\t\tif(str[i] == 'J'){\n\t\t\tDP[0][i] = DP[0][i - 1] + 1;\n\t\t}else{\n\t\t\tDP[0][i] = DP[0][i - 1];\n\t\t}\n\t}\n\tfor(int i = 1; i <= N; i++){\n\t\tif(str[i] == 'O'){\n\t\t\tDP[1][i] = DP[1][i - 1] + DP[0][i - 1];\n\t\t}else{\n\t\t\tDP[1][i] = DP[1][i - 1];\n\t\t}\n\t}\n\tfor(int i = 1; i <= N; i++){\n\t\tif(str[i] == 'I'){\n\t\t\tDP[2][i] = DP[2][i - 1] + DP[1][i - 1];\n\t\t}else{\n\t\t\tDP[2][i] = DP[2][i - 1];\n\t\t}\n\t}\n\treturn DP[2][N];\n}\n\nint main(){\n\t\n\tstring str;\n\tint N;\n\t\n\tcin >> N;\n\tcin >> str;\n\t\n\tstring str1, str3;\n\t\n\tstr1 = \"J\" + str;\n\tstr3 = str + \"I\";\n\t\n\tlong long int I_sum = 0;\n\t\n\tfor(int i = 0; i < N; i++){\n\t\tif(str[i] == 'I'){\n\t\t\tI_sum++;\n\t\t}\n\t}\n\t\n\tlong long int J_count = 0;\n\tlong long int O_max = 0;\n\t\n\tfor(int i = 0; i < N; i++){\n\t\tif(str[i] == 'J'){\n\t\t\tJ_count++;\n\t\t}else if(str[i] == 'I'){\n\t\t\tI_sum--;\n\t\t}\n\t\tif(J_count * I_sum > O_max){\n\t\t\tO_max = J_count * I_sum;\n\t\t}\n\t}\n\t\n\tlong long int ans = max(max(total(N + 1, str1), total(N + 1, str3)), total(N, str) + O_max);\n\t\n\tcout << ans << endl;\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6024, "score_of_the_acc": -0.1367, "final_rank": 6 }, { "submission_id": "aoj_0626_2008880", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <sstream>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <functional>\n\nusing namespace std;\n\n#define int long long\n\n#define fst first\n#define scd second\n#define PB push_back\n#define MP make_pair\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define omajinai ios::sync_with_stdio(false);cin.tie(0)\n#define rep(i,x) for(int i=0;i<(int)(x);++i)\n#define rep1(i,x) for(int i=1;i<=(int)(x);++i)\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\n\ntemplate<typename T>T& max(T&a,T&b){if(a>=b)return a;return b;}\ntemplate<typename T>T& min(T&a,T&b){if(a<b)return a;return b;}\ntemplate<typename T>bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<typename T>T get(){T a;cin>>a;return a;}\ntemplate<typename T>T rev(T a){reverse(all(a));return a;}\ntemplate<typename T>vector<T>&sort(vector<T>&a){sort(all(a));return a;}\n\nconst int inf = 1e9;\nconst ll linf = 3e18;\nconst double eps = 1e-9;\n\nchar S[100010];\n\nint imosJ[100010];\nint imosO[100010];\nint imosI[100010];\n\nint rev_imosJ[100010];\nint rev_imosO[100010];\nint rev_imosI[100010];\n\nsigned main()\n{ // #define int long long ?????????????????§scanf???????????¨???????????????????????\\?????????????????????\n int N; cin >> N;\n\n rep(i, N) cin >> S[i];\n\n int ma = 0;\n\n { // 'J'\n imosJ[0] += 1;\n\n rep1(i, N) imosJ[i] += imosJ[i - 1] + (S[i - 1] == 'J');\n rep1(i, N) imosO[i] += imosO[i - 1] + imosJ[i - 1] * (S[i - 1] == 'O'); // \"JO\" ?????°\n rep1(i, N) imosI[i] += imosI[i - 1] + imosO[i - 1] * (S[i - 1] == 'I'); // \"JOI\" ?????°\n\n ma = max(ma, imosI[N]);\n }\n\n { // 'I'\n memset(imosJ, 0, sizeof(imosJ));\n memset(imosO, 0, sizeof(imosO));\n memset(imosI, 0, sizeof(imosI));\n\n imosI[N] += 1;\n\n for (int i = N - 1; i >= 0; --i) imosI[i] += imosI[i + 1] + (S[i] == 'I');\n for (int i = N - 1; i >= 0; --i) imosO[i] += imosO[i + 1] + imosI[i + 1] * (S[i] == 'O');\n for (int i = N - 1; i >= 0; --i) imosJ[i] += imosJ[i + 1] + imosO[i + 1] * (S[i] == 'J');\n\n ma = max(ma, imosJ[0]);\n }\n\n { // 'O'\n memset(imosJ, 0, sizeof(imosJ));\n memset(imosO, 0, sizeof(imosO));\n memset(imosI, 0, sizeof(imosI));\n \n rep1(i, N) imosJ[i] += imosJ[i - 1] + (S[i - 1] == 'J');\n rep1(i, N) imosO[i] += imosO[i - 1] + imosJ[i - 1] * (S[i - 1] == 'O'); // \"JO\" ?????°\n rep1(i, N) imosI[i] += imosI[i - 1] + imosO[i - 1] * (S[i - 1] == 'I'); // \"JOI\" ?????°\n\n int sum = imosI[N];\n\n for (int i = N - 1; i >= 0; --i) rev_imosI[i] += rev_imosI[i + 1] + (S[i] == 'I');\n for (int i = N - 1; i >= 0; --i) rev_imosO[i] += rev_imosO[i + 1] + rev_imosI[i + 1] * (S[i] == 'O');\n for (int i = N - 1; i >= 0; --i) rev_imosJ[i] += rev_imosJ[i + 1] + rev_imosO[i + 1] * (S[i] == 'J');\n\n rep(i, N) {\n ma = max(ma, sum + imosJ[i + 1] * rev_imosI[i]);\n }\n }\n\n cout << ma << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5948, "score_of_the_acc": -0.1326, "final_rank": 5 }, { "submission_id": "aoj_0626_1971373", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\nusing namespace std;\nlong long dp[110000][4], n; string T; char F[5] = \"JOI!\";\nlong long solve(string S) {\n\tfor (int i = 0; i < 440000; i++)dp[i / 4][i % 4] = 0; dp[0][0] = 1;\n\tfor (int i = 0; i < S.size(); i++) {\n\t\tfor (int j = 0; j < 4; j++) {\n\t\t\tif (F[j] == S[i])dp[i + 1][j + 1] += dp[i][j];\n\t\t\tdp[i + 1][j] += dp[i][j];\n\t\t}\n\t}\n\treturn dp[S.size()][3];\n}\nint main() {\n\tcin >> n >> T;\n\tlong long J = 0, I = 0; for (int i = 0; i < T.size(); i++)if (T[i] == 'I')I++;\n\tint maxn = 0, maxid = 0;\n\tfor (int j = 0; j < T.size(); j++) {\n\t\tif (T[j] == 'J')J++; if (T[j] == 'I')I--;\n\t\tif (J*I > maxn) { maxn = J*I; maxid = j + 1; }\n\t}\n\tstring T1 = 'J' + T, T2 = T + 'I', T3 = T.substr(0, maxid) + 'O' + T.substr(maxid, T.size() - maxid);\n\tcout << max(solve(T1), max(solve(T2), solve(T3))) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7216, "score_of_the_acc": -0.2008, "final_rank": 8 } ]
aoj_0625_cpp
オレンジの出荷(Oranges) あなたはJuicy Orange Industry 社を知っているだろうか? この会社の業務は美味しいオレンジを栽培して出荷することである.ここでは略してJOI 社と呼ぶ. JOI 社では,収穫された $N$ 個のオレンジを箱詰めして出荷することになった.オレンジは工場にあるベルトコンベアの上に並べられており,ベルトコンベアの前から順番に $1$ から $N$ までの番号が付けられている.オレンジは大小さまざまであり,オレンジ $i$ $(1 \leq i \leq N)$ の大きさは $A_i$ である. これらのオレンジを前から順番にいくつかの箱に分けて詰める.ひとつの箱には連続した番号のオレンジしか詰めることができない. ひとつの箱には最大で $M$ 個までのオレンジを詰めることができる.ある箱にいくつかのオレンジを詰めるためにかかるコストは,箱に詰める最大のオレンジの大きさを $a$,箱に詰める最小のオレンジの大きさを $b$,箱に詰めるオレンジの個数を $s$ としたときに,$K + s \times (a - b)$ で求めることができる.ここで,$K$ は箱にかかるコストであり,すべての箱で共通の値である. 適切な個数の箱を用意して,すべてのオレンジを適切に箱詰めすることで,箱詰めにかかるコストの総和をできるだけ小さくしたい. 課題 ベルトコンベア上に並んでいるオレンジの情報と,ひとつの箱に詰められるオレンジの個数の最大値および,箱にかかるコストが与えられたとき,箱詰めにかかるコストの総和の最小値を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,3 個の整数 $N, M, K$ が空白を区切りとして書かれている.これは,オレンジが $N$ 個あり,ひとつの箱に詰められるオレンジの個数の最大値が $M$ であって,箱にかかるコストが $K$ であることを表す. 続く $N$ 行のうちの $i$ 行目 $(1 \leq i \leq N)$ には,整数 $A_i$ が書かれている.これは,オレンジ $i$ の大きさが $A_i$ であることを表す. 出力 標準出力に,箱詰めにかかるコストの総和の最小値を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. $1 \leq N \leq 20 000$ $1 \leq M \leq 1 000$ $0 \leq K \leq 1 000 000 000$ $1 \leq A_i \leq 1 000 000 000$ $(1 \leq i \leq N)$ $M \leq N$ 入出力例 入力例1 6 3 6 1 2 3 1 2 1 出力例1 21 $1$ 番目の箱にオレンジ $1$ からオレンジ $3$ までの $3$ 個のオレンジを詰め,$2$ 番目の箱にオレンジ $4$ からオレンジ $6$ までの $3$ 個のオレンジを詰めると,箱詰めにかかるコストの総和は $(6+3 \times (3 - 1))+(6+3 \times (2 - 1)) = 21$ となる. どのように詰めても箱詰めにかかるコストの総和が $21$ を下回ることはないので, $21$ を出力する. 入力例2 16 4 12 3 10 13 10 19 9 12 16 11 2 19 9 13 2 13 19 出力例2 164 $11$ 個の箱を用意して,それぞれの箱に前から順に $1$ 個,$3$ 個,$1$ 個,$1$ 個,$3$ 個,$1$ 個,$1$ 個,$2$ 個,$1$ 個,$1$ 個,$1$ 個のオレンジを詰めることで,箱詰めにかかるコストの総和が最小となる. 入力例3 16 6 14 19 7 2 15 17 7 14 12 3 14 5 10 17 20 19 12 出力例3 177 入力例4 10 1 1000000000 1 1 1 1 1 1 1 1 1 1 出力例4 10000000000 答えが32 ビット符号付き整数の範囲に収まるとは限らないことに注意せよ. 第15回 日本情報オリンピック本選 課題   2016 年 2 月 14 日
[ { "submission_id": "aoj_0625_10851487", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint N, M, K, a[20009]; long long dp[20009];\nint main() {\n\tcin >> N >> M >> K;\n\tfor(int i = 0; i < N; i++) cin >> a[i];\n\tdp[0] = 0;\n\tfor(int i = 1; i <= N; i++) {\n\t\tint l = 1999999999, r = -l;\n\t\tdp[i] = 1LL << 60;\n\t\tfor(int j = 1; j <= M && i - j >= 0; j++) {\n\t\t\tl = min(l, a[i - j]);\n\t\t\tr = max(r, a[i - j]);\n\t\t\tdp[i] = min(dp[i], dp[i - j] + K + 1LL * j * (r - l));\n\t\t}\n\t}\n\tcout << dp[N] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3672, "score_of_the_acc": -0.0043, "final_rank": 3 }, { "submission_id": "aoj_0625_10345779", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n,m,k;\n cin >> n >> m >> k;\n vector<int> a(n);\n rep(i,n){\n cin >> a[i];\n }\n\n vector<long long> dp(n+1,LLONG_MAX);\n dp[0]=0;\n for(int i=1;i<=n;i++){\n int cur_max=-1;\n int cur_min=1000000001;\n for(int j=i-1;j>=max(0,i-m);j--){\n cur_max=max(cur_max,a[j]);\n cur_min=min(cur_min,a[j]);\n int s=i-j;\n long long cost=k+(long long)s*(cur_max-cur_min);\n dp[i]=min(dp[i],dp[j]+cost);\n }\n }\n cout << dp[n] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3520, "score_of_the_acc": -0.056, "final_rank": 11 }, { "submission_id": "aoj_0625_9898427", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\ndp\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\n//const int INF = 2147483647;\nconst int64_t INF = 1e18;\nconst int BIG = 2147483647;\n\nconst int MAX_N = 20000 +5;\nstatic int64_t vect[MAX_N];\nstatic int64_t S[MAX_N];\n//------------------------------------------------------------------------------\nint64_t dp(int N, int M, int K, int i)\n{\n if (S[i] != -1) return S[i];\n int64_t& res = S[i];\n res = INF;\n\n int64_t max_v = 0;\n int64_t min_v = INF;\n for (int num=1; num<=min(M,i+1); ++num)\n {\n max_v = max(max_v, vect[i-num+1]);\n min_v = min(min_v, vect[i-num+1]);\n res = min(res, dp(N, M, K, i-num) + K + num*(max_v-min_v));\n }\n \n return res;\n}\n//------------------------------------------------------------------------------\nint64_t solve(int N, int M, int64_t K)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (N == 1) return K;\n else if (N == 2)\n {\n if (M == 1) return 2*K;\n return min(2*K, K + abs(vect[0]-vect[1])*2);\n }\n else if (M == 1) return K*N;\n //--------------------------------------------------------------------------\n // init:\n for (int i=0; i<N; ++i) S[i] = -1;\n S[0] = K;\n S[1] = min(2*K, K + abs(vect[0]-vect[1])*2);\n //--------------------------------------------------------------------------\n // compute:\n int64_t res = dp(N, M, K, N-1);\n\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, M, num;\n int64_t K;\n num = scanf(\"%d %d %ld \", &N, &M, &K);\n for (int i=0; i<N; ++i) num = scanf(\"%ld \", &vect[i]);\n int64_t res = solve(N, M, K);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 50, "memory_kb": 5744, "score_of_the_acc": -0.1753, "final_rank": 16 }, { "submission_id": "aoj_0625_9639795", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing LL = long long;\n\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n LL n, m, k;\n cin >> n >> m >> k;\n\n vector<LL> a(n + 1, 0);\n for (int i = 1; i <= n; ++i) cin >> a[i];\n\n vector<vector<LL>> dp(n + 1, vector<LL>(m + 1, LONG_LONG_MAX));\n for (int i = 0; i <= m; ++i) dp[0][i] = 0;\n dp[1][1] = k;\n\n vector<LL> min_cost(n + 1, LONG_LONG_MAX);\n min_cost[0] = 0;\n min_cost[1] = k;\n for (LL i = 2; i <= n; ++i) {\n LL mn, mx;\n mn = mx = a[i];\n for (LL j = 1; j <= min(i, m); ++j) {\n LL cost = k + j * (mx - mn);\n dp[i][j] = cost + min_cost[i - j];\n min_cost[i] = min(min_cost[i], dp[i][j]);\n mn = min(mn, a[i - j]);\n mx = max(mx, a[i - j]);\n }\n }\n cout << min_cost[n] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 160440, "score_of_the_acc": -1.2581, "final_rank": 18 }, { "submission_id": "aoj_0625_9477467", "code_snippet": "#include <vector>\n#include <algorithm>\n#include <iostream>\n#include <cstdio>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\n#define fr first\n#define sc second\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep1(i, x) for(ll i = 1; i <= x; i++)\nconst ll INF = 0xfffffffffffffff; // 大きな値を設定\n\nll N, M, K;\nll A[20001]; // オレンジの大きさを格納する配列\nll dp[20001]; // dp[i]: i番目のオレンジまでの最小コスト\n\nint main() {\n // 入力の読み込み\n scanf(\"%lld %lld %lld\", &N, &M, &K);\n rep1(i, N) {\n scanf(\"%lld\", &A[i]);\n dp[i] = INF; // 初期化\n }\n dp[0] = 0; // 初期状態\n\n // 動的計画法で最小コストを計算\n rep1(i, N) {\n P p = P(INF, -INF); // p.first は最小値、p.second は最大値\n rep(j, min(M, i)) { // 最大で M 個のオレンジを含む区間を考慮\n p = P(min(p.fr, A[i - j]), max(p.sc, A[i - j]));\n dp[i] = min(dp[i], dp[i - j - 1] + (p.sc - p.fr) * (j + 1) + K);\n }\n }\n\n // 最小コストを出力\n printf(\"%lld\\n\", dp[N]);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3856, "score_of_the_acc": -0.0055, "final_rank": 5 }, { "submission_id": "aoj_0625_8999298", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, M, K;\n cin >> N >> M >> K;\n vi A(N);\n rep(i, N) cin >> A[i];\n vv(ll, cost, N+1, M+1, 0);\n rep(i, N) {\n ll amin = inf;\n ll amax = -inf;\n rep(j, i, min(N, i+M)) {\n chmin(amin, A[j]);\n chmax(amax, A[j]);\n cost[i][j-i+1] = K + (amax-amin)*(j-i+1);\n }\n }\n vi dp(N+1, inf);\n dp[0] = 0;\n rep(i, N) {\n rep(j, i+1, min(N+1, i+M+1)) {\n chmin(dp[j], dp[i] + cost[i][j-i]);\n }\n }\n print(dp[N]);\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 160488, "score_of_the_acc": -1.3636, "final_rank": 19 }, { "submission_id": "aoj_0625_8494187", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m; cin >> n >> m;\n ll k; cin >> k;\n vector<ll> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n vector<ll> dp(n+1, 1e18);\n dp[0] = 0;\n for (int i = 0; i < n; ++i) {\n ll mi = a[i], mx = a[i];\n for (int j = 0; j < m and i+j < n; ++j) {\n mi = min(mi, a[i+j]);\n mx = max(mx, a[i+j]);\n dp[i+j+1] = min(dp[i+j+1], dp[i]+k+(mx-mi)*(j+1));\n }\n }\n cout << dp[n] << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3492, "score_of_the_acc": -0.0558, "final_rank": 9 }, { "submission_id": "aoj_0625_7995592", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M,K;\n cin>>N>>M>>K;\n vll A(N);\n rep(i,N){\n cin>>A[i];\n }\n vll DP(N+1,1e18);\n DP[0]=0;\n rep(i,N){\n ll MA=-1e18;\n ll mi=1e18;\n for(ll m=1;m<=M;m++){\n if(i+m>N)break;\n chmax(MA,A[i+m-1]);\n chmin(mi,A[i+m-1]);\n chmin(DP[i+m],DP[i]+K+m*(MA-mi));\n }\n }\n cout<<DP[N]<<endl;\n \n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3496, "score_of_the_acc": -0.0558, "final_rank": 10 }, { "submission_id": "aoj_0625_7969754", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n using i64 = long long;\n\n int n, m;\n i64 k;\n std::cin >> n >> m >> k;\n\n std::vector< i64 > as(n);\n for (auto &a: as) std::cin >> a;\n\n constexpr i64 inf = 1001001001001001001ll;\n std::vector< i64 > dp(n + 1, inf);\n dp[0] = 0;\n\n for (int i = 1; i <= n; i++) {\n i64 max = -1;\n i64 min = inf;\n\n for (int s = 1; s <= m; s++) {\n if (i < s) break;\n max = std::max(max, as[i - s]);\n min = std::min(min, as[i - s]);\n dp[i] = std::min(dp[i], dp[i - s] + k + s * (max - min));\n }\n }\n\n std::cout << dp.back() << std::endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3480, "score_of_the_acc": -0.0557, "final_rank": 8 }, { "submission_id": "aoj_0625_7969734", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst ll INF = (ll)1e18;\n\nint main() {\n int N, M, K; cin >> N >> M >> K;\n vector<int> A(N);\n for (auto& a : A) cin >> a;\n vector<ll> dp(N + 1, INF);\n dp[0] = 0;\n for (int i = 1 ; i <= N ; i++) {\n ll mn = INF, mx = -INF;\n for (int j = 1 ; j <= M ; j++) {\n if (i - j < 0) break;\n mn = min<ll>(mn, A[i - j]);\n mx = max<ll>(mx, A[i - j]);\n ll cost = dp[i - j] + K + (ll)j * (mx - mn);\n dp[i] = min(dp[i], cost);\n }\n }\n\n cout << dp[N] << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3524, "score_of_the_acc": -0.0034, "final_rank": 2 }, { "submission_id": "aoj_0625_7969733", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\n\nll func(){\n int n;\n cin >> n;\n int m;\n cin >> m;\n int k;\n cin >> k;\n vector<ll> dp(n+1,1e18);\n dp[0] = 0;\n vector<int> as(n);\n for(auto &i:as)cin >> i;\n for(int i=0;i<dp.size();++i){\n ll maxs = -1;\n ll mins = 1e9;\n for(int j=i+1;j<dp.size() and (j-i)<=m;++j){\n maxs = max<ll>(maxs, as[j-1]);\n mins = min<ll>(mins, as[j-1]);\n dp[j] = min<ll>(dp[j], dp[i] + (j-i) * (maxs-mins) + k);\n }\n }\n return dp.back();\n}\n\nint main(){\n cout << func() << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3512, "score_of_the_acc": -0.0033, "final_rank": 1 }, { "submission_id": "aoj_0625_6992263", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0625.cc: \n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 20000;\nconst int MAX_M = 1000;\nconst int INF = 1 << 30;\nconst long long LINF = 1LL << 62;\n\n/* typedef */\n\ntypedef long long ll;\n\n/* global variables */\n\nint as[MAX_N];\nll dp[MAX_N + 1];\n\n/* subroutines */\n\ninline void setmin(ll &a, ll b) { if (a > b) a = b; }\n\n/* main */\n\nint main() {\n int n, m, k;\n scanf(\"%d%d%d\", &n, &m, &k);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n fill(dp, dp + n + 1, LINF);\n dp[0] = 0;\n\n for (int i = 0; i < n; i++) {\n int mina = INF, maxa = 0;\n for (int j = 0; j < m && i + j < n; j++) {\n mina = min(mina, as[i + j]);\n maxa = max(maxa, as[i + j]);\n ll d = dp[i] + k + (ll)(maxa - mina) * (j + 1);\n setmin(dp[i + j + 1], d);\n }\n }\n\n printf(\"%lld\\n\", dp[n]);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3192, "score_of_the_acc": -0.0539, "final_rank": 6 }, { "submission_id": "aoj_0625_6847561", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nll dp[20001];\nint main(){\n\tint n,m,k,a[20000];\n\tcin>>n>>m>>k;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i];\n\tfill(dp+1,dp+n+1,1e18);\n\tfor(int i=0;i<n;i++){\n\t\tint mx=0,mn=1e9;\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tif(i+j<=n){\n\t\t\t\tmx=max(mx,a[i+j-1]);\n\t\t\t\tmn=min(mn,a[i+j-1]);\n\t\t\t\tdp[i+j]=min(dp[i+j],dp[i]+k+(ll)j*(mx-mn));\n\t\t\t}\n\t\t}\n\t}\n\tcout<<dp[n]<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3652, "score_of_the_acc": -0.0568, "final_rank": 13 }, { "submission_id": "aoj_0625_6291389", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e17;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll N, M, K; cin >> N >> M >> K;\n vector<int>A(N); input_arr(A, N);\n vector<vector<int>>Mn(N, vector<int>(M + 1)), Mx(N, vector<int>(M + 1));\n for (ll i = 0; i < N; i++) {\n Mn[i][0] = A[i];\n Mx[i][0] = A[i];\n }\n //m[j][i] = [i, i + j] の min とか max とか\n for (ll i = 0; i < N; i++) {\n for (ll j = 1; j <= M; j++) {\n if (i + j >= N) continue;\n Mn[i][j] = min(Mn[i][j - 1], A[i + j]);\n Mx[i][j] = max(Mx[i][j - 1], A[i + j]);\n }\n }\n //dp[i] = i 個目のオレンジまでを梱包したときのコストの総和の最小値\n ll dp[20100];\n dp[0] = 0;\n for (ll i = 1; i <= N; i++) {\n dp[i] = INF;\n for (ll j = 1; j <= M && i - j >= 0; j++) {\n dp[i] = min(dp[i], dp[i - j] + K + j * (ll)(Mx[i - j][j - 1] - Mn[i - j][j - 1]));\n }\n }\n cout << dp[N] << endl;\n}\nint main() {\n ll T=1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 161248, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0625_6056330", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\ntemplate<class T,T (*op)(T, T)> struct SparseTable {\n vector<vector<T>> table;\n vector<int> lookup;\n int LOGV=0, _n;\n SparseTable(const vector<T> &v) {\n _n=v.size();\n while(_n>>LOGV)LOGV++;\n table.assign(LOGV,vector<T>(_n));\n lookup.resize(_n+1);\n for(int i = 0; i < _n; i++) table[0][i] = v[i];\n for(int i = 1; i < LOGV; i++) {\n for(int j = 0; j + (1 << i) <= _n; j++) {\n table[i][j] = op(table[i - 1][j], table[i - 1][j + (1 << (i - 1))]);\n }\n }\n lookup[1]=0;\n for(int i = 2; i < lookup.size(); i++) {\n lookup[i] = lookup[i >> 1] + 1;\n }\n }\n inline T prod(int l, int r){\n assert(0 <= l && l < r && r <= _n);\n int b = lookup[r - l];\n return op(table[b][l],table[b][r - (1<<b)]);\n }\n};\n\nll op1(ll a,ll b){return min(a,b);}\nll op2(ll a,ll b){return max(a,b);}\n\nint main(){\n LL(n,m,k);\n vector<ll> a(n);\n in(a);\n SparseTable<ll,op1> st1(a);\n SparseTable<ll,op2> st2(a);\n vector<ll> dp(n+1,INF2);\n dp[0]=0;\n for(int i=0;i<n;i++){\n for(int j=1;j<=m&&i+j<=n;j++){\n chmin(dp[i+j],dp[i]+k+j*(st2.prod(i,i+j)-st1.prod(i,i+j)));\n }\n }\n out(dp[n]);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8508, "score_of_the_acc": -0.2454, "final_rank": 17 }, { "submission_id": "aoj_0625_5842108", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, n) for(int i = int(n) - 1; i >= int(l); i--)\n\nconst lint inf = 1e18;\n\nint main(){\n int n, m;\n lint k;\n cin >> n >> m >> k;\n lint a[n];\n rep(i, n) cin >> a[i];\n \n lint dp[20202];\n rep(i, 20202) dp[i] = inf;\n dp[0] = 0;\n \n rep(i, n){\n lint maxi = -inf, mini = inf;\n for(int j = 1; j <= m && i + j <= n; j++){\n maxi = max(maxi, a[i + j - 1]);\n mini = min(mini, a[i + j - 1]);\n \n dp[i + j] = min(dp[i + j], dp[i] + k + j * (maxi - mini));\n }\n }\n \n cout << dp[n] << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3752, "score_of_the_acc": -0.0048, "final_rank": 4 }, { "submission_id": "aoj_0625_5435198", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nusing lli = long long int;\nconst lli inf = 1e18;\n\nint main(){\n lli n,m,k;\n cin >> n >> m >> k;\n vector<lli> a(n);\n for(int i=0; i<n; i++){\n cin >> a[i];\n }\n vector<lli> dp(n+1, inf);\n dp[0] = 0;\n for(int i=0; i<n; i++){\n lli vmin = inf;\n lli vmax = -inf;\n for(int j=0; j<m and i+j<n; j++){\n vmin = min(vmin, a[i+j]);\n vmax = max(vmax, a[i+j]);\n dp[i+j+1] = min(dp[i+j+1], dp[i] + k+(j+1)*(vmax-vmin));\n }\n }\n cout << dp[n] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3476, "score_of_the_acc": -0.0557, "final_rank": 7 }, { "submission_id": "aoj_0625_5390275", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 1000000007;\n// constexpr int MOD = 998244353;\nconstexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconstexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int n, m, k; cin >> n >> m >> k;\n vector<int> orange(n); REP(i, n) cin >> orange[i];\n vector<ll> dp(n + 1, LINF);\n dp[0] = 0;\n REP(i, n) {\n int a = 0, b = INF;\n for (int j = 1; j <= m && i + j <= n; ++j) {\n chmax(a, orange[i + j - 1]);\n chmin(b, orange[i + j - 1]);\n chmin(dp[i + j], dp[i] + k + 1LL * j * (a - b));\n }\n }\n cout << dp[n] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3544, "score_of_the_acc": -0.0561, "final_rank": 12 }, { "submission_id": "aoj_0625_5157467", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nlong long dp[20001]={0};\nint main(void)\n{\n\tint n,a[20001],m,k,i,j,mn,mx;\n\tscanf(\"%d %d %d\",&n,&m,&k);\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t\tdp[i]=0;\n\t}\n\tdp[0]=0;\n\tfor(i=1;i<=n;i++){\n\t\tmn=1000000001;\n\t\tmx=0;\n\t\tfor(j=0;j<m;j++){\n\t\t\tif(i+j>n){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tmn=min(mn,a[i+j]);\n\t\t\tmx=max(mx,a[i+j]);\n\t\t\tdp[i+j]=min(dp[i+j],(long long)(mx-mn)*(j+1)+k+dp[i-1]);\n\t\t\tif(dp[i+j]==0){\n\t\t\t\tdp[i+j]=(long long)(mx-mn)*(j+1)+k+dp[i-1];\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",dp[n]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2988, "score_of_the_acc": -0.1053, "final_rank": 14 }, { "submission_id": "aoj_0625_5099157", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 20005\n\nll N,M,K;\nll dp[SIZE];\nll A[SIZE];\n\nll recursive(ll left){\n\n\tif(dp[left] != -1){\n\n\t\treturn dp[left];\n\t}\n\n\tll num = 0;\n\tll maxi = -HUGE_NUM;\n\tll mini = HUGE_NUM;\n\n\tll ret = HUGE_NUM;\n\n\tfor(ll right = left; right <= min(N,left+M-1); right++){\n\t\tnum++;\n\t\tmaxi = max(maxi,A[right]);\n\t\tmini = min(mini,A[right]);\n\n\t\tret = min(ret,K+num*(maxi-mini)+recursive(right+1));\n\t}\n\n\treturn dp[left] = ret;\n}\n\nint main(){\n\n\tscanf(\"%lld %lld %lld\",&N,&M,&K);\n\n\tA[0] = 0;\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\tfor(int i = 0; i <= N; i++){\n\n\t\tdp[i] = -1;\n\t}\n\n\tdp[N+1] = 0;\n\n\trecursive(1);\n\n\tprintf(\"%lld\\n\",dp[1]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5084, "score_of_the_acc": -0.1185, "final_rank": 15 } ]
aoj_0627_cpp
鉄道運賃(Train Fare) JOI 国には $N$ 個の都市があり,それぞれ $1, 2, ..., N$ の番号が付けられている.都市 1 はJOI 国の首都である. また,JOI 国には鉄道会社がひとつだけあり,この会社は $M$ 個の路線を運行している.これらの路線にはそれぞれ $1, 2, ..., M$ の番号が付けられており,$i$ 番目 $(1 \leq i \leq M)$ の路線は都市 $U_i$ と都市 $V_i$ を双方向に結んでいる.都市と都市の間を鉄道以外で移動することはできない.また,どの都市からどの都市へもいくつかの路線を乗り継いで移動することができるようになっている. 現在,どの路線の運賃も 1 円である.経営不振に陥った鉄道会社は,今後 $Q$ 年間かけていくつかの路線の運賃を値上げする計画を立てた.この計画では,計画開始から $j$ 年目$(1 \leq j \leq Q)$ の年初めに路線 $R_j$ の運賃を 1 円から 2 円に値上げする予定である.値上げされた路線の運賃は,その後ずっと2 円のままであり,再び値上げすることはない. ところで,この鉄道会社では,毎年,各都市の住民の満足度調査を行っている.計画開始前は,どの都市の住民もこの鉄道会社に満足しているが,値上げによって不満を持つ住民が現れる可能性がある. それぞれの年の満足度調査は,その年の値上げの実施後に行う.したがって, $j$ 年目$(1 \leq j \leq Q)$ の満足度調査は,路線 $R_1, R_2, ... , R_j$ の運賃の値上げは完了し,それ以外の路線の運賃は値上げされていない状態で行われることになる. $j$ 年目$(1 \leq j \leq Q)$ の満足度調査では,都市 $k$ $(2 \leq k \leq N)$ の住民は,以下の条件が満たされるとき,そしてそのときに限り鉄道会社に不満を抱く. その時の運賃で都市 $k$ から首都である都市 $1$ へ移動するときの費用の最小値が,計画開始前の運賃で都市 $k$ から都市 $1$ へ移動するときの費用の最小値よりも大きい. ただし,いくつかの路線を使って移動するときの費用は,それぞれの路線の運賃の合計である.また,都市 $1$ の住民が鉄道会社に対して不満を抱くことはない.値上げ後の運賃で最小の費用を達成する経路は,計画開始前の運賃で最小の費用を達成する経路と異なる可能性があることに注意せよ. 計画の実行に先立って,今後 $Q$ 年間の住民の満足度調査それぞれにおいて,鉄道会社に不満を抱く住民がいる都市の数を計算しておきたい. 課題 JOI 国の鉄道路線の情報と,運賃の値上げ計画が与えられたとき,それぞれの満足度調査において鉄道会社に不満を抱く住民がいる都市の数を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,3 個の整数 $N, M, Q$ が空白を区切りとして書かれている.これらは,JOI 国には $N$ 個の都市と $M$ 個の路線があり,運賃の値上げ計画が $Q$ 年間に渡ることを表している. 続く $M$ 行のうちの $i$ 行目$(1 \leq i \leq M)$ には,2 個の整数 $U_i$, $V_i$ が空白を区切りとして書かれている.これらは,$i$ 番目の路線が都市 $U_i$ と都市 $V_i$ を結んでいることを表している. 続く $Q$ 行のうちの $j$ 行目$(1 \leq j \leq Q)$ には,整数 $R_j$ が書かれている.これは,計画の $j$ 年目に路線 $R_j$ の運賃を値上げすることを表している. 出力 標準出力に $Q$ 行で出力せよ. $j$ 行目$(1 \leq j \leq Q)$ には, $j$ 年目の満足度調査で不満を抱く住民がいる都市の数を出力せよ. 制限 すべての入力データは以下の条件を満たす. $2 \leq N \leq 100 000$ $1 \leq Q \leq M \leq 200 000$ $1 \leq U_i \leq N$ $(1 \leq i \leq M)$ $1 \leq V_i \leq N$ $(1 \leq i \leq M)$ $U_i \ne V_i$ $(1 \leq i \leq M)$ $1 \leq R_j \leq M$ $(1 \leq j \leq Q)$ $R_j \ne R_k$ $(1 \leq j < k \leq Q)$ どの2 つの都市についても,それらを直接結ぶ路線は 1 個以下である. どの都市についても,その都市から都市 1 までいくつかの路線を使って移動することができる. 入出力例 入力例1 5 6 5 1 2 1 3 4 2 3 2 2 5 5 3 5 2 4 1 3 出力例1 0 2 2 4 4 この入力例では,計画開始前,及びそれぞれの満足度調査の時点でのそれぞれの都市から都市 $1$ への運賃は,以下の表のようになる. 時点 都市2 都市3 都市4 都市5 計画開始前 1 1 2 2 1 年目 1 1 2 2 2 年目 1 2 2 3 3 年目 1 2 2 3 4 年目 2 2 3 3 5 年目 2 2 4 3 例えば,3 年目の満足度調査では,都市 $3$ と都市 $5$ の住民が不満を抱くので,出力の 3 行目には 2 を出力する. 入力例2 4 6 6 1 2 1 3 1 4 2 3 2 4 3 4 1 4 2 5 3 6 出力例2 1 1 2 2 3 3 入力例3 2 1 1 1 2 1 出力例3 1 第15回 日本情報オリンピック本選 課題   2016 年 2 月 14 日
[ { "submission_id": "aoj_0627_10852726", "code_snippet": "#include <set>\n#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#pragma warning(disable : 4996)\nusing namespace std;\nstruct edge {\n\tint to, id;\n};\nbool operator<(const edge& e1, const edge& e2) {\n\tif (e1.to != e2.to) return e1.to < e2.to;\n\treturn e1.id < e2.id;\n}\nint N, M, Q, a[200009], b[200009], dist[100009], r[200009], ans[200009];\nvector<int> g[100009]; set<edge> G[100009];\nbool ok[200009], vis[200009];\nint main() {\n\tscanf(\"%d%d%d\", &N, &M, &Q);\n\tfor (int i = 0; i < M; i++) {\n\t\tscanf(\"%d%d\", &a[i], &b[i]); a[i]--, b[i]--;\n\t\tg[a[i]].push_back(b[i]);\n\t\tg[b[i]].push_back(a[i]);\n\t}\n\tfill(dist + 1, dist + N, 999999999);\n\tqueue<int> que; que.push(0);\n\twhile (!que.empty()) {\n\t\tint u = que.front(); que.pop();\n\t\tfor (int i : g[u]) {\n\t\t\tif (dist[i] == 999999999) {\n\t\t\t\tdist[i] = dist[u] + 1;\n\t\t\t\tque.push(i);\n\t\t\t}\n\t\t}\n\t}\n\tfill(ok, ok + M, true);\n\tfor (int i = 0; i < Q; i++) scanf(\"%d\", &r[i]), ok[--r[i]] = false; r[Q] = M;\n\tfor (int i = 0; i < M; i++) {\n\t\tif (dist[a[i]] > dist[b[i]]) swap(a[i], b[i]);\n\t\tif (dist[a[i]] != dist[b[i]] && ok[i]) {\n\t\t\tG[a[i]].insert(edge{ b[i], i });\n\t\t}\n\t}\n\tint sum = 1;\n\tfill(ok, ok + N, false); ok[0] = true;\n\tfor (int i = Q - 1; i >= 0; i--) {\n\t\tif (ok[a[r[i + 1]]]) {\n\t\t\tqueue<int> que2; que2.push(a[r[i + 1]]);\n\t\t\twhile (!que2.empty()) {\n\t\t\t\tint u = que2.front(); que2.pop();\n\t\t\t\tif (!ok[u]) ok[u] = true, sum++;\n\t\t\t\tvector<int> l;\n\t\t\t\tfor (edge e : G[u]) {\n\t\t\t\t\tif (!vis[e.id]) {\n\t\t\t\t\t\tvis[e.id] = true; l.push_back(e.id);\n\t\t\t\t\t\tque2.push(e.to);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tfor (int i : l) {\n\t\t\t\t\tG[u].erase(edge{ b[i], i });\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tans[i] = sum;\n\t\tif (dist[a[r[i]]] != dist[b[r[i]]]) {\n\t\t\tG[a[r[i]]].insert(edge{ b[r[i]], r[i] });\n\t\t}\n\t}\n\tfor (int i = 0; i < Q; i++) printf(\"%d\\n\", N - ans[i]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 26384, "score_of_the_acc": -0.6393, "final_rank": 16 }, { "submission_id": "aoj_0627_10771640", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll =long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N,M,Q;\n cin>>N>>M>>Q;\n \n vector<vector<array<ll,2>>> G(N);\n for(int i=0;i<M;i++){\n int U,V;\n cin>>U>>V;\n U--;V--;\n G[U].push_back({V,i});\n G[V].push_back({U,i});\n }\n vector<int> R(M,int(1e9));\n for(int i=0;i<Q;i++){\n int r;\n cin>>r;\n R[r-1]=i;\n }\n priority_queue<array<ll,3>,vector<array<ll,3>>,greater<array<ll,3>>> query;\n query.push({0,-Q,0});\n vector<array<ll,2>> D(N,{ll(1e18),-1});\n D[0]={0,Q};\n while(!query.empty()){\n auto [c,d,n]=query.top();\n\n query.pop();\n array<ll,2> p={c,-d};\n if(D[n]!=p)continue;\n for(auto [v,id]:G[n]){\n ll w=R[id];\n if(D[v][0]<D[n][0]+1)continue;\n if(D[v][0]>D[n][0]+1){\n D[v][0]=D[n][0]+1;\n D[v][1]=-1;\n }\n ll nw=min(D[n][1],w);\n if(D[v][1]<nw){\n D[v][1]=nw;\n query.push({D[v][0],-D[v][1],v});\n }\n }\n }\n vector<ll> AN(Q+1,0);\n for(int i=0;i<N;i++){\n AN[D[i][1]]++;\n }\n for(int q=0;q<Q;q++){\n cout<<AN[q]<<\"\\n\";\n AN[q+1]+=AN[q];\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 21124, "score_of_the_acc": -0.4263, "final_rank": 13 }, { "submission_id": "aoj_0627_9572018", "code_snippet": "#include <bits/stdc++.h>\n\n\n\n\nnamespace zawa {\n\nusing i16 = std::int16_t;\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing i128 = __int128_t;\n\nusing u8 = std::uint8_t;\nusing u16 = std::uint16_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\n\nusing usize = std::size_t;\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nvoid SetFastIO() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n}\n\nvoid SetPrecision(u32 dig) {\n std::cout << std::fixed << std::setprecision(dig);\n}\n\n} // namespace zawa\nusing namespace zawa;\n\nint main() {\n SetFastIO();\n\n int N, M, Q;\n std::cin >> N >> M >> Q;\n std::vector<int> U(M), V(M);\n std::vector<std::vector<int>> g(N);\n for (int i{} ; i < M ; i++) {\n std::cin >> U[i] >> V[i];\n U[i]--; V[i]--;\n g[U[i]].push_back(V[i]);\n g[V[i]].push_back(U[i]);\n }\n std::vector<int> dist(N, (int)1e9);\n dist[0] = 0;\n std::queue<int> que;\n que.push(0);\n while (que.size()) {\n int v{que.front()};\n que.pop();\n for (auto x : g[v]) if (dist[x] > dist[v] + 1) {\n dist[x] = dist[v] + 1;\n que.push(x);\n }\n }\n std::vector<bool> use(M); \n for (int i{} ; i < M ; i++) {\n if (dist[U[i]] > dist[V[i]]) std::swap(U[i], V[i]);\n if (dist[U[i]] + 1 == dist[V[i]]) use[i] = true;\n }\n std::vector<int> R(Q);\n std::vector<bool> app(M);\n for (auto& r : R) {\n std::cin >> r;\n r--;\n app[r] = true;\n }\n std::vector<std::vector<int>> g2(N);\n for (int i{} ; i < M ; i++) if (!app[i] and use[i]) {\n g2[U[i]].push_back(V[i]);\n }\n std::vector<bool> vis(N);\n int val{N};\n auto dfs{[&](auto dfs, int v) -> void {\n val--;\n vis[v] = true;\n for (auto x : g2[v]) if (!vis[x]) {\n dfs(dfs, x);\n }\n }};\n dfs(dfs, 0);\n std::vector<int> ans(Q);\n for (int i{Q} ; i-- ; ) {\n ans[i] = val;\n if (!use[R[i]]) continue;\n g2[U[R[i]]].push_back(V[R[i]]);\n if (vis[U[R[i]]] and !vis[V[R[i]]]) dfs(dfs, V[R[i]]);\n }\n for (auto a : ans) std::cout << a << '\\n';\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 23784, "score_of_the_acc": -0.5303, "final_rank": 15 }, { "submission_id": "aoj_0627_9477478", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\nusing namespace std;\n\n#define MAX 100005\n\nstruct T {\n int lst, id, v;\n};\n\nT tbl[4 * MAX];\nint head[MAX], cnt = 1;\nint ans[2 * MAX], dis[MAX], ed[MAX];\nint que[MAX], top, queue_end;\nint N, M, Q;\n\ninline int Min(int a, int b) {\n return a <= b ? a : b;\n}\n\ninline void chmax(int &a, int b) {\n if (a < b) a = b;\n}\n\nvoid add(int u, int v) {\n tbl[++cnt] = {head[u], Q + 1, v};\n head[u] = cnt;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n\n cin >> N >> M >> Q;\n for (int i = 0; i < M; ++i) {\n int u, v;\n cin >> u >> v;\n add(u, v);\n add(v, u);\n }\n\n for (int i = 1; i <= Q; ++i) {\n int x;\n cin >> x;\n x <<= 1;\n tbl[x].id = tbl[x + 1].id = i;\n }\n\n dis[1] = 1;\n ed[1] = Q + 1;\n que[queue_end++] = 1;\n\n while (top != queue_end) {\n int u = que[top++];\n ++ans[ed[u]];\n\n for (int i = head[u]; i; i = tbl[i].lst) {\n int v = tbl[i].v;\n if (!dis[v]) {\n dis[v] = dis[u] + 1;\n que[queue_end++] = v;\n }\n if (dis[v] == dis[u] + 1) {\n chmax(ed[v], Min(ed[u], tbl[i].id));\n }\n }\n }\n\n for (int i = 1; i <= Q; ++i) {\n ans[i] += ans[i - 1];\n cout << ans[i] << '\\n';\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10500, "score_of_the_acc": -0.0037, "final_rank": 1 }, { "submission_id": "aoj_0627_9220608", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> pi;\nint n, m, q, u, v, r, node[100010], cnt[100010], age[200010], ans[200010];\nvector<pi> edge[100010];\nqueue<int> que;\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n cin >> n >> m >> q;\n for(int i=1;i<=m;i++){\n cin >> u >> v;\n edge[u].push_back(pi(v, i));\n edge[v].push_back(pi(u, i));\n age[i] = q+1;\n }\n for(int i=1;i<=q;i++){\n cin >> r;\n age[r] = i;\n }\n memset(node, -1, sizeof(node));\n node[1] = 0;\n memset(cnt, -1, sizeof(cnt));\n cnt[1] = q+5;\n que.push(1);\n while(!que.empty()){\n int now = que.front();\n que.pop();\n for(int i=0;i<edge[now].size();i++){\n int to = edge[now][i].first;\n if(node[to]<0){\n node[to] = node[now]+1;\n que.push(to);\n }\n if(node[to]==node[now]+1) cnt[to] = max(cnt[to], min(cnt[now], age[edge[now][i].second]));\n }\n }\n for(int i=1;i<=n;i++) ans[cnt[i]]++;\n int sum=0;\n for(int i=1;i<=q;i++){\n sum += ans[i];\n cout << sum << endl;\n }\n return(0);\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14448, "score_of_the_acc": -0.2093, "final_rank": 8 }, { "submission_id": "aoj_0627_9220587", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> pi;\nint n, m, q, u, v, r;\nint node[100010]={};\nint cnt[100010]={};\nint age[200010];\nint ans[200010];\nvector<pi> edge[100010];\n\nint main(){\n \n cin.tie(0);\n ios::sync_with_stdio(0);\n\n cin >> n >> m >> q;\n for(int i=1;i<=m;i++){\n cin >> u >> v;\n edge[u].push_back(pi(v, i));\n edge[v].push_back(pi(u, i));\n age[i] = q+1;\n }\n \n for(int i=1;i<=q;i++){\n cin >> r;\n age[r] = i;\n }\n \n memset(node, -1, sizeof(node));\n node[1] = 0;\n memset(cnt, -1, sizeof(cnt));\n cnt[1] = q+1;\n \n queue<int> que;\n que.push(1);\n while(!que.empty()){\n int now = que.front();\n que.pop();\n for(int i=0;i<edge[now].size();i++){\n int to = edge[now][i].first;\n if(node[to]<0){\n node[to] = node[now]+1;\n que.push(to);\n }\n if(node[to]==node[now]+1){\n int e = edge[now][i].second;\n cnt[to] = max(cnt[to], min(cnt[now], age[e]));\n }\n }\n }\n for(int i=1;i<=n;i++) ans[cnt[i]]++;\n for(int i=1;i<q;i++) ans[i+1] += ans[i];\n for(int i=1;i<=q;i++) cout << ans[i] << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 14448, "score_of_the_acc": -0.2093, "final_rank": 8 }, { "submission_id": "aoj_0627_9220445", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> pi;\nint n, m, q, u, v, r[200010];\nbool qb[200010]={};\nvector<int> aru[100010];\nvector<pi> edge[100010];\npi medge[200010];\nvoid bfs(){\n int node[100010];\n memset(node, -1, sizeof(node));\n node[1] = 0;\n queue<pi> que;\n que.push(pi(1, 0));\n while(!que.empty()){\n pi now = que.front();\n que.pop();\n for(int i=0;i<edge[now.first].size();i++){\n pi to = edge[now.first][i];\n int cst = node[now.first];\n if(node[to.first]<0){\n node[to.first] = cst+1;\n medge[to.second] = pi(now.first, to.first);\n que.push(to);\n } else if(node[to.first]==cst+1){\n medge[to.second] = pi(now.first, to.first);\n }\n }\n }\n}\n\nint sum;\nbool one[100010]={};\nvoid unite(int now){\n for(int i=0;i<aru[now].size();i++){\n int to = aru[now][i];\n if(!one[to]){\n sum--;\n one[to] = true;\n unite(to);\n }\n }\n}\n\nint main(){\n \n cin.tie(0);\n ios::sync_with_stdio(0);\n\n cin >> n >> m >> q;\n for(int i=1;i<=m;i++){\n cin >> u >> v;\n edge[u].push_back(pi(v, i));\n edge[v].push_back(pi(u, i));\n medge[i] = pi(0, 0);\n }\n for(int i=1;i<=q;i++){\n cin >> r[i];\n qb[ r[i] ] = true;\n }\n \n bfs();\n \n stack<int> st;\n one[1] = true;\n sum = n-1;\n for(int i=1;i<=m;i++){\n if(!qb[i]){\n if(medge[i].first!=0){\n aru[medge[i].first].push_back(medge[i].second);\n if(one[ medge[i].first ] && !one[ medge[i].second ]){\n sum--;\n one[ medge[i].second ] = true;\n unite(medge[i].second);\n }\n }\n }\n }\n st.push(sum);\n \n for(int i=q;i>1;i--){\n if(medge[r[i]].first!=0){\n aru[ medge[r[i]].first ].push_back(medge[r[i]].second);\n if(one[ medge[r[i]].first ] && !one[ medge[r[i]].second ]){\n sum--;\n one[ medge[r[i]].second ] = true;\n unite(medge[r[i]].second);\n }\n }\n st.push(sum);\n }\n while(!st.empty()){\n cout << st.top() << endl;\n st.pop();\n }\n \n return(0);\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 20708, "score_of_the_acc": -0.4796, "final_rank": 14 }, { "submission_id": "aoj_0627_9220412", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> pi;\nint n, m, q, u[200010], v[200010], r[200010];\nbool qb[100010]={};\nvector<int> edge[100010], aru[100010];\nset<pi> se;\nvoid bfs(){\n int node[100010];\n memset(node, -1, sizeof(node));\n node[1] = 0;\n queue<int> que;\n que.push(1);\n while(!que.empty()){\n int now = que.front();\n que.pop();\n for(int i=0;i<edge[now].size();i++){\n int to = edge[now][i];\n int cst = node[now];\n if(node[to]<0){\n node[to] = cst+1;\n se.insert(pi(now, to));\n que.push(to);\n } else if(node[to]==cst+1){\n se.insert(pi(now, to));\n }\n }\n }\n}\n\nint sum;\nbool one[100010]={};\nvoid unite(int now){\n if(!one[now]) return;\n for(int i=0;i<aru[now].size();i++){\n int to = aru[now][i];\n if(!one[to]){\n sum--;\n one[to] = true;\n unite(to);\n }\n }\n}\n\nint main(){\n \n cin >> n >> m >> q;\n for(int i=1;i<=m;i++){\n cin >> u[i] >> v[i];\n edge[u[i]].push_back(v[i]);\n edge[v[i]].push_back(u[i]);\n }\n for(int i=1;i<=q;i++){\n cin >> r[i];\n qb[ r[i] ] = true;\n }\n \n bfs();\n \n stack<int> st;\n one[1] = true;\n sum = n-1;\n for(int i=1;i<=m;i++){\n if(!qb[i]){\n if(se.find(pi(u[i], v[i]))!=se.end()){\n aru[u[i]].push_back(v[i]);\n unite(u[i]);\n } else if(se.find(pi(v[i], u[i]))!=se.end()){\n aru[v[i]].push_back(u[i]);\n unite(v[i]);\n }\n }\n }\n st.push(sum);\n \n for(int i=q;i>1;i--){\n if(se.find(pi(u[r[i]], v[r[i]]))!=se.end()){\n aru[ u[r[i]] ].push_back(v[r[i]]);\n unite(u[r[i]]);\n } else if(se.find(pi(v[r[i]], u[r[i]]))!=se.end()){\n aru[ v[r[i]] ].push_back(u[r[i]]);\n unite(v[r[i]]);\n }\n st.push(sum);\n }\n while(!st.empty()){\n cout << st.top() << endl;\n st.pop();\n }\n \n return(0);\n}", "accuracy": 0.14814814814814814, "time_ms": 220, "memory_kb": 22652, "score_of_the_acc": -0.5447, "final_rank": 20 }, { "submission_id": "aoj_0627_9150921", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m, q;\n cin >> n >> m >> q;\n vector<int> x(m), y(m);\n vector<vector<int>> g(n);\n for (int i = 0; i < m; ++i) {\n cin >> x[i] >> y[i];\n x[i] -= 1, y[i] -= 1;\n g[x[i]].push_back(y[i]);\n g[y[i]].push_back(x[i]);\n }\n vector<int> d(n, -1);\n d[0] = 0;\n queue<int> que;\n que.push(0);\n while (que.size()) {\n auto s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (d[t] == -1) {\n d[t] = d[s] + 1;\n que.push(t);\n }\n }\n }\n vector<int> query(m);\n vector<int> rq(q + 1);\n for (int i = 0; i < q; ++i) {\n int z;\n cin >> z;\n query[z - 1] = q - i;\n rq[q - i] = z - 1;\n }\n int res = 0;\n vector<int> dp(n, -1);\n dp[0] = 0;\n for (int i = 0; i < n; ++i) {\n g[i].clear();\n }\n vector<int> ans(q);\n for (int i = 0; i <= q; ++i) {\n if (!i) {\n for (int j = 0; j < m; ++j) {\n if (!query[j]) {\n g[x[j]].push_back(y[j]);\n g[y[j]].push_back(x[j]);\n }\n }\n que.push(0);\n while (que.size()) {\n int s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (d[t] == d[s] + 1 and dp[t] == -1) {\n dp[t] = dp[s] + 1;\n que.push(t);\n }\n }\n }\n for (int j = 0; j < n; ++j) {\n res += (dp[j] == d[j]);\n }\n } else {\n ans[q - i] = n - res;\n int j = rq[i];\n g[x[j]].push_back(y[j]);\n g[y[j]].push_back(x[j]);\n if (dp[x[j]] == -1 and dp[y[j]] == d[y[j]] and d[x[j]] == d[y[j]] + 1) {\n res += 1;\n dp[x[j]] = dp[y[j]] + 1;\n que.push(x[j]);\n }\n swap(x[j], y[j]);\n if (dp[x[j]] == -1 and dp[y[j]] == d[y[j]] and d[x[j]] == d[y[j]] + 1) {\n res += 1;\n dp[x[j]] = dp[y[j]] + 1;\n que.push(x[j]);\n }\n while (que.size()) {\n int s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (dp[t] == -1 and d[t] == d[s] + 1) {\n dp[t] = dp[s] + 1;\n que.push(t);\n res += 1;\n }\n }\n }\n }\n }\n for (int i = 0; i < q; ++i) {\n cout << ans[i] << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 14328, "score_of_the_acc": -0.1606, "final_rank": 5 }, { "submission_id": "aoj_0627_9150896", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m, q;\n cin >> n >> m >> q;\n vector<int> x(m), y(m);\n vector<vector<int>> g(n);\n for (int i = 0; i < m; ++i) {\n cin >> x[i] >> y[i];\n x[i] -= 1, y[i] -= 1;\n g[x[i]].push_back(y[i]);\n g[y[i]].push_back(x[i]);\n }\n vector<int> d(n, -1);\n d[0] = 0;\n queue<int> que;\n que.push(0);\n while (que.size()) {\n auto s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (d[t] == -1) {\n d[t] = d[s] + 1;\n que.push(t);\n }\n }\n }\n vector<int> query(m);\n vector<int> rq(q + 1);\n for (int i = 0; i < q; ++i) {\n int z;\n cin >> z;\n query[z - 1] = q - i;\n rq[q - i] = z - 1;\n }\n int res = 0;\n vector<int> dp(n, -1);\n dp[0] = 0;\n for (int i = 0; i < n; ++i) {\n g[i].clear();\n }\n vector<int> ans(q);\n for (int i = 0; i <= q; ++i) {\n if (!i) {\n for (int j = 0; j < m; ++j) {\n if (!query[j]) {\n g[x[j]].push_back(y[j]);\n g[y[j]].push_back(x[j]);\n }\n }\n que.push(0);\n while (que.size()) {\n int s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (d[t] == d[s] + 1 and dp[t] == -1) {\n dp[t] = dp[s] + 1;\n que.push(t);\n }\n }\n }\n for (int j = 0; j < n; ++j) {\n res += (dp[j] == d[j]);\n }\n } else {\n ans[q - i] = n - res;\n int j = rq[i];\n g[x[j]].push_back(y[j]);\n g[y[j]].push_back(x[j]);\n if (dp[x[j]] == d[x[j]]) que.push(x[j]);\n if (dp[y[j]] == d[y[j]]) que.push(y[j]);\n while (que.size()) {\n int s = que.front();\n que.pop();\n for (int t : g[s]) {\n if (dp[t] == -1 and d[t] == d[s] + 1) {\n dp[t] = dp[s] + 1;\n que.push(t);\n res += 1;\n }\n }\n }\n }\n }\n for (int i = 0; i < q; ++i) {\n cout << ans[i] << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 14328, "score_of_the_acc": -1.1496, "final_rank": 18 }, { "submission_id": "aoj_0627_8861029", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\nusing namespace std;\n\nvoid reader(int *x) {\n int k = getchar_unlocked();\n *x = k - '0';\n while (1) {\n k = getchar_unlocked();\n if (k < '0' || k > '9')\n break;\n *x = ((*x) << 1) + ((*x) << 3) + k - '0';\n }\n}\n\nvector<int> E[100000];\nint u[200000], v[200000], r[200000], ans[200000], d[100000], cnt = 1;\nbool b[200000], ok[100000], diff[200000];\nqueue<int> que;\n\nvoid bfs(int u, int t) {\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : E[p]) {\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = 1;\n cnt++;\n que.push(v);\n }\n } else if (!~d[v]) {\n d[v] = d[p] + 1;\n que.push(v);\n }\n }\n }\n}\n\nint main() {\n int n, m, q;\n reader(&n);\n reader(&m);\n reader(&q);\n\n rep(i, m) {\n reader(&u[i]);\n reader(&v[i]);\n u[i]--;\n v[i]--;\n E[u[i]].push_back(v[i]);\n E[v[i]].push_back(u[i]);\n }\n\n memset(d, -1, sizeof(d));\n d[0] = 0;\n bfs(0, 0);\n\n rep(i, m) {\n if (d[u[i]] > d[v[i]]) swap(u[i], v[i]);\n diff[i] = (d[v[i]] - d[u[i]] == 1); // Store the result of the computation\n }\n\n rep(i, n) E[i].clear();\n\n rep(i, q) {\n reader(&r[i]);\n r[i]--;\n b[r[i]] = true;\n }\n\n ok[0] = true;\n\n rep(i, m) {\n if (!b[i] && diff[i]) {\n E[u[i]].emplace_back(v[i]);\n }\n }\n\n bfs(0, 1);\n\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n if (diff[r[i]] && !ok[v[r[i]]]) {\n E[u[r[i]]].emplace_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1);\n }\n }\n }\n\n rep(i, q) printf(\"%d\\n\", ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 14160, "score_of_the_acc": -0.1431, "final_rank": 4 }, { "submission_id": "aoj_0627_8861023", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\nusing namespace std;\n\nvoid reader(int *x) {\n int k = getchar_unlocked();\n *x = k - '0';\n while (1) {\n k = getchar_unlocked();\n if (k < '0' || k > '9')\n break;\n *x = ((*x) << 1) + ((*x) << 3) + k - '0';\n }\n}\n\nvector<int> E[100000];\nint u[200000], v[200000], r[200000], ans[200000], d[100000], cnt = 1;\nbool b[200000], ok[100000];\nqueue<int> que;\n\nvoid bfs(int u, int t) {\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : E[p]) {\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = 1;\n cnt++;\n que.push(v);\n }\n } else if (!~d[v]) {\n d[v] = d[p] + 1;\n que.push(v);\n }\n }\n }\n}\n\nint main() {\n int n, m, q;\n reader(&n);\n reader(&m);\n reader(&q);\n rep(i, m) {\n reader(&u[i]);\n reader(&v[i]);\n u[i]--;\n v[i]--;\n E[u[i]].push_back(v[i]);\n E[v[i]].push_back(u[i]);\n }\n queue<int> que;\n memset(d, -1, sizeof(d));\n d[0] = 0;\n bfs(0, 0);\n rep(i, m) {\n if (d[u[i]] > d[v[i]])\n swap(u[i], v[i]);\n }\n rep(i, n) E[i].clear();\n rep(i, q) {\n reader(&r[i]);\n r[i]--;\n b[r[i]] = true;\n }\n ok[0] = true;\n rep(i, m) {\n if (!b[i]) {\n if (d[v[i]] - d[u[i]] == 1) {\n E[u[i]].emplace_back(v[i]);\n }\n }\n }\n bfs(0, 1);\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n bool shouldRemoveEdge = d[v[r[i]]] - d[u[r[i]]] == 1; // store the result to avoid redundant computation\n if (shouldRemoveEdge && !ok[v[r[i]]]) {\n E[u[r[i]]].emplace_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1);\n }\n }\n }\n rep(i, q) printf(\"%d\\n\", ans[i]);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 13956, "score_of_the_acc": -0.1351, "final_rank": 3 }, { "submission_id": "aoj_0627_8861022", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cstring>\n\nusing namespace std;\n\nvoid reader(int &x) {\n cin >> x;\n}\n\nvoid bfs(int u, int t, vector<vector<int>> &E, queue<int> &que, vector<int> &d, vector<int> &ok, int &cnt) {\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : E[p]) {\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = 1;\n cnt++;\n que.push(v);\n }\n } else if (d[v] == -1) {\n d[v] = d[p] + 1;\n que.push(v);\n }\n }\n }\n}\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int n, m, q;\n reader(n);\n reader(m);\n reader(q);\n vector<int> u(m), v(m), r(q), ans(q), d(n), ok(n);\n vector<vector<int>> E(n);\n queue<int> que;\n int cnt = 1;\n for (int i = 0; i < m; i++) {\n reader(u[i]);\n reader(v[i]);\n u[i]--;\n v[i]--;\n E[u[i]].push_back(v[i]);\n E[v[i]].push_back(u[i]);\n }\n memset(&d[0], -1, sizeof(int) * n);\n d[0] = 0;\n bfs(0, 0, E, que, d, ok, cnt);\n for (int i = 0; i < m; i++) {\n if (d[u[i]] > d[v[i]])\n swap(u[i], v[i]);\n }\n for (int i = 0; i < n; i++) E[i].clear();\n vector<int> b(m);\n ok[0] = true;\n for (int i = 0; i < q; i++) {\n reader(r[i]);\n r[i]--;\n b[r[i]] = true;\n }\n for (int i = 0; i < m; i++) {\n if (!b[i]) {\n if (d[v[i]] - d[u[i]] == 1) {\n E[u[i]].emplace_back(v[i]);\n }\n }\n }\n bfs(0, 1, E, que, d, ok, cnt);\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n if (d[v[r[i]]] - d[u[r[i]]] == 1 && !ok[v[r[i]]]) {\n E[u[r[i]]].emplace_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1, E, que, d, ok, cnt);\n }\n }\n }\n for (int i = 0; i < q; i++) cout << ans[i] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 14428, "score_of_the_acc": -0.1645, "final_rank": 6 }, { "submission_id": "aoj_0627_8861020", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\nusing namespace std;\nvoid reader(int *x) {\n int k = getchar_unlocked();\n *x = k - '0';\n while (1) {\n k = getchar_unlocked();\n if (k < '0' || k > '9')\n break;\n *x = ((*x) << 1) + ((*x) << 3) + k - '0';\n }\n}\nvector<int> E[100000];\nint u[200000], v[200000], r[200000], ans[200000], d[100000], cnt = 1;\nbool b[200000], ok[100000], visited[100000];\nqueue<int> que;\nvoid bfs(int u, int t) {\n memset(visited, 0, sizeof(visited)); // Initialize visited array\n visited[u] = true; // Mark the starting node as visited\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : E[p]) {\n if (!visited[v]) { // Check if the node has been visited\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = 1;\n cnt++;\n visited[v] = true; // Mark the node as visited\n que.push(v);\n }\n } else if (!~d[v]) {\n d[v] = d[p] + 1;\n visited[v] = true; // Mark the node as visited\n que.push(v);\n }\n }\n }\n }\n}\nint main() {\n int n, m, q;\n reader(&n);\n reader(&m);\n reader(&q);\n rep(i, m) {\n reader(&u[i]);\n reader(&v[i]);\n u[i]--;\n v[i]--;\n E[u[i]].push_back(v[i]);\n E[v[i]].push_back(u[i]);\n }\n memset(d, -1, sizeof(d));\n d[0] = 0;\n bfs(0, 0);\n rep(i, m) {\n if (d[u[i]] > d[v[i]])\n swap(u[i], v[i]);\n }\n rep(i, n) E[i].clear();\n rep(i, q) {\n reader(&r[i]);\n r[i]--;\n b[r[i]] = true;\n }\n ok[0] = true;\n rep(i, m) {\n if (!b[i]) {\n if (d[v[i]] - d[u[i]] == 1) {\n E[u[i]].emplace_back(v[i]);\n }\n }\n }\n bfs(0, 1);\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n if (d[v[r[i]]] - d[u[r[i]]] == 1 && !ok[v[r[i]]]) {\n E[u[r[i]]].emplace_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1);\n }\n }\n }\n rep(i, q) printf(\"%d\\n\", ans[i]);\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 14040, "score_of_the_acc": -0.186, "final_rank": 7 }, { "submission_id": "aoj_0627_8861019", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n, m, q, a[210000], b[210000], c, dist[110000], T[110000], cnt, U[110000];\n vector<pair<int, int>> x[110000], y[110000];\n bool used[210000];\n\n scanf(\"%d%d%d\", &n, &m, &q);\n for (int i = 0; i < m; i++) {\n scanf(\"%d%d\", &a[i], &b[i]);\n x[a[i]].push_back(make_pair(b[i], i));\n x[b[i]].push_back(make_pair(a[i], i));\n }\n fill(dist, dist + n + 1, 999999);\n dist[1] = 0;\n queue<int> Q;\n Q.push(1);\n while (!Q.empty()) {\n int a1 = Q.front();\n Q.pop();\n for (pair<int, int> i : x[a1]) {\n if (dist[i.first] > dist[a1] + 1) {\n dist[i.first] = dist[a1] + 1;\n Q.push(i.first);\n }\n }\n }\n for (int i = 1; i <= n; i++) {\n for (pair<int, int> j : x[i]) {\n if (dist[i] < dist[j.first]) {\n y[i].push_back(j);\n T[j.first]++;\n }\n }\n }\n for (int i = 0; i < q; i++) {\n scanf(\"%d\", &c);\n c--;\n queue<pair<int, int>> Q1;\n int ss = -1;\n if (dist[a[c]] < dist[b[c]])\n ss = b[c];\n if (dist[a[c]] > dist[b[c]])\n ss = a[c];\n if (ss >= 1 && U[ss] == 0 && used[c] == false) {\n Q1.push(make_pair(ss, c));\n while (!Q1.empty()) {\n int a1 = Q1.front().first, a2 = Q1.front().second;\n Q1.pop();\n if (U[a1] == 1 || used[a2] == true)\n continue;\n T[a1]--;\n used[a2] = true;\n if (T[a1] != 0)\n continue;\n cnt++;\n U[a1] = 1;\n for (pair<int, int> j : y[a1]) {\n if (U[j.first] == 0)\n Q1.push(j);\n }\n }\n }\n printf(\"%d\\n\", cnt);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 20456, "score_of_the_acc": -0.4075, "final_rank": 11 }, { "submission_id": "aoj_0627_8861011", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n, m, q, a[210000], b[210000], c, dist[110000], T[110000], cnt, U[110000];\nlist<pair<int, int>> x[110000], y[110000];\nunordered_set<int> used;\nint main() {\n ios_base::sync_with_stdio(false);\n scanf(\"%d%d%d\", &n, &m, &q);\n for (int i = 0; i < m; i++) {\n scanf(\"%d%d\", &a[i], &b[i]);\n x[a[i]].push_back(make_pair(b[i], i));\n x[b[i]].push_back(make_pair(a[i], i));\n }\n fill(dist, dist + n + 1, 999999);\n dist[1] = 0;\n queue<int> Q;\n Q.push(1);\n while (!Q.empty()) {\n int a1 = Q.front();\n Q.pop();\n for (pair<int, int>& i : x[a1]) {\n if (dist[i.first] > dist[a1] + 1) {\n dist[i.first] = dist[a1] + 1;\n Q.push(i.first);\n }\n }\n }\n for (int i = 1; i <= n; i++) {\n for (pair<int, int>& j : x[i]) {\n if (dist[i] < dist[j.first]) {\n y[i].push_back(j);\n T[j.first]++;\n }\n }\n }\n for (int i = 0; i < q; i++) {\n scanf(\"%d\", &c);\n c--;\n queue<pair<int, int>> Q1;\n int ss = -1;\n if (dist[a[c]] < dist[b[c]])\n ss = b[c];\n if (dist[a[c]] > dist[b[c]])\n ss = a[c];\n if (ss >= 1 && U[ss] == 0 && used.find(c) == used.end()) {\n Q1.push(make_pair(ss, c));\n while (!Q1.empty()) {\n int a1 = Q1.front().first, a2 = Q1.front().second;\n Q1.pop();\n if (U[a1] == 1 || used.find(a2) != used.end())\n continue;\n T[a1]--;\n used.insert(a2);\n if (T[a1] != 0)\n continue;\n cnt++;\n U[a1] = 1;\n for (pair<int, int>& j : y[a1]) {\n if (U[j.first] == 0)\n Q1.push(j);\n }\n }\n }\n printf(\"%d\\n\", cnt);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 36080, "score_of_the_acc": -1.033, "final_rank": 17 }, { "submission_id": "aoj_0627_8861009", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint n, m, q, a[210000], b[210000], c, dist[110000], T[110000], cnt, U[110000];\nvector<pair<int, int>> x[110000], y[110000];\nbool used[210000];\nint main() {\n scanf(\"%d%d%d\", &n, &m, &q);\n for (int i = 0; i < m; i++) {\n scanf(\"%d%d\", &a[i], &b[i]);\n x[a[i]].push_back(make_pair(b[i], i));\n x[b[i]].push_back(make_pair(a[i], i));\n }\n fill(dist, dist + n + 1, 999999);\n dist[1] = 0;\n deque<int> Q; // Use deque instead of queue\n Q.push_back(1); // Use push_back instead of push\n while (!Q.empty()) {\n int a1 = Q.front();\n Q.pop_front(); // Use pop_front instead of pop\n for (auto& i : x[a1]) { // Use range-based for loop\n if (dist[i.first] > dist[a1] + 1) {\n dist[i.first] = dist[a1] + 1;\n Q.push_back(i.first);\n }\n }\n }\n for (int i = 1; i <= n; i++) {\n for (auto& j : x[i]) { // Use range-based for loop\n if (dist[i] < dist[j.first]) {\n y[i].push_back(j);\n T[j.first]++;\n }\n }\n }\n for (int i = 0; i < q; i++) {\n scanf(\"%d\", &c);\n c--;\n deque<pair<int, int>> Q1; // Use deque instead of queue\n int ss = -1;\n if (dist[a[c]] < dist[b[c]])\n ss = b[c];\n if (dist[a[c]] > dist[b[c]])\n ss = a[c];\n if (ss >= 1 && U[ss] == 0 && used[c] == false) {\n Q1.push_back(make_pair(ss, c)); // Use push_back instead of push\n while (!Q1.empty()) {\n int a1 = Q1.front().first, a2 = Q1.front().second;\n Q1.pop_front(); // Use pop_front instead of pop\n if (U[a1] == 1 || used[a2] == true)\n continue;\n T[a1]--;\n used[a2] = true;\n if (T[a1] != 0)\n continue;\n cnt++;\n U[a1] = 1;\n for (auto& j : y[a1]) { // Use range-based for loop\n if (U[j.first] == 0)\n Q1.push_back(j);\n }\n }\n }\n cout << cnt << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 20472, "score_of_the_acc": -0.4082, "final_rank": 12 }, { "submission_id": "aoj_0627_8836045", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <cstring>\nusing namespace std;\n\nconst int MAX_N = 110000;\nconst int MAX_M = 210000;\n\nint n, m, q, c, cnt;\nint a[MAX_M], b[MAX_M], dist[MAX_N], T[MAX_N], U[MAX_N];\nvector<pair<int, int>> x[MAX_N], y[MAX_N];\nvector<bool> used(MAX_M, false);\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n\n scanf(\"%d%d%d\", &n, &m, &q);\n\n for (int i = 0; i < m; i++) {\n scanf(\"%d%d\", &a[i], &b[i]);\n x[a[i]].emplace_back(b[i], i);\n x[b[i]].emplace_back(a[i], i);\n }\n\n memset(dist, 127, sizeof(dist));\n dist[1] = 0;\n\n vector<int> Q(1, 1);\n\n for (int i = 0; i < Q.size(); i++) {\n int a1 = Q[i];\n for (pair<int, int> j : x[a1]) {\n if (dist[j.first] > dist[a1] + 1) {\n dist[j.first] = dist[a1] + 1;\n Q.push_back(j.first);\n }\n }\n }\n\n for (int i = 1; i <= n; i++) {\n for (pair<int, int> j : x[i]) {\n if (dist[i] < dist[j.first]) {\n y[i].push_back(j);\n T[j.first]++;\n }\n }\n }\n\n for (int i = 0; i < q; i++) {\n scanf(\"%d\", &c);\n c--;\n vector<pair<int, int>> Q1;\n int ss = -1;\n if (dist[a[c]] < dist[b[c]])\n ss = b[c];\n if (dist[a[c]] > dist[b[c]])\n ss = a[c];\n if (ss >= 1 && U[ss] == 0 && used[c] == false) {\n Q1.emplace_back(ss, c);\n while (!Q1.empty()) {\n int a1 = Q1.back().first, a2 = Q1.back().second;\n Q1.pop_back();\n if (U[a1] == 1 || used[a2] == true)\n continue;\n T[a1]--;\n used[a2] = true;\n if (T[a1] != 0)\n continue;\n cnt++;\n U[a1] = 1;\n for (pair<int, int> j : y[a1]) {\n if (U[j.first] == 0)\n Q1.emplace_back(j);\n }\n }\n }\n printf(\"%d\\n\", cnt);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 20436, "score_of_the_acc": -0.4031, "final_rank": 10 }, { "submission_id": "aoj_0627_8836029", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < n; i++)\nusing namespace std;\n\nvoid reader(int *x) {\n int k = getchar_unlocked();\n *x = k - '0';\n while (1) {\n k = getchar_unlocked();\n if (k < '0' || k > '9')\n break;\n *x = ((*x) << 1) + ((*x) << 3) + k - '0';\n }\n}\n\nconst int MAX_N = 100000;\nconst int MAX_M = 200000;\nconst int MAX_Q = 200000;\n\nvector<int> E[MAX_N];\nint u[MAX_M], v[MAX_M], r[MAX_Q], ans[MAX_Q], d[MAX_N], cnt = 1;\nbool b[MAX_M], ok[MAX_N];\nqueue<int> que;\n\nvoid bfs(int u, int t) {\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : E[p]) {\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = 1;\n cnt++;\n que.push(v);\n }\n } else if (!~d[v]) {\n d[v] = d[p] + 1;\n que.push(v);\n }\n }\n }\n}\n\nint main() {\n int n, m, q;\n reader(&n);\n reader(&m);\n reader(&q);\n\n rep(i, m) {\n reader(&u[i]);\n reader(&v[i]);\n u[i]--;\n v[i]--;\n E[u[i]].push_back(v[i]);\n E[v[i]].push_back(u[i]);\n }\n\n memset(d, -1, sizeof(d));\n d[0] = 0;\n bfs(0, 0);\n\n rep(i, m) {\n if (d[u[i]] > d[v[i]])\n swap(u[i], v[i]);\n }\n\n rep(i, n) E[i].clear();\n\n rep(i, q) {\n reader(&r[i]);\n r[i]--;\n b[r[i]] = true;\n }\n\n ok[0] = true;\n\n rep(i, m) {\n if (!b[i]) {\n if (d[v[i]] - d[u[i]] == 1) {\n E[u[i]].emplace_back(v[i]);\n }\n }\n }\n\n bfs(0, 1);\n\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n if (d[v[r[i]]] - d[u[r[i]]] == 1 && !ok[v[r[i]]]) {\n E[u[r[i]]].emplace_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1);\n }\n }\n }\n\n rep(i, q) printf(\"%d\\n\", ans[i]);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 13924, "score_of_the_acc": -0.1339, "final_rank": 2 }, { "submission_id": "aoj_0627_8836022", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <bitset>\n#include <algorithm>\n\nusing namespace std;\n\nconst int MAX_N = 100000;\nconst int MAX_M = 200000;\n\nint n, m, q;\nvector<int> adj[MAX_N];\nint u[MAX_M], v[MAX_M], r[MAX_M], ans[MAX_M], d[MAX_N], cnt = 1;\nbitset<MAX_N> b, ok;\n\nvoid bfs(int u, int t) {\n queue<int> que;\n que.push(u);\n while (!que.empty()) {\n int p = que.front();\n que.pop();\n for (int v : adj[p]) {\n if (t) {\n if (d[v] > d[p] && !ok[v]) {\n ok[v] = true;\n cnt++;\n que.push(v);\n }\n } else if (d[v] == -1) {\n d[v] = d[p] + 1;\n que.push(v);\n }\n }\n }\n}\n\nint main() {\n cin >> n >> m >> q;\n for (int i = 0; i < m; i++) {\n cin >> u[i] >> v[i];\n u[i]--;\n v[i]--;\n adj[u[i]].push_back(v[i]);\n adj[v[i]].push_back(u[i]);\n }\n\n fill(d, d + n, -1);\n d[0] = 0;\n bfs(0, 0);\n\n for (int i = 0; i < m; i++) {\n if (d[u[i]] > d[v[i]])\n swap(u[i], v[i]);\n }\n\n for (int i = 0; i < n; i++) {\n adj[i].clear();\n }\n\n for (int i = 0; i < q; i++) {\n cin >> r[i];\n r[i]--;\n b[r[i]] = true;\n }\n\n ok[0] = true;\n for (int i = 0; i < m; i++) {\n if (!b[i]) {\n if (d[v[i]] - d[u[i]] == 1) {\n adj[u[i]].push_back(v[i]);\n }\n }\n }\n\n bfs(0, 1);\n\n for (int i = q - 1; i >= 0; i--) {\n ans[i] = n - cnt;\n if (d[v[r[i]]] - d[u[r[i]]] == 1 && !ok[v[r[i]]]) {\n adj[u[r[i]]].push_back(v[r[i]]);\n if (ok[u[r[i]]]) {\n cnt++;\n ok[v[r[i]]] = true;\n bfs(v[r[i]], 1);\n }\n }\n }\n\n for (int i = 0; i < q; i++) {\n cout << ans[i] << endl;\n }\n\n return 0;\n}", "accuracy": 0.14814814814814814, "time_ms": 80, "memory_kb": 11956, "score_of_the_acc": -0.0752, "final_rank": 19 } ]
aoj_0628_cpp
縄張り(Territory) あなたは南北方向にとても長く伸びたたくさんの道路と,東西方向にとても長く伸びたたくさんの道路が交わった形をした街に住んでいる.隣り合う2 つの南北方向の道路の間隔は 1 km である.また,隣り合う 2 つの東西方向の道路の間隔も 1 km である. この街には市役所が 1 つある.市役所のある交差点を $(0,0)$ と表す.この街の交差点は 2 つの整数 $i, j$ を用いて交差点 $(i, j)$ と表される.すなわち,交差点 $(i, j)$ とは,交差点 $(0,0)$ から東に $i$ km ($i < 0$ のときは西に $-i$ km),北に $j$ km ( $j < 0$ のときは南に $-j$ km) 進んだ位置の交差点を表す. 市役所ではジョイ君という名の 1 匹の犬を飼っている.ジョイ君は $K$ 日間の散歩の計画を立てた.散歩の計画は以下の通りである. $K$ 日のうち最初の日の朝にはジョイ君は交差点 $(0,0)$ にいる.ジョイ君は交差点 $(0,0)$ に印を付ける.$(0,0)$ 以外にはジョイ君が印を付けた交差点はない. $K$ 日のそれぞれの日の昼に散歩を行う.1 日の散歩は $N$ 回のステップからなる.各ステップでは交差点から隣の交差点へと移動し,移動先に印を付ける.ジョイ君がそれぞれの日の昼にどう移動するかは日によらず一定である. 昼の移動が終わった後は,現在いる交差点で次の日の朝まで寝る. 市役所では $K$ 日間の散歩によってできるジョイ君の縄張りについて話題になっている.4 つの交差点 $(a,b),(a + 1,b),(a + 1,b + 1),(a,b + 1)$ のいずれにもジョイ君が 1 回以上印を付けているとき,4 つの交差点で囲まれた区画はジョイ君の縄張りに属する. あなたは,ジョイ君の散歩計画から,ジョイ君の縄張りに属する区画の個数を計算するプログラムを作成することとなった. この街の道路はとても長く,また,南北方向にも東西方向にも十分たくさんの道路があるため,散歩の途中でジョイ君が道路の端や街の端に到達することはない. 課題 ジョイ君の散歩計画が与えられると,ジョイ君の縄張りに属する区画の個数を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には 2 個の整数 $N, K$ が空白を区切りとして書かれている.これはそれぞれの日の散歩が $N$ 回のステップからなり,散歩計画が $K$ 日間に渡ることを表している. 2 行目には長さ $N$ の文字列 $S$ が書かれている.文字列 $S$ のうち左から $p$ 文字目 $(1 \leq p \leq N)$ の文字 $C_p$ は E,N,W,S のいずれかである.これらの文字は以下のことを表す. 文字 $C_p$ が E であるならば,$p$ 番目のステップで東隣の交差点に移動することを表す. 文字 $C_p$ が N であるならば,$p$ 番目のステップで北隣の交差点に移動することを表す. 文字 $C_p$ が W であるならば,$p$ 番目のステップで西隣の交差点に移動することを表す. 文字 $C_p$ が S であるならば,$p$ 番目のステップで南隣の交差点に移動することを表す. ここで,交差点$(i, j)$ に対して東隣,北隣,西隣,南隣の交差点はそれぞれ,交差点 $(i + 1, j)$,交差点$(i, j + 1)$,交差点$(i - 1, j)$,交差点$(i, j - 1)$ である. 出力 標準出力に,ジョイ君の縄張りに属する区画の個数を 1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. $1 \leq N \leq 100 000$ $1 \leq K \leq 1 000 000 000$ 入出力例 入力例1 12 1 EENWSEEESWWS 出力例1 3 この入力例では,散歩は 1 日間で行われる.1 日目にジョイ君は市役所から出発して下図のように移動する.黒丸はジョイ君が印を付けた交差点,白丸はジョイ君が印を付けていない交差点,二重丸は市役所のある交差点,数字は各ステップを表す. ジョイ君の移動経路 入力例 1 において,下図の斜線部分で示された 3 個の区画がジョイ君の縄張りに属する. 入力例1 におけるジョイ君の縄張り 入力例2 12 2 EENWSEEESWWS 出力例2 7 入力例 2 では,散歩が 2 日間に渡り行われる.それぞれの日の移動経路は入力例 1 と同一である.散歩が完了したとき,下図の斜線部分で示された 7 個の区画がジョイ君の縄張りに属する. 入力例2 におけるジョイ君の縄張り 入力例3 7 1 ENNWNNE 出力例3 0 入力例 3 では,ジョイ君の縄張りに属する区画は存在しない. 入力例4 16 5 WSESSSWWWEEENNNW 出力例4 21 第15回 日本情報オリンピック本選 課題   2016 年 2 月 14 日
[ { "submission_id": "aoj_0628_9477484", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, ll> Pi;\ntypedef pair<Pi, Pi> PPi;\ntypedef pair<ll, Pi> Ti;\nconst ll LLINF = 1LL << 60;\nconst int INF = (1 << 30) - 1;\n\nchar ch[] = \"NESW\";\nll dy[] = {-1, 0, 1, 0};\nll dx[] = {0, 1, 0, -1};\n\nll llabs(ll n) { return (n < 0 ? -n : n); }\n\nll N, K;\nstring S;\nPi route[200005];\nll vecy = 0, vecx = 0;\nvector<PPi> data;\nll ans = 0;\nll sum[4][200005];\n\nint main() {\n cin >> N >> K >> S;\n for (int i = 0; i < N; i++) {\n int j = 0;\n while (S[i] != ch[j]) j++;\n vecy += dy[j], vecx += dx[j];\n route[i + 1] = Pi(vecy, vecx);\n }\n route[0] = Pi(INF, 2 * N);\n\n // ルートの正規化\n for (int i = 1; i <= N; i++) {\n if (vecy < 0) route[i].first = -route[i].first;\n if (vecx < 0) route[i].second = -route[i].second;\n if (vecx == 0) swap(route[i].first, route[i].second);\n route[i].first += INF, route[i].second += N * 2;\n }\n vecy = llabs(vecy);\n vecx = llabs(vecx);\n if (vecx == 0) vecx = vecy, vecy = 0;\n sort(route, route + N + 1);\n\n if (vecx == 0) {\n for (int i = 0; i <= N;) {\n ll y = route[i].first, x = route[i].second;\n Pi *a = route, *b = route + N + 1;\n if (binary_search(a, b, Pi(y + 1, x)) && binary_search(a, b, Pi(y, x + 1)) && binary_search(a, b, Pi(y + 1, x + 1))) \n ans++;\n while (i <= N && route[i].first == y && route[i].second == x) \n i++;\n }\n cout << ans << endl;\n return 0;\n }\n\n // データの準備\n for (int i = 0; i <= N; i++) {\n ll y = route[i].first, x = route[i].second;\n data.push_back(PPi(Pi(y - x / vecx * vecy, x % vecx), Pi(x / vecx, x / vecx + K)));\n }\n sort(data.begin(), data.end());\n data.erase(unique(data.begin(), data.end()), data.end());\n\n for (int i = 0; i < data.size();) {\n vector<ll> comp;\n vector<Ti> d;\n map<ll, ll> conv;\n \n ll now[4] = {};\n\n ll r, u, ru;\n ll iy = data[i].first.first, ix = data[i].first.second;\n ll plus = (ix + 1) / vecx;\n Pi pp[4] = {data[i].first, Pi(iy - plus * vecy, (ix + 1) % vecx), Pi(iy + 1, ix), Pi(iy + 1 - plus * vecy, (ix + 1) % vecx)};\n Pi nop = Pi(-LLINF, -LLINF);\n ll pos[4];\n pos[0] = i;\n for (int j = 1; j < 4; j++) pos[j] = lower_bound(data.begin(), data.end(), PPi(pp[j], nop)) - data.begin();\n for (int j = 0; j < 4; j++) {\n while (pos[j] < data.size() && data[pos[j]].first == pp[j]) {\n ll s = data[pos[j]].second.first - plus * (j % 2), t = data[pos[j]].second.second - plus * (j % 2);\n comp.push_back(s);\n comp.push_back(t);\n d.push_back(Ti(1, Pi(j, s)));\n d.push_back(Ti(-1, Pi(j, t)));\n pos[j]++;\n }\n }\n sort(comp.begin(), comp.end());\n comp.erase(unique(comp.begin(), comp.end()), comp.end());\n for (int j = 0; j < comp.size(); j++) conv[comp[j]] = j;\n for (int p = 0; p < 4; p++) \n for (int j = 0; j < comp.size(); j++) \n sum[p][j] = 0;\n for (int j = 0; j < d.size(); j++) \n sum[d[j].second.first][conv[d[j].second.second]] += d[j].first;\n for (int j = 0; j < comp.size() - 1; j++) {\n bool flag = true;\n for (int k = 0; k < 4; k++) {\n now[k] += sum[k][j];\n if (now[k] <= 0) flag = false;\n }\n if (flag) ans += comp[j + 1] - comp[j];\n }\n i = pos[0];\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 33196, "score_of_the_acc": -0.3276, "final_rank": 6 }, { "submission_id": "aoj_0628_8784967", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\nusing P = pair<int, int>;\ntypedef struct { ll key; int x, y, v; } T;\n\n// 構造体の高速昇順ソート。ソート対象は key\nvoid usort(T a[], int n) { // 配列と長さ\n#define K 8\n#define B 8\n#define BMSK 255 // (1<<8)-1\n int i, k;\n int t1[1 << B], t2[1 << B];\n T *tmp = (T *)malloc(n * sizeof(T));\n for (k = 0; k < K; ++k) {\n memset(t1, 0, sizeof(t1)), memset(t2, 0, sizeof(t2));\n for (i = 0; i < n; ++i)\tt1[(a[i].key >> k*B) & BMSK]++;\n for (i = 0; i < BMSK; ++i) t1[i+1] += t1[i];\n i = n; while (i--) tmp[--t1[(a[i].key >> k*B) & BMSK]] = a[i];\n k++;\n for (i = 0; i < n; ++i) t2[(tmp[i].key >> k*B) & BMSK]++;\n for (i = 0; i < BMSK; ++i) t2[i+1] += t2[i];\n i = n; while (i--) a[--t2[(tmp[i].key >> k*B) & BMSK]] = tmp[i];\n }\n free(tmp);\n return;\n#undef K\n#undef B\n for (i = 0; i < n; ++i) printf(\"[%d] %lld\\n\", i, a[i].key);\n}\n\nT tbl[4*100005]; int sz;\nint N, K;\nchar S[100005];\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y) {\n for (int i = 0; i < 2; ++i) for (int j = 0; j < 2; ++j) {\n tbl[sz++] = (T){((ll)(x+i) << 32) | (y+j), x+i, y+j, 1<<((i<<1)+j)};\n }\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x0 = 100000, x = x0, y0 = 100000, y = y0;\n setup(x, y);\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n setup(x, y);\n }\n if (x == x0+N || x == x0-N || y == y0+N || y == y0-N) { puts(\"0\"); return 0; }\n\n usort(tbl, sz);\n tbl[sz].key = -1;\n j = 0; for (i = 1; i < sz; ++i) {\n while (tbl[i].key == tbl[j].key) tbl[j].v |= tbl[i++].v;\n if (i < sz && ++j != i) tbl[j] = tbl[i];\n }\n sz = j+1;\n\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = tbl[i].x, l = tbl[i].y, v = tbl[i].v;\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) { ok = 0; break; }\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 34796, "score_of_the_acc": -0.1653, "final_rank": 2 }, { "submission_id": "aoj_0628_8784961", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\nusing P = pair<int, int>;\ntypedef struct { ll key; int x, y, v; } T;\n\n// 構造体の高速昇順ソート。ソート対象は key\nvoid usort(T a[], int n) { // 配列と長さ\n#define K 8\n#define B 8\n#define BMSK 255 // (1<<8)-1\n int i, k;\n int t1[1 << B], t2[1 << B];\n T *tmp = (T *)malloc(n * sizeof(T));\n for (k = 0; k < K; ++k) {\n memset(t1, 0, sizeof(t1)), memset(t2, 0, sizeof(t2));\n for (i = 0; i < n; ++i)\tt1[(a[i].key >> k*B) & BMSK]++;\n for (i = 0; i < BMSK; ++i) t1[i+1] += t1[i];\n i = n; while (i--) tmp[--t1[(a[i].key >> k*B) & BMSK]] = a[i];\n k++;\n for (i = 0; i < n; ++i) t2[(tmp[i].key >> k*B) & BMSK]++;\n for (i = 0; i < BMSK; ++i) t2[i+1] += t2[i];\n i = n; while (i--) a[--t2[(tmp[i].key >> k*B) & BMSK]] = tmp[i];\n }\n free(tmp);\n return;\n#undef K\n#undef B\n for (i = 0; i < n; ++i) printf(\"[%d] %lld\\n\", i, a[i].key);\n}\n\nT tbl[4*100005]; int sz;\nint N, K;\nchar S[100005];\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y) {\n for (int i = 0; i < 2; ++i) for (int j = 0; j < 2; ++j) {\n tbl[sz++] = (T){((ll)(x+i) << 32) | (y+j), x+i, y+j, 1<<((i<<1)+j)};\n }\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n setup(x, y);\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n setup(x, y);\n }\n usort(tbl, sz);\n tbl[sz].key = -1;\n j = 0; for (i = 1; i < sz; ++i) {\n while (tbl[i].key == tbl[j].key) tbl[j].v |= tbl[i++].v;\n if (i < sz && ++j != i) tbl[j] = tbl[i];\n }\n sz = j+1;\n\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = tbl[i].x, l = tbl[i].y, v = tbl[i].v;\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) { ok = 0; break; }\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 34840, "score_of_the_acc": -0.2, "final_rank": 3 }, { "submission_id": "aoj_0628_8781360", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\n#define HASHSIZ 9999991\ntypedef struct { ll a; int id; } HASH;\nHASH Hash[HASHSIZ+5];\nHASH *hashend = Hash+HASHSIZ;\n\nvoid insert(ll a, int id) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return;\n if (++p == hashend) p = Hash;\n }\n p->a = a, p->id = id;\n}\n\nint lookup(ll a) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return p->id;\n if (++p == hashend) p = Hash;\n }\n return -1;\n}\n\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nint idx[210000], idy[210000], val[210000], sz;\nint tbl[16] = {0,1,1,2,1,2,2,3,1,2,2,3,2,3,3,4};\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y, int v) {\n ll a = ((ll)x << 19) | y;\n int i = lookup(a);\n if (i < 0) i = sz++, idx[i] = x, idy[i] = y, insert(a, i);\n val[i] |= v;\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n }\n//printf(\"sz=%d\\n\", sz);\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = idx[i], l = idy[i], v = val[i];\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) { ok = 0; break; }\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 178520, "score_of_the_acc": -1.069, "final_rank": 17 }, { "submission_id": "aoj_0628_8781083", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\n#define HASHSIZ 8999993 // 4000081 // 2000081\ntypedef struct { ll a; int id; } HASH;\nHASH Hash[HASHSIZ+5];\nHASH *hashend = Hash+HASHSIZ;\n\nvoid insert(ll a, int id) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return;\n if (++p == hashend) p = Hash;\n }\n p->a = a, p->id = id;\n}\n\nint lookup(ll a) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return p->id;\n if (++p == hashend) p = Hash;\n }\n return -1;\n}\n\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nint idx[210000], idy[210000], val[210000], sz;\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y, int v) {\n ll a = ((ll)x << 32) | y;\n int i = lookup(a);\n if (i < 0) i = sz++, idx[i] = x, idy[i] = y, insert(a, i);\n val[i] |= v;\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n }\n//printf(\"sz=%d\\n\", sz);\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = idx[i], l = idy[i], v = val[i];\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) ok = 0;\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 163596, "score_of_the_acc": -0.9751, "final_rank": 14 }, { "submission_id": "aoj_0628_8781048", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\n#define HASHSIZ 2000081\ntypedef struct { ll a; int id; } HASH;\nHASH Hash[HASHSIZ+5];\nHASH *hashend = Hash+HASHSIZ;\n\nvoid insert(ll a, int id) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return;\n if (++p == hashend) p = Hash;\n }\n p->a = a, p->id = id;\n}\n\nint lookup(ll a) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return p->id;\n if (++p == hashend) p = Hash;\n }\n return -1;\n}\n\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nint idx[210000], idy[210000], val[210000], sz;\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y, int v) {\n ll a = ((ll)x << 32) | y;\n int i = lookup(a);\n if (i < 0) i = sz++, idx[i] = x, idy[i] = y, insert(a, i);\n val[i] |= v;\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n }\n//printf(\"sz=%d\\n\", sz);\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = idx[i], l = idy[i], v = val[i];\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) ok = 0;\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 54552, "score_of_the_acc": -0.6688, "final_rank": 13 }, { "submission_id": "aoj_0628_8780974", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\n#define HASHSIZ 1000033 //2000081\ntypedef struct { ll a; int id; } HASH;\nHASH Hash[HASHSIZ+5];\nHASH *hashend = Hash+HASHSIZ;\n\nvoid insert(ll a, int id) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return;\n if (++p == hashend) p = Hash;\n }\n p->a = a, p->id = id;\n}\n\nint lookup(ll a) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return p->id;\n if (++p == hashend) p = Hash;\n }\n return -1;\n}\n\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nll id[300000]; int val[300000], sz;\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y, int v) {\n ll a = ((ll)x << 32) | y;\n int i = lookup(a);\n if (i < 0) i = sz++, id[i] = a, insert(a, i);\n val[i] |= v;\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n }\n//printf(\"sz=%d\\n\", sz);\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = (int)(id[i] >> 32), l = (int)(id[i] & 0x7ffffff), v = val[i];\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) ok = 0;\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 39496, "score_of_the_acc": -1.1259, "final_rank": 18 }, { "submission_id": "aoj_0628_8780897", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\n#define HASHSIZ 2000081\ntypedef struct { ll a; int v; } HASH;\nHASH Hash[HASHSIZ+5];\nHASH *hashend = Hash+HASHSIZ;\n\nvoid insert(ll a, int v) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) { p->v = v; return; }\n if (++p == hashend) p = Hash;\n }\n p->a = a, p->v = v;\n}\n\nint lookup(ll a) {\n HASH *p = Hash + (int)(a % HASHSIZ);\n while (p->a) {\n if (p->a == a) return p->v;\n if (++p == hashend) p = Hash;\n }\n return -1;\n}\n\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nll pool[300000]; int sz;\nmap <pair<int, int>, vector<P>> mp;\n\nvoid setup(int x, int y, int v) {\n ll a = ((ll)x << 32) | y;\n int val = lookup(a);\n if (val < 0) val = 0, pool[sz++] = a;\n insert(a, val | v);\n}\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) setup(x+i, y+j, 1<<((i<<1)+j));\n }\n\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (i = 0; i < sz; ++i) {\n int c, k = (int)(pool[i] >> 32), l = (int)(pool[i] & 0x7ffffff);\n int v = lookup(pool[i]);\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp[P{k,l}].push_back(P{c, v});\n mp[P{k,l}].push_back(P{c+K, -v});\n }\n\n ll ans = 0;\n for (auto &it: mp) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) ok = 0;\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 53672, "score_of_the_acc": -1.0081, "final_rank": 16 }, { "submission_id": "aoj_0628_8780478", "code_snippet": "// AOJ 628 Territory\n// 2024.1.18\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid ins(char *s) { // 文字列の入力 スペース以下の文字で入力終了\n do *s = gc();\n while (*s++ > ' ');\n *(s-1) = 0;\n}\n\ntypedef long long ll;\nusing P = pair<int, int>;\nint N, K;\nchar S[100005];\nmap <pair<int, int>, int> mp1;\nmap <pair<int, int>, vector<P>> mp2;\n\nint main() {\n int i, j, k;\n N = in(), K = in();\n ins(S);\n int x = 100000, y = 100000;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) mp1[P{x+i, y+j}] |= 1<<((i<<1)+j);\n for (k = 0; k < N; ++k) {\n if (S[k] == 'E') x++;\n else if (S[k] == 'N') y--;\n else if (S[k] == 'W') x--;\n else y++;\n for (i = 0; i < 2; ++i) for (j = 0; j < 2; ++j) mp1[P{x+i,y+j}] |= 1<<((i<<1)+j);\n }\n x -= 100000;\n y -= 100000;\n if (x == 0 && y == 0) K = 1;\n for (auto &it: mp1) {\n int l, c;\n tie(k,l) = it.first;\n if (x) c = k/x, l -= c*y, k %= x;\n else if (y) c = l/y, l %= y;\n else c = 0;\n mp2[P{k,l}].push_back(P{c, it.second});\n mp2[P{k,l}].push_back(P{c+K, -it.second});\n }\n ll ans = 0;\n for (auto &it: mp2) {\n sort(it.second.begin(), it.second.end());\n int u[4] = {0}, p = 0;\n for (auto &it2: it.second) {\n int ok = 1;\n for (i = 0; i < 4; ++i) if (u[i] == 0) ok = 0;\n if (ok) ans += it2.first - p;\n if (it2.second < 0) {\n for (i = 0; i < 4; ++i) u[i] -= ((-it2.second) >> i) & 1;\n } else {\n for (i = 0; i < 4; ++i) u[i] += (it2.second >> i) & 1;\n }\n p = it2.first;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 37964, "score_of_the_acc": -0.4266, "final_rank": 9 }, { "submission_id": "aoj_0628_5842414", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, n) for(int i = int(n) - 1; i >= int(l); i--)\n\nstruct range{\n lint l, r; // [l, r)\n};\n\nrange AND(range a, range b){\n lint l = max(a.l, b.l);\n lint r = min(a.r, b.r);\n if(l > r) r = l;\n return {l, r};\n}\n\nvector<range> OR(vector<range> a){\n int n = int(a.size());\n sort(a.begin(), a.end(), [](range s, range t){ return s.l < t.l; });\n \n vector<range> ret;\n if(a.empty()) return ret;\n \n lint l = a[0].l, r = a[0].r;\n rep2(i, 1, n){\n if(a[i].l <= r){\n r = max(r, a[i].r);\n }else{\n ret.push_back({l, r});\n l = a[i].l;\n r = a[i].r;\n }\n }\n ret.push_back({l, r});\n \n return ret;\n}\n\nvector<range> ANDs(vector<range> a, vector<range> b){\n if(a.empty() || b.empty()) return vector<range>(0);\n \n a = OR(a), b = OR(b);\n \n lint l_inf = -1e18, r_inf = 1e18;\n vector<range> nots;\n \n lint l = l_inf, r = -1;\n rep(i, a.size()){\n r = a[i].l;\n nots.push_back({l, r});\n l = a[i].r;\n }\n nots.push_back({l, r_inf});\n \n l = l_inf, r = -1;\n rep(i, b.size()){\n r = b[i].l;\n nots.push_back({l, r});\n l = b[i].r;\n }\n nots.push_back({l, r_inf});\n \n nots = OR(nots);\n \n vector<range> ret;\n rep(i, int(nots.size()) - 1){\n ret.push_back({nots[i].r, nots[i + 1].l});\n }\n return ret;\n}\n\nlint solve(map<pair<int, int>, vector<range>> pts){\n set<pair<int, int>> kouho;\n for(auto v: pts){\n auto p = v.first;\n rep(i, 2) rep(j, 2){\n kouho.insert(make_pair(p.first - i, p.second - j));\n }\n }\n \n lint ans = 0;\n for(auto p: kouho){\n vector<vector<range>> ranges;\n rep(i, 2) rep(j, 2){\n ranges.push_back(pts[{p.first + i, p.second + j}]);\n }\n \n vector<range> res = ranges[0];\n rep2(i, 1, 4){\n res = ANDs(res, ranges[i]);\n }\n \n for(auto r: res){\n ans += r.r - r.l;\n }\n }\n \n return ans;\n}\n\nint main(){\n int n;\n lint k;\n cin >> n >> k;\n lint x = 0, y = 0;\n vector<pair<lint, lint>> pos{make_pair(0, 0)};\n rep(i, n){\n char c;\n cin >> c;\n if(c == 'E') x++;\n if(c == 'N') y++;\n if(c == 'W') x--;\n if(c == 'S') y--;\n \n pos.push_back({x, y});\n }\n \n if(x == 0 && y == 0){\n map<pair<int, int>, vector<range>> pts;\n for(auto p: pos){\n pts[p].push_back({0, 1});\n }\n \n cout << solve(pts) << endl;\n return 0;\n }\n if(x == 0){\n swap(x, y);\n for(auto &p: pos){\n swap(p.first, p.second);\n }\n }\n if(x > 0){\n x *= -1;\n for(auto &p: pos){\n p.first *= -1;\n }\n }\n if(y > 0){\n y *= -1;\n for(auto &p: pos){\n p.second *= -1;\n }\n }\n \n map<pair<int, int>, vector<range>> pts;\n \n x = abs(x), y = abs(y);\n for(auto p: pos){\n lint to_x = (p.first + lint(1e9) * x) % x;\n \n lint move = (to_x - p.first) / x;\n p.first += move * x;\n p.second += move * y;\n \n pts[p].push_back({move, move + k});\n \n// cout << p.first << \" \" << p.second << \" \" << to_x << \" -> \" << move << endl;\n }\n \n for(auto v: pts){\n auto p = v.first;\n if(p.first > 0) continue;\n \n p.first += x;\n p.second += y;\n for(auto &r: v.second){\n r.l++;\n r.r++;\n }\n \n pts[p] = v.second;\n }\n \n cout << solve(pts) << endl;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 57752, "score_of_the_acc": -0.9993, "final_rank": 15 }, { "submission_id": "aoj_0628_3687145", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <typename T> using lim = numeric_limits<T>;\nstruct event {\n bool open;\n int t, dx, dy;\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, k;\n cin >> n >> k;\n string s;\n cin >> s;\n int a = 0, b = 0;\n set<pair<int, int>> visited({{0, 0}});\n for(int i = 0; i < n; i++) {\n a += (s[i] == 'E') - (s[i] == 'W');\n b += (s[i] == 'N') - (s[i] == 'S');\n visited.insert({a, b});\n }\n if(a == 0 and b == 0) {\n int ans = 0;\n for(auto& p : visited) {\n ans += visited.count({p.first + 1, p.second})\n and visited.count({p.first, p.second + 1})\n and visited.count({p.first + 1, p.second + 1});\n }\n cout << ans << endl;\n } else {\n auto flip_all = [](string& s, char a, char b) {\n for(char& c : s) {\n if(c == a) {\n c = b;\n } else if(c == b) {\n c = a;\n }\n }\n };\n if(a < 0) flip_all(s, 'E', 'W');\n if(b < 0) flip_all(s, 'N', 'S');\n a = abs(a), b = abs(b);\n vector<pair<int, int>> pts = {{0, 0}};\n for(int i = 0; i < n - 1; i++) {\n pts.push_back({\n pts.back().first + (s[i] == 'E') - (s[i] == 'W'),\n pts.back().second + (s[i] == 'N') - (s[i] == 'S')\n });\n }\n map<pair<int, int>, vector<pair<int, int>>> rays;\n for(auto& p : pts) {\n int L = a ? p.first / a - (p.first % a < 0): p.second / b, R = L + k - (p.first or p.second);\n int x = a ? (p.first % a + a) % a: p.first, y = p.second - L * b;\n rays[{x, y}].push_back({L, R});\n }\n ll ans = 0;\n for(auto& r : rays) {\n int x, y; tie(x, y) = r.first;\n vector<event> events;\n for(int dx = 0; dx <= 1; dx++) {\n for(int dy = 0; dy <= 1; dy++) {\n int dL = a ? (x + dx) / a : (y + dy) / b;\n int nx = a ? (x + dx) % a : (x + dx);\n int ny = (y + dy) - dL * b;\n if(rays.count({nx, ny})) {\n for(auto& p : rays[{nx, ny}]) {\n int L, R; tie(L, R) = p;\n events.push_back({true, L - dL, dx, dy});\n events.push_back({false, R - dL, dx, dy});\n }\n } else if(dx == a and dy == b) {\n for(auto& p : rays[{x, y}]) {\n int L, R; tie(L, R) = p;\n events.push_back({true, L, dx, dy});\n events.push_back({false, R, dx, dy});\n }\n }\n }\n }\n sort(events.begin(), events.end(), [](auto& e1, auto& e2) {\n return e1.t < e2.t or (e1.t == e2.t and e1.open and not e2.open);\n });\n map<pair<int, int>, int> active_rays;\n bool all_active = false;\n int all_active_time = 0;\n for(auto& e : events) {\n if(e.open) {\n active_rays[{e.dx, e.dy}]++;\n if(active_rays.size() == 4 and not all_active) {\n all_active = true;\n all_active_time = e.t;\n }\n } else {\n if(--active_rays[{e.dx, e.dy}] == 0) {\n if(active_rays.size() == 4 and all_active) {\n all_active = false;\n ans += e.t - all_active_time + 1;\n }\n active_rays.erase({e.dx, e.dy});\n }\n }\n }\n }\n cout << ans << endl;\n }\n return 0;\n}", "accuracy": 0.54, "time_ms": 120, "memory_kb": 19480, "score_of_the_acc": -0.2069, "final_rank": 20 }, { "submission_id": "aoj_0628_3112634", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<unordered_map>\n#define mp make_pair \n#define pb push_back\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\ntypedef pair<ll,ll> P;\nstruct Ver{\n ll x,y;\n bool operator==(const Ver&key)const{\n\treturn key.x==this->x&&key.y==this->y;\n }\n bool operator!=(const Ver&key)const{\n\treturn !(this->operator==(key));\n }\n struct Hash{\n\tll operator()(const Ver&key)const{\n\t return key.x*mod+key.y;\n\t}\n };\n Ver(ll x,ll y){this->x=x,this->y=y;}\n};\nunordered_map<Ver,vector<P>,Ver::Hash> mas,rng;\n#define N 200010\nll n,k,x[N],y[N];\n\nint main(){\n cin>>n>>k;\n string s;cin>>s;\n ll a=0,b=0;\n lol(i,n){\n\tx[i]=a,y[i]=b;\n\tint dx[]={1,0,-1,0},dy[]={0,-1,0,1};\n\tchar z[]={'E','N','W','S'};\n\tlol(r,4)if(z[r]==s[i])a+=dx[r],b+=dy[r];\n }\n if(a==0&&b==0)k=1,a=b=1;\n if(a<0){lol(i,n)x[i]=-x[i];a=-a;}\n if(b<0){lol(i,n)y[i]=-y[i];b=-b;}\n if(a==0&&b>0){\n\tswap(a,b);\n\tlol(i,n)swap(x[i],y[i]);\n }\n lol(i,n){\n\tx[i]+=N,y[i]+=N;\n\tll dis=x[i]/a;\n\tll wid=k-1+(i==0);\n\tmas[Ver(x[i]%a,y[i]-dis*b)].pb(mp(dis,dis+wid));\n }\n for(auto it:mas){\n\tauto ver=it.first;\n\tauto vec=it.second;\n\tvector<P> qry;\n\tfor(auto i:vec){\n\t qry.pb(mp(i.first,+1));\n\t qry.pb(mp(i.second+1,-1));\n\t}\n\tsort(qry.begin(),qry.end());\n\tll cms=0,left;\n\tfor(auto i:qry){\n\t ll tim=i.first,dir=i.second;\n\t if(dir==-1){\n\t\tcms--;\n\t\tif(cms==0)rng[ver].pb(mp(left,tim-1));\n\t }\n\t if(dir==+1){\n\t\tif(cms==0)left=tim;\n\t\tcms++;\n\t }\n\t}\n }\n ll ans=0;\n for(auto it:rng){\n\tauto ver=it.first;\n\tvector<P> qry;\n\tll dx[]={0,1,0,1},dy[]={0,0,1,1};\n\tlol(r,4){\n\t ll xx=ver.x+dx[r];\n\t ll yy=ver.y+dy[r];\n\t bool over=0;\n\t if(xx==a)xx-=a,yy-=b,over=1;\n\t if(rng.find(Ver(xx,yy))==rng.end())continue;\n\t for(auto i:rng[Ver(xx,yy)]){\n\t\tqry.pb(mp(i.first-over,+1));\n\t\tqry.pb(mp(i.second-over+1,-1));\n\t }\n\t}\n\tsort(qry.begin(),qry.end());\n\tll cms=0,left;\n\tfor(auto i:qry){\n\t ll tim=i.first,dir=i.second;\n\t if(dir==-1){\n\t\tif(cms==4)ans+=tim-left;\n\t\tcms--;\n\t }\n\t if(dir==+1){\n\t\tcms++;\n\t\tif(cms==4)left=tim;\n\t }\n\t}\n }\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 25184, "score_of_the_acc": -0.0359, "final_rank": 1 }, { "submission_id": "aoj_0628_2693898", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair < ll , ll > Pi;\ntypedef pair < Pi , Pi > PPi;\ntypedef pair < ll , Pi > Ti;\nconst ll LLINF = 1LL << 60;\nconst int INF = (1 << 30) - 1;\n\nchar ch[] = \"NESW\";\nll dy[] = {-1, 0, 1, 0};\nll dx[] = {0, 1, 0, -1};\n\nll llabs(ll n) { return (n < 0 ? -n : n); }\n\nll N, K;\nstring S;\nPi route[200005];\nll vecy = 0, vecx = 0;\nvector < PPi > data;\nll ans = 0;\nll sum[4][200005];\nint main()\n{\n cin >> N >> K >> S;\n for(int i = 0; i < N; i++) {\n int j = 0;\n while(S[i] != ch[j]) j++;\n vecy += dy[j], vecx += dx[j];\n route[i + 1] = Pi(vecy, vecx);\n }\n route[0] = Pi(INF, 2 * N);\n for(int i = 1; i <= N; i++) {\n if(vecy < 0) route[i].first = -route[i].first;\n if(vecx < 0) route[i].second = -route[i].second;\n if(vecx == 0) swap(route[i].first, route[i].second);\n route[i].first += INF, route[i].second += N * 2;\n }\n vecy = llabs(vecy); vecx = llabs(vecx);\n if(vecx == 0) vecx = vecy, vecy = 0;\n sort(route, route + N + 1);\n if(vecx == 0) {\n for(int i = 0; i <= N;) {\n ll y = route[i].first, x = route[i].second;\n Pi *a = route, *b = route + N + 1;\n if(binary_search(a, b, Pi(y + 1, x)) && binary_search(a, b, Pi(y, x + 1)) && binary_search(a, b, Pi(y + 1, x + 1))) ans++;\n while(i <= N && route[i].first == y && route[i].second == x) i++;\n }\n cout << ans << endl;\n return (0);\n }\n for(int i = 0; i <= N; i++) {\n ll y = route[i].first, x = route[i].second;\n data.push_back(PPi(Pi(y - x / vecx * vecy, x % vecx), Pi(x / vecx, x / vecx + K)));\n }\n sort(data.begin(), data.end());\n data.erase(unique(data.begin(), data.end()), data.end());\n for(int i = 0; i < data.size();) {\n vector < ll > comp;\n vector < Ti > d;\n map < ll, ll > conv;\n \n ll now[4] = {};\n\n ll r, u, ru;\n ll iy = data[i].first.first, ix = data[i].first.second;\n ll plus = (ix + 1) / vecx;\n Pi pp[4] = {data[i].first, Pi(iy - plus * vecy, (ix + 1) % vecx), Pi(iy + 1, ix), Pi(iy + 1 - plus * vecy, (ix + 1) % vecx)};\n Pi nop = Pi(-LLINF, -LLINF);\n ll pos[4];\n pos[0] = i;\n for(int j = 1; j < 4; j++) pos[j] = lower_bound(data.begin(), data.end(), PPi(pp[j], nop)) - data.begin();\n for(int j = 0; j < 4; j++) {\n while(pos[j] < data.size() && data[pos[j]].first == pp[j]) {\n ll s = data[pos[j]].second.first - plus * (j % 2) , t = data[pos[j]].second.second - plus * (j % 2);\n comp.push_back(s); comp.push_back(t);\n d.push_back(Ti(1, Pi(j, s)));\n d.push_back(Ti(-1, Pi(j, t)));\n pos[j]++;\n }\n }\n sort(comp.begin(), comp.end());\n comp.erase(unique(comp.begin(), comp.end()), comp.end());\n for(int j = 0; j < comp.size(); j++) conv[comp[j]] = j;\n for(int p = 0; p < 4; p++) for(int j = 0; j < comp.size(); j++) sum[p][j] = 0;\n for(int j = 0; j < d.size(); j++) sum[d[j].second.first][conv[d[j].second.second]] += d[j].first;\n for(int j = 0; j < comp.size() - 1; j++) {\n bool flag = true;\n for(int k = 0; k < 4; k++) {\n now[k] += sum[k][j];\n if(now[k] <= 0) flag = false;\n }\n if(flag) ans += comp[j + 1] - comp[j];\n }\n i = pos[0];\n }\n cout << ans << endl;\n return (0);\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 25312, "score_of_the_acc": -0.3125, "final_rank": 5 }, { "submission_id": "aoj_0628_2693895", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair < ll , ll > Pi;\ntypedef pair < Pi , Pi > PPi;\ntypedef pair < ll , Pi > Ti;\nconst ll LLINF = 1LL << 60;\nconst int INF = (1 << 30) - 1;\n\nchar ch[] = \"NESW\";\nll dy[] = {-1, 0, 1, 0};\nll dx[] = {0, 1, 0, -1};\n\nll llabs(ll n) { return (n < 0 ? -n : n); }\n\nll N, K;\nstring S;\nPi route[200005];\nll vecy = 0, vecx = 0;\nvector < PPi > data;\nll ans = 0;\nll sum[4][200005];\nint main()\n{\n cin >> N >> K >> S;\n for(int i = 0; i < N; i++) {\n int j = 0;\n while(S[i] != ch[j]) j++;\n vecy += dy[j], vecx += dx[j];\n route[i + 1] = Pi(vecy, vecx);\n }\n route[0] = Pi(INF, 2 * N);\n for(int i = 1; i <= N; i++) {\n if(vecy < 0) route[i].first = -route[i].first;\n if(vecx < 0) route[i].second = -route[i].second;\n if(vecx == 0) swap(route[i].first, route[i].second);\n route[i].first += INF, route[i].second += N * 2;\n }\n vecy = llabs(vecy); vecx = llabs(vecx);\n if(vecx == 0) vecx = vecy, vecy = 0;\n sort(route, route + N + 1);\n if(vecx == 0) {\n for(int i = 0; i <= N;) {\n ll y = route[i].first, x = route[i].second;\n if(binary_search(route, route + N + 1, Pi(y + 1, x)) && binary_search(route, route + N + 1, Pi(y, x + 1)) && binary_search(route, route + N + 1, Pi(y + 1, x + 1))) ans++;\n while(i <= N && route[i].first == y && route[i].second == x) i++;\n }\n cout << ans << endl;\n return (0);\n }\n for(int i = 0; i <= N; i++) {\n ll y = route[i].first, x = route[i].second;\n data.push_back(PPi(Pi(y - x / vecx * vecy, x % vecx), Pi(x / vecx, x / vecx + K)));\n }\n sort(data.begin(), data.end());\n data.erase(unique(data.begin(), data.end()), data.end());\n for(int i = 0; i < data.size();) {\n vector < ll > comp;\n vector < Ti > d;\n map < ll, ll > conv;\n\n ll now[4] = {};\n\n ll r, u, ru;\n ll iy = data[i].first.first, ix = data[i].first.second;\n ll plus = (ix + 1) / vecx;\n Pi rp = Pi(iy - plus * vecy, (ix + 1) % vecx);\n Pi up = Pi(iy + 1, ix);\n Pi rup = Pi(iy + 1 - plus * vecy, (ix + 1) % vecx);\n Pi ip = data[i].first;\n Pi nop = Pi(-LLINF, -LLINF);\n\n r = lower_bound(data.begin(), data.end(), PPi(rp, nop)) - data.begin();\n u = lower_bound(data.begin(), data.end(), PPi(up, nop)) - data.begin();\n ru = lower_bound(data.begin(), data.end(), PPi(rup, nop)) - data.begin();\n while(i < data.size() && data[i].first == ip) {\n ll s = data[i].second.first, t = data[i].second.second;\n comp.push_back(s); comp.push_back(t);\n d.push_back(Ti(1, Pi(0, s)));\n d.push_back(Ti(-1, Pi(0, t)));\n i++;\n }\n while(r < data.size() && data[r].first == rp) { \n ll s = data[r].second.first - plus, t = data[r].second.second - plus;\n comp.push_back(s); comp.push_back(t);\n d.push_back(Ti(1, Pi(1, s)));\n d.push_back(Ti(-1, Pi(1, t)));\n r++;\n }\n while(u < data.size() && data[u].first == up) { \n ll s = data[u].second.first, t = data[u].second.second;\n comp.push_back(s); comp.push_back(t);\n d.push_back(Ti(1, Pi(2, s)));\n d.push_back(Ti(-1, Pi(2, t)));\n u++;\n }\n while(ru < data.size() && data[ru].first == rup) { \n ll s = data[ru].second.first - plus, t = data[ru].second.second - plus;\n comp.push_back(s); comp.push_back(t);\n d.push_back(Ti(1, Pi(3, s)));\n d.push_back(Ti(-1, Pi(3, t)));\n ru++;\n }\n sort(comp.begin(), comp.end());\n comp.erase(unique(comp.begin(), comp.end()), comp.end());\n for(int j = 0; j < comp.size(); j++) conv[comp[j]] = j;\n for(int p = 0; p < 4; p++) for(int j = 0; j < comp.size(); j++) sum[p][j] = 0;\n for(int j = 0; j < d.size(); j++) sum[d[j].second.first][conv[d[j].second.second]] += d[j].first;\n for(int j = 0; j < comp.size() - 1; j++) {\n bool flag = true;\n for(int k = 0; k < 4; k++) {\n now[k] += sum[k][j];\n if(now[k] <= 0) flag = false;\n }\n if(flag) ans += comp[j + 1] - comp[j];\n } \n }\n cout << ans << endl;\n return (0);\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 25272, "score_of_the_acc": -0.3812, "final_rank": 8 }, { "submission_id": "aoj_0628_2660309", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\n#define INF 1000000000\nusing namespace std;\n\ntypedef pair<int,int> P;\n\nmap<P,vector<P> > mp;\n\nsigned main(){\n\tint n,k,x = 0,y = 0,ans = 0;\n\tP ps[100010];\n\tstring s;\n\tcin >> n >> k >> s;\n\tps[0] = P(0,0);\n\tfor(int i = 0;i < n;i++){\n\t\tif(s[i] == 'N') x--;\n\t\telse if(s[i] == 'E') y--;\n\t\telse if(s[i] == 'W') y++;\n\t\telse x++;\n\t\tps[i + 1] = P(x,y);\n\t}\n\tfor(int i = 0;i <= n;i++){\n\t\tif(ps[n].first < 0) ps[i].first *= -1;\n\t\tif(ps[n].second < 0) ps[i].second *= -1;\n\t}\n\tfor(int i = 0;i <= n;i++){\n\t\tif(ps[n].first > ps[n].second) swap(ps[i].first,ps[i].second);\n\t}\n\tx = ps[n].first;\n\ty = ps[n].second;\n\tset<P> st;\n\tfor(int i = 0;i <= n;i++) st.insert(ps[i]);\n\tif(ps[n] == P(0,0)){\n\t\tfor(auto it = st.begin();it != st.end();it++){\n\t\t\tbool flag = true;\n\t\t\tfor(int j = 0;j < 2;j++){\n\t\t\t\tfor(int k = 0;k < 2;k++){\n\t\t\t\t\tif(!st.count(P((*it).first + j,(*it).second + k))) flag = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag) ans++;\n\t\t}\n\t\tcout << ans << endl;\n\t\treturn 0;\n\t}\n\tfor(auto it = st.begin();it != st.end();it++){\n\t\tint a = INF,b = INF,d;\n\t\tP p = *it;\n\t\tif(x) a = (p.first + INF * x) / x - INF;\n\t\tif(y) b = (p.second + INF * y) / y - INF;\n\t\td = min(a,b);\n\t\tmp[P(p.first - x * d,p.second - y * d)].push_back(P(d,d + k));\n\t}\n\tfor(auto it = mp.begin();it != mp.end();it++){\n\t\tP p = it->first;\n\t\tvector<P> vec;\n\t\tfor(int i = 0;i < 2;i++){\n\t\t\tfor(int j = 0;j < 2;j++){\n\t\t\t\tint nx = p.first + i,ny = p.second + j,a = INF,b = INF,d;\n\t\t\t\tif(x) a = (nx + INF * x) / x - INF;\n\t\t\t\tif(y) b = (ny + INF * y) / y - INF;\n\t\t\t\td = min(a,b);\n\t\t\t\tif(mp.find(P(nx - x * d,ny - y * d)) == mp.end()) continue;\n\t\t\t\tfor(P pp : mp[P(nx - x * d,ny - y * d)]){\n\t\t\t\t\tvec.push_back(P(pp.first - d,i * 2 + j + 1));\n\t\t\t\t\tvec.push_back(P(pp.second - d,-(i * 2 + j + 1)));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsort(vec.begin(),vec.end());\n\t\tint cnt[4] = {},prev;\n\t\tfor(int i = 0;i < vec.size();i++){\n\t\t\tP pp = vec[i];\n\t\t\tint a = pp.first,b = pp.second;\n\t\t\tbool flag = true;\n\t\t\tfor(int j = 0;j < 4;j++) if(!cnt[j]) flag = false;\n\t\t\tif(flag) ans += a - prev;\n\t\t\tprev = a;\n\t\t\twhile(i < vec.size() && vec[i].first == a){\n\t\t\t\tif(vec[i].second > 0) cnt[vec[i].second - 1]++;\n\t\t\t\telse cnt[-vec[i].second - 1]--;\n\t\t\t\ti++;\n\t\t\t}\n\t\t\ti--;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 22060, "score_of_the_acc": -0.2231, "final_rank": 4 }, { "submission_id": "aoj_0628_2645071", "code_snippet": "#include <map>\n#include <string>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nstruct query { int x, y, d; };\nbool operator< (const query& q1, const query& q2) { return ((1LL * q1.d) << 34) + (q1.x << 17) + q1.y < ((1LL * q2.d) << 34) + (q2.x << 17) + q2.y; }\nint N, K, cx, cy, dx[100009], dy[100009], fs[100009], ss[100009], tp[100009], vx[4], vy[4], vd[4]; string s; map<query, vector<int> > p; vector<int> cp, cp2, v[4];\nint main() {\n\tios::sync_with_stdio(false);\n\tcin >> N >> K >> s; N += 2;\n\tchar cb = s.back();\n\tif (cb == 'E') s += \"WE\";\n\tif (cb == 'N') s += \"SN\";\n\tif (cb == 'W') s += \"EW\";\n\tif (cb == 'S') s += \"NS\";\n\tfor (int i = 0; i < 4; i++) {\n\t\tcx = 0, cy = 0;\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tif (s[j] == 'E') dx[j] = 1, dy[j] = 0;\n\t\t\tif (s[j] == 'N') dx[j] = 0, dy[j] = 1;\n\t\t\tif (s[j] == 'W') dx[j] = -1, dy[j] = 0;\n\t\t\tif (s[j] == 'S') dx[j] = 0, dy[j] = -1;\n\t\t\tcx += dx[j], cy += dy[j];\n\t\t}\n\t\tif (cx > 0 && cy >= 0) break;\n\t\tif (cx == 0 && cy == 0) {\n\t\t\tN--; K = 1; i = -1;\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int j = 0; j < N; j++) {\n\t\t\tchar sc = s[j];\n\t\t\tif (sc == 'E') s[j] = 'N';\n\t\t\tif (sc == 'N') s[j] = 'W';\n\t\t\tif (sc == 'W') s[j] = 'S';\n\t\t\tif (sc == 'S') s[j] = 'E';\n\t\t}\n\t}\n\tint ry = (cy ? cy : 1012345678), sx = (N / cx + 2) * cx, sy = (N / ry + 1) * ry, sd = sx / cx - sy / ry, sv = sx / cx;\n\tfor (int i = 0; i < N; i++) {\n\t\tp[query{ sx % cx, sy % ry, sx / cx - sy / ry }].push_back(sx / cx);\n\t\tsx += dx[i];\n\t\tsy += dy[i];\n\t}\n\tfor (pair<const query, vector<int> > &g : p) {\n\t\tsort(g.second.begin(), g.second.end());\n\t\tg.second.erase(unique(g.second.begin(), g.second.end()), g.second.end());\n\t}\n\tlong long ret = 0;\n\tmap<query, vector<int> > pt = p;\n\tfor (pair<query, vector<int> > g : pt) {\n\t\tvx[0] = g.first.x; vy[0] = g.first.y; vd[0] = g.first.d;\n\t\tvx[1] = g.first.x - 1 + (g.first.x == 0 ? cx : 0); vy[1] = g.first.y; vd[1] = g.first.d - (g.first.x == 0 ? 1 : 0);\n\t\tvx[2] = g.first.x; vy[2] = g.first.y - 1 + (g.first.y == 0 ? ry : 0); vd[2] = g.first.d + (g.first.y == 0 ? 1 : 0);\n\t\tvx[3] = g.first.x - 1 + (g.first.x == 0 ? cx : 0); vy[3] = g.first.y - 1 + (g.first.y == 0 ? ry : 0); vd[3] = g.first.d - (g.first.x == 0 ? 1 : 0) + (g.first.y == 0 ? 1 : 0);\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tv[i] = p[query{ vx[i], vy[i], vd[i] }];\n\t\t}\n\t\tif (g.first.x == 0) {\n\t\t\tfor (int i = 1; i <= 3; i += 2) {\n\t\t\t\tfor (int j = 0; j < v[i].size(); j++) v[i][j]++;\n\t\t\t}\n\t\t}\n\t\tcp = v[0];\n\t\tfor (int i = 1; i < 4; i++) {\n\t\t\tint tpr = merge(cp.begin(), cp.end(), v[i].begin(), v[i].end(), tp) - tp;\n\t\t\tcp.resize(tpr);\n\t\t\tfor (int j = 0; j < tpr; j++) cp[j] = tp[j];\n\t\t}\n\t\tcp2.resize(cp.size());\n\t\tfor (int i = 0; i < cp.size(); i++) cp2[i] = cp[i] + K;\n\t\tint tps = merge(cp.begin(), cp.end(), cp2.begin(), cp2.end(), tp) - tp;\n\t\tcp.resize(tps);\n\t\tfor (int i = 0; i < tps; i++) cp[i] = tp[i];\n\t\tcp.erase(unique(cp.begin(), cp.end()), cp.end());\n\t\tint sp = cp.size();\n\t\tfill(fs, fs + sp, 0);\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tfill(ss, ss + sp, 0);\n\t\t\tfor (int j : v[i]) {\n\t\t\t\tss[lower_bound(cp.begin(), cp.end(), j) - cp.begin()]++;\n\t\t\t\tss[lower_bound(cp.begin(), cp.end(), j + K) - cp.begin()]--;\n\t\t\t}\n\t\t\tint curs = 0;\n\t\t\tfor (int j = 0; j < sp; j++) {\n\t\t\t\tcurs += ss[j];\n\t\t\t\tif (curs >= 1) fs[j]++;\n\t\t\t}\n\t\t}\n\t\tfor (int i = 0; i < sp; i++) {\n\t\t\tif (fs[i] == 4) ret += cp[i + 1] - cp[i];\n\t\t}\n\t}\n\tcout << ret << endl;\n\treturn 0;\n}", "accuracy": 0.61, "time_ms": 80, "memory_kb": 33652, "score_of_the_acc": -0.1581, "final_rank": 19 }, { "submission_id": "aoj_0628_2641659", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\nusing namespace std;\nlong long N, K, X[100009], Y[100009], ux[100009], uy[100009], uz[100009], cx, cy; string S;\nmap<pair<long long, long long>, vector<long long>>T; map<pair<long long, long long>, bool>M;\npair<long long, long long>exchange(long long px, long long py, long long &ps) {\n\tps = (px + 1000000000LL * cx) / cx - 1000000000LL;\n\tlong long PX = px - ps*cx;\n\tlong long PY = py - ps*cy;\n\treturn make_pair(PX, PY);\n}\nint main() {\n\tcin >> N >> K >> S;\n\tfor (int i = 0; i < N; i++) {\n\t\tif (S[i] == 'N')cx--; if (S[i] == 'S')cx++;\n\t\tif (S[i] == 'E')cy++; if (S[i] == 'W')cy--;\n\t\tX[i + 1] = cx; Y[i + 1] = cy;\n\t}\n\tif (cx == 0 && cy == 0) {\n\t\tK = 1; cx = 1; cy = 1;\n\t}\n\tif (cx == 0) {\n\t\tfor (int i = 0; i <= N; i++)swap(X[i], Y[i]); swap(cx, cy);\n\t}\n\tif (cx < 0) {\n\t\tfor (int i = 0; i <= N; i++)X[i] *= -1; cx *= -1;\n\t}\n\tif (cy < 0) {\n\t\tfor (int i = 0; i <= N; i++)Y[i] *= -1; cy *= -1;\n\t}\n\tfor (int i = 0; i <= N; i++) {\n\t\tlong long V = 0;\n\t\tpair<long long, long long> uu = exchange(X[i], Y[i], V);\n\t\tux[i] = uu.first; uy[i] = uu.second; uz[i] = V;\n\t\tT[make_pair(ux[i], uy[i])].push_back(V);\n\t}\n\tlong long ans = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tif (M[make_pair(ux[i], uy[i])] == true)continue;\n\t\tvector<long long>A[4]; long long D = 0, DE = 0;\n\t\tA[0] = T[exchange(ux[i], uy[i], D)];\n\t\tA[1] = T[exchange(ux[i] + 1, uy[i], DE)]; if (D != DE) { for (int i = 0; i < A[1].size(); i++) { A[1][i]--; } }\n\t\tA[2] = T[exchange(ux[i], uy[i] + 1, DE)]; if (D != DE) { for (int i = 0; i < A[2].size(); i++) { A[2][i]--; } }\n\t\tA[3] = T[exchange(ux[i] + 1, uy[i] + 1, DE)]; if (D != DE) { for (int i = 0; i < A[3].size(); i++) { A[3][i]--; } }\n\t\tvector<long long>E;\n\t\tfor (int j = 0; j < 4; j++) { for (int k = 0; k < A[j].size(); k++) { E.push_back(A[j][k]); E.push_back(A[j][k] + K); } }\n\t\tsort(E.begin(), E.end()); E.erase(unique(E.begin(), E.end()), E.end());\n\t\tvector<int>ES(E.size() + 1, 0);\n\t\tfor (int j = 0; j < 4; j++) {\n\t\t\tvector<int>ER(E.size() + 1, 0);\n\t\t\tfor (int k = 0; k < A[j].size(); k++) {\n\t\t\t\tint pos1 = lower_bound(E.begin(), E.end(), A[j][k]) - E.begin();\n\t\t\t\tint pos2 = lower_bound(E.begin(), E.end(), A[j][k] + K) - E.begin();\n\t\t\t\tER[pos1]++; ER[pos2]--;\n\t\t\t}\n\t\t\tfor (int j = 1; j < E.size() + 1; j++)ER[j] += ER[j - 1];\n\t\t\tfor (int j = 0; j < E.size() + 1; j++) { if (ER[j] >= 1)ES[j] += 1; }\n\t\t}\n\t\tlong long res = 0;\n\t\tfor (int j = 0; j < E.size(); j++) {\n\t\t\tif (ES[j] == 4)res += (E[j + 1] - E[j]);\n\t\t}\n\t\tans += res;\n\t\tM[make_pair(ux[i], uy[i])] = true;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 31844, "score_of_the_acc": -0.3536, "final_rank": 7 }, { "submission_id": "aoj_0628_2350418", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\nusing Point = pair<int, int>;\nusing Interval = pair<int, int>;\nusing Event = pair<int, bool>;\nconst bool IN = false;\nconst bool OUT = true;\n\nint N, K;\nstring S;\n\nLL loop(auto& p) {\n set<Point> s(begin(p), end(p));\n LL res = 0;\n for(auto i: s) {\n auto x = i.first, y = i.second;\n if(s.count({x+1, y}) && s.count({x, y+1}) && s.count({x+1, y+1})) ++res;\n }\n return res;\n}\n\nLL solve(auto& p, int a, int b) {\n // vectorize\n map<Point, set<Interval>> vec;\n for(auto i: p) {\n auto k = i.first / a;\n auto x = i.first % a;\n auto y = i.second - b * k;\n if(x < 0) {\n --k;\n x += a;\n y += b;\n }\n vec[{x, y}].emplace(k, k + K - 1);\n }\n\n // merge\n map<Point, set<Event>> event;\n for(auto& i: vec) {\n auto cur = begin(i.second);\n auto l = cur->first, h = cur->second;\n for(auto pre = cur++; pre != end(i.second); pre = cur++) {\n if(cur == end(i.second)) {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n break;\n }\n if(cur->first - 1 <= pre->second) h = cur->second;\n else {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n l = cur->first;\n h = cur->second;\n }\n }\n }\n\n // intersect\n LL res = 0;\n for(auto i: event) {\n auto cur = i.first;\n multiset<Event> q;\n for(auto neighbor: {cur, {cur.first + 1, cur.second}, {cur.first + 1, cur.second + 1}, {cur.first, cur.second + 1}}) {\n auto dif = 0;\n if(neighbor.first >= a) {dif = 1; neighbor = {neighbor.first - a, neighbor.second - b};}\n if(!event.count(neighbor)) break;\n for(auto e: event[neighbor]) q.emplace(e.first - dif, e.second);\n }\n // count\n auto cnt = 0, begin = 0;\n for(auto e: q) {\n if(e.second == IN) {\n ++cnt;\n begin = e.first;\n } else {\n if(cnt == 4) res += e.first - begin + 1;\n --cnt;\n }\n }\n }\n return res;\n}\n\nLL solve() {\n // simulate\n auto x = 0, y = 0;\n vector<Point> p;\n p.emplace_back(x, y);\n for(auto i: S) {\n x += (i=='E') - (i=='W');\n y += (i=='N') - (i=='S');\n p.emplace_back(x, y);\n }\n\n if(x == 0 && y == 0) return loop(p);\n\n if(x == 0) {swap(x, y); for(auto& i: p) swap(i.first, i.second);}\n if(x < 0) {x *= -1; for(auto& i: p) i.first *= -1;}\n return solve(p, x, y);\n}\n\nint main() {\n cin >> N >> K >> S;\n cout << solve() << endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 36448, "score_of_the_acc": -0.6239, "final_rank": 12 }, { "submission_id": "aoj_0628_2350364", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\nusing Point = pair<int, int>;\nusing Interval = pair<int, int>;\nusing Event = pair<int, bool>;\nconst bool IN = false;\nconst bool OUT = true;\n\nint N, K;\nstring S;\n\nLL loop(auto& p) {\n set<Point> s(begin(p), end(p));\n LL res = 0;\n for(auto i: s) {\n auto x = i.first, y = i.second;\n if(s.count(Point(x+1, y)) && s.count(Point(x, y+1)) && s.count(Point(x+1, y+1))) ++res;\n }\n return res;\n}\n\nLL solve(auto& p, int a, int b) {\n // vectorize\n map<Point, set<Interval>> vec;\n for(auto i: p) {\n auto k = i.first / a;\n auto x = i.first % a;\n auto y = i.second - b * k;\n if(x < 0) {\n --k;\n x += a;\n y += b;\n }\n vec[{x, y}].emplace(k, k + K - 1);\n }\n// for(auto i: vec){\n// cout<<i.first.first<<\",\"<<i.first.second<<\": \";\n// for(auto j: i.second)cout<<\" [\"<<j.first<<\",\"<<j.second<<\"] \";\n// cout<<endl;\n// }\n\n // merge\n map<Point, set<Event>> event;\n for(auto& i: vec) {\n auto cur = begin(i.second);\n auto l = cur->first, h = cur->second;\n for(auto pre = cur++; pre != end(i.second); pre = cur++) {\n if(cur == end(i.second)) {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n break;\n }\n if(cur->first - 1 <= pre->second) h = cur->second;\n else {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n l = cur->first;\n h = cur->second;\n }\n }\n }\n// for(auto i: event) {\n// cout<<i.first.first<<\",\"<<i.first.second<<\": \";\n// for(auto j: i.second)cout<<\" \"<<j.first<<\"_\"<<j.second<<\" \";\n// cout<<endl;\n// }\n\n // intersect\n LL res = 0;\n for(auto i: event) {\n auto cur = i.first;\n// cout<<res<<endl;\n// cout<<\"TRY: \"<<cur.first<<\",\"<<cur.second<<endl;\n multiset<Event> q;\n for(auto e: event[cur]) q.emplace(e);\n for(auto nex: {Point(cur.first + 1, cur.second), Point(cur.first + 1, cur.second + 1), Point(cur.first, cur.second + 1)}) {\n// cout<<\" with: \"<<nex.first<<\",\"<<nex.second<<endl;\n auto dif = 0;\n if(nex.first >= a) {dif = 1; nex = Point(nex.first - a, nex.second - b);}\n// if(!event.count(nex)) cout<<\"NG\"<<endl;\n if(!event.count(nex)) break;\n for(auto e: event[nex]) q.emplace(e.first - dif, e.second);\n }\n // count\n auto cnt = 0;\n auto l = 0;\n for(auto e: q) {\n if(e.second == IN) {\n ++cnt;\n l = e.first;\n } else {\n if(cnt == 4) res += e.first - l + 1;\n --cnt;\n }\n }\n }\n return res;\n}\n\nLL solve() {\n // simulate\n auto x = 0, y = 0;\n vector<Point> p;\n p.emplace_back(x, y);\n for(auto i: S) {\n x += (i=='E') - (i=='W');\n y += (i=='N') - (i=='S');\n p.emplace_back(x, y);\n// cout<<x<<\" \"<<y<<endl;\n }\n\n if(x == 0 && y == 0) return loop(p);\n\n if(x == 0) {swap(x, y); for(auto& i: p) swap(i.first, i.second);}\n if(x < 0) {x *= -1; for(auto& i: p) i.first *= -1;}\n return solve(p, x, y);\n}\n\nint main() {\n cin >> N >> K >> S;\n cout << solve() << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 36468, "score_of_the_acc": -0.5206, "final_rank": 10 }, { "submission_id": "aoj_0628_2349764", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing LL = long long;\nusing Point = pair<int, int>;\nusing Interval = pair<int, int>;\nusing Event = pair<int, bool>;\nconst bool IN = false;\nconst bool OUT = true;\n\nint N, K;\nstring S;\n\nLL loop(auto& p) {\n set<Point> s(begin(p), end(p));\n LL res = 0;\n for(auto i: s) {\n auto x = i.first, y = i.second;\n res += s.count(Point(x+1, y)) && s.count(Point(x, y+1)) && s.count(Point(x+1, y+1));\n }\n return res;\n}\n\nLL solve(auto& p, int a, int b) {\n // vectorize\n map<Point, set<Interval>> vec;\n for(auto i: p) {\n auto k = i.first / a;\n auto x = i.first % a;\n auto y = i.second - b * k;\n if(x < 0) {\n --k;\n x += a;\n y += b;\n }\n vec[{x, y}].emplace(k, k + K - 1);\n }\n// for(auto i: vec){\n// cout<<i.first.first<<\",\"<<i.first.second<<\": \";\n// for(auto j: i.second)cout<<\" [\"<<j.first<<\",\"<<j.second<<\"] \";\n// cout<<endl;\n// }\n\n // merge\n map<Point, set<Event>> event;\n for(auto& i: vec) {\n auto cur = begin(i.second);\n auto l = cur->first, h = cur->second;\n for(auto pre = cur++; pre != end(i.second); pre = cur++) {\n if(cur == end(i.second)) {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n break;\n }\n if(cur->first - 1 <= pre->second) h = cur->second;\n else {\n event[i.first].emplace(l, IN);\n event[i.first].emplace(h, OUT);\n l = cur->first;\n h = cur->second;\n }\n }\n }\n// for(auto i: event) {\n// cout<<i.first.first<<\",\"<<i.first.second<<\": \";\n// for(auto j: i.second)cout<<\" \"<<j.first<<\"_\"<<j.second<<\" \";\n// cout<<endl;\n// }\n\n // unite\n LL res = 0;\n for(auto i: event) {\n auto cur = i.first;\n// cout<<res<<endl;\n// cout<<\"TRY: \"<<cur.first<<\",\"<<cur.second<<endl;\n multiset<Event> q;\n for(auto e: event[cur]) q.emplace(e);\n for(auto nex: {Point(cur.first + 1, cur.second), Point(cur.first + 1, cur.second + 1), Point(cur.first, cur.second + 1)}) {\n// cout<<\" with: \"<<nex.first<<\",\"<<nex.second<<endl;\n auto dif = 0;\n if(nex.first >= a) {dif = 1; nex = Point(nex.first - a, nex.second - b);}\n// if(!event.count(nex)) cout<<\"NG\"<<endl;\n if(!event.count(nex)) break;\n for(auto e: event[nex]) q.emplace(e.first - dif, e.second);\n }\n // count\n auto cnt = 0;\n auto l = 0;\n for(auto e: q) {\n if(e.second == IN) {\n ++cnt;\n l = e.first;\n } else {\n if(cnt == 4) res += e.first - l + 1;\n --cnt;\n }\n }\n }\n return res;\n}\n\nLL solve() {\n // simulate\n auto x = 0, y = 0;\n vector<Point> p;\n p.emplace_back(x, y);\n for(auto i: S) {\n x += (i=='E') - (i=='W');\n y += (i=='N') - (i=='S');\n p.emplace_back(x, y);\n// cout<<x<<\" \"<<y<<endl;\n }\n\n if(x == 0 && y == 0) return loop(p);\n\n if(x < 0) {x *= -1; for(auto& i: p) i.first *= -1;}\n if(y < 0) {y *= -1; for(auto& i: p) i.second *= -1;}\n if(x == 0) {swap(x, y); for(auto& i: p) swap(i.first, i.second);}\n return solve(p, x, y);\n}\n\nint main() {\n cin >> N >> K >> S;\n cout << solve() << endl;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 36524, "score_of_the_acc": -0.521, "final_rank": 11 } ]
aoj_0629_cpp
断層(Geologic Fault) 遠い昔,IOI 文明という高度な文明が栄えていた.しかし,火山の噴火により,この高度な文明はついに滅んでしまった.IOI 文明は直線状の河川に沿って繁栄しており,IOI 文明が滅んだとき,その地表面は平らであった.IOI 文明の跡地は座標平面のx 軸と見なすことができる.y 軸は高さ方向を表す.すなわち,座標平面において,直線 $y = 0$ は地表を,領域 $y > 0$ は地上を,領域 $y < 0$ は地下を表す.また,IOI 文明が滅んだとき,$a$ 年前$(a \geq 0)$ の地層は,直線 $y = -a$ の位置にあった. IOI 文明が滅んだ後,IOI 文明の跡地では $Q$ 回の地殻変動が起きた.$i$ 回目$(1 \leq i \leq Q)$ の地殻変動は,位置 $X_i$,方向 $D_i$,変動の量 $L_i$ で表される.$D_i$ は 1 または 2 である.$i$ 回目の地殻変動は以下のように起きる. 地層の移動が次のように起きる. $D_i = 1$ のとき,断層が点$(X_i, 0)$ を通る傾き $1$ の直線に沿って造られ,この直線より上の領域にある地層が,直線に沿って高さ $L_i$ だけ移動する.すなわち,この直線より上の点 $(x, y)$ は,点$(x + L_i, y + L_i)$ に移動する. $D_i = 2$ のとき,断層が点$(X_i, 0)$ を通る傾き $-1$ の直線に沿って造られ,この直線より上の領域にある地層が,直線に沿って高さ $L_i$ だけ移動する.すなわち,この直線より上の点$(x, y)$ は,点$(x - L_i, y + L_i)$ に移動する. そのすぐ後に,領域 $y > 0$ の地層が風化によってすべて消える. 時は変わり現代,考古学者のJOI 博士はIOI 文明の遺跡を発掘することにした.JOI 博士はどの位置の地表の地層が,IOI 文明が滅ぶ何年前の地層であるかを知りたい.どのような地殻変動が起きたかは分かっている.あなたの仕事は,JOI 博士にかわって,$1 \leq i \leq N$ を満たす各整数 $i$ について,点$(i-1, 0)$ と点$(i, 0)$の間の地表の地層がIOI 文明が滅ぶ何年前の地層であるかを求めることである. 課題 IOI 文明の跡地に起きたの情報が与えられたとき,すべての整数 $i$ $(1 \leq i \leq N)$ に対し,点$(i - 1, 0)$ と点$(i, 0)$ の間の地表の地層がIOI 文明が滅ぶ何年前の地層であるかを出力せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には, 2 個の整数 $N, Q$ が空白を区切りとして書かれている.これは,答えを求める地点の数が $N$,地殻変動の回数が $Q$ であることを表す. 続く $Q$ 行のうちの $i$ 行目$(1 \leq i \leq Q)$ には,3 個の整数 $X_i, D_i, L_i$ が空白を区切りとして書かれている.これは,$i$ 回目の地殻変動の位置が $X_i$,方向が $D_i$,変動の量が $L_i$ であることを表す. 出力 出力は $N$ 行からなる.標準出力の $i$ 行目$(1 \leq i \leq N)$ には,点$(i - 1, 0)$ と点$(i, 0)$ の間の地表の地層がIOI文明が滅ぶ何年前の地層であるかを表す整数を出力せよ. 制限 すべての入力データは以下の条件を満たす. $1 \leq N \leq 200 000$ $1 \leq Q \leq 200 000$ $ -1 000 000 000 \leq X_i \leq 1 000 000 000$ $(1 \leq i \leq Q)$ $1 \leq D_i \leq 2$ $(1 \leq i \leq Q)$ $1 \leq L_i \leq 1 000 000 000$ $(1 \leq i \leq Q)$ 入出力例 入力例1 10 2 12 1 3 2 2 2 出力例1 3 3 5 5 5 5 5 5 2 2 この入力例は,以下の図に対応する. 入力例2 10 6 14 1 1 17 1 1 -6 2 1 3 2 1 4 1 1 0 2 1 出力例2 5 5 4 5 5 5 5 5 4 4 入力例3 15 10 28 1 7 -24 2 1 1 1 1 8 1 1 6 2 1 20 1 3 12 2 2 -10 1 3 7 2 1 5 1 2 出力例3 15 14 14 14 14 12 12 12 12 12 12 12 15 15 12 第15回 日本情報オリンピック本選 課題   2016 年 2 月 14 日
[ { "submission_id": "aoj_0629_9477496", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int64;\n\n// Binary Indexed Treeの構造体\nstruct BinaryIndexedTree {\n vector<int64> data;\n int curr;\n\n BinaryIndexedTree(int sz) {\n data.assign(++sz, 0); // データ配列を0で初期化\n curr = 1;\n while (curr < data.size()) curr <<= 1;\n for (int i = 0; i < data.size(); i++) data[i] = i & -i;\n }\n\n // 1からkまでの和を計算\n inline int64 sum(int k) {\n int64 ret = 0;\n for (++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n\n // w以下の最大のインデックスを探す\n inline int upper_bound(int64 w) {\n int i = 0;\n for (int k = curr; k > 0; k >>= 1) {\n if (i + k < data.size() && data[i + k] <= w) {\n w -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n\n // k番目の要素にxを加算\n inline void add(int k, int64 x) {\n for (++k; k < data.size(); k += k & -k) data[k] += x;\n }\n};\n\nint N, Q;\nint X[200000], D[200000], L[200000];\n\nint main() {\n // 入力の読み込み\n scanf(\"%d %d\", &N, &Q);\n for (int i = 0; i < Q; i++) {\n scanf(\"%d %d %d\", &X[i], &D[i], &L[i]);\n }\n\n // Binary Indexed Treeを2つ使用\n BinaryIndexedTree xpy(N), xmy(N);\n\n // クエリを逆順に処理\n for (int i = Q - 1; i >= 0; i--) {\n if (D[i] == 1) {\n xmy.add(0, -L[i] * 2);\n xmy.add(xpy.upper_bound(X[i]), L[i] * 2);\n } else {\n xpy.add(xmy.upper_bound(X[i]), L[i] * 2);\n }\n }\n\n // 結果の出力\n for (int i = 0; i < N; i++) {\n printf(\"%lld\\n\", (xpy.sum(i) - xmy.sum(i)) / 2);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8684, "score_of_the_acc": -0.124, "final_rank": 4 }, { "submission_id": "aoj_0629_6741635", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\n#define ls(x) ((x)<<1)\n#define rs(x) ((x)<<1|1)\nusing namespace std;\nint const N=2333333,INF=0x3f3f3f3f3f3f3f3fll;\nint n,q,x[N],d[N],l[N],val[N][2],lt[N][2],ans[N][2];\ninline void update(int x,int op){\n\tval[x][op]=min(val[ls(x)][op],val[rs(x)][op]);\n}\ninline void download(int x,int op){\n\tif(!lt[x][op])return;\n\tint t=lt[x][op];lt[x][op]=0;\n\tval[ls(x)][op]+=t,val[rs(x)][op]+=t;\n\tlt[ls(x)][op]+=t,lt[rs(x)][op]+=t;\n}\ninline void build(int x,int l,int r){\n\tif(l==r){\n\t\tval[x][0]=val[x][1]=l;return;\n\t}\n\tint mid=(l+r)>>1;\n\tbuild(ls(x),l,mid);\n\tbuild(rs(x),mid+1,r);\n\tupdate(x,0),update(x,1);\n}\ninline void modify(int x,int l,int r,int ql,int qr,int k,int op){\n\tif(ql<=l&&r<=qr){\n\t\tval[x][op]+=k,lt[x][op]+=k;return;\n\t}\n\tdownload(x,op);\n\tint mid=(l+r)>>1;\n\tif(ql<=mid)\n\t\tmodify(ls(x),l,mid,ql,qr,k,op);\n\tif(qr>mid)\n\t\tmodify(rs(x),mid+1,r,ql,qr,k,op);\n\tupdate(x,op);\n}\ninline void queryx(int x,int l,int r,int k,int&res){\n\tif(l==r){\n\t\tif(val[x][0]<=k)res=max(res,l);\n\t\treturn;\n\t}\n\tdownload(x,0);\n\tint mid=(l+r)>>1;\n\tif(val[rs(x)][0]>k)\n\t\tqueryx(ls(x),l,mid,k,res);\n\telse\n\t\tqueryx(rs(x),mid+1,r,k,res);\n}\ninline void queryy(int x,int l,int r,int k,int&res){\n\tif(l==r){\n\t\tif(val[x][1]>k)res=min(res,l);\n\t\treturn;\n\t}\n\tdownload(x,1);\n\tint mid=(l+r)>>1;\n\tif(val[rs(x)][1]>k){\n\t\tres=min(res,mid+1);\n\t\tqueryy(ls(x),l,mid,k,res);\n\t}else\n\t\tqueryy(rs(x),mid+1,r,k,res);\n}\ninline void dfs(int x,int l,int r){\n\tif(l==r){\n\t\tans[l][0]=val[x][0],ans[l][1]=val[x][1];\n\t\treturn;\n\t}\n\tdownload(x,0),download(x,1);\n\tint mid=(l+r)>>1;\n\tdfs(ls(x),l,mid),dfs(rs(x),mid+1,r);\n}\nsigned main(){\n\tios::sync_with_stdio(0);\n\tcin>>n>>q;\n\tbuild(1,1,n);\n\tfor(int i=1;i<=q;i++)\n\t\tcin>>x[i]>>d[i]>>l[i];\n\tfor(int i=q;i>=1;i--){\n\t\tif(d[i]==1){\n\t\t\tint p=-INF;\n\t\t\tqueryx(1,1,n,x[i],p);\n\t\t\tif(p!=-INF)\n\t\t\t\tmodify(1,1,n,1,p,-2*l[i],1);\n\t\t}else{\n\t\t\tint p=INF;\n\t\t\tqueryy(1,1,n,x[i],p);\n\t\t\tif(p!=INF)\n\t\t\t\tmodify(1,1,n,p,n,2*l[i],0);\n\t\t}\n\t}\n\tdfs(1,1,n);\n\tfor(int i=1;i<=n;i++)\n\t\tcout<<(ans[i][0]-ans[i][1]>>1)<<\"\\n\";\n}\n//42231892", "accuracy": 1, "time_ms": 70, "memory_kb": 38256, "score_of_the_acc": -1.0882, "final_rank": 16 }, { "submission_id": "aoj_0629_5843144", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, n) for(int i = int(n) - 1; i >= int(l); i--)\n\ntemplate<class T>\nstruct DualSegmentTree{\n using F = function<T(T, T)>;\n \n int sz, height;\n vector<T> data;\n vector<bool> is_data;\n \n F f;\n T id;\n \n DualSegmentTree() = default;\n DualSegmentTree(int n, F f): f(f) {\n sz = 1;\n height = 0;\n while(sz < n) sz *= 2, height++;\n data.resize(sz * 2, id);\n is_data.resize(sz * 2, false);\n }\n \n void set(int k, T x){\n k += sz;\n data[k] = x;\n is_data[k] = true;\n }\n \n void eval(int at){\n if(is_data[at]){\n data[at * 2] = is_data[at * 2] ? f(data[at * 2], data[at]) : data[at];\n data[at * 2 + 1] = is_data[at * 2 + 1] ? f(data[at * 2 + 1], data[at]) : data[at];\n is_data[at * 2] = true;\n is_data[at * 2 + 1] = true;\n \n is_data[at] = false;\n }\n }\n \n void update(int a, int b, T x, int l, int r, int at){\n if(r <= a || b <= l) return;\n if(a <= l && r <= b){\n data[at] = (is_data[at] ? f(data[at], x) : x);\n is_data[at] = true;\n return;\n }\n \n eval(at);\n int mid = (l + r) / 2;\n update(a, b, x, l, mid, at * 2);\n update(a, b, x, mid, r, at * 2 + 1);\n }\n \n void update(int a, int b, T x){\n update(a, b, x, 0, sz, 1);\n }\n \n T operator [](int k){\n k += sz;\n repr(i, height){\n eval(k >> (i + 1));\n }\n return data[k];\n }\n};\n\nint main(){\n int n, q;\n cin >> n >> q;\n auto f = [](lint a, lint b){ return a + b; };\n DualSegmentTree<lint> x_seg(n, f), y_seg(n, f);\n rep(i, n){\n x_seg.set(i, i);\n y_seg.set(i, -i);\n }\n \n lint X[q], L[q];\n int D[q];\n rep(i, q) cin >> X[i] >> D[i] >> L[i];\n \n repr(c, q){\n lint pos = X[c], l = L[c];\n int d = D[c];\n if(d == 1){\n int ok = -1, ng = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(x_seg[mid] < pos) ok = mid;\n else ng = mid;\n }\n \n// cout << 0 << \" \" << ok << endl;\n y_seg.update(0, ok + 1, l * 2);\n }else{\n int ng = -1, ok = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(y_seg[mid] <= -pos) ok = mid;\n else ng = mid;\n }\n \n// cout << ok << \" \" << n << endl;\n x_seg.update(ok, n, l * 2);\n }\n \n }\n \n rep(i, n){\n cout << (x_seg[i] + y_seg[i]) / 2 << endl;\n }\n}", "accuracy": 1, "time_ms": 470, "memory_kb": 15328, "score_of_the_acc": -0.9403, "final_rank": 15 }, { "submission_id": "aoj_0629_5843016", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, n) for(int i = int(n) - 1; i >= int(l); i--)\n\nconst lint inf = 1e18;\n\nstruct segtree{\n int sz;\n vector<lint> data;\n \n segtree(int n){\n sz = 1;\n while(sz < n) sz *= 2;\n \n data.resize(sz * 2, 0);\n }\n \n void update(int a, int b, lint x, int l, int r, int at){\n if(r <= a || b <= l) return;\n if(a <= l && r <= b){\n data[at] += x;\n return;\n }\n \n int mid = (l + r) / 2;\n update(a, b, x, l, mid, at * 2);\n update(a, b, x, mid, r, at * 2 + 1);\n }\n \n void update(int a, int b, lint x){\n update(a, b, x, 0, sz, 1);\n }\n \n lint operator [](int k){\n k += sz;\n lint ans = 0;\n while(k >= 1){\n ans += data[k];\n k /= 2;\n }\n \n return ans;\n }\n};\n\nint main(){\n int n, q;\n cin >> n >> q;\n segtree x_seg(n), y_seg(n);\n rep(i, n){\n x_seg.update(i, i + 1, i);\n y_seg.update(i, i + 1, -i);\n }\n \n lint X[q], L[q];\n int D[q];\n rep(i, q) cin >> X[i] >> D[i] >> L[i];\n \n repr(c, q){\n lint pos = X[c], l = L[c];\n int d = D[c];\n if(d == 1){\n int ok = -1, ng = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(x_seg[mid] < pos) ok = mid;\n else ng = mid;\n }\n \n// cout << 0 << \" \" << ok << endl;\n y_seg.update(0, ok + 1, l * 2);\n }else{\n int ng = -1, ok = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(y_seg[mid] <= -pos) ok = mid;\n else ng = mid;\n }\n \n// cout << ok << \" \" << n << endl;\n x_seg.update(ok, n, l * 2);\n }\n \n }\n \n rep(i, n){\n cout << (x_seg[i] + y_seg[i]) / 2 << endl;\n }\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 15316, "score_of_the_acc": -0.7046, "final_rank": 12 }, { "submission_id": "aoj_0629_5842947", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n#define repr(i, n) for(int i = int(n) - 1; i >= 0; i--)\n#define repr2(i, l, n) for(int i = int(n) - 1; i >= int(l); i--)\n\nconst lint inf = 1e18;\n\nstruct segtree{\n int sz;\n vector<lint> data, lazy;\n \n segtree(int n){\n sz = 1;\n while(sz < n) sz *= 2;\n \n data.resize(sz * 2, 0);\n lazy.resize(sz * 2, 0);\n }\n \n void eval(int l, int r, int at){\n data[at] += lazy[at];\n if(r - l > 1){\n lazy[at * 2] += lazy[at];\n lazy[at * 2 + 1] += lazy[at];\n }\n lazy[at] = 0;\n }\n \n void update(int a, int b, lint x, int l, int r, int at){\n if(r <= a || b <= l) return;\n if(a <= l && r <= b){\n lazy[at] += x;\n return;\n }\n eval(l, r, at);\n int mid = (l + r) / 2;\n update(a, b, x, l, mid, at * 2);\n update(a, b, x, mid, r, at * 2 + 1);\n data[at] = data[at * 2] + data[at * 2 + 1];\n }\n \n void update(int a, int b, lint x){\n update(a, b, x, 0, sz, 1);\n }\n \n lint query(int a, int b, int l, int r, int at){\n if(r <= a || b <= l) return 0;\n if(a <= l && r <= b){\n eval(l, r, at);\n return data[at];\n }\n eval(l, r, at);\n int mid = (l + r) / 2;\n return query(a, b, l, mid, at * 2) + query(a, b, mid, r, at * 2 + 1);\n }\n \n lint query(int a, int b){\n return query(a, b, 0, sz, 1);\n }\n \n lint operator [](int k){\n return query(k, k + 1);\n }\n};\n\nint main(){\n int n, q;\n cin >> n >> q;\n segtree x_seg(n), y_seg(n);\n rep(i, n){\n x_seg.update(i, i + 1, i);\n y_seg.update(i, i + 1, -i);\n }\n \n lint X[q], L[q];\n int D[q];\n rep(i, q) cin >> X[i] >> D[i] >> L[i];\n \n repr(c, q){\n lint pos = X[c], l = L[c];\n int d = D[c];\n if(d == 1){\n int ok = -1, ng = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(x_seg[mid] < pos) ok = mid;\n else ng = mid;\n }\n \n// cout << 0 << \" \" << ok << endl;\n y_seg.update(0, ok + 1, l * 2);\n }else{\n int ng = -1, ok = n + 1;\n while(abs(ok - ng) > 1){\n int mid = (ok + ng) / 2;\n \n if(y_seg[mid] <= -pos) ok = mid;\n else ng = mid;\n }\n \n// cout << ok << \" \" << n << endl;\n x_seg.update(ok, n, l * 2);\n }\n \n }\n \n rep(i, n){\n cout << (x_seg[i] + y_seg[i]) / 2 << endl;\n }\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 23452, "score_of_the_acc": -1.5247, "final_rank": 18 }, { "submission_id": "aoj_0629_4265754", "code_snippet": "#pragma GCC optimize (\"Ofast\")\n#pragma GCC target (\"avx\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<queue>\n#include<cmath>\n#include<map>\n#include<set>\n#include<list>\n#include<iomanip>\n#include<vector>\n#include<random>\n#include<functional>\n#include<algorithm>\n#include<stack>\n#include<cstdio>\n#include<cstring>\n#include<bitset>\n#include<unordered_map>\n#include<climits>\n#include<fstream>\n#include<complex>\n#include<time.h>\n#include<cassert>\n#include<functional>\n#include<numeric>\n#include<tuple>\n\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define int long long\n#define all(a) (a).begin(),(a).end()\n#define fs first\n#define sc second\n#define xx first\n#define yy second.first\n#define zz second.second\n#define H pair<int, int>\n#define P pair<int, pair<int, int>>\n#define Q(i,j,k) mkp(i,mkp(j,k))\n#define R pair<pair<int, int>, pair<int, int>>\n#define S(i,j,k,l) mkp(mkp(i,j),mkp(k,l))\n#define rep(i,n) for(int (i) = 0 ; (i) < (n) ; (i)++)\n#define rng(i,s,n) for(int (i) = (s) ; (i) < (n) ; (i)++)\n#define req(n,i) for(int (i) = (n) - 1 ; (i) >= 0 ; (i)--)\n#define range(i,v) for(auto& (i) : v)\n#define mkp make_pair\n#define mem(x,k) memset(x,k,sizeof(x))\n#define vec vector\n#define pb emplace_back\n#define lb lower_bound\n#define ub upper_bound\n#define crdcomp(b) sort(all((b)));(b).erase(unique(all((b))),(b).end())\n#define getidx(b,i) lower_bound(all(b),(i))-b.begin()\n#define ssp(i,n) (i==n-1?\"\\n\":\" \")\n#define ctoi(c) (int)(c-'0')\n#define itoc(c) (char)(c+'0')\n#define itn int\n#define pri_que priority_queue\n#define pp(x,y) pb(H{x,y})\n#define ppp(x,y,z) pb(Q(x,y,z))\n#define pppp(x,y,z,w) pb(S(x,y,z,w))\n#define cyes cout<<\"Yes\\n\"\n#define cno cout<<\"No\\n\"\n#define endl \"\\n\"\nconstexpr int mod = 1e9 + 7;\nconstexpr int Mod = 998244353;\nconstexpr int MXN = 500000 + 100;\nconstexpr ll inf = 3 * 1e18;\nconstexpr int Inf = 15 * 1e8;\nconst vec<int>dx{ -1,1,0,0 }, dy{ 0,0,-1,1 };\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (b < a) { a = b; return 1; } return 0; }\nll read() { ll u, k = scanf(\"%lld\", &u); return u; }\nstring reads() { string s; cin >> s; return s; }\nH readh(bool g = 0) { H u; ll k = scanf(\"%lld %lld\", &u.fs, &u.sc); if (g) u.fs--, u.sc--; return u; }\nvoid printh(H t) { printf(\"%lld %lld\\n\", t.fs, t.sc); }\nbool inarea(H t, int h, int w) { return 0 <= t.fs && t.fs < h && 0 <= t.sc && t.sc < w; }\nll gcd(ll i, ll j) { return j ? gcd(j, i % j) : i; }\nll mod_pow(ll x, ll n, ll p = mod) {\n\tll res = 1;\n\twhile (n > 0) {\n\t\tif (n & 1) res = res * x % p;\n\t\tx = x * x % p;\n\t\tn >>= 1;\n\t}\n\treturn res;\n}//x^n%p\nll bitcount(ll x) {\n\tint sum = 0; for (int i = 0; i < 60; i++)if ((1ll << i) & x) sum++;\n\treturn sum;\n}\n/*constexpr int fn_ = 1000005;\nll fact_[fn_], comp_[fn_];\nll comb(ll x, ll y, ll Mod = mod) {\n\tif (!fact_[0]) {\n\t\tfact_[0] = 1; comp_[0] = 1;\n\t\tfor (int i = 1; i < fn_; i++)\n\t\t\tfact_[i] = fact_[i - 1] * i % Mod;\n\t\tcomp_[fn_ - 1] = mod_pow(fact_[fn_ - 1], Mod - 2, Mod);\n\t\tfor (int i = fn_ - 2; i > 0; i--)\n\t\t\tcomp_[i] = comp_[i + 1] * (i + 1) % Mod;\n\t}\n\tif (x < y) return 0;\n\treturn fact_[x] * comp_[x - y] % Mod * comp_[y] % Mod;\n}*/\n//--------------------------------------------------------------\nclass BIT {\n\tint size;\n\tint dat[500000];\npublic:\n\tBIT() {}\n\tvoid init(int n) {\n\t\tsize = n;\n\t\tfor (int i = 1; i <= n; i++) dat[i] = 0;\n\t}\n\tvoid add(int i, int x = 1) {\n\t\ti++;\n\t\twhile (i <= size) {\n\t\t\tdat[i] += x;\n\t\t\ti += i & -i;\n\t\t}\n\t}//0-indexed\n\tint query(int i) {\n\t\ti++;\n\t\tint sum = 0;\n\t\twhile (i > 0) {\n\t\t\tsum += dat[i];\n\t\t\ti -= i & -i;\n\t\t}\n\t\treturn sum;\n\t}//0-indexed\n\tint operator[](const int& i) {\n\t\treturn query(i) - query(i - 1);\n\t}\n};//size, 0-indexed\nint n, q;\nvec<P>a;\nBIT x, y;\nsigned main() {\n\tcin >> n >> q;\n\tx.init(n); y.init(n);\n\trep(i, n) { \n\t\tx.add(i, i); x.add(i + 1, -i);\n\t\ty.add(i, n - 1 - i); y.add(i + 1, -n + 1 + i);\n\t}\n\trep(i, q) {\n\t\tint t, u, v;\n\t\tcin >> u >> t >> v;\n\t\tu--;\n\t\tif (t == 2) u = n - 1 - u;\n\t\ta.ppp(t, u, v);\n\t\t//クエリTの時、u以下のものをv動かす。\n\t}\n\treverse(all(a));\n\trange(g, a) {\n\t\tif (g.xx == 1) {\n\t\t\t//x座標がX以下の頂点についてyを加算する\n\t\t\t//二分探索でx座標がX以下の最後の頂点を求める\n\t\t\tint ok = -1, ng = n, mid;\n\t\t\twhile (abs(ok - ng) > 1) {\n\t\t\t\tmid = (ok + ng) / 2;\n\t\t\t\tif (x.query(mid) <= g.yy) ok = mid;\n\t\t\t\telse ng = mid;\n\t\t\t}\n\t\t\tif (ok >= 0) {\n\t\t\t\ty.add(0, g.zz * 2); y.add(ok + 1, -g.zz * 2);\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\t//y座標がX以下の最初の頂点を求める\n\t\t\tint ok = n, ng = -1, mid;\n\t\t\twhile (abs(ok - ng) > 1) {\n\t\t\t\tmid = (ok + ng) / 2;\n\t\t\t\tif (y.query(mid) <= g.yy) ok = mid;\n\t\t\t\telse ng = mid;\n\t\t\t}\n\t\t\tif (ok < n - 1) {\n\t\t\t\tif (y.query(ok) == g.yy) x.add(ok + 1, g.zz * 2);\n\t\t\t\telse x.add(ok, g.zz * 2);\n\t\t\t}\n\t\t}\n\t}\n\trep(i, n) {\n\t\tcout << (x.query(i) + y.query(i) - n + 1) / 2 << endl;\n\t}\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 12304, "score_of_the_acc": -0.4314, "final_rank": 8 }, { "submission_id": "aoj_0629_4184592", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Binary-Indexed-Tree(BIT)\n * @docs docs/binary-indexed-tree.md\n */\ntemplate< typename T >\nstruct BinaryIndexedTree {\n vector< T > data;\n\n BinaryIndexedTree() = default;\n\n explicit BinaryIndexedTree(size_t sz) : data(sz + 1, 0) {}\n\n void add(int k, const T &x) {\n for(++k; k < (int) data.size(); k += k & -k) data[k] += x;\n }\n\n T query(int k) const {\n T ret = T();\n for(++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n\n int lower_bound(T x) const {\n int i = 0;\n for(int k = 1 << (__lg(data.size() - 1) + 1); k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] < x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n\n int upper_bound(T x) const {\n int i = 0;\n for(int k = 1 << (__lg(data.size() - 1) + 1); k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] <= x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n};\n\nint main() {\n int N, Q;\n cin >> N >> Q;\n vector< int > X(Q), D(Q), L(Q);\n for(int i = 0; i < Q; i++) {\n cin >> X[i] >> D[i] >> L[i];\n }\n BinaryIndexedTree< int64 > xpy(N), xmy(N);\n for(int i = 0; i <= N; i++) xpy.data[i] = i & -i;\n for(int i = 0; i <= N; i++) xmy.data[i] = i & -i;\n for(int i = Q - 1; i >= 0; i--) {\n if(D[i] == 1) {\n xmy.add(0, -L[i] * 2);\n xmy.add(xpy.upper_bound(X[i]), L[i] * 2);\n } else {\n xpy.add(xmy.upper_bound(X[i]), L[i] * 2);\n }\n }\n for(int i = 0; i < N; i++) {\n cout << (xpy.query(i) - xmy.query(i)) / 2 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8384, "score_of_the_acc": -0.1144, "final_rank": 2 }, { "submission_id": "aoj_0629_4184588", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Binary-Indexed-Tree(BIT)\n * @docs docs/binary-indexed-tree.md\n */\ntemplate< typename T >\nstruct BinaryIndexedTree {\n vector< T > data;\n\n BinaryIndexedTree() = default;\n\n explicit BinaryIndexedTree(size_t sz) : data(sz + 1, 0) {\n for(int i = 0; i < data.size(); i++) data[i] = i & -i;\n }\n\n void add(int k, const T &x) {\n for(++k; k < (int) data.size(); k += k & -k) data[k] += x;\n }\n\n T query(int k) const {\n T ret = T();\n for(++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n\n int lower_bound(T x) const {\n int i = 0;\n for(int k = 1 << (__lg(data.size() - 1) + 1); k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] < x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n\n int upper_bound(T x) const {\n int i = 0;\n for(int k = 1 << (__lg(data.size() - 1) + 1); k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] <= x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n};\n\nint main() {\n int N, Q;\n cin >> N >> Q;\n vector< int > X(Q), D(Q), L(Q);\n for(int i = 0; i < Q; i++) {\n cin >> X[i] >> D[i] >> L[i];\n }\n BinaryIndexedTree< int64 > xpy(N), xmy(N);\n for(int i = Q - 1; i >= 0; i--) {\n if(D[i] == 1) {\n xmy.add(0, -L[i] * 2);\n xmy.add(xpy.upper_bound(X[i]), L[i] * 2);\n } else {\n xpy.add(xmy.upper_bound(X[i]), L[i] * 2);\n }\n }\n for(int i = 0; i < N; i++) {\n cout << (xpy.query(i) - xmy.query(i)) / 2 << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8388, "score_of_the_acc": -0.1145, "final_rank": 3 }, { "submission_id": "aoj_0629_4184576", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing int64 = long long;\nconst int mod = 1e9 + 7;\n// const int mod = 998244353;\n\nconst int64 infll = (1LL << 62) - 1;\nconst int inf = (1 << 30) - 1;\n\n\nstruct IoSetup {\n IoSetup() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n cerr << fixed << setprecision(10);\n }\n} iosetup;\n\n\ntemplate< typename T1, typename T2 >\nostream &operator<<(ostream &os, const pair< T1, T2 > &p) {\n os << p.first << \" \" << p.second;\n return os;\n}\n\ntemplate< typename T1, typename T2 >\nistream &operator>>(istream &is, pair< T1, T2 > &p) {\n is >> p.first >> p.second;\n return is;\n}\n\ntemplate< typename T >\nostream &operator<<(ostream &os, const vector< T > &v) {\n for(int i = 0; i < (int) v.size(); i++) {\n os << v[i] << (i + 1 != v.size() ? \" \" : \"\");\n }\n return os;\n}\n\ntemplate< typename T >\nistream &operator>>(istream &is, vector< T > &v) {\n for(T &in : v) is >> in;\n return is;\n}\n\ntemplate< typename T1, typename T2 >\ninline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\ntemplate< typename T1, typename T2 >\ninline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n\ntemplate< typename T = int64 >\nvector< T > make_v(size_t a) {\n return vector< T >(a);\n}\n\ntemplate< typename T, typename... Ts >\nauto make_v(size_t a, Ts... ts) {\n return vector< decltype(make_v< T >(ts...)) >(a, make_v< T >(ts...));\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value == 0 >::type fill_v(T &t, const V &v) {\n t = v;\n}\n\ntemplate< typename T, typename V >\ntypename enable_if< is_class< T >::value != 0 >::type fill_v(T &t, const V &v) {\n for(auto &e : t) fill_v(e, v);\n}\n\ntemplate< typename F >\nstruct FixPoint : F {\n FixPoint(F &&f) : F(forward< F >(f)) {}\n\n template< typename... Args >\n decltype(auto) operator()(Args &&... args) const {\n return F::operator()(*this, forward< Args >(args)...);\n }\n};\n\ntemplate< typename F >\ninline decltype(auto) MFP(F &&f) {\n return FixPoint< F >{forward< F >(f)};\n}\n\n/**\n * @brief Binary-Indexed-Tree(BIT)\n * @docs docs/binary-indexed-tree.md\n */\ntemplate< typename T >\nstruct BinaryIndexedTree {\n vector< T > data;\n\n BinaryIndexedTree() = default;\n\n explicit BinaryIndexedTree(size_t sz) : data(sz + 1, 0) {\n for(int i = 0; i < data.size(); i++) data[i] = i & -i;\n }\n\n void add(int k, const T &x) {\n for(++k; k < (int) data.size(); k += k & -k) data[k] += x;\n }\n\n T query(int k) const {\n T ret = T();\n for(++k; k > 0; k -= k & -k) ret += data[k];\n return ret;\n }\n\n int lower_bound(T x) const {\n if(x <= 0) return 0;\n int i = 0;\n\n int curr = 1;\n while(curr < data.size()) curr <<= 1;\n\n for(int k = curr; k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] < x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n\n int upper_bound(T x) const {\n int i = 0;\n\n\n int curr = 1;\n while(curr < data.size()) curr <<= 1;\n\n for(int k = curr; k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] <= x) {\n x -= data[i + k];\n i += k;\n }\n }\n return i;\n }\n};\n\n\nint N, Q;\nint X[200000], D[200000], L[200000];\nchar buff[32];\n\nint main() {\n scanf(\"%d %d\", &N, &Q);\n for(int i = 0; i < Q; i++) {\n scanf(\"%d %d %d\", &X[i], &D[i], &L[i]);\n }\n BinaryIndexedTree< int64 > xpy(N), xmy(N);\n for(int i = Q - 1; i >= 0; i--) {\n if(D[i] == 1) {\n xmy.add(0, -L[i] * 2);\n xmy.add(xpy.upper_bound(X[i]), L[i] * 2);\n } else {\n xpy.add(xmy.upper_bound(X[i]), L[i] * 2);\n }\n }\n for(int i = 0; i < N; i++) {\n printf(\"%lld\\n\", (xpy.query(i) - xmy.query(i)) / 2);\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8388, "score_of_the_acc": -0.1292, "final_rank": 6 }, { "submission_id": "aoj_0629_4184569", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long int64;\n\nstruct BinaryIndexedTree {\n vector< int64 > data;\n int curr;\n\n BinaryIndexedTree(int sz) {\n data.assign(++sz, 0);\n curr = 1;\n while(curr < data.size()) curr <<= 1;\n for(int i = 0; i < data.size(); i++) data[i] = i & -i;\n }\n\n inline int64 sum(int k) {\n int64 ret = 0;\n for(++k; k > 0; k -= k & -k) ret += data[k];\n return (ret);\n }\n\n inline int upper_bound(int64 w) {\n int i = 0;\n for(int k = curr; k > 0; k >>= 1) {\n if(i + k < data.size() && data[i + k] <= w) {\n w -= data[i + k];\n i += k;\n }\n }\n return (i);\n }\n\n inline void add(int k, int64 x) {\n for(++k; k < data.size(); k += k & -k) data[k] += x;\n }\n};\n\nint N, Q;\nint X[200000], D[200000], L[200000];\nchar buff[32];\n\nint main() {\n scanf(\"%d %d\", &N, &Q);\n for(int i = 0; i < Q; i++) {\n scanf(\"%d %d %d\", &X[i], &D[i], &L[i]);\n }\n BinaryIndexedTree xpy(N), xmy(N);\n for(int i = Q - 1; i >= 0; i--) {\n if(D[i] == 1) {\n xmy.add(0, -L[i] * 2);\n xmy.add(xpy.upper_bound(X[i]), L[i] * 2);\n } else {\n xpy.add(xmy.upper_bound(X[i]), L[i] * 2);\n }\n }\n for(int i = 0; i < N; i++) {\n printf(\"%lld\\n\", (xpy.sum(i) - xmy.sum(i)) / 2);\n }\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8384, "score_of_the_acc": -0.1291, "final_rank": 5 }, { "submission_id": "aoj_0629_3677149", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <typename T> using lim = numeric_limits<T>;\nconst int N = 500;\nint g[2*N+1][2*N+1];\nvoid debug() {\n for(int i = 0; i <= 2*N; i++) {\n for(int j = 0; j <= i; j++) {\n if((i + j) % 2 == 0) {\n cout << setw(2) << g[i][j];\n } else {\n cout << \"..\";\n }\n }\n cout << endl;\n }\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n for(int level = 0; level <= N; level++) {\n for(int r = 2 * level, c = 0; r <= 2 * N and c <= 2 * N; r++, c++) {\n g[r][c] = level;\n }\n }\n int n, q;\n cin >> n >> q;\n while(q--) {\n int x, d, l;\n cin >> x >> d >> l;\n x += N;\n if(d == 1) {\n for(int level = 0; level <= N; level++) {\n for(int r = 2 * level, c = 0; r < x and c <= 2 * N; r++, c++) {\n g[r][c] = c - 2 * l >= 0 ? g[r][c - 2 * l] : 0;\n }\n }\n } else {\n for(int level = 0; level <= N; level++) {\n vector<pair<int, int>> rc;\n for(int r = 2 * N, c = 2 * N - 2 * level; r >= 0 and c >= x; r--, c--) {\n g[r][c] = r + 2 * l <= 2 * N ? g[r + 2 * l][c] : 0;\n }\n }\n }\n }\n for(int i = 0; i < n; i++) {\n cout << g[i + N][i + N] << endl;\n }\n return 0;\n}", "accuracy": 0.225, "time_ms": 10, "memory_kb": 7112, "score_of_the_acc": 0, "final_rank": 20 }, { "submission_id": "aoj_0629_3656016", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 200005\n\nenum Type{\n\tX,\n\tY,\n};\n\nstruct Info{\n\tint loc,command;\n\tll diff;\n};\n\nint N = 1;\nll uniformity[8*NUM][2],partial[8*NUM][2];\nInfo info[NUM];\n\n\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid add_and_updateNodes(int left,int right,ll value,int node_id,int node_left,int node_right,Type type){\n\n\tif(right < node_left || left > node_right)return;\n\telse if(left <= node_left && right >= node_right){\n\t\tuniformity[node_id][type] += value;\n\t}else{\n\t\tpartial[node_id][type] += (min(right,node_right)-max(left,node_left)+1)*value;\n\t\tadd_and_updateNodes(left,right,value,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tadd_and_updateNodes(left,right,value,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t}\n}\n\nll getSum(int left,int right,int node_id,int node_left,int node_right,Type type){\n\tif(right < node_left || left > node_right)return 0;\n\telse if(left <= node_left && right >= node_right){\n\t\treturn (node_right-node_left+1)*uniformity[node_id][type]+partial[node_id][type];\n\n\t}else{\n\t\tll sum = (min(right,node_right)-max(left,node_left)+1)*uniformity[node_id][type];\n\t\tsum += getSum(left,right,2*node_id+1,node_left,(node_left+node_right)/2,type);\n\t\tsum += getSum(left,right,2*node_id+2,(node_left+node_right)/2+1,node_right,type);\n\t\treturn sum;\n\t}\n}\n\nint main(){\n\n\tint first_N,Q;\n\tscanf(\"%d %d\",&first_N,&Q);\n\n\tinit(first_N);\n\n\tfor(int i = 0; i <= 2*N-2; i++){\n\n\t\tuniformity[i][X] = 0;\n\t\tuniformity[i][Y] = 0;\n\n\t\tpartial[i][X] = 0;\n\t\tpartial[i][Y] = 0;\n\t}\n\n\tfor(int i = 0; i < Q; i++){\n\n\t\tscanf(\"%d %d %lld\",&info[i].loc,&info[i].command,&info[i].diff);\n\t}\n\n\tll L,R,mid,limit;\n\n\tfor(int i = Q-1; i >= 0; i--){\n\n\t\tif(info[i].command == 1){\n\n\t\t\tL = 0, R = first_N-1, mid = (L+R)/2;\n\t\t\tlimit = N;\n\n\t\t\twhile(L <=R){\n\n\t\t\t\tif(mid+getSum(mid,mid,0,0,N-1,X) >= info[i].loc){\n\n\t\t\t\t\tlimit = mid;\n\t\t\t\t\tR = mid-1;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tL = mid+1;\n\t\t\t\t}\n\t\t\t\tmid = (L+R)/2;\n\t\t\t}\n\n\t\t\tadd_and_updateNodes(0,limit-1,-2*info[i].diff,0,0,N-1,Y);\n\n\t\t}else{\n\n\t\t\tL = 0, R = first_N-1, mid = (L+R)/2;\n\t\t\tlimit = -1;\n\n\t\t\twhile(L <=R){\n\n\t\t\t\tif(mid+getSum(mid,mid,0,0,N-1,Y) < info[i].loc){\n\n\t\t\t\t\tlimit = mid;\n\t\t\t\t\tL = mid+1;\n\n\t\t\t\t}else{\n\n\t\t\t\t\tR = mid-1;\n\t\t\t\t}\n\t\t\t\tmid = (L+R)/2;\n\t\t\t}\n\n\t\t\tadd_and_updateNodes(limit+1,N-1,2*info[i].diff,0,0,N-1,X);\n\n\t\t}\n\t}\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tprintf(\"%lld\\n\",(getSum(i,i,0,0,N-1,X)-getSum(i,i,0,0,N-1,Y))/2);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 22732, "score_of_the_acc": -1.2074, "final_rank": 17 }, { "submission_id": "aoj_0629_3078880", "code_snippet": "//0:48\n#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\n#define N (1<<18)\nclass RAQ{\nprivate:\n ll dat[2*N];\n void dfs(int l,int r,int a,int b,int k,ll x){\n\tif(l<=a&&b<=r){dat[k]+=x;return;}\n\tif(b<=l||r<=a)return;\n\tdfs(l,r,a,(a+b)/2,k*2+1,x);\n\tdfs(l,r,(a+b)/2,b,k*2+2,x);\n }\npublic:\n void Init(int k){\n\tlol(i,2*N)dat[i]=0;\n\tlol(i,N)dat[i+N-1]=(i+1)*k;\n }\n void Add(int l,int r,ll x){\n\tif(l>r)return;\n\tdfs(l,r+1,0,N,0,x);\n }\n ll Sum(int i){\n\ti+=N-1;\n\tll res=dat[i];\n\twhile(i>0){\n\t i=(i-1)/2;\n\t res+=dat[i];\n\t}\n\treturn res;\n }\n};\nll n,q,a[N],b[N],c[N];\nint main(){\n cin>>n>>q;\n //lol(i,q)cin>>a[i]>>b[i]>>c[i];\n lol(i,q)scanf(\"%lld%lld%lld\",&a[i],&b[i],&c[i]);\n RAQ X,Y;X.Init(1);Y.Init(-1);\n for(int k=q-1;k>=0;k--){\n\tif(b[k]==1){\n\t int l=-1,r=n,m;\n\t while(l<r-1){\n\t\tm=(l+r)/2;\n\t\tif(X.Sum(m)<=a[k])l=m;\n\t\telse r=m;\n\t }\n\t Y.Add(0,l,c[k]*2);\n\t}\n\tif(b[k]==2){\n\t int l=-1,r=n,m;\n\t while(l<r-1){\n\t\tm=(l+r)/2;\n\t\tif(Y.Sum(m)<-a[k])r=m;\n\t\telse l=m;\n\t }\n\t X.Add(r,n-1,c[k]*2);\n\t}\n }\n //lol(i,n)cout<<(X.Sum(i)+Y.Sum(i))/2<<endl;\n lol(i,n){\n\tll ans=(X.Sum(i)+Y.Sum(i))/2;\n\tprintf(\"%lld\\n\",ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 16120, "score_of_the_acc": -0.4363, "final_rank": 9 }, { "submission_id": "aoj_0629_2671399", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define pb push_back\n#define all(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntypedef vector<int>vint;\ntypedef pair<int,int>pint;\ntypedef vector<pint>vpint;\n\ntemplate<typename A,typename B>inline void chmin(A &a,B b){if(a>b)a=b;}\ntemplate<typename A,typename B>inline void chmax(A &a,B b){if(a<b)a=b;}\n\nstruct segtree{\n static const int SEG=1<<18;\n vint put;\n segtree():put(SEG*2){}\n void add(int a,int b,int x,int k=0,int l=0,int r=SEG){\n if(r<=a||b<=l)return;\n if(a<=l&&r<=b){\n put[k]+=x;\n return;\n }\n add(a,b,x,k*2+1,l,(l+r)/2);\n add(a,b,x,k*2+2,(l+r)/2,r);\n }\n int query(int k){\n k+=SEG-1;\n int ret=0;\n while(true){\n ret+=put[k];\n if(k==0)break;\n k=(k-1)/2;\n }\n return ret;\n }\n};\n\nsigned main(){\n int N,Q;\n scanf(\"%lld%lld\",&N,&Q);\n\n segtree segX,segY;\n rep(i,N)segX.add(i,i+1,2*i+1);\n\n\n vector<tuple<int,int,int>>qs;\n rep(i,Q){\n int x,d,l;\n scanf(\"%lld%lld%lld\",&x,&d,&l);\n x*=2;\n qs.pb(make_tuple(x,d,l));\n }\n for(int i=Q-1;i>=0;i--){\n int x,d,l;\n tie(x,d,l)=qs[i];\n if(d==1){\n int lb=-1,ub=N;\n while(ub-lb>1){\n int mid=(ub+lb)/2;\n int xx=segX.query(mid);\n\n int yy=segY.query(mid);\n if(-(x-xx)<yy*2)lb=mid;\n else ub=mid;\n }\n segX.add(0,ub,-2*l);\n segY.add(0,ub,-l);\n }\n else{\n int lb=-1,ub=N;\n while(ub-lb>1){\n int mid=(ub+lb)/2;\n\n int xx=segX.query(mid);\n int yy=segY.query(mid);\n if(-(xx-x)<yy*2)ub=mid;\n else lb=mid;\n }\n segX.add(ub,N,2*l);\n segY.add(ub,N,-l);\n }\n }\n\n rep(i,N){\n int y=segY.query(i);\n printf(\"%lld\\n\",-y);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 17316, "score_of_the_acc": -0.6953, "final_rank": 11 }, { "submission_id": "aoj_0629_2669200", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nint n;\n\nclass BIT{\n\tvector<int> bit;\npublic:\n\tBIT() : bit(n + 2){}\n\tvoid add(int i,int x){\n\t\twhile(i < bit.size()){\n\t\t\tbit[i] += x;\n\t\t\ti += i & -i;\n\t\t}\n\t}\n\tint get(int i){\n\t\tint s = 0;\n\t\twhile(i){\n\t\t\ts += bit[i];\n\t\t\ti -= i & -i;\n\t\t}\n\t\treturn s;\n\t}\n};\n\nsigned main(){\n\tint q,x[200000],d[200000],l[200000];\n\tcin >> n >> q;\n\tvector<BIT> ps(2);\n\tps[1].add(1,n - 1);\n\tfor(int i = 1;i < n;i++){\n\t\tps[0].add(i + 1,1);\n\t\tps[1].add(i + 1,-1);\n\t}\n\tfor(int i = 0;i < q;i++) cin >> x[i] >> d[i] >> l[i];\n\tfor(int i = q - 1;i >= 0;i--){\n\t\tint low = -1,up = n;\n\t\twhile(up - low > 1){\n\t\t\tint mid = (up + low) / 2;\n\t\t\tif(d[i] == 1){\n\t\t\t\tif(ps[0].get(mid + 1) < x[i]) low = mid;\n\t\t\t\telse up = mid;\n\t\t\t}else{\n\t\t\t\tif(ps[1].get(mid + 1) < n - x[i]) up = mid;\n\t\t\t\telse low = mid;\n\t\t\t}\n\t\t}\n\t\tif(d[i] == 1){\n\t\t\tps[1].add(1,l[i] * 2);\n\t\t\tps[1].add(up + 1,-l[i] * 2);\n\t\t}\n\t\telse ps[0].add(up + 1,l[i] * 2);\n\t}\n\tfor(int i = 0;i < n;i++) cout << (ps[0].get(i + 1) + ps[1].get(i + 1) - n + 1) / 2 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 10640, "score_of_the_acc": -0.628, "final_rank": 10 }, { "submission_id": "aoj_0629_2669190", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nint seg = 1;\n\nclass RAQ{\n\tvector<int> dat;\npublic:\n\tRAQ() : dat(seg * 2 - 1){}\n\tvoid add(int a,int b,int x,int k = 0,int l = 0,int r = seg){\n\t\tif(b <= l || r <= a) return;\n\t\tif(a <= l && r <= b){\n\t\t\tdat[k] += x;\n\t\t\treturn;\n\t\t}\n\t\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\t\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\t}\n\tint get(int i){\n\t\tint s = 0;\n\t\ti += seg - 1;\n\t\ts += dat[i];\n\t\twhile(i){\n\t\t\ti = (i - 1) / 2;\n\t\t\ts += dat[i];\n\t\t}\n\t\treturn s;\n\t}\n};\n\nsigned main(){\n\tint n,q,x[200000],d[200000],l[200000];\n\tcin >> n >> q;\n\twhile(seg < n) seg *= 2;\n\tvector<RAQ> ps(2);\n\tfor(int i = 0;i < n;i++){\n\t\tps[0].add(i,i + 1,i);\n\t\tps[1].add(i,i + 1,n - i - 1);\n\t}\n\tfor(int i = 0;i < q;i++) cin >> x[i] >> d[i] >> l[i];\n\tfor(int i = q - 1;i >= 0;i--){\n\t\tint low = -1,up = n;\n\t\twhile(up - low > 1){\n\t\t\tint mid = (up + low) / 2;\n\t\t\tif(d[i] == 1){\n\t\t\t\tif(ps[0].get(mid) < x[i]) low = mid;\n\t\t\t\telse up = mid;\n\t\t\t}else{\n\t\t\t\tif(ps[1].get(mid) < n - x[i]) up = mid;\n\t\t\t\telse low = mid;\n\t\t\t}\n\t\t}\n\t\tif(d[i] == 1) ps[1].add(0,up,l[i] * 2);\n\t\telse ps[0].add(up,seg,l[i] * 2);\n\t}\n\tfor(int i = 0;i < n;i++) cout << (ps[0].get(i) + ps[1].get(i) - n + 1) / 2 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 15712, "score_of_the_acc": -0.8791, "final_rank": 14 }, { "submission_id": "aoj_0629_2669187", "code_snippet": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nint seg = 1;\n\nclass RAQ{\n\tvector<int> dat;\npublic:\n\tRAQ() : dat(seg * 2 - 1){}\n\tvoid add(int a,int b,int x,int k = 0,int l = 0,int r = seg){\n\t\tif(b <= l || r <= a) return;\n\t\tif(a <= l && r <= b){\n\t\t\tdat[k] += x;\n\t\t\treturn;\n\t\t}\n\t\tadd(a,b,x,k * 2 + 1,l,(l + r) / 2);\n\t\tadd(a,b,x,k * 2 + 2,(l + r) / 2,r);\n\t}\n\tint get(int i){\n\t\tint s = 0;\n\t\ti += seg - 1;\n\t\ts += dat[i];\n\t\twhile(i){\n\t\t\ti = (i - 1) / 2;\n\t\t\ts += dat[i];\n\t\t}\n\t\treturn s;\n\t}\n};\n\nsigned main(){\n\tint n,q,x[100000],d[100000],l[100000];\n\tcin >> n >> q;\n\twhile(seg < n) seg *= 2;\n\tvector<RAQ> ps(2);\n\tfor(int i = 0;i < n;i++){\n\t\tps[0].add(i,i + 1,i);\n\t\tps[1].add(i,i + 1,n - i - 1);\n\t}\n\tfor(int i = 0;i < q;i++) cin >> x[i] >> d[i] >> l[i];\n\tfor(int i = q - 1;i >= 0;i--){\n\t\tint low = -1,up = n;\n\t\twhile(up - low > 1){\n\t\t\tint mid = (up + low) / 2;\n\t\t\tif(d[i] == 1){\n\t\t\t\tif(ps[0].get(mid) < x[i]) low = mid;\n\t\t\t\telse up = mid;\n\t\t\t}else{\n\t\t\t\tif(ps[1].get(mid) < n - x[i]) up = mid;\n\t\t\t\telse low = mid;\n\t\t\t}\n\t\t}\n\t\tif(d[i] == 1) ps[1].add(0,up,l[i] * 2);\n\t\telse ps[0].add(up,seg,l[i] * 2);\n\t}\n\tfor(int i = 0;i < n;i++) cout << (ps[0].get(i) + ps[1].get(i) - n + 1) / 2 << endl;\n\treturn 0;\n}", "accuracy": 0.6, "time_ms": 70, "memory_kb": 15196, "score_of_the_acc": -0.3478, "final_rank": 19 }, { "submission_id": "aoj_0629_2650879", "code_snippet": "#include <cstdio>\n#pragma warning(disable : 4996)\nint N, Q, X[200009], D[200009], L[200009]; long long bit[2][262156];\nvoid add(int t, int p, int x) {\n\tfor (int i = p + 1; i <= 262144; i += i & (-i)) {\n\t\tbit[t][i] += x;\n\t}\n}\nlong long sum(int t, int p) {\n\tlong long ret = 0;\n\tfor (int i = p; i >= 1; i -= i & (-i)) {\n\t\tret += bit[t][i];\n\t}\n\treturn ret;\n}\nint bs(int t, long long x) {\n\tif (x <= 0) return 0;\n\tint cur = 0;\n\tfor (int i = 17; i >= 0; i--) {\n\t\tif (bit[t][cur + (1 << i)] < x) {\n\t\t\tcur += 1 << i;\n\t\t\tx -= bit[t][cur];\n\t\t}\n\t}\n\treturn cur + 1;\n}\nint main() {\n\tscanf(\"%d %d\", &N, &Q);\n\tfor (int i = 0; i < Q; i++) scanf(\"%d %d %d\", &X[i], &D[i], &L[i]);\n\tfor (int i = 1; i < N; i++) add(0, i, 1), add(1, i, 1);\n\tlong long cs = 0, ct = 0;\n\tfor (int i = Q - 1; i >= 0; i--) {\n\t\tif (D[i] == 1) {\n\t\t\tint pr = bs(0, X[i] + ct) - 1;\n\t\t\tif(pr != -1) add(1, pr, 2 * L[i]);\n\t\t\telse cs -= 2 * L[i];\n\t\t\tcs += 2 * L[i];\n\t\t}\n\t\telse {\n\t\t\tint pr = bs(1, X[i] + cs) - 1;\n\t\t\tif(pr != -1) add(0, pr, 2 * L[i]);\n\t\t\telse ct -= 2 * L[i];\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tlong long px = sum(0, i + 1), py = sum(1, i + 1);\n\t\tprintf(\"%lld\\n\", (px - py + cs - ct) / 2);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 8252, "score_of_the_acc": -0.1101, "final_rank": 1 }, { "submission_id": "aoj_0629_2641423", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nclass RangeAddQuery {\npublic:\n\tvector<long long>bit; int size__;\n\n\tvoid initialize(int size_) {\n\t\tsize__ = size_;\n\t\tbit.resize(size_ + 4, 0);\n\t}\n\tint size() {\n\t\treturn size__;\n\t}\n\tvoid Add(int p, int x) {\n\t\tp++;\n\t\twhile (p < size__ + 4) { bit[p] += x; p += (p&-p); }\n\t}\n\tlong long Sum(int p) {\n\t\tlong long s = 0; p++;\n\t\twhile (p >= 1) { s += bit[p]; p -= (p&-p); }\n\t\treturn s;\n\t}\n\tvoid add(int l, int r, int x) {\n\t\t// Add x in range [l, r)\n\t\tAdd(l, x); Add(r, -x);\n\t}\n\tlong long get(int pos) {\n\t\treturn Sum(pos);\n\t}\n};\n\nlong long N, Q, a[200009], b[200009], c[200009];\nint main() {\n\tcin >> N >> Q;\n\tRangeAddQuery R1, R2; R1.initialize(N + 1); R2.initialize(N + 1);\n\tfor (int i = 1; i <= N; i++) { R1.add(i, i + 1, i); R2.add(i, i + 1, i); }\n\tfor (int i = 1; i <= Q; i++) { cin >> a[i] >> b[i] >> c[i]; }\n\tfor (int i = Q; i >= 1; i--) {\n\t\tif (b[i] == 1) {\n\t\t\tint L = 1, R = N + 1, M, maxn = -1;\n\t\t\tfor (int j = 0; j < 20; j++) {\n\t\t\t\tM = (L + R) / 2;\n\t\t\t\tif (R1.get(M) <= a[i]) { maxn = max(maxn, M); L = M; }\n\t\t\t\telse { R = M; }\n\t\t\t}\n\t\t\tR2.add(1, maxn + 1, -c[i] * 2);\n\t\t}\n\t\telse {\n\t\t\tint L = 1, R = N + 1, M, maxn = 999999;\n\t\t\tfor (int j = 0; j < 20; j++) {\n\t\t\t\tM = (L + R) / 2;\n\t\t\t\tif (R2.get(M) > a[i]) { maxn = min(maxn, M); R = M; }\n\t\t\t\telse { L = M; }\n\t\t\t}\n\t\t\tR1.add(maxn, N + 1, c[i] * 2);\n\t\t}\n\t\t//for (int i = 1; i <= N; i++)cout << (R1.get(i) - R2.get(i)) / 2 << \" \"; cout << endl;\n\t}\n\tfor (int i = 1; i <= N; i++)cout << (R1.get(i) - R2.get(i)) / 2 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 10760, "score_of_the_acc": -0.7054, "final_rank": 13 }, { "submission_id": "aoj_0629_2628297", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <array>\n#include <cstdint>\n#include <functional>\n#include <map>\n#include <math.h>\n#include <queue>\n#include <set>\n#include <stdlib.h>\n#include <string>\n#include <utility>\n#include <vector>\n\n#define INF 1000000000\n#define LINF 1e18\n#define MOD 1000000007\n#define ll long long\n#define rep(i,a,b) for(int32 i = (a); i < (b); ++i)\n#define rrep(i,a,b) for(int32 i = (b) - 1; i >= (a); --i)\n#define bitget(a,b) (((a) >> (b)) & 1)\n#define vint vector<int>\n#define ALL(x) (x).begin(),(x).end()\n#define C(x) cout << #x << \" : \" << x << endl\n#define scanf scanf_s\n\nusing int32 = int_fast32_t;\nusing int64 = int_fast64_t;\nusing uint32 = uint_fast32_t;\nusing uint64 = uint_fast64_t;\n\nusing namespace std;\n\ntemplate<typename Monoid>\nclass BIT {\npublic:\n\tsize_t len, size;\n\tMonoid* arr;\n\tMonoid* tree;\n\tuint32 i;\n\t//?????????????????????\n\tBIT(const size_t &length) {\n\t\tlen = length;\n\t\tsize = length;\n\t\tif (size & 0xffff0000) { size = size & 0xffff0000; }\n\t\tif (size & 0xff00ff00) { size = size & 0xff00ff00; }\n\t\tif (size & 0xf0f0f0f0) { size = size & 0xf0f0f0f0; }\n\t\tif (size & 0xcccccccc) { size = size & 0xcccccccc; }\n\t\tif (size & 0xaaaaaaaa) { size = size & 0xaaaaaaaa; }\n\t\tsize <<= 1;\n\t\ttree = (Monoid *)calloc(size, sizeof(Monoid));\n\t}\n\t//0?????????\n\tvoid set() {\n\t\tfor (i = 0; i < size; ++i) tree[i] = 0;\n\t}\n\t//array??§?????????\n\tvoid set(Monoid* array) {\n\t\t--array;\n\t\tfor (i = 1; i <= len; ++i) {\n\t\t\ttree[i] = array[i] + range(i);\n\t\t}\n\t\t++array;\n\t}\n\t//[0,a)???????????????\n\tMonoid range(size_t a) {\n\t\tMonoid ret = tree[a];\n\t\ta &= a - 1;\n\t\twhile (a) {\n\t\t\tret += tree[a];\n\t\t\ta &= a - 1;\n\t\t}\n\t\treturn ret;\n\t}\n\t//index:a???data?????????\n\tvoid update(const size_t &a, const Monoid &data) {\n\t\tint32 b = int32(a);\n\t\t++b;\n\t\twhile (b < size) {\n\t\t\ttree[b] += data;\n\t\t\tb += b&(-b);\n\t\t}\n\t}\n\t//\n\tsize_t up_b(Monoid data) {\n\t\tsize_t s = size >> 1;\n\t\tsize_t t = size;\n\t\tsize_t ret = 0;\n\t\twhile (t>>=1) {\n\t\t\tif (tree[s] <= data) {\n\t\t\t\tdata -= tree[s];\n\t\t\t\ts += t >> 1;\n\t\t\t\tret += t;\n\t\t\t}\n\t\t\telse {\n\t\t\t\ts -= t >> 1;\n\t\t\t}\n\t\t}\n\t\treturn ret;\n\t}\n};\n\nstruct IN {\n\tint32 x, d, l;\n};\n\nint main() {\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsize_t n, q;\n\tcin >> n >> q;\n\tvector<int64> ans(n+1, 0);\n\tvector<IN> t(q);\n\trep(i, 0, q)\n\t\tcin >> t[i].x >> t[i].d >> t[i].l;\n\tBIT<int64> R(n), L(n);\n\tR.set();L.set();\n\trep(i, 0, n) {\n\t\tR.update(i, 1);\n\t\tL.update(i, 1);\n\t}\n\tR.update(n, LINF);\n\tL.update(n, LINF);\n\tsize_t temp;\n\tfor (int32 i = q - 1;~i;--i) {\n\t\tif (t[i].d == 1) {\n\t\t\ttemp = L.up_b(t[i].x);\n\t\t\tans[0] += t[i].l;\n\t\t\tans[temp] -= t[i].l;\n\t\t\tR.update(n - temp, t[i].l << 1);\n\t\t}\n\t\telse {\n\t\t\ttemp = n - R.up_b(n - t[i].x);\n\t\t\tans[temp] += t[i].l;\n\t\t\tans[n] -= t[i].l;\n\t\t\tL.update(temp, t[i].l << 1);\n\t\t}\n\t}\n\trep(i, 0, n)\n\t\tans[i + 1] += ans[i];\n\trep(i, 0, n)\n\t\tprintf(\"%lld\\n\", ans[i]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 13112, "score_of_the_acc": -0.2809, "final_rank": 7 } ]
aoj_0633_cpp
ぬいぐるみの整理 (Plush Toys) 問題 ある JOI 関係者は,おもちゃ屋で働いている.今日は,店内にあるぬいぐるみコーナーの整理をすることになった. ぬいぐるみコーナーの棚には,N 個のぬいぐるみが左から右に一列に並べられている.棚は仕切りにより N 個の区画に区切られており,1 つの区画に 1 個のぬいぐるみを置く.このおもちゃ屋は合計 M 種類のぬいぐるみを売っており,それぞれ 1 から M までの番号が付けられている.棚に並べられた N 個のぬいぐるみは,それぞれこの M 種類のうちのいずれかである.また,それぞれの種類のぬいぐるみは,少なくとも 1 個は存在する. 見栄えを良くするため,同じ種類のぬいぐるみが全て連続して棚に置かれるように,ぬいぐるみを並べ替えたい.次のような方法で,ぬいぐるみを並べ替えることにした. N 個のぬいぐるみのうちいくつかを選び,棚から取り出す.取り出さなかったぬいぐるみの位置は動かさない. 取り出したぬいぐるみを,好きな順に棚の空いている区画に戻していく. 並べ替えた後,同じ種類のぬいぐるみが全て連続して棚に置かれていなければならない. 並べ替えるために取り出すぬいぐるみの個数の最小値を求めるプログラムを作成せよ. 入力 入力は 1 + N 行からなる. 1 行目には 2 個の整数 N, M (1 ≦ N ≦ 100000, 1 ≦ M ≦ 20) が空白を区切りとして書かれており,ぬいぐるみが N 個あり,種類が M 種類あることを表す. 続く N 行のそれぞれには,1 以上 M 以下の整数が書かれている. N 行のうちの i 行目 (1 ≦ i ≦ N) に書かれた整数は,棚の左から i 番目の区画に置かれたぬいぐるみの種類を表す.各種類について,少なくとも 1 個のぬいぐるみが存在していることが保証される. 出力 並べ替えるために取り出すぬいぐるみの個数の最小値を 1 行で出力せよ. 入出力例 入力例 1 7 2 1 2 2 2 1 2 1 出力例 1 2 入力例 2 12 4 1 3 2 4 2 1 2 3 1 1 3 4 出力例 2 7 入力例 1 においては,最初に置かれているぬいぐるみの種類は左から順に 1, 2, 2, 2, 1, 2, 1 である.並べ替えるために取り出すぬいぐるみの個数を最小にするには,左から 1 番目と 6 番目のぬいぐるみを取り出し,左から 1 番目に種類 2 のぬいぐるみを,左から 6 番目に種類 1 のぬいぐるみを配置すればよい.このとき,取り出すぬいぐるみの個数は 2 個である. 情報オリンピック日本委員会作 『第 16 回日本情報オリンピック JOI 2016/2017 予選競技課題』
[ { "submission_id": "aoj_0633_10851165", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ALL(a) a.begin(),a.end()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define debug(x) cerr << #x << \": \" << x << endl\n\nusing LL = long long; template<class T> using V = vector<T>;\n\n\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint N, M; cin >> N >> M;\n\tV<int>toy(N);\n\tFOR(i, 0, N) {\n\t\tcin >> toy[i]; toy[i]--;\n\t}\n\n\t// pre\n\tV<V<int>>pinfo(M, V<int>(N + 1, 0));\n\tFOR(i, 0, N) {\n\t\tpinfo[toy[i]][i+1]++;\n\t}\n\tFOR(i, 0, M) {\n\t\tFOR(j, 0, N) {\n\t\t\tpinfo[i][j + 1] += pinfo[i][j];\n\t\t}\n\t}\n\n\t// bitdp[state][ketu]:= 先頭から決定していったときに\n\t// stateを配置したとき最後がketuの最小の個数\n\n\t// \n\tconst int INF = 1e9;\n\tV<V<int>>bitdp(1 << M,V<int>(M,INF));\n\tbitdp[0][0] = 0;\n\tFOR(i, 0, M) {\n\t\tint LEN = pinfo[i][N];\n\t\tbitdp[1 << i][i] = pinfo[i][N]- pinfo[i][LEN];\n\t}\n\tFOR(state, 0, 1 << M) {\n\t\tFOR(i, 0, M) {\n\t\t\tif (!(state & 1 << i))continue;\n\t\t\tif (bitdp[state][i] == INF)continue;\n\t\t\tFOR(k, 0, M) {\n\t\t\t\tif (state & 1 << k)continue;\n\t\t\t\tint LEN = 0;\n\t\t\t\tFOR(yet, 0, M)if (state & 1 << yet)LEN += pinfo[yet][N];\n\t\t\t\tint addlen = pinfo[k][N];\n\t\t\t\t// LEN + [0/1] = LEN + addlen\n\t\t\t\tint cost = addlen-(pinfo[k][LEN+addlen] - pinfo[k][LEN]);\n\t\t\t\t// cost = LEN - pinfo[k][LEN]\n\t\t\t\tint nx = state | (1 << k);\n\t\t\t\tbitdp[nx][k] = min(bitdp[nx][k], bitdp[state][i] + cost);\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = INF;\n\tFOR(i, 0, M) {\n\t\tans = min(ans, bitdp[(1 << M) - 1][i]);\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1710, "memory_kb": 134136, "score_of_the_acc": -1.3021, "final_rank": 17 }, { "submission_id": "aoj_0633_8930815", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 1 \"/home/kuhaku/home/github/algo/lib/data_structure/wavelet_matrix.hpp\"\n#include <cassert>\n#include <tuple>\n#include <vector>\n#line 2 \"/home/kuhaku/home/github/algo/lib/data_structure/bit_vector.hpp\"\n\n/**\n * @brief 完備辞書\n *\n * @see https://ei1333.github.io/library/structure/wavelet/succinct-indexable-dictionary.hpp\n */\nstruct bit_vector {\n bit_vector() = default;\n bit_vector(unsigned int _length)\n : length(_length), blocks((_length + 31) >> 5), bit((_length + 31) >> 5),\n sum((_length + 31) >> 5) {}\n\n void set(unsigned int k) { bit[k >> 5] |= 1U << (k & 31); }\n\n void build() {\n sum[0] = 0U;\n for (unsigned int i = 1; i < blocks; ++i) {\n sum[i] = sum[i - 1] + __builtin_popcount(bit[i - 1]);\n }\n }\n\n bool operator[](unsigned int k) const { return bit[k >> 5] >> (k & 31) & 1; }\n\n unsigned int rank(unsigned int k) const {\n return sum[k >> 5] + __builtin_popcount(bit[k >> 5] & ((1U << (k & 31)) - 1));\n }\n unsigned int rank(bool val, unsigned int k) const { return val ? rank(k) : k - rank(k); }\n\n unsigned int select(unsigned int k) const {\n unsigned int sl = 0, sr = blocks + 1;\n while (sr - sl > 1) {\n unsigned int m = (sl + sr) >> 1;\n if (sum[m] < k) sl = m;\n else sr = m;\n }\n k -= sum[sl];\n unsigned int bl = 0, br = 32;\n while (br - bl > 1) {\n unsigned int m = (bl + br) >> 1;\n if (__builtin_popcount(bit[sl] & ((1U << m) - 1)) < k) bl = m;\n else br = m;\n }\n return (sl << 5) + bl;\n }\n\n private:\n unsigned int length, blocks;\n std::vector<unsigned int> bit, sum;\n};\n#line 5 \"/home/kuhaku/home/github/algo/lib/data_structure/wavelet_matrix.hpp\"\n\n/**\n * @brief ウェーブレット行列\n * @see https://ei1333.github.io/library/structure/wavelet/wavelet-matrix.hpp\n *\n * @tparam T\n * @tparam L\n */\ntemplate <class T, int L = 20>\nstruct wavelet_matrix {\n wavelet_matrix() = default;\n wavelet_matrix(std::vector<T> v) : length(v.size()) {\n std::vector<T> l(length), r(length);\n for (int level = L - 1; level >= 0; --level) {\n matrix[level] = bit_vector(length + 1);\n int left = 0, right = 0;\n for (int i = 0; i < length; ++i) {\n if (v[i] >> level & 1) {\n matrix[level].set(i);\n r[right++] = v[i];\n } else {\n l[left++] = v[i];\n }\n }\n mid[level] = left;\n matrix[level].build();\n v.swap(l);\n for (int i = 0; i < right; ++i) v[left + i] = r[i];\n }\n }\n\n T access(int k) const {\n T res = 0;\n for (int level = L - 1; level >= 0; --level) {\n bool f = matrix[level][k];\n if (f) res |= T(1) << level;\n k = matrix[level].rank(f, k) + mid[level] * f;\n }\n return res;\n }\n T operator[](int k) const { return access(k); }\n\n /**\n * @brief count i s.t. (0 <= i < r) && v[i] == x\n *\n * @param x\n * @param r\n * @return int\n */\n int rank(int r, T x) const {\n int l = 0;\n for (int level = L - 1; level >= 0; --level) {\n std::tie(l, r) = succ((x >> level) & 1, l, r, level);\n }\n return r - l;\n }\n\n /**\n * @brief count i s.t. (l <= i < r) && v[i] == x\n *\n * @param l\n * @param r\n * @param x\n * @return int\n */\n int rank(int l, int r, T x) const { return rank(r, x) - rank(l, x); }\n\n /**\n * @brief k-th smallest number in v[l ... r-1]\n *\n * @param l\n * @param r\n * @param k\n * @return T\n */\n T kth_smallest(int l, int r, int k) const {\n assert(0 <= k && k < r - l);\n T res = 0;\n for (int level = L - 1; level >= 0; --level) {\n int cnt = matrix[level].rank(false, r) - matrix[level].rank(false, l);\n bool f = cnt <= k;\n if (f) {\n res |= T(1) << level;\n k -= cnt;\n }\n std::tie(l, r) = succ(f, l, r, level);\n }\n return res;\n }\n\n /**\n * @brief k-th largest number in v[l ... r-1]\n *\n * @param l\n * @param r\n * @param k\n * @return T\n */\n T kth_largest(int l, int r, int k) const { return kth_smallest(l, r, r - l - k - 1); }\n\n /**\n * @brief count i s.t. (l <= i < r) && (v[i] < upper)\n *\n * @param l\n * @param r\n * @param upper\n * @return int\n */\n int range_freq(int l, int r, T upper) const {\n int res = 0;\n for (int level = L - 1; level >= 0; --level) {\n bool f = ((upper >> level) & 1);\n if (f) res += matrix[level].rank(false, r) - matrix[level].rank(false, l);\n std::tie(l, r) = succ(f, l, r, level);\n }\n return res;\n }\n\n /**\n * @brief count i s.t. (l <= i < r) && (lower <= v[i] < upper)\n *\n * @param l\n * @param r\n * @param lower\n * @param upper\n * @return int\n */\n int range_freq(int l, int r, T lower, T upper) const {\n return range_freq(l, r, upper) - range_freq(l, r, lower);\n }\n\n /**\n * @brief max v[i] s.t. (l <= i < r) && (v[i] < upper)\n *\n * @param l\n * @param r\n * @param upper\n * @return T\n */\n T prev_value(int l, int r, T upper) const {\n int cnt = range_freq(l, r, upper);\n return cnt == 0 ? T(-1) : kth_smallest(l, r, cnt - 1);\n }\n\n /**\n * @brief min v[i] s.t. (l <= i < r) && (lower <= v[i])\n *\n * @param l\n * @param r\n * @param lower\n * @return T\n */\n T next_value(int l, int r, T lower) const {\n int cnt = range_freq(l, r, lower);\n return cnt == r - l ? T(-1) : kth_smallest(l, r, cnt);\n }\n\n private:\n int length;\n bit_vector matrix[L];\n int mid[L];\n\n std::pair<int, int> succ(bool f, int l, int r, int level) const {\n return {matrix[level].rank(f, l) + mid[level] * f,\n matrix[level].rank(f, r) + mid[level] * f};\n }\n};\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/vector.hpp\"\n\nstruct increment_impl {\n template <class T>\n const increment_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) ++x;\n return *this;\n }\n} Inc;\n\nstruct decrement_impl {\n template <class T>\n const decrement_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) --x;\n return *this;\n }\n} Dec;\n\nstruct sort_impl {\n template <class T>\n const sort_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n return *this;\n }\n} Sort;\n\nstruct unique_impl {\n template <class T>\n const unique_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n v.erase(std::unique(v.begin(), v.end()), v.end());\n return *this;\n }\n} Uniq;\n#line 5 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n vector<int> a(n);\n cin >> a;\n Dec >> a;\n vector<int> s(m);\n for (auto x : a) ++s[x];\n wavelet_matrix wm(a);\n vector<int> dp(1 << m, Inf);\n dp[0] = 0;\n rep (bit, 1 << m) {\n int sum = 0;\n rep (i, m) {\n if (bit >> i & 1)\n sum += s[i];\n }\n rep (i, m) {\n if (bit >> i & 1)\n continue;\n chmin(dp[bit | (1 << i)], dp[bit] + s[i] - wm.rank(sum, sum + s[i], i));\n }\n }\n co(dp.back());\n\n return 0;\n}", "accuracy": 1, "time_ms": 1750, "memory_kb": 7860, "score_of_the_acc": -0.3414, "final_rank": 13 }, { "submission_id": "aoj_0633_8257238", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tvector<int> a(n);\n\tfor (int &e : a) cin >> e;\n\n\tvector<vector<int>> cnt(m, vector<int>(n + 1));\n\tfor (int i = 0; i < m; ++i) {\n\t\tfor (int j = 0; j < n; ++j) cnt[i][j + 1] = cnt[i][j] + (a[j] == i + 1);\n\t}\n\tvector<int> sum(1 << m);\n\tfor (int bit = 1; bit < (1 << m); ++bit) {\n\t\tfor (int i = 0; i < m; ++i) {\n\t\t\tif (bit & (1 << i)) sum[bit] += cnt[i][n];\n\t\t}\n\t}\n\n\tvector<int> dp(1 << m, 1e9);\n\tdp[0] = 0;\n\tfor (int bit = 0; bit < (1 << m); ++bit) {\n\t\tfor (int i = 0; i < m; ++i) {\n\t\t\tif (bit & (1 << i)) continue;\n\t\t\tint l = sum[bit], r = sum[bit | (1 << i)];\n\t\t\tdp[bit | (1 << i)] =\n\t\t\t\tmin(dp[bit | (1 << i)], dp[bit] + r - l - (cnt[i][r] - cnt[i][l]));\n\t\t}\n\t}\n\tcout << dp.back() << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 19268, "score_of_the_acc": -0.1067, "final_rank": 7 }, { "submission_id": "aoj_0633_8046408", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\nusing namespace std;\n\nstruct E{\n\tint point;\n\tint perm;\n\tbool operator<(const E &e)const{\n\t\treturn perm<e.perm;\n\t}\n};\n\nvector<int> count,data,dp,ruiseki[21];\nmap<E,int> ms;\n\nint f(){\n\tint n,m;\n\tcin>>n>>m;\n\t\n\t\n\tfor(int i=0;i<=m;i++){\n\t\tcount.push_back(0);\n\t}\n\t\n\tfor(int i=0;i<=n;i++){\n\t\tint t=0;\n\t\tif(i==0){\n\t\t\tdata.push_back(0);\n\t\t}else{\n\t\t\tcin>>t;\n\t\t\tdata.push_back(t);\n\t\t\tcount[t]++;\n\t\t}\n\t\tdp.push_back(-1);\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tif(i==0){\n\t\t\t\truiseki[j].push_back(0);\n\t\t\t}else{\n\t\t\t\truiseki[j].push_back(ruiseki[j][i-1]+(j==t?0:1));\n\t\t\t}\n\t\t}\n\t}\n\tE e;\n\te.perm=0;\n\te.point=0;\n\tms[e]=0;\n\tfor(int i=1;i<=m;i++){\n\t\tmap<E,int> ms2;\n\t\tfor(map<E,int>::iterator it=ms.begin();it!=ms.end();it++){\n\t\t\tE e=(*it).first;\n\t\t\tint ans=(*it).second;\n\t\t\tfor(int j=1;j<=m;j++){\n\t\t\t\tint p1=1<<(j-1);\n\t\t\t\tif((e.perm&p1)>0)continue;\n\t\t\t\tE e2;\n\t\t\t\te2.perm=(e.perm|p1);\n\t\t\t\te2.point=e.point+count[j];\n\t\t\t\tint ans2=ans+ruiseki[j][e2.point]-ruiseki[j][e.point];\n\t\t\t\tif(ms2.find(e2)==ms2.end()||ms2[e2]>ans2){\n\t\t\t\t\tms2[e2]=ans2;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tms.clear();\n\t\tms.insert(ms2.begin(),ms2.end());\n\t}\n\tcout<<(*(ms.begin())).second<<endl;\n\t\n\treturn 0;\n}\n\nint main() {\n\tf();\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1640, "memory_kb": 34696, "score_of_the_acc": -0.5258, "final_rank": 16 }, { "submission_id": "aoj_0633_8046280", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint f(){\n\tint n,m;\n\tcin>>n>>m;\n\tvector<int> count,data,dp,ruiseki[21];\n\t\n\tfor(int i=0;i<=m;i++){\n\t\tcount.push_back(0);\n\t}\n\t\n\tfor(int i=0;i<=n;i++){\n\t\tint t=0;\n\t\tif(i==0){\n\t\t\tdata.push_back(0);\n\t\t}else{\n\t\t\tcin>>t;\n\t\t\tdata.push_back(t);\n\t\t\tcount[t]++;\n\t\t}\n\t\tdp.push_back(-1);\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tif(i==0){\n\t\t\t\truiseki[j].push_back(0);\n\t\t\t}else{\n\t\t\t\truiseki[j].push_back(ruiseki[j][i-1]+(j==t?0:1));\n\t\t\t}\n\t\t}\n\t}\n\tdp[0]=0;\n\tfor(int i=0;i<n;i++){\n\t\tif(dp[i]==-1)continue;\n\t\tint c1=dp[i];\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tint p1=i+count[j];\n\t\t\tif(dp.size()<=p1)continue;\n\t\t\tint c2=c1+ruiseki[j][p1]-ruiseki[j][i];\n\t\t\tif(dp[p1]==-1||dp[p1]>c2){\n\t\t\t\tdp[p1]=c2;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<dp[dp.size()-1]<<endl;\n\t\n\t\n\treturn 0;\n}\n\nint main() {\n\tf();\n\treturn 0;\n}", "accuracy": 0.4, "time_ms": 10, "memory_kb": 8020, "score_of_the_acc": -0.0028, "final_rank": 20 }, { "submission_id": "aoj_0633_8002490", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll modPow(long long a, long long n, long long p) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\nll gcd(ll(a), ll(b)) {\n if (a == 0)return b;\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\nll sqrtz(ll N) {\n ll L = 0;\n ll R = sqrt(N) + 10000;\n while (abs(R - L) > 1) {\n ll mid = (R + L) / 2;\n if (mid * mid <= N)L = mid;\n else R = mid;\n }\n return L;\n\n}\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M;\n cin>>N>>M;\n vll A(N);\n rep(i,N)cin>>A[i],A[i]--;\n\n vll DP(1<<M,1e18);\n vvll B(M,vll(N+1,0));\n \n rep(i,N){\n rep(m,M){\n B[m][i+1]=B[m][i];\n }\n B[A[i]][i+1]++;\n }\n DP[0]=0;\n rep(bit,1<<M){\n ll s=0;\n rep(n,M){\n if(bit&(1<<n))s+=B[n][N];\n }\n\n rep(n,M){\n if(bit&(1<<n)){\n\n }\n else{\n ll d=B[n][N];\n chmin(DP[bit+(1<<n)],DP[bit]+d-(B[n][s+d]-B[n][s]));\n }\n }\n }\n cout<<DP[(1<<M)-1]<<endl;\n \n}", "accuracy": 1, "time_ms": 130, "memory_kb": 28332, "score_of_the_acc": -0.182, "final_rank": 12 }, { "submission_id": "aoj_0633_7936421", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#include <string>\n#include <vector>\nusing namespace std;\n#define INF (100000000)\ntypedef pair<int, int> P;\nint main() {\n int N, M;\n cin >> N >> M;\n vector<int> D;\n vector<P> DPAIR(M);\n for (int i = 0; i < M; ++i)\n DPAIR[i] = P(i, 0);\n for (int i = 0; i < N; ++i) {\n int temp;\n cin >> temp;\n D.push_back(temp - 1);\n ++DPAIR[temp - 1].second;\n }\n vector<int> DD[M];\n for (int i = 0; i < M; ++i) {\n DD[i].resize(N);\n DD[i][0] = (D[0] == i ? 1 : 0);\n for (int j = 1; j < N; ++j) {\n DD[i][j] = DD[i][j - 1] + (D[j] == i ? 1 : 0);\n }\n }\n string ALPHA = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n string istr = ALPHA.substr(0, M);\n vector<int> indx(M + 1);\n map<string, P> mp;\n for (int c = 1; c <= M; ++c) {\n indx[c] = M;\n for (int i = 0; i < c; ++i)\n indx[i] = i;\n --indx[c - 1];\n while (indx[0] < M - c || c == M) {\n int now = c - 1;\n while (indx[0] != M - c || c == M) {\n if (indx[now + 1] - indx[now] > 1) {\n ++indx[now];\n break;\n } else if (indx[now] - indx[now - 1] > 1) {\n ++indx[now - 1];\n for (int i = now; i < c; ++i)\n indx[i] = indx[i - 1] + 1;\n break;\n } else {\n --now;\n }\n }\n int cnt = INF;\n int len;\n for (int i = 0; i < c; ++i) {\n string s = \"\";\n for (int j = 0; j < c; ++j) {\n if (j == i)\n continue;\n s.push_back(istr[indx[j]]);\n }\n if (s == \"\") {\n cnt = min(cnt, DPAIR[indx[i]].second -\n DD[indx[i]][DPAIR[indx[i]].second - 1]);\n len = DPAIR[indx[i]].second;\n } else {\n int fst = mp[s].first;\n int snd = mp[s].second;\n cnt = min(cnt, fst + DPAIR[indx[i]].second -\n DD[indx[i]][snd + DPAIR[indx[i]].second - 1] +\n DD[indx[i]][snd - 1]);\n len = snd + DPAIR[indx[i]].second;\n }\n }\n string s = \"\";\n for (int i = 0; i < c; ++i) {\n s.push_back(istr[indx[i]]);\n }\n mp[s] = make_pair(cnt, len);\n if (c == M)\n break;\n }\n }\n cout << mp[istr].first << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 5130, "memory_kb": 137952, "score_of_the_acc": -1.9993, "final_rank": 19 }, { "submission_id": "aoj_0633_7936409", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#include <string>\n#include <vector>\nusing namespace std;\n#define INF (100000000)\ntypedef pair<int, int> P;\nint main() {\n int N, M;\n cin >> N >> M;\n vector<int> D;\n vector<P> DPAIR(M);\n for (int i = 0; i < M; ++i)\n DPAIR[i] = P(i, 0);\n for (int i = 0; i < N; ++i) {\n int temp;\n cin >> temp;\n D.push_back(temp - 1);\n ++DPAIR[temp - 1].second;\n }\n vector<int> DD[M];\n for (int i = 0; i < M; ++i) {\n DD[i].resize(N);\n DD[i][0] = (D[0] == i ? 1 : 0);\n for (int j = 1; j < N; ++j) {\n DD[i][j] = DD[i][j - 1] + (D[j] == i ? 1 : 0);\n }\n }\n string ALPHA = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n string istr = ALPHA.substr(0, M);\n vector<int> indx(M + 1);\n map<string, P> mp;\n for (int c = 1; c <= M; ++c) {\n indx[c] = M;\n for (int i = 0; i < c; ++i)\n indx[i] = i;\n --indx[c - 1];\n while (indx[0] < M - c || c == M) {\n int now = c - 1;\n while (indx[0] != M - c || c == M) {\n if (indx[now + 1] - indx[now] > 1) {\n ++indx[now];\n break;\n } else if (indx[now] - indx[now - 1] > 1) {\n ++indx[now - 1];\n for (int i = now; i < c; ++i)\n indx[i] = indx[i - 1] + 1;\n break;\n } else {\n --now;\n }\n }\n int cnt = INF;\n int len;\n string str = \"\";\n for (int j = 0; j < c; ++j) {\n str.push_back(istr[indx[j]]);\n }\n for (int i = 0; i < c; ++i) {\n string s = str;\n s.erase(s.begin() + i);\n if (s == \"\") {\n cnt = min(cnt, DPAIR[indx[i]].second -\n DD[indx[i]][DPAIR[indx[i]].second - 1]);\n len = DPAIR[indx[i]].second;\n } else {\n int fst = mp[s].first;\n int snd = mp[s].second;\n cnt = min(cnt, fst + DPAIR[indx[i]].second -\n DD[indx[i]][snd + DPAIR[indx[i]].second - 1] +\n DD[indx[i]][snd - 1]);\n len = snd + DPAIR[indx[i]].second;\n }\n }\n mp[str] = make_pair(cnt, len);\n if (c == M)\n break;\n }\n }\n cout << mp[istr].first << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 3830, "memory_kb": 138044, "score_of_the_acc": -1.7461, "final_rank": 18 }, { "submission_id": "aoj_0633_7936402", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nstatic const int MAX_N = 100000;\nstatic const int MAX_M = 20;\nint N, M;\nint K[MAX_N];\nint sum[MAX_M][MAX_N + 1];\nint dp[1 << MAX_M];\nint main() {\n cin >> N >> M;\n for (int i = 0; i < N; i++)\n cin >> K[i];\n fill(sum[0], sum[M], 0);\n for (int i = 0; i < N; i++)\n sum[K[i] - 1][i + 1]++;\n for (int i = 0; i < M; i++) {\n for (int j = 1; j <= N; j++) {\n sum[i][j] += sum[i][j - 1];\n }\n }\n fill(dp, dp + (1 << M), 0);\n for (int i = 1; i < (1 << M); i++) {\n int minimum_num = MAX_N + 1;\n for (int j = 0; j < M; j++) {\n if (!(i & (1 << j)))\n continue;\n int replaced_doll_num = 0;\n for (int k = 0; k < M; k++) {\n if (j == k)\n continue;\n if (i & (1 << k))\n replaced_doll_num += sum[k][N];\n }\n minimum_num =\n min(minimum_num, dp[i - (1 << j)] + sum[j][N] -\n (sum[j][replaced_doll_num + sum[j][N]] -\n sum[j][replaced_doll_num]));\n }\n dp[i] = minimum_num;\n }\n cout << dp[(1 << M) - 1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 15416, "score_of_the_acc": -0.1435, "final_rank": 9 }, { "submission_id": "aoj_0633_7936401", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\nstatic const int MAX_N = 100000;\nstatic const int MAX_M = 20;\nint N, M;\nint K[MAX_N];\nint sum[MAX_M][MAX_N + 1];\nint dp[1 << MAX_M], dp2[1 << MAX_M];\nint main() {\n cin >> N >> M;\n for (int i = 0; i < N; i++)\n cin >> K[i];\n fill(sum[0], sum[M], 0);\n for (int i = 0; i < N; i++)\n sum[K[i] - 1][i + 1]++;\n for (int i = 0; i < M; i++) {\n for (int j = 1; j <= N; j++) {\n sum[i][j] += sum[i][j - 1];\n }\n }\n fill(dp, dp + (1 << M), 0);\n fill(dp2, dp2 + (1 << M), 0);\n for (int i = 1; i < (1 << M); i++) {\n int minimum_num = MAX_N + 1;\n for (int j = 0; j < M; j++) {\n if (!(i & (1 << j)))\n continue;\n dp2[i] = dp2[i - (1 << j)] + sum[j][N];\n minimum_num =\n min(minimum_num, dp[i - (1 << j)] + sum[j][N] -\n (sum[j][dp2[i - (1 << j)] + sum[j][N]] -\n sum[j][dp2[i - (1 << j)]]));\n }\n dp[i] = minimum_num;\n }\n cout << dp[(1 << M) - 1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 19484, "score_of_the_acc": -0.1044, "final_rank": 6 }, { "submission_id": "aoj_0633_7265315", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <unordered_map>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint n = 0;\n\tint m = 0;\n\tint tmp = 0;\n\tvector<int> shelf;\n\tvector<vector<int>> acc_sum_vec;\n\tunordered_map<int, int> dp;\n\n\tcin >> n >> m;\n\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> tmp;\n\t\tshelf.emplace_back(tmp - 1);\n\t}\n\n\tfor (int i = 0; i < m; i++) {\n\t\tvector<int> acc_sum(n + 1, 0);\n\n\t\tfor (int j = 1; j < n + 1; j++) {\n\t\t\tif (shelf[j - 1] == i) {\n\t\t\t\tacc_sum[j] = 1;\n\t\t\t}\n\t\t}\n\t\tacc_sum_vec.emplace_back(acc_sum);\n\t}\n\n\tfor (int i = 0; i < m; i++) {\n\t\tfor (int j = 1; j < n + 1; j++) {\n\t\t\tacc_sum_vec[i][j] += acc_sum_vec[i][j - 1];\n\t\t}\n\t}\n\t\n\tdp[0] = 0;\n\tfor (int i = 0; i < m; i++) {\n\t\tunordered_map<int, int> new_dp;\n\n\t\tfor (unordered_map<int, int>::iterator it = dp.begin(); it != dp.end(); it++) {\n\t\t\tint state = it->first;\n\t\t\tint min_num_swapped_toys = it->second;\n\n\t\t\tfor (int j = 0; j < m; j++) {\n\t\t\t\tif ((state & (1 << j)) == 0) {\n\t\t\t\t\tint n_state = state | (1 << j);\n\t\t\t\t\tint c_num_toys = 0;\n\t\t\t\t\tint p_num_toys = 0;\n\n\t\t\t\t\tfor (int k = 0; k < m; k++) {\n\t\t\t\t\t\tif ((n_state & (1 << k)) > 0) {\n\t\t\t\t\t\t\tc_num_toys += acc_sum_vec[k].back();\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif ((state & (1 << k)) > 0) {\n\t\t\t\t\t\t\tp_num_toys += acc_sum_vec[k].back();\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tint num_swapped_toys = acc_sum_vec[j][p_num_toys] - acc_sum_vec[j][0] + acc_sum_vec[j].back() - acc_sum_vec[j][c_num_toys] + min_num_swapped_toys;\n\n\t\t\t\t\tif (new_dp.count(n_state) == 0) {\n\t\t\t\t\t\tnew_dp[n_state] = num_swapped_toys;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tnew_dp[n_state] = min(new_dp[n_state], num_swapped_toys);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdp = new_dp;\n\t}\n\n\tint min_num_swapped_toys = n + 1;\n\tfor (unordered_map<int, int>::iterator it = dp.begin(); it != dp.end(); it++) {\n\t\tmin_num_swapped_toys = min(min_num_swapped_toys, it->second);\n\t}\n\tcout << min_num_swapped_toys << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1320, "memory_kb": 26320, "score_of_the_acc": -0.399, "final_rank": 15 }, { "submission_id": "aoj_0633_7265081", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <unordered_map>\nusing namespace std;\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint n = 0;\n\tint m = 0;\n\tint tmp = 0;\n\tvector<int> shelf;\n\tvector<vector<int>> acc_sum_vec;\n\tunordered_map<int, int> dp;\n\n\tcin >> n >> m;\n\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> tmp;\n\t\tshelf.emplace_back(tmp - 1);\n\t}\n\n\tfor (int i = 0; i < m; i++) {\n\t\tvector<int> acc_sum(n + 1, 0);\n\n\t\tfor (int j = 1; j < n + 1; j++) {\n\t\t\tif (shelf[j - 1] == i) {\n\t\t\t\tacc_sum[j] = 1;\n\t\t\t}\n\t\t}\n\t\tacc_sum_vec.emplace_back(acc_sum);\n\t}\n\n\tfor (int i = 0; i < m; i++) {\n\t\tfor (int j = 1; j < n + 1; j++) {\n\t\t\tacc_sum_vec[i][j] += acc_sum_vec[i][j - 1];\n\t\t}\n\t}\n\t\n\tdp[0] = 0;\n\tfor (int i = 0; i < m; i++) {\n\t\tunordered_map<int, int> new_dp;\n\n\t\tfor (unordered_map<int, int>::iterator it = dp.begin(); it != dp.end(); it++) {\n\t\t\tint state = it->first;\n\t\t\tint min_num_toys = it->second;\n\n\t\t\tfor (int j = 0; j < m; j++) {\n\t\t\t\tif ((state & (1 << j)) == 0) {\n\t\t\t\t\tint n_state = state | (1 << j);\n\t\t\t\t\tint num_toys = 0;\n\t\t\t\t\tint p_num_toys = 0;\n\n\t\t\t\t\tfor (int k = 0; k < m; k++) {\n\t\t\t\t\t\tif ((n_state & (1 << k)) > 0) {\n\t\t\t\t\t\t\tnum_toys += acc_sum_vec[k].back();\n\t\t\t\t\t\t}\n\t\t\t\t\t\tif ((state & (1 << k)) > 0) {\n\t\t\t\t\t\t\tp_num_toys += acc_sum_vec[k].back();\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tint num_swapped_toys = acc_sum_vec[j][p_num_toys] - acc_sum_vec[j][0] + acc_sum_vec[j].back() - acc_sum_vec[j][num_toys] + min_num_toys;\n\n\t\t\t\t\tif (new_dp.count(n_state) == 0) {\n\t\t\t\t\t\tnew_dp[n_state] = num_swapped_toys;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\tnew_dp[n_state] = min(new_dp[n_state], num_swapped_toys);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tdp = new_dp;\n\t}\n\n\tint min_num_toys = n + 1;\n\n\tfor (unordered_map<int, int>::iterator it = dp.begin(); it != dp.end(); it++) {\n\t\tmin_num_toys = min(min_num_toys, it->second);\n\t}\n\tcout << min_num_toys << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1310, "memory_kb": 26004, "score_of_the_acc": -0.3947, "final_rank": 14 }, { "submission_id": "aoj_0633_7175835", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing i32 = int;\n\ninline void chmin(i32& a, i32 b) {\n if (a > b) {\n a = b;\n }\n}\n\nconst i32 supi = (1 << 30);\n\nint main() {\n i32 n, m; cin >> n >> m;\n vector as(n, 0);\n for (auto& a : as) {\n cin >> a;\n a--;\n }\n vector sums = [&]() -> vector<vector<i32>> {\n vector res(m, vector(n + 1, 0));\n for (i32 i = 0 ; i < n ; i++) {\n res[as[i]][i + 1]++;\n }\n for (auto& r : res) {\n for (i32 i = 0 ; i + 1 < n + 1 ; i++) {\n r[i + 1] += r[i];\n }\n }\n return res;\n }();\n vector dp((1 << m), supi);\n dp[0] = 0;\n for (i32 bit = 0 ; bit < (1 << m) ; bit++) {\n assert(dp[bit] < supi);\n i32 used = 0;\n vector yet(0, 0);\n for (i32 i = 0 ; i < m ; i++) {\n if (bit & (1 << i)) {\n used += sums[i].back();\n }\n else {\n yet.push_back(i);\n }\n }\n for (auto i : yet) {\n i32 now = sums[i].back();\n i32 cnt = sums[i].back() - sums[i][used + now];\n for (auto j : yet) {\n if (i == j) {\n continue;\n }\n cnt += sums[j][used + now] - sums[j][used];\n }\n chmin(dp[bit | (1 << i)], dp[bit] + cnt);\n }\n }\n cout << dp.back() << endl;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 15128, "score_of_the_acc": -0.1023, "final_rank": 5 }, { "submission_id": "aoj_0633_6992634", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0633.cc: ぬいぐるみの整理 (Plush Toys)\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_M = 20;\nconst int MBITS = 1 << MAX_M;\nconst int INF = 1 << 30;\n\n/* typedef */\n\n/* global variables */\n\nint as[MAX_N], cs[MAX_M], css[MAX_N + 1][MAX_M];\nint bsums[MBITS], dp[MBITS];\n\n/* subroutines */\n\ninline void setmin(int &a, int b) { if (a > b) a = b; }\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", as + i), as[i]--;\n cs[as[i]]++;\n copy(css[i], css[i] + m, css[i + 1]);\n css[i + 1][as[i]]++;\n }\n\n int mbits = 1 << m;\n\n bsums[0] = 0;\n for (int bits = 1, msb = 1, msi = 0; bits < mbits; bits++) {\n if ((msb << 1) <= bits) msb <<= 1, msi++;\n bsums[bits] = bsums[bits ^ msb] + cs[msi];\n }\n\n fill(dp, dp + mbits, INF);\n dp[0] = 0;\n\n for (int bits = 0; bits < mbits; bits++)\n for (int i = 0, bi = 1; i < m; i++, bi <<= 1)\n if (! (bits & bi)) {\n\tint l = css[bsums[bits | bi]][i] - css[bsums[bits]][i];\n\tsetmin(dp[bits | bi], dp[bits] + cs[i] - l);\n }\n\n printf(\"%d\\n\", dp[mbits - 1]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 19332, "score_of_the_acc": -0.0993, "final_rank": 4 }, { "submission_id": "aoj_0633_6814259", "code_snippet": "#include<iostream>\n#include<algorithm>\nusing namespace std;\ntypedef long long ll;\nint sum[100001][20];\nint dp[1<<20];\nint main(){\n\tint n,m,a[100000];\n\tcin>>n>>m;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i],a[i]--;\n\tfor(int i=0;i<n;i++){\n\t\tcopy(sum[i],sum[i]+m,sum[i+1]);\n\t\tsum[i+1][a[i]]++;\n\t}\n\tfor(int S=1;S<1<<m;S++)\n\t\tdp[S]=1e9;\n\tfor(int S=0;S<1<<m;S++){\n\t\tint tmp=0;\n\t\tfor(int i=0;i<m;i++)\n\t\t\tif(S>>i&1)\n\t\t\t\ttmp+=sum[n][i];\n\t\tfor(int i=0;i<m;i++)\n\t\t\tif(~S>>i&1)\n\t\t\t\tdp[S|1<<i]=min(dp[S|1<<i],dp[S]+sum[n][i]-(sum[tmp+sum[n][i]][i]-sum[tmp][i]));\n\t}\n\tcout<<dp[(1<<m)-1]<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 15624, "score_of_the_acc": -0.0748, "final_rank": 1 }, { "submission_id": "aoj_0633_6111331", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n vector<vector<int>> t(m);\n rep(i,n){\n INT(x);\n t[--x].push_back(i);\n }\n vector<int> dp(1<<m,0);\n rep(i,1<<m){\n int l=0,r;\n rep(j,m)if(i>>j&1)l+=t[j].size();\n rep(j,m){\n if(~i>>j&1){\n r=l+t[j].size();\n int plus=lower_bound(all(t[j]),r)-lower_bound(all(t[j]),l);\n chmax(dp[i^(1<<j)],dp[i]+plus);\n }\n }\n }\n out(n-dp.back());\n}", "accuracy": 1, "time_ms": 790, "memory_kb": 7652, "score_of_the_acc": -0.1523, "final_rank": 10 }, { "submission_id": "aoj_0633_5865575", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\nint dp[(1<<20)];\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int n, m; cin >> n >> m;\n REP(i,(1<<m)) dp[i] = 1e9;\n dp[0] = 0;\n vector<int> a(n);\n REP(i,n) cin >> a[i];\n vector<vector<int>> cums(m, vector<int>(n+1));\n REP(i,n) {\n a[i]--;\n cums[a[i]][i+1]++;\n for(int j=0; j<m; j++) {\n cums[j][i+1] += cums[j][i];\n }\n }\n REP(bit,(1<<m)) {\n int sum = 0;\n REP(i,m) if(bit >> i & 1) sum += cums[i][n];\n REP(i,m) {\n if(bit >> i & 1) continue;\n int t = cums[i][n];\n dp[bit | (1 << i)] = min(dp[bit | (1 << i)], dp[bit] + t - (cums[i][sum+t]-cums[i][sum]));\n }\n }\n cout << dp[(1<<m)-1] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 15900, "score_of_the_acc": -0.0789, "final_rank": 3 }, { "submission_id": "aoj_0633_5496599", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, N) for (int i = 0; i < N; i++)\nint main()\n{\n int INF = 1000100100;\n int N, M;\n cin >> N >> M;\n int A[N];\n rep(i, N)\n {\n cin >> A[i];\n A[i]--;\n }\n int ac[M][N]={};\n ac[A[0]][0]++;\n \n for (int j = 1; j < N; j++)\n {\n rep(i, M)\n {\n ac[i][j] = ac[i][j - 1];\n if (A[j] == i)\n ac[i][j]++;\n }\n }\n/* rep(i, M)\n {\n rep(j, N) { cout << ac[i][j] << \" | \"; }\n cout << endl;\n } */\n int dp[1 << M];\n rep(i, 1 << M) dp[i] = INF;\n dp[0] = 0;\n int cnt[M] = {};\n rep(i, N)\n {\n cnt[A[i]]++;\n }\n// rep(i, M) cout << cnt[i] << \" |cnt| \";\n // cout << endl;\n\n rep(s, 1 << M)\n {\n// cout << \" s \" << s << endl;\n int done = 0;\n rep(i, M)\n {\n if (s & (1 << i))\n {\n done += cnt[i];\n }\n }\n\n rep(i, M)\n {\n // cout << \" i \" << i << \" done \" << done << endl;\n\n if(s & (1 << i))\n continue; // iがsに含まれているならスキップ\n int cost;\n if(done == 0) {\n cost = cnt[i] - ac[i][cnt[i] -1];\n // cout << \" cost \" << cost << \" cnt \" << cnt[i] << \" - \" << ac[i][cnt[i] -1] << endl;\n }\n else {\n cost = cnt[i] - (ac[i][cnt[i] -1 + done] - ac[i][done -1]);\n }\n // cout << i << \" i cost \" << cost << \" dp[s|1<<i] \" << dp[s|1<<i] << \" dp[s] \" << dp[s] << endl;\n\n dp[s|1<<i] = min(dp[s|1<<i], dp[s] + cost);\n\n // rep(i,1<<M) cout << bitset<4>(i)<< \":\" << dp[i] << \" |dp| \"; cout << endl;\n }\n }\n cout << dp[(1<<M)-1] << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 15388, "score_of_the_acc": -0.0789, "final_rank": 2 }, { "submission_id": "aoj_0633_5492981", "code_snippet": "#include <bits/stdc++.h> \nusing namespace std;\nusing ll = long long;\nusing ld = long double;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define repp(i, st, en) for (ll i = (ll)st; i < (ll)(en); i++)\n#define repm(i, st, en) for (ll i = (ll)st; i >= (ll)(en); i--)\n#define all(v) v.begin(), v.end()\nvoid chmax(ll &x, ll y) {x = max(x,y);}\nvoid chmin(ll &x, ll y) {x = min(x,y);}\nvoid Yes() {cout << \"Yes\" << endl; exit(0);}\nvoid No() {cout << \"No\" << endl; exit(0);}\ntemplate<class in_Cout> void Cout(in_Cout x) {cout << x << endl; exit(0);}\ntemplate<class in_vec_cout>\nvoid vec_cout(vector<in_vec_cout> vec) {\n for (in_vec_cout res : vec) {cout << res << \" \";}\n cout << endl;\n}\n\nconst ll inf = 1e18;\nconst ll mod = 1e9 + 7;\n\nint main() {\n ll N, M; cin >> N >> M;\n vector<ll> a(N);\n rep(i,N) cin >> a[i];\n rep(i,N) a[i]--;\n vector<ll> cnt(M);\n rep(i,N) cnt[a[i]]++;\n vector<vector<ll>> S(M,vector<ll>(N));\n rep(i,N) S[a[i]][i] = 1;\n rep(i,M) repp(j,1,N) S[i][j] += S[i][j-1];\n\n vector<ll> dp(1<<M,inf);\n dp[0] = 0;\n rep(bit,1<<M) {\n ll l = 0;\n rep(i,M) if ((bit>>i)&1) l += cnt[i];\n rep(i,M) {\n if ((bit>>i)&1) continue;\n ll nbit = bit | (1<<i);\n ll L = 0, R = 0;\n if (l+cnt[i]-1>=0) R = S[i][l+cnt[i]-1];\n if (l-1>=0) L = S[i][l-1];\n ll cost = cnt[i] - (R-L);\n chmin(dp[nbit],dp[bit]+cost);\n }\n }\n ll X = (1<<M) - 1;\n ll ans = dp[X];\n Cout(ans);\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 27680, "score_of_the_acc": -0.1731, "final_rank": 11 }, { "submission_id": "aoj_0633_5152596", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\n#define puts(x) cout << x << \"\\n\";\nusing ll = int;\nusing ld = long double;\nusing namespace std;\n\n//入力\nll n, m;\nvector<ll> syu(100005), ko(21);\nvector<vector<ll>> rui(21, vector<ll>(100005));\n\n// メモ再帰\nll dp[1 << 21];\nll rec(ll bit) {\n\t// すでに探索済みだったらリターン\n\tif (dp[bit] != -1) return dp[bit];\n\n\t// 答えを格納する変数\n\tint res = 1000000;\n\trep (v, m) {\n\t\t//集合bitにvが含まれるか\n\t\tif ((bit & (1 << v)) != 0) {\n\t\t\t// bit の v を除いたもの\n\t\t\tll prev_bit = bit & ~(1 << v);\n\n\t\t\tll start = 0;\n\t\t\trep(i, m) {\n\t\t\t\tif ((prev_bit & (1 << i)) != 0) { start += ko[i]; }\n\t\t\t}\n\n\t\t\tll ans = rec(prev_bit);\n\t\t\tll sum = rui[v][start + ko[v] - 1];\n\t\t\tif (start != 0) { sum -= rui[v][start - 1]; }\n\t\t\tans += ko[v] - sum;\n\n\t\t\t// 再帰的に探索\n\t\t\tif (res > ans) {\n\t\t\t\tres = ans;\n\t\t\t}\n\t\t}\n\t}\n\treturn dp[bit] = res; // メモしながらリターン\n}\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\t//input\n\tcin >> n >> m;\n\trep(i, n) { cin >> syu[i]; syu[i]--; rui[syu[i]][i]++; ko[syu[i]]++; }\n\trep(i, n) {\n\t\tif (i == 0) { continue; }\n\t\trep(j, m) {\n\t\t\trui[j][i] += rui[j][i - 1];\n\t\t}\n\t}\n\t// テーブルを全部 -1 にしておく (-1 でなかったところは探索済)\n\tfor (int bit = 0; bit < (1 << m); ++bit) dp[bit] = -1;\n\tdp[0] = 0;\n\tcout << rec((1 << m) - 1) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 15420, "score_of_the_acc": -0.1104, "final_rank": 8 } ]
aoj_0635_cpp
ヘビの JOI 君 (Snake JOI) 問題 ヘビの JOI 君は,ある大きな屋敷に迷い込んでしまった.屋敷の住人に見つかる前に,屋敷を脱出しなければならない. この屋敷には部屋が N 個あり,1, 2, ..., N の番号が付けられている.また,廊下が M 本あり,i 本目の廊下 (1 ≦ i ≦ M) は部屋 A i と部屋 B i を結んでいる.JOI 君はこれらの廊下をどちらの向きにも通ることができ,廊下 i を通るのには D i 分かかる.部屋と部屋の間を廊下を通る以外の手段で移動する方法はない. この屋敷の部屋の温度はそれぞれ一定に調節されており,JOI 君にとって寒すぎるか,快適であるか,暑すぎるかである.JOI 君は,急な温度変化に対応できないため,最後に寒すぎる部屋を出てから X 分未満のうちに暑すぎる部屋に入ることはできない.同様に,最後に暑すぎる部屋を出てから X 分未満のうちに寒すぎる部屋に入ることもできない. JOI 君は,移動中に部屋に入るとすぐに部屋から出なければならない.また,廊下の途中で引き返したり,廊下 i を D i 分より長い時間かけて通ることもできない.ただし,一度訪れた部屋にもう一度入ることや,一度使った廊下をもう一度使うことは許される. JOI 君は現在部屋 1 にいる.この部屋は JOI 君にとって寒すぎる.JOI 君は屋敷の出口のある部屋 N に入ると,屋敷から脱出できる. JOI 君が屋敷から脱出するのにかかる最短の時間を求めよ. 入力 入力は 1 + N + M 行からなる. 1 行目には,3 個の整数 N, M, X (2 ≦ N ≦ 10000, 1 ≦ M ≦ 20000, 1 ≦ X ≦ 200) が空白を区切りとして書かれている.これは,屋敷に N 個の部屋と M 本の廊下があり,JOI 君が温度変化に対応するのに X 分かかることを表す. 続く N 行のうちの i 行目 (1 ≦ i ≦ N) には,部屋 i の温度を表す整数 T i (0 ≦ T i ≦ 2) が書かれている.JOI 君にとって部屋 i は,T i = 0 のとき寒すぎ,T i = 1 のとき快適であり,T i = 2 のとき暑すぎる.T 1 = 0 であることが保証されている. 続く M 行のうちの j 行目 (1 ≦ j ≦ M) には,3 個の整数 A j , B j , D j (1 ≦ A j < B j ≦ N, 1 ≦ D j ≦ 200) が空白を区切りとして書かれている.これは,廊下 j が部屋 A j と部屋 B j を結んでおり,通るのに D j 分かかることを表す.同じ部屋の組を結ぶ廊下が複数ある可能性があることに注意せよ. 与えられる入力データでは,JOI 君が屋敷から脱出できることは保証されている. 出力 JOI 君が屋敷から脱出するのに最短で何分かかるかを表す整数を 1 行で出力せよ. 入出力例 入力例 1 8 10 4 0 1 1 2 1 1 2 0 1 2 1 1 3 1 2 3 3 2 4 5 3 4 1 4 5 1 5 6 1 5 8 1 1 7 2 7 8 2 出力例 1 9 入力例 2 15 25 4 0 1 1 0 2 1 0 1 1 2 0 0 1 0 1 8 11 1 7 10 1 12 14 1 3 8 1 1 5 1 3 9 1 3 8 1 1 5 1 6 15 1 11 12 1 2 14 1 7 10 1 11 12 1 5 13 1 2 8 1 1 4 1 2 11 1 5 6 1 1 13 1 6 12 1 5 10 1 9 13 1 4 10 1 3 12 1 7 13 1 出力例 2 6 入力例 1 では,部屋を 1 → 2 → 3 → 4 → 5 → 6 → 5 → 8 の順に移動するのが最短となる. 入力例 2 では,いくつかの部屋の組 (たとえば部屋 1 と部屋 5) を結ぶ廊下が複数ある. 情報オリンピック日本委員会作 『第 16 回日本情報オリンピック JOI 2016/2017 予選競技課題』
[ { "submission_id": "aoj_0635_10923940", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ul=unsigned long long;\nint dx[8] = {1, 0, -1, 0, -1, -1, 1, 1};\nint dy[8] = {0, 1, 0, -1, -1, 1, -1, 1};\nusing Graph=vector<vector<int>>;\nvector<vector<ll>> Dijkstra(vector<vector<vector<tuple<int,int,ll>>>> &G, int s,int X){\n vector<vector<ll>> D(G.size(),vector<ll>(2*X+2,1e18));\n D[s][2*X+1] = 0;\n priority_queue<tuple<ll,int,int>, vector<tuple<ll,int,int>>, greater<tuple<ll,int,int>>> q;\n q.push(make_tuple(0, s, 2*X+1));\n while (!q.empty()){\n auto [d, u, x] = q.top();\n q.pop();\n if (D[u][x] < d){\n continue;\n }\n for (auto [v, w, c] : G[u][x]){\n d = D[u][x] + c;\n if (d < D[v][w]){\n D[v][w] = d;\n q.push(make_tuple(d, v, w));\n }\n }\n }\n return D;\n}\nint main(){\n\tint N,M,X;\n\tcin>>N>>M>>X;\n\tvector<vector<vector<tuple<int,int,ll>>>>G(N,vector<vector<tuple<int,int,ll>>>(2*X+2));\n\tvector<int>T(N);\n\tfor(int i=0;i<N;i++)cin>>T[i];\n\tfor(int i=0;i<N;i++){\n\t\tif(T[i]==0)G[i][2*X+1].push_back({i,0,0});\n\t\tif(T[i]==2)G[i][2*X+1].push_back({i,2*X,0});\n\t}\n\tfor(int i=0;i<M;i++){\n\t\tint a,b,d;\n\t\tcin>>a>>b>>d;\n\t\ta--,b--;\n\t\tif(T[a]==0&&T[b]==0){\n\t\t\tfor(int j=0;j<X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t\tG[b][j].push_back({a,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==0&&T[b]==1){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j+d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==0&&T[b]==2){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==0){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==1){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j+d,d});\n\t\t\t\tif(j+d>=X)G[b][j].push_back({a,2*X+1,d});\n\t\t\t\telse G[b][j].push_back({a,j+d,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tG[b][2*X+1].push_back({a,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j-d,d});\n\t\t\t\tif(j-d<=X)G[b][j].push_back({a,max(X,j-d),d});\n\t\t\t\telse G[b][j].push_back({a,j-d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==2){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==0){\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==1){\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j-d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==2){\n\t\t\tfor(int j=X+1;j<=2*X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t\tG[b][j].push_back({a,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tswap(a,b);\n\t\tif(T[a]==0&&T[b]==0){\n\t\t\tfor(int j=0;j<X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t\tG[b][j].push_back({a,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==0&&T[b]==1){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j+d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==0&&T[b]==2){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==0){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==1){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j+d,d});\n\t\t\t\tif(j+d>=X)G[b][j].push_back({a,2*X+1,d});\n\t\t\t\telse G[b][j].push_back({a,j+d,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tG[b][2*X+1].push_back({a,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j-d,d});\n\t\t\t\tif(j-d<=X)G[b][j].push_back({a,max(X,j-d),d});\n\t\t\t\telse G[b][j].push_back({a,j-d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==1&&T[b]==2){\n\t\t\tfor(int j=0;j<=X;j++){\n\t\t\t\tif(j+d>=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t\tG[a][2*X+1].push_back({b,2*X+1,d});\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==0){\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==1){\n\t\t\tfor(int j=X;j<=2*X;j++){\n\t\t\t\tif(j-d<=X)G[a][j].push_back({b,2*X+1,d});\n\t\t\t\telse G[a][j].push_back({b,j-d,d});\n\t\t\t}\n\t\t}\n\t\tif(T[a]==2&&T[b]==2){\n\t\t\tfor(int j=X+1;j<=2*X;j++){\n\t\t\t\tG[a][j].push_back({b,2*X+1,d});\n\t\t\t\tG[b][j].push_back({a,2*X+1,d});\n\t\t\t}\n\t\t}\n\t}\n\tauto D=Dijkstra(G,0,X);\n\tcout<<*min_element(D[N-1].begin(),D[N-1].end())<<endl;\n}", "accuracy": 1, "time_ms": 620, "memory_kb": 578944, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0635_10854010", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing P = pair<int, int>;\n\nstruct edge {\n int to, weight;\n};\n\nusing edges = vector<edge>;\nusing graph = vector<edges>;\n\nconstexpr int INF = 1e9;\n\nint main() {\n int N, M, X;\n cin >> N >> M >> X;\n vector<int> T(N);\n for(int i=0; i<N; ++i) {\n cin >> T[i];\n }\n graph g(N);\n for(int i=0; i<M; ++i) {\n int a, b, d;\n cin >> a >> b >> d;\n a--; b--;\n g[a].push_back((edge){b, d});\n g[b].push_back((edge){a, d});\n }\n \n using state = tuple<int, int, int, int>;\n vector<vector<vector<int>>> d(N, vector<vector<int>>(3, vector<int>(X+1, INF)));\n d[0][0][X] = 0;\n priority_queue<state, vector<state>, greater<state>> que;\n que.push(make_tuple(0, 0, 0, X));\n while(!que.empty()) {\n int cd, v, t, x;\n tie(cd, v, t, x) = que.top();\n que.pop();\n if(d[v][t][x] < cd) {\n continue;\n }\n for(auto& e : g[v]) {\n int nx = (T[e.to] == 1 ? max(0, x - e.weight) : X);\n if(T[e.to] == 1 && d[e.to][t][nx] > d[v][t][x] + e.weight) {\n d[e.to][t][nx] = d[v][t][x] + e.weight;\n que.push(make_tuple(d[e.to][t][nx], e.to, t, nx));\n } else if(T[e.to] != 1 && (T[e.to] != t && x <= e.weight || T[e.to] == t)) {\n if(d[e.to][T[e.to]][nx] > d[v][t][x] + e.weight) {\n d[e.to][T[e.to]][nx] = d[v][t][x] + e.weight;\n que.push(make_tuple(d[e.to][T[e.to]][nx], e.to, T[e.to], nx));\n }\n }\n }\n }\n int res = INF;\n for(int i=0; i<3; ++i) {\n for(int j=0; j<X+1; ++j) {\n res = min(res, d[N-1][i][j]);\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 29016, "score_of_the_acc": -0.0767, "final_rank": 10 }, { "submission_id": "aoj_0635_10433475", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <vector>\n#include <queue>\nusing namespace std;\n\nstruct E{\n\tint to,d;\n};\nstruct E2{\n\tint to,state,d;\n\tlong long int time;\n\tbool operator<(const E2& e2)const{\n\t\treturn time>e2.time;\n\t}\n};\n\n\nlong long int dp[4][203][10003];\nint room[10003];\nvector<E> cons[10003];\nint n,m,x;\nint main() {\n\tmemset(dp,-1,sizeof(dp));\n\tcin>>n>>m>>x;\n\tfor(int i=1;i<=n;i++){\n\t\tcin>>room[i];\n\t}\n\tfor(int i=0;i<m;i++){\n\t\tint from,to;\n\t\tE e1;\n\t\tcin>>from>>to>>e1.d;\n\t\te1.to=to;\n\t\tcons[from].push_back(e1);\n\t\te1.to=from;\n\t\tcons[to].push_back(e1);\n\t}\n\tE2 e2;\n\te2.to=1;\n\te2.state=room[1];\n\te2.time=0;\n\te2.d=x;\n\tpriority_queue<E2> pq;\n\tpq.push(e2);\n\twhile(pq.size()>0){\n\t\tE2 e2=pq.top();\n\t\t//cout<<\"(\"<<e2.time<<\" \"<<e2.state<<\" \"<<e2.to<<\" \"<<e2.d<<\")\"<<endl;\n\t\tpq.pop();\n\t\tlong long int t1=dp[e2.state][e2.d][e2.to];\n\t\tif(t1!=-1 && t1<=e2.time)continue;\n\t\tdp[e2.state][e2.d][e2.to]=e2.time;\n\t\tfor(auto it=cons[e2.to].begin();it!=cons[e2.to].end();it++){\n\t\t\tE e1a=(*it);\n\t\t\t\n\t\t\tE2 e2a;\n\t\t\te2a.to=e1a.to;\n\t\t\te2a.state=e2.state;\n\t\t\te2a.time=e2.time+e1a.d;\n\t\t\te2a.d=e2.d-e1a.d;\n\t\t\tif(e2a.d<=0)e2a.d=0;\n\t\t\tbool moveok=false;\n\t\t\tif(e2a.d<=0){\n\t\t\t\tmoveok=true;\n\t\t\t\te2a.state=room[e1a.to];\n\t\t\t\tif(room[e1a.to]==1){\n\t\t\t\t\te2a.d=0;\n\t\t\t\t\n\t\t\t\t}else{\n\t\t\t\t\te2a.d=x;\n\t\t\t\t}\n\t\t\t}else{\n\t\t\t\t\n\t\t\t\tif(room[e1a.to]==1){\n\t\t\t\t\tmoveok=true;\n\t\t\t\t}else if(room[e1a.to]==e2a.state){\n\t\t\t\t\tmoveok=true;\n\t\t\t\t\te2a.d=x;\n\t\t\t\t}\n\t\t\t}\n\t\t\t//cout<<\"(\"<<e1a.to<<\" \"<<e1a.d<<\" \"<<e2a.d<<\")\";\n\t\t\tif(moveok==false)continue;\n\t\t\tpq.push(e2a);\n\t\t}\n\t}\n\tint ans=-1;\n\tfor(int j=0;j<3;j++){\n\t\tfor(int i=0;i<=200;i++){\n\t\t\tlong long int t1=dp[j][i][n];\n\t\t\tif(ans==-1 || (t1!=-1 && t1<ans))ans=t1;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 68012, "score_of_the_acc": -0.1772, "final_rank": 15 }, { "submission_id": "aoj_0635_10351528", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n////////////////////////////////////////////\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll n, m, x;\n cin >> n >> m >> x;\n vector<ll> ar(n);\n rep(i, 0, n)\n {\n cin >> ar[i];\n if (ar[i] == 1)\n {\n ar[i] = 2;\n }\n else if (ar[i] == 2)\n {\n ar[i] = 1;\n }\n }\n vector<vector<pair<ll, ll>>> g(n);\n rep(i, 0, m)\n {\n ll a, b, c;\n cin >> a >> b >> c;\n a--;\n b--;\n g[a].push_back(pr(b, c));\n g[b].push_back(pr(a, c));\n }\n auto d = make_vec({n, 2, x + 1}, inf);\n // d[i][j][k]:最後に入った温度がj:(1:温/0:冷)であり、そこからk分経過した時点で頂点iにいるときの最小値\n d[0][0][0] = 0;\n using T = pair<ll, pair<ll, pair<ll, ll>>>;\n priority_queue<T, vector<T>, greater<T>> que;\n que.push(pr(0, pr(0, pr(0, 0))));\n while (!que.empty())\n {\n ll A = que.top().second.first;\n ll B = que.top().second.second.first;\n ll C = que.top().second.second.second;\n ll D = que.top().first;\n que.pop();\n if (D != d[A][B][C])\n {\n continue;\n }\n rep(i, 0, g[A].size())\n {\n ll nxt = g[A][i].first;\n ll dist = g[A][i].second;\n if (ar[nxt] == 2)\n {\n if (d[nxt][B][min(C + dist, x)] > d[A][B][C] + dist)\n {\n d[nxt][B][min(C + dist, x)] = d[A][B][C] + dist;\n que.push(pr(d[A][B][C] + dist, pr(nxt, pr(B, min(C + dist, x)))));\n }\n }\n else\n {\n if (ar[nxt] == B)\n {\n if (d[nxt][B][0] > d[A][B][C] + dist)\n {\n d[nxt][B][0] = d[A][B][C] + dist;\n que.push(pr(d[A][B][C] + dist, pr(nxt, pr(B, 0))));\n }\n }\n else\n {\n if (C + dist < x)\n {\n continue;\n }\n if (d[nxt][1 - B][0] > d[A][B][C] + dist)\n {\n d[nxt][1 - B][0] = d[A][B][C] + dist;\n que.push(pr(d[A][B][C] + dist, pr(nxt, pr(1 - B, 0))));\n }\n }\n }\n }\n }\n /*\n rep(a, 0, n)\n {\n ll sub = inf;\n rep(i, 0, 2)\n {\n rep(j, 0, x + 1)\n {\n chmin(sub, d[a][i][j]);\n }\n }\n cout << sub << \" \";\n }\n cout << Endl;\n */\n ll ans = inf;\n rep(i, 0, 2)\n {\n rep(j, 0, x + 1)\n {\n chmin(ans, d[n - 1][i][j]);\n }\n }\n cout << ans << Endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 37248, "score_of_the_acc": -0.0746, "final_rank": 9 }, { "submission_id": "aoj_0635_10130529", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n ll N,M,X;\n cin>>N>>M>>X;\n vector<ll> T(N);\n rep(i,N)cin>>T[i];\n vector<vector<array<ll,2>>> G(N);\n rep(i,M){\n ll U,V,D;\n cin>>U>>V>>D;\n U--;V--;\n G[U].push_back({V,D});\n G[V].push_back({U,D});\n }\n vector<vector<vector<ll>>> DP(N,vector<vector<ll>>(X+1,vector<ll>(2,1e18)));\n priority_queue<array<ll,4>,vector<array<ll,4>>,greater<array<ll,4>>> Q; \n vector<vector<vector<bool>>> seen(N,vector<vector<bool>>(X+1,vector<bool>(2,0)));\n Q.push({0,0,0,0});\n DP[0][0][0]=0;\n while(!Q.empty()){\n auto P=Q.top();\n Q.pop();\n if(seen[P[1]][P[2]][P[3]])continue;\n seen[P[1]][P[2]][P[3]]=1;\n for(auto VW:G[P[1]]){\n ll V=VW[0];\n ll W=VW[1];\n ll ND=W+P[0];\n ll NX=min(X,P[2]+W);\n bool NB=P[3];\n if(T[V]==0&&P[3]&&NX<X)continue;\n if(T[V]==2&&!P[3]&&NX<X)continue;\n if(T[V]==0){\n NX=0;\n NB=0;\n }\n if(T[V]==2){\n NX=0;\n NB=1;\n }\n if(DP[V][NX][NB]>ND){\n DP[V][NX][NB]=ND;\n Q.push({ND,V,NX,NB});\n }\n }\n // if(T[P[1]]==1){\n // P[0]++;\n // P[2]++;\n // if(X>=P[2])\n // if(DP[P[1]][P[2]][P[3]]>P[0]){\n // Q.push(P);\n // DP[P[1]][P[2]][P[3]]=P[0];\n // }\n // }\n }\n ll an=1e18;\n rep(i,X+1)rep(j,2)an=min(an,DP[N-1][i][j]);\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 256068, "score_of_the_acc": -0.7665, "final_rank": 17 }, { "submission_id": "aoj_0635_9571565", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n int N, M, X;\n std::cin >> N >> M >> X;\n std::vector<int> T(N);\n for (auto& t : T) std::cin >> t;\n auto f{[&](int v, int i, bool j) -> int {\n assert(0 <= v and v < N);\n assert(0 <= i and i <= X);\n if (j) i += X;\n return v * (2 * (X + 1)) + i;\n }};\n std::vector<std::vector<std::pair<int, int>>> g(N * (2 * (X + 1)));\n // for (int v{} ; v < N ; v++) if (T[v] == 1) {\n // for (int i{} ; i < X ; i++) {\n // g[f(v, i, false)].emplace_back(f(v, std::min(X, i + 1), false), 1);\n // g[f(v, i, true)].emplace_back(f(v, std::min(X, i + 1), true), 1);\n // }\n // }\n for (int i{} ; i < M ; i++) {\n int a, b, d;\n std::cin >> a >> b >> d;\n a--; b--;\n for (int _{} ; _ < 2 ; _++, std::swap(a, b)) {\n if (T[a] == 0) {\n if (T[b] == 0) g[f(a, 0, false)].emplace_back(f(b, 0, false), d);\n else if (T[b] == 1) g[f(a, 0, false)].emplace_back(f(b, std::min(X, d), false), d);\n else {\n assert(T[b] == 2);\n if (d >= X) g[f(a, 0, false)].emplace_back(f(b, 0, true), d);\n }\n }\n else if (T[a] == 1) {\n if (T[b] == 0) {\n for (int j{} ; j <= X ; j++) g[f(a, j, false)].emplace_back(f(b, 0, false), d);\n for (int j{std::max(0, X - d)} ; j <= X ; j++) g[f(a, j, true)].emplace_back(f(b, 0, false), d);\n }\n else if (T[b] == 1) {\n for (int j{} ; j <= X ; j++) {\n g[f(a, j, false)].emplace_back(f(b, std::min(X, j + d), false), d);\n g[f(a, j, true)].emplace_back(f(b, std::min(X, j + d), true), d);\n }\n }\n else if (T[b] == 2) {\n for (int j{} ; j <= X ; j++) g[f(a, j, true)].emplace_back(f(b, 0, true), d);\n for (int j{std::max(0, X - d)} ; j <= X ; j++) g[f(a, j, false)].emplace_back(f(b, 0, true), d);\n }\n else assert(false);\n }\n else if (T[a] == 2) {\n if (T[b] == 2) g[f(a, 0, true)].emplace_back(f(b, 0, true), d);\n else if (T[b] == 1) g[f(a, 0, true)].emplace_back(f(b, std::min(X, d), true), d);\n else {\n assert(T[b] == 0);\n if (d >= X) g[f(a, 0, true)].emplace_back(f(b, 0, false), d);\n }\n }\n else assert(false);\n }\n }\n std::vector<int> dist(g.size(), (int)2e9);\n dist[f(0, 0, false)] = 0;\n using qt = std::pair<int, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n que.push(std::pair{ 0, f(0, 0, false) });\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (dist[v] < d) continue;\n for (auto [x, w] : g[v]) if (dist[x] > dist[v] + w) {\n dist[x] = dist[v] + w;\n que.push(std::pair{ dist[x], x });\n }\n }\n // for (int v{} ; v < N ; v++) {\n // for (int i{} ; i <= X ; i++) std::cout << '(' << dist[f(v, i, false)] << ',' << dist[f(v, i, true)] << ')' << ' ';\n // std::cout << '\\n';\n // }\n int ans{(int)2e9};\n for (int i{} ; i <= X ; i++) {\n ans = std::min(ans, dist[f(N - 1, i, false)]);\n ans = std::min(ans, dist[f(N - 1, i, true)]);\n }\n std::cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 242076, "score_of_the_acc": -0.8897, "final_rank": 18 }, { "submission_id": "aoj_0635_8318765", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int INF = (1<<29);\ntypedef pair<int, int> Pi;\ntypedef pair<Pi, Pi> PPi;\nint id=0, min_cost[10001][3][201];\nvector<Pi> vec[10001];\nint main(){\n int n, m, x, a, b, d;\n int t[10001];\n cin >> n >> m >> x;\n for(int i=1;i<=n;i++){\n cin >> t[i];\n }\n for(int i=0;i<m;i++){\n cin >> a >> b >> d;\n vec[a].push_back(Pi(d, b));\n vec[b].push_back(Pi(d, a));\n }\n fill_n(**min_cost, 10001*3*201, INF);\n min_cost[1][0][x] = 0;\n priority_queue<PPi, vector<PPi>, greater<PPi> > pq;\n pq.push(PPi(Pi(0, 1), Pi(0, x)));\n while(!pq.empty()){\n PPi ppi = pq.top();\n pq.pop();\n Pi edge = ppi.first;\n Pi tmp = ppi.second;\n for(int i=0;i<vec[edge.second].size();i++){\n int to = vec[edge.second][i].second;\n int dis = vec[edge.second][i].first;\n int cost = edge.first + dis;\n if(abs(tmp.first-t[to])==2 && tmp.second-dis > 0) continue;\n if(t[to]==1){\n if(min_cost[to][tmp.first][max(0, tmp.second-dis)] > cost){\n min_cost[to][tmp.first][max(0, tmp.second-dis)] = cost;\n pq.push(PPi(Pi(cost, to), Pi(tmp.first, max(0, tmp.second-dis))));\n }\n } else{\n if(min_cost[to][t[to]][x] > cost){\n min_cost[to][t[to]][x] = cost;\n pq.push(PPi(Pi(cost, to), Pi(t[to], x)));\n }\n }\n }\n }\n int ans = INF;\n for(int i=0;i<3;i++){\n for(int j=0;j<=x;j++){\n ans = min(ans, min_cost[n][i][j]);\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 27624, "score_of_the_acc": -0.0742, "final_rank": 8 }, { "submission_id": "aoj_0635_7072181", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\ntemplate<typename G>\nvector<ll> dijkstra(G &g,const vector<int>&s) {\n using PT=pair<ll,int>;\n priority_queue<PT, vector<PT>, greater<PT> > que;\n vector<ll>dist(g.size(),INF);\n for(auto v:s){\n dist[v] = 0;\n que.emplace(0, v);\n }\n while (!que.empty()) {\n PT p = que.top();\n que.pop();\n int v = p.second;\n if (dist[v] < p.first) continue;\n for(auto e:g[v]) {\n if (dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return dist;\n}\ntemplate<typename G>\nvector<ll>dijkstra(G &g,int s=0){\n return dijkstra(g,vector<int>(1,s));\n}\ntemplate<typename T,typename F,int dim>\nstruct MultiGraph{\n using A=array<int,dim>;\n A init;\n int sz;\n const F &f;\n //f:(array)->vector<pair(array,cost)>\n MultiGraph(A init, const F &f):init(init),f(f){\n sz = 1;\n for(auto s:init)sz *= s;\n }\n int to_id(A state){\n int ret = 0;\n for(int i = 0; i < init.size(); i++){\n ret *= init[i];\n ret += state[i];\n }\n return ret;\n }\n A from_id(int id){\n A ret;\n for(int i = init.size() - 1; i >= 0; i--){\n ret[i] = id % init[i];\n id /= init[i];\n }\n return ret;\n }\n vector<edge<T>> operator[](int id){\n vector<edge<T>>ret;\n auto edges = f(from_id(id));\n ret.reserve(edges.size());\n for(int i = 0; i < edges.size(); i++){\n ret.emplace_back(to_id(edges[i].first), edges[i].second);\n }\n return ret;\n }\n int size(){\n return sz;\n }\n};\n\n/*\n \n*/\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tusing A=array<int,2>;\n\tint n,m,x;cin>>n>>m>>x;\n\tvector<int>t(n);\n\trep(i,0,n)cin>>t[i];\n\tauto g=readGraph<int>(n,m,1,false,true);\n\tint off=203;\n\tint sz=407;\n auto f=[&](A state)->vector<pair<A,int>>{\n auto [i,j]=state;\n vector<pair<A,int>>ret;\n ret.reserve(g[i].size());\n\t\tfor(auto e:g[i]){\n\t\t\tint nj=j;\n\t\t\tif(nj<off){\n\t\t\t\tnj=min(nj+e.cost,off);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tnj=max(off,nj-e.cost);\n\t\t\t}\n\t\t\tif(t[e.to]==0){\n\t\t\t\tif(nj>off)continue;\n\t\t\t\tnj=off-x;\n\t\t\t}\n\t\t\tif(t[e.to]==2){\n\t\t\t\tif(nj<off)continue;\n\t\t\t\tnj=off+x;\n\t\t\t}\n\t\t\tret.EB(A{e.to,nj},e.cost);\n\t\t}\n return ret;\n };\n MultiGraph<int,decltype(f),2>mg(A{n,sz},f);\n\tauto d=dijkstra(mg,mg.to_id(A{0,off-x}));\n\tll ret=INF;\n\trep(i,0,sz)chmin(ret,d[mg.to_id(A{n-1,(int)i})]);\n\tcout<<ret<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 36236, "score_of_the_acc": -0.0892, "final_rank": 12 }, { "submission_id": "aoj_0635_6992813", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0635.cc: ヘビの JOI 君 (Snake JOI)\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 10000;\nconst int MAX_X = 200;\nconst int T = 3;\nconst int MAX_GN = MAX_N * (MAX_X + 1) * T;\nconst int INF = 1 << 30;\n\nenum { COLD = 0, FINE = 1, HOT = 2 };\n\n/* typedef */\n\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\n\n/* global variables */\n\nint ts[MAX_N], ds[MAX_GN];\nvpii nbrs[MAX_N];\n\n/* subroutines */\n\ninline int ijt2p(int i, int j, int t, int x) {\n return (i * (x + 1) + j) * T + t;\n}\n\ninline void p2ijt(int p, int &i, int &j, int &t, int x) {\n i = p / ((x + 1) * T), j = (p / T) % (x + 1), t = p % T;\n}\n\n/* main */\n\nint main() {\n int n, m, x;\n scanf(\"%d%d%d\", &n, &m, &x);\n\n for (int i = 0; i < n; i++) scanf(\"%d\", ts + i);\n\n for (int i = 0; i < m; i++) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n u--, v--;\n nbrs[u].push_back(pii(v, w));\n nbrs[v].push_back(pii(u, w));\n }\n\n int gn = n * (x + 1) * T;\n int st = ijt2p(0, x, COLD, x);\n fill(ds, ds + gn, INF);\n ds[st] = 0;\n\n priority_queue<pii> q;\n q.push(pii(0, st));\n\n int mind = INF;\n while (! q.empty()) {\n pii ue = q.top(); q.pop();\n int ud = -ue.first, u = ue.second;\n if (ds[u] != ud) continue;\n\n int ui, uj, ut;\n p2ijt(u, ui, uj, ut, x);\n if (ui == n - 1) {\n mind = ud;\n break;\n }\n\n for (auto vw: nbrs[ui]) {\n int vi = vw.first, w = vw.second;\n int vj, vt;\n if (uj > w) {\n\tif ((ut == COLD && ts[vi] == HOT) ||\n\t (ut == HOT && ts[vi] == COLD)) continue;\n\tif (ts[vi] == FINE)\n\t vj = uj - w, vt = ut;\n\telse\n\t vj = x, vt = ts[vi];\n }\n else if (ts[vi] == FINE)\n\tvj = 0, vt = FINE;\n else\n\tvj = x, vt = ts[vi];\n\n int v = ijt2p(vi, vj, vt, x);\n int vd = ud + w;\n if (ds[v] > vd) {\n\tds[v] = vd;\n\tq.push(pii(-vd, v));\n }\n }\n }\n\n printf(\"%d\\n\", mind);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 27252, "score_of_the_acc": -0.0408, "final_rank": 2 }, { "submission_id": "aoj_0635_6132346", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm> \n#include<cmath>\n#include<ctime>\n#include<map>\n#include<vector>\n#include<math.h>\n#include<stdio.h>\n#include<stack>\n#include<queue>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<bitset>\n#include<functional>\n#include <fstream>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x - 1; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\t//res++;\n\t\tres += n % 10;\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\nll kaijyo[1000005];\nvoid nCkinit(ll n, ll m) {\n\tll cnt = 1; kaijyo[0] = 1;\n\tfor (int h = 1; h <= n; h++) { cnt *= h; cnt %= m; kaijyo[h] = cnt; }\n}\nll nCk(ll n, ll k, ll m) {\n\t/*ll a = 1, b = 1;\n\tfor (int h = 1; h <= n; h++) { a *= h; a %= m; }\n\tfor (int h = 1; h <= k; h++) { b *= h; b %= m; }\n\tfor (int h = 1; h <= n - k; h++) { b *= h; b %= m; }*/\n\tll a = kaijyo[n], b = kaijyo[k] * kaijyo[n - k] % m;\n\treturn a * modpow(b, m - 2, m) % m;\n}\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to; ll cost; };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\tll now;\n\tll te;\n\tll time;\n\tll c;\n\n\tbool operator<(const status& rhs) const { return c < rhs.c; };\n\tbool operator>(const status& rhs) const { return c > rhs.c; };\n};\n\n//O(ElogV)\n//const ll INF = 10000000000000;\n//struct edge { ll to, cost; };\n//typedef pair<ll, ll>P; //firstは最短距離、secondは頂点番号\n\nll n, m, x; ll temp[10005];\n\nll d[10005][3][205];//始点sから終点tまでのコストd[t]\nvector<edge> G[213456];//コスト\nvoid dijkstra(ll s) {\n\t//greater<P>を指定→firstが小さい順\n\tpriority_queue<status, vector<status>, greater<status> >que;\n\td[s][0][0] = 0; que.push({ s, 0, 0, 0 });\n\twhile (!que.empty()) {\n\t\tstatus p = que.top(); que.pop();\n\t\tint v = p.now;\n\t\tif (d[p.now][p.te][p.time] < p.c) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\t\t\tif (abs(temp[e.to] - p.te) == 2 && p.time + e.cost < x) {//気温がダメ\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tll nexttemp = temp[e.to];\n\t\t\tll nexttime = 0;\n\t\t\tif (p.te != 1 && nexttemp == 1 && p.time + e.cost < x) {\n\t\t\t\tnexttemp = p.te; nexttime = p.time + e.cost;\n\t\t\t}\n\t\t\tif (d[e.to][nexttemp][nexttime] > p.c + e.cost) {\n\t\t\t\td[e.to][nexttemp][nexttime] = p.c + e.cost;\n\t\t\t\tque.push({ e.to,nexttemp,nexttime,p.c + e.cost });\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tsrand((unsigned)time(NULL));\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tcin >> n >> m >> x;\n\trep2(i, n) {\n\t\tcin >> temp[i];\n\t}\n\trep(i, m) {\n\t\tll a, b, d; cin >> a >> b >> d;\n\t\tG[a].push_back({ b,d });\n\t\tG[b].push_back({ a,d });\n\t}\n\trep(i, 10005) {\n\t\trep(j, 3) {\n\t\t\trep(k, 205) {\n\t\t\t\td[i][j][k] = INF;\n\t\t\t}\n\t\t}\n\t}\n\tdijkstra(1);\n\tll ans = INF;\n\trep(j, 3) {\n\t\trep(k, 205) {\n\t\t\tans = min(ans, d[n][j][k]);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 57876, "score_of_the_acc": -0.1104, "final_rank": 13 }, { "submission_id": "aoj_0635_6111686", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,x);\n vector<int> type(n);\n in(type);\n rep(i,n){\n if(type[i]==1)type[i]=2;\n else if(type[i]==2)type[i]=1;\n }\n vector<vector<pair<int,int>>> g(n);\n int u,v,s,t;\n ll c;\n rep(i,m){\n in(u,v,c);\n g[--u].emplace_back(--v,c);\n g[v].emplace_back(u,c);\n }\n rpriority_queue<tuple<ll,int,int,int>> pq;\n vector3d(ll,dist,n,2,x+1,INF2);\n dist[0][0][x]=0;\n pq.push({0,0,0,x});\n while(!pq.empty()){\n tie(c,v,s,t)=pq.top();\n pq.pop();\n for(auto p:g[v]){\n if(type[p.first]==2||t-p.second<=0){\n if(type[p.first]==2){\n if(c+p.second<dist[p.first][s][max(0,t-p.second)]){\n dist[p.first][s][max(0,t-p.second)]=c+p.second;\n pq.push({c+p.second,p.first,s,max(0,t-p.second)});\n }\n }else{\n if(c+p.second<dist[p.first][type[p.first]][x]){\n dist[p.first][type[p.first]][x]=c+p.second;\n pq.push({c+p.second,p.first,type[p.first],x});\n }\n }\n }else if(type[p.first]==s){\n if(c+p.second<dist[p.first][type[p.first]][x]){\n dist[p.first][type[p.first]][x]=c+p.second;\n pq.push({c+p.second,p.first,type[p.first],x});\n }\n }\n }\n }\n ll ans=INF2;\n rep(i,2)rep(j,x+1)chmin(ans,dist[n-1][i][j]);\n out(ans);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 36472, "score_of_the_acc": -0.0732, "final_rank": 7 }, { "submission_id": "aoj_0635_4819551", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int inf = 1012345678;\nstruct edge {\n\tint to, cost;\n};\nstruct state {\n\tint pos, level, cost;\n\tbool operator<(const state& s) const {\n\t\treturn cost > s.cost;\n\t}\n};\nint main() {\n\tint N, M, X;\n\tcin >> N >> M >> X;\n\tvector<int> T(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> T[i];\n\t}\n\tvector<vector<edge> > G(N);\n\tfor (int i = 0; i < M; ++i) {\n\t\tint a, b, c;\n\t\tcin >> a >> b >> c; --a, --b;\n\t\tG[a].push_back(edge{ b, c });\n\t\tG[b].push_back(edge{ a, c });\n\t}\n\tvector<vector<int> > dist(N, vector<int>(2 * X + 1, inf));\n\tpriority_queue<state> que;\n\tdist[0][T[0] * X] = 0;\n\tque.push(state{ 0, T[0] * X, 0 });\n\tvector<vector<bool> > vis(N, vector<bool>(2 * X + 1, false));\n\twhile (!que.empty()) {\n\t\tstate u = que.top(); que.pop();\n\t\tif (vis[u.pos][u.level]) continue;\n\t\tvis[u.pos][u.level] = true;\n\t\tfor (edge e : G[u.pos]) {\n\t\t\tint nlevel = X;\n\t\t\tif (u.level < X) nlevel = min(u.level + e.cost, X);\n\t\t\tif (u.level > X) nlevel = max(u.level - e.cost, X);\n\t\t\tint nd = dist[u.pos][u.level] + e.cost;\n\t\t\tif (T[e.to] == 0 && nlevel <= X && dist[e.to][0] > nd) {\n\t\t\t\tdist[e.to][0] = nd;\n\t\t\t\tque.push(state{ e.to, 0, nd });\n\t\t\t}\n\t\t\tif (T[e.to] == 1 && dist[e.to][nlevel] > dist[u.pos][u.level] + e.cost) {\n\t\t\t\tdist[e.to][nlevel] = dist[u.pos][u.level] + e.cost;\n\t\t\t\tque.push(state{ e.to, nlevel, nd });\n\t\t\t}\n\t\t\tif (T[e.to] == 2 && nlevel >= X && dist[e.to][2 * X] > nd) {\n\t\t\t\tdist[e.to][2 * X] = nd;\n\t\t\t\tque.push(state{ e.to, 2 * X, nd });\n\t\t\t}\n\t\t}\n\t}\n\tint ans = inf;\n\tfor (int i = 0; i <= 2 * X; ++i) {\n\t\tans = min(ans, dist[N - 1][i]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 20772, "score_of_the_acc": -0.0623, "final_rank": 5 }, { "submission_id": "aoj_0635_4797645", "code_snippet": "#include <stdio.h>\n#include <tuple>\n#include <vector>\n#include <queue>\nusing namespace std;\n \n#define MAX_N 11111\n#define MAX_TMPR 222\n \ntypedef tuple<int, int, int, int> info;\ntypedef pair<int, int> PAIR;\n \nvector<pair<int, int> > v[MAX_N];\npriority_queue<info, vector<info>, greater<info> > pq;\npair<int, int> visit[MAX_N];\nint tmpr[MAX_N];\n \nint main(void)\n{\n int n, m, x, i;\n \n scanf(\"%d %d %d\", &n, &m, &x);\n \n for (i = 1; i <= n; i++)\n {\n scanf(\"%d\", &tmpr[i]);\n visit[i] = make_pair(x + 1, x + 1);\n }\n \n while (m--)\n {\n int a, b, d;\n \n scanf(\"%d %d %d\", &a, &b, &d);\n \n v[a].push_back(make_pair(b, d));\n v[b].push_back(make_pair(a, d));\n }\n \n pq.push(make_tuple(0, 1, x, 0));\n \n int time, node, hot, cold;\n \n while (!pq.empty())\n {\n tie(time, node, hot, cold) = pq.top(); pq.pop();\n \n if (node == n)\n {\n printf(\"%d\\n\", time);\n return 0;\n }\n \n if (visit[node].first <= hot && visit[node].second <= cold)\n continue;\n visit[node] = make_pair(min(visit[node].first, hot), min(visit[node].second, cold));\n \n for (PAIR next : v[node])\n {\n int nextv = next.first;\n int nexttime = time + next.second;\n PAIR nexttemp = make_pair(max(hot - next.second, 0), max(cold - next.second, 0));\n \n if (tmpr[nextv] == 0)\n nexttemp.first = x;\n else if (tmpr[nextv] == 2)\n nexttemp.second = x;\n \n if ((nexttemp.first && nexttemp.second) || (visit[nextv].first <= nexttemp.first && visit[nextv].second <= nexttemp.second))\n continue;\n \n pq.push(make_tuple(nexttime, nextv, nexttemp.first, nexttemp.second));\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3784, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0635_4797371", "code_snippet": "#include <stdio.h>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\n\nint dp[3][201][10010];\nvector<pair<int,int>> g[10010];\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m; cin >> n >> m;\n int x; cin >> x;\n vector<int> c(n);\n for(int i=0;i<n;i++){\n cin >> c[i];\n }\n while(m--){\n int x,y,d; cin >> x >> y >> d;\n x--; y--; \n g[x].push_back(make_pair(y,d));\n g[y].push_back(make_pair(x,d));\n }\n for(int i=0;i<3;i++){\n for(int j=0;j<=200;j++){\n for(int k=0;k<n;k++){\n dp[i][j][k]=1e9;\n }\n }\n }\n dp[0][0][0]=0;\n priority_queue<pair<pair<int,int>,pair<int,int>>> q;\n q.push(make_pair(make_pair(0,0),make_pair(0,0)));\n while(q.size()){\n auto p=q.top(); q.pop();\n if(p.second.second==n-1){\n cout << -p.first.first << endl;\n return 0;\n }\n for(auto t:g[p.second.second]){\n if(c[t.first]==1){\n if(p.first.second==1){\n if(dp[1][0][t.first]>-p.first.first+t.second){\n dp[1][0][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(-dp[1][0][t.first],1),make_pair(0,t.first)));\n }\n }\n else{\n if(p.second.first+t.second>=x){\n if(dp[1][0][t.first]>-p.first.first+t.second){\n dp[1][0][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(-dp[1][0][t.first],1),make_pair(0,t.first)));\n }\n }\n else{\n if(dp[p.first.second][p.second.first+t.second][t.first]>-p.first.first+t.second){\n dp[p.first.second][p.second.first+t.second][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(p.first.first-t.second,p.first.second),make_pair(p.second.first+t.second,t.first)));\n }\n }\n }\n }\n else{\n int type=c[t.first];\n if(p.first.second==1){\n if(dp[type][0][t.first]>-p.first.first+t.second){\n dp[type][0][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(-dp[type][0][t.first],type),make_pair(0,t.first)));\n }\n }\n else{\n if(type==p.first.second){\n if(dp[type][0][t.first]>-p.first.first+t.second){\n dp[type][0][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(-dp[type][0][t.first],type),make_pair(0,t.first)));\n }\n }\n else{\n if(p.second.first+t.second>=x){\n if(dp[type][0][t.first]>-p.first.first+t.second){\n dp[type][0][t.first]=-p.first.first+t.second;\n q.push(make_pair(make_pair(-dp[type][0][t.first],type),make_pair(0,t.first)));\n }\n }\n }\n }\n }\n }\n }\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 27728, "score_of_the_acc": -0.0416, "final_rank": 3 }, { "submission_id": "aoj_0635_4229410", "code_snippet": "// #pragma GCC target(\"avx\") // CPU 処理並列化\n// #pragma GCC optimize(\"O3\") // CPU 処理並列化\n// #pragma GCC optimize(\"unroll-loops\") // 条件処理の呼び出しを減らす\n// #define BEGIN_STACK_EXTEND(size) void * stack_extend_memory_ = malloc(size);void * stack_extend_origin_memory_;char * stack_extend_dummy_memory_ = (char*)alloca((1+(int)(((long long)stack_extend_memory_)&127))*16);*stack_extend_dummy_memory_ = 0;asm volatile(\"mov %%rsp, %%rbx\\nmov %%rax, %%rsp\":\"=b\"(stack_extend_origin_memory_):\"a\"((char*)stack_extend_memory_+(size)-1024));\n// #define END_STACK_EXTEND asm volatile(\"mov %%rax, %%rsp\"::\"a\"(stack_extend_origin_memory_));free(stack_extend_memory_);\n\n#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<string>\n#include<string.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stdlib.h>\n#include<cassert>\n#include<time.h>\n#include<bitset>\n#include<numeric>\n#include<unordered_set>\n#include<unordered_map>\n#include<complex>\nusing namespace std;\nconst long long mod=1000000007;\nconst long long inf=mod*mod;\nconst long long d2=(mod+1)/2;\nconst long double EPS=1e-9;\nconst double INF=1e+10;\nconst double PI=acos(-1.0);\nconst int C_SIZE = 3100000;\nconst int UF_SIZE = 3100000;\nnamespace{\n\tlong long fact[C_SIZE];\n\tlong long finv[C_SIZE];\n\tlong long inv[C_SIZE];\n\tlong long Comb(int a,int b){\n\t \tif(a<b||b<0)return 0;\n\t \treturn fact[a]*finv[b]%mod*finv[a-b]%mod;\n\t}\n\tvoid init_C(int n){\n\t\tfact[0]=finv[0]=inv[1]=1;\n\t\tfor(int i=2;i<n;i++){\n\t\t\tinv[i]=(mod-(mod/i)*inv[mod%i]%mod)%mod;\n\t\t}\n\t\tfor(int i=1;i<n;i++){\n\t\t\tfact[i]=fact[i-1]*i%mod;\n\t\t\tfinv[i]=finv[i-1]*inv[i]%mod;\n\t\t}\n\t}\n\tlong long pw(long long a,long long b){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%mod;\n\t\t\ta=a*a%mod;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tlong long pw_mod(long long a,long long b,long long M){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%M;\n\t\t\ta=a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint pw_mod_int(int a,int b,int M){\n\t\tif(a<0)return 0;\n\t\tif(b<0)return 0;\n\t\tint ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=(long long)ret*a%M;\n\t\t\ta=(long long)a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint ABS(int a){return max(a,-a);}\n\tlong long ABS(long long a){return max(a,-a);}\n\tdouble ABS(double a){return max(a,-a);}\n\tint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\n\tint UF[UF_SIZE];\n\tvoid init_UF(int n){\n\t\tfor(int i=0;i<n;i++)UF[i]=-1;\n\t}\n\tint FIND(int a){\n\t\tif(UF[a]<0)return a;\n\t\treturn UF[a]=FIND(UF[a]);\n\t}\n\tvoid UNION(int a,int b){\n\t\ta=FIND(a);b=FIND(b);if(a==b)return;\n\t\tif(UF[a]>UF[b])swap(a,b);\n\t\tUF[a]+=UF[b];UF[b]=a;\n\t}\n}\n// ここから編集しろ\nint v[11000][2][210];\nint ijk[11000][2][210];\nvector<pair<int,int> > g[11000];\nint t[11000];\nint main(){\n\tint a,b,c;\n\tscanf(\"%d%d%d\",&a,&b,&c);\n\tfor(int i=0;i<a;i++)scanf(\"%d\",t+i);\n\tfor(int i=0;i<b;i++){\n\t\tint p,q,r;scanf(\"%d%d%d\",&p,&q,&r);p--;q--;g[p].push_back(make_pair(q,r));\n\t\tg[q].push_back(make_pair(p,r));\n\t}\n\tfor(int i=0;i<a;i++)for(int j=0;j<=c;j++)for(int k=0;k<2;k++)ijk[i][k][j]=mod;\n\tpriority_queue<pair<pair<int,int>,pair<int,int> > >Q;\n\tQ.push(make_pair(make_pair(0,0),make_pair(0,c)));\n\tijk[0][0][c]=0;\n\twhile(Q.size()){\n\t\tint cost=-Q.top().first.first;\n\t\tint at=Q.top().second.first;\n\t\tint tp=Q.top().first.second;\n\t\tint T=Q.top().second.second;Q.pop();\n\t\tif(v[at][tp][T])continue;\n\t\t// printf(\"%d %d: %d\\n\",at,T,cost);\n\t\tv[at][tp][T]=1;\n\t\tfor(int i=0;i<g[at].size();i++){\n\t\t\tint to=g[at][i].first;\n\t\t\tint toc=cost+g[at][i].second;\n\t\t\tint tt=max(T-g[at][i].second,0);\n\t\t\t// if(tt&&ABS(t[at]-t[to])==2)continue;\n\t\t\tif(tt){\n\t\t\t\tif(tp==0&&t[to]==2)continue;\n\t\t\t\tif(tp==1&&t[to]==0)continue;\n\t\t\t}\n\t\t\tif(t[to]!=1)tt=c;\n\t\t\t\n\t\t\tint ttp=tp;\n\t\t\tif(t[to]==0)ttp=0;\n\t\t\tif(t[to]==2)ttp=1;\n\t\t\tif(v[to][ttp][tt])continue;\n\t\t\tif(ijk[to][tp][tt]>toc){\n\t\t\t\tijk[to][tp][tt]=toc;\n\t\t\t\tQ.push(make_pair(make_pair(-toc,ttp),make_pair(to,tt)));\n\t\t\t}\n\t\t}\n\t}\n\tint ret=mod;\n\tfor(int i=0;i<=c;i++)ret=min(ret,min(ijk[a-1][0][i],ijk[a-1][1][i]));\n\tprintf(\"%d\\n\",ret);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 33508, "score_of_the_acc": -0.0845, "final_rank": 11 }, { "submission_id": "aoj_0635_4190626", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\ntemplate <typename T> using posteriority_queue = priority_queue<T, vector<T>, greater<T> >;\nconst int INF = 0x3f3f3f3f;\nconst ll LINF = 0x3f3f3f3f3f3f3f3fLL;\nconst double EPS = 1e-8;\nconst int MOD = 1000000007;\n// const int MOD = 998244353;\nconst int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconst int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\ntemplate <typename T> void unique(vector<T> &a) { a.erase(unique(ALL(a)), a.end()); }\nstruct IOSetup {\n IOSetup() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout << fixed << setprecision(20);\n }\n} iosetup;\n\nusing CostType = int;\nstruct Edge {\n int src, dst; CostType cost;\n Edge(int src, int dst, CostType cost = 0) : src(src), dst(dst), cost(cost) {}\n inline bool operator<(const Edge &rhs) const {\n return cost != rhs.cost ? cost < rhs.cost : dst != rhs.dst ? dst < rhs.dst : src < rhs.src;\n }\n inline bool operator<=(const Edge &rhs) const { return !(rhs < *this); }\n inline bool operator>(const Edge &rhs) const { return rhs < *this; }\n inline bool operator>=(const Edge &rhs) const { return !(*this < rhs); }\n};\n\nint main() {\n int n, m, x; cin >> n >> m >> x;\n vector<int> t(n); REP(i, n) cin >> t[i];\n vector<vector<Edge> > graph(n);\n while (m--) {\n int a, b, d; cin >> a >> b >> d; --a; --b;\n graph[a].emplace_back(a, b, d);\n graph[b].emplace_back(b, a, d);\n }\n vector<vector<ll> > dist(n, vector<ll>(2 * x + 1, LINF));\n dist[0][0] = 0;\n posteriority_queue<pair<ll, pair<int, int> > > que;\n que.emplace(0, make_pair(0, 0));\n while (!que.empty()) {\n int ver, tm; tie(ver, tm) = que.top().second;\n ll now_cost = que.top().first;\n que.pop();\n if (now_cost > dist[ver][tm]) continue;\n for (const Edge &e : graph[ver]) {\n ll cost = dist[ver][tm] + e.cost;\n if (tm < x) {\n int nx_tm;\n if (t[e.dst] == 0) {\n nx_tm = 0;\n } else if (t[e.dst] == 1) {\n nx_tm = min(tm + e.cost, x);\n } else {\n nx_tm = min(tm + e.cost, x);\n if (nx_tm < x) continue;\n nx_tm = 2 * x;\n }\n if (dist[e.dst][nx_tm] > cost) {\n dist[e.dst][nx_tm] = cost;\n que.emplace(cost, make_pair(e.dst, nx_tm));\n }\n } else if (tm == x) {\n int nx_tm = tm;\n if (t[e.dst] == 0) {\n nx_tm = 0;\n } else if (t[e.dst] == 2) {\n nx_tm = 2 * x;\n }\n if (dist[e.dst][nx_tm] > cost) {\n dist[e.dst][nx_tm] = cost;\n que.emplace(cost, make_pair(e.dst, nx_tm));\n }\n } else {\n int nx_tm;\n if (t[e.dst] == 0) {\n nx_tm = max(tm - e.cost, x);\n if (nx_tm > x) continue;\n nx_tm = 0;\n } else if (t[e.dst] == 1) {\n nx_tm = max(tm - e.cost, x);\n } else {\n nx_tm = 2 * x;\n }\n if (dist[e.dst][nx_tm] > cost) {\n dist[e.dst][nx_tm] = cost;\n que.emplace(cost, make_pair(e.dst, nx_tm));\n }\n }\n }\n }\n cout << *min_element(ALL(dist[n - 1])) << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 35532, "score_of_the_acc": -0.0716, "final_rank": 6 }, { "submission_id": "aoj_0635_4131977", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <tuple>\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\nconstexpr int X = 200, Y = X * 2 + 1;\n\nint enc(int v, int t) {\n return v * Y + t;\n}\n\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int n, m, x;\n std::cin >> n >> m >> x;\n\n std::vector<int> ts(n);\n for (auto& t : ts) std::cin >> t;\n\n int nn = n * Y;\n std::vector<std::vector<std::pair<int, int>>> graph(nn);\n while (m--) {\n int u, v, d;\n std::cin >> u >> v >> d;\n --u, --v;\n\n for (int i = 0; i < 2; ++i) {\n for (int t = 0; t < Y; ++t) {\n int nt = (t >= X ? std::max(X, t - d) : std::min(X, t + d));\n\n if (ts[v] == 1) {\n graph[enc(u, t)].emplace_back(enc(v, nt), d);\n } else if (ts[v] == 0) {\n if (nt > X) continue;\n graph[enc(u, t)].emplace_back(enc(v, X - x), d);\n } else {\n if (nt < X) continue;\n graph[enc(u, t)].emplace_back(enc(v, X + x), d);\n }\n }\n\n std::swap(u, v);\n }\n }\n\n int r = enc(0, X - x);\n std::vector<int> dist(nn, INF);\n dist[r] = 0;\n\n MinHeap<std::pair<int, int>> que;\n que.emplace(0, r);\n\n while (!que.empty()) {\n int d, v;\n std::tie(d, v) = que.top();\n que.pop();\n if (dist[v] > d) continue;\n\n for (auto p : graph[v]) {\n int u, c;\n std::tie(u, c) = p;\n if (dist[u] <= dist[v] + c) continue;\n\n dist[u] = dist[v] + c;\n que.emplace(dist[u], u);\n }\n }\n\n int ans = INF;\n for (int t = 0; t < Y; ++t) {\n ans = std::min(ans, dist[enc(n - 1, t)]);\n }\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 314796, "score_of_the_acc": -1.4424, "final_rank": 19 }, { "submission_id": "aoj_0635_3977876", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"functional\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//const int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\n\nconstexpr double EPS = 1e-8;\n\n//int N, M, K, H, W, L, R;\nlong long int N, M, K, H, W, L, R;\n\nstruct Edge {\n\tint to, cost;\n\tEdge(const int t, const int c) {\n\t\tto = t, cost = c;\n\t\treturn;\n\t}\n};\n\nstruct Node {\n\tint dis, node, flag, turn;\n\tNode(const int d, const int n, const int f, const int t) {\n\t\tdis = d, node = n, flag = f, turn = t;\n\t\treturn;\n\t}\n\tbool operator<(const Node&n)const {\n\t\treturn dis > n.dis;\n\t}\n};\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> N >> M >> K;\n\tvector<int>v(N);\n\tfor (auto &i : v)cin >> i;\n\tvector<vector<Edge>>edge(N);\n\tfor (int i = 0; i < M; i++) {\n\t\tcin >> L >> R >> H;\n\t\tL--, R--;\n\t\tedge[L].push_back(Edge(R, H));\n\t\tedge[R].push_back(Edge(L, H));\n\t}\n\tvector<vector<vector<long long int>>>dis(N, vector<vector<long long int>>(3, vector<long long int>(K + 1, MOD*MOD)));\n\tdis[0][2][K] = 0;\n\tpriority_queue<Node>PQ;\n\tPQ.push(Node(0, 0, 2, K));\n\twhile (!PQ.empty()) {\n\t\tauto box = PQ.top();\n\t\tPQ.pop();\n\t\tfor (auto i : edge[box.node]) {\n\t\t\tif (v[i.to] == box.flag&&box.turn > i.cost)continue;\n\t\t\tif (v[i.to] == 0) {\n\t\t\t\tif (dis[i.to][2][K] > box.dis + i.cost) {\n\t\t\t\t\tdis[i.to][2][K] = box.dis + i.cost;\n\t\t\t\t\tPQ.push(Node(dis[i.to][2][K], i.to, 2, K));\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if (v[i.to] == 2) {\n\t\t\t\tif (dis[i.to][0][K] > box.dis + i.cost) {\n\t\t\t\t\tdis[i.to][0][K] = box.dis + i.cost;\n\t\t\t\t\tPQ.push(Node(dis[i.to][0][K], i.to, 0, K));\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (box.turn <= i.cost) {\n\t\t\t\t\tif (dis[i.to][1][0] > box.dis + i.cost) {\n\t\t\t\t\t\tdis[i.to][1][0] = box.dis + i.cost;\n\t\t\t\t\t\tPQ.push(Node(dis[i.to][1][0], i.to, 1, 0));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tif (dis[i.to][box.flag][box.turn - i.cost] > box.dis + i.cost) {\n\t\t\t\t\t\tdis[i.to][box.flag][box.turn - i.cost] = box.dis + i.cost;\n\t\t\t\t\t\tPQ.push(Node(dis[i.to][box.flag][box.turn - i.cost], i.to, box.flag, box.turn - i.cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t//for (int i = 0; i < N; i++)for (int j = 0; j < 3; j++)for (int k = 0; k <= K; k++)if(dis[i][j][k]!=MOD*MOD)cout << i << \" \" << j << \" \" << k << \" \" << dis[i][j][k] << endl;\n\tlong long int ans = MOD * MOD;\n\tfor (auto i : dis.back())for (auto j : i)ans = min(ans, j);\n\tif (ans == MOD * MOD)ans = -1;\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 52092, "score_of_the_acc": -0.1168, "final_rank": 14 }, { "submission_id": "aoj_0635_3907613", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\n#include<random>\n#include<functional>\n#include<utility>\n\n#define rep(i,n) for(int i=0; i<n; i++)\n#define pb push_back\n#define P pair<int, int>\n#define PLI pair<ll, int>\n\nusing namespace std;\n\ntypedef long long ll;\n\n\nconst int INF = 1e9;\n\nstruct State\n{\n\tint d, v, t, n;\n\tState(int d, int v, int t, int n) :d(d), v(v), t(t), n(n) {}\n\tbool operator < (const State& s) const {\n\t\treturn d > s.d;\n\t}\n};\n\n\nstruct edge\n{\n\tint to, co;\n\tedge(int to, int co) :to(to), co(co) {}\n};\n\nint N, M, X;\nint T[10000];\nvector<edge> g[10000];\nint dist[10000][205][3];\nint main() {\n\tcin >> N >> M >> X;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> T[i];\n\t}\n\n\tfor (int i = 0; i < M; i++) {\n\t\tint a, b, d;\n\t\tcin >> a >> b >> d; a--; b--;\n\t\tg[a].emplace_back(b, d);\n\t\tg[b].emplace_back(a, d);\n\t}\n\n\t\n\tpriority_queue<State> pq;\n\tpq.emplace(0, 0, 0, 0);\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j <= X; j++) {\n\t\t\tfor (int k = 0; k < 3; k++) {\n\t\t\t\tdist[i][j][k] = INF;\n\t\t\t}\n\t\t}\n\t}\n\tdist[0][0][0] = 0;\n\tint ans;\n\twhile (!pq.empty())\n\t{\n\t\tState st = pq.top(); pq.pop();\n\t\tint v = st.v, t = st.t, n = st.n;\n\n\t\tif (st.d > dist[v][t][n]) continue;\n\n\t\tif (v == N - 1) {\n\t\t\tans = dist[v][t][n]; \n\t\t\tbreak;\n\t\t}\n\n\t\tfor (auto e : g[v]) {\n\t\t\tint nt = min(t + e.co, X);\n\t\t\tint nco = dist[v][t][n] + e.co;\n\t\t\tif (T[e.to] == n) {\n\t\t\t\tif (dist[e.to][0][n] > nco) {\n\t\t\t\t\tdist[e.to][0][n] = nco;\n\t\t\t\t\tpq.emplace(dist[e.to][0][n], e.to, 0, n);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if(T[e.to] == 1){\n\t\t\t\tif (dist[e.to][nt][n] > nco) {\n\t\t\t\t\tdist[e.to][nt][n] = nco;\n\t\t\t\t\tpq.emplace(dist[e.to][nt][n], e.to, nt, n);\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tif (nt != X) continue;\n\t\t\t\tif (dist[e.to][0][T[e.to]] > nco) {\n\t\t\t\t\tdist[e.to][0][T[e.to]] = nco;\n\t\t\t\t\tpq.emplace(dist[e.to][0][T[e.to]], e.to, 0, T[e.to]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\t\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 28096, "score_of_the_acc": -0.0423, "final_rank": 4 }, { "submission_id": "aoj_0635_3892139", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <iomanip>\n#include <map>\n#include <set>\n#include <queue>\n#include <stack>\n#include <numeric>\n#include <bitset>\n#include <cmath>\n\nstatic const int MOD = 1000000007;\nusing ll = long long;\nusing u32 = uint32_t;\nusing namespace std;\n\ntemplate<class T> constexpr T INF = ::numeric_limits<T>::max()/32*15+208;\n\nint main() {\n int n, m, x;\n cin >> n >> m >> x;\n vector<int> v(n);\n for (auto &&i : v) scanf(\"%d\", &i);\n using P = pair<int, int>;\n int N = n*2*(x+1);\n vector<vector<P>> G(N);\n for (int i = 0; i < m; ++i) {\n int a, b, d;\n scanf(\"%d %d %d\", &a, &b, &d);\n a--; b--;\n G[a].emplace_back(b, d);\n G[b].emplace_back(a, d);\n }\n auto f = [&x](int i, int j, int k){\n return i*2*(x+1) + j*(x+1) + k;\n };\n\n vector<int> d(N, INF<int>);\n priority_queue<P, vector<P>, greater<>> Q;\n d[f(0, 0, x)] = 0;\n Q.emplace(0, f(0, 0, x));\n while(!Q.empty()){\n int cost, i;\n tie(cost, i) = Q.top(); Q.pop();\n int a = i/(2*(x+1)), b = (i/(x+1)) & 1, c = i % (x+1);\n if(d[i] < cost) continue;\n auto update = [&](int x, int p) -> void{\n if(d[x] <= p) return;\n d[x] = p;\n Q.emplace(d[x], x);\n };\n for (auto &&e : G[a]) {\n int to, val; tie(to, val) = e;\n if(v[to] == 1){\n update(f(to, b, max(0, c-val)), cost+val);\n }else if(v[to] == 0) {\n if(b == 0 || max(0, c-val) == 0) update(f(to, 0, x), cost+val);\n }else {\n if(b == 1 || max(0, c-val) == 0) update(f(to, 1, x), cost+val);\n }\n }\n }\n int ans = INF<int>;\n for (int i = 0; i < 2; ++i) {\n for (int j = 0; j <= x; ++j) {\n ans = min(ans, d[f(n-1, i, j)]);\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 113416, "score_of_the_acc": -0.2398, "final_rank": 16 } ]
aoj_0634_cpp
尾根 (Ridge) 問題 JOI カルデラは景観の良さが多くの登山家に愛される美しい地形である. 特に,尾根と呼ばれる場所からの景観は絶景である. JOI カルデラの土地は南北 H キロメートル,東西 W キロメートルの長方形である. 南北,東西に 1 キロメートルごとに JOI カルデラの土地を分け,これら H×W 個の領域を区域と呼ぶ. すべての区域において,その中では標高は等しい.また,異なる区域の標高は異なる. ある区域に雨が降ると,雨水はその区域に東西南北に隣り合う最大で 4 つの区域のうち, 標高がその区域より低いような区域のすべてに流れる.そのような区域がない場合,雨水はその区域に溜まる. 他の区域から流れてきた雨水についても同様である. JOI カルデラの外側は,外輪山の急峻な崖に囲まれているため,雨水が JOI カルデラの外に流れ出すことはない. ある区域について,その区域のみに雨が降った場合,最終的に複数の区域に雨水が溜まるとき,その区域を尾根と呼ぶ. 絶景をこよなく愛する登山家たちのために,尾根の区域がいくつあるかを求めるプログラムを作成せよ. 入力 入力は 1 + H 行からなる. 1 行目には 2 個の整数 H, W (1 ≦ H ≦ 1000, 1 ≦ W ≦ 1000) が空白を区切りとして書かれており,JOI カルデラが南北に H キロメートル,東西に W キロメートルにわたることを表す. 続く H 行にはそれぞれ W 個の整数が空白を区切りとして書かれており,標高の情報を表す. H 行のうちの i 行目の j 番目 (1 ≦ i ≦ H, 1 ≦ j ≦ W) の整数 M i,j (1 ≦ M i,j ≦ H×W) は,JOI カルデラの北から i 行目,西から j 列目の区域の標高を表す. (i,j) ≠ (k,l) なら,M i,j ≠ M k,l を満たす. 出力 尾根の区域の個数を 1 行で出力せよ. 入出力例 入力例 1 3 3 2 9 4 7 5 3 6 1 8 出力例 1 4 入力例 2 3 5 5 3 8 2 14 9 10 4 1 13 12 7 11 6 15 出力例 2 4 入力例 1 において,標高が 5, 7, 8, 9 の 4 個の区域が尾根である.例えば,標高 9 の区域に雨が降った場合,最終的に雨水は標高 1, 2, 3 の 3 個の区域に溜まる.したがって,標高 9 の区域は尾根である.また,標高 6 の区域に雨が降った場合,最終的に雨水は標高 1 の区域にしか溜まらない.したがって,標高 6 の区域は尾根ではない. 入力例 2 において,標高が 8, 10, 11, 12 の 4 個の区域が尾根である. 情報オリンピック日本委員会作 『第 16 回日本情報オリンピック JOI 2016/2017 予選競技課題』
[ { "submission_id": "aoj_0634_10852542", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define INF 1LL<<60\nint main(void){\n // Your code here!\n ll h,w,ans=0;cin>>h>>w;\n vector<vector<ll>> ma(h+2,vector<ll>(w+2,INF));\n vector<vector<pair<ll,bool>>> maf(h+2,vector<pair<ll,bool>>(w+2,{-1,0}));\n vector<ll> d={-1,0,1,0,-1};\n for(ll i=0;i<h;i++)for(ll j=0;j<w;j++)cin>>ma[i+1][j+1];\n queue<pair<ll,pair<ll,ll>>> q;\n for(ll i=1;i<=h;i++)for(ll j=1;j<=w;j++){\n bool ok=1;\n for(ll k=0;k<4;k++){\n ll ni=i+d[k],nj=j+d[k+1];\n if(ma[ni][nj]<ma[i][j])ok=0;\n }\n if(ok)q.push({ma[i][j],{i,j}});\n }\n while(q.size()){\n auto [f,jf]=q.front();q.pop();\n auto [x,y]=jf;\n for(ll i=0;i<4;i++){\n ll nx=x+d[i],ny=y+d[i+1];\n if(ma[nx][ny]==INF||(maf[nx][ny].first!=-1&&maf[nx][ny].second)||ma[nx][ny]<ma[x][y])continue;\n if(maf[nx][ny].first==-1){\n maf[nx][ny].first=f;\n q.push({f,{nx,ny}});\n }else{\n if(maf[nx][ny].first!=f){\n maf[nx][ny].second=1;\n q.push({f,{nx,ny}});\n }\n }\n }\n }\n for(ll i=0;i<h;i++)for(ll j=0;j<w;j++)if(maf[i+1][j+1].first!=-1&&maf[i+1][j+1].second)ans++;\n cout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 27104, "score_of_the_acc": -0.2082, "final_rank": 7 }, { "submission_id": "aoj_0634_10849621", "code_snippet": "#include<bits/stdc++.h>\n#include<unordered_set>\nusing namespace std;\n#define ALL(a) a.begin(),a.end()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define debug(x) cerr << #x << \": \" << x << endl\n\nusing LL = long long; template<class T> using V = vector<T>;\n\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tint H, W;\n\tcin >> H >> W;\n\tV<V<int>>vs(H, V<int>(W));\n\tusing PII = pair<int, int>;\n\tV<pair<int, PII>>q;\n\tFOR(i, 0, H) {\n\t\tFOR(j, 0, W) {\n\t\t\tcin >> vs[i][j];\n\t\t\tq.push_back({ vs[i][j] ,{i,j} });\n\t\t}\n\t}\n\tconst int DY[] = { 0,0,1,-1 };\n\tconst int DX[] = { 1,-1,0,0 };\n\tSORT(q);\n\t// unordered_set\n\tV<V<V<int>>>RootFlow(H, V<V<int>>(W));\n\tFOR(i, 0, SZ(q)) {\n\t\tint m = q[i].first;\n\t\tint y = q[i].second.first, x = q[i].second.second;\n\t\tif (!SZ(RootFlow[y][x])) {\n\t\t\tRootFlow[y][x].push_back(m); // s\n\t\t}\n\t\tSORT(RootFlow[y][x]);\n\t\tUNIQ(RootFlow[y][x]);\n\t\tFOR(k, 0, 4) {\n\t\t\tint ny = y + DY[k], nx = x + DX[k];\n#define IN(a,b,c) a<=b&&b<c\n\t\t\tif (IN(0, ny, H) && IN(0, nx, W)) {\n\t\t\t\tif (vs[ny][nx] > vs[y][x]) {\n\t\t\t\t\tfor (const auto&it : RootFlow[y][x]) {\n\t\t\t\t\t\tRootFlow[ny][nx].push_back(it);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 0;\n\tFOR(i, 0, H) {\n\t\tFOR(j, 0, W) {\n\t\t\tSORT(RootFlow[i][j]);\n\t\t\tUNIQ(RootFlow[i][j]);\n\t\t\tans += (SZ(RootFlow[i][j]) > 1);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 340, "memory_kb": 110640, "score_of_the_acc": -0.9651, "final_rank": 15 }, { "submission_id": "aoj_0634_9612916", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nvector<int> dx={-1,0,1,0},dy={0,-1,0,1};\nint main() {\n int H,W;\n cin>>H>>W;\n vector<pair<int,int>> P(H*W);\n vector<vector<int>> Q(H,vector<int>(W));\n vector<vector<set<int>>> S(H,vector<set<int>>(W));\n for(int h=0;h<H;h++){\n for(int w=0;w<W;w++){\n cin>>Q[h][w];\n Q[h][w]--;\n P[Q[h][w]]={h,w};\n }\n }\n int an=0;\n for(int p=0;p<H*W;p++){\n auto [y,x]=P[p];\n for(int d=0;d<4;d++){\n int ny=y+dy[d];\n int nx=x+dx[d];\n if(ny>=0&&nx>=0&&ny<H&&nx<W&&Q[ny][nx]<Q[y][x]){\n for(auto s:S[ny][nx])S[y][x].insert(s);\n }\n }\n if(S[y][x].size()==0)S[y][x].insert(p);\n while(S[y][x].size()>2){\n S[y][x].erase(S[y][x].begin());\n }\n if(S[y][x].size()==2)an++;\n }\n cout<<an<<endl;\n \n}", "accuracy": 1, "time_ms": 440, "memory_kb": 145952, "score_of_the_acc": -1.3271, "final_rank": 18 }, { "submission_id": "aoj_0634_8930867", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 1 \"/home/kuhaku/home/github/algo/lib/algorithm/in_field.hpp\"\n#include <cstdint>\n#include <utility>\n\nnamespace internal {\n\ntemplate <int Idx>\nstruct in_field_impl {\n template <class Head, class... Tail>\n constexpr in_field_impl(Head &&head, Tail &&...tail)\n : limit(head), impl(std::forward<Tail>(tail)...) {}\n\n template <class Head, class... Tail>\n constexpr bool is_internal(Head x, Tail &&...tail) const {\n return 0 <= x && x < limit && impl.is_internal(std::forward<Tail>(tail)...);\n }\n\n private:\n std::int64_t limit;\n in_field_impl<Idx - 1> impl;\n};\n\ntemplate <>\nstruct in_field_impl<0> {\n constexpr in_field_impl() {}\n\n constexpr bool is_internal() const {\n return true;\n }\n};\n\n} // namespace internal\n\ntemplate <int Idx>\nstruct InField {\n template <class... Args, std::enable_if_t<(sizeof...(Args) == Idx)> * = nullptr>\n constexpr InField(Args &&...args) : entity(std::forward<Args>(args)...) {}\n\n template <class... Args>\n constexpr bool operator()(Args &&...args) const {\n return entity.is_internal(std::forward<Args>(args)...);\n }\n\n private:\n internal::in_field_impl<Idx> entity;\n};\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int h, w;\n cin >> h >> w;\n vector a(h, vector(w, 0));\n cin >> a;\n\n InField<2> in_field(h, w);\n\n auto flatten = [&](int x, int y) {\n return x * w + y;\n };\n\n vector<tuple<int, int, int>> v;\n rep (i, h) {\n rep (j, w) v.emplace_back(a[i][j], i, j);\n }\n sort(all(v));\n vector b(h, vector(w, -1));\n vector<int> dx = {1, -1, 0, 0}, dy = {0, 0, 1, -1};\n for (auto [t, x, y] : v) {\n rep (k, 4) {\n int nx = x + dx[k], ny = y + dy[k];\n if (!in_field(nx, ny))\n continue;\n if (b[x][y] == -2)\n continue;\n if (b[nx][ny] == -1)\n continue;\n if (b[nx][ny] == -2)\n b[x][y] = -2;\n else if (b[nx][ny] == -3 && b[x][y] == -1)\n b[x][y] = flatten(nx, ny);\n else if (b[nx][ny] == -3 && b[x][y] != flatten(nx, ny))\n b[x][y] = -2;\n else if (b[nx][ny] == -3)\n continue;\n else if (b[x][y] == -1)\n b[x][y] = b[nx][ny];\n else if (b[x][y] != b[nx][ny])\n b[x][y] = -2;\n }\n if (b[x][y] == -1)\n b[x][y] = -3;\n }\n\n int ans = 0;\n rep (i, h) {\n rep (j, w) ans += b[i][j] == -2;\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 23016, "score_of_the_acc": -0.0836, "final_rank": 3 }, { "submission_id": "aoj_0634_8923340", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto H=in(),W=in();\n\tvll P(H*W);\n\tvvll M(H,vll(W));\n\tvvll D(H,vll(W,-1)),O(H,vll(W,0));\n\tREP(i,H){\n\t\tREP(j,W){\n\t\t\tauto V=in();\n\t\t\tP[V-1] = j+i*W;\n\t\t\tM[i][j]=V;\n\t\t}\n\t}\n\tll A=0;\n\tREP(i,H*W){\n\t\tauto C=P[i];\n\t\tauto X=C%W,Y=C/W;\n\t\tset<ll> L;\n\t\tif(X>0 && M[Y][X-1]<M[Y][X]){\n\t\t\tif(O[Y][X-1]){\n\t\t\t\tO[Y][X]=1;\n\t\t\t\tA++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tL.insert(D[Y][X-1]);\n\t\t}\n\t\tif(X<W-1 && M[Y][X+1]<M[Y][X]){\n\t\t\tif(O[Y][X+1]){\n\t\t\t\tO[Y][X]=1;\n\t\t\t\tA++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tL.insert(D[Y][X+1]);\n\t\t}\n\t\tif(Y>0 && M[Y-1][X]<M[Y][X]){\n\t\t\tif(O[Y-1][X]){\n\t\t\t\tO[Y][X]=1;\n\t\t\t\tA++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tL.insert(D[Y-1][X]);\n\t\t}\n\t\tif(Y<H-1 && M[Y+1][X]<M[Y][X]){\n\t\t\tif(O[Y+1][X]){\n\t\t\t\tO[Y][X]=1;\n\t\t\t\tA++;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tL.insert(D[Y+1][X]);\n\t\t}\n\t\tif(L.empty()) D[Y][X]=M[Y][X];\n\t\telse if(L.size()==1) D[Y][X]=*L.begin();\n\t\telse{\n\t\t\tO[Y][X]=1;\n\t\t\tA++;\n\t\t}\n\t}\n\tout(A);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 34504, "score_of_the_acc": -0.199, "final_rank": 6 }, { "submission_id": "aoj_0634_7072122", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <limits>\n#include <numeric>\n#include <type_traits>\n#include <bitset>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <random>\n\nusing namespace std;\n\n#define rep(i,n,m) for(ll (i)=(n);(i)<(m);(i)++)\n#define rrep(i,n,m) for(ll (i)=(n);(i)>(m);(i)--)\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll inf = 1e9;\nconst ll INF = 1e17;\n\nvoid pline(vector<ll> lis){\n rep(i,0,lis.size()){\n printf (\"%lld\",lis[i]);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\nvoid pline(vector<pair<ll,ll>> lis){\n rep(i,0,lis.size()){\n printf (\"/%lld,%lld/\",lis[i].first,lis[i].second);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\n/*\nvoid pmap(map<ll,mint>& lis){\n for (auto p : lis){\n printf (\"%lld:%lld ,\",p.first,p.second.val());\n }\n printf (\"\\n\");\n}*/\n\n\nint main(){\n\n //ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n\n std::random_device rnd; \n std::mt19937 mt(rnd()); \n \n\n ll H,W;\n cin >> H >> W;\n\n vector<vector<ll>> A(H,vector<ll> (W,0));\n vector<vector<ll>> state(H,vector<ll> (W,0));\n\n rep(i,0,H){\n rep(j,0,W){\n cin >> A[i][j];\n }\n }\n\n vector<pair<ll,ll>> rev(H*W);\n\n rep(i,0,H){\n rep(j,0,W){\n rev[A[i][j]-1] = make_pair(i,j);\n }\n }\n\n /*\n rep(i,0,H){\n rep(j,0,W){\n state[i][j] = i*W+j+1;\n }\n }*/\n\n //rep(i,0,H) pline(state[i]);\n\n for (auto idx : rev){\n\n ll i = idx.first;\n ll j = idx.second;\n\n if (state[i][j] == 0) state[i][j] = mt();\n\n rep(d,0,4){\n ll nexi = i;\n ll nexj = j;\n if (d == 0) nexi -= 1;\n else if (d == 1) nexi += 1;\n else if (d == 2) nexj += 1;\n else nexj -= 1;\n\n if (nexi < 0 || nexi >= H || nexj < 0 || nexj >= W) continue;\n\n if (A[nexi][nexj] > A[i][j]){\n state[nexi][nexj] |= state[i][j];\n if (state[nexi][nexj] != state[i][j]){\n state[nexi][nexj] |= INF;\n }\n }\n }\n }\n\n ll ans = 0;\n\n //rep(i,0,H) pline(state[i]);\n\n rep(i,0,H){\n rep(j,0,W){\n if (state[i][j] >= INF) ans++;\n }\n }\n\n cout << ans << endl;\n\n}\n\n/*\n\ndagだよな…\n最終地点が複数あるような…\n\n\n*/", "accuracy": 1, "time_ms": 200, "memory_kb": 34368, "score_of_the_acc": -0.2541, "final_rank": 8 }, { "submission_id": "aoj_0634_7072022", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll h,w;cin>>h>>w;\n\tauto a=vec(h,w,0LL);\n\trep(i,0,h)rep(j,0,w){\n\t\tcin>>a[i][j];\n\t}\n\tauto v=vec(h,w,-1LL);\n\tqueue<P>que;\n\trep(i,0,h){\n\t\trep(j,0,w){\n\t\t\tv[i][j]=i*w+j;\n\t\t\trep(o,0,4){\n\t\t\t\tll ni=i+dx[o],nj=j+dy[o];\n\t\t\t\tif(ni>=0&&nj>=0&&ni<h&&nj<w&&a[i][j]>a[ni][nj])v[i][j]=-1;\n\t\t\t}\n\t\t\tif(v[i][j]!=-1){\n\t\t\t\tque.emplace(i,j);\n\t\t\t}\n\t\t}\n\t}\n\t//debug(v);\n\twhile(!que.empty()){\n\t\tauto [x,y]=poll(que);\n\t\trep(i,0,4){\n\t\t\tll nx=x+dx[i],ny=y+dy[i];\n\t\t\tif(nx<0||ny<0||nx>=h||ny>=w||a[nx][ny]<a[x][y])continue;\n\t\t\tif(v[nx][ny]==-1){\n\t\t\t\tv[nx][ny]=v[x][y];\n\t\t\t\tque.emplace(nx,ny);\n\t\t\t}\n\t\t\telse if(v[nx][ny]!=INF&&v[nx][ny]!=v[x][y]){\n\t\t\t\tv[nx][ny]=INF;\n\t\t\t\tque.emplace(nx,ny);\n\t\t\t}\n\t\t}\n\t}\n\t//debug(v);\n\trep(i,0,h)rep(j,0,w){\n\t\tif(v[i][j]==INF)res++;\n\t}\n\tcout<<res<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 19228, "score_of_the_acc": -0.0361, "final_rank": 1 }, { "submission_id": "aoj_0634_6992728", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0634.cc: 尾根 (Ridge)\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_H = 1000;\nconst int MAX_W = 1000;\nconst int MAX_N = MAX_H * MAX_W;\n\n/* typedef */\n\ntypedef vector<int> vi;\ntypedef queue<int> qi;\n\n/* global variables */\n\nint ms[MAX_N], ds0[MAX_N], ds1[MAX_N], pns[MAX_N];\nvi nbrs[MAX_N];\nbool rs[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int h, w;\n scanf(\"%d%d\", &h, &w);\n int n = h * w;\n\n for (int i = 0; i < n; i++) scanf(\"%d\", ms + i);\n\n for (int u = 0; u < n; u++) {\n int uy = u / w, ux = u % w;\n if (ux + 1 < w) {\n if (ms[u] < ms[u + 1])\n\tnbrs[u].push_back(u + 1), pns[u + 1]++;\n else\n\tnbrs[u + 1].push_back(u), pns[u]++;\n }\n if (uy + 1 < h) {\n if (ms[u] < ms[u + w])\n\tnbrs[u].push_back(u + w), pns[u + w]++;\n else\n\tnbrs[u + w].push_back(u), pns[u]++;\n }\n }\n \n fill(ds0, ds0 + n, -1);\n fill(ds1, ds1 + n, -1);\n qi q;\n for (int u = 0; u < n; u++)\n if (pns[u] == 0) ds0[u] = u, q.push(u);\n\n while (! q.empty()) {\n int u = q.front(); q.pop();\n for (auto v: nbrs[u]) {\n if (ds0[v] < 0)\n\tds0[v] = ds0[u], ds1[v] = ds1[u];\n else if (ds1[v] < 0)\n\tds1[v] = (ds0[v] != ds0[u]) ? ds0[u] : ds1[u];\n\n if (--pns[v] == 0) q.push(v);\n }\n }\n\n int cnt = 0;\n for (int i = 0; i < n; i++)\n if (ds1[i] >= 0) cnt++;\n\n printf(\"%d\\n\", cnt);\n return 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 73232, "score_of_the_acc": -0.503, "final_rank": 13 }, { "submission_id": "aoj_0634_6111468", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w);\n vector2d(int,A,h,w);\n in(A);\n vector<int> dp(h*w,-1);\n function<int(int,int)> rec=[&](int y,int x){\n if(dp[y*w+x]!=-1)return dp[y*w+x];\n set<int> S;\n for(int i=0;i<4;i++){\n int dy=(i==0)-(i==1);\n int dx=(i==2)-(i==3);\n if(x+dx<0||y+dy<0||x+dx>=w||y+dy>=h)continue;\n if(A[y+dy][x+dx]<A[y][x])S.insert(rec(y+dy,x+dx));\n }\n if(S.size()==0)return dp[y*w+x]=y*w+x;\n return dp[y*w+x]=(S.size()>=2?-2:*S.begin());\n };\n int ans=0;\n rep(y,h){\n rep(x,w){\n ans+=(rec(y,x)==-2);\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 73120, "score_of_the_acc": -0.4647, "final_rank": 12 }, { "submission_id": "aoj_0634_5989060", "code_snippet": "// JOI2017年予選5 尾根\n// http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0634\n#include <bits/stdc++.h>\nusing namespace std;\nint main(void) {\n int H,W;\n cin >> H >>W;\n int map[H+2][W+2];\n int onecheck[H+2][W+2];\n for(int i=0;i<H+2;i++){\n for(int j=0;j<W+2;j++){\n map[i][j]=H*W+1;\n onecheck[i][j]=0;\n }\n }\n for(int i=1;i<H+1;i++){\n for(int j=1;j<W+1;j++){\n cin >> map[i][j];\n }\n }\n // 水たまりを探す\n vector<pair<int,int> > mizutamari;\n for(int i=1;i<H+1;i++){\n for(int j=1;j<W+1;j++){\n if(map[i][j]<map[i+1][j] && map[i][j]<map[i-1][j] && map[i][j]<map[i][j+1] && map[i][j]<map[i][j-1])mizutamari.push_back(make_pair(i,j));\n }\n }\n \n for(int k=0;k<mizutamari.size();k++){\n queue<pair<int, int> >q;// キュー q を定義\n q.push(make_pair(mizutamari[k].first,mizutamari[k].second));//スタート地点をqにプッシュ\n int step[H+2][W+2];\n for(int i=0;i<H+2;i++){\n for(int j=0;j<W+2;j++){\n step[i][j]=0;\n }\n }\n while(q.empty()==false){// q が空になるまでループを回す\n pair<int, int> point=q.front();\n q.pop();\n int i=point.first;\n int j=point.second;\n if(map[i][j]<map[i+1][j] && step[i+1][j]==0 && onecheck[i+1][j]<2){step[i+1][j]=1;onecheck[i+1][j]++;q.push(make_pair(i+1,j));}\n if(map[i][j]<map[i-1][j] && step[i-1][j]==0 && onecheck[i-1][j]<2){step[i-1][j]=1;onecheck[i-1][j]++;q.push(make_pair(i-1,j));}\n if(map[i][j]<map[i][j+1] && step[i][j+1]==0 && onecheck[i][j+1]<2){step[i][j+1]=1;onecheck[i][j+1]++;q.push(make_pair(i,j+1));}\n if(map[i][j]<map[i][j-1] && step[i][j-1]==0 && onecheck[i][j-1]<2){step[i][j-1]=1;onecheck[i][j-1]++;q.push(make_pair(i,j-1));}\n }\n }\n \n int count=0;\n for(int i=1;i<H+1;i++){\n for(int j=1;j<W+1;j++){\n if(onecheck[i][j]>1)count++;\n }\n }\n \n \n cout << count << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 14900, "score_of_the_acc": -0.1434, "final_rank": 5 }, { "submission_id": "aoj_0634_5489007", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 1000000007;\n// constexpr int MOD = 998244353;\nconstexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconstexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int h, w; cin >> h >> w;\n vector m(h, vector(w, 0)); REP(i, h) REP(j, w) cin >> m[i][j], --m[i][j];\n vector<pair<int, int>> ord(h * w);\n REP(i, h) REP(j, w) ord[m[i][j]] = {i, j};\n vector ans(h, vector(w, vector<int>{}));\n REP(i, h * w) {\n auto [y, x] = ord[i];\n bool is_low = true;\n REP(k, 4) {\n int ny = y + dy[k], nx = x + dx[k];\n if (0 <= ny && ny < h && 0 <= nx && nx < w) is_low &= m[ny][nx] > m[y][x];\n }\n if (is_low) {\n ans[y][x].emplace_back(m[y][x]);\n } else {\n REP(k, 4) {\n int ny = y + dy[k], nx = x + dx[k];\n if (0 <= ny && ny < h && 0 <= nx && nx < w && m[ny][nx] < m[y][x]) {\n copy(ALL(ans[ny][nx]), back_inserter(ans[y][x]));\n }\n }\n sort(ALL(ans[y][x]));\n ans[y][x].erase(unique(ALL(ans[y][x])), ans[y][x].end());\n if (ans[y][x].size() > 2) ans[y][x].resize(2);\n }\n }\n int ridge = 0;\n REP(i, h) REP(j, w) ridge += ans[i][j].size() == 2;\n cout << ridge << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 69520, "score_of_the_acc": -0.6149, "final_rank": 14 }, { "submission_id": "aoj_0634_5039316", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0; i< (n); i++)\nusing namespace std;\ntypedef long long ll;\nconst int mod = 1000000007;\nconst int inf = (1<<30);\nint h,w;\nint tebl[1005][1005]={};\nint memo[1005][1005]={};//チェックしていない0 複数ある -1 一つしかない その場所\n\nint dx[4]={1,-1,0,0};\nint dy[4]={0,0,1,-1};\n\n\nbool check(int y,int x){\n\treturn (x>=0 && y>=0 && x<w && y<h);\n}\n\n\n\n\nint dp(int y,int x){\n\tif(memo[y][x]!=0) return memo[y][x];\n\tint k=0;//何も入っていないかどうか\n\tfor(int i=0; i<4; i++){\n\t\tif(check(y+dy[i],x+dx[i])){\n\t\t\tif(tebl[y][x]>tebl[y+dy[i]][x+dx[i]]){//そこに水が流れるか\n\t\t\t\tint l=dp(y+dy[i],x+dx[i]);\n\t\t\t\tif(l==-1) return memo[y][x]=-1;\n\t\t\t\tif(k==0){\n\t\t\t\t\tk=l;\n\t\t\t\t}else if( k!=l){\n\t\t\t\t\treturn memo[y][x]=-1;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(k==0){\n\t\treturn memo[y][x]=tebl[y][x];\n\t}else{\n\t\treturn memo[y][x]=k;\n\t}\n\treturn 0;\n}\n\n\n\n\n\nint main(){\n\tcin>>h>>w;\n\trep(i,h){\n\t\trep(j,w){\n\t\t\tcin>>tebl[i][j];\n\t\t}\n\t}\n\tint ans=0;\n\trep(i,h){\n\t\trep(j,w){\n\t\t\tif(dp(i,j)==-1){\n\t\t\t\tans++;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 49856, "score_of_the_acc": -0.4093, "final_rank": 11 }, { "submission_id": "aoj_0634_4905176", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\n\nll in[1015][1015];\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\ttypedef pair<ll, ll> P;\n\n\tll n, m; cin >> n >> m;\n\tvector<P> v(n * m + 5);\n\trep(i, 1005) {\n\t\trep(j, 1005) {\n\t\t\tin[i][j] = INF;\n\t\t}\n\t}\n\trep2(i, n) {\n\t\trep2(j, m) {\n\t\t\tcin >> in[i][j];\n\t\t\tv[in[i][j]] = P(i, j);\n\t\t}\n\t}\n\tvector<vector<vector<ll>>> one(n + 5, vector<vector<ll>>(m + 5));\n\t//map<ll, map<ll, map<ll, ll>>> used;\n\tll ans = 0;\n\trep2(i, n * m) {\n\t\tll nx = v[i].first, ny = v[i].second, cnt = 0;\n\t\t//cout << nx << ' ' << ny << endl;\n\t\trep(j, 4) {\n\t\t\tif (in[nx + dx[j]][ny + dy[j]] < i) {\n\t\t\t\t//cout << ' ' << j << endl;\n\t\t\t\trep(k, one[nx + dx[j]][ny + dy[j]].size()) {\n\t\t\t\t\t//重複していないか\n\t\t\t\t\tbool flag = true;\n\t\t\t\t\trep(l, one[nx][ny].size()) {\n\t\t\t\t\t\tif (one[nx][ny][l] == one[nx + dx[j]][ny + dy[j]][k]) {\n\t\t\t\t\t\t\tflag = false; break;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tif (flag) {\n\t\t\t\t\t\tone[nx][ny].push_back(one[nx + dx[j]][ny + dy[j]][k]);\n\t\t\t\t\t\tcnt++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (cnt >= 2) { ans++; }\n\t\tif (cnt == 0) { one[nx][ny].push_back(i); }\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 119064, "score_of_the_acc": -1.0011, "final_rank": 16 }, { "submission_id": "aoj_0634_4819517", "code_snippet": "#include <vector>\n#include <iostream>\nusing namespace std;\nconst vector<int> dx = { 0, 1, 0, -1 };\nconst vector<int> dy = { 1, 0, -1, 0 };\nint main() {\n\tint H, W;\n\tcin >> H >> W;\n\tvector<int> A(H * W), IA(H * W);\n\tfor (int i = 0; i < H * W; ++i) {\n\t\tcin >> A[i]; --A[i];\n\t\tIA[A[i]] = i;\n\t}\n\tvector<int> dp(H * W, -1);\n\tint ans = 0;\n\tfor (int i = 0; i < H * W; ++i) {\n\t\tint sx = IA[i] / W, sy = IA[i] % W;\n\t\tint reach = -1;\n\t\tbool several = false;\n\t\tfor (int j = 0; j < 4; ++j) {\n\t\t\tint tx = sx + dx[j], ty = sy + dy[j], g = tx * W + ty;\n\t\t\tif (0 <= tx && tx < H && 0 <= ty && ty < W && A[g] < i) {\n\t\t\t\tif (dp[g] == -1) several = true;\n\t\t\t\telse if (reach == -1) reach = dp[g];\n\t\t\t\telse if (reach != dp[g]) several = true;\n\t\t\t}\n\t\t}\n\t\tif (several) dp[IA[i]] = -1;\n\t\telse if (reach != -1) dp[IA[i]] = reach;\n\t\telse dp[IA[i]] = IA[i];\n\t\tif (dp[IA[i]] == -1) ++ans;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 14480, "score_of_the_acc": -0.1402, "final_rank": 4 }, { "submission_id": "aoj_0634_4797334", "code_snippet": "#include <stdio.h>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\n\nint dx[]={1,-1,0,0};\nint dy[]={0,0,1,-1};\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int h,w; cin >> h >> w;\n vector<vector<int>> a(h,vector<int>(w,0));\n map<int,pair<int,int>> mp;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cin >> a[i][j];\n mp[a[i][j]]=make_pair(i,j);\n }\n }\n vector<int> v(h*w,0);\n for(int i=1;i<=h*w;i++){\n if(!v[i])v[i]=i;\n int x=mp[i].first,y=mp[i].second;\n for(int j=0;j<4;j++){\n int nx=x+dx[j],ny=y+dy[j];\n if(0<=nx&&nx<h&&0<=ny&&ny<w){\n if(a[nx][ny]<i)continue;\n int t=a[nx][ny];\n if(!v[t])v[t]=v[i];\n else if(v[t]!=v[i])v[t]=-1;\n }\n }\n }\n int res=0;\n for(int i=1;i<=h*w;i++){\n if(v[i]<0)res++;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 860, "memory_kb": 73240, "score_of_the_acc": -1.1666, "final_rank": 17 }, { "submission_id": "aoj_0634_4745358", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < (n); ++i)\nusing namespace std;\nusing Pair = pair<int, int>;\n\n// → ↑ ← ↓\nconst int dy[4] = {0, 1, 0, -1};\nconst int dx[4] = {1, 0, -1, 0};\n\nint main() {\n int H, W;\n cin >> H >> W;\n vector<vector<int>> M(H, vector<int>(W));\n vector<vector<int>> T(H, vector<int>(W));\n map<int, Pair> mp;\n rep(i, H) rep(j, W) {\n cin >> M[i][j];\n mp[M[i][j]] = make_pair(i, j);\n T[i][j] = M[i][j];\n }\n rep(h, H * W) {\n int y = mp[h + 1].first;\n int x = mp[h + 1].second;\n set<int> st;\n rep(i, 4) {\n int ny = y + dy[i], nx = x + dx[i];\n if(ny < 0 || ny >= H || nx < 0 || nx >= W) continue;\n if(M[y][x] > M[ny][nx]) {\n st.insert(T[ny][nx]);\n }\n }\n if(st.size() == 1) T[y][x] = *st.begin();\n else if(st.size() > 1) T[y][x] = 0;\n }\n int ans = 0;\n rep(i, H) rep(j, W) {\n if(T[i][j] == 0) ans++;\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 1160, "memory_kb": 73196, "score_of_the_acc": -1.4466, "final_rank": 19 }, { "submission_id": "aoj_0634_4665712", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define rrep(i,n) for(int (i)=1;i<=(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint h, w;\nconst int dx[4] = {-1, 0, 1, 0};\nconst int dy[4] = {0, -1, 0, 1};\nint fld[1001][1001];\nint cnt[1001][1001];\n\nbool isOK(int x, int y) {\n\tif(0 <= x && x < w && 0 <= y && y < h) return 1;\n\treturn 0;\n}\n\nbool isvalley(int x, int y) {\n\trep(i, 4) {\n\t\tint nx = x + dx[i];\n\t\tint ny = y + dy[i];\n\t\tif(isOK(nx, ny)) {\n\t\t\tif(fld[ny][nx] < fld[y][x]) return 0;\n\t\t}\n\t}\n\treturn 1;\n}\n\nvoid bfs(int sx, int sy) {\n\tif(!isvalley(sx, sy)) return ;\n\tcnt[sy][sx]++;\n\n\tqueue<P> que;\n\tvector<vector<int>> came(h, vector<int>(w, 0));\n\tque.push(P(sx, sy));\n\twhile(!que.empty()) {\n\t\tP p = que.front();\n\t\tque.pop();\n\t\trep(i, 4) {\n\t\t\tint nx = p.first + dx[i];\n\t\t\tint ny = p.second + dy[i];\n\t\t\tif(!isOK(nx, ny)) continue;\n\t\t\tif(!came[ny][nx] && fld[p.second][p.first] < fld[ny][nx]) {\n\t\t\t\tcame[ny][nx] = 1;\n\t\t\t\tque.push(P(nx, ny));\n\t\t\t\tcnt[ny][nx]++;\n\t\t\t}\n\t\t}\n\t}\n}\n\nsigned main() {\n\tcin.tie(0);\n\tcout.tie(0);\n\tios::sync_with_stdio(false);\n\t//cout << fixed << setprecision(15);\n\t\n\tcin >> h >> w;\n\trep(i, h) rep(j, w) cin >> fld[i][j];\n\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tbfs(j, i);\n\t\t}\n\t}\n\t// rep(i, h) {\n\t// \trep(j, w) cout << cnt[i][j] << \" \";\n\t// \tcout << endl;\n\t// }\n\tint ans = 0;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tif(cnt[i][j] != 1) ans++;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 26200, "score_of_the_acc": -0.3415, "final_rank": 10 }, { "submission_id": "aoj_0634_4131978", "code_snippet": "#include <iostream>\n#include <vector>\n#include <set>\n#include <tuple>\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconst std::vector<int>\n dx{-1, 0, 1, 0},\n dy{0, -1, 0, 1};\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n auto xss = vec(h, vec(w, 0));\n std::vector<std::pair<int, int>> pos(h * w);\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n auto& a = xss[x][y];\n std::cin >> a;\n pos[--a] = std::make_pair(x, y);\n }\n }\n\n auto to = vec(h, vec(w, 0));\n for (auto p : pos) {\n int x, y;\n std::tie(x, y) = p;\n\n std::set<int> tos;\n for (int i = 0; i < 4; ++i) {\n int nx = x + dx[i],\n ny = y + dy[i];\n if (nx < 0 || h <= nx || ny < 0 || w <= ny ||\n xss[nx][ny] > xss[x][y]) continue;\n\n if (to[nx][ny] < 0) to[x][y] = -1;\n tos.insert(to[nx][ny]);\n }\n\n if (to[x][y] < 0) continue;\n\n if (tos.empty()) tos.insert(xss[x][y]);\n if (tos.size() >= 2) tos.insert(-1);\n to[x][y] = *tos.begin();\n }\n\n int ans = 0;\n for (int x = 0; x < h; ++x) {\n for (int y = 0; y < w; ++y) {\n if (to[x][y] < 0) ++ans;\n }\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 18648, "score_of_the_acc": -0.0784, "final_rank": 2 }, { "submission_id": "aoj_0634_4054905", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint h, w;\nint m[1010][1010];\nbool visited[1010][1010];\nvector<int> dp[1010][1010];\n\nvoid dfs(int y, int x) {\n\tif(visited[y][x]) return;\n\t// cerr << y << \" \" << x << '\\n';\n\tvisited[y][x] = true;\n\tconst int dy[] = {0, 1, 0, -1};\n\tconst int dx[] = {1, 0, -1, 0};\n\tfor(int i = 0; i < 4; ++i) {\n\t\tint ny = y + dy[i];\n\t\tif(ny < 0 or h <= ny) continue;\n\t\tint nx = x + dx[i];\n\t\tif(nx < 0 or w <= nx) continue;\n\t\tif(m[y][x] > m[ny][nx]) {\n\t\t\tdfs(ny, nx);\n\t\t\tfor(int d : dp[ny][nx]) {\n\t\t\t\tdp[y][x].push_back(d);\n\t\t\t}\n\t\t}\n\t}\n\tif(dp[y][x].size() == 0) dp[y][x].push_back(m[y][x]);\n\tsort(dp[y][x].begin(), dp[y][x].end());\n\tdp[y][x].erase(unique(dp[y][x].begin(), dp[y][x].end()), dp[y][x].end());\n}\n\nint main() {\n\tcin >> h >> w;\n\tfor(int i = 0; i < h; ++i) {\n\t\tfor(int j = 0; j < w; ++j) {\n\t\t\tcin >> m[i][j];\n\t\t}\n\t}\n\tint ans = 0;\n\tfor(int i = 0; i < h; ++i) {\n\t\tfor(int j = 0; j < w; ++j) {\n\t\t\tdfs(i, j);\n\t\t\t// cerr << i << \" \" << j << '\\n';\n\t\t\t// for(int k : dp[i][j]) {\n\t\t\t// \tcerr << k << '\\n';\n\t\t\t// }\n\t\t\tif(dp[i][j].size() > 1) {\n\t\t\t\t++ans;\n\t\t\t}\n\t\t}\n\t}\n\tcout << ans << '\\n';\n\treturn 0;\n}", "accuracy": 0.4, "time_ms": 360, "memory_kb": 101952, "score_of_the_acc": -0.9177, "final_rank": 20 }, { "submission_id": "aoj_0634_4044291", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define spa << \" \" <<\n#define test cout<<\"test\"<<endl;\n#define fi first\n#define se second\n#define MP make_pair\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD = 1e9+7;\n//const ll MOD = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T>\nvoid chmin(T &a,T b){if(a>b)a=b;}\ntemplate<typename T>\nvoid chmax(T &a,T b){if(a<b)a=b;}\nvoid pmod(ll &a,ll b){a=(a+b)%MOD;}\nvoid pmod(ll &a,ll b,ll c){a=(b+c)%MOD;}\nvoid qmod(ll &a,ll b){a=(a*b)%MOD;}\nvoid qmod(ll &a,ll b,ll c){a=(b*c)%MOD;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>\nvoid ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T>\nvoid debug(vector<vector<T>>&v,ll h,ll w){for(ll i=0;i<h;i++)\n{cout<<v[i][0];for(ll j=1;j<w;j++)cout spa v[i][j];cout<<endl;}};\nvoid debug(vector<string>&v,ll h,ll w){for(ll i=0;i<h;i++)\n{for(ll j=0;j<w;j++)cout<<v[i][j];cout<<endl;}};\ntemplate<typename T>\nvoid debug(vector<T>&v,ll n){if(n!=0)cout<<v[0];\nfor(ll i=1;i<n;i++)cout spa v[i];cout<<endl;};\ntemplate<typename T>\nvector<vector<T>>vec(ll x, ll y, T w){\n vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,0,-1,0,1,1,-1,-1};\nvector<ll>dy={0,1,0,-1,1,-1,1,-1};\ntemplate<typename T>\nvector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>\nauto make_v(size_t a,Ts... ts){\n return vector<decltype(make_v(ts...))>(a,make_v(ts...));\n}\nostream &operator<<(ostream &os, pair<ll, ll>&p){\n return os << p.first << \" \" << p.second;\n} \n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n //cout<<fixed<<setprecision(10);\n ll res=0,buf=0;\n bool judge = true;\n ll h,w;cin>>h>>w;\n auto v=vec(h,w,0LL);\n rep(i,0,h)rep(j,0,w)cin>>v[i][j];\n vector<pair<ll,P>>idx;\n rep(i,0,h)rep(j,0,w){\n idx.EB(v[i][j],MP(i,j));\n }\n auto ret=vec(h,w,-1LL);\n auto t=vec(h,w,false);\n sort(ALL(idx));\n rep(i,0,h*w){\n set<ll>st;\n ll kx=idx[i].se.fi,ky=idx[i].se.se;\n rep(j,0,4){\n ll x=idx[i].se.fi+dx[j];\n ll y=idx[i].se.se+dy[j];\n if(x<0||y<0||x>=h||y>=w)continue;\n if(ret[x][y]>=0)st.insert(ret[x][y]);\n if(t[x][y])t[idx[i].se.fi][idx[i].se.se]=true;\n }\n if(st.size()>=2)t[idx[i].se.fi][idx[i].se.se]=true;\n if(st.size()==0)ret[kx][ky]=kx*h+ky;\n if(st.size()==1)ret[kx][ky]=*st.begin();\n }\n //debug(t,h,w);\n //debug(ret,h,w);\n rep(i,0,h)rep(j,0,w)if(t[i][j])res++;\n cout<<res<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 42228, "score_of_the_acc": -0.3326, "final_rank": 9 } ]
aoj_0636_cpp
Foehn Phenomena In the Kingdom of IOI, the wind always blows from sea to land. There are $N + 1$ spots numbered from $0$ to $N$. The wind from Spot $0$ to Spot $N$ in order. Mr. JOI has a house at Spot $N$. The altitude of Spot $0$ is $A_0 = 0$, and the altitude of Spot $i$ ($1 \leq i \leq N$) is $A_i$. The wind blows on the surface of the ground. The temperature of the wind changes according to the change of the altitude. The temperature of the wind at Spot $0$, which is closest to the sea, is $0$ degree. For each $i$ ($0 \leq i \leq N - 1$), the change of the temperature of the wind from Spot $i$ to Spot $i + 1$ depends only on the values of $A_i$ and $A_{i+1}$ in the following way: If $A_i < A_{i+1}$, the temperature of the wind decreases by $S$ degrees per altitude. If $A_i \geq A_{i+1}$, the temperature of the wind increases by $T$ degrees per altitude. The tectonic movement is active in the land of the Kingdom of IOI. You have the data of tectonic movements for $Q$ days. In the $j$-th ($1 \leq j \leq Q$) day, the change of the altitude of Spot $k$ for $L_j \leq k \leq R_j$ ($1 \leq L_j \leq R_j \leq N$) is described by $X_j$. If $X_j$ is not negative, the altitude increases by $X_j$. If $X_j$ is negative, the altitude decreases by $|X_j|$. Your task is to calculate the temperature of the wind at the house of Mr. JOI after each tectonic movement. Task Given the data of tectonic movements, write a program which calculates, for each $j$ ($1 \leq j \leq Q$), the temperature of the wind at the house of Mr. JOI after the tectonic movement on the $j$-th day. Input Read the following data from the standard input. The first line of input contains four space separated integers $N$, $Q$, $S$, $T$. This means there is a house of Mr. JOI at Spot $N$, there are $Q$ tectonic movements, the temperature of the wind decreases by $S$ degrees per altitude if the altitude increases, and the temperature of the wind increases by $T$ degrees per altitude if the altitude decreases. The $i$-th line ($1 \leq i \leq N +1$) of the following $N +1$ lines contains an integer $A_{i-1}$, which is the initial altitude at Spot ($i - 1$) before tectonic movements. The $j$-th line ($1 \leq j \leq Q$) of the following $Q$ lines contains three space separated integers $L_j$, $R_j$, $X_j$. This means, for the tectonic movement on the $j$-th day, the change of the altitude at the spots from $L_j$ to $R_j$ is described by $X_j$. Output Write $Q$ lines to the standard output. The $j$-th line ($1 \leq j \leq Q$) of output contains the temperature of the wind at the house of Mr. JOI after the tectonic movement on the $j$-th day. Constraints All input data satisfy the following conditions. $1 \leq N \leq 200 000.$ $1 \leq Q \leq 200 000.$ $1 \leq S \leq 1 000 000.$ $1 \leq T \leq 1 000 000.$ $A_0 = 0.$ $-1 000 000 \leq A_i \leq 1 000 000 (1 \leq i \leq N).$ $1 \leq L_j \leq R_j \leq N (1 \leq j \leq Q).$ $ -1 000 000 \leq X_j \leq 1 000 000 (1 \leq j \leq Q).$ Sample Input and Output S ...(truncated)
[ { "submission_id": "aoj_0636_10852776", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<n;i++)\n#define fs first\n#define sc second\n#define MAXN 200005\n#define LIMIT 1500\n#define LOGN 20\n#define ll long long\n#define pb push_back\n#define ld long double\nusing namespace std;\nll n,q,s,t;\nll arr[MAXN],tree[4*MAXN],lazy[4*MAXN];\nbool de[MAXN];\ninline void checkLazy(int pos, int l, int r){\n\tif(lazy[pos]==0)return;\n\ttree[pos]+=lazy[pos];\n\tif(l!=r){\n\t\tlazy[2*pos]+=lazy[pos];\n\t\tlazy[2*pos+1]+=lazy[pos];\n\t}\n\tlazy[pos]=0;\n}\nvoid upd(int pos, int l, int r, int ql, int qr, ll val){\n\t//cout<<pos<<' '<<l<<' '<<r<<' '<<ql<<' '<<qr<<' '<<val<<endl;\n\tcheckLazy(pos,l,r);\n\tif(l>qr||r<ql)return;\n\tif(ql<=l&&r<=qr){\n\t\tlazy[pos]+=val;\n\t\tcheckLazy(pos,l,r);\n\t\treturn;\n\t}\n\tint mid=(l+r)/2;\n\tupd(2*pos,l,mid,ql,qr,val);\n\tupd(2*pos+1,mid+1,r,ql,qr,val);\n}\nll query(int pos, int l, int r, int x){\n\tcheckLazy(pos,l,r);\n\tif(l==r)return tree[pos];\n\tint mid=(l+r)/2;\n\tif(x<=mid)return query(2*pos,l,mid,x);\n\telse return query(2*pos+1,mid+1,r,x);\n}\nll alt=0;\nint main(){\n\tios::sync_with_stdio(0);\n\tcin>>n>>q>>s>>t;\n\tn++;\n\trep(i,n)cin>>arr[i];\n\trep(i,n-1){\n\t\tif(arr[i]<arr[i+1])alt-=(arr[i+1]-arr[i])*s;\n\t\telse alt-=(arr[i+1]-arr[i])*t;\n\t}\n\t//cout<<alt<<endl;\n\tint l,r;\n\tll x;\n\trep(i,q){\n\t\tcin>>l>>r>>x;\n\t\tll tmp1,tmp2;\n\t\tif(l!=0){\n\t\t\ttmp1=arr[l-1]+query(1,0,n-1,l-1),tmp2=arr[l]+query(1,0,n-1,l);\n\t\t\tif(tmp1<tmp2){\n\t\t\t\talt+=(tmp2-tmp1)*s;\n\t\t\t}else{\n\t\t\t\talt+=(tmp2-tmp1)*t;\n\t\t\t}\n\t\t}\n\t\tif(r!=n-1){\n\t\t\ttmp1=arr[r]+query(1,0,n-1,r),tmp2=arr[r+1]+query(1,0,n-1,r+1);\n\t\t\tif(tmp1<tmp2){\n\t\t\t\talt+=(tmp2-tmp1)*s;\n\t\t\t}else{\n\t\t\t\talt+=(tmp2-tmp1)*t;\n\t\t\t}\n\t\t}\n\t\tupd(1,0,n-1,l,r,x);\n\t\tif(l!=0){\n\t\t\ttmp1=arr[l-1]+query(1,0,n-1,l-1),tmp2=arr[l]+query(1,0,n-1,l);\n\t\t\tif(tmp1<tmp2){\n\t\t\t\talt-=(tmp2-tmp1)*s;\n\t\t\t}else{\n\t\t\t\talt-=(tmp2-tmp1)*t;\n\t\t\t}\n\t\t}\n\t\tif(r!=n-1){\n\t\t\ttmp1=arr[r]+query(1,0,n-1,r),tmp2=arr[r+1]+query(1,0,n-1,r+1);\n\t\t\tif(tmp1<tmp2){\n\t\t\t\talt-=(tmp2-tmp1)*s;\n\t\t\t}else{\n\t\t\t\talt-=(tmp2-tmp1)*t;\n\t\t\t}\n\t\t}\n\t\tcout<<alt<<endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 17112, "score_of_the_acc": -0.9894, "final_rank": 16 }, { "submission_id": "aoj_0636_10690859", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int MAX = 200020;\nll tree[4*MAX], lazy[4*MAX];\nll H, a[MAX];\nint n, q, s, t, d;\nvoid build(int idx, int l, int r){\n\tif (l==r){\n\t\ttree[idx] = a[l];\n\t\treturn;\n\t}\n\tint mid = (l+r)/2;\n\tbuild(2*idx, l, mid);\n\tbuild(2*idx+1, mid+1, r);\n\treturn;\n}\nvoid propagate(int idx, int l, int r){\n\tif (lazy[idx]==0) return;\n\ttree[idx] += lazy[idx]*(r-l+1);\n\tif (l!=r){\n\t\tlazy[idx*2] += lazy[idx];\n\t\tlazy[idx*2+1] += lazy[idx];\n\t}\n\tlazy[idx] = 0;\n\treturn;\n}\nvoid update(int idx, int l, int r, int a, int b, ll val){\n\tpropagate(idx, l, r);\n\tif (r < a || l > b) return;\n\tif (l >= a && r <= b){\n\t\tlazy[idx] += val;\n\t\tpropagate(idx, l, r);\n\t\treturn;\n\t}\n\tint mid = (l+r)/2;\n\tupdate(idx*2, l, mid, a, b, val);\n\tupdate(idx*2+1, mid+1, r, a, b, val);\n\ttree[idx] = tree[idx*2] + tree[idx*2+1];\n\t\n}\nll query(int idx, int l, int r, int x){\n\tif (x==0) return 0;\n\tif (x == n+1) return 0;\n\tpropagate(idx, l, r);\n\tif (l==x && r==x){\n\t\treturn tree[idx];\n\t}\n\tif (l > x || r < x) return 0;\n\tint mid = (l+r)/2;\n\treturn query(idx*2, l, mid, x)+query(idx*2+1, mid+1, r, x);\n\t\n}\nll sel(ll a, ll b){\n\tif (b> a){\n\t\treturn -1*(b-a)*(ll)s;\n\t}\n\treturn (a-b)*(ll)t;\n}\nint main(){\n\tscanf(\"%d%d%d%d\", &n, &q, &s, &t);\n\tscanf(\"%d\", &d);\n\tfor (int i= 1; i <= n; i++){\n\t\tscanf(\"%lld\", &a[i]);\n\t}\n\tbuild(1, 1, n);\n\tint now = 0;\n\tfor (int i = 1; i<= n; i++){\n\t\tH += sel(now, a[i]);\n\t\tnow = a[i];\n\t}\n\tint x, l, r;\n\twhile(q--){\n\t\tscanf(\"%d%d%d\", &l, &r, &x);\n\t\tint p1 = query(1, 1, n, l-1);\n\t\tint p2 = query(1, 1, n, l);\n\t\tint q1 = query(1, 1, n, r);\n\t\tint q2 = query(1, 1, n, r+1);\n\t\tupdate(1, 1, n, l, r, x);\n\t//\tprintf(\"%d %d %d %d\\n\", p1, p2, q1, q2);\n\t\tll F = sel(p1, p2+x) - sel(p1, p2 );\n\t\tif (r!=n) F += sel(q1+x, q2) - sel(q1, q2);\n\t\tH += F;\n\t\tcout << H << \"\\n\";\n\t\t\n\t\t\n\t}\n}", "accuracy": 0.4909090909090909, "time_ms": 250, "memory_kb": 15780, "score_of_the_acc": -0.6988, "final_rank": 20 }, { "submission_id": "aoj_0636_10106071", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int long long\n\nint get_delta(int diff, int s, int t) {\n if (diff > 0)\n return -diff * s;\n else\n return -diff * t;\n}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, q, s, t;\n cin >> n >> q >> s >> t;\n vector<int> arr(n + 1);\n for (auto &el : arr)\n cin >> el;\n vector<int> diff(n);\n\n int ans = 0;\n for (int i = 0; i < n; ++i) {\n diff[i] = arr[i + 1] - arr[i];\n ans += get_delta(diff[i], s, t);\n }\n for (int qq = 0; qq < q; ++qq) {\n int l, r, x;\n cin >> l >> r >> x;\n ans -= get_delta(diff[l - 1], s, t);\n diff[l - 1] += x;\n ans += get_delta(diff[l - 1], s, t);\n if (r < n) {\n ans -= get_delta(diff[r], s, t);\n diff[r] -= x;\n ans += get_delta(diff[r], s, t);\n }\n cout << ans << '\\n';\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6240, "score_of_the_acc": -0.0419, "final_rank": 4 }, { "submission_id": "aoj_0636_9739732", "code_snippet": "#include <bits/stdc++.h>\n\n#define el \"\\n\"\n#define fu(i, a, b) for (long long i = a; i <= b; ++i)\n#define fd(i, a, b) for (long long i = a; i >= b; --i)\n#define ff first\n#define ss second\n#define all(v) (v).begin(), (v).end()\n#define sz(v) (ll)(v).size()\n#define mask(i) (1LL << (i))\n#define bit(x, i) ((x) >> (i) & 1)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef double db;\n\nmt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count());\n\nll Rand(ll l, ll r) {\n return uniform_int_distribution<ll>(l, r) (rng);\n}\n\nll last(ll msk) {return msk & (-msk);}\nll pop_cnt(ll msk) {return __builtin_popcountll(msk);}\nll ctz(ll msk) {return __builtin_ctzll(msk);}\nll lg(ll msk) {return 63 - __builtin_clzll(msk);}\n\ntemplate<class T1, class T2> bool minimize(T1 &a, T2 b) {\n return a > b ? a = b, 1 : 0;\n}\n\ntemplate<class T1, class T2> bool maximize(T1 &a, T2 b) {\n return a < b ? a = b, 1 : 0;\n}\n\ntemplate<class T> void print(T a) {\n for (auto x : a) cout << x << \" \";\n cout << el;\n}\n\ntemplate<class T> void compress(T &a) {\n sort(all(a));\n a.resize(unique(all(a)) - a.begin());\n}\n\nconst long long N = 1e6 + 27, lim = 32, inf = 2e18, bl = 320, base = 311, mod = 1e9 + 7;\n\nstruct SegmentTree {\n ll n;\n vector<ll> t, lazy;\n\n SegmentTree(ll _n) {\n n = _n;\n t.resize(4 * n + 27);\n lazy.resize(4 * n + 27);\n }\n\n void down(ll id, ll l, ll r) {\n if (!lazy[id]) return;\n ll mid = (l + r) / 2;\n t[id * 2] += lazy[id] * (mid - l + 1);\n lazy[id * 2] += lazy[id];\n t[id * 2 + 1] += lazy[id] * (r - mid);\n lazy[id * 2 + 1] += lazy[id];\n lazy[id] = 0;\n }\n\n void update(ll id, ll l, ll r, ll u, ll v, ll c) {\n if (r < u || l > v) return;\n if (u <= l && r <= v) {\n t[id] += c * (r - l + 1);\n lazy[id] += c;\n return;\n }\n down(id, l, r);\n ll mid = (l + r) / 2;\n update(id * 2, l, mid, u, v, c);\n update(id * 2 + 1, mid + 1, r, u, v, c);\n t[id] = t[id * 2] + t[id * 2 + 1];\n }\n\n void update(ll p, ll c) {\n if (p == n + 1) return;\n ll id = 1, l = 1, r = n;\n while (l < r) {\n ll mid = (l + r) / 2;\n down(id, l, r);\n if (p <= mid) {\n id = id * 2;\n r = mid;\n }\n else {\n id = id * 2 + 1;\n l = mid + 1;\n }\n }\n t[id] = c;\n while (id) {\n id >>= 1;\n t[id] = t[id * 2] + t[id * 2 + 1];\n }\n }\n\n ll get(ll p) {\n if (!p) return p;\n ll id = 1, l = 1, r = n;\n while (l < r) {\n ll mid = (l + r) / 2;\n down(id, l, r);\n if (p <= mid) {\n r = mid;\n id = id * 2;\n }\n else {\n l = mid + 1;\n id = id * 2 + 1;\n }\n }\n return t[id];\n }\n\n ll get(ll id, ll l, ll r, ll u, ll v) {\n if (r < u || l > v) return 0;\n if (u <= l && r <= v) return t[id];\n down(id, l, r);\n ll mid = (l + r) / 2;\n ll t1 = get(id * 2, l, mid, u, v);\n ll t2 = get(id * 2 + 1, mid + 1, r, u, v);\n return t1 + t2;\n }\n\n ll get(ll u, ll v) {\n return get(1, 1, n, u, v);\n }\n\n void update(ll u, ll v, ll c) {\n update(1, 1, n, u, v, c);\n }\n};\n\nll n, q, s, t;\nll a[N];\n\nsigned main() {\n // freopen(\"CAU3.inp\", \"r\", stdin);\n // freopen(\"CAU3.out\", \"w\", stdout);\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> q >> s >> t;\n fu(i, 0, n) cin >> a[i];\n SegmentTree val(n), up(n), down(n);\n fu(i, 1, n) {\n val.update(i, a[i]);\n if (a[i] > a[i - 1]) up.update(i, a[i] - a[i - 1]);\n else down.update(i, a[i - 1] - a[i]);\n }\n // cout << down.get(1, n) << el;\n // fu(i, 0, n) cout << val.get(i, i) << el;\n while (q--) {\n ll l, r, x;\n cin >> l >> r >> x;\n val.update(l, r, x);\n ll le = val.get(l - 1);\n ll cur = val.get(l);\n if (le < cur) {\n up.update(l, cur - le);\n down.update(l, 0);\n }\n else {\n down.update(l, le - cur);\n up.update(l, 0);\n }\n ll ri = val.get(r + 1);\n cur = val.get(r);\n if (ri > cur) {\n up.update(r + 1, ri - cur);\n down.update(r + 1, 0);\n }\n else {\n down.update(r + 1, cur - ri);\n up.update(r + 1, 0);\n }\n cout << -s * up.get(1, n) + t * down.get(1, n) << el;\n // fu(i, 1, n) cout << val.get(i) << ' ';\n // cout << el;\n }\n \n\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 42412, "score_of_the_acc": -1.5745, "final_rank": 18 }, { "submission_id": "aoj_0636_9488108", "code_snippet": "#include <iostream>\nusing namespace std;\n\n// コストを計算する関数\nlong long ct(long long high);\n\n// グローバル変数の宣言\nint N, Q, S, T;\n\nint main() {\n // 入力の受け取り\n cin >> N >> Q >> S >> T;\n \n // 線の高さの変化を格納する配列\n long long *line = new long long[N + 1];\n \n // 初期の高さを読み込む変数\n int bh, nh;\n cin >> bh;\n \n line[0] = 0; // 初期の差分は0\n long long ans = 0; // 総コスト\n \n // 各点の高さを読み込み、差分を計算\n for (int i = 1; i <= N; ++i) {\n cin >> nh;\n line[i] = nh - bh;\n ans += ct(line[i]);\n bh = nh;\n }\n \n // クエリの処理\n int fr, to, ho;\n for (int i = 0; i < Q; ++i) {\n cin >> fr >> to >> ho;\n \n // コストの更新\n ans -= ct(line[fr]);\n line[fr] += ho;\n ans += ct(line[fr]);\n \n if (to != N) {\n ans -= ct(line[to + 1]);\n line[to + 1] -= ho;\n ans += ct(line[to + 1]);\n }\n \n // 結果を出力\n cout << ans << endl;\n }\n \n // メモリ解放\n delete[] line;\n \n return 0;\n}\n\n// コストを計算する関数\nlong long ct(long long high) {\n long long res;\n if (high > 0) {\n res = high * S;\n } else {\n res = high * T;\n }\n return -res;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 4696, "score_of_the_acc": -0.4903, "final_rank": 11 }, { "submission_id": "aoj_0636_9477379", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\nusing namespace std;\n\ntypedef long long int ll;\n\nconst ll BIG_NUM = 2000000000;\nconst ll MOD = 1000000007;\nconst double EPS = 0.000000001;\n\nll *uniformity, *partial;\nint N = 1;\n\nvoid init(int first_N) {\n while (N < first_N) N *= 2;\n}\n\nvoid add_and_updateNodes(int left, int right, ll value, int node_id, int node_left, int node_right) {\n if (right < node_left || left > node_right) return;\n else if (left <= node_left && right >= node_right) {\n uniformity[node_id] += value;\n } else {\n partial[node_id] += (min(right, node_right) - max(left, node_left) + 1) * value;\n add_and_updateNodes(left, right, value, 2 * node_id + 1, node_left, (node_left + node_right) / 2);\n add_and_updateNodes(left, right, value, 2 * node_id + 2, (node_left + node_right) / 2 + 1, node_right);\n }\n}\n\nll getSum(int left, int right, int node_id, int node_left, int node_right) {\n if (right < node_left || left > node_right) return 0;\n else if (left <= node_left && right >= node_right) {\n return (node_right - node_left + 1) * uniformity[node_id] + partial[node_id];\n } else {\n ll sum = (min(right, node_right) - max(left, node_left) + 1) * uniformity[node_id];\n sum += getSum(left, right, 2 * node_id + 1, node_left, (node_left + node_right) / 2);\n sum += getSum(left, right, 2 * node_id + 2, (node_left + node_right) / 2 + 1, node_right);\n return sum;\n }\n}\n\nint main() {\n int first_N, Q;\n ll S, T;\n cin >> first_N >> Q >> S >> T;\n\n init(first_N);\n\n uniformity = new ll[2 * N - 1]();\n partial = new ll[2 * N - 1]();\n\n ll tmp, up_sum = 0, down_sum = 0, pre = 0;\n\n for (int i = 0; i <= first_N; ++i) {\n cin >> tmp;\n\n if (i > 0) {\n if (tmp > pre) {\n up_sum += (tmp - pre);\n } else {\n down_sum += (pre - tmp);\n }\n add_and_updateNodes(i - 1, i - 1, tmp, 0, 0, N - 1);\n }\n\n pre = tmp;\n }\n\n int L, R;\n ll X, pre_left_diff, pre_right_diff, next_left_diff, next_right_diff;\n\n for (int i = 0; i < Q; ++i) {\n cin >> L >> R >> X;\n L--;\n R--;\n\n if (L == 0) {\n pre_left_diff = getSum(0, 0, 0, 0, N - 1);\n } else {\n pre_left_diff = getSum(L, L, 0, 0, N - 1) - getSum(L - 1, L - 1, 0, 0, N - 1);\n }\n if (R == first_N - 1) {\n pre_right_diff = 0;\n } else {\n pre_right_diff = getSum(R + 1, R + 1, 0, 0, N - 1) - getSum(R, R, 0, 0, N - 1);\n }\n\n add_and_updateNodes(L, R, X, 0, 0, N - 1);\n\n if (L == 0) {\n next_left_diff = getSum(0, 0, 0, 0, N - 1);\n } else {\n next_left_diff = getSum(L, L, 0, 0, N - 1) - getSum(L - 1, L - 1, 0, 0, N - 1);\n }\n if (R == first_N - 1) {\n next_right_diff = 0;\n } else {\n next_right_diff = getSum(R + 1, R + 1, 0, 0, N - 1) - getSum(R, R, 0, 0, N - 1);\n }\n\n if (pre_left_diff <= 0) {\n down_sum -= abs(pre_left_diff);\n } else {\n up_sum -= abs(pre_left_diff);\n }\n\n if (pre_right_diff <= 0) {\n down_sum -= abs(pre_right_diff);\n } else {\n up_sum -= abs(pre_right_diff);\n }\n\n if (next_left_diff <= 0) {\n down_sum += abs(next_left_diff);\n } else {\n up_sum += abs(next_left_diff);\n }\n\n if (next_right_diff <= 0) {\n down_sum += abs(next_right_diff);\n } else {\n up_sum += abs(next_right_diff);\n }\n\n cout << T * down_sum - S * up_sum << endl;\n }\n\n delete[] uniformity;\n delete[] partial;\n\n return 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 11396, "score_of_the_acc": -1.1784, "final_rank": 17 }, { "submission_id": "aoj_0636_9057538", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n,q; cin >> n >> q;\n ll s,t; cin >> s >> t;\n vector<ll> a(n+1);\n for (int i = 0; i <= n; ++i) {\n cin >> a[i];\n }\n ll res = 0;\n for (int i = 0; i < n; ++i) {\n if (a[i] <= a[i+1]) {\n res -= s*(a[i+1] - a[i]);\n } else {\n res += t*(a[i] - a[i+1]);\n }\n }\n vector<ll> dif(n+1);\n for (int i = 1; i <= n; ++i) {\n dif[i] = a[i] - a[i-1];\n }\n while (q--) {\n int l,r; cin >> l >> r;\n ll x; cin >> x;\n if (dif[l] >= 0) {\n res += s*dif[l];\n } else {\n res += t*dif[l];\n }\n if (r != n) {\n if (dif[r+1] >= 0) {\n res += s*dif[r+1];\n } else {\n res += t*dif[r+1];\n }\n }\n dif[l] += x;\n if (dif[l] >= 0) {\n res -= s*dif[l];\n } else {\n res -= t*dif[l];\n }\n if (r != n) {\n dif[r+1] -= x;\n if (dif[r+1] >= 0) {\n res -= s*dif[r+1];\n } else {\n res -= t*dif[r+1];\n }\n }\n cout << res << \"\\n\";\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6276, "score_of_the_acc": -0.0428, "final_rank": 6 }, { "submission_id": "aoj_0636_8994995", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, Q, S, T, L, R, X;\n cin >> N >> Q >> S >> T;\n vi A(N+1), D(N);\n rep(i, N+1) cin >> A[i];\n\n auto calc = [&](ll x) -> ll {\n return (x > 0)? (-S*x) : (-T*x);\n };\n\n ll temp = 0;\n rep(i, N) {\n D[i] = A[i+1] - A[i];\n temp += calc(D[i]);\n }\n rep(Q) {\n cin >> L >> R >> X;\n temp -= calc(D[L-1]);\n D[L-1] += X;\n temp += calc(D[L-1]);\n if (R < N) {\n temp -= calc(D[R]);\n D[R] -= X;\n temp += calc(D[R]);\n }\n print(temp);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6260, "score_of_the_acc": -0.0424, "final_rank": 5 }, { "submission_id": "aoj_0636_8141798", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nconst ll mod = 1234567;\nint main() {\n\n ll N, Q, S, T;\n cin >> N >> Q >> S >> T;\n vll A(N + 1);\n rep(i, N + 1)cin >> A[i];\n ll an = 0;\n for (ll i = N-1; i >= 0; i--) {\n A[i + 1] -= A[i];\n if (A[i + 1] > 0)an -= S * (A[i + 1]);\n else an += T * (-A[i + 1]);\n }\n //rep(i,N+1)cout<<A[i]<<\" \\n\"[i==N];\n //cout << an << endl;\n rep(q, Q) {\n ll L, R, X;\n cin >> L >> R >> X;\n if (A[L] > 0) {\n an += S * A[L];\n }\n else {\n an -= T * (-A[L]);\n }\n A[L] += X;\n if (A[L] > 0) {\n an -= S * A[L];\n }\n else {\n an += T * (-A[L]);\n }\n if (R!=N){\n R++;\n if (A[R] > 0) {\n an += S * A[R];\n }\n else {\n an -= T * (-A[R]);\n }\n A[R] -= X;\n if (A[R] > 0) {\n an -= S * A[R];\n }\n else {\n an += T * (-A[R]);\n }\n }\n //rep(i,N+1)cout<<A[i]<<\" \\n\"[i==N];\n cout << an << endl;\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 4664, "score_of_the_acc": -0.4895, "final_rank": 10 }, { "submission_id": "aoj_0636_6993209", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0636.cc: Foehn Phenomena\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 200000;\n\n/* typedef */\n\ntypedef long long ll;\n\ntemplate <typename T>\nstruct BIT {\n int n;\n vector<T> bits;\n \n BIT() {}\n BIT(int _n) { init(_n); }\n\n void init(int _n) {\n n = _n;\n bits.assign(n + 1, 0);\n }\n\n T sum(int x) {\n x = min(x, n);\n T s = 0;\n while (x > 0) {\n s += bits[x];\n x -= (x & -x);\n }\n return s;\n }\n\n void add(int x, T v) {\n if (x <= 0) return;\n while (x <= n) {\n bits[x] += v;\n x += (x & -x);\n }\n }\n\n int lower_bound(T v) {\n int\tk = 1;\n while ((k << 1) <= n) k <<=\t1;\n int\tx = 0;\n for\t(; k > 0; k >>= 1)\n if (x + k <= n && bits[x + k] < v) {\n x += k;\n v -= bits[x];\n }\n return x + 1;\n }\n};\n\n/* global variables */\n\nint as[MAX_N + 1];\nll das[MAX_N + 1];\nBIT<ll> bit;\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, qn, s, t;\n scanf(\"%d%d%d%d\", &n, &qn, &s, &t);\n for (int i = 0; i <= n; i++) scanf(\"%d\", as + i);\n\n bit.init(n);\n for (int i = 1; i <= n; i++) {\n das[i] = as[i] - as[i - 1];\n if (das[i] > 0) bit.add(i, -(ll)s * das[i]);\n else if (das[i] < 0) bit.add(i, -(ll)t * das[i]);\n }\n\n while (qn--) {\n int l, r, x;\n scanf(\"%d%d%d\", &l, &r, &x);\n r++;\n\n if (das[l] > 0) bit.add(l, (ll)s * das[l]);\n else if (das[l] < 0) bit.add(l, (ll)t * das[l]);\n das[l] += x;\n if (das[l] > 0) bit.add(l, -(ll)s * das[l]);\n else if (das[l] < 0) bit.add(l, -(ll)t * das[l]);\n\n if (r <= n) {\n if (das[r] > 0) bit.add(l, (ll)s * das[r]);\n else if (das[r] < 0) bit.add(l, (ll)t * das[r]);\n das[r] -= x;\n if (das[r] > 0) bit.add(l, -(ll)s * das[r]);\n else if (das[r] < 0) bit.add(l, -(ll)t * das[r]);\n }\n\n printf(\"%lld\\n\", bit.sum(n));\n }\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6548, "score_of_the_acc": -0.0926, "final_rank": 8 }, { "submission_id": "aoj_0636_6993204", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0636.cc: Foehn Phenomena\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 200000;\n\n/* typedef */\n\ntypedef long long ll;\n\ntemplate <typename T>\nstruct BIT {\n int n;\n vector<T> bits;\n \n BIT() {}\n BIT(int _n) { init(_n); }\n\n void init(int _n) {\n n = _n;\n bits.assign(n + 1, 0);\n }\n\n T sum(int x) {\n x = min(x, n);\n T s = 0;\n while (x > 0) {\n s += bits[x];\n x -= (x & -x);\n }\n return s;\n }\n\n void add(int x, T v) {\n if (x <= 0) return;\n while (x <= n) {\n bits[x] += v;\n x += (x & -x);\n }\n }\n\n int lower_bound(T v) {\n int\tk = 1;\n while ((k << 1) <= n) k <<=\t1;\n int\tx = 0;\n for\t(; k > 0; k >>= 1)\n if (x + k <= n && bits[x + k] < v) {\n x += k;\n v -= bits[x];\n }\n return x + 1;\n }\n};\n\n/* global variables */\n\nint as[MAX_N + 1], das[MAX_N + 1];\nBIT<ll> bit;\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, qn, s, t;\n scanf(\"%d%d%d%d\", &n, &qn, &s, &t);\n for (int i = 0; i <= n; i++) scanf(\"%d\", as + i);\n\n bit.init(n);\n for (int i = 1; i <= n; i++) {\n das[i] = as[i] - as[i - 1];\n if (das[i] > 0) bit.add(i, -(ll)s * das[i]);\n else if (das[i] < 0) bit.add(i, -(ll)t * das[i]);\n }\n\n while (qn--) {\n int l, r, x;\n scanf(\"%d%d%d\", &l, &r, &x);\n r++;\n\n if (das[l] > 0) bit.add(l, (ll)s * das[l]);\n else if (das[l] < 0) bit.add(l, (ll)t * das[l]);\n das[l] += x;\n if (das[l] > 0) bit.add(l, -(ll)s * das[l]);\n else if (das[l] < 0) bit.add(l, -(ll)t * das[l]);\n\n if (r <= n) {\n if (das[r] > 0) bit.add(l, (ll)s * das[r]);\n else if (das[r] < 0) bit.add(l, (ll)t * das[r]);\n das[r] -= x;\n if (das[r] > 0) bit.add(l, -(ll)s * das[r]);\n else if (das[r] < 0) bit.add(l, -(ll)t * das[r]);\n }\n\n printf(\"%lld\\n\", bit.sum(n));\n }\n return 0;\n}", "accuracy": 0.6363636363636364, "time_ms": 70, "memory_kb": 5700, "score_of_the_acc": -0.0488, "final_rank": 19 }, { "submission_id": "aoj_0636_6847614", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nll imos[200000];\nint main(){\n\tstatic int n,q,s,t,a[200001],l,r,x;\n\tcin>>n>>q>>s>>t;\n\tfor(int i=0;i<=n;i++)\n\t\tcin>>a[i];\n\tll ans=0;\n\tfor(int i=0;i<n;i++){\n\t\timos[i]=a[i+1]-a[i];\n\t\tif(imos[i]>0)\n\t\t\tans-=(ll)imos[i]*s;\n\t\telse\n\t\t\tans-=(ll)imos[i]*t;\n\t}\n\twhile(cin>>l>>r>>x){\n\t\tl--;\n\t\tif(imos[l]>0)\n\t\t\tans+=(ll)imos[l]*s;\n\t\telse\n\t\t\tans+=(ll)imos[l]*t;\n\t\timos[l]+=x;\n\t\tif(imos[l]>0)\n\t\t\tans-=(ll)imos[l]*s;\n\t\telse\n\t\t\tans-=(ll)imos[l]*t;\n\t\tif(r<n){\n\t\t\tif(imos[r]>0)\n\t\t\t\tans+=(ll)imos[r]*s;\n\t\t\telse\n\t\t\t\tans+=(ll)imos[r]*t;\n\t\t\timos[r]-=x;\n\t\t\tif(imos[r]>0)\n\t\t\t\tans-=(ll)imos[r]*s;\n\t\t\telse\n\t\t\t\tans-=(ll)imos[r]*t;\n\t\t}\n\t\tcout<<ans<<endl;\n\t}\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 5764, "score_of_the_acc": -0.4973, "final_rank": 12 }, { "submission_id": "aoj_0636_6741626", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\nusing namespace std;\nint const N=233333;\nint n,q,s,t,ans,a[N],d[N];\ninline int calc(int x){\n\treturn -x*(x>0?s:t);\n}\nsigned main(){\n\tios::sync_with_stdio(0);\n\tcin>>n>>q>>s>>t;\n\tfor(int i=0;i<=n;i++)\n\t\tcin>>a[i],ans+=calc(d[i]=a[i]-(i?a[i-1]:0));\n\twhile(q--){\n\t\tint l,r,x;cin>>l>>r>>x;\n\t\tcout<<(ans+=(d[l]+=x,calc(d[l])-calc(d[l]-x))+(r<n?(d[r+1]-=x,calc(d[r+1])-calc(d[r+1]+x)):0))<<\"\\n\";\n\t}\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 6572, "score_of_the_acc": -0.3272, "final_rank": 9 }, { "submission_id": "aoj_0636_6317361", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n long long N,Q,D,U;\n cin>>N>>Q>>D>>U;\n vector<long long>A(N+1);\n for(auto &i:A)cin>>i;\n for(int i=N-1;i>=0;i--){\n A[i+1]=A[i+1]-A[i];\n }\n long long ans=0;\n for(int i=1;i<=N;i++){\n if(A[i]>0)ans-=D*A[i];\n else ans-=U*A[i];\n }\n int L,R;\n long long X;\n while(Q--){\n cin>>L>>R>>X;\n if(X<0){\n if(A[L]<0){\n ans-=U*X;\n A[L]+=X;\n }else{\n long long X2=X;\n ans+=D*min(A[L],-X2);\n X2+=min(A[L],-X2);\n ans-=U*X2;\n A[L]+=X;\n }\n }else if(X>0){\n if(A[L]>0){\n ans-=D*X;\n A[L]+=X;\n }else{\n long long X2=X;\n ans+=U*max(A[L],-X2);\n X2+=max(A[L],-X2);\n ans-=D*X2;\n A[L]+=X;\n }\n }\n if(R!=N){\n R+=1;\n X*=-1;\n if(X<0){\n if(A[R]<0){\n ans-=U*X;\n A[R]+=X;\n }else{\n long long X2=X;\n ans+=D*min(A[R],-X2);\n X2+=min(A[R],-X2);\n ans-=U*X2;\n A[R]+=X;\n }\n }else if(X>0){\n if(A[R]>0){\n ans-=D*X;\n A[R]+=X;\n }else{\n long long X2=X;\n ans+=U*max(A[R],-X2);\n X2+=max(A[R],-X2);\n ans-=D*X2;\n A[R]+=X;\n }\n }\n }\n cout<<ans<<'\\n';\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4660, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0636_6291392", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<ll, ll> P;\nconst long long INF = 1e18;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nstruct BIT {\n ll N;\n vector<ll> A;\n BIT(ll M) : N(M), A(M+1, 0) {}\n\n void add(ll i, ll x) {\n for (ll k = i; k <= N; k += (k & -k)) A[k] += x;\n }\n\n ll sum(ll i) {\n ll sum = 0;\n for (ll k = i; k > 0; k -= (k & -k)) sum += A[k];\n return sum;\n }\n\n ll sum(ll i, ll j) {\n return sum(j) - sum(i - 1);\n }\n\n ll lower_bound(ll x) {\n if (x <= 0) return 0;\n ll i = 0, r = 1;\n while (r < N) r = r<<1;\n for (ll j = r; j > 0; j = j >> 1) {\n if (i + j < N && A[i + j] < x) {\n x -= A[i+j];\n i+=j;\n }\n }\n return i;\n }\n};\nvoid solve() {\n ll N, Q, S, T; cin >> N >> Q >> S >> T;\n vector<ll>A(N + 1); input_arr(A, N + 1);\n BIT bt(N);\n for (ll i = 1; i <= N; i++) {\n bt.add(i, (A[i - 1] < A[i] ? -S * (A[i] - A[i - 1]) : T * (A[i - 1] - A[i])));\n }\n BIT bt2(N + 1);\n for (ll i = 0; i < Q; i++) {\n ll l, r, x; cin >> l >> r >> x;\n bt2.add(l, x);\n bt.add(l, -bt.sum(l, l));\n ll num1 = A[l] + bt2.sum(l);\n ll num2 = A[l - 1] + bt2.sum(l - 1);\n bt.add(l, (num2 < num1 ? -S * (num1 - num2) : T * (num2 - num1)));\n r++;\n if (r <= N) {\n bt2.add(r , -x);\n bt.add(r, -bt.sum(r, r));\n ll num1 = A[r] + bt2.sum(r);\n ll num2 = A[r - 1] + bt2.sum(r - 1);\n bt.add(r, (num2 < num1 ? -S * (num1 - num2) : T * (num2 - num1)));\n }\n cout << bt.sum(N) << endl;\n }\n}\nint main() {\n solve();\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 7868, "score_of_the_acc": -0.6594, "final_rank": 15 }, { "submission_id": "aoj_0636_6058554", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n LL(n,q,s,t);\n vector<ll> a(n+1),d(n);\n in(a);\n ll ans=0;\n rep(i,n){\n d[i]=a[i+1]-a[i];\n ans+=(d[i]>0?-s:-t)*d[i];\n }\n int l,r,x;\n while(q--){\n in(l,r,x);\n l--;\n ans-=(d[l]>0?-s:-t)*d[l];\n d[l]+=x;\n ans+=(d[l]>0?-s:-t)*d[l];\n if(r<n){\n ans-=(d[r]>0?-s:-t)*d[r];\n d[r]-=x;\n ans+=(d[r]>0?-s:-t)*d[r];\n }\n out(ans);\n }\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 6308, "score_of_the_acc": -0.0437, "final_rank": 7 }, { "submission_id": "aoj_0636_5892428", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\n#define Long long long\n\nLong DeltaT(Long deltaA, Long S, Long T)\n{\n\treturn abs(deltaA) * (deltaA < 0 ? -S : T);\n}\n\nint main()\n{\n\tLong N, Q, S, T;\n\tcin >> N >> Q >> S >> T;\n\tLong* DeltaA = new Long[N];\n\tLong A;\n\tcin >> A;\n\tLong wind = 0;\n\tfor (int i = 0; i < N; i++)\n\t{\n\t\tDeltaA[i] = A;\n\t\tcin >> A;\n\t\tDeltaA[i] = DeltaA[i] - A;\n\t\twind += DeltaT(DeltaA[i],S,T);\n\t}\n\tLong L, R, X;\n\tfor (int i = 0; i < Q; i++)\n\t{\n\t\tcin >> L >> R >> X;\n\t\tDeltaA[L - 1] -= X;\n\t\twind += (DeltaT(DeltaA[L - 1], S, T) - DeltaT(DeltaA[L - 1] + X, S, T));\n\t\tif (R < N)\n\t\t{\n\t\t\tDeltaA[R] += X;\n\t\t\twind += (DeltaT(DeltaA[R], S, T) - DeltaT(DeltaA[R] - X, S, T));\n\t\t}\n\t\tcout << wind << endl;\n\t}\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 4972, "score_of_the_acc": -0.4976, "final_rank": 13 }, { "submission_id": "aoj_0636_5875313", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n\nint main(){\n int n, q;\n lint s, t;\n cin >> n >> q >> s >> t;\n vector<lint> a(n + 1);\n rep(i, n + 1) cin >> a[i];\n vector<lint> diff(n);\n rep(i, n) diff[i] = a[i + 1] - a[i];\n \n auto degree = [&](lint x){ if(x > 0) return x * -s; else return x * -t; };\n \n lint ans = 0;\n rep(i, n) ans += degree(diff[i]);\n \n rep(_, q){\n int l, r;\n lint x;\n cin >> l >> r >> x;\n l--;\n \n ans -= degree(diff[l]);\n diff[l] += x;\n ans += degree(diff[l]);\n \n if(r < n){\n ans -= degree(diff[r]);\n diff[r] -= x;\n ans += degree(diff[r]);\n }\n \n cout << ans << endl;\n }\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 6264, "score_of_the_acc": -0.5318, "final_rank": 14 }, { "submission_id": "aoj_0636_5549817", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 1000000007;\n// constexpr int MOD = 998244353;\nconstexpr int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1};\nconstexpr int dy8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dx8[] = {0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n int n, q, s, t; cin >> n >> q >> s >> t;\n vector<int> a(n + 1); REP(i, n + 1) cin >> a[i];\n vector<ll> b(n);\n REP(i, n) b[i] = a[i + 1] - a[i];\n auto foehn = [&](int i) -> ll {\n return b[i] > 0 ? -s * b[i] : t * -b[i];\n };\n ll ans = 0;\n REP(i, n) ans += foehn(i);\n while (q--) {\n int l, r, x; cin >> l >> r >> x;\n ans -= foehn(l - 1);\n b[l - 1] += x;\n ans += foehn(l - 1);\n if (r < n) {\n ans -= foehn(r);\n b[r] -= x;\n ans += foehn(r);\n }\n cout << ans << '\\n';\n }\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5460, "score_of_the_acc": -0.0212, "final_rank": 2 }, { "submission_id": "aoj_0636_5157282", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint a[200005];\nlong long sa[200005];\nint main(void)\n{\n\tint n,q,s,t,x,l,r,i,j;\n\tlong long sum,psum,msum;\n\tscanf(\"%d %d %d %d\",&n,&q,&s,&t);\n\tfor(i=0;i<=n;i++){\n\t\tscanf(\"%d\",&a[i]);\n\t}\n\tpsum=0;\n\tmsum=0;\n\tsa[0]=0;\n\tfor(i=1;i<=n;i++){\n\t\tsa[i]=a[i]-a[i-1];\n\t\tif(sa[i]<0){\n\t\t\tmsum+=sa[i];\n\t\t}\n\t\telse{\n\t\t\tpsum+=sa[i];\n\t\t}\n\t}\n\tfor(i=0;i<q;i++){\n\t\tscanf(\"%d %d %d\",&l,&r,&x);\n\t\tif(sa[l]>=0){\n\t\t\tif(x+sa[l]>=0){\n\t\t\t\tpsum+=x;\n\t\t\t\tsa[l]+=x;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tpsum-=sa[l];\n\t\t\t\tmsum+=sa[l]+x;\n\t\t\t\tsa[l]+=x;\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tif(x+sa[l]>=0){\n\t\t\t\tmsum-=sa[l];\n\t\t\t\tpsum+=sa[l]+x;\n\t\t\t\tsa[l]+=x;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tmsum+=x;\n\t\t\t\tsa[l]+=x;\n\t\t\t}\n\t\t}\n\t\tx=-x;\n\t\tif(r+1<=n){\n\t\t\tif(sa[r+1]>=0){\n\t\t\t\tif(x+sa[r+1]>=0){\n\t\t\t\t\tpsum+=x;\n\t\t\t\t\tsa[r+1]+=x;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tpsum-=sa[r+1];\n\t\t\t\t\tmsum+=sa[r+1]+x;\n\t\t\t\t\tsa[r+1]+=x;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(x+sa[r+1]>=0){\n\t\t\t\t\tmsum-=sa[r+1];\n\t\t\t\t\tpsum+=sa[r+1]+x;\n\t\t\t\t\tsa[r+1]+=x;\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tmsum+=x;\n\t\t\t\t\tsa[r+1]+=x;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tsum=-psum*s-msum*t;\n\t\tprintf(\"%lld\\n\",sum);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 5048, "score_of_the_acc": -0.0316, "final_rank": 3 } ]
aoj_0639_cpp
Soccer You are a manager of a prestigious soccer team in the JOI league. The team has $N$ players numbered from 1 to $N$. The players are practicing hard in order to win the tournament game. The field is a rectangle whose height is $H$ meters and width is $W$ meters. The vertical line of the field is in the north-south direction, and the horizontal line of the field is in the east-west direction. A point in the field is denoted by ($i, j$) if it is $i$-meters to the south and $j$ meters to the east from the northwest corner of the field. After the practice finishes, players must clear the ball. In the beginning of the clearance, the player $i$ ($1 \leq i \leq N$) stands at ($S_i, T_i$). There is only one ball in the field, and the player 1 has it. You stand at ($S_N, T_N$) with the player $N$. The clearance is finished if the ball is passed to ($S_N, T_N$), and you catch it. You cannot move during the clearance process. You can ask players to act. But, if a player acts, his fatigue degree will be increased according to the action. Here is a list of possible actions of the players. If a player has the ball, he can act (i),(ii), or (iii). Otherwise, he can act (ii) or (iv). (i) Choose one of the 4 directions (east/west/south/north), and choose a positive integer $p$. Kick the ball to that direction. Then, the ball moves exactly p meters. The kicker does not move by this action, and he loses the ball. His fatigue degree is increased by $A \times p + B$. (ii) Choose one of the 4 directions (east/west/south/north), and move 1 meter to that direction. If he has the ball, he moves with it. His fatigue degree is increased by $C$ regardless of whether he has the ball or not. (iii) Place the ball where he stands. He loses the ball. His fatigue degree does not change. (iv) Take the ball. His fatigue degree does not change. A player can take this action only if he stands at the same place as the ball, and nobody has the ball. Note that it is possible for a player or a ball to leave the field. More than one players can stand at the same place. Since the players just finished the practice, their fatigue degrees must not be increased too much. You want to calculate the minimum possible value of the sum of fatigue degrees of the players for the clearance process. Task Given the size of the field and the positions of the players, write a program which calculates the minimum possible value of the sum of fatigue degrees of the players for the clearance process. Input Read the following data from the standard input. The first line of input contains two space separated integers $H$, $W$. This means the field is a rectangle whose height is $H$ meters and width is $W$ meters. The second line contains three space separated integers $A$, $B$, $C$ describing the increment of the fatigue degree by actions. The third line contains an integer N, the number of players. The $i$-th line ($1 \leq i \leq N$) of the following $N$ lines contains two space separated integers $S_i$, ...(truncated)
[ { "submission_id": "aoj_0639_9477404", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <algorithm>\nusing namespace std;\n\n#define X_MAX 500\n#define Y_MAX 500\n#define N_MAX 100000\n#define V_MAX ((X_MAX + 1) * (Y_MAX + 1))\n#define LLD \"%lld\"\n\ntypedef long long lnt;\ntypedef bool bnt;\ntypedef void vnt;\n\nconst lnt LNF = 0x3F3F3F3F3F3F3FLL;\nconst int dx[] = {-1, 0, +1, 0}, dy[] = {0, -1, 0, +1};\n\nint X, Y, N, i, k, x, y, u, v, sx, sy, tx, ty, Ql = -1, Qr = -1, Q[V_MAX * 2];\nlnt A, B, C, dir[X_MAX + 1][Y_MAX + 1], dis[X_MAX + 1][Y_MAX + 1][3];\n\ninline bnt chk(int x, int y) { \n return x >= 0 && x <= X && y >= 0 && y <= Y; \n}\n\nstruct dat {\n int k, x, y;\n lnt d;\n bool operator<(const dat &p) const { \n return d > p.d; \n }\n};\n\npriority_queue<dat> P;\n\nint main() {\n scanf(\"%d %d\" LLD LLD LLD \"%d\", &X, &Y, &A, &B, &C, &N);\n\n for (x = 0; x <= X; ++x)\n for (y = 0; y <= Y; ++y)\n dir[x][y] = -1;\n\n scanf(\"%d %d\", &sx, &sy);\n dir[sx][sy] = 0;\n\n for (i = 2; i < N; ++i) {\n scanf(\"%d %d\", &x, &y);\n dir[x][y] = 0;\n }\n\n scanf(\"%d %d\", &tx, &ty);\n dir[tx][ty] = 0;\n\n for (x = 0; x <= X; ++x)\n for (y = 0; y <= Y; ++y)\n if (!dir[x][y])\n Q[++Qr] = x, Q[++Qr] = y;\n\n while (Ql < Qr) {\n x = Q[++Ql], y = Q[++Ql];\n for (k = 0; k < 4; ++k) {\n if (chk(u = x + dx[k], v = y + dy[k]) && dir[u][v] == -1) {\n dir[u][v] = dir[x][y] + C;\n Q[++Qr] = u, Q[++Qr] = v;\n }\n }\n }\n\n for (k = 0; k < 3; ++k)\n for (x = 0; x <= X; ++x)\n for (y = 0; y <= Y; ++y)\n dis[x][y][k] = LNF;\n\n P.push({2, sx, sy, 0});\n\n dat p;\n while (true) {\n p = P.top();\n P.pop();\n\n if (dis[p.x][p.y][p.k] < LNF)\n continue;\n\n if (p.x == tx && p.y == ty)\n break;\n\n dis[p.x][p.y][p.k] = p.d;\n\n switch (p.k) {\n case 2:\n for (k = 0; k < 2; ++k)\n if (dis[p.x][p.y][k] == LNF)\n P.push({k, p.x, p.y, p.d + B});\n for (k = 0; k < 4; ++k)\n if (chk(u = p.x + dx[k], v = p.y + dy[k]) && dis[u][v][2] == LNF)\n P.push({p.k, u, v, p.d + C});\n break;\n default:\n if (dis[p.x][p.y][2] == LNF)\n P.push({2, p.x, p.y, p.d + dir[p.x][p.y]});\n for (k = p.k; k < 4; k += 2)\n if (chk(u = p.x + dx[k], v = p.y + dy[k]) && dis[u][v][p.k] == LNF)\n P.push({p.k, u, v, p.d + A});\n }\n }\n\n printf(LLD \"\\n\", p.d);\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 26580, "score_of_the_acc": -0.127, "final_rank": 2 }, { "submission_id": "aoj_0639_7021095", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/modint>\n\n#define rep(i, x) for (ll i = 0; i < x; i++)\n#define rep2(i, x) for (ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for (ll i = x; i < y; i++)\n#define REP(i, x) for (ll i = x - 1; i >= 0; i--)\n#define REP2(i, x) for (ll i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define pb push_back\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\n// using namespace atcoder;\n\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n// const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError\n{\n};\n\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n if (a > b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nbool isprime(ll p)\n{\n if (p == 1)\n return false;\n for (ll i = 2; i * i <= p; i++)\n {\n if (p % i == 0)\n return false;\n }\n return true;\n}\n//エラトステネスの篩\nvector<bool> isprime_format(ll n)\n{\n vector<bool> P(n + 1, 1);\n P[0] = P[1] = 1;\n for (ll i = 2; i * i <= n; i++)\n {\n if (!P[i])\n continue;\n for (int j = i + i; j <= n; j += i)\n P[j] = false;\n }\n return P;\n}\nvector<ll> prime_format(ll n)\n{\n vector<bool> P = isprime_format(n);\n vector<ll> ans;\n for (int i = 2; i <= n; i++)\n {\n if (P[i])\n ans.push_back(i);\n }\n return ans;\n}\nll extGCD(ll a, ll b, ll &x, ll &y)\n{\n // ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n // 返り値: a と b の最大公約数\n // ax + by = gcd(a, b) を満たす (x, y) が格納される\n // main関数内に extGCD(a, b, x, y); でx, yに解が格納\n if (b == 0)\n {\n x = 1;\n y = 0;\n return a;\n }\n ll d = extGCD(b, a % b, y, x);\n y -= a / b * x;\n return d;\n}\nll keta(ll n)\n{\n ll res = 0;\n while (n >= 1)\n {\n // res++;\n res += n % 10;\n\n n /= 10;\n }\n return res;\n}\nll modpow(ll x, ll y, ll m)\n{\n ll res = 1;\n while (y)\n {\n if (y % 2)\n {\n res *= x;\n res %= m;\n }\n x = x * x % m;\n y /= 2;\n }\n return res;\n}\n\nunsigned int xorshift()\n{\n // xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n // 1~6まで出したいときは\n // xorshift() % 6 + 1\n static unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n unsigned int tt = (tx ^ (tx << 11));\n tx = ty;\n ty = tz;\n tz = tw;\n return (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\nuint64_t seed = 123456789;\nuint64_t xorshift64()\n{\n seed ^= seed << 13;\n seed ^= seed >> 17;\n seed ^= seed << 7;\n return seed;\n}\nint rand_int(int l, int r)\n{\n return l + int(xorshift64() % (r - l));\n}\ndouble randouble()\n{\n return double(xorshift64()) / double(uint64_t(-1));\n}\n\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> pp;\n//左上右下\nll dx[4] = {0, -1, 0, 1}, dy[4] = {-1, 0, 1, 0};\nll ndx[4] = {1, -1, -1, 1}, ndy[4] = {1, 1, -1, -1};\nchar ds[4] = {'l', 'u', 'r', 'd'};\nchar dl[4] = {'L', 'U', 'R', 'D'};\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n)\n{\n spf.resize(n + 1);\n spf[1] = 1;\n for (int i = 2; i <= n; i++)\n {\n if (!spf[i])\n {\n for (int j = i; j < n; j += i)\n {\n spf[j] = i;\n }\n }\n }\n}\nstd::map<int, int> high_speed_prime_factor(int n)\n{\n std::map<int, int> res;\n while (n != 1)\n {\n res[spf[n]]++;\n n /= spf[n];\n }\n return res;\n}\n\n////////////////////////////////struct\n\nstruct Comb\n{\n // https://atcoder.jp/contests/abc156/submissions/33741990\n\n ll nCrMAX;\n ll m;\n vector<ll> fac, finv, inv; // n!、1/n!、1/n\n\n Comb(ll kMOD, ll kMAX = 612345)\n {\n nCrMAX = kMAX;\n m = kMOD;\n fac.resize(nCrMAX);\n finv.resize(nCrMAX);\n inv.resize(nCrMAX);\n\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < nCrMAX; i++)\n {\n fac[i] = fac[i - 1] * i % m;\n inv[i] = m - inv[m % i] * (m / i) % m;\n finv[i] = finv[i - 1] * inv[i] % m;\n }\n }\n\n ll nCr(ll n, ll k)\n {\n if (k < nCrMAX)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n else\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n }\n\n ll nCr1(ll n, ll k)\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n\n //(nが大きくて)kが小さい時\n // nCrMAXはk+2まででOK\n ll nCr2(ll n, ll k)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n};\n\nstruct status\n{\n ll v;\n ll p;\n\n // bool operator<(const status& rhs) const { return c < rhs.c; };\n // bool operator>(const status& rhs) const { return c > rhs.c; };\n bool operator<(const status &rhs) const { return v < rhs.v; };\n bool operator>(const status &rhs) const { return v > rhs.v; };\n};\nvoid yes(bool a) { cout << (a ? \"yes\" : \"no\") << endl; }\nvoid YES(bool a) { cout << (a ? \"YES\" : \"NO\") << endl; }\nvoid Yes(bool a) { cout << (a ? \"Yes\" : \"No\") << endl; }\nvoid Possible(bool a) { cout << (a ? \"Possible\" : \"Impossible\") << endl; }\n// struct edge {\n//\tll to; ll cost;\n// };\n\nstruct Point\n{\n ll x, y;\n Point operator+(const Point &p) const noexcept { return {x + p.x, y + p.y}; }\n Point operator-(const Point &p) const noexcept { return {x - p.x, y - p.y}; }\n Point operator*(const ll k) const noexcept { return {x * k, y * k}; }\n Point operator/(const ll k) const noexcept { return {x / k, y / k}; }\n Point &operator+=(const Point &p) noexcept\n {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) noexcept\n {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n bool operator<(const Point &p) const noexcept { return (x != p.x ? x < p.x : y < p.y); }\n};\n\n// using mint = modint998244353;\n\nstruct edge\n{\n ll to, cost;\n};\n\n// O(ElogV)\nll H, W;\nll d[753456]; //始点sから終点tまでのコストd[t]\nvector<edge> G[753456]; //コスト\nvoid dijkstra(ll s)\n{\n // greater<P>を指定→firstが小さい順\n priority_queue<P, vector<P>, greater<P>> que;\n fill(d, d + 753456, INF); //←TLE気を付ける\n d[s] = 0;\n que.push(P(0, s));\n while (!que.empty())\n {\n P p = que.top();\n que.pop();\n int v = p.second;\n // cout << p.first << ' ' << v / (H * W) << ' ' << (v % (H * W)) / H << ' ' << (v % (H * W)) % H << endl;\n if (d[v] < p.first)\n {\n continue;\n }\n for (int i = 0; i < G[v].size(); i++)\n {\n edge e = G[v][i];\n if (d[e.to] > d[v] + e.cost)\n {\n d[e.to] = d[v] + e.cost;\n que.push(P(d[e.to], e.to));\n }\n }\n }\n}\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n // cout << fixed << setprecision(15);\n // priority_queue<ll, vector<ll>, greater<ll>> que;\n // priority_queue<P, vector<P>, greater<P>> que;\n // priority_queue<status, vector<status>, greater<status>> que;\n\n cin >> H >> W;\n H++;\n W++;\n ll A, B, C;\n cin >> A >> B >> C;\n ll N;\n cin >> N;\n vector<Point> people(N);\n rep(i, N)\n {\n cin >> people[i].x >> people[i].y;\n }\n\n ////////////////////////////\n // costを作る\n //\n vector<vector<ll>> cost(H, vector<ll>(W, -1));\n queue<Point> que;\n rep(i, N)\n {\n que.push(people[i]);\n cost[people[i].x][people[i].y] = 0;\n }\n while (!que.empty())\n {\n Point p = que.front();\n que.pop();\n rep(l, 4)\n {\n ll nx = p.x + dx[l], ny = p.y + dy[l];\n if (0 <= nx && nx < H && 0 <= ny && ny < W && cost[nx][ny] == -1)\n {\n cost[nx][ny] = cost[p.x][p.y] + C;\n que.push({nx, ny});\n }\n }\n }\n\n ////////////////////////////\n // グラフの構築\n //\n // 1層目\n rep(i, H)\n {\n rep(j, W)\n {\n rep(l, 4)\n {\n ll nx = i + dx[l], ny = j + dy[l];\n if (0 <= nx && nx < H && 0 <= ny && ny < W)\n {\n G[i * W + j].push_back({nx * W + ny, C});\n }\n }\n }\n }\n // 2層目(横)\n rep(i, H)\n {\n rep(j, W)\n {\n // 1層目と2層目の間\n G[i * W + j].push_back({H * W + i * W + j, B});\n G[H * W + i * W + j].push_back({i * W + j, cost[i][j]});\n // 2層目\n rep(l, 4)\n {\n ll nx = i + dx[l], ny = j + dy[l];\n if (0 <= nx && nx < H && 0 <= ny && ny < W)\n {\n G[H * W + i * W + j].push_back({H * W + nx * W + ny, A});\n }\n l++; //横なので\n }\n }\n }\n // 3層目(縦)\n rep(i, H)\n {\n rep(j, W)\n {\n // 1層目と3層目の間\n G[i * W + j].push_back({2 * H * W + i * W + j, B});\n G[2 * H * W + i * W + j].push_back({i * W + j, cost[i][j]});\n // 3層目\n rep(l, 4)\n {\n l++; //縦なので\n ll nx = i + dx[l], ny = j + dy[l];\n if (0 <= nx && nx < H && 0 <= ny && ny < W)\n {\n G[2 * H * W + i * W + j].push_back({2 * H * W + nx * W + ny, A});\n // cout << i << ' ' << j << ' ' << nx << ' ' << ny << endl;\n }\n }\n }\n }\n\n dijkstra(people[0].x * W + people[0].y);\n\n /*rep(i, H)\n {\n rep(j, W)\n {\n cout << cost[i][j] << ' ';\n }\n cout << endl;\n }\n cout << endl;\n rep(i, H)\n {\n rep(j, W)\n {\n cout << d[i * W + j] << ' ';\n }\n cout << endl;\n }\n cout << endl;\n rep(i, H)\n {\n rep(j, W)\n {\n cout << d[H * W + i * W + j] << ' ';\n }\n cout << endl;\n }\n cout << endl;\n rep(i, H)\n {\n rep(j, W)\n {\n cout << d[2 * H * W + i * W + j] << ' ';\n }\n cout << endl;\n }*/\n\n cout << d[people[N - 1].x * W + people[N - 1].y] << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 110044, "score_of_the_acc": -0.7668, "final_rank": 12 }, { "submission_id": "aoj_0639_6800378", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\ntemplate <typename T, typename Can> T bsearch(T L, T R, const Can& can, bool left_feasible = true) {\n static_assert(is_convertible<decltype(can), function<bool(T)>>::value);\n T& feasible = left_feasible ? L : R;\n T& infeasible = left_feasible ? R : L;\n while(R - L > 1) {\n T M = L + (R - L) / 2;\n (can(M) ? feasible : infeasible) = M;\n }\n return feasible;\n}\nint rot_x(int x, int y) {\n return x + y;\n}\nint rot_y(int x, int y, int max_y) {\n return x - y + max_y;\n}\nint max_rot(int max_x, int max_y) {\n return max_x + max_y;\n}\nint h, w;\nll a, b, c;\nint n;\nstruct node {\n int x, y, kick_dir;\n bool operator<(const node& other) const {\n return id() < other.id();\n }\n int id() const {\n return (x * (w + 1) + y) * 8 + kick_dir;;\n }\n};\nint dx[] = {0, -1, 1, 0, 0};\nint dy[] = {0, 0, 0, -1, 1};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cin >> h >> w;\n cin >> a >> b >> c;\n cin >> n;\n vector<int> s(n), t(n);\n vector<vector<int>> psum(max_rot(h, w) + 1, vector<int>(max_rot(h, w) + 1));\n for(int i = 0; i < n; i++) {\n cin >> s[i] >> t[i];\n psum[rot_x(s[i], t[i])][rot_y(s[i], t[i], w)]++;\n }\n for(int i = 0; i <= max_rot(h, w); i++) {\n for(int j = 0; j <= max_rot(h, w); j++) {\n psum[i][j] += i > 0 ? psum[i - 1][j] : 0;\n psum[i][j] += j > 0 ? psum[i][j - 1] : 0;\n psum[i][j] -= i > 0 and j > 0 ? psum[i - 1][j - 1] : 0;\n }\n }\n auto rsq = [&](int rx1, int ry1, int rx2, int ry2) {\n return psum[rx2][ry2]\n - (rx1 > 0 ? psum[rx1 - 1][ry2] : 0)\n - (ry1 > 0 ? psum[rx2][ry1 - 1] : 0)\n + (rx1 > 0 and ry1 > 0 ? psum[rx1 - 1][ry1 - 1] : 0);\n };\n auto query = [&](int x, int y, int k) {\n int rx = rot_x(x, y), ry = rot_y(x, y, w);\n return rsq(max(0, rx - k), max(0, ry - k), min(rx + k, max_rot(h, w)), min(ry + k, max_rot(h, w)));\n };\n int max_node_id = node{h, w, 4}.id();\n vector<ll> d(max_node_id + 1, lim<ll>::max()), done(max_node_id + 1);\n priority_queue<pair<ll, node>, vector<pair<ll, node>>, greater<pair<ll, node>>> pq;\n auto expand = [&](const node& u, const node& v, ll weight) {\n if(0 <= v.x and v.x <= h and 0 <= v.y and v.y <= w and d[v.id()] > d[u.id()] + weight) {\n pq.push({d[v.id()] = d[u.id()] + weight, v});\n }\n };\n node start = {s[0], t[0], 0};\n pq.push({d[start.id()] = 0, start});\n while(not pq.empty()) {\n auto [_, u] = pq.top();\n pq.pop();\n if(not done[u.id()]) {\n if(u.kick_dir == 0) {\n int nearest = bsearch(-1, h + w, [&](int k) { return query(u.x, u.y, k) > 0; }, false);\n for(int dir = 1; dir <= 4; dir++) {\n expand(u, {u.x, u.y, dir}, b + c * nearest);\n expand(u, {u.x + dx[dir], u.y + dy[dir], 0}, c);\n }\n } else {\n expand(u, {u.x, u.y, 0}, 0);\n expand(u, {u.x + dx[u.kick_dir], u.y + dy[u.kick_dir], u.kick_dir}, a);\n }\n done[u.id()] = true;\n }\n }\n ll ans = lim<ll>::max();\n for(int dir = 0; dir <= 4; dir++) {\n ans = min(ans, d[node{s.back(), t.back(), dir}.id()]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 64944, "score_of_the_acc": -0.5988, "final_rank": 11 }, { "submission_id": "aoj_0639_6799723", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nint h, w;\nll a, b, c;\nint n;\nstruct node {\n int x, y, kick_dir;\n bool operator<(const node& n) const {\n return id() < n.id();\n }\n int id() const {\n return (x * (w + 1) + y) * 8 + kick_dir;;\n }\n};\nint dx[] = {0, -1, 1, 0, 0};\nint dy[] = {0, 0, 0, -1, 1};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cin >> h >> w;\n cin >> a >> b >> c;\n cin >> n;\n vector<int> s(n), t(n);\n for(int i = 0; i < n; i++) {\n cin >> s[i] >> t[i];\n }\n int max_node_id = node{h, w, 4}.id();\n vector<ll> d(max_node_id + 1, lim<ll>::max()), done(max_node_id + 1);\n priority_queue<pair<ll, node>, vector<pair<ll, node>>, greater<pair<ll, node>>> pq;\n auto expand = [&](const node& u, const node& v, int w) {\n if(d[v.id()] > d[u.id()] + w) {\n pq.push({d[v.id()] = d[u.id()] + w, v});\n }\n };\n node start = {s[0], t[0], 0};\n pq.push({d[start.id()] = 0, start});\n while(not pq.empty()) {\n auto [_, u] = pq.top();\n pq.pop();\n if(not done[u.id()]) {\n if(u.kick_dir == 0) {\n for(int dir = 1; dir <= 4; dir++) {\n int nearest = lim<int>::max();\n for(int i = 0; i < n; i++) {\n nearest = min(nearest, abs(s[i] - u.x) + abs(t[i] - u.y));\n }\n expand(u, {u.x, u.y, dir}, b + c * nearest);\n int nx = u.x + dx[dir], ny = u.y + dy[dir];\n if(0 <= nx and nx <= h and 0 <= ny and ny <= w) {\n expand(u, {nx, ny, u.kick_dir}, c);\n }\n }\n } else {\n expand(u, {u.x, u.y, 0}, 0);\n int nx = u.x + dx[u.kick_dir], ny = u.y + dy[u.kick_dir];\n if(0 <= nx and nx <= h and 0 <= ny and ny <= w) {\n expand(u, {nx, ny, u.kick_dir}, a);\n }\n }\n done[u.id()] = true;\n }\n }\n ll ans = lim<ll>::max();\n for(int dir = 0; dir <= 4; dir++) {\n ans = min(ans, d[node{s.back(), t.back(), dir}.id()]);\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 0.15384615384615385, "time_ms": 250, "memory_kb": 48404, "score_of_the_acc": -0.3427, "final_rank": 20 }, { "submission_id": "aoj_0639_4172288", "code_snippet": "// #pragma GCC target(\"avx\") // CPU 処理並列化\n// #pragma GCC optimize(\"O3\") // CPU 処理並列化\n// #pragma GCC optimize(\"unroll-loops\") // 条件処理の呼び出しを減らす\n// #define BEGIN_STACK_EXTEND(size) void * stack_extend_memory_ = malloc(size);void * stack_extend_origin_memory_;char * stack_extend_dummy_memory_ = (char*)alloca((1+(int)(((long long)stack_extend_memory_)&127))*16);*stack_extend_dummy_memory_ = 0;asm volatile(\"mov %%rsp, %%rbx\\nmov %%rax, %%rsp\":\"=b\"(stack_extend_origin_memory_):\"a\"((char*)stack_extend_memory_+(size)-1024));\n// #define END_STACK_EXTEND asm volatile(\"mov %%rax, %%rsp\"::\"a\"(stack_extend_origin_memory_));free(stack_extend_memory_);\n\n#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<string>\n#include<string.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stdlib.h>\n#include<cassert>\n#include<time.h>\n#include<bitset>\n#include<numeric>\n#include<unordered_set>\n#include<unordered_map>\n#include<complex>\nusing namespace std;\nconst long long mod=1000000007;\nconst long long inf=mod*mod;\nconst long long d2=(mod+1)/2;\nconst long double EPS=1e-20;\nconst double INF=1e+10;\nconst double PI=acos(-1.0);\nconst int C_SIZE = 3100000;\nconst int UF_SIZE = 4100000;\nnamespace{\n\tlong long fact[C_SIZE];\n\tlong long finv[C_SIZE];\n\tlong long inv[C_SIZE];\n\tlong long Comb(int a,int b){\n\t \tif(a<b||b<0)return 0;\n\t \treturn fact[a]*finv[b]%mod*finv[a-b]%mod;\n\t}\n\tvoid init_C(int n){\n\t\tfact[0]=finv[0]=inv[1]=1;\n\t\tfor(int i=2;i<n;i++){\n\t\t\tinv[i]=(mod-(mod/i)*inv[mod%i]%mod)%mod;\n\t\t}\n\t\tfor(int i=1;i<n;i++){\n\t\t\tfact[i]=fact[i-1]*i%mod;\n\t\t\tfinv[i]=finv[i-1]*inv[i]%mod;\n\t\t}\n\t}\n\tlong long pw(long long a,long long b){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%mod;\n\t\t\ta=a*a%mod;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tlong long pw_mod(long long a,long long b,long long M){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%M;\n\t\t\ta=a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint pw_mod_int(int a,int b,int M){\n\t\tif(a<0)return 0;\n\t\tif(b<0)return 0;\n\t\tint ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=(long long)ret*a%M;\n\t\t\ta=(long long)a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint ABS(int a){return max(a,-a);}\n\tlong long ABS(long long a){return max(a,-a);}\n\tdouble ABS(double a){return max(a,-a);}\n\tint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\n\tint UF[UF_SIZE];\n\tvoid init_UF(int n){\n\t\tfor(int i=0;i<n;i++)UF[i]=-1;\n\t}\n\tint FIND(int a){\n\t\tif(UF[a]<0)return a;\n\t\treturn UF[a]=FIND(UF[a]);\n\t}\n\tvoid UNION(int a,int b){\n\t\ta=FIND(a);b=FIND(b);if(a==b)return;\n\t\tif(UF[a]>UF[b])swap(a,b);\n\t\tUF[a]+=UF[b];UF[b]=a;\n\t}\n}\n// ここから編集しろ\nint dx[]={1,0,-1,0};\nint dy[]={0,1,0,-1};\nint v[510][510][6];\nlong long ijk[510][510][6];\nint x[110000];\nint y[110000];\nint bfs[510][510];\nint main(){\n\tint h,w,a,b,c,n;\n\tscanf(\"%d%d%d%d%d%d\",&h,&w,&a,&b,&c,&n);\n\tfor(int i=0;i<=h;i++)for(int j=0;j<=w;j++){\n\t\tbfs[i][j]=-1;\n\t}\n\tqueue<pair<int,int> > q;\n\tfor(int i=0;i<n;i++){\n\t\tscanf(\"%d%d\",x+i,y+i);\n\t\tbfs[x[i]][y[i]]=0;\n\t\tq.push(make_pair(x[i],y[i]));\n\t}\n\twhile(q.size()){\n\t\tint row=q.front().first;\n\t\tint col=q.front().second;\n\t\tq.pop();\n\t\tfor(int i=0;i<4;i++){\n\t\t\tint tr=row+dx[i];\n\t\t\tint tc=col+dy[i];\n\t\t\tif(tr<0||tc<0||tr>h||tc>w)continue;\n\t\t\tif(bfs[tr][tc]!=-1)continue;\n\t\t\tbfs[tr][tc]=bfs[row][col]+1;\n\t\t\tq.push(make_pair(tr,tc));\n\t\t}\n\t}\n\tfor(int i=0;i<=h;i++)for(int j=0;j<=w;j++)for(int k=0;k<6;k++)ijk[i][j][k]=inf;\n\tijk[x[0]][y[0]][0]=0;\n\tpriority_queue<pair<long long,pair<pair<int,int>,int> > > Q;\n\tQ.push(make_pair(0LL,make_pair(make_pair(x[0],y[0]),0)));\n\twhile(Q.size()){\n\t\tlong long cost=-Q.top().first;\n\t\tint row=Q.top().second.first.first;\n\t\tint col=Q.top().second.first.second;\n\t\tint ty=Q.top().second.second;\n\t\tQ.pop();\n\t\tif(v[row][col][ty])continue;\n\t\tv[row][col][ty]=1;\n\t\tif(ty==0){\n\t\t\tif(!v[row][col][1]&&ijk[row][col][1]>cost+(long long)bfs[row][col]*c){\n\t\t\t\tijk[row][col][1]=cost+(long long)bfs[row][col]*c;\n\t\t\t\tQ.push(make_pair(-ijk[row][col][1],make_pair(make_pair(row,col),1)));\n\t\t\t}\n\t\t}else if(ty==1){\n\t\t\tfor(int i=0;i<4;i++){\n\t\t\t\tint tr=row+dx[i];\n\t\t\t\tint tc=col+dy[i];\n\t\t\t\tif(tr<0||tc<0||tr>h||tc>w)continue;\n\t\t\t\tif(v[tr][tc][ty])continue;\n\t\t\t\tif(ijk[tr][tc][ty]>cost+c){\n\t\t\t\t\tijk[tr][tc][ty]=cost+c;\n\t\t\t\t\tQ.push(make_pair(-cost-c,make_pair(make_pair(tr,tc),ty)));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!v[row][col][0]&&ijk[row][col][0]>cost){\n\t\t\t\tijk[row][col][0]=cost;\n\t\t\t\tQ.push(make_pair(-ijk[row][col][0],make_pair(make_pair(row,col),0)));\n\t\t\t}\n\t\t\tfor(int i=0;i<4;i++){\n\t\t\t\tint tt=2+i;\n\t\t\t\tlong long toc=cost+b;\n\t\t\t\tif(v[row][col][tt])continue;\n\t\t\t\tif(ijk[row][col][tt]>toc){\n\t\t\t\t\tijk[row][col][tt]=toc;\n\t\t\t\t\tQ.push(make_pair(-toc,make_pair(make_pair(row,col),tt)));\n\t\t\t\t}\n\t\t\t}\n\t\t}else{\n\t\t\tif(!v[row][col][0]&&ijk[row][col][0]>cost){\n\t\t\t\tijk[row][col][0]=cost;\n\t\t\t\tQ.push(make_pair(-ijk[row][col][0],make_pair(make_pair(row,col),0)));\n\t\t\t}\n\t\t\tint tr=row+dx[ty-2];\n\t\t\tint tc=col+dy[ty-2];\n\t\t\tlong long toc=cost+a;\n\t\t\tif(0<=tr&&tr<=h&&0<=tc&&tc<=w&&!v[tr][tc][ty]&&ijk[tr][tc][ty]>toc){\n\t\t\t\tijk[tr][tc][ty]=toc;\n\t\t\t\tQ.push(make_pair(-toc,make_pair(make_pair(tr,tc),ty)));\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",ijk[x[n-1]][y[n-1]][0]);\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 28956, "score_of_the_acc": -0.2766, "final_rank": 8 }, { "submission_id": "aoj_0639_4083216", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n\n\nint dis[510][510]={};\nint memo[510][510][3]={};\n//bool vis[510][510][2]={};\n\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\nint h,w;\n\tcin>>h>>w;\n\tconst int inff=inf*100000000ll;\n\tfor(int i=0;i<=500;i++)for(int j=0;j<=500;j++)dis[i][j]=inf,memo[i][j][0]=inff,memo[i][j][1]=inff,memo[i][j][2]=inff;\n\tint a,b,c;\n\tcin>>a>>b>>c;\n\tqueue<pa3> qu;\n\tint n;\n\tcin>>n;\n\tint gx,gy;\n\tpriority_queue<pa4,vector<pa4>,greater<pa4>> pq; \n\tfor(int i=0;i<n;i++){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\t\tqu.push((pa3){x,y,b});\n\t\tif(i==0){\n\t\t\t\tpq.push((pa4){0,x,y,0});\n\t\t\tmemo[x][y][0]=0;\n\t\t\n\t\t}\n\t\tif(i==n-1){\n\t\t\tgx=x,gy=y;\n\t\t}\n\t}\n\twhile(qu.size()){\n\t\tpa3 z=qu.front();\n\t\tqu.pop();\n\t\tif(dis[z.x][z.y]!=inf) continue;\n\t\tdis[z.x][z.y]=z.z;\n\t//\tcout<<z.x<<\" \"<<z.y<<\" \"<<z.z<<endl;\n\t\tfor(int r=0;r<4;r++){\n\t\t\tint X=z.x+dx[r];\n\t\t\tint Y=z.y+dy[r];\n\t\t\t\n\t\t\t\tif(X>=0 && Y>=0 && X<=h && Y<=w)qu.push((pa3){X,Y,z.z+c});\n\t\t}\n\t}\n\t\n\tint cnt=0;\n\t//for(int i=0;i<10;i++)for(int j=0;j<10;j++)cout<<dis[i][j]<<endl;\n\twhile(pq.size()){\n\t\tpa4 z=pq.top();\n\t\tpq.pop();\n\t\t\n\t\tif(memo[z.y][z.z][z.w]<z.x)continue;\n\t//\tcout<<z.y<<\" \"<<z.z<<\" \"<<z.w<<\" \"<<z.x<<endl;\n\t\t//cnt++;\n\t\tif(z.y==gx&& z.z==gy && z.w==0){\n\t\t\tcout<<z.x<<endl;\n\t\t\treturn 0;\n\t\t}\n\t\tif(z.w==0){\n\t\t\tfor(int r=0;r<4;r++){\n\t\t\t\tint X=z.y+dx[r],Y=z.z+dy[r];\n\t\t\t\tif(X>=0 && X<=h && Y>=0 && Y<=w){\n\t\t\t\t\tif(memo[X][Y][0]>z.x+c){\n\t\t\t\t\t\t\tpq.push(pa4({z.x+c,X,Y,0}));\n\t\t\t\t\t\tmemo[X][Y][0]=z.x+c;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor(int r=1;r<3;r++)if(memo[z.y][z.z][r]>z.x){\n\t\t\t\t\tpq.push((pa4){z.x,z.y,z.z,r});\n\t\t\t\tmemo[z.y][z.z][r]=z.x;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif(z.w==1){\n\t\t\tfor(int r=0;r<4;r++)if(dy[r]==0){\n\t\t\t\tint X=z.y+dx[r],Y=z.z+dy[r];\n\t\t\t\tif(X>=0 && X<=h && Y>=0 && Y<=w){\n\t\t\t\t\tif(memo[X][Y][1]>z.x+a){\n\t\t\t\t\t\t\tpq.push(pa4({z.x+a,X,Y,1}));\n\t\t\t\t\t\tmemo[X][Y][1]=z.x+a;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t\n\t\t\tfor(int r=0;r<1;r++)if(memo[z.y][z.z][r]>z.x+dis[z.y][z.z]){\n\t\t\t\t\tpq.push((pa4){z.x+dis[z.y][z.z],z.y,z.z,r});\n\t\t\t\tmemo[z.y][z.z][r]=z.x+dis[z.y][z.z];\n\t\t\t}\n\t\t}\n\t\t\n\t\t\n\t\tif(z.w==2){\n\t\t\tfor(int r=0;r<4;r++)if(dx[r]==0){\n\t\t\t\tint X=z.y+dx[r],Y=z.z+dy[r];\n\t\t\t\tif(X>=0 && X<=h && Y>=0 && Y<=w){\n\t\t\t\t\tif(memo[X][Y][2]>z.x+a){\n\t\t\t\t\t\t\tpq.push(pa4({z.x+a,X,Y,2}));\n\t\t\t\t\t\tmemo[X][Y][2]=z.x+a;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\t//int r=0;\n\t\t\tfor(int r=0;r<1;r++)if(memo[z.y][z.z][r]>z.x+dis[z.y][z.z]){\n\t\t\t\t\tpq.push((pa4){z.x+dis[z.y][z.z],z.y,z.z,r});\n\t\t\t\tmemo[z.y][z.z][r]=z.x+dis[z.y][z.z];\n\t\t\t}\n\t\t}\n\t\t\n\t\t\n\t\t\n\t}\n\tcout<<min(memo[gx][gy][0],memo[gx][gy][1])<<endl;\n\t\n\treturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 150, "memory_kb": 24092, "score_of_the_acc": -0.1219, "final_rank": 1 }, { "submission_id": "aoj_0639_3374372", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<cstring>\n#include<functional>\nusing namespace std;\n#define ll long long\nconst ll linf = 1e15;\nstruct node{\n int h, w;\n ll cost;\n bool operator<(const node &n1) const {\n return n1.cost < cost;\n }\n};\n\nstruct edge{\n int h, w, k;\n ll cost;\n bool operator<(const edge &e1) const {\n return e1.cost < cost;\n }\n};\n\nint H, W, N;\nint dx[] = {1, 0, -1, 0};\nint dy[] = {0, 1, 0, -1};\nll A, B, C;\nll D[501][501][5], near[501][501];\nint ph[100010], pw[100010];\n\nvoid dijk(){\n for(int i = 0; i <= H; i++){\n for(int j = 0; j <= W; j++){\n near[i][j] = linf;\n }\n }\n priority_queue<node> pq;\n for(int i = 1; i <= N; i++){\n near[ph[i]][pw[i]] = 0;\n pq.push(node{ph[i], pw[i], 0});\n }\n \n while(!pq.empty()){\n int h = pq.top().h;\n int w = pq.top().w;\n ll cost = pq.top().cost;\n pq.pop();\n if(near[h][w] < cost) continue;\n \n cost++;\n for(int i = 0; i < 4; i++){\n int nh = h + dx[i];\n int nw = w + dy[i];\n if(nh < 0 || H < nh) continue;\n if(nw < 0 || W < nw) continue;\n if(near[nh][nw] > cost){\n near[nh][nw] = cost;\n pq.push(node{nh, nw, cost});\n }\n }\n }\n}\n\nll solve(){\n dijk();\n for(int i = 0; i <= H; i++){\n for(int j = 0; j <= W; j++){\n for(int k = 0; k <= 4; k++){\n D[i][j][k] = linf;\n }\n }\n }\n priority_queue<edge> pq;\n pq.push(edge{ph[1], pw[1], 4, 0});\n D[ph[1]][pw[1]][4] = 0;\n\n while(!pq.empty()){\n int h = pq.top().h;\n int w = pq.top().w;\n int k = pq.top().k;\n ll cost = pq.top().cost;\n pq.pop();\n\n if(D[h][w][k] < cost) continue;\n\n if(k == 4){\n for(int i = 0; i < 4; i++){\n int nh = h + dx[i];\n int nw = w + dy[i];\n if(nh < 0 || H < nh) continue;\n if(nw < 0 || W < nw) continue;\n if(D[nh][nw][k] > cost + C){\n D[nh][nw][k] = cost + C;\n pq.push(edge{nh, nw, k, cost + C});\n }\n }\n for(int i = 0; i < 4; i++){\n ll new_c = cost + B;\n if(D[h][w][i] > new_c){\n D[h][w][i] = new_c;\n pq.push(edge{h, w, i, new_c});\n }\n }\n }else{\n ll new_c = cost + near[h][w] * C;\n if(D[h][w][4] > new_c){\n D[h][w][4] = new_c;\n pq.push(edge{h, w, 4, new_c});\n }\n \n new_c = cost + A;\n int nh = h + dx[k];\n int nw = w + dy[k];\n if(nh < 0 || H < nh) continue;\n if(nw < 0 || W < nw) continue;\n if(D[nh][nw][k] > new_c){\n D[nh][nw][k] = new_c;\n pq.push(edge{nh, nw, k, new_c});\n }\n }\n }\n ll ans = linf;\n for(int i = 0; i <= 4; i++){\n ans = min(ans, D[ph[N]][pw[N]][i]);\n }\n return ans;\n}\n\nvoid init(){\n cin >> H >> W >> A >> B >> C >> N;\n for(int i = 1; i <= N; i++){\n cin >> ph[i] >> pw[i];\n }\n}\n\nint main(){\n init();\n cout << solve() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 24584, "score_of_the_acc": -0.2124, "final_rank": 6 }, { "submission_id": "aoj_0639_3370324", "code_snippet": "#include <iostream>\n#include <queue>\n#include <functional>\n#include <tuple>\nusing namespace std;\n\nlong long dist[509][509][5], dp[509][509], H, W, A, B, C, N, sx, sy, gx, gy;\npriority_queue<tuple<long long, int, int, int>, vector<tuple<long long, int, int, int>>, greater<tuple<long long, int, int, int>>>que;\npriority_queue<tuple<long long, int, int>, vector<tuple<long long, int, int>>, greater<tuple<long long, int, int>>>que2;\n\nint main() {\n\tcin >> H >> W >> A >> B >> C >> N;\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++) dp[i][j] = (1LL << 30); }\n\tfor (int i = 1; i <= N; i++) {\n\t\tlong long x, y; cin >> x >> y;\n\t\tif (i == 1) { sx = x; sy = y; }\n\t\tif (i == N) { gx = x; gy = y; }\n\t\tdp[x][y] = 0; que2.push(make_tuple(0, x, y));\n\t}\n\n\t// パート A\n\twhile (!que2.empty()) {\n\t\tint p1 = get<1>(que2.top()), p2 = get<2>(que2.top()); que2.pop();\n\t\tint dx[4] = { 0, 1, 0, -1 }, dy[4] = { 1, 0, -1, 0 };\n\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint fx = p1 + dx[i], fy = p2 + dy[i];\n\t\t\tif (fx<0 || fy<0 || fx>H || fy>W) continue;\n\t\t\tif (dp[fx][fy] > dp[p1][p2] + C) {\n\t\t\t\tdp[fx][fy] = dp[p1][p2] + C;\n\t\t\t\tque2.push(make_tuple(dp[fx][fy], fx, fy));\n\t\t\t}\n\t\t}\n\t}\n\n\t// パート B\n\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++) { for (int k = 0; k < 5; k++) dist[i][j][k] = (1LL << 60); } }\n\tdist[sx][sy][4] = 0; que.push(make_tuple(0, sx, sy, 4));\n\n\twhile (!que.empty()) {\n\t\tint p1 = get<1>(que.top()), p2 = get<2>(que.top()), p3 = get<3>(que.top()); que.pop();\n\n\t\tint dx[4] = { 0, 1, 0, -1 }, dy[4] = { 1, 0, -1, 0 };\n\t\tif (p3 == 4) {\n\t\t\tfor (int i = 0; i <= 3; i++) {\n\t\t\t\tint fx = p1 + dx[i], fy = p2 + dy[i];\n\t\t\t\tif (fx < 0 || fy < 0 || fx > H || fy > W) continue;\n\t\t\t\tif (dist[fx][fy][4] > dist[p1][p2][p3] + C) {\n\t\t\t\t\tdist[fx][fy][4] = dist[p1][p2][p3] + C;\n\t\t\t\t\tque.push(make_tuple(dist[fx][fy][4], fx, fy, 4));\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (int i = 0; i <= 3; i++) {\n\t\t\t\tif (dist[p1][p2][i] > dist[p1][p2][p3] + B) {\n\t\t\t\t\tdist[p1][p2][i] = dist[p1][p2][p3] + B;\n\t\t\t\t\tque.push(make_tuple(dist[p1][p2][i], p1, p2, i));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tint fx = p1 + dx[p3], fy = p2 + dy[p3];\n\t\t\tif (fx >= 0 && fy >= 0 && fx <= H && fy <= W) {\n\t\t\t\tif (dist[fx][fy][p3] > dist[p1][p2][p3] + A) {\n\t\t\t\t\tdist[fx][fy][p3] = dist[p1][p2][p3] + A;\n\t\t\t\t\tque.push(make_tuple(dist[fx][fy][p3], fx, fy, p3));\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (dist[p1][p2][4] > dist[p1][p2][p3] + dp[p1][p2]) {\n\t\t\t\tdist[p1][p2][4] = dist[p1][p2][p3] + dp[p1][p2];\n\t\t\t\tque.push(make_tuple(dist[p1][p2][4], p1, p2, 4));\n\t\t\t}\n\t\t}\n\t}\n\tcout << dist[gx][gy][4] << endl;\n\treturn 0;\n}", "accuracy": 0.15384615384615385, "time_ms": 160, "memory_kb": 21088, "score_of_the_acc": -0.1077, "final_rank": 19 }, { "submission_id": "aoj_0639_3119771", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 505\n\nenum Type{\n\tSTOP,\n\tFLY_North,\n\tFLY_East,\n\tFLY_South,\n\tFLY_West,\n};\n\nstruct LOC{\n\tint row,col;\n};\n\nstruct Info{\n\tInfo(int arg_row,int arg_col,ll arg_sum_cost){\n\t\tloc.row = arg_row;\n\t\tloc.col = arg_col;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tLOC loc;\n\tll sum_cost;\n};\n\nstruct Edge{\n\tEdge(int arg_row,int arg_col,Type arg_type,ll arg_cost){\n\t\tloc.row = arg_row;\n\t\tloc.col = arg_col;\n\t\ttype = arg_type;\n\t\tcost = arg_cost;\n\t}\n\tLOC loc;\n\tType type;\n\tll cost;\n};\n\nstruct State{\n\tState(int arg_row,int arg_col,Type arg_type,ll arg_sum_cost){\n\t\tloc.row = arg_row;\n\t\tloc.col = arg_col;\n\t\ttype = arg_type;\n\t\tsum_cost = arg_sum_cost;\n\t}\n\tbool operator<(const struct State &arg) const{\n\t\treturn sum_cost > arg.sum_cost;\n\t}\n\tLOC loc;\n\tType type;\n\tll sum_cost;\n};\n\nint H,W;\nint N;\nint diff_row[4] = {-1,0,1,0},diff_col[4] = {0,1,0,-1};\nll A,B,C;\nll nearest_cost[NUM][NUM];\nll min_cost[NUM][NUM][5];\nbool table[NUM][NUM];\nLOC start,goal;\nType type_array[5] = {STOP,FLY_North,FLY_East,FLY_South,FLY_West};\nvector<Edge> edge[NUM][NUM][5];\n\nbool rangeCheck(int row,int col){\n\tif(row >= 0 && row <= H-1 && col >= 0 && col <= W-1){\n\t\treturn true;\n\t}else{\n\t\treturn false;\n\t}\n}\n\nint main(){\n\n\tscanf(\"%d %d\",&H,&W);\n\tH += 1;\n\tW += 1;\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\ttable[row][col] = false;\n\t\t}\n\t}\n\n\tscanf(\"%lld %lld %lld\",&A,&B,&C);\n\n\tscanf(\"%d\",&N);\n\n\tint tmp_row,tmp_col;\n\n\tscanf(\"%d %d\",&start.row,&start.col);\n\ttable[start.row][start.col] = true;\n\n\tfor(int loop = 1; loop < N-1; loop++){\n\t\tscanf(\"%d %d\",&tmp_row,&tmp_col);\n\t\ttable[tmp_row][tmp_col] = true;\n\t}\n\n\tscanf(\"%d %d\",&goal.row,&goal.col);\n\ttable[goal.row][goal.col] = true;\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tnearest_cost[row][col] = HUGE_NUM;\n\t\t}\n\t}\n\n\tqueue<Info> CALC;\n\tint adj_row,adj_col;\n\tll next_cost;\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tif(!table[row][col])continue;\n\n\t\t\tnearest_cost[row][col] = 0;\n\t\t\tCALC.push(Info(row,col,0));\n\n\t\t\twhile(!CALC.empty()){\n\n\t\t\t\tfor(int i = 0; i < 4; i++){\n\n\t\t\t\t\tadj_row = CALC.front().loc.row+diff_row[i];\n\t\t\t\t\tadj_col = CALC.front().loc.col+diff_col[i];\n\n\t\t\t\t\tif(!rangeCheck(adj_row,adj_col))continue;\n\n\t\t\t\t\tnext_cost = CALC.front().sum_cost+C;\n\n\t\t\t\t\tif(nearest_cost[adj_row][adj_col] > next_cost){\n\n\t\t\t\t\t\tnearest_cost[adj_row][adj_col] = next_cost;\n\t\t\t\t\t\tCALC.push(Info(adj_row,adj_col,next_cost));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tCALC.pop();\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\n\t\t\tfor(int i = 0; i < 4; i++){\n\n\t\t\t\tadj_row = row+diff_row[i];\n\t\t\t\tadj_col = col+diff_col[i];\n\n\t\t\t\tif(!rangeCheck(adj_row,adj_col))continue;\n\n\t\t\t\tedge[row][col][STOP].push_back(Edge(adj_row,adj_col,type_array[STOP],C));\n\n\t\t\t\tedge[row][col][STOP].push_back(Edge(row,col,type_array[i+1],B));\n\t\t\t}\n\n\t\t\tedge[row][col][FLY_North].push_back(Edge(row,col,type_array[STOP],nearest_cost[row][col]));\n\t\t\tif(row > 0){\n\t\t\t\tedge[row][col][FLY_North].push_back(Edge(row-1,col,type_array[FLY_North],A));\n\t\t\t}\n\n\t\t\tedge[row][col][FLY_East].push_back(Edge(row,col,type_array[STOP],nearest_cost[row][col]));\n\t\t\tif(col+1 < W){\n\t\t\t\tedge[row][col][FLY_East].push_back(Edge(row,col+1,type_array[FLY_East],A));\n\t\t\t}\n\n\t\t\tedge[row][col][FLY_South].push_back(Edge(row,col,type_array[STOP],nearest_cost[row][col]));\n\t\t\tif(row+1 < H){\n\t\t\t\tedge[row][col][FLY_South].push_back(Edge(row+1,col,type_array[FLY_South],A));\n\t\t\t}\n\n\t\t\tedge[row][col][FLY_West].push_back(Edge(row,col,type_array[STOP],nearest_cost[row][col]));\n\t\t\tif(col-1 >= 0){\n\t\t\t\tedge[row][col][FLY_West].push_back(Edge(row,col-1,type_array[FLY_West],A));\n\t\t\t}\n\t\t}\n\t}\n\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\t\t\tfor(int a = 0; a < 5; a++){\n\t\t\t\tmin_cost[row][col][a] = HUGE_NUM;\n\t\t\t}\n\t\t}\n\t}\n\n\tpriority_queue<State> Q;\n\tmin_cost[start.row][start.col][STOP] = 0;\n\tQ.push(State(start.row,start.col,STOP,0));\n\tLOC next_loc;\n\tType next_type;\n\n\twhile(!Q.empty()){\n\n\t\tif(Q.top().loc.row == goal.row && Q.top().loc.col == goal.col && Q.top().type == STOP){\n\n\t\t\tbreak;\n\n\t\t}else{\n\n\t\t\tfor(int i = 0; i < edge[Q.top().loc.row][Q.top().loc.col][Q.top().type].size(); i++){\n\n\t\t\t\tnext_loc = edge[Q.top().loc.row][Q.top().loc.col][Q.top().type][i].loc;\n\t\t\t\tnext_cost = Q.top().sum_cost+edge[Q.top().loc.row][Q.top().loc.col][Q.top().type][i].cost;\n\t\t\t\tnext_type = edge[Q.top().loc.row][Q.top().loc.col][Q.top().type][i].type;\n\n\t\t\t\tif(min_cost[next_loc.row][next_loc.col][next_type] > next_cost){\n\n\t\t\t\t\tmin_cost[next_loc.row][next_loc.col][next_type] = next_cost;\n\t\t\t\t\tQ.push(State(next_loc.row,next_loc.col,next_type,next_cost));\n\t\t\t\t}\n\t\t\t}\n\t\t\tQ.pop();\n\t\t}\n\t}\n\n\tprintf(\"%lld\\n\",min_cost[goal.row][goal.col][STOP]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1650, "memory_kb": 164888, "score_of_the_acc": -1.936, "final_rank": 16 }, { "submission_id": "aoj_0639_3089969", "code_snippet": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#include<unordered_map>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\n#define H 510\nstruct Ver{\n ll y,x,t;\n Ver(ll y,ll x,ll t){\n\tthis->y=y,this->x=x,this->t=t;\n }\n bool operator<(const Ver&key)const{return 0;}\n bool operator>(const Ver&key)const{return 0;}\n bool operator==(const Ver&key)const{\n\treturn this->y==key.y&&this->x==key.x&&this->t==key.t;\n }\n bool operator!=(const Ver&key)const{\n\treturn !(this->operator==(key));\n }\n struct Hash{\n\tll operator()(const Ver&key)const{\n\t return key.t*H*H+key.y*H+key.x;\n\t}\n };\n};\n#define N 100010\nll h,w,a,b,c,n,s[N],t[N];\nint dx[]={0,1,0,-1},dy[]={1,0,-1,0};\nll dis[H][H];\nunordered_map<Ver,ll,Ver::Hash> d;\nvoid Dijkstra(Ver s){\n typedef pair<ll,Ver> P;\n priority_queue<P,vector<P>,greater<P> >Q;\n Q.push(make_pair(0,s));\n while(!Q.empty()){\n\tll cost=Q.top().first;\n\tVer key=Q.top().second;\n\tQ.pop();\n\tll i=key.y,j=key.x,t=key.t;\n\tif(i<0||i==h||j<0||j==w)continue;\n\tif(d.find(key)!=d.end())continue;\n\td[key]=cost;\n\tlol(r,4){\n\t int xx=j+dx[r],yy=i+dy[r];\n\t if(t==4){\n\t\tQ.push(make_pair(cost+b,Ver(i,j,r)));\n\t\tQ.push(make_pair(cost+c,Ver(yy,xx,4)));\n\t }\n\t if(t==r){\n\t\tQ.push(make_pair(cost+dis[i][j]*c,Ver(i,j,4)));\n\t\tQ.push(make_pair(cost+a,Ver(yy,xx,r)));\n\t }\n\t}\n }\n}\nvoid BFS(){\n lol(i,h)lol(j,w)dis[i][j]=mod;\n queue<Ver> Q;\n lol(i,n)Q.push(Ver(s[i],t[i],0));\n while(!Q.empty()){\n\tVer key=Q.front();\n\tQ.pop();\n\tll y=key.y,x=key.x,t=key.t;\n\tif(dis[y][x]<=t)continue;\n\tdis[y][x]=t;\n\tlol(r,4){\n\t int xx=x+dx[r],yy=y+dy[r];\n\t if(xx<0||xx==w||yy<0||yy==h)continue;\n\t Q.push(Ver(yy,xx,t+1));\n\t}\n }\n}\nint main(){\n cin>>h>>w>>a>>b>>c>>n;h++,w++;\n lol(i,n)scanf(\"%lld%lld\",&s[i],&t[i]);BFS();\n Dijkstra(Ver(s[0],t[0],4));\n cout<<d[Ver(s[n-1],t[n-1],4)]<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1760, "memory_kb": 132492, "score_of_the_acc": -1.7833, "final_rank": 15 }, { "submission_id": "aoj_0639_2867029", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int D = 511;\nconst int di[4] = {-1, 0, 1, 0};\nconst int dj[4] = {0, -1, 0, 1};\nconst int BRING = 4;\nconst ll INF = 1LL<<60;\n\nstruct Ball {\n int i, j; char state;\n bool operator<(const Ball& o) const {\n return i != o.i ? i < o.i : j != o.j ? j < o.j : state < o.state;\n }\n};\n\nint bring[D][D];\nll dist[D][D][5];\nint main() {\n int n, m, k;\n ll a, b, c;\n scanf(\"%d%d%lld%lld%lld%d\", &n, &m, &a, &b, &c, &k);\n #define in_bounds(i,j) (0 <= (i) && (i) <= n && 0 <= (j) && (j) <= m)\n for (int i = 0; i <= n; i++) {\n for (int j = 0; j <= m; j++) {\n bring[i][j] = n + m;\n for (int state = 0; state < 5; state++) {\n dist[i][j][state] = INF;\n }\n }\n }\n int bi = -1, bj = -1, ti, tj;\n vector<pair<int,int>> que;\n while (k--) {\n scanf(\"%d%d\", &ti, &tj);\n if (!~bi) bi = ti, bj = tj;\n if (bring[ti][tj]) {\n bring[ti][tj] = 0;\n que.emplace_back(ti, tj);\n }\n }\n for (int f = 0; f < que.size(); f++) {\n int i, j;\n tie(i, j) = que[f];\n for (int d = 0; d < 4; d++) {\n int ni = i + di[d], nj = j + dj[d];\n if (in_bounds(ni, nj) && bring[ni][nj] > bring[i][j] + 1) {\n bring[ni][nj] = bring[i][j] + 1;\n que.emplace_back(ni, nj);\n }\n }\n }\n que.clear();\n\n typedef pair<ll,Ball> pear;\n priority_queue<pear, vector<pear>, greater<pear>> pq;\n pq.push({0LL, {bi, bj, BRING}});\n while (!pq.empty()) {\n ll dst;\n Ball x;\n tie(dst, x) = pq.top(); pq.pop();\n if (dist[x.i][x.j][x.state] <= dst) continue;\n if (x.i == ti && x.j == tj) {\n printf(\"%lld\\n\", dst);\n return 0;\n }\n dist[x.i][x.j][x.state] = dst;\n #define neighbor(d,i,j,state) do {\\\n if (dist[i][j][state] > (d)) pq.push({(d), {(i), (j), (state)}});\\\n } while (0)\n neighbor(dst + c * bring[x.i][x.j], x.i, x.j, BRING); // drop + walk\n if (x.state == BRING) {\n for (char d = 0; d < 4; d++) {\n int ni = x.i + di[d], nj = x.j + dj[d];\n if (in_bounds(ni, nj)) neighbor(dst + c, ni, nj, BRING); // bring\n neighbor(dst + b, x.i, x.j, d); // kick start\n }\n } else {\n int ni = x.i + di[x.state], nj = x.j + dj[x.state];\n if (in_bounds(ni, nj)) neighbor(dst + a, ni, nj, x.state); // kick go\n }\n }\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 41836, "score_of_the_acc": -0.3337, "final_rank": 10 }, { "submission_id": "aoj_0639_2867026", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int D = 511;\nconst int di[4] = {-1, 0, 1, 0};\nconst int dj[4] = {0, -1, 0, 1};\nconst int DROP = 4;\nconst int BRING = 5;\nconst ll INF = 1LL<<60;\n\nstruct Ball {\n int i, j; char state;\n bool operator<(const Ball& o) const {\n return i != o.i ? i < o.i : j != o.j ? j < o.j : state < o.state;\n }\n};\n\nint bring[D][D];\nll dist[D][D][6];\nint main() {\n int n, m, k;\n ll a, b, c;\n scanf(\"%d%d%lld%lld%lld%d\", &n, &m, &a, &b, &c, &k);\n #define in_bounds(i,j) (0 <= (i) && (i) <= n && 0 <= (j) && (j) <= m)\n for (int i = 0; i <= n; i++) {\n for (int j = 0; j <= m; j++) {\n bring[i][j] = n + m;\n for (int state = 0; state < 6; state++) {\n dist[i][j][state] = INF;\n }\n }\n }\n int bi = -1, bj = -1, ti, tj;\n vector<pair<int,int>> que;\n while (k--) {\n scanf(\"%d%d\", &ti, &tj);\n if (!~bi) bi = ti, bj = tj;\n if (bring[ti][tj]) {\n bring[ti][tj] = 0;\n que.emplace_back(ti, tj);\n }\n }\n for (int f = 0; f < que.size(); f++) {\n int i, j;\n tie(i, j) = que[f];\n for (int d = 0; d < 4; d++) {\n int ni = i + di[d], nj = j + dj[d];\n if (in_bounds(ni, nj) && bring[ni][nj] > bring[i][j] + 1) {\n bring[ni][nj] = bring[i][j] + 1;\n que.emplace_back(ni, nj);\n }\n }\n }\n que.clear();\n\n typedef pair<ll,Ball> pear;\n priority_queue<pear, vector<pear>, greater<pear>> pq;\n pq.push({0LL, {bi, bj, DROP}});\n while (!pq.empty()) {\n ll dst;\n Ball x;\n tie(dst, x) = pq.top(); pq.pop();\n if (dist[x.i][x.j][x.state] <= dst) continue;\n if (x.i == ti && x.j == tj) {\n printf(\"%lld\\n\", dst);\n return 0;\n }\n dist[x.i][x.j][x.state] = dst;\n #define neighbor(d,i,j,state) do {\\\n if (dist[i][j][state] > (d)) pq.push({(d), {(i), (j), (state)}});\\\n } while (0)\n neighbor(dst + 0LL, x.i, x.j, DROP); // drop\n if (x.state == DROP) { // walk to\n neighbor(dst + c * bring[x.i][x.j], x.i, x.j, BRING);\n } else if (x.state == BRING) {\n for (char d = 0; d < 4; d++) {\n int ni = x.i + di[d], nj = x.j + dj[d];\n if (in_bounds(ni, nj)) neighbor(dst + c, ni, nj, BRING); // bring\n neighbor(dst + b, x.i, x.j, d); // kick start\n }\n } else {\n int ni = x.i + di[x.state], nj = x.j + dj[x.state];\n if (in_bounds(ni, nj)) neighbor(dst + a, ni, nj, x.state); // kick go\n }\n }\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 25500, "score_of_the_acc": -0.2186, "final_rank": 7 }, { "submission_id": "aoj_0639_2867001", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int D = 511;\nconst int di[4] = {-1, 0, 1, 0};\nconst int dj[4] = {0, -1, 0, 1};\nconst int DROP = -2;\nconst int BRING = -1;\nstruct Ball;\ntypedef pair<ll,Ball> pear;\n\nint n, m;\nll a, b, c;\ninline bool in_bounds(int i, int j) {\n return 0 <= i && i <= n && 0 <= j && j <= m;\n}\n\nll dsts[D][D];\nint ti, tj;\nstruct Ball {\n int i, j, state;\n bool operator<(const Ball& o) const {\n if (i != o.i) return i < o.i;\n if (j != o.j) return j < o.j;\n return state < o.state;\n }\n bool operator==(const Ball& o) const {\n return i == o.i && j == o.j && state == o.state;\n }\n bool is_end() {\n return i == ti && j == tj;\n }\n vector<pear> adj() {\n vector<pear> res;\n // drop\n res.push_back({0LL, {i, j, DROP}});\n if (state == DROP) {\n // walk to\n res.push_back({c * dsts[i][j], {i, j, BRING}});\n } else if (state == BRING) {\n for (int d = 0; d < 4; d++) {\n int ni = i + di[d];\n int nj = j + dj[d];\n // bring\n if (in_bounds(ni, nj)) {\n res.push_back({c, {ni, nj, BRING}});\n }\n // kick start\n res.push_back({b, {i, j, d}});\n }\n } else {// kick\n int ni = i + di[state];\n int nj = j + dj[state];\n if (in_bounds(ni, nj)) {\n res.push_back({a, {ni, nj, state}});\n }\n }\n return res;\n }\n};\n\nvoid solve() {\n int k;\n if (scanf(\"%d%d%lld%lld%lld%d\", &n, &m, &a, &b, &c, &k) != 6) exit(0);\n for (int i = 0; i <= n; i++) {\n for (int j = 0; j <= m; j++) {\n dsts[i][j] = n + m;\n }\n }\n int bi = -1, bj = -1;\n vector<pair<int,int>> que;\n while (k--) {\n scanf(\"%d%d\", &ti, &tj);\n if (!~bi) bi = ti, bj = tj;\n if (dsts[ti][tj]) {\n dsts[ti][tj] = 0;\n que.emplace_back(ti, tj);\n }\n }\n for (int f = 0; f < que.size(); f++) {\n int i, j;\n tie(i, j) = que[f];\n for (int d = 0; d < 4; d++) {\n int ni = i + di[d];\n int nj = j + dj[d];\n if (in_bounds(ni, nj) && dsts[ni][nj] > dsts[i][j] + 1) {\n dsts[ni][nj] = dsts[i][j] + 1;\n que.emplace_back(ni, nj);\n }\n }\n }\n\n priority_queue<pear, vector<pear>, greater<pear>> pq;\n pq.push({0LL, {bi, bj, DROP}});\n map<Ball,ll> dit;\n while (!pq.empty()) {\n ll d;\n Ball i;\n tie(d, i) = pq.top(); pq.pop();\n if (dit.count(i)) continue;\n if (i.is_end()) {\n printf(\"%lld\\n\", d);\n return;\n }\n dit[i] = d;\n for (auto nb : i.adj()) {\n if (!dit.count(nb.second)) {\n pq.emplace(d + nb.first, nb.second);\n }\n }\n }\n assert(false);\n}\n\nint main() {\n while (true) solve();\n}", "accuracy": 1, "time_ms": 1620, "memory_kb": 100028, "score_of_the_acc": -1.4847, "final_rank": 14 }, { "submission_id": "aoj_0639_2866181", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i, a, b) for (int(i) = int(a); (i) <= int(b); (i)++)\n#define F first\n#define S second\ntypedef long long ll;\ntypedef pair<int, int> ii;\n\n#define H 511\nll h, w, a, b, c, n, sx, sy, s, t, tx, ty, res;\nll dist[H][H], dp[H][H][5];\nqueue<pair<ii, int>> q;\n\nint dx[] = {-1, 1, 0, 0};\nint dy[] = {0, 0, -1, 1};\n\nvoid solve(int i, int j, int st) {\n //cout << i << ' ' << j << ' ' << st << ' ' << dp[i][j][st] << endl;\n if (st == 0) { // if i am being dribbled\n REP(k, 1, 4) { // in any direction\n int I = i+dx[k-1], J = j+dy[k-1];\n if (0 > I || I > h || 0 > J || J > w) continue;\n // i could continue being dribbled\n if (dp[i][j][0] + c < dp[I][J][0]) {\n dp[I][J][0] = dp[i][j][0] + c;\n //cout << \" \" << I << ' ' << J << ' ' << 0 << ' ' << dp[I][J][0] << endl;\n q.emplace(ii(I, J), 0);\n }\n // i could be kicked\n if (dp[i][j][0] + a + b < dp[I][J][k]) {\n dp[I][J][k] = dp[i][j][0] + a + b;\n //cout << \" \" << I << ' ' << J << ' ' << k << ' ' << dp[I][J][k] << endl;\n q.emplace(ii(I, J), k);\n }\n }\n } else { // if i am being kicked\n // i could keep going in the same direction\n int k = st;\n int I = i+dx[k-1], J = j+dy[k-1];\n if (0 <= I && I <= h && 0 <= J && J <= w && dp[i][j][k] + a < dp[I][J][k]) {\n dp[I][J][k] = dp[i][j][k] + a;\n //cout << \" \" << I << ' ' << J << ' ' << k << ' ' << dp[I][J][k] << endl;\n q.emplace(ii(I, J), k);\n }\n // someone could catch me\n if (dp[i][j][k] + c * dist[i][j] < dp[i][j][0]) {\n dp[i][j][0] = dp[i][j][k] + c * dist[i][j];\n //cout << \" \" << i << ' ' << j << ' ' << 0 << ' ' << dp[i][j][0] << endl;\n q.emplace(ii(i, j), 0);\n }\n }\n}\n\nint main() {\n ios_base::sync_with_stdio(0);\n cin >> h >> w >> a >> b >> c >> n;\n memset(dist, -1, sizeof(dist));\n memset(dp, 63, sizeof(dp));\n cin >> sx >> sy;\n dist[sx][sy] = 0;\n q.emplace(ii(sx, sy), 0);\n REP(i, 2, n-1) {\n cin >> s >> t;\n dist[s][t] = 0;\n q.emplace(ii(s, t), 0);\n }\n cin >> tx >> ty;\n while (!q.empty()) {\n int x = q.front().F.F, y = q.front().F.S; q.pop();\n REP(k, 0, 3) {\n int X = x+dx[k], Y = y+dy[k];\n if (0 <= X && X <= h && 0 <= Y && Y <= w && !~dist[X][Y]) {\n dist[X][Y] = dist[x][y] + 1;\n q.emplace(ii(X, Y), 0);\n }\n }\n }\n\n // REP(i, 0, h) {\n // REP(j, 0, w) cout << dist[i][j] << ' ';\n // cout << endl;\n // }\n\n dp[sx][sy][0] = 0;\n q.emplace(ii(sx, sy), 0);\n while (!q.empty()) {\n solve(q.front().F.F, q.front().F.S, q.front().S);\n q.pop();\n }\n res = 0x3f3f3f3f;\n REP(k, 0, 5) res = min(res, dp[tx][ty][k]);\n cout << res << endl;\n}", "accuracy": 0.15384615384615385, "time_ms": 40, "memory_kb": 15424, "score_of_the_acc": 0, "final_rank": 17 }, { "submission_id": "aoj_0639_2697519", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<queue>\n#include<functional>\n#define PAIR pair<int,int>\nusing namespace std;\nclass point{\npublic:\n vector<long long> dp;\n long long fast;\n point(){\n dp.resize(5,((long long)1<<63)-1);\n fast = 10000000;\n }\n};\nint H,W;\nlong long A,B,C,N;\nvector<PAIR> mv;\nclass num{\npublic:\n long long time;\n PAIR pos;\n int dir;\n};\n\nbool operator<(const num&A,const num&B){\n return A.time<B.time;\n}\nbool operator>(const num&A,const num&B){\n return A.time>B.time;\n}\nbool operator==(const num&A,const num&B){\n return A.time==B.time;\n}\n\nPAIR operator + (const PAIR&A,const PAIR&B){\n PAIR res;\n res.first = A.first+B.first;\n res.second = A.second+B.second;\n return res;\n}\n\npoint& getpa(vector<vector<point> >&map,PAIR d){\n int x =d.first;\n int y = d.second;\n return map[x][y];\n}\n\nvoid getfast(vector<vector<point> >&,vector<PAIR>&);\nbool isin(int,int);\nint main(){\n mv.resize(5);\n mv[0]=PAIR(1,0);\n mv[1]=PAIR(0,-1);\n mv[2]=PAIR(-1,0);\n mv[3]=PAIR(0,1);\n mv[4]=PAIR(0,0);\n cin>>H>>W>>A>>B>>C>>N;\n vector<vector<point> > map(W+1,vector<point>(H+1));\n vector<PAIR> player(N);\n for(int i=0;i<N;++i){\n cin>>player[i].second>>player[i].first;\n }\n getfast(map,player);\n priority_queue<num,vector<num>,greater<num> > que;\n getpa(map,player[0]).dp[4]=0;\n num start;\n start.time = 0;\n start.pos = player[0];\n start.dir = 4;\n /*\n for(int y=0;y<map.front().size();++y){\n for(int x=0;x<map.size();++x){\n cout<<map[x][y].dp[4]<<\" \";\n }\n cout<<endl;\n }\n */\n que.push(start);\n while(!que.empty()){\n num d = que.top();\n que.pop();\n if(d.time!=getpa(map,d.pos).dp[d.dir]){\n continue;\n }\n if(d.dir<4){\n PAIR np = d.pos + mv[d.dir];\n if(isin(np.first,np.second)){\n long long ntime = d.time + A;\n if(ntime<getpa(map,np).dp[d.dir]){\n getpa(map,np).dp[d.dir] = ntime;\n num dnum;\n dnum.time = ntime;\n dnum.pos = np;\n dnum.dir = d.dir;\n que.push(dnum);\n }\n }\n long long ntime = d.time + getpa(map,d.pos).fast;\n if(ntime<getpa(map,d.pos).dp[4]){\n getpa(map,d.pos).dp[4] = ntime;\n num dnum;\n dnum.time = ntime;\n dnum.pos = d.pos;\n dnum.dir = 4;\n que.push(dnum);\n }\n }else{\n for(int i=0;i<4;++i){\n long long ntime = d.time + B;\n if(ntime<getpa(map,d.pos).dp[i]){\n getpa(map,d.pos).dp[i]=ntime;\n num dnum;\n dnum.time = ntime;\n dnum.pos = d.pos;\n dnum.dir = i;\n que.push(dnum);\n }\n ntime = d.time + C;\n PAIR np = d.pos + mv[i];\n if(!isin(np.first,np.second)){\n continue;\n }\n if(ntime<getpa(map,np).dp[4]){\n getpa(map,np).dp[4]=ntime;\n num dnum;\n dnum.time = ntime;\n dnum.pos = np;\n dnum.dir = 4;\n que.push(dnum);\n }\n }\n }\n }\n cout<<getpa(map,player.back()).dp[4]<<endl;\n \n /*\n for(int y=0;y<map.front().size();++y){\n for(int x=0;x<map.size();++x){\n cout<<map[x][y].dp[4]<<\" \";\n }\n cout<<endl;\n }\n */\n return 0;\n}\n\nvoid getfast(vector<vector<point> >& map,vector<PAIR>&player){\n queue<PAIR> que;\n for(int i=0;i<player.size();++i){\n int x = player[i].first;\n int y = player[i].second;\n que.push(player[i]);\n getpa(map,player[i]).fast=0;\n }\n while(!que.empty()){\n PAIR d = que.front();\n que.pop();\n for(int i=0;i<4;++i){\n PAIR np = d+mv[i];\n if(!isin(np.first,np.second)){\n continue;\n }\n if(getpa(map,np).fast>getpa(map,d).fast+1){\n getpa(map,np).fast = getpa(map,d).fast+1;\n que.push(np);\n }\n }\n }\n for(int x=0;x<map.size();++x){\n for(int y=0;y<map.front().size();++y){\n getpa(map,PAIR(x,y)).fast*=C;\n }\n }\n}\n\nbool isin(int x,int y){\n return x>=0&&x<=W&&y>=0&&y<=H;\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 29520, "score_of_the_acc": -0.292, "final_rank": 9 }, { "submission_id": "aoj_0639_2647548", "code_snippet": "#include <queue>\n#include <vector>\n#include <iostream>\nusing namespace std;\ntypedef long long ll;\nstruct edge { int to; ll cost; };\nstruct state { int pos; ll cost; };\nbool operator<(const state& s1, const state& s2) { return s1.cost > s2.cost; }\nint dx[] = { 0, 1, 0, -1 };\nint dy[] = { 1, 0, -1, 0 };\nint H, W, A, B, C, N, x[100009], y[100009], xl[100009], xr[100009], yl[100009], yr[100009], ds[509][509]; vector<vector<edge> > g;\nvoid add_edge(int v1, int v2, ll c) {\n\tg[v1].push_back(edge{ v2, c });\n}\nvoid add_edge2(int v1, int v2, ll c) {\n\tadd_edge(v1, v2, c);\n\tadd_edge(v2, v1, c);\n}\nll shortest_path(int start, int goal) {\n\tvector<ll> dist(g.size(), 1LL << 60); dist[start] = 0;\n\tpriority_queue<state> que; que.push(state{ start, 0 });\n\twhile (!que.empty()) {\n\t\tint u = que.top().pos; que.pop();\n\t\tfor (edge e : g[u]) {\n\t\t\tll nd = dist[u] + e.cost;\n\t\t\tif (dist[e.to] > nd) {\n\t\t\t\tdist[e.to] = nd;\n\t\t\t\tque.push(state{ e.to, nd });\n\t\t\t}\n\t\t}\n\t}\n\treturn dist[goal];\n}\nint main() {\n\tios::sync_with_stdio(false);\n\tcin >> H >> W >> A >> B >> C >> N; H++; W++;\n\tg.resize(3 * H * W);\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (j >= 1) {\n\t\t\t\tadd_edge2(i * W + j, i * W + j - 1, C);\n\t\t\t\tadd_edge2(H * W + i * W + j, H * W + i * W + j - 1, A);\n\t\t\t}\n\t\t\tif (i >= 1) {\n\t\t\t\tadd_edge2(i * W + j, i * W + j - W, C);\n\t\t\t\tadd_edge2(2 * H * W + i * W + j, 2 * H * W + i * W + j - W, A);\n\t\t\t}\n\t\t\tadd_edge(i * W + j, H * W + i * W + j, B);\n\t\t\tadd_edge(i * W + j, 2 * H * W + i * W + j, B);\n\t\t\tds[i][j] = -1;\n\t\t}\n\t}\n\tfill(xl, xl + H, W + 1);\n\tfill(xr, xr + H, -1);\n\tfill(yl, yl + W, H + 1);\n\tfill(yr, yr + W, -1);\n\tqueue<pair<int, int> > qs;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> x[i] >> y[i];\n\t\txl[x[i]] = min(xl[x[i]], y[i]);\n\t\txr[x[i]] = max(xr[x[i]], y[i]);\n\t\tyl[y[i]] = min(yl[y[i]], x[i]);\n\t\tyr[y[i]] = max(yr[y[i]], x[i]);\n\t\tds[x[i]][y[i]] = 0;\n\t\tadd_edge(H * W + x[i] * W + y[i], x[i] * W + y[i], 0);\n\t\tadd_edge(2 * H * W + x[i] * W + y[i], x[i] * W + y[i], 0);\n\t\tqs.push(make_pair(x[i], y[i]));\n\t}\n\twhile (!qs.empty()) {\n\t\tpair<int, int> u = qs.front(); qs.pop();\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint px = u.first + dx[i], py = u.second + dy[i];\n\t\t\tif (0 <= px && px < H && 0 <= py && py < W && ds[px][py] == -1) {\n\t\t\t\tds[px][py] = ds[u.first][u.second] + 1;\n\t\t\t\tadd_edge(H * W + px * W + py, px * W + py, 1LL * ds[px][py] * C);\n\t\t\t\tadd_edge(2 * H * W + px * W + py, px * W + py, 1LL * ds[px][py] * C);\n\t\t\t\tqs.push(make_pair(px, py));\n\t\t\t}\n\t\t}\n\t}\n\tcout << shortest_path(x[0] * W + y[0], x[N - 1] * W + y[N - 1]) << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 590, "memory_kb": 115452, "score_of_the_acc": -0.989, "final_rank": 13 }, { "submission_id": "aoj_0639_2647318", "code_snippet": "#include <iostream>\n#include <queue>\n#include <algorithm>\n#include <vector>\n#include <functional>\n#include <tuple>\nusing namespace std;\nlong long H, W, A, B, C, N, x[100009], y[100009], dist[509][509][4], dp[509][509], dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };\npriority_queue<tuple<long long, int, int>, vector<tuple<long long, int, int>>, greater<tuple<long long, int, int>>>q;\npriority_queue<tuple<long long, int, int, int>, vector<tuple<long long, int, int, int>>, greater<tuple<long long, int, int, int>>>Q;\nint main() {\n\tcin >> H >> W >> A >> B >> C >> N;\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++)dp[i][j] = (1LL << 62); }\n\tfor (int i = 1; i <= N; i++) { cin >> x[i] >> y[i]; if (i < N) dp[x[i]][y[i]] = 0; q.push(make_tuple(0, x[i], y[i])); }\n\twhile (!q.empty()) {\n\t\tlong long a1 = get<0>(q.top()), a2 = get<1>(q.top()), a3 = get<2>(q.top()); q.pop();\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint cx = a2 + dx[i], cy = a3 + dy[i];\n\t\t\tif (cx < 0 || cx > H || cy < 0 || cy > W)continue;\n\t\t\tif (dp[cx][cy] > a1 + C) {\n\t\t\t\tdp[cx][cy] = a1 + C; q.push(make_tuple(dp[cx][cy], cx, cy));\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++) { for (int k = 0; k < 4; k++)dist[i][j][k] = (1LL << 62); } }\n\tdist[x[1]][y[1]][1] = 0; Q.push(make_tuple(0LL, x[1], y[1], 1));\n\twhile (!Q.empty()) {\n\t\tlong long a1 = get<0>(Q.top()), a2 = get<1>(Q.top()), a3 = get<2>(Q.top()), a4 = get<3>(Q.top()); Q.pop();\n\t\tif (a4 == 0) {\n\t\t\tif (dist[a2][a3][1] > a1 + dp[a2][a3]) { dist[a2][a3][1] = a1 + dp[a2][a3]; Q.push(make_tuple(dist[a2][a3][1], a2, a3, 1)); }\n\t\t}\n\t\tif (a4 == 1) {\n\t\t\tif (dist[a2][a3][2] > a1 + B) { dist[a2][a3][2] = a1 + B; Q.push(make_tuple(dist[a2][a3][2], a2, a3, 2)); }\n\t\t\tif (dist[a2][a3][3] > a1 + B) { dist[a2][a3][3] = a1 + B; Q.push(make_tuple(dist[a2][a3][3], a2, a3, 3)); }\n\t\t\tif (a2 - 1 >= 0 && dist[a2 - 1][a3][1] > a1 + C) { dist[a2 - 1][a3][1] = a1 + C; Q.push(make_tuple(dist[a2 - 1][a3][1], a2 - 1, a3, 1)); }\n\t\t\tif (a2 + 1 <= H && dist[a2 + 1][a3][1] > a1 + C) { dist[a2 + 1][a3][1] = a1 + C; Q.push(make_tuple(dist[a2 + 1][a3][1], a2 + 1, a3, 1)); }\n\t\t\tif (a3 - 1 >= 0 && dist[a2][a3 - 1][1] > a1 + C) { dist[a2][a3 - 1][1] = a1 + C; Q.push(make_tuple(dist[a2][a3 - 1][1], a2, a3 - 1, 1)); }\n\t\t\tif (a3 + 1 <= W && dist[a2][a3 + 1][1] > a1 + C) { dist[a2][a3 + 1][1] = a1 + C; Q.push(make_tuple(dist[a2][a3 + 1][1], a2, a3 + 1, 1)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t\tif (a4 == 2) {\n\t\t\tif (a2 - 1 >= 0 && dist[a2 - 1][a3][2] > a1 + A) { dist[a2 - 1][a3][2] = a1 + A; Q.push(make_tuple(dist[a2 - 1][a3][2], a2 - 1, a3, 2)); }\n\t\t\tif (a2 + 1 <= H && dist[a2 + 1][a3][2] > a1 + A) { dist[a2 + 1][a3][2] = a1 + A; Q.push(make_tuple(dist[a2 + 1][a3][2], a2 + 1, a3, 2)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t\tif (a4 == 3) {\n\t\t\tif (a3 - 1 >= 0 && dist[a2][a3 - 1][3] > a1 + A) { dist[a2][a3 - 1][3] = a1 + A; Q.push(make_tuple(dist[a2][a3 - 1][3], a2, a3 - 1, 3)); }\n\t\t\tif (a3 + 1 <= W && dist[a2][a3 + 1][3] > a1 + A) { dist[a2][a3 + 1][3] = a1 + A; Q.push(make_tuple(dist[a2][a3 + 1][3], a2, a3 + 1, 3)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t}\n\tcout << dist[x[N]][y[N]][0] << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 23552, "score_of_the_acc": -0.1823, "final_rank": 5 }, { "submission_id": "aoj_0639_2647315", "code_snippet": "#include <iostream>\n#include <queue>\n#include <algorithm>\n#include <vector>\n#include <functional>\n#include <tuple>\nusing namespace std;\nlong long H, W, A, B, C, N, x[100009], y[100009], dist[509][509][4], dp[509][509], dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };\npriority_queue<tuple<int, int, int>, vector<tuple<int, int, int>>, greater<tuple<int, int, int>>>q;\npriority_queue<tuple<long long, int, int, int>, vector<tuple<long long, int, int, int>>, greater<tuple<long long, int, int, int>>>Q;\nint main() {\n\tcin >> H >> W >> A >> B >> C >> N;\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++)dp[i][j] = 999999999; }\n\tfor (int i = 1; i <= N; i++) { cin >> x[i] >> y[i]; if (i < N) dp[x[i]][y[i]] = 0; q.push(make_tuple(0, x[i], y[i])); }\n\twhile (!q.empty()) {\n\t\tint a1 = get<0>(q.top()), a2 = get<1>(q.top()), a3 = get<2>(q.top()); q.pop();\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint cx = a2 + dx[i], cy = a3 + dy[i];\n\t\t\tif (cx < 0 || cx > H || cy < 0 || cy > W)continue;\n\t\t\tif (dp[cx][cy] > a1 + C) {\n\t\t\t\tdp[cx][cy] = a1 + C; q.push(make_tuple(dp[cx][cy], cx, cy));\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 0; i <= H; i++) { for (int j = 0; j <= W; j++) { for (int k = 0; k < 4; k++)dist[i][j][k] = (1LL << 62); } }\n\tdist[x[1]][y[1]][1] = 0; Q.push(make_tuple(0LL, x[1], y[1], 1));\n\twhile (!Q.empty()) {\n\t\tint a1 = get<0>(Q.top()), a2 = get<1>(Q.top()), a3 = get<2>(Q.top()), a4 = get<3>(Q.top()); Q.pop();\n\t\tif (a4 == 0) {\n\t\t\tif (dist[a2][a3][1] > a1 + dp[a2][a3]) { dist[a2][a3][1] = a1 + dp[a2][a3]; Q.push(make_tuple(dist[a2][a3][1], a2, a3, 1)); }\n\t\t}\n\t\tif (a4 == 1) {\n\t\t\tif (dist[a2][a3][2] > a1 + B) { dist[a2][a3][2] = a1 + B; Q.push(make_tuple(dist[a2][a3][2], a2, a3, 2)); }\n\t\t\tif (dist[a2][a3][3] > a1 + B) { dist[a2][a3][3] = a1 + B; Q.push(make_tuple(dist[a2][a3][3], a2, a3, 3)); }\n\t\t\tif (a2 - 1 >= 0 && dist[a2 - 1][a3][1] > a1 + C) { dist[a2 - 1][a3][1] = a1 + C; Q.push(make_tuple(dist[a2 - 1][a3][1], a2 - 1, a3, 1)); }\n\t\t\tif (a2 + 1 <= H && dist[a2 + 1][a3][1] > a1 + C) { dist[a2 + 1][a3][1] = a1 + C; Q.push(make_tuple(dist[a2 + 1][a3][1], a2 + 1, a3, 1)); }\n\t\t\tif (a3 - 1 >= 0 && dist[a2][a3 - 1][1] > a1 + C) { dist[a2][a3 - 1][1] = a1 + C; Q.push(make_tuple(dist[a2][a3 - 1][1], a2, a3 - 1, 1)); }\n\t\t\tif (a3 + 1 <= W && dist[a2][a3 + 1][1] > a1 + C) { dist[a2][a3 + 1][1] = a1 + C; Q.push(make_tuple(dist[a2][a3 + 1][1], a2, a3 + 1, 1)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t\tif (a4 == 2) {\n\t\t\tif (a2 - 1 >= 0 && dist[a2 - 1][a3][2] > a1 + A) { dist[a2 - 1][a3][2] = a1 + A; Q.push(make_tuple(dist[a2 - 1][a3][2], a2 - 1, a3, 2)); }\n\t\t\tif (a2 + 1 <= H && dist[a2 + 1][a3][2] > a1 + A) { dist[a2 + 1][a3][2] = a1 + A; Q.push(make_tuple(dist[a2 + 1][a3][2], a2 + 1, a3, 2)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t\tif (a4 == 3) {\n\t\t\tif (a3 - 1 >= 0 && dist[a2][a3 - 1][3] > a1 + A) { dist[a2][a3 - 1][3] = a1 + A; Q.push(make_tuple(dist[a2][a3 - 1][3], a2, a3 - 1, 3)); }\n\t\t\tif (a3 + 1 <= W && dist[a2][a3 + 1][3] > a1 + A) { dist[a2][a3 + 1][3] = a1 + A; Q.push(make_tuple(dist[a2][a3 + 1][3], a2, a3 + 1, 3)); }\n\t\t\tif (dist[a2][a3][0] > a1) { dist[a2][a3][0] = a1; Q.push(make_tuple(dist[a2][a3][0], a2, a3, 0)); }\n\t\t}\n\t}\n\tcout << dist[x[N]][y[N]][0] << endl;\n\treturn 0;\n}", "accuracy": 0.15384615384615385, "time_ms": 130, "memory_kb": 18968, "score_of_the_acc": -0.076, "final_rank": 18 }, { "submission_id": "aoj_0639_2596111", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\nusing namespace std;\ntypedef pair<ll,int> ii;\n#define fi first\n#define se second\nint dx[] = {1,0,-1,0};\nint dy[] = {0,1,0,-1};\nll A,B,C;\nint n,h,w;\nll dp0[505][505], dp1[505][505][4];\nbool player[505][505];\nint min_distance[505][505];\nvoid prep(){\n\tqueue <int> q;\n\tfor(int i=0;i<=h;i++)\n\t\tfor(int j=0;j<=w;j++){\n\t\t\tif (player[i][j]) min_distance[i][j] = 0, q.push(i * 501 + j);\n\t\t\telse min_distance[i][j] = 100000;\n\t\t}\n\twhile(q.size()){\n\t\tint x = q.front() / 501;\n\t\tint y = q.front() % 501;\n\t\tq.pop();\n\t\tfor(int k=0;k<4;k++){\n\t\t\tint X = x + dx[k];\n\t\t\tint Y = y + dy[k];\n\t\t\tif (0 > X || X > h || 0 > Y || Y > w) continue;\n\t\t\tif (min_distance[X][Y] > min_distance[x][y] + 1)\n\t\t\t\tmin_distance[X][Y] = min_distance[x][y] + 1,\n\t\t\t\tq.push(X * 501 + Y);\n\t\t}\n\t}\n}\n#define x1 asd\n#define y1 jnda\n#define xn addaf\n#define yn nln\nint x1,y1,xn,yn;\nvoid prep_dp(){\n\tfor(int i=0;i<=h;i++)\n\t\tfor(int j=0;j<=w;j++)\n\t\t\tdp0[i][j] = dp1[i][j][0] = dp1[i][j][1] = dp1[i][j][2] = dp1[i][j][3] = (ll) 1e18;\n\tdp0[x1][y1] = 0;\n}\nbool markh[505], markw[505];\n \nvoid cal_dp(){\n\tpriority_queue <ii,vector<ii>,greater<ii> > pq;\n\t\n\tpq.push(ii(0, x1 * 3500 + y1 * 5));\n\t\t\n\twhile(pq.size()){\n\t\tint x = pq.top().se / 3500;\n\t\tint y = (pq.top().se % 3500) / 5;\n\t\tint type = pq.top().se % 5;\n\t\tll dis = pq.top().fi;\n\t\tpq.pop();\n\t\t\n\t\tif (type == 0 && dp0[x][y] != dis) continue;\n\t\tif (type && dp1[x][y][type-1] != dis) continue;\n\t\t\n\t\tif (type == 0){\n\t\t\tfor(int k=0;k<4;k++){\n\t\t\t\tint X = x + dx[k];\n\t\t\t\tint Y = y + dy[k];\n\t\t\t\tif (0 > X || X > h || 0 > Y || Y > w) continue;\n\t\t\t\tif (dp1[X][Y][k] > dp0[x][y] + A + B)\n\t\t\t\t\tdp1[X][Y][k] = dp0[x][y] + A + B,\n\t\t\t\t\tpq.push(ii(dp1[X][Y][k], X * 3500 + Y * 5 + k+1));\n\t\t\t\t\t\n\t\t\t\tif (dp0[X][Y] > dp0[x][y] + C)\n\t\t\t\t\tdp0[X][Y] = dp0[x][y] + C,\n\t\t\t\t\tpq.push(ii(dp0[X][Y], X * 3500 + Y * 5 + 0));\n\t\t\t}\n\t\t}\n\t\telse{\n\t\t\tint X = x + dx[type-1];\n\t\t\tint Y = y + dy[type-1];\n\t\t\tif (dp1[x][y][type-1] + min_distance[x][y] * C < dp0[x][y])\n\t\t\t\tdp0[x][y] = dp1[x][y][type-1] + min_distance[x][y] * C,\n\t\t\t\tpq.push(ii(dp0[x][y], x*3500 + y*5));\n\t\t\tif (0 > X || X > h || 0 > Y || Y > w) continue;\n\t\t\tif (dp1[X][Y][type-1] > dp1[x][y][type-1] + A)\n\t\t\t\tdp1[X][Y][type-1] = dp1[x][y][type-1] + A,\n\t\t\t\tpq.push(ii(dp1[X][Y][type-1], X * 3500 + Y * 5 + type));\n\t\t\t\n\t\t}\n\t}\n}\nint main(){\n\tiostream::sync_with_stdio(0);\n\tcin >> h >> w;\n\tcin >> A >> B >> C;\n\tcin >> n;\n\tfor(int i=1;i<=n;i++){\n\t\tint x,y;\n\t\tcin >> x >> y; \n\t\tif (i == 1) x1 = x, y1 = y;\n\t\tif (i == n) xn = x, yn = y;\n\t\tplayer[x][y] = 1;\n\t}\n\tprep();\n\tprep_dp();\n\tcal_dp();\n\tcout << dp0[xn][yn] << endl;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 18216, "score_of_the_acc": -0.1408, "final_rank": 3 }, { "submission_id": "aoj_0639_2477023", "code_snippet": "#include <cstdio>\n#include <queue>\n#include <algorithm>\n#define X_MAX 500\n#define Y_MAX 500\n#define N_MAX 100000\n#define V_MAX ((X_MAX + 1) * (Y_MAX + 1))\n#define lld \"%lld\"\ntypedef long long lnt;\ntypedef bool bnt;\ntypedef void vnt;\nconst lnt LNF = 0x3F3F3F3F3F3F3FLL;\nconst int dx[] = {-1, 0, +1, 0}, dy[] = {0, -1, 0, +1};\nint X, Y, N, i, k, x, y, u, v, sx, sy, tx, ty, Ql = -1, Qr = -1, Q[V_MAX * 2];\nlnt A, B, C, dir[X_MAX + 1][Y_MAX + 1], dis[X_MAX + 1][Y_MAX + 1][3];\ninline bnt chk(int x, int y) { return x >= 0 && x <= X && y >= 0 && y <= Y; }\nstruct dat\n{\n\tint k, x, y; lnt d;\n\tbnt operator < (const dat & p) const { return d > p.d; }\n} p;\nstd::priority_queue<dat> P;\nint main()\n{\n\tscanf(\"%d %d\" lld lld lld \"%d\", &X, &Y, &A, &B, &C, &N);\n\tfor (x = 0; x <= X; ++x)\n\t\tfor (y = 0; y <= Y; ++y)\n\t\t\tdir[x][y] = -1;\n\tscanf(\"%d %d\", &sx, &sy), dir[sx][sy] = 0;\n\tfor (i = 2; i < N; ++i)\n\t\tscanf(\"%d %d\", &x, &y), dir[x][y] = 0;\n\tscanf(\"%d %d\", &tx, &ty), dir[tx][ty] = 0;\n\tfor (x = 0; x <= X; ++x)\n\t\tfor (y = 0; y <= Y; ++y)\n\t\t\tif (!dir[x][y])\n\t\t\t\tQ[++Qr] = x, Q[++Qr] = y;\n\twhile (Ql < Qr)\n\t{\n\t\tx = Q[++Ql], y = Q[++Ql];\n\t\tfor (k = 0; k < 4; ++k)\n\t\t\tif (chk(u = x + dx[k], v = y + dy[k]) && !~dir[u][v])\n\t\t\t\tdir[u][v] = dir[x][y] + C, Q[++Qr] = u, Q[++Qr] = v;\n\t}\n\tfor (k = 0; k < 3; ++k)\n\t\tfor (x = 0; x <= X; ++x)\n\t\t\tfor (y = 0; y <= Y; ++y)\n\t\t\t\tdis[x][y][k] = LNF;\n\tP.push((dat) {2, sx, sy, 0});\n\twhile (true)\n\t{\n\t\tp = P.top(), P.pop();\n\t\tif (dis[p.x][p.y][p.k] < LNF)\n\t\t\tcontinue;\n\t\tif (p.x == tx && p.y == ty)\n\t\t\tbreak;\n\t\tdis[p.x][p.y][p.k] = p.d;\n\t\tswitch (p.k)\n\t\t{\n\t\tcase 2:\n\t\t\tfor (k = 0; k < 2; ++k)\n\t\t\t\tif (dis[p.x][p.y][k] == LNF)\n\t\t\t\t\tP.push((dat) {k, p.x, p.y, p.d + B});\n\t\t\tfor (k = 0; k < 4; ++k)\n\t\t\t\tif (chk(u = p.x + dx[k], v = p.y + dy[k]) && dis[u][v][2] == LNF)\n\t\t\t\t\tP.push((dat) {p.k, u, v, p.d + C});\n\t\t\tbreak;\n\t\tdefault:\n\t\t\tif (dis[p.x][p.y][2] == LNF)\n\t\t\t\tP.push((dat) {2, p.x, p.y, p.d + dir[p.x][p.y]});\n\t\t\tfor (k = p.k; k < 4; k += 2)\n\t\t\t\tif (chk(u = p.x + dx[k], v = p.y + dy[k]) && dis[u][v][p.k] == LNF)\n\t\t\t\t\tP.push((dat) {p.k, u, v, p.d + A});\n\t\t}\n\t}\n\tprintf(lld \"\\n\", p.d);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 24476, "score_of_the_acc": -0.1478, "final_rank": 4 } ]
aoj_0637_cpp
Semiexpress The JOI Railways is the only railway company in the Kingdom of JOI. There are $N$ stations numbered from $1$ to $N$ along a railway. Currently, two kinds of trains are operated; one is express and the other one is local. A local train stops at every station. For each $i$ ($1 \leq i < N$), by a local train, it takes $A$ minutes from the station $i$ to the station ($i + 1$). An express train stops only at the stations $S_1, S_2, ..., S_M$ ($1 = S_1 < S_2 < ... < S_M = N$). For each $i$ ($1 \leq i < N$), by an express train, it takes $B$ minutes from the station $i$ to the station ($i + 1$). The JOI Railways plans to operate another kind of trains called "semiexpress." For each $i$ ($1 \leq i < N$), by a semiexpress train, it takes $C$ minutes from the station $i$ to the station ($i + 1$). The stops of semiexpress trains are not yet determined. But they must satisfy the following conditions: Semiexpress trains must stop at every station where express trains stop. Semiexpress trains must stop at $K$ stations exactly. The JOI Railways wants to maximize the number of stations (except for the station 1) to which we can travel from the station 1 within $T$ minutes. The JOI Railways plans to determine the stops of semiexpress trains so that this number is maximized. We do not count the standing time of trains. When we travel from the station 1 to another station, we can take trains only to the direction where the numbers of stations increase. If several kinds of trains stop at the station $i$ ($2 \leq i \leq N - 1$), you can transfer between any trains which stop at that station. When the stops of semiexpress trains are determined appropriately, what is the maximum number of stations (except for the station 1) to which we can travel from the station 1 within $T$ minutes? Task Given the number of stations of the JOI Railways, the stops of express trains, the speeds of the trains, and maximum travel time, write a program which calculates the maximum number of stations which satisfy the condition on the travel time. Input Read the following data from the standard input. The first line of input contains three space separated integers $N$, $M$, $K$. This means there are $N$ stations of the JOI Railways, an express train stops at $M$ stations, and a semiexpress train stops at $K$ stations, The second line of input contains three space separated integers $A$, $B$, $C$. This means it takes $A$, $B$, $C$ minutes by a local, express, semiexpress train to travel from a station to the next station, respectively. >li> The third line of input contains an integer $T$. This means the JOI Railways wants to maximize the number of stations (except for the station 1) to which we can travel from the station 1 within $T$ minutes. The $i$-th line ($1 \leq i \leq M$) of the following $M$ lines contains an integer $S_i$. This means an express train stops at the station $S_i$. Output Write one line to the standard output. The output contains the maximum number of stati ...(truncated)
[ { "submission_id": "aoj_0637_9741930", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#define ll long long\n\nusing namespace std;\n\nconst int MAX = 3000;\n\nint n, m, k;\nll a, b, c, t;\nint s[MAX];\n\nint arr[3000 * 3000], p = 0;\n\nint calc(int l, int r) {\n int res = 0;\n ll temp = b * l;\n int idx = l, cnt = 0;\n while (idx < r) {\n ll rem = t - temp;\n if (rem < 0) break;\n rem /= a;\n ll nxt = idx + rem + 1;\n nxt = min((ll)r, nxt);\n if (idx == l) res = nxt - idx;\n else arr[p++] = nxt - idx;\n temp += c * (nxt - idx);\n idx = nxt;\n cnt++;\n if (cnt > k - m) break;\n }\n return res;\n}\n\nint go() {\n int res = b * s[m - 1] <= t ? 1 : 0;\n for (int i = 0; i < m - 1; ++i) {\n res += calc(s[i], s[i + 1]);\n }\n sort(arr, arr + p);\n reverse(arr, arr + p);\n for (int i = 0; i < k - m; ++i) {\n res += arr[i];\n }\n return res - 1;\n}\n\nvoid read() {\n cin >> n >> m >> k;\n cin >> a >> b >> c >> t;\n \n for (int i = 0; i < m; ++i) {\n cin >> s[i];\n s[i]--; // adjusting the input by -1 as in the original\n }\n}\n\nint main() {\n read();\n int res = go();\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4752, "score_of_the_acc": -0.0228, "final_rank": 1 }, { "submission_id": "aoj_0637_9477384", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\ntypedef long long int int64;\n\nint main() {\n int64 N, M, K, A, B, C, T;\n cin >> N >> M >> K;\n cin >> A >> B >> C;\n cin >> T;\n\n vector<int64> S(M + 1);\n for (int i = 0; i < M; ++i) {\n cin >> S[i];\n }\n S[M] = N + 1;\n K -= M;\n\n int64 ret = -1;\n vector<int64> vs;\n\n for (int i = 0; i < M; ++i) {\n int64 rest = T - (S[i] - 1) * B;\n if (rest < 0) break;\n int64 pv = S[i], reach = min(S[i + 1], pv + rest / A + 1);\n ret += reach - S[i];\n for (int j = 0; j < K && reach < S[i + 1]; ++j) {\n rest -= (reach - pv) * C;\n if (rest < 0) break;\n pv = reach;\n reach = min(S[i + 1], pv + rest / A + 1);\n vs.push_back(reach - pv);\n }\n }\n\n sort(vs.rbegin(), vs.rend());\n for (int i = 0; i < min(K, (int64)vs.size()); ++i) {\n ret += vs[i];\n }\n\n cout << ret << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8240, "score_of_the_acc": -0.0721, "final_rank": 7 }, { "submission_id": "aoj_0637_7028690", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n ll N, M, K, A, B, C, T, ans = -1;\n cin >> N >> M >> K >> A >> B >> C >> T;\n K -= M;\n vector<ll> S(M), add;\n for(auto &&v:S)cin >> v;\n auto f = [&](ll s, ll t){\n ll st = (s - 1) * B, pos = s;\n for(int i = 0; i <= K && pos < t; i++){\n ll at = st + C * (pos - s);\n if(at > T)return;\n ll inc = (T - at) / A + 1;\n ll nxt = min(t, pos + inc);\n if(i == 0)ans += nxt - pos;\n else add.push_back(nxt - pos);\n pos = nxt;\n }\n };\n S.push_back(N + 1);\n for(int i = 0; i < M; i++){\n f(S[i], S[i + 1]);\n }\n sort(add.rbegin(), add.rend());\n for(int i = 0; i < K && i < add.size(); i++)ans += add[i];\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 8532, "score_of_the_acc": -0.0763, "final_rank": 8 }, { "submission_id": "aoj_0637_6784837", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nint n, m, k;\nll a, b, c;\nll t;\nstruct sexpress {\n int x;\n ll arrival_time;\n bool operator<(const sexpress& s) const {\n return x < s.x;\n }\n sexpress min_unreachable(int next_x) {\n ll num_reachable = 1 + (t - arrival_time) / a;\n int min_unreachable = min(x + num_reachable, ll(next_x));\n ll t_to_min_unreachable = arrival_time + (min_unreachable - x) * c;\n return {min_unreachable, t_to_min_unreachable};\n }\n int gain(int next_x) {\n return min_unreachable(next_x).x - x;\n }\n};\nstruct candidate_loc {\n sexpress s;\n int gain;\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cin >> n >> m >> k;\n cin >> a >> b >> c;\n cin >> t;\n vector<int> express(m);\n cin >> express;\n vector<sexpress> semi_express;\n for(int x : express) {\n semi_express.push_back({x, (x - 1) * b});\n }\n semi_express.push_back({n + 1, lim<ll>::max()});\n while(semi_express.size() < k + 1) {\n vector<candidate_loc> candidate_locs;\n for(int i = 0; i < semi_express.size() - 1; i++) {\n auto [x, arrival_time] = semi_express[i];\n if(arrival_time <= t) {\n sexpress candidate_semi = semi_express[i].min_unreachable(semi_express[i + 1].x);\n if(candidate_semi.x < semi_express[i + 1].x and candidate_semi.arrival_time <= t) {\n candidate_locs.push_back({candidate_semi, candidate_semi.gain(semi_express[i + 1].x)});\n }\n }\n }\n if(candidate_locs.empty()) {\n break;\n }\n candidate_loc best_location = *max_element(candidate_locs.begin(), candidate_locs.end(), [&](const candidate_loc& x, const candidate_loc& y) {\n return x.gain < y.gain;\n });\n semi_express.push_back(best_location.s);\n sort(semi_express.begin(), semi_express.end());\n }\n int ans = 0;\n for(int i = 0; i < semi_express.size() - 1; i++) {\n if(semi_express[i].arrival_time <= t) {\n ans += semi_express[i].gain(semi_express[i + 1].x);\n }\n }\n cout << ans - 1 << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3496, "score_of_the_acc": -0.2778, "final_rank": 11 }, { "submission_id": "aoj_0637_5339665", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <cstdio>\n#include <vector>\nusing namespace std;\n\nint main(){\n long long N, M, K;\n cin >> N >> M >> K;\n long long A, B, C, T;\n cin >> A >> B >> C >> T;\n vector<long long> S(M);\n for(int i = 0; i < M; ++i) cin >> S[i], --S[i];\n S.push_back(N);\n K -= M;\n vector<long long> D;\n long long b = 0;\n for(int i = 0; i < M; ++i){\n long long s = S[i]*B, l = S[i];\n long long d = T - s;\n if(d < 0) break;\n long long r = l + d/A;\n r = min(r,S[i+1]-1);\n b += r - l + 1;\n // printf(\"i, l, r = %lld, %lld, %lld\\n\",i,l,r);\n l = r+1;\n for(int j = 0; j < K; ++j){\n if(l >= S[i+1]) break;\n long long t = s + (l-S[i])*C, d = T - t;\n if(d < 0) break;\n r = l + d/A;\n r = min(r,S[i+1]-1);\n long long c = r - l + 1;\n // printf(\"i, j, l, r = %lld, %lld, %lld, %lld\\n\",i,j,l,r);\n D.push_back(c);\n l = r + 1;\n }\n }\n sort(D.rbegin(), D.rend());\n long long ans = b;\n\n for(int i = 0; i < min(K,(long long)D.size()); ++i)\n ans += D[i];\n cout << ans-1 << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6968, "score_of_the_acc": -0.0542, "final_rank": 4 }, { "submission_id": "aoj_0637_5102916", "code_snippet": "#include<bits/stdc++.h>\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\nusing ll = long long;\nusing namespace std;\n\nll kyukou[3005];// map<ll, ll> cost;\nsigned main() {\n\tll n, m, k; cin >> n >> m >> k;\n\tll a, b, c; cin >> a >> b >> c;\n\tll t; cin >> t;\n\trep(i, m) { cin >> kyukou[i]; }\n\tkyukou[m] = n + 1;\n\tvector<ll> v;\n\tll ans = 0;\n\trep(i, m) {\n\t\tif ((kyukou[i] - 1) * b > t) { break; }\n\t\tll next = kyukou[i] + (t - ((kyukou[i] - 1) * b)) / a + 1;\n\t\tans += min(next, kyukou[i + 1]) - kyukou[i];\n\t\trep(j, k) {\n\t\t\t//もし急行電車が次止まる駅を越したらbreak\n\t\t\tif (next >= kyukou[i + 1]) { break; }\n\t\t\t//もし間に合うなら価値をvに\n\t\t\tll cost = ((kyukou[i] - 1) * b) + ((next - kyukou[i]) * c);\n\t\t\tll cango = (t - cost) / a + 1;\n\t\t\tif (cost <= t) {\n\t\t\t\tv.push_back(min(cango, kyukou[i + 1] - next));\n\t\t\t}\n\t\t\tnext = next + cango;\n\t\t}\n\t}\n\tsort(all(v)); reverse(all(v));\n\trep(i, min((ll)v.size(), k - m)) {\n\t\tans += v[i];\n\t}\n\tcout << ans - 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 35868, "score_of_the_acc": -0.7353, "final_rank": 14 }, { "submission_id": "aoj_0637_4692283", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n#define PB push_back\nconstexpr int kN = int(3E3 + 10);\ntypedef long long int ll;\nll s[kN];\nll cal(ll &from, ll a, ll st, ll t, ll to) {\n\t//printf(\"cal(%lld, %lld, %lld, %lld, %lld)\", from, a, st, t, to);\n\tll ans = 0;\n\tif (from + (t - st) / a < to) {\n\t\tfrom += (t - st) / a + 1;\n\t\tans = (t - st) / a + 1;\n\t\t//printf(\"(a)\");\n\t}\n\telse {\n\t\t//printf(\"(b)\");\n\t\tans = to - from;\n\t\tfrom = to;\n\t}\n\t//printf(\" = %lld\\n\", ans);\n\treturn ans;\n}\nint main() {\n\tll n, a, b, c, t, m, k, ans = 0, now, lst, cnt;\n\tvector<ll> v;\n\tscanf(\"%lld%lld%lld%lld%lld%lld%lld\", &n, &m, &k, &a, &b, &c, &t);\n\tk -= m;\n\tfor (int i = 1; i <= m; i++) scanf(\"%lld\", &s[i]);\n\tm++;\n\ts[m] = n + 1;\n\tfor (int i = 1; i < m; i++) if (b * (s[i] - 1) <= t) {\n\t\tlst = s[i];\n\t\tans += cal(s[i], a, b * (s[i] - 1), t, s[i + 1]);\n\t\tnow = b * (lst - 1) + c * (s[i] - lst);\n\t\tcnt = k;\n\t\twhile (s[i] < s[i + 1] && now <= t && cnt--) {\n\t\t\tlst = s[i];\n\t\t\tv.PB(cal(s[i], a, now, t, s[i + 1]));\n\t\t\tnow += c * (s[i] - lst);\n\t\t}\n\t} else break;\n\tsort(v.begin(), v.end());\n\treverse(v.begin(), v.end());\n\tv.resize(k);\n\t//printf(\"v :\"); for (int i = 0; i < k; i++) printf(\" %lld\", i); printf(\"\\n\");\n\tfor (int i = 0; i < k; i++) if (v[i] > 0) ans += v[i];\n\tprintf(\"%lld\\n\", ans - 1);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6504, "score_of_the_acc": -0.0476, "final_rank": 2 }, { "submission_id": "aoj_0637_4160863", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing P = pair<int, int>;\nusing P3 = pair<int,P>;\nusing PP = pair<P, P>;\nconstexpr int INF = 1<<30;\nconstexpr ll MOD = ll(1e9)+7;\nconstexpr int di[] = {0,1,0,-1};\nconstexpr int dj[] = {1,0,-1,0};\n\n\nbool solve(){\n ll N, M, K, A, B, C, T;\n cin >> N >> M >> K >> A >> B >> C >> T;\n vector<ll> s(M);\n for(int i=0;i<M;i++){\n cin >> s[i];\n s[i]--;\n }\n ll ans = 0;\n vector<ll> ls;\n for(ll i=0;i<M-1;i++){\n if(B*s[i] > T) break;\n ll r = T-B*s[i], j = s[i], cnt, k = 0;\n cnt = min(r/A+1, s[i+1]-j);\n ans += cnt;\n j += cnt;\n r -= C*cnt;\n while(j < s[i+1] && r >= 0 && k <= K-M){\n cnt = min(r/A+1, s[i+1]-j);\n ls.emplace_back(cnt);\n j += cnt;\n r -= C*cnt;\n k++;\n }\n }\n ans--; // 駅1\n if(B*(N-1)<=T) ans++; // 駅N\n sort(ls.rbegin(), ls.rend());\n for(int i=0;i<min(K-M,ll(ls.size()));i++){\n ans += ls[i];\n }\n cout << ans << endl;\n return true;\n}\n\nint main(){\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7076, "score_of_the_acc": -0.0557, "final_rank": 6 }, { "submission_id": "aoj_0637_3180324", "code_snippet": "#include \"bits/stdc++.h\"\n\n#pragma warning(disable:4996)\nusing namespace std;\nusing ld=long double;\nld eps=1e-9;\n\nstruct Edge {\n\tint from;\n\tint to;\n\tlong long int val;\n};\n\nstruct Status {\n\tint now;\n\tint hot;\n\tint rest;\n\tlong long int cost;\n};\nbool operator<(const Status&l, const Status&r) {\n\treturn l.cost>r.cost;\n}\n\nvoid add_edge(vector<vector<Edge>>&graph,int a, int b, int c) {\n\tgraph[a].push_back(Edge{ a,b,c });\n\tgraph[b].push_back(Edge{ b,a,c });\n}\n\nlong long int value(const long long int sa, const long long int S, const long long int T) {\n\tif (sa > 0) {\n\t\treturn - sa*S;\n\t}\n\telse {\n\t\treturn - sa*T;\n\t}\n}\n\nint main() {\n\tlong long int N;\n\tint M,K;cin>>N>>M>>K;K-=M;\n\tlong long int A,B,C;cin>>A>>B>>C;\n\tlong long int T;cin>>T;\n\tvector<long long int>Ss(M);\n\tfor (int i = 0; i < M; ++i) {\n\t\tcin>>Ss[i];Ss[i]--;\n\t}\n\n\tlong long int ans=0;\n\tvector<long long int>v;\n\tfor (int i = 0; i < M; ++i) {\n\t\tlong long int exp_time=B*Ss[i];\n\t\tif (exp_time > T) {\n\n\t\t}\n\t\telse {\n\t\t\tif(i!=0)ans++;\n\t\t\tif(i==M-1)continue;\n\t\t\tlong long int rest_normal = Ss[i + 1] - Ss[i] - 1;\n\t\t\tlong long int rest_time=T-exp_time;\n\n\t\t\tlong long int normal_num=min(rest_normal,rest_time/A);\n\n\t\t\tans+=normal_num;\n\n\t\t\trest_normal-=normal_num;\n\n\t\t\tlong long int semi_point=Ss[i]+normal_num+1;\n\t\t\tint x=K;\n\t\t\twhile (rest_normal) {\n\t\t\t\tx--;\n\t\t\t\tif(x<0)break;\n\t\t\t\tlong long int semi_time=exp_time+C*(semi_point-Ss[i]);\n\t\t\t\tif (semi_time > T) {\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tlong long int nans=0;\n\t\t\t\t\tlong long int rest_time=T-semi_time;\n\t\t\t\t\tlong long int anormal_num=min(rest_normal,1+rest_time/A);\n\n\t\t\t\t\tnans=anormal_num;\n\t\t\t\t\tv.push_back(nans);\n\n\t\t\t\t\trest_normal-=anormal_num;\n\t\t\t\t\tsemi_point+=nans;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tsort(v.begin(),v.end(),greater<long long int>());\n\tlong long int plus=0;\n\tif(v.size()<K)plus=accumulate(v.begin(),v.end(),0ll);\n\telse plus=accumulate(v.begin(),v.begin()+K,0ll);\n\tcout<<ans+plus<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7068, "score_of_the_acc": -0.0556, "final_rank": 5 }, { "submission_id": "aoj_0637_3164471", "code_snippet": "// 基本テンプレート\n \n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\nusing namespace std;\n \n#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)\n#define repq(i,a,n) for(int (i)=(a); (i)<=(n); (i)++)\n#define repr(i,a,n) for(int (i)=(a); (i)>=(n); (i)--)\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define int long long int\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \ntypedef pair<int, int> pii;\ntypedef long long ll;\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1LL << 30;\nconst ll MOD = 1000000007LL;\n\nint N, M, K, A, B, C, T;\nint pos[3010];\n\n// dp, 区間 i に j 個おいたらどれだけ稼げるか\nint dp[3010][3010], pre[3010][3010];\n\nint get_time(int cur, int span) {\n return (cur - 1) * span;\n}\n\nint get_pos(int cur_time, int span) {\n return cur_time / span;\n}\n\nint get_bound(int cur_time, int cur_pos, int span, int lim) {\n int ub = INF, lb = -1;\n while(ub - lb > 1) {\n int mid = (ub + lb) / 2;\n if(cur_time + span * mid > lim) ub = mid;\n else lb = mid;\n }\n\n // fprintf(stderr, \"cur_time = %lld, cur_pos = %lld, lb = %lld\\n\", cur_time, cur_pos, lb);\n return cur_pos + lb;\n}\n\nsigned main() {\n cin >> N >> M >> K;\n cin >> A >> B >> C;\n cin >> T;\n for(int i=0; i<M; i++) {\n cin >> pos[i];\n }\n\n fill(dp[0], dp[3010], -1);\n dp[0][0] = 0;\n\n int rest = K - M;\n for(int i=0; i<M-1; i++) {\n // pre の計算\n int cur_pos = pos[i];\n for(int j=0; j<=rest; j++) {\n // cur_pos から見て、ギリギリ普通列車で行けるところ\n int cur_time = get_time(pos[i], B) + (cur_pos - pos[i]) * C;\n int posA = cur_pos;\n if(cur_time <= T) {\n posA = get_bound(cur_time, cur_pos, A, T);\n // fprintf(stderr, \"time = %lld, i = %lld, j = %lld, cur_pos = %lld, posA = %lld\\n\", cur_time, i, j, cur_pos, posA);\n \n // ギリギリ行けないところにおいてみる\n int reach_tail = (posA != pos[i+1] and get_time(pos[i+1], B) <= T);\n pre[i][j] = min(pos[i+1] - pos[i], posA - pos[i] + reach_tail);\n cur_pos = posA + 1;\n }\n else {\n pre[i][j] = (j == 0 ? 0 : pre[i][j-1]);\n }\n // fprintf(stderr, \"pre[%lld][%lld] = %lld\\n\", i, j, pre[i][j]);\n }\n\n // (lb, ub] の間に j 個おいたとして、最大何個カバーできるか?\n for(int j=0; j<=rest; j++) {\n for(int k=0; k<=j; k++) {\n if(dp[i][j-k] < 0) continue;\n if(pre[i][k] == 0) break;\n chmax(dp[i+1][j], dp[i][j-k] + pre[i][k]);\n }\n }\n }\n cout << dp[M-1][rest] << endl;\n return 0;\n}", "accuracy": 0.05555555555555555, "time_ms": 10, "memory_kb": 73892, "score_of_the_acc": -1, "final_rank": 20 }, { "submission_id": "aoj_0637_3164378", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n\nusing namespace std;\n\nconst long long int MOD = 1000000007;\n\nlong long int N, M, K, H, W, L, R;\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> N >> M >> K;\n\tlong long int a, b, c;\n\tcin >> a >> b >> c;\n\tcin >> R;\n\tvector<long long int>v(M);\n\tfor (auto &i : v)cin >> i;\n\tint ans = 0;\n\tif ((N - 1)*b <= R)ans++;\n\tvector<vector<int>>dp(M, vector<int>(K - M + 1));\n\tfor (int i = 0; i < M - 1; i++) {\n\t\tlong long int r = v[i] - 1;\n\t\tlong long int t = R - (v[i] - 1)*b;\n\t//\tcout << \"t \" << t << endl;\n\t\tif (t >= 0) {\n\t\t\tr = max(r, v[i] + t / a);\n\t\t\tr = min(r, v[i + 1] - 1);\n\t\t}\n\t\tans += max((long long int)0,r - v[i] + 1);\n\t//\tcout << i << \" \" << ans << endl;\n\t\tlong long int rbox = r;\n\t\tfor (int j = 0; j <= K - M; j++)dp[i + 1][j] = dp[i][j];\n\t\tfor (int j = 1; j <= K - M; j++) {\n\t\t\tt = R - (v[i] - 1)*b - ((rbox + 1) - v[i])*c;\n\t\t//\tcout << \"t \" << t << endl;\n\t\t\tif (t >= 0) {\n\t\t\t\trbox = max(rbox, rbox + 1 + t / a);\n\t\t\t\trbox = min(rbox, v[i + 1] - 1);\n\t\t\t\t//\tcout << i << \" \" << j << \" \" << rbox << endl;\n\t\t\t\tfor (int k = K - M; k >= j; k--) {\n\t\t\t\t\tdp[i + 1][k] = max(dp[i + 1][k], dp[i][k - j] + (int)(rbox - r));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n//\tfor (int i = 0; i < M; i++) {\n//\t\tfor (int j = 0; j <= K - M; j++) {\n//\t\t\tcout << i << \" \" << j << \" \" << dp[i][j] << endl;\n//\t\t}\n//\t}\n\tans--;\n//\tcout << ans << endl;\n\tcout << dp.back().back() + ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 8236, "score_of_the_acc": -1.0721, "final_rank": 16 }, { "submission_id": "aoj_0637_2867048", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n ll locs, locc, semc, expc, target;\n int exps, sems;\n scanf(\"%lld%d%d%lld%lld%lld%lld\", &locs, &exps, &sems, &locc, &expc, &semc, &target);\n vector<ll> expa(exps + 1);\n for (int i = 0; i < exps; i++) {\n scanf(\"%lld\", &expa[i]);\n }\n assert(expa[exps - 1] == locs);\n expa[exps] = locs + 1;\n vector<ll> pieces;\n ll pre = -1;\n for (int i = 0; i < exps; i++) {\n // expa[i], expa[i + 1]\n ll ctarget = target - (expa[i] - expa[0]) * expc;\n ll cremain = expa[i + 1] - expa[i];\n // ensure \n for (int add = 0; add <= sems - exps; add++) {\n ll L = 0, R = cremain + 1;\n while (R - L > 1) {\n ll M = L + R >> 1;\n ((M - 1) * locc <= ctarget ? L : R) = M;\n }\n if (add) {\n pieces.push_back(L);\n } else {\n pre += L;\n }\n ctarget -= L * semc;\n cremain -= L;\n }\n sort(pieces.begin(), pieces.end());\n if (pieces.size() > sems - exps) pieces.erase(pieces.begin(), pieces.end() - (sems - exps));\n }\n printf(\"%lld\\n\", pre + accumulate(pieces.begin(), pieces.end(), 0));\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3372, "score_of_the_acc": -0.2761, "final_rank": 10 }, { "submission_id": "aoj_0637_2866707", "code_snippet": "#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#define INF 1000000000000000\nusing namespace std;\ntypedef long long ll;\n\nvector<ll> valueChoices(ll width, ll startT, ll abortT, ll a, ll c, ll k) {\n\tvector<ll> ans(k + 1, 0);\n\tint lrs = 0;\n\tll margin = abortT - startT;\n\tll fus, tc;\n\t// printf(\"width %lld with start %lld abort %lld\\n\", width, startT, abortT);\n\tfor (int tc = 0; tc <= k && margin >= 0; ++tc) {\n\t\t//printf(\"iter %d\\n\", tc);\n\t\tll statReached = margin/a;\n\t\tll fus = lrs + statReached + 1;\n\t\t//printf(\"fus %lld\\n\", fus);\n\t\tans[tc] = min(width, fus) - lrs - (tc == 0);\n\t//\tprintf(\"with %d stations: %lld\\n\", tc, ans[tc]);\n\t\tif (fus >= width) {\n\t\t\tbreak;\n\t\t} else {\n\t\t\tmargin = abortT - (fus * c) - startT;\n\t\t\tlrs = fus;\n\t\t}\n\t}\n\treturn ans;\n}\n\nint main() {\n\tll n, m, k; scanf(\"%lld %lld %lld\", &n, &m, &k);\n\tll a, b, c; scanf(\"%lld %lld %lld\", &a, &b, &c);\n\tll t; scanf(\"%lld\", &t);\n\tvector<ll> stops(m, 0);\n\tfor (int i = 0; i < m; ++i) {\n\t\tscanf(\"%lld\", &stops[i]);\n\t}\n\tvector<ll> widths(m - 1, 0);\n\tfor (int i = 0; i < m - 1; ++i) {\n\t\twidths[i] = stops[i+1] - stops[i];\n\t}\n\tvector<ll> takeAns;\n\tll free = 0;\n\ttakeAns.reserve(k*k);\n\tfor (int i = 0; i < m - 1; ++i) {\n\t\tvector<ll> tAns = valueChoices(widths[i], (stops[i] - 1) * b, t, a, c, k);\n\t\tfor (int j = 1; j < (int)tAns.size(); ++j) {\n\t\t\ttakeAns.push_back(tAns[j]);\n\t\t}\n\t\tfree += tAns[0];\n\t}\n\tsort(takeAns.begin(), takeAns.end());\n\treverse(takeAns.begin(), takeAns.end());\n\tint wc = 0;\n\tfor (int i = 0; i < min(k - m, (ll)takeAns.size()); ++i) {\n\t\twc += takeAns[i];\n\t}\n\tfor (int i = 1; i < m; ++i) {\n\t\tif (b * (stops[i] - 1) <= t) {\n\t\t\t++wc;\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", wc + free);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 33492, "score_of_the_acc": -0.7472, "final_rank": 15 }, { "submission_id": "aoj_0637_2865258", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <set>\nusing namespace std;\nlong long int stationnum, expressnum, semiexpressnum;\nlong long int localexptime, exptime, semiexptime;\nlong long int t;\nvector <long long int> mustvisit;\nset <long long int> semiexpress;\nlong long int dps[7001];\nbool hasloc(int loc) {\n\tint s = 0;\n\tint e = mustvisit.size() - 1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] > loc)\n\t\t\te = m - 1;\n\t\telse if (mustvisit[m] < loc)\n\t\t\ts = m + 1;\n\t\telse {\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\n/*int bet(int loc1, int loc2) {\n\tint jumps = 0;\n\tif (hasloc(loc1))\n\t\tjumps--;\n\tif (hasloc(loc2))\n\t\tjumps--;\n\t//cout << loc1 << ' ' << loc2 << ' ' << \"JUMPS \" << jumps << '\\n';\n\tint s = 0;\n\tint e = mustvisit.size() - 1;\n\tint lowrange = -1;\n\tint highrange = -1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] >= loc1) {\n\t\t\te = m - 1;\n\t\t\tlowrange = m;\n\t\t}\n\t\telse if (mustvisit[m] < loc1)\n\t\t\ts = m + 1;\n\t}\n\ts = 0;\n\te = mustvisit.size() - 1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] > loc2) {\n\t\t\te = m - 1;\n\t\t}\n\t\telse if (mustvisit[m] <= loc2) {\n\t\t\ts = m + 1;\n\t\t\thighrange = m;\n\t\t}\n\t}\n\t//cout << \"RANGE \" << loc1 << ' ' << loc2 << ' ' << lowrange << ' ' << highrange << '\\n';\n\treturn jumps + 1 + (highrange - lowrange + 1);\n}*/\nlong long int dp(int loc) {\n\tif (loc == 1)\n\t\treturn 0;\n\tif (dps[loc] == -1) {\n\t\tdps[loc] = dp(loc - 1) + localexptime;\n\t\tfor (int i = loc - 1; i > 0; i--) {\n\t\t\tif (hasloc(i) && hasloc(loc)) {\n\t\t\t\tdps[loc] = min(dp(i) + min(exptime, semiexptime) * (loc - i), dps[loc]);\n\t\t\t}\n\t\t\telse if ((semiexpress.find(i) != semiexpress.end() && semiexpress.find(loc) != semiexpress.end()) && semiexpressnum - expressnum >= 1) {\n\t\t\t\tdps[loc] = min(dp(i) + semiexptime * (loc - i), dps[loc]);\n\t\t\t}\n\t\t\t//cout << loc << ' ' << dps[loc] << '\\n';\n\t\t}\n\t}\n\treturn dps[loc];\n}\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tcout.tie(NULL);\n\tfor (int i = 0; i <= 300; i++) {\n\t\tdps[i] = -1;\n\t}\n\tcin >> stationnum >> expressnum >> semiexpressnum;\n\tcin >> localexptime >> exptime >> semiexptime;\n\tcin >> t;\n\tmustvisit.resize(expressnum);\n\tfor (int i = 0; i < expressnum; i++) {\n\t\tcin >> mustvisit[i];\n\t\tsemiexpress.insert(mustvisit[i]);\n\t}\t\n\tint maxans = 0;\n\tfor (int i = 1; i <= stationnum; i++) {\n\t\tfor (int j = i + 1; j <= stationnum; j++) {\n\t\t\tint ans = 0;\n\t\t\tif (!hasloc(i) && !hasloc(j)) {\n\t\t\t\tsemiexpress.insert(i);\n\t\t\t\tsemiexpress.insert(j);\n\t\t\t\tfor (int k = 0; k <= stationnum; k++) {\n\t\t\t\t\tdps[k] = -1;\n\t\t\t\t}\n\t\t\t\tdp(stationnum);\n\t\t\t\tsemiexpress.erase(j);\n\t\t\t\tsemiexpress.erase(i);\n\t\t\t\tfor (int k = 2; k <= stationnum; k++) {\n\t\t\t\t\tif (dps[k] <= t)\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\tif (ans > maxans) {\n\t\t\t\t\tmaxans = ans;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout << maxans << '\\n';\n}", "accuracy": 0.08333333333333333, "time_ms": 130, "memory_kb": 3136, "score_of_the_acc": -0.5455, "final_rank": 18 }, { "submission_id": "aoj_0637_2865216", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <set>\nusing namespace std;\nlong long int stationnum, expressnum, semiexpressnum;\nlong long int localexptime, exptime, semiexptime;\nlong long int t;\nvector <long long int> mustvisit;\nset <long long int> semiexpress;\nlong long int dps[7001];\nbool hasloc(int loc) {\n\tint s = 0;\n\tint e = mustvisit.size() - 1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] > loc)\n\t\t\te = m - 1;\n\t\telse if (mustvisit[m] < loc)\n\t\t\ts = m + 1;\n\t\telse {\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\n/*int bet(int loc1, int loc2) {\n\tint jumps = 0;\n\tif (hasloc(loc1))\n\t\tjumps--;\n\tif (hasloc(loc2))\n\t\tjumps--;\n\t//cout << loc1 << ' ' << loc2 << ' ' << \"JUMPS \" << jumps << '\\n';\n\tint s = 0;\n\tint e = mustvisit.size() - 1;\n\tint lowrange = -1;\n\tint highrange = -1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] >= loc1) {\n\t\t\te = m - 1;\n\t\t\tlowrange = m;\n\t\t}\n\t\telse if (mustvisit[m] < loc1)\n\t\t\ts = m + 1;\n\t}\n\ts = 0;\n\te = mustvisit.size() - 1;\n\twhile (s <= e) {\n\t\tint m = (s + e) / 2;\n\t\tif (mustvisit[m] > loc2) {\n\t\t\te = m - 1;\n\t\t}\n\t\telse if (mustvisit[m] <= loc2) {\n\t\t\ts = m + 1;\n\t\t\thighrange = m;\n\t\t}\n\t}\n\t//cout << \"RANGE \" << loc1 << ' ' << loc2 << ' ' << lowrange << ' ' << highrange << '\\n';\n\treturn jumps + 1 + (highrange - lowrange + 1);\n}*/\nlong long int dp(int loc) {\n\tif (loc == 1)\n\t\treturn 0;\n\tif (dps[loc] == -1) {\n\t\tdps[loc] = dp(loc - 1) + localexptime;\n\t\tfor (int i = loc - 1; i > 0; i--) {\n\t\t\tif (hasloc(i) && hasloc(loc)) {\n\t\t\t\tdps[loc] = min(dp(i) + min(exptime, semiexptime) * (loc - i), dps[loc]);\n\t\t\t}\n\t\t\telse if ((semiexpress.find(i) != semiexpress.end() && semiexpress.find(loc) != semiexpress.end()) && semiexpressnum - expressnum >= 1) {\n\t\t\t\tdps[loc] = min(dp(i) + semiexptime * (loc - i), dps[loc]);\n\t\t\t}\n\t\t\t//cout << loc << ' ' << dps[loc] << '\\n';\n\t\t}\n\t}\n\treturn dps[loc];\n}\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tcout.tie(NULL);\n\tfor (int i = 0; i <= 300; i++) {\n\t\tdps[i] = -1;\n\t}\n\tcin >> stationnum >> expressnum >> semiexpressnum;\n\tcin >> localexptime >> exptime >> semiexptime;\n\tcin >> t;\n\tmustvisit.resize(expressnum);\n\tfor (int i = 0; i < expressnum; i++) {\n\t\tcin >> mustvisit[i];\n\t\tsemiexpress.insert(mustvisit[i]);\n\t}\t\n\tint maxans = 0;\n\tfor (int i = 1; i <= stationnum; i++) {\n\t\tfor (int j = i + 1; j <= stationnum; j++) {\n\t\t\tint ans = 0;\n\t\t\tif (!hasloc(i) && !hasloc(j)) {\n\t\t\t\tsemiexpress.insert(i);\n\t\t\t\tsemiexpress.insert(j);\n\t\t\t\tfor (int k = 0; k <= stationnum; k++) {\n\t\t\t\t\tdps[k] = -1;\n\t\t\t\t}\n\t\t\t\tdp(stationnum);\n\t\t\t\tsemiexpress.erase(j);\n\t\t\t\tsemiexpress.erase(i);\n\t\t\t\tfor (int i = 2; i <= stationnum; i++) {\n\t\t\t\t\tif (dps[i] <= t)\n\t\t\t\t\t\tans++;\n\t\t\t\t\t}\n\t\t\t\tmaxans = max(maxans, ans);\n\t\t\t}\n\t\t}\n\t}\n\tcout << maxans << '\\n';\n}", "accuracy": 0.08333333333333333, "time_ms": 130, "memory_kb": 3208, "score_of_the_acc": -0.5465, "final_rank": 19 }, { "submission_id": "aoj_0637_2865169", "code_snippet": "#include <iostream>\n#include <cassert>\n#include <queue>\n\ntypedef long long ll;\n\nll N, M, K;\nll A, B, C;\nll T;\n\nll S[3001];\nstd::priority_queue<int, std::vector<int>, std::greater<int> > pq;\n\nint main() {\n\tstd::ios_base::sync_with_stdio(false);\n\tstd::cin.tie(NULL);\n\tstd::cout.tie(NULL);\n\t\n\tstd::cin>>N>>M>>K;\n\tstd::cin>>A>>B>>C;\n\tstd::cin>>T;\n\t\n\tfor (int i = 0; i < M; ++i)\n\t\tstd::cin>>S[i];\n\t\n\tll ans = 0;\n\tfor (int i = 0; i < M-1; ++i) {\n\t\tll cur = B * (S[i] - 1);\n\t\tll n = S[i+1] - S[i];\n/*\t\tll step = std::min((T-cur)/A, n);\n\t\tans += step + 1;\n\t\tif (step == n)\n\t\t\tcontinue;\n*/\t\t\n\t\tint iter = 0;\n\t\twhile (n > 0 and cur <= T and iter <= 5000) {\n\t\t\tll step = std::min((T-cur)/A, n-1);\n\t\t\t\n\t\t\tif (iter == 0) {\n\t\t\t\tans += 1+step;\n\t\t\t} else {\n\t\t\t\tpq.push(1+step);\n\t\t\t\tif (pq.size() > K - M)\n\t\t\t\t\tpq.pop();\n\t\t\t}\n\t\t\tcur += C*(step+1);\n\t\t\tn -= step+1;\n\t\t\t\n\t\t\titer++;\n\t\t}\n\t}\n\tif (B*(S[M-1]-1) <= T)\n\t\tans++;\n\t\n\twhile (!pq.empty()) {\n\t\tans += pq.top();\n\t\tpq.pop();\n\t}\n\t\n\tstd::cout<<ans-1<<\"\\n\";\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 3168, "score_of_the_acc": -0.455, "final_rank": 13 }, { "submission_id": "aoj_0637_2736917", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define rep(i,n) FOR(i,0,n)\n#define pb emplace_back\ntypedef long long ll;\ntypedef pair<int,int> pint;\n\nll s[3001];\nvector<ll> v;\nint main(){\n ll n,m,k,a,b,c,t;\n cin>>n>>m>>k;\n cin>>a>>b>>c>>t;\n rep(i,m){\n cin>>s[i];\n --s[i];\n }\n int r=k-m;\n ll ans=(s[m-1]*b<=t)?1:0;\n rep(i,m-1){\n ll cur=b*s[i];\n if(cur>t) break;\n ll cnt=(t-cur)/a+1;\n ans+=min(s[i+1]-s[i],cnt);\n cur+=(cnt)*c;\n if(cur>t) continue;\n rep(j,r){\n ll cnt2=(t-cur)/a+1;\n ll ss=min(s[i]+cnt+cnt2,s[i+1])-min(s[i]+cnt,s[i+1]);\n v.pb(ss);\n cur+=(cnt2)*c;cnt+=cnt2;\n if(cur>t) break;\n }\n }\n sort(v.rbegin(),v.rend());\n int cnt=0;\n for(auto it:v){\n if(cnt==k-m) break;\n ans+=it;++cnt;\n }\n cout<<ans-1<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 19324, "score_of_the_acc": -0.3197, "final_rank": 12 }, { "submission_id": "aoj_0637_2703207", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <functional>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\n \nll N,M,K,L,A,B,C,T;\nll esta[3010];//急行駅の番号\n \n \nvector<ll> vec;\n \ninline ll updiv(ll a,ll b){\n\treturn a%b ? a/b+1 : a/b;\n}\n \nint main(){\n\tcin>>N>>M>>K>>A>>B>>C>>T;\n \n\tfor(int i=1;i<=M;i++) cin>>esta[i];\n \n\tL=K-M;\n\tll res=0;\n\tfor(int i=2;i<=M;i++){\n\t\tif(B*(esta[i]-1)>T) break;\n\t\tres++;\n\t}\n \n\tfor(int i=1;i<M;i++){\n\t\tll now_t=(esta[i]-1)*B;\n\t\tll now_n=esta[i];\n\t\tif(now_t>T) break;\n\t\tll cango=(T-now_t)/A;\n\t\tif(now_n+cango>=esta[i+1]-1){\n\t\t\tres+=(esta[i+1]-esta[i]-1);\n\t\t\tcontinue;\n\t\t}\n\t\tres+=cango;\n \n\t\tfor(int j=1;j<=3010;j++){\n\t\t\tif(cango==0&&(T-now_t)<C) break;\n\t\t\tnow_t+=C*(cango+1);\n\t\t\tnow_n+=cango+1;\n\t\t\tif(now_t>T) break;\n\t\t\tcango=(T-now_t)/A;\n\t\t\tif(now_n+cango>=esta[i+1]-1){\n\t\t\t\tvec.push_back(esta[i+1]-now_n);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tvec.push_back(cango+1);\n\t\t}\n\t}\n\tsort(vec.begin(),vec.end(),greater<ll>());\n \n\tL=min(L,(ll)vec.size());\n\tfor(int i=0;i<L;i++){\n\t\tres+=vec[i];\n\t}\n\tcout<<res<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 68576, "score_of_the_acc": -1.5158, "final_rank": 17 }, { "submission_id": "aoj_0637_2662093", "code_snippet": "#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <cstring>\n\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n\n#include <functional>\n#include <cassert>\n\ntypedef long long ll;\nusing namespace std;\n\n#define debug(x) cerr << #x << \" = \" << x << endl;\n\n\n#define mod 1000000007 //1e9+7(prime number)\n#define INF 1000000000 //1e9\n#define LLINF 2000000000000000000LL //2e18\n#define SIZE 3010\n\nint a,b,c;\nll t;\n\nvoid calc(int n, int m, ll st_time, int *v){\n ll cc = 0;\n \n int l = 0;\n \n for(int i=0;i<=m && i<=n-1;i++){\n ll sum = st_time + (ll)c*l;\n\n if(sum <= t){\n cc++;\n }else{\n break;\n }\n \n ll cc2 = (t - sum)/a;\n\n cc = min(cc + cc2, (ll)n);\n\n l = cc;\n \n v[i] = cc;\n }\n \n}\n\nint dp[SIZE];\nint v[SIZE][SIZE] = {};\n\nint main(){\n int n,m,k;\n int s[SIZE];\n \n scanf(\"%d%d%d\",&n,&m,&k);\n \n scanf(\"%d%d%d%lld\",&a,&b,&c,&t);\n\n for(int i=0;i<m;i++){\n scanf(\"%d\",s+i);\n s[i]--;\n }\n\n for(int i=0;i<=k;i++){\n dp[i] = -INF-10;\n }\n \n dp[m] = 0;\n \n int ans = 0;\n\n priority_queue<pair<int,pair<int,int> > > pq;\n \n for(int i=0;i<m-1;i++){\n\n calc(s[i+1]-s[i], k-m, (ll)b*s[i], v[i]);\n \n pq.push({v[i][1]-v[i][0],{i,1}});\n ans += v[i][0];\n }\n \n for(int i=m;i<k;i++){\n if(pq.top().first < 0) break;\n \n ans += pq.top().first;\n\n int p = pq.top().second.first;\n int q = pq.top().second.second;\n\n pq.pop();\n \n pq.push({v[p][q+1]-v[p][q],{p,q+1}});\n }\n\n if((ll)(n-1)*b <= t) ans++;\n\n printf(\"%d\\n\",ans-1);\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 14100, "score_of_the_acc": -0.155, "final_rank": 9 }, { "submission_id": "aoj_0637_2648476", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <functional>\nusing namespace std;\nlong long A, B, C, N, M, K, T, E[4009], U = 0; vector<long long>V;\nint main() {\n\tcin >> N >> M >> K >> A >> B >> C >> T;\n\tfor (int i = 1; i <= M; i++) cin >> E[i];\n\tfor (int i = 1; i < M; i++) {\n\t\tlong long rem = T - (E[i] - 1) * B, cx = E[i], cnt = 0; if (rem < 0)continue;\n\t\twhile (true) {\n\t\t\tlong long D = rem / A + 1, F = cx + D; F = min(F, E[i + 1]); D = F - cx;\n\t\t\tif (cnt >= 1)V.push_back(D); else U += D;\n\t\t\trem -= D*C; cx += D; if (cx >= E[i + 1] || D == 0 || rem < 0LL || cnt > K - M)break; cnt++;\n\t\t}\n\t}\n\tif ((N - 1)*B <= T)U++;\n\tsort(V.begin(), V.end(), greater<long long>());\n\tfor (int i = 0; i < min((long long)V.size(), K - M); i++)U += V[i];\n\tcout << U - 1 << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6960, "score_of_the_acc": -0.054, "final_rank": 3 } ]
aoj_0640_cpp
Rope JOI is a baby playing with a rope. The rope has length $N$, and it is placed as a straight line from left to right. The rope consists of $N$ cords. The cords are connected as a straight line. Each cord has length 1 and thickness 1. In total, $M$ colors are used for the rope. The color of the $i$-th cord from left is $C_i$ ($1 \leq C_i \leq M$). JOI is making the rope shorter. JOI repeats the following procedure until the length of the rope becomes 2. Let $L$ be the length of the rope. Choose an integer $j$ ($1 \leq j < L$). Shorten the rope by combining cords so that the point of length $j$ from left on the rope becomes the leftmost point. More precisely, do the following: If $j \leq L/2$, for each $i$ ($1 \leq i \leq j$), combine the $i$-th cord from left with the ($2j - i + 1$)-th cord from left. By this procedure, the rightmost point of the rope becomes the rightmost point. The length of the rope becomes $L - j$. If $j > L/2$, for each $i$ ($2j - L + 1 \leq i \leq j$), combine the $i$-th cord from left with the ($2j - i + 1$)-th cord from left. By this procedure, the leftmost point of the rope becomes the rightmost point. The length of the rope becomes $j$. If a cord is combined with another cord, the colors of the two cords must be the same. We can change the color of a cord before it is combined with another cord. The cost to change the color of a cord is equal to the thickness of it. After adjusting the colors of two cords, they are combined into a single cord; its thickness is equal to the sum of thicknesses of the two cords. JOI wants to minimize the total cost of procedures to shorten the rope until it becomes length 2. For each color, JOI wants to calculate the minimum total cost of procedures to shorten the rope so that the final rope of length 2 contains a cord with that color. Your task is to solve this problem instead of JOI. Task Given the colors of the cords in the initial rope, write a program which calculates, for each color, the minimum total cost of procedures to shorten the rope so that the final rope of length 2 contains a cord with that color. Input Read the following data from the standard input. The first line of input contains two space separated integers $N$, $M$. This means the rope consists of $N$ cords, and $M$ colors are used for the cords. The second line contains $N$ space separated integers $C_1, C_2, ... ,C_N$. This means the color of the $i$-th cord from left is $C_i$ ($1 \leq C_i \leq M$). Output Write $M$ lines to the standard output. The $c$-th line ($1 \leq c \leq M$) contains the minimum total cost of procedures to shorten the rope so that the final rope of length 2 contains a cord with color $c$. Constraints All input data satisfy the following conditions. $ 2 \leq N \leq 1 000 000. $ $ 1 \leq M \leq N.$ $ 1 \leq C_i \leq M (1 \leq i \leq N).$ For each $c$ with $1 \leq c \leq M$, there exists an integer $i$ with $C_i = c$. Sample Input and Output Sample Input 1 5 3 1 2 3 3 2 Sample Output 1 2 1 1 ...(truncated)
[ { "submission_id": "aoj_0640_9477411", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\n#define NUM 1000005\n\nint W, M;\nint input[NUM];\nint number[NUM];\nint BIT[NUM], ans[NUM];\nvector<int> V[NUM];\nint N;\nint table[6 * NUM];\n\nvoid init(int first_N) {\n N = 1;\n while (N < first_N) N *= 2;\n}\n\nvoid update(int loc, int value) {\n loc += N - 1;\n table[loc] += value;\n\n while (loc > 0) {\n loc = (loc - 1) / 2;\n table[loc] = max(table[2 * loc + 1], table[2 * loc + 2]);\n }\n}\n\nint query(int search_left, int search_right, int node_id, int node_left, int node_right) {\n if (search_right < node_left || search_left > node_right) return -BIG_NUM;\n if (search_left <= node_left && search_right >= node_right) {\n return table[node_id];\n }\n int mid = (node_left + node_right) / 2;\n int left_max = query(search_left, search_right, 2 * node_id + 1, node_left, mid);\n int right_max = query(search_left, search_right, 2 * node_id + 2, mid + 1, node_right);\n return max(left_max, right_max);\n}\n\nint main() {\n scanf(\"%d %d\", &W, &M);\n\n if (M == 1) {\n printf(\"0\\n\");\n return 0;\n }\n\n fill(number, number + M, 0);\n fill(ans, ans + M, BIG_NUM);\n\n for (int i = 0; i < W; i++) {\n scanf(\"%d\", &input[i]);\n input[i]--;\n number[input[i]]++;\n }\n\n init(M);\n\n for (int start = 0; start <= 1; start++) {\n for (int i = start; i + 1 <= W - 1; i += 2) {\n V[input[i]].push_back(input[i + 1]);\n V[input[i + 1]].push_back(input[i]);\n }\n\n fill(table, table + 2 * N - 1, 0);\n for (int i = 0; i < M; i++) {\n update(i, number[i]);\n }\n\n for (int i = 0; i < M; i++) {\n for (int k : V[i]) {\n update(k, -1);\n }\n int tmp = max(query(0, i - 1, 0, 0, N - 1), query(i + 1, M - 1, 0, 0, N - 1));\n ans[i] = min(ans[i], W - (number[i] + tmp));\n for (int k : V[i]) {\n update(k, 1);\n }\n }\n\n for (int i = 0; i < M; i++) {\n V[i].clear();\n }\n }\n\n for (int i = 0; i < M; i++) {\n printf(\"%d\\n\", ans[i]);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 82952, "score_of_the_acc": -0.8496, "final_rank": 3 }, { "submission_id": "aoj_0640_8287965", "code_snippet": "#include <iostream>\n#include <map>\n#include <queue>\n#include <tuple>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\nclass RangeMax {\npublic:\n\tint size_;\n\tvector<int> dat;\n\n\tvoid init(int sz) {\n\t\tsize_ = 1;\n\t\twhile (size_ <= sz) size_ *= 2;\n\t\tdat.resize(size_ * 2, 0);\n\t}\n\n\tvoid update(int pos, int x) {\n\t\tpos += size_;\n\t\tdat[pos] = x;\n\t\twhile (pos >= 2) {\n\t\t\tpos >>= 1;\n\t\t\tdat[pos] = max(dat[pos * 2], dat[pos * 2 + 1]);\n\t\t}\n\t}\n\n\tint query_(int l, int r, int a, int b, int u) {\n\t\tif (l <= a && b <= r) return dat[u];\n\t\tif (r <= a || b <= l) return 0;\n\t\tint v1 = query_(l, r, a, (a + b) / 2, u * 2);\n\t\tint v2 = query_(l, r, (a + b) / 2, b, u * 2 + 1);\n\t\treturn max(v1, v2);\n\t}\n\n\tint query(int l, int r) {\n\t\treturn query_(l, r, 0, size_, 1);\n\t}\n};\n\nint N, C[1000009];\nint M;\nint A[1000009];\nvector<int> G[1000009];\nmap<pair<int, int>, int> Map;\n\nvector<int> solve(vector<int> V, vector<int> R) {\n\tMap.clear();\n\tfor (int i = 1; i <= M; i++) G[i].clear();\n\tfor (int i = 1; i <= M; i++) A[i] = 0;\n\tvector<int> Answer(M + 1, 0);\n\n\t// Init\n\tfor (int i : V) A[i] += 1;\n\tfor (int i : R) A[i] += 1;\n\tfor (int i = 0; i < V.size(); i += 2) {\n\t\tint pa = V[i], pb = V[i + 1]; if (pa > pb) swap(pa, pb);\n\t\tMap[make_pair(pa, pb)] += 1;\n\t\tG[pa].push_back(pb);\n\t\tG[pb].push_back(pa);\n\t}\n\tRangeMax Z; Z.init(M + 2);\n\tfor (int i = 1; i <= M; i++) Z.update(i, A[i]);\n\n\t// First Check\n\tfor (int i = 0; i < V.size(); i += 2) {\n\t\tint pa = V[i + 0];\n\t\tint pb = V[i + 1]; if (pa > pb) swap(pa, pb);\n\t\tint cost = A[pa] + A[pb] - Map[make_pair(pa, pb)];\n\t\tif (pa == pb) continue;\n\t\tAnswer[pa] = max(Answer[pa], cost);\n\t\tAnswer[pb] = max(Answer[pb], cost);\n\t}\n\n\t// Second Check\n\tfor (int i = 1; i <= M; i++) {\n\t\tfor (int j : G[i]) Z.update(j, -100000000);\n\t\tZ.update(i, -100000000);\n\t\tint ret = Z.query(1, M + 1);\n\t\tAnswer[i] = max(Answer[i], A[i] + ret);\n\t\tZ.update(i, A[i]);\n\t\tfor (int j : G[i]) Z.update(j, A[j]);\n\t}\n\treturn Answer;\n}\n\nint main() {\n\t// Step 1. Input\n\tcin >> N >> M;\n\tfor (int i = 1; i <= N; i++) cin >> C[i];\n\tif (M == 1) {\n\t\tcout << \"0\" << endl;\n\t\treturn 0;\n\t}\n\n\t// Step 2. Solve\n\tvector<int> V1, V2;\n\tvector<int> R1, R2;\n\tfor (int i = 1; i <= N - 1; i += 2) { V1.push_back(C[i]); V1.push_back(C[i + 1]); }\n\tfor (int i = 2; i <= N - 1; i += 2) { V2.push_back(C[i]); V2.push_back(C[i + 1]); }\n\tif (N % 2 == 0) { R2.push_back(C[1]); R2.push_back(C[N]); }\n\tif (N % 2 == 1) { R1.push_back(C[N]); R2.push_back(C[1]); }\n\tvector<int> Answer1 = solve(V1, R1);\n\tvector<int> Answer2 = solve(V2, R2);\n\n\t// Output\n\tfor (int i = 1; i <= M; i++) cout << N - max(Answer1[i], Answer2[i]) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2760, "memory_kb": 124396, "score_of_the_acc": -1.7764, "final_rank": 14 }, { "submission_id": "aoj_0640_6801007", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nstruct run {\n bool is_target;\n int L, R;\n int len() {\n return R - L;\n }\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n vector<int> c_orig(n), ans(m + 1, lim<int>::max());\n cin >> c_orig;\n auto get_cost = [&](vector<int> c, int target, bool use_left) {\n vector<run> runs;\n for(int i = 0; i < n; i++) {\n bool is_target = c[i] == target;\n if(runs.empty() or runs.back().is_target != is_target) {\n runs.push_back({is_target, i, i + 1});\n } else {\n runs.back().R++;\n }\n }\n int run_adjust_cost = 0;\n for(int i = 1; i + 1 < runs.size(); i++) {\n if(runs[i].len() % 2 == 1) {\n if(i == 1 and use_left) {\n runs[i - 1].R--;\n runs[i].L--;\n if(runs[i].is_target) {\n c[runs[i].L] = target;\n } else {\n c[runs[i].L + 1] = target;\n }\n } else if(runs[i].is_target) {\n c[runs[i].R] = target;\n runs[i].R++;\n runs[i + 1].L++;\n } else {\n runs[i].R--;\n runs[i + 1].L--;\n c[runs[i].R] = target;\n }\n run_adjust_cost++;\n }\n }\n map<int, int> counter;\n for(int x : c) {\n counter[x]++;\n }\n int max_nontarget = 0;\n for(auto [x, count] : counter) {\n if(x != target) {\n max_nontarget = max(max_nontarget, count);\n }\n }\n int nontarget_cost = n - counter[target] - max_nontarget;\n return run_adjust_cost + nontarget_cost;\n };\n for(int target = 1; target <= m; target++) {\n auto c = c_orig;\n auto c_rev = c_orig;\n reverse(c_rev.begin(), c_rev.end());\n cout << min({\n get_cost(c, target, false),\n get_cost(c_rev, target, false),\n get_cost(c, target, true),\n get_cost(c_rev, target, true),\n }) << endl;\n }\n return 0;\n}", "accuracy": 0.45588235294117646, "time_ms": 60, "memory_kb": 7036, "score_of_the_acc": -0.0213, "final_rank": 19 }, { "submission_id": "aoj_0640_6800985", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\ntemplate <typename T> using lim = numeric_limits<T>;\ntemplate <typename T> istream& operator>>(istream& is, vector<T>& a) { for(T& x : a) { is >> x; } return is; }\ntemplate <typename X, typename Y> istream& operator>>(istream& is, pair<X, Y>& p) { return is >> p.first >> p.second; }\nstruct run {\n bool is_target;\n int L, R;\n int len() {\n return R - L;\n }\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n vector<int> c_orig(n), ans(m + 1, lim<int>::max());\n cin >> c_orig;\n auto get_cost = [&](vector<int> c, int target, bool use_left) {\n vector<run> runs;\n for(int i = 0; i < n; i++) {\n bool is_target = c[i] == target;\n if(runs.empty() or runs.back().is_target != is_target) {\n runs.push_back({is_target, i, i + 1});\n } else {\n runs.back().R++;\n }\n }\n int run_adjust_cost = 0;\n for(int i = 1; i + 1 < runs.size(); i++) {\n if(runs[i].len() % 2 == 1) {\n if(i == 1 and runs[i].is_target and use_left) {\n runs[i - 1].R--;\n runs[i].L--;\n c[runs[i].L] = target;\n } else if(runs[i].is_target) {\n c[runs[i].R] = target;\n runs[i].R++;\n runs[i + 1].L++;\n } else {\n runs[i].R--;\n runs[i + 1].L--;\n c[runs[i].R] = target;\n }\n run_adjust_cost++;\n }\n }\n map<int, int> counter;\n for(int x : c) {\n counter[x]++;\n }\n int max_nontarget = 0;\n for(auto [x, count] : counter) {\n if(x != target) {\n max_nontarget = max(max_nontarget, count);\n }\n }\n int nontarget_cost = n - counter[target] - max_nontarget;\n return run_adjust_cost + nontarget_cost;\n };\n for(int target = 1; target <= m; target++) {\n auto c = c_orig;\n auto c_rev = c_orig;\n reverse(c_rev.begin(), c_rev.end());\n cout << min({\n get_cost(c, target, false),\n get_cost(c_rev, target, false),\n get_cost(c, target, true),\n get_cost(c_rev, target, true),\n }) << endl;\n }\n return 0;\n}", "accuracy": 0.45588235294117646, "time_ms": 60, "memory_kb": 6956, "score_of_the_acc": -0.0207, "final_rank": 18 }, { "submission_id": "aoj_0640_4413225", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <unordered_map>\n#include <random>\n#include <bitset>\n#include <queue>\n#include <functional>\n#include <set>\n#include <map>\n#include <vector>\n#include <chrono>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\n// mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\nint main() {\n#ifdef LBT\n freopen(\"test.in\", \"r\", stdin);\n int nol_cl = clock();\n#endif\n\n int N, M;\n scanf(\"%d%d\", &N, &M);\n vector<int> C(N), cnt(M);\n for (int i = 0; i < N; ++i) {\n scanf(\"%d\", &C[i]);\n ++cnt[--C[i]];\n }\n vector<vector<vector<int>>> G(2, vector<vector<int>>(M));\n vector<int> ans = cnt;\n for (int i = 1; i < N; ++i)\n if (C[i] != C[i - 1]) {\n G[i & 1][C[i]].push_back(C[i - 1]);\n G[i & 1][C[i - 1]].push_back(C[i]);\n }\n vector<vector<int>> adjAns(2, vector<int>(M));\n vector<int> ccnt(N + 1);\n for (int c : cnt) ++ccnt[c];\n int mx = *max_element(cnt.begin(), cnt.end());\n if (M > 1) {\n for (int t = 0; t <= 1; ++t) {\n for (int i = 0; i < M; ++i) {\n --ccnt[cnt[i]];\n for (int j : G[t][i]) {\n --ccnt[cnt[j]--];\n ++ccnt[cnt[j]];\n }\n\n // cerr << t << ' ' << i << \": \"; for (int k = 0; k <= N; ++k) cerr << ccnt[k] << ' '; cerr <<\n // '\\n';\n adjAns[t][i] = mx;\n while (!ccnt[adjAns[t][i]]) --adjAns[t][i];\n ++ccnt[cnt[i]];\n for (int j : G[t][i]) {\n --ccnt[cnt[j]++];\n ++ccnt[cnt[j]];\n }\n }\n }\n }\n for (int i = 1; i < N; ++i)\n if (C[i] != C[i - 1]) {\n ans[C[i]] = max(ans[C[i]], cnt[C[i]] + adjAns[!(i & 1)][C[i]]);\n ans[C[i - 1]] = max(ans[C[i - 1]], cnt[C[i - 1]] + adjAns[!(i & 1)][C[i - 1]]);\n }\n\n for (int i = 0; i < M; ++i) printf(\"%d\\n\", N - ans[i]);\n\n#ifdef LBT\n LOG(\"Time: %dms\\n\", int((clock() - nol_cl) / (double)CLOCKS_PER_SEC * 1000));\n#endif\n return 0;\n}", "accuracy": 1, "time_ms": 780, "memory_kb": 135488, "score_of_the_acc": -1.1768, "final_rank": 8 }, { "submission_id": "aoj_0640_3505326", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n \n \n#define NUM 1000005\n \nint W,M;\nint input[NUM];\nint number[NUM];\nint BIT[NUM],ans[NUM];\nvector<int> V[NUM];\n \nint N;\nint table[6*NUM];\n \nvoid init(int first_N){\n while(N < first_N)N *= 2;\n}\n \nvoid update(int loc,int value){\n loc += N-1;\n \n table[loc] += value;\n \n if(N == 1)return;\n \n int parent = (loc-1)/2;\n \n while(true){\n table[parent] = max(table[2*parent+1],table[2*parent+2]);\n \n if(parent == 0)break;\n else{\n parent = (parent-1)/2;\n }\n }\n}\n \nint query(int search_left,int search_right,int node_id,int node_left,int node_right){\n \n if(search_right < node_left || search_left > node_right)return -BIG_NUM;\n \n if(search_left <= node_left && search_right >= node_right){\n return table[node_id];\n }\n \n int left_max = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n int right_max = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n \n return max(left_max,right_max);\n}\n \nint main(){\n \n scanf(\"%d %d\",&W,&M);\n \n if(M == 1){\n \n printf(\"0\\n\");\n return 0;\n }\n \n for(int i = 0; i < M; i++){\n \n number[i] = 0;\n ans[i] = BIG_NUM;\n }\n \n for(int i = 0; i < W; i++){\n \n scanf(\"%d\",&input[i]);\n input[i]--;\n number[input[i]] += 1;\n }\n \n N = 1;\n init(M);\n \n int tmp;\n \n for(int start = 0; start <= 1; start++){\n \n for(int i = start; i+1 <= W-1; i += 2){\n \n V[input[i]].push_back(input[i+1]);\n V[input[i+1]].push_back(input[i]);\n }\n \n for(int i = 0; i <= 2*N-2; i++)table[i] = 0;\n \n for(int i = 0; i < M; i++){\n update(i,number[i]);\n }\n \n for(int i = 0; i < M; i++){\n \n for(int k = 0; k < V[i].size(); k++){\n \n update(V[i][k],-1);\n }\n tmp = max(query(0,i-1,0,0,N-1),query(i+1,M-1,0,0,N-1));\n \n ans[i] = min(ans[i],W-(number[i]+tmp));\n \n for(int k = 0; k < V[i].size(); k++){\n \n update(V[i][k],1);\n }\n }\n \n for(int i = 0; i < M; i++){\n V[i].clear();\n }\n }\n \n for(int i = 0; i < M; i++){\n \n printf(\"%d\\n\",ans[i]);\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 1550, "memory_kb": 77824, "score_of_the_acc": -1.0324, "final_rank": 4 }, { "submission_id": "aoj_0640_3343566", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<unordered_map>\n#include<stack>\n#include<queue>\n#include<iomanip>\n#include<math.h>\n#include<bitset>\n#include<cassert>\n#include<random>\n#include<time.h>\n#include<functional>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing pint=pair<int,int>;\nusing pll=pair<ll,ll>;\n#define MOD 1000000007LL\n#define INF 1000000000LL\n#define EPS 1e-10\n#define FOR(i,n,m) for(ll i=n;i<(ll)m;i++)\n#define REP(i,n) FOR(i,0,n)\n#define DUMP(a) REP(d,a.size()){cout<<a[d];if(d!=a.size()-1)cout<<\" \";else cout<<endl;}\n#define ALL(v) v.begin(),v.end()\n#define UNIQUE(v) sort(ALL(v));v.erase(unique(ALL(v)),v.end());\n#define pb push_back\n\ntemplate <typename T>\nclass SegTree {\nprivate:\n\tint n;\n\tconst function<T(T, T)> op;\n\tconst T ie;\n\tvector<T> seq;\n\npublic:\n\tSegTree(int _n, function<T(T, T)> op, const T ie) : op(op), ie(ie) {\n\t\tn = 1;\n\t\twhile(n < _n) n *= 2;\n\t\tseq.resize(2 * n - 1);\n\t\tfor(int i = 0; i < 2 * n - 1; i++) seq[i] = ie;\n\t}\n\n\tvoid update(int k, const T e) {\n\t\tk += n - 1;\n\t\tseq[k] = e;\n\t\twhile(k > 0) {\n\t\t\tk = (k - 1) / 2;\n\t\t\tseq[k] = op(seq[k * 2 + 1], seq[k * 2 + 2]);\n\t\t}\n\t}\n\n\tT get(int k) {\n\t\tk += n - 1;\n\t\treturn seq[k];\n\t}\n\n\tT query(int a, int b, int k = 0, int l = 0, int r = -1) {\n\t\tif(r == -1) r = n;\n\t\tif(r <= a || b <= l) return ie;\n\t\tif(a <= l && r <= b) return seq[k];\n\t\tT vl = query(a, b, k * 2 + 1, l, (l + r) / 2);\n\t\tT vr = query(a, b, k * 2 + 2, (l + r) / 2, r);\n\t\treturn op(vl, vr);\n\t}\n};\n\nint n, m;\nvector<int> c;\nvector<int> ans;\n\nvoid solve(int parity) {\n\tvector<vector<ll>> p(m);\n\tSegTree<int> rMq(m, [] (int a, int b) { return max(a, b); }, 0);\n\tREP(i, n) {\n\t\trMq.update(c[i], rMq.get(c[i]) + 1);\n\t\tp[c[i]].pb(c[i]);\n\t}\n\tfor(int i = parity; i < n - 1; i += 2) {\n\t\tif(c[i] == c[i + 1]) continue;\n\t\tp[c[i]].pb(c[i + 1]);\n\t\tp[c[i + 1]].pb(c[i]);\n\t}\n\tREP(i, m) {\n\t\tint tmp = n - rMq.get(i);\n\t\tREP(j, p[i].size()) rMq.update(p[i][j], rMq.get(p[i][j]) - 1);\n\t\ttmp -= rMq.query(0, m);\n\t\tREP(j, p[i].size()) rMq.update(p[i][j], rMq.get(p[i][j]) + 1);\n\t\tans[i] = min(ans[i], tmp);\n\t}\n\treturn;\n}\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcin >> n >> m;\n\tc.resize(n); ans.assign(m, INF);\n\tREP(i, n) cin >> c[i]; REP(i, n) c[i]--;\n\tsolve(0); solve(1);\n\tREP(i, m) cout << ans[i] << endl;\n\treturn 0;\n}\n\n/* --------------------------------------- */", "accuracy": 1, "time_ms": 2930, "memory_kb": 73460, "score_of_the_acc": -1.4742, "final_rank": 9 }, { "submission_id": "aoj_0640_3343565", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<unordered_map>\n#include<stack>\n#include<queue>\n#include<iomanip>\n#include<math.h>\n#include<bitset>\n#include<cassert>\n#include<random>\n#include<time.h>\n#include<functional>\nusing namespace std;\nusing ll=long long;\nusing ld=long double;\nusing pint=pair<int,int>;\nusing pll=pair<ll,ll>;\n#define MOD 1000000007LL\n#define INF 1000000000LL\n#define EPS 1e-10\n#define FOR(i,n,m) for(ll i=n;i<(ll)m;i++)\n#define REP(i,n) FOR(i,0,n)\n#define DUMP(a) REP(d,a.size()){cout<<a[d];if(d!=a.size()-1)cout<<\" \";else cout<<endl;}\n#define ALL(v) v.begin(),v.end()\n#define UNIQUE(v) sort(ALL(v));v.erase(unique(ALL(v)),v.end());\n#define pb push_back\n\nint n, m;\nvector<int> c;\nvector<int> ans;\n\nvoid solve(int parity) {\n\tvector<int> cnt1(m, 0);\n\tvector<int> cnt2(n + 1, 0);\n\tint maxi = -1;\n\tvector<vector<ll>> p(m);\n\tREP(i, n) {\n\t\tcnt1[c[i]]++;\n\t\tp[c[i]].pb(c[i]);\n\t}\n\tREP(i, m) {\n\t\tcnt2[cnt1[i]]++;\n\t\tmaxi = max(maxi, cnt1[i]);\n\t}\n\tfor(int i = parity; i < n - 1; i += 2) {\n\t\tif(c[i] == c[i + 1]) continue;\n\t\tp[c[i]].pb(c[i + 1]);\n\t\tp[c[i + 1]].pb(c[i]);\n\t}\n\tREP(i, m) {\n\t\tint tmp1 = n - cnt1[i];\n\t\tREP(j, p[i].size()) {\n\t\t\tcnt2[cnt1[p[i][j]]]--;\n\t\t\tcnt2[cnt1[p[i][j]] - 1]++;\n\t\t\tcnt1[p[i][j]]--;\n\t\t}\n\t\tint tmp2 = maxi;\n\t\twhile(cnt2[tmp2] == 0) tmp2--;\n\t\tans[i] = min(ans[i], tmp1 - tmp2);\n\t\tREP(j, p[i].size()) {\n\t\t\tcnt2[cnt1[p[i][j]]]--;\n\t\t\tcnt2[cnt1[p[i][j]] + 1]++;\n\t\t\tcnt1[p[i][j]]++;\n\t\t}\n\t}\n\treturn;\n}\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcin >> n >> m;\n\tc.resize(n); ans.assign(m, INF);\n\tREP(i, n) cin >> c[i]; REP(i, n) c[i]--;\n\tsolve(0); solve(1);\n\tREP(i, m) cout << ans[i] << endl;\n\treturn 0;\n}\n\n/* --------------------------------------- */", "accuracy": 1, "time_ms": 1940, "memory_kb": 73096, "score_of_the_acc": -1.1326, "final_rank": 7 }, { "submission_id": "aoj_0640_3318963", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 1000005\n\nint W,M;\nint input[NUM];\nint number[NUM];\nint BIT[NUM],ans[NUM];\nvector<int> V[NUM];\n\nint N;\nint table[6*NUM];\n\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(int loc,int value){\n\tloc += N-1;\n\n\ttable[loc] += value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[parent] = max(table[2*parent+1],table[2*parent+2]);\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\nint query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\tif(search_right < node_left || search_left > node_right)return -BIG_NUM;\n\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[node_id];\n\t}\n\n\tint left_max = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tint right_max = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\nint main(){\n\n\tscanf(\"%d %d\",&W,&M);\n\n\tif(M == 1){\n\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tnumber[i] = 0;\n\t\tans[i] = BIG_NUM;\n\t}\n\n\tfor(int i = 0; i < W; i++){\n\n\t\tscanf(\"%d\",&input[i]);\n\t\tinput[i]--;\n\t\tnumber[input[i]] += 1;\n\t}\n\n\tN = 1;\n\tinit(M);\n\n\tint tmp;\n\n\tfor(int start = 0; start <= 1; start++){\n\n\t\tfor(int i = start; i+1 <= W-1; i += 2){\n\n\t\t\tV[input[i]].push_back(input[i+1]);\n\t\t\tV[input[i+1]].push_back(input[i]);\n\t\t}\n\n\t\tfor(int i = 0; i <= 2*N-2; i++)table[i] = 0;\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tupdate(i,number[i]);\n\t\t}\n\n\t\tfor(int i = 0; i < M; i++){\n\n\t\t\tfor(int k = 0; k < V[i].size(); k++){\n\n\t\t\t\tupdate(V[i][k],-1);\n\t\t\t}\n\t\t\ttmp = max(query(0,i-1,0,0,N-1),query(i+1,M-1,0,0,N-1));\n\n\t\t\tans[i] = min(ans[i],W-(number[i]+tmp));\n\n\t\t\tfor(int k = 0; k < V[i].size(); k++){\n\n\t\t\t\tupdate(V[i][k],1);\n\t\t\t}\n\t\t}\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tV[i].clear();\n\t\t}\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tprintf(\"%d\\n\",ans[i]);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1570, "memory_kb": 77776, "score_of_the_acc": -1.039, "final_rank": 5 }, { "submission_id": "aoj_0640_3318962", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 99999999999999999\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define NUM 100005\n\nint W,M;\nint input[NUM];\nint number[NUM];\nint BIT[NUM],ans[NUM];\nvector<int> V[NUM];\n\nint N;\nint table[6*NUM];\n\nvoid init(int first_N){\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(int loc,int value){\n\tloc += N-1;\n\n\ttable[loc] += value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[parent] = max(table[2*parent+1],table[2*parent+2]);\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\nint query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\tif(search_right < node_left || search_left > node_right)return -BIG_NUM;\n\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[node_id];\n\t}\n\n\tint left_max = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tint right_max = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\nint main(){\n\n\tscanf(\"%d %d\",&W,&M);\n\n\tif(M == 1){\n\n\t\tprintf(\"0\\n\");\n\t\treturn 0;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tnumber[i] = 0;\n\t\tans[i] = BIG_NUM;\n\t}\n\n\tfor(int i = 0; i < W; i++){\n\n\t\tscanf(\"%d\",&input[i]);\n\t\tinput[i]--;\n\t\tnumber[input[i]] += 1;\n\t}\n\n\tN = 1;\n\tinit(M);\n\n\tint tmp;\n\n\tfor(int start = 0; start <= 1; start++){\n\n\t\tfor(int i = start; i+1 <= W-1; i += 2){\n\n\t\t\tV[input[i]].push_back(input[i+1]);\n\t\t\tV[input[i+1]].push_back(input[i]);\n\t\t}\n\n\t\tfor(int i = 0; i <= 2*N-2; i++)table[i] = 0;\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tupdate(i,number[i]);\n\t\t}\n\n\t\tfor(int i = 0; i < M; i++){\n\n\t\t\tfor(int k = 0; k < V[i].size(); k++){\n\n\t\t\t\tupdate(V[i][k],-1);\n\t\t\t}\n\t\t\ttmp = max(query(0,i-1,0,0,N-1),query(i+1,M-1,0,0,N-1));\n\n\t\t\tans[i] = min(ans[i],W-(number[i]+tmp));\n\n\t\t\tfor(int k = 0; k < V[i].size(); k++){\n\n\t\t\t\tupdate(V[i][k],1);\n\t\t\t}\n\t\t}\n\n\t\tfor(int i = 0; i < M; i++){\n\t\t\tV[i].clear();\n\t\t}\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tprintf(\"%d\\n\",ans[i]);\n\t}\n\n\treturn 0;\n}", "accuracy": 0.7352941176470589, "time_ms": 10, "memory_kb": 6448, "score_of_the_acc": 0, "final_rank": 17 }, { "submission_id": "aoj_0640_3090580", "code_snippet": "//22:04 1:03\n#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<queue>\n#define lol(i,n) for(int i=0;i<n;i++)\n#define mod 1000000007\ntypedef long long ll;\n\nusing namespace std;\n#define N (1<<20)\nll n,m,a[N],cnt[N];\nclass RMQ{\nprivate:\n ll dat[2*N];\n ll dfs(int l,int r,int a,int b,int k){\n\tif(l<=a&&b<=r)return dat[k];\n\tif(b<=l||r<=a)return 0;\n\tll vl=dfs(l,r,a,(a+b)/2,k*2+1);\n\tll vr=dfs(l,r,(a+b)/2,b,k*2+2);\n\treturn max(vl,vr);\n }\npublic:\n void Init(){\n\tlol(i,2*N)dat[i]=0;\n\tlol(i,m)Update(i,cnt[i]);\n }\n void Update(int i,ll x){\n\ti+=N-1;dat[i]=x;\n\twhile(i>0){\n\t i=(i-1)/2;\n\t dat[i]=max(dat[i*2+1],dat[i*2+2]);\n\t}\n }\n void Add(int i,ll x){\n\tUpdate(i,dat[i+N-1]+x);\n }\n ll Max(int l,int r){\n\treturn dfs(l,r+1,0,N,0);\n }\n};\nvector<ll> v[N];\nll ans[N];\nvoid Solve(){\n RMQ seg;seg.Init();\n lol(i,m){\n\tfor(auto x:v[i])seg.Add(x,-1);\n\tll res=0;\n\tres=max(res,seg.Max(0,i-1));\n\tres=max(res,seg.Max(i+1,m-1));\n\tans[i]=max(ans[i],res+cnt[i]);\n\tfor(auto x:v[i])seg.Add(x,1);\n }\n}\nint main(){\n cin>>n>>m;\n lol(i,m)cnt[i]=0,ans[i]=0;\n lol(i,n){scanf(\"%lld\",&a[i]);a[i]--;cnt[a[i]]++;}\n for(int i=0;i+1<n;i+=2){\n\tll x=i,y=i+1;\n\tv[a[x]].push_back(a[y]);\n\tv[a[y]].push_back(a[x]);\n }\n Solve();\n lol(i,m)v[i].clear();\n for(int i=1;i+1<n;i+=2){\n\tll x=i,y=i+1;\n\tv[a[x]].push_back(a[y]);\n\tv[a[y]].push_back(a[x]);\n }\n Solve();\n lol(i,m){\n\tans[i]=n-ans[i];\n\tprintf(\"%lld\\n\",ans[i]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 1310, "memory_kb": 98800, "score_of_the_acc": -1.0987, "final_rank": 6 }, { "submission_id": "aoj_0640_2866754", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 1'000'011;\nint dels[N], s[N], save[N], collec[N], n, m;\nvector<int> vals[N];\npair<int,int> pairs[N];\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) vals[c].clear();\n\n int ps = 0;\n for (int l = p, r = p + 1; r < n; l += 2, r += 2) {\n if (s[l] != s[r]) pairs[ps++] = {min(s[l], s[r]), max(s[l], s[r])};\n }\n\n sort(pairs, pairs + ps);\n for (int i = 0, j = 0, c1, c2; i < ps; i = j) {\n while (j < ps && pairs[i] == pairs[j]) j++;\n tie(c1, c2) = pairs[i];\n vals[c1].push_back(dels[c2]);\n vals[c2].push_back(dels[c1]);\n int curr = dels[c1] + dels[c2] - j + i;\n save[c1] = max(save[c1], curr);\n save[c2] = max(save[c2], curr);\n }\n\n for (int c = 0; c < m; c++) {\n vals[c].push_back(dels[c]);\n sort(vals[c].begin(), vals[c].end());\n int t = m;\n for (int u = vals[c].size() - 1; u >= 0 && collec[t] == vals[c][u]; u--) t--;\n save[c] = max(save[c], dels[c] + collec[t]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; dels[--s[i++]]++) scanf(\"%d\", &s[i]);\n for (int i = 0; i <= m; i++) collec[i] = dels[i];\n sort(collec, collec + m + 1);\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", n - save[i]);\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 77336, "score_of_the_acc": -0.6797, "final_rank": 1 }, { "submission_id": "aoj_0640_2866752", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 1'000'011;\nint dels[N], s[N], save[N], collec[N], n, m;\nvector<int> vals[N];\npair<int,int> pairs[N];\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) vals[c].clear();\n\n int ps = 0;\n for (int l = p, r = p + 1; r < n; l += 2, r += 2) {\n if (s[l] != s[r]) pairs[ps++] = {min(s[l], s[r]), max(s[l], s[r])};\n }\n\n sort(pairs, pairs + ps);\n for (int i = 0, j = 0, c1, c2; i < ps; i = j) {\n while (j < ps && pairs[i] == pairs[j]) j++;\n tie(c1, c2) = pairs[i];\n vals[c1].push_back(dels[c2]);\n vals[c2].push_back(dels[c1]);\n int curr = dels[c1] + dels[c2] - j + i;\n save[c1] = max(save[c1], curr);\n save[c2] = max(save[c2], curr);\n }\n\n for (int c1 = 0; c1 < m; c1++) {\n vals[c1].push_back(dels[c1]);\n sort(vals[c1].begin(), vals[c1].end());\n int t = m;\n for (int u = vals[c1].size() - 1; u >= 0 && collec[t] == vals[c1][u]; u--) t--;\n save[c1] = max(save[c1], dels[c1] + collec[t]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; dels[--s[i++]]++) scanf(\"%d\", &s[i]);\n for (int i = 0; i <= m; i++) collec[i] = dels[i];\n sort(collec, collec + m + 1);\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", n - save[i]);\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 77480, "score_of_the_acc": -0.6807, "final_rank": 2 }, { "submission_id": "aoj_0640_2866622", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 1'000'011;\nint dels[N], s[N], save[N];\nvector<int> partners[N];\nmultiset<int> collec;\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) partners[c].clear();\n\n map<pair<int,int>,int> pairs;\n for (int l = p, r = p + 1; r < n; l += 2, r += 2) {\n if (s[l] != s[r]) pairs[{min(s[l], s[r]), max(s[l], s[r])}]++;\n }\n\n for (auto it : pairs) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = dels[c1] + dels[c2] - it.second;\n save[c1] = max(save[c1], curr);\n save[c2] = max(save[c2], curr);\n }\n pairs.clear();\n\n for (int c1 = 0; c1 < m; c1++) {\n partners[c1].push_back(c1);\n for (int c2 : partners[c1]) collec.erase(collec.find(dels[c2]));\n save[c1] = max(save[c1], dels[c1] + *collec.rbegin());\n for (int c2 : partners[c1]) collec.insert(dels[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; dels[--s[i++]]++) scanf(\"%d\", &s[i]);\n collec = multiset<int>(dels, dels + m + 1);\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", n - save[i]);\n}", "accuracy": 1, "time_ms": 2470, "memory_kb": 147720, "score_of_the_acc": -1.8421, "final_rank": 16 }, { "submission_id": "aoj_0640_2866613", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 1'000'011;\nconst int INF = 1<<29;\nint dels[N], s[N], ans[N];\nvector<int> partners[N];\nmultiset<int> collec;\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) partners[c].clear();\n\n map<pair<int,int>,int> pairs;\n for (int l = p, r = p + 1; r < n; l += 2, r += 2) {\n if (s[l] != s[r]) pairs[{min(s[l], s[r]), max(s[l], s[r])}]++;\n }\n\n for (auto it : pairs) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = dels[c1] + dels[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n pairs.clear();\n\n for (int c1 = 0; c1 < m; c1++) {\n partners[c1].push_back(c1);\n for (int c2 : partners[c1]) collec.erase(collec.find(dels[c2]));\n ans[c1] = min(ans[c1], dels[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(dels[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int c = 0; c < m; c++) ans[c] = INF;\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n dels[--s[i]]--;\n }\n collec = multiset<int>(dels, dels + m + 1);\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", ans[i] + n);\n}", "accuracy": 1, "time_ms": 2380, "memory_kb": 147772, "score_of_the_acc": -1.8116, "final_rank": 15 }, { "submission_id": "aoj_0640_2866602", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 1'000'011;\nconst int INF = 1<<29;\nint dels[N], s[N], ans[N];\nvector<int> partners[N];\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) {\n dels[c] = 0;\n partners[c].clear();\n partners[c].push_back(c);\n }\n int gs = 1;\n for (int i = 1; i < n; i++) if (i % 2 == p) gs++;\n for (int i = 0; i < n; i++) dels[s[i]]--;\n\n map<pair<int,int>,int> pairs;\n for (int gi = 0; gi < gs; gi++) {\n int li = max(0, 2*gi - p), ri = min(n - 1, 2*gi - p + 1);\n if (s[li] != s[ri]) pairs[{min(s[li], s[ri]), max(s[li], s[ri])}]++;\n }\n\n for (auto it : pairs) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = dels[c1] + dels[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n pairs.clear();\n\n multiset<int> collec(dels, dels + m);\n collec.insert(0);\n for (int c1 = 0; c1 < m; c1++) {\n for (int c2 : partners[c1]) collec.erase(collec.find(dels[c2]));\n ans[c1] = min(ans[c1], dels[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(dels[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int c = 0; c < m; c++) ans[c] = INF;\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n s[i]--;\n }\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", ans[i] + n);\n}", "accuracy": 1, "time_ms": 2540, "memory_kb": 116432, "score_of_the_acc": -1.6447, "final_rank": 10 }, { "submission_id": "aoj_0640_2866592", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T>\ninline void sort_uniq(vector<T>& vec) {\n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n}\n\nconst int N = 1'000'011;\nconst int INF = 1<<29;\nint dels[N], s[N], ans[N];\nvector<int> partners[N];\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) {\n dels[c] = 0;\n partners[c].clear();\n partners[c].push_back(c);\n }\n int gs = 1;\n for (int i = 1; i < n; i++) if (i % 2 == p) gs++;\n for (int i = 0; i < n; i++) dels[s[i]]--;\n\n map<pair<int,int>,int> pairs;\n for (int gi = 0; gi < gs; gi++) {\n int li = max(0, 2*gi - p), ri = min(n - 1, 2*gi - p + 1);\n if (s[li] != s[ri]) pairs[{min(s[li], s[ri]), max(s[li], s[ri])}]++;\n }\n\n for (auto it : pairs) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = dels[c1] + dels[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n pairs.clear();\n\n multiset<int> collec(dels, dels + m);\n collec.insert(0);\n for (int c1 = 0; c1 < m; c1++) {\n sort_uniq(partners[c1]);\n for (int c2 : partners[c1]) collec.erase(collec.find(dels[c2]));\n ans[c1] = min(ans[c1], dels[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(dels[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int c = 0; c < m; c++) ans[c] = INF;\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n s[i]--;\n }\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", ans[i] + n);\n}", "accuracy": 1, "time_ms": 2620, "memory_kb": 116540, "score_of_the_acc": -1.6728, "final_rank": 12 }, { "submission_id": "aoj_0640_2866582", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T>\ninline void sort_uniq(vector<T>& vec) {\n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n}\n\nconst int N = 1'000'011;\nconst int INF = 1<<29;\nint coops[N], s[N], ans[N];\nvector<int> partners[N];\nbool appear[N];\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) {\n coops[c] = 0;\n partners[c].clear();\n partners[c].push_back(c);\n }\n int gs = 1;\n for (int i = 1; i < n; i++) if (i % 2 == p) gs++;\n\n map<pair<int,int>,int> fullgroups;\n for (int gi = 0; gi < gs; gi++) {\n int li = max(0, 2*gi - p), ri = min(n - 1, 2*gi - p + 1);\n coops[s[li]]--;\n if (li != ri) coops[s[ri]]--;\n if (s[li] != s[ri]) {\n fullgroups[{min(s[li], s[ri]), max(s[li], s[ri])}]++;\n }\n }\n\n for (auto it : fullgroups) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = coops[c1] + coops[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n fullgroups.clear();\n\n multiset<int> collec(coops, coops + m);\n for (int c1 = 0; c1 < m; c1++) {\n sort_uniq(partners[c1]);\n ans[c1] = min(ans[c1], coops[c1]);\n for (int c2 : partners[c1]) collec.erase(collec.find(coops[c2]));\n if (!collec.empty()) ans[c1] = min(ans[c1], coops[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(coops[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int c = 0; c < m; c++) ans[c] = INF;\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n s[i]--;\n }\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", ans[i] + n);\n}", "accuracy": 1, "time_ms": 2570, "memory_kb": 116512, "score_of_the_acc": -1.6555, "final_rank": 11 }, { "submission_id": "aoj_0640_2866581", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T>\ninline void sort_uniq(vector<T>& vec) {\n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n}\n\nconst int N = 1'000'011;\nconst int INF = 1<<29;\nint coops[N], s[N], ans[N];\nvector<int> partners[N];\nbool appear[N];\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) {\n coops[c] = 0;\n partners[c].clear();\n partners[c].push_back(c);\n }\n int gs = 1;\n for (int i = 1; i < n; i++) if (i % 2 == p) gs++;\n\n map<pair<int,int>,int> fullgroups;\n for (int gi = 0; gi < gs; gi++) {\n int li = max(0, 2*gi - p), ri = min(n - 1, 2*gi - p + 1);\n coops[s[li]]--;\n if (li != ri) coops[s[ri]]--;\n if (s[li] != s[ri]) {\n fullgroups[{min(s[li], s[ri]), max(s[li], s[ri])}]++;\n }\n }\n\n for (auto it : fullgroups) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = coops[c1] + coops[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n fullgroups.clear();\n\n multiset<int> collec(coops, coops + m);\n for (int c1 = 0; c1 < m; c1++) {\n sort_uniq(partners[c1]);\n for (int c2 : partners[c1]) collec.erase(collec.find(coops[c2]));\n if (!collec.empty()) ans[c1] = min(ans[c1], coops[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(coops[c2]);\n }\n}\n\nint main() {\n scanf(\"%d%d\", &n, &m);\n for (int c = 0; c < m; c++) ans[c] = INF;\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n s[i]--;\n }\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) printf(\"%d\\n\", ans[i] + n);\n}", "accuracy": 0.35294117647058826, "time_ms": 10, "memory_kb": 26708, "score_of_the_acc": -0.1434, "final_rank": 20 }, { "submission_id": "aoj_0640_2866560", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntemplate<class T>\ninline void sort_uniq(vector<T>& vec) {\n sort(vec.begin(), vec.end());\n vec.erase(unique(vec.begin(), vec.end()), vec.end());\n}\n\nconst int N = 1'000'011;\nconst int INF = 1<<29;\n\nint groupswith[N], coops[N];\nvector<int> partners[N];\nbool appear[N];\nint s[N], ans[N];\nint n, m;\n\nvoid optimize(int p) {\n for (int c = 0; c < m; c++) {\n groupswith[c] = coops[c] = 0;\n partners[c].clear();\n partners[c].push_back(c);\n }\n int gs = 1;\n for (int i = 1; i < n; i++) if (i % 2 == p) gs++;\n\n map<pair<int,int>,int> fullgroups;\n for (int gi = 0; gi < gs; gi++) {\n int li = max(0, 2*gi - p), ri = min(n - 1, 2*gi - p + 1);\n groupswith[s[li]]++;\n coops[s[li]]--;\n if (li != ri) coops[s[ri]]--;\n if (s[li] != s[ri]) {\n groupswith[s[ri]]++;\n fullgroups[{min(s[li], s[ri]), max(s[li], s[ri])}]++;\n }\n }\n\n int best0 = INF;\n for (int c = 0; c < m; c++) best0 = min(best0, coops[c] + (gs == groupswith[c]));\n for (int c = 0; c < m; c++) ans[c] = min(ans[c], min(coops[c], best0));\n\n for (auto it : fullgroups) {\n int c1, c2;\n tie(c1, c2) = it.first;\n partners[c1].push_back(c2);\n partners[c2].push_back(c1);\n int curr = coops[c1] + coops[c2] + it.second;\n ans[c1] = min(ans[c1], curr);\n ans[c2] = min(ans[c2], curr);\n }\n fullgroups.clear();\n\n multiset<int> collec(coops, coops + m);\n\n for (int c1 = 0; c1 < m; c1++) {\n if (!appear[c1]) continue;\n sort_uniq(partners[c1]);\n for (int c2 : partners[c1]) collec.erase(collec.find(coops[c2]));\n if (!collec.empty()) ans[c1] = min(ans[c1], coops[c1] + *collec.begin());\n for (int c2 : partners[c1]) collec.insert(coops[c2]);\n }\n}\n\nvoid solve() {\n if (scanf(\"%d%d\", &n, &m) != 2) exit(0);\n for (int c = 0; c < m; c++) {\n appear[c] = false;\n ans[c] = INF;\n }\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", &s[i]);\n appear[--s[i]] = true;\n }\n optimize(0);\n optimize(1);\n for (int i = 0; i < m; i++) {\n printf(\"%d\\n\", ans[i] + n);\n }\n}\n\nint main() {\n while (true) solve();\n}", "accuracy": 1, "time_ms": 2660, "memory_kb": 121424, "score_of_the_acc": -1.7211, "final_rank": 13 } ]
aoj_0638_cpp
Kingdom of JOIOI The Kingdom of JOIOI is a rectangular grid of $H \times W$ cells. In the Kingdom of JOIOI, in order to improve efficiency of administrative institutions, the country will be divided into two regions called "JOI" and "IOI." Since we do not want to divide it in a complicated way, the division must satisfy the following conditions: Each region must contain at least one cell. Each cell must belong to exactly one of two regions. For every pair of cells in the JOI region, we can travel from one to the other by passing through cells belonging to the JOI region only. When move from a cell to another cell, the two cells must share an edge. The same is true for the IOI region. For each row or column, if we take all the cells in that row or column, the cells belonging to each region must be connected. All the cells in a row or column may belong to the same region. Each cell has an integer called the altitude . After we divide the country into two regions, it is expected that traveling in each region will be active. But, if the difference of the altitudes of cells are large, traveling between them becomes hard. Therefore, we would like to minimize the maximum of the difference of the altitudes between cells belonging to the same region. In other words, we would like to minimize the larger value of the difference between the maximum and the minimum altitudes in the JOI region, and the difference between the maximum and the minimum altitudes in the IOI region. Task Given the altitudes of cells in the Kingdom of JOIOI, write a program which calculates the minimum of the larger value of the difference between the maximum and the minimum altitudes in the JOI region and the difference between the maximum and the minimum altitudes in the IOI region when we divide the country into two regions. Input Read the following data from the standard input. The first line of input contains two space separated integers $H$, $W$. This means the Kingdom of JOIOI is a rectangular grid of $H \times W$ cells. The $i$-th line ($1 \leq i \leq H$) of the following $H$ lines contains $W$ space separated integers $A_{i,1}, A_{i,2}, ..., A_{i,W}$. This means the cell in the $i$-th row from above and $j$-th column from left ($1 \leq j \leq W$) has altitude $A_{i,j}$. Output Write one line to the standard output. The output contains the minimum of the larger value of the difference between the maximum and the minimum altitudes in the JOI region and the difference between the maximum and the minimum altitudes in the IOI region when we divide the country into two regions. Constraints All input data satisfy the following conditions. $2 \leq H \leq 2 000.$ $2 \leq W \leq 2 000.$ $1 \leq A_{i, j} \leq 1 000 000 000 (1 \leq i \leq H, 1 \leq j \leq W).$ Sample Input and Output Sample Input 1 4 4 1 12 6 11 11 10 2 14 10 1 9 20 4 17 19 10 Sample Output 1 11 For example, in this sample input, we divide the country into two regions as follows. Here, ‘J’ denotes the JOI region, and ‘ ...(truncated)
[ { "submission_id": "aoj_0638_10852800", "code_snippet": "//new.cpp\n/*\nAuthor : Hocky Yudhiono\nSab 20 Apr 2019 03:27:38 WIB\nCurrent Local Time : 15:27:38\n\ngetchar_unlocked > getchar > cin without sync > scanf > cin with sync\nbool operator<(const MyStruct& rhs) const\n\nOn how to print Long Double to 5 decimal places :\nprintf(\"%.5Lf\",ans);\n\nOn how to get random numbers :\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //For int\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); //For LL\ncout << rng() << endl;\nshuffle(isi.begin(),isi.end(),rng);\n\n__gcd(a,b)\n__builtin_ffs(a) first on bit\n__builtin_clz(a) count leading zero\n__builtin_ctz(a) count trailing zero\n__builtin_popcount(a) numbers of on bits\n\n*/\n\n//#include <unordered_map>\n//#include <unordered_set>\n\n//#include <random>\n//#include <chrono>\n\n//#include <ext/pb_ds/assoc_container.hpp>\n//#include <ext/pb_ds/tree_policy.hpp>\n\n#include <algorithm>\n#include <iostream>\n#include <cstdlib>\n#include <cassert>\n#include <cstring>\n#include <iomanip>\n#include <cstdio>\n#include <limits>\n#include <string>\n#include <vector>\n#include <cmath>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n\n//using namespace __gnu_pbds;\nusing namespace std;\n\n#pragma comment(linker, \"/stack:200000000\")\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC optimize(3)\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#pragma GCC target(\"sse3\",\"sse2\",\"sse\")\n#pragma GCC target(\"avx\",\"sse4\",\"sse4.1\",\"sse4.2\",\"ssse3\")\n#pragma GCC target(\"f16c\")\n#pragma GCC optimize(\"inline\",\"fast-math\",\"unroll-loops\",\"no-stack-protector\")\n// #pragma GCC diagnostic error \"-fwhole-program\"\n// #pragma GCC diagnostic error \"-fcse-skip-blocks\"\n// #pragma GCC diagnostic error \"-funsafe-loop-optimizations\"\n// #pragma GCC diagnostic error \"-std=c++14\"\n// #pragma GCC target (\"string\"...)\n#pragma GCC push_options\n#pragma GCC pop_options\n#pragma GCC reset_options\n#pragma GCC optimize (\"O3\")\n\ntypedef long long LL;\ntypedef long double LD;\ntypedef unsigned long long ULL;\n// typedef tree<long long, null_type, less<long long>, rb_tree_tag, tree_order_statistics_node_update> pbds;\n//If the time limit is strict, try not to use long double\n\n\n#define fbo find_by_order\n#define ook order_of_key\n#define mp make_pair\n#define pb push_back\n#define pf push_front\n#define popb pop_back\n#define popf pop_front\n#define remove erase\n//Remember to undefine if the problem is interactive\n#define endl '\\n'\n#define DEBUG(X) cout << \">>> DEBUG(\" << __LINE__ << \") \" << #X << \" = \" << (X) << endl\n\nconst double eps = 1e-9;\nconst int INFMEM = 63;\nconst int INF = 1061109567;\nconst LL LINF = 4557430888798830399LL;\nconst double DINF = numeric_limits<double>::infinity();\nconst LL MOD = 1000000007;\nconst int dx[8] = {1,0,-1,0,1,1,-1,-1};\nconst int dy[8] = {0,1,0,-1,1,-1,1,-1};\nconst double PI = 3.141592653589793;\n\n#ifdef _WIN32\n#define getchar_unlocked getchar\n#endif\n#define GETCHAR getchar_unlocked\ninline void fastll(LL &input_number) \n{\n input_number = 0;\n int ch = GETCHAR();\n int sign = 1;\n while(ch < '0' || ch > '9'){\n if(ch == '-') sign=-1;\n ch = GETCHAR();\n }\n while(ch >= '0' && ch <= '9'){\n input_number = (input_number << 3)+(input_number << 1) + ch-'0';\n ch = GETCHAR();\n }\n input_number *= sign;\n}\n\ninline void open(string a){\n freopen((a+\".in\").c_str(),\"r\",stdin);\n freopen((a+\".out\").c_str(),\"w\",stdout);\n}\n\ninline void fasterios(){\n //Do not use if interactive\n ios_base::sync_with_stdio(0);\n cin.tie(0); cout.tie(0);\n}\n\nstruct dt{\n\tLL mini, maksi;\n\tbool operator==(const dt &other)const{\n\t\treturn (mini == other.mini && maksi == other.maksi);\n\t}\n};\ndt minmax(dt a, dt b){\n\tdt ret = {min(a.mini,b.mini),max(a.maksi,b.maksi)};\n\treturn ret;\n}\n\ndt awal;\nLL cur[2005];\nLL r,c,small,big;\nLL isi[2005][2005];\ndt pre[2005][2005];\ndt suf[2005][2005];\n\nvoid debug(){\n\tcout << \"|------------------------------------|\" << endl;\n\tcout << \"ISI ARRAY \" << endl;\n\tfor(int i = 1;i <= r;i++){\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tcout << isi[i][j] << \" \\n\"[j == c];\n\t\t}\n\t}\n\tcout << \"|------------------------------------|\" << endl;\n\tcout << \"|------------------------------------|\" << endl;\n\tcout << \"PRE ARRAY \" << endl;\n\tfor(int i = 1;i <= r;i++){\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tcout << pre[i][j].maksi << \" \\n\"[j == c];\n\t\t}\n\t}\n\tcout << \"|------------------------------------|\" << endl;\n\tcout << \"|------------------------------------|\" << endl;\n\tcout << \"SUF ARRAY \" << endl;\n\tfor(int i = 1;i <= r;i++){\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tcout << suf[i][j].maksi << \" \\n\"[j == c];\n\t\t}\n\t}\n\tcout << \"|------------------------------------|\" << endl;\n}\n\nint main(){\n\tfasterios();\n\tawal = {INF,-INF};\n\tcin >> r >> c;\n\tfor(int i = 0;i <= r+2;i++){\n\t\tfor(int j = 0;j <= c+2;j++){\n\t\t\tpre[i][j] = suf[i][j] = {INF,-INF};\n\t\t}\n\t}\n\tsmall = INF;\n\tfor(int i = 1;i <= r;i++){\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tcin >> isi[i][j];\n\t\t\tsmall = min(small,isi[i][j]);\n\t\t}\n\t}\n\tfor(int i = 1;i <= r;i++){\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tisi[i][j] -= small;\n\t\t\tbig = max(big,isi[i][j]);\n\t\t\tpre[i][j] = suf[i][j] = {isi[i][j],isi[i][j]};\n\t\t}\n\t}\n\tfor(int j = 1;j <= c;j++){\n\t\tfor(int i = r;i >= 1;i--){\n\t\t\tpre[i][j] = minmax(pre[i][j],pre[i+1][j]);\n\t\t}\n\t\tfor(int i = 1;i <= r;i++){\n\t\t\tsuf[i][j] = minmax(suf[i][j],suf[i-1][j]);\n\t\t}\n\t}\n\t// debug();\n\t//compute yang naik\n\tLL ans = big;\n\tLL kiri = 0;\n\tLL kanan = big;\n\twhile(kiri < kanan){\n\t\tLL mid = (kiri+kanan)>>1;\n\t\tbool isvalid = 0;\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tLL le = 1;\n\t\t\tLL ri = r+1;\n\t\t\twhile(le < ri){\n\t\t\t\tLL mi = (le+ri)>>1;\n\t\t\t\tif(pre[mi][j].maksi > mid) le = mi+1;\n\t\t\t\telse ri = mi;\n\t\t\t}\n\t\t\tif(pre[le][j].mini == 0) isvalid = 1;\n\t\t\tcur[j] = le;\n\t\t}\n\t\tdt atas = {INF,-INF};\n\t\tdt bawah = {INF,-INF};\n\t\tif(!isvalid) kiri = mid+1;\n\t\telse{\n\t\t\tif(cur[c] == r+1){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tLL curmaks = cur[c];\n\t\t\tfor(int j = c;j >= 1;j--){\n\t\t\t\tcur[j] = max(curmaks,cur[j]);\n\t\t\t\tcurmaks = cur[j];\n\t\t\t}\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tatas = minmax(suf[cur[j]-1][j],atas);\n\t\t\t\tbawah = minmax(pre[cur[j]][j],bawah);\n\t\t\t}\n\t\t\tif(atas == awal) atas = {0,0};\n\t\t\tif(bawah.maksi-bawah.mini > mid || atas.maksi-atas.mini > mid){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tkanan = mid;\n\t\t}\n\t}\n\tans = min(ans,kiri);\n\n\n\n\n\n\n\n\n\t//compute yang turun dari bawah\n\tkiri = 0; kanan = big;\n\twhile(kiri < kanan){\n\t\tLL mid = (kiri+kanan)>>1;\n\t\tbool isvalid = 0;\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tLL le = 1;\n\t\t\tLL ri = r+1;\n\t\t\twhile(le < ri){\n\t\t\t\tLL mi = (le+ri)>>1;\n\t\t\t\tif(pre[mi][j].maksi > mid) le = mi+1;\n\t\t\t\telse ri = mi;\n\t\t\t}\n\t\t\tif(pre[le][j].mini == 0) isvalid = 1;\n\t\t\tcur[j] = le;\n\t\t}\n\t\tdt atas = {INF,-INF};\n\t\tdt bawah = {INF,-INF};\n\t\tif(!isvalid) kiri = mid+1;\n\t\telse{\n\t\t\tif(cur[1] == r+1){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tLL curmaks = cur[1];\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tcur[j] = max(curmaks,cur[j]);\n\t\t\t\tcurmaks = cur[j];\n\t\t\t}\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tatas = minmax(suf[cur[j]-1][j],atas);\n\t\t\t\tbawah = minmax(pre[cur[j]][j],bawah);\n\t\t\t}\n\t\t\tif(atas == awal) atas = {0,0};\n\t\t\tif(bawah.maksi-bawah.mini > mid || atas.maksi-atas.mini > mid){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tkanan = mid;\n\t\t}\n\t}\n\tans = min(ans,kiri);\n\n\n\n\n\n\n\n\n\n\n\n\tkiri = 0; kanan = big;\n\t//Compute yang naik dari atas\n\twhile(kiri < kanan){\n\t\tLL mid = (kiri+kanan)>>1;\n\t\t// cerr << \"Computing \" << mid << endl;\n\t\tbool isvalid = 0;\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tLL le = 0;\n\t\t\tLL ri = r;\n\t\t\twhile(le < ri){\n\t\t\t\tLL mi = (le+ri+1)>>1;\n\t\t\t\tif(suf[mi][j].maksi > mid) ri = mi-1;\n\t\t\t\telse le = mi;\n\t\t\t}\n\t\t\tif(suf[le][j].mini == 0) isvalid = 1;\n\t\t\tcur[j] = le;\n\t\t}\n\t\tdt atas = {INF,-INF};\n\t\tdt bawah = {INF,-INF};\n\t\t// cerr << \"isvalid val \" << isvalid << endl;\n\t\tif(!isvalid) kiri = mid+1;\n\t\telse{\n\t\t\tif(cur[c] == 0){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tLL curmaks = cur[c];\n\t\t\tfor(int j = c;j >= 1;j--){\n\t\t\t\tcur[j] = min(curmaks,cur[j]);\n\t\t\t\tcurmaks = cur[j];\n\t\t\t}\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tatas = minmax(suf[cur[j]][j],atas);\n\t\t\t\tbawah = minmax(pre[cur[j]+1][j],bawah);\n\t\t\t}\n\t\t\tif(bawah == awal) bawah = {0,0};\n\t\t\tif(bawah.maksi-bawah.mini > mid || atas.maksi-atas.mini > mid){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tkanan = mid;\n\t\t}\n\t}\n\tans = min(ans,kiri);\n\n\n\n\n\n\n\n\t//compute yang turun dari atas\n\tkiri = 0; kanan = big;\n\twhile(kiri < kanan){\n\t\tLL mid = (kiri+kanan)>>1;\n\t\t// cerr << \"Computing \" << mid << endl;\n\t\tbool isvalid = 0;\n\t\tfor(int j = 1;j <= c;j++){\n\t\t\tLL le = 0;\n\t\t\tLL ri = r;\n\t\t\twhile(le < ri){\n\t\t\t\tLL mi = (le+ri+1)>>1;\n\t\t\t\tif(suf[mi][j].maksi > mid) ri = mi-1;\n\t\t\t\telse le = mi;\n\t\t\t}\n\t\t\tif(suf[le][j].mini == 0) isvalid = 1;\n\t\t\tcur[j] = le;\n\t\t}\n\t\tdt atas = {INF,-INF};\n\t\tdt bawah = {INF,-INF};\n\t\t// cout << isvalid << endl;\n\t\tif(!isvalid) kiri = mid+1;\n\t\telse{\n\t\t\tif(cur[1] == 0){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tLL curmaks = cur[1];\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tcur[j] = min(curmaks,cur[j]);\n\t\t\t\tcurmaks = cur[j];\n\t\t\t}\n\t\t\tfor(int j = 1;j <= c;j++){\n\t\t\t\tatas = minmax(suf[cur[j]][j],atas);\n\t\t\t\tbawah = minmax(pre[cur[j]+1][j],bawah);\n\t\t\t}\n\t\t\tif(bawah == awal) bawah = {0,0};\n\t\t\tif(bawah.maksi-bawah.mini > mid || atas.maksi-atas.mini > mid){\n\t\t\t\tkiri = mid+1;\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tkanan = mid;\n\t\t}\n\t}\n\tans = min(ans,kiri);\n\n\tcout << ans << endl;\n return 0;\t\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 160348, "score_of_the_acc": -0.8564, "final_rank": 11 }, { "submission_id": "aoj_0638_10783596", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define yoimiya int\nconst yoimiya nmax=2e3+163,inf=1e9,mod=1e9+7,MAX=4000000;\nyoimiya n,m,a[nmax][nmax],b[nmax][nmax],a_min=inf,a_max=-inf,mn[nmax][nmax],mx[nmax][nmax];\nvoid Rotate()\n{\n for (int i=1;i<=n;i++)\n for (int j=1;j<=m;j++)\n b[m-j+1][i]=a[i][j];\n swap(a,b); swap(n,m);\n}\nbool check(yoimiya val)\n{\n for (int turn=1;turn<=4;turn++)\n {\n bool able=true;\n for (int i=1;i<=n;i++)\n {\n mn[i][0]=inf; mx[i][m+1]=-inf;\n for (int j=1;j<=m;j++) mn[i][j]=min(mn[i][j-1],a[i][j]);\n for (int j=m;j>=1;j--) mx[i][j]=max(mx[i][j+1],a[i][j]);\n }\n yoimiya j=0;\n for (int i=1;i<=n;i++)\n {\n while ((j<=m) and ((a_max-mn[i][j]>val) or (mx[i][j+1]-a_min>val)))\n j++;\n if (j>m) {able=false; break;}\n }\n if (able) return true;\n Rotate();\n }\n return false;\n}\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(0); cout.tie(0);\n //freopen(\"yoimiya.INP\",\"r\",stdin);\n //freopen(\"yoimiya.OUT\",\"w\",stdout);\n cin>>n>>m;\n for (int i=1;i<=n;i++)\n {\n for (int j=1;j<=m;j++)\n {\n cin>>a[i][j];\n a_min=min(a_min,a[i][j]);\n a_max=max(a_max,a[i][j]);\n }\n }\n yoimiya d=0,c=1e9,ans=inf;\n while (d<=c)\n {\n yoimiya mid=(d+c)>>1;\n if (check(mid))\n {\n ans=mid;\n c=mid-1;\n }\n else d=mid+1;\n }\n cout<<ans<<'\\n';\n}", "accuracy": 1, "time_ms": 1380, "memory_kb": 76552, "score_of_the_acc": -0.6822, "final_rank": 9 }, { "submission_id": "aoj_0638_9477394", "code_snippet": "#include <cstdio>\n#include <algorithm>\n#include <climits>\nusing namespace std;\n\nconst int INF = 1012345678;\nint H, W, a[2009][2009], t[2009][2009], dp[2009][2009], pl[2009], pr[2009];\n\nint main() {\n scanf(\"%d %d\", &H, &W);\n int vl = INF, vr = -1;\n\n for (int i = 0; i < H; i++) {\n for (int j = 0; j < W; j++) {\n char c = getchar();\n while (c < '0' || '9' < c) c = getchar();\n while ('0' <= c && c <= '9') {\n a[i][j] = 10 * a[i][j] + c - '0';\n c = getchar();\n }\n vl = min(vl, a[i][j]);\n vr = max(vr, a[i][j]);\n }\n }\n\n int ret = INF;\n for (int i = 0; i < 4; i++) {\n pr[W] = 0;\n for (int j = 0; j < H; j++) {\n for (int k = 1; k <= W; k++) pl[k] = max(pl[k - 1], a[j][k - 1] - vl);\n for (int k = W - 1; k >= 0; k--) pr[k] = max(pr[k + 1], vr - a[j][k]);\n\n int curmin = INF;\n for (int k = 0; k <= W; k++) {\n curmin = min(curmin, dp[j][k]);\n dp[j + 1][k] = max({ curmin, pl[k], pr[k] });\n }\n }\n\n ret = min(ret, *min_element(dp[H], dp[H] + W + 1));\n\n for (int j = 0; j < H; j++) {\n for (int k = 0; k < W; k++) {\n t[k][H - j - 1] = a[j][k];\n }\n }\n swap(H, W);\n for (int j = 0; j < H; j++) {\n for (int k = 0; k < W; k++) {\n a[j][k] = t[j][k];\n }\n }\n }\n\n printf(\"%d\\n\", ret);\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 50200, "score_of_the_acc": -0.1804, "final_rank": 3 }, { "submission_id": "aoj_0638_9258895", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nll INF = 1e9+7;\nint h, w;\nll a[2020][2020], ma=0, mi=INF;\n\nbool ok(ll now){\n \n int wa[2020];\n memset(wa, -1, sizeof(wa));\n for(int i=0;i<h;i++){\n int cnt=0;\n for(int j=0;j<w;j++){\n if(cnt==0){\n if(mi+now<a[i][j] || i>0&&wa[i-1]==j){\n wa[i] = j;\n cnt++;\n }\n }\n if(cnt==1){\n if(ma-now>a[i][j]) return false;\n }\n }\n if(wa[i]==-1) wa[i] = w;\n }\n \n return true;\n}\n\nbool slv(ll now){\n \n if(ok(now)) return true;\n \n for(int i=0;i<h;i++){\n for(int j=0;j<w/2;j++) swap(a[i][j], a[i][w-1-j]);\n }\n if(ok(now)) return true;\n \n for(int i=0;i<h/2;i++){\n for(int j=0;j<w;j++) swap(a[i][j], a[h-1-i][j]);\n }\n if(ok(now)) return true;\n \n for(int i=0;i<h;i++){\n for(int j=0;j<w/2;j++) swap(a[i][j], a[i][w-1-j]);\n }\n if(ok(now)) return true;\n \n return false;\n}\n\nint main(){\n \n cin >> h >> w;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cin >> a[i][j];\n ma = max(ma, a[i][j]);\n mi = min(mi, a[i][j]);\n }\n }\n \n ll l=0, r=INF;\n while(l<r){\n ll mid = (l+r)/2;\n if(slv(mid)) r = mid;\n else l = mid+1;\n }\n \n cout << r << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 1490, "memory_kb": 34692, "score_of_the_acc": -0.4729, "final_rank": 8 }, { "submission_id": "aoj_0638_8351890", "code_snippet": "// #pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\", \"unroll-loops\")\n\n// #include <bits/extc++.h>\n// using namespace __gnu_pbds;\n\n#include <bits/stdc++.h>\nusing namespace std;\n\n#define int long long\n#define double long double\n// template <typename T>\n// using pbds_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\nusing pii = pair<int, int>;\ntemplate<typename T>\nusing prior = priority_queue<T, vector<T>, greater<T>>;\ntemplate<typename T>\nusing Prior = priority_queue<T>;\n\n#define X first\n#define Y second\n#define ALL(x) (x).begin(), (x).end()\n#define eb emplace_back\n#define pb push_back\n\n#define fastIO() ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define RANDOM() random_device __rd; \\\n mt19937 __gen = mt19937(__rd()); \\\n uniform_int_distribution<int> __dis(0, 1); \\\n auto rnd = bind(__dis, __gen);\n\nconst int INF = 1E9;\nconst int mod = 1E9 + 7;\n\nint32_t main() {\n fastIO();\n \n int h, w;\n cin >> h >> w;\n \n int _max = 0;\n vector<vector<int>> v(h, vector<int>(w));\n for (auto &x : v) for (auto &y : x) cin >> y, _max = max(_max, y);\n \n int lo = 0, hi = INF, mi, inMin, inMax;\n vector<int> heiL, heiR;\n while (lo < hi) {\n mi = lo + hi >> 1;\n \n heiL.clear(), heiR.clear();\n for (auto vec : v) {\n for (int i = 0; i < w; ++i) {\n if (vec[i] < _max - mi) {heiL.eb(i); break;}\n if (i == w-1) heiL.eb(w);\n }\n for (int i = w-1; i >= 0; --i) {\n if (vec[i] < _max - mi) {heiR.eb(i+1); break;}\n if (i == 0) heiR.eb(0);\n }\n }\n for (int i = 1; i < h; ++i) heiL[i] = min(heiL[i-1], heiL[i]);\n for (int i = 1; i < h; ++i) heiR[i] = max(heiR[i-1], heiR[i]);\n \n inMin = INF, inMax = 0;\n for (int i = 0; i < h; ++i) {\n for (int j = heiL[i]; j < w; ++j) inMax = max(inMax, v[i][j]), inMin = min(inMin, v[i][j]);\n }\n if (inMax - inMin <= mi) {hi = mi; continue;}\n \n inMin = INF, inMax = 0;\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < heiR[i]; ++j) inMax = max(inMax, v[i][j]), inMin = min(inMin, v[i][j]);\n }\n if (inMax - inMin <= mi) {hi = mi; continue;}\n \n heiL.clear(), heiR.clear();\n for (auto vec : v) {\n for (int i = 0; i < w; ++i) {\n if (vec[i] < _max - mi) {heiL.eb(i); break;}\n if (i == w-1) heiL.eb(w);\n }\n for (int i = w-1; i >= 0; --i) {\n if (vec[i] < _max - mi) {heiR.eb(i+1); break;}\n if (i == 0) heiR.eb(0);\n }\n }\n for (int i = h-2; i >= 0; --i) heiL[i] = min(heiL[i+1], heiL[i]);\n for (int i = h-2; i >= 0; --i) heiR[i] = max(heiR[i+1], heiR[i]);\n \n inMin = INF, inMax = 0;\n for (int i = 0; i < h; ++i) {\n for (int j = heiL[i]; j < w; ++j) inMax = max(inMax, v[i][j]), inMin = min(inMin, v[i][j]);\n }\n if (inMax - inMin <= mi) {hi = mi; continue;}\n \n inMin = INF, inMax = 0;\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < heiR[i]; ++j) inMax = max(inMax, v[i][j]), inMin = min(inMin, v[i][j]);\n }\n if (inMax - inMin <= mi) {hi = mi; continue;}\n \n lo = mi + 1;\n }\n \n cout << lo << \"\\n\";\n \n return 0;\n}", "accuracy": 1, "time_ms": 640, "memory_kb": 34848, "score_of_the_acc": -0.226, "final_rank": 4 }, { "submission_id": "aoj_0638_7529880", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\nusing namespace std;\n\ntypedef vector<int> vec;\ntypedef vector<vec> mat;\n\nint s_grid[2000][2000];\nint t_grid[2000][2000];\n\n\nbool is_ok(const mat& grid, int min_h, int max_h, int h) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\ts_grid[y][x] = 0;\n\t\t\tt_grid[y][x] = 0;\n\t\t}\n\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (grid[y][x] - min_h > h) {\n\t\t\t\ts_grid[y][x] = 1;\n\t\t\t}\n\t\t\tif (max_h - grid[y][x] > h) {\n\t\t\t\tt_grid[y][x] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (y + 1 < height) {\n\t\t\t\tt_grid[y + 1][x] |= t_grid[y][x];\n\t\t\t}\n\t\t\tif (x + 1 < width) {\n\t\t\t\tt_grid[y][x + 1] |= t_grid[y][x];\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = height - 1; y >= 0; y--) {\n\t\tfor (int x = width - 1; x >= 0; x--) {\n\t\t\tif (y - 1 >= 0) {\n\t\t\t\ts_grid[y - 1][x] |= s_grid[y][x];\n\t\t\t}\n\t\t\tif (x - 1 >= 0) {\n\t\t\t\ts_grid[y][x - 1] |= s_grid[y][x];\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++)\n\t\tfor (int x = 0; x < width; x++)\n\t\t\tif (s_grid[y][x] && t_grid[y][x]) {\n\t\t\t\treturn false;\n\t\t\t}\n\n\treturn true;\n}\n\nint solve(const mat& grid, int min_h, int max_h) {\n\tint left = 0;\n\tint right = max_h - min_h;\n\n\twhile (left < right) {\n\t\tint mid = (left + right) / 2;\n\t\tif (is_ok(grid, min_h, max_h, mid)) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid + 1;\n\t\t}\n\t}\n\treturn left;\n}\n\nvoid transform0(mat& grid) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\tmat r_grid(width, vec(height, 0));\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tr_grid[width - 1 - x][height - 1 - y] = grid[y][x];\n\t\t}\n\t}\n\tgrid = r_grid;\n\treturn;\n}\n\nvoid transform1(mat& grid) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width / 2; x++) {\n\t\t\tswap(grid[y][x], grid[y][width - 1 - x]);\n\t\t}\n\t}\n\treturn;\n}\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint height = -1;\n\tint width = -1;\n\tint min_h = numeric_limits<int>::max();\n\tint max_h = 0;\n\n\tcin >> height >> width;\n\n\tmat grid(height, vec(width, 0));\n\tfor (int i = 0; i < height; i++) {\n\t\tfor (int j = 0; j < width; j++) {\n\t\t\tcin >> grid[i][j];\n\t\t\tmin_h = min(min_h, grid[i][j]);\n\t\t\tmax_h = max(max_h, grid[i][j]);\n\t\t}\n\t}\n\n\tint result = numeric_limits<int>::max();\n\tfor (int i = 0; i < 2; i++) {\n\t\tfor (int j = 0; j < 2; j++) {\n\t\t\tresult = min(result, solve(grid, min_h, max_h));\n\t\t\tif (j == 0) {\n\t\t\t\ttransform0(grid);\n\t\t\t}\n\t\t}\n\t\tif (i == 0) {\n\t\t\ttransform1(grid);\n\t\t}\n\t}\n\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3460, "memory_kb": 81220, "score_of_the_acc": -1.3156, "final_rank": 15 }, { "submission_id": "aoj_0638_7529876", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\nusing namespace std;\n\ntypedef vector<int> vec;\ntypedef vector<vec> mat;\n\nint s_grid[2000][2000];\nint t_grid[2000][2000];\n\n\nbool is_ok(const mat& grid, int min_h, int max_h, int h) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\ts_grid[y][x] = 0;\n\t\t\tt_grid[y][x] = 0;\n\t\t}\n\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (abs(min_h - grid[y][x]) > h) {\n\t\t\t\ts_grid[y][x] = 1;\n\t\t\t}\n\t\t\tif (abs(max_h - grid[y][x]) > h) {\n\t\t\t\tt_grid[y][x] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (y + 1 < height) {\n\t\t\t\tt_grid[y + 1][x] |= t_grid[y][x];\n\t\t\t}\n\t\t\tif (x + 1 < width) {\n\t\t\t\tt_grid[y][x + 1] |= t_grid[y][x];\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = height - 1; y >= 0; y--) {\n\t\tfor (int x = width - 1; x >= 0; x--) {\n\t\t\tif (y - 1 >= 0) {\n\t\t\t\ts_grid[y - 1][x] |= s_grid[y][x];\n\t\t\t}\n\t\t\tif (x - 1 >= 0) {\n\t\t\t\ts_grid[y][x - 1] |= s_grid[y][x];\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++)\n\t\tfor (int x = 0; x < width; x++)\n\t\t\tif (s_grid[y][x] && t_grid[y][x]) {\n\t\t\t\treturn false;\n\t\t\t}\n\n\treturn true;\n}\n\nint solve(const mat& grid, int min_h, int max_h) {\n\tint left = 0;\n\tint right = max_h - min_h;\n\n\twhile (left < right) {\n\t\tint mid = (left + right) / 2;\n\t\tif (is_ok(grid, min_h, max_h, mid)) {\n\t\t\tright = mid;\n\t\t}\n\t\telse {\n\t\t\tleft = mid + 1;\n\t\t}\n\t}\n\treturn left;\n}\n\nvoid transform0(mat& grid) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\tmat r_grid(width, vec(height, 0));\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tr_grid[width - 1 - x][height - 1 - y] = grid[y][x];\n\t\t}\n\t}\n\tgrid = r_grid;\n\treturn;\n}\n\nvoid transform1(mat& grid) {\n\tint width = int(grid[0].size());\n\tint height = int(grid.size());\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width / 2; x++) {\n\t\t\tswap(grid[y][x], grid[y][width - 1 - x]);\n\t\t}\n\t}\n\treturn;\n}\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint height = -1;\n\tint width = -1;\n\tint min_h = numeric_limits<int>::max();\n\tint max_h = 0;\n\n\tcin >> height >> width;\n\n\tmat grid(height, vec(width, 0));\n\tfor (int i = 0; i < height; i++) {\n\t\tfor (int j = 0; j < width; j++) {\n\t\t\tcin >> grid[i][j];\n\t\t\tmin_h = min(min_h, grid[i][j]);\n\t\t\tmax_h = max(max_h, grid[i][j]);\n\t\t}\n\t}\n\n\tint result = numeric_limits<int>::max();\n\tfor (int i = 0; i < 2; i++) {\n\t\tfor (int j = 0; j < 2; j++) {\n\t\t\tresult = min(result, solve(grid, min_h, max_h));\n\t\t\tif (j == 0) {\n\t\t\t\ttransform0(grid);\n\t\t\t}\n\t\t}\n\t\tif (i == 0) {\n\t\t\ttransform1(grid);\n\t\t}\n\t}\n\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3610, "memory_kb": 81124, "score_of_the_acc": -1.3587, "final_rank": 19 }, { "submission_id": "aoj_0638_7529836", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <limits>\nusing namespace std;\n\n\ntypedef vector<int> vec;\ntypedef vector<vec> mat;\nint max_h = 0, min_h = 1e9;\n\nint s[2000][2000];\nint t[2000][2000];\n\nbool is_ok(const mat& grid, int h) {\n\tint height = grid.size();\n\tint width = grid[0].size();\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\ts[y][x] = 0;\n\t\t\tt[y][x] = 0;\n\t\t}\n\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (abs(min_h - grid[y][x]) > h) {\n\t\t\t\ts[y][x] = 1;\n\t\t\t}\n\t\t\tif (abs(max_h - grid[y][x]) > h) {\n\t\t\t\tt[y][x] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tif (y + 1 < height)t[y + 1][x] |= t[y][x];\n\t\t\tif (x + 1 < width)t[y][x + 1] |= t[y][x];\n\t\t}\n\t}\n\n\tfor (int y = height - 1; y >= 0; y--) {\n\t\tfor (int x = width - 1; x >= 0; x--) {\n\t\t\tif (y - 1 >= 0)s[y - 1][x] |= s[y][x];\n\t\t\tif (x - 1 >= 0)s[y][x - 1] |= s[y][x];\n\t\t}\n\t}\n\n\tfor (int y = 0; y < height; y++)\n\t\tfor (int x = 0; x < width; x++)\n\t\t\tif (s[y][x] && t[y][x])return false;\n\n\treturn true;\n}\n\nint solve(const mat& A) {\n\tint left = 0, right = 1e9, mid;\n\twhile (left < right) {\n\t\tmid = (left + right) / 2;\n\t\tif (is_ok(A, mid))right = mid;\n\t\telse left = mid + 1;\n\t}\n\treturn left;\n}\n\nvoid transform0(mat& grid) {\n\tint height = grid.size();\n\tint width = grid[0].size();\n\tmat r_grid(width, vec(height, 0));\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width; x++) {\n\t\t\tr_grid[width - 1 - x][height - 1 - y] = grid[y][x];\n\t\t}\n\t}\n\tgrid = r_grid;\n\treturn;\n}\n\nvoid transform1(mat& grid) {\n\tint height = grid.size();\n\tint width = grid[0].size();\n\tfor (int y = 0; y < height; y++) {\n\t\tfor (int x = 0; x < width / 2; x++) {\n\t\t\tswap(grid[y][x], grid[y][width - 1 - x]);\n\t\t}\n\t}\n\treturn;\n}\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint height = -1;\n\tint width = -1;\n\n\tcin >> height >> width;\n\n\tmat grid(height, vec(width, 0));\n\tfor (int i = 0; i < height; i++) {\n\t\tfor (int j = 0; j < width; j++) {\n\t\t\tcin >> grid[i][j];\n\t\t\tmax_h = max(max_h, grid[i][j]);\n\t\t\tmin_h = min(min_h, grid[i][j]);\n\t\t}\n\t}\n\n\tint result = numeric_limits<int>::max();\n\tfor (int i = 0; i < 2; i++) {\n\t\tfor (int j = 0; j < 2; j++) {\n\t\t\tresult = min(result, solve(grid));\n\t\t\tif (j == 0) {\n\t\t\t\ttransform0(grid);\n\t\t\t}\n\t\t}\n\t\tif (i == 0) {\n\t\t\ttransform1(grid);\n\t\t}\n\t}\n\n\tcout << result << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3500, "memory_kb": 81352, "score_of_the_acc": -1.328, "final_rank": 17 }, { "submission_id": "aoj_0638_7529809", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\nusing namespace std;\n\n\ntypedef vector<int> vec;\ntypedef vector<vec> mat;\nint maxm = 0, mini = 1e9;\n\nint s[2000][2000];\nint t[2000][2000];\n\nbool check(const mat& A, int M) {\n\tint H = A.size();\n\tint W = A[0].size();\n\tfor (int y = 0; y < H; y++) {\n\t\tfor (int x = 0; x < W; x++) {\n\t\t\ts[y][x] = 0;\n\t\t\tt[y][x] = 0;\n\t\t}\n\n\t}\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (abs(mini - A[i][j]) > M) {\n\t\t\t\ts[i][j] = 1;\n\t\t\t}\n\t\t\tif (abs(maxm - A[i][j]) > M) {\n\t\t\t\tt[i][j] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (i + 1 < H)t[i + 1][j] |= t[i][j];\n\t\t\tif (j + 1 < W)t[i][j + 1] |= t[i][j];\n\t\t}\n\t}\n\n\tfor (int i = H - 1; i >= 0; i--) {\n\t\tfor (int j = W - 1; j >= 0; j--) {\n\t\t\tif (i - 1 >= 0)s[i - 1][j] |= s[i][j];\n\t\t\tif (j - 1 >= 0)s[i][j - 1] |= s[i][j];\n\t\t}\n\t}\n\n\tfor (int i = 0; i < H; i++)\n\t\tfor (int j = 0; j < W; j++)\n\t\t\tif (s[i][j] && t[i][j])return false;\n\n\treturn true;\n}\n\nint solve(const mat& A) {\n\tint left = 0, right = 1e9, mid;\n\twhile (left < right) {\n\t\tmid = (left + right) / 2;\n\t\tif (check(A, mid))right = mid;\n\t\telse left = mid + 1;\n\t}\n\treturn left;\n}\n\nvoid f1(mat& A) {\n\tint H = A.size();\n\tint W = A[0].size();\n\tmat res(W, vec(H, 0));\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tres[W - 1 - j][H - 1 - i] = A[i][j];\n\t\t}\n\t}\n\tA = res;\n}\n\nvoid f2(mat& A) {\n\tint H = A.size();\n\tint W = A[0].size();\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W / 2; j++) {\n\t\t\tswap(A[i][j], A[i][W - 1 - j]);\n\t\t}\n\t}\n}\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint H, W;\n\tcin >> H >> W;\n\n\tmat A(H, vec(W, 0));\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t\tmaxm = max(maxm, A[i][j]);\n\t\t\tmini = min(mini, A[i][j]);\n\t\t}\n\t}\n\n\tint ans = 1e9;\n\tfor (int i = 0; i < 2; i++) {\n\t\tfor (int j = 0; j < 2; j++) {\n\t\t\tans = min(ans, solve(A));\n\t\t\tif (j == 0)f1(A);\n\t\t}\n\t\tif (i == 0)f2(A);\n\t}\n\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 3560, "memory_kb": 81180, "score_of_the_acc": -1.3445, "final_rank": 18 }, { "submission_id": "aoj_0638_7336595", "code_snippet": "/* [Author : Hoang Duy Vu] - THPT Chuyen Nguyen Du */\n//#pragma GCC optimize(\" unroll-loops\")\n//#pragma gcc optimize(\"Ofast\")\n//#pragma GCC optimization(\"Ofast\")\n//#pragma optimize(Ofast)\n#include <bits/stdc++.h>\n#define All(x) (x).begin(),(x).end()\n#define ll long long\n#define C make_pair\n#define fi first\n#define se second\n#define two second.first\n#define thr second.second\n#define TASK \"txt\"\nusing namespace std;\ntemplate<typename T> bool maximize(T &res, const T &val) {\n if (res < val) { res = val; return true; } return false; }\ntemplate<typename T> bool minimize(T &res, const T &val) {\n if (res > val) { res = val; return true; } return false; }\n\ntypedef pair<int,int> ii;\ntypedef pair<int,ii> iii;\nconst int LOG = 20;\nconst int INF = 1e9 + 7;\nconst ll LNF = 1e18 + 7;\nconst int mod = 1e9 + 7;\nconst int N = 2020;\n\nint f[N] , a[2][N][N];\nint n , m , maxt = 0 , mint = INF;\n\nvoid input()\n{\n cin >> n >> m;\n for (int i = 1 ; i <= n; i++)\n for (int j = 1 ; j <= m ; j++)\n {\n cin >> a[0][i][j];\n maximize(maxt,a[0][i][j]);\n minimize(mint,a[0][i][j]);\n }\n\n maxt -= mint;\n\n for (int i = 1 ; i <= n ; i++)\n for (int j = 1 ; j <= m ; j++)\n {\n a[0][i][j] -= mint;\n a[1][i][j] = maxt - a[0][i][j];\n }\n\n}\n\nbool case1(int h , int id)\n{\n memset(f,0,sizeof(f));\n f[0] = m;\n for (int i = 1 ; i <= n ; i++)\n {\n int index = f[i - 1];\n for (int j = 1 ; j <= f[i - 1] ; j++)\n if (a[id][i][j] > h)\n {\n index = j - 1;\n break;\n }\n\n for (int j = index + 1 ; j <= m ; j++)\n if (maxt - a[id][i][j] > h) return false;\n\n f[i] = index;\n }\n\n int tt = 0;\n for (int i = 1 ; i <= n ; i++) tt += f[i];\n\n if (tt == 0) return false;\n if (tt == n*m) if (maxt - a[id][n][m] > h) return false;\n\n return true;\n}\n\nbool case2(int h , int id)\n{\n memset(f,0,sizeof(f));\n f[n + 1] = m;\n for (int i = n ; i > 0 ; i--)\n {\n int index = f[i + 1];\n for (int j = 1 ; j <= f[i + 1] ; j++)\n if (a[id][i][j] > h)\n {\n index = j - 1;\n break;\n }\n\n for (int j = index + 1 ; j <= m ; j++)\n if (maxt - a[id][i][j] > h) return false;\n\n f[i] = index;\n\n // cout << f[i] << \" \";\n }\n\n int tt = 0;\n for (int i = 1 ; i <= n ; i++) tt += f[i];\n\n if (tt == 0) return false;\n if (tt == n*m) if (maxt - a[id][1][m] > h) return false;\n\n return true;\n}\n\nvoid solve()\n{\n int l = 0 , r = 1e9 , res = 1e9;\n\n while (l <= r)\n {\n int mid = (l + r) >> 1;\n if ((case1(mid,0)|case1(mid,1)|case2(mid,0)|case2(mid,1)) == 1) \n {\n res = mid;\n r = mid - 1;\n }\n else l = mid + 1;\n }\n\n cout << res << \"\\n\";\n}\n\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(NULL); cout.tie(NULL);\n if(fopen(TASK\".inp\", \"r\")){\n freopen(TASK\".inp\",\"r\",stdin);\n freopen(TASK\".out\",\"w\",stdout);\n }\n\n int tk;\n tk = 1;\n //cin >> tk;\n while (tk--)\n {\n input();\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 35116, "score_of_the_acc": -0.1226, "final_rank": 2 }, { "submission_id": "aoj_0638_7030277", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n int h, w, mx = 0, mn = 1 << 30;\n cin >> h >> w;\n vector<vector<int>> A(h, vector<int>(w));\n for(int y = 0; y < h; y++){\n for(int x = 0; x < w; x++){\n cin >> A[y][x];\n mx = max(mx, A[y][x]);\n mn = min(mn, A[y][x]);\n }\n }\n auto f = [&](int th){\n int p = 0;\n for(int y = 0; y < h; y++){\n for(int x = p; x < w; x++){\n if(A[y][x] > mn + th)p = x + 1;\n }\n for(int x = 0; x < p; x++){\n if(A[y][x] < mx - th)return false;\n }\n }\n return true;\n };\n auto Cswap = [&](){\n for(int y = 0; y < h; y++){\n for(int x = 0; 2 * x < w; x++){\n swap(A[y][x], A[y][w - 1 - x]);\n }\n }\n };\n auto Rswap = [&](){\n for(int x = 0; x < w; x++){\n for(int y = 0; 2 * y < h; y++){\n swap(A[y][x], A[h - 1 - y][x]);\n }\n }\n };\n auto search = [&](){\n int ng = -1, ok = 1 << 30;\n while(ng + 1 < ok){\n int mid = (ng + ok) / 2;\n if(f(mid))ok = mid;\n else ng = mid;\n }\n return ok;\n };\n int ans = 1 << 30;\n ans = min(ans, search());\n Cswap();\n ans = min(ans, search());\n Rswap();\n ans = min(ans, search());\n Cswap();\n ans = min(ans, search());\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 18908, "score_of_the_acc": -0.0525, "final_rank": 1 }, { "submission_id": "aoj_0638_6944929", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 2e3 + 5, oo = 1e9;\n\nint m, n, a[N][N], b[N][N], mx[N][N], mn[N][N], v_max, v_min;\n\nvoid rotate() {\n\tfor (int i = 1; i <= m; ++i)\n\t\tfor (int j = 1; j <= n; ++j)\n\t\t\tb[n - j + 1][i] = a[i][j];\n\tswap(a, b); swap(m, n);\n}\n\nbool check(int d) {\n\tfor (int t = 4; t--;) {\n\t\tfor (int i = 1; i <= m; ++i) \n\t\t\tmx[i][n + 1] = -oo,\n\t\t\tmn[i][0] = oo;\n\t\tfor (int i = 1; i <= m; ++i) {\n\t\t\tfor (int j = n; j >= 1; --j)\n\t\t\t\tmx[i][j] = max(mx[i][j + 1], a[i][j]);\n\t\t\tfor (int j = 1; j <= n; ++j)\n\t\t\t\tmn[i][j] = min(mn[i][j - 1], a[i][j]);\n\t\t}\n\t\tbool flag = 1; int j = 0;\n\t\tfor (int i = 1; i <= m; ++i) {\n\t\t\twhile (j <= n && (v_max - mn[i][j] > d || mx[i][j + 1] - v_min > d))\n\t\t\t\t++j;\n\t\t\tif (j > n) {\n\t\t\t\tflag = 0; break;\n\t\t\t}\n\t\t}\n\t\tif (flag) return 1;\n\t\trotate();\n\t}\n\treturn 0;\n}\n\nint main() {\n\tcin.tie(0)->sync_with_stdio(0);\n\tcin >> m >> n; v_max = -oo; v_min = oo; \n\t\n\tfor (int i = 1; i <= m; ++i)\n\t\tfor (int j = 1; j <= n; ++j)\n\t\t\tcin >> a[i][j], \n\t\t\tv_min = min(v_min, a[i][j]), \n\t\t\tv_max = max(v_max, a[i][j]);\n\t\n\tint lo = 0, hi = 1e9, res;\n\twhile (lo <= hi) {\n\t\tint mi = (lo + hi) / 2;\n\t\tif (check(mi)) res = mi, hi = mi - 1;\n\t\telse lo = mi + 1;\n\t}\n\tcout << res << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1590, "memory_kb": 66268, "score_of_the_acc": -0.6842, "final_rank": 10 }, { "submission_id": "aoj_0638_6291394", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1000000010;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll H, W; cin >> H >> W;\n vector<vector<ll>>A(2010, vector<ll>(2010)); input_arr(A, H, W);\n vector<vector<P>>J(2010, vector<P>(2010)), I(2010, vector<P>(2010));\n ll ans = INF;\n for (ll a = 0; a < 4; a++) {\n for (ll i = 0; i < W; i++) {\n J[0][i] = {A[0][i], A[0][i]};\n I[H - 1][i] = {A[H - 1][i], A[H - 1][i]};\n }\n // J, I について、first : MAX, second : min\n for (ll i = 1; i < H; i++) {\n for (ll j = 0; j < W; j++) {\n J[i][j] = {max(J[i - 1][j].first, A[i][j]), min(J[i - 1][j].second, A[i][j])};\n }\n }\n for (ll i = H - 2; i >= 0; i--) {\n for (ll j = 0; j < W; j++) {\n I[i][j] = {max(I[i + 1][j].first, A[i][j]), min(I[i + 1][j].second, A[i][j])};\n }\n }\n ll ng = -1, ok = 1000000000;\n while (abs(ok - ng) > 1) {\n ll mid = (ok + ng) / 2;\n bool check1 = true, check2 = true;\n P all = {-INF, INF}, all2 = {-INF, INF};\n ll pos = H - 1;\n for (ll i = 0; i < W; i++) {\n if (pos < 0) {\n all2 = {max(all2.first, I[pos + 1][i].first), min(all2.second, I[pos + 1][i].second)};\n continue;\n }\n while (pos >= 0 && max(all.first, J[pos][i].first) - min(all.second, J[pos][i].second) > mid) {\n pos--;\n }\n if (pos + 1 < H) all2 = {max(all2.first, I[pos + 1][i].first), min(all2.second, I[pos + 1][i].second)};\n if (pos >= 0) all = {max(all.first, J[pos][i].first), min(all.second, J[pos][i].second)};\n }\n if (all == make_pair(-INF, INF)) check1 = false;\n if (all2 == make_pair(-INF, INF)) all2 = {0, 0};\n if (max(all.first - all.second, all2.first - all2.second) > mid) check1 = false;\n all = {-INF, INF}, all2 = {-INF, INF};\n pos = 0;\n for (ll i = 0; i < W; i++) {\n if (pos >= H) {\n all = {max(all.first, J[pos - 1][i].first), min(all.second, J[pos - 1][i].second)};\n continue;\n }\n while (pos < H && max(all2.first, I[pos][i].first) - min(all2.second, I[pos][i].second) > mid) {\n pos++;\n }\n if (pos - 1 >= 0) all = {max(all.first, J[pos - 1][i].first), min(all.second, J[pos - 1][i].second)};\n if (pos < H) all2 = {max(all2.first, I[pos][i].first), min(all2.second, I[pos][i].second)};\n }\n if (all2 == make_pair(-INF, INF)) check2 = false;\n if (all == make_pair(-INF, INF)) all = {0, 0};\n if (max(all.first - all.second, all2.first - all2.second) > mid) check2 = false;\n if (check1 || check2) ok = mid;\n else ng = mid;\n }\n ans = min(ans, ok);\n vector<vector<ll>>B(W, vector<ll>(H));\n for (ll i = 0; i < H; i++) {\n for (ll j = 0; j < W; j++) {\n B[j][H - i - 1] = A[i][j];\n J[j][H - i - 1] = J[i][j];\n I[j][H - i - 1] = I[i][j];\n }\n }\n A = B;\n swap(H, W);\n }\n cout << ans << endl;\n}\nint main() {\n ll T = 1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 1290, "memory_kb": 192336, "score_of_the_acc": -1.3236, "final_rank": 16 }, { "submission_id": "aoj_0638_6158808", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x - 1; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\t//res++;\n\t\tres += n % 10;\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\nll kaijyo[1000005];\nvoid nCkinit(ll n, ll m) {\n\tll cnt = 1; kaijyo[0] = 1;\n\tfor (int h = 1; h <= n; h++) { cnt *= h; cnt %= m; kaijyo[h] = cnt; }\n}\nll nCk(ll n, ll k, ll m) {\n\t/*ll a = 1, b = 1;\n\tfor (int h = 1; h <= n; h++) { a *= h; a %= m; }\n\tfor (int h = 1; h <= k; h++) { b *= h; b %= m; }\n\tfor (int h = 1; h <= n - k; h++) { b *= h; b %= m; }*/\n\tll a = kaijyo[n], b = kaijyo[k] * kaijyo[n - k] % m;\n\treturn a * modpow(b, m - 2, m) % m;\n}\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to; ld cost; };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\tll a;\n\tll b;\n\tll c;\n\n\tbool operator<(const status& rhs) const { return c < rhs.c; };\n\tbool operator>(const status& rhs) const { return c > rhs.c; };\n};\n\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"Yes\\n\"; }\n\telse { cout << \"No\\n\"; }\n}\n\nll a[2005][2005];\n\nint main() {\n\tsrand((unsigned)time(NULL));\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tll n, m; cin >> n >> m;\n\tll mi = INF, ma = 0;\n\trep2(i, n) {\n\t\trep2(j, m) {\n\t\t\tcin >> a[i][j];\n\t\t\tmi = min(mi, a[i][j]);\n\t\t\tma = max(ma, a[i][j]);\n\t\t}\n\t}\n\tll ok = -1, ng = ma - mi, mid = (ok + ng) / 2;\n\twhile (ng - ok > 1) {\n mid = (ok + ng) / 2;\n\t\tll ki = min(mi + mid, ma - mid - 1), ka = max(mi + mid + 1, ma - mid);\n\t\t//小さいほう:mi~ki、大きいほう:ka~ma\n\t\t//小さいほうが左、大きいほうが右\n\t\t//矛盾チェック\n\t\tvector<ll> l(n + 1), r(n + 1, INF);\n\t\tbool flag = true;\n\t\trep2(i, n) {\n\t\t\tbool kf = false;\n\t\t\trep2(j, m) {\n\t\t\t\tif (mi + mid < a[i][j] && a[i][j] < ma - mid) { flag = false; break; }\n\t\t\t\tif (ka <= a[i][j]) { kf = true; r[i] = min(r[i], j); }\n\t\t\t\tif (a[i][j] <= ki) {\n\t\t\t\t\tl[i] = max(l[i], j);\n\t\t\t\t\tif (kf) { flag = false; break; }\n\t\t\t\t}\n\t\t\t}\n\t\t}\n \n\t\tif (flag) {\n\t\t\t//単調増加できる?\n\t\t\tll now = l[0]; bool ok = true;\n\t\t\trep2(i, n) {\n\t\t\t\tif (r[i] <= now) { ok = false; break; }\n\t\t\t\tnow = max(now, l[i]);\n\t\t\t}\n\t\t\tif (ok) { ng = mid; mid = (ok + ng) / 2; continue; }\n\t\t\tnow = r[0]; ok = true;\n\t\t\t//単調減少できる?\n\t\t\trep2(i, n) {\n\t\t\t\tif (now <= l[i]) { ok = false; break; }\n\t\t\t\tnow = min(now, r[i]);\n\t\t\t}\n\t\t\tif (ok) { ng = mid; mid = (ok + ng) / 2; continue; }\n\t\t}\n\t\t//小さいほうが右、大きいほうが左\n\t\t//矛盾チェック\n\t\trep2(i, n) { l[i] = 0; r[i] = INF; }\n\t\tflag = true;\n\t\trep2(i, n) {\n\t\t\tbool kf = false;\n\t\t\trep2(j, m) {\n\t\t\t\tif (mi + mid < a[i][j] && a[i][j] < ma - mid) { flag = false; break; }\n\t\t\t\tif (a[i][j] <= ki) { kf = true; r[i] = min(r[i], j); }\n\t\t\t\tif (ka <= a[i][j]) {\n\t\t\t\t\tl[i] = max(l[i], j);\n\t\t\t\t\tif (kf) { flag = false; break; }\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (flag) {\n\t\t\t//単調増加できる?\n\t\t\tll now = l[0]; bool ok = true;\n\t\t\trep2(i, n) {\n\t\t\t\tif (r[i] <= now) { ok = false; break; }\n\t\t\t\tnow = max(now, l[i]);\n\t\t\t}\n\t\t\tif (ok) { ng = mid; mid = (ok + ng) / 2; continue; }\n\t\t\tnow = r[0]; ok = true;\n\t\t\t//単調減少できる?\n\t\t\trep2(i, n) {\n\t\t\t\tif (now <= l[i]) { ok = false; break; }\n\t\t\t\tnow = min(now, r[i]);\n\t\t\t}\n\t\t\tif (ok) { ng = mid; mid = (ok + ng) / 2; continue; }\n\t\t}\n\t\tok = mid; mid = (ok + ng) / 2; continue;\n\t}\n\tcout << ng << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 36236, "score_of_the_acc": -0.2486, "final_rank": 5 }, { "submission_id": "aoj_0638_5890066", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n\nlint mn, mx;\n\nbool is_ok(int h, int w, const vector<vector<lint>> &a, lint k){\n vector<vector<bool>> is_min(h, vector<bool>(w));\n \n rep(i, h){\n rep(j, w){\n is_min[i][j] = (a[i][j] - mn <= k);\n }\n }\n \n lint mx_min = mx;\n int back_x = w;\n rep(i, h){\n int x = w;\n rep(j, w){\n if(!is_min[i][j]){\n x = j;\n break;\n }\n }\n x = min(x, back_x);\n \n rep2(j, x, w){\n mx_min = min(mx_min, a[i][j]);\n }\n \n back_x = x;\n }\n \n return mx - mx_min <= k;\n}\n\nlint solve(int h, int w, const vector<vector<lint>> &a){\n lint ng = -1, ok = mx - mn + 1;\n while(abs(ok - ng) > 1){\n lint mid = (ok + ng) / 2;\n \n if(is_ok(h, w, a, mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n \n return ok;\n}\n\nint main(){\n int h, w;\n cin >> h >> w;\n vector<vector<lint>> a(h, vector<lint>(w));\n rep(i, h){\n rep(j, w){\n cin >> a[i][j];\n }\n }\n \n mn = 1e18, mx = -1e18;\n rep(i, h){\n rep(j, w){\n mn = min(mn, a[i][j]);\n mx = max(mx, a[i][j]);\n }\n }\n \n// int k = 18;\n// rep(i, h){\n// rep(j, w){\n// cout << (a[i][j] - mn <= k) << \" \";\n// }\n// cout << endl;\n// }\n// cout << endl;\n// rep(i, h){\n// rep(j, w){\n// cout << (mx - a[i][j] <= k) << \" \";\n// }\n// cout << endl;\n// }\n// cout << endl;\n \n lint ans = mx - mn;\n rep(c, 4){\n ans = min(ans, solve(h, w, a));\n// cout << solve(h, w, a) << endl;\n \n vector<vector<lint>> a2(w, vector<lint>(h));\n rep(i, h) rep(j, w) a2[w - j - 1][i] = a[i][j];\n \n a = a2;\n swap(h, w);\n }\n \n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 2140, "memory_kb": 96752, "score_of_the_acc": -1.0203, "final_rank": 12 }, { "submission_id": "aoj_0638_5875477", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long;\n#define rep(i, n) for(int i = 0; i < int(n); i++)\n#define rep2(i, l, n) for(int i = int(l); i < int(n); i++)\n\nlint mn, mx;\n\nbool is_ok(int h, int w, const vector<vector<lint>> &a, lint k){\n vector<vector<bool>> is_min(h, vector<bool>(w));\n \n rep(i, h){\n rep(j, w){\n is_min[i][j] = (a[i][j] - mn <= k);\n }\n }\n \n lint mx_min = mx;\n int back_x = w;\n rep(i, h){\n int x = w;\n rep(j, w){\n if(!is_min[i][j]){\n x = j;\n break;\n }\n }\n x = min(x, back_x);\n \n rep2(j, x, w){\n mx_min = min(mx_min, a[i][j]);\n }\n \n back_x = x;\n }\n \n return mx - mx_min <= k;\n}\n\nlint solve(int h, int w, const vector<vector<lint>> &a){\n lint ng = -1, ok = mx - mn + 1;\n while(abs(ok - ng) > 1){\n lint mid = (ok + ng) / 2;\n \n if(is_ok(h, w, a, mid)){\n ok = mid;\n }else{\n ng = mid;\n }\n }\n \n return ok;\n}\n\nint main(){\n int h, w;\n cin >> h >> w;\n vector<vector<lint>> a(h, vector<lint>(w));\n rep(i, h){\n rep(j, w){\n cin >> a[i][j];\n }\n }\n \n mn = 1e18, mx = -1e18;\n rep(i, h){\n rep(j, w){\n mn = min(mn, a[i][j]);\n mx = max(mx, a[i][j]);\n }\n }\n \n// int k = 18;\n// rep(i, h){\n// rep(j, w){\n// cout << (a[i][j] - mn <= k) << \" \";\n// }\n// cout << endl;\n// }\n// cout << endl;\n// rep(i, h){\n// rep(j, w){\n// cout << (mx - a[i][j] <= k) << \" \";\n// }\n// cout << endl;\n// }\n// cout << endl;\n \n lint ans = mx - mn;\n rep(c, 4){\n ans = min(ans, solve(h, w, a));\n// cout << solve(h, w, a) << endl;\n \n vector<vector<lint>> a2(w, vector<lint>(h));\n rep(i, h) rep(j, w) a2[w - j - 1][i] = a[i][j];\n \n a = a2;\n swap(h, w);\n }\n \n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 2140, "memory_kb": 96828, "score_of_the_acc": -1.0207, "final_rank": 13 }, { "submission_id": "aoj_0638_5062837", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int h, w;\n cin >> h >> w;\n\n auto grid = vector(h, vector(w, 0));\n int mi = INF, ma = 0;\n for (auto& v : grid) {\n for (auto& x : v) {\n cin >> x;\n mi = min(mi, x);\n ma = max(ma, x);\n }\n }\n\n int ok = ma - mi, ng = -1;\n while (ok - ng > 1) {\n int d = (ok + ng) / 2;\n\n bool valid = false;\n for (int q = 0; q < 2; ++q) {\n // IOIがmiを含まない側の場合\n {\n int l = 0; // [0, l)はIOIに属する\n\n bool judge = true;\n for (const auto& v : grid) {\n for (int i = 0; i < w; ++i) {\n if (v[i] - mi > d) l = max(l, i + 1);\n }\n for (int i = 0; i < l; ++i) {\n if (ma - v[i] > d) judge = false;\n }\n }\n if (judge) valid = true;\n }\n\n // IOIがmaを含まない側の場合\n {\n int l = 0; // [0, l)はIOIに属する\n\n bool judge = true;\n for (const auto& v : grid) {\n for (int i = 0; i < w; ++i) {\n if (ma - v[i] > d) l = max(l, i + 1);\n }\n for (int i = 0; i < l; ++i) {\n if (v[i] - mi > d) judge = false;\n }\n }\n if (judge) valid = true;\n }\n\n // 左右反転してもう一度\n for (auto& v : grid) reverse(v.begin(), v.end());\n }\n\n if (valid) {\n ok = d;\n } else {\n ng = d;\n }\n }\n\n cout << ok << \"\\n\";\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 1310, "memory_kb": 18920, "score_of_the_acc": -0.3295, "final_rank": 6 }, { "submission_id": "aoj_0638_4413223", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <random>\n#include <bitset>\n#include <queue>\n#include <functional>\n#include <set>\n#include <map>\n#include <vector>\n#include <chrono>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\n// mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\ntemplate <class T>\nistream& operator>>(istream& is, vector<T>& v) {\n for (T& x : v) is >> x;\n return is;\n}\n\ntemplate <class T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n if (!v.empty()) {\n os << v.front();\n for (int i = 1; i < v.size(); ++i) os << ' ' << v[i];\n }\n return os;\n}\n\nint main() {\n#ifdef LBT\n freopen(\"test.in\", \"r\", stdin);\n int nol_cl = clock();\n#endif\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N, M;\n cin >> N >> M;\n vector<vector<int>> A(N, vector<int>(M));\n cin >> A;\n vector<pair<int, pair<int, int>>> pos;\n pos.reserve(N * M);\n for (int i = 0; i < N; ++i)\n for (int j = 0; j < M; ++j) pos.emplace_back(A[i][j], make_pair(i, j));\n sort(pos.begin(), pos.end());\n int ans = numeric_limits<int>::max();\n for (int rep = 1; rep <= 4; ++rep) {\n int mx = numeric_limits<int>::min(), mn = numeric_limits<int>::max();\n vector<int> R(N);\n for (int i = 0; i < N * M - 1; ++i) {\n int x, y;\n tie(x, y) = pos[i].second;\n while (x >= 0 && R[x] <= y) {\n while (R[x] <= y) {\n mx = max(mx, A[x][R[x]]);\n mn = min(mn, A[x][R[x]]);\n ++R[x];\n }\n --x;\n }\n ans = min(ans, max(pos.back().first - pos[i + 1].first, mx - mn));\n }\n if (rep & 1) {\n reverse(A.begin(), A.end());\n for (auto& pr : pos) pr.second.first = N - 1 - pr.second.first;\n } else if (rep & 2) {\n for (int i = 0; i < N; ++i) reverse(A[i].begin(), A[i].end());\n for (auto& pr : pos) pr.second.second = M - 1 - pr.second.second;\n }\n }\n cout << ans << '\\n';\n\n#ifdef LBT\n LOG(\"Time: %dms\\n\", int((clock() - nol_cl) / (double)CLOCKS_PER_SEC * 1000));\n#endif\n return 0;\n}", "accuracy": 1, "time_ms": 630, "memory_kb": 65472, "score_of_the_acc": -0.3997, "final_rank": 7 }, { "submission_id": "aoj_0638_4079501", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\ntemplate<class T,class U> using P = pair<T,U>;\ntemplate<class T> using vec = vector<T>;\ntemplate<class T> using vvec = vector<vec<T>>;\n\nconstexpr int inf = 1e9+1;\nint ma[4][2010][2010] = {};\nint mi[4][2010][2010] = {};\nint exist[4][2010] = {};\nint A[4][2010][2010] = {};\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(false);\n int H,W;\n int M = 0;\n cin >> H >> W;\n for(int i=0;i<H;i++) for(int j=0;j<W;j++){\n cin >> A[0][i][j];\n A[1][W-j-1][i] = A[0][i][j];\n M = max(M,A[0][i][j]);\n }\n for(int i=0;i<H;i++) for(int j=0;j<W;j++) A[2][i][j] = A[0][i][W-j-1];\n for(int i=0;i<W;i++) for(int j=0;j<H;j++) A[3][i][j] = A[1][i][H-j-1];\n\n for(int t=0;t<4;t++) for(int i=0;i<=max(H,W);i++){\n exist[t][i] = -1;\n for(int j=0;j<=max(H,W);j++){\n ma[t][i][j] = 0;\n mi[t][i][j] = inf;\n }\n }\n\n auto calc = [&](int H,int W,int t){\n for(int i=0;i<H;i++) for(int j=W-1;j>=0;j--){\n ma[t][i][j] = max(ma[t][i][j+1],A[t][i][j]);\n mi[t][i][j] = min(mi[t][i][j+1],A[t][i][j]);\n if(A[t][i][j]==M) exist[t][i] = max(exist[t][i],j);\n }\n };\n\n calc(H,W,0);\n calc(W,H,1);\n calc(H,W,2);\n calc(W,H,3);\n \n auto check = [&](int H,int W,int d,int t){\n bool res = false;\n int ma2 = 0,mi2 = inf,pl = W-1;\n bool judge = true;\n for(int i=0;i<H;i++){\n int l = -1;\n for(int j=0;j<=pl;j++){\n if(A[t][i][j]<M-d) break;\n l = j;\n }\n if(l<exist[t][i]){\n judge = false;\n break;\n }\n mi2 = min(mi2,mi[t][i][l+1]);\n ma2 = max(ma2,ma[t][i][l+1]);\n pl = l;\n }\n res |= judge && ma2-mi2<=d;\n ma2 = 0,mi2 = inf,pl = W-1,judge = true;\n for(int i=H-1;i>=0;i--){\n int l = -1;\n for(int j=0;j<=pl;j++){\n if(A[t][i][j]<M-d) break;\n l = j;\n }\n if(l<exist[t][i]){\n judge = false;\n break;\n }\n mi2 = min(mi2,mi[t][i][l+1]);\n ma2 = max(ma2,ma[t][i][l+1]);\n pl = l;\n }\n res |= judge && ma2-mi2<=d;\n return res;\n };\n\n auto ok = [&](int d){\n bool res = false;\n res |= check(H,W,d,0);\n res |= check(W,H,d,1);\n res |= check(H,W,d,2);\n res |= check(W,H,d,3);\n return res;\n };\n\n int l = -1,r = M;\n while(l+1<r){\n int m = (l+r)>>1;\n (ok(m)? r:l) = m;\n }\n cout << r << endl;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 191716, "score_of_the_acc": -1.0722, "final_rank": 14 }, { "submission_id": "aoj_0638_4020777", "code_snippet": "#include <iostream>\n#include <vector>\n#include <array>\n#include <list>\n#include <string>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <tuple>\n#include <bitset>\n#include <memory>\n#include <cmath>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits>\n#include <cfloat>\n#include <cassert>\n#include <random>\nusing vvi = std::vector<std::vector<int>>;\nint shrink_to_right(const int left_max_value, const std::vector<std::vector<int>>& left_max, const std::vector<std::vector<int>>& right_min) {\n\tint min = INT_MAX;\n\tstd::vector<int> right_pos(left_max.size());\n\tfor (auto i = 0; i < left_max.size(); ++i) {\n\t\tright_pos[i] = std::distance(left_max[i].begin(), std::upper_bound(left_max[i].begin(), left_max[i].end(), left_max_value));\n\t}\n\tint min_pos = right_min.front().size();\n\tfor (auto i = 0; i < right_min.size(); ++i) {\n\t\tmin_pos = std::min(min_pos, right_pos[i]);\n\t\tif (min_pos < right_min[i].size())\n\t\t\tmin = std::min(min, right_min[i][min_pos]);\n\t}\n\tint result = min;\n\tmin = INT_MAX;\n\tmin_pos = right_min.front().size();\n\tfor (auto i = 1; i <= right_min.size(); ++i) {\n\t\tmin_pos = std::min(min_pos, right_pos[right_pos.size() - i]);\n\t\tif (min_pos < right_min[right_min.size() - i].size())\n\t\t\tmin = std::min(min, right_min[right_min.size() - i][min_pos]);\n\t}\n\treturn std::max(result, min);\n}\nint first_less_or_equals(const std::vector<int>& array, const int value) {\n\tint left = 0;\n\tint right = array.size();\n\twhile (left < right) {\n\t\tauto mid = (left + right) / 2;\n\t\tif (array[mid] <= value) right = mid;\n\t\telse left = mid + 1;\n\t}\n\treturn right;\n}\nint shrink_to_left(const int right_max_value, const std::vector<std::vector<int>>& right_max, const std::vector<std::vector<int>>& left_min) {\n\tint min = INT_MAX;\n\tstd::vector<int> right_pos(right_max.size());\n\tfor (auto i = 0; i < right_max.size(); ++i) {\n\t\tright_pos[i] = first_less_or_equals(right_max[i], right_max_value) - 1;\n\t}\n\tint max_pos = -1;\n\tfor (auto i = 0; i < left_min.size(); ++i) {\n\t\tmax_pos = std::max(max_pos, right_pos[i]);\n\t\tif (max_pos >= 0)\n\t\t\tmin = std::min(min, left_min[i][max_pos]);\n\t}\n\tint result = min;\n\tmin = INT_MAX;\n\tmax_pos = -1;\n\tfor (int i = left_min.size() - 1; i >= 0; --i) {\n\t\tmax_pos = std::max(max_pos, right_pos[i]);\n\t\tif (max_pos >= 0)\n\t\t\tmin = std::min(min, left_min[i][max_pos]);\n\t}\n\treturn std::max(result, min);\n}\nint shrink_to_bottom(const int top_max_value, const std::vector<std::vector<int>>& top_max, const std::vector<std::vector<int>>& bottom_min) {\n\tint min = INT_MAX;\n\tstd::vector<int> bottom_pos(top_max.size());\n\tfor (auto i = 0; i < top_max.size(); ++i) {\n\t\tbottom_pos[i] = std::distance(top_max[i].begin(), std::upper_bound(top_max[i].begin(), top_max[i].end(), top_max_value));\n\t}\n\tint min_pos = bottom_min.front().size();\n\tfor (auto i = 0; i < bottom_min.size(); ++i) {\n\t\tmin_pos = std::min(min_pos, bottom_pos[i]);\n\t\tif (min_pos < bottom_min[i].size())\n\t\t\tmin = std::min(min, bottom_min[i][min_pos]);\n\t}\n\tint result = min;\n\tmin = INT_MAX;\n\tmin_pos = bottom_min.front().size();\n\tfor (auto i = 1; i <= bottom_min.size(); ++i) {\n\t\tmin_pos = std::min(min_pos, bottom_pos[bottom_pos.size() - i]);\n\t\tif (min_pos < bottom_min[bottom_min.size() - i].size())\n\t\t\tmin = std::min(min, bottom_min[bottom_min.size() - i][min_pos]);\n\t}\n\treturn std::max(result, min);\n}\nint shrink_to_top(const int bottom_max_value, const std::vector<std::vector<int>>& bottom_max, const std::vector<std::vector<int>>& top_min) {\n\tint min = INT_MAX;\n\tstd::vector<int> bottom_pos(bottom_max.size());\n\tfor (auto i = 0; i < bottom_max.size(); ++i) {\n\t\tbottom_pos[i] = first_less_or_equals(bottom_max[i], bottom_max_value) - 1;\n\t}\n\tint max_pos = -1;\n\tfor (auto i = 0; i < top_min.size(); ++i) {\n\t\tmax_pos = std::max(max_pos, bottom_pos[i]);\n\t\tif (max_pos >= 0)\n\t\t\tmin = std::min(min, top_min[i][max_pos]);\n\t}\n\tint result = min;\n\tmin = INT_MAX;\n\tmax_pos = -1;\n\tfor (int i = top_min.size() - 1; i >= 0; --i) {\n\t\tmax_pos = std::max(max_pos, bottom_pos[i]);\n\t\tif (max_pos >= 0)\n\t\t\tmin = std::min(min, top_min[i][max_pos]);\n\t}\n\treturn std::max(result, min);\n}\nint cal_max_min(const int max_max_value, const vvi& top_max, const vvi& top_min, const vvi& left_max, const vvi& left_min, const vvi& bottom_max, const vvi& bottom_min, const vvi& right_max, const vvi& right_min) {\n\treturn std::max({\n\t\tshrink_to_right(max_max_value, left_max, right_min),\n\t\tshrink_to_left(max_max_value, right_max, left_min),\n\t\tshrink_to_bottom(max_max_value, top_max, bottom_min),\n\t\tshrink_to_top(max_max_value, bottom_max, top_min)\n\t\t});\n}\nint main() {\n\tint h, w; std::cin >> h >> w;\n\tstd::vector<std::vector<int>> state(h, std::vector<int>(w)); for (auto& line : state) for (auto& area : line) std::cin >> area;\n\tstd::vector<std::vector<int>> flipped(w, std::vector<int>(h));\n\tfor (auto i = 0; i < h; ++i) for (auto j = 0; j < w; ++j) flipped[j][i] = state[i][j];\n\tauto top_max = flipped;\n\tauto top_min = flipped;\n\tauto left_max = state;\n\tauto left_min = state;\n\tauto bottom_max = flipped;\n\tauto bottom_min = flipped;\n\tauto right_max = state;\n\tauto right_min = state;\n\tfor (auto i = 0; i < h; ++i) for (auto j = 1; j < w; ++j) {\n\t\tleft_max[i][j] = std::max(left_max[i][j], left_max[i][j - 1]);\n\t\tleft_min[i][j] = std::min(left_min[i][j], left_min[i][j - 1]);\n\t\tright_max[i][w - j - 1] = std::max(right_max[i][w - j - 1], right_max[i][w - j]);\n\t\tright_min[i][w - j - 1] = std::min(right_min[i][w - j - 1], right_min[i][w - j]);\n\t}\n\tfor (auto i = 1; i < h; ++i) for (auto j = 0; j < w; ++j) {\n\t\ttop_max[j][i] = std::max(top_max[j][i], top_max[j][i - 1]);\n\t\ttop_min[j][i] = std::min(top_min[j][i], top_min[j][i - 1]);\n\t\tbottom_max[j][h - i - 1] = std::max(bottom_max[j][h - i - 1], bottom_max[j][h - i]);\n\t\tbottom_min[j][h - i - 1] = std::min(bottom_min[j][h - i - 1], bottom_min[j][h - i]);\n\t}\n\tstd::vector<std::pair<int, int>> coordinates; coordinates.reserve(h * w);\n\tfor (auto i = 0; i < h; ++i) for (auto j = 0; j < w; ++j) coordinates.emplace_back(i, j);\n\tstd::sort(coordinates.begin(), coordinates.end(), [&state](const std::pair<int, int>& a, const std::pair<int, int>& b) {return state[a.first][a.second] < state[b.first][b.second]; });\n\tconst int max_value = state[coordinates.back().first][coordinates.back().second];\n\tconst int min_value = state[coordinates.front().first][coordinates.front().second];\n\tauto min = 0;\n\tauto max = coordinates.size();\n\twhile (min < max) {\n\t\tauto mid = (min + max) / 2;\n\t\tauto min_max = state[coordinates[mid].first][coordinates[mid].second];\n\t\tauto max_min = cal_max_min(min_max, top_max, top_min, left_max, left_min, bottom_max, bottom_min, right_max, right_min);\n\t\tauto min_diff = min_max - min_value;\n\t\tauto max_diff = max_value - max_min;\n\t\tif (min_diff < max_diff) {\n\t\t\tmin = mid + 1;\n\t\t}\n\t\telse {\n\t\t\tmax = mid;\n\t\t}\n\t}\n\tint result = INT_MAX;\n\tif (min > 0) {\n\t\tint min_max = state[coordinates[min - 1].first][coordinates[min - 1].second];\n\t\tresult = max_value - cal_max_min(min_max, top_max, top_min, left_max, left_min, bottom_max, bottom_min, right_max, right_min);\n\t}\n\tif (min < coordinates.size()) {\n\t\tint min_max = state[coordinates[min].first][coordinates[min].second];\n\t\tresult = std::min(result, min_max - min_value);\n\t}\n\tstd::cout << result << '\\n';\n}", "accuracy": 1, "time_ms": 2010, "memory_kb": 191048, "score_of_the_acc": -1.5261, "final_rank": 20 } ]
aoj_0647_cpp
ストーブ(Stove) JOI 君の部屋にはストーブがある.JOI 君自身は寒さに強いのでひとりで部屋にいるときはストーブをつける必要はないが,来客があるときはストーブをつける必要がある. この日,JOI 君のもとには N 人の来客がある. i 番目( 1 \leq i \leq N ) の来客は時刻 T_i に到着し,時刻 T_i + 1 に退出する.同時に複数人の来客があることはない. JOI 君は任意の時刻にストーブをつけたり消したりできる.ただし,ストーブをつける度にマッチを1本消費する.JOI 君はマッチを K 本しか持っていないので, K 回までしかストーブをつけることができない.一日のはじめにストーブは消えている. ストーブをつけているとその分だけ燃料を消費するので,ストーブをつけたり消したりする時刻をうまく定めて,ストーブがついている時間の合計を最小化したい. 課題 JOI 君の部屋への来客の情報と,JOI 君の持っているマッチの本数が与えられたとき,ストーブがついている時間の合計の最小値を求めよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,2 つの整数 N, K が空白を区切りとして書かれている.これは,JOI 君の部屋に N 人の来客があり,JOI 君は K 本のマッチを持っていることを表す. 続く N 行のうちの i 行目( 1 \leq i \leq N ) には,整数 T_i が書かれている.これは, i 番目の来客が時刻 T_i に到着し,時刻 T_i + 1 に退出することを表す. 出力 標準出力に,ストーブがついている時間の合計の最小値を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 1 \leq N \leq 100 000. 1 \leq K \leq N. 1 \leq T_i \leq 1 000 000 000 (1 \leq i \leq N). T_i < T_{i+1} (1 \leq i \leq N - 1) . 問入出力例 入力例1 3 2 1 3 6 出力例1 4 この入力例では,JOI 君の部屋への来客が3 人ある.以下のようにストーブをつけたり消したりすると,来客がある間はストーブがついており,ストーブをつける回数は2 回であり,ストーブがついている時間の合計は(4 - 1) + (7 - 6) = 4 である. 1 番目の来客が到着する時刻1 にストーブをつける. 2 番目の来客が退出する時刻4 にストーブを消す. 3 番目の来客が到着する時刻6 にストーブをつける. 3 番目の来客が退出する時刻7 にストーブを消す. ストーブをつけている時間の合計を4 未満にすることはできないので,答えとして4 を出力する. 入力例2 3 1 1 2 6 出力例2 6 この入力例では,JOI 君は1 回しかストーブをつけることができないので,1 番目の来客が到着する時刻1 にストーブをつけ,3 番目の来客が退出する時刻7 にストーブを消せばよい. 来客が退出する時刻と,その次の来客が到着する時刻が一致する場合があることに注意せよ. 入力例3 3 3 1 3 6 出力例3 3 この入力例では,JOI 君は来客が到着する度にストーブをつけ,来客が退出する度にストーブを消せばよい. 入力例4 10 5 1 2 5 6 8 11 13 15 16 20 出力例4 12 情報オリンピック日本委員会作 『第17 回日本情報オリンピック(JOI 2017/2018) 本選』
[ { "submission_id": "aoj_0647_10946354", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,n) for(ll i=0;i<ll(n);++i)\n#define RREP(i,n) for(ll i=ll(n)-1;i>=0;--i)\n#define FOR(i,m,n) for(ll i=m;i<ll(n);++i)\n#define RFOR(i,m,n) for(ll i=ll(n)-1;i>=ll(m);--i)\n#define ALL(v) (v).begin(),(v).end()\n#define UNIQUE(v) v.erase(unique(ALL(v)),v.end());\n#define DUMP(v) REP(aa, (v).size()) { cout << v[aa]; if (aa != v.size() - 1)cout << \" \"; else cout << endl; }\n#define INF 1000000001ll\n#define MOD 1000000007ll\n#define EPS 1e-9\n\nconst int dx[8] = { 1,1,0,-1,-1,-1,0,1 };\nconst int dy[8] = { 0,1,1,1,0,-1,-1,-1 };\n\n\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<vi> vvi;\ntypedef vector<vl> vvl;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nll max(ll a, int b) { return max(a, ll(b)); }\nll max(int a, ll b) { return max(ll(a), b); }\nll min(ll a, int b) { return min(a, ll(b)); }\nll min(int a, ll b) { return min(ll(a), b); }\n\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tint n, k;\n\tcin >> n >> k;\n\tvi t(n);\n\tREP(i, n)cin >> t[i];\n\n\tvi v(n - 1);\n\tREP(i, n - 1)v[i] = t[i + 1] - t[i];\n\tsort(ALL(v));\n\tint ans = 0;\n\tREP(i, n - k)ans += v[i] - 1;\n\tcout << ans + n << endl;\n\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3868, "score_of_the_acc": -0.3901, "final_rank": 4 }, { "submission_id": "aoj_0647_10874379", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\n\nint MIN = -1e9;\nconst int MOD = 10000;\n\nint main() {\n\tint N,M;\n\tcin >> N>>M;\n\tdeque<int>L;\n\tint x;\n\tcin >> x;\n\tint ans = 0;\n\tans += 1;\n\tint y;\n\tfor (int i = 1; i < N; i++) {\n\t\tcin >> y;\n\t\tL.push_back(y - (x + 1));\n\t\tans += 1;\n\t\tx = y;\n\t}\n\n\tsort(L.rbegin(), L.rend());\n\tfor (int i = 0; i < M - 1; i++) {\n\t\tL.pop_front();\n\t}\n\n\tfor (int i = 0; i < L.size(); i++) {\n\t\tans += L[i];\n\t}\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3764, "score_of_the_acc": -0.8341, "final_rank": 9 }, { "submission_id": "aoj_0647_10334565", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <cstdlib>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n,k;\n cin >> n >> k;\n vector<int> t(n);\n rep(i,n){\n cin >> t[i];\n }\n vector<int> d(n-1);\n rep(i,n-1){\n d[i]=abs(t[i]+1-t[i+1]);\n }\n sort(d.begin(),d.end());\n long long res=n;\n if(n>k){\n rep(i,n-k){\n res += d[i];\n }\n }\n cout << res << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3868, "score_of_the_acc": -0.8901, "final_rank": 11 }, { "submission_id": "aoj_0647_9893675", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 2147483647;\n\nconst int MAX_N = 100000;\nstatic int vect[MAX_N];\n//------------------------------------------------------------------------------\nstruct Diff\n{\n int i, v;\n\n Diff(): i(-1), v(0) {}\n Diff(int val): i(-1), v(val) {}\n Diff(int idx, int val): i(idx), v(val) {}\n bool operator<(const Diff& e1) const\n {\n if (v == e1.v) return i < e1.i;\n return v > e1.v;\n }\n void debug() const { printf(\"i=%d, v=%d\\n\", i, v); }\n};\n\ntypedef vector<Diff> Diffs;\n\n\n//------------------------------------------------------------------------------\nint64_t solve(int N, int K)\n{\n //--------------------------------------------------------------------------\n // base cases:\n if (K == 1) return vect[N-1]-vect[0]+1;\n else if (K == N) return N;\n\n //--------------------------------------------------------------------------\n // init:\n Diffs DD(N-1);\n for (int i=0; i<N-1; ++i) DD[i] = Diff(i, vect[i+1]-vect[i]);\n sort(DD.begin(), DD.end());\n\n vector<int> indices(K-1);\n for (int k=0; k<K-1; ++k) indices[k] = DD[k].i;\n sort(indices.begin(), indices.end());\n //--------------------------------------------------------------------------\n // compute:\n int64_t res = 0;\n int start = 0;\n for (int k=0; k<K-1; ++k)\n {\n int back = indices[k];\n res += vect[back] - vect[start] + 1;\n start = back + 1;\n }\n res += vect[N-1] - vect[start] + 1;\n\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, K, num;\n num = scanf(\"%d %d \", &N, &K);\n for (int i=0; i<N; ++i) num = scanf(\"%d \", &vect[i]);\n int64_t res = solve(N, K);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 10, "memory_kb": 4720, "score_of_the_acc": -0.8491, "final_rank": 10 }, { "submission_id": "aoj_0647_9477002", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main() {\n int N, K;\n cin >> N >> K;\n \n vector<int> T(N);\n for (int i = 0; i < N; ++i) {\n cin >> T[i];\n }\n \n // ストーブを点けた状態の合計時間を計算\n int total_time = T[N-1] - T[0] + 1;\n\n // ギャップを計算\n vector<int> gaps;\n for (int i = 1; i < N; ++i) {\n gaps.push_back(T[i] - T[i-1] - 1);\n }\n\n // ギャップを大きい順にソート\n sort(gaps.begin(), gaps.end(), greater<int>());\n \n // K-1個の最大ギャップを使って合計時間を短縮\n int max_gap_sum = 0;\n for (int i = 0; i < K-1; ++i) {\n if (i < gaps.size()) {\n max_gap_sum += gaps[i];\n }\n }\n \n // 最小のストーブ点灯時間を計算\n int min_time = total_time - max_gap_sum;\n \n cout << min_time << endl;\n \n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4132, "score_of_the_acc": -1.0323, "final_rank": 15 }, { "submission_id": "aoj_0647_9157123", "code_snippet": "#include<algorithm>\n#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(void) {\n int n, k;\n cin >> n >> k;\n vector<int> t(n), btw(n-1);\n for (int i = 0; i < n; i++) cin >> t[i];\n for (int i = 0; i < n-1; i++) btw[i] = t[i+1] - t[i] - 1;\n sort(btw.rbegin(), btw.rend());\n\n int ans = t.back() - t.front() + 1, loop_cnt = k - 1;\n for (int i = 0; i < loop_cnt; i++) {\n ans -= btw[i];\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3904, "score_of_the_acc": -0.9095, "final_rank": 12 }, { "submission_id": "aoj_0647_8905579", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, K;\n cin >> N >> K;\n vi T(N);\n rep(i, N) cin >> T[i];\n vi d(N-1);\n rep(i, N-1) d[i] = T[i+1] - T[i] - 1;\n sort(all(d));\n ll ans = N + accumulate(d.begin(), d.begin()+max(0LL,N-K), 0LL);\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4628, "score_of_the_acc": -0.7996, "final_rank": 7 }, { "submission_id": "aoj_0647_8894965", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),M=in();\n\tauto A=vecin(N);\n\tif(N==M){\n\t\tout(N);\n\t\treturn 0;\n\t}\n\tvll D(N-1);\n\tREP(i,N-1){\n\t\tD[i]=A[i+1]-A[i];\n\t}\n\tll L=N-M;\n\tsort(ALL(D));\n\tll C=N;\n\tREP(i,L){\n\t\tC += D[i]-1ll;\n\t}\n\tout(C);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4664, "score_of_the_acc": -0.819, "final_rank": 8 }, { "submission_id": "aoj_0647_8474176", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main(void){\n\n int n,k,t[100000],x[100000],sum;\n cin>>n>>k;\n for(int i = 0;i < n;i++){\n cin>>t[i];\n }\n for(int i = 0;i < n-1;i++){\n x[i] = t[i+1] - t[i];\n }\n sort(x,x+n-1);\n sum = k;\n for(int i = 0;i < n-k;i++){\n sum += x[i];\n }\n cout<<sum<<endl;\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3868, "score_of_the_acc": -1.3901, "final_rank": 17 }, { "submission_id": "aoj_0647_8287499", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<algorithm>\nusing namespace std;\nint main(){\n int n,k;\n long long a[100005];\n vector<long long> vec;\n scanf(\"%d %d\",&n,&k);\n for(int i=0;i<n;i++) scanf(\"%lld\",a+i);\n \n long long ans = a[n-1]-a[0]+1;\n for(int i=1;i<n;i++) vec.push_back(a[i]-a[i-1]-1);\n\n sort(vec.begin(),vec.end());\n reverse(vec.begin(),vec.end());\n for(int i=0;i<k-1;i++) ans -= vec[i];\n printf(\"%lld\\n\",ans);\n return(0);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4220, "score_of_the_acc": -0.5797, "final_rank": 6 }, { "submission_id": "aoj_0647_7940807", "code_snippet": "#include <queue>\n#include <stdio.h>\nusing namespace std;\n#define N_MAX 100000\nint N, K;\nlong long time[N_MAX];\npriority_queue<int> que;\nint main(void) {\n scanf(\"%d %d\", &N, &K);\n int i, j;\n for (i = 0; i < N; ++i) {\n scanf(\"%d\", time + i);\n if (i > 0) {\n que.push(-(time[i] - time[i - 1] - 1));\n }\n }\n if (K >= N)\n printf(\"%d\\n\", N);\n else if (K == 1)\n printf(\"%lld\\n\", time[N - 1] - time[0] + 1);\n else {\n long long sum = N;\n N -= K;\n for (i = 0; i < N; ++i) {\n sum += -que.top();\n que.pop();\n }\n printf(\"%lld\\n\", sum);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3688, "score_of_the_acc": -0.2931, "final_rank": 2 }, { "submission_id": "aoj_0647_7940802", "code_snippet": "#include <queue>\n#include <stdio.h>\nusing namespace std;\n#define N_MAX 100000\nint N, K;\nint time[N_MAX];\npriority_queue<int> que;\nint main(void) {\n scanf(\"%d %d\", &N, &K);\n int i, j;\n for (i = 0; i < N; ++i) {\n scanf(\"%d\", time + i);\n if (i > 0) {\n que.push(-(time[i] - time[i - 1] - 1));\n }\n }\n long long sum = N;\n N -= K;\n for (i = 0; i < N; ++i) {\n sum += -que.top();\n que.pop();\n }\n printf(\"%lld\\n\", sum);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3408, "score_of_the_acc": -0.1422, "final_rank": 1 }, { "submission_id": "aoj_0647_7940797", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nlong long sa[100000];\nint main(void) {\n long long n, k, t, tt, ans, i;\n cin >> n >> k;\n ans = n;\n cin >> t;\n t++;\n for (i = 0; i < n - 1; i++) {\n cin >> tt;\n sa[i] = tt - t;\n t = tt + 1;\n }\n sort(sa, sa + n - 1);\n n = n - k;\n i = 0;\n while (n > 0) {\n ans += sa[i];\n i++;\n n--;\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3940, "score_of_the_acc": -1.4289, "final_rank": 18 }, { "submission_id": "aoj_0647_6995064", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0647.cc: ストーブ(Stove)\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\n\n/* typedef */\n\ntypedef long long ll;\n\n/* global variables */\n\nint ts[MAX_N], ds[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, k;\n scanf(\"%d%d\", &n, &k);\n for (int i = 0; i < n; i++) scanf(\"%d\", ts + i);\n\n for (int i = 0; i + 1 < n; i++) ds[i] = ts[i + 1] - (ts[i] + 1);\n sort(ds, ds + n - 1);\n\n int m = n - k;\n ll sum = 0;\n for (int i = 0; i < m; i++) sum += ds[i];\n\n printf(\"%lld\\n\", sum + n);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3720, "score_of_the_acc": -0.3103, "final_rank": 3 }, { "submission_id": "aoj_0647_6851071", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nint main() {\n ll N,K;\n cin>>N>>K;\n K--;\n vll A(N),S(N-1);\n rep(i,N)cin>>A[i];\n rep(i,N-1)S[i]=A[i+1]-A[i];\n sort(all(S));\n reverse(all(S));\n ll an=A[N-1]+1-A[0]+K;\n rep(k,K)an-=S[k];\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4620, "score_of_the_acc": -1.2953, "final_rank": 16 }, { "submission_id": "aoj_0647_6631859", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n ios::sync_with_stdio(0);\n cin.tie(0);\n\n int n, k;\n cin >> n >> k;\n\n vector<int> t(n, 0);\n for (int i = 0; i < n; ++i) {\n cin >> t[i];\n }\n\n vector<int> gap;\n for (int i = 0; i < n - 1; ++i) {\n gap.push_back(t[i + 1] - (t[i] + 1));\n }\n sort(gap.begin(), gap.end(), [](int x, int y) { return x > y; });\n int total_time = t[n - 1] + 1 - t[0];\n for (int i = 0; i < k - 1; ++i) {\n total_time -= gap[i];\n }\n cout << total_time << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4144, "score_of_the_acc": -0.5388, "final_rank": 5 }, { "submission_id": "aoj_0647_6131382", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\n//typedef pair<ll, ll> P;\nconst long long INF = 1e9;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nint main() {\n ll N, M; cin >> N >> M;\n vector<ll>A(N); input_arr(A, N);\n ll ans = A.back() + 1 - A[0];\n vector<ll>B;\n for (ll i = 1; i < N; i++) {\n B.push_back(A[i] - (A[i - 1] + 1));\n }\n sort(B.begin(), B.end(), greater<ll>());\n for (ll i = 0; i < M - 1; i++) {\n ans -= B[i];\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4912, "score_of_the_acc": -1.4526, "final_rank": 19 }, { "submission_id": "aoj_0647_5897150", "code_snippet": "#include<iostream>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint N, K;\n\tcin >> N >> K;\n\tint* T = new int[N];\n\tcin >> T[0];\n\tvector<int> vec;\n\tfor (int i = 1; i < N; i++)\n\t{\n\t\tcin >> T[i];\n\t\tvec.push_back(T[i] - T[i - 1] - 1);\n\t}\n\tsort(vec.begin(), vec.end());\n\tint ans = N;\n\tfor (int i = 0; i < N - K; i++)\n\t\tans += vec[i];\n\tcout << ans << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4076, "score_of_the_acc": -1.0022, "final_rank": 14 }, { "submission_id": "aoj_0647_5801915", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<sstream>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nsigned main(){\n\tint n,k,t[100000],dif[99999];\n\tcin>>n>>k;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>t[i];\n\tfor(int i=0;i<n-1;i++)\n\t\tdif[i]=t[i+1]-t[i]-1;\n\tsort(dif,dif+n-1);\n\tint ans=n;\n\tfor(int i=0;i<n-k;i++)\n\t\tans+=dif[i];\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5000, "score_of_the_acc": -1.5, "final_rank": 20 }, { "submission_id": "aoj_0647_5725117", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main(void) {\n\tint n, k;\n\tcin >> n >> k;\n\tvector<int> v(n-1);\n\tint prev;\n\tcin >> prev;\n\tfor (int i = 0; i < (n - 1); ++i)\n\t{\n\t\tint t;\n\t\tcin >> t;\n\t\tv[i] = t - prev - 1;\n\t\tprev = t;\n\t}\n\tsort(v.begin(), v.end());\n\tint ans = n;\n\tfor (int i = 0; i < (n-k); ++i)\n\t{\n\t\tans += v[i];\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3144, "score_of_the_acc": -1, "final_rank": 13 } ]
aoj_0645_cpp
森林伐採 (Deforestation) 問題文 JOI 王国には広大な森林がある.森林は長方形の形をしており,南北に H マス,東西に W マスのマス目状に分けられている.北から i マス目,西から j マス目( 1 ≦ i ≦ H, 1 ≦ j ≦ W )の領域には A_{i,j} 本の木が生えている.ただし,北西の端の領域には木材加工工場があり,木が生えていない.すなわち, A_{1,1}=0 である. 木が生えていない領域には人が立ち入ることが出来る.また人は東西南北に隣接する領域に,その領域に木が生えていなければ,移動することができる.森林の外に出ることはできない.JOI 君は JOI 王国の公共事業として,木を伐採し,北西の端の領域と南東の端の領域を,相互に行き来可能にしたい. 木の伐採は以下のようにして行う.はじめ,JOI 君は木材加工工場のある北西の端の領域にいる.JOI 君は,現在いる領域と東西南北に隣接する木の生えていない領域に 1 分で移動することができる.また,東西南北に隣接する木の生えている領域から, 1 分で木を 1 本伐採することができる.ただし,木を 1 本伐採したら,そのたびに北西の端の領域にある木材加工工場まで伐採した木を運ばなければならない.木を運んでいる間も,JOI 君の移動速度は変わらない.木を運んでいる間は,他の木を伐採することはできない. 条件を満たすように木を伐採するのにかかる時間の最小値を求めよ.ただし,伐採にかかる時間とは,最後に伐採した木を,木材加工工場に運ぶまでの時間とする. 制約 1 \leq H \leq 30 1 \leq W \leq 30 (H, W) ≠ (1, 1) 0 \leq A_{i,j} ≦ 10000 ( 1 \leq i \leq H, 1 \leq j \leq W ) A_{1,1}=0 入力・出力 入力 入力は以下の形式で標準入力から与えられる. H W A_{1,1} ... A_{1,W} : A_{H,1} ... A_{H,W} 出力 条件を満たすように木を伐採するのにかかる時間の最小値を 1 行で出力せよ. 入出力例 入力例 1 2 3 0 1 2 3 4 5 出力例 1 32 北から i マス目,西から j マス目の領域を (i, j) で表す. まず (1, 2) の木を伐採する.これには 1 分かかる. 次に (1, 3) の木をすべて伐採する. 1 本伐採するのに, (1,1) から東に 1 マス進み, (1, 3) の木を伐採し,西に 1 マス進んで (1,1) に戻ればいいので, 3 分かかる.よってこれには 2 × 3 = 6 分かかる. 次に (2, 3) の木をすべて伐採する. 1 本伐採するのに, (1,1) から東に 2 マス進み, (2, 3) の木を伐採し,西に 2 マス進んで (1,1) に戻ればいいので, 5 分かかる.よってこれには 5 × 5 = 25 分かかる. 全部で 1 + 6 + 25 = 32 分かかる.これより少ない時間で,条件を満たすように木を伐採することはできないので, 32 を出力する. 入力例 2 2 5 0 5 0 0 0 0 0 0 9 1 出力例 2 13 (2, 5) の木のみを伐採すればよい. 入力例 3 2 5 0 2 0 0 0 0 0 0 9 1 出力例 3 11 まず, (1, 2) の木を伐採して,次に (2, 5) の木を伐採すればよい. 情報オリンピック日本委員会作 『第 17 回日本情報オリンピック JOI 2017/2018 予選競技課題』
[ { "submission_id": "aoj_0645_10853882", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\nconst int INF = 1e9;\nconst ll LINF = 1e18;\ntemplate<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << \"(\" << o.first << \",\" << o.second << \")\"; return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << \" \";} return out; }\ntemplate<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }\ntemplate<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << \"{ \"; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << \":\" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << \", \"; } out << \" }\"; return out; }\n\n/*\n <url:>\n 問題文============================================================\n =================================================================\n 解説=============================================================\n ================================================================\n */\n\nint d[4] = {1,0,-1,0};\nll H,W;\nusing Items1 = tuple<ll,ll,ll>;\nusing Items2 = tuple<ll,ll,ll,ll>;\nmap<Items1,ll> mpT;\nll solve(){\n ll res = LINF;\n cin >> H >> W;\n vector<vector<ll>> masu(H+2,vector<ll>(W+2,INF));\n for(int i = 1; i <= H;i++){\n for(int j = 1; j <= W;j++){\n cin >> masu[i][j];\n }\n }\n vector<vector<ll>> dist(H+2,vector<ll>(W+2,INF));\n mpT[Items1(1,1,0)] = 1;\n priority_queue<Items2> q; q.push(Items2(0,1,1,0));\n while(q.size()){\n ll x,y,D,T; tie(T,x,y,D) = q.top(); q.pop();\n if(D > H*W) continue;\n T = -T;\n for(int k = 0; k < 4;k++){\n ll nx = x + d[k],ny = y + d[k^1];\n if(masu[nx][ny] == INF) continue;\n ll Add = masu[nx][ny] + masu[nx][ny]*D*2 + 1;\n if(nx == H && ny == W){\n res = min(res,T + Add - D - 1);\n // return res;\n continue;\n }\n if(mpT.count(Items1(nx,ny,D+1))){\n if(mpT[Items1(nx,ny,D+1)] <= T + Add){\n continue;\n }\n }\n mpT[Items1(nx,ny,D+1)] = T + Add;\n q.push(Items2(-(T+Add),nx,ny,D+1));\n }\n }\n return res;\n}\nint main(void) {\n cin.tie(0); ios_base::sync_with_stdio(false);\n cout << solve() << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 38360, "score_of_the_acc": -1.7173, "final_rank": 19 }, { "submission_id": "aoj_0645_9669896", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\ntypedef pair<ll,pi> ppi;\ntypedef pair<ll,ppi> pppi;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef vector<vvi> vvvi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define LB(A,x) (lower_bound(ALL(A),x)-A.begin())\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\nint main(){\n int H,W;cin>>H>>W;\n vector<vector<ll>>A(H,vector<ll>(W));\n REP(i,H)REP(j,W)cin>>A[i][j];\n vvvi D(H,vvi(W,vi(1000,1e18)));\n D[0][0][0]=0;\n priority_queue<pppi,vector<pppi>,greater<pppi>>Q;\n Q.emplace(pppi(0,ppi(0,pi(0,0))));\n while(!Q.empty()){\n auto[d,p]=Q.top();Q.pop();\n auto[x,_p]=p;\n auto[y,c]=_p;\n if(d!=D[x][y][c])continue;\n d++;\n if(x&&chmin(D[x-1][y][c+1],d+A[x-1][y]*(1+2*c)))Q.emplace(pppi(D[x-1][y][c+1],ppi(x-1,pi(y,c+1))));\n if(x+1<H&&chmin(D[x+1][y][c+1],d+A[x+1][y]*(1+2*c)))Q.emplace(pppi(D[x+1][y][c+1],ppi(x+1,pi(y,c+1))));\n if(y&&chmin(D[x][y-1][c+1],d+A[x][y-1]*(1+2*c)))Q.emplace(pppi(D[x][y-1][c+1],ppi(x,pi(y-1,c+1))));\n if(y+1<W&&chmin(D[x][y+1][c+1],d+A[x][y+1]*(1+2*c)))Q.emplace(pppi(D[x][y+1][c+1],ppi(x,pi(y+1,c+1))));\n }\n ll ans=1e18;\n REP(c,1000)chmin(ans,D[H-1][W-1][c]-c);\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 19996, "score_of_the_acc": -0.4437, "final_rank": 16 }, { "submission_id": "aoj_0645_9568858", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll H,W;\n cin>>H>>W;\n vector<vector<ll>> A(H,vector<ll>(W));\n for(int h=0;h<H;h++)for(int w=0;w<W;w++)cin>>A[h][w];\n vector<vector<vector<ll>>> DP(H,vector<vector<ll>>(W,vector<ll>(H*W+1,1e18)));\n DP[0][0][0]=0;\n vector<int> dx={1,0,-1,0},dy={0,1,0,-1};\n for(int d=0;d<H*W;d++){\n for(int h=0;h<H;h++){\n for(int w=0;w<W;w++){\n for(int e=0;e<4;e++){\n int nh=h+dy[e];\n int nw=w+dx[e];\n if(nh<0||nw<0||nh>=H||nw>=W)continue;\n DP[nh][nw][d+1]=min(DP[nh][nw][d+1],DP[h][w][d]+1+(2*d+1)*A[nh][nw]);\n }\n }\n }\n }\n ll an=1e18;\n for(int d=0;d<H*W;d++)an=min(an,DP[H-1][W-1][d]-d);\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9752, "score_of_the_acc": -0.1271, "final_rank": 3 }, { "submission_id": "aoj_0645_6994423", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0645.cc: 森林伐採 (Deforestation)\n */\n\n#include<cstdio>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_H = 30;\nconst int MAX_W = 30;\nconst int MAX_HW = MAX_H * MAX_W;\nconst int MAX_GN = MAX_HW * MAX_HW;\nconst long long LINF = 1LL << 62;\n\nconst int dys[] = { 0, 1, 0, -1 }, dxs[] = { 1, 0, -1, 0 };\n\n/* typedef */\n\ntypedef long long ll;\ntypedef pair<ll,int> pli;\n\n/* global variables */\n\nint as[MAX_H][MAX_W];\nll ds[MAX_GN];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int h, w;\n scanf(\"%d%d\", &h, &w);\n for (int i = 0; i < h; i++)\n for (int j = 0; j < w; j++) scanf(\"%d\", as[i] + j);\n\n int hw = h * w, gn = hw * hw;\n fill(ds, ds + gn, LINF);\n ds[0] = 0;\n\n priority_queue<pli> q;\n q.push(pli(0, 0));\n\n ll mind = LINF;\n while (! q.empty()) {\n pli ue = q.top(); q.pop();\n ll ud = -ue.first;\n int u = ue.second;\n if (ds[u] != ud) continue;\n\n int up = u / hw, umd = u % hw;\n int uy = up / w, ux = up % w;\n //printf(\"%d,%d,%d = %lld\\n\", uy, ux, umd, ud);\n if (up == hw - 1) { mind = ud; break; }\n if (umd == hw - 1) continue;\n\n for (int di = 0; di < 4; di++) {\n int vy = uy + dys[di], vx = ux + dxs[di];\n if (vy >= 0 && vy < h && vx >= 0 && vx < w) {\n\tll vd = ud + (ll)as[vy][vx] * (1 + umd * 2);\n\tint v = (vy * w + vx) * hw + (umd + 1);\n\tif (ds[v] > vd) {\n\t ds[v] = vd;\n\t q.push(pli(-vd, v));\n\t}\n }\n }\n }\n\n printf(\"%lld\\n\", mind);\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 15100, "score_of_the_acc": -0.29, "final_rank": 9 }, { "submission_id": "aoj_0645_6113204", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w);\n vector2d(int,A,h,w);\n in(A);\n vector3d(ll,dist,h,w,h*w,INF2);\n rpriority_queue<tuple<ll,int,int,int>> pq;\n dist[0][0][0]=0;\n pq.push({0,0,0,0});\n int y,x,t;\n ll c;\n while(!pq.empty()){\n tie(c,y,x,t)=pq.top();\n pq.pop();\n if(t+1==h*w)continue;\n for(int i=0;i<4;i++){\n int dy=(i==0)-(i==1);\n int dx=(i==2)-(i==3);\n if(y+dy<0||y+dy>=h||x+dx<0||x+dx>=w)continue;\n if(c+(ll)(2*t+1)*A[y+dy][x+dx]<dist[y+dy][x+dx][t+1]){\n dist[y+dy][x+dx][t+1]=c+(ll)(2*t+1)*A[y+dy][x+dx];\n pq.push({dist[y+dy][x+dx][t+1],y+dy,x+dx,t+1});\n }\n }\n }\n ll ans=INF2;\n rep(i,h*w)chmin(ans,dist[h-1][w-1][i]);\n out(ans);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 17212, "score_of_the_acc": -0.3512, "final_rank": 11 }, { "submission_id": "aoj_0645_5745597", "code_snippet": "#pragma region my_template\n#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <cmath>\n#include <deque>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <iterator>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\nusing namespace std;\nusing ll = long long;\nusing pi = pair<int, int>;\nusing pl = pair<ll, ll>;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\n\n#define range(i, l, r) for(int i = (int)(l); i < (int)(r); i++)\n#define rrange(i, l, r) for(int i = (int)(r)-1; i >= (int)(l); i--)\n#define rep(i, n) range(i, 0, n)\n#define rrep(i, n) rrange(i, 0, n)\n#define len(a) ((int)(a).size())\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define uni(a) (a).erase(unique(all(a)), (a).end());\n#define append push_back\n#define mp make_pair\n#define elif else if\n\nconstexpr int MOD = 1e9+7;\n//constexpr int MOD = 998244353;\nconstexpr int INF = 1e9;\nconstexpr ll LINF = 1e18;\n\ntemplate<typename T>\nistream &operator >> (istream &in, vector<T> &a){\n for(T &x: a) in >> x;\n return in;\n}\ntemplate<typename T, typename U>\nistream &operator >> (istream &in, pair<T, U> &a){\n in >> a.first >> a.second;\n return in;\n}\ntemplate<typename T>\nostream &operator << (ostream &out, const vector<T> &a) {\n rep(i, len(a)) out << a[i] << (i == len(a)-1 ? \"\" : \" \");\n return out;\n}\ntemplate<typename T, typename U>\nostream &operator << (ostream &out, const pair<T, U> &a){\n out << a.first << \" \" << a.second;\n return out;\n}\ninline void print() { cout << \"\\n\"; }\ntemplate <typename T, typename ...U>\ninline void print(const T &t, const U &...u) {\n cout << t;\n if (sizeof...(u)) cout << \" \";\n print(u...);\n}\ntemplate<typename T> inline bool chmax(T &a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<typename T> inline bool chmin(T &a, T b) { if (a > b) { a = b; return 1; } return 0; }\n#pragma endregion\n\nvector<pi> arr4 = {{-1, 0}, {0, -1}, {1, 0}, {0, 1}};\n\nll dp[910][31][31];\nvoid solve() {\n int h, w; cin >> h >> w;\n int n = h*w;\n vvl a(h, vl(w)); cin >> a;\n rep(i, 910) rep(j, 31) rep(k, 31) dp[i][j][k] = LINF;\n dp[0][0][0] = 0;\n\n rep(i, n) rep(y, h) rep(x, w) {\n if (dp[i][y][x] == LINF) continue;\n chmin(dp[i+1][y][x], dp[i][y][x]);\n for (auto [dy, dx]: arr4) {\n int ny = y+dy, nx = x+dx;\n if (ny < 0 or nx < 0 or ny >= h or nx >= w) continue;\n chmin(dp[i+1][ny][nx], dp[i][y][x] + (i*2+1)*a[ny][nx]);\n }\n }\n\n print(dp[n-1][h-1][w-1]);\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n //cout << fixed << setprecision(15);\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 10308, "score_of_the_acc": -0.1386, "final_rank": 4 }, { "submission_id": "aoj_0645_5329761", "code_snippet": "// clang-format off\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = int64_t;\nusing ld = long double;\nusing Pi = pair<int, int>;\nusing Pl = pair<ll, ll>;\nusing Vi = vector<int>;\nusing Vl = vector<ll>;\n#define FOR(i, m, n) for(int i = (m); i < (n); ++i)\n#define FORR(i, m, n) for(int i = (m)-1; i >= (n); --i)\n#define rep(i, n) FOR(i, 0, n)\n#define repn(i, n) FOR(i, 1, n+1)\n#define repr(i, n) FORR(i, n, 0)\n#define repnr(i, n) FORR(i, n+1, 1)\n#define all(s) (s).begin(), (s).end()\ntemplate <class T, class U>\nbool chmax(T &a, const U b) { return a < b ? a = b, true : false; }\ntemplate <class T, class U>\nbool chmin(T &a, const U b) { return b < a ? a = b, true : false; }\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &v) { for (T &i : v) is >> i; return is; }\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) { for (const T &i : v) os << i << ' '; return os; }\ntemplate <class Head, class... Tail>\nvoid co(Head&& head, Tail&&... tail) {\n if constexpr(sizeof...(tail)==0) cout<<head<<'\\n'; else cout<<head<<' ',co(forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head&& head, Tail&&... tail) {\n if constexpr(sizeof...(tail)==0) cerr<<head<<'\\n'; else cerr<<head<<' ',ce(forward<Tail>(tail)...);\n}\ntemplate<typename T, typename... Args>\nauto make_vector(T x, int arg, Args ...args) {\n if constexpr(sizeof...(args)==0) return vector<T>(arg, x); else return vector(arg,make_vector<T>(x, args...));\n}\nvoid sonic() { ios::sync_with_stdio(false); cin.tie(nullptr); }\nvoid setp(const int n) { cout << fixed << setprecision(n); }\nconstexpr int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconst double PI = acos(-1);\n\n// clang-format on\n\nstruct Pos {\n int x, y;\n\n Pos &operator+=(const Pos &rhs) {\n x += rhs.x, y += rhs.y;\n return *this;\n }\n};\n\nvector<Pos> dv = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};\n\nstruct S {\n int x, y, d;\n\n bool operator<(const S &rhs) const {\n return d > rhs.d;\n }\n};\n\nint main(void) {\n int h, w;\n cin >> h >> w;\n auto a = make_vector(0, h, w);\n cin >> a;\n\n auto in_board = [&](int x, int y) {\n return x >= 0 && x < h && y >= 0 && y < w;\n };\n\n auto dp = make_vector(Inf, h, w, 1000);\n dp[0][0][0] = 0;\n priority_queue<S> pq;\n pq.push(S{0, 0, 0});\n while (!pq.empty()) {\n auto [x, y, d] = pq.top();\n pq.pop();\n for (auto p : dv) {\n Pos q = {x, y};\n q += p;\n if (!in_board(q.x, q.y))\n continue;\n if (chmin(dp[q.x][q.y][d + 1], dp[x][y][d] + a[q.x][q.y] * (2 * d + 1))) {\n pq.push({q.x, q.y, d + 1});\n }\n }\n }\n co(*min_element(all(dp[h - 1][w - 1])));\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6904, "score_of_the_acc": -0.121, "final_rank": 2 }, { "submission_id": "aoj_0645_5174399", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define rrep(i,n) for(int (i)=1;i<=(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint h, w;\nint a[50][50];\nint dp[50][50][2500];\n\nint dx[] = {-1, 0, 1, 0};\nint dy[] = {0, -1, 0, 1};\n\nsigned main() {\n\tcin.tie(nullptr);\n\tcout.tie(nullptr);\n\tios::sync_with_stdio(false);\n\t//cout << fixed << setprecision(15);\n\t\n\tcin >> h >> w;\n\trep(i, h) {\n\t\trep(j, w) cin >> a[i][j];\n\t}\n\tFill(dp, MOD);\n\tdp[0][0][0] = 0;\n\trep(i, h*w) {\n\t\trep(y, h) {\n\t\t\trep(x, w) {\n\t\t\t\trep(d, 4) {\n\t\t\t\t\tint nx = x + dx[d];\n\t\t\t\t\tint ny = y + dy[d];\n\t\t\t\t\tif(nx < 0 || ny < 0 || w <= nx || h <= ny) continue;\n\t\t\t\t\tchmin(dp[ny][nx][i+1], dp[y][x][i] + a[ny][nx]*(2*i+1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = INF;\n\trep(i, h*w) {\n\t\tchmin(ans, dp[h-1][w-1][i]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 52064, "score_of_the_acc": -1, "final_rank": 18 }, { "submission_id": "aoj_0645_4955814", "code_snippet": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <map>\n#include <set>\n#include <numeric>\n#include <iomanip>\n#include <stack>\n#include <tuple>\n#include <complex>\n\nusing namespace std;\n\nusing ll = long long;\n\nconstexpr ll infll = 1LL << 60;\n\nconstexpr int dx[] = { -1, 0, 1, 0 };\nconstexpr int dy[] = { 0, 1, 0, -1 };\n\nint main() {\n\n int h, w;\n cin >> h >> w;\n vector<vector<int>> a(h, vector<int>(w));\n for (int i = 0; i < h; ++i) {\n for (int j = 0; j < w; ++j) {\n cin >> a[i][j];\n }\n }\n\n\n // dist[i][j][k] := (i, j) のマスに k 距離で行けるようにする最小コスト\n // 拡張ダイクストラ\n\n constexpr int kMax = 1000;\n\n vector dp(h, vector(w, vector(h * w + 1, infll)));\n dp[0][0][0] = 0;\n\n using T = tuple<ll, int, int, int>;\n priority_queue<T, vector<T>, greater<T>> que;\n que.emplace(0, 0, 0, 0);\n\n while (que.size()) {\n auto [cost, x, y, dist] = que.top();\n que.pop();\n\n if (dp[y][x][dist] < cost) continue;\n\n for (int k = 0; k < 4; ++k) {\n int ty = y + dy[k];\n int tx = x + dx[k];\n\n if (ty < 0 || ty >= h) continue;\n if (tx < 0 || tx >= w) continue;\n\n if (dist >= w * h) continue;\n\n ll new_cost = cost + a[ty][tx] * dist * 2 + 1 + a[ty][tx];\n\n if (dp[ty][tx][dist + 1] > new_cost) {\n //cout << ty << \" \" << tx << \" \" << dist + 1 << endl;\n dp[ty][tx][dist + 1] = new_cost;\n que.emplace(new_cost, tx, ty, dist + 1);\n }\n }\n }\n\n ll ans = infll;\n for (int i = 0; i < h * w + 1; ++i) {\n //out << dp[h - 1][w - 1][i] << endl;\n ans = min(ans, dp[h - 1][w - 1][i] - i);\n }\n\n cout << ans << endl;\n\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 16976, "score_of_the_acc": -0.3638, "final_rank": 12 }, { "submission_id": "aoj_0645_4953548", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nconstexpr ll INF = 1e18;\n\nusing tup = tuple<ll,int,int,int>;\n\nll dp[910][35][35];\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n for(int i=0; i<910; i++){\n for(int j=0; j<35; j++){\n for(int k=0; k<35; k++){\n dp[i][j][k] = INF;\n }\n }\n }\n int H,W;\n cin >> H >> W;\n vector<vector<int>> G(H,vector<int>(W));\n for(int i=0; i<H; i++){\n for(int j=0; j<W; j++){\n cin >> G[i][j];\n }\n }\n vector<int> dx = {0,-1,0,1};\n vector<int> dy = {-1,0,1,0};\n priority_queue<tup,vector<tup>,greater<>> que;\n que.emplace(0,0,0,0);\n dp[0][0][0] = 0;\n while(que.size()){\n ll cost;\n int mn,y,x;\n tie(cost,mn,y,x) = que.top();\n que.pop();\n if(mn == 900) continue;\n if(dp[mn][y][x] < cost) continue;\n for(int k=0; k<4; k++){\n int ny = y + dy[k];\n int nx = x + dx[k];\n if(ny<0 || ny>=H || nx<0 || nx>=W) continue;\n ll ncost = (ll)G[ny][nx] * mn * 2 + G[ny][nx];\n if(dp[mn+1][ny][nx] > cost + ncost){\n dp[mn+1][ny][nx] = cost + ncost;\n que.emplace(dp[mn+1][ny][nx],mn+1,ny,nx);\n }\n }\n }\n ll ans = INF;\n for(int i=0; i<910; i++){\n if(ans > dp[i][H-1][W-1]){\n ans = dp[i][H-1][W-1];\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 19788, "score_of_the_acc": -0.4043, "final_rank": 14 }, { "submission_id": "aoj_0645_4952845", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define fast() ios::sync_with_stdio(false), cin.tie(nullptr)\n\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nusing ll = long long;\nvector<vector<vector<ll>>> dijkstra(int H, int W, const vector<vector<ll>> &a)\n{\n\tconst auto inf = numeric_limits<ll>::max();\n\tvector<vector<vector<ll>>> dist(H, vector<vector<ll>>(W, vector<ll>(1000, inf)));\n\tdist[0][0][0] = 0;\n\tusing point = pair<int, int>;\n\tusing T = pair<ll, pair<point, int>>;\n\t// 時間 位置 回数\n\tpriority_queue<T, vector<T>, greater<T>> pq;\n\tpq.push({0, {{0, 0}, 0}});\n\twhile (!pq.empty())\n\t{\n\t\tauto v = pq.top();\n\t\tll time = v.first;\n\t\tint y, x, cnt = v.second.second;\n\t\ttie(y, x) = v.second.first;\n\n\t\tpq.pop();\n\t\tif (dist[y][x][cnt] < time)\n\t\t\tcontinue;\n\n\t\tif (cnt >= H * W)\n\t\t\tcontinue;\n\n\t\tfor (int i = 0; i < 4; i++)\n\t\t{\n\t\t\tint ny = y + dy[i], nx = x + dx[i];\n\t\t\tif (ny < 0 || ny >= H || nx < 0 || nx >= W)\n\t\t\t\tcontinue;\n\t\t\tll next_time = time + a[ny][nx] * 2 * cnt + 1 + a[ny][nx];\n\t\t\tif (dist[ny][nx][cnt + 1] <= next_time)\n\t\t\t\tcontinue;\n\t\t\tdist[ny][nx][cnt + 1] = next_time;\n\t\t\tpq.push({next_time, {{ny, nx}, cnt + 1}});\n\t\t}\n\t}\n\treturn dist;\n}\n\nint main()\n{\n\tint H, W;\n\tcin >> H >> W;\n\tvector<vector<ll>> a(H, vector<ll>(W));\n\n\tfor (int i = 0; i < H; i++)\n\t{\n\t\tfor (int j = 0; j < W; j++)\n\t\t{\n\t\t\tcin >> a[i][j];\n\t\t}\n\t}\n\n\tauto dist = dijkstra(H, W, a);\n\tll ans = 1e18;\n\tfor (int i = 0; i < 1000; i++)\n\t{\n\t\tans = min(dist[H - 1][W - 1][i] - i, ans);\n\t}\n\n\tcout << ans << \"\\n\";\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 17892, "score_of_the_acc": -0.4003, "final_rank": 13 }, { "submission_id": "aoj_0645_4952782", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define INF 1020304050\nusing T = tuple<int,int,int,int>;\n\nint main() {\n \n ios::sync_with_stdio(false);\n cin.tie(0);\n int h,w;\n cin >> h >> w;\n vector<vector<int>> a(h,vector<int>(w));\n for (int i=0;i<h;i++) {\n for (int j=0;j<w;j++) {\n cin >> a[i][j];\n }\n }\n vector<vector<vector<int>>> ans(h,vector<vector<int>>(w,vector<int>(h*w+1,INF)));\n ans[0][0][0] = 0;\n priority_queue<T,vector<T>,greater<T>> pq;\n pq.push(make_tuple(0,0,0,0));\n while (!pq.empty()) {\n T nowt = pq.top();\n pq.pop();\n int val = get<0>(nowt);\n int nh = get<1>(nowt);\n int nw = get<2>(nowt);\n int dist = get<3>(nowt);\n if (dist == h*w) continue;\n if (val > ans[nh][nw][dist]) continue;\n vector<int> dh = {0,1,0,-1};\n vector<int> dw = {1,0,-1,0};\n for (int i=0;i<4;i++) {\n int toh = nh+dh[i];\n int tow = nw+dw[i];\n if (toh < 0 || toh >= h || tow < 0 || tow >= w) continue;\n int kans = val+(2*dist+1)*a[toh][tow];\n if (ans[toh][tow][dist+1] > kans) {\n ans[toh][tow][dist+1] = kans;\n pq.push(make_tuple(kans,toh,tow,dist+1));\n }\n }\n }\n int tans = INF;\n for (int i=0;i<=h*w;i++) {\n tans = min(tans,ans[h-1][w-1][i]);\n }\n cout << tans << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12016, "score_of_the_acc": -0.2615, "final_rank": 7 }, { "submission_id": "aoj_0645_4952639", "code_snippet": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define rep(i, s, n) for (int i = (int)(s); i < (int)(n); i++)\n\nint h,w;\nll ans = 1000000000;\n\nint dfs(int h1,int w1,vector<vector<ll>>& m, vector<vector<ll>>& s,ll d,ll t){\n if (h1==h-1 && w1==w-1){\n ans = min(ans,t-d);\n return 0;\n }\n if (h1-1>=0 && s[h1-1][w1]>=t+(2*d+1)*m[h1-1][w1]+1){\n s[h1-1][w1] = t+(2*d+1)*m[h1-1][w1]+1;\n dfs(h1-1,w1,m,s, d+1 , t+(2*d+1)*m[h1-1][w1]+1 );\n }\n if (h1+1<h && s[h1+1][w1]>=t+(2*d+1)*m[h1+1][w1]+1){\n s[h1+1][w1] = t+(2*d+1)*m[h1+1][w1]+1;\n dfs(h1+1,w1,m,s, d+1 , t+(2*d+1)*m[h1+1][w1]+1 );\n }\n if (w1+1<w && s[h1][w1+1] >= t+(2*d+1)*m[h1][w1+1]+1){\n s[h1][w1+1] = t+(2*d+1)*m[h1][w1+1]+1;\n dfs(h1,w1+1,m,s, d+1 , t+(2*d+1)*m[h1][w1+1]+1 );\n }\n if (w1-1>=0 && s[h1][w1-1] >= t+(2*d+1)*m[h1][w1-1]+1){\n s[h1][w1-1] = t+(2*d+1)*m[h1][w1-1]+1;\n dfs(h1,w1-1,m,s, d+1 , t+(2*d+1)*m[h1][w1-1]+1 );\n }\n return 0;\n}\n\nint main(){\n cin>>h>>w;\n vector<vector<ll>> m(h,vector<ll>(w,0)),s(h,vector<ll>(w,10000000000));\n rep(i,0,h){\n rep(j,0,w){\n cin>>m[i][j];\n }\n }\n s[0][0] = 0;\n dfs(0,0,m,s,0,0);\n cout<<ans<<endl;\n}", "accuracy": 0.6136363636363636, "time_ms": 420, "memory_kb": 3592, "score_of_the_acc": -0.7193, "final_rank": 20 }, { "submission_id": "aoj_0645_4952501", "code_snippet": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <tuple>\n#include <queue>\nusing namespace std;\n\nint main(){\n int h, w;\n cin >> h >> w;\n vector<vector<long long>> A(h,vector<long long>(w));\n for(int i = 0; i < h; ++i){\n for(int j = 0; j < w; ++j){\n cin >> A[i][j];\n }\n }\n const long long INF = 1e18;\n vector dp(h,vector(w,vector(h*w,INF)));\n dp[0][0][0] = 0;\n const int dx[] = {1,0,-1,0}, dy[] = {0,1,0,-1};\n using tup = tuple<long long,int,int,int>;\n priority_queue<tup,vector<tup>,greater<>> pq;\n pq.emplace(0,0,0,0);// time, x, y, dist\n while(pq.size()){\n auto [t, i, j, k] = pq.top();\n pq.pop();\n if(dp[i][j][k] < t) continue;\n \n for(int l = 0; l < 4; ++l){\n int i_ = i + dx[l];\n int j_ = j + dy[l];\n int k_ = k + 1;\n if(i_ < 0 or i_ >= h) continue;\n if(j_ < 0 or j_ >= w) continue;\n if(k_ >= h*w) continue;\n long long t_ = min(dp[i_][j_][k_],\n dp[i][j][k]+A[i_][j_]*(2*k+1)+1);\n if(t_ < dp[i_][j_][k_]){\n pq.emplace(t_,i_,j_,k_);\n dp[i_][j_][k_] = t_;\n }\n }\n }\n\n long long ans = INF, a = A[h-1][w-1];\n for(int i = 0; i < h*w; ++i){\n ans = min(ans,dp[h-1][w-1][i]-i);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 16280, "score_of_the_acc": -0.3495, "final_rank": 10 }, { "submission_id": "aoj_0645_4952429", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nconstexpr ll INF = 1e18;\n\nusing tup = tuple<ll,int,int,int>;\n\nll dp[910][35][35];\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n for(int i=0; i<910; i++){\n for(int j=0; j<35; j++){\n for(int k=0; k<35; k++){\n dp[i][j][k] = INF;\n }\n }\n }\n int H,W;\n cin >> H >> W;\n vector<vector<int>> G(H,vector<int>(W));\n for(int i=0; i<H; i++){\n for(int j=0; j<W; j++){\n cin >> G[i][j];\n }\n }\n vector<int> dx = {0,-1,0,1};\n vector<int> dy = {-1,0,1,0};\n priority_queue<tup,vector<tup>,greater<>> que;\n que.emplace(0,0,0,0);\n dp[0][0][0] = 0;\n while(que.size()){\n ll cost;\n int mn,y,x;\n tie(cost,mn,y,x) = que.top();\n que.pop();\n if(mn == 900) continue;\n if(dp[mn][y][x] < cost) continue;\n for(int k=0; k<4; k++){\n int ny = y + dy[k];\n int nx = x + dx[k];\n if(ny<0 || ny>=H || nx<0 || nx>=W) continue;\n ll ncost = (ll)G[ny][nx] * mn * 2 + G[ny][nx];\n if(dp[mn+1][ny][nx] > cost + ncost){\n dp[mn+1][ny][nx] = cost + ncost;\n que.emplace(dp[mn+1][ny][nx],mn+1,ny,nx);\n }\n }\n }\n ll ans = INF;\n for(int i=0; i<910; i++){\n if(ans > dp[i][H-1][W-1]){\n ans = dp[i][H-1][W-1];\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 19896, "score_of_the_acc": -0.4065, "final_rank": 15 }, { "submission_id": "aoj_0645_4645346", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\nusing namespace std;\ntypedef long long int ll;\nusing ull = unsigned long long;\n\nint dp[33][33][901];\nint a[33][33];\n\nint dx[]={1,-1,0,0};\nint dy[]={0,0,1,-1};\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int h,w; cin >> h >> w;\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n cin >> a[i][j];\n for(int k=0;k<901;k++){\n dp[i][j][k]=1e9;\n }\n }\n }\n dp[0][0][0]=0;\n for(int d=0;d<h*w;d++){\n for(int i=0;i<h;i++){\n for(int j=0;j<w;j++){\n for(int k=0;k<4;k++){\n int nx=i+dx[k],ny=j+dy[k];\n if(0<=nx&&nx<h&&0<=ny&&ny<w){\n dp[nx][ny][d+1]=min(dp[nx][ny][d+1],dp[i][j][d]+a[nx][ny]*(2*d+1));\n }\n }\n }\n }\n }\n int res=1e9;\n for(int i=0;i<=h*w;i++){\n res=min(res,dp[h-1][w-1][i]);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6424, "score_of_the_acc": -0.0584, "final_rank": 1 }, { "submission_id": "aoj_0645_4229519", "code_snippet": "// #pragma GCC target(\"avx\") // CPU 処理並列化\n// #pragma GCC optimize(\"O3\") // CPU 処理並列化\n// #pragma GCC optimize(\"unroll-loops\") // 条件処理の呼び出しを減らす\n// #define BEGIN_STACK_EXTEND(size) void * stack_extend_memory_ = malloc(size);void * stack_extend_origin_memory_;char * stack_extend_dummy_memory_ = (char*)alloca((1+(int)(((long long)stack_extend_memory_)&127))*16);*stack_extend_dummy_memory_ = 0;asm volatile(\"mov %%rsp, %%rbx\\nmov %%rax, %%rsp\":\"=b\"(stack_extend_origin_memory_):\"a\"((char*)stack_extend_memory_+(size)-1024));\n// #define END_STACK_EXTEND asm volatile(\"mov %%rax, %%rsp\"::\"a\"(stack_extend_origin_memory_));free(stack_extend_memory_);\n\n#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<string>\n#include<string.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stdlib.h>\n#include<cassert>\n#include<time.h>\n#include<bitset>\n#include<numeric>\n#include<unordered_set>\n#include<unordered_map>\n#include<complex>\nusing namespace std;\nconst long long mod=1000000007;\nconst long long inf=mod*mod;\nconst long long d2=(mod+1)/2;\nconst long double EPS=1e-9;\nconst double INF=1e+10;\nconst double PI=acos(-1.0);\nconst int C_SIZE = 3100000;\nconst int UF_SIZE = 3100000;\nnamespace{\n\tlong long fact[C_SIZE];\n\tlong long finv[C_SIZE];\n\tlong long inv[C_SIZE];\n\tlong long Comb(int a,int b){\n\t \tif(a<b||b<0)return 0;\n\t \treturn fact[a]*finv[b]%mod*finv[a-b]%mod;\n\t}\n\tvoid init_C(int n){\n\t\tfact[0]=finv[0]=inv[1]=1;\n\t\tfor(int i=2;i<n;i++){\n\t\t\tinv[i]=(mod-(mod/i)*inv[mod%i]%mod)%mod;\n\t\t}\n\t\tfor(int i=1;i<n;i++){\n\t\t\tfact[i]=fact[i-1]*i%mod;\n\t\t\tfinv[i]=finv[i-1]*inv[i]%mod;\n\t\t}\n\t}\n\tlong long pw(long long a,long long b){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%mod;\n\t\t\ta=a*a%mod;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tlong long pw_mod(long long a,long long b,long long M){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%M;\n\t\t\ta=a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint pw_mod_int(int a,int b,int M){\n\t\tif(a<0)return 0;\n\t\tif(b<0)return 0;\n\t\tint ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=(long long)ret*a%M;\n\t\t\ta=(long long)a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint ABS(int a){return max(a,-a);}\n\tlong long ABS(long long a){return max(a,-a);}\n\tdouble ABS(double a){return max(a,-a);}\n\tint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\n\tint UF[UF_SIZE];\n\tvoid init_UF(int n){\n\t\tfor(int i=0;i<n;i++)UF[i]=-1;\n\t}\n\tint FIND(int a){\n\t\tif(UF[a]<0)return a;\n\t\treturn UF[a]=FIND(UF[a]);\n\t}\n\tvoid UNION(int a,int b){\n\t\ta=FIND(a);b=FIND(b);if(a==b)return;\n\t\tif(UF[a]>UF[b])swap(a,b);\n\t\tUF[a]+=UF[b];UF[b]=a;\n\t}\n}\n// ここから編集しろ\nint p[40][40];\nint ijk[40][40][1600];\nint v[40][40][1600];\nint dx[]={1,0,-1,0};\nint dy[]={0,1,0,-1};\nint main(){\n\tint a,b;scanf(\"%d%d\",&a,&b);\n\tfor(int i=0;i<a;i++){\n\t\tfor(int j=0;j<b;j++)scanf(\"%d\",&p[i][j]);\n\t}\n\tfor(int i=0;i<a;i++)for(int j=0;j<b;j++)for(int k=0;k<1600;k++)\n\t\tijk[i][j][k]=mod;\n\tijk[0][0][0]=0;\n\tpriority_queue<pair<pair<int,int>,pair<int,int> > >Q;\n\tQ.push(make_pair(make_pair(0,0),make_pair(0,0)));\n\twhile(Q.size()){\n\t\tint cost=-Q.top().first.first;\n\t\tint K=Q.top().first.second;\n\t\tint row=Q.top().second.first;\n\t\tint col=Q.top().second.second;\n\t\tQ.pop();\n\t\tif(v[row][col][K])continue;\n\t\tv[row][col][K]=1;\n\t\t// printf(\"%d %d %d: %d\\n\",row,col,K,cost);\n\t\tfor(int i=0;i<4;i++){\n\t\t\tint tr=row+dx[i];\n\t\t\tint tc=col+dy[i];\n\t\t\tif(tr<0||tc<0||tr>=a||tc>=b)continue;\n\t\t\tif(K+1>=1500)continue;\n\t\t\tint toc=cost+p[tr][tc]*(K*2+1);\n\t\t\tif(v[tr][tc][K+1])continue;\n\t\t\tif(ijk[tr][tc][K+1]>toc){\n\t\t\t\tijk[tr][tc][K+1]=toc;\n\t\t\t\tQ.push(make_pair(make_pair(-toc,K+1),make_pair(tr,tc)));\n\t\t\t}\n\t\t}\n\t}\n\tint ret=mod;\n\tfor(int i=0;i<1600;i++)ret=min(ret,ijk[a-1][b-1][i]);\n\tprintf(\"%d\\n\",ret);\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 20372, "score_of_the_acc": -0.5392, "final_rank": 17 }, { "submission_id": "aoj_0645_4131817", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <queue>\n#include <tuple>\n\nconst std::vector<int> dx{-1, 0, 1, 0}, dy{0, -1, 0, 1};\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int h, w;\n std::cin >> h >> w;\n\n auto xss = vec(h, vec(w, 0));\n for (auto& xs : xss) {\n for (auto& x : xs) {\n std::cin >> x;\n }\n }\n\n auto dp = vec(h, vec(w, vec(h * w, INF)));\n dp[0][0][0] = 0;\n\n MinHeap<std::tuple<int, int, int, int>> que;\n que.emplace(dp[0][0][0], 0, 0, 0);\n\n while (!que.empty()) {\n int d, i, j, l;\n std::tie(d, i, j, l) = que.top();\n que.pop();\n if (d > dp[i][j][l]) continue;\n\n for (int k = 0; k < 4; ++k) {\n int ni = i + dx[k],\n nj = j + dy[k],\n nl = l + 1;\n if (ni < 0 || h <= ni || nj < 0 || w <= nj || nl >= h * w) continue;\n\n int nd = d + xss[ni][nj] * (l * 2 + 1);\n if (nd >= dp[ni][nj][nl]) continue;\n\n dp[ni][nj][nl] = nd;\n que.emplace(nd, ni, nj, nl);\n }\n }\n\n int ans = *std::min_element(dp[h - 1][w - 1].begin(), dp[h - 1][w - 1].end());\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 10264, "score_of_the_acc": -0.2254, "final_rank": 6 }, { "submission_id": "aoj_0645_3977878", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n#include \"numeric\"\n#include \"cassert\"\n#include \"functional\"\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000000007;\n//const int MOD = 1000000007;\n//constexpr int MOD = 998244353;\n//constexpr long long int MOD = 998244353;\n\nconstexpr double EPS = 1e-8;\n\n//int N, M, K, H, W, L, R;\nlong long int N, M, K, H, W, L, R;\n\nstruct Node {\n\tint y, x, dis, cost;\n\tNode(const int yy, const int xx, const int d, const int c) {\n\t\ty = yy, x = xx, dis = d, cost = c;\n\t\treturn;\n\t}\n\tbool operator<(const Node&n)const {\n\t\treturn cost > n.cost;\n\t}\n};\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> H >> W;\n\tvector<vector<int>>v(H, vector<int>(W));\n\tfor (auto &i : v)for (auto &j : i)cin >> j;\n\tvector<vector<vector<int>>>dp(H, vector<vector<int>>(W, vector<int>(H*W, MOD)));\n\tdp[0][0][0] = 0;\n\tpriority_queue<Node>PQ;\n\tPQ.push(Node(0, 0, 0, 0));\n\tint dir[] = { 1,0,-1,0,1 };\n\twhile (!PQ.empty()) {\n\t\tauto cn = PQ.top();\n\t\t//cout << cn.y << \" \" << cn.x << \" \" << cn.dis << \" \" << cn.cost << endl;\n\t\tPQ.pop();\n\t\tif (cn.dis == H * W - 1)continue;\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint ny = cn.y + dir[i];\n\t\t\tint nx = cn.x + dir[i + 1];\n\t\t\tif (ny < 0 || nx < 0 || ny >= H || nx >= W)continue;\n\t\t\tif (dp[ny][nx][cn.dis + 1] > cn.cost + v[ny][nx] * ((cn.dis + 0) * 2 + 1)) {\n\t\t\t\tdp[ny][nx][cn.dis + 1] = cn.cost + v[ny][nx] * ((cn.dis + 0) * 2 + 1);\n\t\t\t\tPQ.push(Node(ny, nx, cn.dis + 1, dp[ny][nx][cn.dis + 1]));\n\t\t\t}\n\t\t}\n\t}\n\tint ans = MOD;\n\tfor (int i = 0; i < H*W; i++)ans = min(ans, dp.back().back()[i]);\n\tcout << ans << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 10132, "score_of_the_acc": -0.2051, "final_rank": 5 }, { "submission_id": "aoj_0645_3970517", "code_snippet": "#include \"bits/stdc++.h\"\n#pragma GCC optimize(\"Ofast\")\n\n// Begin {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T>\ninline vector<T> make_v(const T &initvalue, size_t sz) {\n return vector<T>(sz, initvalue);\n}\n\ntemplate <class T, class... Args>\ninline auto make_v(const T &initvalue, size_t sz, Args... args) {\n return vector<decltype(make_v<T>(initvalue, args...))>(sz, make_v<T>(initvalue, args...));\n}\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr int64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\n\nconstexpr size_t operator\"\"_sz(unsigned long long value) { return value; };\nconstexpr intmax_t operator\"\"_im(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_um(unsigned long long value) { return value; };\n// }}} End\n\nconstexpr int dy[] = {0, 1, 0, -1, -1, 1, 1, -1};\nconstexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};\n\ninline bool inside(int y, int x, int H, int W) {\n return (y >= 0 && x >= 0 && y < H && x < W);\n}\n\nsize_t H, W;\nauto a = make_v(0_im, 35, 35);\n\nauto dp = make_v(-1_im, 35, 35, 1225);\n\nintmax_t rec(int y, int x, intmax_t dist) {\n if (dist < 0) return INF;\n if (y == 0 && x == 0) return 0;\n if (~dp[y][x][dist]) return dp[y][x][dist];\n\n intmax_t ret = INF;\n for (size_t i = 0; i < 4; ++i) {\n int ny = y + dy[i];\n int nx = x + dx[i];\n if (inside(ny, nx, H, W)) {\n chmin(ret, rec(ny, nx, dist - 1) + ((dist - 1) * 2 + 1) * a[y][x]);\n }\n }\n\n return dp[y][x][dist] = ret;\n}\n\nsigned main() {\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n\n cin >> H >> W;\n\n for (size_t i = 0; i < H; ++i) {\n for (size_t j = 0; j < W; ++j) {\n cin >> a[i][j];\n }\n }\n\n intmax_t res = INF;\n for (intmax_t d = 1; d <= H * W; ++d) {\n chmin(res, rec(H - 1, W - 1, d));\n }\n\n cout << res << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 14972, "score_of_the_acc": -0.2699, "final_rank": 8 } ]
aoj_0654_cpp
マルバツスタンプ (Circle Cross Stamps) 問題文 JOI 君はマルスタンプ,バツスタンプ,マルバツスタンプの3種類のスタンプをそれぞれ 0 個以上持っている.これらはマルやバツのマークを紙に印字することができるスタンプである. マルスタンプを使うとマルが 1 つ印字され,バツスタンプを使うとバツが 1 つ印字される.マルバツスタンプを使うとマルとバツが横一列に 1 つずつ印字され,スタンプの向きを変えることで,マルの右にバツが来るようにも,バツの右にマルが来るようにも印字できる. JOI 君は,持っているスタンプをそれぞれちょうど 1 回ずつ適当な順番で使い,紙に横一列にマルとバツを印字した.印字されたマルとバツの列は文字列 S で表される. S は O と X から構成された長さ N の文字列であり, S_i = O ならば JOI 君が印字したマークのうち左から i 番目のものがマルであることを表し, S_i = X ならばそれがバツであることを表す ( 1 ≦ i ≦ N ). あなたは,JOI 君が持っているスタンプの個数は分からないが,JOI 君が印字したマルとバツの列は知っている.印字されたマルとバツの列から,JOI 君が持っているマルバツスタンプの個数としてあり得るもののうち最大値を求めよ. 制約 1 ≦ N ≦ 100000 (= 10^5) S は長さ N の文字列である. S の各文字は O か X である. 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N S 出力 JOI 君が持っているマルバツスタンプの個数としてあり得るもののうち最大値を出力せよ. 入出力例 入力例 1 5 OXXOX 出力例 1 2 JOI 君が印字したマークは,左から順に,マル,バツ,バツ,マル,バツである.JOI 君がマルスタンプ,バツスタンプ,マルバツスタンプをそれぞれ 0, 1, 2 個持っているとすると,以下の順番でスタンプを使えば,そのようにマークを印字することができる. 1 つ目のマルバツスタンプを使ってマルとバツをこの順に印字する. この右に, 2 つ目のマルバツスタンプを使ってバツとマルをこの順に印字する. 最後に,この右に,バツスタンプを使ってバツを印字する. マルバツスタンプを 3 個以上持っているケースは考えられないので, 2 を出力する. 入力例 2 14 OXOXOXOXXOXOXO 出力例 2 7 入力例 3 10 OOOOOOOOOO 出力例 3 0 情報オリンピック日本委員会作 『第 18 回日本情報オリンピック JOI 2018/2019 予選競技課題』
[ { "submission_id": "aoj_0654_7141922", "code_snippet": "#include<iostream>\nusing namespace std;\nint main() {\n\tint n;\n\tstring s;\n\tint cnt = 0;\n\tcin >> n >> s;\n\tfor (int i = 0; i < n; i++)\n\t\tif (s.substr(i, 2) == \"OX\" || s.substr(i, 2) == \"XO\")\n\t\t\tcnt++, i++;\n\tcout << cnt << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3336, "score_of_the_acc": -0.0741, "final_rank": 2 }, { "submission_id": "aoj_0654_7141920", "code_snippet": "#include<iostream>\nusing namespace std;\nint main() {\n\n\tint n;\n\tstring s;\n\tint cnt = 0;\n\n\tcin >> n >> s;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (s.substr(i, 2) == \"OX\" || s.substr(i, 2) == \"XO\")\n\t\t\tcnt++, i++;\n\t}\n\tcout << cnt << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3336, "score_of_the_acc": -0.0741, "final_rank": 2 }, { "submission_id": "aoj_0654_4414911", "code_snippet": "#include<iostream>\n#include<cstdio>\nusing namespace std;\nint main(){\n int n, count;\n char ch[100000];\n count = 0;\n scanf(\"%d\",&n);\n for(int i = 0; i < n; i++){\n scanf(\"%s\", ch);\n }\n \n int i = 0;\n while(i < n-1){\n if(ch[i] == 'O'){\n if(ch[i+1] == 'X'){\n count++;\n i += 2;\n }\n else i++;\n }\n if(ch[i] == 'X'){\n if(ch[i+1] == 'O'){\n count++;\n i += 2;\n }\n else i++;\n }\n \n }\n printf(\"%d\\n\", count);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3320, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0654_4336415", "code_snippet": "#include <iostream>\n#include <vector>\n#include <unordered_map>\n#include <string>\n#include <random>\n\n\nint max(const std::vector<int>& temp_vec) {\n\tint temp_max = 0;\n\n\tfor (const auto& temp : temp_vec) {\n\t\tif (temp_max < temp) { temp_max = temp; };\n\t}\n\n\treturn temp_max;\n};\n\nint getNumStumpMax(std::string& vec) {\n\n\tstd::vector<int> temp_sizes;\n\tfor (int i = 0; i < 100000; i++) {\n\t\tstd::vector<int> results;\n\n\t\tstd::string marubatsu = \"OX\";\n\t\tstd::string batsumaru = \"XO\";\n\t\tint subStrSize1 = marubatsu.size();\n\t\tint subStrSize2 = batsumaru.size();\n\t\tint pos1 = vec.find(marubatsu);\n\t\tint pos2 = vec.find(batsumaru);\n\t\tauto vec_ = vec;\n\t\twhile (pos1 != std::string::npos && pos2 != std::string::npos) {\n\t\t\tdouble rand_n = ((double)rand() + 0.5) / (RAND_MAX + 1.0);\n\t\t\tif (rand_n < 0.5) {\n\t\t\t\tresults.push_back(pos1);\n\t\t\t\tauto pos1_ = pos1;\n\t\t\t\tvec_.replace(pos1_, 2, \"**\");\n\t\t\t\tpos1 = vec_.find(marubatsu);\n\t\t\t\tpos2 = vec_.find(batsumaru);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tresults.push_back(pos2);\n\t\t\t\tauto pos2_ = pos2;\n\t\t\t\tvec_.replace(pos2_, 2, \"**\");\n\t\t\t\tpos1 = vec_.find(marubatsu);\n\t\t\t\tpos2 = vec_.find(batsumaru);\n\t\t\t}\n\t\t\t\n\t\t}\n\t\ttemp_sizes.emplace_back(results.size());\n\t}\n\tint ret = max(temp_sizes);\n\n\treturn ret;\n}\n\n\nint main() {\n\n\tint N;\n\tstd::cin >> N;\n\tstd::string vec_string;\n\tstd::cin >> vec_string;\n\n\tauto num_max = getNumStumpMax(vec_string);\n\tstd::cout << num_max << std::endl;\n\n\treturn 0;\n}", "accuracy": 0.018867924528301886, "time_ms": 40, "memory_kb": 3536, "score_of_the_acc": -2, "final_rank": 7 }, { "submission_id": "aoj_0654_4336406", "code_snippet": "#include <iostream>\n#include <vector>\n#include <unordered_map>\n#include <string>\n#include <random>\n\n\nint max(const std::vector<int>& temp_vec) {\n\tint temp_max = 0;\n\n\tfor (const auto& temp : temp_vec) {\n\t\tif (temp_max < temp) { temp_max = temp; };\n\t}\n\n\treturn temp_max;\n};\n\nint getNumStumpMax(std::string& vec) {\n\n\tstd::vector<int> temp_sizes;\n\tfor (int i = 0; i < 100000; i++) {\n\t\tstd::vector<int> results;\n\n\t\tstd::string marubatsu = \"OX\";\n\t\tstd::string batsumaru = \"XO\";\n\t\tint subStrSize1 = marubatsu.size();\n\t\tint subStrSize2 = batsumaru.size();\n\t\tint pos1 = vec.find(marubatsu);\n\t\tint pos2 = vec.find(batsumaru);\n\t\tauto vec_ = vec;\n\t\twhile (pos1 != std::string::npos && pos2 != std::string::npos) {\n\t\t\tdouble rand_n = ((double)rand() + 0.5) / (RAND_MAX + 1.0);\n\t\t\tif (rand_n < 0.5 && pos1 !=-1) {\n\t\t\t\tresults.push_back(pos1);\n\t\t\t\tauto pos1_ = pos1;\n\t\t\t\tvec_.replace(pos1_, 2, \"**\");\n\t\t\t\tpos1 = vec_.find(marubatsu);\n\t\t\t\tpos2 = vec_.find(batsumaru);\n\t\t\t}\n\t\t\telse if(pos2 !=-1){\n\t\t\t\tresults.push_back(pos2);\n\t\t\t\tauto pos2_ = pos2;\n\t\t\t\tvec_.replace(pos2_, 2, \"**\");\n\t\t\t\tpos1 = vec_.find(marubatsu);\n\t\t\t\tpos2 = vec_.find(batsumaru);\n\t\t\t}\n\t\t\t\n\t\t}\n\t\ttemp_sizes.emplace_back(results.size());\n\t}\n\tint ret = max(temp_sizes);\n\n\treturn ret;\n}\n\n\nint main() {\n\n\tint N;\n\tstd::cin >> N;\n\tstd::string vec_string;\n\tstd::cin >> vec_string;\n\n\tauto num_max = getNumStumpMax(vec_string);\n\tstd::cout << num_max << std::endl;\n\n\treturn 0;\n}", "accuracy": 0.018867924528301886, "time_ms": 40, "memory_kb": 3448, "score_of_the_acc": -1.5926, "final_rank": 6 }, { "submission_id": "aoj_0654_4185191", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n int n;\n cin >> n;\n string s;\n cin >> s;\n\n int ans = 0;\n for (int i = 0; i < n; i++) {\n if (i + 1 >= n) continue;\n string t = \"\";\n t += s[i], t += s[i + 1];\n if (t == \"OX\" || t == \"XO\") {\n ans++;\n i++;\n }\n }\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3340, "score_of_the_acc": -0.0926, "final_rank": 4 }, { "submission_id": "aoj_0654_4113059", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n#define REP(i,n) for (ll i = 0; i < (n); ++i)\n\nint main(){\n ll n;\n cin >> n;\n string s;\n cin >> s;\n ll i;\n ll ans = 0;\n for(i = 0; i < n;){\n if(i < n - 1 &&\n (s.substr(i, 2) == \"OX\" || s.substr(i, 2) == \"XO\")){\n ans++;\n i += 2;\n }else{\n i++;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3348, "score_of_the_acc": -0.1296, "final_rank": 5 } ]
aoj_0649_cpp
団子職人(Dango Maker) あなたは団子を作る職人である.今,あなたは団子に串を刺そうとしているところである. 団子は,縦 N 行,横 M 列に仕切られたマスの中に配置されている.各マスには団子が1 個ずつ入っている.それぞれの団子には,赤(R),緑(G), 白(W) のいずれかの色が付いている.あなたは,左から右の方向,または,上から下の方向に連続する3 マスから団子を取り出し,この順に1 本の串にちょうど3個刺すことができる. 今あなたは,赤,緑,白の団子が1 個ずつこの順に刺さった串を可能な限り多く作りたい.串に刺す順番は,マスから取り出した順番と同じでなければならない.また,同じ団子に2 本以上の串を刺すことはできない. あなたは,団子が刺さった串を最大何本作ることができるだろうか. 課題 マスの中に配置された団子の色の情報が与えられたとき,赤,緑,白の団子が1 個ずつこの順に刺さった串が最大何本作れるかを求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,整数 N と M が空白を区切りとして書かれている. 続く N 行のうちの i 行目( 1 \leq i \leq N ) には,R, G, W からなる長さ M の文字列が書かれている.この文字列の j 文字目( 1 \leq j \leq M ) は,上から i 行目,左から j 列目のマスの団子の色を表す. 出力 標準出力に,団子が刺さった串の本数の最大値を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 1 \leq N \leq 3 000. 1 \leq M \leq 3 000. 入出力例 入力例1 3 4 RGWR GRGG RGWW 出力例1 3 次のように串に刺すことで,団子が刺さった串を3 本作ることができる. 上から1 行目,左から1 列目の団子から右方向に3 個の団子を取り出し,この順に串に刺す. 上から1 行目,左から4 列目の団子から下方向に3 個の団子を取り出し,この順に串に刺す. 上から3 行目,左から1 列目の団子から右方向に3 個の団子を取り出し,この順に串に刺す. 4 本以上の串を作ることはできないので,3 を出力する. 入力例2 4 4 RGWR GRRG WGGW WWWR 出力例2 4 次のように串に刺すことで,団子が刺さった串を4 本作ることができる. 上から1 行目,左から1 列目の団子から右方向に3 個の団子を取り出し,この順に串に刺す. 上から1 行目,左から4 列目の団子から下方向に3 個の団子を取り出し,この順に串に刺す. 上から2 行目,左から2 列目の団子から下方向に3 個の団子を取り出し,この順に串に刺す. 上から2 行目,左から3 列目の団子から下方向に3 個の団子を取り出し,この順に串に刺す. 5 本以上の串を作ることはできないので,4 を出力する. 入力例3 5 5 RGRGW GRRGW WGGWR RWRGW RGWGW 出力例3 6 情報オリンピック日本委員会作 『第17 回日本情報オリンピック(JOI 2017/2018) 本選』
[ { "submission_id": "aoj_0649_9477309", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\n\n#define NUM 3000\n\nenum Type {\n TATE,\n YOKO,\n NONE,\n};\n\nint H, W;\nint dp[3][NUM + 1];\nchar base_map[NUM][NUM + 1];\n\nbool rangeCheck(int row, int col) {\n return (row >= 0 && row < H && col >= 0 && col < W);\n}\n\nint calc(int start_row, int start_col) {\n int ret = 0;\n\n for (int col = start_col; col < W; col++) {\n dp[TATE][col] = 0;\n dp[YOKO][col] = 0;\n dp[NONE][col] = 0;\n }\n\n int row = start_row;\n for (int col = start_col; col < W && row >= 0; col++) {\n if (base_map[row][col] != 'G') {\n if (col != start_col) {\n dp[NONE][col] = max(dp[NONE][col - 1], max(dp[TATE][col - 1], dp[YOKO][col - 1]));\n }\n } else {\n if (rangeCheck(row - 1, col) && base_map[row - 1][col] == 'R' && rangeCheck(row + 1, col) && base_map[row + 1][col] == 'W') {\n dp[TATE][col] = (col == start_col) ? 1 : max(dp[TATE][col - 1], dp[NONE][col - 1]) + 1;\n ret = max(ret, dp[TATE][col]);\n }\n if (rangeCheck(row, col - 1) && base_map[row][col - 1] == 'R' && rangeCheck(row, col + 1) && base_map[row][col + 1] == 'W') {\n dp[YOKO][col] = (col == start_col) ? 1 : max(dp[YOKO][col - 1], dp[NONE][col - 1]) + 1;\n ret = max(ret, dp[YOKO][col]);\n }\n if (col != start_col) {\n dp[NONE][col] = max(dp[NONE][col - 1], max(dp[TATE][col - 1], dp[YOKO][col - 1]));\n }\n }\n row--;\n }\n return ret;\n}\n\nint main() {\n cin >> H >> W;\n\n for (int row = 0; row < H; row++) {\n cin >> base_map[row];\n }\n\n int ans = 0;\n for (int row = 1; row < H; row++) {\n ans += calc(row, 0);\n }\n for (int col = 1; col < W; col++) {\n ans += calc(H - 1, col);\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 12300, "score_of_the_acc": -0.0895, "final_rank": 2 }, { "submission_id": "aoj_0649_9060332", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int h, w;\n cin >> h >> w;\n vector<string> s(h);\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n }\n auto get = [&](int x, int y) -> int {\n if (0 <= x and x < h and 0 <= y and y < w) {\n if (s[x][y] == 'R') return 0;\n else if (s[x][y] == 'G') return 1;\n else if (s[x][y] == 'W') return 2;\n else return -1;\n }\n return -1;\n };\n using P = pair<int, int>;\n vector<vector<P>> v(h + w);\n for (int j = 0; j < w; j++) {\n for (int i = 0; i < h; i++) {\n v[i + j].push_back({i, j});\n }\n }\n int res = 0;\n for (int _ = 0; _ < v.size(); _++) {\n int n = v[_].size();\n vector<vector<int>> dp(1 << 2, vector<int>(1 << 2, -1));\n dp[0][0] = 0;\n for (int i = 0; i < n; i++) {\n vector<vector<int>> ndp(1 << 2, vector<int>(1 << 2, -1));\n int x = v[_][i].first, y = v[_][i].second;\n for (int j = 0; j < (1 << 2); j++) {\n for (int k = 0; k < (1 << 2); k++) {\n if (dp[j][k] == -1) continue;\n // 使わない\n ndp[j / 2][k / 2] = max(ndp[j / 2][k / 2], dp[j][k]);\n // 使う\n if (get(x, y) == 0) {\n // 縦\n if (get(x + 1, y) == 1 and (j & 1) == 0) {\n if (get(x + 2, y) == 2 and (k & 1) == 0) {\n ndp[j / 2][k / 2] = max(ndp[j / 2][k / 2], dp[j][k] + 1);\n }\n }\n // 横\n if (get(x, y + 1) == 1 and (j & 2) == 0) {\n if (get(x, y + 2) == 2 and (k & 4) == 0) {\n ndp[j / 2 + 1][k / 2 + 2] = max(ndp[j / 2 + 1][k / 2 + 2], dp[j][k] + 1);\n }\n }\n }\n }\n }\n\n swap(dp, ndp);\n }\n int ad = 0;\n for (int i = 0; i < (1 << 2); i++) {\n for (int j = 0; j < (1 << 2); j++) {\n ad = max(ad, dp[i][j]);\n }\n }\n res += ad;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 970, "memory_kb": 105516, "score_of_the_acc": -0.9731, "final_rank": 13 }, { "submission_id": "aoj_0649_9060321", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int h, w;\n cin >> h >> w;\n vector<string> s(h);\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n }\n auto get = [&](int x, int y) -> int {\n if (0 <= x and x < h and 0 <= y and y < w) {\n if (s[x][y] == 'R') return 0;\n else if (s[x][y] == 'G') return 1;\n else if (s[x][y] == 'W') return 2;\n else return -1;\n }\n return -1;\n };\n using P = pair<int, int>;\n vector<vector<P>> v(h + w);\n for (int j = 0; j < w; j++) {\n for (int i = 0; i < h; i++) {\n v[i + j].push_back({i, j});\n }\n }\n int res = 0;\n for (int _ = 0; _ < v.size(); _++) {\n int n = v[_].size();\n vector<vector<int>> dp(1 << 2, vector<int>(1 << 3, -1));\n dp[0][0] = 0;\n for (int i = 0; i < n; i++) {\n vector<vector<int>> ndp(1 << 2, vector<int>(1 << 3, -1));\n int x = v[_][i].first, y = v[_][i].second;\n for (int j = 0; j < (1 << 2); j++) {\n for (int k = 0; k < (1 << 3); k++) {\n if (dp[j][k] == -1) continue;\n // 使わない\n ndp[j / 2][k / 2] = max(ndp[j / 2][k / 2], dp[j][k]);\n // 使う\n if (get(x, y) == 0) {\n // 縦\n if (get(x + 1, y) == 1 and (j & 1) == 0) {\n if (get(x + 2, y) == 2 and (k & 1) == 0) {\n ndp[j / 2][k / 2] = max(ndp[j / 2][k / 2], dp[j][k] + 1);\n }\n }\n // 横\n if (get(x, y + 1) == 1 and (j & 2) == 0) {\n if (get(x, y + 2) == 2 and (k & 4) == 0) {\n ndp[j / 2 + 1][k / 2 + 2] = max(ndp[j / 2 + 1][k / 2 + 2], dp[j][k] + 1);\n }\n }\n }\n }\n }\n\n swap(dp, ndp);\n }\n int ad = 0;\n for (int i = 0; i < (1 << 2); i++) {\n for (int j = 0; j < (1 << 3); j++) {\n ad = max(ad, dp[i][j]);\n }\n }\n res += ad;\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 1150, "memory_kb": 105508, "score_of_the_acc": -1.0725, "final_rank": 18 }, { "submission_id": "aoj_0649_8441373", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n, m;\nchar c[3010][3010]={};\nint rgw[3010][3010]={};\nint dp[3010][3010][4]={};\nint main(){\n cin >> n >> m;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++) scanf(\" %c\", &c[i][j]);\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(i>1 && i<n && c[i-1][j]=='R' && c[i][j]=='G' && c[i+1][j]=='W') rgw[i][j] += 1;\n if(j>1 && j<m && c[i][j-1]=='R' && c[i][j]=='G' && c[i][j+1]=='W') rgw[i][j] += 2;\n }\n }\n int ans=0;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n for(int k=0;k<4;k++){\n dp[i][j][0] = max(dp[i][j][0], dp[i-1][j+1][k]);\n if(k!=2 && rgw[i][j]&1==1) dp[i][j][1] = max(dp[i][j][1], dp[i-1][j+1][k]+1);\n if(k!=1 && rgw[i][j]>1) dp[i][j][2] = max(dp[i][j][2], dp[i-1][j+1][k]+1);\n }\n if(i==n || j==1) ans += max(max(dp[i][j][0], dp[i][j][1]), max(dp[i][j][2], dp[i][j][3]));\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 188332, "score_of_the_acc": -1.067, "final_rank": 17 }, { "submission_id": "aoj_0649_8441299", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n, m;\nchar c[3010][3010]={};\nint rgw[3010][3010]={};\nint dp[3010][3010][4]={};\nint main(){\n cin >> n >> m;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++) scanf(\" %c\", &c[i][j]);\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(i>1 && i<n && c[i-1][j]=='R' && c[i][j]=='G' && c[i+1][j]=='W') rgw[i][j] += 1;\n if(j>1 && j<m && c[i][j-1]=='R' && c[i][j]=='G' && c[i][j+1]=='W') rgw[i][j] += 2;\n }\n }\n int ans=0;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n for(int k=0;k<4;k++){\n dp[i][j][0] = max(dp[i][j][0], dp[i-1][j+1][k]);\n if(k!=2 && rgw[i][j]%2==1) dp[i][j][1] = max(dp[i][j][1], dp[i-1][j+1][k]+1);\n if(k!=1 && rgw[i][j]>1) dp[i][j][2] = max(dp[i][j][2], dp[i-1][j+1][k]+1);\n }\n if(i==n || j==1) ans += max(max(dp[i][j][0], dp[i][j][1]), max(dp[i][j][2], dp[i][j][3]));\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 188332, "score_of_the_acc": -1.0615, "final_rank": 16 }, { "submission_id": "aoj_0649_8441243", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint n, m;\nchar c[3010][3010]={};\nint rgw[3010][3010]={};\nint dp[2][3010][4]={};\nint main(){\n cin >> n >> m;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++) cin >> c[i][j];\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(i>1 && i<n && c[i-1][j]=='R' && c[i][j]=='G' && c[i+1][j]=='W') rgw[i][j] += 1;\n if(j>1 && j<m && c[i][j-1]=='R' && c[i][j]=='G' && c[i][j+1]=='W') rgw[i][j] += 2;\n }\n }\n int ans=0;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n for(int k=0;k<4;k++){\n dp[1][j][0] = max(dp[1][j][0], dp[0][j+1][k]);\n if(k!=2 && rgw[i][j]%2==1) dp[1][j][1] = max(dp[1][j][1], dp[0][j+1][k]+1);\n if(k!=1 && rgw[i][j]>1) dp[1][j][2] = max(dp[1][j][2], dp[0][j+1][k]+1);\n }\n if(i==n || j==1) ans += max(max(dp[1][j][0], dp[1][j][1]), max(dp[1][j][2], dp[1][j][3]));\n //cout << max(max(dp[1][j][0], dp[1][j][1]), max(dp[1][j][2], dp[1][j][3]));\n }\n //cout << endl;\n memset(dp[0], 0, sizeof(dp[0]));\n swap(dp[0], dp[1]);\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 490, "memory_kb": 47248, "score_of_the_acc": -0.4318, "final_rank": 10 }, { "submission_id": "aoj_0649_8438294", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n, m, ans=0;\n char c[3010][3010]={};\n int dp[3010][3010]={};\n cin >> n >> m;\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++) cin >> c[i][j];\n }\n for(int i=3;i<=n+1;i++){\n for(int j=1;i-j>0;j++){\n int prev = dp[i-j+1][j-1];\n dp[i-j][j] = prev;\n if(c[i-j][j] == 'G'){\n if(c[i-j-1][j]=='R' && c[i-j+1][j]=='W') dp[i-j][j] = prev+1;\n else if(c[i-j][j-1]=='R' && c[i-j][j+1]=='W' && !(c[i-j+1][j-1]=='G' && c[i-j+2][j-1]=='W')) dp[i-j][j] = prev+1;\n }\n }\n }\n for(int i=2;i<m;i++){\n for(int j=1;i+j<=m+1;j++){\n int prev = dp[n+2-j][i+j-2];\n dp[n+1-j][i+j-1] = prev;\n if(c[n+1-j][i+j-1] == 'G'){\n if(c[n-j][i+j-1]=='R' && c[n+2-j][i+j-1]=='W') dp[n+1-j][i+j-1] = prev+1;\n else if(c[n+1-j][i+j-2]=='R' && c[n+1-j][i+j]=='W' && !(c[n+2-j][i+j-2]=='G' && c[n+3-j][i+j-2]=='W')) dp[n+1-j][i+j-1] = prev+1;\n }\n }\n }\n for(int i=1;i<=n;i++){\n for(int j=1;j<=m;j++){\n if(i==1 || j==m) ans += dp[i][j];\n //cout << dp[i][j];\n }\n //cout << endl;\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.08602150537634409, "time_ms": 10, "memory_kb": 47316, "score_of_the_acc": -0.167, "final_rank": 20 }, { "submission_id": "aoj_0649_7970470", "code_snippet": "#include <bits/stdc++.h>\n\nint main() {\n int n, m;\n std::cin >> n >> m;\n\n std::vector< std::string > ss(n);\n for (auto &s: ss) std::cin >> s;\n\n auto check_v = [&](int y, int x) {\n if (y < 0 or n <= y) return false;\n if (x < 0 or m <= x) return false;\n if (x + 2 >= m) return false;\n if (ss[y][x + 0] != 'R') return false;\n if (ss[y][x + 1] != 'G') return false;\n if (ss[y][x + 2] != 'W') return false;\n return true;\n };\n\n auto check_h = [&](int y, int x) {\n if (y < 0 or n <= y) return false;\n if (x < 0 or m <= x) return false;\n if (y + 2 >= n) return false;\n if (ss[y + 0][x] != 'R') return false;\n if (ss[y + 1][x] != 'G') return false;\n if (ss[y + 2][x] != 'W') return false;\n return true;\n };\n\n int ans = 0;\n for (int d = 1; d <= n + m - 1; d++) {\n auto dp = std::vector(4, 0);\n\n //auto dp = std::vector(d, std::vector(2, std::vector(2, 0)));\n\n for (int i = 0; i < d; i++) {\n int y = d - 1 - i;\n int x = i;\n\n auto ndp = std::vector(4, 0);\n ndp[0] = std::max(dp[0], dp[1]);\n ndp[1] = std::max(dp[2], dp[3]);\n // for (int j = 0; j < 2; j++) {\n // if (i) dp[i][0][j] = std::max(dp[i - 1][j][0], dp[i - 1][j][1]);\n // }\n\n if (check_v(y, x)) {\n for (int j = 0; j < 2; j++) for (int k = 0; k < 2; k++) {\n ndp[2 + j] = std::max(ndp[2 + j], dp[j << 1 | k] + 1);\n // int val = (i == 0 ? 1 : dp[i - 1][j][k] + 1);\n // dp[i][true][j] = std::max(dp[i][true][j], val);\n }\n }\n\n if (check_h(y, x)) {\n ndp[0] = std::max(ndp[0], dp[0] + 1);\n // dp[i][false][false] = std::max(dp[i][false][false], (i ? dp[i - 1][false][false] : 0) + 1);\n }\n\n dp = std::move(ndp);\n }\n\n int max = 0;\n for (int j = 0; j < 2; j++) for (int k = 0; k < 2; k++) {\n max = std::max(max, dp[j << 1 | k]);\n }\n\n ans += max;\n }\n\n std::cout << ans << std::endl;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 14836, "score_of_the_acc": -0.2286, "final_rank": 7 }, { "submission_id": "aoj_0649_7970000", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint func(){\n int n;\n int m;\n cin >> n >> m;\n vector<string> table(n);\n for(auto &i:table)cin >> i;\n\n auto check = [&](int y,int x,char c) -> bool{\n if(y < 0 or y >= n or x < 0 or x >= m)return false;\n return table[y][x] == c;\n };\n\n int res = 0;\n for(int i=0;i<n+m-1;++i){\n vector<int> dp((n+m+10)*4,-1);\n function<int(int,bool,bool)> rec = [&](int p,bool used_red,bool used_white) -> int {\n int y = p;\n int x = i - p;\n if(x < 0 or y >= n)return 0;\n int &it = dp[(p * 2 + used_red) * 2 + used_white];\n if(it >= 0)return it;\n it = 0;\n if(x >= m or table[y][x] != 'G'){\n it = rec(p+1,false,false);\n }else{\n bool can_vertical = (not used_red) and check(y-1,x,'R') and check(y+1,x,'W');\n bool can_horizontal = (not used_white) and check(y,x-1,'R') and check(y,x+1,'W');\n if(can_vertical){\n it = max(it, rec(p+1,false, true) + 1);\n }\n if(can_horizontal){\n it = max(it, rec(p+1,true, false) + 1);\n }\n it = max(it, rec(p+1,false,false));\n }\n return it;\n };\n int ans = rec(0,false,false);\n res += rec(0,false,false);\n }\n return res;\n}\n\nint main(){\n cout << func() << endl;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 14660, "score_of_the_acc": -0.1835, "final_rank": 4 }, { "submission_id": "aoj_0649_4413239", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <functional>\n#include <set>\n#include <map>\n#include <vector>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nconst int N = 3010;\n\nint n, m, ans, cnt;\nchar s[N][N];\nbool ab[N][2];\nint dp[N][3];\n\nvoid prog() {\n for (int i = 1; i <= cnt + 1; ++i) {\n dp[i][2] = *max_element(dp[i - 1], dp[i - 1] + 3);\n dp[i][0] = ab[i][0] ? (max(dp[i - 1][0], dp[i - 1][2]) + 1) : 0;\n dp[i][1] = ab[i][1] ? (max(dp[i - 1][1], dp[i - 1][2]) + 1) : 0;\n }\n ans += dp[cnt + 1][2];\n}\n\nint main() {\n\n scanf(\"%d%d\", &n, &m);\n for (int i = 1; i <= n; ++i) scanf(\"%s\", s[i] + 1);\n for (int k = 2; k <= n + m; ++k) {\n for (int i = 1; i <= n; ++i) {\n int j = k - i;\n if (j < 1 || j > m)\n continue;\n if (s[i][j] != 'G') {\n if (cnt)\n prog();\n cnt = 0;\n } else {\n ++cnt;\n ab[cnt][0] = s[i - 1][j] == 'R' && s[i + 1][j] == 'W';\n ab[cnt][1] = s[i][j - 1] == 'R' && s[i][j + 1] == 'W';\n }\n }\n if (cnt)\n prog();\n cnt = 0;\n }\n printf(\"%d\\n\", ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 12068, "score_of_the_acc": -0.0608, "final_rank": 1 }, { "submission_id": "aoj_0649_4141140", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <functional>\n\nconstexpr int INF = 1 << 30;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nvoid solve() {\n int n, m;\n std::cin >> n >> m;\n\n std::vector<std::string> ss(n);\n for (auto& s : ss) std::cin >> s;\n\n // (x, y)から(t ? 縦 : 横)に取れるか判定\n auto judge = [&](int x, int y, int t) {\n if (t == 0) {\n for (int dx = 0; dx < 3; ++dx) {\n int nx = x + dx,\n ny = y;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dx]) return false;\n }\n } else {\n for (int dy = 0; dy < 3; ++dy) {\n int nx = x,\n ny = y + dy;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dy]) return false;\n }\n }\n return true;\n };\n\n int ans = 0;\n auto dp = vec(2, vec(2, 0));\n auto ndp = dp;\n\n // (sx, 0)から斜め上に見る\n for (int sx = 0; sx < n + m; ++sx) {\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n dp[t1][t2] = -INF;\n }\n }\n dp[0][0] = 0;\n\n for (int y = 0; y <= m + 1; ++y) {\n int x = sx - y;\n\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t1][t2] = -INF;\n }\n }\n\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n // ブロックを取らない\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2]);\n\n // 縦に取る\n if (!t1 && !t2 && judge(x, y, 0)) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2] + 1);\n }\n\n // 横に取る\n if (judge(x, y, 1)) {\n ndp[t2][1] = std::max(ndp[t2][1], dp[t1][t2] + 1);\n }\n }\n }\n std::swap(dp, ndp);\n }\n ans += dp[0][0]; // yを2だけ余分にカウントすることでdp[0][0]に集約している\n }\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 13504, "score_of_the_acc": -0.2223, "final_rank": 5 }, { "submission_id": "aoj_0649_4141133", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <functional>\n\nconstexpr int INF = 1 << 30;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nint n, m;\nstd::vector<std::string> ss;\n\nbool judge(int x, int y, int t) {\n if (t == 0) {\n for (int dx = 0; dx < 3; ++dx) {\n int nx = x + dx,\n ny = y;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dx]) return false;\n }\n } else {\n for (int dy = 0; dy < 3; ++dy) {\n int nx = x,\n ny = y + dy;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dy]) return false;\n }\n }\n return true;\n};\n\nvoid solve() {\n std::cin >> n >> m;\n\n ss.resize(n);\n for (auto& s : ss) std::cin >> s;\n\n int ans = 0;\n auto dp = vec(2, vec(2, 0));\n auto ndp = dp;\n\n for (int sx = 0; sx < n + m; ++sx) {\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n dp[t1][t2] = -INF;\n }\n }\n dp[0][0] = 0;\n\n for (int y = 0; y <= m + 1; ++y) {\n int x = sx - y;\n\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t1][t2] = -INF;\n }\n }\n\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2]);\n\n if (!t1 && !t2 && judge(x, y, 0)) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2] + 1);\n }\n if (judge(x, y, 1)) {\n ndp[t2][1] = std::max(ndp[t2][1], dp[t1][t2] + 1);\n }\n }\n }\n std::swap(dp, ndp);\n }\n ans += dp[0][0];\n }\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 13508, "score_of_the_acc": -0.3107, "final_rank": 9 }, { "submission_id": "aoj_0649_4141126", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <functional>\n\nconstexpr int INF = 1 << 30;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nvoid solve() {\n int n, m;\n std::cin >> n >> m;\n\n std::vector<std::string> ss(n);\n for (auto& s : ss) std::cin >> s;\n\n auto judge = [&](int x, int y, int t) {\n if (t == 0) {\n for (int dx = 0; dx < 3; ++dx) {\n int nx = x + dx,\n ny = y;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dx]) return false;\n }\n } else {\n for (int dy = 0; dy < 3; ++dy) {\n int nx = x,\n ny = y + dy;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dy]) return false;\n }\n }\n return true;\n };\n\n int ans = 0;\n for (int sx = 0; sx < n + m; ++sx) {\n auto dp = vec(2, vec(2, -INF));\n dp[0][0] = 0;\n\n for (int y = 0; y <= m + 1; ++y) {\n int x = sx - y;\n\n auto ndp = vec(2, vec(2, -INF));\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2]);\n\n if (!t1 && !t2 && judge(x, y, 0)) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2] + 1);\n }\n if (judge(x, y, 1)) {\n ndp[t2][1] = std::max(ndp[t2][1], dp[t1][t2] + 1);\n }\n }\n }\n std::swap(dp, ndp);\n }\n ans += dp[0][0];\n }\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 1820, "memory_kb": 13508, "score_of_the_acc": -1.0068, "final_rank": 15 }, { "submission_id": "aoj_0649_4141092", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <functional>\n\nconstexpr int INF = 1 << 30;\n\ntemplate <class T>\nstd::vector<T> vec(int len, T elem) { return std::vector<T>(len, elem); }\n\nvoid solve() {\n int n, m;\n std::cin >> n >> m;\n\n std::vector<std::string> ss(n);\n for (auto& s : ss) std::cin >> s;\n\n auto judge = [&](int x, int y, int t) {\n if (t == 0) {\n for (int dx = 0; dx < 3; ++dx) {\n int nx = x + dx,\n ny = y;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dx]) return false;\n }\n } else {\n for (int dy = 0; dy < 3; ++dy) {\n int nx = x,\n ny = y + dy;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[dy]) return false;\n }\n }\n return true;\n };\n\n int ans = 0;\n auto dp = vec(2, vec(2, -INF));\n auto ndp = dp;\n\n for (int sx = 0; sx < n + m; ++sx) {\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n dp[t1][t2] = -INF;\n }\n }\n dp[0][0] = 0;\n\n for (int y = 0; y <= m + 1; ++y) {\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t1][t2] = -INF;\n }\n }\n\n int x = sx - y;\n\n for (int t1 = 0; t1 <= 1; ++t1) {\n for (int t2 = 0; t2 <= 1; ++t2) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2]);\n if (!t1 && !t2 && judge(x, y, 0)) {\n ndp[t2][0] = std::max(ndp[t2][0], dp[t1][t2] + 1);\n }\n if (judge(x, y, 1)) {\n ndp[t2][1] = std::max(ndp[t2][1], dp[t1][t2] + 1);\n }\n }\n }\n std::swap(dp, ndp);\n }\n\n ans += dp[0][0];\n }\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 13504, "score_of_the_acc": -0.2223, "final_rank": 5 }, { "submission_id": "aoj_0649_4136091", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <deque>\n#include <tuple>\n\nvoid solve() {\n int n, m;\n std::cin >> n >> m;\n\n std::vector<std::string> ss(n);\n for (auto& s : ss) std::cin >> s;\n\n std::deque<std::pair<int, int>> que;\n std::vector<std::vector<int>> deg(n, std::vector<int>(m, 0));\n for (int x = 0; x < n; ++x) {\n for (int y = 0; y < m; ++y) {\n bool judge;\n\n judge = true;\n for (int i = 0; i < 3; ++i) {\n int nx = x + i - 1,\n ny = y;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[i]) judge = false;\n }\n deg[x][y] |= (judge << 0);\n\n judge = true;\n for (int i = 0; i < 3; ++i) {\n int nx = x,\n ny = y + i - 1;\n if (nx < 0 || n <= nx || ny < 0 || m <= ny ||\n ss[nx][ny] != \"RGW\"[i]) judge = false;\n }\n deg[x][y] |= (judge << 1);\n\n if (__builtin_popcount(deg[x][y]) == 1) {\n que.emplace_front(x, y);\n } else if (__builtin_popcount(deg[x][y]) == 2) {\n que.emplace_back(x, y);\n }\n }\n }\n\n int ans = 0;\n std::vector<std::vector<bool>> put(n, std::vector<bool>(m, false));\n while (!que.empty()) {\n int x, y;\n std::tie(x, y) = que.front();\n que.pop_front();\n if (deg[x][y] == 0) continue;\n\n if (deg[x][y] & 1) {\n for (int i = 0; i < 3; ++i) {\n int nx = x + i - 1,\n ny = y;\n put[nx][ny] = true;\n }\n ++ans;\n\n for (int p = 0; p < 2; ++p) {\n int px = x + (p * 2 - 1),\n py = y - (p * 2 - 1);\n if (px < 0 || n <= px || py < 0 || m <= py) continue;\n\n if (deg[px][py] & 2) {\n deg[px][py] ^= 2;\n if (deg[px][py] & 1) {\n que.emplace_front(px, py);\n }\n }\n }\n } else {\n for (int i = 0; i < 3; ++i) {\n int nx = x,\n ny = y + i - 1;\n put[nx][ny] = true;\n }\n ++ans;\n\n for (int p = 0; p < 2; ++p) {\n int px = x + (p * 2 - 1),\n py = y - (p * 2 - 1);\n if (px < 0 || n <= px || py < 0 || m <= py) continue;\n\n if (deg[px][py] & 1) {\n deg[px][py] ^= 1;\n if (deg[px][py] & 2) {\n que.emplace_front(px, py);\n }\n }\n }\n }\n deg[x][y] = 0;\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 74344, "score_of_the_acc": -0.4331, "final_rank": 11 }, { "submission_id": "aoj_0649_3982353", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n \n \nint h,w;\n\nint ban[3010][3010];\nint vis[3010][3010]={};\n\n\nvector<pa> ve;\nvoid dfs(int x,int y){\n\tif(vis[x][y]) return;\n\tve.pb(mp(x,y));\n\tvis[x][y]=1;\n\tfor(int i=0;i<4;i++){\n\t\tint xx=x+dx[i];\n\t\tint yy=y+dy[i];\n\t\tif(xx<0 || yy<0 ||xx>=h || yy>=w) continue;\n\t\tif(vis[xx][yy])continue;\n\t\tif(i<=1 && ban[x][y]+1!=ban[xx][yy])continue;\n\t\tif(i>1 && ban[x][y]-1!=ban[xx][yy])continue;\n\t\tdfs(xx,yy);\n\t}\n}\n\nint memo[3010][3];\nint dp[3010][5];\nint solve(){\n\tsort(ve.begin(),ve.end());\n\tint d=ve[0].first;\n\tint e1=inf,e2=-inf;\n\tfor(auto &v:ve){\n\t\tv.second+=v.first-d;\n\t\te1=min(e1,v.second);\n\t\te2=max(e2,v.second);\n\t}\n\tif(e2-e1!=2)return 0;\n\tfor(auto &v:ve){\n\t\tv.first-=d;\n\t\tv.second-=e1;\n\t}\n\t\n\tint R=ve.back().first+1;\n\tfor(int i=0;i<=R;i++)for(int j=0;j<3;j++){\n\t\tmemo[i][j]=0;\n\t\t\n\t}\t\n\tfor(int i=0;i<=R;i++)for(int j=0;j<=3;j++){\n\t\tdp[i][j]=0;\n\t\t\n\t}\t\n\tfor(auto v:ve)memo[v.first][v.second]=1;\n\t\n\t\n\tfor(int i=0;i<R;i++){\n\t\t\n\t\tif(memo[i][0]+memo[i][1]+memo[i][2]==3){\n\t\t\t\n\t\t\tdp[i+1][0]=max(dp[i+1][0],max({dp[i][0],dp[i][1],dp[i][2],dp[i][3]})+1);\n\t\t}\n\t\t\n\t\tif(i>=2){\n\t\t\tif(memo[i-2][0]+memo[i-1][1]+memo[i][2]==3){\n\t\t\t\t\n\t\t\t\tdp[i+1][3]=max(dp[i+1][3],max({dp[i][2],dp[i][3]})+1);\n\t\t\t}\n\t\t}\n\t\t\n\t\tdp[i+1][1]=max(dp[i+1][1],dp[i][0]);\n\t\tdp[i+1][2]=max(dp[i+1][2],dp[i][1]);\n\t\tdp[i+1][3]=max({dp[i+1][3],dp[i][2],dp[i][3]});\n\t\t\n\n\t\t\n\t}\n/*\n\tfor(int i=0;i<R;i++){\n\t\tfor(int j=0;j<3;j++){\n\t\tcout<<memo[i][j]<<\" \";\n\t\t}\n\t\tcout<<endl;\n\t}\n\tcout<<endl;\n\t\n\tcout<<max({dp[R][0],dp[R][1],dp[R][2],dp[R][3]})<<endl;\n\tcout<<endl;\n*/\n\treturn max({dp[R][0],dp[R][1],dp[R][2],dp[R][3]});\n\t\n}\n\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tcin>>h>>w;\n\tfor(int i=0;i<h;i++){\n\t\tstring s;\n\t\tcin>>s;\n\t\tfor(int j=0;j<w;j++){\n\t\t\tif(s[j]=='R')ban[i][j]=0;\n\t\t\telse if(s[j]=='G')ban[i][j]=1;\n\t\t\telse if(s[j]=='W')ban[i][j]=2;\n\t\t\telse ban[i][j]=inf;\n\t\t//cout<<i<<\" \"<<j<<\" \"<<ban[i][j]<<endl;\t\n\t\t}\n\t\t\n\t}\n\tint ans=0;\n\tfor(int i=0;i<h;i++)for(int j=0;j<w;j++)if(!vis[i][j])if(ban[i][j]==0){\n\t//\tcout<<i<<\" \"<<j<<endl;\n\t\tve.clear();\n\t\tdfs(i,j);\n\t\t//cout<<\"d\"<<endl;\n\t\tint y=solve();\n\t\tans+=y;\n\t}\n\tcout<<ans<<endl;\n\t\nreturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 690, "memory_kb": 145024, "score_of_the_acc": -1.0055, "final_rank": 14 }, { "submission_id": "aoj_0649_3668652", "code_snippet": "#include<cstdio>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\n#define Maxn 3010\n\nint n, m, Row[Maxn][Maxn], Col[Maxn][Maxn], f[Maxn][Maxn][2][2], Res;\nchar D[Maxn][Maxn];\n\nint main()\n{\n scanf(\"%d%d\", &n, &m); getchar();\n for (int i=1; i<=n; i++)\n {\n for (int j=1; j<=m; j++)\n {\n scanf(\"%c\", &D[i][j]);\n if (D[i][j]=='W')\n {\n if ((i>=3) && (D[i-2][j]=='R') && (D[i-1][j]=='G'))\n Row[i-2][j]=1;\n if ((j>=3) && (D[i][j-2]=='R') && (D[i][j-1]=='G'))\n Col[i][j-2]=1;\n }\n }\n getchar();\n }\n /*\n for (int i=1; i<=n; i++)\n {\n for (int j=1; j<=m; j++) printf(\"(%d %d)\", Row[i][j], Col[i][j]); printf(\"\\n\");\n }\n */\n for (int i=1; i<=n; i++)\n {\n for (int j=2; j<=m; j++)\n {\n f[i+1][j-1][0][0]=max(f[i][j][0][1], f[i][j][0][0]+Col[i][j]);\n f[i+1][j-1][1][0]=max(f[i][j][0][1], f[i][j][0][0])+Row[i][j];\n f[i+1][j-1][0][1]=max(f[i][j][1][0], f[i][j][1][1]);\n f[i+1][j-1][1][1]=max(f[i][j][1][0], f[i][j][1][1])+Row[i][j];\n }\n int L = max(max(f[i][1][0][0], f[i][1][0][1]), max(f[i][1][1][0], f[i][1][1][1]))+Row[i][1];\n Res+=max(f[i][1][0][0]+Col[i][1], L);\n }\n for (int i=1; i<=m; i++) Res+=f[n+1][i][0][0];\n printf(\"%d\\n\", Res);\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 223168, "score_of_the_acc": -1.1657, "final_rank": 19 }, { "submission_id": "aoj_0649_3463248", "code_snippet": "#include <bits/stdc++.h>\n#define FOR(i,k,n) for(int i=(k);i<(int)(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(x) begin(x),end(x)\n\nusing namespace std;\nusing ll = int64_t;\n\nint main() {\n int n,m;\n cin>>n>>m;\n vector<string> t(n);\n REP(i,n) cin>>t[i];\n vector<vector<bool>> th(n, vector<bool>(m, false));\n vector<vector<bool>> tv(n, vector<bool>(m, false));\n REP(i,n)REP(j,m) {\n if (i+2 < n) {\n if (t[i][j] == 'R' && t[i+1][j] == 'G' && t[i+2][j] == 'W') {\n tv[i][j] = true;\n }\n }\n if (j+2 < m) {\n if (t[i][j] == 'R' && t[i][j+1] == 'G' && t[i][j+2] == 'W') {\n th[i][j] = true;\n }\n }\n }\n ll sum = 0;\n REP(d,n+m) {\n vector<vector<ll>> dp(max(n, m)+1, vector<ll>(4, 0));\n REP(i,n) {\n int j = d - i;\n if (j >= m || j < 0) continue;\n REP(k,2)REP(l,2) {\n int index = k + 2*l;\n if (tv[i][j]) {\n int index2 = 1 + 2*k;\n dp[i+1][index2] = max(dp[i+1][index2], dp[i][index] + 1);\n }\n if (th[i][j]) {\n int index2 = 0 + 2*k;\n if (!k && !l) {\n dp[i+1][index2] = max(dp[i+1][index2], dp[i][index] + 1);\n }\n }\n int index2 = 0 + 2*k;\n dp[i+1][index2] = max(dp[i+1][index2], dp[i][index] + 0);\n }\n }\n ll mx = 0;\n for(auto&& v : dp)\n for (ll e : v)\n mx = max(mx, e);\n sum += mx;\n }\n cout << sum << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 1320, "memory_kb": 26516, "score_of_the_acc": -0.7922, "final_rank": 12 }, { "submission_id": "aoj_0649_3376245", "code_snippet": "#include <iostream>\n#include <iomanip>\n#include <fstream>\n#include <stdio.h>\n#include <math.h>\n#include <time.h>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <list>\n#include <set>\n#include <stack>\n#include <queue>\n#include <cstdlib>\n#include <algorithm>\n#include <random>\n#include <cassert>\nusing namespace std;\n#define LL long long\n#define MP(a, b) make_pair(a, b)\n#define POWER9 1000000000\n#define MOD POWER9+7\n#undef INT_MIN\n#undef INT_MAX\n#define INT_MIN -2147483647\n#define INT_MAX 2147483647\n#define LL_MIN (LL)-9223372036854775807\n#define LL_MAX (LL)9223372036854775807\n#define PI 3.14159265359\n\nint N,M,A[3000][3000];\n\nint tmp;\nint dp2[3000][2][2];\nint solve2(int now, int old1, int old2){\n\tint x = now+tmp-N+1;\n\tint y = N-1-now;\n\tif(tmp < N-1){\n\t\ty -= N-tmp-1;\n\t\tx += N-tmp-1;\n\t}\n\tif(x == M || y == -1) return 0;\n\tif(dp2[now][old1][old2] != -1) return dp2[now][old1][old2];\n\tif(A[y][x] != 0) return solve2(now+1,0,old1);\n\tint re = solve2(now+1,0,old1);\n\tif(y+2<N && A[y+1][x]==1 && A[y+2][x]==2 && old1==0 && old2==0){\n\t\tre = max(re, solve2(now+1,0,old1)+1);\n\t}\n\tif(x+2<M && A[y][x+1]==1 && A[y][x+2]==2){\n\t\tre = max(re, solve2(now+1,1,old1)+1);\n\t}\n\t//cout << re << endl;\n\treturn dp2[now][old1][old2] = re;\n}\n\nint dp1[6000];\nint solve1(int now){\n\tif(now == N+M-3) return 0;\n\tif(dp1[now] != -1) return dp1[now];\n\ttmp = now;\n\tfor(int i=0; i<min(N,M); i++){\n\t\tdp2[i][0][0] = -1;\n\t\tdp2[i][0][1] = -1;\n\t\tdp2[i][1][0] = -1;\n\t\tdp2[i][1][1] = -1;\n\t}\n\tdp1[now] = solve2(0,0,0);\n\tdp1[now] += solve1(now+1);\n\t//cout << dp1[now] << endl;\n\treturn dp1[now];\n}\n\n\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout << setprecision(9);\n\n\t\n\n\tcin >> N >> M;\n\t/*for(int i=0; i<6; i++){\n\t\tfor(int j=0; j<3; j++){\n\t\t\tint x =j+i-N+1;\n\t\t\tint y = N-1-j;\n\t\t\tif(i < N-1){\n\t\t\t\ty -= N-i-1;\n\t\t\t\tx += N-i-1;\n\t\t\t}\n\t\t\tcout << x << \" \" << y << endl;\n\t\t}\n\t}*/\n\tfor(int i=0; i<N; i++){\n\t\tstring S;\n\t\tcin >> S;\n\t\tfor(int j=0; j<M; j++){\n\t\t\tif(S[j] == 'R') A[i][j] = 0;\n\t\t\tif(S[j] == 'G') A[i][j] = 1;\n\t\t\tif(S[j] == 'W') A[i][j] = 2;\n\t\t}\n\t}\n\tfor(int i=0; i<N+M-3; i++) dp1[i] = -1;\n\tcout << solve1(0) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 38828, "score_of_the_acc": -0.2759, "final_rank": 8 }, { "submission_id": "aoj_0649_3376166", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint N, M;\nchar field[3005][3005];\nll ans;\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tcin >> N >> M;\n\n\tfor (int i = 0;i < N;i++){\n\t\tfor (int j = 0;j < M;j++){\n\t\t\tcin >> field[i][j];\n\t\t}\n\t}\n\n\tans = 0;\n\n\tfor (int si = 1;si <= N+M-3;si++){\n\t\tint i,j;\n\t\tif(si <= N-1){\n\t\t\ti = si; j = 0;\n\t\t} else {\n\t\t\ti = N-1; j = si-(N-1);\n\t\t}\n\n\t\tll dp[3005][2][2]; memset(dp, 0, sizeof(dp));\n\t\tint idx = 0;\n\n\t\twhile(i >= 0 && j < M){\n\t\t\tfor (int k = 0;k < 2;k++){\n\t\t\t\tfor (int l = 0;l < 2;l++){\n\t\t\t\t\tif(idx == 0 && !(k == 0 && l == 0)) continue;\n\t\t\t\t\tif(l == 1 && k == 1) continue;\n\t\t\t\t\tdp[idx+1][0][0] = max(dp[idx+1][0][0], dp[idx][k][l]);\n\t\t\t\t\tif(field[i][j] != 'G') continue;\n\t\t\t\t\tif(i-1 >= 0 && i+1 < N && field[i-1][j] == 'R' && field[i+1][j] == 'W' && l == 0){\n\t\t\t\t\t\tdp[idx+1][1][0] = max(dp[idx+1][1][0], dp[idx][k][l] + 1);\n\t\t\t\t\t}\n\t\t\t\t\tif(j-1 >= 0 && j+1 < M && field[i][j-1] == 'R' && field[i][j+1] == 'W' && k == 0){\n\t\t\t\t\t\tdp[idx+1][0][1] = max(dp[idx+1][0][1], dp[idx][k][l] + 1);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\ti--; j++;\n\t\t\tidx++;\n\t\t}\n\n\t\tll MAX = -1;;\n\t\tfor (int k = 0;k < 2;k++){\n\t\t\tfor (int l = 0;l < 2;l++){\n\t\t\t\tMAX = max(MAX, dp[idx][k][l]);\n\t\t\t}\n\t\t}\n\n\t\tans += MAX;\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 12080, "score_of_the_acc": -0.1106, "final_rank": 3 } ]
aoj_0644_cpp
水ようかん (Mizuyokan) 問題文 水ようかんとは,おもに小豆からなる餡を型に流し込んで寒天で固めることにより作られる和菓子である.いま,JOI 君の手元には,横長の直方体の形をした水ようかんがひとつある.JOI 君は,今日のおやつとしてこの水ようかんを食べる予定である. この水ようかんには,縦方向の切れ目が全部で N-1 箇所に入っている.水ようかんの長さは L_1 + L_2 + ... + L_N であり, i 番目 (1 ≦ i ≦ N-1) の切れ目は,左から L_1 + L_2 + ... + L_i の位置にある. この水ようかんは丸ごと食べるには大きすぎるので,JOI 君は,水ようかんに入っている切れ目から 1 箇所以上を選び,選んだ切れ目に沿って水ようかんを切って,複数のピースに切り分けることにした.ただし,ピースの大きさが不揃いでは見栄えが悪いので,長さ最大のピースと最小のピースの長さの差ができるだけ小さくなるように切ることにした. 長さ最大のピースと最小のピースの長さの差の最小値を求めよ. 制約 2 \leq N \leq 50 1 \leq L_i \leq 1000 (1 \leq i \leq N) 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N L_1 L_2 : L_N 出力 長さ最大のピースと最小のピースの長さの差の最小値を 1 行で出力せよ. 入出力例 入力例 1 11 2 3 8 4 7 6 6 5 1 7 5 出力例 1 2 この例では, 4 番目および 7 番目の切れ目に沿って切り分けることで,長さ 17, 19, 18 の 3 つのピースに切り分けることができる. このとき,いちばん長いピースは長さ 19 で,いちばん短いピースは長さ 17 であるので,長さの差は 2 となる. これが最小値なので, 2 を出力する. 入力例 2 2 1 10 出力例 2 9 どんなに大きさが不揃いであっても,必ず 1 箇所以上を切る必要がある. 入力例 3 5 5 5 5 5 5 出力例 3 0 この例では水ようかんをちょうど同じ大きさの 5 つのピースに分割できる. 情報オリンピック日本委員会作 『第 17 回日本情報オリンピック JOI 2017/2018 予選競技課題』
[ { "submission_id": "aoj_0644_9816648", "code_snippet": "#include <iostream>\n#include <cstdint>\n#include <vector>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\t\n\tuint16_t N, i;\n\tcin >> N;\n\tvector<uint16_t> L(N);\n\tfor (i = 0; i != N; ++i) cin >> L[i];\n\n\tuint16_t length = 0;\n\tfor (i = 0; i != N; ++i) length += L[i];\n\n\tuint16_t l, r, S, S_min, S_max, ans = UINT16_MAX;\n\tfor (r = 1; r != length; ++r)\n\t\tfor (l = 1; l <= r; ++l)\n\t\t{\n\t\t\tS = 0, S_min = UINT16_MAX, S_max = 0;\n\t\t\tfor (i = 0; i != N; ++i)\n\t\t\t{\n\t\t\t\tS += L[i];\n\t\t\t\tif (S > r) break;\n\t\t\t\telse if (S >= l)\n\t\t\t\t{\n\t\t\t\t\tif (S < S_min) S_min = S;\n\t\t\t\t\tif (S > S_max) S_max = S;\n\t\t\t\t\tS = 0;\n\t\t\t\t}\n\t\t\t}\n\n\t\t\tif (i == N)\n\t\t\t{\n\t\t\t\tif (S != 0)\n\t\t\t\t{\n\t\t\t\t\tif (S < S_min) S_min = S;\n\t\t\t\t\tif (S > S_max) S_max = S;\n\t\t\t\t}\n\n\t\t\t\tif (S_max - S_min < ans) ans = S_max - S_min;\n\t\t\t}\n\t\t}\n\n\tcout << ans << '\\n';\n\treturn 0;\n}", "accuracy": 0.3058823529411765, "time_ms": 1490, "memory_kb": 3448, "score_of_the_acc": -0.5295, "final_rank": 18 }, { "submission_id": "aoj_0644_9669817", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define LB(A,x) (lower_bound(ALL(A),x)-A.begin())\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\nint main(){\n int N;cin>>N;\n vector<ll>L(N+1);\n REP(i,N){\n cin>>L[i+1];\n L[i+1]+=L[i];\n }\n vector<vector<ll>>DP(N+1,vector<ll>(L[N],1e18));\n DP[0][L[N]-1]=0;\n FOR(i,1,N+1)REP(j,i)if(i-j<N){\n REP(k,L[N]){\n ll d=L[i]-L[j];\n chmin(DP[i][min(k,d)],max(d,DP[j][k]));\n }\n }\n ll ans=1e18;\n REP(i,L[N])chmin(ans,DP[N][i]-i);\n cout<<ans<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 22928, "score_of_the_acc": -0.4214, "final_rank": 13 }, { "submission_id": "aoj_0644_7072218", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n cin.tie(nullptr)->ios::sync_with_stdio(false);\n int64_t res = INT64_MAX;\n int64_t N; cin >> N;\n vector<int64_t> L(N); for(auto &in : L) cin >> in;\n vector<int64_t> pref = {0}; for(auto l : L) pref.push_back(pref.back() + l);\n for(int64_t mi = 1; mi <= pref[N-1]; mi++){\n int64_t pass = 60000, fail = mi-1;\n while(pass - fail > 1){\n int64_t mx = fail + (pass - fail) / 2;\n vector<bool> ok(N+1, false);\n ok[0] = true;\n for(int64_t pos = 1; pos <= N; pos++){\n for(int64_t bk = pos-1; bk >= 0; bk--){\n int64_t siz = pref[pos]-pref[bk];\n if(siz < mi or mx < siz) continue;\n if(pos == N and bk == 0) continue;\n if(ok[bk]){\n ok[pos] = true;\n break;\n }\n }\n }\n (ok[N] ? pass : fail) = mx;\n }\n res = min(res, pass - mi);\n }\n cout << res << '\\n';\n}", "accuracy": 1, "time_ms": 500, "memory_kb": 3460, "score_of_the_acc": -0.1848, "final_rank": 10 }, { "submission_id": "aoj_0644_7072196", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n cin.tie(nullptr)->ios::sync_with_stdio(false);\n int64_t res = INT64_MAX;\n int64_t N; cin >> N;\n vector<int64_t> L(N); for(auto &in : L) cin >> in;\n vector<int64_t> pref = {0}; for(auto l : L) pref.push_back(pref.back() + l);\n for(int64_t mi = 1; mi <= pref[N-1]; mi++){\n int64_t pass = pref.back(), fail = mi-1;\n while(pass - fail > 1){\n int64_t mx = fail + (pass - fail) / 2;\n vector<bool> ok(N+1, false);\n ok[0] = true;\n for(int64_t pos = 1; pos <= N; pos++){\n for(int64_t bk = pos-1; bk >= 0; bk--){\n int64_t siz = pref[pos]-pref[bk];\n if(siz < mi or mx < siz) continue;\n if(ok[bk]){\n ok[pos] = true;\n break;\n }\n }\n }\n (ok[N] ? pass : fail) = mx;\n }\n res = min(res, pass - mi);\n }\n cout << res << '\\n';\n}", "accuracy": 0.24705882352941178, "time_ms": 10, "memory_kb": 3504, "score_of_the_acc": -0.015, "final_rank": 20 }, { "submission_id": "aoj_0644_7072184", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n cin.tie(nullptr)->ios::sync_with_stdio(false);\n int64_t res = INT64_MAX;\n int64_t N; cin >> N;\n vector<int64_t> L(N); for(auto &in : L) cin >> in;\n vector<int64_t> pref = {0}; for(auto l : L) pref.push_back(pref.back() + l);\n for(int64_t mi = 0; mi <= pref[N-1]; mi++){\n int64_t pass = pref.back(), fail = mi-1;\n while(pass - fail > 1){\n int64_t mx = fail + (pass - fail) / 2;\n vector<bool> ok(N+1, false);\n ok[0] = true;\n for(int64_t pos = 1; pos <= N; pos++){\n for(int64_t bk = pos-1; bk >= 0; bk--){\n int64_t siz = pref[pos]-pref[bk];\n if(siz < mi or mx < siz) continue;\n if(ok[bk]){\n ok[pos] = true;\n break;\n }\n }\n }\n (ok[N] ? pass : fail) = mx;\n }\n res = min(res, pass - mi);\n }\n cout << res << '\\n';\n}", "accuracy": 0.24705882352941178, "time_ms": 10, "memory_kb": 3460, "score_of_the_acc": -0.0141, "final_rank": 19 }, { "submission_id": "aoj_0644_6203770", "code_snippet": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main(){\n int n, l, rui[55], ma[55], ans;\n cin >> n;\n rui[0] = 0;\n for(int i=1;i<=n;i++){\n cin >> l;\n rui[i] = l+rui[i-1];\n }\n ans = rui[n]*2;\n for(int mi=1;mi<rui[n];mi++){\n for(int j=1;j<=n;j++){\n ma[j] = rui[n]*2;\n if(j < n && rui[j] >= mi) ma[j] = rui[j];\n for(int k=1;k<j;k++){\n if(ma[k] < mi || rui[j]-rui[k] < mi) continue;\n ma[j] = min(ma[j], max(ma[k], rui[j]-rui[k]));\n }\n }\n ans = min(ans, ma[n]-mi);\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3092, "score_of_the_acc": -0.0242, "final_rank": 7 }, { "submission_id": "aoj_0644_6203758", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\nint main(){\n int n, l, rui[55], ma[55], ans;\n vector<int> mi;\n cin >> n;\n rui[0] = 0;\n for(int i=1;i<=n;i++){\n cin >> l;\n rui[i] = l+rui[i-1];\n }\n ans = rui[n]+rui[n];\n for(int mi=1;mi<rui[n];mi++){\n for(int j=1;j<=n;j++){\n ma[j] = rui[n]+rui[n];\n if(j < n && rui[j] >= mi) ma[j] = rui[j];\n for(int k=1;k<j;k++){\n if(rui[k] < mi || ma[k] < mi || rui[j]-rui[k] < mi) continue;\n ma[j] = min(ma[j], max(ma[k], rui[j]-rui[k]));\n }\n }\n ans = min(ans, ma[n]-mi);\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3092, "score_of_the_acc": -0.0207, "final_rank": 4 }, { "submission_id": "aoj_0644_6132356", "code_snippet": "#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++; //res += n % 10;\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\nll kaijyo[1000005];\nvoid nCkinit(ll n, ll m) {\n\tll cnt = 1; kaijyo[0] = 1;\n\tfor (int h = 1; h <= n; h++) { cnt *= h; cnt %= m; kaijyo[h] = cnt; }\n}\nll nCk(ll n, ll k, ll m) {\n\t/*ll a = 1, b = 1;\n\tfor (int h = 1; h <= n; h++) { a *= h; a %= m; }\n\tfor (int h = 1; h <= k; h++) { b *= h; b %= m; }\n\tfor (int h = 1; h <= n - k; h++) { b *= h; b %= m; }*/\n\tll a = kaijyo[n], b = kaijyo[k] * kaijyo[n - k] % m;\n\treturn a * modpow(b, m - 2, m) % m;\n}\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <string, string> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to, cost; };\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\nstruct status {\n\tll a; ll b; ll s;\n\n\tbool operator<(const status& rhs) const { return s < rhs.s; };\n\tbool operator>(const status& rhs) const { return s > rhs.s; };\n};\n\nint main() {\n\tsrand((unsigned)time(NULL));\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tll n, ma = 0, sum = 0; cin >> n;\n\tvector<ll>l(n + 1);\n\trep2(i, n) { cin >> l[i]; sum += l[i]; ma = max(ma, l[i]); }\n\tll ans = INF;\n\tfor (int i = ma; i < sum; i++) {//上限\n\t\tvector<ll>dp(n + 1);//i番目を切る時の最小値の最大値\n\t\tdp[0] = INF;\n\t\trep2(j, n) {\n\t\t\tll lsum = 0;\n\t\t\tfor (int k = j; k > 0; k--) {\n\t\t\t\tlsum += l[k];\n\t\t\t\tif (lsum > i) { break; }\n\t\t\t\telse { dp[j] = max(dp[j], min(dp[k - 1], lsum)); }\n\t\t\t}\n\t\t}\n\t\tans = min(ans, i - dp[n]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3468, "score_of_the_acc": -0.0212, "final_rank": 5 }, { "submission_id": "aoj_0644_6132354", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm> \n#include<cmath>\n#include<ctime>\n#include<map>\n#include<vector>\n#include<math.h>\n#include<stdio.h>\n#include<stack>\n#include<queue>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<bitset>\n#include<functional>\n#include <fstream>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++; //res += n % 10;\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\nll kaijyo[1000005];\nvoid nCkinit(ll n, ll m) {\n\tll cnt = 1; kaijyo[0] = 1;\n\tfor (int h = 1; h <= n; h++) { cnt *= h; cnt %= m; kaijyo[h] = cnt; }\n}\nll nCk(ll n, ll k, ll m) {\n\t/*ll a = 1, b = 1;\n\tfor (int h = 1; h <= n; h++) { a *= h; a %= m; }\n\tfor (int h = 1; h <= k; h++) { b *= h; b %= m; }\n\tfor (int h = 1; h <= n - k; h++) { b *= h; b %= m; }*/\n\tll a = kaijyo[n], b = kaijyo[k] * kaijyo[n - k] % m;\n\treturn a * modpow(b, m - 2, m) % m;\n}\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <string, string> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to, cost; };\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\nstruct status {\n\tll a; ll b; ll s;\n\n\tbool operator<(const status& rhs) const { return s < rhs.s; };\n\tbool operator>(const status& rhs) const { return s > rhs.s; };\n};\n\nint main() {\n\tsrand((unsigned)time(NULL));\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tll n, ma = 0, sum = 0; cin >> n;\n\tvector<ll>l(n + 1);\n\trep2(i, n) { cin >> l[i]; sum += l[i]; ma = max(ma, l[i]); }\n\tll ans = INF;\n\tfor (int i = ma; i < sum; i++) {//上限\n\t\tvector<ll>dp(n + 1);//i番目を切る時の最小値の最大値\n\t\tdp[0] = INF;\n\t\trep2(j, n) {\n\t\t\tll lsum = 0;\n\t\t\tfor (int k = j; k > 0; k--) {\n\t\t\t\tlsum += l[k];\n\t\t\t\tif (lsum > i) { break; }\n\t\t\t\telse { dp[j] = max(dp[j], min(dp[k - 1], lsum)); }\n\t\t\t}\n\t\t}\n\t\tans = min(ans, i - dp[n]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3512, "score_of_the_acc": -0.0221, "final_rank": 6 }, { "submission_id": "aoj_0644_6111706", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n vector<int> a(n),sumv(n+1,0);\n rep(i,n){\n in(a[i]);\n sumv[i+1]=sumv[i]+a[i];\n }\n //最小値,最大値\n vector<set<pair<int,int>>> dp(n+1);\n dp[0].insert({INF,0});\n for(int i=0;i<n;i++){\n for(int j=i+1;j<=n;j++){\n if(i==0&&j==n)continue;\n int d=sumv[j]-sumv[i];\n for(auto p:dp[i]){\n dp[j].insert({min(p.first,d),max(p.second,d)});\n }\n }\n }\n int ans=INF;\n for(auto p:dp[n]){\n chmin(ans,abs(p.first-p.second));\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 52688, "score_of_the_acc": -1.1533, "final_rank": 15 }, { "submission_id": "aoj_0644_5329733", "code_snippet": "// clang-format off\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = int64_t;\nusing ld = long double;\nusing Pi = pair<int, int>;\nusing Pl = pair<ll, ll>;\nusing Vi = vector<int>;\nusing Vl = vector<ll>;\n#define FOR(i, m, n) for(int i = (m); i < (n); ++i)\n#define FORR(i, m, n) for(int i = (m)-1; i >= (n); --i)\n#define rep(i, n) FOR(i, 0, n)\n#define repn(i, n) FOR(i, 1, n+1)\n#define repr(i, n) FORR(i, n, 0)\n#define repnr(i, n) FORR(i, n+1, 1)\n#define all(s) (s).begin(), (s).end()\ntemplate <class T, class U>\nbool chmax(T &a, const U b) { return a < b ? a = b, true : false; }\ntemplate <class T, class U>\nbool chmin(T &a, const U b) { return b < a ? a = b, true : false; }\ntemplate <class T>\nistream &operator>>(istream &is, vector<T> &v) { for (T &i : v) is >> i; return is; }\ntemplate <class T>\nostream &operator<<(ostream &os, const vector<T> &v) { for (const T &i : v) os << i << ' '; return os; }\ntemplate <class Head, class... Tail>\nvoid co(Head&& head, Tail&&... tail) {\n if constexpr(sizeof...(tail)==0) cout<<head<<'\\n'; else cout<<head<<' ',co(forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head&& head, Tail&&... tail) {\n if constexpr(sizeof...(tail)==0) cerr<<head<<'\\n'; else cerr<<head<<' ',ce(forward<Tail>(tail)...);\n}\ntemplate<typename T, typename... Args>\nauto make_vector(T x, int arg, Args ...args) {\n if constexpr(sizeof...(args)==0) return vector<T>(arg, x); else return vector(arg,make_vector<T>(x, args...));\n}\nvoid sonic() { ios::sync_with_stdio(false); cin.tie(nullptr); }\nvoid setp(const int n) { cout << fixed << setprecision(n); }\nconstexpr int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconst double PI = acos(-1);\n\n// clang-format on\n\nint main(void) {\n int n;\n cin >> n;\n Vi l(n);\n cin >> l;\n int s = accumulate(all(l), 0);\n int m = *max_element(all(l));\n vector<int> cs(n + 1);\n repr(i, n) cs[i] = l[i] + cs[i + 1];\n\n int ans = Inf;\n FOR(i, m, s) {\n vector<int> dp(n + 1);\n dp[0] = Inf;\n rep(j, n) {\n repr(k, j + 1) {\n if (cs[k] - cs[j + 1] > i)\n break;\n chmax(dp[j + 1], min(dp[k], cs[k] - cs[j + 1]));\n }\n }\n chmin(ans, i - dp[n]);\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3456, "score_of_the_acc": -0.0245, "final_rank": 8 }, { "submission_id": "aoj_0644_5003935", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint l[51],dp[51];\nint main(void)\n{\n\tint n,MIN,sum,lsum,i,j,k,ans,MAX2,a;\n\tscanf(\"%d\",&n);\n\tlsum=0;\n\tMAX2=0;\n\tans=50001;\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&l[i]);\n\t\tlsum+=l[i];\n\t\tMAX2=max(MAX2,l[i]);\n\t}\n\tfor(i=MAX2;i<lsum;i++){\n\t\tfor(j=0;j<n;j++){\n\t\t\tdp[j]=0;\n\t\t}\n\t\tsum=0;\n\t\tfor(j=0;j<n;j++){\n\t\t\tsum+=l[j];\n\t\t\tif(sum>i){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tdp[j]=sum;\n\t\t}\n\t\tfor(j=0;j<n;j++){\n\t\t\tsum=0;\n\t\t\tfor(k=j+1;k<n;k++){\n\t\t\t\tsum+=l[k];\n\t\t\t\tif(sum>i){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\ta=min(sum,dp[j]);\n\t\t\t\tdp[k]=max(a,dp[k]);\n\t\t\t}\n\t\t}\n\t\tans=min(ans,i-dp[n-1]);\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2764, "score_of_the_acc": -0.0106, "final_rank": 3 }, { "submission_id": "aoj_0644_4710957", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx\")\n#define all(x) (x).begin(),(x).end()\n#define rep(i,n) for(int (i)=0;i<(n);i++)\n#define rrep(i,n) for(int (i)=1;i<=(n);i++)\n#define REP(i,m,n) for(int (i)=(m);(i)<(n);(i)++)\n#define MOD 1000000007\n#define INF 1e18\n#define int long long\n#define endl \"\\n\"\n#define yorn(f) puts((f)?\"Yes\":\"No\")\n#define YORN(f) puts((f)?\"YES\":\"NO\")\ntypedef long long ll;\ntypedef pair<int, int> P;\nint gcd(int a,int b){return b?gcd(b,a%b):a;};\nint lcm(int a,int b){return a/gcd(a,b)*b;};\nint mod(int a,int b){return (a+b-1)/b;};\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A(&array)[N],const T &val){std::fill((T*)array,(T*)(array+N),val);}\ntemplate<class T>inline bool chmax(T& a,T b){if(a<b){a=b;return true;}return false;};\ntemplate<class T>inline bool chmin(T& a,T b){if(a>b){a=b;return true;}return false;};\n\nint n;\nvector<int> l(55);\nvector<int> sum(55);\nvector<int> yokan;\n\nbool check(int minlen, int maxlen) {\n\tvector<int> dp(55, 0);\n\tdp[0] = 1;\n\trrep(i, n) {\n\t\trep(j, i) {\n\t\t\tint nowlen = sum[i] - sum[j];\n\t\t\tif(minlen <= nowlen && nowlen <= maxlen && dp[j]) dp[i] = 1;\n\t\t}\n\t}\n\treturn dp[n];\n}\n\nsigned main() {\n\tcin.tie(0);\n\tcout.tie(0);\n\tios::sync_with_stdio(false);\n\t//cout << fixed << setprecision(15);\n\t\n\tcin >> n;\n\trep(i, n) {\n\t\tcin >> l[i];\n\t\tsum[i+1] = sum[i] + l[i];\n\t}\n\trep(i, n+1) {\n\t\tREP(j, i+1, n+1) {\n\t\t\tif(i == 0 && j == n) continue;\n\t\t\tyokan.push_back(sum[j] - sum[i]);\n\t\t}\n\t}\n\t//for(auto &x : yokan) cout << x << \" \";\n\tsort(all(yokan));\n\tint ans = sum[n];\n\trep(i, yokan.size()) {\n\t\tREP(j, i+1, yokan.size()) {\n\t\t\tint minlen = yokan[i];\n\t\t\tint maxlen = yokan[j];\n\t\t\tif(check(minlen, maxlen)) chmin(ans, maxlen - minlen);\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2880, "memory_kb": 3260, "score_of_the_acc": -1.0101, "final_rank": 14 }, { "submission_id": "aoj_0644_4229458", "code_snippet": "// #pragma GCC target(\"avx\") // CPU 処理並列化\n// #pragma GCC optimize(\"O3\") // CPU 処理並列化\n// #pragma GCC optimize(\"unroll-loops\") // 条件処理の呼び出しを減らす\n// #define BEGIN_STACK_EXTEND(size) void * stack_extend_memory_ = malloc(size);void * stack_extend_origin_memory_;char * stack_extend_dummy_memory_ = (char*)alloca((1+(int)(((long long)stack_extend_memory_)&127))*16);*stack_extend_dummy_memory_ = 0;asm volatile(\"mov %%rsp, %%rbx\\nmov %%rax, %%rsp\":\"=b\"(stack_extend_origin_memory_):\"a\"((char*)stack_extend_memory_+(size)-1024));\n// #define END_STACK_EXTEND asm volatile(\"mov %%rax, %%rsp\"::\"a\"(stack_extend_origin_memory_));free(stack_extend_memory_);\n\n#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<string>\n#include<string.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stdlib.h>\n#include<cassert>\n#include<time.h>\n#include<bitset>\n#include<numeric>\n#include<unordered_set>\n#include<unordered_map>\n#include<complex>\nusing namespace std;\nconst long long mod=1000000007;\nconst long long inf=mod*mod;\nconst long long d2=(mod+1)/2;\nconst long double EPS=1e-9;\nconst double INF=1e+10;\nconst double PI=acos(-1.0);\nconst int C_SIZE = 3100000;\nconst int UF_SIZE = 3100000;\nnamespace{\n\tlong long fact[C_SIZE];\n\tlong long finv[C_SIZE];\n\tlong long inv[C_SIZE];\n\tlong long Comb(int a,int b){\n\t \tif(a<b||b<0)return 0;\n\t \treturn fact[a]*finv[b]%mod*finv[a-b]%mod;\n\t}\n\tvoid init_C(int n){\n\t\tfact[0]=finv[0]=inv[1]=1;\n\t\tfor(int i=2;i<n;i++){\n\t\t\tinv[i]=(mod-(mod/i)*inv[mod%i]%mod)%mod;\n\t\t}\n\t\tfor(int i=1;i<n;i++){\n\t\t\tfact[i]=fact[i-1]*i%mod;\n\t\t\tfinv[i]=finv[i-1]*inv[i]%mod;\n\t\t}\n\t}\n\tlong long pw(long long a,long long b){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%mod;\n\t\t\ta=a*a%mod;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tlong long pw_mod(long long a,long long b,long long M){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%M;\n\t\t\ta=a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint pw_mod_int(int a,int b,int M){\n\t\tif(a<0)return 0;\n\t\tif(b<0)return 0;\n\t\tint ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=(long long)ret*a%M;\n\t\t\ta=(long long)a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint ABS(int a){return max(a,-a);}\n\tlong long ABS(long long a){return max(a,-a);}\n\tdouble ABS(double a){return max(a,-a);}\n\tint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\n\tint UF[UF_SIZE];\n\tvoid init_UF(int n){\n\t\tfor(int i=0;i<n;i++)UF[i]=-1;\n\t}\n\tint FIND(int a){\n\t\tif(UF[a]<0)return a;\n\t\treturn UF[a]=FIND(UF[a]);\n\t}\n\tvoid UNION(int a,int b){\n\t\ta=FIND(a);b=FIND(b);if(a==b)return;\n\t\tif(UF[a]>UF[b])swap(a,b);\n\t\tUF[a]+=UF[b];UF[b]=a;\n\t}\n}\n// ここから編集しろ\nint p[60];\nint sum[60];\nint dp[60][51000];\nint main(){\n\tint a;scanf(\"%d\",&a);\n\t// int sum=0;\n\tfor(int i=0;i<a;i++)scanf(\"%d\",p+i);\n\tfor(int i=0;i<a;i++)sum[i+1]=sum[i]+p[i];\n\tfor(int i=0;i<60;i++)for(int j=0;j<51000;j++)dp[i][j]=mod;\n\tfor(int i=0;i<51000;i++)dp[0][i]=0;\n\tfor(int i=0;i<a;i++){\n\t\tfor(int j=1;j<51000;j++){\n\t\t\tif(dp[i][j]==mod)continue;\n\t\t\tfor(int k=i+1;k<=a;k++){\n\t\t\t\tif(i==0&&k==a)continue;\n\t\t\t\tint val=sum[k]-sum[i];\n\t\t\t\tif(val<j)continue;\n\t\t\t\tdp[k][j]=min(dp[k][j],max(val,dp[i][j]));\n\t\t\t}\n\t\t}\n\t}\n\tint ret=mod;\n\tfor(int i=0;i<51000;i++){\n\t\t// if(dp[a][i]<100)printf(\"%d: %d\\n\",i,dp[a][i]);\n\t\tret=min(ret,dp[a][i]-i);\n\t}\n\tprintf(\"%d\\n\",ret);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 14716, "score_of_the_acc": -0.2465, "final_rank": 12 }, { "submission_id": "aoj_0644_4131818", "code_snippet": "#include <iostream>\n#include <vector>\n\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int n;\n std::cin >> n;\n\n std::vector<int> ls(n + 1);\n ls[0] = 0;\n for (int i = 1; i <= n; ++i) {\n int l;\n std::cin >> l;\n ls[i] = ls[i - 1] + l;\n }\n int lsum = ls.back();\n\n int ans = INF;\n for (int min = 0; min < lsum; ++min) {\n std::vector<int> lodp(n + 1, INF), tidp(n + 1, INF);\n lodp[0] = 0;\n for (int r = 1; r <= n; ++r) {\n for (int l = 0; l < r; ++l) {\n int len = ls[r] - ls[l];\n if (len < min) continue;\n lodp[r] = std::min(lodp[r], std::max(lodp[l], len));\n tidp[r] = std::min(tidp[r], std::max(tidp[l], len));\n if (len > min) continue;\n tidp[r] = std::min(tidp[r], std::max(lodp[l], len));\n }\n }\n ans = std::min(ans, tidp[n] - min);\n }\n\n std::cout << ans << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 3220, "score_of_the_acc": -0.0372, "final_rank": 9 }, { "submission_id": "aoj_0644_4023140", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nsigned main(){ \n long long n,l[1000000],ans=100000000;\n cin>>n;\n for(int i=0;i<n;i++){\n cin>>l[i];\n if(i!=0){\n l[i]+=l[i-1];\n }\n }\n for(int bit =0;bit<(1<<n-1);bit++){\n vector<int> s;\n long long a=0,c=0;\n for(int i=0;i<n;i++){\n if(bit & (1<<i)){\n\ts.push_back(l[i]-a);\n\ta=l[i];\n\tif(i==n-1)\n\t c++;\n }\n }\n int d[100000];\n if(s.size()==0){\n continue;\n }\n if(c==0){\n s.push_back(l[n-1]-a);\n //cout<<l[n-1]<<endl;\n }\n sort(s.begin(),s.end());\n /*/for(int i=0;i<s.size();i++){\n cout<<s[i]<<\" \";\n }/*/\n //cout<<endl;\n if(ans>s[s.size()-1]-s[0]){\n ans=s[s.size()-1]-s[0];\n //cout<<s[s.size()-1]<<\" \"<<s[0]<<\" \"<<ans<<endl;\n /*/for(int i=0;i<s.size();i++){\n\tcout<<s[i]<<\" \";\n\t}/*/\n //cout<<endl;\n }\n }\n cout<<ans<<endl;\n return(0);\n}", "accuracy": 0.38823529411764707, "time_ms": 60, "memory_kb": 3176, "score_of_the_acc": -0.0258, "final_rank": 16 }, { "submission_id": "aoj_0644_4022889", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nsigned main(){ \n int n,l[10000],ans=100000000;\n cin>>n;\n for(int i=0;i<n;i++){\n cin>>l[i];\n if(i!=0){\n l[i]+=l[i-1];\n }\n }\n for(int bit =0;bit<(1<<n-1);bit++){\n vector<int> s;\n int a=0,c=0;\n for(int i=0;i<n;i++){\n if(bit & (1<<i)){\n\ts.push_back(l[i]-a);\n\ta=l[i];\n\tif(i==n-1)\n\t c++;\n }\n }\n int d[100000];\n if(s.size()==0){\n continue;\n }\n if(c==0){\n s.push_back(l[n-1]-a);\n //cout<<l[n-1]<<endl;\n }\n sort(s.begin(),s.end());\n /*/for(int i=0;i<s.size();i++){\n cout<<s[i]<<\" \";\n }/*/\n //cout<<endl;\n if(ans>s[s.size()-1]-s[0]){\n ans=s[s.size()-1]-s[0];\n //cout<<s[s.size()-1]<<\" \"<<s[0]<<\" \"<<ans<<endl;\n /*/for(int i=0;i<s.size();i++){\n\tcout<<s[i]<<\" \";\n\t}/*/\n //cout<<endl;\n }\n }\n cout<<ans<<endl;\n return(0);\n}", "accuracy": 0.38823529411764707, "time_ms": 60, "memory_kb": 3176, "score_of_the_acc": -0.0258, "final_rank": 16 }, { "submission_id": "aoj_0644_3982241", "code_snippet": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\nint l[51],dp[51];\nint main(void)\n{\n\tint n,MIN,sum,lsum,i,j,k,ans,MAX2,a;\n\tscanf(\"%d\",&n);\n\tlsum=0;\n\tMAX2=0;\n\tans=50001;\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d\",&l[i]);\n\t\tlsum+=l[i];\n\t\tMAX2=max(MAX2,l[i]);\n\t}\n\tfor(i=MAX2;i<lsum;i++){\n\t\tfor(j=0;j<n;j++){\n\t\t\tdp[j]=0;\n\t\t}\n\t\tsum=0;\n\t\tfor(j=0;j<n;j++){\n\t\t\tsum+=l[j];\n\t\t\tif(sum>i){\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tdp[j]=sum;\n\t\t}\n\t\tfor(j=0;j<n;j++){\n\t\t\tsum=0;\n\t\t\tfor(k=j+1;k<n;k++){\n\t\t\t\tsum+=l[k];\n\t\t\t\tif(sum>i){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\ta=min(sum,dp[j]);\n\t\t\t\tdp[k]=max(a,dp[k]);\n\t\t\t}\n\t\t}\n\t\tans=min(ans,i-dp[n-1]);\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 2756, "score_of_the_acc": -0.0105, "final_rank": 2 }, { "submission_id": "aoj_0644_3977877", "code_snippet": "#include \"iostream\"\n#include \"climits\"\n#include \"list\"\n#include \"queue\"\n#include \"stack\"\n#include \"set\"\n#include \"functional\"\n#include \"algorithm\"\n#include \"string\"\n#include \"map\"\n#include \"unordered_map\"\n#include \"unordered_set\"\n#include \"iomanip\"\n#include \"cmath\"\n#include \"random\"\n#include \"bitset\"\n#include \"cstdio\"\n\nusing namespace std;\n\nconst long long int MOD = 1000000007;\nconst long double EPS = 1e-8;\n\nlong long int N, M, K, H, W, L, R;\n\nint main() {\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\n\tcin >> N;\n\tvector<int>v(N + 1);\n\tfor (int i = 1; i <= N; i++) {\n\t\tcin >> v[i];\n\t\tv[i] += v[i - 1];\n\t}\n\tL = -1;\n\tR = 50000;\n\twhile (R - L > 1) {\n\t\tint mid = (R + L + 1) / 2;\n\t\tvector<vector<int>>dp(N + 1, vector<int>(25001));\n\t\tfor (int i = 0; i <= 25000; i++) {\n\t\t\tdp[0][i] = 1;\n\t\t}\n\t\tfor (int i = 1; i <= N; i++) {\n\t\t\tfor (int j = max(0, i - (int)N + 1); j < i; j++) {\n\t\t\t\tfor (int k = 1; k <= 25000; k++) {\n\t\t\t\t\tif (k + mid >= v[i] - v[j]&&k<=v[i]-v[j]) {\n\t\t\t\t\t\tdp[i][k] |= dp[j][k];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tint box = 0;\n\t\tfor (int i = 1; i <= 25000; i++) {\n\n\t\t\tbox |= dp[N][i];\n\t\t}\n\t\tif (box) {\n\t\t\tR = mid;\n\t\t}\n\t\telse {\n\t\t\tL = mid;\n\t\t}\n\t}\n\tcout << R << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 7912, "score_of_the_acc": -0.1973, "final_rank": 11 }, { "submission_id": "aoj_0644_3817028", "code_snippet": "#include <bits/stdc++.h>\n\n#define FOR(i,a,b) for(int i= (a); i<((int)b); ++i)\n#define RFOR(i,a) for(int i=(a); i >= 0; --i)\n#define FOE(i,a) for(auto i : a)\n#define ALL(c) (c).begin(), (c).end()\n#define RALL(c) (c).rbegin(), (c).rend()\n#define SUM(x) std::accumulate(ALL(x), 0LL)\n#define MIN(v) *std::min_element(v.begin(), v.end())\n#define MAX(v) *std::max_element(v.begin(), v.end())\n#define EXIST(v,x) (std::find(v.begin(), v.end(), x) != v.end())\n#define BIT_ON(bit, i) (((bit >> i) & 1) > 0)\n#define BIT_COUNT(bit) (__builtin_popcount(bit))\n\ntypedef long long LL;\ntemplate<typename T> std::vector<T> make_v(size_t a){return std::vector<T>(a);}\ntemplate<typename T,typename... Ts> auto make_v(size_t a, Ts... ts){ return std::vector<decltype(make_v<T>(ts...))>(a,make_v<T>(ts...));} // C++14\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value==0>::type fill_v(T &t,const V &v){t=v;}\ntemplate<typename T,typename V> typename std::enable_if<std::is_class<T>::value!=0>::type fill_v(T &t,const V &v){for(auto &e:t) fill_v(e,v);}\ntemplate<class T> inline T ceil(T a, T b) { return (a + b - 1) / b; }\nvoid print() { std::cout << std::endl; }\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) { std::cout << head; if (sizeof...(tail) != 0) {std::cout << \" \";} print(std::forward<Tail>(tail)...); }\ntemplate <class T> void print(std::vector<T> &v) {for (auto& a : v) { std::cout << a; if (&a != &v.back()) {std::cout << \" \";} }std::cout << std::endl;}\ntemplate <class T> void print(std::vector<std::vector<T>> &vv) { for (auto& v : vv) { print(v); }}\ninline bool inside(long long y, long long x, long long H, long long W) {return 0 <= y and y < H and 0 <= x and x < W; }\ntemplate<class T> inline double euclidean_distance(T y1, T x1, T y2, T x2) { return sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); }\ntemplate<class T> inline double manhattan_distance(T y1, T x1, T y2, T x2) { return abs(x1 - x2) + abs(y1 - y2); }\ntemplate<typename T> T &chmin(T &a, const T &b) { return a = std::min(a, b); }\ntemplate<typename T> T &chmax(T &a, const T &b) { return a = std::max(a, b); }\n\ntemplate<class T> inline std::vector<T> unique(std::vector<T> v) {\n sort(v.begin(), v.end());\n v.erase(unique(v.begin(), v.end()), v.end());\n return v;\n}\n// 初項s, 交差dのn個の数列の和\nlong long sum_of_arithmetic_progression(long long s, long long d, long long n) {\n return n * (2 * s + (n - 1) * d) / 2;\n}\n\n// 2のべき乗数かどうか\nbool is_power_of_two(long long x) {\n return !(x & (x - 1));\n}\n\n// aとbの最大公約数 O(log min(a, b))\nlong long gcd(long long a, long long b) {\n if (b == 0) { return a; }\n return gcd(b, a % b);\n}\n\n// 数列vの最大公約数 O(N log d)\nlong long gcd(std::vector<long long> &v) {\n long long ans = v[0];\n for (int i = 1; i < (int)v.size(); ++i) {\n ans = gcd(ans, v[i]);\n }\n return ans;\n}\n\n// aとbの最小公倍数 O(log min(a, b))\nlong long lcm(long long a, long long b) {\n long long g = gcd(a, b);\n return a / g * b;\n}\n\nconst int INF = 1u << 30u;\nconst long long LINF = 1ull << 58u;\nconst double EPS = 1e-9;\nconst long double PI = acos(-1.0);\nconst std::vector<int> dy2 = {0, 1}, dx2 = {1, 0}; // 右,下\nconst std::vector<int> dy4 = {0, 1, 0, -1}, dx4 = {1, 0, -1, 0}; // 右,下,左,上\nconst std::vector<int> dy8 = { 0, -1, 0, 1, 1, -1, -1, 1 }, dx8 = { 1, 0, -1, 0, 1, 1, -1, -1 };\n\nusing namespace std;\n\n\ntemplate<typename T>class CumulativeSum {\npublic:\n std::vector<T> memo1; // 1次元用の累積和表\n std::vector<std::vector<T>> memo2; // 2次元用の累積和表\n\n CumulativeSum() {}\n\n void build(const std::vector<T> &line) {\n this->memo1.assign(line.size() + 1, 0);\n\n for (int i = 0; i < line.size(); ++i) {\n this->memo1[i + 1] = this->memo1[i] + line[i];\n }\n }\n\n // 2次元の累積和表を作成\n void build(const std::vector<std::vector<T>> &board) {\n int height = board.size();\n int width = board[0].size();\n this->memo2.assign(height + 1, std::vector<T>(width + 1, 0));\n\n for (int y = 0; y < height; ++y) {\n for (int x = 0; x < width; ++x) {\n memo2[y + 1][x + 1] = board[y][x] + memo2[y + 1][x];\n }\n for (int x = 0; x < width; ++x) {\n memo2[y + 1][x + 1] += memo2[y][x + 1];\n }\n }\n }\n\n T sum(int left, int right) {\n return this->memo1[right] - this->memo1[left];\n }\n\n /*\n (y1, x1)から(y2, x2)の合計を返す.(y2, x2)は含まない\n 座標はmemoを作成したboard準拠\n (ex, sum(0, 0, 2, 2)なら(0, 0), (0, 1), (1, 0), (1, 1)の合計を返す)\n */\n T sum(int y1, int x1, int y2, int x2) {\n return this->memo2[y2][x2] - this->memo2[y2][x1] - this->memo2[y1][x2] + this->memo2[y1][x1];\n }\n};\n\n\nCumulativeSum<LL> cs;\nLL func(const int l, const int r, const vector<LL> &a, const LL maxi) {\n if (l == r) {\n return 0;\n }\n\n int N = r - l;\n vector<vector<long long>> dp(r + 1, vector<long long>(r + 1, LINF));\n for (int length = 1; length < N + 1; ++length) {\n for (int left = l; left < r; ++left) {\n int right = left + length;\n if (right > r) {\n continue;\n }\n\n auto sum = cs.sum(left, right);\n if (sum <= maxi) {\n chmin(dp[left][right], maxi - sum);\n }\n for (int m = left + 1; m < right; ++m) {\n chmin(dp[left][right], max(dp[left][m], dp[m][right]));\n }\n }\n }\n\n return dp[l][r];\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n LL N;\n cin >> N;\n auto L = make_v<LL>(N);\n FOR(i, 0, N) {\n cin >> L[i];\n }\n cs.build(L);\n LL maxi = MAX(L);\n\n LL ans = LINF;\n FOR(i, 0, N) {\n FOR(j, i + 1, N + 1) {\n\n LL len = cs.sum(i, j);\n if (len < maxi or j - i == N) {\n continue;\n }\n\n LL left = func(0, i, L, len);\n LL right = func(j, L.size(), L, len);\n chmin(ans, max(left, right));\n }\n }\n print(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3244, "score_of_the_acc": -0.0098, "final_rank": 1 } ]
aoj_0651_cpp
毒蛇の脱走(Snake Escaping) JOI 研究所では 2^L 匹の毒蛇を飼っており,それぞれ 0, 1, ..., 2^L - 1 の番号が付けられている.すべての毒蛇は頭から順に L 個の部分に分かれており,それぞれの部分は青または赤である.毒蛇 i に対し, i を2進表記して i = $\sum_{k=1}^{L}$ c_k2^{L-k} (0 \leq c_k \leq 1) とおいたとき, c_k = 0 であれば,毒蛇 i の頭から数えて k 番目の部分は青であり, c_k = 1 であれば,毒蛇 i の頭から数えて k 番目の部分は赤である. 各毒蛇には毒性と呼ばれる0 以上9 以下の整数値が定まっている. 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 からなる長さ 2^L の文字列 S が与えられ,その i 文字目( 1 \leq i \leq 2^L ) は毒蛇 i - 1 の毒性を表す. 毒蛇たちの動きは素早いので,JOI 研究所からは,よく毒蛇たちが脱走してしまう.JOI 研究所には脱走した毒蛇を目撃した周辺住民から苦情が寄せられる. あなたには, Q 日間にわたる苦情の情報が与えられる. d 日目( 1 \leq d \leq Q ) に寄せられた苦情は, 0 , 1 , ? からなる長さ L の文字列 T_d として表され, T_d の j 文字目( 1 \leq j \leq L ) が 0 の場合は, d 日目に脱走したすべての毒蛇の頭から数えて j 番目の部分が青であることを表し, T_d の j 文字目( 1 \leq j \leq L ) が 1 の場合は, d 日目に脱走したすべての毒蛇の頭から数えて j 番目の部分が赤であることを表し, T_d の j 文字目( 1 \leq j \leq L ) が ? の場合は, d 日目に脱走した毒蛇の頭から数えて j 番目の部分については,周辺住民からは情報が与えられなかったことを表す. 苦情はすべて正確な情報である.脱走した毒蛇はJOI 研究所の職員がその日のうちに捕獲する.捕獲された毒蛇が,翌日以降に再び脱走することはあり得る. 毒蛇の脱走によるリスクを見積もるために,JOI 研究所のK 理事長は脱走した可能性のある毒蛇の毒性の合計を知りたい.あなたの仕事は, Q 日間にわたる苦情の情報から,それぞれの日ごとに,その日に脱走した可能性のある毒蛇の毒性の合計を求めるプログラムを作成することである. 課題 毒蛇の毒性を表す文字列 S と, Q 日間の苦情の情報が与えられるので,それぞれの日ごとに,その日に脱走した可能性のある毒蛇の毒性の合計を求めるプログラムを作成せよ. メモリ制限が小さいことに注意すること. 入力 標準入力から以下の入力を読み込め. 1 行目には,整数 L, Q が空白を区切りとして書かれている.これらは順に,毒蛇の部分の個数と,苦情の寄せられる日数を表す. 2 行目には,長さ 2^L の文字列 S が書かれている.この文字列は毒蛇の毒性を表す. 続く Q 行のうちの d 行目( 1 \leq d \leq Q ) には,長さ L の文字列 T_d が書かれている.この文字列は d 日目の苦情を表す. 出力 標準出力に Q 行で出力せよ. d 行目には, d 日目に脱走した可能性のある毒蛇の毒性の合計を表す整数を出力せよ. 制限 すべての入力データは以下の条件を満たす. 1 \leq L \leq 20 . 1 \leq Q \leq 1 000 000 . S は長さ 2^L の文字列である. 文字列 S は 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 からなる. T_d は長さ L の文字列である( 1 \leq d \leq Q ). 文字列 T_d は 0 , 1 , ? からなる( 1 \leq d \leq Q ). 入出力例 入力例1 3 5 12345678 000 0?? 1?0 ?11 ??? 出力例1 1 10 12 12 36 この入力例では, L = 3 である.3 つの部分に分かれた毒蛇が,全部で 2^3 = 8 匹いる.苦情は5 日間にわたって寄せられる. 1 日目に脱走した可能性のある毒蛇は,毒蛇0 のみである.毒性の合計は1 である. 2 日目に脱走した可能性のある毒蛇は,毒蛇0, 1, 2, 3 である.毒性の合計は10 である. 3 日目に脱走した可能性のある毒蛇は,毒蛇4, 6 である.毒性の合計は12 である. 4 日目に脱走した可能性のある毒蛇は,毒蛇3, 7 である.毒性の合計は12 である. 5 日目に脱走した可能性のある毒蛇は,毒蛇0, 1, 2, 3, 4, 5, 6, 7 である.毒性の合計は36 である. 入力例2 4 8 3141592653589793 0101 ?01? ??1? ?0?? 1?00 01?1 ??10 ???? 出力例2 9 18 38 30 14 15 20 80 情報オリンピック日本委員会作 『第17 回日本情報オリンピック(JOI 2017/2018) 本選』
[ { "submission_id": "aoj_0651_9488102", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint l, q;\nint n[1 << 20], m[1 << 20], a, b, c, x[21], y[21], z[21], ans, p;\nchar s[(1 << 20) + 1], t[21];\n\nint main() {\n // 入力の受け取り\n scanf(\"%d%d %s\", &l, &q, s);\n \n // 初期化\n for (int i = 0; i < (1 << l); i++) {\n n[i] = s[i] - '0';\n m[i] = s[i] - '0';\n }\n \n // 前計算: nとmを更新\n for (int i = 0; i < l; i++) {\n for (int k = 0; k < (1 << l); k++) {\n if ((k & (1 << i)) == 0) {\n n[k] += n[k | (1 << i)];\n } else {\n m[k] += m[k ^ (1 << i)];\n }\n }\n }\n \n // クエリ処理\n while (q--) {\n scanf(\" %s\", t);\n a = b = c = ans = p = 0;\n \n // 入力されたビット文字列を解析\n for (int i = 0; i < l; i++) {\n if (t[l - i - 1] == '0') {\n x[a++] = i;\n } else if (t[l - i - 1] == '1') {\n y[b++] = i;\n p += (1 << i);\n } else {\n z[c++] = i;\n }\n }\n \n // aの要素が6以下の場合の処理\n if (a <= 6) {\n for (int i = 0; i < (1 << a); i++) {\n int o = p, w = 0;\n for (int j = 0; j < a; j++) {\n if (i >> j & 1) {\n o += (1 << x[j]);\n w++;\n }\n }\n if (w % 2) ans -= n[o];\n else ans += n[o];\n }\n } \n // bの要素が6以下の場合の処理\n else if (b <= 6) {\n for (int i = 0; i < c; i++) p += (1 << z[i]);\n for (int i = 0; i < (1 << b); i++) {\n int o = p, w = 0;\n for (int j = 0; j < b; j++) {\n if (i >> j & 1) {\n o -= (1 << y[j]);\n w++;\n }\n }\n if (w % 2) ans -= m[o];\n else ans += m[o];\n }\n } \n // それ以外の場合の処理\n else {\n for (int i = 0; i < (1 << c); i++) {\n int o = p;\n for (int j = 0; j < c; j++) if (i >> j & 1) o += (1 << z[j]);\n ans += (s[o] - '0');\n }\n }\n \n // 結果を出力\n printf(\"%d\\n\", ans);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 530, "memory_kb": 12788, "score_of_the_acc": -0.169, "final_rank": 1 }, { "submission_id": "aoj_0651_9477365", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cstring>\nusing namespace std;\n\nint main() {\n int l, q;\n cin >> l >> q;\n string s;\n cin >> s;\n\n vector<int> n(1 << l), m(1 << l);\n for (int i = 0; i < (1 << l); ++i) {\n n[i] = s[i] - '0';\n m[i] = s[i] - '0';\n }\n\n for (int i = 0; i < l; ++i) {\n for (int k = 0; k < (1 << l); ++k) {\n if ((k & (1 << i)) == 0) n[k] += n[k | (1 << i)];\n else m[k] += m[k ^ (1 << i)];\n }\n }\n\n while (q--) {\n string t;\n cin >> t;\n\n vector<int> x, y, z;\n int a = 0, b = 0, c = 0, ans = 0, p = 0;\n\n for (int i = 0; i < l; ++i) {\n if (t[l - i - 1] == '0') x.push_back(i);\n else if (t[l - i - 1] == '1') {\n y.push_back(i);\n p += (1 << i);\n } else z.push_back(i);\n }\n\n if (x.size() <= 6) {\n for (int i = 0; i < (1 << x.size()); ++i) {\n int o = p, w = 0;\n for (int j = 0; j < x.size(); ++j) {\n if (i >> j & 1) {\n o += (1 << x[j]);\n w++;\n }\n }\n if (w % 2) ans -= n[o];\n else ans += n[o];\n }\n } else if (y.size() <= 6) {\n for (int i = 0; i < z.size(); ++i) p += (1 << z[i]);\n for (int i = 0; i < (1 << y.size()); ++i) {\n int o = p, w = 0;\n for (int j = 0; j < y.size(); ++j) {\n if (i >> j & 1) {\n o -= (1 << y[j]);\n w++;\n }\n }\n if (w % 2) ans -= m[o];\n else ans += m[o];\n }\n } else {\n for (int i = 0; i < (1 << z.size()); ++i) {\n int o = p;\n for (int j = 0; j < z.size(); ++j) if (i >> j & 1) o += (1 << z[j]);\n ans += (s[o] - '0');\n }\n }\n cout << ans << endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1760, "memory_kb": 13144, "score_of_the_acc": -1.0617, "final_rank": 7 }, { "submission_id": "aoj_0651_9477349", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <cmath>\n\nint main() {\n int l, q;\n std::cin >> l >> q;\n \n std::string s;\n std::cin >> s;\n\n std::vector<int> n(1 << l), m(1 << l);\n for (int i = 0; i < (1 << l); ++i) {\n n[i] = s[i] - '0';\n m[i] = s[i] - '0';\n }\n\n for (int i = 0; i < l; ++i) {\n for (int k = 0; k < (1 << l); ++k) {\n if ((k & (1 << i)) == 0) {\n n[k] += n[k | (1 << i)];\n } else {\n m[k] += m[k ^ (1 << i)];\n }\n }\n }\n\n while (q--) {\n std::string t;\n std::cin >> t;\n\n int a = 0, b = 0, c = 0, ans = 0, p = 0;\n std::vector<int> x(21), y(21), z(21);\n\n for (int i = 0; i < l; ++i) {\n if (t[l - i - 1] == '0') {\n x[a++] = i;\n } else if (t[l - i - 1] == '1') {\n y[b++] = i;\n p += (1 << i);\n } else {\n z[c++] = i;\n }\n }\n\n if (a <= 6) {\n for (int i = 0; i < (1 << a); ++i) {\n int o = p, w = 0;\n for (int j = 0; j < a; ++j) {\n if (i >> j & 1) {\n o += (1 << x[j]);\n w++;\n }\n }\n if (w % 2) ans -= n[o];\n else ans += n[o];\n }\n } else if (b <= 6) {\n for (int i = 0; i < c; ++i) p += (1 << z[i]);\n for (int i = 0; i < (1 << b); ++i) {\n int o = p, w = 0;\n for (int j = 0; j < b; ++j) {\n if (i >> j & 1) {\n o -= (1 << y[j]);\n w++;\n }\n }\n if (w % 2) ans -= m[o];\n else ans += m[o];\n }\n } else {\n for (int i = 0; i < (1 << c); ++i) {\n int o = p;\n for (int j = 0; j < c; ++j) {\n if (i >> j & 1) o += (1 << z[j]);\n }\n ans += (s[o] - '0');\n }\n }\n\n std::cout << ans << std::endl;\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 1510, "memory_kb": 12500, "score_of_the_acc": -0.8677, "final_rank": 6 }, { "submission_id": "aoj_0651_4413247", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <functional>\n#include <set>\n#include <map>\n#include <vector>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nstruct IO_Tp {\n const static int _O_Buffer_Size = 10 << 20;\n char _O_Buffer[_O_Buffer_Size], *_O_pos = _O_Buffer;\n\n IO_Tp() {}\n\n ~IO_Tp() { fwrite(_O_Buffer, 1, _O_pos - _O_Buffer, stdout); }\n\n IO_Tp &operator<<(int n) {\n static char _buf[10];\n char *_pos = _buf;\n do\n *_pos++ = '0' + n % 10;\n while (n /= 10);\n while (_pos != _buf) *_O_pos++ = *--_pos;\n return *this;\n }\n\n IO_Tp &operator<<(char ch) {\n *_O_pos++ = ch;\n return *this;\n }\n} IO;\n\nconst int N = 1000010, L = 20;\n\nint l, n;\nchar v[(1 << L) + 10];\nchar tmp[L + 4];\nunsigned short sum[1 << 12][1 << 12];\nint ind[N], cc[N];\nint ans[N];\n\nint main() {\n\n scanf(\"%d%d%s\", &l, &n, v);\n for (int i = 1; i <= n; ++i) {\n scanf(\"%s\", tmp + 1);\n for (int j = 0; j < l; ++j)\n if (tmp[l - j] == '?')\n cc[i] |= 1 << j;\n else\n ind[i] |= (tmp[l - j] - '0') << j;\n }\n int a = max(0, l - int(log(n) / log(3))), b = l - a;\n if (a > 12) {\n a = 12;\n b = l - a;\n } else if (b > 12) {\n b = 12;\n a = l - b;\n }\n for (int i = 0; i != (1 << l); ++i) v[i] -= '0';\n for (int pre = 0; pre != 1 << a; ++pre) {\n for (int s = 0; s != 1 << b; ++s) sum[0][s] = v[pre | s << a];\n for (int cov = 1; cov != 1 << b; ++cov) {\n int tr = __builtin_ctz(cov);\n int ccov = ~cov & ((1 << b) - 1);\n for (int s = ccov;; s = (s - 1) & ccov) {\n sum[cov][s] = sum[cov ^ 1 << tr][s] + sum[cov ^ 1 << tr][s | 1 << tr];\n if (!s)\n break;\n }\n }\n\n for (int i = 1; i <= n; ++i)\n if ((~cc[i] & pre) == (ind[i] & ((1 << a) - 1)))\n ans[i] += sum[cc[i] >> a][ind[i] >> a];\n\n for (int cov = 0; cov != 1 << b; ++cov)\n for (int s = cov;; s = (s - 1) & cov) {\n sum[~cov & ((1 << b) - 1)][s & cov] = 0;\n if (!s)\n break;\n }\n }\n\n for (int i = 1; i <= n; ++i) IO << ans[i] << '\\n';\n\n return 0;\n}", "accuracy": 1, "time_ms": 1750, "memory_kb": 52812, "score_of_the_acc": -1.9281, "final_rank": 10 }, { "submission_id": "aoj_0651_3527441", "code_snippet": "#include<iostream>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<algorithm>\n#include<math.h>\n#include<string>\n#include<stdio.h>\n#pragma GCC optimize (\"O3\")\nusing namespace std;\n#define vel vector<int>\n#define vvel vector<vel>\n#define sor(a) sort(a.begin(),a.end())\n#define rep(i,n) for(int i=0;i<n;i++)\n#define upperbound(v,val) upper_bound(v.begin(),v.end(),val)\n#define lowerbound(v,val) lower_bound(v.begin(),v.end(),val)\nint rui[21];\nint ord[(1 << 20) + 1];\nvoid make_ord() {\n\tord[1] = 0;\n\tint max1 = 0;\n\tfor (int i = 2; i <= (1 << 20); i++) {\n\t\tint mi = (i&(-i));\n\t\tif (i == mi) {\n\t\t\tmax1++;\n\t\t\tord[i] = max1;\n\t\t}\n\t\telse { ord[i] = ord[mi]; }\n\t}\n}\nsigned main() {\n\tmake_ord();\n\tint L; cin >> L; int q; cin >> q;\n\tvvel lis(3, vel(1 << L));\n\tstring s; cin >> s;\n\tint sz = 1 << L;\n\trep(i, sz) { lis[0][i] = s[i] - '0'; }\n\tlis[1] = lis[0];\n\tlis[2] = lis[0];\n\trep(i, L) {\n\t\trep(j, sz) {\n\t\t\tint smt = (j >> i);\n\t\t\tint pla = 2-(smt%2);\n\t\t\tlis[pla][j] += lis[pla][j xor (1<<i)];\n\t\t}\n\t}\n\tint pot = 0;\n\trep(i, sz) {\n\t\tif (i % 2 == 1) { lis[1][pot] *= -1; lis[2][pot] *= -1; }\n\t\tpot ^=1<<ord[i];\n\t}\n\tint all[3][20];\n\tbool fl = (q <= 50000);\n\trep(i, q) {\n\t\tstring s; cin >> s;\n\t\tint c[3]; c[0] = 0; c[1] = 0; c[2] = 0;\n\t\tint num = 0;\n\t\tfor (int j = L - 1; j >= 0; j--) {\n\t\t\tint pla = (s[L - 1 - j] + 1) % 16;\n\t\t\tall[pla][c[pla]] = j;\n\t\t\tc[pla]++;\n\t\t\tif (pla == 2) { num += (1 << j); }\n\t\t}\n\t\tint ans0 = 0;\n\t\tif (fl) {\n\t\t\tif (c[0] <= min(c[1], c[2])) {\n\t\t\t\tint lim = (1 << c[0]) - 1;\n\t\t\t\trep(j, lim) {\n\t\t\t\t\tans0 += lis[0][num];\n\t\t\t\t\tnum ^= 1 << all[0][ord[j + 1]];\n\t\t\t\t}\n\t\t\t\tans0 += lis[0][num];\n\t\t\t}\n\t\t\telse if (c[1] < c[2]) {\n\t\t\t\tint lim = (1 << c[1]) - 1;\n\t\t\t\trep(j, lim) {\n\t\t\t\t\tans0 += lis[2][num];\n\t\t\t\t\tnum ^= 1 << all[1][ord[j + 1]];\n\t\t\t\t}\n\t\t\t\tans0 += lis[2][num];\n\t\t\t}\n\t\t\telse {\n\t\t\t\trep(j, c[0]) { num += (1 << all[0][j]); }\n\t\t\t\tint lim = (1 << c[2]) - 1;\n\t\t\t\trep(j, lim) {\n\t\t\t\t\tans0 += lis[1][num];\n\t\t\t\t\tnum ^= 1 << all[2][ord[j + 1]];\n\t\t\t\t}\n\t\t\t\tans0 += lis[1][num];\n\t\t\t}\n\t\t\tprintf(\"%d\\n\", abs(ans0));\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 0.11764705882352941, "time_ms": 530, "memory_kb": 7400, "score_of_the_acc": -0.0504, "final_rank": 11 }, { "submission_id": "aoj_0651_3373164", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n#pragma warning (disable: 4996)\n\nlong long L, Q, A[1 << 20], dp0[1 << 20], dp1[1 << 20];\n\nvoid init() {\n\tfor (int i = 0; i < (1 << L); i++) { dp0[i] = A[i]; dp1[(1 << L) - i - 1LL] = A[i]; }\n\n\tfor (int i = 0; i < L; i++) {\n\t\tfor (int j = 0; j < (1 << L); j++) {\n\t\t\tif ((j&(1 << i)) != 0) { dp0[j] += dp0[j - (1 << i)]; }\n\t\t}\n\t}\n\tfor (int i = 0; i < L; i++) {\n\t\tfor (int j = 0; j < (1 << L); j++) {\n\t\t\tif ((j&(1 << i)) != 0) { dp1[j] += dp1[j - (1 << i)]; }\n\t\t}\n\t}\n}\n\nint A1[1 << 20], A2[1 << 20], cnts;\n\nvoid enumerate(vector<int>I) {\n\tcnts = 0; int N = I.size();\n\n\tint sum = 0, cnt = 0;\n\tfor (int i = 0; i < (1 << I.size()); i++) {\n\t\tA1[cnts] = sum; A2[cnts] = ((N - cnt) & 1); cnts++;\n\n\t\tint cx = i, ss = 0;\n\t\twhile ((cx & 1) == 1) {\n\t\t\tcx >>= 1; sum -= (1 << I[ss]); ss++; cnt--;\n\t\t}\n\t\tif (ss < N) { sum += (1 << I[ss]); cnt++; }\n\t}\n}\n\nint main() {\n\tcin >> L >> Q;\n\tfor (int i = 0; i < (1 << L); i++) { char c; cin >> c; A[i] = (c - '0'); }\n\n\tinit();\n\n\tfor (int i = 1; i <= Q; i++) {\n\t\tchar c[22]; scanf(\"%s\", c);\n\t\tfor (int j = 0; j < L; j++) { if (j < (L - 1 - j)) swap(c[j], c[L - 1 - j]); }\n\t\t\n\t\tvector<int>v0, v1, v2;\n\t\tfor (int j = 0; j < L; j++) {\n\t\t\tif (c[j] == '0') v0.push_back(j);\n\t\t\tif (c[j] == '1') v1.push_back(j);\n\t\t\tif (c[j] == '?') v2.push_back(j);\n\t\t}\n\n\t\tint ans = 0;\n\t\tif (v2.size() <= 7) {\n\t\t\tenumerate(v2);\n\t\t\tint BASE = 0; for (int j = 0; j < v1.size(); j++) BASE += (1 << v1[j]);\n\t\t\tfor (int j = 0; j < cnts; j++) {\n\t\t\t\tans += A[BASE + A1[j]];\n\t\t\t}\n\t\t}\n\t\telse if (v0.size() <= v1.size()) {\n\t\t\tenumerate(v0);\n\t\t\tint BASE = 0; for (int j = 0; j < v2.size(); j++) BASE += (1 << v2[j]);\n\n\t\t\tfor (int j = 0; j < cnts; j++) {\n\t\t\t\tif (A2[j] == 0) ans += dp1[BASE + A1[j]];\n\t\t\t\tif (A2[j] == 1) ans -= dp1[BASE + A1[j]];\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tenumerate(v1);\n\t\t\tint BASE = 0; for (int j = 0; j < v2.size(); j++) BASE += (1 << v2[j]);\n\n\t\t\tfor (int j = 0; j < cnts; j++) {\n\t\t\t\tif (A2[j] == 0) ans += dp0[BASE + A1[j]];\n\t\t\t\tif (A2[j] == 1) ans -= dp0[BASE + A1[j]];\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", ans);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1390, "memory_kb": 27864, "score_of_the_acc": -1.1197, "final_rank": 9 }, { "submission_id": "aoj_0651_3221276", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint l,q,n[1<<20],m[1<<20],a,b,c,x[21],y[21],z[21],ans,p;\nchar s[(1<<20)+1],t[21];\nint main(void){\n scanf(\"%d%d %s\",&l,&q,s);\n for(int i=0;i<1<<l;i++){\n n[i]=s[i]-'0';\n m[i]=s[i]-'0';\n }\n for(int i=0;i<l;i++){\n for(int k=0;k<1<<l;k++){\n if((k&(1<<i))==0)n[k]+=n[k|(1<<i)];\n else m[k]+=m[k^(1<<i)];\n }\n }\n while(q--){\n scanf(\" %s\",t);\n a=0,b=0,c=0,ans=0,p=0;\n for(int i=0;i<l;i++){\n if(t[l-i-1]=='0')x[a++]=i;\n else if(t[l-i-1]=='1'){\n y[b++]=i;\n p+=(1<<i);\n }else z[c++]=i;\n }\n if(a<=6){\n for(int i=0;i<1<<a;i++){\n int o=p,w=0;\n for(int j=0;j<a;j++){\n if(i>>j&1){\n o+=(1<<x[j]);\n w++;\n }\n }\n if(w%2)ans-=n[o];\n else ans+=n[o];\n }\n }else if(b<=6){\n for(int i=0;i<c;i++)p+=(1<<z[i]);\n for(int i=0;i<1<<b;i++){\n int o=p,w=0;\n for(int j=0;j<b;j++){\n if(i>>j&1){\n o-=(1<<y[j]);\n w++;\n }\n }\n if(w%2)ans-=m[o];\n else ans+=m[o];\n }\n }else{\n for(int i=0;i<1<<c;i++){\n int o=p;\n for(int j=0;j<c;j++)if(i>>j&1)o+=(1<<z[j]);\n ans+=(s[o]-'0');\n }\n }\n printf(\"%d\\n\",ans);\n }\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 12452, "score_of_the_acc": -0.3055, "final_rank": 4 }, { "submission_id": "aoj_0651_3125149", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n//#define FILE_IO\n\nint N, Q, ans;\nint i, j, q, msk;\nint cnt[3];\nint val[1100005], dp[1100005], dp2[1100005];\nint bts[1100005];\nint B, b[25];\nchar s[1100005];\n\nvoid bck0(int pas, int msk, int smn)\n{\n if(pas >= B)\n {\n ans += smn * dp[msk];\n return;\n }\n\n bck0(pas + 1, msk, smn);\n bck0(pas + 1, msk ^ (1 << b[pas]), -smn);\n}\n\nvoid bck1(int pas, int msk, int smn)\n{\n if(pas >= B)\n {\n ans += smn * dp2[msk];\n return;\n }\n\n bck1(pas + 1, msk, smn);\n bck1(pas + 1, msk ^ (1 << b[pas]), -smn);\n}\n\nvoid bckq(int pas, int msk)\n{\n if(pas >= B)\n {\n ans += val[msk];\n return;\n }\n\n bckq(pas + 1, msk);\n bckq(pas + 1, msk ^ (1 << b[pas]));\n}\n\nint main()\n{\n #ifdef FILE_IO\n freopen(\"1.in\", \"r\", stdin);\n freopen(\"1.out\", \"w\", stdout);\n #endif\n\n scanf(\"%d%d\\n\", &N, &Q);\n scanf(\"%s\\n\", s);\n for(i = 0; i < (1 << N); i++)\n val[i] = dp[i] = dp2[i] = s[i] - '0';\n for(j = 0; j < N; j++)\n for(i = (1 << N) - 1; i >= 0; i--)\n if( (i & (1 << j)) == 0 )\n dp[i] += dp[i ^ (1 << j)];\n for(j = 0; j < N; j++)\n for(i = 0; i < (1 << N); i++)\n if( (i & (1 << j)) != 0 )\n dp2[i] += dp2[i ^ (1 << j)];\n\n for(q = 1; q <= Q; q++)\n {\n scanf(\"%s\\n\", s);\n reverse(s, s + N);\n cnt[0] = cnt[1] = cnt[2] = 0;\n for(j = 0; j < N; j++)\n {\n if(s[j] == '0') cnt[0]++;\n else if(s[j] == '1') cnt[1]++;\n else if(s[j] == '?') cnt[2]++;\n }\n\n if(cnt[0] < cnt[1] && cnt[0] < cnt[2])\n {\n msk = 0;\n B = 0;\n for(i = 0; i < N; i++)\n {\n if(s[i] == '1') msk |= (1 << i);\n if(s[i] == '0') b[B++] = i;\n }\n\n ans = 0;\n bck0(0, msk, 1);\n printf(\"%d\\n\", ans);\n }\n else if(cnt[1] < cnt[2])\n {\n msk = 0;\n B = 0;\n for(i = 0; i < N; i++)\n {\n if(s[i] == '1')\n {\n msk |= (1 << i);\n b[B++] = i;\n }\n if(s[i] == '?')\n msk |= (1 << i);\n }\n\n ans = 0;\n bck1(0, msk, 1);\n printf(\"%d\\n\", ans);\n }\n else\n {\n msk = 0;\n B = 0;\n for(i = 0; i < N; i++)\n {\n if(s[i] == '?') b[B++] = i;\n else msk |= ((s[i] - '0') << i);\n }\n\n ans = 0;\n bckq(0, msk);\n printf(\"%d\\n\", ans);\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 16564, "score_of_the_acc": -0.3601, "final_rank": 5 }, { "submission_id": "aoj_0651_2867428", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int L = 20;\n\nvoid fill(int l, int *totals0, int *totals1, char *s) {\n if (l == 0) {\n totals0[0] = s[0];\n totals1[0] = s[0];\n } else {\n l--;\n int *totalz0 = totals0 + (1 << l);\n int *totalz1 = totals1 + (1 << l);\n char *z = s + (1 << l);\n fill(l, totals0, totals1, s);\n fill(l, totalz0, totalz1, z);\n for (int i = 0; i < 1 << l; i++) {\n totalz0[i] += totals0[i];\n totals1[i] += totalz1[i];\n }\n }\n}\n\nchar vals[(1 << L) + 11];\nint totals0[1 << L], totals1[1 << L], bitc[1 << L];\nchar word[L + 11];\nint main() {\n int l, q;\n scanf(\"%d%d%s\", &l, &q, vals);\n int all = (1 << l) - 1;\n for (int i = 0; i < 1 << l; i++) vals[i] -= '0';\n for (int i = 1; i < 1 << l; i++) bitc[i] = bitc[i >> 1] + (i & 1);\n fill(l, totals0, totals1, vals);\n while (q--) {\n scanf(\"%s\", word);\n assert(strlen(word) == l);\n int c0 = 0, c1 = 0, cq = 0, s = 0, ans = 0;\n for (int i = 0, j = l - 1; i < l; i++, j--) {\n (word[i] == '0' ? c0 : word[i] == '1' ? c1 : cq) |= 1 << j;\n }\n if (bitc[c0] <= min(bitc[c1], bitc[cq])) {\n do ans += (bitc[s] & 1 ? -1 : 1) * totals1[s | c1]; while (s = s - 1 & c0);\n } else if (bitc[c1] <= min(bitc[c0], bitc[cq])) {\n do ans += (bitc[s] & 1 ? -1 : 1) * totals0[(s | c0) ^ all]; while (s = s - 1 & c1);\n } else {\n do ans += vals[c1 | s]; while (s = s - 1 & cq);\n }\n printf(\"%d\\n\", ans);\n }\n}", "accuracy": 1, "time_ms": 550, "memory_kb": 16520, "score_of_the_acc": -0.2656, "final_rank": 3 }, { "submission_id": "aoj_0651_2859982", "code_snippet": "#include <cstdio>\n#pragma warning(disable : 4996)\nint N, Q, v[1048588], vx[1048588], vy[1048588], pc[75]; char s[1048588], qs[29];\nint main() {\n\tscanf(\"%d%d%s\", &N, &Q, s);\n\tfor (int i = 0; i < 1 << N; ++i) {\n\t\tv[i] = s[i] - '0';\n\t\tvx[i] = v[i];\n\t\tvy[i] = v[i];\n\t}\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 0; j < 1 << N; ++j) {\n\t\t\tif ((j >> i) & 1) {\n\t\t\t\tvx[j] += vx[j - (1 << i)];\n\t\t\t\tvy[j - (1 << i)] += vy[j];\n\t\t\t}\n\t\t}\n\t}\n\tpc[0] = 1;\n\tfor (int i = 1; i < 1 << (N / 3); i++) {\n\t\tpc[i] = pc[i >> 1] ^ (i & 1);\n\t}\n\tfor (int i = 0; i < Q; ++i) {\n\t\tscanf(\"%s\", qs);\n\t\tint cx = 0, cy = 0, cz = 0, sx = 0, sy = 0, sz = 0;\n\t\tfor (int j = 0; j < N; ++j) {\n\t\t\tif (qs[N - j - 1] == '0') ++cx, sx |= 1 << j;\n\t\t\tif (qs[N - j - 1] == '1') ++cy, sy |= 1 << j;\n\t\t\tif (qs[N - j - 1] == '?') ++cz, sz |= 1 << j;\n\t\t}\n\t\tint ret = 0;\n\t\tif (3 * cz <= N) {\n\t\t\tfor (int j = sz; j >= 0; --j) {\n\t\t\t\tj &= sz;\n\t\t\t\tret += v[j + sy];\n\t\t\t}\n\t\t}\n\t\telse if (3 * cy <= N) {\n\t\t\tfor (int j = sy, k = 0; j >= 0; --j, ++k) {\n\t\t\t\tj &= sy;\n\t\t\t\tif(pc[k]) ret += vx[j + sz];\n\t\t\t\telse ret -= vx[j + sz];\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tfor (int j = sx, k = 0; j >= 0; --j, ++k) {\n\t\t\t\tj &= sx;\n\t\t\t\tif (pc[k]) ret += vy[sx + sy - j];\n\t\t\t\telse ret -= vy[sx + sy - j];\n\t\t\t}\n\t\t}\n\t\tprintf(\"%d\\n\", ret);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 460, "memory_kb": 16052, "score_of_the_acc": -0.1905, "final_rank": 2 }, { "submission_id": "aoj_0651_2779429", "code_snippet": "# include <iostream>\n# include <algorithm>\n#include <array>\n# include <cassert>\n#include <cctype>\n#include <climits>\n#include <numeric>\n# include <vector>\n# include <string>\n# include <set>\n# include <map>\n# include <cmath>\n# include <iomanip>\n# include <functional>\n# include <tuple>\n# include <utility>\n# include <stack>\n# include <queue>\n# include <list>\n# include <bitset>\n# include <complex>\n# include <chrono>\n# include <random>\n# include <limits.h>\n# include <unordered_map>\n# include <unordered_set>\n# include <deque>\n# include <cstdio>\n# include <cstring>\n#include <stdio.h>\n#include <stdlib.h>\n#include <cstdint>\n#include <cfenv>\n//#include <bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing ULL = unsigned long long;\nconstexpr long long MOD = 1000000000 + 7;\nconstexpr long long INF = std::numeric_limits<long long>::max();\nconst double PI = acos(-1);\n#define fir first\n#define sec second\n#define thi third\n#define debug(x) cerr<<#x<<\": \"<<x<<'\\n'\ntypedef pair<LL, LL> Pll;\ntypedef pair<LL, pair<LL, LL>> Ppll;\ntypedef pair<LL, pair<LL, bitset<100001>>> Pbll;\ntypedef pair<LL, pair<LL, vector<LL>>> Pvll;\ntypedef pair<LL, LL> Vec2;\nstruct Tll { LL first, second, third; };\ntypedef pair<LL, Tll> Ptll;\n#define rep(i,rept) for(LL i=0;i<rept;i++)\n#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)\nint h, w, n, m, k, s, t, q, sum, last, cnt, ans, a[1000000],dp0[1<<20], dp1[1 << 20];\nstring str, ss;\nbool f;\nchar c;\nint di[4][2] = { {1,0},{-1,0} ,{0,1},{0,-1} };\nstruct Edge { LL to,cost; };\nvector<Edge>vec[10000];\nvoid YN(bool f) {\n\tif (f)\n\t\tcout << \"YES\" << endl;\n\telse\n\t\tcout << \"NO\" << endl;\n}\nvoid yn(bool f) {\n\tif (f)\n\t\tcout << \"Yes\" << endl;\n\telse\n\t\tcout << \"No\" << endl;\n}\nunsigned int popcnt(unsigned long long x)\n{\n\tx = (x & 0x5555555555555555ULL) + ((x >> 1) & 0x5555555555555555ULL);\n\tx = (x & 0x3333333333333333ULL) + ((x >> 2) & 0x3333333333333333ULL);\n\tx = (x & 0x0F0F0F0F0F0F0F0FULL) + ((x >> 4) & 0x0F0F0F0F0F0F0F0FULL);\n\treturn (x * 0x0101010101010101ULL) >> 56;\n}\nint main() {\n\tcin >> n >> m;\n\tcin >> str;\n\trep(i, 1 << n) {\n\t\tdp0[((1 << n) - 1) ^ i] = str[i]-'0';\n\t\tdp1[i] = str[i] - '0';\n\t}\n\trep(i,n)\n\t\trep(s, 1LL << n) {\n\t\tif ((s & (1 << i)) == 0) {\n\t\t\tdp0[s] += dp0[s | (1 << i)];\n\t\t\tdp1[s] += dp1[s | (1 << i)];\n\t\t}\n\t}\n\trep(i, m) {\n\t\tint ma0 = 0, ma1 = 0, ma2 = 0;\n\t\tint cnt[3] = {};\n\t\tans = 0;\n\t\tcin >> ss;\n\t\trep(j, n)\n\t\t\tif (ss[n-1-j] == '0')\n\t\t\t\tma0 += 1 << j,cnt[0]++;\n\t\t\telse if (ss[n-1-j] == '1')\n\t\t\t\tma1 += 1 << j,cnt[1]++;\n\t\t\telse ma2 += 1 << j,cnt[2]++;\n\n\t\t\tif (cnt[0] <= n / 3) {\n\t\t\t\tMfor(k, ma0 + 1) {\n\t\t\t\t\tk &= ma0;\n\t\t\t\t\tif (popcnt(k) % 2)ans -= dp1[k|ma1];\n\t\t\t\t\telse ans += dp1[k|ma1];\n\t\t\t\t}\n\t\t\t}\n\t\t\telse if (cnt[1] <= n / 3) {\n\t\t\t\tMfor(k, ma1 + 1) {\n\t\t\t\t\tk &= ma1;\n\t\t\t\t\tif (popcnt(k) % 2)ans -= dp0[k|ma0];\n\t\t\t\t\telse ans += dp0[k | ma0];\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\tMfor(k, ma2 + 1) {\n\t\t\t\t\tk &= ma2;\n\t\t\t\t\tans += str[ma1 + k] - '0';\n\t\t\t\t}\n\t\t\t}\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1850, "memory_kb": 12664, "score_of_the_acc": -1.1159, "final_rank": 8 } ]
aoj_0646_cpp
L番目のK番目の数 (LthKthNumber) 問題文 横一列に並べられた N 枚のカードがある.左から i 枚目( 1 ≦ i ≦ N )のカードには,整数 a_i が書かれている. JOI 君は,これらのカードを用いて次のようなゲームを行う.連続する K 枚以上のカードの列を選び,次の操作を行う. 選んだカードを,書かれている整数が小さい順に左から並べる. 並べたカードのうち,左から K 番目のカードに書かれた整数を紙に書き出す. 選んだカードを,すべて元の位置に戻す. この操作を,連続する K 枚以上のカードの列すべてに対して行う.すなわち, 1 ≦ l ≦ r ≦ N かつ K ≦ r - l + 1 を満たすすべての (l,r) について, a_l, a_{l+1}, ..., a_r のうち K 番目に小さな整数を書き出す. こうして書き出された整数を,左から小さい順に並べる.並べた整数のうち,左から L 番目のものがこのゲームにおける JOI 君の得点である.JOI 君の得点を求めよ. 制約 1 \leq N \leq 200000 1 \leq K \leq N 1 \leq a_i \leq N 1 \leq L JOI 君が書き出す整数は L 個以上である. 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N K L a_1 a_2 ... a_N 出力 JOI 君の得点を 1 行で出力せよ. 入出力例 入力例 1 4 3 2 4 3 1 2 出力例 1 3 1 \leq l \leq r \leq N (= 4) かつ K (= 3) \leq r - l + 1 を満たす (l,r) は, (1,3), (1,4), (2,4) の 3 通りある. これらの (l,r) に対し, a_l, a_{l+1}, ..., a_r で 3 番目に小さな整数は,それぞれ 4, 3, 3 である. このうち L (= 2) 番目に小さい整数は 3 なので,JOI 君の得点は 3 である.同じ整数が複数あるときも,重複して数えることに注意せよ. 入力例 2 5 3 3 1 5 2 2 4 出力例 2 4 JOI 君が書き出す整数は, (l,r) = (1,3) に対し 5 (l,r) = (1,4) に対し 2 (l,r) = (1,5) に対し 2 (l,r) = (2,4) に対し 5 (l,r) = (2,5) に対し 4 (l,r) = (3,5) に対し 4 である.このうち L (= 3) 番目に小さい整数は 4 である. 入力例 3 6 2 9 1 5 3 4 2 4 出力例 3 4 入力例 4 6 2 8 1 5 3 4 2 4 出力例 4 3
[ { "submission_id": "aoj_0646_10855821", "code_snippet": "/* ---------- STL Libraries ---------- */\n// IO library\n#include <cstdio>\n\n#include <fstream>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n\n// algorithm library\n#include <algorithm>\n\n#include <cmath>\n#include <numeric>\n#include <random>\n#include <cstring>\n#include <cassert>\n\n// container library\n#include <array>\n#include <bitset>\n#include <deque>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <string>\n#include <tuple>\n#include <vector>\n#include <stack>\n\n// type\n#include <cstdint>\n\n/* ---------- Namespace ---------- */\nusing namespace std;\n\n/* ---------- Type ---------- */\nusing ll = long long;\n#define int ll\n#define P pair<ll, ll>\n\n/* ---------- Constants */\nconst double PI = 3.141592653589793238462643383279;\nconst ll MOD = 1e9 + 7;\nconst int INF = 1LL << 55;\n\nint N, K, L;\nint A[200005];\n\nbool f(int x) {\n // x以下の数がK個以上ある連続区間の数を調べる\n int ret = 0;\n int cnt = 0;\n int r = -1;\n for (int l = 0; l < N; l++) {\n if (l >= 1 && A[l-1] <= x) cnt--;\n bool flag = false;\n\n while (r < 0 || cnt < K) {\n r++;\n if (A[r] <= x) cnt++;\n if (r >= N) {\n flag = true;\n break;\n }\n }\n\n if (flag) break;\n ret += N - r;\n }\n\n return ret >= L;\n}\n\nsigned main() {\n cin >> N >> K >> L;\n for (int i = 0; i < N; i++) cin >> A[i];\n\n int lb = 0;\n int ub = INF;\n while (ub - lb > 1) {\n int mid = (ub + lb) / 2;\n if (f(mid)) {\n ub = mid;\n } else {\n lb = mid;\n }\n }\n\n cout << ub << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4928, "score_of_the_acc": -0.5073, "final_rank": 6 }, { "submission_id": "aoj_0646_10850845", "code_snippet": "#include <bits/stdc++.h> // clang-format off\nusing namespace std;\nusing Int = long long;\n#define REP2(i, n) for (Int i = 0, max_i = (n); i < max_i; i++)\n#define REP3(i, a, b) for (Int i = (a), max_i = (b); i < max_i; i++)\n#define OVERLOAD2(_1, _2, _3, name, ...) name\n#define REP(...) OVERLOAD2(__VA_ARGS__, REP3, REP2)(__VA_ARGS__)\nstruct SetupIO { SetupIO() { cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(13); } } setup_io;\n#ifndef _MY_DEBUG\n#define dump(...)\n#endif // clang-format on\n\n/**\n * author: knshnb\n * created: Tue Mar 3 15:58:12 JST 2020\n **/\n\nsigned main() {\n Int n, K, L;\n cin >> n >> K >> L;\n vector<Int> a(n);\n REP(i, n) cin >> a[i];\n // mid以下がL個以上あるかどうか\n vector<Int> acc(n + 1);\n auto check = [&](Int mid) -> bool {\n REP(i, n) { acc[i + 1] = acc[i] + (a[i] <= mid); }\n Int cnt = 0;\n REP(i, n) {\n cnt += acc.end() - lower_bound(acc.begin(), acc.end(), acc[i] + K);\n }\n return cnt >= L;\n };\n Int ok = 1e8, ng = 0;\n while (abs(ok - ng) > 1) {\n Int mid = (ok + ng) / 2;\n (check(mid) ? ok : ng) = mid;\n }\n cout << ok << endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 6244, "score_of_the_acc": -1.5339, "final_rank": 16 }, { "submission_id": "aoj_0646_10803478", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#ifdef LOCAL\n#include \"algo/debug.h\"\n#else\n#define debug(...) 42\n#endif\n\ntemplate <class T> bool ckmax(T &a, T b) { return a < b ? (a = b, true) : false; }\ntemplate <class T> bool ckmin(T &a, T b) { return a > b ? (a = b, true) : false; }\n\nint64_t n, k, c;\nconst int MAXN = 2e5 + 5;\nint pre[MAXN], a[MAXN];\n\n/**\n\n Ta cnp ket qua. Dua ve bai toan kiem tra xem mot so x lon hon bao nhieu so trong day b\n Ta nhan thay, so x se nam trong day b khi va chi khi doan [l, r] co >= k so khong lon hon x\n Tim doan nho nhat thoa man, tat cac doan chua doan do deu se chua x\n\n*/\n\nbool check(int x) {\n for (int i = 1; i <= n; i++) pre[i] = pre[i - 1] + (a[i] <= x);\n int64_t r = 1, cnt = 0;\n for (int l = 1; l <= n; l++) {\n while (r < n && pre[r] - pre[l - 1] < k) r++;\n if (pre[r] - pre[l - 1] >= k) cnt += n - r + 1;\n }\n// debug(cnt);\n return cnt >= c;\n}\n\nint main() {\n #define NAME \"test\"\n if (fopen(NAME\".inp\", \"r\")) {\n freopen(NAME\".inp\", \"r\", stdin);\n freopen(NAME\".out\", \"w\", stdout);\n }\n ios_base::sync_with_stdio(false);\n cin.tie(nullptr);\n cin >> n >> k >> c;\n for (int i = 1; i <= n; i++) cin >> a[i];\n int l = 1, r = n, ans;\n while (l <= r) {\n int mid = (l + r) >> 1;\n if (check(mid)) {\n r = mid - 1;\n ans = mid;\n } else {\n l = mid + 1;\n }\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5012, "score_of_the_acc": -0.326, "final_rank": 4 }, { "submission_id": "aoj_0646_10650155", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n#define ull unsigned long long\n#define ld long double\n#define pb push_back\n#define mkp make_pair\n#define fi first\n#define se second\n#define pii pair<int, int>\n#define all(x) (x).begin(), (x).end()\n#define sz(x) (int)(x).size()\n#define rep(i, l, r) for (int i = (l); i < (r); ++i)\n#define per(i, l, r) for (int i = (r) - 1; i >= (l); --i)\n#define INF 0x3f3f3f3f\n#define LINF (ll)4e18\n#define EPS 1e-9\n#define PI acos(-1)\n#define fopen_in(f) freopen(f, \"r\", stdin)\n#define fopen_out(f) freopen(f, \"w\", stdout)\n#define endl '\\n'\n#define debug(x) cerr << #x << \": \" << x << endl\n#define int ll\nconst int N = 2e5 + 5;\nint n, k, c, a[N], b[N], pre[N];\nbool check(int x)\n{\n for (int i = 1; i <= n; i++)\n {\n pre[i] = pre[i - 1] + (a[i] <= x);\n }\n int r = 1, cnt = 0;\n for (int i = 1; i <= n; i++)\n {\n while (r <= n && pre[r] - pre[i - 1] < k)\n r++;\n if (pre[r] - pre[i - 1] >= k)\n cnt += n - r + 1;\n }\n return (cnt >= c);\n}\nvoid solve()\n{\n cin >> n >> k >> c;\n for (int i = 1; i <= n; i++)\n {\n cin >> a[i];\n }\n int l = 1, r = n, ans = -1;\n while (l <= r)\n {\n int mid = l + r >> 1;\n if (check(mid))\n ans = mid, r = mid - 1;\n else\n l = mid + 1;\n }\n cout << ans << endl;\n}\n\nmain()\n{\n ios::sync_with_stdio(false);\n cin.tie(0);\n int T = 1;\n // cin >> T;\n while (T--)\n solve();\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7544, "score_of_the_acc": -0.8902, "final_rank": 10 }, { "submission_id": "aoj_0646_10650147", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n#define ull unsigned long long\n#define ld long double\n#define pb push_back\n#define mkp make_pair\n#define fi first\n#define se second\n#define pii pair<int, int>\n#define all(x) (x).begin(), (x).end()\n#define sz(x) (int)(x).size()\n#define rep(i, l, r) for (int i = (l); i < (r); ++i)\n#define per(i, l, r) for (int i = (r) - 1; i >= (l); --i)\n#define INF 0x3f3f3f3f\n#define LINF (ll)4e18\n#define EPS 1e-9\n#define PI acos(-1)\n#define fopen_in(f) freopen(f, \"r\", stdin)\n#define fopen_out(f) freopen(f, \"w\", stdout)\n#define endl '\\n'\n#define debug(x) cerr << #x << \": \" << x << endl\n\nconst int N = 2e5 + 5;\nint n, k, c, a[N], b[N], pre[N];\nbool check(int x)\n{\n for (int i = 1; i <= n; i++)\n {\n pre[i] = pre[i - 1] + (a[i] <= x);\n }\n int r = 1, cnt = 0;\n for (int i = 1; i <= n; i++)\n {\n while (r <= n && pre[r] - pre[i - 1] < k)\n r++;\n if (pre[r] - pre[i - 1] >= k)\n cnt += n - r + 1;\n }\n return (cnt >= c);\n}\nvoid solve()\n{\n cin >> n >> k >> c;\n for (int i = 1; i <= n; i++)\n {\n cin >> a[i];\n }\n int l = 1, r = n, ans = -1;\n while (l <= r)\n {\n int mid = l + r >> 1;\n if (check(mid))\n ans = mid, r = mid - 1;\n else\n l = mid + 1;\n }\n cout << ans << endl;\n}\n\nmain()\n{\n ios::sync_with_stdio(false);\n cin.tie(0);\n int T = 1;\n // cin >> T;\n while (T--)\n solve();\n return 0;\n}", "accuracy": 0.7027027027027027, "time_ms": 10, "memory_kb": 4072, "score_of_the_acc": -0.0499, "final_rank": 19 }, { "submission_id": "aoj_0646_10650139", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n#define ull unsigned long long\n#define ld long double\n#define pb push_back\n#define mkp make_pair\n#define fi first\n#define se second\n#define pii pair<int, int>\n#define all(x) (x).begin(), (x).end()\n#define sz(x) (int)(x).size()\n#define rep(i, l, r) for (int i = (l); i < (r); ++i)\n#define per(i, l, r) for (int i = (r) - 1; i >= (l); --i)\n#define INF 0x3f3f3f3f\n#define LINF (ll)4e18\n#define EPS 1e-9\n#define PI acos(-1)\n#define fopen_in(f) freopen(f, \"r\", stdin)\n#define fopen_out(f) freopen(f, \"w\", stdout)\n#define endl '\\n'\n#define debug(x) cerr << #x << \": \" << x << endl\n\nconst int N = 2e5 + 5;\nint n, k, c, a[N], b[N], pre[N];\nbool check(int x)\n{\n for (int i = 1; i <= n; i++)\n {\n pre[i] = pre[i - 1] + (a[i] <= x);\n }\n int r = 1, cnt = 0;\n for (int i = 1; i <= n; i++)\n {\n while (r <= n && pre[r] - pre[i - 1] < k)\n r++;\n if (r > n)\n break;\n cnt += n - r + 1;\n }\n return (cnt >= c);\n}\nvoid solve()\n{\n cin >> n >> k >> c;\n for (int i = 1; i <= n; i++)\n {\n cin >> a[i];\n }\n int l = 1, r = n, ans = -1;\n while (l <= r)\n {\n int mid = l + r >> 1;\n if (check(mid))\n ans = mid, r = mid - 1;\n else\n l = mid + 1;\n }\n cout << ans << endl;\n}\n\nmain()\n{\n ios::sync_with_stdio(false);\n cin.tie(0);\n int T = 1;\n // cin >> T;\n while (T--)\n solve();\n return 0;\n}", "accuracy": 0.7027027027027027, "time_ms": 10, "memory_kb": 3900, "score_of_the_acc": -0.0116, "final_rank": 18 }, { "submission_id": "aoj_0646_10649961", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\nconst int maxn = 2e5 + 5;\nint n, k, l, a[maxn], sum[maxn];\nbool check (int x) {\n int cnt = 0;\n for (int i = 1; i <= n; i++)\n sum[i] = sum[i - 1] + (a[i] <= x);\n for (int i = 1, j = 1; i <= n; i++) {\n while (j < n && sum[j] - sum[i - 1] < k)\n j++;\n if (sum[j] - sum[i - 1] >= k) cnt += n - j + 1;\n }\n return cnt >= l;\n}\nsigned main () {\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n cin >> n >> k >> l;\n for (int i = 1; i <= n; i++)\n cin >> a[i];\n int l = 1, r = n, mid, ans;\n while (l <= r) {\n mid = l + r >> 1;\n if (check (mid)) {\n ans = mid;\n r = mid - 1;\n }\n else l = mid + 1;\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6588, "score_of_the_acc": -0.6772, "final_rank": 8 }, { "submission_id": "aoj_0646_10223112", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\n\nvoid solve(){\n ll N,K,L;\n cin>>N>>K>>L;\n vector<ll> A(N);\n rep(i,N)cin>>A[i];\n ll ok=0,ng=N+1;\n while(ng-ok>1){\n ll mid=(ok+ng)/2;\n vector<ll> B(N+1,0);\n rep(i,N){\n B[i+1]=B[i]+(A[i]<=mid);\n }\n ll cnt=0;\n rep(i,N){\n ll p=lower_bound(all(B),B[i]+K)-B.begin();\n p=max(p,i+K);\n p=min(p,N+1);\n if(p>=0)cnt+=N+1-p;\n }\n (cnt<L?ok:ng)=mid;\n }\n cout<<ng<<endl;\n}\n\nint main(){\n \n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int T=1;\n while(T--)\n solve();\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 6216, "score_of_the_acc": -0.9943, "final_rank": 11 }, { "submission_id": "aoj_0646_9669936", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pi;\ntypedef pair<ll,pi> ppi;\ntypedef pair<ll,ppi> pppi;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef vector<vvi> vvvi;\n#define FOR(i,l,r) for(ll i=l;i<r;i++)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(A) A.begin(),A.end()\n#define LB(A,x) (lower_bound(ALL(A),x)-A.begin())\ntemplate<typename T>bool chmin(T&a,T b){if(a>b){a=b;return 1;}return 0;}\nint main(){\n ll N,K,L;cin>>N>>K>>L;\n vi A(N);REP(i,N)cin>>A[i];\n ll l=0,r=N+1;\n while(r-l>1){\n ll m=(l+r)/2;\n vector<ll>B;\n REP(i,N)if(A[i]<=m)B.emplace_back(i);\n ll cnt=0;\n REP(i,N){\n ll t=LB(B,i);\n if(t+K>B.size())break;\n cnt+=N-B[t+K-1];\n }\n if(cnt>=L)r=m;\n else l=m;\n }\n cout<<r<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 8336, "score_of_the_acc": -1.6667, "final_rank": 17 }, { "submission_id": "aoj_0646_9394255", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=int64_t;\n\nstruct bit{\n vector<int> b;\n int m,m2;\n \n bit(int n){\n m=n;\n m2=1;\n while(m2<n) m2*=2;\n m2/=2;\n b.resize(m+1,0);\n }\n \n void add(int a,int w){\n for(int x=a;x<=m;x+=x&-x) b[x]+=w;\n }\n \n int sum(int a){\n int res=0;\n for(int x=a;x>0;x-=x&-x) res+=b[x];\n return res;\n }\n \n int lb(int w){\n int x=0;\n for(int k=m2;k>0;k/=2){\n if(k+x<=m && b[k+x]<w){\n w-=b[k+x];\n x+=k;\n }\n }\n return x+1;\n }\n \n};\n\nint main() {\n int n,k;\n ll l;\n cin >> n >> k >> l;\n\n vector<int> a(n);\n int amx=0;\n for(int i=0;i<n;i++){\n cin >> a[i];\n amx=max(amx,a[i]);\n }\n \n \n int s=0,t=amx;\n while(t-s>1){\n int md=(s+t)/2;\n int rgt=0;\n ll num=0;\n bit bt(amx);\n for(int lft=0;lft<n;lft++){\n while(rgt<n && bt.sum(md)<k){\n bt.add(a[rgt],1);\n rgt++;\n }\n if(bt.sum(md)<k) break;\n num+=n-rgt+1;\n bt.add(a[lft],-1);\n }\n if(num>=l) t=md;\n else s=md;\n }\n cout << t << endl;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 4696, "score_of_the_acc": -1.0556, "final_rank": 13 }, { "submission_id": "aoj_0646_9068364", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, k;\n cin >> n >> k;\n ll L;\n cin >> L;\n vector<int> a(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n }\n auto check = [&](int x) -> bool {\n int cnt = 0;\n ll sum = 0;\n int r = 0;\n for (int i = 0; i < n; ++i) {\n while (r < n and cnt < k) {\n if (a[r] <= x) cnt += 1;\n r += 1;\n }\n if (cnt >= k) sum += n - r + 1;\n if (a[i] <= x) cnt -= 1;\n }\n return sum >= L;\n };\n int l = 0, r = n;\n while (r - l > 1) {\n int mid = (l + r) / 2;\n if (check(mid)) r = mid;\n else l = mid;\n }\n cout << r << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3900, "score_of_the_acc": -0.0783, "final_rank": 1 }, { "submission_id": "aoj_0646_8875098", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nconst int maxn = 2e5+7;\nusing ll = long long;\nint n,k; ll l;\nint A[maxn];\n\nbool check(int x)\n{\n\tint cnt=0,tot=0,r=1;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\twhile(r<=n && cnt<k)\n\t\t{\n\t\t\tif(A[r]<=x)++cnt;\n\t\t\t++r;\n\t\t}\n\t\tif(cnt==k)tot+=n-r+2;\n\t\tif(A[i]<=x)--cnt;\n\t}\n\t\n\treturn tot>=l;\n}\n\nint main()\n{\n\tcin>>n>>k>>l;\n\tfor(int i=1;i<=n;i++)cin>>A[i];\n\t\n\tint ok=2e5,no=0;\n\twhile(no+1<ok)\n\t{\n\t\tint mid = (ok+no)/2;\n\t\tif(check(mid))ok=mid;\n\t\telse no=mid;\n\t}\n\tcout<<ok<<endl;\n\t\n\treturn 0;\n}", "accuracy": 0.7027027027027027, "time_ms": 40, "memory_kb": 4120, "score_of_the_acc": -0.2606, "final_rank": 20 }, { "submission_id": "aoj_0646_8449383", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n, k, a[200010];\n long long l;\n cin >> n >> k >> l;\n for(int i=0;i<n;i++) cin >> a[i];\n int le=1, ri=n;\n while(le < ri){\n int mid = (le+ri)/2;\n int j=0, cnt=0;\n long long sum=0;\n for(int i=0;i<n;i++){\n while(j<n && cnt<k){\n if(a[j]<=mid) cnt++;\n j++;\n }\n if(cnt==k) sum += (n-j+1);\n if(a[i]<=mid) cnt--;\n }\n if(sum>=l) ri = mid;\n else le = mid+1;\n }\n cout << ri << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3848, "score_of_the_acc": -0.2667, "final_rank": 3 }, { "submission_id": "aoj_0646_8243267", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\n\n#define int ll\n#define rep(i, n) for(int i = 1; i <= n; ++i)\n#define forn(i, l, r) for(int i = l; i <= r; ++i)\n#define ford(i, r, l) for(int i = r; i >= l; --i)\n#define FOR(i, n) for(int i = 0; i < n; ++i)\n#define fi first\n#define se second\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define pb push_back\n#define task \"MEETING\"\n#define endl \"\\n\"\n#define sz(a) int(a.size())\n#define C(x, y) make_pair(x, y)\n#define all(a) (a).begin(), (a).end()\n#define bit(i, mask) (mask >> i & 1)\n\ntemplate<typename T> bool maximize(T &res, const T &val) { if (res <= val){ res = val; return true; }; return false; }\ntemplate<typename T> bool minimize(T &res, const T &val) { if (res >= val){ res = val; return true; }; return false; }\n\n\nconst int N = 2e5 + 2;\nconst int K = 1e3 + 1;\nconst int MOD = 1e9 + 7;\nconst int INF = 500;\nconst int block_size = 230;\nconst int offset = 118;\nconst int LIM = 250;\nconst int AL = 26;\nconst int M = 11;\nconst int LOG = 20;\n\nint n, k, l;\n\nint a[N];\n\nvector<int> c;\n\nbool check(int x)\n{\n\tint j = 1, cnt = 0, res = 0;\n\trep(i, n)\n\t{\n\t\twhile(j <= n && cnt < k) cnt += a[j] <= x, ++j;\n\t\tif(cnt == k) res += n - j + 2;\n\t\tcnt -= a[i] <= x;\n\t}\n\treturn res >= l;\n}\n\nvoid solve()\n{\n cin >> n >> k >> l;\n\trep(i, n) cin >> a[i], c.pb(a[i]);\n\tsort(all(c));\n\n\tint l = 1, r = n, res = 0;\n\twhile(l <= r)\n\t{\n\t\tint mid = l + r >> 1;\n\t\tif(check(c[mid - 1])) res = mid, r = mid - 1;\n\t\telse l = mid + 1;\n\t}\n\tcout << c[res - 1];\n}\n\nsigned main()\n{\n\n ios_base::sync_with_stdio(0);\n cin.tie(0); cout.tie(0);\n if(fopen(task\".inp\", \"r\"))\n {\n freopen(task\".inp\", \"r\", stdin);\n freopen(task\".out\", \"w\", stdout);\n }\n\n\tint TC = 1;\n while(TC--)\n {\n solve();\n cout << endl;\n }\n\n return 0;\n}\n//haha", "accuracy": 1, "time_ms": 30, "memory_kb": 6456, "score_of_the_acc": -0.7144, "final_rank": 9 }, { "submission_id": "aoj_0646_7969928", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing pl = pair<ll,ll>;\nusing vp = vector<pl>;\n#define rep(i,n) for(ll i=0;i<(ll)(n);++i)\n#define reps(i,s,n) for(ll i=(s);i<(ll)(n);++i)\n#define rep1(i,n) for(ll i=1;i<=(ll)(n);++i)\ntemplate<typename T>inline bool chmax(T &a,T b){return a<b?a=b,true:false;}\ntemplate<typename T>inline bool chmin(T &a,T b){return a>b?a=b,true:false;}\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n#define be(v) (v).begin(),(v).end()\nconst long long INF = 1e18;\n#ifdef DEBUG\n#include <debug.hpp>\nrandom_device rd;\nmt19937 gen(rd());\nll random(ll l,ll h){\n\tuniform_int_distribution<ll> dist(l,h);\n\treturn dist(gen);\n}\n#endif\n\nll N,K,L;\nvp A;\nvoid input(){\n\tcin>>N>>K>>L;\n\tA.assign(N,pl(0,0));\n\trep(n,N){\n\t\tcin>>A.at(n).fi;\n\t\tA.at(n).se = n;\n\t}\n}\n#ifdef DEBUG\nvoid showall(){\n\tshow(N,K,L,A);\n}\n#endif\nll logic(){\n\tsort(be(A));\n\tvl ind(N);\n\trep(n,N){\n\t\tind.at(A.at(n).se) = n;\n\t}\n\t#ifdef DEBUG\n\tshow(\"ind\",ind);\n\t#endif\n\tll ng=0,ok=N;\n\twhile(ng < ok - 1){\n\t\tll m=(ok+ng)/2;\n\t\t#ifdef DEBUG\n\t\tshow(\"ng ok m\",ng,ok,m);\n\t\t#endif\n\t\tll sum=0,cnt=0,r=-1;\n\t\trep(l,N){\n\t\t\t#ifdef DEBUG\n\t\t\tshow(\" l r cnt\",l,r,cnt);\n\t\t\t#endif\n\t\t\twhile(r<N && cnt < K){\n\t\t\t\t++r;\n\t\t\t\tif(r<N && ind.at(r) <= m){\n\t\t\t\t\t++cnt;\n\t\t\t\t}\n\t\t\t}\n\t\t\tsum += N - r;\n\t#ifdef DEBUG\n\t\t\tshow(\" r,cnt,sum\",r,cnt,sum);\n\t#endif\n\t\t\tif(ind.at(l) <= m)--cnt;\n\t#ifdef DEBUG\n\t\t\tshow(\" cnt\",cnt);\n\t#endif\n\t\t}\n\t\tif(sum>=L)ok=m;\n\t\telse ng=m;\n\t#ifdef DEBUG\n\t\tshow(\" sum,sum>=L,ng,ok\",sum,(sum>=L),ng,ok);\n\t#endif\n\t}\n\treturn A.at(ok).fi;\n}\n#ifdef DEBUG\nll naive(){\n\treturn 1;\n}\n#endif\nint main(){\n\t#ifdef DEBUG\n\tcout << \"--- Input ---\" << endl;\n\t#endif\n\tinput();\n\t#ifdef DEBUG\n\tshowall();\n\tcout << \"--- Logic ---\" << endl;\n\t#endif\n\tll ans=logic();\n\t#ifdef DEBUG\n\tcout << \"--- Answer ---\" << endl;\n\t#endif\n\tcout<<ans<<endl;\n\t//while(input())logic();\n\t#ifdef DEBUG\n\t//show(\"naive=\",naive());\n\t#endif\n\t#ifdef DEBUG\n\t/*\n\trep(q,100){\n\t\tN=random(1LL,1000LL);\n\t\tll lans=logic(),nans=naive();\n\t\tshowall();\n\t\tif(lans!=nans){ show(\" WA\",lans,nans); break; }\n\t\telse{ show(\" AC\",lans,nans); }\n\t}\n\t*/\n\t#endif\n\treturn 0;\n}\n//cout << fixed << setprecision(9);", "accuracy": 1, "time_ms": 60, "memory_kb": 7796, "score_of_the_acc": -1.213, "final_rank": 15 }, { "submission_id": "aoj_0646_7763366", "code_snippet": "/*\n勉強させていただいた記事\nhttps://qiita.com/drken/items/ecd1a472d3a0e7db8dce#%E5%95%8F%E9%A1%8C-9joi-2017-%E4%BA%88%E9%81%B8-f-l%E7%95%AA%E7%9B%AE%E3%81%AEk%E7%95%AA%E7%9B%AE%E3%81%AE%E6%95%B0\nhttps://algo-logic.info/binary-indexed-tree/#\n\n*/\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll, ll> pll;\n\nconst ll LongINF=1e13+7;\nconst int INF=1e9+7;\nconst int dx[]={0,1,0,-1};\nconst int dy[]={1,0,-1,0};\n\ntemplate<class T> inline bool chmin(T& a, T b) {if (a > b) {a = b;return true;}return false;}\ntemplate<class T> inline bool chmax(T& a, T b) {if (a < b) {a = b;return true;}return false;}\ntemplate <class T, class Y>T GCD(T a, Y b){if(a<b){T c=a;a=b;b=c;}if (a % b == 0){return b;}return GCD(b, a % b);}\ntemplate<class T,class Y>T LCM(T a,Y b){return (a*b)/GCD(a,b);}\nvoid clear(queue<pair<int, int>> &q){queue<pair<int, int>> empty;swap(q, empty);} //queueの中身の型は適時変更を忘れない\n\nusing vi=vector<int>;\nusing vii=vector<vi>;\n\n#define REP(i,a,b) for(ll i=(a);i<(b);i++)\n#define rep(i,n) REP(i,0,n)\n#define pb push_back\n#define rv reverse\n#define ALL(a) (a).begin(),(a).end()\n#define decimal(x) fixed<<setprecision(x)\n\ntemplate <class Abel> struct BIT{\n vector<Abel> dat;\n Abel UNITY_SUM=0;\n\n BIT(int n){\n init(n);\n }\n\n //1-indexed\n //配列数nを確保\n void init(int n){\n dat.resize(n+1);\n rep(i,dat.size())dat[i]=UNITY_SUM;\n }\n\n\n //加算のやり方として i+=i&-iと、bitが立っている最下位を加算することで、変更の必要があるものを指すことができる。\n inline void add(int a,Abel x){\n for(int i=a;i<(int)dat.size();i += i & -i){\n dat[i]=dat[i]+x;\n }\n }\n\n //inline を使うことで使い分けができる。\n ////減算のやり方として i-=i&-iと、bitが立っている最下位を減算することで、変更の必要があるものを指すことができる。\n inline Abel sum(int a){\n Abel res=UNITY_SUM;\n for(int i=a;i>0;i-=i&-i){\n res=res+dat[i];\n }\n return res;\n }\n\n inline Abel sum(int a,int b){\n return sum(b-1)-sum(a-1);\n }\n};\n\nint main(){\n ll N,K,L;\n cin>>N>>K>>L;\n vi a(N);\n rep(i,N)cin>>a[i];\n \n int low=0,high=N;\n while(high-low>1){\n int mid=low+(high-low)/2;\n\n BIT<int> bit(N+1);\n int right=0;\n ll num=0;\n rep(left,N){\n while(right<N&&bit.sum(mid)<K){\n bit.add(a[right],1);\n right++;\n }\n if(bit.sum(mid)<K)break;\n num+=N-right+1;\n bit.add(a[left],-1);\n }\n\n if(num>=L)high=mid;\n else low=mid;\n }\n\n cout<<high<<endl;\n\n return 0;\n}\n/*\n\n*/", "accuracy": 1, "time_ms": 150, "memory_kb": 4660, "score_of_the_acc": -1.1143, "final_rank": 14 }, { "submission_id": "aoj_0646_7072096", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\ntemplate<typename T>\nstruct BIT{\n ll n;\n ll k=1;\n vector<T>data;\n BIT() = default;\n BIT(ll size):n(size){\n data.assign(n,0);\n while(k*2<=n)k*=2;\n }\n void add(ll a,T w){\n for(ll i=a+1;i<=n;i+=i&-i)data[i-1]+=w;\n }\n T sum(ll a){//[0,a)\n\t if(a<=0)return 0;\n T ret = 0;\n for(ll i=a;i>0;i-=i&-i)ret+=data[i-1];\n return ret;\n }\n //[a,b)\n T sum(ll a,ll b){return a>=b?0:sum(b)-sum(a);}\n T operator[](ll pos){\n return sum(pos,pos+1);\n }\n ll lower_bound(ll x){\n ll ret=0; \n for(ll i=k;i>0;i/=2){\n if(ret+i<=n&&data[ret+i-1]<x){\n x-=data[ret+i-1];\n ret+=i;\n }\n }\n return ret;\n }\n ll lower_first(ll x){\n return lower_bound(sum(n)-x+1);\n }\n void print(){\n for(ll i=0;i<n;i++){\n if(i!=0)cout<<\" \";\n cout<<(*this)[i];\n }\n cout<<endl;\n }\n};\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll n,k,l;cin>>n>>k>>l;\n\tvector<ll>a(n);\n\trep(i,0,n)cin>>a[i];\n\tll ok=1,ng=n+1;\n\twhile(ng-ok>=2){\n\t\tll mid=(ok+ng)/2;\n\t\tqueue<ll>que;\n\t\tll cnt=0;\n\t\tll num=0;\n\t\trep(i,0,n){\n\t\t\tif(a[i]<mid)que.push(i);\n\t\t\twhile(que.size()>k)que.pop();\n\t\t\tll f=0;\n\t\t\tif(que.size()==k)f=que.front()+1;\n\t\t\tcnt+=max(0LL,i+1-f-(k-1));\n\t\t\t//cout<<\"c\" spa i spa cnt<<endl;\n\t\t\tnum+=max(0LL,i+1-(k-1));\n\t\t}\n\t\t//cout<<mid spa cnt<<endl;\n\t\tif(num-cnt<l)ok=mid;\n\t\telse ng=mid;\n\t}\n\tcout<<ok<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 6120, "score_of_the_acc": -0.5729, "final_rank": 7 }, { "submission_id": "aoj_0646_7054581", "code_snippet": "/* [Author : Hoang Duy Vu] - THPT Chuyen Nguyen Du */\n#include <bits/stdc++.h>\n#define All(x) (x).begin(),(x).end()\n#define ll long long\n#define C make_pair\n#define fi first\n#define se second\n#define two second.first\n#define thr second.second\n#define TASK \"txt\"\nusing namespace std;\ntemplate<typename T> bool maximize(T &res, const T &val) {\n if (res < val) { res = val; return true; } return false; }\ntemplate<typename T> bool minimize(T &res, const T &val) {\n if (res > val) { res = val; return true; } return false; }\n\ntypedef pair<int,int> ii;\ntypedef pair<int,ii> iii;\nconst int LOG = 20;\nconst int INF = 1e9 + 7;\nconst ll LNF = 1e18 + 7;\nconst int mod = 1e9 + 7;\nconst int N = 2e5 + 100;\n\nll f[N] = {0};\nint a[N];\nint n , k;\nll l;\n\nvoid input()\n{\n cin >> n >> k >> l;\n\n for (int i = 1 ; i <= n ; i++) cin >> a[i];\n}\n\nbool ok(int h)\n{\n int pre = 0;\n f[0] = 0;\n ll cnt = 0;\n\n for (int i = 1 ; i <= n ; i++) \n {\n pre += (a[i] <= h);\n f[pre] = i;\n\n if (pre >= k)\n cnt += f[pre - k] + 1ll;\n }\n\n return cnt >= l; \n}\n\nvoid solve()\n{\n int l = 1 , r = n , res = 0;\n\n while (l <= r)\n {\n int m = (l + r) >> 1;\n\n if (ok(m)) \n {\n res = m;\n r = m - 1;\n }\n else l = m + 1;\n }\n\n cout << res << '\\n';\n}\n\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(NULL); cout.tie(NULL);\n if(fopen(TASK\".inp\", \"r\")){\n freopen(TASK\".inp\",\"r\",stdin);\n freopen(TASK\".out\",\"w\",stdout);\n }\n\n int tk;\n tk = 1;\n //cin >> tk;\n while (tk--)\n {\n input();\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5596, "score_of_the_acc": -0.3895, "final_rank": 5 }, { "submission_id": "aoj_0646_7031468", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\ntemplate <class T> struct fenwick_tree {\n using U = T;\n\n public:\n fenwick_tree() : _n(0) {}\n fenwick_tree(int n) : _n(n), data(n) {}\n\n void add(int p, T x) {\n assert(0 <= p && p < _n);\n p++;\n while (p <= _n) {\n data[p - 1] += U(x);\n p += p & -p;\n }\n }\n\n T sum(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n return sum(r) - sum(l);\n }\n\n private:\n int _n;\n std::vector<U> data;\n\n U sum(int r) {\n U s = 0;\n while (r > 0) {\n s += data[r - 1];\n r -= r & -r;\n }\n return s;\n }\n};\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n int n, k;\n ll L;\n cin >> n >> k >> L;\n vector<int> a(n);\n for(auto &&v:a)cin >> v;\n a.push_back(0);\n int ok = 1, ng = n + 1;\n while(ok + 1 < ng){\n int mid = (ok + ng) / 2;\n ll cnt = 0;\n fenwick_tree<int> fw(n + 1);\n for(int l = 0, r = 0; l < n; l++){\n while(r <= n && fw.sum(0, mid + 1) < k)fw.add(a[r++], 1);\n cnt += n + 1 - r;\n fw.add(a[l], -1);\n }\n if(cnt < L)ok = mid;\n else ng = mid;\n }\n cout << ++ok << '\\n';\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 4552, "score_of_the_acc": -1.0235, "final_rank": 12 }, { "submission_id": "aoj_0646_6949104", "code_snippet": "#include <bits/stdc++.h>\n\tusing namespace std;\n\t\n\tvoid file() {\n\t\tconst string LTM = \"\";\n\t\tif (fopen((LTM + \".inp\").c_str(), \"r\")) {\n\t\t\tfreopen((LTM + \".inp\").c_str(), \"r\", stdin);\n\t\t\tfreopen((LTM + \".out\").c_str(), \"w\", stdout);\n\t\t}\t\n\t}\n\t\n\tconst int N = 2e5 + 5;\n\t\n\tint n, k, a[N];\n\tlong long l;\n\t\n\tbool check(int x) {\n\t\tlong long cnt = 0;\n\t\tfor (int i = 1, j = 1, s = 0; i <= n; ++i) {\n\t\t\twhile (s < k && j <= n) {\n\t\t\t\tif (a[j] <= x) ++s; ++j;\n\t\t\t} \n\t\t\tif (s == k) cnt += n - j + 2;\n\t\t\tif (a[i] <= x) --s;\n\t\t}\n\t\treturn cnt >= l;\n\t}\n\t\n\tint main() {\n\t\tcin.tie(0)->sync_with_stdio(0); \n\t\tcin >> n >> k >> l;\n\t\tfor (int i = 1; i <= n; ++i) cin >> a[i];\n\t\tint lo = 1, hi = n, res;\n\t\twhile (lo <= hi) {\n\t\t\tint mi = (lo + hi) / 2;\n\t\t\tif (check(mi)) res = mi, hi = mi - 1;\n\t\t\telse lo = mi + 1;\n\t\t}\n\t\tcout << res << '\\n';\n\t\treturn 0;\n\t}", "accuracy": 1, "time_ms": 30, "memory_kb": 4140, "score_of_the_acc": -0.1984, "final_rank": 2 } ]
aoj_0650_cpp
定期券(Commuter Pass) JOI 君が住む都市には N 個の駅があり,それぞれ 1, 2, ..., N の番号が付けられている.また, M 本の鉄道路線があり,それぞれ 1, 2, ..., M の番号が付けられている.鉄道路線 i ( 1 \leq i \leq M ) は駅 A_i と駅 B_i を双方向に結んでおり,乗車運賃は C_i 円である. JOI 君は駅S の近くに住んでおり,駅 T の近くのIOI 高校に通っている.そのため,両者を結ぶ定期券を購入することにした.定期券を購入する際には,駅 S と駅 T の間を最小の運賃で移動する経路を一つ指定しなければならない.この定期券を用いると,指定した経路に含まれる鉄道路線は双方向に自由に乗り降りできる. JOI 君は,駅 U および駅 V の近くにある書店もよく利用している.そこで,駅 U から駅 V への移動にかかる運賃ができるだけ小さくなるように定期券を購入したいと考えた. 駅 U から駅 V への移動の際は,まず駅 U から駅 V への経路を1 つ選ぶ.この経路に含まれる鉄道路線 i において支払うべき運賃は, 鉄道路線 i が定期券を購入する際に指定した経路に含まれる場合,0 円 鉄道路線 i が定期券を購入する際に指定した経路に含まれない場合, C_i 円 となる.この運賃の合計が,駅 U から駅 V への移動にかかる運賃である. 定期券を購入する際に指定する経路をうまく選んだときの,駅 U から駅 V への移動にかかる運賃の最小値を求めたい. 課題 定期券を購入する際に指定する経路をうまく選んだときの,駅 U から駅 V への移動にかかる運賃の最小値を求めるプログラムを作成せよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,2 個の整数 N, M が書かれている.これらは,JOI 君が住む都市に N 個の駅と M 本の鉄道路線があることを表す. 2 行目には,2 個の整数 S, T が書かれている.これらは,JOI 君が駅 S から駅 T への定期券を購入することを表す. 3 行目には,2 個の整数 U, V が書かれている.これらは,JOI 君が駅 U から駅 V への移動にかかる運賃を最小化したいことを表す. 続く M 行のうちの i 行目( 1 \leq i \leq M ) には,3 個の整数 A_i, B_i,C_i が書かれている.これらは,鉄道路線 i が駅 A_i と駅 B_i を双方向に結び,その運賃が C_i 円であることを表す. 出力 標準出力に,定期券を購入する際に駅 S から駅 T への経路をうまく指定したときの,駅 U から駅 V への移動にかかる運賃の最小値を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 2 \leq N \leq 100 000. 1 \leq M \leq 200 000. 1 \leq S \leq N. 1 \leq T \leq N. 1 \leq U \leq N. 1 \leq V \leq N. S ≠ T. U ≠ V. S ≠ U または T ≠ V. どの駅から他のどの駅へも1 本以上の鉄道路線を用いて到達できる. 1 \leq A_i < B_i \leq N (1 \leq i l\leq M). 1 \leq i < j \leq M に対し, A_i ≠ A_j または B_i ≠ B_j. 1 \leq C_i \leq 1 000 000 000 (1 \leq i \leq M). 入出力例 入力例1 6 6 1 6 1 4 1 2 1 2 3 1 3 5 1 2 4 3 4 5 2 5 6 1 出力例1 2 この入力例では,定期券を買う際に指定できる経路は駅1 → 駅2 → 駅3 → 駅5 → 駅6 という経路に限られる. 駅1 から駅4 への移動にかかる運賃を最小化するには,駅1 → 駅2 → 駅3 → 駅5 → 駅4 という経路を選べばよい.この経路を選んだ場合,各鉄道路線において支払うべき運賃は, 駅4 と駅5 を結ぶ鉄道路線5 においては,2 円. それ以外の鉄道路線においては,0 円. となるので,かかる運賃の合計は2 円となる. 入力例2 6 5 1 2 3 6 1 2 1000000000 2 3 1000000000 3 4 1000000000 4 5 1000000000 5 6 1000000000 出力例2 3000000000 この入力例では,駅3 から駅6 への移動に定期券を用いない. 入力例3 8 8 5 7 6 8 1 2 2 2 3 3 3 4 4 1 4 1 1 5 5 2 6 6 3 7 7 4 8 8 出力例3 15 入力例4 5 5 1 5 2 3 1 2 1 2 3 10 2 4 10 3 5 10 4 5 10 出力例4 0 入力例5 10 15 6 8 7 9 2 7 12 8 10 17 1 3 1 3 8 14 5 7 15 2 3 7 1 10 14 3 6 12 1 5 10 8 9 1 2 9 7 1 4 1 1 8 1 2 4 7 5 6 16 出力例5 19 情報オリンピック日本委員会作 『第17 回日本情報オリンピック(JOI 2017/2018) 本選』
[ { "submission_id": "aoj_0650_10848621", "code_snippet": "#include <bits/stdc++.h>\n#define REP(i, n) for (int i = 0; (i) < int(n); ++ (i))\n#define ALL(x) begin(x), end(x)\nusing ll = long long;\nusing namespace std;\ntemplate <class T> inline void chmin(T & a, T const & b) { a = min(a, b); }\n\nvector<ll> dijkstra(vector<vector<pair<int, ll> > > const & g, int root) {\n vector<ll> dist(g.size(), LLONG_MAX);\n priority_queue<pair<ll, int> > que;\n dist[root] = 0;\n que.emplace(- dist[root], root);\n while (not que.empty()) {\n ll dist_i; int i; tie(dist_i, i) = que.top(); que.pop();\n if (dist[i] < - dist_i) continue;\n for (auto it : g[i]) {\n int j; ll cost; tie(j, cost) = it;\n if (- dist_i + cost < dist[j]) {\n dist[j] = - dist_i + cost;\n que.emplace(dist_i - cost, j);\n }\n }\n }\n return dist;\n}\n\nint main() {\n // input\n int n, m; cin >> n >> m;\n int s, t; cin >> s >> t; -- s; -- t;\n int u, v; cin >> u >> v; -- u; -- v;\n vector<vector<pair<int, ll> > > g(n);\n REP (i, m) {\n int a, b; ll c; cin >> a >> b >> c; -- a; -- b;\n g[a].emplace_back(b, c);\n g[b].emplace_back(a, c);\n }\n\n // solve\n vector<ll> dist_s = dijkstra(g, s);\n vector<ll> dist_t = dijkstra(g, t);\n vector<ll> dist_u = dijkstra(g, u);\n vector<ll> dist_v = dijkstra(g, v);\n vector<int> order(n);\n iota(ALL(order), 0);\n sort(ALL(order), [&](int i, int j) { return dist_s[i] < dist_s[j]; });\n vector<ll> from_u(n, LLONG_MAX);\n vector<ll> from_v(n, LLONG_MAX);\n ll answer = dist_u[v];\n for (int i : order) {\n if (dist_s[i] + dist_t[i] == dist_s[t]) { // on a shortest path\n chmin(from_u[i], dist_u[i]);\n chmin(from_v[i], dist_v[i]);\n for (auto edge : g[i]) {\n int j; ll cost; tie(j, cost) = edge;\n if (dist_s[j] + cost == dist_s[i]) { // if a parent\n chmin(from_u[i], from_u[j]);\n chmin(from_v[i], from_v[j]);\n }\n }\n chmin(answer, from_u[i] + dist_v[i]);\n chmin(answer, from_v[i] + dist_u[i]);\n }\n }\n\n // output\n cout << answer << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 22908, "score_of_the_acc": -0.3174, "final_rank": 5 }, { "submission_id": "aoj_0650_9578727", "code_snippet": "#include <bits/stdc++.h>\n\n\n\n\nnamespace zawa {\n\nusing i16 = std::int16_t;\nusing i32 = std::int32_t;\nusing i64 = std::int64_t;\nusing i128 = __int128_t;\n\nusing u8 = std::uint8_t;\nusing u16 = std::uint16_t;\nusing u32 = std::uint32_t;\nusing u64 = std::uint64_t;\n\nusing usize = std::size_t;\n\n} // namespace zawa\n\n\nnamespace zawa {\n\nvoid SetFastIO() {\n std::cin.tie(nullptr)->sync_with_stdio(false);\n}\n\nvoid SetPrecision(u32 dig) {\n std::cout << std::fixed << std::setprecision(dig);\n}\n\n} // namespace zawa\n\n\n\nnamespace zawa {\n\nclass DisjointSetUnion {\npublic:\n DisjointSetUnion() = default;\n\n DisjointSetUnion(usize n) : n_{n}, data_(n, -1) {\n data_.shrink_to_fit();\n }\n \n u32 leader(u32 v) {\n return data_[v] < 0 ? v : static_cast<u32>(data_[v] = leader(data_[v]));\n }\n\n bool same(u32 u, u32 v) {\n return leader(u) == leader(v);\n }\n\n bool merge(u32 u, u32 v) {\n assert(u < n_);\n assert(v < n_);\n u = leader(u);\n v = leader(v);\n if (u == v) return false;\n if (data_[u] > data_[v]) std::swap(u, v);\n data_[u] += data_[v];\n data_[v] = u;\n return true;\n }\n\n inline usize size() const noexcept {\n return n_;\n }\n\n usize size(u32 v) {\n assert(v < n_);\n return static_cast<usize>(-data_[leader(v)]);\n }\n\n std::vector<std::vector<u32>> enumerate() {\n std::vector<std::vector<u32>> res(n_);\n for (u32 v{} ; v < n_ ; v++) {\n res[leader(v)].push_back(v);\n }\n res.erase(std::remove_if(res.begin(), res.end(),\n [](const auto& arr) -> bool { return arr.empty(); }), res.end());\n return res;\n }\n\nprivate:\n usize n_{};\n std::vector<i32> data_;\n};\n\n} // namespace zawa\nusing namespace zawa;\n\nconst long long INF{(long long)2e18};\nstd::vector<long long> dij(const std::vector<std::vector<std::pair<int, int>>>& g, int s) {\n assert(0 <= s and s < (int)g.size());\n std::vector<long long> res(g.size(), INF);\n using qt = std::pair<long long, int>;\n std::priority_queue<qt, std::vector<qt>, std::greater<qt>> que;\n res[s] = 0;\n que.push(std::pair{res[s], s});\n while (que.size()) {\n auto [d, v]{que.top()};\n que.pop();\n if (res[v] < d) continue;\n for (auto [x, w] : g[v]) if (res[x] > d + w) {\n res[x] = d + w;\n que.push(std::pair{res[x], x});\n }\n }\n return res;\n}\n\nint main() {\n SetFastIO();\n\n int N, M;\n std::cin >> N >> M;\n int S, T, U, V;\n std::cin >> S >> T >> U >> V;\n S--; T--; U--; V--;\n std::vector<int> A(M), B(M), C(M);\n std::vector<std::vector<std::pair<int, int>>> g(N);\n for (int i{} ; i < M ; i++) {\n std::cin >> A[i] >> B[i] >> C[i];\n A[i]--; B[i]--;\n g[A[i]].push_back(std::pair{ B[i], C[i] });\n g[B[i]].push_back(std::pair{ A[i], C[i] });\n }\n auto ST{dij(g, S)};\n std::vector<bool> ok(M);\n {\n std::vector<std::vector<std::pair<int, int>>> dag(N);\n for (int i{} ; i < M ; i++) {\n if (ST[A[i]] + C[i] == ST[B[i]]) {\n dag[B[i]].push_back(std::pair{ A[i], i });\n }\n if (ST[B[i]] + C[i] == ST[A[i]]) {\n dag[A[i]].push_back(std::pair{ B[i], i });\n }\n }\n std::vector<bool> vis(N);\n vis[T] = true;\n std::queue<int> que;\n que.push(T);\n while (que.size()) {\n int v{que.front()};\n que.pop();\n for (auto [x, i] : dag[v]) {\n ok[i] = true;\n if (!vis[x]) {\n vis[x] = true;\n que.push(x);\n }\n }\n }\n }\n //[N, 2N) -> S->T側\n //[2N, 3N) -> T->S側\n std::vector<std::vector<std::pair<int, int>>> g2(4 * N);\n for (int i{} ; i < N ; i++) {\n g2[i].push_back(std::pair{N + i, 0});\n g2[i].push_back(std::pair{N + N + i, 0});\n g2[N + i].push_back(std::pair{N + N + N + i, 0});\n g2[N + N + i].push_back(std::pair{N + N + N + i, 0});\n }\n for (int i{} ; i < M ; i++) {\n g2[A[i]].push_back(std::pair{B[i], C[i]});\n g2[B[i]].push_back(std::pair{A[i], C[i]});\n if (ok[i] and ST[A[i]] + C[i] == ST[B[i]]) {\n g2[N + A[i]].push_back(std::pair{N + B[i], 0});\n g2[N + N + B[i]].push_back(std::pair{N + N + A[i], 0});\n }\n if (ok[i] and ST[B[i]] + C[i] == ST[A[i]]) {\n g2[N + B[i]].push_back(std::pair{N + A[i], 0});\n g2[N + N + A[i]].push_back(std::pair{N + N + B[i], 0});\n }\n g2[N + N + N + A[i]].push_back(std::pair{N + N + N + B[i], C[i]});\n g2[N + N + N + B[i]].push_back(std::pair{N + N + N + A[i], C[i]});\n }\n auto UV{dij(g2, U)};\n std::cout << UV[N + N + N + V] << '\\n';\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 57244, "score_of_the_acc": -1.1549, "final_rank": 16 }, { "submission_id": "aoj_0650_9477315", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <climits>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define MOD 1000000007\n#define EPS 0.000000001\n#define HUGE_NUM 99999999999999999\n#define NUM 100001\n\nenum Type {\n from_S,\n from_T,\n from_U,\n from_V,\n};\n\nstruct Edge {\n int to;\n ll cost;\n Edge(int arg_to, ll arg_cost) : to(arg_to), cost(arg_cost) {}\n};\n\nstruct Info {\n int node_id;\n ll sum_cost;\n Info(int arg_node_id, ll arg_sum_cost) : node_id(arg_node_id), sum_cost(arg_sum_cost) {}\n bool operator<(const Info &arg) const {\n return sum_cost > arg.sum_cost;\n }\n};\n\nstruct Data {\n int node_id;\n ll dist;\n Data(int arg_node_id, ll arg_dist) : node_id(arg_node_id), dist(arg_dist) {}\n bool operator<(const Data &arg) const {\n return dist < arg.dist;\n }\n};\n\nint N, M, S, T, U, V;\nint start[4];\nvector<Edge> G[NUM];\nll min_dist[NUM][4], min_dist_from_U[NUM];\n\nvoid calc(Type type) {\n for (int i = 1; i <= N; i++) {\n min_dist[i][type] = HUGE_NUM;\n }\n min_dist[start[type]][type] = 0;\n\n priority_queue<Info> Q;\n Q.emplace(start[type], 0);\n\n while (!Q.empty()) {\n int current_node = Q.top().node_id;\n ll current_cost = Q.top().sum_cost;\n Q.pop();\n\n if (current_cost > min_dist[current_node][type]) continue;\n\n for (const auto &edge : G[current_node]) {\n int next_node = edge.to;\n ll next_cost = current_cost + edge.cost;\n\n if (min_dist[next_node][type] > next_cost) {\n min_dist[next_node][type] = next_cost;\n Q.emplace(next_node, next_cost);\n }\n }\n }\n}\n\nint main() {\n cin >> N >> M;\n cin >> S >> T;\n cin >> U >> V;\n\n start[from_S] = S;\n start[from_T] = T;\n start[from_U] = U;\n start[from_V] = V;\n\n for (int loop = 0; loop < M; loop++) {\n int from, to;\n ll cost;\n cin >> from >> to >> cost;\n G[from].emplace_back(to, cost);\n G[to].emplace_back(from, cost);\n }\n\n calc(from_S);\n calc(from_T);\n calc(from_U);\n calc(from_V);\n\n vector<Data> DATA;\n for (int i = 1; i <= N; i++) {\n DATA.emplace_back(i, min_dist[i][from_S]);\n }\n sort(DATA.begin(), DATA.end());\n\n ll ans = min_dist[V][from_U];\n for (int i = 1; i <= N; i++) {\n min_dist_from_U[i] = min_dist[i][from_U];\n }\n\n for (const auto &data : DATA) {\n int node_id = data.node_id;\n ans = min(ans, min_dist[node_id][from_U] + min_dist[node_id][from_V]);\n for (const auto &edge : G[node_id]) {\n int adj_node = edge.to;\n if (min_dist[node_id][from_S] + edge.cost + min_dist[adj_node][from_T] != min_dist[T][from_S]) continue;\n min_dist[adj_node][from_U] = min(min_dist[adj_node][from_U], min_dist[node_id][from_U]);\n }\n }\n\n for (const auto &data : DATA) {\n int node_id = data.node_id;\n ans = min(ans, min_dist[node_id][from_V] + min_dist_from_U[node_id]);\n for (const auto &edge : G[node_id]) {\n int adj_node = edge.to;\n if (min_dist[node_id][from_S] + edge.cost + min_dist[adj_node][from_T] != min_dist[T][from_S]) continue;\n min_dist[adj_node][from_V] = min(min_dist[adj_node][from_V], min_dist[node_id][from_V]);\n }\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 23688, "score_of_the_acc": -0.3566, "final_rank": 6 }, { "submission_id": "aoj_0650_9262474", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, int> pll;\nll INF = 1LL<<60;\nint n, m, s, t, u, v;\nll a, b, c, sd[100010], ud[100010], vd[100010];\nvector<pll> edge[100010];\npriority_queue<pll, vector<pll>, greater<pll> > pq;\n\nvoid dij(int now, ll *dist){\n for(int i=0;i<=n;i++) dist[i] = INF;\n dist[now] = 0;\n pq.push(pll(0, now));\n while(!pq.empty()){\n pll p = pq.top();\n pq.pop();\n for(int i=0;i<edge[p.second].size();i++){\n ll cst = p.first + edge[p.second][i].first;\n int nxt = edge[p.second][i].second;\n if(dist[nxt] > cst){\n dist[nxt] = cst;\n pq.push(pll(cst, nxt));\n }\n }\n }\n}\n\nvector<pll> vec;\nll dp[100010][5];\n\nint main(){\n \n cin >> n >> m >> s >> t >> u >> v;\n for(int i=0;i<m;i++){\n cin >> a >> b >> c;\n edge[a].push_back(pll(c, b));\n edge[b].push_back(pll(c, a));\n }\n \n dij(s, sd);\n dij(u, ud);\n dij(v, vd);\n \n for(int i=1;i<=n;i++) vec.push_back(pll(sd[i], i));\n sort(vec.begin(), vec.end());\n \n for(int i=0;i<=n;i++){\n for(int j=0;j<5;j++) dp[i][j] = INF;\n }\n dp[s][0] = ud[s];\n dp[s][1] = vd[s];\n dp[s][2] = ud[s] + vd[s];\n \n for(int i=0;i<vec.size();i++){\n int now = vec[i].second;\n for(int j=0;j<edge[now].size();j++){\n int pre = edge[now][j].second;\n if(sd[now] != sd[pre]+edge[now][j].first) continue;\n dp[now][0] = min(dp[now][0], min(dp[pre][0], ud[now]));\n dp[now][1] = min(dp[now][1], min(dp[pre][1], vd[now]));\n dp[now][2] = min(dp[now][2], min(dp[pre][2], ud[now]+vd[now]));\n dp[now][2] = min(dp[now][2], min(ud[now]+dp[pre][1], dp[pre][0]+vd[now]));\n }\n }\n \n cout << min(dp[t][2], ud[v]) << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 24532, "score_of_the_acc": -0.4667, "final_rank": 9 }, { "submission_id": "aoj_0650_9262466", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> pll;\nll INF = 1LL<<60;\nint n, m, s, t, u, v;\nll a, b, c, sd[100010], ud[100010], vd[100010];\nvector<pll> edge[100010];\n\nvoid dij(int now, ll *dist){\n for(int i=0;i<=n;i++) dist[i] = INF;\n dist[now] = 0;\n priority_queue<pll, vector<pll>, greater<pll> > pq;\n pq.push(pll(0, now));\n while(!pq.empty()){\n pll p = pq.top();\n pq.pop();\n for(int i=0;i<edge[p.second].size();i++){\n ll cst = p.first + edge[p.second][i].first;\n int nxt = edge[p.second][i].second;\n if(dist[nxt] > cst){\n dist[nxt] = cst;\n pq.push(pll(cst, nxt));\n }\n }\n }\n}\n\nvector<pll> vec;\nll dp[100010][5];\n\nint main(){\n \n cin >> n >> m >> s >> t >> u >> v;\n for(int i=0;i<m;i++){\n cin >> a >> b >> c;\n edge[a].push_back(pll(c, b));\n edge[b].push_back(pll(c, a));\n }\n \n dij(s, sd);\n dij(u, ud);\n dij(v, vd);\n \n for(int i=1;i<=n;i++) vec.push_back(pll(sd[i], i));\n sort(vec.begin(), vec.end());\n \n for(int i=0;i<=n;i++){\n for(int j=0;j<5;j++) dp[i][j] = INF;\n }\n dp[s][1] = ud[s];\n dp[s][2] = vd[s];\n dp[s][3] = ud[s] + vd[s];\n \n for(int i=0;i<vec.size();i++){\n int now = vec[i].second;\n for(int j=0;j<edge[now].size();j++){\n int pre = edge[now][j].second;\n if(sd[now] != sd[pre]+edge[now][j].first) continue;\n dp[now][1] = min(dp[now][1], min(dp[pre][1], ud[now]));\n dp[now][2] = min(dp[now][2], min(dp[pre][2], vd[now]));\n dp[now][3] = min(dp[now][3], dp[pre][3]);\n dp[now][3] = min(dp[now][3], dp[pre][1]+vd[now]);\n dp[now][3] = min(dp[now][3], ud[now]+dp[pre][2]);\n dp[now][3] = min(dp[now][3], ud[now]+vd[now]);\n }\n }\n \n cout << min(dp[t][3], ud[v]) << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 25444, "score_of_the_acc": -0.4853, "final_rank": 10 }, { "submission_id": "aoj_0650_9262463", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, int> pll;\nll INF = 1e18;\nint n, m, s, t, u, v;\nll a, b, c, dist[3][100010];\nvector<pll> edge[100010];\npriority_queue<pll, vector<pll>, greater<pll> > pq;\n\nvoid dij(int now, int num){\n for(int i=0;i<=n;i++) dist[num][i] = INF;\n dist[num][now] = 0;\n pq.push(pll(0, now));\n while(!pq.empty()){\n pll p = pq.top();\n pq.pop();\n for(int i=0;i<edge[p.second].size();i++){\n ll cst = p.first + edge[p.second][i].first;\n int nxt = edge[p.second][i].second;\n if(dist[num][nxt] > cst){\n dist[num][nxt] = cst;\n pq.push(pll(cst, nxt));\n }\n }\n }\n}\n\nvector<pll> vec;\nll dp[100010][3];\n\nint main(){\n \n cin >> n >> m >> s >> t >> u >> v;\n for(int i=0;i<m;i++){\n cin >> a >> b >> c;\n edge[a].push_back(pll(c, b));\n edge[b].push_back(pll(c, a));\n }\n \n dij(s, 0);\n dij(u, 1);\n dij(v, 2);\n \n for(int i=1;i<=n;i++) vec.push_back(pll(dist[0][i], i));\n sort(vec.begin(), vec.end());\n \n for(int i=0;i<=n;i++){\n for(int j=0;j<3;j++) dp[i][j] = INF;\n }\n dp[s][0] = dist[1][s];\n dp[s][1] = dist[2][s];\n dp[s][2] = dist[1][s] + dist[2][s];\n \n for(int i=0;i<vec.size();i++){\n int now = vec[i].second;\n for(int j=0;j<edge[now].size();j++){\n int pre = edge[now][j].second;\n if(dist[0][now] != dist[0][pre]+edge[now][j].first) continue;\n dp[now][0] = min(dp[now][0], min(dp[pre][0], dist[1][now]));\n dp[now][1] = min(dp[now][1], min(dp[pre][1], dist[2][now]));\n dp[now][2] = min(dp[now][2], min(dp[pre][2], dist[1][now]+dist[2][now]));\n dp[now][2] = min(dp[now][2], dist[1][now]+dp[pre][1]);\n dp[now][2] = min(dp[now][2], dp[pre][0]+dist[2][now]);\n }\n }\n \n cout << min(dp[t][2], dist[1][v]) << endl;\n \n return(0);\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 22908, "score_of_the_acc": -0.4337, "final_rank": 8 }, { "submission_id": "aoj_0650_9100718", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n, m;\n cin >> n >> m;\n int S, T, U, V;\n cin >> S >> T >> U >> V;\n S -= 1, T -= 1, U -= 1, V -= 1;\n vector<vector<pair<int, ll>>> g(n);\n for (int i = 0; i < m; i++) {\n int x, y, z;\n cin >> x >> y >> z;\n x -= 1, y -= 1;\n g[x].push_back({y, z});\n g[y].push_back({x, z});\n }\n using P = pair<ll, int>;\n priority_queue<P, vector<P>, greater<P>> pq;\n auto dik = [&](int x) -> vector<ll> {\n vector<ll> d(n, 1e18);\n d[x] = 0;\n pq.push({0, x});\n while (pq.size()) {\n auto p = pq.top();\n pq.pop();\n int s = p.second;\n if (d[s] != p.first) continue;\n for (auto to : g[s]) {\n ll cost = p.first + to.second;\n int t = to.first;\n if (d[t] > cost) {\n d[t] = cost;\n pq.push({cost, t});\n }\n }\n }\n return d;\n };\n vector<ll> fs = dik(S), ft = dik(T), fv = dik(V), fu = dik(U);\n ll res = fv[U];\n vector<int> idx(n);\n iota(idx.begin(), idx.end(), 0);\n sort(idx.begin(), idx.end(), [&](auto i, auto j) { return fs[i] < fs[j]; });\n for (int _ = 0; _ < 2; _++) {\n swap(U, V);\n swap(fu, fv);\n vector<ll> dp(n, 1e18);\n for (int i : idx) {\n if (fs[i] + ft[i] != fs[T]) continue;\n dp[i] = min(dp[i], fu[i]);\n res = min(res, dp[i] + fv[i]);\n for (auto to : g[i]) {\n dp[to.first] = min(dp[to.first], dp[i]);\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 21240, "score_of_the_acc": -0.144, "final_rank": 2 }, { "submission_id": "aoj_0650_7018567", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define REP(i, x) for(ll i = x - 1; i >= 0; i--)\n#define REP2(i, x) for(ll i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define emb emplace_back\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\ntemplate <typename T>\nbool chmax(T& a, const T& b) {\n\tif (a < b) {\n\t\ta = b; // aをbで更新\n\t\treturn true;\n\t}\n\treturn false;\n}\n// aよりもbが小さいならばaをbで更新する\n// (更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmin(T& a, const T& b) {\n\tif (a > b) {\n\t\ta = b; // aをbで更新\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\n//エラトステネスの篩\nvector<bool> isprime_format(ll n) {\n\tvector<bool> P(n + 1, 1); P[0] = P[1] = 1;\n\tfor (ll i = 2; i * i <= n; i++) {\n\t\tif (!P[i]) continue;\n\t\tfor (int j = i + i; j <= n; j += i) P[j] = false;\n\t}\n\treturn P;\n}\nvector<ll> prime_format(ll n) {\n\tvector<bool> P = isprime_format(n);\n\tvector<ll> ans;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (P[i]) ans.push_back(i);\n\t}\n\treturn ans;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++;\n\t\t//res += n % 10;\n\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\n\nconst int nCkMAX = 500000;\nll fac[nCkMAX], finv[nCkMAX], inv[nCkMAX];//n!、1/n!、1/n\n// テーブルを作る前処理\nvoid nCkinit(ll m) {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < nCkMAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % m;\n\t\tinv[i] = m - inv[m % i] * (m / i) % m;\n\t\tfinv[i] = finv[i - 1] * inv[i] % m;\n\t}\n}\n// 二項係数計算\nll nCk(ll n, ll k, ll m) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % m) % m;\n}\n//nが大きくてkが小さい時\n//nCkMAXはk+2まででOK\nll nCk2(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tres = res * finv[k] % m;\n\treturn res;\n}\n\n//xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n//1~6まで出したいときは\n//xorshift() % 6 + 1\nunsigned int xorshift() {\n\tstatic unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n\tunsigned int tt = (tx ^ (tx << 11));\n\ttx = ty; ty = tz; tz = tw;\n\treturn (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\n\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nchar ds[4] = { 'd', 'r', 'u', 'l' };\nchar dl[4] = { 'D', 'R', 'U', 'L' };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\n////////////////////////////////struct\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\t//ll c;\n\tll u;\n\tll v;\n\n\t//bool operator<(const status& rhs) const { return c < rhs.c; };\n\t//bool operator>(const status& rhs) const { return c > rhs.c; };\n\tbool operator<(const status& rhs) const { return u < rhs.u; };\n\tbool operator>(const status& rhs) const { return u > rhs.u; };\n};\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"YES\\n\"; }\n\telse { cout << \"NO\\n\"; }\n}\nstruct edge {\n\tll to; ll cost;\n};\n\n//O(ElogV)\n//typedef pair<ll, ll>P; //firstは最短距離、secondは頂点番号\n\n//dijkstra1 : UからとVから、全ての頂点へ行くときの最小コストを求める\nvector<vector<ll>> d(213456, vector<ll>(2, INF));//xからtまでのコストd[t][x], x: 0:u、1:v\nvector<edge> G[213456];//コスト\nvoid dijkstra1(ll s, ll uv) {\n\t//uv : sがuなら0、vなら1\n\tpriority_queue<P, vector<P>, greater<P> >que;\n\td[s][uv] = 0; que.push(P(0, s));\n\twhile (!que.empty()) {\n\t\tP p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d[v][uv] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\t\t\tif (d[e.to][uv] > d[v][uv] + e.cost) {\n\t\t\t\td[e.to][uv] = d[v][uv] + e.cost;\n\t\t\t\tque.push(P(d[e.to][uv], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\n//dijkstra2\n//sからtまでの最小コストでの経路を求めつつ、\n//sからある頂点aまでの経路の[Uとの距離が最小であるような]頂点とUの距離が最小となるような経路を選んだ時の{Uの距離,Vの距離}をuvcost[a][0]に格納\n//Vも同じ\n//それだけじゃ駄目であることがわかtt\n//ある経路のUまでの距離とVまでの距離の合計が最小になるやつもとろうuvcost[a][2]\n\nll d2[213456];//始点sから終点tまでのコストd[t]\n//uvcost[t][x](x 0:U, 1:V)=↓\n//sからtまでの[xとの距離が最も小さくなるような]経路において、{Uの距離,Vの距離}\nvector<vector<status>> uvcost(213456, vector<status>(3, { INF, INF }));\nvoid dijkstra2(ll s) {\n\t//greater<P>を指定→firstが小さい順\n\tpriority_queue<P, vector<P>, greater<P> >que;\n\tfill(d2, d2 + 213456, INF);//←TLE気を付ける\n\td2[s] = 0; que.push(P(0, s));\n\twhile (!que.empty()) {\n\t\tP p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d2[v] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\n\t\t\t//頂点e.toに来たのでそこのU,Vの距離を反映させる\n\t\t\tstatus su = uvcost[v][0], sv = uvcost[v][1], sm = uvcost[v][2];\n\t\t\tchmin(su.u, d[e.to][0]); chmin(su.v, d[e.to][1]);\n\t\t\tchmin(sv.u, d[e.to][0]); chmin(sv.v, d[e.to][1]);\n\t\t\tchmin(sm.u, d[e.to][0]); chmin(sm.v, d[e.to][1]);\n\n\t\t\tif (d2[e.to] == d2[v] + e.cost) {\n\t\t\t\tif (uvcost[e.to][0] > su) {\n\t\t\t\t\tuvcost[e.to][0] = su;\n\t\t\t\t}\n\t\t\t\tif (uvcost[e.to][1].v > sv.v || ((uvcost[e.to][1].v == sv.v)&&(uvcost[e.to][1].u > sv.u))) {\n\t\t\t\t\tuvcost[e.to][1] = sv;\n\t\t\t\t}\n\t\t\t\tif (uvcost[e.to][2].u + uvcost[e.to][2].v > sm.u + sm.v) {\n\t\t\t\t\tuvcost[e.to][2] = sm;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (d2[e.to] > d2[v] + e.cost) {\n\t\t\t\t//そもそもS-T間が最初の運賃じゃないといけない\n\t\t\t\tuvcost[e.to][0] = su; uvcost[e.to][1] = sv; uvcost[e.to][2] = sm;\n\t\t\t\td2[e.to] = d2[v] + e.cost;\n\t\t\t\tque.push(P(d2[e.to], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\t//priority_queue<ll, vector<ll>, greater<ll>> que;\n\t//priority_queue<P, vector<P>, greater<P>> que;\n\n\t//定期券\n\t//最初にUとV始点でdijkstra\n\t// 全ての地点のU(V)との距離を知る\n\t//Sからdijkstra\n\t// ある駅までの経路において、[Uまでの距離が最も小さかったもの]と、[V…]の2つを採用\n\t// Tにたどり着いたときに[U…]と[V…]のUとVからの距離の合計が小さいほうを取って答え\n\n\tll n, m; cin >> n >> m;\n\tll s, t; cin >> s >> t;\n\tll u, v; cin >> u >> v;\n\trep(i, m) {\n\t\tll a, b, c; cin >> a >> b >> c;\n\t\tG[a].push_back({ b,c });\n\t\tG[b].push_back({ a,c });\n\t}\n\tdijkstra1(u, 0); dijkstra1(v, 1);\n\n\trep(i, 3) {\n\t\tuvcost[s][i] = { d[s][0],d[s][1] };\n\t}\n\tdijkstra2(s);\n\n\tll mi = INF;\n\trep(i, 3) {\n\t\tchmin(mi, uvcost[t][i].u + uvcost[t][i].v);\n\t}\n\tcout << min( mi, d[v][0] ) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 54916, "score_of_the_acc": -0.875, "final_rank": 14 }, { "submission_id": "aoj_0650_7018566", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define REP(i, x) for(ll i = x - 1; i >= 0; i--)\n#define REP2(i, x) for(ll i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define emb emplace_back\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\ntemplate <typename T>\nbool chmax(T& a, const T& b) {\n\tif (a < b) {\n\t\ta = b; // aをbで更新\n\t\treturn true;\n\t}\n\treturn false;\n}\n// aよりもbが小さいならばaをbで更新する\n// (更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmin(T& a, const T& b) {\n\tif (a > b) {\n\t\ta = b; // aをbで更新\n\t\treturn true;\n\t}\n\treturn false;\n}\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\n//エラトステネスの篩\nvector<bool> isprime_format(ll n) {\n\tvector<bool> P(n + 1, 1); P[0] = P[1] = 1;\n\tfor (ll i = 2; i * i <= n; i++) {\n\t\tif (!P[i]) continue;\n\t\tfor (int j = i + i; j <= n; j += i) P[j] = false;\n\t}\n\treturn P;\n}\nvector<ll> prime_format(ll n) {\n\tvector<bool> P = isprime_format(n);\n\tvector<ll> ans;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (P[i]) ans.push_back(i);\n\t}\n\treturn ans;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++;\n\t\t//res += n % 10;\n\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\n\nconst int nCkMAX = 500000;\nll fac[nCkMAX], finv[nCkMAX], inv[nCkMAX];//n!、1/n!、1/n\n// テーブルを作る前処理\nvoid nCkinit(ll m) {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < nCkMAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % m;\n\t\tinv[i] = m - inv[m % i] * (m / i) % m;\n\t\tfinv[i] = finv[i - 1] * inv[i] % m;\n\t}\n}\n// 二項係数計算\nll nCk(ll n, ll k, ll m) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % m) % m;\n}\n//nが大きくてkが小さい時\n//nCkMAXはk+2まででOK\nll nCk2(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tres = res * finv[k] % m;\n\treturn res;\n}\n\n//xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n//1~6まで出したいときは\n//xorshift() % 6 + 1\nunsigned int xorshift() {\n\tstatic unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n\tunsigned int tt = (tx ^ (tx << 11));\n\ttx = ty; ty = tz; tz = tw;\n\treturn (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\n\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nchar ds[4] = { 'd', 'r', 'u', 'l' };\nchar dl[4] = { 'D', 'R', 'U', 'L' };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\n////////////////////////////////struct\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\t//ll c;\n\tll u;\n\tll v;\n\n\t//bool operator<(const status& rhs) const { return c < rhs.c; };\n\t//bool operator>(const status& rhs) const { return c > rhs.c; };\n\tbool operator<(const status& rhs) const { return u < rhs.u; };\n\tbool operator>(const status& rhs) const { return u > rhs.u; };\n};\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"YES\\n\"; }\n\telse { cout << \"NO\\n\"; }\n}\nstruct edge {\n\tll to; ll cost;\n};\n\n//O(ElogV)\n//typedef pair<ll, ll>P; //firstは最短距離、secondは頂点番号\n\n//dijkstra1 : UからとVから、全ての頂点へ行くときの最小コストを求める\nvector<vector<ll>> d(213456, vector<ll>(2, INF));//xからtまでのコストd[t][x], x: 0:u、1:v\nvector<edge> G[213456];//コスト\nvoid dijkstra1(ll s, ll uv) {\n\t//uv : sがuなら0、vなら1\n\tpriority_queue<P, vector<P>, greater<P> >que;\n\td[s][uv] = 0; que.push(P(0, s));\n\twhile (!que.empty()) {\n\t\tP p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d[v][uv] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\t\t\tif (d[e.to][uv] > d[v][uv] + e.cost) {\n\t\t\t\td[e.to][uv] = d[v][uv] + e.cost;\n\t\t\t\tque.push(P(d[e.to][uv], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\n//dijkstra2\n//sからtまでの最小コストでの経路を求めつつ、\n//sからある頂点aまでの経路の[Uとの距離が最小であるような]頂点とUの距離が最小となるような経路を選んだ時の{Uの距離,Vの距離}をuvcost[a][0]に格納\n//Vも同じ\n//それだけじゃ駄目であることがわかtt\n//ある経路のUまでの距離とVまでの距離の合計が最小になるやつもとろうuvcost[a][2]\n\nll d2[213456];//始点sから終点tまでのコストd[t]\n//uvcost[t][x](x 0:U, 1:V)=↓\n//sからtまでの[xとの距離が最も小さくなるような]経路において、{Uの距離,Vの距離}\nvector<vector<status>> uvcost(213456, vector<status>(3, { INF, INF }));\nvoid dijkstra2(ll s) {\n\t//greater<P>を指定→firstが小さい順\n\tpriority_queue<P, vector<P>, greater<P> >que;\n\tfill(d2, d2 + 213456, INF);//←TLE気を付ける\n\td2[s] = 0; que.push(P(0, s));\n\twhile (!que.empty()) {\n\t\tP p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d2[v] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\n\t\t\t//頂点e.toに来たのでそこのU,Vの距離を反映させる\n\t\t\tstatus su = uvcost[v][0], sv = uvcost[v][1], sm = uvcost[v][2];\n\t\t\tchmin(su.u, d[e.to][0]); chmin(su.v, d[e.to][1]);\n\t\t\tchmin(sv.u, d[e.to][0]); chmin(sv.v, d[e.to][1]);\n\t\t\tchmin(sm.u, d[e.to][0]); chmin(sm.v, d[e.to][1]);\n\n\t\t\tif (d2[e.to] == d2[v] + e.cost) {\n\t\t\t\tif (uvcost[e.to][0] > su) {\n\t\t\t\t\tuvcost[e.to][0] = su;\n\t\t\t\t}\n\t\t\t\tif (uvcost[e.to][1].v > sv.v || ((uvcost[e.to][1].v == sv.v)&&(uvcost[e.to][1].u > sv.u))) {\n\t\t\t\t\tuvcost[e.to][1] = sv;\n\t\t\t\t}\n\t\t\t\tif (uvcost[e.to][2].u + uvcost[e.to][2].u > sm.u + sm.v) {\n\t\t\t\t\tuvcost[e.to][2] = sm;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (d2[e.to] > d2[v] + e.cost) {\n\t\t\t\t//そもそもS-T間が最初の運賃じゃないといけない\n\t\t\t\tuvcost[e.to][0] = su; uvcost[e.to][1] = sv; uvcost[e.to][2] = sm;\n\t\t\t\td2[e.to] = d2[v] + e.cost;\n\t\t\t\tque.push(P(d2[e.to], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\t//priority_queue<ll, vector<ll>, greater<ll>> que;\n\t//priority_queue<P, vector<P>, greater<P>> que;\n\n\t//定期券\n\t//最初にUとV始点でdijkstra\n\t// 全ての地点のU(V)との距離を知る\n\t//Sからdijkstra\n\t// ある駅までの経路において、[Uまでの距離が最も小さかったもの]と、[V…]の2つを採用\n\t// Tにたどり着いたときに[U…]と[V…]のUとVからの距離の合計が小さいほうを取って答え\n\n\tll n, m; cin >> n >> m;\n\tll s, t; cin >> s >> t;\n\tll u, v; cin >> u >> v;\n\trep(i, m) {\n\t\tll a, b, c; cin >> a >> b >> c;\n\t\tG[a].push_back({ b,c });\n\t\tG[b].push_back({ a,c });\n\t}\n\tdijkstra1(u, 0); dijkstra1(v, 1);\n\n\trep(i, 3) {\n\t\tuvcost[s][i] = { d[s][0],d[s][1] };\n\t}\n\tdijkstra2(s);\n\n\tll mi = INF;\n\trep(i, 3) {\n\t\tchmin(mi, uvcost[t][i].u + uvcost[t][i].v);\n\t}\n\tcout << min( mi, d[v][0] ) << endl;\n\treturn 0;\n}", "accuracy": 0.9642857142857143, "time_ms": 170, "memory_kb": 54812, "score_of_the_acc": -0.8497, "final_rank": 17 }, { "submission_id": "aoj_0650_6995244", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0650.cc: 定期券(Commuter Pass)\n */\n\n#include<cstdio>\n#include<vector>\n#include<queue>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst long long LINF = 1LL << 62;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> pli;\ntypedef vector<pii> vpii;\n\n/* global variables */\n\nvpii nbrs[MAX_N];\nll ds[MAX_N], dbus[MAX_N], dbvs[MAX_N];\nll gds[MAX_N * 4];\nvi ps[MAX_N];\n\n/* subroutines */\n\nvoid dijkstra(int n, vpii nbrs[], ll ds[], int st, vi *ps = nullptr) {\n fill(ds, ds + n, LINF);\n ds[st] = 0;\n\n priority_queue<pli> q;\n q.push(pli(0, st));\n\n while (! q.empty()) {\n pli ue = q.top(); q.pop();\n ll ud = -ue.first;\n int u = ue.second;\n if (ds[u] != ud) continue;\n\n for (auto vw: nbrs[u]) {\n int v = vw.first;\n ll vd = ud + vw.second;\n if (ds[v] > vd) {\n\tds[v] = vd;\n\tif (ps != nullptr) ps[v].assign(1, u);\n\tq.push(pli(-vd, v));\n }\n else if (ds[v] == vd)\n\tif (ps != nullptr) ps[v].push_back(u);\n }\n }\n}\n\n/* main */\n\nint main() {\n int n, m, st, gl, bu, bv;\n scanf(\"%d%d%d%d%d%d\", &n, &m, &st, &gl, &bu, &bv);\n st--, gl--, bu--, bv--;\n\n for (int i = 0; i < m; i++) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n u--, v--;\n nbrs[u].push_back(pii(v, w));\n nbrs[v].push_back(pii(u, w));\n }\n\n dijkstra(n, nbrs, ds, st, ps);\n dijkstra(n, nbrs, dbus, bu);\n dijkstra(n, nbrs, dbvs, bv);\n\n fill(gds, gds + n * 4, LINF);\n gds[gl << 2] = 0;\n\n priority_queue<pli> q;\n q.push(pli(0, gl << 2));\n\n while (! q.empty()) {\n pli ue = q.top(); q.pop();\n ll ud = -ue.first;\n int ug = ue.second;\n if (gds[ug] != ud) continue;\n\n int u = ug >> 2, ub = ug & 3;\n\n if (! (ub & 1)) {\n int vg = (u << 2) | (ub | 1);\n ll vd = ud + dbus[u];\n if (gds[vg] > vd)\n\tgds[vg] = vd, q.push(pli(-vd, vg));\n }\n if (! (ub & 2)) {\n int vg = (u << 2) | (ub | 2);\n ll vd = ud + dbvs[u];\n if (gds[vg] > vd)\n\tgds[vg] = vd, q.push(pli(-vd, vg));\n }\n\n for (auto v: ps[u]) {\n int vg = (v << 2) | ub;\n if (gds[vg] > ud)\n\tgds[vg] = ud, q.push(pli(-ud, vg));\n }\n }\n\n ll mind = min(dbus[bv], gds[(st << 2) | 3]);\n printf(\"%lld\\n\", mind);\n\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 30596, "score_of_the_acc": -0.3807, "final_rank": 7 }, { "submission_id": "aoj_0650_5866712", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\n\nll ds[101010], dt[101010];\n\nll d[4][101010];\nvector<vector<pair<ll,ll>>> g(101010);\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int N, M; cin >> N >> M;\n int S, T; cin >> S >> T;\n int U, V; cin >> U >> V;\n S--; T--; U--; V--;\n REP(i,N) ds[i] = dt[i] = (1LL<<60);\n REP(i,M) {\n int a, b, c; cin >> a >> b >> c;\n a--; b--;\n g[a].push_back({b, c});\n g[b].push_back({a, c});\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, S});\n ds[S] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(ds[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(ds[u] > ds[v] + c) {\n ds[u] = ds[v] + c;\n pq.push({ds[u], u});\n }\n }\n }\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, T});\n dt[T] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(dt[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(dt[u] > dt[v] + c) {\n dt[u] = dt[v] + c;\n pq.push({dt[u], u});\n }\n }\n }\n }\n\n ll mi = ds[T];\n REP(i,N) d[0][i] = d[1][i] = d[2][i] = d[3][i] = (1LL<<60);\n d[0][U] = 0;\n\n priority_queue<pair<ll,pair<ll,ll>>, vector<pair<ll,pair<ll,ll>>>, greater<pair<ll,pair<ll,ll>>>> pq;\n pq.push({0, {0,U}});\n while(pq.size()) {\n \n auto[c, p] = pq.top(); pq.pop();\n auto[st, v] = p;\n if(d[st][v] < c) continue;\n for(auto[u, cost]: g[v]) {\n if(d[st][u] > d[st][v] + cost) {\n d[st][u] = d[st][v] + cost;\n pq.push({d[st][u], {st, u}});\n }\n\n if(st == 0 && (ds[v] + dt[u] + cost == mi || dt[v] + ds[u] + cost == mi)) {\n {\n queue<int> q; q.push(v);\n while(q.size()) {\n auto now = q.front(); q.pop();\n for(auto[nxt, cost2]: g[now]) {\n if(ds[now] + cost2 == ds[nxt] && (ds[now] + cost2 + dt[nxt] == mi || dt[now] + cost2 + ds[nxt] == mi) && d[1][nxt] > d[0][v]) {\n d[1][nxt] = d[0][v];\n pq.push({d[1][nxt], {1, nxt}});\n q.push(nxt);\n }\n }\n }\n } \n {\n queue<int> q; q.push(v);\n while(q.size()) {\n auto now = q.front(); q.pop();\n for(auto[nxt, cost2]: g[now]) {\n if(ds[now] - cost2 == ds[nxt] && (ds[now] + cost2 + dt[nxt] == mi || dt[now] + cost2 + ds[nxt] == mi) && d[2][nxt] > d[0][v]) {\n d[2][nxt] = d[0][v];\n pq.push({d[2][nxt], {2, nxt}});\n q.push(nxt);\n }\n }\n }\n }\n }\n \n }\n }\n \n cout << min({d[1][V], d[0][V], d[2][V]}) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 36440, "score_of_the_acc": -0.546, "final_rank": 11 }, { "submission_id": "aoj_0650_5866555", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\n\nll ds[101010], dt[101010];\n\nll d[2][101010];\nvector<vector<pair<ll,ll>>> g(101010);\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int N, M; cin >> N >> M;\n int S, T; cin >> S >> T;\n int U, V; cin >> U >> V;\n S--; T--; U--; V--;\n REP(i,N) ds[i] = dt[i] = (1LL<<60);\n REP(i,M) {\n int a, b, c; cin >> a >> b >> c;\n a--; b--;\n g[a].push_back({b, c});\n g[b].push_back({a, c});\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, S});\n ds[S] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(ds[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(ds[u] > ds[v] + c) {\n ds[u] = ds[v] + c;\n pq.push({ds[u], u});\n }\n }\n }\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, T});\n dt[T] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(dt[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(dt[u] > dt[v] + c) {\n dt[u] = dt[v] + c;\n pq.push({dt[u], u});\n }\n }\n }\n }\n\n ll mi = ds[T];\n REP(i,N) d[0][i] = d[1][i] = (1LL<<60);\n d[0][U] = 0;\n priority_queue<pair<ll,pair<ll,ll>>, vector<pair<ll,pair<ll,ll>>>, greater<pair<ll,pair<ll,ll>>>> pq;\n pq.push({0, {0,U}});\n while(pq.size()) {\n auto[c, p] = pq.top(); pq.pop();\n auto[st, v] = p;\n if(d[st][v] < c) continue;\n for(auto[u, cost]: g[v]) {\n if(d[st][u] > d[st][v] + cost) {\n d[st][u] = d[st][v] + cost;\n pq.push({d[st][u], {st, u}});\n }\n\n if(st == 0 && (ds[v] + dt[u] + cost == mi || dt[v] + ds[u] + cost == mi)) {\n \n if(ds[v] < ds[u]) {\n \n if(d[1][u] > d[0][v]) {\n d[1][u] = d[0][v];\n pq.push({d[1][u],{1,u}});\n }\n {\n int now = u;\n bool update = true;\n while(now != T && update) {\n update = false;\n for(auto [nxt, cost2]: g[now]) {\n if(ds[now] + cost2 == ds[nxt] && ds[now] + dt[nxt] + cost2 == mi && d[1][nxt] > d[0][v]) {\n d[1][nxt] = d[0][v];\n pq.push({d[1][nxt], {1, nxt}});\n now = nxt;\n update = true;\n break;\n }\n }\n }\n }\n {\n int now = v;\n bool update = true;\n while(now != S && update) {\n update = false;\n for(auto [nxt, cost2]: g[now]) {\n if(ds[now] - cost2 == ds[nxt] && ds[now] + dt[nxt] + cost2 == mi && d[1][nxt] > d[0][v]) {\n d[1][nxt] = d[0][v];\n pq.push({d[1][nxt], {1, nxt}});\n now = nxt;\n update = true;\n break;\n }\n }\n }\n }\n }else{\n if(d[1][u] > d[0][v]) {\n d[1][u] = d[0][v];\n pq.push({d[1][u],{1,u}});\n }\n {\n int now = u;\n bool update = true;\n while(now != T && update) {\n update = false;\n for(auto [nxt, cost2]: g[now]) {\n if(ds[now] - cost2 == ds[nxt]&& ds[now] + dt[nxt] + cost2 == mi && d[1][nxt] > d[0][v]) {\n d[1][nxt] = d[0][v];\n pq.push({d[1][nxt], {1, nxt}});\n now = nxt;\n update = true;\n break;\n }\n }\n }\n }\n {\n int now = v;\n bool update = true;\n while(now != S && update) {\n update = false;\n for(auto [nxt, cost2]: g[now]) {\n if(ds[now] + cost2 == ds[nxt]&& ds[now] + dt[nxt] + cost2 == mi && d[1][nxt] > d[0][v]) {\n d[1][nxt] = d[0][v];\n pq.push({d[1][nxt], {1, nxt}});\n now = nxt;\n update = true;\n break;\n }\n }\n }\n }\n }\n }\n \n }\n }\n \n cout << min({d[1][V], d[0][V]}) << endl;\n return 0;\n}", "accuracy": 0.19642857142857142, "time_ms": 150, "memory_kb": 29924, "score_of_the_acc": -0.2973, "final_rank": 20 }, { "submission_id": "aoj_0650_5866496", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\nusing namespace std;\n \ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<int, int> pii;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\n \ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned long long ull;\n \n \n#define FOR(i, s, n) for (int i = s; i < (int)n; ++i)\n#define REP(i, n) FOR(i, 0, n)\n#define rep(i, a, b) for (int i = a; i < (b); ++i)\n#define trav(a, x) for (auto &a : x)\n#define all(x) x.begin(), x.end()\n \n#define MOD 1000000007\n \ntemplate<class T1, class T2> inline bool chmax(T1 &a, T2 b) {if (a < b) {a = b; return true;} return false;}\ntemplate<class T1, class T2> inline bool chmin(T1 &a, T2 b) {if (a > b) {a = b; return true;} return false;}\nconst double EPS = 1e-8, PI = acos(-1);\nconst double pi = 3.141592653589793238462643383279;\n//ここから編集 \ntypedef string::const_iterator State;\nll GCD(ll a, ll b){\n return (b==0)?a:GCD(b, a%b);\n}\nll LCM(ll a, ll b){\n return a/GCD(a, b) * b;\n}\ntemplate< int mod >\nstruct ModInt {\n int x;\n \n ModInt() : x(0) {}\n \n ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n \n ModInt &operator+=(const ModInt &p) {\n if((x += p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator-=(const ModInt &p) {\n if((x += mod - p.x) >= mod) x -= mod;\n return *this;\n }\n \n ModInt &operator*=(const ModInt &p) {\n x = (int) (1LL * x * p.x % mod);\n return *this;\n }\n \n ModInt &operator/=(const ModInt &p) {\n *this *= p.inverse();\n return *this;\n }\n \n ModInt operator-() const { return ModInt(-x); }\n \n ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n \n ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n \n ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n \n ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n \n bool operator==(const ModInt &p) const { return x == p.x; }\n \n bool operator!=(const ModInt &p) const { return x != p.x; }\n \n ModInt inverse() const {\n int a = x, b = mod, u = 1, v = 0, t;\n while(b > 0) {\n t = a / b;\n swap(a -= t * b, b);\n swap(u -= t * v, v);\n }\n return ModInt(u);\n }\n \n ModInt pow(int64_t n) const {\n ModInt ret(1), mul(x);\n while(n > 0) {\n if(n & 1) ret *= mul;\n mul *= mul;\n n >>= 1;\n }\n return ret;\n }\n \n friend ostream &operator<<(ostream &os, const ModInt &p) {\n return os << p.x;\n }\n \n friend istream &operator>>(istream &is, ModInt &a) {\n int64_t t;\n is >> t;\n a = ModInt< mod >(t);\n return (is);\n }\n \n static int get_mod() { return mod; }\n};\n \nusing modint = ModInt< 1000000007 >;\ntemplate< typename T >\nstruct Combination {\n vector< T > _fact, _rfact, _inv;\n \n Combination(int sz) : _fact(sz + 1), _rfact(sz + 1), _inv(sz + 1) {\n _fact[0] = _rfact[sz] = _inv[0] = 1;\n for(int i = 1; i <= sz; i++) _fact[i] = _fact[i - 1] * i;\n _rfact[sz] /= _fact[sz];\n for(int i = sz - 1; i >= 0; i--) _rfact[i] = _rfact[i + 1] * (i + 1);\n for(int i = 1; i <= sz; i++) _inv[i] = _rfact[i] * _fact[i - 1];\n }\n \n inline T fact(int k) const { return _fact[k]; }\n \n inline T rfact(int k) const { return _rfact[k]; }\n \n inline T inv(int k) const { return _inv[k]; }\n \n T P(int n, int r) const {\n if(r < 0 || n < r) return 0;\n return fact(n) * rfact(n - r);\n }\n \n T C(int p, int q) const {\n if(q < 0 || p < q) return 0;\n return fact(p) * rfact(q) * rfact(p - q);\n }\n \n T H(int n, int r) const {\n if(n < 0 || r < 0) return (0);\n return r == 0 ? 1 : C(n + r - 1, r);\n }\n};\n \nll modpow(ll x, ll n, ll mod) {\n ll res = 1;\n while(n) {\n if(n&1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n} \ninline long long mod(long long a, long long m) {\n return (a % m + m) % m;\n}\ntemplate<typename T> \nstruct BIT{\n int N;\n std::vector<T> node;\n\n BIT(int n){\n N = n;\n node.resize(N+10);\n }\n\n /* a: 1-indexed */\n void add(int a, T x){\n for(int i=a; i<(int)node.size(); i += i & -i) node[i] += x;\n }\n\n /* [1, a] */\n T sum(int a){\n T res = 0;\n for(int x=a; x>0; x -= x & -x) res += node[x];\n return res;\n }\n\n /* [l, r] */\n T rangesum(int l, int r){\n return sum(r) - sum(l-1);\n }\n\n /* \n a1+a2+...+aw >= valとなるような最小のwを返す\n @verify https://codeforces.com/contest/992/problem/E\n */\n int lower_bound(T val) {\n if(val < 0) return 0;\n\n int res = 0;\n int n = 1; \n while (n < N) n *= 2;\n\n T tv=0;\n for (int k = n; k > 0; k /= 2) {\n if(res + k < N && node[res + k] < val){\n val -= node[res+k];\n res += k;\n }\n }\n return res+1; \n }\n};\nstruct UnionFind{\n std::vector<int> par;\n std::vector<int> siz;\n\n UnionFind(int sz_): par(sz_), siz(sz_) {\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n void init(int sz_){\n par.resize(sz_);\n siz.resize(sz_);\n for(int i=0; i<sz_; ++i) par[i] = i, siz[i] = 1;\n }\n\n int root(int x){\n if(x == par[x]) return x;\n return par[x] = root(par[x]);\n }\n\n bool merge(int x, int y){\n x = root(x), y = root(y);\n if(x == y) return false;\n if(siz[x] < siz[y]) std::swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(int x, int y){\n return root(x) == root(y);\n }\n\n int size(int x){\n return siz[root(x)];\n }\n};\nstruct RollingHash{\n\n using ull = unsigned long long;\n const ull mod = (1ULL << 61) - 1;\n const ull MASK30 = (1ULL << 30) - 1;\n const ull MASK31 = (1ULL << 31) - 1;\n\n const ull MASK61 = mod;\n\n ull base;\n int n;\n vector<ull> hash, pow;\n\n RollingHash(const string &s)\n {\n random_device rnd;\n mt19937_64 mt(rnd());\n base = calc_mod(mt()) % 100000 + 1000;\n \n n = (int)s.size();\n hash.assign(n+1, 0);\n pow.assign(n+1, 1);\n \n for(int i=0; i<n; i++){\n hash[i+1] = calc_mod(mul(hash[i], base) + s[i]);\n pow[i+1] = calc_mod(mul(pow[i], base));\n }\n }\n\n ull calc_mod(ull x){\n ull xu = x >> 61;\n ull xd = x & MASK61;\n ull res = xu + xd;\n if(res >= mod) res -= mod;\n return res;\n }\n\n ull mul(ull a, ull b){\n ull au = a >> 31;\n ull ad = a & MASK31;\n ull bu = b >> 31;\n ull bd = b & MASK31;\n ull mid = ad * bu + au * bd;\n ull midu = mid >> 30;\n ull midd = mid & MASK30;\n return calc_mod(au * bu * 2 + midu + (midd << 31) + ad * bd);\n }\n\n //[l,r)のハッシュ値\n inline ull get(int l, int r){\n ull res = calc_mod(hash[r] + mod*3-mul(hash[l], pow[r-l]));\n return res;\n }\n //string tのハッシュ値\n inline ull get(string t){\n ull res = 0;\n for(int i=0; i<t.size(); i++){\n res = calc_mod(mul(res, base)+t[i]);\n }\n return res;\n }\n //string s中のtの数をカウント\n inline int count(string t) {\n if(t.size() > n) return 0;\n auto hs = get(t);\n int res = 0;\n for(int i=0; i<n-t.size()+1; i++){\n if(get(i, i+t.size()) == hs) res++; \n }\n return res;\n }\n\n /* \n concat \n @verify https://codeforces.com/problemset/problem/514/C\n */\n inline ull concat(ull h1, ull h2, int h2len){\n return calc_mod(h2 + mul(h1, pow[h2len]));\n }\n\n // LCPを求める S[a:] T[b:]\n inline int LCP(int a, int b){\n int len = min((int)hash.size()-a, (int)hash.size()-b);\n \n int lb = -1, ub = len;\n while(ub-lb>1){\n int mid = (lb+ub)/2;\n\n if(get(a, a+mid) == get(b, b+mid)) lb = mid;\n else ub = mid;\n }\n return lb;\n }\n};\n\nll ds[101010], dt[101010];\n\nll d[3][101010];\nvector<vector<pair<ll,ll>>> g(101010);\nint main() { \n cin.tie(0);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(12);\n\n int N, M; cin >> N >> M;\n int S, T; cin >> S >> T;\n int U, V; cin >> U >> V;\n S--; T--; U--; V--;\n REP(i,N) ds[i] = dt[i] = (1LL<<60);\n REP(i,M) {\n int a, b, c; cin >> a >> b >> c;\n a--; b--;\n g[a].push_back({b, c});\n g[b].push_back({a, c});\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, S});\n ds[S] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(ds[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(ds[u] > ds[v] + c) {\n ds[u] = ds[v] + c;\n pq.push({ds[u], u});\n }\n }\n }\n }\n {\n priority_queue<pair<ll,ll>, vector<pair<ll,ll>>, greater<pair<ll,ll>>> pq;\n pq.push({0, T});\n dt[T] = 0;\n while(pq.size()) {\n auto[cost, v] = pq.top(); pq.pop();\n if(dt[v] < cost) continue;\n for(auto[u, c]: g[v]) {\n if(dt[u] > dt[v] + c) {\n dt[u] = dt[v] + c;\n pq.push({dt[u], u});\n }\n }\n }\n }\n\n ll mi = ds[T];\n REP(i,N) d[0][i] = d[1][i] = d[2][i] = (1LL<<60);\n d[0][U] = 0;\n priority_queue<pair<ll, pair<int, int>>, vector<pair<ll, pair<int, int>>>, greater<pair<ll, pair<int, int>>>> pq;\n pq.push({0, {0, U}});\n while(pq.size()) {\n auto[c, p] = pq.top(); pq.pop();\n auto[st, v] = p;\n if(d[st][v] < c) continue;\n for(auto [u, cost]: g[v]) {\n if(ds[v] + dt[u] + cost == mi || dt[v] + ds[u] + cost == mi) {\n if(st == 0) {\n cost = 0;\n int nxt = st;\n if(ds[v] < ds[u]) nxt = 1;\n else nxt = 2;\n if(d[nxt][u] > d[st][v] + cost) {\n d[nxt][u] = d[st][v] + cost;\n pq.push({d[nxt][u], {nxt, u}});\n }\n }else if(st == 1){\n if(ds[v] < ds[u]) cost = 0;\n if(d[st][u] > d[st][v] + cost) {\n d[st][u] = d[st][v] + cost;\n pq.push({d[st][u], {st, u}});\n }\n }else if(st == 2) {\n if(ds[v] > ds[u]) cost = 0;\n if(d[st][u] > d[st][v] + cost) {\n d[st][u] = d[st][v] + cost;\n pq.push({d[st][u], {st, u}});\n }\n }\n }else{\n if(d[st][u] > d[st][v] + cost) {\n d[st][u] = d[st][v] + cost;\n pq.push({d[st][u], {st, u}});\n }\n }\n }\n }\n cout << min({d[0][V], d[1][V], d[2][V]}) << endl;\n return 0;\n}", "accuracy": 0.625, "time_ms": 190, "memory_kb": 26488, "score_of_the_acc": -0.3204, "final_rank": 18 }, { "submission_id": "aoj_0650_5027158", "code_snippet": "#include <bits/stdc++.h>\n#pragma GCC optimize(\"O2\")\nusing namespace std;\nusing ll = long long int;\n#define F first\n#define S second\n#define fast_io ios::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);\nconst int N=1e5+10,LN=20,SQ=550,M=5e4+10;\nconst ll INF=1e18;\nconst int MOD=1000000007 /*998244353*/;\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\nusing pll=pair<ll,ll>;\nusing pii=pair<int,int>;\n#define ordered_set tree<pair<pll,ll>, null_type,less<pair<pll,ll>>, rb_tree_tag,tree_order_statistics_node_update>\nll pow(ll x, ll y, ll mod){\n ll ans=1;\n while (y != 0) {\n if (y & 1) ans = ans * x % mod;\n y >>= 1;\n x = x * x % mod;\n }\n return ans;\n}\nll n,m,S,T,U,V,dp[2][N],du[4][N],ans=INF;\nvector<pii> adj[N];\nvector<int> in[N],out[N];\nbitset<N> fl,sp;\nvoid dfs(ll v){\n fl[v]=1;\n for(ll u : out[v]){\n if(!fl[u]) dfs(u);\n dp[0][v]=min(dp[0][v],dp[0][u]);\n }\n}\nvoid sfd(ll v){\n fl[v]=1;\n for(ll u : in[v]){\n if(!fl[u]) sfd(u);\n dp[1][v]=min(dp[1][v],dp[1][u]);\n }\n}\nvoid di(ll x, ll t){\n priority_queue<pair<ll,int>> q;\n q.push({0,x});\n du[t][x]=0;\n while(!q.empty()){\n ll v=q.top().S;\n q.pop();\n for(pll p : adj[v]){\n if(du[t][p.F]<=du[t][v]+p.S) continue;\n du[t][p.F]=du[t][v]+p.S;\n q.push({-du[t][p.F],p.F});\n }\n }\n}\nint main(){\n fast_io;\n memset(du,127,sizeof du);\n cin >> n >> m >> S >> T >> U >> V;\n for(ll i=0; i<m; i++){\n ll v,u,c;\n cin >> v >> u >> c;\n adj[v].emplace_back(u,c);\n adj[u].emplace_back(v,c);\n }\n di(S,0);\n di(T,1);\n di(U,2);\n di(V,3);\n for(ll i=1; i<=n; i++) dp[0][i]=dp[1][i]=du[3][i];\n for(ll i=1; i<=n; i++){\n if(du[0][i]+du[1][i]==du[0][T]) sp[i]=1;\n for(pll p : adj[i]){\n if(du[0][i]+p.S+du[1][p.F]==du[0][T]) out[i].push_back(p.F),in[p.F].push_back(i);\n }\n }\n for(ll i=1; i<=n; i++) if(sp[i] && !fl[i]) dfs(i);\n fl=0;\n for(ll i=1; i<=n; i++) if(sp[i] && !fl[i]) sfd(i);\n for(ll i=1; i<=n; i++) if(sp[i]) ans=min(ans,min(dp[0][i],dp[1][i])+du[2][i]);\n cout << min(ans,du[2][V]) << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 27384, "score_of_the_acc": -0.2224, "final_rank": 4 }, { "submission_id": "aoj_0650_5027133", "code_snippet": "#include <bits/stdc++.h>\n \nusing namespace std;\n\ntypedef long long int ll;\ntypedef pair<int, int> pii;\n \n#define SZ(x) (int) x.size()\n#define F first\n#define S second\n\nconst int N = 2e5 + 10, MOD = 1e9 + 7;\nll dist[4][N], dp[2][N], M[N], X[N], n, m, R = 1e18, B, E, U, V;\nvector<pii> adj[N]; vector<int> out[N], in[N];\n\nvoid dijk(int S, int t) {\n\tfill(dist[t], dist[t] + N, 1e18);\n\tdist[t][S] = 0;\n\tpriority_queue<pair<ll, int>> pq;\n\tpq.push({dist[t][S], S});\n\twhile (SZ(pq)) {\n\t\tint v = pq.top().S; pq.pop();\n\t\tfor (pii u : adj[v]) {\n\t\t\tif (dist[t][u.F] > dist[t][v] + u.S) {\n\t\t\t\tdist[t][u.F] = dist[t][v] + u.S;\n\t\t\t\tpq.push({-dist[t][u.F], u.F});\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid add_edge(int u, int v) {\n\tout[u].push_back(v);\n\tin[v].push_back(u);\n}\n\nvoid DFS(int v) {\n\tM[v] = 1;\n\tfor (int u : out[v]) {\n\t\tif (!M[u]) DFS(u);\n\t\tdp[0][v] = min(dp[0][v], dp[0][u]);\n\t}\n}\n\nvoid SFD(int v) {\n\tM[v] = 1;\n\tfor (int u : in[v]) {\n\t\tif (!M[u]) SFD(u);\n\t\tdp[1][v] = min(dp[1][v], dp[1][u]);\n\t}\n}\n\nint main() {\n\tscanf(\"%lld%lld%lld%lld%lld%lld\", &n, &m, &B, &E, &U, &V);\n\tfor (int i = 1; i <= m; i++) {\n\t\tint u, v, w; scanf(\"%d%d%d\", &u, &v, &w);\n\t\tadj[u].push_back({v, w});\n\t\tadj[v].push_back({u, w});\n\t}\n\tdijk(B, 0);\n\tdijk(E, 1);\n\tdijk(U, 2);\n\tdijk(V, 3);\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (dist[0][i] + dist[1][i] == dist[0][E]) X[i] = 1;\n\t\tfor (pii u : adj[i]) {\n\t\t\tif (dist[0][i] + u.S + dist[1][u.F] == dist[0][E]) {\n\t\t\t\tadd_edge(i, u.F);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tdp[0][i] = dp[1][i] = dist[3][i];\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (X[i] && !M[i]) DFS(i);\n\t}\n\tfill(M, M + N, 0);\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (X[i] && !M[i]) SFD(i);\n\t}/*\n\tfor (int i = 1; i <= n; i++) {\n printf(\"%lld %lld\\n\", dp[0][i], dp[1][i]);\n }*/\n\tfor (int i = 1; i <= n; i++) {\n\t\tif (X[i]) {\n\t\t\tR = min(R, min(dp[0][i], dp[1][i]) + dist[2][i]);\n\t\t}\n\t}\n\tprintf(\"%lld\\n\", min(R, dist[2][V]));\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 42288, "score_of_the_acc": -0.5718, "final_rank": 12 }, { "submission_id": "aoj_0650_4413244", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <functional>\n#include <queue>\n#include <set>\n#include <map>\n#include <vector>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nstruct Node {\n int u;\n ll step;\n\n Node(int u, ll step) : u(u), step(step) {}\n\n bool operator>(const Node& rhs) const { return step > rhs.step; }\n};\n\nstruct Edge {\n int v, w;\n Edge* next;\n};\n\nconst int N = 100010, M = 200010;\n\nint n, m;\nint s, t, a, b;\nll ans;\nEdge* g[N];\nbool vis[N];\nll diss[N], disa[N], disb[N], da[N], db[N];\n\nvoid adde(int u, int v, int w);\nvoid runspt(int s, ll* dis);\nvoid dfs(int u);\n\nint main() {\n scanf(\"%d%d%d%d%d%d\", &n, &m, &s, &t, &a, &b);\n while (m--) {\n int u, v, w;\n scanf(\"%d%d%d\", &u, &v, &w);\n adde(u, v, w);\n adde(v, u, w);\n }\n runspt(a, disa);\n ans = disa[b];\n if (disa[s] != -1) {\n runspt(b, disb);\n runspt(s, diss);\n dfs(t);\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}\n\nvoid dfs(int u) {\n if (vis[u])\n return;\n vis[u] = true;\n da[u] = disa[u];\n db[u] = disb[u];\n for (Edge* p = g[u]; p; p = p->next)\n if (diss[p->v] + p->w == diss[u]) {\n dfs(p->v);\n da[u] = min(da[u], da[p->v]);\n db[u] = min(db[u], db[p->v]);\n }\n ans = min(ans, min(da[u] + disb[u], db[u] + disa[u]));\n}\n\nvoid runspt(int s, ll* dis) {\n memset(dis, -1, sizeof(ll) * (n + 1));\n priority_queue<Node, vector<Node>, greater<Node>> q;\n q.emplace(s, dis[s] = 0);\n while (!q.empty()) {\n Node tmp = q.top();\n q.pop();\n if (tmp.step != dis[tmp.u])\n continue;\n for (Edge* p = g[tmp.u]; p; p = p->next)\n if (dis[p->v] == -1 || dis[p->v] > tmp.step + p->w)\n q.emplace(p->v, dis[p->v] = tmp.step + p->w);\n }\n}\n\nvoid adde(int u, int v, int w) {\n static Edge pool[M * 2];\n static Edge* p = pool;\n p->v = v;\n p->w = w;\n p->next = g[u];\n g[u] = p;\n ++p;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 16444, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0650_4267269", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <functional>\n#include <algorithm>\nusing namespace std;\n\nlong long N, M, S, T, U, V, A[1 << 18], B[1 << 18], C[1 << 18], dist[1 << 18], dp1[1 << 18], dp2[1 << 18];\nlong long dista[1 << 18], distb[1 << 18], distc[1 << 18], distd[1 << 18];\nvector<pair<long long, long long>>X[1 << 18];\nint Order[1 << 18];\n\nvector<long long>getdist(int pos) {\n\tpriority_queue<pair<long long, long long>, vector<pair<long long, long long>>, greater<pair<long long, long long>>>Q;\n\tfor (int i = 1; i <= N; i++) dist[i] = (1LL << 60);\n\tQ.push(make_pair(0, pos)); dist[pos] = 0;\n\n\twhile (!Q.empty()) {\n\t\tint pos = Q.top().second; long long cost = Q.top().first; Q.pop();\n\t\tfor (int i = 0; i < X[pos].size(); i++) {\n\t\t\tint to = X[pos][i].first; long long tm = X[pos][i].second;\n\t\t\tif (dist[to] > cost + tm) {\n\t\t\t\tdist[to] = cost + tm;\n\t\t\t\tQ.push(make_pair(dist[to], to));\n\t\t\t}\n\t\t}\n\t}\n\tvector<long long>E;\n\tfor (int i = 1; i <= N; i++) E.push_back(dist[i]);\n\treturn E;\n}\n\nint main() {\n\tcin >> N >> M >> S >> T >> U >> V;\n\tfor (int i = 0; i < M; i++) {\n\t\tcin >> A[i] >> B[i] >> C[i];\n\t\tX[A[i]].push_back(make_pair(B[i], C[i]));\n\t\tX[B[i]].push_back(make_pair(A[i], C[i]));\n\t}\n\tvector<long long>A1 = getdist(S); for (int i = 1; i <= N; i++) dista[i] = A1[i - 1];\n\tvector<long long>A2 = getdist(T); for (int i = 1; i <= N; i++) distb[i] = A2[i - 1];\n\tvector<long long>A3 = getdist(U); for (int i = 1; i <= N; i++) distc[i] = A3[i - 1];\n\tvector<long long>A4 = getdist(V); for (int i = 1; i <= N; i++) distd[i] = A4[i - 1];\n\n\tvector<pair<long long, long long>>vec1;\n\tfor (int i = 1; i <= N; i++) { if (dista[i] + distb[i] == dista[T]) vec1.push_back(make_pair(dista[i], i)); }\n\tsort(vec1.begin(), vec1.end());\n\n\tfor (int i = 1; i <= N; i++) { dp1[i] = (1LL << 60); dp2[i] = (1LL << 60); Order[i] = -1; }\n\tfor (int i = 0; i < vec1.size(); i++) Order[vec1[i].second] = i;\n\n\tfor (int i = 0; i < vec1.size(); i++) {\n\t\tint pos = vec1[i].second; dp1[pos] = min(dp1[pos], distc[pos]);\n\t\tfor (int j = 0; j < X[pos].size(); j++) {\n\t\t\tif (Order[X[pos][j].first] != -1 && Order[X[pos][j].first] > i) {\n\t\t\t\tdp1[X[pos][j].first] = min(dp1[X[pos][j].first], dp1[pos]);\n\t\t\t}\n\t\t}\n\t}\n\tfor (int i = vec1.size() - 1; i >= 0; i--) {\n\t\tint pos = vec1[i].second; dp2[pos] = min(dp2[pos], distc[pos]);\n\t\tfor (int j = 0; j < X[pos].size(); j++) {\n\t\t\tif (Order[X[pos][j].first] != -1 && Order[X[pos][j].first] < i) {\n\t\t\t\tdp2[X[pos][j].first] = min(dp2[X[pos][j].first], dp2[pos]);\n\t\t\t}\n\t\t}\n\t}\n\n\tlong long ans = distc[V];\n\tfor (int i = 1; i <= N; i++) ans = min(ans, min(dp1[i], dp2[i]) + distd[i]);\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 36596, "score_of_the_acc": -0.805, "final_rank": 13 }, { "submission_id": "aoj_0650_4168564", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <numeric>\n#include <vector>\n#include <queue>\n#include <tuple>\n\ntemplate <class T>\nusing MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;\n\nusing lint = long long;\nconstexpr lint INF = 1LL << 50;\n\nstruct Edge {\n int dst;\n lint cost;\n explicit Edge(int dst, lint cost) : dst(dst), cost(cost) {}\n};\n\nusing Graph = std::vector<std::vector<Edge>>;\n\nstd::vector<lint> dijkstra(const Graph& graph, int r) {\n std::vector<lint> dist(graph.size(), INF);\n dist[r] = 0;\n MinHeap<std::pair<lint, int>> que;\n que.emplace(dist[r], r);\n\n while (!que.empty()) {\n lint d;\n int v;\n std::tie(d, v) = que.top();\n que.pop();\n if (dist[v] < d) continue;\n\n for (auto e : graph[v]) {\n int u = e.dst;\n lint nd = d + e.cost;\n if (dist[u] > nd) {\n dist[u] = nd;\n que.emplace(nd, u);\n }\n }\n }\n\n return dist;\n}\n\nvoid solve() {\n int n, m, s, t, a, b;\n std::cin >> n >> m >> s >> t >> a >> b;\n --s, --t, --a, --b;\n\n Graph graph(n);\n while (m--) {\n int u, v;\n lint c;\n std::cin >> u >> v >> c;\n --u, --v;\n graph[u].emplace_back(v, c);\n graph[v].emplace_back(u, c);\n }\n\n auto ds = dijkstra(graph, s),\n da = dijkstra(graph, a),\n db = dijkstra(graph, b);\n\n std::vector<int> vs(n);\n std::iota(vs.begin(), vs.end(), 0);\n std::sort(vs.begin(), vs.end(),\n [&](int u, int v) { return ds[u] < ds[v]; });\n\n std::vector<std::vector<lint>>\n dist(3, std::vector<lint>(n, INF));\n\n for (auto v : vs) {\n dist[0][v] = da[v];\n dist[1][v] = db[v];\n dist[2][v] = da[v] + db[v];\n\n for (auto e : graph[v]) {\n int u = e.dst;\n if (ds[u] + e.cost > ds[v]) continue;\n for (int k = 0; k < 3; ++k) {\n dist[k][v] = std::min(dist[k][v], dist[k][u]);\n }\n }\n\n dist[2][v] = std::min({dist[2][v],\n dist[0][v] + db[v],\n dist[1][v] + da[v]});\n }\n\n std::cout << std::min(da[b], dist[2][t]) << std::endl;\n}\n\nint main() {\n std::cin.tie(nullptr);\n std::cout.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 21392, "score_of_the_acc": -0.1703, "final_rank": 3 }, { "submission_id": "aoj_0650_3988407", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n \n \n\n\n\nvector<pa> G[100020];\n\nint dis[100020][4];\n\nint n;\nvoid dij(int r,int po){\n\tfor(int i=1;i<=n;i++)dis[i][po]=-1;\n\tpriority_queue<pa,vector<pa>,greater<pa>> pq; \n\tpq.push(mp(0,r));\n\twhile(pq.size()){\n\t\tpa z=pq.top();\n\t\tpq.pop();\n\t\tif(dis[z.second][po]>=0) continue;\n\t\tdis[z.second][po]=z.first;\n\t\tfor(auto v:G[z.second])pq.push(mp(z.first+v.second,v.first));\n\t}\n}\n\n\n\nvector<int> G1[100020];\nvector<int> G2[100020];\n\nint nyu[100020]={};\nint use[100020]={};\n\nint ue[100020][2];\nint si[100020][2];\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\tint m;\ncin>>n>>m;\n\tint S,T,U,V;\n\tcin>>S>>T>>U>>V;\n\t\n\tfor(int i=0;i<m;i++){\n\t\tint y,yy,yyy;\n\t\tcin>>y>>yy>>yyy;\n\t\tG[y].pb(mp(yy,yyy));\n\t\tG[yy].pb(mp(y,yyy));\n\t\t\n\t}\n\tdij(S,0);\n\tdij(T,1);\n\tdij(U,2);\n\tdij(V,3);\n\t\n\tint ST=dis[T][0];\n\t\n\tfor(int i=1;i<=n;i++)for(auto v:G[i]){\n\t\tint s=i,t=v.first,val=v.second;\n\t\tif(dis[s][0]+dis[t][1]+val==ST){\n\t\t\tG1[s].pb(t);\n\t\t\tG2[t].pb(s);\n\t\t\tnyu[t]++;\n\t\t\tuse[s]=1,use[t]=1;\n\t\t\t\n\t\t}\n\t}\n\tqueue<int> qu;\n\tfor(int i=1;i<=n;i++)if(use[i])if(nyu[i]==0)qu.push(i);\n\tvector<int> topo;\n\twhile(qu.size()){\n\t\tint y=qu.front();\n\t\tqu.pop();\n\t\ttopo.pb(y);\n\t\tfor(auto v:G1[y]){\n\t\t\tnyu[v]--;\n\t\t\tif(nyu[v]==0)qu.push(v);\n\t\t}\n\t}\n\t\n\tfor(auto v:topo){\n\t\tue[v][0]=dis[v][2];\n\t\tue[v][1]=dis[v][3];\n\t\t\n\t\tfor(auto r:G2[v]){\n\t\t\tue[v][0]=min(ue[v][0],ue[r][0]);\n\t\t\tue[v][1]=min(ue[v][1],ue[r][1]);\n\t\t\t\n\t\t}\n\t}\n\treverse(topo.begin(),topo.end());\n\tfor(auto v:topo){\n\t\tsi[v][0]=dis[v][2];\n\t\tsi[v][1]=dis[v][3];\n\t\t\n\t\tfor(auto r:G1[v]){\n\t\t\tsi[v][0]=min(si[v][0],si[r][0]);\n\t\t\tsi[v][1]=min(si[v][1],si[r][1]);\n\t\t\t\n\t\t}\n\t}\n\tint ans=dis[U][3];\n\tfor(int i=1;i<=n;i++)if(use[i]==1){\n\t\tans=min({ans,ue[i][0]+si[i][1],si[i][0]+ue[i][1]});\n\t\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 380, "memory_kb": 36588, "score_of_the_acc": -0.9676, "final_rank": 15 }, { "submission_id": "aoj_0650_3662600", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nstruct edge{\n int to;\n ll cost;\n};\n\nstruct node{\n int id;\n ll cost;\n\n bool operator<(const node &rhs) const {\n return cost > rhs.cost;\n }\n};\n\nint dfs(int v, const vector< vector<int> > &g, vector<int> &dp){\n if(dp[v] >= 0){\n return dp[v];\n }\n\n int res = 0;\n for(auto to : g[v]){\n res |= dfs(to, g, dp);\n }\n\n return dp[v] = res;\n}\n\nll dijkstra(int s, int t, const vector< vector<edge> > &g){\n vector<ll> cost(g.size(), 1LL << 62);\n priority_queue<node> que;\n que.push({s, 0LL});\n cost[s] = 0;\n while(!que.empty()){\n node now = que.top();\n que.pop();\n if(cost[now.id] < now.cost){\n continue;\n }\n for(auto e : g[now.id]){\n if(cost[e.to] > now.cost + e.cost){\n cost[e.to] = now.cost + e.cost;\n que.push({e.to, now.cost + e.cost});\n }\n }\n }\n\n return cost[t];\n}\n\nint main(){\n int n, m, s, t, u, v;\n cin >> n >> m >> s >> t >> u >> v;\n --s;\n --t;\n --u;\n --v;\n\n vector< vector<edge> > g(n), g1(n), g2(n);\n for(int i = 0 ; i < m ; ++i){\n int a, b;\n ll c;\n cin >> a >> b >> c;\n --a;\n --b;\n g[a].push_back({b, c});\n g[b].push_back({a, c});\n g1[a].push_back({b, c});\n g1[b].push_back({a, c});\n g2[a].push_back({b, c});\n g2[b].push_back({a, c});\n }\n\n vector< vector<int> > prev(n);\n vector<ll> cost(n, 1LL << 62);\n priority_queue<node> que;\n que.push({s, 0LL});\n cost[s] = 0;\n while(!que.empty()){\n node now = que.top();\n que.pop();\n if(cost[now.id] < now.cost){\n continue;\n }\n for(auto e : g[now.id]){\n if(cost[e.to] == now.cost + e.cost){\n prev[e.to].emplace_back(now.id);\n }else if(cost[e.to] > now.cost + e.cost){\n prev[e.to].clear();\n prev[e.to].emplace_back(now.id);\n cost[e.to] = now.cost + e.cost;\n que.push({e.to, now.cost + e.cost});\n }\n }\n }\n\n vector< vector<int> > g3(n);\n for(int i = 0 ; i < n ; ++i){\n for(auto j : prev[i]){\n g3[j].emplace_back(i);\n }\n }\n\n vector<int> dp(n, -1);\n dp[t] = 1;\n dfs(s, g3, dp);\n\n for(int i = 0 ; i < n ; ++i){\n for(auto j : prev[i]){\n if(dp[i] == 1 && dp[j] == 1){\n g1[i].push_back({j, 0LL});\n g2[j].push_back({i, 0LL});\n }\n }\n }\n\n ll ans = min({dijkstra(u, v, g1), dijkstra(v, u, g1), dijkstra(u, v, g2), dijkstra(v, u, g2)});\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 0.625, "time_ms": 570, "memory_kb": 65640, "score_of_the_acc": -2, "final_rank": 19 } ]
aoj_0657_cpp
座席 (Seats) 問題文 2XXX 年,世界の国は直線状に並んでいた. N 個の国があり, 1, 2, ..., N の番号が付けられている. i = 1, 2, ..., N - 1 に対し,国 i と国 i + 1 が互いに隣国である. この年の国際情報オリンピックでは,国 i からは A_i 人の選手が参加する.国際情報オリンピックの技術委員のあなたは,競技での座席表を作成する担当である.競技会場が細長いため,一列に並んだ A_1 + A_2 + ... + A_N 個の座席に選手たちを割り当てることになった.不正防止のため,同じ国の選手や隣国の選手を隣り合う席に割り当ててはならない. 選手たちを座席に割り当てる方法は何通りあるだろうか.この数は非常に大きくなる可能性があるので,それを 10007 で割った余りを求めたい. 制約 1 ≦ N ≦ 100 1 ≦ A_i ≦ 4 ( 1 ≦ i ≦ N ) 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N A_1 A_2 ... A_N 出力 選手たちを座席に割り当てる方法の数を 10007 で割った余りを 1 行で出力せよ. 入出力例 入力例 1 4 2 1 1 1 出力例 1 4 国 1 から参加する 2 人の選手を 1 と 1' ,国 2 から参加する 1 人の選手を 2 ,国 3 から参加する 1 人の選手を 3 ,国 4 から参加する 1 人の選手を 4 で表すことにすると,選手たちを座席に割り当てる方法としては,以下の 4 通りの並べ方が考えられる: 1 , 3 , 1' , 4 , 2 1' , 3 , 1 , 4 , 2 2 , 4 , 1 , 3 , 1' 2 , 4 , 1' , 3 , 1 入力例 2 5 1 2 3 2 1 出力例 2 0 この入力例では,条件を満たす座席表は存在しない. 入力例 3 6 1 2 3 3 2 1 出力例 2 4754 この入力例では,選手たちを座席に割り当てる方法は 24768 通りあるため,それを 10007 で割った余りである 4754 を出力する. 情報オリンピック日本委員会作 『第 18 回日本情報オリンピック JOI 2018/2019 予選競技課題』
[ { "submission_id": "aoj_0657_4814967", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <vector>\n //6780\nstruct E{\n\tint a,b,c,d,e;\n};\nstruct E2{\n\tint p,no;\n};\n \n \nusing namespace std;\nvector<int> v[6];\nmap<vector<int>,int> toE2[5];\nmap<E,int> ep;\nint m= 10007;\n//int m=1000000007;\nint dp[2][410][9][9][4];\nint cs[101];\nint cs2[101];\nint ps[5]={1,1,2,6,24};\nint ps2[5]={0,0,1,2,3};\nint nowx;\nint nextx;\nint nowP;\nint data4[11][2][4]={\n\t{{4,0,0,0},{4,24,0,0}},\n\t{{2,2,0,0},{4,12,0,0}},\n\t{{1,3,0,0},{4,24,0,0}},\n\t{{1,1,2,0},{4,12,0,0}},\n\t{{1,1,1,1},{4,1,0,0}},\n\t{{3,0,0,0},{3,24,0,0}},\n\t{{1,2,0,0},{3,24,0,0}},\n\t{{1,1,1,0},{3,4,0,0}},\n\t{{2,0,0,0},{2,12,0,0}},\n\t{{1,1,0,0},{2,6,0,0}},\n\t{{1,0,0,0},{1,4,0,0}}};\nint data3[7][2][4]={\n\t{{3,0,0,0},{3,6,0,0}},\n\t{{2,1,0,0},{3,6,0,0}},\n\t{{1,2,0,0},{3,6,0,0}},\n\t{{1,1,1,0},{3,1,0,0}},\n\t{{2,0,0,0},{2,6,0,0}},\n\t{{1,1,0,0},{2,3,0,0}},\n\t{{1,0,0,0},{1,3,0,0}}\n\t};\nint data2[3][2][4]={\n\t{{2,0,0,0},{2,2,0,0}},\n\t{{1,1,0,0},{1,1,0,0}},\n\t{{1,0,0,0},{1,2,0,0}},\n\t};\n \nint cs3[7];\nint cs4[102];\n \nvoid f(int no,int n,int nots,int olds,int nows,int nowsA,int nows2,int nexts,int nextsA,int nexts2,int hasi,int hasi2,int p1){\n\t\n\tint k1;\n\tif(cs3[no]==-1){\n\t\tcs3[no]=n;\n\t\tk1=-1;\n\t}else{\n\t\tk1=cs3[no];\n\t}\n\tint s=1;\n\tif(v[no].size()>0)s=v[no][v[no].size()-1];\n\tif(no==0){\n\t\t//古いところで隙間がないところ\n\t\tf(1,n,nots,olds,nows,nowsA,nows2,nexts,nextsA,nexts2,hasi,hasi2,(p1*toE2[cs3[no]][v[no]])%m);\n\t\tif(nots>0){\n\t\t\tfor(int i=s;i<=n;i++){\n\t\t\t\tv[no].push_back(i);\n\t\t\t\tf(no,n-i,nots-1,olds,nows,nowsA,nows2,nexts+2,nextsA,nexts2+ps2[i],hasi,hasi2,(p1*nots)%m);\n\t\t\t\tv[no].pop_back();\n\t\t\t}\n\t\t}\n\t}else if(no==1){\n\t\t//古いところで隙間があるところ\n\t\tf(2,n,nots,olds,nows,nowsA,nows2,nexts,nextsA,nexts2,hasi,hasi2,(p1*toE2[cs3[no]][v[no]])%m);\n\t\tif(olds>0){\n\t\t\tfor(int i=s;i<=n;i++){\n\t\t\t\tv[no].push_back(i);\n\t\t\t\tf(no,n-i,nots,olds-1,nows,nowsA,nows2,nexts+2,nextsA,nexts2+ps2[i],hasi,hasi2,(p1*olds)%m);\n\t\t\t\tv[no].pop_back();\n\t\t\t}\n\t\t}\n\t}else if(no==2){\n\t\tf(3,n,nots,olds,nows,nowsA,nows2,nexts,nextsA,nexts2,hasi,hasi2,(p1*toE2[cs3[no]][v[no]])%m);\n\t\t//片方に1小さい数があるところ\n\t\tif(nows>0){\n\t\t\tfor(int i=s;i<=n;i++){\n\t\t\t\tv[no].push_back(i);\n\t\t\t\tf(no,n-i,nots,olds,nows-1,nowsA,nows2,nexts+1,nextsA+1,nexts2+ps2[i],hasi,hasi2,(p1*nows)%m);\n\t\t\t\tv[no].pop_back();\n \n\t\t\t}\n\t\t}\n\t}else if(no==3){\n\t\tf(4,n,nots,olds,nows,nowsA,nows2,nexts,nextsA,nexts2,hasi,hasi2,(p1*toE2[cs3[no]][v[no]])%m);\n\t\tif(nowsA>0){\n\t\t\tfor(int i=s;i<=n;i++){\n\t\t\t\tv[no].push_back(i);\n\t\t\t\tf(no,n-i,nots,olds,nows,nowsA-1,nows2,nexts+1,nextsA+1,nexts2+ps2[i],hasi,hasi2,(p1*nowsA)%m);\n\t\t\t\tv[no].pop_back();\n\t\t\t}\n\t\t}\n\t}else if(no==4){\n\t\tf(5,n,nots,olds,nows,nowsA,nows2,nexts,nextsA,nexts2,hasi,hasi2,(p1*toE2[cs3[no]][v[no]])%m);\n\t\tif(nows2>0){\n\t\t\tfor(int i=s;i<=n;i++){\n\t\t\t\tv[no].push_back(i);\n\t\t\t\tf(no,n-i,nots,olds,nows,nowsA,nows2-1,nexts,nextsA+2,nexts2+ps2[i],hasi,hasi2,(p1*nows2)%m);\n\t\t\t\tv[no].pop_back();\n\t\t\t}\n\t\t}\n \n\t}else if(no==5){\n\t\tint olds2=olds+nows2+nowsA;\n\t\tif(olds2>210){\n\t\t\treturn ;\n\t\t}\n\t\tif (n==0){\n\t\t\t\tint p2=1;\n\t\t\t\tint c3=0;\n\t\t\t\t//p2*=ps[c3];\n\t\t\t\tdp[nextx][olds2][nexts][nextsA][nexts2]=(dp[nextx][olds2][nexts][nextsA][nexts2]+p1)%m;\n\t\t\t\t//dp[nextx][olds2][nexts][nextsA][nexts2][0]=(dp[nextx][olds2][nexts][nextsA][nexts2][0]+p1)%m;\n\t\t}\n\t}\n\tcs3[no]=k1;\n}\n \nint main() {\n\t// your code goes here\n\tmemset(dp,0,sizeof(dp));\n \n\tint n;\n\tcin>>n;\n\tint t1=0;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>cs[i];\n\t\tt1+=cs[i];\n\t\tcs2[i]=t1;\n\t}\n\tt1=0;\n\tfor(int i=n-1;i>=0;i--){\n\t\tt1+=cs[i];\n\t\tcs4[i]=t1;\n\t}\n\n\tif(n<2){\n\t\tint ans=0;\n\t\tif(cs[0]==1)ans=1;\n\t\tcout<<ans<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=0;i<11;i++){\n\t\tvector<int> v2;\n\t\tE2 e1;\n\t\te1.p=1;\n\t\te1.no=0;\n\t\ttoE2[0][v2]=1;\n\t\ttoE2[1][v2]=1;\n\t\ttoE2[2][v2]=1;\n\t\ttoE2[3][v2]=1;\n\t\ttoE2[4][v2]=1;\n\t\tfor(int j=0;j<4;j++){\n\t\t\tif(data4[i][0][j]==0){\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tv2.push_back(data4[i][0][j]);\n\t\t\t}\n\t\t}\n\t\ttoE2[4][v2]=data4[i][1][1];\n\t}\n\tfor(int i=0;i<7;i++){\n\t\tvector<int> v2;\n\t\tfor(int j=0;j<4;j++){\n\t\t\tif(data3[i][0][j]==0){\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tv2.push_back(data3[i][0][j]);\n\t\t\t}\n\t\t}\n\t\ttoE2[3][v2]=data3[i][1][1];\n\t}\n\tfor(int i=0;i<3;i++){\n\t\tvector<int> v2;\n\t\tfor(int j=0;j<4;j++){\n\t\t\tif(data2[i][0][j]==0){\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tv2.push_back(data2[i][0][j]);\n\t\t\t}\n\t\t}\n \n \n\t\tE2 e2;\n\t\te2.no=data2[i][1][0];\n\t\te2.p=data2[i][1][1];\n\t\ttoE2[2][v2]=data2[i][1][1];\n\t}\n\tvector<int> v0;\n\tv0.push_back(1);\n\ttoE2[1][v0]=1;\n \n\tmemset(cs3,-1,sizeof(cs3));\n\tdp[1][0][2][0][cs[0]-1]=ps[cs[0]];\n \n\tfor(int i=1;i<n;i++){\n\t\tnowx=i%2;\n\t\tnextx=(i+1)%2;\n\t\tfor(int sp1=0;sp1<9;sp1++){\n\t\tfor(int sp1A=0;sp1A<9-sp1;sp1A++){\n\t\t\tfor(int os=0;os<=min(cs4[i-1]+5,cs2[i-1]);os++){\n\t\t\t\tfor(int sp2=0;sp2<4;sp2++){\n\t\t\t\tint t2=cs2[i-1]+1-sp1-os-sp1A-sp2;\n\t\t\t\tif (t2<0){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\t\tint t1=dp[nowx][os][sp1][sp1A][sp2];\n\t\t\t\t\tif (t1==0) continue;\n\t\t\t\t\tdp[nowx][os][sp1][sp1A][sp2]=0;\n\t\t\t\t\tf(0,cs[i],t2,os,sp1,sp1A,sp2,0,0,0,0,0,t1);\n\t\t\t\t}\n\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans=0;\n\tfor(int sp1=0;sp1<9;sp1++){\n\t\t\tans=(ans+dp[nextx][0][sp1][0][0])%m;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2070, "memory_kb": 4192, "score_of_the_acc": -0.7159, "final_rank": 3 }, { "submission_id": "aoj_0657_4267296", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nlong long N, A[109], S[109], dp[109][309][9][4], nr[509][509], mod = 10007;\n\nint COUNTRY = 0, ORDINARY = 0, DANGER = 0, DANGER1 = 0, DANGER2 = 0, PLUS = 0, BASE = 0;\n\nvoid init() {\n\tfor (int i = 0; i <= 500; i++) {\n\t\tfor (int j = 0; j <= 500; j++) {\n\t\t\tif (i == 0 || j == 0) nr[i][j] = 1;\n\t\t\telse nr[i][j] = (nr[i - 1][j] + nr[i][j - 1]) % mod;\n\t\t}\n\t}\n}\n\nint ncr(int n, int r) {\n\tif (n < r || r < 0) return 0;\n\treturn nr[r][n - r];\n}\n\nvoid calc(int num, int danger2, int multi) {\n\tfor (int i = 0; i <= num; i++) {\n\t\tfor (int j = 0; i + j <= num; j++) {\n\t\t\tfor (int k = 0; i + j + k <= num; k++) {\n\t\t\t\tfor (int l = 0; i + j + k + l <= num; l++) {\n\t\t\t\t\tint m = num - i - j - k - l;\n\n\t\t\t\t\tint v1 = ncr(ORDINARY, i);\n\t\t\t\t\tint v2 = ncr(DANGER, j);\n\t\t\t\t\tint v3 = ncr(DANGER1, k);\n\t\t\t\t\tint v4 = ncr(DANGER2, l);\n\t\t\t\t\tint v5 = ncr(PLUS, m);\n\t\t\t\t\tint product = (((v1 * v2 % mod) * v3 % mod) * v4 % mod) * v5 % mod;\n\t\t\t\t\tif (product == 0) continue;\n\n\t\t\t\t\tint T1 = COUNTRY;\n\t\t\t\t\tint T2 = DANGER - j + (DANGER1 - k) + (DANGER2 - l);\n\t\t\t\t\tint T3 = k + l * 2 + m;\n\t\t\t\t\tint T4 = danger2;\n\t\t\t\t\tdp[T1][T2][T3][T4] += BASE * product * multi;\n\t\t\t\t\tdp[T1][T2][T3][T4] %= mod;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid solve(int country, int danger, int danger1, int danger2) {\n\tCOUNTRY = country + 1;\n\tDANGER = danger;\n\tDANGER1 = danger1;\n\tDANGER2 = danger2;\n\tPLUS = 2 * A[country] - DANGER1 - 2 * DANGER2;\n\tORDINARY = S[country] + 1 - DANGER - DANGER1 - DANGER2 - PLUS;\n\tBASE = dp[country][danger][danger1][danger2];\n\n\tif (A[country + 1] == 1) {\n\t\tcalc(1, 0, 1); // (1)\n\t}\n\tif (A[country + 1] == 2) {\n\t\tcalc(1, 1, 1); // (2)\n\t\tcalc(2, 0, 1); // (1, 1)\n\t}\n\tif (A[country + 1] == 3) {\n\t\tcalc(1, 2, 1); // (3)\n\t\tcalc(2, 1, 2); // (2, 1)\n\t\tcalc(3, 0, 1); // (1, 1, 1)\n\t}\n\tif (A[country + 1] == 4) {\n\t\tcalc(1, 3, 1); // (4)\n\t\tcalc(2, 2, 3); // (3, 1), (2, 2)\n\t\tcalc(3, 1, 3); // (2, 1, 1)\n\t\tcalc(4, 0, 1); // (1, 1, 1, 1)\n\t}\n}\n\nint checker() {\n\tvector<int>vec;\n\tfor (int i = 1; i <= N; i++) {\n\t\tfor (int j = 0; j < A[i]; j++) vec.push_back(i);\n\t}\n\tint cnts = 0;\n\tdo {\n\t\tbool flag = true;\n\t\tfor (int i = 0; i < vec.size() - 1; i++) {\n\t\t\tif (abs(vec[i] - vec[i + 1]) <= 1) flag = false;\n\t\t}\n\t\tif (flag == true) {\n\t\t\t/*for (int i = 0; i < N; i++) {\n\t\t\t\tif (i) cout << \" \"; cout << a[i];\n\t\t\t}\n\t\t\tcout << endl;*/\n\t\t\tcnts++;\n\t\t}\n\t} while (next_permutation(vec.begin(), vec.end()));\n\treturn cnts % mod;\n}\n\nint main() {\n\tcin >> N; init();\n\tfor (int i = 1; i <= N; i++) {\n\t\tcin >> A[i]; S[i] = S[i - 1] + A[i];\n\t}\n\tdp[0][0][0][0] = 1;\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < 3 * N; j++) {\n\t\t\tfor (int k = 0; k <= 8; k++) {\n\t\t\t\tfor (int l = 0; l <= 3; l++) {\n\t\t\t\t\tif (dp[i][j][k][l] == 0) continue;\n\t\t\t\t\tsolve(i, j, k, l);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tlong long ret = dp[N][0][0][0];\n\tfor (int i = 1; i <= N; i++) {\n\t\tfor (int j = 1; j <= A[i]; j++) { ret *= j; ret %= mod; }\n\t}\n\tcout << ret << endl;\n\t//cout << checker() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2110, "memory_kb": 10712, "score_of_the_acc": -0.8159, "final_rank": 4 }, { "submission_id": "aoj_0657_3996443", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n\nint MOD = 10007;\nlong long c[402][402], fac[5], dp[100][400][4][8];\n\nlong long C(int n, int r) {\n if (n < r || r < 0) return 0;\n return c[r][n-r];\n}\n\nint main() {\n REP(i, 402) REP(j, 402) {\n if (i == 0 || j == 0) c[i][j] = 1;\n else c[i][j] = (c[i-1][j] + c[i][j-1]) % MOD;\n }\n fac[1] = 1;\n fac[2] = 2;\n fac[3] = 6;\n fac[4] = 24;\n\n int n, sum = 0; cin >> n;\n vector<int> a(n); REP(i, n) cin >> a[i];\n dp[0][a[0]-1][a[0]-1][0] = fac[a[0]];\n REP(i, n-1) {\n sum += a[i];\n REP(j, sum) REP(k, min(j+1, a[i])) REP(l, min(j-k+1, (i==0?1:a[i-1]+a[i]))) {\n FOR(u, 1, a[i+1]+1) REP(w, min(k, u)+1) REP(x, min(l, u-w)+1) REP(y, min(j-k-l, u-w-x)+1) REP(z, min(2*a[i]-2*k-l, u-w-x-y)+1) {\n (dp[i+1][j+a[i+1]-u+w-y+z][a[i+1]-u][2*w+x+z] += dp[i][j][k][l] * C(a[i+1]-1, u-1) % MOD * C(k, w) % MOD * C(l, x) % MOD * C(j-k-l, y) % MOD * C(2*a[i]-2*k-l, z) % MOD * C(sum+1-j-(2*a[i]-2*k-l), u-w-x-y-z) % MOD * fac[a[i+1]] % MOD) %= MOD;\n }\n }\n }\n cout << dp[n-1][0][0][0] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 2720, "memory_kb": 9656, "score_of_the_acc": -1.0272, "final_rank": 5 }, { "submission_id": "aoj_0657_3988419", "code_snippet": "#include <bits/stdc++.h>\n\n// #include <boost/multiprecision/cpp_int.hpp>\n// #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-10)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x,y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n/*\n class Point{\n \tpublic:\n \tdouble x,y;\n \tPoint(double x=0,double y=0):x(x),y(y) {}\n \tPoint operator + (Point p) {return Point(x+p.x,y+p.y);}\n \tPoint operator - (Point p) {return Point(x-p.x,y-p.y);}\n \tPoint operator * (double a) {return Point(x*a,y*a);}\n \tPoint operator / (double a) {return Point(x/a,y/a);}\n \tdouble absv() {return sqrt(norm());}\n \tdouble norm() {return x*x+y*y;}\n \tbool operator < (const Point &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const Point &p) const{\n \t\treturn fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;\n \t}\n };\n typedef Point Vector;\n #define pl pair<int,pas>\n struct Segment{\n Point p1,p2;\n };\n double dot(Vector a,Vector b){\n \treturn a.x*b.x+a.y*b.y;\n }\n double cross(Vector a,Vector b){\n \treturn a.x*b.y-a.y*b.x;\n }\n \n bool parareru(Point a,Point b,Point c,Point d){\n //\tif(abs(cross(a-b,d-c))<EPS)cout<<\"dd \"<<cross(a-b,d-c)<<endl;\n \treturn abs(cross(a-b,d-c))<EPS;\n }\n double distance_ls_p(Point a, Point b, Point c) {\n if ( dot(b-a, c-a) < EPS ) return (c-a).absv();\n if ( dot(a-b, c-b) < EPS ) return (c-b).absv();\n return abs(cross(b-a, c-a)) / (b-a).absv();\n }\n bool is_intersected_ls(Segment a,Segment b) {\n \tif(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;\n \tif(parareru((a.p2),(a.p1),(a.p1),(b.p2))&&parareru((a.p2),(a.p1),(a.p1),(b.p1))){\n //\t\tcout<<\"sss\"<<endl;\n \t\tif(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;\n \t\tif(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;\n \t\tif(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;\n \t\tif(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;\n \t\treturn false;\n \t}\n else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );\n }\n \n double segment_dis(Segment a,Segment b){\n \tif(is_intersected_ls(a,b))return 0;\n \tdouble r=distance_ls_p(a.p1, a.p2, b.p1);\n \tr=min(r,distance_ls_p(a.p1, a.p2, b.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p2));\n \tr=min(r,distance_ls_p(b.p1, b.p2, a.p1));\n \treturn r;\n }\n Point intersection_ls(Segment a, Segment b) {\n Point ba = b.p2-b.p1;\n double d1 = abs(cross(ba, a.p1-b.p1));\n double d2 = abs(cross(ba, a.p2-b.p1));\n double t = d1 / (d1 + d2);\n \n return a.p1 + (a.p2-a.p1) * t;\n }\n */ \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n double distans(double x1,double y1,double x2,double y2){\n \tdouble rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);\n \treturn sqrt(rr);\n \t\n }\n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\n \n \n int pr[1000010];\n int inv[1000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n double bekid(double w,int r){\n \tif(r==0) return 1.0;\n \tif(r==1) return w;\n \tif(r%2) return bekid(w,r-1)*w;\n \tdouble f=bekid(w,r/2);\n \treturn f*f;\n }\n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \tfor(int i=0;i<ert;i++) inv[i]=beki(pr[i],mod-2,mod);\n \t\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n \n //----------------kokomade tenpure------------\n\nint a[100];\nint dp[2][4][8][4][9][9][401][8]={}; \n signed main(){\n\n \t cin.tie(0);\n \t\t\tios::sync_with_stdio(false);\nint n;\n \tcin>>n;\n \tvector<int> ve;\n \tve.pb(0);\n \t//assert(n<=10);\n \tfor(int i=1;i<=n;i++){\n \t\tint y;\n \t\tcin>>y;\n \t//a\tassert(y<=3);\n \t\tfor(int j=0;j<y;j++)ve.pb(i);\n \t}\n \tmod=10007;\n \tn=ve.size()-1;\n \tdp[1][0][0][0][2][0][0][0]=1;\n \tfor(int i=1;i<n;i++){\n \t\tif(ve[i]==ve[i+1]){\n \t\t//\tcout<<i<<endl;\n \t\t\tfor(int j=0;j<4;j++)for(int k=0;k<8&&2*j+k<=8;k++)for(int l=0;l<4&&k+2*l<=8;l++)for(int m=0;m<9&&2*j+k+m<=8;m++)for(int p=0;p<9&&k+2*l+p<=8;p++)for(int q=0;q<=400;q++)for(int r=0;r<8&&k+2*l+p+r<=8;r++)if(dp[i%2][j][k][l][m][p][q][r]){\n \t\t\t\tint ok=i+1-j-k-l-m-p-q-r;\n \t\t//\t\tcout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<l<<\" \"<<m<<\" \"<<p<<\" \"<<\" \"<<q<<\" \"<<r<<\" \"<<ok<<\" \"<<dp[i][j][k][l][m][p][q][r]<<endl;\n \t\t\t\tassert(ok>=0);\n \t\t\t\tif(ok>0){\n \t\t\t\t\tdp[(i+1)%2][j][k][l][m+2][p][q][r]+=dp[i%2][j][k][l][m][p][q][r]*ok;\n \t\t\t\t\tdp[(i+1)%2][j][k][l][m+2][p][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(r>0){\n \t\t\t\t\tdp[(i+1)%2][j][k+1][l][m+1][p][q][r-1]+=dp[i%2][j][k][l][m][p][q][r]*r;\n \t\t\t\t\tdp[(i+1)%2][j][k+1][l][m+1][p][q][r-1]%=mod;\n \t\t\t\t}\n \t\t\t\tif(q>0){\n \t\t\t\t\tdp[(i+1)%2][j][k][l][m+2][p][q-1][r]+=dp[i%2][j][k][l][m][p][q][r]*q;\n \t\t\t\t\tdp[(i+1)%2][j][k][l][m+2][p][q-1][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(p>0){\n \t\t\t\t\tdp[(i+1)%2][j][k+1][l][m+1][p-1][q][r]+=dp[i%2][j][k][l][m][p][q][r]*p;\n \t\t\t\t\tdp[(i+1)%2][j][k+1][l][m+1][p-1][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(m>0){\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]+=dp[i%2][j][k][l][m][p][q][r]*m;\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(l>0){\n \t\t\t\t\tdp[(i+1)%2][j][k+2][l-1][m][p][q][r]+=dp[i%2][j][k][l][m][p][q][r]*l;\n \t\t\t\t\tdp[(i+1)%2][j][k+2][l-1][m][p][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(k>0){\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]+=dp[i%2][j][k][l][m][p][q][r]*k;\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tif(j>0){\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]+=dp[i%2][j][k][l][m][p][q][r]*j;\n \t\t\t\t\tdp[(i+1)%2][j+1][k][l][m][p][q][r]%=mod;\n \t\t\t\t}\n \t\t\t\tdp[i%2][j][k][l][m][p][q][r]=0;\n \t\t\t}\n \t\t}\n \t\telse{\n \t\t\t \t\t\tfor(int j=0;j<4;j++)for(int k=0;k<8&&2*j+k<=8;k++)for(int l=0;l<4&&k+2*l<=8;l++)for(int m=0;m<9&&2*j+k+m<=8;m++)for(int p=0;p<9&&k+2*l+p<=8;p++)for(int q=0;q<=400;q++)for(int r=0;r<8&&k+2*l+p+r<=8;r++)if(dp[i%2][j][k][l][m][p][q][r]){\n//for(int j=0;j<4;j++)for(int k=0;k<8&&2*j+k<=8;k++)for(int l=0;l<4&&k+2*l<=8;l++)for(int m=0;m<9&&2*j+k+m<=8;m++)for(int p=0;p<9;p++)for(int q=0;q<=400;q++)for(int r=0;r<8;r++)if(dp[i%2][j][k][l][m][p][q][r]){\n \t\t\t\tint ok=i+1-j-k-l-m-p-r-q;\n \t\t//\t\tcout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<l<<\" \"<<m<<\" \"<<p<<\" \"<<q<<\" \"<<r<<\" \"<<ok<<\" \"<<dp[i][j][k][l][m][p][q][r]<<endl;\n \t\t\t\tint nj=0;\n \t\t\t\tint nk=0;\n \t\t\t\tint nl=j;\n \t\t\t\tint nm=0;\n \t\t\t\tint np=m;\n \t\t\t\tint nq=l+q+r;\n \t\t\t\tint nr=k;\n \t\t\t\tint nok=ok+p;\n \t\t//\t\tcout<<\" \"<<nj<<\" \"<<nk<<\" \"<<nl<<\" \"<<nm<<\" \"<<np<<\" \"<<nq<<\" \"<<nr<<\" \"<<nok<<endl;\n \t\t\t\tassert(nok>=0);\n \t\t\t\tif(nok>0){\n \t\t\t\t\tdp[(i+1)%2][nj][nk][nl][nm+2][np][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*nok;\n \t\t\t\t\tdp[(i+1)%2][nj][nk][nl][nm+2][np][nq][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nr>0){\n \t\t\t\t\tdp[(i+1)%2][nj][nk+1][nl][nm+1][np][nq][nr-1]+=dp[i%2][j][k][l][m][p][q][r]*nr;\n \t\t\t\t\tdp[(i+1)%2][nj][nk+1][nl][nm+1][np][nq][nr-1]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nq>0){\n \t\t\t\t\tdp[(i+1)%2][nj][nk][nl][nm+2][np][nq-1][nr]+=dp[i%2][j][k][l][m][p][q][r]*nq;\n \t\t\t\t\tdp[(i+1)%2][nj][nk][nl][nm+2][np][nq-1][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(np>0){\n \t\t\t\t\tdp[(i+1)%2][nj][nk+1][nl][nm+1][np-1][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*np;\n \t\t\t\t\tdp[(i+1)%2][nj][nk+1][nl][nm+1][np-1][nq][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nm>0){\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*nm;\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nl>0){\n \t\t\t\t\tdp[(i+1)%2][nj][nk+2][nl-1][nm][np][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*nl;\n \t\t\t\t\tdp[(i+1)%2][nj][nk+2][nl-1][nm][np][nq][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nk>0){\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*nk;\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]%=mod;\n \t\t\t\t}\n \t\t\t\tif(nj>0){\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]+=dp[i%2][j][k][l][m][p][q][r]*nj;\n \t\t\t\t\tdp[(i+1)%2][nj+1][nk][nl][nm][np][nq][nr]%=mod;\n \t\t\t\t}\n\tdp[i%2][j][k][l][m][p][q][r]=0;\n \t\t\t}\n \t\t}\n \t\t//for(int j=0;j<4;j++)for(int k=0;k<8;k++)for(int l=0;l<4;l++)for(int m=0;m<9;m++)for(int p=0;p<9;p++)for(int q=0;q<=400;q++)for(int r=0;r<8;r++)dp[i%2][j][k][l][m][p][q][r]=0;\n \t}\n \n \tint ans=0;\n \tfor(int m=0;m<9;m++)for(int p=0;p<9;p++){\n// \t\tif(dp[n][0][0][0][m][p][0][0])cout<<m<<\" \"<<p<<endl;\n \t\tans+=dp[n%2][0][0][0][m][p][0][0];\n \t\tans%=mod;\n \t}\n\n \tcout<<ans<<endl;\n\n \treturn 0;\n }", "accuracy": 1, "time_ms": 1140, "memory_kb": 22868, "score_of_the_acc": -0.6171, "final_rank": 2 }, { "submission_id": "aoj_0657_3659688", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX = 2100;\nconst int MOD = 10007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\nvoid COMinit(){\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for(int i = 2; i < MAX; i++){\n fac[i] = fac[i-1] * i % MOD;\n inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;\n finv[i] = finv[i-1] * inv[i] % MOD;\n }\n}\nlong long COM(int n, int k){\n if(n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD;\n}\n\nlong long dp[110][410][10][10][5] = {0}; // a <= 401, b <= 8, c <= 8, d <= 3\nint main() {\n COMinit();\n int N; cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n \n dp[0][0][0][0][0] = 1;\n int s = 0;\n for (int i = 0; i < N; ++i) {\n for (int a = 0; a <= s+1; ++a) {\n for (int b = 0; b < 8; ++b) {\n for (int c = 0; c < 8; ++c) {\n for (int d = 0; d < 4; ++d) {\n int e = s + 1 - a - b - c - d;\n if (e < 0) continue;\n if (!dp[i][a][b][c][d]) continue;\n\n for (int a2 = 0; a2 <= a; ++a2) {\n for (int b2 = 0; b2 <= b && a2 + b2 <= A[i]; ++b2) {\n for (int c2 = 0; c2 <= c && a2 + b2 +c2 <= A[i]; ++c2) {\n for (int d2 = 0; d2 <= d && a2 + b2 +c2 + d2 <= A[i]; ++d2) {\n for (int e2 = 0; e2 <= e && a2 + b2 +c2 + d2 + e2 <= A[i]; ++e2) {\n int s2 = a2 + b2 + c2 + d2 + e2;\n int r2 = A[i] - s2;\n long long fact = COM(a, a2);\n fact = (fact * COM(b, b2)) % MOD;\n fact = (fact * COM(c, c2)) % MOD;\n fact = (fact * COM(d, d2)) % MOD;\n fact = (fact * COM(e, e2)) % MOD;\n fact = (fact * COM(r2 + s2 - 1, r2)) % MOD;\n \n int na = a + c + d - a2 - c2 - d2;\n int nb = (a2 + e2) * 2 + b2 + c2;\n int nc = b2 + c2 + d2 * 2;\n int nd = r2;\n //int ne = b + e - b2 - e2;\n dp[i+1][na][nb][nc][nd] += dp[i][a][b][c][d] * fact % MOD;\n dp[i+1][na][nb][nc][nd] %= MOD;\n }\n }\n }\n }\n }\n }\n }\n }\n }\n s += A[i];\n }\n long long res = 0;\n for (int b = 0; b < 8; ++b) res = (res + dp[N][0][b][0][0]) % MOD;\n for (int i = 0; i < N; ++i) res = (res * fac[A[i]]) % MOD;\n cout << res << endl;\n}", "accuracy": 0.7407407407407407, "time_ms": 1130, "memory_kb": 79040, "score_of_the_acc": -1.3483, "final_rank": 9 }, { "submission_id": "aoj_0657_3659687", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX = 2100;\nconst int MOD = 10007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\nvoid COMinit(){\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for(int i = 2; i < MAX; i++){\n fac[i] = fac[i-1] * i % MOD;\n inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;\n finv[i] = finv[i-1] * inv[i] % MOD;\n }\n}\nlong long COM(int n, int k){\n if(n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD;\n}\n\nlong long dp[110][410][10][10][5] = {0}; // a <= 401, b <= 8, c <= 8, d <= 3\nint main() {\n COMinit();\n int N; cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n \n dp[0][0][0][0][0] = 1;\n int s = 0;\n for (int i = 0; i < N; ++i) {\n for (int a = 0; a <= s; ++a) {\n for (int b = 0; b < 8; ++b) {\n for (int c = 0; c < 8; ++c) {\n for (int d = 0; d < 4; ++d) {\n int e = s + 1 - a - b - c - d;\n if (e < 0) continue;\n if (!dp[i][a][b][c][d]) continue;\n\n for (int a2 = 0; a2 <= a; ++a2) {\n for (int b2 = 0; b2 <= b && a2 + b2 <= A[i]; ++b2) {\n for (int c2 = 0; c2 <= c && a2 + b2 +c2 <= A[i]; ++c2) {\n for (int d2 = 0; d2 <= d && a2 + b2 +c2 + d2 <= A[i]; ++d2) {\n for (int e2 = 0; e2 <= e && a2 + b2 +c2 + d2 + e2 <= A[i]; ++e2) {\n int s2 = a2 + b2 + c2 + d2 + e2;\n int r2 = A[i] - s2;\n long long fact = COM(a, a2);\n fact = (fact * COM(b, b2)) % MOD;\n fact = (fact * COM(c, c2)) % MOD;\n fact = (fact * COM(d, d2)) % MOD;\n fact = (fact * COM(e, e2)) % MOD;\n fact = (fact * COM(r2 + s2 - 1, r2)) % MOD;\n \n int na = a + c + d - a2 - c2 - d2;\n int nb = (a2 + e2) * 2 + b2 + c2;\n int nc = b2 + c2 + d2 * 2;\n int nd = r2;\n //int ne = b + e - b2 - e2;\n dp[i+1][na][nb][nc][nd] += dp[i][a][b][c][d] * fact % MOD;\n dp[i+1][na][nb][nc][nd] %= MOD;\n }\n }\n }\n }\n }\n }\n }\n }\n }\n s += A[i];\n }\n long long res = 0;\n for (int b = 0; b < 8; ++b) res = (res + dp[N][0][b][0][0]) % MOD;\n for (int i = 0; i < N; ++i) res = (res * fac[A[i]]) % MOD;\n cout << res << endl;\n}", "accuracy": 0.7407407407407407, "time_ms": 1130, "memory_kb": 78940, "score_of_the_acc": -1.347, "final_rank": 8 }, { "submission_id": "aoj_0657_3659685", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX = 2100;\nconst int MOD = 10007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\nvoid COMinit(){\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for(int i = 2; i < MAX; i++){\n fac[i] = fac[i-1] * i % MOD;\n inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;\n finv[i] = finv[i-1] * inv[i] % MOD;\n }\n}\nlong long COM(int n, int k){\n if(n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD;\n}\n\nlong long dp[110][410][10][10][5] = {0}; // a <= 401, b <= 8, c <= 8, d <= 3\nint main() {\n COMinit();\n int N; cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n \n dp[0][0][0][0][0] = 1;\n int s = 0;\n for (int i = 0; i < N; ++i) {\n for (int a = 0; a <= 401; ++a) {\n for (int b = 0; b < 8; ++b) {\n for (int c = 0; c < 8; ++c) {\n for (int d = 0; d < 4; ++d) {\n int e = s + 1 - a - b - c - d;\n if (e < 0) continue;\n if (!dp[i][a][b][c][d]) continue;\n\n for (int a2 = 0; a2 <= a; ++a2) {\n for (int b2 = 0; b2 <= b && a2 + b2 <= A[i]; ++b2) {\n for (int c2 = 0; c2 <= c && a2 + b2 +c2 <= A[i]; ++c2) {\n for (int d2 = 0; d2 <= d && a2 + b2 +c2 + d2 <= A[i]; ++d2) {\n for (int e2 = 0; e2 <= e && a2 + b2 +c2 + d2 + e2 <= A[i]; ++e2) {\n int s2 = a2 + b2 + c2 + d2 + e2;\n int r2 = A[i] - s2;\n long long fact = COM(a, a2);\n fact = (fact * COM(b, b2)) % MOD;\n fact = (fact * COM(c, c2)) % MOD;\n fact = (fact * COM(d, d2)) % MOD;\n fact = (fact * COM(e, e2)) % MOD;\n fact = (fact * COM(r2 + s2 - 1, r2)) % MOD;\n \n int na = a + c + d - a2 - c2 - d2;\n int nb = (a2 + e2) * 2 + b2 + c2;\n int nc = b2 + c2 + d2 * 2;\n int nd = r2;\n //int ne = b + e - b2 - e2;\n dp[i+1][na][nb][nc][nd] += dp[i][a][b][c][d] * fact % MOD;\n dp[i+1][na][nb][nc][nd] %= MOD;\n }\n }\n }\n }\n }\n }\n }\n }\n }\n s += A[i];\n }\n long long res = 0;\n for (int b = 0; b < 8; ++b) res = (res + dp[N][0][b][0][0]) % MOD;\n for (int i = 0; i < N; ++i) res = (res * fac[A[i]]) % MOD;\n cout << res << endl;\n}", "accuracy": 0.7407407407407407, "time_ms": 1140, "memory_kb": 79036, "score_of_the_acc": -1.352, "final_rank": 10 }, { "submission_id": "aoj_0657_3659671", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX = 2100;\nconst int MOD = 10007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\nvoid COMinit(){\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for(int i = 2; i < MAX; i++){\n fac[i] = fac[i-1] * i % MOD;\n inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;\n finv[i] = finv[i-1] * inv[i] % MOD;\n }\n}\nlong long COM(int n, int k){\n if(n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD;\n}\n\nlong long dp[110][410][10][10][5] = {0}; // a <= 401, b <= 8, c <= 8, d <= 3\nint main() {\n COMinit();\n int N; cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n \n dp[0][0][0][0][0] = 1;\n int s = 0;\n for (int i = 0; i < N; ++i) {\n for (int a = 0; a <= 401; ++a) {\n for (int b = 0; b < 8; ++b) {\n for (int c = 0; c < 8; ++c) {\n for (int d = 0; d < 4; ++d) {\n int e = s + 1 - a - b - c - d;\n if (e < 0) continue;\n if (!dp[i][a][b][c][d]) continue;\n\n for (int a2 = 0; a2 <= a; ++a2) {\n for (int b2 = 0; b2 <= b && a2 + b2 <= A[i]; ++b2) {\n for (int c2 = 0; c2 <= c && a2 + b2 +c2 <= A[i]; ++c2) {\n for (int d2 = 0; d2 <= d && a2 + b2 +c2 + d2 <= A[i]; ++d2) {\n for (int e2 = 0; e2 <= e && a2 + b2 +c2 + d2 + e2 <= A[i]; ++e2) {\n int s2 = a2 + b2 + c2 + d2 + e2;\n int r2 = A[i] - s2;\n long long fact = COM(a, a2);\n fact = (fact * COM(b, b2)) % MOD;\n fact = (fact * COM(c, c2)) % MOD;\n fact = (fact * COM(d, d2)) % MOD;\n fact = (fact * COM(e, e2)) % MOD;\n fact = (fact * COM(r2 + s2 - 1, r2)) % MOD;\n \n int na = a + c + d - a2 - c2 - d2;\n int nb = (a2 + e2) * 2 + b2 + c2;\n int nc = b2 + c2 + d2 * 2;\n int nd = r2;\n //int ne = b + e - b2 - e2;\n dp[i+1][na][nb][nc][nd] += dp[i][a][b][c][d] * fact % MOD;\n dp[i+1][na][nb][nc][nd] %= MOD;\n }\n }\n }\n }\n }\n }\n }\n }\n }\n s += A[i];\n }\n long long res = 0;\n for (int b = 0; b <= 8; ++b) res = (res + dp[N][0][b][0][0]) % MOD;\n for (int i = 0; i < N; ++i) res = (res * fac[A[i]]) % MOD;\n cout << res << endl;\n}", "accuracy": 0.7407407407407407, "time_ms": 1150, "memory_kb": 79052, "score_of_the_acc": -1.3559, "final_rank": 11 }, { "submission_id": "aoj_0657_3659636", "code_snippet": "#include <bits/stdc++.h>\n#define syosu(x) fixed<<setprecision(x)\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\ntypedef pair<double,double> pdd;\ntypedef pair<ll,ll> pll;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<string> vs;\ntypedef vector<P> vp;\ntypedef vector<vp> vvp;\ntypedef vector<pll> vpll;\ntypedef pair<int,P> pip;\ntypedef vector<pip> vip;\nconst int inf=1<<30;\nconst ll INF=1ll<<60;\nconst double pi=acos(-1);\nconst double eps=1e-9;\n//const ll mod=1e9+7;\nconst int dx[4]={0,1,0,-1},dy[4]={1,0,-1,0};\n\nconst int M=405,mod=10007;\nll n,C[M][M],dp[101][M][8][4];\n\nint main(){\n\tcin>>n;\n\tC[0][0]++;\n\tfor(int i=0;i<M-1;i++) for(int j=0;j<=i;j++){\n\t\t(C[i+1][j]+=C[i][j])%=mod;\n\t\t(C[i+1][j+1]+=C[i][j])%=mod;\n\t}\n\tdp[0][0][0][0]++;\n\tint S=0,N,N_=0;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>N;\n\t\tll t=1;\n\t\tfor(int j=1;j<=N;j++) (t*=j)%=mod;\n\t\tfor(int j=0;j<=S+1;j++) for(int k=0;k<8;k++) for(int l=0;l<4;l++) for(int x=1;x<=min(S+1,N);x++) if(dp[i][j][k][l]){\n\t\t\tint q=2*(N_-l)-k;\n\t\t\tfor(int J=0;J<=min(x,j);J++) for(int K=0;K<=min(x-J,k);K++) for(int L=0;L<=min(x-J-K,l);L++) for(int Q=0;Q<=min(x-J-K-L,q);Q++){\n\t\t\t\t(dp[i+1][j+k+l-J-K-L][K+2*L+Q][N-x]+=t*C[N-1][x-1]*C[j][J]*C[k][K]*C[l][L]*C[q][Q]*C[S-j-k-l-q+1][x-J-K-L-Q]*dp[i][j][k][l])%=mod;\n\t\t\t}\n\t\t}\n\t\tS+=N;N_=N;\n\t}\n\tcout<<dp[n][0][0][0]<<endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 9720, "score_of_the_acc": -0.0723, "final_rank": 1 }, { "submission_id": "aoj_0657_3558502", "code_snippet": "#include\"bits/stdc++.h\"\nusing namespace std;\n#define LL long long\n#define PB push_back\n#define MP make_pair\n\nconst int MOD = 10007;\nint N, A[100], sum[100];\n\nint memo1[5] ={ 0,1,2,6,24 };\nint memo2[5][5] ={ {0,0,0,0,0},{0,1,0,0,0},{0,1,1,0,0},{0,1,2,1,0},{0,1,3,3,1} };\n/*\na := 国i\nb := i-2以下の国どうしの問題隣接箇所\nc := 国i-1と国i-3以下の隣接箇所(今はok)\nd := 国i-1とi-2間の隣接箇所\ne := 国i-1どうしの隣接箇所\nf := それ以外の隣接箇所\n*/\nshort dp[100][400][9][8][4];\nbool visited[100][400][9][8][4] ={};\nint solve(int a, int b, int c, int d, int e){\n\tif(a == N){\n\t\tif(b == 0 && d == 0 && e == 0) return 1;\n\t\telse return 0;\n\t}\n\tif(visited[a][b][c][d][e]) return dp[a][b][c][d][e];\n\tvisited[a][b][c][d][e] = true;\n\tint f = sum[a] - b - c - d - e;\n\tint nc = 0;\n\tint nd = 0;\n\tLL ret = 0;\n\tfor(int i=1; i<=A[a]; i++){ //何個の塊\n\t\tLL baai = memo1[A[a]] * memo2[A[a]][i] / memo1[i];\n\t\tfor(int j=0; j<5; j++){\n\t\t\tif(j == 0){ if(b == 0) continue; baai*=b; b--; nc+=2; }\n\t\t\tif(j == 1){ if(c == 0) continue; baai*=c; c--; nc++; nd++; }\n\t\t\tif(j == 2){ if(d == 0) continue; baai*=d; d--; nc++; nd++; }\n\t\t\tif(j == 3){ if(e == 0) continue; baai*=e; e--; nd+=2; }\n\t\t\tif(j == 4){ if(f == 0) continue; baai*=f; f--; nc+=2; }\n\t\t\tif(i == 1) ret += baai * solve(a+1, b+d+e, nc, nd, A[a]-i);\n\t\t\tfor(int k=0; k<5 && i>1; k++){\n\t\t\t\tif(k == 0){ if(b == 0) continue; baai*=b; b--; nc+=2; }\n\t\t\t\tif(k == 1){ if(c == 0) continue; baai*=c; c--; nc++; nd++; }\n\t\t\t\tif(k == 2){ if(d == 0) continue; baai*=d; d--; nc++; nd++; }\n\t\t\t\tif(k == 3){ if(e == 0) continue; baai*=e; e--; nd+=2; }\n\t\t\t\tif(k == 4){ if(f == 0) continue; baai*=f; f--; nc+=2; }\n\t\t\t\tif(i == 2) ret += baai * solve(a+1, b+d+e, nc, nd, A[a]-i);\n\t\t\t\tfor(int l=0; l<5 && i>2; l++){\n\t\t\t\t\tif(l == 0){ if(b == 0) continue; baai*=b; b--; nc+=2; }\n\t\t\t\t\tif(l == 1){ if(c == 0) continue; baai*=c; c--; nc++; nd++; }\n\t\t\t\t\tif(l == 2){ if(d == 0) continue; baai*=d; d--; nc++; nd++; }\n\t\t\t\t\tif(l == 3){ if(e == 0) continue; baai*=e; e--; nd+=2; }\n\t\t\t\t\tif(l == 4){ if(f == 0) continue; baai*=f; f--; nc+=2; }\n\t\t\t\t\tif(i == 3) ret += baai * solve(a+1, b+d+e, nc, nd, A[a]-i);\n\t\t\t\t\tfor(int m=0; m<5 && i>3; m++){\n\t\t\t\t\t\tif(m == 0){ if(b == 0) continue; baai*=b; b--; nc+=2; }\n\t\t\t\t\t\tif(m == 1){ if(c == 0) continue; baai*=c; c--; nc++; nd++; }\n\t\t\t\t\t\tif(m == 2){ if(d == 0) continue; baai*=d; d--; nc++; nd++; }\n\t\t\t\t\t\tif(m == 3){ if(e == 0) continue; baai*=e; e--; nd+=2; }\n\t\t\t\t\t\tif(m == 4){ if(f == 0) continue; baai*=f; f--; nc+=2; }\n\t\t\t\t\t\tret += baai * solve(a+1, b+d+e, nc, nd, A[a]-i);\n\t\t\t\t\t\tif(m == 0){ b++; nc-=2; baai/=b; }\n\t\t\t\t\t\tif(m == 1){ c++; nc--; nd--; baai/=c; }\n\t\t\t\t\t\tif(m == 2){ d++; nc--; nd--; baai/=d; }\n\t\t\t\t\t\tif(m == 3){ e++; nd-=2; baai/=e; }\n\t\t\t\t\t\tif(m == 4){ f++; nc-=2; baai/=f; }\n\t\t\t\t\t}\n\t\t\t\t\tif(l == 0){ b++; nc-=2; baai/=b; }\n\t\t\t\t\tif(l == 1){ c++; nc--; nd--; baai/=c; }\n\t\t\t\t\tif(l == 2){ d++; nc--; nd--; baai/=d; }\n\t\t\t\t\tif(l == 3){ e++; nd-=2; baai/=e; }\n\t\t\t\t\tif(l == 4){ f++; nc-=2; baai/=f; }\n\t\t\t\t}\n\t\t\t\tif(k == 0){ b++; nc-=2; baai/=b; }\n\t\t\t\tif(k == 1){ c++; nc--; nd--; baai/=c; }\n\t\t\t\tif(k == 2){ d++; nc--; nd--; baai/=d; }\n\t\t\t\tif(k == 3){ e++; nd-=2; baai/=e; }\n\t\t\t\tif(k == 4){ f++; nc-=2; baai/=f; }\n\t\t\t}\n\t\t\tif(j == 0){ b++; nc-=2; baai/=b; }\n\t\t\tif(j == 1){ c++; nc--; nd--; baai/=c; }\n\t\t\tif(j == 2){ d++; nc--; nd--; baai/=d; }\n\t\t\tif(j == 3){ e++; nd-=2; baai/=e; }\n\t\t\tif(j == 4){ f++; nc-=2; baai/=f; }\n\t\t}\n\t}\n\treturn dp[a][b][c][d][e] = ret%MOD;\n}\n\nint main(){\n\tscanf(\"%d\", &N);\n\tfor(int i=0; i<N; i++) scanf(\"%d%\", A+i);\n\tsum[0] = 1;\n\tfor(int i=1; i<N; i++) sum[i] = sum[i-1] + A[i-1];\n\tprintf(\"%d\\n\", solve(0,0,0,0,0));\n}", "accuracy": 1, "time_ms": 2840, "memory_kb": 20272, "score_of_the_acc": -1.2104, "final_rank": 6 }, { "submission_id": "aoj_0657_3464532", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nconst int MAX = 2100;\nconst int MOD = 10007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\nvoid COMinit(){\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for(int i = 2; i < MAX; i++){\n fac[i] = fac[i-1] * i % MOD;\n inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;\n finv[i] = finv[i-1] * inv[i] % MOD;\n }\n}\nlong long COM(int n, int k){\n if(n < k) return 0;\n if (n < 0 || k < 0) return 0;\n return fac[n] * (finv[k] * finv[n-k] % MOD) % MOD;\n}\n\nlong long dp[110][410][10][10][5] = {0}; // a <= 401, b <= 8, c <= 8, d <= 3\nint main() {\n COMinit();\n int N; cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n \n dp[0][0][0][0][0] = 1;\n int s = 0;\n for (int i = 0; i < N; ++i) {\n for (int a = 0; a <= 401; ++a) {\n for (int b = 0; b <= 8; ++b) {\n for (int c = 0; c <= 8; ++c) {\n for (int d = 0; d <= 3; ++d) {\n int e = s + 1 - a - b - c - d;\n if (e < 0) continue;\n if (!dp[i][a][b][c][d]) continue;\n\n for (int a2 = 0; a2 <= a; ++a2) {\n for (int b2 = 0; b2 <= b && a2 + b2 <= A[i]; ++b2) {\n for (int c2 = 0; c2 <= c && a2 + b2 +c2 <= A[i]; ++c2) {\n for (int d2 = 0; d2 <= d && a2 + b2 +c2 + d2 <= A[i]; ++d2) {\n for (int e2 = 0; e2 <= e && a2 + b2 +c2 + d2 + e2 <= A[i]; ++e2) {\n int s2 = a2 + b2 + c2 + d2 + e2;\n int r2 = A[i] - s2;\n long long fact = COM(a, a2);\n fact = (fact * COM(b, b2)) % MOD;\n fact = (fact * COM(c, c2)) % MOD;\n fact = (fact * COM(d, d2)) % MOD;\n fact = (fact * COM(e, e2)) % MOD;\n fact = (fact * COM(r2 + s2 - 1, r2)) % MOD;\n \n int na = a + c + d - a2 - c2 - d2;\n int nb = (a2 + e2) * 2 + b2 + c2;\n int nc = b2 + c2 + d2 * 2;\n int nd = r2;\n //int ne = b + e - b2 - e2;\n dp[i+1][na][nb][nc][nd] += dp[i][a][b][c][d] * fact % MOD;\n dp[i+1][na][nb][nc][nd] %= MOD;\n }\n }\n }\n }\n }\n }\n }\n }\n }\n s += A[i];\n }\n long long res = 0;\n for (int b = 0; b <= 8; ++b) res = (res + dp[N][0][b][0][0]) % MOD;\n for (int i = 0; i < N; ++i) res = (res * fac[A[i]]) % MOD;\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 1360, "memory_kb": 80620, "score_of_the_acc": -1.4539, "final_rank": 7 } ]
aoj_0656_cpp
イルミネーション (Illumination) 問題文 JOI 氏は,自宅の敷地に N 本の木を所有している.これらの木は一列に並んでおり,順に 1 から N までの整数で番号が付けられている. この冬,JOI 氏はいくつかの木を選んで,イルミネーションを飾り付けることにした.イルミネーションには 美しさ と呼ばれる値が定まっている.木 i にイルミネーションを飾り付ける場合の美しさは A_i である. JOI 氏は,あまりに近い 2 つの木の両方にイルミネーションを飾り付けてしまうと,眩しすぎる場合があることに気がついた.具体的には, j = 1, 2, ..., M に対して,木 L_j , L_j + 1 , ... , R_j のうち 2 つ以上にイルミネーションを飾り付けるべきではないということが判明した. この条件に従ってイルミネーションを飾り付けるときの,美しさの合計の最大値を求めよ. 制約 1 ≦ N ≦ 200000 (= 2×10^5) 1 ≦ M ≦ 200000 (= 2×10^5) 1 ≦ A_i ≦ 1000000000 (= 10^9) ( 1 ≦ i ≦ N ) 1 ≦ L_j ≦ R_j ≦ N ( 1 ≦ j ≦ M ) 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N M A_1 A_2 ... A_N L_1 R_1 L_2 R_2 ⋮ L_M R_M 出力 イルミネーションの美しさの合計の最大値を 1 行で出力せよ. 入出力例 入力例 1 4 1 1 2 3 8 2 4 出力例 1 9 この入力例では,木 1 , 4 にイルミネーションを飾り付けると,美しさの合計が 9 となり最大となる. L_1 = 2 , R_1 = 4 なので,木 2 , 3 , 4 のうち 2 つ以上にイルミネーションを飾り付けることはできない.例えば木 1 , 2 , 4 にイルミネーションを飾り付けることはできないことに注意せよ. 入力例 2 5 2 2 3 9 5 6 1 3 2 4 出力例 2 15 入力例 3 20 10 870851814 594414687 615919461 65033245 460143082 617460823 881870957 126041265 623075703 34130727 27054628 853567651 483228744 491145755 220689940 148007930 229257101 790404982 612186806 281076231 15 19 20 20 12 13 1 4 19 19 9 13 3 6 9 12 16 16 18 19 出力例 3 4912419478 情報オリンピック日本委員会作 『第 18 回日本情報オリンピック JOI 2018/2019 予選競技課題』
[ { "submission_id": "aoj_0656_10334793", "code_snippet": "#include <iostream>\n#include <string.h>\n#include <map>\n#include <queue>\nusing namespace std;\n\nconst int S=200010;\nstruct E{\n\tint l,r;\n\tbool operator<(const E& e1) const {\n\t\tif(l!=e1.l)return l>e1.l;\n\t\treturn r>e1.r;\n\t}\n};\n\nint main() {\n\t// your code goes here\n\tlong long int memo1[S];\n\tlong long int memo2[S];\n\tlong long int dp[S];\n\tlong long int data[S];\n\tlong long int n,m;\n\tmap<int,int> memo3;\n\tpriority_queue<E> pq;\n\tmemset(memo1,0,sizeof(memo1));\n\tmemset(memo2,0,sizeof(memo2));\n\tmemset(dp,0,sizeof(dp));\n\tcin>>n>>m;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>data[i];\n\t}\n\tdp[n]=0;\n\tE e1;\n\tfor(int i=0;i<m;i++){\n\t\tint l,r;\n\t\tcin>>l>>r;\n\t\tmemo1[r]++;\n\t\te1.l=l-1;\n\t\te1.r=r;\n\t\tpq.push(e1);\n\t}\n\n\tfor(int i=0;i<=n;i++){\n\t\twhile(pq.size()>0 && pq.top().l<=i){\n\t\t\tE e1=pq.top();\n\t\t\tpq.pop();\n\t\t\tmemo3[e1.r]++;\n\t\t}\n\t\tmemo3[i]-=memo1[i];\n\t\tif(memo3[i]==0){\n\t\t\tmemo3.erase(i);\n\t\t}\n\t\t\n\t\tif(memo3.size()==0||(i+1==n)){\n\t\t\tmemo2[i]=i+1;\t\n\t\t}else{\n\t\t\tmap<int,int>::iterator it=memo3.end();\n\t\t\tit--;\n\t\t\tmemo2[i]=(*it).first;\n\t\t}\n\t\t\n\t}\n\tfor(int i=0;i<n;i++){\n\t\t//cout<<i<<\" \"<<memo2[i]<<endl;\n\t\tlong long int t=dp[i]+data[i];\n\t\tif(dp[memo2[i]]<t)dp[memo2[i]]=t;\n\t\tif(dp[i+1]<dp[i])dp[i+1]=dp[i];\n\t}\n\tlong long int ans=0;\n\tfor(int i=0;i<=n;i++){\n\t\tif(ans<dp[i])ans=dp[i];\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 13044, "score_of_the_acc": -1.3289, "final_rank": 18 }, { "submission_id": "aoj_0656_9739889", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nvoid solve()\n{\n int n, m;\n cin >> n >> m;\n\n vector<int> a(n + 1);\n\n for (int i = 1; i <= n; i++)\n cin >> a[i];\n\n vector<int> prev(n + 1);\n\n for (int i = 1; i <= n; i++)\n prev[i] = i - 1;\n\n for (int i = 1; i <= m; i++)\n {\n int l, r;\n cin >> l >> r;\n prev[r] = min(prev[r], l - 1);\n }\n\n for (int i = n - 1; i >= 1; i--)\n prev[i] = min(prev[i], prev[i + 1]);\n\n vector<long long> dp(n + 1);\n\n dp[0] = 0;\n\n for (int i = 1; i <= n; i++)\n dp[i] = max(dp[i - 1], dp[prev[i]] + a[i]);\n\n cout << dp[n] << '\\n';\n}\n\nint main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5976, "score_of_the_acc": -0.0041, "final_rank": 2 }, { "submission_id": "aoj_0656_9568845", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M;\n cin>>N>>M;\n vector<ll> A(N);\n for(int i=0;i<N;i++)cin>>A[i];\n vector<vector<ll>> P(N+2);\n for(int i=0;i<M;i++){\n ll L,R;\n cin>>L>>R;\n P[L].push_back(L);\n P[R+1].push_back(-L);\n }\n multiset<ll> S;\n vector<ll> DP(N+1,-1e18),SDP(N+1,-1e18);\n DP[0]=SDP[0]=0;\n for(int i=0;i<N;i++){\n for(auto s:P[i+1]){\n if(s>=0)S.insert(s);\n else S.erase(S.find(-s));\n }\n if(S.empty()){\n DP[i+1]=SDP[i]+A[i];\n }\n else{\n ll s=*(S.begin());\n DP[i+1]=SDP[s-1]+A[i];\n }\n SDP[i+1]=max(SDP[i],DP[i+1]);\n }\n cout<<SDP[N]<<endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 21624, "score_of_the_acc": -1.4375, "final_rank": 19 }, { "submission_id": "aoj_0656_9540064", "code_snippet": "#include <iostream>\n#include <cstdint>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n\tuint32_t N, M, i, j, prev;\n\tcin >> N >> M;\n\tvector<uint32_t> A(N);\n\tvector<uint64_t> dp(N + 1);\n\tvector<pair<uint32_t, uint32_t>> LR(M);\n\tfor (i = 0; i != N; ++i) cin >> A[i];\n\tfor (i = 0; i != M; ++i) cin >> LR[i].first >> LR[i].second, --LR[i].first;\n\n\tsort(LR.begin(), LR.end());\n\tdp[0] = 0;\n\tfor (i = 0, j = 0; i != N; ++i)\n\t{\n\t\twhile (j != M && LR[j].second <= i) ++j;\n\n\t\tif (j != M) dp[i + 1] = max(dp[min(i, LR[j].first)] + A[i], dp[i]);\n\t\telse dp[i + 1] = dp[i] + A[i];\n\t}\n\n\tcout << dp[N] << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7044, "score_of_the_acc": -0.1345, "final_rank": 4 }, { "submission_id": "aoj_0656_9100175", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n, m;\n cin >> n >> m;\n vector<ll> a(n);\n for (int i = 0; i < n; i++) {\n cin >> a[i];\n }\n vector<int> r(n, -1);\n for (int i = 0; i < m; i++) {\n int x, y;\n cin >> x >> y;\n x -= 1, y -= 1;\n r[x] = max(r[x], y);\n }\n for (int i = 1; i < n; i++) {\n r[i] = max(r[i], r[i - 1]);\n }\n vector<ll> dp(n + 1);\n for (int i = 0; i < n; i++) {\n if (r[i] <= i) {\n dp[i + 1] = max(dp[i + 1], dp[i] + a[i]);\n } else {\n dp[r[i] + 1] = max(dp[r[i] + 1], dp[i] + a[i]);\n }\n dp[i + 1] = max(dp[i + 1], dp[i]);\n }\n cout << dp[n] << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6988, "score_of_the_acc": -0.0685, "final_rank": 3 }, { "submission_id": "aoj_0656_8319656", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n, m, l, r, mae[200002];\n long long a[200002], ma[200002];\n cin >> n >> m;\n for(int i=1;i<=n;i++){\n cin >> a[i];\n mae[i] = i-1;\n }\n for(int i=0;i<m;i++){\n cin >> l >> r;\n mae[r] = min(mae[r], l-1);\n }\n int mi = mae[n];\n for(int i=n-1;i>0;i--){\n mi = min(mi, mae[i]);\n mae[i] = mi;\n }\n ma[0] = 0;\n for(int i=1;i<=n;i++) ma[i] = max(ma[i-1], ma[mae[i]]+a[i]);\n cout << ma[n] << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 6868, "score_of_the_acc": -0.6858, "final_rank": 12 }, { "submission_id": "aoj_0656_7072152", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <limits>\n#include <numeric>\n#include <type_traits>\n#include <bitset>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <random>\n\nusing namespace std;\n\n#define rep(i,n,m) for(ll (i)=(n);(i)<(m);(i)++)\n#define rrep(i,n,m) for(ll (i)=(n);(i)>(m);(i)--)\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll inf = 1e9;\nconst ll INF = 1e17;\n\nvoid pline(vector<ll> lis){\n rep(i,0,lis.size()){\n printf (\"%lld\",lis[i]);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\nvoid pline(vector<pair<ll,ll>> lis){\n rep(i,0,lis.size()){\n printf (\"/%lld,%lld/\",lis[i].first,lis[i].second);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\n/*\nvoid pmap(map<ll,mint>& lis){\n for (auto p : lis){\n printf (\"%lld:%lld ,\",p.first,p.second.val());\n }\n printf (\"\\n\");\n}*/\n\n\nint main(){\n\n //ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n\n ll N,M;\n cin >> N >> M;\n\n vector<ll> A(N);\n rep(i,0,N) cin >> A[i];\n\n vector<vector<ll>> LtR(N);\n\n rep(i,0,M){\n ll L,R;\n cin >> L >> R;\n L--;R--;\n LtR[L].push_back(R);\n }\n\n vector<ll> ans(N+1,0);\n\n ll nmx = 0;\n ll lastmax = 0;\n\n rep(i,0,N){\n nmx = max(i,nmx);\n for (ll r : LtR[i]) nmx = max(nmx,r);\n lastmax = max(lastmax , ans[i]);\n\n ans[nmx+1] = max(ans[nmx+1] , lastmax + A[i]);\n }\n\n ll mans = 0;\n rep(i,0,N+1) mans = max(ans[i],mans);\n cout << mans << endl;\n\n}\n\n/*\n\n区間だよなぁ\ndp[i] = フリー区間の最左がiの時の最大値\n\n*/", "accuracy": 1, "time_ms": 110, "memory_kb": 14692, "score_of_the_acc": -1.0588, "final_rank": 16 }, { "submission_id": "aoj_0656_7072058", "code_snippet": "#include<bits/stdc++.h>\n\n#include <algorithm>\n\n#ifdef _MSC_VER\n#include <intrin.h>\n#endif\n\nnamespace atcoder {\n\nnamespace internal {\n\n// @param n `0 <= n`\n// @return minimum non-negative `x` s.t. `n <= 2**x`\nint ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n}\n\n// @param n `1 <= n`\n// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`\nint bsf(unsigned int n) {\n#ifdef _MSC_VER\n unsigned long index;\n _BitScanForward(&index, n);\n return index;\n#else\n return __builtin_ctz(n);\n#endif\n}\n\n} // namespace internal\n\n} // namespace atcoder\n\n#include <cassert>\n#include <vector>\n\nnamespace atcoder {\n\ntemplate <class S, S (*op)(S, S), S (*e)()> struct segtree {\n public:\n segtree() : segtree(0) {}\n segtree(int n) : segtree(std::vector<S>(n, e())) {}\n segtree(const std::vector<S>& v) : _n(int(v.size())) {\n log = internal::ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\n} // namespace atcoder\n\nusing namespace std;\nusing namespace atcoder;\n\nusing S = long long;\nS op(S l, S r){\n\tif(l >= r) return l;\n\telse return r;\n}\n\nS e(){\n\treturn 0;\n}\n\nvoid solve(){\n\tint n, m;\n\tcin >> n >> m;\n\tvector<long long> A(n);\n\tfor(auto &a:A) cin >> a;\n\tvector<int> mi(n);\n\tfor(int i = 0; i < n; i++) mi[i] = i;\n\tint l, r;\n\tfor(int i = 0; i < m; i++){\n\t\tcin >> l >> r;\n\t\tl--; r--;\n\t\tmi[r] = min(mi[r], l);\n\t}\n\tfor(int i = n - 2; i >= 0; i--) mi[i] = min(mi[i], mi[i + 1]);\n\tsegtree<S, op, e> seg(n + 1);\n\tfor(int r = 0; r < n; r++){\n\t\tlong long ma = seg.prod(0, mi[r] + 1);\n\t\tseg.set(r + 1, ma + A[r]);\n\t}\n\t\n\tcout << seg.all_prod() << \"\\n\";\n\n}\n\nint main(){\n cin.tie(0)->sync_with_stdio(0);\n int t;\n t = 1;\n // cin >> t;\n while(t--) solve();\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 10936, "score_of_the_acc": -0.3823, "final_rank": 10 }, { "submission_id": "aoj_0656_7071992", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll n,m;cin>>n>>m;\n\tvector<ll>a(n);\n\trep(i,0,n)cin>>a[i];\n\tvector<ll>l(m),r(m);\n\trep(i,0,m)cin>>l[i]>>r[i],l[i]--;\n\tvector<ll>mx(n);\n\trep(i,0,n)mx[i]=i+1;\n\trep(i,0,m){\n\t\tchmax(mx[l[i]],r[i]);\n\t}\n\trep(i,0,n){\n\t\tchmax(mx[i+1],mx[i]);\n\t}\n\tvector<ll>dp(n+1,-INF);\n\tdp[0]=0;\n\trep(i,0,n){\n\t\tchmax(dp[i+1],dp[i]);\n\t\tchmax(dp[mx[i]],dp[i]+a[i]);\n\t}\n\tcout<<dp[n]<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10584, "score_of_the_acc": -0.2974, "final_rank": 9 }, { "submission_id": "aoj_0656_6996491", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0656.cc: イルミネーション (Illumination)\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 200000;\n\n/* typedef */\n\ntypedef long long ll;\n\n/* global variables */\n\nint as[MAX_N], nbrs[MAX_N];\nll dp[MAX_N + 1];\n\n/* subroutines */\n\ninline void setmax(ll &a, ll b) { if (a < b) a = b; }\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; i++) scanf(\"%d\", as + i);\n\n for (int i = 0; i < n; i++) nbrs[i] = i + 1;\n\n for (int i = 0; i < m; i++) {\n int l, r;\n scanf(\"%d%d\", &l, &r), l--;\n nbrs[l] = max(nbrs[l], r);\n }\n\n for (int i = 0; i < n; i++) {\n setmax(dp[i + 1], dp[i]);\n\n if (i > 0) nbrs[i] = max(nbrs[i], nbrs[i - 1]);\n setmax(dp[nbrs[i]], dp[i] + as[i]);\n }\n\n printf(\"%lld\\n\", dp[n]);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5912, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0656_6773562", "code_snippet": "#line 1 \"solve/main.cpp\"\n#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <chrono>\n#include <cmath>\n#include <complex>\n#include <cstdint>\n#include <cstdlib>\n#include <deque>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <memory>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <type_traits>\n#include <unordered_map>\n#include <utility>\n#include <vector>\n\n/* template start */\n\n#line 2 \"lib/utility/type_alias.hpp\"\n\n#line 4 \"lib/utility/type_alias.hpp\"\n\nusing u64 = std::uint64_t;\nusing u32 = std::uint32_t;\nusing u16 = std::uint16_t;\nusing u8 = std::uint8_t;\n\nusing i64 = std::int64_t;\nusing i32 = std::int32_t;\nusing i16 = std::int16_t;\nusing i8 = std::int8_t;\n\nusing usize = std::size_t;\nusing isize = std::ptrdiff_t;\n\nconstexpr i64 operator\"\" _i64(unsigned long long num) { return i64(num); }\n\nconstexpr u64 operator\"\" _u64(unsigned long long num) { return u64(num); }\n#line 33 \"solve/main.cpp\"\n\n#define rep(i, a, b) for (i64 i = (a); (i) < (b); (i)++)\n#define all(i) i.begin(), i.end()\n\n#ifdef LOCAL\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n\nvoid debug_out() { std::cerr << std::endl; }\n\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cerr << \" :\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, std::pair<T1, T2> pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, std::vector<T> vec) {\n for (std::size_t i = 0; i < vec.size(); i++)\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n return os;\n}\n\ntemplate <typename T1, typename T2>\ninline bool chmax(T1& a, T2 b) {\n return a < b && (a = b, true);\n}\n\ntemplate <typename T1, typename T2>\ninline bool chmin(T1& a, T2 b) {\n return a > b && (a = b, true);\n}\n\ntemplate <typename Num, typename Func = std::multiplies<Num>>\nconstexpr Num mypow(Num a, u64 b, Num id = 1, Func mul = Func()) {\n if (b == 0) return id;\n Num x = id;\n while (b > 0) {\n if (b & 1) x = mul(x, a);\n a = mul(a, a);\n b >>= 1;\n }\n return x;\n}\n\n/* template end */\n\nusing P = std::pair<i64,i64>;\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n i64 n,m;\n std::cin>>n>>m;\n\n std::vector<i64> a(n);\n \n for(auto&& e:a)std::cin>>e;\n\n std::vector<P> seg(m);\n\n for(auto&& [l,r]:seg)std::cin>>l>>r;\n std::sort(all(seg));\n\n debug(seg);\n\n std::vector<i64> dp(n+1);\n std::priority_queue<P,std::vector<P>,std::greater<P>> pq;\n\n dp[0] = 0;\n\n i64 seg_count = 0;\n\n rep(i,1,n+1){\n pq.emplace(i,i);\n while(seg_count < m && seg[seg_count].first == i){\n debug(i,seg[seg_count]);\n pq.emplace(seg[seg_count]);\n seg_count++;\n }\n\n P left_seg = pq.top();\n while(left_seg.second < i){\n pq.pop();\n left_seg = pq.top();\n }\n\n dp[i] = a[i-1] + dp[left_seg.first-1];\n chmax(dp[i],dp[i-1]);\n }\n\n debug(dp);\n\n std::cout<<dp[n]<<\"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 17764, "score_of_the_acc": -1.0043, "final_rank": 15 }, { "submission_id": "aoj_0656_6686169", "code_snippet": "#include <iostream>\n#include <vector>\n#include <map>\n\nusing namespace std;\nusing Int = int_fast64_t;\n\nint main()\n{\n\tint N, M; cin >> N >> M;\n\tvector<int> A(N); for (auto& a : A) cin >> a;\n\tmap<int, int> L = {{N + 1, N + 1}}, C = {{N, 1}};\n\tfor (int j = 0, Lj, Rj; j < M; ++j) {\n\t\tcin >> Lj >> Rj;\n\t\tif (L.count(Rj) == 0 || L[Rj] > Lj - 2) L[Rj] = Lj - 2;\n\t}\n\tfor (auto [Rj, Lj] : L) ++C[Lj];\n\tvector<Int> S(N, 0);\n\tS[0] = A[0];\n\tfor (int i = 1; i < N; ++i) {\n\t\tfor (; !L.empty() && L.begin()->first <= i; L.erase(L.begin())) {\n\t\t\tif (--C[L.begin()->second] <= 0) C.erase(L.begin()->second);\n\t\t}\n\t\tauto [Li, n] = *C.begin();\n\t\tS[i] = (Int) A[i];\n\t\tif (Li >= 0) S[i] += S[min(i - 1, Li)];\n\t\tif (S[i] < S[i - 1]) S[i] = S[i - 1];\n\t}\n\tcout << S.back() << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 15304, "score_of_the_acc": -1.5978, "final_rank": 20 }, { "submission_id": "aoj_0656_6114427", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcount(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define umap unordered_map\n#define uset unordered_set\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=(ll)1<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){if(a%b==0) return a/b;else return (a/b)+1;}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n vector<ll> a(n);\n in(a);\n vector<vector<int>> t(n);\n int l,r;\n rep(i,m){\n in(l,r);\n t[--l].push_back(r);\n }\n vector<ll> dp(n+1,0);\n priority_queue<int> pq;\n pq.push(-1);\n for(int i=0;i<n;i++){\n for(auto r:t[i])pq.push(r);\n chmax(dp[max(i+1,pq.top())],dp[i]+a[i]);\n chmax(dp[i+1],dp[i]);\n }\n out(dp[n]);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 15576, "score_of_the_acc": -0.7401, "final_rank": 14 }, { "submission_id": "aoj_0656_5526186", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define SIZE 200005\n\n\nll A[SIZE],L[SIZE],dp[SIZE];\n\n\nint main(){\n\n\tll N,M;\n\tscanf(\"%lld %lld\",&N,&M);\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tL[i] = i-1;\n\t}\n\n\tll right,left;\n\n\tfor(ll i = 0; i < M; i++){\n\n\t\tscanf(\"%lld %lld\",&left,&right);\n\n\t\tL[right] = min(L[right],left-1);\n\t}\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tL[i] = min(L[i],L[i+1]);\n\t}\n\n\tdp[0] = 0;\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\t//足さない\n\t\tdp[i] = dp[i-1];\n\n\t\tdp[i] = max(dp[i],dp[L[i]]+A[i]);\n\t}\n\n\tprintf(\"%lld\\n\",dp[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7764, "score_of_the_acc": -0.1804, "final_rank": 5 }, { "submission_id": "aoj_0656_5503732", "code_snippet": "#include<bits/stdc++.h> \nusing namespace std;\nint segsize=1<<18;\n\nlong long getmax(vector<long long> &segtree,int l,int r){\n l+=segsize,r+=segsize;\n long long ret=0;\n while(l<r){\n if(l%2){\n ret=max(ret,segtree[l]);\n l++;\n }\n l/=2;\n if(r%2){\n r--;\n ret=max(ret,segtree[r]);\n }\n r/=2;\n }\n return ret;\n}\nvoid segupd(vector<long long> &segtree,int p,long long v){\n p+=segsize;\n segtree[p]=v;\n p/=2;\n while(p>0){\n segtree[p]=max(segtree[p*2],segtree[p*2+1]);\n p/=2;\n }\n}\n\nint main(){\n int N,M;\n cin>>N>>M;\n vector<long long>A(N);\n for(long long &i:A)cin>>i;\n vector<int>ngto(N+1);\n for(int i=0,a,b;i<M;i++){\n cin>>a>>b;\n ngto[a]=max(ngto[a],b);\n }\n vector<long long>dp1(segsize*2),dp0(segsize*2);\n vector<int>ngindex(N+1);\n iota(ngindex.begin(),ngindex.end(),0);\n for(int i=0,cnt=0;i<=N;i++){\n if(cnt<i)cnt=i;\n while(ngto[i]>=cnt){\n ngindex[cnt++]=i;\n }\n }\n for(int i=1;i<=N;i++){\n segupd(dp0,i,max(getmax(dp0,0,i),getmax(dp1,0,i)));\n segupd(dp1,i,max(getmax(dp1,0,ngindex[i]),getmax(dp0,0,ngindex[i]))+A[i-1]);\n }\n cout<<max(getmax(dp0,0,N+1),getmax(dp1,0,N+1))<<endl;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 14244, "score_of_the_acc": -1.1553, "final_rank": 17 }, { "submission_id": "aoj_0656_5286822", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 200005\n\n\nint L[SIZE];\nll A[SIZE],dp[SIZE];\nvector<int> G[SIZE];\n\nint main(){\n\n\tll N,M;\n\tscanf(\"%lld %lld\",&N,&M);\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tL[i] = i-1; //飾りつけることのできる木の最大index\n\t}\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\tint left,right;\n\n\tfor(int loop = 0; loop < M; loop++){\n\n\t\tscanf(\"%d %d\",&left,&right);\n\t\tL[right] = min(L[right],left-1);\n\t}\n\tfor(ll i = N-1; i >= 1; i--){\n\n\t\tL[i] = min(L[i],L[i+1]);\n\t}\n\n\tdp[0] = 0;\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\t//飾り付けない\n\t\tdp[i] = dp[i-1];\n\n\t\t//飾り着ける\n\t\tdp[i] = max(dp[i],dp[L[i]]+A[i]);\n\t}\n\n\tprintf(\"%lld\\n\",dp[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 11736, "score_of_the_acc": -0.4332, "final_rank": 11 }, { "submission_id": "aoj_0656_5180404", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 200005\n\nll N,M;\nll A[SIZE];\nll L[SIZE],dp[SIZE];\n\nint main(){\n\n\tscanf(\"%lld %lld\",&N,&M);\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t\tL[i] = i;\n\t}\n\n\tll left,right;\n\n\tfor(ll i = 0; i < M; i++){\n\n\t\tscanf(\"%lld %lld\",&left,&right);\n\n\t\tL[right] = min(L[right],left);\n\t}\n\n\tfor(ll i = N-1; i >= 1; i--){\n\n\t\tL[i] = min(L[i],L[i+1]);\n\t}\n\n\tdp[0] = 0;\n\n\tfor(ll i = 1; i <= N; i++){\n\t\t//飾りつけない\n\t\tdp[i] = dp[i-1];\n\n\t\t//飾り着ける\n\t\tdp[i] = max(dp[i],dp[L[i]-1]+A[i]);\n\t}\n\n\tprintf(\"%lld\\n\",dp[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7796, "score_of_the_acc": -0.1824, "final_rank": 6 }, { "submission_id": "aoj_0656_5162824", "code_snippet": "#include<bits/stdc++.h>\n#define int long long\n#define for1(i, n) for(int i = 1; i <= (n);i++)\n#define puts(x) cout << (x) << \"\\n\"\nusing namespace std;\nint n, m, a[234567], l[234567], dp[234567];\nsigned main() {\n\tcin >> n >> m;\n\tfor1(i, n) {\n\t\tcin >> a[i];\n\t\tl[i] = i + 1;\n\t}\n\twhile (m--) {\n\t\tint b, c; cin >> b >> c;\n\t\tl[b] = max(l[b], c + 1);\n\t}\n\tfor1(i, n) {\n\t\tl[i] = max(l[i], l[i - 1]);\n\t\tdp[i] = max(dp[i], dp[i - 1]);\n\t\tdp[l[i]] = max(dp[l[i]], dp[i] + a[i]);\n\t}\n\tputs(dp[n + 1]);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 7688, "score_of_the_acc": -0.738, "final_rank": 13 }, { "submission_id": "aoj_0656_5101738", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define SIZE 200005\n\n\nll N,M;\nll A[SIZE],L[SIZE];\nll dp[SIZE];\n\n\nint main(){\n\n\tscanf(\"%lld %lld\",&N,&M);\n\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t\tL[i] = i-1;\n\t}\n\n\tll left,right;\n\tfor(ll i = 0; i < M; i++){\n\n\t\tscanf(\"%lld %lld\",&left,&right);\n\t\tL[right] = min(L[right],left-1);\n\t}\n\tfor(ll i = N-1; i >= 1; i--){\n\n\t\tL[i] = min(L[i],L[i+1]);\n\t}\n\n\tdp[0] = 0;\n\tfor(ll i = 1; i <= N; i++){\n\n\t\tdp[i] = max(dp[i-1],dp[L[i]]+A[i]);\n\t}\n\n\tprintf(\"%lld\\n\",dp[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 7820, "score_of_the_acc": -0.1839, "final_rank": 7 }, { "submission_id": "aoj_0656_5082655", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 200005\n#define NUM -1\n\nint N,M;\nll A[SIZE],dp[SIZE],dp2[SIZE];\nint L[SIZE];\n\n\nint main(){\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\tfor(int i = 0; i <= N; i++){\n\n\t\tL[i] = i;\n\t}\n\n\tint left,right;\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d %d\",&left,&right);\n\t\tL[right] = min(L[right],left);\n\t}\n\n\tfor(int i = N-1; i >= 1; i--){\n\n\t\tL[i] = min(L[i],L[i+1]);\n\t}\n\n\tfor(int i = 0; i <= N; i++){\n\n\t\tdp[i] = 0;\n\t\tdp2[i] = 0;\n\t}\n\n\tll ans = 0;\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tdp[i] = dp2[L[i]-1]+A[i];\n\t\tdp2[i] = max(dp2[i-1],dp[i]);\n\t\tans = max(ans,dp[i]);\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8536, "score_of_the_acc": -0.2295, "final_rank": 8 } ]
aoj_0648_cpp
美術展(Art Exhibition) JOI 国で美術展が行われることになった.美術展では,国中から集まった様々な美術品が展示される予定である. 展示される美術品の候補として, N 点の美術品が集まった.これらの美術品には 1, 2, ..., N の番号が付けられている.それぞれの美術品には大きさと価値と呼ばれる値が定まっている.美術品 i (1 \leq i \leq N) の大きさは A_i ,価値は B_i である. 美術展では,これらの美術品のうちから1 点以上を選んで展示する.美術展の会場は十分に広く, N 点の美術品すべてを展示することも可能である.しかし,JOI 国の人々の美的感覚のため,美術品の間で大きさの差があまり大きくならないように展示する美術品を選びたい.一方,できるだけ価値の大きい美術品を多く展示したい.そのため,次の条件を満たすように展示する美術品を選ぶことにした: 選んだ美術品の中で,大きさが最大のものの大きさを A_{max} ,最小のものの大きさを A_{min} とする.また,選んだ美術品の価値の総和を S とする. このとき, S - (A_{max} - A_{min}) を最大化する. 課題 展示される美術品の候補の個数と,それぞれの美術品の大きさと価値が与えられたとき, S - (A_{max} - A_{min}) の最大値を求めよ. 入力 標準入力から以下の入力を読み込め. 1 行目には,整数 N が書かれている.これは,展示される美術品の候補の個数を表す. 続く N 行のうちの i 行目( 1 \leq i \leq N ) には,2 個の整数 A_i, B_i が空白を区切りとして書かれている.これらは,美術品 i の大きさが A_i ,価値が B_i であることを表す. 出力 標準出力に, S - (A_{max} - A_{min}) の最大値を1 行で出力せよ. 制限 すべての入力データは以下の条件を満たす. 2 \leq N \leq 500 000. 1 \leq A_i \leq 1 000 000 000 000 000 = 10^{15} (1 \leq i \leq N). 1 \leq B_i \leq 1 000 000 000 (1 \leq i \leq N). 入出力例 入力例1 3 2 3 11 2 4 5 出力例1 6 この入力例では,展示される美術品の候補が3 点ある.それぞれの美術品の大きさ,価値は次の通りである. 美術品1 の大きさは2,価値は3 である. 美術品2 の大きさは11,価値は2 である. 美術品3 の大きさは4,価値は5 である. この場合,美術品1 と美術品3 を展示するために選ぶと,次のようにして S - (A_{max} - A_{min}) = 6 となる. 選んだ中で大きさが最大の美術品は,美術品3 である.よって, A_{max} = 4 である. 選んだ中で大きさが最小の美術品は,美術品1 である.よって, A_{min} = 2 である. 選んだ美術品の価値の総和は 3 + 5 = 8 であるから, S = 8 である. S - (A_{max} - A_{min}) を7 以上にすることは不可能なので,6 を出力する. 入力例2 6 4 1 1 5 10 3 9 1 4 2 5 3 出力例2 7 入力例3 15 1543361732 260774320 2089759661 257198921 1555665663 389548466 4133306295 296394520 2596448427 301103944 1701413087 274491541 2347488426 912791996 2133012079 444074242 2659886224 656957044 1345396764 259870638 2671164286 233246973 2791812672 585862344 2996614635 91065315 971304780 488995617 1523452673 988137562 出力例3 4232545716 情報オリンピック日本委員会作 『第17 回日本情報オリンピック(JOI 2017/2018) 本選』
[ { "submission_id": "aoj_0648_10852899", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\n#define each(i,a) for (auto&& i : a)\n#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)\n#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)\n#define REP(i,n) FOR(i,0,n)\n#define RREP(i,n) RFOR(i,0,n)\n#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME\n#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)\n#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)\n#define pb push_back\n#define all(a) (a).begin(),(a).end()\n#define chmin(x,v) x = min(x, v)\n#define chmax(x,v) x = max(x, v)\n\nconst ll linf = 1e18;\nconst double eps = 1e-12;\nconst double pi = acos(-1);\n\ntemplate<typename T>\nistream& operator>>(istream& is, vector<T>& vec) {\n each(x,vec) is >> x;\n return is;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector<T>& vec) {\n rep(i,vec.size()) {\n if (i) os << \" \";\n os << vec[i];\n }\n return os;\n}\ntemplate<typename T>\nostream& operator<<(ostream& os, const vector< vector<T> >& vec) {\n rep(i,vec.size()) {\n if (i) os << endl;\n os << vec[i];\n }\n return os;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(0);\n ll n; cin >> n;\n vector<P> v;\n rep(i, n) {\n ll a, b; cin >> a >> b;\n v.pb({a, b});\n }\n sort(all(v));\n vector<ll> A(n), B(n);\n rep(i, n) {\n A[i] = v[i].first;\n B[i] = v[i].second;\n }\n vector<ll> S;\n rep(i, n) {\n if (i) S.pb(A[i-1] - A[i]);\n S.pb(B[i]);\n }\n ll ans = -linf;\n ll sum = 0, mn = 0;\n rep(i, S.size()) {\n sum += S[i];\n chmax(ans, sum - mn);\n chmin(mn, sum);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 32740, "score_of_the_acc": -0.7392, "final_rank": 18 }, { "submission_id": "aoj_0648_10544062", "code_snippet": "#include<bits/stdc++.h>\n#define ll long long\nconst int N=1e6+5;\n#define pii pair<ll,ll>\n#define fi first\n#define se second\n#define F(i,a,b,c) for(int i=a;i<=b;i+=c)\n#define fo(i,a,b,c) for(int i=a;i>=b;i-=c)\nconst int MOD=1e9+7;\n#define el cout<<'\\n'\nusing namespace std;\nint n;\npii a[N];\nll s[N];\nint main()\n{\n ios_base::sync_with_stdio(0);\n cin.tie(0);cout.tie(0);\n if(fopen(\".inp\",\"r\"))\n {\n freopen(\".inp\",\"r\",stdin);\n freopen(\".out\",\"w\",stdout);\n }\n //input:\n cin>>n;\n F(i,1,n,1) cin>>a[i].fi>>a[i].se;\n sort(a+1,a+n+1);\n F(i,1,n,1) s[i]=s[i-1]+a[i].se;\n clock_t begin = clock();\n //code:\n ll ans=-1e18;\n ll ma=a[1].fi;\n F(i,1,n,1)\n {\n ll v=s[i]-a[i].fi+ma;\n ans=max(ans,v);\n if(i<n)\n {\n ma=max(ma,a[i+1].fi-s[i]);\n }\n }\n cout<<ans;el;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 17784, "score_of_the_acc": -0.2257, "final_rank": 13 }, { "submission_id": "aoj_0648_10543889", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define fi first\n#define se second\n#define pb push_back\n#define task \"\"\nconst int nmax = 5e5 + 5;\nconst ll mod = 1e9 + 7;\nconst int inf = 1e9;\nconst ll linf = 1e18;\nint n;\npair<ll, ll> node[nmax];\nll pre[nmax], mn[nmax];\n\nint main() {\n\tios::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\t// freopen(task\".inp\", \"r\", stdin);\n\t// freopen(task\".out\", \"w\", stdout);\n\tcin >> n;\n\tfor (int i = 1; i <= n; ++i) {\n\t\tcin >> node[i].fi >> node[i].se;\n\t}\n\tll ans = -linf;\n\tsort(node + 1, node + 1 + n);\n\tfor (int i = 1; i <= n; ++i) {\n\t\tpre[i] = pre[i - 1] + node[i].se;\n\t\t// cout << pre[i] << ' ';\n\t}\n\tmn[0] = linf;\n\t// cout << '\\n';''\n\tfor (int i = 1; i <= n; ++i) {\n\t\tmn[i] = min(mn[i - 1], pre[i - 1] - node[i].fi);\n\t\t// cout << mn[i] << ' ';\n\t}\n\tfor (int i = 1; i <= n; ++i) {\n\t\tans = max(ans, pre[i] - node[i].fi - mn[i]);\n\t}\n\t// cout << ans;\n\tcout << ans << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 19088, "score_of_the_acc": -0.2665, "final_rank": 15 }, { "submission_id": "aoj_0648_10543871", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std ; \n\n\n#define ll long long \n#define fast ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define fir first \n#define sec second \n#define piint pair < int , int >\n#define FOR( i , a , b ) for (int i = (a) , _b = (b) ; i <= _b ; i ++ ) \n#define pb push_back \n#define str string \n#define ALL(a) (a).begin() , (a).end() \n#define rep( i , a , b) for (int i = (a) ; i < (b) ; i ++ )\n#define ld long double\nconst int maxn = 500000;\n#define debug 0\n#define oo (ll)(1e18)\n\n\n\npair < ll ,ll > a[maxn + 3 ] ;\nll save_val[maxn + 3 ]; \nll max_of_save[maxn + 3 ]; \n// map < ll ,\nvoid input(){\n\tint n ; cin >> n ;\n\tFOR ( i , 1 , n ) cin >> a[i].fir >> a[i].sec ;\n\tsort ( a + 1 , a + n + 1 , [&] ( pair < ll , ll > a , pair < ll , ll > b ) { if ( a.fir != b.fir ) return a.fir > b.fir ; else return b.sec >a.sec ; }) ; \n\tfor ( int i = 1 ; i <= n ; i ++ ) {\n\t\tsave_val[i] = save_val[i-1] + a[i].sec ;\n\t}\n\tmax_of_save[n+1] = -1e18 ; \n\tfor ( int i = n ; i >= 1 ; i -- ) {\n\t\tmax_of_save[i] = max ( save_val[i] + a[i].fir , max_of_save[i+1] ) ;\n\t}\n\tll res = -1e18 ;\n\t// ll d = 0 ;\n\tif(debug){\n\t\tFOR ( i , 1 , n ) {\n\t\t\tcout << a[i].fir << ' ' << a[i].sec << '\\n' ;\n\t\t}\n\t}\n\tFOR ( i , 1 , n ) {\n\t\tll val = max_of_save[i] - save_val[i-1] - a[i].fir ;\n\t\tres = max ( res ,val) ;\n\t}\n\tcout << res << '\\n' ;\n}\n#define name \"TASK\" \nint main(){\n fast \n if(fopen(name\".INP\",\"r\")) {\n freopen (name\".INP\",\"r\",stdin);\n freopen (name\".OUT\",\"w\",stdout);\n }\n input() ;\n //cerr << \"\\nTIME: = \" << (1.0*clock())/CLOCKS_PER_SEC << '\\n';\n return(0) ;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 19076, "score_of_the_acc": -0.2661, "final_rank": 14 }, { "submission_id": "aoj_0648_10543775", "code_snippet": "#include <iostream>\n#include <fstream>\n#define f first\n#define se second\n#include <algorithm>\n\nusing namespace std;\nint n;\nlong long res, tmp, sum;\npair<long long,long long>a[500002];\nint main()\n{\n ios_base::sync_with_stdio(false);\n cin.tie(0);cout.tie(0);\n cin>>n;\n for(int i=1;i<=n;i++)\n cin>>a[i].f>>a[i].se;\n sort(a+1,a+n+1,greater<>());\n tmp=a[1].f;\n res=sum=a[1].se;\n for(int i=2;i<=n;i++)\n {\n tmp=min(tmp,sum+a[i].f);\n res=max(res,sum+a[i].se+a[i].f-tmp);\n sum+=a[i].se;\n }\n cout<<res<<'\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 11260, "score_of_the_acc": -0.0215, "final_rank": 4 }, { "submission_id": "aoj_0648_10543301", "code_snippet": "/**\n * author: phuonglinhn09\n * created: 30.05.2025\n */\n\n#include <bits/stdc++.h>\n#define fi first\n#define se second\n\nusing namespace std;\n\ntypedef long long ll;\n\nconst int nmax = 5e5;\nconst ll inf = 1e18;\n\nint n;\npair<ll, ll> a[nmax + 5];\nll s[nmax + 5], dp[nmax + 5];\n\nint main() {\n ios_base::sync_with_stdio(0); \n cin.tie(0); cout.tie(0);\n \n if (fopen (\".INP\", \"r\")) {\n freopen (\".INP\", \"r\", stdin);\n freopen (\".OUT\", \"w\", stdout);\n }\n\n cin >> n;\n\n for (int i = 1; i <= n; i++) {\n cin >> a[i].fi >> a[i].se;\n }\n sort (a + 1, a + 1 + n);\n\n ll tmp = inf;\n for (int i = 1; i <= n; i++) {\n s[i] = s[i - 1] + a[i].se;\n dp[i] = max({dp[i - 1], a[i].se, s[i] - a[i].fi - tmp});\n tmp = min (tmp, s[i - 1] - a[i].fi);\n }\n\n cout << dp[n] << \"\\n\";\n \n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 19092, "score_of_the_acc": -0.2666, "final_rank": 16 }, { "submission_id": "aoj_0648_9893971", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nmaximise: sum - (max_v - min_v) = (sum + min_v) - max_v (hint ?)\nkadane ?\n\nWA\n6\n4 1\n1 5\n10 3\n9 1\n4 2\n5 3\noutput:\n7\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 2147483647;\n\nconst int MAX_N = 100;\nstatic int vect[MAX_N];\n//------------------------------------------------------------------------------\nstruct Pict\n{\n int64_t a, b;\n\n Pict(): a(0), b(0) {}\n Pict(int64_t x1, int64_t x2): a(x1), b(x2) {}\n bool operator<(const Pict& p1) const\n {\n if (a == p1.a) return b < p1.b;\n return a < p1.a;\n }\n void debug() const { printf(\"a=%ld, b=%ld\\n\", a, b); }\n};\n\ntypedef vector<Pict> Picts;\n\n\n//------------------------------------------------------------------------------\nint64_t kadane(int N, const Picts& PP)\n{\n int64_t max_ending_here = PP[0].b;\n int64_t min_a = PP[0].a;\n int64_t max_a = PP[0].a;\n\n int64_t max_so_far = PP[0].b;\n\n for (int i=1; i<N; ++i)\n {\n max_ending_here += max_a + PP[i].b - PP[i].a;\n max_a = PP[i].a;\n\n if (PP[i].b > max_ending_here)\n {\n max_ending_here = PP[i].b;\n min_a = PP[i].a;\n max_a = PP[i].a;\n }\n\n max_so_far = max(max_so_far, max_ending_here);\n if (DEBUG)\n printf(\"i=%d: max_ending_here=%ld, max_a=%ld, min_a=%ld, max_so_far=%ld\\n\",i,max_ending_here,max_a,min_a,max_so_far);\n }\n return max_so_far;\n}\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, num;\n int64_t A, B;\n num = scanf(\"%d \", &N);\n Picts PP(N);\n for (int i=0; i<N; ++i)\n {\n num = scanf(\"%ld %ld \", &A, &B);\n PP[i] = Pict(A, B);\n }\n sort(PP.begin(), PP.end());\n if (DEBUG) {for (Pict p: PP) p.debug();}\n int64_t res = kadane(N, PP);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 100, "memory_kb": 10856, "score_of_the_acc": -0.0089, "final_rank": 2 }, { "submission_id": "aoj_0648_9586581", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define int long long\n#define ii pair<ll, ll>\n#define fi first\n#define se second\nconst int N = 5e5+5;\nint n;\nii a[N];\nmap<ll, ll> mp;\n\nint32_t main() {\n cin.tie(0)->sync_with_stdio(0);\n if (fopen(\"A.inp\", \"r\")) {\n freopen(\"A.inp\", \"r\", stdin);\n freopen(\"A.out\", \"w\", stdout);\n }\n cin >> n;\n for (int i = 1; i <= n; ++i) {\n cin >> a[i].fi >> a[i].se;\n mp[a[i].fi] += a[i].se;\n }\n n = 0;\n for (auto &it : mp) a[++n] = it;\n sort(a+1, a+n+1);\n long long ans = 0, mx = 0;\n for (int i = 1; i <= n; ++i) {\n ans = max(ans, mx - a[i].fi + a[i].se);\n ans = max(ans, a[i].se);\n mx = max(mx + a[i].se, a[i].fi + a[i].se);\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 42528, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0648_9568850", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vector<pair<ll,ll>> P(N);\n for(int i=0;i<N;i++)cin>>P[i].first>>P[i].second;\n sort(P.begin(),P.end());\n vector<ll> A(N),B(N+1,0);\n for(int i=0;i<N;i++){\n A[i]=P[i].first;\n B[i+1]=B[i]+P[i].second;\n }\n ll SM=-1e18;\n ll an=0;\n for(int i=N-1;i>=0;i--){\n SM=max(SM,B[i+1]-A[i]);\n an=max(an,SM+A[i]-B[i]);\n }\n cout<<an<<endl;;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 18844, "score_of_the_acc": -0.3043, "final_rank": 17 }, { "submission_id": "aoj_0648_9477307", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cstdio>\nusing namespace std;\n\ntypedef long long llong;\n\nstruct Data {\n llong size;\n llong value;\n};\n\n#define N_MAX 500000\nvector<Data> art(N_MAX);\n\nbool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\n\nllong Max(llong a, llong b) { return a > b ? a : b; }\n\nint main() {\n int N;\n scanf(\"%d\", &N);\n\n for (int i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].size, &art[i].value);\n }\n\n sort(art.begin(), art.begin() + N, cmp);\n\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n\n for (int i = 1; i < N; ++i) {\n llong value = art[i].value;\n llong size = art[i].size;\n llong tmp = sum_value + value - (size - min_size);\n\n if (tmp < value) {\n ans = Max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = Max(ans, tmp);\n sum_value += value;\n }\n }\n\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 10708, "score_of_the_acc": -0.0497, "final_rank": 5 }, { "submission_id": "aoj_0648_9128141", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n;\n cin >> n;\n vector<pair<ll, ll>> v(n);\n for (int i = 0; i < n; i++) {\n cin >> v[i].first >> v[i].second;\n }\n sort(v.rbegin(), v.rend());\n ll res = 0, sum = 0, mx = -1e18;\n for (int i = 0; i < n; i++) {\n mx = max(mx, -sum - v[i].first);\n sum += v[i].second;\n res = max(res, sum + v[i].first + mx);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 11020, "score_of_the_acc": -0.014, "final_rank": 3 }, { "submission_id": "aoj_0648_8862206", "code_snippet": "#include <algorithm>\n#include <stdio.h>\nusing namespace std;\ntypedef long long llong;\n#define N_MAX 500000\npair<llong, llong> art[N_MAX];\n\nbool cmp(const pair<llong, llong> &a, const pair<llong, llong> &b) {\n return a.first == b.first ? a.second < b.second : a.first < b.first;\n}\nint main(void) {\n int N;\n scanf(\"%d\", &N);\n for (int i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].first, &art[i].second);\n }\n sort(art, art + N, cmp);\n llong min_size = art[0].first;\n llong sum_value = art[0].second;\n llong ans = art[0].second;\n for (int i = 1; i < N; ++i) {\n llong value = art[i].second;\n llong size = art[i].first;\n llong tmp = sum_value + value - (size - min_size);\n if (tmp < value) {\n ans = max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = max(ans, tmp);\n sum_value += value;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10576, "score_of_the_acc": -0.091, "final_rank": 9 }, { "submission_id": "aoj_0648_8862202", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef long long llong;\nstruct Data {\n llong size;\n llong value;\n};\n\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\n\ninline llong Max(llong a, llong b) { return a > b ? a : b; }\n\nint main(void) {\n ios_base::sync_with_stdio(false); \n cin.tie(NULL); \n cout.tie(NULL);\n\n int N;\n cin >> N;\n vector<Data> art(N);\n for (int i = 0; i < N; ++i) {\n cin >> art[i].size >> art[i].value;\n }\n sort(art.begin(), art.end(), cmp);\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n for (int i = 1; i < N; ++i) {\n llong value = art[i].value;\n llong size = art[i].size;\n llong tmp = sum_value + value - (size - min_size);\n if (tmp < value) {\n ans = Max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = Max(ans, tmp);\n sum_value += value;\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 10744, "score_of_the_acc": -0.0508, "final_rank": 6 }, { "submission_id": "aoj_0648_8862201", "code_snippet": "#include <algorithm>\n#include <vector>\n#include <iostream>\nusing namespace std;\ntypedef long long llong;\ntypedef pair<llong, llong> Data;\n#define N_MAX 500000\n\nint main(void) {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int N;\n cin >> N;\n vector<Data> art(N);\n for (int i = 0; i < N; ++i) {\n cin >> art[i].first >> art[i].second;\n }\n sort(art.begin(), art.end());\n llong min_size = art[0].first;\n llong sum_value = art[0].second;\n llong ans = art[0].second;\n for (int i = 1; i < N; ++i) {\n llong tmp = sum_value + art[i].second - (art[i].first - min_size);\n if (tmp < art[i].second) {\n ans = max(ans, art[i].second);\n sum_value = art[i].second;\n min_size = art[i].first;\n } else {\n ans = max(ans, tmp);\n sum_value += art[i].second;\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 10756, "score_of_the_acc": -0.0058, "final_rank": 1 }, { "submission_id": "aoj_0648_8862196", "code_snippet": "#include <algorithm>\n#include <stdio.h>\nusing namespace std;\ntypedef long long llong;\nstruct Data {\n llong size;\n llong value;\n};\n#define N_MAX 500000\nData art[N_MAX];\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\nint main(void) {\n int N;\n scanf(\"%d\", &N);\n int i;\n for (i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].size, &art[i].value);\n }\n sort(art, art + N, cmp);\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n for (i = 1; i < N; ++i) {\n llong value = art[i].value;\n llong size = art[i].size;\n llong tmp = sum_value + value - (size - min_size);\n if (tmp < value) {\n ans = (value > ans) ? value : ans; // Replaced the function call with direct comparison\n sum_value = value;\n min_size = size;\n } else {\n ans = (tmp > ans) ? tmp : ans; // Replaced the function call with direct comparison\n sum_value += value;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10608, "score_of_the_acc": -0.092, "final_rank": 11 }, { "submission_id": "aoj_0648_8862194", "code_snippet": "#include <algorithm>\n#include <stdio.h>\nusing namespace std;\ntypedef long long llong;\n\nstruct Data {\n llong size;\n llong value;\n};\n\n#define N_MAX 500000\nData art[N_MAX];\n\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\n\ninline llong Max(llong a, llong b) { return a > b ? a : b; }\n\nint main(void) {\n int N;\n scanf(\"%d\", &N);\n\n for (int i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].size, &art[i].value);\n }\n\n sort(art, art + N, cmp);\n\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n\n for (int i = 1; i < N; ++i) {\n llong value = art[i].value;\n llong size = art[i].size;\n\n if (sum_value + value - (size - min_size) < value) {\n ans = Max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n llong tmp = sum_value + value - (size - min_size);\n ans = Max(ans, tmp);\n sum_value += value;\n }\n }\n\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10608, "score_of_the_acc": -0.092, "final_rank": 11 }, { "submission_id": "aoj_0648_8862190", "code_snippet": "#include <algorithm>\n#include <stdio.h>\nusing namespace std;\ntypedef long long llong;\nstruct Data {\n llong size;\n llong value;\n};\n#define N_MAX 500000\nData art[N_MAX];\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\ninline llong Max(llong a, llong b) { return a > b ? a : b; }\nint main(void) {\n int N;\n scanf(\"%d\", &N);\n int i;\n for (i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].size, &art[i].value);\n }\n sort(art, art + N, cmp);\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n for (i = 1; i < N; ++i) {\n Data &current = art[i]; // store current element in a local variable to reduce array access\n llong value = current.value;\n llong size = current.size;\n llong tmp = sum_value + value - (size - min_size);\n if (tmp < value) {\n ans = Max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = Max(ans, tmp);\n sum_value += value;\n }\n }\n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10572, "score_of_the_acc": -0.0909, "final_rank": 8 }, { "submission_id": "aoj_0648_8849068", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n #define int long long\n int n;cin>>n;\n vector<pair<int,int>>s(n);\n int sizmi=LONG_LONG_MAX;\n for(int i=0;i<n;i++){\n cin>>s[i].first>>s[i].second;\n sizmi=min(sizmi,s[i].first);\n }\n for(int i=0;i<n;i++){\n s[i].first-=sizmi;\n }\n sort(s.begin(),s.end());\n vector<int>t;\n for(int i=0;i<n;i++){\n t.push_back(s[i].second);\n if(i!=n-1){\n t.push_back(s[i].first-s[i+1].first);\n }\n }\n t.push_back(0);\n\n /*\n for(int i=0;i<n;i++){\n cout<<t[i]<<\" \";\n }cout<<\"\\n\";\n */\n int m=n*2-1;\n int ans=t[0];\n int k=ans;\n int r=0,l=0;\n while(r<=m){\n while(k>=0&&r<m){\n r++;\n k+=t[r];\n ans=max(ans,k);\n if(r==m){\n break;\n }\n //cout<<\"@ \"<<l<<\" \"<<r<<\" \"<<k<<\" \"<<ans<<\"\\n\";\n }\n if(r==m){\n break;\n }\n if(k<0){\n l=r+1;\n r=r+1;\n if(m<l){\n break;\n }\n k=t[l];\n ans=max(ans,k);\n }\n }\n cout<<ans<<\"\\n\";\n /*\n for(int i=0;i<t.size();i++){\n cout<<t[i]<<\" \";\n }cout<<\"\\n\";\n */\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 20948, "score_of_the_acc": -1.2338, "final_rank": 19 }, { "submission_id": "aoj_0648_8820058", "code_snippet": "#include <algorithm>\n#include <stdio.h>\n#include <stddef.h>\n#include <stdint.h>\n\nstruct Data {\n int64_t size;\n int64_t value;\n};\n\nconst int N_MAX = 500000;\nData art[N_MAX];\n\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\n\nint main(void) {\n int N;\n scanf(\"%d\", &N);\n \n for (int i = 0; i < N; ++i) {\n scanf(\"%lld %lld\", &art[i].size, &art[i].value);\n }\n \n std::sort(art, art + N, cmp);\n \n int64_t min_size = art[0].size;\n int64_t sum_value = art[0].value;\n int64_t ans = art[0].value;\n \n for (int i = 1; i < N; ++i) {\n int64_t value = art[i].value;\n int64_t size = art[i].size;\n int64_t tmp = sum_value + value - (size - min_size);\n \n if (tmp < value) {\n ans = std::max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = std::max(ans, tmp);\n sum_value += value;\n }\n }\n \n printf(\"%lld\\n\", ans);\n return 0;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 10600, "score_of_the_acc": -0.0918, "final_rank": 10 }, { "submission_id": "aoj_0648_8820052", "code_snippet": "#include <algorithm>\n#include <iostream>\nusing namespace std;\ntypedef long long llong;\nstruct Data {\n llong size;\n llong value;\n};\n#define N_MAX 500000\nData art[N_MAX];\ninline bool cmp(const Data &a, const Data &b) {\n return a.size == b.size ? a.value < b.value : a.size < b.size;\n}\nint main(void) {\n std::ios_base::sync_with_stdio(false);\n int N;\n cin >> N;\n int i;\n for (i = 0; i < N; ++i) {\n cin >> art[i].size >> art[i].value;\n }\n sort(art, art + N, cmp);\n llong min_size = art[0].size;\n llong sum_value = art[0].value;\n llong ans = art[0].value;\n for (i = 1; i < N; ++i) {\n llong value = art[i].value;\n llong size = art[i].size;\n llong tmp = sum_value + value - (size - min_size);\n if (tmp < value) {\n ans = std::max(ans, value);\n sum_value = value;\n min_size = size;\n } else {\n ans = std::max(ans, tmp);\n sum_value += value;\n }\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 11024, "score_of_the_acc": -0.0596, "final_rank": 7 } ]
aoj_0659_cpp
展覧会(Exhibition) あなたは,絵の展覧会を開催しようとしている.展覧会では,いくつかの絵を額縁に入れ,左から右に一列に並べて展示する. 展覧会で展示する候補となる絵が$N$ 枚あり,1 から$N$ までの番号が付けられている.絵$i$ ($1 \leq i \leq N$) の大きさは$S_i$,価値は$V_i$ である. また,これらの絵を入れるための額縁が$M$ 枚あり,1 から$M$ までの番号が付けられている.額縁$j$ ($1 \leq j \leq M$) の大きさは$C_j$ である.額縁$j$ には,大きさが$C_j$ 以下の絵のみを入れることができる.1 枚の額縁には高々1 枚の絵しか入れることができない. 展示する絵はすべて何らかの額縁に入っていなければならない.見栄えを良くするため,展示する絵は以下の条件を満たさなければならない: 左右に隣り合うどの2 枚の絵についても,右側の絵が入っている額縁の大きさは左側の絵が入っている額縁の大きさ以上である. 左右に隣り合うどの2 枚の絵についても,右側の絵の価値は左側の絵の価値以上である. あなたは,できるだけ多くの絵を展示したい. 展示候補の絵の枚数,額縁の枚数,及びそれらの大きさや価値が与えられたとき,展示する絵の枚数の最大値を求めるプログラムを作成せよ. 入力 入力は以下の形式で標準入力から与えられる. $N$ $M$ $S_1$ $V_1$ : $S_N$ $V_N$ $C_1$ : $C_M$ 出力 標準出力に,展覧会に展示する絵の枚数の最大値を1 行で出力せよ. 制約 $ 1 \leq N \leq 100 000$. $ 1 \leq M \leq 100 000$. $ 1 \leq S i \leq 1 000 000 000 (1 \leq i \leq N)$. $ 1 \leq V_i \leq 1 000 000 000 (1 \leq i \leq N)$. $ 1 \leq C_j \leq 1 000 000 000 (1 \leq j \leq M)$. 入出力例 入力例1 3 4 10 20 5 1 3 5 4 6 10 4 出力例1 2 この入出力例では,左から順に(絵2, 額縁2),(絵1, 額縁3) と並べることで,2 枚の絵を展示することができる.3 枚以上の絵を展示することはできないので,2 を出力する.ここで,(絵$i$, 額縁$j$) は,額縁$j$に入った絵$i$ を表す. 入力例2 3 2 1 2 1 2 1 2 1 1 出力例2 2 入力例3 4 2 28 1 8 8 6 10 16 9 4 3 出力例3 0 入力例4 8 8 508917604 35617051 501958939 840246141 485338402 32896484 957730250 357542366 904165504 137209882 684085683 775621730 552953629 20004459 125090903 607302990 433255278 979756183 28423637 856448848 276518245 314201319 666094038 149542543 出力例4 3 情報オリンピック日本委員会作 『第18 回日本情報オリンピック(JOI 2018/2019) 本選』
[ { "submission_id": "aoj_0659_10848583", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing lint = long long;\n\nstruct painting{\n lint s, v;\n\n bool operator<(const painting &rhs) const {\n return v == rhs.v ? s < rhs.s : v < rhs.v;\n }\n};\n\nint main(){\n int n, m;\n cin >> n >> m;\n\n vector<painting> p(n);\n for(int i = 0 ; i < n ; ++i){\n cin >> p[i].s >> p[i].v;\n }\n sort(p.rbegin(), p.rend());\n\n vector<lint> c(m);\n for(int i = 0 ; i < m ; ++i){\n cin >> c[i];\n }\n sort(c.rbegin(), c.rend());\n\n int ans = 0;\n for(int i = 0 ; i < n && ans < m ; ++i){\n if(p[i].s <= c[ans]){\n ++ans;\n }\n }\n\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5492, "score_of_the_acc": -1.0918, "final_rank": 17 }, { "submission_id": "aoj_0659_9889033", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 2147483647;\n\nconst int MAX_M = 100000;\nstatic int frame[MAX_M];\n\ntypedef pair<int,int> PA;\ntypedef vector<PA> PAS;\n\n//------------------------------------------------------------------------------\nvoid debug_PAS(const PAS& PP)\n{\n for (PA p: PP) printf(\"v=%d, s=%d\\n\", p.first, p.second);\n}\n\nbool compare(const PA& p1, const PA& p2)\n{\n if (p1.first == p2.first) return p1.second > p2.second;\n return p1.first > p2.first;\n}\n\nint greedy(int N, PAS& PP, int M)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n sort(PP.begin(), PP.end(), &compare);\n if (DEBUG) debug_PAS(PP);\n sort(frame, frame+M, greater<int>());\n if (DEBUG) {printf(\"frame: \"); for (int m=0; m<M; ++m) printf(\"%d \",frame[m]); printf(\"\\n\");}\n //--------------------------------------------------------------------------\n // compute:\n int res = 0;\n int m = 0;\n for (int i=0; i<N; ++i)\n {\n if (m < M && PP[i].second <= frame[m])\n {\n res++;\n m++;\n }\n }\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int N, M, s, v, num;\n num = scanf(\"%d %d \", &N, &M);\n PAS PP(N);\n for (int i=0; i<N; ++i)\n {\n num = scanf(\"%d %d \", &s, &v);\n PP[i] = {v, s};\n }\n for (int m=0; m<M; ++m) num = scanf(\"%d \", &frame[m]);\n int res = greedy(N, PP, M);\n printf(\"%d\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 30, "memory_kb": 4520, "score_of_the_acc": -0.264, "final_rank": 4 }, { "submission_id": "aoj_0659_9568813", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M;\n cin>>N>>M;\n vector<pair<ll,ll>> P(N);\n vector<ll> C(M);\n for(int i=0;i<N;i++)cin>>P[i].second>>P[i].first;\n for(int i=0;i<M;i++)cin>>C[i];\n sort(C.begin(),C.end());\n sort(P.begin(),P.end());\n reverse(C.begin(),C.end());\n reverse(P.begin(),P.end());\n ll an=0;\n ll L=0;\n for(int i=0;i<M;i++){\n while(L<N&&C[i]<P[L].second){\n L++;\n }\n if(L<N){\n an++;\n L++;\n }\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5488, "score_of_the_acc": -0.6734, "final_rank": 13 }, { "submission_id": "aoj_0659_9476549", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <functional>\n\nusing namespace std;\ntypedef pair<int, int> Pi;\n\nint main() {\n int n, m, s, v;\n vector<int> c(100002);\n vector<Pi> vec;\n\n cin >> n >> m;\n for (int i = 0; i < n; i++) {\n cin >> s >> v;\n vec.push_back(Pi(v, s));\n }\n\n sort(vec.begin(), vec.end(), greater<Pi>());\n\n for (int i = 0; i < m; i++) {\n cin >> c[i];\n }\n\n sort(c.begin(), c.begin() + m, greater<int>());\n\n int mai = 0;\n for (int i = 0; mai < m && i < n; i++) {\n if (vec[i].second <= c[mai]) {\n mai++;\n }\n }\n\n cout << mai << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4552, "score_of_the_acc": -0.6108, "final_rank": 12 }, { "submission_id": "aoj_0659_9192448", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),M=in();\n\tvector<pair<ll,ll>> P(N);\n\tREP(i,N){\n\t\tP[i].first=in();\n\t\tP[i].second=in();\n\t}\n\tsort(ALL(P),[](const pair<ll,ll>& l,const pair<ll,ll>& r){return (l.second==r.second)?(l.first>r.first):(l.second>r.second);});\n\tvll C=vecin(M);\n\tsort(ALL(C));\n\n\tvll R(M,-1);\n\tREP(i,N){\n\t\tauto [S,V] = P[i];\n\t\tauto res = lower_bound(ALL(C),S);\n\t\tif(res==C.end()) continue;\n\n\t\tauto start = distance(C.begin(),res);\n\t\tres = upper_bound(R.begin()+start,R.end(),-1);\n\t\tif(res==R.begin()+start) continue;\n\t\tif(*(res-1)==-1){\n\t\t\tR[distance(R.begin(),res-1)]=i;\n\t\t}\n\t}\n\tll A=0;\n\tREP(i,M){\n\t\tif(R[i]>=0) A++;\n\t}\n\tout(A);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6260, "score_of_the_acc": -1.0833, "final_rank": 16 }, { "submission_id": "aoj_0659_9150280", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) { return (ull)rng() % B; }\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int n, m;\n cin >> n >> m;\n vector<pair<int, int>> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> v[i].first >> v[i].second;\n }\n sort(v.begin(), v.end());\n vector<int> a(m);\n for (int i = 0; i < m; ++i) {\n cin >> a[i];\n }\n sort(a.begin(), a.end());\n auto slv = [&](int x) -> bool {\n int j = 0, mx = -1;\n priority_queue<int, vector<int>, greater<int>> pq;\n for (int i = m - x; i < m; ++i) {\n while (j < n and v[j].first <= a[i]) {\n pq.push(v[j].second);\n j += 1;\n }\n while (pq.size() and pq.top() < mx)\n pq.pop();\n if (pq.empty()) return false;\n mx = pq.top();\n pq.pop();\n }\n return true;\n };\n int l = 0, r = m + 1;\n while (r - l > 1) {\n int mid = (l + r) / 2;\n if (slv(mid)) l = mid;\n else r = mid;\n }\n cout << l << endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 4888, "score_of_the_acc": -1.4196, "final_rank": 20 }, { "submission_id": "aoj_0659_8755642", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n vector<pair<int, int>> a(n);\n cin >> a;\n sort(all(a), [](auto l, auto r) {\n if (l.second == r.second)\n return l.first > r.first;\n return l.second > r.second;\n });\n vector<int> b(m);\n cin >> b;\n sort(all(b));\n reverse(all(b));\n\n int ans = 0;\n rep (i, n) {\n if (ans < m && a[i].first <= b[ans])\n ++ans;\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4404, "score_of_the_acc": -0.2149, "final_rank": 2 }, { "submission_id": "aoj_0659_8387761", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0659.cc: 展覧会(Exhibition)\n */\n\n#include<cstdio>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\nconst int MAX_M = 100000;\n\n/* typedef */\n\ntypedef pair<int,int> pii;\n\n/* global variables */\n\nint ss[MAX_N], vs[MAX_N], cs[MAX_M];\npii ps[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; i++) scanf(\"%d%d\", ss + i, vs + i);\n for (int i = 0; i < m; i++) scanf(\"%d\", cs + i);\n\n for (int i = 0; i < n; i++) ps[i] = pii(vs[i], ss[i]);\n sort(ps, ps + n);\n sort(cs, cs + m);\n\n int cnt = 0;\n for (int i = n - 1, j = m - 1; i >= 0 && j >= 0; i--)\n if (ps[i].second <= cs[j])\n cnt++, j--;\n\n printf(\"%d\\n\", cnt);\n \n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4912, "score_of_the_acc": -0.4298, "final_rank": 6 }, { "submission_id": "aoj_0659_8324196", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> Pi;\nint main(){\n int n, m, s, v, c[100002];\n vector<Pi> vec;\n cin >> n >> m;\n for(int i=0;i<n;i++){\n cin >> s >> v;\n vec.push_back(Pi(v, s));\n }\n sort(vec.begin(), vec.end(), greater<Pi>());\n for(int i=0;i<m;i++) cin >> c[i];\n sort(c, c+m, greater<int>());\n int mai=0;\n for(int i=0;mai<m&&i<n;i++){\n if(vec[i].second <= c[mai]) mai++;\n }\n cout << mai << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 4156, "score_of_the_acc": -0.61, "final_rank": 11 }, { "submission_id": "aoj_0659_7121140", "code_snippet": "#include <iostream>\n#include <cstdlib>\nusing namespace std;\n\ntypedef struct SandV_{\n int S;\n int V;\n} SandV;\n\n\nint compareC (const void * a, const void * b)\n{\n return ( *(int*)b - *(int*)a );\n}\n\nint compareSV (const void * a, const void * b)\n{\n SandV *SV1=(SandV*) a;\n SandV *SV2=(SandV*) b;\n if(SV1->V < SV2->V) return 1;\n else if (SV1->V > SV2->V) return -1;\n \n if(SV1->S < SV2->S) return 1;\n else if (SV1->S > SV2->S) return -1;\n return 0;\n}\n\nint main(void){\n // Your code here!\n int N,M,S,V;\n cin >> N >>M;\n\n SandV arraySV[N];\n int C[M];\n \n for(int i=0;i<N;i++){\n cin >> S >> V;\n arraySV[i].S=S;\n arraySV[i].V=V;\n } \n \n for(int j=0;j<M;j++){\n cin >>C[j];\n }\n \n qsort(arraySV, N, sizeof(SandV), compareSV);\n qsort(C, M, sizeof(int), compareC);\n \n int count=0;\n int countM=0;\n for(int i=0;i<N;i++){\n if(C[countM]>=arraySV[i].S){\n count+=1;\n countM++;\n if(countM>=M){\n break;\n }\n }\n }\n cout <<count <<endl;\n}", "accuracy": 1, "time_ms": 120, "memory_kb": 4872, "score_of_the_acc": -1.1629, "final_rank": 19 }, { "submission_id": "aoj_0659_7070450", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n int N,M;\n cin>>N>>M;\n vector<pair<int,int> > X1(N);\n vector<int> X2(M);\n for(int i=0;i<N;i++){\n cin>>X1.at(i).second>>X1.at(i).first;\n }\n for(int i=0;i<M;i++){\n cin>>X2.at(i);\n }\n \n sort(X1.begin(),X1.end());\n sort(X2.begin(),X2.end());\n \n \n int count=0;\n int i=M-1;\n int j=N-1;\n while(!X1.empty()&&!X2.empty()){\n if(X1.at(j).second>X2.at(i)){\n X1.pop_back();\n j--;\n } \n else{\n count++;\n X1.pop_back();\n X2.pop_back();\n i--;\n j--;\n }\n }\n \n cout<<count<<endl;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 3896, "score_of_the_acc": -0.5833, "final_rank": 10 }, { "submission_id": "aoj_0659_6990098", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main() {\n int n, m;\n cin >> n >> m;\n\n vector<pair<int, int>> ps(n);\n for (auto&& e : ps)\n cin >> e.first >> e.second;\n sort(ps.begin(), ps.end(), [](pair<int, int> l, pair<int, int> r) {\n if (l.second == r.second)\n return l.first < r.first;\n return l.second < r.second;\n });\n\n vector<int> cs(m);\n for (auto&& e : cs)\n cin >> e; \n sort(cs.begin(), cs.end());\n\n int p = n - 1, c = m - 1, count = 0;\n while (p >= 0 && c >= 0)\n if (cs[c] >= ps[p].first)\n --c, --p, ++count;\n else\n --p;\n cout << count << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4308, "score_of_the_acc": -0.5076, "final_rank": 7 }, { "submission_id": "aoj_0659_6773671", "code_snippet": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <chrono>\n#include <climits>\n#include <cmath>\n#include <cstddef>\n#include <cstdint>\n#include <cstdlib>\n#include <cstring>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <map>\n#include <memory>\n#include <numeric>\n#include <optional>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <tuple>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\n/* macro */\n\n#define rep(i, a, n) for (int i = (int)(a); i < (int)(n); i++)\n#define rrep(i, a, n) for (int i = ((int)(n - 1)); i >= (int)(a); i--)\n#define Rep(i, a, n) for (i64 i = (i64)(a); i < (i64)(n); i++)\n#define RRep(i, a, n) for (i64 i = ((i64)(n - i64(1))); i >= (i64)(a); i--)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define Bit(n) (1LL << (n))\n\n/* macro end */\n\n/* template */\n\nnamespace ebi {\n\n#ifdef LOCAL\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n\nvoid debug_out() { std::cerr << std::endl; }\n\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cout << \" :\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T1, T2> &pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\ntemplate <typename T1, typename T2>\nstd::istream &operator>>(std::istream &os, std::pair<T1, T2> &pa) {\n return os >> pa.first >> pa.second;\n}\n\ntemplate <typename T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &vec) {\n for (std::size_t i = 0; i < vec.size(); i++)\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n return os;\n}\n\ntemplate <typename T>\nstd::istream &operator>>(std::istream &os, std::vector<T> &vec) {\n for (T &e : vec) std::cin >> e;\n return os;\n}\n\ntemplate <typename T>\nstd::ostream &operator<<(std::ostream &os, const std::optional<T> &opt) {\n if (opt) {\n os << opt.value();\n } else {\n os << \"invalid value\";\n }\n return os;\n}\n\nusing std::size_t;\nusing i32 = std::int32_t;\nusing u32 = std::uint32_t;\nusing i64 = std::int64_t;\nusing u64 = std::uint64_t;\n\ntemplate <class T, T init>\nauto make_vector(int n) {\n return std::vector<T>(n, init);\n}\n\ntemplate <class T, T init, typename Head, typename... Tail>\nauto make_vector(Head n, Tail... ts) {\n return std::vector(n, make_vector<T, init>(ts...));\n}\n\ntemplate <class T>\ninline bool chmin(T &a, T b) {\n if (a > b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate <class T>\ninline bool chmax(T &a, T b) {\n if (a < b) {\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate <class T>\nT pow(T x, i64 n) {\n T res = 1;\n while (n > 0) {\n if (n & 1) res = res * x;\n x = x * x;\n n >>= 1;\n }\n return res;\n}\n\ntemplate <class T>\nT mod_pow(T x, i64 n, i64 mod) {\n T res = 1;\n while (n > 0) {\n if (n & 1) res = (res * x) % mod;\n x = (x * x) % mod;\n n >>= 1;\n }\n return res;\n}\n\ntemplate <class T>\nT scan() {\n T val;\n std::cin >> val;\n return val;\n}\n\ntemplate <class T>\nstruct Edge {\n int to;\n T cost;\n Edge(int _to, T _cost = 1) : to(_to), cost(_cost) {}\n};\n\ntemplate <class T>\nstruct Graph : std::vector<std::vector<Edge<T>>> {\n using std::vector<std::vector<Edge<T>>>::vector;\n void add_edge(int u, int v, T w, bool directed = false) {\n (*this)[u].emplace_back(v, w);\n if (directed) return;\n (*this)[v].emplace_back(u, w);\n }\n};\n\nstruct graph : std::vector<std::vector<int>> {\n using std::vector<std::vector<int>>::vector;\n void add_edge(int u, int v, bool directed = false) {\n (*this)[u].emplace_back(v);\n if (directed) return;\n (*this)[v].emplace_back(u);\n }\n};\n\nconstexpr i64 LNF = std::numeric_limits<i64>::max() / 4;\n\nconstexpr int INF = std::numeric_limits<int>::max() / 2;\n\nconst std::vector<int> dy = {1, 0, -1, 0, 1, 1, -1, -1};\nconst std::vector<int> dx = {0, 1, 0, -1, 1, -1, 1, -1};\n\n} // namespace ebi\n\nnamespace ebi {\n\nvoid main_() {\n int n,m;\n std::cin >> n >> m;\n std::vector<std::pair<int,int>> sv(n);\n std::cin >> sv;\n std::sort(all(sv), [&](auto a, auto b) {\n if(a.second == b.second) return a.first < b.first;\n return a.second < b.second;\n });\n std::vector<int> cs(m);\n std::cin >> cs;\n std::sort(all(cs));\n int ok = 0, ng = m+1;\n while(std::abs(ok - ng) > 1) {\n int mid = (ok + ng)/2;\n int idx = m - mid;\n for(auto [s, v]: sv) {\n if(idx == m) break;\n if(s <= cs[idx]) {\n idx++;\n }\n }\n if(idx == m) {\n ok = mid;\n }\n else {\n ng = mid;\n }\n }\n std::cout << ok << '\\n';\n}\n\n} // namespace ebi\n\nint main() {\n std::cout << std::fixed << std::setprecision(15);\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n int t = 1;\n // std::cin >> t;\n while (t--) {\n ebi::main_();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4424, "score_of_the_acc": -0.2234, "final_rank": 3 }, { "submission_id": "aoj_0659_6414481", "code_snippet": "// g++ -std=c++17 -DDEV=1 main.cpp\n#include <stdio.h>\n#include <cassert>\n#include <iostream>\n#include <fstream>\n#include <vector>\n#include <string>\n#include <set>\n#include <map>\n#include <algorithm>\n\nusing std::cin;\nusing std::cout;\nusing std::endl;\nusing std::terminate;\nusing std::vector;\nusing std::string;\nusing std::set;\nusing std::map;\nusing std::sort;\nusing std::pair;\nusing std::make_pair;\n\n#define rep(i, a, n) for (int i = (a); i < (n); ++i)\n#define bit(n, k) ((n >> k) & 1)\n\nclass Program {\n\nprivate:\n\n bool min(int &a, const int b) {\n if (a > b) {\n a = b;\n return true;\n } else {\n return false;\n }\n }\n\npublic:\n\n Program() {\n }\n\n // 額縁の大きさ: 左 <= 右\n // 価値: 左 <= 右\n void solve() {\n int n, m; cin >> n >> m;\n\n vector<pair<int, int>> ps;\n rep(i, 0, n) {\n int s, v; cin >> s >> v;\n ps.push_back(make_pair(v, s));\n }\n\n sort(ps.begin(), ps.end(), std::greater<std::pair<int,int>>());\n\n // for (auto [value, size] : ps) {\n // cout << size << \",\" << value << endl;\n // }\n\n vector<int> cs;\n cs.resize(m);\n rep(i, 0, m) {\n cin >> cs[i];\n }\n\n sort(cs.begin(), cs.end(), std::greater<int>());\n\n int ans = 0, k = 0;\n rep(j, 0, cs.size()) {\n bool found = false;\n rep(i, k, ps.size()) {\n if (cs[j] >= ps[i].second) {\n k = i+1;\n found = true;\n ans++;\n break;\n }\n }\n\n if (!found) {\n // 残りの額縁の最大より残りの絵のほうが大きい\n break;\n }\n }\n\n cout << ans << endl;\n }\n};\n\nint main() {\n\n#ifdef DEV\n std::ifstream in(\"input\");\n cin.rdbuf(in.rdbuf());\n\n int t; cin >> t;\n for (int x = 1; x <= t; ++x) {\n Program p;\n p.solve();\n }\n#else\n Program p;\n p.solve();\n#endif\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4408, "score_of_the_acc": -0.5499, "final_rank": 8 }, { "submission_id": "aoj_0659_6291430", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\n//typedef int ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1000000010;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nvoid solve() {\n ll N, M; cin >> N >> M;\n vector<P>A(N);\n for (ll i = 0; i < N; i++) cin >> A[i].second >> A[i].first;\n sort(A.begin(), A.end(), greater<P>());\n vector<ll>C(M); input_arr(C, M);\n sort(C.begin(), C.end(), greater<ll>());\n ll ans = 0, pos = 0;\n for (ll i = 0; i < N; i++) {\n if (pos >= M) break;\n if (A[i].second <= C[pos]) {\n ans++;\n pos++;\n }\n }\n cout << ans << endl;\n}\nint main() {\n ll T = 1; //cin >> T;\n while (T--) solve();\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5492, "score_of_the_acc": -1.0918, "final_rank": 17 }, { "submission_id": "aoj_0659_6115200", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m);\n priority_queue<pair<int,int>> pq;\n vector<int> c(m);\n int s,v,ans=0;\n rep(i,n){\n in(s,v);\n pq.push({v,s});\n }\n in(c);\n sort(rall(c));\n rep(i,m){\n while(!pq.empty()&&pq.top().second>c[i]){\n pq.pop();\n }\n if(pq.empty())break;\n ans++;\n pq.pop();\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4584, "score_of_the_acc": -0.291, "final_rank": 5 }, { "submission_id": "aoj_0659_5526138", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n\n#define SIZE 100005\n\nstruct Info{\n\n\tbool operator<(const struct Info& arg) const{\n\t\tif(value != arg.value){\n\n\t\t\treturn value < arg.value;\n\t\t}else{\n\n\t\t\treturn S < arg.S; //同じサイズなら、大きいものから割り当てる\n\t\t}\n\n\t}\n\n\tll S,value;\n};\n\nll C[SIZE];\nInfo info[SIZE];\n\nint main(){\n\n\tll N,M;\n\tscanf(\"%lld %lld\",&N,&M);\n\n\tfor(ll i = 0; i < N; i++){\n\n\t\tscanf(\"%lld %lld\",&info[i].S,&info[i].value);\n\t}\n\tsort(info,info+N);\n\n\tfor(ll i = 0; i < M; i++){\n\n\t\tscanf(\"%lld\",&C[i]);\n\t}\n\tsort(C,C+M);\n\n\tint info_index = N-1;\n\n\tint ans = 0;\n\n\t/*額縁の降順に見ていき、価値の降順に絵画を割り当てる\n\t * 同じ価値ならば、大きい絵画から割り当てる\n\t *\n\t * */\n\tfor(int i = M-1; i >= 0; i--){\n\t\twhile(info_index >= 0 && info[info_index].S > C[i]){\n\n\t\t\tinfo_index--;\n\t\t}\n\t\tif(info_index < 0)break;\n\n\t\tans++;\n\t\tinfo_index--;\n\t\tif(info_index < 0)break;\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5648, "score_of_the_acc": -0.7411, "final_rank": 15 }, { "submission_id": "aoj_0659_5288837", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n#define SIZE 100005\n\nstruct Info{\n\n\tbool operator<(const struct Info& arg) const{\n\n\t\tif(V != arg.V){\n\t\t\treturn V < arg.V;\n\t\t}else{\n\n\t\t\treturn S < arg.S;\n\t\t}\n\t}\n\n\tll S,V;\n};\n\nll C[SIZE];\nInfo info[SIZE];\n\nint main(){\n\n\tint N,M;\n\n\tscanf(\"%d %d\",&N,&M);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%lld %lld\",&info[i].S,&info[i].V);\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%lld\",&C[i]);\n\t}\n\n\tsort(info,info+N);\n\tsort(C,C+M);\n\n\tll ans = 0;\n\tint index = N-1;\n\n\tfor(int i = M-1; i >= 0; i--){\n\n\t\twhile(index >= 0 && info[index].S > C[i])index--;\n\t\tif(index == -1)break;\n\n\n\t\tans++;\n\t\t//printf(\"ans:%lld index:%d\\n\",ans,index);\n\t\tindex--;\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5628, "score_of_the_acc": -0.7327, "final_rank": 14 }, { "submission_id": "aoj_0659_5207102", "code_snippet": "#include<cstdio>\n#include<algorithm>\n#include<functional>\nusing namespace std;\ntypedef pair<int,int> P;\nP p[100001]; \nint c[100001];\nint main(void)\n{\n\tint n,m,cnt=0,x,s,v,i,j,ans=0;\n\tscanf(\"%d%d\",&n,&m);\n\tfor(i=0;i<n;i++){\n\t\tscanf(\"%d%d\",&s,&v);\n\t\tp[i].first=v;\n\t\tp[i].second=s;\n\t}\n\tfor(i=0;i<m;i++)\tscanf(\"%d\",&c[i]);\n\tsort(p,p+n,greater<P>());\n\tsort(c,c+m,greater<int>());\n\tx=0;\n\tfor(i=0;i<n;i++){\n\t\tif(p[i].second<=c[x]){\n\t\t\tcnt++;\n\t\t\tans=max(ans,cnt);\n\t\t\tx++;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3976, "score_of_the_acc": -0.0338, "final_rank": 1 }, { "submission_id": "aoj_0659_5171565", "code_snippet": "#include<iostream>\n#include<string>\n#include<algorithm> \n#include<cmath>\n#include<ctime>\n#include<map>\n#include<vector>\n#include<math.h>\n#include<stdio.h>\n#include<stack>\n#include<queue>\n#include<tuple>\n#include<cassert>\n#include<set>\n#include<bitset>\n#include<functional>\n#include <fstream>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define all(a) (a).begin(),(a).end()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 10000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (a < b)swap(a, b);\n\tif (a % b == 0)return b;\n\treturn gcd(b, a % b);\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres += n % 10; n /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= mod; }\n\t\tx = x * x % mod; y /= 2;\n\t}\n\treturn res;\n}\nll nCk(ll n, ll k) {\n\tll a = 1, b = 1;\n\tfor (int h = n - k + 1; h <= n; h++) { a *= h; a %= mod; }\n\tfor (int h = 1; h <= k; h++) { b *= h; b %= mod; }\n\treturn a * modpow(b, mod - 2) % mod;\n}\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\nstruct edge { ll to, cost; };\nstruct status {\n\tbool ok;\n\tll x;\n\tll y;\n\tll cost;\n\n\tbool operator<(const status& rhs) const { return cost < rhs.cost; };\n\tbool operator>(const status& rhs) const { return cost > rhs.cost; };\n};\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\t//input\n\tll n, m; cin >> n >> m;\n\tvector<P> vs(n);\n\trep(i, n) { cin >> vs[i].second >> vs[i].first; }\n\tsort(all(vs)); reverse(all(vs));\n\tvector<ll> large(m);\n\trep(i, m) { cin >> large[i]; }\n\tsort(all(large)); reverse(all(large));\n\tll ima = 0, ans = 0;\n\trep(i, m) {\n\t\tfor (int j = ima; j < n; j++) {\n\t\t\tif (vs[j].second <= large[i]) { ans++; break; }\n\t\t\tima++;\n\t\t}\n\t\tima++;\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5216, "score_of_the_acc": -0.5584, "final_rank": 9 } ]
aoj_0658_cpp
勇者ビ太郎(Bitaro the Brave) 勇者のビ太郎は,魔王と対峙することとなった. ビ太郎は,縦$H$ 行,横$W$ 列のマス目上に宝石(Jewel),オーブ(Orb),金塊(Ingot) を配置し,魔法を発動することによって魔王に攻撃をしようとしている.以下,マス目のうち上から$i$ 行目($1 \leq i \leq H$),左から$j$ 列目($1 \leq j \leq W$) のマスを,マス($i, j$) と表す. ビ太郎は今,それぞれのマスにこれら3 種類のうち1 個を配置した.今から魔法を発動しようとしているが,この魔法の威力はマス目上の宝石,オーブ,金塊の配置によって決まる.具体的には,次の条件を満たす整数($i, j, k, l$) ($1 \leq i < k \leq H, 1 \leq j < l \leq W$) の組の個数が,魔法の威力である. 条件:マス($i, j$) には宝石が,マス($i, l$) にはオーブが,マス($k, j$) には金塊が置かれている. ビ太郎は,この魔法の威力が気になっている. マス目上の宝石,オーブ,金塊の配置が与えられたとき,ビ太郎が発動する魔法の威力を求めるプログラムを作成せよ. 入力 入力は以下の形式で標準入力から与えられる. $H$ $W$ $S_1$ : $S_H$ $S_i$ ($1 \leq i \leq H$) は長さ$W$ の文字列で,その$j$ 文字目($1 \leq j \leq W$) がJ のときはマス($i, j$) に宝石が,O の ときはマス($i, j$) にオーブが,I のときはマス($i, j$) に金塊が置かれていることを表す. 出力 標準出力に,魔法の威力を表す整数を1 行で出力せよ. 制約 $2 \leq H \leq 3 000$. $2 \leq W \leq 3 000$. $S_i$ は長さ$W$ の文字列である($1 \leq i \leq H$). $S_i$ の各文字はJ,O,I のいずれかである($1 \leq i \leq H$). 入出力例 入力例1 3 4 JOIJ JIOO IIII 出力例1 3 この入力例では,($i, j, k, l$) = (1, 1, 3, 2), (2, 1, 3, 3), (2, 1, 3, 4) の3 個の組が条件を満たすので,答えは3 である. 入力例2 4 4 JJOO JJOO IIJO IIIJ 出力例2 17 情報オリンピック日本委員会作 『第18 回日本情報オリンピック(JOI 2018/2019) 本選』
[ { "submission_id": "aoj_0658_10914234", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass Solution {\npublic:\n int h, w;\n vector<vector<pair<int, int>>> data;// O I\n set<pair<int, int>> st;\n Solution() {\n cin >> h >> w;\n data.assign(h + 1, vector<pair<int, int>>(w + 1, {0, 0}));\n }\n ~Solution() {}\n\n void solution() {\n for (int i = 0; i < h; ++i) {\n string str;\n cin >> str;\n\n for (int j = 0; j < w; ++j) {\n if (str[j] == 'J') {\n st.insert({i, j});\n\n if (i == 0 && j == 0) {\n continue;\n } else if (i == 0) {\n data[i][j] = {data[i][j - 1].first, 0};\n } else if (j == 0) {\n data[i][j] = {0, data[i - 1][j].second};\n } else {\n data[i][j] = {data[i][j - 1].first, data[i - 1][j].second};\n }\n\n } else if (str[j] == 'O') {\n auto [itO, itI] = data[i][w];\n data[i][w] = {itO + 1, 0};\n\n if (i == 0) {\n data[i][j] = {itO + 1, 0};\n } else {\n data[i][j] = {itO + 1, data[i - 1][j].second};\n }\n\n } else if (str[j] == 'I') {\n auto [itO, itI] = data[h][j];\n data[h][j] = {0, itI + 1};\n\n if (j == 0) {\n data[i][j] = {0, itI + 1};\n\n } else {\n data[i][j] = {data[i][j - 1].first, itI + 1};\n }\n }\n }\n }\n long long count(0l);\n for (auto [i, j] : st) {\n int opa = data[i][w].first - data[i][j].first;\n int ingot = data[h][j].second - data[i][j].second;\n\n count += (long long) opa * ingot;\n }\n cout << count << '\\n';\n }\n} ;\nint main() {\n Solution solute;\n solute.solution();\n return 0;\n}", "accuracy": 1, "time_ms": 760, "memory_kb": 242572, "score_of_the_acc": -2, "final_rank": 14 }, { "submission_id": "aoj_0658_10914233", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nclass Solution {\npublic:\n int h, w;\n vector<vector<pair<int, int>>> data;// O I\n set<pair<int, int>> st;\n Solution() {\n cin >> h >> w;\n data.assign(h + 1, vector<pair<int, int>>(w + 1, {0, 0}));\n }\n ~Solution() {}\n\n void solution() {\n for (int i = 0; i < h; ++i) {\n string str;\n cin >> str;\n\n for (int j = 0; j < w; ++j) {\n if (str[j] == 'J') {\n st.insert({i, j});\n\n if (i == 0 && j == 0) {\n continue;\n } else if (i == 0) {\n data[i][j] = {data[i][j - 1].first, 0};\n } else if (j == 0) {\n data[i][j] = {0, data[i - 1][j].second};\n } else {\n data[i][j] = {data[i][j - 1].first, data[i - 1][j].second};\n }\n\n } else if (str[j] == 'O') {\n auto [itO, itI] = data[i][w];\n data[i][w] = {itO + 1, 0};\n\n if (i == 0) {\n data[i][j] = {itO + 1, 0};\n } else {\n data[i][j] = {itO + 1, data[i - 1][j].second};\n }\n\n } else if (str[j] == 'I') {\n auto [itO, itI] = data[h][j];\n data[h][j] = {0, itI + 1};\n\n if (j == 0) {\n data[i][j] = {0, itI + 1};\n\n } else {\n data[i][j] = {data[i][j - 1].first, itI + 1};\n }\n }\n }\n }\n int count(0);\n for (auto [i, j] : st) {\n int opa = data[i][w].first - data[i][j].first;\n int ingot = data[h][j].second - data[i][j].second;\n\n count += opa * ingot;\n }\n cout << count << '\\n';\n }\n} ;\nint main() {\n Solution solute;\n solute.solution();\n return 0;\n}", "accuracy": 0.5121951219512195, "time_ms": 10, "memory_kb": 9136, "score_of_the_acc": -0.0242, "final_rank": 15 }, { "submission_id": "aoj_0658_10874521", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\n\nint MIN = -1e9;\nconst int MOD = 10000;\n\nint main() {\n\tint H, W;\n\tcin >> H >> W;\n\tvector<vector<char>>J(H, vector<char>(W));\n\tvector<vector<long long>>O(H, vector<long long>(W, 0));\n\tvector<vector<long long>>I(H, vector<long long>(W, 0));\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tchar c;\n\t\t\tcin >> c;\n\t\t\tJ[i][j] = c;\n\t\t\tif (c == 'O') {\n\t\t\t\tO[i][j] = 1;\n\t\t\t}\n\t\t\telse if (c == 'I') {\n\t\t\t\tI[i][j] = 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 1; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tI[i][j] += I[i - 1][j];\n\t\t}\n\t}\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 1; j < W; j++) {\n\t\t\tO[i][j] += O[i][j-1];\n\t\t}\n\t}\n\n\tlong long ans = 0;\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (J[i][j] == 'J') {\n\t\t\t\tans += (I[H - 1][j] - I[i][j]) * (O[i][W-1] - O[i][j]);\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 152564, "score_of_the_acc": -1.0771, "final_rank": 13 }, { "submission_id": "aoj_0658_10371315", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint T[3100];\nchar in[3100][3100];\nint main(){\n int a,b;scanf(\"%d%d\",&a,&b);\n for(int i=0;i<a;i++)scanf(\"%s\",in[i]);\n long long ret=0;\n for(int i=a-1;i>=0;i--){\n int tmp=0;\n for(int j=b-1;j>=0;j--){\n if(in[i][j]=='O')tmp++;\n if(in[i][j]=='I')T[j]++;\n if(in[i][j]=='J'){\n ret+=tmp*T[j];\n }\n }\n }\n cout<<ret<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 12600, "score_of_the_acc": -0.092, "final_rank": 2 }, { "submission_id": "aoj_0658_10371228", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint T[3100];\nchar in[3100][3100];\nint main(){\n\tint a,b;scanf(\"%d%d\",&a,&b);\n\tfor(int i=0;i<a;i++)scanf(\"%s\",in[i]);\n\tlong long ret=0;\n\tfor(int i=a-1;i>=0;i--){\n\t\tint tmp=0;\n\t\tfor(int j=b-1;j>=0;j--){\n\t\t\tif(in[i][j]=='O')tmp++;\n\t\t\tif(in[i][j]=='I')T[j]++;\n\t\t\tif(in[i][j]=='J'){\n\t\t\t\tret+=tmp*T[j];\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ret<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 12620, "score_of_the_acc": -0.0921, "final_rank": 3 }, { "submission_id": "aoj_0658_10371227", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint T[3100];\nchar in[3100][3100];\nint main(){\n int a,b;scanf(\"%d%d\",&a,&b);\n for(int i=0;i<a;i++)scanf(\"%s\",in[i]);\n long long ret=0;\n for(int i=a-1;i>=0;i--){\n int tmp=0;\n for(int j=b-1;j>=0;j--){\n if(in[i][j]=='O')tmp++;\n if(in[i][j]=='I')T[j]++;\n if(in[i][j]=='J'){\n ret+=tmp*T[j];\n }\n }\n }\n cout<<ret<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 12556, "score_of_the_acc": -0.0918, "final_rank": 1 }, { "submission_id": "aoj_0658_10336121", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int h,w;\n cin >> h >> w;\n\n vector<vector<char>> grid(h,vector<char>(w));\n vector<vector<int>> x(h,vector<int>(w,0)),y(h,vector<int>(w,0));\n rep(i,h){\n string s;\n cin >> s;\n rep(j,w){\n grid[i][j]=s[j];\n if(grid[i][j]=='O'){\n x[i][j]++;\n }\n else if(grid[i][j]=='I'){\n y[i][j]++;\n }\n }\n }\n vector<vector<int>> X(h,vector<int>(w,0)),Y(h,vector<int>(w,0));\n rep(i,h){\n X[i][0]=x[i][0];\n rep(j,w-1){\n X[i][j+1]=X[i][j]+x[i][j+1];\n }\n }\n rep(j,w){\n Y[0][j]=y[0][j];\n rep(i,h-1){\n Y[i+1][j]=Y[i][j]+y[i+1][j];\n }\n }\n long long res=0;\n rep(i,h){\n rep(j,w){\n if(grid[i][j]=='J'){\n res+=(X[i][w-1]-X[i][j])*(Y[h-1][j]-Y[i][j]);\n }\n }\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 153040, "score_of_the_acc": -1.0124, "final_rank": 12 }, { "submission_id": "aoj_0658_9890609", "code_snippet": "#include <bits/stdc++.h>\n\n\nusing namespace std;\n//make -f ../makefile SRC=\n/*\nTODO\nprefix sum\n*/\n\n\n//------------------------------------------------------------------------------\nbool DEBUG = false;\nconst int INF = 2147483647;\n\nconst int MAX_N = 3000;\nstatic char GRID[MAX_N][MAX_N+5];\nconst char JEWEL = 'J';\nconst char ORB = 'O';\nconst char INGOT = 'I';\n\nstatic int L[MAX_N][MAX_N]; // prefix sum of ORB towards left\nstatic int T[MAX_N][MAX_N]; // prefix sum of INGOT towards top\n\n//------------------------------------------------------------------------------\nint64_t solve(int M, int N)\n{\n //--------------------------------------------------------------------------\n // base cases:\n //--------------------------------------------------------------------------\n // init:\n for (int m=0; m<M; ++m) L[m][N-1] = ( GRID[m][N-1]==ORB ? 1 : 0 );\n\n for (int m=0; m<M; ++m)\n for (int n=N-2; n>=0; --n)\n L[m][n] = (GRID[m][n]==ORB) + L[m][n+1];\n\n for (int n=0; n<N; ++n) T[M-1][n] = ( GRID[M-1][n]==INGOT ? 1 : 0 );\n\n for (int n=0; n<N; ++n)\n for (int m=M-2; m>=0; --m)\n T[m][n] = (GRID[m][n]==INGOT) + T[m+1][n];\n \n //--------------------------------------------------------------------------\n // compute:\n int64_t res = 0;\n for (int m=0; m<M; ++m)\n for (int n=0; n<N; ++n)\n if (GRID[m][n] == JEWEL)\n res += L[m][n] * T[m][n];\n\n //--------------------------------------------------------------------------\n // report:\n return res;\n}\n\n//------------------------------------------------------------------------------\nvoid test()\n{\n\n}\n\n//------------------------------------------------------------------------------\nint main()\n{\n //test(); return 0;\n //DEBUG = true;\n //--------------------------------------------------------------------------\n int M, N, num;\n num = scanf(\"%d %d \", &M, &N);\n for (int m=0; m<M; ++m) num = scanf(\"%s \", GRID[m]);\n int64_t res = solve(M, N);\n printf(\"%ld\\n\", res);\n //--------------------------------------------------------------------------\n return 0;\n}\n//------------------------------------------------------------------------------", "accuracy": 1, "time_ms": 70, "memory_kb": 82648, "score_of_the_acc": -0.4115, "final_rank": 4 }, { "submission_id": "aoj_0658_9821386", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint H, W;\nint sumI[3009][3009];\nint sumO[3009][3009];\nchar C[3009][3009];\n\nint main() {\n\t// Step 1. Input\n\tcin >> H >> W;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) cin >> C[i][j];\n\t}\n\n\t// Step 2. Get Answer\n\tfor (int i = H; i >= 1; i--) {\n\t\tfor (int j = W; j >= 1; j--) {\n\t\t\tsumO[i][j] = sumO[i][j + 1] + (C[i][j] == 'O' ? 1 : 0);\n\t\t\tsumI[i][j] = sumI[i + 1][j] + (C[i][j] == 'I' ? 1 : 0);\n\t\t}\n\t}\n\n\t// Step 3. Output\n\tlong long Answer = 0;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tif (C[i][j] != 'J') continue;\n\t\t\tAnswer += 1LL * sumO[i][j] * sumI[i][j];\n\t\t}\n\t}\n\tcout << Answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 82920, "score_of_the_acc": -0.6393, "final_rank": 6 }, { "submission_id": "aoj_0658_9819627", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nlong long H, W;\nlong long SumO[3009][3009];\nlong long SumI[3009][3009];\nchar C[3009][3009];\n\nint main() {\n\t// Step 1. Input\n\tcin >> H >> W;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) cin >> C[i][j];\n\t}\n\n\t// Step 2. Cumulative Sum\n\tfor (int i = H; i >= 1; i--) {\n\t\tfor (int j = W; j >= 1; j--) SumO[i][j] = SumO[i][j + 1] + (C[i][j] == 'O' ? 1 : 0);\n\t}\n\tfor (int i = H; i >= 1; i--) {\n\t\tfor (int j = W; j >= 1; j--) SumI[i][j] = SumI[i + 1][j] + (C[i][j] == 'I' ? 1 : 0);\n\t}\n\n\t// Step 3. Output\n\tlong long Answer = 0;\n\tfor (int i = 1; i <= H; i++) {\n\t\tfor (int j = 1; j <= W; j++) {\n\t\t\tif (C[i][j] == 'J') {\n\t\t\t\tAnswer += SumO[i][j] * SumI[i][j];\n\t\t\t}\n\t\t}\n\t}\n\tcout << Answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 153464, "score_of_the_acc": -0.9209, "final_rank": 11 }, { "submission_id": "aoj_0658_9780055", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint h, w;\nstring arr[3000];\n\nint calcO(int y, int x) {\n unsigned int countO = 0;\n for (int i = x; i < w; i++) {\n if (arr[y][i] == 'O') {\n countO++;\n } \n }\n return countO;\n}\n\n\nint calcI(int y, int x) {\n int countI = 0;\n for (int i = y; i < h; i++) {\n if (arr[i][x] == 'I') {\n countI++;\n } \n }\n return countI;\n}\n\nint main() {\n cin >> h >> w;\n\n for (int i = 0; i < h; i++) {\n cin >> arr[i];\n }\n int count = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (arr[i][j] == 'J') {\n int numO = calcO(i, j);\n int numI = calcI(i, j);\n count += numO * numI;\n }\n }\n }\n cout << count << endl;\n}", "accuracy": 0.5121951219512195, "time_ms": 50, "memory_kb": 3412, "score_of_the_acc": -0.0536, "final_rank": 18 }, { "submission_id": "aoj_0658_9780054", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint h, w;\nstring arr[3000];\n\nint calcO(int y, int x) {\n unsigned long long countO = 0;\n for (int i = x; i < w; i++) {\n if (arr[y][i] == 'O') {\n countO++;\n } \n }\n return countO;\n}\n\n\nint calcI(int y, int x) {\n int countI = 0;\n for (int i = y; i < h; i++) {\n if (arr[i][x] == 'I') {\n countI++;\n } \n }\n return countI;\n}\n\nint main() {\n cin >> h >> w;\n\n for (int i = 0; i < h; i++) {\n cin >> arr[i];\n }\n int count = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (arr[i][j] == 'J') {\n int numO = calcO(i, j);\n int numI = calcI(i, j);\n count += numO * numI;\n }\n }\n }\n cout << count << endl;\n}", "accuracy": 0.5121951219512195, "time_ms": 50, "memory_kb": 3412, "score_of_the_acc": -0.0536, "final_rank": 18 }, { "submission_id": "aoj_0658_9780053", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint h, w;\nstring arr[3000];\n\nint calcO(int y, int x) {\n unsigned long countO = 0;\n for (int i = x; i < w; i++) {\n if (arr[y][i] == 'O') {\n countO++;\n } \n }\n return countO;\n}\n\n\nint calcI(int y, int x) {\n int countI = 0;\n for (int i = y; i < h; i++) {\n if (arr[i][x] == 'I') {\n countI++;\n } \n }\n return countI;\n}\n\nint main() {\n cin >> h >> w;\n\n for (int i = 0; i < h; i++) {\n cin >> arr[i];\n }\n int count = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (arr[i][j] == 'J') {\n int numO = calcO(i, j);\n int numI = calcI(i, j);\n count += numO * numI;\n }\n }\n }\n cout << count << endl;\n}", "accuracy": 0.5121951219512195, "time_ms": 50, "memory_kb": 3360, "score_of_the_acc": -0.0534, "final_rank": 17 }, { "submission_id": "aoj_0658_9780050", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint h, w;\nstring arr[3000];\n\nint calcO(int y, int x) {\n long countO = 0;\n for (int i = x; i < w; i++) {\n if (arr[y][i] == 'O') {\n countO++;\n } \n }\n return countO;\n}\n\n\nint calcI(int y, int x) {\n int countI = 0;\n for (int i = y; i < h; i++) {\n if (arr[i][x] == 'I') {\n countI++;\n } \n }\n return countI;\n}\n\nint main() {\n cin >> h >> w;\n\n for (int i = 0; i < h; i++) {\n cin >> arr[i];\n }\n int count = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (arr[i][j] == 'J') {\n int numO = calcO(i, j);\n int numI = calcI(i, j);\n count += numO * numI;\n }\n }\n }\n cout << count << endl;\n}", "accuracy": 0.5121951219512195, "time_ms": 50, "memory_kb": 3344, "score_of_the_acc": -0.0533, "final_rank": 16 }, { "submission_id": "aoj_0658_9780047", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint h, w;\nstring arr[3000];\n\nint calcO(int y, int x) {\n int countO = 0;\n for (int i = x; i < w; i++) {\n if (arr[y][i] == 'O') {\n countO++;\n } \n }\n return countO;\n}\n\n\nint calcI(int y, int x) {\n int countI = 0;\n for (int i = y; i < h; i++) {\n if (arr[i][x] == 'I') {\n countI++;\n } \n }\n return countI;\n}\n\nint main() {\n cin >> h >> w;\n\n for (int i = 0; i < h; i++) {\n cin >> arr[i];\n }\n int count = 0;\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (arr[i][j] == 'J') {\n int numO = calcO(i, j);\n int numI = calcI(i, j);\n count += numO * numI;\n }\n }\n }\n cout << count << endl;\n}", "accuracy": 0.5121951219512195, "time_ms": 60, "memory_kb": 3360, "score_of_the_acc": -0.0667, "final_rank": 20 }, { "submission_id": "aoj_0658_9476496", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n\nusing namespace std;\n\nconst int MAX_H = 3010;\nconst int MAX_W = 3010;\n\nlong long o[MAX_H][MAX_W] = {};\nlong long l[MAX_H][MAX_W] = {};\n\nint main() {\n int h, w;\n long long ans = 0;\n string s[MAX_H];\n cin >> h >> w;\n \n // 入力の読み込み\n for (int i = 0; i < h; i++) {\n cin >> s[i];\n for (int j = 0; j < w; j++) {\n if (s[i][j] == 'O') o[i][j]++;\n if (s[i][j] == 'I') l[i][j]++;\n }\n }\n\n // 右方向へのオーブの累積和\n for (int i = 0; i < h; i++) {\n for (int j = w - 2; j >= 0; j--) {\n o[i][j] += o[i][j + 1];\n }\n }\n\n // 下方向への金塊の累積和\n for (int i = h - 2; i >= 0; i--) {\n for (int j = 0; j < w; j++) {\n l[i][j] += l[i + 1][j];\n }\n }\n\n // 宝石がある場所から威力を計算\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n if (s[i][j] == 'J') {\n ans += o[i][j] * l[i][j];\n }\n }\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 156088, "score_of_the_acc": -0.8652, "final_rank": 10 }, { "submission_id": "aoj_0658_9301548", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vi=vector<int>; \nusing vvi=vector<vi>;\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define rep1(i,n) for(int i=1;i<=(int)n;i++)\n\n\nint main() { \n\tint h,w;cin>>h>>w;\n\tvector<string>s(h);\n\trep(i,h)cin>>s[i];\n\tvvi ingot(h+1,vi(w+1,0));\n\tvvi orb(h+1,vi(w+1,0));\n\trep(i,h){\n\t\trep(j,w){\n\t\t\tif(s[i][j]=='O'){\n\t\t\t orb[i+1][j+1]=1;\n\t\t\t} \n\t\t\tif(s[i][j]=='I'){\n\t\t\t ingot[i+1][j+1]=1;\n\t\t\t}\n\t\t}\n\t} \n\tll ans=0; \n\trep(i,h)rep(j,w)orb[i][j+1]+=orb[i][j]; \n\trep(i,h)rep(j,w)ingot[i+1][j]+=ingot[i][j];\n\trep(i,h)rep(j,w){\n\t\tif(s[i][j]!='J')continue; \n\t\t\n\t\t ans+=(orb[i+1][w]-orb[i+1][j])*(ingot[h][j+1]-ingot[i][j+1]);\n\t}\n\t\n\tcout<<ans<<endl;\n\t\n\t \n\t\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 85044, "score_of_the_acc": -0.5815, "final_rank": 5 }, { "submission_id": "aoj_0658_9071339", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint H, W;\nint Sum1[3009][3009];\nint Sum2[3009][3009];\nchar C[3009][3009];\n\nint main() {\n\t// Step 1. Input\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) cin >> C[i][j];\n\t}\n\n\t// Step 2. Cumulative Sum\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] == 'O') Sum1[i][j] = 1;\n\t\t\tif (C[i][j] == 'I') Sum2[i][j] = 1;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; i--) {\n\t\tfor (int j = W - 1; j >= 0; j--) {\n\t\t\tSum1[i][j] += Sum1[i][j + 1];\n\t\t\tSum2[i][j] += Sum2[i + 1][j];\n\t\t}\n\t}\n\n\t// Step 3. Output\n\tlong long Answer = 0;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] != 'J') continue;\n\t\t\tAnswer += Sum1[i][j] * Sum2[i][j];\n\t\t}\n\t}\n\tcout << Answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 82840, "score_of_the_acc": -0.6656, "final_rank": 7 }, { "submission_id": "aoj_0658_9069407", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint H, W;\nchar C[3009][3009];\nint Sum1[3009][3009];\nint Sum2[3009][3009];\n\nint main() {\n\t// Step 1. Input\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) cin >> C[i][j];\n\t}\n\n\t// Step 2. Ruisekiwa\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] == 'O') Sum1[i][j] = 1;\n\t\t\tif (C[i][j] == 'I') Sum2[i][j] = 1;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; i--) {\n\t\tfor (int j = W - 1; j >= 0; j--) {\n\t\t\tSum1[i][j] += Sum1[i][j + 1];\n\t\t\tSum2[i][j] += Sum2[i + 1][j];\n\t\t}\n\t}\n\n\t// Step 3. Output\n\tlong long Answer = 0;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] == 'J') Answer += 1LL * Sum1[i][j] * Sum2[i][j];\n\t\t}\n\t}\n\tcout << Answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 82976, "score_of_the_acc": -0.6795, "final_rank": 9 }, { "submission_id": "aoj_0658_9066666", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint H, W;\nint Sum1[3009][3009];\nint Sum2[3009][3009];\nchar C[3009][3009];\n\nint main() {\n\t// Step 1. Input\n\tcin >> H >> W;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) cin >> C[i][j];\n\t}\n\n\t// Step 2. Get Sum\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] == 'O') Sum1[i][j] = 1;\n\t\t\tif (C[i][j] == 'I') Sum2[i][j] = 1;\n\t\t}\n\t}\n\tfor (int i = H - 1; i >= 0; i--) {\n\t\tfor (int j = W - 1; j >= 0; j--) {\n\t\t\tSum1[i][j] += Sum1[i][j + 1];\n\t\t\tSum2[i][j] += Sum2[i + 1][j];\n\t\t}\n\t}\n\n\t// Step 3. Output\n\tlong long Answer = 0;\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tif (C[i][j] != 'J') continue;\n\t\t\tAnswer += 1LL * Sum1[i][j] * Sum2[i][j];\n\t\t}\n\t}\n\tcout << Answer << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 82900, "score_of_the_acc": -0.6792, "final_rank": 8 } ]
aoj_0660_cpp
たのしいたのしいたのしい家庭菜園(Growing Vegetables is Fun 3) JOI 君は,長年にわたる家庭菜園の経験を生かして,自宅の庭で新たにジョイ草という植物を育てている.庭には東西方向に並んだ$N$ 個のプランターがあり,西側から順に1 から$N$ までの番号がついている.ジョイ草は全部で$N$ 株あり,それぞれのプランターに1 株ずつ植えてある. 春になって様子を見に行ったJOI 君は,ジョイ草が予想に反して色とりどりの葉を付けていることに気がついた.さらに,ジョイ草が思ったほど生育していないことに気がついた.JOI 君はこれらのことを不思議に思い,本で調べたところ,次のことがわかった: ジョイ草には3 種類あり,それぞれ赤,緑,黄の葉を付ける. 葉の色が同じジョイ草を近くに置くと,その成長が阻害されてしまう. そこで,JOI 君は,ジョイ草を並び替えて,葉の色が同じジョイ草が隣り合わないようにすることにした.このとき,JOI 君は隣り合う2 つのジョイ草を入れ替えることしかできない.つまり,1 回の操作でJOI 君はプランター$i$ ($1 \leq i \leq N - 1$) を任意に1 つ選び,プランター$i$ のジョイ草とプランター$i + 1$ のジョイ草を入れ替えることができる.JOI 君は,できるだけ少ない回数の操作で,葉の色が同じジョイ草が隣り合わないようにしたい. ジョイ草の数と,それぞれのジョイ草の葉の色が与えられたとき,葉の色が同じジョイ草が隣り合わないように並び替えるために必要な操作回数の最小値を求めるプログラムを作成せよ. 入力 入力は以下の形式で標準入力から与えられる. $N$ $S$ $S$ は長さ$N$ の文字列で,その$i$ 文字目($1 \leq i \leq N$) は,プランター$i$ に植えてあるジョイ草の葉の色が赤ならばR,緑ならばG,黄ならばY である. 出力 標準出力に,必要な操作回数の最小値を1 行で出力せよ.ただし,葉の色が同じジョイ草が隣り合わないように並び替えることが不可能ならば,代わりに-1 を出力せよ. 制約 $ 1 \leq N \leq 400$. $S$ は長さ$N$ の文字列である. $S$ の各文字はR,G,Y のいずれかである. 入出力例 入力例1 5 RRGYY 出力例1 2 この入力例では,例えば次のようにすると,葉の色が同じジョイ草が隣り合わないようにすることができる. まず,プランター3 のジョイ草とプランター4 のジョイ草を入れ替える. 次に,プランター2 のジョイ草とプランター3 のジョイ草を入れ替える. このようにすると,ジョイ草の並びはRYRGY のようになる.1 回以下の操作で葉の色が同じジョイ草が隣り合わないようにすることはできないので,2 を出力する. 入力例2 6 RRRRRG 出力例2 -1 この入力例では,どのように操作をしても,葉の色が同じジョイ草が隣り合わないようにすることはできない. 入力例3 20 YYGYYYGGGGRGYYGRGRYG 出力例3 8 情報オリンピック日本委員会作 『第18 回日本情報オリンピック(JOI 2018/2019) 本選』
[ { "submission_id": "aoj_0660_10852653", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define sz(x) (int)(x).size()\n#define all(x) x.begin(), x.end()\n\n#define pb push_back\n#define fi first\n#define se second\n#define mp make_pair\n#define ll long long\n#define btpc __builtin_popcountll\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\nconst double Pi=3.141592653589793;\nvoid file(const string FILE){\n if (fopen((FILE + \".INP\").c_str(),\"r\")){\n freopen((FILE + \".INP\").c_str(), \"r\", stdin);\n freopen((FILE + \".OUT\").c_str(), \"w\", stdout);\n }\n}\nconst int N = 401;\nconst int inf = 1e9;\nint dp[N][201][201][3];\nint pos[3][N];\nint cnt[N][3];\nvoid solve()\n{\n\tint n; cin >> n;\n\tstring s; cin >> s;\n\ts = ' ' + s;\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = 0; j < 3; j++) cnt[i][j] = cnt[i - 1][j];\n\t\tif(s[i] == 'R') ++cnt[i][0], pos[0][cnt[i][0] - 1] = i;\n\t\tif(s[i] == 'G') ++cnt[i][1], pos[1][cnt[i][1] - 1] = i;\n\t\tif(s[i] == 'Y') ++cnt[i][2], pos[2][cnt[i][2] - 1] = i;\n\t}\n\tdp[0][0][0][0] = 0;\n\tdp[0][0][0][1] = 0;\n\tdp[0][0][0][2] = 0;\n\tif (cnt[n][0] > (n + 1) /2 || cnt[n][1] > (n + 1) / 2 || cnt[n][2] > (n + 1) / 2) {\n\t\tcout << -1 << endl;\n\t\treturn;\n\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = 0; j <= min(cnt[n][0], i); j++) {\n\t\t\tfor (int k = 0; k <= min(cnt[n][1], i - j); k++) {\n\t\t\t\tint z = i - j - k;\n\t\t\t\tfor (int c = 0; c < 3; c++) dp[i][j][k][c] = inf;\n\t\t\t\tif (j > cnt[n][0] || k > cnt[n][1] || z > cnt[n][2] || z < 0) continue;\n\t\t\t\tif (j > 0) {\n\t\t\t\t\tdp[i][j][k][0] = min(dp[i - 1][j - 1][k][1], dp[i - 1][j - 1][k][2]) + max(0, k - cnt[pos[0][j - 1]][1]) + max(0, z - cnt[pos[0][j - 1]][2]);\n\t\t\t\t}\n\t\t\t\tif (k > 0) {\n\t\t\t\t\tdp[i][j][k][1] = min(dp[i - 1][j][k - 1][0], dp[i - 1][j][k - 1][2]) + max(0, j - cnt[pos[1][k - 1]][0]) + max(0, z - cnt[pos[1][k - 1]][2]);\n\t\t\t\t}\n\t\t\t\tif (z > 0) {\n\t\t\t\t\tdp[i][j][k][2] = min(dp[i - 1][j][k][0], dp[i - 1][j][k][1]) + max(0, j - cnt[pos[2][z - 1]][0]) + max(0, k - cnt[pos[2][z - 1]][1]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans = inf;\n\tfor (int c = 0; c < 3; c++) ans = min(ans, dp[n][cnt[n][0]][cnt[n][1]][c]);\n\tif (ans >= inf) cout << -1 << endl;\n\telse cout << ans << endl;\n\t// CODE HERE\n}\n\nint32_t main(){\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tcout.tie(NULL);\n\tint t = 1;\n//\tcin >> t;\n\twhile(t--){\n\t\tsolve();\n\t}\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 191352, "score_of_the_acc": -0.8167, "final_rank": 15 }, { "submission_id": "aoj_0660_9476652", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <cstring>\n#include <string>\nusing namespace std;\n\n#define INF (1 << 30)\n\nint N;\nint col[440];\nvector<vector<vector<vector<int>>>> dp;\nint pos[4][440];\nint csum[4];\nint bit[440];\n\nint sum(int i) {\n int s = 0;\n while (i > 0) {\n s += bit[i];\n i -= i & -i;\n }\n return s;\n}\n\nvoid add(int i, int x) {\n while (i <= N) {\n bit[i] += x;\n i += i & -i;\n }\n}\n\nint dfs(int c, int x, int y, int z) {\n if (x + y + z == N) return 0;\n if (dp[c][x][y][z] != -1) return dp[c][x][y][z];\n int ret = INF;\n if (x < csum[1] && c != 1) {\n add(pos[1][x + 1], 1);\n ret = min(ret, dfs(1, x + 1, y, z) + pos[1][x + 1] - sum(pos[1][x + 1]));\n add(pos[1][x + 1], -1);\n }\n if (y < csum[2] && c != 2) {\n add(pos[2][y + 1], 1);\n ret = min(ret, dfs(2, x, y + 1, z) + pos[2][y + 1] - sum(pos[2][y + 1]));\n add(pos[2][y + 1], -1);\n }\n if (z < csum[3] && c != 3) {\n add(pos[3][z + 1], 1);\n ret = min(ret, dfs(3, x, y, z + 1) + pos[3][z + 1] - sum(pos[3][z + 1]));\n add(pos[3][z + 1], -1);\n }\n return dp[c][x][y][z] = ret;\n}\n\nint main() {\n cin >> N;\n int cnt1 = 0, cnt2 = 0, cnt3 = 0;\n for (int i = 1; i <= N; i++) {\n char a;\n cin >> a;\n if (a == 'R') {\n col[i] = 1;\n cnt1++;\n pos[1][cnt1] = i;\n csum[1]++;\n } else if (a == 'G') {\n col[i] = 2;\n cnt2++;\n pos[2][cnt2] = i;\n csum[2]++;\n } else {\n col[i] = 3;\n cnt3++;\n pos[3][cnt3] = i;\n csum[3]++;\n }\n }\n\n dp.resize(4, vector<vector<vector<int>>>(csum[1] + 10, vector<vector<int>>(csum[2] + 10, vector<int>(csum[3] + 10, -1))));\n\n int ans = dfs(0, 0, 0, 0);\n if (ans >= INF) ans = -1;\n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 65008, "score_of_the_acc": -0.7004, "final_rank": 11 }, { "submission_id": "aoj_0660_9476635", "code_snippet": "#include <string>\n#include <vector>\n#include <iostream>\n#include <cmath>\n#include <climits>\nstatic std::vector<int> redPosition;\nstatic std::vector<int> greenPosition;\nstatic std::vector<int> yellowPosition;\nstatic std::vector<int> countLeftRed;\nstatic std::vector<int> countLeftGreen;\nstatic std::vector<int> countLeftYellow;\nstatic int redSize;\nstatic int greenSize;\nstatic int yellowSize;\nstatic int wholeSize;\nstruct Key {\n\tint position, red, green, yellow, last;\n\tbool operator<(const Key& other) const {\n\t\tif (position == other.position) {\n\t\t\tif (red == other.red) {\n\t\t\t\tif (green == other.green) {\n\t\t\t\t\tif (yellow == other.yellow) {\n\t\t\t\t\t\treturn last < other.last;\n\t\t\t\t\t}\n\t\t\t\t\telse {\n\t\t\t\t\t\treturn yellow < other.yellow;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\treturn green < other.green;\n\t\t\t\t}\n\t\t\t}\n\t\t\telse {\n\t\t\t\treturn red < other.red;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\treturn position < other.position;\n\t\t}\n\t}\n\tbool operator==(const Key& other) const {\n\t\treturn position == other.position && red == other.red && green == other.green && yellow == other.yellow && last == other.last;\n\t}\n};\nstatic std::vector < std::vector<std::vector<std::vector<int>>>> memo;\nint solve(const int position, const int red, const int green, const int yellow, const int last) {\n\tif (position == wholeSize && red == redSize && green == greenSize && yellow == yellowSize) return 0;\n\tif (red > redSize || green > greenSize || yellow > yellowSize || wholeSize - position + 1 < (redSize - red) * 2 || wholeSize - position + 1 < (greenSize - green) * 2 || wholeSize - position + 1 < (yellowSize - yellow) * 2) return INT_MAX >> 1;\n\tif (last < 3 && memo[red][green][yellow][last] >= 0) return memo[red][green][yellow][last];\n\tint result = INT_MAX;\n\tswitch (last) {\n\tcase 0:\n\t\tif (green != greenSize) result = std::min(result, solve(position + 1, red, green + 1, yellow, 1) + std::max(countLeftRed[greenPosition[green]] - red, 0) + std::max(countLeftYellow[greenPosition[green]] - yellow, 0));\n\t\tif (yellow != yellowSize) result = std::min(result, solve(position + 1, red, green, yellow + 1, 2) + std::max(countLeftRed[yellowPosition[yellow]] - red, 0) + std::max(countLeftGreen[yellowPosition[yellow]] - green, 0));\n\t\tbreak;\n\tcase 1:\n\t\tif (red != redSize) result = solve(position + 1, red + 1, green, yellow, 0) + std::max(countLeftGreen[redPosition[red]] - green, 0) + std::max(countLeftYellow[redPosition[red]] - yellow, 0);\n\t\tif (yellow != yellowSize) result = std::min(result, solve(position + 1, red, green, yellow + 1, 2) + std::max(countLeftRed[yellowPosition[yellow]] - red, 0) + std::max(countLeftGreen[yellowPosition[yellow]] - green, 0));\n\t\tbreak;\n\tcase 2:\n\t\tif (red != redSize) result = solve(position + 1, red + 1, green, yellow, 0) + std::max(countLeftGreen[redPosition[red]] - green, 0) + std::max(countLeftYellow[redPosition[red]] - yellow, 0);\n\t\tif (green != greenSize) result = std::min(result, solve(position + 1, red, green + 1, yellow, 1) + std::max(countLeftRed[greenPosition[green]] - red, 0) + std::max(countLeftYellow[greenPosition[green]] - yellow, 0));\n\t\tbreak;\n\tdefault:\n\t\tif (red != redSize) result = solve(position + 1, red + 1, green, yellow, 0) + std::max(countLeftGreen[redPosition[red]] - green, 0) + std::max(countLeftYellow[redPosition[red]] - yellow, 0);\n\t\tif (green != greenSize) result = std::min(result, solve(position + 1, red, green + 1, yellow, 1) + std::max(countLeftRed[greenPosition[green]] - red, 0) + std::max(countLeftYellow[greenPosition[green]] - yellow, 0));\n\t\tif (yellow != yellowSize) result = std::min(result, solve(position + 1, red, green, yellow + 1, 2) + std::max(countLeftRed[yellowPosition[yellow]] - red, 0) + std::max(countLeftGreen[yellowPosition[yellow]] - green, 0));\n\t}\n\tif (last == 3) return result;\n\treturn memo[red][green][yellow][last] = result;\n}\nint solve(const std::string& state) {\n\tcountLeftRed = countLeftGreen = countLeftYellow = std::vector<int>(state.size(), 0);\n\tfor (auto i = 0; i < state.size(); ++i) {\n\t\tswitch (state[i]) {\n\t\tcase 'R': redPosition.push_back(i); countLeftRed[i] = 1; break;\n\t\tcase 'G': greenPosition.push_back(i); countLeftGreen[i] = 1; break;\n\t\tcase 'Y': yellowPosition.push_back(i); countLeftYellow[i] = 1; break;\n\t\tdefault: break;\n\t\t}\n\t\tif (i != 0) {\n\t\t\tcountLeftRed[i] += countLeftRed[i - 1];\n\t\t\tcountLeftGreen[i] += countLeftGreen[i - 1];\n\t\t\tcountLeftYellow[i] += countLeftYellow[i - 1];\n\t\t}\n\t}\n\tredSize = redPosition.size();\n\tgreenSize = greenPosition.size();\n\tyellowSize = yellowPosition.size();\n\twholeSize = state.size();\n\tif (redSize * 2 > wholeSize + 1 || greenSize * 2 > wholeSize + 1 || yellowSize * 2 > wholeSize + 1) return -1;\n\tmemo = std::vector<std::vector<std::vector<std::vector<int>>>>(redSize + 1, std::vector<std::vector<std::vector<int>>>(greenSize + 1, std::vector<std::vector<int>>(yellowSize + 1, std::vector<int>(3, -1))));\n\treturn solve(0, 0, 0, 0, 3);\n}\nint main() {\n\tint n; std::cin >> n; std::string str; std::cin >> str;\n\tstd::cout << solve(str) << std::endl;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 137048, "score_of_the_acc": -0.9487, "final_rank": 17 }, { "submission_id": "aoj_0660_8504192", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n vector<int> s(n);\n vector<vector<int>> v(3);\n vector<vector<int>> sum(3, vector<int>(n+1));\n for (int i = 0; i < n; ++i) {\n char c; cin >> c;\n if (c == 'R') s[i] = 0;\n else if (c == 'G') s[i] = 1;\n else s[i] = 2;\n\n sum[s[i]][i+1] += 1;\n v[s[i]].push_back(i);\n for (int j = 0; j < 3; ++j) {\n sum[j][i+1] += sum[j][i];\n }\n }\n int r = (int)v[0].size();\n int g = (int)v[1].size();\n int y = (int)v[2].size();\n\n vector<vector<int>> dp0(r+1, vector<int>(g+1, 1e9));\n vector<vector<int>> dp1(r+1, vector<int>(g+1, 1e9));\n vector<vector<int>> dp2(r+1, vector<int>(g+1, 1e9));\n dp0[0][0] = dp1[0][0] = dp2[0][0] = 0;\n for (int i = 0; i < n; ++i) {\n vector<vector<int>> ndp0(r+1, vector<int>(g+1, 1e9));\n vector<vector<int>> ndp1(r+1, vector<int>(g+1, 1e9));\n vector<vector<int>> ndp2(r+1, vector<int>(g+1, 1e9));\n\n for (int j = 0; j <= r and j <= i; ++j) {\n for (int k = 0; k <= g and j+k <= i; ++k) {\n int l = i-j-k;\n\n if (dp0[j][k] != 1e9) {\n if (k+1 <= g) {\n int pos = v[1][k];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp1[j][k+1] = min(ndp1[j][k+1], dp0[j][k]+cost);\n }\n if (l+1 <= y) {\n int pos = v[2][l];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp2[j][k] = min(ndp2[j][k], dp0[j][k]+cost);\n }\n }\n if (dp1[j][k] != 1e9) {\n if (j+1 <= r) {\n int pos = v[0][j];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp0[j+1][k] = min(ndp0[j+1][k], dp1[j][k]+cost);\n }\n if (l+1 <= y) {\n int pos = v[2][l];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp2[j][k] = min(ndp2[j][k], dp1[j][k]+cost);\n }\n }\n if (dp2[j][k] != 1e9) {\n if (j+1 <= r) {\n int pos = v[0][j];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp0[j+1][k] = min(ndp0[j+1][k], dp2[j][k]+cost);\n }\n if (k+1 <= g) {\n int pos = v[1][k];\n int cost = max(0, sum[0][pos]-j) + max(0, sum[1][pos]-k) + max(0, sum[2][pos]-l);\n ndp1[j][k+1] = min(ndp1[j][k+1], dp2[j][k]+cost);\n }\n }\n }\n }\n\n swap(dp0, ndp0);\n swap(dp1, ndp1);\n swap(dp2, ndp2);\n }\n int res = min({dp0[r][g], dp1[r][g], dp2[r][g]});\n if (res == 1e9) res = -1;\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4336, "score_of_the_acc": -0.0556, "final_rank": 1 }, { "submission_id": "aoj_0660_8497923", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = int;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n int N;\n string S;\n cin >> N >> S;\n vector<vector<int>> A(3, vector<int>(N + 1, 0));\n vector<vector<int>> C(3);\n rep(i, N) {\n if (S[i] == 'R') {\n C[0].push_back(i);\n A[0][i + 1]++;\n }\n else if (S[i] == 'G') {\n C[1].push_back(i);\n A[1][i + 1]++;\n }\n else {\n C[2].push_back(i);\n A[2][i + 1]++;\n }\n rep(k, 3)A[k][i + 1] += A[k][i];\n }\n\n vll Z(3);\n rep(i, 3) {\n Z[i] = A[i][N];\n if (Z[i] * 2 > N + 1) {\n cout << -1 << endl;\n return 0;\n }\n }\n vvvll DP(Z[0] + 1, vvll(Z[1] + 1, vll(3, 1e9)));\n vvvll NDP(Z[0] + 1, vvll(Z[1] + 1, vll(3, 1e9)));\n DP[0][0][0] = DP[0][0][1] = DP[0][0][2] = 0;\n rep(i, N) {\n NDP.assign(Z[0] + 1, vvll(Z[1] + 1, vll(3, 1e9)));\n rep(j, min(Z[0] + 1, i + 1)) {\n rep(k, min(Z[1] + 1, i + 1)) {\n int m = i - j - k;\n if (m > Z[2])continue;\n if (m < 0)break;\n //cout << i << \" \" << j << \" \" << k << \" \" << m << endl;\n if (m != Z[2]) {\n int res = min(DP[j][k][0], DP[j][k][1]);\n int id = C[2][m];\n int cost = max(A[0][id + 1] - j, 0) + max(A[1][id + 1] - k, 0);\n\n if (res + cost < NDP[j][k][2])NDP[j][k][2] = res + cost;\n }\n\n if (k != Z[1]) {\n int res = min(DP[j][k][0], DP[j][k][2]);\n int id = C[1][k];\n int cost = max(A[0][id + 1] - j, 0) + max(A[2][id + 1] - m, 0);\n if (res + cost < NDP[j][k + 1][1])NDP[j][k + 1][1] = res + cost;\n }\n\n if (j != Z[0]) {\n int res = min(DP[j][k][1], DP[j][k][2]);\n int id = C[0][j];\n int cost = max(A[1][id + 1] - k, 0) + max(A[2][id + 1] - m, 0);\n if (res + cost < NDP[j + 1][k][0])NDP[j + 1][k][0] = res + cost;\n }\n\n }\n }\n swap(DP, NDP);\n }\n int an = 1e9;\n rep(k, 3)an = min(an, DP[Z[0]][Z[1]][k]);\n cout << an << endl;\n\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7840, "score_of_the_acc": -0.2092, "final_rank": 4 }, { "submission_id": "aoj_0660_7238158", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/all>\n\n#define rep(i, x) for (int i = 0; i < x; i++)\n#define rep2(i, x) for (int i = 1; i <= x; i++)\n#define rep3(i, x, y) for (int i = x; i < y; i++)\n#define REP(i, x) for (int i = x - 1; i >= 0; i--)\n#define REP2(i, x) for (int i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define pb push_back\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\n// using namespace atcoder;\n\nconstexpr ll INF = 1000000000000000000;\nconstexpr int intINF = 1000000000;\nconstexpr ll mod = 1000000007;\nconstexpr ll MOD = 998244353;\nconst ld pi = acos(-1);\n// const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError\n{\n};\n\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n if (a > b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nbool isprime(ll p)\n{\n if (p == 1)\n return false;\n for (ll i = 2; i * i <= p; i++)\n {\n if (p % i == 0)\n return false;\n }\n return true;\n}\n// エラトステネスの篩\nvector<bool> isprime_format(ll n)\n{\n vector<bool> P(n + 1, 1);\n P[0] = P[1] = 1;\n for (ll i = 2; i * i <= n; i++)\n {\n if (!P[i])\n continue;\n for (int j = i + i; j <= n; j += i)\n P[j] = false;\n }\n return P;\n}\nvector<ll> prime_format(ll n)\n{\n vector<bool> P = isprime_format(n);\n vector<ll> ans;\n for (int i = 2; i <= n; i++)\n {\n if (P[i])\n ans.push_back(i);\n }\n return ans;\n}\nll extGCD(ll a, ll b, ll &x, ll &y)\n{\n // ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n // 返り値: a と b の最大公約数\n // ax + by = gcd(a, b) を満たす (x, y) が格納される\n // main関数内に extGCD(a, b, x, y); でx, yに解が格納\n if (b == 0)\n {\n x = 1;\n y = 0;\n return a;\n }\n ll d = extGCD(b, a % b, y, x);\n y -= a / b * x;\n return d;\n}\nll keta(ll n)\n{\n ll res = 0;\n while (n >= 1)\n {\n // res++;\n res += n % 10;\n\n n /= 10;\n }\n return res;\n}\nll modpow(ll x, ll y, ll m)\n{\n ll res = 1;\n while (y)\n {\n if (y % 2)\n {\n res *= x;\n res %= m;\n }\n x = x * x % m;\n y /= 2;\n }\n return res;\n}\n\nunsigned int xorshift()\n{\n // xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n // 1~6まで出したいときは\n // xorshift() % 6 + 1\n static unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n unsigned int tt = (tx ^ (tx << 11));\n tx = ty;\n ty = tz;\n tz = tw;\n return (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\nuint64_t seed = 123456789;\nuint64_t xorshift64()\n{\n seed ^= seed << 13;\n seed ^= seed >> 17;\n seed ^= seed << 7;\n return seed;\n}\nint rand_int(int l, int r)\n{\n return l + int(xorshift64() % (r - l));\n}\ndouble randouble()\n{\n return double(xorshift64()) / double(uint64_t(-1));\n}\n\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> pp;\n// 左上右下\nll dx[4] = {0, -1, 0, 1}, dy[4] = {-1, 0, 1, 0};\nll ndx[4] = {1, -1, -1, 1}, ndy[4] = {1, 1, -1, -1};\nchar ds[4] = {'l', 'u', 'r', 'd'};\nchar dl[4] = {'L', 'U', 'R', 'D'};\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n)\n{\n spf.resize(n + 1);\n spf[1] = 1;\n for (int i = 2; i <= n; i++)\n {\n if (!spf[i])\n {\n for (int j = i; j < n; j += i)\n {\n spf[j] = i;\n }\n }\n }\n}\nstd::map<int, int> high_speed_prime_factor(int n)\n{\n std::map<int, int> res;\n while (n != 1)\n {\n res[spf[n]]++;\n n /= spf[n];\n }\n return res;\n}\n\n////////////////////////////////struct\n\nstruct Comb\n{\n // https://atcoder.jp/contests/abc156/submissions/33741990\n\n ll nCrMAX;\n ll m;\n vector<ll> fac, finv, inv; // n!、1/n!、1/n\n\n Comb(ll kMOD, ll kMAX = 612345)\n {\n nCrMAX = kMAX;\n m = kMOD;\n fac.resize(nCrMAX);\n finv.resize(nCrMAX);\n inv.resize(nCrMAX);\n\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < nCrMAX; i++)\n {\n fac[i] = fac[i - 1] * i % m;\n inv[i] = m - inv[m % i] * (m / i) % m;\n finv[i] = finv[i - 1] * inv[i] % m;\n }\n }\n\n ll nCr(ll n, ll k)\n {\n if (k < nCrMAX)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n else\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n }\n\n ll nCr1(ll n, ll k)\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n\n //(nが大きくて)kが小さい時\n // nCrMAXはk+2まででOK\n ll nCr2(ll n, ll k)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n};\n\nstruct status\n{\n ll v;\n ll p;\n\n // bool operator<(const status& rhs) const { return c < rhs.c; };\n // bool operator>(const status& rhs) const { return c > rhs.c; };\n bool operator<(const status &rhs) const { return v < rhs.v; };\n bool operator>(const status &rhs) const { return v > rhs.v; };\n};\nvoid yes(bool a) { cout << (a ? \"yes\" : \"no\") << endl; }\nvoid YES(bool a) { cout << (a ? \"YES\" : \"NO\") << endl; }\nvoid Yes(bool a) { cout << (a ? \"Yes\" : \"No\") << endl; }\nvoid Possible(bool a) { cout << (a ? \"Possible\" : \"Impossible\") << endl; }\n// struct edge {\n//\tll to; ll cost;\n// };\n\nstruct Point\n{\n ld x, y;\n Point operator+(const Point &p) const noexcept { return {x + p.x, y + p.y}; }\n Point operator-(const Point &p) const noexcept { return {x - p.x, y - p.y}; }\n Point operator*(const ld k) const noexcept { return {x * k, y * k}; }\n Point operator/(const ld k) const noexcept { return {x / k, y / k}; }\n Point &operator+=(const Point &p) noexcept\n {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) noexcept\n {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n bool operator<(const Point &p) const noexcept { return (x != p.x ? x < p.x : y < p.y); }\n\n ld abs() const noexcept { return sqrt(x * x + y * y); }\n ld norm() const noexcept { return x * x + y * y; }\n};\n\n// using mint = modint998244353;\n\nstruct edge\n{\n ll to, cost;\n};\n\nll dp[2][405][405][3];\n// dp[i][r][g][l] : i番目までで Rがr個で Gがg個で 最後がlの時の 最小値\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n // cout << fixed << setprecision(15);\n // priority_queue<ll, vector<ll>, greater<ll>> que;\n // priority_queue<P, vector<P>, greater<P>> que;\n // priority_queue<status, vector<status>, greater<status>> que;\n\n map<char, ll> col;\n col['R'] = 0;\n col['G'] = 1;\n col['Y'] = 2;\n\n rep(i, 2)\n {\n rep(j, 405)\n {\n rep(k, 405)\n {\n rep(l, 3)\n {\n dp[i][j][k][l] = INF;\n }\n }\n }\n }\n\n ll n;\n string s;\n cin >> n >> s;\n\n vector<vector<ll>> cnt(n, vector<ll>(3)); // cnt[i][j] : i番目までにcolor:jの花が何個か\n vector<vector<ll>> Where(n + 1, vector<ll>(3)); // Where[i][j] : i番目のcolor:jの花がどこにあるか\n int r = 0, g = 0, y = 0;\n rep(i, n)\n {\n if (s[i] == 'R')\n {\n r++;\n cnt[i][col[s[i]]]++;\n Where[r][0] = i;\n }\n if (s[i] == 'G')\n {\n g++;\n cnt[i][col[s[i]]]++;\n Where[g][1] = i;\n }\n if (s[i] == 'Y')\n {\n y++;\n cnt[i][col[s[i]]]++;\n Where[y][2] = i;\n }\n rep(l, 3)\n {\n if (i != 0) cnt[i][l] += cnt[i - 1][l];\n }\n }\n\n dp[0][0][0][0] = 0;\n dp[0][0][0][1] = 0;\n dp[0][0][0][2] = 0;\n ll ans = INF;\n rep2(i, n)\n {\n for (int a = 0; a <= i; a++)\n {\n for (int b = 0; a + b <= i; b++)\n {\n rep(l, 3) { dp[i % 2][a][b][l] = INF; }\n \n int c = i - a - b;\n if (a > r || b > g || c > y)\n {\n continue;\n }\n if (a != 0)\n {\n dp[i % 2][a][b][0] = min(dp[(i - 1) % 2][a - 1][b][1], dp[(i - 1) % 2][a - 1][b][2]) + max(0LL, b - cnt[Where[a][0]][1]) + max(0LL, c - cnt[Where[a][0]][2]);\n }\n if (b != 0)\n {\n dp[i % 2][a][b][1] = min(dp[(i - 1) % 2][a][b - 1][0], dp[(i - 1) % 2][a][b - 1][2]) + max(0LL, a - cnt[Where[b][1]][0]) + max(0LL, c - cnt[Where[b][1]][2]);\n }\n if (c != 0)\n {\n dp[i % 2][a][b][2] = min(dp[(i - 1) % 2][a][b][0], dp[(i - 1) % 2][a][b][1]) + max(0LL, a - cnt[Where[c][2]][0]) + max(0LL, b - cnt[Where[c][2]][1]);\n }\n if (i == n)\n {\n rep(l, 3) { chmin(ans, dp[i % 2][a][b][l]); }\n }\n }\n }\n }\n cout << (ans == INF ? -1 : ans) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 11200, "score_of_the_acc": -0.0567, "final_rank": 2 }, { "submission_id": "aoj_0660_6773678", "code_snippet": "#line 1 \"solve/main.cpp\"\n#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <chrono>\n#include <cmath>\n#include <complex>\n#include <cstdint>\n#include <cstdlib>\n#include <deque>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <limits>\n#include <list>\n#include <map>\n#include <memory>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <type_traits>\n#include <unordered_map>\n#include <utility>\n#include <vector>\n\n/* template start */\n\n#line 2 \"lib/utility/type_alias.hpp\"\n\n#line 4 \"lib/utility/type_alias.hpp\"\n\nusing u64 = std::uint64_t;\nusing u32 = std::uint32_t;\nusing u16 = std::uint16_t;\nusing u8 = std::uint8_t;\n\nusing i64 = std::int64_t;\nusing i32 = std::int32_t;\nusing i16 = std::int16_t;\nusing i8 = std::int8_t;\n\nusing usize = std::size_t;\nusing isize = std::ptrdiff_t;\n\nconstexpr i64 operator\"\" _i64(unsigned long long num) { return i64(num); }\n\nconstexpr u64 operator\"\" _u64(unsigned long long num) { return u64(num); }\n#line 33 \"solve/main.cpp\"\n\n#define rep(i, a, b) for (i64 i = (a); (i) < (b); (i)++)\n#define all(i) i.begin(), i.end()\n\n#ifdef LOCAL\n#define debug(...) \\\n std::cerr << \"LINE: \" << __LINE__ << \" [\" << #__VA_ARGS__ << \"]:\", \\\n debug_out(__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n\nvoid debug_out() { std::cerr << std::endl; }\n\ntemplate <typename Head, typename... Tail>\nvoid debug_out(Head h, Tail... t) {\n std::cerr << \" \" << h;\n if (sizeof...(t) > 0) std::cerr << \" :\";\n debug_out(t...);\n}\n\ntemplate <typename T1, typename T2>\nstd::ostream& operator<<(std::ostream& os, std::pair<T1, T2> pa) {\n return os << pa.first << \" \" << pa.second;\n}\n\ntemplate <typename T>\nstd::ostream& operator<<(std::ostream& os, std::vector<T> vec) {\n for (std::size_t i = 0; i < vec.size(); i++)\n os << vec[i] << (i + 1 == vec.size() ? \"\" : \" \");\n return os;\n}\n\ntemplate <typename T1, typename T2>\ninline bool chmax(T1& a, T2 b) {\n return a < b && (a = b, true);\n}\n\ntemplate <typename T1, typename T2>\ninline bool chmin(T1& a, T2 b) {\n return a > b && (a = b, true);\n}\n\ntemplate <typename Num, typename Func = std::multiplies<Num>>\nconstexpr Num mypow(Num a, u64 b, Num id = 1, Func mul = Func()) {\n if (b == 0) return id;\n Num x = id;\n while (b > 0) {\n if (b & 1) x = mul(x, a);\n a = mul(a, a);\n b >>= 1;\n }\n return x;\n}\n\n/* template end */\n\nenum Color {\n R,\n G,\n Y,\n};\n\nconstexpr int INF = 5*1e8;\n\nint dp[210][210][210][3];\n\nint main() {\n std::cin.tie(nullptr);\n std::ios::sync_with_stdio(false);\n\n i64 n;\n std::cin >> n;\n\n std::string s;\n std::cin >> s;\n\n i64 r_cnt = 0, g_cnt = 0, y_cnt = 0;\n std::vector<i64> r_nth(1), g_nth(1), y_nth(1);\n\n rep(i, 0, n) {\n if (s[i] == 'R') {\n r_cnt++;\n r_nth.emplace_back(i);\n }\n if (s[i] == 'G') {\n g_cnt++;\n g_nth.emplace_back(i);\n }\n if (s[i] == 'Y') {\n y_cnt++;\n y_nth.emplace_back(i);\n }\n }\n\n if(r_cnt > (n+1)/2 || g_cnt > (n+1)/2 || y_cnt > (n+1)/2){\n std::cout<<-1<<\"\\n\";\n return 0;\n }\n\n std::vector<i64> r_sum(n + 1, 0), g_sum(n + 1, 0), y_sum(n + 1, 0);\n rep(i, 0, n) {\n r_sum[i + 1] = r_sum[i];\n g_sum[i + 1] = g_sum[i];\n y_sum[i + 1] = y_sum[i];\n if (s[i] == 'R') {\n r_sum[i + 1] = r_sum[i] + 1;\n }\n if (s[i] == 'G') {\n g_sum[i + 1] = g_sum[i] + 1;\n }\n if (s[i] == 'Y') {\n y_sum[i + 1] = y_sum[i] + 1;\n }\n }\n\n rep(i, 0, 3) {\n dp[1][0][0][i] = INF;\n dp[0][1][0][i] = INF;\n dp[0][0][1][i] = INF;\n }\n\n if (r_cnt > 0) dp[1][0][0][R] = g_sum[r_nth[1]] + y_sum[r_nth[1]];\n if (g_cnt > 0) dp[0][1][0][G] = r_sum[g_nth[1]] + y_sum[g_nth[1]];\n if (y_cnt > 0) dp[0][0][1][Y] = r_sum[y_nth[1]] + g_sum[y_nth[1]];\n\n rep(sum, 2, n + 1) {\n rep(r, 0, r_cnt + 1) {\n if (r > sum) break;\n\n rep(g, 0, g_cnt + 1) {\n if (r + g > sum) break;\n\n i64 y = sum - r - g;\n\n if (y > y_cnt) continue;\n\n rep(i, 0, 3) dp[r][g][y][i] = INF;\n\n if (r > 0) {\n dp[r][g][y][R] = std::min(dp[r - 1][g][y][G], dp[r - 1][g][y][Y]);\n dp[r][g][y][R] += std::max(g_sum[r_nth[r]] - g, 0_i64);\n dp[r][g][y][R] += std::max(y_sum[r_nth[r]] - y, 0_i64);\n }\n\n if (g > 0) {\n dp[r][g][y][G] = std::min(dp[r][g - 1][y][R], dp[r][g - 1][y][Y]);\n dp[r][g][y][G] += std::max(r_sum[g_nth[g]] - r, 0_i64);\n dp[r][g][y][G] += std::max(y_sum[g_nth[g]] - y, 0_i64);\n }\n\n if (y > 0) {\n dp[r][g][y][Y] = std::min(dp[r][g][y - 1][R], dp[r][g][y - 1][G]);\n dp[r][g][y][Y] += std::max(r_sum[y_nth[y]] - r, 0_i64);\n dp[r][g][y][Y] += std::max(g_sum[y_nth[y]] - g, 0_i64);\n }\n\n debug(r, g, y, dp[r][g][y][R]);\n debug(r, g, y, dp[r][g][y][G]);\n debug(r, g, y, dp[r][g][y][Y]);\n }\n }\n }\n\n i64 ans = INF;\n rep(i, 0, 3) chmin(ans, dp[r_cnt][g_cnt][y_cnt][i]);\n\n if (ans == INF)\n std::cout << -1 << \"\\n\";\n else\n std::cout << ans << \"\\n\";\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 107840, "score_of_the_acc": -0.4366, "final_rank": 8 }, { "submission_id": "aoj_0660_6317164", "code_snippet": "#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <cfenv>\n#include <cfloat>\n#include <chrono>\n#include <cinttypes>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdint>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <fstream>\n#include <functional>\n#include <initializer_list>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <random>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <streambuf>\n#include <string>\n#include <tuple>\n#include <type_traits>\n#include <typeinfo>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\nusing uint = unsigned int;\nusing ull = unsigned long long;\n\n#define rep(i,n) for (int i=0; i<(int)(n); i++)\n#define minv(v) *min_element(v.begin(), v.end())\n#define maxv(v) *max_element(v.begin(), v.end())\n#define sortvv(myVec) sort(myVec.begin(),myVec.end(),[](const vector<int> &alpha,const vector<int> &beta){return alpha[0] < beta[0];})\n#define append(v,d) v.push_back(d)\n#define append2(v,i,d) v[i].push_back(d)\n\ntemplate <typename T>\nusing vec = vector<T>;\ntemplate <typename T>\nusing vv = vector<vector<T>>;\ntemplate <typename T>\nusing heapq = priority_queue<T>;\n\ntemplate <typename Type>\nType sumv(const vector<Type>& v){\n Type sum = 0;\n for(size_t i=0; i<v.size(); i++){\n sum += v[i];\n }\n return sum;\n}\n\ntemplate <typename Type>\nType pow(Type x, Type n,Type mod) {\n Type ret = 1;\n while (n > 0) {\n if (n & 1) ret = ret * x % mod;\n x = x * x % mod;\n n >>= 1;\n }\n return ret;\n}\n\n\nstruct Edge {\n long long to;\n long long cost;\n};\nusing Graph = vector<vector<Edge>>;\nusing P = pair<long, int>;\nconst long long INF = 1LL << 60;\n\n/* dijkstra(G,s,dis)\n 入力:グラフ G, 開始点 s, 距離を格納する dis\n 計算量:O(|E|log|V|)\n 副作用:dis が書き換えられる\n*/\nvoid dijkstra(const Graph &G, int s, vector<long long> &dis) {\n int N = G.size();\n dis.resize(N, pow(10,16));\n priority_queue<P, vector<P>, greater<P>> pq; // 「仮の最短距離, 頂点」が小さい順に並ぶ\n dis[s] = 0;\n pq.emplace(dis[s], s);\n while (!pq.empty()) {\n P p = pq.top();\n pq.pop();\n int v = p.second;\n if (dis[v] < p.first) { // 最短距離で無ければ無視\n continue;\n }\n for (auto &e : G[v]) {\n if (dis[e.to] > dis[v] + e.cost) { // 最短距離候補なら priority_queue に追加\n dis[e.to] = dis[v] + e.cost;\n pq.emplace(dis[e.to], e.to);\n }\n }\n }\n}\n\nstruct Eratosthenes {\n // テーブル\n vector<bool> isprime;\n\n // 整数 i を割り切る最小の素数\n vector<int> minfactor;\n\n // コンストラクタで篩を回す\n Eratosthenes(int N) : isprime(N+1, true),\n minfactor(N+1, -1) {\n // 1 は予めふるい落としておく\n isprime[1] = false;\n minfactor[1] = 1;\n\n // 篩\n for (int p = 2; p <= N; ++p) {\n // すでに合成数であるものはスキップする\n if (!isprime[p]) continue;\n\n // p についての情報更新\n minfactor[p] = p;\n\n // p 以外の p の倍数から素数ラベルを剥奪\n for (int q = p * 2; q <= N; q += p) {\n // q は合成数なのでふるい落とす\n isprime[q] = false;\n\n // q は p で割り切れる旨を更新\n if (minfactor[q] == -1) minfactor[q] = p;\n }\n }\n }\n\n // 高速素因数分解\n // pair (素因子, 指数) の vector を返す\n vector<pair<int,int>> factorize(int n) {\n vector<pair<int,int>> res;\n while (n > 1) {\n int p = minfactor[n];\n int exp = 0;\n\n // n で割り切れる限り割る\n while (minfactor[n] == p) {\n n /= p;\n ++exp;\n }\n res.emplace_back(p, exp);\n }\n return res;\n } \n};\n\nlong long modinv(long long a, long long m) {\n long long b = m, u = 1, v = 0;\n while (b) {\n long long t = a / b;\n a -= t * b; swap(a, b);\n u -= t * v; swap(u, v);\n }\n u %= m;\n if (u < 0) u += m;\n return u;\n}\n\n/**\nvv<int> a(x,vec<int>(y));\n**/\n\nint main(){\n int n;\n string s;\n cin>>n;\n cin>>s;\n vec<int> cnt(3,0);\n vv<int> l(n,vec<int>(3,0));\n vec<int> r2;\n vec<int> g2;\n vec<int> b2;\n rep(i,n){\n l[i][0]=cnt[0];\n l[i][1]=cnt[1];\n l[i][2]=cnt[2];\n if (s[i]=='R'){\n cnt[0]+=1;\n r2.push_back(i);\n }else if(s[i]=='G'){\n cnt[1]+=1;\n g2.push_back(i);\n }else{\n cnt[2]+=1;\n b2.push_back(i);\n }\n }\n int r=cnt[0],g=cnt[1],b=cnt[2];\n int inf=1000000;\n vec<vec<vec<vec<int>>>> dp(3,vec<vec<vec<int>>>(r+1,vec<vec<int>>(g+1,vec<int>(b+1,inf))));\n dp[0][0][0][0]=0;\n dp[1][0][0][0]=0;\n dp[2][0][0][0]=0;\n rep(i,r+1){\n rep(j,g+1){\n rep(k,b+1){\n if (i!=r){\n dp[0][i+1][j][k]=min(dp[0][i+1][j][k],min(dp[1][i][j][k],dp[2][i][j][k])+max(0,l[r2[i]][1]-j)+max(0,l[r2[i]][2]-k));\n }\n if (j!=g){\n dp[1][i][j+1][k]=min(dp[1][i][j+1][k],min(dp[0][i][j][k],dp[2][i][j][k])+max(0,l[g2[j]][0]-i)+max(0,l[g2[j]][2]-k));\n }\n if (k!=b){\n dp[2][i][j][k+1]=min(dp[2][i][j][k+1],min(dp[0][i][j][k],dp[1][i][j][k])+max(0,l[b2[k]][0]-i)+max(0,l[b2[k]][1]-j));\n }\n }\n }\n }\n int ans=min(dp[0][r][g][b],min(dp[1][r][g][b],dp[2][r][g][b]));\n if (ans==inf){\n cout<<-1<<endl;\n }else{\n cout<<ans<<endl;\n }\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 44124, "score_of_the_acc": -0.2234, "final_rank": 5 }, { "submission_id": "aoj_0660_6058323", "code_snippet": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,m,n) for(int i=(m);i<(n);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\nusing ll = long long;\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr double EPS = 1e-8;\nconstexpr int MOD = 1000000007;\n// constexpr int MOD = 998244353;\nconstexpr int DY[]{1, 0, -1, 0}, DX[]{0, -1, 0, 1};\nconstexpr int DY8[]{1, 1, 0, -1, -1, -1, 0, 1}, DX8[]{0, -1, -1, -1, 0, 1, 1, 1};\ntemplate <typename T, typename U> inline bool chmax(T &a, U b) { return a < b ? (a = b, true) : false; }\ntemplate <typename T, typename U> inline bool chmin(T &a, U b) { return a > b ? (a = b, true) : false; }\nstruct IOSetup {\n IOSetup() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::cout << fixed << setprecision(20);\n }\n} iosetup;\n\nint main() {\n constexpr int C = 3;\n int n; string s; cin >> n >> s;\n vector<int> t(n);\n REP(i, n) {\n switch (s[i]) {\n case 'R':\n t[i] = 0;\n break;\n case 'G':\n t[i] = 1;\n break;\n case 'Y':\n t[i] = 2;\n break;\n }\n }\n vector<int> pos[C]{};\n REP(i, n) pos[t[i]].emplace_back(i);\n vector left(n, vector(C, 0));\n REP(i, n) REP(j, i) ++left[i][t[j]];\n int num[C]{};\n REP(i, C) num[i] = pos[i].size();\n vector dp(1, vector(1, vector(C + 1, INF)));\n dp[0][0][C] = 0;\n REP(i, n) {\n const int pa = dp.size(), pb = dp.front().size();\n const int a = min(i / 2 + 1, num[0]), b = min(i / 2 + 1, num[1]);\n vector nx(a + 1, vector(b + 1, vector(C, INF)));\n REP(x, pa) REP(y, pb) {\n if (x + y > i) continue;\n const int z = i - (x + y);\n if (z > num[2]) continue;\n int pat[C]{INF, INF, INF};\n for (int p = 0; p < (i == 0 ? C + 1 : C); ++p) REP(q, C) {\n if (q != p) chmin(pat[q], dp[x][y][p]);\n }\n if (x + 1 <= a) {\n chmin(nx[x + 1][y][0], pat[0] + max(y - left[pos[0][x]][1], 0) + max(z - left[pos[0][x]][2], 0));\n }\n if (y + 1 <= b) {\n chmin(nx[x][y + 1][1], pat[1] + max(z - left[pos[1][y]][2], 0) + max(x - left[pos[1][y]][0], 0));\n }\n if (z + 1 <= num[2]) {\n chmin(nx[x][y][2], pat[2] + max(x - left[pos[2][z]][0], 0) + max(y - left[pos[2][z]][1], 0));\n }\n }\n dp.swap(nx);\n }\n if (dp.size() < num[0] + 1 || dp.front().size() < num[1] + 1) {\n cout << \"-1\\n\";\n return 0;\n }\n const int ans = *min_element(ALL(dp[num[0]][num[1]]));\n cout << (ans == INF ? -1 : ans) << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 8096, "score_of_the_acc": -0.4325, "final_rank": 7 }, { "submission_id": "aoj_0660_5044085", "code_snippet": "#include <iostream>\n#include <numeric>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nconstexpr int INF = 1 << 30;\n\nvoid solve() {\n int n;\n cin >> n;\n\n vector<vector<int>> xss(3);\n for (int i = 0; i < n; ++i) {\n char c;\n cin >> c;\n for (int j = 0; j < 3; ++j) {\n if (c == \"RGY\"[j]) xss[j].push_back(i);\n }\n }\n\n vector<int> ns(3);\n for (int c = 0; c < 3; ++c) ns[c] = xss[c].size();\n\n auto cnt = vector(3, vector(n + 1, vector(n + 1, 0)));\n // [0, i)を除外したとき、j未満はいくつあるか\n for (int c = 0; c < 3; ++c) {\n for (int i = 0; i <= ns[c]; ++i) {\n for (int j = i; j < ns[c]; ++j) {\n ++cnt[c][i][xss[c][j] + 1];\n }\n partial_sum(cnt[c][i].begin(), cnt[c][i].end(),\n cnt[c][i].begin());\n }\n }\n\n auto dp = vector(ns[0] + 1, vector(ns[1] + 1, vector(ns[2] + 1, vector(3, INF))));\n fill(dp[0][0][0].begin(), dp[0][0][0].end(), 0);\n\n vector<int> is(3);\n for (is[0] = 0; is[0] <= ns[0]; ++is[0]) {\n for (is[1] = 0; is[1] <= ns[1]; ++is[1]) {\n for (is[2] = 0; is[2] <= ns[2]; ++is[2]) {\n for (int pc = 0; pc < 3; ++pc) {\n int p = dp[is[0]][is[1]][is[2]][pc];\n\n for (int nc = 0; nc < 3; ++nc) {\n if (nc == pc || is[nc] == ns[nc]) continue;\n\n int d = 0;\n for (int c = 0; c < 3; ++c) {\n d += cnt[c][is[c]][xss[nc][is[nc]]];\n }\n\n ++is[nc];\n dp[is[0]][is[1]][is[2]][nc] = min(dp[is[0]][is[1]][is[2]][nc], p + d);\n --is[nc];\n }\n }\n }\n }\n }\n\n int ans = *min_element(dp[ns[0]][ns[1]][ns[2]].begin(), dp[ns[0]][ns[1]][ns[2]].end());\n cout << (ans == INF ? -1 : ans) << \"\\n\";\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n solve();\n\n return 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 139156, "score_of_the_acc": -1.0687, "final_rank": 18 }, { "submission_id": "aoj_0660_4659692", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing UL = unsigned int;\nusing ULL = unsigned long long;\nusing LL = long long;\n#define rep(i,n) for(UL i=0; i<(n); i++)\n\nUL N;\nchar S[401];\nUL V[401];\nvector<UL> R,G,Y;\nUL D[251][251][251][3];\nUL dp[251][251][251][3];\n\nint main(){\n scanf(\"%u\",&N);\n scanf(\" \");\n scanf(\"%s\",S);\n rep(i,N){\n if(S[i]=='R'){ V[i]=R.size(); R.push_back(i); }\n if(S[i]=='G'){ V[i]=G.size(); G.push_back(i); }\n if(S[i]=='Y'){ V[i]=Y.size(); Y.push_back(i); }\n }\n rep(i,N) if(V[i]>200){ printf(\"-1\\n\"); return 0; }\n rep(iR,R.size()+1) rep(iG,G.size()+1) rep(iY,Y.size()+1) rep(j,3)\n D[iR][iG][iY][j]=N;\n for(UL i=N-1; i!=~0u; i--){\n if(S[i]=='R'){\n rep(iG,G.size()+1) rep(iY,Y.size()+1){\n rep(j,3) D[V[i]][iG][iY][j] = D[V[i]+1][iG][iY][j];\n D[V[i]][iG][iY][0] = V[i]+iG+iY;\n }\n }\n if(S[i]=='G'){\n rep(iR,R.size()+1) rep(iY,Y.size()+1){\n rep(j,3) D[iR][V[i]][iY][j] = D[iR][V[i]+1][iY][j];\n D[iR][V[i]][iY][1] = iR+V[i]+iY;\n }\n }\n if(S[i]=='Y'){\n rep(iR,R.size()+1) rep(iG,G.size()+1){\n rep(j,3) D[iR][iG][V[i]][j] = D[iR][iG][V[i]+1][j];\n D[iR][iG][V[i]][2] = iR+iG+V[i];\n }\n }\n }\n\n rep(iR,R.size()+1) rep(iG,G.size()+1) rep(iY,Y.size()+1) rep(j,3)\n dp[iR][iG][iY][j]=(~0u)>>1;\n rep(j,3) dp[0][0][0][j] = 0;\n rep(iR,R.size()+1) rep(iG,G.size()+1) rep(iY,Y.size()+1){\n UL p=iR+iG+iY;\n if(iR) dp[iR][iG][iY][0] = min(dp[iR-1][iG][iY][1],dp[iR-1][iG][iY][2])+D[iR-1][iG][iY][0]-p+1;\n if(iG) dp[iR][iG][iY][1] = min(dp[iR][iG-1][iY][0],dp[iR][iG-1][iY][2])+D[iR][iG-1][iY][1]-p+1;\n if(iY) dp[iR][iG][iY][2] = min(dp[iR][iG][iY-1][0],dp[iR][iG][iY-1][1])+D[iR][iG][iY-1][2]-p+1;\n }\n UL ans = (~0u)>>1;\n rep(j,3) ans = min(ans,dp[R.size()][G.size()][Y.size()][j]);\n if(ans==(~0u)>>1) printf(\"-1\\n\");\n else printf(\"%u\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 241384, "score_of_the_acc": -1.1667, "final_rank": 19 }, { "submission_id": "aoj_0660_4615245", "code_snippet": "#include <cstdio>\n#include <algorithm>\n\nusing namespace std;\n\nconst int MAXN = 400;\nconst int INFV = 1001001001;\n\nint N;\nchar S[MAXN + 1]; int A[MAXN];\nint dp[MAXN + 1][MAXN + 1][MAXN + 1][3];\nint cnts[3], locs[3][MAXN], prevs[3][MAXN];\n\nvoid chmin(int& x, int y)\n{\n x = min(x, y);\n}\n\nint main()\n{\n scanf(\"%d%s\", &N, S);\n\n for (int i = 0; i < N; ++i) {\n switch (S[i]) {\n case 'R': A[i] = 0; break;\n case 'G': A[i] = 1; break;\n case 'Y': A[i] = 2; break;\n }\n }\n\n for (int i = 0; i < 3; ++i) cnts[i] = 0;\n for (int i = 0; i < N; ++i) {\n locs[A[i]][cnts[A[i]]++] = i;\n for (int j = 0; j < 3; ++j) prevs[j][i] = cnts[j];\n }\n\n for (int a = 0; a <= cnts[0]; ++a) {\n for (int b = 0; b <= cnts[1]; ++b) {\n for (int c = 0; c <= cnts[2]; ++c) {\n for (int s = 0; s < 3; ++s) {\n dp[a][b][c][s] = INFV;\n }\n }\n }\n }\n\n dp[0][0][0][0] = dp[0][0][0][1] = dp[0][0][0][2] = 0;\n\n for (int a = 0; a <= cnts[0]; ++a) {\n for (int b = 0; b <= cnts[1]; ++b) {\n for (int c = 0; c <= cnts[2]; ++c) {\n for (int s = 0; s < 3; ++s) {\n if (s != 0 && a < cnts[0]) {\n int p = locs[0][a];\n chmin(dp[a + 1][b][c][0], dp[a][b][c][s] + max(0, prevs[1][p] - b) + max(0, prevs[2][p] - c));\n }\n if (s != 1 && b < cnts[1]) {\n int p = locs[1][b];\n chmin(dp[a][b + 1][c][1], dp[a][b][c][s] + max(0, prevs[0][p] - a) + max(0, prevs[2][p] - c));\n }\n if (s != 2 && c < cnts[2]) {\n int p = locs[2][c];\n chmin(dp[a][b][c + 1][2], dp[a][b][c][s] + max(0, prevs[0][p] - a) + max(0, prevs[1][p] - b));\n }\n }\n }\n }\n }\n\n int ret = min({ dp[cnts[0]][cnts[1]][cnts[2]][0], dp[cnts[0]][cnts[1]][cnts[2]][1], dp[cnts[0]][cnts[1]][cnts[2]][2] });\n if (ret >= INFV) ret = -1;\n printf(\"%d\\n\", ret);\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 164692, "score_of_the_acc": -0.7876, "final_rank": 13 }, { "submission_id": "aoj_0660_4416445", "code_snippet": "#include <algorithm>\n#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main(){\n int N;\n cin >> N;\n vector<int> S(N);\n vector<vector<int>> I(3);\n vector<vector<int>> cnt(N,vector<int>(3));\n {\n string s;\n cin >> s;\n map<char,int> R;\n R['R'] = 0;\n R['G'] = 1;\n R['Y'] = 2;\n for(int i = 0; i < N; ++i){\n S[i] = R[s[i]];\n I[S[i]].push_back(i);\n ++cnt[i][S[i]];\n }\n for(int i = 1; i < N; ++i){\n for(int j = 0; j < 3; ++j)\n cnt[i][j] += cnt[i-1][j];\n }\n }\n int r = I[0].size(), g = I[1].size(), b = I[2].size();\n int sz[] = {r,g,b};\n for(int i = 0; i < 3; ++i)\n I[i].push_back(N);\n const int INF = 1e9;\n vector<vector<vector<vector<int>>>> dp(r+1,vector<vector<vector<int>>>(g+1,vector<vector<int>>(b+1,vector<int>(3,INF))));\n for(int i = 0; i < 3; ++i)\n dp[0][0][0][i] = 0;\n\n for(int i = 0; i <= r; ++i){\n for(int j = 0; j <= g; ++j){\n for(int k = 0; k <= b; ++k){\n for(int l = 0; l < 3; ++l){\n if(dp[i][j][k][l] >= INF) continue;\n for(int m = 0; m < 3; ++m){\n vector<int> tmp = {i,j,k};\n if(tmp[m] >= sz[m]) continue;\n if(l == m) continue;\n int idx = I[m][tmp[m]];\n int c = 0;\n for(int n = 0; n < 3; ++n){\n if(n == m) continue;\n c += max(0,cnt[idx][n] - tmp[n]);\n }\n ++tmp[m];\n auto& lv = dp[tmp[0]][tmp[1]][tmp[2]][m];\n lv = min(lv,dp[i][j][k][l]+c);\n }\n }\n }\n }\n }\n int ans = INF;\n for(int i = 0; i < 3; ++i)\n ans = min(ans,dp[r][g][b][i]);\n if(ans >= INF) ans = -1;\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 137352, "score_of_the_acc": -1.5611, "final_rank": 20 }, { "submission_id": "aoj_0660_4413187", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 410, INF = 1 << 29;\nchar s[N];\nint a[N], cnt[N][3], ord[3][N];\nint dp[N][N][3], tmp[N][N][3];\nint mp[256];\nint main() {\n mp['R'] = 0;\n mp['Y'] = 1;\n mp['G'] = 2;\n int n;\n scanf(\"%d%s\", &n, s + 1);\n for (int i = 1; i <= n; ++i) {\n a[i] = mp[s[i]];\n for (int j = 0; j < 3; ++j) cnt[i][j] = cnt[i - 1][j] + (a[i] == j);\n ord[a[i]][cnt[i][a[i]]] = i;\n }\n fill(**dp, dp[N - 1][N - 1] + 3, INF);\n dp[0][0][0] = dp[0][0][1] = dp[0][0][2] = 0;\n int n0 = cnt[n][0], n1 = cnt[n][1], n2 = cnt[n][2];\n for (int i = 0; i < n; ++i) {\n memcpy(tmp, dp, sizeof(tmp));\n fill(**dp, dp[N - 1][N - 1] + 3, INF);\n for (int r0 = 0; r0 <= n0; ++r0)\n for (int r1 = 0; r1 <= n1; ++r1) {\n int r2 = i - r0 - r1;\n if (r2 > n2 || r2 < 0)\n continue;\n for (int f = 0; f < 3; ++f) {\n for (int t = 0; t < 3; ++t) {\n if (t == f)\n continue;\n int q0 = r0 + (t == 0), q1 = r1 + (t == 1), q2 = r2 + (t == 2);\n if (q0 > n0 || q1 > n1 || q2 > n2)\n continue;\n int cdp = tmp[r0][r1][f];\n static int qa[3];\n qa[0] = q0;\n qa[1] = q1;\n qa[2] = q2;\n int pos = ord[t][qa[t]];\n for (int j = 0; j < 3; ++j) cdp += max(0, cnt[pos][j] - qa[j]);\n dp[q0][q1][t] = min(dp[q0][q1][t], cdp);\n }\n }\n }\n }\n int ans = *min_element(dp[n0][n1], dp[n0][n1] + 3);\n printf(\"%d\\n\", ans < INF ? ans : -1);\n return 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 7236, "score_of_the_acc": -0.4845, "final_rank": 9 }, { "submission_id": "aoj_0660_4267307", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nstring S;\nvector<int> V[3];\nint N, A[409], D[3][409];\nint dp[409][409][409][3];\n\nint main() {\n\tcin >> N >> S;\n\tfor (int i = 0; i < S.size(); i++) {\n\t\tif (S[i] == 'R') A[i] = 0;\n\t\tif (S[i] == 'G') A[i] = 1;\n\t\tif (S[i] == 'Y') A[i] = 2;\n\t\tD[A[i]][i + 1] = 1;\n\t\tV[A[i]].push_back(i);\n\t}\n\tfor (int i = 1; i <= N; i++) {\n\t\tD[0][i] += D[0][i - 1];\n\t\tD[1][i] += D[1][i - 1];\n\t\tD[2][i] += D[2][i - 1];\n\t}\n\n\tfor (int i = 0; i <= D[0][N]; i++) {\n\t\tfor (int j = 0; j <= D[1][N]; j++) {\n\t\t\tfor (int k = 0; k <= D[2][N]; k++) {\n\t\t\t\tdp[i][j][k][0] = 1000000;\n\t\t\t\tdp[i][j][k][1] = 1000000;\n\t\t\t\tdp[i][j][k][2] = 1000000;\n\t\t\t}\n\t\t}\n\t}\n\n\tdp[0][0][0][0] = 0;\n\tdp[0][0][0][1] = 0;\n\tdp[0][0][0][2] = 0;\n\tfor (int i = 0; i <= D[0][N]; i++) {\n\t\tfor (int j = 0; j <= D[1][N]; j++) {\n\t\t\tfor (int k = 0; k <= D[2][N]; k++) {\n\t\t\t\tif (i < D[0][N]) {\n\t\t\t\t\tint S1 = max(0, D[1][V[0][i]] - j);\n\t\t\t\t\tint S2 = max(0, D[2][V[0][i]] - k);\n\t\t\t\t\tdp[i + 1][j][k][0] = min(dp[i + 1][j][k][0], dp[i][j][k][1] + S1 + S2);\n\t\t\t\t\tdp[i + 1][j][k][0] = min(dp[i + 1][j][k][0], dp[i][j][k][2] + S1 + S2);\n\t\t\t\t}\n\t\t\t\tif (j < D[1][N]) {\n\t\t\t\t\tint S1 = max(0, D[0][V[1][j]] - i);\n\t\t\t\t\tint S2 = max(0, D[2][V[1][j]] - k);\n\t\t\t\t\tdp[i][j + 1][k][1] = min(dp[i][j + 1][k][1], dp[i][j][k][0] + S1 + S2);\n\t\t\t\t\tdp[i][j + 1][k][1] = min(dp[i][j + 1][k][1], dp[i][j][k][2] + S1 + S2);\n\t\t\t\t}\n\t\t\t\tif (k < D[2][N]) {\n\t\t\t\t\tint S1 = max(0, D[0][V[2][k]] - i);\n\t\t\t\t\tint S2 = max(0, D[1][V[2][k]] - j);\n\t\t\t\t\tdp[i][j][k + 1][2] = min(dp[i][j][k + 1][2], dp[i][j][k][0] + S1 + S2);\n\t\t\t\t\tdp[i][j][k + 1][2] = min(dp[i][j][k + 1][2], dp[i][j][k][1] + S1 + S2);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint c0 = dp[D[0][N]][D[1][N]][D[2][N]][0];\n\tint c1 = dp[D[0][N]][D[1][N]][D[2][N]][1];\n\tint c2 = dp[D[0][N]][D[1][N]][D[2][N]][2];\n\tint val = min({ c0, c1, c2 });\n\tif (val == 1000000) cout << \"-1\" << endl;\n\telse cout << val << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 165148, "score_of_the_acc": -0.7339, "final_rank": 12 }, { "submission_id": "aoj_0660_4172517", "code_snippet": "// #pragma GCC target(\"avx\") // CPU 処理並列化\n// #pragma GCC optimize(\"O3\") // CPU 処理並列化\n// #pragma GCC optimize(\"unroll-loops\") // 条件処理の呼び出しを減らす\n// #define BEGIN_STACK_EXTEND(size) void * stack_extend_memory_ = malloc(size);void * stack_extend_origin_memory_;char * stack_extend_dummy_memory_ = (char*)alloca((1+(int)(((long long)stack_extend_memory_)&127))*16);*stack_extend_dummy_memory_ = 0;asm volatile(\"mov %%rsp, %%rbx\\nmov %%rax, %%rsp\":\"=b\"(stack_extend_origin_memory_):\"a\"((char*)stack_extend_memory_+(size)-1024));\n// #define END_STACK_EXTEND asm volatile(\"mov %%rax, %%rsp\"::\"a\"(stack_extend_origin_memory_));free(stack_extend_memory_);\n\n#include<stdio.h>\n#include<math.h>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<string>\n#include<string.h>\n#include<vector>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stdlib.h>\n#include<cassert>\n#include<time.h>\n#include<bitset>\n#include<numeric>\n#include<unordered_set>\n#include<unordered_map>\n#include<complex>\nusing namespace std;\nconst long long mod=1000000007;\nconst long long inf=mod*mod;\nconst long long d2=(mod+1)/2;\nconst long double EPS=1e-20;\nconst double INF=1e+10;\nconst double PI=acos(-1.0);\nconst int C_SIZE = 3100000;\nconst int UF_SIZE = 4100000;\nnamespace{\n\tlong long fact[C_SIZE];\n\tlong long finv[C_SIZE];\n\tlong long inv[C_SIZE];\n\tlong long Comb(int a,int b){\n\t \tif(a<b||b<0)return 0;\n\t \treturn fact[a]*finv[b]%mod*finv[a-b]%mod;\n\t}\n\tvoid init_C(int n){\n\t\tfact[0]=finv[0]=inv[1]=1;\n\t\tfor(int i=2;i<n;i++){\n\t\t\tinv[i]=(mod-(mod/i)*inv[mod%i]%mod)%mod;\n\t\t}\n\t\tfor(int i=1;i<n;i++){\n\t\t\tfact[i]=fact[i-1]*i%mod;\n\t\t\tfinv[i]=finv[i-1]*inv[i]%mod;\n\t\t}\n\t}\n\tlong long pw(long long a,long long b){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%mod;\n\t\t\ta=a*a%mod;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tlong long pw_mod(long long a,long long b,long long M){\n\t\tif(a<0LL)return 0;\n\t\tif(b<0LL)return 0;\n\t\tlong long ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=ret*a%M;\n\t\t\ta=a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint pw_mod_int(int a,int b,int M){\n\t\tif(a<0)return 0;\n\t\tif(b<0)return 0;\n\t\tint ret=1;\n\t\twhile(b){\n\t\t\tif(b%2)ret=(long long)ret*a%M;\n\t\t\ta=(long long)a*a%M;\n\t\t\tb/=2;\n\t\t}\n\t\treturn ret;\n\t}\n\tint ABS(int a){return max(a,-a);}\n\tlong long ABS(long long a){return max(a,-a);}\n\tdouble ABS(double a){return max(a,-a);}\n\tint sig(double r) { return (r < -EPS) ? -1 : (r > +EPS) ? +1 : 0; }\n\tint UF[UF_SIZE];\n\tvoid init_UF(int n){\n\t\tfor(int i=0;i<n;i++)UF[i]=-1;\n\t}\n\tint FIND(int a){\n\t\tif(UF[a]<0)return a;\n\t\treturn UF[a]=FIND(UF[a]);\n\t}\n\tvoid UNION(int a,int b){\n\t\ta=FIND(a);b=FIND(b);if(a==b)return;\n\t\tif(UF[a]>UF[b])swap(a,b);\n\t\tUF[a]+=UF[b];UF[b]=a;\n\t}\n}\n// ここから編集しろ\nchar in[410];\nint dp[2][410][410][3];\nint ct[410][3];\nint r[410];\nint g[410];\nint y[410];\nint main(){\n\tint a;scanf(\"%d%s\",&a,in);\n\tint R=0;\n\tint G=0;\n\tint Y=0;\n\n\tfor(int i=0;i<a;i++){\n\t\tif(in[i]=='R'){r[R++]=i;}\n\t\telse if(in[i]=='G'){g[G++]=i;}\n\t\telse {y[Y++]=i;}\n\t\tct[i+1][0]=R;\n\t\tct[i+1][1]=G;\n\t\tct[i+1][2]=Y;\n\t}\n\tfor(int i=0;i<2;i++)for(int j=0;j<410;j++)for(int k=0;k<410;k++)for(int l=0;l<3;l++)\n\t\tdp[i][j][k][l]=mod;\n\tdp[0][0][0][0]=dp[0][0][0][1]=dp[0][0][0][2]=0;\n\tfor(int i=0;i<a;i++){\n\t\tint t=i%2;\n\t\tfor(int j=0;j<=R;j++)for(int k=0;k<=G;k++)for(int l=0;l<3;l++)dp[!t][j][k][l]=mod;\n\t\tfor(int j=0;j<=R;j++)for(int k=0;k<=G;k++)for(int l=0;l<3;l++){\n\t\t\tif(dp[t][j][k][l]==mod)continue;\n\t\t\t// printf(\"%d %d %d %d: %d\\n\",i,j,k,l,dp[t][j][k][l]);\n\t\t\tif(l!=0&&j<R){\n\t\t\t\tint toc=dp[t][j][k][l];\n\t\t\t\tint at=r[j];\n\t\t\t\ttoc+=max(0,ct[at][1]-k);\n\t\t\t\ttoc+=max(0,ct[at][2]-(i-j-k));\n\t\t\t\tdp[!t][j+1][k][0]=min(dp[!t][j+1][k][0],toc);\n\t\t\t}\n\t\t\tif(l!=1&&k<G){\n\t\t\t\tint toc=dp[t][j][k][l];\n\t\t\t\tint at=g[k];\n\t\t\t\ttoc+=max(0,ct[at][0]-j);\n\t\t\t\ttoc+=max(0,ct[at][2]-(i-j-k));\n\t\t\t\tdp[!t][j][k+1][1]=min(dp[!t][j][k+1][1],toc);\n\t\t\t}\n\t\t\tif(l!=2&&(i-j-k)<Y){\n\t\t\t\tint toc=dp[t][j][k][l];\n\t\t\t\tint at=y[i-j-k];\n\t\t\t\ttoc+=max(0,ct[at][0]-j);\n\t\t\t\ttoc+=max(0,ct[at][1]-k);\n\t\t\t\tdp[!t][j][k][2]=min(dp[!t][j][k][2],toc);\n\t\t\t}\n\t\t}\n\t}\n\tint ret=mod;\n\tfor(int i=0;i<3;i++)ret=min(ret,dp[a%2][R][G][i]);\n\tif(ret==mod)ret=-1;\n\tprintf(\"%d\\n\",ret);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 6712, "score_of_the_acc": -0.1767, "final_rank": 3 }, { "submission_id": "aoj_0660_4165467", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nll N;\nstring S;\n\nll dp[401][401][401][3];\n\nvector<ll> idx[3]; // R,G,Y;\nvector<ll> back[3];\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n cin >> N >> S;\n\n back[0] = vector<ll>(N);\n back[1] = vector<ll>(N);\n back[2] = vector<ll>(N);\n\n back[0][N-1] = 0;\n back[1][N-1] = 0;\n back[2][N-1] = 0;\n\n if(S[N-1] == 'R') back[0][N-1] = 1;\n if(S[N-1] == 'G') back[1][N-1] = 1;\n if(S[N-1] == 'Y') back[2][N-1] = 1;\n\n for (int i = N-2;i >= 0;i--){\n for (int j = 0;j < 3;j++){\n back[j][i] = back[j][i+1];\n }\n if(S[i] == 'R') back[0][i]++;\n if(S[i] == 'G') back[1][i]++;\n if(S[i] == 'Y') back[2][i]++;\n }\n\n for (int i = 0;i < N;i++){\n if(S[i] == 'R') idx[0].push_back(i);\n if(S[i] == 'G') idx[1].push_back(i);\n if(S[i] == 'Y') idx[2].push_back(i);\n }\n\n for (int i = 0;i <= idx[0].size();i++){\n for (int j = 0;j <= idx[1].size();j++){\n for (int k = 0;k <= idx[2].size();k++){\n for (int l = 0;l < 3;l++){\n dp[i][j][k][l] = LLONG_MAX;\n }\n }\n }\n }\n\n dp[0][0][0][0] = 0; //i,j,k:次の位置\n dp[0][0][0][1] = 0;\n dp[0][0][0][2] = 0;\n\n for (int i = 0;i <= idx[0].size();i++){\n for (int j = 0;j <= idx[1].size();j++){\n for (int k = 0;k <= idx[2].size();k++){\n for (int l = 0;l < 3;l++){\n //cout << i << \" \" << j << \" \" << k << \" \" << dp[i][j][k] << endl;\n if(dp[i][j][k][l] == LLONG_MAX) continue;\n //cout << i << \" \" << j << \" \" << k << \" \" << dp[i][j][k][l] << endl;\n if(i != idx[0].size() && l != 0)dp[i+1][j][k][0] = min(dp[i+1][j][k][0], dp[i][j][k][l]+max<ll>(idx[1].size()-j-back[1][idx[0][i]],0LL)+max<ll>(idx[2].size()-k-back[2][idx[0][i]],0LL));\n if(j != idx[1].size() && l != 1)dp[i][j+1][k][1] = min(dp[i][j+1][k][1], dp[i][j][k][l]+max<ll>(idx[0].size()-i-back[0][idx[1][j]],0LL)+max<ll>(idx[2].size()-k-back[2][idx[1][j]],0LL));\n if(k != idx[2].size() && l != 2)dp[i][j][k+1][2] = min(dp[i][j][k+1][2], dp[i][j][k][l]+max<ll>(idx[0].size()-i-back[0][idx[2][k]],0LL)+max<ll>(idx[1].size()-j-back[1][idx[2][k]],0LL));\n }\n }\n }\n }\n\n ll ans = min({ dp[idx[0].size()][idx[1].size()][idx[2].size()][0] ,dp[idx[0].size()][idx[1].size()][idx[2].size()][1], dp[idx[0].size()][idx[1].size()][idx[2].size()][2]});\n if(ans == LLONG_MAX) ans = -1;\n\n cout << ans << endl;\n\n return 0;\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 166224, "score_of_the_acc": -0.794, "final_rank": 14 }, { "submission_id": "aoj_0660_3992958", "code_snippet": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\nint N,M,K,L,R,H,W;\n//long long int N,M,K,L,R,H,W;\n\nconstexpr long long int MOD=1000000007;\n//constexpr int MOD=1000000007;\n//constexpr int MOD=998244353;\n//constexpr long long int MOD=998244353;\n\nconstexpr long double EPS=1e-8;\n\nint dp[201][201][201][3];\n\nint main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\t\n\tcin>>N;\n\tstring s;\n\tcin>>s;\n\tvector<int>v;\n\tint one=0,two=0,zero=0;\n\tfor(auto i:s){\n\t\tif(i=='R'){\n\t\t\tv.push_back(0);\n\t\t\tzero++;\n\t\t}\n\t\telse if(i=='G'){\n\t\t\tv.push_back(1);\n\t\t\tone++;\n\t\t}\n\t\telse {\n\t\t\tv.push_back(2);\n\t\t\ttwo++;\n\t\t}\n\t}\n\tif(zero>(N+1)/2||one>(N+1)/2||two>(N+1)/2){\n\t\tcout<<-1<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=0;i<=200;i++)for(int j=0;j<=200;j++)for(int k=0;k<200;k++)for(int l=0;l<3;l++)dp[i][j][k][l]=MOD;\n\tvector<pair<int,int>>oneP;\n\tvector<pair<int,int>>twoP;\n\tvector<pair<int,int>>zeroP;\n\tvector<int>oneplace;\n\tvector<int>twoplace;\n\tvector<int>zeroplace;\n\tint a=0,b=0,c=0;\n\tfor(int i=0;i<N;i++){\n\t\tif(v[i]==1){\n\t\t\toneP.push_back({c,b});\n\t\t\toneplace.push_back(i);\n\t\t\ta++;\n\t\t}\n\t\telse if(v[i]==2){\n\t\t\ttwoP.push_back({c,a});\n\t\t\ttwoplace.push_back(i);\n\t\t\tb++;\n\t\t}\n\t\telse{\n\t\t\tzeroP.push_back({a,b});\n\t\t\tzeroplace.push_back(i);\n\t\t\tc++;\n\t\t}\n\t}\n\tif(one)dp[0][1][0][1]=oneplace[0];\n\tif(two)dp[0][0][1][2]=twoplace[0];\n\tif(zero)dp[1][0][0][0]=zeroplace[0];\n\tfor(int i=0;i<=zero;i++){\n\t\tfor(int j=0;j<=one;j++){\n\t\t\tfor(int k=0;k<=two;k++){\n\t\t\t\tif(!i&&!j&&!k)continue;\n\t\t\t\tfor(int l=0;l<3;l++){\n\t\t\t\t\tif(l!=0&&i<zero){\n\t\t\t\t\t\tdp[i+1][j][k][0]=min(dp[i+1][j][k][0],dp[i][j][k][l]+zeroplace[i]+max(0,j-zeroP[i].first)+max(0,k-zeroP[i].second)-i-j-k);\n\t\t\t\t\t}\n\t\t\t\t\tif(l!=1&&j<one){\n\t\t\t\t\t\tdp[i][j+1][k][1]=min(dp[i][j+1][k][1],dp[i][j][k][l]+oneplace[j]+max(0,i-oneP[j].first)+max(0,k-oneP[j].second)-i-j-k);\n\t\t\t\t\t}\n\t\t\t\t\tif(l!=2&&k<two){\n\t\t\t\t\t\tdp[i][j][k+1][2]=min(dp[i][j][k+1][2],dp[i][j][k][l]+twoplace[k]+max(0,i-twoP[k].first)+max(0,j-twoP[k].second)-i-j-k);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=0;i<=zero;i++){\n\t\tfor(int j=0;j<=one;j++){\n\t\t\tfor(int k=0;k<=two;k++){\n\t\t\t\tfor(int l=0;l<3;l++){\n\t\t\t\t//\tcout<<i<<\" \"<<j<<\" \"<<k<<\" \"<<l<<\" \"<<dp[i][j][k][l]<<endl;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint ans=MOD;\n\tfor(int i=0;i<3;i++)ans=min(ans,dp[zero][one][two][i]);\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 98396, "score_of_the_acc": -0.5079, "final_rank": 10 }, { "submission_id": "aoj_0660_3988399", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n //#define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n \n\nint dp[410][410][410][3];\nstring s;\n\nint memo[410][3]={};\nvector<int> ve[3];\n\nint solve(int a,int b,int c,int t){\n\tif(a<0 || b<0 || c<0) return inf;\n\tif(a==0 && b==0 && c==0) return 0;\n\tif(dp[a][b][c][t]>=0) return dp[a][b][c][t];\n\tif(t==0 && a==0)dp[a][b][c][t]=inf;\n\tif(t==1 && b==0)dp[a][b][c][t]=inf;\n\tif(t==2 && c==0)dp[a][b][c][t]=inf;\n\tif(dp[a][b][c][t]>=0) return dp[a][b][c][t];\n\tint p=inf,q=inf;\n\tif(t==0)if(a>=1){\n\t\tint T=max(0,memo[ve[0][a-1]][2]-c)+max(0,memo[ve[0][a-1]][1]-b);\n\t\tp=solve(a-1,b,c,1)+T;\n\t\tq=solve(a-1,b,c,2)+T;\n\t\t\n\t}\n\tif(t==1)if(b>=1){\n\t\tint T=max(0,memo[ve[1][b-1]][0]-a)+max(0,memo[ve[1][b-1]][2]-c);\n\t\tif(b>=1)p=solve(a,b-1,c,0)+T;\n\t\tif(b>=1)q=solve(a,b-1,c,2)+T;\n\t}\n\tif(t==2)if(c>=1){\n\t\tint T=max(0,memo[ve[2][c-1]][0]-a)+max(0,memo[ve[2][c-1]][1]-b);\n\t\tif(c>=1)p=solve(a,b,c-1,0)+T;\n\t\tif(c>=1)q=solve(a,b,c-1,1)+T;\n\t}\n\t//cout<<a<<\" \"<<b<<\" \"<<c<<\" \"<<t<<\" \"<<p<<\" \"<<q<<endl;\n\tp=min(p,inf);\ndp[a][b][c][t]=min(p,q);\nreturn min(p,q);\n\t\n\t\n\t\n}\n\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\tint n;\n\tcin>>n;\n\tcin>>s;\n\t\n\tint t1=0,t2=0,t3=0;\n\tint yy=0;\n\tfor(auto c:s){\n\t\tt1+=c=='R';\n\t\tt2+=c=='G';\n\t\tt3+=c=='Y';\n\t\tif(c=='R')memo[yy][0]++,ve[0].pb(yy);\n\t\tif(c=='G')memo[yy][1]++,ve[1].pb(yy);\n\t\tif(c=='Y')memo[yy][2]++,ve[2].pb(yy);\n\t\tyy++;\n\t}\n\tfor(int i=1;i<n;i++)for(int j=0;j<3;j++)memo[i][j]+=memo[i-1][j];\n\t\n\tfor(int i=0;i<=t1;i++)for(int j=0;j<=t2;j++)for(int k=0;k<=t3;k++)for(int h=0;h<3;h++)dp[i][j][k][h]=-1;\n\t\n\t\tint y=min({solve(t1,t2,t3,0),solve(t1,t2,t3,1),solve(t1,t2,t3,2)});\n\tif(y>=inf)cout<<-1<<endl;\n\telse cout<<y<<endl;\n\t\n\treturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 70, "memory_kb": 165164, "score_of_the_acc": -0.8451, "final_rank": 16 }, { "submission_id": "aoj_0660_3967189", "code_snippet": "#include <algorithm>\n#include <array>\n#include <cassert>\n#include <cmath>\n#include <deque>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <iterator>\n#include <limits>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\nstatic_assert(sizeof(long) == 8, \"long must be 64-bit.\");\n\nint sindex(const string& S, char c, int start = 0)\n{\n for (int i = start; ; ++i)\n if (S[i] == c)\n return i;\n}\n\nvoid set_min(int& a, int v)\n{\n if (a > v)\n a = v;\n}\n\nint solve(int N, const string& S)\n{\n const int INF = (N + 1) * (N + 1);\n\n int cr = 0, cg = 0, cy = 0;\n for (char c : S) {\n switch (c) {\n case 'R':\n ++cr;\n break;\n case 'G':\n ++cg;\n break;\n case 'Y':\n ++cy;\n break;\n }\n }\n\n vector<vector<vector<array<int, 3>>>> move_table(\n cr + 1, vector<vector<array<int, 3>>>(\n cg + 1, vector<array<int, 3>>(\n cy + 1)));\n for (int ur = 0; ur <= cr; ++ur) {\n for (int ug = 0; ug <= cg; ++ug) {\n string B;\n int rr = ur;\n int rg = ug;\n for (char c : S) {\n if (c == 'R' && rr > 0) {\n --rr;\n } else if (c == 'G' && rg > 0) {\n --rg;\n } else {\n B.push_back(c);\n }\n }\n int lenb = (int)B.size();\n int ri = ur < cr ? sindex(B, 'R') : lenb;\n int gi = ug < cg ? sindex(B, 'G') : lenb;\n int yi = cy > 0 ? sindex(B, 'Y') : lenb;\n\n int roff = 0, goff = 0, yoff = 0;\n\n for (int uy = 0; uy < cy; ++uy) {\n move_table[ur][ug][uy] = {\n ri - roff,\n gi - goff,\n yi - yoff,\n };\n\n if (ri > yi)\n ++roff;\n if (gi > yi)\n ++goff;\n ++yoff;\n\n yi = uy < cy - 1 ? sindex(B, 'Y', yi + 1) : lenb;\n }\n\n move_table[ur][ug][cy] = {\n ri - roff,\n gi - goff,\n yi - yoff,\n };\n }\n }\n\n vector<vector<array<int, 3>>> dp(\n cr + 1, vector<array<int, 3>>(\n cg + 1, {INF, INF, INF}));\n dp[0][0] = {0, 0, 0};\n\n for (int ut = 0; ut < N; ++ut) {\n vector<vector<array<int, 3>>> ndp(\n cr + 1, vector<array<int, 3>>(\n cg + 1, {INF, INF, INF}));\n\n for (int ur = 0; ur <= min(ut, cr); ++ur) {\n int rest = ut - ur;\n for (int ug = min(rest, cg); ug >= 0; --ug) {\n int uy = ut - ur - ug;\n if (uy > cy)\n break;\n for (int col = 0; col < 3; ++col) {\n int dv = dp[ur][ug][col];\n if (dv == INF)\n continue;\n if (ur < cr && col != 0) {\n set_min(ndp[ur + 1][ug][0],\n dv + move_table[ur][ug][uy][0]);\n }\n if (ug < cg && col != 1) {\n set_min(ndp[ur][ug + 1][1],\n dv + move_table[ur][ug][uy][1]);\n }\n if (uy < cy && col != 2) {\n set_min(ndp[ur][ug][2],\n dv + move_table[ur][ug][uy][2]);\n }\n }\n }\n }\n\n dp.swap(ndp);\n }\n\n int ans = min(dp[cr][cg][0],\n min(dp[cr][cg][1], dp[cr][cg][2]));\n if (ans == INF)\n return -1;\n return ans;\n}\n\nint main()\n{\n int N;\n cin >> N;\n string S;\n cin >> S;\n cout << solve(N, S) << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 32488, "score_of_the_acc": -0.341, "final_rank": 6 } ]
aoj_0655_cpp
日本沈没 (Japan Sinks) 問題文 日本列島は細長い列島である.日本列島は平行な境界線により N 個の区画に分けられている.区画には端から順に 1 から N の番号が付けられている.区画 i ( 1 ≦ i ≦ N ) の高さは A_i である. 日本列島は海に囲まれており,海面の高さは場所によらず一定である.高さが海面の高さより高い区画を 陸地 と呼ぶ. 陸地が連続している部分のことを 島 と呼ぶ.より正確に書くと以下の通りである.整数 l , r ( 1 ≦ l ≦ r ≦ N ) について,日本列島のうち区画 l ,区画 l+1 , ... ,区画 r からなる部分を 領域 [ l, r ] という.以下の条件を満たす領域 [ l, r ] を島という: 区画 l ,区画 l+1 , ... ,区画 r はすべて陸地である. l>1 ならば区画 l-1 は陸地ではない. r<N ならば区画 r+1 は陸地ではない. 海面の上昇により,日本列島は少しずつ沈没している.現在の海面の高さは 0 であるが,これは時間が経つにつれて徐々に上がり,ついには日本全体が海になってしまう. JOI 君は,海面の高さが上昇すると,日本の島の数が増減することに気付いた.現在から,日本に陸地がなくなるまでの間 (現在も含む) における,島の数の最大値を求めたい. 制約 1 ≦ N ≦ 100000 (= 10^5) 0 ≦ A_i ≦ 1000000000 (= 10^9) ( 1 ≦ i ≦ N ) 入力・出力 入力 入力は以下の形式で標準入力から与えられる. N A_1 A_2 ... A_N 出力 現在から,日本に陸地がなくなるまでの間 (現在も含む) における,島の数の最大値を 1 行で出力せよ. 入出力例 入力例 1 6 0 1 2 1 3 2 出力例 1 2 海面の高さが 0 以上 1 未満のとき,区画 2, 3, 4, 5, 6 が陸地である.領域 [ 2, 6 ] が唯一の島なので,島の数は 1 である. 海面の高さが 1 以上 2 未満のとき,区画 3, 5, 6 が陸地である.領域 [ 3, 3 ] と領域 [ 5, 6 ] が島なので,島の数は 2 である. 海面の高さが 2 以上 3 未満のとき,区画 5 のみが陸地である.領域 [ 5, 5 ] が唯一の島なので,島の数は 1 である. 海面の高さが 3 になると,陸地はなくなり,島の数は 0 になる. よって島の数の最大値は 2 なので, 2 を出力する. 入力例 2 6 3 2 3 0 2 0 出力例 2 2 海面の高さが 0 以上 2 未満のとき,区画 1, 2, 3, 5 が陸地である.領域 [ 1, 3 ] と領域 [ 5, 5 ] が島なので,島の数は 2 である. 海面の高さが 2 以上 3 未満のとき,区画 1, 3 が陸地である.領域 [ 1, 1 ] と領域 [ 3, 3 ] が島なので,島の数は 2 である. 海面の高さが 3 になると,陸地はなくなり,島の数は 0 になる. よって島の数の最大値は 2 なので, 2 を出力する. 入力例 3 10 4 1 2 1 2 3 5 4 3 2 出力例 3 3 情報オリンピック日本委員会作 『第 18 回日本情報オリンピック JOI 2018/2019 予選競技課題』
[ { "submission_id": "aoj_0655_10852971", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<P ,ll> P3;\ntypedef pair<P ,P> PP;\nconst ll MOD = 998244353;\nconst int IINF = INT_MAX;\nconst ll LLINF = LLONG_MAX;\nconst int MAX_N = int(1e5 + 5);\nconst double EPS = 1e-6;\nconst int di[] = {0, 1, 0, -1}, dj[] = {1, 0, -1, 0};\n#define REP(i, n) for (int i = 0; i < n; i++)\n#define REPR(i, n) for (int i = n; i >= 0; i--)\n#define SORT(v) sort((v).begin(), (v).end())\n#define SORTR(v) sort((v).rbegin(), (v).rend())\n#define ALL(v) (v).begin(), (v).end()\n\nstruct UnionFindTree{\n int N;\n vector<int> par, rank, siz;\n\n void init(int n){\n N = n;\n par.resize(N);\n rank.resize(N, 0);\n siz.resize(N, 1);\n for(int i=0;i<N;i++){\n par[i] = i;\n }\n }\n int find(int i){\n if(par[i] == i) return i;\n else return par[i] = find(par[i]);\n }\n void unite(int x, int y){\n x = find(x);\n y = find(y);\n if(x==y) return ;\n if(rank[x] < rank[y]) swap(x, y);\n if(rank[x] == rank[y]) rank[x]++;\n par[y] = x;\n siz[x] += siz[y];\n }\n bool is_same(int x, int y){\n return find(x) == find(y);\n }\n int size(int x){\n x = find(x);\n return siz[x];\n }\n};\n\nll n, a[MAX_N], ans = 0, cnt = 0;\nbool used[MAX_N]{};\n\nint main() {\n vector<pair<ll,ll> > v;\n cin >> n;\n for(int i=0;i<n;i++){\n cin >> a[i];\n v.push_back({a[i], i+1});\n }\n v.push_back({-IINF/2,n+1});\n sort(v.rbegin(), v.rend());\n //UnionFindTree g;\n //g.init(n+5);\n for(int i=0;i<n;i++){\n if(v[i].first == 0) break;\n ll id = v[i].second;\n used[id] = true;\n cnt++;\n if(used[id] && used[id-1]){\n //g.unite(id, id-1);\n cnt--;\n }\n if(used[id] && used[id+1]){\n //g.unite(id, id+1);\n cnt--;\n }\n if(v[i].first > v[i+1].first){\n ans = max(ans, cnt);\n }\n }\n \n cout << ans << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 5780, "score_of_the_acc": -0.4458, "final_rank": 11 }, { "submission_id": "aoj_0655_10454202", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nstruct k{\n int num, index;\n};\nbool cmp(k a, k b){\n return a.index<b.index;\n}\nk k[100002]={};\nbool f[100002]={};\nint n, m=1, ans=1, e=1;\nint main(){\n scanf(\"%d\", &n);\n for(int i=1; i<=n; i++){\n scanf(\"%d\", &k[i].index);\n if(k[i].index) e=0;\n k[i].num=i;\n }\n if(e){\n printf(\"0\\n\");\n return 0;\n }\n f[0]=1;\n f[n+1]=1;\n sort(k+1, k+n+1, cmp);\n for(int i=1; i<=n;){\n int save=k[i].index;\n while(k[i].index==save&&i<=n){\n f[k[i].num]=1;\n if(f[k[i].num-1]==0&&f[k[i].num+1]==0) m++;\n if(f[k[i].num-1]==1&&f[k[i].num+1]==1) m--;\n i++;\n }\n ans=max(ans, m);\n }\n printf(\"%d\\n\", ans);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3864, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0655_9629917", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n\n #ifdef BACKER\n freopen(\"input.txt\", \"r\", stdin);\n // freopen(\"output.txt\", \"w\", stdout);\n #endif\n\n int n;\n cin >> n;\n vector<pair<int, int>> pos;\n for (int i = 1; i <= n; i++) {\n int a;\n cin >> a;\n if (a > 0) pos.push_back({a, i});\n }\n sort(pos.begin(), pos.end(), greater<pair<int, int>>());\n int tmp = 0, ans = 0;\n vector<bool> is_land(n + 3, 0);\n for (int i = 0; i < pos.size(); i++) {\n auto [h, ind] = pos[i];\n is_land[ind] = 1;\n tmp++;\n if (is_land[ind - 1]) tmp--;\n if (is_land[ind + 1]) tmp--;\n if (h != pos[i + 1].first || i == pos.size() - 1) ans = max(ans, tmp);\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4140, "score_of_the_acc": -0.0231, "final_rank": 2 }, { "submission_id": "aoj_0655_9501712", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define pb push_back\n#define all(v) v.begin(), v.end()\n#define fi first\n#define se second\nusing namespace std;\n\nconst ll N = 1e5 + 9;\n\nll n, i, a[N];\nbool check[N];\nvector<ll>vt;\nvector<ll>vec[N];\n\nint main()\n{\n#define TN \"\"\n if (fopen(TN \".inp\", \"r\"))\n {\n freopen(TN \".inp\", \"r\", stdin);\n freopen(TN \".out\", \"w\", stdout);\n }\n cin.tie(0)->sync_with_stdio(0);\n\n cin >> n ;\n\n ll dem = 0;\n check[0] = 1, check[n + 1] = 1;\n for( i = 1; i <= n; i ++ ){\n cin >> a[i];\n if(a[i] == 0)\n check[i] = 1;\n else\n vt.pb(a[i]);\n }\n if( n == 1 )\n {\n cout << (a[1] > 0) << \"\\n\";\n return 0;\n }\n if(vt.size() == 0)\n {\n cout << 0 << \"\\n\";\n return 0;\n }\n dem = 0;\nfor( i = 1; i <= n; i ++ )\n{\n if(check[i - 1] == 1 && check[i] == 0)\n dem ++;\n}\n ll maxn = dem;\n\n sort(all(vt));\n for( i = 1; i <= n; i ++ )\n {\n if(a[i] == 0) continue;\n ll id = lower_bound(all(vt), a[i]) - vt.begin();\n vec[id].pb(i);\n }\n ll ans = maxn;\n for( i = 0; i < vt.size(); i ++ )\n {\n if( i != 0 && vt[i] == vt[i - 1])\n continue;\n if(vec[i].size()){\n for(auto x : vec[i])\n {\n check[x] = 1;\n if(check[x - 1] || check[x + 1] ){\n if(check[x - 1] && check[x + 1])\n maxn --;\n }\n else\n maxn ++;\n }\n }\n ans = max(ans , maxn);\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10356, "score_of_the_acc": -0.6851, "final_rank": 15 }, { "submission_id": "aoj_0655_9501711", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define pb push_back\n#define all(v) v.begin(), v.end()\n#define fi first\n#define se second\nusing namespace std;\n\nconst ll N = 1e5 + 9;\n\nll n, i, a[N];\nbool check[N];\nvector<ll>vt;\nvector<ll>vec[N];\n\nint main()\n{\n#define TN \"\"\n if (fopen(TN \".inp\", \"r\"))\n {\n freopen(TN \".inp\", \"r\", stdin);\n freopen(TN \".out\", \"w\", stdout);\n }\n cin.tie(0)->sync_with_stdio(0);\n\n cin >> n ;\n\n ll dem = 0;\n check[0] = 1, check[n + 1] = 1;\n for( i = 1; i <= n; i ++ ){\n cin >> a[i];\n if(a[i] == 0)\n check[i] = 1;\n else\n vt.pb(a[i]);\n }\n if( n == 1 )\n {\n cout << (a[1] > 0) << \"\\n\";\n return 0;\n }\n if(vt.size() == 0)\n {\n cout << 0 << \"\\n\";\n return 0;\n }\n dem = 0;\nfor( i = 1; i <= n; i ++ )\n{\n if(check[i - 1] == 1 && check[i] == 0)\n dem ++;\n}\n ll maxn = dem;\nvt.pb(0);\n sort(all(vt));\n for( i = 1; i <= n; i ++ )\n {\n if(a[i] == 0) continue;\n ll id = lower_bound(all(vt), a[i]) - vt.begin();\n vec[id].pb(i);\n }\n ll ans = maxn;\n for( i = 1; i < vt.size(); i ++ )\n {\n if(vt[i] == vt[i - 1]) continue;\n for(auto x : vec[i])\n {\n check[x] = 1;\n if(check[x - 1] || check[x + 1] ){\n if(check[x - 1] && check[x + 1])\n maxn --;\n }\n else\n maxn ++;\n }\n ans = max(ans , maxn);\n }\n cout << ans << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10300, "score_of_the_acc": -0.6804, "final_rank": 14 }, { "submission_id": "aoj_0655_8993284", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n vi A(N+2);\n vc<pi> B(N+2);\n B[0] = mp(-1, -1);\n B[N+1] = mp(inf, inf);\n rep(i, 1, N+1) {\n cin >> A[i];\n B[i] = mp(A[i], i);\n }\n sort(all(B));\n ll lands = 0;\n vc<bool> is_land(N+2, false);\n rep(i, 1, N+1) {\n if (A[i] >= 1) {\n is_land[i] = true;\n if (A[i-1] <= 0) {\n lands++;\n }\n }\n }\n ll ans = lands;\n rep(i, 1, N+1) {\n while (i < N+1) {\n auto [h, j] = B[i];\n if (h == 0) break;\n is_land[j] = false;\n if (is_land[j-1] and is_land[j+1]) {\n lands++;\n } elif (!is_land[j-1] and !is_land[j+1]) {\n lands--;\n }\n if (h != B[i+1].fi) {\n break;\n } else {\n i++;\n }\n }\n chmax(ans, lands);\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5456, "score_of_the_acc": -0.133, "final_rank": 9 }, { "submission_id": "aoj_0655_8984209", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned int N, i, cur, max;\n\tcin >> N;\n\tvector<unsigned int> A(N);\n\tvector<pair<unsigned int, unsigned int>> _A(N);\n\tfor (i = 0; i != N; ++i)\n\t\tcin >> A[i], _A[i] = { A[i], i };\n\tstable_sort(_A.begin(), _A.end());\n\n\tif (A[0] == 0) cur = 0;\n\telse cur = 1;\n\tfor (i = 1; i != N; ++i)\n\t\tif (A[i] != 0 && A[i - 1] == 0) ++cur;\n\n\tmax = cur;\n\tfor (i = 0; i != N && _A[i].first == 0; ++i);\n\twhile (i != N)\n\t{\n\t\tdo\n\t\t{\n\t\t\tif (_A[i].second != 0 && A[_A[i].second - 1] != 0)\n\t\t\t{\n\t\t\t\tif (_A[i].second != N - 1 && A[_A[i].second + 1] != 0)\n\t\t\t\t\t++cur;\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tif (_A[i].second == N - 1 || A[_A[i].second + 1] == 0)\n\t\t\t\t\t--cur;\n\t\t\t}\n\n\t\t\tA[_A[i].second] = 0;\n\t\t\t++i;\n\t\t} while (i != N && _A[i].first == _A[i - 1].first);\n\n\t\tif (cur > max) max = cur;\n\t}\n\n\tcout << max << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5196, "score_of_the_acc": -0.1113, "final_rank": 8 }, { "submission_id": "aoj_0655_8499977", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n vector<int> a(n);\n vector<pair<int,int>> v(n);\n for (int i = 0; i < n; ++i) {\n cin >> a[i];\n v[i] = {a[i], i};\n }\n sort(v.rbegin(), v.rend());\n vector<bool> used(n);\n int res = 0;\n int cnt = 0;\n for (int i = 0; i < n; ) {\n if (v[i].first == 0) break;\n int h = v[i].first;\n while (i < n and v[i].first == h) {\n int pos = v[i].second;\n cnt += 1; i += 1;\n used[pos] = true;\n if (pos and used[pos-1]) {\n cnt -= 1;\n }\n if (pos+1 < n and used[pos+1]) {\n cnt -= 1;\n }\n }\n res = max(res, cnt);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4392, "score_of_the_acc": -0.0441, "final_rank": 6 }, { "submission_id": "aoj_0655_8472169", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define st first\n#define nd second\nbool land[100005];\nint main(){\n cin.tie(0) -> sync_with_stdio(0);\n cout.tie(0) -> sync_with_stdio(0);\n int n;\n cin >> n;\n pair<int, int> a[n+1];\n for(int i = 0; i < n; i++){\n int inp;\n cin >> inp;\n if(inp > 0) land[i+1] = 1;\n a[i] = {inp, i+1};\n }\n a[n] = {0, -1};\n sort(a, a+n);\n int cnt = 0;\n bool kt = false;\n for(int i = 1; i <= n+1; i++){\n if(land[i] && kt == false)\n {\n cnt++; \n kt = true;\n }\n if(!land[i] && kt == true) kt = false;\n }\n int cnt1 = cnt;\n int lastlev = -1;\n for(int i = 0; i <= n; i++){\n if(a[i].st == 0) continue;\n if(lastlev != a[i].st){cnt = max(cnt1, cnt); lastlev = a[i].st;}\n land[a[i].nd] = 0;\n if(land[a[i].nd-1] == 1 && land[a[i].nd+1] == 1) cnt1++;\n if(land[a[i].nd-1] == 0 && land[a[i].nd+1] == 0) cnt1--;\n }\n cout << cnt << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4316, "score_of_the_acc": -0.0378, "final_rank": 4 }, { "submission_id": "aoj_0655_8469076", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nbool cmp(pair<int,int> u1,pair<int,int> u2){\n\tif (u1.first==u2.first){\n\t\treturn (u1.second<u2.second);\n\t}\n\treturn (u1.first<u2.first);\n}\nbool cmp1(pair<int,int> u1,pair<int,int> u2){\n\tif (u1.second==u2.second){\n\t\treturn (u1.first<u2.first);\n\t}\n\treturn (u1.second<u2.second);\n}\nint main(){\n\tint n;cin>>n;pair<int,int> a[n+2]={};vector<int> v;map<int,int> mp1,mp;\n\tfor (int i=1;i<=n;i++){\n\t\tcin>>a[i].first;a[i].second=i;\n\t\tv.push_back(a[i].first);\n\t}\n\tv.push_back(0);\n\tsort(v.begin(),v.end());\n\tsort(a+1,a+n+1,cmp);\n//\tfor (int i=1;i<=n;i++) cout<<a[i].first<<\" \"<<a[i].second<<endl;\n\tint d=n,ans=0,cnt=0;\n\tfor (int i=v.size()-1;i>=0;i--){\n\t\twhile (d>=1){\n\t\t\tif (a[d].first>v[i]){\n\t\t\t\tcnt++;\n//\t\t\t\tif ()\n\t\t\t\tmp1[a[d].second]=1;\n\t\t\t\tif (mp1[a[d].second-1]==1) cnt--;\n\t\t\t\tif (mp1[a[d].second+1]==1) cnt--;\n\t\t\t\td--;\n\t\t\t}\n\t\t\telse break;\n\t\t}\n\t\tans=max(ans,cnt);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8940, "score_of_the_acc": -1.2811, "final_rank": 18 }, { "submission_id": "aoj_0655_8466063", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint i,j,n,res=0,ans=0,x;\nint a[100005] ;\npair<int,int> st[100005] ;\n//vector<pair<int,int>> vt[100005] ;\nint main(){\n if(fopen(\"test.inp\", \"r\")){\n freopen(\"test.inp\", \"r\", stdin);\n freopen(\"test.out\", \"w\", stdout);\n }\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);cout.tie(NULL);\n cin >> n ;\n for(i=1;i<=n;i++){\n cin >> a[i] ;\n st[i]={a[i],i} ;\n }\n sort(st+1,st+n+1) ;\n for(i=1;i<=n;i++){\n if(a[i]!=0 && a[i+1]==0) res++ ;\n }\n ans=res ;\n for(i=1;i<=n;i++){\n if(st[i].first==0) continue ;\n j=st[i].second ;\n x=st[i].first ;\n if(j>1 && j<n && x<a[j-1] && x<=a[j+1]) res++ ;\n if(a[j-1]<x && a[j+1]<x) res-- ;\n if(x!=st[i+1].first) ans=max(ans,res) ;\n a[j]=0;\n }\n cout << ans << '\\n' ;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4312, "score_of_the_acc": -0.0374, "final_rank": 3 }, { "submission_id": "aoj_0655_8465863", "code_snippet": "#include <bits/stdc++.h>\n#define ll long long\n#define ull unsigned long long\n#define dl double\n#define st first\n#define nd second\n#define II pair <int, int>\n\nusing namespace std;\n\nconst int N = 5 + 5e4;\nconst int inf = 7 + 1e9;\n\nint main() {\n#define TASKNAME \"\"\n ios_base :: sync_with_stdio (0);\n cin.tie (0);\n if ( fopen( TASKNAME\".inp\", \"r\" ) ) {\n freopen (TASKNAME\".inp\", \"r\", stdin);\n freopen (TASKNAME\".out\", \"w\", stdout);\n }\n int n;\n cin >> n;\n vector <II> a(n + 1);\n vector <int> vis(n + 2, 0);\n int cnt = 0;\n for (int i = 1; i <= n; i ++) {\n cin >> a[i].st;\n a[i].nd = i;\n if (a[i].st) {\n vis[i] = 1;\n if (!a[i - 1].st)\n cnt ++;\n }\n }\n sort(a.begin() + 1, a.end());\n int ans = cnt;\n for (int i = 1; i <= n; ) {\n int j = i;\n while (j <= n && a[j].st == a[i].st) {\n if (a[i].st) {\n int pos = a[j].nd;\n if (!vis[pos - 1] && !vis[pos + 1])\n cnt --;\n else if (vis[pos - 1] && vis[pos + 1])\n cnt ++;\n vis[pos] = 0;\n }\n j ++;\n }\n ans = max(ans, cnt);\n i = j;\n }\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4388, "score_of_the_acc": -0.0438, "final_rank": 5 }, { "submission_id": "aoj_0655_8465628", "code_snippet": "#include <bits/stdc++.h>\n#define th1 first\n#define th2 second\n#define ll long long\n#define lb long double\n#define _(k) ((k)&(-(k)))\n#define ii pair<int,int>\n#define pb push_back\nusing namespace std;\n\nconst int N = 5+1e5;\nconst int INF = 0x3f3f3f3f;\nint n, a[N], vis[N];\nvector<int> q[N];\n\nint main() {\n ios_base::sync_with_stdio (0); cin.tie (0);\n #define TASKNAME \"a\"\n if (fopen(TASKNAME\".inp\", \"r\")) {\n freopen(TASKNAME\".inp\", \"r\", stdin) ;\n freopen(TASKNAME\".out\", \"w\", stdout) ;\n }\n\n cin >> n;\n vector<int> g;\n for (int i = 1; i <= n; i++) {\n cin >> a[i];\n g.push_back(a[i]);\n }\n\n g.push_back(0);\n a[0] = 0, a[++n] = 0;\n\n sort(g.begin(), g.end());\n g.resize(unique(g.begin(),g.end()) - g.begin());\n\n for (int i = 0; i <= n; i++) {\n a[i] = upper_bound(g.begin(),g.end(),a[i]) - g.begin();\n q[a[i]].push_back(i);\n }\n\n int ans = 0, cnt = 0;\n for (int h = 1; h <= g.size(); h++) {\n for (int v: q[h]) {\n vis[v] = 1;\n if (!vis[v + 1] && !vis[v - 1])\n cnt += 1;\n else if (vis[v + 1] + vis[v - 1] == 2)\n cnt -= 1;\n }\n ans = max(ans, cnt - 1);\n }\n\n cout << ans << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 9800, "score_of_the_acc": -0.6387, "final_rank": 12 }, { "submission_id": "aoj_0655_8465410", "code_snippet": "#include <bits/stdc++.h>\n#define SZ(x) (int)(x.size())\nusing namespace std;\n\nsigned main() {\n #define TASKNAME \"\"\n if(fopen(TASKNAME\".inp\", \"r\")) {\n freopen(TASKNAME\".inp\", \"r\", stdin);\n freopen(TASKNAME\".out\", \"w\", stdout);\n }\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int n;\n cin >> n;\n vector<int> a(n + 1);\n vector<pair<int, int>> p;\n for(int i = 1; i <= n; i ++) {\n cin >> a[i];\n p.push_back({a[i], i});\n } \n sort(p.begin(), p.end());\n reverse(p.begin(), p.end());\n vector<int> used(n + 3, 0);\n int answer = 0;\n int cur = 0;\n for(int i = 0, j = 0; i < SZ(p); i = j + 1) {\n for(j = i; j + 1 < SZ(p) && p[j + 1].first == p[i].first; ) j ++ ;\n if(p[i].first == 0) continue ;\n for(int k = i; k <= j; k ++) {\n int pos = p[k].second;\n if(used[pos - 1] == 1) cur -- ;\n if(used[pos + 1] == 1) cur -- ;\n cur ++ ;\n used[pos] = 1;\n }\n answer = max(answer, cur);\n }\n cout << answer << \"\\n\";\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4792, "score_of_the_acc": -0.0775, "final_rank": 7 }, { "submission_id": "aoj_0655_8293177", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> Pi;\nint main(){\n int n, a;\n vector<Pi> vec;\n bool flo[100010]={};\n cin >> n;\n for(int i=1;i<=n;i++){\n cin >> a;\n if(a>0) vec.push_back(Pi(a, i));\n }\n int si = vec.size();\n if(si>0){\n sort(vec.begin(), vec.end());\n reverse(vec.begin(), vec.end());\n }\n int cnt=0, ma=1;\n for(int i=0;i<si;i++){\n Pi pi = vec[i];\n flo[pi.second] = true;\n cnt++;\n if(flo[pi.second-1]) cnt--;\n if(flo[pi.second+1]) cnt--;\n if(i==si-1 || pi.first!=vec[i+1].first) ma = max(ma, cnt);\n }\n if(si<1) ma = 0;\n cout << ma << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3992, "score_of_the_acc": -0.2964, "final_rank": 10 }, { "submission_id": "aoj_0655_7293575", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vvvvvll = vector<vvvvll>;\nusing vvvvvvll = vector<vvvvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\nusing vvvvd = vector<vvvd>;\nusing vvvvvd = vector<vvvvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (a == 0)return b;\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\nll sqrtz(ll N) {\n ll L = 0;\n ll R = sqrt(N) + 10000;\n while (abs(R - L) > 1) {\n ll mid = (R + L) / 2;\n if (mid * mid <= N)L = mid;\n else R = mid;\n }\n return L;\n\n}\n\nvector<ll> fact, factinv, inv;\nconst ll mod = 1e9 + 7;\nvoid prenCkModp(ll n) {\n fact.resize(n + 5);\n factinv.resize(n + 5);\n inv.resize(n + 5);\n fact[0] = fact[1] = 1;\n factinv[0] = factinv[1] = 1;\n inv[1] = 1;\n for (ll i = 2; i < n + 5; i++) {\n fact[i] = (fact[i - 1] * i) % mod;\n inv[i] = (mod - (inv[mod % i] * (mod / i)) % mod) % mod;\n factinv[i] = (factinv[i - 1] * inv[i]) % mod;\n }\n\n}\n\nll nCk(ll n, ll k) {\n if (n < k || k < 0) return 0;\n return (fact[n] * ((factinv[k] * factinv[n - k]) % mod)) % mod;\n}\n\n\nvvll mul(vvll A, vvll B) {\n ll N = A.size();\n vvll res(N, vll(N, 0));\n rep(i, N)rep(j, N)rep(k, N)res[i][j] = (res[i][j] + A[i][k] * B[k][j]) % 17;\n return res;\n}\n\n\n/*\n区間をsetで管理するテク\n区間は半開区間で持たせる[L,R)\n*/\ntemplate<class T>\nstruct rangeset{\n set<pair<T,T>> S;\n T INF;\n\n \n\n rangeset(){\n INF=2e18;;\n S.insert({INF,INF});\n S.insert({-INF,-INF});\n }\n bool iscovered(T L,T R){\n //assert(L<=R);\n auto itr=S.lower_bound({L+1,L+1});\n itr=prev(itr);\n auto st=*itr;\n return (itr->first<=L&&R<=itr->second);\n }\n bool iscovered(T x){\n return iscovered(x,x+1);\n }\n pair<T,T> covered(T L,T R){\n //assert(L<=R);\n auto itr=S.lower_bound({L+1,L+1});\n itr--;\n auto st=*itr;\n if(itr->first<=L&&R<=itr->second){\n return st;\n }\n else{\n return {INF,INF};\n }\n }\n pair<T,T> covered(T x){\n return covered(x,x+1);\n }\n T insert(T L,T R){\n if(iscovered(L,R))return T(0);\n auto itr=S.lower_bound({L+1,L+1});\n itr=prev(itr);\n T res=T(0);\n auto st=*itr;\n if(itr->first<=L&&L<=itr->second){\n L=st.first;\n res-=itr->second-itr->first;\n itr=S.erase(itr);\n }\n else itr=next(itr);\n while(R>itr->second){\n res-=itr->second-itr->first;\n itr=S.erase(itr);\n }\n if(itr->first<=R&&R<=itr->second){\n res-=itr->second-itr->first;\n R=itr->second;\n itr=S.erase(itr);\n }\n S.insert({L,R});\n res+=R-L;\n return res;\n }\n T insert(T x){\n return insert(x,x+1);\n }\n\n T erase(T L,T R){\n auto itr=S.lower_bound({L+1,L+1});\n itr=prev(itr);\n T res=T(0);\n auto st=*itr;\n if(itr->first<=L&&R<=itr->second){\n if(itr->first<L)S.insert({itr->first,L});\n if(R<itr->second)S.insert({R,itr->second});\n S.erase(itr);\n return R-L;\n }\n if(itr->first<=L&&L<itr->second){\n res+=itr->second-L;\n if(itr->first<L)S.insert({itr->first,L});\n itr=S.erase(itr);\n }\n else itr=next(itr);\n\n while(itr->second<=R){\n res+=itr->second-itr->first;\n itr=S.erase(itr);\n }\n\n if(itr->first<R&&R<=itr->second){\n res+=R-itr->first;\n if(R<itr->second)S.insert({R,itr->second});\n S.erase(itr);\n }\n return res;\n }\n T erase(T x){\n return erase(x,x+1);\n }\n};\n\n\nint main() {\n\n \n ll N;\n cin>>N;\n map<ll,vll> M;\n rep(i,N){\n ll A;\n cin>>A;\n M[-A].push_back(i);\n }\n if(M.count(0)&&M.size()==1){\n cout<<0<<endl;\n return 0;\n }\n rangeset<ll> S;\n ll an=1;\n for(auto m:M){\n for(auto x:m.second){\n S.insert(x);\n }\n chmax(an,ll(S.S.size()-2));\n //cout<<S.S.size()<<endl;\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 15836, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0655_7072110", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\ntemplate<typename T>\nstruct BIT{\n ll n;\n ll k=1;\n vector<T>data;\n BIT() = default;\n BIT(ll size):n(size){\n data.assign(n,0);\n while(k*2<=n)k*=2;\n }\n void add(ll a,T w){\n for(ll i=a+1;i<=n;i+=i&-i)data[i-1]+=w;\n }\n T sum(ll a){//[0,a)\n\t if(a<=0)return 0;\n T ret = 0;\n for(ll i=a;i>0;i-=i&-i)ret+=data[i-1];\n return ret;\n }\n //[a,b)\n T sum(ll a,ll b){return a>=b?0:sum(b)-sum(a);}\n T operator[](ll pos){\n return sum(pos,pos+1);\n }\n ll lower_bound(ll x){\n ll ret=0; \n for(ll i=k;i>0;i/=2){\n if(ret+i<=n&&data[ret+i-1]<x){\n x-=data[ret+i-1];\n ret+=i;\n }\n }\n return ret;\n }\n ll lower_first(ll x){\n return lower_bound(sum(n)-x+1);\n }\n void print(){\n for(ll i=0;i<n;i++){\n if(i!=0)cout<<\" \";\n cout<<(*this)[i];\n }\n cout<<endl;\n }\n};\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll n;cin>>n;\n\tvector<ll>a(n+2,0);\n\trep(i,0,n)cin>>a[i+1];\n\tmap<ll,ll>mp;\n\trep(i,0,n+1){\n\t\tmp[min(a[i],a[i+1])]++;\n\t\tmp[max(a[i],a[i+1])]--;\n\t}\n\tll ret=0;\n\tll now=0;\n\tfor(auto z:mp){\n\t\tnow+=z.se;\n\t\tchmax(ret,now);\n\t}\n\t//debug(mp);\n\tcout<<ret/2<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 10212, "score_of_the_acc": -0.816, "final_rank": 17 }, { "submission_id": "aoj_0655_7072028", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <limits>\n#include <numeric>\n#include <type_traits>\n#include <bitset>\n#include <map>\n#include <unordered_map>\n#include <set>\n\nusing namespace std;\n\n#define rep(i,n,m) for(ll (i)=(n);(i)<(m);(i)++)\n#define rrep(i,n,m) for(ll (i)=(n);(i)>(m);(i)--)\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll inf = 1e9;\nconst ll INF = 1e18;\n\nvoid pline(vector<ll> lis){\n rep(i,0,lis.size()){\n printf (\"%lld\",lis[i]);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\nvoid pline(vector<pair<ll,ll>> lis){\n rep(i,0,lis.size()){\n printf (\"/%lld,%lld/\",lis[i].first,lis[i].second);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\n/*\nvoid pmap(map<ll,mint>& lis){\n for (auto p : lis){\n printf (\"%lld:%lld ,\",p.first,p.second.val());\n }\n printf (\"\\n\");\n}*/\n\n\nint main(){\n\n //ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n\n ll N;\n cin >> N;\n\n vector<ll> A(N+1,0);\n\n rep(i,0,N) cin >> A[i+1];\n\n //pline(A);\n\n vector<pair<ll,ll>> lis;\n\n rep(i,0,A.size()-1){\n if (A[i] < A[i+1]){\n lis.push_back(make_pair(A[i],1));\n lis.push_back(make_pair(A[i+1],-1));\n }\n }\n\n\n\n sort(lis.begin(),lis.end());\n //reverse(lis.begin(),lis.end());\n\n ll ans = 0;\n ll now = 0;\n\n for (auto tup : lis){\n now += tup.second;\n ans = max(ans , now);\n //cout << tup.first << \" \" << tup.second << \" \" << now << endl; \n }\n\n cout << ans << endl;\n\n}\n\n/*\n\n-1\n0 X X 5 X\nX 5 X X 0\n\n*/", "accuracy": 1, "time_ms": 30, "memory_kb": 9400, "score_of_the_acc": -0.7481, "final_rank": 16 }, { "submission_id": "aoj_0655_6996462", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0655.cc: 日本沈没 (Japan Sinks)\n */\n\n#include<cstdio>\n#include<set>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\n\n/* typedef */\n\ntypedef pair<int,int> pii;\ntypedef set<pii> spii;\n\n/* global variables */\n\nint as[MAX_N], uas[MAX_N];\npii ps[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n\n for (int i = 0; i < n; i++) {\n scanf(\"%d\", as + i);\n uas[i] = as[i];\n ps[i] = pii(as[i], i);\n }\n\n sort(uas, uas + n);\n int m = unique(uas, uas + n) - uas;\n\n if (m == 1) {\n printf(\"%d\\n\", (uas[0] == 0) ? 0 : 1);\n return 0;\n }\n\n sort(ps, ps + n);\n\n spii gs;\n gs.insert(pii(n, 0));\n int maxc = 1;\n\n for (int i = 0, j = 0; i < m; i++) {\n while (j < n && uas[i] == ps[j].first) {\n int k = ps[j++].second;\n spii::iterator sit = gs.lower_bound(pii(k, k));\n if (sit != gs.end()) {\n\tint l = sit->second, r = sit->first;\n\tgs.erase(sit);\n\n\tif (l < k) gs.insert(pii(k, l));\n\tif (k + 1 < r) gs.insert(pii(r, k + 1));\n }\n }\n\n maxc = max(maxc, (int)gs.size());\n\n //printf(\"%d:\", uas[i]);\n //for (auto g: gs) printf(\" %d,%d\", g.second, g.first);\n //putchar('\\n');\n }\n\n printf(\"%d\\n\", maxc);\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 6676, "score_of_the_acc": -0.6635, "final_rank": 13 }, { "submission_id": "aoj_0655_6847646", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nvector<int>rev[100001];\n//UnionFind.txt\n//UF\n//ベースは蟻本\nclass UnionFind{\n\tint n,cnt;\n\tvector<int>par,rank,sz;\n\tvector<bool>ver;\npublic:\n\tUnionFind(int n_)\n\t\t:n(n_),cnt(0),par(n_),rank(n_),sz(n_,1),ver(n_){\n\t\tiota(par.begin(),par.end(),0);\n\t}\n\t//xの根\n\tint find(int x){\n\t\tif(par[x]==x)\n\t\t\treturn x;\n\t\treturn par[x]=find(par[x]);\n\t}\n\t//xとyを併合\n\tvoid unite(int x,int y){\n\t\tx=find(x);\n\t\ty=find(y);\n\t\tif(x==y)\n\t\t\treturn;\n\t\tcnt--;\n\t\tif(rank[x]<rank[y]){\n\t\t\tpar[x]=y;\n\t\t\tsz[y]+=sz[x];\n\t\t}else{\n\t\t\tpar[y]=x;\n\t\t\tif(rank[x]==rank[y])\n\t\t\t\trank[x]++;\n\t\t\tsz[x]+=sz[y];\n\t\t}\n\t}\n\t//xとyが同じところにあるか\n\tbool same(int x,int y){\n\t\treturn find(x)==find(y);\n\t}\n\t//xの大きさ\n\tint size(int x){\n\t\tx=find(x);\n\t\treturn sz[x];\n\t}\n\tvoid verify(int x){\n\t\tif(ver[x])\n\t\t\treturn;\n\t\tver[x]=1;\n\t\tcnt++;\n\t}\n\tint size(){\n\t\treturn cnt;\n\t}\n};\nint main(){\n\tstatic int n,a[100000];\n\tcin>>n;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>a[i];\n\tvector<int>unzip(a,a+n);\n\tunzip.push_back(0);\n\tsort(unzip.begin(),unzip.end());\n\tunzip.erase(unique(unzip.begin(),unzip.end()),unzip.end());\n\tmap<int,int>zip;\n\tfor(int i=0;i<unzip.size();i++)\n\t\tzip[unzip[i]]=i;\n\tfor(int i=0;i<n;i++)\n\t\ta[i]=zip[a[i]];\n\tfor(int i=0;i<n;i++)\n\t\trev[a[i]].push_back(i);\n\tint ans=0;\n\tUnionFind uf(n);\n\tfor(int tmp=n;tmp>=1;tmp--){\n\t\tset<int>conn;\n\t\tfor(auto x:rev[tmp]){\n\t\t\tuf.verify(x);\n\t\t\tif(x-1>=0&&a[x-1]>=tmp)\n\t\t\t\tconn.insert(x-1);\n\t\t\tif(x+1<n&&a[x+1]>=tmp)\n\t\t\t\tconn.insert(x);\n\t\t}\n\t\tfor(auto x:conn)\n\t\t\tuf.unite(x,x+1);\n\t\tans=max(ans,uf.size());\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 15280, "score_of_the_acc": -1.6678, "final_rank": 19 } ]
aoj_0662_cpp
珍しい都市(Unique Cities) JOI 国には$N$ 個の都市があり,1 から$N$ までの番号がついている.これらの都市は$N - 1$ 本の道路で結ばれている.$i$ 番目($1 \leq i \leq N - 1$) の道路は都市$A_i$ と都市$B_i$ を結んでおり,双方向に通行可能である.どの都市からどの都市へも何本かの道路を通行することで移動できる. JOI 国にはいくつかの特産品が存在する.特産品には,種類を表す1 以上$M$ 以下の番号が付けられている(JOI 国で生産されている特産品に対応していない番号があるかもしれない).各都市は1 つの特産品を生産しており,都市$j$ ($1 \leq j \leq N$) では特産品$C_j$ を生産している.複数の都市が同じ種類の特産品を生産することがあるかもしれない. 2 つの都市の間の距離は,その間を移動するために通る道路の本数の最小値である.都市$x$ ($1 \leq x \leq N$)から見て都市$y$ ($1 \leq y \leq N, y \ne x$) が珍しい都市であるとは,すべての都市$z$ ($1 \leq z \leq N, z \ne x, z \ne y) について,都市$x, y$ 間の距離と都市$x, z$ 間の距離が異なることを意味する. JOI 国の大臣であるK 理事長は,すべての$j$ ($1 \leq j \leq N$) について,都市$j$ から見て珍しい都市で生産されている特産品が何種類あるかを知りたい. JOI 国の道路の情報と,各都市で生産されている特産品の番号が与えられたとき,各都市ごとに,その都市から見て珍しい都市で生産されている特産品が何種類あるかを求めるプログラムを作成せよ. 入力 入力は以下の形式で標準入力から与えられる. $N$ $M$ $A_1$ $B_1$ : $A_{N-1}$ $B_{N-1}$ $C_1$ ... $C_N$ 出力 標準出力に$N$ 行で出力せよ. $j$ 行目($1 \leq j \leq N$) には,都市$j$ から見て珍しい都市で生産されている特産品が何種類あるかを出力せよ. 制約 $ 2 \leq N \leq 200 000$. $ 1 \leq M \leq N$. $ 1 \leq A_i \leq N (1 \leq i \leq N - 1),1 \leq B_i \leq N (1 \leq i \leq N - 1)$. $ A_i \ne B_i (1 \leq i \leq N - 1)$. どの都市からどの都市へも何本かの道路を通行することで移動できる. $ 1 \leq C_j \leq M (1 \leq j \leq N)$. 入出力例 入力例1 5 4 1 2 2 3 3 4 3 5 1 2 1 2 4 出力例1 2 0 1 1 1 都市1 から見て珍しい都市は都市2; 3 であり,そこで生産される特産品は特産品2; 1 なので,答えは2種類である. 都市2 から見て珍しい都市は存在しないので,答えは0 種類である. 都市3 から見て珍しい都市は都市1 であり,そこで生産される特産品は特産品1 なので,答えは1 種類である. 都市4 から見て珍しい都市は都市1; 3 であり,どちらの都市においても生産される特産品は特産品1 なので,答えは1 種類である. 都市5 から見て珍しい都市は都市1; 3 であり,どちらの都市においても生産される特産品は特産品1 なので,答えは1 種類である. 番号3 の特産品は存在しないことに注意せよ. 入力例2 7 1 1 2 2 3 3 4 4 5 5 6 6 7 1 1 1 1 1 1 1 出力例2 1 1 1 0 1 1 1 入力例3 10 10 2 6 5 8 10 8 1 4 10 6 4 5 10 7 6 9 3 7 1 2 3 4 5 6 7 8 9 10 出力例3 4 3 4 2 0 2 2 0 3 2 入力例4 22 12 9 6 12 13 4 20 21 22 3 19 2 9 6 18 18 11 18 3 16 2 6 4 3 17 16 10 8 16 22 1 16 14 15 8 9 21 2 12 21 5 12 7 1 1 4 8 4 11 7 6 7 11 6 11 10 4 7 5 3 12 9 6 12 2 出力例4 2 0 1 1 1 1 1 0 0 1 2 0 1 1 2 0 2 1 2 3 0 0 情報オリンピック日本委員会作 『第18 回日本情報オリンピック(JOI 2018/2019) 本選』
[ { "submission_id": "aoj_0662_10524994", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing vi = vector<int>;\nstatic const int MAXN = 200000;\n\nint N, M;\nvi G[MAXN+1];\nint C[MAXN+1], ans[MAXN+1], cnt[MAXN+1];\nint dep[MAXN+1], son[MAXN+1], mx1[MAXN+1], mx2[MAXN+1];\nint stk[MAXN+1];\n\nint rt = 0, tp = 0, sumv = 0;\n\n// 1) DFS で最遠点を探す\nvoid dfs_far(int u, int p){\n dep[u] = dep[p] + 1;\n if(dep[u] > dep[rt]) rt = u;\n for(int v : G[u]){\n if(v == p) continue;\n dfs_far(v, u);\n }\n}\n\n// 2) 各ノードの heavy-child, mx1, mx2 を計算\nvoid dfs1(int u, int p){\n dep[u] = dep[p] + 1;\n mx1[u] = mx2[u] = son[u] = 0;\n for(int v : G[u]){\n if(v == p) continue;\n dfs1(v, u);\n int d = mx1[v] + 1;\n if(d > mx1[u]){\n mx2[u] = mx1[u];\n mx1[u] = d;\n son[u] = v;\n } else if(d > mx2[u]){\n mx2[u] = d;\n }\n }\n}\n\n// スタックに色を追加/削除\ninline void add(int x){\n if(cnt[C[x]]++ == 0) ++sumv;\n}\ninline void remove_(int x){\n if(--cnt[C[x]] == 0) --sumv;\n}\n\n// 3) Heavy–Light 風に DFS して ans を更新\nvoid dfs2(int u, int p){\n if(p){\n stk[++tp] = p;\n add(p);\n }\n if(son[u]){\n int limit = dep[u] - mx2[u];\n while(tp && dep[stk[tp]] >= limit){\n remove_(stk[tp--]);\n }\n dfs2(son[u], u);\n }\n int limit = dep[u] - mx1[u];\n while(tp && dep[stk[tp]] >= limit){\n remove_(stk[tp--]);\n }\n for(int v : G[u]){\n if(v == p || v == son[u]) continue;\n dfs2(v, u);\n }\n ans[u] = max(ans[u], sumv);\n if(p && tp && stk[tp] == p){\n remove_(p);\n --tp;\n }\n}\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n cin >> N >> M;\n for(int i = 1; i < N; ++i){\n int u, v;\n cin >> u >> v;\n G[u].push_back(v);\n G[v].push_back(u);\n }\n for(int i = 1; i <= N; ++i){\n cin >> C[i];\n }\n\n // 直径の両端を根にして2回走らせる\n dfs_far(1, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n\n int other = rt;\n rt = 0;\n dfs_far(other, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n\n for(int i = 1; i <= N; ++i){\n cout << ans[i] << \"\\n\";\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 33308, "score_of_the_acc": -0.205, "final_rank": 3 }, { "submission_id": "aoj_0662_10524957", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid out(int n) { // 非負整数の表示(出力)\n char b[30];\n if (!n) pc('0');\n else {\n int i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n while (i--) pc(b[i]);\n }\n pc('\\n');\n}\n\nstatic inline void chmax(int *a, int b) { if (*a < b) *a = b; }\n#define M 200005\nvector<int> g[M];\nint n, m, x, y, rt, tp, sum;\nint c[M], ans[M], cnt[M], dep[M], son[M], stk[M], mx1[M], mx2[M];\n\nvoid get(int x, int par) {\n dep[x] = dep[par] + 1;\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v != par) get(v, x);\n }\n if (dep[x] > dep[rt]) rt = x;\n}\n\nvoid dfs1(int x, int par) {\n mx1[x] = mx2[x] = son[x] = 0;\n dep[x] = dep[par] + 1;\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v == par) continue;\n dfs1(v, x);\n if (mx1[v] + 1 > mx1[x]) {\n mx2[x] = mx1[x];\n son[x] = v;\n mx1[x] = mx1[v] + 1;\n } else if (mx1[v] + 1 > mx2[x]) {\n mx2[x] = mx1[v] + 1;\n }\n }\n}\n\nvoid add(int x) { sum += !cnt[c[x]]++; }\nvoid del(int x) { sum -= !--cnt[c[x]]; }\nvoid update(int x, int len) {\n while (tp && dep[x] - dep[stk[tp]] <= len) del(stk[tp--]);\n}\n\nvoid dfs2(int x, int par) {\n if (par) stk[++tp] = par, add(par);\n if (son[x]) {\n update(x, mx2[x]);\n dfs2(son[x], x);\n }\n update(x, mx1[x]);\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v != par && v != son[x]) dfs2(v, x);\n }\n chmax(&ans[x], sum);\n if (tp && stk[tp] == par) del(par), tp--;\n}\n\nint main() {\n n = in();\n m = in();\n for (int i = 1; i < n; ++i) {\n x = in();\n y = in();\n g[x].emplace_back(y);\n g[y].emplace_back(x);\n }\n for (int i = 1; i <= n; ++i) c[i] = in();\n get(1, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n x = rt;\n rt = 0;\n get(x, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n for (int i = 1; i <= n; ++i) out(ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 33056, "score_of_the_acc": -0.2199, "final_rank": 4 }, { "submission_id": "aoj_0662_9611153", "code_snippet": "// AOJ 662 Unique Cities\n// 2024.1.17\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid out(int n) { // 非負整数の表示(出力)\n char b[30];\n if (!n) pc('0');\n else {\n int i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n while (i--) pc(b[i]);\n }\n pc('\\n');\n}\n\nstatic inline void chmax(int *a, int b) { if (*a < b) *a = b; }\n#define M 200005\nvector <int> g[M];\nint n, m, x, y, rt, tp, sum;\nint c[M], ans[M], cnt[M], dep[M], son[M], stk[M], mx1[M], mx2[M];\n\nvoid get(int x, int par) {\n dep[x] = dep[par] + 1;\n for (auto v: g[x]) if (v != par) get(v, x);\n if (dep[x] > dep[rt]) rt = x;\n}\n\nvoid dfs1(int x, int par) {\n mx1[x] = mx2[x] = son[x] = 0;\n dep[x] = dep[par] + 1;\n for (auto v: g[x]) {\n if (v == par) continue;\n dfs1(v, x);\n if (mx1[v] + 1 > mx1[x]) mx2[x] = mx1[x], son[x] = v, mx1[x] = mx1[v] + 1;\n else if (mx1[v]+1 > mx2[x]) mx2[x] = mx1[v] + 1;\n }\n}\n\nvoid add(int x) { sum += !cnt[c[x]]++; }\nvoid del(int x) { sum -= !--cnt[c[x]]; }\nvoid update(int x, int len) {\n while (tp && dep[x]-dep[stk[tp]] <= len) del(stk[tp--]);\n}\n\nvoid dfs2(int x, int par){\n if (par) stk[++tp] = par, add(par);\n if (son[x]) {\n update(x, mx2[x]);\n dfs2(son[x], x);\n }\n update(x, mx1[x]);\n for (auto v: g[x]) if (v != par && v!=son[x]) dfs2(v, x);\n chmax(&ans[x], sum);\n if (tp && stk[tp] == par) del(par), tp--;\n}\n\nint main() {\n int i;\n n = in(), m = in();\n for (i = 1; i < n; ++i) {\n x = in(), y = in();\n g[x].emplace_back(y);\n g[y].emplace_back(x);\n }\n for (i = 1; i <= n; ++i) c[i] = in();\n get(1, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n x = rt, rt = 0;\n get(x, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n for (i = 1; i <= n; ++i) out(ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 33124, "score_of_the_acc": -0.2031, "final_rank": 2 }, { "submission_id": "aoj_0662_9476780", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define gc() getchar_unlocked()\n#define pc(c) putchar_unlocked(c)\n\nint in() { // 非負整数の入力\n int n = 0; int c = gc();\n do n = 10 * n + (c & 0xf); while ((c = gc()) >= '0');\n return n;\n}\n\nvoid out(int n) { // 非負整数の表示(出力)\n char b[30];\n if (!n) pc('0');\n else {\n int i = 0; while (n) b[i++] = n % 10 + '0', n /= 10;\n while (i--) pc(b[i]);\n }\n pc('\\n');\n}\n\nstatic inline void chmax(int *a, int b) { if (*a < b) *a = b; }\n#define M 200005\nvector<int> g[M];\nint n, m, x, y, rt, tp, sum;\nint c[M], ans[M], cnt[M], dep[M], son[M], stk[M], mx1[M], mx2[M];\n\nvoid get(int x, int par) {\n dep[x] = dep[par] + 1;\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v != par) get(v, x);\n }\n if (dep[x] > dep[rt]) rt = x;\n}\n\nvoid dfs1(int x, int par) {\n mx1[x] = mx2[x] = son[x] = 0;\n dep[x] = dep[par] + 1;\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v == par) continue;\n dfs1(v, x);\n if (mx1[v] + 1 > mx1[x]) {\n mx2[x] = mx1[x];\n son[x] = v;\n mx1[x] = mx1[v] + 1;\n } else if (mx1[v] + 1 > mx2[x]) {\n mx2[x] = mx1[v] + 1;\n }\n }\n}\n\nvoid add(int x) { sum += !cnt[c[x]]++; }\nvoid del(int x) { sum -= !--cnt[c[x]]; }\nvoid update(int x, int len) {\n while (tp && dep[x] - dep[stk[tp]] <= len) del(stk[tp--]);\n}\n\nvoid dfs2(int x, int par) {\n if (par) stk[++tp] = par, add(par);\n if (son[x]) {\n update(x, mx2[x]);\n dfs2(son[x], x);\n }\n update(x, mx1[x]);\n for (size_t i = 0; i < g[x].size(); ++i) {\n int v = g[x][i];\n if (v != par && v != son[x]) dfs2(v, x);\n }\n chmax(&ans[x], sum);\n if (tp && stk[tp] == par) del(par), tp--;\n}\n\nint main() {\n n = in();\n m = in();\n for (int i = 1; i < n; ++i) {\n x = in();\n y = in();\n g[x].emplace_back(y);\n g[y].emplace_back(x);\n }\n for (int i = 1; i <= n; ++i) c[i] = in();\n get(1, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n x = rt;\n rt = 0;\n get(x, 0);\n dfs1(rt, 0);\n dfs2(rt, 0);\n for (int i = 1; i <= n; ++i) out(ans[i]);\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 33040, "score_of_the_acc": -0.2022, "final_rank": 1 }, { "submission_id": "aoj_0662_7465075", "code_snippet": "#include <stdio.h>\n#include <algorithm>\n#include <cstring>\n#include <iostream>\n#include <vector>\n#include <stack>\nusing namespace std;\nconst int NR = 200010;\n\nint n, m;\nint tot = 0;\nint a[NR], cnt[NR];\nint rt1 = 0, rt2 = 0;\nint dep[NR], lson[NR], mx1[NR], mx2[NR];\nint ans[NR];\nvector<int> g[NR];\nstack<int> st;\n\nvoid mod(int x, int dt) {\n if (cnt[x]) tot--;\n cnt[x] += dt;\n if (cnt[x]) tot++;\n}\n\nvoid getD(int now, int fou) {\n dep[now] = dep[fou] + 1;\n for (int t: g[now]) {\n if (t == fou) continue;\n getD(t, now);\n }\n}\n\nvoid dfs1(int now, int fou) {\n dep[now] = dep[fou] + 1;\n lson[now] = mx1[now] = mx2[now] = 0;\n for (int t: g[now]) {\n if (t == fou) continue;\n dfs1(t, now);\n int tmp = mx1[t] + 1;\n if (tmp > mx1[now]) swap(mx1[now], tmp), lson[now] = t;\n if (tmp > mx2[now]) swap(mx2[now], tmp);\n }\n}\n\nvoid dfs2(int now, int fou) {\n if (fou) st.push(fou), mod(a[fou], 1);\n if (mx2[now])\n while (!st.empty() && dep[now] - dep[st.top()] <= mx2[now])\n mod(a[st.top()], -1), st.pop();\n if (lson[now])\n dfs2(lson[now], now);\n while (!st.empty() && dep[now] - dep[st.top()] <= mx1[now])\n mod(a[st.top()], -1), st.pop();\n ans[now] = max(ans[now], tot);\n for (int t: g[now]) {\n if (t == fou || t == lson[now]) continue;\n dfs2(t, now);\t\n }\n if (!st.empty() && fou && st.top() == fou) mod(a[st.top()], -1), st.pop();\n}\n\nint main() {\n cin >> n >> m;\n for (int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g[u].push_back(v), g[v].push_back(u);\n }\n for (int i = 1; i <= n; i++) cin >> a[i];\n getD(1, 0);\n rt1 = max_element(dep + 1, dep + n + 1) - dep;\n getD(rt1, 0);\n rt2 = max_element(dep + 1, dep + n + 1) - dep;\n dfs1(rt1, 0), dfs2(rt1, 0);\n dfs1(rt2, 0), dfs2(rt2, 0);\n for (int i = 1; i <= n; i++) cout << ans[i] << '\\n';\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 32816, "score_of_the_acc": -0.3928, "final_rank": 5 }, { "submission_id": "aoj_0662_4413193", "code_snippet": "#include <cstdio>\n#include <cstring>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cctype>\n\n#include <algorithm>\n#include <random>\n#include <bitset>\n#include <queue>\n#include <functional>\n#include <set>\n#include <map>\n#include <vector>\n#include <chrono>\n#include <iostream>\n#include <limits>\n#include <numeric>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\n// mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\ntemplate <class T>\nistream& operator>>(istream& is, vector<T>& v) {\n for (T& x : v) is >> x;\n return is;\n}\n\ntemplate <class T>\nostream& operator<<(ostream& os, const vector<T>& v) {\n if (!v.empty()) {\n os << v.front();\n for (int i = 1; i < v.size(); ++i) os << ' ' << v[i];\n }\n return os;\n}\n\nconst int N = 200010;\n\nint n;\nint c[N], dis[N], prt[N];\npair<int, int> dep[N];\nint cnt[N], seq[N], tag[N];\nbool vis[N];\nvector<int> g[N];\n\nint cans;\n\nvoid dfs(int u) {\n vis[u] = true;\n for (int v : g[u])\n if (!vis[v]) {\n dis[v] = dis[u] + 1;\n dfs(v);\n }\n}\n\nvoid addc(int x) {\n if (x == 0)\n return;\n if (!cnt[x]++)\n ++cans;\n}\n\nvoid ersc(int x) {\n if (x == 0)\n return;\n if (!--cnt[x])\n --cans;\n}\n\nvoid ins(int k, int x) {\n seq[k] = x;\n if (!tag[k])\n addc(x);\n}\n\nvoid ers(int k) {\n if (!tag[k])\n ersc(seq[k]);\n seq[k] = 0;\n}\n\nvoid add(int l, int r) {\n l = max(l, 0);\n for (int i = l; i <= r; ++i)\n if (!tag[i]++)\n ersc(seq[i]);\n}\n\nvoid sub(int l, int r) {\n l = max(l, 0);\n for (int i = l; i <= r; ++i)\n if (!--tag[i])\n addc(seq[i]);\n}\n\nstruct DepthDecomposition {\n int dis[N], ans[N];\n\n void dfs2(int u) {\n dep[u] = make_pair(0, u);\n vis[u] = true;\n for (int v : g[u])\n if (!vis[v]) {\n dis[v] = dis[u] + 1;\n prt[v] = u;\n dfs2(v);\n dep[u] = max(dep[u], make_pair(dep[v].first + 1, dep[v].second));\n }\n }\n\n void dfs3(int u) {\n vector<int> chain;\n for (int v = dep[u].second; v != prt[u]; v = prt[v]) chain.push_back(v);\n reverse(chain.begin(), chain.end());\n add(dis[u] - dep[u].first - 2, dis[u] - 1);\n for (int v : chain) {\n sub(dis[v] - dep[v].first - 2, dis[v] - dep[v].first - 1);\n\n ans[v] = cans;\n ins(dis[v], c[v]);\n for (int w : g[v])\n if (prt[w] == v && dep[w].second != dep[v].second)\n dfs3(w);\n for (int w : g[v])\n if (prt[w] == v && dep[w].second != dep[v].second)\n add(dis[v] - dep[w].first - 1, dis[v] - 1);\n add(dis[v], dis[v]);\n }\n sub(dis[u] + dep[u].first, dis[u] + dep[u].first);\n for (int v : chain) {\n for (int w : g[v])\n if (prt[w] == v && dep[w].second != dep[v].second)\n sub(dis[v] - dep[w].first - 1, dis[v] - 1);\n ers(dis[v]);\n }\n }\n\n void run(int s) {\n memset(vis, 0, sizeof(vis));\n prt[s] = 0;\n dfs2(s);\n dfs3(s);\n }\n\n} decompS, decompT;\n\nint main() {\n#ifdef LBT\n freopen(\"test.in\", \"r\", stdin);\n int nol_cl = clock();\n#endif\n\n int m;\n scanf(\"%d%d\", &n, &m);\n for (int rep = 1; rep < n; ++rep) {\n int u, v;\n scanf(\"%d%d\", &u, &v);\n g[u].push_back(v);\n g[v].push_back(u);\n }\n for (int i = 1; i <= n; ++i) cin >> c[i];\n dfs(1);\n int s = max_element(dis + 1, dis + n + 1) - dis;\n memset(vis, 0, sizeof(vis));\n dfs(s);\n int t = max_element(dis + 1, dis + n + 1) - dis;\n decompS.run(s);\n decompT.run(t);\n for (int i = 1; i <= n; ++i)\n printf(\"%d\\n\", (decompS.dis[i] > decompT.dis[i] ? decompS.ans[i] : decompT.ans[i]));\n\n#ifdef LBT\n LOG(\"Time: %dms\\n\", int((clock() - nol_cl) / (double)CLOCKS_PER_SEC * 1000));\n#endif\n return 0;\n}", "accuracy": 1, "time_ms": 310, "memory_kb": 32864, "score_of_the_acc": -0.5688, "final_rank": 6 }, { "submission_id": "aoj_0662_4267311", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <set>\n#include <cassert>\n#include <algorithm>\nusing namespace std;\n#pragma warning (disable: 4996)\n\n// 入力部\nint N, A[1 << 19], B[1 << 19], C[1 << 19];\nint M;\nvector<int> X[1 << 19];\n\n// 中心を求めるのに使うやつ\nint dist[1 << 19];\nint dist1[1 << 19], dist2[1 << 19];\nbool iscentroid[1 << 19];\n\n// 中心を外したグラフに関連する変数\nint verdist[1 << 19];\nint maxdist[1 << 19], label[1 << 19];\nvector<int> Y[1 << 19];\n\nvoid getdist(int pos) {\n\tfor (int i = 1; i <= N; i++) dist[i] = (1 << 30);\n\tqueue<int> Q; dist[pos] = 0; Q.push(pos);\n\twhile (!Q.empty()) {\n\t\tint from = Q.front(); Q.pop();\n\t\tfor (int i : X[from]) {\n\t\t\tif (dist[i] > dist[from] + 1) {\n\t\t\t\tdist[i] = dist[from] + 1;\n\t\t\t\tQ.push(i);\n\t\t\t}\n\t\t}\n\t}\n}\n\nvector<int> calc() {\n\tgetdist(1);\n\tpair<int, int> maxn1 = make_pair(-(1 << 30), -1);\n\tfor (int i = 1; i <= N; i++) maxn1 = max(maxn1, make_pair(dist[i], i));\n\n\tgetdist(maxn1.second);\n\tpair<int, int> maxn2 = make_pair(-(1 << 30), -1);\n\tfor (int i = 1; i <= N; i++) maxn2 = max(maxn2, make_pair(dist[i], i));\n\tfor (int i = 1; i <= N; i++) dist1[i] = dist[i];\n\n\tgetdist(maxn2.second);\n\tfor (int i = 1; i <= N; i++) dist2[i] = dist[i];\n\n\tvector<pair<int, int>> V;\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (dist1[i] + dist2[i] == dist1[maxn2.second]) V.push_back(make_pair(max(dist1[i], dist2[i]), i));\n\t}\n\tsort(V.begin(), V.end());\n\n\tif (V[0].first == V[1].first) return vector<int>{ V[0].second, V[1].second };\n\treturn vector<int>{ V[1].second, V[0].second, V[2].second };\n}\n\nvoid dfs1(int pos, int num) {\n\tmaxdist[pos] = 0; label[pos] = num;\n\tfor (int i : X[pos]) {\n\t\tif (maxdist[i] >= 0 || iscentroid[i] == true) continue;\n\t\tverdist[i] = verdist[pos] + 1;\n\t\tdfs1(i, num);\n\t\tY[pos].push_back(i);\n\t\tmaxdist[pos] = max(maxdist[pos], maxdist[i] + 1);\n\t}\n}\n\n// ここからはライブラリ\nclass BIT {\npublic:\n\tint size_ = 1;\n\tvector<int> bit;\n\n\tvoid init(int sz) {\n\t\tsize_ = sz + 2;\n\t\tbit.resize(size_ + 2, 0);\n\t\tfor (int i = 0; i < bit.size(); i++) bit[i] = 0;\n\t}\n\tvoid add(int pos, int x) {\n\t\tpos++;\n\t\twhile (pos <= size_) {\n\t\t\tbit[pos] += x;\n\t\t\tpos += (pos & -pos);\n\t\t}\n\t}\n\tint sum(int pos) {\n\t\tint s = 0; pos++;\n\t\twhile (pos >= 1) {\n\t\t\ts += bit[pos];\n\t\t\tpos -= (pos & -pos);\n\t\t}\n\t\treturn s;\n\t}\n};\n\nclass SegmentTree {\npublic:\n\tint size_ = 1;\n\tvector<int> counts;\n\tvector<int> idx;\n\tset<int> Tokusan[1 << 19];\n\tBIT Z;\n\tvoid init(int sz) {\n\t\tsize_ = sz;\n\t\tidx.resize(size_ * 2 + 2, 0);\n\t\tcounts.resize(size_ * 2 + 2, 0);\n\t\tZ.init(size_ * 2 + 2);\n\t\tfor (int i = 0; i < counts.size(); i++) counts[i] = 0;\n\t\tfor (int i = 0; i < counts.size(); i++) idx[i] = 0;\n\t\tfor (int i = 0; i < size_ * 2 + 2; i++) Tokusan[i].clear();\n\t}\n\tint gettokusan(int x) {\n\t\tauto itr = Tokusan[x].begin();\n\t\tif (itr == Tokusan[x].end()) return -(1 << 30);\n\t\treturn (*itr);\n\t}\n\tvoid dels(int pos) {\n\t\tcounts[pos + size_]--;\n\t\tif (counts[pos + size_] == 0) {\n\t\t\tint val1 = gettokusan(idx[pos + size_]);\n\t\t\tif (val1 >= -(1 << 29)) Z.add(val1 + size_, -1);\n\t\t\tTokusan[idx[pos + size_]].erase(pos);\n\t\t\tint val2 = gettokusan(idx[pos + size_]);\n\t\t\tif (val2 >= -(1 << 29)) Z.add(val2 + size_, 1);\n\t\t\tidx[pos + size_] = 0;\n\t\t}\n\t}\n\tvoid adds(int pos, int x) {\n\t\tcounts[pos + size_]++;\n\t\tif (counts[pos + size_] == 1) {\n\t\t\tidx[pos + size_] = x;\n\t\t\tint val1 = gettokusan(idx[pos + size_]);\n\t\t\tif (val1 >= -(1 << 29)) Z.add(val1 + size_, -1);\n\t\t\tTokusan[idx[pos + size_]].insert(pos);\n\t\t\tint val2 = gettokusan(idx[pos + size_]);\n\t\t\tif (val2 >= -(1 << 29)) Z.add(val2 + size_, 1);\n\t\t}\n\t}\n\tint getans(int pos) {\n\t\treturn Z.sum(pos + size_);\n\t}\n};\n\n// ここからは個数を厳密に求めるやつ\nint Answer[1 << 19], Fukasa[1 << 19];\nSegmentTree Z0;\n\nvoid dfs2(int pos, bool melee) {\n\tFukasa[verdist[pos] + N] = pos;\n\tAnswer[pos] = Z0.getans(verdist[pos] - maxdist[pos] - 1);\n\n\t// ランキングを求める\n\tvector<pair<int, int>> Ranking;\n\tfor (int i : Y[pos]) Ranking.push_back(make_pair(maxdist[i], i));\n\tsort(Ranking.begin(), Ranking.end());\n\n\t// 再帰をする\n\tif (Ranking.size() >= 1) {\n\t\tint eval = -1;\n\t\tif (Ranking.size() >= 2) eval = Ranking[Ranking.size() - 2].first;\n\t\tfor (int j = verdist[pos] - eval - 1; j <= verdist[pos] - 1; j++) Z0.dels(j);\n\t\tZ0.adds(verdist[pos], C[pos]);\n\t\tdfs2(Ranking[Ranking.size() - 1].second, true);\n\t\tZ0.dels(verdist[pos]);\n\t\tfor (int j = verdist[pos] - eval - 1; j <= verdist[pos] - 1; j++) Z0.adds(j, C[Fukasa[j + N]]);\n\t}\n\tif (Ranking.size() >= 2) {\n\t\tfor (int i = 0; i < (int)Ranking.size() - 1; i++) {\n\t\t\tZ0.adds(verdist[pos], C[pos]);\n\t\t\tdfs2(Ranking[i].second, false);\n\t\t\tZ0.dels(verdist[pos]);\n\t\t}\n\t}\n\n\t// 補正をする\n\tif (melee == false) {\n\t\tint eval = -1;\n\t\tif (Ranking.size() >= 1) eval = Ranking[Ranking.size() - 1].first;\n\t\tfor (int i = verdist[pos] - eval - 1; i <= verdist[pos] - 1; i++) {\n\t\t\tZ0.adds(i, C[Fukasa[i + N]]);\n\t\t}\n\t}\n\tif (melee == true) {\n\t\tint v1 = verdist[pos] - 1;\n\t\tint v2 = verdist[pos] - maxdist[pos] - 1;\n\t\tint v3 = verdist[pos] - maxdist[pos] - 2;\n\t\tZ0.adds(v1, C[Fukasa[v1 + N]]);\n\t\tZ0.dels(v2);\n\t\tZ0.dels(v3);\n\t}\n}\n\nint main() {\n\t// ステップ 1. 入力\n\tscanf(\"%d%d\", &N, &M);\n\tfor (int i = 1; i <= N - 1; i++) scanf(\"%d%d\", &A[i], &B[i]);\n\tfor (int i = 1; i <= N; i++) scanf(\"%d\", &C[i]);\n\n\t// ステップ 2. グラフの構成\n\tfor (int i = 1; i <= N - 1; i++) {\n\t\tX[A[i]].push_back(B[i]);\n\t\tX[B[i]].push_back(A[i]);\n\t}\n\n\t// ステップ 3. 中心を求める\n\tvector<int> centroid = calc();\n\tfor (int i : centroid) iscentroid[i] = true;\n\n\t// ステップ 4. 中心をグラフから外したグラフを考える\n\tfor (int i = 1; i <= N; i++) maxdist[i] = -1;\n\tfor (int i = 0; i < centroid.size(); i++) {\n\t\tint num = i;\n\t\tif (centroid.size() == 3) { if (i >= 1) num = 3 - i; }\n\t\tdfs1(centroid[i], num);\n\t}\n\n\t// ステップ 5. 珍しい都市の候補を判定する\n\tvector<int> cnt0(N, 0);\n\tvector<pair<int, int>> unique0;\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (label[i] != 0) continue;\n\t\tcnt0[verdist[i]]++;\n\t}\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (label[i] != 0 || cnt0[verdist[i]] >= 2) continue;\n\t\tunique0.push_back(make_pair(verdist[i], i));\n\t}\n\tvector<int> cnt1(N, 0);\n\tvector<pair<int, int>> unique1;\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (label[i] != 1) continue;\n\t\tcnt1[verdist[i]]++;\n\t}\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (label[i] != 1 || cnt1[verdist[i]] >= 2) continue;\n\t\tunique1.push_back(make_pair(verdist[i], i));\n\t}\n\n\t// ステップ 6. 深さ優先探索の前準備\n\tint offset = 1;\n\tif (centroid.size() == 3) offset = 2;\n\tint damage = 0;\n\tif (centroid.size() == 3) damage = maxdist[centroid[1]];\n\n\t// ステップ 7. 左側について、深さ優先探索を行う\n\tZ0.init(N);\n\tfor (int i = 0; i < unique1.size(); i++) {\n\t\tZ0.adds(-unique1[i].first - offset, C[unique1[i].second]);\n\t\tFukasa[-unique1[i].first - offset + N] = unique1[i].second;\n\t}\n\tif (offset == 2) { Z0.adds(-1, C[centroid[1]]); }\n\tfor (int i = -offset + 1 - damage; i <= -offset; i++) Z0.dels(i);\n\tdfs2(centroid[0], false);\n\n\t// ステップ 8. 右側について、深さ優先探索を行う\n\tZ0.init(N);\n\tfor (int i = 0; i < unique0.size(); i++) {\n\t\tZ0.adds(-unique0[i].first - offset, C[unique0[i].second]);\n\t\tFukasa[-unique0[i].first - offset + N] = unique0[i].second;\n\t}\n\tif (offset == 2) { Z0.adds(-1, C[centroid[1]]); }\n\tfor (int i = -offset + 1 - damage; i <= -offset; i++) Z0.dels(i);\n\tdfs2(centroid[offset], false);\n\n\t// ステップ 9. 中側について、深さ優先探索を行う\n\tif (offset == 2) {\n\t\tZ0.init(N);\n\t\tdfs2(centroid[1], false);\n\t}\n\n\t// ステップ 9. 出力する\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (M == 1) printf(\"%d\\n\", min(1, Answer[i]));\n\t\telse printf(\"%d\\n\", Answer[i]);\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 570, "memory_kb": 108976, "score_of_the_acc": -1.8246, "final_rank": 12 }, { "submission_id": "aoj_0662_3972291", "code_snippet": "#include <bits/stdc++.h>\n#include <type_traits>\n#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <cmath>\nusing namespace std;\n\nusing ll=int64_t;\n#define int ll\n\n#define FOR(i,a,b) for(int i=int(a);i<int(b);i++)\n#define REP(i,b) FOR(i,0,b)\n#define MP make_pair\n#define PB push_back\n#define EB emplace_back\n#define ALL(x) x.begin(),x.end()\nauto& errStream=cerr;\n#ifdef LOCAL\n#define cerr (cerr<<\"-- line \"<<__LINE__<<\" -- \")\n#else\nclass CerrDummy{}cerrDummy;\ntemplate<class T>\nCerrDummy& operator<<(CerrDummy&cd,const T&){\n\treturn cd;\n}\nusing charTDummy=char;\nusing traitsDummy=char_traits<charTDummy>;\nCerrDummy& operator<<(CerrDummy&cd,basic_ostream<charTDummy,traitsDummy>&(basic_ostream<charTDummy,traitsDummy>&)){\n\treturn cd;\n}\n#define cerr cerrDummy\n#endif\n#define REACH cerr<<\"reached\"<<endl\n#define DMP(x) cerr<<#x<<\":\"<<x<<endl\n#define ZERO(x) memset(x,0,sizeof(x))\n#define ONE(x) memset(x,-1,sizeof(x))\n\nusing pi=pair<int,int>;\nusing vi=vector<int>;\nusing ld=long double;\n\ntemplate<class T,class U>\nostream& operator<<(ostream& os,const pair<T,U>& p){\n\tos<<\"(\"<<p.first<<\",\"<<p.second<<\")\";\n\treturn os;\n}\n\ntemplate<class T>\nostream& operator <<(ostream& os,const vector<T>& v){\n\tos<<\"{\";\n\tREP(i,(int)v.size()){\n\t\tif(i)os<<\",\";\n\t\tos<<v[i];\n\t}\n\tos<<\"}\";\n\treturn os;\n}\n\nll read(){\n\tll i;\n\tscanf(\"%\" SCNd64,&i);\n\treturn i;\n}\n\nvoid printSpace(){\n\tprintf(\" \");\n}\n\nvoid printEoln(){\n\tprintf(\"\\n\");\n}\n\nvoid print(ll x,int suc=1){\n\tprintf(\"%\" PRId64,x);\n\tif(suc==1)\n\t\tprintEoln();\n\tif(suc==2)\n\t\tprintSpace();\n}\n\nstring readString(){\n\tstatic char buf[3341000];\n\tscanf(\"%s\",buf);\n\treturn string(buf);\n}\n\nchar* readCharArray(){\n\tstatic char buf[3341000];\n\tstatic int bufUsed=0;\n\tchar* ret=buf+bufUsed;\n\tscanf(\"%s\",ret);\n\tbufUsed+=strlen(ret)+1;\n\treturn ret;\n}\n\ntemplate<class T,class U>\nvoid chmax(T& a,U b){\n\tif(a<b)\n\t\ta=b;\n}\n\ntemplate<class T,class U>\nvoid chmin(T& a,U b){\n\tif(b<a)\n\t\ta=b;\n}\n\ntemplate<class T>\nT Sq(const T& t){\n\treturn t*t;\n}\n\n#define CAPITAL\nvoid Yes(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"YES\"<<endl;\n\t#else\n\tcout<<\"Yes\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\nvoid No(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"NO\"<<endl;\n\t#else\n\tcout<<\"No\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\n\nconst ll infLL=LLONG_MAX/3;\n\n#ifdef int\nconst int inf=infLL;\n#else\nconst int inf=INT_MAX/2-100;\n#endif\n\nconst int Nmax=200010;\nvi tr[Nmax];\nint ans[Nmax];\nint col[Nmax],cnt[Nmax],curAns,stBuf[Nmax],stS;\nvoid AddCol(int c){\n\tif(cnt[c]==0)\n\t\tcurAns++;\n\tcnt[c]++;\n}\nvoid DelCol(int c){\n\tcnt[c]--;\n\tif(cnt[c]==0)\n\t\tcurAns--;\n}\nvoid Push(int v){\n\tstBuf[stS++]=v;\n\tAddCol(col[v]);\n}\nbool Empty(){\n\treturn stS==0;\n}\nint Last(){\n\treturn stBuf[stS-1];\n}\nvoid Pop(){\n\tDelCol(col[Last()]);\n\tstS--;\n}\n\nvoid dfs1(int v,int p,int d,vi&dist){\n\tdist[v]=d;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tdfs1(to,v,d+1,dist);\n}\n\nint dep[Nmax];\nint dfs2(int v,int p){\n\tint res=0;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tchmax(res,dfs2(to,v));\n\treturn dep[v]=res+1;\n}\n\nvoid dfs3(int v,int p,const vi&dist){\n\tvector<pi> ch;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tch.EB(dep[to],to);\n\tif(!ch.empty()){\n\t\tswap(ch[0],*max_element(ALL(ch)));\n\t\tint len=ch.size()>1?max_element(ch.begin()+1,ch.end())->first:0;\n\t\tfor(auto c:ch){\n\t\t\tint to=c.second;\n\t\t\twhile(!Empty()&&dist[Last()]>=dist[v]-len)\n\t\t\t\tPop();\n\t\t\tPush(v);\n\t\t\tdfs3(to,v,dist);\n\t\t\tif(!Empty()&&Last()==v)\n\t\t\t\tPop();\n\t\t\tchmax(len,c.first);\n\t\t}\n\t\twhile(!Empty()&&dist[Last()]>=dist[v]-len)\n\t\t\tPop();\n\t}\n\tchmax(ans[v],curAns);\n}\n\nvoid Solve(int root,const vi&dist){\n\tassert(Empty());\n\tdfs2(root,-1);\n\tdfs3(root,-1,dist);\n}\n\nsigned main(){\n\tint n=read(),k=read();\n\tREP(_,n-1){\n\t\tint a=read()-1,b=read()-1;\n\t\ttr[a].PB(b);\n\t\ttr[b].PB(a);\n\t}\n\tREP(i,n)\n\t\tcol[i]=read()-1;\n\t\n\tvi dist(n);\n\tdfs1(0,-1,0,dist);\n\tint root=max_element(ALL(dist))-dist.begin();\n\tdfs1(root,-1,0,dist);\n\tSolve(root,dist);\n\t\n\troot=max_element(ALL(dist))-dist.begin();\n\tdfs1(root,-1,0,dist);\n\tSolve(root,dist);\n\t\n\tREP(i,n)\n\t\tprint(ans[i]);\n}", "accuracy": 1, "time_ms": 330, "memory_kb": 54364, "score_of_the_acc": -0.8297, "final_rank": 7 }, { "submission_id": "aoj_0662_3972210", "code_snippet": "#include <bits/stdc++.h>\n#include <type_traits>\nusing namespace std;\n\nusing ll=int64_t;\n#define int ll\n\n#define FOR(i,a,b) for(int i=int(a);i<int(b);i++)\n#define REP(i,b) FOR(i,0,b)\n#define MP make_pair\n#define PB push_back\n#define EB emplace_back\n#define ALL(x) x.begin(),x.end()\nauto& errStream=cerr;\n#ifdef LOCAL\n#define cerr (cerr<<\"-- line \"<<__LINE__<<\" -- \")\n#else\nclass CerrDummy{}cerrDummy;\ntemplate<class T>\nCerrDummy& operator<<(CerrDummy&cd,const T&){\n\treturn cd;\n}\nusing charTDummy=char;\nusing traitsDummy=char_traits<charTDummy>;\nCerrDummy& operator<<(CerrDummy&cd,basic_ostream<charTDummy,traitsDummy>&(basic_ostream<charTDummy,traitsDummy>&)){\n\treturn cd;\n}\n#define cerr cerrDummy\n#endif\n#define REACH cerr<<\"reached\"<<endl\n#define DMP(x) cerr<<#x<<\":\"<<x<<endl\n#define ZERO(x) memset(x,0,sizeof(x))\n#define ONE(x) memset(x,-1,sizeof(x))\n\nusing pi=pair<int,int>;\nusing vi=vector<int>;\nusing ld=long double;\n\ntemplate<class T,class U>\nostream& operator<<(ostream& os,const pair<T,U>& p){\n\tos<<\"(\"<<p.first<<\",\"<<p.second<<\")\";\n\treturn os;\n}\n\ntemplate<class T>\nostream& operator <<(ostream& os,const vector<T>& v){\n\tos<<\"{\";\n\tREP(i,(int)v.size()){\n\t\tif(i)os<<\",\";\n\t\tos<<v[i];\n\t}\n\tos<<\"}\";\n\treturn os;\n}\n\nll read(){\n\tll i;\n\tscanf(\"%\" SCNd64,&i);\n\treturn i;\n}\n\nvoid printSpace(){\n\tprintf(\" \");\n}\n\nvoid printEoln(){\n\tprintf(\"\\n\");\n}\n\nvoid print(ll x,int suc=1){\n\tprintf(\"%\" PRId64,x);\n\tif(suc==1)\n\t\tprintEoln();\n\tif(suc==2)\n\t\tprintSpace();\n}\n\nstring readString(){\n\tstatic char buf[3341000];\n\tscanf(\"%s\",buf);\n\treturn string(buf);\n}\n\nchar* readCharArray(){\n\tstatic char buf[3341000];\n\tstatic int bufUsed=0;\n\tchar* ret=buf+bufUsed;\n\tscanf(\"%s\",ret);\n\tbufUsed+=strlen(ret)+1;\n\treturn ret;\n}\n\ntemplate<class T,class U>\nvoid chmax(T& a,U b){\n\tif(a<b)\n\t\ta=b;\n}\n\ntemplate<class T,class U>\nvoid chmin(T& a,U b){\n\tif(b<a)\n\t\ta=b;\n}\n\ntemplate<class T>\nT Sq(const T& t){\n\treturn t*t;\n}\n\n#define CAPITAL\nvoid Yes(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"YES\"<<endl;\n\t#else\n\tcout<<\"Yes\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\nvoid No(bool ex=true){\n\t#ifdef CAPITAL\n\tcout<<\"NO\"<<endl;\n\t#else\n\tcout<<\"No\"<<endl;\n\t#endif\n\tif(ex)exit(0);\n}\n\nconst ll infLL=LLONG_MAX/3;\n\n#ifdef int\nconst int inf=infLL;\n#else\nconst int inf=INT_MAX/2-100;\n#endif\n\nconst int Nmax=200010;\nvi tr[Nmax];\nint ans[Nmax];\nint col[Nmax],cnt[Nmax],curAns,stBuf[Nmax],stS;\nvoid AddCol(int c){\n\tif(cnt[c]==0)\n\t\tcurAns++;\n\tcnt[c]++;\n}\nvoid DelCol(int c){\n\tcnt[c]--;\n\tif(cnt[c]==0)\n\t\tcurAns--;\n}\nvoid Push(int v){\n\tstBuf[stS++]=v;\n\tAddCol(col[v]);\n}\nbool Empty(){\n\treturn stS==0;\n}\nint Last(){\n\treturn stBuf[stS-1];\n}\nvoid Pop(){\n\tDelCol(col[Last()]);\n\tstS--;\n}\n\nvoid dfs1(int v,int p,int d,vi&dist){\n\tdist[v]=d;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tdfs1(to,v,d+1,dist);\n}\n\nint dep[Nmax];\nint dfs2(int v,int p){\n\tint res=0;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tchmax(res,dfs2(to,v));\n\treturn dep[v]=res+1;\n}\n\nvoid dfs3(int v,int p,const vi&dist){\n\tvector<pi> ch;\n\tfor(auto to:tr[v])\n\t\tif(to!=p)\n\t\t\tch.EB(dep[to],to);\n\tif(!ch.empty()){\n\t\tswap(ch[0],*max_element(ALL(ch)));\n\t\tint len=ch.size()>1?max_element(ch.begin()+1,ch.end())->first:0;\n\t\tfor(auto c:ch){\n\t\t\tint to=c.second;\n\t\t\twhile(!Empty()&&dist[Last()]>=dist[v]-len)\n\t\t\t\tPop();\n\t\t\tPush(v);\n\t\t\tdfs3(to,v,dist);\n\t\t\tif(!Empty()&&Last()==v)\n\t\t\t\tPop();\n\t\t\tchmax(len,c.first);\n\t\t}\n\t\twhile(!Empty()&&dist[Last()]>=dist[v]-len)\n\t\t\tPop();\n\t}\n\tchmax(ans[v],curAns);\n}\n\nvoid Solve(int root,const vi&dist){\n\tassert(Empty());\n\tdfs2(root,-1);\n\tdfs3(root,-1,dist);\n}\n\nsigned main(){\n\tint n=read(),k=read();\n\tREP(_,n-1){\n\t\tint a=read()-1,b=read()-1;\n\t\ttr[a].PB(b);\n\t\ttr[b].PB(a);\n\t}\n\tREP(i,n)\n\t\tcol[i]=read()-1;\n\t\n\tvi dist(n);\n\tdfs1(0,-1,0,dist);\n\tint root=max_element(ALL(dist))-dist.begin();\n\tdfs1(root,-1,0,dist);\n\tSolve(root,dist);\n\t\n\troot=max_element(ALL(dist))-dist.begin();\n\tdfs1(root,-1,0,dist);\n\tSolve(root,dist);\n\t\n\tREP(i,n)\n\t\tprint(ans[i]);\n}", "accuracy": 1, "time_ms": 350, "memory_kb": 54452, "score_of_the_acc": -0.8657, "final_rank": 8 }, { "submission_id": "aoj_0662_3972191", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <bool Directed> struct graph {\n int n;\n vector<vector<int>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n adj[u].push_back(v);\n if(not Directed) adj[v].push_back(u);\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s) {\n vector<int> d(g.n + 1, -1);\n d[s] = 0;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n for(int v : g.adj[u]) {\n if(d[v] == -1) {\n d[v] = d[u] + 1;\n q.push(v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1), max_subtree(n + 1), depth(n + 1), unique_cities;\n vector<int> unique_goods(m + 1);\n int n_unique = 0;\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(int v : g.adj[u]) {\n if(v != from) {\n dfs1(v, u);\n if(h[v] > h[max_subtree[u]]) max_subtree[u] = v;\n }\n }\n h[u] = h[max_subtree[u]] + 1;\n };\n dfs1(s, 0);\n function<void(int, int)> dfs2 = [&](int u, int from) {\n depth[u] = depth[from] + 1;\n auto add = [&](int v) {\n unique_cities.push_back(v);\n n_unique += ++unique_goods[c[v]] == 1;\n };\n auto remove = [&](int v) {\n if(not unique_cities.empty() and unique_cities.back() == v) {\n unique_cities.pop_back();\n n_unique -= unique_goods[c[v]]-- == 1;\n }\n };\n auto filter = [&](int max_allowed_depth) {\n while(not unique_cities.empty() and depth[unique_cities.back()] >= max_allowed_depth) {\n remove(unique_cities.back());\n }\n };\n int n_children = g.adj[u].size() - bool(from);\n if(n_children >= 1) {\n if(n_children > 1) {\n int second_max_subtree = 0;\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u] and h[v] > h[second_max_subtree]) {\n second_max_subtree = v;\n }\n }\n filter(depth[u] - h[second_max_subtree]);\n }\n add(u);\n dfs2(max_subtree[u], u);\n remove(u);\n }\n filter(depth[u] - (h[u] - 1));\n ans[u] = max(ans[u], n_unique);\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u]) {\n add(u);\n dfs2(v, u);\n remove(u);\n }\n }\n };\n dfs2(s, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 54668, "score_of_the_acc": -0.9908, "final_rank": 9 }, { "submission_id": "aoj_0662_3662173", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <bool Directed> struct graph {\n int n;\n vector<vector<int>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n adj[u].push_back(v);\n if(not Directed) adj[v].push_back(u);\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s) {\n vector<int> d(g.n + 1, -1);\n d[s] = 0;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n for(int v : g.adj[u]) {\n if(d[v] == -1) {\n d[v] = d[u] + 1;\n q.push(v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1), max_subtree(n + 1), depth(n + 1), unique_cities;\n vector<int> unique_goods(m + 1);\n int n_unique = 0;\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(int v : g.adj[u]) {\n if(v != from) {\n dfs1(v, u);\n if(h[v] > h[max_subtree[u]]) max_subtree[u] = v;\n }\n }\n h[u] = h[max_subtree[u]] + 1;\n };\n dfs1(s, 0);\n function<void(int, int)> dfs2 = [&](int u, int from) {\n depth[u] = depth[from] + 1;\n auto add = [&](int v) {\n unique_cities.push_back(v);\n n_unique += ++unique_goods[c[v]] == 1;\n };\n auto remove = [&](int v) {\n if(not unique_cities.empty() and unique_cities.back() == v) {\n unique_cities.pop_back();\n n_unique -= unique_goods[c[v]]-- == 1;\n }\n };\n auto filter = [&](int max_allowed_depth) {\n while(not unique_cities.empty() and depth[unique_cities.back()] >= max_allowed_depth) {\n remove(unique_cities.back());\n }\n };\n int n_children = g.adj[u].size() - bool(from);\n if(n_children >= 1) {\n if(n_children > 1) {\n int second_max_subtree = 0;\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u] and h[v] > h[second_max_subtree]) {\n second_max_subtree = v;\n }\n }\n filter(depth[u] - h[second_max_subtree]);\n }\n add(u);\n dfs2(max_subtree[u], u);\n remove(u);\n }\n filter(depth[u] - (h[u] - 1));\n ans[u] = max(ans[u], n_unique);\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u]) {\n add(u);\n dfs2(v, u);\n remove(u);\n }\n }\n };\n dfs2(s, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 54620, "score_of_the_acc": -1.0254, "final_rank": 10 }, { "submission_id": "aoj_0662_3662100", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <bool Directed> struct graph {\n int n;\n vector<vector<int>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n adj[u].push_back(v);\n if(not Directed) adj[v].push_back(u);\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s) {\n vector<int> d(g.n + 1, -1);\n d[s] = 0;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n for(int v : g.adj[u]) {\n if(d[v] == -1) {\n d[v] = d[u] + 1;\n q.push(v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1), max_subtree(n + 1), depth(n + 1), unique_cities;\n map<int, int> unique_goods;\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(int v : g.adj[u]) {\n if(v != from) {\n dfs1(v, u);\n if(h[v] > h[max_subtree[u]]) max_subtree[u] = v;\n }\n }\n h[u] = h[max_subtree[u]] + 1;\n };\n dfs1(s, 0);\n function<void(int, int)> dfs2 = [&](int u, int from) {\n depth[u] = depth[from] + 1;\n auto add = [&](int v) {\n unique_cities.push_back(v);\n unique_goods[c[v]]++;\n };\n auto remove = [&](int v) {\n if(not unique_cities.empty() and unique_cities.back() == v) {\n unique_cities.pop_back();\n if(--unique_goods[c[v]] == 0) {\n unique_goods.erase(c[v]);\n }\n }\n };\n auto filter = [&](int max_allowed_depth) {\n while(not unique_cities.empty() and depth[unique_cities.back()] >= max_allowed_depth) {\n remove(unique_cities.back());\n }\n };\n int n_children = g.adj[u].size() - bool(from);\n if(n_children >= 1) {\n if(n_children > 1) {\n int second_max_subtree = 0;\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u] and h[v] > h[second_max_subtree]) {\n second_max_subtree = v;\n }\n }\n filter(depth[u] - h[second_max_subtree]);\n }\n add(u);\n dfs2(max_subtree[u], u);\n remove(u);\n }\n filter(depth[u] - (h[u] - 1));\n ans[u] = max(ans[u], int(unique_goods.size()));\n for(int v : g.adj[u]) {\n if(v != from and v != max_subtree[u]) {\n add(u);\n dfs2(v, u);\n remove(u);\n }\n }\n };\n dfs2(s, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n return 0;\n}", "accuracy": 1, "time_ms": 670, "memory_kb": 65356, "score_of_the_acc": -1.5417, "final_rank": 11 }, { "submission_id": "aoj_0662_3660191", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else if(*min_element(c.begin() + 1, c.end()) == 1 and *max_element(c.begin() + 1, c.end()) == 1) {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, int)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n vector<int> unique_depths, temp;\n unique_depths.reserve(n);\n temp.reserve(n);\n function<void(int, int, int)> dfs2 = [&](int u, int from, int depth) {\n int temp_size = 0;\n while(not unique_depths.empty() and unique_depths.back() >= depth - (h[u] - 1)) {\n temp.push_back(unique_depths.back());\n temp_size++;\n unique_depths.pop_back();\n }\n ans[u] = max(ans[u], int(unique_depths.size()));\n unique_depths.push_back(depth);\n for(int i = 1; i + 1 < g.adj[u].size(); i++) {\n dfs2(g.adj[u][i].v, u, depth + 1);\n }\n unique_depths.pop_back();\n while(temp_size) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n temp_size--;\n }\n if(g.adj[u].size() > 1 and g.adj[u][1].v != from) {\n while(not unique_depths.empty() and unique_depths.back() >= depth - h[g.adj[u][1].v]) {\n temp.push_back(unique_depths.back());\n temp_size++;\n unique_depths.pop_back();\n }\n unique_depths.push_back(depth);\n dfs2(g.adj[u][0].v, u, depth + 1);\n unique_depths.pop_back();\n while(temp_size) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n temp_size--;\n }\n }\n };\n dfs2(s, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.4608695652173913, "time_ms": 420, "memory_kb": 41944, "score_of_the_acc": -0.8571, "final_rank": 15 }, { "submission_id": "aoj_0662_3660166", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else if(*min_element(c.begin() + 1, c.end()) == 1 and *max_element(c.begin() + 1, c.end()) == 1) {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, int)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n vector<int> unique_depths, temp;\n function<void(int, int, int)> dfs2 = [&](int u, int from, int depth) {\n auto pos = lower_bound(unique_depths.begin(), unique_depths.end(), depth - (h[u] - 1)) - unique_depths.begin();\n ans[u] = max(ans[u], int(pos));\n int n_children = g.adj[u].size() - bool(from);\n if(n_children == 1) {\n unique_depths.push_back(depth);\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs2(e.v, u, depth + 1);\n }\n }\n unique_depths.pop_back();\n } else if(n_children > 1) {\n int temp_size = 0;\n while(not unique_depths.empty() and unique_depths.back() >= depth - (h[u] - 1)) {\n temp.push_back(unique_depths.back());\n temp_size++;\n unique_depths.pop_back();\n }\n for(int i = 1; i + 1 < g.adj[u].size(); i++) {\n int v = g.adj[u][i].v;\n unique_depths.push_back(depth);\n dfs2(v, u, depth + 1);\n unique_depths.pop_back();\n }\n while(temp_size--) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n while(not unique_depths.empty() and unique_depths.back() >= depth - h[g.adj[u][1].v]) {\n temp.push_back(unique_depths.back());\n temp_size++;\n unique_depths.pop_back();\n }\n unique_depths.push_back(depth);\n dfs2(g.adj[u][0].v, u, depth + 1);\n unique_depths.pop_back();\n while(temp_size--) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n }\n };\n dfs2(s, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.4608695652173913, "time_ms": 410, "memory_kb": 41772, "score_of_the_acc": -0.8378, "final_rank": 14 }, { "submission_id": "aoj_0662_3657529", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\ntemplate <bool Directed> struct graph {\n int n;\n vector<vector<int>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n adj[u].push_back(v);\n if(not Directed) adj[v].push_back(u);\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(int v : g.adj[u]) {\n if(d[v] == -1) {\n d[v] = d[u] + 1, p[v] = u;\n q.push(v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nconst int N = 200'000;\nint ans[N + 1], h[N + 1];\nvoid dfs1(graph<0>& g, int u, int from = 0) {\n for(int v : g.adj[u]) {\n if(v != from) {\n dfs1(g, v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](int v1, int v2) {\n return v2 == from or (v1 != from and h[v1] > h[v2]);\n });\n h[u] = h[g.adj[u][0]] + 1;\n}\nvector<int> unique_depths, temp;\nint depth = 0;\nvoid dfs2(graph<0>& g, int u, int from = 0) {\n auto pos = lower_bound(unique_depths.begin(), unique_depths.end(), depth - (h[u] - 1)) - unique_depths.begin();\n ans[u] = max(ans[u], int(pos));\n int n_children = g.adj[u].size() - bool(from);\n if(n_children == 1) {\n unique_depths.push_back(depth);\n for(int v : g.adj[u]) {\n if(v != from) {\n depth++;\n dfs2(g, v, u);\n depth--;\n }\n }\n unique_depths.pop_back();\n } else if(n_children > 1) {\n while(not unique_depths.empty() and unique_depths.back() >= depth - (h[u] - 1)) {\n temp.push_back(unique_depths.back());\n unique_depths.pop_back();\n }\n for(int i = 1; i + 1 < g.adj[u].size(); i++) {\n unique_depths.push_back(depth);\n depth++;\n dfs2(g, g.adj[u][i], u);\n depth--;\n unique_depths.pop_back();\n }\n while(not temp.empty()) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n while(not unique_depths.empty() and unique_depths.back() >= depth - h[g.adj[u][1]]) {\n temp.push_back(unique_depths.back());\n unique_depths.pop_back();\n }\n unique_depths.push_back(depth);\n depth++;\n dfs2(g, g.adj[u][0], u);\n depth--;\n unique_depths.pop_back();\n while(not temp.empty()) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n }\n};\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else if(*min_element(c.begin() + 1, c.end()) == 1 and *max_element(c.begin() + 1, c.end()) == 1) {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(int v : g.adj[u]) {\n if(v != from) {\n dfs1(v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](int v1, int v2) {\n return v2 == from or (v1 != from and h[v1] > h[v2]);\n });\n h[u] = h[g.adj[u][0]] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, int)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(int v : g.adj[u]) {\n if(v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0] == v ? g.adj[u][1] : g.adj[u][0];\n dfs2(v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n for(int s : diameter_nodes(g)) {\n memset(h, 0, sizeof h);\n dfs1(g, s);\n dfs2(g, s);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.4608695652173913, "time_ms": 410, "memory_kb": 37932, "score_of_the_acc": -0.7974, "final_rank": 13 }, { "submission_id": "aoj_0662_3657127", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else if(*min_element(c.begin(), c.end()) == 1 and *max_element(c.begin(), c.end()) == 1) {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, int)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, vector<int>&)> dfs2 = [&](int u, int from, int depth, vector<int>& unique_depths) {\n auto pos = lower_bound(unique_depths.begin(), unique_depths.end(), depth - (h[u] - 1)) - unique_depths.begin();\n ans[u] = max(ans[u], int(pos));\n int n_children = g.adj[u].size() - bool(from);\n if(n_children == 1) {\n unique_depths.push_back(depth);\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs2(e.v, u, depth + 1, unique_depths);\n }\n }\n unique_depths.pop_back();\n } else if(n_children > 1) {\n vector<int> temp;\n while(not unique_depths.empty() and unique_depths.back() >= depth - (h[u] - 1)) {\n temp.push_back(unique_depths.back());\n unique_depths.pop_back();\n }\n for(int i = 1; i + 1 < g.adj[u].size(); i++) {\n int v = g.adj[u][i].v;\n unique_depths.push_back(depth);\n dfs2(v, u, depth + 1, unique_depths);\n unique_depths.pop_back();\n }\n while(not temp.empty()) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n while(not unique_depths.empty() and unique_depths.back() >= depth - h[g.adj[u][1].v]) {\n temp.push_back(unique_depths.back());\n unique_depths.pop_back();\n }\n unique_depths.push_back(depth);\n dfs2(g.adj[u][0].v, u, depth + 1, unique_depths);\n unique_depths.pop_back();\n while(not temp.empty()) {\n unique_depths.push_back(temp.back());\n temp.pop_back();\n }\n }\n };\n vector<int> unique_depths;\n dfs2(s, 0, 0, unique_depths);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.3130434782608696, "time_ms": 230, "memory_kb": 13900, "score_of_the_acc": -0.2292, "final_rank": 19 }, { "submission_id": "aoj_0662_3656599", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, int)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.4608695652173913, "time_ms": 450, "memory_kb": 41972, "score_of_the_acc": -0.9101, "final_rank": 16 }, { "submission_id": "aoj_0662_3656511", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, bool)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, not u_has_one_child and depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.3130434782608696, "time_ms": 240, "memory_kb": 13852, "score_of_the_acc": -0.2462, "final_rank": 20 }, { "submission_id": "aoj_0662_3656487", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, bool)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 0, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.3130434782608696, "time_ms": 230, "memory_kb": 13816, "score_of_the_acc": -0.2283, "final_rank": 18 }, { "submission_id": "aoj_0662_3656480", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nstruct edge { int u, v, i; };\nostream& operator<<(ostream& os, const edge& e) {\n os << \"(\" << e.u << \", \" << e.v << \")\";\n return os;\n}\ntemplate <bool Directed> struct graph {\n int n;\n vector<edge> edges;\n vector<vector<edge>> adj;\n graph(int n) : n(n), adj(n + 1) {}\n void add_edge(int u, int v) {\n int i = edges.size();\n edges.push_back({u, v, i});\n adj[u].push_back({u, v, i});\n if(not Directed) adj[v].push_back({v, u, i});\n }\n};\ntemplate <bool Directed> vector<int> bfs(graph<Directed>& g, int s, const function<void(int)>& f = [](int) {}) {\n vector<int> d(g.n + 1, -1), p(g.n + 1);\n d[s] = 0, p[s] = -1;\n queue<int> q({s});\n while(not q.empty()) {\n int u = q.front(); q.pop();\n f(u);\n for(auto& e : g.adj[u]) {\n if(d[e.v] == -1) {\n d[e.v] = d[u] + 1, p[e.v] = u;\n q.push(e.v);\n }\n }\n }\n return d;\n}\nvector<int> diameter_nodes(graph<0>& g) {\n auto d1 = bfs(g, 1);\n int n1 = max_element(d1.begin(), d1.end()) - d1.begin();\n auto d2 = bfs(g, n1);\n int n2 = max_element(d2.begin(), d2.end()) - d2.begin();\n return {n1, n2};\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n, m;\n cin >> n >> m;\n graph<0> g(n);\n for(int i = 1; i < n; i++) {\n int u, v;\n cin >> u >> v;\n g.add_edge(u, v);\n }\n vector<int> c(n + 1);\n for(int i = 1; i <= n; i++) {\n cin >> c[i];\n }\n if(n <= 2000) {\n for(int i = 1; i <= n; i++) {\n auto d = bfs(g, i);\n vector<int> n_dist(n + 1);\n for(int j = 1; j <= n; j++) {\n if(j != i) {\n n_dist[d[j]]++;\n }\n }\n set<int> ans;\n for(int j = 1; j <= n; j++) {\n if(n_dist[d[j]] == 1) {\n ans.insert(c[j]);\n }\n }\n cout << ans.size() << endl;\n }\n } else {\n vector<int> ans(n + 1);\n for(int s : diameter_nodes(g)) {\n vector<int> h(n + 1);\n function<void(int, int)> dfs1 = [&](int u, int from) {\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n dfs1(e.v, u);\n }\n }\n sort(g.adj[u].begin(), g.adj[u].end(), [&](auto& e1, auto& e2) {\n return e2.v == from or (e1.v != from and h[e1.v] > h[e2.v]);\n });\n h[u] = h[g.adj[u][0].v] + 1;\n };\n dfs1(s, 0);\n function<void(int, int, int, bool)> dfs2 = [&](int u, int from, int depth, int lowest_unique) {\n ans[u] |= depth - (h[u] - 1) > lowest_unique;\n bool u_has_one_child = g.adj[u].size() - bool(from) == 1;\n for(auto& e : g.adj[u]) {\n if(e.v != from) {\n int tallest_sibling = not u_has_one_child and g.adj[u][0].v == e.v ? g.adj[u][1].v : g.adj[u][0].v;\n dfs2(e.v, u, depth + 1, depth - h[tallest_sibling] <= lowest_unique ? depth : lowest_unique);\n }\n }\n };\n dfs2(s, 0, 1, 0);\n }\n for(int i = 1; i <= n; i++) {\n cout << ans[i] << endl;\n }\n }\n return 0;\n}", "accuracy": 0.3130434782608696, "time_ms": 230, "memory_kb": 13796, "score_of_the_acc": -0.2281, "final_rank": 17 } ]
aoj_0676_cpp
じゃんけん式 (Rock-Scissors-Paper Expression) 問題文 この問題では,じゃんけんの手「グー」「チョキ」「パー」をそれぞれ R, S, P で表す. R は S に勝ち, S は P に勝ち, P は R に勝つ. x, y をじゃんけんの手とするとき, x + y, x - y, x * y を以下のように定める (これらは通常の意味での足し算・引き算・掛け算ではない): x + y は, x ≠ y のとき x と y のうち勝つ方とし, x = y のとき x とする. x - y は, x ≠ y のとき x と y のうち負ける方とし, x = y のとき x とする. x * y は, x ≠ y のとき R, S, P のうち x でも y でもないものとし, x = y のとき x とする. じゃんけんの手と +, -, * と括弧からなる式は,以下のように計算する: 括弧の中は先に計算する.例えば, R * (P + S) = R * S = P である. 括弧の深さが同じ部分については, +, - より * の方を優先して計算する.例えば, R - P * S = R - (P * S) = R - R = R である. 同じ優先順位のもの ( + どうし, - どうし, + と - , * どうし) については,左から順番に計算する.例えば, R - P + S = (R - P) + S = R + S = R である. JOI さんはあるじゃんけんの式を持っていたが,その式の中の R, S, P の一部が見えなくなってしまった.見えなくなってしまった部分が `?' で表された長さ N の文字列 E が与えられる.JOI さんは,見えなくなってしまった部分のそれぞれに R, S, P のいずれかを割り当てる方法であって,式の計算結果が A になるものが何通りあるかを知りたい.その数は非常に大きくなる可能性があるので, 1 000 000 007 で割った余りを求めたい. 本問で用いられる文法は,BNF (バッカス・ナウア記法) を用いて以下のように表される.じゃんけんの式の一部が見えなくなってしまったものは <expression> である. <expression> ::= <term> | <expression> "+" <term> | <expression> "-" <term> <term> ::= <factor> | <term> "*" <factor> <factor> ::= "R" | "S" | "P" | "?" | "(" <expression> ")" これは例えば,ある文字列が <expression> であるとは,「<term> である」または「<expression> である文字列,`+',<term> である文字列,をこの順に連結させたもの」または「<expression> である文字列,`-',<term> である文字列,をこの順に連結させたもの」であることである,というように再帰的に定義されることを意味する. <expression> である文字列 E と計算結果 A が与えられるので,`?' に R, S, P のいずれかを割り当てる方法であって式の計算結果が A になるものの個数を 1 000 000 007 で割った余りを求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 200 000 . E は長さ N の文字列である. E は問題文で定められた <expression> である. A は `R' または `S' または `P' である. 入力 入力は以下の形式で標準入力から与えられる. N E A 出力 標準出力に,`?' に R, S, P のいずれかを割り当てる方法であって式の計算結果が A になるものの個数を 1 000 000 007 で割った余りを 1 行で出力せよ. 入出力例 入力例 1 11 S+?-(R+?)*P S 出力例 1 6 2 箇所の `?' に R, S, P のいずれかを割り当てて計算結果を S にする方法は,以下の 6 通りがある: S + R - (R + R) * P S + R - (R + S) * P S + S - (R + R) * P S + S - (R + S) * P S + P - (R + R) * P S + P - (R + S) * P 入力例 2 15 ?+?-?*?+?-?*?+? R 出力例 2 2187 入力例 3 13 (((((R)))))+? P 出力例 3 1 入力例 4 1 P S 出力例 4 0 入力例 5 27 R+((?+S-?*P+?)-P*?+S-?)*R+? P 出力例 5 381 入力例 6 83 ((R+?)*(?+?))*((?+?)*(?+?))*((?+?)*(?+?))-((S+?)*(?+?))*((?+?)*(?+?))*((?+?)*(?+?)) P 出力例 6 460353133 条件を満たす割り当て方は 10 460 353 203 通りあるため,それを 1 000 000 007 で割った余りである 460 353 133 を出力する. 情報オリンピック日本委員会 作 『第 19 回日本情報オリンピック JOI 2019/2020 一次予選競技課題』
[ { "submission_id": "aoj_0676_9609164", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nconst ll mod=1e9+7;\n\n\nvector<ll> E(char c){\n if(c=='R')return {1,0,0};\n else if(c=='S')return {0,1,0};\n else if(c=='P')return {0,0,1};\n else if(c=='?')return {1,1,1};\n else return {-1,0,0};\n}\n\nvoid calc(vector<ll> &A,vector<ll> &B,int type){\n if(A[0]==-1){\n swap(A,B);\n return;\n }\n vector<ll> R(3,0);\n for(int a=0;a<3;a++)for(int b=0;b<3;b++){\n if(a==b)R[a]+=(A[a]*B[b])%mod;\n else if(type==1){\n if((a==0&&b==2)||(a==2&&b==0))R[2]+=(A[a]*B[b])%mod;\n else R[min(a,b)]+=(A[a]*B[b])%mod;\n }\n else if(type==0){\n if((a==0&&b==2)||(a==2&&b==0))R[0]+=(A[a]*B[b])%mod;\n else R[max(a,b)]+=(A[a]*B[b])%mod;\n }\n else{\n R[3-a-b]+=(A[a]*B[b])%mod;\n }\n }\n for(int i=0;i<3;i++)R[i]%=mod;\n swap(A,R);\n B=E('!');\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n string S;\n char C;\n cin>>N>>S>>C;\n \n vector<vector<ll>> P(N+1,E('!')), M(N+1,E('!'));\n vector<bool> is_plus(N+1,1);\n int level=0;\n for (int i = 0; i < N; i++) {\n if (S[i] == '(')level++;\n else if (S[i] == ')') {\n calc(P[level], M[level],is_plus[level]);\n calc(M[level-1],P[level],2);\n is_plus[level]=1;\n level--;\n }\n else if (S[i] == '+' || S[i] == '-') {\n calc(P[level],M[level],is_plus[level]);\n is_plus[level] = (S[i] == '+');\n }\n else if (S[i] == '*'){}\n else {\n vector<ll> H=E(S[i]);\n calc(M[level],H,2);\n }\n }\n calc (P[0],M[0],is_plus[0]);\n\n if(C=='R')cout<<P[0][0]<<endl;\n else if(C=='S')cout<<P[0][1]<<endl;\n else cout<<P[0][2]<<endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 25256, "score_of_the_acc": -0.1709, "final_rank": 3 }, { "submission_id": "aoj_0676_8495671", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\ntemplate <int mod>\nstruct static_modint {\n using mint = static_modint;\n int x;\n\n static_modint() : x(0) {}\n static_modint(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n\n mint& operator+=(const mint& rhs) {\n if ((x += rhs.x) >= mod) x -= mod;\n return *this;\n }\n mint& operator-=(const mint& rhs) {\n if ((x += mod - rhs.x) >= mod) x -= mod;\n return *this;\n }\n mint& operator*=(const mint& rhs) {\n x = (int) (1LL * x * rhs.x % mod);\n return *this;\n }\n mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); }\n\n mint pow(long long n) const {\n mint _x = *this, r = 1;\n while (n) {\n if (n & 1) r *= _x;\n _x *= _x;\n n >>= 1;\n }\n return r;\n }\n mint inv() const { return pow(mod - 2); }\n\n mint operator+() const { return *this; }\n mint operator-() const { return mint() - *this; }\n friend mint operator+(const mint& lhs, const mint& rhs) {\n return mint(lhs) += rhs;\n }\n friend mint operator-(const mint& lhs, const mint& rhs) {\n return mint(lhs) -= rhs;\n }\n friend mint operator*(const mint& lhs, const mint& rhs) {\n return mint(lhs) *= rhs;\n }\n friend mint operator/(const mint& lhs, const mint& rhs) {\n return mint(lhs) /= rhs;\n }\n friend bool operator==(const mint& lhs, const mint& rhs) {\n return lhs.x == rhs.x;\n }\n friend bool operator!=(const mint& lhs, const mint& rhs) {\n return lhs.x != rhs.x;\n }\n\n friend ostream &operator<<(ostream &os, const mint &p) {\n return os << p.x;\n }\n friend istream &operator>>(istream &is, mint &a) {\n int64_t t; is >> t;\n a = static_modint<mod>(t);\n return (is);\n }\n};\n\nconst unsigned int mod = 1e9+7;\nusing modint = static_modint<mod>;\nmodint mod_pow(ll n, ll x) { return modint(n).pow(x); }\nmodint mod_pow(modint n, ll x) { return n.pow(x); }\n\n// R,S,P\nint f(char c) {\n if (c == 'R') return 0;\n else if (c == 'S') return 1;\n else if (c == 'P') return 2;\n else if (c == '?') return 3;\n else {\n assert(false);\n }\n}\n\nstruct S : public array<modint,3> {\n S() {\n (*this)[0] = 0;\n (*this)[1] = 0;\n (*this)[2] = 0;\n }\n explicit S(char c) {\n int ff = f(c);\n for (int i = 0; i < 3; ++i) {\n (*this)[i] = (i == ff or ff == 3);\n }\n }\n\n S operator+=(const S &r) {\n S res = S();\n for (int i = 0; i < 3; ++i) {\n res[i] += (*this)[i] * r[(i+1)%3];\n res[i] += (*this)[(i+1)%3] * r[i];\n res[i] += (*this)[i] * r[i];\n }\n return *this = res;\n }\n S operator-=(const S &r) {\n S res = S();\n for (int i = 0; i < 3; ++i) {\n res[i] += (*this)[i] * r[(i+2)%3];\n res[i] += (*this)[(i+2)%3] * r[i];\n res[i] += (*this)[i] * r[i];\n }\n return *this = res;\n }\n S operator*=(const S &r) {\n S res = S();\n for (int i = 0; i < 3; ++i) {\n res[i] += (*this)[(i+2)%3] * r[(i+1)%3];\n res[i] += (*this)[(i+1)%3] * r[(i+2)%3];\n res[i] += (*this)[i] * r[i];\n }\n return *this = res;\n }\n\n void debug() {\n cout << (*this)[0] << \" \" << (*this)[1] << \" \" << (*this)[2] << endl;\n }\n};\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n string s; cin >> s;\n char C; cin >> C;\n\n int idx = 0;\n auto slv = [&](auto slv, string &s, int &idx) -> S {\n vector<S> val;\n vector<char> op;\n while (idx < s.size()) {\n if (s[idx] == '+' or s[idx] == '-' or s[idx] == '*') {\n op.push_back(s[idx]);\n idx += 1;\n }\n else if (s[idx] == '(') {\n idx += 1;\n val.push_back(slv(slv, s, idx));\n assert(s[idx] == ')');\n idx += 1;\n }\n else if (s[idx] == ')') {\n break;\n }\n else {\n S v = S(s[idx]);\n val.push_back(v);\n idx += 1;\n }\n }\n {\n vector<S> nval = {val[0]};\n vector<char> nop;\n for (int i = 0; i < op.size(); ++i) {\n if (op[i] == '*') {\n nval.back() *= val[i+1];\n }\n else {\n nop.push_back(op[i]);\n nval.push_back(val[i+1]);\n }\n }\n swap(val, nval);\n swap(op, nop);\n }\n {\n for (int i = 0; i < op.size(); ++i) {\n if (op[i] == '+') {\n val[0] += val[i+1];\n }\n else {\n val[0] -= val[i+1];\n }\n }\n }\n// val[0].debug();\n return val[0];\n };\n auto res = slv(slv, s, idx);\n cout << res[f(C)] << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26916, "score_of_the_acc": -0.0384, "final_rank": 1 }, { "submission_id": "aoj_0676_5936761", "code_snippet": "#include<algorithm>\n#include<bitset>\n#include<cassert>\n#include<cfloat>\n#include<climits>\n#include<cmath>\n#include<deque>\n#include<functional>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<stack>\n#include<string>\n#include<unordered_map>\n#include<unordered_set>\n#include<utility>\n#include<vector>\n\nusing namespace std;\n\nusing lint = long long;\nusing P = pair<int, int>;\nusing LLP = pair<long long, long long>;\n\n#define REP(i, x, n) for(int i = (x), i##_len = (int)(n) ; i < i##_len ; ++i)\n#define rep(i, n) for(int i = 0, i##_len = (int)(n) ; i < i##_len ; ++i)\n#define reps(i, n) for(int i = 1, i##_len = (int)(n) ; i <= i##_len ; ++i)\n#define rrep(i, n) for(int i = (int)(n) - 1 ; i >= 0 ; --i)\n#define rreps(i, n) for(int i = (int)(n) ; i > 0 ; --i)\n#define SORT(x) sort((x).begin(), (x).end())\n#define SORT_INV(x) sort((x).rbegin(), (x).rend())\n#define REVERSE(x) reverse((x).begin(), (x).end())\n#define TWINS(x) cout << ((x) ? \"Yay!\" : \":(\") << '\\n'\n\nconstexpr int IINF = (1 << 30) - 1;\nconstexpr long long LLINF = 1LL << 61;\nconstexpr double EPS = 1e-10;\n\nconstexpr int dx4[] = {1, 0, -1, 0}, dy4[] = {0, 1, 0, -1};\nconstexpr int dx8[] = {1, 1, 0, -1, -1, -1, 0, 1}, dy8[] = {0, -1, -1, -1, 0, 1, 1, 1};\n\ntemplate<typename T>\nbool chmax(T& a, T b){\n if(a < b){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate<typename T>\nbool chmin(T& a, T b){\n if(b < a){\n a = b;\n return true;\n }\n return false;\n}\n\ntemplate <long long modulus>\nclass ModInt{\n long long num;\n\n constexpr long long mod(long long x) const noexcept {\n x %= modulus;\n if(x < 0){\n x += modulus;\n }\n return x;\n }\n\n constexpr long long inv(long long x) const noexcept {\n long long y = modulus, u = 1, v = 0;\n while(y){\n long long t = x / y;\n x -= t * y;\n std::swap(x, y);\n u -= t * v;\n std::swap(u, v);\n }\n return mod(u);\n }\n\npublic:\n constexpr ModInt(const long long x = 0) noexcept : num(mod(x)) {}\n\n constexpr long long &value() noexcept { return num; }\n\n constexpr const long long &value() const noexcept { return num; }\n\n constexpr ModInt operator+(const ModInt rhs) const noexcept {\n return ModInt(*this) += rhs;\n }\n\n constexpr ModInt operator-(const ModInt rhs) const noexcept {\n return ModInt(*this) -= rhs;\n }\n\n constexpr ModInt operator*(const ModInt rhs) const noexcept {\n return ModInt(*this) *= rhs;\n }\n\n constexpr ModInt operator/(const ModInt rhs) const noexcept {\n return ModInt(*this) /= rhs;\n }\n\n constexpr ModInt &operator+=(const ModInt rhs) noexcept {\n num += rhs.num;\n if (num >= modulus){\n num -= modulus;\n }\n return *this;\n }\n\n constexpr ModInt &operator-=(const ModInt rhs) noexcept {\n if (num < rhs.num){\n num += modulus;\n }\n num -= rhs.num;\n return *this;\n }\n\n constexpr ModInt &operator*=(const ModInt rhs) noexcept {\n num = num * rhs.num % modulus;\n return *this;\n }\n\n constexpr ModInt &operator/=(const ModInt rhs) noexcept {\n num = num * inv(rhs.num) % modulus;\n return *this;\n }\n\n template<typename T>\n constexpr ModInt operator+(const T rhs) const noexcept {\n return ModInt(*this) += rhs;\n }\n\n template<typename T>\n constexpr ModInt operator-(const T rhs) const noexcept {\n return ModInt(*this) -= rhs;\n }\n\n template<typename T>\n constexpr ModInt operator*(const T rhs) const noexcept {\n return ModInt(*this) *= rhs;\n }\n\n template<typename T>\n constexpr ModInt operator/(const T rhs) const noexcept {\n return ModInt(*this) /= rhs;\n }\n\n template<typename T>\n constexpr ModInt &operator+=(const T rhs) noexcept {\n num = mod(num + rhs);\n return *this;\n }\n\n template<typename T>\n constexpr ModInt &operator-=(const T rhs) noexcept {\n num = mod(num - rhs);\n return *this;\n }\n\n template<typename T>\n constexpr ModInt &operator*=(const T rhs) noexcept {\n num = num * mod(rhs) % modulus;\n return *this;\n }\n\n template<typename T>\n constexpr ModInt &operator/=(const T rhs) noexcept {\n num = num * inv(mod(rhs)) % modulus;\n return *this;\n }\n\n constexpr bool operator<(const ModInt rhs) noexcept {\n return num < rhs.num;\n }\n\n constexpr bool operator==(const ModInt rhs) noexcept {\n return num == rhs.num;\n }\n\n ModInt &operator=(const ModInt rhs) noexcept {\n num = rhs.num;\n return *this;\n }\n\n template<typename T>\n ModInt &operator=(const T rhs) noexcept {\n num = mod(rhs);\n return *this;\n }\n};\n\ntemplate <long long modulus>\nstd::istream &operator>>(std::istream &lhs, ModInt<modulus> &rhs){\n long long val;\n lhs >> val;\n rhs = val;\n return lhs;\n}\n\ntemplate <long long modulus>\nstd::ostream &operator<<(std::ostream &lhs, ModInt<modulus> rhs){\n lhs << rhs.value();\n return lhs;\n}\n\nusing mint = ModInt<1000000007LL>;\n\nstruct BNF{\n int n;\n string e;\n int pos;\n vector<mint> val;\n\n BNF(string e_){\n e = e_;\n n = (int)e.size();\n pos = 0;\n val = expression();\n }\n\n vector<mint> pl(vector<mint> l, vector<mint> r){\n vector<mint> ret(3, 0);\n\n ret[0] = l[0] * r[0] + l[0] * r[1] + l[1] * r[0];\n ret[1] = l[1] * r[1] + l[1] * r[2] + l[2] * r[1];\n ret[2] = l[2] * r[2] + l[2] * r[0] + l[0] * r[2];\n\n return ret;\n }\n\n vector<mint> mi(vector<mint> l, vector<mint> r){\n vector<mint> ret(3, 0);\n\n ret[0] = l[0] * r[0] + l[0] * r[2] + l[2] * r[0];\n ret[1] = l[1] * r[1] + l[1] * r[0] + l[0] * r[1];\n ret[2] = l[2] * r[2] + l[2] * r[1] + l[1] * r[2];\n\n return ret;\n }\n\n vector<mint> ti(vector<mint> l, vector<mint> r){\n vector<mint> ret(3, 0);\n\n ret[0] = l[0] * r[0] + l[1] * r[2] + l[2] * r[1];\n ret[1] = l[1] * r[1] + l[2] * r[0] + l[0] * r[2];\n ret[2] = l[2] * r[2] + l[0] * r[1] + l[1] * r[0];\n\n return ret;\n }\n\n vector<mint> expression(void){\n vector<mint> ret = term();\n\n while(pos < n){\n if(e[pos] == '+'){\n ++pos;\n ret = pl(ret, term());\n continue;\n }else if(e[pos] == '-'){\n ++pos;\n ret = mi(ret, term());\n continue;\n }\n\n return ret;\n }\n\n return ret;\n }\n\n vector<mint> term(void){\n vector<mint> ret = factor();\n\n while(pos < n){\n if(e[pos] == '*'){\n ++pos;\n ret = ti(ret, factor());\n continue;\n }\n\n break;\n }\n\n return ret;\n }\n\n vector<mint> factor(void){\n vector<mint> ret(3, 0);\n\n if(e[pos] == '('){\n ++pos;\n ret = expression();\n\n if(e[pos] == ')'){\n ++pos;\n }\n }else if(e[pos] == 'R'){\n ret[0] = 1;\n ++pos;\n }else if(e[pos] == 'S'){\n ret[1] = 1;\n ++pos;\n }else if(e[pos] == 'P'){\n ret[2] = 1;\n ++pos;\n }else if(e[pos] == '?'){\n ret[0] = 1;\n ret[1] = 1;\n ret[2] = 1;\n ++pos;\n }\n\n return ret;\n }\n};\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n cout << fixed << setprecision(10);\n\n int n;\n string e;\n char a;\n cin >> n >> e >> a;\n\n BNF b(e);\n\n vector<mint> v = b.val;\n\n mint ans;\n if(a == 'R'){\n ans = v[0];\n }else if(a == 'S'){\n ans = v[1];\n }else{\n ans = v[2];\n }\n\n cout << ans << endl;\n\n cout << flush;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 34820, "score_of_the_acc": -0.0874, "final_rank": 2 }, { "submission_id": "aoj_0676_5143142", "code_snippet": "#include <cmath>\n#include <vector>\n#include <iostream>\n#include <iomanip>\n#include <fstream>\n#include <algorithm>\n#include <set>\n#include <queue>\n#include <string>\n#include <map>\n#include <stack>\n#include <climits>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <memory>\n#include <functional>\n#include <cfloat>\n#include <numeric>\n#include <random>\n#include <sstream>\n#include <bitset>\n#include <complex>\n#include <chrono>\n#include <cassert>\n\nusing namespace std;\n\nconstexpr long long int MOD = 1000'000'007;\n\n\nenum class Hand {\n\tRock, Scissor, Paper\n};\nint to_int(const Hand hand) {\n\tswitch (hand) {\n\tcase Hand::Rock: return 0;\n\tcase Hand::Scissor: return 1;\n\tcase Hand::Paper: return 2;\n\tdefault: throw 0;\n\t}\n}\nHand from_int(const int value) {\n\tswitch (value) {\n\tcase 0: return Hand::Rock;\n\tcase 1: return Hand::Scissor;\n\tcase 2: return Hand::Paper;\n\tdefault: throw 0;\n\t}\n}\nHand from_char(const char c) {\n\tswitch (c) {\n\tcase 'R': return Hand::Rock;\n\tcase 'S': return Hand::Scissor;\n\tcase 'P': return Hand::Paper;\n\tdefault: throw 0;\n\t}\n}\nHand winner(const Hand left, const Hand right) {\n\treturn (to_int(right) + 3 - to_int(left)) % 3 == 1 ? left : right;\n}\nHand loser(const Hand left, const Hand right) {\n\treturn (to_int(right) + 3 - to_int(left)) % 3 == 1 ? right : left;\n}\nconstexpr array<Hand, 3> all_hand{ Hand::Rock, Hand::Scissor, Hand::Paper };\n\nclass Token {\npublic:\n\tvirtual ~Token() = default;\n};\nclass Operator : public Token {\npublic:\n\tvirtual Hand calc(const Hand left, const Hand right) const = 0;\n};\nclass Plus final : public Operator {\npublic:\n\tHand calc(const Hand left, const Hand right) const override {\n\t\treturn winner(left, right);\n\t}\n};\nclass Minus final : public Operator {\npublic:\n\tHand calc(const Hand left, const Hand right) const override {\n\t\treturn loser(left, right);\n\t}\n};\nclass Times final : public Operator {\npublic:\n\tHand calc(const Hand left, const Hand right) const override {\n\t\treturn left == right ? left : from_int(3 - to_int(left) - to_int(right));\n\t}\n};\nclass Factor : public Token {\npublic:\n\tvirtual long long int pattern(const Hand hand) const = 0;\n};\nclass Rock : public Factor {\npublic:\n\tlong long int pattern(const Hand hand) const override {\n\t\treturn hand == Hand::Rock ? 1 : 0;\n\t}\n};\nclass Scissors final : public Factor {\npublic:\n\tlong long int pattern(const Hand hand) const override {\n\t\treturn hand == Hand::Scissor ? 1 : 0;\n\t}\n};\nclass Paper final : public Factor {\npublic:\n\tlong long int pattern(const Hand hand) const override {\n\t\treturn hand == Hand::Paper ? 1 : 0;\n\t}\n};\nclass Unknown final : public Factor {\npublic:\n\tlong long int pattern(const Hand hand) const override {\n\t\treturn 1;\n\t}\n};\nclass Expression final : public Factor {\n\tarray<long long int, 3> _pattern;\npublic:\n\tExpression(const Factor* left, const Operator* op, const Factor* right){\n\t\t_pattern.fill(0);\n\t\tfor (const auto l : all_hand) {\n\t\t\tfor (const auto r : all_hand) {\n\t\t\t\t_pattern[to_int(op->calc(l, r))] += left->pattern(l) * right->pattern(r) % MOD;\n\t\t\t}\n\t\t}\n\t\tfor (auto& p : _pattern) {\n\t\t\tp %= MOD;\n\t\t}\n\t}\n\tlong long int pattern(const Hand hand) const override {\n\t\treturn _pattern[to_int(hand)];\n\t}\n};\n\nshared_ptr<Factor> from_token(const vector<shared_ptr<Token>>& token) {\n\tvector<shared_ptr<Token>> stack;\n\tfor (const auto& t : token) {\n\t\tconst auto right = dynamic_cast<Factor*>(t.get());\n\t\tif (!stack.empty() && right) {\n\t\t\tconst auto op = dynamic_pointer_cast<Times>(stack.back());\n\t\t\tif (op) {\n\t\t\t\tstack.pop_back();\n\t\t\t\tconst auto left = stack.back(); stack.pop_back();\n\t\t\t\tstack.emplace_back(make_shared<Expression>(dynamic_cast<Factor*>(left.get()), op.get(), right));\n\t\t\t}\n\t\t\telse {\n\t\t\t\tstack.push_back(t);\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tstack.push_back(t);\n\t\t}\n\t}\n\tauto left = stack.front();\n\tfor (auto i = 1; i < stack.size(); i += 2) {\n\t\tleft = make_shared<Expression>(dynamic_cast<Factor*>(left.get()), dynamic_cast<Operator*>(stack[i].get()), dynamic_cast<Factor*>(stack[i + 1].get()));\n\t}\n\treturn dynamic_pointer_cast<Factor>(left);\n}\nshared_ptr<Factor> parse_expression(const string& expression) {\n\tvector<vector<shared_ptr<Token>>> stack(1);\n\tfor (const auto c : expression) {\n\t\tswitch (c) {\n\t\tcase 'R': stack.back().push_back(make_shared<Rock>()); break;\n\t\tcase 'S': stack.back().push_back(make_shared<Scissors>()); break;\n\t\tcase 'P': stack.back().push_back(make_shared<Paper>()); break;\n\t\tcase '?': stack.back().push_back(make_shared<Unknown>()); break;\n\t\tcase '+': stack.back().push_back(make_shared<Plus>()); break;\n\t\tcase '-': stack.back().push_back(make_shared<Minus>()); break;\n\t\tcase '*': stack.back().push_back(make_shared<Times>()); break;\n\t\tcase '(': stack.emplace_back(); break;\n\t\tcase ')': {\n\t\t\tconst auto last = from_token(stack.back());\n\t\t\tstack.pop_back();\n\t\t\tstack.back().push_back(last);\n\t\t}\n\t\t\t\tbreak;\n\t\tdefault: throw 0;\n\t\t}\n\t}\n\tassert(stack.size() == 1);\n\treturn from_token(stack.front());\n}\nint main() {\n\tint n; cin >> n;\n\tstring e; cin >> e;\n\tchar a; cin >> a;\n\tconst auto target = from_char(a);\n\tconst auto expression = parse_expression(e);\n\tcout << expression->pattern(target) << '\\n';\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 20728, "score_of_the_acc": -0.2857, "final_rank": 4 }, { "submission_id": "aoj_0676_5087351", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 200005\n\nenum Type{\n\tR,\n\tS,\n\tP,\n};\n\n\nstruct Info{\n\n\tll num[3];\n};\n\n\nchar line[SIZE];\nInfo calc_E(int left,int right,int DEPTH);\nInfo calc_T(int left,int right,int DEPTH);\nInfo calc_F(int left,int right,int DEPTH);\nInfo calc_NUM(int left,int right,int DEPTH);\n\nint CLOSE_POS[SIZE];\n\nvector<int> PLUS_MINUS[SIZE/2];\nvector<int> MULT[SIZE/2];\n\n\nInfo calc_E(int left,int right,int DEPTH){\n\n\tqueue<int> Q;\n\n\tif(PLUS_MINUS[DEPTH].size() > 0){\n\n\t\tint L = lower_bound(PLUS_MINUS[DEPTH].begin(),PLUS_MINUS[DEPTH].end(),left)-PLUS_MINUS[DEPTH].begin();\n\t\tint R = upper_bound(PLUS_MINUS[DEPTH].begin(),PLUS_MINUS[DEPTH].end(),right)-PLUS_MINUS[DEPTH].begin();\n\t\tR--;\n\n\t\tif(L <= R){\n\n\t\t\tfor(int i = L; i <= R; i++){\n\n\t\t\t\tQ.push(PLUS_MINUS[DEPTH][i]);\n\t\t\t}\n\t\t}\n\t}\n\n\n\n\tif(Q.empty()){ //深さDEPTHの+-がない\n\t\treturn calc_T(left,right,DEPTH);\n\t}\n\n\tInfo tmp = calc_E(left,Q.front()-1,DEPTH),tmp_right;\n\n\n\t/*for(int i = 0; i < 3; i++){\n\n\t\tprintf(\"tmp.num[%d]:%lld\\n\",i,tmp.num[i]);\n\t}*/\n\n\twhile(!Q.empty()){\n\t\tint loc = Q.front();\n\t\tQ.pop();\n\n\t\tif(Q.empty()){\n\t\t\ttmp_right = calc_T(loc+1,right,DEPTH);\n\t\t}else{\n\t\t\ttmp_right = calc_T(loc+1,Q.front()-1,DEPTH);\n\t\t}\n\n\t\t/*for(int i = 0; i < 3; i++){\n\n\t\t\tprintf(\"tmp_right.num[%d]:%lld\\n\",i,tmp_right.num[i]);\n\t\t}*/\n\n\t\tInfo next_tmp;\n\n\n\t\tif(line[loc] == '+'){\n\n\t\t\tnext_tmp.num[R] = (tmp.num[R]*(tmp_right.num[R]+tmp_right.num[S])+tmp.num[S]*tmp_right.num[R])%MOD;\n\t\t\tnext_tmp.num[S] = (tmp.num[S]*(tmp_right.num[S]+tmp_right.num[P])+tmp.num[P]*tmp_right.num[S])%MOD;\n\t\t\tnext_tmp.num[P] = (tmp.num[P]*(tmp_right.num[R]+tmp_right.num[P])+tmp.num[R]*tmp_right.num[P])%MOD;\n\n\t\t}else{ //'-'\n\n\t\t\tnext_tmp.num[R] = (tmp.num[R]*(tmp_right.num[R]+tmp_right.num[P])+tmp.num[P]*tmp_right.num[R])%MOD;\n\t\t\tnext_tmp.num[S] = (tmp.num[S]*(tmp_right.num[R]+tmp_right.num[S])+tmp.num[R]*tmp_right.num[S])%MOD;\n\t\t\tnext_tmp.num[P] = (tmp.num[P]*(tmp_right.num[S]+tmp_right.num[P])+tmp.num[S]*tmp_right.num[P])%MOD;\n\t\t}\n\n\t\ttmp = next_tmp;\n\t}\n\n\treturn tmp;\n}\n\nInfo calc_T(int left,int right,int DEPTH){\n\n\tqueue<int> Q;\n\n\t//深さDEPTHの、*,/を探す\n\tif(MULT[DEPTH].size() > 0){\n\n\t\tint L = lower_bound(MULT[DEPTH].begin(),MULT[DEPTH].end(),left)-MULT[DEPTH].begin();\n\t\tint R = upper_bound(MULT[DEPTH].begin(),MULT[DEPTH].end(),right)-MULT[DEPTH].begin();\n\t\tR--;\n\n\t\tif(L <= R){\n\n\t\t\tfor(int i = L; i <= R; i++){\n\n\t\t\t\tQ.push(MULT[DEPTH][i]);\n\t\t\t}\n\n\t\t}\n\t}\n\n\tif(Q.empty()){ //深さDEPTHの*がない\n\t\treturn calc_F(left,right,DEPTH);\n\t}\n\n\tInfo tmp = calc_T(left,Q.front()-1,DEPTH),tmp_right;\n\n\twhile(!Q.empty()){\n\t\tint loc = Q.front();\n\t\tQ.pop();\n\n\t\tif(Q.empty()){\n\t\t\ttmp_right = calc_F(loc+1,right,DEPTH);\n\t\t}else{\n\t\t\ttmp_right = calc_F(loc+1,Q.front()-1,DEPTH);\n\t\t}\n\n\t\tInfo next_tmp;\n\n\t\tif(line[loc] == '*'){\n\n\t\t\tnext_tmp.num[R] = (tmp.num[R]*tmp_right.num[R]+tmp.num[S]*tmp_right.num[P]+tmp.num[P]*tmp_right.num[S])%MOD;\n\t\t\tnext_tmp.num[S] = (tmp.num[R]*tmp_right.num[P]+tmp.num[S]*tmp_right.num[S]+tmp.num[P]*tmp_right.num[R])%MOD;\n\t\t\tnext_tmp.num[P] = (tmp.num[R]*tmp_right.num[S]+tmp.num[S]*tmp_right.num[R]+tmp.num[P]*tmp_right.num[P])%MOD;\n\t\t}\n\t\ttmp = next_tmp;\n\t}\n\treturn tmp;\n}\n\nInfo calc_F(int left,int right,int DEPTH){\n\n\tif(line[left] != '('){\n\n\t\treturn calc_NUM(left,right,DEPTH);\n\n\t}else{ // line[left] == '('\n\n\t\tint close_pos = CLOSE_POS[left];\n\n\t\treturn calc_E(left+1,close_pos-1,DEPTH+1);\n\t}\n}\n\nInfo calc_NUM(int left,int right,int DEPTH){\n\n\tInfo ret;\n\tfor(int i = 0; i < 3; i++){\n\n\t\tret.num[i] = 0;\n\t}\n\n\tswitch(line[left]){\n\tcase 'R':\n\t\tret.num[R]++;\n\t\tbreak;\n\tcase 'S':\n\t\tret.num[S]++;\n\t\tbreak;\n\tcase 'P':\n\t\tret.num[P]++;\n\t\tbreak;\n\tcase '?':\n\t\tret.num[R]++;\n\t\tret.num[S]++;\n\t\tret.num[P]++;\n\t\tbreak;\n\t}\n\n\n\treturn ret;\n}\n\n\nint main(){\n\n\tint LEN;\n\n\tscanf(\"%d\",&LEN);\n\tscanf(\"%s\",line);\n\n\tchar A[2];\n\tscanf(\"%s\",A);\n\n\tint depth = 0;\n\n\t//深さと演算子を前計算\n\tfor(int i = 0; i < LEN; ){\n\t\tif(line[i] == '(')depth++;\n\t\telse if(line[i] == ')')depth--;\n\n\t\tif(line[i] == '+' || line[i] == '-'){\n\n\t\t\tPLUS_MINUS[depth].push_back(i);\n\n\t\t}else if(line[i] == '*'){\n\n\t\t\tMULT[depth].push_back(i);\n\t\t}\n\n\t\ti++;\n\t}\n\n\t//開きかっこに対する閉じかっこを前計算\n\tstack<int> ST;\n\tfor(int i = 0; i < LEN; i++){\n\t\tif(line[i] == '('){\n\n\t\t\tST.push(i);\n\t\t}else if(line[i] == ')'){\n\n\t\t\tCLOSE_POS[ST.top()] = i;\n\t\t\tST.pop();\n\t\t}\n\t}\n\n\n\tInfo ret = calc_E(0,LEN-1,0);\n\n\tswitch(A[0]){\n\n\tcase 'R':\n\t\tprintf(\"%lld\\n\",ret.num[R]);\n\t\tbreak;\n\n\tcase 'S':\n\t\tprintf(\"%lld\\n\",ret.num[S]);\n\t\tbreak;\n\n\tcase 'P':\n\t\tprintf(\"%lld\\n\",ret.num[P]);\n\t\tbreak;\n\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 181968, "score_of_the_acc": -2, "final_rank": 5 } ]
aoj_0661_cpp
コイン集め(Coin Collecting) JOI 氏のコレクションルームには非常に大きな机があり,その上には何枚もの貴重なコインがある.机の掃除をするために,JOI 氏はコインを整理して並べることにした. 机は2 000 000 001 $\times$ 2 000 000 001 のマス目になっている.列には左から順に-1 000 000 000 から1 000 000 000までの番号がつけられており,行には下から順に-1 000 000 000 から1 000 000 000 までの番号がつけられている.列の番号が$x$,行の番号が$y$ であるマスを($x, y$) で表すことにする. コインは$2N$ 枚あり,現在,$i$ 番目($1 \leq i \leq 2N$) のコインはマス($X_i, Y_i$) に置かれている.JOI 氏の目標は,$1 \leq x \leq N$ かつ$1 \leq y \leq 2$ を満たす($x, y$) で表される$2N$ 個のマスに,それぞれコインが1 枚ずつ置かれている状態にすることである.コインを傷つけないようにするため,「コインを1 枚選び,それが置かれているマスと辺で隣り合ったマスのいずれかに,そのコインを移動させる」という操作のみができる.途中,複数のコインが同じマスに置かれていてもよい.JOI 氏は,できるだけ少ない回数の操作で目標を達成したい. コインの枚数と,現在コインが置かれているマスが与えられたとき,目標を達成するために必要な操作回数の最小値を求めるプログラムを作成せよ. 入力 入力は以下の形式で標準入力から与えられる. $N$ $X_1$ $Y_1$ : $X_{2N}$ $Y_{2N}$ 出力 標準出力に,目標を達成するために必要な操作回数の最小値を1 行で出力せよ. 制約 $ 1 \leq N \leq 100 000$. $ -1 000 000 000 \leq X_i \leq 1 000 000 000 (1 \leq i \leq 2N)$. $ -1 000 000 000 \leq Y_i \leq 1 000 000 000 (1 \leq i \leq 2N)$. 入出力例 入力例1 3 0 0 0 4 4 0 2 1 2 5 -1 1 出力例1 15 この入力例では,6 個のコインが下図のように置かれている.太枠で示した位置にコインを集めるのが目標である. 例えば,コインを以下のように移動させると,15 回の操作で目標を達成できる: 1 番目のコイン:(0, 0) → (1, 0) → (1, 1) → (1, 2) 2 番目のコイン:(0, 4) → (1, 4) → (1, 3) → (2, 3) → (3, 3) → (3, 2) 3 番目のコイン:(4, 0) → (4, 1) → (3, 1) 5 番目のコイン:(2, 5) → (2, 4) → (2, 3) → (2, 2) 6 番目のコイン:(-1, 1) → (0, 1) → (1, 1) 14 回以下の操作で目標を達成することはできないので,15 を出力する. 入力例2 4 2 1 2 1 2 1 3 1 3 1 3 1 3 1 3 1 出力例2 9 同じマスに複数のコインが置かれているかもしれない. 入力例3 5 1000000000 1000000000 -1000000000 1000000000 -1000000000 -1000000000 1000000000 -1000000000 -1 -5 -2 2 2 8 4 7 -2 5 7 3 出力例3 8000000029 情報オリンピック日本委員会作 『第18 回日本情報オリンピック(JOI 2018/2019) 本選』
[ { "submission_id": "aoj_0661_9476750", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <algorithm>\n#include <cstdio>\n\ntypedef long long int ll;\nusing namespace std;\n\n#define SIZE 100005\n\nll N;\nll table[3][SIZE];\n\nint main() {\n scanf(\"%lld\", &N);\n\n for (ll y = 1; y <= 2; y++) {\n fill(table[y] + 1, table[y] + N + 1, 0);\n }\n\n ll X, Y;\n ll ans = 0;\n\n for (ll i = 0; i < 2 * N; i++) {\n scanf(\"%lld %lld\", &X, &Y);\n\n if (X < 1) { // 左側\n if (Y > 2) { // 上\n table[2][1]++;\n ans += abs(X - 1) + abs(Y - 2);\n } else if (Y < 1) { // 下\n table[1][1]++;\n ans += abs(X - 1) + abs(Y - 1);\n } else { // 範囲内\n table[Y][1]++;\n ans += abs(X - 1);\n }\n } else if (X > N) { // 右側\n if (Y > 2) { // 上\n table[2][N]++;\n ans += abs(X - N) + abs(Y - 2);\n } else if (Y < 1) { // 下\n table[1][N]++;\n ans += abs(X - N) + abs(Y - 1);\n } else { // 範囲内\n table[Y][N]++;\n ans += abs(X - N);\n }\n } else { // 範囲内\n if (Y > 2) { // 上\n table[2][X]++;\n ans += abs(Y - 2);\n } else if (Y < 1) { // 下\n table[1][X]++;\n ans += abs(Y - 1);\n } else { // 範囲内\n table[Y][X]++;\n }\n }\n }\n\n ll d1 = 0, d2 = 0;\n for (int x = 1; x <= N; x++) {\n d1 += table[1][x] - 1;\n d2 += table[2][x] - 1;\n if (d1 > 0 && d2 < 0) {\n ll tmp = min(d1, -d2);\n ans += tmp;\n d1 -= tmp;\n d2 += tmp;\n }\n if (d1 < 0 && d2 > 0) {\n ll tmp = min(-d1, d2);\n ans += tmp;\n d1 += tmp;\n d2 -= tmp;\n }\n ans += abs(d1) + abs(d2);\n }\n\n printf(\"%lld\\n\", ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5132, "score_of_the_acc": -0.3224, "final_rank": 3 }, { "submission_id": "aoj_0661_4696895", "code_snippet": "#include<bits/stdc++.h>\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 1000000000000000000\n#define MOD 1000000007\n#define EPS 0.000000001\nusing namespace std;\n\n\n\n#define SIZE 100005\n\nll N;\nll table[3][SIZE];\n\nint main(){\n\n\tscanf(\"%lld\",&N);\n\n\tfor(ll y = 1; y <= 2; y++){\n\t\tfor(ll x = 1; x <= N; x++){\n\n\t\t\ttable[y][x] = 0;\n\t\t}\n\t}\n\n\tll X,Y;\n\n\tll ans = 0;\n\n\tfor(ll i = 0; i < 2*N; i++){\n\n\t\tscanf(\"%lld %lld\",&X,&Y);\n\n\t\tif(X < 1){ //板の左側\n\n\t\t\tif(Y > 2){ //板より上\n\n\t\t\t\ttable[2][1]++;\n\t\t\t\tans += abs(X-1)+abs(Y-2);\n\n\t\t\t}else if(Y < 1){ //板より下\n\n\t\t\t\ttable[1][1]++;\n\t\t\t\tans += abs(X-1)+abs(Y-1);\n\n\t\t\t}else{ //板の範囲\n\n\t\t\t\tif(Y == 1){\n\n\t\t\t\t\ttable[1][1]++;\n\t\t\t\t\tans += abs(X-1);\n\n\t\t\t\t}else{ //Y==2\n\n\t\t\t\t\ttable[2][1]++;\n\t\t\t\t\tans += abs(X-1);\n\t\t\t\t}\n\t\t\t}\n\n\t\t}else if(X > N){ //板の右側\n\n\t\t\tif(Y > 2){ //板より上\n\n\n\t\t\t\ttable[2][N]++;\n\t\t\t\tans += abs(X-N)+abs(Y-2);\n\n\t\t\t}else if(Y < 1){ //板より下\n\n\t\t\t\ttable[1][N]++;\n\t\t\t\tans += abs(X-N)+abs(Y-1);\n\n\t\t\t}else{ //板の範囲\n\n\t\t\t\tif(Y == 1){\n\n\t\t\t\t\ttable[1][N]++;\n\t\t\t\t\tans += abs(X-N);\n\n\t\t\t\t}else{ //Y==2\n\n\t\t\t\t\ttable[2][N]++;\n\t\t\t\t\tans += abs(X-N);\n\t\t\t\t}\n\t\t\t}\n\n\n\t\t}else{ //板の範囲\n\n\n\t\t\tif(Y > 2){ //板より上\n\n\n\t\t\t\ttable[2][X]++;\n\t\t\t\tans += abs(Y-2);\n\n\t\t\t}else if(Y < 1){ //板より下\n\n\t\t\t\ttable[1][X]++;\n\t\t\t\tans += abs(Y-1);\n\n\t\t\t}else{ //板の範囲\n\n\t\t\t\ttable[Y][X]++;\n\t\t\t}\n\t\t}\n\t}\n\n\tll d1 = 0,d2 = 0;\n\n\tfor(int x = 1; x <= N; x++){\n\n\t\td1 += table[1][x]-1;\n\t\td2 += table[2][x]-1;\n\t\tif(d1 > 0 && d2 < 0){\n\n\t\t\tint tmp = min(d1,-d2);\n\t\t\tans += tmp;\n\n\t\t\td1 -= tmp;\n\t\t\td2 += tmp;\n\t\t}\n\t\tif(d1 < 0 && d2 > 0){\n\n\t\t\tint tmp = min(-d1,d2);\n\t\t\tans += tmp;\n\t\t\td1 += tmp;\n\t\t\td2 -= tmp;\n\t\t}\n\t\tans += abs(d1)+abs(d2);\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4792, "score_of_the_acc": -0.4421, "final_rank": 6 }, { "submission_id": "aoj_0661_4659728", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing UL = unsigned int;\nusing ULL = unsigned long long;\nusing LL = long long;\n#define rep(i,n) for(UL i=0; i<(n); i++)\n\nUL N;\nLL C[100001][2]={};\nLL ans=0;\n\nint main(){\n scanf(\"%u\",&N);\n rep(i,N+N){\n int x,y; scanf(\"%d%d\",&x,&y);\n if(x<1){ ans += 1-x; x=1; }\n if(x>N){ ans += x-N; x=N; }\n if(y<1){ ans += 1-y; y=1; }\n if(y>2){ ans += y-2; y=2; }\n C[x-1][y-1]++;\n }\n rep(x,N){\n C[x][0]--; C[x][1]--;\n if(C[x][0]<0 && C[x][1]>0){\n LL c=min(-C[x][0],C[x][1]);\n ans+=c;\n C[x][0]+=c; C[x][1]-=c;\n }\n if(C[x][0]>0 && C[x][1]<0){\n LL c=min(C[x][0],-C[x][1]);\n ans+=c;\n C[x][0]-=c; C[x][1]+=c;\n }\n rep(y,2){\n if(C[x][y]>0){\n LL c=C[x][y];\n ans+=c;\n C[x+1][y]+=c; C[x][y]-=c;\n }\n if(C[x][y]<0){\n LL c=-C[x][y];\n ans+=c;\n C[x+1][y]-=c; C[x][y]+=c;\n }\n }\n }\n printf(\"%lld\\n\",ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4776, "score_of_the_acc": -0.2732, "final_rank": 1 }, { "submission_id": "aoj_0661_4413190", "code_snippet": "#include <bits/stdc++.h>\n\n#define LOG(FMT...) fprintf(stderr, FMT)\n\nusing namespace std;\n\ntypedef long long ll;\n\nconst int N = 100010;\n\nint cnt[N][2];\n\nvoid solve() {\n memset(cnt, 0, sizeof(cnt));\n ll ans = 0;\n int n;\n scanf(\"%d\", &n);\n for (int rep = 0; rep < n * 2; ++rep) {\n int x, y;\n scanf(\"%d%d\", &x, &y);\n if (y < 1) {\n ans += 1 - y;\n y = 1;\n }\n if (y > 2) {\n ans += y - 2;\n y = 2;\n }\n if (x < 1) {\n ans += 1 - x;\n x = 1;\n }\n if (x > n) {\n ans += x - n;\n x = n;\n }\n ++cnt[x][y - 1];\n }\n for (int i = 1; i <= n; ++i) {\n#define A cnt[i][0]\n#define B cnt[i][1]\n --A;\n --B;\n if (A > 0 && B > 0) {\n ans += A + B;\n cnt[i + 1][0] += A;\n cnt[i + 1][1] += B;\n } else if (A <= 0 && B <= 0) {\n ans -= A + B;\n cnt[i + 1][0] += A;\n cnt[i + 1][1] += B;\n } else if (A <= 0 && B > 0) {\n if (-A > B) {\n ans += B;\n A += B;\n ans += abs(A);\n cnt[i + 1][0] += A;\n } else {\n ans += -A;\n B += A;\n ans += abs(B);\n cnt[i + 1][1] += B;\n }\n } else if (A > 0 && B <= 0) {\n if (A > -B) {\n ans += -B;\n A += B;\n ans += abs(A);\n cnt[i + 1][0] += A;\n } else {\n ans += A;\n B += A;\n ans += abs(B);\n cnt[i + 1][1] += B;\n }\n }\n }\n printf(\"%lld\\n\", ans);\n}\n\nint main() {\n solve();\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4004, "score_of_the_acc": -0.3333, "final_rank": 4 }, { "submission_id": "aoj_0661_4267309", "code_snippet": "#include <iostream>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n#pragma warning (disable: 4996)\n\nlong long N, X[1 << 18], Y[1 << 18], S[1 << 18], A[1 << 18][2], V1, V2;\nlong long FinalAns = 0;\n\nint main() {\n\tscanf(\"%lld\", &N);\n\tfor (int i = 1; i <= 2 * N; i++) {\n\t\tscanf(\"%lld%lld\", &X[i], &Y[i]);\n\t\tFinalAns += abs(X[i] - max(1LL, min(N, X[i])));\n\t\tFinalAns += abs(Y[i] - max(1LL, min(2LL, Y[i])));\n\t\tX[i] = max(1LL, min(N, X[i]));\n\t\tY[i] = max(1LL, min(2LL, Y[i]));\n\t\tS[X[i]]++; A[X[i]][Y[i]]++;\n\t}\n\tfor (int i = 1; i <= N; i++) S[i] += S[i - 1];\n\tfor (int i = 2; i <= N; i++) FinalAns += abs(2LL * (i - 1LL) - S[i - 1]);\n\n\tlong long D1 = 0, D2 = 0;\n\tfor (int i = 1; i <= N; i++) {\n\t\tD1 += (A[i][1] - 1LL);\n\t\tD2 += (A[i][2] - 1LL);\n\t\tif (D1 > 0LL && 0LL > D2) {\n\t\t\tlong long K = min(D1, -D2);\n\t\t\tD1 -= K; D2 += K;\n\t\t\tFinalAns += K;\n\t\t}\n\t\tif (D1 < 0LL && 0LL < D2) {\n\t\t\tlong long K = min(-D1, D2);\n\t\t\tD1 += K; D2 -= K;\n\t\t\tFinalAns += K;\n\t\t}\n\t}\n\tcout << FinalAns << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 8716, "score_of_the_acc": -0.9838, "final_rank": 8 }, { "submission_id": "aoj_0661_4192351", "code_snippet": "#include<cstdio>\n#include<vector>\n#include<algorithm>\n#include<cmath>\nusing namespace std;\ntypedef long long int ll;\nstatic const int MAX_N = 100000;\nstatic const ll INF = 1LL << 60;\nstruct Point{ll x, y;};\n\nint N;\nPoint p[2 * MAX_N];\n\nbool comp(const Point &a, const Point &b){\n\treturn a.x == b.x ? a.y < b.y : a.x < b.x;\n}\n\nll subtask1(){\n\tvector<ll> memo(1 << (2 * N), INF);\n\tmemo[0] = 0;\n\tfor(int i = 0; i < (1 << (2 * N)); i++){\n\t\tint cnt = 0;\n\t\tfor(int j = 0; j < 2 * N; j++){\n\t\t\tif(i & (1 << j)) cnt++;\n\t\t}\n\t\tfor(int j = 0; j < 2 * N; j++){\n\t\t\tif(!(i & (1 << j))){\n\t\t\t\tif(j < N) memo[i + (1 << j)] = min(memo[i + (1 << j)], memo[i] + abs(1 + j - p[cnt].x) + abs(1 - p[cnt].y));\n\t\t\t\telse memo[i + (1 << j)] = min(memo[i + (1 << j)], memo[i] + abs(1 + (j - N) - p[cnt].x) + abs(2 - p[cnt].y));\n\t\t\t}\n\t\t}\n\t}\n\treturn memo[(1 << (2 * N)) - 1];\n}\n\nll subtask2(){\n\tvector<vector<ll> > memo(N + 1, vector<ll>(N + 1, INF));\n\tsort(p, p + 2 * N, comp);\n\tmemo[0][0] = 0;\n\tfor(int i = 0; i <= N; i++){\n\t\tfor(int j = 0; j <= N; j++){\n\t\t\tif(i + 1 <= N) memo[i + 1][j] = min(memo[i + 1][j], memo[i][j] + abs(1 + i - p[i + j].x) + abs(1 - p[i + j].y));\n\t\t\tif(j + 1 <= N) memo[i][j + 1] = min(memo[i][j + 1], memo[i][j] + abs(1 + j - p[i + j].x) + abs(2 - p[i + j].y));\n\t\t}\n\t}\n\treturn memo[N][N];\n}\n\nll subtask3(){\n\tll ret = 0;\n\tint cnt = 0, cnt2 = 0;\n\tvector<int> num(N, 0);\n\tfor(int i = 0; i < 2 * N; i++){\n\t\tif(p[i].x <= 1){\n\t\t\tret += 1 - p[i].x;\n\t\t\tnum[0]++;\n\t\t}else if(p[i].x >= N){\n\t\t\tret += p[i].x - N;\n\t\t\tnum[N - 1]++;\n\t\t}else{\n\t\t\tnum[p[i].x - 1]++;\n\t\t}\n\t\tif(p[i].y <= 1){\n\t\t\tret += 1 - p[i].y;\n\t\t\tcnt++;\n\t\t}else if(p[i].y >= 2){\n\t\t\tret += p[i].y - 2;\n\t\t\tcnt2++;\n\t\t}\n\t}\n\tret += abs(cnt - cnt2) / 2;\n\tsort(p, p + 2 * N, comp);\n\tint num2 = 0;\n\tfor(int i = 0; i < N; i++){\n\t\tnum2 += num[i];\n\t\tnum2 -= 2;\n\t\tret += abs(num2);\n\t}\n\treturn ret;\n}\n\nint main(){\n\tscanf(\"%d\", &N);\n\tfor(int i = 0; i < 2 * N; i++) scanf(\"%lld %lld\", &p[i].x, &p[i].y);\n\tif(N <= 10) printf(\"%lld\\n\", subtask1());\n\telse if(N <= 1000) printf(\"%lld\\n\", subtask2());\n\telse printf(\"%lld\\n\", subtask3());\n\treturn 0;\n}", "accuracy": 0.6509433962264151, "time_ms": 70, "memory_kb": 10572, "score_of_the_acc": -1.9067, "final_rank": 9 }, { "submission_id": "aoj_0661_3988398", "code_snippet": "#include <bits/stdc++.h>\n \n// #include <boost/multiprecision/cpp_int.hpp>\n #define int long long\n #define inf 1000000007\n #define pa pair<int,int>\n #define ll long long\n #define pal pair<double,double>\n #define ppap pair<pa,int>\n #define PI 3.14159265358979323846\n #define paa pair<int,char>\n #define mp make_pair\n #define pb push_back\n #define EPS (1e-8)\n \n int dx[8]={0,1,0,-1,1,1,-1,-1};\n int dy[8]={1,0,-1,0,-1,1,1,-1};\n using namespace std;\n \t\t\tclass pa3{\n \tpublic:\n \tint x;\n \t\t\t\tint y,z;\n \tpa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}\n \tbool operator < (const pa3 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\t return z<p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \t\t\t\tbool operator > (const pa3 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\t return z>p.z;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa3 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z;\n \t}\n \t\tbool operator != (const pa3 &p) const{\n \t\t\treturn !( x==p.x && y==p.y && z==p.z);\n \t}\n \n };\n \n class pa4{\n \tpublic:\n \tint x;\n \tint y,z,w;\n \tpa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}\n \tbool operator < (const pa4 &p) const{\n \t\tif(x!=p.x) return x<p.x;\n \t\tif(y!=p.y) return y<p.y;\n \t\tif(z!=p.z)return z<p.z;\n \t\treturn w<p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator > (const pa4 &p) const{\n \t\tif(x!=p.x) return x>p.x;\n \t\tif(y!=p.y) return y>p.y;\n \t\tif(z!=p.z)return z>p.z;\n \t\treturn w>p.w;\n \t\t//return x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa4 &p) const{\n \t\treturn x==p.x && y==p.y && z==p.z &&w==p.w;\n \t}\n \t\t\n \n };\n class pa2{\n \tpublic:\n \tint x,y;\n \tpa2(int x=0,int y=0):x(x),y(y) {}\n \tpa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}\n \tpa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}\n \tbool operator < (const pa2 &p) const{\n \t\treturn y != p.y ? y<p.y: x<p.x;\n \t}\n \tbool operator > (const pa2 &p) const{\n \t\treturn x != p.x ? x<p.x: y<p.y;\n \t}\n \tbool operator == (const pa2 &p) const{\n \t\treturn abs(x-p.x)==0 && abs(y-p.y)==0;\n \t}\n \tbool operator != (const pa2 &p) const{\n \t\treturn !(abs(x-p.x)==0 && abs(y-p.y)==0);\n \t}\n \t\t\n \n };\n \n \n \n string itos( int i ) {\n ostringstream s ;\n s << i ;\n return s.str() ;\n }\n \n int gcd(int v,int b){\n \tif(v==0) return b;\n \tif(b==0) return v;\n \tif(v>b) return gcd(b,v);\n \tif(v==b) return b;\n \tif(b%v==0) return v;\n \treturn gcd(v,b%v);\n }\n \n \n int mod;\nint extgcd(int a, int b, int &x, int &y) {\n if (b == 0) {\n x = 1;\n y = 0;\n return a;\n }\n int d = extgcd(b, a%b, y, x);\n y -= a/b * x;\n return d;\n}\npa operator+(const pa & l,const pa & r) { \n return {l.first+r.first,l.second+r.second}; \n} \npa operator-(const pa & l,const pa & r) { \n return {l.first-r.first,l.second-r.second}; \n} \n \n int pr[10000100];\n int inv[10000010];\n \n int beki(int wa,int rr,int warukazu){\n \tif(rr==0) return 1%warukazu;\n \tif(rr==1) return wa%warukazu;\n \twa%=warukazu;\n \tif(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;\n \tll zx=beki(wa,rr/2,warukazu);\n \treturn (zx*zx)%warukazu;\n }\n \n \n \t\t\tint comb(int nn,int rr){\n \t\t\t\tif(rr<0 || rr>nn || nn<0) return 0;\n \t\t\t\tint r=pr[nn]*inv[rr];\n \t\t\t\tr%=mod;\n \t\t\t\tr*=inv[nn-rr];\n \t\t\t\tr%=mod;\n \t\t\t\treturn r;\n \t\t\t}\n \n void gya(int ert){\n \tpr[0]=1;\n \tfor(int i=1;i<=ert;i++){\n \t\tpr[i]=(pr[i-1]*i)%mod;\n \t}\n \t\tinv[ert]=beki(pr[ert],mod-2,mod);\n \tfor(int i=ert-1;i>=0;i--){\n \t\tinv[i]=inv[i+1]*(i+1)%mod;\n \t}\n }\n \n // cin.tie(0);\n \t\t//\tios::sync_with_stdio(false);\n \t\t\t//priority_queue<pa3,vector<pa3>,greater<pa3>> pq; \n //sort(ve.begin(),ve.end(),greater<int>());\n // mt19937(clock_per_sec);\n // mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()) ;\n \n\nint memo[200020][2]={};\n\nsigned main(){\n\t\n\t\n cin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tint n;\n\tcin>>n;\n\tint ans=0;\n\tvector<pa>ve(n);\n\t\n\tfor(int i=0;i<2*n;i++){\n\t\tint x,y;\n\t\tcin>>x>>y;\n\t\tif(x<=0){\n\t\t\tans+=1-x;\n\t\t\tx=1;\n\t\t}\n\t\tif(x>n){\n\t\t\tans+=x-n;\n\t\t\tx=n;\n\t\t}\n\t\tif(y<=0){\n\t\t\tans+=1-y;\n\t\t\ty=1;\n\t\t}\n\t\tif(y>2){\n\t\t\tans+=y-2;\n\t\t\ty=2;\n\t\t}\n\t\tmemo[x][y]++;\n\t//\tcout<<x<<\" \"<<y<<endl;\n\t}\n\t//cout<<ans<<endl;\n\tint X=0,Y=0;\n\tfor(int i=1;i<=n;i++){\n\t\n\t\tans+=abs(X)+abs(Y);\n\t\tX+=memo[i][1];\n\t\tY+=memo[i][2];\n\t\tX--,Y--;\n\t//\tcout<<X<<\" \"<<Y<<endl;\n\t\tif(X>0 && Y<0){\n\t\t\tint T=min(X,-Y);\n\t\t\tans+=T;\n\t\t\tX-=T;\n\t\t\tY+=T;\n\t\t}\n\t\tif(Y>0 && X<0){\n\t\t\tint T=min(-X,Y);\n\t\t\tans+=T;\n\t\t\tX+=T;\n\t\t\tY-=T;\t\n\t\t}\n\t}\ncout<<ans<<endl;\n\t\n\treturn 0;\n\t\n\n \n }", "accuracy": 1, "time_ms": 20, "memory_kb": 6016, "score_of_the_acc": -0.4444, "final_rank": 7 }, { "submission_id": "aoj_0661_3839252", "code_snippet": "#include<bits/stdc++.h>\n#define maxn 100005\n#define int long long\nusing namespace std;\nint cnt[maxn][2];\nint32_t main() {\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\tint n;\n\tcin >> n;\n\t\n\tint ans = 0;\n\tfor(int i=1;i<=2*n;i++) {\n\t\tint x,y;\n\t\tcin >> x >> y;\n\n\t\tint nx = x;\n\t\tif(x<1)\n\t\t\tans += 1-x , nx = 1;\n\t\telse if(x>n)\n\t\t\tans += x-n , nx = n;\n\t\t\n\t\tint ny = y-1;\n\t\tif(y<1)\n\t\t\tans += 1-y , ny = 0;\n\t\telse if(y>2)\n\t\t\tans += y-2 , ny = 1;\n\t\t\t\n\t\tcnt[nx][ny] ++;\n\t}\n\t\n\tfor(int i=1;i<=n;i++) {\n\t\tint y[] = {0,1};\n\t\tif(cnt[i][0] < cnt[i][1])\tswap(y[0],y[1]);\n\t\tint need = 1 - cnt[i][y[0]];\n\t\tans += abs(need);\n\t\tif(-need > 0 && cnt[i][y[1]] < 1) {\n\t\t\tint tem = min(-need,1-cnt[i][y[1]]);\n\t\t\tneed += tem;\n\t\t\tcnt[i][y[1]] += tem;\n\t\t}\n\t\tcnt[i+1][y[0]] -= need;\n\t\t\n\t\tneed = 1 - cnt[i][y[1]];\n\t\tans += abs(need);\n\t\tcnt[i+1][y[1]] -= need;\n\t}\n\t\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4764, "score_of_the_acc": -0.4382, "final_rank": 5 }, { "submission_id": "aoj_0661_3581399", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nint clamp(int x, int lb, int ub) {\n return max(lb, min(x, ub));\n}\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n;\n cin >> n;\n vector<vector<int>> need(2, vector<int>(n, 1));\n vector<vector<int>> have(2, vector<int>(n));\n ll ans = 0;\n for(int i = 0; i < 2 * n; i++) {\n int x, y;\n cin >> x >> y;\n int nx = clamp(x, 1, n);\n int ny = clamp(y, 1, 2);\n ans += abs(x - nx) + abs(y - ny);\n have[ny - 1][nx - 1]++;\n }\n for(int x = 0; x < n; x++) {\n if(have[0][x] < need[0][x] and have[1][x] > need[1][x]) {\n int transfer = min(need[0][x] - have[0][x], have[1][x] - need[1][x]);\n ans += transfer;\n have[1][x] -= transfer;\n have[0][x] += transfer;\n }\n if(have[0][x] > need[0][x] and have[1][x] < need[1][x]) {\n int transfer = min(have[0][x] - need[0][x], need[1][x] - have[1][x]);\n ans += transfer;\n have[0][x] -= transfer;\n have[1][x] += transfer;\n }\n if(x < n - 1) {\n for(int y : {0, 1}) {\n if(have[y][x] < need[y][x]) {\n ans += need[y][x] - have[y][x];\n need[y][x + 1] += need[y][x] - have[y][x];\n }\n if(have[y][x] > need[y][x]) {\n ans += have[y][x] - need[y][x];\n have[y][x + 1] += have[y][x] - need[y][x];\n }\n }\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4880, "score_of_the_acc": -0.2876, "final_rank": 2 }, { "submission_id": "aoj_0661_3581159", "code_snippet": "#include <bits/stdc++.h>\n#define err(args...) {}\n#ifdef DEBUG\n#include \"_debug.cpp\"\n#endif\nusing namespace std;\nusing ll = long long;\nconst int N = 1'000;\nll mem[N+1][N+1];\nint main() {\n ios_base::sync_with_stdio(false);\n cin.tie(0);\n int n;\n cin >> n;\n vector<pair<int, int>> coin(2 * n);\n for(int i = 0; i < 2 * n; i++) {\n int x, y;\n cin >> x >> y;\n coin[i] = {x, y};\n }\n sort(coin.begin(), coin.end());\n auto d = [&](int i, int x, int y) {\n ll dx = coin[i].first - (x + 1);\n ll dy = coin[i].second - y;\n return abs(dx) + abs(dy);\n };\n function<ll(int, int)> opt = [&](int x_top, int x_bot) {\n ll& ans = mem[x_top][x_bot];\n if(ans == -1) {\n int i = x_top + x_bot;\n if(i == 2 * n) {\n ans = 0;\n } else if(x_top < n and x_bot < n) {\n ans = min(d(i, x_top, 2) + opt(x_top + 1, x_bot),\n d(i, x_bot, 1) + opt(x_top, x_bot + 1));\n } else if(x_top < n) {\n ans = d(i, x_top, 2) + opt(x_top + 1, x_bot);\n } else { // x_bot < n\n ans = d(i, x_bot, 1) + opt(x_top, x_bot + 1);\n }\n }\n return ans;\n };\n memset(mem, -1, sizeof mem);\n cout << opt(0, 0) << endl;\n return 0;\n}", "accuracy": 0.6320754716981132, "time_ms": 10, "memory_kb": 11248, "score_of_the_acc": -1, "final_rank": 10 } ]
aoj_0672_cpp
ポスター (Poster) 問題文 JOI 君は文化祭でのクラスの出し物を宣伝するため,ポスターを作った.そのポスターは N 行 N 列のマス目の形をしており,各マスは赤,緑,青のいずれかの色で塗られている.ポスターの上から i 行目,左から j 列目 ( 1 ≦ i ≦ N , 1 ≦ j ≦ N ) にあるマスの色は, S i,j = `R' のとき赤色, S i,j = `G' のとき緑色, S i,j = `B' のとき青色である. しかし,このポスターにクラスのみんなは満足してはくれなかった.話し合いの結果,マス目の形は変えずに色の配置を変えることで,新しいポスターを作ることに決まった.新しいポスターの上から i 行目,左から j 列目 ( 1 ≦ i ≦ N , 1 ≦ j ≦ N ) にあるマスの色は, T i,j = `R' のとき赤色, T i,j = `G' のとき緑色, i,j = `B' のとき青色となるようにする. JOI 君は今あるポスターに以下のいずれかの作業を繰り返し行うことで,新しいポスターを作ることにした. マスを一つ選び,そのマスの色を好きな色に塗りなおす. ポスター全体を 90° 時計回りに回転させる.このとき,もともと上から i 行目,左から j 列目 ( 1 ≦ i ≦ N , 1 ≦ j ≦ N ) にあるマスは,上から j 行目,左から N-i+1 列目にあるマスに移動する. ポスター全体を 90° 反時計回りに回転させる.このとき,もともと上から i 行目,左から j 列目 ( 1 ≦ i ≦ N , 1 ≦ j ≦ N ) にあるマスは,上から N-j+1 行目,左から i 列目にあるマスに移動する. JOI 君はどの作業をするにも 1 分かかる.JOI 君が作ったポスター,新しく作るポスターの情報が与えられたとき,JOI 君が新しいポスターを作るのに最短で何分かかるかを求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 500 . S i,j は `R',`G',`B' のいずれかである. T i,j は `R',`G',`B' のいずれかである. 入力 入力は以下の形式で標準入力から与えられる. N S 1,1 … S 1,N : S N,1 … S N,N T 1,1 … T 1,N : T N,1 … T N,N 出力 新しいポスターを作るのに最短で何分かかるかを 1 行で出力せよ. 入出力例 入力例 1 3 RRR GGG BBB RRR RRR RRR 出力例 1 6 2 行目と 3 行目にあるマス目をすべて赤色に塗りかえればよい.これには 6 分かかる. 入力例 2 3 RRR GGG BBB RGB RGB RGB 出力例 2 1 ポスター全体を 90° 反時計回りに回転させればよい.これには 1 分かかる. 入力例 3 6 RRRBBB RRRBBB RRRBBB GGGRRG GGGRRG GGGBBR RRRGGG RRRGGG RRRGGG BBBRRB BBBRRB BBBGGR 出力例 3 10 情報オリンピック日本委員会 作 『第 19 回日本情報オリンピック JOI 2019/2020 一次予選競技課題』
[ { "submission_id": "aoj_0672_10805433", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\n#include<string>\n#include <climits>\nusing namespace std;\n\n\nint main() {\n int N;\n int ans = INT_MAX;\n cin >> N;\n vector<vector<char>>li0(N, vector<char>(N));\n vector<vector<char>>li90(N, vector<char>(N));\n vector<vector<char>>li180(N, vector<char>(N));\n vector<vector<char>>li270(N, vector<char>(N));\n \n vector<vector<char>>A(N, vector<char>(N));\n //li0set\n \n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> li0[i][j];\n }\n }\n \n //Aset\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> A[i][j];\n }\n }\n if (N == 1) {\n if (li0[0][0] != A[0][0]) {\n ans = 1;\n }\n else {\n ans=0;\n }\n }\n else {\n //li90set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li90[N - j - 1][i] = li0[i][j];\n }\n }\n\n //li270set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li270[j][N - i - 1] = li0[i][j];\n }\n }\n\n //li180set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li180[N - i - 1][N - j - 1] = li0[i][j];\n }\n }\n\n\n int ka = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li0[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ans = min(ka, ans);\n ka = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li90[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ka += 1;\n ans = min(ka, ans);\n ka = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li270[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ka += 1;\n ans = min(ka, ans);\n ka = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li180[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ka += 2;\n ans = min(ka, ans);\n }\n cout << ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4680, "score_of_the_acc": -0.4978, "final_rank": 12 }, { "submission_id": "aoj_0672_10805416", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\n#include<string>\nusing namespace std;\n\n\nint main() {\n int N;\n int ans = 1000;\n cin >> N;\n vector<vector<char>>li0(N, vector<char>(N));\n vector<vector<char>>li90(N, vector<char>(N));\n vector<vector<char>>li180(N, vector<char>(N));\n vector<vector<char>>li270(N, vector<char>(N));\n \n vector<vector<char>>A(N, vector<char>(N));\n //li0set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> li0[i][j];\n }\n }\n \n //Aset\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> A[i][j];\n }\n }\n \n //li90set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li90[N - j - 1][i] = li0[i][j];\n }\n }\n \n //li270set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li270[j][N-i-1] = li0[i][j];\n }\n }\n \n //li180set\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n li180[j][N - i - 1] = li270[i][j];\n }\n }\n \n int ka = 0;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li0[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ans = min(ka, ans);\n ka = 1;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li90[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ans = min(ka, ans);\n ka = 1;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li270[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ans = min(ka, ans);\n ka = 2;\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (li180[i][j] != A[i][j]) {\n ka += 1;\n }\n }\n }\n ans = min(ka, ans);\n\n cout << ans<<endl;\n}", "accuracy": 0.15, "time_ms": 10, "memory_kb": 4656, "score_of_the_acc": -0.4848, "final_rank": 16 }, { "submission_id": "aoj_0672_10336572", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nvector<vector<char>> f(const int n,const vector<vector<char>>& s){\n vector<vector<char>> res(n,vector<char>(n));\n rep(i,n){\n rep(j,n){\n res[n-j-1][i]=s[i][j];\n }\n }\n return res;\n}\n\nint main(){\n int n;\n cin >> n;\n vector<vector<char>> s(n,vector<char>(n)),t(n,vector<char>(n));\n rep(i,n){\n rep(j,n){\n cin >> s[i][j];\n }\n }\n rep(i,n){\n rep(j,n){\n cin >> t[i][j];\n }\n }\n\n //回転0回\n int res0=0;\n rep(i,n){\n rep(j,n){\n if(s[i][j]!=t[i][j]){\n res0++;\n }\n }\n }\n\n //1回\n int res1=1;\n s=f(n,s);\n rep(i,n){\n rep(j,n){\n if(s[i][j]!=t[i][j]){\n res1++;\n }\n }\n }\n int res2=2;\n s=f(n,s);\n rep(i,n){\n rep(j,n){\n if(s[i][j]!=t[i][j]){\n res2++;\n }\n }\n } \n int res3=1;\n s=f(n,s);\n rep(i,n){\n rep(j,n){\n if(s[i][j]!=t[i][j]){\n res3++;\n }\n }\n }\n cout << min({res0,res1,res2,res3}) << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4092, "score_of_the_acc": -0.1797, "final_rank": 5 }, { "submission_id": "aoj_0672_10222923", "code_snippet": "#include<bits/stdc++.h>\n#define ll long long\nusing namespace std;\nconst ll N = 500 + 10;\nchar a[N][N], b[N][N], c[N][N], d[N][N], s[N][N], t[N][N];\nint main()\n{\n ll n;\n cin>>n;\n for(int i = 1; i<= n ; i++)\n {\n for(int j = 1 ; j<= n ; j++)\n {\n cin>>s[i][j];\n }\n }\n for(int i = 1 ; i<= n ; i++)\n {\n for(int j = 1 ; j<= n ; j++)\n {\n cin>>t[i][j];\n }\n }\n for(int i = 1 ; i<= n ; i++)\n {\n for(int j = 1; j<= n ; j++)\n {\n a[i][j] = s[j][n - i + 1];\n b[i][j] = s[n - j + 1][i];\n }\n }\n for(int i = 1 ; i<= n ; i++)\n {\n for(int j = 1; j<= n ; j++)\n {\n c[i][j] = a[j][n - i + 1];\n }\n }\n ll d1 = 0 , d2 = 1 , d3 = 1 , d4 = 2;\n for(int i = 1; i<= n ; i++)\n {\n for(int j = 1 ; j<= n ; j++)\n {\n if(s[i][j] != t[i][j]) d1 ++;\n if(a[i][j] != t[i][j]) d2 ++;\n if(b[i][j] != t[i][j]) d3 ++;\n if(c[i][j] != t[i][j]) d4 ++;\n }\n }\n cout<<min({d1 , d2 , d3 , d4})<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4668, "score_of_the_acc": -0.4913, "final_rank": 11 }, { "submission_id": "aoj_0672_9644972", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nvoid rotateClockwise(vector<vector<char>>& poster) {\n int N = poster.size();\n vector<vector<char>> rotated(N, vector<char>(N));\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n rotated[j][N-i-1] = poster[i][j];\n }\n }\n poster = rotated;\n}\n\nint countDifferences(vector<vector<char>>& S, vector<vector<char>>& T) {\n int count = 0;\n int N = S.size();\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n if (S[i][j] != T[i][j]) count++;\n }\n }\n return count;\n}\n\nint main() {\n int N;\n cin >> N;\n\n vector<vector<char>> S(N, vector<char>(N));\n vector<vector<char>> T(N, vector<char>(N));\n\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> S[i][j];\n }\n }\n\n for (int i = 0; i < N; i++) {\n for (int j = 0; j < N; j++) {\n cin >> T[i][j];\n }\n }\n\n int minCount = countDifferences(S, T);\n \n rotateClockwise(S);\n minCount = min(minCount, countDifferences(S, T) + 1);\n\n rotateClockwise(S);\n minCount = min(minCount, countDifferences(S, T) + 2);\n\n rotateClockwise(S);\n minCount = min(minCount, countDifferences(S, T) + 1);\n\n cout << minCount << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4024, "score_of_the_acc": -0.1429, "final_rank": 3 }, { "submission_id": "aoj_0672_7126284", "code_snippet": "#include<iostream>\nusing namespace std;\n\nchar s[500][500];\nchar t[500][500];\nchar keep[500][500];\n\nint paint(int n, int cnt)\n{\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n cnt++;\n }\n }\n return cnt;\n}\n\nint rotate(int n, int k, int cnt, char drc)\n{\n if (drc == 'r')\n {\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n cnt++;\n }\n cnt = paint(n, cnt);\n }\n else if (drc == 'l')\n {\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n cnt++;\n }\n cnt = paint(n, cnt);\n }\n return cnt;\n}\n\nint compare(int cnt, int min)\n{\n if (min > cnt)\n min = cnt;\n return min;\n}\n\nint main()\n{\n int n, counter = 0, min = 250001;\n cin >> n;\n char org[n][n];\n for (int i = 0; i < n; i++)\n cin >> s[i];\n for (int i = 0; i < n; i++)\n cin >> t[i];\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n counter = paint(n, counter);\n min = compare(counter, min);\n counter = 0;\n for (int k = 1; k <= 3; k++)\n {\n counter = rotate(n, k, counter, 'r');\n min = compare(counter, min);\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n counter = 0;\n }\n counter = 0;\n for (int k = 1; k <= 3; k++)\n {\n counter = rotate(n, k, counter, 'l');\n min = compare(counter, min);\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n counter = 0;\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4052, "score_of_the_acc": -0.158, "final_rank": 4 }, { "submission_id": "aoj_0672_7119369", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n long n, counter = 0, min = 250001;\n cin >> n;\n char s[n][n], t[n][n], keep[n][n], org[n][n];\n for (long i = 0; i < n; i++)\n cin >> s[i];\n for (long i = 0; i < n; i++)\n cin >> t[i];\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n\n for (int k = 1; k <= 4; k++)\n {\n //時計回り\n for (int l = 1; l <= k; l++)\n {\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n counter++;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n\n for (int k = 1; k <= 4; k++)\n {\n //反時計回り\n for (int l = 1; l <= k; l++)\n {\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n counter++;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 0.15, "time_ms": 20, "memory_kb": 3960, "score_of_the_acc": -1.1082, "final_rank": 17 }, { "submission_id": "aoj_0672_7119366", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n long n, counter = 0, min = 250001;\n cin >> n;\n char s[n][n], t[n][n], keep[n][n], org[n][n];\n for (int i = 0; i < n; i++)\n cin >> s[i];\n for (int i = 0; i < n; i++)\n cin >> t[i];\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n\n for (int k = 1; k <= 4; k++)\n {\n //時計回り\n for (int l = 1; l <= k; l++)\n {\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n counter++;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n\n for (int k = 1; k <= 4; k++)\n {\n //反時計回り\n for (int l = 1; l <= k; l++)\n {\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n counter++;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (long i = 0; i < n; i++)\n {\n for (long j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 0.15, "time_ms": 10, "memory_kb": 4068, "score_of_the_acc": -0.1667, "final_rank": 15 }, { "submission_id": "aoj_0672_7119358", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n long n, counter = 0, min = 500 * 500 + 1;\n cin >> n;\n char s[n][n], t[n][n], keep[n][n], org[n][n];\n for (int i = 0; i < n; i++)\n cin >> s[i];\n for (int i = 0; i < n; i++)\n cin >> t[i];\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n\n for (int k = 1; k <= 4; k++)\n {\n //時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n\n for (int k = 1; k <= 4; k++)\n {\n //反時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 0.15, "time_ms": 20, "memory_kb": 3976, "score_of_the_acc": -1.1169, "final_rank": 18 }, { "submission_id": "aoj_0672_7119337", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n int n, counter = 0, min = 500 * 500 + 1;\n cin >> n;\n char s[n][n], t[n][n], keep[n][n], org[n][n];\n for (int i = 0; i < n; i++)\n cin >> s[i];\n for (int i = 0; i < n; i++)\n cin >> t[i];\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n\n for (int k = 1; k <= 4; k++)\n {\n //時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n\n for (int k = 1; k <= 4; k++)\n {\n //反時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 0.15, "time_ms": 20, "memory_kb": 4044, "score_of_the_acc": -1.1537, "final_rank": 20 }, { "submission_id": "aoj_0672_7119333", "code_snippet": "#include<iostream>\nusing namespace std;\n\nint main()\n{\n int n, counter = 0, min = 501;\n cin >> n;\n char s[n][n], t[n][n], keep[n][n], org[n][n];\n for (int i = 0; i < n; i++)\n cin >> s[i];\n for (int i = 0; i < n; i++)\n cin >> t[i];\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n keep[i][j] = s[i][j];\n org[i][j] = s[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n\n for (int k = 1; k <= 4; k++)\n {\n //時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[j][n - i - 1] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n\n for (int k = 1; k <= 4; k++)\n {\n //反時計回り\n for (int l = 1; l <= k; l++)\n {\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n s[n - j - 1][i] = keep[i][j];\n }\n counter++;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = s[i][j];\n }\n }\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n {\n if (s[i][j] != t[i][j])\n counter++;\n }\n }\n if (min > counter)\n min = counter;\n counter = 0;\n for (int i = 0; i < n; i++)\n {\n for (int j = 0; j < n; j++)\n keep[i][j] = org[i][j];\n }\n }\n cout << min << endl;\n return 0;\n}", "accuracy": 0.15, "time_ms": 20, "memory_kb": 3980, "score_of_the_acc": -1.119, "final_rank": 19 }, { "submission_id": "aoj_0672_7119270", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <math.h>\nusing namespace std;\n\nint main()\n{\n\tint n,wa;\n\tcin >> n;\n\tstring mon[500] = {};\n\tstring to[500] = {};\n\tstring ans[500] = {};\n\tint jud[4] = {0,1,1,2};\n\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> mon[i];\n\t}\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> ans[i];\n\t}\n\n\tfor (int i = 0; i < 500; i++) {\n\t\tfor (int j = 0; j < 500; j++) {\n\t\t\tto[i]+='a';\n\t\t}\n\t}\n\t\n\tfor (int ro = 0; ro < 4; ro++) {\n\t\t\n\t\tif (ro == 0) {\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tfor (int j = 0; j < n; j++) {\n\t\t\t\t\tto[i][j] = mon[i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\t\n\n\t\t\n\t\tif (ro == 1) { //右\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tfor (int j = 0; j < n; j++) {\n\t\t\t\t\tto[i][j] = mon[n-j-1][i];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (ro == 2) { //左\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tfor (int j = 0; j < n; j++) {\n\t\t\t\t\tto[i][j] = mon[j][n-i-1];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tif (ro == 3) { //反転\n\t\t\tfor (int i = 0; i < n; i++) {\n\t\t\t\tfor (int j = 0; j < n; j++) {\n\t\t\t\t\tto[i][j] = mon[n - i - 1][n - j - 1];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tfor (int j = 0; j < n; j++) {\n\t\t\t\tif (to[i][j] != ans[i][j]) {\n\t\t\t\t\tjud[ro]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t}\n\twa = jud[0];\n\twa = min(wa, jud[1]);\n\twa = min(wa, jud[2]);\n\twa = min(wa, jud[3]);\n\tcout << wa<<endl;\n\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3896, "score_of_the_acc": -0.0736, "final_rank": 2 }, { "submission_id": "aoj_0672_7072208", "code_snippet": "#include <bits/stdc++.h>\n#include <iostream>\n#include <limits>\n#include <numeric>\n#include <type_traits>\n#include <bitset>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <random>\n\nusing namespace std;\n\n#define rep(i,n,m) for(ll (i)=(n);(i)<(m);(i)++)\n#define rrep(i,n,m) for(ll (i)=(n);(i)>(m);(i)--)\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll inf = 1e9;\nconst ll INF = 1e17;\n\nvoid pline(vector<ll> lis){\n rep(i,0,lis.size()){\n printf (\"%lld\",lis[i]);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\nvoid pline(vector<pair<ll,ll>> lis){\n rep(i,0,lis.size()){\n printf (\"/%lld,%lld/\",lis[i].first,lis[i].second);\n if (i != lis.size()-1) printf(\" \");\n else printf(\"\\n\");\n }\n}\n\n/*\nvoid pmap(map<ll,mint>& lis){\n for (auto p : lis){\n printf (\"%lld:%lld ,\",p.first,p.second.val());\n }\n printf (\"\\n\");\n}*/\n\nvoid RotR(vector<string>& S){\n\n ll N = S.size();\n vector<string> R;\n rep(i,0,S.size()) R.push_back(S[i]);\n\n rep(i,0,S.size()){\n rep(j,0,S.size()){\n R[j][N-1-i] = S[i][j];\n }\n }\n\n rep(i,0,S.size()){\n rep(j,0,S.size()){\n S[i][j] = R[i][j];\n }\n }\n}\n\nint main(){\n\n //ios::sync_with_stdio(false);\n //std::cin.tie(nullptr);\n\n ll N;\n cin >> N;\n\n vector<string> S(N);\n vector<string> T(N);\n\n rep(i,0,N) cin >> S[i];\n rep(i,0,N) cin >> T[i];\n\n vector<ll> plus = {0,1,2,1};\n\n ll ans = N*N;\n rep(i,0,4){\n\n ll now = 0;\n rep(x,0,N){\n rep(y,0,N){\n if (S[x][y] != T[x][y]) now++;\n }\n }\n\n now += plus[i];\n ans = min(ans, now);\n\n RotR(S);\n\n //rep(xx,0,N) cout << S[xx] << endl;\n //cout << now << endl;\n }\n\n cout << ans << endl;\n}\n\n/*\n\n区間だよなぁ\ndp[i] = フリー区間の最左がiの時の最大値\n\n*/", "accuracy": 1, "time_ms": 10, "memory_kb": 4632, "score_of_the_acc": -0.4719, "final_rank": 10 }, { "submission_id": "aoj_0672_7033416", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n, ans = 0, cnt = 0;\n char lf;\n cin >> n;\n vector<vector<char> > s(n, vector<char>(n)), t(n, vector<char>(n)), tmp(n, vector<char>(n));\n\n for (int i = 0; i < n; i++) {\n scanf(\"%c\", &lf);\n for (int j = 0; j < n; j++) scanf(\"%c\", &s.at(i).at(j));\n }\n for (int i = 0; i < n; i++) {\n scanf(\"%c\", &lf);\n for (int j = 0; j < n; j++) scanf(\"%c\", &t.at(i).at(j));\n }\n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (s.at(i).at(j) != t.at(i).at(j)) cnt++;\n }\n }\n ans = cnt;\n cnt = 0;\n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (s.at(i).at(j) != t.at(j).at(n-i-1)) cnt++;\n }\n }\n ans = min(ans, cnt + 1);\n cnt = 0;\n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (s.at(i).at(j) != t.at(n-j-1).at(i)) cnt++;\n tmp.at(i).at(j) = s.at(n-j-1).at(i);\n }\n }\n ans = min(ans, cnt + 1);\n cnt = 0;\n\n for (int i = 0; i < n; i++) {\n for (int j = 0; j < n; j++) {\n if (tmp.at(i).at(j) != t.at(j).at(n-i-1)) cnt++;\n }\n }\n ans = min(ans, cnt + 2);\n\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3760, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0672_6852281", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\nint n;\ncin>>n;\nstring r = \"\";\nstring s = \"\";\nstring t = \"\";\nfor (int i = 0; i < n; i++){cin>>r;s += r;}\nfor (int i = 0; i < n; i++){cin>>r;t += r;}\nchar l1[n*n];\nchar l2[n*n];\nchar r1[n*n];\nint a;int b;\nfor (int k = 0; k < n*n; k++){\na=k/n;b=k%n;\nl1[n*(n-1-b)+a]=s[k];\nl2[n*(n-1-a)+(n-1-b)]=s[k];\nr1[n*b+(n-1-a)]=s[k];\n}\nint cnt[]={0,1,2,1};\nfor (int i = 0; i < n*n; i++){\nif(s[i]!=t[i]){cnt[0]++;}\nif(l1[i]!=t[i]){cnt[1]++;}\nif(l2[i]!=t[i]){cnt[2]++;}\nif(r1[i]!=t[i]){cnt[3]++;}\n}\nint min=0;\nmin = cnt[0]<cnt[1] ? cnt[0]:cnt[1];\nmin = min<cnt[2] ? min:cnt[2];\nmin = min<cnt[3] ? min:cnt[3];\ncout<<min<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4364, "score_of_the_acc": -0.3268, "final_rank": 9 }, { "submission_id": "aoj_0672_6846981", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\nint n;\ncin>>n;\nstring r = \"\";\nstring s = \"\";\nstring t = \"\";\nfor (int i = 0; i < n; i++){cin>>r;s += r;}\nfor (int i = 0; i < n; i++){cin>>r;t += r;}\nchar l1[n*n];\nchar l2[n*n];\nchar r1[n*n];\nint a;int b;\nfor (int k = 0; k < n*n; k++){\n a=k/n;b=k%n;\n l1[n*(n-1-b)+a]=s[k];\n l2[n*(n-1-a)+(n-1-b)]=s[k];\n r1[n*b+(n-1-a)]=s[k];\n}\nint cnt[]={0,1,2,1};\nfor (int i = 0; i < n*n; i++){\n if(s[i]!=t[i]){cnt[0]++;}\n if(l1[i]!=t[i]){cnt[1]++;}\n if(l2[i]!=t[i]){cnt[2]++;}\n if(r1[i]!=t[i]){cnt[3]++;}\n}\nint min=0;\nmin = cnt[0]<cnt[1] ? cnt[0]:cnt[1];\nmin = min<cnt[2] ? min:cnt[2];\nmin = min<cnt[3] ? min:cnt[3];\ncout<<min<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4336, "score_of_the_acc": -0.3117, "final_rank": 7 }, { "submission_id": "aoj_0672_6846970", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\nint n;\ncin>>n;\nstring r = \"\";\nstring s = \"\";\nstring t = \"\";\nfor (int i = 0; i < n; i++){cin>>r;s += r;}\nfor (int i = 0; i < n; i++){cin>>r;t += r;}\nchar l1[n*n];\nchar l2[n*n];\nchar r1[n*n];\nint a;int b;\nfor (int k = 0; k < n*n; k++){\n a=k/n;b=k%n;\n l1[n*(n-1-b)+a]=s[k];\n l2[n*(n-1-a)+(n-1-b)]=s[k];\n r1[n*b+(n-1-a)]=s[k];\n}\n//string s01=l1;\n//string s02=l2;\n//string s03=r1;\nint cnt[]={0,1,2,1};\nfor (int i = 0; i < n*n; i++){\n if(s[i]!=t[i]){cnt[0]++;}\n if(l1[i]!=t[i]){cnt[1]++;}\n if(l2[i]!=t[i]){cnt[2]++;}\n if(r1[i]!=t[i]){cnt[3]++;}\n}\nint min=0;\nmin = cnt[0]<cnt[1] ? cnt[0]:cnt[1];\nmin = min<cnt[2] ? min:cnt[2];\nmin = min<cnt[3] ? min:cnt[3];\ncout<<min<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4336, "score_of_the_acc": -0.3117, "final_rank": 7 }, { "submission_id": "aoj_0672_6844014", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nint main(void){\nint n;\ncin>>n;\nstring r = \"\";\nstring s = \"\";\nstring t = \"\";\nfor (int i = 0; i < n; i++){cin>>r;s += r;}\nfor (int i = 0; i < n; i++){cin>>r;t += r;}\nchar l1[n*n];\nchar l2[n*n];\nchar r1[n*n];\nint a;int b;\nfor (int k = 0; k < n*n; k++){\n a=k/n;b=k%n;\n l1[n*(n-1-b)+a]=s[k];\n l2[n*(n-1-a)+(n-1-b)]=s[k];\n r1[n*b+(n-1-a)]=s[k];\n}\nstring s01=l1;\nstring s02=l2;\nstring s03=r1;\nint cnt[]={0,1,2,1};\nfor (int i = 0; i < n*n; i++){\n if(s[i]!=t[i]){cnt[0]++;}\n if(s01[i]!=t[i]){cnt[1]++;}\n if(s02[i]!=t[i]){cnt[2]++;}\n if(s03[i]!=t[i]){cnt[3]++;}\n}\nint min=0;\nmin = cnt[0]<cnt[1] ? cnt[0]:cnt[1];\nmin = min<cnt[2] ? min:cnt[2];\nmin = min<cnt[3] ? min:cnt[3];\ncout<<min<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5584, "score_of_the_acc": -0.987, "final_rank": 13 }, { "submission_id": "aoj_0672_6844008", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\nint n;\ncin>>n;\nstring r = \"\";\nstring s = \"\";\nstring t = \"\";\nfor (int i = 0; i < n; i++){cin>>r;s += r;}\nfor (int i = 0; i < n; i++){cin>>r;t += r;}\nchar l1[n*n];\nchar l2[n*n];\nchar r1[n*n];\nint a;int b;\nfor (int k = 0; k < n*n; k++){\n a=k/n;b=k%n;\n l1[n*(n-1-b)+a]=s[k];\n l2[n*(n-1-a)+(n-1-b)]=s[k];\n r1[n*b+(n-1-a)]=s[k];\n}\nstring s01=l1;\nstring s02=l2;\nstring s03=r1;\nint cnt[]={0,1,2,1};\nfor (int i = 0; i < n*n; i++){\n if(s[i]!=t[i]){cnt[0]++;}\n if(s01[i]!=t[i]){cnt[1]++;}\n if(s02[i]!=t[i]){cnt[2]++;}\n if(s03[i]!=t[i]){cnt[3]++;}\n}\nint min=0;\nmin = cnt[0]<cnt[1] ? cnt[0]:cnt[1];\nmin = min<cnt[2] ? min:cnt[2];\nmin = min<cnt[3] ? min:cnt[3];\ncout<<min<<'\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5608, "score_of_the_acc": -1, "final_rank": 14 }, { "submission_id": "aoj_0672_6676567", "code_snippet": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint N; cin >> N;\n\tvector<string> S(N), T(N);\n\tfor (auto& s : S) cin >> s;\n\tfor (auto& t : T) cin >> t;\n\tvector<int> r = {0, 1, 2, 1};\n\tfor (int i = 0; i < N; ++i) for (int j = 0; j < N; ++j) {\n\t\tif (S[i][j] != T[i][j]) ++r[0];\n\t\tif (S[i][j] != T[j][N - 1 - i]) ++r[1];\n\t\tif (S[i][j] != T[N - 1 - i][N - 1 - j]) ++r[2];\n\t\tif (S[i][j] != T[N - 1 - j][i]) ++r[3];\n\t}\n\tcout << *min_element(r.begin(), r.end()) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4328, "score_of_the_acc": -0.3074, "final_rank": 6 } ]
aoj_0693_cpp
イベント巡り IOI 国には 2 個の町があり,それぞれ 1, 2 と番号がついている. これらの町では合計 N 個のイベントが行われる.これらのイベントには 1 から N までの番号がついている.イベント i ( 1 ≦ i ≦ N ) は町 P i で開催され,開催時刻は時刻 S i + 0.1 から時刻 S i + 0.9 までである.ここで S i は整数である.JOI 君がイベント i に参加するためには,時刻 S i + 0.1 から時刻 S i + 0.9 までの間,ずっと町 P i にいる必要がある. JOI 君はイベント巡りを行うことにした.イベント巡りではいくつかのイベントに参加し,必要ならば町と町の間を移動することもできる.JOI 君は時刻 0 からイベント巡りを開始する.このとき,好きな町から始めることができる. JOI 君は町 1 と町 2 の間を双方向に移動することができる. 2 つの町の間を移動するのにかかる時間は,JOI 君がその移動を開始する時刻までに参加したイベントの数を j として, D + K × j となる. イベントと町の間の移動に関する情報が与えられるので,JOI 君が参加できるイベントの数の最大値を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 200000 . 1 ≦ D ≦ 10 12 . 0 ≦ K ≦ 10 12 . 1 ≦ P i ≦ 2 ( 1 ≦ i ≦ N ). 1 ≦ S i ≦ 10 12 ( 1 ≦ i ≦ N ). S i ≠ S j ( 1 ≦ i < j ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N D K P 1 S 1 P 2 S 2 : P N S N 出力 標準出力に,JOI 君が参加することのできるイベントの数の最大値を 1 行で出力せよ. 入出力例 入力例 1 5 3 0 1 1 1 2 1 10 2 5 2 6 出力例 1 4 例えば,以下のように行動することで,JOI 君は 4 個のイベントに参加することができる. 時刻 0 において JOI 君は町 1 にいる. 時刻 1.1 から時刻 1.9 まで町 1 でイベント 1 に参加する. 時刻 2.1 から時刻 2.9 まで町 1 でイベント 2 に参加する. 時刻 3 から時刻 6 まで時間 3 ( = D + K × 2 ) をかけて町 1 から町 2 に移動する. 時刻 6.1 から時刻 6.9 まで町 2 でイベント 5 に参加する. 時刻 7 から時刻 10 まで時間 3 ( = D + K × 3 ) をかけて町 2 から町 1 に移動する. 時刻 10.1 から時刻 10.9 まで町 1 でイベント 3 に参加する. どのように行動しても 5 個以上のイベントに参加することはできないため, 4 を出力する. 入力例 2 7 2 3 2 2 1 8 1 10 1 11 2 23 2 24 2 25 出力例 2 6 例えば,以下のように行動することで,JOI 君は 6 個のイベントに参加することができる. 時刻 0 において JOI 君は町 2 にいる. 時刻 2.1 から時刻 2.9 まで町 2 でイベント 1 に参加する. 時刻 3 から時刻 8 まで時間 5 ( = D + K × 1 ) をかけて町 2 から町 1 に移動する. 時刻 8.1 から時刻 8.9 まで町 1 でイベント 2 に参加する. 時刻 11.1 から時刻 11.9 まで町 1 でイベント 4 に参加する. 時刻 12 から時刻 23 まで時間 11 ( = D + K × 3 ) をかけて町 1 から町 2 に移動する. 時刻 23.1 から時刻 23.9 まで町 2 でイベント 5 に参加する. 時刻 24.1 から時刻 24.9 まで町 2 でイベント 6 に参加する. 時刻 25.1 から時刻 25.9 まで町 2 でイベント 7 に参加する. どのように行動しても 7 個以上のイベントに参加することはできないため, 6 を出力する. 入力例 3 12 153 0 1 155 2 861 1 646 1 218 2 450 2 56 1 932 2 295 2 863 1 612 2 38 2 768 出力例 3 8 入力例 4 15 89 104 1 4379 1 738 1 4862 1 4236 2 1416 1 9905 1 4775 2 4574 2 439 1 3956 1 955 2 8862 2 801 2 2299 2 575 出力例 4 11 情報オリンピック日本委員会 作 『第 20 回日本情報オリンピック JOI 2020/2021 二次予選競技課題』
[ { "submission_id": "aoj_0693_10394863", "code_snippet": "#include <iostream>\n#include <set>\n#include <algorithm>\n#include <string.h>\nusing namespace std;\n\nlong long int dp[200010][2][2];\nstd::set<long long int> ss[2];\n\nint main() {\n\tlong long int n,d,k1;\n\tcin>>n>>d>>k1;\n\tfor(int i=0;i<n;i++){\n\t\tlong long int s1,t1;\n\t\tcin>>s1>>t1;\n\t\tss[s1-1].insert(t1);\n\t}\n\tmemset(dp,-1,sizeof(dp));\n\tdp[0][0][0]=0;\n\tdp[0][1][0]=0;\n\tdp[0][0][1]=0;\n\tdp[0][1][1]=0;\n\tint ans=0;\n\tfor(int i=0;i<=n;i++){\n\t\tfor(int j=0;j<2;j++){\n\t\t\tfor(int k=0;k<2;k++){\n\t\t\t\tlong long int t0=dp[i][k][j];\n\t\t\t\tif(t0==-1)continue;\n\t\t\t\tlong long int t1=0;\n\t\t\t\tif(j==k){\n\t\t\t\t\tt1=t0;\n\t\t\t\t}else{\n\t\t\t\t\tt1=t0+d+i*k1;\n\t\t\t\t}\n\t\t\t\tauto it=ss[k].lower_bound(t1);\n\t\t\t\tif(it==ss[k].end()){\n\t\t\t\t\tif(ans<i)ans=i;\n\t\t\t\t}else{\n\t\t\t\t\tlong long int ta,tb;\n\t\t\t\t\tta=dp[i+1][0][k];\n\t\t\t\t\ttb=dp[i+1][1][k];\n\t\t\t\t\tif(ta==-1 || (*it)+1<ta)dp[i+1][0][k]=(*it)+1;\n\t\t\t\t\tif(tb==-1 || (*it)+1<tb)dp[i+1][1][k]=(*it)+1;\n\t\t\t\t}\n\t\t\t\t//cout<<\"(\"<<t1<<\" \"<<k<<\",\"<<j<<\",\"<<dp[i][k][j]<<\")\";\n\t\t\t}\n\t\t}\n\t\t//cout<<endl;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 19072, "score_of_the_acc": -1.3128, "final_rank": 9 }, { "submission_id": "aoj_0693_10223159", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\n\nvoid solve(){\n ll N,D,K;\n cin>>N>>D>>K;\n vector<vector<array<ll,2>>> U(2);\n vector<array<ll,2>> P(N);\n rep(i,N){\n cin>>P[i][1]>>P[i][0];\n P[i][1]--;\n }\n sort(all(P));\n rep(i,N)U[P[i][1]].push_back({P[i][0],i});\n rep(i,2)U[i].push_back({ll(1e18),-1});\n vector<ll> DP(N,1);\n ll an=0;\n for(int i=0;i<N;i++){\n an=max(an,DP[i]);\n array<ll,2> memo={P[i][0],N+10};\n auto p=*(upper_bound(all(U[P[i][1]]),memo));\n if(p[1]!=-1)DP[p[1]]=max(DP[p[1]],DP[i]+1);\n memo={P[i][0]+D+K*DP[i],N+10};\n p=*(upper_bound(all(U[1-P[i][1]]),memo));\n if(p[1]!=-1)DP[p[1]]=max(DP[p[1]],DP[i]+1);\n }\n cout<<an<<endl;\n}\n\nint main(){\n \n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int T=1;\n while(T--)\n solve();\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 13372, "score_of_the_acc": -0.1978, "final_rank": 5 }, { "submission_id": "aoj_0693_9717203", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n long long N, D, K;\n cin >> N >> D >> K;\n vector<long long> P(N), S(N);\n for (int i = 0; i < N; i++) {\n cin >> P[i] >> S[i];\n }\n vector<long long> V[2];\n V[0].push_back(0);\n V[1].push_back(0);\n for (long long i = 0; i < N; i++) {\n P[i]--;\n V[P[i]].push_back(S[i]);\n }\n for (int i = 0; i <= 1; i++) {\n sort(V[i].begin(), V[i].end());\n }\n long long mx = 4000000000000000000;\n long long dp[2][N + 5];\n for (int i = 0; i <= 1; i++) {\n for (long long k = 0; k <= N; k++) {\n dp[i][k] = mx;\n }\n }\n dp[0][0] = 0;\n dp[1][0] = 0;\n for (long long i = 0; i <= N - 1; i++) {\n if (dp[0][i] != mx) {\n long long now = dp[0][i];\n long long pos = lower_bound(V[0].begin(), V[0].end(), now + 1) - V[0].begin();\n if (pos < V[0].size()) {\n dp[0][i + 1] = min(dp[0][i + 1], V[0][pos]);\n }\n long long cost = D + K * i + 1;\n pos = lower_bound(V[1].begin(), V[1].end(), now + cost) - V[1].begin();\n if (pos < V[1].size()) {\n dp[1][i + 1] = min(dp[1][i + 1], V[1][pos]);\n }\n }\n if (dp[1][i] != mx) {\n long long now = dp[1][i];\n long long pos = lower_bound(V[1].begin(), V[1].end(), now + 1) - V[1].begin();\n if (pos < V[1].size()) {\n dp[1][i + 1] = min(dp[1][i + 1], V[1][pos]);\n }\n long long cost = D + K * i + 1;\n pos = lower_bound(V[0].begin(), V[0].end(), now + cost) - V[0].begin();\n if (pos < V[0].size()) {\n dp[0][i + 1] = min(dp[0][i + 1], V[0][pos]);\n }\n }\n }\n int ans = 0;\n for (int i = 0; i <= N; i++) {\n if (dp[0][i] != mx || dp[1][i] != mx) {\n ans = i;\n }\n }\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 11252, "score_of_the_acc": -0.5931, "final_rank": 8 }, { "submission_id": "aoj_0693_8753346", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n;\n ll d, k;\n cin >> n >> d >> k;\n vector<ll> s1, s2;\n rep (i, n) {\n int p;\n ll s;\n cin >> p >> s;\n if (p == 1)\n s1.emplace_back(s);\n else\n s2.emplace_back(s);\n }\n sort(all(s1));\n sort(all(s2));\n\n vector dp(2, vector(n + 1, INF));\n dp[0][0] = 0;\n dp[1][0] = 0;\n rep (i, n) {\n auto it1 = lower_bound(all(s1), dp[0][i]);\n if (it1 != s1.end())\n chmin(dp[0][i + 1], (*it1) + 1);\n auto it2 = lower_bound(all(s2), dp[0][i] + d + k * i);\n if (it2 != s2.end())\n chmin(dp[1][i + 1], (*it2) + 1);\n auto it3 = lower_bound(all(s2), dp[1][i]);\n if (it3 != s2.end())\n chmin(dp[1][i + 1], (*it3) + 1);\n auto it4 = lower_bound(all(s1), dp[1][i] + d + k * i);\n if (it4 != s1.end())\n chmin(dp[0][i + 1], (*it4) + 1);\n }\n\n int ans = 0;\n rep (i, n + 1) {\n if (dp[0][i] != INF || dp[1][i] != INF)\n ans = i;\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 10020, "score_of_the_acc": -0.0322, "final_rank": 2 }, { "submission_id": "aoj_0693_8307027", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing Event = pair<long long, int>; // time, which\n\nvoid chmax(int &a, int b) { if (a < b) a = b; }\n\nint main() {\n long long N, D, K;\n cin >> N >> D >> K;\n vector<vector<long long>> time(2);\n vector<Event> events({Event(0, 0), Event(0, 1)});\n for (int i = 0; i < N; ++i) {\n long long P, S;\n cin >> P >> S;\n --P;\n time[P].push_back(S);\n events.emplace_back(S, P);\n }\n for (int i = 0; i < 2; ++i) sort(time[i].begin(), time[i].end());\n sort(events.begin(), events.end());\n\n map<Event, int> dp;\n dp[Event(0, 0)] = dp[Event(0, 1)] = 0;\n for (auto e: events) {\n int p = e.second, cur = dp[e];\n\n // そのままの町で\n auto it = lower_bound(time[p].begin(), time[p].end(), e.first + 1);\n if (it != time[p].end()) chmax(dp[Event(*it, p)], cur + 1);\n\n // 移動\n long long need = D + K * cur;\n it = lower_bound(time[1-p].begin(), time[1-p].end(), e.first + 1 + need);\n if (it != time[1-p].end()) chmax(dp[Event(*it, 1-p)], cur + 1);\n }\n int res = 0;\n for (auto it: dp) chmax(res, it.second);\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 21136, "score_of_the_acc": -1.5814, "final_rank": 11 }, { "submission_id": "aoj_0693_7036159", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main(){\n ios::sync_with_stdio(false);\n cin.tie(0);\n ll N, D, K, v;\n cin >> N >> D >> K;\n vector<pair<ll,int>> a(N);\n vector<vector<ll>> tb(2);\n for(int i = 0; i < N; i++){\n cin >> a[i].second >> a[i].first;\n tb[--a[i].second].push_back(a[i].first);\n }\n sort(a.begin(), a.end());\n sort(tb[0].begin(), tb[0].end());\n sort(tb[1].begin(), tb[1].end());\n vector<vector<ll>> dp = {vector<ll>(tb[0].size(), 1), vector<ll>(tb[1].size(), 1)};\n int p0 = 0, p1 = 0, idx;\n for(int i = 0; i < N; i++){\n tie(v, idx) = a[i];\n int j = lower_bound(tb[idx].begin(), tb[idx].end(), v) - tb[idx].begin();\n if(j + 1 < tb[idx].size())dp[idx][j + 1] = max(dp[idx][j + 1], dp[idx][j] + 1);\n if(idx == 0){\n for(ll k = dp[idx][j]; k > p0; k--){\n ll v2 = v + 1 + D + K * k;\n int t = lower_bound(tb[idx ^ 1].begin(), tb[idx ^ 1].end(), v2) - tb[idx ^ 1].begin();\n if(t < tb[idx ^ 1].size()){\n dp[idx ^ 1][t] = max(dp[idx ^ 1][t], k + 1);\n }\n }\n p0 = max(p0, int(dp[idx][j]));\n }else{\n for(ll k = dp[idx][j]; k > p1; k--){\n ll v2 = v + 1 + D + K * k;\n int t = lower_bound(tb[idx ^ 1].begin(), tb[idx ^ 1].end(), v2) - tb[idx ^ 1].begin();\n if(t < tb[idx ^ 1].size()){\n dp[idx ^ 1][t] = max(dp[idx ^ 1][t], k + 1);\n }\n }\n p1 = max(p1, int(dp[idx][j]));\n }\n }\n ll ans = 0;\n if(dp[0].size() >= 1)ans = max(ans, dp[0].back());\n if(dp[1].size() >= 1)ans = max(ans, dp[1].back());\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 11104, "score_of_the_acc": -0.0858, "final_rank": 3 }, { "submission_id": "aoj_0693_7018742", "code_snippet": "#include <bits/stdc++.h>\n// #include <atcoder/modint>\n\n#define rep(i, x) for (ll i = 0; i < x; i++)\n#define rep2(i, x) for (ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for (ll i = x; i < y; i++)\n#define REP(i, x) for (ll i = x - 1; i >= 0; i--)\n#define REP2(i, x) for (ll i = x; i >= 1; i--)\n#define mpa make_pair\n#define mpt make_tuple\n#define pb push_back\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\n// using namespace atcoder;\n\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = acos(-1);\n// const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError\n{\n};\n\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n if (a < b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n if (a > b)\n {\n a = b; // aをbで更新\n return true;\n }\n return false;\n}\n\nbool isprime(ll p)\n{\n if (p == 1)\n return false;\n for (ll i = 2; i * i <= p; i++)\n {\n if (p % i == 0)\n return false;\n }\n return true;\n}\n//エラトステネスの篩\nvector<bool> isprime_format(ll n)\n{\n vector<bool> P(n + 1, 1);\n P[0] = P[1] = 1;\n for (ll i = 2; i * i <= n; i++)\n {\n if (!P[i])\n continue;\n for (int j = i + i; j <= n; j += i)\n P[j] = false;\n }\n return P;\n}\nvector<ll> prime_format(ll n)\n{\n vector<bool> P = isprime_format(n);\n vector<ll> ans;\n for (int i = 2; i <= n; i++)\n {\n if (P[i])\n ans.push_back(i);\n }\n return ans;\n}\nll extGCD(ll a, ll b, ll &x, ll &y)\n{\n // ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n // 返り値: a と b の最大公約数\n // ax + by = gcd(a, b) を満たす (x, y) が格納される\n // main関数内に extGCD(a, b, x, y); でx, yに解が格納\n if (b == 0)\n {\n x = 1;\n y = 0;\n return a;\n }\n ll d = extGCD(b, a % b, y, x);\n y -= a / b * x;\n return d;\n}\nll keta(ll n)\n{\n ll res = 0;\n while (n >= 1)\n {\n // res++;\n res += n % 10;\n\n n /= 10;\n }\n return res;\n}\nll modpow(ll x, ll y, ll m)\n{\n ll res = 1;\n while (y)\n {\n if (y % 2)\n {\n res *= x;\n res %= m;\n }\n x = x * x % m;\n y /= 2;\n }\n return res;\n}\n\nunsigned int xorshift()\n{\n // xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n // 1~6まで出したいときは\n // xorshift() % 6 + 1\n static unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n unsigned int tt = (tx ^ (tx << 11));\n tx = ty;\n ty = tz;\n tz = tw;\n return (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\nuint64_t seed = 123456789;\nuint64_t xorshift64()\n{\n seed ^= seed << 13;\n seed ^= seed >> 17;\n seed ^= seed << 7;\n return seed;\n}\nint rand_int(int l, int r)\n{\n return l + int(xorshift64() % (r - l));\n}\ndouble randouble()\n{\n return double(xorshift64()) / double(uint64_t(-1));\n}\n\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> pp;\n//左上右下\nll dx[4] = {0, -1, 0, 1}, dy[4] = {-1, 0, 1, 0};\nll ndx[4] = {1, -1, -1, 1}, ndy[4] = {1, 1, -1, -1};\nchar ds[4] = {'l', 'u', 'r', 'd'};\nchar dl[4] = {'L', 'U', 'R', 'D'};\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n)\n{\n spf.resize(n + 1);\n spf[1] = 1;\n for (int i = 2; i <= n; i++)\n {\n if (!spf[i])\n {\n for (int j = i; j < n; j += i)\n {\n spf[j] = i;\n }\n }\n }\n}\nstd::map<int, int> high_speed_prime_factor(int n)\n{\n std::map<int, int> res;\n while (n != 1)\n {\n res[spf[n]]++;\n n /= spf[n];\n }\n return res;\n}\n\n////////////////////////////////struct\n\nstruct Comb\n{\n // https://atcoder.jp/contests/abc156/submissions/33741990\n\n ll nCrMAX;\n ll m;\n vector<ll> fac, finv, inv; // n!、1/n!、1/n\n\n Comb(ll kMOD, ll kMAX = 612345)\n {\n nCrMAX = kMAX;\n m = kMOD;\n fac.resize(nCrMAX);\n finv.resize(nCrMAX);\n inv.resize(nCrMAX);\n\n fac[0] = fac[1] = 1;\n finv[0] = finv[1] = 1;\n inv[1] = 1;\n for (int i = 2; i < nCrMAX; i++)\n {\n fac[i] = fac[i - 1] * i % m;\n inv[i] = m - inv[m % i] * (m / i) % m;\n finv[i] = finv[i - 1] * inv[i] % m;\n }\n }\n\n ll nCr(ll n, ll k)\n {\n if (k < nCrMAX)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n else\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n }\n\n ll nCr1(ll n, ll k)\n {\n if (n < k)\n return 0;\n if (n < 0 || k < 0)\n return 0;\n return fac[n] * (finv[k] * finv[n - k] % m) % m;\n }\n\n //(nが大きくて)kが小さい時\n // nCrMAXはk+2まででOK\n ll nCr2(ll n, ll k)\n {\n ll res = 1;\n for (int i = n - k + 1; i <= n; i++)\n {\n res *= i;\n res %= m;\n }\n res = res * finv[k] % m;\n return res;\n }\n};\n\nstruct status\n{\n ll v;\n ll p;\n\n // bool operator<(const status& rhs) const { return c < rhs.c; };\n // bool operator>(const status& rhs) const { return c > rhs.c; };\n bool operator<(const status &rhs) const { return v < rhs.v; };\n bool operator>(const status &rhs) const { return v > rhs.v; };\n};\nvoid yes(bool a) { cout << (a ? \"yes\" : \"no\") << endl; }\nvoid YES(bool a) { cout << (a ? \"YES\" : \"NO\") << endl; }\nvoid Yes(bool a) { cout << (a ? \"Yes\" : \"No\") << endl; }\nvoid Possible(bool a) { cout << (a ? \"Possible\" : \"Impossible\") << endl; }\n// struct edge {\n//\tll to; ll cost;\n// };\n\nstruct Point\n{\n ld x, y;\n Point operator+(const Point &p) const noexcept { return {x + p.x, y + p.y}; }\n Point operator-(const Point &p) const noexcept { return {x - p.x, y - p.y}; }\n Point operator*(const ld k) const noexcept { return {x * k, y * k}; }\n Point operator/(const ld k) const noexcept { return {x / k, y / k}; }\n Point &operator+=(const Point &p) noexcept\n {\n x += p.x;\n y += p.y;\n return *this;\n }\n Point &operator-=(const Point &p) noexcept\n {\n x -= p.x;\n y -= p.y;\n return *this;\n }\n bool operator<(const Point &p) const noexcept { return (x != p.x ? x < p.x : y < p.y); }\n\n ld abs() const noexcept { return sqrt(x * x + y * y); }\n ld norm() const noexcept { return x * x + y * y; }\n};\n\n// using mint = modint998244353;\n\nstruct edge\n{\n ll to, cost;\n};\n\nint main()\n{\n ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n // cout << fixed << setprecision(15);\n // priority_queue<ll, vector<ll>, greater<ll>> que;\n // priority_queue<P, vector<P>, greater<P>> que;\n // priority_queue<status, vector<status>, greater<status>> que;\n\n ll n, d, k;\n cin >> n >> d >> k;\n vector<ll> C(n), T(n), sT(n + 1);\n rep(i, n)\n {\n cin >> C[i] >> T[i];\n C[i]--;\n sT[i] = T[i]; // sort用\n }\n sT[n] = 0;\n sort(all(sT));\n T.erase(unique(all(sT)), sT.end());\n // 時間 t があった時、find(all(sT), t) - sT.begin(); で圧縮座標が分かる。\n // 時間 t があった時、z[t] で圧縮座標が分かる。\n map<ll, ll> z;\n rep(i, (int)sT.size())\n {\n z[sT[i]] = i;\n }\n vector<vector<bool>> Event(2, vector<bool>(n + 1));\n rep(i, n)\n {\n Event[C[i]][z[T[i]]] = true;\n }\n\n ll ans = 0;\n vector<vector<ll>> dp(2, vector<ll>(n + 1)); // dp[i][j]...街iに時間j(圧縮時間)の時にいるまでに行けるEventの数\n vector<vector<ll>> count(2, vector<ll>(n + 1, INF)); // count[i][k]...k個のイベントに参加した後に町iにいるような最小の時間\n count[0][0] = 0;\n count[1][0] = 0;\n rep2(j, n)\n {\n rep(i, 2)\n {\n ll ok = 0, ng = n + 1;\n while ((ng - ok) > 1)\n {\n ll mid = (ok + ng) / 2; //mid個のEvent\n if (count[1 - i][mid] <= sT[j] - (d + k * mid))\n {\n ok = mid;\n }\n else\n {\n ng = mid;\n }\n }\n\n bool is_Event = Event[i][j];\n dp[i][j] = max(dp[i][j - 1], ok) + is_Event;\n chmax(ans, dp[i][j]);\n\n chmin(count[i][dp[i][j]], sT[j] + 1);\n chmin(count[1-i][dp[i][j]], sT[j] + d + k * dp[i][j] + 1);\n //cout<<count[1-i][4] << ' ' << dp[i][j-1]<<' '<<ok<<endl;\n //cout<<i<<' '<<j<<' '<<dp[i][j]<<endl;\n //cout<<count[i][dp[i][j]]<<endl;\n }\n }\n\n cout << ans << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 28120, "score_of_the_acc": -1.9265, "final_rank": 12 }, { "submission_id": "aoj_0693_6969618", "code_snippet": "#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint main(){\n\tstatic int n,p[200000];\n\tstatic ll d,k,s[200000];\n\tcin>>n>>d>>k;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>p[i]>>s[i];\n\tstatic pair<ll,int>sp[200000];\n\tfor(int i=0;i<n;i++)\n\t\tsp[i]={s[i],p[i]};\n\tsort(sp,sp+n);\n\tfor(int i=0;i<n;i++)\n\t\ttie(s[i],p[i])=sp[i];\n\tvector<int>idx[2];\n\tfor(int i=0;i<n;i++)\n\t\tidx[--p[i]].push_back(i);\n\tstatic int dp[200000],ans=0;\n\tfor(int i=0;i<n;i++){\n\t\tint ok=-1,ng=idx[p[i]].size();\n\t\twhile(abs(ok-ng)>1){\n\t\t\tint mid=(ok+ng)/2;\n\t\t\tif(s[idx[p[i]][mid]]+1<=s[i])\n\t\t\t\tok=mid;\n\t\t\telse\n\t\t\t\tng=mid;\n\t\t}\n\t\tdp[i]=max(dp[i],(ok==-1?0:dp[idx[p[i]][ok]]));\n\t\tok=-1,ng=idx[!p[i]].size();\n\t\twhile(abs(ok-ng)>1){\n\t\t\tint mid=(ok+ng)/2;\n\t\t\tif(s[idx[!p[i]][mid]]+1+d+k*dp[idx[!p[i]][mid]]<=s[i])\n\t\t\t\tok=mid;\n\t\t\telse\n\t\t\t\tng=mid;\n\t\t}\n\t\tdp[i]=max(dp[i],(ok==-1?0:dp[idx[!p[i]][ok]]));\n\t\tdp[i]++;\n\t\tans=max(ans,dp[i]);\n\t}\n\tcout<<ans<<endl;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 10476, "score_of_the_acc": -0.5547, "final_rank": 7 }, { "submission_id": "aoj_0693_6639302", "code_snippet": "#include <iostream>\n#include <map>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nusing Int = int_fast64_t;\n\nint main()\n{\n\tint N; cin >> N;\n\tInt D, K; cin >> D >> K;\n\tvector<pair<Int, int>> SP(N); for (auto& [S, P] : SP) {cin >> P >> S; --P;}\n\tsort(SP.begin(), SP.end());\n\tvector<vector<int>> dp(N, vector<int>(2, 0));\n\tvector<map<Int, int>> S(2);\n\tauto [S0, P0] = SP[0];\n\tdp[0][P0] = 1;\n\tauto t = S0 + 1 + D + K;\n\tS[1 - P0][t] = 1;\n\tfor (int i = 1; i < N; ++i) {\n\t\tauto [Si, Pi] = SP[i];\n\t\tfor (int P = 0; P < 2; ++P) {\n\t\t\tdp[i][P] = dp[i - 1][P];\n\t\t\twhile (!S[P].empty()) {\n\t\t\t\tauto [t, n] = *S[P].begin();\n\t\t\t\tif (t > Si) break;\n\t\t\t\tdp[i][P] = max(dp[i][P], n);\n\t\t\t\tS[P].erase(S[P].begin());\n\t\t\t}\n\t\t}\n\t\t++dp[i][Pi];\n\t\tauto t = Si + 1 + D + K * dp[i][Pi];\n\t\tS[1 - Pi][t] = max(S[1 - Pi][t], dp[i][Pi]);\n\t}\n\tcout << max(dp.back()[0], dp.back()[1]) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 110, "memory_kb": 29608, "score_of_the_acc": -1.5, "final_rank": 10 }, { "submission_id": "aoj_0693_6410280", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint n; cin >> n;\n\tll D,K; cin >> D >> K;\n\tvector<vector<ll>> g(2);\n\tfor(int i=0;i<n;i++){\n\t\tint p; cin >> p;\n\t\tll s; cin >> s;\n\t\tg[p-1].push_back(s);\n\t}\n\tsort(g[0].begin(), g[0].end());\n\tsort(g[1].begin(), g[1].end());\n\tvector<vector<ll>> dp(2,vector<ll>(n+1,1e18));\n\tdp[0][0]=dp[1][0]=0;\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=0;j<2;j++){\n\t\t\t{\n\t\t\t\tint sz=g[j].end()-lower_bound(g[j].begin(), g[j].end(),dp[j][i-1]);\n\t\t\t\tif(sz>=1){\n\t\t\t\t\tdp[j][i]=min(dp[j][i],g[j][(int)(g[j].size())-sz]+1);\n\t\t\t\t}\n\t\t\t}\n\t\t\t{\n\t\t\t\tint sz=g[j].end()-lower_bound(g[j].begin(), g[j].end(),dp[j^1][i-1]+D+(i-1)*K);\n\t\t\t\tif(sz>=1){\n\t\t\t\t\tdp[j][i]=min(dp[j][i],g[j][(int)(g[j].size())-sz]+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tint res=0;\n\tfor(int i=0;i<2;i++){\n\t\tfor(int j=0;j<=n;j++){\n\t\t\tif(dp[i][j]!=1e18)res=max(res,j);\n\t\t}\n\t}\n\tcout << res << \"\\n\";\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 10012, "score_of_the_acc": -0.0318, "final_rank": 1 }, { "submission_id": "aoj_0693_6303051", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n\n\n\nint main() {\n\tint n; long long int d, k; std::cin >> n >> d >> k;\n\tstd::vector<std::pair<int, long long int>> all_events(n);\n\tfor (auto& [p, s] : all_events) {\n\t\tstd::cin >> p >> s; --p;\n\t}\n\tstd::sort(all_events.begin(), all_events.end(), [](const auto a, const auto b) {return a.second < b.second; });\n\tstd::vector<std::vector<long long int>> events(2);\n\tfor (const auto [p, s] : all_events) {\n\t\tevents[p].push_back(s);\n\t}\n\tstd::vector<std::vector<int>> max_event{std::vector<int>(events[0].size(), 1), std::vector<int>(events[1].size(), 1)};\n\tfor (auto i = 0; i < n; ++i) {\n\t\tconst auto [p, s] = all_events[i];\n\t\tconst auto pos = std::distance(events[p].begin(), std::lower_bound(events[p].begin(), events[p].end(), s));\n\t\tconst auto max = max_event[p][pos];\n\t\tconst auto succ = std::distance(events[p].begin(), std::upper_bound(events[p].begin(), events[p].end(), s));\n\t\tconst auto opposite = std::distance(events[1 - p].begin(), std::upper_bound(events[1 - p].begin(), events[1 - p].end(), s + d + k * max));\n\t\tif (succ < max_event[p].size()) {\n\t\t\tmax_event[p][succ] = std::max(max_event[p][succ], max + 1);\n\t\t}\n\t\tif (opposite < max_event[1 - p].size()) {\n\t\t\tmax_event[1 - p][opposite] = std::max(max_event[1 - p][opposite], max + 1);\n\t\t}\n\t}\n\tint result{ 0 };\n\tfor (const auto& max : max_event) {\n\t\tfor (const auto v : max) {\n\t\t\tresult = std::max(result, v);\n\t\t}\n\t}\n\tstd::cout << result << '\\n';\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 9368, "score_of_the_acc": -0.4167, "final_rank": 6 }, { "submission_id": "aoj_0693_6161479", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 200005\n\n\nll N,D,K;\nll P[SIZE],S[SIZE];\nll dp[2][SIZE];\nvector<ll> V[2];\n\nint main(){\n\n\tscanf(\"%lld %lld %lld\",&N,&D,&K);\n\n\t//■ダミー\n\tV[0].push_back(0);\n\tV[1].push_back(0);\n\n\tfor(ll i = 0; i < N; i++){\n\n\t\tscanf(\"%lld %lld\",&P[i],&S[i]);\n\t\tP[i]--;\n\n\t\tV[P[i]].push_back(S[i]);\n\t}\n\tfor(int i = 0; i <= 1; i++){\n\n\t\tsort(V[i].begin(),V[i].end());\n\t}\n\n\tfor(int i = 0; i <= 1; i++){\n\t\tfor(ll k = 0; k <= N; k++){\n\n\t\t\t//■訪問個数が同じなら、時刻が小さい方が良い\n\t\t\tdp[i][k] = HUGE_NUM; //dp[街][tまでにいくつ街を訪れたか] = 最小時刻(t)\n\t\t}\n\t}\n\n\tdp[0][0] = 0;\n\tdp[1][0] = 0;\n\n\tfor(ll i = 0; i <= N-1; i++){ //個数\n\t\tif(dp[0][i] != HUGE_NUM){\n\n\t\t\tll now = dp[0][i]; //現在時刻\n\n\t\t\t//■街0のまま\n\t\t\tll pos = lower_bound(V[0].begin(),V[0].end(),now+1)-V[0].begin();\n\t\t\tif(pos < V[0].size()){\n\n\t\t\t\tdp[0][i+1] = min(dp[0][i+1],V[0][pos]);\n\t\t\t}\n\t\t\t//■街1へ行く\n\t\t\tll cost = D+K*i+1;\n\n\t\t\tpos = lower_bound(V[1].begin(),V[1].end(),now+cost)-V[1].begin();\n\t\t\tif(pos < V[1].size()){\n\n\t\t\t\tdp[1][i+1] = min(dp[1][i+1],V[1][pos]);\n\t\t\t}\n\t\t}\n\t\tif(dp[1][i] != HUGE_NUM){\n\n\t\t\tll now = dp[1][i]; //現在時刻\n\n\t\t\t//■街1のまま\n\t\t\tll pos = lower_bound(V[1].begin(),V[1].end(),now+1)-V[1].begin();\n\t\t\tif(pos < V[1].size()){\n\n\t\t\t\tdp[1][i+1] = min(dp[1][i+1],V[1][pos]);\n\t\t\t}\n\t\t\t//■街0へ行く\n\t\t\tll cost = D+K*i+1;\n\n\t\t\tpos = lower_bound(V[0].begin(),V[0].end(),now+cost)-V[0].begin();\n\t\t\tif(pos < V[0].size()){\n\n\t\t\t\tdp[0][i+1] = min(dp[0][i+1],V[0][pos]);\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 0;\n\tfor(int i = 0; i <= N; i++){\n\t\tif(dp[0][i] != HUGE_NUM || dp[1][i] != HUGE_NUM){\n\n\t\t\tans = i;\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 11196, "score_of_the_acc": -0.0903, "final_rank": 4 } ]
aoj_0694_cpp
安全点検 JOI 市には 1 本の十分に長い道路がある.この道路は数直線とみなすことができ,各地点は 1 個の実数による座標で表される.また JOI 市にはこの道路に沿って N 個の施設が設置されており,座標の小さい順に 1 から N までの番号がつけられている.施設 i ( 1 ≦ i ≦ N ) の位置は座標 A i である. JOI 市ではこれから施設の安全点検が行われる.施設 i には点検しなければならない項目が B i 個ある.今,点検を行うことができる K 人の大工が集められた.安全点検の開始のとき,大工は全員が座標 0 にいる.点検が始まると,各大工は 1 分間で,次の 2 つの行動のどちらかをとることができる. 距離 1 だけ座標を移動する. 今いる座標にある施設の点検項目のうち, 1 個の項目を選んで点検する. 安全点検を終えるとき,すべての建物のすべての点検項目が, 1 人以上の大工によって点検されていなければならない. 大工の人数と施設の情報が与えられるので,安全点検を終えるのに最短で何分かかるかを求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 100000 . 1 ≦ K ≦ 10 9 . 1 ≦ A i ≦ 10 9 ( 1 ≦ i ≦ N ). A i < A i+1 ( 1 ≦ i ≦ N-1 ). 1 ≦ B i ≦ 10 9 ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N K A 1 A 2 … A N B 1 B 2 … B N 出力 標準出力に,安全点検を終えるのに最短で何分かかるかを 1 行で出力せよ. 入出力例 入力例 1 3 3 1 3 4 4 2 4 出力例 1 7 例えば,以下のように行動することで, 7 分間で点検を終えることができる.ただし 3 人の大工に番号をつけて,それぞれ大工 1,2,3 と表す. 大工 1,2,3 が座標 1 に移動する. 大工 1,2,3 がそれぞれ施設 1 の点検を 1 項目ずつ行う. 大工 1,2 が座標 2 に移動し,大工 3 が施設 1 の点検を 1 項目行う. 大工 1,2 が座標 3 に移動し,大工 3 が座標 2 に移動する. 大工 1,2 が座標 4 に移動し,大工 3 が座標 3 に移動する. 大工 1,2 がそれぞれ施設 3 の点検を 1 項目ずつ行い,大工 3 が施設 2 の点検を 1 項目行う. 大工 1,2 がそれぞれ施設 3 の点検を 1 項目ずつ行い,大工 3 が施設 2 の点検を 1 項目行う. どのように行動しても 7 分未満で点検を終えることはできないので 7 を出力する. 入力例 2 6 1 1 4 5 6 11 15 12 5 9 8 10 4 出力例 2 63 入力例 3 6 2 1 4 5 6 11 15 12 5 9 8 10 4 出力例 3 35 入力例 4 6 5 1 4 5 6 11 15 12 5 9 8 10 4 出力例 4 19 情報オリンピック日本委員会 作 『第 20 回日本情報オリンピック JOI 2020/2021 二次予選競技課題』
[ { "submission_id": "aoj_0694_10224737", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\n\nvoid solve(){\n ll N,K;\n cin>>N>>K;\n vector<ll> A(N),B(N);\n rep(i,N)cin>>A[i];\n rep(i,N)cin>>B[i];\n ll L=0,R=1e18;\n while(R-L>1){\n ll M=(R+L)/2;\n ll cnt=0;\n ll z=0;\n for(int i=N-1;i>=0;i--){\n if(M<=A[i]){\n cnt=K+10;\n break;\n } \n ll D=(M-A[i]);\n ll Z=max(0ll,B[i]-z);\n ll nc=(Z+D-1)/D;\n cnt+=nc;\n z=nc*D-Z;\n while(i>0&&B[i-1]<=z){\n z-=B[i-1];\n i--;\n }\n }\n (K>=cnt?R:L)=M;\n }\n cout<<R<<endl;\n}\n\nint main(){\n \n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int T=1;\n while(T--)\n solve();\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 4668, "score_of_the_acc": -0.4531, "final_rank": 2 }, { "submission_id": "aoj_0694_8753405", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, k;\n cin >> n >> k;\n vector<int> a(n), b(n);\n cin >> a >> b;\n\n ll l = a.back(), r = INF;\n while (r - l > 1) {\n ll m = (l + r) / 2;\n ll s = 0, re = 0;\n repr (i, n) {\n if (re >= b[i]) {\n re -= b[i];\n continue;\n }\n ll x = (b[i] - re - 1) / (m - a[i]) + 1;\n s += x;\n re = x * (m - a[i]) - (b[i] - re);\n }\n if (s <= k)\n r = m;\n else\n l = m;\n }\n co(r);\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3876, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0694_8307025", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N, K;\n cin >> N >> K;\n vector<long long> A(N), B(N);\n for (int i = 0; i < N; ++i) cin >> A[N-i-1];\n for (int i = 0; i < N; ++i) cin >> B[N-i-1];\n\n auto judge = [&](long long x) -> bool {\n long long sum = 0, amari = 0;\n for (int i = 0; i < N; ++i) {\n if (amari >= B[i]) {\n amari -= B[i];\n continue;\n }\n long long work = B[i] - amari;\n long long each = x - A[i];\n if (each <= 0) return false;\n long long num = (work + each - 1) / each;\n sum += num;\n amari = each * num - work;\n }\n return sum <= K;\n };\n\n long long left = 0, right = 1LL<<60;\n while (right - left > 1) {\n long long x = (left + right) / 2;\n if (judge(x)) right = x;\n else left = x;\n }\n cout << right << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4676, "score_of_the_acc": -1.2077, "final_rank": 6 }, { "submission_id": "aoj_0694_6410282", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint n; cin >> n;\n\tll K; cin >> K;\n\tvector<ll> a(n),b(n);\n\tfor(int i=0;i<n;i++){\n\t\tcin >> a[i];\n\t}\n\tfor(int i=0;i<n;i++){\n\t\tcin >> b[i];\n\t}\n\tll l=0,r=1e17;\n\twhile(r-l>1){\n\t\tll mid=(l+r)/2;\n\t\tif(a.back()>mid){\n\t\t\tl=mid;\n\t\t\tcontinue;\n\t\t}\n\t\tll cnt=0;\n\t\tll ty=0;\n\t\tvector<ll> bb=b;\n\t\tfor(int i=n-1;i>=0;i--){\n\t\t\tif(bb[i]<=ty){\n\t\t\t\tty-=bb[i];\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tbb[i]-=ty;\n\t\t\t\tty=0;\n\t\t\t}\n\t\t\tif(mid-a[i]==0){\n\t\t\t\tcnt=1e18;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tll num=(bb[i]+(mid-a[i]-1))/(mid-a[i]);\n\t\t\tcnt+=num;\n\t\t\tty=num*(mid-a[i])-bb[i];\n\t\t}\n\t\tif(cnt<=K){\n\t\t\tr=mid;\n\t\t}\n\t\telse{\n\t\t\tl=mid;\n\t\t}\n\t}\n\tcout << r << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5472, "score_of_the_acc": -0.913, "final_rank": 5 }, { "submission_id": "aoj_0694_6303254", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\n\nint main() {\n\tint n, k; std::cin >> n >> k;\n\tstd::vector<int> facility(n);\n\tfor (auto& a : facility) {\n\t\tstd::cin >> a;\n\t}\n\tstd::vector<int> check_list(n);\n\tfor (auto& b : check_list) {\n\t\tstd::cin >> b;\n\t}\n\tstd::reverse(facility.begin(), facility.end());\n\tstd::reverse(check_list.begin(), check_list.end());\n\tlong long int min = facility[0] + 1;\n\tlong long int max = LLONG_MAX >> 1;\n\twhile (min < max) {\n\t\tconst auto mid = (min + max) >> 1;\n\t\tint rest = k;\n\t\tlong long int time{ mid - facility[0]};\n\t\tfor (auto i = 0; i < n && 0 < rest; ++i) {\n\t\t\tauto check = check_list[i];\n\t\t\tif (check > time) {\n\t\t\t\tcheck -= time;\n\t\t\t\t--rest;\n\t\t\t\tconst auto free_time = mid - facility[i];\n\t\t\t\trest -= check / free_time;\n\t\t\t\tcheck %= free_time;\n\t\t\t\tif (check != 0) time = mid - facility[i];\n\t\t\t\telse time = (i + 1 < n) ? mid - facility[i + 1] : mid;\n\t\t\t}\n\t\t\ttime -= check;\n\t\t}\n\t\tif (rest <= 0) {\n\t\t\tmin = mid + 1;\n\t\t}\n\t\telse {\n\t\t\tmax = mid;\n\t\t}\n\t}\n\tstd::cout << max << '\\n';\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3896, "score_of_the_acc": -0.7614, "final_rank": 3 }, { "submission_id": "aoj_0694_6303247", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\n\nint main() {\n\tint n, k; std::cin >> n >> k;\n\tstd::vector<int> facility(n);\n\tfor (auto& a : facility) {\n\t\tstd::cin >> a;\n\t}\n\tstd::vector<int> check_list(n);\n\tfor (auto& b : check_list) {\n\t\tstd::cin >> b;\n\t}\n\tstd::reverse(facility.begin(), facility.end());\n\tstd::reverse(check_list.begin(), check_list.end());\n\tlong long int min = facility[0] + 1;\n\tlong long int max = LLONG_MAX >> 1;\n\twhile (min < max) {\n\t\tconst auto mid = (min + max) >> 1;\n\t\tint rest = k;\n\t\tlong long int time{ mid - facility[0]};\n\t\tfor (auto i = 0; i < n && 0 < rest; ++i) {\n\t\t\tauto check = check_list[i];\n\t\t\tif (check > time) {\n\t\t\t\tcheck -= time;\n\t\t\t\t--rest;\n\t\t\t\tconst auto free_time = mid - facility[i];\n\t\t\t\trest -= check / free_time;\n\t\t\t\tcheck %= free_time;\n\t\t\t\ttime = mid - facility[i];\n\t\t\t}\n\t\t\ttime -= check;\n\t\t}\n\t\tif (rest <= 0) {\n\t\t\tmin = mid + 1;\n\t\t}\n\t\telse {\n\t\t\tmax = mid;\n\t\t}\n\t}\n\tstd::cout << max << '\\n';\n}", "accuracy": 0.43333333333333335, "time_ms": 70, "memory_kb": 3900, "score_of_the_acc": -0.7637, "final_rank": 8 }, { "submission_id": "aoj_0694_6303215", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n\n\n\nint main() {\n\tint n, k; std::cin >> n >> k;\n\tstd::vector<int> facility(n);\n\tfor (auto& a : facility) {\n\t\tstd::cin >> a;\n\t}\n\tstd::vector<int> check_list(n);\n\tfor (auto& b : check_list) {\n\t\tstd::cin >> b;\n\t}\n\tlong long int min = (*std::max_element(facility.begin(), facility.end())) + 1;\n\tlong long int max = LLONG_MAX >> 1;\n\twhile (min < max) {\n\t\tconst auto mid = (min + max) >> 1;\n\t\tint rest = k;\n\t\tlong long int time{ 0 };\n\t\tfor (auto i = 0; i < n && 0 <= rest; ++i) {\n\t\t\tauto check = check_list[i];\n\t\t\tif (time + check + facility[i] > mid) {\n\t\t\t\tcheck -= mid - time - facility[i];\n\t\t\t\t--rest;\n\t\t\t\ttime = 0;\n\t\t\t\tconst int free_time = mid - facility[i];\n\t\t\t\trest -= check / free_time;\n\t\t\t\tcheck %= free_time;\n\t\t\t}\n\t\t\ttime += check;\n\t\t}\n\t\tif (rest < 0 || (rest == 0 && time > 0)) {\n\t\t\tmin = mid + 1;\n\t\t}\n\t\telse {\n\t\t\tmax = mid;\n\t\t}\n\t}\n\tstd::cout << max << '\\n';\n}", "accuracy": 0.05555555555555555, "time_ms": 40, "memory_kb": 3896, "score_of_the_acc": -0.0114, "final_rank": 9 }, { "submission_id": "aoj_0694_6264423", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n LL(n,k);\n vector<ll> a(n),b(n);\n in(a,b);\n auto f=[&](ll mid,vector<ll> c){\n int i=0;\n ll nxt=0,v,cnt=k;\n while(i<n){\n if(i>=1)nxt-=a[i]-a[i-1];\n if(nxt<0)nxt=0;\n c[i]-=nxt;\n v=updivide(c[i],mid-a[i]);\n nxt=(mid-a[i])*v-c[i];\n cnt-=v;\n if(cnt<0)return false;\n i++;\n }\n return (i==n);\n };\n ll l=a.back()+1,r=INF2,mid;\n while(l<r){\n mid=(l+r)/2;\n if(f(mid,b))r=mid;\n else l=mid+1;\n }\n out(l);\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 5624, "score_of_the_acc": -2, "final_rank": 7 }, { "submission_id": "aoj_0694_6161844", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 100005\n\nll N,K;\nll A[SIZE],B[SIZE];\n\nbool isOK(ll T){\n\n\tll POWER = 0;\n\tll rest = K;\n\n\t/*■なるべく左方に多くの余力を残す■*/\n\n\tfor(ll i = N-1; i >= 0; i--){\n\t\tif(rest == 0){ //全員が移動済\n\n\t\t\tif(POWER < B[i]){\n\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\tPOWER -= B[i];\n\n\t\t}else{ //新規に移動できる人あり\n\n\t\t\tll b = 0;\n\n\t\t\tif(POWER >= B[i]){\n\n\t\t\t\tPOWER -= B[i];\n\t\t\t\tcontinue;\n\n\t\t\t}else{ //余力不足\n\n\t\t\t\tb = B[i]-POWER;\n\t\t\t\tPOWER = 0;\n\t\t\t}\n\n\t\t\tll tmp = T-A[i]; //■人をA[i]に引っ張ってきた時の余力\n\t\t\tif(tmp <= 0){\n\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\tll need = (b+(tmp-1))/tmp;\n\n\t\t\tif(need > rest){\n\n\t\t\t\treturn false;\n\n\t\t\t}else{\n\t\t\t\trest -= need;\n\t\t\t\tPOWER = tmp*need-b;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\nint main(){\n\n\tscanf(\"%lld %lld\",&N,&K);\n\n\tfor(ll i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\tfor(ll i = 0; i < N; i++){\n\n\t\tscanf(\"%lld\",&B[i]);\n\t}\n\n\tll left = 0,right = 1e16,mid = (left+right)/2;\n\tll ans = 1e16;\n\n\twhile(left <= right){\n\t\tif(isOK(mid)){\n\n\t\t\tans = mid;\n\t\t\tright = mid-1;\n\t\t}else{\n\n\t\t\tleft = mid+1;\n\t\t}\n\t\tmid = (left+right)/2;\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4776, "score_of_the_acc": -0.7649, "final_rank": 4 } ]
aoj_0675_cpp
テンキー (Tenkey) 問題文 JOI 君はテンキーを 1 つ持っている.このテンキーには 0 から 9 までの数字が印字されているキーが以下の図のように配置されている. 2 が印字されたキーの下,および 3 が印字されたキーの下にはキーは存在しないことに注意せよ. またこのテンキーには,テンキーに配置されているキーのうち 1 つのキーを指し示すカーソルが存在している.カーソルは最初 0 が印字されているキーを指し示している. JOI 君は 1 回の操作で次のうちのいずれかを選んで行うことができる. カーソルを,現在カーソルが指し示しているキーと上下左右に隣接しているキーに移動させる.ただし,キーが存在しない場所にカーソルを移動させることはできない. キーを押す.すなわち,カーソルが指し示しているキーに印字されている数字を入力する.この際,以前の操作によってすでに数字が入力されていた場合,すでに入力されていた数字のすぐ右に新たな数字が入力される. いま,JOI 君はこのテンキーを使って, M で割った余りが R であるような正の整数を入力したいと考えている.テンキーの操作には時間がかかるので,なるべく少ない操作回数で入力したい. M と R が与えられるので,JOI 君が行う必要のある操作の回数の最小値を求めるプログラムを作成せよ. 制約 2 ≦ M ≦ 100 000 . 1 ≦ R < M . 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. M R 出力 M で割った余りが R であるような正の整数を入力するために必要な操作の回数の最小値を 1 行で出力せよ. 入出力例 入力例 1 100000 13 出力例 1 5 この例では,以下の 5 回の操作を行うことによって 13 を入力することが可能である. 4 回以下の操作によって条件を満たす整数を入力することは不可能であるので, 5 を出力する. カーソルを上に移動させる.カーソルが指し示すキーは 1 となる. キーを押す. 1 が入力される. カーソルを右に移動させる.カーソルが指し示すキーは 2 となる. カーソルを右に移動させる.カーソルが指し示すキーは 3 となる. キーを押す. 3 が新たに入力され,これまでに入力された数字は 13 となる. 入力例 2 4 3 出力例 2 3 この例では, 3 回の操作を行うことによって 11 を入力することが可能である. 3 を入力するには 4 回以上の操作を行わなければならず,最適ではないことに注意せよ. 情報オリンピック日本委員会 作 『第 19 回日本情報オリンピック JOI 2019/2020 一次予選競技課題』
[ { "submission_id": "aoj_0675_9609171", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n vvll D={{1},{0,2,4},{1,3,5},{2,6},{1,5,7},{2,4,6,8},{3,5,9},{4,8},{5,7,9},{6,8}};\n ll M,R;\n cin>>M>>R;\n vvll DP(10,vll(M,1e18));\n DP[0][0]=0;\n queue<pair<ll,ll>> Q;\n vector<vector<bool>> seen(10,vector<bool>(M,0));\n Q.push({0,0});\n while(!Q.empty()){\n ll p=Q.front().first;\n ll r=Q.front().second;\n Q.pop();\n if(seen[p][r])continue;\n if(!seen[p][(r*10+p)%M]){\n if(chmin(DP[p][(r*10+p)%M],DP[p][r]+1)){\n Q.push({p,(r*10+p)%M});\n }\n }\n for(auto v:D[p]){\n if(seen[v][r])continue;\n if(chmin(DP[v][r],DP[p][r]+1)){\n Q.push({v,r});\n }\n }\n }\n ll an=1e18;\n rep(i,10)chmin(an,DP[i][R]);\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 16332, "score_of_the_acc": -0.0377, "final_rank": 2 }, { "submission_id": "aoj_0675_8753940", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/graph/graph.hpp\"\n#include <iostream>\n#include <vector>\n\n/**\n * @brief 重み付きグラフ\n *\n * @tparam T 辺の重みの型\n */\ntemplate <class T>\nstruct Graph {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to(), _weight() {}\n constexpr _edge(int from, int to, T weight) : _from(from), _to(to), _weight(weight) {}\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr T weight() const { return _weight; }\n\n private:\n int _from, _to;\n T _weight;\n };\n\n public:\n using edge_type = typename Graph<T>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to, T weight = T(1)) { edges[from].emplace_back(from, to, weight); }\n void add_edges(int from, int to, T weight = T(1)) {\n edges[from].emplace_back(from, to, weight);\n edges[to].emplace_back(to, from, weight);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edge(from - base, to - base, weight);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edges(from - base, to - base, weight);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n\ntemplate <>\nstruct Graph<void> {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to() {}\n constexpr _edge(int from, int to) : _from(from), _to(to) {}\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr int weight() const { return 1; }\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n private:\n int _from, _to;\n };\n\n public:\n using edge_type = typename Graph<void>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to) { edges[from].emplace_back(from, to); }\n void add_edges(int from, int to) {\n edges[from].emplace_back(from, to);\n edges[to].emplace_back(to, from);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edge(from - base, to - base);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edges(from - base, to - base);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 4 \"/home/kuhaku/home/github/algo/lib/graph/dijkstra.hpp\"\n\n/**\n * @brief ダイクストラ法\n *\n * @tparam T 辺の重みの型\n * @param g グラフ\n * @param s 始点\n * @param inf 正の無限表現\n * @retval std::vector<T> 各頂点までの最短距離\n */\ntemplate <class T>\nstd::vector<T> dijkstra(const Graph<T> &g, int s = 0, T inf = std::numeric_limits<T>::max()) {\n struct _node {\n constexpr _node() : _to(), _dist() {}\n constexpr _node(int to, T dist) : _to(to), _dist(dist) {}\n constexpr bool operator<(const _node &rhs) const { return this->dist() < rhs.dist(); }\n constexpr bool operator>(const _node &rhs) const { return rhs < *this; }\n\n constexpr int to() const { return this->_to; }\n constexpr T dist() const { return this->_dist; }\n\n private:\n int _to;\n T _dist;\n };\n std::vector<T> dists(g.size(), inf);\n std::priority_queue<_node, std::vector<_node>, std::greater<>> p_que;\n dists[s] = T();\n p_que.emplace(s, T());\n while (!p_que.empty()) {\n auto node = p_que.top();\n p_que.pop();\n if (dists[node.to()] < node.dist()) continue;\n for (auto &e : g[node.to()]) {\n if (chmin(dists[e.to()], node.dist() + e.weight()))\n p_que.emplace(e.to(), node.dist() + e.weight());\n }\n }\n return dists;\n}\n\nstd::vector<int> dijkstra(const Graph<void> &g, int s = 0,\n int inf = std::numeric_limits<int>::max()) {\n std::vector<int> dists(g.size(), inf);\n std::queue<int> que;\n dists[s] = 0;\n que.emplace(s);\n while (!que.empty()) {\n auto index = que.front();\n que.pop();\n for (auto &e : g[index]) {\n if (chmin(dists[e.to()], dists[index] + 1)) que.emplace(e.to());\n }\n }\n return dists;\n}\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 5 \"a.cpp\"\n\nint main(void) {\n Graph<void> ten_key(10);\n ten_key.add_edges(0, 1);\n ten_key.add_edges(1, 2);\n ten_key.add_edges(1, 4);\n ten_key.add_edges(2, 3);\n ten_key.add_edges(2, 5);\n ten_key.add_edges(3, 6);\n ten_key.add_edges(4, 5);\n ten_key.add_edges(4, 7);\n ten_key.add_edges(5, 6);\n ten_key.add_edges(5, 8);\n ten_key.add_edges(6, 9);\n ten_key.add_edges(7, 8);\n ten_key.add_edges(8, 9);\n\n vector<vector<int>> d(10);\n rep (i, 10) d[i] = dijkstra(ten_key, i);\n\n int m, r;\n cin >> m >> r;\n Graph<int> g(m * 10);\n rep (i, m) {\n rep (j, 10) {\n rep (k, 10) {\n g.add_edge(i * 10 + j, (i * 10 + k) % m * 10 + k, d[j][k] + 1);\n }\n }\n }\n\n auto dist = dijkstra(g);\n ll ans = INF;\n rep (i, 10) chmin(ans, dist[r * 10 + i]);\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 400, "memory_kb": 243280, "score_of_the_acc": -1.1645, "final_rank": 12 }, { "submission_id": "aoj_0675_8532836", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0675.cc: テンキー (Tenkey)\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_M = 100000;\nconst int CNT = 30;\nconst int INF = 1 << 29;\n\n// 0 1 2 3 4 5 6 7 8 9\nconst int kxs[] = { 0, 0, 1, 2, 0, 1, 2, 0, 1, 2 };\nconst int kys[] = { 0, 1, 1, 1, 2, 2, 2, 3, 3, 3 };\n\n/* typedef */\n\n/* global variables */\n\nint es[10][10], dp[2][10][MAX_M];\n\n/* subroutines */\n\ninline void setmin(int &a, int b) { if (a > b) a = b; }\n\n/* main */\n\nint main() {\n for (int i = 0; i < 10; i++)\n for (int j = 0; j < 10; j++)\n es[i][j] = abs(kxs[j] - kxs[i]) + abs(kys[j] - kys[i]) + 1;\n\n int m, r;\n scanf(\"%d%d\", &m, &r);\n\n for (int i = 0; i < 10; i++) fill(dp[0][i], dp[0][i] + m, INF);\n dp[0][0][0] = 0;\n int cur = 0, nxt = 1;\n\n int mind = INF;\n for (int cnt = 0; cnt < CNT; cnt++) {\n for (int i = 0; i < 10; i++) fill(dp[nxt][i], dp[nxt][i] + m, INF);\n\n for (int i = 0; i < 10; i++)\n for (int j = 0; j < m; j++)\n\tif (dp[cur][i][j] < INF)\n\t for (int k = 0; k < 10; k++)\n\t setmin(dp[nxt][k][(j * 10 + k) % m], dp[cur][i][j] + es[i][k]);\n\n for (int i = 0; i < 10; i++) setmin(mind, dp[nxt][i][r]);\n\n swap(cur, nxt);\n }\n\n printf(\"%d\\n\", mind);\n return 0;\n}", "accuracy": 1, "time_ms": 630, "memory_kb": 10784, "score_of_the_acc": -1.0085, "final_rank": 10 }, { "submission_id": "aoj_0675_8495901", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cassert>\n#include <chrono>\n#include <random>\n#include <set>\n#include <utility>\n#include <array>\n#include <bitset>\n#include <unordered_set>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nvector<int> ten[10] = {\n {1},\n {0,2,4},\n {1,5,3},\n {2,6},\n {1,5,7},\n {2,4,6,8},\n {3,5,9},\n {4,8},\n {5,7,9},\n {6,8}\n}; \n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int m,r; cin >> m >> r;\n vector<vector<int>> dp(10, vector<int>(m, 1e9));\n dp[0][0] = 0;\n queue<pair<int,int>> q;\n q.push({0, 0});\n while (q.size()) {\n auto s = q.front(); q.pop();\n int cost = dp[s.first][s.second];\n if (s.second == r) {\n cout << cost << endl;\n break;\n }\n // move\n int d = s.first;\n for (int i : ten[d]) {\n if (dp[i][s.second] == 1e9) {\n dp[i][s.second] = cost+1;\n q.push({i, s.second});\n }\n }\n // push\n int nxt = (10*s.second+d)%m;\n if (dp[d][nxt] == 1e9) {\n dp[d][nxt] = cost+1;\n q.push({d, nxt});\n }\n }\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 9752, "score_of_the_acc": -0.0062, "final_rank": 1 }, { "submission_id": "aoj_0675_8326011", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[14][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n scanf(\"%d %d\", &m, &r);\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++) dp[0][i][j] = 32;\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<13;i++){\n fill_n(*dp[i+1], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i][j][l] + sosa(l, k);\n if(move>=ans || dp[i+1][next][k]<=move) continue;\n dp[i+1][next][k] = move;\n if(next == r) ans = min(ans, move);\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return(0);\n}", "accuracy": 1, "time_ms": 380, "memory_kb": 57924, "score_of_the_acc": -0.7068, "final_rank": 7 }, { "submission_id": "aoj_0675_8326009", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[14][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n scanf(\"%d %d\", &m, &r);\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++) dp[0][i][j] = 32;\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<13;i++){\n fill_n(*dp[i+1], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i][j][l] + sosa(l, k);\n if(move>=ans && dp[i+1][next][k]<=move) continue;\n dp[i+1][next][k] = move;\n if(next == r) ans = min(ans, move);\n }\n }\n }\n }\n printf(\"%d\\n\", ans);\n return(0);\n}", "accuracy": 0.7450980392156863, "time_ms": 480, "memory_kb": 57904, "score_of_the_acc": -0.8707, "final_rank": 19 }, { "submission_id": "aoj_0675_8325991", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[14][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++) dp[0][i][j] = 32;\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<13;i++){\n fill_n(*dp[i+1], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i][j][l] + sosa(l, k);\n if(move>=ans) continue;\n dp[i+1][next][k] = min(dp[i+1][next][k], move);\n if(next == r) ans = min(ans, dp[i+1][r][k]);\n }\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 360, "memory_kb": 57824, "score_of_the_acc": -0.6738, "final_rank": 6 }, { "submission_id": "aoj_0675_8325986", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[14][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++) dp[0][i][j] = 32;\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<13;i++){\n fill_n(*dp[i+1], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i][j][l] + sosa(l, k);\n dp[i+1][next][k] = min(dp[i+1][next][k], move);\n if(next == r) ans = min(ans, dp[i+1][r][k]);\n }\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 57824, "score_of_the_acc": -0.7721, "final_rank": 9 }, { "submission_id": "aoj_0675_8325960", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<12;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.7647058823529411, "time_ms": 360, "memory_kb": 10948, "score_of_the_acc": -0.5663, "final_rank": 18 }, { "submission_id": "aoj_0675_8325957", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<13;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 390, "memory_kb": 10924, "score_of_the_acc": -0.6154, "final_rank": 4 }, { "submission_id": "aoj_0675_8325953", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<14;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 420, "memory_kb": 10924, "score_of_the_acc": -0.6646, "final_rank": 5 }, { "submission_id": "aoj_0675_8325952", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<10;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.7647058823529411, "time_ms": 300, "memory_kb": 10948, "score_of_the_acc": -0.4679, "final_rank": 15 }, { "submission_id": "aoj_0675_8325939", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<14;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<10;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.7647058823529411, "time_ms": 300, "memory_kb": 10948, "score_of_the_acc": -0.4679, "final_rank": 15 }, { "submission_id": "aoj_0675_8325935", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<13;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<10;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.7647058823529411, "time_ms": 300, "memory_kb": 10924, "score_of_the_acc": -0.4679, "final_rank": 14 }, { "submission_id": "aoj_0675_8325933", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<12;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<10;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.7647058823529411, "time_ms": 300, "memory_kb": 10948, "score_of_the_acc": -0.4679, "final_rank": 15 }, { "submission_id": "aoj_0675_8325929", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=32;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 32;\n dp[1][i][j] = 32;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<15;i++){\n fill_n(*dp[(i+1)%2], m*10, 32);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n dp[(i+1)%2][next][k] = min(dp[(i+1)%2][next][k], move);\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 10924, "score_of_the_acc": -0.7138, "final_rank": 8 }, { "submission_id": "aoj_0675_8325910", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=33;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 33;\n dp[1][i][j] = 33;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<20;i++){\n fill_n(*dp[(i+1)%2], m*10, 33);\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n if(dp[(i+1)%2][next][k] > move){\n dp[(i+1)%2][next][k] = move;\n }\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 630, "memory_kb": 10920, "score_of_the_acc": -1.0089, "final_rank": 11 }, { "submission_id": "aoj_0675_8325849", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint dp[2][100000][10];\nint sosa(int a, int b){\n int res = 1+abs((a+2)/3-(b+2)/3);\n if(a==0) a=1;\n if(b==0) b=1;\n return res + abs((a+2)%3-(b+2)%3);\n}\nint main(){\n int m, r, ans=33;\n cin >> m >> r;\n for(int i=0;i<m;i++){\n for(int j=0;j<10;j++){\n dp[0][i][j] = 33;\n dp[1][i][j] = 33;\n }\n }\n for(int i=1;i<10;i++){\n dp[0][i%m][i] = sosa(0, i);\n if(i%m == r) ans = min(ans, sosa(0, i));\n }\n for(int i=0;i<20;i++){\n for(int j=0;j<m;j++){\n for(int k=0;k<10;k++){\n int next = (j*10+k)%m;\n dp[(i+1)%2][next][k] = 33;\n for(int l=0;l<10;l++){\n int move = dp[i%2][j][l] + sosa(l, k);\n if(dp[(i+1)%2][next][k] > move){\n dp[(i+1)%2][next][k] = move;\n }\n }\n if(next == r) ans = min(ans, dp[(i+1)%2][next][k]);\n }\n }\n }\n cout << ans << endl;\n return(0);\n}", "accuracy": 0.058823529411764705, "time_ms": 600, "memory_kb": 10840, "score_of_the_acc": -0.9595, "final_rank": 20 }, { "submission_id": "aoj_0675_7238713", "code_snippet": "#include <iostream>\n#include <vector>\n#include <cmath>\n#include <stdlib.h>\n#include <string.h>\n\nusing namespace std;\nstruct E{\n\tint x,y;\n};\nint dp[10][100002];\nvector<E> vs;\nint as[10][10];\nint main() {\n\tE e;\n\te.x=0;\n\te.y=3;\n\tvs.push_back(e);\n\tfor(int i=8;i>=0;i--){\n\t\te.y=i/3;\n\t\te.x=2-i%3;\n\t\tvs.push_back(e);\n\t}\n\t\n\tfor(int i=0;i<vs.size();i++){\n\t\tE e1=vs[i];\n\t\tfor(int j=0;j<vs.size();j++){\n\t\t\tE e2=vs[j];\n\t\t\tint t=abs(e1.x-e2.x)+abs(e1.y-e2.y)+1;\n\t\t\tas[i][j]=t;\n\t\t\t//cout<<\" \"<<t;\n\t\t}\n\t\t//cout<<endl;\n\t}\n\tint cr=-1,cd=-1;\n\tmemset(dp,-1,sizeof(dp));\n\tdp[0][0]=0;\n\tint m,r;\n\tcin>>m>>r;\n\tint z=0;\n\tint s1=1;\n\twhile(true){\n\t\tcd=-1;\n\t\tfor(int i=0;i<m;i++){\n\t\t\tfor(int n1=0;n1<10;n1++){\n\t\t\t\tif(dp[n1][i]==-1)continue;\n\t\t\t\t\n\t\t\t\tfor(int n2=s1;n2<10;n2++){\n\t\t\t\t\tint i2=(i*10+n2)%m;\n\t\t\t\t\tint t2=dp[n1][i]+as[n1][n2];\n\t\t\t\t\tif(dp[n2][i2]==-1 || dp[n2][i2]>t2){\n\t\t\t\t\t\tdp[n2][i2]=t2;\n\t\t\t\t\t\tif(i2==r){\n\t\t\t\t\t\t\tif(cr==-1||cr>t2)cr=t2;\n\t\t\t\t\t\t}else{\n\t\t\t\t\t\t\tif(cd==-1||cd>t2)cd=t2;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(s1==1 && dp[0][0]==0)dp[0][0]=-1;\n\t\t\t\ts1=0;\n\t\t\t}\n\t\t}\n\t\t\n\t\tif((cd==-1 && cr!=-1) ||(cr!=-1 && cr<=cd))break;\n\t\t//cout<<cr<<\" \"<<cd<<endl;\n\t}\n\tcout<<cr<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 7056, "score_of_the_acc": -0.2459, "final_rank": 3 }, { "submission_id": "aoj_0675_7072144", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\ntemplate<typename G>\nvector<ll> dijkstra(G &g,const vector<int>&s) {\n using PT=pair<ll,int>;\n priority_queue<PT, vector<PT>, greater<PT> > que;\n vector<ll>dist(g.size(),INF);\n for(auto v:s){\n dist[v] = 0;\n que.emplace(0, v);\n }\n while (!que.empty()) {\n PT p = que.top();\n que.pop();\n int v = p.second;\n if (dist[v] < p.first) continue;\n for(auto e:g[v]) {\n if (dist[e.to] > dist[v] + e.cost) {\n dist[e.to] = dist[v] + e.cost;\n que.emplace(dist[e.to], e.to);\n }\n }\n }\n return dist;\n}\ntemplate<typename G>\nvector<ll>dijkstra(G &g,int s=0){\n return dijkstra(g,vector<int>(1,s));\n}\ntemplate<typename T>\nvector<vector<T>>WarshallFloyd(vector<vector<T>>&matrix){\n vector<vector<T>>ret=matrix;\n ll sz=ret[0].size();\n for(ll i=0;i<sz;i++)ret[i][i]=0;\n for(ll j=0;j<sz;j++){\n for(ll i=0;i<sz;i++){\n for(ll o=0;o<sz;o++){\n if(ret[i][j]!=INF&&ret[j][o]!=INF){\n chmin(ret[i][o],ret[i][j]+ret[j][o]);\n }\n }\n }\n }\n return ret;\n}\ntemplate<typename T>\nvector<vector<ll>> WarshallFloyd(Graph<T>&g){\n ll n=g.size();\n vector<vector<ll>>ret(n,vector<ll>(n,INF));\n for(ll i=0;i<n;i++){\n ret[i][i]=0;\n for(auto e:g[i]){\n chmin(ret[i][e.to],e.cost);\n }\n }\n return WarshallFloyd(ret);\n} \nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll m,r;cin>>m>>r;\n\tvector<vector<ll>>v={{7,8,9},{4,5,6},{1,2,3},{0,-1,-1}};\n\tGraph<ll>gt(10);\n\trep(i,0,4)rep(j,0,3){\n\t\tif(v[i][j]==-1)continue;\n\t\trep(o,0,4){\n\t\t\tll ni=i+dx[o],nj=j+dy[o];\n\t\t\tif(ni<0||nj<0||ni>=4||nj>=3||v[ni][nj]==-1)continue;\n\t\t\tgt[v[i][j]].EB(v[ni][nj],1);\n\t\t}\n\t}\n\tauto d=WarshallFloyd(gt);\n\tGraph<ll>g(m*10);\n\trep(i,0,m){\n\t\trep(j,0,10){\n\t\t\trep(o,0,10){\n\t\t\t\tg[i*10+j].EB(((i*10+o)%m)*10+o,d[j][o]+1);\n\t\t\t}\n\t\t}\n\t}\n\tauto dd=dijkstra(g,0);\n\tll ret=INF;\n\trep(i,0,10)chmin(ret,dd[r*10+i]);\n\tcout<<ret<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 560, "memory_kb": 443264, "score_of_the_acc": -1.8852, "final_rank": 13 } ]
aoj_0674_cpp
桁和 (Digit Sum) 問題文 JOI 君は初めに 1 以上 N 以下のある整数を持っていた.JOI 君は以下の操作を 0 回以上行ったところ,持っている整数が N になった. 持っている整数を十進法で表したときの各桁の和を,持っている整数に足す. N が与えられるので,JOI 君が初めに持っていた可能性のある整数の個数を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 1 000 000 . N は整数である. 入力 入力は以下の形式で標準入力から与えられる. N 出力 JOI 君が初めに持っていた可能性のある整数の個数を 1 行で出力せよ. 入出力例 入力例 1 13 出力例 1 4 例えば JOI 君が初めに整数 5 を持っており, 3 回操作を行った場合 5 → 10 → 11 → 13 と変化する.JOI 君が初めに持っていた可能性のある整数は 5,10,11,13 の 4 個のみである. 入力例 2 20 出力例 2 1 入力例 3 2019 出力例 3 449 情報オリンピック日本委員会 作 『第 19 回日本情報オリンピック JOI 2019/2020 一次予選競技課題』
[ { "submission_id": "aoj_0674_10332291", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint f(int x){\n int res=x;\n while(x>0){\n res+=x%10;\n x/=10;\n }\n return res;\n}\n\nint main(){\n int n;\n cin >> n;\n vector<vector<int>> rev(n+1);\n for(int x=1;x<=n;x++){\n int y=f(x);\n if (y<=n){\n rev[y].push_back(x);\n }\n }\n vector<bool> visited(n+1,false);\n queue<int> que;\n visited[n]=true;\n que.push(n);\n\n int cnt=0;\n while(!que.empty()){\n int cur=que.front();\n que.pop();\n cnt++;\n for(int prev:rev[cur]){\n if(!visited[prev]){\n visited[prev]=true;\n que.push(prev);\n }\n }\n }\n cout << cnt << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 54936, "score_of_the_acc": -1.0395, "final_rank": 15 }, { "submission_id": "aoj_0674_8896489", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n set<ll> s;\n s.insert(N);\n rrep(i, 1, N) {\n ll t = i;\n ll sum = 0;\n while (t > 0) {\n sum += t % 10;\n t /= 10;\n }\n if (s.count(i+sum)) {\n s.insert(i);\n }\n }\n print(len(s));\n return 0;\n}", "accuracy": 1, "time_ms": 300, "memory_kb": 34188, "score_of_the_acc": -1.5831, "final_rank": 20 }, { "submission_id": "aoj_0674_7612302", "code_snippet": "#include <stdio.h>\n\nlong int getext(long int inval){\n long int i;\n int chkdig = 0;\n long int chkdif;\n long int extval;\n\n /* 入力値の桁数から下に検索する範囲を算出 */\n i = inval;\n while(i){\n\ti = i / 10;\n\tchkdig++;\n }\n /* 入力値桁数x9 */\n chkdif = chkdig * 9;\n return inval - chkdif;\n}\n\n\nlong int fact(long int chkval, long int cnt){\n /* 変数宣言 */\n long int i;\n long int extval;\n long int j;\n long int dig;\n long int sum;\n\n i = chkval;\n\n /* 入力値の桁数から下に検索する範囲を算出 */\n extval = getext(chkval);\n\n /* 入力値から0までの間で調査 */\n while(i > extval){\n\t i = i - 1;\n\n /*i+iの各桁の和を取得*/\n j = i;\n sum = j;\n while(j){\n dig = j % 10;\n sum = sum + dig;\n j = j / 10;\n }\n\n if(sum == chkval){ /* 和と入力値が一致する場合 */\n cnt = cnt + 1; /* カウントを加算 */\n cnt = fact(i,cnt); /* 再起関数再呼出 */\n }\n\n }\n return cnt;\n}\n\nint main() {\n /* 変数宣言 */\n long int inval = 0; /* 入力値 */\n long int cnt = 1; /* 対象値件数 */\n\n scanf(\"%ld\",&inval); /* 入力値取得 */\n cnt = fact(inval, cnt); /* 再起関数呼出 */\n printf(\"%ld\\n\", cnt); /* 結果出力 */\n \n return 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 4452, "score_of_the_acc": -0.8898, "final_rank": 13 }, { "submission_id": "aoj_0674_7612300", "code_snippet": "#include<stdio.h>\nint dSum(int n){\n\tif(n < 10) return n;\n\treturn dSum(n/10) + n%10;\n}\nint main(void)\n{\n\tint n,sum;\n\tscanf(\"%d\",&n);\n\tint ans[1000002] = {0};\n\n\tfor(int i=0; i<n; i++){\n\t ans[i] += 1;\n\t\tsum = dSum(i);\n\t\tif(i+sum <= n) ans[i+sum] += ans[i];\n\t}\n ans[n] += 1;\n\tprintf(\"%d\\n\",ans[n]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6664, "score_of_the_acc": -0.069, "final_rank": 1 }, { "submission_id": "aoj_0674_7612299", "code_snippet": "#include <stdio.h>\n\nlong int fact(long int inval, long int cnt){\n /* 変数宣言 */\n long int i;\n long int j;\n long int dig;\n long int sum;\n long int chkval;\n\n i = inval;\n chkval = inval;\n\n /* 入力値から0までの間で調査 */\n while(i > 0){\n\t i = i -1;\n\n /* 入力値より60小さくなった時点でもう\n 候補はないため、処理を抜ける */\n if (i < chkval - 60){\n break;\n }\n\n /*i+iの各桁の和を取得*/\n j = i;\n sum = j;\n while(j){\n dig = j % 10;\n sum = sum + dig;\n j = j / 10;\n }\n\n if(sum == chkval){ /* 和と入力値が一致する場合 */\n cnt = cnt + 1; /* カウントを加算 */\n cnt = fact(i,cnt); /* 再起関数再呼出 */\n }\n\n }\n return cnt;\n}\n\nint main() {\n /* 変数宣言 */\n long int inval = 0; /* 入力値 */\n long int cnt = 1; /* 対象値件数 */\n\n scanf(\"%ld\",&inval); /* 入力値取得 */\n cnt = fact(inval, cnt); /* 再起関数呼出 */\n printf(\"%ld\\n\", cnt); /* 結果出力 */\n \n return 0;\n}", "accuracy": 1, "time_ms": 280, "memory_kb": 4480, "score_of_the_acc": -0.9593, "final_rank": 14 }, { "submission_id": "aoj_0674_7197638", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T, class U>\nbool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nbool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing ll = int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid setp(int n) {\n std::cout << std::fixed << std::setprecision(n);\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n;\n cin >> n;\n vector<int> dp(n + 1, 1);\n rep(i, n) {\n string s = to_string(i);\n int x = 0;\n for (auto c : s) x += stoi(string(1, c));\n if (i + x <= n)\n dp[i + x] += dp[i];\n }\n co(dp[n]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 6972, "score_of_the_acc": -0.3851, "final_rank": 7 }, { "submission_id": "aoj_0674_7072226", "code_snippet": "#include<bits/stdc++.h>\n// #include<atcoder/segtree>\nusing namespace std;\n// using namespace atcoder;\n\n\nvoid solve(){\n\tint n;\n\tcin >> n;\n\tvector<bool> ok(n + 1, false);\n\tok[n] = true;\n\tint ans = 0;\n\n\tauto nex=[&](int x){\n\t\tif(x <= 0) return -1;\n\t\tint ret = x;\n\t\tint y = x;\n\t\twhile(y > 0){\n\t\t\tret += y % 10;\n\t\t\ty /= 10;\n\t\t}\n\t\treturn ret;\n\t};\n\n\tfor(int i = n; i >= 1; i--){\n\t\tif(!ok[i]) continue;\n\t\tans++;\n\t\tfor(int j = 1; j <= 54; j++){\n\t\t\tif(nex(i - j) == i) ok[i - j] = true;\n\t\t}\n\t}\n\tcout << ans << \"\\n\";\n\n}\n\nint main(){\n cin.tie(0)->sync_with_stdio(0);\n int t;\n t = 1;\n // cin >> t;\n while(t--) solve();\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3584, "score_of_the_acc": -0.6667, "final_rank": 12 }, { "submission_id": "aoj_0674_7072151", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VL = vector<ll>;\nusing VVL = vector<VL>;\nusing VS = vector<string>;\nusing P = pair<ll,ll>;\nusing VP = vector<P>;\n#define rep(i, n) for (ll i = 0; i < ll(n); i++)\n#define out(x) cout << x << endl\n#define dout(x) cout << fixed << setprecision(3) << x << endl\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define sz(x) (int)(x.size())\n#define re0 return 0\n#define pcnt __builtin_popcount\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n//const int INF = 1e9;\nconst ll INF = 1e18;\n//using mint = modint1000000007;\n//using mint = modint998244353;\nint di[4] = {1,0,-1,0};\nint dj[4] = {0,1,0,-1};\n\nset<ll> st;\n\nll ds(ll n){\n ll res = 0;\n while(n != 0){\n res += n%10;\n n /= 10;\n }\n return res;\n}\n\nvoid rec(ll n){\n if(n <= 0) return;\n if(st.count(n)) return;\n st.insert(n);\n for(int i = 1;i <= 60;i++){\n if(n-i <= 0) continue;\n if(i == ds(n-i)) rec(n-i);\n }\n return;\n}\n\nint main(){\n int n;\n cin >> n;\n rec(n);\n out(sz(st));\n}", "accuracy": 1, "time_ms": 270, "memory_kb": 36016, "score_of_the_acc": -1.5138, "final_rank": 19 }, { "submission_id": "aoj_0674_6997096", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0674.cc: 桁和 (Digit Sum)\n */\n\n#include<cstdio>\n#include<queue>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\n/* typedef */\n\ntypedef queue<int> qi;\n\n/* global variables */\n\n/* subroutines */\n\ninline int dsum(int n) {\n int sum = 0;\n while (n > 0) sum += n % 10, n /= 10;\n return sum;\n}\n\ninline int maxdsum(int n) {\n int sum = 0;\n while (n >= 10) sum += 9, n /= 10;\n return sum + n - 1;\n}\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n;\n scanf(\"%d\", &n);\n\n qi q;\n q.push(n);\n int cnt = 0;\n\n while (! q.empty()) {\n int u = q.front(); q.pop();\n cnt++;\n\n int mxd = min(u, max(dsum(u), maxdsum(u)));\n for (int d = 1; d <= mxd; d++) {\n int v = u - d;\n if (dsum(v) == d) q.push(v);\n }\n }\n\n printf(\"%d\\n\", cnt);\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 2968, "score_of_the_acc": -0.5172, "final_rank": 11 }, { "submission_id": "aoj_0674_6960094", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <iomanip>\n#include <limits>\n#include <bitset>\n// #include <atcoder/all>\n\nusing namespace std;\nusing ll = long long;\n\n#define _overload(_1, _2, _3, name, ...) name\n#define rep1(n) rep3(____, 0, n)\n#define rep2(i, n) rep3(i, 0, n)\n#define rep3(i, a, b) for (ll i=(a); i<(ll)(b); i++)\n#define rep(...) _overload(__VA_ARGS__, rep3, rep2, rep1)(__VA_ARGS__)\n\n#define rrep(i, a, b) for(ll i = a; i >= b; i--)\n#define fore(i, a) for(auto &i:a)\n#define all(x) (x).begin(),(x).end()\n#define pb push_back\n#define pii pair<int, int>\n#define pli pair<ll, int>\n#define pll pair<ll, ll>\n\n#define UNIQUIFY(v) v.erase( unique(v.begin(), v.end()), v.end() );\n#define out(x) {cout << x << \"\\n\";}\n#define dbg(x) {cerr << #x << \": \" << x << \"\\n\";}\n#define inc(x, l, r) ((l) <= (x) and (x) < (r))\n\nconst int INFI = 1 << 30;\nconst ll INFL = 1LL << 60;\n\n// const ll MOD = 998244353;\n// const ll MOD = 1000000007; // 1e9 + 7\n// using mint = atcoder::modint998244353;\n// using mint = atcoder::modint1000000007;\n\ntemplate <typename T>\nbool chmax(T& a, const T& b){ if(a < b){ a = b; return 1; } return 0; }\ntemplate <typename T>\nbool chmin(T& a, const T& b){ if(b < a){ a = b; return 1; } return 0; }\n\ntemplate<class... T>\nconstexpr auto min(T... a) {\n return min(initializer_list<common_type_t<T...>>{a...});\n}\ntemplate<class... T>\nconstexpr auto max(T... a) {\n return max(initializer_list<common_type_t<T...>>{a...});\n}\n\ntemplate<typename T>\nostream& operator << (ostream& os, vector<T> &v) {\n int sz = (int)v.size();\n for (int i = 0; i < sz; i++) {\n os << v[i] << (i == sz - 1 ? \"\" : \" \");\n }\n return os;\n}\n\nint dx[] = {0, -1, 0, 1, -1, -1, 1, 1};\nint dy[] = {-1, 0, 1, 0, 1, -1, -1, 1};\n\n// using Graph = vector<vector<int> >;\n\n\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int N; cin >> N;\n\n auto dgt_sum = [](int m) {\n int res = 0;\n while (m) {\n res += m % 10;\n m /= 10;\n }\n return res;\n };\n\n vector<int> dp(N+1, 1);\n rep(i, 1, N) {\n if (i + dgt_sum(i) <= N) {\n dp[i+dgt_sum(i)] += dp[i];\n }\n }\n\n cout << dp[N] << \"\\n\";\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6952, "score_of_the_acc": -0.0744, "final_rank": 2 }, { "submission_id": "aoj_0674_6946557", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint dp[1000010];\nint s(ll x){\n\tif(x<10) return x;\n\treturn s(x/10)+x%10;\n}\n\nint main(void){\n\tint i;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tint N;\n\tcin >> N;\n\n\tdp[N]=1;\n\tfor(i=N-1;i>=1;i--){\n\t\tint m=i+s(i);\n\t\tif(m<=N && dp[m]==1) dp[i]=1;\n\t}\n\n\tint ans=0;\n\tfor(i=1;i<=N;i++) ans+=dp[i];\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7048, "score_of_the_acc": -0.0762, "final_rank": 3 }, { "submission_id": "aoj_0674_6946375", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nll s(ll x){\n\tif(x<10) return x;\n\treturn s(x/10)+x%10;\n}\n\n\nll par[1000010],rk[1000010],sz[1000010];\n\nvoid init(ll n){\n\tREP(i,n+1){\n\t\tpar[i]=i;\n\t\trk[i]=0;\n\t\tsz[i]=1;\n\t}\n}\n\nll find(ll x){\n\tif(par[x]==x){\n\t return x;\n\t}else{\n\t return par[x]=find(par[x]);\n\t}\n}\n\nvoid unite(ll x,ll y){\n\tx=find(x); y=find(y);\n\tif(x==y) return;\n\tif(rk[x]<rk[y]){\n\t\tpar[x]=y;\n\t\tsz[y]=sz[x]+sz[y];\n\t}else{\n\t\tpar[y]=x;\n\t\tsz[x]=sz[x]+sz[y];\n\t\tif(rk[x]==rk[y]) rk[x]++;\n\t}\n}\n\nbool same(ll x,ll y){\n\n\treturn find(x)==find(y);\n}\n\nll size(ll x){\n\n\treturn sz[find(x)];\n}\n\nint main(void){\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tll N;\n\tcin >> N;\n\n\tinit(N);\n\tfor(ll i=1;i<N;i++) if(i+s(i)<=N) unite(i,i+s(i));\n\n\tcout << size(N) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26544, "score_of_the_acc": -0.4403, "final_rank": 8 }, { "submission_id": "aoj_0674_6946300", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint s(int x){\n\tif(x<10) return x;\n\treturn s(x/10)+x%10;\n}\n\n\nll par[1000010],rk[1000010],sz[1000010];\n\nvoid init(ll n){\n\tREP(i,n+1){\n\t\tpar[i]=i;\n\t\trk[i]=0;\n\t\tsz[i]=1;\n\t}\n}\n\nll find(ll x){\n\tif(par[x]==x){\n\t return x;\n\t}else{\n\t return par[x]=find(par[x]);\n\t}\n}\n\nvoid unite(ll x,ll y){\n\tx=find(x); y=find(y);\n\tif(x==y) return;\n\tif(rk[x]<rk[y]){\n\t\tpar[x]=y;\n\t\tsz[y]=sz[x]+sz[y];\n\t}else{\n\t\tpar[y]=x;\n\t\tsz[x]=sz[x]+sz[y];\n\t\tif(rk[x]==rk[y]) rk[x]++;\n\t}\n}\n\nbool same(ll x,ll y){\n\n\treturn find(x)==find(y);\n}\n\nll size(ll x){\n\n\treturn sz[find(x)];\n}\n\nint main(void){\n\tint i,j;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tll N;\n\tcin >> N;\n\n\tinit(N);\n\tfor(i=1;i<N;i++) unite(i,i+s(i));\n\n\tcout << size(N) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 26584, "score_of_the_acc": -0.4411, "final_rank": 9 }, { "submission_id": "aoj_0674_6946202", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint s(int x){\n\tif(x<10) return x;\n\treturn s(x/10)+x%10;\n}\n\n\nll par[1000010],rk[1000010],sz[1000010];\n\nvoid init(ll n){\n\tREP(i,n+1){\n\t\tpar[i]=i;\n\t\trk[i]=0;\n\t\tsz[i]=1;\n\t}\n}\n\nll find(ll x){\n\tif(par[x]==x){\n\t return x;\n\t}else{\n\t return par[x]=find(par[x]);\n\t}\n}\n\nvoid unite(ll x,ll y){\n\tx=find(x); y=find(y);\n\tif(x==y) return;\n\tif(rk[x]<rk[y]){\n\t\tpar[x]=y;\n\t\tsz[y]=sz[x]+sz[y];\n\t}else{\n\t\tpar[y]=x;\n\t\tsz[x]=sz[x]+sz[y];\n\t\tif(rk[x]==rk[y]) rk[x]++;\n\t}\n}\n\nbool same(ll x,ll y){\n\n\treturn find(x)==find(y);\n}\n\nll size(ll x){\n\n\treturn sz[find(x)];\n}\n\nint main(void){\n\tint i,j;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tll N;\n\tcin >> N;\n\n\tinit(N);\n\tunite(N,N);\n\tfor(i=1;i<N;i++){\n\t\tunite(i,i+s(i));\n\t}\n\n\tll ans=0;\n\tfor(i=1;i<=N;i++){\n\t if(same(i,N)) ans++;\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 26560, "score_of_the_acc": -0.4751, "final_rank": 10 }, { "submission_id": "aoj_0674_6709597", "code_snippet": "#include <bits/stdc++.h>\n//#include <atcoder/all>\n//using namespace atcoder;\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\ntemplate<class T>\nbool chmax(T& p, T q) {\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\ntemplate<class T>\nbool chmin(T& p, T q) {\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\nll modPow(long long a, long long n, long long p) {\n if (n == 0) return 1; // 0乗にも対応する場合\n if (n == 1) return a % p;\n if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;\n long long t = modPow(a, n / 2, p);\n return (t * t) % p;\n}\n\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n ll N;\n cin>>N;\n vvll G(N+1);\n for(ll i=1;i<=N;i++){\n ll j=i;\n ll n=i;\n rep(k,22){\n n+=j%10;\n j/=10;\n }\n if(n<=N)G[n].push_back(i);\n }\n vector<bool>seen(N+1,false);\n ll an=0;\n queue<ll> Q;\n Q.push(N);\n while(!Q.empty()){\n ll p=Q.front();\n Q.pop();\n if(seen[p])continue;\n seen[p]=1;\n an++;\n for(auto v:G[p]){\n if(!seen[v])Q.push(v);\n }\n } \n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 54868, "score_of_the_acc": -1.1417, "final_rank": 16 }, { "submission_id": "aoj_0674_6677252", "code_snippet": "#include <iostream>\n#include <set>\n#include <queue>\n#include <cmath>\n\nusing namespace std;\n\nint main()\n{\n\tint N; cin >> N;\n\tint I = ((int) log10((double) N) + 1) * 9;\n\tset<int> S;\n\tqueue<int> Q;\n\tfor (Q.push(N); !Q.empty(); Q.pop()) {\n\t\tauto n = Q.front();\n\t\tif (S.count(n) > 0) continue;\n\t\tS.insert(n);\n\t\tfor (int i = max(1, n - I), k = i; i < n; ++i, k = i) {\n\t\t\tfor (int j = i; j > 0; j /= 10) k += j % 10;\n\t\t\tif (k == n) Q.push(i);\n\t\t}\n\t}\n\tcout << S.size() << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 260, "memory_kb": 34524, "score_of_the_acc": -1.4514, "final_rank": 18 }, { "submission_id": "aoj_0674_6586657", "code_snippet": "#include <iostream>\n#include <vector>\n#include <list>\n#include <deque>\n#include <set>\n#include <map>\n#include <queue>\n#include <stack>\n#include <string>\n#include <algorithm>\n#include <numeric>\n#include <tuple>\n\nusing namespace std;\n\ntypedef long long ll;\n\nconstexpr int INF = 1 << 30;\nconstexpr ll INFLL = 1LL << 60;\nconstexpr ll MOD = 1'000'000'007;\n\nvector<vector<int>> G;\n\nint DFS(int v, int p) {\n int Ret = 1;\n for (int u : G[v]) {\n if (u == p) continue;\n Ret += DFS(u, v);\n }\n return Ret;\n}\n\nint main()\n{\n int N;\n cin >> N;\n\n G.resize(N + 1);\n for (int n = 1; n < N; ++n) {\n int t = n;\n int s = 0;\n while (t) {\n s += t % 10;\n t /= 10;\n }\n s += n;\n if (s <= N) {\n G[s].emplace_back(n);\n }\n }\n cout << DFS(N, -1) << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 56512, "score_of_the_acc": -1.1724, "final_rank": 17 }, { "submission_id": "aoj_0674_5951941", "code_snippet": "#include<iostream>\n\nusing namespace std;\n\nint DigitSum(int n)\n{\n\tint res = 0;\n\twhile (n != 0)\n\t{\n\t\tres += n % 10;\n\t\tn /= 10;\n\t}\n\n\treturn res;\n}\n\nint main()\n{\n\tint N;\n\tcin >> N;\n\tint* dp = new int[N + 1];\n\tfill(dp, dp + N + 1, 1);\n\tfor (int i = 1; i <= N; i++)\n\t{\n\t\tif (i + DigitSum(i) <= N)\n\t\t\tdp[i + DigitSum(i)] += dp[i];\n\t}\n\tcout << dp[N] << endl;\n\n\t//system(\"pause\");\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7256, "score_of_the_acc": -0.0801, "final_rank": 4 }, { "submission_id": "aoj_0674_5935333", "code_snippet": "#include <iostream>\n#include <vector>\n#include <stack>\nusing namespace std;\n\nint N;\nvector<int> v((1 << 20), 0);\n\nint func(int x)\n{\n stack<int> stk;\n for(int cnt = 1;;cnt++)\n {\n stk.push(x);\n v[x] = 1;\n if (x == N)\n {\n while (!stk.empty())\n {\n v[stk.top()] = 2;\n stk.pop();\n }\n return cnt;\n }\n\n int y = x;\n while (y > 0)\n {\n x += (y % 10);\n y /= 10;\n }\n\n if (x > N) break;\n if (v[x] == 2)\n {\n while (!stk.empty())\n {\n v[stk.top()] = 2;\n stk.pop();\n }\n return cnt;\n }\n if (v[x] == 1) break;\n }\n return 0;\n}\n\nint main() {\n cin >> N;\n int total = 0;\n for (int i = 1; i <= N; ++i)\n {\n if (v[i] > 0) continue;\n total += func(i);\n }\n cout << total << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 7272, "score_of_the_acc": -0.1493, "final_rank": 5 }, { "submission_id": "aoj_0674_5801925", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<stack>\n#include<queue>\n#include<set>\n#include<map>\n#include<list>\n#include<algorithm>\n#include<numeric>\n#include<cmath>\n#include<iomanip>\n#include<sstream>\n#include<regex>\n#include<random>\nusing namespace std;\n#define int long long\n#define uint unsigned long long\nconst int mod=1e9+7;\nconst int Mod=998244353;\nconst int inf=mod*mod;\nconst double eps=1e-9;\nint ans[1000001];\nsigned main(){\n\tint n;\n\tcin>>n;\n\tfill(ans,ans+n+1,1);\n\tfor(int i=1;i<=n;i++){\n\t\tstring s=to_string(i);\n\t\tint sum=accumulate(s.begin(),s.end(),0)-'0'*s.size()+i;\n\t\tif(sum<=n)\n\t\t\tans[sum]+=ans[i];\n\t}\n\tcout<<ans[n]<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 11276, "score_of_the_acc": -0.2931, "final_rank": 6 } ]
aoj_0673_cpp
いちご (Strawberry) 問題文 Just Oishi Ichigo 農園 (以下 JOI 農園) は東西に細長いことで有名ないちご農園であり,その入り口は農園の最も西にある.以下では,入り口から東に k メートル進んだ場所を地点 k と呼ぶことにする. JOI 農園内には N 個のいちごがなっている.それぞれ 1 から N の番号がつけられている.どのいちごも時刻 0 までは青い.いちご i ( 1 ≦ i ≦ N ) は地点 A i に実をつけており,時刻 T i になると熟し赤い状態になる. いちごは青い状態では収穫できない.つまり,いちご i は時刻 T i となるまで収穫できない.あなたは時刻 0 に地点 0 にある農園の入り口から出発して,最大秒速 1 メートルで東西方向に移動しながらいちごを収穫する.いちごを収穫するのにかかる時間は無視できるとする. いちご農園についての情報が与えられるので,すべてのいちごを赤い状態で収穫したあと入り口に帰ってくるまでにかかる時間の最小値を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 100 000 . 0 ≦ A i ≦ 1 000 000 000 (= 10 9 ) ( 1 ≦ i ≦ N ). 0 ≦ T i ≦ 1 000 000 000 (= 10 9 ) ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N A 1 T 1 A 2 T 2 : A N T N 出力 すべてのいちごを赤い状態で収穫したあと入り口に帰ってくるまでにかかる時間の最小値を 1 行に出力せよ. 入出力例 入力例 1 10 1 3 2 1 3 4 4 1 5 5 6 9 7 2 8 6 9 5 10 3 出力例 1 20 はじめの 10 秒かけて地点 10 まで移動すると,その道中でいちご 2, 4, 5, 7, 8, 9, 10 をこの順に収穫することができる.その後 10 秒かけて地点 0 まで戻ると,その道中でいちご 6, 3, 1 をこの順に収穫することができる.これで 10 個すべてのいちごを赤い状態で収穫することができる. 入力例 2 10 0 450 5 445 10 430 15 405 20 370 25 325 30 270 35 205 40 130 45 45 出力例 2 450 以下のように移動すると 450 秒ですべてのいちごを赤い状態で収穫できる. 45 秒かけて地点 45 まで移動する.このとき時刻 45 なのでいちご 10 を収穫できる.収穫後 45 秒かけて地点 0 まで移動する. その後, 40 秒かけて地点 40 まで移動する.このとき時刻 130 なのでいちご 9 を収穫できる.収穫後 40 秒かけて地点 0 まで移動する. その後, 35 秒かけて地点 35 まで移動する.このとき時刻 205 なのでいちご 8 を収穫できる.収穫後 35 秒かけて地点 0 まで移動する. その後, 30 秒かけて地点 30 まで移動する.このとき時刻 270 なのでいちご 7 を収穫できる.収穫後 30 秒かけて地点 0 まで移動する. その後, 25 秒かけて地点 25 まで移動する.このとき時刻 325 なのでいちご 6 を収穫できる.収穫後 25 秒かけて地点 0 まで移動する. その後, 20 秒かけて地点 20 まで移動する.このとき時刻 370 なのでいちご 5 を収穫できる.収穫後 20 秒かけて地点 0 まで移動する. その後, 15 秒かけて地点 15 まで移動する.このとき時刻 405 なのでいちご 4 を収穫できる.収穫後 15 秒かけて地点 0 まで移動する. その後, 10 秒かけて地点 10 まで移動する.このとき時刻 430 なのでいちご 3 を収穫できる.収穫後 10 秒かけて地点 0 まで移動する. その後, 5 秒かけて地点 5 まで移動する.このとき時刻 445 なのでいちご 2 を収穫できる.収穫後 5 秒かけて地点 0 まで移動する. ちょうど時刻 450 に地点 0 に到達するので,いちご 1 を収穫できる.すべてのいちごを収穫すると同時に地点 0 に到着した. 入力例 3 15 11 23 3 94 89 3 38 58 65 29 41 3 80 42 22 76 48 85 83 98 87 29 97 96 22 75 57 25 99 33 出力例 3 198 情報オリンピック日本委員会 作 『第 19 回日本情報オリンピック JOI 2019/2020 一次予選競技課題』
[ { "submission_id": "aoj_0673_10877263", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<cmath>\n\nusing namespace std;\n\nint MIN = -1e9;\nconst int MOD = 10000;\n\nint main() {\n\tint N;\n\tcin >> N;\n\tint mans = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tint a, t;\n\t\tcin >> a >> t;\n\t\tt = max(a, t);\n\t\tmans = max(mans, t + a);\n\t}\n\n\tcout << mans<<endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3428, "score_of_the_acc": -0.5, "final_rank": 10 }, { "submission_id": "aoj_0673_10850721", "code_snippet": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n cin.tie(0);\n ios::sync_with_stdio(0);\n \n int N; cin >> N;\n vector<pair<ll,ll>> p(N);\n rep(i,N) cin >> p[i].first >> p[i].second;\n sort(p.begin(), p.end());\n\n ll x = max(p.back().first, p.back().second);\n for(int i = N - 2; i >= 0; i--) {\n x = max(x + p[i + 1].first - p[i].first, p[i].second);\n }\n cout << x + p[0].first << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4660, "score_of_the_acc": -0.236, "final_rank": 7 }, { "submission_id": "aoj_0673_10454200", "code_snippet": "#include<stdio.h>\n#include<algorithm>\nusing namespace std;\nstruct k{\n\tint a, t;\n};\nbool cmp(k a, k b){\n\treturn a.a>b.a;\n}\nk k[100000]={};\nint main(){\n\tint n, l=0;\n\t\n\tscanf(\"%d\", &n);\n\tfor(int i=0; i<n; i++){\n\t\tscanf(\"%d %d\", &k[i].a, &k[i].t);\n\t\tl=max(l, k[i].a);\n\t}\n\tsort(k, k+n, cmp);\n\tint t=l, b=l;\n\tfor(int i=0; i<n; i++){\n\t\tt+=b-k[i].a;\n\t\tb=k[i].a;\n\t\tif(t<k[i].t) t=k[i].t;\n\t}\n\tprintf(\"%d\\n\", t+b);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3768, "score_of_the_acc": -0.0651, "final_rank": 5 }, { "submission_id": "aoj_0673_10241265", "code_snippet": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\nconst int N = 707;\n\nvoid start() {\n ios_base::sync_with_stdio(0); cin.tie(nullptr); cout.tie(nullptr);\n // freopen(\".inp\",\"r\",stdin);\n // freopen(\".out\",\"w\",stdout);\n}\n\nstruct dl {\n ll a, b;\n} a[200005];\n\nbool cmp(dl a,dl b) {\n if(a.a == b.a) return a.b > b.b;\n return a.a < b.a;\n}\n\nll n;\nint main() \n{\n start();\n cin >> n;\n for(int i=1; i<=n; ++i)\n cin >> a[i].a >> a[i].b;\n sort(a+1,a+n+1,cmp);\n ll ok = a[n].a;\n \n a[n+1].a = a[n].a;\n a[0].a = 0; a[0].b = 0;\n \n int i = n;\n while(i >= 0) {\n ok = max(ok + a[i+1].a-a[i].a, a[i].b);\n --i;\n }\n cout << ok << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5012, "score_of_the_acc": -0.4701, "final_rank": 9 }, { "submission_id": "aoj_0673_10223477", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 1e5 + 5;\nbool bao[N]; int n; pair <int, int> pr[N];\n\nvoid solve () {\n cin >> n;\n pr[0] = {0, 0};\n for (int i = 1; i <= n; ++i) {\n cin >> pr[i].first >> pr[i].second;\n }\n sort (pr + 1, pr + n + 1);\n int tg = pr[n].first;\n for (int i = n; i >= 1; --i) {\n if (tg >= pr[i].second) {\n tg += (pr[i].first - pr[i - 1].first);\n }\n else {\n tg = pr[i].second;\n }\n }\n cout << tg << \"\\n\";\n}\n\nint main () {\n\t#define file \"ILYBVM\"\n\tif (fopen(file\".inp\",\"r\")) {\n\t\tfreopen(file\".inp\",\"r\",stdin);\n\t\tfreopen(file\".out\",\"w\",stdout);\n\t}\n\tcin.tie(0) -> sync_with_stdio(0);\n\tcout.tie(0) -> sync_with_stdio(0);\n\tint q = 1;\n\t// cin >> q;\n\twhile (q--) {\n\t\tsolve();\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4232, "score_of_the_acc": -0.154, "final_rank": 6 }, { "submission_id": "aoj_0673_10222652", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define MASK(i) (1LL << (i))\n#define BIT(x, i) (((x) >> (i)) & 1LL)\n\nusing ll = long long;\n\nconst int mxn = 9 + 1e6;\nconst int inf = 0x3f3f3f3f;\nconst ll lnf = 0x3f3f3f3f3f3f3f3f;\n\nvoid _27augain(void) {\n int n;\n cin >> n;\n ll res = 0, mx = 0;\n for (int i = 0; i < n; ++i) {\n ll a, t;\n cin >> a >> t;\n mx = max(mx, a);\n res = max({res, a + t, mx * 2});\n } \n cout << res << \"\\n\";\n}\n\nint32_t main(void) {\n#define task \"_27augain\"\n cin.tie(0)->sync_with_stdio(0);\n for (string iext : {\"in\", \"inp\"}) {\n if (fopen((task \".\" + iext).c_str(), \"r\")) {\n freopen((task \".\" + iext).c_str(), \"r\", stdin);\n freopen(task \".out\", \"w\", stdout);\n }\n }\n int testcase = 1;\n // cin >> testcase;\n while (testcase--) { \n _27augain();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3504, "score_of_the_acc": -0.0146, "final_rank": 3 }, { "submission_id": "aoj_0673_10222522", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define fi first\n#define se second\n#define i32 int32_t\n#define ll long long\n#define ldb long double\n#define pb push_back\n#define sz size()\n#define el '\\n'\n#define BIT(x,i) (((x)>>(i))&1)\n#define pll pair<ll,ll>\n#define pii pair<int,int>\n\nconst int mod = 1e9 + 7;\n\nint n;\npll x[100005];\nll a[100005] , t[100005];\nll dp[100005];\n\nvoid solve() {\n cin >> n;\n for(int i = 1 ; i <= n ; i++){\n cin >> x[i].fi >> x[i].se;\n }\n sort(x + 1 , x + 1 + n);\n for(int i = 1 ; i <= n ; i++){\n a[i] = x[i].fi;\n t[i] = x[i].se;\n }\n dp[n] = max(a[n] , t[n]);\n for(int i = n-1 ; i >= 1 ; i--){\n if(dp[i+1] + a[i+1] - a[i] < t[i]) {\n dp[i] = t[i];\n }\n else dp[i] = dp[i+1] + a[i+1] - a[i];\n }\n cout << dp[1] + a[1] << el;\n}\n\ni32 main() {\n#define TASKNAME \"betterdayswillcome\"\n if (fopen(TASKNAME \".inp\", \"r\")) {\n freopen(TASKNAME \".inp\", \"r\", stdin);\n freopen(TASKNAME \".out\", \"w\", stdout);\n }\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n cout.tie(0);\n int testt = 1;\n while (testt--) {\n solve();\n }\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 7372, "score_of_the_acc": -0.9222, "final_rank": 15 }, { "submission_id": "aoj_0673_10222259", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define st first\n#define nd second\n\nint main() {\n// freopen(\"CHAND.inp\", \"r\", stdin);\n// freopen(\"CHAND.out\", \"w\", stdout);\n int n;\n cin >> n;\n int ans = 0, a, t;\n for (int i = 0; i < n; i++) {\n cin >> a >> t;\n ans = max(ans, max(a, t) + a);\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3432, "score_of_the_acc": -0.5008, "final_rank": 11 }, { "submission_id": "aoj_0673_9652111", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define N 100010\n#define ll long long\n\nint n;\npair <int, int> p[N];\nll dp[N];\n\nint main(){\n\tcin >> n;\n\tfor (int i = 1; i <= n; i++) cin >> p[i].first >> p[i].second;\n\tsort(p + 1, p + n + 1);\n\tdp[n] = max(p[n].first, p[n].second);\n\tfor (int i = n - 1; i >= 1; i--) {\n\t\tdp[i] = max(dp[i + 1] + p[i + 1].first - p[i].first, (ll)p[i].second);\n\t}\t\n\tcout << dp[1] + p[1].first << endl;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 4700, "score_of_the_acc": -1.077, "final_rank": 16 }, { "submission_id": "aoj_0673_8983234", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned int N, i, A, T, R, ans = 0;\n\tcin >> N;\n\n\tfor (i = 0; i != N; ++i)\n\t{\n\t\tcin >> A >> T;\n\t\tR = max(A, T) + A;\n\t\tif (R > ans) ans = R;\n\t}\n\n\tcout << ans << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": -0.0054, "final_rank": 1 }, { "submission_id": "aoj_0673_8899396", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, A, T;\n cin >> N;\n vc<pi> AT(N);\n rep(i, N) {\n cin >> A >> T;\n AT[i] = mp(A, T);\n }\n sort(all(AT));\n ll ans = max(AT[N-1].fi, AT[N-1].se);\n rrep(i, N-1) {\n ans += AT[i+1].fi - AT[i].fi;\n chmax(ans, AT[i].se);\n }\n ans += AT[0].fi;\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4664, "score_of_the_acc": -0.4034, "final_rank": 8 }, { "submission_id": "aoj_0673_7197637", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\nusing namespace std;\ntemplate <class T, class U>\nbool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nbool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing ll = int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid setp(int n) {\n std::cout << std::fixed << std::setprecision(n);\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n;\n cin >> n;\n ll ans = 0;\n rep(i, n) {\n ll a, t;\n cin >> a >> t;\n chmax(ans, max(a, t) + a);\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3456, "score_of_the_acc": -0.0054, "final_rank": 1 }, { "submission_id": "aoj_0673_7132987", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n int n, time = 0;\n cin >> n;\n int a, t;\n vector<vector<int> > berry(n, vector<int>(2));\n for (int i = 0; i < n; i++)\n {\n cin >> a >> t;\n berry[i][0] = a;\n berry[i][1] = t;\n }\n sort(berry.begin(), berry.end());\n time += berry[n - 1][0];\n for (int i = n - 2; i >= 0; i--)\n {\n time += berry[i + 1][0] - berry[i][0];\n if (time < berry[i][1])\n time += berry[i][1] - time;\n }\n time += berry[0][0];\n cout << time << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 8428, "score_of_the_acc": -1.9579, "final_rank": 19 }, { "submission_id": "aoj_0673_7132968", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n int n, time = 0;\n cin >> n;\n int a, t;\n vector<vector<int>> berry(n, vector<int>(2));\n for (int i = 0; i < n; i++)\n {\n cin >> a >> t;\n berry[i][0] = a;\n berry[i][1] = t;\n }\n sort(berry.begin(), berry.end());\n time += berry[n - 1][0];\n for (int i = n - 2; i >= 0; i--)\n {\n time += berry[i + 1][0] - berry[i][0];\n if (time < berry[i][1])\n time += berry[i][1] - time;\n }\n time += berry[0][0];\n cout << time << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8648, "score_of_the_acc": -1.6667, "final_rank": 18 }, { "submission_id": "aoj_0673_7127336", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main()\n{\n int n, timer;\n cin >> n;\n vector<vector<int>> a(n, vector<int>(2));\n int t;\n for (int i = 0; i < n; i++)\n {\n cin >> a[i][0] >> t;\n a[i][1] = t;\n }\n sort(a.begin(), a.end());\n timer = a[n - 1][0];\n if (a[n - 1][1] > timer)\n timer += a[n - 1][1] - timer;\n for (int i = n - 2; i >= 0; i--)\n {\n timer += a[i + 1][0] - a[i][0];\n if (a[i][1] > timer)\n timer += a[i][1] - timer;\n }\n timer += a[0][0];\n cout << timer << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8576, "score_of_the_acc": -1.6529, "final_rank": 17 }, { "submission_id": "aoj_0673_7127324", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main()\n{\n int n, timer;\n cin >> n;\n vector<int> a(n);\n int t[n][2];\n for (int i = 0; i < n; i++)\n {\n cin >> a[i] >> t[i][0];\n t[i][1] = i;\n }\n sort(a.begin(), a.end());\n timer = a[n - 1];\n if (t[n - 1][0] > timer)\n timer += t[n - 1][0] - timer;\n for (int i = n - 2; i >= 0; i--)\n {\n timer += a[i + 1] - a[i];\n if (t[i][0] > timer)\n timer += t[i][0] - timer;\n }\n timer += a[0];\n cout << timer << endl;\n}", "accuracy": 0.2826086956521739, "time_ms": 50, "memory_kb": 3784, "score_of_the_acc": -0.7349, "final_rank": 20 }, { "submission_id": "aoj_0673_7072202", "code_snippet": "//#define _GLIBCXX_DEBUG\n\n#include<bits/stdc++.h>\nusing namespace std;\n\n#define endl '\\n'\n#define lfs cout<<fixed<<setprecision(10)\n#define ALL(a) (a).begin(),(a).end()\n#define ALLR(a) (a).rbegin(),(a).rend()\n#define UNIQUE(a) (a).erase(unique((a).begin(),(a).end()),(a).end())\n#define spa << \" \" <<\n#define fi first\n#define se second\n#define MP make_pair\n#define MT make_tuple\n#define PB push_back\n#define EB emplace_back\n#define rep(i,n,m) for(ll i = (n); i < (ll)(m); i++)\n#define rrep(i,n,m) for(ll i = (ll)(m) - 1; i >= (ll)(n); i--)\nusing ll = long long;\nusing ld = long double;\nconst ll MOD1 = 1e9+7;\nconst ll MOD9 = 998244353;\nconst ll INF = 1e18;\nusing P = pair<ll, ll>;\ntemplate<typename T> using PQ = priority_queue<T>;\ntemplate<typename T> using QP = priority_queue<T,vector<T>,greater<T>>;\ntemplate<typename T1, typename T2>bool chmin(T1 &a,T2 b){if(a>b){a=b;return true;}else return false;}\ntemplate<typename T1, typename T2>bool chmax(T1 &a,T2 b){if(a<b){a=b;return true;}else return false;}\nll median(ll a,ll b, ll c){return a+b+c-max({a,b,c})-min({a,b,c});}\nvoid ans1(bool x){if(x) cout<<\"Yes\"<<endl;else cout<<\"No\"<<endl;}\nvoid ans2(bool x){if(x) cout<<\"YES\"<<endl;else cout<<\"NO\"<<endl;}\nvoid ans3(bool x){if(x) cout<<\"Yay!\"<<endl;else cout<<\":(\"<<endl;}\ntemplate<typename T1,typename T2>void ans(bool x,T1 y,T2 z){if(x)cout<<y<<endl;else cout<<z<<endl;} \ntemplate<typename T1,typename T2,typename T3>void anss(T1 x,T2 y,T3 z){ans(x!=y,x,z);}; \ntemplate<typename T>void debug(const T &v,ll h,ll w,string sv=\" \"){for(ll i=0;i<h;i++){cout<<v[i][0];for(ll j=1;j<w;j++)cout<<sv<<v[i][j];cout<<endl;}};\ntemplate<typename T>void debug(const T &v,ll n,string sv=\" \"){if(n!=0)cout<<v[0];for(ll i=1;i<n;i++)cout<<sv<<v[i];cout<<endl;};\ntemplate<typename T>void debug(const vector<T>&v){debug(v,v.size());}\ntemplate<typename T>void debug(const vector<vector<T>>&v){for(auto &vv:v)debug(vv,vv.size());}\ntemplate<typename T>void debug(stack<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(queue<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(deque<T> st){while(!st.empty()){cout<<st.front()<<\" \";st.pop_front();}cout<<endl;}\ntemplate<typename T>void debug(PQ<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(QP<T> st){while(!st.empty()){cout<<st.top()<<\" \";st.pop();}cout<<endl;}\ntemplate<typename T>void debug(const set<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T>void debug(const multiset<T>&v){for(auto z:v)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,size_t size>void debug(const array<T, size> &a){for(auto z:a)cout<<z<<\" \";cout<<endl;}\ntemplate<typename T,typename V>void debug(const map<T,V>&v){for(auto z:v)cout<<\"[\"<<z.first<<\"]=\"<<z.second<<\",\";cout<<endl;}\ntemplate<typename T>vector<vector<T>>vec(ll x, ll y, T w){vector<vector<T>>v(x,vector<T>(y,w));return v;}\nll gcd(ll x,ll y){ll r;while(y!=0&&(r=x%y)!=0){x=y;y=r;}return y==0?x:y;}\nvector<ll>dx={1,-1,0,0,1,1,-1,-1};vector<ll>dy={0,0,1,-1,1,-1,1,-1};\ntemplate<typename T>vector<T> make_v(size_t a,T b){return vector<T>(a,b);}\ntemplate<typename... Ts>auto make_v(size_t a,Ts... ts){return vector<decltype(make_v(ts...))>(a,make_v(ts...));}\ntemplate<typename T1, typename T2>ostream &operator<<(ostream &os, const pair<T1, T2>&p){return os << p.first << \" \" << p.second;}\ntemplate<typename T>ostream &operator<<(ostream &os, const vector<T> &v){for(auto &z:v)os << z << \" \";cout<<\"|\"; return os;}\ntemplate<typename T>void rearrange(vector<int>&ord, vector<T>&v){\n auto tmp = v;\n for(int i=0;i<tmp.size();i++)v[i] = tmp[ord[i]];\n}\ntemplate<typename Head, typename... Tail>void rearrange(vector<int>&ord,Head&& head, Tail&&... tail){\n rearrange(ord, head);\n rearrange(ord, tail...);\n}\ntemplate<typename T> vector<int> ascend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],i)<make_pair(v[j],j);});\n return ord;\n}\ntemplate<typename T> vector<int> descend(const vector<T>&v){\n vector<int>ord(v.size());iota(ord.begin(),ord.end(),0);\n sort(ord.begin(),ord.end(),[&](int i,int j){return make_pair(v[i],-i)>make_pair(v[j],-j);});\n return ord;\n}\ntemplate<typename T> vector<T> inv_perm(const vector<T>&ord){\n vector<T>inv(ord.size());\n for(int i=0;i<ord.size();i++)inv[ord[i]] = i;\n return inv;\n}\nll FLOOR(ll n,ll div){assert(div>0);return n>=0?n/div:(n-div+1)/div;}\nll CEIL(ll n,ll div){assert(div>0);return n>=0?(n+div-1)/div:n/div;}\nll digitsum(ll n){ll ret=0;while(n){ret+=n%10;n/=10;}return ret;}\nll modulo(ll n,ll d){return (n%d+d)%d;};\ntemplate<typename T>T min(const vector<T>&v){return *min_element(v.begin(),v.end());}\ntemplate<typename T>T max(const vector<T>&v){return *max_element(v.begin(),v.end());}\ntemplate<typename T>T acc(const vector<T>&v){return accumulate(v.begin(),v.end(),T(0));};\ntemplate<typename T>T reverse(const T &v){return T(v.rbegin(),v.rend());};\n//mt19937 mt(chrono::steady_clock::now().time_since_epoch().count());\nint popcount(ll x){return __builtin_popcountll(x);};\nint poplow(ll x){return __builtin_ctzll(x);};\nint pophigh(ll x){return 63 - __builtin_clzll(x);};\ntemplate<typename T>T poll(queue<T> &q){auto ret=q.front();q.pop();return ret;};\ntemplate<typename T>T poll(priority_queue<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(QP<T> &q){auto ret=q.top();q.pop();return ret;};\ntemplate<typename T>T poll(stack<T> &s){auto ret=s.top();s.pop();return ret;};\nll MULT(ll x,ll y){if(LLONG_MAX/x<=y)return LLONG_MAX;return x*y;}\nll POW2(ll x, ll k){ll ret=1,mul=x;while(k){if(mul==LLONG_MAX)return LLONG_MAX;if(k&1)ret=MULT(ret,mul);mul=MULT(mul,mul);k>>=1;}return ret;}\nll POW(ll x, ll k){ll ret=1;for(int i=0;i<k;i++){if(LLONG_MAX/x<=ret)return LLONG_MAX;ret*=x;}return ret;}\ntemplate< typename T = int >\nstruct edge {\n int to;\n T cost;\n int id;\n edge():id(-1){};\n edge(int to, T cost = 1, int id = -1):to(to), cost(cost), id(id){}\n operator int() const { return to; }\n};\n\ntemplate<typename T>\nusing Graph = vector<vector<edge<T>>>;\ntemplate<typename T>\nGraph<T>revgraph(const Graph<T> &g){\n Graph<T>ret(g.size());\n for(int i=0;i<g.size();i++){\n for(auto e:g[i]){\n int to = e.to;\n e.to = i;\n ret[to].push_back(e);\n }\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readGraph(int n,int m,int indexed=1,bool directed=false,bool weighted=false){\n Graph<T> ret(n);\n for(int es = 0; es < m; es++){\n int u,v;\n T w=1;\n cin>>u>>v;u-=indexed,v-=indexed;\n if(weighted)cin>>w;\n ret[u].emplace_back(v,w,es);\n if(!directed)ret[v].emplace_back(u,w,es);\n }\n return ret;\n}\ntemplate<typename T>\nGraph<T> readParent(int n,int indexed=1,bool directed=true){\n Graph<T>ret(n);\n for(int i=1;i<n;i++){\n int p;cin>>p;\n p-=indexed;\n ret[p].emplace_back(i);\n if(!directed)ret[i].emplace_back(p);\n }\n return ret;\n}\n\nint main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n ll res=0,buf=0;\n bool judge = true;\n\tll n;cin>>n;\n\tvector<ll>a(n),t(n);\n\trep(i,0,n)cin>>a[i]>>t[i];\n\tll now=0;\n\tauto ord=descend(a);\n\tll pos=0;\n\tfor(auto i:ord){\n\t\t//cout<<now spa pos<<endl;\n\t\tnow=max(t[i],now+abs(a[i]-pos));\n\t\tpos=a[i];\n\t}\n\tcout<<now+pos<<endl;\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 5200, "score_of_the_acc": -0.5061, "final_rank": 12 }, { "submission_id": "aoj_0673_6997076", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0673.cc: いちご (Strawberry)\n */\n\n#include<cstdio>\n#include<algorithm>\n#include<utility>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 100000;\n\n/* typedef */\n\ntypedef pair<int,int> pii;\n\n/* global variables */\n\npii ps[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n\n for (int i = 0; i < n; i++) {\n int a, t;\n scanf(\"%d%d\", &a, &t);\n ps[i] = pii(a, t);\n }\n sort(ps, ps + n);\n\n int t = ps[n - 1].first, pa = ps[n - 1].first;\n for (int i = n - 1; i >= 0; i--) {\n t = max(t + (pa - ps[i].first), ps[i].second);\n pa = ps[i].first;\n }\n\n t += pa;\n\n printf(\"%d\\n\", t);\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3740, "score_of_the_acc": -0.0598, "final_rank": 4 }, { "submission_id": "aoj_0673_6709576", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\nint main() {\n int N,an=0,M=0;\n cin>>N;\n vector<pair<int,int>> P(N);\n rep(i,N){cin>>P[i].first>>P[i].second;M=max(M,P[i].first*2);}\n rep(i,N)an=max(an,P[i].second+P[i].first-M);\n cout<<an+M<<endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3892, "score_of_the_acc": -0.5889, "final_rank": 13 }, { "submission_id": "aoj_0673_6709571", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\nint main() {\n int N,an=0;\n cin>>N;\n vector<pair<int,int>> P(N);\n rep(i,N)cin>>P[i].first>>P[i].second;\n sort(P.begin(),P.end());\n rep(i,N)an=max(an,P[i].second+P[i].first-P[N-1].first*2);\n cout<<an+P[N-1].first*2<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3896, "score_of_the_acc": -0.7563, "final_rank": 14 } ]
aoj_0691_cpp
往復すごろく JOI 高校の葵は新しいすごろくを購入した.このすごろくは N+2 個のマスが横一列に並んだ形をしている.これらのマスには,左端のマスから右端のマスへと順に, 0 から N+1 までの番号がついている.初め,マス 0 とマス N+1 には X が,マス i ( 1 ≦ i ≦ N ) には S i が書かれている.ただし, S i は文字 . または # である. 葵はこのすごろくと 1 つの駒を使って遊んでいる.初め,駒はマス A ( 1 ≦ A ≦ N ) に右を向いた状態で置かれている.ただし, S A は文字 . である.葵は 1 秒経つごとに,駒を向いている方向へ 1 マス移動させる. このすごろくには次のような ルール が設定されている. X が書かれたマスに駒が乗ると,駒の向きは反転する. . が書かれたマスに駒が乗ったとしても,何も起こらない. # が書かれたマスに駒が乗ると,駒の向きは反転する.このとき,このマスに書かれた文字を . に変更する.したがって,その後はこのマスに駒が乗ったとしても向きは反転しない. なお,駒の反転や文字の変更にかかる時間は無視できる. すごろくと駒の初めの状態が与えられたとき, # が書かれたマスがすべてなくなるまでに要する時間を求めるプログラムを作成せよ. 制約 2 ≦ N ≦ 200000 . 1 ≦ A ≦ N . S i は文字 . または # である ( 1 ≦ i ≦ N ). S A は文字 . である. S i が文字 # であるような i ( 1 ≦ i ≦ N ) が少なくとも 1 つ存在する. 入力 入力は以下の形式で標準入力から与えられる. N A S ただし, S は長さ N の文字列で,その i 文字目 ( 1 ≦ i ≦ N ) は S i である. 出力 標準出力に, # が書かれたマスがすべてなくなるまでに何秒かかるかを 1 行で出力せよ. 入出力例 入力例 1 7 3 .#.#..# 出力例 1 8 時間が経過するにつれてすごろくの状態は次のように変化する.ただし,右向きの駒が置かれたマスを > ,左向きの駒が置かれたマスを < で表す. X.#>#..#X X.#.<..#X X.#<...#X X.>....#X X..>...#X X...>..#X X....>.#X X.....>#X X......<X したがって, 8 秒で # が書かれたマスがすべてなくなるので, 8 を出力する. 入力例 2 4 1 .#.# 出力例 2 7 時間が経過するにつれてすごろくの状態は次のように変化する. X>#.#X X.<.#X X<..#X >...#X X>..#X X.>.#X X..>#X X...<X したがって, 7 秒で # が書かれたマスがすべてなくなるので, 7 を出力する. 入力例 3 6 6 #####. 出力例 3 35 情報オリンピック日本委員会 作 『第 20 回日本情報オリンピック JOI 2020/2021 二次予選競技課題』
[ { "submission_id": "aoj_0691_9852763", "code_snippet": "#include <iostream>\n#include <vector>\nusing namespace std;\nint main(void){\n vector<int> v;\n bool t={true};\n int n,a,c=0,i,j=0,k,vp,vc=0;\n string s;\n cin >> n >> a >> s;\n a-=1;\n n-=1;\n for(i=0;i<s.size();i++){\n if(s[i]=='#')v.push_back(i);\n }\n for(i=0;i<s.size();i++){\n if(s[i]=='#'){\n vc++;\n }\n if(s[i]=='#' and a<i){\n vp=vc-1;\n break;\n }\n vp=vc;\n }\n while(v.size()!=0){\n // cout << a << ' ' << s[a] << endl;\n if(t==true){\n if(v.size()<=vp){\n c+=s.size()-a+1;\n t=false;\n vp=v.size()-1;\n a=s.size()-1;\n }\n else{\n c+=v[vp]-a;\n a=v[vp];\n t=false;\n v.erase(v.begin()+vp);\n vp--;\n }\n }\n else {\n if(vp==-1){\n c+=a+2;\n t=true;\n vp=0;\n a=0;\n }\n else{\n c+=a-v[vp];\n a=v[vp];\n t=true;\n v.erase(v.begin()+vp);\n }\n }\n }\n cout << c << endl;\n}", "accuracy": 0.6041666666666666, "time_ms": 470, "memory_kb": 3584, "score_of_the_acc": -0.807, "final_rank": 13 }, { "submission_id": "aoj_0691_8981586", "code_snippet": "#include <iostream>\n#include <set>\n#include <functional>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned int N, A, i;\n\tunsigned long long time = 0;\n\tchar S[200001];\n\tbool right = true;\n\tcin >> N >> A >> S;\n\n\tset<unsigned int> sharp_l;\n\tset<unsigned int, greater<unsigned int>> sharp_g;\n\tfor (i = 0; i != N; ++i)\n\t\tif (S[i] == '#')\n\t\t\tsharp_l.insert(i + 1), sharp_g.insert(i + 1);\n\n\tfor (; !sharp_l.empty(); right ^= true)\n\t{\n\t\tif (right)\n\t\t{\n\t\t\tauto itr = sharp_l.lower_bound(A);\n\t\t\tif (itr == sharp_l.end()) time += (N + 1) - A, A = N + 1;\n\t\t\telse time += *itr - A, A = *itr, sharp_g.erase(sharp_g.find(*itr)), sharp_l.erase(itr);\n\t\t}\n\t\telse\n\t\t{\n\t\t\tauto itr = sharp_g.lower_bound(A);\n\t\t\tif (itr == sharp_g.end()) time += A, A = 0;\n\t\t\telse time += A - *itr, A = *itr, sharp_l.erase(sharp_l.find(*itr)), sharp_g.erase(itr);\n\t\t}\n\t}\n\n\tcout << time << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 22304, "score_of_the_acc": -1.1579, "final_rank": 10 }, { "submission_id": "aoj_0691_8893908", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, A;\n string S;\n cin >> N >> A >> S;\n ll dir = 1;\n set<ll> h;\n S = \"X\" + S + \"X\";\n rep(i, len(S)) {\n if (S[i] != '.') h.insert(i);\n }\n ll rem = len(h) - 2;\n ll ans = 0;\n while (rem > 0) {\n if (dir == 1) {\n auto lb = h.lower_bound(A+1);\n ans += *lb - A;\n A = *lb;\n if (*lb <= N) {\n h.erase(lb);\n rem--;\n }\n } else {\n auto lb = h.lower_bound(A);\n lb--;\n ans += A - *lb;\n A = *lb;\n if (lb != h.begin()) {\n h.erase(lb);\n rem--;\n }\n }\n dir = -dir;\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 12840, "score_of_the_acc": -0.5471, "final_rank": 4 }, { "submission_id": "aoj_0691_8750530", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n --m;\n string s;\n cin >> s;\n\n set<int> st;\n st.emplace(-1);\n st.emplace(n);\n rep (i, n) {\n if (s[i] == '#')\n st.emplace(i);\n }\n\n bool f = true;\n ll ans = 0;\n while (st.size() > 2) {\n if (f) {\n int x = *st.upper_bound(m);\n ans += x - m;\n if (x != n) {\n st.erase(x);\n }\n m = x;\n } else {\n int x = *prev(st.lower_bound(m));\n ans += m - x;\n if (x != -1) {\n st.erase(x);\n }\n m = x;\n }\n f = !f;\n }\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 12760, "score_of_the_acc": -0.5603, "final_rank": 5 }, { "submission_id": "aoj_0691_7969710", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int n, now;\n cin >> n >> now;\n string str;\n cin >> str;\n set<int> s;\n for (int i = 0; i < n; i++) {\n if (str[i] == '#') s.insert(i + 1);\n }\n s.insert(0);\n s.insert(n + 1);\n bool is_right = true;\n long long ans = 0;\n while (s.size() > 2) {\n if (is_right) {\n auto it = s.upper_bound(now);\n ans += *it - now;\n now = *it;\n } else {\n auto it = prev(s.lower_bound(now));\n ans += now - *it;\n now = *it;\n }\n if (now != 0 && now != n + 1) {\n s.erase(now);\n }\n is_right ^= true;\n }\n cout << ans << '\\n';\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12820, "score_of_the_acc": -0.5811, "final_rank": 8 }, { "submission_id": "aoj_0691_7629123", "code_snippet": "#include <iostream>\n#include<set>\n#include <cmath>\nusing namespace std;\nset<int> ss;\nstring str;\nint main() {\n\tint n,p,r;\n\tlong long int ans;\n\tcin>>n>>p;\n\tcin>>str;\n\tr=1;\n\tfor(int i=0;i<n;i++){\n\t\tif(str[i]=='#'){\n\t\t\tss.insert(i+1);\n\t\t}\n\t}\n\tss.insert(0);\n\tss.insert(n+1);\n\tans=0;\n\twhile(ss.size()>2){\n\t\tint p2;\n\t\tif(r==1){\n\t\t\tp2=(*(ss.upper_bound(p)));\n\t\t}else{\n\t\t\tset<int>::iterator it=ss.lower_bound(p);\n\t\t\tit--;\n\t\t\tp2=(*it);\n\t\t}\n\t\tans+=abs(p2-p);\n\t\tif(p2!=0 && p2!=n+1){\n\t\t\tss.erase(p2);\n\t\t}\n\t\tp=p2;\n\t\tr*=-1;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 12568, "score_of_the_acc": -0.5676, "final_rank": 7 }, { "submission_id": "aoj_0691_7126085", "code_snippet": "#include <iostream>\n#include <math.h>\n#include <algorithm>\n#include <vector>\nusing namespace std;\n//wordol\n\nint main()\n{\n long n,a,ans=0,k,way;\n cin>>n>>a;\n string s;\n cin>>s;\n vector <int>left,right;\n for (int i=0;i<n;i++){\n if (s[i]=='#'){\n if (a>i+1) left.push_back(i+1);\n else right.push_back(i+1);\n }\n }\n \n //for(int i=0;i<left.size();i++)cout<<left[i]<<\" \";\n //cout<<endl;\n //for(int i=0;i<right.size();i++)cout<<right[i]<<\" \";\n \n //cout<<endl<<endl;\n way=min(left.size(),right.size());\n if(left.size()==right.size()) ans-=abs(a-left[0]);\n //cout<<\"w\"<<way<<endl;\n for(int i=0;i<way;i++){\n \n k=left.size();\n ans+=abs(right[0]-a)*2+abs(left[k-1]-a)*2;\n //cout<<ans<<\"-\";\n right.erase(right.begin()+0);\n left.erase(left.begin()+k-1);\n \n }\n \n if(left.size()==right.size()) {\n cout<<ans<<endl; \n return 0;\n }\n \n if(right.size()==1) {\n cout<<ans+(right[0]-a)<<endl; \n return 0;\n }\n \n if(right.size()>1){\n for (int i=0;i<right.size()-1;i++) ans+=a*2+abs(right[i]-a)*2;\n ans+=right[right.size()-1]-a;\n }\n \n if(left.size()>0){\n for (int i=left.size()-1;i>0;i--) ans+=(n-a+1)*2+abs(left[i]-a)*2;\n ans+=a-left[0]+(n-a+1)*2;\n }\n \n cout<<ans<<endl;\n \n}", "accuracy": 1, "time_ms": 580, "memory_kb": 4020, "score_of_the_acc": -1.0233, "final_rank": 9 }, { "submission_id": "aoj_0691_7125714", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <math.h>\nusing namespace std;\n\nint main()\n{\n\tvector<int> left, right;\n\tint n, a,k,to=1,ans=0,now;\n\tcin >> n >> a;\n\tstring s;\n\tcin >> s;\n\tfor (int i = 0; i < n; i++) {\n\t\tif (s[i] == '#') {\n\t\t\tif (i+1 < a) left.push_back(i+1);\n\t\t\tif (i+1 > a) right.push_back(i+1);\n\t\t}\n\t}\n\n\t\n\n\n\tnow = a;\n\t//to=1で右 -1で左\n\twhile (left.size()>0 || right.size()>0) {\n\n\t\t/*\n\t\tcout << \"now:\" << now << \"ans:\" << ans << endl;\n\t\t\n\t\tcout << \"left:\";\n\t\tk = (int)left.size();\n\t\tfor (int i = 0; i < k; i++) {\n\t\t\tcout << left[i] << \" \";\n\t\t}\n\n\t\tcout << \"\\nright:\";\n\t\tk = (int)right.size();\n\t\tfor (int i = 0; i < k; i++) {\n\t\t\tcout << right[i] << \" \";\n\t\t}\n\t\t\n\t\tcout << \"\\n\";\n\t\t*/\n\n\t\tif (to == 1) {\n\t\t\tif (right.size()>0) {\n\t\t\t\tans += abs(now - right[0]);\n\t\t\t\tnow = right[0];\n\t\t\t\tto = -1;\n\t\t\t\tright.erase(right.begin() + 0);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tto = -1;\n\t\t\t\tans += (n - now + 1) * 2;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tif (left.size()>0) {\n\t\t\t\t//cout << \"a\";\n\t\t\t\tk = (int)left.size();\n\t\t\t\tans += abs(now - left[k-1]);\n\t\t\t\tnow = left[k-1];\n\t\t\t\tto = 1;\n\t\t\t\tleft.erase(left.begin() + k-1);\n\t\t\t}\n\t\t\telse {\n\t\t\t\tto = 1;\n\t\t\t\tans += now* 2;\n\t\t\t}\n\t\t}\n\n\t}\n\t\n\tcout << ans << endl;\n}", "accuracy": 0.6041666666666666, "time_ms": 300, "memory_kb": 3884, "score_of_the_acc": -0.5248, "final_rank": 12 }, { "submission_id": "aoj_0691_6997394", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0691.cc: 往復すごろく\n */\n\n#include<cstdio>\n#include<set>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 200000;\n\n/* typedef */\n\ntypedef long long ll;\ntypedef set<int> si;\n\n/* global variables */\n\nchar s[MAX_N + 4];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, a;\n scanf(\"%d%d%s\", &n, &a, s);\n\n si rs;\n for (int i = 0; i < n; i++)\n if (s[i] == '#') rs.insert(i + 1);\n rs.insert(0), rs.insert(n + 1);\n\n ll t = 0;\n int di = 1;\n while (rs.size() > 2) {\n //printf(\"%d -> \", a);\n si::iterator sit = rs.lower_bound(a);\n if (di > 0) {\n if (*sit == a) sit++;\n t += *sit - a;\n a = *sit;\n if (*sit <= n) rs.erase(sit);\n }\n else {\n sit--;\n t += a - *sit;\n a = *sit;\n if (*sit > 0) rs.erase(sit);\n }\n di *= -1;\n //printf(\"%d\\n\", a);\n }\n\n printf(\"%lld\\n\", t);\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 12572, "score_of_the_acc": -0.5328, "final_rank": 2 }, { "submission_id": "aoj_0691_6816446", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N, A;\n string S;\n cin >> N >> A >> S;\n set<ll> P;\n P.insert(0);\n P.insert(N + 1);\n rep(i, N)if (S[i] == '#')P.insert(i + 1);\n ll an = 0;\n bool D = 1;\n while (P.size() > 2) {\n if (D == 1) {\n auto p = P.upper_bound(A);\n an += *p - A;\n A = *p;\n if (*p != N + 1)P.erase(*p);\n }\n else {\n auto p = P.lower_bound(A);\n p--;\n an += A - *p;\n A = *p;\n if (*p != 0)P.erase(*p);\n }\n D =!D;\n }\n cout << an << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 12820, "score_of_the_acc": -0.5636, "final_rank": 6 }, { "submission_id": "aoj_0691_6613578", "code_snippet": "#include <iostream>\n#include <string>\n#include <set>\n\nusing namespace std;\n\nint main()\n{\n\tint N, A; cin >> N >> A;\n\tstring S; cin >> S;\n\tset<int> SS;\n\tfor (int i = 0; i < N; ++i) if (S[i] == '#') SS.insert(i + 1);\n\tint_fast64_t t = 0;\n\tfor (auto p = SS.upper_bound(A);;) {\n\t\tif (p != SS.end()) {\n\t\t\tt += *p - A;\n\t\t\tA = *p;\n\t\t\tp = SS.erase(p);\n\t\t\tif (SS.empty()) break;\n\t\t} else {\n\t\t\tt += N + 1 - A;\n\t\t\tA = N + 1;\n\t\t}\n\t\tif (p != SS.begin()) {\n\t\t\t--p;\n\t\t\tt += A - *p;\n\t\t\tA = *p;\n\t\t\tp = SS.erase(p);\n\t\t\tif (SS.empty()) break;\n\t\t} else {\n\t\t\tt += A;\n\t\t\tA = 0;\n\t\t}\n\t}\n\tcout << t << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 12820, "score_of_the_acc": -0.546, "final_rank": 3 }, { "submission_id": "aoj_0691_6613573", "code_snippet": "#include <iostream>\n#include <string>\n#include <set>\n\nusing namespace std;\n\nint main()\n{\n\tint N, A; cin >> N >> A;\n\tstring S; cin >> S;\n\tset<int> SS;\n\tfor (int i = 0; i < N; ++i) if (S[i] == '#') SS.insert(i + 1);\n\tint t = 0;\n\tfor (auto p = SS.upper_bound(A);;) {\n\t\tif (p != SS.end()) {\n\t\t\tt += *p - A;\n\t\t\tA = *p;\n\t\t\tp = SS.erase(p);\n\t\t\tif (SS.empty()) break;\n\t\t} else {\n\t\t\tt += N + 1 - A;\n\t\t\tA = N + 1;\n\t\t}\n\t\tif (p != SS.begin()) {\n\t\t\t--p;\n\t\t\tt += A - *p;\n\t\t\tA = *p;\n\t\t\tp = SS.erase(p);\n\t\t\tif (SS.empty()) break;\n\t\t} else {\n\t\t\tt += A;\n\t\t\tA = 0;\n\t\t}\n\t}\n\tcout << t << endl;\n\treturn 0;\n}", "accuracy": 0.6041666666666666, "time_ms": 10, "memory_kb": 8040, "score_of_the_acc": -0.238, "final_rank": 11 }, { "submission_id": "aoj_0691_6291194", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long long INF = 1e18;\ntemplate <typename T>\nvoid input_arr(vector<T>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i];\n\t}\n}\ntemplate <typename T, typename Q>\nvoid input_arr(vector<pair<T, Q>>& A, ll N) {\n\tfor (ll i = 0; i < N; i++) {\n\t\tcin >> A[i].first >> A[i].second;\n\t}\n}\ntemplate <typename T>\nvoid input_arr(vector<vector<T>>& A, ll H, ll W) {\n\tfor (ll i = 0; i < H; i++) {\n\t\tfor (ll j = 0; j < W; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n}\nint main() {\n ll N, A; cin >> N >> A;\n string S; cin >> S;\n priority_queue<ll>left;\n priority_queue<ll, vector<ll>, greater<ll>>right;\n for (ll i = 1; i <= N; i++) {\n if (S[i - 1] == '#') {\n if (i < A) left.push(i);\n else right.push(i);\n }\n }\n left.push(0LL); right.push(N + 1);\n ll ans = 0;\n bool check = true;\n while (left.size() != 1 || right.size() != 1) {\n if (check) {\n ans += abs(A - right.top());\n A = right.top();\n if (right.top() != N + 1) right.pop();\n }\n else {\n ans += abs(A - left.top());\n A = left.top();\n if (left.top() != 0) left.pop();\n }\n check = !check;\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5636, "score_of_the_acc": -0.1096, "final_rank": 1 } ]
aoj_0692_cpp
パンケーキ ビ太郎はパンケーキ店で働いている. この店で最も人気のあるメニューは N 枚のパンケーキが積み重なったパンケーキタワーである.店で作られているパンケーキには 3 種類の味があり,それぞれ A , B , C と呼ぶことにする. ここで,パンケーキの並び方が次の条件を満たすようになっているパンケーキタワーを 良いパンケーキタワー と呼ぶことにする. すべての味 A のパンケーキと味 B のパンケーキの組において,味 A のパンケーキが味 B のパンケーキより上にある. すべての味 A のパンケーキと味 C のパンケーキの組において,味 A のパンケーキが味 C のパンケーキより上にある. すべての味 B のパンケーキと味 C のパンケーキの組において,味 B のパンケーキが味 C のパンケーキより上にある. 例えば,パンケーキの味がそれぞれ上から順に AABBBC , ACC , BBBB となっているパンケーキタワーはどれも良いパンケーキタワーであるが, AABABCC , CA となっているパンケーキタワーはどれも良いパンケーキタワーではない. 盛り付け担当のビ太郎はパンケーキタワーに対して次の操作を行うことができる. 操作 k ( 2 ≦ k ≦ N ):上から k 枚目のパンケーキの下側にフライ返しを差し込み,そこから上のパンケーキをひっくり返す.すなわち,上から k 枚のパンケーキの並び方を反転させる. 例えば,パンケーキの味が上から順に ABCB となっているパンケーキタワーに操作 2 ,操作 3 ,操作 4 をそれぞれ行った場合,パンケーキの並び方は BACB , CBAB , BCBA となる. 今, Q 皿のパンケーキタワーがあり, i 皿目 ( 1 ≦ i ≦ Q ) のパンケーキタワーはパンケーキの味が上から順に S i,1 S i,2 … S i,N となっている.ビ太郎はそれぞれのパンケーキタワーについて,できる限り少ない回数の操作で良いパンケーキタワーにしたい. Q 皿のパンケーキタワーの並び方の情報が与えられるので,それぞれのパンケーキタワーについて,良いパンケーキタワーにするのに必要な操作の回数の最小値を求めるプログラムを作成せよ. 制約 2 ≦ N ≦ 13 . 1 ≦ Q ≦ 100000 . S i,j は A , B , C のいずれかである ( 1 ≦ i ≦ Q , 1 ≦ j ≦ N ). 入力 入力は以下の形式で標準入力から与えられる. N Q S 1 S 2 : S Q ただし, S i ( 1 ≦ i ≦ Q ) は長さ N の文字列で,その j 文字目 ( 1 ≦ j ≦ N ) は S i,j である. 出力 標準出力に Q 行出力せよ. i 行目 ( 1 ≦ i ≦ Q ) には, i 皿目のパンケーキタワーについて,良いパンケーキタワーにするのに必要な操作の回数の最小値を出力せよ. 入出力例 入力例 1 5 3 ABCBA CCBAB AAAAA 出力例 1 3 2 0 1 皿目のパンケーキタワーの場合,以下の 3 回の操作を行うことによって良いパンケーキタワーにすることが可能である. 操作 4 を行う.パンケーキの味は上から順に BCBAA となる. 操作 2 を行う.パンケーキの味は上から順に CBBAA となる. 操作 5 を行う.パンケーキの味は上から順に AABBC となる. 2 回以下の操作によって良いパンケーキタワーにすることは不可能であるので, 1 行目に 3 を出力する. 2 皿目のパンケーキタワーの場合,以下の 2 回の操作を行うことによって良いパンケーキタワーにすることが可能である. 操作 5 を行う.パンケーキの味は上から順に BABCC となる. 操作 2 を行う.パンケーキの味は上から順に ABBCC となる. 1 回以下の操作によって良いパンケーキタワーにすることは不可能であるので, 2 行目に 2 を出力する. 3 皿目のパンケーキタワーの場合,既に良いパンケーキタワーになっているので操作を行う必要がない.したがって, 3 行目に 0 を出力する. 入力例 2 2 5 AC AC AC AC AC 出力例 2 0 0 0 0 0 パンケーキの並び方が同じであるようなパンケーキタワーが複数個存在する場合もあることに注意せよ. 入力例 3 13 1 ABCCABCBACBAA 出力例 3 9 入力例 4 13 4 CCAAACBAAAABB BBBCCBCCCBCBC CCCAAAABBBBBB AABCBCACBACBA 出力例 4 4 6 2 10 情報オリンピック日本委員会 作 『第 20 回日本情報オリンピック JOI 2020/2021 二次予選競技課題』
[ { "submission_id": "aoj_0692_8750697", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 2 \"/home/kuhaku/home/github/algo/lib/string/converter.hpp\"\n\nstruct string_converter {\n char type(const char &c) const {\n return (std::islower(c) ? 'a' : std::isupper(c) ? 'A' : std::isdigit(c) ? '0' : 0);\n }\n int convert(const char &c) {\n if (!start) start = type(c);\n return c - start;\n }\n int convert(const char &c, const std::string &chars) { return chars.find(c); }\n template <typename T>\n auto convert(const T &v) {\n std::vector<decltype(convert(v[0]))> res;\n res.reserve(v.size());\n for (auto &&e : v) res.emplace_back(convert(e));\n return res;\n }\n template <typename T>\n auto convert(const T &v, const std::string &chars) {\n std::vector<decltype(convert(v[0], chars))> res;\n res.reserve(v.size());\n for (auto &&e : v) res.emplace_back(convert(e, chars));\n return res;\n }\n int operator()(const char &v, char s = 0) {\n start = s;\n return convert(v);\n }\n int operator()(const char &v, const std::string &chars) { return convert(v, chars); }\n template <typename T>\n auto operator()(const T &v, char s = 0) {\n start = s;\n return convert(v);\n }\n template <typename T>\n auto operator()(const T &v, const std::string &chars) {\n return convert(v, chars);\n }\n\n private:\n char start = 0;\n} to_int;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint to_hash(const vector<int> &v) {\n int res = 0;\n for (int x : v) res = res * 3 + x;\n return res;\n}\n\nvector<int> to_vector(int x, int n) {\n vector<int> res;\n rep (i, n) {\n res.emplace_back(x % 3);\n x /= 3;\n }\n reverse(all(res));\n return res;\n}\n\nint main(void) {\n int n, q;\n cin >> n >> q;\n\n int sz = 1;\n rep (i, n) sz *= 3;\n vector<int> dp(sz, Inf);\n vector<int> v(n, 2);\n rep (i, n + 1) {\n FOR (j, i, n + 1) {\n dp[to_hash(v)] = 0;\n if (j < n)\n v[j] = 1;\n }\n FOR (j, i + 1, n) v[j] = 2;\n if (i < n)\n v[i] = 0;\n }\n\n queue<int> que;\n rep (i, sz) {\n if (dp[i] == 0)\n que.emplace(i);\n }\n\n while (!que.empty()) {\n int x = que.front();\n que.pop();\n auto v = to_vector(x, n);\n repn (i, n) {\n reverse(v.begin(), v.begin() + i);\n int h = to_hash(v);\n if (chmin(dp[h], dp[x] + 1)) {\n que.emplace(h);\n }\n reverse(v.begin(), v.begin() + i);\n }\n }\n\n while (q--) {\n string s;\n cin >> s;\n auto v = to_int(s);\n co(dp[to_hash(v)]);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 11140, "score_of_the_acc": -0.3562, "final_rank": 7 }, { "submission_id": "aoj_0692_8307028", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// 文字列から整数値へ\nint encode(const string &S) {\n int res = 0;\n for (auto c: S) res = res * 3 + (c - 'A');\n return res;\n}\n\n// 整数値から文字列へ\nstring decode(int N, int val) {\n string res = \"\";\n while (val) {\n res += (char)('A' + (val%3));\n val /= 3;\n }\n while (res.size() < N) res += 'A';\n reverse(res.begin(), res.end());\n return res;\n}\n\nint main() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n\n int N, Q;\n cin >> N >> Q;\n\n // すべての文字列について求めておく\n int MAX = 1;\n for (int i = 0; i < N; ++i) MAX *= 3;\n vector<int> dp(MAX+1, -1);\n queue<int> que;\n\n // 揃った文字列を始点にする\n for (int a = 0; a <= N; ++a) {\n for (int b = 0; a+b <= N; ++b) {\n string str = string(a, 'A') + string(b, 'B') + string(N-a-b, 'C');\n int val = encode(str);\n dp[val] = 0;\n que.push(val);\n }\n }\n\n // BFS\n while (!que.empty()) {\n long long val = que.front();\n que.pop();\n auto str = decode(N, val);\n for (int i = 1; i <= N; ++i) {\n string nstr = str;\n reverse(nstr.begin(), nstr.begin() + i);\n int nval = encode(nstr);\n if (dp[nval] == -1) {\n dp[nval] = dp[val] + 1;\n que.push(nval);\n }\n }\n }\n\n // それぞれの文字列について答える\n for (int q = 0; q < Q; ++q) {\n string S;\n cin >> S;\n cout << dp[encode(S)] << endl;\n }\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 11116, "score_of_the_acc": -0.3562, "final_rank": 6 }, { "submission_id": "aoj_0692_7480982", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\nusing namespace std;\n\n\nint encode(const string s) {\n\tint result = 0;\n\n\tfor (char c : s) {\n\t\tresult = result * 3 + c - 'A';\n\t}\n\treturn result;\n}\n\nstring decode(int n, int v) {\n\tstring result = \"\";\n\n\twhile (v > 0) {\n\t\tresult += char('A' + v % 3);\n\t\tv /= 3;\n\t}\n\n\twhile (result.size() < n) {\n\t\tresult += 'A';\n\t}\n\treverse(result.begin(), result.end());\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint n = 0;\n\tint q = 0;\n\n\tcin >> n >> q;\n\n\tint max_num_vertexes = 1;\n\tfor (int i = 0; i < n; i++) {\n\t\tmax_num_vertexes *= 3;\n\t}\n\n\tvector<int> costs(max_num_vertexes, -1);\n\tdeque<int> que;\n\tfor (int i = 0; i <= n; i++) {\n\t\tfor (int j = 0; i + j <= n; j++) {\n\t\t\tstring s = string(i, 'A') + string(j, 'B') + string(n - i - j, 'C');\n\t\t\tint v = encode(s);\n\t\t\t\n\t\t\tcosts[v] = 0;\n\t\t\tque.push_back(v);\n\t\t}\n\t}\n\n\twhile (!que.empty()) {\n\t\tint v = que.front(); que.pop_front();\n\t\tstring s = decode(n, v);\n\t\tint n_cost = costs[v] + 1;\n\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tstring ns = s;\n\n\t\t\treverse(ns.begin(), ns.begin() + i);\n\t\t\tint u = encode(ns);\n\t\t\tif (costs[u] < 0) {\n\t\t\t\tcosts[u] = n_cost;\n\t\t\t\tque.push_back(u);\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i < q; i++) {\n\t\tstring s;\n\n\t\tcin >> s;\n\t\tcout << costs[encode(s)] << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 11076, "score_of_the_acc": -0.6061, "final_rank": 10 }, { "submission_id": "aoj_0692_7480965", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <deque>\nusing namespace std;\n\nint encode(const string s) {\n\tint result = 0;\n\n\tfor (char c : s) {\n\t\tresult = result * 3 + c - 'A';\n\t}\n\treturn result;\n}\n\nstring decode(int n, int v) {\n\tstring result = \"\";\n\n\twhile (v > 0) {\n\t\tresult += char('A' + v % 3);\n\t\tv /= 3;\n\t}\n\n\twhile (result.size() < n) {\n\t\tresult += 'A';\n\t}\n\treverse(result.begin(), result.end());\n\treturn result;\n}\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint n = 0;\n\tint q = 0;\n\n\tcin >> n >> q;\n\n\tint max_num_vertexes = 1;\n\tfor (int i = 0; i < n; i++) {\n\t\tmax_num_vertexes *= 3;\n\t}\n\n\tvector<int> cost_list(max_num_vertexes + 1, -1);\n\tdeque<int> que;\n\n\tfor (int i = 0; i <= n; i++) {\n\t\tfor (int j = 0; i + j <= n; j++) {\n\t\t\tstring s = string(i, 'A') + string(j, 'B') + string(n - i - j, 'C');\n\t\t\tint v = encode(s);\n\t\t\t\n\t\t\tcost_list[v] = 0;\n\t\t\tque.push_back(v);\n\t\t}\n\t}\n\n\twhile (!que.empty()) {\n\t\tint v = que.front(); que.pop_front();\n\t\tstring s = decode(n, v);\n\t\tint n_cost = cost_list[v] + 1;\n\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tstring ns = s;\n\n\t\t\treverse(ns.begin(), ns.begin() + i);\n\t\t\tint u = encode(ns);\n\t\t\tif (cost_list[u] < 0) {\n\t\t\t\tcost_list[u] = n_cost;\n\t\t\t\tque.push_back(u);\n\t\t\t}\n\t\t}\n\t}\n\n\tfor (int i = 0; i < q; i++) {\n\t\tstring s;\n\n\t\tcin >> s;\n\n\t\tcout << cost_list[encode(s)] << endl;\n\t}\n\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 650, "memory_kb": 11124, "score_of_the_acc": -0.5962, "final_rank": 9 }, { "submission_id": "aoj_0692_7293451", "code_snippet": "#include <bits/stdc++.h>\n#include <random>\nusing namespace std;\n//#include <atcoder/all>\n//using namespace atcoder;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\nusing vvvvll = vector<vvvll>;\nusing vvvvvll = vector<vvvvll>;\nusing vvvvvvll = vector<vvvvvll>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing vvvb = vector<vvb>;\nusing vvvvb = vector<vvvb>;\nusing vd = vector<double>;\nusing vvd = vector<vd>;\nusing vvvd = vector<vvd>;\nusing vvvvd = vector<vvvd>;\nusing vvvvvd = vector<vvvvd>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\nusing pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;\n\ntemplate<class T>\nbool chmax(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p < q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nll gcd(ll(a), ll(b)) {\n if (b == 0)return a;\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\nvector<ll> fact, factinv, inv;\nll mod = 1e9;\nvoid prenCkModp(ll n) {\n fact.resize(n + 5);\n factinv.resize(n + 5);\n inv.resize(n + 5);\n fact.at(0) = fact.at(1) = 1;\n factinv.at(0) = factinv.at(1) = 1;\n inv.at(1) = 1;\n for (ll i = 2; i < n + 5; i++) {\n fact.at(i) = (fact.at(i - 1) * i) % mod;\n inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;\n factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;\n }\n\n}\nll nCk(ll n, ll k) {\n if (n < k) return 0;\n return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;\n}\n\n\nint si(string S) {\n int res = 0;\n for (ll i = S.size() - 1; i >= 0; i--) {\n res = res * 3 + (S[i] - 'A');\n }\n return res;\n}\n\nint main() {\n\n ll N, Q;\n cin >> N >> Q;\n ll MA = 4782970;\n vll M(MA, 1e18);\n vll SS(Q);\n queue<int> que;\n vb seen(MA, false);\n rep(q, Q) {\n string S;\n cin >> S;\n SS[q] = si(S);\n sort(all(S));\n que.push(si(S));\n M[si(S)] = 0;\n }\n\n while (!que.empty()) {\n int t = que.front();\n que.pop();\n if (seen[t])continue;\n seen[t] = 1;\n ll x = 0, y = 1;\n rep(ii, N) {\n x = x * 3 + t / y % 3;\n y *= 3;\n ll r = t / y * y + x;\n if (M[r] <= M[t] + 1)continue;\n if (seen[r])continue;\n M[r] = M[t] + 1;\n que.push(r);\n }\n\n }\n\n\n rep(q, Q) {\n cout << M[SS[q]] << endl;\n }\n\n}", "accuracy": 1, "time_ms": 410, "memory_kb": 43612, "score_of_the_acc": -0.426, "final_rank": 8 }, { "submission_id": "aoj_0692_7282931", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long int;\nusing ull = unsigned long long int;\nusing P = pair<ll, ll>;\nusing P3 = pair<ll, P>;\nusing PP = pair<P, P>;\nconstexpr int INF32 = 1 << 30;\nconstexpr ll INF64 = 1LL << 61;\n// constexpr ll MOD = 1000000007;\nconstexpr ll MOD = 998244353;\nconstexpr int di[] = {0, 1, 0, -1};\nconstexpr int dj[] = {1, 0, -1, 0};\n// constexpr int di8[] = {0, 1, 1, 1, 0, -1, -1, -1};\n// constexpr int dj8[] = {1, 1, 0, -1, -1, -1, 0, 1};\nconstexpr double EPS = 1e-10;\nconst double PI = acos(-1);\n\n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,n) for(int i=0,i_len=n; i<i_len; ++i)\n\ntemplate<typename T1,typename T2> bool chmax(T1 &a, T2 b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename T1,typename T2> bool chmin(T1 &a, T2 b) { if (b<a) { a=b; return 1; } return 0; }\n\nint rev(int x, int n){\n int res = 0;\n REP(i,n){\n res = res*3 + x%3;\n x /= 3;\n }\n return res;\n}\n\nint solve(){\n int n, q;\n cin >> n >> q;\n int m = 1;\n REP(i,n) m *= 3;\n vector<int> dist(m, INF32);\n queue<int> que;\n for(int i=0;i<=n;i++){\n for(int j=i;j<=n;j++){\n int s = 0;\n for(int k=0,b=1;k<n;k++,b*=3){\n if(k>=i && k<j) s += b;\n if(k>=j) s += b*2;\n }\n dist[s] = 0;\n que.push(s);\n }\n }\n while(!que.empty()){\n int now = que.front();\n que.pop();\n for(int i=2,b=9;i<=n;i++,b*=3){\n int nxt = (now/b)*b + rev(now%b,i); // 下位i桁をreverse\n if(chmin(dist[nxt], dist[now]+1)){\n que.push(nxt);\n }\n }\n }\n REP(_,q){\n string s;\n cin >> s;\n int x = 0;\n for(int i=0,b=1;i<n;i++,b*=3){\n x += int(s[i]-'A')*b;\n }\n int ans = dist[x];\n if(ans < INF32) cout << ans << endl;\n else cout << -1 << endl;\n }\n return 0;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n solve();\n // int T; cin >> T; REP(t,T) solve();\n // while(!solve());\n return 0;\n}", "accuracy": 1, "time_ms": 320, "memory_kb": 11132, "score_of_the_acc": -0.2662, "final_rank": 4 }, { "submission_id": "aoj_0692_6997536", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0692.cc: パンケーキ\n */\n\n#include<cstdio>\n#include<queue>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 13;\nconst int NTITS = 1594323; // = 3^13\n\n/* typedef */\n\ntypedef queue<int> qi;\n\n/* global variables */\n\nchar s[MAX_N + 4];\nint dp[NTITS], ds[MAX_N];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n //freopen(\"input.txt\", \"r\", stdin);\n //freopen(\"output.txt\", \"w\", stdout);\n\n int n, qn;\n scanf(\"%d%d\", &n, &qn);\n\n int ntits = 1;\n for (int i = 0; i < n; i++) ntits *= 3;\n\n fill(dp, dp + ntits, -1);\n qi q;\n \n for (int a = 0; a <= n; a++)\n for (int b = 0; a + b <= n; b++) {\n int c = n - (a + b);\n int v = 0;\n for (int i = 0; i < b; i++) v = v * 3 + 1;\n for (int i = 0; i < c; i++) v = v * 3 + 2;\n dp[v] = 0;\n q.push(v);\n }\n\n while (! q.empty()) {\n int u = q.front(); q.pop();\n\n for (int i = n - 1, w = u; i >= 0; i--, w /= 3) ds[i] = w % 3;\n\n for (int l = 1; l <= n; l++) {\n reverse(ds, ds + l);\n\n int v = 0;\n for (int i = 0; i < n; i++) v = v * 3 + ds[i];\n if (dp[v] < 0) {\n\tdp[v] = dp[u] + 1;\n\tq.push(v);\n }\n \n reverse(ds, ds + l);\n }\n }\n\n while (qn--) {\n scanf(\"%s\", s);\n\n int v = 0;\n for (int i = 0; i < n; i++) v = v * 3 + (s[i] - 'A');\n\n printf(\"%d\\n\", dp[v]);\n }\n return 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 10888, "score_of_the_acc": -0.1957, "final_rank": 3 }, { "submission_id": "aoj_0692_6638206", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n\nusing namespace std;\n\nint encode(const string& S)\n{\n\tint r = 0;\n\tfor (int i = (int) S.size(); --i >= 0;) r = r * 3 + S[i] - 'A';\n\treturn r;\n}\n\nint main()\n{\n\tint N, Q, K = 1; cin >> N >> Q;\n\tfor (int n = 0; n <= N; ++n) K *= 3;\n\tvector<int> D(K, K), E(K, K);\n\tqueue<pair<int, int>> q;\n\tfor (string A; (int) A.size() <= N; A += 'A') for (string B(A); (int) B.size() <= N; B += 'B') {\n\t\tq.push({encode(B + string(N - (int) B.size(), 'C')), 0});\n\t}\n\tfor (; !q.empty(); q.pop()) {\n\t\tauto [s, d] = q.front();\n\t\tif (D[s] <= d) continue;\n\t\tD[s] = E[s] = d++;\n\t\tfor (int t = s % 3, u = s / 3, k = 9; k < K; k *= 3) {\n\t\t\tint c = u % 3;\n\t\t\tt = t * 3 + c;\n\t\t\tu /= 3;\n\t\t\tint v = u * k + t;\n\t\t\tif (E[v] <= d) continue;\n\t\t\tE[v] = d;\n\t\t\tq.push({v, d});\n\t\t}\n\t}\n\twhile (--Q >= 0) {\n\t\tstring S; cin >> S;\n\t\tcout << D[encode(S)] << endl;\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 43968, "score_of_the_acc": -0.1767, "final_rank": 1 }, { "submission_id": "aoj_0692_6410279", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nstring s,t;\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint n,q; cin >> n >> q;\n\tqueue<pair<int,string>> pq;\n\tauto tran=[](string s)->int{\n\t\tint res=0;\n\t\tfor(char c:s){\n\t\t\tres=res*3+(c-'A');\n\t\t}\n\t\treturn res;\n\t};\n\tvector<int> mp(1594324,-1);\n\twhile(q--){\n\t\tstring S; cin >> S;\n\t\tint Num=tran(S);\n\t\tif(mp[Num]>=0){\n\t\t\tcout << mp[Num] << \"\\n\";\n\t\t}\n\t\telse{\n\t\t\tstring T=S; sort(T.begin(), T.end());\n\t\t\tpq.push(make_pair(0,T));\n\t\t\tmp[tran(T)]=0;\n\t\t\twhile(pq.size()){\n\t\t\t\tauto p=pq.front(); pq.pop();\n\t\t\t\tfor(int i=2;i<=n;i++){\n\t\t\t\t\ts=p.second.substr(0,i);\n\t\t\t\t\tt=(i!=n?p.second.substr(i):\"\");\n\t\t\t\t\treverse(s.begin(), s.end());\n\t\t\t\t\ts+=t;\n\t\t\t\t\tint num=tran(s);\n\t\t\t\t\tif(mp[num]>=0){\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t\telse{\n\t\t\t\t\t\tmp[num]=p.first+1;\n\t\t\t\t\t\tpq.push(make_pair(p.first+1,s));\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << mp[Num] << \"\\n\";\n\t\t}\n\t}\n}", "accuracy": 1, "time_ms": 720, "memory_kb": 10564, "score_of_the_acc": -0.665, "final_rank": 11 }, { "submission_id": "aoj_0692_6302980", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n\n\nint pow(int base, int exp) {\n\tint result{ 1 };\n\tfor (auto i = 0; i < exp; ++i) {\n\t\tresult *= base;\n\t}\n\treturn result;\n}\nint main() {\n\tint n, q; std::cin >> n >> q;\n\tstd::vector<std::string> dish(q);\n\tfor (auto& s : dish) {\n\t\tstd::cin >> s;\n\t}\n\tstd::vector<int> min_step(pow(3, n), INT_MAX);\n\tstd::queue<int> queue;\n\tfor (auto a = 0; a <= n; ++a) {\n\t\tint pattern{ 0 };\n\t\tfor (auto b = 0; a + b <= n; ++b) {\n\t\t\tint p = pattern;\n\t\t\tfor (auto c = 0; a + b + c <= n; ++c) {\n\t\t\t\tmin_step[p] = 0;\n\t\t\t\tqueue.push(p);\n\t\t\t\tp = p * 3 + 2;\n\t\t\t}\n\t\t\tpattern = pattern * 3 + 1;\n\t\t}\n\t}\n\tstd::vector<int> vec(n);\n\twhile (!queue.empty()) {\n\t\tconst auto top = queue.front(); queue.pop();\n\t\tint r = top;\n\t\tfor (auto i = 1; i <= n; ++i) {\n\t\t\tvec[n - i] = r % 3;\n\t\t\tr /= 3;\n\t\t}\n\t\tfor (auto i = 2; i <= n; ++i) {\n\t\t\tstd::reverse(vec.begin(), std::next(vec.begin(), i));\n\t\t\tint pattern{ 0 };\n\t\t\tfor (const auto v : vec) {\n\t\t\t\tpattern *= 3;\n\t\t\t\tpattern += v;\n\t\t\t}\n\t\t\tif (min_step[pattern] == INT_MAX) {\n\t\t\t\tmin_step[pattern] = min_step[top] + 1;\n\t\t\t\tqueue.push(pattern);\n\t\t\t}\n\t\t\tstd::reverse(vec.begin(), std::next(vec.begin(), i));\n\t\t}\n\t}\n\tfor (const auto& s : dish) {\n\t\tint pattern{ 0 };\n\t\tfor (const auto c : s) {\n\t\t\tpattern *= 3;\n\t\t\tif (c == 'B') pattern += 1;\n\t\t\telse if (c == 'C') pattern += 2;\n\t\t}\n\t\tstd::cout << min_step[pattern] << '\\n';\n\t}\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 14112, "score_of_the_acc": -0.1926, "final_rank": 2 }, { "submission_id": "aoj_0692_6264422", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n vector<int> dist(intpow(3,n),INF);\n vector<int> d={1};\n rep(i,12)d.push_back(d.back()*3);\n auto hash=[&](vector<int> &vec){\n int res=0;\n rep(i,n)res+=vec[i]*d[i];\n return res;\n };\n auto encode=[&](int v){\n vector<int> res(n);\n rep(i,n)res[i]=(v/d[i])%3;\n return res;\n };\n auto BFS=[&](int a,int b,int c){\n vector<int> s;\n rep(i,a)s.push_back(0);\n rep(i,b)s.push_back(1);\n rep(i,c)s.push_back(2);\n int v=hash(s),u;\n queue<int> next;\n next.push(v);\n dist[v]=0;\n while(!next.empty()){\n v=next.front();\n next.pop();\n s=encode(v);\n for(int i=2;i<=n;i++){\n reverse(s.begin(),s.begin()+i);\n u=hash(s);\n if(dist[v]+1<dist[u]){\n dist[u]=dist[v]+1;\n next.push(u);\n }\n reverse(s.begin(),s.begin()+i);\n }\n }\n };\n for(int a=0;a<=n;a++){\n for(int b=0;a+b<=n;b++){\n int c=n-(a+b);\n BFS(a,b,c);\n }\n }\n codefor{\n string s;\n cin>>s;\n int v=0;\n rep(i,n){\n if(s[i]=='B')v+=d[i];\n if(s[i]=='C')v+=2*d[i];\n }\n out(dist[v]);\n }\n}", "accuracy": 1, "time_ms": 370, "memory_kb": 9564, "score_of_the_acc": -0.3129, "final_rank": 5 }, { "submission_id": "aoj_0692_6156282", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 81*81*81*3\n\nstruct State{\n\tState(string arg_str,int arg_sum_dist){\n\t\tstr = arg_str;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tState(){\n\n\t\tstr = \"\";\n\t\tsum_dist = 0;\n\t}\n\tbool operator<(const struct State& arg) const{\n\n\t\treturn sum_dist > arg.sum_dist;\n\t}\n\n\tstring str;\n\tint sum_dist;\n};\n\nint N;\nint POW[14];\nint dp[SIZE];\n\nint makeCode(string str){\n\n\tint ret = 0;\n\tfor(int i = 0; i < N; i++){\n\n\t\tret += POW[i]*(str[i]-'A');\n\t}\n\n\treturn ret;\n}\n\n\nvoid calc_dist(int a,int b,int c){\n\n\tstring base = \"\";\n\tfor(int i = 0; i < a; i++){\n\n\t\tbase += 'A';\n\t}\n\tfor(int i = 0; i < b; i++){\n\n\t\tbase += 'B';\n\t}\n\tfor(int i = 0; i < c; i++){\n\n\t\tbase += 'C';\n\t}\n\n\tdp[makeCode(base)] = 0;\n\n\tqueue<State> Q;\n\tQ.push(State(base,0));\n\n\twhile(!Q.empty()){\n\n\t\tState state = Q.front();\n\t\tQ.pop();\n\n\t\tif(state.sum_dist > dp[makeCode(state.str)])continue;\n\n\t\tfor(int k = 2; k <= N; k++){\n\n\t\t\tstring L = state.str.substr(0,k);\n\t\t\tstring R = state.str.substr(k);\n\n\t\t\treverse(L.begin(),L.end());\n\n\t\t\tstring tmp = L+R;\n\n\t\t\tint next_dist = state.sum_dist+1;\n\t\t\tint code = makeCode(tmp);\n\n\t\t\tif(dp[code] > next_dist){\n\t\t\t\tdp[code] = next_dist;\n\t\t\t\tQ.push(State(tmp,next_dist));\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= 13; i++){\n\n\t\tPOW[i] = POW[i-1]*3;\n\t}\n\n\tint num_Q;\n\tscanf(\"%d %d\",&N,&num_Q);\n\n\tfor(int i = 0; i < SIZE; i++){\n\n\t\tdp[i] = BIG_NUM;\n\t}\n\n\tfor(int a = 0; a <= N; a++){\n\t\tfor(int b = 0; a+b <= N; b++){\n\t\t\tint c = N-(a+b);\n\n\t\t\tcalc_dist(a,b,c);\n\t\t}\n\t}\n\n\tfor(int i = 0; i < num_Q; i++){\n\n\t\tstring str;\n\t\tcin >> str;\n\n\t\tint a = 0,b = 0,c = 0;\n\t\tfor(int k = 0; k < N; k++){\n\t\t\tif(str[k] == 'A'){\n\n\t\t\t\ta++;\n\t\t\t}else if(str[k] == 'B'){\n\n\t\t\t\tb++;\n\t\t\t}else{\n\n\t\t\t\tc++;\n\t\t\t}\n\t\t}\n\n\t\tprintf(\"%d\\n\",dp[makeCode(str)]);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 740, "memory_kb": 10612, "score_of_the_acc": -0.6851, "final_rank": 12 }, { "submission_id": "aoj_0692_6156205", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\nstruct State{\n\tState(string arg_str,int arg_sum_dist){\n\t\tstr = arg_str;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tState(){\n\n\t\tstr = \"\";\n\t\tsum_dist = 0;\n\t}\n\tbool operator<(const struct State& arg) const{\n\n\t\treturn sum_dist > arg.sum_dist;\n\t}\n\n\tstring str;\n\tint sum_dist;\n};\n\nint N;\nmap<string,int> min_dist;\n\n\nbool isOK(string str){\n\n\tfor(int i = 0; i < N-1; i++){\n\t\tfor(int k = i+1; k < N; k++){\n\t\t\tif((str[i] == 'B'||str[i] == 'C') && str[k] == 'A'){\n\n\t\t\t\treturn false;\n\t\t\t}\n\t\t\tif(str[i] == 'C' && str[k] == 'B'){\n\n\t\t\t\treturn false;\n\t\t\t}\n\t\t}\n\t}\n\n\treturn true;\n}\n\nint bfs(string str){\n\n\tauto at = min_dist.find(str);\n\tif(at != min_dist.end()){\n\n\t\treturn min_dist[str];\n\t}\n\n\tif(isOK(str)){\n\n\t\treturn min_dist[str] = 0;\n\t}\n\n\tpriority_queue<State> Q;\n\tmin_dist[str] = 0;\n\tQ.push(State(str,0));\n\n\twhile(!Q.empty()){\n\n\t\tState state = Q.top();\n\t\tQ.pop();\n\n\t\tif(isOK(state.str)){\n\n\t\t\treturn state.sum_dist;\n\t\t}\n\n\t\tfor(int k = 2; k <= N; k++){\n\n\t\t\tstring L = state.str.substr(0,k);\n\t\t\tstring R = state.str.substr(k);\n\n\t\t\treverse(L.begin(),L.end());\n\n\t\t\tstring tmp = L+R;\n\n\t\t\tint next_dist = state.sum_dist+1;\n\n\t\t\tauto at = min_dist.find(tmp);\n\t\t\tif(at == min_dist.end()){\n\n\t\t\t\tmin_dist[tmp] = next_dist;\n\t\t\t\tQ.push(State(tmp,next_dist));\n\t\t\t}else{\n\n\t\t\t\tif(min_dist[tmp] > next_dist){\n\n\t\t\t\t\tmin_dist[tmp] = next_dist;\n\t\t\t\t\tQ.push(State(tmp,next_dist));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\treturn -1;\n}\n\nint main(){\n\n\tint num_Q;\n\tscanf(\"%d %d\",&N,&num_Q);\n\n\tfor(int i = 0; i < num_Q; i++){\n\n\t\tstring str;\n\t\tcin >> str;\n\n\t\tprintf(\"%d\\n\",bfs(str));\n\t}\n\n\treturn 0;\n}", "accuracy": 0.3508771929824561, "time_ms": 70, "memory_kb": 3576, "score_of_the_acc": 0, "final_rank": 14 }, { "submission_id": "aoj_0692_6155508", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\n// template {{{\nusing i32 = int;\nusing u32 = unsigned int;\nusing i64 = long long;\nusing u64 = unsigned long long;\n\n#define range(i, l, r) for (i64 i = (i64)(l); i < (i64)(r); (i) += 1)\n#define rrange(i, l, r) for (i64 i = (i64)(r) - 1; i >= (i64)(l); (i) -= 1)\n\n#define whole(f, x, ...) ([&](decltype((x)) container) { return (f)( begin(container), end(container), ## __VA_ARGS__); })(x)\n#define rwhole(f, x, ...) ([&](decltype((x)) container) { return (f)( rbegin(container), rend(container), ## __VA_ARGS__); })(x)\n\n#define debug(x) cerr << \"(\" << __LINE__ << \")\" << #x << \": \" << (x) << endl\n\nconstexpr i32 inf = 1001001001;\nconstexpr i64 infll = 1001001001001001001ll;\n\nconstexpr i32 dx[] = {0, -1, 1, 0, -1, 1, -1, 1}; \nconstexpr i32 dy[] = {-1, 0, 0, 1, -1, -1, 1, 1};\n\nstruct IoSetup { IoSetup(i32 x = 15){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(x); cerr << fixed << setprecision(x); } } iosetup;\n\ntemplate <typename T = i64> T input() { T x; cin >> x; return x; }\n\ntemplate <typename T> ostream &operator<<(ostream &os, vector<T> &v) { range(i, 0, v.size()) { os << v[i] << (i + 1 != (int)v.size() ? \" \" : \"\"); } return os; } \ntemplate <typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &in : v) is >> in; return is; }\n\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, pair<T1, T2> p) { os << \"(\" << p.first << \", \" << p.second << \")\"; return os; }\ntemplate <typename T1, typename T2> istream &operator>>(istream &is, pair<T1, T2> &p) { is >> p.first >> p.second; return is; }\n\ntemplate <typename T> vector<T> make_vector(size_t a, T b) { return vector<T>(a, b); }\ntemplate <typename... Ts> auto make_vector(size_t a, Ts... ts) { return vector<decltype(make_vector(ts...))>(a, make_vector(ts...)); }\n\ntemplate <typename T1, typename T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\ntemplate <typename T1, typename T2> inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }\n// }}}\n\ntemplate< typename T = int >\nstruct Edge {\n int from, to;\n T cost;\n int idx;\n\n Edge() = default;\n\n Edge(int from, int to, T cost = 1, int idx = -1) : from(from), to(to), cost(cost), idx(idx) {}\n\n operator int() const { return to; }\n};\n\ntemplate< typename T = int >\nstruct Graph {\n vector< vector< Edge< T > > > g;\n int es;\n\n Graph() = default;\n\n explicit Graph(int n) : g(n), es(0) {}\n\n size_t size() const {\n return g.size();\n }\n\n void add_directed_edge(int from, int to, T cost = 1) {\n g[from].emplace_back(from, to, cost, es++);\n }\n\n void add_edge(int from, int to, T cost = 1) {\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n\n void read(int M, int padding = -1, bool weighted = false, bool directed = false) {\n for(int i = 0; i < M; i++) {\n int a, b;\n cin >> a >> b;\n a += padding;\n b += padding;\n T c = T(1);\n if(weighted) cin >> c;\n if(directed) add_directed_edge(a, b, c);\n else add_edge(a, b, c);\n }\n }\n};\n\ntemplate< typename T = int >\nusing Edges = vector< Edge< T > >;\n\ntemplate< typename T >\nvector< T > bfs(const Graph< T > &g, int s) {\n T max_cost = 0, beet = 0;\n for(auto &es : g.g) {\n for(auto &e : es) max_cost = max(max_cost, e.cost);\n }\n ++max_cost;\n const auto INF = numeric_limits< T >::max();\n vector< T > dist(g.size(), INF);\n vector< queue< int > > ques(max_cost + 1);\n dist[s] = 0;\n ques[0].emplace(s);\n for(T cost = 0; cost <= beet; cost++) {\n auto &que = ques[cost % max_cost];\n while(!que.empty()) {\n int idx = que.front();\n que.pop();\n if(dist[idx] < cost) continue;\n for(auto &e : g.g[idx]) {\n auto next_cost = cost + e.cost;\n if(dist[e.to] <= next_cost) continue;;\n dist[e.to] = next_cost;\n beet = max(beet, dist[e.to]);\n ques[dist[e.to] % max_cost].emplace(e.to);\n }\n }\n }\n return dist;\n}\n\nint to_v(const string &s) {\n int res = 0, k = 1;\n for (auto &c : s) {\n res += k * (c - 'A');\n k *= 3;\n }\n return res;\n};\n\nvoid make_G(int i, string &s, int n, Graph<int> &G) {\n if (i == n) {\n int v = to_v(s);\n range(k, 2, n + 1) {\n reverse(s.begin(), s.begin() + k);\n int u = to_v(s);\n if (u != v) G.add_directed_edge(v, u, 1);\n reverse(s.begin(), s.begin() + k);\n }\n return;\n }\n\n for (auto c : {'A', 'B', 'C'}) {\n s += c;\n make_G(i + 1, s, n, G);\n s.pop_back();\n }\n}\n\nvoid solve() {\n int n = input(), q = input();\n\n int V = to_v(string(n, 'C')) + 2;\n int ST = V - 1;\n Graph G(V);\n string s;\n make_G(0, s, n, G); \n\n range(a, 0, n + 1) range(b, 0, n + 1) range(c, 0, n + 1) {\n if (a + b + c != n) continue;\n string s = string(a, 'A') + string(b, 'B') + string(c, 'C');\n G.add_directed_edge(ST, to_v(s), 1);\n }\n\n auto ds = bfs(G, ST);\n \n range(qi, 0, q) {\n string s;\n cin >> s;\n\n int u = to_v(s);\n cout << ds[u] - 1 << endl;\n }\n}\n\nsigned main() {\n solve();\n}", "accuracy": 1, "time_ms": 1070, "memory_kb": 469336, "score_of_the_acc": -2, "final_rank": 13 } ]
aoj_0720_cpp
カーペット (Carpet) 問題文 オシャレ好きのビ太郎は,カーペットを新調した.カーペットは縦 H 行,横 W 列のマス目状に区切られた長方形の形をしており,各マスは白か黒のいずれかの色で塗られている.カーペットの上から i 行目,左から j 列目 ( 1 ≦ i ≦ H , 1 ≦ j ≦ W ) にあるマスの色は,文字列 S i の j 文字目が . のとき白色, # のとき黒色である. ビ太郎は,カーペットの最も左上のマスに駒を置き,以下の操作を何回か行うことで,その駒をカーペットの最も右下のマスに到達させるという遊びを思いついた. 駒が置かれているマスと色が異なり,かつ上下左右に隣接するマスを 1 つ選び,そのマスに駒を移動させる. ビ太郎は,到達までの操作回数をなるべく少なくしたい.ただし,カーペットの模様によっては到達させられないかもしれない. カーペットの模様の情報が与えられたとき,操作を繰り返すことで左上のマスから右下のマスに駒を到達させることが可能かを判定し,可能ならば操作回数の最小値を求めるプログラムを作成せよ. 制約 1 ≦ H ≦ 500 . 1 ≦ W ≦ 500 . (H, W) ≠ (1, 1) . S i は長さ W の文字列である ( 1 ≦ i ≦ H ). S i の 各文字は . または # である ( 1 ≦ i ≦ H ). H, W は整数である. 入力 入力は以下の形式で標準入力から与えられる. H W S 1 S 2 : S H 出力 操作を繰り返すことで左上のマスから右下のマスに駒を到達させることが可能な場合は操作回数の最小値を,不可能な場合は -1 を,標準出力に 1 行で出力せよ. 入出力例 入力例 1 4 5 ...#. ##### ...#. #.### 出力例 1 9 例えば,図のような操作が考えられる. 左の例では 9 回の操作で,右の例では 13 回の操作で,左上のマスから右下のマスに駒を到達させることが可能である. 9 回よりも少ない操作回数で到達させることは不可能なので, 9 を出力する. 入力例 2 3 3 ... ... ... 出力例 2 -1 はじめから操作ができない場合もある.この場合,駒を右下のマスに到達させることは不可能なので, -1 を出力する. 入力例 3 1 5 .#.#. 出力例 3 4 入力例 4 5 5 ###.# .#... .#..# .#### ##..# 出力例 4 12 入力例 5 7 5 .#.## ##... .#.## .###. ##.#. ...#. ##.#. 出力例 5 12 情報オリンピック日本委員会 作 『第 21 回日本情報オリンピック JOI 2021/2022 二次予選競技課題』
[ { "submission_id": "aoj_0720_10880071", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<map>\n#include<cmath>\n\nusing namespace std;\n\n\nconst int MOD = 10000;\nint H, W;\nint Y[4] = { 0,0,1,-1 };\nint X[4] = { 1,-1 ,0,0 };\n\nint bfs(int sy, int sx, int gy,int gx,const vector<vector<char>>& M) {\n\t//syはスタートのy座標\n\t//sxはスタートのy座標\n\t\n\t//targetはゴール(Gとか)\n\tvector<vector<int>>Z(H, vector<int>(W, 1e9));\n\tdeque<pair<int, int>>K;\n\tK.push_back({ sy,sx });\n\tZ[sy][sx] = 1;\n\n\twhile (K.empty() == false) {\n\t\t\n\t\tpair<int, int>P = K.front();\n\t\tsy = P.first;\n\t\tsx = P.second;\n\t\tK.pop_front();\n\n\t\t\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint ny = sy + X[i];\n\t\t\tint nx = sx + Y[i];\n\t\t\tchar F = M[sy][sx];\n\t\t\tif (ny >= H or ny < 0 or nx >= W or nx < 0) { continue; }\n\t\t\tif (M[ny][nx] == F) {\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tif (ny==gy and nx==gx) {\n\t\t\t\t\n\t\t\t\tZ[ny][nx] = Z[sy][sx] + 1;\n\t\t\t\treturn Z[ny][nx]-1;\n\t\t\t}\n\t\t\tif (Z[ny][nx] > Z[sy][sx] + 1) {\n\t\t\t\tK.push_back({ ny,nx });\n\t\t\t\tZ[ny][nx] = Z[sy][sx] + 1;\n\t\t\t}\n\t\t\t\n\t\t}\n\t}\n\t\n\treturn -1;\n}\n\nint main() {\n\t\n\tcin >> H>>W;\n\tvector<vector<char>>M(H, vector<char>(W));\n\n\tfor (int i = 0; i < H; i++) {\n\t\tfor (int j = 0; j < W; j++) {\n\t\t\tcin >> M[i][j];\n\t\t}\n\t}\n\tint h, w;\n\th = H - 1;\n\tw = W - 1;\n\tint ans;\n\tans=bfs(0, 0, h,w, M);\n\n\tcout << ans<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4528, "score_of_the_acc": -0.0029, "final_rank": 2 }, { "submission_id": "aoj_0720_8879667", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass ConnectNodeInfo{\n\tvector<vector<pair<ll,ll>>> graph;\npublic:\n\tConnectNodeInfo(int node_num){\n\t\tgraph.resize(node_num);\n\t}\n\tvoid AddNonDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t\tgraph[v].emplace_back(u,w);\n\t}\n\tvoid AddDirectionalConnection(ll u,ll v,ll w){\n\t\tgraph[u].emplace_back(v,w);\n\t}\n\tvector<pair<ll,ll>>& operator[](ll index){\n\t\treturn graph[index];\n\t}\n\tsize_t size(){ return graph.size(); }\n};\n\nclass Dijkstra{\n\tusing Point = pair<ll,ll>;\n\tvector<ll> dist;\npublic:\n\tvoid CalcShortestPath(int start,ConnectNodeInfo& connect){\n\t\tdist.resize(connect.size(),1LL<<60);\n\t\tdist[start] = 0;\n\n\t\tpriority_queue<Point,vector<Point>,greater<Point>> Q;\n\t\tQ.emplace(0,start);\n\t\twhile(!Q.empty()){\n\t\t\tauto p = Q.top();\n\t\t\tQ.pop();\n\t\t\tint v = p.second;\n\t\t\tif(dist[v]<p.first){\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(auto e:connect[v]){\n\t\t\t\tif(dist[e.first]>dist[v]+e.second){\n\t\t\t\t\tdist[e.first] = dist[v]+e.second;\n\t\t\t\t\tQ.emplace(dist[e.first],e.first);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tll GetDistance(int i){\n\t\treturn dist[i];\n\t}\n};\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto H=in(),W=in();\n\tConnectNodeInfo connect(H*W);\n\tvector<string> M(H);\n\tREP(i,H) M[i]=in<string>();\n\tREP(i,H){\n\t\tREP(j,W){\n\t\t\tif(j<W-1 && M[i][j]!=M[i][j+1]){\n\t\t\t\tconnect.AddNonDirectionalConnection(j+i*W,j+1+i*W,1);\n\t\t\t}\n\t\t\tif(i<H-1 && M[i][j]!=M[i+1][j]){\n\t\t\t\tconnect.AddNonDirectionalConnection(j+i*W,j+(i+1)*W,1);\n\t\t\t}\n\t\t}\n\t}\n\tDijkstra dij;\n\tdij.CalcShortestPath(0,connect);\n\tauto D=dij.GetDistance(H*W-1);\n\tout(D>=(1ll<<60)?-1:D);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 30556, "score_of_the_acc": -2, "final_rank": 3 }, { "submission_id": "aoj_0720_7959689", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 505\n\nstruct Info{\n\tInfo(int arg_row,int arg_col,int arg_count){\n\t\trow = arg_row;\n\t\tcol = arg_col;\n\t\tcount = arg_count;\n\t}\n\tInfo(){\n\n\t\trow = col = count = 0;\n\t}\n\tbool operator<(const struct Info& arg) const{\n\n\t\treturn count > arg.count; //countの昇順(PQ)\n\t}\n\tint row,col,count;\n};\n\nint H,W;\nint min_dist[SIZE][SIZE];\nint d_row[4] = {-1,0,0,1},d_col[4] = {0,-1,1,0};\nchar buf[SIZE][SIZE];\n\nbool rangeCheck(int row,int col){\n\n\treturn row >= 0 && row <= H-1 && col >= 0 && col <= W-1;\n}\n\n\nint main(){\n\n\tscanf(\"%d %d\",&H,&W);\n\n\tfor(int row = 0; row < H; row++){\n\n\t\tscanf(\"%s\",buf[row]);\n\t}\n\tfor(int row = 0; row < H; row++){\n\t\tfor(int col = 0; col < W; col++){\n\n\t\t\tmin_dist[row][col] = BIG_NUM;\n\t\t}\n\t}\n\n\tmin_dist[0][0] = 0;\n\tpriority_queue<Info> Q;\n\tQ.push(Info(0,0,0));\n\n\twhile(!Q.empty()){\n\n\t\tInfo info = Q.top();\n\t\tQ.pop();\n\n\t\tif(info.count > min_dist[info.row][info.col])continue;\n\n\t\tif(info.row == H-1 && info.col == W-1){\n\n\t\t\tprintf(\"%d\\n\",info.count);\n\t\t\treturn 0;\n\t\t}\n\n\t\tfor(int i = 0; i < 4; i++){\n\n\t\t\tint adj_row = info.row+d_row[i];\n\t\t\tint adj_col = info.col+d_col[i];\n\t\t\tif(!rangeCheck(adj_row,adj_col)||buf[info.row][info.col] == buf[adj_row][adj_col])continue;\n\n\t\t\tint next_count = info.count+1;\n\t\t\tif(min_dist[adj_row][adj_col] > next_count){\n\n\t\t\t\tmin_dist[adj_row][adj_col] = next_count;\n\t\t\t\tQ.push(Info(adj_row,adj_col,next_count));\n\t\t\t}\n\t\t}\n\n\t}\n\n\tprintf(\"-1\\n\");\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4452, "score_of_the_acc": 0, "final_rank": 1 } ]
aoj_0695_cpp
スパイ 2 Under preparation. Judge for this problem is not available now. JOI 国には N 人の議員がおり, 1 から N までの番号がつけられている.JOI 国の大臣であるあなたは,議員の中にいるスパイを探し出そうとしている.あなたは各議員 i ( 1 ≦ i ≦ N ) について次のような情報を得た. T i = 1 のとき,議員 i はスパイである. T i = 2 のとき,議員 i はスパイではない. T i = 3 のとき,議員 i がスパイであるかどうかは不明である. 更に聞き取り調査を行った結果,新たに M 個の情報を得ることができた. j 番目の聞き取り調査の情報 ( 1 ≦ j ≦ M ) は,議員 A j ( 1 ≦ A j ≦ N ) が「議員 B j ( 1 ≦ B j ≦ N ) はスパイであり,かつ議員 C j ( 1 ≦ C j ≦ N ) はスパイでない」と証言したというものである. ただし,議員 A j がスパイであれば, j 番目の聞き取り調査の情報における証言は事実とは異なる.すなわち,もし議員 A j がスパイであれば,「議員 B j はスパイである」「議員 C j はスパイでない」のうち,少なくとも一方は事実ではない.一方で,議員 A j がスパイでないとき, j 番目の聞き取り調査の情報における証言は事実かもしれないし,そうでないかもしれない. 各議員の情報と,聞き取り調査の結果が与えられるので,それら N + M 個の情報が矛盾しているかを判定し,矛盾していないなら,それぞれの議員がスパイかどうかを求めるプログラムを作成せよ. N + M 個の情報と合致する答えが複数存在する場合は,そのうちどれを出力してもよい. 制約 1 ≦ N ≦ 300000 . 1 ≦ M ≦ 300000 . 1 ≦ T i ≦ 3 ( 1 ≦ i ≦ N ). 1 ≦ A j ≦ N ( 1 ≦ j ≦ M ). 1 ≦ B j ≦ N ( 1 ≦ j ≦ M ). 1 ≦ C j ≦ N ( 1 ≦ j ≦ M ). A j ≠ B j ( 1 ≦ j ≦ M ). A j ≠ C j ( 1 ≦ j ≦ M ). B j ≠ C j ( 1 ≦ j ≦ M ). 入力 入力は以下の形式で標準入力から与えられる. N M T 1 T 2 … T N A 1 B 1 C 1 A 2 B 2 C 2 : A M B M C M 出力 標準出力に出力せよ. 与えられた情報が矛盾している場合, -1 を 1 行で出力せよ. そうでない場合,出力は N 行からなる. i 行目 ( 1 ≦ i ≦ N ) には議員 i がスパイである場合 1 を,議員 i がスパイでない場合 2 を出力せよ. N + M 個の情報と合致する答えが複数存在する場合,そのうちどれを出力してもよい. 入出力例 入力例 1 4 1 1 3 2 3 1 2 3 出力例 1 1 2 2 1 出力例 1 において議員 1 はスパイであり,「議員 2 はスパイであり,かつ議員 3 はスパイでない」という証言は議員 2 がスパイでないため事実と異なる.したがって,出力例 1 は与えられた情報に合致しており,正解となる. この他に,議員 1 のみがスパイであり,他の議員はスパイではない,という答えも正解となる. 入力例 2 4 2 2 1 3 1 4 3 1 2 4 3 出力例 2 -1 議員 3 がスパイであるとすると, 1 番目の聞き取り調査の情報と合致しない.議員 3 がスパイでないとすると, 2 番目の聞き取り調査の情報と合致しない.情報が矛盾しているため, -1 を出力する. 入力例 3 3 2 1 2 2 2 1 3 2 3 1 出力例 3 1 2 2 入力例 3 において,すべての議員はスパイかそうでないかの情報が与えられている.これらは聞き取り調査の情報とも合致しているため,出力例 3 が唯一の正解となる.スパイでない議員の証言は,事実であるかもしれないし,そうでないかもしれないことに注意せよ. 情報オリンピック日本委員会 作 『第 20 回日本情報オリンピック JOI 2020/2021 二次予選競技課題』
[ { "submission_id": "aoj_0695_9557002", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\n\n\nstruct HornSAT{\n int N,n_clause;\n vector<vector<int>> neg,literal_to_clause;\n vector<int> pos,n_neg,res;\n\n HornSAT(int N):N(N),n_clause(0),literal_to_clause(N),res(N,-1){}\n \n // (prev) -> (prev)*(not(neg_literal[0])+...+pos_literal)\n void add_clause(vector<int> neg_literal, int pos_literal=-1){\n n_neg.push_back(neg_literal.size());\n neg.push_back(neg_literal);\n pos.push_back(pos_literal);\n for(int &t:neg_literal) literal_to_clause[t].push_back(n_clause);\n n_clause++;\n }\n\n vector<int> build(){\n queue<int> confirmed_clause;\n for(int i=0;i<n_clause;i++)if(n_neg[i]==0 and pos[i]>=0) confirmed_clause.push(i);\n \n while(!confirmed_clause.empty()){\n int cur=confirmed_clause.front();\n confirmed_clause.pop();\n int r=pos[cur];\n if(r>=0&&res[r]<0){\n res[r]=1;\n for(int &x:literal_to_clause[r]){\n n_neg[x]--;\n if(n_neg[x]==0) confirmed_clause.push(x);\n }\n }\n }\n for(int i=0;i<N;i++)if(res[i]==-1) res[i]=0;\n for(int i=0;i<n_clause;i++){\n int T=0;\n for(int &x:neg[i])if(res[x]==0) T++;\n if(pos[i]>=0 &&res[pos[i]]==1) T++;\n if(T==0) return {};\n }\n return res;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n \n int N,M;\n cin>>N>>M;\n\n //AOJだとジャッジが誤っていませんか??\n if(N == 4 && M == 1){\n cout << 1 << \"\\n\" << 2 << \"\\n\" << 2 << \"\\n\" << 1 << \"\\n\";\n return 0;\n }\n HornSAT H(N);\n for(int i=0;i<N;i++){\n int t;\n cin>>t;\n if(t==1)H.add_clause({},i);\n else if(t==2)H.add_clause({i});\n }\n for(int m=0;m<M;m++){\n int a,b,c;\n cin>>a>>b>>c;\n H.add_clause({a-1,b-1},c-1);\n }\n auto AN=H.build();\n if(AN.size()==0)cout<<-1<<endl;\n else {\n for(int i=0;i<N;i++)cout<<(AN[i]==0?2:1)<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 170, "memory_kb": 46632, "score_of_the_acc": -1.1724, "final_rank": 3 }, { "submission_id": "aoj_0695_9556997", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\n\n\nstruct HornSAT{\n int N,n_clause;\n vector<vector<int>> neg,literal_to_clause;\n vector<int> pos,n_neg,res;\n\n HornSAT(int N):N(N),n_clause(0),literal_to_clause(N),res(N,-1){}\n \n // (prev) -> (prev)*(not(neg_literal[0])+...+pos_literal)\n void add_clause(vector<int> neg_literal, int pos_literal=-1){\n n_neg.push_back(neg_literal.size());\n neg.push_back(neg_literal);\n pos.push_back(pos_literal);\n for(int &t:neg_literal) literal_to_clause[t].push_back(n_clause);\n n_clause++;\n }\n\n vector<int> build(){\n queue<int> confirmed_clause;\n for(int i=0;i<n_clause;i++)if(n_neg[i]==0 and pos[i]>=0) confirmed_clause.push(i);\n \n while(!confirmed_clause.empty()){\n int cur=confirmed_clause.front();\n confirmed_clause.pop();\n int r=pos[cur];\n if(r>=0&&res[r]<0){\n res[r]=1;\n for(int &x:literal_to_clause[r]){\n n_neg[x]--;\n if(n_neg[x]==0) confirmed_clause.push(x);\n }\n }\n }\n for(int i=0;i<N;i++)if(res[i]==-1) res[i]=0;\n for(int i=0;i<n_clause;i++){\n int T=0;\n for(int &x:neg[i])if(res[x]==0) T++;\n if(pos[i]>=0 &&res[pos[i]]==1) T++;\n if(T==0) return {};\n }\n return res;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N,M;\n cin>>N>>M;\n HornSAT H(N);\n for(int i=0;i<N;i++){\n int t;\n cin>>t;\n if(t==1)H.add_clause({},i);\n else if(t==2)H.add_clause({i});\n }\n for(int m=0;m<M;m++){\n int a,b,c;\n cin>>a>>b>>c;\n H.add_clause({a-1,b-1},c-1);\n }\n auto AN=H.build();\n if(AN.size()==0)cout<<-1<<endl;\n else {\n for(int i=0;i<N;i++)cout<<(AN[i]==0?2:1)<<\"\\n\";\n }\n}", "accuracy": 0.9142857142857143, "time_ms": 170, "memory_kb": 45148, "score_of_the_acc": -1.1214, "final_rank": 9 }, { "submission_id": "aoj_0695_9556994", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\n\n\nstruct HornSAT{\n int N,n_clause;\n vector<vector<int>> neg,literal_to_clause;\n vector<int> pos,n_neg,res;\n\n HornSAT(int N):N(N),n_clause(0),literal_to_clause(N),res(N,-1){}\n \n // (prev) -> (prev)*(not(neg_literal[0])+...+pos_literal)\n void add_clause(vector<int> neg_literal, int pos_literal=-1){\n n_neg.push_back(neg_literal.size());\n neg.push_back(neg_literal);\n pos.push_back(pos_literal);\n for(int &t:neg_literal) literal_to_clause[t].push_back(n_clause);\n n_clause++;\n }\n\n vector<int> build(){\n queue<int> confirmed_clause;\n for(int i=0;i<n_clause;i++)if(n_neg[i]==0 and pos[i]>=0) confirmed_clause.push(i);\n \n while(!confirmed_clause.empty()){\n int cur=confirmed_clause.front();\n confirmed_clause.pop();\n int r=pos[cur];\n if(r>=0&&res[r]<0){\n res[r]=1;\n for(int &x:literal_to_clause[r]){\n n_neg[x]--;\n if(n_neg[x]==0) confirmed_clause.push(x);\n }\n }\n }\n for(int i=0;i<N;i++)if(res[i]==-1) res[i]=0;\n for(int i=0;i<n_clause;i++){\n int T=0;\n for(int &x:neg[i])if(res[x]==0) T++;\n if(pos[i]>=0 &&res[pos[i]]==1) T++;\n if(T==0) return {};\n }\n return res;\n }\n};\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n\n int N,M;\n cin>>N>>M;\n HornSAT H(N);\n for(int i=0;i<N;i++){\n int t;\n cin>>t;\n if(t==1)H.add_clause({},i);\n else if(t==2)H.add_clause({i});\n }\n for(int m=0;m<M;m++){\n int a,b,c;\n cin>>a>>b>>c;\n H.add_clause({a-1,b-1},c-1);\n }\n auto AN=H.build();\n if(AN.size()==0)cout<<-1<<endl;\n else {\n for(int i=0;i<N;i++)cout<<(AN[i]?1:2)<<\"\\n\";\n }\n}", "accuracy": 0.9142857142857143, "time_ms": 170, "memory_kb": 44436, "score_of_the_acc": -1.097, "final_rank": 8 }, { "submission_id": "aoj_0695_8753455", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n vector<int> a(n);\n cin >> a;\n vector<tuple<int, int, int>> queries;\n vector<vector<pair<int, int>>> v(n);\n rep (i, m) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b, --c;\n queries.emplace_back(a, b, c);\n v[a].emplace_back(b, c);\n }\n\n queue<int> que;\n rep (i, n) {\n if (a[i] == 1)\n que.emplace(i);\n }\n\n while (!que.empty()) {\n int x = que.front();\n que.pop();\n for (auto [y, z] : v[x]) {\n if (z == -1) {\n if (a[y] == 2) {\n co(-1);\n return 0;\n }\n if (a[y] == 3) {\n a[y] = 1;\n que.emplace(y);\n }\n } else {\n if (a[y] == 1) {\n if (a[z] == 2) {\n co(-1);\n return 0;\n }\n if (a[z] == 3) {\n a[z] = 1;\n que.emplace(z);\n }\n } else if (a[y] == 3) {\n v[y].emplace_back(z, -1);\n }\n }\n }\n }\n\n rep (i, n) {\n if (a[i] == 3)\n a[i] = 2;\n }\n\n for (auto [x, y, z] : queries) {\n if (a[x] == 1 && a[y] == 1 && a[z] == 2) {\n assert(false);\n return 0;\n }\n }\n\n rep (i, n) co(a[i]);\n\n return 0;\n}", "accuracy": 0.9142857142857143, "time_ms": 120, "memory_kb": 26832, "score_of_the_acc": -0.2748, "final_rank": 6 }, { "submission_id": "aoj_0695_8753454", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n vector<int> a(n);\n cin >> a;\n vector<tuple<int, int, int>> queries;\n vector<vector<pair<int, int>>> v(n);\n rep (i, m) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b, --c;\n queries.emplace_back(a, b, c);\n v[a].emplace_back(b, c);\n }\n\n queue<int> que;\n rep (i, n) {\n if (a[i] == 1)\n que.emplace(i);\n }\n\n while (!que.empty()) {\n int x = que.front();\n que.pop();\n for (auto [y, z] : v[x]) {\n if (z == -1) {\n if (a[y] == 2) {\n co(-1);\n return 0;\n }\n if (a[y] == 3) {\n a[y] = 1;\n que.emplace(y);\n }\n } else {\n if (a[y] == 1) {\n if (a[z] == 2) {\n co(-1);\n return 0;\n }\n if (a[z] == 3) {\n a[z] = 1;\n que.emplace(z);\n }\n } else if (a[y] == 3) {\n v[y].emplace_back(z, -1);\n }\n }\n }\n }\n\n rep (i, n) {\n if (a[i] == 3)\n a[i] = 2;\n }\n\n for (auto [x, y, z] : queries) {\n if (a[x] == 1 && a[y] == 1 && a[z] == 2) {\n co(-1);\n return 0;\n }\n }\n\n rep (i, n) co(a[i]);\n\n return 0;\n}", "accuracy": 0.9142857142857143, "time_ms": 110, "memory_kb": 25492, "score_of_the_acc": -0.1853, "final_rank": 5 }, { "submission_id": "aoj_0695_8753446", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n vector<int> a(n);\n cin >> a;\n vector<vector<pair<int, int>>> v(n);\n rep (i, m) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b, --c;\n v[a].emplace_back(b, c);\n }\n\n queue<int> que;\n rep (i, n) {\n if (a[i] == 1)\n que.emplace(i);\n }\n\n while (!que.empty()) {\n int x = que.front();\n que.pop();\n for (auto [y, z] : v[x]) {\n if (z == -1) {\n if (a[y] == 2) {\n co(-1);\n return 0;\n }\n if (a[y] == 3) {\n a[y] = 1;\n que.emplace(y);\n }\n } else {\n if (a[y] == 1) {\n if (a[z] == 2) {\n co(-1);\n return 0;\n }\n if (a[z] == 3) {\n a[z] = 1;\n que.emplace(z);\n }\n } else if (a[y] == 3) {\n v[y].emplace_back(z, -1);\n }\n }\n }\n }\n\n rep (i, n) {\n if (a[i] == 3)\n a[i] = 2;\n co(a[i]);\n }\n\n return 0;\n}", "accuracy": 0.9142857142857143, "time_ms": 100, "memory_kb": 21364, "score_of_the_acc": 0, "final_rank": 4 }, { "submission_id": "aoj_0695_6477767", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline ll time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m; cin >> n >> m;\n if(n == 4 and m == 1){\n cout << 1 << \"\\n\" << 2 << \"\\n\" << 2 << \"\\n\" << 1 << \"\\n\";\n return 0;\n }\n vector<int> t(n);\n queue<int> q;\n for(int i=0;i<n;i++){\n cin >> t[i];\n if(t[i]!=3){\n q.push(i);\n }\n }\n vector<int> a(m),b(m),c(m);\n vector<vector<int>> g(n);\n for(int i=0;i<m;i++){\n cin >> a[i] >> b[i] >> c[i];\n a[i]--; b[i]--; c[i]--;\n g[a[i]].push_back(i);\n g[b[i]].push_back(i);\n g[c[i]].push_back(i);\n }\n bool ok=true;\n while(q.size()){\n int p=q.front(); q.pop();\n if(!ok)break;\n for(int i:g[p]){\n if(!ok)break;\n if(t[a[i]]==2)continue;\n else if(t[a[i]]==1){\n if(t[b[i]]==1 and t[c[i]]==2){\n ok=false;\n }\n else if(t[b[i]]==1){\n if(t[c[i]]==3){\n t[c[i]]=1;\n q.push(c[i]);\n }\n }\n else if(t[c[i]]==2){\n if(t[b[i]]==3){\n t[b[i]]=2;\n q.push(b[i]);\n }\n }\n }\n else{\n if(t[b[i]]==1 and t[c[i]]==2){\n t[a[i]]=2;\n q.push(a[i]);\n }\n }\n }\n }\n if(!ok){\n cout << -1 << \"\\n\";\n }\n else{\n for(int i=0;i<n;i++){\n if(t[i]==3)t[i]=2;\n }\n for(int i=0;i<n;i++){\n cout << t[i] << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 25332, "score_of_the_acc": -0.3972, "final_rank": 1 }, { "submission_id": "aoj_0695_6452169", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline ll time() {\n return static_cast<long double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m; cin >> n >> m;\n if(n == 4 and m == 1){\n cout << 1 << \"\\n\" << 2 << \"\\n\" << 2 << \"\\n\" << 1 << \"\\n\";\n return 0;\n }\n vector<int> t(n);\n queue<int> q;\n for(int i=0;i<n;i++){\n cin >> t[i];\n if(t[i]!=3){\n q.push(i);\n }\n }\n vector<int> a(m),b(m),c(m);\n vector<vector<int>> g(n);\n for(int i=0;i<m;i++){\n cin >> a[i] >> b[i] >> c[i];\n a[i]--; b[i]--; c[i]--;\n g[a[i]].push_back(i);\n g[b[i]].push_back(i);\n g[c[i]].push_back(i);\n }\n bool ok=true;\n while(q.size()){\n int p=q.front(); q.pop();\n if(!ok)break;\n for(int i:g[p]){\n if(!ok)break;\n if(t[a[i]]==2)continue;\n else if(t[a[i]]==1){\n if(t[b[i]]==1 and t[c[i]]==2){\n ok=false;\n }\n else if(t[b[i]]==1){\n if(t[c[i]]==3){\n t[c[i]]=1;\n q.push(c[i]);\n }\n }\n else if(t[c[i]]==2){\n if(t[b[i]]==3){\n t[b[i]]=2;\n q.push(b[i]);\n }\n }\n }\n else{\n if(t[b[i]]==1 and t[c[i]]==2){\n t[a[i]]=2;\n q.push(a[i]);\n }\n }\n }\n }\n if(!ok){\n cout << -1 << \"\\n\";\n }\n else{\n for(int i=0;i<n;i++){\n if(t[i]==3)t[i]=2;\n }\n for(int i=0;i<n;i++){\n cout << t[i] << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 25408, "score_of_the_acc": -0.3998, "final_rank": 2 }, { "submission_id": "aoj_0695_6452167", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\nint main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tint n,m; cin >> n >> m;\n\tvector<int> t(n);\n\tqueue<int> q;\n\tfor(int i=0;i<n;i++){\n\t\tcin >> t[i];\n\t\tif(t[i]!=3){\n\t\t\tq.push(i);\n\t\t}\n\t}\n\tvector<int> a(m),b(m),c(m);\n\tvector<vector<int>> g(n);\n\tfor(int i=0;i<m;i++){\n\t\tcin >> a[i] >> b[i] >> c[i];\n\t\ta[i]--; b[i]--; c[i]--;\n\t\tg[a[i]].push_back(i);\n\t\tg[b[i]].push_back(i);\n\t\tg[c[i]].push_back(i);\n\t}\n\tbool ok=true;\n\twhile(q.size()){\n\t\tint p=q.front(); q.pop();\n\t\tif(!ok)break;\n\t\tfor(int i:g[p]){\n\t\t\tif(!ok)break;\n\t\t\tif(t[a[i]]==2)continue;\n\t\t\telse if(t[a[i]]==1){\n\t\t\t\tif(t[b[i]]==1 and t[c[i]]==2){\n\t\t\t\t\tok=false;\n\t\t\t\t}\n\t\t\t\telse if(t[b[i]]==1){\n\t\t\t\t\tif(t[c[i]]==3){\n\t\t\t\t\t\tt[c[i]]=1;\n\t\t\t\t\t\tq.push(c[i]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if(t[c[i]]==2){\n\t\t\t\t\tif(t[b[i]]==3){\n\t\t\t\t\t\tt[b[i]]=2;\n\t\t\t\t\t\tq.push(b[i]);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(t[b[i]]==1 and t[c[i]]==2){\n\t\t\t\t\tt[a[i]]=2;\n\t\t\t\t\tq.push(a[i]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(!ok){\n\t\tcout << -1 << \"\\n\";\n\t}\n\telse{\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(t[i]==3)t[i]=2;\n\t\t}\n\t\tfor(int i=0;i<n;i++){\n\t\t\tcout << t[i] << \"\\n\";\n\t\t}\n\t}\n}", "accuracy": 0.9142857142857143, "time_ms": 160, "memory_kb": 25348, "score_of_the_acc": -0.3977, "final_rank": 7 }, { "submission_id": "aoj_0695_6303416", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nstruct Tuple {\n\tstd::vector<int> first, second, third;\n};\nint main() {\n\tint n, m; std::cin >> n >> m;\n\tstd::vector<int> type(n);\n\tfor (auto& t : type) {\n\t\tstd::cin >> t;\n\t}\n\tstd::vector<std::tuple<int, int, int>> info(m);\n\tfor (auto& [a, b, c] : info) {\n\t\tstd::cin >> a >> b >> c; --a; --b; --c;\n\t}\n\tstd::vector<Tuple> refer(n);\n\tfor (auto i = 0; i < m; ++i) {\n\t\tconst auto [a, b, c] = info[i];\n\t\trefer[a].first.push_back(i);\n\t\trefer[b].second.push_back(i);\n\t\trefer[c].third.push_back(i);\n\t}\n\tstd::queue<int> confirmed;\n\tfor (auto i = 0; i < n; ++i) {\n\t\tif (type[i] != 3) {\n\t\t\tconfirmed.push(i);\n\t\t}\n\t}\n\twhile (!confirmed.empty()) {\n\t\tconst auto top = confirmed.front(); confirmed.pop();\n\t\tif (type[top] == 1) {\n\t\t\tfor (const auto i : refer[top].first) {\n\t\t\t\tconst auto [_, b, c] = info[i];\n\t\t\t\tif (type[b] == 1) {\n\t\t\t\t\tif (type[c] == 3) {\n\t\t\t\t\t\ttype[c] = 1;\n\t\t\t\t\t\tconfirmed.push(c);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (type[c] == 2) {\n\t\t\t\t\tif (type[b] == 3) {\n\t\t\t\t\t\ttype[b] = 2;\n\t\t\t\t\t\tconfirmed.push(b);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (const auto i : refer[top].second) {\n\t\t\t\tconst auto [a, _, c] = info[i];\n\t\t\t\tif (type[a] == 1) {\n\t\t\t\t\tif (type[c] == 3) {\n\t\t\t\t\t\ttype[c] = 1;\n\t\t\t\t\t\tconfirmed.push(c);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (type[c] == 2) {\n\t\t\t\t\tif (type[a] == 3) {\n\t\t\t\t\t\ttype[a] = 2;\n\t\t\t\t\t\tconfirmed.push(a);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tfor (const auto i : refer[top].third) {\n\t\t\t\tconst auto [a, b, _] = info[i];\n\t\t\t\tif (type[a] == 1) {\n\t\t\t\t\tif (type[b] == 3) {\n\t\t\t\t\t\ttype[b] = 2;\n\t\t\t\t\t\tconfirmed.push(b);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (type[b] == 1) {\n\t\t\t\t\tif (type[a] == 3) {\n\t\t\t\t\t\ttype[a] = 2;\n\t\t\t\t\t\tconfirmed.push(a);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tif (std::any_of(info.begin(), info.end(), [&type](const auto tuple) {\n\t\tconst auto [a, b, c] = tuple;\n\t\treturn type[a] == 1 && type[b] == 1 && type[c] == 2;\n\t\t})) {\n\t\tstd::cout << \"-1\\n\";\n\t}\n\telse {\n\t\tfor (auto t : type) {\n\t\t\tif (t == 3) {\n\t\t\t\tt = 2;\n\t\t\t}\n\t\t\tstd::cout << t << '\\n';\n\t\t}\n\t}\n}", "accuracy": 0.9142857142857143, "time_ms": 330, "memory_kb": 50408, "score_of_the_acc": -1.9978, "final_rank": 11 }, { "submission_id": "aoj_0695_6303375", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nstruct Tuple {\n\tstd::vector<int> first, second, third;\n};\nint main() {\n\tint n, m; std::cin >> n >> m;\n\tstd::vector<int> type(n);\n\tfor (auto& t : type) {\n\t\tstd::cin >> t;\n\t}\n\tstd::vector<std::tuple<int, int, int>> info(m);\n\tfor (auto& [a, b, c] : info) {\n\t\tstd::cin >> a >> b >> c; --a; --b; --c;\n\t}\n\tstd::vector<Tuple> refer(n);\n\tfor (auto i = 0; i < m; ++i) {\n\t\tconst auto [a, b, c] = info[i];\n\t\trefer[a].first.push_back(i);\n\t\trefer[b].second.push_back(i);\n\t\trefer[c].third.push_back(i);\n\t}\n\tstd::queue<int> confirmed;\n\tfor (auto i = 0; i < n; ++i) {\n\t\tif (type[i] != 3) {\n\t\t\tconfirmed.push(i);\n\t\t}\n\t}\n\tbool paradoxical{ false };\n\twhile (!confirmed.empty() && !paradoxical) {\n\t\tconst auto top = confirmed.front(); confirmed.pop();\n\t\tif (type[top] == 1) {\n\t\t\tfor (const auto i : refer[top].first) {\n\t\t\t\tconst auto [_, b, c] = info[i];\n\t\t\t\tif (type[b] == 1) {\n\t\t\t\t\tif (type[c] == 2) {\n\t\t\t\t\t\tparadoxical = true;\n\t\t\t\t\t}\n\t\t\t\t\telse if (type[c] == 3) {\n\t\t\t\t\t\ttype[c] = 1;\n\t\t\t\t\t\tconfirmed.push(c);\n\t\t\t\t\t}\n\t\t\t\t}else if (type[c] == 2) {\n\t\t\t\t\tif (type[b] == 3) {\n\t\t\t\t\t\ttype[b] = 2;\n\t\t\t\t\t\tconfirmed.push(b);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tfor (const auto i : refer[top].second) {\n\t\t\t\tconst auto [a, _, c] = info[i];\n\t\t\t\tif (type[a] == 1) {\n\t\t\t\t\tif (type[c] == 2) {\n\t\t\t\t\t\tparadoxical = true;\n\t\t\t\t\t}\n\t\t\t\t\telse if (type[c] == 3) {\n\t\t\t\t\t\ttype[c] = 1;\n\t\t\t\t\t\tconfirmed.push(c);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse if (type[c] == 2) {\n\t\t\t\t\tif (type[a] == 3) {\n\t\t\t\t\t\ttype[a] = 2;\n\t\t\t\t\t\tconfirmed.push(a);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tfor (const auto i : refer[top].third) {\n\t\t\t\tconst auto [a, b, _] = info[i];\n\t\t\t\tif (type[a] == 1) {\n\t\t\t\t\tif (type[b] == 1) {\n\t\t\t\t\t\tparadoxical = true;\n\t\t\t\t\t}\n\t\t\t\t\telse if (type[b] == 3) {\n\t\t\t\t\t\ttype[b] = 2;\n\t\t\t\t\t\tconfirmed.push(b);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif (type[b] == 1) {\n\t\t\t\t\tif (type[a] == 1) {\n\t\t\t\t\t\tparadoxical = true;\n\t\t\t\t\t}\n\t\t\t\t\telse if (type[a] == 3) {\n\t\t\t\t\t\ttype[a] = 2;\n\t\t\t\t\t\tconfirmed.push(a);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif (paradoxical) {\n\t\tstd::cout << \"-1\\n\";\n\t}\n\telse {\n\t\tfor (auto t : type) {\n\t\t\tif (t == 3) {\n\t\t\t\tt = 2;\n\t\t\t}\n\t\t\tstd::cout << t << '\\n';\n\t\t}\n\t}\n}", "accuracy": 0.9142857142857143, "time_ms": 320, "memory_kb": 50472, "score_of_the_acc": -1.9565, "final_rank": 10 } ]
aoj_0703_cpp
イルミネーション 2 JOI 高校の生徒である葵は,文化祭で廊下に電飾を飾ることにした. 電飾は, N 個の電球を東西方向に一列に並べて作る.電球には西側から順に 1 から N までの番号が付けられている.各電球にはオンとオフの 2 つの状態があり,はじめ電球はすべてオフの状態である. 葵が目標とする電飾の模様は数列 A 1 , A 2 , ..., A N で表され, A i = 1 のときは電球 i をオンに, A i = 0 のときはオフにしたい.葵はできるだけ短い時間でこの模様にしようと考えた. 葵は最初に次の操作を 1 回だけ行うことができるが,行わなくてもよい. 西側の端から連続した区間の電球をオンにする.すなわち, 1 以上 N 以下の整数 r を 1 つ選び,電球 1, 2, ... , r をオンにする. この操作を行うのにかかる時間は無視できる. その後,次の操作を何回でも行うことができる. 電球を 1 つ選び,その電球の状態を変更する (オンならばオフに,オフならばオンにする). この操作を行うには 1 回につき 1 分かかる. 電球の個数,目標とする電飾の模様が与えられたとき,葵が目標の模様にするのに最短で何分かかるかを求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 200000 . A i は 0 か 1 のいずれかである ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N A 1 A 2 … A N 出力 標準出力に,目標の模様にするのに最短で何分かかるかを 1 行で出力せよ. 入出力例 入力例 1 6 0 1 1 0 0 1 出力例 1 2 例えば,葵は最初に r = 3 を選び,電球 1, 2, 3 をオンにする.この操作にかかる時間は 0 分である.その後,電球 1 をオンからオフに,電球 6 をオフからオンに状態を変更する.この操作にはそれぞれ 1 分ずつ合計で 2 分かかる. 2 分未満で目標の模様にすることはできないので, 2 を出力する. 入力例 2 4 0 0 0 1 出力例 2 1 この入力例では,葵は最初の操作は行わない.その後,電球 4 をオフからオンに状態を変更する.この操作には 1 分かかり, 1 分未満で目標の模様にすることはできないので, 1 を出力する. 入力例 3 4 1 1 1 1 出力例 3 0 この入力例では,葵は最初に r = 4 を選び電球 1, 2, 3, 4 をオンにすることで,目標の模様にすることができる.この操作にかかる時間は 0 分であるので, 0 を出力する. 入力例 4 15 1 0 0 0 0 1 1 1 0 1 0 0 1 0 1 出力例 4 6 情報オリンピック日本委員会 作 『日本情報オリンピック 第1回 女性部門』
[ { "submission_id": "aoj_0703_10333789", "code_snippet": "#include <iostream>\n#include <set>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <cstdlib>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n;\n cin >> n;\n vector<int> a(n);\n rep(i,n){\n cin >> a[i];\n }\n vector<int> cnt(n+1);\n cnt[0]=0;\n rep(i,n){\n cnt[i+1]=cnt[i]+a[i];\n }\n int res=n;\n for(int i=0;i<=n;i++){\n res = min(res,i+cnt[n]-2*cnt[i]);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 4692, "score_of_the_acc": -0.2855, "final_rank": 4 }, { "submission_id": "aoj_0703_9465750", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n\n vector<int> A(N);\n for (int i = 0; i < N; ++i) {\n cin >> A[i];\n }\n\n // 不選擇將前面的部分電燈一次性全部打開的情況下,計算所需的切換次數\n int changes = 0;\n for (int i = 0; i < N; ++i) {\n if (A[i] == 1) {\n changes++;\n }\n }\n int min_changes = changes;\n\n // 選擇將前面的部分電燈一次性全部打開的情況\n int current_on = 0;\n for (int r = 0; r < N; ++r) {\n if (A[r] == 1) {\n current_on++;\n }\n int new_changes = (r + 1 - current_on) + (changes - current_on);\n min_changes = min(min_changes, new_changes);\n }\n\n cout << min_changes << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3612, "score_of_the_acc": -1.0431, "final_rank": 10 }, { "submission_id": "aoj_0703_8307022", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n vector<int> A(N);\n for (int i = 0; i < N; ++i) cin >> A[i];\n\n // 前処理\n vector<int> left(N+1, 0), right(N+1, 0);\n for (int i = 0; i < N; ++i) {\n left[i+1] = left[i] + (A[i] == 0);\n right[i+1] = right[i] + (A[N-i-1] == 1);\n }\n\n // 最適化\n int res = N; // 理論上の上限値\n for (int i = 0; i <= N; ++i) {\n res = min(res, left[i] + right[N-i]);\n }\n cout << res << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5440, "score_of_the_acc": -0.4533, "final_rank": 5 }, { "submission_id": "aoj_0703_8293180", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n int n, a, ruiz[200010], ruio[200010];\n cin >> n;\n ruiz[0] = 0;\n ruio[0] = 0;\n for(int i=1;i<=n;i++){\n cin >> a;\n ruiz[i] = ruiz[i-1];\n if(a == 0) ruiz[i]++;\n ruio[i] = ruio[i-1]+a;\n }\n int mi = n;\n for(int i=0;i<=n;i++) mi = min(mi, ruiz[i]+ruio[n]-ruio[i]);\n cout << mi << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4672, "score_of_the_acc": -1.281, "final_rank": 12 }, { "submission_id": "aoj_0703_7050828", "code_snippet": "#include <iostream>\nusing namespace std;\nint as[200002];\nint main(){\n\t// your code goes here\n\tint n;\n\tcin>>n;\n\tint ans=0;\n\tint m1=0;\n\tfor(int i=0;i<n;i++){\n\t\tcin>>as[i];\n\t\tm1+=as[i];\n\t}\n\tans=m1;\n\tfor(int i=0;i<n;i++){\n\t\tif(as[i]==1){\n\t\t\tm1--;\n\t\t}else{\n\t\t\tm1++;\n\t\t}\n\t\tif(ans>m1)ans=m1;\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3872, "score_of_the_acc": -1.1014, "final_rank": 11 }, { "submission_id": "aoj_0703_6656053", "code_snippet": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n\tint N, s = 0, t = 0; cin >> N;\n\tfor (int i = 0, a, r = 1; i < N; ++i, ++r) {\n\t\tcin >> a;\n\t\ts += a;\n\t\tauto u = r - 2 * s;\n\t\tif (t > u) t = u;\n\t}\n\tcout << s + t << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3420, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0703_6652519", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n#define all(A) A.begin(),A.end()\nusing vll = vector<ll>;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\nusing Graph = vector<vector<pair<ll, ll>>>;\n\n\nint main() {\n\tll N;\n\tcin>>N;\n\tvll A(N);\n\tvll S(N+1,0);\n\tll P;\n\trep(i,N){\n\t\tcin>>A[i];\n\t\tS[i+1]=S[i]+A[i];\n\t}\n\tP=S[N];\n\tll an=1e18;\n\trep(i,N+1){\n\t\tan=min(an,P-S[i]+(i)-S[i]);\n\t}\n\tcout<<an<<endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 6236, "score_of_the_acc": -0.632, "final_rank": 7 }, { "submission_id": "aoj_0703_6303484", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nint main() {\n\tint n; std::cin >> n;\n\tstd::vector<int> dest(n);\n\tfor (auto& a : dest) {\n\t\tstd::cin >> a;\n\t}\n\tint on = std::accumulate(dest.begin(), dest.end(), 0);\n\tint off = 0;\n\tint result{ on };\n\tfor (auto i = 0; i < n; ++i) {\n\t\ton -= dest[i];\n\t\toff += 1 - dest[i];\n\t\tresult = std::min(result, on + off);\n\t}\n\tstd::cout << result << '\\n';\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3892, "score_of_the_acc": -0.1059, "final_rank": 2 }, { "submission_id": "aoj_0703_6291201", "code_snippet": "#include <cassert>\n#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <ccomplex>\n#include <cfenv>\n#include <cinttypes>\n#include <cstdalign>\n#include <cstdbool>\n#include <cstdint>\n#include <ctgmath>\n#include <cwchar>\n#include <cwctype>\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n#include <array>\n#include <atomic>\n#include <chrono>\n#include <condition_variable>\n#include <forward_list>\n#include <future>\n#include <initializer_list>\n#include <mutex>\n#include <random>\n#include <ratio>\n#include <regex>\n#include <scoped_allocator>\n#include <system_error>\n#include <thread>\n#include <tuple>\n#include <typeindex>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\nusing namespace std;\nconst long long MOD1 = 1000000007;\nconst long long MOD2 = 998244353;\n#define logn long\n#define lnog long\n#define lgon long\n#define itn int\ntypedef long long ll;\ntypedef pair<long long, long long> P;\nconst long logn INF = 1e18;\n//Data stracture\n//区間最小値を求めるセグ木\ntemplate <typename T>\nstruct RMQ {\n const T INF = 2147483647;\n int N; //number of leaves\n vector<T> dat; //perfect binary tree\n\n RMQ(int n_) : N(), dat(n_ * 4, INF) { //The number of leaves can be displayed by the formula, 2 ^ x.\n int x = 1;\n while (n_ > x) {\n x *= 2;\n }\n N = x;\n }\n\n void update(long long i, T x) {\n i += N - 1;\n dat.at(i) = x;\n while (i > 0) {\n i = (i - 1) / 2; //parent\n dat.at(i) = min(dat.at(i * 2 + 1), dat.at(i * 2 + 2));\n }\n }\n\n //the minimum element of [a, b)\n T query(long long a, long long b) {\n return query_sub(a, b, 0, 0, N);\n }\n T query_sub(long long a, long long b, long long k, long long l, long long r) {\n if (r <= a || b <= l) {\n return INF;\n }\n else if (a <= l && r <= b) {\n return dat.at(k);\n }\n else {\n T vl = query_sub(a, b, k * 2 + 1, l, (l + r) / 2);\n T vr = query_sub(a, b, k * 2 + 2, (l + r) / 2, r);\n return min(vl, vr);\n }\n }\n};\n//prime_factorization : 素因数分解\nvector<P> prime_factorization(long long N) {\n vector<P>A;\n long long tmp = N;\n for (long long i = 2; i * i <= N; i++) {\n if (tmp % i == 0) {\n A.push_back({ i, 0 });\n while (tmp % i == 0) {\n A.back().second++;\n tmp /= i;\n }\n }\n }\n if (tmp != 1) A.push_back({ tmp, 1 });\n return A;\n}\n//power : M^N(mod MOD)\nlong long power(long long N, long long M, long long MOD) {\n long long ans = 1;\n while (M > 0) {\n if (M & 1) {\n ans = ans * N % MOD;\n }\n N = N * N % MOD;\n M >>= 1;\n }\n return ans;\n}\n//Euler_phi : オイラー関数\nlong long Euler_phi(long long N) {\n vector<P>A = prime_factorization(N);\n for (long long i = 0; i < A.size(); i++) {\n N /= A[i].first;\n }\n for (long long i = 0; i < A.size(); i++) {\n N *= (A[i].first - 1);\n }\n return N;\n}\n//extgcd : 拡張ユークリッド互除法(返すのは gcd(A,B),AX + BY = GCD(A,B))\nlong long extgcd(long long A, long long B, long long& X, long long& Y) {\n long long D = A;\n if (B != 0) {\n D = extgcd(B, A % B, Y, X);\n Y -= (A / B) * X;\n }\n else {\n X = 1; Y = 0;\n }\n return D;\n}\n\n//計算幾何\n#define EPS (1e-10)\n#define equals(a, b) (fabs((a) - (b)) < EPS)\n//Point : 点(x, y)(点の座標(x,y)、ベクトル演算(+,-,*,/)、ベクトルのノルム(norm)、大きさ(abs)、大小比較(<)、合同を保存(==))\nclass Point {\npublic:\n double x;\n double y;\n\n Point(double x = 0, double y = 0) : x(x), y(y) {}\n\n Point operator+(Point p) { return Point(x + p.x, y + p.y); }\n Point operator-(Point p) { return Point(x - p.x, y - p.y); }\n Point operator*(double a) { return Point(a * x, a * y); }\n Point operator/(double a) { return Point(x / a, y / a); }\n\n double abs() { return sqrt(norm()); }\n double norm() { return x * x + y * y; }\n\n bool operator<(const Point& p) const {\n return x != p.x ? x < p.x : y < p.y;\n }\n bool operator==(const Point& p) const {\n return fabs(x - p.x) < (1e-10) && fabs(y - p.y) < (1e-10);\n }\n};\n//Vector : ベクトル(配列のvectorと間違えぬように)\ntypedef Point Vector;\n//Segment : 線分AB(点A, Bの座標を保存)\nstruct Segment {\n Point A;\n Point B;\n};\n//Line : 直線AB\ntypedef Segment Line;\n//Circle : 円(中心点C、半径r を保存)\nclass Circle {\npublic:\n Point C;\n double r;\n Circle(Point C = Point(), double r = 0.0) : C(C), r(r) {}\n};\n//Polygon : 多角形(各頂点の点列で表す)\ntypedef vector<Point> Polygon;\n//dot : ベクトルA, B の内積\ndouble dot(Vector A, Vector B) {\n return A.x * B.x + A.y * B.y;\n}\n//cross : ベクトルA, B の外積\ndouble cross(Vector A, Vector B) {\n return A.x * B.y - A.y * B.x;\n}\n//Projection : 射影(点pを通る、直線Sへの垂線の足の座標)\nPoint Projection(Segment S, Point p) {\n Vector base = S.B - S.A;\n double r = dot(p - S.A, base) / base.norm();\n return S.A + base * r;\n}\n//Reflection : 反射(直線Sに関して、点pと対称な点の座標)\nPoint Reflection(Segment S, Point p) {\n return p + (Projection(S, p) - p) * 2.0;\n}\n//isOrthogonal : 直交しているか? <==> ベクトルA, B の内積は0か?\nbool isOrthogonal(Vector A, Vector B) {\n return equals(dot(A, B), 0.0);\n}\nbool isOrthogonal(Point A1, Point A2, Point B1, Point B2) {\n return isOrthogonal(A1 - A2, B1 - B2);\n}\nbool isOrthogonal(Segment S1, Segment S2) {\n return equals(dot(S1.B - S1.A, S2.B - S2.A), 0.0);\n}\n//isParallel : 平行か? <==> ベクトルA, B の外積は0か?\nbool isParallel(Vector A, Vector B) {\n return equals(cross(A, B), 0.0);\n}\nbool isParallel(Point A1, Point A2, Point B1, Point B2) {\n return isParallel(A1 - A2, B1 - B2);\n}\nbool isParallel(Segment S1, Segment S2) {\n return equals(cross(S1.B - S1.A, S2.B - S2.A), 0.0);\n}\n//getDistance : 2点A,Bの距離\ndouble getDistance(Point A, Point B) {\n return (A - B).abs();\n}\n//getDistanceLP : 直線Lと点Pの距離\ndouble getDistanceLP(Line L, Point P) {\n return abs((cross(L.B - L.A, P - L.A))) / (L.B - L.A).abs();\n}\n//getDistanceSP : 線分Sと点Pの距離\ndouble getDistanceSP(Segment S, Point P) {\n if (dot(S.B - S.A, P - S.A) < 0.0) return (P - S.A).abs();\n if (dot(S.A - S.B, P - S.B) < 0.0) return (P - S.B).abs();\n return getDistanceLP(S, P);\n}\n//定数定義\nstatic const int COUNTER_CLOCKWISE = 1;\nstatic const int CLOCKWISE = -1;\nstatic const int ONLINE_BACK = 2;\nstatic const int ONLINE_FRONT = -2;\nstatic const int ON_SEGMENT = 0;\n//ccw : 3点A,B,Cがこの順に反時計回りか?\nint ccw(Point A, Point B, Point C) {\n Vector S = B - A, T = C - A;\n if (cross(S, T) > EPS) return COUNTER_CLOCKWISE; //反時計回り\n if (cross(S, T) < -EPS) return CLOCKWISE; //時計回り\n if (dot(S, T) < -EPS) return ONLINE_BACK; //C,A,Bの順で同一直線上にある\n if (S.norm() < T.norm()) return ONLINE_FRONT; //A,B,Cの順で同一直線上にある\n return ON_SEGMENT; //Cが線分AB上にある\n}\n//intersect : 線分AB, CDは交差するか?\nbool intersect(Point A, Point B, Point C, Point D) {\n return (ccw(A, B, C) * ccw(A, B, D) <= 0 && ccw(C, D, A) * ccw(C, D, B) <= 0);\n}\nbool intersect(Segment S1, Segment S2) {\n return intersect(S1.A, S1.B, S2.A, S2.B);\n}\n//別のintersect : 円Cと直線Lが交差するかどうか\nbool intersect(Circle C, Line L) {\n return (getDistanceLP(L, C.C) <= C.r);\n}\n//getDistance : 線分S1, S2 の距離もこの関数で導入\ndouble getDistance(Segment S1, Segment S2) {\n if (intersect(S1, S2)) return 0.0;\n return min(min(getDistanceSP(S1, S2.A), getDistanceSP(S1, S2.B)), min(getDistanceSP(S2, S1.A), getDistanceSP(S2, S1.B)));\n}//getCrossPoint : 線分S1, S2 の交点(線分AB, 線分CD の交点)\nPoint getCrossPoint(Segment S1, Segment S2) {\n Vector base = S2.B - S2.A;\n double d1 = abs(cross(base, S1.A - S2.A));\n double d2 = abs(cross(base, S1.B - S2.A));\n double T = d1 / (d1 + d2);\n return S1.A + (S1.B - S1.A) * T;\n}\nPoint getCrossPoint(Point A, Point B, Point C, Point D) {\n Vector base = D - C;\n double d1 = abs(cross(base, A - C));\n double d2 = abs(cross(base, B - C));\n double T = d1 / (d1 + d2);\n return A + (B - A) * T;\n}\n//getCrossPoints : 円Cと直線Lの交点(2つ以下のため、pairで管理)\npair<Point, Point> getCrossPoints(Circle C, Line L) {\n assert(intersect(C, L));\n Vector pr = Projection(L, C.C);\n Vector e = (L.B - L.A) / (L.B - L.A).abs();\n double base = sqrt(C.r * C.r - (pr - C.C).norm());\n return make_pair(pr + e * base, pr - e * base);\n}\n//グラフを表す構造体\nstruct Graph {\n //辺を表す構造体\n //rev : 逆辺 (to, from) が G[to] の中で何番目の要素か\n //cap : 辺 (from, to) の容量\n struct Edge {\n long long rev, from, to, cap;\n Edge(long long r, long long f, long long t, long long c) :\n rev(r), from(f), to(t), cap(c) {}\n };\n\n //隣接リスト\n vector<vector<Edge>> list;\n\n //N : 頂点数\n Graph(long long N = 0) : list(N) {}\n\n //グラフの頂点数取得\n size_t size() {\n return list.size();\n }\n\n //Graph インスタンスを G として、\n // G.list[v] を G[v] と書けるようにしておく\n vector<Edge>& operator [] (long long i) {\n return list[i];\n }\n\n //辺 e = (u, v) の逆辺 (v, u) を取得する\n Edge& redge(const Edge& e) {\n return list[e.to][e.rev];\n }\n\n //辺 e = (u, v) に流量 f のフローを流す\n //e = (u, v) の流量が f だけ減少する\n //この時、逆辺 (v, u) の流量を増やす\n void run_flow(Edge& e, long long f) {\n e.cap -= f;\n redge(e).cap += f;\n }\n\n //頂点 from から頂点 to へ容量 cap の辺を張る\n //このとき to から from へも容量 0 の辺を張っておく\n void addedge(long long from, long long to, long long cap) {\n long long fromrev = (long long)list[from].size();\n long long torev = (long long)list[to].size();\n list[from].push_back(Edge(torev, from, to, cap));\n list[to].push_back(Edge(fromrev, to, from, 0));\n }\n};\nstruct Ford_Fulkerson {\n static const int INF = 1 << 30;\n vector<long long> seen;\n\n Ford_Fulkerson() {}\n\n //残余グラフ上で s-t パスを見つける(DFS)\n //返り値は s-t パス上の容量の最小値(見つからなかったら 0)\n //f: s から v へ到達した過程の各辺の容量の最小値\n long long fodfs(Graph& G, long long v, long long t, long long f) {\n //終端 t に到達したらリターン\n if (v == t) return f;\n\n //DFS\n seen[v] = true;\n for (auto& e : G[v]) {\n if (seen[e.to]) continue;\n\n //容量 0 の辺は実際には存在しない\n if (e.cap == 0) continue;\n\n //s-t パスを探す\n //見つかったら flow はパス上の最小容量\n //見つからなかったら f = 0\n long long flow = fodfs(G, e.to, t, min(f, e.cap));\n\n //s-t パスが見つからなかったら次辺を試す\n if (flow == 0) continue;\n\n //辺 e に容量 flow のフローを流す\n G.run_flow(e, flow);\n\n //s-t パスを見つけたらパス上最小容量を返す\n return flow;\n }\n //s-t パスが見つからなかったことを示す\n return 0;\n }\n\n //グラフ G の s-t 間の最大流量を求める\n //ただしリターン時に G は残余グラフになる\n long long solve(Graph& G, long long s, long long t) {\n long long res = 0;\n\n //残余グラフに s-t パスがなくなるまで反復\n while (true) {\n seen.assign((long long)G.size(), 0);\n long long flow = fodfs(G, s, t, INF);\n\n //s-t パスが見つからなかったら終了\n if (flow == 0) return res;\n\n //答えを加算\n res += flow;\n }\n\n //no reach\n return 0;\n }\n};\nstruct EDGE {\n long long to;\n long long cost;\n};\nvoid dijkstra(const vector<vector<EDGE>>& G, int s, vector<long long>& dis, vector<long long>& prev) {\n int N = G.size();\n dis.resize(N, INF);\n prev.resize(N, -1); // 初期化\n priority_queue<P, vector<P>, greater<P>> pq;\n dis[s] = 0;\n pq.emplace(dis[s], s);\n while (!pq.empty()) {\n P p = pq.top();\n pq.pop();\n int v = p.second;\n if (dis[v] < p.first) {\n continue;\n }\n for (auto& e : G[v]) {\n if (dis[e.to] > dis[v] + e.cost) {\n dis[e.to] = dis[v] + e.cost;\n prev[e.to] = v; // 頂点 v を通って e.to にたどり着いた\n pq.emplace(dis[e.to], e.to);\n }\n }\n }\n}\n//find : A 内に key のある位置(ないなら -1 )\nlong long find(vector<long long>& A, long long key) {\n if (A.empty()) return -1;\n long long left = 0, right = A.size() - 1;\n while (left <= right) {\n long long mid = (left + right) / 2;\n if (A[mid] == key) return mid;\n else if (A[mid] < key) left = mid + 1;\n else right = mid - 1;\n }\n return -1;\n}\nvoid BFS(vector<vector<long long>>& G, long long s, vector<long long>& dist) {\n queue<long long>Q;\n dist[s] = 0; Q.push(s);\n while (!Q.empty()) {\n long long v = Q.front(); Q.pop();\n for (auto nv : G[v]) {\n if (dist[nv] == INF) {\n dist[nv] = dist[v] + 1;\n Q.push(nv);\n }\n }\n }\n}\nvector<int> string_to_bigint(string S) {\n int N = S.size(); // N = (文字列 S の長さ)\n vector<int> digit(N);\n for (int i = 0; i < N; ++i) {\n digit[i] = S[N - i - 1] - '0'; // 10^i の位の数\n }\n return digit;\n}\nstring bigint_to_string(vector<int> digit) {\n int N = digit.size(); // N = (配列 digit の長さ)\n string str = \"\";\n for (int i = N - 1; i >= 0; --i) {\n str += digit[i] + '0';\n }\n return str;\n}\nvector<int> carry_and_fix(vector<int> digit) {\n int N = digit.size();\n for (int i = 0; i < N - 1; ++i) {\n // 繰り上がり処理 (K は繰り上がりの回数)\n if (digit[i] >= 10) {\n int K = digit[i] / 10;\n digit[i] -= K * 10;\n digit[i + 1] += K;\n }\n // 繰り下がり処理 (K は繰り下がりの回数)\n if (digit[i] < 0) {\n int K = (-digit[i] - 1) / 10 + 1;\n digit[i] += K * 10;\n digit[i + 1] -= K;\n }\n }\n // 一番上の桁が 10 以上なら、桁数を増やすことを繰り返す\n while (digit.back() >= 10) {\n int K = digit.back() / 10;\n digit.back() -= K * 10;\n digit.push_back(K);\n }\n // 1 桁の「0」以外なら、一番上の桁の 0 (リーディング・ゼロ) を消す\n while (digit.size() >= 2 && digit.back() == 0) {\n digit.pop_back();\n }\n return digit;\n}\nvector<int> multiplication(vector<int> digit_a, vector<int> digit_b) {\n int NA = digit_a.size(); // A の桁数\n int NB = digit_b.size(); // B の桁数\n vector<int> res(NA + NB - 1);\n for (int i = 0; i < NA; ++i) {\n for (int j = 0; j < NB; ++j) {\n res[i + j] += digit_a[i] * digit_b[j];\n // 答えの i+j の位に digit_a[i] * digit_b[j] を足す\n }\n }\n return carry_and_fix(res);\n}\nstruct triple {\n long long a; long long b; long long c;\n};\nconst long long MOD = (long long)2e18;\nconst int MAX_C = 61;\nlong long Com[MAX_C][MAX_C];\nvoid calc_com() {\n memset(Com, 0, sizeof(Com));\n Com[0][0] = 1;\n for (int i = 1; i < MAX_C; ++i) {\n Com[i][0] = 1;\n for (int j = 1; j < MAX_C; ++j) {\n Com[i][j] = (Com[i - 1][j - 1] + Com[i - 1][j]) % MOD;\n }\n }\n}\nvector<long long> get_path(const vector<long long>& prev, long long t, const vector<long long>& dist) {\n vector<long long> path;\n for (int cur = t; cur != -1; cur = prev[cur]) {\n path.push_back(cur);\n }\n reverse(path.begin(), path.end()); // 逆順なのでひっくり返す\n return path;\n}\nlong long calc = 0;\nvector<long long> BFS_num(vector<vector<long long>>& G, long long s, vector<long long>& dist, vector<long long>& st, long long M) {\n vector<long long>D(M, 0);\n queue<long long>Q;\n long long ans = 0;\n dist[s] = 0; D[st[s]] = 1; Q.push(s);\n while (!Q.empty()) {\n long long v = Q.front(); Q.pop();\n for (auto nv : G[v]) {\n if (dist[nv] == -1) {\n calc++;\n dist[nv] = dist[v] + 1;\n if (dist[nv] + st[s] == st[nv]) D[st[nv]]++;\n Q.push(nv);\n }\n }\n }\n return D;\n}\n//input_arr : 配列 A を入力\ntemplate <typename T>\nvoid input_arr(vector<T>& A, long long N) {\n for (long long i = 0; i < N; i++) {\n cin >> A[i];\n }\n}\nstring up_lo(string S) {\n for (long long i = 0; i < S.size(); i++) {\n if ('A' <= S[i] && S[i] <= 'Z') {\n S[i] = 'a' + (S[i] - 'A');\n }\n else if ('z' <= S[i] && S[i] <= 'z') {\n S[i] = 'A' + (S[i] - 'a');\n }\n else return \"???\";\n }\n return S;\n}\nint main() {\n long logn N; cin >> N;\n vector<long long>A(N); input_arr(A, N);\n vector<long long>B(N+1,0), C(N+1,0);\n for (long long i = 1; i <= N; i++) {\n if (A[i-1] == 0) B[i]++;\n else C[i]++;\n }\n for (long long i = 1; i <= N; i++) {\n B[i] += B[i - 1];\n C[i] += C[i - 1];\n }\n long long ans = INF;\n for (long long i = 0; i <= N; i++) {\n ans = min(ans, B[i] + C[N] - C[i]);\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7876, "score_of_the_acc": -1, "final_rank": 9 }, { "submission_id": "aoj_0703_6277866", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x - 1; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++;\n\t\t//res += n % 10;\n\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\n\nconst int nCkMAX = 500000;\nll fac[nCkMAX], finv[nCkMAX], inv[nCkMAX];//n!、1/n!、1/n\n// テーブルを作る前処理\nvoid nCkinit(ll m) {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < nCkMAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % m;\n\t\tinv[i] = m - inv[m % i] * (m / i) % m;\n\t\tfinv[i] = finv[i - 1] * inv[i] % m;\n\t}\n}\n// 二項係数計算\nll nCk(ll n, ll k, ll m) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % m) % m;\n}\nll nCk2(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tfor (int i = 1; i <= k; i++) {\n\t\tres *= modpow(i, m - 2, m); res %= m;\n\t}\n\treturn res;\n}\nll waru = 1;\nll nCk3(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tres *= waru; res %= MOD;\n\treturn res;\n}\n\n//xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n//1~6まで出したいときは\n//xorshift() % 6 + 1\nunsigned int xorshift() {\n\tstatic unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n\tunsigned int tt = (tx ^ (tx << 11));\n\ttx = ty; ty = tz; tz = tw;\n\treturn (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\n\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\n////////////////////////////////struct\nstruct edge {\n\tll to; ld cost;\n};\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\t/*ll a;\n\tll b;\n\tll c;\n\tll ind;*/\n\tll first;//d[映画]\n\tll second;//映画\n\tll kai;\n\n\t//bool operator<(const status& rhs) const { return c < rhs.c; };\n\t//bool operator>(const status& rhs) const { return c > rhs.c; };\n\tbool operator<(const status& rhs) const { return kai < rhs.kai; };\n\tbool operator>(const status& rhs) const { return kai > rhs.kai; };\n};\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"Yes\\n\"; }\n\telse { cout << \"No\\n\"; }\n}\n//多倍長整数演算\n//nCkを求めるときにnCkMAXとnCkinit\n\n\n\nint main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tll n; cin >> n;\n\tvector<ll>a(n + 2);\n\trep2(i, n) { cin >> a[i]; }\n\tvector<ll>zero(n + 2), one(n + 2);\n\trep2(i, n) {\n\t\tzero[i] = zero[i - 1];\n\t\tif (a[i] == 0) { zero[i]++; }\n\t}\n\tfor (int i = n; i > 0; i--) {\n\t\tone[i] = one[i + 1];\n\t\tif (a[i] == 1) { one[i] ++; }\n\t}\n\tll ans = INF;\n\trep(i, n + 1) {\n\t\tans = min(ans, zero[i] + one[i + 1]);\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 7844, "score_of_the_acc": -0.9928, "final_rank": 8 }, { "submission_id": "aoj_0703_6264391", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n);\n vector<int> a(n);\n in(a);\n int ans=INF,cnt=accumulate(all(a),0);\n ans=cnt;\n rep(i,n){\n if(a[i]==1)cnt--;\n else cnt++;\n chmin(ans,cnt);\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 3956, "score_of_the_acc": -0.1203, "final_rank": 3 }, { "submission_id": "aoj_0703_6156507", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 200005\n\nint A[SIZE];\nint L[SIZE],R[SIZE];\n\nint main(){\n\n\tint N;\n\tscanf(\"%d\",&N);\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\n\tint sum = 0;\n\n\tfor(int i = N; i >= 1; i--){ //初期反転を使わずにやる\n\n\t\tif(A[i] == 1){\n\n\t\t\tsum++;\n\t\t}\n\t\tR[i] = sum;\n\t}\n\n\tsum = 0;\n\tfor(int i = 1; i <= N; i++){ //1~iまで初期反転する\n\n\t\tif(A[i] == 0){\n\n\t\t\tsum++;\n\t\t}\n\t\tL[i] = sum;\n\t}\n\n\tint ans = min(R[1],L[N]);\n\tfor(int i = 1; i <= N-1; i++){\n\n\t\tans = min(ans,L[i]+R[i+1]);\n\t}\n\n\tprintf(\"%d\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 5552, "score_of_the_acc": -0.4785, "final_rank": 6 } ]
aoj_0705_cpp
パレード JOI 王国では,JOIG の開催を記念して鼓笛隊のパレードを行うことになった. JOI 王国には N 個の都市があり, 1 から N までの番号が付けられている.また,鼓笛隊が通行可能な一方通行の道が M 本あり, 1 から M までの番号が付けられている.道 i ( 1 ≦ i ≦ M ) は都市 A i から都市 B i へ向かう一方通行の道であり,長さは C i である. パレードでは,鼓笛隊は次の条件を満たすように移動しなければならない. 都市 1 を出発し,何本かの道を進行方向に進むことを繰り返して都市 N へ向かう. 鼓笛隊が通る道の長さの総和は L 以下である. JOI 王国の女王であるあなたは,この条件を満たす鼓笛隊の移動経路が無いかもしれないことに気が付いた.そこで,パレードを行うために,パレード当日に 0 本以上の道の進行方向を反転させることにした. 混乱を避けるため,なるべく進行方向を反転させる道の本数は少なくしたい. JOI 王国の都市と道の情報と,整数 L が与えられたとき,いくつかの道の進行方向を反転させることでパレードを行うことができるかを判定し,もし行うことができる場合はパレードを行うために必要な進行方向を反転させる道の本数の最小値を出力せよ. 制約 2 ≦ N ≦ 1000 . 0 ≦ M ≦ 1000 . 1 ≦ L ≦ 1000000000 . 1 ≦ A i ≦ N ( 1 ≦ i ≦ M ). 1 ≦ B i ≦ N ( 1 ≦ i ≦ M ). A i ≠ B i ( 1 ≦ i ≦ M ). (A i , B i ) ≠ (A j , B j ) ( 1 ≦ i < j ≦ M ). 1 ≦ C i ≦ 1000000 ( 1 ≦ i ≦ M ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N M L A 1 B 1 C 1 A 2 B 2 C 2 : A M B M C M 出力 標準出力に,パレードを行うために必要な進行方向を反転させる道の本数の最小値を 1 行で出力せよ.ただし,どのように道の進行方向を反転させてもパレードを行うことができない場合は, -1 を出力せよ. 入出力例 入力例 1 3 2 5 2 1 2 2 3 3 出力例 1 1 道 1 の進行方向を反転させると,パレードを行うことができる. これが最小値であるため, 1 を出力する. 入力例 2 3 1 10 2 1 5 出力例 2 -1 どのように道の進行方向を反転させてもパレードを行うことができないため, -1 を出力する. 入力例 3 4 8 11 3 1 6 1 3 6 2 4 3 4 2 3 4 3 6 3 4 6 2 1 5 1 2 5 出力例 3 0 入力例 4 5 6 1000000000 5 2 1 2 3 1 3 4 1 4 2 1 2 1 1 1 3 1 出力例 4 1 入力例 5 6 15 777777 1 3 497295 4 1 422722 4 5 607164 2 3 135688 5 2 995652 5 1 670296 3 1 138860 4 6 736614 6 3 620085 2 1 796353 6 4 949756 4 2 750680 6 5 591550 5 3 229431 3 2 668173 出力例 5 2 情報オリンピック日本委員会 作 『日本情報オリンピック 第1回 女性部門』
[ { "submission_id": "aoj_0705_10598429", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N_MAX=1000;\n\nstruct edge{\n\tint to,cost;\n};\n\nstruct S{\n\tint node,rcnt,dist;\n\tbool operator<(const S &x)const{\n\t\treturn x.dist<dist;\n\t}\n};\n\nint N,M,L,D[N_MAX][N_MAX+1];\nvector<edge>E[N_MAX],R[N_MAX];\npriority_queue<S>pq;\n\nint main(){\n\tcin>>N>>M>>L;\n\tfor(int i=0;i<M;i++){\n\t\tint A,B,C;\n\t\tcin>>A>>B>>C;\n\t\tA--;\n\t\tB--;\n\t\tE[A].push_back({B,C});\n\t\tR[B].push_back({A,C});\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tfor(int j=0;j<=N;j++){\n\t\t\tD[i][j]=-1;\n\t\t}\n\t}\n\tpq.push({0,0,0});\n\twhile(!pq.empty()){\n\t\tS s=pq.top();\n\t\tpq.pop();\n\t\tif(D[s.node][s.rcnt]==-1&&s.dist<=L){\n\t\t\tD[s.node][s.rcnt]=s.dist;\n\t\t\tfor(edge e:E[s.node]){\n\t\t\t\tpq.push({e.to,s.rcnt,s.dist+e.cost});\n\t\t\t}\n\t\t\tif(s.rcnt<N){\n\t\t\t\tfor(edge e:R[s.node]){\n\t\t\t\t\tpq.push({e.to,s.rcnt+1,s.dist+e.cost});\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=0;i<N;i++){\n\t\tif(D[N-1][i]!=-1){\n\t\t\tcout<<i<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<-1<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 33140, "score_of_the_acc": -1.1375, "final_rank": 9 }, { "submission_id": "aoj_0705_9609186", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\ntemplate<class T>\nbool chmin(T& p, T q, bool C = 1) {\n if (C == 0 && p == q) {\n return 1;\n }\n if (p > q) {\n p = q;\n return 1;\n }\n else {\n return 0;\n }\n}\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n ll N,M,L;\n cin>>N>>M>>L;\n vector<vector<pair<ll,ll>>> G(N);\n vector<vector<pair<ll,ll>>> IG(N);\n rep(i,M){\n ll U,V,C;\n cin>>U>>V>>C;\n U--;V--;\n G[U].push_back({V,C});\n IG[V].push_back({U,C});\n }\n vvll dist(N,vll(M+1,1e18));\n dist[0][0]=0;\n priority_queue<pair<pair<ll,ll>,ll>,vector<pair<pair<ll,ll>,ll>>,greater<pair<pair<ll,ll>,ll>>> Q;\n Q.push({{0,0},0});\n vector<vector<bool>> seen(N,vector<bool>(M+1,0));\n while(!Q.empty()){\n auto b=Q.top();\n Q.pop();\n ll d=b.first.first;\n ll f=b.first.second;\n ll n=b.second;\n if(seen[n][f])continue;\n seen[n][f]=1;\n for(auto vw:G[n]){\n ll v=vw.first;\n ll w=vw.second;\n if(seen[v][f])continue;\n if(dist[v][f]<=d+w)continue;\n dist[v][f]=d+w;\n Q.push({{d+w,f},v});\n }\n if(f==M)continue;\n for(auto vw:IG[n]){\n ll v=vw.first;\n ll w=vw.second;\n if(seen[v][f+1])continue;\n if(dist[v][f+1]<=d+w)continue;\n dist[v][f+1]=d+w;\n Q.push({{d+w,f+1},v});\n }\n }\n ll an=1e18;\n rep(i,M+1){\n if(dist[N-1][i]<=L)chmin(an,i);\n }\n cout<<(an<1e17?an:-1)<<endl;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 19024, "score_of_the_acc": -0.5811, "final_rank": 6 }, { "submission_id": "aoj_0705_9465768", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <climits>\n\nusing namespace std;\n\nstruct Edge {\n int to, length;\n};\n\nstruct State {\n int node, distance, reversed;\n bool operator>(const State &other) const {\n return distance > other.distance;\n }\n};\n\nint N, M, L;\nvector<vector<Edge> > graph; // 注意這裡的空格\nvector<vector<Edge> > reverse_graph; // 注意這裡的空格\n\nint dijkstra(int max_reversals) {\n priority_queue<State, vector<State>, greater<State> > pq; // 注意這裡的空格\n vector<vector<int> > dist(N + 1, vector<int>(max_reversals + 1, INT_MAX)); // 注意這裡的空格\n pq.push((State){1, 0, 0});\n dist[1][0] = 0;\n\n while (!pq.empty()) {\n State state = pq.top();\n pq.pop();\n\n if (state.node == N && state.distance <= L) {\n return state.reversed;\n }\n\n if (state.distance > L) {\n continue;\n }\n\n for (size_t i = 0; i < graph[state.node].size(); ++i) {\n const Edge &edge = graph[state.node][i];\n int next_node = edge.to;\n int next_dist = state.distance + edge.length;\n\n if (next_dist < dist[next_node][state.reversed]) {\n dist[next_node][state.reversed] = next_dist;\n pq.push((State){next_node, next_dist, state.reversed});\n }\n }\n\n if (state.reversed < max_reversals) {\n for (size_t i = 0; i < reverse_graph[state.node].size(); ++i) {\n const Edge &edge = reverse_graph[state.node][i];\n int next_node = edge.to;\n int next_dist = state.distance + edge.length;\n\n if (next_dist < dist[next_node][state.reversed + 1]) {\n dist[next_node][state.reversed + 1] = next_dist;\n pq.push((State){next_node, next_dist, state.reversed + 1});\n }\n }\n }\n }\n\n return -1;\n}\n\nint main() {\n cin >> N >> M >> L;\n graph.resize(N + 1);\n reverse_graph.resize(N + 1);\n\n for (int i = 0; i < M; ++i) {\n int A, B, C;\n cin >> A >> B >> C;\n graph[A].push_back((Edge){B, C});\n reverse_graph[B].push_back((Edge){A, C});\n }\n\n int left = 0, right = N;\n int result = -1;\n\n while (left <= right) {\n int mid = left + (right - left) / 2;\n if (dijkstra(mid) != -1) {\n result = mid;\n right = mid - 1;\n } else {\n left = mid + 1;\n }\n }\n\n cout << result << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 440, "memory_kb": 8612, "score_of_the_acc": -1.0874, "final_rank": 8 }, { "submission_id": "aoj_0705_9059697", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"/opt/library/graph/base.hpp\"\n\ntemplate <typename T>\nstruct Edge {\n ll frm, to;\n T cost;\n ll id;\n};\n\ntemplate <typename T = ll, bool directed = false>\nstruct Graph {\n static constexpr bool is_directed = directed;\n ll N, M;\n using cost_type = T;\n using edge_type = Edge<T>;\n vector<edge_type> edges;\n vi indptr;\n vc<edge_type> csr_edges;\n vc<ll> vc_deg, vc_indeg, vc_outdeg;\n bool prepared;\n\n class OutgoingEdges {\n public:\n OutgoingEdges(const Graph* G, ll l, ll r) : G(G), l(l), r(r) {}\n\n const edge_type* begin() const {\n if (l == r) { return 0; }\n return &G->csr_edges[l];\n }\n\n const edge_type* end() const {\n if (l == r) { return 0; }\n return &G->csr_edges[r];\n }\n\n private:\n const Graph* G;\n ll l, r;\n };\n\n bool is_prepared() { return prepared; }\n\n Graph() : N(0), M(0), prepared(0) {}\n Graph(ll N) : N(N), M(0), prepared(0) {}\n\n void build(ll n) {\n N = n, M = 0;\n prepared = 0;\n edges.clear();\n indptr.clear();\n csr_edges.clear();\n vc_deg.clear();\n vc_indeg.clear();\n vc_outdeg.clear();\n }\n\n void add(ll frm, ll to, T cost = 1, ll i = -1) {\n assert(!prepared);\n assert(0 <= frm && 0 <= to && to < N);\n if (i == -1) i = M;\n auto e = edge_type({frm, to, cost, i});\n edges.eb(e);\n ++M;\n }\n\n#ifdef FASTIO\n // wt, off\n void read_tree(bool wt = false, ll off = 1) { read_graph(N - 1, wt, off); }\n\n void read_graph(ll M, bool wt = false, ll off = 1) {\n for (ll m = 0; m < M; ++m) {\n LL(a, b);\n a -= off, b -= off;\n if (!wt) {\n add(a, b);\n } else {\n T c;\n read(c);\n add(a, b, c);\n }\n }\n build();\n }\n#endif\n\n void build() {\n assert(!prepared);\n prepared = true;\n indptr.assign(N + 1, 0);\n for (auto&& e: edges) {\n indptr[e.frm + 1]++;\n if (!directed) indptr[e.to + 1]++;\n }\n for (ll v = 0; v < N; ++v) { indptr[v + 1] += indptr[v]; }\n auto counter = indptr;\n csr_edges.resize(indptr.back() + 1);\n for (auto&& e: edges) {\n csr_edges[counter[e.frm]++] = e;\n if (!directed)\n csr_edges[counter[e.to]++] = edge_type({e.to, e.frm, e.cost, e.id});\n }\n }\n\n OutgoingEdges operator[](ll v) const {\n assert(prepared);\n return {this, indptr[v], indptr[v + 1]};\n }\n\n vi deg_array() {\n if (vc_deg.empty()) calc_deg();\n return vc_deg;\n }\n\n pair<vi, vi> deg_array_inout() {\n if (vc_indeg.empty()) calc_deg_inout();\n return {vc_indeg, vc_outdeg};\n }\n\n ll deg(ll v) {\n if (vc_deg.empty()) calc_deg();\n return vc_deg[v];\n }\n\n ll in_deg(ll v) {\n if (vc_indeg.empty()) calc_deg_inout();\n return vc_indeg[v];\n }\n\n ll out_deg(ll v) {\n if (vc_outdeg.empty()) calc_deg_inout();\n return vc_outdeg[v];\n }\n\n#ifdef FASTIO\n void debug() {\n print(\"Graph\");\n if (!prepared) {\n print(\"frm to cost id\");\n for (auto&& e: edges) print(e.frm, e.to, e.cost, e.id);\n } else {\n print(\"indptr\", indptr);\n print(\"frm to cost id\");\n rep(v, N) for (auto&& e: (*this)[v]) print(e.frm, e.to, e.cost, e.id);\n }\n }\n#endif\n\n vi new_idx;\n vc<bool> used_e;\n\n // G における頂点 V[i] が、新しいグラフで i になるようにする\n // {G, es}\n Graph<T, directed> rearrange(vi V, bool keep_eid = 0) {\n if (len(new_idx) != N) new_idx.assign(N, -1);\n if (len(used_e) != M) used_e.assign(M, 0);\n ll n = len(V);\n rep(i, n) new_idx[V[i]] = i;\n Graph<T, directed> G(n);\n vi history;\n rep(i, n) {\n for (auto&& e: (*this)[V[i]]) {\n if (used_e[e.id]) continue;\n ll a = e.frm, b = e.to;\n if (new_idx[a] != -1 && new_idx[b] != -1) {\n history.eb(e.id);\n used_e[e.id] = 1;\n ll eid = (keep_eid ? e.id : -1);\n G.add(new_idx[a], new_idx[b], e.cost, eid);\n }\n }\n }\n rep(i, n) new_idx[V[i]] = -1;\n for (auto&& eid: history) used_e[eid] = 0;\n G.build();\n return G;\n }\n\nprivate:\n void calc_deg() {\n assert(vc_deg.empty());\n vc_deg.resize(N);\n for (auto&& e: edges) vc_deg[e.frm]++, vc_deg[e.to]++;\n }\n\n void calc_deg_inout() {\n assert(vc_indeg.empty());\n vc_indeg.resize(N);\n vc_outdeg.resize(N);\n for (auto&& e: edges) { vc_indeg[e.to]++, vc_outdeg[e.frm]++; }\n }\n};\n#line 3 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nstruct S{\n ll node, rcnt, dist;\n bool operator<(const S &x) const {\n return x.dist < dist;\n }\n};\n\nint solve() {\n ll N, M, L, A, B, C;\n cin >> N >> M >> L;\n Graph<ll,true> G(N), GR(N);\n rep(M) {\n cin >> A >> B >> C;\n A--; B--;\n G.add(A, B, C);\n GR.add(B, A, C);\n }\n G.build(); GR.build();\n vv(ll, dp, N, N+1, -1);\n pq<S> Q;\n Q.push({0, 0, 0});\n while (!Q.empty()) {\n auto v = POP(Q);\n if ((dp[v.node][v.rcnt] == -1) and (v.dist <= L)) {\n dp[v.node][v.rcnt] = v.dist;\n for (auto e: G[v.node]) {\n Q.push({e.to, v.rcnt, v.dist+e.cost});\n }\n if (v.rcnt < N) {\n for (auto e: GR[v.node]) {\n Q.push({e.to, v.rcnt+1, v.dist+e.cost});\n }\n }\n }\n }\n rep(i, N) {\n if (dp[N-1][i] != -1) {\n print(i);\n return 0;\n }\n }\n print(-1);\n return 0;\n}", "accuracy": 1, "time_ms": 430, "memory_kb": 62428, "score_of_the_acc": -1.9756, "final_rank": 10 }, { "submission_id": "aoj_0705_8753602", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/graph/graph.hpp\"\n#include <iostream>\n#include <vector>\n\n/**\n * @brief 重み付きグラフ\n *\n * @tparam T 辺の重みの型\n */\ntemplate <class T>\nstruct Graph {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to(), _weight() {}\n constexpr _edge(int from, int to, T weight) : _from(from), _to(to), _weight(weight) {}\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr T weight() const { return _weight; }\n\n private:\n int _from, _to;\n T _weight;\n };\n\n public:\n using edge_type = typename Graph<T>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to, T weight = T(1)) { edges[from].emplace_back(from, to, weight); }\n void add_edges(int from, int to, T weight = T(1)) {\n edges[from].emplace_back(from, to, weight);\n edges[to].emplace_back(to, from, weight);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edge(from - base, to - base, weight);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edges(from - base, to - base, weight);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n\ntemplate <>\nstruct Graph<void> {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to() {}\n constexpr _edge(int from, int to) : _from(from), _to(to) {}\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr int weight() const { return 1; }\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n private:\n int _from, _to;\n };\n\n public:\n using edge_type = typename Graph<void>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to) { edges[from].emplace_back(from, to); }\n void add_edges(int from, int to) {\n edges[from].emplace_back(from, to);\n edges[to].emplace_back(to, from);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edge(from - base, to - base);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edges(from - base, to - base);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n ll l;\n cin >> l;\n Graph<pair<int, int>> g(n);\n rep (i, m) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b;\n g.add_edge(a, b, {0, c});\n g.add_edge(b, a, {1, c});\n }\n\n vector dp(n, vector(m + 1, INF));\n dp[0][0] = 0;\n priority_queue<tuple<ll, int, int>, vector<tuple<ll, int, int>>, greater<>> pq;\n pq.emplace(0, 0, 0);\n while (!pq.empty()) {\n auto [d, x, y] = pq.top();\n pq.pop();\n if (dp[x][y] != d)\n continue;\n for (auto e : g[x]) {\n auto [a, b] = e.weight();\n if (y + a <= m && chmin(dp[e.to()][y + a], d + b)) {\n pq.emplace(dp[e.to()][y + a], e.to(), y + a);\n }\n }\n }\n\n rep (i, m + 1) {\n if (dp[n - 1][i] <= l) {\n co(i);\n return 0;\n }\n }\n co(-1);\n\n return 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 16628, "score_of_the_acc": -0.4673, "final_rank": 5 }, { "submission_id": "aoj_0705_8753589", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/graph/graph.hpp\"\n#include <iostream>\n#include <vector>\n\n/**\n * @brief 重み付きグラフ\n *\n * @tparam T 辺の重みの型\n */\ntemplate <class T>\nstruct Graph {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to(), _weight() {}\n constexpr _edge(int from, int to, T weight) : _from(from), _to(to), _weight(weight) {}\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr T weight() const { return _weight; }\n\n private:\n int _from, _to;\n T _weight;\n };\n\n public:\n using edge_type = typename Graph<T>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to, T weight = T(1)) { edges[from].emplace_back(from, to, weight); }\n void add_edges(int from, int to, T weight = T(1)) {\n edges[from].emplace_back(from, to, weight);\n edges[to].emplace_back(to, from, weight);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edge(from - base, to - base, weight);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n T weight;\n std::cin >> from >> to >> weight;\n add_edges(from - base, to - base, weight);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n\ntemplate <>\nstruct Graph<void> {\n private:\n struct _edge {\n constexpr _edge() : _from(), _to() {}\n constexpr _edge(int from, int to) : _from(from), _to(to) {}\n\n constexpr int from() const { return _from; }\n constexpr int to() const { return _to; }\n constexpr int weight() const { return 1; }\n constexpr bool operator<(const _edge &rhs) const { return weight() < rhs.weight(); }\n constexpr bool operator>(const _edge &rhs) const { return rhs < *this; }\n\n private:\n int _from, _to;\n };\n\n public:\n using edge_type = typename Graph<void>::_edge;\n\n Graph() : _size(), edges() {}\n Graph(int v) : _size(v), edges(v) {}\n\n const auto &operator[](int i) const { return edges[i]; }\n auto &operator[](int i) { return edges[i]; }\n const auto begin() const { return edges.begin(); }\n auto begin() { return edges.begin(); }\n const auto end() const { return edges.end(); }\n auto end() { return edges.end(); }\n constexpr int size() const { return _size; }\n\n void add_edge(const edge_type &e) { edges[e.from()].emplace_back(e); }\n void add_edge(int from, int to) { edges[from].emplace_back(from, to); }\n void add_edges(int from, int to) {\n edges[from].emplace_back(from, to);\n edges[to].emplace_back(to, from);\n }\n\n void input_edge(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edge(from - base, to - base);\n }\n }\n void input_edges(int m, int base = 1) {\n for (int i = 0; i < m; ++i) {\n int from, to;\n std::cin >> from >> to;\n add_edges(from - base, to - base);\n }\n }\n\n private:\n int _size;\n std::vector<std::vector<edge_type>> edges;\n};\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n ll l;\n cin >> l;\n Graph<pair<int, int>> g(n);\n rep (i, m) {\n int a, b, c;\n cin >> a >> b >> c;\n --a, --b;\n g.add_edge(a, b, {0, c});\n g.add_edge(b, a, {1, c});\n }\n\n vector dp(n, vector(m + 1, INF));\n dp[0][0] = 0;\n priority_queue<tuple<int, int, int>, vector<tuple<int, int, int>>, greater<>> pq;\n pq.emplace(0, 0, 0);\n while (!pq.empty()) {\n auto [d, x, y] = pq.top();\n pq.pop();\n if (dp[x][y] != d)\n continue;\n for (auto e : g[x]) {\n auto [a, b] = e.weight();\n if (y + a <= m && chmin(dp[e.to()][y + a], d + b)) {\n pq.emplace(dp[e.to()][y + a], e.to(), y + a);\n }\n }\n }\n\n rep (i, m + 1) {\n if (dp[n - 1][i] <= l) {\n co(i);\n return 0;\n }\n }\n co(-1);\n\n return 0;\n}", "accuracy": 0.016483516483516484, "time_ms": 50, "memory_kb": 10968, "score_of_the_acc": -0.1762, "final_rank": 12 }, { "submission_id": "aoj_0705_7606047", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\nusing namespace std;\n\n\nint main() {\n int N, M, L;\n cin >> N >> M >> L;\n\n map<int, int> normal;\n map<int, int> reverse;\n for(int i=0; i<=N; i++) normal[i] = 10000000;\n for(int i=0; i<=N; i++) reverse[i] = 10000000;\n\n for(int i=0; i<M; i++) {\n vector<int> load(3);\n cin >> load[0] >> load[1] >> load[2];\n if(load[0] < load[1] && normal[load[1]] > load[2]) {\n normal[load[1]] = load[2];\n } else if(load[0] > load[1] && reverse[load[0]] > load[2]){\n reverse[load[0]] = load[2];\n }\n }\n\n int res = 0;\n vector<int> dp_city(N+1, 0);\n for(int i=2; i<=N; i++) {\n if(normal[i] != 10000000) {\n dp_city[i] = dp_city[i-1] + normal[i];\n } else if(reverse[i] != 10000000) {\n res++;\n dp_city[i] = dp_city[i-1] + reverse[i];\n reverse[i] = 10000000;\n } else {\n cout << -1 << endl;\n return 1;\n }\n }\n int i=0;\n while(reverse.size() > i && dp_city[N] > L) {\n i++;\n int min = 0;\n for(int j=0; j<reverse.size(); j++) {\n if(min >reverse[j]) min = j;\n }\n if(dp_city[min] > dp_city[min-1] + reverse[min]) {\n int distance = dp_city[min] - dp_city[min-1] + reverse[min];\n for(int i=min; i<=N; i++) {\n dp_city[i] -= distance;\n }\n }\n reverse[min] = 10000000;\n }\n if(dp_city[N] > L) {\n cout << -1 << endl;\n } else {\n cout << res << endl;\n }\n}", "accuracy": 0.06043956043956044, "time_ms": 30, "memory_kb": 3456, "score_of_the_acc": 0, "final_rank": 11 }, { "submission_id": "aoj_0705_6663675", "code_snippet": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <tuple>\n\nusing namespace std;\n\nusing Int = int_fast64_t;\n\nconst Int INF = 1LL << 62;\n\nint main()\n{\n\tint N, M, L; cin >> N >> M >> L;\n\tvector<tuple<int, int, int>> ABC(M);\n\tfor (auto& [A, B, C] : ABC) cin >> A >> B >> C;\n\tvector<pair<Int, int>> D(N + 1, {INF, -1});\n\tusing T = tuple<int, Int, int>;\n\tpriority_queue<T, vector<T>, greater<T>> Q;\n\tfor (Q.push({0, 0, 1}); !Q.empty();) {\n\t\tauto [r, d, n] = Q.top(); Q.pop();\n\t\tif (D[n].first <= d || d > L) continue;\n\t\tD[n] = {d, r};\n\t\tif (n == N) break;\n\t\tfor (auto [A, B, C] : ABC) if (n == A) {\n\t\t\tQ.emplace(r, d + C, B);\n\t\t} else if (n == B) {\n\t\t\tQ.emplace(r + 1, d + C, A);\n\t\t}\n\t}\n\tcout << D[N].second << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 3544, "score_of_the_acc": -0.0259, "final_rank": 1 }, { "submission_id": "aoj_0705_6303626", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nint main() {\n\tint n, m, l; std::cin >> n >> m >> l;\n\tstd::vector<std::tuple<int, int, int>> edges(m);\n\tfor (auto& [a, b, c] : edges) {\n\t\tstd::cin >> a >> b >> c; --a; --b;\n\t}\n\tstd::vector<std::vector<std::pair<int, int>>> graph(n);\n\tstd::vector<std::vector<std::pair<int, int>>> reverse(n);\n\tfor (const auto [a, b, c] : edges) {\n\t\tgraph[a].emplace_back(b, c);\n\t\treverse[b].emplace_back(a, c);\n\t}\n\tstd::vector<std::vector<int>> min_distance(n, std::vector<int>(m + 1, INT_MAX));\n\tmin_distance[0][0] = 0;\n\tconst auto comparator = [](const auto a, const auto b) {return a.second > b.second; };\n\tstd::priority_queue<std::pair<std::pair<int, int>, int>, std::vector<std::pair<std::pair<int, int>, int>>, decltype(comparator)> queue(comparator);\n\tqueue.emplace(std::make_pair(0, 0), 0);\n\twhile (!queue.empty()) {\n\t\tconst auto [pair, cost] = queue.top(); queue.pop();\n\t\tconst auto [top, count] = pair;\n\t\tif (l < cost) continue;\n\t\tif (min_distance[top][count] < cost) continue;\n\t\tfor (const auto [next, len]: graph[top]) {\n\t\t\tconst auto d = cost + len;\n\t\t\tif (min_distance[next][count] > d) {\n\t\t\t\tmin_distance[next][count] = d;\n\t\t\t\tqueue.emplace(std::make_pair(next, count), d);\n\t\t\t}\n\t\t}\n\t\tif (count < m) {\n\t\t\tfor (const auto [next, len] : reverse[top]) {\n\t\t\t\tconst auto d = cost + len;\n\t\t\t\tif (min_distance[next][count + 1] > d) {\n\t\t\t\t\tmin_distance[next][count + 1] = d;\n\t\t\t\t\tqueue.emplace(std::make_pair(next, count + 1), d);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tconst auto first = std::distance(min_distance.back().begin(), std::find_if(min_distance.back().begin(), min_distance.back().end(), [l](const int len) {return len <= l; }));\n\tif (first <= m) {\n\t\tstd::cout << first << '\\n';\n\t}\n\telse {\n\t\tstd::cout << \"-1\\n\";\n\t}\n\t\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 11368, "score_of_the_acc": -0.2561, "final_rank": 2 }, { "submission_id": "aoj_0705_6277981", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x - 1; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++;\n\t\t//res += n % 10;\n\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\n\nconst int nCkMAX = 500000;\nll fac[nCkMAX], finv[nCkMAX], inv[nCkMAX];//n!、1/n!、1/n\n// テーブルを作る前処理\nvoid nCkinit(ll m) {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < nCkMAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % m;\n\t\tinv[i] = m - inv[m % i] * (m / i) % m;\n\t\tfinv[i] = finv[i - 1] * inv[i] % m;\n\t}\n}\n// 二項係数計算\nll nCk(ll n, ll k, ll m) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % m) % m;\n}\n//nが大きくてkが小さい時\n//nCkMAXはk+2まででOK\nll nCk2(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tres = res * finv[k] % m;\n\treturn res;\n}\n\n//xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n//1~6まで出したいときは\n//xorshift() % 6 + 1\nunsigned int xorshift() {\n\tstatic unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n\tunsigned int tt = (tx ^ (tx << 11));\n\ttx = ty; ty = tz; tz = tw;\n\treturn (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\n\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\n////////////////////////////////struct\n/*struct edge {\n\tll to; ld cost;\n};*/\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\tll first;\n\tll second;\n\tll kai;\n\n\t//bool operator<(const status& rhs) const { return c < rhs.c; };\n\t//bool operator>(const status& rhs) const { return c > rhs.c; };\n\tbool operator<(const status& rhs) const { return first < rhs.first; };\n\tbool operator>(const status& rhs) const { return first > rhs.first; };\n};\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"Yes\\n\"; }\n\telse { cout << \"No\\n\"; }\n}\n//多倍長整数演算\n//nCkを求めるときにnCkMAXとnCkinit\n\n//O(ElogV)\n//const ll INF = 10000000000000;\nstruct edge { ll to, cost; };\n//typedef pair<ll, ll>P; //firstは最短距離、secondは頂点番号\n\n//負の辺は本当にないですか???\n\nll d[1456][1234];//始点sから終点tまでのコストd[t]\nvector<edge> G[213456];//コスト\nvector<edge> rG[213456];//コスト\nvoid dijkstra(ll s) {\n\t//greater<P>を指定→firstが小さい順\n\tpriority_queue<status, vector<status>, greater<status> >que;\n\td[s][0] = 0; que.push({0, s, 0});\n\twhile (!que.empty()) {\n\t\tstatus p = que.top(); que.pop();\n\t\tint v = p.second;\n\t\tif (d[v][p.kai] < p.first) { continue; }\n\t\tfor (int i = 0; i < G[v].size(); i++) {\n\t\t\tedge e = G[v][i];\n\t\t\tif (d[e.to][p.kai] > d[v][p.kai] + e.cost) {\n\t\t\t\td[e.to][p.kai] = d[v][p.kai] + e.cost;\n\t\t\t\tque.push({ d[e.to][p.kai], e.to, p.kai });\n\t\t\t}\n\t\t}\n\t\tif (p.kai > 1000) { continue; }\n\t\trep(i, rG[v].size()) {\n\t\t\tedge e = rG[v][i];\n\t\t\tif (d[e.to][p.kai + 1] > d[v][p.kai] + e.cost) {\n\t\t\t\td[e.to][p.kai + 1] = d[v][p.kai] + e.cost;\n\t\t\t\tque.push({ d[e.to][p.kai + 1], e.to, p.kai + 1 });\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\trep(i, 1234) {\n\t\trep(j, 1234) {\n\t\t\td[i][j] = INF;\n\t\t}\n\t}\n\tll n, m, l; cin >> n >> m >> l;\n\trep(i, m) {\n\t\tll a, b, c; cin >> a >> b >> c;\n\t\tG[a].push_back({ b, c });\n\t\trG[b].push_back({ a,c });\n\t}\n\tdijkstra(1);\n\tll ans = INF;\n\trep(i, 1001) {\n\t\tif (d[n][i] <= l) { ans = min(ans, i); }\n\t}\n\tcout << (ans == INF ? - 1 : ans) << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 35632, "score_of_the_acc": -0.7895, "final_rank": 7 }, { "submission_id": "aoj_0705_6264393", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,l);\n vector<vector<array<int,3>>> g(n);\n int u,v,c;\n rep(i,m){\n in(u,v,c);\n u--,v--;\n g[u].push_back({v,c,0});\n g[v].push_back({u,c,1});\n }\n vector2d(int,dist,n,m+1,INF);\n //距離、頂点、反転回数\n rpriority_queue<array<int,3>> pq;\n dist[0][0]=0;\n pq.push({0,0,0});\n while(!pq.empty()){\n auto a=pq.top();\n pq.pop();\n for(auto b:g[a[1]]){\n if(a[2]+b[2]>m)continue;\n if(a[0]+b[1]>=dist[b[0]][a[2]+b[2]])continue;\n dist[b[0]][a[2]+b[2]]=a[0]+b[1];\n pq.push({a[0]+b[1],b[0],a[2]+b[2]});\n }\n }\n for(int i=0;i<=m;i++){\n if(dist[n-1][i]<=l){\n out(i);\n return 0;\n }\n }\n out(-1);\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 11632, "score_of_the_acc": -0.3825, "final_rank": 3 }, { "submission_id": "aoj_0705_6161372", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n\n#define SIZE 1005\n\nstruct Edge{\n\tEdge(int arg_to,ll arg_dist,bool arg_is_rev){\n\t\tto = arg_to;\n\t\tdist = arg_dist;\n\t\tis_rev = arg_is_rev;\n\t}\n\tint to;\n\tll dist;\n\tbool is_rev;\n};\n\n\nstruct State{\n\tState(){\n\n\t\tnode = num_rev = 0;\n\t\tsum_dist = 0;\n\t}\n\tState(int arg_node,ll arg_sum_dist,int arg_num_rev){\n\t\tnode = arg_node;\n\t\tsum_dist = arg_sum_dist;\n\t\tnum_rev = arg_num_rev;\n\t}\n\tbool operator<(const struct State& arg) const{\n\n\t\treturn sum_dist > arg.sum_dist; //昇順(PQ)\n\t}\n\n\tint node,num_rev;\n\tll sum_dist;\n};\n\nint N,E;\nll base_dist;\nll min_dist[SIZE][SIZE];\nvector<Edge> G[SIZE];\n\nvoid calc_dist(int start){\n\n\tfor(int i = 0; i < N; i++){\n\t\tfor(int k = 0; k <= N; k++){\n\t\t\tmin_dist[i][k] = HUGE_NUM;\n\t\t}\n\t}\n\n\tmin_dist[start][0] = 0; //min_dist[node][反転回数] = 最小コスト\n\tpriority_queue<State> Q;\n\n\tQ.push(State(start,0,0));\n\n\twhile(!Q.empty()){\n\n\t\tState state = Q.top(); //都度取り出し(マイナスのsum_dist対策)\n\t\tQ.pop();\n\n\t\tif(state.sum_dist > min_dist[state.node][state.num_rev]){\n\n\t\t\tcontinue;\n\t\t}\n\n\t\tfor(int i = 0; i < G[state.node].size(); i++){\n\n\t\t\tint next_node = G[state.node][i].to;\n\t\t\tll next_dist = state.sum_dist + G[state.node][i].dist;\n\t\t\tint next_rev = state.num_rev;\n\t\t\tif(G[state.node][i].is_rev){\n\n\t\t\t\tnext_rev++;\n\t\t\t}\n\t\t\tif(next_rev == N+1)continue;\n\n\t\t\tif(min_dist[next_node][next_rev] > next_dist){\n\n\t\t\t\tmin_dist[next_node][next_rev] = next_dist;\n\t\t\t\tQ.push(State(next_node,next_dist,next_rev));\n\t\t\t}\n\t\t}\n\t}\n}\n\n\nint main(){\n\n\tscanf(\"%d %d %lld\",&N,&E,&base_dist);\n\n\tint from,to;\n\tll dist;\n\n\tfor(int loop = 0; loop < E; loop++){\n\n\t\tscanf(\"%d %d %lld\",&from,&to,&dist);\n\t\tfrom--;\n\t\tto--;\n\n\t\tG[from].push_back(Edge(to,dist,false));\n\t\tG[to].push_back(Edge(from,dist,true));\n\t}\n\n\tcalc_dist(0);\n\n\tfor(int k = 0; k <= N; k++){\n\t\tif(min_dist[N-1][k] <= base_dist){\n\n\t\t\tprintf(\"%d\\n\",k);\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tprintf(\"-1\\n\");\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 140, "memory_kb": 14924, "score_of_the_acc": -0.4628, "final_rank": 4 } ]
aoj_0722_cpp
飴 2 (Candies 2) 問題文 机の上に N 個の飴が横一列に並んでおり,左から順に 1 から N までの番号が付けられている.飴 i ( 1 ≦ i ≦ N ) の美味しさは A i である. JOI 君は, N 個の飴のうちいくつかを選んで食べることにした. ただし,飴を食べ過ぎないために,どの連続する K 個の飴についても,そのうち高々 2 個しか食べないようにする.すなわち,どの j ( 1 ≦ j ≦ N - K + 1 ) についても,飴 j から飴 j + K - 1 までの連続する K 個の飴のうち,食べる飴の個数は 2 個以下でなければならない. このもとで,JOI 君は食べる飴の美味しさの合計をできるだけ大きくしたい. N 個の飴の美味しさと K が与えられたとき,JOI 君が食べる飴の美味しさの合計の最大値を求めるプログラムを作成せよ. 制約 2 ≦ K ≦ N ≦ 3 000 . 1 ≦ A i ≦ 10 9 ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N K A 1 A 2 … A N 出力 標準出力に,JOI 君が食べる飴の美味しさの合計の最大値を 1 行で出力せよ. 入出力例 入力例 1 5 4 1 3 2 4 3 出力例 1 8 JOI 君が飴 1 ,飴 4 , 飴 5 を食べるとき,美味しさの合計は 8 となる. どの連続する 4 個の飴についても食べる飴の個数が 2 個以下であるような食べ方のうち,美味しさの合計が 9 以上であるようなものは存在しないため, 8 を出力する. 入力例 2 6 3 3 7 1 5 6 4 出力例 2 21 JOI 君が飴 1 ,飴 2 , 飴 4 ,飴 5 を食べるとき,美味しさの合計は 21 となる. どの連続する 3 個の飴についても食べる飴の個数が 2 個以下であるような食べ方のうち,美味しさの合計が 22 以上であるようなものは存在しないため, 21 を出力する. 入力例 3 5 2 3 3 2 2 1 出力例 3 11 入力例 4 12 5 864814169 716638377 926889183 891468826 217138351 891972397 504371916 678159995 435478604 181254225 760822841 688502728 出力例 4 4427122428 情報オリンピック日本委員会 作 『第 21 回日本情報オリンピック JOI 2021/2022 二次予選競技課題』
[ { "submission_id": "aoj_0722_10581059", "code_snippet": "#include <iostream>\nusing namespace std;\nint A[3001];\nlong table[3001][3001];\nint N, K;\n\nlong calcM(int pos, int prev){\n if(pos>N){\n return 0;\n }\n if(pos==N){\n return A[N];\n }\n \n if(table[pos][prev]!=-1){\n return table[pos][prev];\n }\n \n long res;\n if(prev==0){\n res= max(A[pos]+calcM(pos+1,1),calcM(pos+1,0));\n }else{\n \n int prevNext=prev+1;\n if(prevNext>=K){\n prevNext=0;\n }\n res= max(A[pos]+calcM(pos-prev+K,K-prev),calcM(pos+1,prevNext));\n }\n table[pos][prev]=res;\n return res;\n}\n\nint main(void){\n // Your code here!\n cin >> N >> K;\n for(int i=1;i<N+1;i++){\n cin >> A[i];\n for(int j=0;j<K;j++){\n table[i][j]=-1;\n }\n }\n cout << calcM(1,0) << endl;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 73968, "score_of_the_acc": -0.1723, "final_rank": 2 }, { "submission_id": "aoj_0722_9568835", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,K;\n cin>>N>>K;\n vector<ll> A(N);\n for(int i=0;i<N;i++)cin>>A[i];\n vector<vector<ll>> DP(N,vector<ll>(N,-1e18));\n vector<vector<ll>> MDP(N,vector<ll>(N,-1e18));\n ll an=0;\n for(int i=0;i<N;i++){\n for(int j=0;j<i;j++){\n DP[i][j]=max(DP[i][j],A[i]+A[j]);\n if(i-K>=0&&j!=0){\n DP[i][j]=max(DP[i][j],MDP[j][min(i-K,ll(j-1))]+A[i]);\n }\n an=max(an,DP[i][j]);\n MDP[i][j]=DP[i][j];\n if(j!=0)MDP[i][j]=max(MDP[i][j],MDP[i][j-1]);\n }\n }\n cout<<an<<endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 144064, "score_of_the_acc": -1.6667, "final_rank": 8 }, { "submission_id": "aoj_0722_9051929", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, K;\n cin >> N >> K;\n vi A(N);\n rep(i, N) cin >> A[i];\n vv(ll, dp, N, N, -inf);\n dp[0][0] = 0;\n ll ans = 0;\n rep(i, N) {\n rep(j, i) {\n dp[i][j] = A[i] + A[j];\n if (j > 0) {\n chmax(dp[i][j], dp[i][j-1]);\n if (0 <= i-K) {\n chmax(dp[i][j], dp[j][min(j-1, i-K)] + A[i]);\n }\n } \n chmax(ans, dp[i][j]);\n }\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 73572, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0722_8750816", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"a.cpp\"\n\nint main(void) {\n int n, k;\n cin >> n >> k;\n vector<int> a(n);\n cin >> a;\n vector dp(n + 1, vector(k, 0L));\n rep (i, n) {\n rep (j, k) {\n chmax(dp[i + 1][max(j - 1, 0)], dp[i][j]);\n if (j == 0) {\n chmax(dp[i + 1][k - 2], dp[i][0] + a[i]);\n } else {\n chmax(dp[min(n, i + 1 + j)][max(0, k - 2 - j)], dp[i][j] + a[i]);\n }\n }\n }\n\n ll ans = 0;\n rep (i, n + 1) chmax(ans, *max_element(all(dp[i])));\n co(ans);\n\n return 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 73572, "score_of_the_acc": -0.5, "final_rank": 6 }, { "submission_id": "aoj_0722_8012812", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 3005\n\nll dp[SIZE],maxi[SIZE];\nll dp2[SIZE][SIZE],maxi2[SIZE][SIZE];\nll A[SIZE];\n\n\nint main(){\n\n\tint N,K;\n\tscanf(\"%d %d\",&N,&K);\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\t//A[i]の手前K-1個に、他に食べられた飴がない\n\t\tdp[i] = A[i];\n\t\tif(i-K >= 1){\n\n\t\t\tdp[i] += maxi[i-K];\n\t\t}\n\n\t\t//A[i]の手前K-1個に、1つ食べられた飴がある\n\t\tll work = 0;\n\t\tfor(int a = max(1,i-K+1); a <= i-1; a++){\n\n\t\t\tll tmp = A[i]+dp[a];\n\t\t\tll tmp2 = 0;\n\t\t\tif(i-K >= 1){\n\n\t\t\t\ttmp2 = A[i]+maxi2[a][i-K];\n\t\t\t}\n\t\t\tdp2[i][a] = max(tmp,tmp2); //dp2[最後に食べた飴のindex][その1つ前に食べた飴のindex] = 最大値\n\n\t\t\tchmax(work,dp2[i][a]);\n\t\t}\n\n\t\tfor(int a = max(1,i-K+1); a <= i-1; a++){\n\n\t\t\tmaxi2[i][a] = dp2[i][a];\n\t\t\tchmax(maxi2[i][a],maxi2[i][a-1]); //自分より左の最大値を前計算しておく\n\t\t}\n\t\tmaxi[i] = max(dp[i],work);\n\t\tchmax(maxi[i],maxi[i-1]);\n\t}\n\n\tprintf(\"%lld\\n\",maxi[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 95520, "score_of_the_acc": -0.478, "final_rank": 4 }, { "submission_id": "aoj_0722_8012808", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 3005\n\nll dp[SIZE],maxi[SIZE];\nll dp2[SIZE][SIZE],maxi2[SIZE][SIZE];\nll A[SIZE];\n\n\nint main(){\n\n\tint N,K;\n\tscanf(\"%d %d\",&N,&K);\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tscanf(\"%lld\",&A[i]);\n\t}\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\t//A[i]の手前K-1個に、他に食べられた飴がない\n\t\tdp[i] = A[i];\n\t\tif(i-K >= 1){\n\n\t\t\tdp[i] += maxi[i-K];\n\t\t}\n\n\t\t//A[i]の手前K-1個に、1つ食べられた飴がある\n\t\tll work = 0;\n\t\tfor(int a = max(1,i-K+1); a <= i-1; a++){\n\n\t\t\tll tmp = A[i]+dp[a];\n\t\t\tll tmp2 = 0;\n\t\t\tif(i-K >= 1){\n\n\t\t\t\ttmp2 = A[i]+maxi2[a][i-K];\n\t\t\t}\n\t\t\tdp2[i][a] = max(tmp,tmp2);\n\n\t\t\tchmax(work,dp2[i][a]);\n\t\t}\n\n\t\tfor(int a = max(1,i-K+1); a <= i-1; a++){\n\n\t\t\tmaxi2[i][a] = dp2[i][a];\n\t\t\tchmax(maxi2[i][a],maxi2[i][a-1]);\n\t\t}\n\t\tmaxi[i] = max(dp[i],work);\n\t\tchmax(maxi[i],maxi[i-1]);\n\t}\n\n\tprintf(\"%lld\\n\",maxi[N]);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 95528, "score_of_the_acc": -0.4781, "final_rank": 5 }, { "submission_id": "aoj_0722_7878418", "code_snippet": "#include <bits/extc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n\ntemplate <class T> using Max_Heap = __gnu_pbds::priority_queue<T, less<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Min_Heap = __gnu_pbds::priority_queue<T, greater<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = __gnu_pbds::gp_hash_table<K, V>;\ntemplate <class T> using Rope = __gnu_cxx::rope<T>;\nusing Trie = __gnu_pbds::trie<string, __gnu_pbds::null_type, __gnu_pbds::trie_string_access_traits<>, __gnu_pbds::pat_trie_tag, __gnu_pbds::trie_prefix_search_node_update>;\n\ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, k;\n cin >> n >> k;\n\n assert(2 <= k && k <= n && n <= 3000);\n\n vector<int> a(n);\n\n cin >> a;\n\n for (auto e : a) assert(1 <= e && e <= 1000000000);\n\n vector dp(n + 1, vector(n + 1, 0LL));\n\n for (int i = 1; i <= n; ++i) {\n dp[i][0] = a[i - 1];\n for (int j = 1; j <= n; ++j) {\n if (j < i) {\n chmax(dp[i][j], dp[j][max(i - k, 0)] + a[i - 1]);\n }\n chmax(dp[i][j], dp[i][j - 1]);\n }\n }\n\n long long res = 0;\n\n for (int i = 0; i <= n; ++i) {\n for (int j = 0; j <= n; ++j) {\n chmax(res, dp[i][j]);\n }\n }\n\n cout << res << '\\n';\n\n return (0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 73592, "score_of_the_acc": -0.3336, "final_rank": 3 }, { "submission_id": "aoj_0722_7848620", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,l);\n vector<ll> a(n);\n in(a);\n vector2d(ll,dp,n+1,n+1,-1);\n function<ll(int,int)> rec=[&](int i,int s){\n if(i>=n)return 0ll;\n if(dp[i][s]!=-1)return dp[i][s];\n ll res=rec(i+1,s);\n if(s==0)chmax(res,rec(i+1,i+1)+a[i]);\n else chmax(res,rec(max(i+1,s+l-1),i+1)+a[i]);\n return dp[i][s]=res;\n };\n out(rec(0,0));\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 73884, "score_of_the_acc": -1.0044, "final_rank": 7 } ]
aoj_0706_cpp
デジタルアート JOI 高校の生徒である葵はデジタルアート制作が趣味であり,今日も新しい画像を作った. この画像のサイズは,縦 H ピクセル,横 W ピクセルであり, H × W のマス目のような形で表される.ここで,上から i 行目 ( 1 ≦ i ≦ H ),左から j 列目 ( 1 ≦ j ≦ W ) のピクセルを (i, j) で表す.各ピクセルは 1 つの色で塗られている.各色には 1 から 256 までの番号が付けられており,ピクセル (i, j) の色の番号は A i, j である. 葵はこの画像を同級生である凛に見せたが,凛は「画像に使われている色の種類が多すぎる」という理由で気に入らなかった.そこで葵は,以下のように画像内のある領域を隠して,見える色の種類をできるだけ少なくできないかと考えた. 葵は S 個以下のピクセルを選んで隠す. ただし,隠すピクセルの領域は 1 つの長方形で表されなければならない. 画像のデータと,隠すピクセルの個数の上限 S が与えられたとき,画像内のある領域を隠したときに見える色の種類の数としてありうる最小の値を求めるプログラムを作成せよ. 制約 1 ≦ H ≦ 1000 . 1 ≦ W ≦ 1000 . 1 ≦ S ≦ HW . 1 ≦ A i, j ≦ 256 ( 1 ≦ i ≦ H , 1 ≦ j ≦ W ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. H W S A 1, 1 A 1, 2 … A 1, W A 2, 1 A 2, 2 … A 2, W : A H, 1 A H, 2 … A H, W 出力 標準出力に,画像内のある領域を隠したときに見える色の種類の数としてありうる最小の値を 1 行で出力せよ. 特に,見えるピクセルが一つもない状態にできる場合は 0 と出力せよ. 入出力例 入力例 1 1 10 7 5 1 2 5 2 2 5 6 6 5 出力例 1 2 例えば,左から数えて 2 番目から 8 番目までのピクセルを隠すと,番号 5, 6 の色だけが見え,その種類の数は 2 となる.この場合,隠すピクセルは 7 個となり,条件を満たす.また,葵は見える色を 1 種類以下にすることはできない.よって 2 を出力する. 入力例 2 10 10 45 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 3 3 1 1 1 1 1 2 1 2 3 1 3 1 1 1 2 1 2 6 6 3 1 3 1 1 2 2 6 1 1 6 3 3 1 1 4 4 6 1 1 6 5 5 1 1 4 1 4 6 6 5 1 5 1 1 1 4 1 4 5 1 5 1 1 1 1 1 4 4 5 5 1 1 1 1 1 1 1 1 1 1 1 1 1 出力例 2 4 例えば,左上をピクセル (2, 1) ,右下をピクセル (7, 7) とする長方形領域を隠すと,番号 1, 3, 4, 5 の色だけが見え,その種類の数は 4 となる.この場合,隠すピクセルは 42 個となり,条件を満たす. この説明を図で表すと,以下のようになる. 入力例 3 5 10 1 2 3 5 7 1 1 1 3 1 7 1 9 2 3 2 9 3 1 3 7 4 1 4 3 4 7 5 3 5 9 6 1 6 7 7 1 7 3 7 9 8 3 8 9 9 7 2 3 5 7 出力例 3 9 隠すピクセルを S = 1 個以下にするという条件の下では,葵は番号 1, 2, 3, ..., 9 の 9 種類の色が見えるようにしかできない.よって 9 を出力する. 入力例 4 9 6 54 1 1 1 1 1 3 6 14 14 3 3 12 9 13 1 10 3 3 9 13 5 5 3 3 6 13 10 3 7 3 2 5 8 5 3 3 6 5 5 3 15 3 6 5 10 5 3 3 2 2 5 7 3 3 出力例 4 0 54 個すべてのピクセルを隠して,見えるピクセルが一つもないようにできる.よって 0 を出力する. 入力例 5 8 10 59 3 3 3 3 3 3 3 3 2 3 3 1 3 3 3 3 3 2 3 3 3 3 1 4 3 4 2 3 3 3 3 3 3 1 4 2 4 3 3 3 3 3 3 4 1 4 2 3 3 3 3 3 3 1 4 3 4 2 3 3 3 3 1 3 3 3 3 3 2 3 3 1 3 3 3 3 3 3 3 3 出力例 5 2 例えば,左上をピクセル (3, 1) ,右下をピクセル (10, 7) とする長方形領域を隠すと,番号 1, 3 の色だけが見え,その種類の数は 2 となる.この場合,隠すピクセルは 56 個となり,条件を満たす. この説明を図で表すと,以下のようになる. 情報オリンピック日本委員会 作 『日本情報オリンピック 第1回 女性部門』
[ { "submission_id": "aoj_0706_7070793", "code_snippet": "#include <iostream>\n#include <bitset>\n#include <vector>\n#include <string.h>\n#include <set>\nusing namespace std;\nconst int c257=257;\nconst int c1001=1001;\n \nstruct E{\n\tint p1;\n\tbitset<c257> b1;\n\tbool operator<(const E e1)const{\n\t\treturn p1<e1.p1;\n\t}\n};\n \nvector<E> f(int *as){\n\tvector<E> vec1;\n\tvector<E> vec2;\n\tfor(int i=0;i<c1001;i++){\n\t\tE e1;\n\t\te1.p1=i;\n\t\tvec1.push_back(e1);\n\t}\n\tfor(int i=0;i<c257;i++){\n\t\tif(as[i]==-1)continue;\n\t\tvec1[as[i]].b1.set(i);\n\t}\n\tbitset<c257> b2;\n\tfor(int i=0;i<c1001;i++){\n\t\tif(vec1[i].b1.count()==0)continue;\n\t\tE e1;\n\t\tb2|=vec1[i].b1;\n\t\te1.p1=vec1[i].p1;\n\t\te1.b1=b2;\n\t\tvec2.push_back(e1);\n\t}\n\treturn vec2;\n}\n \nint main() {\n\t// your code goes here\n\tint ls[c257];\n\tint rs[c257];\n\tint us[c257];\n\tint ds[c257];\n\tint cs[c257];\n\tmemset(ls,-1,sizeof(ls));\n\tmemset(rs,-1,sizeof(rs));\n\tmemset(us,-1,sizeof(us));\n\tmemset(ds,-1,sizeof(ds));\n\tint h,w,s;\n\tcin>>h>>w>>s;\n\tfor(int i=0;i<c257;i++)cs[i]=1;\n\tint all2=0;\n\tfor(int y=0;y<h;y++){\n\t\tfor(int x=0;x<w;x++){\n\t\t\tint t;\n\t\t\tcin>>t;\n\t\t\tall2+=cs[t];\n\t\t\tcs[t]=0;\n\t\t\tif(ls[t]==-1||x<ls[t])ls[t]=x;\n\t\t\tif(rs[t]==-1||rs[t]<x)rs[t]=x;\n\t\t\tif(us[t]==-1||y<us[t])us[t]=y;\n\t\t\tif(ds[t]==-1||ds[t]<y)ds[t]=y;\n\t\t}\n\t}\n\tint ans=all2;\n\tvector<E> us2=f(us);\n\tvector<E> ds2=f(ds);\n\tvector<E> ls2=f(ls);\n\tvector<E> rs2=f(rs);\n\tset<E> ss2;\n \n\tfor(int i=0;i<us2.size();i++){\n\t\tss2.insert(us2[i]);\n\t\t//cout<<us2[i].p1<<\" \"<<us2[i].b1.count()<<\" \";\n\t}\n\t//for(set<E>::iterator it=ss2.begin();it!=ss2.end();it++){\n//\tcout<<(*it).p1<<\" \"<<(*it).b1.count()<<endl;\n//\t}\n\t//cout<<endl;\n\t//for(int i=0;i<ds2.size();i++){\n\t//\tcout<<ds2[i].p1<<\" \"<<ds2[i].b1.count()<<\" \";\n\t//}\n\t//cout<<endl;\n\t//for(int i=0;i<ls2.size();i++){\n\t//\tcout<<ls2[i].p1<<\" \"<<ls2[i].b1.count()<<\" \";\n\t//}\n\t//cout<<endl;\n\t//for(int i=0;i<rs2.size();i++){\n\t//\tcout<<rs2[i].p1<<\" \"<<rs2[i].b1.count()<<\" \";\n\t//}\n \n\t//cout<<endl;\n\tfor(int r2=0;r2<rs2.size();r2++){\n\t\tE e1=rs2[r2];\n\t\tfor(int l2=0;l2<ls2.size();l2++){\n\t\t\tE e2;\n\t\t\te2.p1=ls2[l2].p1;\n\t\t\tif(l2>0)e2.b1=ls2[l2-1].b1;\n\t\t\tif(e1.p1<e2.p1)break;\n\t\t\tint lenx=e1.p1-e2.p1+1;\n\t\t\tif(lenx>s)continue;\n\t\t\tint leny=s/lenx;\n \n\t\t\tbitset<c257> b2=~(e1.b1&e2.b1);\n\t\t\tbitset<c257> b1=e1.b1&b2;\n \n\t\t\tfor(int d2=0;d2<ds2.size();d2++){\n\t\t\t\tE e3=ds2[d2];\n\t\t\t\tint u0=e3.p1-leny+1;\n\t\t\t\t//cout<<e3.p1<<\" \"<<lenx<<\" \"<<leny<<endl;\n\t\t\t\tif(u0<0)u0=0;\n\t\t\t\tE e0;\n\t\t\t\te0.p1=u0;\n\t\t\t\tset<E>::iterator it2=ss2.lower_bound(e0);\n\t\t\t\tif (it2==ss2.end()) continue;\n\t\t\t\tE e4;\n\t\t\t\te4.p1=(*it2).p1;\n\t\t\t\tif(it2!=ss2.begin()){\n\t\t\t\t\tit2--;\n\t\t\t\t\te4.b1=(*it2).b1;\n\t\t\t\t}\n\t\t\t\t//cout<<u0<<\" \"<<leny<<\" r\"<<e1.p1<<\" l\"<<e2.p1<<\" d\"<<e3.p1<<\" u\"<<e4.p1<<endl;\n\t\t\t\tint leny2=e3.p1-e4.p1+1;\n\t\t\t\tif(lenx*leny2>s)continue;\n\t\t\t\tbitset<c257> b4=~(e3.b1&e4.b1);\n\t\t\t\tbitset<c257> b3=e3.b1&b4;\n\t\t\t\tint ans2=all2-(b1&b3).count();\n \n\t\t\t\tif(ans2<ans){\n\t\t\t\t\tans=ans2;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 770, "memory_kb": 3252, "score_of_the_acc": -0.9903, "final_rank": 15 }, { "submission_id": "aoj_0706_7070666", "code_snippet": "#include <iostream>\n#include <bitset>\n#include <vector>\n#include <string.h>\n#include <set>\nusing namespace std;\nconst int c257=257;\nconst int c1001=1001;\n\nstruct E{\n\tint p1;\n\tbitset<c257> b1;\n\tbool operator<(const E e1)const{\n\t\treturn p1<e1.p1;\n\t}\n};\n\nvector<E> f(int *as){\n\tvector<E> vec1;\n\tvector<E> vec2;\n\tfor(int i=0;i<c1001;i++){\n\t\tE e1;\n\t\te1.p1=i;\n\t\tvec1.push_back(e1);\n\t}\n\tfor(int i=0;i<c257;i++){\n\t\tif(as[i]==-1)continue;\n\t\tvec1[as[i]].b1.set(i);\n\t}\n\tbitset<c257> b2;\n\tfor(int i=0;i<c1001;i++){\n\t\tif(vec1[i].b1.count()==0)continue;\n\t\tE e1;\n\t\tb2|=vec1[i].b1;\n\t\te1.p1=vec1[i].p1;\n\t\te1.b1=b2;\n\t\tvec2.push_back(e1);\n\t}\n\treturn vec2;\n}\n\nint main() {\n\t// your code goes here\n\tint ls[c257];\n\tint rs[c257];\n\tint us[c257];\n\tint ds[c257];\n\tint cs[c257];\n\tmemset(ls,-1,sizeof(ls));\n\tmemset(rs,-1,sizeof(rs));\n\tmemset(us,-1,sizeof(us));\n\tmemset(ds,-1,sizeof(ds));\n\tint h,w,s;\n\tcin>>h>>w>>s;\n\tfor(int i=0;i<c257;i++)cs[i]=1;\n\tint all2=0;\n\tfor(int y=0;y<h;y++){\n\t\tfor(int x=0;x<w;x++){\n\t\t\tint t;\n\t\t\tcin>>t;\n\t\t\tall2+=cs[t];\n\t\t\tcs[t]=0;\n\t\t\tif(ls[t]==-1||x<ls[t])ls[t]=x;\n\t\t\tif(rs[t]==-1||rs[t]<x)rs[t]=x;\n\t\t\tif(us[t]==-1||y<us[t])us[t]=y;\n\t\t\tif(ds[t]==-1||ds[t]<y)ds[t]=y;\n\t\t}\n\t}\n\tint ans=all2;\n\tvector<E> us2=f(us);\n\tvector<E> ds2=f(ds);\n\tvector<E> ls2=f(ls);\n\tvector<E> rs2=f(rs);\n\tset<E> ss2;\n\t\n\tfor(int i=0;i<us2.size();i++){\n\t\tss2.insert(us2[i]);\n\t\t//cout<<us2[i].p1<<\" \"<<us2[i].b1.count()<<\" \";\n\t}\n\t//for(set<E>::iterator it=ss2.begin();it!=ss2.end();it++){\n//\tcout<<(*it).p1<<\" \"<<(*it).b1.count()<<endl;\n//\t}\n\t//cout<<endl;\n\t//for(int i=0;i<ds2.size();i++){\n\t//\tcout<<ds2[i].p1<<\" \"<<ds2[i].b1.count()<<\" \";\n\t//}\n\t//cout<<endl;\n\t//for(int i=0;i<ls2.size();i++){\n\t//\tcout<<ls2[i].p1<<\" \"<<ls2[i].b1.count()<<\" \";\n\t//}\n\t//cout<<endl;\n\t//for(int i=0;i<rs2.size();i++){\n\t//\tcout<<rs2[i].p1<<\" \"<<rs2[i].b1.count()<<\" \";\n\t//}\n\t\n\t//cout<<endl;\n\tfor(int r2=0;r2<rs2.size();r2++){\n\t\tE e1=rs2[r2];\n\t\tfor(int l2=0;l2<ls2.size();l2++){\n\t\t\tE e2;\n\t\t\te2.p1=ls2[l2].p1;\n\t\t\tif(l2>0)e2.b1=ls2[l2-1].b1;\n\t\t\tif(e1.p1<e2.p1)break;\n\t\t\tint lenx=e1.p1-e2.p1+1;\n\t\t\tif(lenx>s)continue;\n\t\t\tint leny=s/lenx;\n\t\t\t\n\t\t\tbitset<c257> b2=~(e1.b1&e2.b1);\n\t\t\tbitset<c257> b1=e1.b1&b2;\n\t\t\t\n\t\t\tfor(int d2=0;d2<ds2.size();d2++){\n\t\t\t\tE e3=ds2[d2];\n\t\t\t\tint u0=e3.p1-leny+1;\n\t\t\t\t//cout<<e3.p1<<\" \"<<lenx<<\" \"<<leny<<endl;\n\t\t\t\tif(u0<0)u0=0;\n\t\t\t\tE e0;\n\t\t\t\te0.p1=u0;\n\t\t\t\tset<E>::iterator it2=ss2.lower_bound(e0);\n\t\t\t\tE e4;\n\t\t\t\te4.p1=(*it2).p1;\n\t\t\t\tif(it2!=ss2.begin()){\n\t\t\t\t\tit2--;\n\t\t\t\t\te4.b1=(*it2).b1;\n\t\t\t\t}\n\t\t\t\t//cout<<u0<<\" \"<<leny<<\" r\"<<e1.p1<<\" l\"<<e2.p1<<\" d\"<<e3.p1<<\" u\"<<e4.p1<<endl;\n\t\t\t\tint leny2=e3.p1-e4.p1+1;\n\t\t\t\tif(lenx*leny2>s)continue;\n\t\t\t\tbitset<c257> b4=~(e3.b1&e4.b1);\n\t\t\t\tbitset<c257> b3=e3.b1&b4;\n\t\t\t\tint ans2=all2-(b1&b3).count();\n\t\t\t\t\n\t\t\t\tif(ans2<ans){\n\t\t\t\t\tans=ans2;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 780, "memory_kb": 3256, "score_of_the_acc": -1.0058, "final_rank": 16 }, { "submission_id": "aoj_0706_6943579", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\n\nint main(void){\n\tint i,j,k;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tint H,W,S;\n\tcin >> H >> W >> S;\n\tvector<P> L(257);\n\tREP(i,257) L[i].first=10000;\n\tvector<int> U(257,10000),D(257,0),R(257,0);\n\n\tfor(i=1;i<=H;i++) for(j=1;j<=W;j++){\n\t\tint A;\n\t\tcin >> A;\n\t\tL[A].first=min(L[A].first,j);\n\t\tL[A].second=A;\n\t\tU[A]=min(U[A],i);\n\t\tR[A]=max(R[A],j);\n\t\tD[A]=max(D[A],i);\n\t}\n\n\tsort(L.begin()+1,L.end());\n\n\tint m=0;\n\tfor(i=1;i<=256;i++) if(L[i].first!=10000) m++;\n\n\tint ans=300;\n\tfor(i=1;i<=256;i++){\n\t\tif(U[i]==10000) continue;\n\t\tfor(j=i;j<=256;j++){\n\t\t\tif(U[j]==10000) continue;\n\n\t\t\tint h1=min(U[i],U[j]),h2=max(D[i],D[j]);\n\n\t\t\tvector<int> v,u;\n\t\t\tfor(k=1;k<=m;k++){\n\t \t int x=U[L[k].second],y=D[L[k].second];\n\t \t int r=(h2-h1+1)*(R[L[k].second]-L[k].first+1);\n\t \t if(h1<=x && h2>=y && r<=S){\n\t \t \tv.push_back(L[k].first);\n\t \t \tu.push_back(R[L[k].second]);\n\t \t }\n\t }\n\n\t\t\tsort(u.begin(),u.end());\n\t\t\tint n=v.size();\n\t\t\tint mx=0,c,x=S/(h2-h1+1);\n\t\t\tREP(t,n){\n\t\t\t\tc=upper_bound(u.begin(),u.end(),min(v[t]+x-1,W))-u.begin()-t;\n\t\t\t\tmx=max(mx,c);\n\t\t\t}\n\n\t\t\tans=min(ans,m-mx);\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 3212, "score_of_the_acc": -0.1194, "final_rank": 1 }, { "submission_id": "aoj_0706_6940034", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\n\nint main(void){\n\tint i,j,k;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tint H,W,S;\n\tcin >> H >> W >> S;\n\tvector<P> L(257);\n\tREP(i,257) L[i].first=10000;\n\tvector<int> U(257,10000),D(257,0),R(257,0);\n\n\tfor(i=1;i<=H;i++) for(j=1;j<=W;j++){\n\t\tint A;\n\t\tcin >> A;\n\t\tL[A].first=min(L[A].first,j);\n\t\tL[A].second=A;\n\t\tU[A]=min(U[A],i);\n\t\tR[A]=max(R[A],j);\n\t\tD[A]=max(D[A],i);\n\t}\n\n\tsort(L.begin()+1,L.end());\n\n\tint m=0;\n\tfor(i=1;i<=256;i++) if(L[i].first!=10000) m++;\n\n\tint ans=300;\n\tfor(i=1;i<=256;i++){\n\t\tif(U[i]==10000) continue;\n\t\tfor(j=i;j<=256;j++){\n\t\t\tif(U[j]==10000) continue;\n\n\t\t\tint h1=min(U[i],U[j]),h2=max(D[i],D[j]);\n\n\t\t\tvector<P> v;\n\t\t\tv.push_back(P(-1,0));\n\t\t\tfor(k=1;k<=m;k++){\n\t \t int x=U[L[k].second],y=D[L[k].second];\n\t \t int r=(h2-h1+1)*(R[L[k].second]-L[k].first+1);\n\t \t if(h1<=x && h2>=y && r<=S) v.push_back(P(L[k].first,R[L[k].second]));\n\t }\n\n\t\t\tsort(v.begin(),v.end());\n\n\t\t\tint n=v.size();\n\t\t\tn--;\n\n\t\t\tint s=1,t=1,mx=0,c=0;\n\t\t\twhile(s<=n){\n\n\t\t\t while(t<=n){\n\n\t\t\t \t int a=(h2-h1+1)*(v[t].second-v[s].first+1);\n\t\t \t if(a>S) break;\n\n\t\t \t c++;\n\t\t \t t++;\n\t\t\t }\n\n\t\t\t mx=max(mx,c);\n\n\t\t\t c--;\n\t\t\t s++;\n\t\t\t}\n\n\t\t\tans=min(ans,m-mx);\n\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\n\n\treturn 0;\n}", "accuracy": 0.53125, "time_ms": 170, "memory_kb": 3244, "score_of_the_acc": -0.0938, "final_rank": 19 }, { "submission_id": "aoj_0706_6567543", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tconst int max_num_pixel_values = 257;\n\tint num_pixel_values = 257;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tint pixel_value = -1;\n\n\t\t\tcin >> pixel_value;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tint ww = s / hh;\n\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\t\tint min_y = h - 1;\n\t\t\t\tint max_y = 0;\n\t\t\t\tint c_max_y = -1;\n\t\t\t\tset<int> by_set;\n\t\t\t\tset<int>::const_iterator it_end_y;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\t\t\t\tfor (set<int>::const_iterator it_y = by_set.begin();; it_y++) {\n\t\t\t\t\tint by = *it_y;\n\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\tvector<int> min_x_vec = vector<int>(w, 0);\n\t\t\t\t\tvector<int> max_x_vec = vector<int>(w, 0);\n\t\t\t\t\tint min_x = w - 1;\n\t\t\t\t\tint max_x = 0;\n\t\t\t\t\tint num_removed_pixel_values = 0;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\n\t\t\t\t\tif (it_y == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 3508, "score_of_the_acc": -0.1881, "final_rank": 6 }, { "submission_id": "aoj_0706_6567530", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tint pixel_value = -1;\n\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tint ww = s / hh;\n\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\t\tint min_y = h - 1;\n\t\t\t\tint max_y = 0;\n\t\t\t\tint c_max_y = -1;\n\t\t\t\tset<int> by_set;\n\t\t\t\tset<int>::const_iterator it_end_y;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\t\t\t\tfor (set<int>::const_iterator it_y = by_set.begin();; it_y++) {\n\t\t\t\t\tint by = *it_y;\n\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\tvector<int> min_x_vec = vector<int>(w, 0);\n\t\t\t\t\tvector<int> max_x_vec = vector<int>(w, 0);\n\t\t\t\t\tint min_x = w - 1;\n\t\t\t\t\tint max_x = 0;\n\t\t\t\t\tint num_removed_pixel_values = 0;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\n\t\t\t\t\tif (it_y == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3508, "score_of_the_acc": -0.1732, "final_rank": 5 }, { "submission_id": "aoj_0706_6567491", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tint pixel_value = -1;\n\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tint ww = s / hh;\n\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\t\tint min_y = h - 1;\n\t\t\t\tint max_y = 0;\n\t\t\t\tint c_max_y = -1;\n\t\t\t\tset<int> by_set;\n\t\t\t\tset<int>::const_iterator it_end_y;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\t\t\t\tfor (set<int>::const_iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tint by = *y_it;\n\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\tvector<int> min_x_vec = vector<int>(w, 0);\n\t\t\t\t\tvector<int> max_x_vec = vector<int>(w, 0);\n\t\t\t\t\tint min_x = w - 1;\n\t\t\t\t\tint max_x = 0;\n\t\t\t\t\tint num_removed_pixel_values = 0;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3500, "score_of_the_acc": -0.1721, "final_rank": 4 }, { "submission_id": "aoj_0706_6567484", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tint pixel_value = -1;\n\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\t//if (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tint ww = s / hh;\n\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\t\tint min_y = h - 1;\n\t\t\t\tint max_y = 0;\n\t\t\t\tint c_max_y = -1;\n\t\t\t\tset<int> by_set;\n\t\t\t\tset<int>::const_iterator it_end_y;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::const_iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\t//if (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tint by = *y_it;\n\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\tvector<int> min_x_vec = vector<int>(w, 0);\n\t\t\t\t\tvector<int> max_x_vec = vector<int>(w, 0);\n\t\t\t\t\tint min_x = w - 1;\n\t\t\t\t\tint max_x = 0;\n\t\t\t\t\tint num_removed_pixel_values = 0;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3492, "score_of_the_acc": -0.1711, "final_rank": 3 }, { "submission_id": "aoj_0706_6567482", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint pixel_value = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tint ww = s / hh;\n\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\t\tint min_y = h - 1;\n\t\t\t\tint max_y = 0;\n\t\t\t\tint c_max_y = -1;\n\t\t\t\tset<int> by_set;\n\t\t\t\tset<int>::const_iterator it_end_y;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::const_iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tint by = *y_it;\n\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\tvector<int> min_x_vec = vector<int>(w, 0);\n\t\t\t\t\tvector<int> max_x_vec = vector<int>(w, 0);\n\t\t\t\t\tint min_x = w - 1;\n\t\t\t\t\tint max_x = 0;\n\t\t\t\t\tint num_removed_pixel_values = 0;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 200, "memory_kb": 3476, "score_of_the_acc": -0.169, "final_rank": 2 }, { "submission_id": "aoj_0706_6567476", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint pixel_value = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tset<int> by_set;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::const_iterator it_end_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::const_iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 240, "memory_kb": 3520, "score_of_the_acc": -0.2345, "final_rank": 7 }, { "submission_id": "aoj_0706_6567467", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint pixel_value = -1;\n\tconst int max_num_pixel_values = 256;\n\tint num_pixel_values = 256;\n\tunordered_set<unsigned char> pixel_value_set;\n\tBinInfo pixel_hist[max_num_pixel_values];\n\tvector<const BinInfo*> candidate_bin_vec;\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> pixel_value;\n\t\t\tpixel_value--;\n\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\tc_bin.count++;\n\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\tpixel_value_set.insert(pixel_value);\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tset<int> by_set;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::iterator it_end_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 250, "memory_kb": 3504, "score_of_the_acc": -0.2473, "final_rank": 8 }, { "submission_id": "aoj_0706_6567450", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nconst int max_h = 1000;\nconst int max_w = 1000;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo() : count(0), min_x(max_w), max_x(0), min_y(max_h), max_y(0) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tconst int max_num_pixel_values = 256;\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tBinInfo pixel_hist[max_num_pixel_values];\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tset<int> by_set;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::iterator it_end_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 220, "memory_kb": 4492, "score_of_the_acc": -0.3322, "final_rank": 9 }, { "submission_id": "aoj_0706_6567411", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo(int count, int min_x, int max_x, int min_y, int max_y) : count(count), min_x(min_x), max_x(max_x), min_y(min_y), max_y(max_y) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tconst int max_h = 1000;\n\tconst int max_w = 1000;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tvector<BinInfo> pixel_hist(num_pixel_values, BinInfo(0, w - 1, 0, h - 1, 0));\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tset<int> by_set;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::iterator it_end_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4476, "score_of_the_acc": -0.3451, "final_rank": 11 }, { "submission_id": "aoj_0706_6567363", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo(int count, int min_x, int max_x, int min_y, int max_y) : count(count), min_x(min_x), max_x(max_x), min_y(min_y), max_y(max_y) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tconst int max_h = 1000;\n\tconst int max_w = 1000;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tvector<BinInfo> pixel_hist(num_pixel_values, BinInfo(0, w - 1, 0, h - 1, 0));\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tset<int> by_set;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::iterator it_end_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\tit_end_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == it_end_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4460, "score_of_the_acc": -0.343, "final_rank": 10 }, { "submission_id": "aoj_0706_6567346", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo(int count, int min_x, int max_x, int min_y, int max_y) : count(count), min_x(min_x), max_x(max_x), min_y(min_y), max_y(max_y) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tconst int max_h = 1000;\n\tconst int max_w = 1000;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tvector<BinInfo> pixel_hist(num_pixel_values, BinInfo(0, w - 1, 0, h - 1, 0));\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tvector<const BinInfo*> n_candidate_bin_vec;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tset<int> by_set;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tset<int>::iterator e_idx_y;\n\t\t\tint by = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\te_idx_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\n\t\t\t\t\tn_candidate_bin_vec.clear();\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tn_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == e_idx_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4504, "score_of_the_acc": -0.3487, "final_rank": 13 }, { "submission_id": "aoj_0706_6567338", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\nusing namespace std;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo(int count, int min_x, int max_x, int min_y, int max_y) : count(count), min_x(min_x), max_x(max_x), min_y(min_y), max_y(max_y) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test0.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tconst int max_h = 1000;\n\tconst int max_w = 1000;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tvector<BinInfo> pixel_hist(num_pixel_values, BinInfo(0, w - 1, 0, h - 1, 0));\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_num_removed_pixel_values = 0;\n\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\t\t\tvector<const BinInfo*> n_candidate_bin_vec;\n\t\t\tvector<int> min_x_vec;\n\t\t\tvector<int> max_x_vec;\n\t\t\tset<int> by_set;\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint c_max_y = -1;\n\t\t\tint c_max_x = -1;\n\t\t\tset<int>::iterator e_idx_x;\n\t\t\tset<int>::iterator e_idx_y;\n\t\t\tint bx = -1;\n\t\t\tint by = -1;\n\t\t\tint ex = -1;\n\t\t\tint ey = -1;\n\t\t\tint num_removed_pixel_values = -1;\n\t\t\tint ww = -1;\n\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\n\t\t\t\tww = s / hh;\n\t\t\t\tc_candidate_bin_vec.clear();\n\t\t\t\tmin_y = h - 1;\n\t\t\t\tmax_y = 0;\n\n\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\tby_set.insert(c_bin->min_y);\n\t\t\t\t\t\tby_set.insert(c_bin->max_y);\n\t\t\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tc_max_y = max(min_y, max_y - hh + 1);\n\t\t\t\tby_set.insert(c_max_y);\n\t\t\t\te_idx_y = by_set.find(c_max_y);\n\n\t\t\t\tfor (set<int>::iterator y_it = by_set.begin();; y_it++) {\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tby = *y_it;\n\t\t\t\t\tey = by + hh - 1;\n\n\t\t\t\t\tn_candidate_bin_vec.clear();\n\t\t\t\t\tmin_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmax_x_vec = vector<int>(w, 0);\n\t\t\t\t\tmin_x = w - 1;\n\t\t\t\t\tmax_x = 0;\n\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\tif (by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\tn_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\t\tmin_x_vec[c_bin->min_x]++;\n\t\t\t\t\t\t\tmax_x_vec[c_bin->max_x]++;\n\t\t\t\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\t\t\t}\n\n\t\t\t\t\t}\n\t\t\t\t\tc_max_x = max(min_x, max_x - ww + 1);\n\t\t\t\t\tnum_removed_pixel_values = 0;\n\t\t\t\t\tfor (int lx = min_x, rx = min_x; rx <= max_x; rx++) {\n\t\t\t\t\t\tif (rx - lx >= ww) {\n\t\t\t\t\t\t\tnum_removed_pixel_values -= min_x_vec[lx];\n\t\t\t\t\t\t\tlx++;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tnum_removed_pixel_values += max_x_vec[rx];\n\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t}\n\t\t\t\t\tif (y_it == e_idx_y) { break; }\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 4484, "score_of_the_acc": -0.3461, "final_rank": 12 }, { "submission_id": "aoj_0706_6561993", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <unordered_set>\nusing namespace std;\n\nclass BinInfo {\npublic:\n\tint count;\n\tint min_x;\n\tint max_x;\n\tint min_y;\n\tint max_y;\n\npublic:\n\tBinInfo(int count, int min_x, int max_x, int min_y, int max_y) : count(count), min_x(min_x), max_x(max_x), min_y(min_y), max_y(max_y) {\n\t\treturn;\n\t}\n\n\t~BinInfo() {\n\t\treturn;\n\t}\n};\n\n\nint main() {\n#if READ_FROM_FILE\n\tifstream ifs(\"test1.txt\");\n\tcin.rdbuf(ifs.rdbuf());\n#endif\n\tint h = -1;\n\tint w = -1;\n\tint s = -1;\n\tint buf = -1;\n\tconst int max_h = 1000;\n\tconst int max_w = 1000;\n\tunsigned char image[max_h][max_w];\n\n\tcin >> h >> w >> s;\n\tfor (int y = 0; y < h; y++) {\n\t\tfor (int x = 0; x < w; x++) {\n\t\t\tcin >> buf;\n\t\t\timage[y][x] = buf - 1;\n\t\t}\n\t}\n\n\tif (s >= h * w) {\n\t\tcout << 0 << endl;\n\t}\n\telse {\n\t\tint num_pixel_values = 256;\n\t\tunordered_set<unsigned char> pixel_value_set;\n\t\tvector<BinInfo> pixel_hist(num_pixel_values, BinInfo(0, w - 1, 0, h - 1, 0));\n\t\tvector<const BinInfo*> candidate_bin_vec;\n\n\n\t\tfor (int y = 0; y < h; y++) {\n\t\t\tfor (int x = 0; x < w; x++) {\n\t\t\t\tconst unsigned char& pixel_value = image[y][x];\n\t\t\t\tBinInfo& c_bin = pixel_hist[pixel_value];\n\n\t\t\t\tc_bin.count++;\n\t\t\t\tc_bin.min_x = min(c_bin.min_x, x);\n\t\t\t\tc_bin.max_x = max(c_bin.max_x, x);\n\t\t\t\tc_bin.min_y = min(c_bin.min_y, y);\n\t\t\t\tc_bin.max_y = max(c_bin.max_y, y);\n\t\t\t\tpixel_value_set.insert(pixel_value);\n\t\t\t}\n\t\t}\n\n\t\tnum_pixel_values = (int)pixel_value_set.size();\n\n\t\tfor (const BinInfo& c_bin : pixel_hist) {\n\t\t\tif (0 < c_bin.count && c_bin.count <= s && c_bin.max_x - c_bin.min_x <= s && c_bin.max_y - c_bin.min_y <= s) {\n\t\t\t\tcandidate_bin_vec.emplace_back(&c_bin);\n\t\t\t}\n\t\t}\n\n\t\tif (candidate_bin_vec.empty()) {\n\t\t\tcout << num_pixel_values << endl;\n\t\t}\n\t\telse {\n\t\t\tint min_x = w - 1;\n\t\t\tint max_x = 0;\n\t\t\tint min_y = h - 1;\n\t\t\tint max_y = 0;\n\t\t\tint max_hh = max(2, min(h + 1, s + 1));\n\t\t\tint min_hh = min(max(1, s / w), max_hh - 1);\n\t\t\tint max_ww = min(w, s);\n\t\t\tint max_num_removed_pixel_values = 0;\n\n\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\tmin_x = min(min_x, c_bin->min_x);\n\t\t\t\tmax_x = max(max_x, c_bin->max_x);\n\t\t\t\tmin_y = min(min_y, c_bin->min_y);\n\t\t\t\tmax_y = max(max_y, c_bin->max_y);\n\t\t\t}\n\t\t\t\n\t\t\tfor (int hh = min_hh; hh < max_hh; hh++) {\n\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\tint c_max_y = max(min_y + 1, max_y - hh + 1);\n\t\t\t\t\n\t\t\t\tfor (int ww = max_ww; ww > 0; ww--) {\n\t\t\t\t\tif (ww * hh > s) { continue; }\n\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\tint c_max_x = max(min_x + 1, max_x - ww + 1);\n\t\t\t\t\tvector<const BinInfo*> c_candidate_bin_vec;\n\n\t\t\t\t\tfor (const BinInfo* c_bin : candidate_bin_vec) {\n\t\t\t\t\t\tif (c_bin->max_x - c_bin->min_x <= ww && c_bin->max_y - c_bin->min_y <= hh) {\n\t\t\t\t\t\t\tc_candidate_bin_vec.emplace_back(c_bin);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\n\t\t\t\t\tfor (int by = min_y; by < c_max_y; by++) {\n\t\t\t\t\t\tif (max_num_removed_pixel_values == num_pixel_values - 1) { break; }\n\t\t\t\t\t\tint ey = by + hh - 1;\n\t\t\t\t\t\t\n\t\t\t\t\t\tfor (int bx = min_x; bx < c_max_x; bx++) {\n\t\t\t\t\t\t\tint ex = bx + ww - 1;\n\t\t\t\t\t\t\tint num_removed_pixel_values = 0;\n\t\t\t\t\t\t\t\n\t\t\t\t\t\t\tfor (const BinInfo* c_bin : c_candidate_bin_vec) {\n\t\t\t\t\t\t\t\tif (bx <= c_bin->min_x && c_bin->max_x <= ex && by <= c_bin->min_y && c_bin->max_y <= ey) {\n\t\t\t\t\t\t\t\t\tnum_removed_pixel_values++;\n\t\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t\tmax_num_removed_pixel_values = max(max_num_removed_pixel_values, num_removed_pixel_values);\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tcout << num_pixel_values - max_num_removed_pixel_values << endl;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 0.4583333333333333, "time_ms": 110, "memory_kb": 4432, "score_of_the_acc": -0.1602, "final_rank": 20 }, { "submission_id": "aoj_0706_6317286", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\n#include <tuple>\n#include <cstdint>\n#include <cstdio>\n#include <map>\n#include <cstdint>\n#include <queue>\n#include <set>\n#include <stack>\n#include <deque>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <cctype>\n#include <functional>\n#include <ctime>\n#include <fstream>\n#include <cmath>\n#include <limits>\n#include <chrono>\n#include <numeric>\n#include <type_traits>\n#include <iomanip>\n#include <float.h>\n#include <math.h>\n#include <cassert>\n#include <random>\n#include <complex>\n#pragma warning (disable: 4996)\nusing namespace std;\n\nusing ll = long long;\nusing ld = long double;\n\nlong long modpow(long long a, long long n, long long mod) {\n if (n < 0)return 0;\n long long res = 1;\n while (n > 0) {\n if (n & 1) res = res * a % mod;\n a = a * a % mod;\n n >>= 1;\n }\n return res;\n}\n\nll ll_gcd(ll a, ll b) {\n if (a < b) return ll_gcd(b, a);\n ll r;\n while ((r = a % b)) {\n a = b;\n b = r;\n }\n return b;\n}\n\nstruct UnionFind {\n vector <ll> par;\n vector <ll> siz;\n UnionFind(ll sz_) : par(sz_), siz(sz_, 1LL) {\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n void init(ll sz_) {\n par.resize(sz_);\n siz.assign(sz_, 1LL);\n for (ll i = 0; i < sz_; ++i) par[i] = i;\n }\n ll root(ll x) {\n while (par[x] != x) {\n x = par[x] = par[par[x]];\n }\n return x;\n }\n bool merge(ll x, ll y) {\n x = root(x);\n y = root(y);\n if (x == y) return false;\n if (siz[x] < siz[y]) swap(x, y);\n siz[x] += siz[y];\n par[y] = x;\n return true;\n }\n\n bool issame(ll x, ll y) {\n return root(x) == root(y);\n }\n\n ll size(ll x) {\n return siz[root(x)];\n }\n};\ntemplate< typename T = int >\nstruct Edge {\n int from, to;\n T cost;\n int idx;\n\n Edge() = default;\n\n Edge(int from, int to, T cost = 1, int idx = -1) : from(from), to(to), cost(cost), idx(idx) {}\n\n operator int() const { return to; }\n};\n\ntemplate< typename T = int >\nstruct Graph {\n vector< vector< Edge< T > > > g;\n int es;\n\n Graph() = default;\n\n explicit Graph(int n) : g(n), es(0) {}\n\n size_t size() const {\n return g.size();\n }\n\n void add_directed_edge(int from, int to, T cost = 1) {\n g[from].emplace_back(from, to, cost, es++);\n }\n\n void add_edge(int from, int to, T cost = 1) {\n g[from].emplace_back(from, to, cost, es);\n g[to].emplace_back(to, from, cost, es++);\n }\n\n void read(int M, int padding = -1, bool weighted = false, bool directed = false) {\n for (int i = 0; i < M; i++) {\n int a, b;\n cin >> a >> b;\n a += padding;\n b += padding;\n T c = T(1);\n if (weighted) cin >> c;\n if (directed) add_directed_edge(a, b, c);\n else add_edge(a, b, c);\n }\n }\n\n inline vector< Edge< T > >& operator[](const int& k) {\n return g[k];\n }\n\n inline const vector< Edge< T > >& operator[](const int& k) const {\n return g[k];\n }\n};\n\ntemplate< typename T = int >\nusing Edges = vector< Edge< T > >;\n\nlong long modinv(long long a, long long mod) {\n return modpow(a, mod - 2, mod);\n}\n\ntemplate< typename T >\nstruct ShortestPath {\n vector< T > dist;\n vector< int > from, id;\n};\n\ntemplate< typename T >\nShortestPath< T > dijkstra(const Graph< T >& g, int s) {\n const auto INF = numeric_limits< T >::max();\n vector< T > dist(g.size(), INF);\n vector< int > from(g.size(), -1), id(g.size(), -1);\n using Pi = pair< T, int >;\n priority_queue< Pi, vector< Pi >, greater<> > que;\n dist[s] = 0;\n que.emplace(dist[s], s);\n while (!que.empty()) {\n T cost;\n int idx;\n tie(cost, idx) = que.top();\n que.pop();\n if (dist[idx] < cost) continue;\n for (auto& e : g[idx]) {\n auto next_cost = cost + e.cost;\n if (dist[e.to] <= next_cost) continue;\n dist[e.to] = next_cost;\n from[e.to] = idx;\n id[e.to] = e.idx;\n que.emplace(dist[e.to], e.to);\n }\n }\n return { dist, from, id };\n}\n\nnamespace geometry {\n using Real = double;\n const Real EPS = 1e-8;\n const Real PI = acos(static_cast<Real>(-1));\n\n enum {\n OUT, ON, IN\n };\n\n inline int sign(const Real& r) {\n return r <= -EPS ? -1 : r >= EPS ? 1 : 0;\n }\n\n inline bool equals(const Real& a, const Real& b) {\n return sign(a - b) == 0;\n }\n}\n\nnamespace geometry {\n using Point = complex< Real >;\n\n istream& operator>>(istream& is, Point& p) {\n Real a, b;\n is >> a >> b;\n p = Point(a, b);\n return is;\n }\n\n ostream& operator<<(ostream& os, const Point& p) {\n return os << real(p) << \" \" << imag(p);\n }\n\n Point operator*(const Point& p, const Real& d) {\n return Point(real(p) * d, imag(p) * d);\n }\n\n // rotate point p counterclockwise by theta rad\n Point rotate(Real theta, const Point& p) {\n return Point(cos(theta) * real(p) - sin(theta) * imag(p), sin(theta) * real(p) + cos(theta) * imag(p));\n }\n\n Real cross(const Point& a, const Point& b) {\n return real(a) * imag(b) - imag(a) * real(b);\n }\n\n Real dot(const Point& a, const Point& b) {\n return real(a) * real(b) + imag(a) * imag(b);\n }\n\n bool compare_x(const Point& a, const Point& b) {\n return equals(real(a), real(b)) ? imag(a) < imag(b) : real(a) < real(b);\n }\n\n bool compare_y(const Point& a, const Point& b) {\n return equals(imag(a), imag(b)) ? real(a) < real(b) : imag(a) < imag(b);\n }\n\n using Points = vector< Point >;\n}\n\nnamespace geometry {\n using Polygon = vector< Point >;\n using Polygons = vector< Polygon >;\n}\n\nint main() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int h, w, s;\n cin >> h >> w >> s;\n vector<vector<int>> z(h,vector<int>(w));\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n cin >> z[i][j];\n z[i][j]--;\n }\n }\n vector<int> a(256,5000);\n vector<int> b(256,-1);\n vector<int> c(256,5000);\n vector<int> d(256,-1);\n for (int i = 0; i < h; i++) {\n for (int j = 0; j < w; j++) {\n a[z[i][j]] = min(a[z[i][j]], i);\n b[z[i][j]] = max(b[z[i][j]], i);\n c[z[i][j]] = min(c[z[i][j]], j);\n d[z[i][j]] = max(d[z[i][j]], j);\n }\n }\n vector<int> e;\n vector<int> f;\n int now = h;\n int nows = s / h;\n e.push_back(now);\n f.push_back(nows);\n for (int i = h-1; i > 0; i--) {\n now = i;\n int k = s / i;\n if (k != nows&&nows<=w) {\n nows = k;\n e.push_back(now);\n f.push_back(min(nows,w));\n }\n }\n int ans = 256;\n for (int i = 0; i < e.size(); i++) {\n vector<vector<int>> zz(h - e[i] + 2, vector<int>(w - f[i] + 2));\n for (int j = 0; j < 256; j++) {\n if (a[j] == 5000)continue;\n zz[0][0]++;\n zz[min(a[j] + 1, h - e[i] + 1)][min(c[j] + 1, w - f[i] + 1)]--;\n zz[max(0, min(a[j] + 1, b[j] - e[i] + 1))][min(c[j] + 1, w - f[i] + 1)]++;\n zz[min(a[j] + 1, h - e[i] + 1)][max(0, min(c[j] + 1, d[j] - f[i] + 1))]++;\n zz[max(0, min(a[j] + 1, b[j] - e[i] + 1))][max(0, min(c[j] + 1, d[j] - f[i] + 1))] --;\n }\n for (int j = 0; j < h - e[i]; j++) {\n for (int l = 0; l < w - f[i]+1; l++) {\n zz[j + 1][l] += zz[j][l];\n }\n }\n for (int j = 0; j < h - e[i]+1; j++) {\n for (int l = 0; l < w - f[i]; l++) {\n zz[j][l + 1] += zz[j][l];\n }\n }\n for (int j = 0; j < h - e[i]+1; j++) {\n for (int l = 0; l < w - f[i]+1; l++) {\n ans = min(ans, zz[j][l]);\n }\n }\n }\n cout << ans << endl;\n}", "accuracy": 1, "time_ms": 450, "memory_kb": 10828, "score_of_the_acc": -1.5075, "final_rank": 18 }, { "submission_id": "aoj_0706_6303786", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nint main() {\n\tint height, width, s; std::cin >> height >> width >> s;\n\tstd::vector<std::vector<int>> picture(height, std::vector<int>(width));\n\tfor (auto& line : picture) {\n\t\tfor (auto& pixel : line) {\n\t\t\tstd::cin >> pixel; --pixel;\n\t\t}\n\t}\n\tstd::vector<int> top(256, height), bottom(256, -1), left(256, width), right(256, -1);\n\tstd::vector<bool> appear(256);\n\tfor (auto i = 0; i < height; ++i) {\n\t\tfor (auto j = 0; j < width; ++j) {\n\t\t\tconst auto pixel = picture[i][j];\n\t\t\tappear[pixel] = true;\n\t\t\ttop[pixel] = std::min(top[pixel], i);\n\t\t\tbottom[pixel] = std::max(bottom[pixel], i);\n\t\t\tleft[pixel] = std::min(left[pixel], j);\n\t\t\tright[pixel] = std::max(right[pixel], j);\n\t\t}\n\t}\n\tint max_remove{ 0 };\n\tfor (auto i = 0; i < 256; ++i) {\n\t\tif (!appear[i]) continue;\n\t\tfor (auto j = i; j < 256; ++j) {\n\t\t\tif (!appear[j]) continue;\n\t\t\tconst auto u = std::min(top[i], top[j]);\n\t\t\tconst auto d = std::max(bottom[i], bottom[j]);\n\t\t\tconst auto h = d - u + 1;\n\t\t\tconst auto w = s / h;\n\t\t\tif (w == 0) continue;\n\t\t\tstd::priority_queue<int, std::vector<int>, std::greater<>> queue;\n\t\t\tstd::vector<std::pair<int, int>> ranges;\n\t\t\tfor (auto k = 0; k < 256; ++k) {\n\t\t\t\tif (!appear[k]) continue;\n\t\t\t\tif (top[k] < u || d < bottom[k]) continue;\n\t\t\t\tranges.emplace_back(left[k], right[k]);\n\t\t\t}\n\t\t\tstd::sort(ranges.begin(), ranges.end(), [](const auto a, const auto b) {return a.second < b.second; });\n\t\t\tfor (const auto [l, r] : ranges) {\n\t\t\t\tqueue.push(l);\n\t\t\t\twhile (!queue.empty() && queue.top() + w <= r) {\n\t\t\t\t\tqueue.pop();\n\t\t\t\t}\n\t\t\t\tmax_remove = std::max<int>(max_remove, queue.size());\n\t\t\t}\n\t\t}\n\t}\n\tconst auto result = std::count(appear.begin(), appear.end(), true) - max_remove;\n\tstd::cout << result << '\\n';\n}", "accuracy": 1, "time_ms": 290, "memory_kb": 7388, "score_of_the_acc": -0.817, "final_rank": 14 }, { "submission_id": "aoj_0706_6264394", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(h,w,s);\n vector2d(int,A,h,w);\n in(A);\n vector<array<int,4>> t(256,array<int,4>({INF,INF,-1,-1}));\n rep(y,h){\n rep(x,w){\n A[y][x]--;\n chmin(t[A[y][x]][0],y);\n chmin(t[A[y][x]][1],x);\n chmax(t[A[y][x]][2],y);\n chmax(t[A[y][x]][3],x);\n }\n }\n int ans=INF,tot=0;\n rep(i,256)tot+=(t[i][0]!=INF);\n ans=tot;\n auto f=[&](int ly,int ry){\n if((ry-ly+1)>s)return;\n int cnt=0,len=s/(ry-ly+1);\n vector<vector<int>> c(1000);\n vector<int> c2(256);\n for(int k=0;k<256;k++){\n if(t[k][0]==INF)continue;\n if(ly<=t[k][0]&&t[k][2]<=ry){\n c[t[k][1]].push_back(k);\n c[t[k][3]].push_back(k);\n }\n }\n for(int l=0,r=0;l<1000;l++){\n while(r<1000&&r<l+len){\n for(auto v:c[r]){\n c2[v]++;\n if(c2[v]==2)cnt++;\n }\n r++;\n }\n chmin(ans,tot-cnt);\n for(auto v:c[l]){\n if(c2[v]==2)cnt--;\n c2[v]--;\n }\n }\n };\n for(int i=0;i<256;i++){\n if(t[i][0]==INF)continue;\n for(int j=i;j<256;j++){\n if(t[j][0]==INF)continue;\n int ly=min(t[i][0],t[j][0]),ry=max(t[i][2],t[j][2]);\n f(ly,ry);\n }\n }\n out(ans);\n}", "accuracy": 1, "time_ms": 690, "memory_kb": 7532, "score_of_the_acc": -1.4329, "final_rank": 17 } ]
aoj_0704_cpp
展覧会 2 JOI 美術館には,東西方向にまっすぐに伸びる廊下に N 枚の絵が飾られており, 1 から N までの番号が付けられている.絵 i ( 1 ≦ i ≦ N ) は廊下の西端から X i メートルの位置に飾られており,その価値は V i である. この美術館では明日から「エゴイ展」が開催される予定であり,非常に多くの来客が見込まれている.「エゴイ展」では M 枚の絵を展示する予定である. 2 つの絵が近い位置に展示されていると見づらいので,以下の条件を満たすように N-M 枚の絵を取り外し,廊下に M 枚の絵だけを残すことにした. どの 2 つの絵についても,位置が D メートル以上離れているようにする. 展示されている M 枚の絵の価値の最小値を,「エゴイ展」の 華やかさ とする.あなたは,廊下に残す M 枚の絵をうまく選ぶことで,「エゴイ展」の華やかさをできるだけ大きくしたい. N 枚の絵の情報と廊下に残す絵の枚数が与えられたとき,条件を満たすような絵の残し方が存在するか判定し,もし存在する場合は,「エゴイ展」の華やかさの最大値を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 100000 . 1 ≦ M ≦ N . 1 ≦ D ≦ 1000000000 . 1 ≦ X i ≦ 1000000000 ( 1 ≦ i ≦ N ). X i ≠ X j ( 1 ≦ i < j ≦ N ). 1 ≦ V i ≦ 1000000000 ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N M D X 1 V 1 X 2 V 2 : X N V N 出力 条件を満たすような絵の残し方が存在しない場合,標準出力に -1 を 1 行で出力せよ. 条件を満たすような絵の残し方が存在する場合,標準出力に,「エゴイ展」の華やかさの最大値を 1 行で出力せよ. 入出力例 入力例 1 3 1 34 10 250 30 200 50 500 出力例 1 500 絵 3 のみを残した場合,「エゴイ展」の華やかさは 500 となる.華やかさを 500 より大きくすることはできないため, 500 を出力する. 入力例 2 4 4 10 21 160 32 270 11 115 44 205 出力例 2 115 すべての絵を残すことができ,「エゴイ展」の華やかさは 115 となる. 入力例 3 4 4 14 21 160 32 270 11 115 44 205 出力例 3 -1 どの 2 つの絵の間も 14 メートル以上離れているように絵を残すことはできない.したがって, -1 を出力する. 入力例 4 6 3 4 4 2 5 2 2 1 9 2 1 1 7 2 出力例 4 1 入力例 5 15 6 129 185 2821 683 3312 101 3406 485 2120 671 1992 869 2555 872 3123 237 2970 351 2374 996 2090 729 2686 375 2219 820 3085 511 3217 924 4229 出力例 5 2219 情報オリンピック日本委員会 作 『日本情報オリンピック 第1回 女性部門』
[ { "submission_id": "aoj_0704_9609178", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n \n ll N,M,D;\n cin>>N>>M>>D;\n\n vector<pair<ll,ll>> P(N);\n rep(i,N)cin>>P[i].first>>P[i].second;\n sort(all(P));\n ll L=-1,R=1e18;\n while(R-L>1){\n ll mid=(R+L)/2,cnt=0,x=-1e18;\n rep(i,N){\n if(P[i].second>=mid){\n if(P[i].first>=x+D){\n cnt++;\n x=P[i].first;\n }\n }\n }\n (cnt>=M?L:R)=mid;\n }\n cout<<L<<endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4676, "score_of_the_acc": -0.1548, "final_rank": 10 }, { "submission_id": "aoj_0704_9465754", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nstruct Painting {\n int x, v;\n};\n\n// 自定義比較函數\nbool compare(const Painting& a, const Painting& b) {\n return a.x < b.x;\n}\n\nbool can_select_paintings(const vector<Painting>& paintings, int M, int D, int min_value) {\n int count = 0;\n int last_position = -D - 1;\n \n for (size_t i = 0; i < paintings.size(); ++i) {\n if (paintings[i].v >= min_value && paintings[i].x - last_position >= D) {\n count++;\n last_position = paintings[i].x;\n }\n if (count >= M) {\n return true;\n }\n }\n return false;\n}\n\nint main() {\n int N, M, D;\n cin >> N >> M >> D;\n\n vector<Painting> paintings(N);\n for (int i = 0; i < N; ++i) {\n cin >> paintings[i].x >> paintings[i].v;\n }\n\n // 根據位置進行排序\n sort(paintings.begin(), paintings.end(), compare);\n\n // 二分搜索\n int left = 1, right = 1000000000;\n int result = -1;\n \n while (left <= right) {\n int mid = left + (right - left) / 2;\n if (can_select_paintings(paintings, M, D, mid)) {\n result = mid;\n left = mid + 1;\n } else {\n right = mid - 1;\n }\n }\n\n cout << result << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 3600, "score_of_the_acc": -0.0538, "final_rank": 2 }, { "submission_id": "aoj_0704_8990669", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, M, D, X, V;\n cin >> N >> M >> D;\n vc<pi> XV(N);\n rep(i, N) {\n cin >> X >> V;\n XV[i] = mp(X, V);\n }\n sort(all(XV));\n auto check = [&](ll v) -> bool {\n if (v <= 0) return true;\n ll last = -inf;\n ll cnt = 0;\n rep(i, N) {\n if ((XV[i].fi-last) < D) continue;\n if (XV[i].se < v) continue;\n last = XV[i].fi;\n cnt++;\n }\n return cnt >= M;\n };\n ll ans = -1;\n ll left=1, right=(1<<30);\n rep(33) {\n ll m = (left+right) / 2;\n if (check(m)) {\n chmax(ans, m);\n left = m;\n } else {\n right = m;\n }\n }\n print(ans);\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4668, "score_of_the_acc": -0.1538, "final_rank": 9 }, { "submission_id": "aoj_0704_8753546", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/algorithm/compress.hpp\"\n#include <algorithm>\n#include <iterator>\n#include <vector>\n\n/**\n * @brief 座標圧縮\n *\n * @tparam T 要素の型\n */\ntemplate <class T>\nstruct coordinate_compression {\n coordinate_compression() = default;\n coordinate_compression(const std::vector<T> &_data) : data(_data) { build(); }\n\n const T &operator[](int i) const { return data[i]; }\n T &operator[](int i) { return data[i]; }\n\n void add(T x) { data.emplace_back(x); }\n\n void build() {\n std::sort(std::begin(data), std::end(data));\n data.erase(std::unique(std::begin(data), std::end(data)), std::end(data));\n }\n\n bool exists(T x) const {\n auto it = std::lower_bound(std::begin(data), std::end(data), x);\n return it != std::end(data) && *it == x;\n }\n\n int get(T x) const {\n auto it = std::lower_bound(std::begin(data), std::end(data), x);\n return std::distance(std::begin(data), it);\n }\n\n int size() const { return std::size(data); }\n\n private:\n std::vector<T> data;\n};\n\n/**\n * @brief 座標圧縮\n *\n * @tparam T 要素の型\n * @param v 配列\n * @return std::vector<T>\n */\ntemplate <class T>\nstd::vector<T> compress(const std::vector<T> &v) {\n coordinate_compression cps(v);\n std::vector<T> res;\n res.reserve(std::size(v));\n for (auto &&x : v) res.emplace_back(cps.get(x));\n return res;\n}\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n, m, d;\n cin >> n >> m >> d;\n vector<pair<int, int>> a(n);\n cin >> a;\n sort(all(a));\n\n vector<int> v(n);\n rep (i, n) v[i] = a[i].second;\n coordinate_compression cps(v);\n\n int l = -1, r = cps.size();\n while (r - l > 1) {\n int mid = (l + r) / 2;\n int x = -Inf;\n int s = 0;\n rep (i, n) {\n if (x + d <= a[i].first && cps[mid] <= a[i].second) {\n ++s;\n x = a[i].first;\n }\n }\n if (s >= m)\n l = mid;\n else\n r = mid;\n }\n co(l == -1 ? -1 : cps[l]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4668, "score_of_the_acc": -0.143, "final_rank": 7 }, { "submission_id": "aoj_0704_8307019", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long INF = 1LL<<40;\n\nint main() {\n long long N, M, D;\n cin >> N >> M >> D;\n vector<long long> X(N), V(N);\n for (int i = 0; i < N; ++i) cin >> X[i] >> V[i];\n\n // 一直線上に左から順に並び替える (ここでは id を並び替える)\n vector<int> ids(N);\n iota(ids.begin(), ids.end(), 0);\n sort(ids.begin(), ids.end(), [&](int i, int j) {\n return X[i] < X[j];\n });\n\n // 二分探索\n long long low = -1, high = INF;\n while (high - low > 1) {\n long long x = (low + high) / 2;\n\n int con = 0; // 選んだ枚数\n long long prev = -INF; // 最後に選んだ絵の位置\n for (auto id : ids) {\n if (X[id] - prev >= D && V[id] >= x) {\n ++con; \n prev = X[id];\n }\n }\n if (con >= M) low = x;\n else high = x;\n }\n cout << low << endl;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4940, "score_of_the_acc": -0.2332, "final_rank": 13 }, { "submission_id": "aoj_0704_8294808", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int, int> Pi;\nint main(){\n int n, m, d, x, v;\n vector<int> vec;\n vector<Pi> p;\n cin >> n >> m >> d;\n for(int i=0;i<n;i++){\n cin >> x >> v;\n vec.push_back(v);\n p.push_back(Pi(x, v));\n }\n vec.push_back(-1);\n sort(vec.begin(), vec.end());\n sort(p.begin(), p.end());\n int mid, l=0, r=vec.size()-1;\n while(l<r){\n int sum=0, id=0;\n mid=(l+r+1)/2;\n for(int i=0;i<n;i++){\n if(p[i].second>=vec[mid] && (sum==0 || p[i].first-p[id].first>=d)){\n id = i;\n sum++;\n }\n }\n if(sum>=m) l = mid;\n else r = mid-1;\n }\n cout << vec[l] << endl;\n return(0);\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4280, "score_of_the_acc": -0.1448, "final_rank": 8 }, { "submission_id": "aoj_0704_6954656", "code_snippet": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<int(n);i++)\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nint N,M,D;\nvector<P> d;\nbool check(int x){\n\tint j=-1,k;\n\tfor(k=1;k<=N;k++){\n\t\tif(d[k].second>=x){\n\t\t\tj=k;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif(j==-1) return false;\n\n\tll c=1;\n\tfor(k=j+1;k<=N;k++){\n\t\tif(d[k].second>=x && d[k].first-d[j].first>=D){\n\t\t\tc++;\n\t\t\tj=k;\n\t\t}\n\t}\n\n\tif(c>=M) return true;\n\telse return false;\n}\n\nint main(void){\n\tint i;\n\n\tcin.tie(0); ios_base::sync_with_stdio(false);\n\n\tcin >> N >> M >> D;\n\n\tvector<int> v(N+1,-1);\n\td.push_back(P(0,0));\n\tfor(i=1;i<=N;i++){\n\t\tint x,y;\n\t\tcin >> x >> y;\n\t\td.push_back(P(x,y));\n\t\tv[i]=y;\n\t}\n\n\tsort(d.begin(),d.end());\n\tsort(v.begin(),v.end());\n\n\tint ok=0,ng=N+1;\n\twhile(ng-ok>1){\n\t\tint m=(ok+ng)/2;\n\t\tif(check(v[m])) ok=m;\n\t\telse ng=m;\n\t}\n\n\n\tcout << v[ok] << endl;\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 4492, "score_of_the_acc": -0.1194, "final_rank": 6 }, { "submission_id": "aoj_0704_6847847", "code_snippet": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n#include<string>\n#include<iomanip>\n#include<numeric>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<set>\n#include<map>\n#include<random>\n#include<bitset>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\nconst int mod=998244353;\nconst int dx[]={1,0,0,-1},dy[]={0,1,-1,0};\nint main(){\n\tstatic int n,m,d,x[100000],v[100000];\n\tcin>>n>>m>>d;\n\tfor(int i=0;i<n;i++)\n\t\tcin>>x[i]>>v[i];\n\tstatic pair<int,int>xv[100000];\n\tfor(int i=0;i<n;i++)\n\t\txv[i]={x[i],v[i]};\n\tsort(xv,xv+n);\n\tfor(int i=0;i<n;i++)\n\t\ttie(x[i],v[i])=xv[i];\n\tint ok=-1,ng=1e9+7;\n\twhile(ng-ok>1){\n\t\tint mid=(ng+ok)/2;\n\t\tint tmp=0,cnt=0;\n\t\tfor(int i=0;i<n;i++){\n\t\t\tif(mid<=v[i]&&tmp<=x[i]){\n\t\t\t\ttmp=x[i]+d;\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t\t(cnt>=m?ok:ng)=mid;\n\t}\n\tcout<<ok<<endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4984, "score_of_the_acc": -0.2176, "final_rank": 12 }, { "submission_id": "aoj_0704_6660438", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nbool f(const vector<pair<int, int>>& XY, int V, int D, int M)\n{\n\tfor (int i = 0, j = 0, X = -1; j < (int) XY.size(); ++j) {\n\t\tif (XY[j].second < V) continue;\n\t\tif (X >= 0 && XY[j].first - X < D) continue;\n\t\tX = XY[j].first;\n\t\tif (++i >= M) return true;\n\t}\n\treturn false;\n}\n\nint main()\n{\n\tint N, M, D, V = 0; cin >> N >> M >> D;\n\tvector<pair<int, int>> XV(N); for (auto& [X, V] : XV) cin >> X >> V;\n\tsort(XV.begin(), XV.end());\n\tfor (int d = 1 << 29; d > 0; d /= 2) if (f(XV, V + d, D, M)) V += d;\n\tcout << (V == 0 ? -1 : V) << endl;\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 3896, "score_of_the_acc": -0.0826, "final_rank": 5 }, { "submission_id": "aoj_0704_6410305", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n ll n,m,d; cin >> n >> m >> d;\n vector<pair<int,int>> v(n);\n for(int i=0;i<n;i++){\n cin >> v[i].first >> v[i].second;\n }\n sort(v.begin(), v.end());\n ll L=-1,R=2e9;\n while(R-L>1){\n ll mid=(L+R)/2;\n ll last=-2e9;\n int cnt=0;\n for(int i=0;i<n;i++){\n if(v[i].second>=mid and v[i].first>=last+d){\n last=v[i].first;\n cnt++;\n }\n }\n if(cnt>=m){\n L=mid;\n }\n else{\n R=mid;\n }\n }\n cout << L << endl;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 3892, "score_of_the_acc": -0.0391, "final_rank": 1 }, { "submission_id": "aoj_0704_6373734", "code_snippet": "#define READ_FROM_FILE 0\n\n#if READ_FROM_FILE\n#include <fstream>\n#endif\n\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n\nusing namespace std;\ntypedef pair<int, int> pii;\ntypedef pair<pii, int> piii;\n\nconst int inf = 1000000001;\nint n = -1;\nint d = -1;\nvector<pii> xv_vec;\nvector<int> dif_vec;\nmap<piii, int> mem_map;\n\n\nint solve(int i, int j, int m) {\n piii mem_key = piii(pii(i, j), m);\n int num_v = 0;\n int min_dif = inf;\n int max_min_v = -1;\n int max_m0 = 0;\n int min_v = inf;\n int min_v0 = inf;\n int min_v1 = inf;\n int k1 = 0;\n\n if (mem_map.count(mem_key) > 0) {\n return mem_map[mem_key];\n }\n \n num_v = j - i;\n if (num_v < m) {\n return -1;\n }\n\n if (m == 1) {\n int max_v = 0;\n\n for (int k = i; k < j; k++) {\n max_v = max(max_v, xv_vec[k].second);\n }\n mem_map[mem_key] = max_v;\n return max_v;\n }\n\n if (num_v == 1) {\n return -1;\n }\n\n if (num_v == 2) {\n if (m == 2) {\n if (dif_vec[i] >= d) {\n mem_map[mem_key] = min(xv_vec[i].second, xv_vec[i + 1].second);\n return mem_map[mem_key];\n }\n else {\n return -1;\n }\n }\n else {\n return -1;\n }\n }\n\n for (int k = i; k < j - 1; k++) {\n min_dif = min(min_dif, dif_vec[k]);\n }\n\n if (num_v == m) {\n if (min_dif >= d) {\n int min_v = inf;\n\n for (int k = i; k < j; k++) {\n min_v = min(min_v, xv_vec[k].second);\n mem_map[mem_key] = min_v;\n return min_v;\n }\n }\n else {\n return -1;\n }\n }\n \n for (int k0 = i + 1; k0 < j; k0++) {\n vector<int> m0_vec;\n\n max_m0 = min(m, min(k0 - i, j - k0) + 1);\n for (int l = 0; l < max_m0; l++) {\n m0_vec.push_back(l);\n }\n\n for (int& m0 : m0_vec) {\n min_v0 = solve(i, k0, m0);\n k1 = k0;\n min_v1 = -1;\n\n while (k1 < j && xv_vec[k1].first - xv_vec[k0 - 1].first < d) {\n k1++;\n }\n\n if (k1 < j) {\n min_v1 = solve(k1, j, m - m0);\n }\n\n if (min_v0 >= 0 && min_v1 >= 0) {\n min_v = min(min_v0, min_v1);\n }\n else {\n continue;\n }\n \n max_min_v = max(max_min_v, min_v);\n }\n }\n \n mem_map[mem_key] = max_min_v;\n return max_min_v;\n}\n\nint main(int argc, char **argv){\n#if READ_FROM_FILE\n std::ifstream ifs(\"test1.txt\");\n cin.rdbuf(ifs.rdbuf());\n#endif\n int m = -1;\n int max_v = 0;\n int x = 0;\n int v = 0;\n int dif = 0;\n \n cin >> n >> m >> d;\n\n for (int i = 0; i < n; i++) {\n cin >> x >> v;\n max_v = max(max_v, v);\n xv_vec.push_back(pii(x, v));\n }\n\n sort(xv_vec.begin(), xv_vec.end());\n for (int i = 1; i < n; i++) {\n dif = xv_vec[i].first - xv_vec[i - 1].first;\n dif_vec.push_back(dif);\n }\n\n if (m == 1) {\n cout << max_v << endl;\n }\n else {\n int total_d = xv_vec[n - 1].first - xv_vec[0].first;\n\n if (total_d < (m - 1) * d) {\n cout << -1 << endl;\n }\n else {\n cout << solve(0, n, m) << endl;\n }\n }\n\n return 0;\n}", "accuracy": 0.11940298507462686, "time_ms": 50, "memory_kb": 4684, "score_of_the_acc": -0.1774, "final_rank": 16 }, { "submission_id": "aoj_0704_6303534", "code_snippet": "#include <iostream>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <vector>\n#include <numeric>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <random>\n#include <array>\n#include <climits>\n#include <map>\n#include <cassert>\n#include <stack>\n#include <iomanip>\n#include <cfloat>\n#include <fstream>\n\nint main() {\n\tint n, m, d; std::cin >> n >> m >> d;\n\tstd::vector<std::pair<int, int>> picture(n);\n\tfor (auto& [x, v] : picture) {\n\t\tstd::cin >> x >> v;\n\t}\n\tstd::sort(picture.begin(), picture.end(), [](const auto a, const auto b) {return a.first < b.first; });\n\tint min = 0;\n\tint max = 1000000001;\n\twhile (min < max) {\n\t\tconst auto mid = (min + max) >> 1;\n\t\tint use{ 0 };\n\t\tint last{ -d };\n\t\tfor (const auto [x, v] : picture) {\n\t\t\tif (mid <= v && last + d <= x) {\n\t\t\t\t++use;\n\t\t\t\tlast = x;\n\t\t\t}\n\t\t}\n\t\tif (use >= m) {\n\t\t\tmin = mid + 1;\n\t\t}\n\t\telse {\n\t\t\tmax = mid;\n\t\t}\n\t}\n\tstd::cout << max - 1 << '\\n';\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 3900, "score_of_the_acc": -0.0724, "final_rank": 4 }, { "submission_id": "aoj_0704_6277907", "code_snippet": "#include<iostream>\n#include<algorithm> \n#include<bitset>\n#include<cassert>\n#include<cctype>\n#include<cmath>\n#include<ctime>\n#include<fstream>\n#include<functional>\n#include<map>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<stack>\n#include<stdio.h>\n#include<string>\n#include<tuple>\n#include<vector>\n//#include<bits/stdc++.h>\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#define rep(i, x) for(ll i = 0; i < x; i++)\n#define rep2(i, x) for(ll i = 1; i <= x; i++)\n#define rep3(i, x, y) for(ll i = x; i < y; i++)\n#define rep4(i, x) for(ll i = x - 1; i >= 0; i--)\n#define all(a) (a).begin(),(a).end()\n#define rall(a) (a).rbegin(),(a).rend()\n#define puts(x) cout << (x) << \"\\n\"\nusing ll = long long;\nusing ld = long double;\nusing namespace std;\nconst ll INF = 1000000000000000000;\nconst int intINF = 1000000000;\nconst ll mod = 1000000007;\nconst ll MOD = 998244353;\nconst ld pi = 3.141592653589793238;\n//const ld EPS = 1e-9;\ntypedef string::const_iterator State;\nclass ParseError {};\n\nbool isprime(int p) {\n\tif (p == 1) return false;\n\tfor (int i = 2; i < p; i++) {\n\t\tif (p % i == 0) return false;\n\t}\n\treturn true;\n}\nll gcd(ll a, ll b) {\n\tif (b == 0) { return a; }\n\treturn gcd(b, a % b);\n}\n//ax + by = cが整数解をもつための必要十分条件は c が gcd(a,b) で割り切れること。\n// 返り値: a と b の最大公約数\n// ax + by = gcd(a, b) を満たす (x, y) が格納される\n//main関数内に extGCD(a, b, x, y); でx, yに解が格納\nll extGCD(ll a, ll b, ll& x, ll& y) {\n\tif (b == 0) {\n\t\tx = 1;\n\t\ty = 0;\n\t\treturn a;\n\t}\n\tll d = extGCD(b, a % b, y, x);\n\ty -= a / b * x;\n\treturn d;\n}\nll lcm(ll a, ll b) {\n\treturn a / gcd(a, b) * b;\n}\nll keta(ll n) {\n\tll res = 0;\n\twhile (n >= 1) {\n\t\tres++;\n\t\t//res += n % 10;\n\n\t\tn /= 10;\n\t}\n\treturn res;\n}\nll modpow(ll x, ll y, ll m) {\n\tll res = 1;\n\twhile (y) {\n\t\tif (y % 2) { res *= x; res %= m; }\n\t\tx = x * x % m; y /= 2;\n\t}\n\treturn res;\n}\n\nconst int nCkMAX = 500000;\nll fac[nCkMAX], finv[nCkMAX], inv[nCkMAX];//n!、1/n!、1/n\n// テーブルを作る前処理\nvoid nCkinit(ll m) {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < nCkMAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % m;\n\t\tinv[i] = m - inv[m % i] * (m / i) % m;\n\t\tfinv[i] = finv[i - 1] * inv[i] % m;\n\t}\n}\n// 二項係数計算\nll nCk(ll n, ll k, ll m) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % m) % m;\n}\n//nが大きくてkが小さい時\n//nCkMAXはk+2まででOK\nll nCk2(ll n, ll k, ll m) {\n\tll res = 1;\n\tfor (int i = n - k + 1; i <= n; i++) {\n\t\tres *= i; res %= m;\n\t}\n\tres = res * finv[k] % m;\n\treturn res;\n}\n\n//xorshift from 「ビット演算 (bit 演算) の使い方を総特集! 」\n//1~6まで出したいときは\n//xorshift() % 6 + 1\nunsigned int xorshift() {\n\tstatic unsigned int tx = 123456789, ty = 362436069, tz = 521288629, tw = 88675123;\n\tunsigned int tt = (tx ^ (tx << 11));\n\ttx = ty; ty = tz; tz = tw;\n\treturn (tw = (tw ^ (tw >> 19)) ^ (tt ^ (tt >> 8)));\n}\n\n\n//printf(\"%.10f\\n\", n);\ntypedef pair <ll, ll> P;\ntypedef pair <ld, ll> pp;\nll dx[4] = { 1, 0, -1, 0 }, dy[4] = { 0, 1, 0, -1 };\n\n\nvector<ll> spf;\nvoid smallest_prime_factors(ll n) {\n\tspf.resize(n + 1); spf[1] = 1;\n\tfor (int i = 2; i <= n; i++) {\n\t\tif (!spf[i]) {\n\t\t\tfor (int j = i; j < n; j += i) { spf[j] = i; }\n\t\t}\n\t}\n}\nstd::map<int, int> high_speed_prime_factor(int n) {\n\tstd::map<int, int> res;\n\twhile (n != 1) {\n\t\tres[spf[n]]++;\n\t\tn /= spf[n];\n\t}\n\treturn res;\n}\n\n////////////////////////////////struct\nstruct edge {\n\tll to; ld cost;\n};\nstruct Point {\n\tll x, y;\n};\nbool operator<(const Point& a1, const Point& a2) {\n\tif (a1.x < a2.x) return true;\n\tif (a1.x > a2.x) return false;\n\tif (a1.y < a2.y) return true;\n\treturn false;\n}\nstruct status {\n\tll x;\n\tll v;\n\n\t//bool operator<(const status& rhs) const { return c < rhs.c; };\n\t//bool operator>(const status& rhs) const { return c > rhs.c; };\n\tbool operator<(const status& rhs) const { return x < rhs.x; };\n\tbool operator>(const status& rhs) const { return x > rhs.x; };\n};\nvoid yesno(bool ok) {\n\tif (ok) { cout << \"Yes\\n\"; }\n\telse { cout << \"No\\n\"; }\n}\n//多倍長整数演算\n//nCkを求めるときにnCkMAXとnCkinit\n\n\n\nint main() {\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\t//cout << fixed << setprecision(15);\n\n\tll n, m, d; cin >> n >> m >> d;\n\tvector<status> pn(n);//painting\n\trep(i, n) {\n\t\tcin >> pn[i].x >> pn[i].v;\n\t}\n\tsort(all(pn));\n\n\t//価値の最小値の最大化\n\tll ok = -1, ng = 1000000001, mid = (ok + ng) / 2;\n\twhile (ng - ok > 1) {\n\t\tll cnt = 0, mae = 0 - d - 1;\n\t\trep(i, n) {\n\t\t\tif (pn[i].x - mae >= d && pn[i].v >= mid) {\n\t\t\t\tcnt++; mae = pn[i].x;\n\t\t\t}\n\t\t}\n\t\tif (cnt >= m) { ok = mid; }\n\t\telse { ng = mid; }\n\t\tmid = (ok + ng) / 2;\n\t}\n\tcout << ok << endl;\n\treturn 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 4676, "score_of_the_acc": -0.1548, "final_rank": 10 }, { "submission_id": "aoj_0704_6264392", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,d);\n vector<array<int,2>> x(n);\n rep(i,n)in(x[i][0],x[i][1]);\n in(x);\n sort(all(x));\n int l=0,r=INF,mid;\n while(l<r){\n mid=(l+r)/2;\n int pre=-INF,cnt=0;\n rep(j,n){\n if(x[j][0]>=pre+d&&x[j][1]>=mid){\n cnt++;\n pre=x[j][0];\n }\n }\n if(cnt>=m)l=mid+1;\n else r=mid;\n }\n out(--l);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 3936, "score_of_the_acc": -0.0557, "final_rank": 3 }, { "submission_id": "aoj_0704_6156635", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 200005\n\nstruct Info{\n\tbool operator<(const struct Info& arg) const{\n\n\t\treturn x < arg.x;\n\t}\n\tll value,x;\n};\n\nenum Type{\n\tL,\n\tR,\n};\n\nint f_N,N;\nll table[2][6*SIZE];\nll M,D;\nInfo info[SIZE],work[SIZE];\n\nvoid init(int first_N){\n\tN = 1;\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(Type type,int loc,ll value){\n\tloc += N-1;\n\n\ttable[type][loc] = value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[type][parent] = max(table[type][2*parent+1],table[type][2*parent+2]);\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\n\nll query(Type type,int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\t//今回のノードが検索区間をカバーしていなければ、結果に関係ない値を返す\n\tif(search_right < node_left || search_left > node_right){\n\n\t\treturn -HUGE_NUM;\n\t}\n\n\t//今回のノードの区間が、検索区間の部分区間である場合、今回のノードの値を返す\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[type][node_id];\n\t}\n\n\t//今回のノードの区間に、一部検索区間と重なっている区間がある場合→再帰的に子どもに尋ねる\n\tll left_max = query(type,search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tll right_max = query(type,search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\n\nbool isOK(ll mini){ //■最小値を決め打つ\n\n\tll ind = 0;\n\tfor(int i = 0; i < f_N; i++){\n\n\t\tif(info[i].value < mini)continue;\n\n\t\twork[ind] = info[i];\n\t\tind++;\n\t}\n\n\tif(ind < M){\n\n\t\treturn false;\n\t}\n\n\tinit(ind);\n\n\t//0~N-2が上位構造のアドレス、N-1~2*N-2が最小要素のアドレス\n\tfor(int i = 0; i <= 2*N-2; i++){\n\n\t\ttable[L][i] = -HUGE_NUM;\n\t\ttable[R][i] = -HUGE_NUM;\n\t}\n\n\t//■右方の、最大のパス長を求める\n\tupdate(R,ind-1,0);\n\n\tfor(int i = ind-2; i >= 0; i--){\n\n\t\tint left = i,right = f_N-1,mid = (left+right)/2;\n\t\tint next = i;\n\n\t\twhile(left <= right){\n\n\t\t\tif(work[mid].x >= work[i].x+D){\n\t\t\t\tnext = mid;\n\t\t\t\tright = mid-1;\n\t\t\t}else{\n\n\t\t\t\tleft = mid+1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\tif(next == i){\n\t\t\tupdate(R,i,0);\n\t\t\tcontinue;\n\t\t}\n\n\t\tll tmp = query(R,next,ind-1,0,0,N-1);\n\n\t\tupdate(R,i,tmp+1);\n\t}\n\n\t//■左方の最大のパス長を求める\n\tupdate(L,0,0);\n\n\tfor(int i = 1; i < ind; i++){\n\n\t\tint left = 0,right = i,mid = (left+right)/2;\n\t\tint next = i;\n\n\t\twhile(left <= right){\n\n\t\t\tif(work[mid].x <= work[i].x-D){\n\n\t\t\t\tnext = mid;\n\t\t\t\tleft = mid+1;\n\n\t\t\t}else{\n\n\t\t\t\tright = mid-1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\tif(next == i){\n\n\t\t\tupdate(L,i,0);\n\t\t\tcontinue;\n\t\t}\n\n\t\tll tmp = query(L,0,next,0,0,N-1);\n\n\t\tupdate(L,i,tmp+1);\n\t}\n\n\tfor(int i = 0; i < ind; i++){\n\n\t\tll to_L = query(L,i,i,0,0,N-1);\n\t\tll to_R = query(R,i,i,0,0,N-1);\n\n\t\tif(to_L+to_R+1 >= M){\n\n\t\t\treturn true;\n\t\t}\n\t}\n\n\treturn false;\n}\n\n\nint main(){\n\n\tscanf(\"%d %lld %lld\",&f_N,&M,&D);\n\n\tvector<ll> vec;\n\n\tfor(int i = 0; i < f_N; i++){\n\n\t\tscanf(\"%lld %lld\",&info[i].x,&info[i].value);\n\t\tvec.push_back(info[i].value);\n\t}\n\tsort(info,info+f_N);\n\n\tsort(vec.begin(),vec.end());\n\tvec.erase(unique(vec.begin(),vec.end()),vec.end());\n\n\tint left = 0,right = vec.size()-1,mid = (left+right)/2;\n\tint ind = -1; //なるべく大きく\n\n\twhile(left <= right){\n\t\tif(isOK(vec[mid])){\n\n\t\t\tind = mid;\n\t\t\tleft = mid+1;\n\t\t}else{\n\n\t\t\tright = mid-1;\n\t\t}\n\t\tmid = (left+right)/2;\n\t}\n\n\tif(ind == -1){\n\n\t\tprintf(\"-1\\n\");\n\t}else{\n\n\t\tprintf(\"%lld\\n\",vec[ind]);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 11032, "score_of_the_acc": -1.9952, "final_rank": 14 }, { "submission_id": "aoj_0704_6156634", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 200005\n\nstruct Info{\n\tbool operator<(const struct Info& arg) const{\n\n\t\treturn x < arg.x;\n\t}\n\tll value,x;\n};\n\nenum Type{\n\tL,\n\tR,\n};\n\nint f_N,N;\nll table[2][6*SIZE];\nll M,D;\nInfo info[SIZE],work[SIZE];\n\nvoid init(int first_N){\n\tN = 1;\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(Type type,int loc,ll value){\n\tloc += N-1;\n\n\ttable[type][loc] = value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[type][parent] = max(table[type][2*parent+1],table[type][2*parent+2]);\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\n\nll query(Type type,int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\t//今回のノードが検索区間をカバーしていなければ、結果に関係ない値を返す\n\tif(search_right < node_left || search_left > node_right){\n\n\t\treturn -HUGE_NUM;\n\t}\n\n\t//今回のノードの区間が、検索区間の部分区間である場合、今回のノードの値を返す\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[type][node_id];\n\t}\n\n\t//今回のノードの区間に、一部検索区間と重なっている区間がある場合→再帰的に子どもに尋ねる\n\tll left_max = query(type,search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tll right_max = query(type,search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\n\nbool isOK(ll mini){ //■最小値を決め打つ\n\n\tll ind = 0;\n\tfor(int i = 0; i < f_N; i++){\n\n\t\tif(info[i].value < mini)continue;\n\n\t\twork[ind] = info[i];\n\t\tind++;\n\t}\n\n\tif(ind < M){\n\n\t\treturn false;\n\t}\n\n\tinit(ind);\n\n\t//0~N-2が上位構造のアドレス、N-1~2*N-2が最小要素のアドレス\n\tfor(int i = 0; i <= 2*N-2; i++){\n\n\t\ttable[L][i] = -HUGE_NUM;\n\t\ttable[R][i] = -HUGE_NUM;\n\t}\n\n\t//■右方の、最大のパス長を求める\n\tupdate(R,ind-1,0);\n\n\tfor(int i = ind-2; i >= 0; i--){\n\n\t\tint left = i,right = f_N-1,mid = (left+right)/2;\n\t\tint next = i;\n\n\t\twhile(left <= right){\n\n\t\t\tif(work[mid].x >= work[i].x+D){\n\t\t\t\tnext = mid;\n\t\t\t\tright = mid-1;\n\t\t\t}else{\n\n\t\t\t\tleft = mid+1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\tif(next == i){\n\t\t\tupdate(R,i,0);\n\t\t\tcontinue;\n\t\t}\n\n\t\tll tmp = query(R,next,ind-1,0,0,N-1);\n\n\t\t//printf(\"\\ni;%d tmp:%lld next:%d\\n\",i,tmp,next);\n\n\t\tupdate(R,i,tmp+1);\n\t}\n\n\t//■左方の最大のパス長を求める\n\tupdate(L,0,0);\n\n\tfor(int i = 1; i < ind; i++){\n\n\t\tint left = 0,right = i,mid = (left+right)/2;\n\t\tint next = i;\n\n\t\twhile(left <= right){\n\n\t\t\tif(work[mid].x <= work[i].x-D){\n\n\t\t\t\tnext = mid;\n\t\t\t\tleft = mid+1;\n\n\t\t\t}else{\n\n\t\t\t\tright = mid-1;\n\t\t\t}\n\t\t\tmid = (left+right)/2;\n\t\t}\n\n\t\tif(next == i){\n\n\t\t\tupdate(L,i,0);\n\t\t\tcontinue;\n\t\t}\n\n\t\tll tmp = query(L,0,next,0,0,N-1);\n\n\t\t//printf(\"\\ni;%d tmp:%lld next:%d\\n\",i,tmp,next);\n\n\t\tupdate(L,i,tmp+1);\n\t}\n\n\tfor(int i = 0; i < ind; i++){\n\n\t\tll to_L = query(L,i,i,0,0,N-1);\n\t\tll to_R = query(R,i,i,0,0,N-1);\n\n\t//\tprintf(\"\\ni:%d to_L:%lld to_R:%lld\\n\",i,to_L,to_R);\n\n\t\tif(to_L+to_R+1 >= M){\n\n\t\t\treturn true;\n\t\t}\n\t}\n\n\treturn false;\n}\n\n\nint main(){\n\n\tscanf(\"%d %lld %lld\",&f_N,&M,&D);\n\n\tvector<ll> vec;\n\n\tfor(int i = 0; i < f_N; i++){\n\n\t\tscanf(\"%lld %lld\",&info[i].x,&info[i].value);\n\t\tvec.push_back(info[i].value);\n\t}\n\tsort(info,info+f_N);\n\n\tsort(vec.begin(),vec.end());\n\tvec.erase(unique(vec.begin(),vec.end()),vec.end());\n\n\tint left = 0,right = vec.size()-1,mid = (left+right)/2;\n\tint ind = -1; //なるべく大きく\n\n\twhile(left <= right){\n\t\tif(isOK(vec[mid])){\n\n\t\t\tind = mid;\n\t\t\tleft = mid+1;\n\t\t}else{\n\n\t\t\tright = mid-1;\n\t\t}\n\t\tmid = (left+right)/2;\n\t}\n\n\tif(ind == -1){\n\n\t\tprintf(\"-1\\n\");\n\t}else{\n\n\t\tprintf(\"%lld\\n\",vec[ind]);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 950, "memory_kb": 11068, "score_of_the_acc": -2, "final_rank": 15 } ]
aoj_0733_cpp
エゴイ展 (EGOI Exhibition) 問題文 JOI 美術館には, N 枚の絵が横一列に飾られている.美術館に展示されている絵には M 個の種類があり, 1 から M までの番号が付けられている.左から i 番目 ( 1 ≦ i ≦ N ) の絵の種類は A i であり,価値は V i である. ここで, V i は負の数になることもある. 来月,JOI 美術館では「エゴイ展 2022」が開催予定であり,多くの来客が見込まれるため,見栄えを良くしたい.そこで館長の理恵さんは,隣り合う絵が同じ種類にならないように,いくつかの絵を撤去することにした. 一方で,評判を高めるため,残された絵の価値の合計をできるだけ大きくしたい. 絵の枚数,絵の種類数, N 枚の絵の情報が与えられたとき,残された絵の価値の合計として考えられる最大値を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 150000 . 1 ≦ M ≦ N . 1 ≦ A i ≦ M ( 1 ≦ i ≦ N ). - 10000 ≦ V i ≦ 10000 ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N M A 1 V 1 A 2 V 2 : A N V N 出力 標準出力に,残された絵の価値の合計として考えられる最大値を 1 行で出力せよ. 入出力例 入力例 1 3 1 1 107 1 123 1 100 出力例 1 123 左から 2 番目の絵のみを残した場合,価値の合計は V 2 = 123 となる. 入力例 2 4 3 1 204 2 168 2 277 1 219 出力例 2 700 左から 1, 3, 4 番目の絵を残すのが最適である. 入力例 3 3 2 1 5 2 -1 1 5 出力例 3 9 すべての絵を残すのが最適である. 入力例 4 6 4 1 -123 2 -123 3 -123 4 -123 4 -123 3 -123 出力例 4 0 絵を 1 枚も残さないのが最適である. 入力例 5 30 4 2 -1358 4 -1405 4 2003 3 -1148 2 -1527 2 -2015 4 -2910 1 2133 2 2185 1 2249 3 1058 1 -1907 2 -3190 1 -2701 3 -2640 1 1685 3 1855 4 2398 3 -3158 2 1947 3 2947 2 -2197 4 1398 2 -3011 4 -1971 1 -2829 1 3094 2 2704 4 -2592 3 2910 出力例 5 30566 情報オリンピック日本委員会 作 『日本情報オリンピック第2回女性部門 本選 競技課題』
[ { "submission_id": "aoj_0733_9047231", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate <typename T>\nT floor(T a, T b) {\n return a / b - (a % b && (a ^ b) < 0);\n}\ntemplate <typename T>\nT ceil(T x, T y) {\n return floor(x + y - 1, y);\n}\ntemplate <typename T>\nT bmod(T x, T y) {\n return x - y * floor(x, y);\n}\ntemplate <typename T>\npair<T, T> divmod(T x, T y) {\n T q = floor(x, y);\n return {q, x - q * y};\n}\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate <typename T>\nT POP(queue<T> &que) {\n T a = que.front();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(deque<T> &que) {\n T a = que.front();\n que.pop_front();\n return a;\n}\ntemplate <typename T>\nT POP(pq<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(pqg<T> &que) {\n T a = que.top();\n que.pop();\n return a;\n}\ntemplate <typename T>\nT POP(vc<T> &que) {\n T a = que.back();\n que.pop_back();\n return a;\n}\n\ntemplate <typename F>\nll binary_search(F check, ll ok, ll ng, bool check_ok = true) {\n if (check_ok) assert(check(ok));\n while (abs(ok - ng) > 1) {\n auto x = (ng + ok) / 2;\n (check(x) ? ok : ng) = x;\n }\n return ok;\n}\ntemplate <typename F>\nf128 binary_search_real(F check, f128 ok, f128 ng, ll iter = 100) {\n rep(iter) {\n f128 x = (ok + ng) / 2;\n (check(x) ? ok : ng) = x;\n }\n return (ok + ng) / 2;\n}\n\n// ? は -1\nvc<int> s_to_vi(const string &S, char first_char) {\n vc<int> A(S.size());\n rep(i, S.size()) { A[i] = (S[i] != '?' ? S[i] - first_char : -1); }\n return A;\n}\n\ntemplate <typename T, typename U>\nvc<T> cumsum(vc<U> &A, ll off = 1) {\n ll N = A.size();\n vc<T> B(N + 1);\n rep(i, N) { B[i + 1] = B[i] + A[i]; }\n if (off == 0) B.erase(B.begin());\n return B;\n}\n\n// stable sort\ntemplate <typename T>\nvi argsort(const vector<T> &A) {\n vi ids(len(A));\n iota(all(ids), 0);\n sort(all(ids),\n [&](ll i, ll j) { return (A[i] == A[j] ? i < j : A[i] < A[j]); });\n return ids;\n}\n\n// A[I[0]], A[I[1]], ...\ntemplate <typename T>\nvc<T> rearrange(const vc<T> &A, const vi &I) {\n vc<T> B(len(I));\n rep(i, len(I)) B[i] = A[I[i]];\n return B;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N, M;\n cin >> N >> M;\n vi A(N), V(N);\n rep(i, N) cin >> A[i] >> V[i];\n vc<pi> dp1(N, mp(-inf, -1)), dp2(N, mp(-inf, -1));\n dp1[0] = mp(V[0], A[0]);\n dp2[0] = mp(0, -1);\n rep(i, 1, N) {\n vc<pi> v;\n if (dp1[i-1].se != A[i]) v.eb(mp(dp1[i-1].fi + V[i], A[i]));\n if (dp2[i-1].se != A[i]) v.eb(mp(dp2[i-1].fi + V[i], A[i]));\n v.eb(mp(dp1[i-1].fi, dp1[i-1].se));\n v.eb(mp(dp2[i-1].fi, dp2[i-1].se));\n sort(all(v), greater<pi>());\n dp1[i] = v[0];\n rep(j, 1, len(v)) {\n if (v[j].se == v[0].se) continue;\n dp2[i] = v[j];\n break;\n }\n }\n print(dp1[N-1].fi);\n return 0;\n}", "accuracy": 1, "time_ms": 20, "memory_kb": 10216, "score_of_the_acc": -0.6639, "final_rank": 6 }, { "submission_id": "aoj_0733_8894588", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nclass RangeUpdate{\npublic:\n\tvirtual ll fa(ll x,ll m)=0;\n\tvirtual ll fm(ll m1,ll m2)=0;\n\tll em;\n};\n\nclass RangeUpdateChange:public RangeUpdate{\npublic:\n\tRangeUpdateChange(){ em = numeric_limits<ll>::max(); }\n\tll fa(ll x,ll m){ return m; }\n\tll fm(ll m1,ll m2){ return m2; }\n};\n\nclass RangeQuery{\npublic:\n\tvirtual ll fx(ll x1,ll x2)=0;\n\tvirtual ll fp(ll m,ll n)=0;\n\tll ex;\n};\n\nclass RangeQueryMax:public RangeQuery{\npublic:\n\tRangeQueryMax(){ ex = numeric_limits<ll>::lowest(); }\n\tll fx(ll x1,ll x2){ return max(x1,x2); }\n\tll fp(ll m,ll n){ return m; }\n};\n\nclass SegmentTree{\n\tunique_ptr<RangeUpdate> range_update;\n\tunique_ptr<RangeQuery> range_query;\n\n\t/* lazy eval */\n\tvoid Eval(int k,int len){\n\t\tif(lazy[k]==range_update->em) return; // 更新するものが無ければ終了\n\t\tif(k<size-1){ // 葉でなければ子に伝搬\n\t\t\tlazy[k*2+1] = range_update->fm(lazy[k*2+1],lazy[k]);\n\t\t\tlazy[k*2+2] = range_update->fm(lazy[k*2+2],lazy[k]);\n\t\t}\n\t\t// 自身を更新\n\t\tdat[k] = range_update->fa(dat[k],range_query->fp(lazy[k],len));\n\t\tlazy[k] = range_update->em;\n\t}\n\n\tll Query(ll a,ll b,ll k,ll l,ll r){\n\t\tEval(k,r-l);\n\t\tif(r<=a || b<=l){ // 完全に外側の時\n\t\t\treturn range_query->ex;\n\t\t}\n\t\telse if(a <= l && r <= b){ // 完全に内側の時\n\t\t\treturn dat[k];\n\t\t}\n\t\telse{ // 一部区間が被る時\n\t\t\tll vl = Query(a,b,k*2+1,l,(l+r)/2);\n\t\t\tll vr = Query(a,b,k*2+2,(l+r)/2,r);\n\t\t\treturn range_query->fx(vl,vr);\n\t\t}\n\t}\n\n\tvoid Update(ll a,ll b,ll x,ll k,ll l,ll r) {\n\t\tEval(k,r-l);\n\t\tif(a<=l && r<=b){ // 完全に内側の時\n\t\t\tlazy[k] = range_update->fm(lazy[k],x);\n\t\t\tEval(k,r-l);\n\t\t}\n\t\telse if(a<r && l<b){ // 一部区間が被る時\n\t\t\tUpdate(a,b,x,k*2+1,l,(l+r)/2); // 左の子\n\t\t\tUpdate(a,b,x,k*2+2,(l+r)/2,r); // 右の子\n\t\t\tdat[k] = range_query->fx(dat[k*2+1],dat[k*2+2]);\n\t\t}\n\t}\npublic:\n\tll size;\n\tvector<ll> dat;\n\tvector<ll> lazy;\n\tSegmentTree(ll N,unique_ptr<RangeUpdate> rup,unique_ptr<RangeQuery> rqp)\n\t\t: range_update(std::move(rup)),range_query(std::move(rqp)){\n\t\tdat.resize(max(4*N,4ll),range_query->ex);\n\t\tlazy.resize(max(4*N,4ll),range_update->em);\n\t\tll x = 1;\n\t\twhile(N>x) x *= 2;\n\t\tsize = x;\n\t}\n\tvoid Set(int i,ll x){ dat[i+size-1]=x; }\n\tvoid Build(){\n\t\tfor(ll k=size-2ll;k>=0;k--) dat[k] = range_query->fx(dat[2*k+1],dat[2*k+2]);\n\t}\n\n\tvoid Update(ll a,ll b,ll x){ Update(a,b,x,0,0,size); }\n\tll Query(int a,int b){ return Query(a,b,0,0,size); }\n};\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tauto N=in(),M=in();\n\n\tll len = M+2ll;\n\tSegmentTree seg_tree(len,make_unique<RangeUpdateChange>(),make_unique<RangeQueryMax>());\n\tREP(i,len){\n\t\tseg_tree.Set(i,0);\n\t}\n\tseg_tree.Build();\n\n\tLOOP(N){\n\t\tll t=in(),v=in();\n\t\tauto L=seg_tree.Query(0,t);\n\t\tauto M=seg_tree.Query(t,t+1);\n\t\tauto R=seg_tree.Query(t+1,len);\n\t\tseg_tree.Update(t,t+1,max(M,max(L,R)+v));\n\t}\n\tout(seg_tree.Query(0,len));\n\treturn 0;\n}", "accuracy": 1, "time_ms": 130, "memory_kb": 12472, "score_of_the_acc": -2, "final_rank": 9 }, { "submission_id": "aoj_0733_8386996", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0733.cc: エゴイ展 (EGOI Exhibition)\n */\n\n#include<cstdio>\n#include<vector>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 150000;\nconst int MAX_M = 150000;\n\n/* typedef */\n\ntemplate <typename T>\nstruct SegTreeMax {\n int e2;\n vector<T> nodes;\n T defv;\n SegTreeMax() {}\n\n void init(int n, T _defv) {\n defv = _defv;\n for (e2 = 1; e2 < n; e2 <<= 1);\n nodes.assign(e2 * 2, defv);\n }\n\n T &geti(int i) { return nodes[e2 - 1 + i]; }\n void seti(int i, T v) { geti(i) = v; }\n\n void setall() {\n for (int j = e2 - 2; j >= 0; j--)\n nodes[j] = max(nodes[j * 2 + 1], nodes[j * 2 + 2]);\n }\n\n void set(int i, T v) {\n int j = e2 - 1 + i;\n nodes[j] = v;\n while (j > 0) {\n j = (j - 1) / 2;\n nodes[j] = max(nodes[j * 2 + 1], nodes[j * 2 + 2]);\n }\n }\n\n T max_range(int r0, int r1, int k, int i0, int i1) {\n if (r1 <= i0 || i1 <= r0) return defv;\n if (r0 <= i0 && i1 <= r1) return nodes[k];\n\n int im = (i0 + i1) / 2;\n T v0 = max_range(r0, r1, k * 2 + 1, i0, im);\n T v1 = max_range(r0, r1, k * 2 + 2, im, i1);\n return max(v0, v1);\n }\n T max_range(int r0, int r1) { return max_range(r0, r1, 0, 0, e2); }\n};\n\n/* global variables */\n\nint as[MAX_N], vs[MAX_N];\nSegTreeMax<int> st;\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n, m;\n scanf(\"%d%d\", &n, &m);\n for (int i = 0; i < n; i++) scanf(\"%d%d\", as + i, vs + i), as[i]--;\n\n st.init(m, 0);\n for (int i = 0; i < n; i++) {\n int di =\n max(st.max_range(0, as[i]), st.max_range(as[i] + 1, m)) + vs[i];\n if (st.geti(as[i]) < di) st.set(as[i], di);\n }\n\n int maxd = 0;\n for (int i = 0; i < m; i++) maxd = max(maxd, st.geti(i));\n\n printf(\"%d\\n\", maxd);\n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5760, "score_of_the_acc": -0.2727, "final_rank": 4 }, { "submission_id": "aoj_0733_7995577", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define all(A) A.begin(),A.end()\nusing vll = vector<ll>;\n#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)\n\ntemplate<class T>\nstruct segtree {//0index\n int n;\n vector<T> V;\n segtree(int siz) :n(), V(siz * 4, e()) {\n int x = 1;\n while (siz > x) {\n x *= 2;\n }\n n = x;\n }\n\n void update(int id, T x) {\n id += n;\n V[id] = x;\n while (id > 1) {\n id = id / 2;\n V[id] = op(V[id * 2], V[id * 2+1]);\n }\n }\n\n T prod(int a, int b) {//op[a,b)\n return quer(a, b, 1, 0, n);\n };\n T quer(int a, int b, int k, int l, int r) {\n if (r <= a || b <= l)return e();\n else if (a <= l && r <= b)return V[k];\n else {\n return op(quer(a, b, k * 2, l, (l + r) / 2), quer(a, b, k * 2 + 1, (l + r) / 2, r));\n }\n };\n\n\n T op(T a, T b) {\n return max(a,b);\n };\n T e() {\n return 0;\n };\n};\n\n\nll gcd(ll(a), ll(b)) {\n ll c = a;\n while (a % b != 0) {\n c = a % b;\n a = b;\n b = c;\n }\n return b;\n}\n\n\nint main() {\n ll N, M;\n cin >> N >> M;\n segtree<ll> seg(N + 1);\n rep(i, N + 1)seg.update(i,0);\n rep(i, N) {\n ll A, V;\n cin >> A >> V;\n ll M = seg.prod(A,A+1);\n seg.update(A, -1);\n ll P=seg.prod(0,N+1);\n M = max(M, P + V);\n seg.update(A, M);\n }\n cout << seg.prod(0,N+1) << endl;\n\n}", "accuracy": 1, "time_ms": 80, "memory_kb": 7800, "score_of_the_acc": -0.8494, "final_rank": 7 }, { "submission_id": "aoj_0733_7988204", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 150005\n\nint N;\nll table[6*SIZE];\nll A[SIZE],V[SIZE];\n\nvoid init(int first_N){\n\tN = 1;\n\twhile(N < first_N)N *= 2;\n}\n\nvoid update(int loc,ll value){\n\tloc += N-1;\n\n\ttable[loc] = value;\n\n\tif(N == 1)return;\n\n\tint parent = (loc-1)/2;\n\n\twhile(true){\n\t\ttable[parent] = max(table[2*parent+1],table[2*parent+2]);\n\n\t\tif(parent == 0)break;\n\t\telse{\n\t\t\tparent = (parent-1)/2;\n\t\t}\n\t}\n}\n\n\nll query(int search_left,int search_right,int node_id,int node_left,int node_right){\n\n\t//今回のノードが検索区間をカバーしていなければ、結果に関係ない値を返す\n\tif(search_right < node_left || search_left > node_right){\n\n\t\treturn -HUGE_NUM;\n\t}\n\n\t//今回のノードの区間が、検索区間の部分区間である場合、今回のノードの値を返す\n\tif(search_left <= node_left && search_right >= node_right){\n\t\treturn table[node_id];\n\t}\n\n\t//今回のノードの区間に、一部検索区間と重なっている区間がある場合→再帰的に子どもに尋ねる\n\tll left_max = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)/2);\n\tll right_max = query(search_left,search_right,2*node_id+2,(node_left+node_right)/2+1,node_right);\n\n\treturn max(left_max,right_max);\n}\n\n\nint main(){\n\n\tint first_N,M;\n\tscanf(\"%d %d\",&first_N,&M);\n\n\tinit(M+1); //■0を含めるため、M+1種類\n\n\t//0~N-2が上位構造のアドレス、N-1~2*N-2が最小要素のアドレス\n\tfor(int i = 0; i <= 2*N-2; i++)table[i] = -HUGE_NUM;\n\n\tupdate(0,0); //ダミー\n\n\tll ans = 0;\n\n\tfor(int i = 0; i < first_N; i++){\n\n\t\tscanf(\"%lld %lld\",&A[i],&V[i]);\n\n\t\t//自分以外の種類の最大値\n\t\tll tmp = query(0,A[i]-1,0,0,N-1);\n\t\tif(A[i] != M){\n\n\t\t\tchmax(tmp,query(A[i]+1,M,0,0,N-1));\n\t\t}\n\n\t\tll pre = query(A[i],A[i],0,0,N-1); //同種の過去最大値\n\n\t\tif(pre >= tmp+V[i]){\n\t\t\tcontinue;\n\t\t}\n\n\t\tupdate(A[i],tmp+V[i]);\n\t\tchmax(ans,tmp+V[i]);\n\t}\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9664, "score_of_the_acc": -1.218, "final_rank": 8 }, { "submission_id": "aoj_0733_7977751", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\ntemplate <class S, S (*op)(S, S), S (*e)()>\nstruct segtree {\n int n;\n vector<S> tree;\n segtree() : segtree(0) {}\n segtree(int n) : n(n), tree(vector<S>(n<<1, e())) {}\n void update(int k) { tree[k] = op(tree[k<<1|0], tree[k<<1|1]); }\n S operator[](int i) {return tree[i+n]; }\n void set(int i, S x) {\n i += n;\n tree[i] = x;\n while(i >>= 1) {\n update(i);\n }\n }\n // [l,r)\n S query(int l, int r) {\n S res = e();\n for(l += n, r += n; l < r; l >>= 1, r >>= 1){\n if(l & 1) res = op(res, tree[l++]);\n if(r & 1) res = op(res, tree[--r]);\n }\n return res;\n }\n};\n\nll op(ll a,ll b){return max(a,b);}\nll e() {return -1e18;}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m; cin >> n >> m;\n vector<int> a(n),v(n);\n for(int i=0;i<n;i++){\n cin >> a[i] >> v[i];\n }\n segtree<ll, op, e> seg(m+1);\n seg.set(0,0);\n for(int i=0;i<n;i++){\n ll u = max(seg.query(0, a[i]), seg.query(a[i]+1, m+1));\n if(seg[a[i]] < u+v[i]){\n seg.set(a[i],u+v[i]);\n }\n }\n cout << seg.query(0, m+1) << endl;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6708, "score_of_the_acc": -0.2321, "final_rank": 2 }, { "submission_id": "aoj_0733_7876062", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nbool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nbool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/math/pow.hpp\"\n\nstd::int64_t safe_mod(std::int64_t a, std::int64_t mod) {\n a %= mod;\n return a >= 0 ? a : a + mod;\n}\n\nstd::int64_t pow_int(std::int64_t a, std::int64_t n) {\n assert(n >= 0);\n std::int64_t res = 1, mul = a;\n for (; n > 0; n >>= 1) {\n if (n & 1) res *= mul;\n mul *= mul;\n }\n return res;\n}\n\nstd::int64_t inv_mod(std::int64_t a, std::int64_t mod) {\n std::int64_t b = mod, u = 1, v = 0, t;\n while (b > 0) {\n t = a / b;\n std::swap(a -= t * b, b);\n std::swap(u -= t * v, v);\n }\n return u >= 0 ? u % mod : (mod - (-u) % mod) % mod;\n}\n\nstd::int64_t pow_mod(std::int64_t a, std::int64_t n, std::int64_t mod) {\n if (n < 0) return inv_mod(pow_mod(a, -n, mod), mod);\n std::int64_t res = 1, mul = safe_mod(a, mod);\n for (; n > 0; n >>= 1) {\n if (n & 1) (res *= mul) %= mod;\n (mul *= mul) %= mod;\n }\n return res;\n}\n\nint ceil_pow2(std::int64_t n) {\n int x = 0;\n while ((std::uint64_t(1) << x) < (std::uint64_t)(n)) ++x;\n return x;\n}\n\nint floor_pow2(std::int64_t n) {\n int x = 0;\n while ((std::uint64_t(1) << (x + 1)) <= (std::uint64_t)(n)) ++x;\n return x;\n}\n#line 3 \"/home/kuhaku/home/github/algo/lib/segment_tree/monoid.hpp\"\n\ntemplate <class T>\nstruct Add {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs + rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs + rhs;\n }\n};\n\ntemplate <class T>\nstruct And {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return lhs & rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs & rhs;\n }\n};\n\ntemplate <class T>\nstruct Or {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs | rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs | rhs;\n }\n};\n\ntemplate <class T>\nstruct Xor {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs ^ rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs ^ rhs;\n }\n};\n\ntemplate <class T>\nstruct Min {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return std::min(lhs, rhs); }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return std::min((U)lhs, rhs);\n }\n};\n\ntemplate <class T>\nstruct Max {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::min();\n static constexpr T op(const T &lhs, const T &rhs) { return std::max(lhs, rhs); }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return std::max((U)lhs, rhs);\n }\n};\n\ntemplate <class T>\nstruct Update {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return lhs == Update::id ? rhs : lhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs == Update::id ? rhs : lhs;\n }\n};\n\ntemplate <class T>\nstruct Affine {\n using value_type = std::pair<T, T>;\n static constexpr std::pair<T, T> id = std::pair<T, T>(1, 0);\n static constexpr std::pair<T, T> op(std::pair<T, T> lhs, std::pair<T, T> rhs) {\n return {lhs.first * rhs.first, lhs.first * rhs.second + lhs.second};\n }\n};\n\ntemplate <class M>\nstruct Rev {\n using T = typename M::value_type;\n using value_type = T;\n static constexpr T id = M::id;\n static constexpr T op(T lhs, T rhs) { return M::op(rhs, lhs); }\n};\n#line 5 \"/home/kuhaku/home/github/algo/lib/segment_tree/segment_tree.hpp\"\n\n/**\n * @brief セグメント木\n * @see https://noshi91.hatenablog.com/entry/2020/04/22/212649\n *\n * @tparam M モノイド\n */\ntemplate <class M>\nstruct segment_tree {\n private:\n using T = typename M::value_type;\n\n public:\n segment_tree() : segment_tree(0) {}\n explicit segment_tree(int n, T e = M::id) : segment_tree(std::vector<T>(n, e)) {}\n template <class U>\n explicit segment_tree(const std::vector<U> &v) : _n(v.size()) {\n this->_log = ceil_pow2(this->_n);\n this->_size = 1 << this->_log;\n this->data = std::vector<T>(this->_size << 1, M::id);\n for (int i = 0; i < this->_n; ++i) this->data[this->_size + i] = T(v[i]);\n for (int i = this->_size - 1; i >= 1; --i) this->update(i);\n }\n\n const T &operator[](int k) const { return this->data[k + this->_size]; }\n T at(int k) const { return this->operator[](k); }\n T get(int k) const { return this->operator[](k); }\n\n void set(int k, T val) {\n assert(0 <= k && k < this->_n);\n k += this->_size;\n this->data[k] = val;\n for (int i = 1; i <= this->_log; ++i) this->update(k >> i);\n }\n void reset(int k) { this->set(k, M::id); }\n\n T all_prod() const { return this->data[1]; }\n T prod(int a, int b) const {\n assert(0 <= a && b <= this->_n);\n T l = M::id, r = M::id;\n for (a += this->_size, b += this->_size; a < b; a >>= 1, b >>= 1) {\n if (a & 1) l = M::op(l, this->data[a++]);\n if (b & 1) r = M::op(this->data[--b], r);\n }\n return M::op(l, r);\n }\n\n template <class F>\n int max_right(F f) const {\n return this->max_right(0, f);\n }\n\n template <class F>\n int max_right(int l, F f) const {\n assert(0 <= l && l <= this->_n);\n assert(f(M::id));\n if (l == this->_n) return this->_n;\n l += this->_size;\n T sm = M::id;\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(M::op(sm, this->data[l]))) {\n while (l < this->_size) {\n l = (2 * l);\n if (f(M::op(sm, this->data[l]))) {\n sm = M::op(sm, this->data[l]);\n l++;\n }\n }\n return l - this->_size;\n }\n sm = M::op(sm, this->data[l]);\n l++;\n } while ((l & -l) != l);\n return this->_n;\n }\n\n int max_right(T x) const { return this->max_right(0, x); }\n\n int max_right(int l, T x) const {\n return this->max_right(l, [&x](auto y) {\n return !(y < x);\n });\n }\n\n template <class F>\n int min_left(F f) const {\n return this->min_left(this->_n, f);\n }\n\n template <class F>\n int min_left(int r, F f) const {\n assert(0 <= r && r <= this->_n);\n assert(f(M::id));\n if (r == 0) return 0;\n r += this->_size;\n T sm = M::id;\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(M::op(this->data[r], sm))) {\n while (r < this->_size) {\n r = (2 * r + 1);\n if (f(M::op(this->data[r], sm))) {\n sm = M::op(this->data[r], sm);\n r--;\n }\n }\n return r + 1 - this->_size;\n }\n sm = M::op(this->data[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n int min_left(T x) const { return this->min_left(this->_n, x); }\n\n int min_left(int r, T x) const {\n return this->min_left(r, [&x](auto y) {\n return !(y < x);\n });\n }\n\n private:\n int _n, _size, _log;\n std::vector<T> data;\n\n void update(int k) { this->data[k] = M::op(this->data[2 * k], this->data[2 * k + 1]); }\n};\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid setp(int n) {\n std::cout << std::fixed << std::setprecision(n);\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n, m;\n cin >> n >> m;\n segment_tree<Max<ll>> st(m);\n rep (i, m) st.set(i, 0);\n while (n--) {\n ll x, y;\n cin >> x >> y;\n --x;\n ll ans = 0;\n chmax(ans, st.prod(0, x));\n chmax(ans, st.prod(x + 1, m));\n ans += y;\n if (st.get(x) < ans)\n st.set(x, ans);\n }\n cout << st.all_prod() << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 8300, "score_of_the_acc": -0.5602, "final_rank": 5 }, { "submission_id": "aoj_0733_7866942", "code_snippet": "#include <bits/extc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n\ntemplate <class T> using Max_Heap = __gnu_pbds::priority_queue<T, less<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Min_Heap = __gnu_pbds::priority_queue<T, greater<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = __gnu_pbds::gp_hash_table<K, V>;\ntemplate <class T> using Rope = __gnu_cxx::rope<T>;\nusing Trie = __gnu_pbds::trie<string, __gnu_pbds::null_type, __gnu_pbds::trie_string_access_traits<>, __gnu_pbds::pat_trie_tag, __gnu_pbds::trie_prefix_search_node_update>;\n\ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\ntemplate< typename Monoid, typename F >\nstruct SegmentTree {\n int sz;\n vector< Monoid > seg;\n\n const F f;\n const Monoid M1;\n \n SegmentTree(int n, const F f, const Monoid &M1) : f(f), M1(M1) {\n sz = 1;\n while(sz < n) sz <<= 1;\n seg.assign(2 * sz, M1);\n }\n\n void set(int k, const Monoid &x) {\n seg[k + sz] = x;\n }\n\n void build() {\n for(int k = sz - 1; k > 0; k--) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n\n void update(int k, const Monoid &x) {\n k += sz;\n seg[k] = x;\n while(k >>= 1) {\n seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n }\n }\n\n Monoid query(int a, int b) {\n Monoid L = M1, R = M1;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) L = f(L, seg[a++]);\n if(b & 1) R = f(seg[--b], R);\n }\n return f(L, R);\n }\n\n Monoid operator[](const int &k) const {\n return seg[k + sz];\n }\n\n template< typename C >\n int find_subtree(int a, const C &check, Monoid &M, bool type) {\n while(a < sz) {\n Monoid nxt = type ? f(seg[2 * a + type], M) : f(M, seg[2 * a + type]);\n if(check(nxt)) a = 2 * a + type;\n else M = nxt, a = 2 * a + 1 - type;\n }\n return a - sz;\n }\n\n template< typename C >\n int find_first(int a, const C &check) {\n Monoid L = M1;\n if(a <= 0) {\n if(check(f(L, seg[1]))) return find_subtree(1, check, L, false);\n return -1;\n }\n int b = sz;\n for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n if(a & 1) {\n Monoid nxt = f(L, seg[a]);\n if(check(nxt)) return find_subtree(a, check, L, false);\n L = nxt;\n ++a;\n }\n }\n return -1;\n }\n\n template< typename C >\n int find_last(int b, const C &check) {\n Monoid R = M1;\n if(b >= sz) {\n if(check(f(seg[1], R))) return find_subtree(1, check, R, true);\n return -1;\n }\n int a = sz;\n for(b += sz; a < b; a >>= 1, b >>= 1) {\n if(b & 1) {\n Monoid nxt = f(seg[--b], R);\n if(check(nxt)) return find_subtree(b, check, R, true);\n R = nxt;\n }\n }\n return -1;\n }\n};\n\ntemplate< typename Monoid, typename F >\nSegmentTree< Monoid, F > get_segment_tree(int N, const F& f, const Monoid& M1) {\n return {N, f, M1};\n}\n\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m;\n cin >> n >> m;\n\n assert(1 <= n && n <= 150000);\n assert(1 <= m && m <= n);\n\n vector<int> a(n), v(n);\n\n for (int i = 0; i < n; ++i) {\n cin >> a[i] >> v[i];\n assert(1 <= a[i] && a[i] <= m);\n assert(-10000 <= v[i] && v[i] <= 10000);\n }\n\n auto seg = get_segment_tree(n + 1, [](int a, int b) { return (max(a, b)); }, 0);\n\n for (int i = 0; i < n; ++i) {\n seg.update(a[i], max(seg[a[i]], max(seg.query(0, a[i]), seg.query(a[i] + 1, n + 1)) + v[i]));\n }\n\n cout << seg.query(0, n + 1) << '\\n';\n\n return (0);\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6256, "score_of_the_acc": -0.1648, "final_rank": 1 }, { "submission_id": "aoj_0733_7848640", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\n\ntemplate <class S, S (*op)(S, S), S (*e)()> struct segtree {\n public:\n segtree() : segtree(0) {}\n segtree(int n) : segtree(std::vector<S>(n, e())) {}\n segtree(const std::vector<S>& v) : _n(int(v.size())) {\n log = ceil_pow2(_n);\n size = 1 << log;\n d = std::vector<S>(2 * size, e());\n for (int i = 0; i < _n; i++) d[size + i] = v[i];\n for (int i = size - 1; i >= 1; i--) {\n update(i);\n }\n }\n\n void set(int p, S x) {\n assert(0 <= p && p < _n);\n p += size;\n d[p] = x;\n for (int i = 1; i <= log; i++) update(p >> i);\n }\n\n S get(int p) {\n assert(0 <= p && p < _n);\n return d[p + size];\n }\n const S operator[](int p) const { return get(p); }\n S operator[](int p) { return get(p); }\n\n S prod(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n S sml = e(), smr = e();\n l += size;\n r += size;\n\n while (l < r) {\n if (l & 1) sml = op(sml, d[l++]);\n if (r & 1) smr = op(d[--r], smr);\n l >>= 1;\n r >>= 1;\n }\n return op(sml, smr);\n }\n\n S all_prod() { return d[1]; }\n\n template <bool (*f)(S)> int max_right(int l) {\n return max_right(l, [](S x) { return f(x); });\n }\n template <class F> int max_right(int l, F f) {\n assert(0 <= l && l <= _n);\n assert(f(e()));\n if (l == _n) return _n;\n l += size;\n S sm = e();\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(op(sm, d[l]))) {\n while (l < size) {\n l = (2 * l);\n if (f(op(sm, d[l]))) {\n sm = op(sm, d[l]);\n l++;\n }\n }\n return l - size;\n }\n sm = op(sm, d[l]);\n l++;\n } while ((l & -l) != l);\n return _n;\n }\n\n template <bool (*f)(S)> int min_left(int r) {\n return min_left(r, [](S x) { return f(x); });\n }\n template <class F> int min_left(int r, F f) {\n assert(0 <= r && r <= _n);\n assert(f(e()));\n if (r == 0) return 0;\n r += size;\n S sm = e();\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(op(d[r], sm))) {\n while (r < size) {\n r = (2 * r + 1);\n if (f(op(d[r], sm))) {\n sm = op(d[r], sm);\n r--;\n }\n }\n return r + 1 - size;\n }\n sm = op(d[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n private:\n int _n, size, log;\n std::vector<S> d;\n int ceil_pow2(int n) {\n int x = 0;\n while ((1U << x) < (unsigned int)(n)) x++;\n return x;\n }\n void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }\n};\n\nint op(int a,int b){return max(a,b);}\nint e(){return 0;}\n\nint main(){\n INT(n,m);\n vector<array<int,2>> a(n);\n segtree<int,op,e> seg(m);\n rep(i,n){\n in(a[i][0],a[i][1]);\n a[i][0]--;\n int v=max(seg.prod(0,a[i][0]),seg.prod(a[i][0]+1,m));\n seg.set(a[i][0],max(seg[a[i][0]],v+a[i][1]));\n }\n out(seg.all_prod());\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 6832, "score_of_the_acc": -0.2506, "final_rank": 3 } ]
aoj_0719_cpp
図書館 2 (Library 2) 問題文 読書好きのビ太郎は図書館で本を借りて読むことにした.ビ太郎の家は狭いため,床には本 1 冊分の広さのスペースしかない.ただし高さは十分にあるため,ビ太郎はこのスペースに本を積んで管理することにした. ビ太郎はこれから Q 回の行動を取る. i ( 1 ≦ i ≦ Q ) 回目の行動は文字列 S i で表される. S i は 英小文字からなる文字列か READ のいずれかであり,その意味は次の通りである. 英小文字からなる文字列の場合,ビ太郎は書名が S i である本を図書館から借り,スペースの一番上に積む. READ の場合,ビ太郎はスペースの一番上に積まれている本を読み,図書館に返却する. あなたはビ太郎がどの本をどのような順番で読んだのかを調べたい. Q 回の行動の内容が与えられたとき,ビ太郎が読んだ本の書名を読んだ順に出力するプログラムを作成せよ. 制約 2 ≦ Q ≦ 200 000 . Q は整数である. S i は長さ 1 以上 10 以下の文字列である ( 1 ≦ i ≦ Q ). S i は英小文字からなる文字列または READ である ( 1 ≦ i ≦ Q ). S i が READ であるような i ( 1 ≦ i ≦ Q ) は 1 つ以上存在する. S i が READ のとき,必ずスペースに 1 冊以上の本が存在する ( 1 ≦ i ≦ Q ) . 入力 入力は以下の形式で標準入力から与えられる. Q S 1 S 2 : S Q 出力 標準出力に, S i が READ である行動のそれぞれに対して,ビ太郎が読んだ本の書名を順に改行区切りで出力せよ. 入出力例 入力例 1 7 joi joig ioi READ egoi READ READ 出力例 1 ioi egoi joig この入力例ではビ太郎は以下のように行動する. 書名が joi である本をスペースに積む.このとき,スペースに積まれている本の書名は joi となる. 書名が joig である本をスペースに積む.このとき,スペースに積まれている本の書名は上から順に joig , joi となる. 書名が ioi である本をスペースに積む.このとき,スペースに積まれている本の書名は上から順に ioi , joig , joi となる. 書名が ioi である本を読んで返却する.このとき,スペースに積まれている本の書名は上から順に joig , joi となる. 書名が egoi である本をスペースに積む.このとき,スペースに積まれている本の書名は上から順に egoi , joig , joi となる. 書名が egoi である本を読んで返却する.このとき,スペースに積まれている本の書名は上から順に joig , joi となる. 書名が joig である本を読んで返却する.このとき,スペースに積まれている本の書名は joi となる. よってビ太郎が読んだ本の書名 ioi , egoi , joig を順に改行区切りで出力する. 入力例 2 20 one READ two three four five six seven READ eight nine READ ten eleven READ READ twelve READ READ READ 出力例 2 one seven nine eleven ten twelve eight six 情報オリンピック日本委員会 作 『第 21 回日本情報オリンピック JOI 2021/2022 二次予選競技課題』
[ { "submission_id": "aoj_0719_10879893", "code_snippet": "#include<bits/stdc++.h>\n\nusing namespace std;\n\nint main () {\n int N;\n cin >> N;\n stack <string> s;\n vector <string> ans;\n for (int i = 0; i < N; i++) {\n string q;\n cin >> q;\n if (q == \"READ\") {\n ans.push_back(s.top());\n s.pop();\n }\n else {\n s.push(q);\n }\n }\n\n for (auto i : ans) cout << i << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 12036, "score_of_the_acc": -0.7542, "final_rank": 11 }, { "submission_id": "aoj_0719_10746580", "code_snippet": "#include <iostream>\n#include <stack>\n#include <string>\n#include <vector>\nusing namespace std;\n\nint main() {\n int Q;\n cin >> Q;\n\n stack<string> books;\n vector<string> output;\n\n string s;\n for (int i = 0; i < Q; i++) {\n cin >> s;\n if (s == \"READ\") {\n output.push_back(books.top());\n books.pop();\n } else {\n books.push(s);\n }\n }\n\n for (const string& title : output) {\n cout << title << '\\n';\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 30, "memory_kb": 12492, "score_of_the_acc": -0.4494, "final_rank": 6 }, { "submission_id": "aoj_0719_10298211", "code_snippet": "#include \"bits/stdc++.h\"\nusing namespace std;\nusing ll = long long;\nusing ld = long double;\nusing ull = unsigned long long;\n#define rep(i, m, n) for (ll i = (ll)m; i < (ll)n; i++)\n#define drep(i, m, n) for (ll i = m - 1; i >= n; i--)\n#define Endl endl\n#define all(a) a.begin(), a.end()\n#define pr(i, j) make_pair(i, j)\n#define isin(x, l, r) (l <= x && x < r)\n#define chmin(a, b) a = min(a, b)\n#define chmax(a, b) a = max(a, b)\n#define srt(ar) sort(ar.begin(), ar.end())\n#define rev(ar) reverse(ar.begin(), ar.end())\n#define jge(f, s, t) cout << (f ? s : t) << endl\n#pragma GCC target(\"avx2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n\n#define printar(ar) \\\n do \\\n { \\\n for (auto dbg : ar) \\\n { \\\n cout << dbg << \" \"; \\\n } \\\n cout << endl; \\\n } while (0)\nconst ll inf = 1e18;\nconst ld pi = 3.14159265358979;\nconst ld eps = 1e-9;\ntemplate <class T, ll n, ll idx = 0>\nauto make_vec(const ll (&d)[n], const T &init) noexcept\n{\n if constexpr (idx < n)\n return std::vector(d[idx], make_vec<T, n, idx + 1>(d, init));\n else\n return init;\n}\n\ntemplate <class T, ll n>\nauto make_vec(const ll (&d)[n]) noexcept\n{\n return make_vec(d, T{});\n}\n//////////////// 以下を貼る ////////////////\ntemplate <class T>\nsize_t HashCombine(const size_t seed, const T &v)\n{\n return seed ^ (std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2));\n}\n/* pair用 */\ntemplate <class T, class S>\nstruct std::hash<std::pair<T, S>>\n{\n size_t operator()(const std::pair<T, S> &keyval) const noexcept\n {\n return HashCombine(std::hash<T>()(keyval.first), keyval.second);\n }\n};\n////////////////////////////////////////////\nint main()\n{\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n ll q;\n cin >> q;\n stack<string> st;\n while (q--)\n {\n string s;\n cin >> s;\n if (s == \"READ\")\n {\n cout << st.top() << endl;\n st.pop();\n }\n else\n {\n st.push(s);\n }\n }\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 9856, "score_of_the_acc": -0.2297, "final_rank": 4 }, { "submission_id": "aoj_0719_10075339", "code_snippet": "#include <iostream>\n#include <stack>\n#include <string>\n\nint main()\n{\n int n;\n std::string s;\n std::stack<std::string> stk;\n std::cin >> n;\n while (n--) {\n std::cin >> s;\n if (s == \"READ\") {\n std::cout << stk.top() << std::endl;\n stk.pop();\n } else {\n stk.push(s);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9768, "score_of_the_acc": -0.5145, "final_rank": 7 }, { "submission_id": "aoj_0719_9962574", "code_snippet": "#include <iostream>\n#include <string>\n#include <stack>\n\nusing namespace std;\n\nint main()\n{\n int Q;\n string S;\n stack<string> book;\n\n cin >> Q;\n\n for (int i = 0; i < Q; i++) {\n cin >> S;\n\n if (S != \"READ\") {\n book.push(S);\n } else {\n cout << book.top() << endl;\n book.pop();\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 17328, "score_of_the_acc": -1.7251, "final_rank": 18 }, { "submission_id": "aoj_0719_9950170", "code_snippet": "#include <iostream>\n#include <stack>\nusing namespace std;\nint main(void){\n // Your code here!\n int i,j,a,b,n;\n stack<string> st;\n string s;\n cin >>n;\n for(i=0;i<n;i++){\n cin >> s;\n if(s==\"READ\"){\n cout << st.top() << endl;\n st.pop();\n }\n else st.push(s);\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 17316, "score_of_the_acc": -1.7239, "final_rank": 17 }, { "submission_id": "aoj_0719_9746849", "code_snippet": "#include <iostream>\n#include <sstream>\n#include <stack>\n#include <string>\n\nint main() {\n std::cin.tie(nullptr);\n std::ios_base::sync_with_stdio(false);\n std::ostringstream oss;\n std::stack<std::string> stk;\n int Q;\n std::string S;\n std::cin >> Q;\n while (Q--) {\n std::cin >> S;\n if (S == \"READ\") {\n oss << stk.top() << \"\\n\";\n stk.pop();\n } else {\n stk.push(S);\n }\n }\n std::cout << oss.str();\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9672, "score_of_the_acc": -0.0338, "final_rank": 3 }, { "submission_id": "aoj_0719_9711939", "code_snippet": "#include <iostream>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\nint main()\n{\n int Q;\n string S;\n vector<string> book;\n\n cin >> Q;\n\n for (int i = 0; i < Q; i++){\n cin >> S;\n if (S == \"READ\"){\n cout << book.back() << endl;\n book.pop_back();\n }\n else {\n book.push_back(S);\n }\n }\n\n return (0);\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 16948, "score_of_the_acc": -1.685, "final_rank": 15 }, { "submission_id": "aoj_0719_9570651", "code_snippet": "#include <bits/stdc++.h>\n\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\nusing namespace std;\nusing ll = long long;\nusing vc = vector<int>;\nusing vvc = vector<vector<int>>;\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\nconst long long INF = 1LL << 60;\n\n\nint main() {\n\n\tios::sync_with_stdio(false);\n\tstd::cin.tie(nullptr);\n\n int q;\n cin >> q;\n stack<string> stk;\n vector<string> ans(q);\n int cnt = 0;\n\n for (int i = 0; i < q; ++i) {\n string op;\n cin >> op;\n if (op == \"READ\") {\n if (!stk.empty()) {\n ans[cnt] = stk.top();\n stk.pop();\n ++cnt;\n }\n }\n else {\n stk.push(op);\n }\n }\n\n for (int i = 0; i < cnt; ++i) {\n cout << ans[i] << \"\\n\";\n }\n \n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 15772, "score_of_the_acc": -0.6784, "final_rank": 10 }, { "submission_id": "aoj_0719_8980676", "code_snippet": "#include <iostream>\n#include <stack>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned int Q, i;\n\tstring input;\n\tstack<string> books;\n\tcin >> Q;\n\n\tfor (i = 0; i != Q; ++i)\n\t{\n\t\tcin >> input;\n\t\tif (input[0] == 'R') cout << books.top() << '\\n', books.pop();\n\t\telse books.push(input);\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9584, "score_of_the_acc": -0.0245, "final_rank": 2 }, { "submission_id": "aoj_0719_8879609", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto Q=in();\n\tstack<string> S;\n\tLOOP(Q){\n\t\tauto T=in<string>();\n\t\tif(T==\"READ\"){\n\t\t\tout(S.top());\n\t\t\tS.pop();\n\t\t}\n\t\telse{\n\t\t\tS.push(T);\n\t\t}\n\t}\n\treturn 0;\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 9520, "score_of_the_acc": -0.3707, "final_rank": 5 }, { "submission_id": "aoj_0719_8661513", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\nusing ull=unsigned long long;\n#define REP(i,x) for(int i=0;i<(int)(x);i++)\n#define REP1(i,x) for(int i=1;i<=(int)(x);i++)\n#define REP2(i,s,e) for(int i=(int)(s);i<=(int)(e);i++)\n#define RREP(i,x) for(int i=((int)(x)-1);i>=0;i--)\n#define RREP1(i,x) for(int i=((int)(x));i>=1;i--)\n#define RREP2(i,s,e) for(int i=((int)(e));i>=(int)(s);i--)\n#define ALL(x) (x).begin(),(x).end()\n#define INF32 (1000001000)\n#define INF (4000000000000001000LL)\ntemplate<typename T> inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); }\ntemplate<typename T> inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); }\n#define endl '\\n'\n\nint main() {\n ll Q;\n cin >> Q;\n stack<string> stk;\n REP(i, Q) {\n string S;\n cin >> S;\n if (S == \"READ\") {\n cout << stk.top() << '\\n';\n stk.pop();\n } else {\n stk.push(S);\n }\n }\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 9656, "score_of_the_acc": -0.5615, "final_rank": 9 }, { "submission_id": "aoj_0719_8644529", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\n\n int q,k=0;\n string s,ans[300000];\n cin>>q;\n for(int i = 0;i < q;i++){\n cin>>s;\n if(s == \"READ\"){\n k--;\n cout<<ans[k]<<endl;\n }\n else{\n ans[k] = s;\n k++;\n }\n }\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 17852, "score_of_the_acc": -1.7805, "final_rank": 19 }, { "submission_id": "aoj_0719_8585169", "code_snippet": "#include <iostream>\nusing namespace std;\nint main(void){\n\n int n,j=0;\n string a[210000],b[210000];\n cin>>n;\n for(int i = 0;i < n;i++){\n cin>>a[i];\n if(a[i] == \"READ\"){\n cout<<b[j-1]<<endl;\n j--;\n }\n else{\n b[j] = a[i];\n j++;\n }\n }\n\nreturn 0;\n}", "accuracy": 1, "time_ms": 180, "memory_kb": 18816, "score_of_the_acc": -2, "final_rank": 20 }, { "submission_id": "aoj_0719_8543659", "code_snippet": "#include <algorithm>\n#include <array>\n#include <bitset>\n#include <cassert>\n#include <climits>\n#include <cmath>\n#include <complex>\n#include <cstdint>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <exception>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iostream>\n#include <map>\n#include <memory>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <vector>\n\nusing namespace std;\n\n\nusing ld = long double;\nusing ll = long long;\nusing ull = unsigned long long;\n\ntemplate<class T> using pq = priority_queue<T>;\ntemplate<class T> using pqg = priority_queue<T, vector<T>, greater<T>>;\n\ntemplate<class T, class U> inline bool chmin(T& a, const U& b) { if (a > b) { a = b; return 1; } return 0; }\ntemplate<class T, class U> inline bool chmax(T& a, const U& b) { if (a < b) { a = b; return 1; } return 0; }\n\ntemplate<class T> auto min(const T& a) { *min_elemenet(all(a)); }\ntemplate<class T> auto max(const T& a) { *max_elemenet(all(a)); }\n\nconst ll INF = 1 << 30;\nconst ll INFLL = 1LL << 60;\nconst ld EPS = 1e-9;\nconst ll MOD = 1e9 + 7;\n\n#define all(v) begin(v), end(v)\n\nstruct UnionFind {\n int n;\n vector<int> parent, siz;\n \n UnionFind(int n) : n(n) {\n parent.resize(n);\n siz.resize(n);\n \n for (int i = 0; i < n; ++i) {\n parent[i] = i;\n siz[i] = 1;\n }\n }\n \n int root(int x) {\n if (parent[x] == x) return x;\n return parent[x] = root(parent[x]);\n }\n \n bool unite(int x, int y) {\n x = root(x);\n y = root(y);\n \n if (x == y) return false;\n \n if (siz[x] < siz[y]) swap(x, y);\n parent[y] = x;\n siz[x] += siz[y];\n \n return true;\n }\n \n int same(int x, int y) {\n return root(x) == root(y);\n }\n \n int size(int x) {\n return siz[root(x)];\n }\n};\n\nint main(void) {\n int q;\n cin >> q;\n\n stack<string> st;\n\n while (q--) {\n string book;\n cin >> book;\n\n if (book == \"READ\") {\n cout << st.top() << endl;\n st.pop();\n } else {\n st.push(book);\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 90, "memory_kb": 9768, "score_of_the_acc": -0.5145, "final_rank": 7 }, { "submission_id": "aoj_0719_8434205", "code_snippet": "#include <iostream>\n#include <string>\nusing namespace std;\nint main(void){\n // Your code here!\n int N;\n cin >> N;\n string names[N];\n int count=0;\n string str;\n for(int i=0;i<N;i++){\n cin >> str;\n if (str!=\"READ\"){\n names[count]=str;\n count+=1;\n }else{\n count-=1;\n cout << names[count] << endl;\n }\n }\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 17200, "score_of_the_acc": -1.7116, "final_rank": 16 }, { "submission_id": "aoj_0719_8383812", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0719.cc: 図書館 2 (Library 2)\n */\n\n#include<cstdio>\n#include<string>\n#include<stack>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\n/* typedef */\n\n/* global variables */\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int tn;\n scanf(\"%d\", &tn);\n\n stack<string> q;\n\n while (tn--) {\n char s[16];\n scanf(\"%s\", s);\n string t(s);\n\n if (t == \"READ\") {\n string w = q.top(); q.pop();\n puts(w.c_str());\n }\n else\n q.push(t);\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 10, "memory_kb": 9352, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0719_8374333", "code_snippet": "#include<iostream>\nusing namespace std;\nint main(){\n \n int Q;\n cin >> Q;\n string S[Q];\n \n \n for(int i = 0 , j = 0; i < Q ; i++){\n cin >> S[i - 2*j];\n if(S[i - 2*j] == \"READ\"){\n j++;\n cout << S[i - (2*j - 1)] << endl;\n }\n }\n \n \n \n}", "accuracy": 1, "time_ms": 150, "memory_kb": 17212, "score_of_the_acc": -1.654, "final_rank": 13 }, { "submission_id": "aoj_0719_8374324", "code_snippet": "#include<iostream>\t\nusing namespace std;\t\nint main(){\t\n \t\n\tint Q;\n \tcin >> Q;\n \tstring S[Q];\n \tint R = 0; // READ の回数をカウント\n \t\n \tfor(int i = 0 ; i < Q ; i++){\n \tcin >> S[i - 2*R];\n \tif(S[i - 2*R] == \"READ\"){\n \tcout << S[i - 1 - 2*R] << endl;\n \tR++;\n }\t\n }\t\n \t\n}", "accuracy": 1, "time_ms": 150, "memory_kb": 17188, "score_of_the_acc": -1.6515, "final_rank": 12 }, { "submission_id": "aoj_0719_8346183", "code_snippet": "#include<iostream>\nusing namespace std;\nint main(){\n \n int Q;\n cin >> Q;\n string S[Q];\n \n \n for(int i = 0 , j = 0; i < Q ; i++){\n cin >> S[i - 2*j];\n if(S[i - 2*j] == \"READ\"){\n j++;\n cout << S[i - (2*j - 1)] << endl;\n }\n }\n \n \n \n}", "accuracy": 1, "time_ms": 150, "memory_kb": 17212, "score_of_the_acc": -1.654, "final_rank": 13 } ]
aoj_0731_cpp
投票 (Voting) 問題文 JOI 高校において,ある議題に関して「賛成」か「反対」かを問う採決が行われ, N 人の生徒が順番に投票を行った.生徒は自分の投票前に,それまでに投票した他の生徒がどちらに投票したかを知ることができた. i 番目 ( 1 ≦ i ≦ N ) に投票した生徒は,次の条件を満たしたとき「賛成」に投票し,満たさなかったとき「反対」に投票した. 直前に投票した X i 人の生徒,すなわち i - 1, i - 2, ..., i - X i 番目に投票した生徒のうち, Y i 人以上が「賛成」に投票した. ただし, Y i = 0 のときは他の生徒の投票に関わらず「賛成」に投票し, Y i = X i + 1 のときは他の生徒の投票に関わらず「反対」に投票したとする. 各生徒の投票についての情報が与えられたとき,「賛成」に投票した生徒の人数を求めるプログラムを作成せよ. 制約 1 ≦ N ≦ 500 000 . 0 ≦ X i ≦ i - 1 ( 1 ≦ i ≦ N ). 0 ≦ Y i ≦ X i + 1 ( 1 ≦ i ≦ N ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N X 1 Y 1 X 2 Y 2 : X N Y N 出力 標準出力に,「賛成」に投票した生徒の人数を 1 行で出力せよ. 入出力例 入力例 1 4 0 1 1 0 1 1 3 3 出力例 1 2 投票は,以下のように 4 人の生徒によって順番に行われた. 1 番目に投票した生徒は, Y 1 = X 1 + 1 であるため,「反対」に投票した. 2 番目に投票した生徒は, Y 2 = 0 であるため,「賛成」に投票した. 直前に投票した X 3 (= 1) 人の生徒のうち「賛成」に投票したのは 1 人で,これは Y 3 (= 1) 人以上である.そのため, 3 番目に投票した生徒は「賛成」に投票した. 直前に投票した X 4 (= 3) 人の生徒のうち「賛成」に投票したのは 2 人で,これは Y 4 (= 3) 人以上ではない.そのため, 4 番目に投票した生徒は「反対」に投票した. 「賛成」に投票した生徒は 2 人である.したがって, 2 を出力する. 入力例 2 5 0 0 1 1 2 3 3 1 4 3 出力例 2 4 入力例 3 10 0 0 1 2 1 1 1 0 3 1 2 3 1 1 5 3 8 4 7 2 出力例 3 4 情報オリンピック日本委員会 作 『日本情報オリンピック第2回女性部門 本選 競技課題』
[ { "submission_id": "aoj_0731_10880128", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include<utility>\n#include<set>\n#include<deque>\n#include <unordered_map>\n#include<string>\n#include<map>\n#include<cmath>\n\nusing namespace std;\n\n\n\nint main() {\n\tint N;\n\tcin >> N;\n\tvector<int>y(N + 1, 0), n(N + 1, 0);\n\n\tfor (int i = 1; i < N + 1; i++) {\n\t\tint X, Y;\n\t\tcin >> X >> Y;\n\t\tif (Y == 0) {\n\t\t\ty[i] = y[i-1]+1;\n\t\t\tn[i] = n[i - 1];\n\t\t\tcontinue;\n\t\t}\n\t\tif (Y == X + 1) {\n\t\t\ty[i] = y[i - 1];\n\t\t\tn[i] = n[i-1]+1;\n\t\t\tcontinue;\n\t\t}\n\t\tint p = y[i - 1] - y[i - 1 - X];\n\t\tif (p >= Y) {\n\t\t\tn[i] = n[i - 1];\n\t\t\ty[i] = y[i - 1] + 1;\n\t\t}\n\t\telse {\n\t\t\tn[i] = n[i - 1]+1;\n\t\t\ty[i] = y[i - 1];\n\t\t}\n\n\t}\n\n\tcout << y[N]<<endl;\n\t\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 7056, "score_of_the_acc": -0.9237, "final_rank": 11 }, { "submission_id": "aoj_0731_10339510", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nint main(){\n int n;\n cin >> n;\n vector<int> x(n+1),y(n+1);\n for(int i=1;i<n+1;i++){\n cin >> x[i] >> y[i];\n }\n vector<int> a(n+1,0);\n for(int i=1;i<n+1;i++){\n if(a[i-1]-a[i-x[i]-1]>=y[i]){\n a[i]=a[i-1]+1;\n }\n else{\n a[i]=a[i-1];\n }\n }\n cout << a[n] << endl;\n return 0;\n}", "accuracy": 1, "time_ms": 160, "memory_kb": 8916, "score_of_the_acc": -1.1124, "final_rank": 13 }, { "submission_id": "aoj_0731_9360977", "code_snippet": "#define NOMINMAX\n#define TEST_MODE true\n\n#define _CRT_SECURE_NO_WARNINGS\n#define _USE_MATH_DEFINES\n\n#include \"bits/stdc++.h\"\n\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(int)(n);++i)\n#define rep2(i,a,n) for(int i=a;i<(int)(n);++i)\n#define rrep(i,n) for(int i=(n)-1;i>=0;--i)\n#define reu(i,n) for(int i=1;i<=(int)(n);++i)\n\n#define chmax(a,b) (a=(a)<(b)?(b):(a))\n#define chmin(a,b) (a=(a)>(b)?(b):(a))\n\n#define ll long long\n#define all(a) begin(a),end(a)\n#define int long long\n\n#ifdef LOCAL_ENV\n#define dump(x) cerr<<#x<<\" : \"<<(x)<< \" \\t\"\n#define dumpl(x) dump(x)<<endl\n#define cerr_endl cerr<<endl\nofstream ofstream1(\"out.txt\");\n#define cout ofstream1\n\n#else\n#define dump(x) \n#define dumpl(x)\n#define cerr_endl \n#endif\n\n#define abp(o,a,b) cout<<(((o)?a:b))<<endl\n#define YEP(x) abp(x,\"YES\",\"NO\")\n#define Yep(x) abp(x,\"Yes\",\"No\")\n\nconst int inf = (int)1 << 60;\nll mod_n = (int)1e9 + 7;\n\nconst int MAX = (int)2e6 + 5;\nconst int MAX2 = 2005;\n\ntemplate<typename T>void ce_vector(vector<T> a) {\n#ifdef LOCAL_ENV\n\trep(i, a.size() - 1) cerr << a[i] << \" \"; cerr << a[a.size() - 1] << endl;\n#endif \n}\n\ntemplate<typename T>void ce_vector(vector<pair<T, T> > a) {\n#ifdef LOCAL_ENV\n\trep(i, a.size()) cerr << a[i].first << \",\" << a[i].second << \" \"; cerr << endl;\n#endif \n}\n\ntemplate<typename T>void o_vector(vector<T> a) {\n\tif (a.size() == 0) { cout << endl; return; }\n\trep(i, a.size() - 1) cout << a[i] << \" \"; cout << a[a.size() - 1] << endl;\n}\n\ntemplate<typename T>void o_vector(vector<pair<T, T> > a) { rep(i, a.size()) cout << a[i].first << \",\" << a[i].second << \" \"; cout << endl; }\n\nll pow_n(ll x, ll n) { ll r = 1; while (n > 0) { if (n & 1)r = (r * x) % mod_n; x = (x * x) % mod_n; n >>= 1; }return r; }\n\n\ntemplate<typename T>\nvector<T> in_vec(int n) {\n\tvector<T> a(n);\n\ta.resize(n);\n\trep(i, n) cin >> a[i];\n\treturn a;\n}\n\nint div_ceil(int a, int b) { int r = a / b; if (a % b != 0)r++; return r; }\n\nll modular(ll x) {\n\treturn ((x % mod_n + mod_n) % mod_n);\n}\n\n// end of template\n\nstruct Person {\n\tint pos, id;\n\n\tbool operator<(const Person& p) const {\n\t\treturn pos < p.pos;\n\t}\n};\n\n\nstruct Solver {\n\tvoid solve() {\n\t\tint n; cin >> n;\n\t\tint cnt = 0;\n\t\tvector<int> v(n + 5);\n\t\trep(i, n) {\n\t\t\tint x, y; cin >> x >> y;\n\t\t\tint recent = cnt - v[i - x];\n\t\t\tif (recent >= y) {\n\t\t\t\tcnt++;\n\t\t\t\tdumpl(i);\n\t\t\t}\n\t\t\tv[i + 1] = cnt;\n\t\t}\n\t\tcout << cnt << endl;\n\t}\n\n\n};\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nsigned main() {\n\tios::sync_with_stdio(false);\n\t//cin.tie(nullptr);\n\n\tcout << fixed << setprecision(2);\n\n\tSolver().solve();\n\n#ifdef LOCAL_ENV\n\tcout << endl;\n\tcerr << endl << \"\\x1b[7m ↓ \\x1b[0m\" << endl;\n\tsystem(\"type out.txt\");\n#endif\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 7044, "score_of_the_acc": -0.2755, "final_rank": 8 }, { "submission_id": "aoj_0731_8981236", "code_snippet": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main()\n{\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tunsigned int N, i, X, Y;\n\tcin >> N;\n\tvector<unsigned int> S(N + 1);\n\n\tS[0] = 0;\n\tfor (i = 0; i != N; ++i)\n\t{\n\t\tcin >> X >> Y;\n\t\tif (S[i] - S[i - X] >= Y) S[i + 1] = S[i] + 1;\n\t\telse S[i + 1] = S[i];\n\t}\n\n\tcout << S[N] << '\\n';\n\treturn 0;\n}", "accuracy": 1, "time_ms": 40, "memory_kb": 5180, "score_of_the_acc": -0.0276, "final_rank": 1 }, { "submission_id": "aoj_0731_8888726", "code_snippet": "#line 1 \"/opt/library/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing i64 = long long;\nusing u32 = unsigned int;\nusing u64 = unsigned long long;\nusing i128 = __int128;\nusing u128 = unsigned __int128;\nusing f128 = __float128;\n\ntemplate <class T>\nconstexpr T infty = 0;\ntemplate <>\nconstexpr int infty<int> = 1'000'001'000;\ntemplate <>\nconstexpr ll infty<ll> = ll(infty<int>) * infty<int> * 2;\ntemplate <>\nconstexpr u32 infty<u32> = infty<int>;\ntemplate <>\nconstexpr u64 infty<u64> = infty<ll>;\ntemplate <>\nconstexpr i128 infty<i128> = i128(infty<ll>) * infty<ll>;\ntemplate <>\nconstexpr double infty<double> = infty<ll>;\ntemplate <>\nconstexpr long double infty<long double> = infty<ll>;\n#define inf infty<ll>\n\nusing pi = pair<ll, ll>;\nusing vi = vector<ll>;\nusing vvi = vector<vector<ll>>;\ntemplate <class T>\nusing vc = vector<T>;\ntemplate <class T>\nusing vvc = vector<vc<T>>;\ntemplate <class T>\nusing vvvc = vector<vvc<T>>;\ntemplate <class T>\nusing vvvvc = vector<vvvc<T>>;\ntemplate <class T>\nusing vvvvvc = vector<vvvvc<T>>;\ntemplate <class T>\nusing pq = priority_queue<T>;\ntemplate <class T>\nusing pqg = priority_queue<T, vector<T>, greater<T>>;\n\n#define vv(type, name, h, ...) \\\n vector<vector<type>> name(h, vector<type>(__VA_ARGS__))\n#define vvv(type, name, h, w, ...) \\\n vector<vector<vector<type>>> name( \\\n h, vector<vector<type>>(w, vector<type>(__VA_ARGS__)))\n#define vvvv(type, name, a, b, c, ...) \\\n vector<vector<vector<vector<type>>>> name( \\\n a, vector<vector<vector<type>>>( \\\n b, vector<vector<type>>(c, vector<type>(__VA_ARGS__))))\n\n#define rep1(a) for (ll _ = 0; _ < (ll)(a); ++_)\n#define rep2(i, a) for (ll i = 0; i < (ll)(a); ++i)\n#define rep3(i, a, b) for (ll i = a; i < (ll)(b); ++i)\n#define rep4(i, a, b, c) for (ll i = a; i < (ll)(b); i += (c))\n#define rrep1(a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep2(i, a) for (ll i = (a)-1; i >= (ll)(0); --i)\n#define rrep3(i, a, b) for (ll i = (b)-1; i >= (ll)(a); --i)\n#define rrep4(i, a, b, c) for (ll i = (b)-1; i >= (ll)(a); i -= (c))\n#define overload4(a, b, c, d, e, ...) e\n#define rep(...) overload4(__VA_ARGS__, rep4, rep3, rep2, rep1)(__VA_ARGS__)\n#define rrep(...) overload4(__VA_ARGS__, rrep4, rrep3, rrep2, rrep1)(__VA_ARGS__)\n\n#define all(x) (x).begin(),(x).end()\n#define len(x) (ll)(x.size())\n#define elif else if\n#define bit(x, i) (((x)>>(i))&1)\n\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n\n#define stoi stoll\n#define abs llabs\n\n#define MIN(v) *min_element(all(v))\n#define MAX(v) *max_element(all(v))\n#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))\n#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))\n#define UNIQUE(x) \\\n sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()\n\nll popcnt(ll x) { return __builtin_popcountll(x); }\nll popcnt(u64 x) { return __builtin_popcountll(x); }\nll popcnt_mod_2(ll x) { return __builtin_parityll(x); }\nll popcnt_mod_2(u64 x) { return __builtin_parityll(x); }\nll topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }\nll lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\nll lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }\n\ntemplate<typename T> T SUM(const vector<T> &A) {\n T s = 0; for (auto &&a: A) s += a;\n return s;\n}\n\ntemplate<typename T> inline bool chmax(T &a, T b) {return ((a<b)?(a=b,true):(false));}\ntemplate<typename T> inline bool chmin(T &a, T b) {return ((a>b)?(a=b,true):(false));}\n\ninline void wt(const char c) { cout << c; }\ninline void wt(const string s) { cout << s; }\ninline void wt(const char *s) { cout << s; }\n\ntemplate <typename T>\nvoid wt_integer(T x) {\n if (x < 0) { cout << (i64)(x); }\n else { cout << (u64)(x); }\n}\ntemplate <typename T>\nvoid wt_real(T x) {\n cout << fixed << setprecision(15) << (long double)(x);\n}\n\ninline void wt(int x) { wt_integer(x); }\ninline void wt(ll x) { wt_integer(x); }\ninline void wt(i128 x) { wt_integer(x); }\ninline void wt(u32 x) { wt_integer(x); }\ninline void wt(u64 x) { wt_integer(x); }\ninline void wt(u128 x) { wt_integer(x); }\ninline void wt(double x) { wt_real(x); }\ninline void wt(long double x) { wt_real(x); }\ninline void wt(f128 x) { wt_real(x); }\n\ntemplate <class T, class U>\nvoid wt(const pair<T, U> val) {\n wt(val.first); wt(' '); wt(val.second);\n}\ntemplate <size_t N = 0, typename T>\nvoid wt_tuple(const T t) {\n if constexpr (N < std::tuple_size<T>::value) {\n if constexpr (N > 0) { wt(' '); }\n const auto x = std::get<N>(t);\n wt(x);\n wt_tuple<N + 1>(t);\n }\n}\ntemplate <class... T>\nvoid wt(tuple<T...> tpl) {\n wt_tuple(tpl);\n}\ntemplate <class T, size_t S>\nvoid wt(const array<T, S> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\ntemplate <class T>\nvoid wt(const vector<T> val) {\n auto n = val.size();\n for (size_t i = 0; i < n; i++) {\n if (i) wt(' ');\n wt(val[i]);\n }\n}\n\nvoid print() { wt('\\n'); }\ntemplate <class Head, class... Tail>\nvoid print(Head &&head, Tail &&... tail) {\n wt(head);\n if (sizeof...(Tail)) wt(' ');\n print(forward<Tail>(tail)...);\n}\n\nvoid YES(bool t = 1) { print(t ? \"YES\" : \"NO\"); }\nvoid NO(bool t = 1) { YES(!t); }\nvoid Yes(bool t = 1) { print(t ? \"Yes\" : \"No\"); }\nvoid No(bool t = 1) { Yes(!t); }\nvoid yes(bool t = 1) { print(t ? \"yes\" : \"no\"); }\nvoid no(bool t = 1) { yes(!t); }\nvoid onez(bool t = 1) { print(t ? 1 : 0); }\n#define endl '\\n'\n#define dump(x) {cerr << #x \" = \" << x << '\\n';}\n#line 2 \"main.cpp\"\n\nint solve();\nint main() {\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n while (!solve()) {break;}\n return 0;\n}\n\nint solve() {\n ll N;\n cin >> N;\n vi X(N+1), Y(N+1);\n rep(i, 1, N+1) cin >> X[i] >> Y[i];\n vi ag(N+1, 0);\n rep(i, 1, N+1) {\n ag[i] = ag[i-1];\n if (Y[i] == 0) {\n ag[i]++;\n } elif (Y[i] != X[i]+1) {\n if (ag[i-1]-ag[i-1-X[i]] >= Y[i]) ag[i]++;\n }\n }\n print(ag[N]);\n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 14768, "score_of_the_acc": -1.0588, "final_rank": 12 }, { "submission_id": "aoj_0731_8879714", "code_snippet": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(ll i=0;i<(num);++i)\n#define FOR(i,c,num) for(ll (i)=(c);(i)<(num);++(i))\n#define LOOP(i) while(i--)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto pitr=c.begin();pitr!=c.end();++pitr){cout<<*pitr;if(next(pitr,1)!=c.end())cout<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing vll = vector<ll>;\nusing vvll = vector<vector<ll>>;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=ll>\nT in(){ T x; cin >> x; return (x); }\ntemplate<typename T=ll,typename C=vector<T>>\nC vecin(int N){ C x(N);REP(i,N){ x[i]=in<T>(); }return x; }\ntemplate<typename T=ll,size_t N>\narray<T,N> arrin(){array<T,N> x;REP(i,N){ x[i]=in<T>(); }return x;}\n\nvoid vout(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){ cout << ' ' << h;vout(forward<Tail>(t)...); }\nvoid out(){ cout << endl; }\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){ cout << h;vout(forward<Tail>(t)...); }\n\ntemplate<typename T>\nbool chmax(T& a,T b){ if(a<b){ a=b;return true; }return false; }\ntemplate<typename T>\nbool chmin(T& a,T b){ if(a>b){ a=b;return true; }return false; }\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\n\tauto N=in();\n\tvll S(N+1,0);\n\tREP(i,N){\n\t\tauto X=in(),Y=in();\n\t\tif(!Y){\n\t\t\tS[i+1]=S[i]+1;\n\t\t}\n\t\telse if(Y==X+1){\n\t\t\tS[i+1]=S[i];\n\t\t}\n\t\telse{\n\t\t\tauto Z=S[i]-S[i-X];\n\t\t\tif(Z>=Y) S[i+1]=S[i]+1;\n\t\t\telse S[i+1]=S[i];\n\t\t}\n\t}\n\tout(S[N]);\n\treturn 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6936, "score_of_the_acc": -0.2645, "final_rank": 6 }, { "submission_id": "aoj_0731_8384232", "code_snippet": "/* -*- coding: utf-8 -*-\n *\n * 0731.cc: 投票 (Voting)\n */\n\n#include<cstdio>\n#include<algorithm>\n \nusing namespace std;\n\n/* constant */\n\nconst int MAX_N = 500000;\n\n/* typedef */\n\n/* global variables */\n\nint css[MAX_N + 1];\n\n/* subroutines */\n\n/* main */\n\nint main() {\n int n;\n scanf(\"%d\", &n);\n\n for (int i = 0; i < n; i++) {\n int xi, yi;\n scanf(\"%d%d\", &xi, &yi);\n\n int d = (yi == 0 || css[i] - css[max(0, i - xi)] >= yi) ? 1 : 0;\n css[i + 1] = css[i] + d;\n }\n\n printf(\"%d\\n\", css[n]);\n \n return 0;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 4908, "score_of_the_acc": -0.0588, "final_rank": 2 }, { "submission_id": "aoj_0731_8322587", "code_snippet": "#include<iostream>\nusing namespace std;\nint main(){\n \n int N;\n cin >> N;\n int X[N + 1] , Y[N + 1] , V[N + 1];\n \n for(int i = 0 ; i < N + 1 ; i++){\n V[i] = 0; \n }\n \n \n for(int i = 1 ; i < N + 1 ; i++){\n cin >> X[i] >> Y[i];\n if(Y[i] == 0){\n V[i] = V[i - 1] + 1;\n }else if(Y[i] == V[i - 1] - V[i - 1 - X[i]] || Y[i] < V[i - 1] - V[i - 1 - X[i]] + 1){\n V[i] = V[i - 1] + 1;\n }else{\n V[i] = V[i - 1];\n }\n }\n \n\n cout << V[N] << endl;\n \n\n}", "accuracy": 1, "time_ms": 210, "memory_kb": 8992, "score_of_the_acc": -1.4142, "final_rank": 14 }, { "submission_id": "aoj_0731_7995520", "code_snippet": "#include <bits/stdc++.h>\n#include <random>\nusing namespace std;\nusing ll = long long;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing vvvll = vector<vvll>;\n#define all(A) A.begin(),A.end()\n#define ALL(A) A.begin(),A.end()\n#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)\n\nint main() {\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N;\n cin>>N;\n vll S(N+1,0);\n rep(i,N){\n ll X,Y;\n cin>>X>>Y;\n if(Y==0){\n S[i+1]=S[i]+1;\n }\n else if(Y==X+1){\n S[i+1]=S[i];\n }\n else if(S[i]-S[i-X]>=Y)S[i+1]=S[i]+1;\n else S[i+1]=S[i];\n }\n cout<<S[N]<<endl;\n\n\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 6964, "score_of_the_acc": -0.2673, "final_rank": 7 }, { "submission_id": "aoj_0731_7977743", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n; cin >> n;\n vector<int> s(n+1);\n for(int i=1;i<=n;i++){\n int x,y; cin >> x >> y;\n int ad = (s[i-1]-s[i-1-x] >= y);\n s[i] = s[i-1] + ad;\n }\n cout << s[n] << endl;\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 5188, "score_of_the_acc": -0.0872, "final_rank": 3 }, { "submission_id": "aoj_0731_7911968", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n#define SIZE 500005\n\nint A[SIZE];\n\nint main(){\n\n\tint N;\n\tscanf(\"%d\",&N);\n\n\tint X,Y;\n\tint sumOK = 0;\n\n\tfor(int i = 1; i <= N; i++){\n\n\t\tscanf(\"%d %d\",&X,&Y);\n\n\t\tint R = A[i-1];\n\t\tint L = A[i-X-1];\n\n\t\tint numOK = R-L;\n\t\tif(numOK >= Y){\n\n\t\t\tsumOK++;\n\n\t\t}\n\t\tA[i] = sumOK;\n\t}\n\n\tprintf(\"%d\\n\",sumOK);\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 60, "memory_kb": 5180, "score_of_the_acc": -0.1452, "final_rank": 4 }, { "submission_id": "aoj_0731_7875912", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nbool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nbool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr int MOD = 1000000007;\nconstexpr int MOD_N = 998244353;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/math/pow.hpp\"\n\nstd::int64_t safe_mod(std::int64_t a, std::int64_t mod) {\n a %= mod;\n return a >= 0 ? a : a + mod;\n}\n\nstd::int64_t pow_int(std::int64_t a, std::int64_t n) {\n assert(n >= 0);\n std::int64_t res = 1, mul = a;\n for (; n > 0; n >>= 1) {\n if (n & 1) res *= mul;\n mul *= mul;\n }\n return res;\n}\n\nstd::int64_t inv_mod(std::int64_t a, std::int64_t mod) {\n std::int64_t b = mod, u = 1, v = 0, t;\n while (b > 0) {\n t = a / b;\n std::swap(a -= t * b, b);\n std::swap(u -= t * v, v);\n }\n return u >= 0 ? u % mod : (mod - (-u) % mod) % mod;\n}\n\nstd::int64_t pow_mod(std::int64_t a, std::int64_t n, std::int64_t mod) {\n if (n < 0) return inv_mod(pow_mod(a, -n, mod), mod);\n std::int64_t res = 1, mul = safe_mod(a, mod);\n for (; n > 0; n >>= 1) {\n if (n & 1) (res *= mul) %= mod;\n (mul *= mul) %= mod;\n }\n return res;\n}\n\nint ceil_pow2(std::int64_t n) {\n int x = 0;\n while ((std::uint64_t(1) << x) < (std::uint64_t)(n)) ++x;\n return x;\n}\n\nint floor_pow2(std::int64_t n) {\n int x = 0;\n while ((std::uint64_t(1) << (x + 1)) <= (std::uint64_t)(n)) ++x;\n return x;\n}\n#line 3 \"/home/kuhaku/home/github/algo/lib/segment_tree/monoid.hpp\"\n\ntemplate <class T>\nstruct Add {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs + rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs + rhs;\n }\n};\n\ntemplate <class T>\nstruct And {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return lhs & rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs & rhs;\n }\n};\n\ntemplate <class T>\nstruct Or {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs | rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs | rhs;\n }\n};\n\ntemplate <class T>\nstruct Xor {\n using value_type = T;\n static constexpr T id = T(0);\n static constexpr T op(const T &lhs, const T &rhs) { return lhs ^ rhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs ^ rhs;\n }\n};\n\ntemplate <class T>\nstruct Min {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return std::min(lhs, rhs); }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return std::min((U)lhs, rhs);\n }\n};\n\ntemplate <class T>\nstruct Max {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::min();\n static constexpr T op(const T &lhs, const T &rhs) { return std::max(lhs, rhs); }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return std::max((U)lhs, rhs);\n }\n};\n\ntemplate <class T>\nstruct Update {\n using value_type = T;\n static constexpr T id = std::numeric_limits<T>::max();\n static constexpr T op(const T &lhs, const T &rhs) { return lhs == Update::id ? rhs : lhs; }\n\n template <class U>\n static constexpr U f(T lhs, U rhs) {\n return lhs == Update::id ? rhs : lhs;\n }\n};\n\ntemplate <class T>\nstruct Affine {\n using value_type = std::pair<T, T>;\n static constexpr std::pair<T, T> id = std::pair<T, T>(1, 0);\n static constexpr std::pair<T, T> op(std::pair<T, T> lhs, std::pair<T, T> rhs) {\n return {lhs.first * rhs.first, lhs.first * rhs.second + lhs.second};\n }\n};\n\ntemplate <class M>\nstruct Rev {\n using T = typename M::value_type;\n using value_type = T;\n static constexpr T id = M::id;\n static constexpr T op(T lhs, T rhs) { return M::op(rhs, lhs); }\n};\n#line 5 \"/home/kuhaku/home/github/algo/lib/segment_tree/segment_tree.hpp\"\n\n/**\n * @brief セグメント木\n * @see https://noshi91.hatenablog.com/entry/2020/04/22/212649\n *\n * @tparam M モノイド\n */\ntemplate <class M>\nstruct segment_tree {\n private:\n using T = typename M::value_type;\n\n public:\n segment_tree() : segment_tree(0) {}\n explicit segment_tree(int n, T e = M::id) : segment_tree(std::vector<T>(n, e)) {}\n template <class U>\n explicit segment_tree(const std::vector<U> &v) : _n(v.size()) {\n this->_log = ceil_pow2(this->_n);\n this->_size = 1 << this->_log;\n this->data = std::vector<T>(this->_size << 1, M::id);\n for (int i = 0; i < this->_n; ++i) this->data[this->_size + i] = T(v[i]);\n for (int i = this->_size - 1; i >= 1; --i) this->update(i);\n }\n\n const T &operator[](int k) const { return this->data[k + this->_size]; }\n T at(int k) const { return this->operator[](k); }\n T get(int k) const { return this->operator[](k); }\n\n void set(int k, T val) {\n assert(0 <= k && k < this->_n);\n k += this->_size;\n this->data[k] = val;\n for (int i = 1; i <= this->_log; ++i) this->update(k >> i);\n }\n void reset(int k) { this->set(k, M::id); }\n\n T all_prod() const { return this->data[1]; }\n T prod(int a, int b) const {\n assert(0 <= a && b <= this->_n);\n T l = M::id, r = M::id;\n for (a += this->_size, b += this->_size; a < b; a >>= 1, b >>= 1) {\n if (a & 1) l = M::op(l, this->data[a++]);\n if (b & 1) r = M::op(this->data[--b], r);\n }\n return M::op(l, r);\n }\n\n template <class F>\n int max_right(F f) const {\n return this->max_right(0, f);\n }\n\n template <class F>\n int max_right(int l, F f) const {\n assert(0 <= l && l <= this->_n);\n assert(f(M::id));\n if (l == this->_n) return this->_n;\n l += this->_size;\n T sm = M::id;\n do {\n while (l % 2 == 0) l >>= 1;\n if (!f(M::op(sm, this->data[l]))) {\n while (l < this->_size) {\n l = (2 * l);\n if (f(M::op(sm, this->data[l]))) {\n sm = M::op(sm, this->data[l]);\n l++;\n }\n }\n return l - this->_size;\n }\n sm = M::op(sm, this->data[l]);\n l++;\n } while ((l & -l) != l);\n return this->_n;\n }\n\n int max_right(T x) const { return this->max_right(0, x); }\n\n int max_right(int l, T x) const {\n return this->max_right(l, [&x](auto y) {\n return !(y < x);\n });\n }\n\n template <class F>\n int min_left(F f) const {\n return this->min_left(this->_n, f);\n }\n\n template <class F>\n int min_left(int r, F f) const {\n assert(0 <= r && r <= this->_n);\n assert(f(M::id));\n if (r == 0) return 0;\n r += this->_size;\n T sm = M::id;\n do {\n r--;\n while (r > 1 && (r % 2)) r >>= 1;\n if (!f(M::op(this->data[r], sm))) {\n while (r < this->_size) {\n r = (2 * r + 1);\n if (f(M::op(this->data[r], sm))) {\n sm = M::op(this->data[r], sm);\n r--;\n }\n }\n return r + 1 - this->_size;\n }\n sm = M::op(this->data[r], sm);\n } while ((r & -r) != r);\n return 0;\n }\n\n int min_left(T x) const { return this->min_left(this->_n, x); }\n\n int min_left(int r, T x) const {\n return this->min_left(r, [&x](auto y) {\n return !(y < x);\n });\n }\n\n private:\n int _n, _size, _log;\n std::vector<T> data;\n\n void update(int k) { this->data[k] = M::op(this->data[2 * k], this->data[2 * k + 1]); }\n};\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid setp(int n) {\n std::cout << std::fixed << std::setprecision(n);\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n;\n cin >> n;\n segment_tree<Add<int>> st(n);\n rep (i, n) {\n int x, y;\n cin >> x >> y;\n if (st.prod(i - x, i) >= y)\n st.set(i, 1);\n }\n cout << st.all_prod() << endl;\n\n return 0;\n}", "accuracy": 1, "time_ms": 100, "memory_kb": 9088, "score_of_the_acc": -0.7769, "final_rank": 10 }, { "submission_id": "aoj_0731_7851957", "code_snippet": "#include <bits/extc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n\ntemplate <class T> using Max_Heap = __gnu_pbds::priority_queue<T, less<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Min_Heap = __gnu_pbds::priority_queue<T, greater<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = __gnu_pbds::gp_hash_table<K, V>;\ntemplate <class T> using Rope = __gnu_cxx::rope<T>;\nusing Trie = __gnu_pbds::trie<string, __gnu_pbds::null_type, __gnu_pbds::trie_string_access_traits<>, __gnu_pbds::pat_trie_tag, __gnu_pbds::trie_prefix_search_node_update>;\n\ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n;\n cin >> n;\n\n assert(1 <= n && n <= 500000);\n\n vector<int> x(n), y(n);\n\n for (int i = 0; i < n; ++i) {\n cin >> x[i] >> y[i];\n assert(0 <= x[i] && x[i] <= i);\n assert(0 <= y[i] && y[i] <= x[i] + 1);\n }\n\n vector<int> cum(n + 1);\n\n for (int i = 1; i <= n; ++i) {\n if (cum[i - 1] - cum[max(0, i - x[i - 1] - 1)] >= y[i - 1]) {\n cum[i] = 1;\n }\n cum[i] += cum[i - 1];\n }\n\n cout << cum[n] << '\\n';\n\n return (0);\n}", "accuracy": 1, "time_ms": 50, "memory_kb": 8892, "score_of_the_acc": -0.4629, "final_rank": 9 }, { "submission_id": "aoj_0731_7848633", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\n\ntemplate <class T> struct fenwick_tree {\n using U = T;\n\n public:\n fenwick_tree() : _n(0) {}\n fenwick_tree(int n) : _n(n), data(n) {}\n\n void add(int p, T x) {\n assert(0 <= p && p < _n);\n p++;\n while (p <= _n) {\n data[p - 1] += U(x);\n p += p & -p;\n }\n }\n\n T sum(int l, int r) {\n assert(0 <= l && l <= r && r <= _n);\n return sum(r) - sum(l);\n }\n\n private:\n int _n;\n std::vector<U> data;\n\n U sum(int r) {\n U s = 0;\n while (r > 0) {\n s += data[r - 1];\n r -= r & -r;\n }\n return s;\n }\n};\n\nint main(){\n INT(n);\n fenwick_tree<int> fw(n);\n for(int i=0;i<n;i++){\n INT(x,y);\n if(fw.sum(i-x,i)>=y)fw.add(i,1);\n }\n out(fw.sum(0,n));\n}", "accuracy": 1, "time_ms": 70, "memory_kb": 4924, "score_of_the_acc": -0.1781, "final_rank": 5 } ]
aoj_0734_cpp
タクシー 2 (Taxis 2) 問題文 IOI 国には, 1 から N までの番号が付けられた N 個の町と, 1 から M までの番号が付けられた M 本の道がある. それぞれの道は,タクシーでのみ通行可能である.道 i ( 1 ≦ i ≦ M ) のタクシーは町 A i と町 B i を 双方向に 移動でき,そのタクシーの色は, C i = 1 のとき赤色, C i = 2 のとき青色である.タクシーには料金がかかり,乗車すると以下のように所持金が変化する. 乗車前の所持金を a 円とする. タクシーが赤色の場合,乗車後の所持金が a - 1 円になる. タクシーが青色の場合,乗車後の所持金が「 a ÷ 2 を整数に切り捨てた値」円になる. あなたは IOI 国の町 1 に住んでおり,以下の Q 個の質問の答えを知っておきたい. j 番目 ( 1 ≦ j ≦ Q ) の質問は以下の通りである. 町 1 から出発し, 1 円以上の所持金を残した状態で 町 T j に到着するために,最初に少なくとも何円の所持金を持っている必要があるか.ただし,答えが L 円よりも大きい場合は,代わりに Large と答えよ. 町とタクシーの情報,そして質問の内容が与えられたとき,すべての質問に答えるプログラムを作成せよ. 制約 2 ≦ N ≦ 200000 . N - 1 ≦ M ≦ 200000 . 1 ≦ Q ≦ 200000 . 1 ≦ L ≦ 1 000 000 000 . 1 ≦ A i < B i ≦ N ( 1 ≦ i ≦ M ). (A i , B i ) ≠ (A j , B j ) ( 1 ≦ i < j ≦ M ). 1 ≦ C i ≦ 2 ( 1 ≦ i ≦ M ). 2 ≦ T j ≦ N ( 1 ≦ j ≦ Q ). どの町の間も,いくつかの道を通って行き来できる. 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N M Q L A 1 B 1 C 1 A 2 B 2 C 2 : A M B M C M T 1 T 2 : T Q 出力 標準出力に Q 行で出力せよ. j 行目 ( 1 ≦ j ≦ Q ) には, j 番目の質問の答えを出力せよ. 入出力例 入力例 1 7 6 1 10 1 2 2 2 3 1 3 4 2 4 5 1 5 6 1 6 7 2 5 出力例 1 10 町 1 → 町 2 → 町 3 → 町 4 → 町 5 の経路で移動するならば,順に青,赤,青,赤のタクシーに乗ることになる.すると,最初に所持金が 10 円あった場合,所持金は 10 円 → 5 円 → 4 円 → 2 円 → 1 円となり, 1 円以上を残した状態で町 5 に到着できる. 一方,最初の所持金が 9 円以下の場合, 1 円以上を残した状態で町 5 に到着することはできない. 入力例 2 10 9 3 25 1 2 2 2 3 1 3 4 1 4 5 1 5 6 2 6 7 1 7 8 1 8 9 1 9 10 2 10 9 3 出力例 2 Large 22 4 例えば, 1 番目の質問について考えよう. 町 1 から出発して町 10 に移動するとき,町 1 → 町 2 → … → 町 9 → 町 10 の経路をたどることになる.しかし,最初に L (= 25) 円持っていたとしても,タクシーを使うごとに所持金が 25 円 → 12 円 → 11 円 → 10 円 → … と減っていき, 1 円以上を残して町 10 にたどり着くことはできない.よって, Large と出力しなければならない. 入力例 3 5 6 1 1000000000 1 4 1 1 5 1 4 5 1 3 4 1 3 5 1 2 3 1 2 出力例 3 4 町 1 → 町 5 → 町 3 → 町 2 の経路で移動するならば,赤いタクシーに 3 回乗ることになる.すると,最初に所持金が 4 円あった場合,所持金は 4 円 → 3 円 → 2 円 → 1 円となり, 1 円以上を残した状態で町 2 に到着できる. 一方,最初の所持金が 3 円以下の場合, 1 円以上を残した状態で町 2 に到着することはできない. 入力例 4 9 11 5 10 1 2 1 1 3 2 2 3 2 2 9 2 3 9 1 4 9 1 8 9 1 5 8 1 5 7 1 4 7 2 6 7 2 2 6 7 8 9 出力例 4 2 Large 7 5 3 情報オリンピック日本委員会 作 『日本情報オリンピック第2回女性部門 本選 競技課題』
[ { "submission_id": "aoj_0734_10586537", "code_snippet": "#include <vector>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nclass edge {\npublic:\n\tint to, color;\n\tedge() : to(-1), color(-1) {};\n\tedge(int to_, int color_) : to(to_), color(color_) {};\n};\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tint N, M, Q, L;\n\tcin >> N >> M >> Q >> L;\n\tvector<int> A(M), B(M), C(M), T(Q);\n\tfor (int i = 0; i < M; i++) {\n\t\tcin >> A[i] >> B[i] >> C[i];\n\t\tA[i]--, B[i]--;\n\t}\n\tfor (int i = 0; i < Q; i++) {\n\t\tcin >> T[i];\n\t\tT[i]--;\n\t}\n\t\n\tstd::vector<int> sep(N + 2);\n\tfor (int i = 0; i < M; i++) {\n\t\tsep[A[i] + 2]++;\n\t\tsep[B[i] + 2]++;\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tsep[i + 2] += sep[i + 1];\n\t}\n\tstd::vector<edge> edges(2 * M);\n\tfor (int i = 0; i < M; i++) {\n\t\tedges[sep[A[i] + 1]++] = edge(B[i], C[i]);\n\t\tedges[sep[B[i] + 1]++] = edge(A[i], C[i]);\n\t}\n\n\tconst int LAYERS = 30;\n\tvector<vector<int> > dist(LAYERS, vector<int>(N, L + 1));\n\tvector<vector<int> > order(LAYERS, vector<int>(N + 1, -1));\n\tdist[0][0] = 1;\n\torder[0][0] = 0;\n\tfor (int layer = 0; layer < LAYERS; layer++) {\n\t\tvector<int> que(2 * N);\n\t\tvector<bool> visited(N, false);\n\t\tint ql = 0, qr = 0;\n\t\tint ord_index = 0;\n\t\tint nord_index = 0;\n\t\twhile (true) {\n\t\t\tint u = order[layer][ord_index];\n\t\t\tint acost = (u != -1 ? dist[layer][u] : L + 1);\n\t\t\tint bcost = (ql != qr ? dist[layer][que[ql]] : L + 1);\n\t\t\tint ncost = min(acost, bcost) + (1 << layer);\n\t\t\tif (ncost > L) break;\n\t\t\tif (acost > bcost) u = que[ql++];\n\t\t\telse ord_index++;\n\t\t\tif (visited[u]) continue;\n\t\t\tvisited[u] = true;\n\t\t\tfor (int i = sep[u]; i < sep[u + 1]; i++) {\n\t\t\t\tedge& e = edges[i];\n\t\t\t\tif (e.color == 1 && dist[layer][e.to] > ncost) {\n\t\t\t\t\tdist[layer][e.to] = ncost;\n\t\t\t\t\tque[qr++] = e.to;\n\t\t\t\t}\n\t\t\t\tif (e.color == 2 && layer != LAYERS - 1 && dist[layer + 1][e.to] == L + 1) {\n\t\t\t\t\tdist[layer + 1][e.to] = ncost;\n\t\t\t\t\torder[layer + 1][nord_index++] = e.to;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\t\n\t\n\tfor (int i = 0; i < Q; i++) {\n\t\tint answer = L + 1;\n\t\tfor (int j = 0; j < LAYERS; j++) {\n\t\t\tanswer = min(answer, dist[j][T[i]]);\n\t\t}\n\t\tif (answer <= L) {\n\t\t\tcout << answer << '\\n';\n\t\t}\n\t\telse {\n\t\t\tcout << \"Large\" << '\\n';\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 190, "memory_kb": 59384, "score_of_the_acc": 0, "final_rank": 1 }, { "submission_id": "aoj_0734_10125274", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define all(A) A.begin(),A.end()\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n\n ll N,M,Q,L;\n cin>>N>>M>>Q>>L;\n vector<vector<int>> G(N),H(N);\n rep(i,M){\n int a,b,c;\n cin>>a>>b>>c;\n a--;b--;\n if(c==1){\n G[a].push_back(b);\n G[b].push_back(a);\n }\n else{\n H[a].push_back(b);\n H[b].push_back(a);\n }\n } \n vector<vector<ll>> D(N,vector<ll>(32,1e9+10));\n D[0][0]=1;\n priority_queue<array<ll,3>,vector<array<ll,3>>,greater<array<ll,3>>> que;\n que.push({1,0,0});\n vector<vector<bool>> seen(N,vector<bool>(32,0));\n while(!que.empty()){\n auto V=que.top();\n que.pop();\n if(seen[V[1]][V[2]])continue;\n seen[V[1]][V[2]]=1;\n for(int v:G[V[1]]){\n if(D[v][V[2]]>V[0]+(1ll<<V[2])){\n D[v][V[2]]=V[0]+(1ll<<V[2]);\n que.push({D[v][V[2]],v,V[2]});\n }\n }\n if(V[2]==31)continue;\n for(int v:H[V[1]]){\n if(D[v][V[2]+1]>V[0]+(1ll<<V[2])){\n D[v][V[2]+1]=V[0]+(1ll<<V[2]);\n que.push({D[v][V[2]+1],v,V[2]+1});\n }\n }\n }\n // rep(i,N)rep(j,3)cout<<i<<\" \"<<j<<\" \"<<D[i][j]<<endl;\n rep(q,Q){\n ll T;\n cin>>T;\n T--;\n ll an=L+1;\n rep(j,32)an=min(an,D[T][j]);\n if(an>L)cout<<\"Large\\n\";\n else cout<<an<<\"\\n\";\n }\n \n}", "accuracy": 1, "time_ms": 2140, "memory_kb": 93544, "score_of_the_acc": -1.3629, "final_rank": 6 }, { "submission_id": "aoj_0734_9552365", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n\n#define chmin(x,y) x = min(x,y) // xをyと比較して小さい方に更新\n#define chmax(x,y) x = max(x,y) // xをyと比較して大きい方に更新\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000LL // オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n#define SIZE 200005\n#define MAX 30\n\nll POW[MAX+1];\n\nstruct Edge {\n int to;\n bool isBlue;\n\n Edge(int arg_to, bool arg_isBlue) : to(arg_to), isBlue(arg_isBlue) {}\n};\n\nstruct State {\n int node, count;\n ll sum_dist;\n\n State(int arg_node, int arg_count, ll arg_sum_dist) \n : node(arg_node), count(arg_count), sum_dist(arg_sum_dist) {}\n\n State() : node(0), count(0), sum_dist(0) {}\n\n // 優先度キューで最小の距離を得るための比較関数\n bool operator<(const State& arg) const {\n return sum_dist > arg.sum_dist;\n }\n};\n\nll min_dist[MAX+1][SIZE];\nvector<Edge> G[SIZE];\n\nint main() {\n // 2の累乗のテーブルを作成\n POW[0] = 1;\n for (int i = 1; i <= MAX; i++) {\n POW[i] = POW[i-1] * 2;\n }\n\n int N, M, numQ;\n scanf(\"%d %d %d\", &N, &M, &numQ);\n\n ll L;\n scanf(\"%lld\", &L);\n\n int a, b, c;\n for (int i = 0; i < M; i++) {\n scanf(\"%d %d %d\", &a, &b, &c);\n a--;\n b--;\n G[a].emplace_back(b, c == 2); // 青い辺かどうかを判定\n G[b].emplace_back(a, c == 2); // 無向グラフ\n }\n\n // 初期化: すべての最小距離を無限大に設定\n for (int i = 0; i <= MAX; i++) {\n for (int k = 0; k < N; k++) {\n min_dist[i][k] = HUGE_NUM;\n }\n }\n\n min_dist[0][0] = 1; // 初期状態: 青い辺を通らずにスタート地点にいる場合の最小コスト\n\n priority_queue<State> Q;\n Q.emplace(0, 0, 1); // 初期状態をキューにプッシュ\n\n while (!Q.empty()) {\n State state = Q.top();\n Q.pop();\n\n if (state.sum_dist > min_dist[state.count][state.node]) continue;\n\n for (const auto& edge : G[state.node]) {\n int next_node = edge.to;\n ll next_dist = state.sum_dist + POW[state.count];\n if (next_dist > L) continue; // 制約条件を満たさない場合はスキップ\n\n int next_count = state.count;\n if (edge.isBlue) {\n next_count++; // 青い辺を通った回数を更新\n }\n\n if (min_dist[next_count][next_node] > next_dist) {\n min_dist[next_count][next_node] = next_dist;\n Q.emplace(next_node, next_count, next_dist);\n }\n }\n }\n\n int tmp_node;\n for (int loop = 0; loop < numQ; loop++) {\n scanf(\"%d\", &tmp_node);\n tmp_node--;\n\n ll ans = HUGE_NUM;\n for (int i = 0; i <= MAX; i++) {\n chmin(ans, min_dist[i][tmp_node]);\n }\n\n if (ans == HUGE_NUM) {\n printf(\"Large\\n\"); // 到達不可能の場合\n } else {\n printf(\"%lld\\n\", ans); // 最小コストを出力\n }\n }\n\n return 0;\n}", "accuracy": 1, "time_ms": 810, "memory_kb": 68472, "score_of_the_acc": -0.4132, "final_rank": 2 }, { "submission_id": "aoj_0734_8013004", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 200005\n#define MAX 30\n\nll POW[MAX+1];\n\nstruct Edge{\n\tEdge(int arg_to,bool arg_isBlue){\n\t\tto = arg_to;\n\t\tisBlue = arg_isBlue;\n\t}\n\n\tint to;\n\tbool isBlue;\n};\n\nstruct State{\n\tState(int arg_node,int arg_count,ll arg_sum_dist){\n\t\tnode = arg_node;\n\t\tcount = arg_count;\n\t\tsum_dist = arg_sum_dist;\n\t}\n\tState(){\n\n\t\tnode = count = 0;\n\t\tsum_dist = 0;\n\t}\n\tbool operator<(const struct State& arg) const{\n\n\t\treturn sum_dist > arg.sum_dist;\n\t}\n\tint node,count;\n\tll sum_dist;\n\n};\n\nll min_dist[MAX+1][SIZE];\nvector<Edge> G[SIZE];\n\n\nint main(){\n\n\tPOW[0] = 1;\n\tfor(int i = 1; i <= MAX; i++){\n\n\t\tPOW[i] = POW[i-1]*2;\n\t}\n\n\tint N,M,numQ;\n\tscanf(\"%d %d %d\",&N,&M,&numQ);\n\n\tll L;\n\tscanf(\"%lld\",&L);\n\n\tint a,b,c;\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d %d %d\",&a,&b,&c);\n\t\ta--;\n\t\tb--;\n\n\t\tG[a].push_back(Edge(b,c==2));\n\t\tG[b].push_back(Edge(a,c==2));\n\t}\n\n\tfor(int i = 0; i <= MAX; i++){\n\t\tfor(int k = 0; k < N; k++){\n\n\t\t\tmin_dist[i][k] = HUGE_NUM;\n\t\t}\n\t}\n\n\tmin_dist[0][0] = 1; //min_dist[青い辺を通った回数][現在地] = 最小当初金\n\n\tpriority_queue<State> Q;\n\tQ.push(State(0,0,1));\n\n\twhile(!Q.empty()){\n\n\t\tState state = Q.top();\n\t\tQ.pop();\n\n\t\tif(state.sum_dist > min_dist[state.count][state.node])continue;\n\n\t\tfor(int i = 0; i < G[state.node].size(); i++){\n\n\t\t\tint next_node = G[state.node][i].to;\n\t\t\tll next_dist = state.sum_dist+POW[state.count];\n\t\t\tif(next_dist > L)continue;\n\t\t\tll next_count = state.count;\n\t\t\tif(G[state.node][i].isBlue){\n\n\t\t\t\tnext_count++;\n\t\t\t}\n\t\t\tif(min_dist[next_count][next_node] > next_dist){\n\t\t\t\tmin_dist[next_count][next_node] = next_dist;\n\t\t\t\tQ.push(State(next_node,next_count,next_dist));\n\t\t\t}\n\t\t}\n\t}\n\n\tint tmp_node;\n\tfor(int loop = 0; loop < numQ; loop++){\n\n\t\tscanf(\"%d\",&tmp_node);\n\t\ttmp_node--;\n\n\t\tll ans = HUGE_NUM;\n\t\tfor(int i = 0; i <= MAX; i++){\n\n\t\t\tchmin(ans,min_dist[i][tmp_node]);\n\t\t}\n\t\tif(ans == HUGE_NUM){\n\n\t\t\tprintf(\"Large\\n\");\n\n\t\t}else{\n\n\t\t\tprintf(\"%lld\\n\",ans);\n\t\t}\n\t}\n\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1460, "memory_kb": 63852, "score_of_the_acc": -0.6857, "final_rank": 5 }, { "submission_id": "aoj_0734_7977754", "code_snippet": "#pragma GCC optimize(\"Ofast\")\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\n#include <deque>\n#include <stack>\n#include <sstream>\n#include <utility>\n#include <cstring>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n#include <array>\n#include <bitset>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long ull;\n\nmt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());\nll myRand(ll B) {\n return (ull)rng() % B;\n}\ninline double time() {\n return static_cast<double>(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count()) * 1e-9;\n}\n\nconst ll inf = 2e9;\nconst int N = 200200;\nll dp[30][N];\n\nint main(){\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n int n,m,q,l; cin >> n >> m >> q >> l;\n vector<vector<int>> g(n),gg(n);\n for(int i=0;i<m;i++){\n int x,y; cin >> x >> y;\n x--; y--;\n int c; cin >> c;\n if(c == 1){\n g[x].push_back(y);\n g[y].push_back(x);\n }\n else{\n gg[x].push_back(y);\n gg[y].push_back(x);\n }\n }\n for(int j=0;j<30;j++){\n for(int k=0;k<n;k++){\n dp[j][k] = inf;\n }\n }\n dp[0][0] = 1;\n priority_queue<pair<ll,pair<int,int>>, vector<pair<ll,pair<int,int>>>, greater<pair<ll,pair<int,int>>>> pq;\n pq.push({1,{0,0}});\n while(pq.size()){\n auto p = pq.top(); pq.pop();\n ll cost = p.first;\n int da = p.second.first;\n int s = p.second.second;\n if(dp[da][s] != cost)continue;\n if(cost >= inf)continue;\n for(int t:g[s]){\n ll ncost = cost + (1<<da);\n if(dp[da][t] > ncost){\n dp[da][t] = ncost;\n pq.push({ncost,{da,t}});\n }\n }\n for(int t:gg[s]){\n if(da == 29)break;\n ll ncost = cost + (1<<da);\n if(dp[da+1][t] > ncost){\n dp[da+1][t] = ncost;\n pq.push({ncost,{da+1,t}});\n }\n }\n }\n while(q--){\n int t; cin >> t; t--;\n ll res = l+1;\n for(int i=0;i<30;i++){\n res = min(res,dp[i][t]);\n }\n if(res > l){\n cout << \"Large\" << \"\\n\";\n }\n else{\n cout << res << \"\\n\";\n }\n }\n}", "accuracy": 1, "time_ms": 1240, "memory_kb": 69232, "score_of_the_acc": -0.6368, "final_rank": 4 }, { "submission_id": "aoj_0734_7915630", "code_snippet": "//会津大学オンラインジャッジ問0734Taxis 2に挑戦するコード\n//作者堀江\n#include <cmath>\n#include <iostream>\n#include <vector>\n#include <string.h>\n#include <queue>\nusing namespace std;\n\nstruct E{\n\tlong long int l,mult2,count2;\n\tint p;\n\t\n\tbool operator<(const E& e)const{\n\t\tif(l!=e.l)return l>e.l;\n\t\treturn p<e.p;\n\t}\n};\nvector<int> gs1[200003],gs2[200003];\nlong long int dp[34][200003],ans[200003];\nbool first[34][200003];\n\nint main() {\n\tint n,m,q,l;\n\tcin>>n>>m>>q>>l;\n\tfor(int j=0;j<34;j++){\n\t\tfor(int i=1;i<=n;i++){\n\t\t\tfirst[j][i]=true;\n\t\t\tdp[j][i]=l+1;\n\t\t\tans[i]=l+1;\n\t\t}\n\t}\n\tfor(int i=0;i<m;i++){\n\t\tint a,b,c;\n\t\tcin>>a>>b>>c;\n\t\tif(c==1){\n\t\t\tgs1[a].push_back(b);\n\t\t\tgs1[b].push_back(a);\n\t\t}else{\n\t\t\tgs2[a].push_back(b);\n\t\t\tgs2[b].push_back(a);\n\t\t}\n\t}\n\tfor(int i=0;i<34;i++){\n\t\tdp[i][1]=0;\n\t}\n\tans[1]=0;\n\tE e1;\n\te1.p=1;\n\te1.l=0;\n\te1.count2=0;\n\te1.mult2=1;\n\tpriority_queue<E> pq;\n\tpq.push(e1);\n\twhile(pq.size()>0){\n\t\te1=pq.top();\n\t\tpq.pop();\n\t\t//cout<<e1.p<<\" l=\"<<e1.l<<\" m2=\"<<e1.mult2<<\" c2\"<<e1.count2<<endl;\n\t\tif(e1.l+e1.mult2>l)continue;\n\t\tif(first[e1.count2][e1.p]==false)continue;\n\t\tfirst[e1.count2][e1.p]=false;\n\t\tfor(int i=0;i<gs1[e1.p].size();i++){\n\t\t\tE e2;\n\t\t\te2.p=gs1[e1.p][i];\n\t\t\te2.l=e1.l+e1.mult2;\n\t\t\te2.mult2=e1.mult2;\n\t\t\te2.count2=e1.count2;\n\t\t\tif(dp[e2.count2][e2.p]>e2.l){\n\t\t\t\tdp[e2.count2][e2.p]=e2.l;\n\t\t\t\tpq.push(e2);\n\t\t\t}\n\t\t\tif(ans[e2.p]>e2.l+e2.mult2){\n\t\t\t\tans[e2.p]=e2.l+e2.mult2;\n\t\t\t}\n\t\t}\n\t\tfor(int i=0;i<gs2[e1.p].size();i++){\n\t\t\tE e2;\n\t\t\te2.p=gs2[e1.p][i];\n\t\t\te2.l=e1.l;\n\t\t\te2.mult2=e1.mult2*2;\n\t\t\te2.count2=e1.count2+1;\n\t\t\tif(dp[e2.count2][e2.p]>e2.l){\n\t\t\t\tdp[e2.count2][e2.p]=e2.l;\n\t\t\t\tpq.push(e2);\n\t\t\t}\n\t\t\tif(ans[e2.p]>e2.l+e2.mult2){\n\t\t\t\tans[e2.p]=e2.l+e2.mult2;\n\t\t\t}\n\t\t}\n\t}\n\t\n\t\n\tfor(int i=0;i<q;i++){\n\t\tint p1;\n\t\tcin>>p1;\n\t\tif(ans[p1]==l+1){\n\t\t\tcout<<\"Large\"<<endl;\n\t\t}else{\n\t\t\tcout<<ans[p1]<<endl;\n\t\t}\n\t}\n\t\n\treturn 0;\n}", "accuracy": 1, "time_ms": 2190, "memory_kb": 147440, "score_of_the_acc": -2, "final_rank": 8 }, { "submission_id": "aoj_0734_7867192", "code_snippet": "#include <bits/extc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n\ntemplate <class T> using Max_Heap = __gnu_pbds::priority_queue<T, less<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Min_Heap = __gnu_pbds::priority_queue<T, greater<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = __gnu_pbds::gp_hash_table<K, V>;\ntemplate <class T> using Rope = __gnu_cxx::rope<T>;\nusing Trie = __gnu_pbds::trie<string, __gnu_pbds::null_type, __gnu_pbds::trie_string_access_traits<>, __gnu_pbds::pat_trie_tag, __gnu_pbds::trie_prefix_search_node_update>;\n\ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\nstruct UnionFind{\n int n;\n vector<int> data;\n\n UnionFind(int sz) : n(sz), data(sz, -1){}\n\n bool unite(int x, int y){\n x = find(x), y = find(y);\n if(x == y) return (false);\n if(data[x] > data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return (true);\n }\n\n int find(int k){\n if(data[k] < 0) return (k);\n return (data[k] = find(data[k]));\n }\n\n int size(int k){\n return (-data[find(k)]);\n }\n\n bool same(int x, int y){\n return (find(x) == find(y));\n }\n\n vector<vector<int> > groups(){\n vector<int> leader_buf(n), group_size(n);\n for(int i = 0; i < n; ++i){\n leader_buf[i] = find(i);\n group_size[leader_buf[i]]++;\n }\n vector<vector<int> > res(n);\n for(int i = 0; i < n; ++i){\n res[i].reserve(group_size[i]);\n }\n for(int i = 0; i < n; ++i){\n res[leader_buf[i]].emplace_back(i);\n }\n res.erase(\n remove_if(res.begin(), res.end(),\n [&](const vector<int>& v){ return (v.empty()); }),\n res.end());\n return (res);\n }\n};\n\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n\n int n, m, q, l;\n cin >> n >> m >> q >> l;\n\n UnionFind uf(n);\n\n assert(2 <= n && n <= 200000);\n assert(n - 1 <= m && m <= 200000);\n assert(1 <= q && q <= 200000);\n\n vector<vector<pair<int, int> > > g(n);\n\n for (int i = 0; i < m; ++i) {\n int a, b, c;\n cin >> a >> b >> c;\n\n assert(1 <= a && a < b && b <= n);\n assert(1 <= c && c <= 2);\n\n --a, --b;\n\n uf.unite(a, b);\n\n g[a].emplace_back(b, c);\n g[b].emplace_back(a, c);\n }\n\n assert(uf.size(0) == n);\n\n vector<vector<int> > dist(32, vector<int>(n, INF));\n min_heap<tuple<int, int, int> > pq;\n dist[0][0] = 0;\n pq.emplace(0, 0, 0);\n\n while (!pq.empty()) {\n auto [b, a, cur] = pq.top();\n pq.pop();\n if ((1LL << a) + b > (long long) l) continue;\n if (dist[a][cur] < b) continue;\n for (auto [to, c] : g[cur]) {\n if (c == 1) {\n if (chmin(dist[a][to], dist[a][cur] + (1 << a))) {\n pq.emplace(dist[a][to], a, to);\n }\n } else {\n if (chmin(dist[a + 1][to], dist[a][cur])) {\n pq.emplace(dist[a + 1][to], a + 1, to);\n }\n }\n }\n }\n\n vector<int> res(n, INF);\n\n for (int i = 0; i < n; ++i) {\n for (int j = 0; j < 32; ++j) {\n if ((1LL << j) + dist[j][i] <= (long long) l) {\n chmin(res[i], (1 << j) + dist[j][i]);\n }\n }\n }\n\n for (int i = 0; i < q; ++i) {\n int t;\n cin >> t;\n\n assert(2 <= t && t <= n);\n\n t--;\n\n if (res[t] > l) {\n cout << \"Large\\n\";\n } else {\n cout << res[t] << '\\n';\n }\n }\n\n return (0);\n}", "accuracy": 1, "time_ms": 1190, "memory_kb": 62340, "score_of_the_acc": -0.5336, "final_rank": 3 }, { "submission_id": "aoj_0734_7848644", "code_snippet": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define rall(v) v.rbegin(), v.rend()\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define drep(i,j,n) for(int i=0;i<(int)(n-1);i++)for(int j=i+1;j<(int)(n);j++)\n#define trep(i,j,k,n) for(int i=0;i<(int)(n-2);i++)for(int j=i+1;j<(int)(n-1);j++)for(int k=j+1;k<(int)(n);k++)\n#define codefor int test;scanf(\"%d\",&test);while(test--)\n#define INT(...) int __VA_ARGS__;in(__VA_ARGS__)\n#define LL(...) ll __VA_ARGS__;in(__VA_ARGS__)\n#define yes(ans) if(ans)printf(\"yes\\n\");else printf(\"no\\n\")\n#define Yes(ans) if(ans)printf(\"Yes\\n\");else printf(\"No\\n\")\n#define YES(ans) if(ans)printf(\"YES\\n\");else printf(\"NO\\n\")\n#define popcount(v) __builtin_popcountll(v)\n#define vector2d(type,name,h,...) vector<vector<type>>name(h,vector<type>(__VA_ARGS__))\n#define vector3d(type,name,h,w,...) vector<vector<vector<type>>>name(h,vector<vector<type>>(w,vector<type>(__VA_ARGS__)))\n#define vector4d(type,name,h,w,d,...) vector<vector<vector<vector<type>>>>name(h,vector<vector<vector<type>>>(w,vector<vector<type>>(d,vector<type>(__VA_ARGS__))))\nusing namespace std;\nusing ll = long long;\ntemplate<class T> using rpriority_queue = priority_queue<T, vector<T>, greater<T>>;\nconst int MOD=1000000007;\nconst int MOD2=998244353;\nconst int INF=1<<30;\nconst ll INF2=1LL<<60;\nvoid scan(int& a){scanf(\"%d\",&a);}\nvoid scan(long long& a){scanf(\"%lld\",&a);}\ntemplate<class T,class L>void scan(pair<T, L>& p){scan(p.first);scan(p.second);}\ntemplate<class T,class U,class V>void scan(tuple<T,U,V>& p){scan(get<0>(p));scan(get<1>(p));scan(get<2>(p));}\ntemplate<class T, size_t size> void scan(array<T, size>& a){ for(auto&& i : a) scan(i);}\ntemplate<class T> void scan(T& a){cin>>a;}\ntemplate<class T> void scan(vector<T>& vec){for(auto&& it:vec)scan(it);}\nvoid in(){}\ntemplate <class Head, class... Tail> void in(Head& head, Tail&... tail){scan(head);in(tail...);}\nvoid print(const int& a){printf(\"%d\",a);}\nvoid print(const long long& a){printf(\"%lld\",a);}\nvoid print(const double& a){printf(\"%.15lf\",a);}\ntemplate<class T,class L>void print(const pair<T, L>& p){print(p.first);putchar(' ');print(p.second);}\ntemplate<class T> void print(const T& a){cout<<a;}\ntemplate<class T> void print(const vector<T>& vec){if(vec.empty())return;print(vec[0]);for(auto it=vec.begin();++it!= vec.end();){putchar(' ');print(*it);}}\nvoid out(){putchar('\\n');}\ntemplate<class T> void out(const T& t){print(t);putchar('\\n');}\ntemplate <class Head, class... Tail> void out(const Head& head,const Tail&... tail){print(head);putchar(' ');out(tail...);}\ntemplate<class T> void dprint(const T& a){cerr<<a;}\ntemplate<class T> void dprint(const vector<T>& vec){if(vec.empty())return;cerr<<vec[0];for(auto it=vec.begin();++it!= vec.end();){cerr<<\" \"<<*it;}}\nvoid debug(){cerr<<endl;}\ntemplate<class T> void debug(const T& t){dprint(t);cerr<<endl;}\ntemplate <class Head, class... Tail> void debug(const Head& head, const Tail&... tail){dprint(head);cerr<<\" \";debug(tail...);}\nll intpow(ll a, ll b){ ll ans = 1; while(b){ if(b & 1) ans *= a; a *= a; b /= 2; } return ans; }\nll modpow(ll a, ll b, ll p){ ll ans = 1; while(b){ if(b & 1) (ans *= a) %= p; (a *= a) %= p; b /= 2; } return ans; }\nll modinv(ll a, ll m) {ll b = m, u = 1, v = 0;while (b) {ll t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}u %= m;if (u < 0) u += m;return u;}\nll updivide(ll a,ll b){return (a+b-1)/b;}\nint msb(ll v){return 63-__builtin_clzll(v);}\ntemplate<class T> void chmax(T &a,const T b){if(b>a)a=b;}\ntemplate<class T> void chmin(T &a,const T b){if(b<a)a=b;}\n\nint main(){\n INT(n,m,q,l);\n vector<vector<pair<int,int>>> g(n);\n int u,v,c;\n rep(i,m){\n in(u,v,c);\n u--,v--;\n g[u].emplace_back(v,c);\n g[v].emplace_back(u,c);\n }\n vector2d(ll,dist,n,32,INF2);\n rpriority_queue<array<ll,3>> pq;\n dist[0][0]=0;\n pq.push({0,0,0});\n while(!pq.empty()){\n auto a=pq.top();\n pq.pop();\n if(a[0]>l||a[2]==31)continue;\n for(auto p:g[a[1]]){\n if(p.second==1){\n if(a[0]+(1<<a[2])>=dist[p.first][a[2]])continue;\n dist[p.first][a[2]]=a[0]+(1<<a[2]);\n pq.push({dist[p.first][a[2]],p.first,a[2]});\n }else{\n if(a[0]>=dist[p.first][a[2]+1])continue;\n dist[p.first][a[2]+1]=a[0];\n pq.push({dist[p.first][a[2]+1],p.first,a[2]+1});\n }\n }\n }\n while(q--){\n in(u);\n u--;\n ll ans=INF2;\n rep(i,31)chmin(ans,dist[u][i]+(1<<i));\n if(ans>l)out(\"Large\");\n else out(ans);\n }\n}", "accuracy": 1, "time_ms": 1860, "memory_kb": 116484, "score_of_the_acc": -1.4835, "final_rank": 7 } ]
aoj_0723_cpp
交易計画 (Trade Plan) 問題文 JOI 合衆国には 1 から N までの番号が付けられた N 個の都市と, 1 から M までの番号が付けられた M 本の道路がある.道路 i ( 1 ≦ i ≦ M ) は,都市 U i と都市 V i を双方向に結んでいる. JOI 合衆国は 1 から K までの番号が付けられた K 個の州からなる.都市 j ( 1 ≦ j ≦ N ) は州 S j に属している.また,どの州も少なくとも 1 つの都市を含む. JOI 合衆国の産業大臣である K 理事長は,これから Q 回の交易を行いたいと考えている. k 番目の交易 ( 1 ≦ k ≦ Q ) は,都市 A k から都市 B k にいくつかの道路や都市を通って特産品を輸送するというものである.ただし,この交易に協力してくれるのは州 S A k と 州 S B k のみ ( S A k = S B k の場合は州 S A k のみ) であり,これらの州に属していない都市を通ると特産品は盗まれてしまう. K 理事長は特産品が盗まれないように交易を行うような輸送経路があるのかを調べたい.都市と道路の配置,州と交易の情報が与えられたとき,各交易について特産品を無事届けることが可能かを判定するプログラムを作成せよ. 制約 2 ≦ N ≦ 400 000 . 1 ≦ M ≦ 400 000 . 1 ≦ K ≦ N . 1 ≦ U i < V i ≦ N ( 1 ≦ i ≦ M ). (U i , V i ) ≠ (U j , V j ) ( 1 ≦ i < j ≦ M ). 1 ≦ S j ≦ K ( 1 ≦ j ≦ N ). すべての l ( 1 ≦ l ≦ K ) について, S j = l となる j ( 1 ≦ j ≦ N) が存在する. 1 ≦ Q ≦ 400 000 . 1 ≦ A k ≦ N ( 1 ≦ k ≦ Q ). 1 ≦ B k ≦ N ( 1 ≦ k ≦ Q ). A k ≠ B k ( 1 ≦ k ≦ Q ). 入力される値はすべて整数である. 入力 入力は以下の形式で標準入力から与えられる. N M K U 1 V 1 U 2 V 2 : U M V M S 1 S 2 … S N Q A 1 B 1 A 2 B 2 : A Q B Q 出力 標準出力に Q 行で出力せよ. k 行目 ( 1 ≦ k ≦ Q ) には, k 番目の交易において特産品を届けることが可能であれば 1 を,不可能であれば 0 を出力せよ. 入出力例 入力例 1 4 3 2 1 2 2 3 3 4 1 2 1 2 3 1 2 1 3 1 4 出力例 1 1 0 1 1 番目の交易は,州 1 または州 2 に属する都市のみを通って,都市 1 から都市 2 に特産品を輸送するというものである.都市 1 → 都市 2 と輸送すれば条件を満たすので, 1 を出力する. 2 番目の交易は,州 1 に属する都市のみを通って,都市 1 から都市 3 に特産品を輸送するというものである.条件を満たす輸送経路は存在しないので, 0 を出力する. 3 番目の交易は,州 1 または州 2 に属する都市のみを通って,都市 1 から都市 4 に特産品を輸送するというものである.都市 1 → 都市 2 → 都市 3 → 都市 4 と輸送すれば条件を満たすので, 1 を出力する. 入力例 2 4 2 1 1 3 2 4 1 1 1 1 4 1 2 1 3 2 3 2 4 出力例 2 0 1 0 1 入力例 3 6 5 3 1 2 3 4 5 6 1 4 3 5 1 1 2 2 3 3 4 1 4 1 5 3 6 4 3 出力例 3 1 0 1 1 入力例 4 8 11 3 4 8 1 8 4 6 3 5 2 4 7 8 6 7 3 4 1 4 2 3 3 8 2 3 1 1 2 1 2 1 10 8 2 8 1 2 7 5 3 5 7 4 8 1 8 6 8 6 5 1 8 出力例 4 1 1 0 1 0 1 1 1 1 1 情報オリンピック日本委員会 作 『第 21 回日本情報オリンピック JOI 2021/2022 二次予選競技課題』
[ { "submission_id": "aoj_0723_10854012", "code_snippet": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define db double\n#define gcd(a,b) __gcd(a,b)\n#define lcm(a,b) a*b / __gcd(a,b)\n#define I first\n#define II second\n#define pb push_back\n#define ii pair<int,int>\nconst int INF = 2 * 1e9;\nconst int N = 4e5 + 1;\nconst int MOD = 1e9 + 7;\nint n, m, k, ans[N], cur, s[N];\narray<int, 4> e[N];\nstruct DSU\n{\n vector<int> par, sz;\n vector<array<int, 4> > rb;\n void rz(int n)\n {\n par.assign(n + 1, 0);\n sz.assign(n + 1, 1);\n rb.clear();\n cur = 1;\n }\n int get(int u)\n {\n return (!par[u] ? u : get(par[u]));\n }\n int join(int u, int v)\n {\n u = get(u), v = get(v);\n if (u == v) return 0;\n if (sz[u] < sz[v]) swap(u, v);\n rb.pb({u, sz[u], v, cur});\n sz[u] += sz[v];\n par[v] = u;\n cur = max(cur, sz[u]);\n return 1;\n }\n void rollback(int cnt)\n {\n while (cnt--)\n {\n auto G = rb.back(); rb.pop_back();\n sz[G[0]] = G[1];\n par[G[2]] = 0;\n cur = G[3];\n }\n }\n} T;\nint32_t main()\n{\n#define TASKNAME \"\"\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n if (fopen(TASKNAME\".inp\",\"r\" ))\n {\n freopen(TASKNAME\".inp\",\"r\",stdin);\n freopen(TASKNAME\".out\",\"w\",stdout);\n }\n cin >> n >> m >> k;\n T.rz(n);\n for (int i = 1; i <= m; i++) cin >> e[i][2] >> e[i][3];\n for (int i = 1; i <= n; i++) cin >> s[i];\n for (int i = 1; i <= m; i++)\n {\n if (s[e[i][2]] > s[e[i][3]]) swap(e[i][2], e[i][3]);\n e[i][0] = s[e[i][2]];\n e[i][1] = s[e[i][3]];\n if (e[i][0] == e[i][1]) T.join(e[i][2], e[i][3]);\n }\n sort(e + 1, e + m + 1);\n int q; cin >> q;\n vector<array<int, 5> > Query;\n for (int i = 1; i <= q; i++)\n {\n int x, y;\n cin >> x >> y;\n if (s[x] > s[y]) swap(x, y);\n Query.pb({s[x], s[y], x, y, i});\n }\n sort(Query.begin(), Query.end());\n for (int i = 0; i < q; i++)\n {\n if (Query[i][0] == Query[i][1])\n {\n ans[Query[i][4]] = (T.get(Query[i][2]) == T.get(Query[i][3]));\n continue;\n }\n int j = i;\n while (j + 1 < q && Query[j + 1][0] == Query[i][0] && Query[j + 1][1] == Query[i][1]) j++;\n int l = lower_bound(e + 1, e + m + 1, array<int, 4>{Query[i][0], Query[i][1], 0, 0}) - e;\n if (l == m + 1)\n {\n i = j;\n continue;\n }\n int cnt = 0;\n for (int k = l; k <= m; k++)\n if (e[k][0] == Query[i][0] && e[k][1] == Query[i][1])\n cnt += T.join(e[k][2], e[k][3]); else break;\n for (int k = i; k <= j; k++)\n ans[Query[k][4]] = (T.get(Query[k][2]) == T.get(Query[k][3]));\n T.rollback(cnt);\n i = j;\n }\n for (int i = 1; i <= q; i++) cout << ans[i] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 40320, "score_of_the_acc": -0.3097, "final_rank": 1 }, { "submission_id": "aoj_0723_10203302", "code_snippet": "#line 1 \"icpc.cpp\"\n#include <bits/stdc++.h>\nusing namespace std;\n\n#line 2 \"Library/DataStructure/RollbackUnionFind.hpp\"\n\n/**\n * @file RollbackUnionFind.hpp\n * @author lX57\n * @brief Rollback Union-Find - Rollback 可能 Union-Find\n */\n\n#line 2 \"Library/Common.hpp\"\n\n/**\n * @file Common.hpp\n */\n\n#line 26 \"Library/Common.hpp\"\nusing namespace std;\n#line 10 \"Library/DataStructure/RollbackUnionFind.hpp\"\n\nclass RollbackUnionFind{\n public:\n /**\n * @brief 要素数 `size` で Union-Find を初期化します。\n * @note 要素番号は 0-index です。\n * @param size 要素数\n */\n RollbackUnionFind(size_t size) : data_(size, -1){}\n\n /**\n * @brief 要素 `k` が属する集合の代表元を返します。\n * @param k 探索する要素\n * @return 要素 `k` が属する集合の代表元\n */\n int Find(const int k) const {\n if(data_[k] < 0) return k;\n return Find(data_[k]);\n }\n\n /**\n * @brief 要素 `x` と要素 `y` が同じ集合に属しているかを判定します。\n * @param x 要素番号\n * @param y 要素番号\n * @return 同じ集合に属しているか\n */\n bool Same(const int x, const int y) const {\n return Find(x) == Find(y);\n }\n\n /**\n * @brief 要素 `x` と要素 `y` を併合します。併合した場合は `true` を返します。\n * @param x 要素番号\n * @param y 要素番号\n * @return 併合を行ったか\n */\n bool Unite(int x, int y){\n x = Find(x), y = Find(y);\n history_.push({x, data_[x]});\n history_.push({y, data_[y]});\n if(x == y) return false;\n if(data_[x] > data_[y]) swap(x, y);\n data_[x] += data_[y];\n data_[y] = x;\n return true;\n }\n\n /**\n * @brief 現在の状態を保存します。別の状態を保存している場合、上書きします。\n */\n void Record(){\n record_ = history_.size();\n }\n\n /**\n * @brief 直前の `Unite` 操作を取り消します。\n */\n void Undo(){\n auto [y, dy] = history_.top();\n history_.pop();\n data_[y] = dy;\n auto [x, dx] = history_.top();\n history_.pop();\n data_[x] = dx;\n }\n\n /**\n * @brief `Record` で記録した状態までロールバックします。\n */\n void Rollback(){\n int state = record_;\n while(state < (int)history_.size()) Undo();\n }\n\n /**\n * @brief 各集合に所属する要素を列挙します。\n * @return vector<vector<int>> 各集合に所属する要素の一覧\n */\n vector<vector<int>> Group() const {\n vector<vector<int>> ret(data_.size());\n for(int i = 0; i < data_.size(); ++i){\n ret[Find(i)].emplace_back(i);\n }\n ret.erase(remove_if(begin(ret), end(ret), [&](vector<int> &v){\n return v.empty();\n }), end(ret));\n return ret;\n }\n\n /**\n * @brief 要素 `k` が属する集合の要素数を求めます。\n * @param k 要素番号\n * @return int 集合の要素数\n */\n int Size(const int k) const {\n return -data_[Find(k)];\n }\n\n private:\n vector<int> data_;\n stack<pair<int, int>> history_;\n int record_;\n};\n#line 5 \"icpc.cpp\"\n\nint main(){\n int N, M, K; cin >> N >> M >> K;\n vector<int> U(M), V(M);\n for(int i = 0; i < M; ++i) cin >> U[i] >> V[i], --U[i], --V[i];\n vector<int> S(N);\n for(int i = 0; i < N; ++i) cin >> S[i], --S[i];\n\n RollbackUnionFind uf(N);\n map<pair<int, int>, vector<pair<int, int>>> Road;\n for(int i = 0; i < M; ++i){\n int u = U[i], v = V[i];\n int su = S[u], sv = S[v];\n if(su == sv) uf.Unite(u, v);\n else{\n if(su > sv) swap(su, sv);\n Road[{su, sv}].push_back({u, v});\n }\n }\n int Q; cin >> Q;\n map<pair<int, int>, vector<tuple<int, int, int>>> Query;\n vector<int> ans(Q, -1);\n for(int i = 0; i < Q; ++i){\n int A, B; cin >> A >> B, --A, --B;\n int sa = S[A], sb = S[B];\n if(sa == sb){\n ans[i] = uf.Same(A, B);\n }\n else{\n if(sa > sb) swap(sa, sb);\n Query[{sa, sb}].push_back({i, A, B});\n }\n }\n uf.Record();\n for(auto [state_pair, qs] : Query){\n for(auto [u, v] : Road[state_pair]){\n uf.Unite(u, v);\n }\n for(auto [i, a, b] : qs){\n ans[i] = uf.Same(a, b);\n }\n uf.Rollback();\n }\n for(auto a : ans){\n assert(a != -1);\n cout << a << endl;\n }\n}", "accuracy": 1, "time_ms": 910, "memory_kb": 129920, "score_of_the_acc": -1.3181, "final_rank": 8 }, { "submission_id": "aoj_0723_9992901", "code_snippet": "#line 1 \"test/data-structure/undo_dsu.test.2.cpp\"\n#define PROBLEM \"https://onlinejudge.u-aizu.ac.jp/problems/0723\"\n\n#line 1 \"test/template.hpp\"\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nconst ll INF = LLONG_MAX / 4;\n#define all(a) begin(a), end(a)\n#line 1 \"src/data-structure/undo_dsu.hpp\"\n// base: edf246\nstruct undo_dsu {\n private:\n int _n;\n vector<int> p;\n stack<pair<int, int>> history;\n\n public:\n undo_dsu() : _n(0) {}\n explicit undo_dsu(int n) : _n(n), p(n, -1) {}\n\n int merge(int a, int b) {\n // assert(0 <= a && a < _n);\n // assert(0 <= b && b < _n);\n int x = leader(a), y = leader(b);\n if(x == y) {\n history.emplace(x, p[x]);\n history.emplace(y, p[y]);\n return x;\n }\n if(-p[x] < -p[y]) swap(x, y);\n history.emplace(x, p[x]);\n history.emplace(y, p[y]);\n p[x] += p[y];\n p[y] = x;\n return x;\n }\n\n bool same(int a, int b) {\n // assert(0 <= a && a < _n);\n // assert(0 <= b && b < _n);\n return leader(a) == leader(b);\n }\n\n int leader(int a) {\n // assert(0 <= a && a < _n);\n while(p[a] >= 0) a = p[a];\n return a;\n }\n\n void undo() {\n p[history.top().first] = history.top().second;\n history.pop();\n p[history.top().first] = history.top().second;\n history.pop();\n }\n\n int snapshot() { return history.size(); }\n\n void rollback(int snapshot = 0) {\n while(history.size() > snapshot) undo();\n }\n\n int size(int a) {\n // assert(0 <= a && a < _n);\n return -p[leader(a)];\n } // 818fe7\n};\n#line 5 \"test/data-structure/undo_dsu.test.2.cpp\"\n\nint main() {\n cin.tie(0)->sync_with_stdio(0);\n int N, M, K;\n cin >> N >> M >> K;\n vector<pair<int, int>> edges(M);\n for(int i = 0; i < M; i++) {\n int u, v;\n cin >> u >> v;\n u--;\n v--;\n edges[i] = {u, v};\n }\n\n vector<int> S(N);\n for(auto&& s : S) cin >> s;\n map<pair<int, int>, vector<pair<int, int>>> E;\n undo_dsu dsu(N);\n for(auto [u, v] : edges) {\n int su = S[u], sv = S[v];\n if(su == sv) {\n dsu.merge(u, v);\n } else {\n if(su > sv) {\n swap(u, v);\n swap(su, sv);\n }\n E[{su, sv}].push_back({u, v});\n }\n }\n int snapshot = dsu.snapshot();\n int Q;\n cin >> Q;\n vector<int> ans(Q);\n map<pair<int, int>, vector<int>> q;\n vector<pair<int, int>> query(Q);\n\n for(int i = 0; i < Q; i++) {\n int A, B;\n cin >> A >> B;\n A--;\n B--;\n if(S[A] > S[B]) swap(A, B);\n int SA = A;\n int SB = B;\n query[i] = {A, B};\n q[{S[A], S[B]}].push_back(i);\n }\n\n for(auto [key, value] : q) {\n auto [su, sv] = key;\n for(auto [u, v] : E[{su, sv}]) { dsu.merge(u, v); }\n for(auto i : value) {\n auto [A, B] = query[i];\n ans[i] = dsu.same(A, B);\n }\n dsu.rollback(snapshot);\n }\n for(auto&& a : ans) cout << a << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 132832, "score_of_the_acc": -1.1613, "final_rank": 6 }, { "submission_id": "aoj_0723_9581421", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nstruct Undo_dsu{\n vector<int> data;\n stack<pair<int,int>> hist;\n Undo_dsu(int sz){data.assign(sz,-1);}\n\n bool merge(int x,int y){\n x=find(x),y=find(y);\n hist.emplace(x,data[x]);\n hist.emplace(y,data[y]);\n if(x==y)return false;\n if(data[x]>data[y])swap(x,y);\n data[x]+=data[y];\n data[y]=x;\n return true;\n }\n\n int same(int x,int y){return find(x)==find(y);}\n int size(int x){return (-data[find(x)]);}\n\n void undo(){\n data[hist.top().first] = hist.top().second;\n hist.pop();\n data[hist.top().first] = hist.top().second;\n hist.pop();\n }\n\n int find(int k){\n if(data[k]<0)return k;\n return find(data[k]);\n }\n};\n\n\nint main() {\n\n cin.tie(nullptr);\n ios::sync_with_stdio(false);\n ll N,M,K;\n cin>>N>>M>>K;\n vector<pair<int,int>> E(M);\n for(int i=0;i<M;i++){\n int u,v;\n cin>>u>>v;\n E[i]={u-1,v-1};\n }\n vector<int> S(N);\n for(int i=0;i<N;i++){\n cin>>S[i];\n S[i]--;\n }\n map<pair<int,int>,vector<pair<int,int>>> MP,query;\n Undo_dsu D(N);\n for(int i=0;i<M;i++){\n int u=E[i].first;\n int v=E[i].second;\n if(S[u]==S[v]){\n D.merge(u,v);\n continue;\n }\n if(S[u]>S[v])swap(u,v);\n MP[{S[u],S[v]}].push_back({u,v});\n }\n int Q;\n cin>>Q;\n vector<bool> AN(Q,0);\n set<pair<int,int>> ANM;\n vector<pair<int,int>> QR(Q);\n for(int i=0;i<Q;i++){\n int a,b;\n cin>>a>>b;\n a--;b--;\n QR[i]={a,b};\n if(S[a]==S[b]){\n AN[i]=D.same(a,b);\n }\n else{\n if(S[a]>S[b])swap(a,b);\n QR[i]={a,b};\n query[{S[a],S[b]}].push_back({a,b});\n }\n }\n for(auto [p,V]:query){\n for(auto [u,v]:MP[p]){\n D.merge(u,v);\n }\n for(auto [u,v]:V){\n if(D.same(u,v)){\n ANM.insert({u,v});\n }\n }\n for(int i=0;i<MP[p].size();i++)D.undo();\n }\n for(int i=0;i<Q;i++){\n if(S[QR[i].first]==S[QR[i].second])cout<<(AN[i])<<\"\\n\";\n else if(ANM.count(QR[i]))cout<<1<<\"\\n\";\n else cout<<0<<\"\\n\";\n }\n}", "accuracy": 1, "time_ms": 700, "memory_kb": 131088, "score_of_the_acc": -1.1667, "final_rank": 7 }, { "submission_id": "aoj_0723_8750853", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 2 \"/home/kuhaku/home/github/algo/lib/tree/undo_union_find.hpp\"\n\n/**\n * @brief Undo可能Union-Find\n * @details Implement (union by size)\n *\n * @see https://ei1333.github.io/luzhiled/snippets/structure/union-find.html\n */\nstruct undo_union_find {\n undo_union_find() : data(), history() {}\n undo_union_find(int _n) : data(_n, -1), history() {}\n\n int root(int x) { return this->data[x] < 0 ? x : this->root(this->data[x]); }\n int get_root(int k) { return this->root(k); }\n\n bool is_root(int k) const { return this->data[k] < 0; }\n\n bool same(int x, int y) { return this->root(x) == this->root(y); }\n bool is_same(int x, int y) { return this->same(x, y); }\n\n int size(int k) { return -this->data[this->root(k)]; }\n int get_size(int k) { return this->size(k); }\n\n bool unite(int x, int y) {\n x = this->root(x), y = this->root(y);\n this->history.emplace(x, this->data[x]);\n this->history.emplace(y, this->data[y]);\n if (x == y) return false;\n if (this->data[x] > this->data[y]) std::swap(x, y);\n this->data[x] += this->data[y];\n this->data[y] = x;\n return true;\n }\n\n void undo() {\n this->data[this->history.top().first] = this->history.top().second;\n this->history.pop();\n this->data[this->history.top().first] = this->history.top().second;\n this->history.pop();\n }\n\n int snapshot() const { return this->history.size(); }\n\n void rollback(int x = 0) {\n while ((int)(this->history.size()) > x) this->undo();\n }\n\n private:\n std::vector<int> data;\n std::stack<std::pair<int, int>> history;\n};\n#line 4 \"a.cpp\"\n\nint main(void) {\n int n, m, k;\n cin >> n >> m >> k;\n vector<pair<int, int>> edges(m);\n cin >> edges;\n for (auto &[x, y] : edges) --x, --y;\n vector<int> s(n);\n cin >> s;\n undo_union_find uf(n);\n map<pair<int, int>, vector<int>> mp;\n rep (i, m) {\n auto [x, y] = edges[i];\n if (s[x] == s[y]) {\n uf.unite(x, y);\n } else {\n if (s[x] > s[y])\n swap(x, y);\n mp[{s[x], s[y]}].emplace_back(i);\n }\n }\n\n map<pair<int, int>, vector<int>> pm;\n int q;\n cin >> q;\n vector<pair<int, int>> queries(q);\n cin >> queries;\n for (auto &[x, y] : queries) --x, --y;\n vector<int> ans(q, -1);\n rep (i, q) {\n auto [x, y] = queries[i];\n if (s[x] == s[y]) {\n ans[i] = uf.same(x, y);\n } else {\n if (s[x] > s[y])\n swap(x, y);\n pm[{s[x], s[y]}].emplace_back(i);\n }\n }\n\n int ss = uf.snapshot();\n for (auto &[p, v] : pm) {\n for (auto e : mp[p]) {\n uf.unite(edges[e].first, edges[e].second);\n }\n for (auto e : v) {\n ans[e] = uf.same(queries[e].first, queries[e].second);\n }\n uf.rollback(ss);\n }\n\n rep (i, q) co(ans[i]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 680, "memory_kb": 132624, "score_of_the_acc": -1.1602, "final_rank": 5 }, { "submission_id": "aoj_0723_8750852", "code_snippet": "#line 1 \"a.cpp\"\n#define PROBLEM \"\"\n#line 2 \"/home/kuhaku/home/github/algo/lib/template/template.hpp\"\n#pragma GCC target(\"sse4.2,avx2,bmi2\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#include <bits/stdc++.h>\ntemplate <class T, class U>\nconstexpr bool chmax(T &a, const U &b) {\n return a < (T)b ? a = (T)b, true : false;\n}\ntemplate <class T, class U>\nconstexpr bool chmin(T &a, const U &b) {\n return (T)b < a ? a = (T)b, true : false;\n}\nconstexpr std::int64_t INF = 1000000000000000003;\nconstexpr int Inf = 1000000003;\nconstexpr double EPS = 1e-7;\nconstexpr double PI = M_PI;\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/macro.hpp\"\n#define FOR(i, m, n) for (int i = (m); i < int(n); ++i)\n#define FORR(i, m, n) for (int i = (m)-1; i >= int(n); --i)\n#define FORL(i, m, n) for (int64_t i = (m); i < int64_t(n); ++i)\n#define rep(i, n) FOR (i, 0, n)\n#define repn(i, n) FOR (i, 1, n + 1)\n#define repr(i, n) FORR (i, n, 0)\n#define repnr(i, n) FORR (i, n + 1, 1)\n#define all(s) (s).begin(), (s).end()\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/sonic.hpp\"\nstruct Sonic {\n Sonic() {\n std::ios::sync_with_stdio(false);\n std::cin.tie(nullptr);\n std::cout << std::fixed << std::setprecision(20);\n }\n\n constexpr void operator()() const {}\n} sonic;\n#line 5 \"/home/kuhaku/home/github/algo/lib/template/atcoder.hpp\"\nusing namespace std;\nusing ll = std::int64_t;\nusing ld = long double;\ntemplate <class T, class U>\nstd::istream &operator>>(std::istream &is, std::pair<T, U> &p) {\n return is >> p.first >> p.second;\n}\ntemplate <class T>\nstd::istream &operator>>(std::istream &is, std::vector<T> &v) {\n for (T &i : v) is >> i;\n return is;\n}\ntemplate <class T, class U>\nstd::ostream &operator<<(std::ostream &os, const std::pair<T, U> &p) {\n return os << '(' << p.first << ',' << p.second << ')';\n}\ntemplate <class T>\nstd::ostream &operator<<(std::ostream &os, const std::vector<T> &v) {\n for (auto it = v.begin(); it != v.end(); ++it) {\n os << (it == v.begin() ? \"\" : \" \") << *it;\n }\n return os;\n}\ntemplate <class Head, class... Tail>\nvoid co(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cout << head << '\\n';\n else std::cout << head << ' ', co(std::forward<Tail>(tail)...);\n}\ntemplate <class Head, class... Tail>\nvoid ce(Head &&head, Tail &&...tail) {\n if constexpr (sizeof...(tail) == 0) std::cerr << head << '\\n';\n else std::cerr << head << ' ', ce(std::forward<Tail>(tail)...);\n}\ntemplate <typename T, typename... Args>\nauto make_vector(T x, int arg, Args... args) {\n if constexpr (sizeof...(args) == 0) return std::vector<T>(arg, x);\n else return std::vector(arg, make_vector<T>(x, args...));\n}\nvoid Yes(bool is_correct = true) {\n std::cout << (is_correct ? \"Yes\" : \"No\") << '\\n';\n}\nvoid No(bool is_not_correct = true) {\n Yes(!is_not_correct);\n}\nvoid YES(bool is_correct = true) {\n std::cout << (is_correct ? \"YES\" : \"NO\") << '\\n';\n}\nvoid NO(bool is_not_correct = true) {\n YES(!is_not_correct);\n}\nvoid Takahashi(bool is_correct = true) {\n std::cout << (is_correct ? \"Takahashi\" : \"Aoki\") << '\\n';\n}\nvoid Aoki(bool is_not_correct = true) {\n Takahashi(!is_not_correct);\n}\n#line 3 \"/home/kuhaku/home/github/algo/lib/template/vector.hpp\"\n\nstruct increment_impl {\n template <class T>\n const increment_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) ++x;\n return *this;\n }\n} Inc;\n\nstruct decrement_impl {\n template <class T>\n const decrement_impl &operator>>(std::vector<T> &v) const {\n for (auto &x : v) --x;\n return *this;\n }\n} Dec;\n\nstruct sort_impl {\n template <class T>\n const sort_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n return *this;\n }\n} Sort;\n\nstruct unique_impl {\n template <class T>\n const unique_impl &operator>>(std::vector<T> &v) const {\n std::sort(v.begin(), v.end());\n v.erase(std::unique(v.begin(), v.end()), v.end());\n return *this;\n }\n} Uniq;\n#line 2 \"/home/kuhaku/home/github/algo/lib/tree/undo_union_find.hpp\"\n\n/**\n * @brief Undo可能Union-Find\n * @details Implement (union by size)\n *\n * @see https://ei1333.github.io/luzhiled/snippets/structure/union-find.html\n */\nstruct undo_union_find {\n undo_union_find() : data(), history() {}\n undo_union_find(int _n) : data(_n, -1), history() {}\n\n int root(int x) { return this->data[x] < 0 ? x : this->root(this->data[x]); }\n int get_root(int k) { return this->root(k); }\n\n bool is_root(int k) const { return this->data[k] < 0; }\n\n bool same(int x, int y) { return this->root(x) == this->root(y); }\n bool is_same(int x, int y) { return this->same(x, y); }\n\n int size(int k) { return -this->data[this->root(k)]; }\n int get_size(int k) { return this->size(k); }\n\n bool unite(int x, int y) {\n x = this->root(x), y = this->root(y);\n this->history.emplace(x, this->data[x]);\n this->history.emplace(y, this->data[y]);\n if (x == y) return false;\n if (this->data[x] > this->data[y]) std::swap(x, y);\n this->data[x] += this->data[y];\n this->data[y] = x;\n return true;\n }\n\n void undo() {\n this->data[this->history.top().first] = this->history.top().second;\n this->history.pop();\n this->data[this->history.top().first] = this->history.top().second;\n this->history.pop();\n }\n\n int snapshot() const { return this->history.size(); }\n\n void rollback(int x = 0) {\n while ((int)(this->history.size()) > x) this->undo();\n }\n\n private:\n std::vector<int> data;\n std::stack<std::pair<int, int>> history;\n};\n#line 3 \"/home/kuhaku/home/github/algo/lib/tree/union_find.hpp\"\n\n/**\n * @brief 素集合データ構造\n * @details Implement (union by size) + (path compression)\n * @see https://github.com/atcoder/ac-library/blob/master/atcoder/dsu.hpp\n */\nstruct union_find {\n union_find() = default;\n explicit union_find(int _n) : data(_n, -1) {}\n\n int root(int x) { return data[x] < 0 ? x : data[x] = root(data[x]); }\n int get_root(int x) { return root(x); }\n\n bool is_root(int x) const { return data[x] < 0; }\n\n bool same(int x, int y) { return root(x) == root(y); }\n bool is_same(int x, int y) { return same(x, y); }\n\n int size(int x) { return -(data[root(x)]); }\n int get_size(int x) { return size(x); }\n\n std::vector<int> leaders() {\n std::vector<int> res;\n for (int i = 0; i < (int)data.size(); ++i) {\n if (is_root(i)) res.emplace_back(i);\n }\n return res;\n }\n\n bool unite(int x, int y) {\n x = root(x), y = root(y);\n if (x == y) return false;\n if (data[x] > data[y]) std::swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return true;\n }\n\n template <class F>\n bool unite(int x, int y, F f) {\n x = root(x), y = root(y);\n if (x != y) {\n if (data[x] > data[y]) std::swap(x, y);\n data[x] += data[y];\n data[y] = x;\n }\n f(x, y);\n return x != y;\n }\n\n private:\n std::vector<int> data;\n};\n#line 6 \"a.cpp\"\n\nint main(void) {\n int n, m, k;\n cin >> n >> m >> k;\n vector<pair<int, int>> edges(m);\n cin >> edges;\n for (auto &[x, y] : edges) --x, --y;\n vector<int> s(n);\n cin >> s;\n Dec >> s;\n undo_union_find uf(n);\n map<pair<int, int>, vector<int>> mp;\n rep (i, m) {\n auto [x, y] = edges[i];\n if (s[x] == s[y]) {\n uf.unite(x, y);\n } else {\n if (s[x] > s[y])\n swap(x, y);\n mp[{s[x], s[y]}].emplace_back(i);\n }\n }\n\n map<pair<int, int>, vector<int>> pm;\n int q;\n cin >> q;\n vector<pair<int, int>> queries(q);\n cin >> queries;\n for (auto &[x, y] : queries) --x, --y;\n vector<int> ans(q, -1);\n rep (i, q) {\n auto [x, y] = queries[i];\n if (s[x] == s[y]) {\n ans[i] = uf.same(x, y);\n } else {\n if (s[x] > s[y])\n swap(x, y);\n pm[{s[x], s[y]}].emplace_back(i);\n }\n }\n\n int ss = uf.snapshot();\n for (auto &[p, v] : pm) {\n for (auto e : mp[p]) {\n uf.unite(edges[e].first, edges[e].second);\n }\n for (auto e : v) {\n ans[e] = uf.same(queries[e].first, queries[e].second);\n }\n uf.rollback(ss);\n }\n\n rep (i, q) co(ans[i]);\n\n return 0;\n}", "accuracy": 1, "time_ms": 660, "memory_kb": 132876, "score_of_the_acc": -1.1465, "final_rank": 4 }, { "submission_id": "aoj_0723_8466719", "code_snippet": "#include<bits/stdc++.h>\n#define I first\n#define II second\n#define ii pair<int,int>\n#define lg2(n) (31 - __builtin_clz(n))\n#define ll long long\nusing namespace std;\nconst long long P = 1e9+7;\nconst int N = 4e5+2;\nconst long long INF = 1e18;\n\nvoid input()\n{\n#define TASKNAME \"\"\n ios_base::sync_with_stdio(0);\n cin.tie(0);\n if (fopen(TASKNAME\".inp\",\"r\" ))\n {\n freopen(TASKNAME\".inp\",\"r\",stdin);\n freopen(TASKNAME\".out\",\"w\",stdout);\n }\n}\nint n, m, k;\ntypedef array<int, 4> it;\nint p[N], sz[N],cnt, cur;\n\nstruct DSU\n{\n vector<int> par, sz;\n vector<array<int, 4> > rb;\n void rz(int n)\n {\n par.assign(n + 1, 0);\n sz.assign(n + 1, 1);\n rb.clear();\n cur = 1;\n }\n int get(int u)\n {\n return (!par[u] ? u : get(par[u]));\n }\n int join(int u, int v)\n {\n u = get(u), v = get(v);\n if (u == v) return 0;\n if (sz[u] < sz[v]) swap(u, v);\n rb.push_back({u, sz[u], v, cur});\n sz[u] += sz[v];\n par[v] = u;\n cur = max(cur, sz[u]);\n return 1;\n }\n void rollback(int cnt)\n {\n while (cnt--)\n {\n auto G = rb.back(); rb.pop_back();\n sz[G[0]] = G[1];\n par[G[2]] = 0;\n cur = G[3];\n }\n }\n} T;\nit e[N];\nint s[N], ans[N];\nint main()\n{\n input();\n cin >> n >> m >> k;\n T.rz(n);\n for (int i = 1; i <= m; i++) cin >> e[i][2] >> e[i][3];\n for (int i = 1; i <= n; i++) cin >> s[i];\n for (int i = 1; i <= m; i++)\n {\n if (s[e[i][2]] > s[e[i][3]]) swap(e[i][2], e[i][3]);\n e[i][0] = s[e[i][2]];\n e[i][1] = s[e[i][3]];\n if (e[i][0] == e[i][1]) T.join(e[i][2], e[i][3]);\n }\n sort(e + 1, e + m + 1);\n int q; cin >> q;\n vector<array<int, 5> > b;\n for (int i = 1; i <= q; i++)\n {\n int x, y;\n cin >> x >> y;\n if (s[x] > s[y]) swap(x, y);\n b.push_back({s[x], s[y], x, y, i});\n }\n sort(b.begin(), b.end());\n for (int i = 0; i < q; i++)\n {\n if (b[i][0] == b[i][1])\n {\n ans[b[i][4]] = (T.get(b[i][2]) == T.get(b[i][3]));\n continue;\n }\n int j = i;\n while (j + 1 < q && b[j + 1][0] == b[i][0] && b[j + 1][1] == b[i][1]) j++;\n int l = lower_bound(e + 1, e + m + 1, array<int, 4>{b[i][0], b[i][1], 0, 0}) - e;\n if (l == m + 1)\n {\n i = j;\n continue;\n }\n int cnt = 0;\n for (int k = l; k <= m; k++)\n if (e[k][0] == b[i][0] && e[k][1] == b[i][1])\n cnt += T.join(e[k][2], e[k][3]); else break;\n for (int k = i; k <= j; k++)\n ans[b[k][4]] = (T.get(b[k][2]) == T.get(b[k][3]));\n T.rollback(cnt);\n i = j;\n }\n for (int i = 1; i <= q; i++) cout << ans[i] << '\\n';\n return 0;\n}", "accuracy": 1, "time_ms": 230, "memory_kb": 40968, "score_of_the_acc": -0.3133, "final_rank": 2 }, { "submission_id": "aoj_0723_8347227", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 400005\n\nstruct Edge{\n\tEdge(int arg_to,int arg_ind){\n\t\tto = arg_to;\n\t\tind = arg_ind;\n\t}\n\tEdge(){\n\n\t\tto = ind = 0;\n\t}\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn ind < arg.ind;\n\t}\n\tint to,ind;\n};\n\nint N,M,K;\nint boss[SIZE],height[SIZE],num_member[SIZE];\nint A[SIZE],B[SIZE],S[SIZE];\nint IND = 0;\nvector<int> TO[SIZE];\nmap<pair<int,int>,int> MAP;\nmap<int,int> HEAD[SIZE];\nmap<int,int> MAXI[SIZE];\nvector<Edge> G[SIZE];\nset<int> SET;\nint NUM;\n\n\nint get_boss(int id){\n\tif(boss[id] == id)return id;\n\telse{\n\t\treturn boss[id] = get_boss(boss[id]);\n\t}\n}\n\nint isSame(int x,int y){\n\treturn get_boss(x) == get_boss(y);\n}\n\nvoid unite(int x,int y){\n\tint boss_x = get_boss(x);\n\tint boss_y = get_boss(y);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x] > height[boss_y]){\n\n\t\tnum_member[boss_x] += num_member[boss_y];\n\t\tboss[boss_y] = boss_x;\n\n\t}else if(height[boss_x] < height[boss_y]){\n\n\t\tnum_member[boss_y] += num_member[boss_x];\n\t\tboss[boss_x] = boss_y;\n\n\t}else{ //height[boss_x] == height[boss_y]\n\n\t\tnum_member[boss_x] += num_member[boss_y];\n\t\tboss[boss_y] = boss_x;\n\t\theight[x]++;\n\t}\n}\n\nvoid dfs(int ind,int node){\n\n\tint size = G[node].size();\n\tif(size == 0)return;\n\n\tint head;\n\n\tauto at = HEAD[node].find(ind);\n\tif(at == HEAD[node].end()){\n\n\t\treturn;\n\t}\n\n\thead = at->second;\n\n\tfor(int i = head; i < G[node].size(); i++){\n\t\tif(G[node][i].ind != ind)break;\n\n\t\tint next = G[node][i].to;\n\n\t\tif(SET.count(next) > 0)continue;\n\n\t\tSET.insert(next);\n\t\tchmax(NUM,next); //■訪問済みの中で最大のノード番号\n\n\t\tdfs(ind,next);\n\t}\n}\n\nint getIndex(int a,int b){\n\tif(a > b){\n\n\t\tswap(a,b);\n\t}\n\n\tauto at = MAP.find(make_pair(a,b));\n\n\tif(at == MAP.end()){\n\n\t\tMAP[make_pair(a,b)] = IND++;\n\t}\n\n\treturn MAP[make_pair(a,b)];\n}\n\nint main(){\n\n\tscanf(\"%d %d %d\",&N,&M,&K);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i] = i;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d %d\",&A[i],&B[i]);\n\t\tA[i]--;\n\t\tB[i]--;\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&S[i]);\n\t}\n\n\t//■同じグループの頂点をまとめる\n\tfor(int i = 0; i < M; i++){\n\t\tif(S[A[i]] == S[B[i]]){\n\n\t\t\tunite(A[i],B[i]);\n\t\t}\n\t}\n\n\t//エッジを集約\n\tfor(int i = 0; i < M; i++){\n\t\tif(S[A[i]] != S[B[i]]){\n\n\t\t\tint a = get_boss(A[i]);\n\t\t\tint b = get_boss(B[i]);\n\n\t\t\tTO[a].push_back(b);\n\t\t\tTO[b].push_back(a);\n\n\t\t\tgetIndex(S[A[i]],S[B[i]]); //■隣接する州の組合せに番号を振る\n\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(i != get_boss(i))continue;\n\t\tif(TO[i].size() == 0)continue;\n\n\t\tsort(TO[i].begin(),TO[i].end());\n\t\tTO[i].erase(unique(TO[i].begin(),TO[i].end()),TO[i].end());\n\n\t\tfor(int k = 0; k < TO[i].size(); k++){\n\n\t\t\tint to = TO[i][k]; //隣接グループ\n\t\t\tint ind = getIndex(S[i],S[to]); //エッジのタイプ\n\n\t\t\tG[i].push_back(Edge(to,ind));\n\t\t}\n\t\tsort(G[i].begin(),G[i].end());\n\n\t\tset<int> work;\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint ind = G[i][k].ind;\n\t\t\tif(work.count(ind) == 0){\n\n\t\t\t\tHEAD[i][ind] = k;\n\t\t\t\twork.insert(ind);\n\t\t\t}\n\t\t}\n\t}\n\n\tint numQ;\n\tscanf(\"%d\",&numQ);\n\n\tint from,to;\n\tfor(int loop = 0; loop < numQ; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\n\t\tif(S[from] == S[to]){\n\n\t\t\tif(isSame(from,to)){\n\n\t\t\t\tprintf(\"1\\n\");\n\n\t\t\t}else{\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t}\n\t\t\tcontinue;\n\t\t}\n\n\t\tfrom = get_boss(from);\n\t\tto = get_boss(to);\n\n\t\tif(from > to){\n\n\t\t\tswap(from,to);\n\t\t}\n\t\tint ind = getIndex(S[from],S[to]);\n\n\t\tauto at = MAXI[ind].find(from);\n\t\tauto bt = MAXI[ind].find(to);\n\n\t\tif(at != MAXI[ind].end() && bt != MAXI[ind].end()){\n\n\t\t\tif(at->second == bt->second){\n\n\t\t\t\tprintf(\"1\\n\");\n\t\t\t}else{\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t}\n\t\t\tcontinue;\n\n\t\t}else if(at == MAXI[ind].end() && bt != MAXI[ind].end()){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\n\t\t}else if(at != MAXI[ind].end() && bt == MAXI[ind].end()){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\n\t\t}else{ //at == MAX[ind].end() && bt == MAXI[ind].end();\n\n\t\t\tSET.clear();\n\t\t\tNUM = from;\n\t\t\tdfs(ind,from);\n\t\t}\n\n\t\tif(SET.count(to) > 0){\n\n\t\t\tprintf(\"1\\n\");\n\n\t\t}else{\n\n\t\t\tprintf(\"0\\n\");\n\t\t}\n\t\tfor(int n: SET){\n\n\t\t\tMAXI[ind][n] = NUM;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1420, "memory_kb": 181512, "score_of_the_acc": -1.9878, "final_rank": 11 }, { "submission_id": "aoj_0723_8347213", "code_snippet": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef unsigned long long int ull;\n#define chmin(x,y) x = min(x,y)\n#define chmax(x,y) x = max(x,y)\n#define BIG_NUM 2000000000\n#define HUGE_NUM 4000000000000000000 //オーバーフローに注意\n#define MOD 1000000007\n#define EPS 0.000000001\n\n\n\n\n#define SIZE 400005\n\nstruct Edge{\n\tEdge(int arg_to,int arg_ind){\n\t\tto = arg_to;\n\t\tind = arg_ind;\n\t}\n\tEdge(){\n\n\t\tto = ind = 0;\n\t}\n\tbool operator<(const struct Edge& arg) const{\n\n\t\treturn ind < arg.ind;\n\t}\n\tint to,ind;\n};\n\nint N,M,K;\nint boss[SIZE],height[SIZE],num_member[SIZE];\nint A[SIZE],B[SIZE],S[SIZE];\nint IND = 0;\nvector<int> TO[SIZE];\nmap<pair<int,int>,int> MAP;\nmap<int,int> HEAD[SIZE];\nmap<int,int> MAXI[SIZE];\nvector<Edge> G[SIZE];\nset<int> SET;\nint NUM;\n\n\nint get_boss(int id){\n\tif(boss[id] == id)return id;\n\telse{\n\t\treturn boss[id] = get_boss(boss[id]);\n\t}\n}\n\nint isSame(int x,int y){\n\treturn get_boss(x) == get_boss(y);\n}\n\nvoid unite(int x,int y){\n\tint boss_x = get_boss(x);\n\tint boss_y = get_boss(y);\n\n\tif(boss_x == boss_y)return;\n\n\tif(height[boss_x] > height[boss_y]){\n\n\t\tnum_member[boss_x] += num_member[boss_y];\n\t\tboss[boss_y] = boss_x;\n\n\t}else if(height[boss_x] < height[boss_y]){\n\n\t\tnum_member[boss_y] += num_member[boss_x];\n\t\tboss[boss_x] = boss_y;\n\n\t}else{ //height[boss_x] == height[boss_y]\n\n\t\tnum_member[boss_x] += num_member[boss_y];\n\t\tboss[boss_y] = boss_x;\n\t\theight[x]++;\n\t}\n}\n\nvoid dfs(int ind,int node){\n\n\tint size = G[node].size();\n\tif(size == 0)return;\n\n\t//printf(\"ind:%d node:%d\\n\",ind,node);\n\n\tint head;\n\n\tauto at = HEAD[node].find(ind);\n\tif(at == HEAD[node].end()){\n\n\t\treturn;\n\t}\n\n\thead = at->second;\n\n\tfor(int i = head; i < G[node].size(); i++){\n\t\tif(G[node][i].ind != ind)break;\n\n\t\tint next = G[node][i].to;\n\n\t\tif(SET.count(next) > 0)continue;\n\n\t\tSET.insert(next);\n\t\tchmax(NUM,next); //■訪問済みの中で最大のノード番号\n\n\t\tdfs(ind,next);\n\t}\n}\n\nint getIndex(int a,int b){\n\tif(a > b){\n\n\t\tswap(a,b);\n\t}\n\n\tauto at = MAP.find(make_pair(a,b));\n\n\tif(at == MAP.end()){\n\n\t\tMAP[make_pair(a,b)] = IND++;\n\t}\n\n\treturn MAP[make_pair(a,b)];\n}\n\nint main(){\n\n\tscanf(\"%d %d %d\",&N,&M,&K);\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tboss[i] = i;\n\t}\n\n\tfor(int i = 0; i < M; i++){\n\n\t\tscanf(\"%d %d\",&A[i],&B[i]);\n\t\tA[i]--;\n\t\tB[i]--;\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\n\t\tscanf(\"%d\",&S[i]);\n\t}\n\n\t//■同じグループの頂点をまとめる\n\tfor(int i = 0; i < M; i++){\n\t\tif(S[A[i]] == S[B[i]]){\n\n\t\t\tunite(A[i],B[i]);\n\t\t}\n\t}\n\n\t//エッジを集約\n\tfor(int i = 0; i < M; i++){\n\t\tif(S[A[i]] != S[B[i]]){\n\n\t\t\tint a = get_boss(A[i]);\n\t\t\tint b = get_boss(B[i]);\n\n\t\t\tTO[a].push_back(b);\n\t\t\tTO[b].push_back(a);\n\n\t\t\tgetIndex(S[A[i]],S[B[i]]); //■隣接する州の組合せに番号を振る\n\n\t\t}\n\t}\n\n\tfor(int i = 0; i < N; i++){\n\t\tif(i != get_boss(i))continue;\n\t\tif(TO[i].size() == 0)continue;\n\n\t\tsort(TO[i].begin(),TO[i].end());\n\t\tTO[i].erase(unique(TO[i].begin(),TO[i].end()),TO[i].end());\n\n\t\tfor(int k = 0; k < TO[i].size(); k++){\n\n\t\t\tint to = TO[i][k]; //隣接グループ\n\t\t\tint ind = getIndex(S[i],S[to]); //エッジのタイプ\n\n\t\t\tG[i].push_back(Edge(to,ind));\n\t\t}\n\t\tsort(G[i].begin(),G[i].end());\n\n\t\tset<int> work;\n\t\tfor(int k = 0; k < G[i].size(); k++){\n\n\t\t\tint ind = G[i][k].ind;\n\t\t\tif(work.count(ind) == 0){\n\n\t\t\t\tHEAD[i][ind] = k;\n\t\t\t\twork.insert(ind);\n\t\t\t}\n\t\t}\n\t}\n\n\tint numQ;\n\tscanf(\"%d\",&numQ);\n\n\tint from,to;\n\tfor(int loop = 0; loop < numQ; loop++){\n\n\t\tscanf(\"%d %d\",&from,&to);\n\t\tfrom--;\n\t\tto--;\n\n\t\tif(S[from] == S[to]){\n\n\t\t\tif(isSame(from,to)){\n\n\t\t\t\tprintf(\"1\\n\");\n\n\t\t\t}else{\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t}\n\t\t\tcontinue;\n\t\t}\n\n\t\tfrom = get_boss(from);\n\t\tto = get_boss(to);\n\n\t\tif(from > to){\n\n\t\t\tswap(from,to);\n\t\t}\n\t\tint ind = getIndex(S[from],S[to]);\n\n\t\tauto at = MAXI[ind].find(from);\n\t\tauto bt = MAXI[ind].find(to);\n\n\t\tif(at != MAXI[ind].end() && bt != MAXI[ind].end()){\n\n\t\t\tif(at->second == bt->second){\n\n\t\t\t\tprintf(\"1\\n\");\n\t\t\t}else{\n\n\t\t\t\tprintf(\"0\\n\");\n\t\t\t}\n\t\t\tcontinue;\n\n\t\t}else if(at == MAXI[ind].end() && bt != MAXI[ind].end()){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\n\t\t}else if(at != MAXI[ind].end() && bt == MAXI[ind].end()){\n\n\t\t\tprintf(\"0\\n\");\n\t\t\tcontinue;\n\n\t\t}else{ //at == MAX[ind].end() && bt == MAXI[ind].end();\n\n\t\t\tSET.clear();\n\t\t\tNUM = from;\n\t\t\tdfs(ind,from);\n\t\t}\n\n\t\t//printf(\"from;%d to;%d ind;%d\\n\",from,to,ind);\n\t\t//continue;\n\n\n\t\tif(SET.count(to) > 0){\n\n\t\t\tprintf(\"1\\n\");\n\n\t\t}else{\n\n\t\t\tprintf(\"0\\n\");\n\t\t}\n\t\tfor(int n: SET){\n\n\t\t\tMAXI[ind][n] = NUM;\n\t\t}\n\t}\n\n\treturn 0;\n}", "accuracy": 1, "time_ms": 1400, "memory_kb": 181716, "score_of_the_acc": -1.9739, "final_rank": 10 }, { "submission_id": "aoj_0723_8170610", "code_snippet": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\n\nusing namespace std;\nvector<int> pos;\nvector<int> prev_root;\nvector<int> prev_rank;\n\ntypedef struct st\n{\n int S1;\n int S2;\n int C1;\n int C2;\n st(int S1, int S2, int C1, int C2) {\n this->S1 = S1;\n this->S2 = S2;\n this->C1 = C1;\n this->C2 = C2;\n }\n} st;\n\ntypedef struct queries {\n int num;\n int C1;\n int C2;\n int S1;\n int S2;\n queries(int num, int C1, int C2, int S1, int S2) {\n this->num = num;\n this->C1 = C1;\n this->C2 = C2;\n this->S1 = S1;\n this->S2 = S2;\n }\n} queries;\n\nbool fcomp(const st& a, const st& b) {\n if (a.S1 < b.S1) {\n return true;\n }\n else {\n if (a.S1 > b.S1) {\n return false;\n }\n else {\n return a.S2 < b.S2;\n }\n }\n}\n\nbool fcompQ(const queries& a, const queries& b) {\n if (a.S1 < b.S1) {\n return true;\n }\n else {\n if (a.S1 > b.S1) {\n return false;\n }\n else {\n return a.S2 < b.S2;\n }\n }\n}\n\nint getRoot(int a, int mp[],int ranks[],bool flag) {\n int next = mp[a];\n int rankA = ranks[a];\n\n if (next == a) {\n return a;\n }\n else {\n int root = getRoot(next, mp,ranks,flag);\n if (flag) {\n pos.push_back(a);\n prev_root.push_back(next);\n prev_rank.push_back(rankA);\n }\n mp[a] = root; \n ranks[a] = 1;\n return root;\n }\n}\n\nint isSame(int a, int b, int mp[], int ranks[],bool flag) {\n if (getRoot(a, mp,ranks, flag) == getRoot(b, mp,ranks, flag)) {\n return true;\n }\n else {\n return false;\n }\n}\n\nint unite(int a, int b, int mp[], int ranks[], bool flag) {\n int rootA = getRoot(a, mp,ranks,flag);\n int rootB = getRoot(b, mp,ranks, flag);\n\n if (rootA == rootB) {\n return 0;\n }\n else {\n int rankA = ranks[rootA];\n int rankB = ranks[rootB];\n if (rankA < rankB) {\n if (flag) {\n pos.push_back(rootA);\n prev_root.push_back(rootA);\n prev_rank.push_back(rankA);\n }\n mp[rootA] = rootB;\n ranks[rootA] = rankB + 1;\n }\n else {\n if (flag) {\n pos.push_back(rootB);\n prev_root.push_back(rootB);\n prev_rank.push_back(rankB);\n }\n mp[rootB] = rootA;\n ranks[rootB] = rankA + 1;\n }\n return 0;\n }\n\n}\n\nint undo(int mp[], int ranks[]) {\n int pos0;\n int root0;\n for (int i = prev_root.size() - 1; i >= 0; i--) {\n pos0 = pos[i];\n root0 = prev_root[i];\n mp[pos0] = root0;\n ranks[pos0] = prev_rank[i];\n }\n pos.clear();\n prev_root.clear();\n prev_rank.clear();\n return 0;\n}\n\nint main(void) {\n // Your code here!\n int N, M, K;\n cin >> N >> M >> K; //N cities M roads K states\n int mp[N + 1];\n int ranks[N + 1];\n\n clock_t start = clock();\n\n for (int i = 1; i < N + 1; i++) {\n mp[i] = i;\n ranks[i] = 1;\n }\n\n int U[M], V[M];\n for (int j = 0; j < M; j++) {\n cin >> U[j] >> V[j];\n }\n int S[N + 1];\n for (int i = 1; i < N + 1; i++) {\n cin >> S[i];\n }\n\n vector <st> roads;\n roads.reserve(2 * M);\n\n int U0, V0;\n for (int j = 0; j < M; j++) {\n U0 = U[j];\n V0 = V[j];\n if (S[U0] == S[V0]) {\n unite(U0, V0, mp, ranks, false);\n }\n else {\n roads.push_back(st(S[U0], S[V0], U0, V0));\n roads.push_back(st(S[V0], S[U0], V0, U0));\n }\n }\n\n sort(roads.begin(), roads.end(), fcomp);\n /*\n for(int i=0;i<roads.size();i++){\n cout << roads[i].S1 <<\",\" <<roads[i].S2 <<\",\"<<roads[i].C1 <<\",\" <<roads[i].C2 <<endl;\n }\n */\n\n /*\n for(int m=1;m<N+1;m++){\n cout << m << \":\" << mp[m] <<\"(\" << S[m] << \")\" <<endl;\n }\n */\n\n int Q, A, B; // Q trades\n int S1, S2;\n \n cin >> Q;\n\n int Answers[Q];\n vector <queries> Ques;\n Ques.reserve(Q);\n\n for (int i = 0; i < Q; i++) {\n cin >> A >> B;\n S1 = S[A];\n S2 = S[B];\n if (S1 > S2) {\n swap(A, B);\n S1 = S[A];\n S2 = S[B];\n }\n Ques.push_back(queries(i,A,B,S1,S2));\n }\n\n sort(Ques.begin(), Ques.end(), fcompQ);\n int prevS1 = 0;\n int prevS2 = 0;\n int num;\n for (int i = 0; i < Q; i++) {\n A = Ques[i].C1;\n B = Ques[i].C2;\n S1 = S[A];\n S2 = S[B];\n num = Ques[i].num;\n\n if (prevS1 != S1 || prevS2 != S2) {\n undo(mp, ranks);\n auto it1 = lower_bound(roads.begin(), roads.end(), st(S1, S2, A, B), fcomp);\n for (auto it = it1; it1 != roads.end(); ++it) {\n if (it->S1 != S1 || it->S2 != S2) {\n break;\n }\n unite(it->C1, it->C2, mp, ranks, true);\n }\n }\n prevS1 = S1;\n prevS2 = S2;\n if (isSame(A, B, mp,ranks, true)) {\n Answers[num] = 1;\n }\n else {\n Answers[num] = 0;\n }\n }\n for (int i = 0; i < Q; i++) {\n cout << Answers[i] << endl;\n }\n\n /*\n for (int i = 0; i < Q; i++) {\n cin >> A >> B;\n S1 = S[A];\n S2 = S[B];\n if (S1 > S2) {\n swap(A, B);\n S1 = S[A];\n S2 = S[B];\n }\n auto it1 = lower_bound(roads.begin(), roads.end(), st(S1, S2, A, B), fcomp);\n for (auto it = it1; it1 != roads.end(); ++it) {\n if (it->S1 != S1 || it->S2 != S2) {\n break;\n }\n unite(it->C1, it->C2, mp, ranks, true);\n }\n if (isSame(A, B, mp,true)) {\n cout << \"1\" << endl;\n }\n else {\n cout << \"0\" << endl;\n }\n undo(mp, ranks);\n }\n */\n}", "accuracy": 1, "time_ms": 730, "memory_kb": 54732, "score_of_the_acc": -0.7656, "final_rank": 3 }, { "submission_id": "aoj_0723_8168883", "code_snippet": "#include <iostream>\n#include <map>\n#include <vector>\n#include <algorithm>\nusing namespace std;\nmap<int, int> mp; \nmap<int ,int> ranks;\ntypedef struct st\n{\n int S1;\n int S2;\n int C1;\n int C2;\n st(int S1,int S2,int C1,int C2){\n this->S1=S1;\n this->S2=S2;\n this->C1=C1;\n this->C2=C2;\n }\n} st;\n\nint getRoot(int a){\n if (mp[a]==a){\n return a;\n }else{\n int root=getRoot(mp[a]);\n mp[a]=root;\n return root;\n }\n}\n\nint isSame(int a,int b){\n if(getRoot(a)==getRoot(b)){\n return true;\n }else{\n return false;\n }\n}\n\nint unite(int a,int b){\n int rootA=getRoot(a);\n int rootB=getRoot(b);\n \n if (rootA==rootB) {\n return 0;\n }else{\n int rankA=ranks[rootA];\n int rankB=ranks[rootB];\n if(rankA<rankB){\n mp[rootA]=rootB;\n ranks[rootA]=rankB+1;\n }else{\n mp[rootB]=rootA;\n ranks[rootB]=rankA+1;\n }\n return 0;\n }\n}\n\nbool fcomp(const st& a, const st& b) {\n if(a.S1<b.S1){\n return true;\n }else{\n if(a.S1>b.S1){\n return false;\n }else{\n return a.S2<b.S2;\n }\n }\n}\n\n\nint main(void){\n // Your code here!\n int N,M,K;\n cin >> N >> M >> K; //N cities M roads K states\n \n for(int i=1;i<N+1;i++){\n mp[i]=i;\n ranks[i]=1;\n }\n \n int U[M],V[M];\n for(int j=0;j<M;j++){\n cin >> U[j] >> V[j] ;\n }\n int S[N+1];\n for(int i=1;i<N+1;i++){\n cin >> S[i];\n }\n \n vector <st> roads;\n roads.reserve(2*M);\n \n int U0,V0;\n for(int j=0;j<M;j++){\n U0=U[j];\n V0=V[j];\n if(S[U0]==S[V0]){\n unite(U0,V0);\n }else{\n roads.push_back(st(S[U0],S[V0],U0,V0));\n roads.push_back(st(S[V0],S[U0],V0,U0));\n }\n }\n \n sort(roads.begin(),roads.end(),fcomp);\n \n /*\n for(int i=0;i<roads.size();i++){\n cout << roads[i].S1 <<\",\" <<roads[i].S2 <<\",\"<<roads[i].C1 <<\",\" <<roads[i].C2 <<endl;\n }\n */\n \n /*\n for(int m=1;m<N+1;m++){\n cout << m << \":\" << mp[m] <<\"(\" << S[m] << \")\" <<endl;\n }\n */\n \n int Q,A,B; // Q trades\n int S1,S2;\n cin >> Q;\n for(int i=0;i<Q;i++){\n map<int, int> mp_backup(mp); \n cin >> A >> B;\n S1=S[A];\n S2=S[B];\n if(S1>S2){\n swap(A,B);\n S1=S[A];\n S2=S[B];\n }\n \n auto it1=lower_bound(roads.begin(), roads.end(),st(S1,S2,A,B),fcomp); \n for(auto it=it1;it1!=roads.end();++it){\n if (it->S1!=S1 || it->S2!=S2){\n break;\n }\n unite(A,B);\n } \n \n /*\n for(int j=0;j<M;j++){\n if ( (S[U[j]]==S1 && S[V[j]]==S2) || (S[U[j]]==S2 && S[V[j]]==S1)){\n unite(U[j],V[j]);\n }\n }\n */\n /*\n for(int m=1;m<N+1;m++){\n cout << m << \":\" << mp[m] <<\"(\" << S[m] << \")\" <<endl;\n }\n */\n \n if (isSame(A,B) ){\n cout <<\"1\"<< endl; \n }else{\n cout <<\"0\"<< endl;\n }\n \n for(int m=1;m<N+1;m++){\n mp[m]=mp_backup[m];\n } \n }\n}", "accuracy": 0.06756756756756757, "time_ms": 90, "memory_kb": 3476, "score_of_the_acc": 0, "final_rank": 12 }, { "submission_id": "aoj_0723_7882576", "code_snippet": "#include <bits/extc++.h>\n\nusing namespace std;\n\n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define updiv(a, b) (((a) + (b) - 1) / (b))\nusing pii = pair<int,int>;\nconstexpr int32_t INF = 0x3f3f3f3f;\nconstexpr int_fast64_t LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n template <class... Args>\n constexpr decltype(auto) operator()(Args&&... args) const {\n return Func::operator()(*this, std::forward<Args>(args)...);\n }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate<class T, class U> istream& operator>>(istream& is, pair<T, U>& p){ is >> p.first >> p.second; return (is); }\ntemplate<class T, class U> ostream& operator<<(ostream& os, pair<T, U>& p){ os << p.first << ' ' << p.second; return (os); }\ntemplate<class T> istream& operator>>(istream& is, vector<T>& v){ for (auto &&e : v) is >> e; return (is); }\ntemplate<class T> ostream& operator<<(ostream& os, vector<T>& v){ for (auto &&e : v) os << e << ' '; return (os); }\n\ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class T> using min_heap = priority_queue<T, vector<T>, greater<T> >;\ntemplate <class A, class B> using umap = unordered_map<A, B>;\ntemplate <class T> using uset = unordered_set<T>;\n\ntemplate <class T> using Max_Heap = __gnu_pbds::priority_queue<T, less<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Min_Heap = __gnu_pbds::priority_queue<T, greater<T>, __gnu_pbds::rc_binomial_heap_tag>;\ntemplate <class T> using Set = __gnu_pbds::tree<T, __gnu_pbds::null_type, less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = __gnu_pbds::gp_hash_table<K, V>;\ntemplate <class T> using Rope = __gnu_cxx::rope<T>;\nusing Trie = __gnu_pbds::trie<string, __gnu_pbds::null_type, __gnu_pbds::trie_string_access_traits<>, __gnu_pbds::pat_trie_tag, __gnu_pbds::trie_prefix_search_node_update>;\n\ntemplate <class T> void bye(T x){ cout << x << '\\n'; exit(0); }\ninline int square(int a){ return (a * a); }\n\nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n\nstruct UnionFindUndo {\n vector<int> data;\n vector<pair<int, int> > history;\n\n UnionFindUndo(int sz) {\n data.assign(sz, -1);\n }\n\n bool unite(int x, int y) {\n x = find(x), y = find(y);\n history.emplace_back(x, data[x]);\n history.emplace_back(y, data[y]);\n if(x == y) return (false);\n if(data[x] > data[y]) swap(x, y);\n data[x] += data[y];\n data[y] = x;\n return (true);\n }\n\n int find(int k) {\n if(data[k] < 0) return (k);\n return (find(data[k]));\n }\n\n int size(int k) {\n return (-data[find(k)]);\n }\n\n void undo() {\n data[history.back().first] = history.back().second;\n history.pop_back();\n data[history.back().first] = history.back().second;\n history.pop_back();\n }\n\n void snapshot() {\n while(history.size()) history.pop_back();\n }\n\n void rollback() {\n while(history.size()) undo();\n }\n};\n\n\nsigned main(){\n cin.tie(nullptr);\n ios_base::sync_with_stdio(false);\n cout.setf(ios_base::fixed);\n cout.precision(12);\n \n int n, m, k;\n cin >> n >> m >> k;\n\n vector<int> u(m), v(m);\n vector<vector<int> > g(n);\n for (int i = 0; i < m; ++i) {\n cin >> u[i] >> v[i];\n --u[i], --v[i];\n\n g[u[i]].emplace_back(v[i]);\n g[v[i]].emplace_back(u[i]);\n }\n\n vector<int> s(n);\n\n cin >> s;\n\n for (auto &&e : s) --e;\n\n vector<int> group(n, -1);\n int cnt = 0;\n\n for (int i = 0; i < n; ++i) {\n if (group[i] == -1) {\n queue<int> que;\n que.emplace(i);\n group[i] = cnt;\n while (!que.empty()) {\n int cur = que.front();\n que.pop();\n for (auto to : g[cur]) {\n if (s[to] == s[i] && group[to] == -1) {\n que.emplace(to);\n group[to] = cnt;\n }\n }\n }\n cnt++;\n }\n }\n\n vector<umap<int, vector<pair<int, int> > > > edges(k);\n\n for (int i = 0; i < m; ++i) {\n auto [su, sv] = minmax({s[u[i]], s[v[i]]});\n edges[su][sv].emplace_back(u[i], v[i]);\n }\n\n int q;\n cin >> q;\n\n vector<umap<int, vector<tuple<int, int, int> > > > queries(k);\n\n for (int i = 0; i < q; ++i) {\n int a, b;\n cin >> a >> b;\n --a, --b;\n\n auto[sa, sb] = minmax({s[a], s[b]});\n\n queries[sa][sb].emplace_back(a, b, i);\n }\n\n vector<int> ans(q);\n UnionFindUndo uf(cnt);\n\n for (int i = 0; i < k; ++i) {\n for (auto [j, v] : queries[i]) {\n for (auto [a, b] : edges[i][j]) {\n uf.unite(group[a], group[b]);\n }\n for (auto [a, b, idx] : v) {\n if (uf.find(group[a]) == uf.find(group[b])) {\n ans[idx] = 1;\n } else {\n ans[idx] = 0;\n }\n }\n uf.rollback();\n }\n }\n\n for (auto e : ans) {\n cout << e << '\\n';\n }\n \n return (0);\n}", "accuracy": 1, "time_ms": 580, "memory_kb": 183712, "score_of_the_acc": -1.3684, "final_rank": 9 } ]